{
    "1": {
        "category": "Correspondence",
        "question_ko": "자연수 A에 대해 9로 나눈 몫은 6, 나머지는 5입니다. A의 값은 무엇일까요?",
        "question_en": "For the natural number A, the quotient of A divided by 9 is 6 and the remainder is 5. What is the value of A?",
        "answer_ko": "59",
        "answer_en": "59",
        "solution_abst_ko": "9 6 [OP_MUL] 5 [OP_ADD]",
        "solution_abst_en": "9 6 [OP_MUL] 5 [OP_ADD]",
        "solution_code_ko": "var_a = 9\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "2": {
        "category": "Arithmetic calculation",
        "question_ko": "80보다 작은 수 중에서 9의 배수의 총합을 구하시오.",
        "question_en": "Find the sum of all multiples of 9 that are less than 80.",
        "answer_ko": "324",
        "answer_en": "324",
        "solution_abst_ko": "1 80 1 [OP_SUB] 1 [OP_LIST_ARANGE] 9 [OP_LIST_DIVISIBLE] [OP_LIST_SUM]",
        "solution_abst_en": "1 80 1 [OP_SUB] 1 [OP_LIST_ARANGE] 9 [OP_LIST_DIVISIBLE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 80\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nvar_f = 9\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 80\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nvar_f = 9\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nprint(int(var_g))"
    },
    "3": {
        "category": "Possibility",
        "question_ko": "동주는 숫자가 적힌 쪽지를 뽑아, 처음 뽑은 것을 백의 자리, 두 번째는 십의 자리, 세 번째는 일의 자리로 하여 세 자리수를 만들고자 한다. 쪽지는 1, 6, 8이 있을 때, 동주가 만들 수 있는 두 번째로 작은 수와 세 번째로 작은 세 자리수의 합을 구하시오. 단, 같은 쪽지를 여러 번 뽑을 수 없다.",
        "question_en": "Dongju selects a piece of paper with a number written on it, and wants to make a three-digit number by placing the first selected number in the hundreds place, the second selected in the tens place, and the third selected in the units place. If the numbers written on each paper was 1, 6, and 8, respectively, find the sum of the second smallest and third smallest three-digit numbers that Dongju can make. However, you cannot select the same numbered paper multiple times.",
        "answer_ko": "804",
        "answer_en": "804",
        "solution_abst_ko": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MIN] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MIN] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))"
    },
    "4": {
        "category": "Possibility",
        "question_ko": "숫자 1, 2, 6, 8을 한 번씩 모두 사용하여 두 번째로 큰 네 자리 수와 세 번째로 작은 네 자리수의 합을 구하시오.",
        "question_en": "Among the numbers that you can make using all of the numbers 1, 2, 6, and 8 once each, find the sum of the second largest four-digit number and the third smallest four-digit number.",
        "answer_ko": "10240",
        "answer_en": "10240",
        "solution_abst_ko": "[OP_LIST_SOL] 1 2 6 8 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 1 2 6 8 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 2\nvar_c = 6\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 1\nvar_b = 2\nvar_c = 6\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))"
    },
    "5": {
        "category": "Geometry",
        "question_ko": "십각형 내에 그릴 수 있는 대각선의 개수는?",
        "question_en": "How many diagonals can you draw in a decagon?",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "10 10 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "10 10 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 10\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 10\nvar_b = 10\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "6": {
        "category": "Arithmetic calculation",
        "question_ko": "진서의 한 뼘의 길이는 약 12센티미터(㎝)입니다. 진서가 책꽂이의 짧은 쪽의 길이를 재었더니 뼘으로 2번이었습니다. 책꽂이의 짧은 쪽의 길이는 약 몇 센티미터(㎝)입니까?",
        "question_en": "The length of one span of Jinseo is about 12 centimeters (cm). When Jinseo measured the length of the shorter side of the bookshelf, it was about two spans. How many centimeters (cm) is the short side of the bookshelf?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "12 2 [OP_MUL]",
        "solution_abst_en": "12 2 [OP_MUL]",
        "solution_code_ko": "var_a = 12\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 12\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "7": {
        "category": "Possibility",
        "question_ko": "숫자 자석 2, 0, 3, 5, 8중 4개를 골라 일렬로 배열하여 네 자리 수를 만들 때, 만들 수 있는 수 중 가장 큰 수와 가장 작은 수의 차는 얼마인가?",
        "question_en": "What is the difference between the largest number and the smallest number that can be made by selecting four from the number magnets 2, 0, 3, 5, and 8 and arranging them in a row to form a four-digit number?",
        "answer_ko": "6497",
        "answer_en": "6497",
        "solution_abst_ko": "[OP_LIST_SOL] 2 0 3 5 8 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 2 0 3 5 8 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 2\nvar_b = 0\nvar_c = 3\nvar_d = 5\nvar_e = 8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 2\nvar_b = 0\nvar_c = 3\nvar_d = 5\nvar_e = 8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h - var_j\nprint(int(var_k))"
    },
    "8": {
        "category": "Geometry",
        "question_ko": "지호네 반 학생들이 운동장에 서 있습니다. 학생들이 앞,뒤,좌,우 간격을 맞춰서서 큰 정사각형을 만들었더니 3명이 남았습니다. 만든 정사각형의 가로 한 변과 세로 한 변을 2열씩 늘리려면 41명이 더 필요하다고 합니다. 지호네 반 학생은 모두 몇 명입니까?",
        "question_en": "Jiho's classmates are standing on the playground. When the students made a big square by matching the front, back, left, and right spacing, there were 3 people left. It is said that 44 more students are needed to increase each horizontal and vertical side of the square by 2 columns. How many students are in Jiho's class?",
        "answer_ko": "103",
        "answer_en": "103",
        "solution_abst_ko": "41 3 [OP_ADD] 4 [OP_SUB] 4 [OP_DIV] 2 [OP_POW] 3 [OP_ADD]",
        "solution_abst_en": "41 3 [OP_ADD] 4 [OP_SUB] 4 [OP_DIV] 2 [OP_POW] 3 [OP_ADD]",
        "solution_code_ko": "var_a = 41\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c - var_d\nvar_f = 4\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 3\nvar_k = var_i + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 41\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c - var_d\nvar_f = 4\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 3\nvar_k = var_i + var_j\nprint(int(var_k))"
    },
    "9": {
        "category": "Correspondence",
        "question_ko": "10으로 어떤 수를 나누었더니 6이 됩니다. 윤기는 어떤 수에서 15를 빼 결과를 얻었습니다. 윤기가 얻은 값은?",
        "question_en": "A number divided by 10 is 6. Yoongi got the result by subtracting 15 from a certain number. What is the result he got?",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "6 10 [OP_MUL] 15 [OP_SUB]",
        "solution_abst_en": "6 10 [OP_MUL] 15 [OP_SUB]",
        "solution_code_ko": "var_a = 6\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 15\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 15\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "10": {
        "category": "Correspondence",
        "question_ko": "A85-2B=364입니다. A는 얼마인가요?",
        "question_en": "A85-2B=364. How much is A?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "A85-2B=364 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A85-2B=364 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A85-2B=364'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A85-2B=364'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "11": {
        "category": "Arithmetic calculation",
        "question_ko": "올해 민수와 어머니의 나이의 차는 28살이고, 13년 후에는 어머니의 나이가 민수의 나이의 2배가 된다고 한다. 올해 민수의 나이를 구하시오.",
        "question_en": "This year, the age difference between Minsu and his mother is 28 years old, and after 13 years, the age of his mother will be twice that of Minsu. Find the age of Minsu this year.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "13 28 13 [OP_SUB] 2 [OP_MUL] [OP_ADD] 2 1 [OP_SUB] [OP_DIV] 28 [OP_SUB]",
        "solution_abst_en": "13 28 13 [OP_SUB] 2 [OP_MUL] [OP_ADD] 2 1 [OP_SUB] [OP_DIV] 28 [OP_SUB]",
        "solution_code_ko": "var_a = 13\nvar_b = 28\nvar_c = 13\nvar_d = var_b - var_c\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_a + var_f\nvar_h = 2\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_g / var_j\nvar_l = 28\nvar_m = var_k - var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 13\nvar_b = 28\nvar_c = 13\nvar_d = var_b - var_c\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_a + var_f\nvar_h = 2\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_g / var_j\nvar_l = 28\nvar_m = var_k - var_l\nprint(int(var_m))"
    },
    "12": {
        "category": "Correspondence",
        "question_ko": "46을 어떤 수에서 빼야 하는데 실수로 59를 뺐더니 43이 나왔습니다. 바르게 계산한 결과를 구하여라.",
        "question_en": "You wanted to subtract 46 from a number, but you accidentally subtract 59 and get 43. How much do you get from the correct calculation?",
        "answer_ko": "56",
        "answer_en": "56",
        "solution_abst_ko": "43 59 [OP_ADD] 46 [OP_SUB]",
        "solution_abst_en": "43 59 [OP_ADD] 46 [OP_SUB]",
        "solution_code_ko": "var_a = 43\nvar_b = 59\nvar_c = var_a + var_b\nvar_d = 46\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 43\nvar_b = 59\nvar_c = var_a + var_b\nvar_d = 46\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "13": {
        "category": "Possibility",
        "question_ko": "정희, 철수, 은수, 민준 4명이 공포영화를 보러 영화관에 갔다. 이때, 공포영화를 잘 못보는 은수와 민준은 이웃하여 앉지 않는다고 할 때, 네 명이 한 줄로 앉는 경우의 수를 구하시오. (단, 좌석은 네 좌석이며 모두 붙어있다.)",
        "question_en": "Jeonghee, Cheolsu, Eunsu, and Minjun went to the cinema to watch a horror movie. If Eunsu and Minjun, who can't watch horror movies, don't sit next to each other, find the number of cases in which four people sit in a row. (However, there are four seats and all are attached.)",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "[OP_LIST_SOL] 정희 철수 은수 민준 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] 은수 [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] 은수 민준 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] Jeonghee Cheolsu Eunsu Minjun [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] Eunsu [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] Eunsu Minjun [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = '정희'\nvar_b = '철수'\nvar_c = '은수'\nvar_d = '민준'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = len(list_a)\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nvar_h = '은수'\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_i = len(list_c)\nvar_j = len(list_c)\nvar_k = 1\nvar_i = int(var_i)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_i-i)\nvar_l = '은수'\nvar_m = '민준'\nlist_d= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_d.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_d.append(var_l)\nlist_d.reverse()\nvar_n = len(list_d)\nvar_o = len(list_d)\nvar_p = 1\nvar_n = int(var_n)\nvar_o = int(var_o)\nfor i, elem in enumerate(range(var_o)):\n    var_p = var_p * (var_n-i)\nvar_q = var_k * var_p\nvar_r = var_g - var_q\nprint(int(var_r))",
        "solution_code_en": "var_a = 'Jeonghee'\nvar_b = 'Cheolsu'\nvar_c = 'Eunsu'\nvar_d = 'Minjun'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = len(list_a)\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nvar_h = 'Eunsu'\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_i = len(list_c)\nvar_j = len(list_c)\nvar_k = 1\nvar_i = int(var_i)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_i-i)\nvar_l = 'Eunsu'\nvar_m = 'Minjun'\nlist_d= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_d.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_d.append(var_l)\nlist_d.reverse()\nvar_n = len(list_d)\nvar_o = len(list_d)\nvar_p = 1\nvar_n = int(var_n)\nvar_o = int(var_o)\nfor i, elem in enumerate(range(var_o)):\n    var_p = var_p * (var_n-i)\nvar_q = var_k * var_p\nvar_r = var_g - var_q\nprint(int(var_r))"
    },
    "14": {
        "category": "Possibility",
        "question_ko": "애벌레 3마리가 양갈래 길을 마주했습니다. 각 애벌레는 왼쪽 길과 오른쪽 길 중 하나를 골라야 합니다. 마지막 애벌레가 왼쪽 길을 선택하는 경우의 수를 구하시오.",
        "question_en": "Three caterpillars came across a forked road. Each caterpillar must choose the path between left and right. Find the number of ways the last caterpillar chooses the left path.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "2 2 [OP_MUL]",
        "solution_abst_en": "2 2 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "15": {
        "category": "Possibility",
        "question_ko": "과자 가게의 사장님이 행사로, 1, 7, 0을 모두 한 번씩 사용해서 만든 세 자리 숫자 만큼 과자를 준다고 했습니다. 하늘이는 어떤 수를 만들어야 과자를 가장 많이 받을 수 있을까요?",
        "question_en": "The owner of the snack shop said that for a special occasion, he would give out cookies equal to the three-digit number made by using 1, 7, and 0 all at least once. What number should Haneul make to receive the most sweets?",
        "answer_ko": "710",
        "answer_en": "710",
        "solution_abst_ko": "[OP_LIST_SOL] 7 1 0 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 7 1 0 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 7\nvar_b = 1\nvar_c = 0\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))",
        "solution_code_en": "var_a = 7\nvar_b = 1\nvar_c = 0\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))"
    },
    "16": {
        "category": "Comparison",
        "question_ko": "정국이가 5등입니다. 정국이보다 결승선을 빨리 통과한 사람의 수를 구하세요.",
        "question_en": "Jungkook is the 5th place. Find the number of people who crossed the finish line faster than Jungkook.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "5 1 [OP_SUB]",
        "solution_abst_en": "5 1 [OP_SUB]",
        "solution_code_ko": "var_a = 5\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "17": {
        "category": "Geometry",
        "question_ko": "어떤 평행사변형을 잘라서 사다리꼴 모양을 만들었는데, 아랫변의 길이가 윗변보다 4센티미터(㎝) 더 길다. 윗변의 길이가 12센티미터(㎝)이고, 높이가 10센티미터(㎝)라면, 이 사다리꼴의 넓이는 몇입니까?",
        "question_en": "A parallelogram was cut to form a trapezoid, the lower side being 4 centimeters (cm) longer than the upper side. If the upper side is 12 centimeters (cm) and the height is 10 centimeters (cm), how much is the area of this trapezoid?",
        "answer_ko": "140",
        "answer_en": "140",
        "solution_abst_ko": "12 12 4 [OP_ADD] [OP_ADD] 10 [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "12 12 4 [OP_ADD] [OP_ADD] 10 [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 12\nvar_c = 4\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nvar_f = 10\nvar_g = var_e * var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 12\nvar_b = 12\nvar_c = 4\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nvar_f = 10\nvar_g = var_e * var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "18": {
        "category": "Possibility",
        "question_ko": "1, 3, 5, 7, 9 다섯 장의 숫자카드가 있다. 이 카드를 사용하여 만들 수 있는 3자리 자연수 중 500미만인 수 중 2번째로 큰 값은 얼마인지 구하시오. (단, 카드는 중복사용 가능하다.)",
        "question_en": "There are five cards of numbers 1, 3, 5, 7, and 9. What is the second largest number less than 500 of the three-digit natural numbers that can be created using this card? (However, a card can be used repeatedly.)",
        "answer_ko": "397",
        "answer_en": "397",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 5 7 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 500 [OP_LIST_LESS] 2 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 5 7 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 500 [OP_LIST_LESS] 2 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 5\nvar_d = 7\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 500\nlist_c = []\nfor i in list_b:\n    if i < var_g:\n        list_c.append(i)\nvar_h = 2\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 5\nvar_d = 7\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 500\nlist_c = []\nfor i in list_b:\n    if i < var_g:\n        list_c.append(i)\nvar_h = 2\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nprint(int(var_i))"
    },
    "19": {
        "category": "Geometry",
        "question_ko": "A 농장은 가로 6킬로미터(㎞), 세로 9킬로미터(㎞)인 직사각형 모양이고, B 농장은 가로 8킬로미터(㎞), 세로 8킬로미터(㎞)인 정사각형 모양입니다. 두 농장의 주인 모두 같은 길이의 나무판자를 여러 개를 이어 붙여서 농장 둘레를 따라 울타리를 설치하려고 합니다. 어느 농장이 나무판자를 더 많이 필요로 합니까?",
        "question_en": "Farm A has a rectangular shape measuring 6 kilometers (km) by 9 kilometers (km), and Farm B has a square shape measuring 8 kilometers (km) by 8 km by 8 kilometers (km). The owners of both farms want to build a fence around the perimeter of the farm by putting together wooden planks of the same length. Which farm needs more planks?",
        "answer_ko": "B",
        "answer_en": "B",
        "solution_abst_ko": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 6 9 [OP_ADD] 8 8 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 6 9 [OP_ADD] 8 8 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 9\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = 8\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 9\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = 8\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "20": {
        "category": "Arithmetic calculation",
        "question_ko": "환율은 자기나라 돈과 다른나라 돈의 교환 비율을 말합니다. 수정이는 미국 여행을 다녀와서 남은 돈 140달러를 오늘 은행에 가서 우리나라 돈 158760원으로 교환 하였습니다. 오늘 미국 돈 달러에 대한 우리나라 돈 원의 환율은 얼마입니까?",
        "question_en": "The exchange rate refers to the rate at which one country's currency is exchanged for another country's currency. Soojeong came back from a trip to the U.S. and exchanged the remaining 140 dollars for 158,760 won in Korean money at the bank today. What is the exchange rate of the Korean Won to the US Dollar today?\n",
        "answer_ko": "1134",
        "answer_en": "1134",
        "solution_abst_ko": "158760 140 [OP_DIV]",
        "solution_abst_en": "158760 140 [OP_DIV]",
        "solution_code_ko": "var_a = 158760\nvar_b = 140\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 158760\nvar_b = 140\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "21": {
        "category": "Comparison",
        "question_ko": "지안이 가방에는 공책이 3권, 도윤이 가방에는 공책이 5권, 시우 가방에는 공책이 2권있습니다. 공책이 2번째로 많은 사람은 누구인가요?",
        "question_en": "Jian has 3 notebooks in his bag, Doyun has 5 notebooks in his bag, and Siu has 2 notebooks in his bag. Who has the second most notebooks?",
        "answer_ko": "지안",
        "answer_en": "Jian",
        "solution_abst_ko": "[OP_LIST_SOL] 지안 도윤 시우 [OP_LIST_EOL] [OP_LIST_SOL] 3 5 2 [OP_LIST_EOL] 2 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] 지안 도윤 시우 [OP_LIST_EOL] [OP_LIST_SOL] 3 5 2 [OP_LIST_EOL] 2 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '지안'\nvar_b = '도윤'\nvar_c = '시우'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nvar_e = 5\nvar_f = 2\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = '지안'\nvar_b = '도윤'\nvar_c = '시우'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nvar_e = 5\nvar_f = 2\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "22": {
        "category": "Correspondence",
        "question_ko": "승연이는 리본 테이프로 상자를 포장하고 있다. 전체 길이가 82.04미터(m)인 리본 테이프로 똑같은 상자 28개를 포장하고 남은 테이프가 없다고 할 때 한 상자를 포장하는데 몇 미터(m)의 리본테이프를 사용해야하는가?",
        "question_en": "Seungyeon is wrapping the box with ribbon tape. If 28 identical boxes are wrapped with the ribbon tape that is 82.04 meters (m) long and there should be no tape left after wrapping, how many meters (m) of ribbon tape are needed to wrap one box?",
        "answer_ko": "2.93",
        "answer_en": "2.93",
        "solution_abst_ko": "82.04 28 [OP_DIV]",
        "solution_abst_en": "82.04 28 [OP_DIV]",
        "solution_code_ko": "var_a = 82.04\nvar_b = 28\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 82.04\nvar_b = 28\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "23": {
        "category": "Comparison",
        "question_ko": "네 학생 지민, 윤기, 태형, 남준이의 나이는 모두 다릅니다. 윤기가 남준이 보다 나이가 많고, 지민이는 태형이보다 나이가 많지만 남준이보다는 적습니다. 4사람 중 가장 어린 사람은 누구입니까?",
        "question_en": "The four students, Jimin, Yoongi, Taehyung, and Namjoon, are of different ages. Yoongi is older than Namjoon, and Jimin is older than Taehyung but younger than Namjoon. Who is the youngest among the 4 people?",
        "answer_ko": "태형",
        "answer_en": "Taehyung",
        "solution_abst_ko": "[OP_LIST_SOL] 지민 윤기 태형 남준 [OP_LIST_EOL] [OP_LIST_SOL] 지민 태형 > 지민 남준 < 윤기 남준 > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jimin Yoongi Taehyung Namjoon [OP_LIST_EOL] [OP_LIST_SOL] Jimin Taehyung > Jimin Namjoon < Yoongi Namjoon > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '지민'\nvar_b = '윤기'\nvar_c = '태형'\nvar_d = '남준'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '지민'\nvar_f = '태형'\nvar_g = '>'\nvar_h = '지민'\nvar_i = '남준'\nvar_j = '<'\nvar_k = '윤기'\nvar_l = '남준'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)",
        "solution_code_en": "var_a = 'Jimin'\nvar_b = 'Yoongi'\nvar_c = 'Taehyung'\nvar_d = 'Namjoon'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'Jimin'\nvar_f = 'Taehyung'\nvar_g = '>'\nvar_h = 'Jimin'\nvar_i = 'Namjoon'\nvar_j = '<'\nvar_k = 'Yoongi'\nvar_l = 'Namjoon'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)"
    },
    "24": {
        "category": "Comparison",
        "question_ko": "어느 나라에 총 3개의 섬이 있습니다. 각 섬에는 12척의 배를 가지고 있고, 각 배마다 일하는 선원의 수는 24명으로 같습니다. 이 나라의 모든 섬에서 일하고 있는 선원의 수를 구하시오.",
        "question_en": "A country has a total of 3 islands. Each island has 12 ships, and each ship has 24 crew members. Find the number of crew members working on all the islands in this country.",
        "answer_ko": "864",
        "answer_en": "864",
        "solution_abst_ko": "3 12 [OP_MUL] 24 [OP_MUL]",
        "solution_abst_en": "3 12 [OP_MUL] 24 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 24\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 3\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 24\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "25": {
        "category": "Possibility",
        "question_ko": "10보다 작은 자연수 중에서 서로 다른 세 수를 동시에 뽑으려고 합니다. 세 수의 합이 14인 경우의 수를 구하시오.",
        "question_en": "We want to simultaneously draw three different numbers from among the natural numbers less than 10. Find the number of ways in which the sum of three numbers is 14.",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "1 10 1 [OP_SUB] 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 14 [OP_LIST_LESS_EQUAL] 14 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "1 10 1 [OP_SUB] 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 14 [OP_LIST_LESS_EQUAL] 14 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 10\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_g = 0\n    i = int(i)\n    while i//10 > 0:\n        var_g = var_g + i%10\n        i = i//10\n    var_g = var_g + i%10\n    list_c.append(var_g)\nvar_h = 14\nlist_d = []\nfor i in list_c:\n    if i <= var_h:\n        list_d.append(i)\nvar_i = 14\nlist_e = []\nfor i in list_d:\n    if i >= var_i:\n        list_e.append(i)\nvar_j = len(list_e)\nprint(int(var_j))",
        "solution_code_en": "var_a = 1\nvar_b = 10\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_g = 0\n    i = int(i)\n    while i//10 > 0:\n        var_g = var_g + i%10\n        i = i//10\n    var_g = var_g + i%10\n    list_c.append(var_g)\nvar_h = 14\nlist_d = []\nfor i in list_c:\n    if i <= var_h:\n        list_d.append(i)\nvar_i = 14\nlist_e = []\nfor i in list_d:\n    if i >= var_i:\n        list_e.append(i)\nvar_j = len(list_e)\nprint(int(var_j))"
    },
    "26": {
        "category": "Arithmetic calculation",
        "question_ko": "올해 어머니는 43살입니다. 몇 년 전에는 현재 11살인 딸의 나이에 5를 곱하면 어머니의 나이였습니다. 몇 년 전인지 구하시오.",
        "question_en": "My mother is 43 years old this year. A few years ago, her age was five times her daughter's age, who is 11 years old this year. Find how many years ago it was.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "5 11 [OP_MUL] 43 [OP_SUB] 5 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "5 11 [OP_MUL] 43 [OP_SUB] 5 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 5\nvar_b = 11\nvar_c = var_a * var_b\nvar_d = 43\nvar_e = var_c - var_d\nvar_f = 5\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 5\nvar_b = 11\nvar_c = var_a * var_b\nvar_d = 43\nvar_e = var_c - var_d\nvar_f = 5\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "27": {
        "category": "Geometry",
        "question_ko": "유란이는 가로가 9센티미터(㎝), 세로가 4센티미터(㎝), 높이가 7센티미터(㎝)인 선물 상자를 사려고 합니다. 유란이가 사려고 하는 선물 상자의 부피는 몇 세제곱센티미터(㎤)입니까?",
        "question_en": "Yuran wants to buy a gift box that is 9 centimeters (cm) wide, 4 centimeters (cm) long, and 7 centimeters (cm) high. What is the volume in cubic centimeters (cm) of the gift box Yuran is buying?",
        "answer_ko": "252",
        "answer_en": "252",
        "solution_abst_ko": "9 4 [OP_MUL] 7 [OP_MUL]",
        "solution_abst_en": "9 4 [OP_MUL] 7 [OP_MUL]",
        "solution_code_ko": "var_a = 9\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "28": {
        "category": "Comparison",
        "question_ko": "정국, 지민, 석진, 태형, 남준이가 나란히 서 있습니다. 정국이는 지민이의 오른쪽 옆에 나란히 서 있고, 석진이는 지민이의 왼쪽 옆에 서 있습니다. 또 남준이는 석진이의 왼쪽 옆에 서 있고, 태형이의 왼쪽 옆에는 정국이가 서 있습니다. 가장 오른쪽에 서 있는 사람은 누구입니까?",
        "question_en": "Jungkook, Jimin, Seokjin, Taehyung, and Namjoon are standing side by side. Jungkook is standing next to Jimin's right side, and Seokjin is standing next to Jimin's left side. Also, Namjoon is standing to the left of Seokjin, and Jungkook is standing to the left of Taehyung. Who's standing on the furthest right?",
        "answer_ko": "태형",
        "answer_en": "Taehyung",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 지민 석진 태형 남준 [OP_LIST_EOL] [OP_LIST_SOL] 정국 지민 > 석진 지민 < 남준 석진 < 정국 태형 < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Jimin Seokjin Taehyung Namjoon [OP_LIST_EOL] [OP_LIST_SOL] Jungkook Jimin > Seokjin Jimin < Namjoon Seokjin < Jungkook Taehyung < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '지민'\nvar_c = '석진'\nvar_d = '태형'\nvar_e = '남준'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = '정국'\nvar_g = '지민'\nvar_h = '>'\nvar_i = '석진'\nvar_j = '지민'\nvar_k = '<'\nvar_l = '남준'\nvar_m = '석진'\nvar_n = '<'\nvar_o = '정국'\nvar_p = '태형'\nvar_q = '<'\nlist_b= []\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_r = 1\nvar_s = list_c[var_r-1]\nprint(var_s)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Jimin'\nvar_c = 'Seokjin'\nvar_d = 'Taehyung'\nvar_e = 'Namjoon'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 'Jungkook'\nvar_g = 'Jimin'\nvar_h = '>'\nvar_i = 'Seokjin'\nvar_j = 'Jimin'\nvar_k = '<'\nvar_l = 'Namjoon'\nvar_m = 'Seokjin'\nvar_n = '<'\nvar_o = 'Jungkook'\nvar_p = 'Taehyung'\nvar_q = '<'\nlist_b= []\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_r = 1\nvar_s = list_c[var_r-1]\nprint(var_s)"
    },
    "29": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 14를 곱하였더니 458.64가 되었습니다. 어떤 수를 17로 나누었을 때의 나머지를 반올림하여 소수 둘째 자리까지 나타내시오.",
        "question_en": "When a number is multiplied by 14, it is 458.64. When a number is divided by 17, round the remainder to two decimal places.",
        "answer_ko": "15.76",
        "answer_en": "15.76",
        "solution_abst_ko": "458.64 14 [OP_DIV] 17 [OP_MOD] 2 [OP_ROUND]",
        "solution_abst_en": "458.64 14 [OP_DIV] 17 [OP_MOD] 2 [OP_ROUND]",
        "solution_code_ko": "var_a = 458.64\nvar_b = 14\nvar_c = var_a / var_b\nvar_d = 17\nvar_e = var_c % var_d\nvar_f = 2\nvar_g = round(float(var_e)+1e-10, var_f)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 458.64\nvar_b = 14\nvar_c = var_a / var_b\nvar_d = 17\nvar_e = var_c % var_d\nvar_f = 2\nvar_g = round(float(var_e)+1e-10, var_f)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "30": {
        "category": "Arithmetic calculation",
        "question_ko": "형규는 매일 줄넘기 215회를 넘습니다. 태우는 형규가 하는 줄넘기 횟수의 0.32배를 넘는다면 태우의 하루 줄넘기 횟수는 몇 회입니까?",
        "question_en": "Hyunggyu jumps rope 215 times every day. If Taewoo jumps 0.32 times the number of rope jumps made by Hyeonggyu, how many times does Taewoo jump rope a day?",
        "answer_ko": "68.80",
        "answer_en": "68.8",
        "solution_abst_ko": "215 0.32 [OP_MUL]",
        "solution_abst_en": "215 0.32 [OP_MUL]",
        "solution_code_ko": "var_a = 215\nvar_b = 0.32\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 215\nvar_b = 0.32\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "31": {
        "category": "Correspondence",
        "question_ko": "서로 다른 두 수 A, B가 있습니다. 두 자리 수끼리의 뺄셈식 9A-B4=34에서 B를 구하시오.",
        "question_en": "There are two different numbers A and B. Find B from the two-digit subtraction equation, 9A-B4=34.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "9A-B4=34 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "9A-B4=34 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '9A-B4=34'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '9A-B4=34'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "32": {
        "category": "Possibility",
        "question_ko": "1, 3, 6, 7 중에서 서로 다른 숫자 3개를 사용하여 만들 수 있는 세 자리 수는 모두 몇 개입니까?",
        "question_en": "How many three-digit numbers can you make from three different numbers of the numbers 1, 3, 6, and 7?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 6 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 6 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 6\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 6\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "33": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 30센티미터(㎝)인 리본이 있습니다. 리본 15개를 묶어서 긴 리본을 하나 만들었습니다. 리본을 묶는데 2센티미터(㎝)가 사용된다고 할 때, 만든 리본의 길이는 얼마입니까?",
        "question_en": "There are pieces of ribbon each of which is 30 centimeters (cm) long. I tied 15 pieces of ribbon to each other to make a long piece of ribbon. If 2 centimeters (cm) of a piece of ribbon is used to tie the ribbon, what is the length of the piece of ribbon made?",
        "answer_ko": "422",
        "answer_en": "422",
        "solution_abst_ko": "30 15 [OP_MUL] 15 1 [OP_SUB] 2 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "30 15 [OP_MUL] 15 1 [OP_SUB] 2 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 30\nvar_b = 15\nvar_c = var_a * var_b\nvar_d = 15\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_c - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 30\nvar_b = 15\nvar_c = var_a * var_b\nvar_d = 15\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_c - var_h\nprint(int(var_i))"
    },
    "34": {
        "category": "Correspondence",
        "question_ko": "32×A×A×A=42592를 만족하는 A를 구하시오",
        "question_en": "Find A that satisfies 32×A×A×A=42592",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "32×A×A×A=42592 A [OP_NUM_UNK_SOLVER]",
        "solution_abst_en": "32×A×A×A=42592 A [OP_NUM_UNK_SOLVER]",
        "solution_code_ko": "var_a = '32×A×A×A=42592'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '32×A×A×A=42592'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "35": {
        "category": "Arithmetic calculation",
        "question_ko": "분홍 토끼와 하양 토끼가 경주를 한다. 분홍 토끼는 시속 15킬로미터(㎞)의 속도로 달렸고, 하양 토끼는 시속 10킬로미터(㎞)의 속도로 달렸는데 분홍 토끼보다 30분 늦게 도착했다. 분홍 토끼가 도착할때 까지 걸린 시간을 구하시오.",
        "question_en": "A pink rabbit and a white rabbit is running a race. The pink rabbit ran at a speed of 15 kilometers per hour (km), and the white rabbit ran at a speed of 10 kilometers per hour (km), arriving 30 minutes later than the pink rabbit. Find the time it took for the pink rabbit to arrive.",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "10 30 60 [OP_DIV] [OP_MUL] 15 10 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "10 30 60 [OP_DIV] [OP_MUL] 15 10 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 30\nvar_c = 60\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 15\nvar_g = 10\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 30\nvar_c = 60\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 15\nvar_g = 10\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "36": {
        "category": "Arithmetic calculation",
        "question_ko": "태형이는 시속 60킬로미터(㎞)의 오토바이를 타고 300킬로미터(㎞) 떨어진 할머니댁에 가려고 합니다. 태형이가 출발한 지 2시간이 지났을 때 더 가야할 거리는 얼마인지 구하세요.",
        "question_en": "Taehyung is trying to get to his grandmother's house, which is 300 kilometers (km) away on a motorcycle at 60 kilometers (km) per hour. Find how far Taehyung needs to go when 2 hours have passed since he left.",
        "answer_ko": "180",
        "answer_en": "180",
        "solution_abst_ko": "300 60 2 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "300 60 2 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 300\nvar_b = 60\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 300\nvar_b = 60\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "37": {
        "category": "Arithmetic calculation",
        "question_ko": "태형이는 사탕 45개를 가지고 있습니다. 친구들에게 사탕을 5개씩 나누어 주면 몇 명의 친구들에게 나누어 줄 수 있습니까?",
        "question_en": "Taehyung has 45 candies. If he plans to give 5 candies to his friends, how many friends can get candies in maximum?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "45 5 [OP_FDIV]",
        "solution_abst_en": "45 5 [OP_FDIV]",
        "solution_code_ko": "var_a = 45\nvar_b = 5\nvar_c = var_a // var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 45\nvar_b = 5\nvar_c = var_a // var_b\nprint(int(var_c))"
    },
    "38": {
        "category": "Possibility",
        "question_ko": "숫자 카드 1, 3, 5, 6을 한 번씩 사용하여 만들 수 있는 네 자리 수 중 4의 배수는 모두 몇 개인가?",
        "question_en": "How many multiples of 4 are there among the four-digit numbers made using the number cards 1, 3, 5, and 6 once?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 5 6 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 4 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 5 6 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 4 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 5\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 4\nlist_c = []\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nvar_g = len(list_c)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 5\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 4\nlist_c = []\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nvar_g = len(list_c)\nprint(int(var_g))"
    },
    "39": {
        "category": "Possibility",
        "question_ko": "쥐, 소, 호랑이, 토끼, 용, 뱀 중 쥐의 위치는 맨 앞에, 뱀의 위치는 맨 뒤에 세워놓은 뒤 나머지를 한 줄로 세우는 경우의 수를 구하시오.",
        "question_en": "Among Rat, Cow, Tiger, Rabbit, Dragon, and Snake, find the number of cases in which the rat is placed at the very front, the snake at the very back, and the rest are placed in one line.",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "[OP_LIST_SOL] 쥐 소 호랑이 토끼 용 뱀 [OP_LIST_EOL] [OP_LIST_SOL] 쥐 [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_SOL] 뱀 [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] Rat Cow Tiger Rabbit Dragon Snake [OP_LIST_EOL] [OP_LIST_SOL] Rat [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_SOL] Snake [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM]",
        "solution_code_ko": "var_a = '쥐'\nvar_b = '소'\nvar_c = '호랑이'\nvar_d = '토끼'\nvar_e = '용'\nvar_f = '뱀'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = '쥐'\nlist_b= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_h = '뱀'\nlist_d= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_d.append(var_h)\nlist_d.reverse()\nlist_e = list(set(list_c) - set(list_d))\nvar_i = len(list_e)\nvar_j = len(list_e)\nvar_k = 1\nvar_i = int(var_i)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_i-i)\nprint(int(var_k))",
        "solution_code_en": "var_a = 'Rat'\nvar_b = 'Cow'\nvar_c = 'Tiger'\nvar_d = 'Rabbit'\nvar_e = 'Dragon'\nvar_f = 'Snake'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 'Rat'\nlist_b= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_h = 'Snake'\nlist_d= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_d.append(var_h)\nlist_d.reverse()\nlist_e = list(set(list_c) - set(list_d))\nvar_i = len(list_e)\nvar_j = len(list_e)\nvar_k = 1\nvar_i = int(var_i)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_i-i)\nprint(int(var_k))"
    },
    "40": {
        "category": "Arithmetic calculation",
        "question_ko": "1킬로미터(㎞)를 달리는 데 휘발유 0.14리터(L)가 필요한 자동차로 1시간에 93.6킬로미터(㎞)씩 2시간 30분 동안 달렸습니다. 사용한 휘발유는 모두 몇 리터(L)일까요?",
        "question_en": "A car that requires 0.14 liters (l) of gasoline to run 1 kilometer (km) ran for 2 hours and 30 minutes at 93.6 kilometers (km) per hour. How many liters of gasoline did it use?",
        "answer_ko": "32.76",
        "answer_en": "32.76",
        "solution_abst_ko": "0.14 93.6 [OP_MUL] 2 30 60 [OP_DIV] [OP_ADD] [OP_MUL]",
        "solution_abst_en": "0.14 93.6 [OP_MUL] 2 30 60 [OP_DIV] [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 0.14\nvar_b = 93.6\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = 30\nvar_f = 60\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = var_c * var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 0.14\nvar_b = 93.6\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = 30\nvar_f = 60\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = var_c * var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "41": {
        "category": "Possibility",
        "question_ko": "5명의 서로 다른 사람이 있다. 모두가 임원을 하고 싶어해서 회장 1명, 부회장 1명, 총무 1명, 서기 1명, 관리부장 1명을 하기로 했다. 이렇게 5명을 뽑을 때 경우의 수를 구하여라.",
        "question_en": "There are 5 different people. Everyone wanted to be an executive, so you decided to have 1 chairman, 1 vice-president, 1 secretary, 1 secretary, and 1 manager. Find the possible number of cases for assigning the position.",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "5 1 1 [OP_ADD] 1 [OP_ADD] 1 [OP_ADD] 1 [OP_ADD] [OP_PERM]",
        "solution_abst_en": "5 1 1 [OP_ADD] 1 [OP_ADD] 1 [OP_ADD] 1 [OP_ADD] [OP_PERM]",
        "solution_code_ko": "var_a = 5\nvar_b = 1\nvar_c = 1\nvar_d = var_b + var_c\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h + var_i\nvar_k = 1\nvar_a = int(var_a)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_a-i)\nprint(int(var_k))",
        "solution_code_en": "var_a = 5\nvar_b = 1\nvar_c = 1\nvar_d = var_b + var_c\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h + var_i\nvar_k = 1\nvar_a = int(var_a)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_a-i)\nprint(int(var_k))"
    },
    "42": {
        "category": "Correspondence",
        "question_ko": "3+6AB=691일 때, B에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "When 3+6AB=691, what number should go in B?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "3+6AB=691 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "3+6AB=691 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '3+6AB=691'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '3+6AB=691'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "43": {
        "category": "Possibility",
        "question_ko": "국어문제집이 2가지 종류, 수학문제집이 4가지 종류가 있다. 이 중에서 한 권을 선택할 때, 국어문제집 또는 수학문제집을 선택하는 경우의 수는?",
        "question_en": "There are two types of Korean language workbooks and four types of math workbooks. When choosing one book among them, in how many cases can you choose Korean workbook or math workbook?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "2 4 [OP_ADD] 1 [OP_COMB]",
        "solution_abst_en": "2 4 [OP_ADD] 1 [OP_COMB]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 1\nvar_c = int(var_c)\nvar_d = int(var_d)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e * (var_c-i)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e / (i+1)\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 1\nvar_c = int(var_c)\nvar_d = int(var_d)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e * (var_c-i)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e / (i+1)\nprint(int(var_e))"
    },
    "44": {
        "category": "Geometry",
        "question_ko": "넓이가 21.12제곱센티미터(㎠)인 정육각형을 여섯 조각으로 나누었습니다. 잘린 조각들의 모양과 크기가 같을 때, 한 조각의 넓이는 몇 제곱센티미터(㎠)일지 구하시오.",
        "question_en": "A regular hexagon with an area of 21.12 square centimeters (cm2) is divided into six pieces. If the cut pieces have the same shape and size, find the area of one piece in square centimeters (cm2).",
        "answer_ko": "3.52",
        "answer_en": "3.52",
        "solution_abst_ko": "21.12 6 [OP_DIV]",
        "solution_abst_en": "21.12 6 [OP_DIV]",
        "solution_code_ko": "var_a = 21.12\nvar_b = 6\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 21.12\nvar_b = 6\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "45": {
        "category": "Correspondence",
        "question_ko": "바둑알이 모두 928개가 있고 흰 바둑알이 713개 있다. 흰 바둑알과 검은 바둑알의 개수는 몇 개가 차이나는지 구하시오.",
        "question_en": "There are a total of 928 baduk stones and 713 of them are colored white. Find the difference between the number of white stones and black stones.",
        "answer_ko": "498",
        "answer_en": "498",
        "solution_abst_ko": "713 928 713 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "713 928 713 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 713\nvar_b = 928\nvar_c = 713\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 713\nvar_b = 928\nvar_c = 713\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "46": {
        "category": "Possibility",
        "question_ko": "0, 3, 4, 6, 8을 한 번씩만 사용하여 만든 가장 작은 두 자리 수에서 어떤 수를 뺐더니 7이 됩니다. 어떤 수는 몇인지 구하시오.",
        "question_en": "The smallest two-digit number that can be formed by two of 0, 3, 4, 6, and 8 is subtracted by a certain number and it became 7. Find the number.",
        "answer_ko": "23",
        "answer_en": "23",
        "solution_abst_ko": "[OP_LIST_SOL] 0 3 4 6 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 7 [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 0 3 4 6 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 7 [OP_SUB]",
        "solution_code_ko": "var_a = 0\nvar_b = 3\nvar_c = 4\nvar_d = 6\nvar_e = 8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = 7\nvar_j = var_h - var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 0\nvar_b = 3\nvar_c = 4\nvar_d = 6\nvar_e = 8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = 7\nvar_j = var_h - var_i\nprint(int(var_j))"
    },
    "47": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 7을 곱하였더니 98이 되었습니다. 어떤 수는 얼마입니까?",
        "question_en": "When you multiply a number by 7, it becomes 98. What is that number?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "98 7 [OP_DIV]",
        "solution_abst_en": "98 7 [OP_DIV]",
        "solution_code_ko": "var_a = 98\nvar_b = 7\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 98\nvar_b = 7\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "48": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중에서 가장 작은 수와 2번째로 작은 수의 차는 얼마입니까?",
        "question_en": "There are three numbers 10, 11, and 12. What is the difference between the smallest number and the second smallest number?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e - var_g\nvar_i = abs(var_h)\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e - var_g\nvar_i = abs(var_h)\nprint(int(var_i))"
    },
    "49": {
        "category": "Arithmetic calculation",
        "question_ko": "농장에 닭은 42마리, 오리는 48마리 있고, 거위는 닭의 수와 같습니다. 오리는 닭과 거위를 합한 것보다 몇 마리 더 적게 있습니까?",
        "question_en": "There are 42 chickens and 48 ducks on the farm, and there are as many geese as there are chickens. How many ducks are fewer than the number of chickens and geese combined?",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "42 42 [OP_ADD] 48 [OP_SUB]",
        "solution_abst_en": "42 42 [OP_ADD] 48 [OP_SUB]",
        "solution_code_ko": "var_a = 42\nvar_b = 42\nvar_c = var_a + var_b\nvar_d = 48\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 42\nvar_b = 42\nvar_c = var_a + var_b\nvar_d = 48\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "50": {
        "category": "Correspondence",
        "question_ko": "어떤 수는 6으로 나눴을때 1/10이 된다. 이때 어떤 수를 3/25로 나눈다면 얼마가 되는가?",
        "question_en": "When a number is divided by 6, it becomes 1/10. What is the value of the number divided by 3/25?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "1/10 6 [OP_MUL] 3/25 [OP_DIV]",
        "solution_abst_en": "1/10 6 [OP_MUL] 3/25 [OP_DIV]",
        "solution_code_ko": "var_a = 0.1\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 0.12\nvar_e = var_c / var_d\nprint(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))",
        "solution_code_en": "var_a = 0.1\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 0.12\nvar_e = var_c / var_d\nprint(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))"
    },
    "51": {
        "category": "Geometry",
        "question_ko": "반지름의 길이가 2센티미터(㎝)인 휴지를 한 변의 길이가 8센티미터(㎝)인 정사각형 상자 안에 겹치지 않게 넣으려고 합니다. 한 층에휴지는 모두 몇 개 넣을 수 있습니까?",
        "question_en": "You want to place tissue paper with a radius of 2 centimeters (cm) inside a square box with a side length of 8 centimeters (cm) without overlapping. How many toilet papers can be put on one floor?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "8 2 2 [OP_MUL] [OP_DIV] 2 [OP_POW]",
        "solution_abst_en": "8 2 2 [OP_MUL] [OP_DIV] 2 [OP_POW]",
        "solution_code_ko": "var_a = 8\nvar_b = 2\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nvar_f = 2\nvar_g = var_e ** var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 8\nvar_b = 2\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nvar_f = 2\nvar_g = var_e ** var_f\nprint(int(var_g))"
    },
    "52": {
        "category": "Correspondence",
        "question_ko": "A3B-41=591입니다. A는 얼마인가요?",
        "question_en": "A3B-41=591. How much is A?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "A3B-41=591 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A3B-41=591 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A3B-41=591'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A3B-41=591'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "53": {
        "category": "Arithmetic calculation",
        "question_ko": "3의 배수이면서 5의 배수인 수 중 가장 작은 두 자리 수는?",
        "question_en": "What is the smallest two-digit number that is a multiple of 3 and a multiple of 5 at the same time?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "10 99 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "10 99 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[var_f-1]\nprint(int(var_g))"
    },
    "54": {
        "category": "Correspondence",
        "question_ko": "23을 뺐어야하는데 잘못하여 32를 어떤 수에서 뺐더니 25가 나왔습니다. 바르게 계산하면 얼마입니까?",
        "question_en": "I should have subtracted 23, but I mistakenly subtracted 32 from some number and got 25. How much do you get when calculated correctly?",
        "answer_ko": "34",
        "answer_en": "34",
        "solution_abst_ko": "25 32 [OP_ADD] 23 [OP_SUB]",
        "solution_abst_en": "25 32 [OP_ADD] 23 [OP_SUB]",
        "solution_code_ko": "var_a = 25\nvar_b = 32\nvar_c = var_a + var_b\nvar_d = 23\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 25\nvar_b = 32\nvar_c = var_a + var_b\nvar_d = 23\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "55": {
        "category": "Geometry",
        "question_ko": "직사각형 모양의 딱지의 넓이는 1.77제곱센티미터(㎠)입니다. 이 딱지의 가로의 길이는 3센티미터(㎝)일 때, 세로의 길이는 몇 센티미터(㎝) 일까요?",
        "question_en": "The rectangular shape of the ttakji's area is 1.77 square centimeters (cm2). If the width of this ttakji is 3 centimeters (cm), how many centimeters (cm) will the length be?",
        "answer_ko": "0.59",
        "answer_en": "0.59",
        "solution_abst_ko": "1.77 3 [OP_DIV]",
        "solution_abst_en": "1.77 3 [OP_DIV]",
        "solution_code_ko": "var_a = 1.77\nvar_b = 3\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 1.77\nvar_b = 3\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "56": {
        "category": "Possibility",
        "question_ko": "1, 3, 4, 7 중 세 개를 뽑아 십의 자리가 3인 세 자리 수를 만들 때, 가장 큰 수와 세 번째로 큰 수의 합을 구하시오.",
        "question_en": "Find the sum of the largest number and the third largest number when selecting three of 1, 3, 4, and 7 to form a three-digit number with 3 in the tens place.",
        "answer_ko": "1171",
        "answer_en": "1171",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 4 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 3 [OP_LIST_SEARCH_FIXED_DIGIT] 1 [OP_LIST_MAX] 3 [OP_LIST_MAX] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 4 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 3 [OP_LIST_SEARCH_FIXED_DIGIT] 1 [OP_LIST_MAX] 3 [OP_LIST_MAX] [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 4\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 3\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nvar_j = 3\nlist_e=list_c.copy()\nlist_e.sort()\nvar_k = list_e[-var_j]\nvar_l = var_i + var_k\nprint(int(var_l))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 4\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 3\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nvar_j = 3\nlist_e=list_c.copy()\nlist_e.sort()\nvar_k = list_e[-var_j]\nvar_l = var_i + var_k\nprint(int(var_l))"
    },
    "57": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 가장 큰 수와 2번째로 작은 수의 합은 얼마입니까?",
        "question_en": "You have five numbers 10, 11, 12, 13, and 14. What is the sum of the largest number and the second smallest number?",
        "answer_ko": "25",
        "answer_en": "25",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))"
    },
    "58": {
        "category": "Arithmetic calculation",
        "question_ko": "14.23을 4.7로 나누었을 때 값을 소수 둘째 자리까지 구하시오.",
        "question_en": "When 14.23 is divided by 4.7, find the value to two decimal places.",
        "answer_ko": "3.03",
        "answer_en": "3.03",
        "solution_abst_ko": "14.23 4.7 [OP_DIV] 2 [OP_ROUND]",
        "solution_abst_en": "14.23 4.7 [OP_DIV] 2 [OP_ROUND]",
        "solution_code_ko": "var_a = 14.23\nvar_b = 4.7\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = round(float(var_c)+1e-10, var_d)\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 14.23\nvar_b = 4.7\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = round(float(var_c)+1e-10, var_d)\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "59": {
        "category": "Arithmetic calculation",
        "question_ko": "2개의 수 4, 5로 나누어 떨어질 수 있는 세 자리 수는 모두 몇 개 있습니까?",
        "question_en": "How many three-digit numbers are divisible by the two numbers - 4 and 5?",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "100 999 1 [OP_LIST_ARANGE] 4 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "100 999 1 [OP_LIST_ARANGE] 4 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 4\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 4\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "60": {
        "category": "Comparison",
        "question_ko": "비가 어제는 135 밀리미터(㎜) 내렸고 오늘은 12 센티미터(㎝) 7 밀리미터(㎜) 내렸습니다. 어제와 오늘 중 비가 더 많이 내린 날은 언제인지 답을 구해 보세요.",
        "question_en": "It rained 135 millimeters (mm) yesterday and 12 centimeters (cm) 7 millimeters (mm) today. Find the answer on which day it rained more between yesterday and today.",
        "answer_ko": "어제",
        "answer_en": "yesterday",
        "solution_abst_ko": "[OP_LIST_SOL] 어제 오늘 [OP_LIST_EOL] [OP_LIST_SOL] 135 12 10 [OP_MUL] 7 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] yesterday today [OP_LIST_EOL] [OP_LIST_SOL] 135 12 10 [OP_MUL] 7 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '어제'\nvar_b = '오늘'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 135\nvar_d = 12\nvar_e = 10\nvar_f = var_d * var_e\nvar_g = 7\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'yesterday'\nvar_b = 'today'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 135\nvar_d = 12\nvar_e = 10\nvar_f = var_d * var_e\nvar_g = 7\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "61": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 2를 곱했더니 18이 되었습니다. 어떤 수에서 4를 빼면 얼마입니까?",
        "question_en": "When you multiply a number by 2, you get 18. What is the value of this number when you subtract 4?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "18 2 [OP_DIV] 4 [OP_SUB]",
        "solution_abst_en": "18 2 [OP_DIV] 4 [OP_SUB]",
        "solution_code_ko": "var_a = 18\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 18\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "62": {
        "category": "Arithmetic calculation",
        "question_ko": "하나의 기계에서 8개의 장난감을 만드는 데 1시간이 걸린다고 합니다. 200개의 장난감을 만들기 위해 5개의 기계를 사용한다면 총 몇 시간이 걸리는지 구하시오.",
        "question_en": "It is said that it takes an hour to make 8 toys from one machine. How many hours would it take to make 200 toys using 5 machines?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "200 8 5 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "200 8 5 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 200\nvar_b = 8\nvar_c = 5\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 200\nvar_b = 8\nvar_c = 5\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "63": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 8을 나눠야 할 것을 잘못하여 6을 곱한 결과는 96이 되었습니다. 바르게 계산한 결과는 얼마인가요?",
        "question_en": "I have to divide a number by 8, but I accidentally multiply a number by 6 is 96. What is the correct calculation result?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "96 6 [OP_DIV] 8 [OP_DIV]",
        "solution_abst_en": "96 6 [OP_DIV] 8 [OP_DIV]",
        "solution_code_ko": "var_a = 96\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 96\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "64": {
        "category": "Possibility",
        "question_ko": "16개 팀이 축구 시합을 하려고 합니다. 두 팀씩 경기를 하여 패배한 팀은 탈락하고 승리한 팀만 다음 경기를 할 수 있으며, 마지막에 승리한 팀이 우승합니다. 경기의 총 횟수를 구하시오.",
        "question_en": "16 teams are about to have a soccer match. Two teams have a game to eliminate the losing team, while only the winning team is allowed to proceed to the next game, and the team who won the last game wins the match. Find the total number of games.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "16 1 [OP_SUB]",
        "solution_abst_en": "16 1 [OP_SUB]",
        "solution_code_ko": "var_a = 16\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 16\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "65": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 11을 곱한 뒤 1을 더하면 45이다. 어떤 수를 구하시오.",
        "question_en": "Multiplying a number by 11 and adding 1 equals 45. Find the number.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "45 1 [OP_SUB] 11 [OP_DIV]",
        "solution_abst_en": "45 1 [OP_SUB] 11 [OP_DIV]",
        "solution_code_ko": "var_a = 45\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 11\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 45\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 11\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "66": {
        "category": "Possibility",
        "question_ko": "카페에 커피는 뜨거운 커피 5종류, 차가운 커피 4종류가 있고 빵은 쿠키가 3종류, 머핀이 5종류가 있다. 커피와 빵을 각각 1개식 주문하는 경우의 수를 구하시오.",
        "question_en": "There are 5 types of hot coffee and 4 types of cold coffee in the cafe, and there are 3 types of cookies and 5 types of muffins. Find the number of cases where you order 1 coffee and 1 bread each.",
        "answer_ko": "72",
        "answer_en": "72",
        "solution_abst_ko": "5 4 [OP_ADD] 3 5 [OP_ADD] [OP_MUL]",
        "solution_abst_en": "5 4 [OP_ADD] 3 5 [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 5\nvar_f = var_d + var_e\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 5\nvar_f = var_d + var_e\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "67": {
        "category": "Geometry",
        "question_ko": "어떤 직육면체 모양의 상자는 가로가 18센티미터(㎝), 세로가 10센티미터(㎝), 높이가 2센티미터(㎝)이다. 이 뚜껑이 없는 상자의 안쪽 전체를 색칠하려면 몇 제곱센티미터(㎠)를 칠해야 하는가?",
        "question_en": "A cuboid box is 18 centimeters (cm) long, 10 centimeters (cm) wide, and 2 centimeters (cm) high. How many square centimeters (cm2) will be covered to paint the entire inside of this uncovered box?",
        "answer_ko": "292",
        "answer_en": "292",
        "solution_abst_ko": "18 10 [OP_MUL] 10 2 [OP_MUL] 2 18 [OP_MUL] [OP_ADD] 2 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "18 10 [OP_MUL] 10 2 [OP_MUL] 2 18 [OP_MUL] [OP_ADD] 2 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 18\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 10\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = 2\nvar_h = 18\nvar_i = var_g * var_h\nvar_j = var_f + var_i\nvar_k = 2\nvar_l = var_j * var_k\nvar_m = var_c + var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 18\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 10\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = 2\nvar_h = 18\nvar_i = var_g * var_h\nvar_j = var_f + var_i\nvar_k = 2\nvar_l = var_j * var_k\nvar_m = var_c + var_l\nprint(int(var_m))"
    },
    "68": {
        "category": "Possibility",
        "question_ko": "학교가 끝난 후 학원까지 3가지의 방법으로 갈 수 있고, 학원에서 놀이터까지 4가지의 방법으로 갈 수 있습니다. 학교에서 학원을 거쳐 놀이터로 가는 방법은 총 몇 가지입니까?",
        "question_en": "You can go to the academy from school in 3 ways, and from the academy to the playground in 4 ways. In total, how many ways are there to get from school to the playground passing the academy?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "3 4 [OP_MUL]",
        "solution_abst_en": "3 4 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "69": {
        "category": "Correspondence",
        "question_ko": "9의 배수인 어떤 수가 있다. 어떤 수를 9로 나눈 몫을 다시 9로 나누었더니 몫이 25이고 나머지가 7이었습니다. 어떤 수를 구하시오.",
        "question_en": "There is a number that is a multiple of 9. The quotient of a number divided by 9 is then divided again by 9, and the quotient is 25 and the remainder is 7. Find the number.",
        "answer_ko": "2088",
        "answer_en": "2088",
        "solution_abst_ko": "25 9 [OP_MUL] 7 [OP_ADD] 9 [OP_MUL]",
        "solution_abst_en": "25 9 [OP_MUL] 7 [OP_ADD] 9 [OP_MUL]",
        "solution_code_ko": "var_a = 25\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c + var_d\nvar_f = 9\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 25\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c + var_d\nvar_f = 9\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "70": {
        "category": "Comparison",
        "question_ko": "학교에서 한국어 시험을 본 결과 태형, 민주, 상민, 윤정, 유정이 순으로 높은 점수를 받았다. 누가 가장 높은 점수를 얻었습니까?",
        "question_en": "As a result of the Korean language test in the school, Taehyung, Minju, Sangmin, Yoonjung, and Yoojung received the highest score in that order. Who got the highest score?",
        "answer_ko": "태형",
        "answer_en": "Taehyung",
        "solution_abst_ko": "[OP_LIST_SOL] 태형 민주 상민 윤정 유정 [OP_LIST_EOL] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Taehyung Minju Sangmin Yoonjung Yoojung [OP_LIST_EOL] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '태형'\nvar_b = '민주'\nvar_c = '상민'\nvar_d = '윤정'\nvar_e = '유정'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nvar_g = list_a[var_f-1]\nprint(var_g)",
        "solution_code_en": "var_a = 'Taehyung'\nvar_b = 'Minju'\nvar_c = 'Sangmin'\nvar_d = 'Yoonjung'\nvar_e = 'Yoojung'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nvar_g = list_a[var_f-1]\nprint(var_g)"
    },
    "71": {
        "category": "Comparison",
        "question_ko": "키가 작은 사람부터 순서대로 9명이 한 줄로 서 있습니다. 호석이가 가장 키가 작습니다. 키가 큰 사람부터 순서대로 다시 줄을 서면 호석이는 앞에서부터 몇 번째에 서게 됩니까?",
        "question_en": "There are 9 people standing in a line from shortest to tallest. Consider Hoseok is the shortest. Then what place does Hoseok take when the line is in order from tallest to shortest?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "9 1 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "9 1 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 9\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "72": {
        "category": "Geometry",
        "question_ko": "한 변이 9센티미터(㎝)인 정사각형의 네 변의 길이의 합은 몇 센티미터(㎝)입니까?",
        "question_en": "What is the sum of the lengths of the four sides of a square with a side of 9 centimeters (cm), in cm (cm)?",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "9 4 [OP_MUL]",
        "solution_abst_en": "9 4 [OP_MUL]",
        "solution_code_ko": "var_a = 9\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 9\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "73": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 12미터(m)인 정팔각형의 둘레는 몇 미터(m)인지 구해 보시오.",
        "question_en": "Find the perimeter of a regular octagon with a side length of 12 meters (m), in meters (m).",
        "answer_ko": "96",
        "answer_en": "96",
        "solution_abst_ko": "12 8 [OP_MUL]",
        "solution_abst_en": "12 8 [OP_MUL]",
        "solution_code_ko": "var_a = 12\nvar_b = 8\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 12\nvar_b = 8\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "74": {
        "category": "Correspondence",
        "question_ko": "A는 1000개씩 묶음이 1개, 100개씩 묶음이 16개, 10개씩 묶음이 28개인 수입니다. B는 355에서 245씩 커지게 3번 뛰어서 센 수입니다. A-B의 값을 구하시오.",
        "question_en": "A is a number comprised of 1 group of 1000, 16 groups of 100, and 28 groups of 10. B is calculated as 3 jumps from 355 with an interval of 245. Find the value of A-B.",
        "answer_ko": "1790",
        "answer_en": "1790",
        "solution_abst_ko": "1000 1 [OP_MUL] 100 16 [OP_MUL] [OP_ADD] 10 28 [OP_MUL] [OP_ADD] 355 245 3 [OP_MUL] [OP_ADD] [OP_SUB]",
        "solution_abst_en": "1000 1 [OP_MUL] 100 16 [OP_MUL] [OP_ADD] 10 28 [OP_MUL] [OP_ADD] 355 245 3 [OP_MUL] [OP_ADD] [OP_SUB]",
        "solution_code_ko": "var_a = 1000\nvar_b = 1\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = 16\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 10\nvar_i = 28\nvar_j = var_h * var_i\nvar_k = var_g + var_j\nvar_l = 355\nvar_m = 245\nvar_n = 3\nvar_o = var_m * var_n\nvar_p = var_l + var_o\nvar_q = var_k - var_p\nprint(int(var_q))",
        "solution_code_en": "var_a = 1000\nvar_b = 1\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = 16\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 10\nvar_i = 28\nvar_j = var_h * var_i\nvar_k = var_g + var_j\nvar_l = 355\nvar_m = 245\nvar_n = 3\nvar_o = var_m * var_n\nvar_p = var_l + var_o\nvar_q = var_k - var_p\nprint(int(var_q))"
    },
    "75": {
        "category": "Arithmetic calculation",
        "question_ko": "우유가 가득 담긴 병의 무게는 1650그램(g)입니다. 이 중 우유의 1/3을 마신 후 병의 무게를 다시 재어 보니 1250그램(g)입니다. 병만의 무게는 몇 그램(g)입니까?",
        "question_en": "A full bottle of milk weighs 1650 grams (g). After drinking 1/3 of the milk, I weighed the bottle again, which was 1250 grams (g). How many grams (g) does the bottle alone weigh?",
        "answer_ko": "450",
        "answer_en": "450",
        "solution_abst_ko": "1650 1650 1250 [OP_SUB] 1 [OP_MUL] 1/3 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "1650 1650 1250 [OP_SUB] 1 [OP_MUL] 1/3 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 1650\nvar_b = 1650\nvar_c = 1250\nvar_d = var_b - var_c\nvar_e = 1\nvar_f = var_d * var_e\nvar_g = 0.3333333333333333\nvar_h = var_f / var_g\nvar_i = var_a - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1650\nvar_b = 1650\nvar_c = 1250\nvar_d = var_b - var_c\nvar_e = 1\nvar_f = var_d * var_e\nvar_g = 0.3333333333333333\nvar_h = var_f / var_g\nvar_i = var_a - var_h\nprint(int(var_i))"
    },
    "76": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 연속하는 홀수 100개의 합을 구하시오",
        "question_en": "Find the sum of 100 consecutive odd numbers from 1.",
        "answer_ko": "10000",
        "answer_en": "10000",
        "solution_abst_ko": "1 100 1 [OP_SUB] 2 [OP_MUL] 1 [OP_ADD] 2 [OP_LIST_ARANGE] [OP_LIST_SUM]",
        "solution_abst_en": "1 100 1 [OP_SUB] 2 [OP_MUL] 1 [OP_ADD] 2 [OP_LIST_ARANGE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 100\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = 2\nlist_a = [i for i in range(var_a, var_h + 1, var_i)]\nlist_a = [float(i) for i in list_a]\nvar_j = sum(list_a)\nprint(int(var_j))",
        "solution_code_en": "var_a = 1\nvar_b = 100\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = 2\nlist_a = [i for i in range(var_a, var_h + 1, var_i)]\nlist_a = [float(i) for i in list_a]\nvar_j = sum(list_a)\nprint(int(var_j))"
    },
    "77": {
        "category": "Correspondence",
        "question_ko": "어떤 수는 10보다 작고, 2의 배수나 3의 배수가 아닙니다. 7, 8, 9, 10 중 어떤 수를 구하시오.",
        "question_en": "A number is less than 10 and is not a multiple of 2 or 3. Which number is it out of 7, 8, 9, or 10?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "[OP_LIST_SOL] 7 8 9 10 [OP_LIST_EOL] 2 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] 3 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] 10 [OP_LIST_LESS] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] 7 8 9 10 [OP_LIST_EOL] 2 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] 3 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] 10 [OP_LIST_LESS] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 7\nvar_b = 8\nvar_c = 9\nvar_d = 10\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = []\nvar_e = int(var_e)\nfor i in list_a:\n    i = int(i)\n    if i % var_e == 0:\n        list_b.append(i)\nlist_c = list(set(list_a) - set(list_b))\nvar_f = 3\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nlist_e = list(set(list_c) - set(list_d))\nvar_g = 10\nlist_f = []\nfor i in list_e:\n    if i < var_g:\n        list_f.append(i)\nvar_h = 1\nvar_i = list_f[var_h-1]\nprint(int(var_i))",
        "solution_code_en": "var_a = 7\nvar_b = 8\nvar_c = 9\nvar_d = 10\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = []\nvar_e = int(var_e)\nfor i in list_a:\n    i = int(i)\n    if i % var_e == 0:\n        list_b.append(i)\nlist_c = list(set(list_a) - set(list_b))\nvar_f = 3\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nlist_e = list(set(list_c) - set(list_d))\nvar_g = 10\nlist_f = []\nfor i in list_e:\n    if i < var_g:\n        list_f.append(i)\nvar_h = 1\nvar_i = list_f[var_h-1]\nprint(int(var_i))"
    },
    "78": {
        "category": "Possibility",
        "question_ko": "주사위를 던져 나온 숫자가 2, 4, 3입니다. 나온 숫자를 한 번씩 모두 사용하여 만든 세 자리 수 중 340보다 작은 수는 모두 몇 개입니까?",
        "question_en": "The dice are rolled and the dots 2, 4, and 3 come out. How many three-digit numbers formed by using all the digits once are less than 340?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 2 4 3 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 340 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 2 4 3 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 340 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = 3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 340\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = 3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 340\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "79": {
        "category": "Arithmetic calculation",
        "question_ko": "600부터 800까지의 짝수들의 각 자리의 숫자를 더하면 얼마인지 구하여라.",
        "question_en": "Find the sum of the digits of the even numbers from 600 to 800.",
        "answer_ko": "1508",
        "answer_en": "1508",
        "solution_abst_ko": "600 800 2 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] [OP_LIST_SUM]",
        "solution_abst_en": "600 800 2 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 600\nvar_b = 800\nvar_c = 2\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_b=[]\nfor i in list_a:\n    var_d = 0\n    i = int(i)\n    while i//10 > 0:\n        var_d = var_d + i%10\n        i = i//10\n    var_d = var_d + i%10\n    list_b.append(var_d)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 600\nvar_b = 800\nvar_c = 2\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_b=[]\nfor i in list_a:\n    var_d = 0\n    i = int(i)\n    while i//10 > 0:\n        var_d = var_d + i%10\n        i = i//10\n    var_d = var_d + i%10\n    list_b.append(var_d)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint(int(var_e))"
    },
    "80": {
        "category": "Correspondence",
        "question_ko": "서윤이네 반 선생님께서 피자를 사주셨다. 서윤이네 반 학생은 모두 7명인데 한 명당 12조각씩 가지고 5조각이 남았다. 이때 서윤이의 옆 반 친구가 놀러와 서윤이의 친구를 포함해서 8명에게 다시 나눠주기로 하였다. 이때 남는 피자 조각의 개수는 몇 조각인지 구하시오.",
        "question_en": "Seoyoon's teacher bought her class pizzas. There were 7 students in Seoyoon's class, and each student took 12 pieces, leaving 5 pieces. At this moment, Seoyoon's neighboring classmate came in to play, so it is decided to distribute the pizza again to 8 people including Seoyoon's friend. Find the number of remaining pizza slices at this time.",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "12 7 [OP_MUL] 5 [OP_ADD] 8 [OP_MOD]",
        "solution_abst_en": "12 7 [OP_MUL] 5 [OP_ADD] 8 [OP_MOD]",
        "solution_code_ko": "var_a = 12\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e % var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 12\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e % var_f\nprint(int(var_g))"
    },
    "81": {
        "category": "Comparison",
        "question_ko": "정국이와 지민이는 계단을 걸어서 3층까지 올라갔습니다. 지민이는 3층에서 엘리베이터를 타고 5층까지 올라갔습니다. 정국이와 지민이 중 더 높이 올라간 사람은 누구입니까?",
        "question_en": "JungKook and Jimin walked up the stairs to the third floor. Jimin took the elevator from the 3rd floor to the 5th floor. Who has risen higher, Jung Kook or Jimin?",
        "answer_ko": "지민",
        "answer_en": "Jimin",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 지민 [OP_LIST_EOL] [OP_LIST_SOL] 3 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Jimin [OP_LIST_EOL] [OP_LIST_SOL] 3 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '지민'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nvar_d = 5\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Jimin'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nvar_d = 5\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "82": {
        "category": "Correspondence",
        "question_ko": "A는 348입니다. A는 B보다 173만큼 작습니다. C는 B보다 299만큼 큽니다. C를 구하시오.",
        "question_en": "A is 348 and A is less than B by 173. C is greater than B by 299. Find C.",
        "answer_ko": "820",
        "answer_en": "820",
        "solution_abst_ko": "348 173 [OP_ADD] 299 [OP_ADD]",
        "solution_abst_en": "348 173 [OP_ADD] 299 [OP_ADD]",
        "solution_code_ko": "var_a = 348\nvar_b = 173\nvar_c = var_a + var_b\nvar_d = 299\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 348\nvar_b = 173\nvar_c = var_a + var_b\nvar_d = 299\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "83": {
        "category": "Comparison",
        "question_ko": "각각의 색이 다른 자동차 20대가 한 줄로 주차되어 있습니다. 검은색 자동차는 오른쪽에서 16번째에 있고, 흰색 자동차는 왼쪽에서 11번째에 있습니다. 검은색 자동차와 흰색 자동차 사이에 있는 자동차는 몇 대입니까?",
        "question_en": "20 cars of different colors are parked in a row. The black car is 16th from the right, and the white car is 11th from the left. How many cars are between the black and white cars?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "16 11 [OP_ADD] 20 [OP_SUB] 2 [OP_SUB]",
        "solution_abst_en": "16 11 [OP_ADD] 20 [OP_SUB] 2 [OP_SUB]",
        "solution_code_ko": "var_a = 16\nvar_b = 11\nvar_c = var_a + var_b\nvar_d = 20\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 16\nvar_b = 11\nvar_c = var_a + var_b\nvar_d = 20\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "84": {
        "category": "Correspondence",
        "question_ko": "1반 학생들의 수는 69명이고 2반 학생들의 수는 86명이다. 1반과 2반 학생들에게 몇 명씩 조를 짜라고 하였더니 1반에서는 5명이 남고 2반에는 6명이 남았다. 한 조에 최대 몇 명이 모일 수 있는지 구하시오.",
        "question_en": "The number of students in Class 1 is 69 and the number of students in Class 2 is 86. When I asked the students in Class 1 and Class 2 to form groups, there were 5 students left in Class 1 and 6 students in Class 2. Find the maximum number of people in a group.",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "69 5 [OP_SUB] 86 6 [OP_SUB] [OP_GCD]",
        "solution_abst_en": "69 5 [OP_SUB] 86 6 [OP_SUB] [OP_GCD]",
        "solution_code_ko": "var_a = 69\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 86\nvar_e = 6\nvar_f = var_d - var_e\nvar_g = math.gcd(int(var_f), int(var_c))\nprint(int(var_g))",
        "solution_code_en": "var_a = 69\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 86\nvar_e = 6\nvar_f = var_d - var_e\nvar_g = math.gcd(int(var_f), int(var_c))\nprint(int(var_g))"
    },
    "85": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 25센티미터(㎝)인 종이띠 30장을 6센티미터(㎝)씩 겹쳐서 한 줄로 길게 이어 붙였습니다. 30장을 이어 붙인 종이띠의 전체 길이는 몇 센티미터(㎝)인지 구해 보시오.",
        "question_en": "Thirty sheets of 25 centimeters (cm) long paper strips were overlapped by 6 centimeters (cm) each and made a long line. Find the total length in centimeters (cm) of the 30 strips of paper glued together.",
        "answer_ko": "576",
        "answer_en": "576",
        "solution_abst_ko": "25 25 6 [OP_SUB] 30 1 [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_abst_en": "25 25 6 [OP_SUB] 30 1 [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 25\nvar_b = 25\nvar_c = 6\nvar_d = var_b - var_c\nvar_e = 30\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_a + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 25\nvar_b = 25\nvar_c = 6\nvar_d = var_b - var_c\nvar_e = 30\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_a + var_h\nprint(int(var_i))"
    },
    "86": {
        "category": "Correspondence",
        "question_ko": "632-5AB=41이 성립하기 위해 A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "What number must go into A to make 632-5AB=41?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "632-5AB=41 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "632-5AB=41 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '632-5AB=41'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '632-5AB=41'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "87": {
        "category": "Comparison",
        "question_ko": "A는 10개씩 3묶음과 낱개가 7개이고, B는 40에서 1을 뺀 수입니다. A, B 중 작은 수는 무엇입니까?",
        "question_en": "A is 3 groups of 10 and 7 individual units, and B is the number obtained by subtracting 1 from 40. Which is smaller, A or B?",
        "answer_ko": "A",
        "answer_en": "A",
        "solution_abst_ko": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 10 3 [OP_MUL] 7 [OP_ADD] 40 1 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 10 3 [OP_MUL] 7 [OP_ADD] 40 1 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10\nvar_d = 3\nvar_e = var_c * var_d\nvar_f = 7\nvar_g = var_e + var_f\nvar_h = 40\nvar_i = 1\nvar_j = var_h - var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[var_k-1]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10\nvar_d = 3\nvar_e = var_c * var_d\nvar_f = 7\nvar_g = var_e + var_f\nvar_h = 40\nvar_i = 1\nvar_j = var_h - var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[var_k-1]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "88": {
        "category": "Geometry",
        "question_ko": "직사각형 모양의 공책과 정사각형 모양의 수첩의 넓이는 같습니다. 공책의 두 변의 길이가 각각 9센티미터(㎝), 16센티미터(㎝)일 때, 수첩의 한 변의 길이는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "A rectangle-shaped notebook and a square-shaped notebook have the same area. If the lengths of the two sides of the notebook are 9 centimeters (cm) and 16 centimeters (cm), respectively. How many centimeters (cm) are the length of one side of the notebook?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "9 16 [OP_MUL] 1/2 [OP_POW]",
        "solution_abst_en": "9 16 [OP_MUL] 1/2 [OP_POW]",
        "solution_code_ko": "var_a = 9\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nprint(int(var_e))"
    },
    "89": {
        "category": "Geometry",
        "question_ko": "둘레가 40센티미터(㎝)인 직사각형이 있습니다. 이 직사각형의 가로 길이가 8센티미터(㎝)일 때 세로는 몇 센티미터(㎝)입니까?",
        "question_en": "You have a rectangle with a perimeter of 40 centimeters (cm). If the width of this rectangle is 8 centimeters (cm), how many centimeters (cm) is the length?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "40 2 [OP_DIV] 8 [OP_SUB]",
        "solution_abst_en": "40 2 [OP_DIV] 8 [OP_SUB]",
        "solution_code_ko": "var_a = 40\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 8\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 40\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 8\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "90": {
        "category": "Possibility",
        "question_ko": "30보다 작은 4의 배수는 모두 몇 개인지 구하세요.",
        "question_en": "Find how many multiples of 4 are less than 30.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "1 30 1 [OP_SUB] 1 [OP_LIST_ARANGE] 4 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "1 30 1 [OP_SUB] 1 [OP_LIST_ARANGE] 4 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 30\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nvar_f = 4\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 30\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nvar_f = 4\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "91": {
        "category": "Arithmetic calculation",
        "question_ko": "개가 9마리, 고양이가 23마리 있습니다. 고양이는 개보다 몇 마리 더 많습니까?",
        "question_en": "There are 9 dogs and 23 cats. How many more cats are there than dogs?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "23 9 [OP_SUB]",
        "solution_abst_en": "23 9 [OP_SUB]",
        "solution_code_ko": "var_a = 23\nvar_b = 9\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 23\nvar_b = 9\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "92": {
        "category": "Arithmetic calculation",
        "question_ko": "사과가 45개 있습니다. 배는 사과보다 21개 적습니다. 배가 귤보다 18개 더 적다면 귤은 몇 개입니까?",
        "question_en": "There are 45 apples. There are 21 fewer pears than apples. How many tangerines are there if there are 18 fewer pears than tangerines?",
        "answer_ko": "42",
        "answer_en": "42",
        "solution_abst_ko": "45 21 [OP_SUB] 18 [OP_ADD]",
        "solution_abst_en": "45 21 [OP_SUB] 18 [OP_ADD]",
        "solution_code_ko": "var_a = 45\nvar_b = 21\nvar_c = var_a - var_b\nvar_d = 18\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 45\nvar_b = 21\nvar_c = var_a - var_b\nvar_d = 18\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "93": {
        "category": "Possibility",
        "question_ko": "서로 다른 책 A, B, C, D, E 5권을 책꽂이에 꽂으려고 한다. A, B, C를 차례로 왼쪽에 꽂을 때, 책을 책꽂이에 꽂는 경우의 수를 구하시오.",
        "question_en": "You want to put 5 different books A, B, C, D, and E on a bookshelf. When A, B, and C are placed on the left side in such order, find the number of ways to place books on the bookshelf.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] A B C D E [OP_LIST_EOL] [OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D E [OP_LIST_EOL] [OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 'A'\nvar_g = 'B'\nvar_h = 'C'\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_i = len(list_c)\nvar_j = len(list_c)\nvar_k = 1\nvar_i = int(var_i)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_i-i)\nprint(int(var_k))",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 'A'\nvar_g = 'B'\nvar_h = 'C'\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_i = len(list_c)\nvar_j = len(list_c)\nvar_k = 1\nvar_i = int(var_i)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_i-i)\nprint(int(var_k))"
    },
    "94": {
        "category": "Comparison",
        "question_ko": "두 명의 학생 윤기, 정국은 각각 7, 6만큼의 숫자를 가지고 있습니다. 누구의 수가 더 작습니까?",
        "question_en": "Two students, Yoongi and Jungkook, have numbers 7 and 6, respectively. Whose number is smaller?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 [OP_LIST_EOL] [OP_LIST_SOL] 7 6 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook [OP_LIST_EOL] [OP_LIST_SOL] 7 6 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 7\nvar_d = 6\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 7\nvar_d = 6\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "95": {
        "category": "Arithmetic calculation",
        "question_ko": "10 이 21 개, 1 이 8 개, 0.1 이 5 개, 0.01 이 34 개인 수는 얼마입니까?",
        "question_en": "10's are 21, 1's are 8, 0.1's are 5, and 0.01's are 34 in a certain number. How much is this number?",
        "answer_ko": "218.84",
        "answer_en": "218.84",
        "solution_abst_ko": "10 21 [OP_MUL] 1 8 [OP_MUL] [OP_ADD] 0.1 5 [OP_MUL] [OP_ADD] 0.01 34 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "10 21 [OP_MUL] 1 8 [OP_MUL] [OP_ADD] 0.1 5 [OP_MUL] [OP_ADD] 0.01 34 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 21\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 8\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 0.1\nvar_i = 5\nvar_j = var_h * var_i\nvar_k = var_g + var_j\nvar_l = 0.01\nvar_m = 34\nvar_n = var_l * var_m\nvar_o = var_k + var_n\nprint('{:.2f}'.format(round(var_o+1e-10,2)))",
        "solution_code_en": "var_a = 10\nvar_b = 21\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 8\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 0.1\nvar_i = 5\nvar_j = var_h * var_i\nvar_k = var_g + var_j\nvar_l = 0.01\nvar_m = 34\nvar_n = var_l * var_m\nvar_o = var_k + var_n\nprint('{:.2f}'.format(round(var_o+1e-10,2)))"
    },
    "96": {
        "category": "Possibility",
        "question_ko": "6, 3, 8이 각각 적힌 숫자 카드 3장이 있을 때, 각 카드를 딱 한 번씩만 사용하여 만들 수 있는 세 자리 수 중에서 가장 큰 수와 가장 작은 수의 합을 구하시오.",
        "question_en": "Given 3 number cards with 6, 3, and 8 written on them, find the sum of the largest and smallest three-digit numbers that can be formed by using each card only once.",
        "answer_ko": "1231",
        "answer_en": "1231",
        "solution_abst_ko": "[OP_LIST_SOL] 6 3 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 6 3 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 3\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 6\nvar_b = 3\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))"
    },
    "97": {
        "category": "Arithmetic calculation",
        "question_ko": "세 자리 수 중 4와 5의 공배수는 모두 몇 개 입니까?",
        "question_en": "How many three-digit numbers are common multiples of 4 and 5?",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "100 999 1 [OP_LIST_ARANGE] 4 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "100 999 1 [OP_LIST_ARANGE] 4 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 4\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 4\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "98": {
        "category": "Arithmetic calculation",
        "question_ko": "예원이는 30초에 180미터(m)를 달리는 빠르기로 달렸다. 1분 동안 예원이가 달린 거리는 몇 미터(m)인가?",
        "question_en": "Yewon ran at a speed of 180 meters (m) in 30 seconds. How many meters (m) did Yewon run in 1 minute?",
        "answer_ko": "360",
        "answer_en": "360",
        "solution_abst_ko": "1 60 [OP_MUL] 30 [OP_DIV] 180 [OP_MUL]",
        "solution_abst_en": "1 60 [OP_MUL] 30 [OP_DIV] 180 [OP_MUL]",
        "solution_code_ko": "var_a = 1\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 30\nvar_e = var_c / var_d\nvar_f = 180\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 30\nvar_e = var_c / var_d\nvar_f = 180\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "99": {
        "category": "Correspondence",
        "question_ko": "5로 나누어떨어지고 5로 나눈 몫이 4인 어떤 수가 있다. 어떤 수에서 10을 빼고 3을 곱한 후 18을 뺀 값을 구하세요.",
        "question_en": "There is a number that is divisible by 5 and the resulting quotient is 4. Subtract 10 from that particular number, and then multiply by 3, and then subtract 18. What is the answer?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "4 5 [OP_MUL] 10 [OP_SUB] 3 [OP_MUL] 18 [OP_SUB]",
        "solution_abst_en": "4 5 [OP_MUL] 10 [OP_SUB] 3 [OP_MUL] 18 [OP_SUB]",
        "solution_code_ko": "var_a = 4\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 10\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = var_e * var_f\nvar_h = 18\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 4\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 10\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = var_e * var_f\nvar_h = 18\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "100": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 7/3을 빼면 3/2이다. 어떤 수에서 7/3을 더하면 얼마인지 구하시오.",
        "question_en": "Subtracting 7/3 from a number equals 3/2. What is the result if you add 7/3 to that number?",
        "answer_ko": "6.17",
        "answer_en": "6.17",
        "solution_abst_ko": "3/2 7/3 [OP_ADD] 7/3 [OP_ADD]",
        "solution_abst_en": "3/2 7/3 [OP_ADD] 7/3 [OP_ADD]",
        "solution_code_ko": "var_a = 1.5\nvar_b = 2.3333333333333335\nvar_c = var_a + var_b\nvar_d = 2.3333333333333335\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 1.5\nvar_b = 2.3333333333333335\nvar_c = var_a + var_b\nvar_d = 2.3333333333333335\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "101": {
        "category": "Correspondence",
        "question_ko": "63은 어떤 수에 39를 더하고 44를 빼야하는데 실수로 44를 더하고 39를 빼서 구한 결과이다. 바르게 계산한 결과를 구하여라.",
        "question_en": "63 is the result of mistakely adding 44 and subtracting 39 when you actually have to add 39 to this certain number and subtract 44. Find the result of the correct calculation.",
        "answer_ko": "53",
        "answer_en": "53",
        "solution_abst_ko": "63 44 [OP_SUB] 39 [OP_ADD] 39 [OP_ADD] 44 [OP_SUB]",
        "solution_abst_en": "63 44 [OP_SUB] 39 [OP_ADD] 39 [OP_ADD] 44 [OP_SUB]",
        "solution_code_ko": "var_a = 63\nvar_b = 44\nvar_c = var_a - var_b\nvar_d = 39\nvar_e = var_c + var_d\nvar_f = 39\nvar_g = var_e + var_f\nvar_h = 44\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 63\nvar_b = 44\nvar_c = var_a - var_b\nvar_d = 39\nvar_e = var_c + var_d\nvar_f = 39\nvar_g = var_e + var_f\nvar_h = 44\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "102": {
        "category": "Possibility",
        "question_ko": "5, 6, 4, 7 중에서 3개를 뽑아 한 번씩만 사용하여 세 자리 수를 만들려고 합니다. 만들 수 있는 가장 큰 수의 각 자리 수의 합을 구하시오.",
        "question_en": "You want to create a three-digit number by selecting three out of 5, 6, 4, and 7 and using them only once. Find the sum of the digits of the largest possible number.",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "[OP_LIST_SOL] 5 6 4 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] [OP_NUM2LIST] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 5 6 4 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] [OP_NUM2LIST] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 5\nvar_b = 6\nvar_c = 4\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nlist_d = []\nvar_g = int(var_g)\nwhile var_g//10 > 0:\n    list_d.append(var_g%10)\n    var_g = var_g//10\nlist_d.append(var_g%10)\nlist_d = list_d[::-1]\nlist_d = [float(i) for i in list_d]\nvar_h = sum(list_d)\nprint(int(var_h))",
        "solution_code_en": "var_a = 5\nvar_b = 6\nvar_c = 4\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nlist_d = []\nvar_g = int(var_g)\nwhile var_g//10 > 0:\n    list_d.append(var_g%10)\n    var_g = var_g//10\nlist_d.append(var_g%10)\nlist_d = list_d[::-1]\nlist_d = [float(i) for i in list_d]\nvar_h = sum(list_d)\nprint(int(var_h))"
    },
    "103": {
        "category": "Comparison",
        "question_ko": "윤기는 4, 정국이는 6에서 3을 나눈 몫을 모았습니다. 더 큰 숫자를 가진 사람은 누구입니까?",
        "question_en": "Yoongi has 4, and Jungkook has a number that is the quotient of 6 divided by 3. Who has the bigger number?",
        "answer_ko": "윤기",
        "answer_en": "Yoongi",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_FDIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_FDIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 6\nvar_e = 3\nvar_f = var_d // var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 6\nvar_e = 3\nvar_f = var_d // var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "104": {
        "category": "Arithmetic calculation",
        "question_ko": "기름통에 들어있는 휘발유의 양이 54리터(L)보다 13밀리리터(㎖) 가벼울 때, 기름통에 들어있는 휘발유의 양을 리터(L)로 구한다면 얼마입니까?",
        "question_en": "If the amount of gasoline in the oil canister is 13 milliliters (ml) lighter than 54 liters (L), what is the amount of gasoline in the oil canister in liters (L)?",
        "answer_ko": "53.99",
        "answer_en": "53.99",
        "solution_abst_ko": "54 13 1000 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "54 13 1000 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 54\nvar_b = 13\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 54\nvar_b = 13\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "105": {
        "category": "Possibility",
        "question_ko": "3, 8, 2, 7의 숫자가 적힌 4 장의 카드를 모두 한 번씩 사용하여 소수 두 자리 수를 만들 때 세 번째로 작은 수를 쓰시오.",
        "question_en": "If you can make a number with two decimal digits that is made by using the numbers 3, 8, 2, and 7 once, write the third smallest number.",
        "answer_ko": "27.38",
        "answer_en": "27.38",
        "solution_abst_ko": "[OP_LIST_SOL] 3 8 2 7 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 3 [OP_LIST_MIN] 10 [OP_LIST_POP] [OP_LIST_LEN] 2 [OP_SUB] [OP_POW] [OP_DIV]",
        "solution_abst_en": "[OP_LIST_SOL] 3 8 2 7 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 3 [OP_LIST_MIN] 10 [OP_LIST_POP] [OP_LIST_LEN] 2 [OP_SUB] [OP_POW] [OP_DIV]",
        "solution_code_ko": "var_a = 3\nvar_b = 8\nvar_c = 2\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = 10\nvar_i = len(list_a)\nvar_j = 2\nvar_k = var_i - var_j\nvar_l = var_h ** var_k\nvar_m = var_g / var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))",
        "solution_code_en": "var_a = 3\nvar_b = 8\nvar_c = 2\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = 10\nvar_i = len(list_a)\nvar_j = 2\nvar_k = var_i - var_j\nvar_l = var_h ** var_k\nvar_m = var_g / var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))"
    },
    "106": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 가장 큰 수와 그 다음으로 큰 수로 나눈 몫은 얼마입니까?",
        "question_en": "There are five numbers 10, 11, 12, 13, and 14. What is the quotient of the largest number divided by the next largest number?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_FDIV]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_FDIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[-var_h]\nvar_j = var_g // var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[-var_h]\nvar_j = var_g // var_i\nprint(int(var_j))"
    },
    "107": {
        "category": "Possibility",
        "question_ko": "0, 2, 4, 6, 8, 9 수 카드를 모두 한 번씩만 사용하여 만들 수 있는 가장 작은 수를 찾으시오",
        "question_en": "Find the smallest number that can be made by using all the number cards 0, 2, 4, 6, 8 and 9 only once.",
        "answer_ko": "204689",
        "answer_en": "204689",
        "solution_abst_ko": "[OP_LIST_SOL] 0 2 4 6 8 9 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 2 4 6 8 9 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 0\nvar_b = 2\nvar_c = 4\nvar_d = 6\nvar_e = 8\nvar_f = 9\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nprint(int(var_i))",
        "solution_code_en": "var_a = 0\nvar_b = 2\nvar_c = 4\nvar_d = 6\nvar_e = 8\nvar_f = 9\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nprint(int(var_i))"
    },
    "108": {
        "category": "Possibility",
        "question_ko": "두 자리수 중 1과 4로 이루어져 있고, 뒤짚었을 때 다른 수가 되는 것은 모두 몇 개입니까?",
        "question_en": "How many two-digit numbers are there which are made up of 1 and 4 and, when flipped, become other numbers?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 1 4 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 4 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 4\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = len(list_b)\nprint(int(var_d))",
        "solution_code_en": "var_a = 1\nvar_b = 4\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = len(list_b)\nprint(int(var_d))"
    },
    "109": {
        "category": "Comparison",
        "question_ko": "호석이는 구슬을 576개 가지고 있고, 윤기는 352개 가지고 있습니다. 호석이가 윤기에게 구슬을 100개 주었을 때, 누가 더 구슬을 많이 가지고 있습니까?",
        "question_en": "Hoseok had 576 marbles, and Yoongi had 352. If Hoseok gives Yoongi 100 marbles, who has more marbles?",
        "answer_ko": "호석",
        "answer_en": "Hoseok",
        "solution_abst_ko": "[OP_LIST_SOL] 호석 윤기 [OP_LIST_EOL] [OP_LIST_SOL] 576 100 [OP_SUB] 352 100 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Hoseok Yoongi [OP_LIST_EOL] [OP_LIST_SOL] 576 100 [OP_SUB] 352 100 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '호석'\nvar_b = '윤기'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 576\nvar_d = 100\nvar_e = var_c - var_d\nvar_f = 352\nvar_g = 100\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Hoseok'\nvar_b = 'Yoongi'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 576\nvar_d = 100\nvar_e = var_c - var_d\nvar_f = 352\nvar_g = 100\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "110": {
        "category": "Geometry",
        "question_ko": "미애는 철사를 사용하여 한 변이 20센티미터(㎝)인 정사각형을 1개 만들었습니다. 이 철사와 똑같은 길이의 철사를 사용하여 태희는 가로가 14센티미터(㎝)인 직사각형을 만들었습니다. 태희가 만든 직사각형의 세로의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "Miae made a square with a side of 20 centimeters (cm) using wire. Using a wire of the same length as this one, Taehee made a rectangle wide 14 centimeters (cm). How many centimeters (cm) is the length of the rectangle Taehee made?",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "20 4 [OP_MUL] 2 [OP_DIV] 14 [OP_SUB]",
        "solution_abst_en": "20 4 [OP_MUL] 2 [OP_DIV] 14 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 14\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 20\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 14\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "111": {
        "category": "Arithmetic calculation",
        "question_ko": "(가) 통에 석유 12리터(L) 400밀리리터(㎖), (나) 통에 석유 7600밀리리터(㎖)가 들어 있습니다. (가) 통과 (나) 통에 들어 있는 석유의 양이 같아지려면 (가) 통에서 (나) 통으로 몇 리터(L)를 옮기면 됩니까?",
        "question_en": "A barrel contains 12 liters (L) and 400 milliliters (㎖) of petroleum, and B barrel contains 7600 milliliters (㎖) of petroleum. How many liters (L) must be moved from A barrel to B barrel to equalize the amount of petroleum in A barrel and B barrel?",
        "answer_ko": "2.40",
        "answer_en": "2.4",
        "solution_abst_ko": "12 400 1000 [OP_DIV] [OP_ADD] 7600 1000 [OP_DIV] [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "12 400 1000 [OP_DIV] [OP_ADD] 7600 1000 [OP_DIV] [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 400\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 7600\nvar_g = 1000\nvar_h = var_f / var_g\nvar_i = var_e - var_h\nvar_j = 2\nvar_k = var_i / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 12\nvar_b = 400\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 7600\nvar_g = 1000\nvar_h = var_f / var_g\nvar_i = var_e - var_h\nvar_j = 2\nvar_k = var_i / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "112": {
        "category": "Arithmetic calculation",
        "question_ko": "태형이는 물 21/11리터(L)를 한 컵에 7/11리터(L)씩 나누어 담고, 호석이는 물 8/17리터(L)를 한 컵에 2/17리터(L)씩 나누어 담으려고 합니다. 태형이와 호석이가 각자 가지고 있는 물을 남김없이 컵에 나누어 담으려면 컵은 모두 몇 개 필요합니까?",
        "question_en": "Taehyung is trying to divide 21/11 liters (L) of water into 7/11 liters (L) per cup, and Hoseok is trying to divide 8/17 liters (L) of water into 2/17 liters (L) per cup. How many cups will Taehyung and Hoseok need in order to divide all the water they each have into the cups?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "21/11 7/11 [OP_DIV] 1 [OP_CEIL] 8/17 2/17 [OP_DIV] 1 [OP_CEIL] [OP_ADD]",
        "solution_abst_en": "21/11 7/11 [OP_DIV] 1 [OP_CEIL] 8/17 2/17 [OP_DIV] 1 [OP_CEIL] [OP_ADD]",
        "solution_code_ko": "var_a = 1.9090909090909092\nvar_b = 0.6363636363636364\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nvar_f = 0.47058823529411764\nvar_g = 0.11764705882352941\nvar_h = var_f / var_g\nvar_i = 1\nvar_j=int(((var_h+9*10**(var_i-2))//(10**(var_i-1)))*10**(var_i-1))\n\nvar_k = var_e + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 1.9090909090909092\nvar_b = 0.6363636363636364\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nvar_f = 0.47058823529411764\nvar_g = 0.11764705882352941\nvar_h = var_f / var_g\nvar_i = 1\nvar_j=int(((var_h+9*10**(var_i-2))//(10**(var_i-1)))*10**(var_i-1))\n\nvar_k = var_e + var_j\nprint(int(var_k))"
    },
    "113": {
        "category": "Arithmetic calculation",
        "question_ko": "딸기가 3 킬로그램(㎏) 300 그램(g) 있었습니다. 그중에서 1 킬로그램(㎏) 900 그램(g)을 친구에게 주었습니다. 남은 딸기는 몇 그램(g)일까요?",
        "question_en": "There were 3 kilograms (kg) and 300 grams (g) of strawberries. Among them, I gave 1 kilogram (kg) 900 grams (g) to a friend. How many grams (g) of strawberries are left?",
        "answer_ko": "1400",
        "answer_en": "1400",
        "solution_abst_ko": "3 1000 [OP_MUL] 300 [OP_ADD] 1 1000 [OP_MUL] 900 [OP_ADD] [OP_SUB]",
        "solution_abst_en": "3 1000 [OP_MUL] 300 [OP_ADD] 1 1000 [OP_MUL] 900 [OP_ADD] [OP_SUB]",
        "solution_code_ko": "var_a = 3\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 300\nvar_e = var_c + var_d\nvar_f = 1\nvar_g = 1000\nvar_h = var_f * var_g\nvar_i = 900\nvar_j = var_h + var_i\nvar_k = var_e - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 3\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 300\nvar_e = var_c + var_d\nvar_f = 1\nvar_g = 1000\nvar_h = var_f * var_g\nvar_i = 900\nvar_j = var_h + var_i\nvar_k = var_e - var_j\nprint(int(var_k))"
    },
    "114": {
        "category": "Comparison",
        "question_ko": "세 명의 학생 윤기, 정국, 유나는 각각 7, 6, 9만큼의 숫자를 가지고 있습니다. 가장 작은 숫자를 가진 사람은 누구입니까?",
        "question_en": "The three students, Yoongi, Jungkook and Yuna, have the numbers 7, 6, and 9 respectively. Who has the smallest number?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 유나 [OP_LIST_EOL] [OP_LIST_SOL] 7 6 9 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook Yuna [OP_LIST_EOL] [OP_LIST_SOL] 7 6 9 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nvar_c = '유나'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 7\nvar_e = 6\nvar_f = 9\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nvar_c = 'Yuna'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 7\nvar_e = 6\nvar_f = 9\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "115": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 2575미터(m)인 도로의 한쪽에 25미터(m) 간격으로 가로수를 심으려고 합니다. 도로 한쪽에 심을 가로수는 몇 그루입니까? (단, 도로의 처음과 끝에도 가로수를 심습니다.)",
        "question_en": "Suppose that street trees are planted on the road that is 2575 meters (m) long at intervals of 25 meters (m). How many street trees will be planted? (However, trees are also planted at the beginning and end of the road.)",
        "answer_ko": "104",
        "answer_en": "104",
        "solution_abst_ko": "2575 25 [OP_DIV] 1 [OP_ADD]",
        "solution_abst_en": "2575 25 [OP_DIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 2575\nvar_b = 25\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 2575\nvar_b = 25\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "116": {
        "category": "Comparison",
        "question_ko": "6개의 사과를 가지고 있던 정국이는 3개의 사과를 더 받았습니다. 윤기는 4개의 사과를 가지고 있을 때, 누가 더 사과를 적게 가지고 있습니까?",
        "question_en": "Jungkook, who had 6 apples, received 3 more. When Yoongi has 4 apples, who has fewer apples?",
        "answer_ko": "윤기",
        "answer_en": "Yoongi",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 윤기 [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_ADD] 4 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Yoongi [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_ADD] 4 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '윤기'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = 4\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Yoongi'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = 4\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "117": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 10으로 나누었더니 6이 되었습니다. 어떤 수에서 15를 빼면?",
        "question_en": "When you divide a particular number by 10, you get 6. What number do you get when you subtract 15 from that particular number?",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "6 10 [OP_MUL] 15 [OP_SUB]",
        "solution_abst_en": "6 10 [OP_MUL] 15 [OP_SUB]",
        "solution_code_ko": "var_a = 6\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 15\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 15\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "118": {
        "category": "Comparison",
        "question_ko": "은비와 재연이는 5일 동안 매일 달리기 연습을 하였습니다. 은비는 5일 동안 총 4.3킬로미터(㎞)를 뛰었고, 재연이는 하루에 900미터(m)씩 매일 뛰었다면, 누가 더 많이 뛰었을지 구하시오.",
        "question_en": "Eunbi and Jaeyeon practiced running every day for five days. If Eunbi ran a total of 4.3 kilometers (km) for 5 days and Jaeyeon ran 900 meters (m) every day, find out who would have run more.",
        "answer_ko": "재연",
        "answer_en": "Jaeyeon",
        "solution_abst_ko": "[OP_LIST_SOL] 은비 재연 [OP_LIST_EOL] [OP_LIST_SOL] 4.3 1000 [OP_MUL] 900 5 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Eunbi Jaeyeon [OP_LIST_EOL] [OP_LIST_SOL] 4.3 1000 [OP_MUL] 900 5 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '은비'\nvar_b = '재연'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4.3\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 900\nvar_g = 5\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Eunbi'\nvar_b = 'Jaeyeon'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4.3\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 900\nvar_g = 5\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "119": {
        "category": "Correspondence",
        "question_ko": "6A5+10B=748입니다. A는 얼마인가요?",
        "question_en": "6A5+10B=748. What is A?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "6A5+10B=748 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "6A5+10B=748 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '6A5+10B=748'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '6A5+10B=748'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "120": {
        "category": "Comparison",
        "question_ko": "상품 당첨 번호는 5개의 수이다. 이들의 평균은 81.6이고, 5개 중 가장 높은 것을 뺀 나머지의 평균은 가장 낮은 것을 뺀 나머지의 평균보다 6이 낮다. 중간 3개의 숫자가 88, 84, 76일 때 가장 높은 수를 구하라.",
        "question_en": "Prize winning numbers are 5 numbers. Their average is 81.6, and the average excluding the hightest number is 6 points smaller than the average excluding the lowest number. When the middle three numbers are 88, 84, and 76, find the highest number. ",
        "answer_ko": "92",
        "answer_en": "92",
        "solution_abst_ko": "81.6 5 [OP_MUL] 88 84 [OP_ADD] 76 [OP_ADD] [OP_SUB] 6 4 [OP_MUL] [OP_ADD] 2 [OP_DIV]",
        "solution_abst_en": "81.6 5 [OP_MUL] 88 84 [OP_ADD] 76 [OP_ADD] [OP_SUB] 6 4 [OP_MUL] [OP_ADD] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 81.6\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 88\nvar_e = 84\nvar_f = var_d + var_e\nvar_g = 76\nvar_h = var_f + var_g\nvar_i = var_c - var_h\nvar_j = 6\nvar_k = 4\nvar_l = var_j * var_k\nvar_m = var_i + var_l\nvar_n = 2\nvar_o = var_m / var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 81.6\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 88\nvar_e = 84\nvar_f = var_d + var_e\nvar_g = 76\nvar_h = var_f + var_g\nvar_i = var_c - var_h\nvar_j = 6\nvar_k = 4\nvar_l = var_j * var_k\nvar_m = var_i + var_l\nvar_n = 2\nvar_o = var_m / var_n\nprint(int(var_o))"
    },
    "121": {
        "category": "Correspondence",
        "question_ko": "여섯 자리 수 7ABABA가 6의 배수일 때, 이러한 여섯 자리 수는 모두 몇 가지나 되는지 구하여라.",
        "question_en": "If the six-digit number 7ABABA is a multiple of 6, find possible numbers that can be made.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "7ABABA [OP_GEN_POSSIBLE_LIST] 6 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "7ABABA [OP_GEN_POSSIBLE_LIST] 6 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '7ABABA'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 6\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))",
        "solution_code_en": "var_a = '7ABABA'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 6\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))"
    },
    "122": {
        "category": "Arithmetic calculation",
        "question_ko": "(가) 기계로 240킬로그램(㎏)의 쌀을 가공하는 데 4일이 걸립니다. (가) 기계로 같은 쌀 1920킬로그램(㎏)을 가공하려면 며칠이 걸립니까?",
        "question_en": "It takes 4 days to process 240 kilograms (kg) of rice with the (A) machine. How many days does it take to process 1920 killograms (kg) of the same rice with the (A) machine?",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "1920 240 4 [OP_DIV] [OP_FDIV]",
        "solution_abst_en": "1920 240 4 [OP_DIV] [OP_FDIV]",
        "solution_code_ko": "var_a = 1920\nvar_b = 240\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 1920\nvar_b = 240\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a // var_d\nprint(int(var_e))"
    },
    "123": {
        "category": "Arithmetic calculation",
        "question_ko": "태형이는 1분 동안 114미터(m)를 걷고, 민영이는 1분 동안 79미터(m)를 걷습니다. 태형이와 민영이가 같은 빠르기로 1시간 동안 걷는다면, 태형이는 민영이보다 몇 미터(m) 더 많이 걷겠습니까?",
        "question_en": "Taehyung walks 114 meters (m) in 1 minute, and Minyoung walks 79 meters (m) in 1 minute. If Taehyung and Minyoung walk at the same pace for an hour, how many meters (m) will Taehyung walk more than Minyoung?",
        "answer_ko": "2100",
        "answer_en": "2100",
        "solution_abst_ko": "114 79 [OP_SUB] 1 [OP_MUL] 60 [OP_MUL]",
        "solution_abst_en": "114 79 [OP_SUB] 1 [OP_MUL] 60 [OP_MUL]",
        "solution_code_ko": "var_a = 114\nvar_b = 79\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c * var_d\nvar_f = 60\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 114\nvar_b = 79\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c * var_d\nvar_f = 60\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "124": {
        "category": "Arithmetic calculation",
        "question_ko": "이모의 나이는 38살입니다. 윤기의 나이는 이모 나이보다 23살 더 적습니다. 호석이의 나이는 윤기 나이보다 4살 더 적습니다. 윤기와 호석이의 나이의 합은 몇 살입니까?",
        "question_en": "Yoongi's aunt is 38 years old. Yoongi is 23 years younger than his aunt. Hoseok is 4 years younger than Yoongi. What is the sum of Yoongi and Hoseok's ages?",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "38 23 [OP_SUB] 38 23 [OP_SUB] 4 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "38 23 [OP_SUB] 38 23 [OP_SUB] 4 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 38\nvar_b = 23\nvar_c = var_a - var_b\nvar_d = 38\nvar_e = 23\nvar_f = var_d - var_e\nvar_g = 4\nvar_h = var_f - var_g\nvar_i = var_c + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 38\nvar_b = 23\nvar_c = var_a - var_b\nvar_d = 38\nvar_e = 23\nvar_f = var_d - var_e\nvar_g = 4\nvar_h = var_f - var_g\nvar_i = var_c + var_h\nprint(int(var_i))"
    },
    "125": {
        "category": "Possibility",
        "question_ko": "서로 다른 숫자 3개를 뽑아 세자리 수를 만들려 한다. 주어진 숫자가 1, 2, 6, 7, 8일때 가장 큰 수에서 가장 작은 수를 뺀 값은 얼마인가?",
        "question_en": "I am trying to make a three-digit number by picking three different numbers. Given the numbers 1, 2, 6, 7, and 8, what is the difference between the largest number and the smallest number?",
        "answer_ko": "750",
        "answer_en": "750",
        "solution_abst_ko": "[OP_LIST_SOL] 1 2 6 7 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 1 2 6 7 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 1\nvar_b = 2\nvar_c = 6\nvar_d = 7\nvar_e = 8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 1\nvar_b = 2\nvar_c = 6\nvar_d = 7\nvar_e = 8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h - var_j\nprint(int(var_k))"
    },
    "126": {
        "category": "Geometry",
        "question_ko": "둘레가 17.8 센티미터(㎝) 인 정사각형이 있습니다. 이 도형의 한 변은 몇 센티미터(㎝) 입니까?",
        "question_en": "You have a square with a perimeter of 17.8 centimeters (cm). How many centimeters (cm) is one side of this figure?",
        "answer_ko": "4.45",
        "answer_en": "4.45",
        "solution_abst_ko": "17.8 4 [OP_DIV]",
        "solution_abst_en": "17.8 4 [OP_DIV]",
        "solution_code_ko": "var_a = 17.8\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 17.8\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "127": {
        "category": "Comparison",
        "question_ko": "통로에는 28개의 동일한 자판기가 있습니다. 각 자판기에는 동일한 수의 음료가 가득 차 있습니다. 자판기에서 밑에서 14번째, 위에서 20번째, 오른쪽에서 3번째, 왼쪽에서 2번째인 음료수를 선택하여 마셨다. 이 통로에 있는 모든 자판기들의 음료수 개수 합을 구하시오.",
        "question_en": "There are 28 identical vending machines in the aisle. Each vending machine is full and has the same number of drinks, and I chose the drink in the 14th from the bottom, 20th from the top, 3rd from the right, and 2nd from the left, and drank it. Find the sum of the number of total drinks in vending machines in this aisle.",
        "answer_ko": "3696",
        "answer_en": "3696",
        "solution_abst_ko": "14 20 [OP_ADD] 1 [OP_SUB] 3 2 [OP_ADD] 1 [OP_SUB] [OP_MUL] 28 [OP_MUL]",
        "solution_abst_en": "14 20 [OP_ADD] 1 [OP_SUB] 3 2 [OP_ADD] 1 [OP_SUB] [OP_MUL] 28 [OP_MUL]",
        "solution_code_ko": "var_a = 14\nvar_b = 20\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nvar_l = 28\nvar_m = var_k * var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 14\nvar_b = 20\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nvar_l = 28\nvar_m = var_k * var_l\nprint(int(var_m))"
    },
    "128": {
        "category": "Comparison",
        "question_ko": "지민, 윤기, 태형, 남준이는 모두 같은 아파트에 살고 있습니다. 태형이는 남준이보다 낮고, 지민이네 집은 윤기보다 높습니다. 윤기는 남준이보다 높을 때, 가장 낮은 층에 살고 있는 사람은 누구입니까?",
        "question_en": "Jimin, Yoongi, Taehyung, and Namjoon all live in the same apartment building. Taehyung's house is lower than Namjoon's, and Jimin's house is higher than Yoongi's. When Yoongi's is higher than Namjoon's, who lives on the lowest floor?",
        "answer_ko": "태형",
        "answer_en": "Taehyung",
        "solution_abst_ko": "[OP_LIST_SOL] 지민 윤기 태형 남준 [OP_LIST_EOL] [OP_LIST_SOL] 지민 윤기 > 태형 남준 < 윤기 남준 > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jimin Yoongi Taehyung Namjoon [OP_LIST_EOL] [OP_LIST_SOL] Jimin Yoongi > Taehyung Namjoon < Yoongi Namjoon > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '지민'\nvar_b = '윤기'\nvar_c = '태형'\nvar_d = '남준'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '지민'\nvar_f = '윤기'\nvar_g = '>'\nvar_h = '태형'\nvar_i = '남준'\nvar_j = '<'\nvar_k = '윤기'\nvar_l = '남준'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)",
        "solution_code_en": "var_a = 'Jimin'\nvar_b = 'Yoongi'\nvar_c = 'Taehyung'\nvar_d = 'Namjoon'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'Jimin'\nvar_f = 'Yoongi'\nvar_g = '>'\nvar_h = 'Taehyung'\nvar_i = 'Namjoon'\nvar_j = '<'\nvar_k = 'Yoongi'\nvar_l = 'Namjoon'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)"
    },
    "129": {
        "category": "Correspondence",
        "question_ko": "등식 A5-2B=68이 성립한다고 합니다. 이 때, A에 들어갈 수 있는 숫자는 무엇인가요?",
        "question_en": "A5-2B=68 is said to be true. At this time, what number can go into A?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "A5-2B=68 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A5-2B=68 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A5-2B=68'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A5-2B=68'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "130": {
        "category": "Arithmetic calculation",
        "question_ko": "컴퓨터를 1초 사용하려면 전기 30와트가 필요합니다. 컴퓨터를 25초 사용하려면 전기 몇 와트가 필요합니까?",
        "question_en": "A computer requires 30 watts of electricity to run for one second. How many watts of electricity is required to run your computer for 25 seconds?",
        "answer_ko": "750",
        "answer_en": "750",
        "solution_abst_ko": "30 25 [OP_MUL]",
        "solution_abst_en": "30 25 [OP_MUL]",
        "solution_code_ko": "var_a = 30\nvar_b = 25\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 30\nvar_b = 25\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "131": {
        "category": "Correspondence",
        "question_ko": "어떤 값에서 477을 빼면 273입니다. 어떤 값에 273을 더하면 얼마입니까?",
        "question_en": "Subtracting 477 from a number equals 273. How much is a number plus 273?",
        "answer_ko": "1023",
        "answer_en": "1023",
        "solution_abst_ko": "477 273 [OP_ADD] 273 [OP_ADD]",
        "solution_abst_en": "477 273 [OP_ADD] 273 [OP_ADD]",
        "solution_code_ko": "var_a = 477\nvar_b = 273\nvar_c = var_a + var_b\nvar_d = 273\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 477\nvar_b = 273\nvar_c = var_a + var_b\nvar_d = 273\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "132": {
        "category": "Correspondence",
        "question_ko": "연필의 개수는 공책의 개수의 6배이다. 공책을 6명에게 나누어주었더니 한 명당 9개씩 가지고 남는 것이 없었다. 연필의 개수를 구하시오.",
        "question_en": "The number of pencils is 6 times the number of notebooks. I distributed the notebooks to 6 people, and each person had 9 of them, and there was nothing left. Find the number of pencils.",
        "answer_ko": "324",
        "answer_en": "324",
        "solution_abst_ko": "9 6 [OP_MUL] 6 [OP_MUL]",
        "solution_abst_en": "9 6 [OP_MUL] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 9\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "133": {
        "category": "Geometry",
        "question_ko": "십팔각형 모양의 무늬가 있다. 이 무늬에 대각선을 그릴 수 있는 만큼 그리려고 할 때, 몇 개를 그릴수 있는가?",
        "question_en": "There is an octadecagon-shaped pattern. If you try to draw as many diagonal lines as you can on this pattern, how many can you draw?",
        "answer_ko": "135",
        "answer_en": "135",
        "solution_abst_ko": "18 18 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "18 18 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 18\nvar_b = 18\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 18\nvar_b = 18\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "134": {
        "category": "Possibility",
        "question_ko": "네 자리 수 중 1, 5, 9, 4 하나씩으로 이루어진 가장 큰 수를 구하시오.",
        "question_en": "Find the largest four-digit number consisting of 1, 5, 9, and 4.",
        "answer_ko": "9541",
        "answer_en": "9541",
        "solution_abst_ko": "[OP_LIST_SOL] 1 4 9 5 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1 4 9 5 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1\nvar_b = 4\nvar_c = 9\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 4\nvar_c = 9\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint(int(var_g))"
    },
    "135": {
        "category": "Correspondence",
        "question_ko": "선미는 첫 번째 가게에서 가진 돈의 1/2를 쓰고, 두 번째 가게에서 남은 돈의 1/3을 쓰고, 세 번째 가게에서 남은 돈의 1/2을 썼더니 250원이 남았습니다. 선미가 처음에 가지고 있던 돈은 얼마인지 구하시오",
        "question_en": "Seon-mi spends 1/2 of her money at the first store, 1/3 of her remaining money at the second store, and 1/2 of her remaining money at the third store, leaving her with 250 won. Find how much money Seon-mi had at first.",
        "answer_ko": "1500",
        "answer_en": "1500",
        "solution_abst_ko": "250 1 1/2 [OP_SUB] [OP_DIV] 1 1/3 [OP_SUB] [OP_DIV] 1 1/2 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "250 1 1/2 [OP_SUB] [OP_DIV] 1 1/3 [OP_SUB] [OP_DIV] 1 1/2 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 250\nvar_b = 1\nvar_c = 0.5\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 1\nvar_g = 0.3333333333333333\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 1\nvar_k = 0.5\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nprint(int(eval('{:.2f}'.format(round(var_m+1e-10,2)))))",
        "solution_code_en": "var_a = 250\nvar_b = 1\nvar_c = 0.5\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 1\nvar_g = 0.3333333333333333\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 1\nvar_k = 0.5\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nprint(int(eval('{:.2f}'.format(round(var_m+1e-10,2)))))"
    },
    "136": {
        "category": "Correspondence",
        "question_ko": "AB에서 10을 빼면 15입니다. A는 얼마인가요?",
        "question_en": "Subtracting 10 from AB equals 15. How much is A?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "15 10 [OP_ADD] 10 [OP_FDIV]",
        "solution_abst_en": "15 10 [OP_ADD] 10 [OP_FDIV]",
        "solution_code_ko": "var_a = 15\nvar_b = 10\nvar_c = var_a + var_b\nvar_d = 10\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 10\nvar_c = var_a + var_b\nvar_d = 10\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "137": {
        "category": "Comparison",
        "question_ko": "학교에서 태형이네 집과 정국이네 집까지의 거리는 각각 106/45 킬로미터(㎞), 77/30 킬로미터(㎞)입니다. 누구네 집이 학교에서 더 가깝습니까?",
        "question_en": "The distance from school to Taehyung's house and Jungkook's house is 106/45 kilometers (km) and 77/30 kilometers (km), respectively. Whose house is closer to the school?",
        "answer_ko": "태형",
        "answer_en": "Taehyung",
        "solution_abst_ko": "[OP_LIST_SOL] 태형 정국 [OP_LIST_EOL] [OP_LIST_SOL] 106/45 77/30 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Taehyung Jungkook [OP_LIST_EOL] [OP_LIST_SOL] 106/45 77/30 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '태형'\nvar_b = '정국'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2.3555555555555556\nvar_d = 2.566666666666667\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Taehyung'\nvar_b = 'Jungkook'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2.3555555555555556\nvar_d = 2.566666666666667\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "138": {
        "category": "Arithmetic calculation",
        "question_ko": "1000밀리리터(㎖)짜리의 병에 우유가 가득 차있었는데, 이 병에 금이 가 1분에 5밀리리터(㎖)씩 우유가 샜습니다. 몇 분 후 우유 병을 보니 우유가 300밀리리터(㎖) 남아있었다면 몇 분이 지났을지 구하시오.",
        "question_en": "A 1000 milliliter (ml) bottle was full of milk, but the bottle cracked and milk leaked at a rate of 5 ml (ml) per minute. After a few minutes, if you look at the milk bottle and there are 300 milliliters (ml) of milk left, find how many minutes have passed.",
        "answer_ko": "140",
        "answer_en": "140",
        "solution_abst_ko": "1000 300 [OP_SUB] 5 [OP_DIV]",
        "solution_abst_en": "1000 300 [OP_SUB] 5 [OP_DIV]",
        "solution_code_ko": "var_a = 1000\nvar_b = 300\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 1000\nvar_b = 300\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "139": {
        "category": "Geometry",
        "question_ko": "직육면체에서 가로와 세로가 각각 30센티미터(㎝), 22센티미터(㎝)이며, 모든 모서리의 합이 224센티미터(㎝)라면, 이 직육면체의 높이는 몇 센티미터(㎝)입니까?",
        "question_en": "If the width and length of a cuboid are 30 centimeters (cm) and 22 centimeters (cm) respectively, and the sum of all edges is 224 centimeters (cm), how many centimeters (cm) is the height of this cuboid?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "224 4 [OP_DIV] 30 [OP_SUB] 22 [OP_SUB]",
        "solution_abst_en": "224 4 [OP_DIV] 30 [OP_SUB] 22 [OP_SUB]",
        "solution_code_ko": "var_a = 224\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 30\nvar_e = var_c - var_d\nvar_f = 22\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 224\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 30\nvar_e = var_c - var_d\nvar_f = 22\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "140": {
        "category": "Arithmetic calculation",
        "question_ko": "191.8미터(m) 인 도로의 양쪽에 같은 간격으로 58 개의 깃발을 꽂았습니다. 도로의 처음과 끝에 모두 깃발을 꽂았다면 깃발과 깃발 사이의 거리는 몇 미터(m)입니까?",
        "question_en": "58 flags were planted at equal intervals on both sides of the 191.8 meters (m) long road. If flags are planted at both the beginning and end of the road, find the distance between the flags in meters (m).",
        "answer_ko": "6.85",
        "answer_en": "6.85",
        "solution_abst_ko": "191.8 58 2 [OP_DIV] 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "191.8 58 2 [OP_DIV] 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 191.8\nvar_b = 58\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_a / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 191.8\nvar_b = 58\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_a / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "141": {
        "category": "Arithmetic calculation",
        "question_ko": "꽃병에 장미 5송이, 백합 2송이가 있습니다. 꽃병에는 총 몇 송이가 있을까요?",
        "question_en": "Five roses and two lilies are planted in the vase. How many flowers are there in the vase?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "5 2 [OP_ADD]",
        "solution_abst_en": "5 2 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "142": {
        "category": "Geometry",
        "question_ko": "길이가 각각 10 센티미터(㎝), 8 센티미터(㎝), 6 센티미터(㎝)인 세 변으로 이루어진 직각삼각형이 있습니다. 외접원의 반지름의 길이는?",
        "question_en": "You have a right triangle with three sides, each measuring 10 centimeters (cm), 8 centimeters (cm), and 6 centimeters (cm). What is the length of the radius of the circumscribed circle?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "10 2 [OP_DIV]",
        "solution_abst_en": "10 2 [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 10\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "143": {
        "category": "Comparison",
        "question_ko": "유나는 정국이보다 줄넘기를 더 많이 하려고 합니다. 유나는 1번째와 2번째에 각각 26번씩 했고 정국이는 81번 했을 때 유나는 3번째에 적어도 몇 번을 해야 하나요?",
        "question_en": "Yuna tries to do more jump rope than Jungkook. Yuna did 26 jump ropes in each of 1st and 2nd try and Jungkook did 81 jump ropes, then how many jump ropes should Yuna do on her 3rd try at least?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "81 26 26 [OP_ADD] [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "81 26 26 [OP_ADD] [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 81\nvar_b = 26\nvar_c = 26\nvar_d = var_b + var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 81\nvar_b = 26\nvar_c = 26\nvar_d = var_b + var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "144": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 100배 인 수에 10을 곱하면 17이 된다고 합니다. 어떤 수는 얼마인지 구하시오.",
        "question_en": "When you multiply 10 by 100 times of a certain number, you get 17 as a result. What is that certain number?",
        "answer_ko": "0.02",
        "answer_en": "0.02",
        "solution_abst_ko": "17 10 [OP_DIV] 100 [OP_DIV]",
        "solution_abst_en": "17 10 [OP_DIV] 100 [OP_DIV]",
        "solution_code_ko": "var_a = 17\nvar_b = 10\nvar_c = var_a / var_b\nvar_d = 100\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 17\nvar_b = 10\nvar_c = var_a / var_b\nvar_d = 100\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "145": {
        "category": "Correspondence",
        "question_ko": "AB19를 올림하여 백의 자리까지 나타낸다면 7300의 값을 얻을 수 있습니다. AB19를 십의 자리까지 버림한 값은 무엇이 되겠습니까?",
        "question_en": "If AB19 is rounded up to the hundreds place, it gets a value of 7300. What is AB19 when rounded down to the tens place?",
        "answer_ko": "7210",
        "answer_en": "7210",
        "solution_abst_ko": "AB19 [OP_GEN_POSSIBLE_LIST] 7300 100 [OP_SUB] [OP_LIST_MORE] 7300 [OP_LIST_LESS_EQUAL] AB19 A [OP_LIST_FIND_UNK] 1000 [OP_MUL] AB19 B [OP_LIST_FIND_UNK] 100 [OP_MUL] [OP_ADD] 19 [OP_ADD] 2 [OP_FLOOR]",
        "solution_abst_en": "AB19 [OP_GEN_POSSIBLE_LIST] 7300 100 [OP_SUB] [OP_LIST_MORE] 7300 [OP_LIST_LESS_EQUAL] AB19 A [OP_LIST_FIND_UNK] 1000 [OP_MUL] AB19 B [OP_LIST_FIND_UNK] 100 [OP_MUL] [OP_ADD] 19 [OP_ADD] 2 [OP_FLOOR]",
        "solution_code_ko": "var_a = 'AB19'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 7300\nvar_c = 100\nvar_d = var_b - var_c\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nvar_e = 7300\nlist_c = []\nfor i in list_b:\n    if i <= var_e:\n        list_c.append(i)\nvar_f = 'AB19'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nvar_i = 1000\nvar_j = var_h * var_i\nvar_k = 'AB19'\nvar_l = 'B'\nvar_k = str(var_k)\nvar_l = str(var_l)\nunk_idx = var_k.index(var_l)\nvar_m = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_m = int(elem[unk_idx])\nvar_n = 100\nvar_o = var_m * var_n\nvar_p = var_j + var_o\nvar_q = 19\nvar_r = var_p + var_q\nvar_s = 2\nvar_t=int((var_r//(10**(var_s-1)))*10**(var_s-1))\n\nprint(int(var_t))",
        "solution_code_en": "var_a = 'AB19'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 7300\nvar_c = 100\nvar_d = var_b - var_c\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nvar_e = 7300\nlist_c = []\nfor i in list_b:\n    if i <= var_e:\n        list_c.append(i)\nvar_f = 'AB19'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nvar_i = 1000\nvar_j = var_h * var_i\nvar_k = 'AB19'\nvar_l = 'B'\nvar_k = str(var_k)\nvar_l = str(var_l)\nunk_idx = var_k.index(var_l)\nvar_m = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_m = int(elem[unk_idx])\nvar_n = 100\nvar_o = var_m * var_n\nvar_p = var_j + var_o\nvar_q = 19\nvar_r = var_p + var_q\nvar_s = 2\nvar_t=int((var_r//(10**(var_s-1)))*10**(var_s-1))\n\nprint(int(var_t))"
    },
    "146": {
        "category": "Comparison",
        "question_ko": "도착한 소포는 왼쪽에서 7번째, 오른쪽에서 13번째, 앞에서 8번째, 뒤에서 14번째 소포함에 있었습니다. 각 줄마다 있는 소포함의 수가 같다고 할 때, 소포함의 개수는 모두 몇 개입니까?",
        "question_en": "The arrived parcel was located at 7th from the left, 13th from the right, 8th from the front, and 14th from the back of the parcel boxes. If the number of parcel boxes in each row is the same, what is the total number of parcel boxes?",
        "answer_ko": "399",
        "answer_en": "399",
        "solution_abst_ko": "7 13 [OP_ADD] 1 [OP_SUB] 8 14 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "7 13 [OP_ADD] 1 [OP_SUB] 8 14 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 7\nvar_b = 13\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = 14\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 7\nvar_b = 13\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = 14\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))"
    },
    "147": {
        "category": "Possibility",
        "question_ko": "4, 1, 6, 7 중 3개를 사용하여 십의 자리 숫자가 1인 세 번쩨 작은 수는 무엇입니까?",
        "question_en": "Using 3 of numbers 4, 1, 6, 7, what is the third smallest number with 1 in the tens place?",
        "answer_ko": "614",
        "answer_en": "614",
        "solution_abst_ko": "[OP_LIST_SOL] 4 1 6 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 1 [OP_LIST_SEARCH_FIXED_DIGIT] 3 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 4 1 6 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 1 [OP_LIST_SEARCH_FIXED_DIGIT] 3 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 4\nvar_b = 1\nvar_c = 6\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 1\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 3\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nprint(int(var_i))",
        "solution_code_en": "var_a = 4\nvar_b = 1\nvar_c = 6\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 1\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 3\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nprint(int(var_i))"
    },
    "148": {
        "category": "Arithmetic calculation",
        "question_ko": "아연이는 0.09 킬로미터(㎞) 떨어진 병원에 가려고 합니다. 아연이가 3 미터(m)를 가는데 4초가 걸린다면 병원까지 가는데 걸린 시간은 몇 초인가요?",
        "question_en": "Ayeon tries to go to a hospital 0.09 kilometers (km) away. If Ayeon takes 4 seconds to go 3 meters (m), how many seconds does it take for her to get to the hospital?",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "0.09 1000 [OP_MUL] 3 [OP_DIV] 4 [OP_MUL]",
        "solution_abst_en": "0.09 1000 [OP_MUL] 3 [OP_DIV] 4 [OP_MUL]",
        "solution_code_ko": "var_a = 0.09\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = 4\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 0.09\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = 4\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "149": {
        "category": "Arithmetic calculation",
        "question_ko": "1/4미터(m)의 나무토막이 필요합니다. 3미터(m)의 나무로 몇 도막을 만들 수 있나요?",
        "question_en": "You will need a 1/4 meter (m) block of wood. How many blocks can you make with 3 meters (m) of wood?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "3 1/4 [OP_DIV]",
        "solution_abst_en": "3 1/4 [OP_DIV]",
        "solution_code_ko": "var_a = 3\nvar_b = 0.25\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 0.25\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "150": {
        "category": "Comparison",
        "question_ko": "정윤이는 제비뽑기로 교실 왼쪽에서 7번째, 오른쪽에서 13번째, 앞에서 8번째, 뒤에서 14번째에 있는 자리를 뽑았습니다. 각 줄마다 있는 자리의 수가 같다고 할 때, 교실 안 자리의 개수는 모두 몇 개입니까?",
        "question_en": "By drawing lots, Jeongyun picked the seat 7th from the left, 13th from the right, 8th from the front, and 14th from the back. If the number of seats in each row is the same, how many seats are there in the classroom?",
        "answer_ko": "399",
        "answer_en": "399",
        "solution_abst_ko": "7 13 [OP_ADD] 1 [OP_SUB] 8 14 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "7 13 [OP_ADD] 1 [OP_SUB] 8 14 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 7\nvar_b = 13\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = 14\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 7\nvar_b = 13\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = 14\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))"
    },
    "151": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 3으로 나눈 다음 5를 빼야 할 것을 잘못하여 어떤 수에 3을 곱한 다음 5를 뺐더니 103이 되었습니다. 바르게 계산한 값을 구하시오.",
        "question_en": "I needed to divide a number by 3 and then subtract 5. However, I mistakenly multiplied this number by 3 and subtracted 5 and got 103 as a result. Find the correct calculated value.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "103 5 [OP_ADD] 3 [OP_DIV] 3 [OP_DIV] 5 [OP_SUB]",
        "solution_abst_en": "103 5 [OP_ADD] 3 [OP_DIV] 3 [OP_DIV] 5 [OP_SUB]",
        "solution_code_ko": "var_a = 103\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = 5\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 103\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = 5\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "152": {
        "category": "Correspondence",
        "question_ko": "52는 어떤 수에 48을 더해야 하는데 잘못하여 빼서 나온 결과이다. 바르게 계산한 결과를 구하여라.",
        "question_en": "52 is the result of mistakenly subtracting 48 from a certain number while 48 had to be added. Find the result of the correct calculation.",
        "answer_ko": "148",
        "answer_en": "148",
        "solution_abst_ko": "52 48 [OP_ADD] 48 [OP_ADD]",
        "solution_abst_en": "52 48 [OP_ADD] 48 [OP_ADD]",
        "solution_code_ko": "var_a = 52\nvar_b = 48\nvar_c = var_a + var_b\nvar_d = 48\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 52\nvar_b = 48\nvar_c = var_a + var_b\nvar_d = 48\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "153": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 10, 11, 12, 13이 있습니다. 그 중에서 가장 작은 수와 그 다음으로 작은 수로 나눈 값은 얼마입니까?",
        "question_en": "There are four numbers 10, 11, 12, and 13. What is the difference between the smallest number and the next smallest number?",
        "answer_ko": "0.91",
        "answer_en": "0.91",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_DIV]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "154": {
        "category": "Comparison",
        "question_ko": "정국에는 6 곱하기 3만큼 사과를 모았고, 윤기는 4개의 사과를 모았습니다. 누가 더 사과를 적게 가지고 있습니까?",
        "question_en": "Jungkook collected 6 times 3 apples, and Yoongi collected 4 apples. Who has fewer apples?",
        "answer_ko": "윤기",
        "answer_en": "Yoongi",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 윤기 [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_MUL] 4 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Yoongi [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_MUL] 4 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '윤기'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 3\nvar_e = var_c * var_d\nvar_f = 4\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Yoongi'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 3\nvar_e = var_c * var_d\nvar_f = 4\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "155": {
        "category": "Correspondence",
        "question_ko": "2A32-BBB=1BBB입니다. A,B는 서로 다른 두 수 일때 B-A를 구하시오.",
        "question_en": "Given 2A32-BBB=1BBB, find B-A when A and B are two different numbers.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "2A32-BBB=1BBB B [OP_DIGIT_UNK_SOLVER] 2A32-BBB=1BBB A [OP_DIGIT_UNK_SOLVER] [OP_SUB]",
        "solution_abst_en": "2A32-BBB=1BBB B [OP_DIGIT_UNK_SOLVER] 2A32-BBB=1BBB A [OP_DIGIT_UNK_SOLVER] [OP_SUB]",
        "solution_code_ko": "var_a = '2A32-BBB=1BBB'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '2A32-BBB=1BBB'\nvar_e = 'A'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = '2A32-BBB=1BBB'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '2A32-BBB=1BBB'\nvar_e = 'A'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "156": {
        "category": "Correspondence",
        "question_ko": "서점에서 40권의 책 중 4권을 제외한 책들이 모두 팔렸습니다. 손님이 모두 4명이고 손님들이 모두 같은 수의 책을 구매하였습니다. 손님들은 몇 권의 책을 사갔습니까?",
        "question_en": "In the bookstore, all but 4 of the 40 books were sold out. There were 4 customers in total, and they all bought the same number of books. How many books did a customer buy?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "40 4 [OP_SUB] 4 [OP_DIV]",
        "solution_abst_en": "40 4 [OP_SUB] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 40\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 40\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "157": {
        "category": "Correspondence",
        "question_ko": "서로 다른 두 수 A, B가 있습니다. 두 자리 수끼리의 뺄셈식 8B-A3=38에서 B를 구하시오.",
        "question_en": "There are two different numbers A and B. Find B from the two-digit subtraction equation of 8B-A3=38.",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "8B-A3=38 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "8B-A3=38 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '8B-A3=38'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '8B-A3=38'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "158": {
        "category": "Comparison",
        "question_ko": "첫 번째 역에서 기차를 탄 어린이는 어른보다 17명이 적었습니다. 다음 역에서 어른 57명과 어린이 18명이 타고 44명이 내렸습니다. 지금 기차를 타고 있는 사람이 502명이라면 첫 번째 역에서 기차를 탄 어른은 몇 명인지 구하시오.",
        "question_en": "There were 17 fewer children than adults on the train at the first station. At the next station, 57 adults and 18 children got on and 44 got off. If there are 502 people on the train right now, how many adults got on the train at the first station?",
        "answer_ko": "244",
        "answer_en": "244",
        "solution_abst_ko": "502 18 57 [OP_ADD] 44 [OP_SUB] [OP_SUB] 17 [OP_ADD] 2 [OP_DIV]",
        "solution_abst_en": "502 18 57 [OP_ADD] 44 [OP_SUB] [OP_SUB] 17 [OP_ADD] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 502\nvar_b = 18\nvar_c = 57\nvar_d = var_b + var_c\nvar_e = 44\nvar_f = var_d - var_e\nvar_g = var_a - var_f\nvar_h = 17\nvar_i = var_g + var_h\nvar_j = 2\nvar_k = var_i / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 502\nvar_b = 18\nvar_c = 57\nvar_d = var_b + var_c\nvar_e = 44\nvar_f = var_d - var_e\nvar_g = var_a - var_f\nvar_h = 17\nvar_i = var_g + var_h\nvar_j = 2\nvar_k = var_i / var_j\nprint(int(var_k))"
    },
    "159": {
        "category": "Arithmetic calculation",
        "question_ko": "(가) 반 학생은 모두 44명입니다. (나) 반은 (가) 반보다 2명 더 많고, (다) 반은 (나) 반보다 1명 더 적습니다. (다) 반 학생은 모두 몇 명입니까?",
        "question_en": "There are 44 students in A class. B class has 2 more studemts than A class, and C class has 1 less stuendt than B class. How many students are in C class?",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "44 2 [OP_ADD] 1 [OP_SUB]",
        "solution_abst_en": "44 2 [OP_ADD] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 44\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 44\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "160": {
        "category": "Geometry",
        "question_ko": "가로가 6미터(m), 세로가 4미터(m)인 도로에 가로가 60센티미터(㎝), 세로가 20센티미터(㎝)인 직사각형 모양의 벽돌을 빈틈없이 겹치지 않게 붙이려고 합니다. 도로를 메우기 위해 필요한 벽돌의 개수는 몇 개입니까?",
        "question_en": "On a road measuring 6 meters (m) wide and 4 meters (m) long, we are going to attach rectangular bricks 60 centimeters (cm) wide and 20 centimeters (cm) tall without overlapping. How many bricks are needed to fill the road?",
        "answer_ko": "200",
        "answer_en": "200",
        "solution_abst_ko": "6 100 [OP_MUL] 4 100 [OP_MUL] [OP_MUL] 60 20 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "6 100 [OP_MUL] 4 100 [OP_MUL] [OP_MUL] 60 20 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = 100\nvar_f = var_d * var_e\nvar_g = var_c * var_f\nvar_h = 60\nvar_i = 20\nvar_j = var_h * var_i\nvar_k = var_g / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 6\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = 100\nvar_f = var_d * var_e\nvar_g = var_c * var_f\nvar_h = 60\nvar_i = 20\nvar_j = var_h * var_i\nvar_k = var_g / var_j\nprint(int(var_k))"
    },
    "161": {
        "category": "Correspondence",
        "question_ko": "1/4×1/8=1/(4×A)=1/B 일때 B는 무엇인가?",
        "question_en": "What is B when 1/4×1/8=1/(4×A)=1/B?",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "1/4×1/8=1/(4×A)=1/B B [OP_NUM_UNK_SOLVER]",
        "solution_abst_en": "1/4×1/8=1/(4×A)=1/B B [OP_NUM_UNK_SOLVER]",
        "solution_code_ko": "var_a = '1/4×1/8=1/(4×A)=1/B'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '1/4×1/8=1/(4×A)=1/B'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "162": {
        "category": "Arithmetic calculation",
        "question_ko": "민영, 유정, 은지 세 사람이 모여 구슬을 나누기로 했습니다. 처음 민영이가 가지고 온 구슬은 유정이가 가지고 온 구슬보다 27개 많고 민영이가 은지에게 구슬 9개를 주면 민영이와 은지가 가지고 있는 구슬이 45개로 같아진다고 할 때, 세 사람이 가지고 있는 구슬의 총 개수는 몇 개입니까?",
        "question_en": "Minyoung, Yoojung, and Eunji decided to divide marbles they have. Minyoung first brought 27 more marbles than Yoojung brought and if Minyoung gives Eunji 9 marbles, Minyoung and Eunji have 45 marbles each, how many marbles do the three people have in total? ",
        "answer_ko": "117",
        "answer_en": "117",
        "solution_abst_ko": "45 27 [OP_SUB] 9 [OP_ADD] 27 [OP_ADD] 45 27 [OP_SUB] 9 [OP_ADD] [OP_ADD] 45 9 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "45 27 [OP_SUB] 9 [OP_ADD] 27 [OP_ADD] 45 27 [OP_SUB] 9 [OP_ADD] [OP_ADD] 45 9 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 45\nvar_b = 27\nvar_c = var_a - var_b\nvar_d = 9\nvar_e = var_c + var_d\nvar_f = 27\nvar_g = var_e + var_f\nvar_h = 45\nvar_i = 27\nvar_j = var_h - var_i\nvar_k = 9\nvar_l = var_j + var_k\nvar_m = var_g + var_l\nvar_n = 45\nvar_o = 9\nvar_p = var_n - var_o\nvar_q = var_m + var_p\nprint(int(var_q))",
        "solution_code_en": "var_a = 45\nvar_b = 27\nvar_c = var_a - var_b\nvar_d = 9\nvar_e = var_c + var_d\nvar_f = 27\nvar_g = var_e + var_f\nvar_h = 45\nvar_i = 27\nvar_j = var_h - var_i\nvar_k = 9\nvar_l = var_j + var_k\nvar_m = var_g + var_l\nvar_n = 45\nvar_o = 9\nvar_p = var_n - var_o\nvar_q = var_m + var_p\nprint(int(var_q))"
    },
    "163": {
        "category": "Correspondence",
        "question_ko": "어떤 소수의 소수점을 오른쪽으로 두 자리 옮기면 원래의 소수보다 138.6만큼 커집니다. 원래의 소수를 구하시오.",
        "question_en": "When you move the decimal point of a prime number two places to the right, it becomes 138.6 more than the original prime number. Find the original prime number.",
        "answer_ko": "1.40",
        "answer_en": "1.4",
        "solution_abst_ko": "138.6 10 2 [OP_POW] 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "138.6 10 2 [OP_POW] 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 138.6\nvar_b = 10\nvar_c = 2\nvar_d = var_b ** var_c\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_a / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 138.6\nvar_b = 10\nvar_c = 2\nvar_d = var_b ** var_c\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_a / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "164": {
        "category": "Comparison",
        "question_ko": "각각의 무게가 다른 공 15개를 무게가 가벼운 것부터 순서대로 한 줄로 놓았습니다. 공 (가)는 앞에서 8번째에 놓여 있습니다. 무게가 무거운 것부터 순서대로 다시 한 줄로 놓으면 공 (가)는 앞에서 몇 번째에 놓이게 됩니까?",
        "question_en": "15 balls of different weights are placed in a row in order of weight from the lightest. The ball (a) is placed eighth from the front. If you place the balls again, in a row in order of weight from the heaviest, at what position will the ball (A) be placed from the front?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "15 8 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "15 8 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 15\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "165": {
        "category": "Correspondence",
        "question_ko": "27에서 7을 뺀 값은 어떤 수와 5를 곱한 값과 같다. 어떤 수와 5의 합에 7을 곱하면 얼마인지 구하시오.",
        "question_en": "27 minus 7 equals the multiplication of one number and 5. What is the product of 7 and the sum of the number and 5?",
        "answer_ko": "63",
        "answer_en": "63",
        "solution_abst_ko": "27 7 [OP_SUB] 5 [OP_DIV] 5 [OP_ADD] 7 [OP_MUL]",
        "solution_abst_en": "27 7 [OP_SUB] 5 [OP_DIV] 5 [OP_ADD] 7 [OP_MUL]",
        "solution_code_ko": "var_a = 27\nvar_b = 7\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c / var_d\nvar_f = 5\nvar_g = var_e + var_f\nvar_h = 7\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 27\nvar_b = 7\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c / var_d\nvar_f = 5\nvar_g = var_e + var_f\nvar_h = 7\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "166": {
        "category": "Comparison",
        "question_ko": "위인전 한 권의 무게는 0.3킬로그램(㎏)이고, 동화책 한 권의 무게는 0.27킬로그램(㎏)입니다. 위인전과 동화책 중에서 어느 것이 더 무겁습니까?",
        "question_en": "The weight of one biography is 0.3 kilograms (kg), and the weight of one fairy-tale book is 0.27 kilograms (kg). Which one is heavier, the biography or the fairy tale book?",
        "answer_ko": "위인전",
        "answer_en": "biography",
        "solution_abst_ko": "[OP_LIST_SOL] 위인전 동화책 [OP_LIST_EOL] [OP_LIST_SOL] 0.3 0.27 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] biography fairy-tale [OP_LIST_EOL] [OP_LIST_SOL] 0.3 0.27 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '위인전'\nvar_b = '동화책'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.3\nvar_d = 0.27\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'biography'\nvar_b = 'fairy-tale'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.3\nvar_d = 0.27\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "167": {
        "category": "Arithmetic calculation",
        "question_ko": "숫자 6, 5, 8, 9로 나누어 떨어질 수 있는 세 자리 수 중 가장 큰 수는 무엇입니까?",
        "question_en": "What is the largest three-digit number divisible by the numbers 6, 5, 8, and 9?",
        "answer_ko": "720",
        "answer_en": "720",
        "solution_abst_ko": "100 999 1 [OP_LIST_ARANGE] 6 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_abst_en": "100 999 1 [OP_LIST_ARANGE] 6 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = 1\nlist_f=list_e.copy()\nlist_f.sort()\nvar_i = list_f[-var_h]\nprint(int(var_i))",
        "solution_code_en": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = 1\nlist_f=list_e.copy()\nlist_f.sort()\nvar_i = list_f[-var_h]\nprint(int(var_i))"
    },
    "168": {
        "category": "Correspondence",
        "question_ko": "검은 바둑돌보다 흰 바둑돌이 468개 더 많다고 한다. 954개의 흰색 돌이 있습니다. 바둑돌의 수를 모두 구하십시오.",
        "question_en": "It is said that there are 468 more white Go stones than black Go stones. There are 954 white stones. Find the numbers of all Go stones.",
        "answer_ko": "1440",
        "answer_en": "1440",
        "solution_abst_ko": "954 468 [OP_SUB] 954 [OP_ADD]",
        "solution_abst_en": "954 468 [OP_SUB] 954 [OP_ADD]",
        "solution_code_ko": "var_a = 954\nvar_b = 468\nvar_c = var_a - var_b\nvar_d = 954\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 954\nvar_b = 468\nvar_c = var_a - var_b\nvar_d = 954\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "169": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 10, 11, 12, 13이 있습니다. 그 중에서 2번째로 큰 수와 2번째로 작은 수의 합은 얼마입니까?",
        "question_en": "There are four numbers 10, 11, 12, and 13. What is the sum of the second largest number and the second smallest number?",
        "answer_ko": "23",
        "answer_en": "23",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))"
    },
    "170": {
        "category": "Possibility",
        "question_ko": "1, 3, 0, 5가 적힌 카드가 각각 한 장씩 있습니다. 카드를 한번씩만 사용해서 네 자리 수를 만들 때, 6번째로 큰 수는 무엇입니까?",
        "question_en": "There are cards each with the numbers 1, 3, 0, and 5 on it. When making a four-digit number using the cards once, what is the 6th largest number?",
        "answer_ko": "5013",
        "answer_en": "5013",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 0 5 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 6 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 0 5 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 6 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 0\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 6\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 0\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 6\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint(int(var_g))"
    },
    "171": {
        "category": "Comparison",
        "question_ko": "학생 25명이 한 줄로 서 있습니다. 석진이의 뒤에 13명의 학생들이 서 있습니다. 석진이의 앞에 서 있는 학생은 몇 명입니까?",
        "question_en": "25 students stand in a line. Thirteen students are standing behind Seokjin. How many students are standing in front of Seokjin?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "25 13 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "25 13 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 25\nvar_b = 13\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 25\nvar_b = 13\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "172": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중에서 가장 작은 수와 2번째로 작은 수의 합은 얼마입니까?",
        "question_en": "There are three numbers: 10, 11 and 12. What is the sum of the smallest number and the second smallest number?",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e + var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e + var_g\nprint(int(var_h))"
    },
    "173": {
        "category": "Comparison",
        "question_ko": "운동장에 학생들이 앉아 있습니다. 유정이는 왼쪽에서 12번째 열, 오른쪽에서 11번째 열, 앞에서 18번째 줄, 뒤에서 8번째 줄에 앉아 있습니다. 각 줄마다 학생의 수가 같다고 할 때, 운동장에 앉아 있는 학생은 모두 몇 명입니까?",
        "question_en": "Students are sitting on the playground. Yujeong is seated in the 12th row from the left, 11th row from the right, 18th row from the front, and 8th row from the back. How many students are sitting on the playground, assuming the same number of students are in each row?",
        "answer_ko": "550",
        "answer_en": "550",
        "solution_abst_ko": "12 11 [OP_ADD] 1 [OP_SUB] 18 8 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "12 11 [OP_ADD] 1 [OP_SUB] 18 8 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 12\nvar_b = 11\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 18\nvar_g = 8\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 12\nvar_b = 11\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 18\nvar_g = 8\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))"
    },
    "174": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 9로 나누었더니 몫이 25로 나누어떨어졌습니다. 어떤 수에 7을 더하고 9를 곱한 값은 얼마입니까?",
        "question_en": "When a number is divided by 9, the quotient is divisible by 25. What do you get when the number is added to 7 and multiplied by 9?",
        "answer_ko": "2088",
        "answer_en": "2088",
        "solution_abst_ko": "25 9 [OP_MUL] 7 [OP_ADD] 9 [OP_MUL]",
        "solution_abst_en": "25 9 [OP_MUL] 7 [OP_ADD] 9 [OP_MUL]",
        "solution_code_ko": "var_a = 25\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c + var_d\nvar_f = 9\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 25\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c + var_d\nvar_f = 9\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "175": {
        "category": "Arithmetic calculation",
        "question_ko": "유정이는 오토바이 2대와 자전거 5대를 구매하였습니다. 유정이가 구매한 오토바이와 자전거는 몇 대 인가요?",
        "question_en": "Yoojung bought 2 motorcycles and 5 bicycles. How many motorcycles and bicycles did Yoojung buy?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "2 5 [OP_ADD]",
        "solution_abst_en": "2 5 [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "176": {
        "category": "Arithmetic calculation",
        "question_ko": "한 사람이 53일을 사는 데 155.2리터(L)의 물이 필요하다고 하고, 한 물통에 들어있는 물의 양은 2리터(L)입니다. 만약 사람이 17일을 산다고 한다면 사람에게 필요한 물통은 모두 몇 개입니까?",
        "question_en": "It is said that one person needs 155.2 liters (l) of water to live for 53 days, and the amount of water in one bucket is 2 liters (l). If a person lives 17 days, how many buckets of water does a person need?",
        "answer_ko": "25",
        "answer_en": "25",
        "solution_abst_ko": "155.2 53 [OP_DIV] 17 [OP_MUL] 2 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "155.2 53 [OP_DIV] 17 [OP_MUL] 2 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 155.2\nvar_b = 53\nvar_c = var_a / var_b\nvar_d = 17\nvar_e = var_c * var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 1\nvar_i=int(((var_g+9*10**(var_h-2))//(10**(var_h-1)))*10**(var_h-1))\n\nprint(int(var_i))",
        "solution_code_en": "var_a = 155.2\nvar_b = 53\nvar_c = var_a / var_b\nvar_d = 17\nvar_e = var_c * var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 1\nvar_i=int(((var_g+9*10**(var_h-2))//(10**(var_h-1)))*10**(var_h-1))\n\nprint(int(var_i))"
    },
    "177": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이는 빨간 공 3개와 노란 공 2개를 가지고 있습니다. 정국이가 윤기에게 빨간 공 1개를 주었을 때, 정국이가 가지고 있는 노란 공의 개수는?",
        "question_en": "Jungkook has 3 red balls and 2 yellow balls. When Jungkook gives Yoongi 1 red ball, how many yellow balls does Jungkook have?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "2",
        "solution_abst_en": "2",
        "solution_code_ko": "var_a = 2\nprint(int(var_a))",
        "solution_code_en": "var_a = 2\nprint(int(var_a))"
    },
    "178": {
        "category": "Possibility",
        "question_ko": "동위는 축제를 보기 위해 다른 학교에 놀러가려고 합니다. 하나의 학교에만 놀러갈 수 있고, 남고가 4개, 여고가 3개 있을 때 동위가 놀러가는 경우의 수를 구하시오.",
        "question_en": "Dongwi is going to go to another school to see the festival. If only one school is allowed to go to play, and there are 4 boys' high schools and 3 girls' high schools, find the number of cases in which Dongwi go to play.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "4 3 [OP_ADD]",
        "solution_abst_en": "4 3 [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 3\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 3\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "179": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 5를 곱해 결과로 100을 얻었습니다. 10으로 어떤 수를 나누면 얼마입니까?",
        "question_en": "Multiply a number by 5 to get 100. What is the value of the number when divided by 10?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "100 5 [OP_DIV] 10 [OP_DIV]",
        "solution_abst_en": "100 5 [OP_DIV] 10 [OP_DIV]",
        "solution_code_ko": "var_a = 100\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 10\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 100\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 10\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "180": {
        "category": "Possibility",
        "question_ko": "1, 0, 5, 8 중에서 서로 다른 숫자 2개를 뽑아 만들 수 있는 두 자리 수 중 가장 큰 수에서 2번째로 큰 수를 뺀 값은 얼마입니까?",
        "question_en": "Of the two digits that can be created by taking two different numbers out of 1, 0, 5, and 8, what is the largest minus the second largest?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 1 0 5 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 1 0 5 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_SUB]",
        "solution_code_ko": "var_a = 1\nvar_b = 0\nvar_c = 5\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 2\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nvar_j = var_g - var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 1\nvar_b = 0\nvar_c = 5\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 2\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nvar_j = var_g - var_i\nprint(int(var_j))"
    },
    "181": {
        "category": "Geometry",
        "question_ko": "넓이가 21.12제곱센티미터(㎠)인 정육각형을 6등분하였습니다. 한 등분의 넓이는 얼마입니까?",
        "question_en": "A regular hexagon with an area of 21.12 square centimeters (cm2) is divided into 6 equal parts. What is the area of the divided part?",
        "answer_ko": "3.52",
        "answer_en": "3.52",
        "solution_abst_ko": "21.12 6 [OP_DIV]",
        "solution_abst_en": "21.12 6 [OP_DIV]",
        "solution_code_ko": "var_a = 21.12\nvar_b = 6\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 21.12\nvar_b = 6\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "182": {
        "category": "Arithmetic calculation",
        "question_ko": "남준이는 구슬을 7개씩 3묶음 가지고 있습니다. 이 구슬을 6개씩 6묶음으로 만들려고 합니다. 몇 개의 구슬이 더 필요합니까?",
        "question_en": "Namjoon has 3 sets of 7 marbles. He is going to make these marbles into 6 groups of 6 each. How many more marbles does he need?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "6 6 [OP_MUL] 7 3 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "6 6 [OP_MUL] 7 3 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 6\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 6\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "183": {
        "category": "Geometry",
        "question_ko": "도형의 둘레가 49센티미터(㎝)이며 한 변의 길이가 7센티미터(㎝)인 도형이 있습니다. 총 몇 개의 변이 있습니까?",
        "question_en": "A figure has a perimeter of 49 centimeters (cm) and a side length of 7 centimeters (cm). How many sides are there in total?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "49 7 [OP_DIV]",
        "solution_abst_en": "49 7 [OP_DIV]",
        "solution_code_ko": "var_a = 49\nvar_b = 7\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 49\nvar_b = 7\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "184": {
        "category": "Correspondence",
        "question_ko": "서로 다른 숫자 A, B, C, D가 있습니다. 네 자리 수끼리의 덧셈식 DCBA+ABCD=ABCD0에서 A, B, C, D의 합을 구하시오.",
        "question_en": "There are different numbers A, B, C, and D. Find the sum of A, B, C, and D in the four-digit addition formula DCBA+ABCD=ABCD0.",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "DCBA+ABCD=ABCD0 A [OP_DIGIT_UNK_SOLVER] DCBA+ABCD=ABCD0 B [OP_DIGIT_UNK_SOLVER] DCBA+ABCD=ABCD0 C [OP_DIGIT_UNK_SOLVER] DCBA+ABCD=ABCD0 D [OP_DIGIT_UNK_SOLVER] [OP_ADD] [OP_ADD] [OP_ADD]",
        "solution_abst_en": "DCBA+ABCD=ABCD0 A [OP_DIGIT_UNK_SOLVER] DCBA+ABCD=ABCD0 B [OP_DIGIT_UNK_SOLVER] DCBA+ABCD=ABCD0 C [OP_DIGIT_UNK_SOLVER] DCBA+ABCD=ABCD0 D [OP_DIGIT_UNK_SOLVER] [OP_ADD] [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 'DCBA+ABCD=ABCD0'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 'DCBA+ABCD=ABCD0'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = 'DCBA+ABCD=ABCD0'\nvar_h = 'C'\nans_dict = dict()\nvar_g = var_g.replace('×','*')\nvar_g = var_g.replace('x','*')\nvar_g = var_g.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_g):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_g\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_g):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_i = ans_dict[var_h]\nvar_j = 'DCBA+ABCD=ABCD0'\nvar_k = 'D'\nans_dict = dict()\nvar_j = var_j.replace('×','*')\nvar_j = var_j.replace('x','*')\nvar_j = var_j.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_j):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_j\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_j):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_l = ans_dict[var_k]\nvar_m = var_i + var_l\nvar_n = var_f + var_m\nvar_o = var_c + var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 'DCBA+ABCD=ABCD0'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 'DCBA+ABCD=ABCD0'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = 'DCBA+ABCD=ABCD0'\nvar_h = 'C'\nans_dict = dict()\nvar_g = var_g.replace('×','*')\nvar_g = var_g.replace('x','*')\nvar_g = var_g.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_g):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_g\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_g):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_i = ans_dict[var_h]\nvar_j = 'DCBA+ABCD=ABCD0'\nvar_k = 'D'\nans_dict = dict()\nvar_j = var_j.replace('×','*')\nvar_j = var_j.replace('x','*')\nvar_j = var_j.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_j):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_j\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_j):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_l = ans_dict[var_k]\nvar_m = var_i + var_l\nvar_n = var_f + var_m\nvar_o = var_c + var_n\nprint(int(var_o))"
    },
    "185": {
        "category": "Arithmetic calculation",
        "question_ko": "가로가 20미터(m)인 벽에 7개의 포스터를 붙히려고 한다. 벽의 양쪽 끝에서 1미터(m)씩 떨어뜨려서 붙이기 시작하여 같은 간격으로 포스터를 붙혔다. 포스터 사이의 간격을 구하시오",
        "question_en": "I am trying to put 7 posters on a wall that is 20 meters (m) wide. The posters were pasted at equal intervals, starting at 1 meter (m) apart from each end of the wall. Find the space between the posters.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "20 1 2 [OP_MUL] [OP_SUB] 7 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "20 1 2 [OP_MUL] [OP_SUB] 7 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 20\nvar_b = 1\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 7\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 20\nvar_b = 1\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 7\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "186": {
        "category": "Comparison",
        "question_ko": "다음 중 1보다 작은 수는 몇 개인지 고르시오. 1/10, 8, 0.9, 7/10, 5.",
        "question_en": "How many of the following numbers are less than 1? 1/10, 8, 0.9, 7/10, 5.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 1/10 8 0.9 7/10 5 [OP_LIST_EOL] 1 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1/10 8 0.9 7/10 5 [OP_LIST_EOL] 1 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.1\nvar_b = 8\nvar_c = 0.9\nvar_d = 0.7\nvar_e = 5\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b = []\nfor i in list_a:\n    if i < var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 0.1\nvar_b = 8\nvar_c = 0.9\nvar_d = 0.7\nvar_e = 5\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b = []\nfor i in list_a:\n    if i < var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "187": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 5로 나누어야 하는데 실수로 8로 나누었더니 몫이 156이고 나머지가 2였습니다. 계산을 제대로 했을 때 나오는 값을 구하시오.",
        "question_en": "A number needs to be divided by 5, but when it was accidentally divided by 8, the quotient was 156 and the remainder 2. Find the value that comes out when the calculation is done correctly.",
        "answer_ko": "250",
        "answer_en": "250",
        "solution_abst_ko": "156 8 [OP_MUL] 2 [OP_ADD] 5 [OP_DIV]",
        "solution_abst_en": "156 8 [OP_MUL] 2 [OP_ADD] 5 [OP_DIV]",
        "solution_code_ko": "var_a = 156\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 156\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "188": {
        "category": "Comparison",
        "question_ko": "첫 번째 정류장에서 지하철을 탄 남자는 여자보다 17명이 적었습니다. 다음 역에서 여자 57명과 남자 18명이 타고 44명이 내렸습니다. 지금 지하철을 타고 있는 사람이 502명이라면 첫 번째 정류장에서 지하철 탄 남자는 몇 명인지 구하시오",
        "question_en": "At the first stop, there were 17 men fewer than women that took the subway. At the next station, 57 women and 18 men got on and 44 people got off. If there are 502 people on the subway right now, how many men got on the subway at the first stop?",
        "answer_ko": "227",
        "answer_en": "227",
        "solution_abst_ko": "502 18 57 [OP_ADD] 44 [OP_SUB] [OP_SUB] 17 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "502 18 57 [OP_ADD] 44 [OP_SUB] [OP_SUB] 17 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 502\nvar_b = 18\nvar_c = 57\nvar_d = var_b + var_c\nvar_e = 44\nvar_f = var_d - var_e\nvar_g = var_a - var_f\nvar_h = 17\nvar_i = var_g - var_h\nvar_j = 2\nvar_k = var_i / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 502\nvar_b = 18\nvar_c = 57\nvar_d = var_b + var_c\nvar_e = 44\nvar_f = var_d - var_e\nvar_g = var_a - var_f\nvar_h = 17\nvar_i = var_g - var_h\nvar_j = 2\nvar_k = var_i / var_j\nprint(int(var_k))"
    },
    "189": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 3 으로 나눈 다음 12 를 더해야 할 것을 잘못하여 3 을 곱한 다음 12 를 빼고나서 6으로 나눴더니 60 이 되었습니다. 바르게 계산하면 얼마입니까?",
        "question_en": "I was supposed to divide a certain number by 3 and add 12 to it, but I multiplied this number by 3, subtracted 12 and then divided it by 6 accidentally, getting 60 as a result. How much will I get if I calculate correctly?",
        "answer_ko": "53.33",
        "answer_en": "53.33",
        "solution_abst_ko": "60 6 [OP_MUL] 12 [OP_ADD] 3 [OP_DIV] 3 [OP_DIV] 12 [OP_ADD]",
        "solution_abst_en": "60 6 [OP_MUL] 12 [OP_ADD] 3 [OP_DIV] 3 [OP_DIV] 12 [OP_ADD]",
        "solution_code_ko": "var_a = 60\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = 3\nvar_i = var_g / var_h\nvar_j = 12\nvar_k = var_i + var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 60\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = 3\nvar_i = var_g / var_h\nvar_j = 12\nvar_k = var_i + var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "190": {
        "category": "Possibility",
        "question_ko": "자연수 8, 1, 6으로 만들 수 있는, 각 자릿수가 모두 다른 세 자리 수 중 가장 큰 것과 세 번째로 큰 것의 합을 구하시오.",
        "question_en": "Find the sum of the largest and third largest three-digit numbers with different digits that can be made with the natural numbers 8, 1, and 6.",
        "answer_ko": "1542",
        "answer_en": "1542",
        "solution_abst_ko": "[OP_LIST_SOL] 8 1 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 3 [OP_LIST_MAX] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 8 1 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 3 [OP_LIST_MAX] [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 1\nvar_c = 6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[-var_g]\nvar_i = var_f + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 8\nvar_b = 1\nvar_c = 6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[-var_g]\nvar_i = var_f + var_h\nprint(int(var_i))"
    },
    "191": {
        "category": "Correspondence",
        "question_ko": "두 개의 비커 안에 각각 액체가 담겨있다. 두 비커안에 담겨있는 용액의 합이 9.28밀리리터(㎖)이다. 한 비커에 2.95밀리리터(㎖)가 들어있을 때, 두 비커에 들어있는 용액의 차는 몇 밀리리터(㎖)인지 구하시오.",
        "question_en": "Each of the two beakers contains a liquid. The sum of the solutions contained in the two beakers is 9.28 milliliters (ml). If one beaker contains 2.95 milliliters (ml), what is the difference in milliliters (ml) between the two beakers?",
        "answer_ko": "3.38",
        "answer_en": "3.38",
        "solution_abst_ko": "9.28 2.95 [OP_SUB] 2.95 [OP_SUB]",
        "solution_abst_en": "9.28 2.95 [OP_SUB] 2.95 [OP_SUB]",
        "solution_code_ko": "var_a = 9.28\nvar_b = 2.95\nvar_c = var_a - var_b\nvar_d = 2.95\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 9.28\nvar_b = 2.95\nvar_c = var_a - var_b\nvar_d = 2.95\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "192": {
        "category": "Possibility",
        "question_ko": "A, B, C, D, E, F 6명을 한 줄로 세울 때, A, B, C를 서로 이웃하게 하여 세우는 경우의 수를 구하시오.",
        "question_en": "When 6 people A, B, C, D, E, and F are lined up in a line, find the number of ways in which A, B, and C can be placed next to each other.",
        "answer_ko": "144",
        "answer_en": "144",
        "solution_abst_ko": "[OP_LIST_SOL] A B C D E F [OP_LIST_EOL] [OP_LIST_SOL] B C [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D E F [OP_LIST_EOL] [OP_LIST_SOL] B C [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nvar_f = 'F'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 'B'\nvar_h = 'C'\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_i = len(list_c)\nvar_j = len(list_c)\nvar_k = 1\nvar_i = int(var_i)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_i-i)\nvar_l = 'A'\nvar_m = 'B'\nvar_n = 'C'\nlist_d= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_d.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_d.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_d.append(var_l)\nlist_d.reverse()\nvar_o = len(list_d)\nvar_p = len(list_d)\nvar_q = 1\nvar_o = int(var_o)\nvar_p = int(var_p)\nfor i, elem in enumerate(range(var_p)):\n    var_q = var_q * (var_o-i)\nvar_r = var_k * var_q\nprint(int(var_r))",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nvar_f = 'F'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 'B'\nvar_h = 'C'\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_i = len(list_c)\nvar_j = len(list_c)\nvar_k = 1\nvar_i = int(var_i)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_i-i)\nvar_l = 'A'\nvar_m = 'B'\nvar_n = 'C'\nlist_d= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_d.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_d.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_d.append(var_l)\nlist_d.reverse()\nvar_o = len(list_d)\nvar_p = len(list_d)\nvar_q = 1\nvar_o = int(var_o)\nvar_p = int(var_p)\nfor i, elem in enumerate(range(var_p)):\n    var_q = var_q * (var_o-i)\nvar_r = var_k * var_q\nprint(int(var_r))"
    },
    "193": {
        "category": "Arithmetic calculation",
        "question_ko": "45명의 학생 중 미술을 좋아한다고 거수한 학생이 42명이고 과학을 좋아한다고 거수한 학생은 40명입니다. 모든 학생이 조사에 참여하였을 때, 두 과목 모두 손을 든 학생은 몇 명인가요?",
        "question_en": "Among the 45 students, 42 students raised their hands to say they like art, and 40 students raised their hands to say they like science. If all students participated in the survey, how many students raised their hands in both subjects?",
        "answer_ko": "37",
        "answer_en": "37",
        "solution_abst_ko": "40 42 [OP_ADD] 45 [OP_SUB]",
        "solution_abst_en": "40 42 [OP_ADD] 45 [OP_SUB]",
        "solution_code_ko": "var_a = 40\nvar_b = 42\nvar_c = var_a + var_b\nvar_d = 45\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 40\nvar_b = 42\nvar_c = var_a + var_b\nvar_d = 45\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "194": {
        "category": "Possibility",
        "question_ko": "계산기에서 0, 1, 2, 3, 4, 5의 숫자가 각각 적힌 6개의 버튼 중 3개를 눌러서 만들 수 있는 세 자리 정수의 개수는?",
        "question_en": "How many three-digit integers can be created by pressing 3 of the 6 buttons on a calculator with the numbers 0, 1, 2, 3, 4, and 5 on them?",
        "answer_ko": "100",
        "answer_en": "100",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 4 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 4 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nvar_f = 5\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = len(list_b)\nprint(int(var_h))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nvar_f = 5\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = len(list_b)\nprint(int(var_h))"
    },
    "195": {
        "category": "Arithmetic calculation",
        "question_ko": "25센티미터(㎝) 길이의 나무막대 30장을 6센티미터(㎝)겹쳐 이어붙였을 시 전체 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "What is the total length in centimeters (cm) of 30 wooden sticks 25 centimeters (cm) long when 6 centimeters (cm) are overlapped?",
        "answer_ko": "576",
        "answer_en": "576",
        "solution_abst_ko": "25 25 6 [OP_SUB] 30 1 [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_abst_en": "25 25 6 [OP_SUB] 30 1 [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 25\nvar_b = 25\nvar_c = 6\nvar_d = var_b - var_c\nvar_e = 30\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_a + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 25\nvar_b = 25\nvar_c = 6\nvar_d = var_b - var_c\nvar_e = 30\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_a + var_h\nprint(int(var_i))"
    },
    "196": {
        "category": "Possibility",
        "question_ko": "주어진 숫자카드 0, 8, 7를 한 번씩 모두 사용하여 만들 수 있는 가장 큰 수를 쓰시오.",
        "question_en": "Write the largest number that can be made by using all of the figures 0, 8, and 7 once.",
        "answer_ko": "870",
        "answer_en": "870",
        "solution_abst_ko": "[OP_LIST_SOL] 0 8 7 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 0 8 7 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 0\nvar_b = 8\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))",
        "solution_code_en": "var_a = 0\nvar_b = 8\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))"
    },
    "197": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 3을 곱했더니 33이 되었습니다. 어떤 수는 얼마일까요?",
        "question_en": "When you multiply a number by 3, you get 33. What number is that?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "33 3 [OP_DIV]",
        "solution_abst_en": "33 3 [OP_DIV]",
        "solution_code_ko": "var_a = 33\nvar_b = 3\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 33\nvar_b = 3\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "198": {
        "category": "Possibility",
        "question_ko": "5, 6, 7 중에서 한 번씩만 사용하여 만들 수 있는 세 자리 수중에서 홀수의 개수를 구하시오.",
        "question_en": "Find the number of odd numbers in a three-digit number that can be formed by using 5, 6, or 7 only once.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 5 6 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 5 6 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 5\nvar_b = 6\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nlist_d = list(set(list_b) - set(list_c))\nvar_f = len(list_d)\nprint(int(var_f))",
        "solution_code_en": "var_a = 5\nvar_b = 6\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nlist_d = list(set(list_b) - set(list_c))\nvar_f = len(list_d)\nprint(int(var_f))"
    },
    "199": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 50을 뺀 후 4로 나누고, 3을 곱한 값에 28을 더한 값이 73입니다. 어떤 수를 구하시오.",
        "question_en": "When you subtract 50 from a number, divide it by 4, multiply it by 3, and add 28, it becomes 73. Find out what number this is.",
        "answer_ko": "110",
        "answer_en": "110",
        "solution_abst_ko": "73 28 [OP_SUB] 3 [OP_DIV] 4 [OP_MUL] 50 [OP_ADD]",
        "solution_abst_en": "73 28 [OP_SUB] 3 [OP_DIV] 4 [OP_MUL] 50 [OP_ADD]",
        "solution_code_ko": "var_a = 73\nvar_b = 28\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = 4\nvar_g = var_e * var_f\nvar_h = 50\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 73\nvar_b = 28\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = 4\nvar_g = var_e * var_f\nvar_h = 50\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "200": {
        "category": "Arithmetic calculation",
        "question_ko": "태형이네 모둠 학생 5명의 키는 145센티미터(㎝), 139센티미터(㎝), 155센티미터(㎝), 160센티미터(㎝), 143센티미터(㎝)입니다. 모둠에 1명이 더 늘어서 키의 평균이 1.2센티미터(㎝) 늘어났습니다. 새로 온 학생의 키는 몇 센티미터(㎝)인지 소수점을 포함하여 답을 구하시오.",
        "question_en": "Taehyung's group has five students with a height of 145 centimeters (cm), 139 centimeters (cm), 155 centimeters (cm), 160 centimeters (cm), and 143 centimeters (cm). When one more student joined the group, the average height increased by 1.2 centimeters (cm). Find the height of the new student in centimeters (cm) including the decimal point.",
        "answer_ko": "155.60",
        "answer_en": "155.6",
        "solution_abst_ko": "[OP_LIST_SOL] 145 139 155 160 143 [OP_LIST_EOL] [OP_LIST_MEAN] [OP_LIST_LEN] 1 [OP_ADD] 1.2 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 145 139 155 160 143 [OP_LIST_EOL] [OP_LIST_MEAN] [OP_LIST_LEN] 1 [OP_ADD] 1.2 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 145\nvar_b = 139\nvar_c = 155\nvar_d = 160\nvar_e = 143\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_f = sum(list_a)/len(list_a)\nvar_g = len(list_a)\nvar_h = 1\nvar_i = var_g + var_h\nvar_j = 1.2\nvar_k = var_i * var_j\nvar_l = var_f + var_k\nprint('{:.2f}'.format(round(var_l+1e-10,2)))",
        "solution_code_en": "var_a = 145\nvar_b = 139\nvar_c = 155\nvar_d = 160\nvar_e = 143\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_f = sum(list_a)/len(list_a)\nvar_g = len(list_a)\nvar_h = 1\nvar_i = var_g + var_h\nvar_j = 1.2\nvar_k = var_i * var_j\nvar_l = var_f + var_k\nprint('{:.2f}'.format(round(var_l+1e-10,2)))"
    },
    "201": {
        "category": "Comparison",
        "question_ko": "20명의 학생들이 버스를 기다리고 있습니다. 정국이는 윤기 바로 뒤에 왔고, 정국이보다 먼저 온 사람은 11명이라면 윤기보다 늦게 온 사람들은 몇 명입니까?",
        "question_en": "20 students are waiting for the bus. If Jungkook came right after Yoongi, and there are 11 people who came before Jungkook, how many people came after Yoongi?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "20 11 [OP_SUB] 1 [OP_ADD] 1 [OP_SUB]",
        "solution_abst_en": "20 11 [OP_SUB] 1 [OP_ADD] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 1\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 1\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "202": {
        "category": "Possibility",
        "question_ko": "장미, 백합, 튤립, 국화, 카네이션이 각각 1송이씩 있습니다. 그중에서 3송이를 뽑아 (가), (나), (다) 세 개의 꽃병에 1송이씩 꽂으려고 합니다. 꽃병에 꽃을 서로 다르게 꽂는 방법은 모두 몇 가지입니까?",
        "question_en": "There is one rose, lily, tulip, chrysanthemum, and carnation each. I'm going to pick three of them and put them in three vases A, B, and C. How many different ways can you put flowers in a vase?",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "[OP_LIST_SOL] 장미 백합 튤립 국화 카네이션 [OP_LIST_EOL] [OP_LIST_LEN] 3 [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] rose lily tulip chrysanthemum carnation [OP_LIST_EOL] [OP_LIST_LEN] 3 [OP_PERM]",
        "solution_code_ko": "var_a = '장미'\nvar_b = '백합'\nvar_c = '튤립'\nvar_d = '국화'\nvar_e = '카네이션'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 3\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nprint(int(var_h))",
        "solution_code_en": "var_a = 'rose'\nvar_b = 'lily'\nvar_c = 'tulip'\nvar_d = 'chrysanthemum'\nvar_e = 'carnation'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 3\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nprint(int(var_h))"
    },
    "203": {
        "category": "Possibility",
        "question_ko": "정국, 지민, 윤기, 유나, 태형 중에서 중복을 허용하여 두 사람을 선택하려고 합니다. 선택할 수 있는 경우는 모두 몇 가지 입니까?",
        "question_en": "You are trying to select two people from Jungkook, Jimin, Yoongi, Yuna, and Taehyung allowing duplicate cases. Find the possible number of cases.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 지민 윤기 유나 태형 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Jimin Yoongi Yuna Taehyung [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '지민'\nvar_c = '윤기'\nvar_d = '유나'\nvar_e = '태형'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = 2\nvar_l = 1\nvar_j = int(var_j)\nvar_k = int(var_k)\nfor i, elem in enumerate(range(var_k)):\n    var_l = var_l * (var_j-i)\nfor i, elem in enumerate(range(var_k)):\n    var_l = var_l / (i+1)\nprint(int(var_l))",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Jimin'\nvar_c = 'Yoongi'\nvar_d = 'Yuna'\nvar_e = 'Taehyung'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = 2\nvar_l = 1\nvar_j = int(var_j)\nvar_k = int(var_k)\nfor i, elem in enumerate(range(var_k)):\n    var_l = var_l * (var_j-i)\nfor i, elem in enumerate(range(var_k)):\n    var_l = var_l / (i+1)\nprint(int(var_l))"
    },
    "204": {
        "category": "Possibility",
        "question_ko": "4개의 숫자 1, 2, 3, 4 중에서 중복을 허락하여 3개를 택해 일렬로 나열하여 세 자리의 자연수를 만들 때, 3의 배수의 개수는?",
        "question_en": "If you select three of the four numbers 1, 2, 3, and 4, allowing duplicates, and arrange them in a row to form a three-digit natural number. How many multiples of 3 are there?",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "[OP_LIST_SOL] 1 2 3 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 2 3 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 2\nvar_c = 3\nvar_d = 4\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c = []\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nvar_g = len(list_c)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 2\nvar_c = 3\nvar_d = 4\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c = []\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nvar_g = len(list_c)\nprint(int(var_g))"
    },
    "205": {
        "category": "Arithmetic calculation",
        "question_ko": "사함이는 오늘 2.6킬로미터(㎞) 걸었고, 사함이의 어머니는 5.98킬로미터(㎞) 걸었습니다. 사함이와 어머니가 걸은 거리를 합하면 몇 킬로미터(㎞)입니까?",
        "question_en": "Saham walked 2.6 kilometers (km) today, and Saham's mother walked 5.98 kilometers (km). How many kilometers (km) is the sum of the distance that Saham and his mother walked?",
        "answer_ko": "8.58",
        "answer_en": "8.58",
        "solution_abst_ko": "2.6 5.98 [OP_ADD]",
        "solution_abst_en": "2.6 5.98 [OP_ADD]",
        "solution_code_ko": "var_a = 2.6\nvar_b = 5.98\nvar_c = var_a + var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 2.6\nvar_b = 5.98\nvar_c = var_a + var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "206": {
        "category": "Geometry",
        "question_ko": "직사각형의 네 변의 합이 48센티미터(㎝)이고 가로의 길이가 세로의 길이보다 2센티미터(㎝) 짧다. 직사각형의 가로의 길이를 구하시오.",
        "question_en": "The sum of the four sides of a rectangle is 48 centimeters (cm), and the width of the rectangle is 2 centimeters (cm) shorter than its length. Find the width of the rectangle.",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "48 2 [OP_DIV] 2 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "48 2 [OP_DIV] 2 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 48\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 48\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "207": {
        "category": "Correspondence",
        "question_ko": "백의 자리 숫자가 9인 세 자리 수를 7로 나누면 나누어떨어집니다. 이런 세 자리 수는 모두 몇 개입니까?",
        "question_en": "Dividing a three-digit number with 9 in the hundreds place is divisible by 7. How many of these three digit numbers are there?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "9 100 [OP_MUL] 9 100 [OP_MUL] 99 [OP_ADD] 1 [OP_LIST_ARANGE] 7 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "9 100 [OP_MUL] 9 100 [OP_MUL] 99 [OP_ADD] 1 [OP_LIST_ARANGE] 7 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 9\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = 100\nvar_f = var_d * var_e\nvar_g = 99\nvar_h = var_f + var_g\nvar_i = 1\nlist_a = [i for i in range(var_c, var_h + 1, var_i)]\nvar_j = 7\nlist_b = []\nvar_j = int(var_j)\nfor i in list_a:\n    i = int(i)\n    if i % var_j == 0:\n        list_b.append(i)\nvar_k = len(list_b)\nprint(int(var_k))",
        "solution_code_en": "var_a = 9\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = 100\nvar_f = var_d * var_e\nvar_g = 99\nvar_h = var_f + var_g\nvar_i = 1\nlist_a = [i for i in range(var_c, var_h + 1, var_i)]\nvar_j = 7\nlist_b = []\nvar_j = int(var_j)\nfor i in list_a:\n    i = int(i)\n    if i % var_j == 0:\n        list_b.append(i)\nvar_k = len(list_b)\nprint(int(var_k))"
    },
    "208": {
        "category": "Possibility",
        "question_ko": "2, 4, 5 총 3장의 수 카드 중 2장을 사용하여 두 자리 수를 만들려고 합니다. 만들 수 있는 4의 배수는 모두 몇 개일까요?",
        "question_en": " We are going to use 2 of our number cards 2, 4, and 5 in order to create a double-digit number. How many multiples of 4 can you make?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 2 4 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 4 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 2 4 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 4 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 4\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 4\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "209": {
        "category": "Arithmetic calculation",
        "question_ko": "리본 한 개를 만드는데 리본 테이프 0.84미터(m)가 필요합니다. 유진이가 가지고 있는 리본 테이프로 리본을 10개 만들었더니 50센티미터(㎝)가 남았습니다. 유진이가 처음에 가지고 있던 리본 테이프의 길이는 몇 미터(m)일까요?",
        "question_en": "It takes 0.84 meters (m) of ribbon tape to make one ribbon. After making 10 ribbons with the ribbon tape that Yujin has, there are 50 centimeters (cm) left. How many meters (m) is the ribbon tape that Yujin had at first?",
        "answer_ko": "8.90",
        "answer_en": "8.9",
        "solution_abst_ko": "0.84 10 [OP_MUL] 50 100 [OP_DIV] [OP_ADD]",
        "solution_abst_en": "0.84 10 [OP_MUL] 50 100 [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 0.84\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 50\nvar_e = 100\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 0.84\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 50\nvar_e = 100\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "210": {
        "category": "Correspondence",
        "question_ko": "A78-21B=364일 때, A를 구하시오.",
        "question_en": "When A78-21B=364, where A79 and 21B are three-digit numbers. Find A.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "A78-21B=364 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A78-21B=364 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A78-21B=364'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A78-21B=364'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "211": {
        "category": "Arithmetic calculation",
        "question_ko": "올해는 어머니의 나이가 딸보다 4배, 8년 후에는 어머니와 딸 나이의 합이 71살이라면, 5년 후에 어머니는 몇 살입니까?",
        "question_en": "If the age of the mother is 4 times that of the daughter this year, and the sum of the ages of the mother and daughter is 71 after 8 years, how old will the mother be after 5 years?",
        "answer_ko": "49",
        "answer_en": "49",
        "solution_abst_ko": "71 8 2 [OP_MUL] [OP_SUB] 4 1 [OP_ADD] [OP_DIV] 4 [OP_MUL] 5 [OP_ADD]",
        "solution_abst_en": "71 8 2 [OP_MUL] [OP_SUB] 4 1 [OP_ADD] [OP_DIV] 4 [OP_MUL] 5 [OP_ADD]",
        "solution_code_ko": "var_a = 71\nvar_b = 8\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 4\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = var_e / var_h\nvar_j = 4\nvar_k = var_i * var_j\nvar_l = 5\nvar_m = var_k + var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 71\nvar_b = 8\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 4\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = var_e / var_h\nvar_j = 4\nvar_k = var_i * var_j\nvar_l = 5\nvar_m = var_k + var_l\nprint(int(var_m))"
    },
    "212": {
        "category": "Comparison",
        "question_ko": "2.8, 2.3, 5, 3, 4.3 중 가장 작은 수와 가장 큰 수의 곱을 구하시오.",
        "question_en": "Find the product of the smallest number and the largest number among 2.8, 2.3, 5, 3, and 4.3.",
        "answer_ko": "11.50",
        "answer_en": "11.5",
        "solution_abst_ko": "[OP_LIST_SOL] 2.8 2.3 5 3 4.3 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 2.8 2.3 5 3 4.3 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MUL]",
        "solution_code_ko": "var_a = 2.8\nvar_b = 2.3\nvar_c = 5\nvar_d = 3\nvar_e = 4.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g * var_i\nprint('{:.2f}'.format(round(var_j+1e-10,2)))",
        "solution_code_en": "var_a = 2.8\nvar_b = 2.3\nvar_c = 5\nvar_d = 3\nvar_e = 4.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g * var_i\nprint('{:.2f}'.format(round(var_j+1e-10,2)))"
    },
    "213": {
        "category": "Comparison",
        "question_ko": "총 3개의 숫자 0.8, 1/2, 0.5이 있습니다. 이 중 2보다 작거나 같은 수를 모두 더하면 얼마인가요?",
        "question_en": "There are a total of three numbers: 0.8, 1/2, and 0.5. What is the sum of all numbers less than or equal to 2?",
        "answer_ko": "1.80",
        "answer_en": "1.8",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.5 [OP_LIST_EOL] 2 [OP_LIST_LESS_EQUAL] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.5 [OP_LIST_EOL] 2 [OP_LIST_LESS_EQUAL] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = []\nfor i in list_a:\n    if i <= var_d:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = []\nfor i in list_a:\n    if i <= var_d:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "214": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 일을 하는 데 수민이가 혼자서 하면 10일이 걸리고, 준우가 혼자서 하면 15일이 걸립니다. 이 일을 두 사람이 같이 한다면 일을 끝내는 데 며칠이 걸리는지 답을 구하세요.",
        "question_en": "It takes 10 days for Sumin to do something alone, and 15 days for Junwoo to do it alone. Answer how many days it will take to complete the task if two people are doing it together.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "1 1 10 [OP_DIV] 1 15 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_abst_en": "1 1 10 [OP_DIV] 1 15 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 1\nvar_c = 10\nvar_d = var_b / var_c\nvar_e = 1\nvar_f = 15\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = var_a / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))",
        "solution_code_en": "var_a = 1\nvar_b = 1\nvar_c = 10\nvar_d = var_b / var_c\nvar_e = 1\nvar_f = 15\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = var_a / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))"
    },
    "215": {
        "category": "Possibility",
        "question_ko": "주어진 숫자 7, 1, 3을 한 번씩 모두 사용했을 때, 150보다 크고 700보다 작은 세 자리 수의 개수는 모두 몇 개입니까?",
        "question_en": "How many three-digit numbers are there that are greater than 150 and less than 700, given that the numbers 7, 1, and 3 are used once?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 7 1 3 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 150 [OP_LIST_MORE] 700 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 7 1 3 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 150 [OP_LIST_MORE] 700 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 7\nvar_b = 1\nvar_c = 3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 150\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = 700\nlist_d = []\nfor i in list_c:\n    if i < var_f:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))",
        "solution_code_en": "var_a = 7\nvar_b = 1\nvar_c = 3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 150\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = 700\nlist_d = []\nfor i in list_c:\n    if i < var_f:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))"
    },
    "216": {
        "category": "Geometry",
        "question_ko": "가로가 5센티미터(㎝), 세로가 7센티미터(㎝)인 직사각형 모양의 명함을 겹치지 않게 빈틈없이 늘어놓아 정사각형 모양의 상자 바닥을 가득 채웠습니다. 이 상자의 크기가 최소일 때 한 변의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "Rectangular business cards measuring 5 centimeters (cm) wide and 7 centimeters (cm) long were laid out without overlapping, filling the bottom of the square box. How many centimeters (cm) is each side of this box at its smallest size?",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "5 7 [OP_LCM]",
        "solution_abst_en": "5 7 [OP_LCM]",
        "solution_code_ko": "var_a = 5\nvar_b = 7\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 7\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nprint(int(var_c))"
    },
    "217": {
        "category": "Comparison",
        "question_ko": "학생들이 한 줄로 서 있습니다. 유정이는 맨 앞에 서 있습니다. 유정이 뒤에 10명이 서 있을 때, 줄을 서 있는 학생은 모두 몇 명입니까?",
        "question_en": "Students are standing in a line. Yoojung is standing at the very front. When 10 students are standing behind Yoojeong, how many students are in the line?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "10 1 [OP_ADD]",
        "solution_abst_en": "10 1 [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 10\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "218": {
        "category": "Comparison",
        "question_ko": "윤기는 4, 정국이는 6에서 3을 나눈 몫 만큼 모았고, 유나는 5만큼 모았습니다. 누가 가장 작은 수를 모았습니까?",
        "question_en": "Yoongi collected 4, Jungkook collected 6 divided by 3, and Yuna collected 5. Who got the smallest number?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 유나 [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_FDIV] 5 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook Yuna [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_FDIV] 5 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nvar_c = '유나'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 6\nvar_f = 3\nvar_g = var_e // var_f\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nvar_c = 'Yuna'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 6\nvar_f = 3\nvar_g = var_e // var_f\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "219": {
        "category": "Correspondence",
        "question_ko": "665655를 5로 나눈 몫은 여섯 자리 수 ABCDEF입니다. A, B, C, D, E, F의 합을 구하시오.",
        "question_en": "The quotient of 665655 divided by 5 is the six-digit number ABCDEF. Find the sum of A, B, C, D, E, and F.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "665655 5 [OP_DIV] [OP_NUM2LIST] [OP_LIST_SUM]",
        "solution_abst_en": "665655 5 [OP_DIV] [OP_NUM2LIST] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 665655\nvar_b = 5\nvar_c = var_a / var_b\nlist_a = []\nvar_c = int(var_c)\nwhile var_c//10 > 0:\n    list_a.append(var_c%10)\n    var_c = var_c//10\nlist_a.append(var_c%10)\nlist_a = list_a[::-1]\nlist_a = [float(i) for i in list_a]\nvar_d = sum(list_a)\nprint(int(var_d))",
        "solution_code_en": "var_a = 665655\nvar_b = 5\nvar_c = var_a / var_b\nlist_a = []\nvar_c = int(var_c)\nwhile var_c//10 > 0:\n    list_a.append(var_c%10)\n    var_c = var_c//10\nlist_a.append(var_c%10)\nlist_a = list_a[::-1]\nlist_a = [float(i) for i in list_a]\nvar_d = sum(list_a)\nprint(int(var_d))"
    },
    "220": {
        "category": "Arithmetic calculation",
        "question_ko": "전체 길이가 3.944미터(m)인 철사가 있다. 이 철사에서 29.05센티미터(㎝) 씩 8번 잘라냈다. 남은 길이를 9등분할 때, 잘려진 하나의 길이를 구하시오.",
        "question_en": "There is a wire with a total length of 3.944 meters (m). Eight cuts of 29.05 cm (cm) were cut from this wire. When dividing the remaining length into 9 equal parts, find the length of one cut-off.",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "3.944 100 [OP_MUL] 29.05 8 [OP_MUL] [OP_SUB] 8 1 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "3.944 100 [OP_MUL] 29.05 8 [OP_MUL] [OP_SUB] 8 1 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 3.944\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 29.05\nvar_e = 8\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 8\nvar_i = 1\nvar_j = var_h + var_i\nvar_k = var_g / var_j\nprint(int(eval('{:.2f}'.format(round(var_k+1e-10,2)))))",
        "solution_code_en": "var_a = 3.944\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 29.05\nvar_e = 8\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 8\nvar_i = 1\nvar_j = var_h + var_i\nvar_k = var_g / var_j\nprint(int(eval('{:.2f}'.format(round(var_k+1e-10,2)))))"
    },
    "221": {
        "category": "Comparison",
        "question_ko": "오늘 운동은 예슬이는 13/10시간, 영준이는 22/15시간 하였다. 예슬과 영준 중 누가 더 오래 운동했는가?",
        "question_en": "Today Yeseul exercised for 13/10 hours and Youngjun for 22/15 hours. Who has been exercising longer, Yeseul or Youngjun?",
        "answer_ko": "영준",
        "answer_en": "Youngjun",
        "solution_abst_ko": "[OP_LIST_SOL] 예슬 영준 [OP_LIST_EOL] [OP_LIST_SOL] 13 10 [OP_DIV] 22 15 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yeseul Youngjun [OP_LIST_EOL] [OP_LIST_SOL] 13 10 [OP_DIV] 22 15 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '예슬'\nvar_b = '영준'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 13\nvar_d = 10\nvar_e = var_c / var_d\nvar_f = 22\nvar_g = 15\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Yeseul'\nvar_b = 'Youngjun'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 13\nvar_d = 10\nvar_e = var_c / var_d\nvar_f = 22\nvar_g = 15\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "222": {
        "category": "Arithmetic calculation",
        "question_ko": "사과와 감은 총 210개 있다. 사과와 감의 개수는 각각 바나나의 개수의 4배, 3배이다. 그렇다면 바나나는 총 몇 개입니까?",
        "question_en": "There are the total of 210 apples and persimmons. The number of apples and persimmons is four times and three times the number of bananas, respectively. So how many bananas are there in total?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "210 4 3 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "210 4 3 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 210\nvar_b = 4\nvar_c = 3\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 210\nvar_b = 4\nvar_c = 3\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "223": {
        "category": "Comparison",
        "question_ko": "윤기는 4, 유나는 5를 모았습니다. 정국이는 6에서 3을 합한 수만큼 모았다면 누가 가장 큰 수를 가지고 있나요?",
        "question_en": "Yoongi collected 4 and Yuna collected 5. If Jungkook collects a sum of 6 and 3, who has the largest number?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 유나 정국 [OP_LIST_EOL] [OP_LIST_SOL] 4 5 6 3 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Yuna Jungkook [OP_LIST_EOL] [OP_LIST_SOL] 4 5 6 3 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '유나'\nvar_c = '정국'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 5\nvar_f = 6\nvar_g = 3\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Yuna'\nvar_c = 'Jungkook'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 5\nvar_f = 6\nvar_g = 3\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "224": {
        "category": "Correspondence",
        "question_ko": "어떤 소수의 소수점을 왼쪽으로 옮겼더니 원래의 값에서 1.782를 뺀 것과 같아졌습니다. 소수점을 두 자리 옮겼다고 한다면, 원래 소수는 무엇이었는지 구하시오.",
        "question_en": "Moving some decimal places to the left equals the original value minus 1.782. If you moved the decimal point by two places, what was the original decimal?",
        "answer_ko": "1.80",
        "answer_en": "1.8",
        "solution_abst_ko": "1.782 0.99 [OP_DIV]",
        "solution_abst_en": "1.782 0.99 [OP_DIV]",
        "solution_code_ko": "var_a = 1.782\nvar_b = 0.99\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 1.782\nvar_b = 0.99\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "225": {
        "category": "Comparison",
        "question_ko": "건탁이네 반 학생 7명의 몸무게가 35.1킬로그램(㎏), 41.3킬로그램(㎏), 38.6킬로그램(㎏), 40.2킬로그램(㎏), 39.0킬로그램(㎏), 43.7킬로그램(㎏), 38.4킬로그램(㎏)일 때 39킬로그램(㎏) 이상인 학생들의 평균 몸무게를 구하시오.",
        "question_en": "When the weight of 7 students in Geontak’s class is 35.1 kilograms (kg), 41.3 kilograms (kg), 38.6 kilograms (kg), 40.2 kilograms (kg), 39.0 kilograms (kg), 43.7 kilograms (kg), and 38.4 kilograms (kg), find the average weight of students who weighed more than or equal to 39 kilograms (kg).",
        "answer_ko": "41.05",
        "answer_en": "41.05",
        "solution_abst_ko": "[OP_LIST_SOL] 35.1 41.3 38.6 40.2 39.0 43.7 38.4 [OP_LIST_EOL] 39 [OP_LIST_MORE_EQUAL] [OP_LIST_MEAN]",
        "solution_abst_en": "[OP_LIST_SOL] 35.1 41.3 38.6 40.2 39.0 43.7 38.4 [OP_LIST_EOL] 39 [OP_LIST_MORE_EQUAL] [OP_LIST_MEAN]",
        "solution_code_ko": "var_a = 35.1\nvar_b = 41.3\nvar_c = 38.6\nvar_d = 40.2\nvar_e = 39\nvar_f = 43.7\nvar_g = 38.4\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h = 39\nlist_b = []\nfor i in list_a:\n    if i >= var_h:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_i = sum(list_b)/len(list_b)\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 35.1\nvar_b = 41.3\nvar_c = 38.6\nvar_d = 40.2\nvar_e = 39\nvar_f = 43.7\nvar_g = 38.4\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h = 39\nlist_b = []\nfor i in list_a:\n    if i >= var_h:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_i = sum(list_b)/len(list_b)\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "226": {
        "category": "Arithmetic calculation",
        "question_ko": "숫자 2, 3, 8, 9로 나누어 떨어질 수 있는 네 자리 수 중 가장 작은 수는?",
        "question_en": "What is the smallest four-digit number divisible by 2, 3, 8, and 9?",
        "answer_ko": "1008",
        "answer_en": "1008",
        "solution_abst_ko": "1000 9999 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "1000 9999 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 3\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = 1\nlist_f=list_e.copy()\nlist_f.sort()\nvar_i = list_f[var_h-1]\nprint(int(var_i))",
        "solution_code_en": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 3\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = 1\nlist_f=list_e.copy()\nlist_f.sort()\nvar_i = list_f[var_h-1]\nprint(int(var_i))"
    },
    "227": {
        "category": "Geometry",
        "question_ko": "정육각기둥의 밑면의 한 변의 길이가 6센티미터(㎝), 높이가 11센티미터(㎝)일 때, 모든 모서리 길이의 합은 몇 센티미터(㎝)입니까?",
        "question_en": "If one side of the base of a regular hexagonal prism is 6 centimeters (cm) long, and the prism is 11 centimeters (cm) high, how many centimeters (cm) is the sum of the lengths of all the edges?",
        "answer_ko": "138",
        "answer_en": "138",
        "solution_abst_ko": "6 6 [OP_MUL] 2 [OP_MUL] 11 6 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "6 6 [OP_MUL] 2 [OP_MUL] 11 6 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 11\nvar_g = 6\nvar_h = var_f * var_g\nvar_i = var_e + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 6\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 11\nvar_g = 6\nvar_h = var_f * var_g\nvar_i = var_e + var_h\nprint(int(var_i))"
    },
    "228": {
        "category": "Arithmetic calculation",
        "question_ko": "서준이와 친구들은 과수원에서 사과를 100개 땄습니다. 그중에서 서준이가 11개를 가졌다면 서준이가 가진 사과는 전체 사과의 얼마인지 소수로 나타내시오.",
        "question_en": "Seojun and his friends picked 100 apples from the orchard. If Seojun takes 11 of them, how many apples does Seojun have compared to entire apples as a decimal number?",
        "answer_ko": "0.11",
        "answer_en": "0.11",
        "solution_abst_ko": "11 100 [OP_DIV]",
        "solution_abst_en": "11 100 [OP_DIV]",
        "solution_code_ko": "var_a = 11\nvar_b = 100\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 11\nvar_b = 100\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "229": {
        "category": "Arithmetic calculation",
        "question_ko": "1리터(L)짜리 물이 있습니다. 엄마가 0.1리터(L) 마셨고, 아빠는 엄마보다 0.2리터(L)를 더 마셨습니다. 이때 누나가 0.3리터(L)를 마셨다면, 남은 물은 몇 리터(L)입니까?",
        "question_en": "There is 1 liter (L) of water. The mother drank 0.1 liters (L), and the father drank 0.2 liters (L) more than the mother. If your sister drank 0.3 liters (L) at this time, how many liters (L) of water is left?",
        "answer_ko": "0.30",
        "answer_en": "0.3",
        "solution_abst_ko": "1 0.1 [OP_SUB] 0.1 0.2 [OP_ADD] [OP_SUB] 0.3 [OP_SUB]",
        "solution_abst_en": "1 0.1 [OP_SUB] 0.1 0.2 [OP_ADD] [OP_SUB] 0.3 [OP_SUB]",
        "solution_code_ko": "var_a = 1\nvar_b = 0.1\nvar_c = var_a - var_b\nvar_d = 0.1\nvar_e = 0.2\nvar_f = var_d + var_e\nvar_g = var_c - var_f\nvar_h = 0.3\nvar_i = var_g - var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 0.1\nvar_c = var_a - var_b\nvar_d = 0.1\nvar_e = 0.2\nvar_f = var_d + var_e\nvar_g = var_c - var_f\nvar_h = 0.3\nvar_i = var_g - var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "230": {
        "category": "Correspondence",
        "question_ko": "앞면은 노란색 뒷면은 초록색인 종이가 바닥에 놓여 있다. 이때 학생들이 노란색이 보이는 종이 152개를 뒤집어 초록색이 보이도록 뒤집었다고 한다. 이때 노란색 종이가 초록색 종이보다 346개 많았다면 뒤집기전에는 차이가 얼마였는지 구하시오.",
        "question_en": "A sheet of paper, yellow on the front and green on the back, lies on the floor. At this time, it is said that the students flipped 152 pieces of paper that showed yellow and turned them over to show green. At this time, if there are 346 more yellow papers than green papers, what is the difference before flipping?",
        "answer_ko": "650",
        "answer_en": "650",
        "solution_abst_ko": "346 152 [OP_ADD] 152 [OP_ADD]",
        "solution_abst_en": "346 152 [OP_ADD] 152 [OP_ADD]",
        "solution_code_ko": "var_a = 346\nvar_b = 152\nvar_c = var_a + var_b\nvar_d = 152\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 346\nvar_b = 152\nvar_c = var_a + var_b\nvar_d = 152\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "231": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 2.5를 곱한 다음 2.49를 뺐더니 22.01이 되었습니다. 어떤 수를 2.5로 나눈 다음 2.49를 더하고 22.01을 더한 값을 구하시오.",
        "question_en": "Multiply 2.5 to a particular number and subtract 2.49, and it becomes 22.01. Find the value if you divide the number by 2.5 and add 2.49 and 22.01.",
        "answer_ko": "28.42",
        "answer_en": "28.42",
        "solution_abst_ko": "22.01 2.49 [OP_ADD] 2.5 [OP_DIV] 2.5 [OP_DIV] 2.49 [OP_ADD] 22.01 [OP_ADD]",
        "solution_abst_en": "22.01 2.49 [OP_ADD] 2.5 [OP_DIV] 2.5 [OP_DIV] 2.49 [OP_ADD] 22.01 [OP_ADD]",
        "solution_code_ko": "var_a = 22.01\nvar_b = 2.49\nvar_c = var_a + var_b\nvar_d = 2.5\nvar_e = var_c / var_d\nvar_f = 2.5\nvar_g = var_e / var_f\nvar_h = 2.49\nvar_i = var_g + var_h\nvar_j = 22.01\nvar_k = var_i + var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 22.01\nvar_b = 2.49\nvar_c = var_a + var_b\nvar_d = 2.5\nvar_e = var_c / var_d\nvar_f = 2.5\nvar_g = var_e / var_f\nvar_h = 2.49\nvar_i = var_g + var_h\nvar_j = 22.01\nvar_k = var_i + var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "232": {
        "category": "Arithmetic calculation",
        "question_ko": "두 나눗셈 32.5 / 1.3, 60.8 / 7.6의 몫의 차를 구해보세요",
        "question_en": "Find the difference between the quotients of two divisions 32.5 / 1.3 and 60.8 / 7.6.",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "32.5 1.3 [OP_DIV] 60.8 7.6 [OP_DIV] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "32.5 1.3 [OP_DIV] 60.8 7.6 [OP_DIV] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 32.5\nvar_b = 1.3\nvar_c = var_a / var_b\nvar_d = 60.8\nvar_e = 7.6\nvar_f = var_d / var_e\nvar_g = var_c - var_f\nvar_h = abs(var_g)\nprint(int(var_h))",
        "solution_code_en": "var_a = 32.5\nvar_b = 1.3\nvar_c = var_a / var_b\nvar_d = 60.8\nvar_e = 7.6\nvar_f = var_d / var_e\nvar_g = var_c - var_f\nvar_h = abs(var_g)\nprint(int(var_h))"
    },
    "233": {
        "category": "Possibility",
        "question_ko": "자연수 5, 3, 6, 8 중 3개를 고르고, 고른 수를 모두 사용하여 세 자리 수를 만들고 싶습니다. 만들 수 있는 수 중 10번째로 작은 수를 고르시오.",
        "question_en": "I want to choose three of the natural numbers 5, 3, 6, and 8, and use all of them to create a three-digit number. Choose the 10th smallest possible number.",
        "answer_ko": "568",
        "answer_en": "568",
        "solution_abst_ko": "[OP_LIST_SOL] 5 3 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 5 3 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 5\nvar_b = 3\nvar_c = 6\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 3\nvar_c = 6\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nprint(int(var_g))"
    },
    "234": {
        "category": "Arithmetic calculation",
        "question_ko": "100 이하의 자연수 중 2를 빼면 7과 8의 공배수인 수들 중 가장 큰 수를 구하시오.",
        "question_en": "Find the largest number from all natural numbers less than or equal to 100, which become common multiples of 7 and 8 if 2 is subtracted.",
        "answer_ko": "58",
        "answer_en": "58",
        "solution_abst_ko": "1 100 1 [OP_LIST_ARANGE] 7 2 [OP_LIST_DIVIDE_AND_REMAIN] 8 2 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MAX]",
        "solution_abst_en": "1 100 1 [OP_LIST_ARANGE] 7 2 [OP_LIST_DIVIDE_AND_REMAIN] 8 2 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 7\nvar_e = 2\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 8\nvar_g = 2\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 7\nvar_e = 2\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 8\nvar_g = 2\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nprint(int(var_i))"
    },
    "235": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 일을 완성하는 데 형은 4일, 동생은 12일이 걸린다고 한다. 형과 동생이 함께 이 일을 한다면 일을 완성하는 데 며칠이 걸리는지 구하여라",
        "question_en": "It is said that it takes four days for the older brother and 12 days for the younger to complete a certain task. If the older brother and the younger brother do this together, find how many days it will take to complete the job.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "1 1 4 [OP_DIV] 1 12 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_abst_en": "1 1 4 [OP_DIV] 1 12 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 1\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = 1\nvar_f = 12\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = var_a / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 1\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = 1\nvar_f = 12\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = var_a / var_h\nprint(int(var_i))"
    },
    "236": {
        "category": "Comparison",
        "question_ko": "네 수 A, B, C, D가 있습니다. A는 27입니다. B는 A보다 7 큰 수입니다. C는 B보다 9 작은 수입니다. D는 C의 2배인 수입니다. 가장 큰 수는 어느 것입니까?",
        "question_en": "There are four numbers A, B, C, and D. A is 27. B is 7 greater than A. C is 9 less than B. D is twice the number of C. Which number is the largest?",
        "answer_ko": "D",
        "answer_en": "D",
        "solution_abst_ko": "[OP_LIST_SOL] A B C D [OP_LIST_EOL] [OP_LIST_SOL] 27 27 7 [OP_ADD] 27 7 [OP_ADD] 9 [OP_SUB] 27 7 [OP_ADD] 9 [OP_SUB] 2 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D [OP_LIST_EOL] [OP_LIST_SOL] 27 27 7 [OP_ADD] 27 7 [OP_ADD] 9 [OP_SUB] 27 7 [OP_ADD] 9 [OP_SUB] 2 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 27\nvar_f = 27\nvar_g = 7\nvar_h = var_f + var_g\nvar_i = 27\nvar_j = 7\nvar_k = var_i + var_j\nvar_l = 9\nvar_m = var_k - var_l\nvar_n = 27\nvar_o = 7\nvar_p = var_n + var_o\nvar_q = 9\nvar_r = var_p - var_q\nvar_s = 2\nvar_t = var_r * var_s\nlist_b= []\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_b.append(var_t)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_u = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_v = list_c[-var_u]\nvar_w = list_b.index(var_v)+1\nvar_x = list_a[var_w-1]\nprint(var_x)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 27\nvar_f = 27\nvar_g = 7\nvar_h = var_f + var_g\nvar_i = 27\nvar_j = 7\nvar_k = var_i + var_j\nvar_l = 9\nvar_m = var_k - var_l\nvar_n = 27\nvar_o = 7\nvar_p = var_n + var_o\nvar_q = 9\nvar_r = var_p - var_q\nvar_s = 2\nvar_t = var_r * var_s\nlist_b= []\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_b.append(var_t)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_u = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_v = list_c[-var_u]\nvar_w = list_b.index(var_v)+1\nvar_x = list_a[var_w-1]\nprint(var_x)"
    },
    "237": {
        "category": "Correspondence",
        "question_ko": "4를 어떤 수에서 나누었더니 12가 되었습니다. 어떤 수에 3을 나눈 결과를 구하시오.",
        "question_en": "When a number is divided by 4, it is 12. Find the result of dividing the number by 3.",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "12 4 [OP_MUL] 3 [OP_DIV]",
        "solution_abst_en": "12 4 [OP_MUL] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "238": {
        "category": "Geometry",
        "question_ko": "길이가 32센티미터(㎝) 인 끈으로 가장 큰 정사각형을 만들려고 합니다. 정사각형 한 변의 길이는 몇 센티미터(㎝) 입니까?",
        "question_en": "You want to make the largest square out of a piece of string that is 32 centimeters (cm) long. How many centimeters (cm) is the length of one side of the square?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "32 4 [OP_DIV]",
        "solution_abst_en": "32 4 [OP_DIV]",
        "solution_code_ko": "var_a = 32\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 32\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "239": {
        "category": "Correspondence",
        "question_ko": "122는 어떤 수에서 46을 빼야 하는데 실수로 64를 빼서 나온 결과입니다. 바르게 계산하시오.",
        "question_en": "122 is the result of mistakenly subtracting 64 from a number. We need to subtract 46 from it. Calculate correctly.",
        "answer_ko": "140",
        "answer_en": "140",
        "solution_abst_ko": "122 64 [OP_ADD] 46 [OP_SUB]",
        "solution_abst_en": "122 64 [OP_ADD] 46 [OP_SUB]",
        "solution_code_ko": "var_a = 122\nvar_b = 64\nvar_c = var_a + var_b\nvar_d = 46\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 122\nvar_b = 64\nvar_c = var_a + var_b\nvar_d = 46\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "240": {
        "category": "Arithmetic calculation",
        "question_ko": "큰 상자 안에는 10개의 공이 있습니다. 작은 상자에 공을 5개씩 나누어 담을 때, 필요한 작은 상자의 개수는 몇 개입니까?",
        "question_en": "There are 10 balls in a big box. How many small boxes are needed to if you put 5 balls in each of the small box?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "10 5 [OP_DIV]",
        "solution_abst_en": "10 5 [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 5\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 10\nvar_b = 5\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "241": {
        "category": "Arithmetic calculation",
        "question_ko": "1톤짜리 물건 48개를 옮기려고 합니다. 4톤까지 실을 수 있는 트럭에 물건을 가득 채워 6대씩 한 번에 이동하여 물건을 나르려면, 모두 몇 번 날라야 합니까?",
        "question_en": "You're trying to move 48 one-metric ton (m/t) objects. How many trips would it take to move 6 trucks that can load up to 4-metric ton (m/t) at a time?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "48 4 6 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "48 4 6 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 48\nvar_b = 4\nvar_c = 6\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 48\nvar_b = 4\nvar_c = 6\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "242": {
        "category": "Geometry",
        "question_ko": "한 변이 5센티미터(㎝) 정사각형이 있습니다. 이 정사각형의 네 변의 길이의 합은 몇 센티미터(㎝)입니까?",
        "question_en": "There is a square with a side of 5 centimeters (cm). What is the sum of the lengths of the four sides of this square in centimeters (cm)?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "5 4 [OP_MUL]",
        "solution_abst_en": "5 4 [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "243": {
        "category": "Comparison",
        "question_ko": "기영이네 교실에는 가로, 세로 각 줄의 책상 수가 같게 사각형 모양으로 놓여 있습니다. 기영이의 자리는 앞에서 2번째, 뒤에서 4번째, 오른쪽에서 3번째에 있습니다. 가람이의 자리는 기영이의 바로 왼쪽 옆에 있고 왼쪽에서 2번째에 있습니다. 기영이네 교실의 책상은 모두 몇 개입니까?",
        "question_en": "Kiyoung's classroom is placed in a square shape with the same number of desks in each row. Kiyoung's seat is 2nd from the front, 4th from the back, and 3rd from the right. Karam's seat is right next to Kiyoung's left and is second from the left. How many desks are there in Kiyoung's classroom?",
        "answer_ko": "25",
        "answer_en": "25",
        "solution_abst_ko": "2 4 [OP_ADD] 1 [OP_SUB] 3 2 [OP_ADD] [OP_MUL]",
        "solution_abst_en": "2 4 [OP_ADD] 1 [OP_SUB] 3 2 [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = var_e * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = var_e * var_h\nprint(int(var_i))"
    },
    "244": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 도로의 0.35킬로미터(㎞) 지점에서 0.37킬로미터(㎞) 지점까지 똑같이 4구간으로 나누어 처음부터 끝까지 가로수를 심기로 하였습니다. 네 번째 지점에 심는 가로수의 위치는 몇 킬로미터(㎞) 지점인지 소수로 나타내시오.",
        "question_en": "From the 0.35 kilometer (km) point to the 0.37 kilometer (km) point of a certain road, it was decided to divide it into 4 equal sections and plant street trees from beginning to end. How many kilometers (km) is the location of the street tree planted at the fourth point using a decimal number?",
        "answer_ko": "0.37",
        "answer_en": "0.37",
        "solution_abst_ko": "0.35 0.37 0.35 [OP_SUB] 4 [OP_DIV] 4 1 [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_abst_en": "0.35 0.37 0.35 [OP_SUB] 4 [OP_DIV] 4 1 [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 0.35\nvar_b = 0.37\nvar_c = 0.35\nvar_d = var_b - var_c\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = 4\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = var_f * var_i\nvar_k = var_a + var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 0.35\nvar_b = 0.37\nvar_c = 0.35\nvar_d = var_b - var_c\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = 4\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = var_f * var_i\nvar_k = var_a + var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "245": {
        "category": "Correspondence",
        "question_ko": "225는 어떤수에 20를 더한 뒤 5로 나눠야했던 거를 실수로 20을 더한 뒤 5를 곱하여 나온 결과입니다. 바르게 계산한다면 얼마입니까?",
        "question_en": "225 is the result of adding 20 to a number and multiplying it by 5 by mistake, when it was supposed to be adding 20 and dividing it by 5. How much is it if you calculate it correctly?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "225 5 [OP_DIV] 20 [OP_SUB] 20 [OP_ADD] 5 [OP_DIV]",
        "solution_abst_en": "225 5 [OP_DIV] 20 [OP_SUB] 20 [OP_ADD] 5 [OP_DIV]",
        "solution_code_ko": "var_a = 225\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 20\nvar_e = var_c - var_d\nvar_f = 20\nvar_g = var_e + var_f\nvar_h = 5\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 225\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 20\nvar_e = var_c - var_d\nvar_f = 20\nvar_g = var_e + var_f\nvar_h = 5\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "246": {
        "category": "Comparison",
        "question_ko": "소라, 희수, 지연이는 숫자 카드 모으기 놀이를 하고 있습니다. 소라는 4와 6이 쓰여있는 카드를 집었고, 희수는 7과 5가 쓰여있는 카드를, 지연이는 3과 8이 적혀있는 카드를 모았습니다. 모든 카드에 적혀있는 수의 합이 가장 큰 사람은 누구인지 구하세요.",
        "question_en": "Sora, Heesu, and Jiyeon are playing a game of collecting number cards. Sora picked up cards with 4 and 6 written on them, Heesu picked up cards with 7 and 5 written on them, and Jiyeon collected cards with 3 and 8 written on them. Find who has the greatest sum of the numbers written on all the cards.",
        "answer_ko": "희수",
        "answer_en": "Heesu",
        "solution_abst_ko": "[OP_LIST_SOL] 소라 희수 [OP_LIST_EOL] [OP_LIST_SOL] 4 6 [OP_ADD] 3 8 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Sora Heesu Jiyeon [OP_LIST_EOL] [OP_LIST_SOL] 4 6 [OP_ADD] 7 5 [OP_ADD] 3 8 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '소라'\nvar_b = '희수'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 6\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = 8\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Sora'\nvar_b = 'Heesu'\nvar_c = 'Jiyeon'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 6\nvar_f = var_d + var_e\nvar_g = 7\nvar_h = 5\nvar_i = var_g + var_h\nvar_j = 3\nvar_k = 8\nvar_l = var_j + var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "247": {
        "category": "Arithmetic calculation",
        "question_ko": "준영이는 연필 11타를 가지고 있습니다. 이 중에서 4타를 태수에게 주고, 9자루를 종수에게 주었습니다. 준영이에게 남아 있는 연필은 몇 자루 입니까?",
        "question_en": "Junyoung has 11 dozen pencils. Of these, 4 dozen were given to Taesoo and 9 were given to Jongsoo. How many pencils are left to Junyoung?",
        "answer_ko": "75",
        "answer_en": "75",
        "solution_abst_ko": "11 4 [OP_SUB] 12 [OP_MUL] 9 [OP_SUB]",
        "solution_abst_en": "11 4 [OP_SUB] 12 [OP_MUL] 9 [OP_SUB]",
        "solution_code_ko": "var_a = 11\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 12\nvar_e = var_c * var_d\nvar_f = 9\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 11\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 12\nvar_e = var_c * var_d\nvar_f = 9\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "248": {
        "category": "Comparison",
        "question_ko": "무게가 같은 사과 5개를 담은 바구니의 무게는 2.9킬로그램(㎏) 이고, 무게가 같은 메론 3개를 담은 바구니의 무게는 2.51킬로그램(㎏) 입니다. 빈 바구니의 무게가 0.2킬로그램(㎏) 일 때 사과 한 개와 메론 한 개 중 어느 것이 더 무거운지 구해보시오.",
        "question_en": "Basket containing 5 apples of the same weight weighs 2.9 kilograms (kg), and a basket containing 3 melons of the same weight weighs 2.51 kilograms (kg). If the empty basket weighs 0.2 kilograms (kg), find out which of the apples or melons is heavier.",
        "answer_ko": "메론",
        "answer_en": "melons",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 메론 [OP_LIST_EOL] [OP_LIST_SOL] 2.9 0.2 [OP_SUB] 5 [OP_DIV] 2.51 0.2 [OP_SUB] 3 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] apples melons [OP_LIST_EOL] [OP_LIST_SOL] 2.9 0.2 [OP_SUB] 5 [OP_DIV] 2.51 0.2 [OP_SUB] 3 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '메론'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2.9\nvar_d = 0.2\nvar_e = var_c - var_d\nvar_f = 5\nvar_g = var_e / var_f\nvar_h = 2.51\nvar_i = 0.2\nvar_j = var_h - var_i\nvar_k = 3\nvar_l = var_j / var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'apples'\nvar_b = 'melons'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2.9\nvar_d = 0.2\nvar_e = var_c - var_d\nvar_f = 5\nvar_g = var_e / var_f\nvar_h = 2.51\nvar_i = 0.2\nvar_j = var_h - var_i\nvar_k = 3\nvar_l = var_j / var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "249": {
        "category": "Comparison",
        "question_ko": "미주의 집은 아파트의 집들 중 왼쪽에서 1번째, 오른쪽에서 7번째, 위에서 2번째 층, 아래에서 4번째 층에 있습니다. 각 줄마다 있는 집의 수가 같고 한 집 당 3가구가 살 때, 이 아파트는 모두 몇 가구가 삽니까?",
        "question_en": "Mijoo's house is on the 1st from the left, the 7th from the right, the 2nd from the top floor, and the 4th from the bottom floor of the apartment. If the number of houses in each row is the same and there are 3 households in each house, how many households live in this apartment?",
        "answer_ko": "105",
        "answer_en": "105",
        "solution_abst_ko": "1 7 [OP_ADD] 1 [OP_SUB] 2 4 [OP_ADD] 1 [OP_SUB] [OP_MUL] 3 [OP_MUL]",
        "solution_abst_en": "1 7 [OP_ADD] 1 [OP_SUB] 2 4 [OP_ADD] 1 [OP_SUB] [OP_MUL] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 1\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = 4\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nvar_l = 3\nvar_m = var_k * var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 1\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = 4\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nvar_l = 3\nvar_m = var_k * var_l\nprint(int(var_m))"
    },
    "250": {
        "category": "Geometry",
        "question_ko": "길이가 1미터(m) 70센티미터(㎝)인 끈으로 벽의 가로의 길이를 재었습니다. 벽의 가로의 길이가 끈의 길이의 5배보다 80센티미터(㎝) 더 길다면, 이 벽의 가로 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "The width of the wall was measured with a string measuring 1 meter (m) and 70 centimeters (cm) in length. If the width of the wall is 80 centimeters (cm) greater than 5 times the length of the string, what is the width of this wall in centimeters (cm)?",
        "answer_ko": "930",
        "answer_en": "930",
        "solution_abst_ko": "1 100 [OP_MUL] 70 [OP_ADD] 5 [OP_MUL] 80 [OP_ADD]",
        "solution_abst_en": "1 100 [OP_MUL] 70 [OP_ADD] 5 [OP_MUL] 80 [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 70\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = var_e * var_f\nvar_h = 80\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 70\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = var_e * var_f\nvar_h = 80\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "251": {
        "category": "Possibility",
        "question_ko": "세자리 수를 0, 3, 5, 6 중에서 3번 뽑아 만들려 합니다. 만들어진 수 중에서 가장 작은 수는 무엇인가요?",
        "question_en": "I am trying to make a three digit number by picking 3 times out of 0, 3, 5, 6. What is the smallest number that can be made?",
        "answer_ko": "305",
        "answer_en": "305",
        "solution_abst_ko": "[OP_LIST_SOL] 0 3 5 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 3 5 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 0\nvar_b = 3\nvar_c = 5\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 0\nvar_b = 3\nvar_c = 5\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nprint(int(var_g))"
    },
    "252": {
        "category": "Arithmetic calculation",
        "question_ko": "축사에 돼지 156마리, 소 267마리가 있다. 이 중 115마리가 오늘 팔려 나갔다고 한다면 축사에는 몇 마리가 남아있는지 구하시오.",
        "question_en": "There are 156 pigs and 267 cows in the barn. If 115 of them were sold today, how many are left in the barn?",
        "answer_ko": "308",
        "answer_en": "308",
        "solution_abst_ko": "156 267 [OP_ADD] 115 [OP_SUB]",
        "solution_abst_en": "156 267 [OP_ADD] 115 [OP_SUB]",
        "solution_code_ko": "var_a = 156\nvar_b = 267\nvar_c = var_a + var_b\nvar_d = 115\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 156\nvar_b = 267\nvar_c = var_a + var_b\nvar_d = 115\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "253": {
        "category": "Geometry",
        "question_ko": "둘레가 46센티미터(㎝) 이고 세로가 9센티미터(㎝) 인 직사각형 모양의 수첩이 있습니다. 이 수첩의 가로는 몇 센티미터(㎝) 입니까?",
        "question_en": "You have a rectangular-shaped notebook with a circumference of 46 centimeters (cm) and a length of 9 centimeters (cm). How many centimeters (cm) is the width of this notebook?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "46 2 [OP_DIV] 9 [OP_SUB]",
        "solution_abst_en": "46 2 [OP_DIV] 9 [OP_SUB]",
        "solution_code_ko": "var_a = 46\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 9\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 46\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 9\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "254": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중에서 가장 큰 수와 가장 작은 수의 차는 얼마입니까?",
        "question_en": "There are three numbers 10, 11, and 12. What is the difference between the largest number and the smallest number?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e - var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e - var_g\nprint(int(var_h))"
    },
    "255": {
        "category": "Correspondence",
        "question_ko": "네 수 A, B, C, D가 있습니다. 네 자리 수끼리의 덧셈식 4A5B+C2D7=8070에서 C를 구하시오.",
        "question_en": "There are four numbers A, B, C, and D. Find C from the four-digit addition formula 4A5B+C2D7=8070.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "4A5B+C2D7=8070 C [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "4A5B+C2D7=8070 C [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '4A5B+C2D7=8070'\nvar_b = 'C'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '4A5B+C2D7=8070'\nvar_b = 'C'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "256": {
        "category": "Correspondence",
        "question_ko": "4와 어떤 수의 곱을 7로 나누고 12를 더했더니 36이 되었습니다. 어떤 수를 구하세요.",
        "question_en": "When we divide the product of 4 and a number by 7 and add 12, we get 36. Find this number",
        "answer_ko": "42",
        "answer_en": "42",
        "solution_abst_ko": "36 12 [OP_SUB] 7 [OP_MUL] 4 [OP_DIV]",
        "solution_abst_en": "36 12 [OP_SUB] 7 [OP_MUL] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 36\nvar_b = 12\nvar_c = var_a - var_b\nvar_d = 7\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 36\nvar_b = 12\nvar_c = var_a - var_b\nvar_d = 7\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "257": {
        "category": "Geometry",
        "question_ko": "11개의 변으로 둘러싸인 도형의 대각선의 개수는 몇 개입니까?",
        "question_en": "How many diagonals are there in a figure bounded by 11 sides?",
        "answer_ko": "44",
        "answer_en": "44",
        "solution_abst_ko": "11 11 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "11 11 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 11\nvar_b = 11\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 11\nvar_b = 11\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "258": {
        "category": "Comparison",
        "question_ko": "두 개의 과일 상자가 있습니다. 사과 상자는 3/5킬로그램(㎏), 귤 상자는 0.49킬로그램(㎏)으로 둘 중 더 무거운 상자는 무엇입니까?",
        "question_en": "There are two fruit crates. The apple box is 3/5 kilograms (kg) and the orange box is 0.49 kilograms (kg). Which box is the heavier of the two?",
        "answer_ko": "사과",
        "answer_en": "apple",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 귤 [OP_LIST_EOL] [OP_LIST_SOL] 3/5 0.49 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] apple orange [OP_LIST_EOL] [OP_LIST_SOL] 3/5 0.49 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '귤'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.6\nvar_d = 0.49\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'apple'\nvar_b = 'orange'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.6\nvar_d = 0.49\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "259": {
        "category": "Arithmetic calculation",
        "question_ko": "마법 필통이 있습니다. 금색 필통에 필기구를 넣으면 길이가 10배가 되고, 은색 필통에 넣으면 길이가 1/100이 됩니다. 기훈이는 13.5센티미터(㎝)인 연필을 금색 주머니에 3번, 은색 주머니에 2번 넣었다 뺐습니다. 지금 기훈이의 연필은 몇 센티미터(㎝)입니까?",
        "question_en": "There are magic pencil cases, in which writing materials become 10 times longer when put in a gold pencil case, and 1/100 times longer when put in a silver pencil case. Kihoon put the 13.5 centimeters (cm) pencil in and out of the gold pencil case 3 times and the silver pencil case 2 times. How long is Kihoon's pencil now in centimeters (cm)?",
        "answer_ko": "1.35",
        "answer_en": "1.35",
        "solution_abst_ko": "13.5 10 3 [OP_POW] [OP_MUL] 1/100 2 [OP_POW] [OP_MUL]",
        "solution_abst_en": "13.5 10 3 [OP_POW] [OP_MUL] 1/100 2 [OP_POW] [OP_MUL]",
        "solution_code_ko": "var_a = 13.5\nvar_b = 10\nvar_c = 3\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 0.01\nvar_g = 2\nvar_h = var_f ** var_g\nvar_i = var_e * var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 13.5\nvar_b = 10\nvar_c = 3\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 0.01\nvar_g = 2\nvar_h = var_f ** var_g\nvar_i = var_e * var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "260": {
        "category": "Possibility",
        "question_ko": "4개의 서로 다른 아이스크림을 친구에게 나누어주려고 한다. 친구는 가희, 나희, 다희, 라희 4명이 있다. 경우의 수는 몇 가지인가?",
        "question_en": "You want to distribute 4 different ice creams to your friend. There are 4 friends: Kahi, Nahee, Dahee, and Rahee. How many cases are there?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "4 4 [OP_PERM]",
        "solution_abst_en": "4 4 [OP_PERM]",
        "solution_code_ko": "var_a = 4\nvar_b = 4\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 4\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))"
    },
    "261": {
        "category": "Geometry",
        "question_ko": "둘레의 길이가 8미터(m)인 정삼각형의 한 변의 길이는 몇 미터(m)입니까?",
        "question_en": "What is the side length in meters (m) of an equilateral triangle with a perimeter of 8 meters (m)?",
        "answer_ko": "2.67",
        "answer_en": "2.67",
        "solution_abst_ko": "8 3 [OP_DIV]",
        "solution_abst_en": "8 3 [OP_DIV]",
        "solution_code_ko": "var_a = 8\nvar_b = 3\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 8\nvar_b = 3\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "262": {
        "category": "Possibility",
        "question_ko": "3, 4, 6이 주어졌을 때, 주어진 수를 한 번씩 모두 사용하여 450보다 작은 세 자리 수의 개수를 구하시오.",
        "question_en": "Given 3, 4, and 6, find the number of three-digit numbers less than 450, using all the given numbers once.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 3 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 450 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 3 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 450 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 3\nvar_b = 4\nvar_c = 6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 450\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 3\nvar_b = 4\nvar_c = 6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 450\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "263": {
        "category": "Possibility",
        "question_ko": "숫자카드 5, 7, 8이 있을 때 한 장씩 모두 사용하여 만들 수 있는 세 자리 자연수는 총 몇 개입니까?",
        "question_en": "Given the number cards 5, 7, and 8, how many total three-digit numbers can be formed by using all of them?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 5 7 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 5 7 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 5\nvar_b = 7\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 7\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "264": {
        "category": "Comparison",
        "question_ko": "물 1리터(L)와 물 4리터(L)를 모양과 크기가 같은 병에 각각 똑같이 나누어 담으려고 합니다. 물 1리터(L)를 병 가 3개에, 물 4리터(L)를 병 나 5개에 남김없이 똑같이 나누어 담을 때, 병 가와 병 나 중 어느 병에 물이 더 많을까요?",
        "question_en": "You want to divide 1 liter (L) of water and 4 liters (L) of water equally into bottles of the same shape and size. If 1 liter (L) of water is divided equally into 3 A bottles, and 4 liters (L) of water is equally divided into 5 B bottles, which bottle has more water, bottle A or bottle B?",
        "answer_ko": "나",
        "answer_en": "B",
        "solution_abst_ko": "[OP_LIST_SOL] 가 나 [OP_LIST_EOL] [OP_LIST_SOL] 1 3 [OP_DIV] 4 5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 1 3 [OP_DIV] 4 5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '가'\nvar_b = '나'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = 4\nvar_g = 5\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = 4\nvar_g = 5\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "265": {
        "category": "Arithmetic calculation",
        "question_ko": "학교를 돌 때 처음에는 시속 3킬로미터(㎞)로 걸었고, 두 번째는 그보다 2킬로미터(㎞) 더 걸은 대신 시속 4킬로미터(㎞)로 걸었다. 총 4시간이 걸렸다고 할 때, 처음 돌 때 걸린 시간은 얼마인가?",
        "question_en": "When you walked around the school for the first time, you walked at 3 kilometers (km) per hour. For the second time, you walked 2 kilometers (km) more than the first time at the speed of 4 kilometers (km) per hour. If the walk took 4 hours in total, how much time would be taken for the first walk?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "4 2 4 [OP_DIV] [OP_SUB] 1 3 [OP_DIV] 1 4 [OP_DIV] [OP_ADD] [OP_DIV] 3 [OP_DIV]",
        "solution_abst_en": "4 2 4 [OP_DIV] [OP_SUB] 1 3 [OP_DIV] 1 4 [OP_DIV] [OP_ADD] [OP_DIV] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = 3\nvar_h = var_f / var_g\nvar_i = 1\nvar_j = 4\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_e / var_l\nvar_n = 3\nvar_o = var_m / var_n\nprint(int(eval('{:.2f}'.format(round(var_o+1e-10,2)))))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = 3\nvar_h = var_f / var_g\nvar_i = 1\nvar_j = 4\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_e / var_l\nvar_n = 3\nvar_o = var_m / var_n\nprint(int(eval('{:.2f}'.format(round(var_o+1e-10,2)))))"
    },
    "266": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 1.08킬로미터(㎞)인 도로의 양쪽에 처음부터 끝까지 가로수를 심으려고 합니다. 13.5미터(m)마다 1그루씩 심으려면 가로수는 모두 몇 그루가 필요합니까?",
        "question_en": "We plan to plant street trees on both sides of the 1.08 kilometer (km) long road from beginning to end. How many street trees are needed to plant one tree every 13.5 meters (m)?",
        "answer_ko": "162",
        "answer_en": "162",
        "solution_abst_ko": "1.08 1000 [OP_MUL] 13.5 [OP_DIV] 1 [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "1.08 1000 [OP_MUL] 13.5 [OP_DIV] 1 [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 1.08\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 13.5\nvar_e = var_c / var_d\nvar_f = 1\nvar_g = var_e + var_f\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1.08\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 13.5\nvar_e = var_c / var_d\nvar_f = 1\nvar_g = var_e + var_f\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "267": {
        "category": "Possibility",
        "question_ko": "정국, 지민, 윤기, 유나, 태형 중에서 반장, 부사장, 홍보 담당자를 선발 할 예정이다. 가능한 총 케이스 수는 얼마입니까?",
        "question_en": "Among Jungkook, Jimin, Yoongi, Yuna, and Taehyung, the class president, vice president, and public relations officer will be selected. What is the total number of possible cases?",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 지민 윤기 유나 태형 [OP_LIST_EOL] [OP_LIST_LEN] 3 [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Jimin Yoongi Yuna Taehyung [OP_LIST_EOL] [OP_LIST_LEN] 3 [OP_PERM]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '지민'\nvar_c = '윤기'\nvar_d = '유나'\nvar_e = '태형'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 3\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nprint(int(var_h))",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Jimin'\nvar_c = 'Yoongi'\nvar_d = 'Yuna'\nvar_e = 'Taehyung'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 3\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nprint(int(var_h))"
    },
    "268": {
        "category": "Possibility",
        "question_ko": "8, 7, 9이 적혀있는 숫자카드에서 2가지 카드를 고르려고 합니다. 가능한 경우의 수는 모두 몇 가지인지 구하시오.",
        "question_en": "You want to choose two cards from the number cards with the numbers 8, 7, and 9 on them. Find how many possible cases there are.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 8 7 9 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] 8 7 9 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_code_ko": "var_a = 8\nvar_b = 7\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f / (i+1)\nprint(int(var_f))",
        "solution_code_en": "var_a = 8\nvar_b = 7\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f / (i+1)\nprint(int(var_f))"
    },
    "269": {
        "category": "Arithmetic calculation",
        "question_ko": "민수는 100000원을 저축하려고 합니다. 하루에 7000원씩 저축을 한다고 할 때, 며칠 후에 목표량을 채울 수 있을까요?",
        "question_en": "Minsu wants to save 100,000 won. If he saves 7,000 won per day, how many days will it take for him to reach his goal?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "100000 7000 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "100000 7000 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 100000\nvar_b = 7000\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))",
        "solution_code_en": "var_a = 100000\nvar_b = 7000\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))"
    },
    "270": {
        "category": "Arithmetic calculation",
        "question_ko": "지아와 유준이는 포크를 3개씩 가졌더니 2개가 남았습니다. 처음에 있던 포크는 몇 개 입니까?",
        "question_en": "Jia and Yujun had 3 forks each, so there are 2 left. How many forks were there initially?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "2 3 2 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "2 3 2 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "271": {
        "category": "Comparison",
        "question_ko": "20명의 학생들이 한 줄로 줄을 섰습니다. 윤기의 뒤에는 정국이가 서있고, 정국이 뒤에는 11명의 학생들이 서 있습니다. 윤기의 앞에 서 있는 학생은 몇 명입니까?",
        "question_en": "20 students lined up in a single line. Jungkook is standing behind Yoongi, and 11 students are standing behind Jungkook. How many students are standing in front of Yoongi?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "20 11 [OP_SUB] 1 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "20 11 [OP_SUB] 1 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "272": {
        "category": "Possibility",
        "question_ko": "자동차 게임을 할 때, 3명의 캐릭터 중 하나를 고르고, 다시 3개의 차 중 하나를 골라야 합니다. 경우의 수는 모두 몇 가지입니까?",
        "question_en": "When you play a car game, you have to choose one character from three characters, and then one car from three cars. How many cases are there?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "3 3 [OP_MUL]",
        "solution_abst_en": "3 3 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "273": {
        "category": "Geometry",
        "question_ko": "정육면체 모양의 겉넓이가 864제곱센티미터(㎠)인 상자가 있습니다. 이 상자의 한 변의 길이는 몇 센티미터(㎝)일까요?",
        "question_en": "There is a box in the shape of a cube with a surface area of 864 square centimeters (cm2). How many centimeters (cm) is the length of one side of this box?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "864 6 [OP_DIV] 1/2 [OP_POW]",
        "solution_abst_en": "864 6 [OP_DIV] 1/2 [OP_POW]",
        "solution_code_ko": "var_a = 864\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 864\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nprint(int(var_e))"
    },
    "274": {
        "category": "Arithmetic calculation",
        "question_ko": "10원짜리 동전 10개 중 몇개를 윤기에게 주었더니 7개가 남았습니다. 윤기에게 얼마를 주었는지 구하시오.",
        "question_en": "I gave some ten 10 won coins to Yoongi, and there are 7 left. Find out how much he gave to Yoongi.",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "10 10 7 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "10 10 7 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 10\nvar_c = 7\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 10\nvar_c = 7\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nprint(int(var_e))"
    },
    "275": {
        "category": "Geometry",
        "question_ko": "지혜는 한 변의 길이가 14센티미터(㎝)인 정사각형 모양의 색종이를 갖고 있습니다. 이 색종이를 가로가 8센티미터(㎝), 세로가 2센티미터(㎝)인 직사각형 모양으로 여러개 자르려고 합니다. 이러한 직사각형 모양의 종이 조각을 최대 몇 개 얻을 수 있습니까?",
        "question_en": "Jihye holds a piece of colored paper in the shape of a square whose side is 14 centimeters (cm). When she cut it into rectangles that are 8 centimeters (cm) long and 2 centimeters (cm) wide. How many of these rectangular pieces of paper does she get at most?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "14 2 [OP_POW] 8 2 [OP_MUL] [OP_FDIV]",
        "solution_abst_en": "14 2 [OP_POW] 8 2 [OP_MUL] [OP_FDIV]",
        "solution_code_ko": "var_a = 14\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 8\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c // var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 14\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 8\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c // var_f\nprint(int(var_g))"
    },
    "276": {
        "category": "Geometry",
        "question_ko": "밑면의 넓이가 10제곱센티미터(㎠)이고 높이가 73센티미터(㎝)인 직육면체보다 부피가 1세제곱센티미터(㎤) 더 적은 정육면체의 한 모서리의 길이는 몇 센티미터(㎝)인지 구하세요.",
        "question_en": "Find how many centimeters (cm) is the length of one corner of a cube whose volume is 1 square centimeter (cm2) less than a cuboid whose base is 10 square centimeter (cm2) and whose height is 73 centimeters (cm).",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "10 73 [OP_MUL] 1 [OP_SUB] 1/3 [OP_POW]",
        "solution_abst_en": "10 73 [OP_MUL] 1 [OP_SUB] 1/3 [OP_POW]",
        "solution_code_ko": "var_a = 10\nvar_b = 73\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 0.3333333333333333\nvar_g = var_e ** var_f\nprint(int(eval('{:.2f}'.format(round(var_g+1e-10,2)))))",
        "solution_code_en": "var_a = 10\nvar_b = 73\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 0.3333333333333333\nvar_g = var_e ** var_f\nprint(int(eval('{:.2f}'.format(round(var_g+1e-10,2)))))"
    },
    "277": {
        "category": "Geometry",
        "question_ko": "직육면체 모양의 인형이 있습니다. 이 인형의 부피는 16세제곱센티미터(㎤)입니다. 그리고, 바닥에 접한 면의 가로는 6센티미터(㎝), 세로는 7센티미터(㎝)입니다. 이 인형의 전체 겉넓이를 구하시오",
        "question_en": "There is a doll in the shape of a rectangular cuboid. The volume of this doll is 16 square centimeters (cm2). And, the side facing the floor is 6 centimeters (cm) wide and 7 centimeters (cm) long. Find the total surface area of this doll.",
        "answer_ko": "93.90",
        "answer_en": "93.9",
        "solution_abst_ko": "16 7 [OP_DIV] 6 [OP_DIV] 7 6 [OP_ADD] [OP_MUL] 7 6 [OP_MUL] [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "16 7 [OP_DIV] 6 [OP_DIV] 7 6 [OP_ADD] [OP_MUL] 7 6 [OP_MUL] [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 16\nvar_b = 7\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c / var_d\nvar_f = 7\nvar_g = 6\nvar_h = var_f + var_g\nvar_i = var_e * var_h\nvar_j = 7\nvar_k = 6\nvar_l = var_j * var_k\nvar_m = var_i + var_l\nvar_n = 2\nvar_o = var_m * var_n\nprint('{:.2f}'.format(round(var_o+1e-10,2)))",
        "solution_code_en": "var_a = 16\nvar_b = 7\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c / var_d\nvar_f = 7\nvar_g = 6\nvar_h = var_f + var_g\nvar_i = var_e * var_h\nvar_j = 7\nvar_k = 6\nvar_l = var_j * var_k\nvar_m = var_i + var_l\nvar_n = 2\nvar_o = var_m * var_n\nprint('{:.2f}'.format(round(var_o+1e-10,2)))"
    },
    "278": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 연속된 자연수의 합이 180입니다. 이 5개의 수 중 가장 큰 수를 쓰시오.",
        "question_en": "The sum of 5 consecutive natural numbers is 180. Write the largest of these 5 numbers.",
        "answer_ko": "38",
        "answer_en": "38",
        "solution_abst_ko": "180 5 [OP_DIV] 5 2 [OP_FDIV] [OP_ADD]",
        "solution_abst_en": "180 5 [OP_DIV] 5 2 [OP_FDIV] [OP_ADD]",
        "solution_code_ko": "var_a = 180\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d // var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 180\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d // var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "279": {
        "category": "Arithmetic calculation",
        "question_ko": "유선이는 아침에 일어났더니 감기 기운이 있어 병원에 들렀다 등교를 하기로 했습니다. 유선이네 집에서 병원까지는 1킬로미터(㎞) 700미터(m)이고, 병원에서 학교까지의 거리는 900미터(m)입니다. 유선이네 집에서 병원을 거쳐 학교까지 가는 거리의 중간 지점은 집에서부터 몇 미터(m)인지 구하시오.",
        "question_en": "Yooseon wakes up in the morning and has a cold, so she decides to stop by the hospital and then go to school. It is 1 kilometer (km) 700 meters (m) from Yooseon’s house to the hospital, and the distance from the hospital to the school is 900 meters (m). How many meters (m) is the midway point of a distance starting from Yooseon's house, passing by the hospital and to the school, apart from of Yooseon's house?",
        "answer_ko": "1300",
        "answer_en": "1300",
        "solution_abst_ko": "1 1000 [OP_MUL] 700 [OP_ADD] 900 [OP_ADD] 2 [OP_DIV]",
        "solution_abst_en": "1 1000 [OP_MUL] 700 [OP_ADD] 900 [OP_ADD] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 700\nvar_e = var_c + var_d\nvar_f = 900\nvar_g = var_e + var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 700\nvar_e = var_c + var_d\nvar_f = 900\nvar_g = var_e + var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "280": {
        "category": "Comparison",
        "question_ko": "줄넘기를 재현이는 23번 했고, 슬기는 19번 했습니다. 미란이는 줄넘기를 1번째에 18번, 2번째에 21번 했습니다. 미란이보다 재현이가 줄넘기를 더 많이 하려면 2번째에는 적어도 몇 번을 해야 합니까?",
        "question_en": "Jaehyun skipped 23 times and Seulgi jumped 19 times. Miran jumped rope 18 times in the first and 21 times in the second. In order for Jaehyun to jump rope more than Miran, at least how many times should he do in the second round?",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "18 21 [OP_ADD] 23 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "18 21 [OP_ADD] 23 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 18\nvar_b = 21\nvar_c = var_a + var_b\nvar_d = 23\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 18\nvar_b = 21\nvar_c = var_a + var_b\nvar_d = 23\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "281": {
        "category": "Comparison",
        "question_ko": "유승, 신영, 석기는 멀리뛰기를 하였습니다. 유승이는 15/8미터(m), 신영이는 2미터(m), 석기는 17/8미터(m)를 뛰었습니다. 가장 멀리 뛴 사람은 누구입니까?",
        "question_en": "Yooseung, Shinyoung, and Seokgi did the long jump. Yooseung jumped 15/8 meters (m), Shinyoung 2 meters (m), and Seokgi 17/8 meters (m). Who jumped the furthest?",
        "answer_ko": "석기",
        "answer_en": "Seokgi",
        "solution_abst_ko": "[OP_LIST_SOL] 유승 신영 석기 [OP_LIST_EOL] [OP_LIST_SOL] 15/8 2 17/8 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yooseung Shinyoung Seokgi [OP_LIST_EOL] [OP_LIST_SOL] 15/8 2 17/8 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '유승'\nvar_b = '신영'\nvar_c = '석기'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1.875\nvar_e = 2\nvar_f = 2.125\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Yooseung'\nvar_b = 'Shinyoung'\nvar_c = 'Seokgi'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1.875\nvar_e = 2\nvar_f = 2.125\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "282": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 46으로 나눈 몫에서 27을 뺐더니 46이 되었습니다. 어떤 수를 구하십시오.",
        "question_en": "27 is subtracted from the quotient of a number divided by 46, which gives 46. Find the number.",
        "answer_ko": "3358",
        "answer_en": "3358",
        "solution_abst_ko": "27 46 [OP_ADD] 46 [OP_MUL]",
        "solution_abst_en": "27 46 [OP_ADD] 46 [OP_MUL]",
        "solution_code_ko": "var_a = 27\nvar_b = 46\nvar_c = var_a + var_b\nvar_d = 46\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 27\nvar_b = 46\nvar_c = var_a + var_b\nvar_d = 46\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "283": {
        "category": "Possibility",
        "question_ko": "다섯 개의 숫자 0, 1, 2, 3, 4 , 5 중에서 2개를 골라 두 자리의 수를 만들었다. 같은 수를 여러 번 사용해도 된다면, 만들 수 있는 모든 수들의 합은 얼마인가?",
        "question_en": "Choose two of the five numbers 0, 1, 2, 3, 4, and 5 to make a two-digit number. If you can use the same number multiple times, what is the sum of all possible numbers?",
        "answer_ko": "975",
        "answer_en": "975",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 4 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PRODUCT] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 4 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PRODUCT] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nvar_f = 5\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_b = [float(i) for i in list_b]\nvar_h = sum(list_b)\nprint(int(var_h))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nvar_f = 5\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_b = [float(i) for i in list_b]\nvar_h = sum(list_b)\nprint(int(var_h))"
    },
    "284": {
        "category": "Arithmetic calculation",
        "question_ko": "82명이 타고 있는 기차에 17명이 더 타고 몇 명이 내렸더니 73명이 되었습니다. 몇 명의 사람이 기차에서 내렸는지 구하시오.",
        "question_en": "17 more people got on the train with 82 people on it, and a few people got off. If 73 people were on the train, find how many people left the train.",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "82 17 [OP_ADD] 73 [OP_SUB]",
        "solution_abst_en": "82 17 [OP_ADD] 73 [OP_SUB]",
        "solution_code_ko": "var_a = 82\nvar_b = 17\nvar_c = var_a + var_b\nvar_d = 73\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 82\nvar_b = 17\nvar_c = var_a + var_b\nvar_d = 73\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "285": {
        "category": "Possibility",
        "question_ko": "3, 4, 6이 주어졌을 때, 주어진 수를 한 번씩 모두 사용하여 450보다 큰 세 자리 수의 개수를 구하시오.",
        "question_en": "When 3, 4, and 6 are given, find how many three-digit numbers using these three numbers exist, that is bigger than 450",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 3 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 450 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 3 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 450 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 3\nvar_b = 4\nvar_c = 6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 450\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 3\nvar_b = 4\nvar_c = 6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 450\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "286": {
        "category": "Comparison",
        "question_ko": "정국이는 6에서 3을 나눈 몫 만큼 모았고, 윤기는 4를 모았습니다. 누가 더 작은 수를 모았습니까?",
        "question_en": "Jungkook collected 6 divided by 3, and Yoongi collected 4. Who got the smaller number?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 윤기 [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_FDIV] 4 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Yoongi [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_FDIV] 4 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '윤기'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 3\nvar_e = var_c // var_d\nvar_f = 4\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Yoongi'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 3\nvar_e = var_c // var_d\nvar_f = 4\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "287": {
        "category": "Arithmetic calculation",
        "question_ko": "똑같은 무게의 사과 10개가 들어 있는 상자의 무게를 재었더니 3.1킬로그램(㎏)이었습니다. 이 상자에서 사과 1개를 빼낸 후 다시 무게를 재었더니 2.81킬로그램(㎏)이었습니다.빈 상자의 무게는 몇 킬로그램(㎏)인지 구해 보시오.",
        "question_en": "A box containing 10 apples of the same weight was weighed and found to be 3.1 kg (kg). After removing one apple from the box, it became 2.81 kilograms (kg). Find the weight in kilograms (kg) of the empty box.",
        "answer_ko": "0.20",
        "answer_en": "0.2",
        "solution_abst_ko": "3.1 3.1 2.81 [OP_SUB] 10 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "3.1 3.1 2.81 [OP_SUB] 10 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 3.1\nvar_b = 3.1\nvar_c = 2.81\nvar_d = var_b - var_c\nvar_e = 10\nvar_f = var_d * var_e\nvar_g = var_a - var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 3.1\nvar_b = 3.1\nvar_c = 2.81\nvar_d = var_b - var_c\nvar_e = 10\nvar_f = var_d * var_e\nvar_g = var_a - var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "288": {
        "category": "Arithmetic calculation",
        "question_ko": "사자 한 마리, 호랑이 한 마리, 판다 한 마리의 몸무게의 합은 106킬로그램(㎏) 600그램(g)입니다. 판다는 호랑이보다 7킬로그램(㎏) 700그램(g) 덜 나가고, 호랑이는 사자보다 4.8킬로그램(㎏) 덜 나갑니다. 사자 한 마리의 몸무게는 몇 킬로그램(㎏)입니까?",
        "question_en": "The total weight of one lion, one tiger, and one panda is 106 kilograms (kg) and 600 grams (g). A panda weighs 7 kilograms (kg) and 700 grams (g) less than a tiger, and a tiger weighs 4.8 kilograms (kg) less than a lion. How many kilograms (kg) does one lion weigh?",
        "answer_ko": "41.30",
        "answer_en": "41.3",
        "solution_abst_ko": "106 600 1000 [OP_DIV] [OP_ADD] 7 700 1000 [OP_DIV] [OP_ADD] [OP_ADD] 4.8 2 [OP_MUL] [OP_ADD] 3 [OP_DIV]",
        "solution_abst_en": "106 600 1000 [OP_DIV] [OP_ADD] 7 700 1000 [OP_DIV] [OP_ADD] [OP_ADD] 4.8 2 [OP_MUL] [OP_ADD] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 106\nvar_b = 600\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 7\nvar_g = 700\nvar_h = 1000\nvar_i = var_g / var_h\nvar_j = var_f + var_i\nvar_k = var_e + var_j\nvar_l = 4.8\nvar_m = 2\nvar_n = var_l * var_m\nvar_o = var_k + var_n\nvar_p = 3\nvar_q = var_o / var_p\nprint('{:.2f}'.format(round(var_q+1e-10,2)))",
        "solution_code_en": "var_a = 106\nvar_b = 600\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 7\nvar_g = 700\nvar_h = 1000\nvar_i = var_g / var_h\nvar_j = var_f + var_i\nvar_k = var_e + var_j\nvar_l = 4.8\nvar_m = 2\nvar_n = var_l * var_m\nvar_o = var_k + var_n\nvar_p = 3\nvar_q = var_o / var_p\nprint('{:.2f}'.format(round(var_q+1e-10,2)))"
    },
    "289": {
        "category": "Comparison",
        "question_ko": "윤기는 20명의 친구들과 함께 농구공 많이 넣기 놀이를 하고 있습니다. 11명의 학생들이 윤기보다 공을 못 넣었을 때, 윤기보다 공을 많이 넣은 학생은 몇 명입니까?",
        "question_en": "Yoongi is playing a game of throwing basketballs with his 20 friends. If 11 students scored less than Yoongi, how many students scored more than Yoongi?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "20 11 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "20 11 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "290": {
        "category": "Arithmetic calculation",
        "question_ko": "한 사람당 수박을 2/5통씩 먹으려고 합니다. 10명이 먹기 위해서는 수박을 몇 통 사야 합니까?",
        "question_en": "A group of people wants to eat 2/5 of a watermelon per person. How many watermelons are needed to feed 10 people?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "2/5 10 [OP_MUL]",
        "solution_abst_en": "2/5 10 [OP_MUL]",
        "solution_code_ko": "var_a = 0.4\nvar_b = 10\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 0.4\nvar_b = 10\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "291": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 25센티미터(㎝)인 양초가 있습니다. 이 양초가 10분에 1.75센티미터(㎝)씩 탄다면 불을 붙인지 몇 분 후에 양초의 길이가 11센티미터(㎝)가 되겠습니까?",
        "question_en": "You have a candle that is 25 centimeters (cm) long. If this candle burns 1.75 centimeters (cm) in 10 minutes, how many minutes after lighting will it be 11 centimeters (cm) long?",
        "answer_ko": "80",
        "answer_en": "80",
        "solution_abst_ko": "25 11 [OP_SUB] 1.75 10 [OP_DIV] [OP_DIV]",
        "solution_abst_en": "25 11 [OP_SUB] 1.75 10 [OP_DIV] [OP_DIV]",
        "solution_code_ko": "var_a = 25\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1.75\nvar_e = 10\nvar_f = var_d / var_e\nvar_g = var_c / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 25\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1.75\nvar_e = 10\nvar_f = var_d / var_e\nvar_g = var_c / var_f\nprint(int(var_g))"
    },
    "292": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.9, 1/3 중에서 0.7보다 큰 수 중 가장 작은 수는 무엇인가요?",
        "question_en": "Which of 0.8, 1/2, 0.9, 1/3 is the smallest number greater than 0.7?",
        "answer_ko": "0.80",
        "answer_en": "0.8",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.7 [OP_LIST_MORE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.7 [OP_LIST_MORE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.7\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.7\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "293": {
        "category": "Arithmetic calculation",
        "question_ko": "연정이와 동훈이는 스케이트를 타고, 둘레가 3킬로미터(㎞)인 스케이트장에서 동시에 서로 반대 방향으로 출발하였다. 연정이는 매분 100미터(m)의 속력으로, 동훈이는 매분 150미터(m)의 속력으로 스케이트를 타면 몇 분 후에 처음으로 두 사람이 다시 만나는지 구하여라",
        "question_en": "Yeonjeong and Donghun started skating in opposite directions at the same time on a skating rink with a circumference of 3 km (km). If Yeonjeong skates at a speed of 100 meters (m) per minute and Donghun skates at a speed of 150 meters (m) per minute, find the two meet again for the first time in a few minutes.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "3 100 1000 [OP_DIV] 150 1000 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_abst_en": "3 100 1000 [OP_DIV] 150 1000 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 3\nvar_b = 100\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = 150\nvar_f = 1000\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = var_a / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 3\nvar_b = 100\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = 150\nvar_f = 1000\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = var_a / var_h\nprint(int(var_i))"
    },
    "294": {
        "category": "Correspondence",
        "question_ko": "A, B는 서로 다른 두 자연수입니다. A를 7로 나누면 몫은 15, 나머지는 B입니다. B가 될 수 있는 수 중에 가장 작은 수 일때 A를 구하시오.",
        "question_en": "A and B are two different natural numbers. When A is divided by 7, the quotient is 15 and the remainder is B. Find A when B is the smallest possible number.",
        "answer_ko": "105",
        "answer_en": "105",
        "solution_abst_ko": "7 15 [OP_MUL]",
        "solution_abst_en": "7 15 [OP_MUL]",
        "solution_code_ko": "var_a = 7\nvar_b = 15\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 7\nvar_b = 15\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "295": {
        "category": "Possibility",
        "question_ko": "1, 6, 8이 그려진 장난감이 있습니다. 로운이가 처음 고르는 것을 백의 자리, 두 번째는 십의 자리, 세 번째는 일의 자리라고 할 때, 로운이가 만들 수 있는 수 중 가장 큰 수와 세 번째로 큰 수의 합을 구하시오. 단, 같은 장난감을 여러 번 고를 수 없습니다.",
        "question_en": "There are toys with 1, 6 and 8 drawn on them. Let's say the first one Rowoon chooses is the hundred's place, the second is the tens' place, and the third is the ones' place. Find the sum of the largest number and the third largest number that Rowoon can make. However, Rowwon cannot select the same toy multiple times.",
        "answer_ko": "1542",
        "answer_en": "1542",
        "solution_abst_ko": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 3 [OP_LIST_MAX] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 3 [OP_LIST_MAX] [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[-var_g]\nvar_i = var_f + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[-var_g]\nvar_i = var_f + var_h\nprint(int(var_i))"
    },
    "296": {
        "category": "Comparison",
        "question_ko": "상자 안에 빨간공과 빨간공 보다 17개 더 많은 파란공이 있습니다. 민수가 파란공 57개, 빨간공 18개를 넣고 44개를 뺐습니다. 상자 안을 확인해보니 총 502개의 공이 있었을 때, 처음 상자 안에 있던 파란공의 개수를 구하시오.",
        "question_en": "There are red balls and blue balls in the box with blue balls being 17 more than the red balls. Minsu put in 57 blue balls and 18 red balls and subtracted 44 balls. When you checked the inside of the box and there were 502 balls in total, find the number of blue balls that were in the box at the beginning.",
        "answer_ko": "244",
        "answer_en": "244",
        "solution_abst_ko": "502 18 57 [OP_ADD] 44 [OP_SUB] [OP_SUB] 17 [OP_ADD] 2 [OP_DIV]",
        "solution_abst_en": "502 18 57 [OP_ADD] 44 [OP_SUB] [OP_SUB] 17 [OP_ADD] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 502\nvar_b = 18\nvar_c = 57\nvar_d = var_b + var_c\nvar_e = 44\nvar_f = var_d - var_e\nvar_g = var_a - var_f\nvar_h = 17\nvar_i = var_g + var_h\nvar_j = 2\nvar_k = var_i / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 502\nvar_b = 18\nvar_c = 57\nvar_d = var_b + var_c\nvar_e = 44\nvar_f = var_d - var_e\nvar_g = var_a - var_f\nvar_h = 17\nvar_i = var_g + var_h\nvar_j = 2\nvar_k = var_i / var_j\nprint(int(var_k))"
    },
    "297": {
        "category": "Arithmetic calculation",
        "question_ko": "태홍이는 지원이보다 학교에서 집까지의 거리가 460미터(m) 멉니다. 태홍이네 집에서 학교까지의 거리가 1.05킬로미터(㎞)일 때, 지원이네 집에서 학교까지는 몇 킬로미터(㎞)입니까?",
        "question_en": "Taehong's distance from school to home is 460 meters (m) farther than Jiwon's. If the distance from Taehong's house to the school is 1.05 kilometers (km), how many kilometers (km) is it from Jiwon's house to the school?",
        "answer_ko": "0.59",
        "answer_en": "0.59",
        "solution_abst_ko": "1.05 460 1000 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "1.05 460 1000 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 1.05\nvar_b = 460\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 1.05\nvar_b = 460\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "298": {
        "category": "Arithmetic calculation",
        "question_ko": "무거운 상자의 무게가 14/15킬로그램(㎏)이고, 가벼운 상자의 무게는 무거운 상자의 무게보다 1/10킬로그램(㎏) 더 가볍다면 이때 두 상자의 무게의 합은 몇 킬로그램(㎏)인지 구하시오.",
        "question_en": "If the weight of the heavy box is 14/15 kg (kg), and the light box is 1/10 kg (kg) lighter than the heavy box, find the sum of the weights of the two boxes in kg (kg).",
        "answer_ko": "1.77",
        "answer_en": "1.77",
        "solution_abst_ko": "14/15 2 [OP_MUL] 1/10 [OP_SUB]",
        "solution_abst_en": "14/15 2 [OP_MUL] 1/10 [OP_SUB]",
        "solution_code_ko": "var_a = 0.9333333333333333\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 0.1\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.9333333333333333\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 0.1\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "299": {
        "category": "Possibility",
        "question_ko": "모든 자리 수의 합이 25인 세 자리 수는 모두 몇 개입니까?",
        "question_en": "How many three-digit numbers are there where the sum of all the digits is 25?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "100 1000 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] 25 [OP_LIST_MORE_EQUAL] 25 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "100 1000 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] 25 [OP_LIST_MORE_EQUAL] 25 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 100\nvar_b = 1000\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nlist_b=[]\nfor i in list_a:\n    var_f = 0\n    i = int(i)\n    while i//10 > 0:\n        var_f = var_f + i%10\n        i = i//10\n    var_f = var_f + i%10\n    list_b.append(var_f)\nvar_g = 25\nlist_c = []\nfor i in list_b:\n    if i >= var_g:\n        list_c.append(i)\nvar_h = 25\nlist_d = []\nfor i in list_c:\n    if i <= var_h:\n        list_d.append(i)\nvar_i = len(list_d)\nprint(int(var_i))",
        "solution_code_en": "var_a = 100\nvar_b = 1000\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nlist_b=[]\nfor i in list_a:\n    var_f = 0\n    i = int(i)\n    while i//10 > 0:\n        var_f = var_f + i%10\n        i = i//10\n    var_f = var_f + i%10\n    list_b.append(var_f)\nvar_g = 25\nlist_c = []\nfor i in list_b:\n    if i >= var_g:\n        list_c.append(i)\nvar_h = 25\nlist_d = []\nfor i in list_c:\n    if i <= var_h:\n        list_d.append(i)\nvar_i = len(list_d)\nprint(int(var_i))"
    },
    "300": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 가장 큰 수를 2번째로 작은 수로 나눈 몫은 얼마입니까?",
        "question_en": "There are five numbers 10, 11, 12, 13, and 14. What is the quotient when you divide the largest number by the second smallest number?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_FDIV]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_FDIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g // var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g // var_i\nprint(int(var_j))"
    },
    "301": {
        "category": "Comparison",
        "question_ko": "총 4개의 숫자 0.8, 1/2, 0.5, 1/3이 있습니다. 이 중 0.1보다 큰 수 중 가장 작은 수를 구하면 무엇인가요?",
        "question_en": "There are a total of 4 numbers: 0.8, 1/2, 0.5, and 1/3. What is the smallest of these numbers greater than 0.1?",
        "answer_ko": "0.33",
        "answer_en": "0.33",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.5 1/3 [OP_LIST_EOL] 0.1 [OP_LIST_MORE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.5 1/3 [OP_LIST_EOL] 0.1 [OP_LIST_MORE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.5\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.1\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.5\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.1\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "302": {
        "category": "Comparison",
        "question_ko": "소라는 4와 6을 모았습니다. 희수는 7과 5를 모았고, 지연이는 3과 8을 모았습니다. 모은 수의 합이 가장 큰 사람은 누구입니까?",
        "question_en": "Sora collected 4 and 6. Heesu collected 7 and 5, and Jiyeon collected 3 and 8. Who has the greatest sum of numbers?",
        "answer_ko": "희수",
        "answer_en": "Heesu",
        "solution_abst_ko": "[OP_LIST_SOL] 소라 희수 지연 [OP_LIST_EOL] [OP_LIST_SOL] 4 6 [OP_ADD] 7 5 [OP_ADD] 3 8 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Sora Heesu Jiyeon [OP_LIST_EOL] [OP_LIST_SOL] 4 6 [OP_ADD] 7 5 [OP_ADD] 3 8 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '소라'\nvar_b = '희수'\nvar_c = '지연'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 6\nvar_f = var_d + var_e\nvar_g = 7\nvar_h = 5\nvar_i = var_g + var_h\nvar_j = 3\nvar_k = 8\nvar_l = var_j + var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'Sora'\nvar_b = 'Heesu'\nvar_c = 'Jiyeon'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 6\nvar_f = var_d + var_e\nvar_g = 7\nvar_h = 5\nvar_i = var_g + var_h\nvar_j = 3\nvar_k = 8\nvar_l = var_j + var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "303": {
        "category": "Possibility",
        "question_ko": "서로 다른 숫자 2개를 1, 2, 4, 6 중에서 뽑아 두 자리 수를 만들려고 합니다. 그 중 가장 큰 수를 구하시오.",
        "question_en": "You want to create a two-digit number by drawing two different numbers from 1, 2, 4, and 6. Find the largest number among them.",
        "answer_ko": "64",
        "answer_en": "64",
        "solution_abst_ko": "[OP_LIST_SOL] 1 2 4 6 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1 2 4 6 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1\nvar_b = 2\nvar_c = 4\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 2\nvar_c = 4\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint(int(var_g))"
    },
    "304": {
        "category": "Geometry",
        "question_ko": "가로가 6센티미터(㎝), 둘레가 28 센티미터(㎝)인 직사각형이 있습니다. 이 직사각형의 넓이는?",
        "question_en": "You have a rectangle with a width of 6 centimeters (cm) and a perimeter of 28 centimeters (cm). What is the area of this rectangle?",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "28 2 [OP_DIV] 6 [OP_SUB] 6 [OP_MUL]",
        "solution_abst_en": "28 2 [OP_DIV] 6 [OP_SUB] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 28\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c - var_d\nvar_f = 6\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 28\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c - var_d\nvar_f = 6\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "305": {
        "category": "Geometry",
        "question_ko": "이등변삼각형의 양변의 길이가 12 센티미터(㎝)이며, 나머지 변의 길이가 17 센티미터(㎝)입니다. 이 이등변삼각형의 둘레의 길이는 몇 센티미터(㎝)일까요?",
        "question_en": "Both sides of an isosceles triangle are 12 centimeters (cm) long, and the other side is 17 centimeters (cm) long. What is the perimeter of this isosceles triangle in centimeters (cm)?",
        "answer_ko": "41",
        "answer_en": "41",
        "solution_abst_ko": "12 2 [OP_MUL] 17 [OP_ADD]",
        "solution_abst_en": "12 2 [OP_MUL] 17 [OP_ADD]",
        "solution_code_ko": "var_a = 12\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 17\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 17\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "306": {
        "category": "Comparison",
        "question_ko": "(가), (나), (다), (라) 중 가장 작은 동물을 찾으려 한다. (라)는 (가)보다 작고 (나)는 (다)보다 크며 (라)보다 작다. 답은 무엇인가?",
        "question_en": "Try to find the smallest animal among (a), (b), (c), and (d). (d) is smaller than (a), (b) is larger than (c) and is smaller than (d). What is the answer?",
        "answer_ko": "(다)",
        "answer_en": "(c)",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) (다) (라) [OP_LIST_EOL] [OP_LIST_SOL] (라) (가) < (나) (다) > (나) (라) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (a) (b) (c) (d) [OP_LIST_EOL] [OP_LIST_SOL] (d) (a) < (b) (c) > (b) (d) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nvar_c = '(다)'\nvar_d = '(라)'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '(라)'\nvar_f = '(가)'\nvar_g = '<'\nvar_h = '(나)'\nvar_i = '(다)'\nvar_j = '>'\nvar_k = '(나)'\nvar_l = '(라)'\nvar_m = '<'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)",
        "solution_code_en": "var_a = '(a)'\nvar_b = '(b)'\nvar_c = '(c)'\nvar_d = '(d)'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '(d)'\nvar_f = '(a)'\nvar_g = '<'\nvar_h = '(b)'\nvar_i = '(c)'\nvar_j = '>'\nvar_k = '(b)'\nvar_l = '(d)'\nvar_m = '<'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)"
    },
    "307": {
        "category": "Geometry",
        "question_ko": "직각삼각형의 빗변이 아닌 한 변의 길이가 6, 나머지 빗변이 아닌 한 변의 길이가 8일 때 빗변의 길이는 얼마입니까?",
        "question_en": "What is the length of the hypotenuse of a right triangle if the length of one non-hypotenuse is 6 and the other non-hypotenuse is 8?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "6 2 [OP_POW] 8 2 [OP_POW] [OP_ADD] 1/2 [OP_POW]",
        "solution_abst_en": "6 2 [OP_POW] 8 2 [OP_POW] [OP_ADD] 1/2 [OP_POW]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 8\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c + var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 8\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c + var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))"
    },
    "308": {
        "category": "Possibility",
        "question_ko": "0, 1, 2, 3, 4의 수가 각각 적힌 5장의 카드에서 2장을 뽑아 두 자리 정수를 만들 때 짝수는 모두 몇 개인지 구하시오",
        "question_en": "When two out of five cards with the numbers 0, 1, 2, 3, and 4 written on them are drawn to form two-digit integers, find how many even numbers there are.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 4 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 2 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 4 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 2 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 2\nlist_c = []\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if i % var_g == 0:\n        list_c.append(i)\nvar_h = len(list_c)\nprint(int(var_h))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 2\nlist_c = []\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if i % var_g == 0:\n        list_c.append(i)\nvar_h = len(list_c)\nprint(int(var_h))"
    },
    "309": {
        "category": "Comparison",
        "question_ko": "윤기는 4개, 정국이는 6 나누기 3만큼 사과를 가졌습니다. 사과의 개수가 더 큰 사람은 누구입니까?",
        "question_en": "Yoongi has 4 apples and Jungkook has 6 divided by 3 apples. Who has the greater number of apples?",
        "answer_ko": "윤기",
        "answer_en": "Yoongi",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_FDIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_FDIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 6\nvar_e = 3\nvar_f = var_d // var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 6\nvar_e = 3\nvar_f = var_d // var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "310": {
        "category": "Correspondence",
        "question_ko": "호석이는 어떤 수에 11을 곱해 99를 얻었습니다. 어떤 수는 얼마일까요?",
        "question_en": "Hoseok multiplied a certain number by 11 and the result was 99. What is the certain number?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "99 11 [OP_DIV]",
        "solution_abst_en": "99 11 [OP_DIV]",
        "solution_code_ko": "var_a = 99\nvar_b = 11\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 99\nvar_b = 11\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "311": {
        "category": "Correspondence",
        "question_ko": "10+A=15일 때, A에 들어가야 하는 숫자를 구하시오",
        "question_en": "When 10+A=15, find the correct number for A.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "10+A=15 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "10+A=15 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '10+A=15'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '10+A=15'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "312": {
        "category": "Correspondence",
        "question_ko": "AB+13=64일 때, A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "When AB+13=64, what number should go in A?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "AB+13=64 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "AB+13=64 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'AB+13=64'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'AB+13=64'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "313": {
        "category": "Geometry",
        "question_ko": "혜원이는 미술 시간에 찰흙을 가지고 오각기둥을 만든 후 각각의 면에 서로 다른 색을 칠하였습니다. 혜원이가 오각 기둥에 칠한 색은 모두 몇 가지 입니까?",
        "question_en": "Hyewon made pentagonal pillars with clay during art class and painted each side with a different color. How many colors did Hyewon paint on the pentagonal pillar?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "2 5 [OP_ADD]",
        "solution_abst_en": "2 5 [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "314": {
        "category": "Correspondence",
        "question_ko": "올해 서울에서 경기도로 전학 간 학생이 그 반대의 경우보다 273명 많았다. 올해 경기도에서 학교를 다니는 학생이 서울에서 학교를 다니는 학생보다 477명 많았다. 작년에는 차이가 몇 명이었는지 구하시오.",
        "question_en": "This year, 273 more students transferred from Seoul to Gyeonggi-do than vice versa. This year, there were 477 more students attending schools in Gyeonggi-do than students attending schools in Seoul. Find how many people were different last year.",
        "answer_ko": "1023",
        "answer_en": "1023",
        "solution_abst_ko": "477 273 [OP_ADD] 273 [OP_ADD]",
        "solution_abst_en": "477 273 [OP_ADD] 273 [OP_ADD]",
        "solution_code_ko": "var_a = 477\nvar_b = 273\nvar_c = var_a + var_b\nvar_d = 273\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 477\nvar_b = 273\nvar_c = var_a + var_b\nvar_d = 273\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "315": {
        "category": "Arithmetic calculation",
        "question_ko": "일정한 빠르기로 3분 동안 15리터(L)의 물이 나오는 수도로 들이가 140리터(L)인 욕조에 물을 가득 채우려고 합니다. 몇 분 동안 물을 받아야 합니까?",
        "question_en": "We are trying to fill a bathtub with a capacity of 140 liters (l) with a tap that produces 15 liters (l) of water in 3 minutes at a constant speed. How many minutes should I get water to fill this bathtub?",
        "answer_ko": "28",
        "answer_en": "28",
        "solution_abst_ko": "140 15 3 [OP_DIV] [OP_DIV]",
        "solution_abst_en": "140 15 3 [OP_DIV] [OP_DIV]",
        "solution_code_ko": "var_a = 140\nvar_b = 15\nvar_c = 3\nvar_d = var_b / var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 140\nvar_b = 15\nvar_c = 3\nvar_d = var_b / var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "316": {
        "category": "Correspondence",
        "question_ko": "민영이가 107.8 을 어떤 수로 나누었더니 9.8 이 되었습니다. 어떤 수는 얼마인지 구하시오.",
        "question_en": "When Minyoung divided 107.8 by a certain number, it became 9.8. Find out what the number is.",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "107.8 9.8 [OP_DIV]",
        "solution_abst_en": "107.8 9.8 [OP_DIV]",
        "solution_code_ko": "var_a = 107.8\nvar_b = 9.8\nvar_c = var_a / var_b\nprint(int(eval('{:.2f}'.format(round(var_c+1e-10,2)))))",
        "solution_code_en": "var_a = 107.8\nvar_b = 9.8\nvar_c = var_a / var_b\nprint(int(eval('{:.2f}'.format(round(var_c+1e-10,2)))))"
    },
    "317": {
        "category": "Comparison",
        "question_ko": "삼각형은 밑변이 10센티미터(cm)이고 높이가 11센티미터(cm)입니다. 정사각형은 가로가 8센티미터(cm) 세로가 8센티미터(cm)이고, 원의 지름은 8센티미터(cm)입니다. 가장 넓이가 넓은 도형은 무엇입니까? 원주율은 3.1로 계산하세요.",
        "question_en": "A triangle has a base of 10 centimeters (cm) and a height of 11 centimeters (cm). There is a square with a width of 8 centimeters (cm) and a length of 8 centimeters (cm), and the diameter of a circle is 8 centimeters (cm). Which shape has the widest area? Calculate the circumference ratio as 3.1.",
        "answer_ko": "정사각형",
        "answer_en": "square",
        "solution_abst_ko": "[OP_LIST_SOL] 삼각형 정사각형 원 [OP_LIST_EOL] [OP_LIST_SOL] 10 11 [OP_MUL] 2 [OP_DIV] 8 2 [OP_POW] 8 2 [OP_DIV] 2 [OP_POW] 3.1 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] triangle square circle [OP_LIST_EOL] [OP_LIST_SOL] 10 11 [OP_MUL] 2 [OP_DIV] 8 2 [OP_POW] 8 2 [OP_DIV] 2 [OP_POW] 3.1 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '삼각형'\nvar_b = '정사각형'\nvar_c = '원'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 10\nvar_e = 11\nvar_f = var_d * var_e\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = 8\nvar_j = 2\nvar_k = var_i ** var_j\nvar_l = 8\nvar_m = 2\nvar_n = var_l / var_m\nvar_o = 2\nvar_p = var_n ** var_o\nvar_q = 3.1\nvar_r = var_p * var_q\nlist_b= []\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nlist_b.reverse()\nvar_s = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_t = list_c[-var_s]\nvar_u = list_b.index(var_t)+1\nvar_v = list_a[var_u-1]\nprint(var_v)",
        "solution_code_en": "var_a = 'triangle'\nvar_b = 'square'\nvar_c = 'circle'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 10\nvar_e = 11\nvar_f = var_d * var_e\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = 8\nvar_j = 2\nvar_k = var_i ** var_j\nvar_l = 8\nvar_m = 2\nvar_n = var_l / var_m\nvar_o = 2\nvar_p = var_n ** var_o\nvar_q = 3.1\nvar_r = var_p * var_q\nlist_b= []\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nlist_b.reverse()\nvar_s = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_t = list_c[-var_s]\nvar_u = list_b.index(var_t)+1\nvar_v = list_a[var_u-1]\nprint(var_v)"
    },
    "318": {
        "category": "Comparison",
        "question_ko": "달리기 시합에서 태형이는 정국이보다 잘했고 민영이보다는 못했습니다. 민영이가 5등이고 정국이가 7등을 했을때 태형이는 몇 등입니까?",
        "question_en": "In the running match, Taehyung did better than Jungkook and worse than Minyeong. If Minyoung is 5th and Jungkook is 7th, what rank is Taehyung?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "7 5 [OP_ADD] 2 [OP_DIV]",
        "solution_abst_en": "7 5 [OP_ADD] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 7\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 7\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "319": {
        "category": "Possibility",
        "question_ko": "5, 1, 7, 6과 소수점을 한 번씩만 사용하여 7보다 큰 소수 세 자리 수를 모두 몇 개 만들 수 있습니까?",
        "question_en": "By using 5, 1, 7, 6, and a decimal point only once each, how many decimal numbers greater than 7 with three decimal places can you make?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 5 1 7 6 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 7 10 4 1 [OP_SUB] [OP_POW] [OP_MUL] [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 5 1 7 6 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 7 10 4 1 [OP_SUB] [OP_POW] [OP_MUL] [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 5\nvar_b = 1\nvar_c = 7\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 7\nvar_g = 10\nvar_h = 4\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_g ** var_j\nvar_l = var_f * var_k\nlist_c = []\nfor i in list_b:\n    if i > var_l:\n        list_c.append(i)\nvar_m = len(list_c)\nprint(int(var_m))",
        "solution_code_en": "var_a = 5\nvar_b = 1\nvar_c = 7\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 7\nvar_g = 10\nvar_h = 4\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_g ** var_j\nvar_l = var_f * var_k\nlist_c = []\nfor i in list_b:\n    if i > var_l:\n        list_c.append(i)\nvar_m = len(list_c)\nprint(int(var_m))"
    },
    "320": {
        "category": "Comparison",
        "question_ko": "서로 다른 자동차 20대가 한 줄로 주차되어 있다. 검은색 자동차는 오른쪽에서 16번째에, 흰색 자동차는 왼쪽에서 11번째에 있을 때, 두 자동차 사이에 주차되어 있는 자동차는 총 몇대인가?",
        "question_en": "20 different cars are parked in a row. If the black car is 16th from the right and the white car is 11th from the left, how many total cars are parked between the two cars?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "16 11 [OP_ADD] 20 [OP_SUB] 2 [OP_SUB]",
        "solution_abst_en": "16 11 [OP_ADD] 20 [OP_SUB] 2 [OP_SUB]",
        "solution_code_ko": "var_a = 16\nvar_b = 11\nvar_c = var_a + var_b\nvar_d = 20\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 16\nvar_b = 11\nvar_c = var_a + var_b\nvar_d = 20\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "321": {
        "category": "Arithmetic calculation",
        "question_ko": "민정이와 수혁이의 저금통에는 현재 각각 8000원, 5000원이 들어 있다. 내일부터 매일 민정이는 300원씩, 수혁이는 500원씩 저금통에 넣는다면, 민정이와 수혁이의 저금통에 들어 있는 금액이 같아지는 것은 며칠 후인가?",
        "question_en": "Minjeong and Soohyeok's piggy banks currently contain 8,000 won and 5,000 won, respectively. If Minjeong puts 300 won and Soohyeok puts 500 won into their piggy bank every day, starting tomorrow, how many days later will the money in Minjeong's and Soohyeok's piggy banks become the same?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "8000 5000 [OP_SUB] 500 300 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "8000 5000 [OP_SUB] 500 300 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 8000\nvar_b = 5000\nvar_c = var_a - var_b\nvar_d = 500\nvar_e = 300\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 8000\nvar_b = 5000\nvar_c = var_a - var_b\nvar_d = 500\nvar_e = 300\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))"
    },
    "322": {
        "category": "Geometry",
        "question_ko": "직각삼각형의 빗변의 길이가 13, 빗변이 아닌 한 변의 길이가 12이면 나머지 한 변의 길이는 얼마입니까?",
        "question_en": "If the length of the hypotenuse of a right triangle is 13 and the length of a non-hypotenuse is 12, what is the length of the other side?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "13 2 [OP_POW] 12 2 [OP_POW] [OP_SUB] 1/2 [OP_POW]",
        "solution_abst_en": "13 2 [OP_POW] 12 2 [OP_POW] [OP_SUB] 1/2 [OP_POW]",
        "solution_code_ko": "var_a = 13\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 12\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c - var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 13\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 12\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c - var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))"
    },
    "323": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 23으로 나누면 몫은 17이고 나머지가 19입니다. 이 어떤 수를 10배 한 수를 23으로 나누었을 때의 몫과 나머지의 합을 구하시오.",
        "question_en": "When a number is divided by 23, the quotient is 17 and the remainder is 19. When this number is multiplied by 10 and then divided by 23, find the sum of its quotient and remainder.",
        "answer_ko": "184",
        "answer_en": "184",
        "solution_abst_ko": "23 17 [OP_MUL] 19 [OP_ADD] 10 [OP_MUL] 23 [OP_FDIV] 23 17 [OP_MUL] 19 [OP_ADD] 10 [OP_MUL] 23 [OP_MOD] [OP_ADD]",
        "solution_abst_en": "23 17 [OP_MUL] 19 [OP_ADD] 10 [OP_MUL] 23 [OP_FDIV] 23 17 [OP_MUL] 19 [OP_ADD] 10 [OP_MUL] 23 [OP_MOD] [OP_ADD]",
        "solution_code_ko": "var_a = 23\nvar_b = 17\nvar_c = var_a * var_b\nvar_d = 19\nvar_e = var_c + var_d\nvar_f = 10\nvar_g = var_e * var_f\nvar_h = 23\nvar_i = var_g // var_h\nvar_j = 23\nvar_k = 17\nvar_l = var_j * var_k\nvar_m = 19\nvar_n = var_l + var_m\nvar_o = 10\nvar_p = var_n * var_o\nvar_q = 23\nvar_r = var_p % var_q\nvar_s = var_i + var_r\nprint(int(var_s))",
        "solution_code_en": "var_a = 23\nvar_b = 17\nvar_c = var_a * var_b\nvar_d = 19\nvar_e = var_c + var_d\nvar_f = 10\nvar_g = var_e * var_f\nvar_h = 23\nvar_i = var_g // var_h\nvar_j = 23\nvar_k = 17\nvar_l = var_j * var_k\nvar_m = 19\nvar_n = var_l + var_m\nvar_o = 10\nvar_p = var_n * var_o\nvar_q = 23\nvar_r = var_p % var_q\nvar_s = var_i + var_r\nprint(int(var_s))"
    },
    "324": {
        "category": "Arithmetic calculation",
        "question_ko": "과일 가게에 사과가 1238개, 배는 사과보다 374개 더 많이 있었습니다. 이 중에서 사과 몇 개가 팔리고, 배 276개를 사들였더니 사과와 배를 합하여 2527개가 되었습니다. 팔린 사과는 몇 개입니까?",
        "question_en": "There were 1238 apples and 374 more pears than apples in the fruit shop. Of these, a few apples were sold, and 276 pears were bought, so the total of apples and pears was 2527. How many apples have been sold?",
        "answer_ko": "599",
        "answer_en": "599",
        "solution_abst_ko": "1238 2527 1238 374 [OP_ADD] 276 [OP_ADD] [OP_SUB] [OP_SUB]",
        "solution_abst_en": "1238 2527 1238 374 [OP_ADD] 276 [OP_ADD] [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 1238\nvar_b = 2527\nvar_c = 1238\nvar_d = 374\nvar_e = var_c + var_d\nvar_f = 276\nvar_g = var_e + var_f\nvar_h = var_b - var_g\nvar_i = var_a - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1238\nvar_b = 2527\nvar_c = 1238\nvar_d = 374\nvar_e = var_c + var_d\nvar_f = 276\nvar_g = var_e + var_f\nvar_h = var_b - var_g\nvar_i = var_a - var_h\nprint(int(var_i))"
    },
    "325": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중에서 2번째로 큰 수와 가장 작은 수의 곱은 얼마입니까?",
        "question_en": "There are three numbers: 10, 11 and 12. What is the product of the second largest number and the smallest number?",
        "answer_ko": "110",
        "answer_en": "110",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 2 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 2 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e * var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e * var_g\nprint(int(var_h))"
    },
    "326": {
        "category": "Geometry",
        "question_ko": "세희는 한 모서리의 길이가 1미터(m)인 정육면체 모양의 상자를 가지고 있고, 세린이는 가로 50센티미터(㎝), 세로 50센티미터(㎝), 높이 20센티미터(㎝)인 직육면체 모양의 상자를 가지고 있습니다. 세희가 가진 상자의 부피는 세린이가 가진 상자의 부피의 몇 배입니까?",
        "question_en": "Se-hee has a box in the shape of a cube with 1 meter (m) long, and Se-rin has a cuboid-shaped box with a width of 50 centimeters (cm), a depth of 50 centimeters (cm) and a height of 20 centimeters (cm). How many times larger is the volume of Se-hee's box than the volume of Serin's box?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "1 100 [OP_MUL] 3 [OP_POW] 50 50 [OP_MUL] 20 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "1 100 [OP_MUL] 3 [OP_POW] 50 50 [OP_MUL] 20 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c ** var_d\nvar_f = 50\nvar_g = 50\nvar_h = var_f * var_g\nvar_i = 20\nvar_j = var_h * var_i\nvar_k = var_e / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 1\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c ** var_d\nvar_f = 50\nvar_g = 50\nvar_h = var_f * var_g\nvar_i = 20\nvar_j = var_h * var_i\nvar_k = var_e / var_j\nprint(int(var_k))"
    },
    "327": {
        "category": "Comparison",
        "question_ko": "4마리의 고래가 헤엄치고 있습니다. (가) 고래는 (나) 고래보다 빠르고 (나) 고래와 (라) 고래는 모두 (다) 고래보다 빠릅니다. (라) 고래는 (가) 고래보다 빠릅니다. 이 중 가장 느린 고래는 어느 고래입니까?",
        "question_en": "Four whales are swimming. (a) Whales are faster than (b) whales, and both (b) whales and (d) whales are faster than (c) whales. (d) Whales are faster than (a) whales. Which of these whales is the slowest?",
        "answer_ko": "(다)",
        "answer_en": "(c)",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) (다) (라) [OP_LIST_EOL] [OP_LIST_SOL] (가) (나) > (나) (다) > (다) (라) < (라) (가) > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (a) (b) (c) (d) [OP_LIST_EOL] [OP_LIST_SOL] (a) (b) > (b) (c) > (c) (d) < (d) (a) > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nvar_c = '(다)'\nvar_d = '(라)'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '(가)'\nvar_f = '(나)'\nvar_g = '>'\nvar_h = '(나)'\nvar_i = '(다)'\nvar_j = '>'\nvar_k = '(다)'\nvar_l = '(라)'\nvar_m = '<'\nvar_n = '(라)'\nvar_o = '(가)'\nvar_p = '>'\nlist_b= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_q = len(list_c)\nvar_r = list_c[var_q-1]\nprint(var_r)",
        "solution_code_en": "var_a = '(a)'\nvar_b = '(b)'\nvar_c = '(c)'\nvar_d = '(d)'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '(a)'\nvar_f = '(b)'\nvar_g = '>'\nvar_h = '(b)'\nvar_i = '(c)'\nvar_j = '>'\nvar_k = '(c)'\nvar_l = '(d)'\nvar_m = '<'\nvar_n = '(d)'\nvar_o = '(a)'\nvar_p = '>'\nlist_b= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_q = len(list_c)\nvar_r = list_c[var_q-1]\nprint(var_r)"
    },
    "328": {
        "category": "Correspondence",
        "question_ko": "두 자리 수 6A+B2=77입니다. B는 얼마입니까?",
        "question_en": "The two-digit number 6A+B2=77. How much is B?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "6A+B2=77 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "6A+B2=77 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '6A+B2=77'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '6A+B2=77'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "329": {
        "category": "Geometry",
        "question_ko": "마름모 모양의 운동장이 있습니다. 운동장의 한 대각선은 14미터(m), 다른 대각선은 24미터(m)일 때 운동장의 넓이를 구하시오.",
        "question_en": "There is a rhombic playground. Find the area of the playground if one diagonal of the playground is 14 meters (m) and the other diagonal is 24 meters (m).",
        "answer_ko": "168",
        "answer_en": "168",
        "solution_abst_ko": "14 24 [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "14 24 [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 14\nvar_b = 24\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 14\nvar_b = 24\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "330": {
        "category": "Correspondence",
        "question_ko": "A, B는 한 자리 수입니다. A15B94가 99의 배수라고 할 때 A+B를 구하시오.",
        "question_en": "A and B are single-digit numbers. If A15B94 is a multiple of 99, find A+B.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "A15B94 [OP_GEN_POSSIBLE_LIST] 99 [OP_LIST_DIVISIBLE] A15B94 A [OP_LIST_FIND_UNK] A15B94 B [OP_LIST_FIND_UNK] [OP_ADD]",
        "solution_abst_en": "A15B94 [OP_GEN_POSSIBLE_LIST] 99 [OP_LIST_DIVISIBLE] A15B94 A [OP_LIST_FIND_UNK] A15B94 B [OP_LIST_FIND_UNK] [OP_ADD]",
        "solution_code_ko": "var_a = 'A15B94'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 99\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 'A15B94'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nvar_e = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_e = int(elem[unk_idx])\nvar_f = 'A15B94'\nvar_g = 'B'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nvar_i = var_e + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 'A15B94'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 99\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 'A15B94'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nvar_e = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_e = int(elem[unk_idx])\nvar_f = 'A15B94'\nvar_g = 'B'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nvar_i = var_e + var_h\nprint(int(var_i))"
    },
    "331": {
        "category": "Arithmetic calculation",
        "question_ko": "은지는 35개의 사탕을 가지고 있습니다. 지민이는 은지보다 사탕을 6개 더 가지고 있고 지현이는 은지보다 사탕을 3개 덜 가지고 있을 때 세 명이 가진 평균 사탕의 개수는 몇 개입니까?",
        "question_en": "Eunji has 35 candies. If Jimin has 6 more candies than Eunji and Jihyun has 3 fewer candies than Eunji, what is the average number of candies the three of them have?",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "35 35 6 [OP_ADD] [OP_ADD] 35 3 [OP_SUB] [OP_ADD] 3 [OP_DIV]",
        "solution_abst_en": "35 35 6 [OP_ADD] [OP_ADD] 35 3 [OP_SUB] [OP_ADD] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 35\nvar_b = 35\nvar_c = 6\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nvar_f = 35\nvar_g = 3\nvar_h = var_f - var_g\nvar_i = var_e + var_h\nvar_j = 3\nvar_k = var_i / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 35\nvar_b = 35\nvar_c = 6\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nvar_f = 35\nvar_g = 3\nvar_h = var_f - var_g\nvar_i = var_e + var_h\nvar_j = 3\nvar_k = var_i / var_j\nprint(int(var_k))"
    },
    "332": {
        "category": "Possibility",
        "question_ko": "범진이가 수학책 2권, 영어책 2권을 책꽂이에 꽂으려고 할 때, 수학책끼리 나란히 꽂는 경우의 수는?",
        "question_en": "When Beomjin tries to put 2 Math books and 2 English books on the bookshelf, how many times can he put the math books side by side?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "[OP_LIST_SOL] 수학책 영어책 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_MUL] 1 [OP_SUB] [OP_LIST_LEN] 2 [OP_MUL] 1 [OP_SUB] [OP_PERM] 2 [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] Math English [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_MUL] 1 [OP_SUB] [OP_LIST_LEN] 2 [OP_MUL] 1 [OP_SUB] [OP_PERM] 2 [OP_MUL]",
        "solution_code_ko": "var_a = '수학책'\nvar_b = '영어책'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = len(list_a)\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = len(list_a)\nvar_i = 2\nvar_j = var_h * var_i\nvar_k = 1\nvar_l = var_j - var_k\nvar_m = 1\nvar_g = int(var_g)\nvar_l = int(var_l)\nfor i, elem in enumerate(range(var_l)):\n    var_m = var_m * (var_g-i)\nvar_n = 2\nvar_o = var_m * var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 'Math'\nvar_b = 'English'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = len(list_a)\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = len(list_a)\nvar_i = 2\nvar_j = var_h * var_i\nvar_k = 1\nvar_l = var_j - var_k\nvar_m = 1\nvar_g = int(var_g)\nvar_l = int(var_l)\nfor i, elem in enumerate(range(var_l)):\n    var_m = var_m * (var_g-i)\nvar_n = 2\nvar_o = var_m * var_n\nprint(int(var_o))"
    },
    "333": {
        "category": "Geometry",
        "question_ko": "어떤 육각기둥의 모든 모서리의 길이의 합은 81센티미터(㎝)이고, 모든 모서리의 길이가 같습니다. 어떤 사각뿔은 모든 모서리의 길이가 같고, 한 모서리의 길이가 육각기둥의 모서리의 길이와 같습니다. 사각뿔의 모든 모서리의 길이의 합을 구하시오.",
        "question_en": "The sum of the lengths of all the edges of a hexagonal prism is 81 centimeters (cm), and all edges are the same length. In a quadrangular pyramid, all edges are the same length, and one edge is equal to the length of the edges of a hexagonal prism. Find the sum of the lengths of all the edges of the quadrangular pyramid.",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "81 6 3 [OP_MUL] [OP_DIV] 4 2 [OP_MUL] [OP_MUL]",
        "solution_abst_en": "81 6 3 [OP_MUL] [OP_DIV] 4 2 [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 81\nvar_b = 6\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nvar_f = 4\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_e * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 81\nvar_b = 6\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nvar_f = 4\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_e * var_h\nprint(int(var_i))"
    },
    "334": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이는 색종이를 10장씩 3묶음과 낱개 8장 가지고 있습니다. 정국이가 가지고 있는 색종이는 모두 몇 장입니까?",
        "question_en": "Jungkook has 3 bundles of 10 pieces of colored paper each and 8 individual pieces. How many pieces of colored paper does Jungkook have?",
        "answer_ko": "38",
        "answer_en": "38",
        "solution_abst_ko": "10 3 [OP_MUL] 8 [OP_ADD]",
        "solution_abst_en": "10 3 [OP_MUL] 8 [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "335": {
        "category": "Arithmetic calculation",
        "question_ko": "6/5과 1/10이 있습니다. 이들의 합은 얼마인가요?",
        "question_en": "There are 6/5 and 1/10. What is their sum?",
        "answer_ko": "1.30",
        "answer_en": "1.3",
        "solution_abst_ko": "6/5 1/10 [OP_ADD]",
        "solution_abst_en": "6/5 1/10 [OP_ADD]",
        "solution_code_ko": "var_a = 1.2\nvar_b = 0.1\nvar_c = var_a + var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 1.2\nvar_b = 0.1\nvar_c = var_a + var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "336": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 2.5로 나누고 3.1로 나눈 후 3.1을 더했더니 8.9가 되었습니다. 어떤 수는 얼마인지 구하시오.",
        "question_en": "Divide a number by 2.5, divide by 3.1, add 3.1, and you get 8.9. Find out what the number is.",
        "answer_ko": "44.95",
        "answer_en": "44.95",
        "solution_abst_ko": "8.9 3.1 [OP_SUB] 3.1 [OP_MUL] 2.5 [OP_MUL]",
        "solution_abst_en": "8.9 3.1 [OP_SUB] 3.1 [OP_MUL] 2.5 [OP_MUL]",
        "solution_code_ko": "var_a = 8.9\nvar_b = 3.1\nvar_c = var_a - var_b\nvar_d = 3.1\nvar_e = var_c * var_d\nvar_f = 2.5\nvar_g = var_e * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 8.9\nvar_b = 3.1\nvar_c = var_a - var_b\nvar_d = 3.1\nvar_e = var_c * var_d\nvar_f = 2.5\nvar_g = var_e * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "337": {
        "category": "Comparison",
        "question_ko": "윤기는 왼쪽에서 7번째 열, 오른쪽에서 13번째 열, 앞에서 8번째 줄, 뒤에서 14번째 줄에 서서 나눠주는 선물을 받으려고 합니다. 각 줄마다 서 있는 사람 수가 같고, 한 사람 당 선물을 2개씩 받는다고 할 때, 줄을 선 모든 사람이 받는 선물은 모두 몇 개입니까?",
        "question_en": "Yoongi stands in the 7th row from the left, the 13th row from the right, the 8th row from the front, and the 14th row from the back to receive the gift being handed out. If the number of people in each line is the same and each person gets 2 gifts, how many gifts will everyone in the line get?",
        "answer_ko": "798",
        "answer_en": "798",
        "solution_abst_ko": "7 13 [OP_ADD] 1 [OP_SUB] 8 14 [OP_ADD] 1 [OP_SUB] [OP_MUL] 2 [OP_MUL]",
        "solution_abst_en": "7 13 [OP_ADD] 1 [OP_SUB] 8 14 [OP_ADD] 1 [OP_SUB] [OP_MUL] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 7\nvar_b = 13\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = 14\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nvar_l = 2\nvar_m = var_k * var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 7\nvar_b = 13\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = 14\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nvar_l = 2\nvar_m = var_k * var_l\nprint(int(var_m))"
    },
    "338": {
        "category": "Comparison",
        "question_ko": "노란색 장난감의 위치는 왼쪽으로부터 10번째이고 오른쪽에서 세면 7번째입니다. 장난감이 한 줄로 놓아져 있다면 장난감의 수는 모두 몇 개입니까?",
        "question_en": "The yellow toy is 10th from the left and 7th from the right. How many toys are there if they are placed in a row?",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "10 7 [OP_ADD] 1 [OP_SUB]",
        "solution_abst_en": "10 7 [OP_ADD] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "339": {
        "category": "Possibility",
        "question_ko": "A에는 1부터 9까지의 자연수가 들어갈 수 있습니다. 57×7>65×A일 때, A에 들어갈 수 있는 수의 합은 얼마입니까?",
        "question_en": "A can be a natural number from 1 to 9. If 57×7>65×A, what is the sum of the numbers that can be A?",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "1 9 1 [OP_LIST_ARANGE] 57 7 [OP_MUL] 65 [OP_DIV] [OP_LIST_LESS] [OP_LIST_SUM]",
        "solution_abst_en": "1 9 1 [OP_LIST_ARANGE] 57 7 [OP_MUL] 65 [OP_DIV] [OP_LIST_LESS] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 57\nvar_e = 7\nvar_f = var_d * var_e\nvar_g = 65\nvar_h = var_f / var_g\nlist_b = []\nfor i in list_a:\n    if i < var_h:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_i = sum(list_b)\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 57\nvar_e = 7\nvar_f = var_d * var_e\nvar_g = 65\nvar_h = var_f / var_g\nlist_b = []\nfor i in list_a:\n    if i < var_h:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_i = sum(list_b)\nprint(int(var_i))"
    },
    "340": {
        "category": "Arithmetic calculation",
        "question_ko": "둘레의 길이가 18 킬로미터(㎞)인 공원을 소윤이와 지아가 같은 장소에서 동시에 출발하여 서로 반대 방향으로 돌아서 도중에 만났다. 소윤이는 시속 5 킬로미터(㎞)로 뛰었고 지아는 시속 4 킬로미터(㎞)로 뛰었다고 한다. 소윤이가 뛴 거리는 얼마인가?",
        "question_en": "In a park with a perimeter of 18 kilometers (km), Soyun and Jia started off at the same time from the same place, but in opposite directions, and met on the way. It is said that Soyun ran at 5 kilometers (km) per hour and Jia ran at 4 kilometers (km) per hour. How far did Soyun run?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "18 5 4 [OP_ADD] [OP_DIV] 5 [OP_MUL]",
        "solution_abst_en": "18 5 4 [OP_ADD] [OP_DIV] 5 [OP_MUL]",
        "solution_code_ko": "var_a = 18\nvar_b = 5\nvar_c = 4\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nvar_f = 5\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 18\nvar_b = 5\nvar_c = 4\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nvar_f = 5\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "341": {
        "category": "Arithmetic calculation",
        "question_ko": "1이상 9이하의 홀수 중 6미만인 수들의 총합은 얼마입니까?",
        "question_en": "What is the sum of odd numbers more than 1 and not more than 9 that are less than 6?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "1 9 [OP_LIST_ODD] 6 [OP_LIST_LESS] [OP_LIST_SUM]",
        "solution_abst_en": "1 9 [OP_LIST_ODD] 6 [OP_LIST_LESS] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 6\nlist_b = []\nfor i in list_a:\n    if i < var_c:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_d = sum(list_b)\nprint(int(var_d))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 6\nlist_b = []\nfor i in list_a:\n    if i < var_c:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_d = sum(list_b)\nprint(int(var_d))"
    },
    "342": {
        "category": "Possibility",
        "question_ko": "6, 7, 8, 9가 적혀있는 4장의 카드 중 중복을 허락하여 2가지 카드를 고르려고 합니다. 가능한 경우의 수는 모두 몇 가지 인가요?",
        "question_en": "Of the 4 cards with the numbers 6, 7, 8, and 9 written on them, we want to select two cards by allowing duplicates. How many possible cases are there?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "[OP_LIST_SOL] 6 7 8 9 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] 6 7 8 9 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB]",
        "solution_code_ko": "var_a = 6\nvar_b = 7\nvar_c = 8\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = var_e + var_f\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = 2\nvar_k = 1\nvar_i = int(var_i)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_i-i)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k / (i+1)\nprint(int(var_k))",
        "solution_code_en": "var_a = 6\nvar_b = 7\nvar_c = 8\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = var_e + var_f\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = 2\nvar_k = 1\nvar_i = int(var_i)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_i-i)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k / (i+1)\nprint(int(var_k))"
    },
    "343": {
        "category": "Arithmetic calculation",
        "question_ko": "휘발유 1.7리터(L)로 20.57킬로미터(㎞)를 갈 수 있는 자동차가 있습니다. 휘발유 1리터(L)의 값이 1600원이라면 이 자동차가 91.66킬로미터(㎞)를 가는 데 필요한 휘발유의 값은 얼마입니까?",
        "question_en": "There is a car that can travel 20.57 kilometers (km) with 1.7 liters (L) of gasoline. If the price of gasoline is 1600 won per liter (L), how much gasoline does this car need to travel 91.66 kilometers (km)?",
        "answer_ko": "12120.33",
        "answer_en": "12120.33",
        "solution_abst_ko": "1.7 20.57 [OP_DIV] 91.66 [OP_MUL] 1600 [OP_MUL]",
        "solution_abst_en": "1.7 20.57 [OP_DIV] 91.66 [OP_MUL] 1600 [OP_MUL]",
        "solution_code_ko": "var_a = 1.7\nvar_b = 20.57\nvar_c = var_a / var_b\nvar_d = 91.66\nvar_e = var_c * var_d\nvar_f = 1600\nvar_g = var_e * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 1.7\nvar_b = 20.57\nvar_c = var_a / var_b\nvar_d = 91.66\nvar_e = var_c * var_d\nvar_f = 1600\nvar_g = var_e * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "344": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 25센티미터(㎝)인 철사 15개를 이어붙여서 긴 철사를 만드려고 한다. 철사를 이어붙이는데 0.5센티미터(㎝)의 철사가 사용될 때, 이어붙힌 철사의 길이는 몇 미터(m)인지 구하시오.",
        "question_en": "You are going to make a long wire by splicing 15 pieces of wire together that are 25 centimeters (cm) long. If 0.5 centimeters (cm) of wire is overlapped to join the wires together, find how many meters (m) the length of the wire is spliced together.",
        "answer_ko": "3.68",
        "answer_en": "3.68",
        "solution_abst_ko": "25 25 0.5 [OP_SUB] 15 1 [OP_SUB] [OP_MUL] [OP_ADD] 100 [OP_DIV]",
        "solution_abst_en": "25 25 0.5 [OP_SUB] 15 1 [OP_SUB] [OP_MUL] [OP_ADD] 100 [OP_DIV]",
        "solution_code_ko": "var_a = 25\nvar_b = 25\nvar_c = 0.5\nvar_d = var_b - var_c\nvar_e = 15\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_a + var_h\nvar_j = 100\nvar_k = var_i / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 25\nvar_b = 25\nvar_c = 0.5\nvar_d = var_b - var_c\nvar_e = 15\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_a + var_h\nvar_j = 100\nvar_k = var_i / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "345": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 12로 나누어야 할 것을 잘못하여 21로 나누었더니 4로 나누어떨어졌습니다. 바르게 계산했을 때의 몫을 구하시오.",
        "question_en": "You mistakenly divided a number by 21 instead of by 12, and it was divisible by 4. Find the quotient when calculated correctly.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "4 21 [OP_MUL] 12 [OP_FDIV]",
        "solution_abst_en": "4 21 [OP_MUL] 12 [OP_FDIV]",
        "solution_code_ko": "var_a = 4\nvar_b = 21\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 4\nvar_b = 21\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "346": {
        "category": "Arithmetic calculation",
        "question_ko": "배구공이 9개 있었습니다. 그중에서 5개를 다른 학교에 빌려주었습니다. 현재 남아있는 배구공은 몇 개입니까?",
        "question_en": "There were 9 volleyballs. You lent 5 of them to other schools. How many volleyballs are currently there?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "9 5 [OP_SUB]",
        "solution_abst_en": "9 5 [OP_SUB]",
        "solution_code_ko": "var_a = 9\nvar_b = 5\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 9\nvar_b = 5\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "347": {
        "category": "Geometry",
        "question_ko": "밑면이 여섯 개의 크기가 같은 각으로 이루어진 정다각형인 각뿔의 꼭짓점은 모두 몇 개입니까?",
        "question_en": "How many vertices are there in a pyramid whose base is a regular polygon made up of six equal angles?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "6 1 [OP_ADD]",
        "solution_abst_en": "6 1 [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "348": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 239.66미터(m)인 도로의 한쪽에 같은 간격으로 24그루의 나무를 심으려고 합니다. 도로의 처음과 끝에 각각 한 그루씩 심는다면 나무 사이의 거리는 몇 미터(m)로 심어야 하는지 구하시오.",
        "question_en": "You want to plant 24 trees equally spaced on one side of a road that is 239.66 meters (m) long. If one tree is planted at the beginning and one at the end of the road, how many meters (m) should be spaced between the trees?",
        "answer_ko": "10.42",
        "answer_en": "10.42",
        "solution_abst_ko": "239.66 24 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "239.66 24 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 239.66\nvar_b = 24\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 239.66\nvar_b = 24\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "349": {
        "category": "Correspondence",
        "question_ko": "용희가 무게 1킬로그램(㎏) 750그램(g)인 가방을 들고 저울에 올라섰더니 저울의 눈금이 35킬로그램(㎏) 500그램(g)을 가리켰습니다. 용희가 27킬로그램(㎏) 200그램(g)인 동생을 업고 저울에 올라서면 저울의 눈금은 몇 킬로그램(㎏)을 나타내겠습니까?",
        "question_en": "Yonghee stood on the scale holding a bag weighing 1 kilogram (kg) and 750 grams (g), and the scale indicated 35 kilograms (kg) and 500 grams (g). How many kilograms (kg) will the scale show if Yonghee stands on the scale carrying his younger brother who weighs 27 kilograms (kg) and 200 grams (g) on his back?",
        "answer_ko": "60.95",
        "answer_en": "60.95",
        "solution_abst_ko": "35 500 1000 [OP_DIV] [OP_ADD] 1 750 1000 [OP_DIV] [OP_ADD] [OP_SUB] 27 200 1000 [OP_DIV] [OP_ADD] [OP_ADD]",
        "solution_abst_en": "35 500 1000 [OP_DIV] [OP_ADD] 1 750 1000 [OP_DIV] [OP_ADD] [OP_SUB] 27 200 1000 [OP_DIV] [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 35\nvar_b = 500\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 1\nvar_g = 750\nvar_h = 1000\nvar_i = var_g / var_h\nvar_j = var_f + var_i\nvar_k = var_e - var_j\nvar_l = 27\nvar_m = 200\nvar_n = 1000\nvar_o = var_m / var_n\nvar_p = var_l + var_o\nvar_q = var_k + var_p\nprint('{:.2f}'.format(round(var_q+1e-10,2)))",
        "solution_code_en": "var_a = 35\nvar_b = 500\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 1\nvar_g = 750\nvar_h = 1000\nvar_i = var_g / var_h\nvar_j = var_f + var_i\nvar_k = var_e - var_j\nvar_l = 27\nvar_m = 200\nvar_n = 1000\nvar_o = var_m / var_n\nvar_p = var_l + var_o\nvar_q = var_k + var_p\nprint('{:.2f}'.format(round(var_q+1e-10,2)))"
    },
    "350": {
        "category": "Comparison",
        "question_ko": "네 수 A, B, C, D가 있습니다. A는 3의 3배인 수입니다. B는 C보다 15 작은 수입니다. C는 A의 4배인 수입니다. D는 A보다 19 큰 수입니다. A, B, C, D 중 2번째로 큰 수는 어느 것입니까?",
        "question_en": "There are four numbers A, B, C, and D. A is 3 times 3. B is 15 less than C. C is a number four times A. D is 19 greater than A. Which of A, B, C, and D is the 2nd largest number?",
        "answer_ko": "D",
        "answer_en": "D",
        "solution_abst_ko": "[OP_LIST_SOL] A C B D [OP_LIST_EOL] [OP_LIST_SOL] 3 3 [OP_MUL] 3 3 4 [OP_MUL] [OP_MUL] 9 4 19 [OP_MUL] [OP_SUB] 3 3 19 [OP_MUL] [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A C B D [OP_LIST_EOL] [OP_LIST_SOL] 3 3 [OP_MUL] 3 3 4 [OP_MUL] [OP_MUL] 9 4 19 [OP_MUL] [OP_SUB] 3 3 19 [OP_MUL] [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'C'\nvar_c = 'B'\nvar_d = 'D'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nvar_f = 3\nvar_g = var_e * var_f\nvar_h = 3\nvar_i = 3\nvar_j = 4\nvar_k = var_i * var_j\nvar_l = var_h * var_k\nvar_m = 9\nvar_n = 4\nvar_o = 19\nvar_p = var_n * var_o\nvar_q = var_m - var_p\nvar_r = 3\nvar_s = 3\nvar_t = 19\nvar_u = var_s * var_t\nvar_v = var_r + var_u\nlist_b= []\nif \"/\" in str(var_v):\n    var_v = eval(str(var_v))\nlist_b.append(var_v)\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_w = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_x = list_c[-var_w]\nvar_y = list_b.index(var_x)+1\nvar_z = list_a[var_y-1]\nprint(var_z)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'C'\nvar_c = 'B'\nvar_d = 'D'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nvar_f = 3\nvar_g = var_e * var_f\nvar_h = 3\nvar_i = 3\nvar_j = 4\nvar_k = var_i * var_j\nvar_l = var_h * var_k\nvar_m = 9\nvar_n = 4\nvar_o = 19\nvar_p = var_n * var_o\nvar_q = var_m - var_p\nvar_r = 3\nvar_s = 3\nvar_t = 19\nvar_u = var_s * var_t\nvar_v = var_r + var_u\nlist_b= []\nif \"/\" in str(var_v):\n    var_v = eval(str(var_v))\nlist_b.append(var_v)\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_w = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_x = list_c[-var_w]\nvar_y = list_b.index(var_x)+1\nvar_z = list_a[var_y-1]\nprint(var_z)"
    },
    "351": {
        "category": "Correspondence",
        "question_ko": "바구니 안에 과일이 있다. 이 과일을 30명에게 똑같이 나누어 주면 14개가 남고 50명에게 똑같이 나누어 주면 24개가 남고 70명에게 똑같이 나누어 주면 34개가 남는다고 한다. 최소 몇 개의 과일이 바구니안에 있는지 구하여라.",
        "question_en": "There are fruits in the basket. If you divide this fruit equally to 30 people, you will have 14 fruits left over, if you share it equally with 50 people, you will have 24 fruits left over, and if you share it equally with 70 people, you will have 34 fruits left over. Find the minimum number of fruits in the basket.",
        "answer_ko": "524",
        "answer_en": "524",
        "solution_abst_ko": "0 9999 1 [OP_LIST_ARANGE] 30 14 [OP_LIST_DIVIDE_AND_REMAIN] 50 24 [OP_LIST_DIVIDE_AND_REMAIN] 70 34 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MIN]",
        "solution_abst_en": "0 9999 1 [OP_LIST_ARANGE] 30 14 [OP_LIST_DIVIDE_AND_REMAIN] 50 24 [OP_LIST_DIVIDE_AND_REMAIN] 70 34 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 0\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 30\nvar_e = 14\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 50\nvar_g = 24\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 70\nvar_i = 34\nlist_d = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_c:\n    i = int(i)\n    if i%var_h == var_i:\n        list_d.append(i)\nvar_j = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_k = list_e[var_j-1]\nprint(int(var_k))",
        "solution_code_en": "var_a = 0\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 30\nvar_e = 14\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 50\nvar_g = 24\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 70\nvar_i = 34\nlist_d = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_c:\n    i = int(i)\n    if i%var_h == var_i:\n        list_d.append(i)\nvar_j = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_k = list_e[var_j-1]\nprint(int(var_k))"
    },
    "352": {
        "category": "Comparison",
        "question_ko": "은미는 12일 동안 288문제를 풀었고, 준혁이는 9일 동안 243문제를 풀었습니다. 하루 동안 더 많은 문제를 푼 친구는 누구입니까?",
        "question_en": "Eunmi solved 288 questions in 12 days, and Junhyeok solved 243 questions in 9 days. Who solved more problems in one day?",
        "answer_ko": "준혁",
        "answer_en": "Junhyeok",
        "solution_abst_ko": "[OP_LIST_SOL] 은미 준혁 [OP_LIST_EOL] [OP_LIST_SOL] 288 12 [OP_DIV] 243 9 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Eunmi Junhyeok [OP_LIST_EOL] [OP_LIST_SOL] 288 12 [OP_DIV] 243 9 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '은미'\nvar_b = '준혁'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 288\nvar_d = 12\nvar_e = var_c / var_d\nvar_f = 243\nvar_g = 9\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Eunmi'\nvar_b = 'Junhyeok'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 288\nvar_d = 12\nvar_e = var_c / var_d\nvar_f = 243\nvar_g = 9\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "353": {
        "category": "Correspondence",
        "question_ko": "7A7을 올림하여 십의 자리까지 나타내면 730이 됩니다. A를 구하시오.",
        "question_en": "7A7 rounded up to the tens place is 730. Find A",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "7A7 [OP_GEN_POSSIBLE_LIST] 730 [OP_LIST_LESS_EQUAL] 730 10 [OP_SUB] [OP_LIST_MORE] 7A7 A [OP_LIST_FIND_UNK]",
        "solution_abst_en": "7A7 [OP_GEN_POSSIBLE_LIST] 730 [OP_LIST_LESS_EQUAL] 730 10 [OP_SUB] [OP_LIST_MORE] 7A7 A [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = '7A7'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 730\nlist_b = []\nfor i in list_a:\n    if i <= var_b:\n        list_b.append(i)\nvar_c = 730\nvar_d = 10\nvar_e = var_c - var_d\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = '7A7'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))",
        "solution_code_en": "var_a = '7A7'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 730\nlist_b = []\nfor i in list_a:\n    if i <= var_b:\n        list_b.append(i)\nvar_c = 730\nvar_d = 10\nvar_e = var_c - var_d\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = '7A7'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))"
    },
    "354": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 21센티미터(㎝)인 정사각형과 둘레의 길이가 같은 정삼각형의 한 변의 길이는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "Find the length of a side of an equilateral triangle that has the same perimeter as a square with a side length of 21 centimeters (cm) in centimeters (cm).",
        "answer_ko": "28",
        "answer_en": "28",
        "solution_abst_ko": "21 4 [OP_MUL] 3 [OP_DIV]",
        "solution_abst_en": "21 4 [OP_MUL] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 21\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 21\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "355": {
        "category": "Arithmetic calculation",
        "question_ko": "3센티미터(㎝) 간격으로 누름 못이 꽂혀진 종이띠가 있습니다. 종이띠 양끝에도 누름 못이 꽂혀져 있으며 종이띠의 길이는 114센티미터(㎝)일 때 누름 못은 모두 몇 개 있나요?",
        "question_en": "There is a paper strip with press nails inserted at 3 centimeters (cm) intervals. Pressing nails are inserted at both ends of the paper strip, and how many pressing nails are there when the length of the paper strip is 114 centimeters (cm)?",
        "answer_ko": "39",
        "answer_en": "39",
        "solution_abst_ko": "114 3 [OP_DIV] 1 [OP_ADD]",
        "solution_abst_en": "114 3 [OP_DIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 114\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 114\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "356": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 37로 나누면 몫은 23이고 나머지는 16입니다. 어떤 수는 얼마일까요?",
        "question_en": "When a certain number is divided by 37, the quotient is 23 and the remainder is 16. What is the certain number?",
        "answer_ko": "867",
        "answer_en": "867",
        "solution_abst_ko": "23 37 [OP_MUL] 16 [OP_ADD]",
        "solution_abst_en": "23 37 [OP_MUL] 16 [OP_ADD]",
        "solution_code_ko": "var_a = 23\nvar_b = 37\nvar_c = var_a * var_b\nvar_d = 16\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 23\nvar_b = 37\nvar_c = var_a * var_b\nvar_d = 16\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "357": {
        "category": "Comparison",
        "question_ko": "4명의 학생이 달리기 시합을 했습니다. 민영이는 윤기보다 빨랐습니다. 윤기는 지민이보다 빨랐습니다. 지민이는 유나보다 느렸습니다. 민영이는 유나보다 느렸습니다. 1등은 누구입니까?",
        "question_en": "There were four students running in a race. Minyoung was faster than Yoongi. Yoongi was faster than Jimin. Jimin was slower than Yuna. Minyoung was slower than Yuna. Who would be the number 1?",
        "answer_ko": "유나",
        "answer_en": "Yuna",
        "solution_abst_ko": "[OP_LIST_SOL] 민영 윤기 지민 유나 [OP_LIST_EOL] [OP_LIST_SOL] 민영 윤기 > 윤기 지민 > 지민 유나 < 민영 유나 < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Minyoung Yoongi Jimin Yuna [OP_LIST_EOL] [OP_LIST_SOL] Minyoung Yoongi > Yoongi Jimin > Jimin Yuna < Minyoung Yuna < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '민영'\nvar_b = '윤기'\nvar_c = '지민'\nvar_d = '유나'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '민영'\nvar_f = '윤기'\nvar_g = '>'\nvar_h = '윤기'\nvar_i = '지민'\nvar_j = '>'\nvar_k = '지민'\nvar_l = '유나'\nvar_m = '<'\nvar_n = '민영'\nvar_o = '유나'\nvar_p = '<'\nlist_b= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_q = 1\nvar_r = list_c[var_q-1]\nprint(var_r)",
        "solution_code_en": "var_a = 'Minyoung'\nvar_b = 'Yoongi'\nvar_c = 'Jimin'\nvar_d = 'Yuna'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'Minyoung'\nvar_f = 'Yoongi'\nvar_g = '>'\nvar_h = 'Yoongi'\nvar_i = 'Jimin'\nvar_j = '>'\nvar_k = 'Jimin'\nvar_l = 'Yuna'\nvar_m = '<'\nvar_n = 'Minyoung'\nvar_o = 'Yuna'\nvar_p = '<'\nlist_b= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_q = 1\nvar_r = list_c[var_q-1]\nprint(var_r)"
    },
    "358": {
        "category": "Geometry",
        "question_ko": "가로가 63 센티미터(㎝), 세로가 42 센티미터(㎝)인 직사각형 모양의 종이가 있습니다. 이 종이를 남는 부분 없이 가장 큰 정사각형 모양으로 여러 개 자르려고 합니다. 정사각형의 한 변을 몇 센티미터(㎝)로 해야 할까요?",
        "question_en": "You have a rectangular piece of paper measuring 63 centimeters (cm) wide and 42 centimeters (cm) long. You want to cut several pieces of this paper into the largest square shapes without any remainder. How many centimeters (cm) should each side of the square be?",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "63 42 [OP_GCD]",
        "solution_abst_en": "63 42 [OP_GCD]",
        "solution_code_ko": "var_a = 63\nvar_b = 42\nvar_c = math.gcd(int(var_b), int(var_a))\nprint(int(var_c))",
        "solution_code_en": "var_a = 63\nvar_b = 42\nvar_c = math.gcd(int(var_b), int(var_a))\nprint(int(var_c))"
    },
    "359": {
        "category": "Correspondence",
        "question_ko": "632-5AB=41라는 식이 성립하려면, A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "What number must go in A to make 632-5AB=41?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "632-5AB=41 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "632-5AB=41 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '632-5AB=41'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '632-5AB=41'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "360": {
        "category": "Arithmetic calculation",
        "question_ko": "10미터(m)간격으로 은행나무 10개가 운동장 한 쪽에 심어져있습니다. 처음과 끝에도 은행나무가 심어져 있다면 이 운동장의 길이는 몇 미터(m)인지 구해 보시오.",
        "question_en": "Ten ginkgo trees are planted on one side of the playground at intervals of 10 meters (m). If ginkgo trees are planted at both the beginning and the end, find the length in meters (m) of this field.",
        "answer_ko": "90",
        "answer_en": "90",
        "solution_abst_ko": "10 1 [OP_SUB] 10 [OP_MUL]",
        "solution_abst_en": "10 1 [OP_SUB] 10 [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 10\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 10\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "361": {
        "category": "Possibility",
        "question_ko": "정국, 지민, 윤기, 유나, 태형 중에서 반장, 부반장을 뽑으려고 합니다. 가능한 경우의 수는 모두 몇 가지 입니까",
        "question_en": "You are trying to pick a class president and a vice-captain from Jungkook, Jimin, Yoongi, Yuna, and Taehyung. How many possible cases are there?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 지민 윤기 유나 태형 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Jimin Yoongi Yuna Taehyung [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '지민'\nvar_c = '윤기'\nvar_d = '유나'\nvar_e = '태형'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nprint(int(var_h))",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Jimin'\nvar_c = 'Yoongi'\nvar_d = 'Yuna'\nvar_e = 'Taehyung'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nprint(int(var_h))"
    },
    "362": {
        "category": "Possibility",
        "question_ko": "구슬이 빨강, 파랑, 노랑, 보라, 검정 5개가 있다. 이 중 2개를 골라서 구슬치기를 하려고 한다. 경우의 수를 구하여라.",
        "question_en": "There are 5 marbles: red, blue, yellow, purple and black. You're going to pick two of these and play marbles. Find the number of cases.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "5 2 [OP_COMB]",
        "solution_abst_en": "5 2 [OP_COMB]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))"
    },
    "363": {
        "category": "Arithmetic calculation",
        "question_ko": "5학년 중 12명이 농구 시합에 참가했습니다. 6학년 중 농구 시합에 참가한 학생 수는 참가한 5학년 학생 수의 6배입니다. 농구 시합에 참가한 5학년과 6학년 학생은 모두 몇 명입니까?",
        "question_en": "12 of the 5th graders participated in the basketball game. The number of students participating in basketball games from the sixth grade is 6 times the number of 5th graders who joined the game. How many 5th and 6th graders participated in the game?",
        "answer_ko": "84",
        "answer_en": "84",
        "solution_abst_ko": "12 12 6 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "12 12 6 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 12\nvar_b = 12\nvar_c = 6\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 12\nvar_c = 6\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "364": {
        "category": "Correspondence",
        "question_ko": "어떤 수로 69를 나누면 나머지가 5이고, 86을 나누면 나머지가 6입니다. 어떤 수가 될 수 있는 수 중에서 가장 큰 수는 얼마인지 풀이 과정을 쓰고 답을 구하세요",
        "question_en": "When you divide 69 by a number, the remainder is 5, and when you divide 86, the remainder is 6. Write a process to solve what is the largest number that can be the number and find the answer.",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "69 5 [OP_SUB] 86 6 [OP_SUB] [OP_GCD]",
        "solution_abst_en": "69 5 [OP_SUB] 86 6 [OP_SUB] [OP_GCD]",
        "solution_code_ko": "var_a = 69\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 86\nvar_e = 6\nvar_f = var_d - var_e\nvar_g = math.gcd(int(var_f), int(var_c))\nprint(int(var_g))",
        "solution_code_en": "var_a = 69\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 86\nvar_e = 6\nvar_f = var_d - var_e\nvar_g = math.gcd(int(var_f), int(var_c))\nprint(int(var_g))"
    },
    "365": {
        "category": "Arithmetic calculation",
        "question_ko": "똑같은 음식 14개가 담근 그릇이 있습니다. 이 그릇의 무게는 11.14킬로그램(㎏)이며 빈 그릇의 무게는 0.5킬로그램(㎏)일 때 음식 한 개의 무게는 몇 킬로그램(㎏)입니까?",
        "question_en": "There is a bowl with the same 14 pieces of food on it. If the weight of this bowl is 11.14 kg (kg), how much kg (kg) will one piece of food weigh if the empty bowl weighs 0.5 kg (kg)?",
        "answer_ko": "0.76",
        "answer_en": "0.76",
        "solution_abst_ko": "11.14 0.5 [OP_SUB] 14 [OP_DIV]",
        "solution_abst_en": "11.14 0.5 [OP_SUB] 14 [OP_DIV]",
        "solution_code_ko": "var_a = 11.14\nvar_b = 0.5\nvar_c = var_a - var_b\nvar_d = 14\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 11.14\nvar_b = 0.5\nvar_c = var_a - var_b\nvar_d = 14\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "366": {
        "category": "Possibility",
        "question_ko": "0, 1, 2, 3, 5 중 3개의 숫자를 사용하여 세 자리 수를 만들었습니다. 이 세 자리 수의 각 자릿수가 서로 다르다고 할 때, 만들 수 있는 수는 몇 개입니까?",
        "question_en": "A three-digit number was created using three of the numbers 0, 1, 2, 3, and 5. How many numbers can be made if each digit is different?",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 5\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 5\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "367": {
        "category": "Arithmetic calculation",
        "question_ko": "규리는 5일동안 숙제를 1/3만큼하고 승연이는 2일동안 숙제를 1/5만큼 합니다. 규리와 승연이가 같이 숙제를 한다면 일을 끝내는데 며칠 걸리나요??",
        "question_en": "Gyuri does 1/3 of her homework for 5 days, and Seungyeon does 1/5 of her homework for 2 days. If they do their homework together, how many days will it take to finish the work?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "1 1/3 5 [OP_DIV] 1/5 2 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_abst_en": "1 1/3 5 [OP_DIV] 1/5 2 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 0.3333333333333333\nvar_c = 5\nvar_d = var_b / var_c\nvar_e = 0.2\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = var_a / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))",
        "solution_code_en": "var_a = 1\nvar_b = 0.3333333333333333\nvar_c = 5\nvar_d = var_b / var_c\nvar_e = 0.2\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = var_a / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))"
    },
    "368": {
        "category": "Comparison",
        "question_ko": "어느 양동이 A와 B의 들이는 각각 1100밀리리터(㎖)와 3리터(L) 400밀리리터(㎖)입니다. 이 두 양동이의 무게를 합하였을 때, 들이가 4리터(L) 800밀리리터(㎖) 인 주전자와 비교하여 어느 것의 들이가 더 많습니까?",
        "question_en": "The volumes of buckets A and B are 1100 milliliters (ml), and 3 liters (L) and 400 milliliters (ml), respectively. When the weights of these two buckets are added, which one has more volume compared to the kettle with 4 liters (L) and 800 milliliters (ml)?",
        "answer_ko": "주전자",
        "answer_en": "kettle",
        "solution_abst_ko": "[OP_LIST_SOL] 주전자 양동이 [OP_LIST_EOL] [OP_LIST_SOL] 4 1000 [OP_MUL] 800 [OP_ADD] 1100 3 1000 [OP_MUL] 400 [OP_ADD] [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] kettle bucket [OP_LIST_EOL] [OP_LIST_SOL] 4 1000 [OP_MUL] 800 [OP_ADD] 1100 3 1000 [OP_MUL] 400 [OP_ADD] [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '주전자'\nvar_b = '양동이'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 800\nvar_g = var_e + var_f\nvar_h = 1100\nvar_i = 3\nvar_j = 1000\nvar_k = var_i * var_j\nvar_l = 400\nvar_m = var_k + var_l\nvar_n = var_h + var_m\nlist_b= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_o = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_p = list_c[-var_o]\nvar_q = list_b.index(var_p)+1\nvar_r = list_a[var_q-1]\nprint(var_r)",
        "solution_code_en": "var_a = 'kettle'\nvar_b = 'bucket'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 800\nvar_g = var_e + var_f\nvar_h = 1100\nvar_i = 3\nvar_j = 1000\nvar_k = var_i * var_j\nvar_l = 400\nvar_m = var_k + var_l\nvar_n = var_h + var_m\nlist_b= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_o = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_p = list_c[-var_o]\nvar_q = list_b.index(var_p)+1\nvar_r = list_a[var_q-1]\nprint(var_r)"
    },
    "369": {
        "category": "Comparison",
        "question_ko": "9명의 학생이 달리기를 하고 있습니다. 윤기가 7등으로 달리다가 4명을 앞질렀습니다. 윤기 뒤에서 달리는 학생은 몇 명입니까?",
        "question_en": "9 students are running a race. Yoongi was running in 7th place and passed 4 other students. How many students are running behind Yoongi?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "9 7 4 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "9 7 4 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 9\nvar_b = 7\nvar_c = 4\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 7\nvar_c = 4\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "370": {
        "category": "Geometry",
        "question_ko": "각뿔의 밑면의 수는?",
        "question_en": "How many bases does a pyramid have?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "1",
        "solution_abst_en": "1",
        "solution_code_ko": "var_a = 1\nprint(int(var_a))",
        "solution_code_en": "var_a = 1\nprint(int(var_a))"
    },
    "371": {
        "category": "Correspondence",
        "question_ko": "일곱 자리 수 95738AB가 5로 나누어떨어지고 A와 B에는 0부터 9까지의 숫자가 들어갈 수 있습니다. 이러한 수는 모두 몇 개입니까?",
        "question_en": "The seven-digit number 95738AB is divisible by 5, and A and B can have any number from 0 to 9. How many numbers can satisfy these conditions?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "95738AB [OP_GEN_POSSIBLE_LIST] 5 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "95738AB [OP_GEN_POSSIBLE_LIST] 5 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '95738AB'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 5\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))",
        "solution_code_en": "var_a = '95738AB'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 5\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))"
    },
    "372": {
        "category": "Geometry",
        "question_ko": "밑면의 넓이가 36제곱센티미터(㎠) 직육면체가 있습니다. 이 직육면체의 부피는 252세제곱센티미터(㎤)입니다. 이 직육면체의 높이를 구하시오.",
        "question_en": "There is a cuboid with a base area of 36 square centimeters (cm2). The volume of this cuboid is 252 cubic centimeters (cm3). Find the height of this cuboid.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "252 36 1 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "252 36 1 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 252\nvar_b = 36\nvar_c = 1\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 252\nvar_b = 36\nvar_c = 1\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "373": {
        "category": "Possibility",
        "question_ko": "연서에게는 치마와 바지가 각각 2종류 이상이 있다. 바지는 4종류가 있으며, 바지 또는 치마를 고르는 경우의 수가 7가지일 때, 연서가 치마를 고르는 경우의 수를 구하시오.",
        "question_en": "Yeonseo has more than two types of skirts and pants each. If there are 4 types of pants and 7 ways to choose pants or skirts, find the number of cases that Yeonseo chooses a skirt.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "7 4 [OP_SUB]",
        "solution_abst_en": "7 4 [OP_SUB]",
        "solution_code_ko": "var_a = 7\nvar_b = 4\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 7\nvar_b = 4\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "374": {
        "category": "Arithmetic calculation",
        "question_ko": "승찬이가 동화책을 어제까지 전체의 0.2 만큼 읽었고, 오늘은 어제까지 읽고 남은 부분의 0.35 만큼 읽었더니 130 쪽이 남았습니다. 승찬이가 읽고 있는 동화책은 모두 몇 쪽인지 구하시오",
        "question_en": "Seungchan read 0.2 of the children's book until yesterday, and today, he read 0.35 of the rest of the children's book, so there are 130 pages left. How many pages are there in the children's book Seungchan is reading?",
        "answer_ko": "250",
        "answer_en": "250",
        "solution_abst_ko": "130 1 0.35 [OP_SUB] [OP_DIV] 1 0.2 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "130 1 0.35 [OP_SUB] [OP_DIV] 1 0.2 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 130\nvar_b = 1\nvar_c = 0.35\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 1\nvar_g = 0.2\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 130\nvar_b = 1\nvar_c = 0.35\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 1\nvar_g = 0.2\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "375": {
        "category": "Possibility",
        "question_ko": "숫자 카드 2, 4, 6, 7, 9 중 3장을 뽑아 만들 수 있는 세 자리 자연수의 개수를 구하시오.",
        "question_en": "Find the number of three-digit natural numbers that can be made by drawing three of the number cards 2, 4, 6, 7, and 9.",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "[OP_LIST_SOL] 2 4 6 7 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 2 4 6 7 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = 6\nvar_d = 7\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = 6\nvar_d = 7\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "376": {
        "category": "Geometry",
        "question_ko": "가로가 125센티미터(㎝)이고 세로가 115 센티미터(㎝)인 직사각형의 네 변의 길이의 합과 세 변의 길이의 합이 같은 정삼각형이 있습니다. 이 정삼각형의 한 변의 길이는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "There is an equilateral triangle whose sum of the lengths of three sides is the same as the sum of the lengths of four sides of a rectangle that is 125 centimeters (cm) wide and 115 centimeters (cm) long. Find the length in centimeters (cm) of one side of this equilateral triangle.",
        "answer_ko": "160",
        "answer_en": "160",
        "solution_abst_ko": "125 115 [OP_ADD] 2 [OP_MUL] 3 [OP_DIV]",
        "solution_abst_en": "125 115 [OP_ADD] 2 [OP_MUL] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 125\nvar_b = 115\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 3\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 125\nvar_b = 115\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 3\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "377": {
        "category": "Correspondence",
        "question_ko": "27A8에 1203를 뺀 값은 1022보다 큽니다. 0부터 9까지의 숫자 중 A에 쓸 수 있는 숫자는 모두 몇 개입니까?",
        "question_en": "27A8 minus 1203 is greater than 1022. How many digits from 0 to 9 can be written for A?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "27A8 [OP_GEN_POSSIBLE_LIST] 1022 1203 [OP_ADD] [OP_LIST_MORE] 27A8 A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_abst_en": "27A8 [OP_GEN_POSSIBLE_LIST] 1022 1203 [OP_ADD] [OP_LIST_MORE] 27A8 A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '27A8'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 1022\nvar_c = 1203\nvar_d = var_b + var_c\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nvar_e = '27A8'\nvar_f = 'A'\nvar_e = str(var_e)\nvar_f = str(var_f)\nunk_idx = var_e.index(var_f)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nvar_g = len(list_c)\nprint(int(var_g))",
        "solution_code_en": "var_a = '27A8'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 1022\nvar_c = 1203\nvar_d = var_b + var_c\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nvar_e = '27A8'\nvar_f = 'A'\nvar_e = str(var_e)\nvar_f = str(var_f)\nunk_idx = var_e.index(var_f)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nvar_g = len(list_c)\nprint(int(var_g))"
    },
    "378": {
        "category": "Correspondence",
        "question_ko": "0.375는 어떤 소수의 소수점을 왼쪽으로 세 칸 옮긴 뒤 10배만큼 커지게 했을때의 결과입니다. 원래의 소수를 소수점을 포함하여 구하시오.",
        "question_en": "0.375 is the result of moving a decimal point three places to the left and multiplying it by 10. Find the original decimal number including the decimal point.",
        "answer_ko": "37.50",
        "answer_en": "37.5",
        "solution_abst_ko": "0.375 10 3 [OP_POW] [OP_MUL] 10 [OP_DIV]",
        "solution_abst_en": "0.375 10 3 [OP_POW] [OP_MUL] 10 [OP_DIV]",
        "solution_code_ko": "var_a = 0.375\nvar_b = 10\nvar_c = 3\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 10\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 0.375\nvar_b = 10\nvar_c = 3\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 10\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "379": {
        "category": "Possibility",
        "question_ko": "1보다 크고 7보다 작은 짝수를 한 번씩 모두 사용하여 만들 수 있는 세 자리 수 중 가장 큰 것과 세 번째로 작은 것의 합을 구하시오.",
        "question_en": "Find the sum of the largest and the third smallest three-digit numbers that can be formed by using all even numbers greater than 1 and less than 7 once.",
        "answer_ko": "1068",
        "answer_en": "1068",
        "solution_abst_ko": "1 1 [OP_ADD] 7 1 [OP_SUB] [OP_LIST_EVEN] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "1 1 [OP_ADD] 7 1 [OP_SUB] [OP_LIST_EVEN] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 7\nvar_e = 1\nvar_f = var_d - var_e\nlist_a = []\nif var_c%2!=0:\n    for i in range(var_c+1, var_f+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_c, var_f+1, 2):\n        list_a.append(i)\nvar_g = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_i = list_c[-var_h]\nvar_j = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_k = list_d[var_j-1]\nvar_l = var_i + var_k\nprint(int(var_l))",
        "solution_code_en": "var_a = 1\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 7\nvar_e = 1\nvar_f = var_d - var_e\nlist_a = []\nif var_c%2!=0:\n    for i in range(var_c+1, var_f+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_c, var_f+1, 2):\n        list_a.append(i)\nvar_g = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_i = list_c[-var_h]\nvar_j = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_k = list_d[var_j-1]\nvar_l = var_i + var_k\nprint(int(var_l))"
    },
    "380": {
        "category": "Correspondence",
        "question_ko": "백의 자리에서 반올림하면 6000이 되는 네자리수 6A42가 있습니다. A에 0부터 9까지 들어갈 수 있을 때 가능한 A는 모두 몇 개입니까?",
        "question_en": "There is a four-digit number 6A42 which becomes 6000, when rounded to the hundred's place. How many possible A's are there if A can fit from 0 to 9?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "6A42 [OP_GEN_POSSIBLE_LIST] 6500 [OP_LIST_MORE_EQUAL] 6A42 A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_abst_en": "6A42 [OP_GEN_POSSIBLE_LIST] 6500 [OP_LIST_MORE_EQUAL] 6A42 A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '6A42'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 6500\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = '6A42'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nvar_e = len(list_c)\nprint(int(var_e))",
        "solution_code_en": "var_a = '6A42'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 6500\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = '6A42'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nvar_e = len(list_c)\nprint(int(var_e))"
    },
    "381": {
        "category": "Possibility",
        "question_ko": "숫자 카드 4, 2, 5를 모두 한 번씩 사용하여 만들 수 있는 1000보다 작고 100보다 큰 수는 총 몇 개입니까?",
        "question_en": "How many numbers less than 1000 and greater than 100 can you make by using all of the number cards 4, 2, and 5 once?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 4 2 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 4 2 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "382": {
        "category": "Possibility",
        "question_ko": "사과, 복숭아, 배, 참외가 각각 하나씩 있는 바구니에서 2개의 과일을 뺐습니다. 선택된 과일의 경우의 수는 모두 몇 가지입니까?",
        "question_en": "We took two fruits out of a basket with one apple, one peach, one pear, and one melon each. How many ways are there for the selected fruit?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 복숭아 배 참외 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] apple peach pear melon [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '복숭아'\nvar_c = '배'\nvar_d = '참외'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g / (i+1)\nprint(int(var_g))",
        "solution_code_en": "var_a = 'apple'\nvar_b = 'peach'\nvar_c = 'pear'\nvar_d = 'melon'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g / (i+1)\nprint(int(var_g))"
    },
    "383": {
        "category": "Arithmetic calculation",
        "question_ko": "한 봉지에 사탕 30개가 들어가는 사탕 봉지가 있습니다. 사탕 254개를 모두 넣고 모든 봉지에 남는 자리가 없으려면 더 사야하는 사탕은 모두 몇 개인지 구하세요.",
        "question_en": "There are candy bags with 30 candies in each bag. If you put all 254 candies in and there is no space left in all the bags, find out how many more candies you need to buy.",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "30 254 30 [OP_MOD] [OP_SUB]",
        "solution_abst_en": "30 254 30 [OP_MOD] [OP_SUB]",
        "solution_code_ko": "var_a = 30\nvar_b = 254\nvar_c = 30\nvar_d = var_b % var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 30\nvar_b = 254\nvar_c = 30\nvar_d = var_b % var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "384": {
        "category": "Geometry",
        "question_ko": "어느 어린이집에서 아이들에게 크리스마스 선물을 주기로 하였습니다. 선물은 가로 8센티미터(㎝), 세로 12센티미터(㎝), 높이 30센티미터(㎝)의 직육면체 모양이며, 선물 상자들을 정육면체 모양으로 빈틈없이 쌓았다고 합니다. 가장 선물 상자를 적게 사용하여 쌓았다고 할 때, 선물 상자는 모두 몇 개가 있는지 구하시오.",
        "question_en": "A daycare center decided to give Christmas presents to children. The gift is in the shape of a cuboid measuring 8 centimeters (cm) in width, 12 centimeters (cm) in depth, and 30 centimeters (cm) in height. The presents are neatly stacked in the shape of a box cube. If you use the least number of gift boxes, how many gift boxes are there in total?",
        "answer_ko": "600",
        "answer_en": "600",
        "solution_abst_ko": "8 12 [OP_LCM] 30 [OP_LCM] 8 [OP_DIV] 8 12 [OP_LCM] 30 [OP_LCM] 12 [OP_DIV] 8 12 [OP_LCM] 30 [OP_LCM] 30 [OP_DIV] [OP_MUL] [OP_MUL]",
        "solution_abst_en": "8 12 [OP_LCM] 30 [OP_LCM] 8 [OP_DIV] 8 12 [OP_LCM] 30 [OP_LCM] 12 [OP_DIV] 8 12 [OP_LCM] 30 [OP_LCM] 30 [OP_DIV] [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 12\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nvar_d = 30\nvar_e = var_d * var_c / math.gcd(int(var_d), int(var_c))\nvar_f = 8\nvar_g = var_e / var_f\nvar_h = 8\nvar_i = 12\nvar_j = var_i * var_h / math.gcd(int(var_i), int(var_h))\nvar_k = 30\nvar_l = var_k * var_j / math.gcd(int(var_k), int(var_j))\nvar_m = 12\nvar_n = var_l / var_m\nvar_o = 8\nvar_p = 12\nvar_q = var_p * var_o / math.gcd(int(var_p), int(var_o))\nvar_r = 30\nvar_s = var_r * var_q / math.gcd(int(var_r), int(var_q))\nvar_t = 30\nvar_u = var_s / var_t\nvar_v = var_n * var_u\nvar_w = var_g * var_v\nprint(int(var_w))",
        "solution_code_en": "var_a = 8\nvar_b = 12\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nvar_d = 30\nvar_e = var_d * var_c / math.gcd(int(var_d), int(var_c))\nvar_f = 8\nvar_g = var_e / var_f\nvar_h = 8\nvar_i = 12\nvar_j = var_i * var_h / math.gcd(int(var_i), int(var_h))\nvar_k = 30\nvar_l = var_k * var_j / math.gcd(int(var_k), int(var_j))\nvar_m = 12\nvar_n = var_l / var_m\nvar_o = 8\nvar_p = 12\nvar_q = var_p * var_o / math.gcd(int(var_p), int(var_o))\nvar_r = 30\nvar_s = var_r * var_q / math.gcd(int(var_r), int(var_q))\nvar_t = 30\nvar_u = var_s / var_t\nvar_v = var_n * var_u\nvar_w = var_g * var_v\nprint(int(var_w))"
    },
    "385": {
        "category": "Possibility",
        "question_ko": "450보다 크고, 각 자리수가 모두 다르며 3, 4, 6으로 구성되어 있는 수는 몇 개가 있는가?",
        "question_en": "How many numbers are greater than 450, have different digits, and are consisted of 3, 4, and 6?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 3 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 450 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 3 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 450 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 3\nvar_b = 4\nvar_c = 6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 450\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 3\nvar_b = 4\nvar_c = 6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 450\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "386": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이의 국어와 영어의 평균 점수는 88점이고, 수학 점수는 100점입니다. 정국이의 세 과목 평균 점수는 몇 점입니까?",
        "question_en": "Jungkook's average score for Korean and English is 88 points, and his Math score is 100 points. What is Jungkook's average score of the three subjects?",
        "answer_ko": "92",
        "answer_en": "92",
        "solution_abst_ko": "88 2 [OP_MUL] 100 [OP_ADD] 2 1 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "88 2 [OP_MUL] 100 [OP_ADD] 2 1 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 88\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 88\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "387": {
        "category": "Geometry",
        "question_ko": "한 변이 20미터(m)인 정사각형 모양의 공원을 각 변마다 3등분하여 9개의 구역으로 나누고자 합니다. 나눠진 구역의 넓이는 몇 제곱미터(㎡)입니까?",
        "question_en": "A square-shaped park with a side of 20 meters (m) is to be divided into 9 zones by dividing each side into thirds. What is the area of the divided area in square meters (m2)?",
        "answer_ko": "44.44",
        "answer_en": "44.44",
        "solution_abst_ko": "20 3 [OP_DIV] 2 [OP_POW]",
        "solution_abst_en": "20 3 [OP_DIV] 2 [OP_POW]",
        "solution_code_ko": "var_a = 20\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 20\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "388": {
        "category": "Arithmetic calculation",
        "question_ko": "영수네 학교는 중간고사에서 국어 평균이 1반은 75점, 2반은 85점, 3반은 90점, 4반은 65점을 받았다. 영수네 학교 중간고사 평균보다 아래인 반의 평균 합은 얼마인가?",
        "question_en": "Youngsoo's school received an average of 75 points in the Korean midterm in class 1, 85 in class 2, 90 in class 3, and 65 in class 4. What is the sum of the averages of the classes below the school's midterm exam average?",
        "answer_ko": "140",
        "answer_en": "140",
        "solution_abst_ko": "[OP_LIST_SOL] 75 85 90 65 [OP_LIST_EOL] [OP_LIST_MEAN] [OP_LIST_LESS] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 75 85 90 65 [OP_LIST_EOL] [OP_LIST_MEAN] [OP_LIST_LESS] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 75\nvar_b = 85\nvar_c = 90\nvar_d = 65\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_e = sum(list_a)/len(list_a)\nlist_b = []\nfor i in list_a:\n    if i < var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 75\nvar_b = 85\nvar_c = 90\nvar_d = 65\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_e = sum(list_a)/len(list_a)\nlist_b = []\nfor i in list_a:\n    if i < var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint(int(var_f))"
    },
    "389": {
        "category": "Correspondence",
        "question_ko": "A72-23=549라는 식이 성립하려면, A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "What number must go in A to make A72-23=549?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "A72-23=549 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A72-23=549 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A72-23=549'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A72-23=549'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "390": {
        "category": "Correspondence",
        "question_ko": "연필을 8명에게 똑같이 나누어주니 6개씩 나누어주고 4개가 남았다. 같은 수의 연필을 4명에게 똑같이 나누어주면 몇개씩 나누어 줄 수 있는가?",
        "question_en": "When I distributed pencils equally to 8 people, I could give 6 pencils each and there was 4 left. If you divide the same number of pencils equally among 4 people, how many can you distribute?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "6 8 [OP_MUL] 4 [OP_ADD] 4 [OP_DIV]",
        "solution_abst_en": "6 8 [OP_MUL] 4 [OP_ADD] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 4\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 6\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 4\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "391": {
        "category": "Possibility",
        "question_ko": "3, 5, 7, 8 중에서 서로 다른 숫자 2개를 뽑아 만들 수 있는 두 자리 수 중에서 가장 큰 수와 가장 작은 수의 합을 구하시오.",
        "question_en": "Find the sum of the largest and smallest two-digit numbers that can be formed by drawing out two different numbers from 3, 5, 7, and 8.",
        "answer_ko": "122",
        "answer_en": "122",
        "solution_abst_ko": "[OP_LIST_SOL] 3 5 7 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 3 5 7 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 5\nvar_c = 7\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 3\nvar_b = 5\nvar_c = 7\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))"
    },
    "392": {
        "category": "Possibility",
        "question_ko": "도둑이 비밀 금고를 찾았습니다. 금고의 비밀번호는 6 ,2, 5를 한 번씩 모두 사용하여 만든 세 자리 중 가장 큰 수와 가장 작은 수의 합입니다. 금고의 비밀번호는 무엇입니까?",
        "question_en": "A thief has found a secret safe. The safe's password is the sum of the largest and smallest of the three digits created by using all 6,2 and 5 once. What is the password for the safe?",
        "answer_ko": "908",
        "answer_en": "908",
        "solution_abst_ko": "[OP_LIST_SOL] 6 2 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 6 2 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))"
    },
    "393": {
        "category": "Possibility",
        "question_ko": "5 장의 숫자 카드 0, 1, 5, 7, 9를 한 번씩 사용하여 만들 수 있는 두번째로 큰 다섯 자리 수를 올림하여 십의 자리까지 나타내어 보시오.",
        "question_en": "Round up the second largest five-digit number you can make by using the five number cards 0, 1, 5, 7, and 9 once to the tens digit.",
        "answer_ko": "97510",
        "answer_en": "97510",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 5 7 9 [OP_LIST_EOL] 5 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 2 [OP_CEIL]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 5 7 9 [OP_LIST_EOL] 5 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 2 [OP_CEIL]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 5\nvar_d = 7\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 5\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 2\nvar_j=int(((var_h+9*10**(var_i-2))//(10**(var_i-1)))*10**(var_i-1))\n\nprint(int(var_j))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 5\nvar_d = 7\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 5\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 2\nvar_j=int(((var_h+9*10**(var_i-2))//(10**(var_i-1)))*10**(var_i-1))\n\nprint(int(var_j))"
    },
    "394": {
        "category": "Arithmetic calculation",
        "question_ko": "익은 수박이 11개 덜익은 수박이 13개 있습니다. 이중 15개가 씨없는 수박이라면 씨가 있는 수박의 개수는 몇 개입니까?",
        "question_en": "There are 11 ripe watermelons and 13 unripe watermelons. If 15 of these watermelons are seedless, how many watermelons have seeds?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "11 13 [OP_ADD] 15 [OP_SUB]",
        "solution_abst_en": "11 13 [OP_ADD] 15 [OP_SUB]",
        "solution_code_ko": "var_a = 11\nvar_b = 13\nvar_c = var_a + var_b\nvar_d = 15\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 11\nvar_b = 13\nvar_c = var_a + var_b\nvar_d = 15\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "395": {
        "category": "Geometry",
        "question_ko": "어떤 나무토막은 가로가 5센티미터(㎝), 세로가 4센티미터(㎝), 높이가 3센티미터(㎝)인 직육면체 모양이다. 이 나무토막을 물에 빠뜨려서 모든 면을 적시고, 한 면의 넓이가 1제곱센티미터(㎠)인 60개의 정육면체 조각으로 잘라냈다. 정육면체 조각 중 한 면에만 물이 묻어있는 것은 몇 개인가?",
        "question_en": "A block of wood is in the shape of a cuboid measuring 5 centimeters (cm) in width, 4 centimeters (cm) in depth, and 3 centimeters (cm) in height. This block of wood was dipped in water, wet on all sides, and cut into 60 cubed pieces with a side area of 1 square centimeter (cm2). How many cubes have water on only one side?",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "5 2 [OP_SUB] 4 2 [OP_SUB] [OP_MUL] 5 2 [OP_SUB] 3 2 [OP_SUB] [OP_MUL] [OP_ADD] 4 2 [OP_SUB] 3 2 [OP_SUB] [OP_MUL] [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "5 2 [OP_SUB] 4 2 [OP_SUB] [OP_MUL] 5 2 [OP_SUB] 3 2 [OP_SUB] [OP_MUL] [OP_ADD] 4 2 [OP_SUB] 3 2 [OP_SUB] [OP_MUL] [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = var_c * var_f\nvar_h = 5\nvar_i = 2\nvar_j = var_h - var_i\nvar_k = 3\nvar_l = 2\nvar_m = var_k - var_l\nvar_n = var_j * var_m\nvar_o = var_g + var_n\nvar_p = 4\nvar_q = 2\nvar_r = var_p - var_q\nvar_s = 3\nvar_t = 2\nvar_u = var_s - var_t\nvar_v = var_r * var_u\nvar_w = var_o + var_v\nvar_x = 2\nvar_y = var_w * var_x\nprint(int(var_y))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = var_c * var_f\nvar_h = 5\nvar_i = 2\nvar_j = var_h - var_i\nvar_k = 3\nvar_l = 2\nvar_m = var_k - var_l\nvar_n = var_j * var_m\nvar_o = var_g + var_n\nvar_p = 4\nvar_q = 2\nvar_r = var_p - var_q\nvar_s = 3\nvar_t = 2\nvar_u = var_s - var_t\nvar_v = var_r * var_u\nvar_w = var_o + var_v\nvar_x = 2\nvar_y = var_w * var_x\nprint(int(var_y))"
    },
    "396": {
        "category": "Arithmetic calculation",
        "question_ko": "자전거를 타고 운동장을 5바퀴 도는데 1시간 36분이 걸린다고 합니다. 운동장 한 바퀴 돌 때는 몇 분 걸리나요?",
        "question_en": "It is said that it takes 1 hour and 36 minutes to cycle 5 laps around the playground on a bicycle. How many minutes does it take to complete one lap around the playground?",
        "answer_ko": "19.20",
        "answer_en": "19.2",
        "solution_abst_ko": "1 60 [OP_MUL] 36 [OP_ADD] 5 [OP_DIV]",
        "solution_abst_en": "1 60 [OP_MUL] 36 [OP_ADD] 5 [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 36\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 36\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "397": {
        "category": "Arithmetic calculation",
        "question_ko": "외계인은 달리기를 좋아한다. 토끼를 보고 달릴 때 시속 15킬로미터(㎞)로 뛰었고, 개구리를 보고 달려갈 때는 시속 10킬로미터(㎞)로 뛰었더니, 30분이 더 걸렸다. 개구리를 보고 뛰어갈 때 걸린 시간을 구하시오.",
        "question_en": "This Alien likes to run. When it saw a rabbit and ran, it ran at 15 kilometers (km) per hour, and it ran at 10 kilometers per hour (km) when it spotted a frog, which took 30 minutes more. Find the time it took to run after seeing the frog.",
        "answer_ko": "1.50",
        "answer_en": "1.5",
        "solution_abst_ko": "10 30 60 [OP_DIV] [OP_MUL] 15 10 [OP_SUB] [OP_DIV] 30 60 [OP_DIV] [OP_ADD]",
        "solution_abst_en": "10 30 60 [OP_DIV] [OP_MUL] 15 10 [OP_SUB] [OP_DIV] 30 60 [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 30\nvar_c = 60\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 15\nvar_g = 10\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 30\nvar_k = 60\nvar_l = var_j / var_k\nvar_m = var_i + var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))",
        "solution_code_en": "var_a = 10\nvar_b = 30\nvar_c = 60\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 15\nvar_g = 10\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 30\nvar_k = 60\nvar_l = var_j / var_k\nvar_m = var_i + var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))"
    },
    "398": {
        "category": "Correspondence",
        "question_ko": "23에 어떤 수를 더했더니 결과가 34가 되었습니다. 어떤 수를 정확히 구하시오.",
        "question_en": "When you add a number to 23, the result is 34. Find out which number exactly.",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "34 23 [OP_SUB]",
        "solution_abst_en": "34 23 [OP_SUB]",
        "solution_code_ko": "var_a = 34\nvar_b = 23\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 34\nvar_b = 23\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "399": {
        "category": "Correspondence",
        "question_ko": "18/5를 9/4로 두 번 나눈 값을 구하시오.",
        "question_en": "Find the value of 18/5 divided by 9/4 twice.",
        "answer_ko": "0.71",
        "answer_en": "0.71",
        "solution_abst_ko": "18/5 9/4 [OP_DIV] 9/4 [OP_DIV]",
        "solution_abst_en": "18/5 9/4 [OP_DIV] 9/4 [OP_DIV]",
        "solution_code_ko": "var_a = 3.6\nvar_b = 2.25\nvar_c = var_a / var_b\nvar_d = 2.25\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 3.6\nvar_b = 2.25\nvar_c = var_a / var_b\nvar_d = 2.25\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "400": {
        "category": "Arithmetic calculation",
        "question_ko": "지혜의 지갑에는 1000원짜리가 2장 있고 동전으로는 560원이 있습니다. 지혜의 지갑 속에 있는 돈은 총 얼마입니까?",
        "question_en": "In Jihye's wallet, there are two 1000 wons, and 560 won coins. What is the total amount of money in Jihye's wallet?",
        "answer_ko": "2560",
        "answer_en": "2560",
        "solution_abst_ko": "2 1000 [OP_MUL] 560 [OP_ADD]",
        "solution_abst_en": "2 1000 [OP_MUL] 560 [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 560\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 560\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "401": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 8로 나눈 후 8을 더하고, 30을 뺀 값에 6을 곱한 값이 12입니다. 어떤 수를 구하시오.",
        "question_en": "Dividing a number by 8, adding 8, subtracting 30, and multiplying by 6 equals 12. Find the number.",
        "answer_ko": "192",
        "answer_en": "192",
        "solution_abst_ko": "12 6 [OP_DIV] 30 [OP_ADD] 8 [OP_SUB] 8 [OP_MUL]",
        "solution_abst_en": "12 6 [OP_DIV] 30 [OP_ADD] 8 [OP_SUB] 8 [OP_MUL]",
        "solution_code_ko": "var_a = 12\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 30\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e - var_f\nvar_h = 8\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 12\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 30\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e - var_f\nvar_h = 8\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "402": {
        "category": "Comparison",
        "question_ko": "(가), (나) 두 개의 원이 있습니다. (가)의 넓이는 198.4제곱센티미터(㎠), (나)의 넓이는 251.1제곱센티미터(㎠)입니다. 원주율을 3.1로 계산할 때 (나)의 원 둘레 길이를 (가)의 원 둘레 길이로 뺀 값은 몇 센티미터(㎝)인지 소수점을 포함하여 구하시오.",
        "question_en": "There are two circles of A and B. The area of A is 198.4 square centimeters (cm2), and the area of B is 251.1 square centimeters (cm2). On the condition that pi is calculated as 3.1, what is the number of centimeters (cm) when you subtract the circumference of A from the circumference of B, including the decimal point?",
        "answer_ko": "6.2",
        "answer_en": "6.2",
        "solution_abst_ko": "198.4 3.1 [OP_DIV] 1 2 [OP_DIV] [OP_POW] 2 [OP_MUL] 3.1 [OP_MUL] 251.1 3.1 [OP_DIV] 1 2 [OP_DIV] [OP_POW] 2 [OP_MUL] 3.1 [OP_MUL] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "198.4 3.1 [OP_DIV] 1 2 [OP_DIV] [OP_POW] 2 [OP_MUL] 3.1 [OP_MUL] 251.1 3.1 [OP_DIV] 1 2 [OP_DIV] [OP_POW] 2 [OP_MUL] 3.1 [OP_MUL] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 198.4\nvar_b = 3.1\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = 2\nvar_f = var_d / var_e\nvar_g = var_c ** var_f\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = 3.1\nvar_k = var_i * var_j\nvar_l = 251.1\nvar_m = 3.1\nvar_n = var_l / var_m\nvar_o = 1\nvar_p = 2\nvar_q = var_o / var_p\nvar_r = var_n ** var_q\nvar_s = 2\nvar_t = var_r * var_s\nvar_u = 3.1\nvar_v = var_t * var_u\nvar_w = var_k - var_v\nvar_x = abs(var_w)\nprint('{:.2f}'.format(round(var_x+1e-10,2)))",
        "solution_code_en": "var_a = 198.4\nvar_b = 3.1\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = 2\nvar_f = var_d / var_e\nvar_g = var_c ** var_f\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = 3.1\nvar_k = var_i * var_j\nvar_l = 251.1\nvar_m = 3.1\nvar_n = var_l / var_m\nvar_o = 1\nvar_p = 2\nvar_q = var_o / var_p\nvar_r = var_n ** var_q\nvar_s = 2\nvar_t = var_r * var_s\nvar_u = 3.1\nvar_v = var_t * var_u\nvar_w = var_k - var_v\nvar_x = abs(var_w)\nprint('{:.2f}'.format(round(var_x+1e-10,2)))"
    },
    "403": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 50까지의 자연수 중에서 모든 짝수의 합과 모든 홀수의 합의 합을 구하시오",
        "question_en": "Find the sum of the sum of all even numbers and the sum of all odd numbers from 1 to 50.",
        "answer_ko": "1275",
        "answer_en": "1275",
        "solution_abst_ko": "1 50 [OP_LIST_EVEN] [OP_LIST_SUM] 1 50 [OP_LIST_ODD] [OP_LIST_SUM] [OP_ADD]",
        "solution_abst_en": "1 50 [OP_LIST_EVEN] [OP_LIST_SUM] 1 50 [OP_LIST_ODD] [OP_LIST_SUM] [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 50\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nvar_d = 1\nvar_e = 50\nlist_b = []\nif var_d%2==0:\n    for i in range(var_d+1, var_e+1, 2):\n        list_b.append(i)\nelse:\n    for i in range(var_d, var_e+1, 2):\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 50\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nvar_d = 1\nvar_e = 50\nlist_b = []\nif var_d%2==0:\n    for i in range(var_d+1, var_e+1, 2):\n        list_b.append(i)\nelse:\n    for i in range(var_d, var_e+1, 2):\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "404": {
        "category": "Arithmetic calculation",
        "question_ko": "숫자 4, 5로 나누어 떨어질 수 있는 세 자리 수 중 가장 작은 수는 무엇입니까?",
        "question_en": "What is the smallest three-digit number that is divisible by the numbers 4 and 5?",
        "answer_ko": "100",
        "answer_en": "100",
        "solution_abst_ko": "100 999 1 [OP_LIST_ARANGE] 4 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "100 999 1 [OP_LIST_ARANGE] 4 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 4\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 4\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[var_f-1]\nprint(int(var_g))"
    },
    "405": {
        "category": "Comparison",
        "question_ko": "4개의 숫자 0.8, 1/2, 0.9, 1/3가 있습니다. 3보다 큰 수는 몇 개입니까?",
        "question_en": "There are four numbers 0.8, 1/2, 0.9, 1/3. How many numbers are greater than 3?",
        "answer_ko": "0",
        "answer_en": "0",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 3 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 3 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "406": {
        "category": "Arithmetic calculation",
        "question_ko": "5일동안 60개의 장난감을 만들 수 있다. 540개를 만들려면 며칠 걸리는가?",
        "question_en": "You can make 60 toys in 5 days. How many days will it take to make 540?",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "540 60 [OP_DIV] 5 [OP_MUL]",
        "solution_abst_en": "540 60 [OP_DIV] 5 [OP_MUL]",
        "solution_code_ko": "var_a = 540\nvar_b = 60\nvar_c = var_a / var_b\nvar_d = 5\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 540\nvar_b = 60\nvar_c = var_a / var_b\nvar_d = 5\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "407": {
        "category": "Possibility",
        "question_ko": "3, 5, 6, 7 총 4장의 수 카드 중 2장을 사용하여 두 자리 수를 만들려고 합니다. 만들 수 있는 7의 배수는 모두 몇 개일까요?",
        "question_en": "You are going to use 2 of 4 number cards 3, 5, 6, and 7 to create a two-digit number. How many multiples of 7 can you make?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 3 5 6 7 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 7 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 3 5 6 7 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 7 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 3\nvar_b = 5\nvar_c = 6\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 7\nlist_c = []\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nvar_g = len(list_c)\nprint(int(var_g))",
        "solution_code_en": "var_a = 3\nvar_b = 5\nvar_c = 6\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 7\nlist_c = []\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nvar_g = len(list_c)\nprint(int(var_g))"
    },
    "408": {
        "category": "Comparison",
        "question_ko": "민영이는 줄넘기를 어제는 52번 했고, 오늘은 어제보다 19번 더 적게 했습니다. 유정이는 줄넘기를 어제는 18번 했고, 오늘은 어제보다 21번 더 많이 했습니다. 오늘 줄넘기를 더 많이 한 사람은 누구입니까?",
        "question_en": "Minyoung jumped rope 52 times yesterday, and today she jumped 19 fewer times than yesterday. Yoojung jumped rope 18 times yesterday, and today she jumped 21 times more than yesterday. Who jumped more ropes today?",
        "answer_ko": "유정",
        "answer_en": "Yoojung",
        "solution_abst_ko": "[OP_LIST_SOL] 민영 유정 [OP_LIST_EOL] [OP_LIST_SOL] 52 19 [OP_SUB] 18 21 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Minyoung Yoojung [OP_LIST_EOL] [OP_LIST_SOL] 52 19 [OP_SUB] 18 21 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '민영'\nvar_b = '유정'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 52\nvar_d = 19\nvar_e = var_c - var_d\nvar_f = 18\nvar_g = 21\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Minyoung'\nvar_b = 'Yoojung'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 52\nvar_d = 19\nvar_e = var_c - var_d\nvar_f = 18\nvar_g = 21\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "409": {
        "category": "Arithmetic calculation",
        "question_ko": "국어, 영어, 사회, 과학의 평균 점수는 90점이고 수학 점수를 포함하면 평균 점수가 3점 떨어진다. 수학 점수는 몇 점인가?",
        "question_en": "The average score for Korean, English, social studies, and science is 90 points, and when math scores are included, the average score drops by 3 points. What is math score?",
        "answer_ko": "75",
        "answer_en": "75",
        "solution_abst_ko": "90 3 [OP_SUB] 5 [OP_MUL] 90 4 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "90 3 [OP_SUB] 5 [OP_MUL] 90 4 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 90\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c * var_d\nvar_f = 90\nvar_g = 4\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 90\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c * var_d\nvar_f = 90\nvar_g = 4\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nprint(int(var_i))"
    },
    "410": {
        "category": "Arithmetic calculation",
        "question_ko": "남준이는 국어, 수학, 영어 3과목 시험을 보았습니다. 수학은 100점, 영어는 95점이고 3과목 평균 점수가 95점일 때, 남준이의 국어 점수는 몇 점입니까?",
        "question_en": "Namjoon took the test of 3 subjects: Korean, Mathematics, and English. If his math score is 100, his English 95, and the average score of 3 subjects is 95, what score did Namjoon's get in his Korean test?",
        "answer_ko": "90",
        "answer_en": "90",
        "solution_abst_ko": "95 3 [OP_MUL] 100 [OP_SUB] 95 [OP_SUB]",
        "solution_abst_en": "95 3 [OP_MUL] 100 [OP_SUB] 95 [OP_SUB]",
        "solution_code_ko": "var_a = 95\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = var_c - var_d\nvar_f = 95\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 95\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = var_c - var_d\nvar_f = 95\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "411": {
        "category": "Correspondence",
        "question_ko": "A2-5A=B3을 만족하는 A, B가 서로 다른 두 수라면 AxB의 값을 구하시오",
        "question_en": "If A and B are different numbers and A2-5A=B3 is true, find the value of AxB.",
        "answer_ko": "27",
        "answer_en": "27",
        "solution_abst_ko": "A2-5A=B3 A [OP_DIGIT_UNK_SOLVER] A2-5A=B3 B [OP_DIGIT_UNK_SOLVER] [OP_MUL]",
        "solution_abst_en": "A2-5A=B3 A [OP_DIGIT_UNK_SOLVER] A2-5A=B3 B [OP_DIGIT_UNK_SOLVER] [OP_MUL]",
        "solution_code_ko": "var_a = 'A2-5A=B3'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 'A2-5A=B3'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 'A2-5A=B3'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 'A2-5A=B3'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "412": {
        "category": "Possibility",
        "question_ko": "0부터 4까지의 숫자 중 서로 같지 않은 3개의 숫자를 골라 세 자리 수를 만들었다. 이 중 2, 3, 5로 나누었을 때 나머지가 0 인 수는 몇 개인가?",
        "question_en": "A three-digit number was created by choosing three unequal numbers from 0 to 4. How many of these numbers have a remainder of 0 when divided by 2, 3, or 5?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 3 [OP_LCM] 5 [OP_LCM] [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 3 [OP_LCM] 5 [OP_LCM] [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 2\nvar_h = 3\nvar_i = var_h * var_g / math.gcd(int(var_h), int(var_g))\nvar_j = 5\nvar_k = var_j * var_i / math.gcd(int(var_j), int(var_i))\nlist_c = []\nvar_k = int(var_k)\nfor i in list_b:\n    i = int(i)\n    if i % var_k == 0:\n        list_c.append(i)\nvar_l = len(list_c)\nprint(int(var_l))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 2\nvar_h = 3\nvar_i = var_h * var_g / math.gcd(int(var_h), int(var_g))\nvar_j = 5\nvar_k = var_j * var_i / math.gcd(int(var_j), int(var_i))\nlist_c = []\nvar_k = int(var_k)\nfor i in list_b:\n    i = int(i)\n    if i % var_k == 0:\n        list_c.append(i)\nvar_l = len(list_c)\nprint(int(var_l))"
    },
    "413": {
        "category": "Arithmetic calculation",
        "question_ko": "예리네 학교 전체 학생 수는 5학년 학생 수의 8배보다 32명 더 적고 5학년 남학생은 5학년 여학생보다 10명 더 많습니다. 예리네 학교 전체 학생 수가 1152명일 때, 5학년 여학생은 몇 명입니까?",
        "question_en": "The total number of students at Yerin's school is 32 fewer than eight times the number of 5th graders, and there are 10 more 5th grade boys than 5th grade girls. If the total number of students in Yerin's school is 1152, how many female students are there in the 5th grade?",
        "answer_ko": "69",
        "answer_en": "69",
        "solution_abst_ko": "1152 32 [OP_ADD] 8 [OP_DIV] 10 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "1152 32 [OP_ADD] 8 [OP_DIV] 10 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 1152\nvar_b = 32\nvar_c = var_a + var_b\nvar_d = 8\nvar_e = var_c / var_d\nvar_f = 10\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1152\nvar_b = 32\nvar_c = var_a + var_b\nvar_d = 8\nvar_e = var_c / var_d\nvar_f = 10\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "414": {
        "category": "Arithmetic calculation",
        "question_ko": "세 자리 짝수 자연수들의 합을 구하시오.",
        "question_en": "Find the sum of three-digit even natural numbers.",
        "answer_ko": "247050",
        "answer_en": "247050",
        "solution_abst_ko": "100 999 [OP_LIST_EVEN] [OP_LIST_SUM]",
        "solution_abst_en": "100 999 [OP_LIST_EVEN] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 100\nvar_b = 999\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nprint(int(var_c))",
        "solution_code_en": "var_a = 100\nvar_b = 999\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nprint(int(var_c))"
    },
    "415": {
        "category": "Possibility",
        "question_ko": "광호는 4개의 숫자 자석 2, 6, 0, 7을 가지고 있다. 여기서 3개를 골라 세 자리 수를 만드는 놀이를 할 때, 광호가 만들 수 있는 수 중 세 번째 큰 수와 세 번째 작은 수의 차를 구하시오.",
        "question_en": "Gwangho has four number magnets of 2, 6, 0, and 7. When playing the game of making three-digit numbers by choosing three of those magnets, find the difference between the third largest number and the third smallest number that he can make.",
        "answer_ko": "466",
        "answer_en": "466",
        "solution_abst_ko": "[OP_LIST_SOL] 2 6 0 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 2 6 0 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 2\nvar_b = 6\nvar_c = 0\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 2\nvar_b = 6\nvar_c = 0\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))"
    },
    "416": {
        "category": "Arithmetic calculation",
        "question_ko": "민기는 4시간에 256문제를 풉니다. 소민이는 3시간에 111문제를 풀 수 있다면 3시간 동안 민기와 소민이가 푼 문제는 모두 몇 문제입니까?",
        "question_en": "Mingi solves 256 questions in 4 hours. If Somin can solve 111 questions in 3 hours, how many questions did Mingi and Somin solve in 3 hours?",
        "answer_ko": "303",
        "answer_en": "303",
        "solution_abst_ko": "256 3 4 [OP_DIV] [OP_MUL] 111 [OP_ADD]",
        "solution_abst_en": "256 3 4 [OP_DIV] [OP_MUL] 111 [OP_ADD]",
        "solution_code_ko": "var_a = 256\nvar_b = 3\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 111\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 256\nvar_b = 3\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 111\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "417": {
        "category": "Arithmetic calculation",
        "question_ko": "마트에 오이가 58개 있습니다. 당근이 오이보다 24개 적고, 토마토가 오이보다 49개 많습니다. 무의 수는 당근의 수와 같습니다. 마트에 있는 오이, 당근, 토마토, 무는 모두 몇 개입니까?",
        "question_en": "There are 58 cucumbers in the mart. There are 24 fewer carrots than cucumbers, and 49 more tomatoes than cucumbers. The number of radishes equals the number of carrots. How many cucumbers, carrots, tomatoes, and radishes are in the mart in total?",
        "answer_ko": "233",
        "answer_en": "233",
        "solution_abst_ko": "58 58 24 [OP_SUB] [OP_ADD] 58 49 [OP_ADD] [OP_ADD] 58 24 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "58 58 24 [OP_SUB] [OP_ADD] 58 49 [OP_ADD] [OP_ADD] 58 24 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 58\nvar_b = 58\nvar_c = 24\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 58\nvar_g = 49\nvar_h = var_f + var_g\nvar_i = var_e + var_h\nvar_j = 58\nvar_k = 24\nvar_l = var_j - var_k\nvar_m = var_i + var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 58\nvar_b = 58\nvar_c = 24\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 58\nvar_g = 49\nvar_h = var_f + var_g\nvar_i = var_e + var_h\nvar_j = 58\nvar_k = 24\nvar_l = var_j - var_k\nvar_m = var_i + var_l\nprint(int(var_m))"
    },
    "418": {
        "category": "Arithmetic calculation",
        "question_ko": "유정이는 올해 5살입니다. 유정이의 할머니는 유정이가 10살이 되는 해에 60세입니다. 올해 할머니의 나이는 몇 살입니까?",
        "question_en": "Yoojung is 5 years old this year. In the year when Yoojung turns 10, her grandmother is 60. Find what age is her grandmother this year.",
        "answer_ko": "55",
        "answer_en": "55",
        "solution_abst_ko": "60 10 5 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "60 10 5 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 60\nvar_b = 10\nvar_c = 5\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 60\nvar_b = 10\nvar_c = 5\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "419": {
        "category": "Geometry",
        "question_ko": "사각형에 존재하는 모든 대각선의 개수에 3을 더하면 얼마인지 구하시오.",
        "question_en": "Find the value of adding 3 to the number of diagonals in the rectangle.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "4 4 3 [OP_SUB] [OP_MUL] 2 [OP_DIV] 3 [OP_ADD]",
        "solution_abst_en": "4 4 3 [OP_SUB] [OP_MUL] 2 [OP_DIV] 3 [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 4\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 3\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 4\nvar_b = 4\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 3\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "420": {
        "category": "Possibility",
        "question_ko": "샤프 1개와 똑같은 볼펜 4개를 일렬로 정렬하려고 합니다. 정렬될 수 있는 가지 수는 몇 가지입니까?",
        "question_en": "You want to arrange 4 identical ballpoint pens and 1 mechanical pencil in a line. What is the number of cases to arrange them?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "4 1 [OP_ADD]",
        "solution_abst_en": "4 1 [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "421": {
        "category": "Correspondence",
        "question_ko": "여덟 자리 수 757AB384는 357로 나누어떨어지는 수이다. A를 구하시오.",
        "question_en": "The eight-digit number 757AB384 is divisible by 357. Get A.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "757AB384 [OP_GEN_POSSIBLE_LIST] 357 [OP_LIST_DIVISIBLE] 757AB384 B [OP_LIST_FIND_UNK]",
        "solution_abst_en": "757AB384 [OP_GEN_POSSIBLE_LIST] 357 [OP_LIST_DIVISIBLE] 757AB384 B [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = '757AB384'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 357\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = '757AB384'\nvar_d = 'B'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nvar_e = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_e = int(elem[unk_idx])\nprint(int(var_e))",
        "solution_code_en": "var_a = '757AB384'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 357\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = '757AB384'\nvar_d = 'B'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nvar_e = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_e = int(elem[unk_idx])\nprint(int(var_e))"
    },
    "422": {
        "category": "Possibility",
        "question_ko": "현승이의 옷장에 3종류의 상의, 2종류의 하의, 5종류의 신발이 있다. 현승이가 입을 수 있는 상의, 하의, 신발의 경우의 수는 모두 얼마인가?",
        "question_en": "In Hyunseung's closet, there are 3 types of tops, 2 types of bottoms, and 5 types of shoes. How many types of tops, bottoms, and shoes can Hyunseung wear?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "3 2 [OP_MUL] 5 [OP_MUL]",
        "solution_abst_en": "3 2 [OP_MUL] 5 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "423": {
        "category": "Arithmetic calculation",
        "question_ko": "민영이가 가진 돈은 90원 짜리 사탕을 A개 살 수 있는 돈이었습니다. 90원 짜리 사탕 대신 60원 짜리 사탕을 A개 만큼 샀더니 270원이 남았다면 처음 민영이가 가진 돈은 얼마입니까?",
        "question_en": "The money Minyoung had was enough to buy A pieces of candy worth 90 won. If he bought A pieces of 60 won candies instead of 90 won candies, and he had 270 won left, how much money does Minyoung have at first?",
        "answer_ko": "810",
        "answer_en": "810",
        "solution_abst_ko": "270 90 60 [OP_SUB] [OP_DIV] 90 [OP_MUL]",
        "solution_abst_en": "270 90 60 [OP_SUB] [OP_DIV] 90 [OP_MUL]",
        "solution_code_ko": "var_a = 270\nvar_b = 90\nvar_c = 60\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 90\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 270\nvar_b = 90\nvar_c = 60\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 90\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "424": {
        "category": "Arithmetic calculation",
        "question_ko": "호진이가 등산을 하면서 13/4리터(L)의 물을 가지고 올라갔다. 등산 중에 12/5리터(L)를 마시고 약수터에서 11/6리터(L) 만큼 다시 채웠다. 물통에 남은 물은 몇 리터(L) 인지 구하시오.",
        "question_en": "There is 13/4 liter (L) of water in the water tank. From this water tank, 12/5 liter (L) was scooped out and 11/6 liter (L) was put back in. Find how many liters (L) of water are left in the water tank.",
        "answer_ko": "2.68",
        "answer_en": "2.68",
        "solution_abst_ko": "13/4 12/5 [OP_SUB] 11/6 [OP_ADD]",
        "solution_abst_en": "13/4 12/5 [OP_SUB] 11/6 [OP_ADD]",
        "solution_code_ko": "var_a = 3.25\nvar_b = 2.4\nvar_c = var_a - var_b\nvar_d = 1.8333333333333333\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 3.25\nvar_b = 2.4\nvar_c = var_a - var_b\nvar_d = 1.8333333333333333\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "425": {
        "category": "Geometry",
        "question_ko": "넓이가 54.3제곱센티미터(㎠)인 정육각형을 6 등분하였습니다. 6 등분된 부분 하나의 넓이는 몇 제곱센티미터(㎠) 입니까?",
        "question_en": "A regular hexagon with an area of 54.3 square centimeters (cm2) is divided into 6 equal parts. How many square centimeters (cm2) is the area of one of the 6 equal parts?",
        "answer_ko": "9.05",
        "answer_en": "9.05",
        "solution_abst_ko": "54.3 6 [OP_DIV]",
        "solution_abst_en": "54.3 6 [OP_DIV]",
        "solution_code_ko": "var_a = 54.3\nvar_b = 6\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 54.3\nvar_b = 6\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "426": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 2배 한 것에 3을 빼면 7이다. 어떤 수를 구한 후, 어떤 수에서 2를 나눈 나머지를 구하시오.",
        "question_en": "A number multiplied by 2 minus 3 equals 7. After finding the number, find the remainder when dividing the number by 2.",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "7 3 [OP_ADD] 2 [OP_DIV] 2 [OP_MOD]",
        "solution_abst_en": "7 3 [OP_ADD] 2 [OP_DIV] 2 [OP_MOD]",
        "solution_code_ko": "var_a = 7\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e % var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 7\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e % var_f\nprint(int(var_g))"
    },
    "427": {
        "category": "Arithmetic calculation",
        "question_ko": "3/8, 0.125, 9.51 총 3개의 숫자가 있습니다. 모든 수의 합은?",
        "question_en": "There are three numbers: 3/8, 0.125, and 9.51. What is the sum of all three numbers?",
        "answer_ko": "10.01",
        "answer_en": "10.01",
        "solution_abst_ko": "3/8 0.125 [OP_ADD] 9.51 [OP_ADD]",
        "solution_abst_en": "3/8 0.125 [OP_ADD] 9.51 [OP_ADD]",
        "solution_code_ko": "var_a = 0.375\nvar_b = 0.125\nvar_c = var_a + var_b\nvar_d = 9.51\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.375\nvar_b = 0.125\nvar_c = var_a + var_b\nvar_d = 9.51\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "428": {
        "category": "Correspondence",
        "question_ko": "시간당 32개의 장난감을 만드는 기계가 있다. 이 기계가 3시간 동안 만든 장난감을 4개씩 박스에 나누어 담으려면 몇 개의 박스가 필요한지 구하여라.",
        "question_en": "There is a machine that makes 32 toys per hour. Find how many boxes are needed to put 4 of the toys the machine made for 3 hours into each box.",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "32 3 [OP_MUL] 4 [OP_DIV]",
        "solution_abst_en": "32 3 [OP_MUL] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 32\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 32\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "429": {
        "category": "Correspondence",
        "question_ko": "A는 680입니다. A는 B보다 157만큼 큽니다. B는 C보다 185만큼 큽니다. C를 구하시오.",
        "question_en": "A is 680. A is greater than B by 157. B is greater than C by 185. Find what number C is.",
        "answer_ko": "338",
        "answer_en": "338",
        "solution_abst_ko": "680 157 [OP_SUB] 185 [OP_SUB]",
        "solution_abst_en": "680 157 [OP_SUB] 185 [OP_SUB]",
        "solution_code_ko": "var_a = 680\nvar_b = 157\nvar_c = var_a - var_b\nvar_d = 185\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 680\nvar_b = 157\nvar_c = var_a - var_b\nvar_d = 185\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "430": {
        "category": "Correspondence",
        "question_ko": "어느 미대의 입학생 수는 매년 똑같고 여학생이 남학생보다 많다. 올해는 작년과 비교했을 때 여학생이 16명 더 들어와서 올해 입학한 여학생이 입학한 남학생보다 64명 더 많다고 한다. 작년에는 여학생이 남학생에 비해 얼마나 많이 입학했는지 구하시오.",
        "question_en": "The number of students entering an art school is the same every year, and there are more female students than male students. This year, compared to last year, 16 more female students entered the school, and 64 more female students enrolled this year than male students enrolled. Find how many more female students entered school than male students last year.",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "64 16 [OP_SUB] 16 [OP_SUB]",
        "solution_abst_en": "64 16 [OP_SUB] 16 [OP_SUB]",
        "solution_code_ko": "var_a = 64\nvar_b = 16\nvar_c = var_a - var_b\nvar_d = 16\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 64\nvar_b = 16\nvar_c = var_a - var_b\nvar_d = 16\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "431": {
        "category": "Geometry",
        "question_ko": "어느 동전의 지름이 100 밀리미터(㎜)이고, 둘레는 314 밀리미터(㎜) 였습니다. 이 동전의 둘레는 지름의 몇 배 인가요?",
        "question_en": "A coin has a diameter of 100 millimeters (mm) and a circumference of 314 millimeters (mm). How many times bigger is the circumference compared to the diameter of this coin?",
        "answer_ko": "3.14",
        "answer_en": "3.14",
        "solution_abst_ko": "314 100 [OP_DIV]",
        "solution_abst_en": "314 100 [OP_DIV]",
        "solution_code_ko": "var_a = 314\nvar_b = 100\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 314\nvar_b = 100\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "432": {
        "category": "Arithmetic calculation",
        "question_ko": "연필은 10자루씩 7묶음 있습니다. 색연필은 연필보다 3자루 더 많습니다. 색연필은 몇 자루인지 구하시오.",
        "question_en": "There are 7 bundles of 10 pencils each. There are 3 more colored pencils than pencils. Find how many colored pencils there are.",
        "answer_ko": "73",
        "answer_en": "73",
        "solution_abst_ko": "7 10 [OP_MUL] 3 [OP_ADD]",
        "solution_abst_en": "7 10 [OP_MUL] 3 [OP_ADD]",
        "solution_code_ko": "var_a = 7\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 7\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "433": {
        "category": "Correspondence",
        "question_ko": "세 자연수 A, B, C가 있습니다. A를 9로 나누면 몫은 B이고 나머지는 C가 됩니다. 이 식에서 나머지는 몫보다 3 작습니다. A 중 가장 작은 수를 구하시오.",
        "question_en": "There are three natural numbers A, B and C. When A is divided by 9, the quotient is B and the remainder is C. In this expression, the remainder is 3 less than the quotient. Find the smallest number that can fit A.",
        "answer_ko": "27",
        "answer_en": "27",
        "solution_abst_ko": "9 3 [OP_MUL] 0 [OP_ADD]",
        "solution_abst_en": "9 3 [OP_MUL] 0 [OP_ADD]",
        "solution_code_ko": "var_a = 9\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 0\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 0\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "434": {
        "category": "Arithmetic calculation",
        "question_ko": "토끼가 8마리 있었습니다. 다음 날 토끼 5마리가 새로 태어났습니다. 지금 토끼는 모두 몇 마리 있습니까?",
        "question_en": "There were 8 rabbits. The next day, 5 new rabbits were born. How many rabbits are there now in total?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "8 5 [OP_ADD]",
        "solution_abst_en": "8 5 [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 8\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "435": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 4를 빼야 하는데 잘못하여 5를 뺐더니 4가 되었습니다, 어떤 수를 구하시오.",
        "question_en": "I need to subtract 4 from a certain number, but I mistakenly subtracted 5 and it became 4. Find this certain number.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "4 5 [OP_ADD]",
        "solution_abst_en": "4 5 [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "436": {
        "category": "Comparison",
        "question_ko": "정국이는 6에서 3을 나눈 몫 만큼 모았고, 윤기는 4, 유나는 5만큼 모았습니다. 누가 가장 작은 수를 모았습니까?",
        "question_en": "Jungkook collected the quotient of 6 divided by 3, Yoongi collected 4, and Yuna collected 5. Who collected the smallest number?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 윤기 유나 [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_FDIV] 4 5 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Yoongi Yuna [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_FDIV] 4 5 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '윤기'\nvar_c = '유나'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 6\nvar_e = 3\nvar_f = var_d // var_e\nvar_g = 4\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Yoongi'\nvar_c = 'Yuna'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 6\nvar_e = 3\nvar_f = var_d // var_e\nvar_g = 4\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "437": {
        "category": "Comparison",
        "question_ko": "토끼 20마리가 한 줄로 있습니다. 왼쪽에서 13번째와 왼쪽에서 19번째 사이에는 토끼 몇 마리가 있습니까?",
        "question_en": "There are 20 rabbits in a row. How many rabbits are there between the 13th from the left and the 19th from the left?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "19 13 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "19 13 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 19\nvar_b = 13\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 19\nvar_b = 13\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "438": {
        "category": "Arithmetic calculation",
        "question_ko": "12리터(L) 400밀리리터(㎖)의 사과 주스를 규연이와 나은이가 일주일 동안 나누어 마시려고 합니다. 일주일 동안 마신 사과 주스의 양을 비교했을 때 규연이가 나은이보다 2리터(L) 600미터(m)리터(L) 더 마셨다면 규연이가 마신 사과 주스는 몇 리터(L)입니까?",
        "question_en": "Kyu-yeon and Na-eun are going to share 12 liters (L) and 400 milliliters (㎖) of apple juice for a week. If Kyu-yeon drank 2 liters (L) and 600 meters (m) liters (L) more than Na-eun when comparing the amount of apple juice she drank in a week, how many liters (L) of apple juice did Kyu-yeon drink?",
        "answer_ko": "7.5",
        "answer_en": "7.5",
        "solution_abst_ko": "12 400 1000 [OP_DIV] [OP_ADD] 2 600 1000 [OP_DIV] [OP_ADD] [OP_ADD] 2 [OP_DIV]",
        "solution_abst_en": "12 400 1000 [OP_DIV] [OP_ADD] 2 600 1000 [OP_DIV] [OP_ADD] [OP_ADD] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 400\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 2\nvar_g = 600\nvar_h = 1000\nvar_i = var_g / var_h\nvar_j = var_f + var_i\nvar_k = var_e + var_j\nvar_l = 2\nvar_m = var_k / var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))",
        "solution_code_en": "var_a = 12\nvar_b = 400\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 2\nvar_g = 600\nvar_h = 1000\nvar_i = var_g / var_h\nvar_j = var_f + var_i\nvar_k = var_e + var_j\nvar_l = 2\nvar_m = var_k / var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))"
    },
    "439": {
        "category": "Possibility",
        "question_ko": "1부터 9까지의 숫자카드가 있다. 이를 중복을 허용하여 뽑아서 3자리 자연수를 만든다고 할 때, 가능한 숫자는 몇 개인지 구하시오.",
        "question_en": "There are number cards from 1 to 9. If you make a 3-digit natural number by picking it by allowing duplicates, find how many possible numbers there are.",
        "answer_ko": "729",
        "answer_en": "729",
        "solution_abst_ko": "1 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_LEN]",
        "solution_abst_en": "1 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "440": {
        "category": "Geometry",
        "question_ko": "가로 12개씩, 세로 12개씩 크기가 같은 구슬을 빈틈없이 늘어놓아 정사각형을 만들었을 때, 둘레에 놓인 구슬의 개수를 구하시오.",
        "question_en": "When you make a square by arranging 12 beads of the same size, 12 by 12 vertically and horizontally, find the number of beads placed around the perimeter.",
        "answer_ko": "44",
        "answer_en": "44",
        "solution_abst_ko": "12 2 [OP_SUB] 4 [OP_MUL] 4 [OP_ADD]",
        "solution_abst_en": "12 2 [OP_SUB] 4 [OP_MUL] 4 [OP_ADD]",
        "solution_code_ko": "var_a = 12\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 12\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "441": {
        "category": "Arithmetic calculation",
        "question_ko": "원형 트랙을 따라 30미터(m) 간격으로 기둥이 박혀 있다. 원형 트랙의 길이가 1킬로미터(㎞) 200미터(m)라면, 기둥은 모두 몇 개 있는 것입니까?",
        "question_en": "Pillars are embedded at intervals of 30 meters (m) along the circular track. If the length of the circular track is 1 kilometer (km) and 200 meters (m), how many poles are there?",
        "answer_ko": "40",
        "answer_en": "40",
        "solution_abst_ko": "1 1000 [OP_MUL] 200 [OP_ADD] 30 [OP_DIV]",
        "solution_abst_en": "1 1000 [OP_MUL] 200 [OP_ADD] 30 [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 200\nvar_e = var_c + var_d\nvar_f = 30\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 200\nvar_e = var_c + var_d\nvar_f = 30\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "442": {
        "category": "Possibility",
        "question_ko": "아버지, 어머니, 호석이가 서로 다르게 나란히 서는 방법은 모두 몇 가지입니까?",
        "question_en": "How many different ways can father, mother, and Hoseok stand side by side?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 아버지 어머니 호석 [OP_LIST_EOL] [OP_LIST_LEN] 3 [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] father mother Hoseok [OP_LIST_EOL] [OP_LIST_LEN] 3 [OP_PERM]",
        "solution_code_ko": "var_a = '아버지'\nvar_b = '어머니'\nvar_c = '호석'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 3\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nprint(int(var_f))",
        "solution_code_en": "var_a = 'father'\nvar_b = 'mother'\nvar_c = 'Hoseok'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 3\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nprint(int(var_f))"
    },
    "443": {
        "category": "Correspondence",
        "question_ko": "76은 어떤 수에서 29를 빼고 64를 더한 결과입니다. 어떤 수는 얼마입니까?",
        "question_en": "76 is the result of subtracting 29 from and adding 64 to a particular number. What is that particular number?",
        "answer_ko": "41",
        "answer_en": "41",
        "solution_abst_ko": "76 64 [OP_SUB] 29 [OP_ADD]",
        "solution_abst_en": "76 64 [OP_SUB] 29 [OP_ADD]",
        "solution_code_ko": "var_a = 76\nvar_b = 64\nvar_c = var_a - var_b\nvar_d = 29\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 76\nvar_b = 64\nvar_c = var_a - var_b\nvar_d = 29\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "444": {
        "category": "Correspondence",
        "question_ko": "승현이가 수연이에게 피자 2쪽을 주었더니 승연이가 가진 피자가 수연이가 가진 피자보다 5쪽 많았다. 피자를 주기 전에는 몇 쪽 더 많았는지 구하시오.",
        "question_en": "Seung-hyeon gave Su-yeon 2 pieces of pizza, and Seung-hyeon had 5 more pieces of pizza than Su-yeon had. Find how many more pieces Seung-hyeon had before giving them.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "5 2 [OP_ADD] 2 [OP_ADD]",
        "solution_abst_en": "5 2 [OP_ADD] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "445": {
        "category": "Arithmetic calculation",
        "question_ko": "2부터 56까지의 두 자리 수의 수를 구하세요.",
        "question_en": "Find the two-digit number from 2 to 56.",
        "answer_ko": "47",
        "answer_en": "47",
        "solution_abst_ko": "10 56 1 [OP_LIST_ARANGE] [OP_LIST_LEN]",
        "solution_abst_en": "10 56 1 [OP_LIST_ARANGE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 10\nvar_b = 56\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = len(list_a)\nprint(int(var_d))",
        "solution_code_en": "var_a = 10\nvar_b = 56\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = len(list_a)\nprint(int(var_d))"
    },
    "446": {
        "category": "Correspondence",
        "question_ko": "십의 자리에서 숫자 A567을 버림하면 2560이 됩니다. A는 무엇입니까?",
        "question_en": "Rounding down the number A567 to the nearest tens gives 2560. What is A?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "A567 [OP_GEN_POSSIBLE_LIST] 2560 [OP_LIST_MORE_EQUAL] 2560 10 [OP_ADD] [OP_LIST_LESS] A567 A [OP_LIST_FIND_UNK]",
        "solution_abst_en": "A567 [OP_GEN_POSSIBLE_LIST] 2560 [OP_LIST_MORE_EQUAL] 2560 10 [OP_ADD] [OP_LIST_LESS] A567 A [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = 'A567'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 2560\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 2560\nvar_d = 10\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = 'A567'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))",
        "solution_code_en": "var_a = 'A567'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 2560\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 2560\nvar_d = 10\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = 'A567'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))"
    },
    "447": {
        "category": "Geometry",
        "question_ko": "길이가 18센티미터(㎝)인 종이 테이프 12장을 겹치는 부분의 길이가 같도록 풀로 붙여서 둥근 고리 모양을 만들었습니다. 이 둥근 고리 모양의 둘레의 길이가 210센티미터(㎝)라면, 겹쳐진 부분의 길이는 몇 밀리미터(㎜)입니까?",
        "question_en": "You made a round loop by gluing twelve sheets of paper tape that are each 18 centimeters (cm) long. If they are overlapped by the same length and the shape has a perimeter of 210 centimeters (cm), how many millimeters (mm) are the overlapped parts?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "18 12 [OP_MUL] 210 [OP_SUB] 12 [OP_DIV] 10 [OP_MUL]",
        "solution_abst_en": "18 12 [OP_MUL] 210 [OP_SUB] 12 [OP_DIV] 10 [OP_MUL]",
        "solution_code_ko": "var_a = 18\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 210\nvar_e = var_c - var_d\nvar_f = 12\nvar_g = var_e / var_f\nvar_h = 10\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 18\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 210\nvar_e = var_c - var_d\nvar_f = 12\nvar_g = var_e / var_f\nvar_h = 10\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "448": {
        "category": "Correspondence",
        "question_ko": "48에서 어떤 수를 빼고 4를 곱한 뒤 26을 빼고 2로 나눈 수가 37입니다. 어떤 수를 구하시오.",
        "question_en": "Subtract a number from 48, multiply it by 4, subtract 26, and divide it by 2. Then, the result is 37. Find the number.",
        "answer_ko": "23",
        "answer_en": "23",
        "solution_abst_ko": "48 37 2 [OP_MUL] 26 [OP_ADD] 4 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "48 37 2 [OP_MUL] 26 [OP_ADD] 4 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 48\nvar_b = 37\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = 26\nvar_f = var_d + var_e\nvar_g = 4\nvar_h = var_f / var_g\nvar_i = var_a - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 48\nvar_b = 37\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = 26\nvar_f = var_d + var_e\nvar_g = 4\nvar_h = var_f / var_g\nvar_i = var_a - var_h\nprint(int(var_i))"
    },
    "449": {
        "category": "Comparison",
        "question_ko": "70과 68중 어떤 수가 더 큽니까?",
        "question_en": "Which number is greater, 70 or 68?",
        "answer_ko": "70",
        "answer_en": "70",
        "solution_abst_ko": "[OP_LIST_SOL] 70 68 [OP_LIST_EOL] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 70 68 [OP_LIST_EOL] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 70\nvar_b = 68\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[-var_c]\nprint(int(var_d))",
        "solution_code_en": "var_a = 70\nvar_b = 68\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[-var_c]\nprint(int(var_d))"
    },
    "450": {
        "category": "Arithmetic calculation",
        "question_ko": "농장에 오이가 6개, 토마토가 8개 있습니다. 또 사과가 2개, 바나나가 4개 있습니다. 농장에 있는 야채 수에서 과일의 수를 뺀 값을 구하시오",
        "question_en": "There are 6 cucumbers and 8 tomatoes on the farm. There are also 2 apples and 4 bananas. Find the number of vegetables on the farm minus the number of fruits.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "6 8 [OP_ADD] 2 4 [OP_ADD] [OP_SUB]",
        "solution_abst_en": "6 8 [OP_ADD] 2 4 [OP_ADD] [OP_SUB]",
        "solution_code_ko": "var_a = 6\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = 4\nvar_f = var_d + var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 6\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = 4\nvar_f = var_d + var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "451": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 3을 더했더니 6이 되었습니다. 어떤 수에 5를 더하면 얼마입니까?",
        "question_en": "When you add 3 to a number, you get 6. What number is it when you add 5 to the number?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "6 3 [OP_SUB] 5 [OP_ADD]",
        "solution_abst_en": "6 3 [OP_SUB] 5 [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "452": {
        "category": "Comparison",
        "question_ko": "보겸이네 집에서 하늘이네 집까지의 거리는 3킬로미터(㎞)보다 150미터(m) 더 멀고, 성주네 집까지의 거리는 3096미터(m)입니다. 하늘이와 성주 두 친구 중 보겸이와 더 멀리 사는 친구는 누구입니까?",
        "question_en": "The distance from Bogyeom's house to Haneul's house is 150 meters (m) farther than 3 kilometers (km), and the distance to Seongju's house is 3096 meters (m). Of the two friends, Haneul and Seongju, who lives farther away from Bogyeom?",
        "answer_ko": "하늘",
        "answer_en": "Haneul",
        "solution_abst_ko": "[OP_LIST_SOL] 하늘 성주 [OP_LIST_EOL] [OP_LIST_SOL] 3 1000 [OP_MUL] 150 [OP_ADD] 3096 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Haneul Seongju [OP_LIST_EOL] [OP_LIST_SOL] 3 1000 [OP_MUL] 150 [OP_ADD] 3096 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '하늘'\nvar_b = '성주'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 150\nvar_g = var_e + var_f\nvar_h = 3096\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Haneul'\nvar_b = 'Seongju'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 150\nvar_g = var_e + var_f\nvar_h = 3096\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "453": {
        "category": "Comparison",
        "question_ko": "키가 작은 사람부터 순서대로 9명이 한 줄로 서 있습니다. 호석이는 앞에서부터 3번째에 서 있고, 유나는 호석이로부터 2번째 앞에 서 있습니다. 키가 큰 사람부터 순서대로 다시 줄을 서면 유나는 앞에서부터 몇 번째에 서게 됩니까?",
        "question_en": "Nine people stand in a line in ascending order according to their heights. Hoseok is third from the front, and Yuna is 2 position before Hoseok. If you line them up again in descending order, in what position will Yuna be? Answer in ordinal number.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "9 3 [OP_SUB] 2 [OP_ADD] 1 [OP_ADD]",
        "solution_abst_en": "9 3 [OP_SUB] 2 [OP_ADD] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 9\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c + var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 9\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c + var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "454": {
        "category": "Comparison",
        "question_ko": "한변의 길이가 7센티미터(㎝)인 정오각형과 한 변의 길이가 6센티미터(㎝)인 정육각형이 있다. 어떤 도형의 둘레가 더 깁니까?",
        "question_en": "There is a regular-pentagon with a length of 7 centimeters (cm) on one side and a regular-hexagon with a length of 6 centimeters (cm) on one side. Which shape has the greater perimeter?",
        "answer_ko": "정육각형",
        "answer_en": "regular-hexagon",
        "solution_abst_ko": "[OP_LIST_SOL] 정육각형 정오각형 [OP_LIST_EOL] [OP_LIST_SOL] 6 6 [OP_MUL] 7 5 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] regular-hexagon regular-pentagon [OP_LIST_EOL] [OP_LIST_SOL] 6 6 [OP_MUL] 7 5 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정육각형'\nvar_b = '정오각형'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 6\nvar_e = var_c * var_d\nvar_f = 7\nvar_g = 5\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'regular-hexagon'\nvar_b = 'regular-pentagon'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 6\nvar_e = var_c * var_d\nvar_f = 7\nvar_g = 5\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "455": {
        "category": "Correspondence",
        "question_ko": "어떤 소수를 12 로 나누어야 할 것을 잘못하여 곱했더니 84.6 이 되었습니다. 바르게 계산하면 얼마인지 구해보시오.",
        "question_en": "When I wrongly multiplied a number by 12 that should actually be divided by 12, I got 84.6. Find out how much it is if you calculate it correctly.",
        "answer_ko": "0.59",
        "answer_en": "0.59",
        "solution_abst_ko": "84.6 12 [OP_DIV] 12 [OP_DIV]",
        "solution_abst_en": "84.6 12 [OP_DIV] 12 [OP_DIV]",
        "solution_code_ko": "var_a = 84.6\nvar_b = 12\nvar_c = var_a / var_b\nvar_d = 12\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 84.6\nvar_b = 12\nvar_c = var_a / var_b\nvar_d = 12\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "456": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 엘리베이터가 지상 120미터(m)에서 출발하여, 한 번도 멈추지 않고 초속 4미터(m)의 속도로 내려올 때, 출발한 지 몇 초 후에 지상 20미터(m)가 되는지 구하시오.",
        "question_en": "If an elevator starts at 120 meters (m) above the ground and descends at a speed of 4 meters (m) per second without stopping, find how many seconds after departure it will reach 20 meters (m) above the ground.",
        "answer_ko": "25",
        "answer_en": "25",
        "solution_abst_ko": "120 20 [OP_SUB] 4 [OP_DIV]",
        "solution_abst_en": "120 20 [OP_SUB] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 120\nvar_b = 20\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 120\nvar_b = 20\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "457": {
        "category": "Arithmetic calculation",
        "question_ko": "오늘 닭이 알을 30개 낳았으며 어제는 19개 낳았다. 총 몇개의 알을 낳았는가?",
        "question_en": "The chicken laid 30 eggs today and 19 eggs yesterday. How many eggs did it lay in total?",
        "answer_ko": "49",
        "answer_en": "49",
        "solution_abst_ko": "30 19 [OP_ADD]",
        "solution_abst_en": "30 19 [OP_ADD]",
        "solution_code_ko": "var_a = 30\nvar_b = 19\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 30\nvar_b = 19\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "458": {
        "category": "Correspondence",
        "question_ko": "서울초등학교에서 우유를 학생들에게 똑같이 나눠주는데 8개 반에게 나눠야 할 것을 6개 반에만 나누어 주었더니 반마다 124개를 주고 4개가 남았다. 정상적으로 나누어준다면 몇 개의 우유가 남는지 구하시오.",
        "question_en": "At Seoul Elementary School, milk is distributed equally to the students, but when milk was distributed to 6 classes that should have been distributed to 8 classes, 124 packs were given to each class and 4 packs left over. Calculate how many milks are left if divided normally.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "124 6 [OP_MUL] 4 [OP_ADD] 8 [OP_MOD]",
        "solution_abst_en": "124 6 [OP_MUL] 4 [OP_ADD] 8 [OP_MOD]",
        "solution_code_ko": "var_a = 124\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e % var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 124\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e % var_f\nprint(int(var_g))"
    },
    "459": {
        "category": "Possibility",
        "question_ko": "1, 4, 0을 두 번씩 사용하여 만들 수 있는 여섯 자리 수 중에서 가장 큰 수에서 가장 작은 수를 뺀 값은 얼마입니까?",
        "question_en": "What is the largest minus the smallest six-digit number that can be formed using 1, 4, and 0 twice?",
        "answer_ko": "340956",
        "answer_en": "340956",
        "solution_abst_ko": "[OP_LIST_SOL] 1 1 4 4 0 0 [OP_LIST_EOL] 6 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 1 1 4 4 0 0 [OP_LIST_EOL] 6 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 1\nvar_b = 1\nvar_c = 4\nvar_d = 4\nvar_e = 0\nvar_f = 0\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 6\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_i = list_c[-var_h]\nvar_j = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_k = list_d[var_j-1]\nvar_l = var_i - var_k\nprint(int(var_l))",
        "solution_code_en": "var_a = 1\nvar_b = 1\nvar_c = 4\nvar_d = 4\nvar_e = 0\nvar_f = 0\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 6\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_i = list_c[-var_h]\nvar_j = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_k = list_d[var_j-1]\nvar_l = var_i - var_k\nprint(int(var_l))"
    },
    "460": {
        "category": "Correspondence",
        "question_ko": "10을 어떤 수에서 나누었더니 결과가 6이 나왔습니다. 15를 어떤 수에서 뺀 결과를 정확히 구하시오.",
        "question_en": "If you divide a number by 10, the result is 6. Find the exact result of subtracting 15 from the number.",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "6 10 [OP_MUL] 15 [OP_SUB]",
        "solution_abst_en": "6 10 [OP_MUL] 15 [OP_SUB]",
        "solution_code_ko": "var_a = 6\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 15\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 15\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "461": {
        "category": "Arithmetic calculation",
        "question_ko": "민혁이가 기현이의 수학 시험 점수를 물어보자 기현이는 반올림하여 십의 자리까지 나타내면 90이라고 답하였습니다. 기현이의 수학 점수로 가능한 가장 큰 수는 무엇입니까?",
        "question_en": "When Minhyuk asked Kihyun's math test score, Kihyun answered it would be 90 if he rounded it off to 10 digits. What is the biggest number possible with Kihyun's math score?",
        "answer_ko": "94",
        "answer_en": "94",
        "solution_abst_ko": "[OP_LIST_SOL] 9 A [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 90 5 [OP_ADD] [OP_LIST_LESS] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 9 A [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 90 5 [OP_ADD] [OP_LIST_LESS] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 9\nvar_b = 'A'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c=\"\"\nfor i in list_a:\n    i = str(i)\n    var_c = var_c + i\nans_dict = dict()\nvar_c = str(var_c)\nlist_b = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_c):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_c\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_c) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_b.append(new_elem)\nvar_d = 90\nvar_e = 5\nvar_f = var_d + var_e\nlist_c = []\nfor i in list_b:\n    if i < var_f:\n        list_c.append(i)\nvar_g = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_h = list_d[-var_g]\nprint(int(var_h))",
        "solution_code_en": "var_a = 9\nvar_b = 'A'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c=\"\"\nfor i in list_a:\n    i = str(i)\n    var_c = var_c + i\nans_dict = dict()\nvar_c = str(var_c)\nlist_b = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_c):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_c\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_c) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_b.append(new_elem)\nvar_d = 90\nvar_e = 5\nvar_f = var_d + var_e\nlist_c = []\nfor i in list_b:\n    if i < var_f:\n        list_c.append(i)\nvar_g = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_h = list_d[-var_g]\nprint(int(var_h))"
    },
    "462": {
        "category": "Possibility",
        "question_ko": "자연수 6, 3이 그려진 자석을 하나는 십의 자리에, 하나는 일의 자리에 놓을 수 있습니다. 만들 수 있는 가장 큰 수는 무엇입니까?",
        "question_en": "You can place a magnet with the natural numbers 6 and 3 on it, one in the tens place and one in the ones place. What is the largest number you can make?",
        "answer_ko": "63",
        "answer_en": "63",
        "solution_abst_ko": "[OP_LIST_SOL] 6 3 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 6 3 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 6\nvar_b = 3\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_e = list_c[-var_d]\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 3\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_e = list_c[-var_d]\nprint(int(var_e))"
    },
    "463": {
        "category": "Possibility",
        "question_ko": "두 자리 수 중 0, 6, 3으로 만들 수 있는 것은 몇 가지입니까? 단, 십의 자리와 일의 자리의 숫자는 달라야 합니다.",
        "question_en": "How many two-digit numbers can be made with 0, 6, and 3? Note that the tens and ones places must be different.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 6 0 3 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 6 0 3 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 6\nvar_b = 0\nvar_c = 3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 0\nvar_c = 3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "464": {
        "category": "Correspondence",
        "question_ko": "한 상자에 32개씩 3상자에 들어 있는 당근을 한 바구니에 4개씩 다시 담으려고 합니다. 당근을 담는 데 필요한 바구니는 모두 몇 개입니까?",
        "question_en": "There are 3 boxes of carrots which contains 32 of them each, and you are going to put 4 of these carrots in each basket. How many baskets do you need to put carrots in?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "32 3 [OP_MUL] 4 [OP_DIV]",
        "solution_abst_en": "32 3 [OP_MUL] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 32\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 32\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "465": {
        "category": "Arithmetic calculation",
        "question_ko": "상자에 배추 3포기와 무 2개가 들어 있는 상자가 있습니다. 상자 안에 채소는 몇 개 있습니까?",
        "question_en": "There is a box with 3 cabbages and 2 radishes. How many vegetables are in the box?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "3 2 [OP_ADD]",
        "solution_abst_en": "3 2 [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "466": {
        "category": "Arithmetic calculation",
        "question_ko": "한 개의 무게가 0.36킬로그램(㎏)인 공 30개가 상자 안에 들어있습니다. 공이 들어있는 상자의 무게를 재었더니 11.26킬로그램(㎏)이었다면 공이 들어있지 않은 상자는 몇 킬로그램(㎏)인지 구하세요.",
        "question_en": "One pear weighs 0.36 kilograms (kg). When a basket contains 30 pears, the weight of the entire basket is 11.26 kilograms (kg). Find the weight in kilograms (kg) of the empty basket.",
        "answer_ko": "0.46",
        "answer_en": "0.46",
        "solution_abst_ko": "11.26 0.36 30 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "11.26 0.36 30 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 11.26\nvar_b = 0.36\nvar_c = 30\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 11.26\nvar_b = 0.36\nvar_c = 30\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "467": {
        "category": "Arithmetic calculation",
        "question_ko": "주머니에 파란 구슬은 노란 구슬보다 2개 적게 들어있습니다. 노란 구슬과 파란 구슬 개수의 합이 240이라면 노란 구슬의 개수는 몇 개인지 구하세요.",
        "question_en": "The bag contains 2 fewer blue marbles than yellow marbles. If the sum of the yellow and blue marbles is 240, how many yellow marbles are there?",
        "answer_ko": "121",
        "answer_en": "121",
        "solution_abst_ko": "240 2 [OP_SUB] 2 [OP_DIV] 2 [OP_ADD]",
        "solution_abst_en": "240 2 [OP_SUB] 2 [OP_DIV] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 240\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 240\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "468": {
        "category": "Arithmetic calculation",
        "question_ko": "현일이는 자전거를 타고 1분에 4.25미터(m)의 속도로 1시간 동안 움직였다. 그 이후에 같은 속도로 29.75미터(m)만큼 움직였다면 현일이는 자전거를 몇 분동안 탔는지 구하시오.",
        "question_en": "Hyeonil rode a bicycle and moved for an hour at a speed of 4.25 meters (m) per minute. After that, if he moved 29.75 meters (m) at the same speed, find how many minutes Hyunil rode the bicycle.",
        "answer_ko": "67",
        "answer_en": "67",
        "solution_abst_ko": "29.75 4.25 [OP_DIV] 1 60 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "29.75 4.25 [OP_DIV] 1 60 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 29.75\nvar_b = 4.25\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = 60\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 29.75\nvar_b = 4.25\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = 60\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "469": {
        "category": "Possibility",
        "question_ko": "75의 약수를 모두 한번씩 적으면 숫자 5를 모두 몇 번 적어야 하는지 구하시오.",
        "question_en": "If all divisors of 75 are written once, how many times the number 5 must be written?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "75 [OP_LIST_GET_DIVISOR] [OP_LIST2NUM] [OP_NUM2LIST] 5 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "75 [OP_LIST_GET_DIVISOR] [OP_LIST2NUM] [OP_NUM2LIST] 5 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 75\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b=\"\"\nfor i in list_a:\n    i = str(i)\n    var_b = var_b + i\nlist_b = []\nvar_b = int(var_b)\nwhile var_b//10 > 0:\n    list_b.append(var_b%10)\n    var_b = var_b//10\nlist_b.append(var_b%10)\nlist_b = list_b[::-1]\nvar_c = 5\nvar_d = 0\nvar_c = int(var_c)\nfor i in list_b:\n    i = int(i)\n    if i == var_c:\n        var_d = var_d + 1\nprint(int(var_d))",
        "solution_code_en": "var_a = 75\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b=\"\"\nfor i in list_a:\n    i = str(i)\n    var_b = var_b + i\nlist_b = []\nvar_b = int(var_b)\nwhile var_b//10 > 0:\n    list_b.append(var_b%10)\n    var_b = var_b//10\nlist_b.append(var_b%10)\nlist_b = list_b[::-1]\nvar_c = 5\nvar_d = 0\nvar_c = int(var_c)\nfor i in list_b:\n    i = int(i)\n    if i == var_c:\n        var_d = var_d + 1\nprint(int(var_d))"
    },
    "470": {
        "category": "Geometry",
        "question_ko": "두 대각선의 길이가 각각 9센티미터(㎝), 14센티미터(㎝)인 마름모 모양의 머리핀이 있습니다. 이 머리핀의 넓이는 얼마입니까?",
        "question_en": "\nThere is a rhombic hairpin with two diagonals measuring 9 centimeters (cm) and 14 centimeters (cm), respectively. How wide is this hairpin?",
        "answer_ko": "63",
        "answer_en": "63",
        "solution_abst_ko": "9 14 [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "9 14 [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 9\nvar_b = 14\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 14\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "471": {
        "category": "Arithmetic calculation",
        "question_ko": "2180개의 귤이 있습니다. 이것을 200개짜리와 150개짜리 상자에 담아 모두 12상자가 되도록 하였더니 30개의 귤이 남았습니다. 200개짜리 상자는 몇 상자입니까?",
        "question_en": "There are 2180 tangerines. You distribute them in boxes of 200 and 150 to have organized 12 boxes in total, and then 30 tangerines are left. How many boxes of 200 are there?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "2180 30 [OP_SUB] 150 12 [OP_MUL] [OP_SUB] 200 150 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "2180 30 [OP_SUB] 150 12 [OP_MUL] [OP_SUB] 200 150 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 2180\nvar_b = 30\nvar_c = var_a - var_b\nvar_d = 150\nvar_e = 12\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 200\nvar_i = 150\nvar_j = var_h - var_i\nvar_k = var_g / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 2180\nvar_b = 30\nvar_c = var_a - var_b\nvar_d = 150\nvar_e = 12\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 200\nvar_i = 150\nvar_j = var_h - var_i\nvar_k = var_g / var_j\nprint(int(var_k))"
    },
    "472": {
        "category": "Comparison",
        "question_ko": "9/10리터(L)의 우유가 있습니다. 수연은 전체의 1/3을, 현우는 전체의 4/9를 마셨습니다. 우유를 더 많이 마신 수연과 현우 중 누구입니까?",
        "question_en": "There are 9/10 liters (L) of milk. Suyeon drank 1/3 of the total, and Hyunwoo 4/9 of the total. Who drank more milk, Suyeon or Hyunwoo?",
        "answer_ko": "현우",
        "answer_en": "Hyunwoo",
        "solution_abst_ko": "[OP_LIST_SOL] 수연 현우 [OP_LIST_EOL] [OP_LIST_SOL] 1 3 [OP_DIV] 4 9 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Suyeon Hyunwoo [OP_LIST_EOL] [OP_LIST_SOL] 1 3 [OP_DIV] 4 9 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '수연'\nvar_b = '현우'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = 4\nvar_g = 9\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Suyeon'\nvar_b = 'Hyunwoo'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = 4\nvar_g = 9\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "473": {
        "category": "Correspondence",
        "question_ko": "6A5+B03=748입니다. B는 얼마인가요?",
        "question_en": "6A5+B03=748. How much is B?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "6A5+B03=748 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "6A5+B03=748 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '6A5+B03=748'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '6A5+B03=748'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "474": {
        "category": "Arithmetic calculation",
        "question_ko": "40이상 80 이하인 수 중에서 8의 배수에 해당되는 수는 모두 몇 개입니까?",
        "question_en": "How many of the numbers between 40 and 80 are multiples of 8?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "40 80 1 [OP_LIST_ARANGE] 8 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "40 80 1 [OP_LIST_ARANGE] 8 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 40\nvar_b = 80\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 8\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 40\nvar_b = 80\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 8\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "475": {
        "category": "Possibility",
        "question_ko": "정국이는 서로 다른 과일을 구매해서 지민과 윤기에게 선물하려고 합니다. 과일 가게에서 판매하는 과일이 사과, 복숭아, 배라면 선물할 수 있는 경우의 수는 모두 몇 가지입니까?",
        "question_en": "Jungkook wants to buy two different fruits and give them to Jimin and Yoongi as a present. If the fruits sold at the fruit store are apples, peaches, and pears, in how many ways can you gift them?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 복숭아 배 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] apples peaches pears [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '복숭아'\nvar_c = '배'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nprint(int(var_f))",
        "solution_code_en": "var_a = 'apples'\nvar_b = 'peaches'\nvar_c = 'pears'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nprint(int(var_f))"
    },
    "476": {
        "category": "Comparison",
        "question_ko": "결승선에 태형, 민주, 상민, 윤정, 유정이 차례로 들어갔습니다. 마지막에 들어온 사람은 누구입니까?",
        "question_en": "Taehyung, Minju, Sangmin, Yoonjeong, and Yoojung crossed the finish line in turn. Who came in last?",
        "answer_ko": "유정",
        "answer_en": "Yoojung",
        "solution_abst_ko": "[OP_LIST_SOL] 태형 민주 상민 윤정 유정 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Taehyung Minju Sangmin Yoonjeong Yoojung [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '태형'\nvar_b = '민주'\nvar_c = '상민'\nvar_d = '윤정'\nvar_e = '유정'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = list_a[var_f-1]\nprint(var_g)",
        "solution_code_en": "var_a = 'Taehyung'\nvar_b = 'Minju'\nvar_c = 'Sangmin'\nvar_d = 'Yoonjeong'\nvar_e = 'Yoojung'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = list_a[var_f-1]\nprint(var_g)"
    },
    "477": {
        "category": "Possibility",
        "question_ko": "각 자리 수의 합이 15가 되는 네 자리 수를 만드려고 합니다. 총 몇 가지의 수를 만들 수 있습니까?",
        "question_en": "You want to create a four-digit number where the sum of each digit is 15. How many numbers can you make in total?",
        "answer_ko": "519",
        "answer_en": "519",
        "solution_abst_ko": "1000 9999 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] 15 [OP_LIST_LESS_EQUAL] 15 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "1000 9999 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] 15 [OP_LIST_LESS_EQUAL] 15 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_b=[]\nfor i in list_a:\n    var_d = 0\n    i = int(i)\n    while i//10 > 0:\n        var_d = var_d + i%10\n        i = i//10\n    var_d = var_d + i%10\n    list_b.append(var_d)\nvar_e = 15\nlist_c = []\nfor i in list_b:\n    if i <= var_e:\n        list_c.append(i)\nvar_f = 15\nlist_d = []\nfor i in list_c:\n    if i >= var_f:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_b=[]\nfor i in list_a:\n    var_d = 0\n    i = int(i)\n    while i//10 > 0:\n        var_d = var_d + i%10\n        i = i//10\n    var_d = var_d + i%10\n    list_b.append(var_d)\nvar_e = 15\nlist_c = []\nfor i in list_b:\n    if i <= var_e:\n        list_c.append(i)\nvar_f = 15\nlist_d = []\nfor i in list_c:\n    if i >= var_f:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))"
    },
    "478": {
        "category": "Arithmetic calculation",
        "question_ko": "하이브리드 자동차는 두 종류 이상의 동력 장치를 가진 자동차입니다. 재호네 가족은 하이브리드 자동차를 타고 집에서 120킬로미터(㎞) 떨어진 이모 댁에 1시간 50분 만에 도착했습니다. 처음에는 전기만 사용하여 달렸고, 나중에는 1시간 10분 동안 휘발유만 사용하여 달렸습니다. 이 자동차는 40.8킬로미터(㎞)를 가는데 6리터(L)의 휘발유가 필요하고 재호네 가족이 이모 댁에 가는 데 휘발유를 14리터(L) 사용했다면, 이 자동차가 전기를 사용하여 1분 동안 달린 거리는 몇 킬로미터(㎞)입니까?",
        "question_en": "A hybrid car has two or more types of power units. Jaeho's family rode a hybrid car and arrived at his aunt's house, which is 120 kilometers (km) away, in an hour and 50 minutes. At first, they used electricity only, and later on gasoline only for an hour and ten minutes. This car needs 6 liters of gasoline to go 40.8 kilometers (km), and if Jaeho's family used 14 liters of gasoline to go to his aunt's house, how many kilometers (km) is the distance that this car used only electricity for 1 minute?",
        "answer_ko": "0.62",
        "answer_en": "0.62",
        "solution_abst_ko": "120 40.8 6 [OP_DIV] 14 [OP_MUL] [OP_SUB] 1 60 [OP_MUL] 50 [OP_ADD] 1 60 [OP_MUL] 10 [OP_ADD] [OP_SUB] [OP_DIV]",
        "solution_abst_en": "120 40.8 6 [OP_DIV] 14 [OP_MUL] [OP_SUB] 1 60 [OP_MUL] 50 [OP_ADD] 1 60 [OP_MUL] 10 [OP_ADD] [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 120\nvar_b = 40.8\nvar_c = 6\nvar_d = var_b / var_c\nvar_e = 14\nvar_f = var_d * var_e\nvar_g = var_a - var_f\nvar_h = 1\nvar_i = 60\nvar_j = var_h * var_i\nvar_k = 50\nvar_l = var_j + var_k\nvar_m = 1\nvar_n = 60\nvar_o = var_m * var_n\nvar_p = 10\nvar_q = var_o + var_p\nvar_r = var_l - var_q\nvar_s = var_g / var_r\nprint('{:.2f}'.format(round(var_s+1e-10,2)))",
        "solution_code_en": "var_a = 120\nvar_b = 40.8\nvar_c = 6\nvar_d = var_b / var_c\nvar_e = 14\nvar_f = var_d * var_e\nvar_g = var_a - var_f\nvar_h = 1\nvar_i = 60\nvar_j = var_h * var_i\nvar_k = 50\nvar_l = var_j + var_k\nvar_m = 1\nvar_n = 60\nvar_o = var_m * var_n\nvar_p = 10\nvar_q = var_o + var_p\nvar_r = var_l - var_q\nvar_s = var_g / var_r\nprint('{:.2f}'.format(round(var_s+1e-10,2)))"
    },
    "479": {
        "category": "Correspondence",
        "question_ko": "397는 어떤 수보다 236작은 수 이다. 어떤 수보다 496 작은 수는 얼마인가?",
        "question_en": "397 is 236 lesser than a certain number. What is the value of a number that is 496 lesser than this certain number?",
        "answer_ko": "137",
        "answer_en": "137",
        "solution_abst_ko": "397 236 [OP_ADD] 496 [OP_SUB]",
        "solution_abst_en": "397 236 [OP_ADD] 496 [OP_SUB]",
        "solution_code_ko": "var_a = 397\nvar_b = 236\nvar_c = var_a + var_b\nvar_d = 496\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 397\nvar_b = 236\nvar_c = var_a + var_b\nvar_d = 496\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "480": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중에서 가장 큰 수를 가장 작은 수로 나눈 몫은 얼마입니까?",
        "question_en": "There are three numbers 10, 11 and 12. What is the quotient of the largest number divided by the smallest number?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_FDIV]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_FDIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e // var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e // var_g\nprint(int(var_h))"
    },
    "481": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 5를 빼고 3으로 나누어주었습니다. 결과가 4가 되기 위한 어떤 수를 구하시오.",
        "question_en": "Subtract 5 from a number and divide by 3. Find the number for the result to be 4.",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "4 3 [OP_MUL] 5 [OP_ADD]",
        "solution_abst_en": "4 3 [OP_MUL] 5 [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 4\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "482": {
        "category": "Arithmetic calculation",
        "question_ko": "서로 다른 7개의 상자에 초콜릿이 각각 2개, 3개, 3개, 2개, 1개, 2개, 1개씩 있습니다. 초콜릿이 2개 들어있는 상자는 몇 개입니까?",
        "question_en": "There are 7 different boxes with 2, 3, 3, 2, 1, 2, 1 chocolates, respectively. How many boxes contain 2 chocolates?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 2 3 3 2 1 2 1 [OP_LIST_EOL] 2 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "[OP_LIST_SOL] 2 3 3 2 1 2 1 [OP_LIST_EOL] 2 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = 3\nvar_d = 2\nvar_e = 1\nvar_f = 2\nvar_g = 1\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h = 2\nvar_i = 0\nvar_h = int(var_h)\nfor i in list_a:\n    i = int(i)\n    if i == var_h:\n        var_i = var_i + 1\nprint(int(var_i))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = 3\nvar_d = 2\nvar_e = 1\nvar_f = 2\nvar_g = 1\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h = 2\nvar_i = 0\nvar_h = int(var_h)\nfor i in list_a:\n    i = int(i)\n    if i == var_h:\n        var_i = var_i + 1\nprint(int(var_i))"
    },
    "483": {
        "category": "Geometry",
        "question_ko": "철사 12/25미터(m)를 모두 사용하여 가장 큰 정사각형을 한 개 만들었습니다. 이 정사각형의 한 변의 길이는 몇 미터(m)입니까?",
        "question_en": "I used all 12/25 meters (m) of wire to make one of the largest squares. What is the side length of this square in meters (m)?",
        "answer_ko": "0.12",
        "answer_en": "0.12",
        "solution_abst_ko": "12/25 4 [OP_DIV]",
        "solution_abst_en": "12/25 4 [OP_DIV]",
        "solution_code_ko": "var_a = 0.48\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 0.48\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "484": {
        "category": "Arithmetic calculation",
        "question_ko": "자전거 한 대를 30 분 동안 빌리는 요금은 4000 원이라고 합니다. 6 명이 똑같이 돈을 내어 자전거 4 대를 3 시간 동안 빌려 타려면 한 사람이 얼마씩 내야 합니까?",
        "question_en": "The fee for renting a bicycle for 30 minutes is 4,000 won. How much does one person get to pay when renting 4 bikes for 3 hours with 6 people paying equally?",
        "answer_ko": "16000",
        "answer_en": "16000",
        "solution_abst_ko": "3 60 [OP_MUL] 30 [OP_DIV] 4000 [OP_MUL] 4 [OP_MUL] 6 [OP_DIV]",
        "solution_abst_en": "3 60 [OP_MUL] 30 [OP_DIV] 4000 [OP_MUL] 4 [OP_MUL] 6 [OP_DIV]",
        "solution_code_ko": "var_a = 3\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 30\nvar_e = var_c / var_d\nvar_f = 4000\nvar_g = var_e * var_f\nvar_h = 4\nvar_i = var_g * var_h\nvar_j = 6\nvar_k = var_i / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 3\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 30\nvar_e = var_c / var_d\nvar_f = 4000\nvar_g = var_e * var_f\nvar_h = 4\nvar_i = var_g * var_h\nvar_j = 6\nvar_k = var_i / var_j\nprint(int(var_k))"
    },
    "485": {
        "category": "Possibility",
        "question_ko": "길 가는 사람에게 1부터 4 중 아무 숫자를 두 개 선택하게 시켰을 때, 둘 다 짝수를 선택하거나 하나만 짝수를 선택하는 상황은 몇 가지가 있습니까?",
        "question_en": "When you ask a passerby to pick random two numbers from 1 to 4, what is the number of cases where they pick two even numbers or only one even number?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "2 2 [OP_COMB] 2 1 [OP_COMB] 2 1 [OP_COMB] [OP_MUL] [OP_ADD]",
        "solution_abst_en": "2 2 [OP_COMB] 2 1 [OP_COMB] 2 1 [OP_COMB] [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nvar_d = 2\nvar_e = 1\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f / (i+1)\nvar_g = 2\nvar_h = 1\nvar_i = 1\nvar_g = int(var_g)\nvar_h = int(var_h)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i * (var_g-i)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i / (i+1)\nvar_j = var_f * var_i\nvar_k = var_c + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 2\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nvar_d = 2\nvar_e = 1\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f / (i+1)\nvar_g = 2\nvar_h = 1\nvar_i = 1\nvar_g = int(var_g)\nvar_h = int(var_h)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i * (var_g-i)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i / (i+1)\nvar_j = var_f * var_i\nvar_k = var_c + var_j\nprint(int(var_k))"
    },
    "486": {
        "category": "Correspondence",
        "question_ko": "15명의 사람들 중 여자는 7명이다. 48개의 짐을 남자들만 나른다고 할 때, 모두 똑같은 짐을 나눠들면 한 명이 몇 개의 짐을 들면 되는지 구하시오.",
        "question_en": "Of the 15 people, 7 are women. If only men carry 48 loads, find how many loads each person can carry if they all share the same load.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "48 15 7 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "48 15 7 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 48\nvar_b = 15\nvar_c = 7\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 48\nvar_b = 15\nvar_c = 7\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "487": {
        "category": "Arithmetic calculation",
        "question_ko": "선미는 중간고사에서 국어는 75점, 수학은 85점, 과학은 90점, 영어는 65점을 받았다. 선미의 중간고사 평균보다 위인 과목은 몇 개인가?",
        "question_en": "Sunmi scored 75 points in Korean, 85 points in math, 90 points in science, and 65 points in English in the midterm exam. In how many subjects was Sunmi above the midterm average?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 75 85 90 65 [OP_LIST_EOL] [OP_LIST_MEAN] [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 75 85 90 65 [OP_LIST_EOL] [OP_LIST_MEAN] [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 75\nvar_b = 85\nvar_c = 90\nvar_d = 65\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_e = sum(list_a)/len(list_a)\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 75\nvar_b = 85\nvar_c = 90\nvar_d = 65\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_e = sum(list_a)/len(list_a)\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "488": {
        "category": "Comparison",
        "question_ko": "영빈이와 예찬이는 새총으로 깡통 쓰러트리기 놀이를 하고 있습니다. 영빈이는 25발을 쏴서 19개를 쓰러트렸고, 예찬이는 16발을 쏴서 10개를 쓰러트렸습니다. 두 사람 중 성공률이 더 높은 사람은 누구입니까?",
        "question_en": "Youngbin and Yechan are playing knocking down cans with a slingshot. Youngbin fired 25 shots and knocked down 19, and Yechan shot 16 and knocked down 10. Which of the two has a higher success rate?",
        "answer_ko": "영빈",
        "answer_en": "Youngbin",
        "solution_abst_ko": "[OP_LIST_SOL] 영빈 예찬 [OP_LIST_EOL] [OP_LIST_SOL] 19 25 [OP_DIV] 10 16 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Youngbin Yechan [OP_LIST_EOL] [OP_LIST_SOL] 19 25 [OP_DIV] 10 16 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '영빈'\nvar_b = '예찬'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 19\nvar_d = 25\nvar_e = var_c / var_d\nvar_f = 10\nvar_g = 16\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Youngbin'\nvar_b = 'Yechan'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 19\nvar_d = 25\nvar_e = var_c / var_d\nvar_f = 10\nvar_g = 16\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "489": {
        "category": "Correspondence",
        "question_ko": "59에 대해 8로 나눈 몫은 A, 나머지는 3입니다. A의 값은 무엇일까요?",
        "question_en": "The quotient of 59 divided by 8 is A and the remainder is 3. What is the value of A?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "59 3 [OP_SUB] 8 [OP_DIV]",
        "solution_abst_en": "59 3 [OP_SUB] 8 [OP_DIV]",
        "solution_code_ko": "var_a = 59\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 59\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "490": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 4로 나누어야 할 것을 잘못하여 어떤 수에 4를 더했더니 40이 되었습니다. 바르게 계산하면 얼마인지 구해보시오.",
        "question_en": "I made a mistake in dividing a number by 4, and instead added by 4 to get 40. Find the correctly calculated value.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "40 4 [OP_SUB] 4 [OP_DIV]",
        "solution_abst_en": "40 4 [OP_SUB] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 40\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 40\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "491": {
        "category": "Correspondence",
        "question_ko": "서로 다른 두 수 A, B가 있습니다. 두 자리 수끼리의 뺄셈식 A5-2A=B7에서 A와 B의 합을 구하시오.",
        "question_en": "There are two different numbers A and B. Find the sum of A and B in the two-digit subtraction formula, A5-2A=B7.",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "A5-2A=B7 A [OP_DIGIT_UNK_SOLVER] A5-2A=B7 B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_abst_en": "A5-2A=B7 A [OP_DIGIT_UNK_SOLVER] A5-2A=B7 B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_code_ko": "var_a = 'A5-2A=B7'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 'A5-2A=B7'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 'A5-2A=B7'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 'A5-2A=B7'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "492": {
        "category": "Possibility",
        "question_ko": "A, B, C, D 4개의 부분을 빨강, 노랑, 파랑, 초록 4가지 색으로 칠하려고 한다. 각 부분에 서로 다른 색을 칠하는 경우의 수를 구하시오.",
        "question_en": "I want to paint the 4 parts A, B, C,and D with 4 colors red, yellow, blue and green. Find the number of ways to color each part with a different color.",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "4 4 [OP_PERM]",
        "solution_abst_en": "4 4 [OP_PERM]",
        "solution_code_ko": "var_a = 4\nvar_b = 4\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 4\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))"
    },
    "493": {
        "category": "Comparison",
        "question_ko": "동국이는 하루에 물을 5번 마시고 한 번 마실 때 0.2리터(L)씩 마십니다. 윤지는 하루에 물을 6번 마시고 한 번 마실 때 0.3리터(L)씩 마십니다. 희진이는 하루에 물을 4번 마시고 한 번 마실 때 500밀리리터(㎖)씩 마십니다. 하루에 물을 가장 많이 마시는 사람은 누구입니까?",
        "question_en": "Dongguk drinks water 5 times a day and drinks 0.2 liters (L) each time. Yoonji drinks water 6 times a day and drinks 0.3 liters (L) per drink. Heejin drinks water 4 times a day and drinks 500 milliliters (ml) per drink. Who drinks the most water per day?",
        "answer_ko": "희진",
        "answer_en": "Heejin",
        "solution_abst_ko": "[OP_LIST_SOL] 동국 윤지 희진 [OP_LIST_EOL] [OP_LIST_SOL] 5 0.2 1000 [OP_MUL] [OP_MUL] 6 0.3 1000 [OP_MUL] [OP_MUL] 4 500 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Dongguk Yoonji Heejin [OP_LIST_EOL] [OP_LIST_SOL] 5 0.2 1000 [OP_MUL] [OP_MUL] 6 0.3 1000 [OP_MUL] [OP_MUL] 4 500 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '동국'\nvar_b = '윤지'\nvar_c = '희진'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 5\nvar_e = 0.2\nvar_f = 1000\nvar_g = var_e * var_f\nvar_h = var_d * var_g\nvar_i = 6\nvar_j = 0.3\nvar_k = 1000\nvar_l = var_j * var_k\nvar_m = var_i * var_l\nvar_n = 4\nvar_o = 500\nvar_p = var_n * var_o\nlist_b= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nlist_b.reverse()\nvar_q = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_r = list_c[-var_q]\nvar_s = list_b.index(var_r)+1\nvar_t = list_a[var_s-1]\nprint(var_t)",
        "solution_code_en": "var_a = 'Dongguk'\nvar_b = 'Yoonji'\nvar_c = 'Heejin'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 5\nvar_e = 0.2\nvar_f = 1000\nvar_g = var_e * var_f\nvar_h = var_d * var_g\nvar_i = 6\nvar_j = 0.3\nvar_k = 1000\nvar_l = var_j * var_k\nvar_m = var_i * var_l\nvar_n = 4\nvar_o = 500\nvar_p = var_n * var_o\nlist_b= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nlist_b.reverse()\nvar_q = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_r = list_c[-var_q]\nvar_s = list_b.index(var_r)+1\nvar_t = list_a[var_s-1]\nprint(var_t)"
    },
    "494": {
        "category": "Geometry",
        "question_ko": "가로의 길이가 81/4센티미터(㎝)이고, 세로의 길이가 148/9센티미터(㎝)인 직사각형 모양의 액자가 있습니다. 이 액자의 넓이를 구하시오.",
        "question_en": "There is a rectangular frame with a width of 81/4 centimeters (cm) and a depth of 148/9 centimeters (cm). Find the area of this frame.",
        "answer_ko": "333",
        "answer_en": "333",
        "solution_abst_ko": "81/4 148/9 [OP_MUL]",
        "solution_abst_en": "81/4 148/9 [OP_MUL]",
        "solution_code_ko": "var_a = 20.25\nvar_b = 16.444444444444443\nvar_c = var_a * var_b\nprint(int(eval('{:.2f}'.format(round(var_c+1e-10,2)))))",
        "solution_code_en": "var_a = 20.25\nvar_b = 16.444444444444443\nvar_c = var_a * var_b\nprint(int(eval('{:.2f}'.format(round(var_c+1e-10,2)))))"
    },
    "495": {
        "category": "Possibility",
        "question_ko": "4, 5, 8, 9를 모두 사용한 네 자리 숫자를 만들고자 합니다. 세 번째로 작은 수를 만들었는데, 중간에 두 숫자의 위치가 바뀌어 4958이 되었습니다. 바뀐 두 숫자의 합은 얼마입니까?",
        "question_en": "You want to create a four-digit number using all 4, 5, 8, and 9. When you made the third smallest number, two numbers in the middle were swapped, resulting in 4958. Find the sum of the number created and the number changed.",
        "answer_ko": "9817",
        "answer_en": "9817",
        "solution_abst_ko": "[OP_LIST_SOL] 4 5 8 9 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 3 [OP_LIST_MIN] 4958 [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 4 5 8 9 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 3 [OP_LIST_MIN] 4958 [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 5\nvar_c = 8\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = 4958\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 4\nvar_b = 5\nvar_c = 8\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = 4958\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "496": {
        "category": "Correspondence",
        "question_ko": "지우는 마트에서 과자를 사는데 가진 돈의 절반과 2000원을 사용하고, 초콜릿을 사는데 남은 돈의 절반을 사용하고, 음료수와 물을 사는데 각각 2000원과 1000원을 썼더니, 남은 돈이 없었다고 할 때 지우가 처음 가진 돈은 얼마입니까?",
        "question_en": "Ji-woo used half of his money and 2,000 won to buy snacks at the mart. Then, he used half of the remaining money to buy chocolate, and 2,000 won and 1,000 won to buy drinks and water. How much money does Ji-woo have at first if he has no money left?",
        "answer_ko": "16000",
        "answer_en": "16000",
        "solution_abst_ko": "0 2000 [OP_ADD] 1000 [OP_ADD] 2 [OP_MUL] 2000 [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "0 2000 [OP_ADD] 1000 [OP_ADD] 2 [OP_MUL] 2000 [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 0\nvar_b = 2000\nvar_c = var_a + var_b\nvar_d = 1000\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = 2000\nvar_i = var_g + var_h\nvar_j = 2\nvar_k = var_i * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 0\nvar_b = 2000\nvar_c = var_a + var_b\nvar_d = 1000\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = 2000\nvar_i = var_g + var_h\nvar_j = 2\nvar_k = var_i * var_j\nprint(int(var_k))"
    },
    "497": {
        "category": "Correspondence",
        "question_ko": "어부가 낚시줄 하나당 3마리의 물고기를 낚는다고 한다. 226개의 낚시줄 중에서 3개가 끊어져서 버렸습니다. 어부가 잡은 물고기는 모두 몇마리입니까?",
        "question_en": "A fisherman catches three fish per one fishing line. Out of 226 fishing lines, 3 were broken and discarded. How many fish did the fisherman catch?",
        "answer_ko": "669",
        "answer_en": "669",
        "solution_abst_ko": "226 3 [OP_SUB] 3 [OP_MUL]",
        "solution_abst_en": "226 3 [OP_SUB] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 226\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 226\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "498": {
        "category": "Geometry",
        "question_ko": "지민이는 50에서 200 사이의 수 중 무작위로 4개를 골랐는데, 그 중 3개가 각각 75, 80, 120이었다. 나머지 하나가 몇이 되어야 네 수를 합해서 사각형의 내각의 합과 같겠는가?",
        "question_en": "Jimin randomly picked 4 numbers between 50 and 200, and 3 of them were 75, 80, and 120, respectively. What should be the other number so that the sum of them is equal to interior angles of the quadrilateral?",
        "answer_ko": "85",
        "answer_en": "85",
        "solution_abst_ko": "360 75 [OP_SUB] 80 [OP_SUB] 120 [OP_SUB]",
        "solution_abst_en": "360 75 [OP_SUB] 80 [OP_SUB] 120 [OP_SUB]",
        "solution_code_ko": "var_a = 360\nvar_b = 75\nvar_c = var_a - var_b\nvar_d = 80\nvar_e = var_c - var_d\nvar_f = 120\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 360\nvar_b = 75\nvar_c = var_a - var_b\nvar_d = 80\nvar_e = var_c - var_d\nvar_f = 120\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "499": {
        "category": "Geometry",
        "question_ko": "빗변과 빗변이 아닌 한 변이 각각 5와 3인 직각삼각형의 나머지 한 변의 길이는 얼마입니까?",
        "question_en": "What is the length of the other side of a right triangle with hypotenuse and non-hypotenuse sides equal to 5 and 3 respectively?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "5 2 [OP_POW] 3 2 [OP_POW] [OP_SUB] 1/2 [OP_POW]",
        "solution_abst_en": "5 2 [OP_POW] 3 2 [OP_POW] [OP_SUB] 1/2 [OP_POW]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 3\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c - var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 3\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c - var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))"
    },
    "500": {
        "category": "Correspondence",
        "question_ko": "8을 더하고 3을 곱하면 어떤 수는 36이 됩니다. 어떤 수를 구하시오.",
        "question_en": "When you add 8 and multiply by 3 to this number it becomes 36. Find the number.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "36 3 [OP_DIV] 8 [OP_SUB]",
        "solution_abst_en": "36 3 [OP_DIV] 8 [OP_SUB]",
        "solution_code_ko": "var_a = 36\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 8\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 36\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 8\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "501": {
        "category": "Possibility",
        "question_ko": "6, 7, 8, 9, 1가 적혀있는 5장의 카드 중 중복을 허락하여 2가지 카드를 고르려고 합니다. 가능한 경우의 수는 모두 몇 가지 인가요?",
        "question_en": "Of the five cards with the numbers 6, 7, 8, 9, and 1 written on them, we want to select two cards allowing duplicates. How many possible cases are there?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "[OP_LIST_SOL] 6 7 8 9 1 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] 6 7 8 9 1 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB]",
        "solution_code_ko": "var_a = 6\nvar_b = 7\nvar_c = 8\nvar_d = 9\nvar_e = 1\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = 2\nvar_l = 1\nvar_j = int(var_j)\nvar_k = int(var_k)\nfor i, elem in enumerate(range(var_k)):\n    var_l = var_l * (var_j-i)\nfor i, elem in enumerate(range(var_k)):\n    var_l = var_l / (i+1)\nprint(int(var_l))",
        "solution_code_en": "var_a = 6\nvar_b = 7\nvar_c = 8\nvar_d = 9\nvar_e = 1\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = 2\nvar_l = 1\nvar_j = int(var_j)\nvar_k = int(var_k)\nfor i, elem in enumerate(range(var_k)):\n    var_l = var_l * (var_j-i)\nfor i, elem in enumerate(range(var_k)):\n    var_l = var_l / (i+1)\nprint(int(var_l))"
    },
    "502": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 25로 나누어야 할 것을 잘못하여 1.87을 곱하였더니 231.88이 되었습니다. 바르게 계산했을때 몫이 얼마일지 구하시오.",
        "question_en": "I multiplied a particular number by 1.87, when I should have divided that particular number by 25 and the result of that erroneous calculation was 231.88. Find what the quotient will be when calculated correctly. ",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "231.88 1.87 [OP_DIV] 25 [OP_FDIV]",
        "solution_abst_en": "231.88 1.87 [OP_DIV] 25 [OP_FDIV]",
        "solution_code_ko": "var_a = 231.88\nvar_b = 1.87\nvar_c = var_a / var_b\nvar_d = 25\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 231.88\nvar_b = 1.87\nvar_c = var_a / var_b\nvar_d = 25\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "503": {
        "category": "Comparison",
        "question_ko": "남준이가 가진 구슬 개수는 은지보다 적고, 태형이보다도 적습니다. 은지는 태형이보다도 더 적은 구슬을 갖고 있습니다. 이들 중 구슬이 제일 많은 사람은 누구입니까?",
        "question_en": "Namjoon has fewer marbles than Eunji and also has fewer marbles than Taehyung. Eunji has fewer marbles than Taehyung. Who has the most marbles among them?",
        "answer_ko": "태형",
        "answer_en": "Taehyung",
        "solution_abst_ko": "[OP_LIST_SOL] 남준 은지 태형 [OP_LIST_EOL] [OP_LIST_SOL] 남준 은지 < 남준 태형 < 은지 태형 < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Namjoon Eunji Taehyung [OP_LIST_EOL] [OP_LIST_SOL] Namjoon Eunji < Namjoon Taehyung < Eunji Taehyung < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '남준'\nvar_b = '은지'\nvar_c = '태형'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '남준'\nvar_e = '은지'\nvar_f = '<'\nvar_g = '남준'\nvar_h = '태형'\nvar_i = '<'\nvar_j = '은지'\nvar_k = '태형'\nvar_l = '<'\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_m = 1\nvar_n = list_c[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'Namjoon'\nvar_b = 'Eunji'\nvar_c = 'Taehyung'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'Namjoon'\nvar_e = 'Eunji'\nvar_f = '<'\nvar_g = 'Namjoon'\nvar_h = 'Taehyung'\nvar_i = '<'\nvar_j = 'Eunji'\nvar_k = 'Taehyung'\nvar_l = '<'\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_m = 1\nvar_n = list_c[var_m-1]\nprint(var_n)"
    },
    "504": {
        "category": "Possibility",
        "question_ko": "세 자리 자연수 중 5, 7, 8이 모두 들어가있는 수는 몇 개 입니까?",
        "question_en": "How many three-digit numbers contain all 5, 7, and 8?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 5 7 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 5 7 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 5\nvar_b = 7\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 7\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "505": {
        "category": "Geometry",
        "question_ko": "둘레의 길이가 24센티미터(㎝)인 정사각형 6개로 만든 정육면체의 겉넓이를 구하시오.",
        "question_en": "Find the surface area of a cube made up of 6 squares with a perimeter of 24 centimeters (cm).",
        "answer_ko": "216",
        "answer_en": "216",
        "solution_abst_ko": "24 4 [OP_DIV] 24 4 [OP_DIV] [OP_MUL] 6 [OP_MUL]",
        "solution_abst_en": "24 4 [OP_DIV] 24 4 [OP_DIV] [OP_MUL] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 24\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 24\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = var_c * var_f\nvar_h = 6\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 24\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 24\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = var_c * var_f\nvar_h = 6\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "506": {
        "category": "Geometry",
        "question_ko": "가로의 길이가 세로의 길이보다 2 센티미터(㎝)만큼 긴 직사각형의 둘레의 길이가 16 센티미터(㎝)일 때, 가로의 길이는 얼마인가?",
        "question_en": "If a perimeter of a rectangle whose width is 2 centimeters (cm) longer than its length is 16 centimeters (cm), what is its width?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "16 2 [OP_DIV] 2 [OP_SUB] 2 [OP_DIV] 2 [OP_ADD]",
        "solution_abst_en": "16 2 [OP_DIV] 2 [OP_SUB] 2 [OP_DIV] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 16\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 16\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "507": {
        "category": "Comparison",
        "question_ko": "저울 위에 100그램(g)짜리 추를 올려놓으며 물감과 크레파스의 무게를 비교하려고 합니다. 물감은 추 3개의 무게와 같고, 크레파스는 추 5개의 무게와 같습니다. 물감과 크레파스 중 더 가벼운 것을 구하시오.",
        "question_en": "You are trying to compare the weight of paint and crayons by placing a weight of 100 grams (g) on the scale. Paint is equal to the weight of 3 weights, and crayons are equal to the weight of 5 weights. Get the lighter one between paint and crayons.",
        "answer_ko": "물감",
        "answer_en": "paint",
        "solution_abst_ko": "[OP_LIST_SOL] 물감 크레파스 [OP_LIST_EOL] [OP_LIST_SOL] 100 3 [OP_MUL] 100 5 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] paint crayons [OP_LIST_EOL] [OP_LIST_SOL] 100 3 [OP_MUL] 100 5 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '물감'\nvar_b = '크레파스'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 100\nvar_d = 3\nvar_e = var_c * var_d\nvar_f = 100\nvar_g = 5\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'paint'\nvar_b = 'crayons'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 100\nvar_d = 3\nvar_e = var_c * var_d\nvar_f = 100\nvar_g = 5\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "508": {
        "category": "Geometry",
        "question_ko": "밑변이 9.51센티미터(㎝), 높이가 4.8센티미터(㎝)인 평행사변형의 넓이는 얼마입니까?",
        "question_en": "What is the area of a parallelogram with a base of 9.51 centimeters (cm) and a height of 4.8 centimeters (cm)?",
        "answer_ko": "45.65",
        "answer_en": "45.65",
        "solution_abst_ko": "9.51 4.8 [OP_MUL]",
        "solution_abst_en": "9.51 4.8 [OP_MUL]",
        "solution_code_ko": "var_a = 9.51\nvar_b = 4.8\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 9.51\nvar_b = 4.8\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "509": {
        "category": "Comparison",
        "question_ko": "어느 문구점에 하트 무늬 엽서는 별 무늬 엽서보다 많고, 별 무늬 엽서는 꽃 무늬 엽서보다 많다고 합니다. 이 문구점에 가장 많은 엽서는 어떤 무늬입니까?",
        "question_en": "It is said that at a stationery store, there are more heart patterned postcards than star patterned postcards, and more star patterned postcards than flower patterned postcards. Which pattern has the most postcards in this stationery store?",
        "answer_ko": "하트",
        "answer_en": "heart",
        "solution_abst_ko": "[OP_LIST_SOL] 하트 별 꽃 [OP_LIST_EOL] [OP_LIST_SOL] 하트 별 > 별 꽃 > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] heart star flower [OP_LIST_EOL] [OP_LIST_SOL] heart star > star flower > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '하트'\nvar_b = '별'\nvar_c = '꽃'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '하트'\nvar_e = '별'\nvar_f = '>'\nvar_g = '별'\nvar_h = '꽃'\nvar_i = '>'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(var_k)",
        "solution_code_en": "var_a = 'heart'\nvar_b = 'star'\nvar_c = 'flower'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'heart'\nvar_e = 'star'\nvar_f = '>'\nvar_g = 'star'\nvar_h = 'flower'\nvar_i = '>'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(var_k)"
    },
    "510": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중에서 2번째로 큰 수와 가장 작은 수로 나눈 값은 얼마입니까?",
        "question_en": "There are three numbers 10, 11 and 12. What is the value of second largest number divided by the smallest number?",
        "answer_ko": "1.10",
        "answer_en": "1.1",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 2 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_DIV]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 2 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e / var_g\nprint('{:.2f}'.format(round(var_h+1e-10,2)))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e / var_g\nprint('{:.2f}'.format(round(var_h+1e-10,2)))"
    },
    "511": {
        "category": "Arithmetic calculation",
        "question_ko": "병에 물이 가득 들어있었습니다. 유승이는 병에 들어있는 물의 2/5를 마시고 병의 무게를 재어 보니 144그램(g)이었습니다. 잠시 후 한솔이가 남은 물의 2/3을 마시고 다시 병의 무게를 재어 보니 96그램(g)이었습니다. 모든 물을 마시고 병만의 무게를 재면 몇 그램(g)이 되겠습니까?",
        "question_en": "The bottle was full of water. Yooseung drank 2/5 of the water in the bottle and weighed the bottle and found it to be 144 grams (g). After a while, Hansol drank 2/3 of the remaining water and weighed the bottle again and it was 96 grams (g). How many grams (g) would you get if you drank all the water and weighed only the bottle?",
        "answer_ko": "72",
        "answer_en": "72",
        "solution_abst_ko": "144 144 96 [OP_SUB] 1 2/5 [OP_SUB] [OP_DIV] 2/3 [OP_DIV] 1 2/5 [OP_SUB] [OP_MUL] [OP_SUB]",
        "solution_abst_en": "144 144 96 [OP_SUB] 1 2/5 [OP_SUB] [OP_DIV] 2/3 [OP_DIV] 1 2/5 [OP_SUB] [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 144\nvar_b = 144\nvar_c = 96\nvar_d = var_b - var_c\nvar_e = 1\nvar_f = 0.4\nvar_g = var_e - var_f\nvar_h = var_d / var_g\nvar_i = 0.6666666666666666\nvar_j = var_h / var_i\nvar_k = 1\nvar_l = 0.4\nvar_m = var_k - var_l\nvar_n = var_j * var_m\nvar_o = var_a - var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 144\nvar_b = 144\nvar_c = 96\nvar_d = var_b - var_c\nvar_e = 1\nvar_f = 0.4\nvar_g = var_e - var_f\nvar_h = var_d / var_g\nvar_i = 0.6666666666666666\nvar_j = var_h / var_i\nvar_k = 1\nvar_l = 0.4\nvar_m = var_k - var_l\nvar_n = var_j * var_m\nvar_o = var_a - var_n\nprint(int(var_o))"
    },
    "512": {
        "category": "Geometry",
        "question_ko": "밑변의 길이가 8센티미터(㎝)인 삼각형 두 개를 이어 붙여 평행사변형을 만들었더니 넓이가 78.88제곱센티미터(㎠)이었습니다. 이 평행사변형의 높이는 몇 센티미터(㎝)입니까?",
        "question_en": "Two triangles with a base length of 8 centimeters (cm) are joined to form a parallelogram. The area is 78.88 square cm (cm2). What is the height in centimeters (cm) of this parallelogram?",
        "answer_ko": "9.86",
        "answer_en": "9.86",
        "solution_abst_ko": "78.88 8 [OP_DIV]",
        "solution_abst_en": "78.88 8 [OP_DIV]",
        "solution_code_ko": "var_a = 78.88\nvar_b = 8\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 78.88\nvar_b = 8\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "513": {
        "category": "Correspondence",
        "question_ko": "네 자리 수 22AB는 3으로 나누었을 때 나머지가 2이고, 5의 배수이다. 가능한 A는 모두 몇 개인가?",
        "question_en": "The four-digit number 22AB, when divided by 3, has a remainder of 2, which is a multiple of 5. How many possible A's are there?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "22AB [OP_GEN_POSSIBLE_LIST] 3 2 [OP_LIST_DIVIDE_AND_REMAIN] 5 [OP_LIST_DIVISIBLE] 22AB A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_abst_en": "22AB [OP_GEN_POSSIBLE_LIST] 3 2 [OP_LIST_DIVIDE_AND_REMAIN] 5 [OP_LIST_DIVISIBLE] 22AB A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '22AB'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 3\nvar_c = 2\nlist_b = [] \nvar_b = int(var_b)\nvar_c = int(var_c)\nif var_c < 0:\n    var_c = var_c + var_b\nfor i in list_a:\n    i = int(i)\n    if i%var_b == var_c:\n        list_b.append(i)\nvar_d = 5\nlist_c = []\nvar_d = int(var_d)\nfor i in list_b:\n    i = int(i)\n    if i % var_d == 0:\n        list_c.append(i)\nvar_e = '22AB'\nvar_f = 'A'\nvar_e = str(var_e)\nvar_f = str(var_f)\nunk_idx = var_e.index(var_f)\nlist_d = []\nfor elem in list_c:\n    elem = str(elem)\n    list_d.append(int(elem[unk_idx]))\nlist_d = list(set(list_d))\nvar_g = len(list_d)\nprint(int(var_g))",
        "solution_code_en": "var_a = '22AB'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 3\nvar_c = 2\nlist_b = [] \nvar_b = int(var_b)\nvar_c = int(var_c)\nif var_c < 0:\n    var_c = var_c + var_b\nfor i in list_a:\n    i = int(i)\n    if i%var_b == var_c:\n        list_b.append(i)\nvar_d = 5\nlist_c = []\nvar_d = int(var_d)\nfor i in list_b:\n    i = int(i)\n    if i % var_d == 0:\n        list_c.append(i)\nvar_e = '22AB'\nvar_f = 'A'\nvar_e = str(var_e)\nvar_f = str(var_f)\nunk_idx = var_e.index(var_f)\nlist_d = []\nfor elem in list_c:\n    elem = str(elem)\n    list_d.append(int(elem[unk_idx]))\nlist_d = list(set(list_d))\nvar_g = len(list_d)\nprint(int(var_g))"
    },
    "514": {
        "category": "Geometry",
        "question_ko": "직사각형의 둘레의 길이가 54 센티미터(㎝)이며, 가로의 길이가 세로의 길이보다 3 센티미터(㎝) 더 길다. 가로의 길이를 구하시오.",
        "question_en": "The perimeter of the rectangle is 54 centimeters (cm), and the horizontal length of the rectangle is 3 centimeters (cm) longer than the vertical length of the rectangle. Find the horizontal length.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "54 2 [OP_DIV] 3 [OP_SUB] 2 [OP_DIV] 3 [OP_ADD]",
        "solution_abst_en": "54 2 [OP_DIV] 3 [OP_SUB] 2 [OP_DIV] 3 [OP_ADD]",
        "solution_code_ko": "var_a = 54\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 3\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 3\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 54\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 3\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 3\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "515": {
        "category": "Arithmetic calculation",
        "question_ko": "길을 따라 석기의 집에서부터 동민이의 집 사이에 있는 전봇대를 세어 보니 모두 20개였습니다. 전봇대와 전봇대 사이의 간격이 25미터(m)라면 석기가 동민이의 집에 갈 때, 몇 미터(m)를 걸어야 합니까? (단, 석기의 집과 동민이의 집 앞에는 전봇대가 없고 각 집에서 처음 전봇대까지의 거리는 25미터(m)입니다.)",
        "question_en": "I counted the telephone poles between Seokgi's house and Dongmin's house along the way, and there were 20 in total. If the distance between telephone poles is 25 meters (m), how many meters (m) must Seokgi walk to Dongmin's house? (However, there are no telephone poles in front of Seokgi’s house and Dongmin’s house, and the distance from each house to the first telephone pole is 25 meters (m).)",
        "answer_ko": "525",
        "answer_en": "525",
        "solution_abst_ko": "20 1 [OP_ADD] 25 [OP_MUL]",
        "solution_abst_en": "20 1 [OP_ADD] 25 [OP_MUL]",
        "solution_code_ko": "var_a = 20\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 25\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 25\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "516": {
        "category": "Arithmetic calculation",
        "question_ko": "상, 하 두 권이 한 세트로 된 책이 있습니다. 이 책을 3세트 사고 21000원을 냈습니다. 상권 한 권의 값이 하권 한 권의 값보다 300원 더 비싸다면 하권 한 권의 값은 얼마입니까?",
        "question_en": "There is a set of two books, volumes one and two. I bought 3 sets of this book and paid 21,000 won. If the price of the first volume is 300 won more than the price of the second volume, how much is the price of the second volume?",
        "answer_ko": "3350",
        "answer_en": "3350",
        "solution_abst_ko": "21000 3 [OP_DIV] 300 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "21000 3 [OP_DIV] 300 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 21000\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 300\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 21000\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 300\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "517": {
        "category": "Comparison",
        "question_ko": "운동화 끈을 지희는 1과 1/5미터(m), 현지는 8/5 미터(m)를 사용했습니다. 누가 운동화 끈을 더 많이 사용했는지 답을 구하세요.",
        "question_en": "Jihee used 1 and 1/5 meters (m) for shoelaces, and Hyunji used 8/5 meters (m). Find the answer to who used more shoelaces.",
        "answer_ko": "현지",
        "answer_en": "Hyunji",
        "solution_abst_ko": "[OP_LIST_SOL] 지희 현지 [OP_LIST_EOL] [OP_LIST_SOL] 1 1/5 [OP_ADD] 8/5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jihee Hyunji [OP_LIST_EOL] [OP_LIST_SOL] 1 1/5 [OP_ADD] 8/5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '지희'\nvar_b = '현지'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1\nvar_d = 0.2\nvar_e = var_c + var_d\nvar_f = 1.6\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Jihee'\nvar_b = 'Hyunji'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1\nvar_d = 0.2\nvar_e = var_c + var_d\nvar_f = 1.6\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "518": {
        "category": "Correspondence",
        "question_ko": "12, 14, 15, 20 중 3으로 나누어 지지 않으며 18보다 작은 수는 무엇인가?",
        "question_en": "Which of 12, 14, 15, and 20 is not divisible by 3 and is less than 18?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "[OP_LIST_SOL] 12 14 15 20 [OP_LIST_EOL] 3 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] 18 [OP_LIST_LESS] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] 12 14 15 20 [OP_LIST_EOL] 3 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] 18 [OP_LIST_LESS] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 12\nvar_b = 14\nvar_c = 15\nvar_d = 20\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = []\nvar_e = int(var_e)\nfor i in list_a:\n    i = int(i)\n    if i % var_e == 0:\n        list_b.append(i)\nlist_c = list(set(list_a) - set(list_b))\nvar_f = 18\nlist_d = []\nfor i in list_c:\n    if i < var_f:\n        list_d.append(i)\nvar_g = 1\nvar_h = list_d[var_g-1]\nprint(int(var_h))",
        "solution_code_en": "var_a = 12\nvar_b = 14\nvar_c = 15\nvar_d = 20\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = []\nvar_e = int(var_e)\nfor i in list_a:\n    i = int(i)\n    if i % var_e == 0:\n        list_b.append(i)\nlist_c = list(set(list_a) - set(list_b))\nvar_f = 18\nlist_d = []\nfor i in list_c:\n    if i < var_f:\n        list_d.append(i)\nvar_g = 1\nvar_h = list_d[var_g-1]\nprint(int(var_h))"
    },
    "519": {
        "category": "Arithmetic calculation",
        "question_ko": "장미가 58송이 있습니다. 장미는 튤립보다 15송이 더 많고, 백합보다 25송이 더 적습니다. 장미, 튤립, 백합 3종류의 꽃은 모두 몇 송이 있습니까?",
        "question_en": "There are 58 roses. The number of roses is 15 more than the number of tulips and 25 less than the number of lilies. How many roses, tulips, and lilies are there in total?",
        "answer_ko": "184",
        "answer_en": "184",
        "solution_abst_ko": "58 58 15 [OP_SUB] [OP_ADD] 58 25 [OP_ADD] [OP_ADD]",
        "solution_abst_en": "58 58 15 [OP_SUB] [OP_ADD] 58 25 [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 58\nvar_b = 58\nvar_c = 15\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 58\nvar_g = 25\nvar_h = var_f + var_g\nvar_i = var_e + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 58\nvar_b = 58\nvar_c = 15\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 58\nvar_g = 25\nvar_h = var_f + var_g\nvar_i = var_e + var_h\nprint(int(var_i))"
    },
    "520": {
        "category": "Geometry",
        "question_ko": "직사각형 모양의 수영장의 넓이가 143.2제곱미터(㎡), 세로가 4미터(m) 일 때, 가로는 몇 미터(m)입니까?",
        "question_en": "If the area of a rectangular swimming pool is 143.2 square meters (m2) and the length is 4 meters (m), how many meters (m) is the width?",
        "answer_ko": "35.80",
        "answer_en": "35.8",
        "solution_abst_ko": "143.2 4 [OP_DIV]",
        "solution_abst_en": "143.2 4 [OP_DIV]",
        "solution_code_ko": "var_a = 143.2\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 143.2\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "521": {
        "category": "Arithmetic calculation",
        "question_ko": "220쪽의 동화책이 있습니다. 이 동화책 한 권은 진우가 일주일 안에 모두 읽으려고 한다면 진우가 하루에 읽어야하는 쪽수는 적어도 얼마인가요?",
        "question_en": "There is a children's book with 220 pages. If Jinwoo wants to read this book in a week, at least how many pages does Jinwoo have to read in a day?",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "220 7 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "220 7 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 220\nvar_b = 7\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))",
        "solution_code_en": "var_a = 220\nvar_b = 7\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))"
    },
    "522": {
        "category": "Geometry",
        "question_ko": "가로가 6미터(m), 세로가 4미터(m)인 널판지가 있습니다. 이 널판지에 가로가 60센티미터(㎝), 세로가 20센티미터(㎝)인 직사각형 모양의 색종이를 빈틈없이 겹치지 않게 붙였습니다. 이때 사용한 색종이는 모두 몇 장입니까?",
        "question_en": "You have a plank that is 6 meters (m) wide and 4 meters (m) long. Rectangular colored paper measuring 60 centimeters (cm) in width and 20 centimeters (cm) in height was attached to this plank without overlapping. How many sheets of colored paper did you use at this time?",
        "answer_ko": "200",
        "answer_en": "200",
        "solution_abst_ko": "6 100 [OP_MUL] 4 100 [OP_MUL] [OP_MUL] 60 20 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "6 100 [OP_MUL] 4 100 [OP_MUL] [OP_MUL] 60 20 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = 100\nvar_f = var_d * var_e\nvar_g = var_c * var_f\nvar_h = 60\nvar_i = 20\nvar_j = var_h * var_i\nvar_k = var_g / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 6\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = 100\nvar_f = var_d * var_e\nvar_g = var_c * var_f\nvar_h = 60\nvar_i = 20\nvar_j = var_h * var_i\nvar_k = var_g / var_j\nprint(int(var_k))"
    },
    "523": {
        "category": "Comparison",
        "question_ko": "3개의 숫자 5, 8, 4 중 가장 큰 숫자는 무엇입니까?",
        "question_en": "Which of the three numbers 5, 8, and 4 is the largest?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "[OP_LIST_SOL] 5 8 4 [OP_LIST_EOL] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 5 8 4 [OP_LIST_EOL] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 5\nvar_b = 8\nvar_c = 4\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 8\nvar_c = 4\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nprint(int(var_e))"
    },
    "524": {
        "category": "Arithmetic calculation",
        "question_ko": "돼지 7마리와 기린 6마리가 있습니다. 기린과 돼지는 모두 몇 마리 있습니까?",
        "question_en": "If there are 7 pigs and 6 giraffes, what is the total number of giraffes and pigs?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "7 6 [OP_ADD]",
        "solution_abst_en": "7 6 [OP_ADD]",
        "solution_code_ko": "var_a = 7\nvar_b = 6\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 7\nvar_b = 6\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "525": {
        "category": "Geometry",
        "question_ko": "한 모서리의 길이가 5㎝인 정육면체 2개를 한 줄로 놓아 1개의 직육면체를 만들었습니다. 만들어진 직육면체의 부피는 몇 세제곱센티미터입니까?",
        "question_en": "Two cubes with one edge 5 cm (cm) long were placed in a line to make one cuboid. What is the volume of the cuboid made in cubic centimeters (cm3)?",
        "answer_ko": "250",
        "answer_en": "250",
        "solution_abst_ko": "5 5 2 [OP_MUL] [OP_MUL] 5 [OP_MUL]",
        "solution_abst_en": "5 5 2 [OP_MUL] [OP_MUL] 5 [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 5\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nvar_f = 5\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 5\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nvar_f = 5\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "526": {
        "category": "Comparison",
        "question_ko": "키가 작은 사람부터 순서대로 9명이 한 줄로 서 있습니다. 호석이가 가장 앞에 서 있습니다. 키가 큰 사람부터 순서대로 다시 줄을 서면 호석이는 앞에서부터 몇 번째에 서게 됩니까?",
        "question_en": "Nine people are standing in a line in order from shortest to tallest. Hoseok stands in the forefront. If you line up again in order from tallest to shortest, what number will Hoseok stand from the front?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "9 1 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "9 1 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 9\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "527": {
        "category": "Arithmetic calculation",
        "question_ko": "올해 아버지는 44살이고 어머니는 42살입니다. 아버지와 어머니의 나이 합이 100살이 될 때, 아버지 나이는 몇 살입니까?",
        "question_en": "My father is 44 years old and my mother is 42 this year. How old is the father when the sum of the ages of the father and mother becomes 100?",
        "answer_ko": "51",
        "answer_en": "51",
        "solution_abst_ko": "44 100 44 42 [OP_ADD] [OP_SUB] 2 [OP_DIV] [OP_ADD]",
        "solution_abst_en": "44 100 44 42 [OP_ADD] [OP_SUB] 2 [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 44\nvar_b = 100\nvar_c = 44\nvar_d = 42\nvar_e = var_c + var_d\nvar_f = var_b - var_e\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = var_a + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 44\nvar_b = 100\nvar_c = 44\nvar_d = 42\nvar_e = var_c + var_d\nvar_f = var_b - var_e\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = var_a + var_h\nprint(int(var_i))"
    },
    "528": {
        "category": "Geometry",
        "question_ko": "크기가 같은 색종이를 가로 12개씩, 세로 12개씩 빈틈없이 늘어놓아 정사각형을 만들었습니다. 둘레에 놓인 색종이는 모두 몇 개일까요?",
        "question_en": "A square was made by arranging pieces of colored paper of the same size, 12 pieces in each width and 12 pieces in each length. How many colored papers are there in the border?",
        "answer_ko": "44",
        "answer_en": "44",
        "solution_abst_ko": "12 2 [OP_SUB] 4 [OP_MUL] 4 [OP_ADD]",
        "solution_abst_en": "12 2 [OP_SUB] 4 [OP_MUL] 4 [OP_ADD]",
        "solution_code_ko": "var_a = 12\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 12\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "529": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 25센티미터(㎝)인 휴지 30개를 6센티미터(㎝)씩 겹쳐서 한 줄로 길게 이어 붙였습니다. 30개를 이어 붙인 휴지 전체 길이는 몇 센티미터(㎝)인지 구해 보시오.",
        "question_en": "Thirty pieces of tissue, each 25 centimeters (cm) long, were overlapped by 6 centimeters (cm) and attached in a long line. Find the total length in centimeters (cm) of 30 pieces of toilet paper attached.",
        "answer_ko": "576",
        "answer_en": "576",
        "solution_abst_ko": "25 25 6 [OP_SUB] 30 1 [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_abst_en": "25 25 6 [OP_SUB] 30 1 [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 25\nvar_b = 25\nvar_c = 6\nvar_d = var_b - var_c\nvar_e = 30\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_a + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 25\nvar_b = 25\nvar_c = 6\nvar_d = var_b - var_c\nvar_e = 30\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_a + var_h\nprint(int(var_i))"
    },
    "530": {
        "category": "Arithmetic calculation",
        "question_ko": "호석이는 (가) 사탕 2개와 (나) 사탕 5개를 가지고 있습니다. 호석이가 가지고 있는 사탕은 모두 몇 개입니까?",
        "question_en": "Hoseok has 2 candies of (A) and 5 candies of (B). How many candies does Hoseok have in all?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "2 5 [OP_ADD]",
        "solution_abst_en": "2 5 [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "531": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 2.5로 나누어야 할 것을 잘못하여 2와 2/5로 나누었더니 15/32가 되었습니다. 바르게 계산하면 얼마입니까?",
        "question_en": "The number was supposed to be divided by 2.5, but it is divided by 2 and 2/5 by mistake, resulting in 15/32. What is the correct answer without mistakes?",
        "answer_ko": "0.45",
        "answer_en": "0.45",
        "solution_abst_ko": "15/32 2 2/5 [OP_ADD] [OP_MUL] 2.5 [OP_DIV]",
        "solution_abst_en": "15/32 2 2/5 [OP_ADD] [OP_MUL] 2.5 [OP_DIV]",
        "solution_code_ko": "var_a = 0.46875\nvar_b = 2\nvar_c = 0.4\nvar_d = var_b + var_c\nvar_e = var_a * var_d\nvar_f = 2.5\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 0.46875\nvar_b = 2\nvar_c = 0.4\nvar_d = var_b + var_c\nvar_e = var_a * var_d\nvar_f = 2.5\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "532": {
        "category": "Comparison",
        "question_ko": "색연필 24개가 있습니다. 빨간색 색연필은 전체의 1/4개 이며, 파란색 색연필은 빨간색 색연필보다 6개 더 많고, 나머지는 노란색 색연필입니다. 어떤 색의 색연필이 가장 많은지 구하시오.",
        "question_en": "There are 24 colored pencils, and red colored pencils makes 1/4 of the total. There are 6 more blue colored pencils than the red colored pencils, and the rest are all yellow colored pencils. Find what color pencils you have the most.",
        "answer_ko": "파란색",
        "answer_en": "blue",
        "solution_abst_ko": "[OP_LIST_SOL] 빨간색 파란색 노란색 [OP_LIST_EOL] [OP_LIST_SOL] 24 1/4 [OP_MUL] 24 1/4 [OP_MUL] 6 [OP_ADD] 24 24 1/4 [OP_MUL] 6 [OP_ADD] [OP_SUB] 24 1/4 [OP_MUL] [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] red blue yellow [OP_LIST_EOL] [OP_LIST_SOL] 24 1/4 [OP_MUL] 24 1/4 [OP_MUL] 6 [OP_ADD] 24 24 1/4 [OP_MUL] 6 [OP_ADD] [OP_SUB] 24 1/4 [OP_MUL] [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '빨간색'\nvar_b = '파란색'\nvar_c = '노란색'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 24\nvar_e = 0.25\nvar_f = var_d * var_e\nvar_g = 24\nvar_h = 0.25\nvar_i = var_g * var_h\nvar_j = 6\nvar_k = var_i + var_j\nvar_l = 24\nvar_m = 24\nvar_n = 0.25\nvar_o = var_m * var_n\nvar_p = 6\nvar_q = var_o + var_p\nvar_r = var_l - var_q\nvar_s = 24\nvar_t = 0.25\nvar_u = var_s * var_t\nvar_v = var_r - var_u\nlist_b= []\nif \"/\" in str(var_v):\n    var_v = eval(str(var_v))\nlist_b.append(var_v)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_w = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_x = list_c[-var_w]\nvar_y = list_b.index(var_x)+1\nvar_z = list_a[var_y-1]\nprint(var_z)",
        "solution_code_en": "var_a = 'red'\nvar_b = 'blue'\nvar_c = 'yellow'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 24\nvar_e = 0.25\nvar_f = var_d * var_e\nvar_g = 24\nvar_h = 0.25\nvar_i = var_g * var_h\nvar_j = 6\nvar_k = var_i + var_j\nvar_l = 24\nvar_m = 24\nvar_n = 0.25\nvar_o = var_m * var_n\nvar_p = 6\nvar_q = var_o + var_p\nvar_r = var_l - var_q\nvar_s = 24\nvar_t = 0.25\nvar_u = var_s * var_t\nvar_v = var_r - var_u\nlist_b= []\nif \"/\" in str(var_v):\n    var_v = eval(str(var_v))\nlist_b.append(var_v)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_w = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_x = list_c[-var_w]\nvar_y = list_b.index(var_x)+1\nvar_z = list_a[var_y-1]\nprint(var_z)"
    },
    "533": {
        "category": "Correspondence",
        "question_ko": "어떤 수의 6/11은 48입니다. 어떤 수의 1/8은 얼마인지 구해 보시오.",
        "question_en": "6/11 of a number is 48. What is 1/8 of the number?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "48 6/11 [OP_DIV] 1/8 [OP_MUL]",
        "solution_abst_en": "48 6/11 [OP_DIV] 1/8 [OP_MUL]",
        "solution_code_ko": "var_a = 48\nvar_b = 0.5454545454545454\nvar_c = var_a / var_b\nvar_d = 0.125\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 48\nvar_b = 0.5454545454545454\nvar_c = var_a / var_b\nvar_d = 0.125\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "534": {
        "category": "Correspondence",
        "question_ko": "7A7을 십의 자리까지 올림하면 730의 값을 얻습니다. A에 알맞은 값을 구하시오.",
        "question_en": "If we round 7A7 up to the tens place, we get a value of 730. Find the right value for A.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "7A7 [OP_GEN_POSSIBLE_LIST] 730 [OP_LIST_LESS_EQUAL] 730 10 [OP_SUB] [OP_LIST_MORE] 7A7 A [OP_LIST_FIND_UNK]",
        "solution_abst_en": "7A7 [OP_GEN_POSSIBLE_LIST] 730 [OP_LIST_LESS_EQUAL] 730 10 [OP_SUB] [OP_LIST_MORE] 7A7 A [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = '7A7'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 730\nlist_b = []\nfor i in list_a:\n    if i <= var_b:\n        list_b.append(i)\nvar_c = 730\nvar_d = 10\nvar_e = var_c - var_d\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = '7A7'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))",
        "solution_code_en": "var_a = '7A7'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 730\nlist_b = []\nfor i in list_a:\n    if i <= var_b:\n        list_b.append(i)\nvar_c = 730\nvar_d = 10\nvar_e = var_c - var_d\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = '7A7'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))"
    },
    "535": {
        "category": "Geometry",
        "question_ko": "가로가 15센티미터(㎝), 세로가 12센티미터(㎝), 높이가 8센티미터(㎝)인 직육면체 모양의 나무토막을 잘라서 만들 수 있는 가장 큰 정육면체의 부피는 몇 세제곱센티미터입니까?",
        "question_en": "What is the volume, in cubic centimeters (cm3), of the largest cube you can make by cutting a rectangular cuboid block of wood that is 15 centimeters (cm) wide, 12 centimeters (cm) long, and 8 centimeters (cm) high?",
        "answer_ko": "512",
        "answer_en": "512",
        "solution_abst_ko": "[OP_LIST_SOL] 15 12 8 [OP_LIST_EOL] 1 [OP_LIST_MIN] 3 [OP_POW]",
        "solution_abst_en": "[OP_LIST_SOL] 15 12 8 [OP_LIST_EOL] 1 [OP_LIST_MIN] 3 [OP_POW]",
        "solution_code_ko": "var_a = 15\nvar_b = 12\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nvar_f = 3\nvar_g = var_e ** var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 15\nvar_b = 12\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nvar_f = 3\nvar_g = var_e ** var_f\nprint(int(var_g))"
    },
    "536": {
        "category": "Correspondence",
        "question_ko": "어떤 수는 159에서 45를 더하고 3으로 나눈 뒤 32를 더하여 나온 수 입니다. 이 수를 12로 나눈 값을 구하시오.",
        "question_en": "There is a number obtained by adding 45 to 159, dividing this by 3, and adding 32. Divide this number by 12 to find the value.",
        "answer_ko": "8.33",
        "answer_en": "8.33",
        "solution_abst_ko": "159 45 [OP_ADD] 3 [OP_DIV] 32 [OP_ADD] 12 [OP_DIV]",
        "solution_abst_en": "159 45 [OP_ADD] 3 [OP_DIV] 32 [OP_ADD] 12 [OP_DIV]",
        "solution_code_ko": "var_a = 159\nvar_b = 45\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = 32\nvar_g = var_e + var_f\nvar_h = 12\nvar_i = var_g / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 159\nvar_b = 45\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = 32\nvar_g = var_e + var_f\nvar_h = 12\nvar_i = var_g / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "537": {
        "category": "Geometry",
        "question_ko": "십이각형의 한 꼭짓점에서 그을 수 있는 대각선의 개수를 구하시오.",
        "question_en": "Find the number of diagonals that can be drawn from one vertex of a dodecagon.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "12 3 [OP_SUB]",
        "solution_abst_en": "12 3 [OP_SUB]",
        "solution_code_ko": "var_a = 12\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 12\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "538": {
        "category": "Arithmetic calculation",
        "question_ko": "28을 10.02으로 나누었을 때의 나머지를 구하시오.",
        "question_en": "Find the remainder when 28 is divided by 10.02.",
        "answer_ko": "7.96",
        "answer_en": "7.96",
        "solution_abst_ko": "28 10.02 [OP_MOD]",
        "solution_abst_en": "28 10.02 [OP_MOD]",
        "solution_code_ko": "var_a = 28\nvar_b = 10.02\nvar_c = var_a % var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 28\nvar_b = 10.02\nvar_c = var_a % var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "539": {
        "category": "Comparison",
        "question_ko": "(가), (나), (다), (라) 4마리의 고래가 있습니다. (가) 고래는 (나) 고래보다 빠릅니다. (나) 고래는 (다) 고래보다 빠릅니다. (다) 고래는 (라) 고래보다 느립니다. (라) 고래는 (가) 고래보다 빠릅니다. 가장 느린 고래는 어느 고래입니까?",
        "question_en": "There are four whales of (a), (b), (c), and (d). (a) Whales are faster than (b) whales. (b) Whales are faster than (c) whales. (c) Whales are slower than (d) whales. (d) Whales are faster than (a) whales. Which whale is the slowest?",
        "answer_ko": "(다)",
        "answer_en": "(c)",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) (다) (라) [OP_LIST_EOL] [OP_LIST_SOL] (가) (나) > (나) (다) > (다) (라) < (라) (가) > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (a) (b) (c) (d) [OP_LIST_EOL] [OP_LIST_SOL] (a) (b) > (b) (c) > (c) (d) < (d) (a) > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nvar_c = '(다)'\nvar_d = '(라)'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '(가)'\nvar_f = '(나)'\nvar_g = '>'\nvar_h = '(나)'\nvar_i = '(다)'\nvar_j = '>'\nvar_k = '(다)'\nvar_l = '(라)'\nvar_m = '<'\nvar_n = '(라)'\nvar_o = '(가)'\nvar_p = '>'\nlist_b= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_q = len(list_c)\nvar_r = list_c[var_q-1]\nprint(var_r)",
        "solution_code_en": "var_a = '(a)'\nvar_b = '(b)'\nvar_c = '(c)'\nvar_d = '(d)'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '(a)'\nvar_f = '(b)'\nvar_g = '>'\nvar_h = '(b)'\nvar_i = '(c)'\nvar_j = '>'\nvar_k = '(c)'\nvar_l = '(d)'\nvar_m = '<'\nvar_n = '(d)'\nvar_o = '(a)'\nvar_p = '>'\nlist_b= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_q = len(list_c)\nvar_r = list_c[var_q-1]\nprint(var_r)"
    },
    "540": {
        "category": "Arithmetic calculation",
        "question_ko": "은행에 100만 원짜리 수표 25장, 10만 원짜리 수표 8장을 들고 가서 통장에 넣었습니다. 그 전에 통장에 돈이 없었다면 현재 통장에 들어있는 돈은 얼마입니까?",
        "question_en": "You went to the bank with 25 checks for 1 million won and 8 checks for 100,000 won and put them in your bank account. If there was no money in the account before then, how much money is in the account now?",
        "answer_ko": "25800000",
        "answer_en": "25800000",
        "solution_abst_ko": "100 10000 [OP_MUL] 25 [OP_MUL] 10 10000 [OP_MUL] 8 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "100 10000 [OP_MUL] 25 [OP_MUL] 10 10000 [OP_MUL] 8 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 100\nvar_b = 10000\nvar_c = var_a * var_b\nvar_d = 25\nvar_e = var_c * var_d\nvar_f = 10\nvar_g = 10000\nvar_h = var_f * var_g\nvar_i = 8\nvar_j = var_h * var_i\nvar_k = var_e + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 100\nvar_b = 10000\nvar_c = var_a * var_b\nvar_d = 25\nvar_e = var_c * var_d\nvar_f = 10\nvar_g = 10000\nvar_h = var_f * var_g\nvar_i = 8\nvar_j = var_h * var_i\nvar_k = var_e + var_j\nprint(int(var_k))"
    },
    "541": {
        "category": "Geometry",
        "question_ko": "정사면체에서 꼭짓점의 수는 모두 몇개인가요?",
        "question_en": "What is the total number of vertices in a tetrahedron?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "3 1 [OP_ADD]",
        "solution_abst_en": "3 1 [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "542": {
        "category": "Comparison",
        "question_ko": "정국에는 6에서 3을 뺀 수만큼 모았고, 윤기는 4, 유나는 5를 모았습니다. 누가 가장 작은 수를 가지고 있나요?",
        "question_en": "Jungkook has the number 6 minus 3, Yoongi collected 4, and Yuna collected 5. Who has the smallest number?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 윤기 유나 [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_SUB] 4 5 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Yoongi Yuna [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_SUB] 4 5 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '윤기'\nvar_c = '유나'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 6\nvar_e = 3\nvar_f = var_d - var_e\nvar_g = 4\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Yoongi'\nvar_c = 'Yuna'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 6\nvar_e = 3\nvar_f = var_d - var_e\nvar_g = 4\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "543": {
        "category": "Correspondence",
        "question_ko": "형이 10살일 때 동생은 7살이고, 동생이 5살일 때 어머니는 32살입니다. 형이 12살일 때 동생과 어머니의 나이의 합을 구하시오.",
        "question_en": "When the older brother is 10, the younger brother is 7 years old, and when the younger brother is 5 years old, the mother is 32 years old. Find the sum of the ages of the younger brother and mother when the older brother is 12 years old.",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "12 7 10 [OP_SUB] [OP_ADD] 12 7 10 [OP_SUB] [OP_ADD] 32 5 [OP_SUB] [OP_ADD] [OP_ADD]",
        "solution_abst_en": "12 7 10 [OP_SUB] [OP_ADD] 12 7 10 [OP_SUB] [OP_ADD] 32 5 [OP_SUB] [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 12\nvar_b = 7\nvar_c = 10\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 12\nvar_g = 7\nvar_h = 10\nvar_i = var_g - var_h\nvar_j = var_f + var_i\nvar_k = 32\nvar_l = 5\nvar_m = var_k - var_l\nvar_n = var_j + var_m\nvar_o = var_e + var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 12\nvar_b = 7\nvar_c = 10\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 12\nvar_g = 7\nvar_h = 10\nvar_i = var_g - var_h\nvar_j = var_f + var_i\nvar_k = 32\nvar_l = 5\nvar_m = var_k - var_l\nvar_n = var_j + var_m\nvar_o = var_e + var_n\nprint(int(var_o))"
    },
    "544": {
        "category": "Comparison",
        "question_ko": "2.38, 2.83, 2.401을 큰 순서대로 늘어놓았습니다. 두 번째로 올 수는 무엇인가요?",
        "question_en": "I listed the numbers of 2.38, 2.83, and 2.401 in descending order. What number comes in the second?",
        "answer_ko": "2.40",
        "answer_en": "2.4",
        "solution_abst_ko": "[OP_LIST_SOL] 2.38 2.83 2.401 [OP_LIST_EOL] 2 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 2.38 2.83 2.401 [OP_LIST_EOL] 2 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 2.38\nvar_b = 2.83\nvar_c = 2.401\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 2.38\nvar_b = 2.83\nvar_c = 2.401\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "545": {
        "category": "Geometry",
        "question_ko": "세로가 5.4 센티미터(㎝) , 넓이가 48.6 제곱센티미터(㎠)인 직사각형이 있습니다. 이 직사각형의 가로는 몇 센티미터(㎝) 입니까?",
        "question_en": "There is a rectangle with a length of 5.4 centimeters (cm) and an area of 48.6 square centimeters (cm2). How many centimeters (cm) is the width of this rectangle?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "48.6 5.4 [OP_DIV]",
        "solution_abst_en": "48.6 5.4 [OP_DIV]",
        "solution_code_ko": "var_a = 48.6\nvar_b = 5.4\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 48.6\nvar_b = 5.4\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "546": {
        "category": "Correspondence",
        "question_ko": "6과 9의 배수이면서 7로 나누었을때 나머지가 1인 어떤 두자리수가 있다. 이 두자리 수를 구하시오.",
        "question_en": "Two-digit number that is a multiple of 6 and 9 has a remainder of 1 when divided by 7. Find this two digit number.",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "10 100 1 [OP_LIST_ARANGE] 6 9 [OP_LCM] 0 [OP_LIST_DIVIDE_AND_REMAIN] 7 1 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "10 100 1 [OP_LIST_ARANGE] 6 9 [OP_LCM] 0 [OP_LIST_DIVIDE_AND_REMAIN] 7 1 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 10\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nvar_e = 9\nvar_f = var_e * var_d / math.gcd(int(var_e), int(var_d))\nvar_g = 0\nlist_b = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_a:\n    i = int(i)\n    if i%var_f == var_g:\n        list_b.append(i)\nvar_h = 7\nvar_i = 1\nlist_c = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_b:\n    i = int(i)\n    if i%var_h == var_i:\n        list_c.append(i)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(int(var_k))",
        "solution_code_en": "var_a = 10\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nvar_e = 9\nvar_f = var_e * var_d / math.gcd(int(var_e), int(var_d))\nvar_g = 0\nlist_b = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_a:\n    i = int(i)\n    if i%var_f == var_g:\n        list_b.append(i)\nvar_h = 7\nvar_i = 1\nlist_c = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_b:\n    i = int(i)\n    if i%var_h == var_i:\n        list_c.append(i)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(int(var_k))"
    },
    "547": {
        "category": "Correspondence",
        "question_ko": "한 자리 수 A, B가 있습니다. 757AB384는 357의 배수입니다. B의 값을 구하시오.",
        "question_en": "There are one-digit numbers A and B. 757AB384 is a multiple of 357. Find the value of B.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "757AB384 [OP_GEN_POSSIBLE_LIST] 357 [OP_LIST_DIVISIBLE] 757AB384 B [OP_LIST_FIND_UNK]",
        "solution_abst_en": "757AB384 [OP_GEN_POSSIBLE_LIST] 357 [OP_LIST_DIVISIBLE] 757AB384 B [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = '757AB384'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 357\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = '757AB384'\nvar_d = 'B'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nvar_e = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_e = int(elem[unk_idx])\nprint(int(var_e))",
        "solution_code_en": "var_a = '757AB384'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 357\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = '757AB384'\nvar_d = 'B'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nvar_e = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_e = int(elem[unk_idx])\nprint(int(var_e))"
    },
    "548": {
        "category": "Comparison",
        "question_ko": "5.21, 2/3 3.21, 3.42, 1/3 중 첫 번째로 작은 수와 두 번째로 작은 수의 곱을 구하시오",
        "question_en": "Among 5.21, 2/3, 3.21, 3.42, and 1/3, find the product of the smallest and the second smallest number.",
        "answer_ko": "0.22",
        "answer_en": "0.22",
        "solution_abst_ko": "[OP_LIST_SOL] 5.21 2/3 3.21 3.42 1/3 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 5.21 2/3 3.21 3.42 1/3 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_MUL]",
        "solution_code_ko": "var_a = 5.21\nvar_b = 0.6666666666666666\nvar_c = 3.21\nvar_d = 3.42\nvar_e = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g * var_i\nprint('{:.2f}'.format(round(var_j+1e-10,2)))",
        "solution_code_en": "var_a = 5.21\nvar_b = 0.6666666666666666\nvar_c = 3.21\nvar_d = 3.42\nvar_e = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g * var_i\nprint('{:.2f}'.format(round(var_j+1e-10,2)))"
    },
    "549": {
        "category": "Correspondence",
        "question_ko": "6AB+3=691일 때, A를 구하시오.",
        "question_en": "When 6AB+3=691, find A.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "6AB+3=691 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "6AB+3=691 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '6AB+3=691'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '6AB+3=691'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "550": {
        "category": "Arithmetic calculation",
        "question_ko": "어머니는 올해 42살이고, 아버지는 44살입니다. 두 분의 나이를 합한 값이 100이 되는 해에 아버지의 나이는 몇 살입니까?",
        "question_en": "My mother is 42 years old this year, and my father is 44 years old. How old is the father in the year when the sum of their ages is 100?",
        "answer_ko": "51",
        "answer_en": "51",
        "solution_abst_ko": "44 100 44 42 [OP_ADD] [OP_SUB] 2 [OP_DIV] [OP_ADD]",
        "solution_abst_en": "44 100 44 42 [OP_ADD] [OP_SUB] 2 [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 44\nvar_b = 100\nvar_c = 44\nvar_d = 42\nvar_e = var_c + var_d\nvar_f = var_b - var_e\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = var_a + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 44\nvar_b = 100\nvar_c = 44\nvar_d = 42\nvar_e = var_c + var_d\nvar_f = var_b - var_e\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = var_a + var_h\nprint(int(var_i))"
    },
    "551": {
        "category": "Geometry",
        "question_ko": "음료수를 정사각형으로 정렬하니 36캔이 남았습니다. 가로와 세로를 1열 씩 늘렸더니 아직도 3캔이 남았습니다. 음료수는 모두 몇 캔일까요?",
        "question_en": "When the bottles were arranged in a square, there were 36 bottles left. I increased the width and height of the square by one column each, and there were still 3 bottles left out. How many bottles are there in total?",
        "answer_ko": "292",
        "answer_en": "292",
        "solution_abst_ko": "36 3 [OP_SUB] 1 [OP_SUB] 2 [OP_DIV] 2 [OP_POW] 36 [OP_ADD]",
        "solution_abst_en": "36 3 [OP_SUB] 1 [OP_SUB] 2 [OP_DIV] 2 [OP_POW] 36 [OP_ADD]",
        "solution_code_ko": "var_a = 36\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 36\nvar_k = var_i + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 36\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 36\nvar_k = var_i + var_j\nprint(int(var_k))"
    },
    "552": {
        "category": "Comparison",
        "question_ko": "윤기가 가진 사과가 4개, 유나가 가진 사과가 5개, 정국이는 6개의 사과의 사과를 가지고 있었지만 3개를 먹었습니다. 누가 가장 많은 사과를 가지고 있나요?",
        "question_en": "Yoongi had 4 apples, Yuna had 5 apples, and Jungkook had 6 apples, but he ate 3. Who has the most apples?",
        "answer_ko": "유나",
        "answer_en": "Yuna",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 유나 정국 [OP_LIST_EOL] [OP_LIST_SOL] 4 5 6 3 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Yuna Jungkook [OP_LIST_EOL] [OP_LIST_SOL] 4 5 6 3 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '유나'\nvar_c = '정국'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 5\nvar_f = 6\nvar_g = 3\nvar_h = var_f - var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Yuna'\nvar_c = 'Jungkook'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 5\nvar_f = 6\nvar_g = 3\nvar_h = var_f - var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "553": {
        "category": "Possibility",
        "question_ko": "민수네 집 근처에는 치킨집이 3곳, 피자집이 2곳, 중국집이 2곳이 있다. 이 중 3곳에서 배달음식을 동시에 주문할 때, 주문하는 경우의 수를 구하시오.",
        "question_en": "There are three chicken restaurants, two pizza restaurants, and two Chinese restaurants near Minsu's house. When ordering delivery food from 3 of these places at the same time, find the number of cases.",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "3 2 [OP_ADD] 2 [OP_ADD] 3 [OP_COMB]",
        "solution_abst_en": "3 2 [OP_ADD] 2 [OP_ADD] 3 [OP_COMB]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g / (i+1)\nprint(int(var_g))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g / (i+1)\nprint(int(var_g))"
    },
    "554": {
        "category": "Possibility",
        "question_ko": "숫자 카드 1, 6, 8를 한 번씩 모두 사용하여 세 번째 큰 세 자리 수를 구하시오.",
        "question_en": "Use the all number cards 1, 6, and 8 once and find the third largest three-digit number.",
        "answer_ko": "681",
        "answer_en": "681",
        "solution_abst_ko": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))"
    },
    "555": {
        "category": "Geometry",
        "question_ko": "네모난 종이의 가로 길이가 8센티미터(㎝)이다. 둘레가 40센티미터(㎝)이면 세로의 길이는 얼마인가?",
        "question_en": "The width of the square paper is 8 centimeters (cm). If the perimeter is 40 centimeters (cm), how long is the length?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "40 2 [OP_DIV] 8 [OP_SUB]",
        "solution_abst_en": "40 2 [OP_DIV] 8 [OP_SUB]",
        "solution_code_ko": "var_a = 40\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 8\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 40\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 8\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "556": {
        "category": "Arithmetic calculation",
        "question_ko": "한 반에 있는 학생들에게 인형을 주려고 한다. 한 명당 4개씩 주니 3개의 인형이 남았고, 5개씩 주니 6개가 부족했다. 주려고 한 인형은 모두 몇 개인가?",
        "question_en": "You want to give dolls to students in a class. When 4 dolls were given to each student, 3 dolls were left, and when 5 dolls were given, 6 dolls were in short. How many dolls did you have?",
        "answer_ko": "39",
        "answer_en": "39",
        "solution_abst_ko": "3 6 [OP_ADD] 5 4 [OP_SUB] [OP_DIV] 4 [OP_MUL] 3 [OP_ADD]",
        "solution_abst_en": "3 6 [OP_ADD] 5 4 [OP_SUB] [OP_DIV] 4 [OP_MUL] 3 [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = 4\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 4\nvar_i = var_g * var_h\nvar_j = 3\nvar_k = var_i + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 3\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = 4\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 4\nvar_i = var_g * var_h\nvar_j = 3\nvar_k = var_i + var_j\nprint(int(var_k))"
    },
    "557": {
        "category": "Geometry",
        "question_ko": "변의 길이가 모두 같은 오각형이 있습니다. 이 오각형의 한 변의 길이가 15센티미터(㎝)라면, 모든 변의 길이의 합은 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "There is a pentagon whose all sides have the same length. If one side of this pentagon is 15 centimeters (cm) long, how many centimeters (cm) is the sum of all the side lengths?",
        "answer_ko": "75",
        "answer_en": "75",
        "solution_abst_ko": "15 5 [OP_MUL]",
        "solution_abst_en": "15 5 [OP_MUL]",
        "solution_code_ko": "var_a = 15\nvar_b = 5\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 15\nvar_b = 5\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "558": {
        "category": "Possibility",
        "question_ko": "600보다 크고 950보다 작은 세 자리 자연수 중 4, 6, 9가 각 자릿수에 모두 들어 있는 경우는 몇 가지입니까?",
        "question_en": "How many three-digit integers greater than 600 and less than 950 have 4, 6, and 9 in each digit?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 4 6 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 600 [OP_LIST_MORE] 950 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 4 6 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 600 [OP_LIST_MORE] 950 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 4\nvar_b = 6\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 600\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = 950\nlist_d = []\nfor i in list_c:\n    if i < var_f:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 6\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 600\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = 950\nlist_d = []\nfor i in list_c:\n    if i < var_f:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))"
    },
    "559": {
        "category": "Possibility",
        "question_ko": "실험실에는 저울추 1g, 2g, 4g, 8g짜리가 각각 하나씩 있습니다. 이 추들을 이용하여 최대 몇 가지 다른 무게를 잴 수 있습니까?",
        "question_en": "There are weights of 1 gram (g), 2 grams (g), 4 grams (g), and 8 grams (g) each in the lab. How many different weights can you measure using these weights?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "2 4 [OP_POW] 1 [OP_SUB]",
        "solution_abst_en": "2 4 [OP_POW] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = var_a ** var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = var_a ** var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "560": {
        "category": "Comparison",
        "question_ko": "윤기는 4개, 유나는 5개, 정국이는 6에 3을 합한 수 만큼의 사과를 가지고 있습니다. 누가 가장 사과를 조금 가지고 있습니까?",
        "question_en": "Yoongi has 4 apples, Yuna has 5, and Jungkook has 6 plus 3 apples. Who has the smallest number of apples?",
        "answer_ko": "윤기",
        "answer_en": "Yoongi",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 유나 정국 [OP_LIST_EOL] [OP_LIST_SOL] 4 5 6 3 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Yuna Jungkook [OP_LIST_EOL] [OP_LIST_SOL] 4 5 6 3 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '유나'\nvar_c = '정국'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 5\nvar_f = 6\nvar_g = 3\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Yuna'\nvar_c = 'Jungkook'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 5\nvar_f = 6\nvar_g = 3\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "561": {
        "category": "Geometry",
        "question_ko": "정육각형에 대하여 평행인 변은 모두 몇 쌍인가?",
        "question_en": "How many pairs of sides are parallel in a regular hexagon?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "6 2 [OP_FDIV]",
        "solution_abst_en": "6 2 [OP_FDIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = var_a // var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = var_a // var_b\nprint(int(var_c))"
    },
    "562": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 3을 곱한 후 4를 뺐더니 5가 되었습니다. 어떤 수를 구하시오.",
        "question_en": "When you multiply a number by 3 and then subtract 4, you get 5. Find the number.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "5 4 [OP_ADD] 3 [OP_DIV]",
        "solution_abst_en": "5 4 [OP_ADD] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 5\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "563": {
        "category": "Correspondence",
        "question_ko": "90을 어떤 수로 나누었을 때 나누어떨어지게 하는 수는 모두 몇 개일까요?",
        "question_en": "When 90 is divided by any number, how many divisible numbers are there?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "90 [OP_LIST_GET_DIVISOR] [OP_LIST_LEN]",
        "solution_abst_en": "90 [OP_LIST_GET_DIVISOR] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 90\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = len(list_a)\nprint(int(var_b))",
        "solution_code_en": "var_a = 90\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = len(list_a)\nprint(int(var_b))"
    },
    "564": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 11센티미터(㎝)인 정사각형 모양의 색종이가 있습니다. 이 색종이의 넓이는 얼마입니까?",
        "question_en": "There is a piece of colored paper in the shape of a square with a side length of 11 centimeters (cm). What is the area of this sheet of colored paper?",
        "answer_ko": "121",
        "answer_en": "121",
        "solution_abst_ko": "11 2 [OP_POW]",
        "solution_abst_en": "11 2 [OP_POW]",
        "solution_code_ko": "var_a = 11\nvar_b = 2\nvar_c = var_a ** var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 11\nvar_b = 2\nvar_c = var_a ** var_b\nprint(int(var_c))"
    },
    "565": {
        "category": "Correspondence",
        "question_ko": "A를 8로 나누면 몫이 B, 나머지는 C가 됩니다. A, B, C는 자연수 입니다. B와 C가 같을 때, 가능한 A 중 가장 큰 수는 무엇인가요?",
        "question_en": "When A is divided by 8, the quotient is B and the remainder is C. A, B, and C are natural numbers. If B and C are equal, what is the largest possible number of A?",
        "answer_ko": "63",
        "answer_en": "63",
        "solution_abst_ko": "8 1 [OP_SUB] 8 [OP_MUL] 8 1 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "8 1 [OP_SUB] 8 [OP_MUL] 8 1 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 8\nvar_e = var_c * var_d\nvar_f = 8\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 8\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 8\nvar_e = var_c * var_d\nvar_f = 8\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e + var_h\nprint(int(var_i))"
    },
    "566": {
        "category": "Possibility",
        "question_ko": "빨간색 구슬, 파란색 구슬, 노란색 구슬이 1개씩 있습니다. 이 중 2개를 골라 똑같은 모양의 두 상자에 1개씩 넣는 경우의 수를 구하시오.",
        "question_en": "There are 1 red marble, 1 blue marble, and 1 yellow marble. Find the number of ways in which two of these can be placed in two boxes of the same shape.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 빨간색 파란색 노란색 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] red blue yellow [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '빨간색'\nvar_b = '파란색'\nvar_c = '노란색'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f / (i+1)\nprint(int(var_f))",
        "solution_code_en": "var_a = 'red'\nvar_b = 'blue'\nvar_c = 'yellow'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f / (i+1)\nprint(int(var_f))"
    },
    "567": {
        "category": "Geometry",
        "question_ko": "어떤 정사각형은 한 변의 길이가 14센티미터(㎝)입니다. 이 정사각형을 세로가 2센티미터(㎝), 가로가 8센티미터(㎝)인 직사각형으로 쪼개려고 합니다. 이러한 직사각형은 최대 몇 개 얻을 수 있습니까?",
        "question_en": "There is a square with a side of 14 centimeters (cm). You want to subdivide this square into rectangles that are 2 centimeters (cm) wide and 8 centimeters (cm) long. How many such rectangles can you get at most?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "14 2 [OP_POW] 8 2 [OP_MUL] [OP_FDIV]",
        "solution_abst_en": "14 2 [OP_POW] 8 2 [OP_MUL] [OP_FDIV]",
        "solution_code_ko": "var_a = 14\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 8\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c // var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 14\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 8\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c // var_f\nprint(int(var_g))"
    },
    "568": {
        "category": "Possibility",
        "question_ko": "서로 구분이 가능한 세 개의 동전을 던졌을 때, 몇 가지의 결과가 나옵니까?",
        "question_en": "If you throw three coins that are distinguishable from each other, how many outcomes will you get?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "2 3 [OP_POW]",
        "solution_abst_en": "2 3 [OP_POW]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = var_a ** var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = var_a ** var_b\nprint(int(var_c))"
    },
    "569": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 3을 곱하고 49를 더해야 하는데 3을 빼고 49를 더했더니 66이 되었습니다. 바르게 계산한 값과 틀리게 계산한 값의 차는 얼마인지 구하시오.",
        "question_en": "You need to multiply a number by 3 and add 49. But you subtract 3 and add 49 mistakenly and get 66. Find the difference between the correctly calculated value and the incorrectly calculated value.",
        "answer_ko": "43",
        "answer_en": "43",
        "solution_abst_ko": "66 49 [OP_SUB] 3 [OP_ADD] 3 [OP_MUL] 49 [OP_ADD] 66 [OP_SUB]",
        "solution_abst_en": "66 49 [OP_SUB] 3 [OP_ADD] 3 [OP_MUL] 49 [OP_ADD] 66 [OP_SUB]",
        "solution_code_ko": "var_a = 66\nvar_b = 49\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e * var_f\nvar_h = 49\nvar_i = var_g + var_h\nvar_j = 66\nvar_k = var_i - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 66\nvar_b = 49\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e * var_f\nvar_h = 49\nvar_i = var_g + var_h\nvar_j = 66\nvar_k = var_i - var_j\nprint(int(var_k))"
    },
    "570": {
        "category": "Arithmetic calculation",
        "question_ko": "도현이는 도넛을 똑같이 3조각으로 나누어 한 조각을 먹었습니다. 동민이는 같은 크기의 도넛을 똑같이 12조각으로 나누었습니다. 도현이와 같은 양을 먹으려면 동민이는 몇 조각의 도넛을 먹어야 합니까?",
        "question_en": "Dohyun divided the donut into 3 equal pieces and ate one piece. Dongmin divided a donut of the same size into 12 equal pieces. How many donuts must Dongmin eat to eat the same amount as Dohyun?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "12 3 [OP_DIV]",
        "solution_abst_en": "12 3 [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 3\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 12\nvar_b = 3\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "571": {
        "category": "Arithmetic calculation",
        "question_ko": "3킬로그램(㎏) 300그램(g)의 딸기중 1킬로그램(㎏) 900을 친구에게 줄 시 남은 딸기는 몇 그램(g)인가요",
        "question_en": "If you give 1 kg (kg) 900 grams (g) out of 3 kg (kg) 300 grams (g) of strawberries to a friend, how many grams (g) of strawberries are left?",
        "answer_ko": "1400",
        "answer_en": "1400",
        "solution_abst_ko": "3 1000 [OP_MUL] 300 [OP_ADD] 1 1000 [OP_MUL] 900 [OP_ADD] [OP_SUB]",
        "solution_abst_en": "3 1000 [OP_MUL] 300 [OP_ADD] 1 1000 [OP_MUL] 900 [OP_ADD] [OP_SUB]",
        "solution_code_ko": "var_a = 3\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 300\nvar_e = var_c + var_d\nvar_f = 1\nvar_g = 1000\nvar_h = var_f * var_g\nvar_i = 900\nvar_j = var_h + var_i\nvar_k = var_e - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 3\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 300\nvar_e = var_c + var_d\nvar_f = 1\nvar_g = 1000\nvar_h = var_f * var_g\nvar_i = 900\nvar_j = var_h + var_i\nvar_k = var_e - var_j\nprint(int(var_k))"
    },
    "572": {
        "category": "Geometry",
        "question_ko": "채송이는 실을 이용해 한 변의 길이가 13센티미터(㎝)인 정사각형을 만들었습니다. 채송이가 가진 실의 길이는 얼마입니까?",
        "question_en": "Chae Song-i made a square with a side length of 13 centimeters (cm) using thread. What is the length of the thread that Chaesongi has?",
        "answer_ko": "52",
        "answer_en": "52",
        "solution_abst_ko": "13 4 [OP_MUL]",
        "solution_abst_en": "13 4 [OP_MUL]",
        "solution_code_ko": "var_a = 13\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 13\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "573": {
        "category": "Geometry",
        "question_ko": "실제 거리가 5킬로미터(㎞)인 두 지점이 있습니다. 축척이 1/250000인 지도에서 두 지점을 표시한 후 자로 길이를 재었을 때 몇 센티미터(㎝)가 되겠습니까?",
        "question_en": "There are two points with an actual distance of 5 kilometers (km). On a map with a scale of 1/250000, how many centimeters (cm) would be the length of the two points when measured with a ruler?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "5 100 1000 [OP_MUL] [OP_MUL] 1/250000 [OP_MUL]",
        "solution_abst_en": "5 100 1000 [OP_MUL] [OP_MUL] 1/250000 [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 100\nvar_c = 1000\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nvar_f = 4e-06\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 100\nvar_c = 1000\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nvar_f = 4e-06\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "574": {
        "category": "Geometry",
        "question_ko": "사각기둥의 꼭지점의 개수를 구하시오.",
        "question_en": "Find the number of vertices of the rectangular prism.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "4 2 [OP_MUL]",
        "solution_abst_en": "4 2 [OP_MUL]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "575": {
        "category": "Comparison",
        "question_ko": "색연필로 원을 3개 그렸습니다. 주황색 원의 반지름은 4센티미터(㎝)이고, 연두색 원의 지름은 6센티미터(㎝)이고, 하늘색 원의 반지름은 5센티미터(㎝)입니다. 넓이가 가장 넓은 원은 무슨 색입니까?",
        "question_en": "I drew three circles with colored pencils. The radius of the orange circle is 4 centimeters (cm), the diameter of the light-green circle is 6 centimeters (cm), and the radius of the sky-blue circle is 5 centimeters (cm). What color circle is with the widest area?",
        "answer_ko": "하늘색",
        "answer_en": "sky-blue",
        "solution_abst_ko": "[OP_LIST_SOL] 주황색 연두색 하늘색 [OP_LIST_EOL] [OP_LIST_SOL] 4 6 2 [OP_DIV] 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] orange light-green sky-blue [OP_LIST_EOL] [OP_LIST_SOL] 4 6 2 [OP_DIV] 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '주황색'\nvar_b = '연두색'\nvar_c = '하늘색'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 6\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'orange'\nvar_b = 'light-green'\nvar_c = 'sky-blue'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 6\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "576": {
        "category": "Correspondence",
        "question_ko": "반죽 45그램(g)으로 만두를 만드는데 만두 하나당 4그램(g)씩 들어갑니다. 최대 몇 개의 만두를 만들 수 있는지 구하시오.",
        "question_en": "To make dumplings with 45 grams (g) of dough, each dumpling needs 4 grams (g). Find the maximum number of dumplings you can make.",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "45 4 [OP_FDIV]",
        "solution_abst_en": "45 4 [OP_FDIV]",
        "solution_code_ko": "var_a = 45\nvar_b = 4\nvar_c = var_a // var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 45\nvar_b = 4\nvar_c = var_a // var_b\nprint(int(var_c))"
    },
    "577": {
        "category": "Correspondence",
        "question_ko": "90.1 을 어떤 수로 나누었더니 5.3 이 되었습니다. 어떤 수는 얼마인지 구하시오.",
        "question_en": "Divide 90.1 by some number to get 5.3. Find out what the number is.",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "90.1 5.3 [OP_DIV]",
        "solution_abst_en": "90.1 5.3 [OP_DIV]",
        "solution_code_ko": "var_a = 90.1\nvar_b = 5.3\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 90.1\nvar_b = 5.3\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "578": {
        "category": "Arithmetic calculation",
        "question_ko": "6의 배수이면서 5의 배수이면서 8의 배수이면서 9의 배수인 수 중 세 자리 수는 모두 몇 개 입니까?",
        "question_en": "How many three-digit numbers are multiples of 6, multiples of 5, multiples of 8, and multiples of 9?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "100 999 1 [OP_LIST_ARANGE] 6 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "100 999 1 [OP_LIST_ARANGE] 6 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = len(list_e)\nprint(int(var_h))",
        "solution_code_en": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = len(list_e)\nprint(int(var_h))"
    },
    "579": {
        "category": "Geometry",
        "question_ko": "각뿔의 밑면의 모양이 십이각형이다. 이 각뿔의 면은 모두 몇 개인가?",
        "question_en": "The shape of the base side of the pyramid is a dodecagon. How many faces does this pyramid have?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "12 1 [OP_ADD]",
        "solution_abst_en": "12 1 [OP_ADD]",
        "solution_code_ko": "var_a = 12\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 12\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "580": {
        "category": "Arithmetic calculation",
        "question_ko": "석기와 예슬이가 철사를 나누어 가졌습니다. 철사의 길이는 1미터(m) 50센티미터(㎝)이며 석기는 예슬이보다 16센티미터(㎝) 더 짧게 가진다고 합니다. 석기는 몇 센티미터(㎝)를 가집니까?",
        "question_en": "Seokgi and Yeseul shared a wire. The length of this wire is 1 meter (m) and 50 centimeters (cm), and it is said that the Seokgi's share is 16 centimeters (cm) shorter than Yeseul. How many centimeters (cm) of wire does Seokgi have?",
        "answer_ko": "67",
        "answer_en": "67",
        "solution_abst_ko": "1 100 [OP_MUL] 50 [OP_ADD] 16 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "1 100 [OP_MUL] 50 [OP_ADD] 16 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 50\nvar_e = var_c + var_d\nvar_f = 16\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 50\nvar_e = var_c + var_d\nvar_f = 16\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "581": {
        "category": "Arithmetic calculation",
        "question_ko": "바구니에 사과가 8개 있습니다. 정국이가 바구니에 사과 7개를 더 넣었습니다. 바구니 안에 있는 사과는 모두 몇 개입니까?",
        "question_en": "There are 8 apples in the basket. Jungkook put 7 more apples in the basket. How many apples are in the basket?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "8 7 [OP_ADD]",
        "solution_abst_en": "8 7 [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 8\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "582": {
        "category": "Possibility",
        "question_ko": "1부터 9까지의 자연수 중에서 서로 다른 두 수를 동시에 뽑으려고 합니다. 두 수의 합이 10보다 큰 경우의 수를 구하시오.",
        "question_en": "I am trying to pick two different numbers at the same time from natural numbers from 1 to 9. Find the number of ways in which the sum of two numbers is greater than 10.",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "1 9 1 [OP_LIST_ARANGE] 2 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 10 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "1 9 1 [OP_LIST_ARANGE] 2 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 10 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 10\nlist_d = []\nfor i in list_c:\n    if i > var_f:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 10\nlist_d = []\nfor i in list_c:\n    if i > var_f:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))"
    },
    "583": {
        "category": "Correspondence",
        "question_ko": "4는 어떤 수에서 4를 뻬야 할것을 잘못하여 5를 빼서 나온 결과입니다. 어떤 수를 구하세요.",
        "question_en": "4 is the result of mistakenly subtracting 5 from a number instead of subtracting 4. Find this number",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "4 5 [OP_ADD]",
        "solution_abst_en": "4 5 [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "584": {
        "category": "Correspondence",
        "question_ko": "4A5B+C2D7=8070입니다. 서로 다른 네 수 A, B, C, D가 있을 때 C를 구하세요.",
        "question_en": "4A5B+C2D7=8070. Find C when there are four different numbers A, B, C, and D.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "4A5B+C2D7=8070 C [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "4A5B+C2D7=8070 C [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '4A5B+C2D7=8070'\nvar_b = 'C'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '4A5B+C2D7=8070'\nvar_b = 'C'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "585": {
        "category": "Geometry",
        "question_ko": "모서리의 길이의 합이 14.8미터(m)인 사각뿔이 있습니다. 이 사각뿔의 모서리의 길이는 모두 같을 때, 한 모서리의 길이를 구하시오.",
        "question_en": "There is a quadrangular pyramid with the sum of the lengths of its edges being 14.8 meters (m). Find the length of one edge of this quadrangular pyramid when all the edge lengths are the same.",
        "answer_ko": "1.85",
        "answer_en": "1.85",
        "solution_abst_ko": "14.8 4 2 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "14.8 4 2 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 14.8\nvar_b = 4\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 14.8\nvar_b = 4\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "586": {
        "category": "Possibility",
        "question_ko": "1개의 상자에는 3개의 공이 들어 있습니다. 2개의 상자를 가지고 있을 때 전체 공의 개수는?",
        "question_en": "Each box contains 3 balls. If you have 2 boxes, how many balls do you have in total?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "3 2 [OP_MUL]",
        "solution_abst_en": "3 2 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "587": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.9의 숫자가 있다. 이 중 0.6보다 작은 숫자들 중 가장 큰 수를 구하시오.",
        "question_en": "There are numbers 0.8, 1/2, and 0.9. Find the largest of all numbers less than 0.6.",
        "answer_ko": "0.50",
        "answer_en": "0.5",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 0.6 [OP_LIST_LESS] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 0.6 [OP_LIST_LESS] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.6\nlist_b = []\nfor i in list_a:\n    if i < var_d:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint('{:.2f}'.format(round(var_f+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.6\nlist_b = []\nfor i in list_a:\n    if i < var_d:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint('{:.2f}'.format(round(var_f+1e-10,2)))"
    },
    "588": {
        "category": "Arithmetic calculation",
        "question_ko": "준혁이와 현영이가 둘이서 어떤 일을 8일 동안 하면 전체 일의 7/12를 할 수 있습니다. 이 일을 둘이서 8일 동안 함께 한 후에, 나머지는 준혁이가 혼자 하기로 했습니다. 준혁이가 혼자 일을 한 기간이 10일이라면, 이 일을 처음부터 헌영이가 혼자서 했을 경우 끝내기 위해 며칠이 걸리는지 구하시오.",
        "question_en": "If Junhyeok and Hyeonyoung do a certain task together for 8 days, they can do 7/12 of the total work. After the two of them worked together for eight days, Junhyeok decided to do the rest by himself. If Junhyeok worked alone for 10 days, how many days would it take to finish the job if Heonyeong did it alone from the beginning?",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "1 7/12 8 [OP_DIV] 1 7/12 [OP_SUB] 10 [OP_DIV] [OP_SUB] [OP_DIV]",
        "solution_abst_en": "1 7/12 8 [OP_DIV] 1 7/12 [OP_SUB] 10 [OP_DIV] [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 0.5833333333333334\nvar_c = 8\nvar_d = var_b / var_c\nvar_e = 1\nvar_f = 0.5833333333333334\nvar_g = var_e - var_f\nvar_h = 10\nvar_i = var_g / var_h\nvar_j = var_d - var_i\nvar_k = var_a / var_j\nprint(int(eval('{:.2f}'.format(round(var_k+1e-10,2)))))",
        "solution_code_en": "var_a = 1\nvar_b = 0.5833333333333334\nvar_c = 8\nvar_d = var_b / var_c\nvar_e = 1\nvar_f = 0.5833333333333334\nvar_g = var_e - var_f\nvar_h = 10\nvar_i = var_g / var_h\nvar_j = var_d - var_i\nvar_k = var_a / var_j\nprint(int(eval('{:.2f}'.format(round(var_k+1e-10,2)))))"
    },
    "589": {
        "category": "Comparison",
        "question_ko": "총 3개의 숫자 0.8, 1/2, 0.5이 있습니다. 이 중 0.1보다 크거나 같은 수 중 가장 작거나 같은 수를 구하면 무엇인가요?",
        "question_en": "There are a total of three numbers: 0.8, 1/2, and 0.5. What is the smallest of these numbers greater than or equal to 0.1?",
        "answer_ko": "0.50",
        "answer_en": "0.5",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.5 [OP_LIST_EOL] 0.1 [OP_LIST_MORE_EQUAL] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.5 [OP_LIST_EOL] 0.1 [OP_LIST_MORE_EQUAL] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.1\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nprint('{:.2f}'.format(round(var_f+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.1\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nprint('{:.2f}'.format(round(var_f+1e-10,2)))"
    },
    "590": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 100사이에 있는 모든 수의 합을 구하시오.",
        "question_en": "Find the sum of all numbers between 1 and 100.",
        "answer_ko": "5050",
        "answer_en": "5050",
        "solution_abst_ko": "1 100 1 [OP_LIST_ARANGE] [OP_LIST_SUM]",
        "solution_abst_en": "1 100 1 [OP_LIST_ARANGE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_a = [float(i) for i in list_a]\nvar_d = sum(list_a)\nprint(int(var_d))",
        "solution_code_en": "var_a = 1\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_a = [float(i) for i in list_a]\nvar_d = sum(list_a)\nprint(int(var_d))"
    },
    "591": {
        "category": "Possibility",
        "question_ko": "숫자 카드 0, 1, 2 중 2장을 뽑아 만들 수 있는 두 자리 자연수의 개수를 구하시오.",
        "question_en": "Find the number of two-digit natural numbers that can be made by selecting two figures among 0, 1, and 2.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "592": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 5를 빼고 다시 3으로 나누면 4가 됩니다. 어떤 수를 구하시오.",
        "question_en": "Subtracting 5 from a number and dividing it by 3 gives you 4. Find the number.",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "4 3 [OP_MUL] 5 [OP_ADD]",
        "solution_abst_en": "4 3 [OP_MUL] 5 [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 4\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "593": {
        "category": "Geometry",
        "question_ko": "어떤 원의 지름이 8센티미터(㎝) 이고, 원주가 25.12센티미터(㎝) 일 때, 이 원의 원주율을 구하면 얼마일까요?",
        "question_en": "If the diameter of a circle is 8 centimeters (cm) and the circumference is 25.12 centimeters (cm), what is the pi of the circle?",
        "answer_ko": "3.14",
        "answer_en": "3.14",
        "solution_abst_ko": "25.12 8 [OP_DIV]",
        "solution_abst_en": "25.12 8 [OP_DIV]",
        "solution_code_ko": "var_a = 25.12\nvar_b = 8\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 25.12\nvar_b = 8\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "594": {
        "category": "Comparison",
        "question_ko": "배구팀 (가), (나), (다), (라)가 배구 시합을 하고 있습니다. (가)는 (나)를 3대 2로 이겼으며, (나)는 (라)에게 2대 5로 졌습니다. (다)는 (라)를 3대 2로 이겼을 때, 꼴찌팀을 구하시오.",
        "question_en": "The volleyball teams A, B, C, and D are playing volleyball. A beat B 3-2, and B lost to D 2-5. When C beats D 3-2, find the last-place team.",
        "answer_ko": "(나)",
        "answer_en": "B",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) (다) (라) [OP_LIST_EOL] [OP_LIST_SOL] (가) (나) > (나) (라) < (다) (라) > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D [OP_LIST_EOL] [OP_LIST_SOL] A B > B D < C D > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nvar_c = '(다)'\nvar_d = '(라)'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '(가)'\nvar_f = '(나)'\nvar_g = '>'\nvar_h = '(나)'\nvar_i = '(라)'\nvar_j = '<'\nvar_k = '(다)'\nvar_l = '(라)'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'A'\nvar_f = 'B'\nvar_g = '>'\nvar_h = 'B'\nvar_i = 'D'\nvar_j = '<'\nvar_k = 'C'\nvar_l = 'D'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)"
    },
    "595": {
        "category": "Geometry",
        "question_ko": "10개의 변으로 이루어진 도형 내에 그릴 수 있는 대각선의 개수는 몇 개입니까?",
        "question_en": "How many diagonals can you draw in a 10-sided figure?",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "10 10 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "10 10 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 10\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 10\nvar_b = 10\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "596": {
        "category": "Arithmetic calculation",
        "question_ko": "세 명의 사람 중에서 몸무게가 가장 무거운 사람은 몸무게가 중간인 사람과 7킬로그램(㎏) 700그램(g) 차이 나고, 몸무게가 가장 가벼운 사람은 몸무게가 중간인 사람과 4.8킬로그램(㎏) 차이 납니다. 세 사람의 몸무게 합이 106킬로그램(㎏) 600그램(g)일 때 몸무게가 가장 무거운 사람은 몇 킬로그램(㎏)입니까?",
        "question_en": "Among the three people, the heaviest weight person differs from the middle weight person by 7 kilograms (kg) and 700 grams (g), and the lightest weight person differs from the middle weight person by 4.8 kilograms (kg). If the sum of the weights of the three people is 106 kilograms (kg) and 600 grams (g), how many kilograms (kg) does the heaviest person weigh?",
        "answer_ko": "42.27",
        "answer_en": "42.27",
        "solution_abst_ko": "106 600 1000 [OP_DIV] [OP_ADD] 7 700 1000 [OP_DIV] [OP_ADD] 2 [OP_MUL] [OP_ADD] 4.8 [OP_ADD] 3 [OP_DIV]",
        "solution_abst_en": "106 600 1000 [OP_DIV] [OP_ADD] 7 700 1000 [OP_DIV] [OP_ADD] 2 [OP_MUL] [OP_ADD] 4.8 [OP_ADD] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 106\nvar_b = 600\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 7\nvar_g = 700\nvar_h = 1000\nvar_i = var_g / var_h\nvar_j = var_f + var_i\nvar_k = 2\nvar_l = var_j * var_k\nvar_m = var_e + var_l\nvar_n = 4.8\nvar_o = var_m + var_n\nvar_p = 3\nvar_q = var_o / var_p\nprint('{:.2f}'.format(round(var_q+1e-10,2)))",
        "solution_code_en": "var_a = 106\nvar_b = 600\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 7\nvar_g = 700\nvar_h = 1000\nvar_i = var_g / var_h\nvar_j = var_f + var_i\nvar_k = 2\nvar_l = var_j * var_k\nvar_m = var_e + var_l\nvar_n = 4.8\nvar_o = var_m + var_n\nvar_p = 3\nvar_q = var_o / var_p\nprint('{:.2f}'.format(round(var_q+1e-10,2)))"
    },
    "597": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 4로 나누어야 할 것을 잘못하여 2로 나누었더니 몫이 8이 되었습니다. 바르게 계산하면 얼마입니까?",
        "question_en": "I had to divide a number by 4, but I accidentally divided a number by 2, and the share became 8. How much is it if I calculate it correctly?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "8 2 [OP_MUL] 4 [OP_DIV]",
        "solution_abst_en": "8 2 [OP_MUL] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 8\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "598": {
        "category": "Geometry",
        "question_ko": "반지름의 길이가 6 센티미터(㎝)인 구의 겉넓이는 반지름의 길이가 3 센티미터(㎝)인 구의 겉넓이의 몇 배인가?",
        "question_en": "How many times the surface area of a sphere with a radius of 6 centimeters (cm) is greater than the surface area of a sphere with a radius of 3 centimeters (cm)?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "6 3 [OP_DIV] 2 [OP_POW]",
        "solution_abst_en": "6 3 [OP_DIV] 2 [OP_POW]",
        "solution_code_ko": "var_a = 6\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint(int(var_e))"
    },
    "599": {
        "category": "Comparison",
        "question_ko": "석진이는 건물 입구에서 계단을 걸어 올라가 5층에 도착했습니다. 호석이는 같은 건물 입구에서 엘리베이터를 타고 올라가 8층에 도착했습니다. 더 높이 올라간 사람은 누구입니까?",
        "question_en": "Seokjin walked up the stairs from the building entrance and arrived on the 5th floor. Hoseok took the elevator from the entrance of the same building and reached the 8th floor. Who climbed higher?",
        "answer_ko": "호석",
        "answer_en": "Hoseok",
        "solution_abst_ko": "[OP_LIST_SOL] 석진 호석 [OP_LIST_EOL] [OP_LIST_SOL] 5 8 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Seokjin Hoseok [OP_LIST_EOL] [OP_LIST_SOL] 5 8 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '석진'\nvar_b = '호석'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 5\nvar_d = 8\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Seokjin'\nvar_b = 'Hoseok'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 5\nvar_d = 8\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "600": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 13/12미터(m)인 정삼각형의 모든 변의 길이를 다 더하면 얼마입니까?",
        "question_en": "What is the sum of all the sides of an equilateral triangle with sides of 13/12 meters (m)?",
        "answer_ko": "3.25",
        "answer_en": "3.25",
        "solution_abst_ko": "13/12 3 [OP_MUL]",
        "solution_abst_en": "13/12 3 [OP_MUL]",
        "solution_code_ko": "var_a = 1.0833333333333333\nvar_b = 3\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 1.0833333333333333\nvar_b = 3\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "601": {
        "category": "Arithmetic calculation",
        "question_ko": "숫자 5개, 3.4, 7/2, 1.7, 27/10, 2.9가 있습니다. 가장 작은 수는 얼마인지 소수점을 포함해서 뽑으시오.",
        "question_en": "There are 5 numbers, 3.4, 7/2, 1.7, 27/10, 2.9. What is the smallest number including the decimal point?",
        "answer_ko": "1.70",
        "answer_en": "1.7",
        "solution_abst_ko": "[OP_LIST_SOL] 3.4 7/2 1.7 27/10 2.9 [OP_LIST_EOL] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 3.4 7/2 1.7 27/10 2.9 [OP_LIST_EOL] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 3.4\nvar_b = 3.5\nvar_c = 1.7\nvar_d = 2.7\nvar_e = 2.9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 3.4\nvar_b = 3.5\nvar_c = 1.7\nvar_d = 2.7\nvar_e = 2.9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "602": {
        "category": "Comparison",
        "question_ko": "1.4, 9/10, 1.2, 0.5, 13/10에서 1.1보다 작은 숫자를 나열한뒤, 합을 계산하면 얼마입니까?",
        "question_en": "Of these numbers 1.4, 9/10, 1.2, 0.5, and 13/10, select the numbers that are less than 1.1 and find the sum of those numbers.",
        "answer_ko": "1.40",
        "answer_en": "1.4",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i < var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i < var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "603": {
        "category": "Arithmetic calculation",
        "question_ko": "현우가 주헌이의 과학 시험 점수를 물어보자 주헌이는 80점대라고 답하였습니다. 주헌이의 과학 시험 점수로 가능한 가장 큰 수는 무엇입니까?",
        "question_en": "When Hyunwoo asked about Jooheon's science test score, Jooheon answered that it was in the 80s. What is the possible largest number for Jooheon's science test score?",
        "answer_ko": "89",
        "answer_en": "89",
        "solution_abst_ko": "[OP_LIST_SOL] 8 A [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 8 A [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 8\nvar_b = 'A'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c=\"\"\nfor i in list_a:\n    i = str(i)\n    var_c = var_c + i\nans_dict = dict()\nvar_c = str(var_c)\nlist_b = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_c):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_c\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_c) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_b.append(new_elem)\nvar_d = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_e = list_c[-var_d]\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 'A'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c=\"\"\nfor i in list_a:\n    i = str(i)\n    var_c = var_c + i\nans_dict = dict()\nvar_c = str(var_c)\nlist_b = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_c):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_c\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_c) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_b.append(new_elem)\nvar_d = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_e = list_c[-var_d]\nprint(int(var_e))"
    },
    "604": {
        "category": "Possibility",
        "question_ko": "도희와 가희는 2, 4, 5, 8 이 적힌 숫자 카드 중 2개씩 골라 모두 사용하여 각각 두 자리수를 만든 후, 차가 가장 크게 하려고 합니다. 답은 얼마입니까?",
        "question_en": "Dohee and Gahee choose two of the number cards with the numbers 2, 4, 5, and 8 written on them and use them all to make two digits each, and then try to make the difference as large as possible. What is the answer of it?",
        "answer_ko": "61",
        "answer_en": "61",
        "solution_abst_ko": "[OP_LIST_SOL] 2 4 5 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 2 4 5 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = 5\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = 5\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))"
    },
    "605": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 2를 곱한 뒤 45를 빼야 할 것을 잘못하여 어떤 수를 2로 나누고 45를 더하였더니 85가 되었습니다. 바르게 계산한 값을 구하시오.",
        "question_en": "When you have to multiply a number by 2 and then subtract 45 from it, you mistakenly divide the number by 2 and add 45 and got 85. Find the correctly calculated value.",
        "answer_ko": "115",
        "answer_en": "115",
        "solution_abst_ko": "85 45 [OP_SUB] 2 [OP_MUL] 2 [OP_MUL] 45 [OP_SUB]",
        "solution_abst_en": "85 45 [OP_SUB] 2 [OP_MUL] 2 [OP_MUL] 45 [OP_SUB]",
        "solution_code_ko": "var_a = 85\nvar_b = 45\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = 45\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 85\nvar_b = 45\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = 45\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "606": {
        "category": "Possibility",
        "question_ko": "2종류의 연필과 , 3종류의 지우개가 있습니다. 하나씩 골라 사용하려고 할 때, 가능한 조합의 수를 구하시오.",
        "question_en": "There are 2 types of pencils and 3 types of erasers. When trying to use one by one, find the number of possible combinations.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "2 3 [OP_MUL]",
        "solution_abst_en": "2 3 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "607": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 17을 뺐더니 55가 되었습니다. 9를 어떤 수에서 나눈 결과를 구하시오.",
        "question_en": "Subtracting 17 from a number gives 55. Find the result of dividing this number by 9.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "55 17 [OP_ADD] 9 [OP_DIV]",
        "solution_abst_en": "55 17 [OP_ADD] 9 [OP_DIV]",
        "solution_code_ko": "var_a = 55\nvar_b = 17\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 55\nvar_b = 17\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "608": {
        "category": "Correspondence",
        "question_ko": "632-A9B=41이 성립합니다. A는 무엇인가요?",
        "question_en": "632-A9B=41 is true. What is A?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "632-A9B=41 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "632-A9B=41 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '632-A9B=41'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '632-A9B=41'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "609": {
        "category": "Correspondence",
        "question_ko": "어떤 수로 520을 나누면 몫은 22이고 나머지는 14가 됩니다. 520을 어떤 수보다 7 작은 수로 나눈 몫과 나머지의 곱을 구하시오.",
        "question_en": "Dividing 520 by a particular number gives a quotient of 22 and a remainder of 14. Find the remainder and the quotient of 520 divided by the number that is 7 less than that particular number, and find the product of that remainder and quotient.",
        "answer_ko": "256",
        "answer_en": "256",
        "solution_abst_ko": "520 520 14 [OP_SUB] 22 [OP_DIV] 7 [OP_SUB] [OP_FDIV] 520 520 14 [OP_SUB] 22 [OP_DIV] 7 [OP_SUB] [OP_MOD] [OP_MUL]",
        "solution_abst_en": "520 520 14 [OP_SUB] 22 [OP_DIV] 7 [OP_SUB] [OP_FDIV] 520 520 14 [OP_SUB] 22 [OP_DIV] 7 [OP_SUB] [OP_MOD] [OP_MUL]",
        "solution_code_ko": "var_a = 520\nvar_b = 520\nvar_c = 14\nvar_d = var_b - var_c\nvar_e = 22\nvar_f = var_d / var_e\nvar_g = 7\nvar_h = var_f - var_g\nvar_i = var_a // var_h\nvar_j = 520\nvar_k = 520\nvar_l = 14\nvar_m = var_k - var_l\nvar_n = 22\nvar_o = var_m / var_n\nvar_p = 7\nvar_q = var_o - var_p\nvar_r = var_j % var_q\nvar_s = var_i * var_r\nprint(int(var_s))",
        "solution_code_en": "var_a = 520\nvar_b = 520\nvar_c = 14\nvar_d = var_b - var_c\nvar_e = 22\nvar_f = var_d / var_e\nvar_g = 7\nvar_h = var_f - var_g\nvar_i = var_a // var_h\nvar_j = 520\nvar_k = 520\nvar_l = 14\nvar_m = var_k - var_l\nvar_n = 22\nvar_o = var_m / var_n\nvar_p = 7\nvar_q = var_o - var_p\nvar_r = var_j % var_q\nvar_s = var_i * var_r\nprint(int(var_s))"
    },
    "610": {
        "category": "Geometry",
        "question_ko": "정십각형의 한 꼭짓점에서 그을 수 있는 대각선은 모두 몇 개입니까?",
        "question_en": "How many diagonals can be drawn from a vertex of a regular decagon?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "10 3 [OP_SUB]",
        "solution_abst_en": "10 3 [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 10\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "611": {
        "category": "Geometry",
        "question_ko": "앞면에 1, 3, 5가 앞면에 적힌 동전 3개가 있습니다. 각 동전의 뒷면에는 앞면의 숫자에 1을 더한 수들이 적혀 있습니다. 동전을 던졌을 때, 1이 적힌 동전은 앞면이, 5가 적힌 동전은 뒷면이 나오는 경우는 모두 몇 가지입니까?",
        "question_en": "If there are 3 bus routes, 2 subway routes, and 4 train routes from Seohee's house to school, find the number of ways to go by subway.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "2",
        "solution_abst_en": "2",
        "solution_code_ko": "var_a = 2\nprint(int(var_a))",
        "solution_code_en": "var_a = 2\nprint(int(var_a))"
    },
    "612": {
        "category": "Arithmetic calculation",
        "question_ko": "석기와 예슬이는 배를 한 개 사려고 합니다. 석기가 가진 돈으로는 2000원이 부족하고, 예슬이가 가진 돈으로는 1500원이 부족하다고 합니다. 두 사람이 가진 돈을 합해서 배 한 개를 사면 3500원이 남을 때, 석기가 가진 돈은 몇 원입니까?",
        "question_en": "Seokgi and Ye-seul want to buy a boat. It is said that Seokgi's money is short of 2,000 won, and Ye-seul's money is short of 1,500 won. If 3,500 won is left after buying a boat with the sum of money the two people have, how much money does Seokgi have?",
        "answer_ko": "5000",
        "answer_en": "5000",
        "solution_abst_ko": "2000 1500 [OP_ADD] 3500 [OP_ADD] 2000 [OP_SUB]",
        "solution_abst_en": "2000 1500 [OP_ADD] 3500 [OP_ADD] 2000 [OP_SUB]",
        "solution_code_ko": "var_a = 2000\nvar_b = 1500\nvar_c = var_a + var_b\nvar_d = 3500\nvar_e = var_c + var_d\nvar_f = 2000\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 2000\nvar_b = 1500\nvar_c = var_a + var_b\nvar_d = 3500\nvar_e = var_c + var_d\nvar_f = 2000\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "613": {
        "category": "Arithmetic calculation",
        "question_ko": "가로가 3미터(m) 20센티미터(㎝)인 벽에 가로가 30센티미터(㎝)인 포스터 6장을 일렬로 붙이려고 합니다. 벽의 끝과 포스터 사이, 포스터와 포스터 사이의 간격을 모두 같게 하려면 간격은 몇 센티미터(㎝)로 해야 하는지 구하시오.",
        "question_en": "I am going to put 6 posters with a width of 30 centimeters (cm) in a row on a wall with a width of 3 meters (m) and 20 centimeters (cm). Determine how many centimeters (cm) the distance must be to equalize the distance between the end of the wall and the poster and the distance between the posters.",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "3 100 [OP_MUL] 20 [OP_ADD] 30 6 [OP_MUL] [OP_SUB] 6 1 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "3 100 [OP_MUL] 20 [OP_ADD] 30 6 [OP_MUL] [OP_SUB] 6 1 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 3\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 20\nvar_e = var_c + var_d\nvar_f = 30\nvar_g = 6\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nvar_j = 6\nvar_k = 1\nvar_l = var_j + var_k\nvar_m = var_i / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 3\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 20\nvar_e = var_c + var_d\nvar_f = 30\nvar_g = 6\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nvar_j = 6\nvar_k = 1\nvar_l = var_j + var_k\nvar_m = var_i / var_l\nprint(int(var_m))"
    },
    "614": {
        "category": "Arithmetic calculation",
        "question_ko": "기윤이의 한 걸음은 0.75미터(m)이고, 1분 동안 70걸음을 걷습니다. 기윤이가 집에서 학교까지 걸어서 가는 데 13분이 걸렸다면, 기윤이의 집과 학교 사이의 거리는 몇 미터(m)입니까?",
        "question_en": "Giyun's one step is 0.75 meters (m), and he takes 70 steps in one minute. If it took 13 minutes for Giyun to walk from his house to school, what is the distance in meters (m) between Giyun's house and school?",
        "answer_ko": "682.50",
        "answer_en": "682.5",
        "solution_abst_ko": "0.75 70 [OP_MUL] 13 [OP_MUL]",
        "solution_abst_en": "0.75 70 [OP_MUL] 13 [OP_MUL]",
        "solution_code_ko": "var_a = 0.75\nvar_b = 70\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.75\nvar_b = 70\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "615": {
        "category": "Arithmetic calculation",
        "question_ko": "오렌지 주스 2.87리터(L)를 두 명이 똑같이 나누어 마시려고 합니다. 한 사람이 몇 리터(L)씩 마시게 되는지 나타내시오.",
        "question_en": "Two people are going to drink 2.87 liters of orange juice equally. Find how many liters (l) each person will drink.",
        "answer_ko": "1.44",
        "answer_en": "1.44",
        "solution_abst_ko": "2.87 2 [OP_DIV]",
        "solution_abst_en": "2.87 2 [OP_DIV]",
        "solution_code_ko": "var_a = 2.87\nvar_b = 2\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 2.87\nvar_b = 2\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "616": {
        "category": "Geometry",
        "question_ko": "직사각형의 둘레는 52센티미터(㎝)입니다. 한 변의 길이가 11센티미터(㎝)일 때, 이 직사각형의 넓이는 얼마입니까?",
        "question_en": "The perimeter of the rectangle is 52 centimeters (cm). What is the area of this rectangle if its side is 11 centimeters (cm)?",
        "answer_ko": "165",
        "answer_en": "165",
        "solution_abst_ko": "11 52 2 [OP_DIV] 11 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "11 52 2 [OP_DIV] 11 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 11\nvar_b = 52\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = 11\nvar_f = var_d - var_e\nvar_g = var_a * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 11\nvar_b = 52\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = 11\nvar_f = var_d - var_e\nvar_g = var_a * var_f\nprint(int(var_g))"
    },
    "617": {
        "category": "Possibility",
        "question_ko": "100이하인 홀수를 모두 종이에 적으면, 숫자 1을 몇 번 적어야 하는지 구하시오.",
        "question_en": "If you write down all the odd numbers less than 100 on a piece of paper, how many times do you have to write the figure '1'?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "1 100 [OP_LIST_ODD] [OP_LIST2NUM] [OP_NUM2LIST] 1 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 100 [OP_LIST_ODD] [OP_LIST2NUM] [OP_NUM2LIST] 1 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 100\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c=\"\"\nfor i in list_a:\n    i = str(i)\n    var_c = var_c + i\nlist_b = []\nvar_c = int(var_c)\nwhile var_c//10 > 0:\n    list_b.append(var_c%10)\n    var_c = var_c//10\nlist_b.append(var_c%10)\nlist_b = list_b[::-1]\nvar_d = 1\nvar_e = 0\nvar_d = int(var_d)\nfor i in list_b:\n    i = int(i)\n    if i == var_d:\n        var_e = var_e + 1\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 100\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c=\"\"\nfor i in list_a:\n    i = str(i)\n    var_c = var_c + i\nlist_b = []\nvar_c = int(var_c)\nwhile var_c//10 > 0:\n    list_b.append(var_c%10)\n    var_c = var_c//10\nlist_b.append(var_c%10)\nlist_b = list_b[::-1]\nvar_d = 1\nvar_e = 0\nvar_d = int(var_d)\nfor i in list_b:\n    i = int(i)\n    if i == var_d:\n        var_e = var_e + 1\nprint(int(var_e))"
    },
    "618": {
        "category": "Arithmetic calculation",
        "question_ko": "찹쌀떡 한 개를 만드는 데 찹쌀가루가 6.64그램(g) 필요합니다. 찹쌀가루 212.48그램(g)으로 만들 수 있는 찹쌀떡은 모두 몇 개입니까?",
        "question_en": "It takes 6.64 grams (g) of glutinous rice flour to make one glutinous rice cake. How many glutinous rice cakes can be made with 212.48 grams (g) of glutinous rice flour?",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "212.48 6.64 [OP_FDIV]",
        "solution_abst_en": "212.48 6.64 [OP_FDIV]",
        "solution_code_ko": "var_a = 212.48\nvar_b = 6.64\nvar_c = var_a // var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 212.48\nvar_b = 6.64\nvar_c = var_a // var_b\nprint(int(var_c))"
    },
    "619": {
        "category": "Correspondence",
        "question_ko": "어느 대학의 국문학과 학생은 중국어과 학생의 6/11만큼 있고, 일어과 학생은 중국어과 학생의 1/8만큼 있다. 국문학과 학생이 48명일 때, 일어과 학생은 몇 명인지 구하시오.",
        "question_en": "At a certain university, the number of Korean department students is 6/11 of Chinese department students, and the number of Japanese department students is 1/8 of the students in the Chinese department. If there are 48 Korean department students, find the number of Japanese department students.",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "48 6/11 [OP_DIV] 1/8 [OP_MUL]",
        "solution_abst_en": "48 6/11 [OP_DIV] 1/8 [OP_MUL]",
        "solution_code_ko": "var_a = 48\nvar_b = 0.5454545454545454\nvar_c = var_a / var_b\nvar_d = 0.125\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 48\nvar_b = 0.5454545454545454\nvar_c = var_a / var_b\nvar_d = 0.125\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "620": {
        "category": "Possibility",
        "question_ko": "두 수 3, 5를 한 번씩만 사용하여 만들 수 있는 서로 다른 두 자리 수는 모두 몇 개입니까?",
        "question_en": "How many different two-digit numbers can be formed by using the two numbers 3 and 5 only once?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 3 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 3 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 3\nvar_b = 5\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = len(list_b)\nprint(int(var_d))",
        "solution_code_en": "var_a = 3\nvar_b = 5\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = len(list_b)\nprint(int(var_d))"
    },
    "621": {
        "category": "Possibility",
        "question_ko": "10명의 학생이 조를 짜려고 한다. 한 조의 인원은 3명 이하여야 한다. 만들어질 수 있는 조들의 경우의 수를 구하시오.",
        "question_en": "Ten students are trying to form a group. The number of people in a group must be 3 or less. Find the number of cases of groups that can be created.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PRODUCT] [OP_LIST_NUM2SUM] 10 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PRODUCT] [OP_LIST_NUM2SUM] 10 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_f = 0\n    i = int(i)\n    while i//10 > 0:\n        var_f = var_f + i%10\n        i = i//10\n    var_f = var_f + i%10\n    list_c.append(var_f)\nvar_g = 10\nvar_h = 0\nvar_g = int(var_g)\nfor i in list_c:\n    i = int(i)\n    if i == var_g:\n        var_h = var_h + 1\nprint(int(var_h))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_f = 0\n    i = int(i)\n    while i//10 > 0:\n        var_f = var_f + i%10\n        i = i//10\n    var_f = var_f + i%10\n    list_c.append(var_f)\nvar_g = 10\nvar_h = 0\nvar_g = int(var_g)\nfor i in list_c:\n    i = int(i)\n    if i == var_g:\n        var_h = var_h + 1\nprint(int(var_h))"
    },
    "622": {
        "category": "Arithmetic calculation",
        "question_ko": "재홍이네 학급 학생은 모두 36명입니다. 이중 오늘 반팔 옷을 입은 학생은 긴팔 옷을 입은 학생보다 24명이 더 적다면, 오늘 반팔을 입은 학생은 몇 명인지 구하시오.",
        "question_en": "There are 36 students in Jaehong's class. If there are 24 fewer students wearing short sleeves than students wearing long sleeves, find how many students are wearing short sleeves.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "36 24 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "36 24 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 36\nvar_b = 24\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 36\nvar_b = 24\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "623": {
        "category": "Comparison",
        "question_ko": "수학 시험에서 지민이는 4등이고, 석진이는 지민이보다 낮은 등수를 받았고 둘 사이에는 19명이 있습니다. 석진이는 몇 등입니까?",
        "question_en": "In the math test, Jimin is ranked 4th, and Seokjin is ranked lower than Jimin and there are 19 people between them. What is the rank of Seokjin?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "4 19 [OP_ADD] 1 [OP_ADD]",
        "solution_abst_en": "4 19 [OP_ADD] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 19\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 4\nvar_b = 19\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "624": {
        "category": "Arithmetic calculation",
        "question_ko": "사랑이네 학교 학생은 모두 1500 명이고, 그중 여학생은 전체의 0.4 입니다. 사랑이네 학교 남학생의 0.65 가 수학을 좋아할 때, 수학은 좋아하지 않는 남학생은 몇 명입니까?",
        "question_en": "There are 1500 students in Sarang's School, 0.4 of which are female students. If 0.65 of the male students at Sarang's School like math, how many male students do not like math?",
        "answer_ko": "315",
        "answer_en": "315",
        "solution_abst_ko": "1500 1 0.4 [OP_SUB] [OP_MUL] 1 0.65 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "1500 1 0.4 [OP_SUB] [OP_MUL] 1 0.65 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 1500\nvar_b = 1\nvar_c = 0.4\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 1\nvar_g = 0.65\nvar_h = var_f - var_g\nvar_i = var_e * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1500\nvar_b = 1\nvar_c = 0.4\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 1\nvar_g = 0.65\nvar_h = var_f - var_g\nvar_i = var_e * var_h\nprint(int(var_i))"
    },
    "625": {
        "category": "Arithmetic calculation",
        "question_ko": "작은 상자 1개에는 공을 3개씩 담을 수 있습니다. 정국이는 12개의 공을 작은 상자에 담으려고 합니다. 정국이는 몇 개의 상자가 필요합니까?",
        "question_en": "One small box can contain 3 balls each. Jungkook is trying to put 12 balls in the small boxes. How many boxes does Jungkook need?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "12 3 [OP_DIV]",
        "solution_abst_en": "12 3 [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 3\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 12\nvar_b = 3\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "626": {
        "category": "Geometry",
        "question_ko": "어떤 직육면체 공간에 가로, 세로, 높이가 각각 1센티미터(㎝)인 박스를 36개 넣을 수 있다. 이 공간의 가로, 세로, 높이를 2배 한다면 몇 개의 박스를 넣을 수 있겠는가?",
        "question_en": "A cuboid space can contain 36 boxes, each measuring 1 centimeter (cm) in length, width, and height. How many boxes could fit in this space if you double its length, width, and height?",
        "answer_ko": "288",
        "answer_en": "288",
        "solution_abst_ko": "36 2 3 [OP_POW] [OP_MUL]",
        "solution_abst_en": "36 2 3 [OP_POW] [OP_MUL]",
        "solution_code_ko": "var_a = 36\nvar_b = 2\nvar_c = 3\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 36\nvar_b = 2\nvar_c = 3\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nprint(int(var_e))"
    },
    "627": {
        "category": "Arithmetic calculation",
        "question_ko": "기차에 82명이 타고 있었습니다. 이 중에서 몇 명이 내리고, 17명이 더 타서 73명이 되었습니다. 기차에서 내린 사람은 몇 명입니까?",
        "question_en": "There were 82 people on the train. A few of these got off, and 17 more got on, making the total 73 people. How many people got off the train?",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "82 17 [OP_ADD] 73 [OP_SUB]",
        "solution_abst_en": "82 17 [OP_ADD] 73 [OP_SUB]",
        "solution_code_ko": "var_a = 82\nvar_b = 17\nvar_c = var_a + var_b\nvar_d = 73\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 82\nvar_b = 17\nvar_c = var_a + var_b\nvar_d = 73\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "628": {
        "category": "Comparison",
        "question_ko": "빈우와 지완이가 운동장 한 바퀴를 도는 데 걸린 시간이 각각 1분 33초, 102초입니다. 누가 더 빨리 돌았을까요?",
        "question_en": "The time it took for Binwoo and Jiwan to go around the playground was 1 minute 33 seconds and 102 seconds, respectively. Who would have circled faster?",
        "answer_ko": "빈우",
        "answer_en": "Binwoo",
        "solution_abst_ko": "[OP_LIST_SOL] 빈우 지완 [OP_LIST_EOL] [OP_LIST_SOL] 1 60 [OP_MUL] 33 [OP_ADD] 102 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Binwoo Jiwan [OP_LIST_EOL] [OP_LIST_SOL] 1 60 [OP_MUL] 33 [OP_ADD] 102 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '빈우'\nvar_b = '지완'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1\nvar_d = 60\nvar_e = var_c * var_d\nvar_f = 33\nvar_g = var_e + var_f\nvar_h = 102\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Binwoo'\nvar_b = 'Jiwan'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1\nvar_d = 60\nvar_e = var_c * var_d\nvar_f = 33\nvar_g = var_e + var_f\nvar_h = 102\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "629": {
        "category": "Correspondence",
        "question_ko": "형철이는 계산기를 사용하다 46을 곱해야 할 것을 잘못 눌러 46을 뺐더니 계산기가 27을 답으로 알려주었다. 바르게 계산했다면 얼마가 나오는지 구하시오.",
        "question_en": "Hyung-cheol was using the calculator, but he pressed the wrong number and subtracted 46, which originally should be multiplied. The calculator gave 27 as the answer. If you calculated correctly, find out how much you would get.",
        "answer_ko": "3358",
        "answer_en": "3358",
        "solution_abst_ko": "27 46 [OP_ADD] 46 [OP_MUL]",
        "solution_abst_en": "27 46 [OP_ADD] 46 [OP_MUL]",
        "solution_code_ko": "var_a = 27\nvar_b = 46\nvar_c = var_a + var_b\nvar_d = 46\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 27\nvar_b = 46\nvar_c = var_a + var_b\nvar_d = 46\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "630": {
        "category": "Comparison",
        "question_ko": "학생들이 한 줄로 서 있습니다. 유정이는 맨 오른쪽에 서 있습니다. 은정이는 맨 왼쪽에서 5번째에 서 있습니다. 은정이와 유정이 사이에 8명이 서 있을 때, 줄을 서 있는 학생은 모두 몇 명입니까?",
        "question_en": "Students stand in a line. Yoojung is standing on the far right. Eunjeong is standing 5th from the far left. When 8 students are standing between Eunjeong and Yoojung, how many students are in line?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "5 8 [OP_ADD] 1 [OP_ADD]",
        "solution_abst_en": "5 8 [OP_ADD] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "631": {
        "category": "Arithmetic calculation",
        "question_ko": "사과 한 상자의 무게가 9킬로그램(㎏)이었습니다. 사과의 절반만큼 덜어낸 후에 무게를 다시 재어 보니 5킬로그램(㎏)이 되었습니다. 각 사과의 크기와 무게가 모두 같다고 할 때, 사과 상자만의 무게는 몇 킬로그램(㎏)입니까?",
        "question_en": "A box of apples weighed 9 kilograms (kg). After removing half of the apples, I weighed it again and it was 5 kilograms (kg). If each apple is the same size and weight, how many kilograms (kg) does only one box except apples weigh?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "9 9 5 [OP_SUB] 2 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "9 9 5 [OP_SUB] 2 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 9\nvar_b = 9\nvar_c = 5\nvar_d = var_b - var_c\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_a - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 9\nvar_b = 9\nvar_c = 5\nvar_d = var_b - var_c\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_a - var_f\nprint(int(var_g))"
    },
    "632": {
        "category": "Comparison",
        "question_ko": "유정은 책상 위에 갖가지 색깔의 공들을 일렬로 놓았다. 빨간색, 파란색, 노란색, 보라색, 흰색 공을 순서대로 놓았을 때 첫 번째 공은 무슨 색입니까?",
        "question_en": "Yujeong placed balls of various colors in a row on the desk. When the red, blue, yellow, purple, and white balls are placed in order, what color is the first ball?",
        "answer_ko": "빨간색",
        "answer_en": "red",
        "solution_abst_ko": "[OP_LIST_SOL] 빨간색 파란색 노란색 보라색 흰색 [OP_LIST_EOL] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] red blue yellow purple white [OP_LIST_EOL] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '빨간색'\nvar_b = '파란색'\nvar_c = '노란색'\nvar_d = '보라색'\nvar_e = '흰색'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nvar_g = list_a[var_f-1]\nprint(var_g)",
        "solution_code_en": "var_a = 'red'\nvar_b = 'blue'\nvar_c = 'yellow'\nvar_d = 'purple'\nvar_e = 'white'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nvar_g = list_a[var_f-1]\nprint(var_g)"
    },
    "633": {
        "category": "Arithmetic calculation",
        "question_ko": "은지의 몸무게는 145/4킬로그램(㎏)이고, 준수는 은지보다 47/10킬로그램(㎏) 더 가볍습니다. 준수의 몸무게는 몇 킬로그램(㎏)입니까?",
        "question_en": "Eunji's weight is 145/4 kilograms (kg), and Junsu is 47/10 kilograms (kg) lighter than Eunji. How many kilograms (kg) does Junsu weigh?",
        "answer_ko": "31.55",
        "answer_en": "31.55",
        "solution_abst_ko": "145/4 47/10 [OP_SUB]",
        "solution_abst_en": "145/4 47/10 [OP_SUB]",
        "solution_code_ko": "var_a = 36.25\nvar_b = 4.7\nvar_c = var_a - var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 36.25\nvar_b = 4.7\nvar_c = var_a - var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "634": {
        "category": "Comparison",
        "question_ko": "영희와 지민이 그리고 준수는 이틀동안 물 많이 마시기 대회를 했다. 영희는 1.4리터(L)를 마셨고 지민이는 1.8리터(L)를 마셨으며 준수는 2.1리터(L)를 마셨다. 누가 승자인가?",
        "question_en": "Younghee, Jimin, and Junsu had a water drinking contest for two days. Younghee drank 1.4 liters (L), Jimin drank 1.8 liters (L), and Junsu drank 2.1 liters (L). Who is the winner?",
        "answer_ko": "준수",
        "answer_en": "Junsu",
        "solution_abst_ko": "[OP_LIST_SOL] 영희 지민 준수 [OP_LIST_EOL] [OP_LIST_SOL] 1.4 1.8 2.1 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Younghee Jimin Junsu [OP_LIST_EOL] [OP_LIST_SOL] 1.4 1.8 2.1 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '영희'\nvar_b = '지민'\nvar_c = '준수'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1.4\nvar_e = 1.8\nvar_f = 2.1\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Younghee'\nvar_b = 'Jimin'\nvar_c = 'Junsu'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1.4\nvar_e = 1.8\nvar_f = 2.1\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "635": {
        "category": "Geometry",
        "question_ko": "긴 변의 길이가 4센티미터(㎝)이고, 넓이가 25/2제곱센티미터(㎠)인 직사각형이 있습니다. 이 직사각형의 짧은 변의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "There is a rectangle whose longer side is 4 centimeters (cm) and its area is 25/2 square centimeter (cm2). What is the length of the shorter side of this rectangle in centimeters (cm)?",
        "answer_ko": "3.13",
        "answer_en": "3.13",
        "solution_abst_ko": "25/2 4 [OP_DIV]",
        "solution_abst_en": "25/2 4 [OP_DIV]",
        "solution_code_ko": "var_a = 12.5\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 12.5\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "636": {
        "category": "Correspondence",
        "question_ko": "48을 어떤 수로 나눈 몫에 7을 더했더니 15가 되었습니다. 어떤 수를 구하세요.",
        "question_en": "When you divide 48 by a number and add 7 to the quotient of it, you get 15. Figure out what the number is.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "48 15 7 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "48 15 7 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 48\nvar_b = 15\nvar_c = 7\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 48\nvar_b = 15\nvar_c = 7\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "637": {
        "category": "Comparison",
        "question_ko": "지석의 배낭 무게는 1.49킬로그램(㎏), 미호의 배낭 무게는 9/20킬로그램(㎏)이다. 배낭의 무게가 더 가벼운 사람의 이름은?",
        "question_en": "Jiseok's backpack weighs 1.49 kilograms (kg), and Miho's backpack weighs 9/20 kilograms (kg). What is the name of the person whose backpack weighs less?",
        "answer_ko": "미호",
        "answer_en": "Miho",
        "solution_abst_ko": "[OP_LIST_SOL] 지석 미호 [OP_LIST_EOL] [OP_LIST_SOL] 1.49 9 20 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jiseok Miho [OP_LIST_EOL] [OP_LIST_SOL] 1.49 9 20 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '지석'\nvar_b = '미호'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.49\nvar_d = 9\nvar_e = 20\nvar_f = var_d / var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Jiseok'\nvar_b = 'Miho'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.49\nvar_d = 9\nvar_e = 20\nvar_f = var_d / var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "638": {
        "category": "Correspondence",
        "question_ko": "진호는 친구네 집에 놀러가는데 지하철을 타고 3킬로미터(㎞) 7미터(m)를 가고 나서 몇 미터(m)를 걸었습니다. 그리고 다시 840미터(m)를 버스로 이동하여 전체 6킬로미터(㎞) 30미터(m)만큼 이동했습니다. 진호가 걸은 거리는 몇 킬로미터(㎞)인지 구하시오.",
        "question_en": "Jinho went to a friend's house to play, so he took the subway for 3 kilometers (km) and 7 meters (m), and then walked a few meters (m). And again, he moved 840 meters (m) by bus, which has a total distance of 6 kilometers (km) and 30 meters (m). Find how many kilometers (km) Jinho walked.",
        "answer_ko": "2.18",
        "answer_en": "2.18",
        "solution_abst_ko": "6 1000 [OP_MUL] 30 [OP_ADD] 840 [OP_SUB] 3 1000 [OP_MUL] 7 [OP_ADD] [OP_SUB] 1000 [OP_DIV]",
        "solution_abst_en": "6 1000 [OP_MUL] 30 [OP_ADD] 840 [OP_SUB] 3 1000 [OP_MUL] 7 [OP_ADD] [OP_SUB] 1000 [OP_DIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 30\nvar_e = var_c + var_d\nvar_f = 840\nvar_g = var_e - var_f\nvar_h = 3\nvar_i = 1000\nvar_j = var_h * var_i\nvar_k = 7\nvar_l = var_j + var_k\nvar_m = var_g - var_l\nvar_n = 1000\nvar_o = var_m / var_n\nprint('{:.2f}'.format(round(var_o+1e-10,2)))",
        "solution_code_en": "var_a = 6\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 30\nvar_e = var_c + var_d\nvar_f = 840\nvar_g = var_e - var_f\nvar_h = 3\nvar_i = 1000\nvar_j = var_h * var_i\nvar_k = 7\nvar_l = var_j + var_k\nvar_m = var_g - var_l\nvar_n = 1000\nvar_o = var_m / var_n\nprint('{:.2f}'.format(round(var_o+1e-10,2)))"
    },
    "639": {
        "category": "Geometry",
        "question_ko": "넓이가 32인 직사각형의 가로와 세로가 모두 자연수라고 한다. 가능한 직사각형의 개수를 구하시오. (단, 가로와 세로를 바꾸었을 때 같은 직사각형은 같은 것으로 본다.)",
        "question_en": "The width and height of a rectangle with an area of 32 are both natural numbers. Find the number of possible rectangles. (However, when the width and height are swapped, the same rectangle is considered identical.)",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "32 [OP_LIST_GET_DIVISOR] [OP_LIST_LEN] 2 [OP_DIV]",
        "solution_abst_en": "32 [OP_LIST_GET_DIVISOR] [OP_LIST_LEN] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 32\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = len(list_a)\nvar_c = 2\nvar_d = var_b / var_c\nprint(int(var_d))",
        "solution_code_en": "var_a = 32\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = len(list_a)\nvar_c = 2\nvar_d = var_b / var_c\nprint(int(var_d))"
    },
    "640": {
        "category": "Possibility",
        "question_ko": "숫자 카드 4, 3, 1 중 2 장을 한 번씩 사용하여 가장 큰 두 자리 수를 만들 때, 사용하지 않는 카드의 숫자는 무엇입니까?",
        "question_en": "When two of the number cards 4, 3, and 1 are used once to form the largest two-digit number, what is the number on the unused card?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 4 3 1 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] [OP_LIST_POP] [OP_NUM2LIST] [OP_SET_DIFFERENCE] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] 4 3 1 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] [OP_LIST_POP] [OP_NUM2LIST] [OP_SET_DIFFERENCE] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 4\nvar_b = 3\nvar_c = 1\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nlist_d = []\nvar_f = int(var_f)\nwhile var_f//10 > 0:\n    list_d.append(var_f%10)\n    var_f = var_f//10\nlist_d.append(var_f%10)\nlist_d = list_d[::-1]\nlist_e = list(set(list_a) - set(list_d))\nvar_g = 1\nvar_h = list_e[var_g-1]\nprint(int(var_h))",
        "solution_code_en": "var_a = 4\nvar_b = 3\nvar_c = 1\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nlist_d = []\nvar_f = int(var_f)\nwhile var_f//10 > 0:\n    list_d.append(var_f%10)\n    var_f = var_f//10\nlist_d.append(var_f%10)\nlist_d = list_d[::-1]\nlist_e = list(set(list_a) - set(list_d))\nvar_g = 1\nvar_h = list_e[var_g-1]\nprint(int(var_h))"
    },
    "641": {
        "category": "Comparison",
        "question_ko": "영빈이와 수정이가 동전 빨리 줍기 대결을 하였습니다. 동전을 모두 줍는 데 영빈이는 16.23초 걸렸고 수정이는 16.19초 걸렸다면 누구의 승리입니까?",
        "question_en": "Youngbin and Sujeong had a competition to pick up coins faster. If it took Yeongbin 16.23 seconds and Sujeong 16.19 seconds to pick up all the coins, who wins?",
        "answer_ko": "수정",
        "answer_en": "Sujeong",
        "solution_abst_ko": "[OP_LIST_SOL] 영빈 수정 [OP_LIST_EOL] [OP_LIST_SOL] 16.23 16.19 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Youngbin Sujeong [OP_LIST_EOL] [OP_LIST_SOL] 16.23 16.19 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '영빈'\nvar_b = '수정'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 16.23\nvar_d = 16.19\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Youngbin'\nvar_b = 'Sujeong'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 16.23\nvar_d = 16.19\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "642": {
        "category": "Arithmetic calculation",
        "question_ko": "튤립 56송이 중 파란색 튤립의 비율은 전체의 3/8입니다. 전체의 3/7이 빨간색 튤립이고 나머지는 분홍색이라면, 분홍색 튤립은 모두 몇 송이입니까?",
        "question_en": "The proportion of blue tulips is 3/8 of the 56 tulips. If 3/7 of the total are red tulips, and the others pink, how many pink tulips are there?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "1 3/7 [OP_SUB] 3/8 [OP_SUB] 50 [OP_MUL]",
        "solution_abst_en": "1 3/7 [OP_SUB] 3/8 [OP_SUB] 50 [OP_MUL]",
        "solution_code_ko": "var_a = 1\nvar_b = 0.42857142857142855\nvar_c = var_a - var_b\nvar_d = 0.375\nvar_e = var_c - var_d\nvar_f = 50\nvar_g = var_e * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 0.42857142857142855\nvar_c = var_a - var_b\nvar_d = 0.375\nvar_e = var_c - var_d\nvar_f = 50\nvar_g = var_e * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "643": {
        "category": "Geometry",
        "question_ko": "직육면체 밑면의 가로와 세로의 길이가 7센티미터(㎝), 6센티미터(㎝)일 때 부피가 16세제곱센티미터(㎤)이다. 겉넓이는 얼마인지 구하라.",
        "question_en": "The length and width of the base of a rectangular cuboid are 7 centimeters (cm) and 6 centimeters (cm) respectively, and the volume is 16 cubic centimeters (cm3). Find the value of the surface area.",
        "answer_ko": "93.90",
        "answer_en": "93.9",
        "solution_abst_ko": "16 7 [OP_DIV] 6 [OP_DIV] 7 6 [OP_ADD] [OP_MUL] 7 6 [OP_MUL] [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "16 7 [OP_DIV] 6 [OP_DIV] 7 6 [OP_ADD] [OP_MUL] 7 6 [OP_MUL] [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 16\nvar_b = 7\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c / var_d\nvar_f = 7\nvar_g = 6\nvar_h = var_f + var_g\nvar_i = var_e * var_h\nvar_j = 7\nvar_k = 6\nvar_l = var_j * var_k\nvar_m = var_i + var_l\nvar_n = 2\nvar_o = var_m * var_n\nprint('{:.2f}'.format(round(var_o+1e-10,2)))",
        "solution_code_en": "var_a = 16\nvar_b = 7\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c / var_d\nvar_f = 7\nvar_g = 6\nvar_h = var_f + var_g\nvar_i = var_e * var_h\nvar_j = 7\nvar_k = 6\nvar_l = var_j * var_k\nvar_m = var_i + var_l\nvar_n = 2\nvar_o = var_m * var_n\nprint('{:.2f}'.format(round(var_o+1e-10,2)))"
    },
    "644": {
        "category": "Possibility",
        "question_ko": "가현, 나현, 다현은 숫자 1, 6, 8을 한 번씩 모두 사용하여 세 자리 수를 만드는 게임을 한다. 가현이는 만들 수 있는 가장 큰 수를 만들었고 나현이는 두 번째로 큰 수를. 다현이는 세 번째로 큰 수를 만들었을 때 나현이가 만든 수와 다현이가 만든 수의 차이는 얼마인가?",
        "question_en": "Gahyeon, Nahyeon, and Dahyeon play a game of making a three-digit number using all the numbers 1, 6, and 8 at least once. Gahyeon made the biggest number possible, and Nahyeon made the second largest number. When Dahyun made the third largest number, what is the difference between the number Nahyeon and Dahyun made?",
        "answer_ko": "135",
        "answer_en": "135",
        "solution_abst_ko": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 3 [OP_LIST_MAX] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 3 [OP_LIST_MAX] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[-var_g]\nvar_i = var_f - var_h\nvar_j = abs(var_i)\nprint(int(var_j))",
        "solution_code_en": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[-var_g]\nvar_i = var_f - var_h\nvar_j = abs(var_i)\nprint(int(var_j))"
    },
    "645": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 서로 다른 막대 2개가 있습니다. 긴 막대의 길이는 짧은 막대의 길이보다 12센티미터(㎝) 더 길고, 두 막대의 길이의 합은 20센티미터(㎝)입니다. 긴 막대를 잘라 짧은 막대와 길이가 같은 막대를 몇 개 만들 수 있는지 구해보시오.",
        "question_en": "There are 2 bars of different lengths. The length of the long stick is 12 centimeters (cm) longer than the length of the short stick, and the sum of the lengths of the two sticks is 20 centimeters (cm). Find how many sticks the same length as the shorter sticks can be made by cutting the longer sticks.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "20 12 [OP_SUB] 2 [OP_DIV] 12 [OP_ADD] 20 12 [OP_SUB] 2 [OP_DIV] [OP_FDIV]",
        "solution_abst_en": "20 12 [OP_SUB] 2 [OP_DIV] 12 [OP_ADD] 20 12 [OP_SUB] 2 [OP_DIV] [OP_FDIV]",
        "solution_code_ko": "var_a = 20\nvar_b = 12\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 12\nvar_g = var_e + var_f\nvar_h = 20\nvar_i = 12\nvar_j = var_h - var_i\nvar_k = 2\nvar_l = var_j / var_k\nvar_m = var_g // var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 20\nvar_b = 12\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 12\nvar_g = var_e + var_f\nvar_h = 20\nvar_i = 12\nvar_j = var_h - var_i\nvar_k = 2\nvar_l = var_j / var_k\nvar_m = var_g // var_l\nprint(int(var_m))"
    },
    "646": {
        "category": "Geometry",
        "question_ko": "어떤 칠각형의 대각선의 개수를 A, 어떤 팔각형의 대각선의 개수를 B라 할 때, B-A의 값을 구하시오.",
        "question_en": "If A is the number of diagonals in a heptagon and B is the number of diagonals in an octagon, find the value of B-A.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "8 8 3 [OP_SUB] [OP_MUL] 2 [OP_DIV] 7 7 3 [OP_SUB] [OP_MUL] 2 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "8 8 3 [OP_SUB] [OP_MUL] 2 [OP_DIV] 7 7 3 [OP_SUB] [OP_MUL] 2 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 8\nvar_b = 8\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 7\nvar_i = 7\nvar_j = 3\nvar_k = var_i - var_j\nvar_l = var_h * var_k\nvar_m = 2\nvar_n = var_l / var_m\nvar_o = var_g - var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 8\nvar_b = 8\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 7\nvar_i = 7\nvar_j = 3\nvar_k = var_i - var_j\nvar_l = var_h * var_k\nvar_m = 2\nvar_n = var_l / var_m\nvar_o = var_g - var_n\nprint(int(var_o))"
    },
    "647": {
        "category": "Possibility",
        "question_ko": "4개의 숫자 카드 0, 1, 4, 8을 한 번씩 사용하여 십의 자리 숫자가 0인 세 자리 수의 개수를 구하시오.",
        "question_en": "Using the four number cards 0, 1, 4, and 8 once, find the number of three-digit numbers where the tens digit is zero.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 4 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 0 [OP_LIST_SEARCH_FIXED_DIGIT] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 4 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 0 [OP_LIST_SEARCH_FIXED_DIGIT] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 4\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 0\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = len(list_c)\nprint(int(var_h))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 4\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 0\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = len(list_c)\nprint(int(var_h))"
    },
    "648": {
        "category": "Geometry",
        "question_ko": "정우는 그리기 시간에 같은 넓이를 갖는 직사각형과 정사각형을 그렸습니다. 정우가 그린 직사각형의 두 변은 길이가 각각 9센티미터(㎝), 16센티미터(㎝)입니다. 정사각형의 한 변의 길이는 몇 센티미터(㎝)인가요?",
        "question_en": "Jungwoo drew a rectangle and a square with the same area during drawing time. The two sides of the rectangle drawn by JungWoo are 9 centimeters (cm) and 16 centimeters (cm), respectively. How many centimeters (cm) is the length of one side of the square?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "9 16 [OP_MUL] 1/2 [OP_POW]",
        "solution_abst_en": "9 16 [OP_MUL] 1/2 [OP_POW]",
        "solution_code_ko": "var_a = 9\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nprint(int(var_e))"
    },
    "649": {
        "category": "Comparison",
        "question_ko": "수애와 승호가 100미터(m) 달리기 시합을 하였습니다. 100미터(m) 를 달리는 데 수애는 16.23 초 걸렸고 승호는 16.19 초 걸렸다면 누가 더 빨리 달렸습니까?",
        "question_en": "Sooae and Seungho had a 100 meters (m) running race. If Sooae took 16.23 seconds and Seungho took 16.19 seconds to run 100 meters (m), who ran faster?",
        "answer_ko": "승호",
        "answer_en": "Seungho",
        "solution_abst_ko": "[OP_LIST_SOL] 수애 승호 [OP_LIST_EOL] [OP_LIST_SOL] 100 16.23 [OP_DIV] 100 16.19 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Sooae Seungho [OP_LIST_EOL] [OP_LIST_SOL] 100 16.23 [OP_DIV] 100 16.19 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '수애'\nvar_b = '승호'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 100\nvar_d = 16.23\nvar_e = var_c / var_d\nvar_f = 100\nvar_g = 16.19\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Sooae'\nvar_b = 'Seungho'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 100\nvar_d = 16.23\nvar_e = var_c / var_d\nvar_f = 100\nvar_g = 16.19\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "650": {
        "category": "Arithmetic calculation",
        "question_ko": "분모가 6인 진분수 중에서 가장 큰 진분수와 두 번째로 작은 진분수의 차는 얼마인지 답을 구해 보세요.",
        "question_en": "Find the difference between the largest proper fraction and the second smallest proper fraction with a denominator of 6.",
        "answer_ko": "0.5",
        "answer_en": "0.5",
        "solution_abst_ko": "1 5 1 [OP_LIST_ARANGE] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB] 6 [OP_DIV]",
        "solution_abst_en": "1 5 1 [OP_LIST_ARANGE] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB] 6 [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 5\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e - var_g\nvar_i = 6\nvar_j = var_h / var_i\nprint('{:.2f}'.format(round(var_j+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 5\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e - var_g\nvar_i = 6\nvar_j = var_h / var_i\nprint('{:.2f}'.format(round(var_j+1e-10,2)))"
    },
    "651": {
        "category": "Geometry",
        "question_ko": "직육면체에 대하여 한 모서리와 꼬인 위치에 있는 모서리의 개수를 구하시오.",
        "question_en": "For a cuboid, find the number of edges in skewed positions with one edge.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "4",
        "solution_abst_en": "4",
        "solution_code_ko": "var_a = 4\nprint(int(var_a))",
        "solution_code_en": "var_a = 4\nprint(int(var_a))"
    },
    "652": {
        "category": "Possibility",
        "question_ko": "동물원에 3마리의 팬더가 있습니다. 이 팬더들에게 적어도 2개 이상의 대나무를 준다고 할 때 대나무 20개를 나누어 주는 방법은 몇 가지인가요?",
        "question_en": "There are 3 pandas in the zoo. Let's say you give these pandas at least 2 bamboos. How many ways are there to distribute 20 bamboos?",
        "answer_ko": "560",
        "answer_en": "560",
        "solution_abst_ko": "20 3 2 [OP_MUL] [OP_SUB] 3 [OP_ADD] 1 [OP_SUB] 3 [OP_COMB]",
        "solution_abst_en": "20 3 2 [OP_MUL] [OP_SUB] 3 [OP_ADD] 1 [OP_SUB] 3 [OP_COMB]",
        "solution_code_ko": "var_a = 20\nvar_b = 3\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 3\nvar_g = var_e + var_f\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = 3\nvar_k = 1\nvar_i = int(var_i)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_i-i)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k / (i+1)\nprint(int(var_k))",
        "solution_code_en": "var_a = 20\nvar_b = 3\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 3\nvar_g = var_e + var_f\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = 3\nvar_k = 1\nvar_i = int(var_i)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_i-i)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k / (i+1)\nprint(int(var_k))"
    },
    "653": {
        "category": "Geometry",
        "question_ko": "동민이가 높이 53센티미터(㎝) 7밀리미터(㎜)인 의자에 올라서서 바닥에서부터 키를 재어 보면 190센티미터(㎝)가 되고, 책상 위에 올라서서 바닥에서부터 키를 재면 232센티미터(㎝) 5밀리미터(㎜)가 됩니다. 책상의 높이는 몇 센티미터(㎝)입니까?",
        "question_en": "If Dong-min stands on a chair with a height of 53 centimeters (cm) 7 millimeters (mm) and measures his height from the floor, he will be 190 centimeters (cm), and if he stands on a desk and measures his height from the floor, he will be 232 centimeters (cm) and 5 millimeters (mm). How tall is the desk?",
        "answer_ko": "96.20",
        "answer_en": "96.2",
        "solution_abst_ko": "232 5 10 [OP_DIV] [OP_ADD] 190 [OP_SUB] 53 7 10 [OP_DIV] [OP_ADD] [OP_ADD]",
        "solution_abst_en": "232 5 10 [OP_DIV] [OP_ADD] 190 [OP_SUB] 53 7 10 [OP_DIV] [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 232\nvar_b = 5\nvar_c = 10\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 190\nvar_g = var_e - var_f\nvar_h = 53\nvar_i = 7\nvar_j = 10\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_g + var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))",
        "solution_code_en": "var_a = 232\nvar_b = 5\nvar_c = 10\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 190\nvar_g = var_e - var_f\nvar_h = 53\nvar_i = 7\nvar_j = 10\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_g + var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))"
    },
    "654": {
        "category": "Arithmetic calculation",
        "question_ko": "굴비가 156두름 있습니다. 굴비는 모두 몇 마리 있나요? (한 두름은 20마리 입니다)",
        "question_en": "There are 156 dureums of gulbis. How many gulbis are there in all? (One dureum equals 20 fish)",
        "answer_ko": "3120",
        "answer_en": "3120",
        "solution_abst_ko": "156 20 [OP_MUL]",
        "solution_abst_en": "156 20 [OP_MUL]",
        "solution_code_ko": "var_a = 156\nvar_b = 20\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 156\nvar_b = 20\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "655": {
        "category": "Correspondence",
        "question_ko": "A888<5001에서 A에 1부터 9까지의 숫자를 쓰려고 합니다. A에 쓸 수 있는 숫자는 모두 몇 개입니까?",
        "question_en": "In A888<5001, you are going to write the numbers 1 through 9 in A. How many digits can you write in A?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "A888<5001 A [OP_DIGIT_UNK_SOLVER] [OP_LIST_LEN]",
        "solution_abst_en": "A888<5001 A [OP_DIGIT_UNK_SOLVER] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 'A888<5001'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = len(list_a)\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A888<5001'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = len(list_a)\nprint(int(var_c))"
    },
    "656": {
        "category": "Geometry",
        "question_ko": "트럭에 가로, 세로, 높이가 각각 350센티미터(㎝), 260센티미터(㎝), 165센티미터(㎝)이고, 두께가 5센티미터(㎝)인 직육면체 공간이 있다. 가로, 세로, 높이가 각각 1센티미터(㎝)인 박스 하나를 배송하면 1600원을 받는다고 할 때, 트럭을 박스로 가득 채워서 배송하면 얼마입니까?",
        "question_en": "In the truck, there is a cuboid space of 350 centimeters (cm) in width, 260 centimeters (cm) in depth, 165 centimeters (cm) in height, and 5 centimeters (cm) in thickness, respectively. If you receive 1,600 won for shipping a box measuring 1 centimeter (cm) in width, depth, and height, how much would it cost if the truck was shipped full of boxes?",
        "answer_ko": "21760000000",
        "answer_en": "21760000000",
        "solution_abst_ko": "350 5 2 [OP_MUL] [OP_SUB] 260 5 2 [OP_MUL] [OP_SUB] [OP_MUL] 165 5 [OP_SUB] [OP_MUL] 1600 [OP_MUL]",
        "solution_abst_en": "350 5 2 [OP_MUL] [OP_SUB] 260 5 2 [OP_MUL] [OP_SUB] [OP_MUL] 165 5 [OP_SUB] [OP_MUL] 1600 [OP_MUL]",
        "solution_code_ko": "var_a = 350\nvar_b = 5\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 260\nvar_g = 5\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = var_f - var_i\nvar_k = var_e * var_j\nvar_l = 165\nvar_m = 5\nvar_n = var_l - var_m\nvar_o = var_k * var_n\nvar_p = 1600\nvar_q = var_o * var_p\nprint(int(var_q))",
        "solution_code_en": "var_a = 350\nvar_b = 5\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 260\nvar_g = 5\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = var_f - var_i\nvar_k = var_e * var_j\nvar_l = 165\nvar_m = 5\nvar_n = var_l - var_m\nvar_o = var_k * var_n\nvar_p = 1600\nvar_q = var_o * var_p\nprint(int(var_q))"
    },
    "657": {
        "category": "Arithmetic calculation",
        "question_ko": "대현이와 동길이가 8일 동안 학교 청소를 했더니 전체 면적의 7/12에 해당하는 구역이 깨끗해졌습니다. 나머지 구역을 대현이가 혼자 청소했을 때 10일이 걸렸다면, 전체 구역을 동길이가 혼자 청소했을 때는 며칠이 걸렸을지 구하시오.",
        "question_en": "When Daehyeon and Donggil cleaned the school for 8 days, an area equivalent to 7/12 of the total area was cleaned. If it took 10 days for Daehyeon to clean the rest of the area by himself, how many days did it take for Donggil to clean the entire area alone?",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "1 7/12 8 [OP_DIV] 1 7/12 [OP_SUB] 10 [OP_DIV] [OP_SUB] [OP_DIV]",
        "solution_abst_en": "1 7/12 8 [OP_DIV] 1 7/12 [OP_SUB] 10 [OP_DIV] [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 0.5833333333333334\nvar_c = 8\nvar_d = var_b / var_c\nvar_e = 1\nvar_f = 0.5833333333333334\nvar_g = var_e - var_f\nvar_h = 10\nvar_i = var_g / var_h\nvar_j = var_d - var_i\nvar_k = var_a / var_j\nprint(int(eval('{:.2f}'.format(round(var_k+1e-10,2)))))",
        "solution_code_en": "var_a = 1\nvar_b = 0.5833333333333334\nvar_c = 8\nvar_d = var_b / var_c\nvar_e = 1\nvar_f = 0.5833333333333334\nvar_g = var_e - var_f\nvar_h = 10\nvar_i = var_g / var_h\nvar_j = var_d - var_i\nvar_k = var_a / var_j\nprint(int(eval('{:.2f}'.format(round(var_k+1e-10,2)))))"
    },
    "658": {
        "category": "Arithmetic calculation",
        "question_ko": "윤기는 호석이보다 2살 어리고, 윤기와 호석이의 나이를 합하면 18살이 됩니다. 윤기의 나이는 몇 살입니까?",
        "question_en": "Yoongi is 2 years younger than Hoseok, and together, Yoongi and Hoseok are 18 years old. How old is Yoongi?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "18 2 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "18 2 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 18\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 18\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "659": {
        "category": "Arithmetic calculation",
        "question_ko": "한 병에 242.7밀리리터(㎖) 가 담긴 음료수 병이 5병 있다. 음료수는 모두 몇 밀리리터(㎖)가 있는지 구하시오.",
        "question_en": "There are 5 bottles that each contains 242.7 milliliters (ml) of beverage. How many milliliters (ml) of beverage are there?",
        "answer_ko": "1213.50",
        "answer_en": "1213.5",
        "solution_abst_ko": "242.7 5 [OP_MUL]",
        "solution_abst_en": "242.7 5 [OP_MUL]",
        "solution_code_ko": "var_a = 242.7\nvar_b = 5\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 242.7\nvar_b = 5\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "660": {
        "category": "Possibility",
        "question_ko": "사과 7개를 서로 다른 2마리의 원숭이에게 나누어 주려고 합니다. 원숭이는 적어도 사과 1개는 받습니다. 사과를 나누어 주는 방법은 모두 몇 가지입니까?",
        "question_en": "You are planning to distribute 7 apples to 2 different monkeys. If the monkey must take at least 1 apple, how many cases are there to share apples?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "7 2 1 [OP_MUL] [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "7 2 1 [OP_MUL] [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 7\nvar_b = 2\nvar_c = 1\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 7\nvar_b = 2\nvar_c = 1\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "661": {
        "category": "Comparison",
        "question_ko": "20명의 학생들이 한줄로 섰습니다. 정국이는 3등으로 줄을 섰고, 윤기는 정국이 바로 앞에 섰습니다. 윤기 뒤에 서 있는 학생은 몇 명입니까?",
        "question_en": "20 students stood in a line. Jungkook stood in third place, and Yoongi stood right in front of Jungkook. How many students are standing behind Yoongi?",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "20 3 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "20 3 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 20\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "662": {
        "category": "Arithmetic calculation",
        "question_ko": "호석이네 학교에 있는 농구공은 축구공보다 23개 더 적고 축구공은 배구공보다 18개 더 많습니다. 배구공이 40개 있을 때, 농구공은 몇 개입니까?",
        "question_en": "There are 23 fewer basketballs at Hoseok's school than soccer balls, and 18 more soccer balls than volleyballs. If there are 40 volleyballs, how many basketballs are there?",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "40 18 [OP_ADD] 23 [OP_SUB]",
        "solution_abst_en": "40 18 [OP_ADD] 23 [OP_SUB]",
        "solution_code_ko": "var_a = 40\nvar_b = 18\nvar_c = var_a + var_b\nvar_d = 23\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 40\nvar_b = 18\nvar_c = var_a + var_b\nvar_d = 23\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "663": {
        "category": "Possibility",
        "question_ko": "세 개의 숫자 1, 2, 3을 중복 사용하여 네 자리 숫자를 만들 때, 합이 10이 되도록 만들 수 있는 경우는 모두 몇 가지인가?",
        "question_en": "When the three numbers 1, 2, and 3 are used repeatedly to form a four-digit number, how many ways can the sum be 10?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PRODUCT] [OP_LIST_NUM2SUM] 10 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PRODUCT] [OP_LIST_NUM2SUM] 10 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_f = 0\n    i = int(i)\n    while i//10 > 0:\n        var_f = var_f + i%10\n        i = i//10\n    var_f = var_f + i%10\n    list_c.append(var_f)\nvar_g = 10\nvar_h = 0\nvar_g = int(var_g)\nfor i in list_c:\n    i = int(i)\n    if i == var_g:\n        var_h = var_h + 1\nprint(int(var_h))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_f = 0\n    i = int(i)\n    while i//10 > 0:\n        var_f = var_f + i%10\n        i = i//10\n    var_f = var_f + i%10\n    list_c.append(var_f)\nvar_g = 10\nvar_h = 0\nvar_g = int(var_g)\nfor i in list_c:\n    i = int(i)\n    if i == var_g:\n        var_h = var_h + 1\nprint(int(var_h))"
    },
    "664": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이가 딴 감의 4배가 호석이가 딴 감에서 3개를 뺀 개수와 같다고 합니다. 호석이가 감을 35개 땄을 때 정국이가 딴 감은 몇 개입니까?",
        "question_en": "It is said that four times the number of persimmons Jungkook picked equals the number minus three persimmons picked by Hoseok. When Hoseok picked 35 persimmons, how many persimmons did Jungkook pick?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "35 3 [OP_SUB] 4 [OP_DIV]",
        "solution_abst_en": "35 3 [OP_SUB] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 35\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 35\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "665": {
        "category": "Possibility",
        "question_ko": "0, 3, 5, 7, 8 중에서 서로 다른 숫자 2개를 뽑아 만들 수 있는 두 자리 수 중에서 가장 큰 수와 가장 작은 수의 합을 구하시오.",
        "question_en": "Find the sum of the largest and smallest two-digit numbers that can be formed by drawing two different numbers from 0, 3, 5, 7, and 8.",
        "answer_ko": "117",
        "answer_en": "117",
        "solution_abst_ko": "[OP_LIST_SOL] 0 3 5 7 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 0 3 5 7 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 0\nvar_b = 3\nvar_c = 5\nvar_d = 7\nvar_e = 8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 0\nvar_b = 3\nvar_c = 5\nvar_d = 7\nvar_e = 8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h + var_j\nprint(int(var_k))"
    },
    "666": {
        "category": "Possibility",
        "question_ko": "4개의 숫자 1, 5, 6, 9를 한 번씩 사용하여 백의 자리 숫자가 5인 두 번째로 큰 세 자리 수를 구하시오.",
        "question_en": "Using the four digits 1, 5, 6, and 9 once, find the second largest three-digit number whose hundreds digit is 5.",
        "answer_ko": "591",
        "answer_en": "591",
        "solution_abst_ko": "[OP_LIST_SOL] 1 5 6 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 100 5 [OP_LIST_SEARCH_FIXED_DIGIT] 2 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1 5 6 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 100 5 [OP_LIST_SEARCH_FIXED_DIGIT] 2 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1\nvar_b = 5\nvar_c = 6\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 100\nvar_g = 5\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 2\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 5\nvar_c = 6\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 100\nvar_g = 5\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 2\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nprint(int(var_i))"
    },
    "667": {
        "category": "Possibility",
        "question_ko": "사과, 복숭아, 배, 참외, 딸기가 각각 하나씩 있는 바구니에서 2개를 뺐습니다. 바구니에 남아있는 과일의 경우의 수는 모두 몇 가지입니까?",
        "question_en": "Two were removed from a basket containing one each of apples, peaches, pears, melons, and strawberries. How many cases of fruit are left in the basket?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 복숭아 배 참외 딸기 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] apples peaches pears melons strawberries [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '복숭아'\nvar_c = '배'\nvar_d = '참외'\nvar_e = '딸기'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h / (i+1)\nprint(int(var_h))",
        "solution_code_en": "var_a = 'apples'\nvar_b = 'peaches'\nvar_c = 'pears'\nvar_d = 'melons'\nvar_e = 'strawberries'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h / (i+1)\nprint(int(var_h))"
    },
    "668": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 연속된 홀수의 합이 112입니다. 이 4개의 수 중에서 2번째로 작은 수를 쓰시오.",
        "question_en": "The sum of 4 consecutive odd numbers is 112. Write down the 2nd smallest of these 4 numbers.",
        "answer_ko": "27",
        "answer_en": "27",
        "solution_abst_ko": "112 4 [OP_DIV] 4 2 [OP_FDIV] 2 [OP_MUL] [OP_SUB] 1 [OP_ADD] 2 [OP_ADD]",
        "solution_abst_en": "112 4 [OP_DIV] 4 2 [OP_FDIV] 2 [OP_MUL] [OP_SUB] 1 [OP_ADD] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 112\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = 2\nvar_f = var_d // var_e\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_c - var_h\nvar_j = 1\nvar_k = var_i + var_j\nvar_l = 2\nvar_m = var_k + var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 112\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = 2\nvar_f = var_d // var_e\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_c - var_h\nvar_j = 1\nvar_k = var_i + var_j\nvar_l = 2\nvar_m = var_k + var_l\nprint(int(var_m))"
    },
    "669": {
        "category": "Correspondence",
        "question_ko": "등식 A5+2B=68이 성립한다고 합니다. 이 때, B에 들어갈 수 있는 숫자는 무엇인가요?",
        "question_en": "Given that the equation A5+2B=68 is true, what number can go in B?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "A5+2B=68 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A5+2B=68 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A5+2B=68'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A5+2B=68'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "670": {
        "category": "Comparison",
        "question_ko": "지석의 배낭 무게는 1.49킬로그램(㎏), 미호의 배낭 무게는 9/20킬로그램(㎏)이다. 누구의 배낭이 더 가볍습니까?",
        "question_en": "Jinseok's backpack weighs 1.49 kilograms (kg) and Miho's backpack weighs 9/20 kilograms (kg). Whose backpack is lighter?",
        "answer_ko": "미호",
        "answer_en": "Miho",
        "solution_abst_ko": "[OP_LIST_SOL] 지석 미호 [OP_LIST_EOL] [OP_LIST_SOL] 1.49 9/20 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jinseok Miho [OP_LIST_EOL] [OP_LIST_SOL] 1.49 9/20 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '지석'\nvar_b = '미호'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.49\nvar_d = 0.45\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Jinseok'\nvar_b = 'Miho'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.49\nvar_d = 0.45\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "671": {
        "category": "Geometry",
        "question_ko": "정사각형이 앞에서 4개, 위에서 3개, 옆에서 4개 보입니다. 정육면체는 몇 개 있을까요?",
        "question_en": "You see 4 squares from the front, 3 from the top, and 4 from the side. How many cubes are there?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "4 2 [OP_ADD]",
        "solution_abst_en": "4 2 [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "672": {
        "category": "Geometry",
        "question_ko": "가로가 80센티미터(㎝), 세로가 75센티미터(㎝), 높이가 120센티미터(㎝)인 직육면체의 가로, 세로, 높이를 각각 2배로 하여 만든 직육면체의 부피는 몇 세제곱미터(㎥)인지 답을 구해보세요.",
        "question_en": "How many cubic meters (m3) is the volume of a rectangular parallelepiped made by doubling the length, width, and height of a rectangular parallelepiped with a width of 80 centimeters (cm), a length of 75 centimeters (cm), and a height of 120 centimeters (cm)? Save it.",
        "answer_ko": "5.76",
        "answer_en": "5.76",
        "solution_abst_ko": "80 100 [OP_DIV] 2 [OP_MUL] 75 100 [OP_DIV] 2 [OP_MUL] 120 100 [OP_DIV] 2 [OP_MUL] [OP_MUL] [OP_MUL]",
        "solution_abst_en": "80 100 [OP_DIV] 2 [OP_MUL] 75 100 [OP_DIV] 2 [OP_MUL] 120 100 [OP_DIV] 2 [OP_MUL] [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 80\nvar_b = 100\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 75\nvar_g = 100\nvar_h = var_f / var_g\nvar_i = 2\nvar_j = var_h * var_i\nvar_k = 120\nvar_l = 100\nvar_m = var_k / var_l\nvar_n = 2\nvar_o = var_m * var_n\nvar_p = var_j * var_o\nvar_q = var_e * var_p\nprint('{:.2f}'.format(round(var_q+1e-10,2)))",
        "solution_code_en": "var_a = 80\nvar_b = 100\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 75\nvar_g = 100\nvar_h = var_f / var_g\nvar_i = 2\nvar_j = var_h * var_i\nvar_k = 120\nvar_l = 100\nvar_m = var_k / var_l\nvar_n = 2\nvar_o = var_m * var_n\nvar_p = var_j * var_o\nvar_q = var_e * var_p\nprint('{:.2f}'.format(round(var_q+1e-10,2)))"
    },
    "673": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 5를 뺀 것의 4배는 어떤 수와 같다. 어떤 수를 구하시오.",
        "question_en": "A number equals a number minus 5 and multiply it by 4. Find some number.",
        "answer_ko": "6.67",
        "answer_en": "6.67",
        "solution_abst_ko": "5 4 [OP_MUL] 4 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "5 4 [OP_MUL] 4 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 5\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 5\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "674": {
        "category": "Correspondence",
        "question_ko": "어머니는 매달 같은 양의 달걀을 사오신다. 지난달에 남은 달걀이 27개인데 어머니가 달걀을 사오신 후로 달걀이 58개가 되었다. 이번달에 48개의 달걀을 먹고 다음달에 어머니가 달걀을 사오신다면 달걀은 몇 개가 되겠는가?",
        "question_en": "My mother buys the same amount of eggs every month. There were 27 eggs left last month, but since my mother bought eggs, the number has increased to 58. If you eat 48 eggs this month and your mother buys eggs for the next month, how many eggs will there be?",
        "answer_ko": "41",
        "answer_en": "41",
        "solution_abst_ko": "58 48 [OP_SUB] 58 27 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "58 48 [OP_SUB] 58 27 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 58\nvar_b = 48\nvar_c = var_a - var_b\nvar_d = 58\nvar_e = 27\nvar_f = var_d - var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 58\nvar_b = 48\nvar_c = var_a - var_b\nvar_d = 58\nvar_e = 27\nvar_f = var_d - var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "675": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 공장에서 장난감을 만드는 데 (가) 기계는 1분에 8개씩 만들고, (나) 기계는 1분에 10개씩 만듭니다. 동시에 장난감을 만들기 시작하여 (나) 기계가 장난감을 100개 만들었다면, (가) 기계가 (나) 기계보다 장난감을 몇 개 더 적게 만들었는지 구하시오.",
        "question_en": "In a factory, machine A makes 8 toys per minute, and machine B makes 10 toys per minute. Provided that both machines started making toys at the same time and machine B made 100 toys, find how many fewer toys machine A made than machine B.",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "100 100 10 [OP_DIV] 8 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "100 100 10 [OP_DIV] 8 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 100\nvar_b = 100\nvar_c = 10\nvar_d = var_b / var_c\nvar_e = 8\nvar_f = var_d * var_e\nvar_g = var_a - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 100\nvar_b = 100\nvar_c = 10\nvar_d = var_b / var_c\nvar_e = 8\nvar_f = var_d * var_e\nvar_g = var_a - var_f\nprint(int(var_g))"
    },
    "676": {
        "category": "Geometry",
        "question_ko": "12/25센티미터(㎝) 길이의 실을 모두 사용하여 정사각형을 만들었습니다. 이 정사각형의 한 변의 길이는?",
        "question_en": "I used all the 12/25 centimeter (cm) lengths of yarn to make a square. What is the length of one side of this square?",
        "answer_ko": "0.12",
        "answer_en": "0.12",
        "solution_abst_ko": "12/25 4 [OP_DIV]",
        "solution_abst_en": "12/25 4 [OP_DIV]",
        "solution_code_ko": "var_a = 0.48\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 0.48\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "677": {
        "category": "Comparison",
        "question_ko": "판자 (가)는 2.4센티미터(㎝), 판자 (나)는 3.2센티미터(㎝), 판자 (다)는 2.8센티미터(㎝)이다. 은지, 남준, 호석은 각각 (가)판자 8개, (나)판자 4개, (다)판자 5개를 쌓은 곳 위에 서 있따. 누가 가장 낮은 곳에 있는가?",
        "question_en": "The length of board A is 2.4 centimeters (cm), board B is 3.2 centimeters (cm), and board C is 2.8 centimeters (cm). When Eunji, Namjoon, and Hoseok are standing on top of 8 A boards, 4 B boards, and 5 C boards, respectively, find who is at the lowest.",
        "answer_ko": "남준",
        "answer_en": "Namjoon",
        "solution_abst_ko": "[OP_LIST_SOL] 은지 남준 호석 [OP_LIST_EOL] [OP_LIST_SOL] 2.4 8 [OP_MUL] 3.2 4 [OP_MUL] 2.8 5 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Eunji Namjoon Hoseok [OP_LIST_EOL] [OP_LIST_SOL] 2.4 8 [OP_MUL] 3.2 4 [OP_MUL] 2.8 5 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '은지'\nvar_b = '남준'\nvar_c = '호석'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2.4\nvar_e = 8\nvar_f = var_d * var_e\nvar_g = 3.2\nvar_h = 4\nvar_i = var_g * var_h\nvar_j = 2.8\nvar_k = 5\nvar_l = var_j * var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[var_m-1]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'Eunji'\nvar_b = 'Namjoon'\nvar_c = 'Hoseok'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2.4\nvar_e = 8\nvar_f = var_d * var_e\nvar_g = 3.2\nvar_h = 4\nvar_i = var_g * var_h\nvar_j = 2.8\nvar_k = 5\nvar_l = var_j * var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[var_m-1]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "678": {
        "category": "Geometry",
        "question_ko": "직육면체 모양의 나무토막이 있습니다. 이 나무토막의 높이는 3.5m입니다. 밑몉에 평행한 방향으로 두 번 잘라 세 부분으로 나누면 겉넓이가 144제곱센티미터(㎠) 만큼 늘어난다면 이 나무토막의 부피는 몇 세제곱센티미터(㎤)입니까?",
        "question_en": "There is a block of wood in the shape of a cuboid, and it has a height of 3.5 meters (m). What is the volume in cubic centimeters (cm3) of this block of wood if the surface area is increased by 144 square centimeters (cm2) when divided into three parts by making two cuts parallel to the base?",
        "answer_ko": "12600",
        "answer_en": "12600",
        "solution_abst_ko": "144 4 [OP_DIV] 3.5 100 [OP_MUL] [OP_MUL]",
        "solution_abst_en": "144 4 [OP_DIV] 3.5 100 [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 144\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 3.5\nvar_e = 100\nvar_f = var_d * var_e\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 144\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 3.5\nvar_e = 100\nvar_f = var_d * var_e\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "679": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 70센티미터(㎝)인 끈이 있었습니다. 이 중에서 27센티미터(㎝)는 민영이에게 주고 나머지의 7/9은 (가)를 만드는 데 사용하였습니다. 남은 끈의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "There was a string that was 70 centimeters (cm) long. Of these, 27 centimeters (cm) was given to Minyoung, and 7/9 of the remaining was used to make (A). How many centimeters (cm) is the length of the remaining string?",
        "answer_ko": "9.56",
        "answer_en": "9.56",
        "solution_abst_ko": "70 27 [OP_SUB] 1 7/9 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "70 27 [OP_SUB] 1 7/9 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 70\nvar_b = 27\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = 0.7777777777777778\nvar_f = var_d - var_e\nvar_g = var_c * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 70\nvar_b = 27\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = 0.7777777777777778\nvar_f = var_d - var_e\nvar_g = var_c * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "680": {
        "category": "Possibility",
        "question_ko": "꽃꽂이를 위해 4송이의 장미와 3송이의 튤립 중에서 각각 1송이씩을 선택해 꽂으려 한다. 꽃꽂이를 할 때, 장미와 튤립 중에서 어느 하나만 서로 같은 꽃을 선택하는 경우의 수는?",
        "question_en": "For the flower arrangement, you will pick one of four roses and one of three tulips and arrange them. When arranging flowers, how many cases are there where you pick only one of the roses and tulips the same?",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "4 3 2 [OP_PERM] [OP_MUL] 3 4 2 [OP_PERM] [OP_MUL] [OP_ADD]",
        "solution_abst_en": "4 3 2 [OP_PERM] [OP_MUL] 3 4 2 [OP_PERM] [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 3\nvar_c = 2\nvar_d = 1\nvar_b = int(var_b)\nvar_c = int(var_c)\nfor i, elem in enumerate(range(var_c)):\n    var_d = var_d * (var_b-i)\nvar_e = var_a * var_d\nvar_f = 3\nvar_g = 4\nvar_h = 2\nvar_i = 1\nvar_g = int(var_g)\nvar_h = int(var_h)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i * (var_g-i)\nvar_j = var_f * var_i\nvar_k = var_e + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 4\nvar_b = 3\nvar_c = 2\nvar_d = 1\nvar_b = int(var_b)\nvar_c = int(var_c)\nfor i, elem in enumerate(range(var_c)):\n    var_d = var_d * (var_b-i)\nvar_e = var_a * var_d\nvar_f = 3\nvar_g = 4\nvar_h = 2\nvar_i = 1\nvar_g = int(var_g)\nvar_h = int(var_h)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i * (var_g-i)\nvar_j = var_f * var_i\nvar_k = var_e + var_j\nprint(int(var_k))"
    },
    "681": {
        "category": "Geometry",
        "question_ko": "가영이는 한 모서리의 길이가 20센티미터(㎝)인 정육면체 모양의 상자를 가지고 있습니다. 이 상자의 겉넓이는 얼마입니까?",
        "question_en": "Gayoung has a cube-shaped box with one corner measuring 20 centimeters (cm). What is the surface area of this box?",
        "answer_ko": "2400",
        "answer_en": "2400",
        "solution_abst_ko": "20 2 [OP_POW] 6 [OP_MUL]",
        "solution_abst_en": "20 2 [OP_POW] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 20\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "682": {
        "category": "Possibility",
        "question_ko": "A, B, C, D, E, F 6명의 백성이 있을 때, 신하 2명, 왕 1명을 뽑는 경우의 수를 구하시오.",
        "question_en": "If there are 6 people A, B, C, D, E, and F, find the number of ways to select 2 subjects and 1 king.",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "[OP_LIST_SOL] A B C D E F [OP_LIST_EOL] [OP_LIST_LEN] 2 1 [OP_ADD] [OP_PERM] 2 2 [OP_PERM] [OP_DIV]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D E F [OP_LIST_EOL] [OP_LIST_LEN] 2 1 [OP_ADD] [OP_PERM] 2 2 [OP_PERM] [OP_DIV]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nvar_f = 'F'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = len(list_a)\nvar_h = 2\nvar_i = 1\nvar_j = var_h + var_i\nvar_k = 1\nvar_g = int(var_g)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_g-i)\nvar_l = 2\nvar_m = 2\nvar_n = 1\nvar_l = int(var_l)\nvar_m = int(var_m)\nfor i, elem in enumerate(range(var_m)):\n    var_n = var_n * (var_l-i)\nvar_o = var_k / var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nvar_f = 'F'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = len(list_a)\nvar_h = 2\nvar_i = 1\nvar_j = var_h + var_i\nvar_k = 1\nvar_g = int(var_g)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_g-i)\nvar_l = 2\nvar_m = 2\nvar_n = 1\nvar_l = int(var_l)\nvar_m = int(var_m)\nfor i, elem in enumerate(range(var_m)):\n    var_n = var_n * (var_l-i)\nvar_o = var_k / var_n\nprint(int(var_o))"
    },
    "683": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이네 반 학생 28명은 체육 시간에 짝짓기 놀이를 하였습니다. 5명씩 짝짓기를 하여 남은 학생을 뺀 다음 다시 7명씩 짝짓기를 하고 남은 학생을 뺐습니다. 빠진 학생은 모두 몇 명인지 구하시오.",
        "question_en": "The 28 students in Jungkook's class played matching games during PE class. We paired them up in groups of 5, subtracted the remaining students, then paired them in groups of 7, and subtracted the remaining students. Find how many students are excluded.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "28 5 [OP_MOD] 28 28 5 [OP_MOD] [OP_SUB] 7 [OP_MOD] [OP_ADD]",
        "solution_abst_en": "28 5 [OP_MOD] 28 28 5 [OP_MOD] [OP_SUB] 7 [OP_MOD] [OP_ADD]",
        "solution_code_ko": "var_a = 28\nvar_b = 5\nvar_c = var_a % var_b\nvar_d = 28\nvar_e = 28\nvar_f = 5\nvar_g = var_e % var_f\nvar_h = var_d - var_g\nvar_i = 7\nvar_j = var_h % var_i\nvar_k = var_c + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 28\nvar_b = 5\nvar_c = var_a % var_b\nvar_d = 28\nvar_e = 28\nvar_f = 5\nvar_g = var_e % var_f\nvar_h = var_d - var_g\nvar_i = 7\nvar_j = var_h % var_i\nvar_k = var_c + var_j\nprint(int(var_k))"
    },
    "684": {
        "category": "Possibility",
        "question_ko": "5, 2, 8 세 장의 수 카드를 한 번씩만 사용하여 세 자리 수를 만들려고 합니다. 만들 수 있는 가장 큰 수와 가장 작은 수의 차를 구해 보시오.",
        "question_en": "You are trying to create a three-digit number using three number cards of 5, 2, and 8 only once. Find the difference between the largest number and the smallest number that can be made.",
        "answer_ko": "594",
        "answer_en": "594",
        "solution_abst_ko": "[OP_LIST_SOL] 5 2 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 5 2 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))"
    },
    "685": {
        "category": "Arithmetic calculation",
        "question_ko": "수빈이는 아버지와 함께 뒷산에 올라 밤을 따고 이 밤을 8 바구니에 똑같이 나누어 담으려 하였습니다. 그런데 산을 올라가는 도중 2개의 바구니가 망가져서 한 바구니에 1개씩 밤을 더 담았더니 4개가 남았습니다. 수빈이와 아버지가 함께 딴 밤은 모두 몇 개입니까?",
        "question_en": "Subin climbed a mountain with her father to pick chestnuts and wanted to divide them into 8 baskets equally. However, on the way up the mountain, two baskets were broken, so she put one more chestnut in each basket, and there were four left. How many chestnuts did Subin and her father pick?",
        "answer_ko": "40",
        "answer_en": "40",
        "solution_abst_ko": "8 2 [OP_SUB] 4 [OP_ADD] 8 8 2 [OP_SUB] [OP_SUB] [OP_FDIV] 8 [OP_MUL]",
        "solution_abst_en": "8 2 [OP_SUB] 4 [OP_ADD] 8 8 2 [OP_SUB] [OP_SUB] [OP_FDIV] 8 [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = 8\nvar_h = 2\nvar_i = var_g - var_h\nvar_j = var_f - var_i\nvar_k = var_e // var_j\nvar_l = 8\nvar_m = var_k * var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 8\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = 8\nvar_h = 2\nvar_i = var_g - var_h\nvar_j = var_f - var_i\nvar_k = var_e // var_j\nvar_l = 8\nvar_m = var_k * var_l\nprint(int(var_m))"
    },
    "686": {
        "category": "Arithmetic calculation",
        "question_ko": "한 개의 무게가 0.36킬로그램(㎏) 인 배가 30 개 들어 있는 바구니의 무게는 11.26킬로그램(㎏) 입니다. 바구니만의 무게는 몇 킬로그램(㎏) 입니까?",
        "question_en": "A basket containing 30 pears each weighing 0.36 kilograms (kg) weighs 11.26 kilograms (kg). How many kilograms (kg) does the basket weigh alone?",
        "answer_ko": "0.46",
        "answer_en": "0.46",
        "solution_abst_ko": "11.26 0.36 30 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "11.26 0.36 30 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 11.26\nvar_b = 0.36\nvar_c = 30\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 11.26\nvar_b = 0.36\nvar_c = 30\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "687": {
        "category": "Correspondence",
        "question_ko": "진범이는 12개의 큰 딱지와 34개의 작은 딱지를 가지고 있었다. 진범이는 딱지치기를 하다가 몇 개의 큰 딱지와 그것의 3배 만큼의 작은 딱지를 잃었다. 진범이가 현재 가진 딱지의 개수가 모두 30개일 때, 진범이가 잃은 큰 딱지의 개수는 몇 개인가?",
        "question_en": "Jinbeom had 12 large and 34 small ttakji. Jinbeom lost several large ttakji and three times as many small ones as he was playing a game of ttakji-chigi. If the number of ttakji Jinbeom currently has is 30, how many large ttakji did Jinbeom lose?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "12 34 [OP_ADD] 30 [OP_SUB] 1 3 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "12 34 [OP_ADD] 30 [OP_SUB] 1 3 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 34\nvar_c = var_a + var_b\nvar_d = 30\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = 3\nvar_h = var_f + var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 12\nvar_b = 34\nvar_c = var_a + var_b\nvar_d = 30\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = 3\nvar_h = var_f + var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "688": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 63미터(m)인 도로에 4.5미터(m) 간격으로 가로수를 심으려고 합니다. 시작 부분과 끝 부분에 모두 가로수를 심는다면 모두 몇 그루가 필요합니까?",
        "question_en": "Street trees are to be planted at intervals of 4.5 meters (m) on a road with a length of 63 meters (m). If you plant street trees both at the beginning and at the end, how many trees will you need in total?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "63 4.5 [OP_FDIV] 1 [OP_ADD]",
        "solution_abst_en": "63 4.5 [OP_FDIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 63\nvar_b = 4.5\nvar_c = var_a // var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 63\nvar_b = 4.5\nvar_c = var_a // var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "689": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 2.3미터(m)인 정팔각형의 모든 변의 길이의 합은 몇 센티미터(㎝)입니까?",
        "question_en": "How many centimeters (cm) is the sum of all the side lengths of a regular octagon with a side length of 2.3 meters (m)?",
        "answer_ko": "1840",
        "answer_en": "1840",
        "solution_abst_ko": "2.3 100 [OP_MUL] 8 [OP_MUL]",
        "solution_abst_en": "2.3 100 [OP_MUL] 8 [OP_MUL]",
        "solution_code_ko": "var_a = 2.3\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c * var_d\nprint(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))",
        "solution_code_en": "var_a = 2.3\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c * var_d\nprint(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))"
    },
    "690": {
        "category": "Geometry",
        "question_ko": "가로가 7센티미터(㎝), 세로가 5센티미터(㎝)인 직사각형과 둘레의 길이가 같은 정사각형의 한 변의 길이를 구하시오.",
        "question_en": "Find the length of one side of a square whose perimeter is the same as that of a rectangle whose sides are 7 centimeters (cm) long and 5 centimeters (cm) wide.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "7 5 [OP_ADD] 2 [OP_MUL] 4 [OP_DIV]",
        "solution_abst_en": "7 5 [OP_ADD] 2 [OP_MUL] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 7\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 7\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "691": {
        "category": "Arithmetic calculation",
        "question_ko": "구슬이 담긴 주머니가 있습니다. 이 주머니의 무게가 3.4킬로그램(㎏)이고 구슬의 1/5를 뺀 후 주머니의 무게는 2.98킬로그램(㎏)입니다. 빈 주머니의 무게는 몇 킬로그램(㎏)인지 구하세요.",
        "question_en": "There is a bag with marbles in it. The weight of this bag is 3.4 kilograms (kg), and after taking out 1/5 of the marbles, the bag weighs 2.98 kilograms (kg). Find the weight in kilograms (kg) of the empty bag.",
        "answer_ko": "1.30",
        "answer_en": "1.3",
        "solution_abst_ko": "3.4 3.4 2.98 [OP_SUB] 1/5 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "3.4 3.4 2.98 [OP_SUB] 1/5 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 3.4\nvar_b = 3.4\nvar_c = 2.98\nvar_d = var_b - var_c\nvar_e = 0.2\nvar_f = var_d / var_e\nvar_g = var_a - var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 3.4\nvar_b = 3.4\nvar_c = 2.98\nvar_d = var_b - var_c\nvar_e = 0.2\nvar_f = var_d / var_e\nvar_g = var_a - var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "692": {
        "category": "Geometry",
        "question_ko": "잭과 콩나무라는 동화에는 잭이 콩나무를 타고 기어올라가는 장면이 나옵니다. 잭은 낮에 25미터(m)를 기어올라가고 밤에 3미터(m)를 미끄러져 내려옵니다. 잭이 64일째 낮에 25미터(m)를 기어올라 하늘섬에 도착했다면 하늘섬의 높이는 몇 미터(m)인지 구하시오.",
        "question_en": "In the fairy tale Jack and the Beanstalk, there is a scene where Jack climbs the beanstalk. Jack climbs 25 meters (m) during the day and slides down 3 meters (m) at night. If Jack climbed 25 meters (m) during the day on the 64th day and reached the sky island, find the height in meters (m) of the sky island.",
        "answer_ko": "1411",
        "answer_en": "1411",
        "solution_abst_ko": "25 64 [OP_MUL] 3 64 1 [OP_SUB] [OP_MUL] [OP_SUB]",
        "solution_abst_en": "25 64 [OP_MUL] 3 64 1 [OP_SUB] [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 25\nvar_b = 64\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = 64\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_c - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 25\nvar_b = 64\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = 64\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_c - var_h\nprint(int(var_i))"
    },
    "693": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.9 중에서 0.4보다 크거나 같은 수를 모두 더하면 얼마일까요?",
        "question_en": "What is the sum of all numbers greater than or equal to 0.4 among 0.8, 1/2, and 0.9?",
        "answer_ko": "2.20",
        "answer_en": "2.2",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 0.4 [OP_LIST_MORE_EQUAL] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 0.4 [OP_LIST_MORE_EQUAL] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.4\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.4\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "694": {
        "category": "Arithmetic calculation",
        "question_ko": "하은이의 키는 1.56미터(m)입니다. 나연이는 하은이보다 0.14 미터(m) 작고 민경보다 0.27 미터(m) 작다고 합니다. 민경이의 키는 몇 미터(m)입니까?",
        "question_en": "Haeun is 1.56 meters (m) tall. Nayeon is 0.14 meters (m) shorter than Haeun and 0.27 meters (m) shorter than Minkyung. How tall is Minkyung in meters (m)?",
        "answer_ko": "1.69",
        "answer_en": "1.69",
        "solution_abst_ko": "1.56 0.14 [OP_SUB] 0.27 [OP_ADD]",
        "solution_abst_en": "1.56 0.14 [OP_SUB] 0.27 [OP_ADD]",
        "solution_code_ko": "var_a = 1.56\nvar_b = 0.14\nvar_c = var_a - var_b\nvar_d = 0.27\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 1.56\nvar_b = 0.14\nvar_c = var_a - var_b\nvar_d = 0.27\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "695": {
        "category": "Correspondence",
        "question_ko": "20에 어떤 수를 빼려고 합니다. 잘못하여 40에 어떤 수를 나누었더니 결과는 5가 되었습니다. 바르게 계산한 결과는 얼마일까요?",
        "question_en": "You want to subtract a number from 20. When you mistakenly divide 40 by a number, the result is 5. What is the correct calculation result?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "20 40 5 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "20 40 5 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 40\nvar_c = 5\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 40\nvar_c = 5\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "696": {
        "category": "Arithmetic calculation",
        "question_ko": "둘레가 200미터(m)인 운동장 트랙을 따라 20미터(m) 간격으로 깃발을 꽂으려고 합니다. 준비된 깃발이 12개라면, 깃발은 몇 개 남습니까? 또, 부족하다면 몇 개 부족합니까?",
        "question_en": "You want to plant flags at intervals of 20 meters (m) along a playground track with a circumference of 200 meters (m). If there are 12 flags ready, how many flags are left? Also, if it/s not enough, how many are insufficient?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "12 200 20 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "12 200 20 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 12\nvar_b = 200\nvar_c = 20\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 200\nvar_c = 20\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "697": {
        "category": "Comparison",
        "question_ko": "동균이는 하루에 운동장을 8바퀴씩 4번 돌고, 희진이는 하루에 운동장을 5/7바퀴씩 10번 돕니다. 누가 더 운동장을 많이 도는지 구하시오",
        "question_en": "Dongkyun runs 8 laps around the playground 4 times a day, and Heejin runs 5/7 laps 10 times a day. Find who runs the playground more.",
        "answer_ko": "동균",
        "answer_en": "Dongkyun",
        "solution_abst_ko": "[OP_LIST_SOL] 동균 희진 [OP_LIST_EOL] [OP_LIST_SOL] 8 4 [OP_MUL] 5/7 10 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Dongkyun Heejin [OP_LIST_EOL] [OP_LIST_SOL] 8 4 [OP_MUL] 5/7 10 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '동균'\nvar_b = '희진'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 8\nvar_d = 4\nvar_e = var_c * var_d\nvar_f = 0.7142857142857143\nvar_g = 10\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Dongkyun'\nvar_b = 'Heejin'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 8\nvar_d = 4\nvar_e = var_c * var_d\nvar_f = 0.7142857142857143\nvar_g = 10\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "698": {
        "category": "Comparison",
        "question_ko": "4개의 숫자 0.8, 1/2, 0.9, 1/3가 있습니다. 3보다 작은 수는 몇 개입니까?",
        "question_en": "There are four numbers 0.8, 1/2, 0.9, and 1/3. How many numbers are less than 3?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 3 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 3 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = []\nfor i in list_a:\n    if i < var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = []\nfor i in list_a:\n    if i < var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "699": {
        "category": "Correspondence",
        "question_ko": "A는 742입니다. A는 B보다 397만큼 작습니다. B는 C보다 693만큼 큽니다. A-C의 값을 구하시오.",
        "question_en": "A is 742. A is 397 less than B. B is 693 greater than C. Find the value of A-C.",
        "answer_ko": "296",
        "answer_en": "296",
        "solution_abst_ko": "742 742 397 [OP_ADD] 693 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "742 742 397 [OP_ADD] 693 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 742\nvar_b = 742\nvar_c = 397\nvar_d = var_b + var_c\nvar_e = 693\nvar_f = var_d - var_e\nvar_g = var_a - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 742\nvar_b = 742\nvar_c = 397\nvar_d = var_b + var_c\nvar_e = 693\nvar_f = var_d - var_e\nvar_g = var_a - var_f\nprint(int(var_g))"
    },
    "700": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 20미터(m)인 구름 열차가 1초에 288센티미터(㎝)씩 달리고 있습니다. 이 열차가 터널을 완전히 통과하는 데 25초가 걸렸다면 터널의 길이는 몇 미터(m)인지 구해 보시오.",
        "question_en": "A cloud train with a length of 20 meters (m) is running at 288 centimeters (cm) per second. If this train took 25 seconds to completely pass the tunnel, find the length of the tunnel in meters (m).",
        "answer_ko": "52",
        "answer_en": "52",
        "solution_abst_ko": "288 100 [OP_DIV] 25 [OP_MUL] 20 [OP_SUB]",
        "solution_abst_en": "288 100 [OP_DIV] 25 [OP_MUL] 20 [OP_SUB]",
        "solution_code_ko": "var_a = 288\nvar_b = 100\nvar_c = var_a / var_b\nvar_d = 25\nvar_e = var_c * var_d\nvar_f = 20\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 288\nvar_b = 100\nvar_c = var_a / var_b\nvar_d = 25\nvar_e = var_c * var_d\nvar_f = 20\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "701": {
        "category": "Possibility",
        "question_ko": "4개의 숫자 1, 2, 3, 4 중에서 중복을 허락하여 3개를 택해 일렬로 나열하여 세 자리의 자연수를 만들 때, 3으로 나눠 떨어지는 수의 개수는?",
        "question_en": "Suppose you make a three-digit natural number by selecting three of the four numbers 1, 2, 3, and 4 and arranging them in a row. How many numbers are divisible by 3?",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "[OP_LIST_SOL] 1 2 3 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 2 3 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 2\nvar_c = 3\nvar_d = 4\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c = []\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nvar_g = len(list_c)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 2\nvar_c = 3\nvar_d = 4\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c = []\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nvar_g = len(list_c)\nprint(int(var_g))"
    },
    "702": {
        "category": "Geometry",
        "question_ko": "철수네 학급 친구 9명이 구각형 모양으로 서로 마주 보고 서 있습니다. 모든 학생이 자신의 양옆 사람을 제외하고 다른 친구들과 한 번씩 가위바위보를 한다면, 가위바위보는 모두 몇 번 이루어지는지 구하시오.",
        "question_en": "Cheolsu's nine classmates are standing in a nonagonal shape facing each other. If every student plays rock-paper-scissors once with everyone except for the person next to him/her, how many times do all students play rock-paper-scissors?",
        "answer_ko": "27",
        "answer_en": "27",
        "solution_abst_ko": "9 9 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "9 9 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 9\nvar_b = 9\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 9\nvar_b = 9\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "703": {
        "category": "Arithmetic calculation",
        "question_ko": "중국여행을 위해 17만원을 환전하려고 합니다. 중국 돈 1위안은 우리나라 돈 161.5원입니다. 1000위안과 10위안짜리로 바꾸려하고 1000위안짜리를 가능한 만큼 많이 바꾼다면 10위안으로 바꿔지는 돈은 몇 장인지 구하세요.",
        "question_en": "I would like to exchange 170,000 won for a trip to China. One Chinese yuan equals 161.5 won in Korean won. If you want to exchange 1000 yuan and 10 yuan bills, and you change as many 1000 yuan bills as possible, find how many bills will be converted into 10 yuan bills.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "17 10000 [OP_MUL] 161.5 1000 [OP_MUL] [OP_MOD] 161.5 10 [OP_MUL] [OP_FDIV]",
        "solution_abst_en": "17 10000 [OP_MUL] 161.5 1000 [OP_MUL] [OP_MOD] 161.5 10 [OP_MUL] [OP_FDIV]",
        "solution_code_ko": "var_a = 17\nvar_b = 10000\nvar_c = var_a * var_b\nvar_d = 161.5\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = var_c % var_f\nvar_h = 161.5\nvar_i = 10\nvar_j = var_h * var_i\nvar_k = var_g // var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 17\nvar_b = 10000\nvar_c = var_a * var_b\nvar_d = 161.5\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = var_c % var_f\nvar_h = 161.5\nvar_i = 10\nvar_j = var_h * var_i\nvar_k = var_g // var_j\nprint(int(var_k))"
    },
    "704": {
        "category": "Correspondence",
        "question_ko": "지훈이가 계산을 하다 7을 곱할 것을 실수하여 뺐더니 0.45가 되었다. 지훈이가 원래 찾던 답이 얼마인지 구하시오.",
        "question_en": "Ji-hoon made a mistake while calculating and subtracted 7 from a number instead of multiplying by 7, and it became 0.45. Find out the answer Jihoon was originally looking for.",
        "answer_ko": "52.15",
        "answer_en": "52.15",
        "solution_abst_ko": "0.45 7 [OP_ADD] 7 [OP_MUL]",
        "solution_abst_en": "0.45 7 [OP_ADD] 7 [OP_MUL]",
        "solution_code_ko": "var_a = 0.45\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 7\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.45\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 7\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "705": {
        "category": "Comparison",
        "question_ko": "재호와 경환은 같은 시간 동안 산책을 했습니다. 재호는 10.2킬로미터(㎞)의 1/100의 거리를 걸었고 경환은 100미터(m)의 거리를 걸었습니다. 재호와 경환이 중 누가 더 많은 거리를 걸었습니까?",
        "question_en": "Jaeho and Kyunghwan took a walk for the same amount of time. Jaeho walked a distance of 1/100 of 10.2 kilometers (km), and Kyunghwan walked a distance of 100 meters (m). Who walked more distances, Jaeho or Kyunghwan?",
        "answer_ko": "재호",
        "answer_en": "Jaeho",
        "solution_abst_ko": "[OP_LIST_SOL] 재호 경환 [OP_LIST_EOL] [OP_LIST_SOL] 10.2 1000 [OP_MUL] 1/100 [OP_MUL] 100 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jaeho Kyunghwan [OP_LIST_EOL] [OP_LIST_SOL] 10.2 1000 [OP_MUL] 1/100 [OP_MUL] 100 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '재호'\nvar_b = '경환'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10.2\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 0.01\nvar_g = var_e * var_f\nvar_h = 100\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Jaeho'\nvar_b = 'Kyunghwan'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10.2\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 0.01\nvar_g = var_e * var_f\nvar_h = 100\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "706": {
        "category": "Geometry",
        "question_ko": "꼭짓점, 면, 모서리의 수의 합이 50개인 각기둥이 있습니다. 이 각기둥과 밑면의 모양이 같은 각뿔의 모서리의 수는 몇 개입니까?",
        "question_en": "There is a prism with a sum of the number of vertices, faces, and corners is 50. How many edges of the pyramid have the same base shape as the prism?",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "50 2 [OP_SUB] 2 3 [OP_ADD] 1 [OP_ADD] [OP_DIV] 2 [OP_MUL]",
        "solution_abst_en": "50 2 [OP_SUB] 2 3 [OP_ADD] 1 [OP_ADD] [OP_DIV] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 50\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = var_c / var_h\nvar_j = 2\nvar_k = var_i * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 50\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = var_c / var_h\nvar_j = 2\nvar_k = var_i * var_j\nprint(int(var_k))"
    },
    "707": {
        "category": "Possibility",
        "question_ko": "1부터 9까지의 숫자가 적힌 9개의 숫자 카드가 있습니다. 3장의 카드를 뽑아 합이 17이 되도록 하는 방법의 수는?",
        "question_en": "There are 9 number cards with the numbers 1 through 9 written on them. In how many ways can you draw 3 cards so that the sum is 17?",
        "answer_ko": "42",
        "answer_en": "42",
        "solution_abst_ko": "1 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 17 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 17 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 17\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 17\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))"
    },
    "708": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 수의 7배에서 6을 뺀 수는 어떤 수의 4배보다 12만큼 클 때, 어떤 수를 구하시오.",
        "question_en": "Find the certain number if the certain number multiplied by 7 minus 6 equals the certain number multiplied by 4 plus 12.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "12 6 [OP_ADD] 7 4 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "12 6 [OP_ADD] 7 4 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 7\nvar_e = 4\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 12\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 7\nvar_e = 4\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))"
    },
    "709": {
        "category": "Arithmetic calculation",
        "question_ko": "준호네 집 마당에 강아지 3마리와 병아리 7마리가 놀고 있습니다. 강아지와 병아리의 다리 수를 합하면 모두 몇 개인지 구하세요.",
        "question_en": "3 puppies and 7 chicks are playing in the yard of Junho's house. Find how many legs the puppies and chicks have together.",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "3 4 [OP_MUL] 7 2 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "3 4 [OP_MUL] 7 2 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 3\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "710": {
        "category": "Possibility",
        "question_ko": "귤 2개, 오렌지 3개를 한 줄로 세워 전시할 때, 귤끼리는 반드시 이웃하게 세우는 경우의 수를 구하시오.",
        "question_en": "When displaying 2 tangerines and 3 oranges in a line, find the number of cases where the tangerines must be placed next to each other.",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "1 3 [OP_ADD] 1 3 [OP_ADD] [OP_PERM] 2 2 [OP_PERM] [OP_MUL]",
        "solution_abst_en": "1 3 [OP_ADD] 1 3 [OP_ADD] [OP_PERM] 2 2 [OP_PERM] [OP_MUL]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = 1\nvar_c = int(var_c)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_c-i)\nvar_h = 2\nvar_i = 2\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nvar_k = var_g * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = 1\nvar_c = int(var_c)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_c-i)\nvar_h = 2\nvar_i = 2\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nvar_k = var_g * var_j\nprint(int(var_k))"
    },
    "711": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 10, 11, 12, 13이 있습니다. 그 중에서 가장 큰 수와 그 다음으로 큰 수로 나눈 값은 얼마입니까?",
        "question_en": "Find the largest number divided by the next largest number among 4 numbers: 10, 11, 12, and 13.",
        "answer_ko": "1.08",
        "answer_en": "1.08",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_DIV]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = var_f / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = var_f / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "712": {
        "category": "Arithmetic calculation",
        "question_ko": "바닥에 128개의 동전들이 널려있다. 앞면인 동전이 뒷면인 동전보다 12개 더 많다면, 앞면인 동전은 모두 몇 개입니까?",
        "question_en": "128 coins are scattered on the floor. If there are 12 more coins that are heads than coins that are tails, how many coins are heads?",
        "answer_ko": "70",
        "answer_en": "70",
        "solution_abst_ko": "128 12 [OP_SUB] 2 [OP_DIV] 12 [OP_ADD]",
        "solution_abst_en": "128 12 [OP_SUB] 2 [OP_DIV] 12 [OP_ADD]",
        "solution_code_ko": "var_a = 128\nvar_b = 12\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 12\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 128\nvar_b = 12\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 12\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "713": {
        "category": "Arithmetic calculation",
        "question_ko": "넓이가 2.4제곱미터(㎡)인 화단의 1/3에 장미를 심고, 나머지의 1/4에 튤립을 심었습니다. 튤립이 심어진 부분의 넓이를 구하시오.",
        "question_en": "Roses were planted in one-third of the 2.4 square meters (m2) flower bed, and tulips were planted in the remaining one-quarter. Find the area of the area where the tulips are planted.",
        "answer_ko": "0.40",
        "answer_en": "0.4",
        "solution_abst_ko": "2.4 1 1/3 [OP_SUB] [OP_MUL] 1/4 [OP_MUL]",
        "solution_abst_en": "2.4 1 1/3 [OP_SUB] [OP_MUL] 1/4 [OP_MUL]",
        "solution_code_ko": "var_a = 2.4\nvar_b = 1\nvar_c = 0.3333333333333333\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 0.25\nvar_g = var_e * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 2.4\nvar_b = 1\nvar_c = 0.3333333333333333\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 0.25\nvar_g = var_e * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "714": {
        "category": "Possibility",
        "question_ko": "5, 9, 2 중에서 한 번씩만 사용하여 세 자리 수를 만들려고 합니다. 만든 두 수의 차가 가장 크게 될 때, 그 차를 구하시오.",
        "question_en": "You want to create a three-digit number using 5, 9, and 2 once. When the difference between the two numbers made is the largest, find the difference.",
        "answer_ko": "693",
        "answer_en": "693",
        "solution_abst_ko": "[OP_LIST_SOL] 5 9 2 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "[OP_LIST_SOL] 5 9 2 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 5\nvar_b = 9\nvar_c = 2\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f - var_h\nvar_j = abs(var_i)\nprint(int(var_j))",
        "solution_code_en": "var_a = 5\nvar_b = 9\nvar_c = 2\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f - var_h\nvar_j = abs(var_i)\nprint(int(var_j))"
    },
    "715": {
        "category": "Geometry",
        "question_ko": "빨간색 색종이는 한 변의 길이가 11센티미터(㎝)인 정사각형 모양이고, 파란색 색종이는 한 변의 길이가 5센티미터(㎝)인 정사각형 모양입니다. 두 색종이의 넓이의 합은 몇 제곱센티미터(㎠)일까요?",
        "question_en": "The red confetti has a square shape with a side length of 11 centimeters (cm), and the blue confetti has a square shape with a side length of 5 centimeters (cm). What is the sum of the areas of the two pieces of colored paper in square centimeters (cm2)?",
        "answer_ko": "146",
        "answer_en": "146",
        "solution_abst_ko": "11 2 [OP_POW] 5 2 [OP_POW] [OP_ADD]",
        "solution_abst_en": "11 2 [OP_POW] 5 2 [OP_POW] [OP_ADD]",
        "solution_code_ko": "var_a = 11\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 11\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "716": {
        "category": "Arithmetic calculation",
        "question_ko": "지하 3미터(m)에 있던 풍선이 하늘로 올라간 지 4초만에 지상에 도착했다고 합니다. 풍선이 지상 0.09 킬로미터(㎞)를 넘어가면 터진다고 할 때, 풍선이 같은 속도로 움직인다면 하늘로 올라간 지 몇 초 후에 터지겠습니까?",
        "question_en": "It is said that the balloon 3 meters (m) underground reached the ground in 4 seconds after it went into the air. Assuming that the balloon pops when it travels 0.09 kilometers (km) above the ground, how many seconds after it rises into the sky will it burst, if the balloon moves at the same speed?",
        "answer_ko": "124",
        "answer_en": "124",
        "solution_abst_ko": "0.09 1000 [OP_MUL] 3 [OP_ADD] 3 [OP_DIV] 4 [OP_MUL]",
        "solution_abst_en": "0.09 1000 [OP_MUL] 3 [OP_ADD] 3 [OP_DIV] 4 [OP_MUL]",
        "solution_code_ko": "var_a = 0.09\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = 4\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 0.09\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = 4\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "717": {
        "category": "Arithmetic calculation",
        "question_ko": "교실에 남학생 3명과 여학생 10명이 더 들어와서 여학생이 모두 22명이 되었습니다. 처음에 남학생이 여학생보다 5명 많이 있었다고 할때 현재 교실에 남아있는 남학생은 모두 몇명입니까?",
        "question_en": "Three more boys and 10 girls entered the class, and now the total number of girls became 22. If there were 5 more boys than girls initially, how many boys are still in the classroom?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "22 10 [OP_SUB] 5 [OP_ADD] 3 [OP_ADD]",
        "solution_abst_en": "22 10 [OP_SUB] 5 [OP_ADD] 3 [OP_ADD]",
        "solution_code_ko": "var_a = 22\nvar_b = 10\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 22\nvar_b = 10\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "718": {
        "category": "Arithmetic calculation",
        "question_ko": "민이네 학교 3학년 학생이 현장 체험 학습을가려고 15인승 버스 18대에 나누어 탔습니다.버스마다 3자리씩 비어 있다면 민이네 학교 3학년 학생은 모두 몇 명입니까?",
        "question_en": "3rd grade students from Min's school split into 18 15-seater buses to go on a field trip. If 3 seats are empty in each bus, how many 3rd grade students are there at Min's school?",
        "answer_ko": "216",
        "answer_en": "216",
        "solution_abst_ko": "15 3 [OP_SUB] 18 [OP_MUL]",
        "solution_abst_en": "15 3 [OP_SUB] 18 [OP_MUL]",
        "solution_code_ko": "var_a = 15\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 18\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 18\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "719": {
        "category": "Correspondence",
        "question_ko": "홀수를 1에서 100까지 쓸 때 숫자 9가 몇번 등장합니까?",
        "question_en": "How many times does the figure '9' appear in odd numbers from 1 to 100?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "1 100 [OP_LIST_ODD] [OP_LIST2NUM] [OP_NUM2LIST] 9 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 100 [OP_LIST_ODD] [OP_LIST2NUM] [OP_NUM2LIST] 9 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 100\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c=\"\"\nfor i in list_a:\n    i = str(i)\n    var_c = var_c + i\nlist_b = []\nvar_c = int(var_c)\nwhile var_c//10 > 0:\n    list_b.append(var_c%10)\n    var_c = var_c//10\nlist_b.append(var_c%10)\nlist_b = list_b[::-1]\nvar_d = 9\nvar_e = 0\nvar_d = int(var_d)\nfor i in list_b:\n    i = int(i)\n    if i == var_d:\n        var_e = var_e + 1\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 100\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c=\"\"\nfor i in list_a:\n    i = str(i)\n    var_c = var_c + i\nlist_b = []\nvar_c = int(var_c)\nwhile var_c//10 > 0:\n    list_b.append(var_c%10)\n    var_c = var_c//10\nlist_b.append(var_c%10)\nlist_b = list_b[::-1]\nvar_d = 9\nvar_e = 0\nvar_d = int(var_d)\nfor i in list_b:\n    i = int(i)\n    if i == var_d:\n        var_e = var_e + 1\nprint(int(var_e))"
    },
    "720": {
        "category": "Possibility",
        "question_ko": "A, B, C, D, E, F 6명의 학생이 있을 때, 대표 2명, 총무 1명을 뽑는 경우의 수를 구하시오.",
        "question_en": "If there are 6 students A, B, C, D, E, and F, find the number of ways to select 2 representatives and 1 secretary.",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "[OP_LIST_SOL] A B C D E F [OP_LIST_EOL] [OP_LIST_LEN] 2 1 [OP_ADD] [OP_PERM] 2 2 [OP_PERM] [OP_DIV]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D E F [OP_LIST_EOL] [OP_LIST_LEN] 2 1 [OP_ADD] [OP_PERM] 2 2 [OP_PERM] [OP_DIV]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nvar_f = 'F'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = len(list_a)\nvar_h = 2\nvar_i = 1\nvar_j = var_h + var_i\nvar_k = 1\nvar_g = int(var_g)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_g-i)\nvar_l = 2\nvar_m = 2\nvar_n = 1\nvar_l = int(var_l)\nvar_m = int(var_m)\nfor i, elem in enumerate(range(var_m)):\n    var_n = var_n * (var_l-i)\nvar_o = var_k / var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nvar_f = 'F'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = len(list_a)\nvar_h = 2\nvar_i = 1\nvar_j = var_h + var_i\nvar_k = 1\nvar_g = int(var_g)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_g-i)\nvar_l = 2\nvar_m = 2\nvar_n = 1\nvar_l = int(var_l)\nvar_m = int(var_m)\nfor i, elem in enumerate(range(var_m)):\n    var_n = var_n * (var_l-i)\nvar_o = var_k / var_n\nprint(int(var_o))"
    },
    "721": {
        "category": "Arithmetic calculation",
        "question_ko": "올해 윤기와 호석이의 나이를 더하면 16살입니다. 호석이는 윤기보다 2살 더 적습니다. 올해 윤기의 나이는 몇 살입니까?",
        "question_en": "If you add up Yoongi and Hoseok's ages this year, it is 16. Hoseok is 2 years younger than Yoongi. How old is Yoongi this year?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "16 2 [OP_SUB] 2 [OP_DIV] 2 [OP_ADD]",
        "solution_abst_en": "16 2 [OP_SUB] 2 [OP_DIV] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 16\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 16\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "722": {
        "category": "Correspondence",
        "question_ko": "네 자리 수 4A8B은 93의 배수이다. 이때 A+B의 값을 구하여라.",
        "question_en": "The four-digit number 4A8B is a multiple of 93. Find the value of A+B at this time.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "4A8B [OP_GEN_POSSIBLE_LIST] 93 [OP_LIST_DIVISIBLE] 4A8B A [OP_LIST_FIND_UNK] 4A8B B [OP_LIST_FIND_UNK] [OP_ADD]",
        "solution_abst_en": "4A8B [OP_GEN_POSSIBLE_LIST] 93 [OP_LIST_DIVISIBLE] 4A8B A [OP_LIST_FIND_UNK] 4A8B B [OP_LIST_FIND_UNK] [OP_ADD]",
        "solution_code_ko": "var_a = '4A8B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 93\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = '4A8B'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nvar_e = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_e = int(elem[unk_idx])\nvar_f = '4A8B'\nvar_g = 'B'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nvar_i = var_e + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = '4A8B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 93\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = '4A8B'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nvar_e = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_e = int(elem[unk_idx])\nvar_f = '4A8B'\nvar_g = 'B'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nvar_i = var_e + var_h\nprint(int(var_i))"
    },
    "723": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 2를 더한 후 3을 뺐더니 7이 되었습니다. 어떤 수를 구하시오.",
        "question_en": "When you add 2 to a number and then subtract 3, you get 7. Find out this number",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "7 3 [OP_ADD] 2 [OP_SUB]",
        "solution_abst_en": "7 3 [OP_ADD] 2 [OP_SUB]",
        "solution_code_ko": "var_a = 7\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 7\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "724": {
        "category": "Arithmetic calculation",
        "question_ko": "1킬로미터(㎞)를 가는 데 0.08리터(L)의 휘발유를 사용하는 자동차를 이용하여 1시간에 80킬로미터(㎞)를 움직이는 빠르기로 2시간 36분을 이동하였을 때, 사용한 휘발유는 몇 리터(L)입니까?",
        "question_en": "When traveling for 2 hours and 36 minutes at a speed of 80 kilometers (km) per hour using a car that uses 0.08 liters (L) of gasoline to travel 1 kilometer (km), how many liters (L) of gasoline are used?",
        "answer_ko": "16.64",
        "answer_en": "16.64",
        "solution_abst_ko": "0.08 80 2 36 60 [OP_DIV] [OP_ADD] [OP_MUL] [OP_MUL]",
        "solution_abst_en": "0.08 80 2 36 60 [OP_DIV] [OP_ADD] [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 0.08\nvar_b = 80\nvar_c = 2\nvar_d = 36\nvar_e = 60\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nvar_h = var_b * var_g\nvar_i = var_a * var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 0.08\nvar_b = 80\nvar_c = 2\nvar_d = 36\nvar_e = 60\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nvar_h = var_b * var_g\nvar_i = var_a * var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "725": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이네 반에 안경을 쓴 학생이 9명, 안경을 쓰지 않은 학생이 16명입니다. 정국이네 반 학생은 모두 몇 명입니까?",
        "question_en": "In Jungkook's class, there are 9 students who wear glasses and 16 students who do not wear glasses. How many students are there?",
        "answer_ko": "25",
        "answer_en": "25",
        "solution_abst_ko": "16 9 [OP_ADD]",
        "solution_abst_en": "16 9 [OP_ADD]",
        "solution_code_ko": "var_a = 16\nvar_b = 9\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 16\nvar_b = 9\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "726": {
        "category": "Geometry",
        "question_ko": "가로, 세로, 높이가 1센티미터(㎝)인 레고를 가로로 7줄, 세로로 5줄, 높이를 3층으로 쌓아 올렸다면 전체 부피는 얼마인지 구하시오.",
        "question_en": "Find the total volume if you stack 7 rows, 5 columns, and 3 layers of Legos, each measuring 1 centimeter (cm) in length, width, and height.",
        "answer_ko": "105",
        "answer_en": "105",
        "solution_abst_ko": "1 7 [OP_MUL] 1 5 [OP_MUL] [OP_MUL] 1 3 [OP_MUL] [OP_MUL]",
        "solution_abst_en": "1 7 [OP_MUL] 1 5 [OP_MUL] [OP_MUL] 1 3 [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 1\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = var_c * var_f\nvar_h = 1\nvar_i = 3\nvar_j = var_h * var_i\nvar_k = var_g * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 1\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = var_c * var_f\nvar_h = 1\nvar_i = 3\nvar_j = var_h * var_i\nvar_k = var_g * var_j\nprint(int(var_k))"
    },
    "727": {
        "category": "Possibility",
        "question_ko": "숫자 카드 0, 1, 2, 4, 9 중에서 3장을 뽑아 만들 수 있는 자연수의 개수를 구하시오.",
        "question_en": "Find the number of natural numbers that can be made by drawing three of the number cards 0, 1, 2, 4, and 9.",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 4 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 4 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 4\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 4\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "728": {
        "category": "Correspondence",
        "question_ko": "네 자리 수 중 십의 자리 수가 A인 수가 있습니다. 이 네 자리 수 중 천, 백, 일의 자리 수가 1, 8, 4인 18A4가 1853보다 작다면 A에 쓸 수 있는 숫자는 모두 몇 개입니까?",
        "question_en": "There is a four-digit number that has A in the tens place. If the thousands, hundreds, and ones place of this four-digit number are 1, 8, and 4, and it is less than 1853, how many digits can be written in A in 18A4?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "18A4 [OP_GEN_POSSIBLE_LIST] 1853 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "18A4 [OP_GEN_POSSIBLE_LIST] 1853 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '18A4'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 1853\nlist_b = []\nfor i in list_a:\n    if i < var_b:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))",
        "solution_code_en": "var_a = '18A4'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 1853\nlist_b = []\nfor i in list_a:\n    if i < var_b:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))"
    },
    "729": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 2.95를 두 번 빼었더니 9.28이 되었습니다. 어떤 수를 구하시오.",
        "question_en": "Subtracting 2.95 twice from a number gives 9.28. Find this number.",
        "answer_ko": "15.18",
        "answer_en": "15.18",
        "solution_abst_ko": "9.28 2.95 [OP_ADD] 2.95 [OP_ADD]",
        "solution_abst_en": "9.28 2.95 [OP_ADD] 2.95 [OP_ADD]",
        "solution_code_ko": "var_a = 9.28\nvar_b = 2.95\nvar_c = var_a + var_b\nvar_d = 2.95\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 9.28\nvar_b = 2.95\nvar_c = var_a + var_b\nvar_d = 2.95\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "730": {
        "category": "Geometry",
        "question_ko": "부피가 576세제곱센티미터(㎤) 삼각기둥에 밑면인 삼각형의 넓이는 3제곱센티미터(㎠)다. 이 삼각기중의 높이의 절반은 몇 센티미터(㎝) 얼마입니까?",
        "question_en": "The area of the base triangle of a triangular prism with a volume of 576 cubic centimeters (cm3) is 3 square centimeters (cm2). How many centimeters (cm) is half of the height of this triangular prisim?",
        "answer_ko": "96",
        "answer_en": "96",
        "solution_abst_ko": "576 3 [OP_DIV] 2 [OP_DIV]",
        "solution_abst_en": "576 3 [OP_DIV] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 576\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 576\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "731": {
        "category": "Possibility",
        "question_ko": "동전 2개와 주사위 1개를 동시에 던질 때, 두 동전은 같은 면이 나오고 주사위의 눈은 3의 배수인 경우의 수는?",
        "question_en": "When 2 coins and 1 dice are tossed at the same time, in how many ways can both coins come up equal and the dice roll is a multiple of 3?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "2 1 6 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] [OP_MUL]",
        "solution_abst_en": "2 1 6 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 1\nvar_c = 6\nvar_d = 1\nlist_a = [i for i in range(var_b, var_c + 1, var_d)]\nvar_e = 3\nlist_b = []\nvar_e = int(var_e)\nfor i in list_a:\n    i = int(i)\n    if i % var_e == 0:\n        list_b.append(i)\nvar_f = len(list_b)\nvar_g = var_a * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 2\nvar_b = 1\nvar_c = 6\nvar_d = 1\nlist_a = [i for i in range(var_b, var_c + 1, var_d)]\nvar_e = 3\nlist_b = []\nvar_e = int(var_e)\nfor i in list_a:\n    i = int(i)\n    if i % var_e == 0:\n        list_b.append(i)\nvar_f = len(list_b)\nvar_g = var_a * var_f\nprint(int(var_g))"
    },
    "732": {
        "category": "Arithmetic calculation",
        "question_ko": "민영이와 호석이는 각각 돈을 150만원씩 가지고 있었습니다. 민영이는 돈을 32만원 더 벌고, 호석이는 49만원을 더 벌었다면, 호석이가 가진 돈은 민영이보다 얼마 더 많습니까?",
        "question_en": "Min-young and Hoseok each had 1.5 million won of money. If Minyoung earns 320,000 won more and Hoseok earns 490,000 won more, how much more money does Hoseok have than Minyoung?",
        "answer_ko": "170000",
        "answer_en": "170000",
        "solution_abst_ko": "150 49 [OP_ADD] 150 32 [OP_ADD] [OP_SUB] 10000 [OP_MUL]",
        "solution_abst_en": "150 49 [OP_ADD] 150 32 [OP_ADD] [OP_SUB] 10000 [OP_MUL]",
        "solution_code_ko": "var_a = 150\nvar_b = 49\nvar_c = var_a + var_b\nvar_d = 150\nvar_e = 32\nvar_f = var_d + var_e\nvar_g = var_c - var_f\nvar_h = 10000\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 150\nvar_b = 49\nvar_c = var_a + var_b\nvar_d = 150\nvar_e = 32\nvar_f = var_d + var_e\nvar_g = var_c - var_f\nvar_h = 10000\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "733": {
        "category": "Arithmetic calculation",
        "question_ko": "석기네 식구가 하루 동안 마시는 물의 양은 3리터(L) 200밀리리터(㎖)입니다. 이 중에서 석기와 아버지가 하루 동안 마시는 물의 양은 1리터(L) 100밀리리터(㎖)이고, 모든 식구가 매일 같은 양의 물을 마신다면 석기와 아버지를 제외한 나머지 식구들이 2주일 동안 마시는 물의 양은 몇 리터(L)입니까?",
        "question_en": "The amount of water that Seokgi's family drinks during the day are 3 liters (L) and 200 milliliters (㎖). If out of this, the amount of water Seokgi and his father drink per day is 1 liter (L) and 100 milliliters (㎖) and every member drinks the same amount of water daily, how many liters (L) of water do the other members except Seokgi and his father drink for 2 weeks?",
        "answer_ko": "29.40",
        "answer_en": "29.4",
        "solution_abst_ko": "3 200 1000 [OP_DIV] [OP_ADD] 1 100 1000 [OP_DIV] [OP_ADD] [OP_SUB] 2 7 [OP_MUL] [OP_MUL]",
        "solution_abst_en": "3 200 1000 [OP_DIV] [OP_ADD] 1 100 1000 [OP_DIV] [OP_ADD] [OP_SUB] 2 7 [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 200\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 1\nvar_g = 100\nvar_h = 1000\nvar_i = var_g / var_h\nvar_j = var_f + var_i\nvar_k = var_e - var_j\nvar_l = 2\nvar_m = 7\nvar_n = var_l * var_m\nvar_o = var_k * var_n\nprint('{:.2f}'.format(round(var_o+1e-10,2)))",
        "solution_code_en": "var_a = 3\nvar_b = 200\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 1\nvar_g = 100\nvar_h = 1000\nvar_i = var_g / var_h\nvar_j = var_f + var_i\nvar_k = var_e - var_j\nvar_l = 2\nvar_m = 7\nvar_n = var_l * var_m\nvar_o = var_k * var_n\nprint('{:.2f}'.format(round(var_o+1e-10,2)))"
    },
    "734": {
        "category": "Comparison",
        "question_ko": "B를 2배하고 4를 더한 수가 C이고 A를 3으로 나눈 몫은 B입니다. A는 8에 9를 곱하고 3을 뺀 수라고 할 때 가장 큰 수와 가장 작은 수의 합을 구하시오.",
        "question_en": "Double B plus 4 is C, and the quotient of A divided by 3 is B. When A is 8 multiplied by 9 minus 3. Find the sum of the largest number and the smallest number.",
        "answer_ko": "92",
        "answer_en": "92",
        "solution_abst_ko": "[OP_LIST_SOL] 8 9 [OP_MUL] 3 [OP_SUB] 8 9 [OP_MUL] 3 [OP_SUB] 3 [OP_DIV] 8 9 [OP_MUL] 3 [OP_SUB] 3 [OP_DIV] 2 [OP_MUL] 4 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] 3 [OP_LIST_MAX] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 8 9 [OP_MUL] 3 [OP_SUB] 8 9 [OP_MUL] 3 [OP_SUB] 3 [OP_DIV] 8 9 [OP_MUL] 3 [OP_SUB] 3 [OP_DIV] 2 [OP_MUL] 4 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] 3 [OP_LIST_MAX] [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = 9\nvar_h = var_f * var_g\nvar_i = 3\nvar_j = var_h - var_i\nvar_k = 3\nvar_l = var_j / var_k\nvar_m = 8\nvar_n = 9\nvar_o = var_m * var_n\nvar_p = 3\nvar_q = var_o - var_p\nvar_r = 3\nvar_s = var_q / var_r\nvar_t = 2\nvar_u = var_s * var_t\nvar_v = 4\nvar_w = var_u + var_v\nlist_a= []\nif \"/\" in str(var_w):\n    var_w = eval(str(var_w))\nlist_a.append(var_w)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_a.append(var_l)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nlist_a.reverse()\nvar_x = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_y = list_b[-var_x]\nvar_z = 3\nlist_c=list_a.copy()\nlist_c.sort()\nvar_A = list_c[-var_z]\nvar_B = var_y + var_A\nprint(int(var_B))",
        "solution_code_en": "var_a = 8\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = 9\nvar_h = var_f * var_g\nvar_i = 3\nvar_j = var_h - var_i\nvar_k = 3\nvar_l = var_j / var_k\nvar_m = 8\nvar_n = 9\nvar_o = var_m * var_n\nvar_p = 3\nvar_q = var_o - var_p\nvar_r = 3\nvar_s = var_q / var_r\nvar_t = 2\nvar_u = var_s * var_t\nvar_v = 4\nvar_w = var_u + var_v\nlist_a= []\nif \"/\" in str(var_w):\n    var_w = eval(str(var_w))\nlist_a.append(var_w)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_a.append(var_l)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nlist_a.reverse()\nvar_x = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_y = list_b[-var_x]\nvar_z = 3\nlist_c=list_a.copy()\nlist_c.sort()\nvar_A = list_c[-var_z]\nvar_B = var_y + var_A\nprint(int(var_B))"
    },
    "735": {
        "category": "Comparison",
        "question_ko": "기린의 키는 2.3미터(m), 아기의 키는 9/10미터(m), 고릴라의 키는 1.8미터(m), 공룡의 키는 2.5미터(m)입니다. 두 번째로 키가 큰 생물은 무엇입니까?",
        "question_en": "A giraffe is 2.3 meters (m) tall, a baby is 9/10 meters (m) tall, a gorilla is 1.8 meters (m) tall, and a dinosaur is 2.5 meters (m) tall. What is the second tallest creature?",
        "answer_ko": "기린",
        "answer_en": "giraffe",
        "solution_abst_ko": "[OP_LIST_SOL] 기린 아기 고릴라 공룡 [OP_LIST_EOL] [OP_LIST_SOL] 2.3 9/10 1.8 2.5 [OP_LIST_EOL] 2 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] giraffe baby gorilla dinosaur [OP_LIST_EOL] [OP_LIST_SOL] 2.3 9/10 1.8 2.5 [OP_LIST_EOL] 2 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '기린'\nvar_b = '아기'\nvar_c = '고릴라'\nvar_d = '공룡'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2.3\nvar_f = 0.9\nvar_g = 1.8\nvar_h = 2.5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'giraffe'\nvar_b = 'baby'\nvar_c = 'gorilla'\nvar_d = 'dinosaur'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2.3\nvar_f = 0.9\nvar_g = 1.8\nvar_h = 2.5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "736": {
        "category": "Comparison",
        "question_ko": "버스는 시속 92킬로미터(㎞)로 달리고, 택시는 분속 1500미터(m)로 달립니다. 버스와 택시 중 속력이 더 빠른 것은 무엇입니까?",
        "question_en": "Buses run at 92 kilometers (km) per hour, and taxis run at 1500 meters (m) per minute. Which of the buses or taxis is faster?",
        "answer_ko": "버스",
        "answer_en": "buses",
        "solution_abst_ko": "[OP_LIST_SOL] 버스 택시 [OP_LIST_EOL] [OP_LIST_SOL] 92 1500 1000 [OP_DIV] 60 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] buses taxis [OP_LIST_EOL] [OP_LIST_SOL] 92 1500 1000 [OP_DIV] 60 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '버스'\nvar_b = '택시'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 92\nvar_d = 1500\nvar_e = 1000\nvar_f = var_d / var_e\nvar_g = 60\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'buses'\nvar_b = 'taxis'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 92\nvar_d = 1500\nvar_e = 1000\nvar_f = var_d / var_e\nvar_g = 60\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "737": {
        "category": "Correspondence",
        "question_ko": "5.46에 어떤 수를 더해야 할 것을 잘못하여 뺐더니 3.97이 되었습니다. 바르게 계산한 결과를 구하시오.",
        "question_en": "I mistakenly subtracted a certain number that should have been added to 5.46, and the result was 3.97. Find the result of the correct calculation.",
        "answer_ko": "6.95",
        "answer_en": "6.95",
        "solution_abst_ko": "5.46 5.46 3.97 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "5.46 5.46 3.97 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 5.46\nvar_b = 5.46\nvar_c = 3.97\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 5.46\nvar_b = 5.46\nvar_c = 3.97\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "738": {
        "category": "Arithmetic calculation",
        "question_ko": "나누는 수의 십의 자리 숫자와 일의 자리 숫자를 바꾸어 잘못 보고 나눗셈을 계산하였더니 계산한 몫과 나머지가 각각 25이었습니다. 나누는 수가 65일 때, 바르게 계산한 몫과 나머지의 합을 구하시오.",
        "question_en": "When the division was calculated by changing the tens and units digits of the divisor, the quotient and remainder were 25 each. When the divisor is 65, find the sum of the correctly calculated quotient and remainder.",
        "answer_ko": "81",
        "answer_en": "81",
        "solution_abst_ko": "56 25 [OP_MUL] 25 [OP_ADD] 65 [OP_FDIV] 56 25 [OP_MUL] 25 [OP_ADD] 65 [OP_MOD] [OP_ADD]",
        "solution_abst_en": "56 25 [OP_MUL] 25 [OP_ADD] 65 [OP_FDIV] 56 25 [OP_MUL] 25 [OP_ADD] 65 [OP_MOD] [OP_ADD]",
        "solution_code_ko": "var_a = 56\nvar_b = 25\nvar_c = var_a * var_b\nvar_d = 25\nvar_e = var_c + var_d\nvar_f = 65\nvar_g = var_e // var_f\nvar_h = 56\nvar_i = 25\nvar_j = var_h * var_i\nvar_k = 25\nvar_l = var_j + var_k\nvar_m = 65\nvar_n = var_l % var_m\nvar_o = var_g + var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 56\nvar_b = 25\nvar_c = var_a * var_b\nvar_d = 25\nvar_e = var_c + var_d\nvar_f = 65\nvar_g = var_e // var_f\nvar_h = 56\nvar_i = 25\nvar_j = var_h * var_i\nvar_k = 25\nvar_l = var_j + var_k\nvar_m = 65\nvar_n = var_l % var_m\nvar_o = var_g + var_n\nprint(int(var_o))"
    },
    "739": {
        "category": "Possibility",
        "question_ko": "강아지 2마리, 고양이 3마리를 한 줄로 세워 사진을 찍고자 할 때, 강아지끼리는 반드시 이웃하게 세우는 경우의 수를 구하시오.",
        "question_en": "When you want to take a picture of 2 dogs and 3 cats standing in one line, find the number of cases where the dogs should be placed next to each other.",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "1 3 [OP_ADD] 1 3 [OP_ADD] [OP_PERM] 2 2 [OP_PERM] [OP_MUL]",
        "solution_abst_en": "1 3 [OP_ADD] 1 3 [OP_ADD] [OP_PERM] 2 2 [OP_PERM] [OP_MUL]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = 1\nvar_c = int(var_c)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_c-i)\nvar_h = 2\nvar_i = 2\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nvar_k = var_g * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = 1\nvar_c = int(var_c)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_c-i)\nvar_h = 2\nvar_i = 2\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nvar_k = var_g * var_j\nprint(int(var_k))"
    },
    "740": {
        "category": "Correspondence",
        "question_ko": "여섯 자리 수 A4461B이 72로 나누어 떨어질 때, A+B를 구하시오.",
        "question_en": "When the six-digit number A4461B is divisible by 72, find A+B.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "A4461B [OP_GEN_POSSIBLE_LIST] 72 [OP_LIST_DIVISIBLE] A4461B A [OP_LIST_FIND_UNK] A4461B B [OP_LIST_FIND_UNK] [OP_ADD]",
        "solution_abst_en": "A4461B [OP_GEN_POSSIBLE_LIST] 72 [OP_LIST_DIVISIBLE] A4461B A [OP_LIST_FIND_UNK] A4461B B [OP_LIST_FIND_UNK] [OP_ADD]",
        "solution_code_ko": "var_a = 'A4461B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 72\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 'A4461B'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nvar_e = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_e = int(elem[unk_idx])\nvar_f = 'A4461B'\nvar_g = 'B'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nvar_i = var_e + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 'A4461B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 72\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 'A4461B'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nvar_e = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_e = int(elem[unk_idx])\nvar_f = 'A4461B'\nvar_g = 'B'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nvar_i = var_e + var_h\nprint(int(var_i))"
    },
    "741": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 360미터(m)인 철사를 3.6미터(m) 씩 자르려고 합니다. 철사를 모두 몇 도막으로 자를 수 있습니까?",
        "question_en": "You want to cut 360 meters (m) of wire into 3.6 meters (m) long pieces. In how many pieces can you cut the wire?",
        "answer_ko": "100",
        "answer_en": "100",
        "solution_abst_ko": "360 3.6 [OP_DIV]",
        "solution_abst_en": "360 3.6 [OP_DIV]",
        "solution_code_ko": "var_a = 360\nvar_b = 3.6\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 360\nvar_b = 3.6\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "742": {
        "category": "Arithmetic calculation",
        "question_ko": "지난 일요일 어느 공원에 방문한 사람은 1260명입니다. 그중에서 7/18은 남자이고, 여자 중 6/11은 학생이었습니다. 공원에 방문한 여학생은 몇 명인지 구하시오.",
        "question_en": "1260 people visited the park last Sunday. Of those, 7/18 were men, and 6/11 of the women were students. Find how many female students visited the park.",
        "answer_ko": "420",
        "answer_en": "420",
        "solution_abst_ko": "1260 1 7/18 [OP_SUB] [OP_MUL] 6/11 [OP_MUL]",
        "solution_abst_en": "1260 1 7/18 [OP_SUB] [OP_MUL] 6/11 [OP_MUL]",
        "solution_code_ko": "var_a = 1260\nvar_b = 1\nvar_c = 0.3888888888888889\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 0.5454545454545454\nvar_g = var_e * var_f\nprint(int(eval('{:.2f}'.format(round(var_g+1e-10,2)))))",
        "solution_code_en": "var_a = 1260\nvar_b = 1\nvar_c = 0.3888888888888889\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 0.5454545454545454\nvar_g = var_e * var_f\nprint(int(eval('{:.2f}'.format(round(var_g+1e-10,2)))))"
    },
    "743": {
        "category": "Arithmetic calculation",
        "question_ko": "은지는 44개의 탁구공을 가지고 있습니다. 친구들에게 탁구공을 4개씩 나누어 주면 몇 명의 친구들이 탁구공을 받게 됩니까?",
        "question_en": "Eunji has 44 ping pong balls. If she gives 4 ping pong balls to her friends each, how many friends will get the ping pong balls?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "44 4 [OP_DIV]",
        "solution_abst_en": "44 4 [OP_DIV]",
        "solution_code_ko": "var_a = 44\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 44\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "744": {
        "category": "Geometry",
        "question_ko": "정사면체의 꼭짓점의 개수는?",
        "question_en": "How many vertices are there in a tetrahedron?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "3 1 [OP_ADD]",
        "solution_abst_en": "3 1 [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "745": {
        "category": "Geometry",
        "question_ko": "가로가 세로의 3배인 직사각형이 있습니다. 이 직사각형의 세로가 0.06미터(m)일 때, 넓이는 몇 제곱미터(㎡)입니까?",
        "question_en": "There is a rectangle with a width three times its height. If the length of this rectangle is 0.06 meters (m), how many square meters (m2) is its area?",
        "answer_ko": "0.01",
        "answer_en": "0.01",
        "solution_abst_ko": "0.06 3 [OP_MUL] 0.06 [OP_MUL]",
        "solution_abst_en": "0.06 3 [OP_MUL] 0.06 [OP_MUL]",
        "solution_code_ko": "var_a = 0.06\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 0.06\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.06\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 0.06\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "746": {
        "category": "Arithmetic calculation",
        "question_ko": "배구공은 축구공보다 12개 많고, 농구공은 축구공보다 23개 적습니다. 축구공이 68개일 때 축구공, 배구공, 농구공은 모두 몇 개입니까?",
        "question_en": "There are 12 more volleyballs and 23 fewer basketballs than soccer balls. If there are 68 soccer balls, how many soccer balls, volleyballs, and basketballs are there?",
        "answer_ko": "193",
        "answer_en": "193",
        "solution_abst_ko": "68 12 [OP_ADD] 68 23 [OP_SUB] [OP_ADD] 68 [OP_ADD]",
        "solution_abst_en": "68 12 [OP_ADD] 68 23 [OP_SUB] [OP_ADD] 68 [OP_ADD]",
        "solution_code_ko": "var_a = 68\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 68\nvar_e = 23\nvar_f = var_d - var_e\nvar_g = var_c + var_f\nvar_h = 68\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 68\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 68\nvar_e = 23\nvar_f = var_d - var_e\nvar_g = var_c + var_f\nvar_h = 68\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "747": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 6을 곱해야 하는데 잘못하여 9를 곱했더니 153이 되었습니다. 바르게 계산한 결과를 구하시오.",
        "question_en": "You need to multiply a certain number by 6, but you mistakenly multiplied it by 9, and I got 153. Find the result of the correct calculation.",
        "answer_ko": "102",
        "answer_en": "102",
        "solution_abst_ko": "153 9 [OP_DIV] 6 [OP_MUL]",
        "solution_abst_en": "153 9 [OP_DIV] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 153\nvar_b = 9\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 153\nvar_b = 9\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "748": {
        "category": "Comparison",
        "question_ko": "진호는 가지고 있던 연필 9자루 중에서 3자루를 동생에게 주었고, 영수는 가지고 있던 연필 14자루 중에서 7자루를 친구에게 주었습니다. 진호와 영수 중 누가 더 많은 연필을 가지고 있습니까?",
        "question_en": "Jinho gave 3 of the 9 pencils he had to his younger brother, and Youngsu gave 7 of the 14 pencils he had to his friend. Who has more pencils between Jinho and Youngsu?",
        "answer_ko": "영수",
        "answer_en": "Youngsu",
        "solution_abst_ko": "[OP_LIST_SOL] 진호 영수 [OP_LIST_EOL] [OP_LIST_SOL] 9 3 [OP_SUB] 14 7 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jinho Youngsu [OP_LIST_EOL] [OP_LIST_SOL] 9 3 [OP_SUB] 14 7 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '진호'\nvar_b = '영수'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 9\nvar_d = 3\nvar_e = var_c - var_d\nvar_f = 14\nvar_g = 7\nvar_h = var_f - var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Jinho'\nvar_b = 'Youngsu'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 9\nvar_d = 3\nvar_e = var_c - var_d\nvar_f = 14\nvar_g = 7\nvar_h = var_f - var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "749": {
        "category": "Possibility",
        "question_ko": "2, 4, 6, 8, 9 중에서 2장을 뽑아 한 번씩만 사용하여 두 자리 수를 만들려고 합니다. 만들 수 있는 두 자리 수 중에서 가장 큰 수와 가장 작은 수의 합을 구하시오.",
        "question_en": "Among 2, 4, 6, 8, and 9, you want to create a two-digit number by drawing two cards and using them only once. Find the sum of the largest and smallest two-digit numbers that can be made.",
        "answer_ko": "122",
        "answer_en": "122",
        "solution_abst_ko": "[OP_LIST_SOL] 2 4 6 8 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 2 4 6 8 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = 6\nvar_d = 8\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = 6\nvar_d = 8\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h + var_j\nprint(int(var_k))"
    },
    "750": {
        "category": "Possibility",
        "question_ko": "사과, 복숭아, 배 중 2개를 뽑아 서로 다른 과일 바구니에 담으려고 합니다. 가능한 경우의 수는 모두 몇 가지입니까?",
        "question_en": "You want to pick two fruits out of an apple, a peach and a pear and place them in different fruit baskets. What are the number of cases?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 복숭아 배 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] apple peach pear [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '복숭아'\nvar_c = '배'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nprint(int(var_f))",
        "solution_code_en": "var_a = 'apple'\nvar_b = 'peach'\nvar_c = 'pear'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nprint(int(var_f))"
    },
    "751": {
        "category": "Geometry",
        "question_ko": "한 모서리의 길이가 20센티미터(㎝)인 정육면체 모양의 어항에 높이가 15센티미터(㎝)가 되도록 물을 채워 넣었습니다. 여기에 한 모서리의 길이가 10센티미터(㎝)인 정육면체 모양의 철 조각을 물 안에 완전히 잠기도록 넣었습니다. 이 어항의 물의 높이는 몇 센티미터(㎝) 높아지는지 소수점을 포함하여 구하시오.",
        "question_en": "A cube-shaped fishbowl with an edge length of 20 centimeters (cm) was filled with water up to 15 centimeters (cm) high. Here, a cube-shaped piece of iron whose edge is 10 centimeters (cm) long was placed to be completely submerged in the water. Find how many centimeters (cm) the water level in this fish tank has risen, including the decimal point.",
        "answer_ko": "2.50",
        "answer_en": "2.5",
        "solution_abst_ko": "10 10 [OP_MUL] 10 [OP_MUL] 20 20 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "10 10 [OP_MUL] 10 [OP_MUL] 20 20 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 10\nvar_e = var_c * var_d\nvar_f = 20\nvar_g = 20\nvar_h = var_f * var_g\nvar_i = var_e / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 10\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 10\nvar_e = var_c * var_d\nvar_f = 20\nvar_g = 20\nvar_h = var_f * var_g\nvar_i = var_e / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "752": {
        "category": "Arithmetic calculation",
        "question_ko": "선희네 유치원에서 올해 들어온 유치원생 134명에게 초콜릿 목걸이를 만들어 주려고 합니다. 초콜릿 목걸이 한 개에 초콜릿 7개씩 필요하다면, 한 봉지에 28개씩 들어있는 초콜릿을 적어도 몇 봉지 사야 합니까?",
        "question_en": "You are going to make chocolate necklaces for 134 kindergarteners at Seonhee's Kindergarten this year. If you need 7 chocolates for each chocolate necklace, how many bags of 28 chocolates should you buy at least?",
        "answer_ko": "34",
        "answer_en": "34",
        "solution_abst_ko": "134 7 [OP_MUL] 28 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "134 7 [OP_MUL] 28 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 134\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 28\nvar_e = var_c / var_d\nvar_f = 1\nvar_g=int(((var_e+9*10**(var_f-2))//(10**(var_f-1)))*10**(var_f-1))\n\nprint(int(var_g))",
        "solution_code_en": "var_a = 134\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 28\nvar_e = var_c / var_d\nvar_f = 1\nvar_g=int(((var_e+9*10**(var_f-2))//(10**(var_f-1)))*10**(var_f-1))\n\nprint(int(var_g))"
    },
    "753": {
        "category": "Arithmetic calculation",
        "question_ko": "토끼를 색으로 구별하면 12마리는 흰색이고 9마리는 검은색입니다. 전체 토끼 중 8마리가 암컷이라면 수컷 토끼는 몇 마리입니까?",
        "question_en": "If the rabbits are color coded, 12 are white and 9 are black. If 8 rabbits are female, how many male rabbits are there?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "12 9 [OP_ADD] 8 [OP_SUB]",
        "solution_abst_en": "12 9 [OP_ADD] 8 [OP_SUB]",
        "solution_code_ko": "var_a = 12\nvar_b = 9\nvar_c = var_a + var_b\nvar_d = 8\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 9\nvar_c = var_a + var_b\nvar_d = 8\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "754": {
        "category": "Possibility",
        "question_ko": "윤기네 반에는 5명의 학생이 있고, 반장을 뽑으려고 합니다. 이때, 3명의 반장 후보자에게 투표할 수 있는 경우는 모두 몇 가지입니까?",
        "question_en": "There are 5 students in Yoongi's class, and they are trying to select a class president. At this time, how many cases can Yoongi vote for the 3 class president candidates?",
        "answer_ko": "243",
        "answer_en": "243",
        "solution_abst_ko": "3 5 [OP_POW]",
        "solution_abst_en": "3 5 [OP_POW]",
        "solution_code_ko": "var_a = 3\nvar_b = 5\nvar_c = var_a ** var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 5\nvar_c = var_a ** var_b\nprint(int(var_c))"
    },
    "755": {
        "category": "Arithmetic calculation",
        "question_ko": "연속하는 세 자연수의 합이 30일 때, 세 자연수 중 중간 수를 구하시오.",
        "question_en": "If the sum of three consecutive natural numbers is 30, find the middle number among the three natural numbers.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "30 0 3 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 3 [OP_DIV] 3 2 [OP_FDIV] [OP_ADD]",
        "solution_abst_en": "30 0 3 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 3 [OP_DIV] 3 2 [OP_FDIV] [OP_ADD]",
        "solution_code_ko": "var_a = 30\nvar_b = 0\nvar_c = 3\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nlist_a = [i for i in range(var_b, var_e + 1, var_f)]\nlist_a = [float(i) for i in list_a]\nvar_g = sum(list_a)\nvar_h = var_a - var_g\nvar_i = 3\nvar_j = var_h / var_i\nvar_k = 3\nvar_l = 2\nvar_m = var_k // var_l\nvar_n = var_j + var_m\nprint(int(var_n))",
        "solution_code_en": "var_a = 30\nvar_b = 0\nvar_c = 3\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nlist_a = [i for i in range(var_b, var_e + 1, var_f)]\nlist_a = [float(i) for i in list_a]\nvar_g = sum(list_a)\nvar_h = var_a - var_g\nvar_i = 3\nvar_j = var_h / var_i\nvar_k = 3\nvar_l = 2\nvar_m = var_k // var_l\nvar_n = var_j + var_m\nprint(int(var_n))"
    },
    "756": {
        "category": "Geometry",
        "question_ko": "원주율이 3일 때, 반지름이 0.6미터(m)인 원 모양의 꽃밭의 넓이를 구하시오.",
        "question_en": "Find the area of a flower field in the shape of a circle with a radius of 0.6 meters (m) when the pi is 3.",
        "answer_ko": "1.08",
        "answer_en": "1.08",
        "solution_abst_ko": "3 0.6 2 [OP_POW] [OP_MUL]",
        "solution_abst_en": "3 0.6 2 [OP_POW] [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 0.6\nvar_c = 2\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 3\nvar_b = 0.6\nvar_c = 2\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "757": {
        "category": "Geometry",
        "question_ko": "각기 다른 세 모서리의 길이가 4센티미터(㎝), 6센티미터(㎝), 15센티미터(㎝)인 직육면체가 있다. 부피는 얼마인지 구하시오.",
        "question_en": "There is a rectangular parallelepiped with three distinct edges whose length is 4 centimeters (cm), 6 centimeters (cm), and 15 centimeters (cm) each. Find what is the volume of this rectangular parallelepiped.",
        "answer_ko": "360",
        "answer_en": "360",
        "solution_abst_ko": "15 6 [OP_MUL] 4 [OP_MUL]",
        "solution_abst_en": "15 6 [OP_MUL] 4 [OP_MUL]",
        "solution_code_ko": "var_a = 15\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "758": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 82를 더하고 90을 더하고 88을 더하고 84를 더한 다음 5로 나누면 몫이 88이다. 어떤 수를 구하시오.",
        "question_en": "If you add 82, add 90, add 88, add 84 to a number and divide it by 5, the quotient is 88. Find the number.",
        "answer_ko": "96",
        "answer_en": "96",
        "solution_abst_ko": "88 5 [OP_MUL] 82 [OP_SUB] 90 [OP_SUB] 88 [OP_SUB] 84 [OP_SUB]",
        "solution_abst_en": "88 5 [OP_MUL] 82 [OP_SUB] 90 [OP_SUB] 88 [OP_SUB] 84 [OP_SUB]",
        "solution_code_ko": "var_a = 88\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 82\nvar_e = var_c - var_d\nvar_f = 90\nvar_g = var_e - var_f\nvar_h = 88\nvar_i = var_g - var_h\nvar_j = 84\nvar_k = var_i - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 88\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 82\nvar_e = var_c - var_d\nvar_f = 90\nvar_g = var_e - var_f\nvar_h = 88\nvar_i = var_g - var_h\nvar_j = 84\nvar_k = var_i - var_j\nprint(int(var_k))"
    },
    "759": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 가장 큰 수와 2번째로 큰 수로 나눈 나머지는 얼마입니까?",
        "question_en": "There are five numbers: 10, 11, 12, 13, and 14. What is the remainder if the largest number is divided by the second largest number?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_MOD]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_MOD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[-var_h]\nvar_j = var_g % var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[-var_h]\nvar_j = var_g % var_i\nprint(int(var_j))"
    },
    "760": {
        "category": "Arithmetic calculation",
        "question_ko": "빨간 구슬 12봉투 안에 288개의 구슬이 들어 있고, 파란 구슬 9봉투 안에 243개의 구슬이 들어 있다. 빨간 구슬과 파란 구슬 1봉투에 들어 있는 구슬의 개수 차를 구하시오.",
        "question_en": "There are 288 red marbles in 12 bags, and 243 blue marbles in 9 bags. Find the difference between the number of marbles in one bag of red and blue marbles.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "288 12 [OP_DIV] 243 9 [OP_DIV] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "288 12 [OP_DIV] 243 9 [OP_DIV] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 288\nvar_b = 12\nvar_c = var_a / var_b\nvar_d = 243\nvar_e = 9\nvar_f = var_d / var_e\nvar_g = var_c - var_f\nvar_h = abs(var_g)\nprint(int(var_h))",
        "solution_code_en": "var_a = 288\nvar_b = 12\nvar_c = var_a / var_b\nvar_d = 243\nvar_e = 9\nvar_f = var_d / var_e\nvar_g = var_c - var_f\nvar_h = abs(var_g)\nprint(int(var_h))"
    },
    "761": {
        "category": "Comparison",
        "question_ko": "3개의 숫자 0.8, 1/2, 0.9가 있습니다. 2보다 작은 수 중 가장 큰 숫자는 얼마인가요?",
        "question_en": "There are three numbers 0.8, 1/2, and 0.9. What is the largest number that is less than 2?",
        "answer_ko": "0.90",
        "answer_en": "0.9",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 2 [OP_LIST_LESS] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 2 [OP_LIST_LESS] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = []\nfor i in list_a:\n    if i < var_d:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint('{:.2f}'.format(round(var_f+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = []\nfor i in list_a:\n    if i < var_d:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint('{:.2f}'.format(round(var_f+1e-10,2)))"
    },
    "762": {
        "category": "Arithmetic calculation",
        "question_ko": "종이를 겹치게 1번 접었다가 펼치면 2칸이 생기고, 2번 접었다가 펼치면 4칸, 3번 접었다가 펼치면 8칸이 생깁니다. 같은 방법으로 8번 접었다가 펼치면 종이에는 몇 칸이 생기겠습니까?",
        "question_en": "If you fold and unfold the paper once making them overlap, you get 2 squares, and if you fold and unfold it twice, you get 4 squares, and if you fold and unfold it 3 times, you get 8 squares. How many squares will there be on the paper if you fold and unfold it 8 times in the same way?",
        "answer_ko": "256",
        "answer_en": "256",
        "solution_abst_ko": "2 8 [OP_POW]",
        "solution_abst_en": "2 8 [OP_POW]",
        "solution_code_ko": "var_a = 2\nvar_b = 8\nvar_c = var_a ** var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 8\nvar_c = var_a ** var_b\nprint(int(var_c))"
    },
    "763": {
        "category": "Geometry",
        "question_ko": "네 변의 길이의 합이 52센티미터(㎝)인 정사각형이 있다. 정사각형의 넓이를 구하시오.",
        "question_en": "There is a square with the sum of the lengths of its four sides measuring 52 centimeters (cm). Find the area of this square.",
        "answer_ko": "169",
        "answer_en": "169",
        "solution_abst_ko": "52 4 [OP_DIV] 2 [OP_POW]",
        "solution_abst_en": "52 4 [OP_DIV] 2 [OP_POW]",
        "solution_code_ko": "var_a = 52\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 52\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint(int(var_e))"
    },
    "764": {
        "category": "Arithmetic calculation",
        "question_ko": "사람은 1킬로미터(㎞)를 가면 0.08밀리리터(㎖)의 물이 소모됩니다. 1시간동안 80킬로미터(㎞)를 움직이는 빠르기로 2시간 36분을 이동하였을 때, 소모한 물의 양은 몇 밀리리터(㎖)인지 구하시오.",
        "question_en": "A person consumes 0.08 milliliters (ml) of water per 1 kilometer (km). Find the amount of water consumed in milliliters (㎖) when traveling for 2 hours and 36 minutes at the speed of moving 80 kilometers (㎞) in 1 hour.",
        "answer_ko": "16.64",
        "answer_en": "16.64",
        "solution_abst_ko": "0.08 80 2 36 60 [OP_DIV] [OP_ADD] [OP_MUL] [OP_MUL]",
        "solution_abst_en": "0.08 80 2 36 60 [OP_DIV] [OP_ADD] [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 0.08\nvar_b = 80\nvar_c = 2\nvar_d = 36\nvar_e = 60\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nvar_h = var_b * var_g\nvar_i = var_a * var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 0.08\nvar_b = 80\nvar_c = 2\nvar_d = 36\nvar_e = 60\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nvar_h = var_b * var_g\nvar_i = var_a * var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "765": {
        "category": "Arithmetic calculation",
        "question_ko": "사과가 18개 있고 사과와 감을 합하면 33개가 있습니다. 감은 몇 개 있는지 구하시오.",
        "question_en": "Given that there are 18 apples and the sum of apples and persimmons are 33. Find the number of persimmons.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "33 18 [OP_SUB]",
        "solution_abst_en": "33 18 [OP_SUB]",
        "solution_code_ko": "var_a = 33\nvar_b = 18\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 33\nvar_b = 18\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "766": {
        "category": "Correspondence",
        "question_ko": "윤기는 두 자리 수와 세 자리 수의 덧셈을 하려 합니다. 윤기는 두 자리 수의 일의 자리 숫자 9를 6으로 잘못 보았고, 세 자리 수의 백의 자리 숫자와 일의 자리 숫자를 바꾸어 253이라고 잘못 보았습니다. 윤기가 구한 합은 299 일 때, 두 자리 수를 구하시오.",
        "question_en": "Yoongi wants to add two-digit to three-digit numbers. Yoongi confused the 9 in the ones place of a two-digit number with 6, and switched the digits in the hundreds and ones place of a three-digit number and saw it as 253. If the sum obtained by Yoongi is 299, find the two-digit number.",
        "answer_ko": "49",
        "answer_en": "49",
        "solution_abst_ko": "299 253 [OP_SUB] 6 9 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "299 253 [OP_SUB] 6 9 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 299\nvar_b = 253\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 299\nvar_b = 253\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "767": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.9, 1/3의 숫자가 있다. 이 중 0.3보다 큰 숫자들의 합을 구하시오.",
        "question_en": "There are numbers 0.8, 1/2, 0.9, and 1/3. Find the sum of all numbers greater than 0.3.",
        "answer_ko": "2.53",
        "answer_en": "2.53",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.3 [OP_LIST_MORE] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.3 [OP_LIST_MORE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.3\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint('{:.2f}'.format(round(var_f+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.3\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint('{:.2f}'.format(round(var_f+1e-10,2)))"
    },
    "768": {
        "category": "Correspondence",
        "question_ko": "5A8-B14=364일 때, B를 구하시오.",
        "question_en": "When 5A8-B14=364 is valid, find B.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "5A8-B14=364 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "5A8-B14=364 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '5A8-B14=364'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '5A8-B14=364'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "769": {
        "category": "Possibility",
        "question_ko": "사과, 복숭아, 배, 참외 중에서 2가지의 과일만 구매한다면, 몇 가지의 조합이 가능합니까?",
        "question_en": "If you buy only 2 fruits out of Apples, Peaches, Pears, and Melons, how many combinations are possible?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 복숭아 배 참외 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] Apple Peach Pear Melon [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '복숭아'\nvar_c = '배'\nvar_d = '참외'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g / (i+1)\nprint(int(var_g))",
        "solution_code_en": "var_a = 'Apple'\nvar_b = 'Peach'\nvar_c = 'Pear'\nvar_d = 'Melon'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g / (i+1)\nprint(int(var_g))"
    },
    "770": {
        "category": "Geometry",
        "question_ko": "정사각형 모양의 공원이 있다. 공원의 둘레의 길이가 35보다 작은 4의 배수 중 가장 큰 값이라고 한다. 성훈이가 공원 둘레를 따라 35킬로미터(㎞)를 걸으려고 하면 1바퀴를 돌고 몇 킬로미터(㎞)를 더 걸어야하는가?",
        "question_en": "There is a square-shaped park. It is said that the perimeter of a park is the largest multiple of 4 and is less than 35. If Seong-hoon tries to walk 35 kilometers (km) around the perimeter of the park, how many more kilometers (km) must he walk after one lap?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "35 4 [OP_MOD]",
        "solution_abst_en": "35 4 [OP_MOD]",
        "solution_code_ko": "var_a = 35\nvar_b = 4\nvar_c = var_a % var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 35\nvar_b = 4\nvar_c = var_a % var_b\nprint(int(var_c))"
    },
    "771": {
        "category": "Possibility",
        "question_ko": "850이상 920이하 범위에서 3, 9, 8을 모두 사용하여 만들 수 있는 수는 모두 몇 개입니까?",
        "question_en": "You are making new numbers using all 3, 9, and 8. What is the number of cases in which the number you made is more than or equal to 850 and less than or equal to 920?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 3 9 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 850 [OP_LIST_MORE] 920 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 3 9 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 850 [OP_LIST_MORE] 920 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 3\nvar_b = 9\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 850\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = 920\nlist_d = []\nfor i in list_c:\n    if i < var_f:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))",
        "solution_code_en": "var_a = 3\nvar_b = 9\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 850\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = 920\nlist_d = []\nfor i in list_c:\n    if i < var_f:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))"
    },
    "772": {
        "category": "Geometry",
        "question_ko": "정육면체의 부피가 729세제곱센티미터(㎤)일 때, 한 모서리의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "If the volume of the cube is 729 cubic centimeters (cm3), how many centimeters (cm) is the length of one side of the cube?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "729 1/3 [OP_POW]",
        "solution_abst_en": "729 1/3 [OP_POW]",
        "solution_code_ko": "var_a = 729\nvar_b = 0.3333333333333333\nvar_c = var_a ** var_b\nprint(int(eval('{:.2f}'.format(round(var_c+1e-10,2)))))",
        "solution_code_en": "var_a = 729\nvar_b = 0.3333333333333333\nvar_c = var_a ** var_b\nprint(int(eval('{:.2f}'.format(round(var_c+1e-10,2)))))"
    },
    "773": {
        "category": "Geometry",
        "question_ko": "네 변의 길이가 모두 같은 사각형이 있습니다. 이 도형의 두 대각선의 길이가 각각 9센티미터(㎝), 14센티미터(㎝)라면 넓이는 얼마입니까?",
        "question_en": "There is a tetragon having all four sides the same length. If the lengths of the two diagonals of this figure are 9 centimeters (cm) and 14 centimeters (cm), what is the area?",
        "answer_ko": "63",
        "answer_en": "63",
        "solution_abst_ko": "9 14 [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "9 14 [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 9\nvar_b = 14\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 14\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "774": {
        "category": "Correspondence",
        "question_ko": "지우개 49개와 연필 66개를 반 학생들에게 똑같이 나누어주면 지우개는 4개가 남고 연필은 6개가 남는다. 반 학생들은 몇 명인지 구하시오.",
        "question_en": "Divide 49 erasers and 66 pencils equally to the students in the class, leaving 4 erasers and 6 pencils. Find how many students are in the class.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "49 4 [OP_SUB] 66 6 [OP_SUB] [OP_GCD]",
        "solution_abst_en": "49 4 [OP_SUB] 66 6 [OP_SUB] [OP_GCD]",
        "solution_code_ko": "var_a = 49\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 66\nvar_e = 6\nvar_f = var_d - var_e\nvar_g = math.gcd(int(var_f), int(var_c))\nprint(int(var_g))",
        "solution_code_en": "var_a = 49\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 66\nvar_e = 6\nvar_f = var_d - var_e\nvar_g = math.gcd(int(var_f), int(var_c))\nprint(int(var_g))"
    },
    "775": {
        "category": "Comparison",
        "question_ko": "정국이는 6 나누기 3만큼 사과를 모았고, 윤기는 4개, 유나는 5개의 사과를 모았습니다. 누가 가진 사과가 가장 적습니까?",
        "question_en": "Jungkook collected 6 divided by 3 apples, Yoongi collected 4 apples, and Yuna collected 5 apples. Who has the fewest apples?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 윤기 유나 [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_FDIV] 4 5 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Yoongi Yuna [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_FDIV] 4 5 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '윤기'\nvar_c = '유나'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 6\nvar_e = 3\nvar_f = var_d // var_e\nvar_g = 4\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Yoongi'\nvar_c = 'Yuna'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 6\nvar_e = 3\nvar_f = var_d // var_e\nvar_g = 4\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "776": {
        "category": "Arithmetic calculation",
        "question_ko": "두 자리 자연수 중에서 각 자릿수의 합이 8 이상인 수는 몇 개입니까?",
        "question_en": "How many two-digit numbers meet the condition where the sum of the numbers in the ones and in the tens is greater than or equal to 8?",
        "answer_ko": "62",
        "answer_en": "62",
        "solution_abst_ko": "10 99 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] 8 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "10 99 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] 8 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_b=[]\nfor i in list_a:\n    var_d = 0\n    i = int(i)\n    while i//10 > 0:\n        var_d = var_d + i%10\n        i = i//10\n    var_d = var_d + i%10\n    list_b.append(var_d)\nvar_e = 8\nlist_c = []\nfor i in list_b:\n    if i >= var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_b=[]\nfor i in list_a:\n    var_d = 0\n    i = int(i)\n    while i//10 > 0:\n        var_d = var_d + i%10\n        i = i//10\n    var_d = var_d + i%10\n    list_b.append(var_d)\nvar_e = 8\nlist_c = []\nfor i in list_b:\n    if i >= var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "777": {
        "category": "Correspondence",
        "question_ko": "6A5+B03=748일 때, A를 구하시오.",
        "question_en": "When 6A5+B03=748, find A.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "6A5+B03=748 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "6A5+B03=748 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '6A5+B03=748'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '6A5+B03=748'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "778": {
        "category": "Comparison",
        "question_ko": "공이 들어있는 A, B, C 상자가 있습니다. A 상자에는 B 상자보다 더 적은 공이 들어있고, C 상자에는 A 상자보다 더 많은 공이 들어있습니다. C 상자에 B 상자보다 더 많은 공이 들어있다면 가장 많은 공이 들어있는 상자는 어떤 상자인가요?",
        "question_en": "There are boxes A, B, and C with balls in them. Box A has fewer balls than Box B, and Box C has more balls than Box A. If Box C contains more balls than Box B, which box has the most balls?",
        "answer_ko": "C",
        "answer_en": "C",
        "solution_abst_ko": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] C A > A B < C B > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] C A > A B < C B > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET] ",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'C'\nvar_e = 'A'\nvar_f = '>'\nvar_g = 'A'\nvar_h = 'B'\nvar_i = '<'\nvar_j = 'C'\nvar_k = 'B'\nvar_l = '>'\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_m = 1\nvar_n = list_c[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'C'\nvar_e = 'A'\nvar_f = '>'\nvar_g = 'A'\nvar_h = 'B'\nvar_i = '<'\nvar_j = 'C'\nvar_k = 'B'\nvar_l = '>'\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_m = 1\nvar_n = list_c[var_m-1]\nprint(var_n)"
    },
    "779": {
        "category": "Geometry",
        "question_ko": "반지름이 10센티미터(㎝)인 원 안에 가장 큰 마름모를 그린 다음, 마름모의 네 변의 한가운데를 모두 이어 작은 마름모를 그렸습니다. 작은 마름모의 넓이는 몇 제곱센티미터입니까?",
        "question_en": "I drew the largest rhombus in a circle with a radius of 10 centimeters (cm), and then drew a smaller rhombus by connecting the middle of all four sides of the rhombus. What is the area of the small rhombus in square centimeters (cm2)?",
        "answer_ko": "100",
        "answer_en": "100",
        "solution_abst_ko": "10 2 [OP_MUL] 2 [OP_POW] 2 [OP_DIV] 2 [OP_DIV]",
        "solution_abst_en": "10 2 [OP_MUL] 2 [OP_POW] 2 [OP_DIV] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "780": {
        "category": "Possibility",
        "question_ko": "사과, 복숭아, 배 중에서 2가지의 과일을 뽑아 줄을 세우려고 합니다. 가능한 경우의 수는 모두 몇 가지인가요?",
        "question_en": "I'm trying to draw 2 fruits out of apples, peaches, and pears and line them up. How many possible cases are there?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 복숭아 배 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] apples peaches pears [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '복숭아'\nvar_c = '배'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nprint(int(var_f))",
        "solution_code_en": "var_a = 'apples'\nvar_b = 'peaches'\nvar_c = 'pears'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nprint(int(var_f))"
    },
    "781": {
        "category": "Geometry",
        "question_ko": "한 대각선의 길이는 6센티미터(㎝)의 3배이고, 다른 대각선의 길이는 4센티미터(㎝)의 3배인 마름모의 넓이는 몇 제곱센티미터(㎠)인지 구하시오.",
        "question_en": "Find the area in square centimeters (cm2) of a rhombus where the length of one diagonal is three times 6 centimeters (cm), and the length of the other diagonal is three times 4 centimeters (cm).",
        "answer_ko": "108",
        "answer_en": "108",
        "solution_abst_ko": "6 3 [OP_MUL] 4 3 [OP_MUL] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "6 3 [OP_MUL] 4 3 [OP_MUL] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c * var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 6\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c * var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "782": {
        "category": "Correspondence",
        "question_ko": "지호가 어떤 모형을 만드는데 고무 찰흙을 13/5개 사용했다. 동일한 작품을 하나 더 만들고 남은 고무 찰흙이 9/7이었다. 지호가 처음에 가지고 있던 고무 찰흙의 양을 구하여라.",
        "question_en": "Jiho used 13/5 pieces of rubber clay to make a model. After making another identical piece, the remaining rubber clay was 9/7. Find the amount of rubber clay Jiho had at the beginning.",
        "answer_ko": "6.49",
        "answer_en": "6.49",
        "solution_abst_ko": "9/7 13/5 [OP_ADD] 13/5 [OP_ADD]",
        "solution_abst_en": "9/7 13/5 [OP_ADD] 13/5 [OP_ADD]",
        "solution_code_ko": "var_a = 1.2857142857142858\nvar_b = 2.6\nvar_c = var_a + var_b\nvar_d = 2.6\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 1.2857142857142858\nvar_b = 2.6\nvar_c = var_a + var_b\nvar_d = 2.6\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "783": {
        "category": "Possibility",
        "question_ko": "각 자리 수가 모두 짝수인 세 자리 수의 개수를 구하시오.",
        "question_en": "Find the number of three-digit numbers where each digit is even.",
        "answer_ko": "100",
        "answer_en": "100",
        "solution_abst_ko": "0 9 [OP_LIST_EVEN] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_LEN]",
        "solution_abst_en": "0 9 [OP_LIST_EVEN] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 9\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = len(list_b)\nprint(int(var_d))",
        "solution_code_en": "var_a = 0\nvar_b = 9\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = len(list_b)\nprint(int(var_d))"
    },
    "784": {
        "category": "Arithmetic calculation",
        "question_ko": "사탕 235개를 한 상자에 10개씩 담아 3000원에 팔기로 했습니다. 상자에 담은 사탕을 팔아서 벌 수 있는 돈은 최대 얼마입니까?",
        "question_en": "You decided to put 235 candies in a box of 10 and sell them for 3,000 won. What is the maximum amount of money you can make selling boxed candy?",
        "answer_ko": "69000",
        "answer_en": "69000",
        "solution_abst_ko": "235 10 [OP_FDIV] 3000 [OP_MUL]",
        "solution_abst_en": "235 10 [OP_FDIV] 3000 [OP_MUL]",
        "solution_code_ko": "var_a = 235\nvar_b = 10\nvar_c = var_a // var_b\nvar_d = 3000\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 235\nvar_b = 10\nvar_c = var_a // var_b\nvar_d = 3000\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "785": {
        "category": "Arithmetic calculation",
        "question_ko": "일정한 빠르기로 3분 동안 15미터(m)를 움직이는 거북이가 있습니다. 거북이가 140미터(m)를 이동하기 위해서는 몇 분이 필요합니까?",
        "question_en": "A turtle moves 15 meters (m) in 3 minutes at a constant speed. How many minutes does it take for a tortoise to travel 140 meters (m)?",
        "answer_ko": "28",
        "answer_en": "28",
        "solution_abst_ko": "140 15 3 [OP_DIV] [OP_DIV]",
        "solution_abst_en": "140 15 3 [OP_DIV] [OP_DIV]",
        "solution_code_ko": "var_a = 140\nvar_b = 15\nvar_c = 3\nvar_d = var_b / var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 140\nvar_b = 15\nvar_c = 3\nvar_d = var_b / var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "786": {
        "category": "Geometry",
        "question_ko": "재호는 직사각형 모양의 밭을 가지고 있습니다. 이 밭의 한 변의 길이는 5.9미터(m)이고 다른 한 변의 길이는 3미터(m)입니다. 이 밭의 넓이를 구하시오.",
        "question_en": "Jaeho has a field in the shape of a rectangle. One side of this field is 5.9 meters (m) long and the other side is 3 meters (m) long. Find the area of this field.",
        "answer_ko": "17.70",
        "answer_en": "17.7",
        "solution_abst_ko": "5.9 3 [OP_MUL]",
        "solution_abst_en": "5.9 3 [OP_MUL]",
        "solution_code_ko": "var_a = 5.9\nvar_b = 3\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 5.9\nvar_b = 3\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "787": {
        "category": "Comparison",
        "question_ko": "남준이는 학교에 2번째로 도착했고, 지민이는 남준이보다 바로 전에 학교에 도착했습니다. 지민이는 몇 번째로 도착했습니까?",
        "question_en": "Namjoon was the second to arrive at school, and Jimin arrived just before Namjoon. In what place did Jimin enter school?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "2 1 [OP_SUB]",
        "solution_abst_en": "2 1 [OP_SUB]",
        "solution_code_ko": "var_a = 2\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "788": {
        "category": "Comparison",
        "question_ko": "(가), (나), (다) 마을에는 포도밭이 있습니다. (다) 마을은 (가) 마을보다 더 적은 포도 송이를 수확하였고, (나) 마을은 (가) 마을보다 포도 송이를 더 많이 수확하였다면, 가장 적은 포도 송이를 수확한 마을은 어디인지 구하세요.",
        "question_en": "There are vineyards in the village (a), (b) and (c). If village (c) harvested fewer bunches of grapes than village (a), and village (b) harvested more bunches of grapes than village (a), find which village harvested the fewest bunches of grapes.",
        "answer_ko": "(다)",
        "answer_en": "(c)",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) (다) [OP_LIST_EOL] [OP_LIST_SOL] (나) (가) > (다) (가) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (a) (b) (c) [OP_LIST_EOL] [OP_LIST_SOL] (b) (a) > (c) (a) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nvar_c = '(다)'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '(나)'\nvar_e = '(가)'\nvar_f = '>'\nvar_g = '(다)'\nvar_h = '(가)'\nvar_i = '<'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = len(list_c)\nvar_k = list_c[var_j-1]\nprint(var_k)",
        "solution_code_en": "var_a = '(a)'\nvar_b = '(b)'\nvar_c = '(c)'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '(b)'\nvar_e = '(a)'\nvar_f = '>'\nvar_g = '(c)'\nvar_h = '(a)'\nvar_i = '<'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = len(list_c)\nvar_k = list_c[var_j-1]\nprint(var_k)"
    },
    "789": {
        "category": "Arithmetic calculation",
        "question_ko": "통에 (가) 물고기 4마리와 (나) 물고기 3마리가 들어 있었습니다. 오늘 물고기 몇 마리를 더 사 와서 통에 넣었더니 물고기는 모두 10마리가 되었습니다. 오늘 더 넣은 물고기는 몇 마리입니까?",
        "question_en": "The barrel has contained 4 fish (a) and 3 fish (b). I bought some more fish today and put them in the barrel, so there are 10 fish in total. How many more fish did I put in today?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "10 4 3 [OP_ADD] [OP_SUB]",
        "solution_abst_en": "10 4 3 [OP_ADD] [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 4\nvar_c = 3\nvar_d = var_b + var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 4\nvar_c = 3\nvar_d = var_b + var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "790": {
        "category": "Comparison",
        "question_ko": "256보다 큰 수 중에서 십의 자리 숫자가 5, 백의 자리 숫자가 2인 수는 모두 몇 개인가요?",
        "question_en": "How many numbers greater than 256 have 5 in the tens digit and 2 in the hundreds digit?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 2 5 A [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 256 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 2 5 A [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 256 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 2\nvar_b = 5\nvar_c = 'A'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nans_dict = dict()\nvar_d = str(var_d)\nlist_b = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_d) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_b.append(new_elem)\nvar_e = 256\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 2\nvar_b = 5\nvar_c = 'A'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nans_dict = dict()\nvar_d = str(var_d)\nlist_b = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_d) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_b.append(new_elem)\nvar_e = 256\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "791": {
        "category": "Geometry",
        "question_ko": "두 쌍의 대변이 평행한 사각형이 있습니다. 이 사각형의 높이는 8센티미터(㎝)이고, 넓이는 78.88제곱센티미터(㎠)일 때, 밑변의 길이는 얼마인지 구하시오.",
        "question_en": "A square has two pairs of parallel sides. If the height of this square is 8 centimeters (cm) and the area is 78.88 square cm (cm2), what is the length?",
        "answer_ko": "9.86",
        "answer_en": "9.86",
        "solution_abst_ko": "78.88 8 [OP_DIV]",
        "solution_abst_en": "78.88 8 [OP_DIV]",
        "solution_code_ko": "var_a = 78.88\nvar_b = 8\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 78.88\nvar_b = 8\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "792": {
        "category": "Arithmetic calculation",
        "question_ko": "지영이가 동화책을 펼쳤더니 펼친 두 면의 쪽수의 합이 217이었습니다. 펼친 두 면의 쪽수의 곱은 얼마입니까?",
        "question_en": "When Jiyoung opened the fairy tale book, the sum of the pages on the two pages she opened was 217. What is the product of the number of pages unfolded?",
        "answer_ko": "11772",
        "answer_en": "11772",
        "solution_abst_ko": "217 2 [OP_FDIV] 217 2 [OP_FDIV] 1 [OP_ADD] [OP_MUL]",
        "solution_abst_en": "217 2 [OP_FDIV] 217 2 [OP_FDIV] 1 [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 217\nvar_b = 2\nvar_c = var_a // var_b\nvar_d = 217\nvar_e = 2\nvar_f = var_d // var_e\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = var_c * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 217\nvar_b = 2\nvar_c = var_a // var_b\nvar_d = 217\nvar_e = 2\nvar_f = var_d // var_e\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = var_c * var_h\nprint(int(var_i))"
    },
    "793": {
        "category": "Geometry",
        "question_ko": "어떤 사다리꼴의 넓이가 96.9제곱센티미터(㎠)입니다. 아랫변이 윗변보다 3.6센티미터(㎝) 더 짧고, 높이가 5.2센티미터(㎝)라면 아랫변은 몇 센티미터(㎝)입니까?",
        "question_en": "The area of a trapezoid is 96.9 square centimeters (cm2). If the lower side is 3.6 centimeters (cm) shorter than the upper side and the height is 5.2 centimeters (cm), how many centimeters (cm) is the lower side?",
        "answer_ko": "16.85",
        "answer_en": "16.85",
        "solution_abst_ko": "96.98 2 [OP_MUL] 5.2 [OP_DIV] 3.6 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "96.98 2 [OP_MUL] 5.2 [OP_DIV] 3.6 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 96.98\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 5.2\nvar_e = var_c / var_d\nvar_f = 3.6\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 96.98\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 5.2\nvar_e = var_c / var_d\nvar_f = 3.6\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "794": {
        "category": "Arithmetic calculation",
        "question_ko": "2부터 100까지의 수 중에서 한 자리 수는 모두 몇 개인지 구하시오.",
        "question_en": "Find how many single digits are in all from 2 to 100.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "2 100 1 [OP_LIST_ARANGE] 9 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "2 100 1 [OP_LIST_ARANGE] 9 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 2\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 9\nlist_b = []\nfor i in list_a:\n    if i <= var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 9\nlist_b = []\nfor i in list_a:\n    if i <= var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "795": {
        "category": "Possibility",
        "question_ko": "사과 54개를 접시에 남김없이 똑같이 나누어 담으려고 합니다. 접시에 나누어 담을 수 있는 방법은 모두 몇 가지일까요? (단, 사과 54개를 접시 한 개에 모두 담지 않습니다.)",
        "question_en": "We are going to divide 54 apples equally into every plate. How many different ways can you portion it out on a plate? (However, not all 54 apples are placed on one plate.)",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "54 [OP_LIST_GET_DIVISOR] [OP_LIST_SOL] 54 [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_abst_en": "54 [OP_LIST_GET_DIVISOR] [OP_LIST_SOL] 54 [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 54\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 54\nlist_b= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_b.append(var_b)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_c = len(list_c)\nprint(int(var_c))",
        "solution_code_en": "var_a = 54\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 54\nlist_b= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_b.append(var_b)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_c = len(list_c)\nprint(int(var_c))"
    },
    "796": {
        "category": "Geometry",
        "question_ko": "가로가 262센티미터(㎝)이고 세로가 185센티미터(㎝)인 직사각형 모양의 큰 도화지를 오려서 한 변이 18센티미터(㎝)인 정사각형 모양의 작은 종이를 될 수 있는 대로 많이 만들려고 합니다. 정사각형 모양의 종이는 모두 몇 장까지 만들 수 있는지 구해 보시오.",
        "question_en": "You are going to make as many small square pieces as possible by cutting out a large rectangular piece of paper measuring 262 centimeters (cm) long and 185 centimeters (cm) wide. Find how many square pieces of paper you can make.",
        "answer_ko": "140",
        "answer_en": "140",
        "solution_abst_ko": "262 18 [OP_FDIV] 185 18 [OP_FDIV] [OP_MUL]",
        "solution_abst_en": "262 18 [OP_FDIV] 185 18 [OP_FDIV] [OP_MUL]",
        "solution_code_ko": "var_a = 262\nvar_b = 18\nvar_c = var_a // var_b\nvar_d = 185\nvar_e = 18\nvar_f = var_d // var_e\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 262\nvar_b = 18\nvar_c = var_a // var_b\nvar_d = 185\nvar_e = 18\nvar_f = var_d // var_e\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "797": {
        "category": "Correspondence",
        "question_ko": "2A3+36=269일 때, A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "If 2A3+36=269, what number should go in A?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "2A3+36=269 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "2A3+36=269 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '2A3+36=269'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '2A3+36=269'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "798": {
        "category": "Arithmetic calculation",
        "question_ko": "태형이와 남준이는 색종이를 각각 10장씩 사서 그중에서 몇 장을 사용했습니다. 태형이가 남은 색종이 중 3장을 남준이에게 주었더니 두 사람이 가지고 있는 색종이의 수는 각각 6장이 되었습니다. 남준이가 사용한 색종이는 몇 장입니까?",
        "question_en": "Taehyung and Namjoon bought 10 pieces of colored paper each and used several of them. When Taehyung gave 3 of the remaining pieces of colored paper to Namjoon, the number of pieces of colored paper they both had ended up to 6. How many pieces of colored paper did Namjoon use?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "10 6 3 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "10 6 3 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 6\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 6\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "799": {
        "category": "Correspondence",
        "question_ko": "하나에 530원인 사탕 12개가 초코릿 8개보다 5400원이 더 비싸다. 초콜릿 하나는 얼마인지 구하시오.",
        "question_en": "Twelve candies that cost 530 won each, cost 5,400 won more than 8 chocolates. How much is one chocolate?",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "530 12 [OP_MUL] 5400 [OP_SUB] 8 [OP_DIV]",
        "solution_abst_en": "530 12 [OP_MUL] 5400 [OP_SUB] 8 [OP_DIV]",
        "solution_code_ko": "var_a = 530\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 5400\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 530\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 5400\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "800": {
        "category": "Possibility",
        "question_ko": "3, 5, 6, 7 총 4장의 수 카드 중 2장을 사용하여 두 자리 수를 만들려고 합니다. 만들 수 있는 7의 배수의 평균을 구하시오.",
        "question_en": "You are about to make two-digit numbers by using two of the four cards 3, 5, 6, and 7. Find the average of the multiples of 7 you can make.",
        "answer_ko": "51.33",
        "answer_en": "51.33",
        "solution_abst_ko": "[OP_LIST_SOL] 3 5 6 7 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 7 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MEAN]",
        "solution_abst_en": "[OP_LIST_SOL] 3 5 6 7 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 7 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MEAN]",
        "solution_code_ko": "var_a = 3\nvar_b = 5\nvar_c = 6\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 7\nlist_c = []\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nvar_g = 1\nlist_c = [float(i) for i in list_c]\nvar_h = sum(list_c)/len(list_c)\nprint('{:.2f}'.format(round(var_h+1e-10,2)))",
        "solution_code_en": "var_a = 3\nvar_b = 5\nvar_c = 6\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 7\nlist_c = []\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nvar_g = 1\nlist_c = [float(i) for i in list_c]\nvar_h = sum(list_c)/len(list_c)\nprint('{:.2f}'.format(round(var_h+1e-10,2)))"
    },
    "801": {
        "category": "Comparison",
        "question_ko": "재윤이는 훌라후프를 2분 5초 동안 돌렸고 승아는 183초 동안 돌렸습니다. 훌라후프를 더 오래 돌린 사람은 누구인지 답을 구해 보세요.",
        "question_en": "Jaeyoon spun the hula hoop for 2 minutes and 5 seconds, and Seungah spun it for 183 seconds. Find out who spun the hula hoop longer.",
        "answer_ko": "승아",
        "answer_en": "Seungah",
        "solution_abst_ko": "[OP_LIST_SOL] 재윤 승아 [OP_LIST_EOL] [OP_LIST_SOL] 2 60 [OP_MUL] 5 [OP_ADD] 183 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jaeyoon Seungah [OP_LIST_EOL] [OP_LIST_SOL] 2 60 [OP_MUL] 5 [OP_ADD] 183 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '재윤'\nvar_b = '승아'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nvar_d = 60\nvar_e = var_c * var_d\nvar_f = 5\nvar_g = var_e + var_f\nvar_h = 183\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Jaeyoon'\nvar_b = 'Seungah'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nvar_d = 60\nvar_e = var_c * var_d\nvar_f = 5\nvar_g = var_e + var_f\nvar_h = 183\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "802": {
        "category": "Correspondence",
        "question_ko": "한 자리 수 A, B가 있습니다. 72의 배수인 숫자 A4461B가 있을 때, A와 B의 합은 무엇입니까?",
        "question_en": "There are single digit numbers A and B. Given the number A4461B which is a multiple of 72, what is the sum of A and B?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "A4461B [OP_GEN_POSSIBLE_LIST] 72 [OP_LIST_DIVISIBLE] A4461B A [OP_LIST_FIND_UNK] A4461B B [OP_LIST_FIND_UNK] [OP_ADD]",
        "solution_abst_en": "A4461B [OP_GEN_POSSIBLE_LIST] 72 [OP_LIST_DIVISIBLE] A4461B A [OP_LIST_FIND_UNK] A4461B B [OP_LIST_FIND_UNK] [OP_ADD]",
        "solution_code_ko": "var_a = 'A4461B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 72\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 'A4461B'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nvar_e = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_e = int(elem[unk_idx])\nvar_f = 'A4461B'\nvar_g = 'B'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nvar_i = var_e + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 'A4461B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 72\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 'A4461B'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nvar_e = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_e = int(elem[unk_idx])\nvar_f = 'A4461B'\nvar_g = 'B'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nvar_i = var_e + var_h\nprint(int(var_i))"
    },
    "803": {
        "category": "Correspondence",
        "question_ko": "민영이가 107.8 을 어떤 수로 곱하였더니 9.8 이 되었습니다. 어떤 수는 얼마인지 구하시오.",
        "question_en": "Minyeong multiplied 107.8 by a certain number and it was 9.8. Find out what number it is.",
        "answer_ko": "0.09",
        "answer_en": "0.09",
        "solution_abst_ko": "9.8 107.8 [OP_DIV]",
        "solution_abst_en": "9.8 107.8 [OP_DIV]",
        "solution_code_ko": "var_a = 9.8\nvar_b = 107.8\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 9.8\nvar_b = 107.8\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "804": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 20까지 홀수를 모두 더하시오.",
        "question_en": "Add all odd numbers from 1 to 20.",
        "answer_ko": "100",
        "answer_en": "100",
        "solution_abst_ko": "1 20 [OP_LIST_ODD] [OP_LIST_SUM]",
        "solution_abst_en": "1 20 [OP_LIST_ODD] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 20\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nprint(int(var_c))",
        "solution_code_en": "var_a = 1\nvar_b = 20\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nprint(int(var_c))"
    },
    "805": {
        "category": "Correspondence",
        "question_ko": "어떤 과자는 한 박스에 9개씩 묶음이 들어있고, 1개 묶음에 7개의 과자가 들어있다. 이 과자가 13 박스가 있다면 몇 개의 과자가 있는지 구하시오.",
        "question_en": "Some cookies come in bundles of 9 in a box, and there are 7 cookies in each bundle. If there are 13 boxes of these cookies, how many cookies are there?",
        "answer_ko": "819",
        "answer_en": "819",
        "solution_abst_ko": "13 9 [OP_MUL] 7 [OP_MUL]",
        "solution_abst_en": "13 9 [OP_MUL] 7 [OP_MUL]",
        "solution_code_ko": "var_a = 13\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 13\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "806": {
        "category": "Geometry",
        "question_ko": "길이가 27.9센티미터(㎝)인 철사를 3.1센티미터(㎝)씩 자르면 몇 토막으로 잘리는지 구하시오.",
        "question_en": "How many pieces can be cut if a wire of length 27.9 centimeters (cm) is cut by 3.1 centimeters (cm)?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "27.9 3.1 [OP_DIV]",
        "solution_abst_en": "27.9 3.1 [OP_DIV]",
        "solution_code_ko": "var_a = 27.9\nvar_b = 3.1\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 27.9\nvar_b = 3.1\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "807": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 20센티미터(㎝)인 정사각형 모양의 틀이 있다. 이 안에 원 모양의 메달을 보관하려고 하는데, 보관할 수 있는 가장 큰 메달의 넓이는 얼마인지 구하시오. 단, 원주율은 3.14로 가정한다.",
        "question_en": "There is a frame in the shape of a square with a side length of 20 centimeters (cm). What is the area of the largest medallion that can be stored in a circular medallion? However, the ratio of circumference is assumed to be 3.14.",
        "answer_ko": "314",
        "answer_en": "314",
        "solution_abst_ko": "3.14 20 2 [OP_DIV] [OP_MUL] 20 2 [OP_DIV] [OP_MUL]",
        "solution_abst_en": "3.14 20 2 [OP_DIV] [OP_MUL] 20 2 [OP_DIV] [OP_MUL]",
        "solution_code_ko": "var_a = 3.14\nvar_b = 20\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 20\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = var_e * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 3.14\nvar_b = 20\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 20\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = var_e * var_h\nprint(int(var_i))"
    },
    "808": {
        "category": "Possibility",
        "question_ko": "5, 0, 8, 6, 2 중 서로 다른 3개의 숫자를 뽑아 만들 수 있는 세 자리 수 중 2번째로 큰 수에서 3번째로 작은 수를 뺀 값은 얼마입니까?",
        "question_en": "What is the 2nd largest minus the 3rd smallest 3-digit number that can be formed by drawing 3 different numbers from 5, 0, 8, 6, and 2?",
        "answer_ko": "654",
        "answer_en": "654",
        "solution_abst_ko": "[OP_LIST_SOL] 5 0 8 6 2 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 5 0 8 6 2 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 5\nvar_b = 0\nvar_c = 8\nvar_d = 6\nvar_e = 2\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 5\nvar_b = 0\nvar_c = 8\nvar_d = 6\nvar_e = 2\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h - var_j\nprint(int(var_k))"
    },
    "809": {
        "category": "Arithmetic calculation",
        "question_ko": "연속하는 5개의 자연수의 합이 90입니다. 이 자연수 중 가장 큰 수는 무엇입니까?",
        "question_en": "The sum of five consecutive natural numbers is 90. What is the largest of these natural numbers?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "90 0 5 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 5 [OP_DIV] 5 1 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "90 0 5 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 5 [OP_DIV] 5 1 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 90\nvar_b = 0\nvar_c = 5\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nlist_a = [i for i in range(var_b, var_e + 1, var_f)]\nlist_a = [float(i) for i in list_a]\nvar_g = sum(list_a)\nvar_h = var_a - var_g\nvar_i = 5\nvar_j = var_h / var_i\nvar_k = 5\nvar_l = 1\nvar_m = var_k - var_l\nvar_n = var_j + var_m\nprint(int(var_n))",
        "solution_code_en": "var_a = 90\nvar_b = 0\nvar_c = 5\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nlist_a = [i for i in range(var_b, var_e + 1, var_f)]\nlist_a = [float(i) for i in list_a]\nvar_g = sum(list_a)\nvar_h = var_a - var_g\nvar_i = 5\nvar_j = var_h / var_i\nvar_k = 5\nvar_l = 1\nvar_m = var_k - var_l\nvar_n = var_j + var_m\nprint(int(var_n))"
    },
    "810": {
        "category": "Arithmetic calculation",
        "question_ko": "감이 몇 개 있었습니다. 그중에서 5개를 먹었더니 12개가 남았습니다. 처음에 있던 감은 몇 개입니까?",
        "question_en": "I had a few persimmons. I ate 5 of them, and there are 12 left. How many persimmons were there at first?",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "12 5 [OP_ADD]",
        "solution_abst_en": "12 5 [OP_ADD]",
        "solution_code_ko": "var_a = 12\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 12\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "811": {
        "category": "Comparison",
        "question_ko": "민영이와 은지가 귤을 땄습니다. 민영이는 10/12킬로그램(㎏)을 따고, 은지는 5/12킬로그램(㎏)을 땄습니다. 누가 귤을 더 많이 땄습니까?",
        "question_en": "Minyoung and Eunji picked tangerines. Minyoung picked up 10/12 kg (kg), and Eunji picked up 5/12 kg (kg). Who picked more tangerines?",
        "answer_ko": "민영",
        "answer_en": "Minyoung",
        "solution_abst_ko": "[OP_LIST_SOL] 민영 은지 [OP_LIST_EOL] [OP_LIST_SOL] 10/12 5/12 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Minyoung Eunji [OP_LIST_EOL] [OP_LIST_SOL] 10/12 5/12 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '민영'\nvar_b = '은지'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.8333333333333334\nvar_d = 0.4166666666666667\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Minyoung'\nvar_b = 'Eunji'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.8333333333333334\nvar_d = 0.4166666666666667\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "812": {
        "category": "Arithmetic calculation",
        "question_ko": "연필 1000타를 생산하기 위해 하루에 연필을 370자루씩 생산하는 기계를 사용한다면 며칠 후에 작업이 완료됩니까?",
        "question_en": "If you use a machine that produces 370 pencils a day to produce 1000 pencils, how many days will it be finished?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "1000 370 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "1000 370 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 1000\nvar_b = 370\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))",
        "solution_code_en": "var_a = 1000\nvar_b = 370\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))"
    },
    "813": {
        "category": "Comparison",
        "question_ko": "정국이는 6에서 3을 곱한 수를 모았고, 윤기는 4를 모았습니다. 누구의 수가 더 작나요?",
        "question_en": "Compare the number they have: Jungkook is with the number of 6 multiplied by 3, and Yoongi is with 4. Whose number is smaller?",
        "answer_ko": "윤기",
        "answer_en": "Yoongi",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 윤기 [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_MUL] 4 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Yoongi [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_MUL] 4 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '윤기'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 3\nvar_e = var_c * var_d\nvar_f = 4\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Yoongi'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 3\nvar_e = var_c * var_d\nvar_f = 4\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "814": {
        "category": "Correspondence",
        "question_ko": "어떤 수는 4와 9 사이에 있는 한 자리 수입니다. 어떤 수는 6보다 작습니다. 어떤 수를 구하시오.",
        "question_en": "A certain number is a single digit number that is between 4 and 9. That number is less than 6. Find that number.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "4 1 [OP_ADD] 9 1 [OP_SUB] 1 [OP_LIST_ARANGE] 6 [OP_LIST_LESS] 1 [OP_LIST_GET]",
        "solution_abst_en": "4 1 [OP_ADD] 9 1 [OP_SUB] 1 [OP_LIST_ARANGE] 6 [OP_LIST_LESS] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 4\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = 6\nlist_b = []\nfor i in list_a:\n    if i < var_h:\n        list_b.append(i)\nvar_i = 1\nvar_j = list_b[var_i-1]\nprint(int(var_j))",
        "solution_code_en": "var_a = 4\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = 6\nlist_b = []\nfor i in list_a:\n    if i < var_h:\n        list_b.append(i)\nvar_i = 1\nvar_j = list_b[var_i-1]\nprint(int(var_j))"
    },
    "815": {
        "category": "Geometry",
        "question_ko": "다섯 개의 변으로 이루어진 도형의 모든 변의 길이가 같고, 이 도형의 둘레가 23.4센티미터(㎝)라면 한 변의 길이는 몇 센티미터(㎝)일지 구하시오.",
        "question_en": "If all sides of a five-sided figure are the same length and the perimeter of the figure is 23.4 centimeters (cm), how many centimeters (cm) is the length of one side?",
        "answer_ko": "4.68",
        "answer_en": "4.68",
        "solution_abst_ko": "23.4 5 [OP_DIV]",
        "solution_abst_en": "23.4 5 [OP_DIV]",
        "solution_code_ko": "var_a = 23.4\nvar_b = 5\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 23.4\nvar_b = 5\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "816": {
        "category": "Arithmetic calculation",
        "question_ko": "지하철에 35명의 사람이 타고 있었는데 18명이 내리고 15명이 탔습니다. 지하철 안에 얼마나 많은 사람이 줄었는지 구하시오.",
        "question_en": "There were 35 people on the subway, 18 got off and 15 got on. Find out the number of passengers decreased in the subway.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "35 35 18 [OP_SUB] 15 [OP_ADD] [OP_SUB]",
        "solution_abst_en": "35 35 18 [OP_SUB] 15 [OP_ADD] [OP_SUB]",
        "solution_code_ko": "var_a = 35\nvar_b = 35\nvar_c = 18\nvar_d = var_b - var_c\nvar_e = 15\nvar_f = var_d + var_e\nvar_g = var_a - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 35\nvar_b = 35\nvar_c = 18\nvar_d = var_b - var_c\nvar_e = 15\nvar_f = var_d + var_e\nvar_g = var_a - var_f\nprint(int(var_g))"
    },
    "817": {
        "category": "Geometry",
        "question_ko": "정사각형 모양의 공원의 한 변의 길이는 200미터(m)입니다. 이 공원의 넓이를 구하시오.",
        "question_en": "Each side of the square-shaped park is 200 meters (m). Find the area of this park.",
        "answer_ko": "40000",
        "answer_en": "40000",
        "solution_abst_ko": "200 2 [OP_POW]",
        "solution_abst_en": "200 2 [OP_POW]",
        "solution_code_ko": "var_a = 200\nvar_b = 2\nvar_c = var_a ** var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 200\nvar_b = 2\nvar_c = var_a ** var_b\nprint(int(var_c))"
    },
    "818": {
        "category": "Possibility",
        "question_ko": "6명의 사람들이 서로 다른 사람들과 한번씩 악수를 할때 악수는 총 몇번 진행됩니까?",
        "question_en": "If 6 people shake each other's hand once, how many handshakes are there in total?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "6 6 1 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "6 6 1 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 6\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 6\nvar_b = 6\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "819": {
        "category": "Correspondence",
        "question_ko": "3A4B에 1000을 더한 값은 6233보다 작습니다. 0부터 9까지의 숫자 중 A에 쓸 수 있는 숫자는 모두 몇 개입니까?",
        "question_en": "3A4B plus 1000 is less than 6233. How many digits from 0 to 9 can be written for A?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "3A4B [OP_GEN_POSSIBLE_LIST] 6233 1000 [OP_SUB] [OP_LIST_LESS] 3A4B A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_abst_en": "3A4B [OP_GEN_POSSIBLE_LIST] 6233 1000 [OP_SUB] [OP_LIST_LESS] 3A4B A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '3A4B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 6233\nvar_c = 1000\nvar_d = var_b - var_c\nlist_b = []\nfor i in list_a:\n    if i < var_d:\n        list_b.append(i)\nvar_e = '3A4B'\nvar_f = 'A'\nvar_e = str(var_e)\nvar_f = str(var_f)\nunk_idx = var_e.index(var_f)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nvar_g = len(list_c)\nprint(int(var_g))",
        "solution_code_en": "var_a = '3A4B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 6233\nvar_c = 1000\nvar_d = var_b - var_c\nlist_b = []\nfor i in list_a:\n    if i < var_d:\n        list_b.append(i)\nvar_e = '3A4B'\nvar_f = 'A'\nvar_e = str(var_e)\nvar_f = str(var_f)\nunk_idx = var_e.index(var_f)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nvar_g = len(list_c)\nprint(int(var_g))"
    },
    "820": {
        "category": "Arithmetic calculation",
        "question_ko": "바나나우유 3리터(L)를 세 친구가 나누어 마시려고 합니다. 진솔이는 현주보다 200밀리리터(㎖) 많게, 현주는 창혁이보다 200밀리리터(㎖) 많게 마시려면 현주에게 몇 밀리리터(㎖)의 바나나우유를 나누어 주어야 합니까?",
        "question_en": "Three friends are going to share 3 liters (L) of banana milk. How many milliliters (mL) of banana milk do you have to share with Hyeonju so that Jinsol drinks 200 milliliters (㎖) more than Hyeonju, and Hyunju drinks 200 milliliters (㎖) more than Changhyeok?",
        "answer_ko": "1000",
        "answer_en": "1000",
        "solution_abst_ko": "3 1000 [OP_MUL] 200 [OP_ADD] 200 [OP_SUB] 3 [OP_DIV]",
        "solution_abst_en": "3 1000 [OP_MUL] 200 [OP_ADD] 200 [OP_SUB] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 3\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 200\nvar_e = var_c + var_d\nvar_f = 200\nvar_g = var_e - var_f\nvar_h = 3\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 3\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 200\nvar_e = var_c + var_d\nvar_f = 200\nvar_g = var_e - var_f\nvar_h = 3\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "821": {
        "category": "Correspondence",
        "question_ko": "A-B-B-B=303.1 입니다. A를 10으로 나누면 B와 같습니다. A를 구하시오",
        "question_en": "A-B-B-B=303.1 . Dividing A by 10 equals B. find A",
        "answer_ko": "433",
        "answer_en": "433",
        "solution_abst_ko": "303.1 10 3 [OP_SUB] [OP_DIV] 10 [OP_MUL]",
        "solution_abst_en": "303.1 10 3 [OP_SUB] [OP_DIV] 10 [OP_MUL]",
        "solution_code_ko": "var_a = 303.1\nvar_b = 10\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 10\nvar_g = var_e * var_f\nprint(int(eval('{:.2f}'.format(round(var_g+1e-10,2)))))",
        "solution_code_en": "var_a = 303.1\nvar_b = 10\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 10\nvar_g = var_e * var_f\nprint(int(eval('{:.2f}'.format(round(var_g+1e-10,2)))))"
    },
    "822": {
        "category": "Possibility",
        "question_ko": "500보다 큰 세자리 자연수 중 각 자리수의 합이 7인 숫자는 몇 개 인지 구하시오.",
        "question_en": "How many 3-digit numbers greater than 500 are such that the sum of each digit is 7?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "100 999 1 [OP_LIST_ARANGE] 500 [OP_LIST_MORE] [OP_LIST_NUM2SUM] 7 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "100 999 1 [OP_LIST_ARANGE] 500 [OP_LIST_MORE] [OP_LIST_NUM2SUM] 7 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 500\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 7\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))",
        "solution_code_en": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 500\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 7\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))"
    },
    "823": {
        "category": "Arithmetic calculation",
        "question_ko": "윤기가 8월, 9월에 본 영어 시험의 평균 점수는 86점입니다. 윤기가 10월에 본 영어 시험 점수가 98점일 때, 3달 동안의 영어 시험의 평균 점수를 구하시오.",
        "question_en": "Yoongi's average score on the English test taken in August and September was 86. If Yoongi's English test score was 98 points in October, find the average score of the English test for 3 months.",
        "answer_ko": "90",
        "answer_en": "90",
        "solution_abst_ko": "86 2 [OP_MUL] 98 [OP_ADD] 3 [OP_DIV]",
        "solution_abst_en": "86 2 [OP_MUL] 98 [OP_ADD] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 86\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 98\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 86\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 98\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "824": {
        "category": "Geometry",
        "question_ko": "가로가 50센티미터(㎝), 세로가 35센티미터(㎝), 높이가 40센티미터(㎝)인 뚜껑이 없는 직육면체 모양의 상자를 만들었습니다. 가로, 세로가 각각 1센티미터(㎝)인 타일을 상자의 바깥쪽 겉면에 빈틈없이 붙이려고 할 때, 타일은 적어도 몇 개 필요합니까?",
        "question_en": "A cuboid box is made without a lid, and it is 50 centimeters (cm) wide, 35 centimeters (cm) long, and 40 centimeters (cm) high. How many tiles do you need at least if you want to attach tiles that are 1 centimeter (cm) wide and 1 centimeter (cm) long to the outer surface of the box without any gap? ",
        "answer_ko": "8550",
        "answer_en": "8550",
        "solution_abst_ko": "50 35 [OP_MUL] 50 40 [OP_MUL] 2 [OP_MUL] 40 35 [OP_MUL] 2 [OP_MUL] [OP_ADD] [OP_ADD]",
        "solution_abst_en": "50 35 [OP_MUL] 50 40 [OP_MUL] 2 [OP_MUL] 40 35 [OP_MUL] 2 [OP_MUL] [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 50\nvar_b = 35\nvar_c = var_a * var_b\nvar_d = 50\nvar_e = 40\nvar_f = var_d * var_e\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = 40\nvar_j = 35\nvar_k = var_i * var_j\nvar_l = 2\nvar_m = var_k * var_l\nvar_n = var_h + var_m\nvar_o = var_c + var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 50\nvar_b = 35\nvar_c = var_a * var_b\nvar_d = 50\nvar_e = 40\nvar_f = var_d * var_e\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = 40\nvar_j = 35\nvar_k = var_i * var_j\nvar_l = 2\nvar_m = var_k * var_l\nvar_n = var_h + var_m\nvar_o = var_c + var_n\nprint(int(var_o))"
    },
    "825": {
        "category": "Geometry",
        "question_ko": "변이 총 9개로 이루어져 있으며, 각 길이가 2센티미터(㎝)인 도형의 둘레를 구하시오.",
        "question_en": "Find the perimeter of a figure with a total of 9 sides, each 2 centimeters (cm) long.",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "2 9 [OP_MUL]",
        "solution_abst_en": "2 9 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 9\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 9\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "826": {
        "category": "Comparison",
        "question_ko": "1.4, 9/10, 1.2, 0.5, 13/10에서 1.1보다 작거나 같은 숫자를 나열한뒤, 가장 큰 숫자를 구하면 얼마입니까?",
        "question_en": "In 1.4, 9/10, 1.2, 0.5, and 13/10, if you list the numbers less than or equal to 1.1, what is the largest number?",
        "answer_ko": "0.90",
        "answer_en": "0.9",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS_EQUAL] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS_EQUAL] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i <= var_f:\n        list_b.append(i)\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nprint('{:.2f}'.format(round(var_h+1e-10,2)))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i <= var_f:\n        list_b.append(i)\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nprint('{:.2f}'.format(round(var_h+1e-10,2)))"
    },
    "827": {
        "category": "Arithmetic calculation",
        "question_ko": "도로의 한쪽에 처음부터 끝까지 25미터(m) 간격으로 가로수를 심으려고 합니다. 도로의 길이가 2575미터(m)일 때 심을 가로수는 몇 그루 입니까?",
        "question_en": "If there is a plan to plant trees on one side of the road at intervals of 25 meters (m) including the first and the last point, how many trees will be planted when the length of the road is 2575 meters (m)?",
        "answer_ko": "104",
        "answer_en": "104",
        "solution_abst_ko": "2575 25 [OP_DIV] 1 [OP_ADD]",
        "solution_abst_en": "2575 25 [OP_DIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 2575\nvar_b = 25\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 2575\nvar_b = 25\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "828": {
        "category": "Comparison",
        "question_ko": "윤기는 4, 유나는 5, 정국이는 6에서 3을 곱한 수를 모았습니다. 누가 제일 작은 수를 모았나요?",
        "question_en": "Yoongi got 4, and Yuna got 5, and Jungkook got the numbr that is 6 multiplied by 3. Who got the smallest number?",
        "answer_ko": "윤기",
        "answer_en": "Yoongi",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 유나 정국 [OP_LIST_EOL] [OP_LIST_SOL] 4 5 6 3 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Yuna Jungkook [OP_LIST_EOL] [OP_LIST_SOL] 4 5 6 3 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '유나'\nvar_c = '정국'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 5\nvar_f = 6\nvar_g = 3\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Yuna'\nvar_c = 'Jungkook'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 5\nvar_f = 6\nvar_g = 3\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "829": {
        "category": "Arithmetic calculation",
        "question_ko": "재웅이 아버지는 매일 130번씩 윗몸일으키기를 하고 있습니다. 2주일 동안 윗몸일으키기를 모두 몇 번 할까요?",
        "question_en": "Jaewoong's father does 130 sit-ups every day. How many sit-ups will he do in 2 weeks?",
        "answer_ko": "1820",
        "answer_en": "1820",
        "solution_abst_ko": "130 7 [OP_MUL] 2 [OP_MUL]",
        "solution_abst_en": "130 7 [OP_MUL] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 130\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 130\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "830": {
        "category": "Possibility",
        "question_ko": "숫자 카드 7, 1, 0이 주어졌을 때, 주어진 숫자 카드를 한 번씩 모두 사용하여 만들 수 있는 수 중 가장 큰 수를 구하시오.",
        "question_en": "When the number cards 7, 1, and 0 are given, find the largest number that can be made by using all of the given number cards at least once.",
        "answer_ko": "710",
        "answer_en": "710",
        "solution_abst_ko": "[OP_LIST_SOL] 7 1 0 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 7 1 0 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 7\nvar_b = 1\nvar_c = 0\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))",
        "solution_code_en": "var_a = 7\nvar_b = 1\nvar_c = 0\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))"
    },
    "831": {
        "category": "Geometry",
        "question_ko": "진우는 정사각형 모양의 타일을 여러 장 가지고 있습니다. 이 타일을 빈틈없이 늘어놓아 큰 정사각형을 만들었더니 3장의 타일이 남았습니다. 만든 정사각형의 가로 한 변과 세로 한 변을 2열씩 늘리려면 44장의 타일이 더 필요하다고 합니다. 규형이는 타일 몇 장을 가지고 있습니까?",
        "question_en": "Jinwoo has several square-shaped tiles. These tiles are lined up to make a large square, and there are 3 tiles left. It is said that 44 more tiles are needed to increase each side of the square by 2 columns. How many tiles does Jinwoo have?",
        "answer_ko": "103",
        "answer_en": "103",
        "solution_abst_ko": "44 4 [OP_SUB] 4 [OP_DIV] 2 [OP_POW] 3 [OP_ADD]",
        "solution_abst_en": "44 4 [OP_SUB] 4 [OP_DIV] 2 [OP_POW] 3 [OP_ADD]",
        "solution_code_ko": "var_a = 44\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e ** var_f\nvar_h = 3\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 44\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e ** var_f\nvar_h = 3\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "832": {
        "category": "Arithmetic calculation",
        "question_ko": "45개의 묶음에는 10개씩 들어있습니다. 전체 개수에 100개씩 추가하는 과정을 3번을 반복하면 전체 개수는 얼마입니까?",
        "question_en": "Packs of 45 contain 10 each. If we repeat the process of adding 100 to the total number 3 times, what is the total number?",
        "answer_ko": "750",
        "answer_en": "750",
        "solution_abst_ko": "10 45 [OP_MUL] 100 3 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "10 45 [OP_MUL] 100 3 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 45\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 10\nvar_b = 45\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "833": {
        "category": "Geometry",
        "question_ko": "길이가 10센티미터(㎝)인 종이 20장을 연결 부분을 5밀리미터(㎜)로 하여 이어 붙였습니다. 이어 붙인 종이 전체의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "Twenty sheets of paper with a length of 10 centimeters (cm) were joined together with a joint of 5 millimeters (mm). How many centimeters (cm) is the total length of the joined paper?",
        "answer_ko": "190.50",
        "answer_en": "190.5",
        "solution_abst_ko": "10 20 [OP_MUL] 5 10 [OP_DIV] 20 1 [OP_SUB] [OP_MUL] [OP_SUB]",
        "solution_abst_en": "10 20 [OP_MUL] 5 10 [OP_DIV] 20 1 [OP_SUB] [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = 10\nvar_f = var_d / var_e\nvar_g = 20\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = var_f * var_i\nvar_k = var_c - var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 10\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = 10\nvar_f = var_d / var_e\nvar_g = 20\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = var_f * var_i\nvar_k = var_c - var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "834": {
        "category": "Arithmetic calculation",
        "question_ko": "설탕물 200그램(g)의 진하기는 25%입니다. 다른 설탕물 300그램(g)에는 설탕 60그램(g)이 들어있고 두 설탕물을 섞었을 때의 설탕물의 진하기는 몇 %인지 구하세요.",
        "question_en": "The concentration of 200 grams (g) of sugar water is 25%. If 300 grams (g) of another sugar water contains 60 grams (g) of sugar, find the percent concentration of the sugar water when the two sugar waters are mixed.",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "200 25 100 [OP_DIV] [OP_MUL] 60 [OP_ADD] 200 300 [OP_ADD] [OP_DIV] 100 [OP_MUL]",
        "solution_abst_en": "200 25 100 [OP_DIV] [OP_MUL] 60 [OP_ADD] 200 300 [OP_ADD] [OP_DIV] 100 [OP_MUL]",
        "solution_code_ko": "var_a = 200\nvar_b = 25\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 60\nvar_g = var_e + var_f\nvar_h = 200\nvar_i = 300\nvar_j = var_h + var_i\nvar_k = var_g / var_j\nvar_l = 100\nvar_m = var_k * var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 200\nvar_b = 25\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 60\nvar_g = var_e + var_f\nvar_h = 200\nvar_i = 300\nvar_j = var_h + var_i\nvar_k = var_g / var_j\nvar_l = 100\nvar_m = var_k * var_l\nprint(int(var_m))"
    },
    "835": {
        "category": "Comparison",
        "question_ko": "미나네 학교의 3학년과 4학년 학생 수의 합은 531명입니다. 4학년 학생은 3학년 학생보다 31명 더 많고, 3학년 남학생은 3학년 여학생보다 22명 더 많다고 합니다. 3학년 남학생은 몇 명인지 구하시오.",
        "question_en": "The sum of the 3rd and 4th year students at Mina's school is 531. There are 31 more 4th year students than 3rd year students, and 22 more 3rd year boys than 3rd year girls. Find the number of boys in 3rd grade.",
        "answer_ko": "136",
        "answer_en": "136",
        "solution_abst_ko": "531 31 [OP_SUB] 2 [OP_DIV] 22 [OP_SUB] 2 [OP_DIV] 22 [OP_ADD]",
        "solution_abst_en": "531 31 [OP_SUB] 2 [OP_DIV] 22 [OP_SUB] 2 [OP_DIV] 22 [OP_ADD]",
        "solution_code_ko": "var_a = 531\nvar_b = 31\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 22\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nvar_j = 22\nvar_k = var_i + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 531\nvar_b = 31\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 22\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nvar_j = 22\nvar_k = var_i + var_j\nprint(int(var_k))"
    },
    "836": {
        "category": "Comparison",
        "question_ko": "새로 전학 온 윤정이의 사물함은 왼쪽에서 7번째, 오른쪽에서 13번째, 위에서 8번째, 아래에서 14번째에 있습니다. 각 줄마다 있는 사물함의 수가 같다고 할 때, 사물함의 개수는 모두 몇 개입니까?",
        "question_en": "The locker for the new transfer student, Yunjeong, is 7th from the left, 13th from the right, 8th from the front, and 14th from the back. If the number of lockers in each row is the same, what is the total number of lockers?",
        "answer_ko": "399",
        "answer_en": "399",
        "solution_abst_ko": "7 13 [OP_ADD] 1 [OP_SUB] 8 14 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "7 13 [OP_ADD] 1 [OP_SUB] 8 14 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 7\nvar_b = 13\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = 14\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 7\nvar_b = 13\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = 14\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))"
    },
    "837": {
        "category": "Geometry",
        "question_ko": "똑같은 직사각형 모양의 엽서 2장을 겹치지 않게 가로로 이어 붙였습니다. 이어 붙인 엽서 전체의 둘레가 70센티미터(㎝)이고 세로가 15센티미터(㎝)일 때, 엽서 한 장의 넓이는 몇 제곱센티미터(㎠)입니까?",
        "question_en": "Two identical rectangular-shaped postcards were attached horizontally so that they did not overlap. If the entire perimeter of the stitched postcard is 70 centimeters (cm) and the vertical length is 15 centimeters (cm), how many square centimeters (cm2) is the area of one postcard?",
        "answer_ko": "150",
        "answer_en": "150",
        "solution_abst_ko": "70 2 [OP_DIV] 15 [OP_SUB] 15 [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "70 2 [OP_DIV] 15 [OP_SUB] 15 [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 70\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 15\nvar_e = var_c - var_d\nvar_f = 15\nvar_g = var_e * var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 70\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 15\nvar_e = var_c - var_d\nvar_f = 15\nvar_g = var_e * var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "838": {
        "category": "Arithmetic calculation",
        "question_ko": "(가) 기계로 장난감 60개를 만드는 데 5일 걸립니다. (가) 기계로 540개의 장난감을 만드는 데 며칠이 걸립니까?",
        "question_en": "It takes 5 days to make 60 toys with an (a) machine. How many days does it take to make 540 toys with an (a) machine?",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "540 60 [OP_DIV] 5 [OP_MUL]",
        "solution_abst_en": "540 60 [OP_DIV] 5 [OP_MUL]",
        "solution_code_ko": "var_a = 540\nvar_b = 60\nvar_c = var_a / var_b\nvar_d = 5\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 540\nvar_b = 60\nvar_c = var_a / var_b\nvar_d = 5\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "839": {
        "category": "Arithmetic calculation",
        "question_ko": "과자 10개를 유정이와 민영이가 나누어 먹을 때, 한 사람이 몇 개의 과자를 먹을 수 있나요",
        "question_en": "If Yoojeong and Minyeong share 10 snacks, how many snacks can one person eat?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "10 2 [OP_DIV]",
        "solution_abst_en": "10 2 [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 10\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "840": {
        "category": "Comparison",
        "question_ko": "가희, 나희, 다희, 라희, 마희가 편의점에서 음료수를 각자 샀다. 각 음료수의 가격의 평균보다 가희, 나희, 다희가 산 음료수의 가격 평균이 2원 더 높았고, 라희는 72원짜리 음료수를, 마희는 80원짜리 음료수를 샀다고 할 때 이 다섯 사람의 음료수 가격의 평균은 얼마인가?",
        "question_en": "Gahee, Nahee, Dahee, Rahee, and Mahee each bought drinks at the convenience store. Assuming that the average price of the drinks Gahee, Nahee, and Dahee bought was 2 won higher than the average price of each drink, and that Rahee bought a 72 won drink and Mahee bought a 80 won drink, how much is the average price of the drinks for these five people?",
        "answer_ko": "79",
        "answer_en": "79",
        "solution_abst_ko": "72 80 [OP_ADD] 3 [OP_MUL] 2 3 5 [OP_MUL] [OP_MUL] [OP_ADD] 5 3 [OP_SUB] [OP_DIV] 72 [OP_ADD] 80 [OP_ADD] 5 [OP_DIV]",
        "solution_abst_en": "72 80 [OP_ADD] 3 [OP_MUL] 2 3 5 [OP_MUL] [OP_MUL] [OP_ADD] 5 3 [OP_SUB] [OP_DIV] 72 [OP_ADD] 80 [OP_ADD] 5 [OP_DIV]",
        "solution_code_ko": "var_a = 72\nvar_b = 80\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c * var_d\nvar_f = 2\nvar_g = 3\nvar_h = 5\nvar_i = var_g * var_h\nvar_j = var_f * var_i\nvar_k = var_e + var_j\nvar_l = 5\nvar_m = 3\nvar_n = var_l - var_m\nvar_o = var_k / var_n\nvar_p = 72\nvar_q = var_o + var_p\nvar_r = 80\nvar_s = var_q + var_r\nvar_t = 5\nvar_u = var_s / var_t\nprint(int(var_u))",
        "solution_code_en": "var_a = 72\nvar_b = 80\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c * var_d\nvar_f = 2\nvar_g = 3\nvar_h = 5\nvar_i = var_g * var_h\nvar_j = var_f * var_i\nvar_k = var_e + var_j\nvar_l = 5\nvar_m = 3\nvar_n = var_l - var_m\nvar_o = var_k / var_n\nvar_p = 72\nvar_q = var_o + var_p\nvar_r = 80\nvar_s = var_q + var_r\nvar_t = 5\nvar_u = var_s / var_t\nprint(int(var_u))"
    },
    "841": {
        "category": "Comparison",
        "question_ko": "윤아는 윤아의 친구 희진이와 미영이와 함께 있습니다. 윤아는 23살이고 미영이는 22살, 희진이는 24살입니다. 가장 나이가 많은 사람은 누구입니까?",
        "question_en": "Yoona is with Yoona's friends Heejin and Miyoung. Yoona is 23 years old, Miyoung is 22 years old, and Heejin is 24 years old. Who is the oldest?",
        "answer_ko": "희진",
        "answer_en": "Heejin",
        "solution_abst_ko": "[OP_LIST_SOL] 윤아 미영 희진 [OP_LIST_EOL] [OP_LIST_SOL] 23 22 24 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoona Miyoung Heejin [OP_LIST_EOL] [OP_LIST_SOL] 23 22 24 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤아'\nvar_b = '미영'\nvar_c = '희진'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 23\nvar_e = 22\nvar_f = 24\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Yoona'\nvar_b = 'Miyoung'\nvar_c = 'Heejin'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 23\nvar_e = 22\nvar_f = 24\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "842": {
        "category": "Comparison",
        "question_ko": "키가 작은 사람부터 순서대로 9명이 한 줄로 서 있습니다. 호석이가 앞에서부터 5번째에 서 있습니다. 키가 큰 사람부터 순서대로 다시 줄을 서면 호석이는 앞에서부터 몇 번째에 서게 됩니까?",
        "question_en": "Nine people stand in a line in order of shortest to tallest. Hoseok is standing 5th from the front. If you line up again in order of tallest to smallest, what number will Hoseok stand from the front?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "9 5 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "9 5 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 9\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "843": {
        "category": "Arithmetic calculation",
        "question_ko": "1000 이하의 자연수 중 5의 배수이면서 10의 배수는 아닌 수는 몇 개입니까?",
        "question_en": "How many natural numbers that are 1000 or less are multiples of 5 while are not multiples of 10?",
        "answer_ko": "100",
        "answer_en": "100",
        "solution_abst_ko": "1 1000 1 [OP_LIST_ARANGE] 1 5 [OP_LIST_SEARCH_FIXED_DIGIT] [OP_LIST_LEN]",
        "solution_abst_en": "1 1000 1 [OP_LIST_ARANGE] 1 5 [OP_LIST_SEARCH_FIXED_DIGIT] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 1000\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 1\nvar_e = 5\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i in list_a:\n    i = int(i)\n    if (i//var_d)%10 == var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 1000\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 1\nvar_e = 5\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i in list_a:\n    i = int(i)\n    if (i//var_d)%10 == var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "844": {
        "category": "Comparison",
        "question_ko": "지석 배낭의 크기는 1.49리터(L)이고 미호 배낭의 크기는 9/20리터(L)입니다. 누구의 배낭이 더 작습니까?",
        "question_en": "The size of the Jisuk backpack is 1.49 liters (L) and the size of the Miho backpack is 9/20 liters (L). Whose backpack is smaller?",
        "answer_ko": "미호",
        "answer_en": "Miho",
        "solution_abst_ko": "[OP_LIST_SOL] 지석 미호 [OP_LIST_EOL] [OP_LIST_SOL] 1.49 9/20 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jisuk Miho [OP_LIST_EOL] [OP_LIST_SOL] 1.49 9/20 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '지석'\nvar_b = '미호'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.49\nvar_d = 0.45\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Jisuk'\nvar_b = 'Miho'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.49\nvar_d = 0.45\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "845": {
        "category": "Geometry",
        "question_ko": "10원짜리, 100원짜리, 500원짜리 동전이 각각 1개씩 있습니다. 이 세 동전 중 두 개를 골라 던졌을 때, 나올 수 있는 경우의 수는 모두 몇 가지입니까?",
        "question_en": "There are 10-won, 100-won, and 500-won coins each. If you pick and flip two of these three coins, what are the total number of possible outcomes?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "3 2 [OP_PERM]",
        "solution_abst_en": "3 2 [OP_PERM]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))"
    },
    "846": {
        "category": "Correspondence",
        "question_ko": "15에 어떤 수를 곱해야 하는데 잘못하여 어떤 수를 15로 나누었더니 6이 되었습니다. 바르게 계산한 결과를 구하시오.",
        "question_en": "We need to multiply 15 by a number, but we mistakenly divide a number by 15, which is 6. Find the result of the correct calculation.",
        "answer_ko": "1350",
        "answer_en": "1350",
        "solution_abst_ko": "15 6 15 [OP_MUL] [OP_MUL]",
        "solution_abst_en": "15 6 15 [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 15\nvar_b = 6\nvar_c = 15\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 6\nvar_c = 15\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nprint(int(var_e))"
    },
    "847": {
        "category": "Correspondence",
        "question_ko": "3A5-2B=364이 성립할 때, B에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "When 3A5-2B=364 is true, what number should go in B?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "3A5-2B=364 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "3A5-2B=364 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '3A5-2B=364'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '3A5-2B=364'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "848": {
        "category": "Comparison",
        "question_ko": "하이에나는 일정한 빠르기로 1분에 2.1킬로미터(㎞)를 뛰고, 치타는 4분에 10.5킬로미터(㎞)를 뜁니다. 어느 동물이 더 빠르다고 할 수 있습니까?",
        "question_en": "Hyenas run at a steady speed of 2.1 kilometers (km) per minute, and cheetahs run at 10.5 kilometers (km) in 4 minutes. Which animal can be said to be faster?",
        "answer_ko": "치타",
        "answer_en": "cheetah",
        "solution_abst_ko": "[OP_LIST_SOL] 하이에나 치타 [OP_LIST_EOL] [OP_LIST_SOL] 2.1 1 [OP_DIV] 10.5 4 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Hyena cheetah [OP_LIST_EOL] [OP_LIST_SOL] 2.1 1 [OP_DIV] 10.5 4 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '하이에나'\nvar_b = '치타'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2.1\nvar_d = 1\nvar_e = var_c / var_d\nvar_f = 10.5\nvar_g = 4\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Hyena'\nvar_b = 'cheetah'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2.1\nvar_d = 1\nvar_e = var_c / var_d\nvar_f = 10.5\nvar_g = 4\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "849": {
        "category": "Arithmetic calculation",
        "question_ko": "지민이는 석진이보다 구슬을 2배 더 많이 갖고 있고 유나는 석진이보다 구슬을 1개 더 적게 가지고 있습니다. 석진이가 구슬 3개를 가지고 있을 때 지민이는 유나보다 구슬을 몇 개 더 많이 가지고 있습니까?",
        "question_en": "Jimin has 2 times more marbles than Seokjin and Yuna has 1 less marble than Seokjin. If Seokjin has 3 marbles, how many more marbles does Jimin have than Yuna?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "3 2 [OP_MUL] 3 1 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "3 2 [OP_MUL] 3 1 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "850": {
        "category": "Correspondence",
        "question_ko": "서로 다른 두 수 A, B가 있습니다. 두 자리 수끼리의 뺄셈식 A5-2A=B7에서 A와 B의 합을 구하시오.",
        "question_en": "There are two different numbers A and B. Find the sum of A and B in the two-digit subtraction formula A5-2A=B7.",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "A5-2A=B7 A [OP_DIGIT_UNK_SOLVER] A5-2A=B7 B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_abst_en": "A5-2A=B7 A [OP_DIGIT_UNK_SOLVER] A5-2A=B7 B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_code_ko": "var_a = 'A5-2A=B7'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 'A5-2A=B7'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 'A5-2A=B7'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 'A5-2A=B7'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "851": {
        "category": "Possibility",
        "question_ko": "0부터 7까지 수 중 홀수를 제외한 수를 이용하여 세 자리 수를 만들고자 한다. 만들 수 있는 세 자리 자연수들 중 각 자리의 숫자가 모두 다른 수들의 합은 얼마인가?",
        "question_en": "You are going to create a three-digit number using the numbers from 0 to 7, excluding odd numbers. What is the sum of the three-digit numbers that can be created with different digits?",
        "answer_ko": "7728",
        "answer_en": "7728",
        "solution_abst_ko": "0 7 [OP_LIST_EVEN] 3 [OP_LIST_GET_PERM] [OP_LIST_SUM]",
        "solution_abst_en": "0 7 [OP_LIST_EVEN] 3 [OP_LIST_GET_PERM] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0\nvar_b = 7\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_b = [float(i) for i in list_b]\nvar_d = sum(list_b)\nprint(int(var_d))",
        "solution_code_en": "var_a = 0\nvar_b = 7\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_b = [float(i) for i in list_b]\nvar_d = sum(list_b)\nprint(int(var_d))"
    },
    "852": {
        "category": "Correspondence",
        "question_ko": "어떤 수의 3/4에서 25를 빼고 7로 나눈 뒤 50을 더하면 100이 됩니다. 어떤 수를 구하시오.",
        "question_en": "Subtract 25 from 3/4 of a number, divide by 7, and add 50 to get 100. Find the number.",
        "answer_ko": "500",
        "answer_en": "500",
        "solution_abst_ko": "100 50 [OP_SUB] 7 [OP_MUL] 25 [OP_ADD] 3/4 [OP_DIV]",
        "solution_abst_en": "100 50 [OP_SUB] 7 [OP_MUL] 25 [OP_ADD] 3/4 [OP_DIV]",
        "solution_code_ko": "var_a = 100\nvar_b = 50\nvar_c = var_a - var_b\nvar_d = 7\nvar_e = var_c * var_d\nvar_f = 25\nvar_g = var_e + var_f\nvar_h = 0.75\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 100\nvar_b = 50\nvar_c = var_a - var_b\nvar_d = 7\nvar_e = var_c * var_d\nvar_f = 25\nvar_g = var_e + var_f\nvar_h = 0.75\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "853": {
        "category": "Correspondence",
        "question_ko": "26을 A으로 나눴을 때 몫이 8, 나머지가 2 였습니다. A는 자연수입니다. 이 때 A는 무엇인가요?",
        "question_en": "When 26 is divided by A, the quotient is 8 and the remainder is 2. A is a natural number. What is A in this case?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "26 2 [OP_SUB] 8 [OP_DIV]",
        "solution_abst_en": "26 2 [OP_SUB] 8 [OP_DIV]",
        "solution_code_ko": "var_a = 26\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 26\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "854": {
        "category": "Possibility",
        "question_ko": "주어진 숫자 구슬 0, 3, 4, 8을 한 번씩 모두 사용하여 만들 수 있는 가장 큰 네 자리 수와 가장 작은 네 자리 수의 차를 쓰시오.",
        "question_en": "Write the difference between the largest 4-digit number and the smallest 4-digit number that can be made by using all of the given number marbles 0, 3, 4, and 8 once.",
        "answer_ko": "5382",
        "answer_en": "5382",
        "solution_abst_ko": "[OP_LIST_SOL] 0 3 4 8 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "[OP_LIST_SOL] 0 3 4 8 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 0\nvar_b = 3\nvar_c = 4\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g - var_i\nvar_k = abs(var_j)\nprint(int(var_k))",
        "solution_code_en": "var_a = 0\nvar_b = 3\nvar_c = 4\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g - var_i\nvar_k = abs(var_j)\nprint(int(var_k))"
    },
    "855": {
        "category": "Correspondence",
        "question_ko": "38A-B1=364이 성립합니다. A는 무엇인가요?",
        "question_en": "38A-B1=364 holds. What is A?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "38A-B1=364 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "38A-B1=364 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '38A-B1=364'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '38A-B1=364'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "856": {
        "category": "Possibility",
        "question_ko": "숫자 1, 5, 2를 한 번씩 모두 이용하여 만들 수 있는 수 중 가장 작은 수를 구하시오,",
        "question_en": "Find the smallest number that can be formed by using the numbers 1, 5, and 2 all at once.",
        "answer_ko": "125",
        "answer_en": "125",
        "solution_abst_ko": "[OP_LIST_SOL] 1 5 2 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 5 2 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1\nvar_b = 5\nvar_c = 2\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 5\nvar_c = 2\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nprint(int(var_f))"
    },
    "857": {
        "category": "Comparison",
        "question_ko": "(가), (나), (다), (라) 4개의 꽃병이 있습니다. (가) 꽃병은 (다) 꽃병보다 작습니다. (라) 꽃병은 (가) 꽃병보다 작습니다. (나) 꽃병은 (다) 꽃병보다 큽니다. 크기가 가장 큰 꽃병은 무엇입니까?",
        "question_en": "There are 4 vases, (a), (b), (c), and (d). Vase (a) is smaller than vase (c). Vase (d) is smaller than vase (a). Vase (b) is larger than vase (c). What is the largest vase?",
        "answer_ko": "(나)",
        "answer_en": "(b)",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) (다) (라) [OP_LIST_EOL] [OP_LIST_SOL] (다) (가) > (라) (가) < (다) (나) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (a) (b) (c) (d) [OP_LIST_EOL] [OP_LIST_SOL] (c) (a) > (d) (a) < (c) (b) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nvar_c = '(다)'\nvar_d = '(라)'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '(다)'\nvar_f = '(가)'\nvar_g = '>'\nvar_h = '(라)'\nvar_i = '(가)'\nvar_j = '<'\nvar_k = '(다)'\nvar_l = '(나)'\nvar_m = '<'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = 1\nvar_o = list_c[var_n-1]\nprint(var_o)",
        "solution_code_en": "var_a = '(a)'\nvar_b = '(b)'\nvar_c = '(c)'\nvar_d = '(d)'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '(c)'\nvar_f = '(a)'\nvar_g = '>'\nvar_h = '(d)'\nvar_i = '(a)'\nvar_j = '<'\nvar_k = '(c)'\nvar_l = '(b)'\nvar_m = '<'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = 1\nvar_o = list_c[var_n-1]\nprint(var_o)"
    },
    "858": {
        "category": "Possibility",
        "question_ko": "10 미만의 한 자리 수 중 짝수만을 한 번씩만 이용하여 만들 수 있는 두 자리 자연수의 개수는 모두 몇 가지인가?",
        "question_en": "How many two-digit numbers can be made using even numbers only once among the unit digit less than 10?",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "0 10 1 [OP_SUB] [OP_LIST_EVEN] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "0 10 1 [OP_SUB] [OP_LIST_EVEN] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 10\nvar_c = 1\nvar_d = var_b - var_c\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_d+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_d+1, 2):\n        list_a.append(i)\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 0\nvar_b = 10\nvar_c = 1\nvar_d = var_b - var_c\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_d+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_d+1, 2):\n        list_a.append(i)\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "859": {
        "category": "Correspondence",
        "question_ko": "마트에 있는 과일 바구니에 바나나가 4개, 사과가 3개 들어있습니다. 오늘 과일 바구니 25개가 더 들어와서 과일바구니에 있는 사과의 개수가 150개가 되었다. 어제까지 바나나의 개수를 구하시오.",
        "question_en": "The fruit basket at the supermarket contains 4 bananas and 3 apples. Today, 25 more fruit baskets came in, resulting in the number of apples in the fruit basket to 150. Find the number of bananas by yesterday.",
        "answer_ko": "100",
        "answer_en": "100",
        "solution_abst_ko": "150 3 [OP_DIV] 25 [OP_SUB] 4 [OP_MUL]",
        "solution_abst_en": "150 3 [OP_DIV] 25 [OP_SUB] 4 [OP_MUL]",
        "solution_code_ko": "var_a = 150\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 25\nvar_e = var_c - var_d\nvar_f = 4\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 150\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 25\nvar_e = var_c - var_d\nvar_f = 4\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "860": {
        "category": "Arithmetic calculation",
        "question_ko": "태형이와 지민이가 함께 딱지접기를 하고 있습니다. 태형이는 4시간에 256개를 접고 지민이는 3시간에 111개를 접을 수 있다면 3시간 후에 태형이와 지민이가 접은 딱지의 개수는 몇 개인지 구하세요.",
        "question_en": "Taehyung and Jimin are folding scabs together. If Taehyung can fold 256 in 4 hours and Jimin can fold 111 in 3 hours, how many scabs did Taehyung and Jimin fold after 3 hours?",
        "answer_ko": "303",
        "answer_en": "303",
        "solution_abst_ko": "256 3 4 [OP_DIV] [OP_MUL] 111 [OP_ADD]",
        "solution_abst_en": "256 3 4 [OP_DIV] [OP_MUL] 111 [OP_ADD]",
        "solution_code_ko": "var_a = 256\nvar_b = 3\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 111\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 256\nvar_b = 3\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 111\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "861": {
        "category": "Possibility",
        "question_ko": "7, 6, 5, 8의 자연수를 한 번씩 모두 사용해서 네 자리 숫자를 만들고 싶습니다. 만들 수 있는 수 중 세 번째 큰 수와 세 번째 작은 수의 합은 얼마입니까?",
        "question_en": "I want to create four-digit numbers by using all the natural numbers 7, 6, 5, and 8 once. Among the numbers I can make, what is the sum of the third largest number and the third smallest number?",
        "answer_ko": "14443",
        "answer_en": "14443",
        "solution_abst_ko": "[OP_LIST_SOL] 7 6 8 5 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 7 6 8 5 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 7\nvar_b = 6\nvar_c = 8\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 7\nvar_b = 6\nvar_c = 8\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))"
    },
    "862": {
        "category": "Possibility",
        "question_ko": "5명의 직원이 있다. 이 중 2명을 뽑아 한 명에게 특상을, 다른 한 명에게 2등상을 주려고 한다. 몇 가지의 경우가 있겠는가?",
        "question_en": "There are 5 employees. Among them, you are going to select two people and give one a special prize and the other a second prize. How many cases are there?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "5 2 [OP_PERM]",
        "solution_abst_en": "5 2 [OP_PERM]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))"
    },
    "863": {
        "category": "Possibility",
        "question_ko": "5, 6, 4, 7 중에서 3개를 뽑아 한 번씩만 사용하여 세 자리 수를 만들려고 합니다. 만들 수 있는 네 번째로 작은 수를 구한 후, 각 자리 수의 합을 구하시오.",
        "question_en": "You want to create a three-digit number by drawing three out of 5, 6, 4, and 7 and using them only once. After finding the fourth smallest possible number, find the sum of its digits.",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "[OP_LIST_SOL] 5 6 4 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 4 [OP_LIST_MIN] [OP_NUM2LIST] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 5 6 4 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 4 [OP_LIST_MIN] [OP_NUM2LIST] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 5\nvar_b = 6\nvar_c = 4\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 4\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nlist_d = []\nvar_g = int(var_g)\nwhile var_g//10 > 0:\n    list_d.append(var_g%10)\n    var_g = var_g//10\nlist_d.append(var_g%10)\nlist_d = list_d[::-1]\nlist_d = [float(i) for i in list_d]\nvar_h = sum(list_d)\nprint(int(var_h))",
        "solution_code_en": "var_a = 5\nvar_b = 6\nvar_c = 4\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 4\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nlist_d = []\nvar_g = int(var_g)\nwhile var_g//10 > 0:\n    list_d.append(var_g%10)\n    var_g = var_g//10\nlist_d.append(var_g%10)\nlist_d = list_d[::-1]\nlist_d = [float(i) for i in list_d]\nvar_h = sum(list_d)\nprint(int(var_h))"
    },
    "864": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 9까지의 숫자카드 중 3장을 뽑아 735라는 숫자를 만들었다. 뽑은 숫자카드들 중 4보다 큰 값들의 합은 얼마인지 구하시오.",
        "question_en": "Three of the number cards from 1 to 9 were drawn to make the number 735. Find the sum of the numbers greater than 4 among the number cards drawn.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "735 [OP_NUM2LIST] 4 [OP_LIST_MORE] [OP_LIST_SUM]",
        "solution_abst_en": "735 [OP_NUM2LIST] 4 [OP_LIST_MORE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 735\nlist_a = []\nvar_a = int(var_a)\nwhile var_a//10 > 0:\n    list_a.append(var_a%10)\n    var_a = var_a//10\nlist_a.append(var_a%10)\nlist_a = list_a[::-1]\nvar_b = 4\nlist_b = []\nfor i in list_a:\n    if i > var_b:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_c = sum(list_b)\nprint(int(var_c))",
        "solution_code_en": "var_a = 735\nlist_a = []\nvar_a = int(var_a)\nwhile var_a//10 > 0:\n    list_a.append(var_a%10)\n    var_a = var_a//10\nlist_a.append(var_a%10)\nlist_a = list_a[::-1]\nvar_b = 4\nlist_b = []\nfor i in list_a:\n    if i > var_b:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_c = sum(list_b)\nprint(int(var_c))"
    },
    "865": {
        "category": "Comparison",
        "question_ko": "도자기를 만드는 데 예림이가 사용한 찰흙의 무게는 0.65킬로그램(㎏)이고 찬우가 사용한 찰흙의 무게는 0.645킬로그램(㎏) 입니다. 찰흙을 더 많이 사용한 사람은 누구입니까?",
        "question_en": "The weight of the clay Yerim used to make the pottery is 0.65 kg (kg) and the weight of the clay used by Chanwoo is 0.645 kg (kg). Who used more clay?",
        "answer_ko": "예림",
        "answer_en": "Yerim",
        "solution_abst_ko": "[OP_LIST_SOL] 예림 찬우 [OP_LIST_EOL] [OP_LIST_SOL] 0.65 0.645 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yerim Chanwoo [OP_LIST_EOL] [OP_LIST_SOL] 0.65 0.645 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '예림'\nvar_b = '찬우'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.65\nvar_d = 0.645\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Yerim'\nvar_b = 'Chanwoo'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.65\nvar_d = 0.645\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "866": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 32로 나누어야 할 것을 잘못하여 23으로 나누었더니 몫이 3이고 나머지가 17이었습니다. 바르게 계산했을 때의 몫과 나머지의 합을 구해 보시오.",
        "question_en": "I mistakenly divide a number by 23 when a number should be divided by 32 and it turns out that the quotient is 3 and the remainder is 17. Find the sum of the quotient and remainder when calculated correctly.",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "3 23 [OP_MUL] 17 [OP_ADD] 32 [OP_FDIV] 3 23 [OP_MUL] 17 [OP_ADD] 32 [OP_MOD] [OP_ADD]",
        "solution_abst_en": "3 23 [OP_MUL] 17 [OP_ADD] 32 [OP_FDIV] 3 23 [OP_MUL] 17 [OP_ADD] 32 [OP_MOD] [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 23\nvar_c = var_a * var_b\nvar_d = 17\nvar_e = var_c + var_d\nvar_f = 32\nvar_g = var_e // var_f\nvar_h = 3\nvar_i = 23\nvar_j = var_h * var_i\nvar_k = 17\nvar_l = var_j + var_k\nvar_m = 32\nvar_n = var_l % var_m\nvar_o = var_g + var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 3\nvar_b = 23\nvar_c = var_a * var_b\nvar_d = 17\nvar_e = var_c + var_d\nvar_f = 32\nvar_g = var_e // var_f\nvar_h = 3\nvar_i = 23\nvar_j = var_h * var_i\nvar_k = 17\nvar_l = var_j + var_k\nvar_m = 32\nvar_n = var_l % var_m\nvar_o = var_g + var_n\nprint(int(var_o))"
    },
    "867": {
        "category": "Possibility",
        "question_ko": "서로 같은 꽃 10송이를 서로 다른 2개의 꽃병에 나누어 꽂으려고 합니다. 꽃병에는 적어도 꽃 1송이를 꽂습니다. 꽃을 나누어 꽂는 방법은 모두 몇 가지입니까?",
        "question_en": "You want to divide 10 identical flowers into 2 different vases. You must place at least one flower in a vase. What is the number of possible ways to divide flowers?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "10 2 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "10 2 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "868": {
        "category": "Arithmetic calculation",
        "question_ko": "국어, 영어, 수학의 평균 점수는 92점이다. 사회는 90점, 체육은 95점일때 국어, 영어, 수학, 사회, 체육의 평균 점수는 몇 점인가",
        "question_en": "The average score for Korean, English, and Mathematics is 92 points. If Social Studies is 90 points and Physical Education is 95 points, what is the average score for Korean, English, Mathematics, Social Studies, and Physical Education?",
        "answer_ko": "92.20",
        "answer_en": "92.2",
        "solution_abst_ko": "92 3 [OP_MUL] 90 [OP_ADD] 95 [OP_ADD] 5 [OP_DIV]",
        "solution_abst_en": "92 3 [OP_MUL] 90 [OP_ADD] 95 [OP_ADD] 5 [OP_DIV]",
        "solution_code_ko": "var_a = 92\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 90\nvar_e = var_c + var_d\nvar_f = 95\nvar_g = var_e + var_f\nvar_h = 5\nvar_i = var_g / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 92\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 90\nvar_e = var_c + var_d\nvar_f = 95\nvar_g = var_e + var_f\nvar_h = 5\nvar_i = var_g / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "869": {
        "category": "Possibility",
        "question_ko": "정국이는 빨간 공 3개와 노란 공 2개를 가지고 있습니다. 정국이가 윤기에게 노란 공 1개를 주었을 때, 정국이는 빨간 공을 몇 개 가지고 있습니까?",
        "question_en": "Jungkook has 3 red balls and 2 yellow balls. When Jungkook gives 1 yellow ball to Yoongi, how many red balls does Jungkook have?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "3",
        "solution_abst_en": "3",
        "solution_code_ko": "var_a = 3\nprint(int(var_a))",
        "solution_code_en": "var_a = 3\nprint(int(var_a))"
    },
    "870": {
        "category": "Comparison",
        "question_ko": "1.4, 9/10, 1.2, 0.5, 13/10에서 1.1보다 작거나 같은 숫자는 몇 개 일까요?",
        "question_en": "How many numbers in 1.4, 9/10, 1.2, 0.5, 13/10 are less than or equal to 1.1?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i <= var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i <= var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "871": {
        "category": "Possibility",
        "question_ko": "사과, 복숭아, 배, 참외 중 2개를 뽑아 서로 다른 과일 바구니에 담으려고 합니다. 가능한 경우의 수는 모두 몇 가지입니까?",
        "question_en": "I'm going to pick two out of apples, peaches, pears, and melons and put them in different fruit baskets. How many possible cases are there?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 복숭아 배 참외 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] apples peaches pears melons [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '복숭아'\nvar_c = '배'\nvar_d = '참외'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nprint(int(var_g))",
        "solution_code_en": "var_a = 'apples'\nvar_b = 'peaches'\nvar_c = 'pears'\nvar_d = 'melons'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nprint(int(var_g))"
    },
    "872": {
        "category": "Comparison",
        "question_ko": "철민이는 동화책을 2주일 동안 518쪽 읽었고, 성민이는 8일 동안 328쪽 읽었다. 하루 동안 누가 더 많이 읽은 셈인가?",
        "question_en": "Cheolmin read 518 pages of a children's book in 2 weeks, and Seongmin read 328 pages in 8 days. Who read more in one day?",
        "answer_ko": "성민",
        "answer_en": "Seongmin",
        "solution_abst_ko": "[OP_LIST_SOL] 철민 성민 [OP_LIST_EOL] [OP_LIST_SOL] 518 2 7 [OP_MUL] [OP_DIV] 328 8 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Cheolmin Seongmin [OP_LIST_EOL] [OP_LIST_SOL] 518 2 7 [OP_MUL] [OP_DIV] 328 8 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '철민'\nvar_b = '성민'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 518\nvar_d = 2\nvar_e = 7\nvar_f = var_d * var_e\nvar_g = var_c / var_f\nvar_h = 328\nvar_i = 8\nvar_j = var_h / var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'Cheolmin'\nvar_b = 'Seongmin'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 518\nvar_d = 2\nvar_e = 7\nvar_f = var_d * var_e\nvar_g = var_c / var_f\nvar_h = 328\nvar_i = 8\nvar_j = var_h / var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "873": {
        "category": "Comparison",
        "question_ko": "윤기는 4, 정국이는 6에서 3을 합한 수를 모았고, 유나는 5를 모았습니다. 누가 가장 작은 수를 가지고 있나요?",
        "question_en": "Yoongi collects 4, Jungkook collects a number adding 3 to 6, and Yuna collects 5. Who has the smallest number?",
        "answer_ko": "윤기",
        "answer_en": "Yoongi",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 유나 [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_ADD] 5 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook Yuna [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_ADD] 5 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nvar_c = '유나'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 6\nvar_f = 3\nvar_g = var_e + var_f\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nvar_c = 'Yuna'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 6\nvar_f = 3\nvar_g = var_e + var_f\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "874": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 20을 나누어야 할 것을 22를 나누어 2가 나왔습니다. 바르게 계산하면 얼마인가요?",
        "question_en": "I made a mistake in dividing a number by 20, so I divided a number by 22 and got 2. How much is it if I calculate it correctly?",
        "answer_ko": "2.20",
        "answer_en": "2.2",
        "solution_abst_ko": "2 22 [OP_MUL] 20 [OP_DIV]",
        "solution_abst_en": "2 22 [OP_MUL] 20 [OP_DIV]",
        "solution_code_ko": "var_a = 2\nvar_b = 22\nvar_c = var_a * var_b\nvar_d = 20\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 2\nvar_b = 22\nvar_c = var_a * var_b\nvar_d = 20\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "875": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 650미터(m)인 도로에 32.5미터(m) 간격으로 일정하게 나무를 심으려고 할 때, 도로의 양 끝에 나무를 심는다면 모두 몇 그루의 나무가 필요합니까? 단, 나무의 두께는 생각하지 않습니다.",
        "question_en": "How many trees will be needed if trees are planted on both ends of the road, evenly spaced at 32.5 m (m) intervals on a road that is 650 meters (m) long? However, the thickness of the wood is not considered.",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "650 32.5 [OP_FDIV] 1 [OP_ADD]",
        "solution_abst_en": "650 32.5 [OP_FDIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 650\nvar_b = 32.5\nvar_c = var_a // var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 650\nvar_b = 32.5\nvar_c = var_a // var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "876": {
        "category": "Correspondence",
        "question_ko": "서로 다른 네 수 A, B, C, D가 있습니다. 네 자리 수끼리의 덧셈식 4A5B+C2D7=7070에서 C를 구하시오.",
        "question_en": "There are four different numbers A, B, C, and D. Find C from the four-digit addition formula 4A5B+C2D7=7070.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "4A5B+C2D7=7070 C [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "4A5B+C2D7=7070 C [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '4A5B+C2D7=7070'\nvar_b = 'C'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '4A5B+C2D7=7070'\nvar_b = 'C'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "877": {
        "category": "Geometry",
        "question_ko": "어떤 벽이 가로와 세로의 길이가 각각 36센티미터(㎝), 72센티미터(㎝)인 직사각형 모양이다. 이 벽에 가로와 세로의 길이가 각각 3센티미터(㎝), 4센티미터(㎝)인 타일을 빈 공간 없이 붙이려고 합니다. 타일 하나에 2500원 일 때, 얼마가 드는지 구하시오.",
        "question_en": "There is a wall in the shape of a rectangle with a width of 36 centimeters (cm) and a height of 72 centimeters (cm). On this wall, you want to attach tiles that are 3 centimeters (cm) and 4 centimeters (cm) in length and width, respectively, without any empty space. If it costs 2500 won per tile, how much does it cost?",
        "answer_ko": "540000",
        "answer_en": "540000",
        "solution_abst_ko": "36 3 [OP_FDIV] 72 4 [OP_FDIV] [OP_MUL] 2500 [OP_MUL]",
        "solution_abst_en": "36 3 [OP_FDIV] 72 4 [OP_FDIV] [OP_MUL] 2500 [OP_MUL]",
        "solution_code_ko": "var_a = 36\nvar_b = 3\nvar_c = var_a // var_b\nvar_d = 72\nvar_e = 4\nvar_f = var_d // var_e\nvar_g = var_c * var_f\nvar_h = 2500\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 36\nvar_b = 3\nvar_c = var_a // var_b\nvar_d = 72\nvar_e = 4\nvar_f = var_d // var_e\nvar_g = var_c * var_f\nvar_h = 2500\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "878": {
        "category": "Geometry",
        "question_ko": "실을 사용하여 한 변의 길이가 16센티미터(㎝)인 정오각형을 만들었습니다. 이 실을 똑같이 사용해 모두 사용하여 정팔각형을 만들었습니다. 이 정팔각형의 한 변의 길이를 구하시오.",
        "question_en": "Using yarn, I made a regular pentagon with a side of 16 centimeters (cm). I used all of these yarns to make a regular octagon. Find the length of one side of this regular octagon.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "16 5 [OP_MUL] 8 [OP_DIV]",
        "solution_abst_en": "16 5 [OP_MUL] 8 [OP_DIV]",
        "solution_code_ko": "var_a = 16\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 16\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "879": {
        "category": "Geometry",
        "question_ko": "밑면의 넓이가 50제곱센티미터(㎠)이고, 부피가 2000세제곱센티미터(㎤)인 직육면체의 높이는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "Find the height in centimeters (cm) of a cuboid whose base area is 50 square centimeters (cm2) and its volume is 2000 cubic centimeters (cm3).",
        "answer_ko": "40",
        "answer_en": "40",
        "solution_abst_ko": "2000 50 [OP_DIV]",
        "solution_abst_en": "2000 50 [OP_DIV]",
        "solution_code_ko": "var_a = 2000\nvar_b = 50\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2000\nvar_b = 50\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "880": {
        "category": "Geometry",
        "question_ko": "민정이는 정사각형 모양의 공원을 산책하고 있습니다. 이 공원의 한 변의 길이가 40미터(m)일 때, 민정이가 걸은 거리는 몇 미터(m)일까요?",
        "question_en": "Minjeong is taking a walk in a square-shaped park. Given that one side of this park is 40 meters (m) long, how many meters (m) did Minjeong walk?",
        "answer_ko": "160",
        "answer_en": "160",
        "solution_abst_ko": "40 4 [OP_MUL]",
        "solution_abst_en": "40 4 [OP_MUL]",
        "solution_code_ko": "var_a = 40\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 40\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "881": {
        "category": "Geometry",
        "question_ko": "반지름이 8센티미터(㎝)인 원의 넓이를 지름이 8센티미터(㎝)인 원의 넓이로 나누면 몇인지 구하시오. 단, 원주율은 3.14로 가정한다.",
        "question_en": "Find how much it will be if you divide the area of a circle with a radius of 8 centimeters (cm) by the area of a circle with a diameter of 8 centimeters (cm). Note that the pi is assumed to be 3.14.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "3.14 8 [OP_MUL] 8 [OP_MUL] 3.14 8 2 [OP_DIV] [OP_MUL] 8 2 [OP_DIV] [OP_MUL] [OP_DIV]",
        "solution_abst_en": "3.14 8 [OP_MUL] 8 [OP_MUL] 3.14 8 2 [OP_DIV] [OP_MUL] 8 2 [OP_DIV] [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 3.14\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c * var_d\nvar_f = 3.14\nvar_g = 8\nvar_h = 2\nvar_i = var_g / var_h\nvar_j = var_f * var_i\nvar_k = 8\nvar_l = 2\nvar_m = var_k / var_l\nvar_n = var_j * var_m\nvar_o = var_e / var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 3.14\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c * var_d\nvar_f = 3.14\nvar_g = 8\nvar_h = 2\nvar_i = var_g / var_h\nvar_j = var_f * var_i\nvar_k = 8\nvar_l = 2\nvar_m = var_k / var_l\nvar_n = var_j * var_m\nvar_o = var_e / var_n\nprint(int(var_o))"
    },
    "882": {
        "category": "Comparison",
        "question_ko": "화물칸에 A, B, C 3개의 화물을 실으려고 합니다. A 화물은 B 화물보다 크고 C 화물은 A 화물보다 큽니다. 가장 작은 화물을 먼저 실으려고 한다면 가장 먼저 실어야 하는 화물은 무엇일까요?",
        "question_en": "You are going to load three cargoes, A, B, and C, into the cargo hold. Cargo A is larger than cargo B, and cargo C is larger than cargo A. If you want to load the smallest cargo first, which cargo should be loaded first?",
        "answer_ko": "B",
        "answer_en": "B",
        "solution_abst_ko": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] A B > C A > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] A B > C A > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'A'\nvar_e = 'B'\nvar_f = '>'\nvar_g = 'C'\nvar_h = 'A'\nvar_i = '>'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = len(list_c)\nvar_k = list_c[var_j-1]\nprint(var_k)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'A'\nvar_e = 'B'\nvar_f = '>'\nvar_g = 'C'\nvar_h = 'A'\nvar_i = '>'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = len(list_c)\nvar_k = list_c[var_j-1]\nprint(var_k)"
    },
    "883": {
        "category": "Arithmetic calculation",
        "question_ko": "유나는 가지고 있던 구슬 중에서 12개를 동생에게 주고 언니에게 5개를 받았습니다. 그다음 가지고 있던 구슬의 절반을 남준이에게 주고 윤기에게 3개를 받아서 17개가 되었습니다. 처음에 유나가 가지고 있던 구슬은 몇 개입니까?",
        "question_en": "Yuna gave 12 of the marbles she had to her younger sister and received 5 from her older sister. Then she gave half of the marbles she had to Namjoon and received 3 from Yoongi, making 17. How many marbles did Yuna have in the beginning?",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "17 3 [OP_SUB] 2 [OP_MUL] 5 [OP_SUB] 12 [OP_ADD]",
        "solution_abst_en": "17 3 [OP_SUB] 2 [OP_MUL] 5 [OP_SUB] 12 [OP_ADD]",
        "solution_code_ko": "var_a = 17\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 5\nvar_g = var_e - var_f\nvar_h = 12\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 17\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 5\nvar_g = var_e - var_f\nvar_h = 12\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "884": {
        "category": "Correspondence",
        "question_ko": "0.55에 어떤 수를 곱하였더니 4.235가 되었습니다. 어떤 수를 0.55로 나누면 얼마입니까?",
        "question_en": "Multiplying 0.55 by a number gives 4.235. What is the value of the number divided by 0.55?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "4.235 0.55 [OP_DIV] 0.55 [OP_DIV]",
        "solution_abst_en": "4.235 0.55 [OP_DIV] 0.55 [OP_DIV]",
        "solution_code_ko": "var_a = 4.235\nvar_b = 0.55\nvar_c = var_a / var_b\nvar_d = 0.55\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 4.235\nvar_b = 0.55\nvar_c = var_a / var_b\nvar_d = 0.55\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "885": {
        "category": "Arithmetic calculation",
        "question_ko": "(가) 반에는 여학생이 25명 있고, 여학생이 남학생보다 3명 더 많습니다. (가) 반 학생 수는 모두 몇 명입니까?",
        "question_en": "There are 25 girls in class (A), and there are 3 more girls than boys. How many students are in class (A)?",
        "answer_ko": "47",
        "answer_en": "47",
        "solution_abst_ko": "25 25 3 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "25 25 3 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 25\nvar_b = 25\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 25\nvar_b = 25\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "886": {
        "category": "Correspondence",
        "question_ko": "정현이는 마트에서 가지고 있던 100원 동전의 1/4보다 10개 많게 사용했고, 나머지 동전의 3/5보다 5개 적게 버스 타는데 사용하였고, 그 나머지 동전 중 12개를 동생에게 주었다. 정현이가 마지막에 가진 동전의 개수가 13개일 때 정현이가 처음에 가지고 있던 100원 동전의 개수를 구하시오.",
        "question_en": "Jung Hyun used 10 more than 1/4 of the 100 won coins she had at the mart, 5 less than 3/5 of the remaining coins to ride the bus, and gave 12 of the remaining coins to her younger brother. Find the number of 100 won coins that Jung Hyun had at the beginning when the number of coins she had at the end was 13.",
        "answer_ko": "80",
        "answer_en": "80",
        "solution_abst_ko": "13 12 [OP_ADD] 5 [OP_SUB] 1 3/5 [OP_SUB] [OP_DIV] 10 [OP_ADD] 1 1/4 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "13 12 [OP_ADD] 5 [OP_SUB] 1 3/5 [OP_SUB] [OP_DIV] 10 [OP_ADD] 1 1/4 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 13\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = 0.6\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 10\nvar_k = var_i + var_j\nvar_l = 1\nvar_m = 0.25\nvar_n = var_l - var_m\nvar_o = var_k / var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 13\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = 0.6\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 10\nvar_k = var_i + var_j\nvar_l = 1\nvar_m = 0.25\nvar_n = var_l - var_m\nvar_o = var_k / var_n\nprint(int(var_o))"
    },
    "887": {
        "category": "Arithmetic calculation",
        "question_ko": "오리들이 어제는 알을 1925개 낳았고, 오늘은 어제보다 알을 138개 적게 낳았습니다. 어제와 오늘 낳은 알은 모두 몇 개입니까?",
        "question_en": "The ducks laid 1925 eggs yesterday and 138 fewer eggs today than yesterday. Find out the sum of the eggs laid yesterday and today.",
        "answer_ko": "3712",
        "answer_en": "3712",
        "solution_abst_ko": "1925 1925 138 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "1925 1925 138 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 1925\nvar_b = 1925\nvar_c = 138\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 1925\nvar_b = 1925\nvar_c = 138\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "888": {
        "category": "Geometry",
        "question_ko": "어떠한 수는 3으로도 나누어떨어지고 4로도 나누어떨어진다. 가능한 어떤 수 중 가장 작은 값을 구하시오.",
        "question_en": "Any number is divisible by 3 and even divisible by 4. Find the smallest value of any possible number.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "3 4 [OP_LCM]",
        "solution_abst_en": "3 4 [OP_LCM]",
        "solution_code_ko": "var_a = 3\nvar_b = 4\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 4\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nprint(int(var_c))"
    },
    "889": {
        "category": "Geometry",
        "question_ko": "직각삼각형의 빗변이 아닌 한 변의 길이가 5, 나머지 빗변이 아닌 한 변의 길이가 12일 때 빗변의 길이는 얼마입니까?",
        "question_en": "What is the length of the hypotenuse of a right triangle if the length of the non-hypotenuse is 5 and the other non-hypotenuse is 12?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "12 2 [OP_POW] 5 2 [OP_POW] [OP_ADD] 1/2 [OP_POW]",
        "solution_abst_en": "12 2 [OP_POW] 5 2 [OP_POW] [OP_ADD] 1/2 [OP_POW]",
        "solution_code_ko": "var_a = 12\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c + var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 12\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c + var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))"
    },
    "890": {
        "category": "Possibility",
        "question_ko": "다음과 같이 0, 2, 9 숫자카드 3장을 한 번씩 모두 사용하여 만들 수 있는 3자리 수를 모두 구한다면 전부 몇 개입니까?",
        "question_en": "How many 3-digit numbers can be made by using all three 0, 2, and 9 number cards once?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 0 2 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 2 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 2\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 0\nvar_b = 2\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "891": {
        "category": "Geometry",
        "question_ko": "길이가 78센티미터(㎝)인 리본을 모두 사용하여 삼각형 1개와 정사각형 1개를 만들었습니다. 삼각형의 둘레가 46센티미터(㎝)라면, 정사각형의 한 변의 길이는 몇 센티미터(㎝)일지 구하시오.",
        "question_en": "I used all of the ribbon with a length of 78 centimeters (cm) to make one triangle and one square. If the perimeter of the triangle is 46 centimeters (cm), how many centimeters (cm) is the length of one side of the square?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "78 46 [OP_SUB] 4 [OP_DIV]",
        "solution_abst_en": "78 46 [OP_SUB] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 78\nvar_b = 46\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 78\nvar_b = 46\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "892": {
        "category": "Arithmetic calculation",
        "question_ko": "민준이는 지각을 하여 학교로 갈 때 시속 15킬로미터(㎞)의 속도로 갔고, 돌아올 때는 여유롭게 시속 10킬로미터(㎞)속도로 왔더니 등교 때 보다 30분이 더 걸렸다. 갈 때는 얼마나 시간이 걸렸는가?",
        "question_en": "When Minjun was late, he went to school at 15 kilometers (km) per hour, and when he came back at a leisurely pace of 10 kilometers (km) per hour, it took 30 minutes longer than when he went to school. How long did it take to go to school?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "10 30 60 [OP_DIV] [OP_MUL] 15 10 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "10 30 60 [OP_DIV] [OP_MUL] 15 10 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 30\nvar_c = 60\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 15\nvar_g = 10\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 30\nvar_c = 60\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 15\nvar_g = 10\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "893": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 10까지의 짝수를 모두 더한 값은 얼마인지 구하시오.",
        "question_en": "What is the sum of all even numbers from 1 to 10?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "1 10 [OP_LIST_EVEN] [OP_LIST_SUM]",
        "solution_abst_en": "1 10 [OP_LIST_EVEN] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 10\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nprint(int(var_c))",
        "solution_code_en": "var_a = 1\nvar_b = 10\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nprint(int(var_c))"
    },
    "894": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 구하시오. 어떤 수는 12를 더하고 27을 빼면 24가 되는 수입니다.",
        "question_en": "Find the number. The number results in 24 when you add 12 and subtract 27.",
        "answer_ko": "39",
        "answer_en": "39",
        "solution_abst_ko": "24 27 [OP_ADD] 12 [OP_SUB]",
        "solution_abst_en": "24 27 [OP_ADD] 12 [OP_SUB]",
        "solution_code_ko": "var_a = 24\nvar_b = 27\nvar_c = var_a + var_b\nvar_d = 12\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 24\nvar_b = 27\nvar_c = var_a + var_b\nvar_d = 12\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "895": {
        "category": "Arithmetic calculation",
        "question_ko": "32의 약수이거나 24의 약수인 수를 모두 구하시오.",
        "question_en": "Find the number of numbers that are divisors of 32 or factors of 24.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "32 [OP_LIST_GET_DIVISOR] 24 [OP_LIST_GET_DIVISOR] [OP_SET_UNION] [OP_LIST_LEN]",
        "solution_abst_en": "32 [OP_LIST_GET_DIVISOR] 24 [OP_LIST_GET_DIVISOR] [OP_SET_UNION] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 32\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 24\nlist_b = []\nnum_sqrt = int(math.sqrt(var_b))\nfor i in range(1, num_sqrt+1):\n    if var_b % i == 0:\n        list_b.append(i)\n        list_b.append(int(var_b/i))\nlist_b = sorted(set(list_b))\nlist_c = list(set(list_a) | set(list_b))\nvar_c = len(list_c)\nprint(int(var_c))",
        "solution_code_en": "var_a = 32\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 24\nlist_b = []\nnum_sqrt = int(math.sqrt(var_b))\nfor i in range(1, num_sqrt+1):\n    if var_b % i == 0:\n        list_b.append(i)\n        list_b.append(int(var_b/i))\nlist_b = sorted(set(list_b))\nlist_c = list(set(list_a) | set(list_b))\nvar_c = len(list_c)\nprint(int(var_c))"
    },
    "896": {
        "category": "Arithmetic calculation",
        "question_ko": "형준이는 2리터(L)가 들어있는 콜라를 매일 200밀리리터(㎖)씩 나눠 마십니다. 지금까지 3일 동안 콜라를 마셨을 때 콜라를 다 마시는 데엔 며칠이 걸립니까?",
        "question_en": "Hyungjun drinks 200 milliliters (ml) of Coke every day, which contains 2 liters (L). How many days will it take him to finish drinking Coke if he has been drinking Coke for 3 days?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "2 1000 [OP_MUL] 200 3 [OP_MUL] [OP_SUB] 200 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "2 1000 [OP_MUL] 200 3 [OP_MUL] [OP_SUB] 200 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 200\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 200\nvar_i = var_g / var_h\nvar_j = 1\nvar_k=int(((var_i+9*10**(var_j-2))//(10**(var_j-1)))*10**(var_j-1))\n\nprint(int(var_k))",
        "solution_code_en": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 200\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 200\nvar_i = var_g / var_h\nvar_j = 1\nvar_k=int(((var_i+9*10**(var_j-2))//(10**(var_j-1)))*10**(var_j-1))\n\nprint(int(var_k))"
    },
    "897": {
        "category": "Comparison",
        "question_ko": "무게가 같은 연습장 5 개를 책꽂이에 꽂으면 총 무게는 2.9킬로그램(㎏)입니다. 무게가 같은 책 3 개를 책꽂이에 꽂으면 총 무게는 2.51킬로그램(㎏) 입니다. 책꽂이의 무게가 0.2킬로그램(㎏)일 때, 책 한 권과 연습장 한 권 중 어느 것이 더 무거운지 구하시오.",
        "question_en": "If you put 5 notebooks of the same weight on a bookshelf, the total weight is 2.9 kilograms (kg). If three books of the same weight are placed on a bookshelf, the total weight is 2.51 kilograms (kg). If the weight of the bookshelf is 0.2 kilograms (kg), find out which one is heavier, one book or one notebook.",
        "answer_ko": "책",
        "answer_en": "book",
        "solution_abst_ko": "[OP_LIST_SOL] 연습장 책 [OP_LIST_EOL] [OP_LIST_SOL] 2.9 0.2 [OP_SUB] 5 [OP_DIV] 2.51 0.2 [OP_SUB] 3 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] notebook book [OP_LIST_EOL] [OP_LIST_SOL] 2.9 0.2 [OP_SUB] 5 [OP_DIV] 2.51 0.2 [OP_SUB] 3 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '연습장'\nvar_b = '책'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2.9\nvar_d = 0.2\nvar_e = var_c - var_d\nvar_f = 5\nvar_g = var_e / var_f\nvar_h = 2.51\nvar_i = 0.2\nvar_j = var_h - var_i\nvar_k = 3\nvar_l = var_j / var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'notebook'\nvar_b = 'book'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2.9\nvar_d = 0.2\nvar_e = var_c - var_d\nvar_f = 5\nvar_g = var_e / var_f\nvar_h = 2.51\nvar_i = 0.2\nvar_j = var_h - var_i\nvar_k = 3\nvar_l = var_j / var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "898": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 6센티미터(㎝)인 정사각형을 철사로 만들었습니다. 각 네 변의 길이를 1센티미터(㎝)씩 늘렸을 때 원래 정사각형의 넓이와의 차이는 얼마입니까?",
        "question_en": "We made a square with a side length of 6 centimeters (cm) by wire. If you increase the length of each side by 1 centimeters (cm), how much is the difference of the area from the original square?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "6 1 [OP_ADD] 2 [OP_POW] 6 2 [OP_POW] [OP_SUB]",
        "solution_abst_en": "6 1 [OP_ADD] 2 [OP_POW] 6 2 [OP_POW] [OP_SUB]",
        "solution_code_ko": "var_a = 6\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 6\nvar_g = 2\nvar_h = var_f ** var_g\nvar_i = var_e - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 6\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 6\nvar_g = 2\nvar_h = var_f ** var_g\nvar_i = var_e - var_h\nprint(int(var_i))"
    },
    "899": {
        "category": "Correspondence",
        "question_ko": "동일한 길이의 끈 7개를 이었더니 그 길이가 98센티미터(㎝)였다. 끈 하나의 길이가 얼마인지 구하시오.",
        "question_en": "When 7 strings of the same length were thread together, the total length of it was 98 centimeters (cm). Find the length of one string.",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "98 7 [OP_DIV]",
        "solution_abst_en": "98 7 [OP_DIV]",
        "solution_code_ko": "var_a = 98\nvar_b = 7\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 98\nvar_b = 7\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "900": {
        "category": "Geometry",
        "question_ko": "각뿔의 밑면의 수를 구하시오.",
        "question_en": "How many bases are there in a pyramid?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "1",
        "solution_abst_en": "1",
        "solution_code_ko": "var_a = 1\nprint(int(var_a))",
        "solution_code_en": "var_a = 1\nprint(int(var_a))"
    },
    "901": {
        "category": "Comparison",
        "question_ko": "윤기는 4, 정국이는 6에서 3을 곱한 수를 모았습니다. 둘 중 큰 숫자를 가진 사람은 누구입니까?",
        "question_en": "Yoongi has the number 4, and Jungkook has the number that is 6 multiplied by 3. Which of the two has the larger number?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 6\nvar_e = 3\nvar_f = var_d * var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 6\nvar_e = 3\nvar_f = var_d * var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "902": {
        "category": "Possibility",
        "question_ko": "정국이와 호석이에게 구분할 수 없는 자물쇠 7개를 나누어 주었습니다. 정국이와 호석이는 각자 적어도 1개의 자물쇠를 받았습니다. 자물쇠를 나누어주는 방법의 개수를 구하시오.",
        "question_en": "I gave 7 indistinguishable locks to Jungkook and Hoseok. Jungkook and Hoseok each received at least one lock. Find the number of ways to divide locks.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "7 2 1 [OP_MUL] [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "7 2 1 [OP_MUL] [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 7\nvar_b = 2\nvar_c = 1\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 7\nvar_b = 2\nvar_c = 1\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "903": {
        "category": "Comparison",
        "question_ko": "말, 소, 돼지, 양, 토끼, 다람쥐 순으로 울타리 안으로 들어왔다. 4위를 차지한 동물은?",
        "question_en": "A horse, a cow, a pig, a sheep, a rabbit, and a squirrel sequentially entered the fence in that sequence. Which animal took the 4th place?",
        "answer_ko": "양",
        "answer_en": "sheep",
        "solution_abst_ko": "[OP_LIST_SOL] 말 소 돼지 양 토끼 다람쥐 [OP_LIST_EOL] 4 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] horse cow pig sheep rabbit squirrel [OP_LIST_EOL] 4 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '말'\nvar_b = '소'\nvar_c = '돼지'\nvar_d = '양'\nvar_e = '토끼'\nvar_f = '다람쥐'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 4\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'horse'\nvar_b = 'cow'\nvar_c = 'pig'\nvar_d = 'sheep'\nvar_e = 'rabbit'\nvar_f = 'squirrel'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 4\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "904": {
        "category": "Geometry",
        "question_ko": "한 변이 7센티미터(㎝)이고 나머지 한 변이 5센티미터(㎝)인 직사각형의 네 변의 길이의 합과 정사각형의 네 변의 길이의 합이 같다고 합니다. 정사각형의 한 변의 길이를 구하시오.",
        "question_en": "The sum of the lengths of the four sides of a rectangle with sides measuring 7centimeters (cm) and 5centimeters (cm) is equal to the sum of the lengths of the four sides of a square. Find the length of one side of the square.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "7 5 [OP_ADD] 2 [OP_MUL] 4 [OP_DIV]",
        "solution_abst_en": "7 5 [OP_ADD] 2 [OP_MUL] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 7\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 7\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "905": {
        "category": "Correspondence",
        "question_ko": "0.55에 어떤 수를 곱하고 4를 더하였더니 8.235가 되었습니다. 어떤 수를 0.55로 나누면 얼마입니까?",
        "question_en": "Multiply 0.55 by a number and add 4 to get 8.235. What do you get when the number is divided by 0.55?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "8.235 4 [OP_SUB] 0.55 [OP_DIV] 0.55 [OP_DIV]",
        "solution_abst_en": "8.235 4 [OP_SUB] 0.55 [OP_DIV] 0.55 [OP_DIV]",
        "solution_code_ko": "var_a = 8.235\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 0.55\nvar_e = var_c / var_d\nvar_f = 0.55\nvar_g = var_e / var_f\nprint(int(eval('{:.2f}'.format(round(var_g+1e-10,2)))))",
        "solution_code_en": "var_a = 8.235\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 0.55\nvar_e = var_c / var_d\nvar_f = 0.55\nvar_g = var_e / var_f\nprint(int(eval('{:.2f}'.format(round(var_g+1e-10,2)))))"
    },
    "906": {
        "category": "Arithmetic calculation",
        "question_ko": "75로 나누었더니 몫이 11이 되는 어떤 수가 있습니다. 어떤 수 중 가장 큰 수는 무엇입니까?",
        "question_en": "There are numbers whose quotient is 11 when divided by 75. What is the largest out of these numbers?",
        "answer_ko": "899",
        "answer_en": "899",
        "solution_abst_ko": "11 75 [OP_MUL] 75 1 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "11 75 [OP_MUL] 75 1 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 11\nvar_b = 75\nvar_c = var_a * var_b\nvar_d = 75\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 11\nvar_b = 75\nvar_c = var_a * var_b\nvar_d = 75\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "907": {
        "category": "Possibility",
        "question_ko": "5개 반이 서로 한 번씩 피구 경기를 할 때, 이루어지는 경기의 총 수를 구하시오.",
        "question_en": "Find the total number of games played when 5 classes play dodgeball once against each other.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "5 2 [OP_COMB]",
        "solution_abst_en": "5 2 [OP_COMB]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))"
    },
    "908": {
        "category": "Arithmetic calculation",
        "question_ko": "버스 승객은 한 번에 30명까지 탑승할 수 있습니다. 1284명의 승객을 모두 한 번씩 태우기 위해서는 버스는 적어도 몇 번 운행해야 합니까?",
        "question_en": "Bus passengers can ride up to 30 at a time. At least how many trips does the bus have to make to pick up all 1284 passengers once?",
        "answer_ko": "43",
        "answer_en": "43",
        "solution_abst_ko": "1284 30 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "1284 30 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 1284\nvar_b = 30\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))",
        "solution_code_en": "var_a = 1284\nvar_b = 30\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))"
    },
    "909": {
        "category": "Arithmetic calculation",
        "question_ko": "올해 유나는 12살이고 할머니는 72살입니다. 할머니 나이가 유나 나이의 7배가 될 때, 할머니 나이는 몇 살입니까?",
        "question_en": "This year, Yuna is 12 years old and her grandmother is 72 years old. When grandmother's age is 7 times Yuna's age, how old is her grandmother?",
        "answer_ko": "70",
        "answer_en": "70",
        "solution_abst_ko": "72 12 [OP_SUB] 7 [OP_MUL] 7 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "72 12 [OP_SUB] 7 [OP_MUL] 7 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 72\nvar_b = 12\nvar_c = var_a - var_b\nvar_d = 7\nvar_e = var_c * var_d\nvar_f = 7\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 72\nvar_b = 12\nvar_c = var_a - var_b\nvar_d = 7\nvar_e = var_c * var_d\nvar_f = 7\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "910": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 15.25 센티미터(㎝) 인 붕대 20 장을 겹치게 이어 붙이려고 합니다. 이어 붙인 붕대의 전체 길이가 248 센티미터(㎝) 가 되도록 하려면 각 붕대를 몇 센티미터(㎝) 씩 겹치게 이어 붙여야 합니까?",
        "question_en": "You are going to put 20 bandages 15.25 centimeters (cm) in length, overlapping each other. How many centimeters (cm) must each bandage be overlapped so that the total length of the bandages is 248 centimeters (cm)?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "15.25 248 15.25 [OP_SUB] 20 1 [OP_SUB] [OP_DIV] [OP_SUB]",
        "solution_abst_en": "15.25 248 15.25 [OP_SUB] 20 1 [OP_SUB] [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 15.25\nvar_b = 248\nvar_c = 15.25\nvar_d = var_b - var_c\nvar_e = 20\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d / var_g\nvar_i = var_a - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 15.25\nvar_b = 248\nvar_c = 15.25\nvar_d = var_b - var_c\nvar_e = 20\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d / var_g\nvar_i = var_a - var_h\nprint(int(var_i))"
    },
    "911": {
        "category": "Correspondence",
        "question_ko": "A72+23=695입니다. A는 얼마인가요?",
        "question_en": "A72+23=695. How much is A?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "A72+23=695 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A72+23=695 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A72+23=695'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A72+23=695'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "912": {
        "category": "Comparison",
        "question_ko": "지민, 윤기, 태형, 남준이가 달리기 시합을 하고 있습니다. 가장 먼저 결승선에 들어온 학생은 남준이 이며, 윤기가 태형이보다 빨리 결승선을 통과하였습니다. 태형이가 지민이보다 빨리 결승선을 통과했을 때, 꼴등으로 결승선을 통과한 사람은 누구입니까?",
        "question_en": "Jimin, Yoongi, Taehyung, and Namjoon are in a running race. The student who first crossed the finish line was Namjoon, and Yoongi crossed it faster than Taehyung. If Taehyung was faster than Jimin, who would be the last one to cross the finish line?",
        "answer_ko": "지민",
        "answer_en": "Jimin",
        "solution_abst_ko": "[OP_LIST_SOL] 지민 윤기 태형 남준 [OP_LIST_EOL] [OP_LIST_SOL] 남준 윤기 > 남준 지민 > 남준 태형 > 윤기 태형 > 태형 지민 > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jimin Yoongi Taehyung Namjoon [OP_LIST_EOL] [OP_LIST_SOL] Namjoon Yoongi > Namjoon Jimin > Namjoon Taehyung > Yoongi Taehyung > Taehyung Jimin > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '지민'\nvar_b = '윤기'\nvar_c = '태형'\nvar_d = '남준'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '남준'\nvar_f = '윤기'\nvar_g = '>'\nvar_h = '남준'\nvar_i = '지민'\nvar_j = '>'\nvar_k = '남준'\nvar_l = '태형'\nvar_m = '>'\nvar_n = '윤기'\nvar_o = '태형'\nvar_p = '>'\nvar_q = '태형'\nvar_r = '지민'\nvar_s = '>'\nlist_b= []\nif \"/\" in str(var_s):\n    var_s = eval(str(var_s))\nlist_b.append(var_s)\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_t = len(list_c)\nvar_u = list_c[var_t-1]\nprint(var_u)",
        "solution_code_en": "var_a = 'Jimin'\nvar_b = 'Yoongi'\nvar_c = 'Taehyung'\nvar_d = 'Namjoon'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'Namjoon'\nvar_f = 'Yoongi'\nvar_g = '>'\nvar_h = 'Namjoon'\nvar_i = 'Jimin'\nvar_j = '>'\nvar_k = 'Namjoon'\nvar_l = 'Taehyung'\nvar_m = '>'\nvar_n = 'Yoongi'\nvar_o = 'Taehyung'\nvar_p = '>'\nvar_q = 'Taehyung'\nvar_r = 'Jimin'\nvar_s = '>'\nlist_b= []\nif \"/\" in str(var_s):\n    var_s = eval(str(var_s))\nlist_b.append(var_s)\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_t = len(list_c)\nvar_u = list_c[var_t-1]\nprint(var_u)"
    },
    "913": {
        "category": "Correspondence",
        "question_ko": "6을 어떤 수에 곱해야 하는데 실수로 뺐더니 51이 됐습니다. 바르게 계산하면 얼마입니까?",
        "question_en": "I had to multiply a number by 6 but instead subtracted and it resulted in 51. What is the number if I calculate correctly?",
        "answer_ko": "342",
        "answer_en": "342",
        "solution_abst_ko": "51 6 [OP_ADD] 6 [OP_MUL]",
        "solution_abst_en": "51 6 [OP_ADD] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 51\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 51\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "914": {
        "category": "Geometry",
        "question_ko": "길이가 34.8센티미터(㎝)인 철사를 모두 사용하여 정사각형을 만들었습니다. 정사각형의 한 변의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "A square was made using all of the 34.8 centimeters (cm) lengths of wire. How many centimeters (cm) is the length of one side of the square?",
        "answer_ko": "8.70",
        "answer_en": "8.7",
        "solution_abst_ko": "34.8 4 [OP_DIV]",
        "solution_abst_en": "34.8 4 [OP_DIV]",
        "solution_code_ko": "var_a = 34.8\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 34.8\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "915": {
        "category": "Comparison",
        "question_ko": "달리기 시합에서 유나는 17등으로 달리고 있고, 은지는 유나보다 앞에 있고 은지와 유나 사이에는 8명이 있습니다. 은지는 몇 등으로 달리고 있습니까?",
        "question_en": "In the running event, Yuna is running in 17th place. Eunji is ahead of Yuna, and there are 8 people between Eunji and Yuna. What rank is Eunji running?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "17 8 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "17 8 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 17\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 17\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "916": {
        "category": "Comparison",
        "question_ko": "두 막대의 길이 차는 12센티미터(㎝)이고, 긴 막대의 길이에 2/3을 곱한 것이 짧은 막대의 길이입니다. 짧은 막대의 길이는 얼마입니까?",
        "question_en": "The difference between the lengths of the two sticks is 12 centimeters (cm), and the length of the longer stick multiplied by 2/3 is the length of the shorter stick. What is the length of the shorter stick?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "12 1 2/3 [OP_SUB] [OP_DIV] 2/3 [OP_MUL]",
        "solution_abst_en": "12 1 2/3 [OP_SUB] [OP_DIV] 2/3 [OP_MUL]",
        "solution_code_ko": "var_a = 12\nvar_b = 1\nvar_c = 0.6666666666666666\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 0.6666666666666666\nvar_g = var_e * var_f\nprint(int(eval('{:.2f}'.format(round(var_g+1e-10,2)))))",
        "solution_code_en": "var_a = 12\nvar_b = 1\nvar_c = 0.6666666666666666\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 0.6666666666666666\nvar_g = var_e * var_f\nprint(int(eval('{:.2f}'.format(round(var_g+1e-10,2)))))"
    },
    "917": {
        "category": "Comparison",
        "question_ko": "A, B, C 마을의 사람 수는 서로 다릅니다. A 마을이 C 마을보다 사람이 많고, A 마을이 B 마을보다 사람이 많습니다. B 마을이 C 마을보다 사람이 적다면, 사람 수가 가장 많은 마을은 어느 마을인가요?",
        "question_en": "Villages A, B, and C have different numbers of people. Village A has more people than Village C, and Village A has more people than Village B. If Village B has fewer people than Village C, which village has the most people?",
        "answer_ko": "A",
        "answer_en": "A",
        "solution_abst_ko": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] A B > B C < A C > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] A B > B C < A C > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'A'\nvar_e = 'B'\nvar_f = '>'\nvar_g = 'B'\nvar_h = 'C'\nvar_i = '<'\nvar_j = 'A'\nvar_k = 'C'\nvar_l = '>'\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_m = 1\nvar_n = list_c[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'A'\nvar_e = 'B'\nvar_f = '>'\nvar_g = 'B'\nvar_h = 'C'\nvar_i = '<'\nvar_j = 'A'\nvar_k = 'C'\nvar_l = '>'\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_m = 1\nvar_n = list_c[var_m-1]\nprint(var_n)"
    },
    "918": {
        "category": "Arithmetic calculation",
        "question_ko": "친구 4명이 200원짜리 붕어빵 5개, 800원짜리 호떡 7개를 사 먹었습니다. 돈을 4명이 똑같이 나누어 내려면 한 명이 얼마씩 내야 하는지 쓰시오.",
        "question_en": "4 friends bought 5 fish-shaped bread which is  200 won each and 7 hotteoks which is 800 won each. Write how much each person would have to pay if the money were to be divided equally among 4 people.",
        "answer_ko": "1650",
        "answer_en": "1650",
        "solution_abst_ko": "200 5 [OP_MUL] 800 7 [OP_MUL] [OP_ADD] 4 [OP_DIV]",
        "solution_abst_en": "200 5 [OP_MUL] 800 7 [OP_MUL] [OP_ADD] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 200\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 800\nvar_e = 7\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 4\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 200\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 800\nvar_e = 7\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 4\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "919": {
        "category": "Geometry",
        "question_ko": "넓이가 3제곱미터(㎡)인 문의 가로 길이가 150센티미터(㎝)라면, 세로의 길이는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "If the width of a door with an area of 3 square meters (m2) is 150 centimeters (cm), find the length in centimeters (cm).",
        "answer_ko": "200",
        "answer_en": "200",
        "solution_abst_ko": "3 100 2 [OP_POW] [OP_MUL] 150 [OP_DIV]",
        "solution_abst_en": "3 100 2 [OP_POW] [OP_MUL] 150 [OP_DIV]",
        "solution_code_ko": "var_a = 3\nvar_b = 100\nvar_c = 2\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 150\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 3\nvar_b = 100\nvar_c = 2\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 150\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "920": {
        "category": "Arithmetic calculation",
        "question_ko": "흰색 공 30개와 빨간색 공 18개를 같은 색끼리 상자에 나누어 넣습니다. 각 상자마다 공이 6개씩 들어있습니다. 흰색 공이 든 상자는 빨간색 공이 든 상자보다 몇 상자 더 많습니까?",
        "question_en": "You are told to divide 30 white balls and 18 red balls into boxes by the color. There are 6 balls in each box. How many more boxes of white balls would there be than boxes of red balls? ",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "30 6 [OP_DIV] 18 6 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "30 6 [OP_DIV] 18 6 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 30\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 18\nvar_e = 6\nvar_f = var_d / var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 30\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 18\nvar_e = 6\nvar_f = var_d / var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "921": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 11로 나누면 2가 됩니다. 호석이는 이 어떤 수에 6을 곱해 결과값을 얻었습니다. 이 값은?",
        "question_en": "A number divided by 11 equals 2. Hoseok multiplied the number by 6 to get the result value. What is this value?",
        "answer_ko": "132",
        "answer_en": "132",
        "solution_abst_ko": "2 11 [OP_MUL] 6 [OP_MUL]",
        "solution_abst_en": "2 11 [OP_MUL] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 11\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 11\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "922": {
        "category": "Possibility",
        "question_ko": "집에 서로 다른 바지가 2벌, 윗옷이 3벌 있습니다. 몇 가지의 모습으로 입을 수 있습니까?",
        "question_en": "At home, there are 2 pairs of pants and 3 pairs of tops. How many looks can you wear?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "2 3 [OP_MUL]",
        "solution_abst_en": "2 3 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "923": {
        "category": "Comparison",
        "question_ko": "농장에 있는 오리의 다리 수는 총 40개, 토끼의 다리 수는 총 60개 일 때, 오리와 토끼 중 어느 동물이 더 많이 있습니까?",
        "question_en": "If ducks on the farm have a total of 40 legs and rabbits have a total of 60 legs, which animal are there more, ducks or rabbits?",
        "answer_ko": "오리",
        "answer_en": "ducks",
        "solution_abst_ko": "[OP_LIST_SOL] 오리 토끼 [OP_LIST_EOL] [OP_LIST_SOL] 40 2 [OP_DIV] 60 4 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] ducks rabbits [OP_LIST_EOL] [OP_LIST_SOL] 40 2 [OP_DIV] 60 4 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '오리'\nvar_b = '토끼'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 40\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 60\nvar_g = 4\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'ducks'\nvar_b = 'rabbits'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 40\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 60\nvar_g = 4\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "924": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 6센티미터(㎝)인 정육각형을 밑면으로 하고 높이가 1센티미터(㎝)인 정육각기둥을 11개 쌓아 만든 각기둥의 모든 모서리 길이의 합을 구하시오.",
        "question_en": "Find the sum of the lengths of all edges of a prism made by stacking 11 regular hexagonal prisms with a height of 1 centimeter (cm) and its base as 6 centimeters (cm).",
        "answer_ko": "138",
        "answer_en": "138",
        "solution_abst_ko": "6 6 [OP_MUL] 2 [OP_MUL] 11 6 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "6 6 [OP_MUL] 2 [OP_MUL] 11 6 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 11\nvar_g = 6\nvar_h = var_f * var_g\nvar_i = var_e + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 6\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 11\nvar_g = 6\nvar_h = var_f * var_g\nvar_i = var_e + var_h\nprint(int(var_i))"
    },
    "925": {
        "category": "Arithmetic calculation",
        "question_ko": "한 상자당 100개의 구슬을 가졌다면 10개의 상자는 몇 개의 구슬을 가졌는가?",
        "question_en": "If each box has 100 marbles, how many marbles do 10 boxes have?",
        "answer_ko": "1000",
        "answer_en": "1000",
        "solution_abst_ko": "100 10 [OP_MUL]",
        "solution_abst_en": "100 10 [OP_MUL]",
        "solution_code_ko": "var_a = 100\nvar_b = 10\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 100\nvar_b = 10\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "926": {
        "category": "Comparison",
        "question_ko": "5개의 수를 뽑았다. 평균은 81.6이고 가장 큰 수를 뺀 나머지 점수의 평균보다 가장 작은 수를 뺀 나머지 점수들의 평균이 6높다고 한다. 중간의 세 숫자는 88, 84, 75라고 했을 때 가장 낮은 수는 얼마인가?",
        "question_en": "Five numbers were drawn. The average is 81.6, and the average scores excluding the largest number is 6 higher than the average of the remaining scores. If the middle three numbers are 88, 84, and 75, what is the lowest number?",
        "answer_ko": "68.50",
        "answer_en": "68.5",
        "solution_abst_ko": "81.6 5 [OP_MUL] 88 84 [OP_ADD] 75 [OP_ADD] [OP_SUB] 6 4 [OP_MUL] [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "81.6 5 [OP_MUL] 88 84 [OP_ADD] 75 [OP_ADD] [OP_SUB] 6 4 [OP_MUL] [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 81.6\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 88\nvar_e = 84\nvar_f = var_d + var_e\nvar_g = 75\nvar_h = var_f + var_g\nvar_i = var_c - var_h\nvar_j = 6\nvar_k = 4\nvar_l = var_j * var_k\nvar_m = var_i - var_l\nvar_n = 2\nvar_o = var_m / var_n\nprint('{:.2f}'.format(round(var_o+1e-10,2)))",
        "solution_code_en": "var_a = 81.6\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 88\nvar_e = 84\nvar_f = var_d + var_e\nvar_g = 75\nvar_h = var_f + var_g\nvar_i = var_c - var_h\nvar_j = 6\nvar_k = 4\nvar_l = var_j * var_k\nvar_m = var_i - var_l\nvar_n = 2\nvar_o = var_m / var_n\nprint('{:.2f}'.format(round(var_o+1e-10,2)))"
    },
    "927": {
        "category": "Arithmetic calculation",
        "question_ko": "효성이와 미미는 운동장의 끝에서 서로를 향해 일정한 빠르기로 동시에 출발하였습니다. 운동장의 거리는 2.5 킬로미터(㎞) 입니다. 효성이는 1 분에 0.08 킬로미터(㎞) 를 걷고 미미는 한 시간에 2.4 킬로미터(㎞) 를 걷는다면, 15 분 후 두 사람 사이의 거리는 몇 킬로미터(㎞) 입니까?",
        "question_en": "Hyosung and Mimi started at the same speed toward each other at the end of the playground. The distance of the playground is 2.5 kilometers (km). If Hyosung walks 0.08 kilometers (km) per minute and Mimi walks 2.4 kilometers (km) an hour, how many kilometers (km) is the distance between the two people after 15 minutes?",
        "answer_ko": "0.70",
        "answer_en": "0.7",
        "solution_abst_ko": "2.5 0.08 15 [OP_MUL] [OP_SUB] 2.4 60 [OP_DIV] 15 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "2.5 0.08 15 [OP_MUL] [OP_SUB] 2.4 60 [OP_DIV] 15 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 2.5\nvar_b = 0.08\nvar_c = 15\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 2.4\nvar_g = 60\nvar_h = var_f / var_g\nvar_i = 15\nvar_j = var_h * var_i\nvar_k = var_e - var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 2.5\nvar_b = 0.08\nvar_c = 15\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 2.4\nvar_g = 60\nvar_h = var_f / var_g\nvar_i = 15\nvar_j = var_h * var_i\nvar_k = var_e - var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "928": {
        "category": "Correspondence",
        "question_ko": "12를 A로 나눴더니 몫이 B가 되었고, 나머지는 C가 되었습니다. A, B, C는 자연수 입니다. 가능한 C 중 가장 큰 수는 무엇인가요?",
        "question_en": "When 12 is divided by A, the quotient is B and the remainder is C. A, B, and C are natural numbers. What is the largest number that can be C?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "12 1 [OP_SUB]",
        "solution_abst_en": "12 1 [OP_SUB]",
        "solution_code_ko": "var_a = 12\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 12\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "929": {
        "category": "Geometry",
        "question_ko": "직각삼각형의 빗변의 길이가 5, 빗변이 아닌 한 변의 길이가 3이면 나머지 한 변의 길이는 얼마입니까?",
        "question_en": "If the length of the hypotenuse of a right triangle is 5 and the length of the non-hypotenuse is 3, what is the length of the other side?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "5 2 [OP_POW] 3 2 [OP_POW] [OP_SUB] 1/2 [OP_POW]",
        "solution_abst_en": "5 2 [OP_POW] 3 2 [OP_POW] [OP_SUB] 1/2 [OP_POW]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 3\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c - var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 3\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c - var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))"
    },
    "930": {
        "category": "Correspondence",
        "question_ko": "9는 어떤 수와 5의 합입니다. 어떤 수는 얼마입니까?",
        "question_en": "9 is the sum of a number and 5. What is the number?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "9 5 [OP_SUB]",
        "solution_abst_en": "9 5 [OP_SUB]",
        "solution_code_ko": "var_a = 9\nvar_b = 5\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 9\nvar_b = 5\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "931": {
        "category": "Possibility",
        "question_ko": "세 자연수 A, B, C에 대하여 A + B + C = 8을 만족하는 순서쌍의 개수를 구하시오.",
        "question_en": "For the three natural numbers A, B, and C, find the number of ordered pairs that satisfy A + B + C = 8.",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "1 8 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_NUM2SUM] 8 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 8 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_NUM2SUM] 8 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 8\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 8\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 8\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 8\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))"
    },
    "932": {
        "category": "Arithmetic calculation",
        "question_ko": "볼펜이 2180개 있습니다. 200개짜리 필통과 150개짜리 필통에 담아 모두 12개의 필통이 되었습니다. 또한 30개의 볼펜이 남았는데 200개짜리 필통은 몇 개 있나요?",
        "question_en": "There are 2180 ballpoint pens. A total of 12 pencil cases are left after organizing pens into 200 pencil cases and 150 pencil cases. Also, there are 30 ballpoint pens left. Find the number of 200 pencil cases.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "2180 30 [OP_SUB] 150 12 [OP_MUL] [OP_SUB] 200 150 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "2180 30 [OP_SUB] 150 12 [OP_MUL] [OP_SUB] 200 150 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 2180\nvar_b = 30\nvar_c = var_a - var_b\nvar_d = 150\nvar_e = 12\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 200\nvar_i = 150\nvar_j = var_h - var_i\nvar_k = var_g / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 2180\nvar_b = 30\nvar_c = var_a - var_b\nvar_d = 150\nvar_e = 12\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 200\nvar_i = 150\nvar_j = var_h - var_i\nvar_k = var_g / var_j\nprint(int(var_k))"
    },
    "933": {
        "category": "Geometry",
        "question_ko": "모든 모서리의 길이의 합이 108센티미터(㎝)인 정육면체가 있습니다. 이 정육면체의 한 모서리의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "There is a cube whose sum of all its edges equals to 108 centimeters (cm). How long is one edge of this cube in centimeters (cm)?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "108 4 3 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "108 4 3 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 108\nvar_b = 4\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 108\nvar_b = 4\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "934": {
        "category": "Geometry",
        "question_ko": "모든 모서리의 길이가 같은 육각기둥과 사각뿔이 있습니다. 육각기둥의 모든 모서리의 길이의 합이 81센티미터(㎝)일 때, 사각뿔의 모든 모서리의 길이의 합을 구하시오.",
        "question_en": "There are hexagonal prisms and quadrangular pyramids whose all edges are the same length. If the sum of the lengths of all the edges of the hexagonal prism is 81 centimeters (cm), find the sum of the lengths of all the edges of the pyramid.",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "81 6 3 [OP_MUL] [OP_DIV] 4 2 [OP_MUL] [OP_MUL]",
        "solution_abst_en": "81 6 3 [OP_MUL] [OP_DIV] 4 2 [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 81\nvar_b = 6\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nvar_f = 4\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_e * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 81\nvar_b = 6\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nvar_f = 4\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_e * var_h\nprint(int(var_i))"
    },
    "935": {
        "category": "Geometry",
        "question_ko": "한 모서리의 길이가 10센티미터(㎝)인 정육면체의 각 면의 한가운데서 각각 한 모서리의 길이가 2센티미터(㎝)인 정육면체 모양을 파내어서 새로운 도형을 만들었습니다. 이 도형의 겉넓이는 몇 제곱센티미터입니까?",
        "question_en": "In the middle of each face of a cube with an edge length of 10 centimeters (cm), a cube shape with an edge length of 2 centimeters (cm) was dug out to create a new shape. What is the surface area of this shape in square centimeters (cm2)?",
        "answer_ko": "696",
        "answer_en": "696",
        "solution_abst_ko": "10 10 [OP_MUL] 6 [OP_MUL] 2 2 [OP_MUL] 4 [OP_MUL] 6 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "10 10 [OP_MUL] 6 [OP_MUL] 2 2 [OP_MUL] 4 [OP_MUL] 6 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c * var_d\nvar_f = 2\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = 4\nvar_j = var_h * var_i\nvar_k = 6\nvar_l = var_j * var_k\nvar_m = var_e + var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 10\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c * var_d\nvar_f = 2\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = 4\nvar_j = var_h * var_i\nvar_k = 6\nvar_l = var_j * var_k\nvar_m = var_e + var_l\nprint(int(var_m))"
    },
    "936": {
        "category": "Correspondence",
        "question_ko": "어떤 나눗셈식의 몫을 잘못하여 소수점을 기준으로 수를 왼쪽으로 한 자리씩 이동하여 나타내었더니 바르게 계산한 몫과의 차가 37.35 가 되었습니다. 바르게 계산한 몫을 구해 보시오",
        "question_en": "When the quotient of a certain division formula was incorrectly calculated as the number moved to the left by one from the decimal point, the difference of wrong and correct calculated quotient was 37.35. Find the correct quotient.",
        "answer_ko": "4.15",
        "answer_en": "4.15",
        "solution_abst_ko": "37.35 9 [OP_DIV]",
        "solution_abst_en": "37.35 9 [OP_DIV]",
        "solution_code_ko": "var_a = 37.35\nvar_b = 9\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 37.35\nvar_b = 9\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "937": {
        "category": "Correspondence",
        "question_ko": "280보다 큰 수들 중, 70으로 나누었을때 나머지가 30인 가장 작은 수를 구하시오.",
        "question_en": "Among all numbers greater than 280, find the smallest number that has a remainder of 30 when divided by 70.",
        "answer_ko": "310",
        "answer_en": "310",
        "solution_abst_ko": "280 30 [OP_ADD]",
        "solution_abst_en": "280 30 [OP_ADD]",
        "solution_code_ko": "var_a = 280\nvar_b = 30\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 280\nvar_b = 30\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "938": {
        "category": "Arithmetic calculation",
        "question_ko": "오늘은 쿠키를 140개 먹었다. 어제 먹은 쿠키가 오늘 먹은 쿠키보다 30개 적을 때 어제 먹은 쿠키의 개수는 몇 개 인가?",
        "question_en": "I ate 140 cookies today. If there are 30 fewer cookies yesterday than today, how many cookies did I eat yesterday?",
        "answer_ko": "110",
        "answer_en": "110",
        "solution_abst_ko": "140 30 [OP_SUB]",
        "solution_abst_en": "140 30 [OP_SUB]",
        "solution_code_ko": "var_a = 140\nvar_b = 30\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 140\nvar_b = 30\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "939": {
        "category": "Possibility",
        "question_ko": "사과 20개를 2명이서 모두 나누어 가지려고 한다. 최소 1개씩은 갖는다고 한다면, 나누어 가질 수 있는 방법은 모두 몇 가지가 있습니까?",
        "question_en": "Two people try to share 20 apples. If you say every person should have at least one, how many ways are there?",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "20 2 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "20 2 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 20\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "940": {
        "category": "Arithmetic calculation",
        "question_ko": "숫자 7.31, 1/5를 더하면 얼마인가요?",
        "question_en": "What is the sum of the numbers 7.31 and 1/5?",
        "answer_ko": "7.51",
        "answer_en": "7.51",
        "solution_abst_ko": "7.31 1/5 [OP_ADD]",
        "solution_abst_en": "7.31 1/5 [OP_ADD]",
        "solution_code_ko": "var_a = 7.31\nvar_b = 0.2\nvar_c = var_a + var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 7.31\nvar_b = 0.2\nvar_c = var_a + var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "941": {
        "category": "Comparison",
        "question_ko": "저울과 100원짜리 동전을 사용하여 물감과 크레파스의 무게를 비교하려 합니다. 물감은 100원짜리 동전 3개의 무게와 같고 크레파스는 100원짜리 동전 5개의 무게와 같습니다. 물감과 크레파스 중 더 가벼운 것은 무엇입니까?",
        "question_en": "You are trying to compare the weight of paint and crayons using a scale and a 100 won coin. Paint is equal to the weight of 3 100 won coins, and crayons are equal to the weight of 5 100 won coins. Which is lighter, paint or crayons?",
        "answer_ko": "물감",
        "answer_en": "paint",
        "solution_abst_ko": "[OP_LIST_SOL] 물감 크레파스 [OP_LIST_EOL] [OP_LIST_SOL] 100 3 [OP_MUL] 100 5 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] paint crayons [OP_LIST_EOL] [OP_LIST_SOL] 100 3 [OP_MUL] 100 5 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '물감'\nvar_b = '크레파스'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 100\nvar_d = 3\nvar_e = var_c * var_d\nvar_f = 100\nvar_g = 5\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'paint'\nvar_b = 'crayons'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 100\nvar_d = 3\nvar_e = var_c * var_d\nvar_f = 100\nvar_g = 5\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "942": {
        "category": "Geometry",
        "question_ko": "수학 시험에서 석진이는 4등이고, 지민이는 석진이 바로 다음으로 등수를 받았습니다. 지민이는 몇 등입니까?",
        "question_en": "In the math test, Seokjin is ranked 4th, and Jimin is ranked right after Seokjin. What is Jimin's rank?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "4 1 [OP_ADD]",
        "solution_abst_en": "4 1 [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "943": {
        "category": "Geometry",
        "question_ko": "둘레의 길이가 60센티미터(㎝)인 마름모가 있습니다. 이 마름모의 한 꼭짓점에서 이웃한 꼭짓점까지의 거리는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "You have a rhombus with a perimeter of 60 centimeters (cm). Find the distance in centimeters (cm) from one vertex of this rhombus to the next vertex.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "60 4 [OP_DIV]",
        "solution_abst_en": "60 4 [OP_DIV]",
        "solution_code_ko": "var_a = 60\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 60\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "944": {
        "category": "Geometry",
        "question_ko": "지름이 8센티미터(㎝) 이고, 원주가 25.12센티미터(㎝) 인 원의 원주율을 구하시오.",
        "question_en": "Find the pi of a circle with a diameter of 8 centimeters (cm) and a circumference of 25.12 centimeters (cm).",
        "answer_ko": "3.14",
        "answer_en": "3.14",
        "solution_abst_ko": "25.12 8 [OP_DIV]",
        "solution_abst_en": "25.12 8 [OP_DIV]",
        "solution_code_ko": "var_a = 25.12\nvar_b = 8\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 25.12\nvar_b = 8\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "945": {
        "category": "Comparison",
        "question_ko": "두 원 (가), (나)가 있습니다. (가)의 넓이는 198.4제곱센티미터(㎠), (나)의 넓이는 251.1제곱센티미터(㎠)입니다. 원주율을 3.1로 계산할 때 (나)의 원주에서 (가)의 원주를 뺀 값은 몇 센티미터(㎝)인지 소수점을 포함하여 구하시오.",
        "question_en": "There are two circles A and B. The area of A is 198.4 square centimeters (cm2), and the area of B is 251.1 square centimeters (cm2). When the pi is calculated as 3.1, find the number of centimeters (cm) by subtracting the circumference of A from the circumference of B including the decimal point.",
        "answer_ko": "6.2",
        "answer_en": "6.2",
        "solution_abst_ko": "198.4 3.1 [OP_DIV] 1 2 [OP_DIV] [OP_POW] 2 [OP_MUL] 3.1 [OP_MUL] 251.1 3.1 [OP_DIV] 1 2 [OP_DIV] [OP_POW] 2 [OP_MUL] 3.1 [OP_MUL] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "198.4 3.1 [OP_DIV] 1 2 [OP_DIV] [OP_POW] 2 [OP_MUL] 3.1 [OP_MUL] 251.1 3.1 [OP_DIV] 1 2 [OP_DIV] [OP_POW] 2 [OP_MUL] 3.1 [OP_MUL] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 198.4\nvar_b = 3.1\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = 2\nvar_f = var_d / var_e\nvar_g = var_c ** var_f\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = 3.1\nvar_k = var_i * var_j\nvar_l = 251.1\nvar_m = 3.1\nvar_n = var_l / var_m\nvar_o = 1\nvar_p = 2\nvar_q = var_o / var_p\nvar_r = var_n ** var_q\nvar_s = 2\nvar_t = var_r * var_s\nvar_u = 3.1\nvar_v = var_t * var_u\nvar_w = var_k - var_v\nvar_x = abs(var_w)\nprint('{:.2f}'.format(round(var_x+1e-10,2)))",
        "solution_code_en": "var_a = 198.4\nvar_b = 3.1\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = 2\nvar_f = var_d / var_e\nvar_g = var_c ** var_f\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = 3.1\nvar_k = var_i * var_j\nvar_l = 251.1\nvar_m = 3.1\nvar_n = var_l / var_m\nvar_o = 1\nvar_p = 2\nvar_q = var_o / var_p\nvar_r = var_n ** var_q\nvar_s = 2\nvar_t = var_r * var_s\nvar_u = 3.1\nvar_v = var_t * var_u\nvar_w = var_k - var_v\nvar_x = abs(var_w)\nprint('{:.2f}'.format(round(var_x+1e-10,2)))"
    },
    "946": {
        "category": "Arithmetic calculation",
        "question_ko": "가로 4센티미터(㎝), 세로 5센티미터(㎝), 높이 7센티미터(㎝)인 직육면체를 빈틈없이 쌓아 가로 24센티미터(㎝), 세로 15센티미터(㎝), 높이 28센티미터(㎝)인 직육면체를 만들기 위해선 직육면체가 몇 개 필요합니까?",
        "question_en": "I want to create a cuboid with 24 centimeters (cm) width, 15 centimeters (cm) length, and 28 centimeters (cm) height by stacking cuboids with 4 centimeters (cm) width, 5 centimeters (cm) length, and 7 centimeters (cm) height. How many cuboids do you need to make it?",
        "answer_ko": "72",
        "answer_en": "72",
        "solution_abst_ko": "24 15 [OP_MUL] 28 [OP_MUL] 4 5 [OP_MUL] 7 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "24 15 [OP_MUL] 28 [OP_MUL] 4 5 [OP_MUL] 7 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 24\nvar_b = 15\nvar_c = var_a * var_b\nvar_d = 28\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = 5\nvar_h = var_f * var_g\nvar_i = 7\nvar_j = var_h * var_i\nvar_k = var_e / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 24\nvar_b = 15\nvar_c = var_a * var_b\nvar_d = 28\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = 5\nvar_h = var_f * var_g\nvar_i = 7\nvar_j = var_h * var_i\nvar_k = var_e / var_j\nprint(int(var_k))"
    },
    "947": {
        "category": "Comparison",
        "question_ko": "들이가 1100밀리리터(㎖) 인 물통과 들이가 3리터(L) 400밀리리터(㎖) 인 주스병에 물을 가득 채운 후 양동이에 옮겨 담았더니 양동이가 가득 찼습니다. 들이가 4리터(L) 800밀리리터(㎖) 인 주전자와 양동이 중에서 어느 것의 들이가 더 많습니까?",
        "question_en": "After filling the water into the 1100 milliliter (㎖) water bottle and 3 liter (L) and 400 milliliter (㎖) juice bottle, they were transported to the bucket. As the bucket became full, which one has more capacity: a kettle with a capacity of 4 liters (L) and 800 milliliters (㎖) or the bucket?",
        "answer_ko": "주전자",
        "answer_en": "kettle",
        "solution_abst_ko": "[OP_LIST_SOL] 주전자 양동이 [OP_LIST_EOL] [OP_LIST_SOL] 4 1000 [OP_MUL] 800 [OP_ADD] 1100 3 1000 [OP_MUL] 400 [OP_ADD] [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] kettle bucket [OP_LIST_EOL] [OP_LIST_SOL] 4 1000 [OP_MUL] 800 [OP_ADD] 1100 3 1000 [OP_MUL] 400 [OP_ADD] [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '주전자'\nvar_b = '양동이'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 800\nvar_g = var_e + var_f\nvar_h = 1100\nvar_i = 3\nvar_j = 1000\nvar_k = var_i * var_j\nvar_l = 400\nvar_m = var_k + var_l\nvar_n = var_h + var_m\nlist_b= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_o = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_p = list_c[-var_o]\nvar_q = list_b.index(var_p)+1\nvar_r = list_a[var_q-1]\nprint(var_r)",
        "solution_code_en": "var_a = 'kettle'\nvar_b = 'bucket'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 800\nvar_g = var_e + var_f\nvar_h = 1100\nvar_i = 3\nvar_j = 1000\nvar_k = var_i * var_j\nvar_l = 400\nvar_m = var_k + var_l\nvar_n = var_h + var_m\nlist_b= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_o = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_p = list_c[-var_o]\nvar_q = list_b.index(var_p)+1\nvar_r = list_a[var_q-1]\nprint(var_r)"
    },
    "948": {
        "category": "Arithmetic calculation",
        "question_ko": "5 이하인 자연수들의 합을 구하시오.",
        "question_en": "Find the sum of all natural numbers less than or equal to 5.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "1 5 1 [OP_LIST_ARANGE] [OP_LIST_SUM]",
        "solution_abst_en": "1 5 1 [OP_LIST_ARANGE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 5\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_a = [float(i) for i in list_a]\nvar_d = sum(list_a)\nprint(int(var_d))",
        "solution_code_en": "var_a = 1\nvar_b = 5\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_a = [float(i) for i in list_a]\nvar_d = sum(list_a)\nprint(int(var_d))"
    },
    "949": {
        "category": "Correspondence",
        "question_ko": "A, B는 한 자리 수입니다. 7ABABA가 여섯 자리 수이면서 6의 배수라고 합니다. 이러한 여섯 자리 수는 모두 몇 가지입니까?",
        "question_en": "7ABABA is a six-digit number consisting of single digit numbers of A and B. When it is said to be a multiple of 6, how many of these six digits are there?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "7ABABA [OP_GEN_POSSIBLE_LIST] 6 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "7ABABA [OP_GEN_POSSIBLE_LIST] 6 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '7ABABA'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 6\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))",
        "solution_code_en": "var_a = '7ABABA'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 6\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))"
    },
    "950": {
        "category": "Correspondence",
        "question_ko": "서로 다른 네 수 A, B, C, D가 있습니다. 네 자리 수끼리의 덧셈식 ABCD+ABCD=5472에서 D를 구하시오.",
        "question_en": "There are four different numbers A, B, C, and D. Find D from the four-digit addition formula ABCD+ABCD=5472.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "ABCD+ABCD=5472 D [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "ABCD+ABCD=5472 D [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'ABCD+ABCD=5472'\nvar_b = 'D'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'ABCD+ABCD=5472'\nvar_b = 'D'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "951": {
        "category": "Correspondence",
        "question_ko": "3A+B82=216일 때, A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "When 3A+B82=216, what number should go in A?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "3A+B82=216 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "3A+B82=216 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '3A+B82=216'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '3A+B82=216'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "952": {
        "category": "Arithmetic calculation",
        "question_ko": "유준이네 모둠 학생 8명이 KTX를 타고 서울역에서 부산역까지 가는 데 남은 좌석이 5개밖에 없어서 나머지를 입석표로 끊고 돌아가면서 자리에 않기로 하였습니다. KTX를 탄 시간이 2시간 32분이라면, 한 사람이 평균 몇 분씩 앉은 셈입니까?",
        "question_en": "Yujun's group of 8 students took the KTX from Seoul Station to Busan Station, but there were only 5 seats left, so they decided to buy standing tickets and sit in the remaining seats by turns. If the time taken on the KTX is 2 hours and 32 minutes, how many minutes does one person sit on average?",
        "answer_ko": "95",
        "answer_en": "95",
        "solution_abst_ko": "2 60 [OP_MUL] 32 [OP_ADD] 8 [OP_DIV] 5 [OP_MUL]",
        "solution_abst_en": "2 60 [OP_MUL] 32 [OP_ADD] 8 [OP_DIV] 5 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 32\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e / var_f\nvar_h = 5\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 2\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 32\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e / var_f\nvar_h = 5\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "953": {
        "category": "Correspondence",
        "question_ko": "77은 어떤 수에서 35를 빼야하는데 실수로 더해서 나온 숫자입니다. 바르게 계산하면 얼마입니까?",
        "question_en": "77 is a number that you need to subtract 35 from a number, but you accidentally added it. How much is it when you calculate correctly?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "77 35 [OP_SUB] 35 [OP_SUB]",
        "solution_abst_en": "77 35 [OP_SUB] 35 [OP_SUB]",
        "solution_code_ko": "var_a = 77\nvar_b = 35\nvar_c = var_a - var_b\nvar_d = 35\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 77\nvar_b = 35\nvar_c = var_a - var_b\nvar_d = 35\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "954": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 10, 11, 12, 13이 있습니다. 그 중에서 가장 큰 수를 가장 작은 수로 나눈 값은 얼마입니까?",
        "question_en": "There are four numbers 10, 11, 12, and 13. What is the largest number divided by the smallest number?",
        "answer_ko": "1.30",
        "answer_en": "1.3",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_DIV]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "955": {
        "category": "Correspondence",
        "question_ko": "한 자리 수 A, B로 여덟 자리 수 757AB384를 만들었을 때 이 수는 357로 나누어 떨어진다고 합니다. B가 될 수 있는 값을 구하시오.",
        "question_en": "An eight-digit number 757AB384 is said to be divisible by 357. Find the value that can be B.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "757AB384 [OP_GEN_POSSIBLE_LIST] 357 [OP_LIST_DIVISIBLE] 757AB384 B [OP_LIST_FIND_UNK]",
        "solution_abst_en": "757AB384 [OP_GEN_POSSIBLE_LIST] 357 [OP_LIST_DIVISIBLE] 757AB384 B [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = '757AB384'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 357\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = '757AB384'\nvar_d = 'B'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nvar_e = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_e = int(elem[unk_idx])\nprint(int(var_e))",
        "solution_code_en": "var_a = '757AB384'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 357\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = '757AB384'\nvar_d = 'B'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nvar_e = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_e = int(elem[unk_idx])\nprint(int(var_e))"
    },
    "956": {
        "category": "Arithmetic calculation",
        "question_ko": "버스에 32명이 타고 있었습니다. 정류장에서 19명이 타고 13명이 내렸습니다. 지금 버스에 타고 있는 사람은 몇 명인지 구하시오.",
        "question_en": "There were 32 people on the bus. At the bus stop, 19 people got on and 13 people got off. Find how many people are on the bus right now.",
        "answer_ko": "38",
        "answer_en": "38",
        "solution_abst_ko": "32 19 [OP_ADD] 13 [OP_SUB]",
        "solution_abst_en": "32 19 [OP_ADD] 13 [OP_SUB]",
        "solution_code_ko": "var_a = 32\nvar_b = 19\nvar_c = var_a + var_b\nvar_d = 13\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 32\nvar_b = 19\nvar_c = var_a + var_b\nvar_d = 13\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "957": {
        "category": "Comparison",
        "question_ko": "슈퍼마켓에는 28개의 동일한 계란 상자가 있습니다. 각 계란 상자에는 동일한 수의 계란이 있습니다. 달걀판에서 앞에서 14번째, 뒤에서 20개, 왼쪽에서 3번째, 오른쪽에서 두 번째를 선택했다면, 그 시장의 달걀판에 있는 달걀의 개수를 구하세요.",
        "question_en": "There are 28 identical cartons of eggs in the supermarket. Each egg carton contains the same number of eggs. If you select an egg that is at 14 from the front, 20 from the back, 3 from the left, and 2 from the right on the carton, count the number of eggs on cartons at that market.",
        "answer_ko": "3696",
        "answer_en": "3696",
        "solution_abst_ko": "14 20 [OP_ADD] 1 [OP_SUB] 3 2 [OP_ADD] 1 [OP_SUB] [OP_MUL] 28 [OP_MUL]",
        "solution_abst_en": "14 20 [OP_ADD] 1 [OP_SUB] 3 2 [OP_ADD] 1 [OP_SUB] [OP_MUL] 28 [OP_MUL]",
        "solution_code_ko": "var_a = 14\nvar_b = 20\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nvar_l = 28\nvar_m = var_k * var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 14\nvar_b = 20\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nvar_l = 28\nvar_m = var_k * var_l\nprint(int(var_m))"
    },
    "958": {
        "category": "Correspondence",
        "question_ko": "두 자리 수 3A는 8의 배수이다. A는 몇인가?",
        "question_en": "The two-digit number 3A is a multiple of 8. What number can be A?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "3A [OP_GEN_POSSIBLE_LIST] 8 [OP_LIST_DIVISIBLE] 3A A [OP_LIST_FIND_UNK]",
        "solution_abst_en": "3A [OP_GEN_POSSIBLE_LIST] 8 [OP_LIST_DIVISIBLE] 3A A [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = '3A'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 8\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = '3A'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nvar_e = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_e = int(elem[unk_idx])\nprint(int(var_e))",
        "solution_code_en": "var_a = '3A'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 8\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = '3A'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nvar_e = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_e = int(elem[unk_idx])\nprint(int(var_e))"
    },
    "959": {
        "category": "Possibility",
        "question_ko": "4개의 숫자 1, 5, 6, 9를 한 번씩 사용하여 일의 자리 숫자가 1인 가장 큰 두 자리 수를 구하시오.",
        "question_en": "Using the four numbers 1, 5, 6, and 9 once, find the largest two-digit number with 1 in the ones place.",
        "answer_ko": "91",
        "answer_en": "91",
        "solution_abst_ko": "[OP_LIST_SOL] 1 5 6 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 1 [OP_LIST_SEARCH_FIXED_DIGIT] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1 5 6 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 1 [OP_LIST_SEARCH_FIXED_DIGIT] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1\nvar_b = 5\nvar_c = 6\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nvar_g = 1\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 5\nvar_c = 6\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nvar_g = 1\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nprint(int(var_i))"
    },
    "960": {
        "category": "Arithmetic calculation",
        "question_ko": "하나에 2750원인 공이 25개씩 8박스가 1 트럭에 실려있다. 이와 같은 트럭이 18대가 있을 때, 공을 팔아서 얻을 수 있는 돈은 얼마입니까?",
        "question_en": "8 boxes of 25 balls each costing 2750 won are loaded on one truck. When there are 18 trucks like this, how much money can you make selling the balls?",
        "answer_ko": "9900000",
        "answer_en": "9900000",
        "solution_abst_ko": "18 8 [OP_MUL] 25 [OP_MUL] 2750 [OP_MUL]",
        "solution_abst_en": "18 8 [OP_MUL] 25 [OP_MUL] 2750 [OP_MUL]",
        "solution_code_ko": "var_a = 18\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 25\nvar_e = var_c * var_d\nvar_f = 2750\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 18\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 25\nvar_e = var_c * var_d\nvar_f = 2750\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "961": {
        "category": "Arithmetic calculation",
        "question_ko": "유정이는 가지고 있던 사탕 중에서 언니에게 7개를 주고 동생에게 6개를 주었더니 15개가 남았습니다. 처음에 유정이가 가지고 있던 사탕은 몇 개입니까?",
        "question_en": "Yoojung gave 7 candies to her older sister and 6 to her younger sister, and there were 15 left over. How many candies did Yoojung have at first?",
        "answer_ko": "28",
        "answer_en": "28",
        "solution_abst_ko": "15 7 [OP_ADD] 6 [OP_ADD]",
        "solution_abst_en": "15 7 [OP_ADD] 6 [OP_ADD]",
        "solution_code_ko": "var_a = 15\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 6\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 6\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "962": {
        "category": "Arithmetic calculation",
        "question_ko": "지안이는 5일동안 1/3리터(L)의 물을 마시고 주원이는 2일동안 1/5리터(L)의 물을 마십니다. 지안이와 주원이가 함께 1리터(L)를 다 마시는데 며칠이 걸리나요?",
        "question_en": "When Jian drinks 1/3 liter (L) of water for 5 days and Joowon drinks 1/5 liter (L) for 2 days, find the number of days it takes for them to drink 1 liter (l) of water together.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "1 1/3 5 [OP_DIV] 1/5 2 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_abst_en": "1 1/3 5 [OP_DIV] 1/5 2 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 0.3333333333333333\nvar_c = 5\nvar_d = var_b / var_c\nvar_e = 0.2\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = var_a / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))",
        "solution_code_en": "var_a = 1\nvar_b = 0.3333333333333333\nvar_c = 5\nvar_d = var_b / var_c\nvar_e = 0.2\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = var_a / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))"
    },
    "963": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 동아리에 1학년인 학생이 1학년이 아닌 학생보다 12명이 더 많다. 동아리의 인원이 128명일 때, 이 동아리의 1학년은 몇 명인지 구하시오.",
        "question_en": "A club has 12 more first-year students than non-first-year students. If there are 128 people in the club, how many first-year students are in this club?",
        "answer_ko": "70",
        "answer_en": "70",
        "solution_abst_ko": "128 12 [OP_SUB] 2 [OP_DIV] 12 [OP_ADD]",
        "solution_abst_en": "128 12 [OP_SUB] 2 [OP_DIV] 12 [OP_ADD]",
        "solution_code_ko": "var_a = 128\nvar_b = 12\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 12\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 128\nvar_b = 12\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 12\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "964": {
        "category": "Arithmetic calculation",
        "question_ko": "승주가 소설책을 어제는 전체의 3/10을 읽었고, 오늘은 전체의 4/10를 읽었습니다. 어제와 오늘 읽은 소설책의 쪽수가 140쪽이라면 승주가 읽은 소설책의 전체 쪽수는 몇 쪽인지 구해 보시오.",
        "question_en": "Seungju read 3/10 of the novel yesterday, and 4/10 of it today. If the number of pages of the novel he read yesterday and today is 140, how many pages are there in the novel Seungju read?",
        "answer_ko": "200",
        "answer_en": "200",
        "solution_abst_ko": "140 3/10 4/10 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "140 3/10 4/10 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 140\nvar_b = 0.3\nvar_c = 0.4\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 140\nvar_b = 0.3\nvar_c = 0.4\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "965": {
        "category": "Geometry",
        "question_ko": "사각형에서 그을 수 있는 대각선 개수의 최대값을 구하시오.",
        "question_en": "Find the maximum number of diagonals that can be drawn in a rectangle.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "4 4 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "4 4 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 4\nvar_b = 4\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 4\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "966": {
        "category": "Arithmetic calculation",
        "question_ko": "둘레가 2 킬로미터(㎞) 400 미터(m)인 원 모양의 공원 둘레에 32 미터(m) 간격으로 가로등을 설치하려다가 48 미터(m) 간격으로 설치하였습니다. 가로등을 32 미터(m) 간격으로 설치하려 할 때보다 몇 개 더 적게 설치하였습니까?",
        "question_en": "I was trying to install street lights at 32 meters (m) intervals around a circle-shaped park with a circumference of 2 kilometers (km) and 400 meters (m) but installed them at 48 meters (m) intervals. How many fewer streetlights did I install compare to installing them at 32 meters (m) apart?",
        "answer_ko": "25",
        "answer_en": "25",
        "solution_abst_ko": "2 1000 [OP_MUL] 400 [OP_ADD] 32 [OP_DIV] 2 1000 [OP_MUL] 400 [OP_ADD] 48 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "2 1000 [OP_MUL] 400 [OP_ADD] 32 [OP_DIV] 2 1000 [OP_MUL] 400 [OP_ADD] 48 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 400\nvar_e = var_c + var_d\nvar_f = 32\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = 1000\nvar_j = var_h * var_i\nvar_k = 400\nvar_l = var_j + var_k\nvar_m = 48\nvar_n = var_l / var_m\nvar_o = var_g - var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 400\nvar_e = var_c + var_d\nvar_f = 32\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = 1000\nvar_j = var_h * var_i\nvar_k = 400\nvar_l = var_j + var_k\nvar_m = 48\nvar_n = var_l / var_m\nvar_o = var_g - var_n\nprint(int(var_o))"
    },
    "967": {
        "category": "Arithmetic calculation",
        "question_ko": "둘레가 1킬로미터(㎞) 500미터(m)인 산책로를 따라 꽃을 30미터(m) 간격으로 심으려고 합니다. 꽃 한 송이의 값이 5000원일 때, 필요한 꽃을 사는 데 드는 비용은 얼마입니까?",
        "question_en": "You are planning to plant flowers at intervals of 30 meters (m) along a promenade with a perimeter of 1 kilometer (km) and 500 meters (m). If each flower costs 5,000 won, how much does it cost to buy the flowers you need?",
        "answer_ko": "250000",
        "answer_en": "250000",
        "solution_abst_ko": "1 1000 [OP_MUL] 500 [OP_ADD] 30 [OP_DIV] 5000 [OP_MUL]",
        "solution_abst_en": "1 1000 [OP_MUL] 500 [OP_ADD] 30 [OP_DIV] 5000 [OP_MUL]",
        "solution_code_ko": "var_a = 1\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 500\nvar_e = var_c + var_d\nvar_f = 30\nvar_g = var_e / var_f\nvar_h = 5000\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 500\nvar_e = var_c + var_d\nvar_f = 30\nvar_g = var_e / var_f\nvar_h = 5000\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "968": {
        "category": "Arithmetic calculation",
        "question_ko": "숫자 72.52, 12.23, 5.21에 대한 총합은 얼마인가요?",
        "question_en": "What is the sum of the numbers 72.52, 12.23, and 5.21?",
        "answer_ko": "89.96",
        "answer_en": "89.96",
        "solution_abst_ko": "72.52 12.23 [OP_ADD] 5.21 [OP_ADD]",
        "solution_abst_en": "72.52 12.23 [OP_ADD] 5.21 [OP_ADD]",
        "solution_code_ko": "var_a = 72.52\nvar_b = 12.23\nvar_c = var_a + var_b\nvar_d = 5.21\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 72.52\nvar_b = 12.23\nvar_c = var_a + var_b\nvar_d = 5.21\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "969": {
        "category": "Geometry",
        "question_ko": "세로의 길이가 13센티미터(㎝)이고 둘레가 50센티미터(㎝)인 직사각형이 있습니다. 가로의 길이를 구하시오.",
        "question_en": "A rectangle has a length of 13 centimeters (cm) and a perimeter of 50 centimeters (cm). Find the horizontal length.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "50 2 [OP_DIV] 13 [OP_SUB]",
        "solution_abst_en": "50 2 [OP_DIV] 13 [OP_SUB]",
        "solution_code_ko": "var_a = 50\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 13\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 50\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 13\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "970": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 74를 뺀 뒤 15를 곱하여 5로 나눈 뒤 16을 더한 수가 58입니다. 어떤 수를 구하시오.",
        "question_en": "You get 58 when 74 is subtracted by a number, and then multiplies it by 15, divides by 5, and adds 16. Find what the number is.",
        "answer_ko": "88",
        "answer_en": "88",
        "solution_abst_ko": "58 16 [OP_SUB] 5 [OP_MUL] 15 [OP_DIV] 74 [OP_ADD]",
        "solution_abst_en": "58 16 [OP_SUB] 5 [OP_MUL] 15 [OP_DIV] 74 [OP_ADD]",
        "solution_code_ko": "var_a = 58\nvar_b = 16\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c * var_d\nvar_f = 15\nvar_g = var_e / var_f\nvar_h = 74\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 58\nvar_b = 16\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c * var_d\nvar_f = 15\nvar_g = var_e / var_f\nvar_h = 74\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "971": {
        "category": "Possibility",
        "question_ko": "두 숫자 3, 5를 한 번씩만 사용하여 만들 수 있는 서로 다른 두 자리 수는 모두 몇 개입니까?",
        "question_en": "How many different two-digit numbers can be formed by using the two numbers 3 and 5 only once?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 3 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 3 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 3\nvar_b = 5\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = len(list_b)\nprint(int(var_d))",
        "solution_code_en": "var_a = 3\nvar_b = 5\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = len(list_b)\nprint(int(var_d))"
    },
    "972": {
        "category": "Geometry",
        "question_ko": "밑변이 7.2미터(m), 높이가 7미터(m)인 삼각형과 가로가 4미터(m)인 직사각형이 있습니다. 두 도형의 넓이가 같다면 직사각형의 세로는 몇 미터(m)입니까?",
        "question_en": "A triangle with a base of 7.2 meters (m) and a height of 7 meters (m) and a rectangle with a width of 4 meters (m). If both shapes have the same area, how many meters (m) is the length of the rectangle?",
        "answer_ko": "6.30",
        "answer_en": "6.3",
        "solution_abst_ko": "7.2 7 [OP_MUL] 2 [OP_DIV] 4 [OP_DIV]",
        "solution_abst_en": "7.2 7 [OP_MUL] 2 [OP_DIV] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 7.2\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 4\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 7.2\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 4\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "973": {
        "category": "Geometry",
        "question_ko": "10개의 변으로 이루어진 도형의 한 꼭짓점에서 그을 수 있는 대각선의 개수는 몇 개입니까?",
        "question_en": "How many diagonal lines can be drawn at a vertex of a figure with 10 sides?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "10 3 [OP_SUB]",
        "solution_abst_en": "10 3 [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 10\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "974": {
        "category": "Arithmetic calculation",
        "question_ko": "민영이가 우유를 4/9리터(L) 마시고, 유나는 2/3리터(L) 마셨습니다. 민영이가 마신 우유의 양은 유나가 마신 우유의 양의 몇 배인지 구하시오.",
        "question_en": "Minyoung drank 4/9 liters (L) of milk, and Yuna drank 2/3 liters (L). Find how many times the amount of milk that Minyoung drank was the amount of what Yuna drank.",
        "answer_ko": "0.67",
        "answer_en": "0.67",
        "solution_abst_ko": "4/9 2/3 [OP_DIV]",
        "solution_abst_en": "4/9 2/3 [OP_DIV]",
        "solution_code_ko": "var_a = 0.4444444444444444\nvar_b = 0.6666666666666666\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 0.4444444444444444\nvar_b = 0.6666666666666666\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "975": {
        "category": "Comparison",
        "question_ko": "5, 9, 10, 3, 6중에서 가장 작은 숫자를 선택하십시오.",
        "question_en": "Choose the smallest number among 5, 9, 10, 3, and 6.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 5 9 10 3 6 [OP_LIST_EOL] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 5 9 10 3 6 [OP_LIST_EOL] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 5\nvar_b = 9\nvar_c = 10\nvar_d = 3\nvar_e = 6\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 9\nvar_c = 10\nvar_d = 3\nvar_e = 6\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nprint(int(var_g))"
    },
    "976": {
        "category": "Correspondence",
        "question_ko": "-3보다 -5만큼 작은 수를 A, +2보다 -2만큼 큰 수를 B라 할 때, A-B의 값을 구하시오.",
        "question_en": "If A is the number that is -5 less than -3 and B is the number that is -2 greater than +2, find the value of A-B.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "-3 -5 [OP_SUB] 2 -2 [OP_ADD] [OP_SUB]",
        "solution_abst_en": "-3 -5 [OP_SUB] 2 -2 [OP_ADD] [OP_SUB]",
        "solution_code_ko": "var_a = -3\nvar_b = -5\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = -2\nvar_f = var_d + var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = -3\nvar_b = -5\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = -2\nvar_f = var_d + var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "977": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 8로 나누고 7을 더해야하는데 잘못하여 8을 곱했더니 56이 되었습니다. 바르게 계산하면 얼마인지 소수점 둘째 자리까지 나타내시오.",
        "question_en": "When you mistakenly multiply a number by 8, instead of dividing a number by 8 and adding 7, you get 56. If you calculated correctly, indicate the number to two decimal places.",
        "answer_ko": "7.88",
        "answer_en": "7.88",
        "solution_abst_ko": "56 8 [OP_DIV] 8 [OP_DIV] 7 [OP_ADD]",
        "solution_abst_en": "56 8 [OP_DIV] 8 [OP_DIV] 7 [OP_ADD]",
        "solution_code_ko": "var_a = 56\nvar_b = 8\nvar_c = var_a / var_b\nvar_d = 8\nvar_e = var_c / var_d\nvar_f = 7\nvar_g = var_e + var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 56\nvar_b = 8\nvar_c = var_a / var_b\nvar_d = 8\nvar_e = var_c / var_d\nvar_f = 7\nvar_g = var_e + var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "978": {
        "category": "Geometry",
        "question_ko": "반지름 4인 구의 둘레는 몇 파이인지 구하시오.",
        "question_en": "Find the circumference of a sphere of radius 4 centimeters (cm) in pi.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "4 2 [OP_MUL]",
        "solution_abst_en": "4 2 [OP_MUL]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "979": {
        "category": "Comparison",
        "question_ko": "지훈이의 키는 현서보다 크고 현서의 키는 현수보다 크다고 한다. 세 명중 가장 키가 큰 사람은 누구인가?",
        "question_en": "It is said that Jihoon is taller than Hyeonseo and Hyeonseo is taller than Hyeonsoo. Who is the tallest of the three?",
        "answer_ko": "지훈",
        "answer_en": "Jihoon",
        "solution_abst_ko": "[OP_LIST_SOL] 지훈 현서 현수 [OP_LIST_EOL] [OP_LIST_SOL] 지훈 현서 > 현서 현수 > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jihoon Hyeonseo Hyeonsoo [OP_LIST_EOL] [OP_LIST_SOL] Jihoon Hyeonseo > Hyeonseo Hyeonsoo > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '지훈'\nvar_b = '현서'\nvar_c = '현수'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '지훈'\nvar_e = '현서'\nvar_f = '>'\nvar_g = '현서'\nvar_h = '현수'\nvar_i = '>'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(var_k)",
        "solution_code_en": "var_a = 'Jihoon'\nvar_b = 'Hyeonseo'\nvar_c = 'Hyeonsoo'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'Jihoon'\nvar_e = 'Hyeonseo'\nvar_f = '>'\nvar_g = 'Hyeonseo'\nvar_h = 'Hyeonsoo'\nvar_i = '>'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(var_k)"
    },
    "980": {
        "category": "Comparison",
        "question_ko": "가방의 무게를 재어 보니 지민이 가방은 1.2kg이고, 석진이 가방은 1350g이었습니다. 누구의 가방이 더 무겁습니까?",
        "question_en": "When I weighed the bag, Jimin's bag weighed 1.2 kilograms (kg) and Seokjin's bag weighed 1350 grams (g). Whose bag is heavier?",
        "answer_ko": "석진",
        "answer_en": "Seokjin",
        "solution_abst_ko": "[OP_LIST_SOL] 지민 석진 [OP_LIST_EOL] [OP_LIST_SOL] 1.2 1000 [OP_MUL] 1350 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jimin Seokjin [OP_LIST_EOL] [OP_LIST_SOL] 1.2 1000 [OP_MUL] 1350 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '지민'\nvar_b = '석진'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.2\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 1350\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Jimin'\nvar_b = 'Seokjin'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.2\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 1350\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "981": {
        "category": "Possibility",
        "question_ko": "각 자리의 숫자가 0 또는 자연수인 모두 다른 네 자리 수 중 두 번째 큰 수와 두 번째로 작은 수의 차는 얼마입니까?",
        "question_en": "What is the difference between the second largest and the second smallest of all different four-digit numbers where each digit is 0 or a natural number?",
        "answer_ko": "8851",
        "answer_en": "8851",
        "solution_abst_ko": "0 9 1 [OP_LIST_ARANGE] 4 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "0 9 1 [OP_LIST_ARANGE] 4 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 0\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 2\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 0\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 2\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))"
    },
    "982": {
        "category": "Geometry",
        "question_ko": "이십오각형의 한 꼭짓점에서 그을 수 있는 대각선의 개수를 구하시오.",
        "question_en": "Find the number of diagonals that can be drawn from one vertex of the icosikaipentagon.",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "25 3 [OP_SUB]",
        "solution_abst_en": "25 3 [OP_SUB]",
        "solution_code_ko": "var_a = 25\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 25\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "983": {
        "category": "Comparison",
        "question_ko": "숫자 카드 2개를 뽑았습니다. 두 카드에 적힌 숫자의 합은 1443이고 차는 141입니다. 두 카드에 적힌 숫자 중 큰 수는 얼마입니까?",
        "question_en": "You draw 2 number cards. The sum of the numbers written on the two cards is 1443 and the difference is 141. Which of the numbers on the two cards is greater?",
        "answer_ko": "792",
        "answer_en": "792",
        "solution_abst_ko": "1443 141 [OP_ADD] 2 [OP_DIV]",
        "solution_abst_en": "1443 141 [OP_ADD] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 1443\nvar_b = 141\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 1443\nvar_b = 141\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "984": {
        "category": "Geometry",
        "question_ko": "밑면의 넓이가 10제곱센티미터(㎠)이고 높이가 73센티미터(㎝)인 직육면체 모양의 상자보다 부피가 1세제곱센티미터(㎤) 더 적은 정육면체 모양의 상자의 한 모서리의 길이는 몇 센티미터(㎝)인지 구하세요.",
        "question_en": "What is the length in centimeters (cm) of one edge of a cube-shaped box whose volume is 1 cubic centimeter (cm2) less than a cuboid-shaped box whose base is 10 square centimeter (cm2) wide and whose height is 73 centimeters (cm)?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "10 73 [OP_MUL] 1 [OP_SUB] 1/3 [OP_POW]",
        "solution_abst_en": "10 73 [OP_MUL] 1 [OP_SUB] 1/3 [OP_POW]",
        "solution_code_ko": "var_a = 10\nvar_b = 73\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 0.3333333333333333\nvar_g = var_e ** var_f\nprint(int(eval('{:.2f}'.format(round(var_g+1e-10,2)))))",
        "solution_code_en": "var_a = 10\nvar_b = 73\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 0.3333333333333333\nvar_g = var_e ** var_f\nprint(int(eval('{:.2f}'.format(round(var_g+1e-10,2)))))"
    },
    "985": {
        "category": "Arithmetic calculation",
        "question_ko": "한 봉투에 21개의 과자가 들어 있고 한 박스에는 4개의 과자 봉지가 들어 있다. 과자 박스가 2개 있을 때, 과자는 몇 개있는지 구하시오.",
        "question_en": "There are 21 cookies in one bag and there are 4 bags of cookies in one box. If there are 2 cookie boxes, find how many cookies there are.",
        "answer_ko": "168",
        "answer_en": "168",
        "solution_abst_ko": "21 4 [OP_MUL] 2 [OP_MUL]",
        "solution_abst_en": "21 4 [OP_MUL] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 21\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 21\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "986": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 6을 빼야 할 것을 잘못하여 14을 곱한 결과는 70이 되었습니다. 바르게 계산한 결과는 얼마인가요?",
        "question_en": "When I mistakenly multiplied a number by 14 instead of subtracting 6, I got 70. What is the correct calculation result?",
        "answer_ko": "-1",
        "answer_en": "-1",
        "solution_abst_ko": "70 14 [OP_DIV] 6 [OP_SUB]",
        "solution_abst_en": "70 14 [OP_DIV] 6 [OP_SUB]",
        "solution_code_ko": "var_a = 70\nvar_b = 14\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 70\nvar_b = 14\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "987": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 5미터(m), 무게가 29/8킬로그램(㎏)의 인형과 길이가 4미터(m), 무게가 2.8킬로그램(㎏)인 나무가 있다. 인형과 나무를 2미터(m)씩 잘라 함께 무게를 재면 몇 킬로그램(㎏)입니까?",
        "question_en": "There is a doll that is 5 meters (m) long and weighs 29/8 kilograms (kg) and a tree that is 4 meters (m) long and weighs 2.8 kilograms (kg). If you cut the doll and the tree into 2 meters (m) and weigh them together, how many kilograms (kg) do you get?",
        "answer_ko": "2.85",
        "answer_en": "2.85",
        "solution_abst_ko": "29/8 5 [OP_DIV] 2 [OP_MUL] 2.8 4 [OP_DIV] 2 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "29/8 5 [OP_DIV] 2 [OP_MUL] 2.8 4 [OP_DIV] 2 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 3.625\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 2.8\nvar_g = 4\nvar_h = var_f / var_g\nvar_i = 2\nvar_j = var_h * var_i\nvar_k = var_e + var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 3.625\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 2.8\nvar_g = 4\nvar_h = var_f / var_g\nvar_i = 2\nvar_j = var_h * var_i\nvar_k = var_e + var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "988": {
        "category": "Arithmetic calculation",
        "question_ko": "191.8미터(m) 인 복도 양쪽에 같은 간격으로 58개의 소화기를 세우려고 합니다. 복도의 처음과 끝에 모두 소화기를 세웠다면 소화기와 소화기 사이의 거리는 몇 미터(m)입니까?",
        "question_en": "You want to place 58 fire extinguishers equally spaced on each side of a 191.8-meter (m) hallway. If fire extinguishers are placed at both the beginning and end of the hallway, what is the distance in meters (m) between the fire extinguishers?",
        "answer_ko": "6.85",
        "answer_en": "6.85",
        "solution_abst_ko": "191.8 58 2 [OP_DIV] 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "191.8 58 2 [OP_DIV] 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 191.8\nvar_b = 58\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_a / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 191.8\nvar_b = 58\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_a / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "989": {
        "category": "Comparison",
        "question_ko": "물 1리터(L)를 병 가 2개에, 물 3리터(L)를 병 나 4개에 남김없이 똑같이 나누어 담으려고 합니다. 각 병은 모양과 크기가 같을 때, 병 가와 병 나 중 어느 병에 물이 더 많을까요?",
        "question_en": "We are to plan to divide 1 liter (L) of water into 2 bottles of bottle A and 3 liters (L) of water into 4 bottles of B equally. If each bottle is the same shape and size, which bottle has more water, bottle A or bottle B?",
        "answer_ko": "나",
        "answer_en": "B",
        "solution_abst_ko": "[OP_LIST_SOL] 가 나 [OP_LIST_EOL] [OP_LIST_SOL] 1 2 [OP_DIV] 3 4 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 1 2 [OP_DIV] 3 4 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '가'\nvar_b = '나'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 3\nvar_g = 4\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 3\nvar_g = 4\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "990": {
        "category": "Correspondence",
        "question_ko": "2A+B2=89입니다. A와 B가 서로 다른 수라면, A-B는 얼마입니까?",
        "question_en": "2A+B2=89. If A and B are different numbers, what is A-B?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "2A+B2=89 A [OP_DIGIT_UNK_SOLVER] 2A+B2=89 B [OP_DIGIT_UNK_SOLVER] [OP_SUB]",
        "solution_abst_en": "2A+B2=89 A [OP_DIGIT_UNK_SOLVER] 2A+B2=89 B [OP_DIGIT_UNK_SOLVER] [OP_SUB]",
        "solution_code_ko": "var_a = '2A+B2=89'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '2A+B2=89'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = '2A+B2=89'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '2A+B2=89'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "991": {
        "category": "Correspondence",
        "question_ko": "AB19를 백의 자리까지 올림한 값은 7300입니다. AB19를 버림하여 십의 자리까지 나타낸 값은 무엇입니까?",
        "question_en": "AB19 rounded up to the hundred's place is 7300. What is AB19 rounded down to the tens place?",
        "answer_ko": "7210",
        "answer_en": "7210",
        "solution_abst_ko": "AB19 [OP_GEN_POSSIBLE_LIST] 7300 100 [OP_SUB] [OP_LIST_MORE] 7300 [OP_LIST_LESS_EQUAL] AB19 A [OP_LIST_FIND_UNK] 1000 [OP_MUL] AB19 B [OP_LIST_FIND_UNK] 100 [OP_MUL] [OP_ADD] 19 [OP_ADD] 2 [OP_FLOOR]",
        "solution_abst_en": "AB19 [OP_GEN_POSSIBLE_LIST] 7300 100 [OP_SUB] [OP_LIST_MORE] 7300 [OP_LIST_LESS_EQUAL] AB19 A [OP_LIST_FIND_UNK] 1000 [OP_MUL] AB19 B [OP_LIST_FIND_UNK] 100 [OP_MUL] [OP_ADD] 19 [OP_ADD] 2 [OP_FLOOR]",
        "solution_code_ko": "var_a = 'AB19'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 7300\nvar_c = 100\nvar_d = var_b - var_c\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nvar_e = 7300\nlist_c = []\nfor i in list_b:\n    if i <= var_e:\n        list_c.append(i)\nvar_f = 'AB19'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nvar_i = 1000\nvar_j = var_h * var_i\nvar_k = 'AB19'\nvar_l = 'B'\nvar_k = str(var_k)\nvar_l = str(var_l)\nunk_idx = var_k.index(var_l)\nvar_m = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_m = int(elem[unk_idx])\nvar_n = 100\nvar_o = var_m * var_n\nvar_p = var_j + var_o\nvar_q = 19\nvar_r = var_p + var_q\nvar_s = 2\nvar_t=int((var_r//(10**(var_s-1)))*10**(var_s-1))\n\nprint(int(var_t))",
        "solution_code_en": "var_a = 'AB19'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 7300\nvar_c = 100\nvar_d = var_b - var_c\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nvar_e = 7300\nlist_c = []\nfor i in list_b:\n    if i <= var_e:\n        list_c.append(i)\nvar_f = 'AB19'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nvar_i = 1000\nvar_j = var_h * var_i\nvar_k = 'AB19'\nvar_l = 'B'\nvar_k = str(var_k)\nvar_l = str(var_l)\nunk_idx = var_k.index(var_l)\nvar_m = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_m = int(elem[unk_idx])\nvar_n = 100\nvar_o = var_m * var_n\nvar_p = var_j + var_o\nvar_q = 19\nvar_r = var_p + var_q\nvar_s = 2\nvar_t=int((var_r//(10**(var_s-1)))*10**(var_s-1))\n\nprint(int(var_t))"
    },
    "992": {
        "category": "Arithmetic calculation",
        "question_ko": "딸기맛 사탕 28개와 포도맛 사탕 32개가 있습니다. 사탕을 종류에 관계없이 한 명에게 4개씩 주면 몇 명에게 나누어 줄 수 있습니까?",
        "question_en": "There are 28 strawberry-flavored candies and 32 grape-flavored candies. If you give 4 candies of any type to each person, to how many people can you distribute them?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "28 32 [OP_ADD] 4 [OP_FDIV]",
        "solution_abst_en": "28 32 [OP_ADD] 4 [OP_FDIV]",
        "solution_code_ko": "var_a = 28\nvar_b = 32\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 28\nvar_b = 32\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "993": {
        "category": "Comparison",
        "question_ko": "두 친구가 더 큰 숫자를 뽑으면 이기는 게임을 하고 있습니다. 예슬이는 13/10이 적힌 카드를, 영준이는 22/15가 적힌 카드를 뽑았을 때 누가 이겼습니까?",
        "question_en": "Two friends are playing a game where one wins if he draws the bigger number. When Yeseul drew a card with 13/10 written on it, and Youngjun drew a card written as 22/15, who was the winner?",
        "answer_ko": "영준",
        "answer_en": "Youngjun",
        "solution_abst_ko": "[OP_LIST_SOL] 예슬 영준 [OP_LIST_EOL] [OP_LIST_SOL] 13/10 22/15 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yeseul Youngjun [OP_LIST_EOL] [OP_LIST_SOL] 13/10 22/15 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '예슬'\nvar_b = '영준'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.3\nvar_d = 1.4666666666666666\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Yeseul'\nvar_b = 'Youngjun'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.3\nvar_d = 1.4666666666666666\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "994": {
        "category": "Geometry",
        "question_ko": "길이가 12센티미터(㎝)인 선분 AB에 대하여 점 M은 선분 AB의 중점일 때, 선분 AM의 길이를 구하시오.",
        "question_en": "For line segment AB with a length of 12 centimeters (cm), if point M is the midpoint of line segment AB, find the length of line segment AM.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "12 2 [OP_DIV]",
        "solution_abst_en": "12 2 [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 12\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "995": {
        "category": "Correspondence",
        "question_ko": "세 수 (가), (나), (다)가 있다. (가)를 (나)로 나누면 몫이 1.2로 나누어떨어지고, (나)를 (다)로 나누면 몫이 5/6로 나누어떨어진다. (가)를 (다)로 나누면 그 몫은 얼마인가?",
        "question_en": "There are three numbers (A), (B), and (C). When (A) is divided by (B), the quotient is divided by 1.2, and when (B) is divided by (C), the quotient is divided by 5/6. If (A) is divided by (C), what is the quotient?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "1.2 5/6 [OP_MUL]",
        "solution_abst_en": "1.2 5/6 [OP_MUL]",
        "solution_code_ko": "var_a = 1.2\nvar_b = 0.8333333333333334\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 1.2\nvar_b = 0.8333333333333334\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "996": {
        "category": "Comparison",
        "question_ko": "72의 약수와 120의 약수들 중 중복되는 수를 골라서 작은 것부터 차례대로 썼습니다. 4번째로 큰 수는 무엇입니까?",
        "question_en": "Among the divisors of 72 and 120, you write duplicate numbers on paper in order. What is the 4th largest number?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "72 [OP_LIST_GET_DIVISOR] 120 [OP_LIST_GET_DIVISOR] [OP_SET_INTERSECT] 4 [OP_LIST_MAX",
        "solution_abst_en": "72 [OP_LIST_GET_DIVISOR] 120 [OP_LIST_GET_DIVISOR] [OP_SET_INTERSECT] 4 [OP_LIST_MAX",
        "solution_code_ko": "var_a = 72\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 120\nlist_b = []\nnum_sqrt = int(math.sqrt(var_b))\nfor i in range(1, num_sqrt+1):\n    if var_b % i == 0:\n        list_b.append(i)\n        list_b.append(int(var_b/i))\nlist_b = sorted(set(list_b))\nlist_c = list(set(list_a) & set(list_b))\nvar_c = 4\nvar_d = '[OP_LIST_MAX'\nprint(var_d)",
        "solution_code_en": "var_a = 72\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 120\nlist_b = []\nnum_sqrt = int(math.sqrt(var_b))\nfor i in range(1, num_sqrt+1):\n    if var_b % i == 0:\n        list_b.append(i)\n        list_b.append(int(var_b/i))\nlist_b = sorted(set(list_b))\nlist_c = list(set(list_a) & set(list_b))\nvar_c = 4\nvar_d = '[OP_LIST_MAX'\nprint(var_d)"
    },
    "997": {
        "category": "Comparison",
        "question_ko": "학생들이 한 줄로 서 있습니다. 유정이는 맨 앞에 서 있고, 은지는 맨 뒤에 서 있습니다. 유정이와 은지 사이에는 14명이 서 있습니다. 줄을 서 있는 학생은 모두 몇 명입니까?",
        "question_en": "Students are standing in a line. Yoojung is standing at the head, and Eunji is standing at the tail end. 14 people are standing between Yoojung and Eunji. How many students are in line?",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "1 14 [OP_ADD] 1 [OP_ADD]",
        "solution_abst_en": "1 14 [OP_ADD] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 14\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 14\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "998": {
        "category": "Arithmetic calculation",
        "question_ko": "은지가 가지고 있던 공책 중 언니에게 8권을 남은 것의 반을 동생에게 주었더니 5권이 남았습니다. 처음에 은지가 가지고 있던 공책의 수는 몇 권입니까?",
        "question_en": "Among the notebooks Eunji had, she gave half of the remaining 8 to her younger sister, and there were 5 left. How many notebooks did Eunji have at first?",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "5 2 [OP_MUL] 8 [OP_ADD]",
        "solution_abst_en": "5 2 [OP_MUL] 8 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "999": {
        "category": "Geometry",
        "question_ko": "넓이가 6400제곱센티미터(㎠)인 직사각형 모양의 게시판의 세로의 길이는 160센티미터(㎝)입니다. 가로의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "A rectangular bulletin board with an area of 6400 square centimeters (cm2) is 160 centimeters (cm) long. How many centimeters (cm) is the width?",
        "answer_ko": "40",
        "answer_en": "40",
        "solution_abst_ko": "6400 160 [OP_DIV]",
        "solution_abst_en": "6400 160 [OP_DIV]",
        "solution_code_ko": "var_a = 6400\nvar_b = 160\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6400\nvar_b = 160\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "1000": {
        "category": "Correspondence",
        "question_ko": "서현이는 가지고 있던 구슬의 절반을 지훈이와의 게임에서 뺐겼고, 나머지의 1/3은 잃어버려서 12개가 남았습니다. 서현이가 처음에 가지고 있던 구슬은 몇 개인가요?",
        "question_en": "Jihoon took half of the marbles that Seohyun had in the game, and Seohyun lost 1/3 of the marbles, leaving her 12 marbles. How many marbles did Seohyun have at first?",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "12 1 1/3 [OP_SUB] [OP_DIV] 1 1/2 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "12 1 1/3 [OP_SUB] [OP_DIV] 1 1/2 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 1\nvar_c = 0.3333333333333333\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 1\nvar_g = 0.5\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))",
        "solution_code_en": "var_a = 12\nvar_b = 1\nvar_c = 0.3333333333333333\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 1\nvar_g = 0.5\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))"
    },
    "1001": {
        "category": "Arithmetic calculation",
        "question_ko": "10부터 99까지 수를 공책에 적을 때, 숫자 8은 모두 몇 번 쓰는지 구하시오.",
        "question_en": "When you write the numbers from 10 to 99 in your notebook, how many times do you write the number 8?",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "10 99 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 8 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "10 99 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 8 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 8\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))",
        "solution_code_en": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 8\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))"
    },
    "1002": {
        "category": "Comparison",
        "question_ko": "키가 작은 사람부터 순서대로 9명이 한 줄로 서 있습니다. 호석이는 가장 키가 작고, 유나와 호석이 사이에는 4명이 서 있습니다. 키가 큰 사람부터 순서대로 다시 줄을 서면 유나는 앞에서부터 몇 번째에 서게 됩니까?",
        "question_en": "Nine people stand in a line in order from shortest to tallest. Hoseok is the shortest, and there are 4 people standing between Yuna and Hoseok. If they line up again in order from tallest to shortest, what number will Yuna stand from the front?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "9 1 [OP_SUB] 4 [OP_SUB] 1 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "9 1 [OP_SUB] 4 [OP_SUB] 1 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 9\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = 1\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 9\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = 1\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "1003": {
        "category": "Comparison",
        "question_ko": "서울의 한 초등학교에 다니는 3학년과 4학년 학생은 총 531명 입니다. 4학년은 3학년보다 31명 더 많고, 3학년 여학생은 3학년 남학생보다 22명 적습니다. 이 학교에 다니는 남학생 중, 3학년은 몇 명인지 구하시오.",
        "question_en": "There are a total of 531 third and fourth graders attending an elementary school in Seoul. There are 31 more 4th graders than 3rd graders, and 22 fewer 3rd grade girls than 3rd grade boys. Among the boys attending this school, find how many are in the third grade.",
        "answer_ko": "136",
        "answer_en": "136",
        "solution_abst_ko": "531 31 [OP_SUB] 2 [OP_DIV] 22 [OP_SUB] 2 [OP_DIV] 22 [OP_ADD]",
        "solution_abst_en": "531 31 [OP_SUB] 2 [OP_DIV] 22 [OP_SUB] 2 [OP_DIV] 22 [OP_ADD]",
        "solution_code_ko": "var_a = 531\nvar_b = 31\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 22\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nvar_j = 22\nvar_k = var_i + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 531\nvar_b = 31\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 22\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nvar_j = 22\nvar_k = var_i + var_j\nprint(int(var_k))"
    },
    "1004": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 11.5미터(m) 인 직선 거리 위에 6 개의 깃대를 일정한 간격으로 꽂으려고 합니다. 깃대와 깃대 사이의 거리는 몇 미터(m)로 해야 합니까?",
        "question_en": "You want to place 6 flagpoles at regular intervals on a straight line that is 11.5 meters (m) long. How many meters (m) should be the distance between flagpoles?",
        "answer_ko": "2.30",
        "answer_en": "2.3",
        "solution_abst_ko": "11.5 6 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "11.5 6 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 11.5\nvar_b = 6\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 11.5\nvar_b = 6\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "1005": {
        "category": "Correspondence",
        "question_ko": "어떤 세 자리 수가 있는데 각 자리 수들의 합은 9이고, 이 세 자리 수는 5로 나누어떨어집니다. 이러한 세 자리 수는 모두 몇 개 있습니까?",
        "question_en": "There is a three-digit number whose sum of each digit is 9 and is divisible by 5. How many of these three-digit numbers are there?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "100 1000 1 [OP_SUB] 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] [OP_LIST_NUM2SUM] 9 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "100 1000 1 [OP_SUB] 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] [OP_LIST_NUM2SUM] 9 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 100\nvar_b = 1000\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nvar_f = 5\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nlist_c=[]\nfor i in list_b:\n    var_g = 0\n    i = int(i)\n    while i//10 > 0:\n        var_g = var_g + i%10\n        i = i//10\n    var_g = var_g + i%10\n    list_c.append(var_g)\nvar_h = 9\nvar_i = 0\nvar_h = int(var_h)\nfor i in list_c:\n    i = int(i)\n    if i == var_h:\n        var_i = var_i + 1\nprint(int(var_i))",
        "solution_code_en": "var_a = 100\nvar_b = 1000\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nvar_f = 5\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nlist_c=[]\nfor i in list_b:\n    var_g = 0\n    i = int(i)\n    while i//10 > 0:\n        var_g = var_g + i%10\n        i = i//10\n    var_g = var_g + i%10\n    list_c.append(var_g)\nvar_h = 9\nvar_i = 0\nvar_h = int(var_h)\nfor i in list_c:\n    i = int(i)\n    if i == var_h:\n        var_i = var_i + 1\nprint(int(var_i))"
    },
    "1006": {
        "category": "Possibility",
        "question_ko": "0, 4, 5, 7의 숫자가 각각 적힌 4장의 카드 중에서 3장을 뽑아 만들 수 있는 세 자리 정수의 개수는?",
        "question_en": "How many three-digit integers can be made by drawing 3 out of 4 cards with the numbers 0, 4, 5, and 7 written on them?",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "4 3 [OP_PERM] 3 3 [OP_PERM] [OP_SUB]",
        "solution_abst_en": "4 3 [OP_PERM] 3 3 [OP_PERM] [OP_SUB]",
        "solution_code_ko": "var_a = 4\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nvar_d = 3\nvar_e = 3\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nvar_d = 3\nvar_e = 3\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "1007": {
        "category": "Correspondence",
        "question_ko": "자연수 A를 자연수 B로 나누면 몫이 28이고 나머지가 4입니다. A가 될 수 있는 숫자중에 가장 작은 A를 구하시오.",
        "question_en": "When a natural number A is divided by a natural number B, the quotient is 28 and the remainder is 4. Find the smallest A among all possible numbers that can be A.",
        "answer_ko": "144",
        "answer_en": "144",
        "solution_abst_ko": "5 28 [OP_MUL] 4 [OP_ADD]",
        "solution_abst_en": "5 28 [OP_MUL] 4 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 28\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 28\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "1008": {
        "category": "Correspondence",
        "question_ko": "어떤 수는 50보다 크고 70보다 작습니다. 또한 이 수는 5로 나누었을 때 나머지가 3이고 7로 나누었을 때 나머지가 2입니다. 이 수는 무엇입니까?",
        "question_en": "There is a number that is greater than 50 and less than 70. This number has a remainder of 3 when divided by 5 and a remainder of 2 when divided by 7. What is this number?",
        "answer_ko": "58",
        "answer_en": "58",
        "solution_abst_ko": "50 70 1 [OP_SUB] 1 [OP_LIST_ARANGE] 5 3 [OP_LIST_DIVIDE_AND_REMAIN] 7 2 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "50 70 1 [OP_SUB] 1 [OP_LIST_ARANGE] 5 3 [OP_LIST_DIVIDE_AND_REMAIN] 7 2 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 50\nvar_b = 70\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nvar_f = 5\nvar_g = 3\nlist_b = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_a:\n    i = int(i)\n    if i%var_f == var_g:\n        list_b.append(i)\nvar_h = 7\nvar_i = 2\nlist_c = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_b:\n    i = int(i)\n    if i%var_h == var_i:\n        list_c.append(i)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(int(var_k))",
        "solution_code_en": "var_a = 50\nvar_b = 70\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nvar_f = 5\nvar_g = 3\nlist_b = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_a:\n    i = int(i)\n    if i%var_f == var_g:\n        list_b.append(i)\nvar_h = 7\nvar_i = 2\nlist_c = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_b:\n    i = int(i)\n    if i%var_h == var_i:\n        list_c.append(i)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(int(var_k))"
    },
    "1009": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 개구리는 7/12센티미터(㎝)를 뛰는 데 5/18분이 걸립니다. 이 개구리가 같은 빠르기로 뛴다면 7분 동안 갈 수 있는 거리는 몇 센티미터(㎝)인가요?",
        "question_en": "A frog takes 5/18 minutes to jump 7/12 centimeters (cm). How many centimeters (cm) can this frog travel in 7 minutes if it runs at the same speed?",
        "answer_ko": "14.70",
        "answer_en": "14.7",
        "solution_abst_ko": "7/12 5/18 [OP_DIV] 7 [OP_MUL]",
        "solution_abst_en": "7/12 5/18 [OP_DIV] 7 [OP_MUL]",
        "solution_code_ko": "var_a = 0.5833333333333334\nvar_b = 0.2777777777777778\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.5833333333333334\nvar_b = 0.2777777777777778\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "1010": {
        "category": "Possibility",
        "question_ko": "5명의 서로 다른 면접자가 있다. 이 때, 이 중 2명을 합격시켜주는 경우의 수를 구하시오.",
        "question_en": "There are 5 different interviewers. Find the number of cases in which two of them pass.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "5 2 [OP_COMB]",
        "solution_abst_en": "5 2 [OP_COMB]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))"
    },
    "1011": {
        "category": "Comparison",
        "question_ko": "1.4, 9/10, 1.2, 0.5, 13/10 5개 숫자 중에서 1.1보다 크거나 같은 숫자를 골라 작거나 같은 순서대로 나열했을 때, 가장 앞에 있는 숫자는 무엇입니까?",
        "question_en": "Among the five numbers 1.4, 9/10, 1.2, 0.5, 13/10, which number is at the very front, when numbers greater than or equal to 1.1 are picked up to be lined up in order from the smallest?",
        "answer_ko": "1.20",
        "answer_en": "1.2",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE_EQUAL] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE_EQUAL] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i >= var_f:\n        list_b.append(i)\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nprint('{:.2f}'.format(round(var_h+1e-10,2)))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i >= var_f:\n        list_b.append(i)\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nprint('{:.2f}'.format(round(var_h+1e-10,2)))"
    },
    "1012": {
        "category": "Comparison",
        "question_ko": "태형이는 동화책을 어제는 32쪽 읽었고, 오늘은 어제보다 13쪽 더 적게 읽었습니다. 남준이는 동화책을 어제는 25쪽 읽었고, 오늘은 어제보다 14쪽 더 많이 읽었습니다. 어제와 오늘 합해서 동화책을 더 많이 읽은 사람은 누구입니까?",
        "question_en": "Taehyung read 32 pages of fairy tales yesterday, and today he read 13 fewer pages than yesterday. Namjoon read 25 pages of fairy tales yesterday, and today he read 14 more pages than yesterday. Who read more fairy tales yesterday and today combined?",
        "answer_ko": "남준",
        "answer_en": "Namjoon",
        "solution_abst_ko": "[OP_LIST_SOL] 태형 남준 [OP_LIST_EOL] [OP_LIST_SOL] 32 13 [OP_SUB] 32 [OP_ADD] 25 14 [OP_ADD] 25 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Taehyung Namjoon [OP_LIST_EOL] [OP_LIST_SOL] 32 13 [OP_SUB] 32 [OP_ADD] 25 14 [OP_ADD] 25 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '태형'\nvar_b = '남준'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 32\nvar_d = 13\nvar_e = var_c - var_d\nvar_f = 32\nvar_g = var_e + var_f\nvar_h = 25\nvar_i = 14\nvar_j = var_h + var_i\nvar_k = 25\nvar_l = var_j + var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'Taehyung'\nvar_b = 'Namjoon'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 32\nvar_d = 13\nvar_e = var_c - var_d\nvar_f = 32\nvar_g = var_e + var_f\nvar_h = 25\nvar_i = 14\nvar_j = var_h + var_i\nvar_k = 25\nvar_l = var_j + var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "1013": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 3킬로미터(㎞)인 운동장을 재웅이와 동훈이가 킥보드를 타고 같은 곳에서 서로 반대 방향으로 동시에 출발하였다. 재웅이는 매분 100미터(m)의 속력으로, 동훈이는 매분 150미터(m)의 속력으로 킥보드를 탄다면 몇 분 후에 처음으로 다시 만나는지 구하여라",
        "question_en": "Jae-woong and Dong-hun started at the same place in opposite directions on a kickboard on a 3-kilometer (km)-long playground. If Jaewoong rides a kickboard at a speed of 100 meters (m) per minute and Donghun rides a kickboard at a speed of 150 meters (m) per minute, find out how many minutes later they will meet again for the first time.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "3 100 1000 [OP_DIV] 150 1000 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_abst_en": "3 100 1000 [OP_DIV] 150 1000 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 3\nvar_b = 100\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = 150\nvar_f = 1000\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = var_a / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 3\nvar_b = 100\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = 150\nvar_f = 1000\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = var_a / var_h\nprint(int(var_i))"
    },
    "1014": {
        "category": "Possibility",
        "question_ko": "A지점에서 B지점까지 가는 방법의 수가 3가지이고, B지점에서 C지점까지 가는 방법의 수가 4가지일 때, A지점에서 B지점을 거쳐 C지점으로 가는 방법의 수를 구하시오.",
        "question_en": "If the number of ways to get from point A to point B is 3 and from point B to point C is 4, find how many possible ways are there to get from point A to point C via point B.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "3 4 [OP_MUL]",
        "solution_abst_en": "3 4 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "1015": {
        "category": "Geometry",
        "question_ko": "정사각형 모양의 타일을 빈틈없이 늘어놓아 큰 정사각형을 만들고 보니 36장이 남았습니다. 가로 한 변과 세로 한 변을 1열씩 늘렸더니 아직도 3장의 타일이 남았습니다. 타일은 모두 몇 장입니까?",
        "question_en": "When square-shaped tiles were laid in order to form a large square, 36 tiles were not used. I increased the width and length of the large square by one line each, and there were still 3 residual tiles left. How many tiles did I have?",
        "answer_ko": "292",
        "answer_en": "292",
        "solution_abst_ko": "36 3 [OP_SUB] 1 [OP_SUB] 2 [OP_DIV] 2 [OP_POW] 36 [OP_ADD]",
        "solution_abst_en": "36 3 [OP_SUB] 1 [OP_SUB] 2 [OP_DIV] 2 [OP_POW] 36 [OP_ADD]",
        "solution_code_ko": "var_a = 36\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 36\nvar_k = var_i + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 36\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 36\nvar_k = var_i + var_j\nprint(int(var_k))"
    },
    "1016": {
        "category": "Possibility",
        "question_ko": "0, 2, 4, 6에 한 번만 사용하여 세 자리 숫자를 만들려고 합니다. 가능한 가장 큰 수와 가장 작은 수의 곱을 찾으십시오.",
        "question_en": "You want to create a three-digit number using each 0, 2, 4, and 6 only once. Find the product of the largest possible number and the smallest possible number.",
        "answer_ko": "130968",
        "answer_en": "130968",
        "solution_abst_ko": "[OP_LIST_SOL] 0 2 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 0 2 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MUL]",
        "solution_code_ko": "var_a = 0\nvar_b = 2\nvar_c = 4\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g * var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 0\nvar_b = 2\nvar_c = 4\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g * var_i\nprint(int(var_j))"
    },
    "1017": {
        "category": "Geometry",
        "question_ko": "삼각형을 이등분 했을 때의 넓이가 제곱센티미터(㎠)라면, 이등분 하기 전의 넓이는 얼마입니까?",
        "question_en": "If the area of a triangle when halved is in 7 square centimeters (cm2), what is the area before halving?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "7 2 [OP_MUL]",
        "solution_abst_en": "7 2 [OP_MUL]",
        "solution_code_ko": "var_a = 7\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 7\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "1018": {
        "category": "Comparison",
        "question_ko": "각 열마다 심어져 있는 꽃의 수는 같습니다. 장미는 왼쪽에서 9번째 열, 앞에서 7번째 줄, 뒤에서 16번째 줄, 오른쪽에서 13번째 열에 심어져 있을때 심어져 있는 꽃은 모두 몇 송이입니까?",
        "question_en": "The number of flowers planted in each column is the same. When a rose is planted in the 9th column from the left, the 7th row from the front, the 16th row from the back, and the 13th column from the right, how many flowers are planted?",
        "answer_ko": "462",
        "answer_en": "462",
        "solution_abst_ko": "7 16 [OP_ADD] 1 [OP_SUB] 9 13 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "7 16 [OP_ADD] 1 [OP_SUB] 9 13 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 7\nvar_b = 16\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 9\nvar_g = 13\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 7\nvar_b = 16\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 9\nvar_g = 13\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))"
    },
    "1019": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 3번째로 작은 수와 2번째로 작은 수의 곱은 얼마입니까?",
        "question_en": "There are five numbers 10, 11, 12, 13, and 14. What is the product of the 3rd smallest number and the 2nd smallest number?",
        "answer_ko": "132",
        "answer_en": "132",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 3 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 3 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g * var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g * var_i\nprint(int(var_j))"
    },
    "1020": {
        "category": "Arithmetic calculation",
        "question_ko": "우준이의 나이는 엄마의 나이의 1/4보다 1살이 적고 엄마의 나이는 우준이의 나이의 5배보다 5살이 적을 때, 우준이는 현재 몇 살입니까?",
        "question_en": "When Woo-jun's age is 1 year less than 1/4 of his mother's age and his mother's age is 5 years less than 5 times Woo-jun's age, how old is Woo-jun now?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "1/4 5 [OP_MUL] 1 [OP_ADD] 1/4 5 [OP_MUL] 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "1/4 5 [OP_MUL] 1 [OP_ADD] 1/4 5 [OP_MUL] 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 0.25\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 0.25\nvar_g = 5\nvar_h = var_f * var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 0.25\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 0.25\nvar_g = 5\nvar_h = var_f * var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e / var_j\nprint(int(var_k))"
    },
    "1021": {
        "category": "Correspondence",
        "question_ko": "자연수 A, B, C에 대하여, A를 8로 나누었을 때, 몫이 B이고 나머지가 C가 됩니다. 몫과 나머지가 같은 경우, 나누어지는 수 A 중 가장 큰 수를 구하시오.",
        "question_en": "For the natural numbers A, B, and C, when A is divided by 8, the quotient is B and the remainder is C. If the quotient and the remainder are equal, find the largest number of A.",
        "answer_ko": "63",
        "answer_en": "63",
        "solution_abst_ko": "8 8 1 [OP_SUB] [OP_MUL] 8 1 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "8 8 1 [OP_SUB] [OP_MUL] 8 1 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 8\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 8\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 8\nvar_b = 8\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 8\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e + var_h\nprint(int(var_i))"
    },
    "1022": {
        "category": "Arithmetic calculation",
        "question_ko": "(나) 테이프를 반으로 접은 길이와 같은 (가) 테이프의 길이는 35센티미터(㎝)입니다. (다) 테이프의 길이는 (가) 테이프보다 2배하고도 21센터미터(cm)만큼 더 길다면, (나) 테이프와 (다) 테이프의 길이 합은 몇 센티미터(㎝)입니까?",
        "question_en": "The length of tape A which is equal to the length of the tape B folded in half is 35 centimeters (cm). The length of tape C is 21 centimeters (cm) longer than twice the length of tape A, how many centimeters (cm) is the sum of the lengths of tape B and tape C?",
        "answer_ko": "119",
        "answer_en": "119",
        "solution_abst_ko": "35 2 [OP_MUL] 35 2 [OP_MUL] 21 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "35 2 [OP_MUL] 35 2 [OP_MUL] 21 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 35\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 35\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = 21\nvar_h = var_f - var_g\nvar_i = var_c + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 35\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 35\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = 21\nvar_h = var_f - var_g\nvar_i = var_c + var_h\nprint(int(var_i))"
    },
    "1023": {
        "category": "Geometry",
        "question_ko": "사면체의 면의 개수는?",
        "question_en": "How many faces does a tetrahedron have?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "4",
        "solution_abst_en": "4",
        "solution_code_ko": "var_a = 4\nprint(int(var_a))",
        "solution_code_en": "var_a = 4\nprint(int(var_a))"
    },
    "1024": {
        "category": "Geometry",
        "question_ko": "수지는 정육각형 모양의 색종이를 가지고 있습니다. 이 정육각형의 한 변의 길이는 5센티미터(㎝)입니다. 이 색종이의 둘레를 구하시오.",
        "question_en": "Suzy has a regular hexagon shaped piece of colored paper. The length of one side of this regular hexagon is 5 centimeters (cm). Find the circumference of this colored paper.",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "5 6 [OP_MUL]",
        "solution_abst_en": "5 6 [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 6\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 6\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "1025": {
        "category": "Geometry",
        "question_ko": "가로가 44미터(m), 세로가 35미터(m)인 직사각형 모양의 땅에 가로, 세로, 높이가 모두 1미터(m)인 박스를 보관한다. 첫 날 박스를 7층 쌓았고 둘째날 박스를 3층 쌓았다면 이틀동안 들어온 박스의 양은 몇 개인지 구하시오.",
        "question_en": "A box measuring 1 meter (m) in width, length, and height is stored on a rectangular piece of land measuring 44 meters (m) wide and 35 meters (m) long. If you stacked boxes in 7 layers on the first day and boxes in 3 layers on the second day, how many boxes did you get in two days?",
        "answer_ko": "15400",
        "answer_en": "15400",
        "solution_abst_ko": "44 35 [OP_MUL] 7 3 [OP_ADD] [OP_MUL]",
        "solution_abst_en": "44 35 [OP_MUL] 7 3 [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 44\nvar_b = 35\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 44\nvar_b = 35\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "1026": {
        "category": "Geometry",
        "question_ko": "어떤 정사각형 모양의 칠판의 한 변의 길이를 재었더니 6센티미터(㎝)였습니다. 이 칠판의 넓이는 몇 제곱센티미터(㎠)입니까?",
        "question_en": "When I measured the length of one side of a square-shaped blackboard, it was 6 centimeters (cm). What is the area of this blackboard in square centimeters (cm2)?",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "6 2 [OP_POW]",
        "solution_abst_en": "6 2 [OP_POW]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = var_a ** var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = var_a ** var_b\nprint(int(var_c))"
    },
    "1027": {
        "category": "Comparison",
        "question_ko": "200과 어떤 자연수 사이에는 연속된 자연수가 60개 있습니다. 어떤 수는 200보다 작을 때 200과 어떤 수 사이에 있는 수 중 2와 3으로 나누어떨어지는 수는 모두 몇 개입니까?",
        "question_en": "There are 60 consecutive natural numbers between 200 and this number. If the number is less than 200, how many numbers between 200 and the number are divisible by 2 and 3?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "200 1 [OP_ADD] 60 [OP_SUB] 200 1 [OP_SUB] 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "200 1 [OP_ADD] 60 [OP_SUB] 200 1 [OP_SUB] 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 200\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 60\nvar_e = var_c - var_d\nvar_f = 200\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = 1\nlist_a = [i for i in range(var_e, var_h + 1, var_i)]\nvar_j = 2\nlist_b = []\nvar_j = int(var_j)\nfor i in list_a:\n    i = int(i)\n    if i % var_j == 0:\n        list_b.append(i)\nvar_k = 3\nlist_c = []\nvar_k = int(var_k)\nfor i in list_b:\n    i = int(i)\n    if i % var_k == 0:\n        list_c.append(i)\nvar_l = len(list_c)\nprint(int(var_l))",
        "solution_code_en": "var_a = 200\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 60\nvar_e = var_c - var_d\nvar_f = 200\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = 1\nlist_a = [i for i in range(var_e, var_h + 1, var_i)]\nvar_j = 2\nlist_b = []\nvar_j = int(var_j)\nfor i in list_a:\n    i = int(i)\n    if i % var_j == 0:\n        list_b.append(i)\nvar_k = 3\nlist_c = []\nvar_k = int(var_k)\nfor i in list_b:\n    i = int(i)\n    if i % var_k == 0:\n        list_c.append(i)\nvar_l = len(list_c)\nprint(int(var_l))"
    },
    "1028": {
        "category": "Arithmetic calculation",
        "question_ko": "23.3센티미터(㎝)의 철사에서 105밀리미터(㎜)를 잘라쓰고, 다음 날 4.6센티미터(㎝)를 또 썼을 때 남은 철사의 길이는 몇 밀리미터(㎜)인가요?",
        "question_en": "If you cut and used 105 millimeters (mm) from a 23.3 centimeter (cm) wire and another 4.6 centimeters (cm) the next day, how many millimeters (mm) of wire are left?",
        "answer_ko": "82",
        "answer_en": "82",
        "solution_abst_ko": "23.3 10 [OP_MUL] 105 [OP_SUB] 4.6 10 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "23.3 10 [OP_MUL] 105 [OP_SUB] 4.6 10 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 23.3\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 105\nvar_e = var_c - var_d\nvar_f = 4.6\nvar_g = 10\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 23.3\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 105\nvar_e = var_c - var_d\nvar_f = 4.6\nvar_g = 10\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nprint(int(var_i))"
    },
    "1029": {
        "category": "Geometry",
        "question_ko": "한 모서리의 길이가 7센티미터(㎝)인 정육면체의 부피는 몇 세제곱센티미터입니까?",
        "question_en": "What is the volume, in cubic centimeters (cm3), of a cube with an edge of 7 centimeters (cm)?",
        "answer_ko": "343",
        "answer_en": "343",
        "solution_abst_ko": "7 3 [OP_POW]",
        "solution_abst_en": "7 3 [OP_POW]",
        "solution_code_ko": "var_a = 7\nvar_b = 3\nvar_c = var_a ** var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 7\nvar_b = 3\nvar_c = var_a ** var_b\nprint(int(var_c))"
    },
    "1030": {
        "category": "Geometry",
        "question_ko": "각뿔의 밑면은 N개입니다. N은?",
        "question_en": "A pyramid has N bases. How much is N?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "1",
        "solution_abst_en": "1",
        "solution_code_ko": "var_a = 1\nprint(int(var_a))",
        "solution_code_en": "var_a = 1\nprint(int(var_a))"
    },
    "1031": {
        "category": "Geometry",
        "question_ko": "윗변이 아랫변보다 3.4센티미터(㎝) 더 길고, 높이가 5.2센티미터(㎝)인 사다리꼴의 넓이가 100.62제곱센티미터(㎠)입니다. 아랫변의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "The area of a trapezoid with an upper side that is 3.4 centimeters (cm) longer than the lower side and with a height of 5.2 centimeters (cm) is 100.62 square centimeters (cm2). How many centimeters (cm) is the length of the lower side?",
        "answer_ko": "17.65",
        "answer_en": "17.65",
        "solution_abst_ko": "100.62 2 [OP_MUL] 5.2 [OP_DIV] 3.4 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "100.62 2 [OP_MUL] 5.2 [OP_DIV] 3.4 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 100.62\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 5.2\nvar_e = var_c / var_d\nvar_f = 3.4\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 100.62\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 5.2\nvar_e = var_c / var_d\nvar_f = 3.4\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "1032": {
        "category": "Geometry",
        "question_ko": "가로 30 센티미터(㎝) , 세로 20 센티미터(㎝) , 높이 5센티미터(㎝) 인 직육면체 모양의 상자가 있습니다. 이 상자에 가로 6센티미터(㎝), 세로 4센티미터(㎝), 높이 1센티미터(㎝) 인 직육면체 모양의 초콜릿이 빈틈없이 들어 있다면 상자에 들어 있는 초콜릿은 모두 몇 개 입니까?",
        "question_en": "There is a box in the shape of a cuboid measuring 30 centimeters (cm) wide, 20 centimeters (cm) long, and 5 centimeters (cm) high. If this box contains all the chocolates in the shape of a cuboid measuring 6 centimeters (cm) wide, 4 centimeters (cm) long, and 1 cm (cm high) without leaving any space, how many chocolates are in the box?",
        "answer_ko": "125",
        "answer_en": "125",
        "solution_abst_ko": "30 20 [OP_MUL] 5 [OP_MUL] 6 4 [OP_MUL] 1 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "30 20 [OP_MUL] 5 [OP_MUL] 6 4 [OP_MUL] 1 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 30\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c * var_d\nvar_f = 6\nvar_g = 4\nvar_h = var_f * var_g\nvar_i = 1\nvar_j = var_h * var_i\nvar_k = var_e / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 30\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c * var_d\nvar_f = 6\nvar_g = 4\nvar_h = var_f * var_g\nvar_i = 1\nvar_j = var_h * var_i\nvar_k = var_e / var_j\nprint(int(var_k))"
    },
    "1033": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 9로 나누고, 7로 나누면 13이 됩니다. 어떤 수를 구하시오.",
        "question_en": "A number divided by 9 and by 7 is 13. Find this number.",
        "answer_ko": "819",
        "answer_en": "819",
        "solution_abst_ko": "13 7 [OP_MUL] 9 [OP_MUL]",
        "solution_abst_en": "13 7 [OP_MUL] 9 [OP_MUL]",
        "solution_code_ko": "var_a = 13\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 13\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "1034": {
        "category": "Arithmetic calculation",
        "question_ko": "선물 상자에 한 개에 0.36킬로그램(㎏)인 귤을 30개 넣었습니다. 이때 선물 상자의 무게는 11.26킬로그램(㎏)이었습니다. 그렇다면 빈 선물 상자의 무게는 몇 킬로그램(㎏)일까요?",
        "question_en": "I put 30 tangerines, each weighing 0.36 kilograms (kg), in a gift box. At this moment, the weight of the gift box was 11.26 kilograms (kg). How many kilograms (kg) does an empty gift box weigh?",
        "answer_ko": "0.46",
        "answer_en": "0.46",
        "solution_abst_ko": "11.26 0.36 30 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "11.26 0.36 30 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 11.26\nvar_b = 0.36\nvar_c = 30\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 11.26\nvar_b = 0.36\nvar_c = 30\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "1035": {
        "category": "Geometry",
        "question_ko": "미정이가 가진 직육면체 상자는 한 밑면의 넓이가 14제곱센티미터(㎠)이고 높이가 13센티미터(㎝)라고 합니다. 이 상자의 부피를 구하시오.",
        "question_en": "Mijeong's cuboid box has a bottom area of 14 square centimeters (cm2) and a height of 13 centimeters (cm). Find the volume of this box.",
        "answer_ko": "182",
        "answer_en": "182",
        "solution_abst_ko": "14 13 [OP_MUL]",
        "solution_abst_en": "14 13 [OP_MUL]",
        "solution_code_ko": "var_a = 14\nvar_b = 13\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 14\nvar_b = 13\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "1036": {
        "category": "Correspondence",
        "question_ko": "윤기는 두 자리 수에 57을 빼던 중, 윤기는 두 자리 수의 일의 자리 숫자 9를 6으로 잘못 보았습니다. 윤기가 구한 차가 39 일 때, 두 자리 수는 무엇일까요?",
        "question_en": "While Yoongi was subtracting 57 from the two-digit number, he mistook the two-digit units digit 9 for 6. When the difference obtained by Yoongi is 39, what is the two-digit number?",
        "answer_ko": "99",
        "answer_en": "99",
        "solution_abst_ko": "39 57 [OP_ADD] 6 9 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "39 57 [OP_ADD] 6 9 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 39\nvar_b = 57\nvar_c = var_a + var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 39\nvar_b = 57\nvar_c = var_a + var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "1037": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 9까지의 홀수 중 2번째로 큰 수는?",
        "question_en": "What is the second largest odd number from 1 to 9?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "1 9 [OP_LIST_ODD] 2 [OP_LIST_MAX]",
        "solution_abst_en": "1 9 [OP_LIST_ODD] 2 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[-var_c]\nprint(int(var_d))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[-var_c]\nprint(int(var_d))"
    },
    "1038": {
        "category": "Arithmetic calculation",
        "question_ko": "연주네 분단 11명의 키의 평균은 145.7센티미터(㎝)이다. 그런데 2명의 키가 똑같이 142.1센티미터(㎝)라고 할 때, 나머지 학생의 키의 평균을 구하여라.",
        "question_en": "The average height of 11 members of the Yeonju's line is 145.7 centimeters (cm). However, if the heights of the two students are equal to 142.1 centimeters (cm), find the average of the heights of the other students.",
        "answer_ko": "146.50",
        "answer_en": "146.5",
        "solution_abst_ko": "145.7 11 [OP_MUL] 142.1 2 [OP_MUL] [OP_SUB] 11 2 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "145.7 11 [OP_MUL] 142.1 2 [OP_MUL] [OP_SUB] 11 2 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 145.7\nvar_b = 11\nvar_c = var_a * var_b\nvar_d = 142.1\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 11\nvar_i = 2\nvar_j = var_h - var_i\nvar_k = var_g / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 145.7\nvar_b = 11\nvar_c = var_a * var_b\nvar_d = 142.1\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 11\nvar_i = 2\nvar_j = var_h - var_i\nvar_k = var_g / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "1039": {
        "category": "Arithmetic calculation",
        "question_ko": "색종이를 지민이는 41장 가지고 있고, 석진이는 지민이보다 1장 더 적게 가지고 있습니다. 석진이가 가지고 있는 색종이는 몇 장입니까?",
        "question_en": "Jimin has 41 pieces of colored paper, and Seokjin has 1 less than Jimin. How many pieces of colored paper does Seokjin have?",
        "answer_ko": "40",
        "answer_en": "40",
        "solution_abst_ko": "41 1 [OP_SUB]",
        "solution_abst_en": "41 1 [OP_SUB]",
        "solution_code_ko": "var_a = 41\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 41\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "1040": {
        "category": "Possibility",
        "question_ko": "빨간 공 1개, 노란 공 1개, 파란 공 2개가 있습니다. 같은 색의 공은 각각 구별이 되지 않는다고 할 때, 이 공들을 서로 다르게 일렬로 늘어놓는 방법은 모두 몇 가지입니까?",
        "question_en": "There are 1 red ball, 1 yellow ball, and 2 blue balls. Given that balls of the same color are indistinguishable from each other, how many different ways can you arrange them differently?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "1 1 [OP_ADD] 2 [OP_ADD] 1 1 [OP_ADD] 2 [OP_ADD] [OP_PERM] 2 2 [OP_PERM] [OP_DIV]",
        "solution_abst_en": "1 1 [OP_ADD] 2 [OP_ADD] 1 1 [OP_ADD] 2 [OP_ADD] [OP_PERM] 2 2 [OP_PERM] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c + var_d\nvar_f = 1\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = 2\nvar_j = var_h + var_i\nvar_k = 1\nvar_e = int(var_e)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_e-i)\nvar_l = 2\nvar_m = 2\nvar_n = 1\nvar_l = int(var_l)\nvar_m = int(var_m)\nfor i, elem in enumerate(range(var_m)):\n    var_n = var_n * (var_l-i)\nvar_o = var_k / var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 1\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c + var_d\nvar_f = 1\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = 2\nvar_j = var_h + var_i\nvar_k = 1\nvar_e = int(var_e)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_e-i)\nvar_l = 2\nvar_m = 2\nvar_n = 1\nvar_l = int(var_l)\nvar_m = int(var_m)\nfor i, elem in enumerate(range(var_m)):\n    var_n = var_n * (var_l-i)\nvar_o = var_k / var_n\nprint(int(var_o))"
    },
    "1041": {
        "category": "Correspondence",
        "question_ko": "어떤 수 A를 8로 나누었을 때, 몫과 나머지는 각각 B와 C가 됩니다. A, B, C는 자연수 입니다. 몫과 나머지가 같은 경우, 나누어지는 수 A 중 가장 큰 수를 구하시오.",
        "question_en": "When a number A is divided by 8, the quotient and remainder are B and C, respectively. A, B, and C are natural numbers. If the quotient and the remainder are equal, find the largest number of A.",
        "answer_ko": "63",
        "answer_en": "63",
        "solution_abst_ko": "8 8 1 [OP_SUB] [OP_MUL] 8 1 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "8 8 1 [OP_SUB] [OP_MUL] 8 1 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 8\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 8\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 8\nvar_b = 8\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 8\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e + var_h\nprint(int(var_i))"
    },
    "1042": {
        "category": "Arithmetic calculation",
        "question_ko": "(가), (나), (다) 3개의 테이프가 있습니다. (가) 테이프의 길이가 35센티미터(㎝)입니다. (가) 테이프의 길이는 (나) 테이프의 길이의 반이고, (다) 테이프의 길이는 (가) 테이프의 길이의 2배보다 21센티미터(㎝) 더 짧습니다. (나) 테이프와 (다) 테이프의 길이의 합은 몇 센티미터(㎝)입니까?",
        "question_en": "There are three tapes: tapes A, B, and C. The length of the tape A is 35 centimeters (cm). The length of tape A is half the length of tape B, and the length of tape C is 21 centimeters (cm) less than twice the length of tape A. What is the sum of the lengths of tape B and tape C in centimeters (cm)?",
        "answer_ko": "119",
        "answer_en": "119",
        "solution_abst_ko": "35 2 [OP_MUL] 35 2 [OP_MUL] 21 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "35 2 [OP_MUL] 35 2 [OP_MUL] 21 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 35\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 35\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = 21\nvar_h = var_f - var_g\nvar_i = var_c + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 35\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 35\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = 21\nvar_h = var_f - var_g\nvar_i = var_c + var_h\nprint(int(var_i))"
    },
    "1043": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 239.66미터(m)인 도로의 한쪽에 같은 간격으로 24개의 전봇대를 설치하려고 합니다. 도로의 처음과 끝에 각각 하나씩 설치한다면 전봇대 사이의 거리는 몇 미터(m)가 돼야 하는지 구하시오.",
        "question_en": "You want to install 24 power poles with equal space between two poles on one side of a 239.66 meters (m) long road. If you are to install one at the beginning and one at the end of the road, how long should the distance between the power poles be in meters (m)?",
        "answer_ko": "10.42",
        "answer_en": "10.42",
        "solution_abst_ko": "239.66 24 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "239.66 24 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 239.66\nvar_b = 24\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 239.66\nvar_b = 24\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "1044": {
        "category": "Geometry",
        "question_ko": "가로의 길이가 24센티미터(㎝)이고, 세로의 길이가 8센티미터(㎝)인 직사각형 안에 반지름의 길이가 4센티미터(㎝)인 원을 겹치지 않고 최대 몇 개까지 그릴 수 있습니까?",
        "question_en": "How many circles with a radius of 4 centimeters (cm) can be drawn in a rectangle with a width of 24 centimeters (cm) and a length of 8 centimeters (cm) without overlapping?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "24 4 2 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "24 4 2 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 24\nvar_b = 4\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 24\nvar_b = 4\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "1045": {
        "category": "Arithmetic calculation",
        "question_ko": "(가) 반 학생들은 8그루의 나무를 심었습니다. (나) 반 학생들은 7그루의 나무를 심었습니다. (가) 반과 (나) 반 학생들이 심은 나무는 모두 몇 그루입니까?",
        "question_en": "(A) classmates planted 8 trees. (B) classmates planted 7 trees. How many trees did the students in class (A) and (B) plant?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "8 7 [OP_ADD]",
        "solution_abst_en": "8 7 [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 8\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "1046": {
        "category": "Possibility",
        "question_ko": "동현이는 1, 6, 8이 그려진 자석을 각각 백의 자리, 십의 자리, 일의 자리에 놔둘 수 있습니다. 동현이가 만들 수 있는 수 중 두 번째로 큰 것과 세 번째로 작은 것의 차이는 얼마입니까?",
        "question_en": "Donghyun can put the magnets with 1, 6, and 8 written on them in the hundreds, tens, and ones place, respectively. What is the difference between the second largest and the third smallest number Donghyun can make?",
        "answer_ko": "198",
        "answer_en": "198",
        "solution_abst_ko": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))"
    },
    "1047": {
        "category": "Comparison",
        "question_ko": "삼각기둥, 사각기둥, 삼각뿔, 사각뿔, 사각뿔대 이렇게 다섯 종류의 도형이 있습니다. 각 도형의 면을 서로 다른 색을 이용하여 색칠한다고 할 때, 가장 적은 색이 필요한 도형은 무엇입니까?",
        "question_en": "There are five shapes: triangular-prism, quadrangular-prism, triangular-pyramid, quadrangular-pyramid, and square-frustum. If each shape's face is colored with a different color, which shape needs the fewest colors?",
        "answer_ko": "삼각뿔",
        "answer_en": "triangular-pyramid",
        "solution_abst_ko": "[OP_LIST_SOL] 삼각기둥 사각기둥 삼각뿔 사각뿔 사각뿔대 [OP_LIST_EOL] [OP_LIST_SOL] 3 2 [OP_ADD] 4 2 [OP_ADD] 3 1 [OP_ADD] 4 1 [OP_ADD] 4 2 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] triangular-prism quadrangular-prism triangular-pyramid quadrangular-pyramid square-frustum [OP_LIST_EOL] [OP_LIST_SOL] 3 2 [OP_ADD] 4 2 [OP_ADD] 3 1 [OP_ADD] 4 1 [OP_ADD] 4 2 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '삼각기둥'\nvar_b = '사각기둥'\nvar_c = '삼각뿔'\nvar_d = '사각뿔'\nvar_e = '사각뿔대'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = 4\nvar_j = 2\nvar_k = var_i + var_j\nvar_l = 3\nvar_m = 1\nvar_n = var_l + var_m\nvar_o = 4\nvar_p = 1\nvar_q = var_o + var_p\nvar_r = 4\nvar_s = 2\nvar_t = var_r + var_s\nlist_b= []\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_b.append(var_t)\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nlist_b.reverse()\nvar_u = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_v = list_c[var_u-1]\nvar_w = list_b.index(var_v)+1\nvar_x = list_a[var_w-1]\nprint(var_x)",
        "solution_code_en": "var_a = 'triangular-prism'\nvar_b = 'quadrangular-prism'\nvar_c = 'triangular-pyramid'\nvar_d = 'quadrangular-pyramid'\nvar_e = 'square-frustum'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = 4\nvar_j = 2\nvar_k = var_i + var_j\nvar_l = 3\nvar_m = 1\nvar_n = var_l + var_m\nvar_o = 4\nvar_p = 1\nvar_q = var_o + var_p\nvar_r = 4\nvar_s = 2\nvar_t = var_r + var_s\nlist_b= []\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_b.append(var_t)\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nlist_b.reverse()\nvar_u = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_v = list_c[var_u-1]\nvar_w = list_b.index(var_v)+1\nvar_x = list_a[var_w-1]\nprint(var_x)"
    },
    "1048": {
        "category": "Correspondence",
        "question_ko": "성현이가 지수가 운동장에 서있다. 성현이가 지수 방향으로 200미터(m) 달려갔다가 반대방향으로 1000미터(m)를 달려갔다. 이때 성현이와 지수 사이의 거리가 2000미터(m) 라고 할 때, 성현이가 움직이기 전의 성현이와 지수 사이의 거리는 몇 미터(m)인지 구하시오.",
        "question_en": "Seonghyeon and Jisoo are standing on the playground. Seonghyeon ran 200 meters (m) in the direction of Ji-soo and then ran 1000 meters (m) in the opposite direction. If the distance between Seonghyeon and Jisoo is now 2000 meters (m), find the distance in meters (m) between Seonghyeon and Jisoo before Seonghyeon moved.",
        "answer_ko": "1200",
        "answer_en": "1200",
        "solution_abst_ko": "2000 1000 [OP_SUB] 200 [OP_ADD]",
        "solution_abst_en": "2000 1000 [OP_SUB] 200 [OP_ADD]",
        "solution_code_ko": "var_a = 2000\nvar_b = 1000\nvar_c = var_a - var_b\nvar_d = 200\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 2000\nvar_b = 1000\nvar_c = var_a - var_b\nvar_d = 200\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "1049": {
        "category": "Possibility",
        "question_ko": "정국이는 서로 다른 과일을 구매해서 지민과 윤기에게 선물하려고 합니다. 과일 가게에서 판매하는 과일이 사과, 복숭아, 배, 참외, 딸기라면 선물할 수 있는 경우의 수는 모두 몇 가지입니까?",
        "question_en": "Jungkook wants to buy different fruits and present them to Jimin and Yoongi. If the fruits sold at the fruit shop are apples, peaches, pears, melons, and strawberries, how many numbers of cases are possible for the gift?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 복숭아 배 참외 딸기 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] apples peaches pears melons strawberries [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '복숭아'\nvar_c = '배'\nvar_d = '참외'\nvar_e = '딸기'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nprint(int(var_h))",
        "solution_code_en": "var_a = 'apples'\nvar_b = 'peaches'\nvar_c = 'pears'\nvar_d = 'melons'\nvar_e = 'strawberries'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nprint(int(var_h))"
    },
    "1050": {
        "category": "Possibility",
        "question_ko": "3개의 숫자 1, 2, 3을 한 번씩 모두 사용하여 만들 수 있는 세 자리 수는 몇 개입니까?",
        "question_en": "How many three-digit numbers can be made by using all three numbers 1, 2, and 3 once?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 1 2 3 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 2 3 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 2\nvar_c = 3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 2\nvar_c = 3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "1051": {
        "category": "Correspondence",
        "question_ko": "숫자를 7로 나눌 때 몫은 13이고 나머지는 1입니다. 이 숫자에 9를 더하고 8로 나눈 숫자의 몫과 나머지의 합을 구하세요.",
        "question_en": "When a number is divided by 7, the quotient is 13 and the remainder is 1. Add 9 to this number. Then, divide it by 8 to find the sum of the quotient and remainder.",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "13 7 [OP_MUL] 1 [OP_ADD] 9 [OP_ADD] 8 [OP_FDIV] 13 7 [OP_MUL] 1 [OP_ADD] 9 [OP_ADD] 8 [OP_MOD] [OP_ADD]",
        "solution_abst_en": "13 7 [OP_MUL] 1 [OP_ADD] 9 [OP_ADD] 8 [OP_FDIV] 13 7 [OP_MUL] 1 [OP_ADD] 9 [OP_ADD] 8 [OP_MOD] [OP_ADD]",
        "solution_code_ko": "var_a = 13\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 9\nvar_g = var_e + var_f\nvar_h = 8\nvar_i = var_g // var_h\nvar_j = 13\nvar_k = 7\nvar_l = var_j * var_k\nvar_m = 1\nvar_n = var_l + var_m\nvar_o = 9\nvar_p = var_n + var_o\nvar_q = 8\nvar_r = var_p % var_q\nvar_s = var_i + var_r\nprint(int(var_s))",
        "solution_code_en": "var_a = 13\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 9\nvar_g = var_e + var_f\nvar_h = 8\nvar_i = var_g // var_h\nvar_j = 13\nvar_k = 7\nvar_l = var_j * var_k\nvar_m = 1\nvar_n = var_l + var_m\nvar_o = 9\nvar_p = var_n + var_o\nvar_q = 8\nvar_r = var_p % var_q\nvar_s = var_i + var_r\nprint(int(var_s))"
    },
    "1052": {
        "category": "Geometry",
        "question_ko": "한 변이 20미터(m)인 정사각형 모양의 큰 트랙을 3등분하여 작은 트랙 3개를 만들었습니다. 이 작은 트랙 1개의 넓이는 몇 제곱미터(㎡)입니까?",
        "question_en": "A large track in the shape of a square with a side of 20 meters (m) was divided into 3 equal parts to create 3 smaller tracks. What is the area of this small track in square meters (m2)?",
        "answer_ko": "44.44",
        "answer_en": "44.44",
        "solution_abst_ko": "20 3 [OP_DIV] 2 [OP_POW]",
        "solution_abst_en": "20 3 [OP_DIV] 2 [OP_POW]",
        "solution_code_ko": "var_a = 20\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 20\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "1053": {
        "category": "Geometry",
        "question_ko": "정이십면체의 모서리의 개수는?",
        "question_en": "How many edges does a regular icosahedron have?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "30",
        "solution_abst_en": "30",
        "solution_code_ko": "var_a = 30\nprint(int(var_a))",
        "solution_code_en": "var_a = 30\nprint(int(var_a))"
    },
    "1054": {
        "category": "Comparison",
        "question_ko": "5가지 숫자 1.4, 9/10, 1.2, 0.5, 13/10 중에서 1.1보다 크거나 같은 수들의 합을 구하면 얼마입니까?",
        "question_en": "What is the sum of numbers which are greater than or equal to 1.1 among five numbers 1.4, 9/10, 1.2, 0.5, and 13/10.",
        "answer_ko": "3.90",
        "answer_en": "3.9",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE_EQUAL] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE_EQUAL] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i >= var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i >= var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "1055": {
        "category": "Correspondence",
        "question_ko": "A7B+23=695라는 식이 성립하려면, A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "What number must go in A to make A7B+23=695?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "A7B+23=695 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A7B+23=695 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A7B+23=695'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A7B+23=695'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "1056": {
        "category": "Arithmetic calculation",
        "question_ko": "닭이 15마리 있는데 그중 암탉은 3마리이고 나머지는 수탉입니다. 병아리는 수탉보다 4마리 더 적습니다. 병아리는 몇 마리입니까?",
        "question_en": "There are 15 chickens - 3 are hens and the rest are roosters. Chicks are 4 fewer than roosters. How many chicks do you have?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "15 3 [OP_SUB] 4 [OP_SUB]",
        "solution_abst_en": "15 3 [OP_SUB] 4 [OP_SUB]",
        "solution_code_ko": "var_a = 15\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "1057": {
        "category": "Arithmetic calculation",
        "question_ko": "950개의 바둑돌이 있다. 이 중 흰 바둑돌이 검은 바둑돌보다 150개 더 많다면 검은 바둑돌은 몇 개인지 구하시오.",
        "question_en": "There are 950 stones. If there are 150 more white stones than black stones, how many black stones are there?",
        "answer_ko": "400",
        "answer_en": "400",
        "solution_abst_ko": "950 150 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "950 150 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 950\nvar_b = 150\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 950\nvar_b = 150\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "1058": {
        "category": "Possibility",
        "question_ko": "2, 6, 9를 한 번씩만 사용하여 만들 수 있는 세 자리 수 중에서 가장 큰 수를 쓰시오.",
        "question_en": "Write the largest three-digit number that can be formed by using 2, 6, and 9 only once.",
        "answer_ko": "962",
        "answer_en": "962",
        "solution_abst_ko": "[OP_LIST_SOL] 2 6 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 2 6 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 2\nvar_b = 6\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))",
        "solution_code_en": "var_a = 2\nvar_b = 6\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))"
    },
    "1059": {
        "category": "Arithmetic calculation",
        "question_ko": "두 자리 수끼리의 덧셈에서 더하는 수의 일의 자리 숫자 5를 8로 잘못 보았습니다. 또 더해지는 수의 십의 자리 숫자 7을 4로 잘못 보고 계산하였더니 그 값이 111이 되었습니다. 바르게 계산한 결과를 구하시오.",
        "question_en": "In the addition of two-digit numbers, the units digit of added number was originally 5 but was mistaken as 8. Also, when the number 7 in the tens place of the number being added was mistakenly calculated as 4, the calculated value was 111. Find the result of the correct calculation.",
        "answer_ko": "138",
        "answer_en": "138",
        "solution_abst_ko": "111 1 5 8 [OP_SUB] [OP_MUL] [OP_ADD] 10 7 4 [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_abst_en": "111 1 5 8 [OP_SUB] [OP_MUL] [OP_ADD] 10 7 4 [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 111\nvar_b = 1\nvar_c = 5\nvar_d = 8\nvar_e = var_c - var_d\nvar_f = var_b * var_e\nvar_g = var_a + var_f\nvar_h = 10\nvar_i = 7\nvar_j = 4\nvar_k = var_i - var_j\nvar_l = var_h * var_k\nvar_m = var_g + var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 111\nvar_b = 1\nvar_c = 5\nvar_d = 8\nvar_e = var_c - var_d\nvar_f = var_b * var_e\nvar_g = var_a + var_f\nvar_h = 10\nvar_i = 7\nvar_j = 4\nvar_k = var_i - var_j\nvar_l = var_h * var_k\nvar_m = var_g + var_l\nprint(int(var_m))"
    },
    "1060": {
        "category": "Possibility",
        "question_ko": "주어진 숫자카드 0, 5, 8를 한 번씩 모두 사용하여 만들 수 있는 가장 작은 수에 백의 자리에 오는 숫자를 구하시오.",
        "question_en": "Find the number in the hundredth place of the smallest number that can be made by using all of the given number cards 0, 5, and 8 once.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "[OP_LIST_SOL] 0 5 8 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 100 [OP_FDIV]",
        "solution_abst_en": "[OP_LIST_SOL] 0 5 8 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 100 [OP_FDIV]",
        "solution_code_ko": "var_a = 0\nvar_b = 5\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = 100\nvar_h = var_f // var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 0\nvar_b = 5\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = 100\nvar_h = var_f // var_g\nprint(int(var_h))"
    },
    "1061": {
        "category": "Possibility",
        "question_ko": "석진, 태형, 남준, 유정, 유나의 증명사진이 각각 한 장씩 있습니다. 이 사진을 서로 다르게 한 줄로 나열하는 방법은 모두 몇 가지입니까?",
        "question_en": "There is one ID photo each of Seokjin, Taehyung, Namjoon, Yoojeong, and Yuna. In how many ways can these pictures be arranged in a row?",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "[OP_LIST_SOL] 석진 태형 남준 유정 유나 [OP_LIST_EOL] [OP_LIST_LEN] 5 [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] Seokjin Taehyung Namjoon Yoojeong Yuna [OP_LIST_EOL] [OP_LIST_LEN] 5 [OP_PERM]",
        "solution_code_ko": "var_a = '석진'\nvar_b = '태형'\nvar_c = '남준'\nvar_d = '유정'\nvar_e = '유나'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 5\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nprint(int(var_h))",
        "solution_code_en": "var_a = 'Seokjin'\nvar_b = 'Taehyung'\nvar_c = 'Namjoon'\nvar_d = 'Yoojeong'\nvar_e = 'Yuna'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 5\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nprint(int(var_h))"
    },
    "1062": {
        "category": "Correspondence",
        "question_ko": "소 12마리와 돼지 34마리를 키우는 농장에서 소 몇 마리와 그것의 3배만큼의 돼지를 시장에 팔았습니다. 남은 소와 돼지가 모두 30마리일 때, 판 소는 몇 마리인지 구하시오",
        "question_en": "On a farm of 12 cows and 34 pigs, a few cows and three times as many pigs were sold on the market. When there are 30 remaining cows and pigs, how many cows sold?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "12 34 [OP_ADD] 30 [OP_SUB] 1 3 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "12 34 [OP_ADD] 30 [OP_SUB] 1 3 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 34\nvar_c = var_a + var_b\nvar_d = 30\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = 3\nvar_h = var_f + var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 12\nvar_b = 34\nvar_c = var_a + var_b\nvar_d = 30\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = 3\nvar_h = var_f + var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "1063": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 90센티미터(㎝)인 정사각형 모양의 탁자 가장자리에 3센티미터(㎝) 간격으로 초를 놓으려면, 초는 모두 몇 개가 필요합니까?",
        "question_en": "How many candles are needed to place candles every 3 cm (cm) on the edge of a square table with a side of 90 centimeters (cm)?",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "90 4 [OP_MUL] 3 [OP_FDIV]",
        "solution_abst_en": "90 4 [OP_MUL] 3 [OP_FDIV]",
        "solution_code_ko": "var_a = 90\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 90\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "1064": {
        "category": "Correspondence",
        "question_ko": "A2B6-C97=543D를 만족하는 서로 다른 네 자연수 A, B, C, D가 있다고 한다면, A에 들어갈 수 있는 값은 무엇입니까?",
        "question_en": "If there are four different natural numbers A, B, C, and D that satisfy A2B6-C97=543D, what are the possible values for A?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "A2B6-C97=543D A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A2B6-C97=543D A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A2B6-C97=543D'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A2B6-C97=543D'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "1065": {
        "category": "Comparison",
        "question_ko": "우유를 준수는 0.331리터(L), 지민이는 218밀리리터(㎖) 마셨습니다. 누가 우유를 더 많이 마셨습니까?",
        "question_en": "Junsu drank 0.331 liters (L) of milk, while Jimin drank 218 milliliters (㎖). Who drank more milk?",
        "answer_ko": "준수",
        "answer_en": "Junsu",
        "solution_abst_ko": "[OP_LIST_SOL] 준수 지민 [OP_LIST_EOL] [OP_LIST_SOL] 0.331 1000 [OP_MUL] 218 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Junsu Jimin [OP_LIST_EOL] [OP_LIST_SOL] 0.331 1000 [OP_MUL] 218 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '준수'\nvar_b = '지민'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.331\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 218\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Junsu'\nvar_b = 'Jimin'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.331\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 218\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "1066": {
        "category": "Possibility",
        "question_ko": "0, 7, 4, 5 중에서 3개를 뽑아 중복을 사용하여 세 자리 수를 만들려고 합니다. 만들 수 있는 두 번째로 큰 수와 세 번째로 작은 수의 차를 구하시오.",
        "question_en": "You want to use 3 out of 0, 7, 4, and 5 allowing the repetition of digits to create a three-digit number. Find the difference between the second largest number and the third smallest number that can be made.",
        "answer_ko": "370",
        "answer_en": "370",
        "solution_abst_ko": "[OP_LIST_SOL] 0 7 4 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 2 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "[OP_LIST_SOL] 0 7 4 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 2 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 0\nvar_b = 7\nvar_c = 4\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g - var_i\nvar_k = abs(var_j)\nprint(int(var_k))",
        "solution_code_en": "var_a = 0\nvar_b = 7\nvar_c = 4\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g - var_i\nvar_k = abs(var_j)\nprint(int(var_k))"
    },
    "1067": {
        "category": "Comparison",
        "question_ko": "교회 안에 여러 개의 의자가 있습니다. 한 의자에 9명씩 앉으면 학생 한 명이 앉을 수 없고, 10명씩 앉으면 의자가 1개 빕니다. 교회에 간 학생들은 몇 명입니까?",
        "question_en": "There are several chairs inside the church. If 9 students sit per chair, one student cannot sit, and if 10 students sit per chair, 1 chair becomes vacant. How many students went to church?",
        "answer_ko": "100",
        "answer_en": "100",
        "solution_abst_ko": "1 10 [OP_ADD] 10 9 [OP_SUB] [OP_DIV] 9 [OP_MUL] 1 [OP_ADD]",
        "solution_abst_en": "1 10 [OP_ADD] 10 9 [OP_SUB] [OP_DIV] 9 [OP_MUL] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 10\nvar_c = var_a + var_b\nvar_d = 10\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 9\nvar_i = var_g * var_h\nvar_j = 1\nvar_k = var_i + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 1\nvar_b = 10\nvar_c = var_a + var_b\nvar_d = 10\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 9\nvar_i = var_g * var_h\nvar_j = 1\nvar_k = var_i + var_j\nprint(int(var_k))"
    },
    "1068": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 10, 11, 12, 13이 있습니다. 그 중에서 3번째로 작은 수와 2번째로 작은 수의 차는 얼마입니까?",
        "question_en": "There are four numbers 10, 11, 12, and 13. What is the value of difference between the 3rd smallest number and the 2nd smallest number?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 3 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 3 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))"
    },
    "1069": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 36을 빼야 할 것을 잘못하여 63을 뺀 결과는 8이 되었습니다. 바르게 계산한 결과는 얼마인가요?",
        "question_en": "I was supposed to subtract 36 from a particular number, but mistakenly subtracted 63, and as a result, got 8 as an answer. What should be the answer to the correct calculation?",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "8 63 [OP_ADD] 36 [OP_SUB]",
        "solution_abst_en": "8 63 [OP_ADD] 36 [OP_SUB]",
        "solution_code_ko": "var_a = 8\nvar_b = 63\nvar_c = var_a + var_b\nvar_d = 36\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 63\nvar_c = var_a + var_b\nvar_d = 36\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "1070": {
        "category": "Possibility",
        "question_ko": "1개의 상자에는 빨간 공 3개와 파란 공 5개가 담겨져 있습니다. 정국이는 2개의 상자를 가지고 있을 때 정국이가 가지고 있는 빨간 공의 개수는?",
        "question_en": "Each box contains 3 red balls and 5 blue balls. When Jungkook has 2 boxes, how many red balls does Jungkook have?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "3 2 [OP_MUL]",
        "solution_abst_en": "3 2 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "1071": {
        "category": "Geometry",
        "question_ko": "꽃병을 정사각형 모양으로 빈틈없이 정렬하여 정리해 보니 6개의 병이 남았습니다. 그래서 가로 한 변과 세로 한 변을 1열씩 늘리려 하였지만 11개의 꽃병이 부족하였습니다. 이 꽃병들을 7열로 세운다면 1열에 몇 병씩 있을까요?",
        "question_en": "After arranging the vases in a square shape, there were 6 bottles left. So, I tried to increase the width and length by one row each, but 11 vases were insufficient. If you arrange these vases in 7 rows, how many bottles are there in 1 row?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "6 11 [OP_ADD] 1 [OP_SUB] 2 [OP_DIV] 2 [OP_POW] 6 [OP_ADD] 7 [OP_DIV]",
        "solution_abst_en": "6 11 [OP_ADD] 1 [OP_SUB] 2 [OP_DIV] 2 [OP_POW] 6 [OP_ADD] 7 [OP_DIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 11\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 6\nvar_k = var_i + var_j\nvar_l = 7\nvar_m = var_k / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 6\nvar_b = 11\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 6\nvar_k = var_i + var_j\nvar_l = 7\nvar_m = var_k / var_l\nprint(int(var_m))"
    },
    "1072": {
        "category": "Geometry",
        "question_ko": "한 모서리의 길이가 15센티미터(㎝)인 정육면체의 모든 모서리의 길이의 합은 몇 센티미터(㎝)입니까?",
        "question_en": "What is the sum of the lengths in centimeters (cm) of all the edges of a cube with one edge length of 15 centimeters (cm)?",
        "answer_ko": "180",
        "answer_en": "180",
        "solution_abst_ko": "15 4 3 [OP_MUL] [OP_MUL]",
        "solution_abst_en": "15 4 3 [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 15\nvar_b = 4\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 4\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nprint(int(var_e))"
    },
    "1073": {
        "category": "Possibility",
        "question_ko": "1부터 9까지의 숫자 카드 3장을 사용하여 어떤 세 자리 수를 만들었습니다. 백의 자리는 7, 십의 자리는 4일 때, 일의 자리에 놓을 수 있는 숫자는 모두 몇 개입니까?",
        "question_en": "Three cards of numbers from 1 to 9 are used to create a certain three-digit number. If the hundredth place is 7 and the tens place is 4, how many digits can be placed in the ones place?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "1 9 1 [OP_LIST_ARANGE] [OP_LIST_SOL] 7 4 [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_abst_en": "1 9 1 [OP_LIST_ARANGE] [OP_LIST_SOL] 7 4 [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 7\nvar_e = 4\nlist_b= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 7\nvar_e = 4\nlist_b= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "1074": {
        "category": "Correspondence",
        "question_ko": "형준이는 첫 번째 상자를 포장하는데 가진 리본의 절반과 2000센티미터(㎝)의 리본을 사용하고, 두 번째 상자를 포장하는데 남은 리본의 절반과 2000센티미터(㎝)를 사용했더니 남은 리본이 없었습니다. 형준이가 처음에 가지고 있던 리본은 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "Hyungjun used half of his ribbon and 2000 centimeters (cm) of ribbon to wrap the first box, and used half of the remaining ribbon and 2000 centimeters (cm) of ribbon to wrap the second box, but there was no ribbon left. How many centimeters (cm) is the ribbon Hyeongjun had at first?",
        "answer_ko": "12000",
        "answer_en": "12000",
        "solution_abst_ko": "0 2000 [OP_ADD] 2 [OP_MUL] 2000 [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "0 2000 [OP_ADD] 2 [OP_MUL] 2000 [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 0\nvar_b = 2000\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 2000\nvar_g = var_e + var_f\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 0\nvar_b = 2000\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 2000\nvar_g = var_e + var_f\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "1075": {
        "category": "Geometry",
        "question_ko": "안에 부피가 138000000세제곱센티미터(㎤)인, 여섯 면이 각 사각형이고 마주보는 면이 똑같으며 모서리가 12개이며 꼭짓점이 8개인 통이 있습니다. 윗면의 넓이가 115제곱미터(㎡)일 때, 높이가 몇 미터(m)인지 구하시오.",
        "question_en": "There is a box with an inside volume of 138000000 cubic centimeters (cm3), six sides each being a rectangle, equal opposite sides, twelve edges, and eight vertices. If the area of the top surface is 115 square meters (m2), find the height in meters (m).",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "1380000000 100 3 [OP_POW] [OP_DIV] 115 [OP_DIV]",
        "solution_abst_en": "1380000000 100 3 [OP_POW] [OP_DIV] 115 [OP_DIV]",
        "solution_code_ko": "var_a = 1380000000\nvar_b = 100\nvar_c = 3\nvar_d = var_b ** var_c\nvar_e = var_a / var_d\nvar_f = 115\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1380000000\nvar_b = 100\nvar_c = 3\nvar_d = var_b ** var_c\nvar_e = var_a / var_d\nvar_f = 115\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "1076": {
        "category": "Arithmetic calculation",
        "question_ko": "은지가 펼진 책의 두 쪽수의 합이 137일 때, 은지가 펼친 두 쪽수 중 큰 수는 몇인지 구하시오.",
        "question_en": "If the sum of the two pages of the book Eunji has opened is 137, what is the larger number of the two pages Eunji has opened?",
        "answer_ko": "69",
        "answer_en": "69",
        "solution_abst_ko": "137 2 [OP_FDIV] 1 [OP_ADD]",
        "solution_abst_en": "137 2 [OP_FDIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 137\nvar_b = 2\nvar_c = var_a // var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 137\nvar_b = 2\nvar_c = var_a // var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "1077": {
        "category": "Geometry",
        "question_ko": "정이십면체에서 면의 수를 모두 구하시오.",
        "question_en": "Find the number of all faces of a regular icosahedron.",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "20",
        "solution_abst_en": "20",
        "solution_code_ko": "var_a = 20\nprint(int(var_a))",
        "solution_code_en": "var_a = 20\nprint(int(var_a))"
    },
    "1078": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 10미터(m)인 정사각형 모양의 공원이 있습니다. 이 공원을 밑면이 1센티미터(㎝)이고 높이가 3센티미터(㎝)인 직각삼각형 모양으로 구역을 나누고자 합니다. 나눌 수 있는 구역은 최대 몇 개입니까?",
        "question_en": "A park is in the shape of a square with sides measuring 10 meters (m). We want to divide the park into right triangles with a base of 1 meters (m) and a height of 3 meters (m). What is the maximum number of zones that can be divided?",
        "answer_ko": "66",
        "answer_en": "66",
        "solution_abst_ko": "10 2 [OP_POW] 1 3 [OP_MUL] [OP_FDIV] 2 [OP_MUL]",
        "solution_abst_en": "10 2 [OP_POW] 1 3 [OP_MUL] [OP_FDIV] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 1\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c // var_f\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 1\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c // var_f\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "1079": {
        "category": "Arithmetic calculation",
        "question_ko": "150원짜리 볼펜 269개를 29명의 학생에게 동일한 개수만큼 주려고 합니다. 부족한 개수만큼 볼펜을 더 산다고 할 때 얼마가 필요한지 구하시오.",
        "question_en": "You want to hand out 269 pens each of which costs 150 won to 29 students equally. If you have to buy the lacking pens, find how much money you need.",
        "answer_ko": "3150",
        "answer_en": "3150",
        "solution_abst_ko": "29 269 29 [OP_MOD] [OP_SUB] 150 [OP_MUL]",
        "solution_abst_en": "29 269 29 [OP_MOD] [OP_SUB] 150 [OP_MUL]",
        "solution_code_ko": "var_a = 29\nvar_b = 269\nvar_c = 29\nvar_d = var_b % var_c\nvar_e = var_a - var_d\nvar_f = 150\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 29\nvar_b = 269\nvar_c = 29\nvar_d = var_b % var_c\nvar_e = var_a - var_d\nvar_f = 150\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "1080": {
        "category": "Correspondence",
        "question_ko": "어떤 소수를 8 로 나누어야 할 것을 잘못하여 8 을 곱했더니 69.76 이 되었습니다. 바르게 계산한 값을 구해 보시오",
        "question_en": "A prime number was supposed to be divided by 8, but multiplied by 8 by mistake, and it became 69.76. Find the correct value.",
        "answer_ko": "1.09",
        "answer_en": "1.09",
        "solution_abst_ko": "69.76 8 [OP_DIV] 8 [OP_DIV]",
        "solution_abst_en": "69.76 8 [OP_DIV] 8 [OP_DIV]",
        "solution_code_ko": "var_a = 69.76\nvar_b = 8\nvar_c = var_a / var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 69.76\nvar_b = 8\nvar_c = var_a / var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "1081": {
        "category": "Comparison",
        "question_ko": "지름 10센티미터(㎝)의 원 A, 반지름 4센티미터(㎝)의 원 B, 지름과 반지름 길이의 합이 9인 원 C 중 가장 작은 원은 무엇인가?",
        "question_en": "Which is the smallest among circle A with a diameter of 10 centimeters (cm), circle B with a radius of 4 centimeters (cm), and circle C with a sum of 9 in its diameter and radius?",
        "answer_ko": "C",
        "answer_en": "C",
        "solution_abst_ko": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] 10 2 [OP_DIV] 4 9 2 1 [OP_ADD] [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] 10 2 [OP_DIV] 4 9 2 1 [OP_ADD] [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 10\nvar_e = 2\nvar_f = var_d / var_e\nvar_g = 4\nvar_h = 9\nvar_i = 2\nvar_j = 1\nvar_k = var_i + var_j\nvar_l = var_h / var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[var_m-1]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 10\nvar_e = 2\nvar_f = var_d / var_e\nvar_g = 4\nvar_h = 9\nvar_i = 2\nvar_j = 1\nvar_k = var_i + var_j\nvar_l = var_h / var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[var_m-1]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "1082": {
        "category": "Arithmetic calculation",
        "question_ko": "무궁화가 34송이 있습니다. 무궁화는 국화보다 13송이 더 적습니다. 국화는 민들레보다 23송이 많습니다. 무궁화, 국화, 민들레는 모두 몇 송이 있습니까?",
        "question_en": "There are 34 hibiscus. There are 13 fewer hibiscus than chrysanthemums. There are 23 more chrysanthemums than dandelions. How many hibiscus, chrysanthemum, and dandelion are there in total?",
        "answer_ko": "105",
        "answer_en": "105",
        "solution_abst_ko": "34 34 13 [OP_ADD] [OP_ADD] 34 13 [OP_ADD] 23 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "34 34 13 [OP_ADD] [OP_ADD] 34 13 [OP_ADD] 23 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 34\nvar_b = 34\nvar_c = 13\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nvar_f = 34\nvar_g = 13\nvar_h = var_f + var_g\nvar_i = 23\nvar_j = var_h - var_i\nvar_k = var_e + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 34\nvar_b = 34\nvar_c = 13\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nvar_f = 34\nvar_g = 13\nvar_h = var_f + var_g\nvar_i = 23\nvar_j = var_h - var_i\nvar_k = var_e + var_j\nprint(int(var_k))"
    },
    "1083": {
        "category": "Correspondence",
        "question_ko": "서로 다른 두 수 A, B가 있습니다. 두 자리 수끼리의 덧셈식 AB+25=B3에서 B를 구하시오.",
        "question_en": "There are two different numbers A and B. Find B from the two-digit addition formula AB+25=B3.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "AB+25=B3 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "AB+25=B3 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'AB+25=B3'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'AB+25=B3'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "1084": {
        "category": "Geometry",
        "question_ko": "2.3미터(m)짜리 나무기둥 8개를 이용해서 정팔각형 모양 울타리를 만들었습니다. 이 울타리의 둘레의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "A regular octagonal fence was built using eight 2.3-meter (m) wooden poles. What is the perimeter of this fence in centimeters (cm)?",
        "answer_ko": "1840",
        "answer_en": "1840",
        "solution_abst_ko": "2.3 8 [OP_MUL] 100 [OP_MUL]",
        "solution_abst_en": "2.3 8 [OP_MUL] 100 [OP_MUL]",
        "solution_code_ko": "var_a = 2.3\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = var_c * var_d\nprint(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))",
        "solution_code_en": "var_a = 2.3\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = var_c * var_d\nprint(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))"
    },
    "1085": {
        "category": "Arithmetic calculation",
        "question_ko": "떨어진 높이의 1/4만큼 튀어오르는 공을 12.8미터(m) 의 높이에서 떨어뜨렸을 때, 세 번째로 튀어오른 높이는 몇 센티미터(㎝) 가 되겠습니까?",
        "question_en": "If a ball that bounces 1/4 of its height is dropped from a height of 12.8 meters (m), how many centimeters (cm) will the third bounce be?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "12.8 1/4 3 [OP_POW] [OP_MUL] 100 [OP_MUL]",
        "solution_abst_en": "12.8 1/4 3 [OP_POW] [OP_MUL] 100 [OP_MUL]",
        "solution_code_ko": "var_a = 12.8\nvar_b = 0.25\nvar_c = 3\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 100\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 12.8\nvar_b = 0.25\nvar_c = 3\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 100\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "1086": {
        "category": "Geometry",
        "question_ko": "어느 바퀴의 둘레는 94.2센티미터(㎝)입니다. 이 바퀴의 지름이 30센티미터(㎝)일 때, 바퀴의 둘레는 지름의 몇 배입니까?",
        "question_en": "The circumference of a wheel is 94.2 centimeters (cm). If the diameter of this wheel is 30 centimeters (cm), how many times the circumference of the wheel is than the diameter?",
        "answer_ko": "3.14",
        "answer_en": "3.14",
        "solution_abst_ko": "94.2 30 [OP_DIV]",
        "solution_abst_en": "94.2 30 [OP_DIV]",
        "solution_code_ko": "var_a = 94.2\nvar_b = 30\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 94.2\nvar_b = 30\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "1087": {
        "category": "Arithmetic calculation",
        "question_ko": "대리석 3/4미터(m)의 무게가 15/2킬로그램(㎏)일 때 대리석 1미터(m)의 무게는 몇 킬로그램(㎏)입니까?",
        "question_en": "How many kilograms (kg) does 1 meter (m) of marble weigh if 3/4 meter (m) of marble weighs 15/2 kilograms (kg)?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "15/2 3/4 [OP_DIV]",
        "solution_abst_en": "15/2 3/4 [OP_DIV]",
        "solution_code_ko": "var_a = 7.5\nvar_b = 0.75\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 7.5\nvar_b = 0.75\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "1088": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 1미터(m) 50센티미터(㎝)인 철사를 석기와 예슬이가 나누어 가집니다. 예슬이보다 석기가 16센티미터(㎝) 더 짧게 하려면 석기는 몇 센티미터(㎝)를 가지면 됩니까?",
        "question_en": "Seokgi and Yeseul are going to share a wire that is 1 meter (m) and 50 centimeters (cm) long. Find how many centimeters (cm) of wire must Seokgi take for him to get 16 centimeters (cm) shorter wire than Yeseul's.",
        "answer_ko": "67",
        "answer_en": "67",
        "solution_abst_ko": "1 100 [OP_MUL] 50 [OP_ADD] 16 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "1 100 [OP_MUL] 50 [OP_ADD] 16 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 50\nvar_e = var_c + var_d\nvar_f = 16\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 50\nvar_e = var_c + var_d\nvar_f = 16\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "1089": {
        "category": "Arithmetic calculation",
        "question_ko": "양파 한 개의 가격은 200원이다. 양파 180개를 6개의 망에 나누어 담으려고 할 때 한 망에 담긴 양파의 가격은 얼마입니까?",
        "question_en": "The price of one onion is 200 won. How much does one bag of onions cost, if you divide 180 onions into 6 bags?",
        "answer_ko": "6000",
        "answer_en": "6000",
        "solution_abst_ko": "180 6 [OP_DIV] 200 [OP_MUL]",
        "solution_abst_en": "180 6 [OP_DIV] 200 [OP_MUL]",
        "solution_code_ko": "var_a = 180\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 200\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 180\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 200\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "1090": {
        "category": "Possibility",
        "question_ko": "2, 0, 4, 1, 5, 8을 한 번씩만 사용하여 만들 수 있는 여섯 자리 수 중에서 가장 큰 수와 가장 작은 수의 합을 구하시오.",
        "question_en": "Find the sum of the largest and smallest six-digit numbers that can be formed by using 2, 0, 4, 1, 5, and 8 only once.",
        "answer_ko": "956668",
        "answer_en": "956668",
        "solution_abst_ko": "[OP_LIST_SOL] 2 0 4 1 5 8 [OP_LIST_EOL] 6 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 2 0 4 1 5 8 [OP_LIST_EOL] 6 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 0\nvar_c = 4\nvar_d = 1\nvar_e = 5\nvar_f = 8\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 6\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_i = list_c[-var_h]\nvar_j = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_k = list_d[var_j-1]\nvar_l = var_i + var_k\nprint(int(var_l))",
        "solution_code_en": "var_a = 2\nvar_b = 0\nvar_c = 4\nvar_d = 1\nvar_e = 5\nvar_f = 8\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 6\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_i = list_c[-var_h]\nvar_j = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_k = list_d[var_j-1]\nvar_l = var_i + var_k\nprint(int(var_l))"
    },
    "1091": {
        "category": "Geometry",
        "question_ko": "직사각형 모양의 포장지는 가로 6센티미터(㎝), 둘레 28 센티미터(㎝)입니다. 이 포장지로 포장할 수 있는 면적의 넓이를 구하시오.",
        "question_en": "A rectangular wrapping paper is 6 centimeters (cm) wide and 28 centimeters (cm) in perimeter. Find the area of the area that can be covered with this wrapping paper.",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "28 2 [OP_DIV] 6 [OP_SUB] 6 [OP_MUL]",
        "solution_abst_en": "28 2 [OP_DIV] 6 [OP_SUB] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 28\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c - var_d\nvar_f = 6\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 28\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c - var_d\nvar_f = 6\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "1092": {
        "category": "Arithmetic calculation",
        "question_ko": "현기는 하루에 0.6 시간씩 공부를 합니다. 현기가 3주동안 공부를 한 시간은 모두 몇 시간입니까?",
        "question_en": "Hyeongi studies for 0.6 hours a day. For how many hours did Hyeongi study in 3 weeks?",
        "answer_ko": "12.60",
        "answer_en": "12.6",
        "solution_abst_ko": "0.6 7 [OP_MUL] 3 [OP_MUL]",
        "solution_abst_en": "0.6 7 [OP_MUL] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 0.6\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.6\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "1093": {
        "category": "Geometry",
        "question_ko": "길이가 78센티미터(㎝)인 철사를 잘라 모두 사용하여 삼각형 1개와 정사각형 1개를 만들었습니다. 만든 삼각형의 세 변의 길이의 합이 46센티미터(㎝)일 때 만든 정사각형의 한 변은 몇 센티미터(㎝)입니까?",
        "question_en": "I cut 78 centimeters (cm) of wire and used all of them to make one triangle and one square. If the sum of the lengths of the three sides of the triangle is 46 centimeters (cm), how many centimeters (cm) is the side of the square?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "78 46 [OP_SUB] 4 [OP_DIV]",
        "solution_abst_en": "78 46 [OP_SUB] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 78\nvar_b = 46\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 78\nvar_b = 46\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "1094": {
        "category": "Arithmetic calculation",
        "question_ko": "친구 6명이 공원에서 자전거를 빌려서 타려고 합니다. 자전거 한 대의 30분 대여료는 4000원이고 4대를 3시간 동안 빌려타려면 한 사람이 내야하는 돈은 얼마입니까?",
        "question_en": "Six friends are going to rent bikes for a ride in the park. A 30-minute rental of a bicycle is 4,000 won. How much does one person have to pay to rent 4 bicycles for 3 hours?",
        "answer_ko": "16000",
        "answer_en": "16000",
        "solution_abst_ko": "3 60 [OP_MUL] 30 [OP_DIV] 4000 [OP_MUL] 4 [OP_MUL] 6 [OP_DIV]",
        "solution_abst_en": "3 60 [OP_MUL] 30 [OP_DIV] 4000 [OP_MUL] 4 [OP_MUL] 6 [OP_DIV]",
        "solution_code_ko": "var_a = 3\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 30\nvar_e = var_c / var_d\nvar_f = 4000\nvar_g = var_e * var_f\nvar_h = 4\nvar_i = var_g * var_h\nvar_j = 6\nvar_k = var_i / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 3\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 30\nvar_e = var_c / var_d\nvar_f = 4000\nvar_g = var_e * var_f\nvar_h = 4\nvar_i = var_g * var_h\nvar_j = 6\nvar_k = var_i / var_j\nprint(int(var_k))"
    },
    "1095": {
        "category": "Arithmetic calculation",
        "question_ko": "만화 영화 ‘눈의 왕자’를 1초 동안 상영하려면 그림이 30장 필요합니다. ‘눈의 왕자’를 25초 상영하려면 그림이 몇 장 필요할까요?",
        "question_en": "It requires 30 pictures to play 1 second of the animated film called 'The Snow Prince'. How many pictures are necessary to make a 25-second screening?",
        "answer_ko": "750",
        "answer_en": "750",
        "solution_abst_ko": "30 25 [OP_MUL]",
        "solution_abst_en": "30 25 [OP_MUL]",
        "solution_code_ko": "var_a = 30\nvar_b = 25\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 30\nvar_b = 25\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "1096": {
        "category": "Geometry",
        "question_ko": "밑변이 7.2미터(m), 높이가 7미터(m)인 삼각형 모양의 밭과 넓이가 같은 직사각형 모양의 밭을 만들려고 합니다. 직사각형 모양 밭의 가로를 4미터(m)로 한다면 세로는 몇 미터(m)로 해야 합니까?",
        "question_en": "You want to create a rectangular field that has the same area as a triangular field with a base of 7.2 meters (m) and a height of 7 meters (m). If the width of a rectangular field is 4 meters (m), how many meters (m) should the length be?",
        "answer_ko": "6.30",
        "answer_en": "6.3",
        "solution_abst_ko": "7.2 7 [OP_MUL] 2 [OP_DIV] 4 [OP_DIV]",
        "solution_abst_en": "7.2 7 [OP_MUL] 2 [OP_DIV] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 7.2\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 4\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 7.2\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 4\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "1097": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이가 처음에 가지고 있던 사과는 8개입니다. 사과 7개를 선물받았을 때, 정국이가 가지고 있는 사과의 수는 총 몇 개입니까?",
        "question_en": "At first, Jungkook had 8 apples. How many apples does Jungkook have in total when he is given 7 apples?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "8 7 [OP_ADD]",
        "solution_abst_en": "8 7 [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 8\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "1098": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이는 10개의 공을 5개씩 나누어 담으려고 합니다. 정국이가 필요한 상자의 개수는 몇 개 입니까?",
        "question_en": "Jungkook tries to divide 10 balls into boxes containing 5 balls each. How many boxes does Jungkook need?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "10 5 [OP_DIV]",
        "solution_abst_en": "10 5 [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 5\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 10\nvar_b = 5\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "1099": {
        "category": "Geometry",
        "question_ko": "해찬이는 가지고 있는 리본 테이프 전부를 이용하여 가로가 7센티미터(㎝), 세로가 5센티미터(㎝)인 직사각형을 만들었습니다. 이 리본 테이프를 다시 사용하여 정사각형을 만든다면 한 변의 길이는 몇 센티미터(㎝)로 해야 합니까?",
        "question_en": "Haechan used all the ribbon tapes he had to make a rectangle of 7 centimeters (cm) long and 5 centimeters (cm) wide. If he used this ribbon tape again to make a square, how many centimeters (cm) would each side be?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "7 5 [OP_ADD] 2 [OP_MUL] 4 [OP_DIV]",
        "solution_abst_en": "7 5 [OP_ADD] 2 [OP_MUL] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 7\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 7\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "1100": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 1.2로 나눈 후 22.5를 빼고, 그 값에 0.6을 곱한 후 10.5를 더하면 30이 됩니다. 어떤 수를 구하시오.",
        "question_en": "If you divide a number by 1.2, subtract 22.5, multiply that number by 0.6, then add 10.5, you can get 30. Find out this number. ",
        "answer_ko": "66",
        "answer_en": "66",
        "solution_abst_ko": "30 10.5 [OP_SUB] 0.6 [OP_DIV] 22.5 [OP_ADD] 1.2 [OP_MUL]",
        "solution_abst_en": "30 10.5 [OP_SUB] 0.6 [OP_DIV] 22.5 [OP_ADD] 1.2 [OP_MUL]",
        "solution_code_ko": "var_a = 30\nvar_b = 10.5\nvar_c = var_a - var_b\nvar_d = 0.6\nvar_e = var_c / var_d\nvar_f = 22.5\nvar_g = var_e + var_f\nvar_h = 1.2\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 30\nvar_b = 10.5\nvar_c = var_a - var_b\nvar_d = 0.6\nvar_e = var_c / var_d\nvar_f = 22.5\nvar_g = var_e + var_f\nvar_h = 1.2\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "1101": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 1.9를 뺀 후 1.5를 곱하고, 32를 더한 값을 2.5로 나누면 20이 됩니다. 어떤 수를 소수점을 포함하여 구하시오.",
        "question_en": "Subtracting 1.9 from a number, multiplying by 1.5, adding 32 and then dividing by 2.5 results in 20. Calculate the number including the decimal point.",
        "answer_ko": "13.90",
        "answer_en": "13.9",
        "solution_abst_ko": "20 2.5 [OP_MUL] 32 [OP_SUB] 1.5 [OP_DIV] 1.9 [OP_ADD]",
        "solution_abst_en": "20 2.5 [OP_MUL] 32 [OP_SUB] 1.5 [OP_DIV] 1.9 [OP_ADD]",
        "solution_code_ko": "var_a = 20\nvar_b = 2.5\nvar_c = var_a * var_b\nvar_d = 32\nvar_e = var_c - var_d\nvar_f = 1.5\nvar_g = var_e / var_f\nvar_h = 1.9\nvar_i = var_g + var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 20\nvar_b = 2.5\nvar_c = var_a * var_b\nvar_d = 32\nvar_e = var_c - var_d\nvar_f = 1.5\nvar_g = var_e / var_f\nvar_h = 1.9\nvar_i = var_g + var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "1102": {
        "category": "Arithmetic calculation",
        "question_ko": "성민이네 학교는 수학 상반과 하반이 있다. 상반 20명의 수학 평균은 42점이고 하반 20명의 평균은 38점이다. 성민이네 반 전체 수학 평균은 얼마인지 구하시오.",
        "question_en": "At Seongmin's school, there are upper and lower math classes. The math average of the top 20 students in the upper class is 42 points, and the average of the bottom 20 students in the lower class is 38 points. What is the average math score of Seongmin's class?",
        "answer_ko": "40",
        "answer_en": "40",
        "solution_abst_ko": "20 42 [OP_MUL] 20 38 [OP_MUL] [OP_ADD] 20 20 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "20 42 [OP_MUL] 20 38 [OP_MUL] [OP_ADD] 20 20 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 20\nvar_b = 42\nvar_c = var_a * var_b\nvar_d = 20\nvar_e = 38\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 20\nvar_i = 20\nvar_j = var_h + var_i\nvar_k = var_g / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 20\nvar_b = 42\nvar_c = var_a * var_b\nvar_d = 20\nvar_e = 38\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 20\nvar_i = 20\nvar_j = var_h + var_i\nvar_k = var_g / var_j\nprint(int(var_k))"
    },
    "1103": {
        "category": "Possibility",
        "question_ko": "연지는 2, 4, 6, 8이 적인 과녁에 화살을 쏴 맞춘 순서대로 배열하여 세 자리 수를 만들고자 한다. 이 때, 만들 수 있는 모든 수의 합을 구하여라.",
        "question_en": "Yeonji wants to make a three-digit number by arranging the arrows when they hit the targets which have 2, 4, 6, and 8 written on them. In this case, find the sum of all possible numbers.",
        "answer_ko": "35520",
        "answer_en": "35520",
        "solution_abst_ko": "[OP_LIST_SOL] 2 4 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 2 4 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = 6\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = 6\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint(int(var_f))"
    },
    "1104": {
        "category": "Comparison",
        "question_ko": "어떤 세 자리 수는 백의 자리 숫자가 7이고 일의 자리 숫자가 6이다. 756보다 작은 수는 모두 몇 개인지 구하시오. 십의 자리에는 0부터 9까지의 숫자가 들어갈 수 있습니다.",
        "question_en": "Find how many three-digit numbers 7A6 are less than 756. Each of the numbers from 0 to 9 can be in the place of A.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "[OP_LIST_SOL] 7 A 6 [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 756 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 7 A 6 [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 756 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 7\nvar_b = 'A'\nvar_c = 6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nans_dict = dict()\nvar_d = str(var_d)\nlist_b = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_d) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_b.append(new_elem)\nvar_e = 756\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 7\nvar_b = 'A'\nvar_c = 6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nans_dict = dict()\nvar_d = str(var_d)\nlist_b = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_d) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_b.append(new_elem)\nvar_e = 756\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "1105": {
        "category": "Possibility",
        "question_ko": "3, 5, 6, 7 총 4장의 수 카드 중 2장을 사용하여 두 자리 수를 만들려고 합니다. 만들 수 있는 7의 배수 중 가장 작은 수는 무엇인가요?",
        "question_en": "There is a list of numbers: 3, 5, 6, and 7. You are going to use 2 numbers from it to create a two-digit number. What is the possible smallest number that is a multiple of 7?",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "[OP_LIST_SOL] 3 5 6 7 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 7 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 3 5 6 7 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 7 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 3\nvar_b = 5\nvar_c = 6\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 7\nlist_c = []\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nvar_g = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nprint(int(var_h))",
        "solution_code_en": "var_a = 3\nvar_b = 5\nvar_c = 6\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 7\nlist_c = []\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nvar_g = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nprint(int(var_h))"
    },
    "1106": {
        "category": "Correspondence",
        "question_ko": "세 자리 수 7A7을 십의 자리까지 올림하면 730이 됩니다. A를 구하시오.",
        "question_en": "The three-digit number 7A7 rounded up to the tens place is 730. Find A.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "7A7 [OP_GEN_POSSIBLE_LIST] 730 [OP_LIST_LESS_EQUAL] 730 10 [OP_SUB] [OP_LIST_MORE] 7A7 A [OP_LIST_FIND_UNK]",
        "solution_abst_en": "7A7 [OP_GEN_POSSIBLE_LIST] 730 [OP_LIST_LESS_EQUAL] 730 10 [OP_SUB] [OP_LIST_MORE] 7A7 A [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = '7A7'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 730\nlist_b = []\nfor i in list_a:\n    if i <= var_b:\n        list_b.append(i)\nvar_c = 730\nvar_d = 10\nvar_e = var_c - var_d\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = '7A7'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))",
        "solution_code_en": "var_a = '7A7'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 730\nlist_b = []\nfor i in list_a:\n    if i <= var_b:\n        list_b.append(i)\nvar_c = 730\nvar_d = 10\nvar_e = var_c - var_d\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = '7A7'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))"
    },
    "1107": {
        "category": "Geometry",
        "question_ko": "가로가 25센티미터(㎝)이고 높이가 16센티미터(㎝)인 직사각형의 넓이를 반으로 나눈 값을 구하시오.",
        "question_en": "Find the value of dividing the area of a rectangle in half when the rectangle has a width of 25 centimeters (cm) and a height of 16 centimeters (cm).",
        "answer_ko": "200",
        "answer_en": "200",
        "solution_abst_ko": "25 16 [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "25 16 [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 25\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 25\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "1108": {
        "category": "Comparison",
        "question_ko": "텃밭에 토마토 하나를 앞에서 8번째 줄, 뒤에서 14번째 줄, 왼쪽에서 7번째 열, 오른쪽에서 13번째 열에 심었습니다. 각 줄마다 같은 개수의 토마토를 심는 다고 할 때, 텃밭에 토마토 수는 모두 몇 개 입니까?",
        "question_en": "One tomato was planted in the 8th row from the front, 14th row from the back, 7th row from the left, and 13th row from the right. If you plant the same number of tomatoes in each row, how many tomatoes will there be in your garden?",
        "answer_ko": "399",
        "answer_en": "399",
        "solution_abst_ko": "8 14 [OP_ADD] 1 [OP_SUB] 7 13 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "8 14 [OP_ADD] 1 [OP_SUB] 7 13 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 14\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 7\nvar_g = 13\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 8\nvar_b = 14\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 7\nvar_g = 13\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))"
    },
    "1109": {
        "category": "Correspondence",
        "question_ko": "마트주인은 우유를 21.52리터(L)를 진열해놓았지만 실제로는 12.64리터(L)가 팔렸다. 마트에서 팔리지 못하고 남은 우유는 몇 리터(L)인지 구하시오.",
        "question_en": "The shop owner had arranged 21.52 liters (L) of milk, but only 12.64 liters (L) were sold. Find the amount of liters (L) of the remaining milk.",
        "answer_ko": "8.88",
        "answer_en": "8.88",
        "solution_abst_ko": "21.52 12.64 [OP_SUB]",
        "solution_abst_en": "21.52 12.64 [OP_SUB]",
        "solution_code_ko": "var_a = 21.52\nvar_b = 12.64\nvar_c = var_a - var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 21.52\nvar_b = 12.64\nvar_c = var_a - var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "1110": {
        "category": "Comparison",
        "question_ko": "5마리의 물고기 (가), (나), (다), (라), (마)가 있습니다. (가)는 (나)보다 빠르고 (다)보다 느립니다. (마)는 (라)보다 느립니다. (나)는 (라)보다 빠릅니다. 가장 느린 물고기는 어느 것입니까?",
        "question_en": "There are 5 fish A, B, C, D, and E. A is faster than B and slower than C. E is slower than D. B is faster than D. Which fish is the slowest?",
        "answer_ko": "(마)",
        "answer_en": "E",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) (다) (라) (마) [OP_LIST_EOL] [OP_LIST_SOL] (가) (나) > (가) (다) < (마) (라) < (나) (라) > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D E [OP_LIST_EOL] [OP_LIST_SOL] A B > A C < E D < B D > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nvar_c = '(다)'\nvar_d = '(라)'\nvar_e = '(마)'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = '(가)'\nvar_g = '(나)'\nvar_h = '>'\nvar_i = '(가)'\nvar_j = '(다)'\nvar_k = '<'\nvar_l = '(마)'\nvar_m = '(라)'\nvar_n = '<'\nvar_o = '(나)'\nvar_p = '(라)'\nvar_q = '>'\nlist_b= []\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_r = len(list_c)\nvar_s = list_c[var_r-1]\nprint(var_s)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 'A'\nvar_g = 'B'\nvar_h = '>'\nvar_i = 'A'\nvar_j = 'C'\nvar_k = '<'\nvar_l = 'E'\nvar_m = 'D'\nvar_n = '<'\nvar_o = 'B'\nvar_p = 'D'\nvar_q = '>'\nlist_b= []\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_r = len(list_c)\nvar_s = list_c[var_r-1]\nprint(var_s)"
    },
    "1111": {
        "category": "Arithmetic calculation",
        "question_ko": "우유 1리터(L)가 있었는데 이 중에서 예슬이가 0.1리터(L)를 마셨고, 가영이는 예슬이보다 0.2리터(L)를 더 많이 마셨습니다. 잠시 후에 한초가 와서 우유를 마셨더니 0.3리터(L)가 남았습니다. 한초가 마신 우유는 몇 리터(L)입니까?",
        "question_en": "There was 1 liter (L) of milk, of which Yeseul drank 0.1 liters (L), and Gayoung drank 0.2 liters (L) more than Yeseul. After a while, Hancho came and drank the milk, and as a result, there were 0.3 liters (L) left. How many liters (L) of milk did Hancho drink?",
        "answer_ko": "0.30",
        "answer_en": "0.3",
        "solution_abst_ko": "1 0.1 [OP_SUB] 0.1 0.2 [OP_ADD] [OP_SUB] 0.3 [OP_SUB]",
        "solution_abst_en": "1 0.1 [OP_SUB] 0.1 0.2 [OP_ADD] [OP_SUB] 0.3 [OP_SUB]",
        "solution_code_ko": "var_a = 1\nvar_b = 0.1\nvar_c = var_a - var_b\nvar_d = 0.1\nvar_e = 0.2\nvar_f = var_d + var_e\nvar_g = var_c - var_f\nvar_h = 0.3\nvar_i = var_g - var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 0.1\nvar_c = var_a - var_b\nvar_d = 0.1\nvar_e = 0.2\nvar_f = var_d + var_e\nvar_g = var_c - var_f\nvar_h = 0.3\nvar_i = var_g - var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "1112": {
        "category": "Correspondence",
        "question_ko": "평균이 42인 10개의 자연수 중 한 수를 50으로 고치면 평균이 44가 된다고 한다. 고치기 전에 이 수는 얼마였는지 구하여라.",
        "question_en": "If one of the 10 natural numbers with an average of 42 is set to 50, the average is 44. Find what this number was before fixing it.",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "50 44 42 [OP_SUB] 10 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "50 44 42 [OP_SUB] 10 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 50\nvar_b = 44\nvar_c = 42\nvar_d = var_b - var_c\nvar_e = 10\nvar_f = var_d * var_e\nvar_g = var_a - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 50\nvar_b = 44\nvar_c = 42\nvar_d = var_b - var_c\nvar_e = 10\nvar_f = var_d * var_e\nvar_g = var_a - var_f\nprint(int(var_g))"
    },
    "1113": {
        "category": "Comparison",
        "question_ko": "22명의 사람들이 키가 큰 사람부터 순서대로 한 줄로 서 있습니다. 영철이는 뒤에서 13번째에 서 있을 때, 키가 작은 사람부터 줄을 서게 되면 영철이는 뒤에서 몇 번째에 서게 되는지 구하시오.",
        "question_en": "22 people stand in a line in descending order according to their heights. When Youngchul is the 13th person when counted from the back, where will Youngchul be, when counted from the back, when all the people line up in ascending order? Answer using an ordinal number.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "22 13 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "22 13 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 22\nvar_b = 13\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 22\nvar_b = 13\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "1114": {
        "category": "Correspondence",
        "question_ko": "A+B+B=814.8입니다. B의 소수점을 오른쪽으로 한 칸 옮기면 A와 같습니다. 소수점을 포함하여 A-B의 값을 구하시오.",
        "question_en": "A+B+B=814.8. When you move the decimal point of B one place to the right, it becomes equivalent to A. Calculate the value of A-B including the decimal point.",
        "answer_ko": "611.10",
        "answer_en": "611.1",
        "solution_abst_ko": "814.8 10 2 [OP_ADD] [OP_DIV] 10 [OP_MUL] 814.8 10 2 [OP_ADD] [OP_DIV] [OP_SUB]",
        "solution_abst_en": "814.8 10 2 [OP_ADD] [OP_DIV] 10 [OP_MUL] 814.8 10 2 [OP_ADD] [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 814.8\nvar_b = 10\nvar_c = 2\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nvar_f = 10\nvar_g = var_e * var_f\nvar_h = 814.8\nvar_i = 10\nvar_j = 2\nvar_k = var_i + var_j\nvar_l = var_h / var_k\nvar_m = var_g - var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))",
        "solution_code_en": "var_a = 814.8\nvar_b = 10\nvar_c = 2\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nvar_f = 10\nvar_g = var_e * var_f\nvar_h = 814.8\nvar_i = 10\nvar_j = 2\nvar_k = var_i + var_j\nvar_l = var_h / var_k\nvar_m = var_g - var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))"
    },
    "1115": {
        "category": "Arithmetic calculation",
        "question_ko": "두 자리 자연수 중에서 두 자리 모두 홀수이거나 두 자리 모두 짝수인 수는 몇 개입니까?",
        "question_en": "How many two-digit natural numbers have both odd digits or both even digits?",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "11 99 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] 2 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "11 99 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] 2 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 11\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_b=[]\nfor i in list_a:\n    var_d = 0\n    i = int(i)\n    while i//10 > 0:\n        var_d = var_d + i%10\n        i = i//10\n    var_d = var_d + i%10\n    list_b.append(var_d)\nvar_e = 2\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 11\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_b=[]\nfor i in list_a:\n    var_d = 0\n    i = int(i)\n    while i//10 > 0:\n        var_d = var_d + i%10\n        i = i//10\n    var_d = var_d + i%10\n    list_b.append(var_d)\nvar_e = 2\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "1116": {
        "category": "Arithmetic calculation",
        "question_ko": "교실 벽면에 유화가 9점, 수채화가 7점 붙어져 있습니다. 교실 벽면에 붙어져 있는 그림은 모두 몇 점입니까?",
        "question_en": "Nine oil paintings and seven watercolor paintings are pasted on the walls of the classroom. How many pictures are on the walls of the classroom?",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "9 7 [OP_ADD]",
        "solution_abst_en": "9 7 [OP_ADD]",
        "solution_code_ko": "var_a = 9\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 9\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "1117": {
        "category": "Correspondence",
        "question_ko": "영기는 가지고 있던 돈의 2/5보다 300원 많은 돈을 수지에게 주었고, 남은 돈의 1/2보다 200원 적은 돈을 저금했다. 남은돈이 800원이라면, 영기가 처음 가진 돈은 얼마인가?",
        "question_en": "Young-gi gave Suji 300 won more than 2/5 of the money he had, and saved 200 won less than 1/2 of the remaining money. If the remaining money is 800 won, how much money did Young-gi have at the beginning?",
        "answer_ko": "2500",
        "answer_en": "2500",
        "solution_abst_ko": "800 200 [OP_SUB] 1 1/2 [OP_SUB] [OP_DIV] 300 [OP_ADD] 1 2/5 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "800 200 [OP_SUB] 1 1/2 [OP_SUB] [OP_DIV] 300 [OP_ADD] 1 2/5 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 800\nvar_b = 200\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = 0.5\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 300\nvar_i = var_g + var_h\nvar_j = 1\nvar_k = 0.4\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 800\nvar_b = 200\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = 0.5\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 300\nvar_i = var_g + var_h\nvar_j = 1\nvar_k = 0.4\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nprint(int(var_m))"
    },
    "1118": {
        "category": "Possibility",
        "question_ko": "사과, 복숭아, 배, 참외, 딸기 중에서 2가지의 과일을 뽑아 줄을 세우려고 합니다. 가능한 경우의 수는 모두 몇 가지인가요?",
        "question_en": "We are trying to line up two fruits from among Apples, Peaches, Pears, Melons, and Strawberries. How many possible cases are there?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 복숭아 배 참외 딸기 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] Apples Peaches Pears Melons Strawberries [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '복숭아'\nvar_c = '배'\nvar_d = '참외'\nvar_e = '딸기'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nprint(int(var_h))",
        "solution_code_en": "var_a = 'Apples'\nvar_b = 'Peaches'\nvar_c = 'Pears'\nvar_d = 'Melons'\nvar_e = 'Strawberries'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nprint(int(var_h))"
    },
    "1119": {
        "category": "Correspondence",
        "question_ko": "어떤 수는 40을 8로 나눈 몫과 34을 12로 나눈 몫을 더한 값의 2배인 수입니다. 어떤 수를 구하세요.",
        "question_en": "There is a number that equals twice the sum of the quotient of 40 divided by 8 and the quotient of 34 divided by 12. Find this number. ",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "40 8 [OP_FDIV] 34 12 [OP_FDIV] [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "40 8 [OP_FDIV] 34 12 [OP_FDIV] [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 40\nvar_b = 8\nvar_c = var_a // var_b\nvar_d = 34\nvar_e = 12\nvar_f = var_d // var_e\nvar_g = var_c + var_f\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 40\nvar_b = 8\nvar_c = var_a // var_b\nvar_d = 34\nvar_e = 12\nvar_f = var_d // var_e\nvar_g = var_c + var_f\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "1120": {
        "category": "Arithmetic calculation",
        "question_ko": "1000 이하의 3의 배수 중 끝이 3으로 끝나는 수는 모두 몇 개인지 구하시오.",
        "question_en": "Find how many multiples of 3 ends in 3 that are less than 1000.",
        "answer_ko": "34",
        "answer_en": "34",
        "solution_abst_ko": "1 1000 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 1 3 [OP_LIST_SEARCH_FIXED_DIGIT] [OP_LIST_LEN]",
        "solution_abst_en": "1 1000 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 1 3 [OP_LIST_SEARCH_FIXED_DIGIT] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 1000\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 1\nvar_f = 3\nlist_c = [] \nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if (i//var_e)%10 == var_f:\n        list_c.append(i)\nvar_g = len(list_c)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 1000\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 1\nvar_f = 3\nlist_c = [] \nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if (i//var_e)%10 == var_f:\n        list_c.append(i)\nvar_g = len(list_c)\nprint(int(var_g))"
    },
    "1121": {
        "category": "Comparison",
        "question_ko": "학생들이 한 줄로 서 있습니다. 태형의 앞에는 아무도 없고 태형이와 남준이 사이에는 3명이 있습니다. 남준이 뒤에 8명이 서 있다면 줄을 서 있는 학생은 모두 몇 명입니까?",
        "question_en": "Students stand in a line. There is no one in front of Taehyung and there are three people between Taehyung and Namjoon. If 8 people are standing behind Namjoon, how many students are in the line?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "1 3 [OP_ADD] 1 [OP_ADD] 8 [OP_ADD]",
        "solution_abst_en": "1 3 [OP_ADD] 1 [OP_ADD] 8 [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "1122": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 1.9만큼 빼고 다시 1.5만큼 곱하고 32를 더했습니다. 마지막으로 어떤 수를 2.5로 나누었더니 20이 되었습니다. 소수점을 포함한 어떤 수는 얼마입니까?",
        "question_en": "A number is subtracted by 1.9, multiplied by 1.5, and added by 32. And finally, you divided it by 2.5 and you got 20. What is the number, including the decimal point?",
        "answer_ko": "13.90",
        "answer_en": "13.9",
        "solution_abst_ko": "20 2.5 [OP_MUL] 32 [OP_SUB] 1.5 [OP_DIV] 1.9 [OP_ADD]",
        "solution_abst_en": "20 2.5 [OP_MUL] 32 [OP_SUB] 1.5 [OP_DIV] 1.9 [OP_ADD]",
        "solution_code_ko": "var_a = 20\nvar_b = 2.5\nvar_c = var_a * var_b\nvar_d = 32\nvar_e = var_c - var_d\nvar_f = 1.5\nvar_g = var_e / var_f\nvar_h = 1.9\nvar_i = var_g + var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 20\nvar_b = 2.5\nvar_c = var_a * var_b\nvar_d = 32\nvar_e = var_c - var_d\nvar_f = 1.5\nvar_g = var_e / var_f\nvar_h = 1.9\nvar_i = var_g + var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "1123": {
        "category": "Possibility",
        "question_ko": "100이하인 짝수이면서 3의 배수인 수를 모두 종이에 적으면, 숫자 1을 몇 번 적어야 하는지 구하시오.",
        "question_en": "If you write down all the even numbers that are less than 100 and that are multiples of 3 on a piece of paper, how many times do you have to write down the figure '1'?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "1 100 [OP_LIST_EVEN] 3 [OP_LIST_DIVISIBLE] [OP_LIST2NUM] [OP_NUM2LIST] 1 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 100 [OP_LIST_EVEN] 3 [OP_LIST_DIVISIBLE] [OP_LIST2NUM] [OP_NUM2LIST] 1 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 100\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 3\nlist_b = []\nvar_c = int(var_c)\nfor i in list_a:\n    i = int(i)\n    if i % var_c == 0:\n        list_b.append(i)\nvar_d=\"\"\nfor i in list_b:\n    i = str(i)\n    var_d = var_d + i\nlist_c = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_c.append(var_d%10)\n    var_d = var_d//10\nlist_c.append(var_d%10)\nlist_c = list_c[::-1]\nvar_e = 1\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_c:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 100\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 3\nlist_b = []\nvar_c = int(var_c)\nfor i in list_a:\n    i = int(i)\n    if i % var_c == 0:\n        list_b.append(i)\nvar_d=\"\"\nfor i in list_b:\n    i = str(i)\n    var_d = var_d + i\nlist_c = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_c.append(var_d%10)\n    var_d = var_d//10\nlist_c.append(var_d%10)\nlist_c = list_c[::-1]\nvar_e = 1\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_c:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))"
    },
    "1124": {
        "category": "Geometry",
        "question_ko": "도화지에 지붕을 그렸을 때, 윗변의 길이가 아랫변의 길이보다 6 센티미터(㎝) 짧고, 높이가 8 센티미터(㎝)인 사다리꼴이라고 합니다. 지붕의 넓이가 72제곱센티미터(㎠)일 때, 이 지붕의 윗변의 길이를 구하시오.",
        "question_en": "When the roof is drawn on drawing paper, it is the trapezoid whose length of the upper side is 6 centimeters (cm) shorter than the length of the lower side, and the height is 8 centimeters (cm). If the area of the roof is 72 square centimeters (cm2), find the length of the upper side of the roof.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "72 2 [OP_MUL] 8 [OP_DIV] 6 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "72 2 [OP_MUL] 8 [OP_DIV] 6 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 72\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c / var_d\nvar_f = 6\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 72\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c / var_d\nvar_f = 6\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "1125": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 5를 곱하면 100이 됩니다. 10으로 어떤 수를 나누었을 때 결과값은 얼마인가요?",
        "question_en": "Multiply a number by 5 to get 100. What is the result when the number is divided by 10?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "100 5 [OP_DIV] 10 [OP_DIV]",
        "solution_abst_en": "100 5 [OP_DIV] 10 [OP_DIV]",
        "solution_code_ko": "var_a = 100\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 10\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 100\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 10\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "1126": {
        "category": "Correspondence",
        "question_ko": "민진이가 가진 사과 개수를 8로 나누었습니다. 선경이가 8개를 주었는데 봉건이가 30개를 빼앗아갔습니다. 남은 사과 개수에 6을 곱했더니 12개였다면, 처음 민진이가 가진 사과의 개수는 몇 개입니까?",
        "question_en": "The number of apples Minjin has is divided by 8. Seongyeong gave 8 to Minjin, but Bong-Geon took 30 of them. If the remaining number of apples is 12 when multiplied by 6, how many apples does Minjin have at the beginning?",
        "answer_ko": "192",
        "answer_en": "192",
        "solution_abst_ko": "12 6 [OP_DIV] 30 [OP_ADD] 8 [OP_SUB] 8 [OP_MUL]",
        "solution_abst_en": "12 6 [OP_DIV] 30 [OP_ADD] 8 [OP_SUB] 8 [OP_MUL]",
        "solution_code_ko": "var_a = 12\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 30\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e - var_f\nvar_h = 8\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 12\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 30\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e - var_f\nvar_h = 8\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "1127": {
        "category": "Possibility",
        "question_ko": "3개의 숫자 1, 7, 9가 주어져 있습니다. 주어진 숫자를 한 번씩 사용하여 만들 수 있는 두 자리 수는 모두 몇 개입니까?",
        "question_en": "You are given three numbers 1, 7, and 9. How many two-digit numbers can be formed using a given number once?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 1 7 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 7 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 7\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 7\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "1128": {
        "category": "Comparison",
        "question_ko": "호석이는 제기를 48번 찼습니다. 진수는 제기를 1번째와 2번째에 각각 15번씩 찼습니다. 진수가 호석이보다 제기를 더 많이 차려면 3번째에는 적어도 몇 번을 차야 합니까?",
        "question_en": "Hoseok kicked jegi 48 times. Jinsu kicked jegi 15 times each in the 1st and 2nd attempt. At least how many times should Jinsu kick jegi in the 3rd attempt, in order to kick more than Hoseok?",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "48 15 15 [OP_ADD] [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "48 15 15 [OP_ADD] [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 48\nvar_b = 15\nvar_c = 15\nvar_d = var_b + var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 48\nvar_b = 15\nvar_c = 15\nvar_d = var_b + var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "1129": {
        "category": "Possibility",
        "question_ko": "서로 다른 수 2개를 3, 5, 7, 8 중에서 뽑아 두 자리수를 만들려고 한다. 만들 수 있는 가장 큰 수와 가장 작은 수의 합은 몇인지 구하시오.",
        "question_en": "I am trying to make a two-digit number by picking two different numbers from 3, 5, 7, and 8. Find the sum of the largest and smallest possible numbers.",
        "answer_ko": "122",
        "answer_en": "122",
        "solution_abst_ko": "[OP_LIST_SOL] 3 5 7 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 3 5 7 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 5\nvar_c = 7\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 3\nvar_b = 5\nvar_c = 7\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))"
    },
    "1130": {
        "category": "Comparison",
        "question_ko": "5개의 숫자 5, 8, 4, 3, 2 중 2번째로 큰 수는 무엇인가요?",
        "question_en": "Which of the five numbers 5, 8, 4, 3, 2 is the second largest?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "[OP_LIST_SOL] 5 8 4 3 2 [OP_LIST_EOL] 2 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 5 8 4 3 2 [OP_LIST_EOL] 2 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 5\nvar_b = 8\nvar_c = 4\nvar_d = 3\nvar_e = 2\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 8\nvar_c = 4\nvar_d = 3\nvar_e = 2\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nprint(int(var_g))"
    },
    "1131": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 12미터(m)인 끈을 반으로 접고 한 번 더 반으로 접으면 길이는 몇 미터(m)가 됩니까?",
        "question_en": "How many meters (m) would it be if you fold a 12 meters (m) long string in half and then fold it in half again?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "12 2 [OP_DIV] 2 [OP_DIV]",
        "solution_abst_en": "12 2 [OP_DIV] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "1132": {
        "category": "Possibility",
        "question_ko": "2, 3, 7로 두 자리 자연수를 만들려고 한다. 만들 수 있는 수 중 두 번째로 작은 수를 구하시오.",
        "question_en": "You are trying to make two digit natural numbers with 2, 3, and 7. Find the second smallest possible number.",
        "answer_ko": "23",
        "answer_en": "23",
        "solution_abst_ko": "[OP_LIST_SOL] 2 3 7 [OP_LIST_EOL] 2 [OP_LIST_GET_PRODUCT] 2 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 2 3 7 [OP_LIST_EOL] 2 [OP_LIST_GET_PRODUCT] 2 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nprint(int(var_f))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nprint(int(var_f))"
    },
    "1133": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 69를 뺐더니 37이 되었습니다. 어떤 수에 55를 더하면 얼마가 되는지 구하시오.",
        "question_en": "Subtracting a number by 69 resulted in 37. Find the value of the result by adding 55 to the number.",
        "answer_ko": "161",
        "answer_en": "161",
        "solution_abst_ko": "69 37 [OP_ADD] 55 [OP_ADD]",
        "solution_abst_en": "69 37 [OP_ADD] 55 [OP_ADD]",
        "solution_code_ko": "var_a = 69\nvar_b = 37\nvar_c = var_a + var_b\nvar_d = 55\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 69\nvar_b = 37\nvar_c = var_a + var_b\nvar_d = 55\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "1134": {
        "category": "Comparison",
        "question_ko": "구슬을 민영이는 4개, 유정이는 2개 가지고 있습니다. 은지는 민영이보다 구슬을 1개 더 많이 가지고 있습니다. 구슬을 가장 많이 가지고 있는 사람은 누구입니까?",
        "question_en": "Minyoung has 4 marbles and Yujeong has 2. Eunji has 1 more marble than Minyoung. Who has the most marbles?",
        "answer_ko": "은지",
        "answer_en": "Eunji",
        "solution_abst_ko": "[OP_LIST_SOL] 민영 유정 은지 [OP_LIST_EOL] [OP_LIST_SOL] 4 2 4 1 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Minyoung Yujeong Eunji [OP_LIST_EOL] [OP_LIST_SOL] 4 2 4 1 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '민영'\nvar_b = '유정'\nvar_c = '은지'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 2\nvar_f = 4\nvar_g = 1\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Minyoung'\nvar_b = 'Yujeong'\nvar_c = 'Eunji'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 2\nvar_f = 4\nvar_g = 1\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "1135": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 숫자 85.9, 5.31, 43/2이 있습니다. 이들을 모두 더하면 얼마인가요?",
        "question_en": "There are three numbers 85.9, 5.31, and 43/2. What is the sum of them all?",
        "answer_ko": "112.71",
        "answer_en": "112.71",
        "solution_abst_ko": "85.9 5.31 [OP_ADD] 43/2 [OP_ADD]",
        "solution_abst_en": "85.9 5.31 [OP_ADD] 43/2 [OP_ADD]",
        "solution_code_ko": "var_a = 85.9\nvar_b = 5.31\nvar_c = var_a + var_b\nvar_d = 21.5\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 85.9\nvar_b = 5.31\nvar_c = var_a + var_b\nvar_d = 21.5\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "1136": {
        "category": "Comparison",
        "question_ko": "주리는 정우보다 큽니다. 명현이는 석진이보다 큽니다. 주리는 정국이보다 작습니다. 명현이는 정우보다 작습니다. 키가 가장 큰 사람은 누구입니까?",
        "question_en": "Juri is taller than Jungwoo. Myunghyun is taller than Seokjin. Juri is shorter than Jungkook. Myunghyun is shorter than Jungwoo. Who is the tallest?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 주리 정우 명현 석진 정국 [OP_LIST_EOL] [OP_LIST_SOL] 주리 정우 > 명현 석진 > 주리 정국 < 명현 정우 < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Juri Jungwoo Myunghyun Seokjin Jungkook [OP_LIST_EOL] [OP_LIST_SOL] Juri Jungwoo > Myunghyun Seokjin > Juri Jungkook < Myunghyun Jungwoo < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '주리'\nvar_b = '정우'\nvar_c = '명현'\nvar_d = '석진'\nvar_e = '정국'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = '주리'\nvar_g = '정우'\nvar_h = '>'\nvar_i = '명현'\nvar_j = '석진'\nvar_k = '>'\nvar_l = '주리'\nvar_m = '정국'\nvar_n = '<'\nvar_o = '명현'\nvar_p = '정우'\nvar_q = '<'\nlist_b= []\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_r = 1\nvar_s = list_c[var_r-1]\nprint(var_s)",
        "solution_code_en": "var_a = 'Juri'\nvar_b = 'Jungwoo'\nvar_c = 'Myunghyun'\nvar_d = 'Seokjin'\nvar_e = 'Jungkook'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 'Juri'\nvar_g = 'Jungwoo'\nvar_h = '>'\nvar_i = 'Myunghyun'\nvar_j = 'Seokjin'\nvar_k = '>'\nvar_l = 'Juri'\nvar_m = 'Jungkook'\nvar_n = '<'\nvar_o = 'Myunghyun'\nvar_p = 'Jungwoo'\nvar_q = '<'\nlist_b= []\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_r = 1\nvar_s = list_c[var_r-1]\nprint(var_s)"
    },
    "1137": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 가장 작은 수와 2번째로 작은 수로 나눈 몫은 얼마입니까?",
        "question_en": "There are five numbers 10, 11, 12, 13, and 14. What is the quotient of the smallest number divided by the second smallest number?",
        "answer_ko": "0",
        "answer_en": "0",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_FDIV]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_FDIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g // var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g // var_i\nprint(int(var_j))"
    },
    "1138": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 자연수 4, 6, 8, 9 중 3개를 골라 세 자리 자연수를 만들었다. 이 중 500보다 작은 것은 몇 개인가?",
        "question_en": "3 out of the 4 natural numbers 4, 6, 8, and 9 were chosen to form a three-digit natural number. How many of these are less than 500?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 4 6 8 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 500 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 4 6 8 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 500 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 4\nvar_b = 6\nvar_c = 8\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 500\nlist_c = []\nfor i in list_b:\n    if i < var_f:\n        list_c.append(i)\nvar_g = len(list_c)\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 6\nvar_c = 8\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 500\nlist_c = []\nfor i in list_b:\n    if i < var_f:\n        list_c.append(i)\nvar_g = len(list_c)\nprint(int(var_g))"
    },
    "1139": {
        "category": "Comparison",
        "question_ko": "윤기와 지수는 자전거를 탔습니다. 같은 곳에서 출발하여 지수는 1시간동안 19000미터(m)를 달렸고 윤기는 1시간동안 22킬로미터(㎞)를 달렸습니다. 이때 더 많이 이동한 사람은 누구입니까?",
        "question_en": "Yoongi and Jisoo rode bicycles. Starting from the same place, Jisoo ran 19,000 meters (m) in an hour and Yoongi ran 22 kilometers (km) in an hour. Who moved more in an hour?",
        "answer_ko": "윤기",
        "answer_en": "Yoongi",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 지수 [OP_LIST_EOL] [OP_LIST_SOL] 22 1000 [OP_MUL] 19000 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jisoo [OP_LIST_EOL] [OP_LIST_SOL] 22 1000 [OP_MUL] 19000 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '지수'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 22\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 19000\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jisoo'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 22\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 19000\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "1140": {
        "category": "Comparison",
        "question_ko": "1반과 2반이 우승 상품으로 받은 구슬 1000개를 나누어 가졌습니다. 이 때, 2반이 1반보다 50개를 덜 가져갔고, 2반 남학생들이 2반 여학생보다 총 35개를 더 가져갔습니다. 2반 남학생이 17명이고 남학생들끼리는 똑같이 나누어 가질 때, 2반 남학생 한 명이 받는 구슬의 개수는 얼마입니까?",
        "question_en": "Classes 1 and 2 shared the 1000 marbles they received as prizes. At this time, class 2 took 50 less than class 1, and male students in class 2 took a total of 35 more than female students in class 2. If there are 17 boys in class 2 and the boys share equally, how many marbles will each boy in class 2 receive?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "1000 50 [OP_SUB] 2 [OP_DIV] 35 [OP_SUB] 2 [OP_DIV] 35 [OP_ADD] 17 [OP_DIV]",
        "solution_abst_en": "1000 50 [OP_SUB] 2 [OP_DIV] 35 [OP_SUB] 2 [OP_DIV] 35 [OP_ADD] 17 [OP_DIV]",
        "solution_code_ko": "var_a = 1000\nvar_b = 50\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 35\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nvar_j = 35\nvar_k = var_i + var_j\nvar_l = 17\nvar_m = var_k / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 1000\nvar_b = 50\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 35\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nvar_j = 35\nvar_k = var_i + var_j\nvar_l = 17\nvar_m = var_k / var_l\nprint(int(var_m))"
    },
    "1141": {
        "category": "Possibility",
        "question_ko": "정국, 지민, 석진, 유나가 한 줄로 서서 사진을 찍을 때 서로 다르게 서는 방법은 모두 몇 가지입니까?",
        "question_en": "How many different ways are there for Jungkook, Jimin, Seokjin, and Yuna to stand in a line and take a picture?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 지민 석진 유나 [OP_LIST_EOL] [OP_LIST_LEN] 4 [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Jimin Seokjin Yuna [OP_LIST_EOL] [OP_LIST_LEN] 4 [OP_PERM]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '지민'\nvar_c = '석진'\nvar_d = '유나'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 4\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nprint(int(var_g))",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Jimin'\nvar_c = 'Seokjin'\nvar_d = 'Yuna'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 4\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nprint(int(var_g))"
    },
    "1142": {
        "category": "Geometry",
        "question_ko": "어떤 직사각형의 둘레의 길이는 46센티미터(㎝)이고, 가로의 길이가 세로의 길이보다 7센티미터(㎝)더 길다고 한다. 이 직사각형의 가로의 길이는?",
        "question_en": "The perimeter of a rectangle is 46 centimeters (cm), and its width is 7 centimeters (cm) longer than its length. What is the width of this rectangle?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "46 2 [OP_DIV] 7 [OP_SUB] 2 [OP_DIV] 7 [OP_ADD]",
        "solution_abst_en": "46 2 [OP_DIV] 7 [OP_SUB] 2 [OP_DIV] 7 [OP_ADD]",
        "solution_code_ko": "var_a = 46\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 7\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 46\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 7\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "1143": {
        "category": "Arithmetic calculation",
        "question_ko": "1킬로미터(㎞) 500미터(m)인 도로에 30미터(m) 간격으로 깃발을 설치하려고 합니다. 깃발 하나의 가격이 5000원일 때, 필요한 깃발을 사는데 드는 비용은 얼마인가요?",
        "question_en": "You would like to install flags at intervals of 30 meters (m) on a road that is 1 kilometer (km) and 500 meters (m) long. If the price of one flag is 5,000 won, how much does it cost to buy the required flag?",
        "answer_ko": "250000",
        "answer_en": "250000",
        "solution_abst_ko": "1 1000 [OP_MUL] 500 [OP_ADD] 30 [OP_DIV] 5000 [OP_MUL]",
        "solution_abst_en": "1 1000 [OP_MUL] 500 [OP_ADD] 30 [OP_DIV] 5000 [OP_MUL]",
        "solution_code_ko": "var_a = 1\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 500\nvar_e = var_c + var_d\nvar_f = 30\nvar_g = var_e / var_f\nvar_h = 5000\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 500\nvar_e = var_c + var_d\nvar_f = 30\nvar_g = var_e / var_f\nvar_h = 5000\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "1144": {
        "category": "Arithmetic calculation",
        "question_ko": "무게가 같은 생선이 가득 담긴 통의 무게를 재었더니 54킬로그램(㎏)이었습니다. 절반의 생선을 덜어낸 후 통의 무게를 재어보니 29킬로그램(㎏)이었습니다. 처음 있던 물고기만의 무게는 몇 킬로그램(㎏)입니까?",
        "question_en": "When you weighed a barrel full of fish of the same weight, it was 54 kilograms (kg). Then the barrel weighed 29 kilograms (kg) after being removed of the half of fish. What is the weight of fish that was in the barrel at first in kilograms (kg)?",
        "answer_ko": "50",
        "answer_en": "50",
        "solution_abst_ko": "54 29 [OP_SUB] 2 [OP_MUL]",
        "solution_abst_en": "54 29 [OP_SUB] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 54\nvar_b = 29\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 54\nvar_b = 29\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "1145": {
        "category": "Possibility",
        "question_ko": "배구 선수 7명 중에서 선발로 출전할 선수 6명을 뽑으려고 한다. 가능한 모든 경우의 수를 구하시오.",
        "question_en": "Out of 7 volleyball players, we are trying to select 6 players to start. Find the number of all possible cases.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "7 6 [OP_COMB]",
        "solution_abst_en": "7 6 [OP_COMB]",
        "solution_code_ko": "var_a = 7\nvar_b = 6\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))",
        "solution_code_en": "var_a = 7\nvar_b = 6\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))"
    },
    "1146": {
        "category": "Arithmetic calculation",
        "question_ko": "유나는 올해 8살입니다. 아버지는 유나보다 20살 더 많고, 할아버지는 아버지보다 25살 더 많습니다. 올해 할아버지의 나이는 몇 살입니까?",
        "question_en": "Yuna is 8 years old this year. Her father is 20 years older than Yuna, and her grandfather is 25 years older than her father. How old is her grandfather this year?",
        "answer_ko": "53",
        "answer_en": "53",
        "solution_abst_ko": "8 20 [OP_ADD] 25 [OP_ADD]",
        "solution_abst_en": "8 20 [OP_ADD] 25 [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 20\nvar_c = var_a + var_b\nvar_d = 25\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 20\nvar_c = var_a + var_b\nvar_d = 25\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "1147": {
        "category": "Geometry",
        "question_ko": "가로의 길이가 20센티미터(㎝)인 직사각형의 네 변의 길이의 합이 한 변의 길이가 10센티미터(㎝)인 정오각형의 둘레의 길이와 똑같았습니다. 이 직사각형의 세로 길이는 얼마인지 알아보시오.",
        "question_en": "The sum of the lengths of the four sides of a rectangle with a width of 20 cm (cm) is equal to the perimeter of a regular pentagon with a side length of 10 cm (cm). Find out what the length of this rectangle is.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "10 5 [OP_MUL] 2 [OP_DIV] 20 [OP_SUB]",
        "solution_abst_en": "10 5 [OP_MUL] 2 [OP_DIV] 20 [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 20\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 10\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 20\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "1148": {
        "category": "Arithmetic calculation",
        "question_ko": "연필 한 자루와 공책 한 권의 값의 합은 950원입니다. 공책이 연필보다 150원 비싸다면 연필은 얼마입니까?",
        "question_en": "The sum of the price of a pencil and a notebook is 950 won. If a notebook costs 150 won more than a pencil, how much is the pencil?",
        "answer_ko": "400",
        "answer_en": "400",
        "solution_abst_ko": "950 150 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "950 150 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 950\nvar_b = 150\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 950\nvar_b = 150\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "1149": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 7/3을 더해야 할 것을 잘못하여 빼었더니 3/2이 되었습니다. 바르게 계산하면 얼마인지 구하시오.",
        "question_en": "You mistakenly subtracted 7/3 from a number instead of adding it, so you got 3/2 as a result. How much is it if you calculate it correctly?",
        "answer_ko": "6.17",
        "answer_en": "6.17",
        "solution_abst_ko": "3/2 7/3 [OP_ADD] 7/3 [OP_ADD]",
        "solution_abst_en": "3/2 7/3 [OP_ADD] 7/3 [OP_ADD]",
        "solution_code_ko": "var_a = 1.5\nvar_b = 2.3333333333333335\nvar_c = var_a + var_b\nvar_d = 2.3333333333333335\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 1.5\nvar_b = 2.3333333333333335\nvar_c = var_a + var_b\nvar_d = 2.3333333333333335\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "1150": {
        "category": "Possibility",
        "question_ko": "0, 2, 4를 이용해, 만들 수 있는 수 중 각 자리수가 모두 다른 세 자리 자연수는 몇 가지입니까?",
        "question_en": "When 0, 2, and 4 are used once to make three-digit numbers, how many three-digit numbers can be formed?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 0 2 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 2 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 2\nvar_c = 4\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 0\nvar_b = 2\nvar_c = 4\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "1151": {
        "category": "Arithmetic calculation",
        "question_ko": "배구공 9개 중 5개를 다른 학교에 빌려주었을 때, 남아 있는 배구공의 수는?",
        "question_en": "If 5 out of 9 volleyballs are lent to other schools, what is the number of volleyballs left?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "9 5 [OP_SUB]",
        "solution_abst_en": "9 5 [OP_SUB]",
        "solution_code_ko": "var_a = 9\nvar_b = 5\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 9\nvar_b = 5\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "1152": {
        "category": "Comparison",
        "question_ko": "1.4, 9/10, 1.2, 0.5, 13/10 5개 숫자 중에서 1.1보다 크거나 같은 숫자는 모두 몇 개입니까?",
        "question_en": "Of the five numbers 1.4, 9/10, 1.2, 0.5, and 13/10, how many are greater than or equal to 1.1?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i >= var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i >= var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "1153": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.3 중 0.4보다 작거나 같은 수의 개수를 구하시오.",
        "question_en": "Find the number of numbers less than or equal to 0.4 among 0.8, 1/2, and 0.3.",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.3 [OP_LIST_EOL] 0.4 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.3 [OP_LIST_EOL] 0.4 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.4\nlist_b = []\nfor i in list_a:\n    if i <= var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.4\nlist_b = []\nfor i in list_a:\n    if i <= var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "1154": {
        "category": "Arithmetic calculation",
        "question_ko": "경초는 등교하는 100일 중 11일을 걸어서 학교에 가고 다른 날에는 날은 버스를 타고 학교에 갔습니다. 경초가 걸어서 학교에 간 날은 전체 등교일의 몇 배입니까?",
        "question_en": "Gyungcho walked to school on 11 days out of 100 days and took a bus on other days. How many times is the day he went to school on foot compared to the entire day he went to school?",
        "answer_ko": "0.11",
        "answer_en": "0.11",
        "solution_abst_ko": "11 100 [OP_DIV]",
        "solution_abst_en": "11 100 [OP_DIV]",
        "solution_code_ko": "var_a = 11\nvar_b = 100\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 11\nvar_b = 100\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "1155": {
        "category": "Comparison",
        "question_ko": "윤기는 4개, 정국이는 6 나누기 3만큼 사과를 가졌습니다. 누가 더 사과가 적습니까?",
        "question_en": "Yoongi has 4 apples and Jungkook has 6 divided by 3 apples. Who has fewer apples?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_FDIV] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_FDIV] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 6\nvar_e = 3\nvar_f = var_d // var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 6\nvar_e = 3\nvar_f = var_d // var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "1156": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 5를 곱한 뒤 8로 나누었더니 몫이 156이고 나머지가 2였습니다. 어떤 수를 구하시오.",
        "question_en": "When a number is multiplied by 5 and then divided by 8, the quotient is 156 and the remainder is 2. Find a number.",
        "answer_ko": "250",
        "answer_en": "250",
        "solution_abst_ko": "156 8 [OP_MUL] 2 [OP_ADD] 5 [OP_DIV]",
        "solution_abst_en": "156 8 [OP_MUL] 2 [OP_ADD] 5 [OP_DIV]",
        "solution_code_ko": "var_a = 156\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 156\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "1157": {
        "category": "Geometry",
        "question_ko": "밑면의 가로 길이가 70센티미터(㎝)이고, 세로 길이가 40센티미터(㎝)이며, 높이가 150센티미터(㎝)인 직육면체 모양의 장식장보다 부피가 204000세제곱센티미터(㎤) 더 적은 장식장의 한 모서리의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "How many centimeters (cm) is one edge of a cube-shaped cabinet the volume of which is 204,000 cubic centimeters (cm3) smaller than the volume of a rectangular cuboid-shaped cabinet with a base width of 70 centimeters (cm), a base length of 40 centimeters (cm), and a height of 150 centimeters (cm)?",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "70 40 [OP_MUL] 150 [OP_MUL] 204000 [OP_SUB] 1/3 [OP_POW]",
        "solution_abst_en": "70 40 [OP_MUL] 150 [OP_MUL] 204000 [OP_SUB] 1/3 [OP_POW]",
        "solution_code_ko": "var_a = 70\nvar_b = 40\nvar_c = var_a * var_b\nvar_d = 150\nvar_e = var_c * var_d\nvar_f = 204000\nvar_g = var_e - var_f\nvar_h = 0.3333333333333333\nvar_i = var_g ** var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))",
        "solution_code_en": "var_a = 70\nvar_b = 40\nvar_c = var_a * var_b\nvar_d = 150\nvar_e = var_c * var_d\nvar_f = 204000\nvar_g = var_e - var_f\nvar_h = 0.3333333333333333\nvar_i = var_g ** var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))"
    },
    "1158": {
        "category": "Geometry",
        "question_ko": "직사각형의 가로의 길이가 세로의 길이보다 3 센티미터(㎝) 더 길다. 직사각형의 둘레의 길이가 54 센티미터(㎝)일 때, 가로의 길이는 무엇인가?",
        "question_en": "The width of the rectangle is 3 centimeters (cm) longer than the length of the rectangle. If the perimeter of the rectangle is 54 centimeters (cm), what is the length of its width?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "54 2 [OP_DIV] 3 [OP_SUB] 2 [OP_DIV] 3 [OP_ADD]",
        "solution_abst_en": "54 2 [OP_DIV] 3 [OP_SUB] 2 [OP_DIV] 3 [OP_ADD]",
        "solution_code_ko": "var_a = 54\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 3\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 3\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 54\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 3\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 3\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "1159": {
        "category": "Comparison",
        "question_ko": "정국, 태형, 민영 3명의 학생이 달리기 시합을 하였습니다. 정국이가 가장 먼저 결승선에 도착하고 그 다음 민영, 태형이가 차례로 도착하였습니다. 태형이는 몇 등입니까?",
        "question_en": "Jungkook, Taehyung, and Minyoung had a running race. Jungkook arrived at the finish line first, followed by Minyoung and Taehyung. What rank does Taehyung in?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 민영 태형 [OP_LIST_EOL] 태형 [OP_LIST_INDEX]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Minyoung Taehyung [OP_LIST_EOL] Taehyung [OP_LIST_INDEX]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '민영'\nvar_c = '태형'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '태형'\nvar_e = list_a.index(var_d)+1\nprint(int(var_e))",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Minyoung'\nvar_c = 'Taehyung'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'Taehyung'\nvar_e = list_a.index(var_d)+1\nprint(int(var_e))"
    },
    "1160": {
        "category": "Geometry",
        "question_ko": "평행사변형 모양의 의자가 있다. 한 변은 18센티미터(㎝), 다른 한 변은 12센티미터(㎝)이다. 이 의자의 둘레는?",
        "question_en": "There is a chair in the shape of a parallelogram. One side is 18 centimeters (cm) and the other side is 12 centimeters (cm). What is the circumference of this chair?",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "18 12 [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "18 12 [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 18\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 18\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "1161": {
        "category": "Correspondence",
        "question_ko": "6A35를 버림하여 백의 자리까지 나타내면 6100이 됩니다. A를 구하시오.",
        "question_en": "Rounding down 6A35 to the nearest hundreds gives 6100. Find A.",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "6A35 [OP_GEN_POSSIBLE_LIST] 6100 [OP_LIST_MORE_EQUAL] 6100 100 [OP_ADD] [OP_LIST_LESS] 6A35 A [OP_LIST_FIND_UNK]",
        "solution_abst_en": "6A35 [OP_GEN_POSSIBLE_LIST] 6100 [OP_LIST_MORE_EQUAL] 6100 100 [OP_ADD] [OP_LIST_LESS] 6A35 A [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = '6A35'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 6100\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 6100\nvar_d = 100\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = '6A35'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))",
        "solution_code_en": "var_a = '6A35'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 6100\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 6100\nvar_d = 100\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = '6A35'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))"
    },
    "1162": {
        "category": "Comparison",
        "question_ko": "빵을 민영이는 13개, 은지는 21개 가지고 있습니다. 빵을 더 많이 가지고 있는 사람은 누구입니까?",
        "question_en": "Minyoung has 13 breads and Eunji has 21. Who has more bread?",
        "answer_ko": "은지",
        "answer_en": "Eunji",
        "solution_abst_ko": "[OP_LIST_SOL] 민영 은지 [OP_LIST_EOL] [OP_LIST_SOL] 13 21 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Minyoung Eunji [OP_LIST_EOL] [OP_LIST_SOL] 13 21 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '민영'\nvar_b = '은지'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 13\nvar_d = 21\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Minyoung'\nvar_b = 'Eunji'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 13\nvar_d = 21\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "1163": {
        "category": "Arithmetic calculation",
        "question_ko": "물이 2180리터(L)있습니다. 200리터(L)짜리 통과 150리터(L)짜리 통이 총 12개 있습니다. 물을 전부 나누어 담았더니 30리터(L)가 남았습니다. 200리터(L)짜리 통은 몇 개 있나요?",
        "question_en": "There are 2180 liters (L) of water. There are a total of 12 200 liters (L) barrels and 150 liters (L) barrels. When all the water was divided, 30 liters (L) remained. How many 200-liter (L) barrels are there?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "2180 30 [OP_SUB] 150 12 [OP_MUL] [OP_SUB] 200 150 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "2180 30 [OP_SUB] 150 12 [OP_MUL] [OP_SUB] 200 150 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 2180\nvar_b = 30\nvar_c = var_a - var_b\nvar_d = 150\nvar_e = 12\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 200\nvar_i = 150\nvar_j = var_h - var_i\nvar_k = var_g / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 2180\nvar_b = 30\nvar_c = var_a - var_b\nvar_d = 150\nvar_e = 12\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 200\nvar_i = 150\nvar_j = var_h - var_i\nvar_k = var_g / var_j\nprint(int(var_k))"
    },
    "1164": {
        "category": "Possibility",
        "question_ko": "숫자 카드 2, 0, 3, 5, 8 을 이용하여 만들 수 있는 네 자리 수 중에서 가장 큰 수와 가장 작은 수의 차를 구하시오.",
        "question_en": "Find the difference between the largest and smallest four-digit numbers that can be made using the number cards 2, 0, 3, 5, and 8.",
        "answer_ko": "6497",
        "answer_en": "6497",
        "solution_abst_ko": "[OP_LIST_SOL] 2 0 3 5 8 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 2 0 3 5 8 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 2\nvar_b = 0\nvar_c = 3\nvar_d = 5\nvar_e = 8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 2\nvar_b = 0\nvar_c = 3\nvar_d = 5\nvar_e = 8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h - var_j\nprint(int(var_k))"
    },
    "1165": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.3, 1/3 중 0.4보다 큰 수의 총합은?",
        "question_en": "What is the sum of the numbers greater than 0.4 among 0.8, 1/2, 0.3, and 1/3?",
        "answer_ko": "1.30",
        "answer_en": "1.3",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.3 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_MORE] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.3 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_MORE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.3\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.4\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint('{:.2f}'.format(round(var_f+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.3\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.4\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint('{:.2f}'.format(round(var_f+1e-10,2)))"
    },
    "1166": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 인형 공장에서는 1시간에 평균 18개의 인형을 만든다고 한다. 이 공장에서 하루에 8시간씩 25일 동안 만든 인형을 1개에 2750원 받고 판다면 인형을 판 돈은 모두 얼마인가?",
        "question_en": "It is said that one doll factory makes an average of 18 dolls per hour. If you sell dolls that were made in this factory for 25 days with 8 hours a day, for 2,750 won for each doll, how much money can you get from selling all the dolls?",
        "answer_ko": "9900000",
        "answer_en": "9900000",
        "solution_abst_ko": "18 8 [OP_MUL] 25 [OP_MUL] 2750 [OP_MUL]",
        "solution_abst_en": "18 8 [OP_MUL] 25 [OP_MUL] 2750 [OP_MUL]",
        "solution_code_ko": "var_a = 18\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 25\nvar_e = var_c * var_d\nvar_f = 2750\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 18\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 25\nvar_e = var_c * var_d\nvar_f = 2750\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "1167": {
        "category": "Arithmetic calculation",
        "question_ko": "100미터(m) 길이의 도로에 10미터(m) 간격으로 나무를 심으려고 합니다. 도로의 처음과 끝에도 나무를 심는다고 할 때, 도로 양쪽에 심는다면 몇 그루가 필요합니까?",
        "question_en": "You want to plant trees at intervals of 10 meters (m) on a 100-meter (m) long road. If trees are to be planted at the beginning and end of the road, how many trees are needed if they are planted on both sides of the road?",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "100 10 [OP_DIV] 1 [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "100 10 [OP_DIV] 1 [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 100\nvar_b = 10\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 100\nvar_b = 10\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "1168": {
        "category": "Arithmetic calculation",
        "question_ko": "십의 자리 숫자가 3인 두 자리 자연수 중, 십의 자리와 일의 자리 숫자를 바꾸었을 때 처음 수가 바꾼 수에다가 9를 더한 값과 같았다. 처음 수는 무엇인가?",
        "question_en": "In a two-digit natural number whose tens digit is 3, when the tens and ones digits are switched, the first number is the same as adding 9 to the switched number. What is the original number?",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "3 10 [OP_MUL] 9 [OP_SUB] 3 [OP_SUB] 10 1 [OP_SUB] [OP_DIV] 3 10 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "3 10 [OP_MUL] 9 [OP_SUB] 3 [OP_SUB] 10 1 [OP_SUB] [OP_DIV] 3 10 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = var_e - var_f\nvar_h = 10\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_g / var_j\nvar_l = 3\nvar_m = 10\nvar_n = var_l * var_m\nvar_o = var_k + var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 3\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = var_e - var_f\nvar_h = 10\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_g / var_j\nvar_l = 3\nvar_m = 10\nvar_n = var_l * var_m\nvar_o = var_k + var_n\nprint(int(var_o))"
    },
    "1169": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.3, 1/3 중 0.4보다 작거나 같은 수의 총합은?",
        "question_en": "What is the total of numbers less than or equal to 0.4 among 0.8, 1/2, 0.3, and 1/3?",
        "answer_ko": "0.63",
        "answer_en": "0.63",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.3 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_LESS_EQUAL] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.3 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_LESS_EQUAL] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.3\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.4\nlist_b = []\nfor i in list_a:\n    if i <= var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint('{:.2f}'.format(round(var_f+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.3\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.4\nlist_b = []\nfor i in list_a:\n    if i <= var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint('{:.2f}'.format(round(var_f+1e-10,2)))"
    },
    "1170": {
        "category": "Comparison",
        "question_ko": "정국이의 앞에 2명이 서 있고, 정국이의 뒤에 4명이 서있습니다. 정국이의 줄에 8명이 있고, 각 줄에 서 있는 사람의 수가 같다면, 총 몇 명이 서 있습니까?",
        "question_en": "Two people are standing in front of Jungkook, and four people are standing behind him. If there are 8 people in Jungkook's line and there are the same number of people in each line, how many people are there in total?",
        "answer_ko": "56",
        "answer_en": "56",
        "solution_abst_ko": "2 4 [OP_ADD] 1 [OP_ADD] 8 [OP_MUL]",
        "solution_abst_en": "2 4 [OP_ADD] 1 [OP_ADD] 8 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "1171": {
        "category": "Geometry",
        "question_ko": "한 모서리의 길이가 9센티미터(㎝)인 정육면체가 있습니다. 각 모서리의 중간에서 한 모서리의 길이가 3센티미터(㎝)인 정육면체를 잘랐을 때, 남은 부분의 부피는 몇 세제곱센티미터입니까?",
        "question_en": "There is a cube with one edge 9 centimeters (cm) long. If you cut a cube from the middle of each edge with one edge 3 centimeters (cm) long, what is the volume in cubic centimeters (cm3) of the remaining part?",
        "answer_ko": "702",
        "answer_en": "702",
        "solution_abst_ko": "9 3 [OP_POW] 3 3 [OP_POW] [OP_SUB]",
        "solution_abst_en": "9 3 [OP_POW] 3 3 [OP_POW] [OP_SUB]",
        "solution_code_ko": "var_a = 9\nvar_b = 3\nvar_c = var_a ** var_b\nvar_d = 3\nvar_e = 3\nvar_f = var_d ** var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 9\nvar_b = 3\nvar_c = var_a ** var_b\nvar_d = 3\nvar_e = 3\nvar_f = var_d ** var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "1172": {
        "category": "Comparison",
        "question_ko": "동굴 속에서 원 모양의 보석 2개를 발견했다. A 보석은 지름이 10센티미터(㎝)이고, 다른 B 보석은 반지름이 4센티미터(㎝)이다. 크기가 큰 쪽이 더 비싸다. 더 비싼 것을 들고 가려고 한다면 무엇을 들고 가야하는가?",
        "question_en": "You found two round-shaped jewels in the cave. A gem A is 10 centimeters (cm) in diameter, and the other gem B is 4 centimeters (cm) in radius. The larger size is more expensive. If you're going to bring something more expensive, what should you bring?",
        "answer_ko": "A",
        "answer_en": "A",
        "solution_abst_ko": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 10 2 [OP_DIV] 4 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 10 2 [OP_DIV] 4 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 4\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 4\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "1173": {
        "category": "Geometry",
        "question_ko": "이등변삼각형이 있습니다. 꼭지각의 이등분선을 그었더니, 밑변의 길이가 4 센티미터(㎝)로 나누어졌습니다. 밑변의 길이는 몇 센티미터(㎝)일까요?",
        "question_en": "There is an isosceles triangle. When the bisector of the vertical angle is drawn, the length of the base is divided by 4 centimeters (cm). What is the length of the base in centimeters (cm) ?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "4 2 [OP_MUL]",
        "solution_abst_en": "4 2 [OP_MUL]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "1174": {
        "category": "Correspondence",
        "question_ko": "954에 어떤 수를 더해야 할 것을 잘못하여 뺐더니 468이 되었습니다. 바르게 계산하면 얼마인지 구해 보시오.",
        "question_en": "I mistakenly subtracted a certain number from 954 instead of adding, and I got 468. Find out how much it is if you calculate it correctly.",
        "answer_ko": "1440",
        "answer_en": "1440",
        "solution_abst_ko": "954 468 [OP_SUB] 954 [OP_ADD]",
        "solution_abst_en": "954 468 [OP_SUB] 954 [OP_ADD]",
        "solution_code_ko": "var_a = 954\nvar_b = 468\nvar_c = var_a - var_b\nvar_d = 954\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 954\nvar_b = 468\nvar_c = var_a - var_b\nvar_d = 954\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "1175": {
        "category": "Comparison",
        "question_ko": "정국이, 호석이, 석진이는 색종이를 나누어 가졌습니다. 정국이가 10장, 호석이가 7장을 가져가고, 석진이는 정국이보다 2장 덜 가져갔습니다. 세 명 중에서 색종이를 가장 적게 가져간 사람은 누구입니까?",
        "question_en": "Jungkook, Hoseok, and Seokjin shared colored paper. Jungkook took 10 cards, Hoseok took 7, and Seokjin took 2 less than Jungkook. Which of the three people took the fewest pieces of colored paper?",
        "answer_ko": "호석",
        "answer_en": "Hoseok",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 호석 석진 [OP_LIST_EOL] [OP_LIST_SOL] 10 7 10 2 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Hoseok Seokjin [OP_LIST_EOL] [OP_LIST_SOL] 10 7 10 2 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '호석'\nvar_c = '석진'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 10\nvar_e = 7\nvar_f = 10\nvar_g = 2\nvar_h = var_f - var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Hoseok'\nvar_c = 'Seokjin'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 10\nvar_e = 7\nvar_f = 10\nvar_g = 2\nvar_h = var_f - var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "1176": {
        "category": "Arithmetic calculation",
        "question_ko": "12로 나누면 몫이 25이고 나머지가 11이 되는 어떤 수가 있습니다. 25와 어떤 수의 차는 얼마입니까?",
        "question_en": "There is a certain number that, when divided by 12, have a quotient of 25 and a remainder of 11. What is the difference between 25 and the number?",
        "answer_ko": "286",
        "answer_en": "286",
        "solution_abst_ko": "12 25 [OP_MUL] 11 [OP_ADD] 25 [OP_SUB]",
        "solution_abst_en": "12 25 [OP_MUL] 11 [OP_ADD] 25 [OP_SUB]",
        "solution_code_ko": "var_a = 12\nvar_b = 25\nvar_c = var_a * var_b\nvar_d = 11\nvar_e = var_c + var_d\nvar_f = 25\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 12\nvar_b = 25\nvar_c = var_a * var_b\nvar_d = 11\nvar_e = var_c + var_d\nvar_f = 25\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "1177": {
        "category": "Arithmetic calculation",
        "question_ko": "아버지의 나이는 12년 후에 딸의 나이의 2배가 되고, 현재는 3배이다. 올해 딸의 나이는 얼마인가?",
        "question_en": "The father's age will double the daughter's age in 12 years and is now triple. How old is the daughter this year?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "12 2 [OP_MUL] 12 [OP_SUB] 3 2 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "12 2 [OP_MUL] 12 [OP_SUB] 3 2 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = 2\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 12\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = 2\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "1178": {
        "category": "Possibility",
        "question_ko": "3, 9, 6, 0, 5, 1, 7 위 숫자들을 한 번씩만 사용하여 7자리 수를 만들려고 한다. 만들 수 있는 모든 경우의 수에서 가장 큰 수와 가장 작은 수의 차는 얼마인가?",
        "question_en": "You want to make a 7-digit number using the numbers 3, 9, 6, 0, 5, 1, and 7 only once. What is the difference between the largest and smallest number in all possible numbers?",
        "answer_ko": "8729631",
        "answer_en": "8729631",
        "solution_abst_ko": "[OP_LIST_SOL] 3 9 6 0 5 1 7 [OP_LIST_EOL] 7 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 3 9 6 0 5 1 7 [OP_LIST_EOL] 7 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 3\nvar_b = 9\nvar_c = 6\nvar_d = 0\nvar_e = 5\nvar_f = 1\nvar_g = 7\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h = 7\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_h))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_l = list_d[var_k-1]\nvar_m = var_j - var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 3\nvar_b = 9\nvar_c = 6\nvar_d = 0\nvar_e = 5\nvar_f = 1\nvar_g = 7\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h = 7\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_h))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_l = list_d[var_k-1]\nvar_m = var_j - var_l\nprint(int(var_m))"
    },
    "1179": {
        "category": "Arithmetic calculation",
        "question_ko": "9대의 자동차에 63명이 똑같이 탔을 때, 자동차 한 대에는 몇 명이 있는가?",
        "question_en": "If 63 people are equally in 9 cars, how many people are in one car?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "63 9 [OP_DIV]",
        "solution_abst_en": "63 9 [OP_DIV]",
        "solution_code_ko": "var_a = 63\nvar_b = 9\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 63\nvar_b = 9\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "1180": {
        "category": "Comparison",
        "question_ko": "남준이는 서점에서 43번째로 책을 샀고, 태형이는 남준이 다음으로 10명이 더 산 뒤에 책을 샀습니다. 태형이는 몇 번째로 책을 샀습니까?",
        "question_en": "Namjoon was the 43rd to buy the book at the bookstore, and Taehyung bought the book after 10 more people bought the book after Namjoon. In what number did Taehyung buy the book?",
        "answer_ko": "54",
        "answer_en": "54",
        "solution_abst_ko": "43 10 [OP_ADD] 1 [OP_ADD]",
        "solution_abst_en": "43 10 [OP_ADD] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 43\nvar_b = 10\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 43\nvar_b = 10\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "1181": {
        "category": "Comparison",
        "question_ko": "학교에서 실시한 한국어 시험 결과, 태형, 민주, 상민, 윤정, 유정 순으로 가장 높은 점수를 받았다. 누가 가장 높은 점수를 얻었습니까?",
        "question_en": "As a result of the Korean language test conducted at the school, Taehyung, Minju, Sangmin, Yoonjung, and Yoojung received the highest score in that order. Who got the highest score?",
        "answer_ko": "태형",
        "answer_en": "Taehyung",
        "solution_abst_ko": "[OP_LIST_SOL] 태형 민주 상민 윤정 유정 [OP_LIST_EOL] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Taehyung Minju Sangmin Yoonjung Yoojung [OP_LIST_EOL] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '태형'\nvar_b = '민주'\nvar_c = '상민'\nvar_d = '윤정'\nvar_e = '유정'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nvar_g = list_a[var_f-1]\nprint(var_g)",
        "solution_code_en": "var_a = 'Taehyung'\nvar_b = 'Minju'\nvar_c = 'Sangmin'\nvar_d = 'Yoonjung'\nvar_e = 'Yoojung'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nvar_g = list_a[var_f-1]\nprint(var_g)"
    },
    "1182": {
        "category": "Possibility",
        "question_ko": "공 던지기 놀이를 합니다. 빨간색 원 안에 맞히면 5점, 노란색 원 안에 맞히면 2점, 두 원 안에 모두 맞히지 못하면 0점입니다. 공을 세 번 던질 때 얻을 수 있는 점수는 모두 몇 가지입니까?",
        "question_en": "Play ball toss. If you hit inside the red circle, you get 5 points, if you hit inside the yellow circle, you get 2 points, and if you don't fit inside both circles, you get 0 points. How many possible points can you get by throwing the ball three times?",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "[OP_LIST_SOL] 5 2 0 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_NUM2SUM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 5 2 0 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_NUM2SUM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = 0\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = 0\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "1183": {
        "category": "Geometry",
        "question_ko": "둘레가 36센티미터(㎝) 인 정사각형과 가로가 15 센티미터(㎝) 이고, 둘레가 38센티미터(㎝)인 직사각형의 넓이의 차를 구하시오.",
        "question_en": "Find the difference between the area of a square with a perimeter of 36 centimeters (cm) and a rectangle with a width of 15 centimeters (cm) and a perimeter of 38 centimeters (cm).",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "36 4 [OP_DIV] 2 [OP_POW] 38 2 [OP_DIV] 15 [OP_SUB] 15 [OP_MUL] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "36 4 [OP_DIV] 2 [OP_POW] 38 2 [OP_DIV] 15 [OP_SUB] 15 [OP_MUL] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 36\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 38\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = 15\nvar_j = var_h - var_i\nvar_k = 15\nvar_l = var_j * var_k\nvar_m = var_e - var_l\nvar_n = abs(var_m)\nprint(int(var_n))",
        "solution_code_en": "var_a = 36\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 38\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = 15\nvar_j = var_h - var_i\nvar_k = 15\nvar_l = var_j * var_k\nvar_m = var_e - var_l\nvar_n = abs(var_m)\nprint(int(var_n))"
    },
    "1184": {
        "category": "Arithmetic calculation",
        "question_ko": "4개 반의 국어 시험 평균이 각각 64, 73, 69, 82라고 한다. 평균이 70점을 넘는 반은 모두 몇 개인지 구하시오.",
        "question_en": "It is said that the average Korean language test scores of the four classes is 64, 73, 69, and 82, respectively. How many classes are there with an average above 70?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 64 73 69 82 [OP_LIST_EOL] 70 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 64 73 69 82 [OP_LIST_EOL] 70 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 64\nvar_b = 73\nvar_c = 69\nvar_d = 82\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 70\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 64\nvar_b = 73\nvar_c = 69\nvar_d = 82\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 70\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "1185": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 16을 빼야 하는데 잘못하여 더했더니 64가 되었습니다. 바르게 계산한 값은 얼마입니까?",
        "question_en": "You had to subtract 16 from a certain number, but you mistakenly add it, and the result was 64. What is the value if you calculate correctly?",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "64 16 [OP_SUB] 16 [OP_SUB]",
        "solution_abst_en": "64 16 [OP_SUB] 16 [OP_SUB]",
        "solution_code_ko": "var_a = 64\nvar_b = 16\nvar_c = var_a - var_b\nvar_d = 16\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 64\nvar_b = 16\nvar_c = var_a - var_b\nvar_d = 16\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "1186": {
        "category": "Arithmetic calculation",
        "question_ko": "성모가 수학 문제를 풀고 채점을 했더니 전체의 1/5 문제를 틀렸다면, 정답을 맞힌 문제는 전체 문제의 몇 배입니까?",
        "question_en": "When Sungmo solved and scored the math problems, he got 1/5 of the questions wrong. How many times the number of questions answered correctly is the total number of questions?",
        "answer_ko": "0.80",
        "answer_en": "0.8",
        "solution_abst_ko": "1 1/5 [OP_SUB]",
        "solution_abst_en": "1 1/5 [OP_SUB]",
        "solution_code_ko": "var_a = 1\nvar_b = 0.2\nvar_c = var_a - var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 0.2\nvar_c = var_a - var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "1187": {
        "category": "Arithmetic calculation",
        "question_ko": "야구공은 농구공의 반지름 길이의 1/4입니다. 야구공과 농구공의 부피를 계산할 때 농구공은 야구공의 부피의 몇 배가 큰가요?",
        "question_en": "A baseball is 1/4 the radius of a basketball. When calculating the volume of a baseball and basketball, how many times bigger is the volume of a basketball compared to that of a baseball?",
        "answer_ko": "64",
        "answer_en": "64",
        "solution_abst_ko": "1 1/4 3 [OP_POW] [OP_DIV]",
        "solution_abst_en": "1 1/4 3 [OP_POW] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 0.25\nvar_c = 3\nvar_d = var_b ** var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 0.25\nvar_c = 3\nvar_d = var_b ** var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "1188": {
        "category": "Comparison",
        "question_ko": "석진이는 호석이보다 무겁고 지민이보다 가볍습니다. 남준이는 지민이보다 무겁습니다. 4명 중 가장 가벼운 사람은 누구입니까?",
        "question_en": "Seokjin is heavier than Hoseok and lighter than Jimin. Namjoon is heavier than Jimin. Which of the 4 is the lightest?",
        "answer_ko": "호석",
        "answer_en": "Hoseok",
        "solution_abst_ko": "[OP_LIST_SOL] 석진 호석 지민 남준 [OP_LIST_EOL] [OP_LIST_SOL] 석진 호석 > 석진 지민 < 남준 지민 > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Seokjin Hoseok Jimin Namjoon [OP_LIST_EOL] [OP_LIST_SOL] Seokjin Hoseok > Seokjin Jimin < Namjoon Jimin > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '석진'\nvar_b = '호석'\nvar_c = '지민'\nvar_d = '남준'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '석진'\nvar_f = '호석'\nvar_g = '>'\nvar_h = '석진'\nvar_i = '지민'\nvar_j = '<'\nvar_k = '남준'\nvar_l = '지민'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)",
        "solution_code_en": "var_a = 'Seokjin'\nvar_b = 'Hoseok'\nvar_c = 'Jimin'\nvar_d = 'Namjoon'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'Seokjin'\nvar_f = 'Hoseok'\nvar_g = '>'\nvar_h = 'Seokjin'\nvar_i = 'Jimin'\nvar_j = '<'\nvar_k = 'Namjoon'\nvar_l = 'Jimin'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)"
    },
    "1189": {
        "category": "Arithmetic calculation",
        "question_ko": "사과와 배의 가격의 합은 15000원이다. 사과가 배 보다 2400원 더 비싸다면 배는 얼마인지 구하시오.",
        "question_en": "The sum of the prices of an apple and a pear is 15,000 won. If an apple costs 2,400 won more than a pear, what is the price of the pear?",
        "answer_ko": "6300",
        "answer_en": "6300",
        "solution_abst_ko": "15000 2400 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "15000 2400 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 15000\nvar_b = 2400\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15000\nvar_b = 2400\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "1190": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 수를 75로 나누었더니 몫이 11이 되었습니다. 어떤 수 중 가장 큰 수를 구하세요.",
        "question_en": "When a number is divided by 75, the quotient is 11. Find the largest number.",
        "answer_ko": "899",
        "answer_en": "899",
        "solution_abst_ko": "11 75 [OP_MUL] 75 1 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "11 75 [OP_MUL] 75 1 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 11\nvar_b = 75\nvar_c = var_a * var_b\nvar_d = 75\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 11\nvar_b = 75\nvar_c = var_a * var_b\nvar_d = 75\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "1191": {
        "category": "Comparison",
        "question_ko": "두 숫자가 모두 두 자리 수인 곱셈에서 곱하는 수의 일의 자리 숫자 5를 2로 잘못 보고 계산한 값이 704가 되었습니다. 바르게 계산한 값이 800일 때, 2개의 두 자리 수 중 더 큰 수를 쓰시오.",
        "question_en": "In a multiplication where both numbers are two digits, you multiplied 2 instead of 5 in the ones place of the number by mistake, and got a value of 704. If the correctly calculated value is 800, find what the larger digit of the two two-digit numbers is.",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "[OP_LIST_SOL] 704 800 [OP_SUB] 2 5 [OP_SUB] [OP_DIV] 800 704 800 [OP_SUB] 2 5 [OP_SUB] [OP_DIV] [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 704 800 [OP_SUB] 2 5 [OP_SUB] [OP_DIV] 800 704 800 [OP_SUB] 2 5 [OP_SUB] [OP_DIV] [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 704\nvar_b = 800\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = 5\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 800\nvar_i = 704\nvar_j = 800\nvar_k = var_i - var_j\nvar_l = 2\nvar_m = 5\nvar_n = var_l - var_m\nvar_o = var_k / var_n\nvar_p = var_h / var_o\nlist_a= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_a.append(var_p)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nlist_a.reverse()\nvar_q = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_r = list_b[-var_q]\nprint(int(var_r))",
        "solution_code_en": "var_a = 704\nvar_b = 800\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = 5\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 800\nvar_i = 704\nvar_j = 800\nvar_k = var_i - var_j\nvar_l = 2\nvar_m = 5\nvar_n = var_l - var_m\nvar_o = var_k / var_n\nvar_p = var_h / var_o\nlist_a= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_a.append(var_p)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nlist_a.reverse()\nvar_q = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_r = list_b[-var_q]\nprint(int(var_r))"
    },
    "1192": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 5미터(m), 무게가 29/8킬로그램(㎏)의 줄자와 길이가 4미터(m), 무게가 2.8킬로그램(㎏)인 컴퓨터가 있다. 줄자와 컴퓨터를 2미터(m)씩 잘라 함께 무게를 재면 몇 킬로그램(㎏)입니까?",
        "question_en": "There is a tape measure that is 5 meters (m) long and weighs 29/8 kilograms (kg) and a computer that is 4 meters (m) long and weighs 2.8 kilograms (kg). If you cut a tape measure and computer into 2 meters (m) and weigh them together, how many kilograms (kg) do you get?",
        "answer_ko": "2.85",
        "answer_en": "2.85",
        "solution_abst_ko": "29/8 5 [OP_DIV] 2 [OP_MUL] 2.8 4 [OP_DIV] 2 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "29/8 5 [OP_DIV] 2 [OP_MUL] 2.8 4 [OP_DIV] 2 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 3.625\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 2.8\nvar_g = 4\nvar_h = var_f / var_g\nvar_i = 2\nvar_j = var_h * var_i\nvar_k = var_e + var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 3.625\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 2.8\nvar_g = 4\nvar_h = var_f / var_g\nvar_i = 2\nvar_j = var_h * var_i\nvar_k = var_e + var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "1193": {
        "category": "Geometry",
        "question_ko": "육각형 내에 대각선을 그린다고 할 때, 총 대각선의 수는?",
        "question_en": "If you draw diagonals in a hexagon, what is the total number of diagonals?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "6 6 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "6 6 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 6\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 6\nvar_b = 6\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "1194": {
        "category": "Correspondence",
        "question_ko": "B는 C에 185를 더한 값이고 B보다 A는 157만큼 크다. A가 680일때 C를 구하여라.",
        "question_en": "B is C plus 185, and A is greater than B by 157. Find C when A is 680.",
        "answer_ko": "338",
        "answer_en": "338",
        "solution_abst_ko": "680 157 [OP_SUB] 185 [OP_SUB]",
        "solution_abst_en": "680 157 [OP_SUB] 185 [OP_SUB]",
        "solution_code_ko": "var_a = 680\nvar_b = 157\nvar_c = var_a - var_b\nvar_d = 185\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 680\nvar_b = 157\nvar_c = var_a - var_b\nvar_d = 185\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "1195": {
        "category": "Correspondence",
        "question_ko": "서로 다른 두 수 A, B가 있습니다. 두 자리 수끼리의 뺄셈식 8A-B2=45에서 A와 B의 합을 구하시오.",
        "question_en": "There are two different numbers A and B. Find the sum of A and B given the two-digit subtraction equation 8A-B2=45.",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "8A-B2=45 A [OP_DIGIT_UNK_SOLVER] 8A-B2=45 B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_abst_en": "8A-B2=45 A [OP_DIGIT_UNK_SOLVER] 8A-B2=45 B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_code_ko": "var_a = '8A-B2=45'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '8A-B2=45'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = '8A-B2=45'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '8A-B2=45'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "1196": {
        "category": "Comparison",
        "question_ko": "서로 다른 세 수 A, B, C가 있습니다. A는 95에서 35를 뺀 것과 같습니다. B는 A보다 12 큽니다. C는 B에서 19를 뺀 수입니다. A, B, C 중 가장 큰 수는 무엇입니까?",
        "question_en": "There are three different numbers A, B, and C. A is equal to 95 minus 35. B is 12 more than A. C is B minus 19. Which of A, B, and C is the greatest?",
        "answer_ko": "B",
        "answer_en": "B",
        "solution_abst_ko": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] 95 35 [OP_SUB] 95 35 [OP_SUB] 12 [OP_ADD] 95 35 [OP_SUB] 12 [OP_ADD] 19 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] 95 35 [OP_SUB] 95 35 [OP_SUB] 12 [OP_ADD] 95 35 [OP_SUB] 12 [OP_ADD] 19 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 95\nvar_e = 35\nvar_f = var_d - var_e\nvar_g = 95\nvar_h = 35\nvar_i = var_g - var_h\nvar_j = 12\nvar_k = var_i + var_j\nvar_l = 95\nvar_m = 35\nvar_n = var_l - var_m\nvar_o = 12\nvar_p = var_n + var_o\nvar_q = 19\nvar_r = var_p - var_q\nlist_b= []\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_s = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_t = list_c[-var_s]\nvar_u = list_b.index(var_t)+1\nvar_v = list_a[var_u-1]\nprint(var_v)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 95\nvar_e = 35\nvar_f = var_d - var_e\nvar_g = 95\nvar_h = 35\nvar_i = var_g - var_h\nvar_j = 12\nvar_k = var_i + var_j\nvar_l = 95\nvar_m = 35\nvar_n = var_l - var_m\nvar_o = 12\nvar_p = var_n + var_o\nvar_q = 19\nvar_r = var_p - var_q\nlist_b= []\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_s = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_t = list_c[-var_s]\nvar_u = list_b.index(var_t)+1\nvar_v = list_a[var_u-1]\nprint(var_v)"
    },
    "1197": {
        "category": "Geometry",
        "question_ko": "어떤 마름모를 둘러싸고 있는 가장 작은 원의 반지름의 길이가 10센티미터(㎝)였다. 이 마름모의 네 변의 중앙을 모두 이어서 그린 작은 마름모의 넓이는 얼마입니까?",
        "question_en": "The length of the radius of the smallest circle enclosing a rhombus was 10 centimeters (cm). What is the area of the smaller rhombus drawn through the midpoints of all four sides of the rhombus?",
        "answer_ko": "100",
        "answer_en": "100",
        "solution_abst_ko": "10 2 [OP_MUL] 2 [OP_POW] 2 [OP_DIV] 2 [OP_DIV]",
        "solution_abst_en": "10 2 [OP_MUL] 2 [OP_POW] 2 [OP_DIV] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "1198": {
        "category": "Arithmetic calculation",
        "question_ko": "2개의 수 4, 5로 나누어 떨어질 수 있는 수 중 가장 큰 세 자리 수는?",
        "question_en": "What is the largest three-digit number divisible by two numbers, 4 and 5?",
        "answer_ko": "980",
        "answer_en": "980",
        "solution_abst_ko": "100 999 1 [OP_LIST_ARANGE] 4 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_abst_en": "100 999 1 [OP_LIST_ARANGE] 4 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 4\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[-var_f]\nprint(int(var_g))",
        "solution_code_en": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 4\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[-var_f]\nprint(int(var_g))"
    },
    "1199": {
        "category": "Comparison",
        "question_ko": "두 강아지, 사과와 귤이 있습니다. 사과의 몸무게는 3/5킬로그램(㎏), 귤의 몸무게는 0.49킬로그램(㎏)입니다. 둘 중 더 무거운 강아지는 무엇입니까?",
        "question_en": "I have two puppies, an apple and a tangerine. The weight of an apple is 3/5 kilograms (kg), and the weight of a tangerine is 0.49 kilograms (kg). Which of the two is the heavier dog?",
        "answer_ko": "사과",
        "answer_en": "apple",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 귤 [OP_LIST_EOL] [OP_LIST_SOL] 3/5 0.49 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] apple tangerine [OP_LIST_EOL] [OP_LIST_SOL] 3/5 0.49 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '귤'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.6\nvar_d = 0.49\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'apple'\nvar_b = 'tangerine'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.6\nvar_d = 0.49\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "1200": {
        "category": "Correspondence",
        "question_ko": "14를 A로 나누면 몫은 3이고 나머지는 2가 됩니다. A는 자연수입니다. 이 때 A를 구하시오.",
        "question_en": "When 14 is divided by A, the quotient is 3 and the remainder is 2. A is a natural number. Find A.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "14 2 [OP_SUB] 3 [OP_DIV]",
        "solution_abst_en": "14 2 [OP_SUB] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 14\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 14\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "1201": {
        "category": "Comparison",
        "question_ko": "집에서 학교까지의 거리는 11/4킬로미터(㎞), 집에서 문구점까지의 거리는 2.89킬로미터(㎞)입니다. 학교와 문구점 중 집에서 더 먼 곳은 어디입니까?",
        "question_en": "The distance from the house to the school is 11/4 kilometers (km), and the distance from the house to the stationery store is 2.89 kilometers (km). Which is farther from home, the school or the stationery store?",
        "answer_ko": "문구점",
        "answer_en": "stationery",
        "solution_abst_ko": "[OP_LIST_SOL] 학교 문구점 [OP_LIST_EOL] [OP_LIST_SOL] 11/4 2.89 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] school stationery [OP_LIST_EOL] [OP_LIST_SOL] 11/4 2.89 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '학교'\nvar_b = '문구점'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2.75\nvar_d = 2.89\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'school'\nvar_b = 'stationery'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2.75\nvar_d = 2.89\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "1202": {
        "category": "Correspondence",
        "question_ko": "1부터 100까지 홀수를 쓰려고 합니다. 숫자 9는 모두 몇 번 써야 합니까?",
        "question_en": "I am trying to write odd numbers from 1 to 100. How many times should the number 9 be written in all?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "1 100 [OP_LIST_ODD] [OP_LIST2NUM] [OP_NUM2LIST] 9 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 100 [OP_LIST_ODD] [OP_LIST2NUM] [OP_NUM2LIST] 9 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 100\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c=\"\"\nfor i in list_a:\n    i = str(i)\n    var_c = var_c + i\nlist_b = []\nvar_c = int(var_c)\nwhile var_c//10 > 0:\n    list_b.append(var_c%10)\n    var_c = var_c//10\nlist_b.append(var_c%10)\nlist_b = list_b[::-1]\nvar_d = 9\nvar_e = 0\nvar_d = int(var_d)\nfor i in list_b:\n    i = int(i)\n    if i == var_d:\n        var_e = var_e + 1\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 100\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c=\"\"\nfor i in list_a:\n    i = str(i)\n    var_c = var_c + i\nlist_b = []\nvar_c = int(var_c)\nwhile var_c//10 > 0:\n    list_b.append(var_c%10)\n    var_c = var_c//10\nlist_b.append(var_c%10)\nlist_b = list_b[::-1]\nvar_d = 9\nvar_e = 0\nvar_d = int(var_d)\nfor i in list_b:\n    i = int(i)\n    if i == var_d:\n        var_e = var_e + 1\nprint(int(var_e))"
    },
    "1203": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 5까지 자연수들의 합은 얼마입니까?",
        "question_en": "What is the sum of the natural numbers from 1 to 5?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "1 5 1 [OP_LIST_ARANGE] [OP_LIST_SUM]",
        "solution_abst_en": "1 5 1 [OP_LIST_ARANGE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 5\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_a = [float(i) for i in list_a]\nvar_d = sum(list_a)\nprint(int(var_d))",
        "solution_code_en": "var_a = 1\nvar_b = 5\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_a = [float(i) for i in list_a]\nvar_d = sum(list_a)\nprint(int(var_d))"
    },
    "1204": {
        "category": "Comparison",
        "question_ko": "(가) 상자는 높이가 3센티미터(㎝)이고, (나) 상자는 높이가 3.5센티미터(㎝)입니다. 태형이는 (가) 상자를 16층으로 쌓았고, 윤기는 (나) 상자를 14층으로 쌓았습니다. 상자를 더 높이 쌓은 사람은 누구입니까?",
        "question_en": "The heights of the A and B boxes are 3 centimeters (cm) and 3.5 centimeters (cm), respectively. When Taehyung stacked 16 A boxes and Yoongi stacked 14 B boxes, who stacked them higher?",
        "answer_ko": "윤기",
        "answer_en": "Yoongi",
        "solution_abst_ko": "[OP_LIST_SOL] 태형 윤기 [OP_LIST_EOL] [OP_LIST_SOL] 3 16 [OP_MUL] 3.5 14 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Taehyung Yoongi [OP_LIST_EOL] [OP_LIST_SOL] 3 16 [OP_MUL] 3.5 14 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '태형'\nvar_b = '윤기'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nvar_d = 16\nvar_e = var_c * var_d\nvar_f = 3.5\nvar_g = 14\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Taehyung'\nvar_b = 'Yoongi'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nvar_d = 16\nvar_e = var_c * var_d\nvar_f = 3.5\nvar_g = 14\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "1205": {
        "category": "Comparison",
        "question_ko": "부산에 있는 공장에서 127000킬로그램(㎏)의 제품을 완성하였습니다. 이 제품을 서울까지 5000킬로그램(㎏) 트럭으로 운반하려면 8000킬로그램(㎏) 트럭으로 운반하는 것보다 몇 대가 더 필요합니까?",
        "question_en": "The factory in Busan produced 127,000 kilograms (kg) of products. How many more trucks are needed to transport these products to Seoul by 5000 kilograms (kg) truck than by 8000 kilograms (kg) truck?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "127000 5000 [OP_DIV] 1 [OP_CEIL] 127000 8000 [OP_DIV] 1 [OP_CEIL] [OP_SUB]",
        "solution_abst_en": "127000 5000 [OP_DIV] 1 [OP_CEIL] 127000 8000 [OP_DIV] 1 [OP_CEIL] [OP_SUB]",
        "solution_code_ko": "var_a = 127000\nvar_b = 5000\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nvar_f = 127000\nvar_g = 8000\nvar_h = var_f / var_g\nvar_i = 1\nvar_j=int(((var_h+9*10**(var_i-2))//(10**(var_i-1)))*10**(var_i-1))\n\nvar_k = var_e - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 127000\nvar_b = 5000\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nvar_f = 127000\nvar_g = 8000\nvar_h = var_f / var_g\nvar_i = 1\nvar_j=int(((var_h+9*10**(var_i-2))//(10**(var_i-1)))*10**(var_i-1))\n\nvar_k = var_e - var_j\nprint(int(var_k))"
    },
    "1206": {
        "category": "Comparison",
        "question_ko": "꽃밭의 2/7에는 채송화, 3/8에는 봉선화를 심었습니다. 어느 꽃을 심은 부분이 더 넓습니까?",
        "question_en": "You planted sunplant in 2/7 and snapweed in 3/8 of the flower garden. Which flower planted area is larger?",
        "answer_ko": "봉선화",
        "answer_en": "snapweed",
        "solution_abst_ko": "[OP_LIST_SOL] 채송화 봉선화 [OP_LIST_EOL] [OP_LIST_SOL] 2/7 3/8 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] sunplant snapweed [OP_LIST_EOL] [OP_LIST_SOL] 2/7 3/8 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '채송화'\nvar_b = '봉선화'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.2857142857142857\nvar_d = 0.375\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'sunplant'\nvar_b = 'snapweed'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.2857142857142857\nvar_d = 0.375\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "1207": {
        "category": "Possibility",
        "question_ko": "1부터 9까지의 숫자가 적힌 9장의 숫자 카드가 있습니다. 합이 17이 되도록 3장의 카드를 뽑는 방법은 몇 가지입니까?",
        "question_en": "There are 9 number cards with the numbers 1 through 9 written on them. How many ways exist in order to draw 3 cards and make their sum 17?",
        "answer_ko": "42",
        "answer_en": "42",
        "solution_abst_ko": "1 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 17 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 17 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 17\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 17\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))"
    },
    "1208": {
        "category": "Arithmetic calculation",
        "question_ko": "은지네 집에는 오리 52마리와 닭 78마리가 있습니다. 닭은 오리와 토끼의 수를 합한 것보다 12마리 더 적게 있습니다. 은지네 집에 있는 토끼는 몇 마리입니까?",
        "question_en": "Eunji's house has 52 ducks and 78 chickens. There are 12 fewer chickens than the number of ducks and rabbits combined. How many rabbits are there in Eunji's house?",
        "answer_ko": "38",
        "answer_en": "38",
        "solution_abst_ko": "78 52 [OP_SUB] 12 [OP_ADD]",
        "solution_abst_en": "78 52 [OP_SUB] 12 [OP_ADD]",
        "solution_code_ko": "var_a = 78\nvar_b = 52\nvar_c = var_a - var_b\nvar_d = 12\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 78\nvar_b = 52\nvar_c = var_a - var_b\nvar_d = 12\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "1209": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 200까지의 홀수의 합을 구하시오.",
        "question_en": "Find the sum of odd numbers from 1 to 200.",
        "answer_ko": "10000",
        "answer_en": "10000",
        "solution_abst_ko": "1 200 [OP_LIST_ODD] [OP_LIST_SUM]",
        "solution_abst_en": "1 200 [OP_LIST_ODD] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 200\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nprint(int(var_c))",
        "solution_code_en": "var_a = 1\nvar_b = 200\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nprint(int(var_c))"
    },
    "1210": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중에서 3번째로 작은 수와 2번째로 작은 수로 나눈 몫은 얼마입니까?",
        "question_en": "There are three numbers 10, 11, and 12. What is the quotient of the 3rd smallest number divided by the 2nd smallest number?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 3 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_FDIV]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 3 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_FDIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e // var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e // var_g\nprint(int(var_h))"
    },
    "1211": {
        "category": "Comparison",
        "question_ko": "예림이가 구입한 책은 0.65킬로그램(㎏)였고, 찬우가 구입한 책은 0.645킬로그램(㎏)였습니다. 더 무거운 책을 구매한 사람은 누구인가요?",
        "question_en": "The book Yerim bought was 0.65 kilograms (kg), and the book Chanwoo bought was 0.645 kilograms (kg). Who bought the heavier books?",
        "answer_ko": "예림",
        "answer_en": "Yerim",
        "solution_abst_ko": "[OP_LIST_SOL] 예림 찬우 [OP_LIST_EOL] [OP_LIST_SOL] 0.65 0.645 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yerim Chanwoo [OP_LIST_EOL] [OP_LIST_SOL] 0.65 0.645 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '예림'\nvar_b = '찬우'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.65\nvar_d = 0.645\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Yerim'\nvar_b = 'Chanwoo'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.65\nvar_d = 0.645\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "1212": {
        "category": "Geometry",
        "question_ko": "한 변에 말뚝 5개가 박혀있는 정사각형의 울타리를 만드려고 한다. 말뚝이 몇 개 필요할지 구하시오.",
        "question_en": "You are trying to make a square fence with 5 stakes per side. Find how many stakes you will need.",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "5 4 [OP_MUL] 4 [OP_SUB]",
        "solution_abst_en": "5 4 [OP_MUL] 4 [OP_SUB]",
        "solution_code_ko": "var_a = 5\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "1213": {
        "category": "Geometry",
        "question_ko": "12센티미터(㎝)인 변이 8개가 둘러싸여 만들어진 도형의 둘레는 몇 센티미터(㎝)입니까?",
        "question_en": "What is the perimeter in centimeters (cm) of a figure made by enclosing 8 sides that are 12 centimeters (cm) long each?",
        "answer_ko": "96",
        "answer_en": "96",
        "solution_abst_ko": "12 8 [OP_MUL]",
        "solution_abst_en": "12 8 [OP_MUL]",
        "solution_code_ko": "var_a = 12\nvar_b = 8\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 12\nvar_b = 8\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "1214": {
        "category": "Arithmetic calculation",
        "question_ko": "진우는 케이크를 똑같이 3조각으로 나누어 한 조각을 먹었습니다. 아름이는 같은 크기의 케이크를 똑같이 12조각으로 나누었습니다. 진우와 같은 양을 먹으려면 아름이는 몇 조각을 먹어야 합니까?",
        "question_en": "Jinwoo divided the cake into 3 equal pieces and ate one piece. Areum divided a cake of the same size into 12 equal pieces. How many pieces should she eat to eat the same amount as Jinwoo?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "12 3 [OP_DIV]",
        "solution_abst_en": "12 3 [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 3\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 12\nvar_b = 3\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "1215": {
        "category": "Comparison",
        "question_ko": "3개의 숫자 5, 8, 4 중 가장 작은 숫자는 무엇입니까?",
        "question_en": "What is the smallest number among the three numbers 5, 8, and 4?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 5 8 4 [OP_LIST_EOL] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 5 8 4 [OP_LIST_EOL] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 5\nvar_b = 8\nvar_c = 4\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 8\nvar_c = 4\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nprint(int(var_e))"
    },
    "1216": {
        "category": "Arithmetic calculation",
        "question_ko": "두 통에 주스가 각각 10리터(L), 8리터(L)가 담겨있습니다. 8리터(L)가 담겨 있던 주스 중 3리터(L)를 10리터(L)가 담긴 주스 통에 따랐을 때, 두 주스 통에 담겨 있는 주스의 양은 얼마나 차이 나는지 구하시오.",
        "question_en": "The two barrels contain 10 liters (L) and 8 liters (L) of juice, respectively. When 3 liters (L) of the juice contained in 8 liters (L) is poured into a juice container containing 10 liters (L), find the difference in the amount of juice held in the two juice containers.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "10 3 [OP_ADD] 8 3 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "10 3 [OP_ADD] 8 3 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 8\nvar_e = 3\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 10\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 8\nvar_e = 3\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "1217": {
        "category": "Comparison",
        "question_ko": "집에서 도서관까지의 거리는 2+13/40킬로미터(㎞)이고 집에서 은행까지의 거리는 2.56킬로미터(㎞)입니다. 집에서 도서관까지 혹은 집에서 은행까지 중 어느 것이 더 멀까요?",
        "question_en": "The distance from the house to the library is 2+13/40 kilometers (km), and the distance from the house to the bank is 2.56 kilometers (km). Which is farther, from the house to the library or from the house to the bank?",
        "answer_ko": "은행",
        "answer_en": "bank",
        "solution_abst_ko": "[OP_LIST_SOL] 도서관 은행 [OP_LIST_EOL] [OP_LIST_SOL] 2 13 40 [OP_DIV] [OP_ADD] 2.56 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] library bank [OP_LIST_EOL] [OP_LIST_SOL] 2 13 40 [OP_DIV] [OP_ADD] 2.56 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '도서관'\nvar_b = '은행'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nvar_d = 13\nvar_e = 40\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nvar_h = 2.56\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'library'\nvar_b = 'bank'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nvar_d = 13\nvar_e = 40\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nvar_h = 2.56\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "1218": {
        "category": "Arithmetic calculation",
        "question_ko": "도서관에 있는 책꽂이 한 개에는 6칸이 있고, 각 칸에는 책을 8권씩 꽂을 수 있습니다. 도서관에 있는 책꽂이 16개 중에서 책이 꽂혀 있지 않은 칸은 5칸이고, 한 칸에만 책이 6권 꽂혀 있고, 나머지 칸에는 모두 책이 8권씩 꽂혀 있습니다. 도서관에 있는 책은 모두 몇 권인지 구해보시오.",
        "question_en": "Each bookshelf in the library has 6 slots, and each slot can hold 8 books. Of the 16 bookshelves in the library, there are 5 slots without books, only one slot has 6 books, and all other slots have 8 books. Find how many books there are in the library.",
        "answer_ko": "726",
        "answer_en": "726",
        "solution_abst_ko": "16 6 [OP_MUL] 5 [OP_SUB] 1 [OP_SUB] 8 [OP_MUL] 6 [OP_ADD]",
        "solution_abst_en": "16 6 [OP_MUL] 5 [OP_SUB] 1 [OP_SUB] 8 [OP_MUL] 6 [OP_ADD]",
        "solution_code_ko": "var_a = 16\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = 8\nvar_i = var_g * var_h\nvar_j = 6\nvar_k = var_i + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 16\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = 8\nvar_i = var_g * var_h\nvar_j = 6\nvar_k = var_i + var_j\nprint(int(var_k))"
    },
    "1219": {
        "category": "Possibility",
        "question_ko": "4, 5, 8 숫자카드를 한 번씩 모두 사용하였을 때, 550보다 크지 않은 세 자리 수의 개수를 구하시오.",
        "question_en": "When all 4, 5, and 8 number cards are used once, find the number of three-digit numbers not greater than 550.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 4 5 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 550 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 4 5 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 550 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 4\nvar_b = 5\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 550\nlist_c = []\nfor i in list_b:\n    if i <= var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 4\nvar_b = 5\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 550\nlist_c = []\nfor i in list_b:\n    if i <= var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "1220": {
        "category": "Arithmetic calculation",
        "question_ko": "가지고 있던 사탕 중에 15개를 먹었더니 13개가 남았습니다. 처음에 있던 사탕의 수는 몇 개입니까?",
        "question_en": "After eating 15 out of the candies I had, there are 13 left. How many candies were there initially?",
        "answer_ko": "28",
        "answer_en": "28",
        "solution_abst_ko": "15 13 [OP_ADD]",
        "solution_abst_en": "15 13 [OP_ADD]",
        "solution_code_ko": "var_a = 15\nvar_b = 13\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 15\nvar_b = 13\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "1221": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.9, 1/3 중에서 0.7보다 작거나 같은 수 중 가장 큰 수는 무엇인가요?",
        "question_en": "Among 0.8, 1/2, 0.9, and 1/3, find the largest number which is less than or equal to 0.7.",
        "answer_ko": "0.50",
        "answer_en": "0.5",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.7 [OP_LIST_LESS_EQUAL] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.7 [OP_LIST_LESS_EQUAL] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.7\nlist_b = []\nfor i in list_a:\n    if i <= var_e:\n        list_b.append(i)\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.7\nlist_b = []\nfor i in list_a:\n    if i <= var_e:\n        list_b.append(i)\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "1222": {
        "category": "Comparison",
        "question_ko": "20명의 학생들이 한줄로 섰습니다. 정국이는 꼴지로 줄을 섰고, 윤기는 정국이 바로 앞에 섰습니다. 윤기 뒤에 서 있는 학생은 몇 명입니까?",
        "question_en": "20 students stood in a line. Jungkook stood last in line, and Yoongi stood right in front of Jungkook. How many students are standing behind Yoongi?",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "20 1 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "20 1 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "1223": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 3으로 나눈 후 14를 더하고 2를 곱해야 할 것을 잘못하여 어떤 수에 3을 곱한 후 14를 더하고 2를 곱한 값이 946이 되었습니다. 바르게 계산한 값을 구하시오.",
        "question_en": "I should have divided a certain number by 3 and then add 14 to it and then multiply it by 2, but I mistakingly multiplied 3 by that certain number and added 14, and then multiplied it by 2, which resulted in 946. Find the correct calculated value.",
        "answer_ko": "130",
        "answer_en": "130",
        "solution_abst_ko": "946 2 [OP_DIV] 14 [OP_SUB] 3 [OP_DIV] 3 [OP_DIV] 14 [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "946 2 [OP_DIV] 14 [OP_SUB] 3 [OP_DIV] 3 [OP_DIV] 14 [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 946\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 14\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = 3\nvar_i = var_g / var_h\nvar_j = 14\nvar_k = var_i + var_j\nvar_l = 2\nvar_m = var_k * var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 946\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 14\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = 3\nvar_i = var_g / var_h\nvar_j = 14\nvar_k = var_i + var_j\nvar_l = 2\nvar_m = var_k * var_l\nprint(int(var_m))"
    },
    "1224": {
        "category": "Arithmetic calculation",
        "question_ko": "보경이는 강아지 3마리와 병아리 7마리를 키우고 있습니다. 보경이가 키우는 동물들의 다리 수를 모두 합하면 몇 개입니까?",
        "question_en": "Bokyung is raising 3 puppies and 7 chicks. What is the total number of legs of Bokyung's animals?",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "3 4 [OP_MUL] 7 2 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "3 4 [OP_MUL] 7 2 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 3\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "1225": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 12로 나누어야 할 것을 잘못하여 21로 나누었더니 4로 나누어 떨어졌습니다. 바르게 계산했을 때의 몫에서 4를 더하면 얼마인지 구하시오.",
        "question_en": "When you mistakenly divide a number by 21, not by 12, it is divisible by 4. Find the value when 4 is added to the correct quotient.",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "4 21 [OP_MUL] 12 [OP_FDIV] 4 [OP_ADD]",
        "solution_abst_en": "4 21 [OP_MUL] 12 [OP_FDIV] 4 [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 21\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = var_c // var_d\nvar_f = 4\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 21\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = var_c // var_d\nvar_f = 4\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "1226": {
        "category": "Arithmetic calculation",
        "question_ko": "100미터(m) 길이의 도로에 10미터(m) 간격으로 나무를 심으려고 합니다. 도로의 처음과 끝에도 나무를 심는다고 할 때, 도로 한쪽에만 심는다면 몇 그루가 필요합니까?",
        "question_en": "You want to plant trees at intervals of 10 meters (m) on a 100-meter (m) long road. Supposing that trees are planted at the beginning and end of the road as well, how many trees are needed if they are planted on only one side of the road?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "100 10 [OP_DIV] 1 [OP_ADD]",
        "solution_abst_en": "100 10 [OP_DIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 100\nvar_b = 10\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 100\nvar_b = 10\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "1227": {
        "category": "Comparison",
        "question_ko": "자전거 가게에 네발 자전거와 두발 자전거가 있습니다. 가게 안의 모든 자전거의 바퀴 수를 합치면 48개이고, 네발 자전거는 9대가 있습니다. 두 발 자전거는 몇 대가 있습니까?",
        "question_en": "The bike shop has four-wheeled bikes and two-wheeled bikes. The total number of wheels on all bicycles in the shop is 48, and there are 9 four-wheeled bikes. How many two-wheeled bicycles are there?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "48 4 9 [OP_MUL] [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "48 4 9 [OP_MUL] [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 48\nvar_b = 4\nvar_c = 9\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 48\nvar_b = 4\nvar_c = 9\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "1228": {
        "category": "Possibility",
        "question_ko": "0, 1, 2, 3, 4, 5 여섯개의 숫자가 적힌 주사위를 3번 던져 나온 결과로 세 자리 수를 만들고자 한다. 이 때, 6과 9의 공통 배수인 경우는 모두 몇 가지가 나올 수 있는가?",
        "question_en": "You want to make a three-digit number as a result of throwing a dice with 0, 1, 2, 3, 4, and 5 written on it three times. How many number of cases to have common multiples of 6 and 9 are there?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 4 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 6 9 [OP_LCM] [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 4 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 6 9 [OP_LCM] [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nvar_f = 5\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = 6\nvar_i = 9\nvar_j = var_i * var_h / math.gcd(int(var_i), int(var_h))\nlist_c = []\nvar_j = int(var_j)\nfor i in list_b:\n    i = int(i)\n    if i % var_j == 0:\n        list_c.append(i)\nvar_k = len(list_c)\nprint(int(var_k))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nvar_f = 5\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = 6\nvar_i = 9\nvar_j = var_i * var_h / math.gcd(int(var_i), int(var_h))\nlist_c = []\nvar_j = int(var_j)\nfor i in list_b:\n    i = int(i)\n    if i % var_j == 0:\n        list_c.append(i)\nvar_k = len(list_c)\nprint(int(var_k))"
    },
    "1229": {
        "category": "Arithmetic calculation",
        "question_ko": "1시간에 95킬로미터(㎞) 달리는 기차와 1시간에 65킬로미터(㎞) 달리는 자동차가 있습니다. 이 기차와 자동차가 같은 빠르기로 8시간 동안 달렸을 때, 기차는 자동차보다 몇 킬로미터(㎞) 더 갔습니까?",
        "question_en": "There is a train that runs at 95 kilometers (km) per hour and a car that runs at 65 kilometers (km) per hour. If the train and the car travel for 8 hours at a constant speed, by how many kilometers (km) does the train travel more than the car?",
        "answer_ko": "240",
        "answer_en": "240",
        "solution_abst_ko": "95 65 [OP_SUB] 8 [OP_MUL]",
        "solution_abst_en": "95 65 [OP_SUB] 8 [OP_MUL]",
        "solution_code_ko": "var_a = 95\nvar_b = 65\nvar_c = var_a - var_b\nvar_d = 8\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 95\nvar_b = 65\nvar_c = var_a - var_b\nvar_d = 8\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "1230": {
        "category": "Arithmetic calculation",
        "question_ko": "돼지와 소가 모두 85마리 있습니다. 소가 48마리일 때 소는 돼지보다 몇 개 더 적습니까?",
        "question_en": "There are 85 pigs and cows in total. When there are 48 pigs, how many more cows are there than pigs?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "48 85 48 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "48 85 48 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 48\nvar_b = 85\nvar_c = 48\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 48\nvar_b = 85\nvar_c = 48\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "1231": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이네 반에 여자는 9명, 남자는 16명 있습니다. 정국이네 반 학생은 모두 몇 명입니까?",
        "question_en": "There are 9 girls and 16 boys in Jungkook's class. What is the total number of students in the class?",
        "answer_ko": "25",
        "answer_en": "25",
        "solution_abst_ko": "16 9 [OP_ADD]",
        "solution_abst_en": "16 9 [OP_ADD]",
        "solution_code_ko": "var_a = 16\nvar_b = 9\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 16\nvar_b = 9\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "1232": {
        "category": "Geometry",
        "question_ko": "12개의 각으로 이루어진 도형의 한 꼭짓점에서 그을 수 있는 대각선의 개수는 몇 개입니까?",
        "question_en": "How many diagonals can be drawn from one vertex of a 12-angle figure?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "12 3 [OP_SUB]",
        "solution_abst_en": "12 3 [OP_SUB]",
        "solution_code_ko": "var_a = 12\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 12\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "1233": {
        "category": "Arithmetic calculation",
        "question_ko": "민영이의 국어와 영어 두 과목의 평균 점수는 89점입니다. 국어, 수학, 영어 세 과목의 평균 점수가 91점일 때, 민영이의 수학 점수는 몇 점입니까?",
        "question_en": "Minyoung's average score for Korean and English is 89 points. If his average score in Korean, Mathematics, and English is 91, what is Minyoung's math score?",
        "answer_ko": "95",
        "answer_en": "95",
        "solution_abst_ko": "91 3 [OP_MUL] 89 2 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "91 3 [OP_MUL] 89 2 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 91\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 89\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 91\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 89\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "1234": {
        "category": "Geometry",
        "question_ko": "겉넓이가 54.3제곱센티미터(㎠) 정육면체의 한 면에 색을 칠했다. 색칠된 부분의 넓이를 구하시오.",
        "question_en": "One side of a cube with a surface area of 54.3 square centimeters (cm2) was painted. Find the area of the painted side.",
        "answer_ko": "9.05",
        "answer_en": "9.05",
        "solution_abst_ko": "54.3 6 [OP_DIV]",
        "solution_abst_en": "54.3 6 [OP_DIV]",
        "solution_code_ko": "var_a = 54.3\nvar_b = 6\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 54.3\nvar_b = 6\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "1235": {
        "category": "Arithmetic calculation",
        "question_ko": "민영이가 12.34킬로그램(㎏)짜리 설탕을 7통 사서 3명에게 똑같이 나누어 주려고 합니다. 한 명에게 설탕 몇 킬로그램(㎏)을 줄 수 있습니까?",
        "question_en": "Min-Young bought 7 boxes of 12.34 kg (kg) of sugar and wants to share them equally with 3 people. How many kilograms (kg) of sugar can one person get?",
        "answer_ko": "28",
        "answer_en": "28",
        "solution_abst_ko": "12.34 7 [OP_MUL] 3 [OP_FDIV]",
        "solution_abst_en": "12.34 7 [OP_MUL] 3 [OP_FDIV]",
        "solution_code_ko": "var_a = 12.34\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12.34\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "1236": {
        "category": "Arithmetic calculation",
        "question_ko": "올해 유나는 9살입니다. 아버지는 유나보다 27살이 많고 할아버지는 아버지보다 23살이 많습니다. 올해 할아버지의 나이는 몇 살입니까?",
        "question_en": "Yuna is 9 years old this year. Her father is 27 years older than Yuna and her grandfather is 23 years older than her father. How old is Yuna's grandfather this year?",
        "answer_ko": "59",
        "answer_en": "59",
        "solution_abst_ko": "9 27 [OP_ADD] 23 [OP_ADD]",
        "solution_abst_en": "9 27 [OP_ADD] 23 [OP_ADD]",
        "solution_code_ko": "var_a = 9\nvar_b = 27\nvar_c = var_a + var_b\nvar_d = 23\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 27\nvar_c = var_a + var_b\nvar_d = 23\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "1237": {
        "category": "Possibility",
        "question_ko": "어느 상점에서 판매하는 우유는 초코우유, 딸기우유, 바나나우유, 커피우유, 흰우유 5종류이다. 이 상점에서 우유를 선택할 때, 중복을 허용하여 우유 2팩을 선택하는 방법의 수를 구하시오.",
        "question_en": "There are five types of milk sold at a store: chocolate milk, strawberry milk, banana milk, coffee milk, and white milk. When selecting milk from this store, find the number of ways to select 2 cartons of milk, allowing duplicates.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "[OP_LIST_SOL] 초코우유 딸기우유 바나나우유 커피우유 흰우유 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] chocolate strawberry banana coffee white [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '초코우유'\nvar_b = '딸기우유'\nvar_c = '바나나우유'\nvar_d = '커피우유'\nvar_e = '흰우유'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = 2\nvar_l = 1\nvar_j = int(var_j)\nvar_k = int(var_k)\nfor i, elem in enumerate(range(var_k)):\n    var_l = var_l * (var_j-i)\nfor i, elem in enumerate(range(var_k)):\n    var_l = var_l / (i+1)\nprint(int(var_l))",
        "solution_code_en": "var_a = 'chocolate'\nvar_b = 'strawberry'\nvar_c = 'banana'\nvar_d = 'coffee'\nvar_e = 'white'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = 2\nvar_l = 1\nvar_j = int(var_j)\nvar_k = int(var_k)\nfor i, elem in enumerate(range(var_k)):\n    var_l = var_l * (var_j-i)\nfor i, elem in enumerate(range(var_k)):\n    var_l = var_l / (i+1)\nprint(int(var_l))"
    },
    "1238": {
        "category": "Geometry",
        "question_ko": "큰 원의 반지름은 80센티미터(㎝)이고, 큰 원의 반지름은 작은 원의 반지름의 4배라고 합니다. 작은 원의 반지름은 몇 센티미터(㎝)입니까?",
        "question_en": "The radius of the larger circle is 80 centimeters (cm), and the radius of the larger circle is said to be 4 times the radius of the smaller circle. What is the radius of the small circle in centimeters (cm)?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "80 4 [OP_DIV]",
        "solution_abst_en": "80 4 [OP_DIV]",
        "solution_code_ko": "var_a = 80\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 80\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "1239": {
        "category": "Geometry",
        "question_ko": "육면체 모양의 상자가 있습니다. 이 상자의 면의 수는?",
        "question_en": "There is a box in the shape of a hexahedron. How many sides does this box have?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "6",
        "solution_abst_en": "6",
        "solution_code_ko": "var_a = 6\nprint(int(var_a))",
        "solution_code_en": "var_a = 6\nprint(int(var_a))"
    },
    "1240": {
        "category": "Arithmetic calculation",
        "question_ko": "25센티미터(㎝) 길이의 빨대 30장을 6센티미터(㎝) 겹쳐 이어 붙였을 시 전체 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "What is the total length in centimeters (cm) of 30 straws when each of the straw is 25 centimeters (cm) long, and the overlapped area 6 centimeters (cm) long?",
        "answer_ko": "576",
        "answer_en": "576",
        "solution_abst_ko": "25 25 6 [OP_SUB] 30 1 [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_abst_en": "25 25 6 [OP_SUB] 30 1 [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 25\nvar_b = 25\nvar_c = 6\nvar_d = var_b - var_c\nvar_e = 30\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_a + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 25\nvar_b = 25\nvar_c = 6\nvar_d = var_b - var_c\nvar_e = 30\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_a + var_h\nprint(int(var_i))"
    },
    "1241": {
        "category": "Possibility",
        "question_ko": "3장의 카드의 앞면과 뒷면을 사용해서 신호를 만드려고 합니다. 만들 수 있는 신호는 몇 가지입니까?",
        "question_en": "You are trying to create a signal using the front and back sides of 3 cards. How many signals can you create?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "2 3 [OP_POW]",
        "solution_abst_en": "2 3 [OP_POW]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = var_a ** var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = var_a ** var_b\nprint(int(var_c))"
    },
    "1242": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 가장 작은 수를 그 다음으로 작은 수로 나눈 몫은 얼마입니까?",
        "question_en": "There are five numbers: 10, 11, 12, 13, and 14. What is the quotient of the smallest number divided by the next smallest number?",
        "answer_ko": "0",
        "answer_en": "0",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_FDIV]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_FDIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g // var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g // var_i\nprint(int(var_j))"
    },
    "1243": {
        "category": "Arithmetic calculation",
        "question_ko": "합이 112인 연속된 4개의 홀수가 있습니다. 이 숫자들 중에서 2번째로 작은 숫자는 무엇입니까?",
        "question_en": "There are 4 consecutive odd numbers whose sum is 112. Which of these numbers is the 2nd smallest?",
        "answer_ko": "27",
        "answer_en": "27",
        "solution_abst_ko": "112 4 [OP_DIV] 4 2 [OP_FDIV] 2 [OP_MUL] [OP_SUB] 1 [OP_ADD] 2 [OP_ADD]",
        "solution_abst_en": "112 4 [OP_DIV] 4 2 [OP_FDIV] 2 [OP_MUL] [OP_SUB] 1 [OP_ADD] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 112\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = 2\nvar_f = var_d // var_e\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_c - var_h\nvar_j = 1\nvar_k = var_i + var_j\nvar_l = 2\nvar_m = var_k + var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 112\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = 2\nvar_f = var_d // var_e\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_c - var_h\nvar_j = 1\nvar_k = var_i + var_j\nvar_l = 2\nvar_m = var_k + var_l\nprint(int(var_m))"
    },
    "1244": {
        "category": "Arithmetic calculation",
        "question_ko": "5센티미터(㎝)씩 겹쳐서 색 테이프 15장을 이어 붙였습니다. 색 테이프 하나의 길이가 20센티미터(㎝)일 때 총 길이는 몇 센티미터(㎝)인지 구하시오",
        "question_en": "I attached 15 sheets of colored tape, overlapping by 5 centimeters (cm). If the length of one piece of tape is 20 centimeters (cm), how many centimeters (cm) is the total length?",
        "answer_ko": "230",
        "answer_en": "230",
        "solution_abst_ko": "20 20 5 [OP_SUB] 15 1 [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_abst_en": "20 20 5 [OP_SUB] 15 1 [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 20\nvar_b = 20\nvar_c = 5\nvar_d = var_b - var_c\nvar_e = 15\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_a + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 20\nvar_b = 20\nvar_c = 5\nvar_d = var_b - var_c\nvar_e = 15\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_a + var_h\nprint(int(var_i))"
    },
    "1245": {
        "category": "Geometry",
        "question_ko": "어떤 정사각형의 둘레가 34.8센티미터(㎝)입니다. 한 변의 길이를 구하시오.",
        "question_en": "The perimeter of a square is 34.8 centimeters (cm). Find the length of one side.",
        "answer_ko": "8.70",
        "answer_en": "8.7",
        "solution_abst_ko": "34.8 4 [OP_DIV]",
        "solution_abst_en": "34.8 4 [OP_DIV]",
        "solution_code_ko": "var_a = 34.8\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 34.8\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "1246": {
        "category": "Geometry",
        "question_ko": "한 꼭짓점에서 6개의 대각선을 그을 수 있을 때, 이 다각형의 꼭짓점의 개수를 구하시오.",
        "question_en": "If 6 diagonals can be drawn from one vertex, find the number of vertices in this polygon.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "6 3 [OP_ADD]",
        "solution_abst_en": "6 3 [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 3\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 3\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "1247": {
        "category": "Arithmetic calculation",
        "question_ko": "태형이와 어머니 나이의 차는 31살이고, 태형이와 동생의 나이의 차는 5살입니다. 올해 태형이 동생이 7살이라면 어머니의 나이는 몇 살입니까?",
        "question_en": "The age difference between Taehyung and his mother is 31 years, and the age difference between Taehyung and his younger brother is 5 years. If Taehyung's younger brother is 7 years old this year, how old is his mother?",
        "answer_ko": "43",
        "answer_en": "43",
        "solution_abst_ko": "7 5 [OP_ADD] 31 [OP_ADD]",
        "solution_abst_en": "7 5 [OP_ADD] 31 [OP_ADD]",
        "solution_code_ko": "var_a = 7\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 31\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 7\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 31\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "1248": {
        "category": "Correspondence",
        "question_ko": "30과 40 사이의 두 자리 수 중 일의 자리 숫자가 2인 수를 구하시오.",
        "question_en": "Find the number that has a units digit of 2 and is a two-digit number between 30 and 40.",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "30 40 1 [OP_LIST_ARANGE] 10 2 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "30 40 1 [OP_LIST_ARANGE] 10 2 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 30\nvar_b = 40\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 10\nvar_e = 2\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 1\nvar_g = list_b[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 30\nvar_b = 40\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 10\nvar_e = 2\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 1\nvar_g = list_b[var_f-1]\nprint(int(var_g))"
    },
    "1249": {
        "category": "Correspondence",
        "question_ko": "이번 가을에 여름 옷을 16벌 버리고 그만큼 겨울 옷을 사서 넣어놓았다. 옷장에 겨울 옷이 여름 옷보다 64벌 많다면 여름에는 겨울 옷과 여름 옷의 차이가 몇 벌이었는지 구하시오.",
        "question_en": "I threw away 16 sets of summer clothes this fall and bought winter clothes that much. If there are 64 more winter clothes than summer clothes in your closet, find the difference between winter clothes and summer clothes in summer.",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "64 16 [OP_SUB] 16 [OP_SUB]",
        "solution_abst_en": "64 16 [OP_SUB] 16 [OP_SUB]",
        "solution_code_ko": "var_a = 64\nvar_b = 16\nvar_c = var_a - var_b\nvar_d = 16\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 64\nvar_b = 16\nvar_c = var_a - var_b\nvar_d = 16\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "1250": {
        "category": "Correspondence",
        "question_ko": "A, B는 한 자리 수입니다. A375B는 다섯 자리 수이고 24의 배수입니다. A가 될 수 있는 모든 숫자의 개수는 무엇입니까?",
        "question_en": "A and B are single digit numbers. A375B is a five digit number and is a multiple of 24. What is the number of all numbers that can be A?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "A375B [OP_GEN_POSSIBLE_LIST] 24 [OP_LIST_DIVISIBLE] A375B A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_abst_en": "A375B [OP_GEN_POSSIBLE_LIST] 24 [OP_LIST_DIVISIBLE] A375B A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 'A375B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 24\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 'A375B'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nvar_e = len(list_c)\nprint(int(var_e))",
        "solution_code_en": "var_a = 'A375B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 24\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 'A375B'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nvar_e = len(list_c)\nprint(int(var_e))"
    },
    "1251": {
        "category": "Correspondence",
        "question_ko": "691-68A=4일 때, A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "When 691-68A=4, what number should go in A?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "691-68A=4 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "691-68A=4 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '691-68A=4'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '691-68A=4'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "1252": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 30까지의 자연수 중 홀수가 아닌 수는 몇 개인지 구하시오.",
        "question_en": "Find the number of natural numbers among 1 to 30 that are not odd.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "1 30 1 [OP_LIST_ARANGE] 1 30 [OP_LIST_ODD] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_abst_en": "1 30 1 [OP_LIST_ARANGE] 1 30 [OP_LIST_ODD] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 30\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 1\nvar_e = 30\nlist_b = []\nif var_d%2==0:\n    for i in range(var_d+1, var_e+1, 2):\n        list_b.append(i)\nelse:\n    for i in range(var_d, var_e+1, 2):\n        list_b.append(i)\nlist_c = list(set(list_a) - set(list_b))\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 30\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 1\nvar_e = 30\nlist_b = []\nif var_d%2==0:\n    for i in range(var_d+1, var_e+1, 2):\n        list_b.append(i)\nelse:\n    for i in range(var_d, var_e+1, 2):\n        list_b.append(i)\nlist_c = list(set(list_a) - set(list_b))\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "1253": {
        "category": "Correspondence",
        "question_ko": "20에 어떤 수를 빼려고 합니다. 잘못하여 4에 어떤 수를 곱하였더니 결과는 52가 되었습니다. 바르게 계산한 결과는 얼마일까요?",
        "question_en": "I want to subtract a number from 20. I mistakenly multiplied 4 by a number, and the result was 52. What is the correct calculation result?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "20 52 4 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "20 52 4 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 52\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 52\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "1254": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 46을 빼야 하는데 잘못하여 59를 뺐더니 43이 되었습니다. 바르게 계산한 결과를 구하시오.",
        "question_en": "I needed to subtract 46 from a certain number, but I mistakenly subtracted 59, so I got 43. Find the result of the correct calculation.",
        "answer_ko": "56",
        "answer_en": "56",
        "solution_abst_ko": "43 59 [OP_ADD] 46 [OP_SUB]",
        "solution_abst_en": "43 59 [OP_ADD] 46 [OP_SUB]",
        "solution_code_ko": "var_a = 43\nvar_b = 59\nvar_c = var_a + var_b\nvar_d = 46\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 43\nvar_b = 59\nvar_c = var_a + var_b\nvar_d = 46\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "1255": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 같지 않은 끈이 두 개 있습니다. 두 끈의 길이 차이는 48센티미터(㎝)이고 두 끈의 길이 합은 64센티미터(㎝)일때 긴 끈을 잘라서 짧은 끈과 길이가 같은 끈을 몇 개 만들 수 있나요?",
        "question_en": "There are two strings of unequal length. If the difference in length of the two strings is 48 centimeters (cm) and the sum of the lengths of the two strings is 64 centimeters (cm), how many strings can you make that are the same length as the shorter string by cutting the longer string?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "64 48 [OP_ADD] 2 [OP_DIV] 64 48 [OP_SUB] 2 [OP_DIV] [OP_FDIV]",
        "solution_abst_en": "64 48 [OP_ADD] 2 [OP_DIV] 64 48 [OP_SUB] 2 [OP_DIV] [OP_FDIV]",
        "solution_code_ko": "var_a = 64\nvar_b = 48\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 64\nvar_g = 48\nvar_h = var_f - var_g\nvar_i = 2\nvar_j = var_h / var_i\nvar_k = var_e // var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 64\nvar_b = 48\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 64\nvar_g = 48\nvar_h = var_f - var_g\nvar_i = 2\nvar_j = var_h / var_i\nvar_k = var_e // var_j\nprint(int(var_k))"
    },
    "1256": {
        "category": "Correspondence",
        "question_ko": "5를 어떤 수에 곱하면 100이 됩니다. 윤기는 어떤 수를 10으로 나누어 결과를 얻었습니다. 이 결과값을 구하시오.",
        "question_en": "A certain number multiplied by 5 equals 100. Yoongi divided that certain number by 10 and got an answer. What is his answer?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "100 5 [OP_DIV] 10 [OP_DIV]",
        "solution_abst_en": "100 5 [OP_DIV] 10 [OP_DIV]",
        "solution_code_ko": "var_a = 100\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 10\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 100\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 10\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "1257": {
        "category": "Arithmetic calculation",
        "question_ko": "137보다 크고 151보다 작은 세 자리 수는 모두 몇 개입니까?",
        "question_en": "What is the total number of three-digit numbers that are greater than 137 and less than 151?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "137 1 [OP_ADD] 151 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_LEN]",
        "solution_abst_en": "137 1 [OP_ADD] 151 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 137\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 151\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = len(list_a)\nprint(int(var_h))",
        "solution_code_en": "var_a = 137\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 151\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = len(list_a)\nprint(int(var_h))"
    },
    "1258": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중에서 가장 작은 수를 2번째로 작은 수로 나눈 몫은 얼마입니까?",
        "question_en": "There are three numbers 10, 11 and 12. What is the quotient of the smallest number divided by the second smallest number?",
        "answer_ko": "0",
        "answer_en": "0",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_FDIV]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_FDIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e // var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e // var_g\nprint(int(var_h))"
    },
    "1259": {
        "category": "Comparison",
        "question_ko": "빨간색 승용차는 1시간 45분 동안 147킬로미터(㎞)를 갔고, 검정색 승용차는 2시간 15분 동안 162킬로미터(㎞)를 갔습니다. 어느 승용차가 더 빠릅니까?",
        "question_en": "The red car traveled 147 kilometers (km) in 1 hour and 45 minutes, and the black car traveled 162 kilometers (km) in 2 hours and 15 minutes. Which car is faster?",
        "answer_ko": "빨간색",
        "answer_en": "red",
        "solution_abst_ko": "[OP_LIST_SOL] 빨간색 검정색 [OP_LIST_EOL] [OP_LIST_SOL] 147 1 60 [OP_MUL] 45 [OP_ADD] [OP_DIV] 162 2 60 [OP_MUL] 15 [OP_ADD] [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] red black [OP_LIST_EOL] [OP_LIST_SOL] 147 1 60 [OP_MUL] 45 [OP_ADD] [OP_DIV] 162 2 60 [OP_MUL] 15 [OP_ADD] [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '빨간색'\nvar_b = '검정색'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 147\nvar_d = 1\nvar_e = 60\nvar_f = var_d * var_e\nvar_g = 45\nvar_h = var_f + var_g\nvar_i = var_c / var_h\nvar_j = 162\nvar_k = 2\nvar_l = 60\nvar_m = var_k * var_l\nvar_n = 15\nvar_o = var_m + var_n\nvar_p = var_j / var_o\nlist_b= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nlist_b.reverse()\nvar_q = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_r = list_c[-var_q]\nvar_s = list_b.index(var_r)+1\nvar_t = list_a[var_s-1]\nprint(var_t)",
        "solution_code_en": "var_a = 'red'\nvar_b = 'black'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 147\nvar_d = 1\nvar_e = 60\nvar_f = var_d * var_e\nvar_g = 45\nvar_h = var_f + var_g\nvar_i = var_c / var_h\nvar_j = 162\nvar_k = 2\nvar_l = 60\nvar_m = var_k * var_l\nvar_n = 15\nvar_o = var_m + var_n\nvar_p = var_j / var_o\nlist_b= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nlist_b.reverse()\nvar_q = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_r = list_c[-var_q]\nvar_s = list_b.index(var_r)+1\nvar_t = list_a[var_s-1]\nprint(var_t)"
    },
    "1260": {
        "category": "Arithmetic calculation",
        "question_ko": "자연수 100은 연속된 5개의 자연수의 합이다. 이 연속된 5개의 자연수 중 제일 작은 수가 무엇인지 구하여라.",
        "question_en": "The natural number 100 is the sum of five consecutive natural numbers. Find the smallest of these five consecutive natural numbers.",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "100 5 [OP_DIV] 5 2 [OP_FDIV] [OP_SUB]",
        "solution_abst_en": "100 5 [OP_DIV] 5 2 [OP_FDIV] [OP_SUB]",
        "solution_code_ko": "var_a = 100\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d // var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 100\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d // var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "1261": {
        "category": "Arithmetic calculation",
        "question_ko": "마을 청년회에서 한 상자에 16개씩 들어 있는 배 4상자를 할아버지와 할머니께 선물했습니다. 선물한 배는 모두 몇 개인가?",
        "question_en": "The village youth association presented 4 boxes of pears, each containing 16 pears, to grandpas and grandmas. How many pears did they present?",
        "answer_ko": "64",
        "answer_en": "64",
        "solution_abst_ko": "16 4 [OP_MUL]",
        "solution_abst_en": "16 4 [OP_MUL]",
        "solution_code_ko": "var_a = 16\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 16\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "1262": {
        "category": "Arithmetic calculation",
        "question_ko": "농장에 병아리가 37마리 있었습니다. 1번째 날 병아리 23마리를 더 사 오고, 2번째 날 병아리 12마리를 더 사 왔다면 병아리는 모두 몇 마리가 늘어났습니까?",
        "question_en": "There were 37 chicks on the farm. If a farmer bought 23 more chicks on day 1 and 12 more chicks on day 2, how many more chicks were on the farm?",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "23 12 [OP_ADD]",
        "solution_abst_en": "23 12 [OP_ADD]",
        "solution_code_ko": "var_a = 23\nvar_b = 12\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 23\nvar_b = 12\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "1263": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.9, 1/3의 숫자가 있다. 이 중 0.6보다 큰 숫자들 중 가장 작은 숫자를 구하시오.",
        "question_en": "There are numbers 0.8, 1/2, 0.9, and 1/3. Find the smallest of these numbers greater than 0.6.",
        "answer_ko": "0.80",
        "answer_en": "0.8",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.6 [OP_LIST_MORE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.6 [OP_LIST_MORE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.6\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.6\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "1264": {
        "category": "Correspondence",
        "question_ko": "27A8에 3403를 더한 값은 6153보다 작습니다. 0부터 9까지의 숫자 중 A에 쓸 수 있는 숫자는 모두 몇 개입니까?",
        "question_en": "27A8 plus 3403 is less than 6153. How many digits from 0 to 9 can be A?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "27A8 [OP_GEN_POSSIBLE_LIST] 6153 3403 [OP_SUB] [OP_LIST_LESS] 27A8 A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_abst_en": "27A8 [OP_GEN_POSSIBLE_LIST] 6153 3403 [OP_SUB] [OP_LIST_LESS] 27A8 A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '27A8'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 6153\nvar_c = 3403\nvar_d = var_b - var_c\nlist_b = []\nfor i in list_a:\n    if i < var_d:\n        list_b.append(i)\nvar_e = '27A8'\nvar_f = 'A'\nvar_e = str(var_e)\nvar_f = str(var_f)\nunk_idx = var_e.index(var_f)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nvar_g = len(list_c)\nprint(int(var_g))",
        "solution_code_en": "var_a = '27A8'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 6153\nvar_c = 3403\nvar_d = var_b - var_c\nlist_b = []\nfor i in list_a:\n    if i < var_d:\n        list_b.append(i)\nvar_e = '27A8'\nvar_f = 'A'\nvar_e = str(var_e)\nvar_f = str(var_f)\nunk_idx = var_e.index(var_f)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nvar_g = len(list_c)\nprint(int(var_g))"
    },
    "1265": {
        "category": "Arithmetic calculation",
        "question_ko": "14 초과 105 이하인 자연수 중에서 가장 큰 수를 가장 작은 수로 나눈 몫은 얼마입니까?",
        "question_en": "Of natural numbers greater than 14 and less than 105, what is the quotient of the largest divided by the smallest?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "105 14 1 [OP_ADD] [OP_FDIV]",
        "solution_abst_en": "105 14 1 [OP_ADD] [OP_FDIV]",
        "solution_code_ko": "var_a = 105\nvar_b = 14\nvar_c = 1\nvar_d = var_b + var_c\nvar_e = var_a // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 105\nvar_b = 14\nvar_c = 1\nvar_d = var_b + var_c\nvar_e = var_a // var_d\nprint(int(var_e))"
    },
    "1266": {
        "category": "Correspondence",
        "question_ko": "두 자연수 A와 B에 대해 A를 B로 나누었을 때 몫은 9이고 나머지는 13입니다. A를 9로 나누었을 때 나머지는 얼마입니까?",
        "question_en": "For two natural numbers A and B, the quotient and the remainder are 9 and 13 when A is divided by B. What is the remainder when A is divided by 9?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "13 9 [OP_SUB]",
        "solution_abst_en": "13 9 [OP_SUB]",
        "solution_code_ko": "var_a = 13\nvar_b = 9\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 13\nvar_b = 9\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "1267": {
        "category": "Arithmetic calculation",
        "question_ko": "두 자리 수 중에서 13으로 나누었을 때 나머지가 2인 가장 큰 수를 구하시오.",
        "question_en": "Find the largest two-digit number that has a remainder of 2 when divided by 13.",
        "answer_ko": "93",
        "answer_en": "93",
        "solution_abst_ko": "10 99 1 [OP_LIST_ARANGE] 13 2 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MAX]",
        "solution_abst_en": "10 99 1 [OP_LIST_ARANGE] 13 2 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 13\nvar_e = 2\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint(int(var_g))",
        "solution_code_en": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 13\nvar_e = 2\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint(int(var_g))"
    },
    "1268": {
        "category": "Comparison",
        "question_ko": "20마리의 토끼가 줄을 서 있습니다. 왼쪽에서 13번째와 19번째 토끼 사이에는 몇 마리의 토끼가 있습니까?",
        "question_en": "20 rabbits are lined up. How many rabbits are there between the 13th and 19th rabbits from the left?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "19 13 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "19 13 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 19\nvar_b = 13\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 19\nvar_b = 13\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "1269": {
        "category": "Possibility",
        "question_ko": "A, B, C, D, E 5명이 있을 때, A, C, E를 이웃하여 세우는 경우의 수를 구하시오.",
        "question_en": "If there are 5 people A, B, C, D, E, find the number of ways to make A, C, and E stand next to each other.",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "[OP_LIST_SOL] A B C D E [OP_LIST_EOL] [OP_LIST_SOL] A C [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] A C E [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D E [OP_LIST_EOL] [OP_LIST_SOL] A C [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] A C E [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 'A'\nvar_g = 'C'\nlist_b= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_h = len(list_c)\nvar_i = len(list_c)\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nvar_k = 'A'\nvar_l = 'C'\nvar_m = 'E'\nlist_d= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_d.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_d.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_d.append(var_k)\nlist_d.reverse()\nvar_n = len(list_d)\nvar_o = len(list_d)\nvar_p = 1\nvar_n = int(var_n)\nvar_o = int(var_o)\nfor i, elem in enumerate(range(var_o)):\n    var_p = var_p * (var_n-i)\nvar_q = var_j * var_p\nprint(int(var_q))",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 'A'\nvar_g = 'C'\nlist_b= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_h = len(list_c)\nvar_i = len(list_c)\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nvar_k = 'A'\nvar_l = 'C'\nvar_m = 'E'\nlist_d= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_d.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_d.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_d.append(var_k)\nlist_d.reverse()\nvar_n = len(list_d)\nvar_o = len(list_d)\nvar_p = 1\nvar_n = int(var_n)\nvar_o = int(var_o)\nfor i, elem in enumerate(range(var_o)):\n    var_p = var_p * (var_n-i)\nvar_q = var_j * var_p\nprint(int(var_q))"
    },
    "1270": {
        "category": "Possibility",
        "question_ko": "일곱 개의 숫자 0, 1, 2, 3, 4, 5, 6을 한 번씩 사용하여 일곱 자리 수를 만들었다. 이 수가 55의 배수일 때, 두 번째로 큰 수를 구하여라.",
        "question_en": "The seven digits 0, 1, 2, 3, 4, 5, and 6 are used once to form a seven-digit number. When this number is a multiple of 55, find the second largest number.",
        "answer_ko": "6430215",
        "answer_en": "6430215",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 4 5 6 [OP_LIST_EOL] 7 [OP_LIST_GET_PERM] 55 [OP_LIST_DIVISIBLE] 2 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 4 5 6 [OP_LIST_EOL] 7 [OP_LIST_GET_PERM] 55 [OP_LIST_DIVISIBLE] 2 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nvar_f = 5\nvar_g = 6\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h = 7\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_h))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_i = 55\nlist_c = []\nvar_i = int(var_i)\nfor i in list_b:\n    i = int(i)\n    if i % var_i == 0:\n        list_c.append(i)\nvar_j = 2\nlist_d=list_c.copy()\nlist_d.sort()\nvar_k = list_d[-var_j]\nprint(int(var_k))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nvar_f = 5\nvar_g = 6\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h = 7\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_h))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_i = 55\nlist_c = []\nvar_i = int(var_i)\nfor i in list_b:\n    i = int(i)\n    if i % var_i == 0:\n        list_c.append(i)\nvar_j = 2\nlist_d=list_c.copy()\nlist_d.sort()\nvar_k = list_d[-var_j]\nprint(int(var_k))"
    },
    "1271": {
        "category": "Arithmetic calculation",
        "question_ko": "두 수 12, 36의 공배수 중에서 150보다 작거나 같은 수는 모두 몇 개인지 구하세요.",
        "question_en": "Find how many common multiples of 12 and 36 are less than or equal to 150.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "1 150 1 [OP_LIST_ARANGE] 12 36 [OP_LCM] [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "1 150 1 [OP_LIST_ARANGE] 12 36 [OP_LCM] [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 150\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 12\nvar_e = 36\nvar_f = var_e * var_d / math.gcd(int(var_e), int(var_d))\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 150\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 12\nvar_e = 36\nvar_f = var_e * var_d / math.gcd(int(var_e), int(var_d))\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "1272": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.9, 1/3 중에서 0.4보다 큰 수를 모두 더하면 얼마일까요?",
        "question_en": "What is the sum of numbers which are all greater than 0.4 among 0.8, 1/2, 0.9, and 1/3?",
        "answer_ko": "2.20",
        "answer_en": "2.2",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_MORE] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_MORE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.4\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint('{:.2f}'.format(round(var_f+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.4\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint('{:.2f}'.format(round(var_f+1e-10,2)))"
    },
    "1273": {
        "category": "Arithmetic calculation",
        "question_ko": "10 이하의 홀수 중 3의 배수가 아닌 수들의 합을 구하시오.",
        "question_en": "Out of odd numbers up to 10, find the sum of those that are not multiples of 3.",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "1 10 [OP_LIST_ODD] 3 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] [OP_LIST_SUM]",
        "solution_abst_en": "1 10 [OP_LIST_ODD] 3 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 10\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 3\nlist_b = []\nvar_c = int(var_c)\nfor i in list_a:\n    i = int(i)\n    if i % var_c == 0:\n        list_b.append(i)\nlist_c = list(set(list_a) - set(list_b))\nlist_c = [float(i) for i in list_c]\nvar_d = sum(list_c)\nprint(int(var_d))",
        "solution_code_en": "var_a = 1\nvar_b = 10\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 3\nlist_b = []\nvar_c = int(var_c)\nfor i in list_a:\n    i = int(i)\n    if i % var_c == 0:\n        list_b.append(i)\nlist_c = list(set(list_a) - set(list_b))\nlist_c = [float(i) for i in list_c]\nvar_d = sum(list_c)\nprint(int(var_d))"
    },
    "1274": {
        "category": "Geometry",
        "question_ko": "세로의 길이가 300미터(m)로 같고 넓이도 같은 직사각형 모양의 운동장이 여덟 개 있습니다. 운동장들의 넓이의 합이 0.6제곱킬로미터(㎢)일 때, 운동장의 가로 길이는 몇 미터(m)인지 구하시오.",
        "question_en": "There are eight rectangular-shaped playgrounds with the same length of 300 meters (m) and the same area. If the sum of the areas of the playgrounds is 0.6 square kilometers (km2), how many meters (m) are the width of the playground?",
        "answer_ko": "250",
        "answer_en": "250",
        "solution_abst_ko": "0.6 1000 1000 [OP_MUL] [OP_MUL] 8 [OP_DIV] 300 [OP_DIV]",
        "solution_abst_en": "0.6 1000 1000 [OP_MUL] [OP_MUL] 8 [OP_DIV] 300 [OP_DIV]",
        "solution_code_ko": "var_a = 0.6\nvar_b = 1000\nvar_c = 1000\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nvar_f = 8\nvar_g = var_e / var_f\nvar_h = 300\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 0.6\nvar_b = 1000\nvar_c = 1000\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nvar_f = 8\nvar_g = var_e / var_f\nvar_h = 300\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "1275": {
        "category": "Geometry",
        "question_ko": "94센티미터(㎝)의 테이프를 중간이 겹치도록 접어 68센티미터(㎝)로 만들었습니다. 겹쳐진 부분의 길이를 구하시오.",
        "question_en": "A 94 centimeters (cm) piece of tape is folded as the middle to be overlapped in order to make a 68 centimeters (cm) piece. Find the length of the overlapping part.",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "94 68 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "94 68 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 94\nvar_b = 68\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 94\nvar_b = 68\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "1276": {
        "category": "Arithmetic calculation",
        "question_ko": "8분의 22를 소수로 나타내시오.",
        "question_en": "Convert 22/8 to a decimal number.",
        "answer_ko": "2.75",
        "answer_en": "2.75",
        "solution_abst_ko": "22 8 [OP_DIV]",
        "solution_abst_en": "22 8 [OP_DIV]",
        "solution_code_ko": "var_a = 22\nvar_b = 8\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 22\nvar_b = 8\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "1277": {
        "category": "Correspondence",
        "question_ko": "민정이는 울타리에 페인트를 칠하려고 합니다. 원래 페인트 통에서 4.372밀리리터(㎖)를 덜어내려고 했는데 실수로 43.72밀리리터(㎖)를 덜어내어 16.398밀리리터(㎖)가 페인트 통에 남았다고 한다. 원래대로 덜어내었다면 페인트 통에 몇 밀리리터(㎖)가 남았는지 구하시오.",
        "question_en": "Minjeong wants to paint the fence. Originally, he tried to take 4.372 milliliters (ml) from the paint canister, but accidentally took out 43.72 milliliters (ml), leaving 16.398 milliliters (ml) in the paint canister. If it was taken out as original, find how many milliliters (ml) are left in the paint canister.",
        "answer_ko": "55.75",
        "answer_en": "55.75",
        "solution_abst_ko": "16.398 43.72 [OP_ADD] 4.372 [OP_SUB]",
        "solution_abst_en": "16.398 43.72 [OP_ADD] 4.372 [OP_SUB]",
        "solution_code_ko": "var_a = 16.398\nvar_b = 43.72\nvar_c = var_a + var_b\nvar_d = 4.372\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 16.398\nvar_b = 43.72\nvar_c = var_a + var_b\nvar_d = 4.372\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "1278": {
        "category": "Comparison",
        "question_ko": "학생들이 한 줄로 서 있습니다. 태형이는 맨 앞에 서 있습니다. 남준이의 뒤에는 8명이 서 있습니다. 태형이와 남준이 사이에는 3명이 서 있습니다. 줄을 서 있는 학생은 모두 몇 명입니까?",
        "question_en": "Students stand in a line. Taehyung is standing in the front. Eight people are standing behind Namjoon. There are three people standing between Taehyung and Namjoon. How many students are in line?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "1 3 [OP_ADD] 1 [OP_ADD] 8 [OP_ADD]",
        "solution_abst_en": "1 3 [OP_ADD] 1 [OP_ADD] 8 [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "1279": {
        "category": "Correspondence",
        "question_ko": "A, B는 한 자리 수이다. A에서 2를 빼면 B이고 5보다 3 큰 숫자는 A이다. 이때 A+B를 구하여라.",
        "question_en": "A and B are single-digit numbers. Subtracting 2 from A is B, and the number 3 greater than 5 is A. Find A+B.",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "5 3 [OP_ADD] 5 3 [OP_ADD] 2 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "5 3 [OP_ADD] 5 3 [OP_ADD] 2 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = 2\nvar_h = var_f - var_g\nvar_i = var_c + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 5\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = 2\nvar_h = var_f - var_g\nvar_i = var_c + var_h\nprint(int(var_i))"
    },
    "1280": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 125까지 수를 칠판에 적을 때, 숫자 2는 모두 몇 번 사용되는지 구하시오.",
        "question_en": "When writing the numbers 1 through 125 on the board, how many times is the number 2 used?",
        "answer_ko": "29",
        "answer_en": "29",
        "solution_abst_ko": "1 125 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 2 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 125 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 2 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 125\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 2\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 125\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 2\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))"
    },
    "1281": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 10, 11, 12, 13이 있습니다. 그 중에서 2번째로 큰 수와 가장 작은 수의 곱은 얼마입니까?",
        "question_en": "There are four numbers: 10, 11, 12, and 13. What is the product of the second largest number and the smallest number?",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 2 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 2 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f * var_h\nprint(int(var_i))"
    },
    "1282": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 25센티미터(㎝)인 정사각형 모양의 색종이 15장을 0.5센티미터(㎝)씩 겹치게 이어 붙였습니다. 이렇게 만들어진 색종이의 한 변의 길이가 최대가 될 때, 그 길이는 몇 미터(m)일지 구하시오.",
        "question_en": "There are fifteen pieces of square-shaped colored paper with a side length of 25 centimeters (cm) glued together. Given that they were overlapped by 0.5 centimeters (cm) to connect them having a maximum length of one side of the paper, find its length in meters (m).",
        "answer_ko": "3.68",
        "answer_en": "3.68",
        "solution_abst_ko": "25 15 [OP_MUL] 0.5 15 1 [OP_SUB] [OP_MUL] [OP_SUB] 100 [OP_DIV]",
        "solution_abst_en": "25 15 [OP_MUL] 0.5 15 1 [OP_SUB] [OP_MUL] [OP_SUB] 100 [OP_DIV]",
        "solution_code_ko": "var_a = 25\nvar_b = 15\nvar_c = var_a * var_b\nvar_d = 0.5\nvar_e = 15\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_c - var_h\nvar_j = 100\nvar_k = var_i / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 25\nvar_b = 15\nvar_c = var_a * var_b\nvar_d = 0.5\nvar_e = 15\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_c - var_h\nvar_j = 100\nvar_k = var_i / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "1283": {
        "category": "Arithmetic calculation",
        "question_ko": "집합 A의 원소는 1, 3, 5이고, 집합 B의 원소는 2, 5일 때 집합 A와 B의 교집합의 원소의 개수를 구하시오.",
        "question_en": "If the elements of set A are 1, 3, and 5, and the elements of set B are 2 and 5, find the number of elements in the intersection of sets A and B.",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 5 [OP_LIST_EOL] [OP_LIST_SOL] 2 5 [OP_LIST_EOL] [OP_SET_INTERSECT] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 5 [OP_LIST_EOL] [OP_LIST_SOL] 2 5 [OP_LIST_EOL] [OP_SET_INTERSECT] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nvar_e = 5\nlist_b= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nlist_c = list(set(list_a) & set(list_b))\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nvar_e = 5\nlist_b= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nlist_c = list(set(list_a) & set(list_b))\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "1284": {
        "category": "Comparison",
        "question_ko": "소라빵은 250그램(g)이고 12개씩 담아서 2개의 상자를 만들었습니다. 단팥빵은 200그램(g)이고 16개씩 담아서 3개의 상자로 만들었습니다. 한 상자의 무게가 더 무거운 상자에 들어 있는 빵은 무엇입니까?",
        "question_en": "The conch-shaped bread is 250 grams (g) and I made two boxes with 12 each. The Red-bean bread is 200 grams (g) and is made into three boxes with 16 each. Which bread is in the box that weighs more than other boxes?",
        "answer_ko": "단팥빵",
        "answer_en": "Red-bean",
        "solution_abst_ko": "[OP_LIST_SOL] 단팥빵 소라빵 [OP_LIST_EOL] [OP_LIST_SOL] 200 16 [OP_MUL] 250 12 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Red-bean conch-shaped [OP_LIST_EOL] [OP_LIST_SOL] 200 16 [OP_MUL] 250 12 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '단팥빵'\nvar_b = '소라빵'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 200\nvar_d = 16\nvar_e = var_c * var_d\nvar_f = 250\nvar_g = 12\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Red-bean'\nvar_b = 'conch-shaped'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 200\nvar_d = 16\nvar_e = var_c * var_d\nvar_f = 250\nvar_g = 12\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "1285": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 27을 뺐더니 49가 되었습니다. 어떤 수를 구하시오.",
        "question_en": "Subtracting 27 from a number gives 49. Find a number.",
        "answer_ko": "76",
        "answer_en": "76",
        "solution_abst_ko": "49 27 [OP_ADD]",
        "solution_abst_en": "49 27 [OP_ADD]",
        "solution_code_ko": "var_a = 49\nvar_b = 27\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 49\nvar_b = 27\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "1286": {
        "category": "Arithmetic calculation",
        "question_ko": "지민이의 사회 점수는 과학 점수보다 6점 높다. 과학 점수가 87점이다. 과학, 사회, 영어의 평균 점수가 92점이라면 영어 점수는 몇 점인가?",
        "question_en": "Jimin's social studies score is 6 points higher than his science score. The science score is 87. If the average score for science, social studies, and English is 92, what is his English score?",
        "answer_ko": "96",
        "answer_en": "96",
        "solution_abst_ko": "92 3 [OP_MUL] 87 87 6 [OP_ADD] [OP_ADD] [OP_SUB]",
        "solution_abst_en": "92 3 [OP_MUL] 87 87 6 [OP_ADD] [OP_ADD] [OP_SUB]",
        "solution_code_ko": "var_a = 92\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 87\nvar_e = 87\nvar_f = 6\nvar_g = var_e + var_f\nvar_h = var_d + var_g\nvar_i = var_c - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 92\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 87\nvar_e = 87\nvar_f = 6\nvar_g = var_e + var_f\nvar_h = var_d + var_g\nvar_i = var_c - var_h\nprint(int(var_i))"
    },
    "1287": {
        "category": "Comparison",
        "question_ko": "지수가 설거지를 하고난 후 접시를 선반의 위에서 2번째 칸, 아래에서 4번째 칸, 왼쪽에서 1번째 칸, 오른쪽에서 7번째 칸에 놓았습니다. 선반의 모든 칸의 개수는 몇 칸입니까?",
        "question_en": "After Jisoo washed the dishes, she put the plate on the cupboard 2nd from the top, 4th from the bottom, 1st from the left, and 7th from the right. How many slots are there on the cupboard?",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "2 4 [OP_ADD] 1 [OP_SUB] 1 7 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "2 4 [OP_ADD] 1 [OP_SUB] 1 7 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = 7\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = 7\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))"
    },
    "1288": {
        "category": "Geometry",
        "question_ko": "어떤 직사각형은 넓이가 108제곱센티미터(㎠)인 직사각형보다 작으면서 가로의 비가 8:7이고 세로의 비가 9:4입니다. 이 직사각형의 넓이는 몇 제곱센티미터(㎠)입니까?",
        "question_en": "There is a rectangle that is smaller than a rectangle measuring 108 square centimeters (cm2) with a width ratio of 8:7 and a height ratio of 9:4. What is the area of this rectangle in square centimeters (cm2)?",
        "answer_ko": "42",
        "answer_en": "42",
        "solution_abst_ko": "108 8 [OP_DIV] 7 [OP_MUL] 9 [OP_DIV] 4 [OP_MUL]",
        "solution_abst_en": "108 8 [OP_DIV] 7 [OP_MUL] 9 [OP_DIV] 4 [OP_MUL]",
        "solution_code_ko": "var_a = 108\nvar_b = 8\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c * var_d\nvar_f = 9\nvar_g = var_e / var_f\nvar_h = 4\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 108\nvar_b = 8\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c * var_d\nvar_f = 9\nvar_g = var_e / var_f\nvar_h = 4\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "1289": {
        "category": "Geometry",
        "question_ko": "넓이가 222제곱센티미터(㎠)인 사다리꼴이 있습니다. 이 사다리꼴의 윗변의 길이가 23센티미터(㎝)이고, 높이가 12센티미터(㎝)라면, 밑변의 길이는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "There is a trapezoid with an area of 222 square centimeters (cm2). If the length of the upper side of this trapezoid is 23 centimeters (cm) and the height is 12 centimeters (cm), how many centimeters (cm) is the length of the base of the trapezoid?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "222 2 [OP_MUL] 12 [OP_DIV] 23 [OP_SUB]",
        "solution_abst_en": "222 2 [OP_MUL] 12 [OP_DIV] 23 [OP_SUB]",
        "solution_code_ko": "var_a = 222\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = var_c / var_d\nvar_f = 23\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 222\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = var_c / var_d\nvar_f = 23\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "1290": {
        "category": "Comparison",
        "question_ko": "윤기는 4, 정국에는 6에서 3을 뺀 수를 모았습니다. 누구의 수가 작습니까?",
        "question_en": "Yoongi collected 4, and Jungkook collected 6 minus 3. Whose number is smaller?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 6\nvar_e = 3\nvar_f = var_d - var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 6\nvar_e = 3\nvar_f = var_d - var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "1291": {
        "category": "Arithmetic calculation",
        "question_ko": "선호는 큰 정육면체 나무도막 1개를 잘라서 여러개의 작은 정육면체 나무도막을 만들려고 합니다. 작은 나무도막의 한 변의 길이는 큰 나무도막의 한 변의 길이의 1/4입니다. 이 때 만들 수 있는 작은 나무도막의 개수를 구하세요.",
        "question_en": "Seonho wants to cut 1 large cube of wood into several small cubes of wood. The length of a side of a small block of wood is 1/4 of the length of a side of a block of large wood. Find the number of small wooden blocks that can be made at this time.",
        "answer_ko": "64",
        "answer_en": "64",
        "solution_abst_ko": "1 1/4 3 [OP_POW] [OP_DIV]",
        "solution_abst_en": "1 1/4 3 [OP_POW] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 0.25\nvar_c = 3\nvar_d = var_b ** var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 0.25\nvar_c = 3\nvar_d = var_b ** var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "1292": {
        "category": "Correspondence",
        "question_ko": "A,B는 서로 다른 수입니다. 8AA4-BBB=BBBB일 때 A와 B를 더한 결과를 구하시오.",
        "question_en": "A and B are different numbers. When 8AA4-BBB=BBBB, find the result of A plus B.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "8AA4-BBB=BBBB A [OP_DIGIT_UNK_SOLVER] 8AA4-BBB=BBBB B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_abst_en": "8AA4-BBB=BBBB A [OP_DIGIT_UNK_SOLVER] 8AA4-BBB=BBBB B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_code_ko": "var_a = '8AA4-BBB=BBBB'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '8AA4-BBB=BBBB'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = '8AA4-BBB=BBBB'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '8AA4-BBB=BBBB'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "1293": {
        "category": "Geometry",
        "question_ko": "각기둥의 밑면이 정육각형이며, 정육각형의 한 변의 길이는 6센티미터(㎝), 각기둥의 높이는 11센티미터(㎝)이다. 이 각기둥의 모든 모서리의 길이의 합을 구하시오",
        "question_en": "The base of the prism is a regular hexagon, which has the length of one side as 6 centimeters (cm), and the height of the prism is 11 centimeters (cm). Find the sum of the lengths of all the edges of this prism.",
        "answer_ko": "138",
        "answer_en": "138",
        "solution_abst_ko": "6 6 [OP_MUL] 2 [OP_MUL] 11 6 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "6 6 [OP_MUL] 2 [OP_MUL] 11 6 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 11\nvar_g = 6\nvar_h = var_f * var_g\nvar_i = var_e + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 6\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 11\nvar_g = 6\nvar_h = var_f * var_g\nvar_i = var_e + var_h\nprint(int(var_i))"
    },
    "1294": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 13배 한 수에서 272를 뺐더니 105가 되었습니다. 어떤 수를 구하시오.",
        "question_en": "Multiplying a number by 13 and subtracting 272 gives you 105. Find the number.",
        "answer_ko": "29",
        "answer_en": "29",
        "solution_abst_ko": "105 272 [OP_ADD] 13 [OP_DIV]",
        "solution_abst_en": "105 272 [OP_ADD] 13 [OP_DIV]",
        "solution_code_ko": "var_a = 105\nvar_b = 272\nvar_c = var_a + var_b\nvar_d = 13\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 105\nvar_b = 272\nvar_c = var_a + var_b\nvar_d = 13\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "1295": {
        "category": "Geometry",
        "question_ko": "마주 보는 두 쌍의 변이 서로 평행인 사각형이 있습니다. 이 사각형의 밑변이 9.51센티미터(㎝), 높이가 4.8센티미터(㎝)라면 넓이는 얼마입니까?",
        "question_en": "A quadrilateral has two pairs of opposite sides parallel to each other. If the base of this rectangle is 9.51 centimeters (cm) and the height is 4.8 centimeters (cm), what is the area?",
        "answer_ko": "45.65",
        "answer_en": "45.65",
        "solution_abst_ko": "9.51 4.8 [OP_MUL]",
        "solution_abst_en": "9.51 4.8 [OP_MUL]",
        "solution_code_ko": "var_a = 9.51\nvar_b = 4.8\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 9.51\nvar_b = 4.8\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "1296": {
        "category": "Possibility",
        "question_ko": "도훈이는 3, 6, 9가 써진 공을 산 위에서 한 개씩 굴리려고 합니다. 굴리는 순서에 따라 결과가 다를 때, 도훈이는 총 몇 가지의 결과를 볼 수 있습니까?",
        "question_en": "Dohun is about to roll balls with numbers 3, 6, and 9 one by one on top of the mountain. When the results differ depending on the rolling order, how many total results can Dohun see?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 3 6 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 3 6 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 3\nvar_b = 6\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 3\nvar_b = 6\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "1297": {
        "category": "Correspondence",
        "question_ko": "A, B는 한 자리 수입니다. 7ABABA가 6으로 나누어 떨어진다고 할 때, 7ABABA가 될 수 있는 모든 수의 개수를 구하시오.",
        "question_en": "A and B are single digit numbers. If 7ABABA is divisible by 6, find all possible number of cases that can be 7ABABA.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "7ABABA [OP_GEN_POSSIBLE_LIST] 6 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "7ABABA [OP_GEN_POSSIBLE_LIST] 6 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '7ABABA'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 6\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))",
        "solution_code_en": "var_a = '7ABABA'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 6\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))"
    },
    "1298": {
        "category": "Correspondence",
        "question_ko": "식 5A8-B14=364이 있습니다. A에 들어가야 하는 숫자를 구하시오.",
        "question_en": "We have the expression 5A8-B14=364. Find the number that goes into A.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "5A8-B14=364 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "5A8-B14=364 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '5A8-B14=364'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '5A8-B14=364'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "1299": {
        "category": "Correspondence",
        "question_ko": "A와 B의 합을 찾으시오. 3/7=6/A=B/21",
        "question_en": "Find the sum of A and B. 3/7=6/A=B/21",
        "answer_ko": "23",
        "answer_en": "23",
        "solution_abst_ko": "3/7=6/A=B/21 A [OP_NUM_UNK_SOLVER] 3/7=6/A=B/21 B [OP_NUM_UNK_SOLVER] [OP_ADD]",
        "solution_abst_en": "3/7=6/A=B/21 A [OP_NUM_UNK_SOLVER] 3/7=6/A=B/21 B [OP_NUM_UNK_SOLVER] [OP_ADD]",
        "solution_code_ko": "var_a = '3/7=6/A=B/21'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '3/7=6/A=B/21'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = '3/7=6/A=B/21'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '3/7=6/A=B/21'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "1300": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 가장 작은 수를 2번째로 작은 수로 나눈 나머지는 얼마입니까?",
        "question_en": "There are five numbers 10, 11, 12, 13, and 14. What is the remainder when divided by the smallest number and the second smallest number?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_MOD]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_MOD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g % var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g % var_i\nprint(int(var_j))"
    },
    "1301": {
        "category": "Arithmetic calculation",
        "question_ko": "예준이가 다니는 피아노 학원의 학생 수는 41명이고, 그중에서 푸름초등학교에 다니는 학생은 푸름초등학교에 다니지 않는 학생보다 3명 많습니다. 푸름초등학교에 다니는 학생은 몇 명입니까?",
        "question_en": "There are 41 students in the piano academy that Yejun attends, and among them, 3 more students attend Purum Elementary School than those who do not attend Purum Elementary School. How many students attend Purum Elementary School?",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "41 3 [OP_SUB] 2 [OP_DIV] 3 [OP_ADD]",
        "solution_abst_en": "41 3 [OP_SUB] 2 [OP_DIV] 3 [OP_ADD]",
        "solution_code_ko": "var_a = 41\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 3\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 41\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 3\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "1302": {
        "category": "Arithmetic calculation",
        "question_ko": "한 봉지에 156개씩 담은 초콜릿이 20봉지 있습니다. 초콜릿은 모두 몇 개일까요?",
        "question_en": "There are 20 bags of chocolates, each containing 156 pieces. How many chocolates are there in all?",
        "answer_ko": "3120",
        "answer_en": "3120",
        "solution_abst_ko": "156 20 [OP_MUL]",
        "solution_abst_en": "156 20 [OP_MUL]",
        "solution_code_ko": "var_a = 156\nvar_b = 20\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 156\nvar_b = 20\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "1303": {
        "category": "Correspondence",
        "question_ko": "윤기는 어떤 수에서 56을 빼 11를 얻었습니다. 어떤 수를 구하시오.",
        "question_en": "Yoongi subtracts 56 from a certain number to get 11. Find the number.",
        "answer_ko": "67",
        "answer_en": "67",
        "solution_abst_ko": "11 56 [OP_ADD]",
        "solution_abst_en": "11 56 [OP_ADD]",
        "solution_code_ko": "var_a = 11\nvar_b = 56\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 11\nvar_b = 56\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "1304": {
        "category": "Possibility",
        "question_ko": "4개의 숫자 1, 5, 6, 9를 한 번씩 사용하여 십의 자리 숫자가 5인 두 번째로 작은 두 자리 수를 구하시오.",
        "question_en": "Using the four digits 1, 5, 6, and 9 once, find the second smallest two-digit number whose tens digit is 5.",
        "answer_ko": "56",
        "answer_en": "56",
        "solution_abst_ko": "[OP_LIST_SOL] 1 5 6 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 10 5 [OP_LIST_SEARCH_FIXED_DIGIT] 2 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 5 6 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 10 5 [OP_LIST_SEARCH_FIXED_DIGIT] 2 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1\nvar_b = 5\nvar_c = 6\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 5\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 2\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 5\nvar_c = 6\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 5\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 2\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nprint(int(var_i))"
    },
    "1305": {
        "category": "Arithmetic calculation",
        "question_ko": "네 자리 수 중 2, 3, 8, 9의 공배수 중 가장 작은 수는 무엇입니까?",
        "question_en": "Which four-digit number is the smallest common multiple of 2, 3, 8, and 9?",
        "answer_ko": "1008",
        "answer_en": "1008",
        "solution_abst_ko": "1000 9999 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "1000 9999 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 3\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = 1\nlist_f=list_e.copy()\nlist_f.sort()\nvar_i = list_f[var_h-1]\nprint(int(var_i))",
        "solution_code_en": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 3\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = 1\nlist_f=list_e.copy()\nlist_f.sort()\nvar_i = list_f[var_h-1]\nprint(int(var_i))"
    },
    "1306": {
        "category": "Correspondence",
        "question_ko": "7를 어떤 수에서 뺐더니 9가 되었습니다. 5를 어떤 수에 곱하면 얼마가 되는지 구하시오.",
        "question_en": "Some number minus 7 returns 9. What will be the answer if the number is multiplied by 5?",
        "answer_ko": "80",
        "answer_en": "80",
        "solution_abst_ko": "9 7 [OP_ADD] 5 [OP_MUL]",
        "solution_abst_en": "9 7 [OP_ADD] 5 [OP_MUL]",
        "solution_code_ko": "var_a = 9\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "1307": {
        "category": "Arithmetic calculation",
        "question_ko": "100부터 200까지의 홀수의 합을 구하시오.",
        "question_en": "Find the sum of odd numbers from 100 to 200.",
        "answer_ko": "7500",
        "answer_en": "7500",
        "solution_abst_ko": "100 200 [OP_LIST_ODD] [OP_LIST_SUM]",
        "solution_abst_en": "100 200 [OP_LIST_ODD] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 100\nvar_b = 200\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nprint(int(var_c))",
        "solution_code_en": "var_a = 100\nvar_b = 200\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nprint(int(var_c))"
    },
    "1308": {
        "category": "Geometry",
        "question_ko": "94센티미터(㎝)의 운동화 끈을 중간이 겹치도록 접어 68센티미터(㎝)로 만들었을 때, 겹쳐진 부분의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "If you fold a 94 centimeters (cm) shoelace to be 68 centimeters (cm) so that the middle overlaps, how long is the overlapped part in centimeters (cm)?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "94 68 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "94 68 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 94\nvar_b = 68\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 94\nvar_b = 68\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "1309": {
        "category": "Comparison",
        "question_ko": "밭의 2/7에는 배추, 3/8에는 가지를 심었습니다. 배추와 가지 중 어느 것을 심은 부분이 더 넓을까요?",
        "question_en": "Chinese cabbage was planted on 2/7 of the field and eggplant on 3/8. Cabbage or eggplant, which planted area is larger?",
        "answer_ko": "가지",
        "answer_en": "eggplant",
        "solution_abst_ko": "[OP_LIST_SOL] 배추 가지 [OP_LIST_EOL] [OP_LIST_SOL] 2/7 3/8 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] cabbage eggplant [OP_LIST_EOL] [OP_LIST_SOL] 2/7 3/8 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '배추'\nvar_b = '가지'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.2857142857142857\nvar_d = 0.375\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'cabbage'\nvar_b = 'eggplant'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.2857142857142857\nvar_d = 0.375\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "1310": {
        "category": "Geometry",
        "question_ko": "양을 기르는 목장의 둘레에는 10미터(m) 간격으로 96개의 말뚝이 있고 말을 기르는 목장의 둘레에는 20미터(m) 간격으로 82개의 말뚝이 있습니다. 두 목장의 둘레의 차는 몇 미터(m)입니까?",
        "question_en": "There are 96 stakes at 10-meter (m) intervals around the sheep pasture, and 82 stakes at 20-meter (m) intervals around the perimeter of the horse pasture. What is the difference between the perimeters of the two ranches in meters (m)?",
        "answer_ko": "680",
        "answer_en": "680",
        "solution_abst_ko": "10 96 [OP_MUL] 20 82 [OP_MUL] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "10 96 [OP_MUL] 20 82 [OP_MUL] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 10\nvar_b = 96\nvar_c = var_a * var_b\nvar_d = 20\nvar_e = 82\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = abs(var_g)\nprint(int(var_h))",
        "solution_code_en": "var_a = 10\nvar_b = 96\nvar_c = var_a * var_b\nvar_d = 20\nvar_e = 82\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = abs(var_g)\nprint(int(var_h))"
    },
    "1311": {
        "category": "Possibility",
        "question_ko": "자연수 2, 5, 6, 9를 겹치지 않게 모두 사용하여 만들 수 있는 네 자리 수는 총 몇 가지 입니까?",
        "question_en": "How many total four-digit numbers can be formed by using all the natural numbers 2, 5, 6, and 9 without overlapping?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "[OP_LIST_SOL] 2 5 9 6 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 2 5 9 6 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 2\nvar_b = 5\nvar_c = 9\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 2\nvar_b = 5\nvar_c = 9\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "1312": {
        "category": "Arithmetic calculation",
        "question_ko": "지네는 3분동안 5미터(m)를 기어갈 수 있습니다. 지렁이는 2분에 5미터(m)를 기어갈 수 있습니다. 지네의 출발점은 지렁이보다 20미터(m) 앞서있고 동시에 앞을 보고 출발했다면 지네와 지렁이가 만나게 되는 때는 출발 몇 분 후인지 구하세요.",
        "question_en": "While a centipede can crawl 5 meters (m) in 3 minutes, an earthworm can crawl 5 meters (m) in 2 minutes. If the centipede starts crawling 20 meters (m) ahead of the earthworm and they both start crawling at the same time, find how many minutes takes for them to meet after the departure.",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "20 5 2 [OP_DIV] 5 3 [OP_DIV] [OP_SUB] [OP_DIV]",
        "solution_abst_en": "20 5 2 [OP_DIV] 5 3 [OP_DIV] [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 20\nvar_b = 5\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = 5\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = var_d - var_g\nvar_i = var_a / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))",
        "solution_code_en": "var_a = 20\nvar_b = 5\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = 5\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = var_d - var_g\nvar_i = var_a / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))"
    },
    "1313": {
        "category": "Comparison",
        "question_ko": "정국이는 0.8, 윤기는 1/2, 유정이는 0.9, 유나는 1/3의 숫자카드를 갖고 있습니다. 0.3보다 크거나 같은 숫자카드를 가지고 있는 사람은 몇 명입니까?",
        "question_en": "Jungkook has 0.8, Yoongi has 1/2, Yoojung has 0.9, Yuna has 1/3 number card. How many people have number cards greater than or equal to 0.3?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.3 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.3 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.3\nlist_b = []\nfor i in list_a:\n    if i >= var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.3\nlist_b = []\nfor i in list_a:\n    if i >= var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "1314": {
        "category": "Arithmetic calculation",
        "question_ko": "장미가 34송이 있습니다. 백합은 장미보다 13송이 더 많습니다. 튤립은 백합보다 23송이 적습니다. 장미, 백합, 튤립은 모두 몇 송이 있습니까?",
        "question_en": "There are 34 roses. There are 13 more lilies than roses. There are 23 fewer tulips than lilies. How many roses, lilies and tulips are there in all?",
        "answer_ko": "105",
        "answer_en": "105",
        "solution_abst_ko": "34 34 13 [OP_ADD] [OP_ADD] 34 13 [OP_ADD] 23 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "34 34 13 [OP_ADD] [OP_ADD] 34 13 [OP_ADD] 23 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 34\nvar_b = 34\nvar_c = 13\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nvar_f = 34\nvar_g = 13\nvar_h = var_f + var_g\nvar_i = 23\nvar_j = var_h - var_i\nvar_k = var_e + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 34\nvar_b = 34\nvar_c = 13\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nvar_f = 34\nvar_g = 13\nvar_h = var_f + var_g\nvar_i = 23\nvar_j = var_h - var_i\nvar_k = var_e + var_j\nprint(int(var_k))"
    },
    "1315": {
        "category": "Arithmetic calculation",
        "question_ko": "수영장에 1번째 날에는 215리터(L)의 물을 넣고, 2번째 날에는 1번째 날보다 76리터(L)의 물을 더 많이 넣었습니다. 3번째 날에는 2번째 날보다 53리터(L) 더 적게 넣었습니다. 매일 평균 몇 리터(L)의 물을 넣었습니까?",
        "question_en": "On day 1, 215 liters (l) of water was added to the pool, and on day 2, 76 liters (l) of water was added than on day 1. On the third day, I put 53 liters (l) less than on the second day. How many liters (l) of water do you drink on average each day?",
        "answer_ko": "248",
        "answer_en": "248",
        "solution_abst_ko": "215 215 76 [OP_ADD] [OP_ADD] 215 76 [OP_ADD] 53 [OP_SUB] [OP_ADD] 3 [OP_DIV]",
        "solution_abst_en": "215 215 76 [OP_ADD] [OP_ADD] 215 76 [OP_ADD] 53 [OP_SUB] [OP_ADD] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 215\nvar_b = 215\nvar_c = 76\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nvar_f = 215\nvar_g = 76\nvar_h = var_f + var_g\nvar_i = 53\nvar_j = var_h - var_i\nvar_k = var_e + var_j\nvar_l = 3\nvar_m = var_k / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 215\nvar_b = 215\nvar_c = 76\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nvar_f = 215\nvar_g = 76\nvar_h = var_f + var_g\nvar_i = 53\nvar_j = var_h - var_i\nvar_k = var_e + var_j\nvar_l = 3\nvar_m = var_k / var_l\nprint(int(var_m))"
    },
    "1316": {
        "category": "Possibility",
        "question_ko": "0, 2, 4, 6 중 세 개를 선택하고 이를 한 번씩만 사용하여 세 자리 수를 만들려고 합니다. 가능한 가장 큰 수와 가장 작은 수의 곱을 찾으십시오.",
        "question_en": "You want to create a three-digit number by selecting three numbers from 0, 2, 4, and 6. If only the number can be used once, find the product of the largest possible number and the smallest possible number.",
        "answer_ko": "130968",
        "answer_en": "130968",
        "solution_abst_ko": "[OP_LIST_SOL] 0 2 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 0 2 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MUL]",
        "solution_code_ko": "var_a = 0\nvar_b = 2\nvar_c = 4\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g * var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 0\nvar_b = 2\nvar_c = 4\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g * var_i\nprint(int(var_j))"
    },
    "1317": {
        "category": "Geometry",
        "question_ko": "정사각형 모양의 딱지를 가로와 세로 모두 10장씩 빈틈없이 늘어놓아 정사각형을 만들었습니다. 둘레에 놓인 딱지의 개수를 구하시오.",
        "question_en": "A square was created by arranging 10 square-shaped ttakjis for each vertical and horizontal line without gaps. Find the number of ttakjis placed at the perimeter.",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "10 4 [OP_MUL] 4 [OP_SUB]",
        "solution_abst_en": "10 4 [OP_MUL] 4 [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "1318": {
        "category": "Correspondence",
        "question_ko": "13+4A=58입니다. A는 얼마인가요?",
        "question_en": "13+4A=58. How much is A?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "13+4A=58 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "13+4A=58 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '13+4A=58'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '13+4A=58'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "1319": {
        "category": "Arithmetic calculation",
        "question_ko": "6킬로미터(㎞)인 도로를 1분에 2킬로미터(㎞)달리는 자동차가 있다. 자동차가 2킬로미터(㎞)지점에 있다면 출발한 지 몇 분 후인지 구하시오.",
        "question_en": "A car travels 2 kilometers (km) per minute on a 6-kilometer (km) road. If the car is at a 2-kilometer (km) point, find how many minutes have passed after the car set off.",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "2 2 [OP_DIV]",
        "solution_abst_en": "2 2 [OP_DIV]",
        "solution_code_ko": "var_a = 2\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "1320": {
        "category": "Arithmetic calculation",
        "question_ko": "모든 학생들에게 똑같이 나눌 때, 공책 60권과 연필 84자루는 최대 몇 명에게 나누어줄 수 있습니까?",
        "question_en": "If 60 notebooks and 84 pencils should be distributed equally to all students, think of the maximum number of students that can receive the supplies.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "60 60 84 [OP_GCD] [OP_DIV]",
        "solution_abst_en": "60 60 84 [OP_GCD] [OP_DIV]",
        "solution_code_ko": "var_a = 60\nvar_b = 60\nvar_c = 84\nvar_d = math.gcd(int(var_c), int(var_b))\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 60\nvar_b = 60\nvar_c = 84\nvar_d = math.gcd(int(var_c), int(var_b))\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "1321": {
        "category": "Possibility",
        "question_ko": "4개의 숫자 카드 0, 1, 4, 8을 중복을 사용하여 세 자리 수를 만들려고 한다. 십의 자리 숫자가 0인 가장 큰 세 자리 수를 구하시오.",
        "question_en": "Use the four number cards 0, 1, 4, and 8 in duplicate to find the largest three-digit number with zero in the tens digit.",
        "answer_ko": "808",
        "answer_en": "808",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 4 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 10 0 [OP_LIST_SEARCH_FIXED_DIGIT] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 4 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 10 0 [OP_LIST_SEARCH_FIXED_DIGIT] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 4\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 0\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nprint(int(var_i))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 4\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 0\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nprint(int(var_i))"
    },
    "1322": {
        "category": "Possibility",
        "question_ko": "두 개의 동전 A, B를 던질 때, 앞면이 2개 또는 1개가 나오는 경우의 수는 몇 가지입니까?",
        "question_en": "When tossing two coins, A and B, how many times can you get 2 heads or 1 heads?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "2 [OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_SUB] [OP_POW] 2 [OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_LEN] 1 [OP_SUB] [OP_POW] [OP_ADD]",
        "solution_abst_en": "2 [OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_SUB] [OP_POW] 2 [OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_LEN] 1 [OP_SUB] [OP_POW] [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 'A'\nvar_c = 'B'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = var_a ** var_f\nvar_h = 2\nvar_i = 'A'\nvar_j = 'B'\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nlist_b.reverse()\nvar_k = len(list_b)\nvar_l = 1\nvar_m = var_k - var_l\nvar_n = var_h ** var_m\nvar_o = var_g + var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 2\nvar_b = 'A'\nvar_c = 'B'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = var_a ** var_f\nvar_h = 2\nvar_i = 'A'\nvar_j = 'B'\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nlist_b.reverse()\nvar_k = len(list_b)\nvar_l = 1\nvar_m = var_k - var_l\nvar_n = var_h ** var_m\nvar_o = var_g + var_n\nprint(int(var_o))"
    },
    "1323": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 5센티미터(㎝)인 정사각형의 넓이와 한 변의 길이가 4센티미터(㎝)인 직사각형의 넓이는 같습니다. 직사각형의 다른 한변의 길이를 소수로 나타내어 보세요.",
        "question_en": "The area of a square with a side of 5 centimeters (cm) is equal to the area of a rectangle with a side of 4 centimeters (cm). Find the length of the other side of the rectangle as a decimal number.",
        "answer_ko": "6.25",
        "answer_en": "6.25",
        "solution_abst_ko": "5 2 [OP_POW] 4 [OP_DIV]",
        "solution_abst_en": "5 2 [OP_POW] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "1324": {
        "category": "Arithmetic calculation",
        "question_ko": "사이다 120밀리리터(㎖)가 5병이 있고 콜라 350밀리리터(㎖)가 3병이 있다. 2500밀리리터(㎖)를 마시려고 할 때 더 필요한 음료의 양은 몇 밀리리터(㎖)인지 구하시오.",
        "question_en": "There are 5 bottles of 120 milliliters (ml) of soda and 3 bottles of 350 milliliters (ml) of coke. If you want to drink 2500 milliliters (ml), find how many milliliters (ml) more you need to drink.",
        "answer_ko": "850",
        "answer_en": "850",
        "solution_abst_ko": "2500 120 5 [OP_MUL] 350 3 [OP_MUL] [OP_ADD] [OP_SUB]",
        "solution_abst_en": "2500 120 5 [OP_MUL] 350 3 [OP_MUL] [OP_ADD] [OP_SUB]",
        "solution_code_ko": "var_a = 2500\nvar_b = 120\nvar_c = 5\nvar_d = var_b * var_c\nvar_e = 350\nvar_f = 3\nvar_g = var_e * var_f\nvar_h = var_d + var_g\nvar_i = var_a - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 2500\nvar_b = 120\nvar_c = 5\nvar_d = var_b * var_c\nvar_e = 350\nvar_f = 3\nvar_g = var_e * var_f\nvar_h = var_d + var_g\nvar_i = var_a - var_h\nprint(int(var_i))"
    },
    "1325": {
        "category": "Arithmetic calculation",
        "question_ko": "한 사람당 피자 한 판의 2/5씩 나누어 주려고 합니다. 10명에게 나누어 주려면 피자는 몇 판 필요합니까?",
        "question_en": "They are going to give each person 2/5 of a pizza. How many pizzas are needed to serve 10 people?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "2/5 10 [OP_MUL]",
        "solution_abst_en": "2/5 10 [OP_MUL]",
        "solution_code_ko": "var_a = 0.4\nvar_b = 10\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 0.4\nvar_b = 10\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "1326": {
        "category": "Possibility",
        "question_ko": "어떤 수는 1620006보다 같거나 크고 1629996보다 같거나 작다. 이러한 수 중 123의 배수이면서 가장 큰 수를 구하시오.",
        "question_en": "Some numbers are greater than or equal to 1620006 and less than or equal to 1629996. Find the largest of these numbers that is a multiple of 123.",
        "answer_ko": "1629996",
        "answer_en": "1629996",
        "solution_abst_ko": "1620006 1629996 1 [OP_LIST_ARANGE] 123 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_abst_en": "1620006 1629996 1 [OP_LIST_ARANGE] 123 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1620006\nvar_b = 1629996\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 123\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))",
        "solution_code_en": "var_a = 1620006\nvar_b = 1629996\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 123\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))"
    },
    "1327": {
        "category": "Possibility",
        "question_ko": "1, 3, 0, 5를 한 번씩만 사용하여 만들 수 있는 네 자리 수 중에서 6번째로 큰 수를 쓰시오.",
        "question_en": "Find the 6th largest number among four digits that can be formed by using 1, 3, 0, and 5 only once.",
        "answer_ko": "5013",
        "answer_en": "5013",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 0 5 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 6 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 0 5 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 6 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 0\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 6\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 0\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 6\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint(int(var_g))"
    },
    "1328": {
        "category": "Comparison",
        "question_ko": "다섯 명의 학생 윤기, 정국, 유나, 유정, 태형은 각각 7, 6, 9, 8, 10만큼의 숫자를 가지고 있습니다. 2번째로 큰 숫자를 가진 사람은 누구입니까?",
        "question_en": "The five students, Yoongi, Jungkook, Yuna, Yoojung, and Taehyung, each have the numbers 7, 6, 9, 8, and 10. Who has the 2nd largest number?",
        "answer_ko": "유나",
        "answer_en": "Yuna",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 유나 유정 태형 [OP_LIST_EOL] [OP_LIST_SOL] 7 6 9 8 10 [OP_LIST_EOL] 2 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook Yuna Yoojung Taehyung [OP_LIST_EOL] [OP_LIST_SOL] 7 6 9 8 10 [OP_LIST_EOL] 2 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nvar_c = '유나'\nvar_d = '유정'\nvar_e = '태형'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 7\nvar_g = 6\nvar_h = 9\nvar_i = 8\nvar_j = 10\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_k = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nvar_c = 'Yuna'\nvar_d = 'Yoojung'\nvar_e = 'Taehyung'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 7\nvar_g = 6\nvar_h = 9\nvar_i = 8\nvar_j = 10\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_k = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "1329": {
        "category": "Comparison",
        "question_ko": "동길이네 집에서 마트까지는 0.76킬로미터(㎞)이며 병원까지는 17/25킬로미터(㎞)입니다. 동길이네 집에서 어느 곳이 더 가깝습니까?",
        "question_en": "From Donggil's house, it takes 0.76 kilometers (km) to get to the mart, and it takes 17/25 kilometers (km) to get to the hospital. Which place is closer to Donggil's house?",
        "answer_ko": "병원",
        "answer_en": "hospital",
        "solution_abst_ko": "[OP_LIST_SOL] 마트 병원 [OP_LIST_EOL] [OP_LIST_SOL] 0.76 17/25 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] mart hospital [OP_LIST_EOL] [OP_LIST_SOL] 0.76 17/25 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '마트'\nvar_b = '병원'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.76\nvar_d = 0.68\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'mart'\nvar_b = 'hospital'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.76\nvar_d = 0.68\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "1330": {
        "category": "Correspondence",
        "question_ko": "A78-2B4=364를 성립시키는 A는 얼마인가요?",
        "question_en": "What number in A makes A78-2B4=364 true?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "A78-2B4=364 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A78-2B4=364 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A78-2B4=364'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A78-2B4=364'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "1331": {
        "category": "Arithmetic calculation",
        "question_ko": "집합 A의 원소는 1/2, 1/3, 1/5이고, 집합 B의 원소는 0.2, 0.4, 0.5, 0.7일 때 집합 A와 B의 합집합의 원소의 개수를 구하시오.",
        "question_en": "If the elements of set A are 1/2, 1/3, 1/5 and the elements of set B are 0.2, 0.4, 0.5, 0.7, find the number of elements in the union of sets A and B.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "[OP_LIST_SOL] 1/2 1/3 1/5 [OP_LIST_EOL] [OP_LIST_SOL] 0.2 0.4 0.5 0.7 [OP_LIST_EOL] [OP_SET_UNION] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1/2 1/3 1/5 [OP_LIST_EOL] [OP_LIST_SOL] 0.2 0.4 0.5 0.7 [OP_LIST_EOL] [OP_SET_UNION] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.5\nvar_b = 0.3333333333333333\nvar_c = 0.2\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.2\nvar_e = 0.4\nvar_f = 0.5\nvar_g = 0.7\nlist_b= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nlist_c = list(set(list_a) | set(list_b))\nvar_h = len(list_c)\nprint(int(var_h))",
        "solution_code_en": "var_a = 0.5\nvar_b = 0.3333333333333333\nvar_c = 0.2\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.2\nvar_e = 0.4\nvar_f = 0.5\nvar_g = 0.7\nlist_b= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nlist_c = list(set(list_a) | set(list_b))\nvar_h = len(list_c)\nprint(int(var_h))"
    },
    "1332": {
        "category": "Comparison",
        "question_ko": "20명의 학생들이 한줄로 섰습니다. 정국이는 3등으로 줄을 섰고, 윤기는 정국이보다 뒤에 서있습니다. 윤기와 정국이 사이에 5명의 학생이 있을 때, 윤기 뒤에 서 있는 학생은 몇 명입니까?",
        "question_en": "20 students stood in a line. Jungkook stands third in line, and Yoongi stands behind Jungkook. If there are 5 students between Yoongi and Jungkook, how many students are standing behind Yoongi?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "20 3 [OP_SUB] 5 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "20 3 [OP_SUB] 5 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 20\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "1333": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.9 중에서 0.4보다 작은 수를 모두 더하면 얼마일까요?",
        "question_en": "What is the sum of all numbers less than 0.4 among 0.8, 1/2, and 0.9?",
        "answer_ko": "0",
        "answer_en": "0",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 0.4 [OP_LIST_LESS] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 0.4 [OP_LIST_LESS] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.4\nlist_b = []\nfor i in list_a:\n    if i < var_d:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.4\nlist_b = []\nfor i in list_a:\n    if i < var_d:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint(int(var_e))"
    },
    "1334": {
        "category": "Comparison",
        "question_ko": "민영이를 포함한 35명의 학생이 한 줄로 서 있을 때, 민영이의 앞에 27명의 학생들이 서 있습니다. 민영이 뒤에는 몇 명의 학생이 있습니까?",
        "question_en": "When 35 students including Minyoung are standing in a line, 27 students are standing in front of Minyeong. How many students are behind Minyoung?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "35 27 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "35 27 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 35\nvar_b = 27\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 35\nvar_b = 27\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "1335": {
        "category": "Arithmetic calculation",
        "question_ko": "지열이가 중간고사에서 국어, 수학, 영어 시험을 봤다. 서로 다른 두 시험 간의 평균이 각각 26.5, 34.5, 29 일 때, 지열이의 전체 평균은 얼마인지 구하시오",
        "question_en": "Jiyeol took Korean, Math, and English tests in the midterm exam. If the mean between the two different test scores is 26.5, 34.5, and 29 respectively, what is Jiyeol's whole average score?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "26.5 34.5 [OP_ADD] 29 [OP_ADD] 3 [OP_DIV]",
        "solution_abst_en": "26.5 34.5 [OP_ADD] 29 [OP_ADD] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 26.5\nvar_b = 34.5\nvar_c = var_a + var_b\nvar_d = 29\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 26.5\nvar_b = 34.5\nvar_c = var_a + var_b\nvar_d = 29\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "1336": {
        "category": "Possibility",
        "question_ko": "파인애플 2개를 포함한 서로 다른 과일 5개를 이용해 과일 바구니를 꾸미려고 할 때, 파일애플이 양 끝에 비치되는 경우의 수는?",
        "question_en": "If you are trying to decorate a fruit basket with 5 different fruits, including 2 pineapples, what is the number of cases that pineapples are placed at both ends?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "5 2 [OP_SUB] 5 2 [OP_SUB] [OP_PERM] 2 [OP_MUL]",
        "solution_abst_en": "5 2 [OP_SUB] 5 2 [OP_SUB] [OP_PERM] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = 1\nvar_c = int(var_c)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_c-i)\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = 1\nvar_c = int(var_c)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_c-i)\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "1337": {
        "category": "Possibility",
        "question_ko": "4개의 서로 다른 배구공, 축구공, 농구공, 야구공이 있다. 영빈이가 서로 다른 2개의 공을 산다고 할때 공을 고르는 방법의 경우는 몇가지인가?",
        "question_en": "There is a volleyball, soccerball, basketball, and baseball. If Youngbin buys two different balls, how many ways can he choose the ball?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 배구공 축구공 농구공 야구공 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] volleyball soccerball basketball baseball [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '배구공'\nvar_b = '축구공'\nvar_c = '농구공'\nvar_d = '야구공'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g / (i+1)\nprint(int(var_g))",
        "solution_code_en": "var_a = 'volleyball'\nvar_b = 'soccerball'\nvar_c = 'basketball'\nvar_d = 'baseball'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g / (i+1)\nprint(int(var_g))"
    },
    "1338": {
        "category": "Correspondence",
        "question_ko": "민수는 28일 동안 자전거 여행을 하려고 한다. 총 이동해야 하는 거리가 82.04킬로미터(㎞)이고 하루에 동일한 거리를 이동한다고 하면 하루에 몇 킬로미터(㎞)를 이동해야하는지 구하시오.",
        "question_en": "Minsu plans to go on a bicycle trip for 28 days. If the total distance to be traveled is 82.04 kilometers (km) and he travels an equal distance every day, find how many kilometers (km) must be traveled per day.",
        "answer_ko": "2.93",
        "answer_en": "2.93",
        "solution_abst_ko": "82.04 28 [OP_DIV]",
        "solution_abst_en": "82.04 28 [OP_DIV]",
        "solution_code_ko": "var_a = 82.04\nvar_b = 28\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 82.04\nvar_b = 28\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "1339": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 10, 11, 12, 13이 있습니다. 그 중에서 가장 작은 수와 2번째로 작은 수로 나눈 값은 얼마입니까?",
        "question_en": "There are four numbers 10, 11, 12, and 13. Divide the smallest number by the second smallest number.",
        "answer_ko": "0.91",
        "answer_en": "0.91",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_DIV]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "1340": {
        "category": "Correspondence",
        "question_ko": "6A+B2=77일 때 B는 무엇인지 답하시오",
        "question_en": "When 6A+B2=77, what is B?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "6A+B2=77 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "6A+B2=77 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '6A+B2=77'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '6A+B2=77'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "1341": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중에서 3번째로 큰 수와 2번째로 큰 수로 나눈 값은 얼마입니까?",
        "question_en": "There are three numbers 10, 11, and 12. What is the 3rd largest number divided by the 2nd largest number?",
        "answer_ko": "0.91",
        "answer_en": "0.91",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 3 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_DIV]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 3 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = var_e / var_g\nprint('{:.2f}'.format(round(var_h+1e-10,2)))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = var_e / var_g\nprint('{:.2f}'.format(round(var_h+1e-10,2)))"
    },
    "1342": {
        "category": "Comparison",
        "question_ko": "집에서 도서관까지의 거리는 2 + 13/40킬로미터(㎞)이고 집에서 은행까지의 거리는 2.56킬로미터(㎞)입니다. 집에서 도서관, 은행 중 어느 것이 더 멀까요?",
        "question_en": "The distance from the house to the library is 2 + 13/40 kilometers (km), and from the house to the bank is 2.56 kilometers (km). Which is farther from home, the library or the bank?",
        "answer_ko": "은행",
        "answer_en": "bank",
        "solution_abst_ko": "[OP_LIST_SOL] 도서관 은행 [OP_LIST_EOL] [OP_LIST_SOL] 2 13 40 [OP_DIV] [OP_ADD] 2.56 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] library bank [OP_LIST_EOL] [OP_LIST_SOL] 2 13 40 [OP_DIV] [OP_ADD] 2.56 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '도서관'\nvar_b = '은행'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nvar_d = 13\nvar_e = 40\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nvar_h = 2.56\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'library'\nvar_b = 'bank'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nvar_d = 13\nvar_e = 40\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nvar_h = 2.56\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "1343": {
        "category": "Comparison",
        "question_ko": "오리 20마리가 물을 마시기 위해 순서를 기다리고 있습니다. (가) 오리보다 11마리의 오리가 먼저 물을 마셨을 때, (가) 오리보다 늦게 물을 마시는 오리는 몇 마리입니까?",
        "question_en": "20 ducks are waiting their turn to drink. If 11 ducks drank before the (a) duck, how many ducks drank after the (a) duck?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "20 11 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "20 11 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "1344": {
        "category": "Geometry",
        "question_ko": "정사각형 모양의 딱지를 빈틈없이 규칙적으로 늘어놓아 큰 정사각형을 만들었습니다. 둘레에 놓인 딱지의 개수가 240개였다면, 사용한 딱지 전체의 수는 몇 개입니까?",
        "question_en": "A large square was created by arranging the square-shaped ttakji regularly without gaps. If the number of ttakjis placed at the perimeter was 240, how many ttakjis in total were used?",
        "answer_ko": "3721",
        "answer_en": "3721",
        "solution_abst_ko": "240 4 [OP_DIV] 1 [OP_ADD] 2 [OP_POW]",
        "solution_abst_en": "240 4 [OP_DIV] 1 [OP_ADD] 2 [OP_POW]",
        "solution_code_ko": "var_a = 240\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e ** var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 240\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e ** var_f\nprint(int(var_g))"
    },
    "1345": {
        "category": "Comparison",
        "question_ko": "1, 3, 4, 6, 7, 9의 숫자 카드 중에서 하나를 뽑을 때 9 이하의 수가 적힌 카드가 나올 확률은 어떻게 될까요?",
        "question_en": "What is the probability of getting a card with a number less than or equal to 9 when you draw one of the number cards 1, 3, 4, 6, 7, or 9?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 4 6 7 9 [OP_LIST_EOL] 9 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN] [OP_LIST_SOL] 1 3 4 6 7 9 [OP_LIST_EOL] [OP_LIST_LEN] [OP_DIV]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 4 6 7 9 [OP_LIST_EOL] 9 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN] [OP_LIST_SOL] 1 3 4 6 7 9 [OP_LIST_EOL] [OP_LIST_LEN] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 4\nvar_d = 6\nvar_e = 7\nvar_f = 9\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 9\nlist_b = []\nfor i in list_a:\n    if i <= var_g:\n        list_b.append(i)\nvar_h = len(list_b)\nvar_i = 1\nvar_j = 3\nvar_k = 4\nvar_l = 6\nvar_m = 7\nvar_n = 9\nlist_c= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_c.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_c.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_c.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_c.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_c.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_c.append(var_i)\nlist_c.reverse()\nvar_o = len(list_c)\nvar_p = var_h / var_o\nprint(int(var_p))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 4\nvar_d = 6\nvar_e = 7\nvar_f = 9\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 9\nlist_b = []\nfor i in list_a:\n    if i <= var_g:\n        list_b.append(i)\nvar_h = len(list_b)\nvar_i = 1\nvar_j = 3\nvar_k = 4\nvar_l = 6\nvar_m = 7\nvar_n = 9\nlist_c= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_c.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_c.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_c.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_c.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_c.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_c.append(var_i)\nlist_c.reverse()\nvar_o = len(list_c)\nvar_p = var_h / var_o\nprint(int(var_p))"
    },
    "1346": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 5로 나누어야 할 것을 잘못하여 7을 곱한 후 2/9를 더했더니 5와 4/9가 되었습니다. 바르게 계산하면 얼마인지 소수 2번째 자리까지 나타내어 보세요.",
        "question_en": "I need to divide a number by 5, but I mistakenly multiplied it by 7 and then added 2/9 to get 5 and 4/9. If you calculate correctly, show how much it is to 2 decimal places.",
        "answer_ko": "0.15",
        "answer_en": "0.15",
        "solution_abst_ko": "5 4/9 [OP_ADD] 2/9 [OP_SUB] 7 [OP_DIV] 5 [OP_DIV]",
        "solution_abst_en": "5 4/9 [OP_ADD] 2/9 [OP_SUB] 7 [OP_DIV] 5 [OP_DIV]",
        "solution_code_ko": "var_a = 5\nvar_b = 0.4444444444444444\nvar_c = var_a + var_b\nvar_d = 0.2222222222222222\nvar_e = var_c - var_d\nvar_f = 7\nvar_g = var_e / var_f\nvar_h = 5\nvar_i = var_g / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 5\nvar_b = 0.4444444444444444\nvar_c = var_a + var_b\nvar_d = 0.2222222222222222\nvar_e = var_c - var_d\nvar_f = 7\nvar_g = var_e / var_f\nvar_h = 5\nvar_i = var_g / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "1347": {
        "category": "Possibility",
        "question_ko": "3쌍의 새가 있습니다. 새는 총 몇마리 인가요?",
        "question_en": "There are 3 pairs of birds. How many birds are there in total?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "3 2 [OP_MUL]",
        "solution_abst_en": "3 2 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "1348": {
        "category": "Arithmetic calculation",
        "question_ko": "남준이가 나눗셈을 하는 과정에서 나누는 세 자리 수의 일의 자리에 있는 0을 빠뜨려서 12로 잘못 보고 계산하였더니 몫이 210으로 나누어떨어졌습니다. 바르게 계산한 몫을 구하시오.",
        "question_en": "In the division process, Namjoon omitted the 0 in the one's place of the three-digit divisor and misrepresented it as 12. After calculating, the quotient is divided by 210. Find the correctly calculated quotient.",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "210 12 [OP_MUL] 120 [OP_FDIV]",
        "solution_abst_en": "210 12 [OP_MUL] 120 [OP_FDIV]",
        "solution_code_ko": "var_a = 210\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 120\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 210\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 120\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "1349": {
        "category": "Geometry",
        "question_ko": "어느 마름모 모양의 종이 조각의 넓이가 80제곱센티미터(㎠), 한 대각선의 길이가 16 센티미터(㎝)일 때 다른 대각선의 길이는 몇 센티미터(㎝)일까요?",
        "question_en": "If the area of a piece of paper in the shape of a rhombus is 80 square centimeters (cm2) and one diagonal is 16 centimeters (cm), how long is the other diagonal in centimeters (cm)?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "80 2 [OP_MUL] 16 [OP_DIV]",
        "solution_abst_en": "80 2 [OP_MUL] 16 [OP_DIV]",
        "solution_code_ko": "var_a = 80\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 16\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 80\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 16\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "1350": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.3, 1/3 중 0.4보다 작은 수의 개수를 구하시오.",
        "question_en": "Find the number of numbers less than 0.4 among 0.8, 1/2, 0.3, and 1/3.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.3 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.3 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.3\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.4\nlist_b = []\nfor i in list_a:\n    if i < var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.3\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.4\nlist_b = []\nfor i in list_a:\n    if i < var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "1351": {
        "category": "Arithmetic calculation",
        "question_ko": "가로 24센티미터(㎝), 세로 15센티미터(㎝), 높이 28센티미터(㎝)인 상자가 있습니다. 이 상자에 가로 4센티미터(㎝), 세로 5센티미터(㎝), 높이 7센티미터(㎝)인 우유팩을 최대한 많이 채운다면, 우유팩은 몇 개가 들어가겠습니까?",
        "question_en": "There is a box with a width of 24 centimeters (cm), a length of 15 centimeters (cm), and a height of 28 centimeters (cm). If you fill this box with as many milk cartons as possible, with a width of 4 centimeters (cm), a length of 5 centimeters (cm), and a height of 7 centimeters (cm), how many milk cartons will it fit?",
        "answer_ko": "72",
        "answer_en": "72",
        "solution_abst_ko": "24 15 [OP_MUL] 28 [OP_MUL] 4 5 [OP_MUL] 7 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "24 15 [OP_MUL] 28 [OP_MUL] 4 5 [OP_MUL] 7 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 24\nvar_b = 15\nvar_c = var_a * var_b\nvar_d = 28\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = 5\nvar_h = var_f * var_g\nvar_i = 7\nvar_j = var_h * var_i\nvar_k = var_e / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 24\nvar_b = 15\nvar_c = var_a * var_b\nvar_d = 28\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = 5\nvar_h = var_f * var_g\nvar_i = 7\nvar_j = var_h * var_i\nvar_k = var_e / var_j\nprint(int(var_k))"
    },
    "1352": {
        "category": "Possibility",
        "question_ko": "각 자리수가 1, 6, 8로 이루어져 있고 각각 다른 숫자로 되어 있는 세 자리 수 중 두 번째로 큰 것과 세 번째로 작은 것의 차를 구하시오.",
        "question_en": "Find the difference between the second largest and the third smallest three-digit numbers, each of which has 1, 6, and 8 on each digit.",
        "answer_ko": "198",
        "answer_en": "198",
        "solution_abst_ko": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))"
    },
    "1353": {
        "category": "Comparison",
        "question_ko": "정국이는 색종이를 10장, 호석이는 색종이를 7장 가지고 있습니다. 석진이는 정국이보다 색종이를 2장 더 적게 가지고 있습니다. 색종이를 가장 적게 가지고 있는 사람은 누구입니까?",
        "question_en": "Jungkook has 10 pieces of colored paper, and Hoseok has 7 pieces of colored paper. Seokjin has 2 fewer pieces of colored paper than Jungkook. Who has the least colored paper?",
        "answer_ko": "호석",
        "answer_en": "Hoseok",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 호석 석진 [OP_LIST_EOL] [OP_LIST_SOL] 10 7 10 2 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Hoseok Seokjin [OP_LIST_EOL] [OP_LIST_SOL] 10 7 10 2 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '호석'\nvar_c = '석진'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 10\nvar_e = 7\nvar_f = 10\nvar_g = 2\nvar_h = var_f - var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Hoseok'\nvar_c = 'Seokjin'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 10\nvar_e = 7\nvar_f = 10\nvar_g = 2\nvar_h = var_f - var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "1354": {
        "category": "Correspondence",
        "question_ko": "서로 다른 두 수 A, B가 있습니다. 두 자리 수끼리의 뺄셈식 A7-3B=55에서 A를 구하시오.",
        "question_en": "There are two different numbers A and B. Find A in the two-digit subtraction formula A7-3B=55.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "A7-3B=55 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A7-3B=55 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A7-3B=55'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A7-3B=55'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "1355": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 400센티미터(㎝)인 테이프를 5개 만큼 이어 붙였는데 전체 길이는 1904센티미터(㎝)가 되었다면, 겹친 부분의 길이는 각각 몇 밀리미터(㎜)입니까?",
        "question_en": "If 5 pieces of 400 centimeters (cm) long tape are joined together and the total length is 1904 centimeters (cm), how many millimeters (mm) is the length of each overlapping part?",
        "answer_ko": "2400",
        "answer_en": "2400",
        "solution_abst_ko": "400 5 [OP_MUL] 1904 [OP_SUB] 5 1 [OP_SUB] [OP_DIV] 100 [OP_MUL]",
        "solution_abst_en": "400 5 [OP_MUL] 1904 [OP_SUB] 5 1 [OP_SUB] [OP_DIV] 100 [OP_MUL]",
        "solution_code_ko": "var_a = 400\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 1904\nvar_e = var_c - var_d\nvar_f = 5\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 100\nvar_k = var_i * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 400\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 1904\nvar_e = var_c - var_d\nvar_f = 5\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 100\nvar_k = var_i * var_j\nprint(int(var_k))"
    },
    "1356": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 10, 11, 12, 13이 있습니다. 그 중에서 가장 큰 수와 2번째로 큰 수의 곱은 얼마입니까?",
        "question_en": "There are four numbers: 10, 11, 12, and 13. What is the product of the largest number and the second largest number?",
        "answer_ko": "156",
        "answer_en": "156",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = var_f * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = var_f * var_h\nprint(int(var_i))"
    },
    "1357": {
        "category": "Arithmetic calculation",
        "question_ko": "수영장에 1번째 날에는 318리터(L)의 물을 넣고, 2번째 날에는 312리터(L)의 물을 넣었습니다. 3번째 날 오전에는 180리터(L), 오후에는 162리터(L)의 물을 넣었습니다. 매일 평균 몇 리터(L)의 물을 넣었습니까?",
        "question_en": "On the first day, 318 liters (L) of water were added to the pool, and on the second day, 312 liters (L) of water were added. On the third day, 180 liters (L) of water were added in the morning and 162 liters (L) in the afternoon. How many liters (L) of water were added to the pool on average each day?",
        "answer_ko": "324",
        "answer_en": "324",
        "solution_abst_ko": "318 312 [OP_ADD] 180 162 [OP_ADD] [OP_ADD] 3 [OP_DIV]",
        "solution_abst_en": "318 312 [OP_ADD] 180 162 [OP_ADD] [OP_ADD] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 318\nvar_b = 312\nvar_c = var_a + var_b\nvar_d = 180\nvar_e = 162\nvar_f = var_d + var_e\nvar_g = var_c + var_f\nvar_h = 3\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 318\nvar_b = 312\nvar_c = var_a + var_b\nvar_d = 180\nvar_e = 162\nvar_f = var_d + var_e\nvar_g = var_c + var_f\nvar_h = 3\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "1358": {
        "category": "Comparison",
        "question_ko": "마트에 똑같은 달걀판이 28개 있습니다. 각 달걀판마다 가진 달걀의 수는 같습니다. 어느 달걀판에서 앞에서 14번째, 뒤에서 20번째, 왼쪽에서 3번째, 오른쪽에서 2번째 달걀을 선택했을 때, 이 마트 안 달걀판들 안에 있는 달걀의 수를 모두 구하시오.",
        "question_en": "There are 28 identical egg containers in the mart. Each egg container has the same number of eggs. When you select the 14th egg from the front, the 20th from the back, the 3rd from the left, and the 2nd from the right in an egg container, find all the number of eggs in the egg containers at this mart.",
        "answer_ko": "3696",
        "answer_en": "3696",
        "solution_abst_ko": "14 20 [OP_ADD] 1 [OP_SUB] 3 2 [OP_ADD] 1 [OP_SUB] [OP_MUL] 28 [OP_MUL]",
        "solution_abst_en": "14 20 [OP_ADD] 1 [OP_SUB] 3 2 [OP_ADD] 1 [OP_SUB] [OP_MUL] 28 [OP_MUL]",
        "solution_code_ko": "var_a = 14\nvar_b = 20\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nvar_l = 28\nvar_m = var_k * var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 14\nvar_b = 20\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nvar_l = 28\nvar_m = var_k * var_l\nprint(int(var_m))"
    },
    "1359": {
        "category": "Correspondence",
        "question_ko": "88에 어떤 수를 뺐더니 54가 되었습니다. 어떤 수를 구하시오.",
        "question_en": "Subtracting some number from 88 gives 54. Find the number.",
        "answer_ko": "34",
        "answer_en": "34",
        "solution_abst_ko": "88 54 [OP_SUB]",
        "solution_abst_en": "88 54 [OP_SUB]",
        "solution_code_ko": "var_a = 88\nvar_b = 54\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 88\nvar_b = 54\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "1360": {
        "category": "Correspondence",
        "question_ko": "A, B는 한 자리 수입니다. A56B가 36의 배수일 때 A가 될 수 있는 숫자의 개수를 구하시오.",
        "question_en": "A and B are single-digit numbers. If A56B is a multiple of 36, how many digits can A be?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "A56B [OP_GEN_POSSIBLE_LIST] 36 [OP_LIST_DIVISIBLE] A56B A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_abst_en": "A56B [OP_GEN_POSSIBLE_LIST] 36 [OP_LIST_DIVISIBLE] A56B A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 'A56B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 36\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 'A56B'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nvar_e = len(list_c)\nprint(int(var_e))",
        "solution_code_en": "var_a = 'A56B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 36\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 'A56B'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nvar_e = len(list_c)\nprint(int(var_e))"
    },
    "1361": {
        "category": "Comparison",
        "question_ko": "지희는 7과 8을 모았습니다. 석진이는 3과 10을 모았습니다. 수지는 9와 2를 모았습니다. 모은 수의 합이 석진이보다 더 작은 사람은 누구입니까?",
        "question_en": "Jihee collected 7 and 8. Seokjin collected 3 and 10. Suzy collected 9 and 2. Who is the person whose sum of the collected numbers is less than Seokjin?",
        "answer_ko": "수지",
        "answer_en": "Suzy",
        "solution_abst_ko": "[OP_LIST_SOL] 지희 석진 수지 [OP_LIST_EOL] 석진 [OP_LIST_INDEX] [OP_LIST_SOL] 7 8 [OP_ADD] 3 10 [OP_ADD] 9 2 [OP_ADD] [OP_LIST_EOL] [OP_LIST_GET] [OP_LIST_LESS] 1 [OP_LIST_GET] [OP_LIST_POP] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jihee Seokjin Suzy [OP_LIST_EOL] Seokjin [OP_LIST_INDEX] [OP_LIST_SOL] 7 8 [OP_ADD] 3 10 [OP_ADD] 9 2 [OP_ADD] [OP_LIST_EOL] [OP_LIST_GET] [OP_LIST_LESS] 1 [OP_LIST_GET] [OP_LIST_POP] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '지희'\nvar_b = '석진'\nvar_c = '수지'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '석진'\nvar_e = list_a.index(var_d)+1\nvar_f = 7\nvar_g = 8\nvar_h = var_f + var_g\nvar_i = 3\nvar_j = 10\nvar_k = var_i + var_j\nvar_l = 9\nvar_m = 2\nvar_n = var_l + var_m\nlist_b= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nlist_b.reverse()\nvar_o = list_b[var_e-1]\nlist_c = []\nfor i in list_b:\n    if i < var_o:\n        list_c.append(i)\nvar_p = 1\nvar_q = list_c[var_p-1]\nvar_r = list_b.index(var_q)+1\nvar_s = list_a[var_r-1]\nprint(var_s)",
        "solution_code_en": "var_a = 'Jihee'\nvar_b = 'Seokjin'\nvar_c = 'Suzy'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'Seokjin'\nvar_e = list_a.index(var_d)+1\nvar_f = 7\nvar_g = 8\nvar_h = var_f + var_g\nvar_i = 3\nvar_j = 10\nvar_k = var_i + var_j\nvar_l = 9\nvar_m = 2\nvar_n = var_l + var_m\nlist_b= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nlist_b.reverse()\nvar_o = list_b[var_e-1]\nlist_c = []\nfor i in list_b:\n    if i < var_o:\n        list_c.append(i)\nvar_p = 1\nvar_q = list_c[var_p-1]\nvar_r = list_b.index(var_q)+1\nvar_s = list_a[var_r-1]\nprint(var_s)"
    },
    "1362": {
        "category": "Geometry",
        "question_ko": "두 개의 철사의 길이가 각각 36센티미터(㎝), 38센티미터(㎝)이다. 36센티미터(㎝)의 철사로 정사각형을 만들고 38센티미터(㎝)의 철사로 가로가 15센티미터(㎝)인 직사각형을 만든다. 정사각형과 직사각형의 넓이의 차이를 구하시오.",
        "question_en": "The lengths of the two wires are 36 centimeters (cm) and 38 centimeters (cm), respectively. Make a square with the 36 centimeters (cm) wire and a rectangle 15 centimeters (cm) wide with the 38 centimeters (cm) wire. Find the difference between the area of the square and the rectangle.",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "36 4 [OP_DIV] 2 [OP_POW] 38 2 [OP_DIV] 15 [OP_SUB] 15 [OP_MUL] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "36 4 [OP_DIV] 2 [OP_POW] 38 2 [OP_DIV] 15 [OP_SUB] 15 [OP_MUL] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 36\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 38\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = 15\nvar_j = var_h - var_i\nvar_k = 15\nvar_l = var_j * var_k\nvar_m = var_e - var_l\nvar_n = abs(var_m)\nprint(int(var_n))",
        "solution_code_en": "var_a = 36\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 38\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = 15\nvar_j = var_h - var_i\nvar_k = 15\nvar_l = var_j * var_k\nvar_m = var_e - var_l\nvar_n = abs(var_m)\nprint(int(var_n))"
    },
    "1363": {
        "category": "Comparison",
        "question_ko": "세 삼각형 (가), (나), (다)가 있습니다. (가) 삼각형은 밑변의 길이가 8센티미터(㎝), 높이가 6센티미터(㎝)이고, (나) 삼각형은 밑변의 길이가 5센티미터(㎝), 높이가 9센티미터(㎝)이고, (다) 삼각형은 밑변의 길이가 7센티미터(㎝), 높이가 7센티미터(㎝)입니다. (가), (나), (다) 중에서 넓이가 가장 넓은 삼각형은 어느 것입니까?",
        "question_en": "There are three triangles (A), (B), and (C). Triangle (A) has a base length of 8 centimeters (cm) and a height of 6 centimeters (cm), triangle (B) has a base length of 5 centimeters (cm) and a height of 9 centimeters (cm), triangle (C) has a base of 7 centimeters (cm) and a height of 7 centimeters (cm). Which triangle has the largest area among (A), (B), and (C)?",
        "answer_ko": "(다)",
        "answer_en": "(C)",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) (다) [OP_LIST_EOL] [OP_LIST_SOL] 8 6 [OP_MUL] 2 [OP_DIV] 5 9 [OP_MUL] 2 [OP_DIV] 7 7 [OP_MUL] 2 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (A) (B) (C) [OP_LIST_EOL] [OP_LIST_SOL] 8 6 [OP_MUL] 2 [OP_DIV] 5 9 [OP_MUL] 2 [OP_DIV] 7 7 [OP_MUL] 2 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nvar_c = '(다)'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 8\nvar_e = 6\nvar_f = var_d * var_e\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = 5\nvar_j = 9\nvar_k = var_i * var_j\nvar_l = 2\nvar_m = var_k / var_l\nvar_n = 7\nvar_o = 7\nvar_p = var_n * var_o\nvar_q = 2\nvar_r = var_p / var_q\nlist_b= []\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nlist_b.reverse()\nvar_s = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_t = list_c[-var_s]\nvar_u = list_b.index(var_t)+1\nvar_v = list_a[var_u-1]\nprint(var_v)",
        "solution_code_en": "var_a = '(A)'\nvar_b = '(B)'\nvar_c = '(C)'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 8\nvar_e = 6\nvar_f = var_d * var_e\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = 5\nvar_j = 9\nvar_k = var_i * var_j\nvar_l = 2\nvar_m = var_k / var_l\nvar_n = 7\nvar_o = 7\nvar_p = var_n * var_o\nvar_q = 2\nvar_r = var_p / var_q\nlist_b= []\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nlist_b.reverse()\nvar_s = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_t = list_c[-var_s]\nvar_u = list_b.index(var_t)+1\nvar_v = list_a[var_u-1]\nprint(var_v)"
    },
    "1364": {
        "category": "Comparison",
        "question_ko": "집에서 학교까지의 거리는 11/4킬로미터(㎞), 집에서 문구점까지의 거리는 2.89킬로미터(㎞)입니다. 집에서 학교까지가 멀까요 아니면 집에서 문구점까지가 멀까요?",
        "question_en": "The distance from the house to the school is 11/4 kilometers (km), and the distance from the house to the stationery store is 2.89 kilometers (km). Which is farther from your house, the school or the stationery?",
        "answer_ko": "문구점",
        "answer_en": "stationery",
        "solution_abst_ko": "[OP_LIST_SOL] 학교 문구점 [OP_LIST_EOL] [OP_LIST_SOL] 11 4 [OP_DIV] 2.89 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] school stationery [OP_LIST_EOL] [OP_LIST_SOL] 11 4 [OP_DIV] 2.89 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '학교'\nvar_b = '문구점'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 11\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 2.89\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'school'\nvar_b = 'stationery'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 11\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 2.89\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "1365": {
        "category": "Arithmetic calculation",
        "question_ko": "마법 주머니가 있습니다. 빨간 주머니에 들어갔다 나오면 길이가 10배가 되고, 파란 주머니에 들어갔다 나오면 길이가 들어가기 전 길이의 1/100 이 됩니다. 연우는 13.5센티미터(㎝)인 수수깡을 빨간 주머니에 3번, 파란 주머니에 2번 들어갔다 나오게 했습니다. 지금 연우의 수수깡은 몇 센티미터(㎝)입니까?",
        "question_en": "There are magic bags. The length becomes 10 times longer when a thing gets in and out of the red bag, and the length becomes 1/100 of the original length when a thing gets through the blue bag. Yeonwoo had 13.5 centimeters (cm) of sorghum straw put in and out of the red bag 3 times and the blue bag 2 times. How many centimeters (cm) is Yeonwoo's sorghum straw now?",
        "answer_ko": "1.35",
        "answer_en": "1.35",
        "solution_abst_ko": "13.5 10 3 [OP_POW] [OP_MUL] 1/100 2 [OP_POW] [OP_MUL]",
        "solution_abst_en": "13.5 10 3 [OP_POW] [OP_MUL] 1/100 2 [OP_POW] [OP_MUL]",
        "solution_code_ko": "var_a = 13.5\nvar_b = 10\nvar_c = 3\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 0.01\nvar_g = 2\nvar_h = var_f ** var_g\nvar_i = var_e * var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 13.5\nvar_b = 10\nvar_c = 3\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 0.01\nvar_g = 2\nvar_h = var_f ** var_g\nvar_i = var_e * var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "1366": {
        "category": "Comparison",
        "question_ko": "버스를 타기 위해 학생들이 줄을 서 있습니다. 유정이는 앞에서 부터 5번째에 서 있습니다. 호석이가 유정이 바로 뒤에 서 있다면 호석이는 몇 번째에 서 있을까요?",
        "question_en": "There are students queuing up to get on the bus, and Yoojung is standing at the 5th from the front. If Hoseok stands right behind Yoojung, what place does Hoseok take in the line?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "5 1 [OP_ADD]",
        "solution_abst_en": "5 1 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "1367": {
        "category": "Arithmetic calculation",
        "question_ko": "남준이는 석준이보다 색종이를 15장 더 많이 가지고 있었습니다. 석진이가 윤기에게 색종이 7장을 주었더니 석진이와 윤기가 가지고 있는 색종이는 40장으로 같아졌습니다. 세 사람이 가지고 있는 색종이는 총 몇 장입니까?",
        "question_en": "Consider Namjoon had 15 more pieces of colored paper than what Seokjin had. And Seokjin and Yoongi ended up having the same amount of colored paper after Seokjin gave Yoongi 7 pieces of colored paper. What would be the total amount of colored paper of three people? ",
        "answer_ko": "142",
        "answer_en": "142",
        "solution_abst_ko": "40 7 [OP_ADD] 40 7 [OP_SUB] [OP_ADD] 40 7 [OP_ADD] 15 [OP_ADD] [OP_ADD]",
        "solution_abst_en": "40 7 [OP_ADD] 40 7 [OP_SUB] [OP_ADD] 40 7 [OP_ADD] 15 [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 40\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 40\nvar_e = 7\nvar_f = var_d - var_e\nvar_g = var_c + var_f\nvar_h = 40\nvar_i = 7\nvar_j = var_h + var_i\nvar_k = 15\nvar_l = var_j + var_k\nvar_m = var_g + var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 40\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 40\nvar_e = 7\nvar_f = var_d - var_e\nvar_g = var_c + var_f\nvar_h = 40\nvar_i = 7\nvar_j = var_h + var_i\nvar_k = 15\nvar_l = var_j + var_k\nvar_m = var_g + var_l\nprint(int(var_m))"
    },
    "1368": {
        "category": "Arithmetic calculation",
        "question_ko": "공책 1묶음은 25권입니다. 공책 5묶음을 학생 13명이 8권씩 나누어 가졌습니다. 학생들이 나누어 가지고 남은 공책은 몇 권입니까?",
        "question_en": "One bundle of notebooks is 25. 5 bundles were divided into 8 groups of 13 students. How many notebooks have left after dividing to students?",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "25 5 [OP_MUL] 13 8 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "25 5 [OP_MUL] 13 8 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 25\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = 8\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 25\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = 8\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "1369": {
        "category": "Arithmetic calculation",
        "question_ko": "용찬이는 10분 동안 1.05킬로미터(㎞)를 걸었습니다. 용찬이가 민주보다 460미터(m) 더 걸었을 때 민주가 걸은 거리는 몇킬로미터(㎞)입니까?",
        "question_en": "Yongchan walked 1.05 kilometers (km) in 10 minutes. If Yongchan walked 460 meters (m) longer than Min-joo, how many kilometers (km) did Min-joo walk?",
        "answer_ko": "0.59",
        "answer_en": "0.59",
        "solution_abst_ko": "1.05 460 1000 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "1.05 460 1000 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 1.05\nvar_b = 460\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 1.05\nvar_b = 460\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "1370": {
        "category": "Arithmetic calculation",
        "question_ko": "사과 55.99킬로그램(㎏)을 생산하는 데 155.2리터(L)의 물이 필요하다고 하고, 한 물통에 들어있는 물의 양은 2리터(L)입니다. 만약 사과 1556.5킬로그램(㎏)을 생산한다면 필요한 물통은 모두 몇 개입니까?",
        "question_en": "It is said that 155.2 liters (L) of water is needed to produce 55.99 kilograms (kg) of apples, and the amount of water in one bucket is 2 liters (L). If you produce 1556.5 kilograms (kg) of apples, how many buckets of water are needed?",
        "answer_ko": "2158",
        "answer_en": "2158",
        "solution_abst_ko": "155.2 55.99 [OP_DIV] 1556.5 [OP_MUL] 2 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "155.2 55.99 [OP_DIV] 1556.5 [OP_MUL] 2 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 155.2\nvar_b = 55.99\nvar_c = var_a / var_b\nvar_d = 1556.5\nvar_e = var_c * var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 1\nvar_i=int(((var_g+9*10**(var_h-2))//(10**(var_h-1)))*10**(var_h-1))\n\nprint(int(var_i))",
        "solution_code_en": "var_a = 155.2\nvar_b = 55.99\nvar_c = var_a / var_b\nvar_d = 1556.5\nvar_e = var_c * var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 1\nvar_i=int(((var_g+9*10**(var_h-2))//(10**(var_h-1)))*10**(var_h-1))\n\nprint(int(var_i))"
    },
    "1371": {
        "category": "Correspondence",
        "question_ko": "345A를 올림하여 십의 자리까지 나타내었더니 3460이 되었습니다. 가능한 A 값의 총 합을 구하시오",
        "question_en": "345A rounded up to the nearest ten is 3460. Find the total sum of possible values of A.",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "345A [OP_GEN_POSSIBLE_LIST] 3460 10 [OP_SUB] [OP_LIST_MORE] 3460 [OP_LIST_LESS] 345A A [OP_LIST_FIND_UNK] [OP_LIST_SUM]",
        "solution_abst_en": "345A [OP_GEN_POSSIBLE_LIST] 3460 10 [OP_SUB] [OP_LIST_MORE] 3460 [OP_LIST_LESS] 345A A [OP_LIST_FIND_UNK] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = '345A'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 3460\nvar_c = 10\nvar_d = var_b - var_c\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nvar_e = 3460\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = '345A'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nlist_d = []\nfor elem in list_c:\n    elem = str(elem)\n    list_d.append(int(elem[unk_idx]))\nlist_d = list(set(list_d))\nlist_d = [float(i) for i in list_d]\nvar_h = sum(list_d)\nprint(int(var_h))",
        "solution_code_en": "var_a = '345A'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 3460\nvar_c = 10\nvar_d = var_b - var_c\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nvar_e = 3460\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = '345A'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nlist_d = []\nfor elem in list_c:\n    elem = str(elem)\n    list_d.append(int(elem[unk_idx]))\nlist_d = list(set(list_d))\nlist_d = [float(i) for i in list_d]\nvar_h = sum(list_d)\nprint(int(var_h))"
    },
    "1372": {
        "category": "Geometry",
        "question_ko": "어떤 정다면체의 면의 개수가 8개입니다. 이 정다면체의 모서리의 개수를 구하시오.",
        "question_en": "A regular polyhedron has 8 faces. Find the number of edges of this regular polyhedron.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "4 4 [OP_ADD] 4 [OP_ADD]",
        "solution_abst_en": "4 4 [OP_ADD] 4 [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 4\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "1373": {
        "category": "Comparison",
        "question_ko": "윤기는 4개, 유나는 5개, 정국이는 6 나누기 3만큼 사과를 가졌습니다. 누가 가진 사과가 가장 적습니까?",
        "question_en": "Yoongi has 4 apples, Yuna has 5, and Jungkook has 6 divided by 3 apples. Who has the fewest apples?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 유나 정국 [OP_LIST_EOL] [OP_LIST_SOL] 4 5 6 3 [OP_FDIV] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Yuna Jungkook [OP_LIST_EOL] [OP_LIST_SOL] 4 5 6 3 [OP_FDIV] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '유나'\nvar_c = '정국'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 5\nvar_f = 6\nvar_g = 3\nvar_h = var_f // var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Yuna'\nvar_c = 'Jungkook'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 5\nvar_f = 6\nvar_g = 3\nvar_h = var_f // var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "1374": {
        "category": "Arithmetic calculation",
        "question_ko": "상철이는 책을 읽고 있습니다. 어제는 전체의 1/3을 읽었고, 오늘은 전체의 1/2을 읽었습니다. 이틀 동안 읽은 양은 전체의 얼마입니까?",
        "question_en": "Sangcheol is reading a book. Yesterday he read 1/3 of the total, today he read 1/2 of the total. How much did he read in the two days?",
        "answer_ko": "0.83",
        "answer_en": "0.83",
        "solution_abst_ko": "1/3 1/2 [OP_ADD]",
        "solution_abst_en": "1/3 1/2 [OP_ADD]",
        "solution_code_ko": "var_a = 0.3333333333333333\nvar_b = 0.5\nvar_c = var_a + var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 0.3333333333333333\nvar_b = 0.5\nvar_c = var_a + var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "1375": {
        "category": "Correspondence",
        "question_ko": "426에 0.06을 곱하면 얼마인지 구하시오.",
        "question_en": "Write down what results from 426 multiplied by 0.06.",
        "answer_ko": "25.56",
        "answer_en": "25.56",
        "solution_abst_ko": "426 0.06 [OP_MUL]",
        "solution_abst_en": "426 0.06 [OP_MUL]",
        "solution_code_ko": "var_a = 426\nvar_b = 0.06\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 426\nvar_b = 0.06\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "1376": {
        "category": "Comparison",
        "question_ko": "윤정이가 기차표를 사기위해 매표소에서 줄을 섰습니다. 윤정이 앞에 6명이 기다리고 있고 윤정이는 뒤에서 5번째에 서 있을 때 기차표를 사기위해 줄을 선 사람은 모두 몇 명입니까?",
        "question_en": "Yoon Jeong stood in line at the ticket office to buy a train ticket. How many people are all in line to buy train tickets when there are 6 people waiting in front of Yoon Jeong and Yoon Jeong is the 5th person from the back?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "6 5 [OP_ADD]",
        "solution_abst_en": "6 5 [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "1377": {
        "category": "Comparison",
        "question_ko": "정국이는 6에서 3을 나눈 몫 만큼 모았고, 윤기는 4만큼 모았습니다. 누구의 수가 더 큽니까?",
        "question_en": "Jungkook saved as much as 3 divided by 6, and Yoongi saved as much as 4. Whose number is greater?",
        "answer_ko": "윤기",
        "answer_en": "Yoongi",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 윤기 [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_FDIV] 4 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Yoongi [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_FDIV] 4 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '윤기'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 3\nvar_e = var_c // var_d\nvar_f = 4\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Yoongi'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 3\nvar_e = var_c // var_d\nvar_f = 4\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "1378": {
        "category": "Arithmetic calculation",
        "question_ko": "하루에 사용하는 물의 양은 215리터(L)입니다. 0.32배를 절약하였을 때 아낀 물의 양은 몇 리터(L)입니까?",
        "question_en": "The amount of water used per day is 215 liters (L). How many liters (L) of water are saved when you save 0.32 times?",
        "answer_ko": "68.80",
        "answer_en": "68.8",
        "solution_abst_ko": "215 0.32 [OP_MUL]",
        "solution_abst_en": "215 0.32 [OP_MUL]",
        "solution_code_ko": "var_a = 215\nvar_b = 0.32\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 215\nvar_b = 0.32\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "1379": {
        "category": "Correspondence",
        "question_ko": "유럽 여행 투어를 함께 다니는 일행 10명의 가방 무게의 합은 42로 나눠떨어지고 그 몫은 10이다. 일행 중 한명인 수지가 기념품을 사서 가방 무게가 50킬로그램(㎏)이 되었다. 가방 무게의 평균이 44킬로그램(㎏)가 되었다면 기념품을 사기 전 수지 가방의 무게는 몇 킬로그램(㎏)인가?",
        "question_en": "The sum of the weights of the bags of 10 people traveling together on a European tour is divided by 42, there is no rest, and the quotient is 10. Suji, one of the party, bought a souvenir and the bag weighed 50 kg (kg). If the average weight of the bags is 44 kilograms (kg), how many kilograms (kg) does the Suji bag weigh before buying the souvenir?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "50 44 42 [OP_SUB] 10 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "50 44 42 [OP_SUB] 10 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 50\nvar_b = 44\nvar_c = 42\nvar_d = var_b - var_c\nvar_e = 10\nvar_f = var_d * var_e\nvar_g = var_a - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 50\nvar_b = 44\nvar_c = 42\nvar_d = var_b - var_c\nvar_e = 10\nvar_f = var_d * var_e\nvar_g = var_a - var_f\nprint(int(var_g))"
    },
    "1380": {
        "category": "Arithmetic calculation",
        "question_ko": "1초에 288센티미터(㎝) 달리는 20미터(m) 길이의 자가용이 있습니다. 이 자가용이 터널을 완전히 통과하는 데 25초가 걸렸다면 터널의 길이는 몇 미터(m)인지 구해보시오.",
        "question_en": "There is a car that is 20 meters (m) long and travels at 288 centimeters (cm) in one second. When this car takes 25 seconds to get through the tunnel, find the length in meters (m) of the tunnel.",
        "answer_ko": "52",
        "answer_en": "52",
        "solution_abst_ko": "288 100 [OP_DIV] 25 [OP_MUL] 20 [OP_SUB]",
        "solution_abst_en": "288 100 [OP_DIV] 25 [OP_MUL] 20 [OP_SUB]",
        "solution_code_ko": "var_a = 288\nvar_b = 100\nvar_c = var_a / var_b\nvar_d = 25\nvar_e = var_c * var_d\nvar_f = 20\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 288\nvar_b = 100\nvar_c = var_a / var_b\nvar_d = 25\nvar_e = var_c * var_d\nvar_f = 20\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "1381": {
        "category": "Correspondence",
        "question_ko": "서로 다른 두 숫자 A, B가 있습니다. 두 자리 수끼리의 덧셈식 6A+B2=77에서 B를 구하시오.",
        "question_en": "I have two different numbers, A and B. Find B from the two-digit addition equation 6A+B2=77.",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "6A+B2=77 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "6A+B2=77 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '6A+B2=77'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '6A+B2=77'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "1382": {
        "category": "Arithmetic calculation",
        "question_ko": "8마리의 토끼가 있었는데 토끼를 5마리 더 키우기로 했습니다. 키우게 된 토끼는 모두 몇 마리일까요?",
        "question_en": "We had 8 rabbits and decided to raise 5 more rabbits. How many rabbits are we raising now?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "8 5 [OP_ADD]",
        "solution_abst_en": "8 5 [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 8\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "1383": {
        "category": "Possibility",
        "question_ko": "2, 7, 4, 9 중에서 서로 다른 숫자 3개를 뽑아 만들 수 있는 세 자리 수 중에서 가장 큰 수에서 가장 작은 수를 뺀 값은 얼마입니까?",
        "question_en": "What is the largest three-digit number minus the smallest one that can be formed by choosing three different numbers from 2, 7, 4, and 9?",
        "answer_ko": "727",
        "answer_en": "727",
        "solution_abst_ko": "[OP_LIST_SOL] 2 7 4 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 2 7 4 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 2\nvar_b = 7\nvar_c = 4\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 2\nvar_b = 7\nvar_c = 4\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))"
    },
    "1384": {
        "category": "Comparison",
        "question_ko": "준섭이의 머리카락의 길이는 9센티미터(㎝) 8밀리미터(㎜)이고, 태훈이의 머리카락 길이는 8.9센티미터(㎝)이며, 하율이의 머리카락 길이는 9.3센티미터(㎝)입니다. 세 친구 중 머리카락이 가장 짧은 친구는 누구입니까?",
        "question_en": "Junseop's hair is 9 centimeters (cm) 8 millimeters (mm) long, Taehun's hair is 8.9 centimeters (cm), and Hayul's hair is 9.3 centimeters (cm) long. Which of the three friends has the shortest hair?",
        "answer_ko": "태훈",
        "answer_en": "Taehun",
        "solution_abst_ko": "[OP_LIST_SOL] 준섭 태훈 하율 [OP_LIST_EOL] [OP_LIST_SOL] 9 8 10 [OP_DIV] [OP_ADD] 8.9 9.3 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Junseop Taehun Hayul [OP_LIST_EOL] [OP_LIST_SOL] 9 8 10 [OP_DIV] [OP_ADD] 8.9 9.3 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '준섭'\nvar_b = '태훈'\nvar_c = '하율'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 9\nvar_e = 8\nvar_f = 10\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = 8.9\nvar_j = 9.3\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[var_k-1]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'Junseop'\nvar_b = 'Taehun'\nvar_c = 'Hayul'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 9\nvar_e = 8\nvar_f = 10\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = 8.9\nvar_j = 9.3\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[var_k-1]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "1385": {
        "category": "Arithmetic calculation",
        "question_ko": "올해 아버지는 35살이고 아들은 5살입니다. 몇 년 후에 아버지와 아들의 나이의 합이 60살이 됩니까?",
        "question_en": "This year, the father is 35 years old, and the son is 5 years old. In how many years does the sum of the ages of the father and son become 60?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "60 35 5 [OP_ADD] [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "60 35 5 [OP_ADD] [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 60\nvar_b = 35\nvar_c = 5\nvar_d = var_b + var_c\nvar_e = var_a - var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 60\nvar_b = 35\nvar_c = 5\nvar_d = var_b + var_c\nvar_e = var_a - var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "1386": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 99를 더한 값에 17배는 3111입니다. 어떤 수를 구하시오.",
        "question_en": "When you add 99 to a certain number and multiply that by 17, it becomes 3111. Find that number in question.",
        "answer_ko": "84",
        "answer_en": "84",
        "solution_abst_ko": "3111 17 [OP_DIV] 99 [OP_SUB]",
        "solution_abst_en": "3111 17 [OP_DIV] 99 [OP_SUB]",
        "solution_code_ko": "var_a = 3111\nvar_b = 17\nvar_c = var_a / var_b\nvar_d = 99\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 3111\nvar_b = 17\nvar_c = var_a / var_b\nvar_d = 99\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "1387": {
        "category": "Correspondence",
        "question_ko": "40을 어떤 수에 빼야 할 것을 잘못하여 6을 어떤 수에 나눈 결과는 52가 나옵니다. 바르게 계산하면 얼마인가요?",
        "question_en": "If you mistakenly divide 6 by a number, you get 52 when you should have subtracted 40 from the number. What do you get when you calculate correctly?",
        "answer_ko": "272",
        "answer_en": "272",
        "solution_abst_ko": "52 6 [OP_MUL] 40 [OP_SUB]",
        "solution_abst_en": "52 6 [OP_MUL] 40 [OP_SUB]",
        "solution_code_ko": "var_a = 52\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 40\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 52\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 40\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "1388": {
        "category": "Possibility",
        "question_ko": "10개의 수 0, 1, 2, 3, 4, 5, 6, 7, 8 중에서 서로 다른 3개의 수를 선택하여 일렬로 배열하여 만든 세자리 자연수 중 300 이하의 가장 큰 홀수를 구하시오.",
        "question_en": "Find the largest odd number not more than 300 among the three-digit natural numbers formed by arranging three different numbers from 0, 1, 2, 3, 4, 5, 6, 7, and 8.",
        "answer_ko": "297",
        "answer_en": "297",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 4 5 6 7 8 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 300 [OP_LIST_LESS_EQUAL] 2 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 4 5 6 7 8 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 300 [OP_LIST_LESS_EQUAL] 2 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nvar_f = 5\nvar_g = 6\nvar_h = 7\nvar_i = 8\nvar_j = 9\nlist_a= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_a.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_k = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_k))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_l = 300\nlist_c = []\nfor i in list_b:\n    if i <= var_l:\n        list_c.append(i)\nvar_m = 2\nlist_d = []\nvar_m = int(var_m)\nfor i in list_c:\n    i = int(i)\n    if i % var_m == 0:\n        list_d.append(i)\nlist_e = list(set(list_c) - set(list_d))\nvar_n = 1\nlist_f=list_e.copy()\nlist_f.sort()\nvar_o = list_f[-var_n]\nprint(int(var_o))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nvar_f = 5\nvar_g = 6\nvar_h = 7\nvar_i = 8\nvar_j = 9\nlist_a= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_a.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_k = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_k))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_l = 300\nlist_c = []\nfor i in list_b:\n    if i <= var_l:\n        list_c.append(i)\nvar_m = 2\nlist_d = []\nvar_m = int(var_m)\nfor i in list_c:\n    i = int(i)\n    if i % var_m == 0:\n        list_d.append(i)\nlist_e = list(set(list_c) - set(list_d))\nvar_n = 1\nlist_f=list_e.copy()\nlist_f.sort()\nvar_o = list_f[-var_n]\nprint(int(var_o))"
    },
    "1389": {
        "category": "Possibility",
        "question_ko": "서로 다른 5명의 사람이 있다. 이 중 세 명을 뽑아 회장, 부회장, 총무를 시키려고 한다. 경우의 수를 구하여라.",
        "question_en": "There are 5 different people. We are trying to select three of them to be the president, vice president, and manager. Find the number of cases.",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "5 1 1 [OP_ADD] 1 [OP_ADD] [OP_PERM]",
        "solution_abst_en": "5 1 1 [OP_ADD] 1 [OP_ADD] [OP_PERM]",
        "solution_code_ko": "var_a = 5\nvar_b = 1\nvar_c = 1\nvar_d = var_b + var_c\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = 1\nvar_a = int(var_a)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_a-i)\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 1\nvar_c = 1\nvar_d = var_b + var_c\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = 1\nvar_a = int(var_a)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_a-i)\nprint(int(var_g))"
    },
    "1390": {
        "category": "Arithmetic calculation",
        "question_ko": "연주는 공책 전체 개수에서 1/4만큼 받았고, 민지는 3/7만큼 받았습니다. 공책이 28권 있었다면 남은 공책은 몇 권 인가요?",
        "question_en": "Yeonju received 1/4 of the total number of notebooks, and Minji received 3/7. If there were 28 notebooks, how many notebooks are left?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "28 1 1/4 [OP_SUB] 3/7 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "28 1 1/4 [OP_SUB] 3/7 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 28\nvar_b = 1\nvar_c = 0.25\nvar_d = var_b - var_c\nvar_e = 0.42857142857142855\nvar_f = var_d - var_e\nvar_g = var_a * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 28\nvar_b = 1\nvar_c = 0.25\nvar_d = var_b - var_c\nvar_e = 0.42857142857142855\nvar_f = var_d - var_e\nvar_g = var_a * var_f\nprint(int(var_g))"
    },
    "1391": {
        "category": "Arithmetic calculation",
        "question_ko": "첫번째 날 23마리의 병아리를 두번째 날 병아리 12마리를 더 사왔을 때, 늘어난 병아리는 모두 몇 마리입니까?",
        "question_en": "If a farmer bought 23 chicks and 12 more chicks on the first day and the second day, how many chicks are increased?",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "23 12 [OP_ADD]",
        "solution_abst_en": "23 12 [OP_ADD]",
        "solution_code_ko": "var_a = 23\nvar_b = 12\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 23\nvar_b = 12\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "1392": {
        "category": "Arithmetic calculation",
        "question_ko": "기우는 상금의 1/2을 학용품을 사는데 사용하고 나머지의 3/8으로 저축을 했습니다. 남은 돈이 2500원이라면 기우가 학용품을 사는데 사용한 돈은 얼마인가요?",
        "question_en": "Ki-woo used 1/2 of the winnings to buy school supplies and saved 3/8 of the rest. If the remaining money is 2,500 won, how much money did Ki-woo use to buy school supplies?",
        "answer_ko": "4000",
        "answer_en": "4000",
        "solution_abst_ko": "2500 1 3/8 [OP_SUB] [OP_DIV] 1/2 [OP_DIV] 1/2 [OP_MUL]",
        "solution_abst_en": "2500 1 3/8 [OP_SUB] [OP_DIV] 1/2 [OP_DIV] 1/2 [OP_MUL]",
        "solution_code_ko": "var_a = 2500\nvar_b = 1\nvar_c = 0.375\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 0.5\nvar_g = var_e / var_f\nvar_h = 0.5\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 2500\nvar_b = 1\nvar_c = 0.375\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 0.5\nvar_g = var_e / var_f\nvar_h = 0.5\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "1393": {
        "category": "Possibility",
        "question_ko": "지형이는 색이 다른 연필 2개와 모양이 다른 지우개 4개가 들어있는 필통에서 학용품 하나를 고르려고 합니다. 지형이가 학용품을 고를 경우의 수는?",
        "question_en": "Jihyung is trying to pick up a school supply from a pencil case that contains two pencils of different colors and four erasers of different shapes. How many cases are there in which Jihyung picks up a school supply?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "2 4 [OP_ADD] 1 [OP_COMB]",
        "solution_abst_en": "2 4 [OP_ADD] 1 [OP_COMB]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 1\nvar_c = int(var_c)\nvar_d = int(var_d)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e * (var_c-i)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e / (i+1)\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 1\nvar_c = int(var_c)\nvar_d = int(var_d)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e * (var_c-i)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e / (i+1)\nprint(int(var_e))"
    },
    "1394": {
        "category": "Arithmetic calculation",
        "question_ko": "진우와 성민이 둘이서 어떤 일을 8일 동안 하면 전체 일의 7/12을 할 수 있습니다. 이 일을 둘이서 8일 동안 함께 하고, 나머지는 진우 혼자서 10일 동안 하여 끝냈습니다. 이 일을 처음부터 성민이 혼자서 하여 끝낸다면 며칠이 걸리는지 구하시오.",
        "question_en": "Jinwoo and Seongmin can do 7/12 of the work if they do something for 8 days together. The two of them did this together for 8 days, and the rest was done by Jinwoo alone for 10 days. How many days will it take if Seongmin finishes this task by himself from the beginning?",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "1 7/12 8 [OP_DIV] 1 7/12 [OP_SUB] 10 [OP_DIV] [OP_SUB] [OP_DIV]",
        "solution_abst_en": "1 7/12 8 [OP_DIV] 1 7/12 [OP_SUB] 10 [OP_DIV] [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 0.5833333333333334\nvar_c = 8\nvar_d = var_b / var_c\nvar_e = 1\nvar_f = 0.5833333333333334\nvar_g = var_e - var_f\nvar_h = 10\nvar_i = var_g / var_h\nvar_j = var_d - var_i\nvar_k = var_a / var_j\nprint(int(eval('{:.2f}'.format(round(var_k+1e-10,2)))))",
        "solution_code_en": "var_a = 1\nvar_b = 0.5833333333333334\nvar_c = 8\nvar_d = var_b / var_c\nvar_e = 1\nvar_f = 0.5833333333333334\nvar_g = var_e - var_f\nvar_h = 10\nvar_i = var_g / var_h\nvar_j = var_d - var_i\nvar_k = var_a / var_j\nprint(int(eval('{:.2f}'.format(round(var_k+1e-10,2)))))"
    },
    "1395": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 4.372를 더하고 43.72를 빼었더니 16.398이 되었습니다. 어떤 수에서 3.48을 뺀 값은 얼마인지 구하시오.",
        "question_en": "Adding 4.372 to a number and subtracting 43.72 gives us 16.398. What is the value of subtracting 3.48 from this number?",
        "answer_ko": "52.27",
        "answer_en": "52.27",
        "solution_abst_ko": "16.398 43.72 [OP_ADD] 4.372 [OP_SUB] 3.48 [OP_SUB]",
        "solution_abst_en": "16.398 43.72 [OP_ADD] 4.372 [OP_SUB] 3.48 [OP_SUB]",
        "solution_code_ko": "var_a = 16.398\nvar_b = 43.72\nvar_c = var_a + var_b\nvar_d = 4.372\nvar_e = var_c - var_d\nvar_f = 3.48\nvar_g = var_e - var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 16.398\nvar_b = 43.72\nvar_c = var_a + var_b\nvar_d = 4.372\nvar_e = var_c - var_d\nvar_f = 3.48\nvar_g = var_e - var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "1396": {
        "category": "Arithmetic calculation",
        "question_ko": "48송이의 장미 중 3/8은 빨간색이고 5/16은 노란색입니다. 빨간색 장미의 수는 노란색 장미보다 몇 송이 더 많은지 구하시오.",
        "question_en": "Of the 48 roses, 3/8 are red and 5/16 are yellow. Find how many more red roses are there than yellow roses.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "48 3/8 [OP_MUL] 48 5/16 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "48 3/8 [OP_MUL] 48 5/16 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 48\nvar_b = 0.375\nvar_c = var_a * var_b\nvar_d = 48\nvar_e = 0.3125\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 48\nvar_b = 0.375\nvar_c = var_a * var_b\nvar_d = 48\nvar_e = 0.3125\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "1397": {
        "category": "Comparison",
        "question_ko": "두 자리 수끼리의 곱셈에서 곱하는 수의 십의 자리 숫자 2를 6으로 잘못 보고 계산한 값이 2432가 되었습니다. 바르게 계산한 값이 912일 때, 2개의 두 자리 수 중 더 작은 수를 쓰시오.",
        "question_en": "In a multiplication of two two-digit numbers, you incorrectly saw the tens digit 2 in the number being multiplied as a 6, resulting in a computed value of 2432. Write the smaller of the two two-digit numbers when the correct result is 912.",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "[OP_LIST_SOL] 2432 912 [OP_SUB] 6 2 [OP_SUB] 10 [OP_MUL] [OP_DIV] 912 2432 912 [OP_SUB] 6 2 [OP_SUB] 10 [OP_MUL] [OP_DIV] [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 2432 912 [OP_SUB] 6 2 [OP_SUB] 10 [OP_MUL] [OP_DIV] 912 2432 912 [OP_SUB] 6 2 [OP_SUB] 10 [OP_MUL] [OP_DIV] [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 2432\nvar_b = 912\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = 10\nvar_h = var_f * var_g\nvar_i = var_c / var_h\nvar_j = 912\nvar_k = 2432\nvar_l = 912\nvar_m = var_k - var_l\nvar_n = 6\nvar_o = 2\nvar_p = var_n - var_o\nvar_q = 10\nvar_r = var_p * var_q\nvar_s = var_m / var_r\nvar_t = var_j / var_s\nlist_a= []\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_a.append(var_t)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nlist_a.reverse()\nvar_u = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_v = list_b[var_u-1]\nprint(int(var_v))",
        "solution_code_en": "var_a = 2432\nvar_b = 912\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = 10\nvar_h = var_f * var_g\nvar_i = var_c / var_h\nvar_j = 912\nvar_k = 2432\nvar_l = 912\nvar_m = var_k - var_l\nvar_n = 6\nvar_o = 2\nvar_p = var_n - var_o\nvar_q = 10\nvar_r = var_p * var_q\nvar_s = var_m / var_r\nvar_t = var_j / var_s\nlist_a= []\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_a.append(var_t)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nlist_a.reverse()\nvar_u = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_v = list_b[var_u-1]\nprint(int(var_v))"
    },
    "1398": {
        "category": "Correspondence",
        "question_ko": "3에 어떤 수를 곱해야 하는데 잘못하여 6에 어떤 수를 곱했더니 42가 되었습니다. 바르게 계산한 결과를 구하시오.",
        "question_en": "You were supposed to multiply 3 by a number, but mistakenly multiplied 6 by a number, and got 42. Find the result of the correct calculation.",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "42 6 [OP_DIV] 3 [OP_MUL]",
        "solution_abst_en": "42 6 [OP_DIV] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 42\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 42\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "1399": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 6을 곱해야 하는데 잘못하여 뺐더니 51이 되었습니다. 바르게 계산한 결과를 구하시오.",
        "question_en": "You had to multiply a number by 6 but mistakenly subtracted instead to get 51. Find the correctly calculated result.",
        "answer_ko": "342",
        "answer_en": "342",
        "solution_abst_ko": "51 6 [OP_ADD] 6 [OP_MUL]",
        "solution_abst_en": "51 6 [OP_ADD] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 51\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 51\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "1400": {
        "category": "Geometry",
        "question_ko": "직사각형의 가로가 4센티미터(㎝)이고 세로가 2센티미터(㎝)인 직사각형의 넓이가 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "Find the area in centimeters (cm) of a rectangle whose length is 4 centimeters (cm) and width is 2 centimeters (cm).",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "4 2 [OP_MUL]",
        "solution_abst_en": "4 2 [OP_MUL]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "1401": {
        "category": "Arithmetic calculation",
        "question_ko": "석진이는 4층에 있는 서점에 가려고 합니다. 현재 석진이의 위치가 1층일 때, 서점에 가려면 몇 층을 더 올라가야 합니까?",
        "question_en": "Seokjin is going to the bookstore located on the 4th floor. If Seokjin is currently on the first floor, how many more floors must he go up to get to the bookstore?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "4 1 [OP_SUB]",
        "solution_abst_en": "4 1 [OP_SUB]",
        "solution_code_ko": "var_a = 4\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "1402": {
        "category": "Arithmetic calculation",
        "question_ko": "달리기 시합에서 정국이는 한 시간 동안 2.7킬로미터(㎞)를 달릴 수 있습니다. 이 시합에서 지민이가 같은 빠르기로 4.86킬로미터(㎞)를 달린다면 몇 시간이 걸리겠습니까?",
        "question_en": "In a running match, Jungkook can run 2.7 kilometers (km) in an hour. How many hours would it take for Jimin to run 4.86 kilometers (km) at the same speed in this match?",
        "answer_ko": "1.80",
        "answer_en": "1.8",
        "solution_abst_ko": "1 2.7 [OP_DIV] 4.86 [OP_MUL]",
        "solution_abst_en": "1 2.7 [OP_DIV] 4.86 [OP_MUL]",
        "solution_code_ko": "var_a = 1\nvar_b = 2.7\nvar_c = var_a / var_b\nvar_d = 4.86\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 2.7\nvar_c = var_a / var_b\nvar_d = 4.86\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "1403": {
        "category": "Possibility",
        "question_ko": "5명의 학생 중 3명이 남학생이고 2명이 여학생이다. 5명을 1열로 세울 때, 여학생들이 모두 연속해서 서는 경우를 구하시오.",
        "question_en": "Out of 5 students, 3 are boys and 2 are girls. When 5 people are lined up in a row, find the case where all the female students stand in a row.",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "[OP_LIST_SOL] A B C D E [OP_LIST_EOL] [OP_LIST_SOL] C [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] C D [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D E [OP_LIST_EOL] [OP_LIST_SOL] C [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] C D [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 'C'\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_g = len(list_c)\nvar_h = len(list_c)\nvar_i = 1\nvar_g = int(var_g)\nvar_h = int(var_h)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i * (var_g-i)\nvar_j = 'C'\nvar_k = 'D'\nlist_d= []\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_d.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_d.append(var_j)\nlist_d.reverse()\nvar_l = len(list_d)\nvar_m = len(list_d)\nvar_n = 1\nvar_l = int(var_l)\nvar_m = int(var_m)\nfor i, elem in enumerate(range(var_m)):\n    var_n = var_n * (var_l-i)\nvar_o = var_i * var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 'C'\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_g = len(list_c)\nvar_h = len(list_c)\nvar_i = 1\nvar_g = int(var_g)\nvar_h = int(var_h)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i * (var_g-i)\nvar_j = 'C'\nvar_k = 'D'\nlist_d= []\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_d.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_d.append(var_j)\nlist_d.reverse()\nvar_l = len(list_d)\nvar_m = len(list_d)\nvar_n = 1\nvar_l = int(var_l)\nvar_m = int(var_m)\nfor i, elem in enumerate(range(var_m)):\n    var_n = var_n * (var_l-i)\nvar_o = var_i * var_n\nprint(int(var_o))"
    },
    "1404": {
        "category": "Arithmetic calculation",
        "question_ko": "남준이가 가지고 있던 연필 2타 중 몇 자루를 윤기에게 주었더니 15자루가 남았습니다. 연필 1타는 12자루일때, 윤기가 남준이에게 받은 연필은 몇 자루입니까?",
        "question_en": "Namjoon gave two strokes of a pencil he had to Yoongi, and he had 15 left. If one stroke is 12 pencils, how many pencils did Yoongi receive from Namjoon?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "12 2 [OP_MUL] 15 [OP_SUB]",
        "solution_abst_en": "12 2 [OP_MUL] 15 [OP_SUB]",
        "solution_code_ko": "var_a = 12\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 15\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 15\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "1405": {
        "category": "Correspondence",
        "question_ko": "호석이는 46을 어떤 수에서 빼서 15를 얻었습니다. 어떤 수에 29를 뺀 결과값을 정확히 구하시오.",
        "question_en": "Hoseok subtracted 46 from a number to get 15. Find the exact result of subtracting 29 from this number.",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "15 46 [OP_ADD] 29 [OP_SUB]",
        "solution_abst_en": "15 46 [OP_ADD] 29 [OP_SUB]",
        "solution_code_ko": "var_a = 15\nvar_b = 46\nvar_c = var_a + var_b\nvar_d = 29\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 46\nvar_c = var_a + var_b\nvar_d = 29\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "1406": {
        "category": "Arithmetic calculation",
        "question_ko": "양팔 저울의 한쪽에는 동화책 한 권을 올려놓고, 다른 한쪽에는 0.5킬로그램(㎏)짜리 추 한 개와 0.3킬로그램(㎏)짜리 추 2개를 올려놓았더니 수평이 되었다면, 동화책 한 권의 무게는 몇 킬로그램(㎏)일지 구하시오.",
        "question_en": "When a children's book is placed on one side of the two-arm scale, and a 0.5 kilograms (kg) weight and two 0.3 kilograms (kg) weights are placed on the other side, and they are level, how many kilograms (kg) is the children's book.",
        "answer_ko": "1.10",
        "answer_en": "1.1",
        "solution_abst_ko": "0.5 0.3 2 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "0.5 0.3 2 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 0.5\nvar_b = 0.3\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.5\nvar_b = 0.3\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "1407": {
        "category": "Possibility",
        "question_ko": "숫자 7, 3, 5, 8를 한 번씩만 사용하여 네 자리 수를 만들려고 합니다. 만들 수 있는 네 자리 수는 모두 몇 개입니까?",
        "question_en": "You want to create a four-digit number using the numbers 7, 3, 5, and 8 only once. How many four-digit numbers can you make in total?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "[OP_LIST_SOL] 7 3 5 8 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 7 3 5 8 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 7\nvar_b = 3\nvar_c = 5\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 7\nvar_b = 3\nvar_c = 5\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "1408": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 25 센티미터(㎝) 인 색 테이프 15 장을 0.5 센티미터(㎝) 씩 겹치게 이어 붙였습니다. 이은 색 테이프 전체의 길이는 몇 미터(m) 입니까?",
        "question_en": "Fifteen sheets of colored tape, each 25 centimeters (cm) long, were joined together with an overlap of 0.5 centimeters (cm). How many meters (m) is the total length of the continuous color tape?",
        "answer_ko": "3.68",
        "answer_en": "3.68",
        "solution_abst_ko": "25 25 0.5 [OP_SUB] 15 1 [OP_SUB] [OP_MUL] [OP_ADD] 100 [OP_DIV]",
        "solution_abst_en": "25 25 0.5 [OP_SUB] 15 1 [OP_SUB] [OP_MUL] [OP_ADD] 100 [OP_DIV]",
        "solution_code_ko": "var_a = 25\nvar_b = 25\nvar_c = 0.5\nvar_d = var_b - var_c\nvar_e = 15\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_a + var_h\nvar_j = 100\nvar_k = var_i / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 25\nvar_b = 25\nvar_c = 0.5\nvar_d = var_b - var_c\nvar_e = 15\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_a + var_h\nvar_j = 100\nvar_k = var_i / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "1409": {
        "category": "Comparison",
        "question_ko": "대현이는 288쪽의 소설책을 읽는 데 12일이 걸렸고, 승훈이는 243쪽의 소설책을 읽는 데 9일이 걸렸습니다. 하루 동안 더 많은 쪽을 읽은 친구는 누구인지 구하시오.",
        "question_en": "It took Daehyun 12 days to read the 288-page novel, and Seung-hoon took 9 days to read the 243-page novel. Find out who of the two read more pages in one day.",
        "answer_ko": "승훈",
        "answer_en": "Seung-hoon",
        "solution_abst_ko": "[OP_LIST_SOL] 대현 승훈 [OP_LIST_EOL] [OP_LIST_SOL] 288 12 [OP_DIV] 243 9 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Daehyun Seung-hoon [OP_LIST_EOL] [OP_LIST_SOL] 288 12 [OP_DIV] 243 9 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '대현'\nvar_b = '승훈'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 288\nvar_d = 12\nvar_e = var_c / var_d\nvar_f = 243\nvar_g = 9\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Daehyun'\nvar_b = 'Seung-hoon'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 288\nvar_d = 12\nvar_e = var_c / var_d\nvar_f = 243\nvar_g = 9\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "1410": {
        "category": "Geometry",
        "question_ko": "사각뿔의 면의 개수는?",
        "question_en": "What is the number of faces of a quadrangular pyramid?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "4 1 [OP_ADD]",
        "solution_abst_en": "4 1 [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "1411": {
        "category": "Correspondence",
        "question_ko": "기훈이네 농장에 소와 돼지가 있습니다. 돼지는 모두 100마리가 있고 소의 수의 3/4에서 25를 빼고 7로 나눈 뒤 50을 더하면 돼지의 수와 같아집니다. 기훈이네 농장의 소는 모두 몇마리입니까?",
        "question_en": "There are cows and pigs on Gihun's farm. There are 100 pigs in total, and subtracting 3/4 of the number of cows by 25, dividing it by 7, and adding 50 equals the number of pigs. How many cows are there on Gihun's farm?",
        "answer_ko": "500",
        "answer_en": "500",
        "solution_abst_ko": "100 50 [OP_SUB] 7 [OP_MUL] 25 [OP_ADD] 3/4 [OP_DIV]",
        "solution_abst_en": "100 50 [OP_SUB] 7 [OP_MUL] 25 [OP_ADD] 3/4 [OP_DIV]",
        "solution_code_ko": "var_a = 100\nvar_b = 50\nvar_c = var_a - var_b\nvar_d = 7\nvar_e = var_c * var_d\nvar_f = 25\nvar_g = var_e + var_f\nvar_h = 0.75\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 100\nvar_b = 50\nvar_c = var_a - var_b\nvar_d = 7\nvar_e = var_c * var_d\nvar_f = 25\nvar_g = var_e + var_f\nvar_h = 0.75\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "1412": {
        "category": "Geometry",
        "question_ko": "꼭짓점의 수가 24개이고 모서리의 길이가 5센티미터(㎝)로 모두 같은 각기둥이 있습니다. 이 각기둥의 모든 모서리의 길이의 합은 몇 센티미터(㎝)입니까?",
        "question_en": "A prism has 24 vertices, and all edges are 5 centimeters (cm) long. What is the sum of the lengths of all the edges of this prism in centimeters (cm)?",
        "answer_ko": "180",
        "answer_en": "180",
        "solution_abst_ko": "24 2 [OP_DIV] 3 [OP_MUL] 5 [OP_MUL]",
        "solution_abst_en": "24 2 [OP_DIV] 3 [OP_MUL] 5 [OP_MUL]",
        "solution_code_ko": "var_a = 24\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 3\nvar_e = var_c * var_d\nvar_f = 5\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 24\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 3\nvar_e = var_c * var_d\nvar_f = 5\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "1413": {
        "category": "Correspondence",
        "question_ko": "36에 어떤 수를 더해야 할 것을 잘못하여 63에 어떤 수를 나누었더니 9가 되었습니다. 바르게 계산하면 얼마인지 구하시오.",
        "question_en": "I accidentally divided a certain number by 63 when I was supposed to add this number to 36, and I got 9. How much is it if I calculate it correctly?",
        "answer_ko": "43",
        "answer_en": "43",
        "solution_abst_ko": "36 63 9 [OP_DIV] [OP_ADD]",
        "solution_abst_en": "36 63 9 [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 36\nvar_b = 63\nvar_c = 9\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 36\nvar_b = 63\nvar_c = 9\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "1414": {
        "category": "Correspondence",
        "question_ko": "다섯 자리 수 ABCDE를 6으로 나누었을 때 몫이 13579로 나누어떨어졌습니다. ABC+DE의 값을 구하시오.",
        "question_en": "When the five-digit number ABCDE is divided by 6, the quotient is 13579 without a remainder. Find the value of ABC+DE.",
        "answer_ko": "888",
        "answer_en": "888",
        "solution_abst_ko": "6 13579 [OP_MUL] [OP_NUM2LIST] 1 [OP_LIST_GET] 100 [OP_MUL] 2 [OP_LIST_GET] 10 [OP_MUL] 3 [OP_LIST_GET] [OP_ADD] [OP_ADD] 4 [OP_LIST_GET] 10 [OP_MUL] 5 [OP_LIST_GET] [OP_ADD] [OP_ADD]",
        "solution_abst_en": "6 13579 [OP_MUL] [OP_NUM2LIST] 1 [OP_LIST_GET] 100 [OP_MUL] 2 [OP_LIST_GET] 10 [OP_MUL] 3 [OP_LIST_GET] [OP_ADD] [OP_ADD] 4 [OP_LIST_GET] 10 [OP_MUL] 5 [OP_LIST_GET] [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 13579\nvar_c = var_a * var_b\nlist_a = []\nvar_c = int(var_c)\nwhile var_c//10 > 0:\n    list_a.append(var_c%10)\n    var_c = var_c//10\nlist_a.append(var_c%10)\nlist_a = list_a[::-1]\nvar_d = 1\nvar_e = list_a[var_d-1]\nvar_f = 100\nvar_g = var_e * var_f\nvar_h = 2\nvar_i = list_a[var_h-1]\nvar_j = 10\nvar_k = var_i * var_j\nvar_l = 3\nvar_m = list_a[var_l-1]\nvar_n = var_k + var_m\nvar_o = var_g + var_n\nvar_p = 4\nvar_q = list_a[var_p-1]\nvar_r = 10\nvar_s = var_q * var_r\nvar_t = 5\nvar_u = list_a[var_t-1]\nvar_v = var_s + var_u\nvar_w = var_o + var_v\nprint(int(var_w))",
        "solution_code_en": "var_a = 6\nvar_b = 13579\nvar_c = var_a * var_b\nlist_a = []\nvar_c = int(var_c)\nwhile var_c//10 > 0:\n    list_a.append(var_c%10)\n    var_c = var_c//10\nlist_a.append(var_c%10)\nlist_a = list_a[::-1]\nvar_d = 1\nvar_e = list_a[var_d-1]\nvar_f = 100\nvar_g = var_e * var_f\nvar_h = 2\nvar_i = list_a[var_h-1]\nvar_j = 10\nvar_k = var_i * var_j\nvar_l = 3\nvar_m = list_a[var_l-1]\nvar_n = var_k + var_m\nvar_o = var_g + var_n\nvar_p = 4\nvar_q = list_a[var_p-1]\nvar_r = 10\nvar_s = var_q * var_r\nvar_t = 5\nvar_u = list_a[var_t-1]\nvar_v = var_s + var_u\nvar_w = var_o + var_v\nprint(int(var_w))"
    },
    "1415": {
        "category": "Arithmetic calculation",
        "question_ko": "135.1리터(L)의 물을 7리터(L) 물통에 나누어 담을 때 가득 찬 물통은 몇 개 있나요?",
        "question_en": "How many full buckets are there when 135.1 liters (L) of water is divided into 7 liters (L) buckets?",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "135.1 7 [OP_FDIV]",
        "solution_abst_en": "135.1 7 [OP_FDIV]",
        "solution_code_ko": "var_a = 135.1\nvar_b = 7\nvar_c = var_a // var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 135.1\nvar_b = 7\nvar_c = var_a // var_b\nprint(int(var_c))"
    },
    "1416": {
        "category": "Possibility",
        "question_ko": "집에서 서점까지 버스를 타고 가는 방법은 3가지, 지하철을 타고 가는 방법은 4가지이다. 집에서 서점까지 버스 또는 지하철을 타고 가는 경우의 수를 구하시오.",
        "question_en": "There are 3 ways to get to the bookstore by bus, and 4 ways to go by subway. Find the number of cases you take the bus or subway from your home to the bookstore.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "3 4 [OP_ADD]",
        "solution_abst_en": "3 4 [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 4\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 4\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "1417": {
        "category": "Geometry",
        "question_ko": "가로가 5센티미터(㎝), 세로가 4센티미터(㎝), 높이가 3센티미터(㎝)인 직육면체의 모든 면에 빨간색 물감을 칠하였습니다. 그리고 이 직육면체를 한 모서리의 길이가 1센티미터(㎝)인 정육면체 60개로 잘랐습니다. 1개의 면에만 색칠된 정육면체 조각은 몇 개입니까?",
        "question_en": "Red paint was applied to all faces of a cuboid measuring 5 centimeters (cm) wide, 4 centimeters (cm) long, and 3 centimeters (cm) high. Then, this cuboid was cut into 60 cubes with each edge being 1 centimeters (cm) long. What is the number of cube pieces that are colored on only one side?",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "5 2 [OP_SUB] 4 2 [OP_SUB] [OP_MUL] 5 2 [OP_SUB] 3 2 [OP_SUB] [OP_MUL] [OP_ADD] 4 2 [OP_SUB] 3 2 [OP_SUB] [OP_MUL] [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "5 2 [OP_SUB] 4 2 [OP_SUB] [OP_MUL] 5 2 [OP_SUB] 3 2 [OP_SUB] [OP_MUL] [OP_ADD] 4 2 [OP_SUB] 3 2 [OP_SUB] [OP_MUL] [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = var_c * var_f\nvar_h = 5\nvar_i = 2\nvar_j = var_h - var_i\nvar_k = 3\nvar_l = 2\nvar_m = var_k - var_l\nvar_n = var_j * var_m\nvar_o = var_g + var_n\nvar_p = 4\nvar_q = 2\nvar_r = var_p - var_q\nvar_s = 3\nvar_t = 2\nvar_u = var_s - var_t\nvar_v = var_r * var_u\nvar_w = var_o + var_v\nvar_x = 2\nvar_y = var_w * var_x\nprint(int(var_y))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = var_c * var_f\nvar_h = 5\nvar_i = 2\nvar_j = var_h - var_i\nvar_k = 3\nvar_l = 2\nvar_m = var_k - var_l\nvar_n = var_j * var_m\nvar_o = var_g + var_n\nvar_p = 4\nvar_q = 2\nvar_r = var_p - var_q\nvar_s = 3\nvar_t = 2\nvar_u = var_s - var_t\nvar_v = var_r * var_u\nvar_w = var_o + var_v\nvar_x = 2\nvar_y = var_w * var_x\nprint(int(var_y))"
    },
    "1418": {
        "category": "Arithmetic calculation",
        "question_ko": "한 상자에는 20켤레의 신발이 들어 있습니다. (가) 신발은 8상자 있고, (나) 신발 상자 수는 (가) 신발 상자 수의 5배입니다. (나) 신발은 (가) 신발보다 몇 켤레 더 많습니까?",
        "question_en": "One box contains 20 pairs of shoes. There are 8 boxes of (A) shoes, and the number of (B) shoe boxes is 5 times greater than the number of (A) shoe boxes. How many pairs of (B) shoes do you have more than (A) shoes?",
        "answer_ko": "640",
        "answer_en": "640",
        "solution_abst_ko": "8 5 [OP_MUL] 8 [OP_SUB] 20 [OP_MUL]",
        "solution_abst_en": "8 5 [OP_MUL] 8 [OP_SUB] 20 [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c - var_d\nvar_f = 20\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 8\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c - var_d\nvar_f = 20\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "1419": {
        "category": "Arithmetic calculation",
        "question_ko": "사탕 81개를 학생들에게 나누어주려고 합니다. 한 명에게 9개씩 주려고할 때 사탕을 받을 수 있는 학생 수는 몇 명입니까?",
        "question_en": "I want to distribute 81 candies to students. How many students can get candy if I give 9 candies to each student?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "81 9 [OP_DIV]",
        "solution_abst_en": "81 9 [OP_DIV]",
        "solution_code_ko": "var_a = 81\nvar_b = 9\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 81\nvar_b = 9\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "1420": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 15센티미터(㎝)인 정오각형이 있습니다. 이 도형의 둘레는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "There is a regular pentagon with a side length of 15 centimeters (cm). Find the perimeter of this figure in centimeters (cm).",
        "answer_ko": "75",
        "answer_en": "75",
        "solution_abst_ko": "15 5 [OP_MUL]",
        "solution_abst_en": "15 5 [OP_MUL]",
        "solution_code_ko": "var_a = 15\nvar_b = 5\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 15\nvar_b = 5\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "1421": {
        "category": "Correspondence",
        "question_ko": "과수원에서 사과 170개, 귤 268개, 망고 120개를 트럭에 똑같이 나누어 실었다. 사과는 8개가 남았고, 귤을 2개가 모자랐으며 망고는 12개가 남았다. 과수원에 트럭은 최대 몇 대인지 구하시오.",
        "question_en": "In the orchard, 170 apples, 268 tangerines, and 120 mangoes were loaded equally into each of trucks. There are 8 apples left, 2 tangerines short, and 12 mangoes left. Find the maximum number of trucks in the orchard.",
        "answer_ko": "54",
        "answer_en": "54",
        "solution_abst_ko": "170 8 [OP_SUB] 268 2 [OP_ADD] [OP_GCD] 120 12 [OP_SUB] [OP_GCD]",
        "solution_abst_en": "170 8 [OP_SUB] 268 2 [OP_ADD] [OP_GCD] 120 12 [OP_SUB] [OP_GCD]",
        "solution_code_ko": "var_a = 170\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 268\nvar_e = 2\nvar_f = var_d + var_e\nvar_g = math.gcd(int(var_f), int(var_c))\nvar_h = 120\nvar_i = 12\nvar_j = var_h - var_i\nvar_k = math.gcd(int(var_j), int(var_g))\nprint(int(var_k))",
        "solution_code_en": "var_a = 170\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 268\nvar_e = 2\nvar_f = var_d + var_e\nvar_g = math.gcd(int(var_f), int(var_c))\nvar_h = 120\nvar_i = 12\nvar_j = var_h - var_i\nvar_k = math.gcd(int(var_j), int(var_g))\nprint(int(var_k))"
    },
    "1422": {
        "category": "Correspondence",
        "question_ko": "A45+2B3=418입니다. B는 얼마인가요?",
        "question_en": "What is the corresponding number for the variable B that fits the equation: A45+2B3=418.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "A45+2B3=418 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A45+2B3=418 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A45+2B3=418'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A45+2B3=418'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "1423": {
        "category": "Geometry",
        "question_ko": "어떤 정다각형의 둘레가 49이고 한변의 길이가 7이다. 총 몇 개의 변이 있는지 구하여라.",
        "question_en": "A regular polygon has a perimeter of 49 and a side length of 7. Find how many sides there are in total.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "49 7 [OP_DIV]",
        "solution_abst_en": "49 7 [OP_DIV]",
        "solution_code_ko": "var_a = 49\nvar_b = 7\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 49\nvar_b = 7\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "1424": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 7을 곱해야 할 것을 잘못하여 6을 곱한 결과는 12가 되었습니다. 바르게 계산한 결과는 얼마인가요?",
        "question_en": "I mistakingly multiplied a number by 6, when I should have multiplied it by 7, and the result was 12. What will be the answer to the correct calculation?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "12 6 [OP_DIV] 7 [OP_MUL]",
        "solution_abst_en": "12 6 [OP_DIV] 7 [OP_MUL]",
        "solution_code_ko": "var_a = 12\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "1425": {
        "category": "Arithmetic calculation",
        "question_ko": "80명의 학생 중 45명은 색종이가 이미 있고 나머지는 없다. 색종이가 없는 학생들에게 1645개의 색종이를 동일하게 나누어 주려면 1명당 몇 개씩 나누어 주어야합니까?",
        "question_en": "Of the 80 students, 45 already have colored paper and the rest do not. If you want to distribute 1645 pieces of colored paper equally to students who do not have colored paper, how many pieces do you need to distribute to each student?",
        "answer_ko": "47",
        "answer_en": "47",
        "solution_abst_ko": "1645 80 45 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "1645 80 45 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 1645\nvar_b = 80\nvar_c = 45\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 1645\nvar_b = 80\nvar_c = 45\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "1426": {
        "category": "Geometry",
        "question_ko": "강당에서 학생들이 4줄로 떨어져 앉아 시험을 본다. 한 줄에 8명씩 있을 때 둘레에 앉은 학생들의 수를 구하시오.",
        "question_en": "In the auditorium, students sit in four lines to take the exam. If there are 8 people in a line, find the number of students sitting at the perimeter.",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "4 8 [OP_ADD] 2 [OP_MUL] 4 [OP_SUB]",
        "solution_abst_en": "4 8 [OP_ADD] 2 [OP_MUL] 4 [OP_SUB]",
        "solution_code_ko": "var_a = 4\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "1427": {
        "category": "Arithmetic calculation",
        "question_ko": "빨간색 끈의 길이가 8미터(m)입니다. 파란색 끈은 하얀색 끈의 길이에 8배이고, 하얀색 끝은 빨간색 끈의 5배일 때, 파란색 끈은 몇 미터(m)가 됩니까?",
        "question_en": "The length of the red string is 8 meters (m). If the blue string is 8 times the length of the white string and the white string is 5 times the length of the red string, how many meters (m) is the blue string?",
        "answer_ko": "320",
        "answer_en": "320",
        "solution_abst_ko": "8 5 [OP_MUL] 8 [OP_MUL]",
        "solution_abst_en": "8 5 [OP_MUL] 8 [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "1428": {
        "category": "Arithmetic calculation",
        "question_ko": "5의 배수이면서 6의 배수이면서 2의 배수인 수 중 가장 큰 네 자리 수는?",
        "question_en": "What is the largest four-digit number that is a multiple of 5 and a multiple of 6 and a multiple of 2?",
        "answer_ko": "9990",
        "answer_en": "9990",
        "solution_abst_ko": "1000 9999 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] 6 [OP_LIST_DIVISIBLE] 2 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_abst_en": "1000 9999 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] 6 [OP_LIST_DIVISIBLE] 2 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 6\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 2\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_h = list_e[-var_g]\nprint(int(var_h))",
        "solution_code_en": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 6\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 2\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_h = list_e[-var_g]\nprint(int(var_h))"
    },
    "1429": {
        "category": "Arithmetic calculation",
        "question_ko": "국어, 영어, 과학의 평균이 89점이며 사회 시험을 포함한 평균은 1점 오른다. 호석이의 사회는 몇 점인가",
        "question_en": "Suppose that the average of Korean, English, and Science is 89 points, and the average including the Social studies test rises by 1 point. Find the score of Social studies.",
        "answer_ko": "93",
        "answer_en": "93",
        "solution_abst_ko": "89 1 [OP_ADD] 4 [OP_MUL] 89 3 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "89 1 [OP_ADD] 4 [OP_MUL] 89 3 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 89\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c * var_d\nvar_f = 89\nvar_g = 3\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 89\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c * var_d\nvar_f = 89\nvar_g = 3\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nprint(int(var_i))"
    },
    "1430": {
        "category": "Arithmetic calculation",
        "question_ko": "1학년 학생 중에서 8명이 달리기 시합에 참가하였습니다. 달리기 시합에 참가한 2학년 학생 수는 1학년에서 참가한 학생 수의 5배입니다. 달리기 시합에 참가한 1학년과 2학년 학생은 모두 몇 명입니까?",
        "question_en": "8 of the freshmen participated in the running competition. The number of sophomores participating in the competition is 5 times the number of students in the first grade. What is a total number of freshmen and sophomores participated in the competition?",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "8 5 [OP_MUL] 8 [OP_ADD]",
        "solution_abst_en": "8 5 [OP_MUL] 8 [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "1431": {
        "category": "Comparison",
        "question_ko": "정국이네 반 학생들은 모두 키가 다르고 총 28명입니다. 키가 큰 순서대로 줄을 세우면 은지는 앞에서 20번째, 정국이는 앞에서 14번째입니다. 이때 정국과 은지 사이에 있는 학생은 모두 몇 명입니까?",
        "question_en": "The students in Jungkook's class are all different heights and there are a total of 28 students. If you line up them in order of height, Eunji is 20th from the front and Jungkook is 14th from the front. How many students are between Jungkook and Eunji at this time?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "20 14 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "20 14 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 14\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 14\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "1432": {
        "category": "Possibility",
        "question_ko": "세 자연수 1, 7, 0이 있을 때, 이 숫자들을 한 번씩 모두 사용하여 만들 수 있는 가장 큰 수는 얼마입니까?",
        "question_en": "Given the three natural numbers 1, 7, and 0, what is the largest number that can be formed by using all of these numbers once?",
        "answer_ko": "710",
        "answer_en": "710",
        "solution_abst_ko": "[OP_LIST_SOL] 7 1 0 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 7 1 0 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 7\nvar_b = 1\nvar_c = 0\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))",
        "solution_code_en": "var_a = 7\nvar_b = 1\nvar_c = 0\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))"
    },
    "1433": {
        "category": "Comparison",
        "question_ko": "문슬기는 김현정씨의 할머니 성함입니다. 김호현의 딸 중 김미란은 연하인 정재영과 결혼했습니다. 김호현의 첫째 딸 이름이 김현정일 때, 5명의 사람 중 3번째로 나이가 많은 사람은 누구입니까?",
        "question_en": "Seulgi is the name of Hyunjung's grandmother. One of Hohyun's daughters, Miran, married Jaeyoung, a younger man. When Hohyun's first daughter's name is Hyunjung, who is the 3rd oldest out of 5 people?",
        "answer_ko": "김현정",
        "answer_en": "Hyunjung",
        "solution_abst_ko": "[OP_LIST_SOL] 문슬기 김현정 김미란 김호현 정재영 [OP_LIST_EOL] [OP_LIST_SOL] 문슬기 김현정 > 김미란 김호현 < 김미란 정재영 > 김호현 김현정 > 김현정 김미란 > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 3 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Seulgi Hyunjung Miran Hohyun Jaeyoung [OP_LIST_EOL] [OP_LIST_SOL] Seulgi Hyunjung > Miran Hohyun < Miran Jaeyoung > Hohyun Hyunjung > Hyunjung Miran > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 3 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '문슬기'\nvar_b = '김현정'\nvar_c = '김미란'\nvar_d = '김호현'\nvar_e = '정재영'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = '문슬기'\nvar_g = '김현정'\nvar_h = '>'\nvar_i = '김미란'\nvar_j = '김호현'\nvar_k = '<'\nvar_l = '김미란'\nvar_m = '정재영'\nvar_n = '>'\nvar_o = '김호현'\nvar_p = '김현정'\nvar_q = '>'\nvar_r = '김현정'\nvar_s = '김미란'\nvar_t = '>'\nlist_b= []\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_b.append(var_t)\nif \"/\" in str(var_s):\n    var_s = eval(str(var_s))\nlist_b.append(var_s)\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_u = 3\nvar_v = list_c[var_u-1]\nprint(var_v)",
        "solution_code_en": "var_a = 'Seulgi'\nvar_b = 'Hyunjung'\nvar_c = 'Miran'\nvar_d = 'Hohyun'\nvar_e = 'Jaeyoung'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 'Seulgi'\nvar_g = 'Hyunjung'\nvar_h = '>'\nvar_i = 'Miran'\nvar_j = 'Hohyun'\nvar_k = '<'\nvar_l = 'Miran'\nvar_m = 'Jaeyoung'\nvar_n = '>'\nvar_o = 'Hohyun'\nvar_p = 'Hyunjung'\nvar_q = '>'\nvar_r = 'Hyunjung'\nvar_s = 'Miran'\nvar_t = '>'\nlist_b= []\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_b.append(var_t)\nif \"/\" in str(var_s):\n    var_s = eval(str(var_s))\nlist_b.append(var_s)\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_u = 3\nvar_v = list_c[var_u-1]\nprint(var_v)"
    },
    "1434": {
        "category": "Geometry",
        "question_ko": "구각형의 한 꼭짓점에서 대각선을 그을 때 생기는 삼각형의 개수는?",
        "question_en": "How many triangles are formed when a diagonal is drawn from a vertex of a nonagon?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "9 3 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "9 3 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 9\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "1435": {
        "category": "Geometry",
        "question_ko": "음료수를 정사각형 모양으로 줄세웠습니다. 둘레에 놓인 음료수의 개수가 240개였다면, 전체 음료수의 개수는 몇 개입니까?",
        "question_en": "Drinks are lined up in a square shape. If there were 240 drinks in the perimeter, what is the total number of drinks?",
        "answer_ko": "3721",
        "answer_en": "3721",
        "solution_abst_ko": "240 4 [OP_DIV] 1 [OP_ADD] 2 [OP_POW]",
        "solution_abst_en": "240 4 [OP_DIV] 1 [OP_ADD] 2 [OP_POW]",
        "solution_code_ko": "var_a = 240\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e ** var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 240\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e ** var_f\nprint(int(var_g))"
    },
    "1436": {
        "category": "Geometry",
        "question_ko": "가로가 12센티미터(㎝), 세로가 16센티미터(㎝), 높이가 14센티미터(㎝)인 직육면체가 있다. 이 직육면체를 잘라 만들 수 있는 가장 큰 정육면체의 겉넓이는?",
        "question_en": "A cuboid is 12 centimeters (cm) wide, 16 centimeters (cm) long, and 14 centimeters (cm) high. What is the surface area of the largest cube that can be cut out of this cube?",
        "answer_ko": "864",
        "answer_en": "864",
        "solution_abst_ko": "[OP_LIST_SOL] 12 16 14 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_POW] 6 [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 12 16 14 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_POW] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 12\nvar_b = 16\nvar_c = 14\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nvar_f = 2\nvar_g = var_e ** var_f\nvar_h = 6\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 12\nvar_b = 16\nvar_c = 14\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nvar_f = 2\nvar_g = var_e ** var_f\nvar_h = 6\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "1437": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 14미터(m)인 공원이 있습니다. 이 공원을 가로가 8미터(m), 세로가 2미터(m)인 직사각형 구역으로 여러개 나누려고 합니다. 구역은 최대 몇 개로 나누어질 수 있겠습니까?",
        "question_en": "There is a park with a side length of 14 meters (m). If the park is divided into districts in a rectangular shape measuring 8 meters (m) long by 2 meters (m) wide. How many districts can there be in the maximum?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "14 2 [OP_POW] 8 2 [OP_MUL] [OP_FDIV]",
        "solution_abst_en": "14 2 [OP_POW] 8 2 [OP_MUL] [OP_FDIV]",
        "solution_code_ko": "var_a = 14\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 8\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c // var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 14\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 8\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c // var_f\nprint(int(var_g))"
    },
    "1438": {
        "category": "Possibility",
        "question_ko": "서로 다른 종류의 연필 5자루를 4명의 학생에게 남김 없이 나누어주려고 합니다. 이때, 연필을 받지 못하는 학생이 있을 수 있습니다. 연필을 학생들에게 나누어주는 경우는 모두 몇 가지인가요?",
        "question_en": "You want to distribute 5 different pencils to 4 students. There may be students who do not receive a pencil. Find out the number of cases of distributing the pencils to the students.",
        "answer_ko": "1024",
        "answer_en": "1024",
        "solution_abst_ko": "4 5 [OP_POW]",
        "solution_abst_en": "4 5 [OP_POW]",
        "solution_code_ko": "var_a = 4\nvar_b = 5\nvar_c = var_a ** var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 5\nvar_c = var_a ** var_b\nprint(int(var_c))"
    },
    "1439": {
        "category": "Geometry",
        "question_ko": "옷을 만들기 위해 짜투리 천을 이어 붙이기로 하였습니다. 길이가 10센티미터(㎝)인 천 20장을 이어 붙이고 연결 부분의 길이가 5밀리미터(㎜)로 모두 같다면 이어 붙인 천의 길이는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "To make clothes, I decided to sew up the leftover fabric. If 20 pieces of fabric each 10 centimeters (cm) long are sewn together and the length of the joint is 5 millimeters (mm), how many centimeters (cm) is the length of the piece of fabric sewn together?",
        "answer_ko": "190.50",
        "answer_en": "190.5",
        "solution_abst_ko": "10 20 [OP_MUL] 5 10 [OP_DIV] 20 1 [OP_SUB] [OP_MUL] [OP_SUB]",
        "solution_abst_en": "10 20 [OP_MUL] 5 10 [OP_DIV] 20 1 [OP_SUB] [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = 10\nvar_f = var_d / var_e\nvar_g = 20\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = var_f * var_i\nvar_k = var_c - var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 10\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = 10\nvar_f = var_d / var_e\nvar_g = 20\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = var_f * var_i\nvar_k = var_c - var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "1440": {
        "category": "Correspondence",
        "question_ko": "57A-2B4=364입니다. B는 얼마인가요?",
        "question_en": "57A-2B4=364. What number is B?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "57A-2B4=364 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "57A-2B4=364 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '57A-2B4=364'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '57A-2B4=364'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "1441": {
        "category": "Arithmetic calculation",
        "question_ko": "40 이상 70 미만인 자연수는 모두 몇 개입니까?",
        "question_en": "How many natural numbers are more than 40 and less than 70?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "70 40 [OP_SUB]",
        "solution_abst_en": "70 40 [OP_SUB]",
        "solution_code_ko": "var_a = 70\nvar_b = 40\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 70\nvar_b = 40\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "1442": {
        "category": "Possibility",
        "question_ko": "5, 6, 7 중에서 한 번씩만 사용하여 만들 수 있는 세 자리 수 중에서 짝수의 개수를 구하시오.",
        "question_en": "Find the number of even numbers in a three-digit number that can be formed by using 5, 6, and 7 only once.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 5 6 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 5 6 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 5\nvar_b = 6\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 5\nvar_b = 6\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "1443": {
        "category": "Comparison",
        "question_ko": "5, 8, 4, 3, 2 중에서 2번째로 큰 수를 고르세요.",
        "question_en": "Choose the second largest number among 5, 8, 4, 3, and 2.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "[OP_LIST_SOL] 5 8 4 3 2 [OP_LIST_EOL] 2 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 5 8 4 3 2 [OP_LIST_EOL] 2 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 5\nvar_b = 8\nvar_c = 4\nvar_d = 3\nvar_e = 2\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 8\nvar_c = 4\nvar_d = 3\nvar_e = 2\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nprint(int(var_g))"
    },
    "1444": {
        "category": "Geometry",
        "question_ko": "상연이네 학교의 3학년 학생들이 꽃길을 만들기 위하여 68미터(m)되는 도로의 양쪽에 4미터(m) 간격으로 꽃을 한 송이씩 심기로 하였습니다. 필요한 꽃은 몇 송이입니까? (단, 도로의 양 끝에는 반드시 꽃을 심습니다.)",
        "question_en": "The 3rd-grade students from Sangyeon's school decided to plant one flower at an interval of 4 meters (m) on both sides of the 68-meter (m) road to create a flower path. How many flowers do they need? (Note that flowers must be planted at both ends of the road.)",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "68 4 [OP_DIV] 2 [OP_MUL] 2 [OP_ADD]",
        "solution_abst_en": "68 4 [OP_DIV] 2 [OP_MUL] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 68\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 68\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "1445": {
        "category": "Geometry",
        "question_ko": "길이가 10.4센티미터(㎝)인 철사 16개를 3.5센티미터(㎝)식 겹치게 이어 크리스마스 리스를 만들었습니다. 리스의 전체 길이는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "I made a Christmas wreath by connecting 16 wires of 10.4 centimeters (cm) in length, overlapping each other by 3.5 centimeters (cm). Find the total length of the wreath in centimeters (cm).",
        "answer_ko": "113.9",
        "answer_en": "113.9",
        "solution_abst_ko": "10.4 16 [OP_MUL] 3.5 16 1 [OP_SUB] [OP_MUL] [OP_SUB]",
        "solution_abst_en": "10.4 16 [OP_MUL] 3.5 16 1 [OP_SUB] [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 10.4\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 3.5\nvar_e = 16\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_c - var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 10.4\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 3.5\nvar_e = 16\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_c - var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "1446": {
        "category": "Correspondence",
        "question_ko": "승민이와 효주가 등산을 갔다. 승민이가 효주에게 0.43리터(L)만큼의 물을 주었더니 두 사람이 가진 물의 양의 차이가 0.88리터(L)가 되었다고 한다. 물을 주기전에 차이는 몇 리터(L)였는지 구하시오. 단 승민이가 효주보다 더 많이 물을 가지고 있다.",
        "question_en": "Seungmin and Hyojoo went hiking. When Seungmin gave Hyojoo 0.43 liters (L) of water, the difference between the amount of water the two had was 0.88 liters (L). Find the difference in liters (l) before he gave her water. However, Seungmin has more water than Hyojoo.",
        "answer_ko": "1.74",
        "answer_en": "1.74",
        "solution_abst_ko": "0.88 0.43 [OP_ADD] 0.43 [OP_ADD]",
        "solution_abst_en": "0.88 0.43 [OP_ADD] 0.43 [OP_ADD]",
        "solution_code_ko": "var_a = 0.88\nvar_b = 0.43\nvar_c = var_a + var_b\nvar_d = 0.43\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.88\nvar_b = 0.43\nvar_c = var_a + var_b\nvar_d = 0.43\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "1447": {
        "category": "Comparison",
        "question_ko": "유나, 은지, 민영이가 키 순서대로 서 있습니다. 민영이가 은지보다 키가 작고, 유나가 은지보다 키가 큽니다. 키가 작은 학생이 가장 앞에 서 있다면 맨 앞에 서 있는 학생은 누구인지 구하세요.",
        "question_en": "Yuna, Eunji, and Minyoung are standing in order of height. Minyoung is shorter than Eunji, and Yuna is taller than Eunji. If the shortest student is standing at the front, find out who is standing at the front.",
        "answer_ko": "민영",
        "answer_en": "Minyoung",
        "solution_abst_ko": "[OP_LIST_SOL] 유나 은지 민영 [OP_LIST_EOL] [OP_LIST_SOL] 유나 은지 > 민영 은지 < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yuna Eunji Minyoung [OP_LIST_EOL] [OP_LIST_SOL] Yuna Eunji > Minyoung Eunji < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '유나'\nvar_b = '은지'\nvar_c = '민영'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '유나'\nvar_e = '은지'\nvar_f = '>'\nvar_g = '민영'\nvar_h = '은지'\nvar_i = '<'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = len(list_c)\nvar_k = list_c[var_j-1]\nprint(var_k)",
        "solution_code_en": "var_a = 'Yuna'\nvar_b = 'Eunji'\nvar_c = 'Minyoung'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'Yuna'\nvar_e = 'Eunji'\nvar_f = '>'\nvar_g = 'Minyoung'\nvar_h = 'Eunji'\nvar_i = '<'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = len(list_c)\nvar_k = list_c[var_j-1]\nprint(var_k)"
    },
    "1448": {
        "category": "Geometry",
        "question_ko": "구각형의 한 꼭짓점에서 이웃하지 않은 꼭짓점으로 선분을 그을 때 생기는 삼각형의 개수는 몇 개입니까?",
        "question_en": "How many triangles are formed when a line segment is drawn from one vertex of a nonagon to a non-neighboring vertex?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "9 3 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "9 3 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 9\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "1449": {
        "category": "Geometry",
        "question_ko": "길이가 각각 36센티미터(㎝), 42센티미터(㎝), 48센티미터(㎝) 인 리본이 있다. 이 리본을 1/6을 잘라내고 남은 부분을 서로 묶어서 긴 리본을 하나 만들었다. 만들어진 리본의 길이가 97센티미터(㎝)이다. 리본을 서로 묶는데 몇 센티미터(㎝)가 사용되는지 구하시오.",
        "question_en": "There are ribbons with lengths of 36 centimeters (cm), 42 centimeters (cm), and 48 centimeters (cm), respectively. I cut 1/6 of this ribbons and tied the remaining pieces together to make one long ribbon. The length of the ribbon made is 97 centimeters (cm). Find how many centimeters (cm) are used to tie the ribbons together.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "36 42 [OP_ADD] 48 [OP_ADD] 1 1/6 [OP_SUB] [OP_MUL] 97 [OP_SUB]",
        "solution_abst_en": "36 42 [OP_ADD] 48 [OP_ADD] 1 1/6 [OP_SUB] [OP_MUL] 97 [OP_SUB]",
        "solution_code_ko": "var_a = 36\nvar_b = 42\nvar_c = var_a + var_b\nvar_d = 48\nvar_e = var_c + var_d\nvar_f = 1\nvar_g = 0.16666666666666666\nvar_h = var_f - var_g\nvar_i = var_e * var_h\nvar_j = 97\nvar_k = var_i - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 36\nvar_b = 42\nvar_c = var_a + var_b\nvar_d = 48\nvar_e = var_c + var_d\nvar_f = 1\nvar_g = 0.16666666666666666\nvar_h = var_f - var_g\nvar_i = var_e * var_h\nvar_j = 97\nvar_k = var_i - var_j\nprint(int(var_k))"
    },
    "1450": {
        "category": "Comparison",
        "question_ko": "어부가 잡은 물고기 3마리의 무게를 재었습니다. 광어보다 고등어가 더 무거웠고 고등어보다 우럭이 더 무거웠습니다. 우럭은 몇 번째로 가장 가벼운 물고기입니까?",
        "question_en": "Three fish caught by a fisherman were weighed. The mackerel was heavier than the flatfish, and the rockfish was heavier than the mackerel. How lightest is the rockfish among those three?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 광어 고등어 우럭 [OP_LIST_EOL] 우럭 [OP_LIST_INDEX]",
        "solution_abst_en": "[OP_LIST_SOL] flatfish mackerel rockfish [OP_LIST_EOL] rockfish [OP_LIST_INDEX]",
        "solution_code_ko": "var_a = '광어'\nvar_b = '고등어'\nvar_c = '우럭'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '우럭'\nvar_e = list_a.index(var_d)+1\nprint(int(var_e))",
        "solution_code_en": "var_a = 'flatfish'\nvar_b = 'mackerel'\nvar_c = 'rockfish'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'rockfish'\nvar_e = list_a.index(var_d)+1\nprint(int(var_e))"
    },
    "1451": {
        "category": "Correspondence",
        "question_ko": "38A-B1=364라는 식이 성립하려면, B에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "What number must go in B to make 38A-B1=364?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "38A-B1=364 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "38A-B1=364 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '38A-B1=364'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '38A-B1=364'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "1452": {
        "category": "Arithmetic calculation",
        "question_ko": "창혁이의 용돈은 15000원입니다. 받은 용돈을 남김없이 사용하여 하나에 1000원인 과자와 하나에 1300원인 음료수를 합하여 12개 샀습니다. 창혁이가 산 과자는 모두 몇 개인지 구하세요.",
        "question_en": "Changhyeok's pocket money is 15,000 won. Using all of the pocket money he received, he bought a total of 12 snacks, each costing 1,000 won, and drinks, each costing 1,300 won. Find how many snacks Changhyeok bought.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "1300 12 [OP_MUL] 15000 [OP_SUB] 1300 1000 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "1300 12 [OP_MUL] 15000 [OP_SUB] 1300 1000 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 1300\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 15000\nvar_e = var_c - var_d\nvar_f = 1300\nvar_g = 1000\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1300\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 15000\nvar_e = var_c - var_d\nvar_f = 1300\nvar_g = 1000\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "1453": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 10, 11, 12, 13이 있습니다. 그 중 2번째로 작은 수는 무엇입니까?",
        "question_en": "There are four numbers 10, 11, 12, and 13. Which number is the second smallest?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 2 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 2 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nprint(int(var_f))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nprint(int(var_f))"
    },
    "1454": {
        "category": "Arithmetic calculation",
        "question_ko": "큰 통에 물이 7리터(L) 들어 있고 작은 통에 물이 5리터(L) 들어 있습니다. 작은 통에 들어 있던 물 2리터(L)를 큰 통에 따랐습니다. 큰 통의 물은 작은 통의 물보다 몇 리터(L) 더 많습니까?",
        "question_en": "A large bucket contains 7 liters (L) of water and a small bucket contains 5 liters (L) of water. 2 liters (L) of water from the small bucket was poured into the large bucket. How many liters (L) more water is in the large bucket than in the small bucket?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "7 2 [OP_ADD] 5 2 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "7 2 [OP_ADD] 5 2 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 7\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 7\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "1455": {
        "category": "Arithmetic calculation",
        "question_ko": "민정이네 집에는 매일 0.2리터(L)짜리 우유가 3개씩 배달됩니다. 일주일 동안 민정이네 집에 배달되는 우유는 모두 몇 리터(L)인지 구하시오.",
        "question_en": "3 bottles of 0.2 liters (L) of milk are delivered to Minjeong's house every day. Find how many liters (L) of all the milk was delivered to Minjeong's house for a week.",
        "answer_ko": "4.20",
        "answer_en": "4.2",
        "solution_abst_ko": "0.2 3 [OP_MUL] 7 [OP_MUL]",
        "solution_abst_en": "0.2 3 [OP_MUL] 7 [OP_MUL]",
        "solution_code_ko": "var_a = 0.2\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.2\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "1456": {
        "category": "Arithmetic calculation",
        "question_ko": "어제 삼촌이 은지에게 용돈을 주셨습니다. 은지가 용돈의 절반으로 공책을 사고, 어머니에게 오늘 550원을 더 받았더니 가진 돈이 1,000원이 되었습니다. 삼촌에게 받았던 용돈은 얼마입니까?",
        "question_en": "Yesterday, Eunji's uncle gave Eunji some pocket money. Eunji bought a notebook with half of her pocket money, and when she received an additional 550 won from her mother today, her money became 1,000 won. How much money did she get from her uncle?",
        "answer_ko": "900",
        "answer_en": "900",
        "solution_abst_ko": "1000 550 [OP_SUB] 2 [OP_MUL]",
        "solution_abst_en": "1000 550 [OP_SUB] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 1000\nvar_b = 550\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 1000\nvar_b = 550\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "1457": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 8을 더해 결과로 88을 얻었습니다. 10을 어떤 수에서 나눈 결과는 얼마입니까?",
        "question_en": "Adding 8 to any number gives 88 as a result. What is the result of dividing a number by 10?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "88 8 [OP_SUB] 10 [OP_DIV]",
        "solution_abst_en": "88 8 [OP_SUB] 10 [OP_DIV]",
        "solution_code_ko": "var_a = 88\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 10\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 88\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 10\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "1458": {
        "category": "Comparison",
        "question_ko": "지민이는 호석이보다 게임을 잘하고 호석이는 영수보다 게임을 잘합니다. 세 명이서 게임을 하는 도중 두 명이 더 참여하게 되었습니다. 두 명 중 진우는 호석이보다는 잘하지만 지민이보다는 못하고, 동균이는 지민이보다 잘합니다. 다섯 명 중 게임을 가장 못하는 사람은 누구인가요?",
        "question_en": "Jimin is better at games than Hoseok, and Hoseok is better at games than Youngsoo. While the three of them were playing the game, two more joined them. Of the two, Jinwoo is better than Hoseok but not as good as Jimin, and Donggyun is better than Jimin. Who is the worst gamer out of the five?",
        "answer_ko": "영수",
        "answer_en": "Youngsoo",
        "solution_abst_ko": "[OP_LIST_SOL] 지민 호석 영수 진우 동균 [OP_LIST_EOL] [OP_LIST_SOL] 지민 호석 > 호석 영수 > 진우 호석 > 지민 진우 > 동균 지민 > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jimin Hoseok Youngsoo Jinwoo Donggyun [OP_LIST_EOL] [OP_LIST_SOL] Jimin Hoseok > Hoseok Youngsoo > Jinwoo Hoseok > Jimin Jinwoo > Donggyun Jimin > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '지민'\nvar_b = '호석'\nvar_c = '영수'\nvar_d = '진우'\nvar_e = '동균'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = '지민'\nvar_g = '호석'\nvar_h = '>'\nvar_i = '호석'\nvar_j = '영수'\nvar_k = '>'\nvar_l = '진우'\nvar_m = '호석'\nvar_n = '>'\nvar_o = '지민'\nvar_p = '진우'\nvar_q = '>'\nvar_r = '동균'\nvar_s = '지민'\nvar_t = '>'\nlist_b= []\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_b.append(var_t)\nif \"/\" in str(var_s):\n    var_s = eval(str(var_s))\nlist_b.append(var_s)\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_u = len(list_c)\nvar_v = list_c[var_u-1]\nprint(var_v)",
        "solution_code_en": "var_a = 'Jimin'\nvar_b = 'Hoseok'\nvar_c = 'Youngsoo'\nvar_d = 'Jinwoo'\nvar_e = 'Donggyun'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 'Jimin'\nvar_g = 'Hoseok'\nvar_h = '>'\nvar_i = 'Hoseok'\nvar_j = 'Youngsoo'\nvar_k = '>'\nvar_l = 'Jinwoo'\nvar_m = 'Hoseok'\nvar_n = '>'\nvar_o = 'Jimin'\nvar_p = 'Jinwoo'\nvar_q = '>'\nvar_r = 'Donggyun'\nvar_s = 'Jimin'\nvar_t = '>'\nlist_b= []\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_b.append(var_t)\nif \"/\" in str(var_s):\n    var_s = eval(str(var_s))\nlist_b.append(var_s)\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_u = len(list_c)\nvar_v = list_c[var_u-1]\nprint(var_v)"
    },
    "1459": {
        "category": "Arithmetic calculation",
        "question_ko": "55명의 학생이 (가) 시합과 (나) 시합에 참가했습니다. 그중에서 38명의 학생이 (가) 시합에 참가하고, 42명의 학생이 (나) 시합에 참가했습니다. (가), (나) 두 시합에 모두 참가하지 않은 학생이 한 명도 없을 때, 두 시합에 모두 참가한 학생은 몇 명입니까?",
        "question_en": "55 students participated in A competition and B competition. Among them, 38 students participated in A  competition, and 42 students participated in B competition. If no student did not participate in neither competitions A nor B, how many students participated in both competitions?",
        "answer_ko": "25",
        "answer_en": "25",
        "solution_abst_ko": "38 42 [OP_ADD] 55 [OP_SUB]",
        "solution_abst_en": "38 42 [OP_ADD] 55 [OP_SUB]",
        "solution_code_ko": "var_a = 38\nvar_b = 42\nvar_c = var_a + var_b\nvar_d = 55\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 38\nvar_b = 42\nvar_c = var_a + var_b\nvar_d = 55\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "1460": {
        "category": "Correspondence",
        "question_ko": "서로 다른 세 자연수 A, B, C가 있습니다. A+B=84, B+C=60, A=B+B+B+B+B+B일 때, A-C의 값을 구하시오.",
        "question_en": "There are three different natural numbers A, B, and C. When A+B=84, B+C=60, and A=B+B+B+B+B+B, find the value of A-C.",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "84 7 [OP_DIV] 6 [OP_MUL] 60 84 7 [OP_DIV] [OP_SUB] [OP_SUB]",
        "solution_abst_en": "84 7 [OP_DIV] 6 [OP_MUL] 60 84 7 [OP_DIV] [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 84\nvar_b = 7\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c * var_d\nvar_f = 60\nvar_g = 84\nvar_h = 7\nvar_i = var_g / var_h\nvar_j = var_f - var_i\nvar_k = var_e - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 84\nvar_b = 7\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c * var_d\nvar_f = 60\nvar_g = 84\nvar_h = 7\nvar_i = var_g / var_h\nvar_j = var_f - var_i\nvar_k = var_e - var_j\nprint(int(var_k))"
    },
    "1461": {
        "category": "Arithmetic calculation",
        "question_ko": "세 자리 수 중 3과 5의 공배수 중 가장 작은 수는?",
        "question_en": "Which three-digit number is the smallest among the common multiples of 3 and 5?",
        "answer_ko": "105",
        "answer_en": "105",
        "solution_abst_ko": "100 999 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "100 999 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[var_f-1]\nprint(int(var_g))"
    },
    "1462": {
        "category": "Arithmetic calculation",
        "question_ko": "계주에서 시원이는 전체의 3/10을 달렸고 다원이는 전체의 4/10을 달렸습니다. 시원이와 다원이가 달린 거리가 140미터(m)라면 계주 전체 거리는 얼마입니까?",
        "question_en": "In the relay, Siwon ran 3/10 of the track, and Dawon ran 4/10 of the track. If the distance Siwon and Dawon run is 140 meters (m), what is the total distance of the relay race?",
        "answer_ko": "200",
        "answer_en": "200",
        "solution_abst_ko": "140 3/10 4/10 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "140 3/10 4/10 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 140\nvar_b = 0.3\nvar_c = 0.4\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 140\nvar_b = 0.3\nvar_c = 0.4\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "1463": {
        "category": "Arithmetic calculation",
        "question_ko": "지원이는 친구들과 분식집에 갔습니다. 지원이를 포함한 친구는 모두 4명이고 하나에 200원인 어묵 5개와 하나에 800원인 떡볶이 7인분을 사먹으려고 합니다. 친구들이 모두 같은 돈을 내려면 한 사람이 내야하는 돈은 얼마입니까?",
        "question_en": "Jiwon went to a snack bar with his friends. There are 4 friends, including Jiwon, and they want to buy 5 fish cakes at 200 won each and 7 servings of tteokbokki at 800 won each. How much does one person have to pay if all of his friends pay the same?",
        "answer_ko": "1650",
        "answer_en": "1650",
        "solution_abst_ko": "200 5 [OP_MUL] 800 7 [OP_MUL] [OP_ADD] 4 [OP_DIV]",
        "solution_abst_en": "200 5 [OP_MUL] 800 7 [OP_MUL] [OP_ADD] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 200\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 800\nvar_e = 7\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 4\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 200\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 800\nvar_e = 7\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 4\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "1464": {
        "category": "Correspondence",
        "question_ko": "50은 어떤 수보다 26 큰 수입니다. 어떤 수에 9를 곱하면 얼마가 되나요?",
        "question_en": "50 is 26 greater than a number. What is the value of the number multiplied by 9?",
        "answer_ko": "216",
        "answer_en": "216",
        "solution_abst_ko": "50 26 [OP_SUB] 9 [OP_MUL]",
        "solution_abst_en": "50 26 [OP_SUB] 9 [OP_MUL]",
        "solution_code_ko": "var_a = 50\nvar_b = 26\nvar_c = var_a - var_b\nvar_d = 9\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 50\nvar_b = 26\nvar_c = var_a - var_b\nvar_d = 9\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "1465": {
        "category": "Correspondence",
        "question_ko": "45를 어떤 수로 나누었더니 몫이 11이고 나머지가 1이었다. 어떤 수는 얼마인지 구하시오.",
        "question_en": "When 45 is divided by a number, the quotient is 11 and the remainder is 1. Find the value of the number.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "45 1 [OP_SUB] 11 [OP_DIV]",
        "solution_abst_en": "45 1 [OP_SUB] 11 [OP_DIV]",
        "solution_code_ko": "var_a = 45\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 11\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 45\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 11\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "1466": {
        "category": "Arithmetic calculation",
        "question_ko": "5지선다형 20문제가 적힌 시험지에 1이 몇 번 등장합니까? (단, 문제 번호와 답 번호 외에 다른 숫자는 없습니다.)",
        "question_en": "How many times does the number 1 appear on a test sheet with 5 multiple choice 20 questions? (However, there are no numbers other than the question number and the answer number.)",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "1 20 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 1 [OP_LIST_FIND_NUM] 20 [OP_ADD]",
        "solution_abst_en": "1 20 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 1 [OP_LIST_FIND_NUM] 20 [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 20\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 1\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nvar_g = 20\nvar_h = var_f + var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 1\nvar_b = 20\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 1\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nvar_g = 20\nvar_h = var_f + var_g\nprint(int(var_h))"
    },
    "1467": {
        "category": "Possibility",
        "question_ko": "100이하의 자연수 중 3으로 나눈 나머지가 2인 수들을 순서대로 적을 때, 4는 몇 번 적는지 구하시오.",
        "question_en": "When you write numbers no more than 100 that have a remainder of 2 when divided by 3 in order, how many times 4 is written?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "1 100 1 [OP_LIST_ARANGE] 3 2 [OP_LIST_DIVIDE_AND_REMAIN] [OP_LIST2NUM] [OP_NUM2LIST] 4 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 100 1 [OP_LIST_ARANGE] 3 2 [OP_LIST_DIVIDE_AND_REMAIN] [OP_LIST2NUM] [OP_NUM2LIST] 4 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nvar_e = 2\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f=\"\"\nfor i in list_b:\n    i = str(i)\n    var_f = var_f + i\nlist_c = []\nvar_f = int(var_f)\nwhile var_f//10 > 0:\n    list_c.append(var_f%10)\n    var_f = var_f//10\nlist_c.append(var_f%10)\nlist_c = list_c[::-1]\nvar_g = 4\nvar_h = 0\nvar_g = int(var_g)\nfor i in list_c:\n    i = int(i)\n    if i == var_g:\n        var_h = var_h + 1\nprint(int(var_h))",
        "solution_code_en": "var_a = 1\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nvar_e = 2\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f=\"\"\nfor i in list_b:\n    i = str(i)\n    var_f = var_f + i\nlist_c = []\nvar_f = int(var_f)\nwhile var_f//10 > 0:\n    list_c.append(var_f%10)\n    var_f = var_f//10\nlist_c.append(var_f%10)\nlist_c = list_c[::-1]\nvar_g = 4\nvar_h = 0\nvar_g = int(var_g)\nfor i in list_c:\n    i = int(i)\n    if i == var_g:\n        var_h = var_h + 1\nprint(int(var_h))"
    },
    "1468": {
        "category": "Correspondence",
        "question_ko": "다섯 자리 수 6AB87은 9의 배수이다. A, B에 알맞은 숫자를 찾아 숫자 쌍을 만들 때, 가능한 숫자 쌍은 모두 몇 가지인가?",
        "question_en": "The five-digit number 6AB87 is a multiple of 9. When creating the pair of numbers by putting the right numbers for A and B, how many possible number pairs can be made?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "6AB87 [OP_GEN_POSSIBLE_LIST] 9 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "6AB87 [OP_GEN_POSSIBLE_LIST] 9 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '6AB87'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 9\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))",
        "solution_code_en": "var_a = '6AB87'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 9\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))"
    },
    "1469": {
        "category": "Comparison",
        "question_ko": "20명의 학생들이 한 줄로 줄을 섰습니다. 윤기의 뒤에는 정국이가 서있고, 정국이 앞에는 11명의 학생들이 서 있습니다. 윤기의 뒤에 서 있는 학생은 몇 명입니까?",
        "question_en": "20 students lined up in a single line. Jungkook is standing behind Yoongi, and 11 students are standing in front of Jungkook. How many students are standing behind Yoongi?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "20 11 [OP_SUB] 1 [OP_ADD] 1 [OP_SUB]",
        "solution_abst_en": "20 11 [OP_SUB] 1 [OP_ADD] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 1\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 1\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "1470": {
        "category": "Correspondence",
        "question_ko": "36에 어떤 수를 곱해야 할 것을 잘못하여 63에 어떤 수를 더했더니 70이 되었습니다. 바르게 계산하면 얼마인지 구하시오.",
        "question_en": "You made a mistake in multiplying 36 by a number, so I added a number to 63 instead. Suppose that you got 70. How much is it if you calculate it correctly?",
        "answer_ko": "252",
        "answer_en": "252",
        "solution_abst_ko": "36 70 63 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "36 70 63 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 36\nvar_b = 70\nvar_c = 63\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 36\nvar_b = 70\nvar_c = 63\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nprint(int(var_e))"
    },
    "1471": {
        "category": "Arithmetic calculation",
        "question_ko": "달팽이 A와 B는 밥을 먹으러 꽃으로 갈 때 시속 10미터(m), 15미터(m)로 간다. B가 도착하고 30분 후 A가 도착했다. 꽃과 두 달팽이의 출발 지점 간의 거리를 구하라.",
        "question_en": "Snails A and B travel at 10 meters (m) and 15 meters (m) per hour respectively when they go to the flower to eat. A arrives 30 minutes after B arrives. Find the distance between the flower and the starting points of the two snails.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "30 60 [OP_DIV] 1 10 [OP_DIV] 1 15 [OP_DIV] [OP_SUB] [OP_DIV]",
        "solution_abst_en": "30 60 [OP_DIV] 1 10 [OP_DIV] 1 15 [OP_DIV] [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 30\nvar_b = 60\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = 10\nvar_f = var_d / var_e\nvar_g = 1\nvar_h = 15\nvar_i = var_g / var_h\nvar_j = var_f - var_i\nvar_k = var_c / var_j\nprint(int(eval('{:.2f}'.format(round(var_k+1e-10,2)))))",
        "solution_code_en": "var_a = 30\nvar_b = 60\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = 10\nvar_f = var_d / var_e\nvar_g = 1\nvar_h = 15\nvar_i = var_g / var_h\nvar_j = var_f - var_i\nvar_k = var_c / var_j\nprint(int(eval('{:.2f}'.format(round(var_k+1e-10,2)))))"
    },
    "1472": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 0.06으로 나누었더니 426이 되었습니다. 어떤 수를 구하시오.",
        "question_en": "When a number is divided by 0.06, it results 426. Find the inital unknown number.",
        "answer_ko": "25.56",
        "answer_en": "25.56",
        "solution_abst_ko": "426 0.06 [OP_MUL]",
        "solution_abst_en": "426 0.06 [OP_MUL]",
        "solution_code_ko": "var_a = 426\nvar_b = 0.06\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 426\nvar_b = 0.06\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "1473": {
        "category": "Possibility",
        "question_ko": "서로 다른 세 종류의 상자가 있습니다. 서로 같은 공 5개를 상자에 나눠 담으려고 할 때, 빈 상자가 없게 하는 경우의 수를 구하시오.",
        "question_en": "There are three different types of boxes. Find the number of ways in which there are no empty boxes when putting 5 balls of the same size into these boxes.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "1 3 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_NUM2SUM] 5 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 3 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_NUM2SUM] 5 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 5\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 5\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))"
    },
    "1474": {
        "category": "Arithmetic calculation",
        "question_ko": "놀이 공원에 입장한 사람 중 여자는 1518명이고, 이 중에서 초등학생은 536명이었습니다. 남자는 여자보다 525명이 더 많았고, 이 중에서 초등학생에 아닌 사람은 1257명이었습니다. 놀이 공원에 입장한 초등학생은 모두 몇 명입니까?",
        "question_en": "Among the people who entered the amusement park, 1518 were women, and among them, 536 were elementary school students. There were 525 more males than females, and 1257 of them were not in elementary school. How many elementary school students entered the amusement park in total?",
        "answer_ko": "1322",
        "answer_en": "1322",
        "solution_abst_ko": "1518 525 [OP_ADD] 1257 [OP_SUB] 536 [OP_ADD]",
        "solution_abst_en": "1518 525 [OP_ADD] 1257 [OP_SUB] 536 [OP_ADD]",
        "solution_code_ko": "var_a = 1518\nvar_b = 525\nvar_c = var_a + var_b\nvar_d = 1257\nvar_e = var_c - var_d\nvar_f = 536\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1518\nvar_b = 525\nvar_c = var_a + var_b\nvar_d = 1257\nvar_e = var_c - var_d\nvar_f = 536\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "1475": {
        "category": "Arithmetic calculation",
        "question_ko": "1킬로미터(㎞)를 달리는 데 경유 0.14리터(L)가 필요한 자동차가 있습니다. 이 자동차로 1시간에 93.6킬로미터(㎞)씩 2시간 30분을 달렸다면, 사용한 경유는 모두 몇 리터(L)일까요?",
        "question_en": "A car needs 0.14 liters (l) of diesel to run 1 kilometer (km). If this car ran for 2 hours and 30 minutes at 93.6 kilometers (km) per hour, how many liters (L) of diesel were used?",
        "answer_ko": "32.76",
        "answer_en": "32.76",
        "solution_abst_ko": "0.14 93.6 [OP_MUL] 2 30 60 [OP_DIV] [OP_ADD] [OP_MUL]",
        "solution_abst_en": "0.14 93.6 [OP_MUL] 2 30 60 [OP_DIV] [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 0.14\nvar_b = 93.6\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = 30\nvar_f = 60\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = var_c * var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 0.14\nvar_b = 93.6\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = 30\nvar_f = 60\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = var_c * var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "1476": {
        "category": "Correspondence",
        "question_ko": "호석이는 6으로 어떤 수를 나누었더니 11을 얻었습니다. 어떤 수를 구하시오.",
        "question_en": "When Hoseok divides a number by 6, he gets 11. Find what number is used by Hoseok.",
        "answer_ko": "66",
        "answer_en": "66",
        "solution_abst_ko": "11 6 [OP_MUL]",
        "solution_abst_en": "11 6 [OP_MUL]",
        "solution_code_ko": "var_a = 11\nvar_b = 6\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 11\nvar_b = 6\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "1477": {
        "category": "Arithmetic calculation",
        "question_ko": "구슬 85개를 지혜와 용희가 나누어 가졌습니다. 지혜가 용희보다 구슬을 11개 더 가졌다면 지혜는 구슬을 몇 개 가졌습니까?",
        "question_en": "Jihye and Yonghee shared 85 marbles. If Jihye got 11 more marbles than Yonghee, how many marbles did Jihye got?",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "85 11 [OP_SUB] 2 [OP_DIV] 11 [OP_ADD]",
        "solution_abst_en": "85 11 [OP_SUB] 2 [OP_DIV] 11 [OP_ADD]",
        "solution_code_ko": "var_a = 85\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 11\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 85\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 11\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "1478": {
        "category": "Possibility",
        "question_ko": "1부터 9까지 적혀 있는 카드 9장 중 2장을 동시에 뽑을 때, 두 장의 합이 3 또는 14가 나오는 경우의 수를 구하시오.",
        "question_en": "When two out of nine cards numbered 1 through 9 are selected at the same time, find the number of cases in which the sum of the two cards is 3 or 14.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "1 9 1 [OP_LIST_ARANGE] 2 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 14 [OP_LIST_FIND_NUM] 2 [OP_DIV] 3 [OP_LIST_FIND_NUM] 2 [OP_DIV] [OP_ADD]",
        "solution_abst_en": "1 9 1 [OP_LIST_ARANGE] 2 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 14 [OP_LIST_FIND_NUM] 2 [OP_DIV] 3 [OP_LIST_FIND_NUM] 2 [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 14\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nvar_h = 2\nvar_i = var_g / var_h\nvar_j = 3\nvar_k = 0\nvar_j = int(var_j)\nfor i in list_c:\n    i = int(i)\n    if i == var_j:\n        var_k = var_k + 1\nvar_l = 2\nvar_m = var_k / var_l\nvar_n = var_i + var_m\nprint(int(var_n))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 14\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nvar_h = 2\nvar_i = var_g / var_h\nvar_j = 3\nvar_k = 0\nvar_j = int(var_j)\nfor i in list_c:\n    i = int(i)\n    if i == var_j:\n        var_k = var_k + 1\nvar_l = 2\nvar_m = var_k / var_l\nvar_n = var_i + var_m\nprint(int(var_n))"
    },
    "1479": {
        "category": "Arithmetic calculation",
        "question_ko": "30이하의 자연수 중에서 5의 배수이거나 짝수인 수를 모두 더하면 얼마인가?",
        "question_en": "What is the sum of all integers less than 30 that are multiples of 5 or even numbers?",
        "answer_ko": "285",
        "answer_en": "285",
        "solution_abst_ko": "1 30 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] 1 30 [OP_LIST_EVEN] [OP_SET_UNION] [OP_LIST_SUM]",
        "solution_abst_en": "1 30 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] 1 30 [OP_LIST_EVEN] [OP_SET_UNION] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 30\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 1\nvar_f = 30\nlist_c = []\nif var_e%2!=0:\n    for i in range(var_e+1, var_f+1, 2):\n        list_c.append(i)\nelse:\n    for i in range(var_e, var_f+1, 2):\n        list_c.append(i)\nlist_d = list(set(list_b) | set(list_c))\nlist_d = [float(i) for i in list_d]\nvar_g = sum(list_d)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 30\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 1\nvar_f = 30\nlist_c = []\nif var_e%2!=0:\n    for i in range(var_e+1, var_f+1, 2):\n        list_c.append(i)\nelse:\n    for i in range(var_e, var_f+1, 2):\n        list_c.append(i)\nlist_d = list(set(list_b) | set(list_c))\nlist_d = [float(i) for i in list_d]\nvar_g = sum(list_d)\nprint(int(var_g))"
    },
    "1480": {
        "category": "Arithmetic calculation",
        "question_ko": "어머니는 32살에 석진이를 낳으셨습니다. 외삼촌은 어머니보다 3살 어립니다. 석진이가 12살이 되는 해에 외삼촌은 몇 살인지 구하시오.",
        "question_en": "Seokjin's mother gave birth to Seokjin at the age of 32. If his uncle is 3 years younger than his mother, find out how old his uncle is when Seokjin turns 12.",
        "answer_ko": "41",
        "answer_en": "41",
        "solution_abst_ko": "12 32 [OP_ADD] 3 [OP_SUB]",
        "solution_abst_en": "12 32 [OP_ADD] 3 [OP_SUB]",
        "solution_code_ko": "var_a = 12\nvar_b = 32\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 32\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "1481": {
        "category": "Arithmetic calculation",
        "question_ko": "윤기는 200알이 들어있는 영양제를 사서 매일 12알씩 2주일 동안 먹었습니다. 남은 영양제는 몇 알입니까?",
        "question_en": "Yoongi bought a supplement containing 200 pills and took 12 pills every day for two weeks. How many pills are left?",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "200 12 2 [OP_MUL] 7 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "200 12 2 [OP_MUL] 7 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 200\nvar_b = 12\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = 7\nvar_f = var_d * var_e\nvar_g = var_a - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 200\nvar_b = 12\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = 7\nvar_f = var_d * var_e\nvar_g = var_a - var_f\nprint(int(var_g))"
    },
    "1482": {
        "category": "Possibility",
        "question_ko": "세 자리 수를 0, 1, 3, 5을 사용하여 만들려고 합니다. 각 수는 한번씩 사용이 가능하다면 만들 수 있는 가장 큰 수에서 가장 작은 수를 더한 값을 구하여라",
        "question_en": "I am trying to create a three-digit number using 0, 1, 3, and 5. If each number can be used only once, find out the sum of the smallest number and the largest possible number.",
        "answer_ko": "634",
        "answer_en": "634",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 3 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 3 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 3\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 3\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))"
    },
    "1483": {
        "category": "Correspondence",
        "question_ko": "자연수 A를 자연수 B로 나누면 몫이 28이고 나머지가 4입니다. A가 될 수 있는 숫자 중에 가장 작은 수를 구하시오.",
        "question_en": "When a natural number A is divided by a natural number B, the quotient is 28 and the remainder is 4. Find the smallest number that can be A.",
        "answer_ko": "144",
        "answer_en": "144",
        "solution_abst_ko": "4 1 [OP_ADD] 28 [OP_MUL] 4 [OP_ADD]",
        "solution_abst_en": "4 1 [OP_ADD] 28 [OP_MUL] 4 [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 28\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 28\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "1484": {
        "category": "Possibility",
        "question_ko": "0, 3, 5, 6 중에서 서로 다른 숫자 3개를 뽑아 만들 수 있는 세 자리 수 중에서 가장 작은 수를 쓰시오.",
        "question_en": "Write the smallest three-digit number that can be formed by drawing three different numbers from 0, 3, 5, and 6.",
        "answer_ko": "305",
        "answer_en": "305",
        "solution_abst_ko": "[OP_LIST_SOL] 0 3 5 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 3 5 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 0\nvar_b = 3\nvar_c = 5\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 0\nvar_b = 3\nvar_c = 5\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nprint(int(var_g))"
    },
    "1485": {
        "category": "Comparison",
        "question_ko": "윤기는 7, 정국은 6, 유나는 9, 유정은 8만큼 모았습니다. 2번째로 큰 숫자를 가진 사람은 누구입니까?",
        "question_en": "Yoongi collected 7, Jungkook 6, Yuna 9, and Yoojung 8. Who has the 2nd largest number?",
        "answer_ko": "유정",
        "answer_en": "Yoojung",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 유나 유정 [OP_LIST_EOL] [OP_LIST_SOL] 7 6 9 8 [OP_LIST_EOL] 2 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook Yuna Yoojung [OP_LIST_EOL] [OP_LIST_SOL] 7 6 9 8 [OP_LIST_EOL] 2 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nvar_c = '유나'\nvar_d = '유정'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 7\nvar_f = 6\nvar_g = 9\nvar_h = 8\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nvar_c = 'Yuna'\nvar_d = 'Yoojung'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 7\nvar_f = 6\nvar_g = 9\nvar_h = 8\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "1486": {
        "category": "Geometry",
        "question_ko": "가로 63센티미터(㎝), 세로 42센티미터(㎝)의 직사각형 모양의 종이를 잘라 뽑기를 만들려고 합니다. 뽑기의 모양을 정사각형으로 하고, 뽑기에 당첨된 인원이 최소가 되도록 하기 위해서는 뽑기의 한 변의 길이가 몇 센티미터(㎝)가 되어야 하는지 구하시오.",
        "question_en": "I am going to make a draw by cutting a rectangular piece of paper measuring 63 centimeters (cm) wide and 42 centimeters (cm) long. Find how many centimeters (cm) the length of one side of the lottery paper should be in order to make the lottery paper square and minimize the number of people who won the lottery.",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "63 42 [OP_GCD]",
        "solution_abst_en": "63 42 [OP_GCD]",
        "solution_code_ko": "var_a = 63\nvar_b = 42\nvar_c = math.gcd(int(var_b), int(var_a))\nprint(int(var_c))",
        "solution_code_en": "var_a = 63\nvar_b = 42\nvar_c = math.gcd(int(var_b), int(var_a))\nprint(int(var_c))"
    },
    "1487": {
        "category": "Arithmetic calculation",
        "question_ko": "(가) 상자는 (나) 상자를 4개 넣으면 꽉 차고, (나) 상자는 (다) 상자를 6개 넣으면 꽉 찹니다. (가) 상자는 (다) 상자를 몇 개 넣으면 꽉 찹니까?",
        "question_en": "Box (A) is full when you put four box (B) in it, and box (B) becomes full when you put six box (C) in it. How many box (C) should you put in box (A) to make it full?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "4 6 [OP_MUL] 1 [OP_MUL]",
        "solution_abst_en": "4 6 [OP_MUL] 1 [OP_MUL]",
        "solution_code_ko": "var_a = 4\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 4\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "1488": {
        "category": "Correspondence",
        "question_ko": "169는 어떤 수보다 108 큰 수이다. 어떤 수보다 125 큰 수는 얼마인가?",
        "question_en": "169 is 108 greater than a certain number. What number is 125 greater than the certain number?",
        "answer_ko": "186",
        "answer_en": "186",
        "solution_abst_ko": "169 108 [OP_SUB] 125 [OP_ADD]",
        "solution_abst_en": "169 108 [OP_SUB] 125 [OP_ADD]",
        "solution_code_ko": "var_a = 169\nvar_b = 108\nvar_c = var_a - var_b\nvar_d = 125\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 169\nvar_b = 108\nvar_c = var_a - var_b\nvar_d = 125\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "1489": {
        "category": "Correspondence",
        "question_ko": "들이가 서로 다른 A, B, C 3개의 병이 있습니다. A병 7개와 B병 3개의 들이는 같고, B병 1개의 들이와 C병 5개의 들이는 같습니다. A병 21개의 들이는 C병 몇 개의 들이와 같습니까?",
        "question_en": "There are three bottles, A, B, and C, each with different sizes. 7 bottles of A and 3 bottles of B have the same capacity, and 1 bottle of B and 5 bottles of C are the same. How many bottles of C are equal to 21 bottles of A?",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "21 7 [OP_DIV] 3 [OP_MUL] 1 [OP_DIV] 5 [OP_MUL]",
        "solution_abst_en": "21 7 [OP_DIV] 3 [OP_MUL] 1 [OP_DIV] 5 [OP_MUL]",
        "solution_code_ko": "var_a = 21\nvar_b = 7\nvar_c = var_a / var_b\nvar_d = 3\nvar_e = var_c * var_d\nvar_f = 1\nvar_g = var_e / var_f\nvar_h = 5\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 21\nvar_b = 7\nvar_c = var_a / var_b\nvar_d = 3\nvar_e = var_c * var_d\nvar_f = 1\nvar_g = var_e / var_f\nvar_h = 5\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "1490": {
        "category": "Arithmetic calculation",
        "question_ko": "티비 수신료는 10초당 30원입니다. 민규가 2분 40초 동안 티비를 봤다면 수신료는 얼마입니까?",
        "question_en": "The TV license fee is 30 won per 10 seconds. If Mingyu watched TV for 2 minutes and 40 seconds, how much would the license fee be?",
        "answer_ko": "480",
        "answer_en": "480",
        "solution_abst_ko": "2 60 [OP_MUL] 40 [OP_ADD] 10 [OP_DIV] 30 [OP_MUL]",
        "solution_abst_en": "2 60 [OP_MUL] 40 [OP_ADD] 10 [OP_DIV] 30 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 40\nvar_e = var_c + var_d\nvar_f = 10\nvar_g = var_e / var_f\nvar_h = 30\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 2\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 40\nvar_e = var_c + var_d\nvar_f = 10\nvar_g = var_e / var_f\nvar_h = 30\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "1491": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.9 중에서 0.7보다 작은 수 중 가장 큰 수는 무엇인가요?",
        "question_en": "Which of 0.8, 1/2, and 0.9 is the largest number less than 0.7?",
        "answer_ko": "0.50",
        "answer_en": "0.5",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 0.7 [OP_LIST_LESS] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 0.7 [OP_LIST_LESS] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.7\nlist_b = []\nfor i in list_a:\n    if i < var_d:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint('{:.2f}'.format(round(var_f+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.7\nlist_b = []\nfor i in list_a:\n    if i < var_d:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint('{:.2f}'.format(round(var_f+1e-10,2)))"
    },
    "1492": {
        "category": "Possibility",
        "question_ko": "0, 1, 2, 3, 4의 수가 각각 적힌 5장의 카드에서 2장을 뽑아 만들 수 있는 두 자리의 정수의 개수를 구하시오.",
        "question_en": "Find the number of two-digit integers that can be made by drawing 2 cards from 5 cards each containing the numbers 0, 1, 2, 3, and 4.",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 4 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 4 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "1493": {
        "category": "Geometry",
        "question_ko": "십일각형의 모든 대각선의 개수를 구하시오.",
        "question_en": "Find how many diagonals are in a hendecagon.",
        "answer_ko": "44",
        "answer_en": "44",
        "solution_abst_ko": "11 11 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "11 11 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 11\nvar_b = 11\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 11\nvar_b = 11\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "1494": {
        "category": "Geometry",
        "question_ko": "트리를 꾸미기 위해 철사를 이용해 삼각형을 여러 개 만들었습니다. 트리를 꾸미기 전의 철사 길이는 84센티미터(㎝)였고, 트리를 완성한 후의 철사 길이는 12센티미터(㎝)이며, 삼각형 하나의 한 변의 길이는 1센티미터(㎝)일 때 몇 개의 삼각형을 만들었습니까?",
        "question_en": "To decorate the tree, you made several triangles using wire. The length of the wire was 84 centimeters (cm) before the decoration, and the wire became 12 centimeters (cm) at the end. Given that each triangle had a side length of 1 centimeter (cm), how many triangles can be made?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "84 12 [OP_SUB] 1 3 [OP_MUL] [OP_FDIV]",
        "solution_abst_en": "84 12 [OP_SUB] 1 3 [OP_MUL] [OP_FDIV]",
        "solution_code_ko": "var_a = 84\nvar_b = 12\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c // var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 84\nvar_b = 12\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c // var_f\nprint(int(var_g))"
    },
    "1495": {
        "category": "Comparison",
        "question_ko": "집에서 문구점까지의 거리는 11/20킬로미터(㎞)이고, 집에서 약국까지는 0.53킬로미터(㎞)입니다. 집에서 문구점까지의 거리와 집에서 약국까지의 거리 중 어느 곳이 더 멉니까?",
        "question_en": "The distance from the house to the stationery store is 11/20 kilometers (km), and from the house to the pharmacy is 0.53 kilometers (km). Which is longer, the distance from your house to the stationery store or the distance from your house to the pharmacy?",
        "answer_ko": "문구점",
        "answer_en": "stationery",
        "solution_abst_ko": "[OP_LIST_SOL] 문구점 약국 [OP_LIST_EOL] [OP_LIST_SOL] 11/20 0.53 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] stationery pharmacy [OP_LIST_EOL] [OP_LIST_SOL] 11/20 0.53 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '문구점'\nvar_b = '약국'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.55\nvar_d = 0.53\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'stationery'\nvar_b = 'pharmacy'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.55\nvar_d = 0.53\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "1496": {
        "category": "Arithmetic calculation",
        "question_ko": "민영이와 유정이가 가지고 있는 테이프의 길이를 같게 하려고 합니다. 민영이는 17미터(m) 48센티미터(㎝) 가지고 있고 유정이는 850센티미터(㎝) 가지고 있습니다. 민영이는 유정이에게 테이프를 얼마나 주어야할까요?",
        "question_en": "You are trying to make the length of the tape for Minyoung and Yoojung the same. Minyoung has 17 meters (m) and 48 centimeters (cm), and Yoojung has 850 centimeters (cm). How much tape should Minyoung give to Yoojung?",
        "answer_ko": "449",
        "answer_en": "449",
        "solution_abst_ko": "17 100 [OP_MUL] 48 [OP_ADD] 850 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "17 100 [OP_MUL] 48 [OP_ADD] 850 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 17\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 48\nvar_e = var_c + var_d\nvar_f = 850\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 17\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 48\nvar_e = var_c + var_d\nvar_f = 850\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "1497": {
        "category": "Comparison",
        "question_ko": "(가), (나), (다), (라) 4개의 구슬이 있다. (나) 구슬은 (라)구슬보다 작고, (다) 구슬보다 크다. (가) 구슬은 (라) 구슬보다 클 때, 가장 작은 구슬을 구하여라.",
        "question_en": "There are 4 marbles (A), (B), (C), (D). Marble (B) is smaller than marble (D) and bigger than marble (C). If marble (A) is bigger than marble (D), find the smallest marble.",
        "answer_ko": "(다)",
        "answer_en": "(C)",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) (다) (라) [OP_LIST_EOL] [OP_LIST_SOL] (나) (라) < (가) (라) > (나) (다) > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (A) (B) (C) (D) [OP_LIST_EOL] [OP_LIST_SOL] (B) (D) < (A) (D) > (B) (C) > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nvar_c = '(다)'\nvar_d = '(라)'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '(나)'\nvar_f = '(라)'\nvar_g = '<'\nvar_h = '(가)'\nvar_i = '(라)'\nvar_j = '>'\nvar_k = '(나)'\nvar_l = '(다)'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)",
        "solution_code_en": "var_a = '(A)'\nvar_b = '(B)'\nvar_c = '(C)'\nvar_d = '(D)'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '(B)'\nvar_f = '(D)'\nvar_g = '<'\nvar_h = '(A)'\nvar_i = '(D)'\nvar_j = '>'\nvar_k = '(B)'\nvar_l = '(C)'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)"
    },
    "1498": {
        "category": "Arithmetic calculation",
        "question_ko": "32명이 타고 있는 버스가 정류장에 도착하자 13명이 내리고 19명이 탔습니다. 버스에 남아 있는 사람은 몇 명일까요?",
        "question_en": "When the bus carrying 32 passengers arrived at the bus stop, 13 passengers got off and 19 passengers got on. How many people are left on the bus?",
        "answer_ko": "38",
        "answer_en": "38",
        "solution_abst_ko": "32 19 [OP_ADD] 13 [OP_SUB]",
        "solution_abst_en": "32 19 [OP_ADD] 13 [OP_SUB]",
        "solution_code_ko": "var_a = 32\nvar_b = 19\nvar_c = var_a + var_b\nvar_d = 13\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 32\nvar_b = 19\nvar_c = var_a + var_b\nvar_d = 13\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "1499": {
        "category": "Arithmetic calculation",
        "question_ko": "다섯 자리 수 중에서 2, 3, 5로 나누어떨어지는 수 중 가장 작은 수를 쓰시오.",
        "question_en": "Write the smallest of the five-digit numbers that are divided into 2, 3, or 5.",
        "answer_ko": "10020",
        "answer_en": "10020",
        "solution_abst_ko": "10000 10000 10 [OP_MUL] 1 [OP_SUB] 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "10000 10000 10 [OP_MUL] 1 [OP_SUB] 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 10000\nvar_b = 10000\nvar_c = 10\nvar_d = var_b * var_c\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_a, var_f + 1, var_g)]\nvar_h = 2\nlist_b = []\nvar_h = int(var_h)\nfor i in list_a:\n    i = int(i)\n    if i % var_h == 0:\n        list_b.append(i)\nvar_i = 3\nlist_c = []\nvar_i = int(var_i)\nfor i in list_b:\n    i = int(i)\n    if i % var_i == 0:\n        list_c.append(i)\nvar_j = 5\nlist_d = []\nvar_j = int(var_j)\nfor i in list_c:\n    i = int(i)\n    if i % var_j == 0:\n        list_d.append(i)\nvar_k = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_l = list_e[var_k-1]\nprint(int(var_l))",
        "solution_code_en": "var_a = 10000\nvar_b = 10000\nvar_c = 10\nvar_d = var_b * var_c\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_a, var_f + 1, var_g)]\nvar_h = 2\nlist_b = []\nvar_h = int(var_h)\nfor i in list_a:\n    i = int(i)\n    if i % var_h == 0:\n        list_b.append(i)\nvar_i = 3\nlist_c = []\nvar_i = int(var_i)\nfor i in list_b:\n    i = int(i)\n    if i % var_i == 0:\n        list_c.append(i)\nvar_j = 5\nlist_d = []\nvar_j = int(var_j)\nfor i in list_c:\n    i = int(i)\n    if i % var_j == 0:\n        list_d.append(i)\nvar_k = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_l = list_e[var_k-1]\nprint(int(var_l))"
    },
    "1500": {
        "category": "Correspondence",
        "question_ko": "숫자를 6으로 나누면 몫은 124이고 나머지는 4입니다. 숫자에 24를 더하고 8로 나누면 얼마입니까?",
        "question_en": "When a number is divided by 6, the quotient is 124 and the remainder is 4. What is the remainder when you add 24 to this number and divide it by 8?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "124 6 [OP_MUL] 4 [OP_ADD] 24 [OP_ADD] 8 [OP_MOD]",
        "solution_abst_en": "124 6 [OP_MUL] 4 [OP_ADD] 24 [OP_ADD] 8 [OP_MOD]",
        "solution_code_ko": "var_a = 124\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 24\nvar_g = var_e + var_f\nvar_h = 8\nvar_i = var_g % var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 124\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 24\nvar_g = var_e + var_f\nvar_h = 8\nvar_i = var_g % var_h\nprint(int(var_i))"
    },
    "1501": {
        "category": "Arithmetic calculation",
        "question_ko": "벽에 가로가 30센티미터(㎝), 세로가 20센티미터(㎝)인 포스터를 붙힌다. 포스터를 가로로 연속해서 15장을 붙히는데 2센티미터(㎝)씩 겹쳐서 붙힌다. 포스터를 모두 붙히려면 벽의 가로가 최소 몇 센티미터(㎝) 이상이어야 하는지 구하시오.",
        "question_en": "You are attaching posters measuring 30 centimeters (cm) in width and 20 centimeters (cm) in height to the wall. 15 posters are to be attached horizontally in succession, overlapping each other by 2 centimeters (cm). Find the minimum width of the wall in centimeters (cm) to attach all the posters. ",
        "answer_ko": "422",
        "answer_en": "422",
        "solution_abst_ko": "30 15 [OP_MUL] 15 1 [OP_SUB] 2 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "30 15 [OP_MUL] 15 1 [OP_SUB] 2 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 30\nvar_b = 15\nvar_c = var_a * var_b\nvar_d = 15\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_c - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 30\nvar_b = 15\nvar_c = var_a * var_b\nvar_d = 15\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_c - var_h\nprint(int(var_i))"
    },
    "1502": {
        "category": "Correspondence",
        "question_ko": "A3+31=54이 성립합니다. A는 무엇인가요?",
        "question_en": "A3+31=54 is true. What is A?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "A3+31=54 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A3+31=54 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A3+31=54'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A3+31=54'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "1503": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 125까지 수를 차례대로 적을 때, 숫자 2는 모두 몇 번 쓰는지 구하시오.",
        "question_en": "When writing numbers from 1 to 125, find out how many times all the numbers 2 are written.",
        "answer_ko": "29",
        "answer_en": "29",
        "solution_abst_ko": "1 125 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 2 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 125 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 2 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 125\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 2\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 125\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 2\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))"
    },
    "1504": {
        "category": "Arithmetic calculation",
        "question_ko": "25미터(m) 간격으로 도로 양쪽에 가로수를 심는다고 합니다. 도로의 길이는 2575미터(m)이며 처음과 끝에도 심는다고 합니다. 가로수는 총 몇 그루 필요합니까?",
        "question_en": "It is said that street trees are planted on both sides of the road at intervals of 25 meters (m). The length of the road is 2575 meters (m) and trees are also planted at the beginning and end of the road. How many trees are needed in total?",
        "answer_ko": "208",
        "answer_en": "208",
        "solution_abst_ko": "2575 25 [OP_DIV] 1 [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "2575 25 [OP_DIV] 1 [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 2575\nvar_b = 25\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 2575\nvar_b = 25\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "1505": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.3 중 0.4보다 큰 수의 개수를 구하시오.",
        "question_en": "Find the number of numbers greater than 0.4 among 0.8, 1/2, and 0.3.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.3 [OP_LIST_EOL] 0.4 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.3 [OP_LIST_EOL] 0.4 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.4\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.4\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "1506": {
        "category": "Geometry",
        "question_ko": "어떤 정육면체는 모서리가 5센티미터(㎝)이다. 이 정육면체의 모든 면 한가운데에서 모서리의 길이가 1센티미터(㎝)인 정육면체 모양을 파내려고 했는데, 실수로 하나는 깜빡하고 파내지 못했다. 이 도형의 부피는 몇 세제곱센티미터(㎤)인지 구하라.",
        "question_en": "Some cubes have edges of 5 centimeters (cm). In the middle of all the faces of this cube, I tried to dig out a cube shape with an edge length of 1 centimeter (cm), but I accidentally forgot to dig one out. Find the volume in cubic centimeters (cm3) of this shape.",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "5 3 [OP_POW] 1 3 [OP_POW] 5 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "5 3 [OP_POW] 1 3 [OP_POW] 5 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 5\nvar_b = 3\nvar_c = var_a ** var_b\nvar_d = 1\nvar_e = 3\nvar_f = var_d ** var_e\nvar_g = 5\nvar_h = var_f * var_g\nvar_i = var_c - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 5\nvar_b = 3\nvar_c = var_a ** var_b\nvar_d = 1\nvar_e = 3\nvar_f = var_d ** var_e\nvar_g = 5\nvar_h = var_f * var_g\nvar_i = var_c - var_h\nprint(int(var_i))"
    },
    "1507": {
        "category": "Geometry",
        "question_ko": "네 변의 길이의 합이 38 센티미터(㎝) 인 직사각형이 있습니다. 이 직사각형의 긴 변의 길이가 12센티미터(㎝) 이면, 짧은 변의 길이는 몇 센티미터(㎝) 입니까?",
        "question_en": "A rectangle has a sum of 4 sides equal to 38 centimeters (cm). If the long side of this rectangle is 12 centimeters (cm), how many centimeters (cm) is the short side?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "38 2 [OP_DIV] 12 [OP_SUB]",
        "solution_abst_en": "38 2 [OP_DIV] 12 [OP_SUB]",
        "solution_code_ko": "var_a = 38\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 12\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 38\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 12\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "1508": {
        "category": "Comparison",
        "question_ko": "유정이는 5, 8을 모았고, 유나는 7과 9를 모았습니다. 모은 수의 합이 큰 사람은 누구인가요?",
        "question_en": "Yoojung collected 5 and 8, and Yuna collected 7 and 9. Who has the greatest sum of numbers?",
        "answer_ko": "유나",
        "answer_en": "Yuna",
        "solution_abst_ko": "[OP_LIST_SOL] 유정 유나 [OP_LIST_EOL] [OP_LIST_SOL] 5 8 [OP_ADD] 7 9 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoojung Yuna [OP_LIST_EOL] [OP_LIST_SOL] 5 8 [OP_ADD] 7 9 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '유정'\nvar_b = '유나'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 5\nvar_d = 8\nvar_e = var_c + var_d\nvar_f = 7\nvar_g = 9\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Yoojung'\nvar_b = 'Yuna'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 5\nvar_d = 8\nvar_e = var_c + var_d\nvar_f = 7\nvar_g = 9\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "1509": {
        "category": "Geometry",
        "question_ko": "끈을 이용하여 정육면체를 만들고 정육면체의 넓이가 가장 클 때의 부피는 3375세제곱센티미터(㎤)입니다. 끈의 길이를 구하십시오.",
        "question_en": "Create a cube using string, and the volume of the cube at its largest is 3375 cubic centimeters (cm3). Find the length of the string.",
        "answer_ko": "180",
        "answer_en": "180",
        "solution_abst_ko": "3375 1/3 [OP_POW] 12 [OP_MUL]",
        "solution_abst_en": "3375 1/3 [OP_POW] 12 [OP_MUL]",
        "solution_code_ko": "var_a = 3375\nvar_b = 0.3333333333333333\nvar_c = var_a ** var_b\nvar_d = 12\nvar_e = var_c * var_d\nprint(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))",
        "solution_code_en": "var_a = 3375\nvar_b = 0.3333333333333333\nvar_c = var_a ** var_b\nvar_d = 12\nvar_e = var_c * var_d\nprint(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))"
    },
    "1510": {
        "category": "Comparison",
        "question_ko": "앞에 두 숫자가 적힌 버튼이 있습니다. 두 버튼에 적힌 숫자의 차는 480이고, 적힌 수 중 큰 수를 작은 수로 나누면 몫이 4, 나머지가 30이 나옵니다. 적혀있는 수 중 큰 수는 얼마입니까?",
        "question_en": "There are buttons with two numbers written on them. The difference between the numbers on the buttons is 480. When you divide the larger number by the smaller number, you get a quotient of 4 and a remainder of 30. Find what the larger number is.",
        "answer_ko": "630",
        "answer_en": "630",
        "solution_abst_ko": "480 30 [OP_SUB] 4 1 [OP_SUB] [OP_DIV] 4 [OP_MUL] 30 [OP_ADD]",
        "solution_abst_en": "480 30 [OP_SUB] 4 1 [OP_SUB] [OP_DIV] 4 [OP_MUL] 30 [OP_ADD]",
        "solution_code_ko": "var_a = 480\nvar_b = 30\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 4\nvar_i = var_g * var_h\nvar_j = 30\nvar_k = var_i + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 480\nvar_b = 30\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 4\nvar_i = var_g * var_h\nvar_j = 30\nvar_k = var_i + var_j\nprint(int(var_k))"
    },
    "1511": {
        "category": "Comparison",
        "question_ko": "다섯 명의 학생 윤기, 정국, 유나, 유정, 태형은 각각 7, 6, 9, 8, 10만큼의 숫자를 가지고 있습니다. 제일 작은 숫자를 가진 사람은 누구입니까?",
        "question_en": "The five students, Yoongi, Jungkook, Yuna, Yoojung, and Taehyung, each have the numbers 7, 6, 9, 8, and 10. Who has the smallest number?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 유나 유정 태형 [OP_LIST_EOL] [OP_LIST_SOL] 7 6 9 8 10 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook Yuna Yoojung Taehyung [OP_LIST_EOL] [OP_LIST_SOL] 7 6 9 8 10 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nvar_c = '유나'\nvar_d = '유정'\nvar_e = '태형'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 7\nvar_g = 6\nvar_h = 9\nvar_i = 8\nvar_j = 10\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[var_k-1]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nvar_c = 'Yuna'\nvar_d = 'Yoojung'\nvar_e = 'Taehyung'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 7\nvar_g = 6\nvar_h = 9\nvar_i = 8\nvar_j = 10\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[var_k-1]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "1512": {
        "category": "Geometry",
        "question_ko": "서희네 도시에서 제주도까지 가는 비행기 노선은 3개, 배 노선은 2개일 때, 배로 가는 경우의 수를 구하시오.",
        "question_en": "There are 3 apples and 2 persimmons in the box. How many persimmons are in the box?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "2",
        "solution_abst_en": "2",
        "solution_code_ko": "var_a = 2\nprint(int(var_a))",
        "solution_code_en": "var_a = 2\nprint(int(var_a))"
    },
    "1513": {
        "category": "Comparison",
        "question_ko": "윤기는 4, 유나는 5, 정국이는 6에서 3을 곱한 수를 모았습니다. 누가 가장 큰 수를 모았나요?",
        "question_en": "Yoongi has 4, Yuna has 5, and Jungkook has the number 6 multiplied by 3. Who got the biggest number?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 유나 정국 [OP_LIST_EOL] [OP_LIST_SOL] 4 5 6 3 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Yuna Jungkook [OP_LIST_EOL] [OP_LIST_SOL] 4 5 6 3 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '유나'\nvar_c = '정국'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 5\nvar_f = 6\nvar_g = 3\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Yuna'\nvar_c = 'Jungkook'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 5\nvar_f = 6\nvar_g = 3\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "1514": {
        "category": "Arithmetic calculation",
        "question_ko": "아침 6시부터 밤 11시까지 1시간 간격으로 기차가 서는 역의 기차 시간표에는 숫자 2가 몇 번 등장하는지 구하시오. (단, 밤 11시는 23시와 같이 표기합니다.)",
        "question_en": "Find how many times the number 2 appears on the train timetable for the station where trains stop every hour from 6:00 am to 11:00 pm. (However, 11 o'clock at night is indicated as 23 o'clock.)",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "6 23 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 2 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "6 23 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 2 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 6\nvar_b = 23\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 2\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))",
        "solution_code_en": "var_a = 6\nvar_b = 23\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 2\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))"
    },
    "1515": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 100까지의 자연수 중 5로 나누었을 때 나머지가 2인 수 중에서 세 번째로 큰 수는 얼마인지 구하시오.",
        "question_en": "Among the natural numbers from 1 to 100, what is the third largest number with a remainder of 2 when divided by 5?",
        "answer_ko": "87",
        "answer_en": "87",
        "solution_abst_ko": "1 100 1 [OP_LIST_ARANGE] 5 2 [OP_LIST_DIVIDE_AND_REMAIN] 3 [OP_LIST_MAX]",
        "solution_abst_en": "1 100 1 [OP_LIST_ARANGE] 5 2 [OP_LIST_DIVIDE_AND_REMAIN] 3 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nvar_e = 2\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nvar_e = 2\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint(int(var_g))"
    },
    "1516": {
        "category": "Correspondence",
        "question_ko": "9에 어떤 수를 곱했더니 결과가 36이 나왔습니다. 어떤 수를 정확히 구하시오.",
        "question_en": "When 9 is multiplied by a number, the result is 36. Find out the number exactly.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "36 9 [OP_DIV]",
        "solution_abst_en": "36 9 [OP_DIV]",
        "solution_code_ko": "var_a = 36\nvar_b = 9\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 36\nvar_b = 9\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "1517": {
        "category": "Geometry",
        "question_ko": "쌓기 나무를 늘어놓아 정사각형을 만들었습니다. 정사각형의 가장 바깥쪽에 놓인 쌓기 나무의 개수는 52개 이다. 가장 바깥쪽의 한 변에 놓인 쌓기 나무의 개수는 몇 개인지 구하시오.",
        "question_en": "Building blocks are laid out to form a square. The number of building blocks on the outermost sides of the square is 52. Find the number of building blocks on the outermost of one side.",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "52 4 [OP_SUB] 4 [OP_DIV] 2 [OP_ADD]",
        "solution_abst_en": "52 4 [OP_SUB] 4 [OP_DIV] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 52\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 52\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "1518": {
        "category": "Arithmetic calculation",
        "question_ko": "각 상자마다 6개의 공이 들어있으며 총 흰색 공이 30개, 빨간색 공이 18개 있다. 흰색 공이 든 상자는 빨간색 공이 든 상자보다 몇 상자 더 많습니까?",
        "question_en": "Each box contains 6 balls, and there are 30 white balls and 18 red balls. How many more boxes are there in white ball boxes than red ball boxes?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "30 6 [OP_DIV] 18 6 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "30 6 [OP_DIV] 18 6 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 30\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 18\nvar_e = 6\nvar_f = var_d / var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 30\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 18\nvar_e = 6\nvar_f = var_d / var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "1519": {
        "category": "Arithmetic calculation",
        "question_ko": "2020년 12월 29일이라는 글자를 인쇄하려고 한다. 숫자 '2'는 몇 번 인쇄되는지 구하시오.",
        "question_en": "You want to print the text '29/12/2020'. Find how many times the number '2' is printed.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 2020 12 29 [OP_LIST_EOL] [OP_LIST2NUM] [OP_NUM2LIST] 2 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "[OP_LIST_SOL] 2020 12 29 [OP_LIST_EOL] [OP_LIST2NUM] [OP_NUM2LIST] 2 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 2020\nvar_b = 12\nvar_c = 29\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 2\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))",
        "solution_code_en": "var_a = 2020\nvar_b = 12\nvar_c = 29\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 2\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))"
    },
    "1520": {
        "category": "Arithmetic calculation",
        "question_ko": "기윤이는 함께 봉사 활동에 참여하기로 한 친구 8명에게 똑같이 나누어 주기 위해 초콜릿을 몇 개 준비하였습니다. 그런데 2명이 오지 않아서 한 사람당 1개씩 더 주었더니 초콜릿이 4개 남았습니다. 기윤이가 처음에 가져온 초콜릿은 몇 개였을까요?",
        "question_en": "Giyoon prepared some chocolates to distribute equally to 8 of her friends who decided to do volunteering together. But 2 people didn't come, so she gave one more chocolate to each person, and there were 4 chocolates left. How many chocolates did Giyoon prepare?",
        "answer_ko": "40",
        "answer_en": "40",
        "solution_abst_ko": "8 2 [OP_SUB] 4 [OP_ADD] 8 8 2 [OP_SUB] [OP_SUB] [OP_FDIV] 8 [OP_MUL]",
        "solution_abst_en": "8 2 [OP_SUB] 4 [OP_ADD] 8 8 2 [OP_SUB] [OP_SUB] [OP_FDIV] 8 [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = 8\nvar_h = 2\nvar_i = var_g - var_h\nvar_j = var_f - var_i\nvar_k = var_e // var_j\nvar_l = 8\nvar_m = var_k * var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 8\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = 8\nvar_h = 2\nvar_i = var_g - var_h\nvar_j = var_f - var_i\nvar_k = var_e // var_j\nvar_l = 8\nvar_m = var_k * var_l\nprint(int(var_m))"
    },
    "1521": {
        "category": "Geometry",
        "question_ko": "작은 정사각형 모양의 종이 조각 여러개로 큰 정사각형을 만들고 보니 20개의 종이조각이 남았다. 가로 한 변과 세로 한 변을 1열씩 늘리려고 하였더니 9개의 종이 조각이 부족하였다. 종이 조각의 개수는 총 개일까?",
        "question_en": "After making a large square out of several small square-shaped pieces of paper, there were 20 pieces of paper left. When I tried to increase a horizontal side and a vertical side by one row each, nine pieces of paper were short. How many pieces of paper are there?",
        "answer_ko": "216",
        "answer_en": "216",
        "solution_abst_ko": "20 9 [OP_ADD] 1 [OP_SUB] 2 [OP_DIV] 2 [OP_POW] 20 [OP_ADD]",
        "solution_abst_en": "20 9 [OP_ADD] 1 [OP_SUB] 2 [OP_DIV] 2 [OP_POW] 20 [OP_ADD]",
        "solution_code_ko": "var_a = 20\nvar_b = 9\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 20\nvar_k = var_i + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 20\nvar_b = 9\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 20\nvar_k = var_i + var_j\nprint(int(var_k))"
    },
    "1522": {
        "category": "Comparison",
        "question_ko": "오락실에 똑같은 자판기가 28대 있습니다. 각 자판기마다 가진 음료수의 수는 같습니다. 어느 자판기에서 앞에서 14번째, 뒤에서 20번째, 위에서 3번째, 아래에서 2번째 음료수를 선택했을 때, 이 오락실 자판기들 안에 있는 음료수의 수를 모두 구하시오.",
        "question_en": "There are 28 identical vending machines in the arcade. Each vending machine has the same number of beverages. When you selected the beverage that is 14th from the front, 20th from the back, 3rd from the top and 2nd from the bottom in a vending machine, find the total number of drinks in these arcade vending machines.",
        "answer_ko": "3696",
        "answer_en": "3696",
        "solution_abst_ko": "14 20 [OP_ADD] 1 [OP_SUB] 3 2 [OP_ADD] 1 [OP_SUB] [OP_MUL] 28 [OP_MUL]",
        "solution_abst_en": "14 20 [OP_ADD] 1 [OP_SUB] 3 2 [OP_ADD] 1 [OP_SUB] [OP_MUL] 28 [OP_MUL]",
        "solution_code_ko": "var_a = 14\nvar_b = 20\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nvar_l = 28\nvar_m = var_k * var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 14\nvar_b = 20\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nvar_l = 28\nvar_m = var_k * var_l\nprint(int(var_m))"
    },
    "1523": {
        "category": "Correspondence",
        "question_ko": "7A에서 B6을 뺐더니 23이 되었습니다. A+B는 무엇인가요?",
        "question_en": "I took B6 away from 7A, and it became 23. What is A+B?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "7A-B6=23 A [OP_DIGIT_UNK_SOLVER] 7A-B6=23 B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_abst_en": "7A-B6=23 A [OP_DIGIT_UNK_SOLVER] 7A-B6=23 B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_code_ko": "var_a = '7A-B6=23'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '7A-B6=23'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = '7A-B6=23'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '7A-B6=23'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "1524": {
        "category": "Arithmetic calculation",
        "question_ko": "문방구에서 연필 16자루를 샀는데 오는길에 몇 자루를 잃어버리고 남아 있는 연필의 수를 세보니 8자루였습니다. 잃어버린 연필은 몇 자루입니까?",
        "question_en": "I bought 16 pencils at a stationery store, but I lost a few on the way back home. When I counted the number of remaining pencils, there were 8. How many pencils were lost?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "16 8 [OP_SUB]",
        "solution_abst_en": "16 8 [OP_SUB]",
        "solution_code_ko": "var_a = 16\nvar_b = 8\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 16\nvar_b = 8\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "1525": {
        "category": "Correspondence",
        "question_ko": "공항에서 가방의 무게를 달았는데 35킬로그램(㎏) 500그램(g) 이었습니다. 그 이후 가방 안에서 1킬로그램(㎏) 750그램(g)인 노트북을 꺼내고 27킬로그램(㎏) 200그램(g)의 무게인 다른 가방이 있다면 가방들의 무게의 합은 몇 킬로그램(㎏)입니까?",
        "question_en": "You weighed the bag at the airport and it was 35 kilograms (kg) and 500 grams (g). After that, if you take out a laptop weighing 1 kg (kg) and 750 grams (g) from the bag and there is another bag weighing 27 kilograms (kg) and 200 grams (g), what is the total weight of the bags in kilograms (kg)?",
        "answer_ko": "60.95",
        "answer_en": "60.95",
        "solution_abst_ko": "35 500 1000 [OP_DIV] [OP_ADD] 1 750 1000 [OP_DIV] [OP_ADD] [OP_SUB] 27 200 1000 [OP_DIV] [OP_ADD] [OP_ADD]",
        "solution_abst_en": "35 500 1000 [OP_DIV] [OP_ADD] 1 750 1000 [OP_DIV] [OP_ADD] [OP_SUB] 27 200 1000 [OP_DIV] [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 35\nvar_b = 500\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 1\nvar_g = 750\nvar_h = 1000\nvar_i = var_g / var_h\nvar_j = var_f + var_i\nvar_k = var_e - var_j\nvar_l = 27\nvar_m = 200\nvar_n = 1000\nvar_o = var_m / var_n\nvar_p = var_l + var_o\nvar_q = var_k + var_p\nprint('{:.2f}'.format(round(var_q+1e-10,2)))",
        "solution_code_en": "var_a = 35\nvar_b = 500\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 1\nvar_g = 750\nvar_h = 1000\nvar_i = var_g / var_h\nvar_j = var_f + var_i\nvar_k = var_e - var_j\nvar_l = 27\nvar_m = 200\nvar_n = 1000\nvar_o = var_m / var_n\nvar_p = var_l + var_o\nvar_q = var_k + var_p\nprint('{:.2f}'.format(round(var_q+1e-10,2)))"
    },
    "1526": {
        "category": "Arithmetic calculation",
        "question_ko": "네 자리 수 중 5, 6, 2의 공배수인 수는 모두 몇 개 입니까?",
        "question_en": "How many four-digit numbers are the common multiples of 5, 6, and 2?",
        "answer_ko": "300",
        "answer_en": "300",
        "solution_abst_ko": "1000 9999 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] 6 [OP_LIST_DIVISIBLE] 2 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "1000 9999 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] 6 [OP_LIST_DIVISIBLE] 2 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 6\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 2\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 6\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 2\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))"
    },
    "1527": {
        "category": "Arithmetic calculation",
        "question_ko": "축구공이 12개씩 담겨있는 상자가 8개 있고 농구공이 12개씩 담겨있는 상자는 5개 있습니다. 농구공은 축구공보다 몇 개 더 적습니까?",
        "question_en": "If there are 8 boxes of 12 soccer balls and 5 boxes of 12 basketballs, how many basketballs are fewer than soccer balls?",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "12 8 [OP_MUL] 12 5 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "12 8 [OP_MUL] 12 5 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 12\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 12\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "1528": {
        "category": "Correspondence",
        "question_ko": "A, B는 한 자리 수입니다. A15B94가 99로 나누어 떨어질 때, B에 알맞은 값을 구하시오.",
        "question_en": "A and B are single digit numbers. When A15B94 is divisible by 99, find the appropriate value for B.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "A15B94 [OP_GEN_POSSIBLE_LIST] 99 [OP_LIST_DIVISIBLE] A15B94 B [OP_LIST_FIND_UNK]",
        "solution_abst_en": "A15B94 [OP_GEN_POSSIBLE_LIST] 99 [OP_LIST_DIVISIBLE] A15B94 B [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = 'A15B94'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 99\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 'A15B94'\nvar_d = 'B'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nvar_e = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_e = int(elem[unk_idx])\nprint(int(var_e))",
        "solution_code_en": "var_a = 'A15B94'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 99\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 'A15B94'\nvar_d = 'B'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nvar_e = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_e = int(elem[unk_idx])\nprint(int(var_e))"
    },
    "1529": {
        "category": "Arithmetic calculation",
        "question_ko": "몇 명의 학생들에게 공책을 나누어 주려고 한다. 한 학생에게 4권씩 나누어 주면 3권이 남고, 5권씩 나누어 주면 6권이 부족하다고 할 때, 공책의 수를 구하시오.",
        "question_en": "You are going to hand out notebooks to a few students. If you give each student 4 notebooks, 3 notebooks will be left, and if you give each student 5 notebooks, 6 noteboks will be in short. Find the number of notebooks.",
        "answer_ko": "39",
        "answer_en": "39",
        "solution_abst_ko": "3 6 [OP_ADD] 5 4 [OP_SUB] [OP_DIV] 4 [OP_MUL] 3 [OP_ADD]",
        "solution_abst_en": "3 6 [OP_ADD] 5 4 [OP_SUB] [OP_DIV] 4 [OP_MUL] 3 [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = 4\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 4\nvar_i = var_g * var_h\nvar_j = 3\nvar_k = var_i + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 3\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = 4\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 4\nvar_i = var_g * var_h\nvar_j = 3\nvar_k = var_i + var_j\nprint(int(var_k))"
    },
    "1530": {
        "category": "Arithmetic calculation",
        "question_ko": "사과와 배가 모두 85개 있습니다. 사과가 48개일 때 사과는 배보다 몇 개 더 많습니까?",
        "question_en": "There are 85 apples and pears in total. How many more apples are there than pears when there are 48 apples?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "48 85 48 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "48 85 48 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 48\nvar_b = 85\nvar_c = 48\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 48\nvar_b = 85\nvar_c = 48\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "1531": {
        "category": "Possibility",
        "question_ko": "A, B, C, D, E, F 6명을 한 줄로 세울 때, A, B를 서로 이웃하게 하여 세우는 경우의 수를 구하시오.",
        "question_en": "Find the number of cases to put A and B next to each other in a situation where 6 people A, B, C, D, E, and F are lined up in a line.",
        "answer_ko": "240",
        "answer_en": "240",
        "solution_abst_ko": "[OP_LIST_SOL] A B C D E F [OP_LIST_EOL] [OP_LIST_SOL] A [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D E F [OP_LIST_EOL] [OP_LIST_SOL] A [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nvar_f = 'F'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 'A'\nlist_b= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_h = len(list_c)\nvar_i = len(list_c)\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nvar_k = 'A'\nvar_l = 'B'\nlist_d= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_d.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_d.append(var_k)\nlist_d.reverse()\nvar_m = len(list_d)\nvar_n = len(list_d)\nvar_o = 1\nvar_m = int(var_m)\nvar_n = int(var_n)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o * (var_m-i)\nvar_p = var_j * var_o\nprint(int(var_p))",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nvar_f = 'F'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 'A'\nlist_b= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_h = len(list_c)\nvar_i = len(list_c)\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nvar_k = 'A'\nvar_l = 'B'\nlist_d= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_d.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_d.append(var_k)\nlist_d.reverse()\nvar_m = len(list_d)\nvar_n = len(list_d)\nvar_o = 1\nvar_m = int(var_m)\nvar_n = int(var_n)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o * (var_m-i)\nvar_p = var_j * var_o\nprint(int(var_p))"
    },
    "1532": {
        "category": "Comparison",
        "question_ko": "유정은 책상 위에 색색의 공을 일렬로 늘어놓았다. 빨간색, 파란색, 노란색, 보라색, 흰색 공을 순서대로 놓았을 때 마지막 공은 무슨 색입니까?",
        "question_en": "Yujeong arranged colored balls in a row on the desk in the following order: red, blue, yellow, purple, and white. What color comes last?",
        "answer_ko": "흰색",
        "answer_en": "white",
        "solution_abst_ko": "[OP_LIST_SOL] 빨간색 파란색 노란색 보라색 흰색 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] red blue yellow purple white [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '빨간색'\nvar_b = '파란색'\nvar_c = '노란색'\nvar_d = '보라색'\nvar_e = '흰색'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = list_a[var_f-1]\nprint(var_g)",
        "solution_code_en": "var_a = 'red'\nvar_b = 'blue'\nvar_c = 'yellow'\nvar_d = 'purple'\nvar_e = 'white'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = list_a[var_f-1]\nprint(var_g)"
    },
    "1533": {
        "category": "Possibility",
        "question_ko": "모든 자리 수의 합이 35인 네 자리 수는 모두 몇 개입니까?",
        "question_en": "How many 4-digit numbers are there where the sum of all digits is 35?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "1000 10000 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] 35 [OP_LIST_MORE_EQUAL] 35 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "1000 10000 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] 35 [OP_LIST_MORE_EQUAL] 35 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1000\nvar_b = 10000\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nlist_b=[]\nfor i in list_a:\n    var_f = 0\n    i = int(i)\n    while i//10 > 0:\n        var_f = var_f + i%10\n        i = i//10\n    var_f = var_f + i%10\n    list_b.append(var_f)\nvar_g = 35\nlist_c = []\nfor i in list_b:\n    if i >= var_g:\n        list_c.append(i)\nvar_h = 35\nlist_d = []\nfor i in list_c:\n    if i <= var_h:\n        list_d.append(i)\nvar_i = len(list_d)\nprint(int(var_i))",
        "solution_code_en": "var_a = 1000\nvar_b = 10000\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nlist_b=[]\nfor i in list_a:\n    var_f = 0\n    i = int(i)\n    while i//10 > 0:\n        var_f = var_f + i%10\n        i = i//10\n    var_f = var_f + i%10\n    list_b.append(var_f)\nvar_g = 35\nlist_c = []\nfor i in list_b:\n    if i >= var_g:\n        list_c.append(i)\nvar_h = 35\nlist_d = []\nfor i in list_c:\n    if i <= var_h:\n        list_d.append(i)\nvar_i = len(list_d)\nprint(int(var_i))"
    },
    "1534": {
        "category": "Possibility",
        "question_ko": "0, 1, 5가 적힌 과자 중 2가지를 뽑아 만들 수 있는 두 자리 수는 모두 몇 개인가?",
        "question_en": "How many 2-digit numbers can you make by selecting 2 of the cookies numbered 0, 1, and 5?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "1535": {
        "category": "Correspondence",
        "question_ko": "46을 어떤 수에서 뺐더니 결과로 15를 얻었습니다. 29를 어떤 수에서 빼면 얼마일까요?",
        "question_en": "Subtracting 46 from a number gives 15 as a result. What would be the result if 29 is subtracted from this number?",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "15 46 [OP_ADD] 29 [OP_SUB]",
        "solution_abst_en": "15 46 [OP_ADD] 29 [OP_SUB]",
        "solution_code_ko": "var_a = 15\nvar_b = 46\nvar_c = var_a + var_b\nvar_d = 29\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 46\nvar_c = var_a + var_b\nvar_d = 29\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "1536": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 2로 나눈 값을 다시 2로 나눈 값이 85에 45를 더한 값과 같다고 한다. 어떤 수에서 45를 뺀 값을 구하시오.",
        "question_en": "A number divided by 2 and dividing it by 2 again equals 85 plus 45. What is the value of subtracting 45 from the number?",
        "answer_ko": "475",
        "answer_en": "475",
        "solution_abst_ko": "85 45 [OP_ADD] 2 [OP_MUL] 2 [OP_MUL] 45 [OP_SUB]",
        "solution_abst_en": "85 45 [OP_ADD] 2 [OP_MUL] 2 [OP_MUL] 45 [OP_SUB]",
        "solution_code_ko": "var_a = 85\nvar_b = 45\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = 45\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 85\nvar_b = 45\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = 45\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "1537": {
        "category": "Comparison",
        "question_ko": "여러 명의 아이들이 동그랗게 앉아 있습니다. 어떤 아이는 그 아이로부터 시계 방향으로 15번째에 있는 아이와 마주보고 있습니다. 앉아있는 아이들의 숫자를 구하시오.",
        "question_en": "Several children are sitting in a circle. A child is facing the fifteenth child sitting clockwise from that child. Find the number of children sitting.",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "15 1 [OP_SUB] 2 [OP_MUL] 2 [OP_ADD]",
        "solution_abst_en": "15 1 [OP_SUB] 2 [OP_MUL] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 15\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 15\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "1538": {
        "category": "Arithmetic calculation",
        "question_ko": "2개의 수 3, 5로 나누어 떨어질 수 있는 수 중 가장 작은 두 자리 수는?",
        "question_en": "What is the smallest two-digit number divisible by two numbers, 3 and 5?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "10 99 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "10 99 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[var_f-1]\nprint(int(var_g))"
    },
    "1539": {
        "category": "Comparison",
        "question_ko": "2개의 숫자 0.8, 1/2가 있습니다. 3보다 작은 수는 몇 개입니까?",
        "question_en": "There are two numbers 0.8, 1/2. How many numbers are less than 3?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 [OP_LIST_EOL] 3 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 [OP_LIST_EOL] 3 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nlist_b = []\nfor i in list_a:\n    if i < var_c:\n        list_b.append(i)\nvar_d = len(list_b)\nprint(int(var_d))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nlist_b = []\nfor i in list_a:\n    if i < var_c:\n        list_b.append(i)\nvar_d = len(list_b)\nprint(int(var_d))"
    },
    "1540": {
        "category": "Possibility",
        "question_ko": "학생들을 2그룹으로 나누려고 합니다. 정국, 지민, 윤기, 유나를 나누는 경우는 모두 몇 가지입니까? 각 그룹에 포함된 학생 수는 같습니다.",
        "question_en": "We are going to divide the students into 2 groups. How many ways are there to divide Jungkook, Jimin, Yoongi, and Yuna? The number of students in each group is the same.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 지민 윤기 유나 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Jimin Yoongi Yuna [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '지민'\nvar_c = '윤기'\nvar_d = '유나'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g / (i+1)\nprint(int(var_g))",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Jimin'\nvar_c = 'Yoongi'\nvar_d = 'Yuna'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g / (i+1)\nprint(int(var_g))"
    },
    "1541": {
        "category": "Comparison",
        "question_ko": "19개의 장난감이 한 줄로 놓여있을 때, 오른쪽에서 8번째에 (가) 장난감이 놓여있다면 왼쪽에서는 몇 번 째입니까?",
        "question_en": "When 19 toys are placed in a row, if the toy (A) is placed 8th from the right, in which place is toy (A) placed from the left?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "19 8 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "19 8 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 19\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 19\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "1542": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 8을 곱해야 할 것을 잘못하여 63을 뺀 결과는 8이 되었습니다. 바르게 계산한 결과는 얼마인가요?",
        "question_en": "You made the mistake of subtracting 63 instead of multiplying a number by 8, and got 8. What is the correct calculation result?",
        "answer_ko": "568",
        "answer_en": "568",
        "solution_abst_ko": "8 63 [OP_ADD] 8 [OP_MUL]",
        "solution_abst_en": "8 63 [OP_ADD] 8 [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 63\nvar_c = var_a + var_b\nvar_d = 8\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 63\nvar_c = var_a + var_b\nvar_d = 8\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "1543": {
        "category": "Arithmetic calculation",
        "question_ko": "칩을 10줄 쌓았습니다. 그중 9줄에는 8개씩 쌓았고, 나머지 1줄에는 4개씩 쌓았습니다. 칩은 모두 몇 개입니까?",
        "question_en": "I stacked 10 rows of chips. 9 rows are stacked 8 each, and the other 1 row is stacked 4 each. How many chips are there in total?",
        "answer_ko": "76",
        "answer_en": "76",
        "solution_abst_ko": "9 8 [OP_MUL] 1 4 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "9 8 [OP_MUL] 1 4 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 9\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 4\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 9\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 4\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "1544": {
        "category": "Comparison",
        "question_ko": "지민이네 반 학생은 32명이고 각각의 키가 다릅니다. 이 학생들을 키가 작은 학생부터 순서대로 줄을 세우면 지민이는 앞에서 11번째에 서고, 유나는 앞에서 27번째에 섭니다. 지민이와 유나 사이에 서 있는 학생은 몇 명입니까?",
        "question_en": "There are 32 students in Jimin's class, and each has a different height. If you line up these students in order from shortest to tallest, Jimin will be 11th from the front and Yuna will be 27th from the front. How many students are standing between Jimin and Yuna?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "27 11 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "27 11 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 27\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 27\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "1545": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 8센티미터(㎝)인 정사각형 모양의 종이들을 몇 개 모았습니다. 이 종이들을 한 변의 길이가 72센티미터(㎝)인 정사각형 모양의 통에 겹치지 않도록 최대한 많이 넣는다면, 몇 개까지 넣을 수 있습니까?",
        "question_en": "You gathered several pieces of paper in the shape of an square with a side length of 8 centimeters (cm). If you put as many of these papers as possible without overlapping them in a 72 centimeters (cm) square bin, how many can you fit?",
        "answer_ko": "81",
        "answer_en": "81",
        "solution_abst_ko": "72 8 [OP_DIV] 72 8 [OP_DIV] [OP_MUL]",
        "solution_abst_en": "72 8 [OP_DIV] 72 8 [OP_DIV] [OP_MUL]",
        "solution_code_ko": "var_a = 72\nvar_b = 8\nvar_c = var_a / var_b\nvar_d = 72\nvar_e = 8\nvar_f = var_d / var_e\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 72\nvar_b = 8\nvar_c = var_a / var_b\nvar_d = 72\nvar_e = 8\nvar_f = var_d / var_e\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "1546": {
        "category": "Correspondence",
        "question_ko": "등식 A85-B1=364이 성립한다고 합니다. B에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "The equation A85-B1=364 makes. What number should go in B?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "A85-B1=364 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A85-B1=364 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A85-B1=364'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A85-B1=364'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "1547": {
        "category": "Possibility",
        "question_ko": "3, 4, 5의 숫자가 각각 적힌 3개의 깃발 중 2개를 뽑아서 만들 수 있는 두 자리 정수의 개수는?",
        "question_en": "How many two-digit integers can be formed by drawing two of the three flags with the numbers 3, 4, and 5 on them?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 3 4 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 3 4 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 3\nvar_b = 4\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 3\nvar_b = 4\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "1548": {
        "category": "Correspondence",
        "question_ko": "AB40C는 다섯 자리 수이면서 45의 배수입니다. AB40C가 될 수 있는 수의 개수를 구하시오.",
        "question_en": "AB40C is a five-digit number and a multiple of 45. Find the number of numbers that can be AB40C.",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "AB40C [OP_GEN_POSSIBLE_LIST] 45 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "AB40C [OP_GEN_POSSIBLE_LIST] 45 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 'AB40C'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 45\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))",
        "solution_code_en": "var_a = 'AB40C'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 45\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))"
    },
    "1549": {
        "category": "Correspondence",
        "question_ko": "A78-21B=364일 때, B에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "If A78-21B=364, what number should go in B?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "A78-21B=364 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A78-21B=364 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A78-21B=364'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A78-21B=364'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "1550": {
        "category": "Correspondence",
        "question_ko": "A3+61B=695입니다. B는 얼마인가요?",
        "question_en": "A3+61B=695. What is B?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "A3+61B=695 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A3+61B=695 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A3+61B=695'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A3+61B=695'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "1551": {
        "category": "Correspondence",
        "question_ko": "A를 B로 나누면 몫이 C가 되고, 나머지가 3이 됩니다. A, B, C는 자연수 입니다. B와 C가 같을 때, 가능한 A 중 가장 작은 수는 무엇인가요?",
        "question_en": "When A is divided by B, the quotient is C and the remainder is 3. A, B, and C are natural numbers. If B and C are equal, what is the smallest possible number of A?",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "3 1 [OP_ADD] 2 [OP_POW] 3 [OP_ADD]",
        "solution_abst_en": "3 1 [OP_ADD] 2 [OP_POW] 3 [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 3\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 3\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 3\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "1552": {
        "category": "Geometry",
        "question_ko": "어떤 직육면체의 모든 모서리의 길이의 합은 100센티미터(㎝)이고, 밑면의 세로 길이와 가로 길이는 각각 높이의 2배입니다. 이 직육면체의 겉넓이는 몇 제곱센티미터(㎠)입니까?",
        "question_en": "The sum of the lengths of all the edges of a cuboid is 100 centimeters (cm), and the length and width of the base are twice the height each. What is the surface area of this cuboid in square centimeters (cm2)?",
        "answer_ko": "400",
        "answer_en": "400",
        "solution_abst_ko": "100 4 [OP_DIV] 2 2 [OP_ADD] 1 [OP_ADD] [OP_DIV] 2 [OP_POW] 2 2 [OP_MUL] 2 [OP_MUL] 1 2 [OP_MUL] 2 [OP_MUL] 1 2 [OP_MUL] 2 [OP_MUL] [OP_ADD] [OP_ADD] [OP_MUL]",
        "solution_abst_en": "100 4 [OP_DIV] 2 2 [OP_ADD] 1 [OP_ADD] [OP_DIV] 2 [OP_POW] 2 2 [OP_MUL] 2 [OP_MUL] 1 2 [OP_MUL] 2 [OP_MUL] 1 2 [OP_MUL] 2 [OP_MUL] [OP_ADD] [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 100\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = 2\nvar_f = var_d + var_e\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = var_c / var_h\nvar_j = 2\nvar_k = var_i ** var_j\nvar_l = 2\nvar_m = 2\nvar_n = var_l * var_m\nvar_o = 2\nvar_p = var_n * var_o\nvar_q = 1\nvar_r = 2\nvar_s = var_q * var_r\nvar_t = 2\nvar_u = var_s * var_t\nvar_v = 1\nvar_w = 2\nvar_x = var_v * var_w\nvar_y = 2\nvar_z = var_x * var_y\nvar_A = var_u + var_z\nvar_B = var_p + var_A\nvar_C = var_k * var_B\nprint(int(var_C))",
        "solution_code_en": "var_a = 100\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = 2\nvar_f = var_d + var_e\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = var_c / var_h\nvar_j = 2\nvar_k = var_i ** var_j\nvar_l = 2\nvar_m = 2\nvar_n = var_l * var_m\nvar_o = 2\nvar_p = var_n * var_o\nvar_q = 1\nvar_r = 2\nvar_s = var_q * var_r\nvar_t = 2\nvar_u = var_s * var_t\nvar_v = 1\nvar_w = 2\nvar_x = var_v * var_w\nvar_y = 2\nvar_z = var_x * var_y\nvar_A = var_u + var_z\nvar_B = var_p + var_A\nvar_C = var_k * var_B\nprint(int(var_C))"
    },
    "1553": {
        "category": "Arithmetic calculation",
        "question_ko": "10미터(m) 간격으로 도로의 한쪽에 10그루의 나무가 심어져있습니다. 도로의 양끝에도 나무가 심어져있다면 도로의 길이는 몇 미터(m)인지 구해 보시오.",
        "question_en": "Ten trees are planted on one side of the road at intervals of 10 meters (m). If trees are planted at both ends of the road, find the length in meters (m) of the road.",
        "answer_ko": "90",
        "answer_en": "90",
        "solution_abst_ko": "10 1 [OP_SUB] 10 [OP_MUL]",
        "solution_abst_en": "10 1 [OP_SUB] 10 [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 10\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 10\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "1554": {
        "category": "Comparison",
        "question_ko": "한 변의 길이가 6센티미터(㎝)인 정육각형과 한 변의 길이가 7센티미터(㎝)인 정오각형 중에서 둘레의 길이가 더 긴 도형은 어느 것입니까?",
        "question_en": "Which shape has a longer perimeter, a regular-hexagon with a side length of 6 centimeters (cm) or a regular-pentagon with a side length of 7 centimeters (cm)?",
        "answer_ko": "정육각형",
        "answer_en": "regular-hexagon",
        "solution_abst_ko": "[OP_LIST_SOL] 정육각형 정오각형 [OP_LIST_EOL] [OP_LIST_SOL] 6 6 [OP_MUL] 7 5 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] regular-hexagon regular-pentagon [OP_LIST_EOL] [OP_LIST_SOL] 6 6 [OP_MUL] 7 5 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정육각형'\nvar_b = '정오각형'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 6\nvar_e = var_c * var_d\nvar_f = 7\nvar_g = 5\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'regular-hexagon'\nvar_b = 'regular-pentagon'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 6\nvar_e = var_c * var_d\nvar_f = 7\nvar_g = 5\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "1555": {
        "category": "Geometry",
        "question_ko": "어떤 직사각형 모양의 꽃밭의 세로가 4미터(m)이며 넓이가 143.2제곱미터(㎡)입니다. 이 때, 꽃밭의 가로는 몇 미터(m)입니까?",
        "question_en": "A rectangular flower bed is 4 meters (m) long and has an area of 143.2 square meters (m2). At this time, how many meters (m) is the width of the flower field?",
        "answer_ko": "35.80",
        "answer_en": "35.8",
        "solution_abst_ko": "143.2 4 [OP_DIV]",
        "solution_abst_en": "143.2 4 [OP_DIV]",
        "solution_code_ko": "var_a = 143.2\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 143.2\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "1556": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 10, 11, 12, 13이 있습니다. 그 중에서 3번째로 작은 수와 2번째로 작은 수의 합은 얼마입니까?",
        "question_en": "There are four numbers: 10, 11, 12, and 13. What is the sum of the third smallest and second smallest numbers?",
        "answer_ko": "23",
        "answer_en": "23",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 3 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 3 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))"
    },
    "1557": {
        "category": "Geometry",
        "question_ko": "정육면체의 모든 모서리 길이를 더하면 72센티미터(㎝)입니다. 이 정육면체에서 서로 맞닿아 있는 면 두개를 선택했을 때 경계를 이루는 선분의 길이는 몇 센티미터(㎝)일지 구하시오.",
        "question_en": "The sum of the lengths of all the edges of the cube equals 72 centimeters (cm). If you select two faces of this cube that touch each other, find the length in centimeters (cm) of the line segment that forms the boundary.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "72 4 3 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "72 4 3 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 72\nvar_b = 4\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 72\nvar_b = 4\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "1558": {
        "category": "Correspondence",
        "question_ko": "진용이는 수학시험을 보다가 9/4를 나누어야 하는 문제를 잘못보고 9/4를 곱하여 18/5를 답으로 제출하였다. 진용이가 잘못 푼 문제의 정답은 얼마인가?",
        "question_en": "While taking a math test, Jinyong misunderstood the question that required division by 9/4 as multiplied by 9/4, and submitted 18/5 as the answer. What is the correct answer to the problem that Jinyong solved incorrectly?",
        "answer_ko": "0.71",
        "answer_en": "0.71",
        "solution_abst_ko": "18/5 9/4 [OP_DIV] 9/4 [OP_DIV]",
        "solution_abst_en": "18/5 9/4 [OP_DIV] 9/4 [OP_DIV]",
        "solution_code_ko": "var_a = 3.6\nvar_b = 2.25\nvar_c = var_a / var_b\nvar_d = 2.25\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 3.6\nvar_b = 2.25\nvar_c = var_a / var_b\nvar_d = 2.25\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "1559": {
        "category": "Comparison",
        "question_ko": "5가지 숫자 1.4, 9/10, 1.2, 0.5, 13/10 중에서 1.1보다 작은 수는 몇 개 인가요?",
        "question_en": "Of the five numbers 1.4, 9/10, 1.2, 0.5, and 13/10, how many are less than 1.1?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i < var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i < var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "1560": {
        "category": "Arithmetic calculation",
        "question_ko": "호윤이는 구슬 여러개를 나누어 담으려고 합니다. 호윤이가 가진 구슬을 12개씩 주머니에 나눠 담으면 55개의 주머니가 나옵니다. 이 구슬을 15개씩 담으면 주머니는 모두 몇 개가 될까요?",
        "question_en": "Ho-yun is trying to divide marbles into several pieces. Dividing Hoyun's marbles into pockets 12 each, leaves 55 pockets. How many pockets will there be if you put 15 marbles in each?",
        "answer_ko": "44",
        "answer_en": "44",
        "solution_abst_ko": "12 55 [OP_MUL] 15 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "12 55 [OP_MUL] 15 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 12\nvar_b = 55\nvar_c = var_a * var_b\nvar_d = 15\nvar_e = var_c / var_d\nvar_f = 1\nvar_g=int(((var_e+9*10**(var_f-2))//(10**(var_f-1)))*10**(var_f-1))\n\nprint(int(var_g))",
        "solution_code_en": "var_a = 12\nvar_b = 55\nvar_c = var_a * var_b\nvar_d = 15\nvar_e = var_c / var_d\nvar_f = 1\nvar_g=int(((var_e+9*10**(var_f-2))//(10**(var_f-1)))*10**(var_f-1))\n\nprint(int(var_g))"
    },
    "1561": {
        "category": "Possibility",
        "question_ko": "남준, 윤기, 호석, 민영이 중에서 3명을 뽑아 한 줄로 세우는 경우의 수를 구하시오.",
        "question_en": "Find the number of ways to draw 3 people among Namjoon, Yoongi, Hoseok, and Minyoung and put them in a line.",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "[OP_LIST_SOL] 남준 윤기 호석 민영 [OP_LIST_EOL] [OP_LIST_LEN] 3 [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] Namjoon Yoongi Hoseok Minyoung [OP_LIST_EOL] [OP_LIST_LEN] 3 [OP_PERM]",
        "solution_code_ko": "var_a = '남준'\nvar_b = '윤기'\nvar_c = '호석'\nvar_d = '민영'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 3\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nprint(int(var_g))",
        "solution_code_en": "var_a = 'Namjoon'\nvar_b = 'Yoongi'\nvar_c = 'Hoseok'\nvar_d = 'Minyoung'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 3\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nprint(int(var_g))"
    },
    "1562": {
        "category": "Correspondence",
        "question_ko": "6을 어떤 수에 나누어 줘야 할 것을 잘못하여 7을 어떤 수에 곱한 결과는 126이 나옵니다. 바르게 계산하면 얼마인가요?",
        "question_en": "You had to divide a number by 6 but instead multiplied by 7 to get 126. What is the correctly calculated value?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "126 7 [OP_DIV] 6 [OP_DIV]",
        "solution_abst_en": "126 7 [OP_DIV] 6 [OP_DIV]",
        "solution_code_ko": "var_a = 126\nvar_b = 7\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 126\nvar_b = 7\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "1563": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 8.8 센티미터(㎝) 인 색 테이프를 0.5 센티미터(㎝) 씩 겹치게 이었더니 이은 색 테이프의 전체 길이가 282.7 센티미터(㎝) 였습니다. 이은 색 테이프는 모두 몇 장입니까?",
        "question_en": "When the length of 8.8 centimeters (cm) of colored tape was overlapped by 0.5 centimeters (cm), the total length of the connected colored tape was 282.7 centimeters (cm). How many pieces of colored tape are there in total?",
        "answer_ko": "34",
        "answer_en": "34",
        "solution_abst_ko": "282.7 8.8 [OP_SUB] 8.8 0.5 [OP_SUB] [OP_DIV] 1 [OP_ADD]",
        "solution_abst_en": "282.7 8.8 [OP_SUB] 8.8 0.5 [OP_SUB] [OP_DIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 282.7\nvar_b = 8.8\nvar_c = var_a - var_b\nvar_d = 8.8\nvar_e = 0.5\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 1\nvar_i = var_g + var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))",
        "solution_code_en": "var_a = 282.7\nvar_b = 8.8\nvar_c = var_a - var_b\nvar_d = 8.8\nvar_e = 0.5\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 1\nvar_i = var_g + var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))"
    },
    "1564": {
        "category": "Geometry",
        "question_ko": "서희네 집에서 학교까지 가는 버스 노선은 3개, 지하철 노선은 2개, 기차 노선은 4개일 때 지하철로 가는 경우의 수를 구하시오.",
        "question_en": "If there are 3 airplane routes and 2 boat routes from Seohee’s city to Jeju Island, find the number of ways to go by boat.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "2",
        "solution_abst_en": "2",
        "solution_code_ko": "var_a = 2\nprint(int(var_a))",
        "solution_code_en": "var_a = 2\nprint(int(var_a))"
    },
    "1565": {
        "category": "Geometry",
        "question_ko": "어떤 정육면체는 한 모서리의 길이가 1미터(m)이고, 어떤 직육면체는 가로가 50센티미터(㎝), 세로가 50센티미터(㎝), 높이가 20센티미터(㎝)입니다. 이 정육면체는 직육면체 부피의 몇 배입니까?",
        "question_en": "A cube is 1 meter (m) long on one side, and a cuboid is 50 centimeters (cm) wide, 50 centimeters (cm) long, and 20 centimeters (cm) high. How many times the volume of this cube is the cuboid?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "1 100 [OP_MUL] 3 [OP_POW] 50 50 [OP_MUL] 20 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "1 100 [OP_MUL] 3 [OP_POW] 50 50 [OP_MUL] 20 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c ** var_d\nvar_f = 50\nvar_g = 50\nvar_h = var_f * var_g\nvar_i = 20\nvar_j = var_h * var_i\nvar_k = var_e / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 1\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c ** var_d\nvar_f = 50\nvar_g = 50\nvar_h = var_f * var_g\nvar_i = 20\nvar_j = var_h * var_i\nvar_k = var_e / var_j\nprint(int(var_k))"
    },
    "1566": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 39를 뺐더니 54가 되었습니다. 어떤 수를 3으로 나눈 값을 구하시오.",
        "question_en": "Subtracting 39 from a number gives 54. Find the value of this number divided by 3.",
        "answer_ko": "31",
        "answer_en": "31",
        "solution_abst_ko": "39 54 [OP_ADD] 3 [OP_DIV]",
        "solution_abst_en": "39 54 [OP_ADD] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 39\nvar_b = 54\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 39\nvar_b = 54\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "1567": {
        "category": "Possibility",
        "question_ko": "서로 다른 숫자가 쓰인 숫자 카드 5장을 한 번씩 사용하여 만의 자리 수가 6, 천의 자리 수가 3, 백의 자리 수가 9이면서 99의 배수인 다섯 자리 수를 만들었다. 보이지 않는 2장의 카드에 알맞은 숫자를 찾아 다섯 자리 수를 구하여라.",
        "question_en": "Five number cards with different digits were used each time to create a five-digit number that is a multiple of 99, with 6 in the ten thousands digit, 3 in the thousands digit, and 9 in the hundreds digit. Find the correct number on the two invisible cards and get the five digit number.",
        "answer_ko": "63954",
        "answer_en": "63954",
        "solution_abst_ko": "0 9 1 [OP_LIST_ARANGE] 5 [OP_LIST_GET_PERM] 10000 6 [OP_LIST_SEARCH_FIXED_DIGIT] 1000 3 [OP_LIST_SEARCH_FIXED_DIGIT] 100 9 [OP_LIST_SEARCH_FIXED_DIGIT] 99 [OP_LIST_DIVISIBLE] 1 [OP_LIST_GET]",
        "solution_abst_en": "0 9 1 [OP_LIST_ARANGE] 5 [OP_LIST_GET_PERM] 10000 6 [OP_LIST_SEARCH_FIXED_DIGIT] 1000 3 [OP_LIST_SEARCH_FIXED_DIGIT] 100 9 [OP_LIST_SEARCH_FIXED_DIGIT] 99 [OP_LIST_DIVISIBLE] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 0\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 10000\nvar_f = 6\nlist_c = [] \nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if (i//var_e)%10 == var_f:\n        list_c.append(i)\nvar_g = 1000\nvar_h = 3\nlist_d = [] \nvar_g = int(var_g)\nvar_h = int(var_h)\nfor i in list_c:\n    i = int(i)\n    if (i//var_g)%10 == var_h:\n        list_d.append(i)\nvar_i = 100\nvar_j = 9\nlist_e = [] \nvar_i = int(var_i)\nvar_j = int(var_j)\nfor i in list_d:\n    i = int(i)\n    if (i//var_i)%10 == var_j:\n        list_e.append(i)\nvar_k = 99\nlist_f = []\nvar_k = int(var_k)\nfor i in list_e:\n    i = int(i)\n    if i % var_k == 0:\n        list_f.append(i)\nvar_l = 1\nvar_m = list_f[var_l-1]\nprint(int(var_m))",
        "solution_code_en": "var_a = 0\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 10000\nvar_f = 6\nlist_c = [] \nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if (i//var_e)%10 == var_f:\n        list_c.append(i)\nvar_g = 1000\nvar_h = 3\nlist_d = [] \nvar_g = int(var_g)\nvar_h = int(var_h)\nfor i in list_c:\n    i = int(i)\n    if (i//var_g)%10 == var_h:\n        list_d.append(i)\nvar_i = 100\nvar_j = 9\nlist_e = [] \nvar_i = int(var_i)\nvar_j = int(var_j)\nfor i in list_d:\n    i = int(i)\n    if (i//var_i)%10 == var_j:\n        list_e.append(i)\nvar_k = 99\nlist_f = []\nvar_k = int(var_k)\nfor i in list_e:\n    i = int(i)\n    if i % var_k == 0:\n        list_f.append(i)\nvar_l = 1\nvar_m = list_f[var_l-1]\nprint(int(var_m))"
    },
    "1568": {
        "category": "Possibility",
        "question_ko": "1, 7, 9 가 적힌 카드 중 두 장을 뽑아 10 이상 100이하의 수를 만들 때, 만들 수 있는 경우는 모두 몇 가지입니까?",
        "question_en": "How many cases can you make a number that is 10 or more and 100 or less by selecting two cards from 1, 7, and 9?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 1 7 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 7 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 7\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 7\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "1569": {
        "category": "Correspondence",
        "question_ko": "A, B, C는 0에서 9까지의 서로 다른 숫자입니다. 두 자리 수끼리의 덧셈식 AB+BC=BCB에서 A를 구하시오.",
        "question_en": "A, B, C are different numbers from 0 to 9. Find A from the following two-digit addition: AB+BC=BCB.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "AB+BC=BCB A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "AB+BC=BCB A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'AB+BC=BCB'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'AB+BC=BCB'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "1570": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 수를 85로 나눌 때 나올 수 있는 나머지 중에서 다섯 번째로 큰 수는 얼마입니까?",
        "question_en": "What is the fifth largest number that can come out when you divide a number by 85?",
        "answer_ko": "80",
        "answer_en": "80",
        "solution_abst_ko": "85 5 [OP_SUB]",
        "solution_abst_en": "85 5 [OP_SUB]",
        "solution_code_ko": "var_a = 85\nvar_b = 5\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 85\nvar_b = 5\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "1571": {
        "category": "Comparison",
        "question_ko": "호현이는 키가 162센티미터(㎝)이고 슬기는 키가 159센티미터(㎝)입니다. 키가 더 큰 사람은 누구입니까?",
        "question_en": "Hohyeon is 162 centimeters (cm) tall and Seulgi is 159 centimeters (cm) tall. Who is taller?",
        "answer_ko": "호현",
        "answer_en": "Hohyeon",
        "solution_abst_ko": "[OP_LIST_SOL] 호현 슬기 [OP_LIST_EOL] [OP_LIST_SOL] 162 159 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Hohyeon Seulgi [OP_LIST_EOL] [OP_LIST_SOL] 162 159 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '호현'\nvar_b = '슬기'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 162\nvar_d = 159\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Hohyeon'\nvar_b = 'Seulgi'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 162\nvar_d = 159\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "1572": {
        "category": "Arithmetic calculation",
        "question_ko": "나무 400그램(g)을 사용하여 공예품 3개를 만듭니다. 나무 2.3킬로그램(㎏)을 사용하여 공예품을 최대 몇 개 만들수 있습니까? (단, 공예품은 한 번에 3개씩 만든다.)",
        "question_en": "Use 400 grams (g) of wood to make 3 crafts. How many crafts can you make using 2.3 kilograms (kg) of wood? (However, crafts are made 3 at a time.)",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "2.3 1000 [OP_MUL] 400 [OP_FDIV] 3 [OP_MUL]",
        "solution_abst_en": "2.3 1000 [OP_MUL] 400 [OP_FDIV] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 2.3\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 400\nvar_e = var_c // var_d\nvar_f = 3\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 2.3\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 400\nvar_e = var_c // var_d\nvar_f = 3\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "1573": {
        "category": "Comparison",
        "question_ko": "썰매를 타려고 눈썰매장에서 아이들이 줄을 섰습니다. 맨 앞에 서있는 아이와 뒤에서 5번째에 서 있는 아이 사이에 30 명이 있다면, 줄을 선 아이들은 모두 몇 명입니까?",
        "question_en": "Children lined up at the sledding range to ride the sled. If there are 30 people between the foremost child and the fifth child from the back, how many children are in the line?",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "5 30 [OP_ADD] 1 [OP_ADD]",
        "solution_abst_en": "5 30 [OP_ADD] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 30\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 30\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "1574": {
        "category": "Geometry",
        "question_ko": "직사각형 텃밭이 있다. 텃밭의 가로가 500센티미터(㎝), 세로가 800센티미터(㎝) 이다. 이 텃밭의 넓이는 몇 제곱미터(㎡) 입니까?",
        "question_en": "You have a rectangular garden. The garden is 500 centimeters (cm) wide and 800 centimeters (cm) long. What is the area of this garden in square meters (m2)?",
        "answer_ko": "40",
        "answer_en": "40",
        "solution_abst_ko": "500 100 [OP_DIV] 800 100 [OP_DIV] [OP_MUL]",
        "solution_abst_en": "500 100 [OP_DIV] 800 100 [OP_DIV] [OP_MUL]",
        "solution_code_ko": "var_a = 500\nvar_b = 100\nvar_c = var_a / var_b\nvar_d = 800\nvar_e = 100\nvar_f = var_d / var_e\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 500\nvar_b = 100\nvar_c = var_a / var_b\nvar_d = 800\nvar_e = 100\nvar_f = var_d / var_e\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "1575": {
        "category": "Geometry",
        "question_ko": "키가 작은 사람부터 순서대로 9명이 한 줄로 서 있습니다. 호석이가 앞에서부터 4번째에 서 있습니다. 키가 큰 사람부터 순서대로 다시 줄을 서면 호석이는 뒤에서부터 몇 번째에 서게 됩니까?",
        "question_en": "Nine people stand in a line in order from shortest to tallest. Hoseok is standing 4th from the front. If you line up again in order from the tallest to the shortest, what number will Hoseok stand from the back?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "4",
        "solution_abst_en": "4",
        "solution_code_ko": "var_a = 4\nprint(int(var_a))",
        "solution_code_en": "var_a = 4\nprint(int(var_a))"
    },
    "1576": {
        "category": "Geometry",
        "question_ko": "마주보는 두 쌍의 변이 평행한 사각형의 밑변의 길이가 3.8미터(m)이고 높이가 6.36미터(m)일 때 넓이를 구하시오.",
        "question_en": "Find the area of a quadrilateral with two pairs of opposite sides parallel if the base is 3.8 meters (m) and the height is 6.36 meters (m).",
        "answer_ko": "24.17",
        "answer_en": "24.17",
        "solution_abst_ko": "3.8 6.36 [OP_MUL]",
        "solution_abst_en": "3.8 6.36 [OP_MUL]",
        "solution_code_ko": "var_a = 3.8\nvar_b = 6.36\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 3.8\nvar_b = 6.36\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "1577": {
        "category": "Geometry",
        "question_ko": "모든 변의 길이가 12센티미터(㎝)로 같은 팔각형의 둘레는 몇 센티미터(㎝)입니까?",
        "question_en": "What is the perimeter in centimeters (cm) of an octagon with all sides equal to 12 centimeters (cm)?",
        "answer_ko": "96",
        "answer_en": "96",
        "solution_abst_ko": "12 8 [OP_MUL]",
        "solution_abst_en": "12 8 [OP_MUL]",
        "solution_code_ko": "var_a = 12\nvar_b = 8\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 12\nvar_b = 8\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "1578": {
        "category": "Arithmetic calculation",
        "question_ko": "한 자리 수의 홀수와 두 자리수의 짝수는 모두 몇 개인지 구하시오.",
        "question_en": "How many single-digit odd numbers and two-digit even numbers are there?",
        "answer_ko": "50",
        "answer_en": "50",
        "solution_abst_ko": "10 99 [OP_LIST_EVEN] 1 9 [OP_LIST_ODD] [OP_SET_UNION] [OP_LIST_LEN]",
        "solution_abst_en": "10 99 [OP_LIST_EVEN] 1 9 [OP_LIST_ODD] [OP_SET_UNION] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 10\nvar_b = 99\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 1\nvar_d = 9\nlist_b = []\nif var_c%2==0:\n    for i in range(var_c+1, var_d+1, 2):\n        list_b.append(i)\nelse:\n    for i in range(var_c, var_d+1, 2):\n        list_b.append(i)\nlist_c = list(set(list_a) | set(list_b))\nvar_e = len(list_c)\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 99\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 1\nvar_d = 9\nlist_b = []\nif var_c%2==0:\n    for i in range(var_c+1, var_d+1, 2):\n        list_b.append(i)\nelse:\n    for i in range(var_c, var_d+1, 2):\n        list_b.append(i)\nlist_c = list(set(list_a) | set(list_b))\nvar_e = len(list_c)\nprint(int(var_e))"
    },
    "1579": {
        "category": "Possibility",
        "question_ko": "숫자 카드 0, 3, 4, 8을 모두 사용하여 만들 수 있는 네 자리 수 중 가장 작은 수와 가장 큰 수의 합을 구하시오.",
        "question_en": "Find the sum of the smallest and largest four-digit numbers that can be formed using all the number cards 0, 3, 4, and 8.",
        "answer_ko": "11478",
        "answer_en": "11478",
        "solution_abst_ko": "[OP_LIST_SOL] 0 3 4 8 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 1 [OP_LIST_MAX] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 0 3 4 8 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 1 [OP_LIST_MAX] [OP_ADD]",
        "solution_code_ko": "var_a = 0\nvar_b = 3\nvar_c = 4\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nvar_j = var_g + var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 0\nvar_b = 3\nvar_c = 4\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nvar_j = var_g + var_i\nprint(int(var_j))"
    },
    "1580": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중에서 가장 큰 수와 2번째로 큰 수의 차는 얼마입니까?",
        "question_en": "If you have three numbers of 10, 11 and 12, what do you get for the difference between the largest number and the second largest number?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = var_e - var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = var_e - var_g\nprint(int(var_h))"
    },
    "1581": {
        "category": "Comparison",
        "question_ko": "1.4, 9/10, 1.2, 0.5, 13/10에서 1.1보다 작거나 같은 숫자를 나열한뒤, 합을 계산하면 얼마입니까?",
        "question_en": "If you line up numbers that are less than or equal to 1.1 from among five numbers 1.4, 9/10, 1.2, 0.5, 13/10 and calculate the sum, what is the value?",
        "answer_ko": "1.40",
        "answer_en": "1.4",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS_EQUAL] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS_EQUAL] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i <= var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i <= var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "1582": {
        "category": "Geometry",
        "question_ko": "정팔각형의 둘레가 72 센티미터(㎝) 일 때, 한 변의 길이를 구하시오.",
        "question_en": "If the perimeter of a regular octagon is 72 centimeters (cm), find the length of one side.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "72 8 [OP_DIV]",
        "solution_abst_en": "72 8 [OP_DIV]",
        "solution_code_ko": "var_a = 72\nvar_b = 8\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 72\nvar_b = 8\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "1583": {
        "category": "Correspondence",
        "question_ko": "세 자연수 A, B, C가 있습니다. A를 7로 나누면 몫은 B이고 나머지는 C가 됩니다. 이 식에서 몫과 나머지는 같습니다. A 중 가장 큰 수를 구하시오.",
        "question_en": "There are three natural numbers A, B, and C. When A is divided by 7, the quotient is B and the remainder is C. The quotient and remainder are equal in this equation. Find the largest number among A.",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "7 6 [OP_MUL] 6 [OP_ADD]",
        "solution_abst_en": "7 6 [OP_MUL] 6 [OP_ADD]",
        "solution_code_ko": "var_a = 7\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 7\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "1584": {
        "category": "Geometry",
        "question_ko": "진호는 집에서 학교를 가는 길에 버스를 타고는 4킬로미터(㎞) 436미터(m)를 이동하고, 걸어서는 1999미터(m)를 이동해 학교에 도착한다. 집으로 올때도 마찬가지일 때, 진호는 학교를 갔다오면서 몇 킬로미터(㎞)를 이동하였는가?",
        "question_en": "On the way to school from home, Jinho takes a bus to travel 4 kilometers (km) and 436 meters (m), and walks 1999 meters (m). When he went back home in the same way, how many kilometers (km) did Jinho travel to and from school?",
        "answer_ko": "12.87",
        "answer_en": "12.87",
        "solution_abst_ko": "4 436 1000 [OP_DIV] [OP_ADD] 1999 1000 [OP_DIV] [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "4 436 1000 [OP_DIV] [OP_ADD] 1999 1000 [OP_DIV] [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 4\nvar_b = 436\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 1999\nvar_g = 1000\nvar_h = var_f / var_g\nvar_i = var_e + var_h\nvar_j = 2\nvar_k = var_i * var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 4\nvar_b = 436\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 1999\nvar_g = 1000\nvar_h = var_f / var_g\nvar_i = var_e + var_h\nvar_j = 2\nvar_k = var_i * var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "1585": {
        "category": "Geometry",
        "question_ko": "어떤 그릇의 부피가 36.488밀리리터(㎖)이다. 초 당 6.08밀리리터(㎖)를 부울 때, 그릇을 가득체우는데 얼마가 걸릴지 구하시오.",
        "question_en": "A bowl has a volume of 36.488 milliliters (ml). If you pour 6.08 milliliters (ml) per second, how long will it take to fill the bowl?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "36.48 6.08 [OP_DIV]",
        "solution_abst_en": "36.48 6.08 [OP_DIV]",
        "solution_code_ko": "var_a = 36.48\nvar_b = 6.08\nvar_c = var_a / var_b\nprint(int(eval('{:.2f}'.format(round(var_c+1e-10,2)))))",
        "solution_code_en": "var_a = 36.48\nvar_b = 6.08\nvar_c = var_a / var_b\nprint(int(eval('{:.2f}'.format(round(var_c+1e-10,2)))))"
    },
    "1586": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 10센티미터(㎝)인 정사각형 모양의 종이가 있습니다. 이 종이로 밑면이 1센티미터(㎝)이고 높이가 3센티미터(㎝)인 직각삼각형 모양의 조각을 최대한 몇 개나 오려낼 수 있겠습니까?",
        "question_en": "You have a square piece of paper with a side length of 10 centimeters (cm). How many right triangle-shaped pieces with a base of 1 centimeter (cm) and a hight of 3 centimeters (cm) can you cut out from this piece of paper?",
        "answer_ko": "66",
        "answer_en": "66",
        "solution_abst_ko": "10 2 [OP_POW] 1 3 [OP_MUL] [OP_FDIV] 2 [OP_MUL]",
        "solution_abst_en": "10 2 [OP_POW] 1 3 [OP_MUL] [OP_FDIV] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 1\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c // var_f\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 1\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c // var_f\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "1587": {
        "category": "Correspondence",
        "question_ko": "크기가 다른 공 A, B, C가 있다. A는 B보다 3배 크고 B는 C의 1/2의 크기이다. A는 C의 크기의 몇 배인가?",
        "question_en": "There are balls A, B, and C of different sizes. A is three times bigger than B, and B is half the size of C. How many times the size of A than the size of C?",
        "answer_ko": "1.50",
        "answer_en": "1.5",
        "solution_abst_ko": "3 1/2 [OP_MUL]",
        "solution_abst_en": "3 1/2 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 0.5\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 3\nvar_b = 0.5\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "1588": {
        "category": "Comparison",
        "question_ko": "어느 김밥 가게에서 기본 김밥은 2000원, 참치 김밥은 3500원, 고추 김밥은 3000원, 소고기 김밥은 4000원, 누드 김밥은 3500원일 때 3500원 이상인 김밥은 몇 종류가 있습니까?",
        "question_en": "At a gimbap shop, a basic gimbap is 2,000 won, a tuna gimbap is 3,500 won, red pepper gimbap is 3,000 won, a beef gimbap is 4,000 won, and a rice gimbap is 3,500 won. Find out the number of types of gimbap that costs more than or equal to 3500 won.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 2000 3500 3000 4000 3500 [OP_LIST_EOL] 3500 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 2000 3500 3000 4000 3500 [OP_LIST_EOL] 3500 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 2000\nvar_b = 3500\nvar_c = 3000\nvar_d = 4000\nvar_e = 3500\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3500\nlist_b = []\nfor i in list_a:\n    if i >= var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 2000\nvar_b = 3500\nvar_c = 3000\nvar_d = 4000\nvar_e = 3500\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3500\nlist_b = []\nfor i in list_a:\n    if i >= var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "1589": {
        "category": "Geometry",
        "question_ko": "어느 연극 티켓은 직사각형 모양이며, 둘레가 28 센티미터(㎝), 가로가 6센티미터(㎝) 입니다. 이 연극 티켓의 넓이를 구하시오.",
        "question_en": "A theater ticket is rectangular in shape, measuring 28 centimeters (cm) in perimeter and 6 centimeters (cm) in width. Find the area of this theater ticket.",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "28 2 [OP_DIV] 6 [OP_SUB] 6 [OP_MUL]",
        "solution_abst_en": "28 2 [OP_DIV] 6 [OP_SUB] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 28\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c - var_d\nvar_f = 6\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 28\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c - var_d\nvar_f = 6\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "1590": {
        "category": "Geometry",
        "question_ko": "평행한 선분 두 개를 긋고, 그 위에 다시 평행한 선분 두 개를 그었더니 사각형이 그려졌습니다. 이 사각형의 밑변이 9.51센티미터(㎝), 높이가 4.8센티미터(㎝)라면 넓이는 얼마인지 구하시오.",
        "question_en": "I drew two parallel lines, then drew two parallel lines on top of them, and a square was drawn. If the base of this square is 9.51 centimeters (cm) and the height is 4.8 centimeters (cm), what is the area?",
        "answer_ko": "45.65",
        "answer_en": "45.65",
        "solution_abst_ko": "9.51 4.8 [OP_MUL]",
        "solution_abst_en": "9.51 4.8 [OP_MUL]",
        "solution_code_ko": "var_a = 9.51\nvar_b = 4.8\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 9.51\nvar_b = 4.8\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "1591": {
        "category": "Correspondence",
        "question_ko": "우영이는 첫 번째 가게에서 가지고 있는 돈의 반보다 200원 많은 돈을 사용하였고 두 번째 가게에서 나머지 돈은 반보다 300원 많은 돈을 사용하였더니 350원이 남았습니다. 우영이가 처음 가지고 있던 돈은 얼마입니까?",
        "question_en": "Wooyoung spent 200 won more than half of the money he had at the first store and 300 won more than half of the remaining money at the second store, and was left with 350 won. How much money did Wooyoung have at first?",
        "answer_ko": "3000",
        "answer_en": "3000",
        "solution_abst_ko": "350 300 [OP_ADD] 1 1/2 [OP_SUB] [OP_DIV] 200 [OP_ADD] 1 1/2 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "350 300 [OP_ADD] 1 1/2 [OP_SUB] [OP_DIV] 200 [OP_ADD] 1 1/2 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 350\nvar_b = 300\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 0.5\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 200\nvar_i = var_g + var_h\nvar_j = 1\nvar_k = 0.5\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 350\nvar_b = 300\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 0.5\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 200\nvar_i = var_g + var_h\nvar_j = 1\nvar_k = 0.5\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nprint(int(var_m))"
    },
    "1592": {
        "category": "Arithmetic calculation",
        "question_ko": "2의 배수, 3의 배수, 8의 배수, 9의 배수를 모두 만족하면서 네 자리 수인 것은 모두 몇 개 입니까?",
        "question_en": "How many four-digit numbers are multiples of all of 2, 3, 8, and 9?",
        "answer_ko": "125",
        "answer_en": "125",
        "solution_abst_ko": "1000 9999 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "1000 9999 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 3\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = len(list_e)\nprint(int(var_h))",
        "solution_code_en": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 3\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = len(list_e)\nprint(int(var_h))"
    },
    "1593": {
        "category": "Comparison",
        "question_ko": "1킬로그램(㎏)의 상자를 다미는 1100그램(g)으로, 우식이는 850그램(g)으로 어림하였다면, 두 사람 중 상자의 무게를 가깝게 어림한 사람은 누구인지 구하시오.",
        "question_en": "If a box weighing 1 kg (kg) is estimated to be 1100 grams (g) for Dami and 850 grams (g) for Woosik, find out which of the two people has the closest estimate of the weight of the box.",
        "answer_ko": "다미",
        "answer_en": "Dami",
        "solution_abst_ko": "[OP_LIST_SOL] 다미 우식 [OP_LIST_EOL] [OP_LIST_SOL] 1000 1100 [OP_SUB] [OP_ABS] 1000 850 [OP_SUB] [OP_ABS] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Dami Woosik [OP_LIST_EOL] [OP_LIST_SOL] 1000 1100 [OP_SUB] [OP_ABS] 1000 850 [OP_SUB] [OP_ABS] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '다미'\nvar_b = '우식'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1000\nvar_d = 1100\nvar_e = var_c - var_d\nvar_f = abs(var_e)\nvar_g = 1000\nvar_h = 850\nvar_i = var_g - var_h\nvar_j = abs(var_i)\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[var_k-1]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'Dami'\nvar_b = 'Woosik'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1000\nvar_d = 1100\nvar_e = var_c - var_d\nvar_f = abs(var_e)\nvar_g = 1000\nvar_h = 850\nvar_i = var_g - var_h\nvar_j = abs(var_i)\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[var_k-1]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "1594": {
        "category": "Correspondence",
        "question_ko": "A, B, C는 자연수입니다. A를 9로 나누면 몫이 B고 나머지는 C입니다. 나머지가 몫보다 3만큼 작을때 A가 될 수 있는 수 중에 가장 작은 수를 고르세요.",
        "question_en": "A, B, and C are natural numbers. When A is divided by 9, the quotient is B and the remainder is C. If the remainder is 3 less than the quotient, choose the smallest number that can be A.",
        "answer_ko": "27",
        "answer_en": "27",
        "solution_abst_ko": "9 3 [OP_MUL] 0 [OP_ADD]",
        "solution_abst_en": "9 3 [OP_MUL] 0 [OP_ADD]",
        "solution_code_ko": "var_a = 9\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 0\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 0\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "1595": {
        "category": "Comparison",
        "question_ko": "6명의 친구와 유나가 한 줄로 서 있습니다. 유나의 앞에 2명의 친구가 있다면 유나의 뒤에는 몇 명의 친구가 있는지 구하시오.",
        "question_en": "6 friends and Yuna are standing in a line. If there are 2 friends in front of Yuna, find how many friends are behind Yuna.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "6 1 [OP_ADD] 2 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "6 1 [OP_ADD] 2 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 6\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 6\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "1596": {
        "category": "Comparison",
        "question_ko": "빨간색 테이프가 11/6미터(m), 파란색 테이프가 7/4미터(m), 노란색 테이프가 13/8미터(m) 있습니다. 길이가 가장 긴 테이프는 어느 것입니까?",
        "question_en": "The red tape is 11/6 meters (m), the blue tape is 7/4 meters (m), and the yellow tape is 13/8 meters (m). Which tape is the longest?",
        "answer_ko": "빨간색",
        "answer_en": "red",
        "solution_abst_ko": "[OP_LIST_SOL] 빨간색 파란색 노란색 [OP_LIST_EOL] [OP_LIST_SOL] 11/6 7/4 13/8 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] red blue yellow [OP_LIST_EOL] [OP_LIST_SOL] 11/6 7/4 13/8 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '빨간색'\nvar_b = '파란색'\nvar_c = '노란색'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1.8333333333333333\nvar_e = 1.75\nvar_f = 1.625\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'red'\nvar_b = 'blue'\nvar_c = 'yellow'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1.8333333333333333\nvar_e = 1.75\nvar_f = 1.625\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "1597": {
        "category": "Geometry",
        "question_ko": "팔각형 모양의 선물 상자가 있습니다. 상자의 둘레가 72센티미터(㎝)일 때, 한 변의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "There is an octagon-shaped gift box. If the box's perimeter is 72 centimeters (cm), what is the side length in centimeters (cm)?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "72 8 [OP_DIV]",
        "solution_abst_en": "72 8 [OP_DIV]",
        "solution_code_ko": "var_a = 72\nvar_b = 8\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 72\nvar_b = 8\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "1598": {
        "category": "Arithmetic calculation",
        "question_ko": "사과 40개를 7명에게 최대한 많이 똑같이 나누어 주었을 때, 남는 사과는 몇 개입니까?",
        "question_en": "How many apples are left when you equally distribute 40 apples to as many as possible to 7 people?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "40 7 [OP_MOD]",
        "solution_abst_en": "40 7 [OP_MOD]",
        "solution_code_ko": "var_a = 40\nvar_b = 7\nvar_c = var_a % var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 40\nvar_b = 7\nvar_c = var_a % var_b\nprint(int(var_c))"
    },
    "1599": {
        "category": "Correspondence",
        "question_ko": "상준이는 경제 분야에 전체 책 중 1/4보다 10권 많게 가지고 있고, 나머지 책 중 3/5보다 5개 적게 사회 분야의 책을 가지고 있고, 그 나머지 중 12권은 과학 분야의 책이다. 상준이가 경제, 사회, 과학 분야가 아닌 책이 13권 있을 때, 상준이가 가지고 있는 책은 모두 몇 권인가?",
        "question_en": "Sangjun has 10 more than 1/4 of the books on economics, 5 less than 3/5 of the remaining books on social science, and 12 of the remaining books are on science. If Sangjun has 13 books that are not related to economics, society, or science, how many books does Sangjun have?",
        "answer_ko": "80",
        "answer_en": "80",
        "solution_abst_ko": "13 12 [OP_ADD] 5 [OP_SUB] 1 3/5 [OP_SUB] [OP_DIV] 10 [OP_ADD] 1 1/4 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "13 12 [OP_ADD] 5 [OP_SUB] 1 3/5 [OP_SUB] [OP_DIV] 10 [OP_ADD] 1 1/4 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 13\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = 0.6\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 10\nvar_k = var_i + var_j\nvar_l = 1\nvar_m = 0.25\nvar_n = var_l - var_m\nvar_o = var_k / var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 13\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = 0.6\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 10\nvar_k = var_i + var_j\nvar_l = 1\nvar_m = 0.25\nvar_n = var_l - var_m\nvar_o = var_k / var_n\nprint(int(var_o))"
    },
    "1600": {
        "category": "Possibility",
        "question_ko": "세 자리 수 중 3, 6, 9가 모두 들어있는 것은 몇 개입니까?",
        "question_en": "How many three-digit numbers contain all of 3, 6, and 9?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 3 6 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 3 6 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 3\nvar_b = 6\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 3\nvar_b = 6\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "1601": {
        "category": "Comparison",
        "question_ko": "진수는 제기차기를 2번 시도했는데, 첫 번째와 두 번째에 각각 15번씩을 찼습니다. 호석이는 제기를 모두 48번 찼는데, 진수가 호석이보다 제기를 더 많이 차기 위해서는 세번째 시도에 적어도 몇 번을 차야만 합니까?",
        "question_en": "Jinsu tried to kick jegi twice, and he kicked 15 each in the first and second. Hoseok has kicked 48 times in total. How many times should Jinsu kick on the third try, in order to kick more than Hoseok?",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "48 15 15 [OP_ADD] [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "48 15 15 [OP_ADD] [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 48\nvar_b = 15\nvar_c = 15\nvar_d = var_b + var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 48\nvar_b = 15\nvar_c = 15\nvar_d = var_b + var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "1602": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 가장 큰 수와 가장 작은 수의 차는 얼마입니까?",
        "question_en": "There are five numbers 10, 11, 12, 13, and 14. What is the difference between the largest number and the smallest number?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))"
    },
    "1603": {
        "category": "Possibility",
        "question_ko": "사과, 복숭아, 배, 참외 중에서 2가지의 서로 다른 과일을 사는 경우는 모두 몇 가지입니까?",
        "question_en": "How many ways can you buy 2 different fruits out of Apples, Peaches, Pears, and Melons?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 복숭아 배 참외 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] Apple Peach Pear Melon [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '복숭아'\nvar_c = '배'\nvar_d = '참외'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g / (i+1)\nprint(int(var_g))",
        "solution_code_en": "var_a = 'Apple'\nvar_b = 'Peach'\nvar_c = 'Pear'\nvar_d = 'Melon'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g / (i+1)\nprint(int(var_g))"
    },
    "1604": {
        "category": "Arithmetic calculation",
        "question_ko": "80만원인 전자기기가 할인하여 45만원에 판다. 이 전자기기를 몇 개 샀더니 할인 덕분에 1645만원 더 적은 금액을 사용하였다. 전자기기를 몇 개 샀는지 구하시오.",
        "question_en": "An electronic device worth 800,000 won is discounted and sold for 450,000 won. I bought a few of these electronic devices, and thanks to the discount, I spent 16.45 million won less. Find how many electronic gadgets I have bought.",
        "answer_ko": "47",
        "answer_en": "47",
        "solution_abst_ko": "1645 80 45 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "1645 80 45 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 1645\nvar_b = 80\nvar_c = 45\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 1645\nvar_b = 80\nvar_c = 45\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "1605": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 40센티미터(㎝)인 정사각형 모양의 종이를 잘라 똑같은 모양의 직사각형을 5개 만들었습니다. 이 직사각형의 넓이가 가장 클 때, 직사각형의 짧은 변의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "You made 5 identical rectangles by cutting a square-shaped paper whose side is 40 centimeters (cm) long. How many centimeters (cm) is the length of the shorter side of a rectangle when it has the largest area?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "40 5 [OP_DIV]",
        "solution_abst_en": "40 5 [OP_DIV]",
        "solution_code_ko": "var_a = 40\nvar_b = 5\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 40\nvar_b = 5\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "1606": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 10, 11, 12, 13이 있습니다. 그 중에서 가장 큰 수와 그 다음으로 큰 수로 나눈 몫은 얼마입니까?",
        "question_en": "There are four numbers 10, 11, 12, and 13. What is the quotient of the largest number divided by the next largest number?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_FDIV]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_FDIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = var_f // var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = var_f // var_h\nprint(int(var_i))"
    },
    "1607": {
        "category": "Arithmetic calculation",
        "question_ko": "두 사람이 놀이 공원에서 만나기로 했다. A사람은 시속 3킬로미터(㎞)로 왔고, B사람은 시속 4킬로미터(㎞)로 왔다. B사람과 놀이 공원까지의 거리가 A사람과 놀이공원까지의 거리보다 2킬로미터(㎞) 더 길다. 둘이 합쳐 4시간이 걸렸다면, 놀이 공원과 B사람 집 사이의 거리는?",
        "question_en": "The two people decided to meet at an amusement park. Person A came at 3 kilometers (km) per hour, person B came at 4 kilometers (km) per hour. The distance between person B and the amusement park is 2 kilometers (km) longer than the distance between person A and the amusement park. If the two people took 4 hours together, what is the distance between the amusement park and Person B's house?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "4 2 4 [OP_DIV] [OP_SUB] 1 3 [OP_DIV] 1 4 [OP_DIV] [OP_ADD] [OP_DIV] 2 [OP_ADD]",
        "solution_abst_en": "4 2 4 [OP_DIV] [OP_SUB] 1 3 [OP_DIV] 1 4 [OP_DIV] [OP_ADD] [OP_DIV] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = 3\nvar_h = var_f / var_g\nvar_i = 1\nvar_j = 4\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_e / var_l\nvar_n = 2\nvar_o = var_m + var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = 3\nvar_h = var_f / var_g\nvar_i = 1\nvar_j = 4\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_e / var_l\nvar_n = 2\nvar_o = var_m + var_n\nprint(int(var_o))"
    },
    "1608": {
        "category": "Correspondence",
        "question_ko": "윤기는 어떤 수에 7을 나누려고 합니다. 하지만 실수로 5를 뺐더니 결과는 30이 되었습니다. 바르게 계산한 결과를 구하세요.",
        "question_en": "Yoongi wants to divide a certain number by 7. But he accidentally subtracted 5 and the result was 30. Find the correct calculation result.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "30 5 [OP_ADD] 7 [OP_DIV]",
        "solution_abst_en": "30 5 [OP_ADD] 7 [OP_DIV]",
        "solution_code_ko": "var_a = 30\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 7\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 30\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 7\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "1609": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 15를 곱했더니 결과가 45가 되었습니다. 어떤 수에서 1을 빼면 얼마입니까?",
        "question_en": "When a particular number is multiplied by 15, the result is 45. What will you get when you subtract 1 from that particular number?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "45 15 [OP_DIV] 1 [OP_SUB]",
        "solution_abst_en": "45 15 [OP_DIV] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 45\nvar_b = 15\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 45\nvar_b = 15\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "1610": {
        "category": "Possibility",
        "question_ko": "서로 다른 맛의 사탕 2개와 색깔이 다른 초콜릿 3개가 있습니다. 하나만 먹을 수 있을 때, 몇 가지 경우가 있습니까?",
        "question_en": "You have 2 candies of different flavors and 3 chocolates of different colors. When you can only eat one, how many cases are there?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "2 3 [OP_ADD]",
        "solution_abst_en": "2 3 [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "1611": {
        "category": "Arithmetic calculation",
        "question_ko": "40명의 학생 중 지민, 정국이의 점수를 제외한 평균 점수는 79점이다. 지민, 정국이 98, 100점일때 지민이네 반 평균 점수는 몇 점인가?",
        "question_en": "Among the 40 students, the average score excluding Jimin and Jungkook's scores is 79. If Jimin and Jungkook scored 98 and 100 respectively, what is the average score of Jimin's class?",
        "answer_ko": "80",
        "answer_en": "80",
        "solution_abst_ko": "40 2 [OP_SUB] 79 [OP_MUL] 98 [OP_ADD] 100 [OP_ADD] 40 [OP_DIV]",
        "solution_abst_en": "40 2 [OP_SUB] 79 [OP_MUL] 98 [OP_ADD] 100 [OP_ADD] 40 [OP_DIV]",
        "solution_code_ko": "var_a = 40\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 79\nvar_e = var_c * var_d\nvar_f = 98\nvar_g = var_e + var_f\nvar_h = 100\nvar_i = var_g + var_h\nvar_j = 40\nvar_k = var_i / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 40\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 79\nvar_e = var_c * var_d\nvar_f = 98\nvar_g = var_e + var_f\nvar_h = 100\nvar_i = var_g + var_h\nvar_j = 40\nvar_k = var_i / var_j\nprint(int(var_k))"
    },
    "1612": {
        "category": "Arithmetic calculation",
        "question_ko": "(가) 쌀통에는 쌀이 12킬로그램(㎏) 400그램(g) 있고, (나) 쌀통에는 쌀이 7600그램(g) 들어있습니다. 두 쌀통에 들어있는 쌀의 양이 같아지려면 (가) 통에서 (나) 통으로 몇 킬로그램(㎏)을 옮겨야 합니까?",
        "question_en": "A rice container contains 12 kilograms (kg) and 400 grams (g) of rice, and B rice container contains 7600 grams (g) of rice. How many kilograms (kg) must be moved from A to B to equalize the amount of rice in the two rice containers?",
        "answer_ko": "2.40",
        "answer_en": "2.4",
        "solution_abst_ko": "12 400 1000 [OP_DIV] [OP_ADD] 7600 1000 [OP_DIV] [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "12 400 1000 [OP_DIV] [OP_ADD] 7600 1000 [OP_DIV] [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 400\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 7600\nvar_g = 1000\nvar_h = var_f / var_g\nvar_i = var_e - var_h\nvar_j = 2\nvar_k = var_i / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 12\nvar_b = 400\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 7600\nvar_g = 1000\nvar_h = var_f / var_g\nvar_i = var_e - var_h\nvar_j = 2\nvar_k = var_i / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "1613": {
        "category": "Comparison",
        "question_ko": "책 두 권의 장수의 차이는 10장이고, 한 책의 장수를 2로 나누면 다른 한 책의 장수가 됩니다. 짧은 책의 장수를 구하시오",
        "question_en": "The number of pages of two books is different by 10, and dividing the number of pages of one book by 2 equals the number of pages of the other book. Find the number of pages of the shorter book.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "10 1 1 2 [OP_DIV] [OP_SUB] [OP_DIV] 2 [OP_DIV]",
        "solution_abst_en": "10 1 1 2 [OP_DIV] [OP_SUB] [OP_DIV] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 1\nvar_c = 1\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = var_b - var_e\nvar_g = var_a / var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 1\nvar_c = 1\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = var_b - var_e\nvar_g = var_a / var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "1614": {
        "category": "Comparison",
        "question_ko": "빨간 휴지와 파란 휴지가 있습니다. 빨간 휴지가 파란 휴지보다 12센티미터(㎝)더 길고, 빨간 휴지 길이의 2배가 파란 휴지 길이의 3배와 같을 때, 파란 휴지의 길이를 구하시오.",
        "question_en": "There is a red tissue and a blue tissue. If the red tissue is 12 centimeters (cm) longer than the blue tissue, and twice the length of the red tissue equals three times the length of the blue tissue, find the length of the blue tissue.",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "12 1 1 3 [OP_DIV] 2 [OP_MUL] [OP_SUB] [OP_DIV] 3 [OP_DIV] 2 [OP_MUL]",
        "solution_abst_en": "12 1 1 3 [OP_DIV] 2 [OP_MUL] [OP_SUB] [OP_DIV] 3 [OP_DIV] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 12\nvar_b = 1\nvar_c = 1\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = var_b - var_g\nvar_i = var_a / var_h\nvar_j = 3\nvar_k = var_i / var_j\nvar_l = 2\nvar_m = var_k * var_l\nprint(int(eval('{:.2f}'.format(round(var_m+1e-10,2)))))",
        "solution_code_en": "var_a = 12\nvar_b = 1\nvar_c = 1\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = var_b - var_g\nvar_i = var_a / var_h\nvar_j = 3\nvar_k = var_i / var_j\nvar_l = 2\nvar_m = var_k * var_l\nprint(int(eval('{:.2f}'.format(round(var_m+1e-10,2)))))"
    },
    "1615": {
        "category": "Arithmetic calculation",
        "question_ko": "고구마 52.5그램(g)을 한 사람 당 5그램(g)씩 나누어 줄 때, 나누어 주고 남는 고구마는 몇 킬로그램(㎏)인지 구하시오.",
        "question_en": "When 52.5 grams (g) of sweet potatoes are divided by 5 grams (g) per person, find how many kilograms (kg) of sweet potatoes are left after sharing.",
        "answer_ko": "0",
        "answer_en": "0",
        "solution_abst_ko": "52.5 5 [OP_MOD] 1000 [OP_DIV]",
        "solution_abst_en": "52.5 5 [OP_MOD] 1000 [OP_DIV]",
        "solution_code_ko": "var_a = 52.5\nvar_b = 5\nvar_c = var_a % var_b\nvar_d = 1000\nvar_e = var_c / var_d\nprint(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))",
        "solution_code_en": "var_a = 52.5\nvar_b = 5\nvar_c = var_a % var_b\nvar_d = 1000\nvar_e = var_c / var_d\nprint(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))"
    },
    "1616": {
        "category": "Comparison",
        "question_ko": "책을 빌리기 위해 8명의 학생들이 한 줄로 서 있습니다. 앞에서 1번째에 서 있는 학생과 뒤에서 4번째에 서 있는 학생 사이에는 모두 몇 명의 학생이 서 있습니까?",
        "question_en": "Eight students stand in a line to borrow books. How many students are standing between the student standing 1st from the front and the student standing 4th from the back?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "8 1 [OP_SUB] 4 [OP_SUB]",
        "solution_abst_en": "8 1 [OP_SUB] 4 [OP_SUB]",
        "solution_code_ko": "var_a = 8\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "1617": {
        "category": "Arithmetic calculation",
        "question_ko": "사과가 5개, 바나나가 4개, 포도가 6개 있습니다. 과일은 모두 몇 개 있습니까?",
        "question_en": "There are 5 apples, 4 bananas and 6 grapes. How many fruits are there in total?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "5 6 [OP_ADD] 4 [OP_ADD]",
        "solution_abst_en": "5 6 [OP_ADD] 4 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "1618": {
        "category": "Arithmetic calculation",
        "question_ko": "8부터 21까지의 수는 모두 몇 개입니까?",
        "question_en": "How many numbers from 8 to 21 are there?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "8 21 1 [OP_LIST_ARANGE] [OP_LIST_LEN]",
        "solution_abst_en": "8 21 1 [OP_LIST_ARANGE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 8\nvar_b = 21\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = len(list_a)\nprint(int(var_d))",
        "solution_code_en": "var_a = 8\nvar_b = 21\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = len(list_a)\nprint(int(var_d))"
    },
    "1619": {
        "category": "Correspondence",
        "question_ko": "48개의 바둑돌 중 흰 바둑돌의 개수에 4를 곱한 뒤 37로 나누면 몫이 2 이고 나머지가 26이다. 검은 바둑돌의 개수를 구하여라.",
        "question_en": "If you multiply the number of white stones among 48 stones by 4 and divide it by 37, the quotient is 2 and the remainder is 26. Find the number of black stones.",
        "answer_ko": "23",
        "answer_en": "23",
        "solution_abst_ko": "48 37 2 [OP_MUL] 26 [OP_ADD] 4 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "48 37 2 [OP_MUL] 26 [OP_ADD] 4 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 48\nvar_b = 37\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = 26\nvar_f = var_d + var_e\nvar_g = 4\nvar_h = var_f / var_g\nvar_i = var_a - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 48\nvar_b = 37\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = 26\nvar_f = var_d + var_e\nvar_g = 4\nvar_h = var_f / var_g\nvar_i = var_a - var_h\nprint(int(var_i))"
    },
    "1620": {
        "category": "Arithmetic calculation",
        "question_ko": "10리터(L) 봉지에 공기가 7/10만큼 남아 있습니다. 이 공기를 4개의 가방에 똑같이 나누려고 할때 각 가방에 몇 리터(L)의 공기를 넣어야 할까요?",
        "question_en": "There are 7/10 of the air left in the 10 liter (L) bag. How many liters (liters) of air would we need to put in each bag if we wanted to divide this air equally among 4 bags?",
        "answer_ko": "1.75",
        "answer_en": "1.75",
        "solution_abst_ko": "10 7/10 [OP_MUL] 4 [OP_DIV]",
        "solution_abst_en": "10 7/10 [OP_MUL] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 0.7\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 10\nvar_b = 0.7\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "1621": {
        "category": "Geometry",
        "question_ko": "크기가 같은 각 8개로 이루어진 도형이 있습니다. 이 도형의 한 변의 길이가 12센티미터(㎝)라면 둘레의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "There is a shape consisting of 8 angles of the same size. If the side of this figure is 12 centimeters (cm), how many centimeters (cm) is the perimeter?",
        "answer_ko": "96",
        "answer_en": "96",
        "solution_abst_ko": "12 8 [OP_MUL]",
        "solution_abst_en": "12 8 [OP_MUL]",
        "solution_code_ko": "var_a = 12\nvar_b = 8\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 12\nvar_b = 8\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "1622": {
        "category": "Correspondence",
        "question_ko": "36에 어떤 수를 나누어야 할 것을 잘못하여 63에 어떤 수를 더했더니 69가 되었습니다. 바르게 계산하면 얼마인지 구하시오.",
        "question_en": "I made the mistake of adding this number to 63, when I should have divided 36 by this number. The result of this miscalculation was 69. How much is it if I calculate it right?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "36 69 63 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "36 69 63 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 36\nvar_b = 69\nvar_c = 63\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 36\nvar_b = 69\nvar_c = 63\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "1623": {
        "category": "Possibility",
        "question_ko": "0, 1, 2, 3, 4의 수가 각각 적힌 5장의 카드에서 3장을 뽑아 세 자리 정수를 만들 때 홀수는 모두 몇 개인지 구하시오",
        "question_en": "Find how many odd numbers there are when you draw 3 cards from 5 cards each with the numbers 0, 1, 2, 3, 4 written on them to make a three-digit integer.",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 2\nlist_c = []\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if i % var_g == 0:\n        list_c.append(i)\nlist_d = list(set(list_b) - set(list_c))\nvar_h = len(list_d)\nprint(int(var_h))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 2\nlist_c = []\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if i % var_g == 0:\n        list_c.append(i)\nlist_d = list(set(list_b) - set(list_c))\nvar_h = len(list_d)\nprint(int(var_h))"
    },
    "1624": {
        "category": "Comparison",
        "question_ko": "민영, 유정, 유나, 지민이는 여름 방학이 되어 농촌으로 봉사활동을 갔습니다. 지민이가 민영이보다 배추를 많이 심었고, 민영이는 유정이보다 배추를 많이 심었습니다. 유나는 유정이보다 배추를 적게 심었다면, 가장 배추를 적게 심은 사람은 누구입니까?",
        "question_en": "Minyoung, Yoojung, Yuna, and Jimin went to volunteer in the countryside during summer vacation. Jimin planted more cabbages than Minyoung, and Minyoung planted more cabbages than Yoojung. If Yuna planted fewer cabbages than Yoojung, who planted the fewest cabbages?",
        "answer_ko": "유나",
        "answer_en": "Yuna",
        "solution_abst_ko": "[OP_LIST_SOL] 민영 유정 유나 지민 [OP_LIST_EOL] [OP_LIST_SOL] 민영 유정 > 유나 유정 < 지민 민영 > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Minyoung Yoojung Yuna Jimin [OP_LIST_EOL] [OP_LIST_SOL] Minyoung Yoojung > Yuna Yoojung < Jimin Minyoung > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '민영'\nvar_b = '유정'\nvar_c = '유나'\nvar_d = '지민'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '민영'\nvar_f = '유정'\nvar_g = '>'\nvar_h = '유나'\nvar_i = '유정'\nvar_j = '<'\nvar_k = '지민'\nvar_l = '민영'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)",
        "solution_code_en": "var_a = 'Minyoung'\nvar_b = 'Yoojung'\nvar_c = 'Yuna'\nvar_d = 'Jimin'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'Minyoung'\nvar_f = 'Yoojung'\nvar_g = '>'\nvar_h = 'Yuna'\nvar_i = 'Yoojung'\nvar_j = '<'\nvar_k = 'Jimin'\nvar_l = 'Minyoung'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)"
    },
    "1625": {
        "category": "Possibility",
        "question_ko": "5, 2, 8, 0 중에서 3개의 숫자를 사용하여 550보다 작고 850보다 큰 세 자리 수를 모두 만들려고 합니다. 총 몇 개의 수를 만들 수 있습니까?",
        "question_en": "You want to create three-digit numbers that are less than 550 and greater than 850 by using three numbers from 5, 2, 8, and 0. How many can you make?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 5 2 8 0 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 550 [OP_LIST_MORE] 850 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 5 2 8 0 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 550 [OP_LIST_MORE] 850 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = 8\nvar_d = 0\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 550\nlist_c = []\nfor i in list_b:\n    if i > var_f:\n        list_c.append(i)\nvar_g = 850\nlist_d = []\nfor i in list_c:\n    if i < var_g:\n        list_d.append(i)\nvar_h = len(list_d)\nprint(int(var_h))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = 8\nvar_d = 0\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 550\nlist_c = []\nfor i in list_b:\n    if i > var_f:\n        list_c.append(i)\nvar_g = 850\nlist_d = []\nfor i in list_c:\n    if i < var_g:\n        list_d.append(i)\nvar_h = len(list_d)\nprint(int(var_h))"
    },
    "1626": {
        "category": "Possibility",
        "question_ko": "숫자 카드 0, 1, 5 중 두 가지를 뽑아 배치하여 만들 수 있는 두 자리 자연수의 경우는 모두 몇 가지입니까?",
        "question_en": "How many two-digit natural numbers can be formed by drawing and placing two of the number cards 0, 1, and 5?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "1627": {
        "category": "Comparison",
        "question_ko": "세 사람이 가진 인형에 숫자가 적혀 있다. 모든 인형에 적힌 숫자를 더한 후, 3으로 나눈 값보다 첫 번째, 두 번째 사람이 가진 인형의 평균이 23만큼 더 컸고, 두 번째, 세 번째 사람의 인형에 적힌 수의 평균이 17 더 작았다. 두 번째 사람의 인형에 적힌 수가 66일 때, 세 사람 인형에 적힌 수의 평균을 구하여라.",
        "question_en": "Numbers are written on the dolls the three people have. The average of the numbers written on the first and second person's dolls is 23 greater than the sum of the numbers written on all the dolls and divided by 3. The average of the numbers on the second and third person's dolls was 17 less than the numbers written on all the dolls and divided by 3. If the number written on the second person's doll is 66, find the average of the numbers written on the three people dolls.",
        "answer_ko": "44",
        "answer_en": "44",
        "solution_abst_ko": "66 17 2 [OP_MUL] [OP_SUB] 3 [OP_MUL] 17 23 [OP_ADD] 2 [OP_MUL] [OP_ADD] 66 2 [OP_MUL] [OP_SUB] 2 2 [OP_ADD] 3 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "66 17 2 [OP_MUL] [OP_SUB] 3 [OP_MUL] 17 23 [OP_ADD] 2 [OP_MUL] [OP_ADD] 66 2 [OP_MUL] [OP_SUB] 2 2 [OP_ADD] 3 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 66\nvar_b = 17\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 3\nvar_g = var_e * var_f\nvar_h = 17\nvar_i = 23\nvar_j = var_h + var_i\nvar_k = 2\nvar_l = var_j * var_k\nvar_m = var_g + var_l\nvar_n = 66\nvar_o = 2\nvar_p = var_n * var_o\nvar_q = var_m - var_p\nvar_r = 2\nvar_s = 2\nvar_t = var_r + var_s\nvar_u = 3\nvar_v = var_t - var_u\nvar_w = var_q / var_v\nprint(int(var_w))",
        "solution_code_en": "var_a = 66\nvar_b = 17\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 3\nvar_g = var_e * var_f\nvar_h = 17\nvar_i = 23\nvar_j = var_h + var_i\nvar_k = 2\nvar_l = var_j * var_k\nvar_m = var_g + var_l\nvar_n = 66\nvar_o = 2\nvar_p = var_n * var_o\nvar_q = var_m - var_p\nvar_r = 2\nvar_s = 2\nvar_t = var_r + var_s\nvar_u = 3\nvar_v = var_t - var_u\nvar_w = var_q / var_v\nprint(int(var_w))"
    },
    "1628": {
        "category": "Geometry",
        "question_ko": "길이가 2미터(m) 50센티미터(㎝)인 줄자로 직사각형 모양의 튤립 꽃밭의 가로의 길이를 재었습니다. 꽃밭의 세로의 길이가 줄자의 5배보다 80센티미터(㎝) 더 길다면, 튤립 꽃밭의 세로 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "The width of the rectangle-shaped tulip flower field was measured with a tape measure of 2 meters (m) and 50 centimeters (cm) in length. If the length of the flower field is 80 centimeters (cm) longer than 5 times the tape measure, how many centimeters (cm) is the length of the tulip flower field?",
        "answer_ko": "1330",
        "answer_en": "1330",
        "solution_abst_ko": "2 100 [OP_MUL] 50 [OP_ADD] 5 [OP_MUL] 80 [OP_ADD]",
        "solution_abst_en": "2 100 [OP_MUL] 50 [OP_ADD] 5 [OP_MUL] 80 [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 50\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = var_e * var_f\nvar_h = 80\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 2\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 50\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = var_e * var_f\nvar_h = 80\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "1629": {
        "category": "Correspondence",
        "question_ko": "3A+B82=216입니다. A는 얼마인가요?",
        "question_en": "3A+B82=216. How much is A?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "3A+B82=216 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "3A+B82=216 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '3A+B82=216'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '3A+B82=216'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "1630": {
        "category": "Comparison",
        "question_ko": "유정이는 태형이보다 구슬을 더 적게 가지고 있습니다. 유정이는 석진이보다 구슬을 더 적게 가지고 있습니다. 석진이는 태형이보다 구슬을 더 많이 가지고 있습니다. 구슬을 가장 많이 가지고 있는 사람은 누구입니까?",
        "question_en": "Yoojeong has fewer marbles than Taehyung. Yoojeong has fewer marbles than Seokjin. Seokjin has more marbles than Taehyung. Who has the most marbles?",
        "answer_ko": "석진",
        "answer_en": "Seokjin",
        "solution_abst_ko": "[OP_LIST_SOL] 유정 태형 석진 [OP_LIST_EOL] [OP_LIST_SOL] 유정 태형 < 유정 석진 < 석진 태형 > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoojeong Taehyung Seokjin [OP_LIST_EOL] [OP_LIST_SOL] Yoojeong Taehyung < Yoojeong Seokjin < Seokjin Taehyung > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '유정'\nvar_b = '태형'\nvar_c = '석진'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '유정'\nvar_e = '태형'\nvar_f = '<'\nvar_g = '유정'\nvar_h = '석진'\nvar_i = '<'\nvar_j = '석진'\nvar_k = '태형'\nvar_l = '>'\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_m = 1\nvar_n = list_c[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'Yoojeong'\nvar_b = 'Taehyung'\nvar_c = 'Seokjin'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'Yoojeong'\nvar_e = 'Taehyung'\nvar_f = '<'\nvar_g = 'Yoojeong'\nvar_h = 'Seokjin'\nvar_i = '<'\nvar_j = 'Seokjin'\nvar_k = 'Taehyung'\nvar_l = '>'\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_m = 1\nvar_n = list_c[var_m-1]\nprint(var_n)"
    },
    "1631": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 7를 곱한 다음 21.28을 더했더니 50.68이 되었습니다. 어떤 수를 구하시오.",
        "question_en": "When you multiply a number by 7 and then add 21.28, you get 50.68. Find a number.",
        "answer_ko": "4.20",
        "answer_en": "4.2",
        "solution_abst_ko": "50.68 21.28 [OP_SUB] 7 [OP_DIV]",
        "solution_abst_en": "50.68 21.28 [OP_SUB] 7 [OP_DIV]",
        "solution_code_ko": "var_a = 50.68\nvar_b = 21.28\nvar_c = var_a - var_b\nvar_d = 7\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 50.68\nvar_b = 21.28\nvar_c = var_a - var_b\nvar_d = 7\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "1632": {
        "category": "Arithmetic calculation",
        "question_ko": "교실에 있는 가방 한 개에는 6칸이 있고 한 칸에 필기구 8개를 넣을 수 있습니다. 교실에 있는 가방 16개 중에서 필기구가 있지 않는 칸은 5칸이고, 한칸에는 필기구가 6개 있으며 나머지 칸에는 모두 필기구 8개가 들어있습니다. 교실에 있는 필기구는 모두 몇 개인지 구해보시오.",
        "question_en": "One bag in the classroom has 6 compartments and can hold 8 writing instruments in each compartment. Of the 16 bags in the classroom, 5 compartments have no writing utensils, one compartment has 6 writing instruments, and all other compartments contain 8 writing instruments. Find how many writing instruments are in the classroom.",
        "answer_ko": "726",
        "answer_en": "726",
        "solution_abst_ko": "16 6 [OP_MUL] 5 [OP_SUB] 1 [OP_SUB] 8 [OP_MUL] 6 [OP_ADD]",
        "solution_abst_en": "16 6 [OP_MUL] 5 [OP_SUB] 1 [OP_SUB] 8 [OP_MUL] 6 [OP_ADD]",
        "solution_code_ko": "var_a = 16\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = 8\nvar_i = var_g * var_h\nvar_j = 6\nvar_k = var_i + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 16\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = 8\nvar_i = var_g * var_h\nvar_j = 6\nvar_k = var_i + var_j\nprint(int(var_k))"
    },
    "1633": {
        "category": "Geometry",
        "question_ko": "가로와 세로의 길이가 각각 36센티미터(㎝), 72센티미터(㎝)인 직사각형 모양의 종이가 있습니다. 이 종이를 잘라서 가로와 세로의 길이가 각각 3센티미터(㎝), 4센티미터(㎝)인 직사각형을 만들려고 합니다. 모두 몇 개를 만들 수 있겠습니까?",
        "question_en": "There is a rectangular piece of paper measuring 36 centimeters (cm) and 72 centimeters (cm) in width and length. I am going to cut this paper to make a rectangle with the width and length of 3 centimeters (cm) and 4 centimeters (cm) respectively. How many can you make in all?",
        "answer_ko": "216",
        "answer_en": "216",
        "solution_abst_ko": "36 3 [OP_FDIV] 72 4 [OP_FDIV] [OP_MUL]",
        "solution_abst_en": "36 3 [OP_FDIV] 72 4 [OP_FDIV] [OP_MUL]",
        "solution_code_ko": "var_a = 36\nvar_b = 3\nvar_c = var_a // var_b\nvar_d = 72\nvar_e = 4\nvar_f = var_d // var_e\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 36\nvar_b = 3\nvar_c = var_a // var_b\nvar_d = 72\nvar_e = 4\nvar_f = var_d // var_e\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "1634": {
        "category": "Arithmetic calculation",
        "question_ko": "1000부터 2000까지의 수를 차례로 적었다. 쓰여진 각 자리의 숫자의 평균을 구하면 얼마가 되는지 구하시오.",
        "question_en": "I wrote the numbers from 1000 to 2000 sequentially. Find the average of the numbers in each written digit.",
        "answer_ko": "14.49",
        "answer_en": "14.49",
        "solution_abst_ko": "1000 2000 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] [OP_LIST_MEAN]",
        "solution_abst_en": "1000 2000 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] [OP_LIST_MEAN]",
        "solution_code_ko": "var_a = 1000\nvar_b = 2000\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_b=[]\nfor i in list_a:\n    var_d = 0\n    i = int(i)\n    while i//10 > 0:\n        var_d = var_d + i%10\n        i = i//10\n    var_d = var_d + i%10\n    list_b.append(var_d)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)/len(list_b)\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 1000\nvar_b = 2000\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_b=[]\nfor i in list_a:\n    var_d = 0\n    i = int(i)\n    while i//10 > 0:\n        var_d = var_d + i%10\n        i = i//10\n    var_d = var_d + i%10\n    list_b.append(var_d)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)/len(list_b)\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "1635": {
        "category": "Arithmetic calculation",
        "question_ko": "도로 한쪽에 가로등이 34.1미터(m) 간격으로 세워져 있습니다. 도로의 길이가 852.5미터(m)일 때, 도로 한쪽에 세워진 가로등은 모두 몇 개인지 구하시오. 단, 가로등의 두께는 생각하지 않습니다.",
        "question_en": "Streetlights are standing on one side of the road at intervals of 34.1 meters (m). If the length of the road is 852.5 meters (m), find how many streetlights are on one side of the road. The thickness of the streetlight is not considered.",
        "answer_ko": "25",
        "answer_en": "25",
        "solution_abst_ko": "852.5 34.1 [OP_FDIV] 1 [OP_ADD]",
        "solution_abst_en": "852.5 34.1 [OP_FDIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 852.5\nvar_b = 34.1\nvar_c = var_a // var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 852.5\nvar_b = 34.1\nvar_c = var_a // var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "1636": {
        "category": "Comparison",
        "question_ko": "정국이가 아파트 입구에서 엘리베이터를 타고 올라가서 3층에 도착했습니다. 이때 지민이는 같은 아파트 입구에서 계단을 올라 5층을 지나가고 있었습니다. 더 높이 올라간 사람은 누구입니까?",
        "question_en": "JungKook took the elevator from the entrance of the apartment and arrived on the third floor. At this time, Jimin was going up the stairs from the entrance of the same apartment building and passing by the 5th floor. Who climbed higher?",
        "answer_ko": "지민",
        "answer_en": "Jimin",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 지민 [OP_LIST_EOL] [OP_LIST_SOL] 3 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Jimin [OP_LIST_EOL] [OP_LIST_SOL] 3 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '지민'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nvar_d = 5\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Jimin'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nvar_d = 5\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "1637": {
        "category": "Arithmetic calculation",
        "question_ko": "준서네 학교의 1학년 학생은 247명이며, 2학년 학생은 1학년 학생보다 131명 더 많습니다. 1학년 학생과 2학년 학생에게 한 명당 하나씩 빵을 나누어주려고 할 때, 빵은 모두 몇 개 준비해야 합니까?",
        "question_en": "There are 247 first-year students at Junseo's school, and 131 more sophomores than first-year students. If you are going to distribute one loaf to each first grader and second grader, how many loaves do you need to prepare in total?",
        "answer_ko": "625",
        "answer_en": "625",
        "solution_abst_ko": "247 247 131 [OP_ADD] [OP_ADD]",
        "solution_abst_en": "247 247 131 [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 247\nvar_b = 247\nvar_c = 131\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 247\nvar_b = 247\nvar_c = 131\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "1638": {
        "category": "Comparison",
        "question_ko": "신영은 1/3, 석기는 1/4, 웅이는 1/5을 읽었다. 어린이 책을 가장 많이 읽은 사람은 누구입니까?",
        "question_en": "Shinyoung read 1/3, Seokgi 1/4, and Woong 1/5. Who has read the most children's books?",
        "answer_ko": "신영",
        "answer_en": "Shinyoung",
        "solution_abst_ko": "[OP_LIST_SOL] 신영 석기 웅이 [OP_LIST_EOL] [OP_LIST_SOL] 1 3 [OP_DIV] 1 4 [OP_DIV] 1 5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Shinyoung Seokgi Woong [OP_LIST_EOL] [OP_LIST_SOL] 1 3 [OP_DIV] 1 4 [OP_DIV] 1 5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '신영'\nvar_b = '석기'\nvar_c = '웅이'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nvar_e = 3\nvar_f = var_d / var_e\nvar_g = 1\nvar_h = 4\nvar_i = var_g / var_h\nvar_j = 1\nvar_k = 5\nvar_l = var_j / var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'Shinyoung'\nvar_b = 'Seokgi'\nvar_c = 'Woong'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nvar_e = 3\nvar_f = var_d / var_e\nvar_g = 1\nvar_h = 4\nvar_i = var_g / var_h\nvar_j = 1\nvar_k = 5\nvar_l = var_j / var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "1639": {
        "category": "Correspondence",
        "question_ko": "A는 7로 나누었을때 몫이 5 나머지가 3인 수이다. 이때 A를 구하여라.",
        "question_en": "When A is divided by 7, the quotient is 5 and the remainder is 3. Find A here.",
        "answer_ko": "38",
        "answer_en": "38",
        "solution_abst_ko": "5 7 [OP_MUL] 3 [OP_ADD]",
        "solution_abst_en": "5 7 [OP_MUL] 3 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "1640": {
        "category": "Arithmetic calculation",
        "question_ko": "지혜가 할머니 댁에 가기 위해 전체 거리의 1/5는 걷고, 나머지 거리는 버스를 타고 갔다면, 버스를 타고 간 거리는 전체 거리의 몇 배인지 구하시오.",
        "question_en": "If Jihye walked 1/5 of the distance to her grandmother's house and took the bus for the rest of the distance, find how many times the total distance was taken by bus.",
        "answer_ko": "0.80",
        "answer_en": "0.8",
        "solution_abst_ko": "1 1/5 [OP_SUB]",
        "solution_abst_en": "1 1/5 [OP_SUB]",
        "solution_code_ko": "var_a = 1\nvar_b = 0.2\nvar_c = var_a - var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 0.2\nvar_c = var_a - var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "1641": {
        "category": "Possibility",
        "question_ko": "1에서 12까지 총 12개의 숫자가 적힌 12개의 카드가 있다. 이 중 하나를 뽑아 확인하고 다시 집어넣어 한 장을 다시 뽑는 행동을 할 때, 처음에 3의 배수가 나오고 두 번째에 4의 배수가 나오는 경우의 수를 구하시오.",
        "question_en": "There are 12 cards with 12 numbers from 1 to 12. When one of these cards is drawn, checked, and then put back in to draw another card, find the number of times a multiple of 3 comes out the first time and a multiple of 4 comes out the second time.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "1 12 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] [OP_LIST_POP] 4 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] [OP_MUL]",
        "solution_abst_en": "1 12 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] [OP_LIST_POP] 4 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] [OP_MUL]",
        "solution_code_ko": "var_a = 1\nvar_b = 12\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = len(list_b)\nvar_f = 4\nlist_c = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nvar_g = len(list_c)\nvar_h = var_e * var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 1\nvar_b = 12\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = len(list_b)\nvar_f = 4\nlist_c = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nvar_g = len(list_c)\nvar_h = var_e * var_g\nprint(int(var_h))"
    },
    "1642": {
        "category": "Arithmetic calculation",
        "question_ko": "윤혁이는 친구들과 선물상자를 포장하려고 합니다. 선물상자 하나에는 초콜릿 30개를 넣을 수 있고 윤혁이가 가지고 있는 초콜릿은 254개입니다. 이 초콜릿을 선물상자를 가득채워 나눈 후 선물상자에 남는 공간이 없도록 포장하려면 초콜릿 몇 개가 더 필요한 지 구하세요.",
        "question_en": "Yoonhyuk is going to wrap a gift box with his friends. One gift box can hold 30 chocolates, and Yoonhyuk has 254 chocolates. After filling the gift box with these chocolates, find out how many more chocolates he will need so that there is no space left in the gift box.",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "30 254 30 [OP_MOD] [OP_SUB]",
        "solution_abst_en": "30 254 30 [OP_MOD] [OP_SUB]",
        "solution_code_ko": "var_a = 30\nvar_b = 254\nvar_c = 30\nvar_d = var_b % var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 30\nvar_b = 254\nvar_c = 30\nvar_d = var_b % var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "1643": {
        "category": "Arithmetic calculation",
        "question_ko": "민지네 학급의 학생 수는 41명이고, 학교의 남쪽에 사는 학생은 학교의 북쪽에 사는 학생보다 3명 많습니다. 학교의 남쪽에 사는 학생은 몇 명입니까?",
        "question_en": "There are 41 students in Minji's class, and there are 3 more students living on the south side of the school than students living on the north side of the school. How many students live on the south side of the school?",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "41 3 [OP_SUB] 2 [OP_DIV] 3 [OP_ADD]",
        "solution_abst_en": "41 3 [OP_SUB] 2 [OP_DIV] 3 [OP_ADD]",
        "solution_code_ko": "var_a = 41\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 3\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 41\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 3\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "1644": {
        "category": "Comparison",
        "question_ko": "세 사람은 각각 한 장씩 숫자가 적힌 카드를 가지고 있다. 숫자 카드 3개의 평균은 143이며, A의 카드에 4.5를 더한 것이 B와 C 카드의 평균이다. C의 카드에 적힌 수가 B보다 3 작으면, C 숫자 카드에 적힌 수는 얼마인가?",
        "question_en": "Each of the three people has one card with a number on it. The average of the three number cards is 143, and A's card plus 4.5 is the average of B and C's. If the number on C's card is 3 less than B's, what is the number on C's number card?",
        "answer_ko": "143",
        "answer_en": "143",
        "solution_abst_ko": "143 3 [OP_MUL] 4.5 [OP_ADD] 3 [OP_DIV] 2 [OP_MUL] 3 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "143 3 [OP_MUL] 4.5 [OP_ADD] 3 [OP_DIV] 2 [OP_MUL] 3 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 143\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 4.5\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = 3\nvar_k = var_i - var_j\nvar_l = 2\nvar_m = var_k / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 143\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 4.5\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = 3\nvar_k = var_i - var_j\nvar_l = 2\nvar_m = var_k / var_l\nprint(int(var_m))"
    },
    "1645": {
        "category": "Arithmetic calculation",
        "question_ko": "물 135.1리터(L) 가 있습니다. 이것을 7리터(L) 들이 물통에 가득 나누어 담는다면 가득 담을 수 있는 물통은 몇 개입니까?",
        "question_en": "There are 135.1 liters (L) of water. If this is divided into 7 liters (L) buckets of water, how many buckets can be filled?",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "135.1 7 [OP_FDIV]",
        "solution_abst_en": "135.1 7 [OP_FDIV]",
        "solution_code_ko": "var_a = 135.1\nvar_b = 7\nvar_c = var_a // var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 135.1\nvar_b = 7\nvar_c = var_a // var_b\nprint(int(var_c))"
    },
    "1646": {
        "category": "Comparison",
        "question_ko": "구슬을 학생들에게 나누어 주려고 합니다. 9개씩 나누어 주려고 하니 한 개가 부족하고, 10개씩 나누어 주려고 하니 한 학생에게 줄 수 없습니다. 구슬은 총 몇 개입니까?",
        "question_en": "You going to hand out marbles to students. If you hand out 9 for each, it is 1 short, and if you hand out 10 for each, you cannot hand out to a student. How many marbles are there in total?",
        "answer_ko": "100",
        "answer_en": "100",
        "solution_abst_ko": "1 10 [OP_ADD] 10 9 [OP_SUB] [OP_DIV] 9 [OP_MUL] 1 [OP_ADD]",
        "solution_abst_en": "1 10 [OP_ADD] 10 9 [OP_SUB] [OP_DIV] 9 [OP_MUL] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 10\nvar_c = var_a + var_b\nvar_d = 10\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 9\nvar_i = var_g * var_h\nvar_j = 1\nvar_k = var_i + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 1\nvar_b = 10\nvar_c = var_a + var_b\nvar_d = 10\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 9\nvar_i = var_g * var_h\nvar_j = 1\nvar_k = var_i + var_j\nprint(int(var_k))"
    },
    "1647": {
        "category": "Correspondence",
        "question_ko": "A, B는 서로 다른 두 수입니다. A7-3B=55일때 A를 구하시오.",
        "question_en": "A and B are two different numbers. Find A in A7-3B=55.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "A7-3B=55 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A7-3B=55 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A7-3B=55'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A7-3B=55'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "1648": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 소수의 소수점을 오른쪽으로 한 자리 옮겼더니 원래보다 2.7만큼 더 커졌습니다. 원래의 소수를 구하시오.",
        "question_en": "Moving a decimal point to the right by one place makes it 2.7 greater than before. Find the original decimal.",
        "answer_ko": "0.30",
        "answer_en": "0.3",
        "solution_abst_ko": "2.7 10 1 [OP_POW] 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "2.7 10 1 [OP_POW] 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 2.7\nvar_b = 10\nvar_c = 1\nvar_d = var_b ** var_c\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_a / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 2.7\nvar_b = 10\nvar_c = 1\nvar_d = var_b ** var_c\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_a / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "1649": {
        "category": "Geometry",
        "question_ko": "위에서 내려다 봤을 때 가로가 54센티미터(㎝), 세로가 20센티미터(㎝)인 직사각형 모양의 케이크를 3조각으로 나누어 친구들에게 나누어 주려고 합니다. 3조각 모두 위에서 내려다 봤을 때 같은 크기의 정사각형이 되도록 자르려고 합니다. 이때 가장 큰 정사각형을 만들려면 한 변의 길이를 몇 센티미터(㎝)로 해야 합니까? (단, 케이크는 위에서 아래로만 자릅니다.)",
        "question_en": "There is a rectangular cake whose sides are 54 centimeters (cm) long and 20 centimeters (cm) wide when viewed from above. As you try to divide it into 3 pieces to share with friends, you want to cut all 3 pieces into squares of the same size. What should be one side of a square in centimeters (cm) to make the largest square? (Given that the cake is cut only from top to bottom.)",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "[OP_LIST_SOL] 54 3 [OP_FDIV] 20 3 [OP_FDIV] [OP_LIST_EOL] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 54 3 [OP_FDIV] 20 3 [OP_FDIV] [OP_LIST_EOL] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 54\nvar_b = 3\nvar_c = var_a // var_b\nvar_d = 20\nvar_e = 3\nvar_f = var_d // var_e\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nlist_a.reverse()\nvar_g = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_h = list_b[-var_g]\nprint(int(var_h))",
        "solution_code_en": "var_a = 54\nvar_b = 3\nvar_c = var_a // var_b\nvar_d = 20\nvar_e = 3\nvar_f = var_d // var_e\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nlist_a.reverse()\nvar_g = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_h = list_b[-var_g]\nprint(int(var_h))"
    },
    "1650": {
        "category": "Comparison",
        "question_ko": "형준이는 포도맛 사탕을 324개, 딸기맛 사탕을 541개 가지고 있고, 정혁이는 오렌지맛 사탕을 416개, 체리맛 사탕을 253개 가지고 있습니다. 형준이와 정혁이 중 사탕의 개수가 더 많은 사람은 누구입니까?",
        "question_en": "Hyungjun has 324 grape-flavored candies and 541 strawberry-flavored candies, and Junghyeok has 416 orange-flavored candies and 253 cherry-flavored candies. Who has more candies, Hyungjun or Junghyeok?",
        "answer_ko": "형준",
        "answer_en": "Hyungjun",
        "solution_abst_ko": "[OP_LIST_SOL] 형준 정혁 [OP_LIST_EOL] [OP_LIST_SOL] 324 541 [OP_ADD] 416 253 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Hyungjun Junghyeok [OP_LIST_EOL] [OP_LIST_SOL] 324 541 [OP_ADD] 416 253 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '형준'\nvar_b = '정혁'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 324\nvar_d = 541\nvar_e = var_c + var_d\nvar_f = 416\nvar_g = 253\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Hyungjun'\nvar_b = 'Junghyeok'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 324\nvar_d = 541\nvar_e = var_c + var_d\nvar_f = 416\nvar_g = 253\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "1651": {
        "category": "Arithmetic calculation",
        "question_ko": "5명이 서로 손을 잡고 원형으로 서 있다. 손을 잡지 않은 사람과 서로 인사를 한다면 인사는 몇 번 하게되는가?",
        "question_en": "Five people hold each other's hands and stand in a circle. If they greet each other with those not holding hands, how many times do they say hello?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "5 5 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "5 5 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 5\nvar_b = 5\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 5\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "1652": {
        "category": "Comparison",
        "question_ko": "오락실에 똑같은 자판기가 28대 있습니다. 각 자판기는 6층이고, 각 층마다 놓여 있는 음료수의 개수는 같습니다. 어느 자판기의 한 층에서 2개의 음료수를 뽑았을 때 그 층에 3개의 음료수가 남았다고 합니다. 오락실의 자판기들에 들어있는 음료수는 모두 몇 개입니까?",
        "question_en": "There are 28 identical vending machines in the arcade. Each vending machine has 6 sections, and the number of drinks on each section is the same. When two drinks are dispensed from one section of a vending machine, there are three drinks left on that section. How many drinks are in all the vending machines in the arcade?",
        "answer_ko": "840",
        "answer_en": "840",
        "solution_abst_ko": "3 2 [OP_ADD] 6 [OP_MUL] 28 [OP_MUL]",
        "solution_abst_en": "3 2 [OP_ADD] 6 [OP_MUL] 28 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 6\nvar_e = var_c * var_d\nvar_f = 28\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 6\nvar_e = var_c * var_d\nvar_f = 28\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "1653": {
        "category": "Comparison",
        "question_ko": "어느 공장에서 곰인형은 30분에 500개를 만들고, 토끼인형은 1시간에 800개를 만듭니다. 5시간 후에는 어느 것이 더 많이 만들어질지 구하시오.",
        "question_en": "One factory makes 500 teddy bears in 30 minutes and 800 bunny dolls in 1 hour. Find which one will produce more after 5 hours.",
        "answer_ko": "곰인형",
        "answer_en": "bear",
        "solution_abst_ko": "[OP_LIST_SOL] 곰인형 토끼인형 [OP_LIST_EOL] [OP_LIST_SOL] 5 60 [OP_MUL] 30 [OP_FDIV] 500 [OP_MUL] 5 60 [OP_MUL] 60 [OP_FDIV] 800 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] bear bunny [OP_LIST_EOL] [OP_LIST_SOL] 5 60 [OP_MUL] 30 [OP_FDIV] 500 [OP_MUL] 5 60 [OP_MUL] 60 [OP_FDIV] 800 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '곰인형'\nvar_b = '토끼인형'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 5\nvar_d = 60\nvar_e = var_c * var_d\nvar_f = 30\nvar_g = var_e // var_f\nvar_h = 500\nvar_i = var_g * var_h\nvar_j = 5\nvar_k = 60\nvar_l = var_j * var_k\nvar_m = 60\nvar_n = var_l // var_m\nvar_o = 800\nvar_p = var_n * var_o\nlist_b= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nlist_b.reverse()\nvar_q = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_r = list_c[-var_q]\nvar_s = list_b.index(var_r)+1\nvar_t = list_a[var_s-1]\nprint(var_t)",
        "solution_code_en": "var_a = 'bear'\nvar_b = 'bunny'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 5\nvar_d = 60\nvar_e = var_c * var_d\nvar_f = 30\nvar_g = var_e // var_f\nvar_h = 500\nvar_i = var_g * var_h\nvar_j = 5\nvar_k = 60\nvar_l = var_j * var_k\nvar_m = 60\nvar_n = var_l // var_m\nvar_o = 800\nvar_p = var_n * var_o\nlist_b= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nlist_b.reverse()\nvar_q = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_r = list_c[-var_q]\nvar_s = list_b.index(var_r)+1\nvar_t = list_a[var_s-1]\nprint(var_t)"
    },
    "1654": {
        "category": "Correspondence",
        "question_ko": "호석이는 어떤 수를 10으로 나누어 6을 얻었습니다. 어떤 수에서 15를 뺀 결과는 얼마입니까?",
        "question_en": "Hoseok divided a certain number by 10 to get 6. What is the result of subtracting 15 from the number?",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "6 10 [OP_MUL] 15 [OP_SUB]",
        "solution_abst_en": "6 10 [OP_MUL] 15 [OP_SUB]",
        "solution_code_ko": "var_a = 6\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 15\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 15\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "1655": {
        "category": "Geometry",
        "question_ko": "직선 도로에 전신주 45개가 60미터(m) 간격으로 일렬로 세워져 있다면, 가장 멀리 있는 두 전신주 사이의 거리는 몇 킬로미터(㎞)인지 구하시오.",
        "question_en": "If 45 utility poles are lined up on a straight road at intervals of 60 meters (m), what is the distance in kilometers (km) between the two poles that are farthest apart?",
        "answer_ko": "2.64",
        "answer_en": "2.64",
        "solution_abst_ko": "60 1000 [OP_DIV] 45 1 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "60 1000 [OP_DIV] 45 1 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 60\nvar_b = 1000\nvar_c = var_a / var_b\nvar_d = 45\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_c * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 60\nvar_b = 1000\nvar_c = var_a / var_b\nvar_d = 45\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_c * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "1656": {
        "category": "Arithmetic calculation",
        "question_ko": "숫자 4, 5로 나누어 떨어질 수 있는 세 자리 수는 모두 몇 개 있습니까?",
        "question_en": "How many three-digit numbers are divisible by 4 and 5?",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "100 999 1 [OP_LIST_ARANGE] 4 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "100 999 1 [OP_LIST_ARANGE] 4 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 4\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 4\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "1657": {
        "category": "Geometry",
        "question_ko": "윗변이 5센티미터(㎝), 아랫변이 9센티미터(㎝)인 사다리꼴의 넓이가 56제곱센티미터(㎠)일 떄, 이 사다리꼴의 높이는 몇 센티미터(㎝)입니까?",
        "question_en": "If the area of a trapezoid with an upper side of 5 centimeters (cm) and a lower side of 9 centimeters (cm) is 56 square centimeters (cm2), what is the height in centimeters (cm) of the trapezoid?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "56 2 [OP_MUL] 5 9 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "56 2 [OP_MUL] 5 9 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 56\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = 9\nvar_f = var_d + var_e\nvar_g = var_c / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 56\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = 9\nvar_f = var_d + var_e\nvar_g = var_c / var_f\nprint(int(var_g))"
    },
    "1658": {
        "category": "Arithmetic calculation",
        "question_ko": "수환이가 탄 자동차는 10분동안 15.5킬로미터(㎞)를 이동하였습니다. 이와 같은 빠르기로 46분 동안 달리면 몇 킬로미터(㎞)를 이동하겠습니까?",
        "question_en": "Suhwan's car traveled 15.5 kilometers (km) in 10 minutes. How many kilometers (km) would he travel in 46 minutes at this speed?",
        "answer_ko": "71.30",
        "answer_en": "71.3",
        "solution_abst_ko": "15.5 10 [OP_DIV] 46 [OP_MUL]",
        "solution_abst_en": "15.5 10 [OP_DIV] 46 [OP_MUL]",
        "solution_code_ko": "var_a = 15.5\nvar_b = 10\nvar_c = var_a / var_b\nvar_d = 46\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 15.5\nvar_b = 10\nvar_c = var_a / var_b\nvar_d = 46\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "1659": {
        "category": "Geometry",
        "question_ko": "동전을 정사각형 모양으로 줄세웠더니 둘레에 놓인 동전의 개수가 240개였다면, 동전의 전체의 개수는 몇 개입니까?",
        "question_en": "If the coins are arranged in a square and there are 240 coins at the perimeter, what is the total number of coins?",
        "answer_ko": "3721",
        "answer_en": "3721",
        "solution_abst_ko": "240 4 [OP_DIV] 1 [OP_ADD] 2 [OP_POW]",
        "solution_abst_en": "240 4 [OP_DIV] 1 [OP_ADD] 2 [OP_POW]",
        "solution_code_ko": "var_a = 240\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e ** var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 240\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e ** var_f\nprint(int(var_g))"
    },
    "1660": {
        "category": "Geometry",
        "question_ko": "길이가 32센티미터(㎝) 인 끈으로 가장 큰 정사각형을 만들려고 합니다. 정사각형의 넓이는 몇 제곱센티미터(㎠) 입니까?",
        "question_en": "You want to make the largest square out of a piece of string that is 32 centimeters (cm) long. What is the area of the square in square centimeters (cm2)?",
        "answer_ko": "64",
        "answer_en": "64",
        "solution_abst_ko": "32 4 [OP_DIV] 2 [OP_POW]",
        "solution_abst_en": "32 4 [OP_DIV] 2 [OP_POW]",
        "solution_code_ko": "var_a = 32\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 32\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint(int(var_e))"
    },
    "1661": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 2번째로 큰 수와 가장 작은 수의 차는 얼마입니까?",
        "question_en": "There are five numbers 10, 11, 12, 13, and 14. What is the answer when subtracting the second largest number by the smallest number?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 2 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 2 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))"
    },
    "1662": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 16센티미터(㎝)인 정사각형 안에 가장 큰 원을 그린 다음, 원 안에 가장 큰 마름모를 그렸습니다. 마름모의 넓이는 몇 제곱센티미터입니까?",
        "question_en": "The largest circle was drawn inside a square with a side length of 16 centimeters (cm), and the largest rhombus was drawn inside the circle. What is the area of the rhombus in square centimeters?",
        "answer_ko": "128",
        "answer_en": "128",
        "solution_abst_ko": "16 16 [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "16 16 [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 16\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 16\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "1663": {
        "category": "Comparison",
        "question_ko": "민영이가 교실 사물함들 중 앞에서 8번째 칸, 뒤에서 14번째 칸, 왼쪽에서 7번째 칸, 오른쪽에서 13번째 칸에 가방을 넣었습니다. 교실 안 사물함의 총 개수는 몇 개입니까?",
        "question_en": "Minyoung puts her bag in the locker that is 8th from the front, 14th from the back, 7th from the left, and 13th from the right among the classroom lockers. What is the total number of lockers in the classroom?",
        "answer_ko": "399",
        "answer_en": "399",
        "solution_abst_ko": "8 14 [OP_ADD] 1 [OP_SUB] 7 13 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "8 14 [OP_ADD] 1 [OP_SUB] 7 13 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 14\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 7\nvar_g = 13\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 8\nvar_b = 14\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 7\nvar_g = 13\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))"
    },
    "1664": {
        "category": "Possibility",
        "question_ko": "정국이와 은지가 색종이를 나누어 가지려고 합니다. 색종이가 15장 있을 때, 정국이와 은지가 최소 1장씩은 가지도록 나누어 주는 방법은 몇 가지입니까?",
        "question_en": "Jungkook and Eunji are trying to share pieces of colored paper. When there are 15 pieces of colored paper, how many ways are there to divide them so that Jungkook and Eunji both have at least one piece?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "15 2 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "15 2 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 15\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "1665": {
        "category": "Geometry",
        "question_ko": "둘레의 길이가 80센티미터(㎝)인 정다각형의 한 변의 길이는 16센티미터(㎝)라고 합니다. 이 정다각형에는 총 몇 개의 꼭짓점이 있습니까?",
        "question_en": "A regular polygon with a perimeter of 80 centimeters (cm) has a side length of 16 centimeters (cm). How many vertices are there in this regular polygon?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "80 16 [OP_DIV]",
        "solution_abst_en": "80 16 [OP_DIV]",
        "solution_code_ko": "var_a = 80\nvar_b = 16\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 80\nvar_b = 16\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "1666": {
        "category": "Comparison",
        "question_ko": "여명이가 버스를 타고 학교를 가면 이동 거리가 7150미터(m)이고, 자전거를 타고 학교를 가면 이동 거리가 6킬로미터(㎞) 720미터(m)입니다. 버스와 자전거 중 이동 거리가 더 짧은 교통수단은 무엇입니까?",
        "question_en": "When Yeomyeong goes to school by bus, she travels 7150 meters (m), and when she goes to school by bicycle, she travels 6 kilometers (km) and 720 meters (m). Which transportation travels a shorter distance, bus or bicycle?",
        "answer_ko": "자전거",
        "answer_en": "bicycle",
        "solution_abst_ko": "[OP_LIST_SOL] 버스 자전거 [OP_LIST_EOL] [OP_LIST_SOL] 7150 6 1000 [OP_MUL] 720 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] bus bicycle [OP_LIST_EOL] [OP_LIST_SOL] 7150 6 1000 [OP_MUL] 720 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '버스'\nvar_b = '자전거'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 7150\nvar_d = 6\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = 720\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'bus'\nvar_b = 'bicycle'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 7150\nvar_d = 6\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = 720\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "1667": {
        "category": "Possibility",
        "question_ko": "정십이면체의 각 면에 1부터 12까지 각각 적힌 주사위를 두 번 던질 때, 첫 번째는 3의 배수가 나오고, 두 번째는 4의 배수가 나오는 경우의 수를 구하시오.",
        "question_en": "When two dice with numbers 1 to 12 written on each side of the dodecahedron are thrown twice, find the number of cases a multiple of 3 comes up at the first time and a multiple of 4 comes up at the second time.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "1 12 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] [OP_LIST_POP] 4 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] [OP_MUL]",
        "solution_abst_en": "1 12 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] [OP_LIST_POP] 4 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] [OP_MUL]",
        "solution_code_ko": "var_a = 1\nvar_b = 12\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = len(list_b)\nvar_f = 4\nlist_c = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nvar_g = len(list_c)\nvar_h = var_e * var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 1\nvar_b = 12\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = len(list_b)\nvar_f = 4\nlist_c = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nvar_g = len(list_c)\nvar_h = var_e * var_g\nprint(int(var_h))"
    },
    "1668": {
        "category": "Correspondence",
        "question_ko": "두 개의 자연수 A와 B가 있습니다. B가 A에 9를 곱하고 13을 더한 수라면 B를 9로 나눈 나머지는 얼마입니까?",
        "question_en": "There are two natural numbers A and B. If B is A multiplied by 9 and plus 13, what is the remainder when B is divided by 9?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "13 9 [OP_SUB]",
        "solution_abst_en": "13 9 [OP_SUB]",
        "solution_code_ko": "var_a = 13\nvar_b = 9\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 13\nvar_b = 9\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "1669": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 2.4 로 나누어야 할 것을 잘못하여 곱하였더니 288 이 되었습니다. 바르게 계산한 값을 5로 나누면 얼마입니까?",
        "question_en": "When you wrongly multiplied a number that should have been divided by 2.4, you got 288. What is the correctly calculated value divided by 5?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "288 2.4 [OP_DIV] 2.4 [OP_DIV] 5 [OP_DIV]",
        "solution_abst_en": "288 2.4 [OP_DIV] 2.4 [OP_DIV] 5 [OP_DIV]",
        "solution_code_ko": "var_a = 288\nvar_b = 2.4\nvar_c = var_a / var_b\nvar_d = 2.4\nvar_e = var_c / var_d\nvar_f = 5\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 288\nvar_b = 2.4\nvar_c = var_a / var_b\nvar_d = 2.4\nvar_e = var_c / var_d\nvar_f = 5\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "1670": {
        "category": "Comparison",
        "question_ko": "(가) 원의 넓이는 25제곱센티미터(㎠)이고, (나) 원의 넓이는 49제곱센티미터(㎠)입니다. 원주율이 3.1이라면 (가)와 (나) 중 더 넓은 원의 지름의 길이는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "The area of A circle is 25 square centimeters (cm2), and the area of B circle is 49 square centimeters (cm2). If pi is 3.1, how many centimeters (cm) is the diameter of the larger circle in A or B?",
        "answer_ko": "7.95",
        "answer_en": "7.95",
        "solution_abst_ko": "[OP_LIST_SOL] 25 49 [OP_LIST_EOL] 1 [OP_LIST_MAX] 3.1 [OP_DIV] 0.5 [OP_POW] 2 [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 25 49 [OP_LIST_EOL] 1 [OP_LIST_MAX] 3.1 [OP_DIV] 0.5 [OP_POW] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 25\nvar_b = 49\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[-var_c]\nvar_e = 3.1\nvar_f = var_d / var_e\nvar_g = 0.5\nvar_h = var_f ** var_g\nvar_i = 2\nvar_j = var_h * var_i\nprint('{:.2f}'.format(round(var_j+1e-10,2)))",
        "solution_code_en": "var_a = 25\nvar_b = 49\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[-var_c]\nvar_e = 3.1\nvar_f = var_d / var_e\nvar_g = 0.5\nvar_h = var_f ** var_g\nvar_i = 2\nvar_j = var_h * var_i\nprint('{:.2f}'.format(round(var_j+1e-10,2)))"
    },
    "1671": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 2.5로 나눈 후 10.5를 빼고, 그 값에 0.3을 곱하면 5.85가 됩니다. 어떤 수를 구하시오.",
        "question_en": "Divide this number by 2.5, subtract 10.5 from it, and multiply that by 0.3 to get 5.85. Find this number.",
        "answer_ko": "75",
        "answer_en": "75",
        "solution_abst_ko": "5.85 0.3 [OP_DIV] 10.5 [OP_ADD] 2.5 [OP_MUL]",
        "solution_abst_en": "5.85 0.3 [OP_DIV] 10.5 [OP_ADD] 2.5 [OP_MUL]",
        "solution_code_ko": "var_a = 5.85\nvar_b = 0.3\nvar_c = var_a / var_b\nvar_d = 10.5\nvar_e = var_c + var_d\nvar_f = 2.5\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 5.85\nvar_b = 0.3\nvar_c = var_a / var_b\nvar_d = 10.5\nvar_e = var_c + var_d\nvar_f = 2.5\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "1672": {
        "category": "Correspondence",
        "question_ko": "준형이는 저녁마다 공원에 나가 8050미터(m)를 달린다. 준형이가 지금까지 80.5미터(m)를 달렸다면 전체의 얼마에 해당하는 거리를 달린 것인지 구하시오.",
        "question_en": "Junhyung goes to the park every evening and runs 8050 meters (m). If Junhyung has run 80.5 meters (m) so far, find what percentage of the total distance was run.",
        "answer_ko": "0.01",
        "answer_en": "0.01",
        "solution_abst_ko": "80.5 8050 [OP_DIV]",
        "solution_abst_en": "80.5 8050 [OP_DIV]",
        "solution_code_ko": "var_a = 80.5\nvar_b = 8050\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 80.5\nvar_b = 8050\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "1673": {
        "category": "Possibility",
        "question_ko": "4, 5, 6, 7, 8 중에서 서로 다른 숫자 2개를 사용하여 만들 수 있는 두 자리 수는 모두 몇 개입니까?",
        "question_en": "How many two-digit numbers can you make from 4, 5, 6, 7, and 8 using two different numbers?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "[OP_LIST_SOL] 4 5 6 7 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 4 5 6 7 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 4\nvar_b = 5\nvar_c = 6\nvar_d = 7\nvar_e = 8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 5\nvar_c = 6\nvar_d = 7\nvar_e = 8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "1674": {
        "category": "Correspondence",
        "question_ko": "소수 두 자리 수 중 소수점 둘째 자리에서 반올림하면 3.5가 되는 가장 큰 수와 가장 작은 수의 합을 구하시오",
        "question_en": "Find the sum of the largest and the smallest numbers that becomes 3.5 when numbers with two decimals are rounded from two decimal places.",
        "answer_ko": "6.99",
        "answer_en": "6.99",
        "solution_abst_ko": "3.45 3.54 [OP_ADD]",
        "solution_abst_en": "3.45 3.54 [OP_ADD]",
        "solution_code_ko": "var_a = 3.45\nvar_b = 3.54\nvar_c = var_a + var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 3.45\nvar_b = 3.54\nvar_c = var_a + var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "1675": {
        "category": "Possibility",
        "question_ko": "숫자 카드 1, 3, 5, 6을 한 번씩 사용하여 네 자리 수를 만들 때, 4로 나눈 나머지가 0인 수는 몇 가지인가?",
        "question_en": "If you use the number cards 1, 3, 5, and 6 once each to make a four-digit number, how many numbers divided by 4 have a remainder of 0?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 5 6 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 4 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 5 6 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 4 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 5\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 4\nlist_c = []\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nvar_g = len(list_c)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 5\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 4\nlist_c = []\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nvar_g = len(list_c)\nprint(int(var_g))"
    },
    "1676": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.3, 1/3 중 0.4보다 크거나 같은 수의 총합은?",
        "question_en": "What is the sum of the numbers greater than or equal to 0.4 among 0.8, 1/2, 0.3, and 1/3?",
        "answer_ko": "1.30",
        "answer_en": "1.3",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.3 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_MORE_EQUAL] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.3 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_MORE_EQUAL] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.3\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.4\nlist_b = []\nfor i in list_a:\n    if i >= var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint('{:.2f}'.format(round(var_f+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.3\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.4\nlist_b = []\nfor i in list_a:\n    if i >= var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint('{:.2f}'.format(round(var_f+1e-10,2)))"
    },
    "1677": {
        "category": "Geometry",
        "question_ko": "세로의 길이가 가로의 길이보다 3 센티미터(㎝) 더 짧은 직사각형의 둘레의 길이가 54 센티미터(㎝)일 때, 가로의 길이를 구하시오.",
        "question_en": "If the perimeter of a rectangle whose length is 3 centimeters (cm) shorter than its width is 54 centimeters (cm), find its width.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "54 2 [OP_DIV] 3 [OP_SUB] 2 [OP_DIV] 3 [OP_ADD]",
        "solution_abst_en": "54 2 [OP_DIV] 3 [OP_SUB] 2 [OP_DIV] 3 [OP_ADD]",
        "solution_code_ko": "var_a = 54\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 3\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 3\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 54\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 3\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 3\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "1678": {
        "category": "Possibility",
        "question_ko": "운동장에 있는 8명의 학생 중, 5명을 뽑아 차례대로 세우는 경우의 수를 구하시오.",
        "question_en": "Find the number of ways in which 5 of the 8 students on the playground are picked and placed in order.",
        "answer_ko": "6720",
        "answer_en": "6720",
        "solution_abst_ko": "8 5 [OP_PERM]",
        "solution_abst_en": "8 5 [OP_PERM]",
        "solution_code_ko": "var_a = 8\nvar_b = 5\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))",
        "solution_code_en": "var_a = 8\nvar_b = 5\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))"
    },
    "1679": {
        "category": "Correspondence",
        "question_ko": "280은 70으로 나누어떨어집니다. 280보다 큰 수 중에서 70으로 나누었을 때 나머지가 30이 되는 가장 작은 수를 구하세요.",
        "question_en": "280 is divisible by 70. Find the smallest number greater than 280 that, when divided by 70, has a remainder of 30.",
        "answer_ko": "310",
        "answer_en": "310",
        "solution_abst_ko": "280 30 [OP_ADD]",
        "solution_abst_en": "280 30 [OP_ADD]",
        "solution_code_ko": "var_a = 280\nvar_b = 30\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 280\nvar_b = 30\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "1680": {
        "category": "Arithmetic calculation",
        "question_ko": "0.8킬로그램(㎏)짜리의 바나나 9개와 무게를 알 수 없는 사과 7개가 있습니다. 바나나 9개와 사과 7개의 무게를 합했더니 10.98킬로그램(㎏)이었습니다. 사과의 무게가 모두 같다면 사과 한 개는 몇 킬로그램(㎏)입니까?",
        "question_en": "There are 9 bananas weighing 0.8 kilograms (kg) and 7 apples of unknown weight. The total weight of 9 bananas and 7 apples was 10.98 kilograms (kg). If all apples weigh the same, how many kilograms (kg) is one apple?",
        "answer_ko": "0.54",
        "answer_en": "0.54",
        "solution_abst_ko": "10.98 0.8 9 [OP_MUL] [OP_SUB] 7 [OP_DIV]",
        "solution_abst_en": "10.98 0.8 9 [OP_MUL] [OP_SUB] 7 [OP_DIV]",
        "solution_code_ko": "var_a = 10.98\nvar_b = 0.8\nvar_c = 9\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 7\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 10.98\nvar_b = 0.8\nvar_c = 9\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 7\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "1681": {
        "category": "Correspondence",
        "question_ko": "423에 어떤 수를 곱해야 할 것을 잘못하여 뺐더니 421이 되었습니다. 바르게 계산한 값과 잘못 계산한 값의 합에서 500을 뺀 값을 구하시오.",
        "question_en": "I mistakenly subtracted a number that should be multiplied by 423, and I got 421. Find the value of subtracting 500 from the sum of the correctly calculated and incorrectly calculated values.",
        "answer_ko": "767",
        "answer_en": "767",
        "solution_abst_ko": "421 423 423 421 [OP_SUB] [OP_MUL] [OP_ADD] 500 [OP_SUB]",
        "solution_abst_en": "421 423 423 421 [OP_SUB] [OP_MUL] [OP_ADD] 500 [OP_SUB]",
        "solution_code_ko": "var_a = 421\nvar_b = 423\nvar_c = 423\nvar_d = 421\nvar_e = var_c - var_d\nvar_f = var_b * var_e\nvar_g = var_a + var_f\nvar_h = 500\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 421\nvar_b = 423\nvar_c = 423\nvar_d = 421\nvar_e = var_c - var_d\nvar_f = var_b * var_e\nvar_g = var_a + var_f\nvar_h = 500\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "1682": {
        "category": "Possibility",
        "question_ko": "하진이는 자물쇠 비밀번호를 찾고 싶다. 비밀번호의 각 숫자는 모두 다르며, 1, 7, 4, 3 중 세 개로 구성되어 있고 십의 자리 수가 3이다. 비밀번호가 될 수 있는 수 중 가장 큰 세 자리수와 세 번째로 큰 세 자리수의 합을 구하시오.",
        "question_en": "Hajin wants to find the password of a lock. The password is set with one of the three numbers: 1, 7, 4, with the tens digit of 3. When password has all different numbers, find the sum of the largest and the third largest three-digit number that can be a password.",
        "answer_ko": "1171",
        "answer_en": "1171",
        "solution_abst_ko": "[OP_LIST_SOL] 1 7 4 3 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 3 [OP_LIST_SEARCH_FIXED_DIGIT] 1 [OP_LIST_MAX] 3 [OP_LIST_MAX] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 1 7 4 3 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 3 [OP_LIST_SEARCH_FIXED_DIGIT] 1 [OP_LIST_MAX] 3 [OP_LIST_MAX] [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 7\nvar_c = 4\nvar_d = 3\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 3\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nvar_j = 3\nlist_e=list_c.copy()\nlist_e.sort()\nvar_k = list_e[-var_j]\nvar_l = var_i + var_k\nprint(int(var_l))",
        "solution_code_en": "var_a = 1\nvar_b = 7\nvar_c = 4\nvar_d = 3\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 3\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nvar_j = 3\nlist_e=list_c.copy()\nlist_e.sort()\nvar_k = list_e[-var_j]\nvar_l = var_i + var_k\nprint(int(var_l))"
    },
    "1683": {
        "category": "Arithmetic calculation",
        "question_ko": "튤립이 56송이 있습니다. 빨간색 튤립은 전체의 3/7입니다. 파란색 튤립은 전체의 3/8입니다. 나머지는 분홍색 튤립이라면 분홍색 튤립은 몇 송이입니까?",
        "question_en": "There are 56 tulips. Red tulips are 3/7 of the total. Blue tulips are 3/8 of the total. If the rest are pink tulips, how many pink tulips are there?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "56 56 3/7 [OP_MUL] 56 3/8 [OP_MUL] [OP_ADD] [OP_SUB]",
        "solution_abst_en": "56 56 3/7 [OP_MUL] 56 3/8 [OP_MUL] [OP_ADD] [OP_SUB]",
        "solution_code_ko": "var_a = 56\nvar_b = 56\nvar_c = 0.42857142857142855\nvar_d = var_b * var_c\nvar_e = 56\nvar_f = 0.375\nvar_g = var_e * var_f\nvar_h = var_d + var_g\nvar_i = var_a - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 56\nvar_b = 56\nvar_c = 0.42857142857142855\nvar_d = var_b * var_c\nvar_e = 56\nvar_f = 0.375\nvar_g = var_e * var_f\nvar_h = var_d + var_g\nvar_i = var_a - var_h\nprint(int(var_i))"
    },
    "1684": {
        "category": "Correspondence",
        "question_ko": "A+10=15일 때, A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "If A+10=15, what number should be A?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "A+10=15 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A+10=15 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A+10=15'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A+10=15'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "1685": {
        "category": "Arithmetic calculation",
        "question_ko": "한 변의 길이가 2미터(m)인 정사각형 모양의 분수가 있습니다. 이 분수의 한 쪽에 3개의 의자가 있을 때 의자의 길이는 몇 미터(m)인지 소수로 나타내시오.",
        "question_en": "There is a fountain in the shape of an equilateral triangle with a side length of 2 meters (m). If there are 3 chairs on one side of this fountain, how many meters (m) are the lengths of the chairs as a decimal number?",
        "answer_ko": "0.67",
        "answer_en": "0.67",
        "solution_abst_ko": "2 3 [OP_DIV]",
        "solution_abst_en": "2 3 [OP_DIV]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "1686": {
        "category": "Arithmetic calculation",
        "question_ko": "태형이는 줄넘기를 하루에 56번씩 3일 동안 했고 남준이는 하루에 35번씩 4일 동안 했습니다. 태형이와 남준이가 한 줄넘기의 횟수는 모두 몇 번입니까?",
        "question_en": "Taehyung jumped rope 56 times a day for 3 days and Namjoon did 35 times a day for 4 days. How many times did Taehyung and Namjoon jump rope?",
        "answer_ko": "308",
        "answer_en": "308",
        "solution_abst_ko": "56 3 [OP_MUL] 35 4 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "56 3 [OP_MUL] 35 4 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 56\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 35\nvar_e = 4\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 56\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 35\nvar_e = 4\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "1687": {
        "category": "Geometry",
        "question_ko": "정십이면체 모양의 상자가 있습니다. 이 상자의 꼭짓점의 개수는?",
        "question_en": "You have a box in the shape of a regular dodecahedron. How many vertices does this box have?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "20",
        "solution_abst_en": "20",
        "solution_code_ko": "var_a = 20\nprint(int(var_a))",
        "solution_code_en": "var_a = 20\nprint(int(var_a))"
    },
    "1688": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 30미터(m)인 정사각형 모양의 공원이 있습니다. 이 공원에 반지름이 3미터(m)인 호수를 여러개 만들려고 합니다. 호수는 최대 몇 개 만들 수 있습니까?",
        "question_en": "There is a fountain in the shape of a square with sides measuring 2 meters (m). We are going to create several lakes with a radius of 3 meters (m) in this park. How many lakes can you create?",
        "answer_ko": "25",
        "answer_en": "25",
        "solution_abst_ko": "30 3 2 [OP_MUL] [OP_FDIV] 2 [OP_POW]",
        "solution_abst_en": "30 3 2 [OP_MUL] [OP_FDIV] 2 [OP_POW]",
        "solution_code_ko": "var_a = 30\nvar_b = 3\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a // var_d\nvar_f = 2\nvar_g = var_e ** var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 30\nvar_b = 3\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a // var_d\nvar_f = 2\nvar_g = var_e ** var_f\nprint(int(var_g))"
    },
    "1689": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 3을 빼면 5의 배수이고, 2를 빼면 7의 배수이다. 어떤 수가 50보다 크고 70보다 작을 때, 어떤 수가 얼마인지 구하시오.",
        "question_en": "There is a number that is a multiple of 5 when subtracted by 3, a multiple of 7 when subtracted by 2. If a number is greater than 50 and less than 70, what is this number?",
        "answer_ko": "58",
        "answer_en": "58",
        "solution_abst_ko": "50 70 1 [OP_SUB] 1 [OP_LIST_ARANGE] 5 3 [OP_LIST_DIVIDE_AND_REMAIN] 7 2 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "50 70 1 [OP_SUB] 1 [OP_LIST_ARANGE] 5 3 [OP_LIST_DIVIDE_AND_REMAIN] 7 2 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 50\nvar_b = 70\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nvar_f = 5\nvar_g = 3\nlist_b = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_a:\n    i = int(i)\n    if i%var_f == var_g:\n        list_b.append(i)\nvar_h = 7\nvar_i = 2\nlist_c = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_b:\n    i = int(i)\n    if i%var_h == var_i:\n        list_c.append(i)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(int(var_k))",
        "solution_code_en": "var_a = 50\nvar_b = 70\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nvar_f = 5\nvar_g = 3\nlist_b = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_a:\n    i = int(i)\n    if i%var_f == var_g:\n        list_b.append(i)\nvar_h = 7\nvar_i = 2\nlist_c = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_b:\n    i = int(i)\n    if i%var_h == var_i:\n        list_c.append(i)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(int(var_k))"
    },
    "1690": {
        "category": "Correspondence",
        "question_ko": "축구경기가 있는 날, 물 12병과 음료수 34병을 선수들에게 주었다. 축구 경기가 끝난 후 남은 물과 음료수를 모두 세보니 30병이었다. 선수들이 마신 음료수의 병 수는 선수들이 마신 물병 수의 3배이다. 선수들이 마신 물은 몇 병인가?",
        "question_en": "On the day of the soccer match, 12 bottles of water and 34 bottles of soda were given to the players. After the soccer game, I counted all the remaining water and drinks and it was 30 bottles. The number of bottles of drink consumed by the players is three times the number of bottles of water consumed by the players. How many bottles of water did the players drink?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "12 34 [OP_ADD] 30 [OP_SUB] 1 3 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "12 34 [OP_ADD] 30 [OP_SUB] 1 3 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 34\nvar_c = var_a + var_b\nvar_d = 30\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = 3\nvar_h = var_f + var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 12\nvar_b = 34\nvar_c = var_a + var_b\nvar_d = 30\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = 3\nvar_h = var_f + var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "1691": {
        "category": "Arithmetic calculation",
        "question_ko": "사회를 좋아하는 학생은 (가) 반 학생 중 25명입니다. 음악을 좋아한다고 투표한 학생은 32명이고, 사회와 음악 모두에 투표한 학생은 27명이었습니다. 모든 학생이 둘 중 하나는 투표했을 때, (가) 반에는 모두 몇 명의 학생이 있습니까?",
        "question_en": "Students who like society are 25 students in class (A). 32 students voted to like music, and 27 students voted to both social studies and music. If every student voted for one or the other, how many students are in class (A)?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "25 32 [OP_ADD] 27 [OP_SUB]",
        "solution_abst_en": "25 32 [OP_ADD] 27 [OP_SUB]",
        "solution_code_ko": "var_a = 25\nvar_b = 32\nvar_c = var_a + var_b\nvar_d = 27\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 25\nvar_b = 32\nvar_c = var_a + var_b\nvar_d = 27\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "1692": {
        "category": "Arithmetic calculation",
        "question_ko": "남준이는 트럭 3대가 있고, 태형이는 트럭 2대가 있습니다. 남준이와 태형이가 갖고있는 트럭은 몇 대 인가요?",
        "question_en": "Namjoon has 3 trucks and Taehyung has 2 trucks. How many trucks do Namjoon and Taehyung have?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "3 2 [OP_ADD]",
        "solution_abst_en": "3 2 [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "1693": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 50센티미터(㎝)인 정삼각형 모양의 거울이 있습니다. 이 거울의 둘레에 10센티미터(㎝) 간격으로 조명을 설치할 때 조명은 모두 몇 개가 필요합니까?",
        "question_en": "There is a mirror in the shape of a regular triangle with a side length of 50 centimeters (cm). If you want to place the lights around the perimeter of this mirror with 10 centimeters (cm) of intervals, how many lights do you need?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "50 3 [OP_MUL] 10 [OP_FDIV]",
        "solution_abst_en": "50 3 [OP_MUL] 10 [OP_FDIV]",
        "solution_code_ko": "var_a = 50\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 10\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 50\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 10\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "1694": {
        "category": "Comparison",
        "question_ko": "100보다 작은 3의 배수를 작은 수부터 차례대로 썼습니다. 왼쪽에서 21번째와 24번째에 있는 수의 사이에 있는 수들의 곱을 구하시오.",
        "question_en": "The multiples of 3 less than 100 are written in order from smallest to biggest. Find the product of the numbers between the 21st and 24th numbers from the left.",
        "answer_ko": "4554",
        "answer_en": "4554",
        "solution_abst_ko": "0 3 [OP_ADD] 100 3 [OP_LIST_ARANGE] 22 [OP_LIST_MIN] 23 [OP_LIST_MIN] [OP_MUL]",
        "solution_abst_en": "0 3 [OP_ADD] 100 3 [OP_LIST_ARANGE] 22 [OP_LIST_MIN] 23 [OP_LIST_MIN] [OP_MUL]",
        "solution_code_ko": "var_a = 0\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 100\nvar_e = 3\nlist_a = [i for i in range(var_c, var_d + 1, var_e)]\nvar_f = 22\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nvar_h = 23\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g * var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 0\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 100\nvar_e = 3\nlist_a = [i for i in range(var_c, var_d + 1, var_e)]\nvar_f = 22\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nvar_h = 23\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g * var_i\nprint(int(var_j))"
    },
    "1695": {
        "category": "Arithmetic calculation",
        "question_ko": "넓이가 2.4제곱미터(㎡)인 밭의 1/3에 배추를 심고, 나머지의 1/4에 고추를 심었다. 고추를 심은 밭의 넓이를 구하여라.",
        "question_en": "Cabbage was planted in 1/3 of the 2.4 square meters (m2) field, and peppers were planted in the remaining 1/4. Find the area of the field where the peppers were planted.",
        "answer_ko": "0.40",
        "answer_en": "0.4",
        "solution_abst_ko": "2.4 1 1/3 [OP_SUB] [OP_MUL] 1/4 [OP_MUL]",
        "solution_abst_en": "2.4 1 1/3 [OP_SUB] [OP_MUL] 1/4 [OP_MUL]",
        "solution_code_ko": "var_a = 2.4\nvar_b = 1\nvar_c = 0.3333333333333333\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 0.25\nvar_g = var_e * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 2.4\nvar_b = 1\nvar_c = 0.3333333333333333\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 0.25\nvar_g = var_e * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "1696": {
        "category": "Comparison",
        "question_ko": "20명의 학생들이 버스를 기다리고 있습니다. 정국이는 윤기 바로 앞에 왔고, 정국이보다 먼저 온 사람은 11명이라면 윤기보다 늦게 온 사람들은 몇 명입니까?",
        "question_en": "20 students are waiting for the bus. If Jungkook came right before Yoongi, and there are 11 people who came before Jungkook, how many people came later than Yoongi?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "20 11 [OP_SUB] 1 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "20 11 [OP_SUB] 1 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "1697": {
        "category": "Correspondence",
        "question_ko": "AB-10=15일 때, A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "When AB-10=15, what number should go in A?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "AB-10=15 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "AB-10=15 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'AB-10=15'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'AB-10=15'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "1698": {
        "category": "Geometry",
        "question_ko": "석기는 아버지와 함께 등산을 갔습니다. 산 입구에서 절까지는 4킬로미터(㎞) 436미터(m)이고, 절에서 산꼭대기까지는 1999미터(m)입니다. 석기가 산 입구에서 절을 거쳐 산꼭대기까지 갔다가 같은 길을 내려왔다면 몇 킬로미터(㎞)를 걸은 것입니까?",
        "question_en": "Seokgi went hiking with his father. It is 4 kilometers (km) and 436 meters (m) from the entrance of the mountain to the temple, and 1999 meters (m) from the temple to the top of the mountain. If Seokgi went up starting from the entrance of the mountain through the temple and to the top of the mountain, and then came down the same road, how many kilometers (km) did he walk?",
        "answer_ko": "12.87",
        "answer_en": "12.87",
        "solution_abst_ko": "4 436 1000 [OP_DIV] [OP_ADD] 1999 1000 [OP_DIV] [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "4 436 1000 [OP_DIV] [OP_ADD] 1999 1000 [OP_DIV] [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 4\nvar_b = 436\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 1999\nvar_g = 1000\nvar_h = var_f / var_g\nvar_i = var_e + var_h\nvar_j = 2\nvar_k = var_i * var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 4\nvar_b = 436\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 1999\nvar_g = 1000\nvar_h = var_f / var_g\nvar_i = var_e + var_h\nvar_j = 2\nvar_k = var_i * var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "1699": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 13센티미터(㎝)인 정사각형의 네 변의 길이의 합을 구하시오.",
        "question_en": "Find the sum of the lengths of the four sides of a square whose side is 13 centimeters (cm).",
        "answer_ko": "52",
        "answer_en": "52",
        "solution_abst_ko": "13 4 [OP_MUL]",
        "solution_abst_en": "13 4 [OP_MUL]",
        "solution_code_ko": "var_a = 13\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 13\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "1700": {
        "category": "Geometry",
        "question_ko": "한 모서리의 길이가 7㎝인 정육면체의 겉넓이는 몇 제곱센티미터입니까?",
        "question_en": "What is the surface area, in square centimeters (cm2), of a cube with one edge 7 centimeters (cm) long?",
        "answer_ko": "294",
        "answer_en": "294",
        "solution_abst_ko": "7 2 [OP_POW] 6 [OP_MUL]",
        "solution_abst_en": "7 2 [OP_POW] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 7\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 7\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "1701": {
        "category": "Arithmetic calculation",
        "question_ko": "숫자 4, 5로 나누어 떨어질 수 있는 세 자리 수 중 가장 큰 수는 무엇입니까?",
        "question_en": "What is the largest three-digit number that is divisible by both 4 and 5?",
        "answer_ko": "980",
        "answer_en": "980",
        "solution_abst_ko": "100 999 1 [OP_LIST_ARANGE] 4 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_abst_en": "100 999 1 [OP_LIST_ARANGE] 4 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 4\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[-var_f]\nprint(int(var_g))",
        "solution_code_en": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 4\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[-var_f]\nprint(int(var_g))"
    },
    "1702": {
        "category": "Arithmetic calculation",
        "question_ko": "은지의 나이는 삼촌보다 25살 더 적고 유나의 나이는 은지보다 3살 더 많습니다. 삼촌의 나이가 41살이라면 은지의 나이와 유나의 나이의 합은 몇 살인지 구하시오.",
        "question_en": "Eunji is 25 years younger than her uncle and Yuna is 3 years older than Eunji. If her uncle is 41 years old, what is the sum of Eunji's and Yuna's ages?",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "41 25 [OP_SUB] 41 25 [OP_SUB] 3 [OP_ADD] [OP_ADD]",
        "solution_abst_en": "41 25 [OP_SUB] 41 25 [OP_SUB] 3 [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 41\nvar_b = 25\nvar_c = var_a - var_b\nvar_d = 41\nvar_e = 25\nvar_f = var_d - var_e\nvar_g = 3\nvar_h = var_f + var_g\nvar_i = var_c + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 41\nvar_b = 25\nvar_c = var_a - var_b\nvar_d = 41\nvar_e = 25\nvar_f = var_d - var_e\nvar_g = 3\nvar_h = var_f + var_g\nvar_i = var_c + var_h\nprint(int(var_i))"
    },
    "1703": {
        "category": "Possibility",
        "question_ko": "주어진 숫자 카드 9, 4, 6을 한 번씩 모두 사용하여 세 자리 수를 만들 때, 600보다 크고 950보다 작은 수는 모두 몇 개입니까?",
        "question_en": "Find out the number of three-digit numbers that are greater than 600 and less than 950, and which can be made by combining the numbers 9, 4, and 6 only once.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 9 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 600 [OP_LIST_MORE] 950 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 9 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 600 [OP_LIST_MORE] 950 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 9\nvar_b = 4\nvar_c = 6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 600\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = 950\nlist_d = []\nfor i in list_c:\n    if i < var_f:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))",
        "solution_code_en": "var_a = 9\nvar_b = 4\nvar_c = 6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 600\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = 950\nlist_d = []\nfor i in list_c:\n    if i < var_f:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))"
    },
    "1704": {
        "category": "Comparison",
        "question_ko": "A, B, C, D가 포함된 그룹이 있습니다. A, C, B, D 순으로 연필을 많이 가지고 있습니다. 이 그룹에 E와 F가 합류했습니다. E는 F보다 연필을 많이 가지고 있으며 또한 F는 A보다 연필의 개수가 많습니다. 그렇다면 이 그룹에서 가장 많은 연필을 가진 사람은 누구인가요?",
        "question_en": "I have a group that contains A, B, C, and D. A, C, B, and D is the order of having many pencils in ascending order. E and F joined this group. E has more pencils than F, and F has more pencils than A. Who in this group has the most pencils?",
        "answer_ko": "E",
        "answer_en": "E",
        "solution_abst_ko": "[OP_LIST_SOL] A B C D E F [OP_LIST_EOL] [OP_LIST_SOL] A C > C B > B D > E F > F A > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D E F [OP_LIST_EOL] [OP_LIST_SOL] A C > C B > B D > E F > F A > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nvar_f = 'F'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 'A'\nvar_h = 'C'\nvar_i = '>'\nvar_j = 'C'\nvar_k = 'B'\nvar_l = '>'\nvar_m = 'B'\nvar_n = 'D'\nvar_o = '>'\nvar_p = 'E'\nvar_q = 'F'\nvar_r = '>'\nvar_s = 'F'\nvar_t = 'A'\nvar_u = '>'\nlist_b= []\nif \"/\" in str(var_u):\n    var_u = eval(str(var_u))\nlist_b.append(var_u)\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_b.append(var_t)\nif \"/\" in str(var_s):\n    var_s = eval(str(var_s))\nlist_b.append(var_s)\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_v = 1\nvar_w = list_c[var_v-1]\nprint(var_w)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nvar_f = 'F'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 'A'\nvar_h = 'C'\nvar_i = '>'\nvar_j = 'C'\nvar_k = 'B'\nvar_l = '>'\nvar_m = 'B'\nvar_n = 'D'\nvar_o = '>'\nvar_p = 'E'\nvar_q = 'F'\nvar_r = '>'\nvar_s = 'F'\nvar_t = 'A'\nvar_u = '>'\nlist_b= []\nif \"/\" in str(var_u):\n    var_u = eval(str(var_u))\nlist_b.append(var_u)\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_b.append(var_t)\nif \"/\" in str(var_s):\n    var_s = eval(str(var_s))\nlist_b.append(var_s)\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_v = 1\nvar_w = list_c[var_v-1]\nprint(var_w)"
    },
    "1705": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 20을 더한 다음 5로 나누어야 할 것을 잘못하여 어떤 수에 20을 더한 다음 5를 곱했더니 225가 되었습니다. 바르게 계산한 값을 구하시오.",
        "question_en": "I made the mistake of adding 20 to a number and multiplying it by 5, when I needed to add 20 to this number and divide it by 5. The result value was 225. Find the rightly calculated value.",
        "answer_ko": "225",
        "answer_en": "225",
        "solution_abst_ko": "225 5 [OP_DIV] 20 [OP_SUB] 20 [OP_ADD] 5 [OP_MUL]",
        "solution_abst_en": "225 5 [OP_DIV] 20 [OP_SUB] 20 [OP_ADD] 5 [OP_MUL]",
        "solution_code_ko": "var_a = 225\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 20\nvar_e = var_c - var_d\nvar_f = 20\nvar_g = var_e + var_f\nvar_h = 5\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 225\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 20\nvar_e = var_c - var_d\nvar_f = 20\nvar_g = var_e + var_f\nvar_h = 5\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "1706": {
        "category": "Arithmetic calculation",
        "question_ko": "태연이의 키는 성희의 키의 1.06배입니다. 성희가 키를 쟀을 때 134.5센티미터(㎝)였습니다. 이 때, 태연이의 키는 몇 센티미터(㎝)인지 구해보세요.",
        "question_en": "Taeyeon's height is 1.06 times that of Sunghee's. When Seonghee measured her height, it was 134.5 centimeters (cm). At this time, find out how tall Taeyeon is in centimeters (cm).",
        "answer_ko": "142.57",
        "answer_en": "142.57",
        "solution_abst_ko": "134.5 1.06 [OP_MUL]",
        "solution_abst_en": "134.5 1.06 [OP_MUL]",
        "solution_code_ko": "var_a = 134.5\nvar_b = 1.06\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 134.5\nvar_b = 1.06\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "1707": {
        "category": "Arithmetic calculation",
        "question_ko": "아들의 나이는 아버지의 나이의 1/4보다 1살이 적고 아버지의 나이는 아들의 나이의 5배보다 5살이 적을 때, 아들의 나이는 몇 살입니까?",
        "question_en": "If the son's age is 1 year less than 1/4 of the father's age and the father's age is 5 years less than 5 times the son's age, how old is the son?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "1/4 5 [OP_MUL] 1 [OP_ADD] 1/4 5 [OP_MUL] 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "1/4 5 [OP_MUL] 1 [OP_ADD] 1/4 5 [OP_MUL] 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 0.25\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 0.25\nvar_g = 5\nvar_h = var_f * var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 0.25\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 0.25\nvar_g = 5\nvar_h = var_f * var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e / var_j\nprint(int(var_k))"
    },
    "1708": {
        "category": "Arithmetic calculation",
        "question_ko": "호랑이는 한 시간에 3.8킬로미터(㎞)를 달린다고 합니다. 호랑이가 2시간 45분동안 쉬지않고 달린 거리는 몇 킬로미터(㎞)입니까?",
        "question_en": "Tigers are said to run 3.8 kilometers (km) per hour. How many kilometers (km) could the tiger run without stopping in 2 hours and 45 minutes?",
        "answer_ko": "10.45",
        "answer_en": "10.45",
        "solution_abst_ko": "3.8 2 45 60 [OP_DIV] [OP_ADD] [OP_MUL]",
        "solution_abst_en": "3.8 2 45 60 [OP_DIV] [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 3.8\nvar_b = 2\nvar_c = 45\nvar_d = 60\nvar_e = var_c / var_d\nvar_f = var_b + var_e\nvar_g = var_a * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 3.8\nvar_b = 2\nvar_c = 45\nvar_d = 60\nvar_e = var_c / var_d\nvar_f = var_b + var_e\nvar_g = var_a * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "1709": {
        "category": "Possibility",
        "question_ko": "검은색 바둑돌 1개와 흰색 바둑돌 2개가 있습니다. 바둑돌 3개를 한 줄로 놓을 때 가능한 방법은 모두 몇 가지입니까?",
        "question_en": "There is one black go stone and two white go stones. How many ways are there to place 3 go stones in a row?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "2 1 [OP_ADD] 2 [OP_COMB]",
        "solution_abst_en": "2 1 [OP_ADD] 2 [OP_COMB]",
        "solution_code_ko": "var_a = 2\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = 1\nvar_c = int(var_c)\nvar_d = int(var_d)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e * (var_c-i)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e / (i+1)\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = 1\nvar_c = int(var_c)\nvar_d = int(var_d)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e * (var_c-i)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e / (i+1)\nprint(int(var_e))"
    },
    "1710": {
        "category": "Comparison",
        "question_ko": "갑, 을 병 세 사람의 평균 키는 143센티미터(㎝)이다. 갑의 키에 4.5센티미터(㎝)를 더하면 을과 병의 평균 키가 된다. 을이 병보다 3센티미터(㎝) 더 크면, 병의 키는 몇 센티미터(㎝)인가?",
        "question_en": "The average height of the three people, A, B, and C is 143 centimeters (cm). If A's height is increased by 4.5 centimeters (cm), it becomes the average height of B and C. If B is 3 centimeters (cm) taller than C, how tall is C in centimeters (cm)?",
        "answer_ko": "143",
        "answer_en": "143",
        "solution_abst_ko": "143 3 [OP_MUL] 3 2 [OP_DIV] 4.5 [OP_SUB] [OP_SUB] 3 [OP_SUB] 3 [OP_DIV]",
        "solution_abst_en": "143 3 [OP_MUL] 3 2 [OP_DIV] 4.5 [OP_SUB] [OP_SUB] 3 [OP_SUB] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 143\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = 2\nvar_f = var_d / var_e\nvar_g = 4.5\nvar_h = var_f - var_g\nvar_i = var_c - var_h\nvar_j = 3\nvar_k = var_i - var_j\nvar_l = 3\nvar_m = var_k / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 143\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = 2\nvar_f = var_d / var_e\nvar_g = 4.5\nvar_h = var_f - var_g\nvar_i = var_c - var_h\nvar_j = 3\nvar_k = var_i - var_j\nvar_l = 3\nvar_m = var_k / var_l\nprint(int(var_m))"
    },
    "1711": {
        "category": "Geometry",
        "question_ko": "밑면이 정삼각형 모양인 기둥이 있습니다. 길이가 78센티미터(㎝)인 끈을 이용해 이 기둥을 한 바퀴 감쌌을 때 끈이 부족하지도 남지도 않았다면, 기둥의 밑면의 한 변의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "There is a pillar with a base in the shape of a equilateral triangle. If a 78 centimeters (cm) long string is wrapped around this pillar and there is neither shortage nor excess string, how many centimeters (cm) is one side of the base of this pillar?",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "78 3 [OP_DIV]",
        "solution_abst_en": "78 3 [OP_DIV]",
        "solution_code_ko": "var_a = 78\nvar_b = 3\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 78\nvar_b = 3\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "1712": {
        "category": "Arithmetic calculation",
        "question_ko": "효근, 석기, 가영 세 사람의 몸무게의 합은 106킬로그램(㎏) 600그램(g)입니다. 가영이는 석기보다 7킬로그램(㎏) 700그램(g) 더 가볍고, 석기는 효근이보다 4.8킬로그램(㎏) 더 가볍습니다. 효근이의 몸무게는 몇 킬로그램(㎏)입니까?",
        "question_en": "Hyogeun, Seokgi, and Gayeong weigh 106 kilograms (kg) and 600 grams (g). Gayeong is 7 kg (kg) 700 grams (g) lighter than Seokgi, and Seokgi is 4.8 kg (kg) lighter than Hyogeun. How many kilograms (kg) does Hyogeun weigh?",
        "answer_ko": "41.30",
        "answer_en": "41.3",
        "solution_abst_ko": "106 600 1000 [OP_DIV] [OP_ADD] 7 700 1000 [OP_DIV] [OP_ADD] [OP_ADD] 4.8 2 [OP_MUL] [OP_ADD] 3 [OP_DIV]",
        "solution_abst_en": "106 600 1000 [OP_DIV] [OP_ADD] 7 700 1000 [OP_DIV] [OP_ADD] [OP_ADD] 4.8 2 [OP_MUL] [OP_ADD] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 106\nvar_b = 600\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 7\nvar_g = 700\nvar_h = 1000\nvar_i = var_g / var_h\nvar_j = var_f + var_i\nvar_k = var_e + var_j\nvar_l = 4.8\nvar_m = 2\nvar_n = var_l * var_m\nvar_o = var_k + var_n\nvar_p = 3\nvar_q = var_o / var_p\nprint('{:.2f}'.format(round(var_q+1e-10,2)))",
        "solution_code_en": "var_a = 106\nvar_b = 600\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 7\nvar_g = 700\nvar_h = 1000\nvar_i = var_g / var_h\nvar_j = var_f + var_i\nvar_k = var_e + var_j\nvar_l = 4.8\nvar_m = 2\nvar_n = var_l * var_m\nvar_o = var_k + var_n\nvar_p = 3\nvar_q = var_o / var_p\nprint('{:.2f}'.format(round(var_q+1e-10,2)))"
    },
    "1713": {
        "category": "Possibility",
        "question_ko": "네 자연수 2, 4, 6, 8중 3개만을 골라 모두 사용하여 세 자리 수를 만들 때, 만들 수 있는 개수는 몇 개인가?",
        "question_en": "How many of the three-digit number can be formed from four natural numbers 2, 4, 6, and 8 using only 3 numbers?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "[OP_LIST_SOL] 2 4 8 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 2 4 8 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = 8\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = 8\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "1714": {
        "category": "Possibility",
        "question_ko": "범진이가 책장에 수학책 두 권과 영어책 두 권을 올려놓으려고 할 때, 수학책을 붙여서 놓는 방법의 개수는?",
        "question_en": "When Beomjin wants to put two math books and two English books on the bookshelf, in how many ways can the math books be placed together?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "3 3 [OP_PERM] 2 [OP_MUL]",
        "solution_abst_en": "3 3 [OP_PERM] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 3\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "1715": {
        "category": "Geometry",
        "question_ko": "밑변이 3.6이고 높이가 밑변의 2.5배인 삼각형이 있다. 삼각형의 넓이를 구하시오.",
        "question_en": "There is a triangle whose base is 3.6 and whose height is 2.5 times the base. Find the area of the triangle.",
        "answer_ko": "16.20",
        "answer_en": "16.2",
        "solution_abst_ko": "3.6 3.6 2.5 [OP_MUL] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "3.6 3.6 2.5 [OP_MUL] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 3.6\nvar_b = 3.6\nvar_c = 2.5\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 3.6\nvar_b = 3.6\nvar_c = 2.5\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "1716": {
        "category": "Comparison",
        "question_ko": "유나, 은지, 민영, 유정이가 비행기 멀리 날리기 대회를 하고 있습니다. 민영이는 은지보다, 은지가 유정이보다 비행기를 멀리 날렸고 유나는 유정이보다 비행기를 멀리 날렸습니다. 유정이보다 민영이가 비행기를 멀리 날렸을 때, 대회에서 꼴등한 사람은 누구일까요?",
        "question_en": "Yuna, Eunji, Minyoung, and Yoojung are having a flying contest. Minyoung flew farther than Eunji, Eunji flew farther than Yoojung, and Yuna flew farther than Yoojung. When Minyoung flew farther than Yoojung, who was the bottom person in the competition?",
        "answer_ko": "유정",
        "answer_en": "Yoojung",
        "solution_abst_ko": "[OP_LIST_SOL] 유나 은지 민영 유정 [OP_LIST_EOL] [OP_LIST_SOL] 유나 유정 > 민영 은지 > 은지 유정 > 유정 민영 < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yuna Eunji Minyoung Yoojung [OP_LIST_EOL] [OP_LIST_SOL] Yuna Yoojung > Minyoung Eunji > Eunji Yoojung > Yoojung Minyoung < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '유나'\nvar_b = '은지'\nvar_c = '민영'\nvar_d = '유정'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '유나'\nvar_f = '유정'\nvar_g = '>'\nvar_h = '민영'\nvar_i = '은지'\nvar_j = '>'\nvar_k = '은지'\nvar_l = '유정'\nvar_m = '>'\nvar_n = '유정'\nvar_o = '민영'\nvar_p = '<'\nlist_b= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_q = len(list_c)\nvar_r = list_c[var_q-1]\nprint(var_r)",
        "solution_code_en": "var_a = 'Yuna'\nvar_b = 'Eunji'\nvar_c = 'Minyoung'\nvar_d = 'Yoojung'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'Yuna'\nvar_f = 'Yoojung'\nvar_g = '>'\nvar_h = 'Minyoung'\nvar_i = 'Eunji'\nvar_j = '>'\nvar_k = 'Eunji'\nvar_l = 'Yoojung'\nvar_m = '>'\nvar_n = 'Yoojung'\nvar_o = 'Minyoung'\nvar_p = '<'\nlist_b= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_q = len(list_c)\nvar_r = list_c[var_q-1]\nprint(var_r)"
    },
    "1717": {
        "category": "Comparison",
        "question_ko": "306보다 작은 수 중에서 300보다 크거나 같은 세 자리 수는 몇 개입니까?",
        "question_en": "How many three-digit numbers are less than 306 and greater than or equal to 300?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "3 100 [OP_MUL] 3 100 [OP_MUL] 99 [OP_ADD] 1 [OP_LIST_ARANGE] 306 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "3 100 [OP_MUL] 3 100 [OP_MUL] 99 [OP_ADD] 1 [OP_LIST_ARANGE] 306 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 3\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = 100\nvar_f = var_d * var_e\nvar_g = 99\nvar_h = var_f + var_g\nvar_i = 1\nlist_a = [i for i in range(var_c, var_h + 1, var_i)]\nvar_j = 306\nlist_b = []\nfor i in list_a:\n    if i < var_j:\n        list_b.append(i)\nvar_k = len(list_b)\nprint(int(var_k))",
        "solution_code_en": "var_a = 3\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = 100\nvar_f = var_d * var_e\nvar_g = 99\nvar_h = var_f + var_g\nvar_i = 1\nlist_a = [i for i in range(var_c, var_h + 1, var_i)]\nvar_j = 306\nlist_b = []\nfor i in list_a:\n    if i < var_j:\n        list_b.append(i)\nvar_k = len(list_b)\nprint(int(var_k))"
    },
    "1718": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 28센티미터(㎝)인 종이띠 24장을 같은 길이만큼씩 겹쳐서 한 줄로 길게 이어 붙였습니다. 24장을 이어 붙인 종이띠의 전체 길이가 580센티미터(㎝)라면 종이띠를 몇 센티미터(㎝)씩 겹치게 이어 붙인 것인지 구해 보시오.",
        "question_en": "Twenty-four sheets of 28 centimeters (cm) long paper strips were overlapped to the same length and attached to a long line. If the total length of the 24 strips is 580 cm (cm), find out how many centimeters (cm) of strips were overlapped.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "28 24 [OP_MUL] 580 [OP_SUB] 24 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "28 24 [OP_MUL] 580 [OP_SUB] 24 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 28\nvar_b = 24\nvar_c = var_a * var_b\nvar_d = 580\nvar_e = var_c - var_d\nvar_f = 24\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 28\nvar_b = 24\nvar_c = var_a * var_b\nvar_d = 580\nvar_e = var_c - var_d\nvar_f = 24\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "1719": {
        "category": "Arithmetic calculation",
        "question_ko": "색연필이 36자루 있습니다. 빨간색 색연필 개수는 전체의 5/9입니다. 파란색 색연필 개수는 전체의 5/12입니다. 빨간색 색연필은 파란색 색연필보다 몇 자루 더 많습니까?",
        "question_en": "There are 36 colored pencils. The number of red colored pencils is 5/9 of the total. The number of blue colored pencils is 5/12 of the total. How many more red colored pencils are there than the blue colored pencils?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "36 5/9 [OP_MUL] 36 5/12 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "36 5/9 [OP_MUL] 36 5/12 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 36\nvar_b = 0.5555555555555556\nvar_c = var_a * var_b\nvar_d = 36\nvar_e = 0.4166666666666667\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 36\nvar_b = 0.5555555555555556\nvar_c = var_a * var_b\nvar_d = 36\nvar_e = 0.4166666666666667\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "1720": {
        "category": "Arithmetic calculation",
        "question_ko": "성회네 반의 학생은 41명이고, 그중 걸어서 등교하는 학생은 대중교통을 이용하여 등교하는 학생보다 3명 많을 때, 걸어서 등교하는 학생은 몇 명인지 구하시오.",
        "question_en": "If there are 41 students in Seonghoe's class, and there are 3 more students walking to school than those using public transportation, find out how many students walk to school.",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "41 3 [OP_SUB] 2 [OP_DIV] 3 [OP_ADD]",
        "solution_abst_en": "41 3 [OP_SUB] 2 [OP_DIV] 3 [OP_ADD]",
        "solution_code_ko": "var_a = 41\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 3\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 41\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 3\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "1721": {
        "category": "Comparison",
        "question_ko": "윤기는 왼쪽에서 7번째 열, 오른쪽에서 13번째 열, 앞에서 8번째 줄, 뒤에서 14번째 줄에 서서 체조를 하고 있습니다. 각 줄마다 서 있는 학생의 수가 같다고 할 때, 체조를 하고 있는 학생은 모두 몇 명입니까?",
        "question_en": "Yoongi is standing in the 7th row from the left, the 13th row from the right, the 8th row from the front, and the 14th row from the back. If the number of students standing in each row is the same, how many students are doing gymnastics?",
        "answer_ko": "399",
        "answer_en": "399",
        "solution_abst_ko": "7 13 [OP_ADD] 1 [OP_SUB] 8 14 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "7 13 [OP_ADD] 1 [OP_SUB] 8 14 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 7\nvar_b = 13\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = 14\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 7\nvar_b = 13\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = 14\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))"
    },
    "1722": {
        "category": "Comparison",
        "question_ko": "한별이와 슬기가 달리기를 했습니다. 같은 시간 동안 한별이는 10.2킬로미터(㎞)의 1/100 배를 달렸고, 슬기는 100미터(m)를 달렸습니다. 누가 더 많이 달렸습니까?",
        "question_en": "Hanbyul and Seulgi ran. During the same time, Hanbyul ran 1/100 of 10.2 kilometers (km), and Seulgi ran 100 meters (m). Who ran more?",
        "answer_ko": "한별",
        "answer_en": "Hanbyul",
        "solution_abst_ko": "[OP_LIST_SOL] 한별 슬기 [OP_LIST_EOL] [OP_LIST_SOL] 10.2 1000 [OP_MUL] 1/100 [OP_MUL] 100 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Hanbyul Seulgi [OP_LIST_EOL] [OP_LIST_SOL] 10.2 1000 [OP_MUL] 1/100 [OP_MUL] 100 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '한별'\nvar_b = '슬기'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10.2\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 0.01\nvar_g = var_e * var_f\nvar_h = 100\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Hanbyul'\nvar_b = 'Seulgi'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10.2\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 0.01\nvar_g = var_e * var_f\nvar_h = 100\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "1723": {
        "category": "Possibility",
        "question_ko": "세 자리 수 중 모든 자리의 숫자가 다르고, 0, 2, 7, 6으로 이루어져 있는 수들 중 세 번째로 큰 수와 세 번째 작은 수의 차이를 구하시오.",
        "question_en": "Find the difference between the third largest number and the third smallest number among three-digit numbers, all digits of which are different and consist of 0, 2, 7, and 6.",
        "answer_ko": "466",
        "answer_en": "466",
        "solution_abst_ko": "[OP_LIST_SOL] 0 2 7 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 0 2 7 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 0\nvar_b = 2\nvar_c = 7\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 0\nvar_b = 2\nvar_c = 7\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))"
    },
    "1724": {
        "category": "Arithmetic calculation",
        "question_ko": "지민이는 100원짜리 동전 5개, 50원짜리 동전 1개를 가지고 있고, 석진이는 100원짜리 동전 2개, 10원짜리 동전 7개를 가지고 있습니다. 두 사람이 가지고 있는 돈은 모두 얼마입니까?",
        "question_en": "Jimin has 5 100-won coins and 1 50-won coin, and Seokjin has 2 100-won coins and 7 10-won coins. Find out the sum of the money they both have.",
        "answer_ko": "820",
        "answer_en": "820",
        "solution_abst_ko": "100 5 [OP_MUL] 50 1 [OP_MUL] [OP_ADD] 100 2 [OP_MUL] [OP_ADD] 10 7 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "100 5 [OP_MUL] 50 1 [OP_MUL] [OP_ADD] 100 2 [OP_MUL] [OP_ADD] 10 7 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 100\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 50\nvar_e = 1\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 100\nvar_i = 2\nvar_j = var_h * var_i\nvar_k = var_g + var_j\nvar_l = 10\nvar_m = 7\nvar_n = var_l * var_m\nvar_o = var_k + var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 100\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 50\nvar_e = 1\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 100\nvar_i = 2\nvar_j = var_h * var_i\nvar_k = var_g + var_j\nvar_l = 10\nvar_m = 7\nvar_n = var_l * var_m\nvar_o = var_k + var_n\nprint(int(var_o))"
    },
    "1725": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 53, 98, 69, 84가 있습니다. 그 중에서 가장 큰 수와 가장 작은 수의 차는 얼마입니까?",
        "question_en": "There are four numbers 53, 98, 69, and 84. What is the value of the largest number minus the smallest number?",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "[OP_LIST_SOL] 53 98 69 84 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 53 98 69 84 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 53\nvar_b = 98\nvar_c = 69\nvar_d = 84\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 53\nvar_b = 98\nvar_c = 69\nvar_d = 84\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))"
    },
    "1726": {
        "category": "Correspondence",
        "question_ko": "A, B는 한 자리 수입니다. 3/12<A/12<7/12와 1/10<1/B<1/3이 성립하는 모든 A의 개수와 모든 B의 개수의 합은 얼마입니까?",
        "question_en": "A and B are single-digit numbers. What is the sum of the number of all A's and the number of all B's such that 3/12<A/12<7/12 and 1/10<1/B<1/3?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "3/12<A/12<7/12 A [OP_DIGIT_UNK_SOLVER] [OP_LIST_LEN] 1/10<1/B<1/3 B [OP_DIGIT_UNK_SOLVER] [OP_LIST_LEN] [OP_ADD]",
        "solution_abst_en": "3/12<A/12<7/12 A [OP_DIGIT_UNK_SOLVER] [OP_LIST_LEN] 1/10<1/B<1/3 B [OP_DIGIT_UNK_SOLVER] [OP_LIST_LEN] [OP_ADD]",
        "solution_code_ko": "var_a = '3/12<A/12<7/12'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = len(list_a)\nvar_d = '1/10<1/B<1/3'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_b = list(set(ans_dict[var_e]))\nvar_f = len(list_b)\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = '3/12<A/12<7/12'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = len(list_a)\nvar_d = '1/10<1/B<1/3'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_b = list(set(ans_dict[var_e]))\nvar_f = len(list_b)\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "1727": {
        "category": "Arithmetic calculation",
        "question_ko": "10미터(m) 간격으로 100미터(m) 운동장 양쪽에 처음부터 끝까지 꽃을 심을 때 몇 개의 꽃이 필요합니까?",
        "question_en": "How many flowers are needed to plant flowers from start to finish on both sides of a 100 meter (m) field at 10 meter (m) intervals?",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "100 10 [OP_DIV] 1 [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "100 10 [OP_DIV] 1 [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 100\nvar_b = 10\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 100\nvar_b = 10\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "1728": {
        "category": "Comparison",
        "question_ko": "수학 시험에서 지민이는 24등이고, 석진이는 지민이보다 19명 앞의 등수를 받았습니다. 석진이는 몇 등입니까?",
        "question_en": "In the math test, Jimin ranked 24th, and Seokjin ranked 19 ranks ahead of Jimin. What is Seokjin's rank?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "24 19 [OP_SUB]",
        "solution_abst_en": "24 19 [OP_SUB]",
        "solution_code_ko": "var_a = 24\nvar_b = 19\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 24\nvar_b = 19\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "1729": {
        "category": "Correspondence",
        "question_ko": "어떤 수보다 13 작은 수가 31일 때, 어떤 수보다 11 큰 수를 구하시오.",
        "question_en": "If 31 is 13 less than a certain number, find a number that is 11 greater than this certain number.",
        "answer_ko": "55",
        "answer_en": "55",
        "solution_abst_ko": "31 13 [OP_ADD] 11 [OP_ADD]",
        "solution_abst_en": "31 13 [OP_ADD] 11 [OP_ADD]",
        "solution_code_ko": "var_a = 31\nvar_b = 13\nvar_c = var_a + var_b\nvar_d = 11\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 31\nvar_b = 13\nvar_c = var_a + var_b\nvar_d = 11\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "1730": {
        "category": "Comparison",
        "question_ko": "0.11, 0.98, 3/4, 2/3 중에서 가장 큰 수와 가장 작은 수의 합을 구합니다.",
        "question_en": "Return the sum of the largest and smallest numbers among 0.11, 0.98, 3/4, and 2/3.",
        "answer_ko": "1.09",
        "answer_en": "1.09",
        "solution_abst_ko": "[OP_LIST_SOL] 0.11 0.98 3 4 [OP_DIV] 2 3 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 0.11 0.98 3 4 [OP_DIV] 2 3 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 0.11\nvar_b = 0.98\nvar_c = 3\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = 3\nvar_h = var_f / var_g\nlist_a= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_i = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_j = list_b[-var_i]\nvar_k = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_l = list_c[var_k-1]\nvar_m = var_j + var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))",
        "solution_code_en": "var_a = 0.11\nvar_b = 0.98\nvar_c = 3\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = 3\nvar_h = var_f / var_g\nlist_a= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_i = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_j = list_b[-var_i]\nvar_k = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_l = list_c[var_k-1]\nvar_m = var_j + var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))"
    },
    "1731": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 12로 나눈 뒤 32를 빼고 3을 곱하여 45를 뺀 수가 159입니다. 어떤 수를 구하시오.",
        "question_en": "When we subtract 32 from a number divided by 12, multiply it by 3, and then subtract 45 again, it becomes 159. Find this number. ",
        "answer_ko": "1200",
        "answer_en": "1200",
        "solution_abst_ko": "159 45 [OP_ADD] 3 [OP_DIV] 32 [OP_ADD] 12 [OP_MUL]",
        "solution_abst_en": "159 45 [OP_ADD] 3 [OP_DIV] 32 [OP_ADD] 12 [OP_MUL]",
        "solution_code_ko": "var_a = 159\nvar_b = 45\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = 32\nvar_g = var_e + var_f\nvar_h = 12\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 159\nvar_b = 45\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = 32\nvar_g = var_e + var_f\nvar_h = 12\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "1732": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 8.5센티미터(㎝)인 정사각형 모양의 타일 3.2장을 빈틈없이 붙여서 덮을 수 있는 벽의 넓이는 몇 제곱센티미터(㎠)입니까?",
        "question_en": "What is the area in square centimeters (cm2) of the wall that can be covered by 3.2 square tiles with a side length of 8.5 centimeters (cm)?",
        "answer_ko": "231.20",
        "answer_en": "231.2",
        "solution_abst_ko": "8.5 2 [OP_POW] 3.2 [OP_MUL]",
        "solution_abst_en": "8.5 2 [OP_POW] 3.2 [OP_MUL]",
        "solution_code_ko": "var_a = 8.5\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 3.2\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 8.5\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 3.2\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "1733": {
        "category": "Correspondence",
        "question_ko": "18은 어떤 수에 2를 곱한 결과이다. 어떤수를 구한 뒤 거기서 4를 빼면 얼마가 되는가?",
        "question_en": "18 is the result of multiplying a number by 2. What do you get when you subtract 4 from this number?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "18 2 [OP_DIV] 4 [OP_SUB]",
        "solution_abst_en": "18 2 [OP_DIV] 4 [OP_SUB]",
        "solution_code_ko": "var_a = 18\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 18\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "1734": {
        "category": "Arithmetic calculation",
        "question_ko": "윤기는 마트에서 250원짜리 사탕을 사고 용돈으로 500원을 받았다. 이후 연필을 사는데 가진 돈의 반을 썼더니 420원이 남았다. 윤기가 처음에 가지고 있던 돈은 얼마인지 구하시오",
        "question_en": "Yoongi bought a 250 won candy at the mart and received 500 won as pocket money. After that, he spent half of my money on a pencil, and he had 420 won left. How much money did Yoongi have at first?",
        "answer_ko": "590",
        "answer_en": "590",
        "solution_abst_ko": "420 2 [OP_MUL] 500 [OP_SUB] 250 [OP_ADD]",
        "solution_abst_en": "420 2 [OP_MUL] 500 [OP_SUB] 250 [OP_ADD]",
        "solution_code_ko": "var_a = 420\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 500\nvar_e = var_c - var_d\nvar_f = 250\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 420\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 500\nvar_e = var_c - var_d\nvar_f = 250\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "1735": {
        "category": "Correspondence",
        "question_ko": "AB2-41=591입니다. B는 얼마인가요?",
        "question_en": "AB2-41=591. What should B be?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "AB2-41=591 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "AB2-41=591 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'AB2-41=591'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'AB2-41=591'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "1736": {
        "category": "Correspondence",
        "question_ko": "B보다 397만큼 작은 숫자는 A이고 A는 742이다. B가 C에 693을 더한 숫자일 때 A에서 C를 뺀 수를 구하여라.",
        "question_en": "The number 397 less than B is A, and A is 742. If B equals C plus 693, find the A minus C.",
        "answer_ko": "296",
        "answer_en": "296",
        "solution_abst_ko": "742 742 397 [OP_ADD] 693 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "742 742 397 [OP_ADD] 693 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 742\nvar_b = 742\nvar_c = 397\nvar_d = var_b + var_c\nvar_e = 693\nvar_f = var_d - var_e\nvar_g = var_a - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 742\nvar_b = 742\nvar_c = 397\nvar_d = var_b + var_c\nvar_e = 693\nvar_f = var_d - var_e\nvar_g = var_a - var_f\nprint(int(var_g))"
    },
    "1737": {
        "category": "Correspondence",
        "question_ko": "A를 5로 나누면 몫이 B, 나머지는 C가 됩니다. A, B, C는 자연수 입니다. B와 C가 같을 때, 가능한 C 중 가장 큰 수는 무엇인가요?",
        "question_en": "When A is divided by 5, the quotient is B and the remainder is C. A, B, and C are natural numbers. If B and C are equal, what is the largest number of possible Cs?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "5 1 [OP_SUB]",
        "solution_abst_en": "5 1 [OP_SUB]",
        "solution_code_ko": "var_a = 5\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "1738": {
        "category": "Correspondence",
        "question_ko": "7보다 큰 5와 9사이의 수를 구하시오.",
        "question_en": "Find the number between 5 and 9 that is greater than 7.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "5 1 [OP_ADD] 9 1 [OP_SUB] 1 [OP_LIST_ARANGE] 7 [OP_LIST_MORE] 1 [OP_LIST_GET]",
        "solution_abst_en": "5 1 [OP_ADD] 9 1 [OP_SUB] 1 [OP_LIST_ARANGE] 7 [OP_LIST_MORE] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 5\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = 7\nlist_b = []\nfor i in list_a:\n    if i > var_h:\n        list_b.append(i)\nvar_i = 1\nvar_j = list_b[var_i-1]\nprint(int(var_j))",
        "solution_code_en": "var_a = 5\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = 7\nlist_b = []\nfor i in list_a:\n    if i > var_h:\n        list_b.append(i)\nvar_i = 1\nvar_j = list_b[var_i-1]\nprint(int(var_j))"
    },
    "1739": {
        "category": "Arithmetic calculation",
        "question_ko": "효성와 미미네 집의 거리는 2.5 킬로미터(㎞) 입니다. 효성이와 미미는 만나기로 약속하고, 각자의 집에서 동시에 출발하여 일정한 빠르기로 서로의 집을 향해 걸어갔습니다. 미미는 한 시간에 2.4 킬로미터(㎞) 를 걷고 효성이는 1 분에 0.08 킬로미터(㎞) 를 걷는다면, 15 분 후 두 사람 사이의 거리는 몇 킬로미터(㎞) 입니까?",
        "question_en": "The distance between Hyosung and Mimi's house is 2.5 kilometers (km). Hyoseong and Mimi promised to meet, started from their respective homes at the same time, and walked toward each other's homes at a certain speed. If Mimi walks 2.4 kilometers (km) an hour and Hyosung walks 0.08 kilometers (km) a minute, what is the distance in kilometers (km) between the two after 15 minutes?",
        "answer_ko": "0.70",
        "answer_en": "0.7",
        "solution_abst_ko": "2.5 0.08 15 [OP_MUL] [OP_SUB] 2.4 60 [OP_DIV] 15 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "2.5 0.08 15 [OP_MUL] [OP_SUB] 2.4 60 [OP_DIV] 15 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 2.5\nvar_b = 0.08\nvar_c = 15\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 2.4\nvar_g = 60\nvar_h = var_f / var_g\nvar_i = 15\nvar_j = var_h * var_i\nvar_k = var_e - var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 2.5\nvar_b = 0.08\nvar_c = 15\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 2.4\nvar_g = 60\nvar_h = var_f / var_g\nvar_i = 15\nvar_j = var_h * var_i\nvar_k = var_e - var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "1740": {
        "category": "Comparison",
        "question_ko": "정국이는 6개의 사과에서 3개를 먹었습니다. 윤기가 가진 사과가 4개, 유나가 가진 사과가 5개라면 누가 가장 적은 사과를 가지고 있나요?",
        "question_en": "Jungkook ate 3 out of 6 apples. If Yoongi has 4 apples and Yuna has 5 apples, whose apples are the fewest?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 윤기 유나 [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_SUB] 4 5 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Yoongi Yuna [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_SUB] 4 5 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '윤기'\nvar_c = '유나'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 6\nvar_e = 3\nvar_f = var_d - var_e\nvar_g = 4\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Yoongi'\nvar_c = 'Yuna'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 6\nvar_e = 3\nvar_f = var_d - var_e\nvar_g = 4\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "1741": {
        "category": "Correspondence",
        "question_ko": "6A5+B03=748일 때, B를 구하시오.",
        "question_en": "When 6A5+B03=748 is valid, find B.",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "6A5+B03=748 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "6A5+B03=748 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '6A5+B03=748'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '6A5+B03=748'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "1742": {
        "category": "Correspondence",
        "question_ko": "10개씩 묶음이 19개이고 100개씩 묶음이 55개인 수를 A라 하고, 173을 5번 224씩 커지게 센 수를 B라고 합니다. A-B는 얼마입니까?",
        "question_en": "The number of 19 groups of 10 and 55 groups of 100 is called A, and 173 plus 224 five times is B. How much is A-B?",
        "answer_ko": "4397",
        "answer_en": "4397",
        "solution_abst_ko": "100 55 [OP_MUL] 10 19 [OP_MUL] [OP_ADD] 173 224 5 [OP_MUL] [OP_ADD] [OP_SUB]",
        "solution_abst_en": "100 55 [OP_MUL] 10 19 [OP_MUL] [OP_ADD] 173 224 5 [OP_MUL] [OP_ADD] [OP_SUB]",
        "solution_code_ko": "var_a = 100\nvar_b = 55\nvar_c = var_a * var_b\nvar_d = 10\nvar_e = 19\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 173\nvar_i = 224\nvar_j = 5\nvar_k = var_i * var_j\nvar_l = var_h + var_k\nvar_m = var_g - var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 100\nvar_b = 55\nvar_c = var_a * var_b\nvar_d = 10\nvar_e = 19\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 173\nvar_i = 224\nvar_j = 5\nvar_k = var_i * var_j\nvar_l = var_h + var_k\nvar_m = var_g - var_l\nprint(int(var_m))"
    },
    "1743": {
        "category": "Comparison",
        "question_ko": "지민, 정국, 태형이가 달리기 시합을 한 결과 지민이는 6등을 했고, 정국이는 8등을 했습니다. 태형이는 정국이보다 잘했지만 지민이보다는 못했습니다. 태형이의 등수는 몇 등입니까?",
        "question_en": "Jimin, Jungkook, and Taehyung had a running competition, and as a result, Jimin came in 6th place and Jungkook came in 8th place. Taehyung did better than Jungkook but not when compared with Jimin. What is Taehyung's rank?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "6 8 [OP_ADD] 2 [OP_FDIV]",
        "solution_abst_en": "6 8 [OP_ADD] 2 [OP_FDIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "1744": {
        "category": "Correspondence",
        "question_ko": "어떤 수의 3/10은 12입니다. 어떤 수의 1/5은 얼마인지 구해 보시오.",
        "question_en": "The 3/10 of a number is 12. Find what 1/5 of that number is.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "12 3/10 [OP_DIV] 1/5 [OP_MUL]",
        "solution_abst_en": "12 3/10 [OP_DIV] 1/5 [OP_MUL]",
        "solution_code_ko": "var_a = 12\nvar_b = 0.3\nvar_c = var_a / var_b\nvar_d = 0.2\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 0.3\nvar_c = var_a / var_b\nvar_d = 0.2\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "1745": {
        "category": "Possibility",
        "question_ko": "10보다 작은 자연수 중에서 서로 다른 세 수를 동시에 뽑으려고 합니다. 세 수의 합이 19가 되는 경우의 수를 구하시오.",
        "question_en": "We want to simultaneously draw three different numbers from natural numbers less than 10. Find the number of ways in which the sum of these three numbers become 19.",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "1 10 1 [OP_SUB] 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 19 [OP_LIST_LESS_EQUAL] 19 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "1 10 1 [OP_SUB] 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 19 [OP_LIST_LESS_EQUAL] 19 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 10\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_g = 0\n    i = int(i)\n    while i//10 > 0:\n        var_g = var_g + i%10\n        i = i//10\n    var_g = var_g + i%10\n    list_c.append(var_g)\nvar_h = 19\nlist_d = []\nfor i in list_c:\n    if i <= var_h:\n        list_d.append(i)\nvar_i = 19\nlist_e = []\nfor i in list_d:\n    if i >= var_i:\n        list_e.append(i)\nvar_j = len(list_e)\nprint(int(var_j))",
        "solution_code_en": "var_a = 1\nvar_b = 10\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_g = 0\n    i = int(i)\n    while i//10 > 0:\n        var_g = var_g + i%10\n        i = i//10\n    var_g = var_g + i%10\n    list_c.append(var_g)\nvar_h = 19\nlist_d = []\nfor i in list_c:\n    if i <= var_h:\n        list_d.append(i)\nvar_i = 19\nlist_e = []\nfor i in list_d:\n    if i >= var_i:\n        list_e.append(i)\nvar_j = len(list_e)\nprint(int(var_j))"
    },
    "1746": {
        "category": "Correspondence",
        "question_ko": "282는 어떤 수보다 133 큰 수이다. 어떤 수에서 11를 뺀다면 값이 어떻게 되는가?",
        "question_en": "282 is 133 greater than this number. What is the value if 11 is subtracted from this number?",
        "answer_ko": "138",
        "answer_en": "138",
        "solution_abst_ko": "282 133 [OP_SUB] 11 [OP_SUB]",
        "solution_abst_en": "282 133 [OP_SUB] 11 [OP_SUB]",
        "solution_code_ko": "var_a = 282\nvar_b = 133\nvar_c = var_a - var_b\nvar_d = 11\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 282\nvar_b = 133\nvar_c = var_a - var_b\nvar_d = 11\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "1747": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 36을 더해야 할 것을 잘못하여 63을 뺀 결과는 8이 되었습니다. 바르게 계산한 결과는 얼마인가요?",
        "question_en": "You subtracted a number from 63 and got 8, but then you realized that you were supposed to add 36 to a number. What do you get for the correct answer?",
        "answer_ko": "107",
        "answer_en": "107",
        "solution_abst_ko": "8 63 [OP_ADD] 36 [OP_ADD]",
        "solution_abst_en": "8 63 [OP_ADD] 36 [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 63\nvar_c = var_a + var_b\nvar_d = 36\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 63\nvar_c = var_a + var_b\nvar_d = 36\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "1748": {
        "category": "Arithmetic calculation",
        "question_ko": "미술시간에 미영이가 가로 32센티미터(㎝), 세로 74센티미터(㎝)인 직사각형 모양의 색종이를 잘라 남는 부분 없이 똑같은 정사각형 모양을 여러 장 만들려고 합니다. 미영이가 만들 수 있는 가장 큰 정사각형의 한 변의 크기는?",
        "question_en": "In art class, Miyoung is going to cut a rectangular colored paper measuring 32 centimeters (cm) wide by 74 centimeters (cm) long to make several identical squares without any left over. What is the size of one side of the largest square that Miyoung can make?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "32 74 [OP_GCD]",
        "solution_abst_en": "32 74 [OP_GCD]",
        "solution_code_ko": "var_a = 32\nvar_b = 74\nvar_c = math.gcd(int(var_b), int(var_a))\nprint(int(var_c))",
        "solution_code_en": "var_a = 32\nvar_b = 74\nvar_c = math.gcd(int(var_b), int(var_a))\nprint(int(var_c))"
    },
    "1749": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 15.25 센티미터(㎝) 인 줄자 20 장을 겹치게 이어 붙이려고 합니다. 이어 붙인 줄자의 전체 길이가 248 센티미터(㎝) 가 되도록 하려면 모두 몇 센티미터(㎝) 씩 겹치게 이어 붙여야 합니까?",
        "question_en": "I'm going to connect 20 tape measurements that are 15.25 centimeters (cm) long. How many centimeters (cm) each should the tape be superimposed to make the total length of the attached tape measure 248 centimeters (cm)?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "15.25 248 15.25 [OP_SUB] 20 1 [OP_SUB] [OP_DIV] [OP_SUB]",
        "solution_abst_en": "15.25 248 15.25 [OP_SUB] 20 1 [OP_SUB] [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 15.25\nvar_b = 248\nvar_c = 15.25\nvar_d = var_b - var_c\nvar_e = 20\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d / var_g\nvar_i = var_a - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 15.25\nvar_b = 248\nvar_c = 15.25\nvar_d = var_b - var_c\nvar_e = 20\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d / var_g\nvar_i = var_a - var_h\nprint(int(var_i))"
    },
    "1750": {
        "category": "Correspondence",
        "question_ko": "현정이네 목장에서는 소 100마리가 있다. 현정이네 목장에서 10일 동안 나오는 우유가 2804리터(L)라면 현정이네 목장의 소가 하루에 만드는 우유의 양은 얼마인지 구하시오.",
        "question_en": "Hyeonjeong's farm has 100 cows. If the milk produced by Hyeonjeong's farm for 10 days is 2804 liters (L), find the amount of milk produced per day by the cows at Hyeonjeong's farm.",
        "answer_ko": "280.4",
        "answer_en": "280.4",
        "solution_abst_ko": "2804 10 [OP_DIV]",
        "solution_abst_en": "2804 10 [OP_DIV]",
        "solution_code_ko": "var_a = 2804\nvar_b = 10\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 2804\nvar_b = 10\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "1751": {
        "category": "Possibility",
        "question_ko": "숫자 카드 1, 6, 8를 한 번씩 모두 사용하여 가장 큰 세 자리수와 세 번째로 작은 세 자리수의 합을 구하시오.",
        "question_en": "Using the number cards 1, 6, and 8 all once, find the largest three-digit number plus the third smallest three-digit number.",
        "answer_ko": "1479",
        "answer_en": "1479",
        "solution_abst_ko": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))"
    },
    "1752": {
        "category": "Comparison",
        "question_ko": "어느 양동이에 1100밀리리터(㎖)의 물을 채우고 추가로 3리터(L) 400밀리리터(㎖)의 물을 채웠습니다. 들이가 4리터(L) 800밀리리터(㎖) 인 주전자와 비교하여 양동이와 주전자 중에서 어느 것의 들이가 더 많을까요?",
        "question_en": "A bucket was completed with 1100 milliliters (ml) of water, followed by an additional 3 liters (L) and 400 milliliters (ml) of water. While a kettle holds a capacity of 4 liters (L) and 800 milliliters (ml), which one has a large capacity: a bucket or a kettle?",
        "answer_ko": "주전자",
        "answer_en": "kettle",
        "solution_abst_ko": "[OP_LIST_SOL] 주전자 양동이 [OP_LIST_EOL] [OP_LIST_SOL] 4 1000 [OP_MUL] 800 [OP_ADD] 1100 3 1000 [OP_MUL] 400 [OP_ADD] [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] kettle bucket [OP_LIST_EOL] [OP_LIST_SOL] 4 1000 [OP_MUL] 800 [OP_ADD] 1100 3 1000 [OP_MUL] 400 [OP_ADD] [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '주전자'\nvar_b = '양동이'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 800\nvar_g = var_e + var_f\nvar_h = 1100\nvar_i = 3\nvar_j = 1000\nvar_k = var_i * var_j\nvar_l = 400\nvar_m = var_k + var_l\nvar_n = var_h + var_m\nlist_b= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_o = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_p = list_c[-var_o]\nvar_q = list_b.index(var_p)+1\nvar_r = list_a[var_q-1]\nprint(var_r)",
        "solution_code_en": "var_a = 'kettle'\nvar_b = 'bucket'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 800\nvar_g = var_e + var_f\nvar_h = 1100\nvar_i = 3\nvar_j = 1000\nvar_k = var_i * var_j\nvar_l = 400\nvar_m = var_k + var_l\nvar_n = var_h + var_m\nlist_b= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_o = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_p = list_c[-var_o]\nvar_q = list_b.index(var_p)+1\nvar_r = list_a[var_q-1]\nprint(var_r)"
    },
    "1753": {
        "category": "Correspondence",
        "question_ko": "윤기는 네 자리수와 57의 뺄셈을 하려 합니다. 윤기는 네 자리수의 일의 자리 숫자 9를 6으로 잘못 보았습니다. 윤기가 구한 차는 1819 일 때, 네 자리수를 구하시오.",
        "question_en": "Yoongi wants to subtract 57 from a four-digit number. Yoongi misspelled 9 as a 6 in the unit digit of a four-digit number. When the difference obtained by Yoongi is 1819, find a four-digit number.",
        "answer_ko": "1879",
        "answer_en": "1879",
        "solution_abst_ko": "1819 57 [OP_ADD] 6 9 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "1819 57 [OP_ADD] 6 9 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 1819\nvar_b = 57\nvar_c = var_a + var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1819\nvar_b = 57\nvar_c = var_a + var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "1754": {
        "category": "Correspondence",
        "question_ko": "1A69를 버림하여 백의 자리까지 나타내면 1600이 됩니다. A를 구하시오.",
        "question_en": "Rounding down 1A69 to the hundreds place gives 1600. Find A.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "1A69 [OP_GEN_POSSIBLE_LIST] 1600 [OP_LIST_MORE_EQUAL] 1600 100 [OP_ADD] [OP_LIST_LESS] 1A69 A [OP_LIST_FIND_UNK]",
        "solution_abst_en": "1A69 [OP_GEN_POSSIBLE_LIST] 1600 [OP_LIST_MORE_EQUAL] 1600 100 [OP_ADD] [OP_LIST_LESS] 1A69 A [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = '1A69'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 1600\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 1600\nvar_d = 100\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = '1A69'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))",
        "solution_code_en": "var_a = '1A69'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 1600\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 1600\nvar_d = 100\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = '1A69'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))"
    },
    "1755": {
        "category": "Geometry",
        "question_ko": "어떤 마름모의 넓이가 80제곱센티미터(㎠)이며, 이 마름모의 한 대각선의 길이가 16 센티미터(㎝)입니다. 다른 대각선의 길이는 몇 센티미터(㎝)일까요?",
        "question_en": "The area of a rhombus is 80 square centimeters (cm2), and the length of one diagonal of the rhombus is 16 centimeters (cm).  the length of the other diagonal in centimeters (cm).",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "80 2 [OP_MUL] 16 [OP_DIV]",
        "solution_abst_en": "80 2 [OP_MUL] 16 [OP_DIV]",
        "solution_code_ko": "var_a = 80\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 16\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 80\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 16\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "1756": {
        "category": "Comparison",
        "question_ko": "24대의 차량이 있습니다. 이 중 빨간색 자동차가 전체의 4분의 1을 차지하고 파란색 자동차가 빨간색 자동차보다 6대 더 많으며 나머지는 노란색 자동차입니다. 어떤 색상의 자동차가 가장 많이 있습니까?",
        "question_en": "There are 24 vehicles. The red cars take up a quarter of the total, blue cars outnumber red cars by six, and yellow cars take up the rest. What color of the cars do you have the most?",
        "answer_ko": "파란색",
        "answer_en": "blue",
        "solution_abst_ko": "[OP_LIST_SOL] 빨간색 파란색 노란색 [OP_LIST_EOL] [OP_LIST_SOL] 24 4 [OP_DIV] 24 4 [OP_DIV] 6 [OP_ADD] 24 24 4 [OP_DIV] 6 [OP_ADD] [OP_SUB] 24 4 [OP_DIV] [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] red blue yellow [OP_LIST_EOL] [OP_LIST_SOL] 24 4 [OP_DIV] 24 4 [OP_DIV] 6 [OP_ADD] 24 24 4 [OP_DIV] 6 [OP_ADD] [OP_SUB] 24 4 [OP_DIV] [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '빨간색'\nvar_b = '파란색'\nvar_c = '노란색'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 24\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = 24\nvar_h = 4\nvar_i = var_g / var_h\nvar_j = 6\nvar_k = var_i + var_j\nvar_l = 24\nvar_m = 24\nvar_n = 4\nvar_o = var_m / var_n\nvar_p = 6\nvar_q = var_o + var_p\nvar_r = var_l - var_q\nvar_s = 24\nvar_t = 4\nvar_u = var_s / var_t\nvar_v = var_r - var_u\nlist_b= []\nif \"/\" in str(var_v):\n    var_v = eval(str(var_v))\nlist_b.append(var_v)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_w = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_x = list_c[-var_w]\nvar_y = list_b.index(var_x)+1\nvar_z = list_a[var_y-1]\nprint(var_z)",
        "solution_code_en": "var_a = 'red'\nvar_b = 'blue'\nvar_c = 'yellow'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 24\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = 24\nvar_h = 4\nvar_i = var_g / var_h\nvar_j = 6\nvar_k = var_i + var_j\nvar_l = 24\nvar_m = 24\nvar_n = 4\nvar_o = var_m / var_n\nvar_p = 6\nvar_q = var_o + var_p\nvar_r = var_l - var_q\nvar_s = 24\nvar_t = 4\nvar_u = var_s / var_t\nvar_v = var_r - var_u\nlist_b= []\nif \"/\" in str(var_v):\n    var_v = eval(str(var_v))\nlist_b.append(var_v)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_w = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_x = list_c[-var_w]\nvar_y = list_b.index(var_x)+1\nvar_z = list_a[var_y-1]\nprint(var_z)"
    },
    "1757": {
        "category": "Arithmetic calculation",
        "question_ko": "농장에 닭 45마리가 있었습니다. 1번째 날 닭 18마리를 더 사 오고, 2번째 날 닭 12마리를 더 사 왔다면 닭은 처음보다 몇 마리가 늘어났습니까?",
        "question_en": "There were 45 chickens on the farm. If you bought 18 more chickens on day 1 and 12 more chickens on day 2, how many more chickens increased?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "18 12 [OP_ADD]",
        "solution_abst_en": "18 12 [OP_ADD]",
        "solution_code_ko": "var_a = 18\nvar_b = 12\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 18\nvar_b = 12\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "1758": {
        "category": "Arithmetic calculation",
        "question_ko": "상자 안에는 파란 공 3개와 빨간 공 5개가 있습니다. 2개의 빨간 공을 넣었을 때, 상자 안의 빨간 공의 개수는?",
        "question_en": "There are 3 blue balls and 5 red balls in the box. When 2 red balls are put in, how many red balls are there in the box?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "5 2 [OP_ADD]",
        "solution_abst_en": "5 2 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "1759": {
        "category": "Arithmetic calculation",
        "question_ko": "리본 고리를 만들기 위해 리본을 0.82미터(m)씩 자르려고 합니다. 리본 5.74미터(m)로 고리를 몇 개 만들 수 있는지 구하시오.",
        "question_en": "You are going to cut the ribbon in 0.82 meter (m) to make ribbon loops. Find how many loops can be made with 5.74 meters (m) of ribbon.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "5.74 0.82 [OP_FDIV]",
        "solution_abst_en": "5.74 0.82 [OP_FDIV]",
        "solution_code_ko": "var_a = 5.74\nvar_b = 0.82\nvar_c = var_a // var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5.74\nvar_b = 0.82\nvar_c = var_a // var_b\nprint(int(var_c))"
    },
    "1760": {
        "category": "Possibility",
        "question_ko": "3개의 숫자 6, 0, 3이 주어져 있습니다. 주어진 숫자를 한 번씩 사용하여 만들 수 있는 두 자리 수는 모두 몇 개입니까?",
        "question_en": "You are given three numbers 6, 0 and 3. How many two-digit numbers can be made using given numbers once?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 6 0 3 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 6 0 3 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 6\nvar_b = 0\nvar_c = 3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 0\nvar_c = 3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "1761": {
        "category": "Geometry",
        "question_ko": "가로의 길이가 18센티미터(㎝), 세로의 길이가 12센티미터(㎝), 높이가 1센티미터(㎝)인 직육면체 블록이 9개 쌓여있습니다. 9개의 블록을 한 세트라 하였을  때, 이 세트로 정육면체를 만든다면 몇 개의 세트가 필요한지 구하시오",
        "question_en": "9 cuboid blocks 18 centimeters (cm) wide, 12 centimeters (cm) long, and 1 centimeters (cm) high are stacked. Assuming that 9 blocks are a set, how many sets are needed to make a cube with this set?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "18 12 [OP_LCM] 9 [OP_LCM] 18 [OP_DIV] 18 12 [OP_LCM] 9 [OP_LCM] 9 [OP_DIV] 18 12 [OP_LCM] 9 [OP_LCM] 12 [OP_DIV] [OP_MUL] [OP_MUL]",
        "solution_abst_en": "18 12 [OP_LCM] 9 [OP_LCM] 18 [OP_DIV] 18 12 [OP_LCM] 9 [OP_LCM] 9 [OP_DIV] 18 12 [OP_LCM] 9 [OP_LCM] 12 [OP_DIV] [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 18\nvar_b = 12\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nvar_d = 9\nvar_e = var_d * var_c / math.gcd(int(var_d), int(var_c))\nvar_f = 18\nvar_g = var_e / var_f\nvar_h = 18\nvar_i = 12\nvar_j = var_i * var_h / math.gcd(int(var_i), int(var_h))\nvar_k = 9\nvar_l = var_k * var_j / math.gcd(int(var_k), int(var_j))\nvar_m = 9\nvar_n = var_l / var_m\nvar_o = 18\nvar_p = 12\nvar_q = var_p * var_o / math.gcd(int(var_p), int(var_o))\nvar_r = 9\nvar_s = var_r * var_q / math.gcd(int(var_r), int(var_q))\nvar_t = 12\nvar_u = var_s / var_t\nvar_v = var_n * var_u\nvar_w = var_g * var_v\nprint(int(var_w))",
        "solution_code_en": "var_a = 18\nvar_b = 12\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nvar_d = 9\nvar_e = var_d * var_c / math.gcd(int(var_d), int(var_c))\nvar_f = 18\nvar_g = var_e / var_f\nvar_h = 18\nvar_i = 12\nvar_j = var_i * var_h / math.gcd(int(var_i), int(var_h))\nvar_k = 9\nvar_l = var_k * var_j / math.gcd(int(var_k), int(var_j))\nvar_m = 9\nvar_n = var_l / var_m\nvar_o = 18\nvar_p = 12\nvar_q = var_p * var_o / math.gcd(int(var_p), int(var_o))\nvar_r = 9\nvar_s = var_r * var_q / math.gcd(int(var_r), int(var_q))\nvar_t = 12\nvar_u = var_s / var_t\nvar_v = var_n * var_u\nvar_w = var_g * var_v\nprint(int(var_w))"
    },
    "1762": {
        "category": "Correspondence",
        "question_ko": "세 자리 수 A3B는 300보다 크고 400보다 작다. 또한 3으로 나누어 떨어지고 7의 배수라고 한다. B는 무엇인가?",
        "question_en": "The three-digit number A3B is greater than 300 and less than 400. Also, it is divisible by 3 and a multiple of 7. What is B?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "A3B [OP_GEN_POSSIBLE_LIST] 300 [OP_LIST_MORE] 400 [OP_LIST_LESS] 3 [OP_LIST_DIVISIBLE] 7 [OP_LIST_DIVISIBLE] A3B B [OP_LIST_FIND_UNK]",
        "solution_abst_en": "A3B [OP_GEN_POSSIBLE_LIST] 300 [OP_LIST_MORE] 400 [OP_LIST_LESS] 3 [OP_LIST_DIVISIBLE] 7 [OP_LIST_DIVISIBLE] A3B B [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = 'A3B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 300\nlist_b = []\nfor i in list_a:\n    if i > var_b:\n        list_b.append(i)\nvar_c = 400\nlist_c = []\nfor i in list_b:\n    if i < var_c:\n        list_c.append(i)\nvar_d = 3\nlist_d = []\nvar_d = int(var_d)\nfor i in list_c:\n    i = int(i)\n    if i % var_d == 0:\n        list_d.append(i)\nvar_e = 7\nlist_e = []\nvar_e = int(var_e)\nfor i in list_d:\n    i = int(i)\n    if i % var_e == 0:\n        list_e.append(i)\nvar_f = 'A3B'\nvar_g = 'B'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_e:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))",
        "solution_code_en": "var_a = 'A3B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 300\nlist_b = []\nfor i in list_a:\n    if i > var_b:\n        list_b.append(i)\nvar_c = 400\nlist_c = []\nfor i in list_b:\n    if i < var_c:\n        list_c.append(i)\nvar_d = 3\nlist_d = []\nvar_d = int(var_d)\nfor i in list_c:\n    i = int(i)\n    if i % var_d == 0:\n        list_d.append(i)\nvar_e = 7\nlist_e = []\nvar_e = int(var_e)\nfor i in list_d:\n    i = int(i)\n    if i % var_e == 0:\n        list_e.append(i)\nvar_f = 'A3B'\nvar_g = 'B'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_e:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))"
    },
    "1763": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 2번째로 큰 수와 가장 작은 수로 나눈 몫은 얼마입니까?",
        "question_en": "There are five numbers 10, 11, 12, 13, and 14. What is the quotient of the second largest number divided by the smallest number?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 2 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_FDIV]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 2 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_FDIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g // var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g // var_i\nprint(int(var_j))"
    },
    "1764": {
        "category": "Correspondence",
        "question_ko": "A를 8로 나누면 몫은 B이고 나머지는 C가 됩니다. A, B, C는 자연수입니다. 이 식에서 몫과 나머지가 같습니다. 나누어지는 수 A 중 가장 큰 수를 구하시오.",
        "question_en": "When A is divided by 8, the quotient is B and the remainder is C. A, B, and C are natural numbers. In this, the quotient and remainder are equal. Find the largest number of A which is a divided number.",
        "answer_ko": "63",
        "answer_en": "63",
        "solution_abst_ko": "8 8 1 [OP_SUB] [OP_MUL] 8 1 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "8 8 1 [OP_SUB] [OP_MUL] 8 1 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 8\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 8\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 8\nvar_b = 8\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 8\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e + var_h\nprint(int(var_i))"
    },
    "1765": {
        "category": "Arithmetic calculation",
        "question_ko": "민재와 아버지는 사과를 땄습니다. 민재는 2.6킬로그램(㎏), 아버지는 5.98킬로그램(㎏)을 땄습니다. 민재와 아버지가 딴 사과는 모두 몇 킬로그램(㎏)입니까?",
        "question_en": "Minjae and his father picked apples. Minjae gained 2.6 kilograms (kg), and his father 5.98 kilograms (kg). How many kilograms (kg) are all the apples Minjae and his father picked?",
        "answer_ko": "8.58",
        "answer_en": "8.58",
        "solution_abst_ko": "2.6 5.98 [OP_ADD]",
        "solution_abst_en": "2.6 5.98 [OP_ADD]",
        "solution_code_ko": "var_a = 2.6\nvar_b = 5.98\nvar_c = var_a + var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 2.6\nvar_b = 5.98\nvar_c = var_a + var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "1766": {
        "category": "Correspondence",
        "question_ko": "11을 자연수 A로 나누면, 나머지가 2, 몫이 3이 됩니다. 이 때 A의 값을 구하시오.",
        "question_en": "When 11 is divided by the natural number A, the remainder is 2 and the quotient is 3. Find the value of A at this time.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "11 2 [OP_SUB] 3 [OP_DIV]",
        "solution_abst_en": "11 2 [OP_SUB] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 11\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 11\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "1767": {
        "category": "Comparison",
        "question_ko": "127000킬로그램(㎏)의 화물이 있습니다. 이 화물을 부산에서 서울까지 5000킬로그램(㎏) 트럭으로 운반하려면 8000킬로그램(㎏) 트럭으로 운반하는 것보다 몇 대가 더 필요합니까?",
        "question_en": "There is a cargo of 127000 kilograms (kg). How many more trucks are needed to transport this cargo from Busan to Seoul by 5000 kilograms (kg) trucks than by 8000 kilograms (kg) trucks?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "127000 5000 [OP_DIV] 1 [OP_CEIL] 127000 8000 [OP_DIV] 1 [OP_CEIL] [OP_SUB]",
        "solution_abst_en": "127000 5000 [OP_DIV] 1 [OP_CEIL] 127000 8000 [OP_DIV] 1 [OP_CEIL] [OP_SUB]",
        "solution_code_ko": "var_a = 127000\nvar_b = 5000\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nvar_f = 127000\nvar_g = 8000\nvar_h = var_f / var_g\nvar_i = 1\nvar_j=int(((var_h+9*10**(var_i-2))//(10**(var_i-1)))*10**(var_i-1))\n\nvar_k = var_e - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 127000\nvar_b = 5000\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nvar_f = 127000\nvar_g = 8000\nvar_h = var_f / var_g\nvar_i = 1\nvar_j=int(((var_h+9*10**(var_i-2))//(10**(var_i-1)))*10**(var_i-1))\n\nvar_k = var_e - var_j\nprint(int(var_k))"
    },
    "1768": {
        "category": "Correspondence",
        "question_ko": "승주네 반 학생수는 50명이상 70명 이하이다. 승주네 반 학생들이 5줄로 서면 3명이 남고 7줄로 서면 2명이 남는다. 승주네 반 학생수는 몇 명인가?",
        "question_en": "The number of students in Seungju's class is between 50 and 70. If the students in Seungju's class form 5 lines, there will be 3 left, and if they form 7 lines, 2 will remain. How many students are in Seungju's class?",
        "answer_ko": "58",
        "answer_en": "58",
        "solution_abst_ko": "50 70 1 [OP_SUB] 1 [OP_LIST_ARANGE] 5 3 [OP_LIST_DIVIDE_AND_REMAIN] 7 2 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "50 70 1 [OP_SUB] 1 [OP_LIST_ARANGE] 5 3 [OP_LIST_DIVIDE_AND_REMAIN] 7 2 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 50\nvar_b = 70\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nvar_f = 5\nvar_g = 3\nlist_b = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_a:\n    i = int(i)\n    if i%var_f == var_g:\n        list_b.append(i)\nvar_h = 7\nvar_i = 2\nlist_c = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_b:\n    i = int(i)\n    if i%var_h == var_i:\n        list_c.append(i)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(int(var_k))",
        "solution_code_en": "var_a = 50\nvar_b = 70\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nvar_f = 5\nvar_g = 3\nlist_b = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_a:\n    i = int(i)\n    if i%var_f == var_g:\n        list_b.append(i)\nvar_h = 7\nvar_i = 2\nlist_c = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_b:\n    i = int(i)\n    if i%var_h == var_i:\n        list_c.append(i)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(int(var_k))"
    },
    "1769": {
        "category": "Possibility",
        "question_ko": "A, B, C, D, E, F 6마리의 고양이가 있을 때, 부대장 2마리, 대장 1마리를 뽑는 경우의 수를 구하시오.",
        "question_en": "If there are 6 cats A, B, C, D, E, and F, find the number of ways to select 2 vice captains and 1 captain.",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "[OP_LIST_SOL] A B C D E F [OP_LIST_EOL] [OP_LIST_LEN] 2 1 [OP_ADD] [OP_PERM] 2 2 [OP_PERM] [OP_DIV]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D E F [OP_LIST_EOL] [OP_LIST_LEN] 2 1 [OP_ADD] [OP_PERM] 2 2 [OP_PERM] [OP_DIV]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nvar_f = 'F'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = len(list_a)\nvar_h = 2\nvar_i = 1\nvar_j = var_h + var_i\nvar_k = 1\nvar_g = int(var_g)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_g-i)\nvar_l = 2\nvar_m = 2\nvar_n = 1\nvar_l = int(var_l)\nvar_m = int(var_m)\nfor i, elem in enumerate(range(var_m)):\n    var_n = var_n * (var_l-i)\nvar_o = var_k / var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nvar_f = 'F'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = len(list_a)\nvar_h = 2\nvar_i = 1\nvar_j = var_h + var_i\nvar_k = 1\nvar_g = int(var_g)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_g-i)\nvar_l = 2\nvar_m = 2\nvar_n = 1\nvar_l = int(var_l)\nvar_m = int(var_m)\nfor i, elem in enumerate(range(var_m)):\n    var_n = var_n * (var_l-i)\nvar_o = var_k / var_n\nprint(int(var_o))"
    },
    "1770": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 3을 더했더니 226이 되었습니다. 어떤 수에 3을 곱한 값을 구하시오.",
        "question_en": "When you add 3 to a certain number, you get 226. Find the value of the certain number multiplied by 3.",
        "answer_ko": "669",
        "answer_en": "669",
        "solution_abst_ko": "226 3 [OP_SUB] 3 [OP_MUL]",
        "solution_abst_en": "226 3 [OP_SUB] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 226\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 226\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "1771": {
        "category": "Comparison",
        "question_ko": "윤기는 7, 정국은 6, 유나는 9, 유정은 8만큼 모았습니다. 제일 큰 숫자를 가진 사람은 누구입니까?",
        "question_en": "Yoongi collected 7 points, Jungkook got 6 points, Yuna got 9 points, and Yoojung got 8 points. Who has the largest number?",
        "answer_ko": "유나",
        "answer_en": "Yuna",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 유나 유정 [OP_LIST_EOL] [OP_LIST_SOL] 7 6 9 8 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook Yuna Yoojung [OP_LIST_EOL] [OP_LIST_SOL] 7 6 9 8 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nvar_c = '유나'\nvar_d = '유정'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 7\nvar_f = 6\nvar_g = 9\nvar_h = 8\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nvar_c = 'Yuna'\nvar_d = 'Yoojung'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 7\nvar_f = 6\nvar_g = 9\nvar_h = 8\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "1772": {
        "category": "Possibility",
        "question_ko": "2, 3, 7로 두 자리 자연수를 만들려고 한다. 중복을 허락하여 만들 수 있는 수 중 세 번째로 큰 수를 구하시오.",
        "question_en": "I am trying to create two-digit natural numbers with 2, 3, and 7. Find the third largest possible number that can be made by allowing duplicates.",
        "answer_ko": "72",
        "answer_en": "72",
        "solution_abst_ko": "[OP_LIST_SOL] 2 3 7 [OP_LIST_EOL] 2 [OP_LIST_GET_PRODUCT] 3 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 2 3 7 [OP_LIST_EOL] 2 [OP_LIST_GET_PRODUCT] 3 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))"
    },
    "1773": {
        "category": "Geometry",
        "question_ko": "길이가 2.7미터(m)인 색테이프 5장을 0.3미터(m)씩 겹치게 이어 붙였습니다. 이어 붙인 색테이프를 6도막으로 똑같이 나누면 한 도막의 길이는 몇 미터(m)입니까?",
        "question_en": "Five sheets of 2.7meters (m) long color tape were attached together overlapping each other by 0.3meters (m). How many meters (m) is the length of one layer of colored tape if it is divided equally into 6 layers?",
        "answer_ko": "2.05",
        "answer_en": "2.05",
        "solution_abst_ko": "2.7 5 [OP_MUL] 0.3 5 1 [OP_SUB] [OP_MUL] [OP_SUB] 6 [OP_DIV]",
        "solution_abst_en": "2.7 5 [OP_MUL] 0.3 5 1 [OP_SUB] [OP_MUL] [OP_SUB] 6 [OP_DIV]",
        "solution_code_ko": "var_a = 2.7\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 0.3\nvar_e = 5\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_c - var_h\nvar_j = 6\nvar_k = var_i / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 2.7\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 0.3\nvar_e = 5\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_c - var_h\nvar_j = 6\nvar_k = var_i / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "1774": {
        "category": "Arithmetic calculation",
        "question_ko": "3의 배수이면서 4의 배수인 수 중 가장 큰 다섯 자리 수는?",
        "question_en": "What is the largest five-digit number that is a multiple of 3 and a multiple of 4?",
        "answer_ko": "99996",
        "answer_en": "99996",
        "solution_abst_ko": "10000 99999 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 4 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_abst_en": "10000 99999 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 4 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 10000\nvar_b = 99999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 4\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[-var_f]\nprint(int(var_g))",
        "solution_code_en": "var_a = 10000\nvar_b = 99999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 4\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[-var_f]\nprint(int(var_g))"
    },
    "1775": {
        "category": "Arithmetic calculation",
        "question_ko": "흰색 토끼 11마리와 검은색 토끼 13마리가 있습니다. 이 중 15마리가 수컷 토끼일 때 암컷 토끼는 몇 마리입니까?",
        "question_en": "There are 11 white rabbits and 13 black rabbits. How many female rabbits are there if 15 of them are male rabbits?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "11 13 [OP_ADD] 15 [OP_SUB]",
        "solution_abst_en": "11 13 [OP_ADD] 15 [OP_SUB]",
        "solution_code_ko": "var_a = 11\nvar_b = 13\nvar_c = var_a + var_b\nvar_d = 15\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 11\nvar_b = 13\nvar_c = var_a + var_b\nvar_d = 15\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "1776": {
        "category": "Comparison",
        "question_ko": "수 5개 1.4, 9/10, 1.2, 0.5, 13/10 중 1.1보다 작은 숫자를 구하고, 그 중에서 가장 큰 숫자를 구하면 무엇입니까?",
        "question_en": "Find a number less than 1.11 among five numbers 4, 9/10, 1.2, 0.5, and 13/10, and then find the largest among them.",
        "answer_ko": "0.90",
        "answer_en": "0.9",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i < var_f:\n        list_b.append(i)\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nprint('{:.2f}'.format(round(var_h+1e-10,2)))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i < var_f:\n        list_b.append(i)\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nprint('{:.2f}'.format(round(var_h+1e-10,2)))"
    },
    "1777": {
        "category": "Possibility",
        "question_ko": "숫자 자석 8, 7, 0 이 있습니다. 이를 배치하여 만들 수 있는 가장 큰 수는 무엇입니까?",
        "question_en": "There are magnets with numbers 8, 7 and 0 written respectively. What is the largest number you can make by arranging them?",
        "answer_ko": "870",
        "answer_en": "870",
        "solution_abst_ko": "[OP_LIST_SOL] 0 8 7 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 0 8 7 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 0\nvar_b = 8\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))",
        "solution_code_en": "var_a = 0\nvar_b = 8\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))"
    },
    "1778": {
        "category": "Possibility",
        "question_ko": "정국이가 가지고 있는 상자 3개에는 공이 각각 2개씩 들어 있습니다. 정국이가 가지고 있는 공의 개수는?",
        "question_en": "There are 2 balls in each of the 3 boxes that Jungkook has. How many balls does Jungkook have?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "3 2 [OP_MUL]",
        "solution_abst_en": "3 2 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "1779": {
        "category": "Arithmetic calculation",
        "question_ko": "경훈이가 등산을 하는데 올라갈 때는 시속 3 킬로미터(㎞)로 걷고, 내려올 때는 올라갈 때보다 2 킬로미터(㎞) 더 먼 길을 택하여 시속 4 킬로미터(㎞)로 걸어서 총 4시간이 걸렸다고 한다. 올라가는 데 걸린 시간은?",
        "question_en": "It is said that Gyeonghun climbed the mountain at a speed of 3 kilometers (km) per hour when going up, and 4 kilometers (km) per hour when going down as he changed the route, which takes 2 kilometers (km) longer than the previous one. If he took a total of 4 hours for climbing, how long did it take to go up?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "4 2 4 [OP_DIV] [OP_SUB] 1 3 [OP_DIV] 1 4 [OP_DIV] [OP_ADD] [OP_DIV] 3 [OP_DIV]",
        "solution_abst_en": "4 2 4 [OP_DIV] [OP_SUB] 1 3 [OP_DIV] 1 4 [OP_DIV] [OP_ADD] [OP_DIV] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = 3\nvar_h = var_f / var_g\nvar_i = 1\nvar_j = 4\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_e / var_l\nvar_n = 3\nvar_o = var_m / var_n\nprint(int(eval('{:.2f}'.format(round(var_o+1e-10,2)))))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = 3\nvar_h = var_f / var_g\nvar_i = 1\nvar_j = 4\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_e / var_l\nvar_n = 3\nvar_o = var_m / var_n\nprint(int(eval('{:.2f}'.format(round(var_o+1e-10,2)))))"
    },
    "1780": {
        "category": "Arithmetic calculation",
        "question_ko": "보은이의 아버지가 운전하는 택시는 1시간 15분 동안 100킬로미터(㎞)를 갑니다. 택시가 1시간 동안 이동한 평균 거리는 몇 킬로미터(㎞)입니까?",
        "question_en": "The taxi driven by Boeun's father travels 100 kilometers (km) in 1 hour and 15 minutes. What is the average distance the taxi traveled in 1 hour in kilometers (km)?",
        "answer_ko": "80",
        "answer_en": "80",
        "solution_abst_ko": "100 1 15 60 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_abst_en": "100 1 15 60 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 100\nvar_b = 1\nvar_c = 15\nvar_d = 60\nvar_e = var_c / var_d\nvar_f = var_b + var_e\nvar_g = var_a / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 100\nvar_b = 1\nvar_c = 15\nvar_d = 60\nvar_e = var_c / var_d\nvar_f = var_b + var_e\nvar_g = var_a / var_f\nprint(int(var_g))"
    },
    "1781": {
        "category": "Possibility",
        "question_ko": "다섯 개의 숫자 0, 1, 2, 3, 4 중에서 3개를 골라 세 자리의 홀수를 만들었다. 같은 수를 여러 번 사용해도 된다면, 만들 수 있는 모든 홀수의 총합은 얼마인가?",
        "question_en": "Three out of five digits 0, 1, 2, 3, and 4 were chosen to make a three-digit odd number. If you can use the same number multiple times, what is the total of all the odd numbers that can be made?",
        "answer_ko": "10880",
        "answer_en": "10880",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 2 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 2 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 2\nlist_c = []\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if i % var_g == 0:\n        list_c.append(i)\nlist_d = list(set(list_b) - set(list_c))\nlist_d = [float(i) for i in list_d]\nvar_h = sum(list_d)\nprint(int(var_h))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 2\nlist_c = []\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if i % var_g == 0:\n        list_c.append(i)\nlist_d = list(set(list_b) - set(list_c))\nlist_d = [float(i) for i in list_d]\nvar_h = sum(list_d)\nprint(int(var_h))"
    },
    "1782": {
        "category": "Arithmetic calculation",
        "question_ko": "윤수는 등산을 하면서 첫째 날 물의 7/15를 마시고, 둘째 날 남은 물의 5/8을 마셨으며, 셋째 날 그 나머지의 2/3을 마셨다. 남은 물의 양이 2.6리터(L)라면 처음 윤수가 가지고 있던 물의 양은 얼마인지 구하시오.",
        "question_en": "While hiking, Yunsu drank 7/15 of the water on the first day, 5/8 of the remaining water on the second day, and 2/3 of the rest on the third day. If the amount of remaining water is 2.6 liters (L), what is the amount of water Yunsu had at the beginning?",
        "answer_ko": "39",
        "answer_en": "39",
        "solution_abst_ko": "2.6 1 7/15 [OP_SUB] 1 5/8 [OP_SUB] [OP_MUL] 1 2/3 [OP_SUB] [OP_MUL] [OP_DIV]",
        "solution_abst_en": "2.6 1 7/15 [OP_SUB] 1 5/8 [OP_SUB] [OP_MUL] 1 2/3 [OP_SUB] [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 2.6\nvar_b = 1\nvar_c = 0.4666666666666667\nvar_d = var_b - var_c\nvar_e = 1\nvar_f = 0.625\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = 1\nvar_j = 0.6666666666666666\nvar_k = var_i - var_j\nvar_l = var_h * var_k\nvar_m = var_a / var_l\nprint(int(eval('{:.2f}'.format(round(var_m+1e-10,2)))))",
        "solution_code_en": "var_a = 2.6\nvar_b = 1\nvar_c = 0.4666666666666667\nvar_d = var_b - var_c\nvar_e = 1\nvar_f = 0.625\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = 1\nvar_j = 0.6666666666666666\nvar_k = var_i - var_j\nvar_l = var_h * var_k\nvar_m = var_a / var_l\nprint(int(eval('{:.2f}'.format(round(var_m+1e-10,2)))))"
    },
    "1783": {
        "category": "Arithmetic calculation",
        "question_ko": "사과가 105개씩 들어있는 박스가 14개 있다. 이 사과들 중 84개가 썩어서 버렸고 나머지를 6개씩 한 봉투에 넣어 7봉투를 한 박스에 넣었다. 총 몇 박스가 나오는지 구하시오.",
        "question_en": "There are 14 boxes containing 105 apples each. 84 of these apples were rotten and discarded, and the rest were put in 6 per bag and 7 bags per box. Find how many boxes there are in total.",
        "answer_ko": "33",
        "answer_en": "33",
        "solution_abst_ko": "105 14 [OP_MUL] 84 [OP_SUB] 6 7 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "105 14 [OP_MUL] 84 [OP_SUB] 6 7 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 105\nvar_b = 14\nvar_c = var_a * var_b\nvar_d = 84\nvar_e = var_c - var_d\nvar_f = 6\nvar_g = 7\nvar_h = var_f * var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 105\nvar_b = 14\nvar_c = var_a * var_b\nvar_d = 84\nvar_e = var_c - var_d\nvar_f = 6\nvar_g = 7\nvar_h = var_f * var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "1784": {
        "category": "Geometry",
        "question_ko": "모서리가 14개인 각뿔에서 꼭짓점은 몇 개입니까?",
        "question_en": "How many vertices are there in a 14-sided pyramid?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "14 2 [OP_DIV] 1 [OP_ADD]",
        "solution_abst_en": "14 2 [OP_DIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 14\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 14\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "1785": {
        "category": "Arithmetic calculation",
        "question_ko": "빨간색 사과 15개, 초록색 사과 8개, 배 32개가 있습니다. 배는 사과보다 몇 개 더 많습니까?",
        "question_en": "There are 15 red apples, 8 green apples, and 32 pears. How many more pears are there than apples?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "32 15 8 [OP_ADD] [OP_SUB]",
        "solution_abst_en": "32 15 8 [OP_ADD] [OP_SUB]",
        "solution_code_ko": "var_a = 32\nvar_b = 15\nvar_c = 8\nvar_d = var_b + var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 32\nvar_b = 15\nvar_c = 8\nvar_d = var_b + var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "1786": {
        "category": "Arithmetic calculation",
        "question_ko": "5의 배수이면서 6의 배수이면서 2의 배수인 수 중 네 자리 수는 모두 몇 개 입니까?",
        "question_en": "How many four-digit numbers are multiples of 5, multiples of 6, and multiples of 2 at the same time?",
        "answer_ko": "300",
        "answer_en": "300",
        "solution_abst_ko": "1000 9999 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] 6 [OP_LIST_DIVISIBLE] 2 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "1000 9999 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] 6 [OP_LIST_DIVISIBLE] 2 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 6\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 2\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 6\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 2\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))"
    },
    "1787": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중에서 가장 작은 수와 그 다음으로 작은 수로 나눈 몫은 얼마입니까?",
        "question_en": "Among three numbers of 10, 11 and 12, what is the quotient if the smallest number is divided by the next smallest number?",
        "answer_ko": "0",
        "answer_en": "0",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_FDIV]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_FDIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e // var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e // var_g\nprint(int(var_h))"
    },
    "1788": {
        "category": "Arithmetic calculation",
        "question_ko": "물 10.4킬로그램(㎏)이 담긴 통이 있습니다. 이 물을 작은 물통 한 개에 0.8킬로그램(㎏) 씩 나누어 담으려고 할 때, 필요한 물통은 모두 몇 개 인가요?",
        "question_en": "There is a barrel with 10.4 kilograms (kg) of water. If you want to divide this water by 0.8 kg (kg) into each small bucket, how many buckets are needed?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "10.4 0.8 [OP_DIV]",
        "solution_abst_en": "10.4 0.8 [OP_DIV]",
        "solution_code_ko": "var_a = 10.4\nvar_b = 0.8\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 10.4\nvar_b = 0.8\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "1789": {
        "category": "Arithmetic calculation",
        "question_ko": "고구마 52.5킬로그램(㎏)을 한 사람 당 5킬로그램(㎏)씩 나누어 줄 때, 나누어 주고 남는 고구마는 몇 킬로그램(㎏)인지 구하시오.",
        "question_en": "When 52.5 kg (kg) of sweet potatoes are divided by 5 kg (kg) per person, find how many kg (kg) of sweet potatoes are left after sharing.",
        "answer_ko": "2.50",
        "answer_en": "2.5",
        "solution_abst_ko": "52.5 5 [OP_MOD]",
        "solution_abst_en": "52.5 5 [OP_MOD]",
        "solution_code_ko": "var_a = 52.5\nvar_b = 5\nvar_c = var_a % var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 52.5\nvar_b = 5\nvar_c = var_a % var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "1790": {
        "category": "Possibility",
        "question_ko": "100이하인 자연수를 종이에 적을 때, 숫자 1을 몇 번 적어야 하는지 구하시오.",
        "question_en": "When writing a natural number less than 100 on a piece of paper, find how many times the number 1 must be written down.",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "1 100 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 1 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 100 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 1 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 1\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 1\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))"
    },
    "1791": {
        "category": "Geometry",
        "question_ko": "가로가 9센티미터(㎝), 세로가 4센티미터(㎝), 높이가 7센티미터(㎝)인 상자가 있습니다. 이 상자의 부피는 몇 세제곱센티미터(㎤)입니까?",
        "question_en": "There is a box 9 centimeters (cm) wide, 4 centimeters (cm) long, and 7 centimeters (cm) high. What is the volume of this box in cubic centimeters (cm3)?",
        "answer_ko": "252",
        "answer_en": "252",
        "solution_abst_ko": "9 4 [OP_MUL] 7 [OP_MUL]",
        "solution_abst_en": "9 4 [OP_MUL] 7 [OP_MUL]",
        "solution_code_ko": "var_a = 9\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "1792": {
        "category": "Correspondence",
        "question_ko": "진우가 계산을 하다 1.36을 곱해야 하는데 실수하여 1.36으로 나눈 값이 0.5였다고 한다. 진우가 원래 구하려고 하던 값은 얼마인가?",
        "question_en": "Jinwoo said that he had to multiply by 1.36 while calculating, but he made a mistake and divided it by 1.36 resulting in 0.5. What was the value Jinwoo was originally trying to find?",
        "answer_ko": "0.92",
        "answer_en": "0.92",
        "solution_abst_ko": "0.5 1.36 [OP_MUL] 1.36 [OP_MUL]",
        "solution_abst_en": "0.5 1.36 [OP_MUL] 1.36 [OP_MUL]",
        "solution_code_ko": "var_a = 0.5\nvar_b = 1.36\nvar_c = var_a * var_b\nvar_d = 1.36\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.5\nvar_b = 1.36\nvar_c = var_a * var_b\nvar_d = 1.36\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "1793": {
        "category": "Arithmetic calculation",
        "question_ko": "토끼와 거북이가 경주를 합니다. 거북이는 3분에 5미터(m)를 갈 수 있고 토끼는 2분에 5미터(m)를 갈 수 있습니다. 토끼가 거북이보다 20미터(m) 뒤에서 출발한다면 몇 분 후에 토끼와 거북이가 만나게 됩니까?",
        "question_en": "A hare and a tortoise are racing. A tortoise can cover 5 meters (m) in 3 minutes when a hare can get to 5 meters (m) in 2 minutes. If the hare starts running 20 meters (m) behind the tortoise, in how many minutes will the hare and the tortoise meet?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "20 5 2 [OP_DIV] 5 3 [OP_DIV] [OP_SUB] [OP_DIV]",
        "solution_abst_en": "20 5 2 [OP_DIV] 5 3 [OP_DIV] [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 20\nvar_b = 5\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = 5\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = var_d - var_g\nvar_i = var_a / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))",
        "solution_code_en": "var_a = 20\nvar_b = 5\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = 5\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = var_d - var_g\nvar_i = var_a / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))"
    },
    "1794": {
        "category": "Arithmetic calculation",
        "question_ko": "호석이가 마트에서 (가) 물건을 사면서 지불한 값은 1,000원짜리, 100원짜리, 10원짜리 동전이 각각 7장, 4개, 5개입니다. (가) 물건의 가격은 얼마입니까?",
        "question_en": "When Hoseok bought item (a) at the mart, he paid 7, 4, and 5 1,000 won, 100 won, and 10 won coins, respectively. What is the price of the item (a)?",
        "answer_ko": "7450",
        "answer_en": "7450",
        "solution_abst_ko": "1000 7 [OP_MUL] 100 4 [OP_MUL] [OP_ADD] 10 5 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "1000 7 [OP_MUL] 100 4 [OP_MUL] [OP_ADD] 10 5 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 1000\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = 4\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 10\nvar_i = 5\nvar_j = var_h * var_i\nvar_k = var_g + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 1000\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = 4\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 10\nvar_i = 5\nvar_j = var_h * var_i\nvar_k = var_g + var_j\nprint(int(var_k))"
    },
    "1795": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 4로 나눈 후 3을 더했더니 5가 되었습니다. 어떤 수를 구하시오.",
        "question_en": "When you divide a certain number by 4 and add 3, you get 5. Find that number.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "5 3 [OP_SUB] 4 [OP_MUL]",
        "solution_abst_en": "5 3 [OP_SUB] 4 [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "1796": {
        "category": "Comparison",
        "question_ko": "1.4, 9/10, 1.2, 0.5, 13/10 5개 숫자 중에서 1.1보다 큰 숫자를 골라 작은 순서대로 나열했을 때, 가장 앞에 있는 숫자는 무엇입니까?",
        "question_en": "Among 1.4, 9/10, 1.2, 0.5, and 13/10, pick a number greater than 1.1 and arrange them in descending order. Which number comes first?",
        "answer_ko": "1.20",
        "answer_en": "1.2",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nprint('{:.2f}'.format(round(var_h+1e-10,2)))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nprint('{:.2f}'.format(round(var_h+1e-10,2)))"
    },
    "1797": {
        "category": "Correspondence",
        "question_ko": "서로 다른 네 수 A, B, C, D가 있습니다. 세 자리 수끼리의 덧셈식 7A4+B6C=D29에서 D를 구하시오.",
        "question_en": "There are four different numbers A, B, C, and D. Find D from the three-digit addition formula 7A4+B6C=D29.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "7A4+B6C=D29 D [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "7A4+B6C=D29 D [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '7A4+B6C=D29'\nvar_b = 'D'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '7A4+B6C=D29'\nvar_b = 'D'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "1798": {
        "category": "Comparison",
        "question_ko": "무게가 다른 상자 A, B, C, D가 있습니다. 상자 B는 상자 C보다 무겁고, 상자 A는 상자 C 보다 가볍습니다. 상자 D는 B보다 무거울 때, 가장 무거운 상자는 무엇일까요?",
        "question_en": "There are boxes A, B, C, and D with different weights. Box B is heavier than Box C, and Box A is lighter than Box C. If box D is heavier than B, which box is the heaviest?",
        "answer_ko": "D",
        "answer_en": "D",
        "solution_abst_ko": "[OP_LIST_SOL] A B C D [OP_LIST_EOL] [OP_LIST_SOL] B C > A C < D B > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D [OP_LIST_EOL] [OP_LIST_SOL] B C > A C < D B > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'B'\nvar_f = 'C'\nvar_g = '>'\nvar_h = 'A'\nvar_i = 'C'\nvar_j = '<'\nvar_k = 'D'\nvar_l = 'B'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = 1\nvar_o = list_c[var_n-1]\nprint(var_o)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'B'\nvar_f = 'C'\nvar_g = '>'\nvar_h = 'A'\nvar_i = 'C'\nvar_j = '<'\nvar_k = 'D'\nvar_l = 'B'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = 1\nvar_o = list_c[var_n-1]\nprint(var_o)"
    },
    "1799": {
        "category": "Arithmetic calculation",
        "question_ko": "28명의 학생 중 5명씩 팀을 이룬 학생들을 상대로 다시 7명씩 팀을 이루었다면, 팀을 이루지 못한 학생은 총 몇 명입니까?",
        "question_en": "If 28 students were to form teams of 7 against students who had teams of 5, how many total students did not form teams?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "28 5 [OP_MOD] 28 28 5 [OP_MOD] [OP_SUB] 7 [OP_MOD] [OP_ADD]",
        "solution_abst_en": "28 5 [OP_MOD] 28 28 5 [OP_MOD] [OP_SUB] 7 [OP_MOD] [OP_ADD]",
        "solution_code_ko": "var_a = 28\nvar_b = 5\nvar_c = var_a % var_b\nvar_d = 28\nvar_e = 28\nvar_f = 5\nvar_g = var_e % var_f\nvar_h = var_d - var_g\nvar_i = 7\nvar_j = var_h % var_i\nvar_k = var_c + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 28\nvar_b = 5\nvar_c = var_a % var_b\nvar_d = 28\nvar_e = 28\nvar_f = 5\nvar_g = var_e % var_f\nvar_h = var_d - var_g\nvar_i = 7\nvar_j = var_h % var_i\nvar_k = var_c + var_j\nprint(int(var_k))"
    },
    "1800": {
        "category": "Geometry",
        "question_ko": "부피가 1세제곱센티미터(㎤)인 쌓기나무를 쌓아 부피가 2744세제곱센티미터(㎤)인 정육면체를 만들었습니다. 이 정육면체의 쌓기나무는 몇 층으로 쌓여 있습니까?",
        "question_en": "You created a cube with a volume of 2744 cubic centimeters (cm3) by stacking blocks with a volume of 1 cubic centimeter (cm3). How many blocks are stacked up in this cube?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "2744 1/3 [OP_POW]",
        "solution_abst_en": "2744 1/3 [OP_POW]",
        "solution_code_ko": "var_a = 2744\nvar_b = 0.3333333333333333\nvar_c = var_a ** var_b\nprint(int(eval('{:.2f}'.format(round(var_c+1e-10,2)))))",
        "solution_code_en": "var_a = 2744\nvar_b = 0.3333333333333333\nvar_c = var_a ** var_b\nprint(int(eval('{:.2f}'.format(round(var_c+1e-10,2)))))"
    },
    "1801": {
        "category": "Possibility",
        "question_ko": "각 면에 1에서 12까지의 숫자가 적힌 정십이면체의 주사위 1개를 던질 때, 나오는 눈의 수가 3의 배수인 경우의 수는?",
        "question_en": "If you throw a die of a regular dodecahedron with numbers from 1 to 12 written on each side, how many times will the number of dice roll be a multiple of 3?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "1 12 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "1 12 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 12\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 12\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "1802": {
        "category": "Comparison",
        "question_ko": "(가), (나), (다) 마을에는 포도밭이 있습니다. (나) 마을은 (가) 마을보다 포도 송이를 더 많이 수확하였고 (다) 마을은 (가) 마을보다 더 적은 포도 송이를 수확하였다면 가장 적은 포도 송이를 수확한 마을은 어디인지 구하세요.",
        "question_en": "A, B, and C villages have vineyards. If B village harvested more bunches of grapes than A village and C village harvested fewer bunches than A village, find which village harvested the fewest bunches of grapes.",
        "answer_ko": "(다)",
        "answer_en": "C",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) (다) [OP_LIST_EOL] [OP_LIST_SOL] (나) (가) > (다) (가) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] B A > C A < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nvar_c = '(다)'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '(나)'\nvar_e = '(가)'\nvar_f = '>'\nvar_g = '(다)'\nvar_h = '(가)'\nvar_i = '<'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = len(list_c)\nvar_k = list_c[var_j-1]\nprint(var_k)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'B'\nvar_e = 'A'\nvar_f = '>'\nvar_g = 'C'\nvar_h = 'A'\nvar_i = '<'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = len(list_c)\nvar_k = list_c[var_j-1]\nprint(var_k)"
    },
    "1803": {
        "category": "Geometry",
        "question_ko": "마름모의 두 대각선의 길이는 6센티미터(㎝), 4센티미터(㎝)입니다. 두 대각선의 길이를 각각 3 배로 늘였을 때, 늘인 마름모의 넓이는 몇 제곱센티미터(㎠)인지 구하시오.",
        "question_en": "The lengths of the two diagonals of the rhombus are 6 centimeters (cm) and 4 centimeters (cm). Find the area in square centimeters (cm2) of the stretched rhombus when each of the two diagonals are tripled.",
        "answer_ko": "108",
        "answer_en": "108",
        "solution_abst_ko": "6 3 [OP_MUL] 4 3 [OP_MUL] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "6 3 [OP_MUL] 4 3 [OP_MUL] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c * var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 6\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c * var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "1804": {
        "category": "Correspondence",
        "question_ko": "1/5×3/4=3/(A×5)=3/B일 때 B를 구하시오.",
        "question_en": "Find B when 1/5×3/4=3/(A×5)=3/B.",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "1/5×3/4=3/(A×5)=3/B B [OP_NUM_UNK_SOLVER]",
        "solution_abst_en": "1/5×3/4=3/(A×5)=3/B B [OP_NUM_UNK_SOLVER]",
        "solution_code_ko": "var_a = '1/5×3/4=3/(A×5)=3/B'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '1/5×3/4=3/(A×5)=3/B'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "1805": {
        "category": "Arithmetic calculation",
        "question_ko": "미국 돈 1 달러는 우리나라 돈으로 1178.2 원입니다. 우리나라 돈 120 만 원을 미국 돈 1000 달러와 10 달러짜리로 바꾸려고 합니다. 1000 달러짜리를 될 수 있는 대로 많이 바꾼다면 10 달러짜리는 몇 장으로 바꿀 수 있습니까?",
        "question_en": "One US dollar is equal to 1178.2 won in Korean money. You are going to change 1.2 million won in Korean currency into 1000 US dollars and 10 US dollars. If you change as many 1000-dollar bills as you can, how many 10-dollar bills can you exchange for?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "120 10000 [OP_MUL] 1178.2 1000 [OP_MUL] [OP_MOD] 1178.2 10 [OP_MUL] [OP_FDIV]",
        "solution_abst_en": "120 10000 [OP_MUL] 1178.2 1000 [OP_MUL] [OP_MOD] 1178.2 10 [OP_MUL] [OP_FDIV]",
        "solution_code_ko": "var_a = 120\nvar_b = 10000\nvar_c = var_a * var_b\nvar_d = 1178.2\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = var_c % var_f\nvar_h = 1178.2\nvar_i = 10\nvar_j = var_h * var_i\nvar_k = var_g // var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 120\nvar_b = 10000\nvar_c = var_a * var_b\nvar_d = 1178.2\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = var_c % var_f\nvar_h = 1178.2\nvar_i = 10\nvar_j = var_h * var_i\nvar_k = var_g // var_j\nprint(int(var_k))"
    },
    "1806": {
        "category": "Comparison",
        "question_ko": "달리기 시합에서 남준이는 2등을 했고, 윤기는 4등을 했습니다. 호석이는 윤기보다 잘했지만 남준이보다는 못했습니다. 호석이의 등수는 몇 등입니까?",
        "question_en": "In the running competition, Namjoon placed second and Yoongi placed fourth. Hoseok was better than Yoongi, but worse than Namjoon. What is Hoseok's rank?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "2 4 [OP_ADD] 2 [OP_FDIV]",
        "solution_abst_en": "2 4 [OP_ADD] 2 [OP_FDIV]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "1807": {
        "category": "Comparison",
        "question_ko": "유진이의 가방은 9/25킬로그램(㎏)이고, 승아의 가방은 0.41킬로그램(㎏)입니다. 누구의 가방이 더 무겁습니까?",
        "question_en": "Yujin's bag weighs 9/25 kilograms (kg), and Seungah's bag weighs 0.41 kilograms (kg). Whose bag is heavier?",
        "answer_ko": "승아",
        "answer_en": "Seungah",
        "solution_abst_ko": "[OP_LIST_SOL] 유진 승아 [OP_LIST_EOL] [OP_LIST_SOL] 9/25 0.41 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yujin Seungah [OP_LIST_EOL] [OP_LIST_SOL] 9/25 0.41 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '유진'\nvar_b = '승아'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.36\nvar_d = 0.41\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Yujin'\nvar_b = 'Seungah'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.36\nvar_d = 0.41\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "1808": {
        "category": "Arithmetic calculation",
        "question_ko": "공이 5개가 담겨져 있는 상자를 3개 가지고 있을 때 공의 개수는 몇 개입니까?",
        "question_en": "How many balls are there if you have 3 boxes of 5 balls?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "5 3 [OP_MUL]",
        "solution_abst_en": "5 3 [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "1809": {
        "category": "Possibility",
        "question_ko": "정국, 지민, 윤기, 유정, 태형이 중에 무기명으로 중복을 허용하여 2명에게 투표를 하려고 합니다. 가능한 경우의 수는 몇 가지 일까요?",
        "question_en": "Among Jungkook, Jimin, Yoongi, YooJeong, and Taehyung, we are going to vote for two people by allowing anonymous and duplicates. How many possible cases are there?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 지민 윤기 유정 태형 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Jimin Yoongi YooJeong Taehyung [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '지민'\nvar_c = '윤기'\nvar_d = '유정'\nvar_e = '태형'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = 2\nvar_l = 1\nvar_j = int(var_j)\nvar_k = int(var_k)\nfor i, elem in enumerate(range(var_k)):\n    var_l = var_l * (var_j-i)\nfor i, elem in enumerate(range(var_k)):\n    var_l = var_l / (i+1)\nprint(int(var_l))",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Jimin'\nvar_c = 'Yoongi'\nvar_d = 'YooJeong'\nvar_e = 'Taehyung'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = 2\nvar_l = 1\nvar_j = int(var_j)\nvar_k = int(var_k)\nfor i, elem in enumerate(range(var_k)):\n    var_l = var_l * (var_j-i)\nfor i, elem in enumerate(range(var_k)):\n    var_l = var_l / (i+1)\nprint(int(var_l))"
    },
    "1810": {
        "category": "Arithmetic calculation",
        "question_ko": "16과 24의 공배수 중 200 이하인 것의 개수를 구하시오.",
        "question_en": "Find the number of common multiples of 16 and 24 that are no more than 200.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "1 200 1 [OP_LIST_ARANGE] 16 [OP_LIST_DIVISIBLE] 24 [OP_LIST_DIVISIBLE] [OP_SET_INTERSECT] [OP_LIST_LEN]",
        "solution_abst_en": "1 200 1 [OP_LIST_ARANGE] 16 [OP_LIST_DIVISIBLE] 24 [OP_LIST_DIVISIBLE] [OP_SET_INTERSECT] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 200\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 16\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 24\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nlist_d = list(set(list_b) & set(list_c))\nvar_f = len(list_d)\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 200\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 16\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 24\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nlist_d = list(set(list_b) & set(list_c))\nvar_f = len(list_d)\nprint(int(var_f))"
    },
    "1811": {
        "category": "Arithmetic calculation",
        "question_ko": "민제네 학급에서 기부를 위해 안 입는 옷을 모았습니다. 남학생이 낸 옷은 2.6킬로그램(㎏), 여학생이 낸 옷은 5.98킬로그램(㎏)이라면, 모인 옷의 무게는 총 몇 킬로그램(㎏)입니까?",
        "question_en": "Minjae's class collected clothes they do not wear for donation. If the male student's clothes are 2.6 kilograms (kg) and the female student's clothes are 5.98 kilograms (kg), what is the total weight of the clothes collected?",
        "answer_ko": "8.58",
        "answer_en": "8.58",
        "solution_abst_ko": "2.6 5.98 [OP_ADD]",
        "solution_abst_en": "2.6 5.98 [OP_ADD]",
        "solution_code_ko": "var_a = 2.6\nvar_b = 5.98\nvar_c = var_a + var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 2.6\nvar_b = 5.98\nvar_c = var_a + var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "1812": {
        "category": "Arithmetic calculation",
        "question_ko": "장미 29송이 중 몇 송이를 사람들에게 나누어주고 12송이가 남았습니다. 사람들에게 나누어준 장미는 몇 송이입니까?",
        "question_en": "I handed out some of the 29 roses to people, and there were 12 roses left. How many roses did I hand out to people?",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "29 12 [OP_SUB]",
        "solution_abst_en": "29 12 [OP_SUB]",
        "solution_code_ko": "var_a = 29\nvar_b = 12\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 29\nvar_b = 12\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "1813": {
        "category": "Arithmetic calculation",
        "question_ko": "지효는 가진 구슬 중 3/5를 재석이에게 주었고 나머지의 2/3을 광수에게 주었다. 남은 구슬은 처음의 얼마인지 구하시오.",
        "question_en": "Jihyo gave 3/5 of the marbles she had to Jaesuk and gave 2/3 of the remaining to Gwangsoo. Find how many times as many marbles are left as there were at the beginning.",
        "answer_ko": "0.13",
        "answer_en": "0.13",
        "solution_abst_ko": "1 3/5 [OP_SUB] 1 2/3 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "1 3/5 [OP_SUB] 1 2/3 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 1\nvar_b = 0.6\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = 0.6666666666666666\nvar_f = var_d - var_e\nvar_g = var_c * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 0.6\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = 0.6666666666666666\nvar_f = var_d - var_e\nvar_g = var_c * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "1814": {
        "category": "Arithmetic calculation",
        "question_ko": "두 지점을 움직일 때 오전에는 시속 20킬로미터(㎞)로, 오후에는 시속 10킬로미터(㎞)로 이동했더니 1시간의 차이가 있었다. 오전에 움직일 때 걸린 시간을 구하시오.",
        "question_en": "When I moved the two points at 20 kilometers per hour (km) in the morning and 10 kilometers per hour (km) in the afternoon, there was a difference of 1 hour. Find the time taken to move in the morning.",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "10 1 [OP_MUL] 20 10 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "10 1 [OP_MUL] 20 10 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 1\nvar_c = var_a * var_b\nvar_d = 20\nvar_e = 10\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 10\nvar_b = 1\nvar_c = var_a * var_b\nvar_d = 20\nvar_e = 10\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))"
    },
    "1815": {
        "category": "Arithmetic calculation",
        "question_ko": "5/6과 19/12, 6/7, 9.51이 있습니다. 이들을 모두 더하면 얼마인가요?",
        "question_en": "There are 5/6, 19/12, 6/7 and 9.51. What is the sum of them?",
        "answer_ko": "12.78",
        "answer_en": "12.78",
        "solution_abst_ko": "5/6 19/12 [OP_ADD] 6/7 [OP_ADD] 9.51 [OP_ADD]",
        "solution_abst_en": "5/6 19/12 [OP_ADD] 6/7 [OP_ADD] 9.51 [OP_ADD]",
        "solution_code_ko": "var_a = 0.8333333333333334\nvar_b = 1.5833333333333333\nvar_c = var_a + var_b\nvar_d = 0.8571428571428571\nvar_e = var_c + var_d\nvar_f = 9.51\nvar_g = var_e + var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 0.8333333333333334\nvar_b = 1.5833333333333333\nvar_c = var_a + var_b\nvar_d = 0.8571428571428571\nvar_e = var_c + var_d\nvar_f = 9.51\nvar_g = var_e + var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "1816": {
        "category": "Geometry",
        "question_ko": "길이가 12센티미터(㎝)인 나무막대기의 절반 지점에 빨간 펜으로 표시를 해두었습니다. 나무막대기의 한쪽 끝부터 빨간 펜으로 표시된 부분까지의 절반 지점에는 파란 펜으로 표시를 해두었다면, 빨간 펜으로 표시된 부분과 파란 펜으로 표시된 부분 사이의 길이는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "You marked the halfway point of a 12 centimeters (cm) long wooden stick with a red pen. If you marked with a blue pen halfway from one end of the stick to the point marked with a red pen, find the length in centimeters (cm) between the point marked with a red pen and the point marked with a blue pen.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "12 2 [OP_DIV] 2 [OP_DIV]",
        "solution_abst_en": "12 2 [OP_DIV] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "1817": {
        "category": "Geometry",
        "question_ko": "직사각형과 정사각형이 있습니다. 직사각형의 넓이는 정사각형보다 15.1제곱센티미터(㎠)더 넓고, 가로와 세로의 길이는 정사각형의 한 모서리의 0.8배, 5배 입니다. 처음 정사각형의 넓이를 구하시오.",
        "question_en": "There are rectangles and squares. The area of a rectangle is 15.1 square centimeters (cm2) larger than that of a square, and its length and width are each 0.8 times and 5 times the length of one corner of the square. Find the area of the first square.",
        "answer_ko": "5.06",
        "answer_en": "5.06",
        "solution_abst_ko": "15.18 0.8 5 [OP_MUL] 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "15.18 0.8 5 [OP_MUL] 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 15.18\nvar_b = 0.8\nvar_c = 5\nvar_d = var_b * var_c\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_a / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 15.18\nvar_b = 0.8\nvar_c = 5\nvar_d = var_b * var_c\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_a / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "1818": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 0.4를 곱해야 할 것을 나누었더니 8이 되었습니다. 바르게 계산하면 얼마가 되겠습니까?",
        "question_en": "You divide the number which should be multiplied by 0.4 and get 8. How much would it be if you made it right?",
        "answer_ko": "1.28",
        "answer_en": "1.28",
        "solution_abst_ko": "8 0.4 [OP_MUL] 0.4 [OP_MUL]",
        "solution_abst_en": "8 0.4 [OP_MUL] 0.4 [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 0.4\nvar_c = var_a * var_b\nvar_d = 0.4\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 8\nvar_b = 0.4\nvar_c = var_a * var_b\nvar_d = 0.4\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "1819": {
        "category": "Arithmetic calculation",
        "question_ko": "8 %의 설탕물 300 그램(g)이 있습니다. 이 설탕물에 물을 몇 그램(g) 넣으면 5 %의 설탕물이 됩니까?",
        "question_en": "There are 300 grams (g) of 8% sugar water. How many grams (g) of water are added to this sugar water to make 5% sugar water?",
        "answer_ko": "180",
        "answer_en": "180",
        "solution_abst_ko": "300 8 100 [OP_DIV] [OP_MUL] 100 5 [OP_DIV] [OP_MUL] 300 [OP_SUB]",
        "solution_abst_en": "300 8 100 [OP_DIV] [OP_MUL] 100 5 [OP_DIV] [OP_MUL] 300 [OP_SUB]",
        "solution_code_ko": "var_a = 300\nvar_b = 8\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 100\nvar_g = 5\nvar_h = var_f / var_g\nvar_i = var_e * var_h\nvar_j = 300\nvar_k = var_i - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 300\nvar_b = 8\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 100\nvar_g = 5\nvar_h = var_f / var_g\nvar_i = var_e * var_h\nvar_j = 300\nvar_k = var_i - var_j\nprint(int(var_k))"
    },
    "1820": {
        "category": "Possibility",
        "question_ko": "1반 학생 3명과 2반 학생 3명이 함께 줄을 서 있다. 이때 1반 학생 3명이 연속으로 서 있는 경우의 수를 구하시오.",
        "question_en": "3 students from Class 1 and 3 students from Class 2 are standing in line together. At this time, find the number of cases where 3 students in Class 1 stand in a row.",
        "answer_ko": "144",
        "answer_en": "144",
        "solution_abst_ko": "3 3 [OP_ADD] 3 1 [OP_SUB] [OP_SUB] 3 3 [OP_ADD] 3 1 [OP_SUB] [OP_SUB] [OP_PERM] 3 3 [OP_PERM] [OP_MUL]",
        "solution_abst_en": "3 3 [OP_ADD] 3 1 [OP_SUB] [OP_SUB] 3 3 [OP_ADD] 3 1 [OP_SUB] [OP_SUB] [OP_PERM] 3 3 [OP_PERM] [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nvar_h = 3\nvar_i = 3\nvar_j = var_h + var_i\nvar_k = 3\nvar_l = 1\nvar_m = var_k - var_l\nvar_n = var_j - var_m\nvar_o = 1\nvar_g = int(var_g)\nvar_n = int(var_n)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o * (var_g-i)\nvar_p = 3\nvar_q = 3\nvar_r = 1\nvar_p = int(var_p)\nvar_q = int(var_q)\nfor i, elem in enumerate(range(var_q)):\n    var_r = var_r * (var_p-i)\nvar_s = var_o * var_r\nprint(int(var_s))",
        "solution_code_en": "var_a = 3\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nvar_h = 3\nvar_i = 3\nvar_j = var_h + var_i\nvar_k = 3\nvar_l = 1\nvar_m = var_k - var_l\nvar_n = var_j - var_m\nvar_o = 1\nvar_g = int(var_g)\nvar_n = int(var_n)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o * (var_g-i)\nvar_p = 3\nvar_q = 3\nvar_r = 1\nvar_p = int(var_p)\nvar_q = int(var_q)\nfor i, elem in enumerate(range(var_q)):\n    var_r = var_r * (var_p-i)\nvar_s = var_o * var_r\nprint(int(var_s))"
    },
    "1821": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 무게가 15.3킬로그램(㎏)인 벽돌의 11개는 몇 킬로그램(㎏)입니까?",
        "question_en": "How many kilograms (kg) are in 11 bricks if 5 bricks weigh 15.3 kilograms (kg)?",
        "answer_ko": "33.66",
        "answer_en": "33.66",
        "solution_abst_ko": "15.3 5 [OP_DIV] 11 [OP_MUL]",
        "solution_abst_en": "15.3 5 [OP_DIV] 11 [OP_MUL]",
        "solution_code_ko": "var_a = 15.3\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 11\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 15.3\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 11\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "1822": {
        "category": "Geometry",
        "question_ko": "육면체의 면의 개수는?",
        "question_en": "How many faces does a hexahedron have?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "6",
        "solution_abst_en": "6",
        "solution_code_ko": "var_a = 6\nprint(int(var_a))",
        "solution_code_en": "var_a = 6\nprint(int(var_a))"
    },
    "1823": {
        "category": "Correspondence",
        "question_ko": "트럭이 사과를 가게에 배달하고 있다. 첫 번째 가게에 전체의 2/5보다 300개 많은 사과를 배달하고 두 번째 가게에 남은 사과의 1/2보다 200개 적은 사과를 배달했다. 남은 사과가 800개라면 처음 트럭에 실은 사과의 개수는 몇 개인지 구하시오.",
        "question_en": "A truck is delivering apples to the store. It delivered 300 more apples than 2/5 of the total to the first store, and delivered 200 less than 1/2 of the remaining apples to the second store. If there are 800 apples left, how many apples were loaded on the truck at the beginning?",
        "answer_ko": "2500",
        "answer_en": "2500",
        "solution_abst_ko": "800 200 [OP_SUB] 1 1/2 [OP_SUB] [OP_DIV] 300 [OP_ADD] 1 2/5 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "800 200 [OP_SUB] 1 1/2 [OP_SUB] [OP_DIV] 300 [OP_ADD] 1 2/5 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 800\nvar_b = 200\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = 0.5\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 300\nvar_i = var_g + var_h\nvar_j = 1\nvar_k = 0.4\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 800\nvar_b = 200\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = 0.5\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 300\nvar_i = var_g + var_h\nvar_j = 1\nvar_k = 0.4\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nprint(int(var_m))"
    },
    "1824": {
        "category": "Comparison",
        "question_ko": "달리기 시합에서 호석이는 8등을 했고, 남준이는 6등을 했습니다. 유정이는 호석이보다 잘했지만 남준이보다는 못했습니다. 유정이는 몇 등입니까?",
        "question_en": "In the running competition, Hoseok placed 8th and Namjoon placed 6th. Yoojung did better than Hoseok, but worse than Namjoon. What rank is Yoojung in?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "8 6 [OP_ADD] 2 [OP_DIV]",
        "solution_abst_en": "8 6 [OP_ADD] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 8\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "1825": {
        "category": "Correspondence",
        "question_ko": "지영이네 반 학생 45명이 운동장에 줄을 섰습니다. 한 줄에 몇 명씩 섰더니 11줄이 되고 1명이 남았습니다. 한 줄에 몇 명씩 섰습니까?",
        "question_en": "45 students from Jiyoung's class lined up on the playground. When a certain number of students lined up in each row, it became 11 rows and 1 remained. How many students lined up in a row?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "45 1 [OP_SUB] 11 [OP_DIV]",
        "solution_abst_en": "45 1 [OP_SUB] 11 [OP_DIV]",
        "solution_code_ko": "var_a = 45\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 11\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 45\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 11\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "1826": {
        "category": "Correspondence",
        "question_ko": "윤기는 두 자리 수에 57을 빼던 중, 윤기는 두 자리 수의 일의 자리 숫자 9를 6으로 잘못 봤습니다. 윤기가 구한 차가 39라고 하면, 바르게 계산한 결과는 무엇인가요?",
        "question_en": "While Yoongi was subtracting 57 from the two-digit number, Yoongi misread 9 in the units digit of the two-digit number as 6. If the result Yoongi got is 39, what is the result of the correct calculation?",
        "answer_ko": "42",
        "answer_en": "42",
        "solution_abst_ko": "39 57 [OP_ADD] 6 9 [OP_SUB] [OP_SUB] 57 [OP_SUB]",
        "solution_abst_en": "39 57 [OP_ADD] 6 9 [OP_SUB] [OP_SUB] 57 [OP_SUB]",
        "solution_code_ko": "var_a = 39\nvar_b = 57\nvar_c = var_a + var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nvar_h = 57\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 39\nvar_b = 57\nvar_c = var_a + var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nvar_h = 57\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "1827": {
        "category": "Correspondence",
        "question_ko": "11A3을 버림하여 십의 자리까지 나타내면 1130이 됩니다. A를 구하시오.",
        "question_en": "Rounding down 11A3 to the tens place gives 1130. Find out A.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "11A3 [OP_GEN_POSSIBLE_LIST] 1130 [OP_LIST_MORE_EQUAL] 1130 10 [OP_ADD] [OP_LIST_LESS] 11A3 A [OP_LIST_FIND_UNK]",
        "solution_abst_en": "11A3 [OP_GEN_POSSIBLE_LIST] 1130 [OP_LIST_MORE_EQUAL] 1130 10 [OP_ADD] [OP_LIST_LESS] 11A3 A [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = '11A3'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 1130\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 1130\nvar_d = 10\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = '11A3'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))",
        "solution_code_en": "var_a = '11A3'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 1130\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 1130\nvar_d = 10\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = '11A3'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))"
    },
    "1828": {
        "category": "Possibility",
        "question_ko": "3개의 수의 합을 구하기 위해서 10보다 작은 서로 다른 3개의 수를 뽑았을 때, 값이 12와 동일한 경우는 모두 몇 가지인지 구하시오.",
        "question_en": "In order to find the sum of three numbers, when three different numbers less than 10 are drawn, how many ways are there that the value is equal to 12?",
        "answer_ko": "42",
        "answer_en": "42",
        "solution_abst_ko": "1 10 1 [OP_SUB] 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 12 [OP_LIST_LESS_EQUAL] 12 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "1 10 1 [OP_SUB] 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 12 [OP_LIST_LESS_EQUAL] 12 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 10\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_g = 0\n    i = int(i)\n    while i//10 > 0:\n        var_g = var_g + i%10\n        i = i//10\n    var_g = var_g + i%10\n    list_c.append(var_g)\nvar_h = 12\nlist_d = []\nfor i in list_c:\n    if i <= var_h:\n        list_d.append(i)\nvar_i = 12\nlist_e = []\nfor i in list_d:\n    if i >= var_i:\n        list_e.append(i)\nvar_j = len(list_e)\nprint(int(var_j))",
        "solution_code_en": "var_a = 1\nvar_b = 10\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_g = 0\n    i = int(i)\n    while i//10 > 0:\n        var_g = var_g + i%10\n        i = i//10\n    var_g = var_g + i%10\n    list_c.append(var_g)\nvar_h = 12\nlist_d = []\nfor i in list_c:\n    if i <= var_h:\n        list_d.append(i)\nvar_i = 12\nlist_e = []\nfor i in list_d:\n    if i >= var_i:\n        list_e.append(i)\nvar_j = len(list_e)\nprint(int(var_j))"
    },
    "1829": {
        "category": "Arithmetic calculation",
        "question_ko": "지민이네 학교는 하루에 물 7000리터(L)를 사용합니다. 지민이네 학교에서 사용한 물이 100000리터(L)가 되려면 며칠이 걸리는 지 구하세요.",
        "question_en": "Jimin's school uses 7000 liters (l) of water per day. Find how many days it will take for the water used at Jimin's school to reach 100000 liters (l).",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "100000 7000 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "100000 7000 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 100000\nvar_b = 7000\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))",
        "solution_code_en": "var_a = 100000\nvar_b = 7000\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))"
    },
    "1830": {
        "category": "Arithmetic calculation",
        "question_ko": "희진이는 이번 시험에서 여섯 과목의 점수를 80, 90, 80, 80, 100, 70으로 받았습니다. 80점 받은 과목은 몇 과목 있는지 구하시오.",
        "question_en": "Heejin received scores of 80, 90, 80, 80, 100, and 70 in six subjects on this test. How many subjects did she get 80 points on?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 80 90 80 80 100 70 [OP_LIST_EOL] 80 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "[OP_LIST_SOL] 80 90 80 80 100 70 [OP_LIST_EOL] 80 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 80\nvar_b = 90\nvar_c = 80\nvar_d = 80\nvar_e = 100\nvar_f = 70\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 80\nvar_h = 0\nvar_g = int(var_g)\nfor i in list_a:\n    i = int(i)\n    if i == var_g:\n        var_h = var_h + 1\nprint(int(var_h))",
        "solution_code_en": "var_a = 80\nvar_b = 90\nvar_c = 80\nvar_d = 80\nvar_e = 100\nvar_f = 70\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 80\nvar_h = 0\nvar_g = int(var_g)\nfor i in list_a:\n    i = int(i)\n    if i == var_g:\n        var_h = var_h + 1\nprint(int(var_h))"
    },
    "1831": {
        "category": "Correspondence",
        "question_ko": "28을 3으로 나눴을 때 몫이 9, 나머지가 A 였습니다. 이 때 A는 무엇인가요?",
        "question_en": "When 28 is divided by 3, the quotient is 9 and the remainder is A. What is A in this case?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "28 3 9 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "28 3 9 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 28\nvar_b = 3\nvar_c = 9\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 28\nvar_b = 3\nvar_c = 9\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "1832": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중 가장 큰 수는 무엇입니까?",
        "question_en": "There are three numbers 10, 11, and 12. Which number is the largest?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nprint(int(var_e))"
    },
    "1833": {
        "category": "Geometry",
        "question_ko": "한 모서리가 1미터(m)인 정육면체의 부피는 가로 50센티미터(㎝), 세로 50센티미터(㎝), 높이 20센티미터(㎝)인 직육면체 부피의 몇 배인가?",
        "question_en": "How many times the volume of a cube with an edge of 1 meter (m) is the volume of a cuboid with a width of 50 centimeters (cm), a length of 50 centimeters (cm) and a height of 20 centimeters (cm)?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "1 100 [OP_MUL] 3 [OP_POW] 50 50 [OP_MUL] 20 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "1 100 [OP_MUL] 3 [OP_POW] 50 50 [OP_MUL] 20 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c ** var_d\nvar_f = 50\nvar_g = 50\nvar_h = var_f * var_g\nvar_i = 20\nvar_j = var_h * var_i\nvar_k = var_e / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 1\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c ** var_d\nvar_f = 50\nvar_g = 50\nvar_h = var_f * var_g\nvar_i = 20\nvar_j = var_h * var_i\nvar_k = var_e / var_j\nprint(int(var_k))"
    },
    "1834": {
        "category": "Comparison",
        "question_ko": "어머니가 딸기주스 10리터(L), 포도주스를 5리터(L) 구매하셨습니다. 둘 중에 어느 것을 더 많이 샀습니까?",
        "question_en": "My mother bought 10 liters (L) of strawberry juice and 5 liters (L) of grape juice. Which of the two did she buy more of?",
        "answer_ko": "딸기주스",
        "answer_en": "strawberry",
        "solution_abst_ko": "[OP_LIST_SOL] 딸기주스 포도주스 [OP_LIST_EOL] [OP_LIST_SOL] 10 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] strawberry grape [OP_LIST_EOL] [OP_LIST_SOL] 10 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '딸기주스'\nvar_b = '포도주스'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10\nvar_d = 5\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'strawberry'\nvar_b = 'grape'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10\nvar_d = 5\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "1835": {
        "category": "Possibility",
        "question_ko": "구별이 되지 않는 파란색 연필 4자루와 빨간색 연풀 1자루를 서로 다르게 한줄로 놓으려 한다. 한줄로 놓는 방법은 몇 가지인가?",
        "question_en": "I am trying to place 4 indistinguishable blue pencils and 1 red pencil in a row differently. How many ways are there to put them in a row?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "1 4 [OP_ADD] 1 4 [OP_ADD] [OP_PERM] 4 4 [OP_PERM] [OP_DIV]",
        "solution_abst_en": "1 4 [OP_ADD] 1 4 [OP_ADD] [OP_PERM] 4 4 [OP_PERM] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 4\nvar_f = var_d + var_e\nvar_g = 1\nvar_c = int(var_c)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_c-i)\nvar_h = 4\nvar_i = 4\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nvar_k = var_g / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 1\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 4\nvar_f = var_d + var_e\nvar_g = 1\nvar_c = int(var_c)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_c-i)\nvar_h = 4\nvar_i = 4\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nvar_k = var_g / var_j\nprint(int(var_k))"
    },
    "1836": {
        "category": "Geometry",
        "question_ko": "가로 6센티미터(㎝), 세로 9센티미터(㎝)인 직사각형 A와, 가로 8센티미터(㎝), 세로 8센티미터(㎝)인 정사각형 B가 있다. 어느 것의 둘레가 더 긴가?",
        "question_en": "Rectangle A is 6 centimeters (cm) wide and 9 centimeters (cm) long, and square B is 8 centimeters (cm) wide and 8 centimeters (cm) long. Which one has a longer perimeter?",
        "answer_ko": "B",
        "answer_en": "B",
        "solution_abst_ko": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 6 9 [OP_ADD] 8 8 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 6 9 [OP_ADD] 8 8 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 9\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = 8\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 9\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = 8\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "1837": {
        "category": "Arithmetic calculation",
        "question_ko": "유나가 책을 펼쳤는데 두 쪽수의 합이 125이었습니다. 유나가 펼친 두 쪽수 중 큰 수를 쓰시오.",
        "question_en": "When Yuna opened the book, the sum of the two pages was 125. Write what larger page of the two pages is.",
        "answer_ko": "63",
        "answer_en": "63",
        "solution_abst_ko": "125 1 [OP_SUB] 2 [OP_DIV] 1 [OP_ADD]",
        "solution_abst_en": "125 1 [OP_SUB] 2 [OP_DIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 125\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 125\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "1838": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 7로 나누어야 할 것을 잘못하여 곱하였더니 115.15였습니다. 바르게 계산한 값은 얼마입니까?",
        "question_en": "You wrongly multiply a number by 7 instead of divide by 7, and it resulted 115.15. What would be the answer of the correct calculation?",
        "answer_ko": "2.35",
        "answer_en": "2.35",
        "solution_abst_ko": "115.15 7 [OP_DIV] 7 [OP_DIV]",
        "solution_abst_en": "115.15 7 [OP_DIV] 7 [OP_DIV]",
        "solution_code_ko": "var_a = 115.15\nvar_b = 7\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 115.15\nvar_b = 7\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "1839": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중에서 가장 큰 수를 가장 작은 수로 나눈 값은 얼마입니까?",
        "question_en": "There are three numbers 10, 11, and 12. What is the largest number divided by the smallest number?",
        "answer_ko": "1.20",
        "answer_en": "1.2",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_DIV]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e / var_g\nprint('{:.2f}'.format(round(var_h+1e-10,2)))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e / var_g\nprint('{:.2f}'.format(round(var_h+1e-10,2)))"
    },
    "1840": {
        "category": "Geometry",
        "question_ko": "한 변이 20센티미터(㎝)인 정사각형의 각 변의 길이를 3등분하여 작은 정사각형을 만들었습니다. 새로 만들어진 작은 정사각형 1개의 넓이는 몇 제곱센티미터(㎠)인지 반올림하여 소수 둘째 자리까지 구하시오.",
        "question_en": "A small square is made by dividing a square with a side of 20 centimeters (cm) into thirds. Find the area of the newly created small square in square centimeters (cm2), rounded to two decimal places.",
        "answer_ko": "44.44",
        "answer_en": "44.44",
        "solution_abst_ko": "20 3 [OP_DIV] 2 [OP_POW]",
        "solution_abst_en": "20 3 [OP_DIV] 2 [OP_POW]",
        "solution_code_ko": "var_a = 20\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 20\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "1841": {
        "category": "Comparison",
        "question_ko": "3개의 숫자 0.8, 1/2, 0.9가 있습니다. 2보다 작은 수의 합은 얼마인가요?",
        "question_en": "There are three numbers 0.8, 1/2, and 0.9. What is the sum of numbers less than 2?",
        "answer_ko": "2.20",
        "answer_en": "2.2",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 2 [OP_LIST_LESS] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 2 [OP_LIST_LESS] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = []\nfor i in list_a:\n    if i < var_d:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = []\nfor i in list_a:\n    if i < var_d:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "1842": {
        "category": "Geometry",
        "question_ko": "어떤 직사각형에 대각선을 그어 나눈 영역의 넓이가 576제곱센티미터(㎠)이다. 직사각형의 가로의 길이가 32센티미터(㎝)라면 높이는 몇 센티미터(㎝)입니까?",
        "question_en": "The area of a rectangle divided by a diagonal is 576 square centimeters (cm2). If the width of the rectangle is 32 centimeters (cm), what is the height in centimeters (cm)?",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "576 2 [OP_MUL] 32 [OP_DIV]",
        "solution_abst_en": "576 2 [OP_MUL] 32 [OP_DIV]",
        "solution_code_ko": "var_a = 576\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 32\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 576\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 32\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "1843": {
        "category": "Comparison",
        "question_ko": "윤기가 가진 사과가 4개, 유나가 가진 사과가 5개, 정국이는 6개의 사과를 가지고 있었지만 3개를 먹었습니다. 누가 가장 적은 사과를 가지고 있나요?",
        "question_en": "Yoongi had 4 apples, Yuna had 5, and Jungkook had 6, but he ate 3 of them. Who has the fewest apples?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 유나 정국 [OP_LIST_EOL] [OP_LIST_SOL] 4 5 6 3 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Yuna Jungkook [OP_LIST_EOL] [OP_LIST_SOL] 4 5 6 3 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '유나'\nvar_c = '정국'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 5\nvar_f = 6\nvar_g = 3\nvar_h = var_f - var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Yuna'\nvar_c = 'Jungkook'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 5\nvar_f = 6\nvar_g = 3\nvar_h = var_f - var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "1844": {
        "category": "Comparison",
        "question_ko": "20명의 학생들이 한줄로 섰습니다. 정국이는 꼴지로 줄을 섰고, 윤기와 정국이 사이에는 5명의 학생이 있습니다. 윤기 앞에 서 있는 학생은 몇 명입니까?",
        "question_en": "20 students stood in a line. Jungkook is the last in line, and there are 5 students between Yoongi and Jungkook. How many students are standing in front of Yoongi?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "20 1 [OP_SUB] 5 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "20 1 [OP_SUB] 5 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 20\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "1845": {
        "category": "Comparison",
        "question_ko": "지민, 윤기, 태형, 남준이는 모두 같은 아파트에 살고 있습니다. 지민이네 집은 윤기보다 높고, 태형이는 남준이보다 낮고, 윤기는 남준이보다 높을 때, 가장 낮은 층에 살고 있는 사람은 누구입니까?",
        "question_en": "Jimin, Yoongi, Taehyung, and Namjoon all live in the same apartment. When Jimin's house is higher than Yoongi's, Taehyung's is lower than Namjoon's, and Yoongi's is higher than Namjoon's, who lives on the lowest floor?",
        "answer_ko": "태형",
        "answer_en": "Taehyung",
        "solution_abst_ko": "[OP_LIST_SOL] 지민 윤기 태형 남준 [OP_LIST_EOL] [OP_LIST_SOL] 지민 윤기 > 태형 남준 < 윤기 남준 > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jimin Yoongi Taehyung Namjoon [OP_LIST_EOL] [OP_LIST_SOL] Jimin Yoongi > Taehyung Namjoon < Yoongi Namjoon > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '지민'\nvar_b = '윤기'\nvar_c = '태형'\nvar_d = '남준'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '지민'\nvar_f = '윤기'\nvar_g = '>'\nvar_h = '태형'\nvar_i = '남준'\nvar_j = '<'\nvar_k = '윤기'\nvar_l = '남준'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)",
        "solution_code_en": "var_a = 'Jimin'\nvar_b = 'Yoongi'\nvar_c = 'Taehyung'\nvar_d = 'Namjoon'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'Jimin'\nvar_f = 'Yoongi'\nvar_g = '>'\nvar_h = 'Taehyung'\nvar_i = 'Namjoon'\nvar_j = '<'\nvar_k = 'Yoongi'\nvar_l = 'Namjoon'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)"
    },
    "1846": {
        "category": "Possibility",
        "question_ko": "2, 3, 7, 9의 숫자를 한 번씩 사용하여 얻을 수 있는 네 자리 수 중에서 두 번째로 큰 수를 구하시오",
        "question_en": "Find the second largest four-digit number that can be made by using the digits 2, 3, 7, and 9 without duplication.",
        "answer_ko": "9723",
        "answer_en": "9723",
        "solution_abst_ko": "[OP_LIST_SOL] 2 3 7 9 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 2 3 7 9 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = 7\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint(int(var_g))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = 7\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint(int(var_g))"
    },
    "1847": {
        "category": "Comparison",
        "question_ko": "학교 강당에서 열린 행사에 학생들이 참석하였습니다. 긴 의자 하나에 9명씩 앉았더니 앉지 못하는 학생이 한 명 있었습니다. 그래서 긴 의자 하나에 10명씩 앉혔더니 아무도 앉지 않은 긴 의자 한 개를 제외한 모든 긴 의자에 10명씩 앉았습니다. 이때 행사에 참석한 학생은 모두 몇 명인지 구하시오.",
        "question_en": "Students attended the event held in the school auditorium. When every nine people sat on per bench, there was one student who could not sit down. So we made every ten people sit on per bench, and on each bench, 10 people sat, except one where no one sat. Find how many students attend the event.",
        "answer_ko": "100",
        "answer_en": "100",
        "solution_abst_ko": "1 10 [OP_ADD] 10 9 [OP_SUB] [OP_DIV] 9 [OP_MUL] 1 [OP_ADD]",
        "solution_abst_en": "1 10 [OP_ADD] 10 9 [OP_SUB] [OP_DIV] 9 [OP_MUL] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 10\nvar_c = var_a + var_b\nvar_d = 10\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 9\nvar_i = var_g * var_h\nvar_j = 1\nvar_k = var_i + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 1\nvar_b = 10\nvar_c = var_a + var_b\nvar_d = 10\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 9\nvar_i = var_g * var_h\nvar_j = 1\nvar_k = var_i + var_j\nprint(int(var_k))"
    },
    "1848": {
        "category": "Possibility",
        "question_ko": "4, 3, 1, 7, 9 중 3개를 사용하여 일의 자리 숫자가 3인 두 번째 큰 수는 무엇입니까?",
        "question_en": "3 of 4, 3, 1, 7, and 9 were used once to form a three-digit number. What is the second greatest number with the unit digit 3?",
        "answer_ko": "943",
        "answer_en": "943",
        "solution_abst_ko": "[OP_LIST_SOL] 4 3 1 7 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 3 [OP_LIST_SEARCH_FIXED_DIGIT] 2 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 4 3 1 7 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 3 [OP_LIST_SEARCH_FIXED_DIGIT] 2 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 4\nvar_b = 3\nvar_c = 1\nvar_d = 7\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nvar_h = 3\nlist_c = [] \nvar_g = int(var_g)\nvar_h = int(var_h)\nfor i in list_b:\n    i = int(i)\n    if (i//var_g)%10 == var_h:\n        list_c.append(i)\nvar_i = 2\nlist_d=list_c.copy()\nlist_d.sort()\nvar_j = list_d[-var_i]\nprint(int(var_j))",
        "solution_code_en": "var_a = 4\nvar_b = 3\nvar_c = 1\nvar_d = 7\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nvar_h = 3\nlist_c = [] \nvar_g = int(var_g)\nvar_h = int(var_h)\nfor i in list_b:\n    i = int(i)\n    if (i//var_g)%10 == var_h:\n        list_c.append(i)\nvar_i = 2\nlist_d=list_c.copy()\nlist_d.sort()\nvar_j = list_d[-var_i]\nprint(int(var_j))"
    },
    "1849": {
        "category": "Arithmetic calculation",
        "question_ko": "1상자에 장난감을 9개씩 담으려고 합니다. 장난감 81개를 상자에 모두 담으려면 상자는 몇 개 필요합니까?",
        "question_en": "I'm trying to put 9 toys in 1 box. How many boxes are needed to fit all 81 toys in the box?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "81 9 [OP_DIV]",
        "solution_abst_en": "81 9 [OP_DIV]",
        "solution_code_ko": "var_a = 81\nvar_b = 9\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 81\nvar_b = 9\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "1850": {
        "category": "Correspondence",
        "question_ko": "두 자연수 A, B가 있습니다. A를 B로 나누면 몫은 28이고 나머지는 4가 됩니다. 이 식에서 A가 가장 작을 때 A를 구하시오.",
        "question_en": "There are two natural numbers A and B. When A is divided by B, the quotient is 28 and the remainder is 4. Find A when A is the smallest in this equation.",
        "answer_ko": "144",
        "answer_en": "144",
        "solution_abst_ko": "5 28 [OP_MUL] 4 [OP_ADD]",
        "solution_abst_en": "5 28 [OP_MUL] 4 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 28\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 28\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "1851": {
        "category": "Geometry",
        "question_ko": "칠각형의 모든 대각선의 개수를 구하시오.",
        "question_en": "Find the number of all diagonals in a heptagon.",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "7 7 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "7 7 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 7\nvar_b = 7\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 7\nvar_b = 7\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "1852": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 4로 나누어야 할 것은 잘못하여 8로 나누었더니 몫이 6이고, 나머지가 4가 되었습니다. 바르게 계산한 답은 얼마가 되겠습니까?",
        "question_en": "A number that should be divided by 4 is mistakenly divided by 8, so the quotient is 6 and the remainder is 4. What would be the correct answer?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "6 8 [OP_MUL] 4 [OP_ADD] 4 [OP_DIV]",
        "solution_abst_en": "6 8 [OP_MUL] 4 [OP_ADD] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 4\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 6\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 4\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "1853": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 -5/12를 더하고 다시 -5/2를 빼면 1/3일 때, 어떤 수를 구하시오.",
        "question_en": "If you add -5/12 and subtract -5/2 from a number, it becomes 1/3. What is the number?",
        "answer_ko": "-1.75",
        "answer_en": "-1.75",
        "solution_abst_ko": "1/3 -5/2 [OP_ADD] -5/12 [OP_SUB]",
        "solution_abst_en": "1/3 -5/2 [OP_ADD] -5/12 [OP_SUB]",
        "solution_code_ko": "var_a = 0.3333333333333333\nvar_b = -2.5\nvar_c = var_a + var_b\nvar_d = -0.4166666666666667\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.3333333333333333\nvar_b = -2.5\nvar_c = var_a + var_b\nvar_d = -0.4166666666666667\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "1854": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 24를 빼면 25의 배수이고 어떤 수는 300보다 크다. 가능한 어떤 수들 중 가장 작은 값을 구하시오.",
        "question_en": "A number minus 24 is a multiple of 25, and a number is greater than 300. Find the smallest of all possible numbers.",
        "answer_ko": "301",
        "answer_en": "301",
        "solution_abst_ko": "300 25 [OP_ADD] 24 [OP_SUB]",
        "solution_abst_en": "300 25 [OP_ADD] 24 [OP_SUB]",
        "solution_code_ko": "var_a = 300\nvar_b = 25\nvar_c = var_a + var_b\nvar_d = 24\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 300\nvar_b = 25\nvar_c = var_a + var_b\nvar_d = 24\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "1855": {
        "category": "Geometry",
        "question_ko": "축구부 36명이 252밀리리터(㎖)의 음료수를 똑같이 나눠마셨습니다. 축구부원 1명이 마신 음료수의 양은 얼마인지 구하시오.",
        "question_en": "Thirty-six people on the soccer team equally shared 252 milliliters (ml) of the beverage. Find the amount of water consumed by one member of the soccer team.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "252 36 1 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "252 36 1 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 252\nvar_b = 36\nvar_c = 1\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 252\nvar_b = 36\nvar_c = 1\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "1856": {
        "category": "Correspondence",
        "question_ko": "어떤 소수의 소수점을 오른쪽으로 한 자리 옮기면 원래의 소수보다 5.4만큼 커집니다. 원래의 소수를 구하시오.",
        "question_en": "When you move the decimal point of a prime number to the right by one place, it increases 5.4 more compared to the original number. Find the original prime number.",
        "answer_ko": "0.60",
        "answer_en": "0.6",
        "solution_abst_ko": "5.4 9 [OP_DIV]",
        "solution_abst_en": "5.4 9 [OP_DIV]",
        "solution_code_ko": "var_a = 5.4\nvar_b = 9\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 5.4\nvar_b = 9\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "1857": {
        "category": "Geometry",
        "question_ko": "모든 모서리의 길이의 합이 180센티미터(㎝)인 정육면체의 겉넓이는 몇 제곱센티미터(㎠)입니까?",
        "question_en": "What is the surface area in square centimeters (cm2) of a cube whose lengths add up to 180 centimeters (cm)?",
        "answer_ko": "1350",
        "answer_en": "1350",
        "solution_abst_ko": "180 12 [OP_DIV] 180 12 [OP_DIV] [OP_MUL] 6 [OP_MUL]",
        "solution_abst_en": "180 12 [OP_DIV] 180 12 [OP_DIV] [OP_MUL] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 180\nvar_b = 12\nvar_c = var_a / var_b\nvar_d = 180\nvar_e = 12\nvar_f = var_d / var_e\nvar_g = var_c * var_f\nvar_h = 6\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 180\nvar_b = 12\nvar_c = var_a / var_b\nvar_d = 180\nvar_e = 12\nvar_f = var_d / var_e\nvar_g = var_c * var_f\nvar_h = 6\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "1858": {
        "category": "Arithmetic calculation",
        "question_ko": "1분에 36.6리터(L)의 물이 나오는 수도로 수조에 물을 받는데 수조 바닥에 구멍이 나서 1분에 2.4리터(L)의 물이 샌다고 합니다. 수조에 처음 10리터(L)의 물이 들어 있었다면 7분 45초 후에 수조에 담겨 있는 물은 몇 리터(L)입니까?",
        "question_en": "The faucet is filling the water tank at the speed of 36.6 liters (l) per minute, but there is a hole in the bottom of the tank, so that water leaks out of the tank at the speed of 2.4 liters (l) per minute. If the water tank contained 10 liters (l) of water initially, how many liters (l) of water is in the water tank after 7 minutes 45 seconds?",
        "answer_ko": "275.05",
        "answer_en": "275.05",
        "solution_abst_ko": "10 36.6 2.4 [OP_SUB] 7 45 60 [OP_DIV] [OP_ADD] [OP_MUL] [OP_ADD]",
        "solution_abst_en": "10 36.6 2.4 [OP_SUB] 7 45 60 [OP_DIV] [OP_ADD] [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 36.6\nvar_c = 2.4\nvar_d = var_b - var_c\nvar_e = 7\nvar_f = 45\nvar_g = 60\nvar_h = var_f / var_g\nvar_i = var_e + var_h\nvar_j = var_d * var_i\nvar_k = var_a + var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 10\nvar_b = 36.6\nvar_c = 2.4\nvar_d = var_b - var_c\nvar_e = 7\nvar_f = 45\nvar_g = 60\nvar_h = var_f / var_g\nvar_i = var_e + var_h\nvar_j = var_d * var_i\nvar_k = var_a + var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "1859": {
        "category": "Geometry",
        "question_ko": "둘레가 48센티미터(㎝) 인 직사각형이 있습니다. 이 직사각형의 세로가 가로보다 2센티미터(㎝) 더 길다면, 가로는 몇 센티미터(㎝) 입니까?",
        "question_en": "You have a rectangle with a perimeter of 48 centimeters (cm). If the length of this rectangle is 2 centimeters (cm) longer than its width, how long is its width in centimeters (cm)?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "48 2 [OP_DIV] 2 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "48 2 [OP_DIV] 2 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 48\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 48\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "1860": {
        "category": "Geometry",
        "question_ko": "삼각형의 넓이가 24제곱센티미터(㎠)이고 높이가 8센티미터(㎝)일 때, 밑변의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "If the area of a triangle is 24 square centimeters (cm2) and its height is 8 centimeters (cm), what is the length of the base in centimeters (cm)?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "24 2 [OP_MUL] 8 [OP_DIV]",
        "solution_abst_en": "24 2 [OP_MUL] 8 [OP_DIV]",
        "solution_code_ko": "var_a = 24\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 24\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "1861": {
        "category": "Comparison",
        "question_ko": "용찬이네 집에서 민주네 집까지는 0.76킬로미터(㎞)이며 지원이네 집까지는 17/25킬로미터(㎞)입니다. 용찬이네 집에서 어느 친구네 집까지가 더 가까운지 구하시오.",
        "question_en": "It is 0.76 kilometers (km) from Yongchan's house to Minju's house, and it is 17/25 kilometers (km) to Jiwon's house. Find which friend's house is closer to Yongchan's house.",
        "answer_ko": "지원",
        "answer_en": "Jiwon",
        "solution_abst_ko": "[OP_LIST_SOL] 민주 지원 [OP_LIST_EOL] [OP_LIST_SOL] 0.76 17/25 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Minju Jiwon [OP_LIST_EOL] [OP_LIST_SOL] 0.76 17/25 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '민주'\nvar_b = '지원'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.76\nvar_d = 0.68\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Minju'\nvar_b = 'Jiwon'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.76\nvar_d = 0.68\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "1862": {
        "category": "Arithmetic calculation",
        "question_ko": "숫자 5, 6, 2로 나누어 떨어질 수 있는 네 자리 수는 모두 몇 개 있습니까?",
        "question_en": "How many four-digit numbers are there if they can be divided by 5, 6, and 2 without any remainder?",
        "answer_ko": "300",
        "answer_en": "300",
        "solution_abst_ko": "1000 9999 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] 6 [OP_LIST_DIVISIBLE] 2 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "1000 9999 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] 6 [OP_LIST_DIVISIBLE] 2 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 6\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 2\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 6\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 2\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))"
    },
    "1863": {
        "category": "Possibility",
        "question_ko": "1, 3, 6, 8을 한 번 씩만 사용하여 만들 수 있는 네 자리 수는 모두 몇 개인지 구하시오.",
        "question_en": "How many four-digit numbers can be formed by using 1, 3, 6, and 8 only once?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 6 8 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 6 8 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 6\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 6\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "1864": {
        "category": "Arithmetic calculation",
        "question_ko": "연속하는 8개의 짝수를 더하였더니 424가 되었습니다. 8개의 짝수 중 첫번째 수를 구하시오.",
        "question_en": "Adding 8 consecutive even numbers gives 424. Find the first of the 8 even numbers.",
        "answer_ko": "46",
        "answer_en": "46",
        "solution_abst_ko": "424 0 8 1 [OP_SUB] 2 [OP_MUL] 2 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 8 [OP_DIV]",
        "solution_abst_en": "424 0 8 1 [OP_SUB] 2 [OP_MUL] 2 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 8 [OP_DIV]",
        "solution_code_ko": "var_a = 424\nvar_b = 0\nvar_c = 8\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = 2\nlist_a = [i for i in range(var_b, var_g + 1, var_h)]\nlist_a = [float(i) for i in list_a]\nvar_i = sum(list_a)\nvar_j = var_a - var_i\nvar_k = 8\nvar_l = var_j / var_k\nprint(int(var_l))",
        "solution_code_en": "var_a = 424\nvar_b = 0\nvar_c = 8\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = 2\nlist_a = [i for i in range(var_b, var_g + 1, var_h)]\nlist_a = [float(i) for i in list_a]\nvar_i = sum(list_a)\nvar_j = var_a - var_i\nvar_k = 8\nvar_l = var_j / var_k\nprint(int(var_l))"
    },
    "1865": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 2미터(m) 50센티미터(㎝)인 막대가 있습니다. 이 막대를 잘라 25센티미터(㎝)짜리 막대를 여러 개 만들려고 합니다. 이 막대를 몇 번 잘라야 합니까?",
        "question_en": "You have a rod that is 2 meters (m) 50 centimeters (cm) long. You are going to cut this stick to make several 25 centimeter (cm) sticks. How many times should you cut this rod?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "2 100 [OP_MUL] 50 [OP_ADD] 25 [OP_DIV] 1 [OP_SUB]",
        "solution_abst_en": "2 100 [OP_MUL] 50 [OP_ADD] 25 [OP_DIV] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 2\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 50\nvar_e = var_c + var_d\nvar_f = 25\nvar_g = var_e / var_f\nvar_h = 1\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 2\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 50\nvar_e = var_c + var_d\nvar_f = 25\nvar_g = var_e / var_f\nvar_h = 1\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "1866": {
        "category": "Arithmetic calculation",
        "question_ko": "(가) 자동차는 시속 60킬로미터(km)로 달리고 (나) 자동차는 1시간에 45킬로미터(km)를 달립니다. 같은 시작점에서 출발해서 5시간이 흘렀다면 (가) 자동차는 (나) 자동차보다 몇 킬로미터(km) 앞서있는지 구하시오.",
        "question_en": "(A) car travels at 60 kilometers (km) per hour and (B) car travels at 45 kilometers (km) per hour. If 5 hours have passed since starting from the same starting point, how many kilometers (km) is (A) car ahead of (B) car?",
        "answer_ko": "75",
        "answer_en": "75",
        "solution_abst_ko": "60 5 [OP_MUL] 45 5 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "60 5 [OP_MUL] 45 5 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 60\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 45\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 60\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 45\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "1867": {
        "category": "Possibility",
        "question_ko": "서희네 집에서 학교까지 가는 버스 노선은 3개, 지하철 노선은 2개일 때 버스 또는 지하철로 가는 경우의 수를 구하시오.",
        "question_en": "If there are 3 bus routes and 2 subway routes going from Seohee's house to school, find the number of ways to go by bus or subway.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "3 2 [OP_ADD]",
        "solution_abst_en": "3 2 [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "1868": {
        "category": "Arithmetic calculation",
        "question_ko": "덩크슛은 손으로 농구공을 잡고 공중으로 높이 뛰어 올라 공을 3.05미터(m) 높이의 골대 안으로 내리꽂듯이 집어넣는 슛을 말합니다. 덩크슛으로 들어간 공이 떨어진 높이의 0.7만큼 튀어 오른다면 이 공이 세 번째로 땅에 닿을 때까지 움직인 거리는 모두 몇 미터(m)입니까?",
        "question_en": "A dunk shot is a shot in which a player jumps high into the air and slams a ball into a 3.05-meter (m) high goal post with a ball in the hand. If a dunked ball bounces 0.7 of its landing height, how many meters (m) does the ball travel until it hits the ground for the third time?",
        "answer_ko": "10.31",
        "answer_en": "10.31",
        "solution_abst_ko": "3.05 3.05 0.7 [OP_MUL] 2 [OP_MUL] [OP_ADD] 3.05 0.7 2 [OP_POW] [OP_MUL] 2 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "3.05 3.05 0.7 [OP_MUL] 2 [OP_MUL] [OP_ADD] 3.05 0.7 2 [OP_POW] [OP_MUL] 2 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 3.05\nvar_b = 3.05\nvar_c = 0.7\nvar_d = var_b * var_c\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_a + var_f\nvar_h = 3.05\nvar_i = 0.7\nvar_j = 2\nvar_k = var_i ** var_j\nvar_l = var_h * var_k\nvar_m = 2\nvar_n = var_l * var_m\nvar_o = var_g + var_n\nprint('{:.2f}'.format(round(var_o+1e-10,2)))",
        "solution_code_en": "var_a = 3.05\nvar_b = 3.05\nvar_c = 0.7\nvar_d = var_b * var_c\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_a + var_f\nvar_h = 3.05\nvar_i = 0.7\nvar_j = 2\nvar_k = var_i ** var_j\nvar_l = var_h * var_k\nvar_m = 2\nvar_n = var_l * var_m\nvar_o = var_g + var_n\nprint('{:.2f}'.format(round(var_o+1e-10,2)))"
    },
    "1869": {
        "category": "Geometry",
        "question_ko": "한 모서리의 길이가 7㎝인 정육면체의 부피는 몇 세제곱센티미터입니까?",
        "question_en": "What is the volume in cubic centimeters (cm3) of a cube with an edge of 7 cm?",
        "answer_ko": "343",
        "answer_en": "343",
        "solution_abst_ko": "7 3 [OP_POW]",
        "solution_abst_en": "7 3 [OP_POW]",
        "solution_code_ko": "var_a = 7\nvar_b = 3\nvar_c = var_a ** var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 7\nvar_b = 3\nvar_c = var_a ** var_b\nprint(int(var_c))"
    },
    "1870": {
        "category": "Arithmetic calculation",
        "question_ko": "9/5, 3/5, 1.7, 3/2, 0.4, 9/10 중에서 1보다 작은 수는 모두 몇개입니까?",
        "question_en": "How many numbers are less than 1 among 9/5, 3/5, 1.7, 3/2, 0.4, and 9/10?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 9/5 3/5 1.7 3/2 0.4 9/10 [OP_LIST_EOL] 1 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 9/5 3/5 1.7 3/2 0.4 9/10 [OP_LIST_EOL] 1 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1.8\nvar_b = 0.6\nvar_c = 1.7\nvar_d = 1.5\nvar_e = 0.4\nvar_f = 0.9\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 1\nlist_b = []\nfor i in list_a:\n    if i < var_g:\n        list_b.append(i)\nvar_h = len(list_b)\nprint(int(var_h))",
        "solution_code_en": "var_a = 1.8\nvar_b = 0.6\nvar_c = 1.7\nvar_d = 1.5\nvar_e = 0.4\nvar_f = 0.9\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 1\nlist_b = []\nfor i in list_a:\n    if i < var_g:\n        list_b.append(i)\nvar_h = len(list_b)\nprint(int(var_h))"
    },
    "1871": {
        "category": "Possibility",
        "question_ko": "1부터 12까지의 자연수가 각각 하나씩 적힌 12개의 공이 들어있는 주머니에서 1개의 공을 뽑았다가 다시 넣고, 다시 1개의 공을 뽑을 때, 처음 나온 공에 적힌 수가 3 미만이고, 다음에 나온 공에 적힌 수가 10 이상인 경우의 수를 구하시오.",
        "question_en": "When one ball is drawn from a bag containing 12 balls each of which is written each of natural numbers from 1 to 12 and put back in and then draw one ball again, find the number of cases in which the number written on the first ball is less than 3, and the number written on the next ball is 10 or greater, ",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "1 12 1 [OP_LIST_ARANGE] 3 [OP_LIST_LESS] [OP_LIST_LEN] [OP_LIST_POP] 10 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN] [OP_MUL]",
        "solution_abst_en": "1 12 1 [OP_LIST_ARANGE] 3 [OP_LIST_LESS] [OP_LIST_LEN] [OP_LIST_POP] 10 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN] [OP_MUL]",
        "solution_code_ko": "var_a = 1\nvar_b = 12\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nfor i in list_a:\n    if i < var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nvar_f = 10\nlist_c = []\nfor i in list_a:\n    if i >= var_f:\n        list_c.append(i)\nvar_g = len(list_c)\nvar_h = var_e * var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 1\nvar_b = 12\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nfor i in list_a:\n    if i < var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nvar_f = 10\nlist_c = []\nfor i in list_a:\n    if i >= var_f:\n        list_c.append(i)\nvar_g = len(list_c)\nvar_h = var_e * var_g\nprint(int(var_h))"
    },
    "1872": {
        "category": "Arithmetic calculation",
        "question_ko": "태형이는 한 걸음에 0.45미터(m)를 이동할 수 있습니다. 태형이가 90걸음씩 13번 이동했다면 태형이가 걸은 거리는 몇 미터(m)인지 구하세요.",
        "question_en": "Consider Taehyung can move 0.45 meters (m) in one step. If he moved 90 steps for 13 times, find the distance he walked in meters (m).",
        "answer_ko": "526.50",
        "answer_en": "526.5",
        "solution_abst_ko": "0.45 90 [OP_MUL] 13 [OP_MUL]",
        "solution_abst_en": "0.45 90 [OP_MUL] 13 [OP_MUL]",
        "solution_code_ko": "var_a = 0.45\nvar_b = 90\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.45\nvar_b = 90\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "1873": {
        "category": "Arithmetic calculation",
        "question_ko": "가로가 18미터(m), 세로가 24미터(m)인 직사각형 모양의 땅이 있습니다. 네 모퉁이에는 반드시 말뚝을 박기로 하고 같은 간격으로 땅의 둘레에 말뚝을 박을 때, 최소한 몇 개의 말뚝이 필요합니까?",
        "question_en": "There is a rectangular piece of land measuring 18 meters (m) wide and 24 meters (m) long. If you must drive stakes at the four corners and drive stakes at equal intervals around the perimeter of the land, at least how many stakes are needed?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "18 18 24 [OP_GCD] [OP_DIV] 24 18 24 [OP_GCD] [OP_DIV] [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "18 18 24 [OP_GCD] [OP_DIV] 24 18 24 [OP_GCD] [OP_DIV] [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 18\nvar_b = 18\nvar_c = 24\nvar_d = math.gcd(int(var_c), int(var_b))\nvar_e = var_a / var_d\nvar_f = 24\nvar_g = 18\nvar_h = 24\nvar_i = math.gcd(int(var_h), int(var_g))\nvar_j = var_f / var_i\nvar_k = var_e + var_j\nvar_l = 2\nvar_m = var_k * var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 18\nvar_b = 18\nvar_c = 24\nvar_d = math.gcd(int(var_c), int(var_b))\nvar_e = var_a / var_d\nvar_f = 24\nvar_g = 18\nvar_h = 24\nvar_i = math.gcd(int(var_h), int(var_g))\nvar_j = var_f / var_i\nvar_k = var_e + var_j\nvar_l = 2\nvar_m = var_k * var_l\nprint(int(var_m))"
    },
    "1874": {
        "category": "Arithmetic calculation",
        "question_ko": "2의 배수이면서 3의 배수이면서 8의 배수이면서 9의 배수인 수 중 다섯 자리 수는 모두 몇 개 입니까?",
        "question_en": "How many 5-digit numbers are there that are multiples of 2, 3, 8, and 9?",
        "answer_ko": "1250",
        "answer_en": "1250",
        "solution_abst_ko": "10000 99999 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "10000 99999 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 10000\nvar_b = 99999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 3\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = len(list_e)\nprint(int(var_h))",
        "solution_code_en": "var_a = 10000\nvar_b = 99999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 3\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = len(list_e)\nprint(int(var_h))"
    },
    "1875": {
        "category": "Correspondence",
        "question_ko": "40을 어떤 수에 더해야 할 것을 잘못하여 21을 어떤 수에 곱한 결과는 63이 나옵니다. 바르게 계산하면 얼마인가요?",
        "question_en": "I had to add 40 to a certain number, but I accidentally multiply 21 by that number and the result is 63. How much is it if I calculate it correctly?",
        "answer_ko": "43",
        "answer_en": "43",
        "solution_abst_ko": "63 21 [OP_DIV] 40 [OP_ADD]",
        "solution_abst_en": "63 21 [OP_DIV] 40 [OP_ADD]",
        "solution_code_ko": "var_a = 63\nvar_b = 21\nvar_c = var_a / var_b\nvar_d = 40\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 63\nvar_b = 21\nvar_c = var_a / var_b\nvar_d = 40\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "1876": {
        "category": "Possibility",
        "question_ko": "가, 나, 다, 라, 마, 바 6명의 사람이 있다. 이 중 3명을 뽑아 일렬로 세우는 경우의 수를 구하시오.",
        "question_en": "There are 6 people: A, B, C, D, E, and F. Find the number of ways in which 3 of them are lined up.",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "6 3 [OP_PERM]",
        "solution_abst_en": "6 3 [OP_PERM]",
        "solution_code_ko": "var_a = 6\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))"
    },
    "1877": {
        "category": "Comparison",
        "question_ko": "(라) 과일은 (가) 과일보다 무겁고 (나) 과일보다 가볍습니다. (나) 과일은 (다) 과일보다 가볍습니다. 가장 가벼운 과일은 무엇입니까?",
        "question_en": "Fruit (d) is heavier than fruit (a) and lighter than fruit (b). Fruit (b) is lighter than fruit (c). Which fruit is the lightest?",
        "answer_ko": "(가)",
        "answer_en": "(a)",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) (다) (라) [OP_LIST_EOL] [OP_LIST_SOL] (라) (가) > (라) (나) < (나) (다) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (a) (b) (c) (d) [OP_LIST_EOL] [OP_LIST_SOL] (d) (a) > (d) (b) < (b) (c) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nvar_c = '(다)'\nvar_d = '(라)'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '(라)'\nvar_f = '(가)'\nvar_g = '>'\nvar_h = '(라)'\nvar_i = '(나)'\nvar_j = '<'\nvar_k = '(나)'\nvar_l = '(다)'\nvar_m = '<'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)",
        "solution_code_en": "var_a = '(a)'\nvar_b = '(b)'\nvar_c = '(c)'\nvar_d = '(d)'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '(d)'\nvar_f = '(a)'\nvar_g = '>'\nvar_h = '(d)'\nvar_i = '(b)'\nvar_j = '<'\nvar_k = '(b)'\nvar_l = '(c)'\nvar_m = '<'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)"
    },
    "1878": {
        "category": "Possibility",
        "question_ko": "10, 30, 50이라고 적힌 카드를 2장씩 상자에 넣고, 이 중 3장의 카드를 뽑아 합을 구하려고 합니다. 서로 다른 합이 될 수 있는 수는 모두 몇 가지입니까?",
        "question_en": "Put two number of cards that marked 10, 30, 50 each into a box and draw 3 of them to find the sum. How many different sums can there be?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "[OP_LIST_SOL] 10 30 50 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_MUL] 3 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] 10 30 50 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_MUL] 3 [OP_COMB]",
        "solution_code_ko": "var_a = 10\nvar_b = 30\nvar_c = 50\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = 3\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h / (i+1)\nprint(int(var_h))",
        "solution_code_en": "var_a = 10\nvar_b = 30\nvar_c = 50\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = 3\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h / (i+1)\nprint(int(var_h))"
    },
    "1879": {
        "category": "Arithmetic calculation",
        "question_ko": "경연이는 과자 20개 중 7개를 친구들에게 주었고 다시 친구들로 부터 5개의 과자를 받았다. 경연이가 가지고 있는 과자의 개수를 구하시오.",
        "question_en": "Gyeongyeon gave 7 out of 20 cookies to his friends and received 5 more cookies from her friends. Find the number of cookies Gyeongyeon now has.",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "20 7 [OP_SUB] 5 [OP_ADD]",
        "solution_abst_en": "20 7 [OP_SUB] 5 [OP_ADD]",
        "solution_code_ko": "var_a = 20\nvar_b = 7\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 7\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "1880": {
        "category": "Possibility",
        "question_ko": "세 자리 자연수 7AB가 7의 배수일 때, 두 자리 자연수 AB로 가능한 수는 몇 가지인지 구하시오.",
        "question_en": "If the three-digit natural number 7AB is a multiple of 7, how many numbers are possible to become two-digit natural number AB?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "7AB [OP_GEN_POSSIBLE_LIST] 7 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "7AB [OP_GEN_POSSIBLE_LIST] 7 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '7AB'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 7\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))",
        "solution_code_en": "var_a = '7AB'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 7\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))"
    },
    "1881": {
        "category": "Arithmetic calculation",
        "question_ko": "32를 6.544으로 나누었을 때의 몫을 구하시오.",
        "question_en": "Find the quotient when 32 is divided by 6.544.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "32 6.544 [OP_FDIV]",
        "solution_abst_en": "32 6.544 [OP_FDIV]",
        "solution_code_ko": "var_a = 32\nvar_b = 6.544\nvar_c = var_a // var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 32\nvar_b = 6.544\nvar_c = var_a // var_b\nprint(int(var_c))"
    },
    "1882": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 14를 곱하였더니 458.64가 되었습니다. 어떤 수를 17로 나누었을 때의 값을 반올림하여 소수 둘째 자리까지 나타내시오.",
        "question_en": "When a number is multiplied by 14, it is 458.64. Find the value of the number divided by 17 and round it up to two decimal places.",
        "answer_ko": "1.93",
        "answer_en": "1.93",
        "solution_abst_ko": "458.64 14 [OP_DIV] 17 [OP_DIV] 2 [OP_ROUND]",
        "solution_abst_en": "458.64 14 [OP_DIV] 17 [OP_DIV] 2 [OP_ROUND]",
        "solution_code_ko": "var_a = 458.64\nvar_b = 14\nvar_c = var_a / var_b\nvar_d = 17\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = round(float(var_e)+1e-10, var_f)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 458.64\nvar_b = 14\nvar_c = var_a / var_b\nvar_d = 17\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = round(float(var_e)+1e-10, var_f)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "1883": {
        "category": "Possibility",
        "question_ko": "4개의 숫자 1, 5, 6, 9를 한 번씩 사용하여 백의 자리 숫자가 1인 가장 큰 세 자리 수를 구하시오.",
        "question_en": "Using the four digits 1, 5, 6, and 9 once, find the largest three-digit number with hundreds digit of 1.",
        "answer_ko": "196",
        "answer_en": "196",
        "solution_abst_ko": "[OP_LIST_SOL] 1 5 6 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 100 1 [OP_LIST_SEARCH_FIXED_DIGIT] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1 5 6 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 100 1 [OP_LIST_SEARCH_FIXED_DIGIT] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1\nvar_b = 5\nvar_c = 6\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 100\nvar_g = 1\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 5\nvar_c = 6\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 100\nvar_g = 1\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nprint(int(var_i))"
    },
    "1884": {
        "category": "Correspondence",
        "question_ko": "정미가 어떤 수에 -2/3을 더하고 -4/5를 곱했더니 그 결과가 -1/2이었습니다. 어떤 수를 구하시오.",
        "question_en": "When Jung-mi added -2/3 to a number and multiplied it by -4/5, the result was -1/2. Find that number. ",
        "answer_ko": "1.29",
        "answer_en": "1.29",
        "solution_abst_ko": "-1/2 -4/5 [OP_DIV] -2/3 [OP_SUB]",
        "solution_abst_en": "-1/2 -4/5 [OP_DIV] -2/3 [OP_SUB]",
        "solution_code_ko": "var_a = -0.5\nvar_b = -0.8\nvar_c = var_a / var_b\nvar_d = -0.6666666666666666\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = -0.5\nvar_b = -0.8\nvar_c = var_a / var_b\nvar_d = -0.6666666666666666\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "1885": {
        "category": "Arithmetic calculation",
        "question_ko": "유정이가 가지고 있던 색종이 210장 중 30장을 유나에게 주었더니 유정이가 가진 색정이의 수가 유나보다 50장 더 많아졌습니다. 처음 유나가 가지고 있던 색종이는 몇 장일까요?",
        "question_en": "When you gave Yuna 30 of the 210 pieces of colored paper that Yoojung had, the number of colored paper that Yoojung had was 50 more than Yuna. How many pieces of colored paper did Yuna have at first?",
        "answer_ko": "100",
        "answer_en": "100",
        "solution_abst_ko": "210 30 [OP_SUB] 50 [OP_SUB] 30 [OP_SUB]",
        "solution_abst_en": "210 30 [OP_SUB] 50 [OP_SUB] 30 [OP_SUB]",
        "solution_code_ko": "var_a = 210\nvar_b = 30\nvar_c = var_a - var_b\nvar_d = 50\nvar_e = var_c - var_d\nvar_f = 30\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 210\nvar_b = 30\nvar_c = var_a - var_b\nvar_d = 50\nvar_e = var_c - var_d\nvar_f = 30\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "1886": {
        "category": "Arithmetic calculation",
        "question_ko": "등산을 할 때는 두 가지의 길이 있다. 하나는 짧은 길이고 하나는 2킬로미터(㎞)더 긴 길이다. 올라갈 때는 짧은 길로 시속 3킬로미터(㎞)로 걸었고, 내려올 때는 긴 길로 시속 4킬로미터(㎞)로 내려왔다. 등산은 총 4시간이 걸렸다. 내려올 때 걸린 시간을 구하라.",
        "question_en": "When it comes to mountain climbing, there are two routes. One is shorter and the other is 2 kilometers (km) longer. When I went up, I walked at 3 kilometers (km) per hour on a short path, and when I came down, I came down a long path at 4 kilometers (km) per hour. The hike took 4 hours in total. Find the time taken to come down.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "4 2 4 [OP_DIV] [OP_SUB] 1 3 [OP_DIV] 1 4 [OP_DIV] [OP_ADD] [OP_DIV] 2 [OP_ADD] 4 [OP_DIV]",
        "solution_abst_en": "4 2 4 [OP_DIV] [OP_SUB] 1 3 [OP_DIV] 1 4 [OP_DIV] [OP_ADD] [OP_DIV] 2 [OP_ADD] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = 3\nvar_h = var_f / var_g\nvar_i = 1\nvar_j = 4\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_e / var_l\nvar_n = 2\nvar_o = var_m + var_n\nvar_p = 4\nvar_q = var_o / var_p\nprint(int(var_q))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = 3\nvar_h = var_f / var_g\nvar_i = 1\nvar_j = 4\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_e / var_l\nvar_n = 2\nvar_o = var_m + var_n\nvar_p = 4\nvar_q = var_o / var_p\nprint(int(var_q))"
    },
    "1887": {
        "category": "Geometry",
        "question_ko": "실을 가지고 한 변의 길이가 4센티미터(㎝)인 정육각형을 만들었습니다. 똑같은 실을 가지고 정사각형을 만들었을 때, 이 정사각형의 넓이는 얼마입니까?",
        "question_en": "You made a regular hexagon that has a side length of 4 centimeters (cm) with yarn. If you make a square using the same yarn as the regular hexagon, what is the area of the square?",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "4 6 [OP_MUL] 4 [OP_DIV] 2 [OP_POW]",
        "solution_abst_en": "4 6 [OP_MUL] 4 [OP_DIV] 2 [OP_POW]",
        "solution_code_ko": "var_a = 4\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e ** var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e ** var_f\nprint(int(var_g))"
    },
    "1888": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중에서 가장 큰 수와 그 다음으로 큰 수의 차는 얼마입니까?",
        "question_en": "There are three numbers 10, 11, and 12. What is the difference between the largest number and the next largest number?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = var_e - var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = var_e - var_g\nprint(int(var_h))"
    },
    "1889": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 5로 나눈 다음 16을 더한 수가 58입니다. 어떤 수를 15로 나눈 뒤 74를 더한 값을 구하시오.",
        "question_en": "A number divided by 5 plus 16 equals 58. Find the value of the following equation: a number divided by 15 and added by 74.",
        "answer_ko": "88",
        "answer_en": "88",
        "solution_abst_ko": "58 16 [OP_SUB] 5 [OP_MUL] 15 [OP_DIV] 74 [OP_ADD]",
        "solution_abst_en": "58 16 [OP_SUB] 5 [OP_MUL] 15 [OP_DIV] 74 [OP_ADD]",
        "solution_code_ko": "var_a = 58\nvar_b = 16\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c * var_d\nvar_f = 15\nvar_g = var_e / var_f\nvar_h = 74\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 58\nvar_b = 16\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c * var_d\nvar_f = 15\nvar_g = var_e / var_f\nvar_h = 74\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "1890": {
        "category": "Comparison",
        "question_ko": "유정이가 책상 위에 여러가지 색깔의 공을 한 줄로 놓았습니다. 빨간색, 파란색, 노란색, 보라색, 흰색 공을 차례로 놓았을 때, 마지막 공의 색깔은 무엇입니까?",
        "question_en": "Yoojung placed balls of various colors in a row on the desk. When she places red, blue, yellow, purple, and white ball in sequence, what color is the last ball?",
        "answer_ko": "흰색",
        "answer_en": "white",
        "solution_abst_ko": "[OP_LIST_SOL] 빨간색 파란색 노란색 보라색 흰색 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] red blue yellow purple white [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '빨간색'\nvar_b = '파란색'\nvar_c = '노란색'\nvar_d = '보라색'\nvar_e = '흰색'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = list_a[var_f-1]\nprint(var_g)",
        "solution_code_en": "var_a = 'red'\nvar_b = 'blue'\nvar_c = 'yellow'\nvar_d = 'purple'\nvar_e = 'white'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = list_a[var_f-1]\nprint(var_g)"
    },
    "1891": {
        "category": "Correspondence",
        "question_ko": "17을 2로 나눴더니 몫이 A가 되었고, 나머지는 B가 되었습니다. 이 때 B를 구하시오.",
        "question_en": "When 17 is divided by 2, the quotient is A and the remainder is B. Find what B is.",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "17 2 [OP_MOD]",
        "solution_abst_en": "17 2 [OP_MOD]",
        "solution_code_ko": "var_a = 17\nvar_b = 2\nvar_c = var_a % var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 17\nvar_b = 2\nvar_c = var_a % var_b\nprint(int(var_c))"
    },
    "1892": {
        "category": "Arithmetic calculation",
        "question_ko": "6/5과 1/10이 있습니다. 이들의 차이는 얼마인가요?",
        "question_en": "There are 6/5 and 1/10. What is the difference between them?",
        "answer_ko": "1.10",
        "answer_en": "1.1",
        "solution_abst_ko": "6/5 1/10 [OP_SUB] [OP_ABS]",
        "solution_abst_en": "6/5 1/10 [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 1.2\nvar_b = 0.1\nvar_c = var_a - var_b\nvar_d = abs(var_c)\nprint('{:.2f}'.format(round(var_d+1e-10,2)))",
        "solution_code_en": "var_a = 1.2\nvar_b = 0.1\nvar_c = var_a - var_b\nvar_d = abs(var_c)\nprint('{:.2f}'.format(round(var_d+1e-10,2)))"
    },
    "1893": {
        "category": "Comparison",
        "question_ko": "소라는 4와 6을 모았습니다. 희수는 7과 5를 모았고, 지연이는 3과 8을 모았습니다. 모은 수의 합이 가장 큰 사람은 누구입니까?",
        "question_en": "Sora collected 4 and 6. Heesu collected 7 and 5, and Jiyeon collected 3 and 8. Who has the greatest sum of numbers?",
        "answer_ko": "희수",
        "answer_en": "Heesu",
        "solution_abst_ko": "[OP_LIST_SOL] 소라 희수 지연 [OP_LIST_EOL] [OP_LIST_SOL] 4 6 [OP_ADD] 7 5 [OP_ADD] 3 8 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Sora Heesu Jiyeon [OP_LIST_EOL] [OP_LIST_SOL] 4 6 [OP_ADD] 7 5 [OP_ADD] 3 8 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '소라'\nvar_b = '희수'\nvar_c = '지연'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 6\nvar_f = var_d + var_e\nvar_g = 7\nvar_h = 5\nvar_i = var_g + var_h\nvar_j = 3\nvar_k = 8\nvar_l = var_j + var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'Sora'\nvar_b = 'Heesu'\nvar_c = 'Jiyeon'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 6\nvar_f = var_d + var_e\nvar_g = 7\nvar_h = 5\nvar_i = var_g + var_h\nvar_j = 3\nvar_k = 8\nvar_l = var_j + var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "1894": {
        "category": "Comparison",
        "question_ko": "장미는 앞에서 7번째 줄, 뒤에서 16번째 줄, 왼쪽에서 9번째 열, 오른쪽에서 13번째 열에 심어져 있습니다. 각 열마다 심어져 있는 꽃의 수가 같다고 할 때, 심어져 있는 꽃은 모두 몇 송이입니까?",
        "question_en": "A rose is planted in the 7th row from the front, the 16th row from the back, the 9th row from the left, and the 13th row from the right. If the number of flowers planted in each row is the same, how many flowers are planted in all?",
        "answer_ko": "462",
        "answer_en": "462",
        "solution_abst_ko": "7 16 [OP_ADD] 1 [OP_SUB] 9 13 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "7 16 [OP_ADD] 1 [OP_SUB] 9 13 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 7\nvar_b = 16\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 9\nvar_g = 13\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 7\nvar_b = 16\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 9\nvar_g = 13\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))"
    },
    "1895": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 10을 뺐더니 결과가 15가 나왔습니다. 어떤 수에 5를 더하면?",
        "question_en": "Subtracting 10 from a number yields 15. How much do you get if you add 5 to this number?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "15 10 [OP_ADD] 5 [OP_ADD]",
        "solution_abst_en": "15 10 [OP_ADD] 5 [OP_ADD]",
        "solution_code_ko": "var_a = 15\nvar_b = 10\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 10\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "1896": {
        "category": "Arithmetic calculation",
        "question_ko": "보민이는 오늘 2킬로미터(㎞) 600미터(m) 걸었고, 윤식이는 3700미터(m) 걸었습니다. 보민이와 윤식이가 오늘 하루 걸은 거리는 몇 미터(m)인지 구하시오.",
        "question_en": "The weight of Jung-min's dog is 2 kilograms (kg) and 600 grams (g), and the weight of the cat is 3700 grams (g). Find the total weight in grams (g) of the animals that Jung-min raises.",
        "answer_ko": "6300",
        "answer_en": "6300",
        "solution_abst_ko": "2 1000 [OP_MUL] 600 [OP_ADD] 3700 [OP_ADD]",
        "solution_abst_en": "2 1000 [OP_MUL] 600 [OP_ADD] 3700 [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 600\nvar_e = var_c + var_d\nvar_f = 3700\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 600\nvar_e = var_c + var_d\nvar_f = 3700\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "1897": {
        "category": "Correspondence",
        "question_ko": "성훈이는 중간시험을 봤다. 성훈이의 국어 점수를 수학점수로 나누면 몫이 1.2로 나누어떨어지고, 수학점수를 영어점수로 나누면 5/6으로 나누어떨어진다. 국어점수를 영어점수로 나누면 그 몫은 얼마인가?",
        "question_en": "Sunghoon took the midterm exam. When Sunghoon's Korean score is divided by his math score and the quotient is 1.2, and when his math score is divided by his English score and the quotient is 5/6. If you divide his Korean score by his English score, what is the quotient?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "1.2 5/6 [OP_MUL]",
        "solution_abst_en": "1.2 5/6 [OP_MUL]",
        "solution_code_ko": "var_a = 1.2\nvar_b = 0.8333333333333334\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 1.2\nvar_b = 0.8333333333333334\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "1898": {
        "category": "Arithmetic calculation",
        "question_ko": "물, 우유의 평균 리터(L)가 94리터(L)이다. 커피가 100리터(L) 있다면 물, 우유, 커피의 평균 리터(L)는 무엇인가",
        "question_en": "The average liter (L) of water and milk is 94 liters (L). If there is 100 liters of coffee, what is the average liter of water, milk and coffee?",
        "answer_ko": "96",
        "answer_en": "96",
        "solution_abst_ko": "94 2 [OP_MUL] 100 [OP_ADD] 3 [OP_DIV]",
        "solution_abst_en": "94 2 [OP_MUL] 100 [OP_ADD] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 94\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 94\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "1899": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 2번째로 큰 수와 2번째로 작은 수의 합은 얼마입니까?",
        "question_en": "There are five numbers 10, 11, 12, 13, and 14. What is the sum of the second largest number and the second smallest number?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))"
    },
    "1900": {
        "category": "Comparison",
        "question_ko": "(가), (나), (다) 과일이 있다. (가) 과일은 (나) 과일보다 가볍고 (다) 과일은 (가) 과일보다 가벼울 때 가장 무거운 과일은 무엇인가?",
        "question_en": "There are three fruits, (a), (b), and (c). If fruit (a) is lighter than fruit (b) and fruit (c) is lighter than fruit (a), which fruit is the heaviest?",
        "answer_ko": "(나)",
        "answer_en": "(b)",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) (다) [OP_LIST_EOL] [OP_LIST_SOL] (가) (나) < (다) (가) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (a) (b) (c) [OP_LIST_EOL] [OP_LIST_SOL] (a) (b) < (c) (a) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nvar_c = '(다)'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '(가)'\nvar_e = '(나)'\nvar_f = '<'\nvar_g = '(다)'\nvar_h = '(가)'\nvar_i = '<'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(var_k)",
        "solution_code_en": "var_a = '(a)'\nvar_b = '(b)'\nvar_c = '(c)'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '(a)'\nvar_e = '(b)'\nvar_f = '<'\nvar_g = '(c)'\nvar_h = '(a)'\nvar_i = '<'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(var_k)"
    },
    "1901": {
        "category": "Geometry",
        "question_ko": "어떤 정육면체는 모서리의 길이가 3센티미터(㎝)이다. 이 정육면체에서 모서리의 길이가 1센티미터(㎝)인 정육면체를 면의 개수만큼 잘라내었다면, 남은 부분의 부피는 얼마인가?",
        "question_en": "A cube has an edge length of 3 centimeters (cm). If a cube with an edge length of 1 centimeters (cm) is cut out from this cube as many times as the number of the faces of the cube, what is the volume of the remaining part?",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "3 3 [OP_POW] 1 3 [OP_POW] 6 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "3 3 [OP_POW] 1 3 [OP_POW] 6 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 3\nvar_b = 3\nvar_c = var_a ** var_b\nvar_d = 1\nvar_e = 3\nvar_f = var_d ** var_e\nvar_g = 6\nvar_h = var_f * var_g\nvar_i = var_c - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 3\nvar_b = 3\nvar_c = var_a ** var_b\nvar_d = 1\nvar_e = 3\nvar_f = var_d ** var_e\nvar_g = 6\nvar_h = var_f * var_g\nvar_i = var_c - var_h\nprint(int(var_i))"
    },
    "1902": {
        "category": "Arithmetic calculation",
        "question_ko": "8과 22 중 큰 수를 작은 수로 나눈 몫을 소수로 나타내어 보세요.",
        "question_en": "Express the quotient of the number obtained from dividing the larger number by a smaller number out of numbers 8 and 22, as a decimal number.",
        "answer_ko": "2.75",
        "answer_en": "2.75",
        "solution_abst_ko": "22 8 [OP_DIV]",
        "solution_abst_en": "22 8 [OP_DIV]",
        "solution_code_ko": "var_a = 22\nvar_b = 8\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 22\nvar_b = 8\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "1903": {
        "category": "Correspondence",
        "question_ko": "13을 A로 나눴을 때 몫이 B, 나머지가 3이였습니다. A와 B는 모두 자연수입니다. 이 때, 가능한 A 중 가장 큰 수는 무엇인가요?",
        "question_en": "When 13 is divided by A, the quotient is B and the remainder is 3. A and B are both natural numbers. What is the largest number among possible A's?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "13 3 [OP_SUB]",
        "solution_abst_en": "13 3 [OP_SUB]",
        "solution_code_ko": "var_a = 13\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 13\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "1904": {
        "category": "Arithmetic calculation",
        "question_ko": "같은 만화책 9권과 같은 동화책 7권의 무게의 합이 10.98킬로그램(㎏)이었습니다. 만화책 한 권의 무게가 0.8킬로그램(㎏)일 때 동화책 한 권의 무게는 몇 킬로그램(㎏)인지 구하시오.",
        "question_en": "The sum of the weight of 9 comic books and 7 children's books was 10.98 kilograms (kg). If a comic book weighs 0.8 kilograms (kg), how many kilograms (kg) does a children's book weigh?",
        "answer_ko": "0.54",
        "answer_en": "0.54",
        "solution_abst_ko": "10.98 0.8 9 [OP_MUL] [OP_SUB] 7 [OP_DIV]",
        "solution_abst_en": "10.98 0.8 9 [OP_MUL] [OP_SUB] 7 [OP_DIV]",
        "solution_code_ko": "var_a = 10.98\nvar_b = 0.8\nvar_c = 9\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 7\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 10.98\nvar_b = 0.8\nvar_c = 9\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 7\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "1905": {
        "category": "Correspondence",
        "question_ko": "한초는 가지고 있던 색 테이프의 1/5를 사용하여 미술 작품을 만들고, 그 나머지의 3/4를 가영이에게 주었습니다. 남은 색 테이프의 길이가 1미터(m) 50센티미터(㎝)라면, 한초가 처음에 가지고 있었던 색 테이프의 길이는 몇 미터(m)입니까?",
        "question_en": "Hancho used 1/5 of the colored tape he had to make a work of art and gave 3/4 of the remaining to Gayeong. If the remaining length of the colored tape was 1 meter (m) and 50 centimeters (cm), how many meters (m) was the length of the colored tape that Hancho had at the beginning?",
        "answer_ko": "7.50",
        "answer_en": "7.5",
        "solution_abst_ko": "1 50 100 [OP_DIV] [OP_ADD] 1 3/4 [OP_SUB] [OP_DIV] 1 1/5 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "1 50 100 [OP_DIV] [OP_ADD] 1 3/4 [OP_SUB] [OP_DIV] 1 1/5 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 50\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 1\nvar_g = 0.75\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 1\nvar_k = 0.2\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 50\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 1\nvar_g = 0.75\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 1\nvar_k = 0.2\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))"
    },
    "1906": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.9, 1/3 중에서 0.4보다 작은 수는 몇 개입니까?",
        "question_en": "How many numbers among 0.8, 1/2, 0.9, 1/3 are less than 0.4?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.4\nlist_b = []\nfor i in list_a:\n    if i < var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.4\nlist_b = []\nfor i in list_a:\n    if i < var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "1907": {
        "category": "Arithmetic calculation",
        "question_ko": "마트에서 집까지의 거리는 800미터(m)이고, 집에서 학원까지의 거리는 1킬로미터(㎞) 300미터(m), 학원에서 음식점까지의 거리는 1700미터(m)입니다. 마트에서 집을 거쳐 학원까지의 거리는 학원에서 음식점까지의 거리보다 몇 미터(m) 더 멉니까?",
        "question_en": "It takes 800 meters (m) from the mart to home,1 kilometer (km) and 300 meters (m) from home to the academy, and 1700 meters (m) from the academy to the restaurant. How many meters (m) from the mart to the academy via home is longer than from the academy to the restaurant?",
        "answer_ko": "400",
        "answer_en": "400",
        "solution_abst_ko": "800 1 1000 [OP_MUL] 300 [OP_ADD] [OP_ADD] 1700 [OP_SUB]",
        "solution_abst_en": "800 1 1000 [OP_MUL] 300 [OP_ADD] [OP_ADD] 1700 [OP_SUB]",
        "solution_code_ko": "var_a = 800\nvar_b = 1\nvar_c = 1000\nvar_d = var_b * var_c\nvar_e = 300\nvar_f = var_d + var_e\nvar_g = var_a + var_f\nvar_h = 1700\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 800\nvar_b = 1\nvar_c = 1000\nvar_d = var_b * var_c\nvar_e = 300\nvar_f = var_d + var_e\nvar_g = var_a + var_f\nvar_h = 1700\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "1908": {
        "category": "Possibility",
        "question_ko": "2, 4, 5 총 3장의 수 카드 중 2장을 사용하여 두 자리 수를 만들려고 합니다. 만들 수 있는 수 중에 4로 나누어 떨어지는 수는 모두 몇 개인가요?",
        "question_en": "We are going to use 2 of our 3 number cards 2, 4, 5  to create a double-digit number. How many possible numbers from those are divisible by 4?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 2 4 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 4 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 2 4 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 4 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 4\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 4\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "1909": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 9센티미터(㎝)인 정사각형을 만들기 위해 문방구에서 60센티미터(㎝)짜리 철사를 샀습니다. 이 철사를 이용해서 정사각형을 만든다면, 몇 센티미터(㎝)의 철사가 남겠습니까?",
        "question_en": "You bought 60 centimeters (cm) of wire from a stationery store to make a square with a side length of 9 centimeters (cm). If you use this wire to make a square, how many centimeters (cm) of wire will you have left?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "60 9 4 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "60 9 4 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 60\nvar_b = 9\nvar_c = 4\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 60\nvar_b = 9\nvar_c = 4\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "1910": {
        "category": "Comparison",
        "question_ko": "우유를 지성이는 9/25리터(L) 마셨고, 영표는 0.41리터(L) 마셨습니다. 누가 우유를 더 많이 마셨습니까?",
        "question_en": "Jiseong drank 9/25 liters (L) of milk, and Youngpyo drank 0.41 liters (L). Who drank more milk?",
        "answer_ko": "영표",
        "answer_en": "Youngpyo",
        "solution_abst_ko": "[OP_LIST_SOL] 지성 영표 [OP_LIST_EOL] [OP_LIST_SOL] 9/25 0.41 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jiseong Youngpyo [OP_LIST_EOL] [OP_LIST_SOL] 9/25 0.41 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '지성'\nvar_b = '영표'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.36\nvar_d = 0.41\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Jiseong'\nvar_b = 'Youngpyo'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.36\nvar_d = 0.41\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "1911": {
        "category": "Correspondence",
        "question_ko": "주머니 속의 구슬을 7명에게 나누어주었더니 12개씩 나누어주고 5개가 남았습니다. 이 구슬을 8명에게 똑같이 나누어 준다면 몇 개씩 나누어 줄 수 있는지 구하시오.",
        "question_en": "Giving the marbles in the bag to 7 people, 12 each, and 5 left. If you divide these marbles equally among 8 people, how many marbles can you divide for each people?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "12 7 [OP_MUL] 5 [OP_ADD] 8 [OP_FDIV]",
        "solution_abst_en": "12 7 [OP_MUL] 5 [OP_ADD] 8 [OP_FDIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e // var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 12\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e // var_f\nprint(int(var_g))"
    },
    "1912": {
        "category": "Correspondence",
        "question_ko": "진우의 동생의 나이에 어떤 자연수를 곱하면 90이다. 가능한 진우의 동생의 나이는 모두 몇 개인지 구하시오.",
        "question_en": "If you multiply Jinwoo's younger sibling's age by some natural number, you get 90. Find the age of all possible Jinwoo's younger sibling.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "90 [OP_LIST_GET_DIVISOR] [OP_LIST_LEN]",
        "solution_abst_en": "90 [OP_LIST_GET_DIVISOR] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 90\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = len(list_a)\nprint(int(var_b))",
        "solution_code_en": "var_a = 90\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = len(list_a)\nprint(int(var_b))"
    },
    "1913": {
        "category": "Geometry",
        "question_ko": "세 각뿔 (가), (나), (다)가 있습니다. 세 각뿔의 꼭짓점의 수의 합이 40개일 때 세 각뿔의 모서리의 수의 합은 몇 개입니까?",
        "question_en": "There are three pyramids (a), (b), and (c). Given that the sum of the vertices of the three pyramids is 40, what is the sum of the edges of these pyramids?",
        "answer_ko": "74",
        "answer_en": "74",
        "solution_abst_ko": "40 3 [OP_SUB] 2 [OP_MUL]",
        "solution_abst_en": "40 3 [OP_SUB] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 40\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 40\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "1914": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 36을 더해야 할 것을 잘못하여 7을 나눈 결과는 8이 되었습니다. 바르게 계산한 결과는 얼마인가요?",
        "question_en": "You mistakenly divided 7 to a number instead of adding 36, and got 8. What is the correct calculation result?",
        "answer_ko": "92",
        "answer_en": "92",
        "solution_abst_ko": "8 7 [OP_MUL] 36 [OP_ADD]",
        "solution_abst_en": "8 7 [OP_MUL] 36 [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 36\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 36\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "1915": {
        "category": "Arithmetic calculation",
        "question_ko": "두 자리 숫자를 빼는 연산에서 빼는 숫자의 십의 자리 숫자 2를 실수로 5로 보고 일의 자리 숫자 4를 실수로 9로 보고 계산을 했더니 14가 나왔습니다. 바르게 계산하면 얼마입니까?",
        "question_en": "In the calculation of subtracting a two-digit number, the number 2 in the tens digit of the subtracting number was mistakenly read as 5, and the number 4 in the units digit was mistakenly read as 9, and the result was 14. How much do get when you calculate correctly?",
        "answer_ko": "49",
        "answer_en": "49",
        "solution_abst_ko": "14 1 4 9 [OP_SUB] [OP_MUL] [OP_SUB] 10 2 5 [OP_SUB] [OP_MUL] [OP_SUB]",
        "solution_abst_en": "14 1 4 9 [OP_SUB] [OP_MUL] [OP_SUB] 10 2 5 [OP_SUB] [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 14\nvar_b = 1\nvar_c = 4\nvar_d = 9\nvar_e = var_c - var_d\nvar_f = var_b * var_e\nvar_g = var_a - var_f\nvar_h = 10\nvar_i = 2\nvar_j = 5\nvar_k = var_i - var_j\nvar_l = var_h * var_k\nvar_m = var_g - var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 14\nvar_b = 1\nvar_c = 4\nvar_d = 9\nvar_e = var_c - var_d\nvar_f = var_b * var_e\nvar_g = var_a - var_f\nvar_h = 10\nvar_i = 2\nvar_j = 5\nvar_k = var_i - var_j\nvar_l = var_h * var_k\nvar_m = var_g - var_l\nprint(int(var_m))"
    },
    "1916": {
        "category": "Possibility",
        "question_ko": "자연수 5, 3, 1, 9 중 3장을 골라 세 자리 수를 만듭니다. 큰 수부터 차례로 쓸 때, 10번째 수를 구하시오.",
        "question_en": "Choose three of the natural numbers 5, 3, 1, and 9 to form three-digit numbers. When writing the numbers in order from largest to smallest, find the 10th number.",
        "answer_ko": "531",
        "answer_en": "531",
        "solution_abst_ko": "[OP_LIST_SOL] 5 3 1 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 5 3 1 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 5\nvar_b = 3\nvar_c = 1\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 3\nvar_c = 1\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint(int(var_g))"
    },
    "1917": {
        "category": "Arithmetic calculation",
        "question_ko": "1학년 학생과 2학년 학생이 합하여 24명이 있습니다. 이 중 1학년 학생에게만 초콜릿 50개를 똑같이 나누어 주었더니 2개가 남았습니다. 2학년 학생의 수가 1학년 학생의 수의 2배일 때, 1학년 학생은 초콜릿을 몇 개씩 받았습니까?",
        "question_en": "There are a total of 24 students in Year 1 and Year 2. Of these, 50 chocolates were distributed equally to only the first-year students, and two chocolates were left. If the number of second-year students is twice the number of first-year students, how many chocolates did the first-year students get?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "50 2 [OP_SUB] 24 2 1 [OP_ADD] [OP_FDIV] [OP_FDIV]",
        "solution_abst_en": "50 2 [OP_SUB] 24 2 1 [OP_ADD] [OP_FDIV] [OP_FDIV]",
        "solution_code_ko": "var_a = 50\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 24\nvar_e = 2\nvar_f = 1\nvar_g = var_e + var_f\nvar_h = var_d // var_g\nvar_i = var_c // var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 50\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 24\nvar_e = 2\nvar_f = 1\nvar_g = var_e + var_f\nvar_h = var_d // var_g\nvar_i = var_c // var_h\nprint(int(var_i))"
    },
    "1918": {
        "category": "Correspondence",
        "question_ko": "24는 어떤 수에 2/5를 곱한 값입니다. 어떤 수에 1/15를 곱하면 얼마가 됩니까?",
        "question_en": "24 is the value of a number multiplied by 2/5. What number do you get when the number is multiplied by 1/15?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "24 1 2/5 [OP_DIV] [OP_MUL] 1/15 [OP_MUL]",
        "solution_abst_en": "24 1 2/5 [OP_DIV] [OP_MUL] 1/15 [OP_MUL]",
        "solution_code_ko": "var_a = 24\nvar_b = 1\nvar_c = 0.4\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 0.06666666666666667\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 24\nvar_b = 1\nvar_c = 0.4\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 0.06666666666666667\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "1919": {
        "category": "Arithmetic calculation",
        "question_ko": "처음 농장에 수탉이 암탉보다 6마리 더 많이 있었습니다. 오늘 수탉 4마리와 암탉 8마리를 더 사왔더니 암탉은 모두 20마리가 되었습니다. 현재 농장에 있는 수탉은 몇 마리입니까?",
        "question_en": "At first there were 6 more roosters on the farm compared to hens. Today I bought 4 more roosters and 8 more hens, bringing the total to 20 hens. How many roosters are currently on the farm?",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "20 8 [OP_SUB] 6 [OP_ADD] 4 [OP_ADD]",
        "solution_abst_en": "20 8 [OP_SUB] 6 [OP_ADD] 4 [OP_ADD]",
        "solution_code_ko": "var_a = 20\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = var_c + var_d\nvar_f = 4\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 20\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = var_c + var_d\nvar_f = 4\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "1920": {
        "category": "Arithmetic calculation",
        "question_ko": "선우네 학교 3학년은 한 반에 21명씩 4개 반이 있습니다. 3학년 학생이 모두 자신의 화분에 씨앗을 2개씩 심어 키우려고 합니다. 씨앗은 모두 몇 개가 필요합니까?",
        "question_en": "Seonwoo's school's 3rd graders have 4 classes with 21 students in each class. All 3rd graders are trying to plant 2 seeds in their pots. How many seeds do they need in all?",
        "answer_ko": "168",
        "answer_en": "168",
        "solution_abst_ko": "21 4 [OP_MUL] 2 [OP_MUL]",
        "solution_abst_en": "21 4 [OP_MUL] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 21\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 21\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "1921": {
        "category": "Correspondence",
        "question_ko": "호석이는 어떤 수에 8을 더해 88을 얻었습니다. 어떤 수를 10으로 나눈 결과값을 정확히 구하시오.",
        "question_en": "Hoseok added 8 to a certain number and got 88. Find the exact result of dividing this number by 10.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "88 8 [OP_SUB] 10 [OP_DIV]",
        "solution_abst_en": "88 8 [OP_SUB] 10 [OP_DIV]",
        "solution_code_ko": "var_a = 88\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 10\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 88\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 10\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "1922": {
        "category": "Arithmetic calculation",
        "question_ko": "미국 돈 140달러는 우리나라 돈 158760원으로 바꿀 수 있다고 합니다. 미국 돈에 대한 우리나라 돈의 환율은 얼마인지 구하세요.",
        "question_en": "How much is 1 dollar in Korean money when 140 dollars is converted into 158,760 won in Korean money?",
        "answer_ko": "1134",
        "answer_en": "1134",
        "solution_abst_ko": "158760 140 [OP_DIV]",
        "solution_abst_en": "158760 140 [OP_DIV]",
        "solution_code_ko": "var_a = 158760\nvar_b = 140\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 158760\nvar_b = 140\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "1923": {
        "category": "Geometry",
        "question_ko": "한 면의 둘레가 52센티미터(㎝)인 정육면체가 있습니다. 이 정육면체의 겉넓이는 몇 제곱센티미터입니까?",
        "question_en": "There is a cube with a side perimeter of 52 centimeters (cm). What is the surface area of this cube in square centimeters (cm2)?",
        "answer_ko": "1014",
        "answer_en": "1014",
        "solution_abst_ko": "52 4 [OP_DIV] 52 4 [OP_DIV] [OP_MUL] 6 [OP_MUL]",
        "solution_abst_en": "52 4 [OP_DIV] 52 4 [OP_DIV] [OP_MUL] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 52\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 52\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = var_c * var_f\nvar_h = 6\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 52\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 52\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = var_c * var_f\nvar_h = 6\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "1924": {
        "category": "Geometry",
        "question_ko": "어느 농장은 직사각형 모양의 울타리를 갖고 있습니다. 이 울타리는 둘레가 30미터(m)이고, 가로의 길이가 세로의 길이의 2배입니다. 울타리의 가로 길이는 몇 미터(m)인지 구하시오.",
        "question_en": "One farm has a rectangular fence. This fence is 30 meters (m) in circumference, and its width is twice as long as its length. Find the width of the fence in meters (m).",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "30 2 [OP_DIV] 1 2 [OP_ADD] [OP_DIV] 2 [OP_MUL]",
        "solution_abst_en": "30 2 [OP_DIV] 1 2 [OP_ADD] [OP_DIV] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 30\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = 2\nvar_f = var_d + var_e\nvar_g = var_c / var_f\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 30\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = 2\nvar_f = var_d + var_e\nvar_g = var_c / var_f\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "1925": {
        "category": "Correspondence",
        "question_ko": "17을 5로 나눴더니 몫이 3가 되었고, 나머지는 A가 되었습니다. 이 때 A를 구하시오.",
        "question_en": "When we divide 17 by 5, the quotient is 3, and the remainder is A. Find A here.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "17 5 3 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "17 5 3 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 17\nvar_b = 5\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 17\nvar_b = 5\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "1926": {
        "category": "Arithmetic calculation",
        "question_ko": "체육관에 야구공, 축구공, 배구공이 있습니다. 야구공 수는 축구공 수의 5배이고, 배구공 수는 축구공 수의 3배입니다. 야구공과 배구공 수의 합이 160개라면 축구공은 몇 개인지 구해 보시오.",
        "question_en": "There are baseballs, soccer balls and volleyballs in the gym. The number of baseballs is 5 times the number of soccer balls, and the number of volleyballs is 3 times the number of soccer balls. If the sum of baseballs and volleyballs is 160, how many soccer balls are there?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "160 5 3 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "160 5 3 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 160\nvar_b = 5\nvar_c = 3\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 160\nvar_b = 5\nvar_c = 3\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "1927": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 가게에서 파는 수박이 5천원보다 2백원 비쌀 때, 수박의 가격을 천원 단위로 구하시오.",
        "question_en": "If a watermelon sold at a store costs 200 won more than 5,000 won, find the price of the watermelon in units of 1,000 won.",
        "answer_ko": "5.20",
        "answer_en": "5.2",
        "solution_abst_ko": "5 2 10 [OP_DIV] [OP_ADD]",
        "solution_abst_en": "5 2 10 [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = 10\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = 10\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "1928": {
        "category": "Comparison",
        "question_ko": "유나, 유정, 민영이 은행에서 번호표를 뽑았습니다. 유나의 번호는 유정보다 크고, 민영이의 번호는 유나보다 작습니다. 가장 큰 번호를 가진 사람은 누구입니까?",
        "question_en": "Yuna, Yoojung, and Minyoung took number tickets at the bank. Yuna's number is higher than Yoojung's, and Minyoung's number is lower than Yuna's. Who has the largest number?",
        "answer_ko": "유나",
        "answer_en": "Yuna",
        "solution_abst_ko": "[OP_LIST_SOL] 유나 유정 민영 [OP_LIST_EOL] [OP_LIST_SOL] 유나 유정 > 민영 유나 < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yuna Yoojung Minyoung [OP_LIST_EOL] [OP_LIST_SOL] Yuna Yoojung > Minyoung Yuna < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '유나'\nvar_b = '유정'\nvar_c = '민영'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '유나'\nvar_e = '유정'\nvar_f = '>'\nvar_g = '민영'\nvar_h = '유나'\nvar_i = '<'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(var_k)",
        "solution_code_en": "var_a = 'Yuna'\nvar_b = 'Yoojung'\nvar_c = 'Minyoung'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'Yuna'\nvar_e = 'Yoojung'\nvar_f = '>'\nvar_g = 'Minyoung'\nvar_h = 'Yuna'\nvar_i = '<'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(var_k)"
    },
    "1929": {
        "category": "Comparison",
        "question_ko": "20명의 학생들이 한 줄로 줄을 섰습니다. 정국이는 윤기보다 앞에 서 있고, 윤기와 정국이 사이에는 5명의 학생이 있습니다. 정국의 뒤에는 6명의 학생들이 서 있습니다. 윤기의 앞에 서 있는 학생은 몇 명입니까?",
        "question_en": "20 students are lined up in a single line. Jungkook is standing in front of Yoongi, and there are 5 students between Yoongi and Jungkook. There are 6 students standing behind Jungkook. How many students are standing in front of Yoongi?",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "20 6 [OP_SUB] 5 [OP_ADD]",
        "solution_abst_en": "20 6 [OP_SUB] 5 [OP_ADD]",
        "solution_code_ko": "var_a = 20\nvar_b = 6\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 6\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "1930": {
        "category": "Arithmetic calculation",
        "question_ko": "도로에 전봇대를 25미터(m) 간격으로 세웠다. 첫번째 전봇대와 마지막 전봇대 사이의 거리가 1500미터(m)일 때, 전봇대는 모두 몇 대 인지 구하시오.",
        "question_en": "Electric poles were erected on the road at intervals of 25 meters (m). If the distance between the first and last telephone poles is 1500 m (m), how many telephone poles are there?",
        "answer_ko": "61",
        "answer_en": "61",
        "solution_abst_ko": "1500 25 [OP_DIV] 1 [OP_ADD]",
        "solution_abst_en": "1500 25 [OP_DIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 1500\nvar_b = 25\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 1500\nvar_b = 25\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "1931": {
        "category": "Correspondence",
        "question_ko": "24와 어떤 수는 최소공배수가 168이다. 최대공약수가 4라면 어떤 수는 무엇인가?",
        "question_en": "The least common multiple of 24 and a number is 168. If the greatest common divisor is 4, what number is it?",
        "answer_ko": "28",
        "answer_en": "28",
        "solution_abst_ko": "168 4 [OP_MUL] 24 [OP_FDIV]",
        "solution_abst_en": "168 4 [OP_MUL] 24 [OP_FDIV]",
        "solution_code_ko": "var_a = 168\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 24\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 168\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 24\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "1932": {
        "category": "Arithmetic calculation",
        "question_ko": "2로 나누어 떨어질 수 있는 세 자리 수 중 가장 작은 수는?",
        "question_en": "What is the smallest three-digit number that is divisible by 2?",
        "answer_ko": "100",
        "answer_en": "100",
        "solution_abst_ko": "100 999 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "100 999 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nprint(int(var_f))",
        "solution_code_en": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nprint(int(var_f))"
    },
    "1933": {
        "category": "Comparison",
        "question_ko": "24대의 차량이 있습니다. 이 중 빨간색 자동차가 전체의 4분의 1을 차지하고 파란색 자동차가 빨간색 자동차보다 6대 더 많으며 나머지는 노란색 자동차입니다. 어떤 색의 자동차가 가장 많습니까?",
        "question_en": "There are 24 vehicles. Of these, red cars make up a quarter of the total, blue cars outnumber red cars by six, and yellow cars make up the rest. What color cars are there the most?",
        "answer_ko": "파란색",
        "answer_en": "blue",
        "solution_abst_ko": "[OP_LIST_SOL] 빨간색 파란색 노란색 [OP_LIST_EOL] [OP_LIST_SOL] 24 4 [OP_DIV] 24 4 [OP_DIV] 6 [OP_ADD] 24 24 4 [OP_DIV] 6 [OP_ADD] [OP_SUB] 24 4 [OP_DIV] [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] red blue yellow [OP_LIST_EOL] [OP_LIST_SOL] 24 4 [OP_DIV] 24 4 [OP_DIV] 6 [OP_ADD] 24 24 4 [OP_DIV] 6 [OP_ADD] [OP_SUB] 24 4 [OP_DIV] [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '빨간색'\nvar_b = '파란색'\nvar_c = '노란색'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 24\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = 24\nvar_h = 4\nvar_i = var_g / var_h\nvar_j = 6\nvar_k = var_i + var_j\nvar_l = 24\nvar_m = 24\nvar_n = 4\nvar_o = var_m / var_n\nvar_p = 6\nvar_q = var_o + var_p\nvar_r = var_l - var_q\nvar_s = 24\nvar_t = 4\nvar_u = var_s / var_t\nvar_v = var_r - var_u\nlist_b= []\nif \"/\" in str(var_v):\n    var_v = eval(str(var_v))\nlist_b.append(var_v)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_w = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_x = list_c[-var_w]\nvar_y = list_b.index(var_x)+1\nvar_z = list_a[var_y-1]\nprint(var_z)",
        "solution_code_en": "var_a = 'red'\nvar_b = 'blue'\nvar_c = 'yellow'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 24\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = 24\nvar_h = 4\nvar_i = var_g / var_h\nvar_j = 6\nvar_k = var_i + var_j\nvar_l = 24\nvar_m = 24\nvar_n = 4\nvar_o = var_m / var_n\nvar_p = 6\nvar_q = var_o + var_p\nvar_r = var_l - var_q\nvar_s = 24\nvar_t = 4\nvar_u = var_s / var_t\nvar_v = var_r - var_u\nlist_b= []\nif \"/\" in str(var_v):\n    var_v = eval(str(var_v))\nlist_b.append(var_v)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_w = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_x = list_c[-var_w]\nvar_y = list_b.index(var_x)+1\nvar_z = list_a[var_y-1]\nprint(var_z)"
    },
    "1934": {
        "category": "Arithmetic calculation",
        "question_ko": "체육대회 시간에 지민이 반 학생들이 앞 뒤로 같은 간격으로 서 있다. 맨 앞 학생과 맨 뒤 학생의 거리가 242 미터(m)이고, 지민이 바로 앞 학생과의 거리가 5.5미터(m)라면 지민이 반 학생 수는 몇 명인가?",
        "question_en": "During the athletic meeting, the students in Jimin's class stand at the same intervals back and forth. If the distance between the student in the front and the student at the back is 242 meters (m), and the distance between Jimin and the next student is 5.5 meters (m), how many students are in Jimin's class?",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "242 5.5 [OP_FDIV] 1 [OP_ADD]",
        "solution_abst_en": "242 5.5 [OP_FDIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 242\nvar_b = 5.5\nvar_c = var_a // var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 242\nvar_b = 5.5\nvar_c = var_a // var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "1935": {
        "category": "Arithmetic calculation",
        "question_ko": "오늘은 35046명의 관광객이 벚꽃축제를 찾았다. 그 중 3분의 1이 자가용을 이용하고 절반이 서울에서 왔다. 서울에서 차로 얼마나 많은 사람들이 벚꽃 축제에 왔는지 확인하십시오.",
        "question_en": "Today, 35046 tourists visited the cherry blossom festival. A third of them used their own cars, and half came from Seoul. Check out how many people came to the cherry blossom festival by car from Seoul.",
        "answer_ko": "5841",
        "answer_en": "5841",
        "solution_abst_ko": "35046 1 3 [OP_DIV] [OP_MUL] 1 2 [OP_DIV] [OP_MUL]",
        "solution_abst_en": "35046 1 3 [OP_DIV] [OP_MUL] 1 2 [OP_DIV] [OP_MUL]",
        "solution_code_ko": "var_a = 35046\nvar_b = 1\nvar_c = 3\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 1\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = var_e * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 35046\nvar_b = 1\nvar_c = 3\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 1\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = var_e * var_h\nprint(int(var_i))"
    },
    "1936": {
        "category": "Geometry",
        "question_ko": "사각형에서 두 개의 대각선을 그으면, A각형이 B개 만들어진다. A×B는 얼마인가?",
        "question_en": "There can be some polygon with A as the number of vertices inside the square if you draw two diagonals in it. If B stands for the number of polygons, what is the answer for the following equation: AxB?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "3 4 [OP_MUL]",
        "solution_abst_en": "3 4 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "1937": {
        "category": "Arithmetic calculation",
        "question_ko": "산사태를 대비하기 위한 낙석 주의 표지판을 설치하려고 합니다. 0.35킬로미터(㎞) 지점에서 0.37킬로미터(㎞) 지점까지 똑같이 4구간으로 나누어 처음부터 끝까지 표지판을 설치한다면 네 번째 지점에 설치하는 표지판의 위치는 몇 킬로미터(㎞) 지점인지 소수로 나타내시오.",
        "question_en": "We are going to install a rockfall warning sign to prepare for landslides. If the sign is installed from the beginning to the end by dividing it into 4 sections equally from the 0.35 kilometer (km) point to the 0.37 kilometer (km) point, indicate the  kilometers (km) of the location of the sign installed at the fourth point as a decimal number.",
        "answer_ko": "0.37",
        "answer_en": "0.37",
        "solution_abst_ko": "0.35 0.37 0.35 [OP_SUB] 4 [OP_DIV] 4 1 [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_abst_en": "0.35 0.37 0.35 [OP_SUB] 4 [OP_DIV] 4 1 [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 0.35\nvar_b = 0.37\nvar_c = 0.35\nvar_d = var_b - var_c\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = 4\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = var_f * var_i\nvar_k = var_a + var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 0.35\nvar_b = 0.37\nvar_c = 0.35\nvar_d = var_b - var_c\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = 4\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = var_f * var_i\nvar_k = var_a + var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "1938": {
        "category": "Geometry",
        "question_ko": "가로 30센티미터(㎝), 세로, 높이가 1센티미터(㎝)인 상자를 가로로 7줄, 세로로 5줄, 높이를 3층으로 쌓아 올렸다면 전체 부피는 얼마입니까?",
        "question_en": "What is the total volume of a box measuring 30 centimeters (cm) long, 1 centimeter (cm) wide, and 1 centimeter (cm) high when stacked in 7 horizontal rows, 5 vertical rows, and 3 floors?",
        "answer_ko": "3150",
        "answer_en": "3150",
        "solution_abst_ko": "30 7 [OP_MUL] 1 5 [OP_MUL] [OP_MUL] 1 3 [OP_MUL] [OP_MUL]",
        "solution_abst_en": "30 7 [OP_MUL] 1 5 [OP_MUL] [OP_MUL] 1 3 [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 30\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = var_c * var_f\nvar_h = 1\nvar_i = 3\nvar_j = var_h * var_i\nvar_k = var_g * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 30\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = var_c * var_f\nvar_h = 1\nvar_i = 3\nvar_j = var_h * var_i\nvar_k = var_g * var_j\nprint(int(var_k))"
    },
    "1939": {
        "category": "Comparison",
        "question_ko": "수지네 집에서 대형마트까지의 거리는 2킬로미터(㎞) 280미터(m)이고, 빵집까지의 거리는 4125미터(m)입니다. 수지네 집에서 더 가까운 곳은 대형마트와 빵집 중 어디입니까?",
        "question_en": "The distance from Suji's house to the supermarket is 2 kilometers (km) and 280 meters (m), and the distance to the bakery is 4125 meters (m). Which is closer to Suji's house, a supermarket or a bakery?",
        "answer_ko": "대형마트",
        "answer_en": "supermarket",
        "solution_abst_ko": "[OP_LIST_SOL] 대형마트 빵집 [OP_LIST_EOL] [OP_LIST_SOL] 2 1000 [OP_MUL] 280 [OP_ADD] 4125 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] supermarket bakery [OP_LIST_EOL] [OP_LIST_SOL] 2 1000 [OP_MUL] 280 [OP_ADD] 4125 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '대형마트'\nvar_b = '빵집'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 280\nvar_g = var_e + var_f\nvar_h = 4125\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'supermarket'\nvar_b = 'bakery'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 280\nvar_g = var_e + var_f\nvar_h = 4125\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "1940": {
        "category": "Comparison",
        "question_ko": "1부터 9까지의 카드 중 하나를 뽑아서 44를 곱했을 때 55에 4를 곱한 값보다 작아지는 수들을 모두 더한 값을 구하시오.",
        "question_en": "Draw one of the cards numbered 1 through 9 and find the sum of all the numbers that, when multiplied by 44, are less than 55 multiplied by 4.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "1 9 1 [OP_LIST_ARANGE] 55 4 [OP_MUL] 44 [OP_DIV] [OP_LIST_LESS] [OP_LIST_SUM]",
        "solution_abst_en": "1 9 1 [OP_LIST_ARANGE] 55 4 [OP_MUL] 44 [OP_DIV] [OP_LIST_LESS] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 55\nvar_e = 4\nvar_f = var_d * var_e\nvar_g = 44\nvar_h = var_f / var_g\nlist_b = []\nfor i in list_a:\n    if i < var_h:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_i = sum(list_b)\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 55\nvar_e = 4\nvar_f = var_d * var_e\nvar_g = 44\nvar_h = var_f / var_g\nlist_b = []\nfor i in list_a:\n    if i < var_h:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_i = sum(list_b)\nprint(int(var_i))"
    },
    "1941": {
        "category": "Geometry",
        "question_ko": "한 변이 47/20센티미터(㎝)인 정사각형의 둘레는 센티미터(㎝)몇 입니까?",
        "question_en": "What is the perimeter in centimeters (cm) of a square with a side of 47/20 centimeters (cm)?",
        "answer_ko": "9.40",
        "answer_en": "9.4",
        "solution_abst_ko": "47/20 4 [OP_MUL]",
        "solution_abst_en": "47/20 4 [OP_MUL]",
        "solution_code_ko": "var_a = 2.35\nvar_b = 4\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 2.35\nvar_b = 4\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "1942": {
        "category": "Possibility",
        "question_ko": "음료수가 3종류, 샐러드가 2종류, 피자가 5종류 있을 때, 음료수, 샐러드, 피자를 각각 1종류씩 주문하는 방법은 모두 몇 가지인지 구하시오.",
        "question_en": "If there are 3 drinks, 2 salads, and 5 pizzas, how many ways can you order 1 drink, 1 salad, and 1 pizza?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "3 2 [OP_MUL] 5 [OP_MUL]",
        "solution_abst_en": "3 2 [OP_MUL] 5 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "1943": {
        "category": "Comparison",
        "question_ko": "한별이와 슬기가 공원을 돌면서 달리기를 합니다. 같은 시간 동안 한별이는 10.2킬로미터(㎞)의 1/100의 거리를 달렸고, 슬기는 100미터(m)의 거리를 달렸습니다. 한별이와 슬기 중 누가 더 많은 거리를 달렸습니까?",
        "question_en": "Hanbyul and Seulgi run around the park. During the same time, Hanbyul ran a distance of 1/100 of 10.2 kilometers (km), and Seulgi ran a distance of 100 meters (m). Hanbyul or Seulgi, who ran longer distances?",
        "answer_ko": "한별",
        "answer_en": "Hanbyul",
        "solution_abst_ko": "[OP_LIST_SOL] 한별 슬기 [OP_LIST_EOL] [OP_LIST_SOL] 10.2 1000 [OP_MUL] 1/100 [OP_MUL] 100 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Hanbyul Seulgi [OP_LIST_EOL] [OP_LIST_SOL] 10.2 1000 [OP_MUL] 1/100 [OP_MUL] 100 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '한별'\nvar_b = '슬기'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10.2\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 0.01\nvar_g = var_e * var_f\nvar_h = 100\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Hanbyul'\nvar_b = 'Seulgi'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10.2\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 0.01\nvar_g = var_e * var_f\nvar_h = 100\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "1944": {
        "category": "Comparison",
        "question_ko": "민우의 키는 1.3 미터(m)이고 효진이의 키는 1.4 미터(m)입니다. 민우와 효진이 중 키가 더 큰 사람은 누구일까요?",
        "question_en": "Minwoo is 1.3 meters (m) tall and Hyojin is 1.4 meters (m) tall. Who is taller Minwoo and Hyojin?",
        "answer_ko": "효진",
        "answer_en": "Hyojin",
        "solution_abst_ko": "[OP_LIST_SOL] 민우 효진 [OP_LIST_EOL] [OP_LIST_SOL] 1.3 1.4 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Minwoo Hyojin [OP_LIST_EOL] [OP_LIST_SOL] 1.3 1.4 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '민우'\nvar_b = '효진'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.3\nvar_d = 1.4\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Minwoo'\nvar_b = 'Hyojin'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.3\nvar_d = 1.4\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "1945": {
        "category": "Possibility",
        "question_ko": "A 지점에서 B 지점까지 가는 경우의 수는 2가지, B 지점에서 C 지점까지 가는 경우의 수가 3가지일 때, A 지점에서 B 지점을 거쳐서 C 지점으로 가는 경우의 수를 구하시오.",
        "question_en": "If there are 2 ways to get from point A to point B and 3 ways to get from point B to point C, find the number of ways to go from point A to point C via point B.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "2 3 [OP_MUL]",
        "solution_abst_en": "2 3 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "1946": {
        "category": "Comparison",
        "question_ko": "수영 시합에서 남준이는 2등을 했고, 윤기는 4등을 했습니다. 호석이는 윤기보다 빨랐지만 남준이보다는 느렸습니다. 호석이의 등수는 몇 등입니까?",
        "question_en": "In the swimming competition, Namjoon placed second and Yoongi placed fourth. Hoseok was faster than Yoongi, but slower than Namjoon. What is Hoseok's rank?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "2 4 [OP_ADD] 2 [OP_FDIV]",
        "solution_abst_en": "2 4 [OP_ADD] 2 [OP_FDIV]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "1947": {
        "category": "Correspondence",
        "question_ko": "A는 한 자리 수입니다. 나눗셈 9A5÷5<197에서 A 안에 들어갈 수 있는 숫자는 모두 몇 개입니까?",
        "question_en": "A is a single digit number. How many numbers can fit inside A in division 9A5÷5<197?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "9A5÷5<197 A [OP_DIGIT_UNK_SOLVER] [OP_LIST_LEN]",
        "solution_abst_en": "9A5÷5<197 A [OP_DIGIT_UNK_SOLVER] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '9A5÷5<197'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = len(list_a)\nprint(int(var_c))",
        "solution_code_en": "var_a = '9A5÷5<197'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = len(list_a)\nprint(int(var_c))"
    },
    "1948": {
        "category": "Geometry",
        "question_ko": "한 변이 30 센티미터(㎝) 인 정사각형 모양의 시계가 있습니다. 이 시계의 넓이는 몇 제곱센티미터(㎠)입니까?",
        "question_en": "There is a clock in the shape of a square with sides measuring 30 centimeters (cm). What is the area of this clock in square centimeters (cm2)?",
        "answer_ko": "900",
        "answer_en": "900",
        "solution_abst_ko": "30 2 [OP_POW]",
        "solution_abst_en": "30 2 [OP_POW]",
        "solution_code_ko": "var_a = 30\nvar_b = 2\nvar_c = var_a ** var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 30\nvar_b = 2\nvar_c = var_a ** var_b\nprint(int(var_c))"
    },
    "1949": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2 중에서 0.4보다 작은 수는 몇 개입니까?",
        "question_en": "Among 0.8 and 1/2, how many of them are less than 0.4?",
        "answer_ko": "0",
        "answer_en": "0",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 [OP_LIST_EOL] 0.4 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 [OP_LIST_EOL] 0.4 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.4\nlist_b = []\nfor i in list_a:\n    if i < var_c:\n        list_b.append(i)\nvar_d = len(list_b)\nprint(int(var_d))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.4\nlist_b = []\nfor i in list_a:\n    if i < var_c:\n        list_b.append(i)\nvar_d = len(list_b)\nprint(int(var_d))"
    },
    "1950": {
        "category": "Comparison",
        "question_ko": "3개의 숫자 0.8, 1/2, 0.9가 있습니다. 3보다 작은 수는 몇 개입니까?",
        "question_en": "There are three numbers 0.8, 1/2, and 0.9. How many numbers are less than 3?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 3 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 3 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = []\nfor i in list_a:\n    if i < var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = []\nfor i in list_a:\n    if i < var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "1951": {
        "category": "Correspondence",
        "question_ko": "천의 자리에서 반올림을 하면 260000이 되는 여섯 자리 수 25A735가 있습니다. A에 0부터 9까지의 숫자를 쓸 수 있다면, 가능한 수는 모두 몇 개입니까?",
        "question_en": "There is a six-digit number 25A735 which is 260000 when rounded to the thousandth place. If you can write the numbers 0 through 9 in A, how many possible numbers are there?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "25A735 [OP_GEN_POSSIBLE_LIST] 255000 [OP_LIST_MORE_EQUAL] 25A735 A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_abst_en": "25A735 [OP_GEN_POSSIBLE_LIST] 255000 [OP_LIST_MORE_EQUAL] 25A735 A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '25A735'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 255000\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = '25A735'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nvar_e = len(list_c)\nprint(int(var_e))",
        "solution_code_en": "var_a = '25A735'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 255000\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = '25A735'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nvar_e = len(list_c)\nprint(int(var_e))"
    },
    "1952": {
        "category": "Arithmetic calculation",
        "question_ko": "주원이는 105.8미터(m)의 철사가 있습니다. 모빌 한 개를 만들기 위해서는 철사 4미터(m)가 필요하다면 주원이가 만들 수 있는 모빌의 개수를 구하세요.",
        "question_en": "Juwon has 105.8 meters (m) of wire. If you need 4 meters (m) of wire to make one mobile, find the number of mobiles Juwon can make.",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "105.8 4 [OP_FDIV]",
        "solution_abst_en": "105.8 4 [OP_FDIV]",
        "solution_code_ko": "var_a = 105.8\nvar_b = 4\nvar_c = var_a // var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 105.8\nvar_b = 4\nvar_c = var_a // var_b\nprint(int(var_c))"
    },
    "1953": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 217센티미터(㎝)인 테이프 3개를 겹쳐지는 부분을 같게 하여 길게 이었습니다. 이은 테이프의 길이가 627센티미터(㎝)이면, 테이프의 겹쳐지는 부분의 한 개의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "Three 217 centimeters (cm) long tapes were attached together with the same overlapping parts. If the length of the attached tape is 627 centimeters (cm), how many centimeters (cm) is the length of one overlapping portion of the tape?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "217 3 [OP_MUL] 627 [OP_SUB] 3 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "217 3 [OP_MUL] 627 [OP_SUB] 3 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 217\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 627\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 217\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 627\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "1954": {
        "category": "Correspondence",
        "question_ko": "40을 어떤 수에 더해야 할 것을 잘못하여 21을 어떤 수에 더한 결과는 52가 나옵니다. 바르게 계산하면 얼마인가요?",
        "question_en": "You mistakenly added 21 to a particular number when you were supposed to add 40, and the result was 52. Find out the answer when correctly calculated.",
        "answer_ko": "71",
        "answer_en": "71",
        "solution_abst_ko": "52 21 [OP_SUB] 40 [OP_ADD]",
        "solution_abst_en": "52 21 [OP_SUB] 40 [OP_ADD]",
        "solution_code_ko": "var_a = 52\nvar_b = 21\nvar_c = var_a - var_b\nvar_d = 40\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 52\nvar_b = 21\nvar_c = var_a - var_b\nvar_d = 40\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "1955": {
        "category": "Arithmetic calculation",
        "question_ko": "도로 한쪽에 전봇대가 총 20개 있습니다. 전봇대 사이의 거리는 25미터(m)이며 처음과 끝에는 전봇대가 없습니다. 도로의 총 길이는 몇미터(m) 입니까?",
        "question_en": "There are a total of 20 telephone poles on one side of the road. The distance between the poles is 25 meters (m), and there are no poles at the beginning and end. What is the total length of the road in meters (m)?",
        "answer_ko": "525",
        "answer_en": "525",
        "solution_abst_ko": "20 1 [OP_ADD] 25 [OP_MUL]",
        "solution_abst_en": "20 1 [OP_ADD] 25 [OP_MUL]",
        "solution_code_ko": "var_a = 20\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 25\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 25\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "1956": {
        "category": "Possibility",
        "question_ko": "수영 동아리에는 1학년 3명, 2학년 2명, 3학년 2명이 있다. 동아리의 대표 3명을 뽑는 경우의 수를 구하시오.",
        "question_en": "The swimming club has three first graders, two second graders, and two third graders. Find the number of ways to select 3 representatives of a club.",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "3 2 [OP_ADD] 2 [OP_ADD] 3 [OP_COMB]",
        "solution_abst_en": "3 2 [OP_ADD] 2 [OP_ADD] 3 [OP_COMB]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g / (i+1)\nprint(int(var_g))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g / (i+1)\nprint(int(var_g))"
    },
    "1957": {
        "category": "Comparison",
        "question_ko": "학교에 총 3개의 학년이 있습니다. 각 학년에는 12개의 학급이 있고, 각 학급의 학생 수는 모두 같습니다. 미영이는 어느 학급에서 수학 점수로 앞에서 12등, 뒤에서 12등입니다. 이 학교의 학생 수는 모두 몇 명입니까?",
        "question_en": "The school has a total of 3 grades. Each grade has 12 classes, and each class has the same number of students. Miyoung is ranked 12th from the front and 12th from the back in math scores in a class. How many students are there in this school?",
        "answer_ko": "828",
        "answer_en": "828",
        "solution_abst_ko": "12 12 [OP_ADD] 1 [OP_SUB] 12 [OP_MUL] 3 [OP_MUL]",
        "solution_abst_en": "12 12 [OP_ADD] 1 [OP_SUB] 12 [OP_MUL] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 12\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 12\nvar_g = var_e * var_f\nvar_h = 3\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 12\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 12\nvar_g = var_e * var_f\nvar_h = 3\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "1958": {
        "category": "Geometry",
        "question_ko": "삼각형 모양 피자의 밑변과 빗변은 각각 9센티미터(㎝), 15센티미터(㎝)이다. 피자의 넓이는?",
        "question_en": "The base and hypotenuse of the triangular pizza are 9 centimeters (cm) and 15 centimeters (cm), respectively. How big is the pizza?",
        "answer_ko": "54",
        "answer_en": "54",
        "solution_abst_ko": "15 2 [OP_POW] 9 2 [OP_POW] [OP_SUB] 1/2 [OP_POW] 9 [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "15 2 [OP_POW] 9 2 [OP_POW] [OP_SUB] 1/2 [OP_POW] 9 [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 15\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 9\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c - var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nvar_j = 9\nvar_k = var_i * var_j\nvar_l = 2\nvar_m = var_k / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 15\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 9\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c - var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nvar_j = 9\nvar_k = var_i * var_j\nvar_l = 2\nvar_m = var_k / var_l\nprint(int(var_m))"
    },
    "1959": {
        "category": "Geometry",
        "question_ko": "스티커를 빈틈없이 규칙적으로 붙여 정사각형을 만들었다. 정사각형의 한 변을 만들 때 스티커가 6개 필요할 때, 둘레에 붙여진 스티커는 몇 개인지 구하시오.",
        "question_en": "I made a square by sticking the stickers regularly without any gaps. If I need 6 stickers to make one side of a square, find how many stickers are on the perimeter.",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "6 4 [OP_MUL] 4 [OP_SUB]",
        "solution_abst_en": "6 4 [OP_MUL] 4 [OP_SUB]",
        "solution_code_ko": "var_a = 6\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "1960": {
        "category": "Arithmetic calculation",
        "question_ko": "이모와 윤기의 나이 차이는 23살이고, 호석이는 윤기보다 4살 어립니다. 이모의 나이가 38살일 때, 윤기와 호석이의 나이의 합은 몇 살인지 구하시오.",
        "question_en": "The age difference between Yoongi's aunt and Yoongi is 23 years, and Hoseok is 4 years younger than Yoongi. If his aunt is 38 years old, find the sum of the ages of Yoongi and Hoseok.",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "38 23 [OP_SUB] 38 23 [OP_SUB] 4 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "38 23 [OP_SUB] 38 23 [OP_SUB] 4 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 38\nvar_b = 23\nvar_c = var_a - var_b\nvar_d = 38\nvar_e = 23\nvar_f = var_d - var_e\nvar_g = 4\nvar_h = var_f - var_g\nvar_i = var_c + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 38\nvar_b = 23\nvar_c = var_a - var_b\nvar_d = 38\nvar_e = 23\nvar_f = var_d - var_e\nvar_g = 4\nvar_h = var_f - var_g\nvar_i = var_c + var_h\nprint(int(var_i))"
    },
    "1961": {
        "category": "Geometry",
        "question_ko": "가로가 9센티미터(㎝)인 직사각형과 한 변의 길이가 12센티미터(㎝)인 정사각형의 네 변의 길이의 합이 같습니다. 직사각형의 세로는 몇 센티미터(㎝)입니까?",
        "question_en": "A rectangle with a width of 9 centimeters (cm) and a square with a side length of 12 centimeters (cm) is equal to the sum of the lengths of the four sides. How many centimeters (cm) is the length of the rectangle?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "12 4 [OP_MUL] 2 [OP_DIV] 9 [OP_SUB]",
        "solution_abst_en": "12 4 [OP_MUL] 2 [OP_DIV] 9 [OP_SUB]",
        "solution_code_ko": "var_a = 12\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 9\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 12\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 9\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "1962": {
        "category": "Arithmetic calculation",
        "question_ko": "100 이하의 자연수 중 3의 배수이면서 5의 배수인 수를 나열했을 때 0은 몇 번 등장하는지 구하시오.",
        "question_en": "Find how many times 0 appears in a list of all natural numbers less than 100 that are multiples of 3 and multiples of 5.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "1 100 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] [OP_LIST2NUM] [OP_NUM2LIST] 0 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 100 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] [OP_LIST2NUM] [OP_NUM2LIST] 0 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f=\"\"\nfor i in list_c:\n    i = str(i)\n    var_f = var_f + i\nlist_d = []\nvar_f = int(var_f)\nwhile var_f//10 > 0:\n    list_d.append(var_f%10)\n    var_f = var_f//10\nlist_d.append(var_f%10)\nlist_d = list_d[::-1]\nvar_g = 0\nvar_h = 0\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i == var_g:\n        var_h = var_h + 1\nprint(int(var_h))",
        "solution_code_en": "var_a = 1\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f=\"\"\nfor i in list_c:\n    i = str(i)\n    var_f = var_f + i\nlist_d = []\nvar_f = int(var_f)\nwhile var_f//10 > 0:\n    list_d.append(var_f%10)\n    var_f = var_f//10\nlist_d.append(var_f%10)\nlist_d = list_d[::-1]\nvar_g = 0\nvar_h = 0\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i == var_g:\n        var_h = var_h + 1\nprint(int(var_h))"
    },
    "1963": {
        "category": "Arithmetic calculation",
        "question_ko": "자동차 25대 중 18대가 나가고 12대가 들어왔습니다. 감소한 자동차의 수는 몇 대입니까?",
        "question_en": "Of the 25 cars, 18 went out and 12 came in. How many cars have been reduced?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "25 25 18 [OP_SUB] 12 [OP_ADD] [OP_SUB]",
        "solution_abst_en": "25 25 18 [OP_SUB] 12 [OP_ADD] [OP_SUB]",
        "solution_code_ko": "var_a = 25\nvar_b = 25\nvar_c = 18\nvar_d = var_b - var_c\nvar_e = 12\nvar_f = var_d + var_e\nvar_g = var_a - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 25\nvar_b = 25\nvar_c = 18\nvar_d = var_b - var_c\nvar_e = 12\nvar_f = var_d + var_e\nvar_g = var_a - var_f\nprint(int(var_g))"
    },
    "1964": {
        "category": "Arithmetic calculation",
        "question_ko": "할머니가 우유를 전체의 0.4만큼 마시고 남은 우유가 0.69리터(L)였습니다. 처음에 있던 우유는 몇 리터(L)인지 구하시오.",
        "question_en": "After grandmother had drunk 0.4 of the total milk, the remaining milk was 0.69 liters (L). Find how many liters (L) of milk were there in the beginning.",
        "answer_ko": "1.15",
        "answer_en": "1.15",
        "solution_abst_ko": "0.69 1 0.4 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "0.69 1 0.4 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 0.69\nvar_b = 1\nvar_c = 0.4\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.69\nvar_b = 1\nvar_c = 0.4\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "1965": {
        "category": "Comparison",
        "question_ko": "키가 작은 사람부터 순서대로 9명이 한 줄로 서 있습니다. 호석이는 5번째로 키가 큽니다. 키가 큰 사람부터 순서대로 다시 줄을 서면 호석이는 뒤에서부터 몇 번째에 서게 됩니까?",
        "question_en": "Suppose there is a line of 9 people in order starting with the smallest person. Hoseok is the 5th tallest person. If the line is rearranged in an order from the tallest person, what number does Hoseok take from the back of the line?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "9 5 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "9 5 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 9\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "1966": {
        "category": "Arithmetic calculation",
        "question_ko": "잠수함은 한 시간에 3.8킬로미터(㎞)를 바다 속으로 내려간다고 합니다. 잠수함이 2시간 45분동안 쉬지않고 내려간 높이는 몇 킬로미터(㎞)입니까?",
        "question_en": "When submarines can go down into the sea at 3.8 kilometers (km) per hour, find how deep the submarine can descend for 2 hours and 45 minutes in kilometers (km). (Given that it descends at a constant speed without any stop.)",
        "answer_ko": "10.45",
        "answer_en": "10.45",
        "solution_abst_ko": "3.8 2 45 60 [OP_DIV] [OP_ADD] [OP_MUL]",
        "solution_abst_en": "3.8 2 45 60 [OP_DIV] [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 3.8\nvar_b = 2\nvar_c = 45\nvar_d = 60\nvar_e = var_c / var_d\nvar_f = var_b + var_e\nvar_g = var_a * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 3.8\nvar_b = 2\nvar_c = 45\nvar_d = 60\nvar_e = var_c / var_d\nvar_f = var_b + var_e\nvar_g = var_a * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "1967": {
        "category": "Correspondence",
        "question_ko": "소수 2번째 자리에서 반올림을 하면 1.7이 되는 소수 두 자리 수들이 있습니다. 이러한 수들 중 가장 큰 수에서 가장 작은 수를 뺐을 때의 값을 소수점을 포함하여 구해보시오.",
        "question_en": "There are numbers with two decimal places that give 1.7 if rounded to two decimal places. Find the value of subtracting the smallest of these numbers from the largest, including the decimal point.",
        "answer_ko": "0.09",
        "answer_en": "0.09",
        "solution_abst_ko": "1.74 1.65 [OP_SUB]",
        "solution_abst_en": "1.74 1.65 [OP_SUB]",
        "solution_code_ko": "var_a = 1.74\nvar_b = 1.65\nvar_c = var_a - var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 1.74\nvar_b = 1.65\nvar_c = var_a - var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "1968": {
        "category": "Possibility",
        "question_ko": "3, 4, 5, 6 중에서 서로 다른 숫자 2개를 사용하여 만들 수 있는 두 자리 수는 모두 몇 개입니까?",
        "question_en": "How many two-digit numbers can you make from 3, 4, 5, and 6 using two different numbers?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "[OP_LIST_SOL] 3 4 5 6 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 3 4 5 6 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 3\nvar_b = 4\nvar_c = 5\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 3\nvar_b = 4\nvar_c = 5\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "1969": {
        "category": "Arithmetic calculation",
        "question_ko": "빨간 구슬이 156개, 파란 구슬이 267개가 있습니다. 이 중 115개가 떨어져 깨졌습니다. 남은 구슬은 몇 개입니까?",
        "question_en": "There are 156 red marbles and 267 blue marbles. Of these, 115 fell off and broke. How many marbles are left?",
        "answer_ko": "308",
        "answer_en": "308",
        "solution_abst_ko": "156 267 [OP_ADD] 115 [OP_SUB]",
        "solution_abst_en": "156 267 [OP_ADD] 115 [OP_SUB]",
        "solution_code_ko": "var_a = 156\nvar_b = 267\nvar_c = var_a + var_b\nvar_d = 115\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 156\nvar_b = 267\nvar_c = var_a + var_b\nvar_d = 115\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "1970": {
        "category": "Possibility",
        "question_ko": "가, 나, 다, 라, 마 5명의 사람이 있다. 가, 나, 다를 라, 마의 앞에 세울 때, 5명의 사람이 순서대로 줄을 설 수 있는 경우의 수를 구하시오.",
        "question_en": "There are five people: A, B, C, D, and E. When A, B, and C are placed before D and E, find the number of cases in which 5 people can line up in order.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 가 나 다 라 마 [OP_LIST_EOL] [OP_LIST_SOL] 가 나 다 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D E [OP_LIST_EOL] [OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM]",
        "solution_code_ko": "var_a = '가'\nvar_b = '나'\nvar_c = '다'\nvar_d = '라'\nvar_e = '마'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = '가'\nvar_g = '나'\nvar_h = '다'\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_i = len(list_b)\nvar_j = len(list_b)\nvar_k = 1\nvar_i = int(var_i)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_i-i)\nprint(int(var_k))",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 'A'\nvar_g = 'B'\nvar_h = 'C'\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_i = len(list_b)\nvar_j = len(list_b)\nvar_k = 1\nvar_i = int(var_i)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_i-i)\nprint(int(var_k))"
    },
    "1971": {
        "category": "Possibility",
        "question_ko": "1보다 크고 9보다 작은 홀수 중 두 개를 뽑아 한 번씩 사용하여 만들 수 있는 두 자리 수는 몇 개입니까?",
        "question_en": "How many two-digit numbers can be formed by taking two odd numbers greater than 1 and less than 9 and using them once?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "1 1 [OP_ADD] 9 1 [OP_SUB] [OP_LIST_ODD] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "1 1 [OP_ADD] 9 1 [OP_SUB] [OP_LIST_ODD] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = 1\nvar_f = var_d - var_e\nlist_a = []\nif var_c%2==0:\n    for i in range(var_c+1, var_f+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_c, var_f+1, 2):\n        list_a.append(i)\nvar_g = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = len(list_b)\nprint(int(var_h))",
        "solution_code_en": "var_a = 1\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = 1\nvar_f = var_d - var_e\nlist_a = []\nif var_c%2==0:\n    for i in range(var_c+1, var_f+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_c, var_f+1, 2):\n        list_a.append(i)\nvar_g = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = len(list_b)\nprint(int(var_h))"
    },
    "1972": {
        "category": "Geometry",
        "question_ko": "어떤 직사각형의 둘레는 28 센티미터(㎝) 이고, 가로는 6센티미터(㎝) 입니 다. 이 직사각형의 넓이를 구하시오",
        "question_en": "A rectangle has a perimeter of 28 centimeters (cm) and a width of 6 centimeters (cm). Find the area of this rectangle.",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "28 2 [OP_DIV] 6 [OP_SUB] 6 [OP_MUL]",
        "solution_abst_en": "28 2 [OP_DIV] 6 [OP_SUB] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 28\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c - var_d\nvar_f = 6\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 28\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c - var_d\nvar_f = 6\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "1973": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 병에 물을 가 컵으로 가득 채우려면 10번, 나 컵 으로 가득 채우려면 5번 부어야 합니다. 나 컵의 들이는 가 컵의 들이의 몇 배입니까?",
        "question_en": "A bottle needs to be poured 10 times to fill it with a (a) cup, or 5 times to fill it with a (b) cup. How many times the size of the (b) cup is than the (a) cup?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "10 5 [OP_DIV]",
        "solution_abst_en": "10 5 [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 5\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 10\nvar_b = 5\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "1974": {
        "category": "Correspondence",
        "question_ko": "어떤 수로 229를 나누면 나머지가 어떤 수보다 5가 작은 값이라고 한다. 또한 어떤 수로 197을 나누면 나머지가 2이고, 160을 나누면 나머지가 4라고 한다. 어떤 수 중 가장 큰 수를 구하시오.",
        "question_en": "When 229 is divided by a particular number, the remainder is said to be 5 less than that particular number. Also, when 197 is divided by that particular number, the remainder is 2, and when 160 is divided by that particular number, the remainder is 4. Find the largest of that particular number.",
        "answer_ko": "39",
        "answer_en": "39",
        "solution_abst_ko": "197 2 [OP_SUB] 160 4 [OP_SUB] [OP_GCD] 229 5 [OP_ADD] [OP_GCD]",
        "solution_abst_en": "197 2 [OP_SUB] 160 4 [OP_SUB] [OP_GCD] 229 5 [OP_ADD] [OP_GCD]",
        "solution_code_ko": "var_a = 197\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 160\nvar_e = 4\nvar_f = var_d - var_e\nvar_g = math.gcd(int(var_f), int(var_c))\nvar_h = 229\nvar_i = 5\nvar_j = var_h + var_i\nvar_k = math.gcd(int(var_j), int(var_g))\nprint(int(var_k))",
        "solution_code_en": "var_a = 197\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 160\nvar_e = 4\nvar_f = var_d - var_e\nvar_g = math.gcd(int(var_f), int(var_c))\nvar_h = 229\nvar_i = 5\nvar_j = var_h + var_i\nvar_k = math.gcd(int(var_j), int(var_g))\nprint(int(var_k))"
    },
    "1975": {
        "category": "Correspondence",
        "question_ko": "어떤 철사를 8등분하고 난 하나의 조각에 대해서 다시 8등분을 하면 몇 센티미터(㎝)인지 구하시오. 단, 어떤 철사의 길이는 69.76센티미터(㎝)이다.",
        "question_en": "If you divide a piece of wire into 8 equal parts and then divide it into 8 equal parts, find how many centimeters (cm) it is. However, the length of the wire is 69.76 centimeters (cm).",
        "answer_ko": "1.09",
        "answer_en": "1.09",
        "solution_abst_ko": "69.76 8 [OP_DIV] 8 [OP_DIV]",
        "solution_abst_en": "69.76 8 [OP_DIV] 8 [OP_DIV]",
        "solution_code_ko": "var_a = 69.76\nvar_b = 8\nvar_c = var_a / var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 69.76\nvar_b = 8\nvar_c = var_a / var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "1976": {
        "category": "Comparison",
        "question_ko": "은규와 민영이의 키는 각각 3/8 미터(m) , 1.4미터(m) 입니다. 누구의 키가 더 큰지 나타내시오",
        "question_en": "Eunkyu and Minyoung are 3/8 meters (m) and 1.4 meters (m) respectively. Please indicate whose height is taller.",
        "answer_ko": "민영",
        "answer_en": "Minyoung",
        "solution_abst_ko": "[OP_LIST_SOL] 은규 민영 [OP_LIST_EOL] [OP_LIST_SOL] 3/8 1.4 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Eunkyu Minyoung [OP_LIST_EOL] [OP_LIST_SOL] 3/8 1.4 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '은규'\nvar_b = '민영'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.375\nvar_d = 1.4\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Eunkyu'\nvar_b = 'Minyoung'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.375\nvar_d = 1.4\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "1977": {
        "category": "Arithmetic calculation",
        "question_ko": "현아는 3일부터 8일까지 매일 치킨을 시켜먹었다고 한다. 치킨이 한 마리에 20000원 이라고 할 때, 현아가 치킨을 먹는데 사용한 금액은 얼마인지 구하시오.",
        "question_en": "Hyuna said that she ate chicken every day from the 3rd to the 8th. If the chicken costs 20,000 won per chicken, how much money did Hyuna spend to eat the chicken?",
        "answer_ko": "120000",
        "answer_en": "120000",
        "solution_abst_ko": "20000 8 3 [OP_SUB] 1 [OP_ADD] [OP_MUL]",
        "solution_abst_en": "20000 8 3 [OP_SUB] 1 [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 20000\nvar_b = 8\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = var_a * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 20000\nvar_b = 8\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = var_a * var_f\nprint(int(var_g))"
    },
    "1978": {
        "category": "Comparison",
        "question_ko": "선미는 성주보다 키가 작고 성주는 민영이보다 키가 작습니다. 민영이는 수호보다 키가 작을 때 키가 가장 작은 사람은 누구입니까?",
        "question_en": "Seonmi is shorter than Seongju and Seongju is shorter than Minyoung. Who is the shortest person when Minyoung is shorter than Suho?",
        "answer_ko": "선미",
        "answer_en": "Seonmi",
        "solution_abst_ko": "[OP_LIST_SOL] 수호 민영 성주 선미 [OP_LIST_EOL] [OP_LIST_SOL] 수호 민영 > 성주 민영 < 성주 선미 > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Suho Minyoung Seongju Seonmi [OP_LIST_EOL] [OP_LIST_SOL] Suho Minyoung > Seongju Minyoung < Seongju Seonmi > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '수호'\nvar_b = '민영'\nvar_c = '성주'\nvar_d = '선미'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '수호'\nvar_f = '민영'\nvar_g = '>'\nvar_h = '성주'\nvar_i = '민영'\nvar_j = '<'\nvar_k = '성주'\nvar_l = '선미'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)",
        "solution_code_en": "var_a = 'Suho'\nvar_b = 'Minyoung'\nvar_c = 'Seongju'\nvar_d = 'Seonmi'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'Suho'\nvar_f = 'Minyoung'\nvar_g = '>'\nvar_h = 'Seongju'\nvar_i = 'Minyoung'\nvar_j = '<'\nvar_k = 'Seongju'\nvar_l = 'Seonmi'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)"
    },
    "1979": {
        "category": "Geometry",
        "question_ko": "서로 다른 세 면의 넓이가 각각 4제곱센티미터(㎠) , 3제곱센티미터(㎠) , 6제곱센티미터(㎠)인 직육면체가 있습니다. 이 직육면체의 전개도의 넓이는 몇 제곱센티미터(㎠)입니까?",
        "question_en": "There is a cuboid whose three distinct sides' surface areas are respectively 4 square centimeters (cm2), 3 square centimeters (cm2), and 6 square centimeters (cm2). What is the surface area of this cubioid's planar figure in square centimeters (cm2)?",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "4 3 6 [OP_ADD] [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "4 3 6 [OP_ADD] [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 4\nvar_b = 3\nvar_c = 6\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 3\nvar_c = 6\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "1980": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 8센티미터(㎝)인 정사각형과 한 변의 길이가 10센티미터(㎝), 나머지 한 변의 길이가 5센티미터(㎝)인 직사각형 넓이의 차를 구하세요.",
        "question_en": "Find the difference between a square with side lengths of 8 centimeters (cm) and a rectangle with side lengths of 10 centimeters (cm) and 5 centimeters (cm).",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "8 2 [OP_POW] 10 5 [OP_MUL] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "8 2 [OP_POW] 10 5 [OP_MUL] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 8\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 10\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = abs(var_g)\nprint(int(var_h))",
        "solution_code_en": "var_a = 8\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 10\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = abs(var_g)\nprint(int(var_h))"
    },
    "1981": {
        "category": "Arithmetic calculation",
        "question_ko": "귤 1상자에 50개짜리와 70개짜리 상자를 합쳐 18상자를 샀습니다. 이 귤을 낱개로 세어보니 모두 1020개였다면, 70개짜리 상자는 몇 상자를 산 것입니까?",
        "question_en": "You bought 18 boxes, including boxes of 50 tangerines each and boxes of 70 tangerines each. If you counted these tangerines individually and there were 1020 in total, how many boxes of 70 did you buy?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "1020 50 18 [OP_MUL] [OP_SUB] 70 50 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "1020 50 18 [OP_MUL] [OP_SUB] 70 50 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 1020\nvar_b = 50\nvar_c = 18\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 70\nvar_g = 50\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1020\nvar_b = 50\nvar_c = 18\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 70\nvar_g = 50\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "1982": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 12로 나누어야 하는데 잘못하여 2를 곱했더니 622가 되었습니다. 어떤 수를 12로 나눈 몫과 나머지의 합을 구하시오.",
        "question_en": "You had to divide a number by 12 but mistakenly multiplied by 2 instead to get 622. Find the sum of the quotient and the remainder of the number divided by 12.",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "622 2 [OP_DIV] 12 [OP_FDIV] 622 2 [OP_DIV] 12 [OP_MOD] [OP_ADD]",
        "solution_abst_en": "622 2 [OP_DIV] 12 [OP_FDIV] 622 2 [OP_DIV] 12 [OP_MOD] [OP_ADD]",
        "solution_code_ko": "var_a = 622\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 12\nvar_e = var_c // var_d\nvar_f = 622\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = 12\nvar_j = var_h % var_i\nvar_k = var_e + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 622\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 12\nvar_e = var_c // var_d\nvar_f = 622\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = 12\nvar_j = var_h % var_i\nvar_k = var_e + var_j\nprint(int(var_k))"
    },
    "1983": {
        "category": "Comparison",
        "question_ko": "무게가 각각 1.2킬로그램(㎏), 3.1킬로그램(㎏), 2.4킬로그램(㎏), 3.0킬로그램(㎏), 1.8킬로그램(㎏)인 가방이 있습니다. 현주는 2킬로그램(㎏)보다 가벼운 가방을 사려고 했을 때, 현주가 살 수 있는 가방의 종류는 몇 개입니까?",
        "question_en": "There are bags weighing 1.2 kilograms (kg), 3.1 kilograms (kg), 2.4 kilograms (kg), 3.0 kilograms (kg), and 1.8 kilograms (kg), respectively. If Hyeon-joo wants to buy a bag that is lighter than 2 kg (kg), how many types of bags can Hyeon-joo buy?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 1.2 3.1 2.4 3.0 1.8 [OP_LIST_EOL] 2 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1.2 3.1 2.4 3.0 1.8 [OP_LIST_EOL] 2 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1.2\nvar_b = 3.1\nvar_c = 2.4\nvar_d = 3\nvar_e = 1.8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = []\nfor i in list_a:\n    if i < var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1.2\nvar_b = 3.1\nvar_c = 2.4\nvar_d = 3\nvar_e = 1.8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = []\nfor i in list_a:\n    if i < var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "1984": {
        "category": "Comparison",
        "question_ko": "지민이의 가방 무게는 1.2kg이고, 석진이의 가방 무게는 1350g입니다. 누구의 가방이 더 무겁습니까?",
        "question_en": "Jimin's bag weighs 1.2 kilograms (kg) and Seokjin's bag weighs 1350 grams (g). Whose bag is heavier?",
        "answer_ko": "석진",
        "answer_en": "Seokjin",
        "solution_abst_ko": "[OP_LIST_SOL] 지민 석진 [OP_LIST_EOL] [OP_LIST_SOL] 1.2 1000 [OP_MUL] 1350 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jimin Seokjin [OP_LIST_EOL] [OP_LIST_SOL] 1.2 1000 [OP_MUL] 1350 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '지민'\nvar_b = '석진'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.2\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 1350\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Jimin'\nvar_b = 'Seokjin'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.2\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 1350\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "1985": {
        "category": "Correspondence",
        "question_ko": "어떤 세 자리 수 7A5는 751보다 큽니다. A는 0부터 9까지의 숫자를 사용할 수 있고, 십의 자리 수일 때, A에 들어갈 수 있는 숫자의 개수는 몇 개인지 구하시오.",
        "question_en": "A three digit number 7A5 is greater than 751. If A can use numbers from 0 to 9 and is a tens digit, find how many numbers can fit in A.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "7A5 [OP_GEN_POSSIBLE_LIST] 751 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "7A5 [OP_GEN_POSSIBLE_LIST] 751 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '7A5'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 751\nlist_b = []\nfor i in list_a:\n    if i < var_b:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))",
        "solution_code_en": "var_a = '7A5'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 751\nlist_b = []\nfor i in list_a:\n    if i < var_b:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))"
    },
    "1986": {
        "category": "Correspondence",
        "question_ko": "5는 어떤 수를 4로 나누고 3을 더해준 값입니다. 어떤 수는 얼마입니까?",
        "question_en": "5 is a result of dividing a particular number by 4 and adding 3. What number is that particular number?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "5 3 [OP_SUB] 4 [OP_MUL]",
        "solution_abst_en": "5 3 [OP_SUB] 4 [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "1987": {
        "category": "Possibility",
        "question_ko": "서로 다른 6명이 있을 때, 그 중 2명을 뽑아 한 명은 회장, 다른 한명은 서기를 시키는 경우의 수는?",
        "question_en": "When there are six different people, what is the number of cases in which you select two of them and make one president and the other one secretary?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "6 1 1 [OP_ADD] [OP_PERM]",
        "solution_abst_en": "6 1 1 [OP_ADD] [OP_PERM]",
        "solution_code_ko": "var_a = 6\nvar_b = 1\nvar_c = 1\nvar_d = var_b + var_c\nvar_e = 1\nvar_a = int(var_a)\nvar_d = int(var_d)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e * (var_a-i)\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 1\nvar_c = 1\nvar_d = var_b + var_c\nvar_e = 1\nvar_a = int(var_a)\nvar_d = int(var_d)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e * (var_a-i)\nprint(int(var_e))"
    },
    "1988": {
        "category": "Comparison",
        "question_ko": "영화관에 관객들이 일렬로 나열된 의자에 차례대로 앉았습니다. 맨 오른쪽에 앉은 관객과 맨 왼쪽에 앉은 관객 사이에 30 명이 의자에 앉아 있다면 앉아있는 관객들은 모두 몇 명 입니까?",
        "question_en": "In the cinema, the audience sat in rows of chairs. If there are 30 people sitting in the chairs between the audience sitting on the far right and the audience sitting on the far left, how many people are sitting in the chairs?",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "30 2 [OP_ADD]",
        "solution_abst_en": "30 2 [OP_ADD]",
        "solution_code_ko": "var_a = 30\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 30\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "1989": {
        "category": "Arithmetic calculation",
        "question_ko": "도로의 한쪽에 처음부터 끝까지 10그루의 나무가 10미터(m) 간격으로 심어져 있습니다. 이 도로의 길이는 몇 미터(m)인지 구해 보시오.",
        "question_en": "On one side of the road, 10 trees are planted at intervals of 10 meters (m) from start to finish. Find the length in meters (m) of this road.",
        "answer_ko": "90",
        "answer_en": "90",
        "solution_abst_ko": "10 1 [OP_SUB] 10 [OP_MUL]",
        "solution_abst_en": "10 1 [OP_SUB] 10 [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 10\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 10\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "1990": {
        "category": "Arithmetic calculation",
        "question_ko": "소금물 10리터(L)에서 소금의 비중이 7/10입니다. 4개의 컵에 소금물을 똑같이 나누어 담을때 각 컵에 있는 소금은 몇 리터(L)인가요?",
        "question_en": "The certain amount of salt in 10 liters (L) of salt water is 7/10. If you divide the salt water equally into 4 cups, how many liters of salt are in each cup?",
        "answer_ko": "1.75",
        "answer_en": "1.75",
        "solution_abst_ko": "10 7/10 [OP_MUL] 4 [OP_DIV]",
        "solution_abst_en": "10 7/10 [OP_MUL] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 0.7\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 10\nvar_b = 0.7\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "1991": {
        "category": "Correspondence",
        "question_ko": "철수의 몸무게와 어머니의 몸무게와 아버지의 몸무게의 평균이 어머니의 몸무게와 같다. 철수의 몸무게는 어머니의 몸무게의 2/3이고 아버지의 몸무게는 72킬로그램(㎏)이면 철수의 몸무게는 얼마인지 구하시오.",
        "question_en": "The average of Cheolsu's weight, the mother's weight, and the father's weight is equal to the mother's weight. If Cheolsu's weight is 2/3 of his mother's weight and his father's weight is 72 kilograms (kg), what is Cheolsu's weight?",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "72 2 1 2/3 [OP_DIV] [OP_MUL] 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "72 2 1 2/3 [OP_DIV] [OP_MUL] 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 72\nvar_b = 2\nvar_c = 1\nvar_d = 0.6666666666666666\nvar_e = var_c / var_d\nvar_f = var_b * var_e\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_a / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 72\nvar_b = 2\nvar_c = 1\nvar_d = 0.6666666666666666\nvar_e = var_c / var_d\nvar_f = var_b * var_e\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_a / var_h\nprint(int(var_i))"
    },
    "1992": {
        "category": "Arithmetic calculation",
        "question_ko": "1리터(L)의 우유를 예슬이가 0.1리터(L) 마시고, 가영이가 예슬이보다 0.2리터(L)를 더 많이 마시고, 한초가 몇 리터(L)를 더 마셨더니 0.3리터(L)가 남았습니다. 한초가 마신 우유는 몇 리터(L)일지 구하시오.",
        "question_en": "Of 1 liter (L) of milk, Ye-seul drank 0.1 liters (L), and Ga-young drank 0.2 liters (L) more than Ye-seul, and Hancho drank several liters (L) more and the remaining amount of the milk was 0.3 liters (L). Find how many liters (L) of milk Hancho drank.",
        "answer_ko": "0.30",
        "answer_en": "0.3",
        "solution_abst_ko": "1 0.1 [OP_SUB] 0.1 0.2 [OP_ADD] [OP_SUB] 0.3 [OP_SUB]",
        "solution_abst_en": "1 0.1 [OP_SUB] 0.1 0.2 [OP_ADD] [OP_SUB] 0.3 [OP_SUB]",
        "solution_code_ko": "var_a = 1\nvar_b = 0.1\nvar_c = var_a - var_b\nvar_d = 0.1\nvar_e = 0.2\nvar_f = var_d + var_e\nvar_g = var_c - var_f\nvar_h = 0.3\nvar_i = var_g - var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 0.1\nvar_c = var_a - var_b\nvar_d = 0.1\nvar_e = 0.2\nvar_f = var_d + var_e\nvar_g = var_c - var_f\nvar_h = 0.3\nvar_i = var_g - var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "1993": {
        "category": "Correspondence",
        "question_ko": "어떤 수는 30과 40 사이의 두 자리 수입니다. 어떤 수는 일의 자리 숫자가 2입니다. 어떤 수를 구하시오.",
        "question_en": "A number is a two-digit number between 30 and 40. The number has a units digit of 2. Find the number.",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "30 40 1 [OP_LIST_ARANGE] 10 2 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "30 40 1 [OP_LIST_ARANGE] 10 2 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 30\nvar_b = 40\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 10\nvar_e = 2\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 1\nvar_g = list_b[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 30\nvar_b = 40\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 10\nvar_e = 2\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 1\nvar_g = list_b[var_f-1]\nprint(int(var_g))"
    },
    "1994": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 3.3, 7/2, 1.9, 14/5, 2.1이 있습니다. 이 중에서 2보다 크고 3보다 작은 수는 모두 몇 개입니까?",
        "question_en": "There are five numbers, 3.3, 7/2, 1.9, 14/5, and 2.1. How many of these numbers are greater than 2 and less than 3?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 3.3 7/2 1.9 14/5 2.1 [OP_LIST_EOL] 2 [OP_LIST_MORE] 3 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 3.3 7/2 1.9 14/5 2.1 [OP_LIST_EOL] 2 [OP_LIST_MORE] 3 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 3.3\nvar_b = 3.5\nvar_c = 1.9\nvar_d = 2.8\nvar_e = 2.1\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = 3\nlist_c = []\nfor i in list_b:\n    if i < var_g:\n        list_c.append(i)\nvar_h = len(list_c)\nprint(int(var_h))",
        "solution_code_en": "var_a = 3.3\nvar_b = 3.5\nvar_c = 1.9\nvar_d = 2.8\nvar_e = 2.1\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = 3\nlist_c = []\nfor i in list_b:\n    if i < var_g:\n        list_c.append(i)\nvar_h = len(list_c)\nprint(int(var_h))"
    },
    "1995": {
        "category": "Arithmetic calculation",
        "question_ko": "14 이상 105 미만인 자연수 중에서 가장 큰 수를 가장 작은 수로 나눈 몫은 얼마입니까?",
        "question_en": "Among natural numbers greater than 14 and less than 105, what is the quotient of the largest number divided by the smallest number?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "105 1 [OP_SUB] 14 [OP_FDIV]",
        "solution_abst_en": "105 1 [OP_SUB] 14 [OP_FDIV]",
        "solution_code_ko": "var_a = 105\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 14\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 105\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 14\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "1996": {
        "category": "Geometry",
        "question_ko": "꼭짓점의 수와 모서리의 수의 합이 40개인 각기둥이 있습니다. 이 각기둥의 면의 수는 몇 개입니까?",
        "question_en": "There is a prism with the sum of the number of verticles and the number of edges equal to 40. How many faces does this prism have?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "40 2 3 [OP_ADD] [OP_DIV] 2 [OP_ADD]",
        "solution_abst_en": "40 2 3 [OP_ADD] [OP_DIV] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 40\nvar_b = 2\nvar_c = 3\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 40\nvar_b = 2\nvar_c = 3\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "1997": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 상자에 38개의 인형을 나누어 담았더니 3개의 인형이 남았습니다. 한 상자에 담겨진 인형의 개수는 몇 개입니까?",
        "question_en": "I divided 38 dolls into 5 boxes, and there are 3 dolls left. How many boxes are there?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "38 3 [OP_SUB] 5 [OP_FDIV]",
        "solution_abst_en": "38 3 [OP_SUB] 5 [OP_FDIV]",
        "solution_code_ko": "var_a = 38\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 38\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "1998": {
        "category": "Geometry",
        "question_ko": "철사로 한 모서리의 길이가 13센티미터(㎝)인 정육면체를 만들려고 합니다. 철사는 적어도 몇 센티미터(㎝)가 필요합니까?",
        "question_en": "You are going to make a cube with one edge 13 centimeters (cm) long from a wire. At least how many centimeters (cm) of wire do you need?",
        "answer_ko": "156",
        "answer_en": "156",
        "solution_abst_ko": "13 4 [OP_MUL] 13 4 [OP_MUL] [OP_ADD] 13 4 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "13 4 [OP_MUL] 13 4 [OP_MUL] [OP_ADD] 13 4 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 13\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = 4\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 13\nvar_i = 4\nvar_j = var_h * var_i\nvar_k = var_g + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 13\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = 4\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 13\nvar_i = 4\nvar_j = var_h * var_i\nvar_k = var_g + var_j\nprint(int(var_k))"
    },
    "1999": {
        "category": "Comparison",
        "question_ko": "모든 모서리의 길이가 5센티미터(㎝)인 (가) 정육면체와 가로, 세로, 높이가 각각 4센티미터(㎝), 5센티미터(㎝), 6센티미터(㎝)인 (나) 직육면체 중 더 큰 도형은 무엇인가?",
        "question_en": "Which one is larger between a cube (a) with all edges 5 centimeters (cm) long and a cuboid (b) with width, length, and height 4 centimeters (cm), 5 centimeters (cm), and 6 centimeters (cm), respectively?",
        "answer_ko": "(가)",
        "answer_en": "(a)",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) [OP_LIST_EOL] [OP_LIST_SOL] 5 3 [OP_POW] 4 5 6 [OP_MUL] [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (a) (b) [OP_LIST_EOL] [OP_LIST_SOL] 5 3 [OP_POW] 4 5 6 [OP_MUL] [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 5\nvar_d = 3\nvar_e = var_c ** var_d\nvar_f = 4\nvar_g = 5\nvar_h = 6\nvar_i = var_g * var_h\nvar_j = var_f * var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = '(a)'\nvar_b = '(b)'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 5\nvar_d = 3\nvar_e = var_c ** var_d\nvar_f = 4\nvar_g = 5\nvar_h = 6\nvar_i = var_g * var_h\nvar_j = var_f * var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "2000": {
        "category": "Arithmetic calculation",
        "question_ko": "둘레가 3킬로미터(㎞)인 연못의 둘레를 철수와 영희가 같은 곳에서 동시에 출발하여 서로 반대 방향으로 걸었다. 철수는 매분 100미터(m)의 속력으로, 영희는 매분 150미터(m)의 속력으로 걸었다면 몇 분 후에 처음으로 다시 만나는지 구하여라",
        "question_en": "The circumference of pond, which has a circumference of 3km (km), started from the same place as Cheol-su and Young-hee at the same time and walked in opposite directions. If Cheol-su walks at a speed of 100 meters (m) per minute and Young-hee walks at a speed of 150 meters (m) per minute, find the two meet again for the first time in a few minutes.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "3 100 1000 [OP_DIV] 150 1000 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_abst_en": "3 100 1000 [OP_DIV] 150 1000 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 3\nvar_b = 100\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = 150\nvar_f = 1000\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = var_a / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 3\nvar_b = 100\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = 150\nvar_f = 1000\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = var_a / var_h\nprint(int(var_i))"
    },
    "2001": {
        "category": "Comparison",
        "question_ko": "학생들이 한 줄로 서 있습니다. 호석이는 윤기보다 왼쪽에 있고 그 사이에는 다른 학생들이 5명 서 있습니다. 호석이의 왼쪽에는 9명이 서 있고, 윤기의 오른쪽에는 6명이 서 있습니다. 줄을 서 있는 학생은 모두 몇 명입니까?",
        "question_en": "There are students standing in a line. Hoseok is at the left side of Yoongi, and five other students are standing between them. Nine people are standing to Hoseok's left, and six people are standing to Yoongi's right. How many students are in the line?",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "1 1 [OP_ADD] 5 [OP_ADD] 9 [OP_ADD] 6 [OP_ADD]",
        "solution_abst_en": "1 1 [OP_ADD] 5 [OP_ADD] 9 [OP_ADD] 6 [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 9\nvar_g = var_e + var_f\nvar_h = 6\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 9\nvar_g = var_e + var_f\nvar_h = 6\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "2002": {
        "category": "Correspondence",
        "question_ko": "A, B는 0에서 9까지의 수입니다. 다섯자리 수 A835B가 12로 나누어 떨어질 때 A835B가 될 수 있는 가장 큰 수와 가장 작은 수의 차를 구하시오.",
        "question_en": "A and B are numbers from 0 to 9. When the five-digit number A835B is divisible by 12, find the difference between the largest number and the smallest number that can be made from A835B.",
        "answer_ko": "69996",
        "answer_en": "69996",
        "solution_abst_ko": "A835B [OP_GEN_POSSIBLE_LIST] 12 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "A835B [OP_GEN_POSSIBLE_LIST] 12 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 'A835B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 12\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_d = list_c[-var_c]\nvar_e = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_f = list_d[var_e-1]\nvar_g = var_d - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 'A835B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 12\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_d = list_c[-var_c]\nvar_e = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_f = list_d[var_e-1]\nvar_g = var_d - var_f\nprint(int(var_g))"
    },
    "2003": {
        "category": "Arithmetic calculation",
        "question_ko": "동민이와 규형이는 각각 사탕을 몇 개씩 가지고 있습니다. 동민이가 규형이보다 사탕 수가 5개 더 많고, 두 사람의 사탕 수의 합이 43개라면 규형이는 몇 개를 가지고 있습니까?",
        "question_en": "Dongmin and Kyuhyung each have some candies. If Dongmin has 5 more candies than Kyuhyung and the sum of their candies is 43, how many candies does Kyuhyung have?",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "43 5 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "43 5 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 43\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 43\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "2004": {
        "category": "Comparison",
        "question_ko": "재석이는 이틀 동안 5리터(L)의 물을 마셨고, 재석이의 형은 4900밀리리터(㎖)를 마셨습니다. 둘 중 이틀 동안 물을 더 많이 마신 사람은 누구입니까?",
        "question_en": "Jaesuk drank 5 liters (l) of water for two days, and Jaesuk's brother drank 4900 milliliters (ml). Which of the two drank more water in two days?",
        "answer_ko": "재석",
        "answer_en": "Jaesuk",
        "solution_abst_ko": "[OP_LIST_SOL] 재석 형 [OP_LIST_EOL] [OP_LIST_SOL] 5 1000 [OP_MUL] 4900 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jaesuk brother [OP_LIST_EOL] [OP_LIST_SOL] 5 1000 [OP_MUL] 4900 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '재석'\nvar_b = '형'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 5\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 4900\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Jaesuk'\nvar_b = 'brother'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 5\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 4900\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "2005": {
        "category": "Correspondence",
        "question_ko": "4A5B+C2D7=7070을 만족하는 A, B, C, D가 서로 다른 숫자일 때 C는 얼마입니까?",
        "question_en": "What is C when A, B, C, and D are different numbers that correspond to this equation of 4A58+C2D7=7070?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "4A5B+C2D7=7070 C [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "4A5B+C2D7=7070 C [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '4A5B+C2D7=7070'\nvar_b = 'C'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '4A5B+C2D7=7070'\nvar_b = 'C'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "2006": {
        "category": "Correspondence",
        "question_ko": "35에서 어떤 수를 빼고 2를 곱한 뒤 12를 더하여 8로 나눈 다음 4를 뺀 값이 5입니다. 어떤 수를 구하시오.",
        "question_en": "Subtract this number from 35, and then multiply it by 2, add 12, divide it by 8, then subtract 4, and you get 5. Find this number.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "35 5 4 [OP_ADD] 8 [OP_MUL] 12 [OP_SUB] 2 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "35 5 4 [OP_ADD] 8 [OP_MUL] 12 [OP_SUB] 2 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 35\nvar_b = 5\nvar_c = 4\nvar_d = var_b + var_c\nvar_e = 8\nvar_f = var_d * var_e\nvar_g = 12\nvar_h = var_f - var_g\nvar_i = 2\nvar_j = var_h / var_i\nvar_k = var_a - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 35\nvar_b = 5\nvar_c = 4\nvar_d = var_b + var_c\nvar_e = 8\nvar_f = var_d * var_e\nvar_g = 12\nvar_h = var_f - var_g\nvar_i = 2\nvar_j = var_h / var_i\nvar_k = var_a - var_j\nprint(int(var_k))"
    },
    "2007": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.3, 1/3에서 0.4보다 큰 수 중 가장 작은 수는?",
        "question_en": "What is the smallest number greater than 0.4 among 0.8, 1/2, 0.3, 1/3?",
        "answer_ko": "0.50",
        "answer_en": "0.5",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.3 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_MORE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.3 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_MORE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.3\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.4\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.3\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.4\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "2008": {
        "category": "Arithmetic calculation",
        "question_ko": "땅콩 16킬로그램(㎏)을 6봉지에 똑같게 나누어 담고 한 봉지를 친구들과 나누어 먹으려고 합니다. 한 사람이 4/15킬로그램(㎏)씩 먹는다면 몇 명이 먹을 수 있습니까?",
        "question_en": "You are going to divide 16 kilograms (kg) of peanuts equally into 6 bags and share one bag with your friends. How many people can eat if each person eats 4/15 kilograms (kg)?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "16 6 [OP_DIV] 4/15 [OP_DIV]",
        "solution_abst_en": "16 6 [OP_DIV] 4/15 [OP_DIV]",
        "solution_code_ko": "var_a = 16\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.26666666666666666\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 16\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.26666666666666666\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "2009": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 7로 나누었더니 몫이 12이고 나머지가 5였습니다. 이 수를 8로 나누었을 때 나머지는 얼마입니까?",
        "question_en": "When a number is divided by 7, the quotient is 12 and the remainder is 5. What is the remainder when this number is divided by 8?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "12 7 [OP_MUL] 5 [OP_ADD] 8 [OP_MOD]",
        "solution_abst_en": "12 7 [OP_MUL] 5 [OP_ADD] 8 [OP_MOD]",
        "solution_code_ko": "var_a = 12\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e % var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 12\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e % var_f\nprint(int(var_g))"
    },
    "2010": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 3인 정사각형의 넓이를 구하시오.",
        "question_en": "Find the area of a square with side length 3.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "3 2 [OP_POW]",
        "solution_abst_en": "3 2 [OP_POW]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = var_a ** var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = var_a ** var_b\nprint(int(var_c))"
    },
    "2011": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 공연장의 객석 1260석은 모두 만석입니다. 관객 중 7/18은 안경을 썼고 안경을 쓰지 않은 관객 중 6/11이 남자라면 안경을 쓰지 않은 남자 관객은 모두 몇 명인지 구하세요.",
        "question_en": "All 1,260 seats in a concert hall were full. If 7/18 of the audience wore glasses and 6/11 among the audience with no glasses were male, find out the number of male audience members who were not wearing glasses.",
        "answer_ko": "420",
        "answer_en": "420",
        "solution_abst_ko": "1260 1 7/18 [OP_SUB] [OP_MUL] 6/11 [OP_MUL]",
        "solution_abst_en": "1260 1 7/18 [OP_SUB] [OP_MUL] 6/11 [OP_MUL]",
        "solution_code_ko": "var_a = 1260\nvar_b = 1\nvar_c = 0.3888888888888889\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 0.5454545454545454\nvar_g = var_e * var_f\nprint(int(eval('{:.2f}'.format(round(var_g+1e-10,2)))))",
        "solution_code_en": "var_a = 1260\nvar_b = 1\nvar_c = 0.3888888888888889\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 0.5454545454545454\nvar_g = var_e * var_f\nprint(int(eval('{:.2f}'.format(round(var_g+1e-10,2)))))"
    },
    "2012": {
        "category": "Comparison",
        "question_ko": "상점에서 보석 A, B, C, D를 팔고 있습니다. A는 D보다 비싸고, B는 A보다 비싸며, C가 가장 쌉니다. 가장 비싼 보석은 무엇인가요?",
        "question_en": "The shop sells gems A, B, C, and D. A is more expensive than D, B is more expensive than A, and C is the cheapest. What is the most expensive jewel?",
        "answer_ko": "B",
        "answer_en": "B",
        "solution_abst_ko": "[OP_LIST_SOL] A B C D [OP_LIST_EOL] [OP_LIST_SOL] A D > B A > C A < C B < C D < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D [OP_LIST_EOL] [OP_LIST_SOL] A D > B A > C A < C B < C D < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'A'\nvar_f = 'D'\nvar_g = '>'\nvar_h = 'B'\nvar_i = 'A'\nvar_j = '>'\nvar_k = 'C'\nvar_l = 'A'\nvar_m = '<'\nvar_n = 'C'\nvar_o = 'B'\nvar_p = '<'\nvar_q = 'C'\nvar_r = 'D'\nvar_s = '<'\nlist_b= []\nif \"/\" in str(var_s):\n    var_s = eval(str(var_s))\nlist_b.append(var_s)\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_t = 1\nvar_u = list_c[var_t-1]\nprint(var_u)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'A'\nvar_f = 'D'\nvar_g = '>'\nvar_h = 'B'\nvar_i = 'A'\nvar_j = '>'\nvar_k = 'C'\nvar_l = 'A'\nvar_m = '<'\nvar_n = 'C'\nvar_o = 'B'\nvar_p = '<'\nvar_q = 'C'\nvar_r = 'D'\nvar_s = '<'\nlist_b= []\nif \"/\" in str(var_s):\n    var_s = eval(str(var_s))\nlist_b.append(var_s)\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_t = 1\nvar_u = list_c[var_t-1]\nprint(var_u)"
    },
    "2013": {
        "category": "Possibility",
        "question_ko": "주어진 숫자 구슬 7, 6, 8, 5를 한 번씩 모두 사용하여 만든 수 중 세 번째 큰 수와 세 번째 작은 수의 합을 구하시오.",
        "question_en": "Find the sum of the third largest number and the third smallest number using all of the given number marbles 7, 6, 8, and 5 once.",
        "answer_ko": "14443",
        "answer_en": "14443",
        "solution_abst_ko": "[OP_LIST_SOL] 7 6 8 5 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 7 6 8 5 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 7\nvar_b = 6\nvar_c = 8\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 7\nvar_b = 6\nvar_c = 8\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))"
    },
    "2014": {
        "category": "Possibility",
        "question_ko": "1, 3, 5, 8, 9의 5장의 숫자 카드를 중복을 사용하여 두 자리 수를 만들 때 가장 큰 두 자리 수와 세 번째로 가장 작은 두 자리 수의 합을 구하시오.",
        "question_en": "Find the sum of the largest two-digit number and the third smallest two-digit number when making a two-digit number by allowing the repetition of the five number cards 1, 3, 5, 8, and 9.",
        "answer_ko": "114",
        "answer_en": "114",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 5 8 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PRODUCT] 1 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 5 8 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PRODUCT] 1 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 5\nvar_d = 8\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 5\nvar_d = 8\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h + var_j\nprint(int(var_k))"
    },
    "2015": {
        "category": "Correspondence",
        "question_ko": "어떤 소수 두 자리 수를 소수 2번째 자리에서 반올림하면 1.7이 됩니다. 이러한 수 중 가장 큰 값에서 가장 작은 값을 빼면 무엇이 되는지 구하시오. 단, 소수점을 포함하여 나타내시오.",
        "question_en": "Rounding a number to 2 decimal places gives 1.7. What is the result of subtracting the smallest of these numbers from the largest of these numbers? Please indicate including the decimal point.",
        "answer_ko": "0.09",
        "answer_en": "0.09",
        "solution_abst_ko": "1.74 1.65 [OP_SUB]",
        "solution_abst_en": "1.74 1.65 [OP_SUB]",
        "solution_code_ko": "var_a = 1.74\nvar_b = 1.65\nvar_c = var_a - var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 1.74\nvar_b = 1.65\nvar_c = var_a - var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "2016": {
        "category": "Arithmetic calculation",
        "question_ko": "지민이가 사용한 테이프 길이는 정국이가 사용한 테이프 길이보다 26밀리미터(㎜)깁니다. 정국이가 테이프를 45센티미터(㎝) 사용했다면 지민이가 사용한 테이프 길이는 몇 센티미터(m)입니까?",
        "question_en": "The length of the tape Jimin used is 26 millimeters (mm) longer than the length of the tape Jungkook used. If Jungkook used 45 centimeters (cm) of tape, how many centimeters (m) did Jimin use?",
        "answer_ko": "47.60",
        "answer_en": "47.6",
        "solution_abst_ko": "45 26 10 [OP_DIV] [OP_ADD]",
        "solution_abst_en": "45 26 10 [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 45\nvar_b = 26\nvar_c = 10\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 45\nvar_b = 26\nvar_c = 10\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "2017": {
        "category": "Correspondence",
        "question_ko": "6은 어떤 수에 2를 더해야 할것을 잘못하여 2를 빼서 나온 결과입니다. 어떤 수를 구하세요.",
        "question_en": "If 6 is the result of subtracting 2 from a number, instead of adding 2, write down what the number is.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "6 2 [OP_ADD]",
        "solution_abst_en": "6 2 [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "2018": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중에서 가장 큰 수와 2번째로 큰 수로 나눈 나머지는 얼마입니까?",
        "question_en": "There are three given numbers: 10, 11 and 12. What is the remainder if you divide the largest number by the second largest number?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_MOD]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_MOD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = var_e % var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = var_e % var_g\nprint(int(var_h))"
    },
    "2019": {
        "category": "Arithmetic calculation",
        "question_ko": "180개의 우유를 3개의 상자에 나누어 담고, 각 상자에 담긴 우유는 4개의 봉투에 똑같이 나누어 담았습니다. 한 개의 봉투에 담긴 우유 개수는 몇 개 입니까?",
        "question_en": "180 bottles of milk are divided into 3 cartons, and the bottles of milk in each carton are equally divided into 4 bags. How many bottles of milk are in one bag?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "180 3 [OP_DIV] 4 [OP_DIV]",
        "solution_abst_en": "180 3 [OP_DIV] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 180\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 180\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "2020": {
        "category": "Arithmetic calculation",
        "question_ko": "1 이상 6 이하, 11 이상 16 이하의 수 중 짝수의 개수를 구하시오.",
        "question_en": "Find the number of even numbers from 1 to 6 and from 11 to 16.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "1 6 [OP_LIST_EVEN] [OP_LIST_LEN] 11 16 [OP_LIST_EVEN] [OP_LIST_LEN] [OP_ADD]",
        "solution_abst_en": "1 6 [OP_LIST_EVEN] [OP_LIST_LEN] 11 16 [OP_LIST_EVEN] [OP_LIST_LEN] [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 6\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = len(list_a)\nvar_d = 11\nvar_e = 16\nlist_b = []\nif var_d%2!=0:\n    for i in range(var_d+1, var_e+1, 2):\n        list_b.append(i)\nelse:\n    for i in range(var_d, var_e+1, 2):\n        list_b.append(i)\nvar_f = len(list_b)\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 6\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = len(list_a)\nvar_d = 11\nvar_e = 16\nlist_b = []\nif var_d%2!=0:\n    for i in range(var_d+1, var_e+1, 2):\n        list_b.append(i)\nelse:\n    for i in range(var_d, var_e+1, 2):\n        list_b.append(i)\nvar_f = len(list_b)\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "2021": {
        "category": "Correspondence",
        "question_ko": "13.26 에 어떤 수를 곱하였더니 132.6 이 되었습니다. 0.064 에 어떤 수를 곱한 값을 구하시오.",
        "question_en": "13.26 multiplied by some number is 132.6. Find the value of 0.064 multiplied by that number.",
        "answer_ko": "0.64",
        "answer_en": "0.64",
        "solution_abst_ko": "132.6 13.26 [OP_DIV] 0.064 [OP_MUL]",
        "solution_abst_en": "132.6 13.26 [OP_DIV] 0.064 [OP_MUL]",
        "solution_code_ko": "var_a = 132.6\nvar_b = 13.26\nvar_c = var_a / var_b\nvar_d = 0.064\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 132.6\nvar_b = 13.26\nvar_c = var_a / var_b\nvar_d = 0.064\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "2022": {
        "category": "Correspondence",
        "question_ko": "23를 6으로 나누면 몫과 나머지가 각각 A와 B가 됩니다. 이 때 A를 구하시오.",
        "question_en": "When 23 is divided by 6, the quotient and remainder are A and B, respectively. Find A at this time.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "23 6 [OP_FDIV]",
        "solution_abst_en": "23 6 [OP_FDIV]",
        "solution_code_ko": "var_a = 23\nvar_b = 6\nvar_c = var_a // var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 23\nvar_b = 6\nvar_c = var_a // var_b\nprint(int(var_c))"
    },
    "2023": {
        "category": "Correspondence",
        "question_ko": "A를 6으로 나누면 몫은 3이고 나머지는 2가 됩니다. A는 자연수입니다. 이 때 A를 구하시오.",
        "question_en": "When A is divided by 6, the quotient is 3 and the remainder is 2. A is a natural number. Find A at this time.",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "6 3 [OP_MUL] 2 [OP_ADD]",
        "solution_abst_en": "6 3 [OP_MUL] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "2024": {
        "category": "Possibility",
        "question_ko": "3개의 숫자 4, 2, 5가 주어져 있습니다. 주어진 숫자를 한 번씩 사용하여 만들 수 있는 세 자리 수는 모두 몇 개입니까?",
        "question_en": "You are given three numbers 4, 2 and 5. How many three-digit numbers can you make by using the given numbers once each?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 4 2 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 4 2 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "2025": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 주차장의 주차 요금은 30 분 동안 500 원이고, 30 분 초과시 10 분마다 200 원씩 추가됩니다. 하영이 아버지께서 이 주차장에 1 시간 20 분 동안 주차를 하 였다면 주차 요금은 얼마입니까?",
        "question_en": "The parking fee for this parking lot is 500 won for 30 minutes, and 200 won is added for every 10 minutes after 30 minutes. If Ha-Young's father parked in this parking lot for 1 hour and 20 minutes, what is the parking fee?",
        "answer_ko": "1500",
        "answer_en": "1500",
        "solution_abst_ko": "1 60 [OP_MUL] 20 [OP_ADD] 30 [OP_SUB] 10 [OP_FDIV] 200 [OP_MUL] 500 [OP_ADD]",
        "solution_abst_en": "1 60 [OP_MUL] 20 [OP_ADD] 30 [OP_SUB] 10 [OP_FDIV] 200 [OP_MUL] 500 [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 20\nvar_e = var_c + var_d\nvar_f = 30\nvar_g = var_e - var_f\nvar_h = 10\nvar_i = var_g // var_h\nvar_j = 200\nvar_k = var_i * var_j\nvar_l = 500\nvar_m = var_k + var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 1\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 20\nvar_e = var_c + var_d\nvar_f = 30\nvar_g = var_e - var_f\nvar_h = 10\nvar_i = var_g // var_h\nvar_j = 200\nvar_k = var_i * var_j\nvar_l = 500\nvar_m = var_k + var_l\nprint(int(var_m))"
    },
    "2026": {
        "category": "Possibility",
        "question_ko": "각 자리수가 1, 4, 5, 9 중 하나로 구성되어 있고, 십의 자리수가 9인 두 번째 큰 세 자리수는 얼마입니까? 단, 각 숫자는 한 번씩만 쓰였습니다.",
        "question_en": "What is the second largest three-digit number where each digit is one of the digits 1, 4, 5, or 9 and the tens digit is 9? However, each number is used only once.",
        "answer_ko": "591",
        "answer_en": "591",
        "solution_abst_ko": "[OP_LIST_SOL] 1 4 5 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 9 [OP_LIST_SEARCH_FIXED_DIGIT] 2 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1 4 5 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 9 [OP_LIST_SEARCH_FIXED_DIGIT] 2 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1\nvar_b = 4\nvar_c = 5\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 9\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 2\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 4\nvar_c = 5\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 9\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 2\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nprint(int(var_i))"
    },
    "2027": {
        "category": "Correspondence",
        "question_ko": "32+A7B=705일 때, B를 구하시오.",
        "question_en": "When 32+A7B=705, find B.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "32+A7B=705 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "32+A7B=705 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '32+A7B=705'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '32+A7B=705'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "2028": {
        "category": "Arithmetic calculation",
        "question_ko": "현지는 20개의 연필 중 7개를 현승이에게 주었고 다시 태우에게 5개를 받았다. 현지가 가지고 있는 연필은 모두 몇 개인지 구하시오.",
        "question_en": "Hyunji gave 7 of the 20 pencils to Hyeonseung and again received 5 from Taewoo. Find how many pencils Hyunji has.",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "20 7 [OP_SUB] 5 [OP_ADD]",
        "solution_abst_en": "20 7 [OP_SUB] 5 [OP_ADD]",
        "solution_code_ko": "var_a = 20\nvar_b = 7\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 7\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "2029": {
        "category": "Arithmetic calculation",
        "question_ko": "전체 길이가 950센티미터(㎝)인 막대기를 둘로 나눴다. 긴 막대가 짧은 막대보다 150센티미터(㎝) 더 길다면 짧은 막대는 몇 센티미터(㎝)입니까?",
        "question_en": "A stick with a total length of 950 centimeters (cm) was divided in two. If the long bar is 150 centimeters (cm) longer than the short bar, how many centimeters (cm) is the short bar?",
        "answer_ko": "400",
        "answer_en": "400",
        "solution_abst_ko": "950 150 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "950 150 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 950\nvar_b = 150\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 950\nvar_b = 150\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "2030": {
        "category": "Comparison",
        "question_ko": "빨간 풍선이 50개, 노란 풍선이 26개가 있습니다. 파란 풍선은 노란 풍선보다 8개 많습니다. 가장 많은 색깔의 풍선은 무엇입니까?",
        "question_en": "There are 50 red balloons and 26 yellow balloons. There are 8 more blue ballons than yellow balloons. Which colored balloon is the most?",
        "answer_ko": "빨간",
        "answer_en": "red",
        "solution_abst_ko": "[OP_LIST_SOL] 빨간 노란 파란 [OP_LIST_EOL] [OP_LIST_SOL] 50 26 26 8 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] red yellow blue [OP_LIST_EOL] [OP_LIST_SOL] 50 26 26 8 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '빨간'\nvar_b = '노란'\nvar_c = '파란'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 50\nvar_e = 26\nvar_f = 26\nvar_g = 8\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'red'\nvar_b = 'yellow'\nvar_c = 'blue'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 50\nvar_e = 26\nvar_f = 26\nvar_g = 8\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "2031": {
        "category": "Geometry",
        "question_ko": "오각형 내에 그릴 수 있는 대각선의 개수는?",
        "question_en": "How many diagonals can you draw in a pentagon?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "5 5 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "5 5 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 5\nvar_b = 5\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 5\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "2032": {
        "category": "Arithmetic calculation",
        "question_ko": "6으로 나누어 떨어질 수 있는 세 자리 수 중 가장 큰 수는?",
        "question_en": "What is the largest three-digit number divisible by 6?",
        "answer_ko": "996",
        "answer_en": "996",
        "solution_abst_ko": "100 999 1 [OP_LIST_ARANGE] 6 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_abst_en": "100 999 1 [OP_LIST_ARANGE] 6 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))",
        "solution_code_en": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))"
    },
    "2033": {
        "category": "Possibility",
        "question_ko": "0, 1, 2, 3의 수가 각각 적힌 4장의 카드에서 3장을 뽑아 만들 수 있는 세 자리의 정수의 개수를 구하시오.",
        "question_en": "Find the number of 3-digit integers that can be made by drawing 3 cards from 4 cards each containing the numbers 0, 1, 2, and 3.",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "2034": {
        "category": "Comparison",
        "question_ko": "키가 작은 사람부터 순서대로 9명이 한 줄로 서 있습니다. 호석이가 가장 뒤에 서 있습니다. 키가 큰 사람부터 순서대로 다시 줄을 서면 호석이는 앞에서부터 몇 번째에 서게 됩니까?",
        "question_en": "Nine people are lined up in order from shortest to tallest. Hoseok stands at the very back. If they line up again in order from tallest to shortest, what number will Hoseok be from the front?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "9 9 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "9 9 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 9\nvar_b = 9\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 9\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "2035": {
        "category": "Arithmetic calculation",
        "question_ko": "예원이는 학교가 끝난 후 유치원에 들러서 동생을 만나 집에 함께 가기로 했습니다. 예원이의 학교에서 유치원까지의 거리는 1킬로미터(㎞) 700미터(m)이고, 유치원에서 집까지의 거리는 900미터(m)입니다. 예원이네 학교에서 유치원을 거쳐 집까지 가는 거리의 중간 지점은 학교에서 몇 미터(m)입니까?",
        "question_en": "After school, Yewon plans to stop by the kindergarten to meet her sister and go home with her. The distance from Yewon's school to the kindergarten is 1 kilometer (km) and 700 meters (m), and the distance from the kindergarten to her house is 900 meters (m). How far is the midpoint of the distance starting from Yewon's school through the kindergarten and to her house, from Yewon's school in meters (m)?",
        "answer_ko": "1300",
        "answer_en": "1300",
        "solution_abst_ko": "1 1000 [OP_MUL] 700 [OP_ADD] 900 [OP_ADD] 2 [OP_DIV]",
        "solution_abst_en": "1 1000 [OP_MUL] 700 [OP_ADD] 900 [OP_ADD] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 700\nvar_e = var_c + var_d\nvar_f = 900\nvar_g = var_e + var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 700\nvar_e = var_c + var_d\nvar_f = 900\nvar_g = var_e + var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "2036": {
        "category": "Comparison",
        "question_ko": "국어, 수학, 영어, 과학, 사회 시험을 순서대로 봤습니다. 다음 과목들 중 3번째로 치른 시험은 무엇입니까?",
        "question_en": "You took Korean, Mathematics, English, Science, and History tests in order. Which of the following subjects was the third test taken?",
        "answer_ko": "영어",
        "answer_en": "English",
        "solution_abst_ko": "[OP_LIST_SOL] 국어 수학 영어 과학 사회 [OP_LIST_EOL] 3 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Korean Mathematics English Science History [OP_LIST_EOL] 3 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '국어'\nvar_b = '수학'\nvar_c = '영어'\nvar_d = '과학'\nvar_e = '사회'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nvar_g = list_a[var_f-1]\nprint(var_g)",
        "solution_code_en": "var_a = 'Korean'\nvar_b = 'Mathematics'\nvar_c = 'English'\nvar_d = 'Science'\nvar_e = 'History'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nvar_g = list_a[var_f-1]\nprint(var_g)"
    },
    "2037": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 90센티미터(㎝)인 정사각형 모양의 간판이 있습니다. 이 간판의 가장자리에 3센티미터(㎝) 간격으로 작은 전구를 달기로 했을 때, 전구는 모두 몇 개가 필요합니까?",
        "question_en": "There is a sign in the shape of a square with a side of 90 centimeters (cm). If you decide to hang small light bulbs every 3 centimeters (cm) along the edges of this sign, how many light bulbs will you need in total?",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "90 4 [OP_MUL] 3 [OP_FDIV]",
        "solution_abst_en": "90 4 [OP_MUL] 3 [OP_FDIV]",
        "solution_code_ko": "var_a = 90\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 90\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "2038": {
        "category": "Possibility",
        "question_ko": "3, 9, 6, 0, 5, 1, 7을 한 번씩만 사용하여 만들 수 있는 일곱 자리 수 중 가장 큰 수에서 가장 작은 수를 뺀 값은 얼마입니까?",
        "question_en": "What is the largest minus the smallest seven-digit number that can be formed by using 3, 9, 6, 0, 5, 1, and 7 only once?",
        "answer_ko": "8729631",
        "answer_en": "8729631",
        "solution_abst_ko": "[OP_LIST_SOL] 3 9 6 0 5 1 7 [OP_LIST_EOL] 7 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 3 9 6 0 5 1 7 [OP_LIST_EOL] 7 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 3\nvar_b = 9\nvar_c = 6\nvar_d = 0\nvar_e = 5\nvar_f = 1\nvar_g = 7\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h = 7\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_h))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_l = list_d[var_k-1]\nvar_m = var_j - var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 3\nvar_b = 9\nvar_c = 6\nvar_d = 0\nvar_e = 5\nvar_f = 1\nvar_g = 7\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h = 7\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_h))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_l = list_d[var_k-1]\nvar_m = var_j - var_l\nprint(int(var_m))"
    },
    "2039": {
        "category": "Correspondence",
        "question_ko": "A, B, C는 0에서 9까지의 서로 다른 숫자입니다. 두 자리 수끼리의 덧셈식 AB+CB=CC6에서 B를 구하시오.",
        "question_en": "A, B, C are different numbers from 0 to 9. Find B from the two-digit addition formula AB+CB=CC6.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "AB+CB=CC6 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "AB+CB=CC6 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'AB+CB=CC6'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'AB+CB=CC6'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "2040": {
        "category": "Geometry",
        "question_ko": "어느 세 점은 한 직선 위에 있지 않습니다. 이 세 점으로 만들 수 있는 선분의 개수를 구하시오.",
        "question_en": "When three points are not on a straight line, find the number of line segments that can be formed from these three points.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "3 2 [OP_COMB]",
        "solution_abst_en": "3 2 [OP_COMB]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))"
    },
    "2041": {
        "category": "Arithmetic calculation",
        "question_ko": "빨간색 공 80개와 파란색 공 40개가 있습니다. 빨간색 공은 파란색 공과 흰색 공을 합한 것보다 12개 더 적습니다. 흰색 공은 몇 개입니까?",
        "question_en": "There are 80 red balls and 40 blue balls. There are 12 fewer red balls than blue and white balls combined. How many white balls are there?",
        "answer_ko": "52",
        "answer_en": "52",
        "solution_abst_ko": "80 12 [OP_ADD] 40 [OP_SUB]",
        "solution_abst_en": "80 12 [OP_ADD] 40 [OP_SUB]",
        "solution_code_ko": "var_a = 80\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 40\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 80\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 40\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "2042": {
        "category": "Comparison",
        "question_ko": "정국이는 0.8, 윤기는 1/2, 유정이는 0.9, 유나는 1/3의 숫자카드를 갖고 있습니다. 0.3보다 큰 숫자카드를 가지고 있는 사람은 몇 명입니까?",
        "question_en": "Jungkook has 0.8, Yoongi has 1/2, Yoojung has 0.9, Yuna has 1/3 number card. How many people have number cards greater than 0.3?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.3 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.3 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.3\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.3\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "2043": {
        "category": "Arithmetic calculation",
        "question_ko": "네 자리 수 중, 3200보다 크고 4300보다 작은 것은 몇 개인지 구하시오.",
        "question_en": "How many four-digit numbers are greater than 3200 and less than 4300?",
        "answer_ko": "1099",
        "answer_en": "1099",
        "solution_abst_ko": "3200 1 [OP_ADD] 4300 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_LEN]",
        "solution_abst_en": "3200 1 [OP_ADD] 4300 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 3200\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 4300\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = len(list_a)\nprint(int(var_h))",
        "solution_code_en": "var_a = 3200\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 4300\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = len(list_a)\nprint(int(var_h))"
    },
    "2044": {
        "category": "Geometry",
        "question_ko": "어떤 직사각형의 둘레의 길이가 16 센티미터(㎝)이며, 가로의 길이는 세로의 길이보다 2 센티미터(㎝)만큼 길다. 이 직사각형의 가로의 길이는 얼마인가?",
        "question_en": "The perimeter of a rectangle is 16 centimeters (cm), and its width is 2 centimeters (cm) longer than its length. What is the length of the width of this rectangle?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "16 2 [OP_DIV] 2 [OP_SUB] 2 [OP_DIV] 2 [OP_ADD]",
        "solution_abst_en": "16 2 [OP_DIV] 2 [OP_SUB] 2 [OP_DIV] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 16\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 16\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "2045": {
        "category": "Arithmetic calculation",
        "question_ko": "마트에 오이가 58개 있습니다. 오이는 당근보다 24개 많고, 토마토보다 49개 적습니다. 무의 수는 당근의 수와 같습니다. 마트에 있는 오이, 당근, 토마토, 무는 모두 몇 개입니까?",
        "question_en": "There are 58 cucumbers in the mart. The numbers of cucumbers are 24 more than carrots and 49 less than tomatoes. The number of radishes equals the number of carrots. How many cucumbers, carrots, tomatoes, and radishes are in the supermarket in total?",
        "answer_ko": "233",
        "answer_en": "233",
        "solution_abst_ko": "58 58 24 [OP_SUB] [OP_ADD] 58 49 [OP_ADD] [OP_ADD] 58 24 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "58 58 24 [OP_SUB] [OP_ADD] 58 49 [OP_ADD] [OP_ADD] 58 24 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 58\nvar_b = 58\nvar_c = 24\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 58\nvar_g = 49\nvar_h = var_f + var_g\nvar_i = var_e + var_h\nvar_j = 58\nvar_k = 24\nvar_l = var_j - var_k\nvar_m = var_i + var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 58\nvar_b = 58\nvar_c = 24\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 58\nvar_g = 49\nvar_h = var_f + var_g\nvar_i = var_e + var_h\nvar_j = 58\nvar_k = 24\nvar_l = var_j - var_k\nvar_m = var_i + var_l\nprint(int(var_m))"
    },
    "2046": {
        "category": "Correspondence",
        "question_ko": "인수는 수학 문제를 풀다 1.36을 곱해야 하는데 잘못하여 나누어서 0.5를 정답으로 제출하였습니다. 계산을 제대로 했다면 답이 얼마입니까?",
        "question_en": "Insoo had to multiply a certain number by 1.36, but he mistakenly divided it and submitted 0.5 as an answer. If he calculated it correctly, what is the answer?",
        "answer_ko": "0.92",
        "answer_en": "0.92",
        "solution_abst_ko": "0.5 1.36 [OP_MUL] 1.36 [OP_MUL]",
        "solution_abst_en": "0.5 1.36 [OP_MUL] 1.36 [OP_MUL]",
        "solution_code_ko": "var_a = 0.5\nvar_b = 1.36\nvar_c = var_a * var_b\nvar_d = 1.36\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.5\nvar_b = 1.36\nvar_c = var_a * var_b\nvar_d = 1.36\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "2047": {
        "category": "Arithmetic calculation",
        "question_ko": "일정한 빠르기로 2분에 4미터(m)를 가는 송충이와 3분에 4미터(m)를 가는 굼벵이가 있습니다. 이 굼벵이가 송충이보다 24미터(m)앞에서 동시에 같은 방향으로 출발했다면 몇 분 후에 송충이와 굼벵이가 만나는지 구해보시오.",
        "question_en": "There is a caterpillar that travels 4 meters (m) in 2 minutes and a cicada larva that travels 4 meters (m) in 3 minutes at a constant speed. If this cicada larva, 24 meters (m) ahead of the caterpillar, sets off in the same direction at the same time, find out how many minutes later will the caterpillar and the cicada larva meet.",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "24 4 2 [OP_DIV] 4 3 [OP_DIV] [OP_SUB] [OP_DIV]",
        "solution_abst_en": "24 4 2 [OP_DIV] 4 3 [OP_DIV] [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 24\nvar_b = 4\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = 4\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = var_d - var_g\nvar_i = var_a / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))",
        "solution_code_en": "var_a = 24\nvar_b = 4\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = 4\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = var_d - var_g\nvar_i = var_a / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))"
    },
    "2048": {
        "category": "Comparison",
        "question_ko": "한 숫자에 9를 곱하고 1을 더한 것은, 그 숫자에 10을 곱하고 100을 뺀 것과 같다. 그 숫자를 A라고 할 때, A를 7로 나눈 나머지를 구하시오.",
        "question_en": "Multiplying a certain number by 9 and adding 1 is the same as multiplying that number by 10 and subtracting 100. Let the number be A, what is the remainder when A is divided by 7?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "1 100 [OP_ADD] 10 9 [OP_SUB] [OP_DIV] 7 [OP_MOD]",
        "solution_abst_en": "1 100 [OP_ADD] 10 9 [OP_SUB] [OP_DIV] 7 [OP_MOD]",
        "solution_code_ko": "var_a = 1\nvar_b = 100\nvar_c = var_a + var_b\nvar_d = 10\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 7\nvar_i = var_g % var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 100\nvar_c = var_a + var_b\nvar_d = 10\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 7\nvar_i = var_g % var_h\nprint(int(var_i))"
    },
    "2049": {
        "category": "Geometry",
        "question_ko": "큰 정사각형 모양의 종이는 작은 정사각형 모양의 종이 여러 장으로 만들어졌다. 작은 정사각형 종이가 20장 남아서 가로 한 변과 세로 한 변을 1열씩 늘리려고 하였더니 9개의 작은 종이가 부족하였다. 작은 정사각형 종이는 총 몇 장인가?",
        "question_en": "A large square-shaped piece of paper is made from several small square-shaped pieces of paper. There were 20 small square-shaped pieces of paper left, so I tried to increase each side by 1 row, and 9 small pieces of paper were short. How many small square-shaped pieces of paper are there in total?",
        "answer_ko": "216",
        "answer_en": "216",
        "solution_abst_ko": "20 9 [OP_ADD] 1 [OP_SUB] 2 [OP_DIV] 2 [OP_POW] 20 [OP_ADD]",
        "solution_abst_en": "20 9 [OP_ADD] 1 [OP_SUB] 2 [OP_DIV] 2 [OP_POW] 20 [OP_ADD]",
        "solution_code_ko": "var_a = 20\nvar_b = 9\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 20\nvar_k = var_i + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 20\nvar_b = 9\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 20\nvar_k = var_i + var_j\nprint(int(var_k))"
    },
    "2050": {
        "category": "Arithmetic calculation",
        "question_ko": "숫자 3, 4로 나누어 떨어질 수 있는 다섯 자리 수 중 가장 큰 수는 무엇입니까?",
        "question_en": "What is the largest five-digit number divisible by both 3 and 4?",
        "answer_ko": "99996",
        "answer_en": "99996",
        "solution_abst_ko": "10000 99999 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 4 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_abst_en": "10000 99999 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 4 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 10000\nvar_b = 99999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 4\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[-var_f]\nprint(int(var_g))",
        "solution_code_en": "var_a = 10000\nvar_b = 99999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 4\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[-var_f]\nprint(int(var_g))"
    },
    "2051": {
        "category": "Correspondence",
        "question_ko": "네 자리 수 A56B은 36으로 나누어 떨어진다. A에 알맞은 숫자는 모두 몇 개입니까?",
        "question_en": "The four-digit number A56B is divisible by 36. How many numbers fit for A?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "A56B [OP_GEN_POSSIBLE_LIST] 36 [OP_LIST_DIVISIBLE] A56B A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_abst_en": "A56B [OP_GEN_POSSIBLE_LIST] 36 [OP_LIST_DIVISIBLE] A56B A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 'A56B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 36\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 'A56B'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nvar_e = len(list_c)\nprint(int(var_e))",
        "solution_code_en": "var_a = 'A56B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 36\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 'A56B'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nvar_e = len(list_c)\nprint(int(var_e))"
    },
    "2052": {
        "category": "Arithmetic calculation",
        "question_ko": "각 상자에 20켤레의 신발이 들어있는 상자들이 있습니다. (나) 신발이 (가) 신발보다 5배 많고 (가) 신발이 8상자 있습니다. (나) 신발은 (가) 신발보다 몇 켤레 더 많습니까?",
        "question_en": "There are boxes with 20 pairs of shoes in each box. There are 5 times more (B) shoes than (A) shoes and there are 8 boxes of (A) shoes. How many more pairs of (B) shoes do you have than (A) shoes?",
        "answer_ko": "640",
        "answer_en": "640",
        "solution_abst_ko": "8 5 [OP_MUL] 8 [OP_SUB] 20 [OP_MUL]",
        "solution_abst_en": "8 5 [OP_MUL] 8 [OP_SUB] 20 [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c - var_d\nvar_f = 20\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 8\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c - var_d\nvar_f = 20\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "2053": {
        "category": "Geometry",
        "question_ko": "넓이가 36제곱센티미터(㎠)이며 높이가 8센티미터(㎝)인 삼각형의 밑변의 길이를 구하세요.",
        "question_en": "Find the length of the base of a triangle with an area of 36 square centimeters (cm2) and a height of 8 centimeters (cm) .",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "36 2 [OP_MUL] 8 [OP_DIV]",
        "solution_abst_en": "36 2 [OP_MUL] 8 [OP_DIV]",
        "solution_code_ko": "var_a = 36\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 36\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "2054": {
        "category": "Possibility",
        "question_ko": "자연수 0, 1, 3, 5, 6을 겹치지 않게 이용하여 세 자리 자연수를 만들 때, 200보다 큰 자연수는 몇 개인가?",
        "question_en": "How many natural numbers greater than 200 are formed by using the natural numbers 0, 1, 3, 5, and 6 without overlapping?",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 3 5 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 200 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 3 5 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 200 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 3\nvar_d = 5\nvar_e = 6\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 200\nlist_c = []\nfor i in list_b:\n    if i > var_g:\n        list_c.append(i)\nvar_h = len(list_c)\nprint(int(var_h))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 3\nvar_d = 5\nvar_e = 6\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 200\nlist_c = []\nfor i in list_b:\n    if i > var_g:\n        list_c.append(i)\nvar_h = len(list_c)\nprint(int(var_h))"
    },
    "2055": {
        "category": "Arithmetic calculation",
        "question_ko": "12부터 53까지의 자연수가 있을 때, 이 수들의 평균을 구하시오.",
        "question_en": "Given the natural numbers from 12 to 53, find the average of these numbers.",
        "answer_ko": "32.50",
        "answer_en": "32.5",
        "solution_abst_ko": "12 53 1 [OP_LIST_ARANGE] [OP_LIST_MEAN]",
        "solution_abst_en": "12 53 1 [OP_LIST_ARANGE] [OP_LIST_MEAN]",
        "solution_code_ko": "var_a = 12\nvar_b = 53\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_a = [float(i) for i in list_a]\nvar_d = sum(list_a)/len(list_a)\nprint('{:.2f}'.format(round(var_d+1e-10,2)))",
        "solution_code_en": "var_a = 12\nvar_b = 53\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_a = [float(i) for i in list_a]\nvar_d = sum(list_a)/len(list_a)\nprint('{:.2f}'.format(round(var_d+1e-10,2)))"
    },
    "2056": {
        "category": "Comparison",
        "question_ko": "식당에 손님들이 한 줄로 서 있습니다. 맨 뒤에 줄을 선 사람 앞에 8명이 서 있을 때, 줄을 서 있는 손님은 모두 몇 명입니까?",
        "question_en": "Customers stand in a line at the restaurant. If 8 people are standing in front of the person at the end of the line, how many customers are all in line?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "8 1 [OP_ADD]",
        "solution_abst_en": "8 1 [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 8\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "2057": {
        "category": "Arithmetic calculation",
        "question_ko": "백의 자리가 1인 세 자리 수를 모두 합하면 얼마입니까?",
        "question_en": "What is the sum of all three-digit numbers with 1 in the hundreds place?",
        "answer_ko": "14950",
        "answer_en": "14950",
        "solution_abst_ko": "[OP_LIST_SOL] 1 A B [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 1 A B [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 'A'\nvar_c = 'B'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nans_dict = dict()\nvar_d = str(var_d)\nlist_b = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_d) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_b.append(new_elem)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 'A'\nvar_c = 'B'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nans_dict = dict()\nvar_d = str(var_d)\nlist_b = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_d) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_b.append(new_elem)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint(int(var_e))"
    },
    "2058": {
        "category": "Correspondence",
        "question_ko": "등식 A45+2B3=418이 성립한다고 합니다. B에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "The equation A45+2B3=418 makes sense. What number should go in B?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "A45+2B3=418 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A45+2B3=418 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A45+2B3=418'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A45+2B3=418'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "2059": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 두 자리 수를 13으로 나누었더니 나머지가 2였습니다. 어떤 수가 될 수 있는 수 중 가장 큰 수는 무엇입니까?",
        "question_en": "When a certain two-digit number is divided by 13, the remainder is 2. What is the largest possible number that can be the number?",
        "answer_ko": "93",
        "answer_en": "93",
        "solution_abst_ko": "10 99 1 [OP_LIST_ARANGE] 13 2 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MAX]",
        "solution_abst_en": "10 99 1 [OP_LIST_ARANGE] 13 2 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 13\nvar_e = 2\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint(int(var_g))",
        "solution_code_en": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 13\nvar_e = 2\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint(int(var_g))"
    },
    "2060": {
        "category": "Correspondence",
        "question_ko": "36을 뺀 값에 22를 곱하면 748이 되는 수가 있습니다. 이 수는 무엇입니까?",
        "question_en": "There is a number that becomes 748 when subtracted 36 and multiplied by 22. What is this number?",
        "answer_ko": "70",
        "answer_en": "70",
        "solution_abst_ko": "748 22 [OP_DIV] 36 [OP_ADD]",
        "solution_abst_en": "748 22 [OP_DIV] 36 [OP_ADD]",
        "solution_code_ko": "var_a = 748\nvar_b = 22\nvar_c = var_a / var_b\nvar_d = 36\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 748\nvar_b = 22\nvar_c = var_a / var_b\nvar_d = 36\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "2061": {
        "category": "Possibility",
        "question_ko": "한 변의 길이가 2센티미터(㎝)인 정사각형 210개를 모두 붙여서 서로 다른 직사각형을 만들려고 합니다. 만든 직사각형을 돌렸을 때 같은 모양이면 한 가지로 봅니다. 만드는 방법은 모두 몇 가지입니까?",
        "question_en": "You want to make a rectangle that is different from each other by attaching all 210 squares that has a side length of 2 centimeters (cm). If the rectangle has the same shape when rotated, it is regarded as the same one. How many ways can you think of?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "210 [OP_LIST_GET_DIVISOR] [OP_LIST_LEN] 2 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "210 [OP_LIST_GET_DIVISOR] [OP_LIST_LEN] 2 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 210\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = len(list_a)\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = 1\nvar_f=int(((var_d+9*10**(var_e-2))//(10**(var_e-1)))*10**(var_e-1))\n\nprint(int(var_f))",
        "solution_code_en": "var_a = 210\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = len(list_a)\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = 1\nvar_f=int(((var_d+9*10**(var_e-2))//(10**(var_e-1)))*10**(var_e-1))\n\nprint(int(var_f))"
    },
    "2062": {
        "category": "Comparison",
        "question_ko": "학생 15명이 한 줄로 서 있습니다. 남준이가 왼쪽에서 7번째라면 오른쪽에서는 몇 번째입니까?",
        "question_en": "15 students stand in a line. If Namjoon is the 7th person from the left, what about from the right side?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "15 7 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "15 7 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 15\nvar_b = 7\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 7\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "2063": {
        "category": "Comparison",
        "question_ko": "세 명의 학생 윤기, 정국, 유나는 각각 7, 6, 9만큼의 숫자를 가지고 있습니다. 2번째로 큰 숫자를 가진 사람은 누구입니까?",
        "question_en": "The three students, Yoongi, Jungkook and Yuna, have the numbers 7, 6, and 9 respectively. Who has the 2nd largest number?",
        "answer_ko": "윤기",
        "answer_en": "Yoongi",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 유나 [OP_LIST_EOL] [OP_LIST_SOL] 7 6 9 [OP_LIST_EOL] 2 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook and Yuna [OP_LIST_EOL] [OP_LIST_SOL] 7 6 9 [OP_LIST_EOL] 2 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nvar_c = '유나'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 7\nvar_e = 6\nvar_f = 9\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nvar_c = 'and'\nvar_d = 'Yuna'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 7\nvar_f = 6\nvar_g = 9\nlist_b= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_h = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_i = list_c[-var_h]\nvar_j = list_b.index(var_i)+1\nvar_k = list_a[var_j-1]\nprint(var_k)"
    },
    "2064": {
        "category": "Possibility",
        "question_ko": "세 자리 숫자 중 4, 2, 5가 모두 들어있는 수는 몇 개입니까?",
        "question_en": "How many three-digit numbers contain all of 4, 2, and 5?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 4 2 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 4 2 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "2065": {
        "category": "Arithmetic calculation",
        "question_ko": "빨간 구슬과 파란 구슬을 합쳐서 6000개 있다. 빨간 구슬과 파란 구슬의 차를 빨간 구슬과 파란 구슬의 합에서 빼면 4800개 이다. 파란 구슬이 빨간 구슬보다 많다면 파란 구슬은 몇 개인지 구하시오.",
        "question_en": "There are 6000 red and blue marbles together. If you subtract the difference between the red marbles and the blue marbles from the sum of the red marbles and the blue marbles, you get 4800. If there are more blue marbles than red marbles, how many blue marbles are there?",
        "answer_ko": "3600",
        "answer_en": "3600",
        "solution_abst_ko": "6000 4800 2 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "6000 4800 2 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 6000\nvar_b = 4800\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6000\nvar_b = 4800\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "2066": {
        "category": "Correspondence",
        "question_ko": "과일 바구니에 과일이 60개 있습니다. 바나나가 32개, 사과가 10개, 배가 5개 있습니다. 과일바구니에 과일의 종류가 바나나, 사과, 배, 귤이 있을 경우 귤은 몇 개가 있나요?",
        "question_en": "There are 60 fruits in the fruit basket. There are 32 bananas, 10 apples and 5 pears. If there are bananas, apples, pears, and tangerines in the fruit basket, how many tangerines are there?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "60 32 [OP_SUB] 10 [OP_SUB] 5 [OP_SUB]",
        "solution_abst_en": "60 32 [OP_SUB] 10 [OP_SUB] 5 [OP_SUB]",
        "solution_code_ko": "var_a = 60\nvar_b = 32\nvar_c = var_a - var_b\nvar_d = 10\nvar_e = var_c - var_d\nvar_f = 5\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 60\nvar_b = 32\nvar_c = var_a - var_b\nvar_d = 10\nvar_e = var_c - var_d\nvar_f = 5\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "2067": {
        "category": "Correspondence",
        "question_ko": "케찹이 84.6그램(g)이 있다. 핫도그 12개에 똑같은 양의 케첩을 뿌려 남는 것이 없게 하면 핫도그 하나 당 몇 그램(g)의 케찹을 뿌려야하는지 구하시오.",
        "question_en": "There are 84.6 grams (g) of ketchup. If you put the same amount of ketchup on 12 hot dogs so that there are no leftovers, find how many grams (g) of ketchup you need to put on each hot dog.",
        "answer_ko": "7.05",
        "answer_en": "7.05",
        "solution_abst_ko": "84.6 12 [OP_DIV]",
        "solution_abst_en": "84.6 12 [OP_DIV]",
        "solution_code_ko": "var_a = 84.6\nvar_b = 12\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 84.6\nvar_b = 12\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "2068": {
        "category": "Arithmetic calculation",
        "question_ko": "양팔 저울의 한쪽에는 0.5킬로그램(㎏)짜리 추 한 개와 0.3킬로그램(㎏)짜리 추 2개가 있습니다. 다른 쪽에 책 한 권을 올려두었을 때 저울이 수평이 되려면 책 한 권은 몇 킬로그램(㎏)이어야 합니까?",
        "question_en": "On one side of the two-arm scale, there is one weight weighing 0.5 kilograms (kg) and two weights weighing 0.3 kilograms (kg). How many kilograms (kg) must a book weigh in order to make the scale horizontal when this book is placed on the other side?",
        "answer_ko": "1.10",
        "answer_en": "1.1",
        "solution_abst_ko": "0.5 0.3 2 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "0.5 0.3 2 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 0.5\nvar_b = 0.3\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.5\nvar_b = 0.3\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "2069": {
        "category": "Arithmetic calculation",
        "question_ko": "연필 1타는 12자루입니다. 정국이가 처음에 가진 연필은 17자루였는데 어머니께서 연필을 몇 자루 더 사주셔서 총 가지고 있는 연필의 수가 2타가 되었습니다. 어머니께서 추가로 구매해주신 연필은 몇 자루입니까?",
        "question_en": "A dozen means 12. Jungkook initially had 17 pencils, but his mother bought a few more, bringing the total number of pencils to 2 dozen. How many additional pencils did the mother buy?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "2 12 [OP_MUL] 17 [OP_SUB]",
        "solution_abst_en": "2 12 [OP_MUL] 17 [OP_SUB]",
        "solution_code_ko": "var_a = 2\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 17\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 17\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "2070": {
        "category": "Arithmetic calculation",
        "question_ko": "어머니와 아버지가 각각 공책 7권과 14권을 더 사주셨습니다. 처음에 지민이가 공책을 33권 가지고 있었다고 할 때, 처음보다 공책의 수가 몇 권 더 많아졌습니까?",
        "question_en": "My mother and father bought me 7 more and 14 more notebooks, respectively. If Jimin had 33 notebooks at first, how many more notebooks does she have than at first?",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "33 7 [OP_ADD] 14 [OP_ADD] 33 [OP_SUB]",
        "solution_abst_en": "33 7 [OP_ADD] 14 [OP_ADD] 33 [OP_SUB]",
        "solution_code_ko": "var_a = 33\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 14\nvar_e = var_c + var_d\nvar_f = 33\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 33\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 14\nvar_e = var_c + var_d\nvar_f = 33\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "2071": {
        "category": "Arithmetic calculation",
        "question_ko": "1에서 200까지의 자연수 중에서 16과 24의 공배수는 모두 몇 개 있습니까?",
        "question_en": "How many common multiples of 16 and 24 exist between 1 to 200?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "1 200 1 [OP_LIST_ARANGE] 16 [OP_LIST_DIVISIBLE] 24 [OP_LIST_DIVISIBLE] [OP_SET_INTERSECT] [OP_LIST_LEN]",
        "solution_abst_en": "1 200 1 [OP_LIST_ARANGE] 16 [OP_LIST_DIVISIBLE] 24 [OP_LIST_DIVISIBLE] [OP_SET_INTERSECT] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 200\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 16\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 24\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nlist_d = list(set(list_b) & set(list_c))\nvar_f = len(list_d)\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 200\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 16\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 24\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nlist_d = list(set(list_b) & set(list_c))\nvar_f = len(list_d)\nprint(int(var_f))"
    },
    "2072": {
        "category": "Correspondence",
        "question_ko": "어떤 소수를 10배만큼 커지게 한 후, 소수점을 왼쪽으로 세 칸 옮기면 0.375가 됩니다. 원래의 소수를 소수점을 포함하여 구하시오.",
        "question_en": "After multiplying a decimal by 10, moving the decimal point three places to the left equals 0.375. Find the original decimal number including the decimal point.",
        "answer_ko": "37.50",
        "answer_en": "37.5",
        "solution_abst_ko": "0.375 10 3 [OP_POW] [OP_MUL] 10 [OP_DIV]",
        "solution_abst_en": "0.375 10 3 [OP_POW] [OP_MUL] 10 [OP_DIV]",
        "solution_code_ko": "var_a = 0.375\nvar_b = 10\nvar_c = 3\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 10\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 0.375\nvar_b = 10\nvar_c = 3\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 10\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "2073": {
        "category": "Arithmetic calculation",
        "question_ko": "230명의 학생에게 색종이를 15개씩 나누어 주었다. 나누어 준 색종이의 개수는 몇 개인지 구하시오.",
        "question_en": "230 students were each given 15 pieces of colored paper. Find the number of pieces of colored paper distributed.",
        "answer_ko": "3450",
        "answer_en": "3450",
        "solution_abst_ko": "230 15 [OP_MUL]",
        "solution_abst_en": "230 15 [OP_MUL]",
        "solution_code_ko": "var_a = 230\nvar_b = 15\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 230\nvar_b = 15\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "2074": {
        "category": "Arithmetic calculation",
        "question_ko": "상자 한 개에 구슬이 100개씩 들어 있습니다. 상자 10개에는 구슬이 모두 몇 개 들어 있습니까?",
        "question_en": "Each box contains 100 marbles. How many marbles are in all 10 boxes?",
        "answer_ko": "1000",
        "answer_en": "1000",
        "solution_abst_ko": "100 10 [OP_MUL]",
        "solution_abst_en": "100 10 [OP_MUL]",
        "solution_code_ko": "var_a = 100\nvar_b = 10\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 100\nvar_b = 10\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "2075": {
        "category": "Arithmetic calculation",
        "question_ko": "일정한 빠르기로 1분에 2.1킬로미터(㎞)를 달리는 트럭과 4분에 10.5킬로미터(㎞)를 달리는 택시가 있습니다. 트럭은 택시보다 몇 배 더 빠른지 구하시오.",
        "question_en": "There is a truck that runs at a constant speed of 2.1 kilometers (km) in 1 minute, and a taxi that runs at a constant speed of 10.5 kilometers (km) in 4 minutes. Find how many times the truck is faster than the taxi.",
        "answer_ko": "0.80",
        "answer_en": "0.8",
        "solution_abst_ko": "2.1 1 [OP_DIV] 10.5 4 [OP_DIV] [OP_DIV]",
        "solution_abst_en": "2.1 1 [OP_DIV] 10.5 4 [OP_DIV] [OP_DIV]",
        "solution_code_ko": "var_a = 2.1\nvar_b = 1\nvar_c = var_a / var_b\nvar_d = 10.5\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = var_c / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 2.1\nvar_b = 1\nvar_c = var_a / var_b\nvar_d = 10.5\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = var_c / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "2076": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 6을 곱하면 72가 됩니다. 호석이는 어떤 수에 8을 더하고자 합니다. 올바른 결과값을 구하시오.",
        "question_en": "If a number is multiplied by 6, it is 72. Hoseok wants to add 8 to the number. Write down what Hoseok gets.",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "72 6 [OP_DIV] 8 [OP_ADD]",
        "solution_abst_en": "72 6 [OP_DIV] 8 [OP_ADD]",
        "solution_code_ko": "var_a = 72\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 8\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 72\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 8\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "2077": {
        "category": "Geometry",
        "question_ko": "사면체의 면은 모두 몇 개인가요?",
        "question_en": "Nine people stand in a line in order from shortest to tallest. Hoseok is standing 4th from the front. If you line up again in order from the tallest to the shortest, what number will Hoseok stand from the back?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "4",
        "solution_abst_en": "4",
        "solution_code_ko": "var_a = 4\nprint(int(var_a))",
        "solution_code_en": "var_a = 4\nprint(int(var_a))"
    },
    "2078": {
        "category": "Possibility",
        "question_ko": "7, 9, 3, 6 수 카드 4장을 중복 사용하여 만들 수 있는 가장 작은 네 자리 수를 올림하여 백의 자리까지 나타내어 보세요.",
        "question_en": "Round up the smallest 4-digit number to the hundreds place made from using 4 number cards 7, 9, 3, and 6 with overlapping allowed.",
        "answer_ko": "3400",
        "answer_en": "3400",
        "solution_abst_ko": "[OP_LIST_SOL] 7 9 3 6 [OP_LIST_EOL] 4 [OP_LIST_GET_PRODUCT] 1 [OP_LIST_MIN] 3 [OP_CEIL]",
        "solution_abst_en": "[OP_LIST_SOL] 7 9 3 6 [OP_LIST_EOL] 4 [OP_LIST_GET_PRODUCT] 1 [OP_LIST_MIN] 3 [OP_CEIL]",
        "solution_code_ko": "var_a = 7\nvar_b = 9\nvar_c = 3\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = 3\nvar_i=int(((var_g+9*10**(var_h-2))//(10**(var_h-1)))*10**(var_h-1))\n\nprint(int(var_i))",
        "solution_code_en": "var_a = 7\nvar_b = 9\nvar_c = 3\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = 3\nvar_i=int(((var_g+9*10**(var_h-2))//(10**(var_h-1)))*10**(var_h-1))\n\nprint(int(var_i))"
    },
    "2079": {
        "category": "Geometry",
        "question_ko": "가로 30 센티미터(㎝) , 세로 20 센티미터(㎝) , 높이 5센티미터(㎝) 인 직육면체 모양의 큰 상자와 이 상자에 가로 6센티미터(㎝), 세로 4센티미터(㎝), 높이 1센티미터(㎝) 인 직육면체 모양의 작은 상자가 있다. 큰 상자가 작은 상자보다 몇 배 더 큰지 구하시오.",
        "question_en": "There is a large box in the shape of a cuboid which is 30 centimeters (cm) wide, 20 centimeters (cm) long, and 5 cm (cm) high, and a small cuboid-shaped box 6 centimeters (cm) wide, 4 centimeters (cm) long, and 1 cm (cm) high. Find how many times is the larger box than the smaller box.",
        "answer_ko": "125",
        "answer_en": "125",
        "solution_abst_ko": "30 20 [OP_MUL] 5 [OP_MUL] 6 4 [OP_MUL] 1 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "30 20 [OP_MUL] 5 [OP_MUL] 6 4 [OP_MUL] 1 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 30\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c * var_d\nvar_f = 6\nvar_g = 4\nvar_h = var_f * var_g\nvar_i = 1\nvar_j = var_h * var_i\nvar_k = var_e / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 30\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c * var_d\nvar_f = 6\nvar_g = 4\nvar_h = var_f * var_g\nvar_i = 1\nvar_j = var_h * var_i\nvar_k = var_e / var_j\nprint(int(var_k))"
    },
    "2080": {
        "category": "Comparison",
        "question_ko": "민주가 가지고 있는 끈의 길이는 6.704미터(m)이고 대현이가 가지고 있는 끈의 길이는 6.74미터(m)입니다. 누가 가지고 있는 끈이 더 깁니까?",
        "question_en": "The length of the string that Minju has is 6.704 meters (m) and the length of the string that Daehyun has is 6.74 meters (m). Who has the longer string?",
        "answer_ko": "대현",
        "answer_en": "Daehyun",
        "solution_abst_ko": "[OP_LIST_SOL] 민주 대현 [OP_LIST_EOL] [OP_LIST_SOL] 6.704 6.74 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Minju Daehyun [OP_LIST_EOL] [OP_LIST_SOL] 6.704 6.74 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '민주'\nvar_b = '대현'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6.704\nvar_d = 6.74\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Minju'\nvar_b = 'Daehyun'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6.704\nvar_d = 6.74\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "2081": {
        "category": "Arithmetic calculation",
        "question_ko": "휴대폰 9개를 충전하는데 19kWh가 소모된다고 합니다. 휴대폰 하나를 충전하는데는 몇 kWh가 소모되나요?",
        "question_en": "It is said that charging 9 mobile phones consumes 19 kWh. How many kWh does it take to charge one mobile phone?",
        "answer_ko": "2.11",
        "answer_en": "2.11",
        "solution_abst_ko": "19 9 [OP_DIV]",
        "solution_abst_en": "19 9 [OP_DIV]",
        "solution_code_ko": "var_a = 19\nvar_b = 9\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 19\nvar_b = 9\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "2082": {
        "category": "Arithmetic calculation",
        "question_ko": "유나에게 23개의 사탕이 있었는데 몇 개를 먹었더니 7개가 남았다. 유나가 먹은 사탕의 수는?",
        "question_en": "Yuna had 23 candies, but after eating a few, there are 7 left. How many candies did Yuna eat?",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "23 7 [OP_SUB]",
        "solution_abst_en": "23 7 [OP_SUB]",
        "solution_code_ko": "var_a = 23\nvar_b = 7\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 23\nvar_b = 7\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "2083": {
        "category": "Comparison",
        "question_ko": "백설 공주 옆의 난쟁이 중 5명의 키를 쟀다. 평균이 81.6센티미터(㎝)가 나왔고, 제일 키가 큰 빨강이의 키를 뺀 나머지의 평균이 제일 작은 초록이의 키를 뺀 평균보다 6센티미터(㎝) 낮았다. 파랑이, 검정이, 노랑이의 키가 88센티미터(㎝), 84센티미터(㎝), 76센티미터(㎝)라고 할 때, 초록이의 키를 구하라.",
        "question_en": "The height of 5 of the dwarves next to Snow White is measured. The average was 81.6 centimeters (cm), and the average height without the tallest, Red, was 6 centimeters (cm) lower than the average height without the shortest, Green. If the heights of Blue, Black, and Yellow are 88 centimeters (cm), 84 centimeters (cm), and 76 centimeters (cm), find the height of Green.",
        "answer_ko": "68",
        "answer_en": "68",
        "solution_abst_ko": "81.6 5 [OP_MUL] 88 84 [OP_ADD] 76 [OP_ADD] [OP_SUB] 6 4 [OP_MUL] [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "81.6 5 [OP_MUL] 88 84 [OP_ADD] 76 [OP_ADD] [OP_SUB] 6 4 [OP_MUL] [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 81.6\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 88\nvar_e = 84\nvar_f = var_d + var_e\nvar_g = 76\nvar_h = var_f + var_g\nvar_i = var_c - var_h\nvar_j = 6\nvar_k = 4\nvar_l = var_j * var_k\nvar_m = var_i - var_l\nvar_n = 2\nvar_o = var_m / var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 81.6\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 88\nvar_e = 84\nvar_f = var_d + var_e\nvar_g = 76\nvar_h = var_f + var_g\nvar_i = var_c - var_h\nvar_j = 6\nvar_k = 4\nvar_l = var_j * var_k\nvar_m = var_i - var_l\nvar_n = 2\nvar_o = var_m / var_n\nprint(int(var_o))"
    },
    "2084": {
        "category": "Arithmetic calculation",
        "question_ko": "윤기는 200쪽짜리 책 한 권을 사서 매일 12쪽씩 2주일 동안 읽었습니다. 윤기가 읽지 않은 부분은 몇 쪽인지 구하시오.",
        "question_en": "Yoongi bought a 200-page book and read 12 pages each day for two weeks. Find out how many pages Yoongi has not read.",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "200 12 2 [OP_MUL] 7 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "200 12 2 [OP_MUL] 7 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 200\nvar_b = 12\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = 7\nvar_f = var_d * var_e\nvar_g = var_a - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 200\nvar_b = 12\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = 7\nvar_f = var_d * var_e\nvar_g = var_a - var_f\nprint(int(var_g))"
    },
    "2085": {
        "category": "Correspondence",
        "question_ko": "어떤 수의 3배에서 8을 빼고 2를 뺀 값은 어떤 수와 같다. 어떤 수를 구하시오.",
        "question_en": "3 times a number minus 8 minus 2 equals the number. Find the number.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "2 8 [OP_ADD] 3 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "2 8 [OP_ADD] 3 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 2\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 2\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))"
    },
    "2086": {
        "category": "Comparison",
        "question_ko": "사과 한 박스의 무게는 1.3킬로그램(㎏)이고, 배 한 박스의 무게는 1100그램(g)입니다. 사과와 배가 한 박스씩 있다고 할 때, 둘 중 어느 것이 더 무겁습니까?",
        "question_en": "A box of apples weighs 1.3 kilograms (kg), and a box of pears weighs 1100 grams (g). If you have one box of apples and one box of pears, which one is heavier?",
        "answer_ko": "사과",
        "answer_en": "apples",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 배 [OP_LIST_EOL] [OP_LIST_SOL] 1.3 1000 [OP_MUL] 1100 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] apples pears [OP_LIST_EOL] [OP_LIST_SOL] 1.3 1000 [OP_MUL] 1100 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '배'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.3\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 1100\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'apples'\nvar_b = 'pears'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.3\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 1100\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "2087": {
        "category": "Possibility",
        "question_ko": "3개의 전구를 켜거나 꺼서 신호를 만드려고 합니다. 만들 수 있는 신호는 모두 몇 가지입니까?",
        "question_en": "You are trying to make a signal by turning three light bulbs on or off. How many signals can you make?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "2 3 [OP_POW]",
        "solution_abst_en": "2 3 [OP_POW]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = var_a ** var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = var_a ** var_b\nprint(int(var_c))"
    },
    "2088": {
        "category": "Correspondence",
        "question_ko": "빨간 구슬과 파란 구슬의 개수 차이가 12개이다. 또 전체 구슬의 수는 빨간 구슬과 파란 구슬의 개수 차이보다 40이 많다. 파란 구슬의 개수와 빨간 구슬의 개수를 곱하면 얼마인지 구하시오",
        "question_en": "The difference between the number of red and blue marbles is 12. Also, the total number of marbles is 40 more than the difference between the number of red and blue marbles. What is the product of the number of blue ones times the number of red ones?",
        "answer_ko": "640",
        "answer_en": "640",
        "solution_abst_ko": "40 2 [OP_DIV] 12 [OP_ADD] 40 2 [OP_DIV] [OP_MUL]",
        "solution_abst_en": "40 2 [OP_DIV] 12 [OP_ADD] 40 2 [OP_DIV] [OP_MUL]",
        "solution_code_ko": "var_a = 40\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 12\nvar_e = var_c + var_d\nvar_f = 40\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = var_e * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 40\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 12\nvar_e = var_c + var_d\nvar_f = 40\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = var_e * var_h\nprint(int(var_i))"
    },
    "2089": {
        "category": "Arithmetic calculation",
        "question_ko": "8, 0, 3, 7, 5, 2, 4 중 가장 큰 수와 4번째로 큰 수의 차이를 구하시오.",
        "question_en": "Find the difference between the largest and the 4th largest number of 8, 0, 3, 7, 5, 2, 4.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 8 0 3 7 5 2 4 [OP_LIST_EOL] 1 [OP_LIST_MAX] 4 [OP_LIST_MAX] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 8 0 3 7 5 2 4 [OP_LIST_EOL] 1 [OP_LIST_MAX] 4 [OP_LIST_MAX] [OP_SUB]",
        "solution_code_ko": "var_a = 8\nvar_b = 0\nvar_c = 3\nvar_d = 7\nvar_e = 5\nvar_f = 2\nvar_g = 4\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_i = list_b[-var_h]\nvar_j = 4\nlist_c=list_a.copy()\nlist_c.sort()\nvar_k = list_c[-var_j]\nvar_l = var_i - var_k\nprint(int(var_l))",
        "solution_code_en": "var_a = 8\nvar_b = 0\nvar_c = 3\nvar_d = 7\nvar_e = 5\nvar_f = 2\nvar_g = 4\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_i = list_b[-var_h]\nvar_j = 4\nlist_c=list_a.copy()\nlist_c.sort()\nvar_k = list_c[-var_j]\nvar_l = var_i - var_k\nprint(int(var_l))"
    },
    "2090": {
        "category": "Geometry",
        "question_ko": "넓이가 59.6제곱센티미터(㎠)인 직사각형을 4 등분하였습니다. 1등분의 넓이는 얼마입니까?",
        "question_en": "rectangle with an area of 59.6 square centimeters (cm2) is divided into 4 equal parts. What is the area of one part?",
        "answer_ko": "14.90",
        "answer_en": "14.9",
        "solution_abst_ko": "59.6 4 [OP_DIV]",
        "solution_abst_en": "59.6 4 [OP_DIV]",
        "solution_code_ko": "var_a = 59.6\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 59.6\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "2091": {
        "category": "Geometry",
        "question_ko": "어떤 마름모의 두 대각선의 길이가 4센티미터(㎝)라고 합니다. 이 마름모의 넓이를 구하시오.",
        "question_en": "Let the length of the two diagonals of a rhombus be 4 centimeters (cm). Find the area of this rhombus.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "4 4 [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "4 4 [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 4\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 4\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "2092": {
        "category": "Comparison",
        "question_ko": "수박 1개를 8명이 나눠 먹습니다. 수박이 4개 있으면 몇 명이 나눠 먹을 수 있나요?",
        "question_en": "Eight people will share one watermelon. If there are 4 watermelons, how many people can share them?",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "8 4 [OP_MUL]",
        "solution_abst_en": "8 4 [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 8\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "2093": {
        "category": "Arithmetic calculation",
        "question_ko": "40 이상 80 미만인 수 중에서 8의 배수에 해당되는 수는 모두 몇 개입니까?",
        "question_en": "How many numbers not less than 40 and less than 80 are multiples of 8?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "40 80 1 [OP_SUB] 1 [OP_LIST_ARANGE] 8 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "40 80 1 [OP_SUB] 1 [OP_LIST_ARANGE] 8 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 40\nvar_b = 80\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nvar_f = 8\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 40\nvar_b = 80\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nvar_f = 8\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "2094": {
        "category": "Comparison",
        "question_ko": "학생들이 정국, 민형, 태형 순으로 줄을 섰습니다. 3번째에 줄을 선 사람은 누구인가요?",
        "question_en": "The students are lined up in the order of Jungkook, Minyoung, and Taehyung. Who is the third person in line?",
        "answer_ko": "태형",
        "answer_en": "Taehyung",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 민형 태형 [OP_LIST_EOL] 3 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Minyoung Taehyung [OP_LIST_EOL] 3 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '민형'\nvar_c = '태형'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nvar_e = list_a[var_d-1]\nprint(var_e)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Minyoung'\nvar_c = 'Taehyung'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nvar_e = list_a[var_d-1]\nprint(var_e)"
    },
    "2095": {
        "category": "Comparison",
        "question_ko": "학생들이 한 줄로 서 있습니다. 나경이는 앞에서 5번째에 서 있고 가장 마지막 사람입니다. 줄을 서 있는 학생은 모두 몇 명입니까?",
        "question_en": "Students stand in a line. Nakyung takes the 5th from the front and is the last person. How many students are in line?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "5 1 [OP_ADD]",
        "solution_abst_en": "5 1 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "2096": {
        "category": "Correspondence",
        "question_ko": "20에 어떤 수를 빼려고 합니다. 잘못하여 40에 어떤 수를 더했더니 결과는 52가 되었습니다. 바르게 계산한 결과는 얼마일까요?",
        "question_en": "I want to subtract this number from 20. I mistakenly added this number to 40, and the result was 52. What is the result of the correct calculation?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "20 52 40 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "20 52 40 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 52\nvar_c = 40\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 52\nvar_c = 40\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "2097": {
        "category": "Arithmetic calculation",
        "question_ko": "닭 45마리를 키우는 농장에 첫번째 날 닭 18마리를 더 사오고, 두번째 날에는 12마리의 닭을 더 사왔다. 처음에 키우던 닭보다 몇 마리의 닭이 늘었는지 구하시오.",
        "question_en": "You brought 18 more chickens on the first day and 12 more chickens on the second day to the farm, which originally raised 45 chickens. Find the number of increased chickens since the beginning.",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "18 12 [OP_ADD]",
        "solution_abst_en": "18 12 [OP_ADD]",
        "solution_code_ko": "var_a = 18\nvar_b = 12\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 18\nvar_b = 12\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "2098": {
        "category": "Geometry",
        "question_ko": "(가), (나), (다)는 모두 각뿔입니다. 세 각뿔의 꼭짓점의 수의 합이 40일때 세 각뿔의 모서리의 수의 합은 모두 몇 개입니까?",
        "question_en": "(a), (b), and (c) are all pyramids. If the sum of the vertices of the three pyramids is 40, what is the sum of the edges of the three pyramids?",
        "answer_ko": "74",
        "answer_en": "74",
        "solution_abst_ko": "40 3 [OP_SUB] 2 [OP_MUL]",
        "solution_abst_en": "40 3 [OP_SUB] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 40\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 40\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "2099": {
        "category": "Arithmetic calculation",
        "question_ko": "현주는 일주일에 평균 7000원씩 저금을 한다. 현주가 계속 저금하여 100000원을 모으려면 몇 주가 걸리겠는가?",
        "question_en": "Hyeon-joo saves an average of 7,000 won a week. How many weeks will it take for Hyeon-Joo to save 100,000 won?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "100000 7000 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "100000 7000 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 100000\nvar_b = 7000\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))",
        "solution_code_en": "var_a = 100000\nvar_b = 7000\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))"
    },
    "2100": {
        "category": "Possibility",
        "question_ko": "주어진 숫자 카드 7, 5, 2를 한 번 사용하여 520보다 크고 710보다 작은 수를 만들 때 백의 자리에 들어갈 수 있는 수를 쓰십시오.",
        "question_en": "Write the number that can fit in the hundredth place when using the given number cards 7, 5, and 2 once to make a number greater than 520 and less than 710.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "[OP_LIST_SOL] 7 5 2 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 520 [OP_LIST_MORE] 710 [OP_LIST_LESS] 1 [OP_LIST_GET] [OP_NUM2LIST] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] 7 5 2 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 520 [OP_LIST_MORE] 710 [OP_LIST_LESS] 1 [OP_LIST_GET] [OP_NUM2LIST] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 7\nvar_b = 5\nvar_c = 2\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 520\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = 710\nlist_d = []\nfor i in list_c:\n    if i < var_f:\n        list_d.append(i)\nvar_g = 1\nvar_h = list_d[var_g-1]\nlist_e = []\nvar_h = int(var_h)\nwhile var_h//10 > 0:\n    list_e.append(var_h%10)\n    var_h = var_h//10\nlist_e.append(var_h%10)\nlist_e = list_e[::-1]\nvar_i = 1\nvar_j = list_e[var_i-1]\nprint(int(var_j))",
        "solution_code_en": "var_a = 7\nvar_b = 5\nvar_c = 2\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 520\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = 710\nlist_d = []\nfor i in list_c:\n    if i < var_f:\n        list_d.append(i)\nvar_g = 1\nvar_h = list_d[var_g-1]\nlist_e = []\nvar_h = int(var_h)\nwhile var_h//10 > 0:\n    list_e.append(var_h%10)\n    var_h = var_h//10\nlist_e.append(var_h%10)\nlist_e = list_e[::-1]\nvar_i = 1\nvar_j = list_e[var_i-1]\nprint(int(var_j))"
    },
    "2101": {
        "category": "Comparison",
        "question_ko": "길이가 364 미터(m) 인 무밭과 배추밭이 있습니다. 무는 22.75 미터(m) 간격으로, 배추는 45.5 미터(m) 간격으로 각각 심어져 있을 때, 무와 배추 중 어느 것을 더 많이 심었는지 구하시오.",
        "question_en": "There is a radish field and a cabbage field with a length of 364 meters (m). When radishes are planted at intervals of 22.75 meters (m) and cabbages are planted at intervals of 45.5 meters (m), find out which of radishes and cabbages was planted more.",
        "answer_ko": "무",
        "answer_en": "radish",
        "solution_abst_ko": "[OP_LIST_SOL] 무 배추 [OP_LIST_EOL] [OP_LIST_SOL] 364 22.75 [OP_DIV] 364 45.5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] radish cabbage [OP_LIST_EOL] [OP_LIST_SOL] 364 22.75 [OP_DIV] 364 45.5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '무'\nvar_b = '배추'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 364\nvar_d = 22.75\nvar_e = var_c / var_d\nvar_f = 364\nvar_g = 45.5\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'radish'\nvar_b = 'cabbage'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 364\nvar_d = 22.75\nvar_e = var_c / var_d\nvar_f = 364\nvar_g = 45.5\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "2102": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 16센티미터(㎝)이고, 모든 변의 길이가 같은 도형의 둘레는 80센티미터(㎝)입니다. 이 도형은 총 몇 개의 변으로 이루어져 있습니까?",
        "question_en": "A figure with one side of 16 centimeters (cm) and all sides of the same length has a perimeter of 80 centimeters (cm). How many sides does this figure have?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "80 16 [OP_DIV]",
        "solution_abst_en": "80 16 [OP_DIV]",
        "solution_code_ko": "var_a = 80\nvar_b = 16\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 80\nvar_b = 16\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "2103": {
        "category": "Possibility",
        "question_ko": "영어, 수학, 국어 중 2개 과목을 골라서 공부하는 경우는 모두 몇 가지 입니까?",
        "question_en": "How many cases are there to choose and study two subjects among English, Mathematics, and Korean?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 영어 수학 국어 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] English Mathematics Korean [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '영어'\nvar_b = '수학'\nvar_c = '국어'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f / (i+1)\nprint(int(var_f))",
        "solution_code_en": "var_a = 'English'\nvar_b = 'Mathematics'\nvar_c = 'Korean'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f / (i+1)\nprint(int(var_f))"
    },
    "2104": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 가게에서 파는 연필이 5천원보다 2백원 쌀 때, 연필의 가격을 만원 단위로 구하시오.",
        "question_en": "If a pencil sold at a store is 200 won cheaper than 5,000 won, find the price of the pencil in units of 10,000 won.",
        "answer_ko": "0.48",
        "answer_en": "0.48",
        "solution_abst_ko": "5000 200 [OP_SUB] 10000 [OP_DIV]",
        "solution_abst_en": "5000 200 [OP_SUB] 10000 [OP_DIV]",
        "solution_code_ko": "var_a = 5000\nvar_b = 200\nvar_c = var_a - var_b\nvar_d = 10000\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 5000\nvar_b = 200\nvar_c = var_a - var_b\nvar_d = 10000\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "2105": {
        "category": "Comparison",
        "question_ko": "주차장에 세워진 아빠의 차의 양옆에는 각각 5, 6줄의 차들이 주차되어 있고, 앞뒤에는 각각 6, 7줄의 차들이 주차되어 있다면 각 줄마다 있는 자동차의 수가 같다고 할 때, 주차장에 세워진 차들은 모두 몇 대입니까?",
        "question_en": "There are 5 and 6 rows of cars parked on either side of the father's car in the parking lot, 6 and 7 rows of cars parked in the front and back. Assuming the number of cars in each row is the same, how many cars are in the parking lot?",
        "answer_ko": "168",
        "answer_en": "168",
        "solution_abst_ko": "5 6 [OP_ADD] 1 [OP_ADD] 6 7 [OP_ADD] 1 [OP_ADD] [OP_MUL]",
        "solution_abst_en": "5 6 [OP_ADD] 1 [OP_ADD] 6 7 [OP_ADD] 1 [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 6\nvar_g = 7\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h + var_i\nvar_k = var_e * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 5\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 6\nvar_g = 7\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h + var_i\nvar_k = var_e * var_j\nprint(int(var_k))"
    },
    "2106": {
        "category": "Arithmetic calculation",
        "question_ko": "3으로 나누어 떨어질 수 있는 두 자리 수는 모두 몇 개 있습니까?",
        "question_en": "How many two-digit numbers are divisible by 3?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "10 99 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "10 99 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "2107": {
        "category": "Arithmetic calculation",
        "question_ko": "학생들에게 사탕을 똑같이 나누어 주려고 하는데 모든 학생들에게 7개씩 나누어 주면 12개가 모자라고, 3개씩 나누어 주면 20개가 남는다고 한다. 학생 수를 A명, 사탕의 개수를 B개라 할 때, A+B의 값을 구하여라.",
        "question_en": "You want to divide candies equally among the students, but if you distribute 7 candies to all students, 12 candies are in short, and if you distribute 3 candies, 20 candies are left over. If the number of students is A and the number of candies is B, find the value of A+B.",
        "answer_ko": "52",
        "answer_en": "52",
        "solution_abst_ko": "20 12 [OP_ADD] 7 3 [OP_SUB] [OP_DIV] 7 [OP_MUL] 12 [OP_SUB] 20 12 [OP_ADD] 7 3 [OP_SUB] [OP_DIV] [OP_ADD]",
        "solution_abst_en": "20 12 [OP_ADD] 7 3 [OP_SUB] [OP_DIV] 7 [OP_MUL] 12 [OP_SUB] 20 12 [OP_ADD] 7 3 [OP_SUB] [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 20\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 7\nvar_e = 3\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 7\nvar_i = var_g * var_h\nvar_j = 12\nvar_k = var_i - var_j\nvar_l = 20\nvar_m = 12\nvar_n = var_l + var_m\nvar_o = 7\nvar_p = 3\nvar_q = var_o - var_p\nvar_r = var_n / var_q\nvar_s = var_k + var_r\nprint(int(var_s))",
        "solution_code_en": "var_a = 20\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 7\nvar_e = 3\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 7\nvar_i = var_g * var_h\nvar_j = 12\nvar_k = var_i - var_j\nvar_l = 20\nvar_m = 12\nvar_n = var_l + var_m\nvar_o = 7\nvar_p = 3\nvar_q = var_o - var_p\nvar_r = var_n / var_q\nvar_s = var_k + var_r\nprint(int(var_s))"
    },
    "2108": {
        "category": "Arithmetic calculation",
        "question_ko": "32의 약수들 중에서 8의 약수가 아닌 수들의 총합을 구하시오.",
        "question_en": "Find the sum of the aliquots of 32 that are not aliquots of 8.",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "32 [OP_LIST_GET_DIVISOR] 8 [OP_LIST_GET_DIVISOR] [OP_SET_DIFFERENCE] [OP_LIST_SUM]",
        "solution_abst_en": "32 [OP_LIST_GET_DIVISOR] 8 [OP_LIST_GET_DIVISOR] [OP_SET_DIFFERENCE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 32\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 8\nlist_b = []\nnum_sqrt = int(math.sqrt(var_b))\nfor i in range(1, num_sqrt+1):\n    if var_b % i == 0:\n        list_b.append(i)\n        list_b.append(int(var_b/i))\nlist_b = sorted(set(list_b))\nlist_c = list(set(list_a) - set(list_b))\nlist_c = [float(i) for i in list_c]\nvar_c = sum(list_c)\nprint(int(var_c))",
        "solution_code_en": "var_a = 32\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 8\nlist_b = []\nnum_sqrt = int(math.sqrt(var_b))\nfor i in range(1, num_sqrt+1):\n    if var_b % i == 0:\n        list_b.append(i)\n        list_b.append(int(var_b/i))\nlist_b = sorted(set(list_b))\nlist_c = list(set(list_a) - set(list_b))\nlist_c = [float(i) for i in list_c]\nvar_c = sum(list_c)\nprint(int(var_c))"
    },
    "2109": {
        "category": "Arithmetic calculation",
        "question_ko": "양팔 저울의 한 쪽에는 동화책 한 권을 올려두고, 다른 쪽에는 0.3킬로그램(㎏)짜리 인형 2개와 0.5킬로그램(㎏)짜리 장난감 자동차를 올려두었더니 수평이 되었습니다. 동화책은 한 권은 몇 킬로그램(㎏)일까요?",
        "question_en": "A children's book was placed on one side of the two-arm scale, and two 0.3 kilograms (kg) dolls and 0.5 kilograms (kg) toy cars were placed on the other side. How many kilograms (kg) is one children's book?",
        "answer_ko": "1.10",
        "answer_en": "1.1",
        "solution_abst_ko": "0.5 0.3 2 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "0.5 0.3 2 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 0.5\nvar_b = 0.3\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.5\nvar_b = 0.3\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "2110": {
        "category": "Geometry",
        "question_ko": "가로 10센티미터(㎝), 세로 8센티미터(㎝)인 직사각형과 둘레의 길이가 같은 정사각형이 있습니다. 이 정사각형의 한 변의 길이를 구하시오.",
        "question_en": "There is a rectangle with a length of 10 centimeters (cm) and a width of 8 centimeters (cm) and a square with the same perimeter. Find the length of one side of this square.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "10 8 [OP_ADD] 2 [OP_MUL] 4 [OP_DIV]",
        "solution_abst_en": "10 8 [OP_ADD] 2 [OP_MUL] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 10\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "2111": {
        "category": "Possibility",
        "question_ko": "0, 2, 4, 6 중에서 3개 뽑아 한 번씩만 사용하여 세 자리 수를 만들려고 합니다. 만들 수 있는 가장 큰 수와 가장 작은 수의 합을 구하시오.",
        "question_en": "You are about to make a three-digit number by selecting three from 0, 2, 4, and 6 and using them only once. What is the sum of the largest and smallest possible numbers.",
        "answer_ko": "846",
        "answer_en": "846",
        "solution_abst_ko": "[OP_LIST_SOL] 0 2 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 0 2 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 0\nvar_b = 2\nvar_c = 4\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 0\nvar_b = 2\nvar_c = 4\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))"
    },
    "2112": {
        "category": "Arithmetic calculation",
        "question_ko": "숫자 4, 6, 7, 14의 곱은 얼마입니까?",
        "question_en": "What is the product of the numbers 4, 6, 7, and 14?",
        "answer_ko": "2352",
        "answer_en": "2352",
        "solution_abst_ko": "4 6 [OP_MUL] 7 [OP_MUL] 14 [OP_MUL]",
        "solution_abst_en": "4 6 [OP_MUL] 7 [OP_MUL] 14 [OP_MUL]",
        "solution_code_ko": "var_a = 4\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c * var_d\nvar_f = 14\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c * var_d\nvar_f = 14\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "2113": {
        "category": "Correspondence",
        "question_ko": "42A3을 반올림하여 백의 자리까지 나타내면 4300이 됩니다. 가능한 A는 모두 몇 개입니까?",
        "question_en": "Rounding 42A3 to the hundreds place makes it 4300. How many possible A's are there?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "42A3 [OP_GEN_POSSIBLE_LIST] 4300 50 [OP_SUB] [OP_LIST_MORE_EQUAL] 4300 50 [OP_ADD] [OP_LIST_LESS] 42A3 A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_abst_en": "42A3 [OP_GEN_POSSIBLE_LIST] 4300 50 [OP_SUB] [OP_LIST_MORE_EQUAL] 4300 50 [OP_ADD] [OP_LIST_LESS] 42A3 A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '42A3'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 4300\nvar_c = 50\nvar_d = var_b - var_c\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nvar_e = 4300\nvar_f = 50\nvar_g = var_e + var_f\nlist_c = []\nfor i in list_b:\n    if i < var_g:\n        list_c.append(i)\nvar_h = '42A3'\nvar_i = 'A'\nvar_h = str(var_h)\nvar_i = str(var_i)\nunk_idx = var_h.index(var_i)\nlist_d = []\nfor elem in list_c:\n    elem = str(elem)\n    list_d.append(int(elem[unk_idx]))\nlist_d = list(set(list_d))\nvar_j = len(list_d)\nprint(int(var_j))",
        "solution_code_en": "var_a = '42A3'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 4300\nvar_c = 50\nvar_d = var_b - var_c\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nvar_e = 4300\nvar_f = 50\nvar_g = var_e + var_f\nlist_c = []\nfor i in list_b:\n    if i < var_g:\n        list_c.append(i)\nvar_h = '42A3'\nvar_i = 'A'\nvar_h = str(var_h)\nvar_i = str(var_i)\nunk_idx = var_h.index(var_i)\nlist_d = []\nfor elem in list_c:\n    elem = str(elem)\n    list_d.append(int(elem[unk_idx]))\nlist_d = list(set(list_d))\nvar_j = len(list_d)\nprint(int(var_j))"
    },
    "2114": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 6으로 나누면 4가 남고 8로 나누면 6이 남고 10으로 나누면 8이 남는다. 이러한 수 중 가장 작은 수를 구하시오.",
        "question_en": "Dividing a number by 6 gives a remainder of 4, dividing a number by 8 leaves a remainder of 6, and dividing a number by 10 leaves a remainder of 8. Find the smallest number that satisfies the above condition.",
        "answer_ko": "118",
        "answer_en": "118",
        "solution_abst_ko": "0 9999 1 [OP_LIST_ARANGE] 6 4 [OP_LIST_DIVIDE_AND_REMAIN] 8 6 [OP_LIST_DIVIDE_AND_REMAIN] 10 8 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MIN]",
        "solution_abst_en": "0 9999 1 [OP_LIST_ARANGE] 6 4 [OP_LIST_DIVIDE_AND_REMAIN] 8 6 [OP_LIST_DIVIDE_AND_REMAIN] 10 8 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 0\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nvar_e = 4\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 8\nvar_g = 6\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 10\nvar_i = 8\nlist_d = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_c:\n    i = int(i)\n    if i%var_h == var_i:\n        list_d.append(i)\nvar_j = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_k = list_e[var_j-1]\nprint(int(var_k))",
        "solution_code_en": "var_a = 0\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nvar_e = 4\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 8\nvar_g = 6\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 10\nvar_i = 8\nlist_d = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_c:\n    i = int(i)\n    if i%var_h == var_i:\n        list_d.append(i)\nvar_j = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_k = list_e[var_j-1]\nprint(int(var_k))"
    },
    "2115": {
        "category": "Arithmetic calculation",
        "question_ko": "한 변의 길이가 12 센티미터(㎝)인 정사각형이 있다. 이 정사각형의 가로의 길이를 3 센티미터(㎝)만큼 늘이고, 세로의 길이를 A 센티미터(㎝)만큼 줄여서 만든 직사각형의 넓이가 120제곱센티미터(㎠)일 때, A의 값을 구하시오.",
        "question_en": "There is a square with a side length of 12 centimeters (cm). If the area of the new rectangle made by increasing the horizontal length of this square by 3 centimeters (cm) and reducing the vertical length by A centimeters (cm) is 120 square cm (cm2), find the value of A.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "12 120 12 3 [OP_ADD] [OP_DIV] [OP_SUB]",
        "solution_abst_en": "12 120 12 3 [OP_ADD] [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 12\nvar_b = 120\nvar_c = 12\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = var_b / var_e\nvar_g = var_a - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 12\nvar_b = 120\nvar_c = 12\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = var_b / var_e\nvar_g = var_a - var_f\nprint(int(var_g))"
    },
    "2116": {
        "category": "Arithmetic calculation",
        "question_ko": "200개짜리 상자와 150개짜리 상자가 총 12개 있습니다. 2180개의 사과를 이 상자에 나누어 담았더니 30개가 남았습니다. 200개짜리 상자는 몇 상자인가요?",
        "question_en": "There are 12 crates of 200 and 150 in total. When 2180 apples were divided into these boxes, leaving 30 apples. How many boxes of 200 are there?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "2180 30 [OP_SUB] 150 12 [OP_MUL] [OP_SUB] 200 150 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "2180 30 [OP_SUB] 150 12 [OP_MUL] [OP_SUB] 200 150 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 2180\nvar_b = 30\nvar_c = var_a - var_b\nvar_d = 150\nvar_e = 12\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 200\nvar_i = 150\nvar_j = var_h - var_i\nvar_k = var_g / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 2180\nvar_b = 30\nvar_c = var_a - var_b\nvar_d = 150\nvar_e = 12\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 200\nvar_i = 150\nvar_j = var_h - var_i\nvar_k = var_g / var_j\nprint(int(var_k))"
    },
    "2117": {
        "category": "Comparison",
        "question_ko": "윤기는 4개, 정국이는 6에 3을 합1개수의 사과를 가지고 있습니다. 누가 더 사과를 많이 가지고 있습니까?",
        "question_en": "Yoongi has 4 apples and Jungkook has 6 plus 3 apples. Who has more apples?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 6\nvar_e = 3\nvar_f = var_d + var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 6\nvar_e = 3\nvar_f = var_d + var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "2118": {
        "category": "Arithmetic calculation",
        "question_ko": "태수는 161쪽짜리 동화책을 일주일 동안 읽었습니다. 하루에 평균 몇 쪽을 읽었는가?",
        "question_en": "Taesoo read a 161-page storybook for a week. How many pages did he read on average per day?",
        "answer_ko": "23",
        "answer_en": "23",
        "solution_abst_ko": "161 7 [OP_DIV]",
        "solution_abst_en": "161 7 [OP_DIV]",
        "solution_code_ko": "var_a = 161\nvar_b = 7\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 161\nvar_b = 7\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "2119": {
        "category": "Correspondence",
        "question_ko": "68A+3=691일 때, A를 구하시오.",
        "question_en": "When 68A+3=691, find what A is.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "68A+3=691 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "68A+3=691 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '68A+3=691'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '68A+3=691'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "2120": {
        "category": "Comparison",
        "question_ko": "(가), (나), (다), (라), (마) 5개의 상자가 있습니다. (나) 상자는 (다) 상자보다 크고 (마) 상자보다 작습니다. (가) 상자는 (라) 상자보다 작습니다. (가) 상자는 (마) 상자보다 큽니다. 가장 큰 상자는 어느 상자입니까?",
        "question_en": "There are 5 boxes A, B, C, D, and E. Box B is larger than box C and smaller than box E. Box A is smaller than box D. Box A is larger than box E. Which box is the largest?",
        "answer_ko": "(라)",
        "answer_en": "D",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) (다) (라) (마) [OP_LIST_EOL] [OP_LIST_SOL] (나) (다) > (나) (마) < (가) (라) < (가) (마) > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D E [OP_LIST_EOL] [OP_LIST_SOL] B C > B E < A D < A E > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nvar_c = '(다)'\nvar_d = '(라)'\nvar_e = '(마)'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = '(나)'\nvar_g = '(다)'\nvar_h = '>'\nvar_i = '(나)'\nvar_j = '(마)'\nvar_k = '<'\nvar_l = '(가)'\nvar_m = '(라)'\nvar_n = '<'\nvar_o = '(가)'\nvar_p = '(마)'\nvar_q = '>'\nlist_b= []\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_r = 1\nvar_s = list_c[var_r-1]\nprint(var_s)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 'B'\nvar_g = 'C'\nvar_h = '>'\nvar_i = 'B'\nvar_j = 'E'\nvar_k = '<'\nvar_l = 'A'\nvar_m = 'D'\nvar_n = '<'\nvar_o = 'A'\nvar_p = 'E'\nvar_q = '>'\nlist_b= []\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_r = 1\nvar_s = list_c[var_r-1]\nprint(var_s)"
    },
    "2121": {
        "category": "Comparison",
        "question_ko": "2.23, 3.12, 9.434, 2.453을 작은 순서대로 늘어 놓았습니다. 첫 번째로 올 수는 무엇입니까?",
        "question_en": "The numbers 2.23, 3.12, 9.434, and 2.453 are placed in ascending order. What should come first?",
        "answer_ko": "2.23",
        "answer_en": "2.23",
        "solution_abst_ko": "[OP_LIST_SOL] 2.23 3.12 9.434 2.453 [OP_LIST_EOL] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 2.23 3.12 9.434 2.453 [OP_LIST_EOL] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 2.23\nvar_b = 3.12\nvar_c = 9.434\nvar_d = 2.453\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nprint('{:.2f}'.format(round(var_f+1e-10,2)))",
        "solution_code_en": "var_a = 2.23\nvar_b = 3.12\nvar_c = 9.434\nvar_d = 2.453\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nprint('{:.2f}'.format(round(var_f+1e-10,2)))"
    },
    "2122": {
        "category": "Arithmetic calculation",
        "question_ko": "등산 할 때 오르는 속도는 시속 15킬로미터(㎞)였고 내려가는 속도는 시속 10킬로미터(㎞)였다. 두 시간의 차이가 30분이 났다면, 산을 내려갈 때 걸린 시간은 얼마인가?",
        "question_en": "The climbing speed was 15 kilometers (km) per hour and the descending speed was 10 kilometers (km) per hour. If the difference between the two times is 30 minutes, how hours did it take to go down the mountain?",
        "answer_ko": "1.50",
        "answer_en": "1.5",
        "solution_abst_ko": "10 30 60 [OP_DIV] [OP_MUL] 15 10 [OP_SUB] [OP_DIV] 30 60 [OP_DIV] [OP_ADD]",
        "solution_abst_en": "10 30 60 [OP_DIV] [OP_MUL] 15 10 [OP_SUB] [OP_DIV] 30 60 [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 30\nvar_c = 60\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 15\nvar_g = 10\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 30\nvar_k = 60\nvar_l = var_j / var_k\nvar_m = var_i + var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))",
        "solution_code_en": "var_a = 10\nvar_b = 30\nvar_c = 60\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 15\nvar_g = 10\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 30\nvar_k = 60\nvar_l = var_j / var_k\nvar_m = var_i + var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))"
    },
    "2123": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 7/5을 빼어야 할 것을 잘못하여 더했더니 81/20이 되었습니다. 바르게 계산한 값을 구하시오.",
        "question_en": "You add 7/5 to a number by mistake instead of taking it away, and you get 81/20. Find the value correctly calculated.",
        "answer_ko": "1.25",
        "answer_en": "1.25",
        "solution_abst_ko": "81/20 7/5 [OP_SUB] 7/5 [OP_SUB]",
        "solution_abst_en": "81/20 7/5 [OP_SUB] 7/5 [OP_SUB]",
        "solution_code_ko": "var_a = 4.05\nvar_b = 1.4\nvar_c = var_a - var_b\nvar_d = 1.4\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 4.05\nvar_b = 1.4\nvar_c = var_a - var_b\nvar_d = 1.4\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "2124": {
        "category": "Correspondence",
        "question_ko": "0.46 에 어떤 수를 두 번 더했더니 0.72 가 되었습니다. 어떤 수는 얼마입니까?",
        "question_en": "If you add a number twice to 0.46, you get 0.72. What number is it?",
        "answer_ko": "0.20",
        "answer_en": "0.2",
        "solution_abst_ko": "0.72 0.46 [OP_SUB] 0.46 [OP_SUB]",
        "solution_abst_en": "0.72 0.46 [OP_SUB] 0.46 [OP_SUB]",
        "solution_code_ko": "var_a = 0.72\nvar_b = 0.46\nvar_c = var_a - var_b\nvar_d = 0.46\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.72\nvar_b = 0.46\nvar_c = var_a - var_b\nvar_d = 0.46\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "2125": {
        "category": "Correspondence",
        "question_ko": "3A1+2B=327이 성립합니다. B는 무엇인가요?",
        "question_en": "3A1+2B=327. What is B?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "3A1+2B=327 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "3A1+2B=327 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '3A1+2B=327'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '3A1+2B=327'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "2126": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 19를 빼고 27을 더해야 하는데 잘못하여 27을 빼고 19를 더했더니 84가 되었습니다. 바르게 계산한 결과를 구하시오.",
        "question_en": "You had to subtract 19 from a certain number and add 27 but you accidentally subtract 27 and add 19 and you get 84. Find the correct result.",
        "answer_ko": "100",
        "answer_en": "100",
        "solution_abst_ko": "84 19 [OP_SUB] 27 [OP_ADD] 19 [OP_SUB] 27 [OP_ADD]",
        "solution_abst_en": "84 19 [OP_SUB] 27 [OP_ADD] 19 [OP_SUB] 27 [OP_ADD]",
        "solution_code_ko": "var_a = 84\nvar_b = 19\nvar_c = var_a - var_b\nvar_d = 27\nvar_e = var_c + var_d\nvar_f = 19\nvar_g = var_e - var_f\nvar_h = 27\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 84\nvar_b = 19\nvar_c = var_a - var_b\nvar_d = 27\nvar_e = var_c + var_d\nvar_f = 19\nvar_g = var_e - var_f\nvar_h = 27\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "2127": {
        "category": "Correspondence",
        "question_ko": "백의 자리 수가 5, 십의 자리 수가 A, 일의 자리 수가 5인 세 자리 수가 있습니다. 이 수를 십의 자리에서 버림하면 500이 됩니다. A가 한 자리 수일 때 A에 쓸 수 있는 수들의 합을 구하시오.",
        "question_en": "There is a three-digit number that has a hundreds digit of 5, a tens digit of A, and a ones digit of 5. If we round down this number to the tens place, we get 500. If A is a single digit number, find the sum of the numbers that can be written for A.",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "[OP_LIST_SOL] 5 A 5 [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 600 [OP_LIST_LESS_EQUAL] A [OP_LIST_FIND_UNK] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 5 A 5 [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 600 [OP_LIST_LESS_EQUAL] A [OP_LIST_FIND_UNK] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 5\nvar_b = 'A'\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nans_dict = dict()\nvar_d = str(var_d)\nlist_b = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_d) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_b.append(new_elem)\nvar_e = 600\nlist_c = []\nfor i in list_b:\n    if i <= var_e:\n        list_c.append(i)\nvar_f = 'A'\nvar_d = str(var_d)\nvar_f = str(var_f)\nunk_idx = var_d.index(var_f)\nlist_d = []\nfor elem in list_c:\n    elem = str(elem)\n    list_d.append(int(elem[unk_idx]))\nlist_d = list(set(list_d))\nlist_d = [float(i) for i in list_d]\nvar_g = sum(list_d)\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 'A'\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nans_dict = dict()\nvar_d = str(var_d)\nlist_b = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_d) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_b.append(new_elem)\nvar_e = 600\nlist_c = []\nfor i in list_b:\n    if i <= var_e:\n        list_c.append(i)\nvar_f = 'A'\nvar_d = str(var_d)\nvar_f = str(var_f)\nunk_idx = var_d.index(var_f)\nlist_d = []\nfor elem in list_c:\n    elem = str(elem)\n    list_d.append(int(elem[unk_idx]))\nlist_d = list(set(list_d))\nlist_d = [float(i) for i in list_d]\nvar_g = sum(list_d)\nprint(int(var_g))"
    },
    "2128": {
        "category": "Geometry",
        "question_ko": "길이가 78센티미터(㎝)인 철사로 만들 수 있는 가장 큰 정삼각형의 한 변은 몇 센티미터(㎝)입니까?",
        "question_en": "How many centimeters (cm) is the side of the largest equilateral triangle that can be made with a wire of 78 centimeters (cm)?",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "78 3 [OP_DIV]",
        "solution_abst_en": "78 3 [OP_DIV]",
        "solution_code_ko": "var_a = 78\nvar_b = 3\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 78\nvar_b = 3\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "2129": {
        "category": "Correspondence",
        "question_ko": "진호는 첫 번째 가게에서 가지고 있던 돈의 절반과 300원을 쓰고, 두 번째 가게에서 남은 돈의 절반과 400원을 썼더니 남은 돈이 없었습니다. 진호가 처음에 가지고 있던 돈은 얼마인지 구하시오.",
        "question_en": "Jinho spent half of his money and 300 won at the first store, then half of his money and 400 won at the second store, and he had no money left. Find how much money Jinho had at the beginning.",
        "answer_ko": "2200",
        "answer_en": "2200",
        "solution_abst_ko": "0 400 [OP_ADD] 1 1/2 [OP_SUB] [OP_DIV] 300 [OP_ADD] 1 1/2 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "0 400 [OP_ADD] 1 1/2 [OP_SUB] [OP_DIV] 300 [OP_ADD] 1 1/2 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 0\nvar_b = 400\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 0.5\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 300\nvar_i = var_g + var_h\nvar_j = 1\nvar_k = 0.5\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 0\nvar_b = 400\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 0.5\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 300\nvar_i = var_g + var_h\nvar_j = 1\nvar_k = 0.5\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nprint(int(var_m))"
    },
    "2130": {
        "category": "Comparison",
        "question_ko": "(가)는 한 모서리의 길이가 7센티미터(㎝)인 정육면체이고, (나)는 한 모서리의 길이가 11센티미터(㎝)인 정육면체이고, (다)는 한 모서리의 길이가 9센티미터(㎝)인 정육면체입니다. (가), (나), (다) 중 겉넓이가 가장 넓은 정육면체는 어느 것입니까?",
        "question_en": "(A) is a cube with an edge length of 7 centimeters (cm), (B) is a cube with an edge length of 11 centimeters (cm), and (C) is a cube with an edge length of 9 centimeters (cm). Which cube has the largest surface area among (A), (B), and (C)?",
        "answer_ko": "(나)",
        "answer_en": "(B)",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) (다) [OP_LIST_EOL] [OP_LIST_SOL] 6 7 2 [OP_POW] [OP_MUL] 6 11 2 [OP_POW] [OP_MUL] 6 9 2 [OP_POW] [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (A) (B) (C) [OP_LIST_EOL] [OP_LIST_SOL] 6 7 2 [OP_POW] [OP_MUL] 6 11 2 [OP_POW] [OP_MUL] 6 9 2 [OP_POW] [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nvar_c = '(다)'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 6\nvar_e = 7\nvar_f = 2\nvar_g = var_e ** var_f\nvar_h = var_d * var_g\nvar_i = 6\nvar_j = 11\nvar_k = 2\nvar_l = var_j ** var_k\nvar_m = var_i * var_l\nvar_n = 6\nvar_o = 9\nvar_p = 2\nvar_q = var_o ** var_p\nvar_r = var_n * var_q\nlist_b= []\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nlist_b.reverse()\nvar_s = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_t = list_c[-var_s]\nvar_u = list_b.index(var_t)+1\nvar_v = list_a[var_u-1]\nprint(var_v)",
        "solution_code_en": "var_a = '(A)'\nvar_b = '(B)'\nvar_c = '(C)'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 6\nvar_e = 7\nvar_f = 2\nvar_g = var_e ** var_f\nvar_h = var_d * var_g\nvar_i = 6\nvar_j = 11\nvar_k = 2\nvar_l = var_j ** var_k\nvar_m = var_i * var_l\nvar_n = 6\nvar_o = 9\nvar_p = 2\nvar_q = var_o ** var_p\nvar_r = var_n * var_q\nlist_b= []\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nlist_b.reverse()\nvar_s = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_t = list_c[-var_s]\nvar_u = list_b.index(var_t)+1\nvar_v = list_a[var_u-1]\nprint(var_v)"
    },
    "2131": {
        "category": "Correspondence",
        "question_ko": "A는 한 자리 수입니다. 두 자리 수끼리의 곱셈식 AA×AA=5929에서 A를 구하시오.",
        "question_en": "A is a single digit number. Find A from the multiplication formula AA×AA=5929 between two digit numbers.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "AA×AA=5929 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "AA×AA=5929 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'AA×AA=5929'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'AA×AA=5929'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "2132": {
        "category": "Correspondence",
        "question_ko": "과자가게에 있는 한 선물세트에 초콜릿과 사탕이 동시에 들어간다. 초콜릿은 69개이고 사탕은 86개이다. 초콜릿과 사탕을 선물세트에 동일하게 나누어 담았을때 초콜릿은 5개가 남고 사탕은 6개가 남는다. 최대로 만들 수 있는 선물세트의 개수는 몇 개인지 구하시오.",
        "question_en": "Chocolate and candies go into a gift set at a confectionery store at the same time. Chocolate is 69 pieces and candy is 86 pieces. When chocolates and candies are divided equally into a gift set, there are 5 chocolates left and 6 candies left. Find the maximum number of gift sets that can be made.",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "69 5 [OP_SUB] 86 6 [OP_SUB] [OP_GCD]",
        "solution_abst_en": "69 5 [OP_SUB] 86 6 [OP_SUB] [OP_GCD]",
        "solution_code_ko": "var_a = 69\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 86\nvar_e = 6\nvar_f = var_d - var_e\nvar_g = math.gcd(int(var_f), int(var_c))\nprint(int(var_g))",
        "solution_code_en": "var_a = 69\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 86\nvar_e = 6\nvar_f = var_d - var_e\nvar_g = math.gcd(int(var_f), int(var_c))\nprint(int(var_g))"
    },
    "2133": {
        "category": "Comparison",
        "question_ko": "1000개의 사과를 영식씨와 민기씨가 나눠 가졌습니다. 영식씨는 민기씨보다 50개를 더 많이 가져갔고, 민기씨는 사과를 가지고 가던 중 노기씨를 만나 사과를 나누어 주었습니다. 민기씨의 사과가 노기씨의 사과보다 35개 더 많았습니다. 민기씨가 자신의 사과를 17개의 박스에 넣어 팔려고 할 때, 한 박스에 들어간 사과는 몇 개입니까?",
        "question_en": "Youngsik and Mingi shared 1000 apples. Youngsik took 50 more than Mingi, and while Mingi was carrying apples, he met Nogi and shared them with him. Mingi's apples were 35 more than Nogi's. If Mingi wants to sell her apples in 17 boxes, how many apples are in one box?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "1000 50 [OP_SUB] 2 [OP_DIV] 35 [OP_SUB] 2 [OP_DIV] 35 [OP_ADD] 17 [OP_DIV]",
        "solution_abst_en": "1000 50 [OP_SUB] 2 [OP_DIV] 35 [OP_SUB] 2 [OP_DIV] 35 [OP_ADD] 17 [OP_DIV]",
        "solution_code_ko": "var_a = 1000\nvar_b = 50\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 35\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nvar_j = 35\nvar_k = var_i + var_j\nvar_l = 17\nvar_m = var_k / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 1000\nvar_b = 50\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 35\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nvar_j = 35\nvar_k = var_i + var_j\nvar_l = 17\nvar_m = var_k / var_l\nprint(int(var_m))"
    },
    "2134": {
        "category": "Arithmetic calculation",
        "question_ko": "이번 주 복권 당첨 번호는 11, 25, 42, 15, 28, 39이다. 이 중 가장 큰 수와 두 번째로 큰 수의 차를 구하시오.",
        "question_en": "The lottery winning numbers for this week are 11, 25, 42, 15, 28, and 39. Find the difference between the largest number and the second largest number.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 11 25 42 15 28 39 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 11 25 42 15 28 39 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_SUB]",
        "solution_code_ko": "var_a = 11\nvar_b = 25\nvar_c = 42\nvar_d = 15\nvar_e = 28\nvar_f = 39\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_h = list_b[-var_g]\nvar_i = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = var_h - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 11\nvar_b = 25\nvar_c = 42\nvar_d = 15\nvar_e = 28\nvar_f = 39\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_h = list_b[-var_g]\nvar_i = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = var_h - var_j\nprint(int(var_k))"
    },
    "2135": {
        "category": "Comparison",
        "question_ko": "초아는 1.1미터(m)를 점프할 수 있고, 정아는 20/22미터(m)를 점프할 수 있습니다. 누가 더 높이 점프할 수 있습니까?",
        "question_en": "Choa can jump 1.1 meters (m), and Junga can jump 20/22 meters (m). Who can jump higher?",
        "answer_ko": "초아",
        "answer_en": "Choa",
        "solution_abst_ko": "[OP_LIST_SOL] 초아 정아 [OP_LIST_EOL] [OP_LIST_SOL] 1.1 20/22 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Choa Junga [OP_LIST_EOL] [OP_LIST_SOL] 1.1 20/22 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '초아'\nvar_b = '정아'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.1\nvar_d = 0.9090909090909091\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Choa'\nvar_b = 'Junga'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.1\nvar_d = 0.9090909090909091\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "2136": {
        "category": "Possibility",
        "question_ko": "5명이 서로 한번씩 악수를 한다고 할 때, 모두 몇 번의 악수를 하게 되는지 구하시오.",
        "question_en": "If 5 people shake each other's hands once, how many handshakes will they all do?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "5 2 [OP_COMB]",
        "solution_abst_en": "5 2 [OP_COMB]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))"
    },
    "2137": {
        "category": "Correspondence",
        "question_ko": "백의 자리 숫자가 3인 세 자리 수를 4로 나누면 나누어떨어집니다. 이런 세 자리 수는 모두 몇 개입니까?",
        "question_en": "A three-digit number with 3 in the hundreds is divisible when divided by 4. How many three-digit numbers that meet this condition are there? ",
        "answer_ko": "25",
        "answer_en": "25",
        "solution_abst_ko": "3 100 [OP_MUL] 3 100 [OP_MUL] 99 [OP_ADD] 1 [OP_LIST_ARANGE] 4 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "3 100 [OP_MUL] 3 100 [OP_MUL] 99 [OP_ADD] 1 [OP_LIST_ARANGE] 4 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 3\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = 100\nvar_f = var_d * var_e\nvar_g = 99\nvar_h = var_f + var_g\nvar_i = 1\nlist_a = [i for i in range(var_c, var_h + 1, var_i)]\nvar_j = 4\nlist_b = []\nvar_j = int(var_j)\nfor i in list_a:\n    i = int(i)\n    if i % var_j == 0:\n        list_b.append(i)\nvar_k = len(list_b)\nprint(int(var_k))",
        "solution_code_en": "var_a = 3\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = 100\nvar_f = var_d * var_e\nvar_g = 99\nvar_h = var_f + var_g\nvar_i = 1\nlist_a = [i for i in range(var_c, var_h + 1, var_i)]\nvar_j = 4\nlist_b = []\nvar_j = int(var_j)\nfor i in list_a:\n    i = int(i)\n    if i % var_j == 0:\n        list_b.append(i)\nvar_k = len(list_b)\nprint(int(var_k))"
    },
    "2138": {
        "category": "Comparison",
        "question_ko": "정국이는 줄넘기를 81번 했습니다. 유나는 줄넘기를 1번째와 2번째에 각각 26번씩 했습니다. 유나가 정국이보다 줄넘기를 더 많이 하려면 3번째에는 적어도 몇 번을 해야 합니까?",
        "question_en": "Jungkook did 81 jump ropes. Yuna did 26 jump ropes each in the first and second times. At least how many times should Yuna jump rope more than Jungkook in the third?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "81 26 26 [OP_ADD] [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "81 26 26 [OP_ADD] [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 81\nvar_b = 26\nvar_c = 26\nvar_d = var_b + var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 81\nvar_b = 26\nvar_c = 26\nvar_d = var_b + var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "2139": {
        "category": "Arithmetic calculation",
        "question_ko": "철사 4미터(m)로 모빌을 1개 만들 수 있습니다. 철사 117.6미터(m)로 같은 크기의 모빌을 여러개 만든 후 남은 철사는 몇 미터(m)입니까?",
        "question_en": "You can make one mobile with 4 meters (m) of wire. After making multiple mobiles of the same size with 117.6 meters (m) of wire, how many meters (m) of wire is left?",
        "answer_ko": "1.60",
        "answer_en": "1.6",
        "solution_abst_ko": "117.6 4 [OP_MOD]",
        "solution_abst_en": "117.6 4 [OP_MOD]",
        "solution_code_ko": "var_a = 117.6\nvar_b = 4\nvar_c = var_a % var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 117.6\nvar_b = 4\nvar_c = var_a % var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "2140": {
        "category": "Comparison",
        "question_ko": "진호가 가진 수는 1의 자리가 4, 0.1의 자리가 2, 0.01의 자리가 0, 0.001의 자리가 7입니다. 영희는 진호의 100배인 수를 가지고 있고, 정수는 영희보다 0.05 더 큰 수를 가지고 있습니다. 정수는 얼마의 수를 가지고 있습니까?",
        "question_en": "Jinho's number has 4 digits for 1, 2 digits for 0.1, 0.01 digits for 0, and 7 digits for 0.001. Younghee has a number that is 100 times as large as Jinho's, and the Jungsoo have a number that is 0.05 larger than Younghee's. What number does Jungsoo have?",
        "answer_ko": "420.75",
        "answer_en": "420.75",
        "solution_abst_ko": "1 4 [OP_MUL] 0.1 2 [OP_MUL] [OP_ADD] 0.001 7 [OP_MUL] [OP_ADD] 100 [OP_MUL] 0.05 [OP_ADD]",
        "solution_abst_en": "1 4 [OP_MUL] 0.1 2 [OP_MUL] [OP_ADD] 0.001 7 [OP_MUL] [OP_ADD] 100 [OP_MUL] 0.05 [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 0.1\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 0.001\nvar_i = 7\nvar_j = var_h * var_i\nvar_k = var_g + var_j\nvar_l = 100\nvar_m = var_k * var_l\nvar_n = 0.05\nvar_o = var_m + var_n\nprint('{:.2f}'.format(round(var_o+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 0.1\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 0.001\nvar_i = 7\nvar_j = var_h * var_i\nvar_k = var_g + var_j\nvar_l = 100\nvar_m = var_k * var_l\nvar_n = 0.05\nvar_o = var_m + var_n\nprint('{:.2f}'.format(round(var_o+1e-10,2)))"
    },
    "2141": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 4를 곱하였더니 166.08이 되었습니다. 어떤 수를 4로 나눈 뒤 0.48을 더한 값을 구하시오.",
        "question_en": "When you multiply a number by 4, you get 166.08. Divide a number by 4 and add 0.48 to find the value.",
        "answer_ko": "10.86",
        "answer_en": "10.86",
        "solution_abst_ko": "166.08 4 [OP_DIV] 4 [OP_DIV] 0.48 [OP_ADD]",
        "solution_abst_en": "166.08 4 [OP_DIV] 4 [OP_DIV] 0.48 [OP_ADD]",
        "solution_code_ko": "var_a = 166.08\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 0.48\nvar_g = var_e + var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 166.08\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 0.48\nvar_g = var_e + var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "2142": {
        "category": "Arithmetic calculation",
        "question_ko": "8으로 나누어 떨어질 수 있는 다섯 자리 수 중 가장 큰 수는?",
        "question_en": "What is the largest five-digit number divisible by 8?",
        "answer_ko": "99992",
        "answer_en": "99992",
        "solution_abst_ko": "10000 99999 1 [OP_LIST_ARANGE] 8 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_abst_en": "10000 99999 1 [OP_LIST_ARANGE] 8 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 10000\nvar_b = 99999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 8\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))",
        "solution_code_en": "var_a = 10000\nvar_b = 99999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 8\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))"
    },
    "2143": {
        "category": "Comparison",
        "question_ko": "유정이는 우유를 7/10리터(L) 마셨습니다. 은지는 우유를 0.5리터(L) 마셨습니다. 유나는 우유를 6/10리터(L) 마셨습니다. 우유를 가장 많이 마신 사람은 누구입니까?",
        "question_en": "Yoojeong drank 7/10 liters (L) of milk. Eunji drank 0.5 liters (L) of milk. Yuna drank 6/10 liters (L) of milk. Who drank the most milk?",
        "answer_ko": "유정",
        "answer_en": "Yoojeong",
        "solution_abst_ko": "[OP_LIST_SOL] 유정 은지 유나 [OP_LIST_EOL] [OP_LIST_SOL] 7 10 [OP_DIV] 0.5 6 10 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoojeong Eunji Yuna [OP_LIST_EOL] [OP_LIST_SOL] 7 10 [OP_DIV] 0.5 6 10 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '유정'\nvar_b = '은지'\nvar_c = '유나'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 7\nvar_e = 10\nvar_f = var_d / var_e\nvar_g = 0.5\nvar_h = 6\nvar_i = 10\nvar_j = var_h / var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'Yoojeong'\nvar_b = 'Eunji'\nvar_c = 'Yuna'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 7\nvar_e = 10\nvar_f = var_d / var_e\nvar_g = 0.5\nvar_h = 6\nvar_i = 10\nvar_j = var_h / var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "2144": {
        "category": "Possibility",
        "question_ko": "사과, 복숭아, 배, 참외, 딸기가 각각 하나씩 있는 바구니에서 2개를 뺐습니다. 선택된 과일의 경우의 수는 모두 몇 가지입니까?",
        "question_en": "Two fruits were taken out from a basket containing one apple, one peach, one pear, one melon, and a strawberry. How many ways are there for the selected fruit?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 복숭아 배 참외 딸기 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] apple peach pear melon strawberry [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '복숭아'\nvar_c = '배'\nvar_d = '참외'\nvar_e = '딸기'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h / (i+1)\nprint(int(var_h))",
        "solution_code_en": "var_a = 'apple'\nvar_b = 'peach'\nvar_c = 'pear'\nvar_d = 'melon'\nvar_e = 'strawberry'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h / (i+1)\nprint(int(var_h))"
    },
    "2145": {
        "category": "Arithmetic calculation",
        "question_ko": "민영이네 학교 5학년은 (가) 반이 30명, (나) 반이 27명, (다) 반이 28명입니다. 5학년 학생 모두에게 공책을 4권씩 나누어 주려고 합니다. 공책이 400권 있다면 5학년 학생들에게 나누어 주고 남은 공책은 몇 권인지 구하시오.",
        "question_en": "Minyoung's 5th graders have 30 students in class (a), 27 students in class (b), and 28 students in class (c). I'm going to give out 4 notebooks to every 5th grader. If there are 400 notebooks, find how many notebooks would be left after giving them to all 5th graders.",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "400 30 27 [OP_ADD] 28 [OP_ADD] 4 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "400 30 27 [OP_ADD] 28 [OP_ADD] 4 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 400\nvar_b = 30\nvar_c = 27\nvar_d = var_b + var_c\nvar_e = 28\nvar_f = var_d + var_e\nvar_g = 4\nvar_h = var_f * var_g\nvar_i = var_a - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 400\nvar_b = 30\nvar_c = 27\nvar_d = var_b + var_c\nvar_e = 28\nvar_f = var_d + var_e\nvar_g = 4\nvar_h = var_f * var_g\nvar_i = var_a - var_h\nprint(int(var_i))"
    },
    "2146": {
        "category": "Geometry",
        "question_ko": "정사각형 모양의 타일을 가로와 세로 모두 10장씩 빈틈없이 놓아서 큰 정사각형을 만들었습니다. 둘레에 놓인 타일은 파란색이고, 안쪽에 놓인 타일은 노란색일 때, 노란색 타일은 모두 몇 장입니까?",
        "question_en": "A large square was created by placing 10 square-shaped tiles, both horizontally and vertically, without gaps. If the tiles on the perimeter are blue and the tiles on the inside are yellow, how many yellow tiles are there?",
        "answer_ko": "64",
        "answer_en": "64",
        "solution_abst_ko": "10 2 [OP_SUB] 2 [OP_POW]",
        "solution_abst_en": "10 2 [OP_SUB] 2 [OP_POW]",
        "solution_code_ko": "var_a = 10\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint(int(var_e))"
    },
    "2147": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 먼저 8로 나눠주고, 다시 8만큼 더했습니다. 결과에 30을 빼고 6을 곱했더니 12가 되었다면, 어떤 수는 무엇입니까?",
        "question_en": "A number is first divided by 8, and then added by 8. When the result is subtracted by 30 and then multiplied by 6 to get 12, what is the number?",
        "answer_ko": "192",
        "answer_en": "192",
        "solution_abst_ko": "12 6 [OP_DIV] 30 [OP_ADD] 8 [OP_SUB] 8 [OP_MUL]",
        "solution_abst_en": "12 6 [OP_DIV] 30 [OP_ADD] 8 [OP_SUB] 8 [OP_MUL]",
        "solution_code_ko": "var_a = 12\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 30\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e - var_f\nvar_h = 8\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 12\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 30\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e - var_f\nvar_h = 8\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "2148": {
        "category": "Possibility",
        "question_ko": "1부터 5까지의 자연수가 각각 하나씩 적힌 노란색, 파란색, 빨간색 카드가 각각 5장씩 15장 있다. 이 15장의 카드에서 4장의 카드를 택할 때, 같은 숫자가 적힌 카드를 각각 2장씩 택하는 경우의 수는?",
        "question_en": "There are 15 cards, 5 each of yellow, blue, and red cards, representing a natural number from 1 to 5. If 4 cards are selected from 15 cards, in how many ways can 2 cards with the same number be selected?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "5 2 [OP_COMB] 3 2 [OP_COMB] [OP_MUL]",
        "solution_abst_en": "5 2 [OP_COMB] 3 2 [OP_COMB] [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nvar_d = 3\nvar_e = 2\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f / (i+1)\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nvar_d = 3\nvar_e = 2\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f / (i+1)\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "2149": {
        "category": "Arithmetic calculation",
        "question_ko": "올해 민영이는 7살입니다. 민영이 할머니는 민영이가 10살이 되는 해에 65살이 되십니다. 올해 할머니의 나이는 몇 살입니까?",
        "question_en": "Minyoung is 7 years old this year. When Minyoung's grandmother turns 65 in the year Minyoung turns 10, how old is her grandmother this year?",
        "answer_ko": "62",
        "answer_en": "62",
        "solution_abst_ko": "65 10 7 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "65 10 7 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 65\nvar_b = 10\nvar_c = 7\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 65\nvar_b = 10\nvar_c = 7\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "2150": {
        "category": "Correspondence",
        "question_ko": "A, B, C, D는 서로 다른 수입니다. 이 수들이 세 자리 수 덧셈식 7A4+B6C=D29를 만족할 때, D에 들어갈 수 있는 값은 무엇인지 구하시오.",
        "question_en": "A, B, C, and D are different numbers. When these numbers satisfy the three-digit addition equation 7A4+B6C=D29, find the value of D.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "7A4+B6C=D29 D [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "7A4+B6C=D29 D [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '7A4+B6C=D29'\nvar_b = 'D'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '7A4+B6C=D29'\nvar_b = 'D'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "2151": {
        "category": "Possibility",
        "question_ko": "2, 4, 6과 소수점을 한 번씩만 사용하여 6보다 작은 소수 두 자리 수를 모두 몇 개 만들 수 있습니까?",
        "question_en": "How many two decimal places less than 6 can you make by using 2, 4, 6 and the decimal point only once?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 2 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 6 10 3 1 [OP_SUB] [OP_POW] [OP_MUL] [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 2 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 6 10 3 1 [OP_SUB] [OP_POW] [OP_MUL] [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = 6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 6\nvar_f = 10\nvar_g = 3\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = var_f ** var_i\nvar_k = var_e * var_j\nlist_c = []\nfor i in list_b:\n    if i < var_k:\n        list_c.append(i)\nvar_l = len(list_c)\nprint(int(var_l))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = 6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 6\nvar_f = 10\nvar_g = 3\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = var_f ** var_i\nvar_k = var_e * var_j\nlist_c = []\nfor i in list_b:\n    if i < var_k:\n        list_c.append(i)\nvar_l = len(list_c)\nprint(int(var_l))"
    },
    "2152": {
        "category": "Comparison",
        "question_ko": "정국에는 6에서 3을 합한 수를 모았고, 윤기는 4를 모았습니다. 누가 더 큰 수를 가지고 있나요?",
        "question_en": "Jungkook collects number that adds 3 to 6, and Yoongi collects 4. Who has the bigger number?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 윤기 [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_ADD] 4 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Yoongi [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_ADD] 4 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '윤기'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = 4\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Yoongi'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = 4\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "2153": {
        "category": "Comparison",
        "question_ko": "2분동안 10바퀴 도는 바퀴 A와 1분 30초 동안 7바퀴를 도는 바퀴 B가 있습니다. 둘 중에 더 빠르게 돌아가는 바퀴는 무엇입니까?",
        "question_en": "Wheel A makes 10 revolutions in 2 minutes and Wheel B makes 7 revolutions in 1 minute 30 seconds. Which of the two wheels spins faster?",
        "answer_ko": "A",
        "answer_en": "A",
        "solution_abst_ko": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 10 2 60 [OP_MUL] [OP_DIV] 7 1 60 [OP_MUL] 30 [OP_ADD] [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 10 2 60 [OP_MUL] [OP_DIV] 7 1 60 [OP_MUL] 30 [OP_ADD] [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10\nvar_d = 2\nvar_e = 60\nvar_f = var_d * var_e\nvar_g = var_c / var_f\nvar_h = 7\nvar_i = 1\nvar_j = 60\nvar_k = var_i * var_j\nvar_l = 30\nvar_m = var_k + var_l\nvar_n = var_h / var_m\nlist_b= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_o = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_p = list_c[-var_o]\nvar_q = list_b.index(var_p)+1\nvar_r = list_a[var_q-1]\nprint(var_r)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10\nvar_d = 2\nvar_e = 60\nvar_f = var_d * var_e\nvar_g = var_c / var_f\nvar_h = 7\nvar_i = 1\nvar_j = 60\nvar_k = var_i * var_j\nvar_l = 30\nvar_m = var_k + var_l\nvar_n = var_h / var_m\nlist_b= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_o = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_p = list_c[-var_o]\nvar_q = list_b.index(var_p)+1\nvar_r = list_a[var_q-1]\nprint(var_r)"
    },
    "2154": {
        "category": "Geometry",
        "question_ko": "네 변의 길이가 같은 사각형의 넓이가 21.46제곱센티미터(㎠)라고 합니다. 이 사각형의 한 대각선의 길이가 7.4센티미터(㎝)라면, 다른 대각선은 몇 센티미터(㎝)이겠습니까?",
        "question_en": "The area of a quadrilateral whose all four sides are equal is 21.46 square centimeters (cm2). If the length of one diagonal of this rectangle is 7.4 centimeters (cm), how many centimeters (cm) is the other diagonal?",
        "answer_ko": "5.80",
        "answer_en": "5.8",
        "solution_abst_ko": "21.46 2 [OP_MUL] 7.4 [OP_DIV]",
        "solution_abst_en": "21.46 2 [OP_MUL] 7.4 [OP_DIV]",
        "solution_code_ko": "var_a = 21.46\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 7.4\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 21.46\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 7.4\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "2155": {
        "category": "Possibility",
        "question_ko": "4개의 구분되지 않은 구슬과 1개의 지우개가 있다. 이것들을 한 줄로 나열하는 방법은 몇 가지인가?",
        "question_en": "There are 4 indistinguishable marbles and 1 eraser. How many ways are there to list these on a single line?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "4 1 [OP_ADD] 4 [OP_COMB]",
        "solution_abst_en": "4 1 [OP_ADD] 4 [OP_COMB]",
        "solution_code_ko": "var_a = 4\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = 1\nvar_c = int(var_c)\nvar_d = int(var_d)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e * (var_c-i)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e / (i+1)\nprint(int(var_e))",
        "solution_code_en": "var_a = 4\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = 1\nvar_c = int(var_c)\nvar_d = int(var_d)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e * (var_c-i)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e / (i+1)\nprint(int(var_e))"
    },
    "2156": {
        "category": "Comparison",
        "question_ko": "키가 작은 사람부터 순서대로 9명이 한 줄로 서 있습니다. 호석이는 앞에서부터 2번째에 서 있고, 유나는 호석이 바로 뒤에 서 있습니다. 키가 큰 사람부터 순서대로 다시 줄을 서면 유나는 앞에서부터 몇 번째에 서게 됩니까?",
        "question_en": "Nine people are standing in a line in order from shortest to tallest. Hoseok is standing second from the front, and Yuna is standing right behind Hoseok. If you line up again in order of tallest to shortest, what number will Yuna stand in from the front?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "9 2 [OP_SUB] 1 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "9 2 [OP_SUB] 1 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 9\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 9\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "2157": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 6을 곱했더니 결과가 72가 되었습니다. 어떤 수에 8을 더하면?",
        "question_en": "When a number is multiplied by 6, the result is 72. What is the result when the number is added to 8?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "72 6 [OP_DIV] 8 [OP_ADD]",
        "solution_abst_en": "72 6 [OP_DIV] 8 [OP_ADD]",
        "solution_code_ko": "var_a = 72\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 8\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 72\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 8\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "2158": {
        "category": "Comparison",
        "question_ko": "5개의 수 1.4, 9/10, 1, 0.5, 13/10이 있습니다. 이 중에서 1보다 큰 수는 모두 몇 개입니까?",
        "question_en": "There are five numbers 1.4, 9/10, 1, 0.5, and 13/10. How many of these numbers are greater than 1?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1 0.5 13/10 [OP_LIST_EOL] 1 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1 0.5 13/10 [OP_LIST_EOL] 1 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "2159": {
        "category": "Correspondence",
        "question_ko": "마트에서 쿠폰을 가져가면 쿠폰당 음료수 3병을 주는 이벤트를 진행중이다. 그런데 쿠폰을 가져가다 3장이 날라가버려서 남은 쿠폰이 4장이라고 한다. 쿠폰이 날라가버리지 않았다면 몇 병의 음료수를 받았는지 구하시오.",
        "question_en": "If you take a coupon to the mart, there is an event that gives you 3 bottles of soda per coupon. However, while taking the coupon, 3 coupons were blown away, so there are 4 remaining coupons. How many bottles of drinks would you receive if the coupons were not blown away?",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "4 3 [OP_ADD] 3 [OP_MUL]",
        "solution_abst_en": "4 3 [OP_ADD] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 4\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 4\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "2160": {
        "category": "Comparison",
        "question_ko": "우유를 민현이는 6리터(L)의 0.41 배만큼 마셨고 진영이는 2.3리터(L)를 마셨습니다. 우유를 누가 더 많이 마셨습니까?",
        "question_en": "Minhyun drank 0.41 times as much milk as 6 liters (L) and Jinyoung drank 2.3 liters (L). Who drank more milk?",
        "answer_ko": "민현",
        "answer_en": "Minhyun",
        "solution_abst_ko": "[OP_LIST_SOL] 민현 진영 [OP_LIST_EOL] [OP_LIST_SOL] 6 0.41 [OP_MUL] 2.3 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Minhyun Jinyoung [OP_LIST_EOL] [OP_LIST_SOL] 6 0.41 [OP_MUL] 2.3 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '민현'\nvar_b = '진영'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 0.41\nvar_e = var_c * var_d\nvar_f = 2.3\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Minhyun'\nvar_b = 'Jinyoung'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 0.41\nvar_e = var_c * var_d\nvar_f = 2.3\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "2161": {
        "category": "Geometry",
        "question_ko": "어떤 정육면체는 한 변의 길이가 8센티미터(㎝)라고 합니다. 이 정육면체의 겉넓이는 몇 제곱센티미터(㎠)입니까?",
        "question_en": "A cube is said to have a side length of 8 centimeters (cm). What is the surface area of this cube in square centimeters (cm2)?",
        "answer_ko": "384",
        "answer_en": "384",
        "solution_abst_ko": "8 2 [OP_POW] 6 [OP_MUL]",
        "solution_abst_en": "8 2 [OP_POW] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "2162": {
        "category": "Geometry",
        "question_ko": "모서리가 10개인 각뿔의 꼭짓점은 몇 개일까요?",
        "question_en": "How many vertices are in a pyramid with 10 edges?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "10 2 [OP_DIV] 1 [OP_ADD]",
        "solution_abst_en": "10 2 [OP_DIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "2163": {
        "category": "Geometry",
        "question_ko": "팔면체는 몇 개의 면을 가지고 있습니까?",
        "question_en": "How many faces does an octahedron have?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "8",
        "solution_abst_en": "8",
        "solution_code_ko": "var_a = 8\nprint(int(var_a))",
        "solution_code_en": "var_a = 8\nprint(int(var_a))"
    },
    "2164": {
        "category": "Arithmetic calculation",
        "question_ko": "선우는 10000원을 가지고 한 통에 600원 하는 풍선껌 2통과 2봉지에 1600원 하는 라면 9봉지를 샀습니다. 선우가 받은 거스름돈은 얼마입니까?",
        "question_en": "With 10,000 won, Seonwoo bought 2 packets of bubblegum at 600 won each and 9 bags of ramen that costs 1600 won for 2 bags. How much change did Seonwoo receive?",
        "answer_ko": "1600",
        "answer_en": "1600",
        "solution_abst_ko": "10000 600 2 [OP_MUL] 1600 2 [OP_DIV] 9 [OP_MUL] [OP_ADD] [OP_SUB]",
        "solution_abst_en": "10000 600 2 [OP_MUL] 1600 2 [OP_DIV] 9 [OP_MUL] [OP_ADD] [OP_SUB]",
        "solution_code_ko": "var_a = 10000\nvar_b = 600\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = 1600\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 9\nvar_i = var_g * var_h\nvar_j = var_d + var_i\nvar_k = var_a - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 10000\nvar_b = 600\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = 1600\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 9\nvar_i = var_g * var_h\nvar_j = var_d + var_i\nvar_k = var_a - var_j\nprint(int(var_k))"
    },
    "2165": {
        "category": "Arithmetic calculation",
        "question_ko": "연속된 짝수 3개의 합이 1194일 때, 첫번째 짝수는 얼마입니까?",
        "question_en": "If the sum of three consecutive even numbers is 1194, what is the first even number?",
        "answer_ko": "396",
        "answer_en": "396",
        "solution_abst_ko": "1194 0 3 1 [OP_SUB] 2 [OP_MUL] 2 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 3 [OP_DIV]",
        "solution_abst_en": "1194 0 3 1 [OP_SUB] 2 [OP_MUL] 2 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 1194\nvar_b = 0\nvar_c = 3\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = 2\nlist_a = [i for i in range(var_b, var_g + 1, var_h)]\nlist_a = [float(i) for i in list_a]\nvar_i = sum(list_a)\nvar_j = var_a - var_i\nvar_k = 3\nvar_l = var_j / var_k\nprint(int(var_l))",
        "solution_code_en": "var_a = 1194\nvar_b = 0\nvar_c = 3\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = 2\nlist_a = [i for i in range(var_b, var_g + 1, var_h)]\nlist_a = [float(i) for i in list_a]\nvar_i = sum(list_a)\nvar_j = var_a - var_i\nvar_k = 3\nvar_l = var_j / var_k\nprint(int(var_l))"
    },
    "2166": {
        "category": "Possibility",
        "question_ko": "책꽂이에 책을 순서대로 꽂으려고 합니다. 수학책 1권, 과학책 1권이 있을 때 경우의 수를 구하시오.",
        "question_en": "I'm trying to put the books in order on the bookshelf. Find the number of cases when there are 1 math book and 1 science book.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 수학책 과학책 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] math science [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM]",
        "solution_code_ko": "var_a = '수학책'\nvar_b = '과학책'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = len(list_a)\nvar_d = len(list_a)\nvar_e = 1\nvar_c = int(var_c)\nvar_d = int(var_d)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e * (var_c-i)\nprint(int(var_e))",
        "solution_code_en": "var_a = 'math'\nvar_b = 'science'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = len(list_a)\nvar_d = len(list_a)\nvar_e = 1\nvar_c = int(var_c)\nvar_d = int(var_d)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e * (var_c-i)\nprint(int(var_e))"
    },
    "2167": {
        "category": "Correspondence",
        "question_ko": "10을 어떤 수에서 뺐더니 15가 되었습니다. 어떤 수에 5를 더하면 얼마가 되는지 구하시오.",
        "question_en": "Subtracting 10 from a number gives you 15. What number do you get when you add 5 to it?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "15 10 [OP_ADD] 5 [OP_ADD]",
        "solution_abst_en": "15 10 [OP_ADD] 5 [OP_ADD]",
        "solution_code_ko": "var_a = 15\nvar_b = 10\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 10\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "2168": {
        "category": "Comparison",
        "question_ko": "4의 배수들을 차례로 썼다. 해당 배수들은 0보다 크고 100보다 작다. 왼쪽에서 5번째, 오른쪽에서 8번째 사이에는 모두 몇 개의 수가 있는가?",
        "question_en": "Multiples of 4 are written sequentially. Those multiples are greater than 0 and less than 100. How many numbers are there between the 5th from the left and the 8th from the right?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "0 1 [OP_ADD] 100 1 [OP_SUB] 1 [OP_LIST_ARANGE] 4 [OP_LIST_DIVISIBLE] 5 [OP_LIST_MIN] 8 [OP_LIST_MAX] [OP_LIST_LESS] [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "0 1 [OP_ADD] 100 1 [OP_SUB] 1 [OP_LIST_ARANGE] 4 [OP_LIST_DIVISIBLE] 5 [OP_LIST_MIN] 8 [OP_LIST_MAX] [OP_LIST_LESS] [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 100\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = 4\nlist_b = []\nvar_h = int(var_h)\nfor i in list_a:\n    i = int(i)\n    if i % var_h == 0:\n        list_b.append(i)\nvar_i = 5\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = 8\nlist_d=list_b.copy()\nlist_d.sort()\nvar_l = list_d[-var_k]\nlist_e = []\nfor i in list_b:\n    if i < var_l:\n        list_e.append(i)\nlist_f = []\nfor i in list_e:\n    if i > var_j:\n        list_f.append(i)\nvar_m = len(list_f)\nprint(int(var_m))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 100\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = 4\nlist_b = []\nvar_h = int(var_h)\nfor i in list_a:\n    i = int(i)\n    if i % var_h == 0:\n        list_b.append(i)\nvar_i = 5\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = 8\nlist_d=list_b.copy()\nlist_d.sort()\nvar_l = list_d[-var_k]\nlist_e = []\nfor i in list_b:\n    if i < var_l:\n        list_e.append(i)\nlist_f = []\nfor i in list_e:\n    if i > var_j:\n        list_f.append(i)\nvar_m = len(list_f)\nprint(int(var_m))"
    },
    "2169": {
        "category": "Arithmetic calculation",
        "question_ko": "진희는 16의 배수들을 구하고, 민준이는 24의 배수들을 구하고, 민우는 200이하의 자연수들을 구하고 있습니다. 세 사람이 구한 수들 중 공통적으로 포함된 수들은 몇 개입니까?",
        "question_en": "Jinhee is looking for multiples of 16, Minjun is looking for multiples of 24, and Minwoo is looking for natural numbers less than 200. How many of the numbers found by the three people are included in common?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "1 200 1 [OP_LIST_ARANGE] 16 [OP_LIST_DIVISIBLE] 24 [OP_LIST_DIVISIBLE] [OP_SET_INTERSECT] [OP_LIST_LEN]",
        "solution_abst_en": "1 200 1 [OP_LIST_ARANGE] 16 [OP_LIST_DIVISIBLE] 24 [OP_LIST_DIVISIBLE] [OP_SET_INTERSECT] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 200\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 16\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 24\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nlist_d = list(set(list_b) & set(list_c))\nvar_f = len(list_d)\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 200\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 16\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 24\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nlist_d = list(set(list_b) & set(list_c))\nvar_f = len(list_d)\nprint(int(var_f))"
    },
    "2170": {
        "category": "Comparison",
        "question_ko": "도형 가는 가로가 12센티미터(㎝), 세로가 5센티미터(㎝)인 직사각형입니다. 도형 나는 둘레가 32센티미터(㎝)이고, 세로가 8센티미터(㎝)인 직사각형입니다. 두 도형 중 넓이가 더 넓은 것은 무엇입니까?",
        "question_en": "Figure A is a rectangle measuring 12 centimeters (cm) wide and 5 centimeters (cm) tall. Figure B is a rectangle with a perimeter of 32 centimeters (cm) and a length of 8 centimeters (cm). Which of the two figures has the greater area?",
        "answer_ko": "나",
        "answer_en": "B",
        "solution_abst_ko": "[OP_LIST_SOL] 가 나 [OP_LIST_EOL] [OP_LIST_SOL] 12 5 [OP_MUL] 32 2 [OP_DIV] 8 [OP_SUB] 8 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 12 5 [OP_MUL] 32 2 [OP_DIV] 8 [OP_SUB] 8 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '가'\nvar_b = '나'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 12\nvar_d = 5\nvar_e = var_c * var_d\nvar_f = 32\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = 8\nvar_j = var_h - var_i\nvar_k = 8\nvar_l = var_j * var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 12\nvar_d = 5\nvar_e = var_c * var_d\nvar_f = 32\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = 8\nvar_j = var_h - var_i\nvar_k = 8\nvar_l = var_j * var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "2171": {
        "category": "Correspondence",
        "question_ko": "A3B-41=591입니다. B는 얼마인가요?",
        "question_en": "A3B-41=591. How much is B?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "A3B-41=591 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A3B-41=591 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A3B-41=591'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A3B-41=591'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "2172": {
        "category": "Arithmetic calculation",
        "question_ko": "35, 68, 57, 95가 있습니다. 2번째로 큰 수에서 가장 작은 수를 뺀 값은 얼마입니까?",
        "question_en": "There are 35, 68, 57 and 95. What is the second-largest number minus the smallest number?",
        "answer_ko": "33",
        "answer_en": "33",
        "solution_abst_ko": "[OP_LIST_SOL] 35 68 57 95 [OP_LIST_EOL] 2 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 35 68 57 95 [OP_LIST_EOL] 2 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 35\nvar_b = 68\nvar_c = 57\nvar_d = 95\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 35\nvar_b = 68\nvar_c = 57\nvar_d = 95\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))"
    },
    "2173": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이네 가족이 사과를 땄습니다. 아버지는 8개, 어머니는 13개, 정국이는 7개, 동생은 5개를 땄습니다. 사과를 가장 많이 딴 사람은 가장 적게 딴 사람보다 몇 개 더 많이 땄습니까?",
        "question_en": "Jungkook's family picked apples. My father got 8, my mother got 13, Jungkook got 7, and my younger brother got 5. How many more apples did the person who picked the most apples pick than the person who picked the least?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "[OP_LIST_SOL] 8 13 7 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 8 13 7 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 8\nvar_b = 13\nvar_c = 7\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 8\nvar_b = 13\nvar_c = 7\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))"
    },
    "2174": {
        "category": "Correspondence",
        "question_ko": "한 자리 수 A, B가 있습니다. 어떤 다섯 자리 수 A835B가 12의 배수입니다. A835B로 가능한 수 중에서 가장 큰 수와 가장 작은 수의 차는 무엇입니까?",
        "question_en": "There are single digit numbers A and B. When five-digit number A835B is a multiple of 12, what is the difference between the largest and smallest possible numbers of A835B?",
        "answer_ko": "69996",
        "answer_en": "69996",
        "solution_abst_ko": "A835B [OP_GEN_POSSIBLE_LIST] 12 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "A835B [OP_GEN_POSSIBLE_LIST] 12 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 'A835B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 12\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_d = list_c[-var_c]\nvar_e = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_f = list_d[var_e-1]\nvar_g = var_d - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 'A835B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 12\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_d = list_c[-var_c]\nvar_e = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_f = list_d[var_e-1]\nvar_g = var_d - var_f\nprint(int(var_g))"
    },
    "2175": {
        "category": "Possibility",
        "question_ko": "560보다 작고, 4, 5, 6이 모두 사용된 세 자리 수는 몇 개 입니까?",
        "question_en": "How many 3-digit numbers are less than 560 and contain all 4, 5, and 6?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 4 5 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 560 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 4 5 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 560 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 4\nvar_b = 5\nvar_c = 6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 560\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 4\nvar_b = 5\nvar_c = 6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 560\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "2176": {
        "category": "Geometry",
        "question_ko": "크고 작은 두 직사각형이 있습니다. 이 두 직사각형의 가로의 비는 8:7이고, 세로의 비는 9:4입니다. 큰 직사각형의 넓이가 108제곱센티미터(㎠)일 때, 작은 직사각형의 넓이는 몇 제곱센티미터(㎠)입니까?",
        "question_en": "I have two rectangles, one is large and the other is small. The horizontal ratio of these two rectangles is 8:7, and the vertical ratio is 9:4. If the area of the larger rectangle is 108 square centimeters (cm2), how many square centimeters (cm2) is the area of the smaller rectangle?",
        "answer_ko": "42",
        "answer_en": "42",
        "solution_abst_ko": "108 8 [OP_DIV] 7 [OP_MUL] 9 [OP_DIV] 4 [OP_MUL]",
        "solution_abst_en": "108 8 [OP_DIV] 7 [OP_MUL] 9 [OP_DIV] 4 [OP_MUL]",
        "solution_code_ko": "var_a = 108\nvar_b = 8\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c * var_d\nvar_f = 9\nvar_g = var_e / var_f\nvar_h = 4\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 108\nvar_b = 8\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c * var_d\nvar_f = 9\nvar_g = var_e / var_f\nvar_h = 4\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "2177": {
        "category": "Arithmetic calculation",
        "question_ko": "창현이네 학교 전체의 학생 수는 4학년 학생 수의 8배보다 32명 더 적고 4학년 학생 중 안경 쓴 학생은 안경을 쓰지 않은 학생보다 10명 더 많습니다. 창현이네 학교 전체 학생 수가 1152명일 때, 4학년 중 안경을 쓰지 않은 학생은 몇 명입니까?",
        "question_en": "The total number of students in Changhyeon's school is 32 fewer than eight times the number of fourth-year students. Of the fourth-year students, there are 10 more students who wear glasses than those who do not wear glasses. If the total number of students in Changhyeon's school is 1152, find out the number of 4th graders that do not wear glasses.",
        "answer_ko": "69",
        "answer_en": "69",
        "solution_abst_ko": "1152 32 [OP_ADD] 8 [OP_DIV] 10 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "1152 32 [OP_ADD] 8 [OP_DIV] 10 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 1152\nvar_b = 32\nvar_c = var_a + var_b\nvar_d = 8\nvar_e = var_c / var_d\nvar_f = 10\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1152\nvar_b = 32\nvar_c = var_a + var_b\nvar_d = 8\nvar_e = var_c / var_d\nvar_f = 10\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "2178": {
        "category": "Geometry",
        "question_ko": "기영이는 지름이 80센티미터(㎝)인 원을 그렸습니다. 기영이가 그린 원의 반지름은 가영이가 그린 원의 반지름보다 4배 더 깁니다. 가영이가 그린 원의 반지름을 구하시오.",
        "question_en": "Kiyoung drew a circle with a diameter of 80 centimeters (cm). The radius of the circle drawn by Kiyoung is 4 times longer than the radius of the circle drawn by Gayeong. Find the radius of the circle Gayoung drew.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "80 4 [OP_DIV] 2 [OP_DIV]",
        "solution_abst_en": "80 4 [OP_DIV] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 80\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 80\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "2179": {
        "category": "Correspondence",
        "question_ko": "14A+B73=418이 성립할 때, B에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "When 14A+B73=418 is valid, what number should go into B?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "14A+B73=418 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "14A+B73=418 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '14A+B73=418'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '14A+B73=418'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "2180": {
        "category": "Arithmetic calculation",
        "question_ko": "당근과 오이의 개수를 합치면 10개일 때, 당근의 개수는 4개였습니다. 오이 2개를 더 사왔다면, 오이의 개수는 지금 몇 개인가요?",
        "question_en": "When the sum of carrots and cucumbers was 10, the number of carrots was 4. If you bought 2 more cucumbers, how many cucumbers do you have now?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "10 4 [OP_SUB] 2 [OP_ADD]",
        "solution_abst_en": "10 4 [OP_SUB] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "2181": {
        "category": "Comparison",
        "question_ko": "효민과 진섭은 같은 수학 문제집을 각각 풀었다. 효민은 전체의 4/15를 풀었고, 진섭은 전체의 6/15를 풀었다. 누가 수학 문제를 더 많이 풀었을까?",
        "question_en": "Hyomin and Jinseop each solved the same math problem book. Hyomin solved 4/15 of the total, and Jinseop solved 6/15 of the total. Who has solved more math problems?",
        "answer_ko": "진섭",
        "answer_en": "Jinseop",
        "solution_abst_ko": "[OP_LIST_SOL] 효민 진섭 [OP_LIST_EOL] [OP_LIST_SOL] 4 15 [OP_DIV] 6 15 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Hyomin Jinseop [OP_LIST_EOL] [OP_LIST_SOL] 4 15 [OP_DIV] 6 15 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '효민'\nvar_b = '진섭'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 15\nvar_e = var_c / var_d\nvar_f = 6\nvar_g = 15\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Hyomin'\nvar_b = 'Jinseop'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 15\nvar_e = var_c / var_d\nvar_f = 6\nvar_g = 15\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "2182": {
        "category": "Geometry",
        "question_ko": "같은 넓이의 종이를 이용해 직사각형과 정사각형을 만들었습니다. 직사각형 종이는 9센티미터(㎝), 16센티미터(㎝)의 변을 갖는다면, 정사각형 종이의 한 변의 길이는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "I made a rectangle and a square using the same area of the paper. If a rectangular-shaped paper has sides of 9 centimeters (cm) and 16 centimeters (cm), how many centimeters (cm) is the length of one side of a square-shaped paper?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "9 16 [OP_MUL] 1/2 [OP_POW]",
        "solution_abst_en": "9 16 [OP_MUL] 1/2 [OP_POW]",
        "solution_code_ko": "var_a = 9\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nprint(int(var_e))"
    },
    "2183": {
        "category": "Geometry",
        "question_ko": "어떤 정사면체는 한 변의 길이가 7센티미터(㎝)입니다. 이 정사면체의 겉넓이는?",
        "question_en": "A regular tetrahedron has a side length of 7 centimeters (cm). What is the surface area of this tetrahedron?",
        "answer_ko": "84.87",
        "answer_en": "84.87",
        "solution_abst_ko": "3 1/2 [OP_POW] 7 2 [OP_POW] [OP_MUL]",
        "solution_abst_en": "3 1/2 [OP_POW] 7 2 [OP_POW] [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 0.5\nvar_c = var_a ** var_b\nvar_d = 7\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 3\nvar_b = 0.5\nvar_c = var_a ** var_b\nvar_d = 7\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "2184": {
        "category": "Comparison",
        "question_ko": "수 5개 1.4, 9/10, 1.2, 0.5, 13/10 중 1.1보다 큰 숫자를 구하고, 그 숫자들의 합을 구하면 얼마입니까?",
        "question_en": "What is the sum of the numbers that are greater than 1.1 among five numbers 1.4, 9/10, 1.2, 0.5, and 13/10?",
        "answer_ko": "3.90",
        "answer_en": "3.9",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "2185": {
        "category": "Comparison",
        "question_ko": "은지는 오른쪽에서 8번째 열, 왼쪽에서 14번째 열, 뒤에서 7번째 줄, 앞에서 15번째 줄에 서서 체조를 하고 있습니다. 각 줄마다 서 있는 학생의 수가 같다고 할 때, 체조를 하고 있는 학생은 모두 몇 명입니까?",
        "question_en": "Eunji is doing gymnastics standing in the 8th column from the right, the 14th column from the left, the 7th row from the back, and the 15th row from the front. If the number of students standing in each row is the same, how many students are doing gymnastics?",
        "answer_ko": "441",
        "answer_en": "441",
        "solution_abst_ko": "8 14 [OP_ADD] 1 [OP_SUB] 7 15 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "8 14 [OP_ADD] 1 [OP_SUB] 7 15 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 14\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 7\nvar_g = 15\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 8\nvar_b = 14\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 7\nvar_g = 15\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))"
    },
    "2186": {
        "category": "Arithmetic calculation",
        "question_ko": "한 봉지에 16개씩 들어있는 초콜릿을 7봉지 샀습니다. 그중에서 13개는 뜨거운 햇빛에 녹아버렸고, 남은 초콜릿들을 8봉지에 똑같이 나누어 담으려고 할 때, 한 봉지에 몇 개의 초콜릿을 담아야 합니까?",
        "question_en": "I bought 7 bags of chocolates, each containing 16 pieces. Thirteen of them have melted in the hot sun. You want to split the remaining chocolate equally into 8 bags. How many chocolates should you put in one bag?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "16 7 [OP_MUL] 13 [OP_SUB] 8 [OP_FDIV]",
        "solution_abst_en": "16 7 [OP_MUL] 13 [OP_SUB] 8 [OP_FDIV]",
        "solution_code_ko": "var_a = 16\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = var_e // var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 16\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = var_e // var_f\nprint(int(var_g))"
    },
    "2187": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 3번째로 큰 수와 2번째로 큰 수의 합은 얼마입니까?",
        "question_en": "There are five numbers: 10, 11, 12, 13, and 14. What is the sum of the 3rd largest number and the 2nd largest number?",
        "answer_ko": "25",
        "answer_en": "25",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 3 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 3 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[-var_h]\nvar_j = var_g + var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[-var_h]\nvar_j = var_g + var_i\nprint(int(var_j))"
    },
    "2188": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 72센티미터(㎝)인 정사각형 모양의 종이를 잘라 한 변의 길이가 8센티미터(㎝)인 정사각형을 만들려고 합니다. 몇 개까지 만들 수 있습니까?",
        "question_en": "You want to make a square with a side of 8 centimeters (cm) by cutting a square of paper with a side length of 72 centimeters (cm). How many can you make?",
        "answer_ko": "81",
        "answer_en": "81",
        "solution_abst_ko": "72 8 [OP_DIV] 72 8 [OP_DIV] [OP_MUL]",
        "solution_abst_en": "72 8 [OP_DIV] 72 8 [OP_DIV] [OP_MUL]",
        "solution_code_ko": "var_a = 72\nvar_b = 8\nvar_c = var_a / var_b\nvar_d = 72\nvar_e = 8\nvar_f = var_d / var_e\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 72\nvar_b = 8\nvar_c = var_a / var_b\nvar_d = 72\nvar_e = 8\nvar_f = var_d / var_e\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "2189": {
        "category": "Arithmetic calculation",
        "question_ko": "민수는 가지고 있는 구슬 240개를 큰 상자 4개에 35개씩 담고, 남은 구슬을 작은 상자 3개에 6개씩 담았습니다. 상자에 나누어 담고 남은 구슬은 몇 개입니까?",
        "question_en": "Minsu distributed 240 marbles by putting every 35 marbles in 4 large boxes and putting every 6 marbles in 3 small boxes. How many marbles are left after distributing them into boxes?",
        "answer_ko": "82",
        "answer_en": "82",
        "solution_abst_ko": "240 4 35 [OP_MUL] [OP_SUB] 3 6 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "240 4 35 [OP_MUL] [OP_SUB] 3 6 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 240\nvar_b = 4\nvar_c = 35\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 3\nvar_g = 6\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 240\nvar_b = 4\nvar_c = 35\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 3\nvar_g = 6\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nprint(int(var_i))"
    },
    "2190": {
        "category": "Correspondence",
        "question_ko": "캔디 통에 9개씩 캔디가 들어있는데 그 중 3개만 딸기맛 캔디라고 한다. 여러 개의 캔디 통 안에 딸기맛 캔디가 27개 있을 때 캔디 통의 개수를 구하시오.",
        "question_en": "There are 9 candies in the candy box, but only 3 of them are strawberry-flavored candies. If there are 27 strawberry-flavored candies in multiple candy tins, find the number of candy tins.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "27 3 [OP_MUL] 9 [OP_DIV]",
        "solution_abst_en": "27 3 [OP_MUL] 9 [OP_DIV]",
        "solution_code_ko": "var_a = 27\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 27\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "2191": {
        "category": "Geometry",
        "question_ko": "어떤 정사각형에서 한변의 길이가 3배 늘어난다면 넓이는 몇 배 늘어나는지 구하시오.",
        "question_en": "Find how many times the area of a square increases if the length of one side of the square is tripled.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "3 2 [OP_POW]",
        "solution_abst_en": "3 2 [OP_POW]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = var_a ** var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = var_a ** var_b\nprint(int(var_c))"
    },
    "2192": {
        "category": "Possibility",
        "question_ko": "4개의 수 1, 2, 3, 6를 한 번씩만 사용하여 임의의 네 자리 수를 만들려고 합니다. 만들 수 있는 수는 모두 몇 개 입니까?",
        "question_en": "You want to create a random four-digit number using the four numbers 1, 2, 3, and 6 only once. How many can you make in all?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "[OP_LIST_SOL] 1 2 3 6 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 2 3 6 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 2\nvar_c = 3\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 2\nvar_c = 3\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "2193": {
        "category": "Comparison",
        "question_ko": "경수네 학교의 운동장은 7800제곱미터(㎡)이고, 학생 수는 600명입니다. 그리고 미라네 학교의 운동장은 7000제곱미터(㎡)이고, 학생 수는 500명입니다. 누구네 학교의 학생들이 운동장을 더 넓게 사용할 수 있습니까?",
        "question_en": "The playground of Kyungsoo's school is 7800 square meters (㎡), and the number of students is 600. And Mira's school's playground is 7000 square meters (㎡), and the number of students is 500. Whose school's students can use more area of the playground each?",
        "answer_ko": "미라",
        "answer_en": "Mira",
        "solution_abst_ko": "[OP_LIST_SOL] 경수 미라 [OP_LIST_EOL] [OP_LIST_SOL] 7800 600 [OP_DIV] 7000 500 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Kyungsoo Mira [OP_LIST_EOL] [OP_LIST_SOL] 7800 600 [OP_DIV] 7000 500 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '경수'\nvar_b = '미라'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 7800\nvar_d = 600\nvar_e = var_c / var_d\nvar_f = 7000\nvar_g = 500\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Kyungsoo'\nvar_b = 'Mira'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 7800\nvar_d = 600\nvar_e = var_c / var_d\nvar_f = 7000\nvar_g = 500\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "2194": {
        "category": "Arithmetic calculation",
        "question_ko": "물이 일정하게 빠지는 배수구가 있습니다. 물이 24.7리터(L)일 때 배수구의 마개를 열어 물을 빠지게 했더니 40분 후에 물의 양이 17.1리터(L)가 되어있었습니다. 물이 모두 빠지는 데에 걸리는 시간은 몇 분인지 구하시오.",
        "question_en": "There is a drain through which the water drains consistently. When there were 24.7 liters (L) of water, I opened the drain stopper to drain the water, and after 40 minutes, the amount of water have become 17.1 liters (L). Find how many minutes it takes for all the water to drain out.",
        "answer_ko": "130",
        "answer_en": "130",
        "solution_abst_ko": "24.7 24.7 17.1 [OP_SUB] 40 [OP_DIV] [OP_DIV]",
        "solution_abst_en": "24.7 24.7 17.1 [OP_SUB] 40 [OP_DIV] [OP_DIV]",
        "solution_code_ko": "var_a = 24.7\nvar_b = 24.7\nvar_c = 17.1\nvar_d = var_b - var_c\nvar_e = 40\nvar_f = var_d / var_e\nvar_g = var_a / var_f\nprint(int(eval('{:.2f}'.format(round(var_g+1e-10,2)))))",
        "solution_code_en": "var_a = 24.7\nvar_b = 24.7\nvar_c = 17.1\nvar_d = var_b - var_c\nvar_e = 40\nvar_f = var_d / var_e\nvar_g = var_a / var_f\nprint(int(eval('{:.2f}'.format(round(var_g+1e-10,2)))))"
    },
    "2195": {
        "category": "Arithmetic calculation",
        "question_ko": "연속하는 6개의 자연수의 합이 105입니다. 6개의 자연수 중에서 가장 큰 수와 가장 작은 수의 합을 구하시오.",
        "question_en": "The sum of 6 consecutive natural numbers is 105. Find the sum of the largest and smallest of the six natural numbers.",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "105 0 6 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 6 [OP_DIV] 2 [OP_MUL] 6 1 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "105 0 6 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 6 [OP_DIV] 2 [OP_MUL] 6 1 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 105\nvar_b = 0\nvar_c = 6\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nlist_a = [i for i in range(var_b, var_e + 1, var_f)]\nlist_a = [float(i) for i in list_a]\nvar_g = sum(list_a)\nvar_h = var_a - var_g\nvar_i = 6\nvar_j = var_h / var_i\nvar_k = 2\nvar_l = var_j * var_k\nvar_m = 6\nvar_n = 1\nvar_o = var_m - var_n\nvar_p = var_l + var_o\nprint(int(var_p))",
        "solution_code_en": "var_a = 105\nvar_b = 0\nvar_c = 6\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nlist_a = [i for i in range(var_b, var_e + 1, var_f)]\nlist_a = [float(i) for i in list_a]\nvar_g = sum(list_a)\nvar_h = var_a - var_g\nvar_i = 6\nvar_j = var_h / var_i\nvar_k = 2\nvar_l = var_j * var_k\nvar_m = 6\nvar_n = 1\nvar_o = var_m - var_n\nvar_p = var_l + var_o\nprint(int(var_p))"
    },
    "2196": {
        "category": "Possibility",
        "question_ko": "7, 9, 3, 6 수 카드 4장을 한 번씩만 사용하여 만들 수 있는 가장 큰 네 자리 수를 내림하여 백의 자리까지 나타내어 보세요.",
        "question_en": "Round down the largest four-digit number you can make by playing four 7, 9, 3, and 6 cards only once, to the hundredth place.",
        "answer_ko": "9700",
        "answer_en": "9700",
        "solution_abst_ko": "[OP_LIST_SOL] 7 9 3 6 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 3 [OP_FLOOR]",
        "solution_abst_en": "[OP_LIST_SOL] 7 9 3 6 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 3 [OP_FLOOR]",
        "solution_code_ko": "var_a = 7\nvar_b = 9\nvar_c = 3\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 3\nvar_i=int((var_g//(10**(var_h-1)))*10**(var_h-1))\n\nprint(int(var_i))",
        "solution_code_en": "var_a = 7\nvar_b = 9\nvar_c = 3\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 3\nvar_i=int((var_g//(10**(var_h-1)))*10**(var_h-1))\n\nprint(int(var_i))"
    },
    "2197": {
        "category": "Correspondence",
        "question_ko": "서로 다른 두 자연수 A, B가 있습니다. A를 7로 나누면 몫은 15이고 나머지는 B가 됩니다. 나머지 B가 가장 작은 수일 때 A를 구하시오.",
        "question_en": "There are two different natural numbers, A and B. When A is divided by 7, the quotient is 15 and the remainder is B. Find A when the remainder B is the smallest number.",
        "answer_ko": "105",
        "answer_en": "105",
        "solution_abst_ko": "7 15 [OP_MUL]",
        "solution_abst_en": "7 15 [OP_MUL]",
        "solution_code_ko": "var_a = 7\nvar_b = 15\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 7\nvar_b = 15\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "2198": {
        "category": "Arithmetic calculation",
        "question_ko": "(가) 반 학생은 모두 44명입니다. (가) 반은 (나) 반보다 2명 더 적고, (나) 반은 (다) 반보다 1명 더 많습니다. (다) 반 학생은 모두 몇 명입니까?",
        "question_en": "There are 44 students in the A class. A class has 2 fewer students than B class, and B class has 1 more student than C class. How many students are there in C class?",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "44 2 [OP_ADD] 1 [OP_SUB]",
        "solution_abst_en": "44 2 [OP_ADD] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 44\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 44\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "2199": {
        "category": "Arithmetic calculation",
        "question_ko": "성호와 민수가 영어 신문 1장을 해석을 하는데, 성호 혼자서 하면 5시간이 걸리고 민수 혼자서 하면 3시간이 걸린다고 합니다. 해석해야 할 양이 16장일 때, 두 사람이 함께 일을 마치는 데 걸리는 시간을 구하여라.",
        "question_en": "Seong-ho and Min-soo are trying to interpret a page from an English newspaper. It takes 5 hours for Seong-ho alone and 3 hours for Min-su alone to complete the translation. Find out the time it takes for the two people to complete the task together when the amount of pages to be interpreted is 16 pages.",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "1 16 [OP_MUL] 1 5 [OP_DIV] 1 3 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_abst_en": "1 16 [OP_MUL] 1 5 [OP_DIV] 1 3 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 5\nvar_f = var_d / var_e\nvar_g = 1\nvar_h = 3\nvar_i = var_g / var_h\nvar_j = var_f + var_i\nvar_k = var_c / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 1\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 5\nvar_f = var_d / var_e\nvar_g = 1\nvar_h = 3\nvar_i = var_g / var_h\nvar_j = var_f + var_i\nvar_k = var_c / var_j\nprint(int(var_k))"
    },
    "2200": {
        "category": "Arithmetic calculation",
        "question_ko": "세윤이네 반 학생 10명이 이번 달에 봉사 활동을 하는 데 쓴 시간을 조사해보니, 각각 5, 6, 5, 5, 6, 4, 5, 5, 6, 7시간이었습니다. 이번 달에 5시간의 봉사 활동을 한 학생은 몇 명인지 구하시오.",
        "question_en": "When I investigated the amount of time 10 students in Seyoon's class spent doing volunteer work this month, they were 5, 6, 5, 5, 6, 4, 5, 5, 6, and 7 hours respectively. Find how many students did 5 hours of volunteer work this month.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "[OP_LIST_SOL] 5 6 5 5 6 4 5 5 6 7 [OP_LIST_EOL] 5 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "[OP_LIST_SOL] 5 6 5 5 6 4 5 5 6 7 [OP_LIST_EOL] 5 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 5\nvar_b = 6\nvar_c = 5\nvar_d = 5\nvar_e = 6\nvar_f = 4\nvar_g = 5\nvar_h = 5\nvar_i = 6\nvar_j = 7\nlist_a= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_a.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_k = 5\nvar_l = 0\nvar_k = int(var_k)\nfor i in list_a:\n    i = int(i)\n    if i == var_k:\n        var_l = var_l + 1\nprint(int(var_l))",
        "solution_code_en": "var_a = 5\nvar_b = 6\nvar_c = 5\nvar_d = 5\nvar_e = 6\nvar_f = 4\nvar_g = 5\nvar_h = 5\nvar_i = 6\nvar_j = 7\nlist_a= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_a.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_k = 5\nvar_l = 0\nvar_k = int(var_k)\nfor i in list_a:\n    i = int(i)\n    if i == var_k:\n        var_l = var_l + 1\nprint(int(var_l))"
    },
    "2201": {
        "category": "Geometry",
        "question_ko": "가로가 9.4센티미터(㎝), 세로가 3.7센티미터(㎝)인 직사각형 모양의 색종이를 가로 부분이 0.6센티미터(㎝)씩 겹치도록 15장을 이어 붙였습니다. 이어 붙인 색종이의 전체 넓이는 얼마입니까?",
        "question_en": "Fifteen pieces of colored paper in the shape of a rectangle, 9.4 cm (cm) wide and 3.7 cm (cm) long, overlap each other by 0.6 centimeters (cm). What is the total area of the colored paper glued together?",
        "answer_ko": "490.62",
        "answer_en": "490.62",
        "solution_abst_ko": "9.4 15 [OP_MUL] 15 1 [OP_SUB] 0.6 [OP_MUL] [OP_SUB] 3.7 [OP_MUL]",
        "solution_abst_en": "9.4 15 [OP_MUL] 15 1 [OP_SUB] 0.6 [OP_MUL] [OP_SUB] 3.7 [OP_MUL]",
        "solution_code_ko": "var_a = 9.4\nvar_b = 15\nvar_c = var_a * var_b\nvar_d = 15\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 0.6\nvar_h = var_f * var_g\nvar_i = var_c - var_h\nvar_j = 3.7\nvar_k = var_i * var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 9.4\nvar_b = 15\nvar_c = var_a * var_b\nvar_d = 15\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 0.6\nvar_h = var_f * var_g\nvar_i = var_c - var_h\nvar_j = 3.7\nvar_k = var_i * var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "2202": {
        "category": "Geometry",
        "question_ko": "어떤 공원은 한 변의 길이가 5미터(m)인 정육각형 모양으로 되어 있습니다. 이 공원의 둘레의 길이를 구하시오.",
        "question_en": "Some parks are shaped like a regular hexagon with sides measuring 5 meters (m). Find the length of the perimeter of this park.",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "5 6 [OP_MUL]",
        "solution_abst_en": "5 6 [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 6\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 6\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "2203": {
        "category": "Geometry",
        "question_ko": "지름이 26센티미터(㎝)인 자전거 바퀴의 반지름의 길이는 몇 센티미터(㎝)인가?",
        "question_en": "What is the length in centimeters (cm) of the radius of a bicycle wheel with a diameter of 26 centimeters (cm)?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "26 2 [OP_DIV]",
        "solution_abst_en": "26 2 [OP_DIV]",
        "solution_code_ko": "var_a = 26\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 26\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "2204": {
        "category": "Correspondence",
        "question_ko": "전체 인원이 450명인 어떤 회사가 있다. 그 중 해외에서 근무하는 직원은 전체 직원의 0.06만큼이다. 해외에서 근무하는 직원은 몇 명인가?",
        "question_en": "There is a company with a total of 450 people. Among them, employees working abroad accounted for 0.06 of the total number of employees. How many employees work abroad?",
        "answer_ko": "27",
        "answer_en": "27",
        "solution_abst_ko": "450 0.06 [OP_MUL]",
        "solution_abst_en": "450 0.06 [OP_MUL]",
        "solution_code_ko": "var_a = 450\nvar_b = 0.06\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 450\nvar_b = 0.06\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "2205": {
        "category": "Arithmetic calculation",
        "question_ko": "50 이하의 자연수 중 5의 배수이거나 2의 배수인 수를 나열했을 때 2는 몇 번 등장하는지 구하시오.",
        "question_en": "Find how many times the number 2 appears in a list of all natural numbers less than or equal to 50 that are multiples of 5 or 2.",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "1 50 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] 1 50 [OP_LIST_EVEN] [OP_SET_UNION] [OP_LIST2NUM] [OP_NUM2LIST] 2 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 50 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] 1 50 [OP_LIST_EVEN] [OP_SET_UNION] [OP_LIST2NUM] [OP_NUM2LIST] 2 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 50\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 1\nvar_f = 50\nlist_c = []\nif var_e%2!=0:\n    for i in range(var_e+1, var_f+1, 2):\n        list_c.append(i)\nelse:\n    for i in range(var_e, var_f+1, 2):\n        list_c.append(i)\nlist_d = list(set(list_b) | set(list_c))\nvar_g=\"\"\nfor i in list_d:\n    i = str(i)\n    var_g = var_g + i\nlist_e = []\nvar_g = int(var_g)\nwhile var_g//10 > 0:\n    list_e.append(var_g%10)\n    var_g = var_g//10\nlist_e.append(var_g%10)\nlist_e = list_e[::-1]\nvar_h = 2\nvar_i = 0\nvar_h = int(var_h)\nfor i in list_e:\n    i = int(i)\n    if i == var_h:\n        var_i = var_i + 1\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 50\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 1\nvar_f = 50\nlist_c = []\nif var_e%2!=0:\n    for i in range(var_e+1, var_f+1, 2):\n        list_c.append(i)\nelse:\n    for i in range(var_e, var_f+1, 2):\n        list_c.append(i)\nlist_d = list(set(list_b) | set(list_c))\nvar_g=\"\"\nfor i in list_d:\n    i = str(i)\n    var_g = var_g + i\nlist_e = []\nvar_g = int(var_g)\nwhile var_g//10 > 0:\n    list_e.append(var_g%10)\n    var_g = var_g//10\nlist_e.append(var_g%10)\nlist_e = list_e[::-1]\nvar_h = 2\nvar_i = 0\nvar_h = int(var_h)\nfor i in list_e:\n    i = int(i)\n    if i == var_h:\n        var_i = var_i + 1\nprint(int(var_i))"
    },
    "2206": {
        "category": "Arithmetic calculation",
        "question_ko": "우진이네 밭의 3/5에는 감자를 심었고, 나머지의 2/3에는 고구마를 심었다. 아무것도 심지 않은 부분은 전체의 몇 분의 몇 인가?",
        "question_en": "Potatoes were planted in 3/5 of Woojin's field, and sweet potatoes were planted in 2/3 of the remaining. What fraction of the whole is the unplanted part?",
        "answer_ko": "0.13",
        "answer_en": "0.13",
        "solution_abst_ko": "1 3/5 [OP_SUB] 1 2/3 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "1 3/5 [OP_SUB] 1 2/3 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 1\nvar_b = 0.6\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = 0.6666666666666666\nvar_f = var_d - var_e\nvar_g = var_c * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 0.6\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = 0.6666666666666666\nvar_f = var_d - var_e\nvar_g = var_c * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "2207": {
        "category": "Possibility",
        "question_ko": "0, 1, 2, 3의 숫자가 각각 적힌 4장의 카드로 만들 수 있는 세 자리 정수는 모두 몇 가지입니까?",
        "question_en": "How many three-digit integers can be made with 4 cards each numbered 0, 1, 2, 3?",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "2208": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 유치원의 기린반에는 225명의 학생이 있고, 코끼리반에는 기린반보다 48명의 학생이 더 있습니다. 토끼반은 기린 반보다 24명의 학생이 덜 있습니다. 세 반의 평균 학생 수는 몇 명입니까?",
        "question_en": "There are 225 students in class giraffe, and class elephant as 48 more students than class giraffe. Class rabbit has 24 less students than class giraffe. How many students are in the three classes of this kindergarten on average?",
        "answer_ko": "233",
        "answer_en": "233",
        "solution_abst_ko": "225 225 48 [OP_ADD] [OP_ADD] 225 24 [OP_SUB] [OP_ADD] 3 [OP_DIV]",
        "solution_abst_en": "225 225 48 [OP_ADD] [OP_ADD] 225 24 [OP_SUB] [OP_ADD] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 225\nvar_b = 225\nvar_c = 48\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nvar_f = 225\nvar_g = 24\nvar_h = var_f - var_g\nvar_i = var_e + var_h\nvar_j = 3\nvar_k = var_i / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 225\nvar_b = 225\nvar_c = 48\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nvar_f = 225\nvar_g = 24\nvar_h = var_f - var_g\nvar_i = var_e + var_h\nvar_j = 3\nvar_k = var_i / var_j\nprint(int(var_k))"
    },
    "2209": {
        "category": "Possibility",
        "question_ko": "1, 3, 5, 7, 9 다섯 장의 숫자카드가 있다. 이 카드를 사용하여 만들 수 있는 3자리 자연수 중 500 초과인 수의 합은 얼마인지 구하시오. (단, 카드는 중복사용 가능하다.)",
        "question_en": "There are five number cards 1, 3, 5, 7, and 9. What is the sum of the three-digit natural numbers that can be made using these cards that are greater than 500? (However, the card can be used repeatedly.)",
        "answer_ko": "56625",
        "answer_en": "56625",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 5 7 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 500 [OP_LIST_MORE] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 5 7 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 500 [OP_LIST_MORE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 5\nvar_d = 7\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 500\nlist_c = []\nfor i in list_b:\n    if i > var_g:\n        list_c.append(i)\nlist_c = [float(i) for i in list_c]\nvar_h = sum(list_c)\nprint(int(var_h))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 5\nvar_d = 7\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 500\nlist_c = []\nfor i in list_b:\n    if i > var_g:\n        list_c.append(i)\nlist_c = [float(i) for i in list_c]\nvar_h = sum(list_c)\nprint(int(var_h))"
    },
    "2210": {
        "category": "Possibility",
        "question_ko": "2, 4, 6, 8, 9 중에서 2장을 뽑아 한 번씩만 사용하여 두 자리 수를 만들려고 합니다. 만들 수 있는 두 자리 수 중에서 가장 큰 수와 가장 작은 수의 곱을 구하시오.",
        "question_en": "You are going to create a two-digit number by drawing two cards among 2, 4, 6, 8, and 9 and you can use them only once. Find the product of the largest and smallest two-digit numbers that can be made.",
        "answer_ko": "2352",
        "answer_en": "2352",
        "solution_abst_ko": "[OP_LIST_SOL] 2 4 6 8 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 2 4 6 8 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = 6\nvar_d = 8\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = 6\nvar_d = 8\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h * var_j\nprint(int(var_k))"
    },
    "2211": {
        "category": "Comparison",
        "question_ko": "1개의 무게가 50그램(g)인 노란색 공을 50개씩 담은 상자가 5개 있습니다. 1개의 무게가 45그램(g)인 흰색 공을 60개씩 담은 상자가 6개 있습니다. 또 1개의 무게가 55그램(g)인 파란색 공을 40개씩 담은 상자가 4개 있습니다. 빈 상자의 무게는 모두 같습니다. 한 상자의 무게가 가장 가벼운 상자 안에 들어 있는 공의 색깔은 무엇입니까?",
        "question_en": "There are 5 boxes of 50 yellow balls each weighing 50 grams (g). There are 6 boxes of 60 white balls each weighing 45 grams (g). There are also 4 boxes of 40 blue balls each weighing 55 grams (g). All the empty boxes weigh the same. What is the color of the ball in the box with the lightest weight?",
        "answer_ko": "파란색",
        "answer_en": "blue",
        "solution_abst_ko": "[OP_LIST_SOL] 노란색 흰색 파란색 [OP_LIST_EOL] [OP_LIST_SOL] 50 50 [OP_MUL] 45 60 [OP_MUL] 55 40 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] yellow white blue [OP_LIST_EOL] [OP_LIST_SOL] 50 50 [OP_MUL] 45 60 [OP_MUL] 55 40 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '노란색'\nvar_b = '흰색'\nvar_c = '파란색'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 50\nvar_e = 50\nvar_f = var_d * var_e\nvar_g = 45\nvar_h = 60\nvar_i = var_g * var_h\nvar_j = 55\nvar_k = 40\nvar_l = var_j * var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[var_m-1]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'yellow'\nvar_b = 'white'\nvar_c = 'blue'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 50\nvar_e = 50\nvar_f = var_d * var_e\nvar_g = 45\nvar_h = 60\nvar_i = var_g * var_h\nvar_j = 55\nvar_k = 40\nvar_l = var_j * var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[var_m-1]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "2212": {
        "category": "Comparison",
        "question_ko": "솔이네 집에서 주민센터까지의 거리는 2킬로미터(㎞) 280미터(m)이고, 가장 가까운 지하철역까지의 거리는 4125미터(m)입니다. 솔이네 집에서 더 가까운 곳은 주민센터와 지하철역 중 어디입니까?",
        "question_en": "The distance from Sol's house to the community-center is 2 kilometers (km) and 280 meters (m), and the distance to the nearest subway-station is 4125 meters (m). Which is closer to Sol's house, the community-center or the subway-station?",
        "answer_ko": "주민센터",
        "answer_en": "community-center",
        "solution_abst_ko": "[OP_LIST_SOL] 주민센터 지하철역 [OP_LIST_EOL] [OP_LIST_SOL] 2 1000 [OP_MUL] 280 [OP_ADD] 4125 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] community-center subway-station [OP_LIST_EOL] [OP_LIST_SOL] 2 1000 [OP_MUL] 280 [OP_ADD] 4125 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '주민센터'\nvar_b = '지하철역'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 280\nvar_g = var_e + var_f\nvar_h = 4125\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'community-center'\nvar_b = 'subway-station'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 280\nvar_g = var_e + var_f\nvar_h = 4125\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "2213": {
        "category": "Possibility",
        "question_ko": "사과, 복숭아, 배, 참외, 바나나를 조합하여 2개의 과일을 사려고 합니다. 중복을 허용하여 조합할 수 있는 경우의 수는 모두 몇 가지입니까?",
        "question_en": "You want to buy 2 fruits by combining apple, peach, pear, melon, and banana. How many possible combinations are there when allowing duplicates?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 복숭아 배 참외 바나나 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] apple peach pear melon banana [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '복숭아'\nvar_c = '배'\nvar_d = '참외'\nvar_e = '바나나'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = 2\nvar_l = 1\nvar_j = int(var_j)\nvar_k = int(var_k)\nfor i, elem in enumerate(range(var_k)):\n    var_l = var_l * (var_j-i)\nfor i, elem in enumerate(range(var_k)):\n    var_l = var_l / (i+1)\nprint(int(var_l))",
        "solution_code_en": "var_a = 'apple'\nvar_b = 'peach'\nvar_c = 'pear'\nvar_d = 'melon'\nvar_e = 'banana'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = 2\nvar_l = 1\nvar_j = int(var_j)\nvar_k = int(var_k)\nfor i, elem in enumerate(range(var_k)):\n    var_l = var_l * (var_j-i)\nfor i, elem in enumerate(range(var_k)):\n    var_l = var_l / (i+1)\nprint(int(var_l))"
    },
    "2214": {
        "category": "Geometry",
        "question_ko": "세로의 길이가 가로의 길이보다 2 센티미터(㎝)만큼 짧은 직사각형의 둘레의 길이가 16 센티미터(㎝)일 때, 가로의 길이는 얼마인가?",
        "question_en": "If the perimeter of a rectangle whose length is 2 centimeters (cm) shorter than its width is 16 centimeters (cm), what is its width?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "16 2 [OP_DIV] 2 [OP_SUB] 2 [OP_DIV] 2 [OP_ADD]",
        "solution_abst_en": "16 2 [OP_DIV] 2 [OP_SUB] 2 [OP_DIV] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 16\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 16\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "2215": {
        "category": "Comparison",
        "question_ko": "길이가 364미터(m) 인 도로의 한쪽에는 소나무를 22.75미터(m) , 다른 한쪽에는 은행나무를 45.5미터(m) 간격으로 각각 처음부터 끝까지 심었습니다. 소나무와 은행나무 중 어느 것을 더 많이 심었는지 구하시오.",
        "question_en": "Pine trees were planted 22.75 meters (m) on one side of the 364-meter (m) long road, and ginkgo trees were planted on the other side at intervals of 45.5 meters (m) from start to finish. Find out which of the pine trees or ginkgo trees was planted more.",
        "answer_ko": "소나무",
        "answer_en": "pine",
        "solution_abst_ko": "[OP_LIST_SOL] 소나무 은행나무 [OP_LIST_EOL] [OP_LIST_SOL] 364 22.75 [OP_DIV] 364 45.5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] pine ginkgo [OP_LIST_EOL] [OP_LIST_SOL] 364 22.75 [OP_DIV] 364 45.5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '소나무'\nvar_b = '은행나무'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 364\nvar_d = 22.75\nvar_e = var_c / var_d\nvar_f = 364\nvar_g = 45.5\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'pine'\nvar_b = 'ginkgo'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 364\nvar_d = 22.75\nvar_e = var_c / var_d\nvar_f = 364\nvar_g = 45.5\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "2216": {
        "category": "Arithmetic calculation",
        "question_ko": "가로수를 심으려고 합니다. 0.35킬로미터(㎞) 지점에서 0.37킬로미터(㎞) 지점까지 똑같이 4구간으로 나누어 처음부터 끝까지 가로수를 심는다면 네 번째 지점에 심는 가로 수의 위치는 몇 킬로미터(㎞) 지점인지 소수로 나타내시오.",
        "question_en": "I want to plant street trees. If street trees are planted from the beginning to the end, equally divided into 4 sections from the 0.35 km (km) point to the 0.37 km (km) point, indicate the kilometers (km) of the position of the street tree planted at the fourth point as a decimal number.",
        "answer_ko": "0.37",
        "answer_en": "0.37",
        "solution_abst_ko": "0.35 0.37 0.35 [OP_SUB] 4 [OP_DIV] 4 1 [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_abst_en": "0.35 0.37 0.35 [OP_SUB] 4 [OP_DIV] 4 1 [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 0.35\nvar_b = 0.37\nvar_c = 0.35\nvar_d = var_b - var_c\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = 4\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = var_f * var_i\nvar_k = var_a + var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 0.35\nvar_b = 0.37\nvar_c = 0.35\nvar_d = var_b - var_c\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = 4\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = var_f * var_i\nvar_k = var_a + var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "2217": {
        "category": "Geometry",
        "question_ko": "9개의 변으로 둘러싸인 도형의 대각선의 개수를 구하시오.",
        "question_en": "Find the number of diagonals in a nine-sided polygon.",
        "answer_ko": "27",
        "answer_en": "27",
        "solution_abst_ko": "9 9 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "9 9 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 9\nvar_b = 9\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 9\nvar_b = 9\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "2218": {
        "category": "Arithmetic calculation",
        "question_ko": "두 자리 수의 덧셈에서 더하는 수의 십의 자리 숫자 3을 6으로 잘못 계산했습니다. 또 더해지는 숫자는 일의 자리 숫자를 9에서 2로 잘못 보았습니다. 계산 결과 그 값이 119라면, 바르게 계산한 결과는 얼마입니까?",
        "question_en": "In two-digit addition, the number 3 in the tens place of the number added was incorrectly counted as 6. Again, the numbers being added incorrectly read the ones digit as 9 to 2. If the result of the calculation is 119, what is the result of the correct calculation?",
        "answer_ko": "96",
        "answer_en": "96",
        "solution_abst_ko": "119 1 9 2 [OP_SUB] [OP_MUL] [OP_ADD] 10 3 6 [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_abst_en": "119 1 9 2 [OP_SUB] [OP_MUL] [OP_ADD] 10 3 6 [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 119\nvar_b = 1\nvar_c = 9\nvar_d = 2\nvar_e = var_c - var_d\nvar_f = var_b * var_e\nvar_g = var_a + var_f\nvar_h = 10\nvar_i = 3\nvar_j = 6\nvar_k = var_i - var_j\nvar_l = var_h * var_k\nvar_m = var_g + var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 119\nvar_b = 1\nvar_c = 9\nvar_d = 2\nvar_e = var_c - var_d\nvar_f = var_b * var_e\nvar_g = var_a + var_f\nvar_h = 10\nvar_i = 3\nvar_j = 6\nvar_k = var_i - var_j\nvar_l = var_h * var_k\nvar_m = var_g + var_l\nprint(int(var_m))"
    },
    "2219": {
        "category": "Possibility",
        "question_ko": "2, 0, 7, 5, 9 중 3개의 숫자를 이용하여 자릿수가 서로 다른 세 자리 수를 만들었다. 이렇게 만든 수를 작은 순서대로 왼쪽부터 나열했을 때, 가장 왼쪽에 있는 수와 왼쪽에서 4번째에 있는 수를 더하면 얼마가 되겠는가?",
        "question_en": "Three numbers from 2, 0, 7, 5, and 9 were used to create a three-digit number with different digits. If the numbers made in this way are arranged from left to right in ascending order, what will be the sum of the leftmost number and the fourth number from the left?",
        "answer_ko": "455",
        "answer_en": "455",
        "solution_abst_ko": "[OP_LIST_SOL] 2 0 7 5 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 4 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 2 0 7 5 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 4 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 0\nvar_c = 7\nvar_d = 5\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = 4\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 2\nvar_b = 0\nvar_c = 7\nvar_d = 5\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = 4\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h + var_j\nprint(int(var_k))"
    },
    "2220": {
        "category": "Geometry",
        "question_ko": "가로의 길이가 9미터(m), 세로의 길이가 7미터(m)인 직육면체 모양의 호수가 있습니다. 이 호수의 부피가 315제곱센티미터(㎠) 이라면, 이 호수의 깊이는 몇 센티미터(㎝)입니까?",
        "question_en": "There is a rectangular parallelepiped-shaped lake with a length of 9 meters (m) wide and a length of 7 meters (m) long. If the volume of this lake is 315 square centimeters (cm2), how deep is this lake in centimeters (cm)?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "315 9 [OP_DIV] 7 [OP_DIV]",
        "solution_abst_en": "315 9 [OP_DIV] 7 [OP_DIV]",
        "solution_code_ko": "var_a = 315\nvar_b = 9\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 315\nvar_b = 9\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "2221": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 3을 두번 곱하였더니 18이 되었다. 어떤 수를 구하시오.",
        "question_en": "When a number is multiplied by 3 twice, it is 18. Find the number.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "18 3 [OP_DIV] 3 [OP_DIV]",
        "solution_abst_en": "18 3 [OP_DIV] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 18\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 18\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "2222": {
        "category": "Comparison",
        "question_ko": "귤나무 A, B, C, D가 있습니다. A는 D보다 귤이 많이 달렸고, D는 C보다 귤이 많이 달렸습니다. B는 A보다 귤이 많이 달렸을 때, 가장 많은 귤이 달려있는 귤나무는 무엇일까요?",
        "question_en": "There are tangerine trees (a), (b), (c), and (d). (a) has more tangerines than (d), and (d) has more tangerines than (c). If (b) has more tangerines than (a), which tangerine tree has the most tangerines?",
        "answer_ko": "B",
        "answer_en": "(b)",
        "solution_abst_ko": "[OP_LIST_SOL] A B C D [OP_LIST_EOL] [OP_LIST_SOL] A D > D C > B A > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (a) (b) (c) (d) [OP_LIST_EOL] [OP_LIST_SOL] (a) (d) > (d) (c) > (b) (a) > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'A'\nvar_f = 'D'\nvar_g = '>'\nvar_h = 'D'\nvar_i = 'C'\nvar_j = '>'\nvar_k = 'B'\nvar_l = 'A'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = 1\nvar_o = list_c[var_n-1]\nprint(var_o)",
        "solution_code_en": "var_a = '(a)'\nvar_b = '(b)'\nvar_c = '(c)'\nvar_d = '(d)'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '(a)'\nvar_f = '(d)'\nvar_g = '>'\nvar_h = '(d)'\nvar_i = '(c)'\nvar_j = '>'\nvar_k = '(b)'\nvar_l = '(a)'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = 1\nvar_o = list_c[var_n-1]\nprint(var_o)"
    },
    "2223": {
        "category": "Correspondence",
        "question_ko": "632-5AB=41입니다. B는 얼마인가요?",
        "question_en": "632-5AB=41. How much is B?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "632-5AB=41 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "632-5AB=41 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '632-5AB=41'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '632-5AB=41'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "2224": {
        "category": "Possibility",
        "question_ko": "도훈이는 찬구와 찬희와 숫자 게임을 하고 있습니다. 자신이 가진 숫자 카드를 모두 이용해 만든 숫자 크기대로 등수가 매겨지는 게임으로, 도훈이는 3, 9, 8을 가지고 있습니다. 찬구는 850을, 찬희는 920을 만들었을 때 도훈이가 2등을 하는 경우는 몇 가지 입니까?",
        "question_en": "Dohun is playing a numbers game with Changu and Chanhee. It is a game in which ranks are ranked according to the size of the number made using all the number-written cards you have, and Dohun has numbers of 3, 9, and 8. When Changu made 850 and Chanhee made 920, what is the number of cases in which Dohun rank in second place?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 3 9 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 850 [OP_LIST_MORE] 920 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 3 9 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 850 [OP_LIST_MORE] 920 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 3\nvar_b = 9\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 850\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = 920\nlist_d = []\nfor i in list_c:\n    if i < var_f:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))",
        "solution_code_en": "var_a = 3\nvar_b = 9\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 850\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = 920\nlist_d = []\nfor i in list_c:\n    if i < var_f:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))"
    },
    "2225": {
        "category": "Correspondence",
        "question_ko": "9A6-BB=BBB고, A와 B는 같은 숫자가 아닙니다. A와 B를 더한 값을 구하시오.",
        "question_en": "9A6-BB=BBB is true and A and B are not the same numbers. Find the sum of A and B.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "9A6-BB=BBB A [OP_DIGIT_UNK_SOLVER] 9A6-BB=BBB B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_abst_en": "9A6-BB=BBB A [OP_DIGIT_UNK_SOLVER] 9A6-BB=BBB B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_code_ko": "var_a = '9A6-BB=BBB'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '9A6-BB=BBB'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = '9A6-BB=BBB'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '9A6-BB=BBB'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "2226": {
        "category": "Geometry",
        "question_ko": "둘레에 놓인 동전의 개수가 36개가 되도록 크기가 같은 동전을 빈틈없이 늘어놓아 정사각형을 만들었습니다. 가장 바깥쪽의 한 변에 놓인 동전의 개수를 구하시오.",
        "question_en": "Coins of the same size are arranged without gaps to form a square so that there are 36 coins placed around the perimeter. Find the number of coins lying on the outermost of one side.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "36 4 [OP_DIV] 1 [OP_ADD]",
        "solution_abst_en": "36 4 [OP_DIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 36\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 36\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "2227": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 4센티미터(㎝)이고, 넓이가 25/2제곱센티미터(㎠)인 직사각형이 있습니다. 이 직사각형의 변 중에서 길이가 4센티미터(㎝)가 아닌 변의 길이는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "A rectangle has a side length of 4 centimeters (cm) and an area of 25/2 square centimeters (cm2). Find the length in centimeters (cm) of the side of this rectangle that is not 4 centimeters (cm) long.",
        "answer_ko": "3.13",
        "answer_en": "3.13",
        "solution_abst_ko": "25/2 4 [OP_DIV]",
        "solution_abst_en": "25/2 4 [OP_DIV]",
        "solution_code_ko": "var_a = 12.5\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 12.5\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "2228": {
        "category": "Possibility",
        "question_ko": "빨간색 옷, 파란색 옷, 검정색 옷을 판매하는 옷가게가 있다. 옷 2벌을 구매할 때 중복을 허용하여 선택가능한 모든 방법의 수를 구하시오.",
        "question_en": "There is a clothing store that sells red, blue and black clothes. When purchasing two sets of clothes, find the number of all possible choices, allowing duplicates.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 빨간색 파란색 검정색 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] red blue black [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '빨간색'\nvar_b = '파란색'\nvar_c = '검정색'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = var_d + var_e\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = 2\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j / (i+1)\nprint(int(var_j))",
        "solution_code_en": "var_a = 'red'\nvar_b = 'blue'\nvar_c = 'black'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = var_d + var_e\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = 2\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j / (i+1)\nprint(int(var_j))"
    },
    "2229": {
        "category": "Arithmetic calculation",
        "question_ko": "50보다 크고 100보다 작은 수 중에서 8로 나누어 떨어지지 않고 나머지가 4인 수는 모두 몇 개입니까?",
        "question_en": "How many numbers greater than 50 and less than 100 are not divisible by 8 and have a remainder of 4?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "50 1 [OP_ADD] 100 1 [OP_SUB] 1 [OP_LIST_ARANGE] 8 4 [OP_LIST_DIVIDE_AND_REMAIN] [OP_LIST_LEN]",
        "solution_abst_en": "50 1 [OP_ADD] 100 1 [OP_SUB] 1 [OP_LIST_ARANGE] 8 4 [OP_LIST_DIVIDE_AND_REMAIN] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 50\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 100\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = 8\nvar_i = 4\nlist_b = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_a:\n    i = int(i)\n    if i%var_h == var_i:\n        list_b.append(i)\nvar_j = len(list_b)\nprint(int(var_j))",
        "solution_code_en": "var_a = 50\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 100\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = 8\nvar_i = 4\nlist_b = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_a:\n    i = int(i)\n    if i%var_h == var_i:\n        list_b.append(i)\nvar_j = len(list_b)\nprint(int(var_j))"
    },
    "2230": {
        "category": "Correspondence",
        "question_ko": "어떤 수와 6의 곱에 17을 더한 수를 5로 나누었더니 25가 되었습니다. 어떤 수를 구하세요.",
        "question_en": "A number multiplied by 6 plus 17 divided by 5 equals 25. Find the number.",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "25 5 [OP_MUL] 17 [OP_SUB] 6 [OP_DIV]",
        "solution_abst_en": "25 5 [OP_MUL] 17 [OP_SUB] 6 [OP_DIV]",
        "solution_code_ko": "var_a = 25\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 17\nvar_e = var_c - var_d\nvar_f = 6\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 25\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 17\nvar_e = var_c - var_d\nvar_f = 6\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "2231": {
        "category": "Arithmetic calculation",
        "question_ko": "체육 시간에 멀리 뛰기를 한 결과, 은설이의 기록은 1미터(m) 35센티미터(㎝)가 나왔고, 정연이는 은설이보다 9센티미터(㎝)를 더 뛰었습니다. 정연이의 멀리 뛰기 기록은 몇 미터(m)인지 소수로 나타내시오.",
        "question_en": "As a result of the long jump in PE class, Eunseol's record was 1 meter (m) 35 centimeters (cm), and Jeongyeon jumped 9 centimeters (cm) more than Eunseol. How many meters (m) was Jeongyeon's long jump record as a decimal number?",
        "answer_ko": "1.44",
        "answer_en": "1.44",
        "solution_abst_ko": "1 35 100 [OP_DIV] [OP_ADD] 9 100 [OP_DIV] [OP_ADD]",
        "solution_abst_en": "1 35 100 [OP_DIV] [OP_ADD] 9 100 [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 35\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 9\nvar_g = 100\nvar_h = var_f / var_g\nvar_i = var_e + var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 35\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 9\nvar_g = 100\nvar_h = var_f / var_g\nvar_i = var_e + var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "2232": {
        "category": "Arithmetic calculation",
        "question_ko": "40 초과 70 이하인 자연수는 모두 몇 개입니까?",
        "question_en": "How many natural numbers are greater than 40 and less than or equal to 70?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "70 40 [OP_SUB]",
        "solution_abst_en": "70 40 [OP_SUB]",
        "solution_code_ko": "var_a = 70\nvar_b = 40\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 70\nvar_b = 40\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "2233": {
        "category": "Comparison",
        "question_ko": "블루베리청 3과 2/6 큰 술과 자몽청 21/6 큰 술로 케이크를 만들었습니다. 어떤 것이 케이크에 더 많이 포함되어 있는지 구하시오.",
        "question_en": "I made a cake with 3 and 2/6 tablespoons of blueberry syrup and 21/6 tablespoons of grapefruit syrup. Find which one is contained more in the cake.",
        "answer_ko": "자몽청",
        "answer_en": "grapefruit",
        "solution_abst_ko": "[OP_LIST_SOL] 블루베리청 자몽청 [OP_LIST_EOL] [OP_LIST_SOL] 3 2 6 [OP_DIV] [OP_ADD] 21 6 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] blueberry grapefruit [OP_LIST_EOL] [OP_LIST_SOL] 3 2 6 [OP_DIV] [OP_ADD] 21 6 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '블루베리청'\nvar_b = '자몽청'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nvar_d = 2\nvar_e = 6\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nvar_h = 21\nvar_i = 6\nvar_j = var_h / var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'blueberry'\nvar_b = 'grapefruit'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nvar_d = 2\nvar_e = 6\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nvar_h = 21\nvar_i = 6\nvar_j = var_h / var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "2234": {
        "category": "Geometry",
        "question_ko": "모든 모서리의 길이의 합이 132센티미터(㎝)인 정육면체가 있습니다. 이 정육면체의 한 면의 넓이는 몇 제곱센티미터입니까?",
        "question_en": "There is a cube with the sum of the lengths of all its edges equal to 132 centimeters (cm). What is the area of one side of this cube in square centimeters (cm2)?",
        "answer_ko": "121",
        "answer_en": "121",
        "solution_abst_ko": "132 12 [OP_DIV] 132 12 [OP_DIV] [OP_MUL]",
        "solution_abst_en": "132 12 [OP_DIV] 132 12 [OP_DIV] [OP_MUL]",
        "solution_code_ko": "var_a = 132\nvar_b = 12\nvar_c = var_a / var_b\nvar_d = 132\nvar_e = 12\nvar_f = var_d / var_e\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 132\nvar_b = 12\nvar_c = var_a / var_b\nvar_d = 132\nvar_e = 12\nvar_f = var_d / var_e\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "2235": {
        "category": "Arithmetic calculation",
        "question_ko": "사과 32개를 7개의 상자에 나누어 담았더니 4개의 사과가 남았습니다. 한 상자에 담긴 사과의 개수는 몇 개입니까?",
        "question_en": "32 apples were divided into 7 boxes, leaving 4 apples. How many apples are there in one box?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "32 4 [OP_SUB] 7 [OP_DIV]",
        "solution_abst_en": "32 4 [OP_SUB] 7 [OP_DIV]",
        "solution_code_ko": "var_a = 32\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 7\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 32\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 7\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "2236": {
        "category": "Correspondence",
        "question_ko": "81은 어떤 수에 43을 더한 숫자입니다. 어떤 수보다 25 큰 숫자는 얼마인가요?",
        "question_en": "81 is the result of adding 43 to some number. What number is 25 greater than this number?",
        "answer_ko": "63",
        "answer_en": "63",
        "solution_abst_ko": "81 43 [OP_SUB] 25 [OP_ADD]",
        "solution_abst_en": "81 43 [OP_SUB] 25 [OP_ADD]",
        "solution_code_ko": "var_a = 81\nvar_b = 43\nvar_c = var_a - var_b\nvar_d = 25\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 81\nvar_b = 43\nvar_c = var_a - var_b\nvar_d = 25\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "2237": {
        "category": "Comparison",
        "question_ko": "학교와 공원 사이의 거리가 396미터(m)이고, 학교와 약국 사이의 거리가 0.389킬로미터(㎞)라고 할 때, 공원과 약국 중 학교와 더 가까운 곳을 구하시오.",
        "question_en": "Assuming that the distance between the school and the park is 396 meters (m) and the distance between the school and the pharmacy is 0.389 kilometers (km), find the one closer to the school between the park and the pharmacy.",
        "answer_ko": "약국",
        "answer_en": "pharmacy",
        "solution_abst_ko": "[OP_LIST_SOL] 공원 약국 [OP_LIST_EOL] [OP_LIST_SOL] 396 0.389 1000 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] park pharmacy [OP_LIST_EOL] [OP_LIST_SOL] 396 0.389 1000 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '공원'\nvar_b = '약국'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 396\nvar_d = 0.389\nvar_e = 1000\nvar_f = var_d * var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'park'\nvar_b = 'pharmacy'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 396\nvar_d = 0.389\nvar_e = 1000\nvar_f = var_d * var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "2238": {
        "category": "Geometry",
        "question_ko": "한 대각선의 길이가 12미터(m)인 정사각형이 있습니다. 이 정사각형의 넓이는?",
        "question_en": "Find the area of a square whose diagonal is 12 centimeters (cm).",
        "answer_ko": "72",
        "answer_en": "72",
        "solution_abst_ko": "12 2 [OP_POW] 2 [OP_DIV]",
        "solution_abst_en": "12 2 [OP_POW] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "2239": {
        "category": "Correspondence",
        "question_ko": "-0.4의 역수가 A이고 +5/2의 역수가 B이면 3/A + 2/B의 역수를 찾으십시오.",
        "question_en": "If the reciprocal of -0.4 is A and the reciprocal of +5/2 is B, find the reciprocal of 3/A + 2/B.",
        "answer_ko": "0.26",
        "answer_en": "0.26",
        "solution_abst_ko": "1 3 1 -0.4 [OP_DIV] [OP_DIV] 2 1 5/2 [OP_DIV] [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_abst_en": "1 3 1 -0.4 [OP_DIV] [OP_DIV] 2 1 5/2 [OP_DIV] [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 1\nvar_d = -0.4\nvar_e = var_c / var_d\nvar_f = var_b / var_e\nvar_g = 2\nvar_h = 1\nvar_i = 2.5\nvar_j = var_h / var_i\nvar_k = var_g / var_j\nvar_l = var_f + var_k\nvar_m = var_a / var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 1\nvar_d = -0.4\nvar_e = var_c / var_d\nvar_f = var_b / var_e\nvar_g = 2\nvar_h = 1\nvar_i = 2.5\nvar_j = var_h / var_i\nvar_k = var_g / var_j\nvar_l = var_f + var_k\nvar_m = var_a / var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))"
    },
    "2240": {
        "category": "Comparison",
        "question_ko": "정수는 구슬 28개를 주머니 4개에 똑같이 나누어 담았고, 현주는 구슬 18개를 주머니 3개에 똑같이 나누어 담았습니다. 정수와 현주 중에서 주머니 한 개에 들어 있는 구슬이 더 적은 사람은 누구입니까?",
        "question_en": "Jungsoo put 28 marbles equally divided into 4 bags, and Hyeonju put 18 marbles equally divided into 3 bags. Who has fewer marbles in one bag, Jungsoo or Hyeonju?",
        "answer_ko": "현주",
        "answer_en": "Hyeonju",
        "solution_abst_ko": "[OP_LIST_SOL] 정수 현주 [OP_LIST_EOL] [OP_LIST_SOL] 28 4 [OP_DIV] 18 3 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungsoo Hyeonju [OP_LIST_EOL] [OP_LIST_SOL] 28 4 [OP_DIV] 18 3 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정수'\nvar_b = '현주'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 28\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 18\nvar_g = 3\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Jungsoo'\nvar_b = 'Hyeonju'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 28\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 18\nvar_g = 3\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "2241": {
        "category": "Comparison",
        "question_ko": "총 3개의 숫자 0.8, 1/2, 0.5이 있습니다. 이 중 2보다 작은 수를 모두 더하면 얼마인가요?",
        "question_en": "There are a total of three numbers: 0.8, 1/2, and 0.5. What is the sum of all numbers less than 2?",
        "answer_ko": "1.80",
        "answer_en": "1.8",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.5 [OP_LIST_EOL] 2 [OP_LIST_LESS] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.5 [OP_LIST_EOL] 2 [OP_LIST_LESS] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = []\nfor i in list_a:\n    if i < var_d:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = []\nfor i in list_a:\n    if i < var_d:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "2242": {
        "category": "Arithmetic calculation",
        "question_ko": "사탕을 민영이는 9개, 태형이는 3개 가지고 있습니다. 민영이와 태형이가 가지고 있는 사탕의 수가 같아지려면 민영이는 태형이에게 사탕을 몇 개 주어야 합니까?",
        "question_en": "Minyoung has 9 candies and Taehyung has 3. How many candies must Minyoung give to Taehyung so that Minyoung and Taehyung have the same number of candies?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "9 3 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "9 3 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 9\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "2243": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 3인 정사각형 4개의 넓이가 어떤 원의 넓이와 같을 때, 원의 반지름의 길이를 구하시오. (단, 원주율은 3.1로 계산한다)",
        "question_en": "If the volume of 4 squares with side length 3 is equal to the volume of a circle, find the length of the radius of the circle. (Note that the pi is calculated as 3.1)",
        "answer_ko": "3.41",
        "answer_en": "3.41",
        "solution_abst_ko": "4 3 2 [OP_POW] [OP_MUL] 3.1 [OP_DIV] 1/2 [OP_POW]",
        "solution_abst_en": "4 3 2 [OP_POW] [OP_MUL] 3.1 [OP_DIV] 1/2 [OP_POW]",
        "solution_code_ko": "var_a = 4\nvar_b = 3\nvar_c = 2\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 3.1\nvar_g = var_e / var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 4\nvar_b = 3\nvar_c = 2\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 3.1\nvar_g = var_e / var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "2244": {
        "category": "Geometry",
        "question_ko": "가로가 12센티미터(㎝), 세로가 15센티미터(㎝)인 직사각형 모양의 타일을 겹치지 않게 늘어놓아 최대한 작은 정사각형을 만들려고 합니다. 타일은 모두 몇 장 필요할까요?",
        "question_en": "I'm trying to make a square as small as possible by arranging rectangular tiles that are 12 centimeters (cm) wide and 15 centimeters (cm) tall without any overlap. How many tiles will you need in total?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "12 15 [OP_LCM] 2 [OP_POW] 12 15 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "12 15 [OP_LCM] 2 [OP_POW] 12 15 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 15\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 12\nvar_g = 15\nvar_h = var_f * var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 12\nvar_b = 15\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 12\nvar_g = 15\nvar_h = var_f * var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "2245": {
        "category": "Arithmetic calculation",
        "question_ko": "40 초과 80 미만인 수 중에서 8의 배수에 해당되는 수는 모두 몇 개입니까?",
        "question_en": "How many numbers are there greater than 40 and less than 80 are multiples of 8?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "40 1 [OP_ADD] 80 1 [OP_SUB] 1 [OP_LIST_ARANGE] 8 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "40 1 [OP_ADD] 80 1 [OP_SUB] 1 [OP_LIST_ARANGE] 8 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 40\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 80\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = 8\nlist_b = []\nvar_h = int(var_h)\nfor i in list_a:\n    i = int(i)\n    if i % var_h == 0:\n        list_b.append(i)\nvar_i = len(list_b)\nprint(int(var_i))",
        "solution_code_en": "var_a = 40\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 80\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = 8\nlist_b = []\nvar_h = int(var_h)\nfor i in list_a:\n    i = int(i)\n    if i % var_h == 0:\n        list_b.append(i)\nvar_i = len(list_b)\nprint(int(var_i))"
    },
    "2246": {
        "category": "Correspondence",
        "question_ko": "한 자리 수 A가 있습니다. 나눗셈 9A5÷5<197가 있을 때 A가 될 수 있는 수의 개수를 구하시오.",
        "question_en": "I have a single digit A. If division 9A5÷5<197, count all possible numbers that can be A.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "9A5÷5<197 A [OP_DIGIT_UNK_SOLVER] [OP_LIST_LEN]",
        "solution_abst_en": "9A5÷5<197 A [OP_DIGIT_UNK_SOLVER] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '9A5÷5<197'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = len(list_a)\nprint(int(var_c))",
        "solution_code_en": "var_a = '9A5÷5<197'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = len(list_a)\nprint(int(var_c))"
    },
    "2247": {
        "category": "Arithmetic calculation",
        "question_ko": "민수네 반 학생은 8명이고, 진호네 반 학생은 민수네 반 보다 한 명이 많다. 길이가 3.944미터(m)인 리본에서 때어네 민수네 반 학생들에게 29.05센티미터(㎝)씩 나눠주었다. 그 이후 남은 리본을 진호네 반 학생들에게 동일하게 잘라서 나눠 주었다면, 진호가 받은 리본은 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "There are 8 students in Minsu's class, and Jinho's class has one more student than Minsu's class. From 3.944 meters (m) of ribbon, 29.05 centimeters (cm) were divided to each student in Minsu's class. After that, if you cut and distribute the remaining ribbons equally to Jinho's classmates, find how many centimeters (cm) of ribbons Jinho received.",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "3.944 100 [OP_MUL] 29.05 8 [OP_MUL] [OP_SUB] 8 1 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "3.944 100 [OP_MUL] 29.05 8 [OP_MUL] [OP_SUB] 8 1 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 3.944\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 29.05\nvar_e = 8\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 8\nvar_i = 1\nvar_j = var_h + var_i\nvar_k = var_g / var_j\nprint(int(eval('{:.2f}'.format(round(var_k+1e-10,2)))))",
        "solution_code_en": "var_a = 3.944\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 29.05\nvar_e = 8\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 8\nvar_i = 1\nvar_j = var_h + var_i\nvar_k = var_g / var_j\nprint(int(eval('{:.2f}'.format(round(var_k+1e-10,2)))))"
    },
    "2248": {
        "category": "Comparison",
        "question_ko": "학교에서 국어, 사회, 수학, 영어, 과학의 순서로 시험을 봤습니다. 3번째로 시험을 본 과목은 무엇입니까?",
        "question_en": "At school, you took exams in the order of Korean, Social, Mathematics, English, and Science. What subject did you take the test for the third time?",
        "answer_ko": "수학",
        "answer_en": "Mathematics",
        "solution_abst_ko": "[OP_LIST_SOL] 국어 사회 수학 영어 과학 [OP_LIST_EOL] 3 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Korean Social Mathematics English Science [OP_LIST_EOL] 3 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '국어'\nvar_b = '사회'\nvar_c = '수학'\nvar_d = '영어'\nvar_e = '과학'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nvar_g = list_a[var_f-1]\nprint(var_g)",
        "solution_code_en": "var_a = 'Korean'\nvar_b = 'Social'\nvar_c = 'Mathematics'\nvar_d = 'English'\nvar_e = 'Science'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nvar_g = list_a[var_f-1]\nprint(var_g)"
    },
    "2249": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 소수의 소수점을 오른쪽으로 한 자리 옮기면 원래보다 2.7만큼 커집니다. 원래의 소수를 구하시오.",
        "question_en": "Moving a decimal point to the right by one place makes a some number to become 2.7 larger than it originally was. Find the original decimal number.",
        "answer_ko": "0.30",
        "answer_en": "0.3",
        "solution_abst_ko": "2.7 10 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "2.7 10 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 2.7\nvar_b = 10\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 2.7\nvar_b = 10\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "2250": {
        "category": "Comparison",
        "question_ko": "선생님이 윤기, 지민, 태형이에게 사탕을 나눠줬습니다. 윤기는 태형이보다 많은 사탕을 받았고, 태형이는 지민이보다 많은 사탕을 받았다면 가장 적은 사탕을 받은 학생은 누구인가요?",
        "question_en": "The teacher gave candy to Yoongi, Jimin, and Taehyung. If Yoongi got more candies than Taehyung and Taehyung got more candies than Jimin, who got the fewest candies?",
        "answer_ko": "지민",
        "answer_en": "Jimin",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 지민 태형 [OP_LIST_EOL] [OP_LIST_SOL] 윤기 태형 > 태형 지민 > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jimin Taehyung [OP_LIST_EOL] [OP_LIST_SOL] Yoongi Taehyung > Taehyung Jimin > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '지민'\nvar_c = '태형'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '윤기'\nvar_e = '태형'\nvar_f = '>'\nvar_g = '태형'\nvar_h = '지민'\nvar_i = '>'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = len(list_c)\nvar_k = list_c[var_j-1]\nprint(var_k)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jimin'\nvar_c = 'Taehyung'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'Yoongi'\nvar_e = 'Taehyung'\nvar_f = '>'\nvar_g = 'Taehyung'\nvar_h = 'Jimin'\nvar_i = '>'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = len(list_c)\nvar_k = list_c[var_j-1]\nprint(var_k)"
    },
    "2251": {
        "category": "Correspondence",
        "question_ko": "1A+4B3=469라는 식이 성립하려면, B에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "What number must be in B to make 1A+4B3=469?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "1A+4B3=469 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "1A+4B3=469 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '1A+4B3=469'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '1A+4B3=469'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "2252": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 초등학교의 학생 수는 1256명입니다. 이 중에서 수학을 좋아하는 학생과 기타 과목을 좋아하는 학생 수의 차는 408명입니다. 수학을 좋아하는 학생은 몇 명입니까? (단, 수학을 좋아하는 학생은 500명보다 작습니다.)",
        "question_en": "An elementary school has 1256 students. Of these, the difference between the number of students who like math and those who like other subjects is 408. How many students like math? (However, students who like math are fewer than 500.)",
        "answer_ko": "424",
        "answer_en": "424",
        "solution_abst_ko": "1256 408 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "1256 408 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 1256\nvar_b = 408\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 1256\nvar_b = 408\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "2253": {
        "category": "Comparison",
        "question_ko": "둘레의 길이가 더 긴 도형을 고르려고 합니다. 한 변의 길이가 3센티미터(cm)인 정사각형과 한 변의 길이가 5센티미터(cm)인 정삼각형이 있을 때 어떤 도형의 둘레가 더 깁니까?",
        "question_en": "You want to choose a figure with a longer perimeter. Given a square whose side is 3 centimeters (cm) and an equilateral-triangle whose side is 5 centimeters (cm), which shape has a longer perimeter?",
        "answer_ko": "정삼각형",
        "answer_en": "equilateral-triangle",
        "solution_abst_ko": "[OP_LIST_SOL] 정사각형 정삼각형 [OP_LIST_EOL] [OP_LIST_SOL] 3 4 [OP_MUL] 5 3 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] square equilateral-triangle [OP_LIST_EOL] [OP_LIST_SOL] 3 4 [OP_MUL] 5 3 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정사각형'\nvar_b = '정삼각형'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nvar_d = 4\nvar_e = var_c * var_d\nvar_f = 5\nvar_g = 3\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'square'\nvar_b = 'equilateral-triangle'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nvar_d = 4\nvar_e = var_c * var_d\nvar_f = 5\nvar_g = 3\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "2254": {
        "category": "Geometry",
        "question_ko": "같은 크기의 정사각형 6개로 이루어진 도형의 모든 모서리의 합이 144센티미터(㎝)라면, 정사각형의 한 변의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "If the sum of all the edges of a polyhedron made of 6 equal-sized squares is 144 centimeters (cm), what is the length of one side of the square in centimeters (cm)?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "144 12 [OP_DIV]",
        "solution_abst_en": "144 12 [OP_DIV]",
        "solution_code_ko": "var_a = 144\nvar_b = 12\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 144\nvar_b = 12\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "2255": {
        "category": "Arithmetic calculation",
        "question_ko": "12개의 구슬을 동생에게 주고 언니에게는 5개의 구슬을 받았습니다. 이후 구슬의 절반을 남준이에게 주고 윤기에게 3개를 받았더니 현재 가지고 있는 구슬의 수가 17개가 되었습니다. 처음에 유나가 가지고 있던 구슬은 몇 개입니까?",
        "question_en": "Yuna gave 12 marbles to her younger brother and got 5 marbles to her sister. After that, Yuna gave half of the marbles to Namjoon and received 3 from Yoongi, so the number of marbles She currently have is 17. How many marbles did Yuna have in the first place?",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "17 3 [OP_SUB] 2 [OP_MUL] 5 [OP_SUB] 12 [OP_ADD]",
        "solution_abst_en": "17 3 [OP_SUB] 2 [OP_MUL] 5 [OP_SUB] 12 [OP_ADD]",
        "solution_code_ko": "var_a = 17\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 5\nvar_g = var_e - var_f\nvar_h = 12\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 17\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 5\nvar_g = var_e - var_f\nvar_h = 12\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "2256": {
        "category": "Comparison",
        "question_ko": "유리는 식당에서 떡볶이 6접시를 먹었고, 지수는 8접시를 먹었습니다. 태형이는 유리보다는 많이 먹었고 지수보다는 적게 먹었습니다. 태형이는 떡볶이를 몇 접시 먹었겠습니까?",
        "question_en": "Yuri ate 6 plates of tteokbokki at the restaurant, and Jisoo ate 8 plates. Taehyung ate more than Yuri and less than Jisoo. How many plates of tteokbokki did Taehyung eat?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "6 8 [OP_ADD] 2 [OP_FDIV]",
        "solution_abst_en": "6 8 [OP_ADD] 2 [OP_FDIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "2257": {
        "category": "Arithmetic calculation",
        "question_ko": "현우네 가족은 하루에 물을 215리터(L) 사용합니다. 수압 밸브를 약하게 조절하면 평소 사용량의 0.32 배만큼 아낄 수 있습니다. 수압 밸브를 약하게 조절했을 때 현우네 가족이 하루 동안 아낄 수 있는 물은 몇 리터(L) 입니까?",
        "question_en": "Hyunwoo's family uses 215 liters (L) of water a day. If they adjust the water pressure valve weakly, they can save as much as 0.32 times the usual amount. How many liters (L) of water can Hyunwoo's family save in a day when the water pressure valve is adjusted weakly?",
        "answer_ko": "68.80",
        "answer_en": "68.8",
        "solution_abst_ko": "215 0.32 [OP_MUL]",
        "solution_abst_en": "215 0.32 [OP_MUL]",
        "solution_code_ko": "var_a = 215\nvar_b = 0.32\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 215\nvar_b = 0.32\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "2258": {
        "category": "Correspondence",
        "question_ko": "사탕을 6개, 9개씩 포장하면 남는 것이 없고, 7개씩 포장하면 1개가 남는다. 사탕이 11이상 100이하의 자연수일때 사탕의 개수가 몇 개인지 구하시오.",
        "question_en": "If you pack 6 or 9 candies, you will have nothing left, and if you pack 7 candies, you will have 1 candy left. If the number of candies is a natural number between 11 and 100, how many candies are there?",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "10 100 1 [OP_LIST_ARANGE] 6 9 [OP_LCM] 0 [OP_LIST_DIVIDE_AND_REMAIN] 7 1 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "10 100 1 [OP_LIST_ARANGE] 6 9 [OP_LCM] 0 [OP_LIST_DIVIDE_AND_REMAIN] 7 1 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 10\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nvar_e = 9\nvar_f = var_e * var_d / math.gcd(int(var_e), int(var_d))\nvar_g = 0\nlist_b = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_a:\n    i = int(i)\n    if i%var_f == var_g:\n        list_b.append(i)\nvar_h = 7\nvar_i = 1\nlist_c = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_b:\n    i = int(i)\n    if i%var_h == var_i:\n        list_c.append(i)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(int(var_k))",
        "solution_code_en": "var_a = 10\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nvar_e = 9\nvar_f = var_e * var_d / math.gcd(int(var_e), int(var_d))\nvar_g = 0\nlist_b = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_a:\n    i = int(i)\n    if i%var_f == var_g:\n        list_b.append(i)\nvar_h = 7\nvar_i = 1\nlist_c = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_b:\n    i = int(i)\n    if i%var_h == var_i:\n        list_c.append(i)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(int(var_k))"
    },
    "2259": {
        "category": "Geometry",
        "question_ko": "팔각형이 있을 때 한 꼭짓점에서 대각선을 그었습니다. 이때 생기는 모든 삼각형의 개수를 구하시오.",
        "question_en": "You drew diagonals from one vertex of an octagon. Find the number of triangles formed in this case.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "8 3 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "8 3 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "2260": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 1000까지의 자연수 중 십의 자리 숫자가 3인 수는 몇 개입니까?",
        "question_en": "How many natural numbers from 1 to 1000 have 3 in the tens place?",
        "answer_ko": "100",
        "answer_en": "100",
        "solution_abst_ko": "1 1000 1 [OP_LIST_ARANGE] 10 3 [OP_LIST_SEARCH_FIXED_DIGIT] [OP_LIST_LEN]",
        "solution_abst_en": "1 1000 1 [OP_LIST_ARANGE] 10 3 [OP_LIST_SEARCH_FIXED_DIGIT] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 1000\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 10\nvar_e = 3\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i in list_a:\n    i = int(i)\n    if (i//var_d)%10 == var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 1000\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 10\nvar_e = 3\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i in list_a:\n    i = int(i)\n    if (i//var_d)%10 == var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "2261": {
        "category": "Comparison",
        "question_ko": "두 수 중 작은 수에 30을 더하고 4를 곱하면, 큰 수가 나옵니다. 이 두 수의 차는 480일 때, 큰 수는 얼마입니까?",
        "question_en": "There are two numbers. When you add 30 to the smaller numbers and multiply it by 4, you get the larger number. If the difference between these two numbers is 480, what is the larger number?",
        "answer_ko": "600",
        "answer_en": "600",
        "solution_abst_ko": "480 30 4 [OP_MUL] [OP_SUB] 4 1 [OP_SUB] [OP_DIV] 30 [OP_ADD] 4 [OP_MUL]",
        "solution_abst_en": "480 30 4 [OP_MUL] [OP_SUB] 4 1 [OP_SUB] [OP_DIV] 30 [OP_ADD] 4 [OP_MUL]",
        "solution_code_ko": "var_a = 480\nvar_b = 30\nvar_c = 4\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 4\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 30\nvar_k = var_i + var_j\nvar_l = 4\nvar_m = var_k * var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 480\nvar_b = 30\nvar_c = 4\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 4\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 30\nvar_k = var_i + var_j\nvar_l = 4\nvar_m = var_k * var_l\nprint(int(var_m))"
    },
    "2262": {
        "category": "Correspondence",
        "question_ko": "632-5AB=41일 때, B에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "When 632-5AB=41, what number should be in B?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "632-5AB=41 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "632-5AB=41 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '632-5AB=41'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '632-5AB=41'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "2263": {
        "category": "Geometry",
        "question_ko": "다섯 개의 점 A, B, C, D, E 중 네 점 B, C, D, E는 일직선에 위에 있을 때, 이 중 두 점을 연결하여 만들 수 있는 직선의 개수는?",
        "question_en": "If four points B, C, D, and E of the five points A, B, C, D, and E are on a straight line, how many straight lines can be formed by connecting these two points?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "4 1 [OP_ADD]",
        "solution_abst_en": "4 1 [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "2264": {
        "category": "Possibility",
        "question_ko": "숫자 7, 2, 3, 4, 9를 사용하여 다섯 자리 수를 만들려고 합니다. 만들 수 있는 다섯 자리 수는 모두 몇 개입니까? 같은 숫자는 여러 번 등장할 수 있습니다.",
        "question_en": "You want to create a five-digit number using the numbers 7, 2, 3, 4, and 9. How many five-digit numbers can you make? The same number can appear multiple times.",
        "answer_ko": "3125",
        "answer_en": "3125",
        "solution_abst_ko": "[OP_LIST_SOL] 7 2 3 4 9 [OP_LIST_EOL] 5 [OP_LIST_GET_PRODUCT] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 7 2 3 4 9 [OP_LIST_EOL] 5 [OP_LIST_GET_PRODUCT] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 7\nvar_b = 2\nvar_c = 3\nvar_d = 4\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 5\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 7\nvar_b = 2\nvar_c = 3\nvar_d = 4\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 5\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "2265": {
        "category": "Possibility",
        "question_ko": "1에서 4까지의 숫자가 각각 적힌 4장의 카드에서 3장을 뽑아 만들 수 있는 세 자리 정수의 개수는?",
        "question_en": "How many three-digit integers can be made by drawing 3 cards from 1 through 4?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "4 3 [OP_PERM]",
        "solution_abst_en": "4 3 [OP_PERM]",
        "solution_code_ko": "var_a = 4\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))"
    },
    "2266": {
        "category": "Correspondence",
        "question_ko": "20에 어떤 수를 곱하려고 합니다. 잘못하여 10에 어떤 수를 나눴더니 결과는 5가 되었습니다. 바르게 계산한 결과는 얼마일까요?",
        "question_en": "You want to multiply 20 by some number. But you mistakenly divided a number by 10, and the result was 5. What is the correct calculation result?",
        "answer_ko": "40",
        "answer_en": "40",
        "solution_abst_ko": "20 10 5 [OP_DIV] [OP_MUL]",
        "solution_abst_en": "20 10 5 [OP_DIV] [OP_MUL]",
        "solution_code_ko": "var_a = 20\nvar_b = 10\nvar_c = 5\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 10\nvar_c = 5\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nprint(int(var_e))"
    },
    "2267": {
        "category": "Geometry",
        "question_ko": "네 변의 길이를 더했을 때 60센티미터(㎝)인 마름모의 한 변은 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "Find how many centimeters (cm) per side of a rhombus is 60 centimeters (cm) when the lengths of the four sides are added.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "60 4 [OP_DIV]",
        "solution_abst_en": "60 4 [OP_DIV]",
        "solution_code_ko": "var_a = 60\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 60\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "2268": {
        "category": "Possibility",
        "question_ko": "1, 0, 7, 4, 5 중에서 3개를 뽑아 한 번씩만 사용하여 세 자리 수를 만들려고 합니다. 만들 수 있는 두 번째로 큰 수와 세 번째로 작은 수의 차를 구하시오.",
        "question_en": "You want to create a three-digit number by picking three of 1, 0, 7, 4, and 5 and using them only once. Find the difference between the second largest number and the third smallest number that can be made.",
        "answer_ko": "644",
        "answer_en": "644",
        "solution_abst_ko": "[OP_LIST_SOL] 1 0 7 4 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "[OP_LIST_SOL] 1 0 7 4 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 1\nvar_b = 0\nvar_c = 7\nvar_d = 4\nvar_e = 5\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h - var_j\nvar_l = abs(var_k)\nprint(int(var_l))",
        "solution_code_en": "var_a = 1\nvar_b = 0\nvar_c = 7\nvar_d = 4\nvar_e = 5\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h - var_j\nvar_l = abs(var_k)\nprint(int(var_l))"
    },
    "2269": {
        "category": "Geometry",
        "question_ko": "두 변의 길이가 8 센티미터(㎝), 10 센티미터(㎝)인 직사각형과 정사각형의 네 변의 길이의 합은 같습니다. 정사각형의 한 변의 길이는 몇 센티미터(㎝)일까요?",
        "question_en": "The sum of the lengths of the sides of a rectangle with sides of 8 centimeters (cm) and 10 centimeters (cm) and a square is equal. How many centimeters (cm) is the length of one side of the square?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "8 10 [OP_ADD] 2 [OP_MUL] 4 [OP_DIV]",
        "solution_abst_en": "8 10 [OP_ADD] 2 [OP_MUL] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 8\nvar_b = 10\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 8\nvar_b = 10\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "2270": {
        "category": "Comparison",
        "question_ko": "모래가 가득 들어있는 무게가 1킬로그램(㎏) 780그램(g)인 상자와 무게가 2킬로그램(㎏) 250그램(g)인 통이 있습니다. 상자의 무게는 250그램(g)이었으며, 통의 무게는 460그램(g)이었을 때, 상자와 통 중 어느 것에 들어 있는 모래가 더 무겁습니까?",
        "question_en": "There is a box full of sand weighing 1 kilogram (kg) 780 grams (g) and a barrel weighing 2 kilograms (kg) 250 grams (g). If the box weighs 250 grams (g) and the barrel weighs 460 grams (g), which contains more sand, the box or the barrel?",
        "answer_ko": "통",
        "answer_en": "barrel",
        "solution_abst_ko": "[OP_LIST_SOL] 상자 통 [OP_LIST_EOL] [OP_LIST_SOL] 1 1000 [OP_MUL] 780 [OP_ADD] 250 [OP_SUB] 2 1000 [OP_MUL] 250 [OP_ADD] 460 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] box barrel [OP_LIST_EOL] [OP_LIST_SOL] 1 1000 [OP_MUL] 780 [OP_ADD] 250 [OP_SUB] 2 1000 [OP_MUL] 250 [OP_ADD] 460 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '상자'\nvar_b = '통'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 780\nvar_g = var_e + var_f\nvar_h = 250\nvar_i = var_g - var_h\nvar_j = 2\nvar_k = 1000\nvar_l = var_j * var_k\nvar_m = 250\nvar_n = var_l + var_m\nvar_o = 460\nvar_p = var_n - var_o\nlist_b= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nlist_b.reverse()\nvar_q = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_r = list_c[-var_q]\nvar_s = list_b.index(var_r)+1\nvar_t = list_a[var_s-1]\nprint(var_t)",
        "solution_code_en": "var_a = 'box'\nvar_b = 'barrel'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 780\nvar_g = var_e + var_f\nvar_h = 250\nvar_i = var_g - var_h\nvar_j = 2\nvar_k = 1000\nvar_l = var_j * var_k\nvar_m = 250\nvar_n = var_l + var_m\nvar_o = 460\nvar_p = var_n - var_o\nlist_b= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nlist_b.reverse()\nvar_q = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_r = list_c[-var_q]\nvar_s = list_b.index(var_r)+1\nvar_t = list_a[var_s-1]\nprint(var_t)"
    },
    "2271": {
        "category": "Arithmetic calculation",
        "question_ko": "6명씩 팀을 만들어 게임을 하려고 합니다. 학생이 모두 72명이라면 몇 팀을 만들 수 있습니까?",
        "question_en": "You are trying to make a team of 6 people to play the game. How many teams can you make if there are 72 students in all?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "72 6 [OP_FDIV]",
        "solution_abst_en": "72 6 [OP_FDIV]",
        "solution_code_ko": "var_a = 72\nvar_b = 6\nvar_c = var_a // var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 72\nvar_b = 6\nvar_c = var_a // var_b\nprint(int(var_c))"
    },
    "2272": {
        "category": "Correspondence",
        "question_ko": "C보다 204작은 수는 A이고 A는 520이다. B에 179를 더하면 C가 될때 B를 구하여라.",
        "question_en": "The number that is 204 less than C is A, and A is 520. Calculate B when adding 179 to B equals C.",
        "answer_ko": "545",
        "answer_en": "545",
        "solution_abst_ko": "520 204 [OP_ADD] 179 [OP_SUB]",
        "solution_abst_en": "520 204 [OP_ADD] 179 [OP_SUB]",
        "solution_code_ko": "var_a = 520\nvar_b = 204\nvar_c = var_a + var_b\nvar_d = 179\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 520\nvar_b = 204\nvar_c = var_a + var_b\nvar_d = 179\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "2273": {
        "category": "Arithmetic calculation",
        "question_ko": "1학년 중 달리기 시합에 참가한 학생 수의 5배 만큼 2학년 학생이 달리기 시합에 참가하였습니다. 1학년 중에서 8명이 달리기 시합에 참가하였다면 달리기 시합에 참가한 1학년과 2학년 학생은 모두 몇 명입니까?",
        "question_en": "The second-year students participated in the running competition, which is five times the number of students who participated in the running competition among the first-year students participated in the running competition. If eight of the first graders participated in the race, how many first and second graders participated in the race?",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "8 8 5 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "8 8 5 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 8\nvar_c = 5\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 8\nvar_c = 5\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "2274": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 8을 빼고 12를 뺀 값을 5로 나눈 몫이 7이다. 어떤 수를 구하시오.",
        "question_en": "The quotient of a number subtracted by 8 and then subtracted by 12 and then divided by 5 equals 7. Find the number.",
        "answer_ko": "55",
        "answer_en": "55",
        "solution_abst_ko": "5 7 [OP_MUL] 12 [OP_ADD] 8 [OP_ADD]",
        "solution_abst_en": "5 7 [OP_MUL] 12 [OP_ADD] 8 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "2275": {
        "category": "Arithmetic calculation",
        "question_ko": "우준이는 학교에 가기 위해서 전체 거리의 1/5는 걷고, 남은 거리는 지하철을 탔습니다. 지하철을 타고 간 거리는 전체 거리의 몇 배입니까?",
        "question_en": "To go to school, Woojun walked 1/5 of the total distance and took the subway for the remaining distance. How many times is the total distance taken by subway?",
        "answer_ko": "0.80",
        "answer_en": "0.8",
        "solution_abst_ko": "1 1/5 [OP_SUB]",
        "solution_abst_en": "1 1/5 [OP_SUB]",
        "solution_code_ko": "var_a = 1\nvar_b = 0.2\nvar_c = var_a - var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 0.2\nvar_c = var_a - var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "2276": {
        "category": "Possibility",
        "question_ko": "울타리 안에 닭, 오리, 토끼, 강아지 네 종류의 동물이 있습니다. 울타리 안에서 15마리의 동물을 꺼내는 방법을 구하시오.",
        "question_en": "There are four types of animals in the fence: chicken, duck, rabbit, and dog. Find a way to get 15 animals out of the fence.",
        "answer_ko": "816",
        "answer_en": "816",
        "solution_abst_ko": "4 1 [OP_SUB] 15 [OP_ADD] 15 [OP_COMB]",
        "solution_abst_en": "4 1 [OP_SUB] 15 [OP_ADD] 15 [OP_COMB]",
        "solution_code_ko": "var_a = 4\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 15\nvar_e = var_c + var_d\nvar_f = 15\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g / (i+1)\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 15\nvar_e = var_c + var_d\nvar_f = 15\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g / (i+1)\nprint(int(var_g))"
    },
    "2277": {
        "category": "Comparison",
        "question_ko": "5, 8, 3, 2, 6중 가장 작은 숫자는?",
        "question_en": "Which number is the smallest among 5, 8, 3, 2, and 6?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 5 8 3 2 6 [OP_LIST_EOL] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 5 8 3 2 6 [OP_LIST_EOL] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 5\nvar_b = 8\nvar_c = 3\nvar_d = 2\nvar_e = 6\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 8\nvar_c = 3\nvar_d = 2\nvar_e = 6\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nprint(int(var_g))"
    },
    "2278": {
        "category": "Arithmetic calculation",
        "question_ko": "한 상자에 46개씩 들어있는 사과 19상자와 한 상자에 170개씩 들어있는 귤 몇 상자가 있습니다. 사과와 귤이 1894개라면 귤은 몇 상자입니까?",
        "question_en": "There are 19 boxes of apples, each containing 46 pieces, and several boxes of tangerines, each containing 170 pieces. If there are 1894 apples and tangerines, how many boxes of tangerines are there?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "1894 46 19 [OP_MUL] [OP_SUB] 170 [OP_FDIV]",
        "solution_abst_en": "1894 46 19 [OP_MUL] [OP_SUB] 170 [OP_FDIV]",
        "solution_code_ko": "var_a = 1894\nvar_b = 46\nvar_c = 19\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 170\nvar_g = var_e // var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1894\nvar_b = 46\nvar_c = 19\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 170\nvar_g = var_e // var_f\nprint(int(var_g))"
    },
    "2279": {
        "category": "Comparison",
        "question_ko": "1.4, 9/10, 1.2, 0.5, 13/10에서 1.1보다 크거나 같은 숫자를 나열한뒤, 합을 계산하면 얼마입니까?",
        "question_en": "What is the sum of the numbers greater than or equal to 1.1 in 1.4, 9/10, 1.2, 0.5, and 13/10?",
        "answer_ko": "3.90",
        "answer_en": "3.9",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE_EQUAL] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE_EQUAL] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i >= var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i >= var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "2280": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 7을 빼면 9의 배수가 되고 어떤 수를 9로 나눈 몫이 25라고 한다. 어떤 수에 9를 곱한 값을 구하시오.",
        "question_en": "A number subtract by 7 is a multiple of 9, and the quotient of a number divided by 9 is 25. Find the value of a number multiplied by 9.",
        "answer_ko": "2088",
        "answer_en": "2088",
        "solution_abst_ko": "25 9 [OP_MUL] 7 [OP_ADD] 9 [OP_MUL]",
        "solution_abst_en": "25 9 [OP_MUL] 7 [OP_ADD] 9 [OP_MUL]",
        "solution_code_ko": "var_a = 25\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c + var_d\nvar_f = 9\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 25\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c + var_d\nvar_f = 9\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "2281": {
        "category": "Comparison",
        "question_ko": "나나와 가은이는 종이 비행기 멀리 던지기 놀이를 하고 있습니다. 나나는 종이 비행기를 1.618 미터(m) 날렸고, 가은이는 종이 비행기를 162.3 센티미터(㎝) 날렸습니다. 더 멀리 종이 비행기를 날린 사람은 누구인지 구하시오.",
        "question_en": "Nana and Gaeun are playing a game of tossing paper airplanes far. Nana flew the paper airplane 1.618 meters (m), and Gaeun flew the paper airplane 162.3 centimeters (cm). Find out who flew the paper plane farther.",
        "answer_ko": "가은",
        "answer_en": "Gaeun",
        "solution_abst_ko": "[OP_LIST_SOL] 나나 가은 [OP_LIST_EOL] [OP_LIST_SOL] 1.618 100 [OP_MUL] 162.3 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Nana Gaeun [OP_LIST_EOL] [OP_LIST_SOL] 1.618 100 [OP_MUL] 162.3 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '나나'\nvar_b = '가은'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.618\nvar_d = 100\nvar_e = var_c * var_d\nvar_f = 162.3\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Nana'\nvar_b = 'Gaeun'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.618\nvar_d = 100\nvar_e = var_c * var_d\nvar_f = 162.3\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "2282": {
        "category": "Comparison",
        "question_ko": "정국이는 6에서 3을 곱한 수만큼 모았고, 윤기는 4, 유나는 5를 모았습니다. 누가 가장 작은 수를 모았나요?",
        "question_en": "Jungkook collected the number 6 multiplied by 3, Yoongi collected 4, and Yuna collected 5. Who got the smallest number?",
        "answer_ko": "윤기",
        "answer_en": "Yoongi",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 윤기 유나 [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_MUL] 4 5 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Yoongi Yuna [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_MUL] 4 5 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '윤기'\nvar_c = '유나'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 6\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = 4\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Yoongi'\nvar_c = 'Yuna'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 6\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = 4\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "2283": {
        "category": "Correspondence",
        "question_ko": "오늘 수호의 비커에 있는 물을 7/3리터(L) 만큼 서현이의 비커에 따라주었다. 현재 수호에 비커에 있는 물이 서현이의 비커에 있는 물보다 3/2리터(L)가 더 많다면 원래는 몇 리터(L) 더 많았는지 구하시오.",
        "question_en": "Today, I poured 7/3 liter (L) of water from Suho's beaker into Seohyun's beaker. If the water in Suho's beaker is 3/2 liter (L) more than the water in Seohyun's beaker, how many more water was in Suho's beaker than in Seohyun's beaker originally in liters (L)?",
        "answer_ko": "6.17",
        "answer_en": "6.17",
        "solution_abst_ko": "3/2 7/3 [OP_ADD] 7/3 [OP_ADD]",
        "solution_abst_en": "3/2 7/3 [OP_ADD] 7/3 [OP_ADD]",
        "solution_code_ko": "var_a = 1.5\nvar_b = 2.3333333333333335\nvar_c = var_a + var_b\nvar_d = 2.3333333333333335\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 1.5\nvar_b = 2.3333333333333335\nvar_c = var_a + var_b\nvar_d = 2.3333333333333335\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "2284": {
        "category": "Correspondence",
        "question_ko": "두 자리 수끼리의 곱셈에서 곱하는 수의 십의 자리 숫자 2를 6으로 잘못 보고 계산한 값이 2432가 되었습니다. 바르게 계산한 값이 912일 때, 2개의 두 자리 수 중 더 작은 수를 쓰시오.",
        "question_en": "In the multiplication of two-digit numbers, 2432 was calculated because I had mistaken the number 2 in the tens place of the number being multiplied for 6. If the correctly calculated value is 912, write the smaller of the two two-digit numbers.",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "[OP_LIST_SOL] 2432 912 [OP_SUB] 40 [OP_DIV] 912 2432 912 [OP_SUB] 40 [OP_DIV] [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 2432 912 [OP_SUB] 40 [OP_DIV] 912 2432 912 [OP_SUB] 40 [OP_DIV] [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 2432\nvar_b = 912\nvar_c = var_a - var_b\nvar_d = 40\nvar_e = var_c / var_d\nvar_f = 912\nvar_g = 2432\nvar_h = 912\nvar_i = var_g - var_h\nvar_j = 40\nvar_k = var_i / var_j\nvar_l = var_f / var_k\nlist_a= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_a.append(var_l)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nlist_a.reverse()\nvar_m = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_n = list_b[var_m-1]\nprint(int(var_n))",
        "solution_code_en": "var_a = 2432\nvar_b = 912\nvar_c = var_a - var_b\nvar_d = 40\nvar_e = var_c / var_d\nvar_f = 912\nvar_g = 2432\nvar_h = 912\nvar_i = var_g - var_h\nvar_j = 40\nvar_k = var_i / var_j\nvar_l = var_f / var_k\nlist_a= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_a.append(var_l)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nlist_a.reverse()\nvar_m = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_n = list_b[var_m-1]\nprint(int(var_n))"
    },
    "2285": {
        "category": "Correspondence",
        "question_ko": "승호는 자신이 가지고 있는 구슬 중 273개를 혁진이에게 주었다. 이때 승호가 혁진이보다 구슬을 477개 더 많이 가지고 있다면 구슬을 주기 전에는 몇 개나 더 많았는지 구하시오.",
        "question_en": "Seungho gave 273 of his marbles to Hyukjin. At this time, if Seungho has 477 more marbles than Hyukjin, find out how many more marbles he had before giving them.",
        "answer_ko": "1023",
        "answer_en": "1023",
        "solution_abst_ko": "477 273 [OP_ADD] 273 [OP_ADD]",
        "solution_abst_en": "477 273 [OP_ADD] 273 [OP_ADD]",
        "solution_code_ko": "var_a = 477\nvar_b = 273\nvar_c = var_a + var_b\nvar_d = 273\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 477\nvar_b = 273\nvar_c = var_a + var_b\nvar_d = 273\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "2286": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 250센티미터(㎝)인 테이프 4개를 길게 이어 붙였더니 전체의 길이가 925센티미터(㎝)가 되었습니다. 겹쳐진 각 부분의 길이는 모두 같다고 할 때, 겹쳐진 한 부분의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "When four 250 centimeters (cm) long tapes were attached together, the total length was 925 centimeters (cm). How many centimeters (cm) is the length of one overlapping segment, assuming that each overlapping segment is the same length?",
        "answer_ko": "25",
        "answer_en": "25",
        "solution_abst_ko": "250 4 [OP_MUL] 925 [OP_SUB] 4 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "250 4 [OP_MUL] 925 [OP_SUB] 4 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 250\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 925\nvar_e = var_c - var_d\nvar_f = 4\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 250\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 925\nvar_e = var_c - var_d\nvar_f = 4\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "2287": {
        "category": "Geometry",
        "question_ko": "한 변이 11센티미터(㎝)인 정사각형과 한 변이 5센티미터(㎝)인 정사각형이 있습니다. 두 정사각형의 넓이의 합은 몇 제곱센티미터(㎠)입니까?",
        "question_en": "There is a square with sides of 11 centimeters (cm) and a square with sides of 5 centimeters (cm). What is the sum of the areas of the two squares in square centimeters (cm2)?",
        "answer_ko": "146",
        "answer_en": "146",
        "solution_abst_ko": "11 2 [OP_POW] 5 2 [OP_POW] [OP_ADD]",
        "solution_abst_en": "11 2 [OP_POW] 5 2 [OP_POW] [OP_ADD]",
        "solution_code_ko": "var_a = 11\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 11\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "2288": {
        "category": "Correspondence",
        "question_ko": "네 자리 수 18A4는 1853보다 작습니다. A는 십의 자리 숫자이고 A에는 0부터 9까지의 숫자를 쓸 수 있습니다. A에 쓸 수 있는 숫자는 모두 몇 개입니까?",
        "question_en": "The four-digit number 18A4 is less than 1853. A is in the tens place and can contain any digit from 0 to 9. How many digits can go in A?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "18A4 [OP_GEN_POSSIBLE_LIST] 1853 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "18A4 [OP_GEN_POSSIBLE_LIST] 1853 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '18A4'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 1853\nlist_b = []\nfor i in list_a:\n    if i < var_b:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))",
        "solution_code_en": "var_a = '18A4'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 1853\nlist_b = []\nfor i in list_a:\n    if i < var_b:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))"
    },
    "2289": {
        "category": "Correspondence",
        "question_ko": "A7B+23=695입니다. B는 얼마인가요?",
        "question_en": "A7B+23=695. How much is B?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "A7B+23=695 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A7B+23=695 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A7B+23=695'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A7B+23=695'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "2290": {
        "category": "Arithmetic calculation",
        "question_ko": "민석이와 재윤이가 사과를 3개씩 먹었더니 사과 2개가 남았습니다. 처음에 있던 사과는 몇 개입니까?",
        "question_en": "Minseok and Jaeyoon ate 3 apples each, so there are 2 apples left. How many apples were there initially?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "2 3 2 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "2 3 2 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "2291": {
        "category": "Arithmetic calculation",
        "question_ko": "(가) 책과 (나) 책이 모두 20권 있는데 (가) 책이 (나) 책보다 4권 더 많습니다. (가) 책은 몇 권 있습니까?",
        "question_en": "There are 20 books (a) and books (b) in total, and there are four more books (a) than books (b). How many books (a) are there?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "20 4 [OP_ADD] 2 [OP_FDIV]",
        "solution_abst_en": "20 4 [OP_ADD] 2 [OP_FDIV]",
        "solution_code_ko": "var_a = 20\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "2292": {
        "category": "Possibility",
        "question_ko": "2, 0, 3, 8를 한 번씩 사용하여 만든 십의 자리 숫자가 2인 세 번째 큰 세 자리 수는 무엇입니까?",
        "question_en": "What is the third largest three-digit number with a tens digit of 2 formed by using 2, 0, 3, and 8 once?",
        "answer_ko": "328",
        "answer_en": "328",
        "solution_abst_ko": "[OP_LIST_SOL] 2 0 3 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 2 [OP_LIST_SEARCH_FIXED_DIGIT] 3 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 2 0 3 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 2 [OP_LIST_SEARCH_FIXED_DIGIT] 3 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 2\nvar_b = 0\nvar_c = 3\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 2\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 3\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nprint(int(var_i))",
        "solution_code_en": "var_a = 2\nvar_b = 0\nvar_c = 3\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 2\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 3\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nprint(int(var_i))"
    },
    "2293": {
        "category": "Correspondence",
        "question_ko": "61은 어떤 수에 62를 더해야 하는데 실수로 26을 더해서 나온 결과 입니다. 바르게 계산하면 얼마입니까?",
        "question_en": "61 is the result of accidentally adding 26 to a number, to which 62 should have been added. How much do you get if calculated correctly?",
        "answer_ko": "97",
        "answer_en": "97",
        "solution_abst_ko": "61 26 [OP_SUB] 62 [OP_ADD]",
        "solution_abst_en": "61 26 [OP_SUB] 62 [OP_ADD]",
        "solution_code_ko": "var_a = 61\nvar_b = 26\nvar_c = var_a - var_b\nvar_d = 62\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 61\nvar_b = 26\nvar_c = var_a - var_b\nvar_d = 62\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "2294": {
        "category": "Possibility",
        "question_ko": "보물이 숨겨진 방의 번호는 네 자리 수이고, 각 자리의 숫자가 겹치는 것이 없으며 2, 3, 7, 9로 이루어진 두 번째로 큰 수이다. 보물이 숨겨진 방의 번호는 무엇인가?",
        "question_en": "The number of the room where the treasure is hidden is four digits, each digit does not overlap, and is the second largest number which can be made of 2, 3, 7, and 9. What is the number of the room where the treasure is hidden?",
        "answer_ko": "9723",
        "answer_en": "9723",
        "solution_abst_ko": "[OP_LIST_SOL] 2 3 7 9 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 2 3 7 9 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = 7\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint(int(var_g))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = 7\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint(int(var_g))"
    },
    "2295": {
        "category": "Arithmetic calculation",
        "question_ko": "세 자리 자연수의 백의 자리 숫자가 5, 십의 자리 숫자가 1, 일의 자리 숫자가 3일 때, 이 숫자는 얼마인지 구하시오.",
        "question_en": "If the hundreds digit of a three-digit natural number is 5, the tens digit is 1, and the units digit is 3, what is this number?",
        "answer_ko": "513",
        "answer_en": "513",
        "solution_abst_ko": "[OP_LIST_SOL] 5 1 3 [OP_LIST_EOL] [OP_LIST2NUM]",
        "solution_abst_en": "[OP_LIST_SOL] 5 1 3 [OP_LIST_EOL] [OP_LIST2NUM]",
        "solution_code_ko": "var_a = 5\nvar_b = 1\nvar_c = 3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nprint(int(var_d))",
        "solution_code_en": "var_a = 5\nvar_b = 1\nvar_c = 3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nprint(int(var_d))"
    },
    "2296": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 46을 뺐더니 15가 되었습니다. 어떤 수에서 29를 빼면 얼마가 되는지 구하시오.",
        "question_en": "Subtracting 46 from a number gives 15. What is the number obtained when 29 is subtracted from a number?",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "15 46 [OP_ADD] 29 [OP_SUB]",
        "solution_abst_en": "15 46 [OP_ADD] 29 [OP_SUB]",
        "solution_code_ko": "var_a = 15\nvar_b = 46\nvar_c = var_a + var_b\nvar_d = 29\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 46\nvar_c = var_a + var_b\nvar_d = 29\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "2297": {
        "category": "Arithmetic calculation",
        "question_ko": "남준이는 17개의 구슬을 가지고 있습니다. 윤기가 가진 구슬의 개수는 남준이의 구슬 수의 5배보다 11개 더 적고, 호석이가 가진 구슬의 개수는 윤기의 구슬 수의 2배보다 8개 더 많습니다. 남준, 윤기, 호석이가 가지고 있는 구슬은 모두 몇 개입니까?",
        "question_en": "Namjoon has 17 marbles. Yoongi has 11 fewer marbles than Namjoon's marbles times 5, and Hoseok has 8 more marbles than 2 times Yoongi's. How many marbles do Namjoon, Yoongi, and Hoseok have?",
        "answer_ko": "247",
        "answer_en": "247",
        "solution_abst_ko": "17 17 5 [OP_MUL] 11 [OP_SUB] [OP_ADD] 17 5 [OP_MUL] 11 [OP_SUB] 2 [OP_MUL] 8 [OP_ADD] [OP_ADD]",
        "solution_abst_en": "17 17 5 [OP_MUL] 11 [OP_SUB] [OP_ADD] 17 5 [OP_MUL] 11 [OP_SUB] 2 [OP_MUL] 8 [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 17\nvar_b = 17\nvar_c = 5\nvar_d = var_b * var_c\nvar_e = 11\nvar_f = var_d - var_e\nvar_g = var_a + var_f\nvar_h = 17\nvar_i = 5\nvar_j = var_h * var_i\nvar_k = 11\nvar_l = var_j - var_k\nvar_m = 2\nvar_n = var_l * var_m\nvar_o = 8\nvar_p = var_n + var_o\nvar_q = var_g + var_p\nprint(int(var_q))",
        "solution_code_en": "var_a = 17\nvar_b = 17\nvar_c = 5\nvar_d = var_b * var_c\nvar_e = 11\nvar_f = var_d - var_e\nvar_g = var_a + var_f\nvar_h = 17\nvar_i = 5\nvar_j = var_h * var_i\nvar_k = 11\nvar_l = var_j - var_k\nvar_m = 2\nvar_n = var_l * var_m\nvar_o = 8\nvar_p = var_n + var_o\nvar_q = var_g + var_p\nprint(int(var_q))"
    },
    "2298": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 217센티미터(㎝)인 나무판자 3개를 이어 울타리를 만들려고 합니다. 나무 판자가 겹쳐지는 부분의 길이는 같고 만들어진 울타리의 길이가 627센티미터(㎝)라면 판자가 겹쳐진 부분의 하나의 길이는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "You are going to make a fence by connecting 3 wooden planks that are 217 centimeters (cm) long. If the length of the overlapping part of the wooden planks is the same, and the length of the fence made is 627 centimeters (cm), find how many centimeters (cm) is the length of one overlapping part of the planks.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "217 3 [OP_MUL] 627 [OP_SUB] 3 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "217 3 [OP_MUL] 627 [OP_SUB] 3 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 217\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 627\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 217\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 627\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "2299": {
        "category": "Geometry",
        "question_ko": "평행사변형의 한 변의 길이가 3.8미터(m)이고, 이 변과 마주보는 변 사이의 거리가 6.36미터(m)일 때, 이 평행사변형의 넓이는 얼마입니까?",
        "question_en": "If the length of one side of the parallelogram is 3.8 meters (m) and the distance between this side and the opposite side is 6.36 meters (m), what is the area of the parallelogram?",
        "answer_ko": "24.17",
        "answer_en": "24.17",
        "solution_abst_ko": "3.8 6.36 [OP_MUL]",
        "solution_abst_en": "3.8 6.36 [OP_MUL]",
        "solution_code_ko": "var_a = 3.8\nvar_b = 6.36\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 3.8\nvar_b = 6.36\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "2300": {
        "category": "Correspondence",
        "question_ko": "-3보다 -5만큼 작은 수를 A, +2보다 -2만큼 큰 수를 B라 할 때, A+B의 값을 구하시오.",
        "question_en": "If A is the number less than -3 by -5, and B is the number greater than +2 by -2, find the value of A+B.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "-3 -5 [OP_SUB] 2 -2 [OP_ADD] [OP_ADD]",
        "solution_abst_en": "-3 -5 [OP_SUB] 2 -2 [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = -3\nvar_b = -5\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = -2\nvar_f = var_d + var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = -3\nvar_b = -5\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = -2\nvar_f = var_d + var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "2301": {
        "category": "Arithmetic calculation",
        "question_ko": "양팔 저울 한쪽에 무게가 1050그램(g)인 사전 5권을 올려두었습니다. 무게의 합이 4.5킬로그램(㎏)인 9권의 같은 책 중 2권을 양팔 저울의 반대쪽에 올려두었습니다. 저울의 수평을 맞추기 위해선 책을 올려둔 쪽에 850그램(g)짜리 필통을 몇 개 더 올려야 합니까?",
        "question_en": "Five dictionaries weighing 1050 grams (g) each were placed on one side of the two-arm scale. Two of nine identical books, each weighing 4.5 kilograms (kg), were placed on opposite sides of a two-arm scale. How many more 850-gram (g) pencil cases should be placed on the side where the books are placed to level the scale?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "1050 5 [OP_MUL] 4.5 1000 [OP_MUL] 9 [OP_DIV] 2 [OP_MUL] [OP_SUB] 850 [OP_DIV]",
        "solution_abst_en": "1050 5 [OP_MUL] 4.5 1000 [OP_MUL] 9 [OP_DIV] 2 [OP_MUL] [OP_SUB] 850 [OP_DIV]",
        "solution_code_ko": "var_a = 1050\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 4.5\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = 9\nvar_h = var_f / var_g\nvar_i = 2\nvar_j = var_h * var_i\nvar_k = var_c - var_j\nvar_l = 850\nvar_m = var_k / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 1050\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 4.5\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = 9\nvar_h = var_f / var_g\nvar_i = 2\nvar_j = var_h * var_i\nvar_k = var_c - var_j\nvar_l = 850\nvar_m = var_k / var_l\nprint(int(var_m))"
    },
    "2302": {
        "category": "Geometry",
        "question_ko": "어떤 지도의 축척은 1/250000입니다. 실제 거리가 5킬로미터(㎞)인 두 지점이 있을 때, 지도에서의 길이를 센티미터(㎝)로 구하시오.",
        "question_en": "Some maps have a scale of 1/250000. Given two points whose actual distance is 5 kilometers (km), find the length in centimeters (cm) on the map.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "5 100 1000 [OP_MUL] [OP_MUL] 1/250000 [OP_MUL]",
        "solution_abst_en": "5 100 1000 [OP_MUL] [OP_MUL] 1/250000 [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 100\nvar_c = 1000\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nvar_f = 4e-06\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 100\nvar_c = 1000\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nvar_f = 4e-06\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "2303": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 8로 나누어야 할 것을 잘못하여 곱하고 8을 더했더니 56이 되었습니다. 바르게 계산하면 얼마인지 소수점 둘째 자리까지 나타내어 보세요.",
        "question_en": "You made a mistake in dividing a certain number by 8, so you multiplied it by 8 and added 8 to get 56. Show how much it would be if you did it correctly, to two decimal places.",
        "answer_ko": "0.75",
        "answer_en": "0.75",
        "solution_abst_ko": "56 8 [OP_SUB] 8 [OP_DIV] 8 [OP_DIV]",
        "solution_abst_en": "56 8 [OP_SUB] 8 [OP_DIV] 8 [OP_DIV]",
        "solution_code_ko": "var_a = 56\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 8\nvar_e = var_c / var_d\nvar_f = 8\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 56\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 8\nvar_e = var_c / var_d\nvar_f = 8\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "2304": {
        "category": "Correspondence",
        "question_ko": "다섯 자리의 수 752AB가 3으로 나누어 떨어집니다. A와 B에 0부터 9까지의 숫자가 들어갈 수 있다면, 조건을 만족하는 수는 모두 몇 개인지 구하시오.",
        "question_en": "752AB which is five digit number is divisible by 3. If A and B can contain numbers from 0 to 9, how many numbers satisfy the condition?",
        "answer_ko": "33",
        "answer_en": "33",
        "solution_abst_ko": "752AB [OP_GEN_POSSIBLE_LIST] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "752AB [OP_GEN_POSSIBLE_LIST] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '752AB'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 3\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))",
        "solution_code_en": "var_a = '752AB'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 3\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))"
    },
    "2305": {
        "category": "Geometry",
        "question_ko": "정사면체의 면의 변의 개수는?",
        "question_en": "How many edges are there on the face of a regular tetrahedron?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "3",
        "solution_abst_en": "3",
        "solution_code_ko": "var_a = 3\nprint(int(var_a))",
        "solution_code_en": "var_a = 3\nprint(int(var_a))"
    },
    "2306": {
        "category": "Comparison",
        "question_ko": "1.4, 9/10, 1.2, 0.5, 13/10 중에서 1.1보다 큰 숫자를 고르고, 선택된 숫자들의 합을 구하세요",
        "question_en": "Choose a number greater than 1.1 from among 1.4, 9/10, 1.2, 0.5, and 13/10, and find the sum of the selected numbers",
        "answer_ko": "3.90",
        "answer_en": "3.9",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "2307": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 16을 곱해야 할 것을 잘못하여 16으로 나누었더니 몫이 8로 나누어떨어졌습니다. 바르게 계산한 값을 구하세요.",
        "question_en": "I divided a number by 16 incorrectly, which was supposed to be multiplied by 16, and the quotient is divided by 8. Find the correct calculated value.",
        "answer_ko": "2048",
        "answer_en": "2048",
        "solution_abst_ko": "8 16 [OP_MUL] 16 [OP_MUL]",
        "solution_abst_en": "8 16 [OP_MUL] 16 [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 16\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 16\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "2308": {
        "category": "Correspondence",
        "question_ko": "901개의 바둑이 있습니다. 오목 경기를 하기 위해 총 53개의 바둑 공이 필요한 경우, 동시에 수행할 수 있는 오목 경기의 수를 구하십시오.",
        "question_en": "There are 901 Go balls. If you need a total of 53 Go balls to play a Go game, find the number of Go games that can be played simultaneously.",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "1 53 901 [OP_DIV] [OP_DIV]",
        "solution_abst_en": "1 53 901 [OP_DIV] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 53\nvar_c = 901\nvar_d = var_b / var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 53\nvar_c = 901\nvar_d = var_b / var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "2309": {
        "category": "Comparison",
        "question_ko": "성민이와 단비는 빼빼로를 만들었습니다. 성민이는 12미터(m), 단비는 9미터(m)를 만들었습니다. 둘 중 더 길게 만든 사람은 누구입니까?",
        "question_en": "Seongmin and Danbi made Pepero. Seongmin made 12 meters (m) and Danbi made 9 meters (m). Which of the two made it longer?",
        "answer_ko": "성민",
        "answer_en": "Seongmin",
        "solution_abst_ko": "[OP_LIST_SOL] 성민 단비 [OP_LIST_EOL] [OP_LIST_SOL] 12 9 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Seongmin Danbi [OP_LIST_EOL] [OP_LIST_SOL] 12 9 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '성민'\nvar_b = '단비'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 12\nvar_d = 9\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Seongmin'\nvar_b = 'Danbi'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 12\nvar_d = 9\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "2310": {
        "category": "Arithmetic calculation",
        "question_ko": "우진이네 가족은 밭에서 감자를 캤습니다. 동생은 3.8킬로그램(㎏) 을 캤고, 누나는 동생보다 8.4킬로그램(㎏) 더 많이 캤습니다. 우진이는 누나가 캔 감자의 무게의 1/10 보다 3720그램(g) 더 많이 캤다면 우진이가 캔 감자는 몇 킬로그램(㎏)입니까?",
        "question_en": "Woojin's family harvested potatoes in the field. The younger brother dug out 3.8 kilograms (kg), and the older sister dug out 8.4 kilograms (kg) more than the younger brother did. If Woojin dug out 3720 grams (g) more than 1/10 of the weight of her sister did, how many kilograms (kg) of Woojin's harvested potatoes?",
        "answer_ko": "4.94",
        "answer_en": "4.94",
        "solution_abst_ko": "3.8 8.4 [OP_ADD] 1/10 [OP_MUL] 3720 1000 [OP_DIV] [OP_ADD]",
        "solution_abst_en": "3.8 8.4 [OP_ADD] 1/10 [OP_MUL] 3720 1000 [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 3.8\nvar_b = 8.4\nvar_c = var_a + var_b\nvar_d = 0.1\nvar_e = var_c * var_d\nvar_f = 3720\nvar_g = 1000\nvar_h = var_f / var_g\nvar_i = var_e + var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 3.8\nvar_b = 8.4\nvar_c = var_a + var_b\nvar_d = 0.1\nvar_e = var_c * var_d\nvar_f = 3720\nvar_g = 1000\nvar_h = var_f / var_g\nvar_i = var_e + var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "2311": {
        "category": "Arithmetic calculation",
        "question_ko": "빵이 3개씩 들어있는 봉지 3개에 들어 있는 빵은 모두 몇 개 입니까?",
        "question_en": "Find the total amount of bread in 3 bags containing 3 loaves.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "3 3 [OP_MUL]",
        "solution_abst_en": "3 3 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "2312": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중에서 2번째로 큰 수와 가장 작은 수로 나눈 몫은 얼마입니까?",
        "question_en": "There are three numbers 10, 11, and 12. What is the quotient of the second largest number divided by the smallest number?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 2 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_FDIV]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 2 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_FDIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e // var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e // var_g\nprint(int(var_h))"
    },
    "2313": {
        "category": "Comparison",
        "question_ko": "한 변의 길이가 7센티미터(㎝)인 정사각형, 한 변의 길이가 9센티미터(㎝)인 정삼각형, 반지름의 길이가 5센티미터(㎝)인 원이 있습니다. 원주율을 3으로 계산할 때 둘레의 길이가 가장 긴 도형은 어느 것입니까?",
        "question_en": "There is a square with a side length of 7 centimeters (cm), an equilateral-triangle with a side length of 9 centimeters (cm), and a circle with a radius of 5 centimeters (cm). Which shape has the longest perimeter when pi is calculated as 3?",
        "answer_ko": "원",
        "answer_en": "circle",
        "solution_abst_ko": "[OP_LIST_SOL] 정사각형 정삼각형 원 [OP_LIST_EOL] [OP_LIST_SOL] 7 4 [OP_MUL] 9 3 [OP_MUL] 5 3 2 [OP_MUL] [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] square equilateral-triangle circle [OP_LIST_EOL] [OP_LIST_SOL] 7 4 [OP_MUL] 9 3 [OP_MUL] 5 3 2 [OP_MUL] [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정사각형'\nvar_b = '정삼각형'\nvar_c = '원'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 7\nvar_e = 4\nvar_f = var_d * var_e\nvar_g = 9\nvar_h = 3\nvar_i = var_g * var_h\nvar_j = 5\nvar_k = 3\nvar_l = 2\nvar_m = var_k * var_l\nvar_n = var_j * var_m\nlist_b= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_o = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_p = list_c[-var_o]\nvar_q = list_b.index(var_p)+1\nvar_r = list_a[var_q-1]\nprint(var_r)",
        "solution_code_en": "var_a = 'square'\nvar_b = 'equilateral-triangle'\nvar_c = 'circle'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 7\nvar_e = 4\nvar_f = var_d * var_e\nvar_g = 9\nvar_h = 3\nvar_i = var_g * var_h\nvar_j = 5\nvar_k = 3\nvar_l = 2\nvar_m = var_k * var_l\nvar_n = var_j * var_m\nlist_b= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_o = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_p = list_c[-var_o]\nvar_q = list_b.index(var_p)+1\nvar_r = list_a[var_q-1]\nprint(var_r)"
    },
    "2314": {
        "category": "Arithmetic calculation",
        "question_ko": "과일가게에서 사과는 한 개에 1000원이고 복숭아는 한 개에 2000원입니다. 사과와 복숭아를 합하여 15개를 사고 22000원을 냈다면 복숭아는 모두 몇 개 샀는지 구하세요.",
        "question_en": "At the fruit shop, apples are 1,000 won each and peaches are 2,000 won each. If you bought 15 apples and peaches in total and paid 22,000 won, find how many peaches you have bought.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "22000 1000 15 [OP_MUL] [OP_SUB] 2000 1000 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "22000 1000 15 [OP_MUL] [OP_SUB] 2000 1000 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 22000\nvar_b = 1000\nvar_c = 15\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 2000\nvar_g = 1000\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 22000\nvar_b = 1000\nvar_c = 15\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 2000\nvar_g = 1000\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "2315": {
        "category": "Correspondence",
        "question_ko": "윤기는 어떤 수에서 17을 빼 55를 얻었습니다. 이제 이 어떤 수를 9로 나누고자 합니다. 어떤 값을 얻을 수 있습니까?",
        "question_en": "Yoongi subtracted 17 from a certain number to get 55. Now we want to divide this number by 9. What value can you get?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "55 17 [OP_ADD] 9 [OP_DIV]",
        "solution_abst_en": "55 17 [OP_ADD] 9 [OP_DIV]",
        "solution_code_ko": "var_a = 55\nvar_b = 17\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 55\nvar_b = 17\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "2316": {
        "category": "Correspondence",
        "question_ko": "선우는 여행을 하면서 첫째날 가진 물의 1/2을 마시고, 둘째날 남은 물의 1/3을 마시고, 셋째날 남은 물의 1/2를 마셨더니 250밀리리터(㎖)가 남았습니다. 선우가 처음에 가지고 있던 물의 양은 몇 밀리리터(㎖)입니까?",
        "question_en": "While traveling, Seonwoo drank 1/2 of the water he had on the first day, 1/3 of the remaining water on the second day, and 1/2 of the remaining water on the third day, leaving him with 250 milliliters (ml). How many milliliters (ml) did Seonwoo have at first?",
        "answer_ko": "1500",
        "answer_en": "1500",
        "solution_abst_ko": "250 1 1/2 [OP_SUB] [OP_DIV] 1 1/3 [OP_SUB] [OP_DIV] 1 1/2 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "250 1 1/2 [OP_SUB] [OP_DIV] 1 1/3 [OP_SUB] [OP_DIV] 1 1/2 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 250\nvar_b = 1\nvar_c = 0.5\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 1\nvar_g = 0.3333333333333333\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 1\nvar_k = 0.5\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nprint(int(eval('{:.2f}'.format(round(var_m+1e-10,2)))))",
        "solution_code_en": "var_a = 250\nvar_b = 1\nvar_c = 0.5\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 1\nvar_g = 0.3333333333333333\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 1\nvar_k = 0.5\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nprint(int(eval('{:.2f}'.format(round(var_m+1e-10,2)))))"
    },
    "2317": {
        "category": "Comparison",
        "question_ko": "총 3개의 숫자 0.8, 1/2, 0.5이 있습니다. 이 중 0.1보다 큰 수 중 가장 작은 수를 구하면 무엇인가요?",
        "question_en": "There are three numbers: 0.8, 1/2, and 0.5. What is the smallest of these numbers greater than 0.1?",
        "answer_ko": "0.50",
        "answer_en": "0.5",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.5 [OP_LIST_EOL] 0.1 [OP_LIST_MORE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.5 [OP_LIST_EOL] 0.1 [OP_LIST_MORE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.1\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nprint('{:.2f}'.format(round(var_f+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.1\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nprint('{:.2f}'.format(round(var_f+1e-10,2)))"
    },
    "2318": {
        "category": "Geometry",
        "question_ko": "넓이가 9.31제곱센티미터(㎠)이고 높이가 4.9센티미터(㎝)인 삼각형의 밑변은 몇 센티미터(㎝)입니까?",
        "question_en": "How many centimeters (cm) is the base of a triangle with an area of 9.31 square centimeters (cm2) and a height of 4.9 centimeters (cm)?",
        "answer_ko": "3.80",
        "answer_en": "3.8",
        "solution_abst_ko": "9.31 2 [OP_MUL] 4.9 [OP_DIV]",
        "solution_abst_en": "9.31 2 [OP_MUL] 4.9 [OP_DIV]",
        "solution_code_ko": "var_a = 9.31\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 4.9\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 9.31\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 4.9\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "2319": {
        "category": "Possibility",
        "question_ko": "200보다 큰 세 자리 자연수 중, 각 자리 숫자가 모두 다르고 0, 1, 3, 5, 6으로만 이루어져 있는 수는 모두 몇 개인지 구하시오.",
        "question_en": "How many three-digit natural numbers greater than 200 are there in which each digit is different from one another and consists only of 0, 1, 3, 5, and 6?",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 3 5 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 200 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 3 5 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 200 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 3\nvar_d = 5\nvar_e = 6\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 200\nlist_c = []\nfor i in list_b:\n    if i > var_g:\n        list_c.append(i)\nvar_h = len(list_c)\nprint(int(var_h))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 3\nvar_d = 5\nvar_e = 6\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 200\nlist_c = []\nfor i in list_b:\n    if i > var_g:\n        list_c.append(i)\nvar_h = len(list_c)\nprint(int(var_h))"
    },
    "2320": {
        "category": "Comparison",
        "question_ko": "희진이는 하루에 10번씩 운동을 하고 한 번 운동할 때 30분씩 합니다. 지민이는 하루에 8번씩 운동을 하고 한 번 운동할 때 20분씩 합니다. 하루에 운동을 더 많이 하는 사람은 누구입니까?",
        "question_en": "Heejin works out 10 times a day for 30 minutes each time. And Jimin exercises 8 times a day for 20 minutes each time. Find the one who exercises more in a day.",
        "answer_ko": "희진",
        "answer_en": "Heejin",
        "solution_abst_ko": "[OP_LIST_SOL] 희진 지민 [OP_LIST_EOL] [OP_LIST_SOL] 10 30 [OP_MUL] 8 20 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Heejin Jimin [OP_LIST_EOL] [OP_LIST_SOL] 10 30 [OP_MUL] 8 20 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '희진'\nvar_b = '지민'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10\nvar_d = 30\nvar_e = var_c * var_d\nvar_f = 8\nvar_g = 20\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Heejin'\nvar_b = 'Jimin'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10\nvar_d = 30\nvar_e = var_c * var_d\nvar_f = 8\nvar_g = 20\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "2321": {
        "category": "Geometry",
        "question_ko": "원 위에 존재하는 서로 다른 5개의 점이 있다. 이 중 2점을 연결하여 만들 수 있는 직선의 개수는 몇 개인가? 단, 한 점에서 다른 점까지 원을 따라가다 제일 먼저 만나는 점 끼리는 직선을 만들지 않는다.",
        "question_en": "There are 5 different points on the circle. How many straight lines can be formed by connecting two of these points? Note that the line created with one point and the first next point that meet while following a circle does not count.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "5 5 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "5 5 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 5\nvar_b = 5\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 5\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "2322": {
        "category": "Geometry",
        "question_ko": "28킬로미터(㎞)인 직선도로에 4킬로미터(㎞) 간격으로 나무를 심으려고 한다. 나무를 최대 몇 그루 심을 수 있는지 구하시오.",
        "question_en": "We plan to plant trees at intervals of 4 kilometers (km) on a straight road of 28 kilometers (km). Find the maximum number of trees you can plant.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "28 4 [OP_DIV] 1 [OP_ADD]",
        "solution_abst_en": "28 4 [OP_DIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 28\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 28\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "2323": {
        "category": "Arithmetic calculation",
        "question_ko": "10개의 공이 있습니다. 정국이는 한 상자에 5개의 공을 담으려고 합니다. 이 때, 필요한 상자의 개수는 몇 개입니까?",
        "question_en": "There are 10 balls. Jungkook wants to put 5 balls in one box. How many boxes does he need at this time?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "10 5 [OP_DIV]",
        "solution_abst_en": "10 5 [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 5\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 10\nvar_b = 5\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "2324": {
        "category": "Possibility",
        "question_ko": "숫자카드 1, 4를 한 번씩 모두 사용하여 만들 수 있는 두 자리 수는 총 몇 개입니까?",
        "question_en": "How many total two-digit numbers can be made by using both the number cards 1 and 4 once?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 1 4 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 4 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 4\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = len(list_b)\nprint(int(var_d))",
        "solution_code_en": "var_a = 1\nvar_b = 4\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = len(list_b)\nprint(int(var_d))"
    },
    "2325": {
        "category": "Possibility",
        "question_ko": "중복을 허락하여 2, 3, 7로 두 자리 자연수를 만들려고 한다. 만들 수 있는 모든 수들의 합을 구하시오.",
        "question_en": "You are trying to create two-digit numbers with 2, 3, and 7 allowing duplicates. Find the sum of all possible numbers.",
        "answer_ko": "396",
        "answer_en": "396",
        "solution_abst_ko": "[OP_LIST_SOL] 2 3 7 [OP_LIST_EOL] 2 [OP_LIST_GET_PRODUCT] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 2 3 7 [OP_LIST_EOL] 2 [OP_LIST_GET_PRODUCT] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint(int(var_e))"
    },
    "2326": {
        "category": "Arithmetic calculation",
        "question_ko": "다섯자리 수 1ABC9가 13으로 나누어 떨어진다. 세자리수 ABC가 가능한 수는 몇 개인지 구하시오.",
        "question_en": "The five-digit number 1ABC9 is divisible by 13. How many three-digit numbers ABC is possible?",
        "answer_ko": "77",
        "answer_en": "77",
        "solution_abst_ko": "1ABC9 [OP_GEN_POSSIBLE_LIST] 13 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "1ABC9 [OP_GEN_POSSIBLE_LIST] 13 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '1ABC9'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 13\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))",
        "solution_code_en": "var_a = '1ABC9'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 13\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))"
    },
    "2327": {
        "category": "Correspondence",
        "question_ko": "서로 다른 두 수 A, B가 있습니다. 두 자리 수끼리의 뺄셈식 6A-B2=36에서 A-B의 값을 구하시오.",
        "question_en": "There are two different numbers A and B. Find the value of A-B in the two-digit subtraction equation 6A-B2=36.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "6A-B2=36 A [OP_DIGIT_UNK_SOLVER] 6A-B2=36 B [OP_DIGIT_UNK_SOLVER] [OP_SUB]",
        "solution_abst_en": "6A-B2=36 A [OP_DIGIT_UNK_SOLVER] 6A-B2=36 B [OP_DIGIT_UNK_SOLVER] [OP_SUB]",
        "solution_code_ko": "var_a = '6A-B2=36'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '6A-B2=36'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = '6A-B2=36'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '6A-B2=36'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "2328": {
        "category": "Geometry",
        "question_ko": "(가) 회사에서 만든 가로 20센티미터(㎝), 세로 10센티미터(㎝), 높이 10센티미터(㎝)인 직육면체 모양의 휴지곽과 (나) 회사에서 만든 가로, 세로, 높이가 각각 13센티미터(㎝)인 정육면체 모양의 휴지곽이 있다. 두 휴지곽에 휴지를 넣는다면 어느 회사에서 만든 휴지곽에 더 많은 양의 휴지가 들어가겠는가?",
        "question_en": "The company (a) produces cuboid-shaped tissue boxes with a length of 20 centimeters (cm), a width of 10 centimeters (cm), and a height of 10 centimeters (cm), and the company (b) produces tissue boxes in the shape of a cube whose width, length, and height are 13 centimeters (cm). Suppose you place tissues in both boxes, which company's box will contain more tissues?",
        "answer_ko": "(나)",
        "answer_en": "(b)",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) [OP_LIST_EOL] [OP_LIST_SOL] 20 10 [OP_MUL] 10 [OP_MUL] 13 13 [OP_MUL] 13 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (a) (b) [OP_LIST_EOL] [OP_LIST_SOL] 20 10 [OP_MUL] 10 [OP_MUL] 13 13 [OP_MUL] 13 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 20\nvar_d = 10\nvar_e = var_c * var_d\nvar_f = 10\nvar_g = var_e * var_f\nvar_h = 13\nvar_i = 13\nvar_j = var_h * var_i\nvar_k = 13\nvar_l = var_j * var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = '(a)'\nvar_b = '(b)'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 20\nvar_d = 10\nvar_e = var_c * var_d\nvar_f = 10\nvar_g = var_e * var_f\nvar_h = 13\nvar_i = 13\nvar_j = var_h * var_i\nvar_k = 13\nvar_l = var_j * var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "2329": {
        "category": "Arithmetic calculation",
        "question_ko": "시간당 민영이는 125개의 당근을, 유정이는 137개의 당근을 재배했다. 6시간 동안 당근을 재배했을 시, 유정이는 민영이보다 몇 개 더 재배했나?",
        "question_en": "Minyoung grew 125 carrots per hour, and Yujeong grew 137 carrots per hour. When growing carrots for 6 hours, how many carrots did Yujeong grow more than Minyoung?",
        "answer_ko": "72",
        "answer_en": "72",
        "solution_abst_ko": "137 125 [OP_SUB] 6 [OP_MUL]",
        "solution_abst_en": "137 125 [OP_SUB] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 137\nvar_b = 125\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 137\nvar_b = 125\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "2330": {
        "category": "Comparison",
        "question_ko": "정육면체 (가), (나), (다)가 있습니다. (가)는 한 모서리의 길이가 7센티미터(㎝)이고, (나)는 한 모서리의 길이가 11센티미터(㎝)입니다. 또, (다)는 한 모서리의 길이가 9센티미터(㎝)입니다. (가), (나), (다) 중에서 겉넓이가 가장 넓은 도형은 어느 것입니까?",
        "question_en": "There are cubes (A), (B), and (C). In (A), the length of one edge is 7 centimeters (cm), and in (B), the length of one edge is 11 centimeters (cm). Also, (C) has an edge with 9 centimeters (cm) long. Which shape has the largest surface area among (A), (B), and (C)?",
        "answer_ko": "(나)",
        "answer_en": "(B)",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) (다) [OP_LIST_EOL] [OP_LIST_SOL] 6 7 2 [OP_POW] [OP_MUL] 6 11 2 [OP_POW] [OP_MUL] 6 9 2 [OP_POW] [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (A) (B) (C) [OP_LIST_EOL] [OP_LIST_SOL] 6 7 2 [OP_POW] [OP_MUL] 6 11 2 [OP_POW] [OP_MUL] 6 9 2 [OP_POW] [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nvar_c = '(다)'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 6\nvar_e = 7\nvar_f = 2\nvar_g = var_e ** var_f\nvar_h = var_d * var_g\nvar_i = 6\nvar_j = 11\nvar_k = 2\nvar_l = var_j ** var_k\nvar_m = var_i * var_l\nvar_n = 6\nvar_o = 9\nvar_p = 2\nvar_q = var_o ** var_p\nvar_r = var_n * var_q\nlist_b= []\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nlist_b.reverse()\nvar_s = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_t = list_c[-var_s]\nvar_u = list_b.index(var_t)+1\nvar_v = list_a[var_u-1]\nprint(var_v)",
        "solution_code_en": "var_a = '(A)'\nvar_b = '(B)'\nvar_c = '(C)'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 6\nvar_e = 7\nvar_f = 2\nvar_g = var_e ** var_f\nvar_h = var_d * var_g\nvar_i = 6\nvar_j = 11\nvar_k = 2\nvar_l = var_j ** var_k\nvar_m = var_i * var_l\nvar_n = 6\nvar_o = 9\nvar_p = 2\nvar_q = var_o ** var_p\nvar_r = var_n * var_q\nlist_b= []\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nlist_b.reverse()\nvar_s = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_t = list_c[-var_s]\nvar_u = list_b.index(var_t)+1\nvar_v = list_a[var_u-1]\nprint(var_v)"
    },
    "2331": {
        "category": "Arithmetic calculation",
        "question_ko": "20 이하의 짝수는 몇 개입니까?",
        "question_en": "How many even numbers are no more than 20?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "1 20 [OP_LIST_EVEN] [OP_LIST_LEN]",
        "solution_abst_en": "1 20 [OP_LIST_EVEN] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 20\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = len(list_a)\nprint(int(var_c))",
        "solution_code_en": "var_a = 1\nvar_b = 20\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = len(list_a)\nprint(int(var_c))"
    },
    "2332": {
        "category": "Geometry",
        "question_ko": "한 변이 40센티미터(㎝)인 정사각형을 철사를 사용해 만들고자 합니다. 철사는 몇 센티미터(㎝)가 필요합니까?",
        "question_en": "You want to make a square with a side of 40 centimeters (cm) using wire. Find the amount of wire you need in centimeters (cm).",
        "answer_ko": "160",
        "answer_en": "160",
        "solution_abst_ko": "40 4 [OP_MUL]",
        "solution_abst_en": "40 4 [OP_MUL]",
        "solution_code_ko": "var_a = 40\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 40\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "2333": {
        "category": "Possibility",
        "question_ko": "1부터 1000까지 각 자릿수의 합이 11인 자연수는 몇 개입니까?",
        "question_en": "How many natural numbers are there from 1 to 1000, in which the sum of their digits is equal to 11?",
        "answer_ko": "69",
        "answer_en": "69",
        "solution_abst_ko": "1 1000 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] 11 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 1000 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] 11 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 1000\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_b=[]\nfor i in list_a:\n    var_d = 0\n    i = int(i)\n    while i//10 > 0:\n        var_d = var_d + i%10\n        i = i//10\n    var_d = var_d + i%10\n    list_b.append(var_d)\nvar_e = 11\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 1000\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_b=[]\nfor i in list_a:\n    var_d = 0\n    i = int(i)\n    while i//10 > 0:\n        var_d = var_d + i%10\n        i = i//10\n    var_d = var_d + i%10\n    list_b.append(var_d)\nvar_e = 11\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))"
    },
    "2334": {
        "category": "Possibility",
        "question_ko": "색연필을 한 줄로 놓으려고 한다. 파란색 색연필 1자루와 구분할 수 없는 보라색 색연필 5자루가 있다면 서로 다르게 놓는 방법은 모두 몇 가지입니까?",
        "question_en": "Try to put colored pencils in a line. If you have 1 blue pencil and 5 indistinguishable purple pencils, how many different ways can you place them?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "5 1 [OP_ADD] 1 [OP_COMB]",
        "solution_abst_en": "5 1 [OP_ADD] 1 [OP_COMB]",
        "solution_code_ko": "var_a = 5\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 1\nvar_c = int(var_c)\nvar_d = int(var_d)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e * (var_c-i)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e / (i+1)\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 1\nvar_c = int(var_c)\nvar_d = int(var_d)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e * (var_c-i)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e / (i+1)\nprint(int(var_e))"
    },
    "2335": {
        "category": "Correspondence",
        "question_ko": "691-A87=4일 때, A를 구하시오.",
        "question_en": "When 691-A87=4, find A.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "691-A87=4 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "691-A87=4 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '691-A87=4'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '691-A87=4'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "2336": {
        "category": "Comparison",
        "question_ko": "서로 다른 꽃을 한 줄로 심었습니다. 장미는 앞에서 8번째에 심었고, 백합은 장미 바로 뒤에 심었습니다. 백합은 앞에서 몇 번째에 심었습니까?",
        "question_en": "I planted different flowers in a row. The rose was planted eighth from the front, and the lily was planted right after the rose. At what number from the front was the lily planted?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "8 1 [OP_ADD]",
        "solution_abst_en": "8 1 [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 8\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "2337": {
        "category": "Arithmetic calculation",
        "question_ko": "창기, 채영, 현정 세 사람의 몸무게의 합은 106킬로그램(㎏) 600그램(g)입니다. 채영는 현정이보다 7킬로그램(㎏) 700그램(g) 더 무겁고, 창기는 채영이보다 4.8킬로그램(㎏) 더 무겁습니다. 창기의 몸무게는 몇 킬로그램(㎏)입니까?",
        "question_en": "Changgi, Chaeyoung, and Hyeonjeong weigh 106 kilograms (kg) and 600 grams (g). Chaeyoung is 7 kilograms (kg) 700 grams (g) heavier than Hyunjeong, and Changgi is 4.8 kilograms (kg) heavier than Chaeyoung. How many kilograms (kg) does Changgi weigh?",
        "answer_ko": "41.30",
        "answer_en": "41.3",
        "solution_abst_ko": "106 600 1000 [OP_DIV] [OP_ADD] 7 700 1000 [OP_DIV] [OP_ADD] [OP_ADD] 4.8 2 [OP_MUL] [OP_ADD] 3 [OP_DIV]",
        "solution_abst_en": "106 600 1000 [OP_DIV] [OP_ADD] 7 700 1000 [OP_DIV] [OP_ADD] [OP_ADD] 4.8 2 [OP_MUL] [OP_ADD] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 106\nvar_b = 600\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 7\nvar_g = 700\nvar_h = 1000\nvar_i = var_g / var_h\nvar_j = var_f + var_i\nvar_k = var_e + var_j\nvar_l = 4.8\nvar_m = 2\nvar_n = var_l * var_m\nvar_o = var_k + var_n\nvar_p = 3\nvar_q = var_o / var_p\nprint('{:.2f}'.format(round(var_q+1e-10,2)))",
        "solution_code_en": "var_a = 106\nvar_b = 600\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 7\nvar_g = 700\nvar_h = 1000\nvar_i = var_g / var_h\nvar_j = var_f + var_i\nvar_k = var_e + var_j\nvar_l = 4.8\nvar_m = 2\nvar_n = var_l * var_m\nvar_o = var_k + var_n\nvar_p = 3\nvar_q = var_o / var_p\nprint('{:.2f}'.format(round(var_q+1e-10,2)))"
    },
    "2338": {
        "category": "Arithmetic calculation",
        "question_ko": "사과 40개를 7개의 상자에 최대한 나누어 담는다면, 상자에 담기지 못한 사과는 몇 개입니까?",
        "question_en": "If you divide 40 apples into 7 boxes at most, how many apples do not fit in the box?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "40 7 [OP_FDIV]",
        "solution_abst_en": "40 7 [OP_FDIV]",
        "solution_code_ko": "var_a = 40\nvar_b = 7\nvar_c = var_a // var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 40\nvar_b = 7\nvar_c = var_a // var_b\nprint(int(var_c))"
    },
    "2339": {
        "category": "Geometry",
        "question_ko": "어떤 팔각형에서 대각선을 그리고자 합니다. 그려진 대각선의 개수를 구하시오.",
        "question_en": "I want to draw a diagonal from some octagon. Find the number of diagonals drawn.",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "8 8 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "8 8 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 8\nvar_b = 8\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 8\nvar_b = 8\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "2340": {
        "category": "Correspondence",
        "question_ko": "네 자리 수인 A614를 6으로 나눈 몫은 네 자리 수입니다. A에 쓸 수 있는 숫자는 모두 몇 개입니까?",
        "question_en": "The quotient of A614, which is a four-digit number, divided by 6 is a four-digit number. How many digits are possible for A?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "A614 [OP_GEN_POSSIBLE_LIST] 6000 [OP_LIST_MORE_EQUAL] 60000 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "A614 [OP_GEN_POSSIBLE_LIST] 6000 [OP_LIST_MORE_EQUAL] 60000 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 'A614'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 6000\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 60000\nlist_c = []\nfor i in list_b:\n    if i < var_c:\n        list_c.append(i)\nvar_d = len(list_c)\nprint(int(var_d))",
        "solution_code_en": "var_a = 'A614'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 6000\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 60000\nlist_c = []\nfor i in list_b:\n    if i < var_c:\n        list_c.append(i)\nvar_d = len(list_c)\nprint(int(var_d))"
    },
    "2341": {
        "category": "Geometry",
        "question_ko": "겉넓이가 150제곱센티미터(㎠)인 정육면체의 부피는 몇 세제곱센티미터(㎤)입니까?",
        "question_en": "What is the volume in cubic centimeters (cm3) of a cube with a surface area of 150 square centimeters (cm2)?",
        "answer_ko": "125",
        "answer_en": "125",
        "solution_abst_ko": "150 6 [OP_DIV] 1/2 [OP_POW] 3 [OP_POW]",
        "solution_abst_en": "150 6 [OP_DIV] 1/2 [OP_POW] 3 [OP_POW]",
        "solution_code_ko": "var_a = 150\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 3\nvar_g = var_e ** var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 150\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 3\nvar_g = var_e ** var_f\nprint(int(var_g))"
    },
    "2342": {
        "category": "Geometry",
        "question_ko": "평행사변형의 넓이는 78.88제곱센티미터(㎠)이며 높이는 8센티미터(㎝)입니다. 밑변의 길이는 얼마입니까?",
        "question_en": "The area of a parallelogram is 78.88 square centimeters (cm2) and its height is 8 centimeters (cm). What is the length of the base?",
        "answer_ko": "9.86",
        "answer_en": "9.86",
        "solution_abst_ko": "78.88 8 [OP_DIV]",
        "solution_abst_en": "78.88 8 [OP_DIV]",
        "solution_code_ko": "var_a = 78.88\nvar_b = 8\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 78.88\nvar_b = 8\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "2343": {
        "category": "Correspondence",
        "question_ko": "사탕을 한 봉지에 6개씩 담으면 4개가 남고, 7개씩 담으면 5개가 남고, 8개씩 담으면 6개가 남고, 10개씩 담으면 8개가 남는다고 한다. 사탕은 최소 몇 개인지 구하여라.",
        "question_en": "If you put 6 candies in a bag, there will be 4 left over, and if you put 7 candies in a bag, there will be 5 left over. If 8 candies are in each bag, 6 will be left, and 10 candies in each bag will have 8 left over. Find the minimum number of candies.",
        "answer_ko": "838",
        "answer_en": "838",
        "solution_abst_ko": "0 9999 1 [OP_LIST_ARANGE] 6 4 [OP_LIST_DIVIDE_AND_REMAIN] 7 5 [OP_LIST_DIVIDE_AND_REMAIN] 8 6 [OP_LIST_DIVIDE_AND_REMAIN] 10 8 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MIN]",
        "solution_abst_en": "0 9999 1 [OP_LIST_ARANGE] 6 4 [OP_LIST_DIVIDE_AND_REMAIN] 7 5 [OP_LIST_DIVIDE_AND_REMAIN] 8 6 [OP_LIST_DIVIDE_AND_REMAIN] 10 8 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 0\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nvar_e = 4\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 7\nvar_g = 5\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 8\nvar_i = 6\nlist_d = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_c:\n    i = int(i)\n    if i%var_h == var_i:\n        list_d.append(i)\nvar_j = 10\nvar_k = 8\nlist_e = [] \nvar_j = int(var_j)\nvar_k = int(var_k)\nif var_k < 0:\n    var_k = var_k + var_j\nfor i in list_d:\n    i = int(i)\n    if i%var_j == var_k:\n        list_e.append(i)\nvar_l = 1\nlist_f=list_e.copy()\nlist_f.sort()\nvar_m = list_f[var_l-1]\nprint(int(var_m))",
        "solution_code_en": "var_a = 0\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nvar_e = 4\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 7\nvar_g = 5\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 8\nvar_i = 6\nlist_d = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_c:\n    i = int(i)\n    if i%var_h == var_i:\n        list_d.append(i)\nvar_j = 10\nvar_k = 8\nlist_e = [] \nvar_j = int(var_j)\nvar_k = int(var_k)\nif var_k < 0:\n    var_k = var_k + var_j\nfor i in list_d:\n    i = int(i)\n    if i%var_j == var_k:\n        list_e.append(i)\nvar_l = 1\nlist_f=list_e.copy()\nlist_f.sort()\nvar_m = list_f[var_l-1]\nprint(int(var_m))"
    },
    "2344": {
        "category": "Arithmetic calculation",
        "question_ko": "원 모양의 연못을 따라 30미터(m) 간격으로 버드나무가 심어져 있습니다. 연못의 둘레가 1킬로미터(㎞) 200미터(m)라면, 버드나무는 모두 몇 그루 심어진 것입니까?",
        "question_en": "Willow trees are planted at 30-meter (m) intervals along the circular pond. If the circumference of the pond is 1 kilometer (km) and 200 meters (m), how many willow trees were planted in all?",
        "answer_ko": "40",
        "answer_en": "40",
        "solution_abst_ko": "1 1000 [OP_MUL] 200 [OP_ADD] 30 [OP_DIV]",
        "solution_abst_en": "1 1000 [OP_MUL] 200 [OP_ADD] 30 [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 200\nvar_e = var_c + var_d\nvar_f = 30\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 200\nvar_e = var_c + var_d\nvar_f = 30\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "2345": {
        "category": "Correspondence",
        "question_ko": "AB2-41=591일 때, B에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "When AB2-41=591 is true, what number should go in B?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "AB2-41=591 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "AB2-41=591 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'AB2-41=591'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'AB2-41=591'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "2346": {
        "category": "Arithmetic calculation",
        "question_ko": "직선 도로에 가로수가 30개 있습니다. 가로수 사이의 간격이 3미터(m)이고, 첫 가로수와 마지막 가로수 사이의 거리는 얼마인지 구하시오.",
        "question_en": "There are 30 trees along the straight road. If the distance between every tree is 3 meters (m), what is the distance between the first and the last trees?",
        "answer_ko": "87",
        "answer_en": "87",
        "solution_abst_ko": "3 30 1 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "3 30 1 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 30\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 3\nvar_b = 30\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nprint(int(var_e))"
    },
    "2347": {
        "category": "Comparison",
        "question_ko": "주만이가 가지고 있는 색 테이프의 길이는 0.6미터(m)입니다. 정호가 가지고 있는 색 테이프의 길이는 주만이보다 3/10미터(m) 더 깁니다. 지용이가 가지고 있는 색 테이프의 길이는 19/25미터(m)이고, 철중이가 가지고 있는 색 테이프의 길이는 지용이보다 0.2미터(m) 더 짧습니다. 가지고 있는 색 테이프의 길이가 2번째로 짧은 사람은 누구입니까?",
        "question_en": "The length of the colored tape that Juman has is 0.6 meters (m). The length of the colored tape that Jeongho has is 3/10 meters (m) longer than that of Juman. Jiyong's colored tape is 19/25 meters (m) long, and Cheoljung's colored tape is 0.2 meters (m) shorter than Jiyong's. Who has the 2nd shortest colored tape?",
        "answer_ko": "주만",
        "answer_en": "Juman",
        "solution_abst_ko": "[OP_LIST_SOL] 주만 정호 지용 철중 [OP_LIST_EOL] [OP_LIST_SOL] 0.6 0.6 3/10 [OP_ADD] 19/25 19/25 0.2 [OP_SUB] [OP_LIST_EOL] 2 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Juman Jeongho Jiyong Cheoljung [OP_LIST_EOL] [OP_LIST_SOL] 0.6 0.6 3/10 [OP_ADD] 19/25 19/25 0.2 [OP_SUB] [OP_LIST_EOL] 2 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '주만'\nvar_b = '정호'\nvar_c = '지용'\nvar_d = '철중'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.6\nvar_f = 0.6\nvar_g = 0.3\nvar_h = var_f + var_g\nvar_i = 0.76\nvar_j = 0.76\nvar_k = 0.2\nvar_l = var_j - var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_m = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[var_m-1]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'Juman'\nvar_b = 'Jeongho'\nvar_c = 'Jiyong'\nvar_d = 'Cheoljung'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.6\nvar_f = 0.6\nvar_g = 0.3\nvar_h = var_f + var_g\nvar_i = 0.76\nvar_j = 0.76\nvar_k = 0.2\nvar_l = var_j - var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_m = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[var_m-1]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "2348": {
        "category": "Correspondence",
        "question_ko": "20이 어떤 수를 3으로 나누고 12를 더해준 값이라면 어떤 수는 얼마입니까?",
        "question_en": "If 20 is the product of some number divided by 3 and 12 added, what is that number?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "20 12 [OP_SUB] 3 [OP_MUL]",
        "solution_abst_en": "20 12 [OP_SUB] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 20\nvar_b = 12\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 12\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "2349": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중에서 가장 큰 수를 2번째로 작은 수로 나눈 몫은 얼마입니까?",
        "question_en": "There are three numbers 10, 11, and 12. What is the quotient of the largest number divided by the second smallest number?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_FDIV]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_FDIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e // var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e // var_g\nprint(int(var_h))"
    },
    "2350": {
        "category": "Geometry",
        "question_ko": "재웅이가 사려는 선물 상자는 가로가 9센티미터(㎝), 세로가 4센티미터(㎝), 높이가 7센티미터(㎝)입니다. 이 선물 상자의 부피는 몇 세제곱센티미터(㎤)입니까?",
        "question_en": "The gift box that Jaewoong is buying is 9 centimeters (cm) wide, 4 centimeters (cm) long, and 7 centimeters (cm) high. What is this gift box's volume in cubic centimeters (cm3)?",
        "answer_ko": "252",
        "answer_en": "252",
        "solution_abst_ko": "9 4 [OP_MUL] 7 [OP_MUL]",
        "solution_abst_en": "9 4 [OP_MUL] 7 [OP_MUL]",
        "solution_code_ko": "var_a = 9\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "2351": {
        "category": "Comparison",
        "question_ko": "1개의 무게가 200g인 단팥빵을 16개씩 담은 상자가 3개 있습니다. 1개의 무게가 250g인 소라빵을 12개씩 담은 상자는 2개 있습니다. 빈 상자의 무게는 모두 같습니다. 한 상자의 무게가 더 무거운 상자 안에 들어 있는 빵은 무엇입니까?",
        "question_en": "There are 3 boxes containing 16 Red-bean bread each weighing 200 grams (g). There are 2 boxes containing 12 pieces of conch-shaped bread each weighing 250 grams (g). All empty boxes weigh the same. Which bread is in the box that weighs more than other boxes?",
        "answer_ko": "단팥빵",
        "answer_en": "Red-bean",
        "solution_abst_ko": "[OP_LIST_SOL] 단팥빵 소라빵 [OP_LIST_EOL] [OP_LIST_SOL] 200 16 [OP_MUL] 250 12 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Red-bean conch-shaped [OP_LIST_EOL] [OP_LIST_SOL] 200 16 [OP_MUL] 250 12 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '단팥빵'\nvar_b = '소라빵'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 200\nvar_d = 16\nvar_e = var_c * var_d\nvar_f = 250\nvar_g = 12\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Red-bean'\nvar_b = 'conch-shaped'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 200\nvar_d = 16\nvar_e = var_c * var_d\nvar_f = 250\nvar_g = 12\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "2352": {
        "category": "Arithmetic calculation",
        "question_ko": "손자의 나이에 6을 곱하면 할아버지의 나이와 같습니다. 4년 후 할아버지와 손자의 나이를 더하면 78일 때, 현재 손자는 몇 살입니까?",
        "question_en": "Multiplying the grandson's age by 6 equals the grandfather's age. After 4 years, the ages of grandfather and grandson add up to be 78. How old is the grandson now?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "78 4 2 [OP_MUL] [OP_SUB] 1 6 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "78 4 2 [OP_MUL] [OP_SUB] 1 6 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 78\nvar_b = 4\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = 6\nvar_h = var_f + var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 78\nvar_b = 4\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = 6\nvar_h = var_f + var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "2353": {
        "category": "Arithmetic calculation",
        "question_ko": "연석이는 오늘 18미터(m)를 달렸습니다. 매일 2배씩 거리를 늘려 달린다면 넷째날에는 몇 미터(m)를 달리게 되는 지 구하세요.",
        "question_en": "Yeon-seok ran 18 meters (m) today. If he doubles his distance each day, find how many meters (m) he would run on the fourth day.",
        "answer_ko": "144",
        "answer_en": "144",
        "solution_abst_ko": "18 2 4 1 [OP_SUB] [OP_POW] [OP_MUL]",
        "solution_abst_en": "18 2 4 1 [OP_SUB] [OP_POW] [OP_MUL]",
        "solution_code_ko": "var_a = 18\nvar_b = 2\nvar_c = 4\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = var_b ** var_e\nvar_g = var_a * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 18\nvar_b = 2\nvar_c = 4\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = var_b ** var_e\nvar_g = var_a * var_f\nprint(int(var_g))"
    },
    "2354": {
        "category": "Comparison",
        "question_ko": "윤기는 4개, 정국이는 6 나누기 3만큼의 사과를 모았고, 유나는 5개의 사과를 모았습니다. 누가 가진 사과가 가장 많습니까?",
        "question_en": "Yoongi collected 4 apples, Jungkook collected 6 divided by 3 apples, and Yuna collected 5 apples. Whose apples are the most?",
        "answer_ko": "유나",
        "answer_en": "Yuna",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 유나 [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_FDIV] 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook Yuna [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_FDIV] 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nvar_c = '유나'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 6\nvar_f = 3\nvar_g = var_e // var_f\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nvar_c = 'Yuna'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 6\nvar_f = 3\nvar_g = var_e // var_f\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "2355": {
        "category": "Possibility",
        "question_ko": "세 자연수 1, 6, 8을 한 번씩 이용하여 만들 수 있는 가장 큰 세 자리 수와 세 번째로 작은 세 자리 수의 합을 구하시오.",
        "question_en": "Find the sum of the largest and the third smallest three-digit number that can be created by using the three natural numbers 1, 6, and 8 once.",
        "answer_ko": "1479",
        "answer_en": "1479",
        "solution_abst_ko": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))"
    },
    "2356": {
        "category": "Geometry",
        "question_ko": "길이가 12센티미터(㎝)인 종이를 반으로 한 번 접었더니 가운데에 선이 하나 생겼습니다. 종이의 끝에서 가운데 선까지의 길이는 얼마입니까?",
        "question_en": "A piece of paper that is 12 centimeters (cm) long was folded in half once, leaving a line in the middle. How long is it from the end of the paper to the central line?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "12 2 [OP_DIV]",
        "solution_abst_en": "12 2 [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 12\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "2357": {
        "category": "Correspondence",
        "question_ko": "어떤 과일 박스에 배와 사과가 들어있다. 이 과일을 4개씩 포장하였더니 12묶음이 나오고 3개가 남았다. 사과가 12개 있다면, 배는 몇 개인지 구하시오.",
        "question_en": "Some fruit boxes contain pears and apples. When these fruits were packed in 4 pieces, 12 bundles came out and 3 pieces remained. If there are 12 apples, how many pears are there?",
        "answer_ko": "39",
        "answer_en": "39",
        "solution_abst_ko": "12 4 [OP_MUL] 3 [OP_ADD] 12 [OP_SUB]",
        "solution_abst_en": "12 4 [OP_MUL] 3 [OP_ADD] 12 [OP_SUB]",
        "solution_code_ko": "var_a = 12\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = 12\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 12\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = 12\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "2358": {
        "category": "Correspondence",
        "question_ko": "17은 어떤수에서 28을 빼야 할것을 실수로 82를 빼서 나온 결과입니다. 어떤 수를 구하세요.",
        "question_en": "17 is the result of mistakenly subtracting 82 from a certain number that should have subtracted 28. Find the certain number.",
        "answer_ko": "99",
        "answer_en": "99",
        "solution_abst_ko": "17 82 [OP_ADD]",
        "solution_abst_en": "17 82 [OP_ADD]",
        "solution_code_ko": "var_a = 17\nvar_b = 82\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 17\nvar_b = 82\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "2359": {
        "category": "Correspondence",
        "question_ko": "식 38A-B1=364이 있습니다. B에 들어가야 하는 숫자를 구하시오",
        "question_en": "We have the expression 38A-B1=364. Find the number that is required in B.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "38A-B1=364 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "38A-B1=364 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '38A-B1=364'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '38A-B1=364'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "2360": {
        "category": "Arithmetic calculation",
        "question_ko": "은지는 마트에 갔습니다. 가지고 간 돈의 1/4로 장난감을 사고, 나머지 돈의 1/3로 책을 샀습니다. 남은 돈이 1,600원이라면 은지가 처음에 가지고 간 돈은 얼마입니까?",
        "question_en": "Eunji went to the mart. She bought a toy with 1/4 of the total money and a book with 1/3 of the remaining money. If she ended up having 1,600 won, how much money did Eunji take at the beginning?",
        "answer_ko": "3200",
        "answer_en": "3200",
        "solution_abst_ko": "1600 1 1/3 [OP_SUB] [OP_DIV] 1 1/4 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "1600 1 1/3 [OP_SUB] [OP_DIV] 1 1/4 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 1600\nvar_b = 1\nvar_c = 0.3333333333333333\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 1\nvar_g = 0.25\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))",
        "solution_code_en": "var_a = 1600\nvar_b = 1\nvar_c = 0.3333333333333333\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 1\nvar_g = 0.25\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))"
    },
    "2361": {
        "category": "Geometry",
        "question_ko": "정육면체가 있을 때 모서리의 수를 구하시오.",
        "question_en": "What is the number of edges of a cube?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "6 2 [OP_SUB] 3 [OP_MUL]",
        "solution_abst_en": "6 2 [OP_SUB] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "2362": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 32를 더하고 12를 곱하여야 하는데 실수로 3을 곱하고 45를 빼서 159가 나왔다고 한다. 올바르게 계산하면 얼마인지 구하시오.",
        "question_en": "I should have added 32 to a number and multiply it by 12 but I accidently multiplied it by 3 and subtracted 45, and 159 came out as a result. If you calculate this correctly, how much is it? ",
        "answer_ko": "1200",
        "answer_en": "1200",
        "solution_abst_ko": "159 45 [OP_ADD] 3 [OP_DIV] 32 [OP_ADD] 12 [OP_MUL]",
        "solution_abst_en": "159 45 [OP_ADD] 3 [OP_DIV] 32 [OP_ADD] 12 [OP_MUL]",
        "solution_code_ko": "var_a = 159\nvar_b = 45\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = 32\nvar_g = var_e + var_f\nvar_h = 12\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 159\nvar_b = 45\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = 32\nvar_g = var_e + var_f\nvar_h = 12\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "2363": {
        "category": "Possibility",
        "question_ko": "서희네 집에서 학교까지 가는 버스 노선은 3개, 지하철 노선은 2개일 때 지하철로 가는 경우의 수를 구하시오.",
        "question_en": "If there are 3 bus routes and 2 subway routes going from Seohee's house to school, find the number of ways to go by subway.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 3 2 [OP_LIST_EOL] [OP_LIST_SOL] 버스 지하철 [OP_LIST_EOL] 지하철 [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] 3 2 [OP_LIST_EOL] [OP_LIST_SOL] bus subway [OP_LIST_EOL] subway [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = '버스'\nvar_d = '지하철'\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = '지하철'\nvar_f = list_b.index(var_e)+1\nvar_g = list_a[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 'bus'\nvar_d = 'subway'\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 'subway'\nvar_f = list_b.index(var_e)+1\nvar_g = list_a[var_f-1]\nprint(int(var_g))"
    },
    "2364": {
        "category": "Possibility",
        "question_ko": "공 던지기 놀이를 합니다. 빨간색 원 안에 맞히면 3점, 노란색 원 안에 맞히면 2점, 원 안에 맞히지 못하면 1점입니다. 공을 3번 던질 때 얻을 수 있는 서로 다른 점수는 모두 몇 가지입니까?",
        "question_en": "You are playing ball toss. If you hit inside the red circle, you get 3 points, if you hit inside the yellow circle, you get 2 points, and if you don't hit inside the circle, you get 1 point. How many different points can you get by throwing the ball 3 times?",
        "answer_ko": "27",
        "answer_en": "27",
        "solution_abst_ko": "[OP_LIST_SOL] 3 2 1 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_NUM2SUM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 3 2 1 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_NUM2SUM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = 1\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = 1\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "2365": {
        "category": "Comparison",
        "question_ko": "네 명의 학생 윤기, 정국, 유나, 유정은 각각 7, 6, 9, 8만큼의 숫자를 가지고 있습니다. 2번째로 작은 숫자를 가진 사람은 누구입니까?",
        "question_en": "The four students, Yoongi, Jungkook, Yuna, and Yoojung, each have the numbers 7, 6, 9, and 8. Who has the 2nd smallest number?",
        "answer_ko": "윤기",
        "answer_en": "Yoongi",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 유나 유정 [OP_LIST_EOL] [OP_LIST_SOL] 7 6 9 8 [OP_LIST_EOL] 2 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook Yuna Yoojung [OP_LIST_EOL] [OP_LIST_SOL] 7 6 9 8 [OP_LIST_EOL] 2 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nvar_c = '유나'\nvar_d = '유정'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 7\nvar_f = 6\nvar_g = 9\nvar_h = 8\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nvar_c = 'Yuna'\nvar_d = 'Yoojung'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 7\nvar_f = 6\nvar_g = 9\nvar_h = 8\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "2366": {
        "category": "Comparison",
        "question_ko": "승아, 경환, 도윤 세 친구에겐 각각 용돈이 2만원씩 있습니다. 세 사람이 쓰고 남은 용돈을 보니 승아는 전체의 1/4, 경환이는 전체의 1/8, 도윤이는 전체의 1/5라면 용돈을 가장 많이 쓴 사람은 누구인지 구하시오.",
        "question_en": "The three friends Seunga, Kyunghwan, and Doyun each have 20,000 won in pocket money. Looking at the remaining pocket money of the three people, if Seunga is 1/4 of the total, Kyunghwan is 1/8 of the total, and Doyun is 1/5 of the total, find out who spent the most pocket money.",
        "answer_ko": "경환",
        "answer_en": "Kyunghwan",
        "solution_abst_ko": "[OP_LIST_SOL] 승아 경환 도윤 [OP_LIST_EOL] [OP_LIST_SOL] 1 1/4 [OP_SUB] 1 1/8 [OP_SUB] 1 1/5 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Seunga Kyunghwan Doyun [OP_LIST_EOL] [OP_LIST_SOL] 1 1/4 [OP_SUB] 1 1/8 [OP_SUB] 1 1/5 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '승아'\nvar_b = '경환'\nvar_c = '도윤'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nvar_e = 0.25\nvar_f = var_d - var_e\nvar_g = 1\nvar_h = 0.125\nvar_i = var_g - var_h\nvar_j = 1\nvar_k = 0.2\nvar_l = var_j - var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'Seunga'\nvar_b = 'Kyunghwan'\nvar_c = 'Doyun'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nvar_e = 0.25\nvar_f = var_d - var_e\nvar_g = 1\nvar_h = 0.125\nvar_i = var_g - var_h\nvar_j = 1\nvar_k = 0.2\nvar_l = var_j - var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "2367": {
        "category": "Arithmetic calculation",
        "question_ko": "파란 구슬 수는 빨간 구슬 수의 3배이고 빨간 구슬의 수는 노란 구슬의 수보다 15개가 더 많다. 모든 구슬의 개수가 165개 일 때, 파란 구슬의 수를 구하시오.",
        "question_en": "The number of blue marbles is 3 times the number of red marbles and the number of red marbles is 15 more than the number of yellow marbles. If the number of all marbles is 165, find the number of blue marbles.",
        "answer_ko": "108",
        "answer_en": "108",
        "solution_abst_ko": "165 15 [OP_ADD] 3 1 1 [OP_ADD] [OP_ADD] [OP_DIV] 3 [OP_MUL]",
        "solution_abst_en": "165 15 [OP_ADD] 3 1 1 [OP_ADD] [OP_ADD] [OP_DIV] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 165\nvar_b = 15\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 1\nvar_f = 1\nvar_g = var_e + var_f\nvar_h = var_d + var_g\nvar_i = var_c / var_h\nvar_j = 3\nvar_k = var_i * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 165\nvar_b = 15\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 1\nvar_f = 1\nvar_g = var_e + var_f\nvar_h = var_d + var_g\nvar_i = var_c / var_h\nvar_j = 3\nvar_k = var_i * var_j\nprint(int(var_k))"
    },
    "2368": {
        "category": "Possibility",
        "question_ko": "2, 0, 5, 9, 6 중에서 3개를 뽑아 한 번씩만 사용하여 세 자리 수를 만들려고 합니다. 만들 수 있는 가장 큰 수와 가장 작은 수의 차를 구하시오.",
        "question_en": "You want to create a three-digit number using some numbers from 2, 0, 5, 9, and 6 without any duplicates. Find the value of the largest number minus the smallest number.",
        "answer_ko": "760",
        "answer_en": "760",
        "solution_abst_ko": "[OP_LIST_SOL] 2 0 5 9 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "[OP_LIST_SOL] 2 0 5 9 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 2\nvar_b = 0\nvar_c = 5\nvar_d = 9\nvar_e = 6\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h - var_j\nvar_l = abs(var_k)\nprint(int(var_l))",
        "solution_code_en": "var_a = 2\nvar_b = 0\nvar_c = 5\nvar_d = 9\nvar_e = 6\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h - var_j\nvar_l = abs(var_k)\nprint(int(var_l))"
    },
    "2369": {
        "category": "Arithmetic calculation",
        "question_ko": "지민이는 문구점에 가서 빨간 볼펜 37자루와 파란 볼펜 17자루를 샀습니다. 볼펜은 모두 몇 자루입니까?",
        "question_en": "Jimin went to the stationery store and bought 37 red ballpoint pens and 17 blue ballpoint pens. How many ballpoint pens are there in all?",
        "answer_ko": "54",
        "answer_en": "54",
        "solution_abst_ko": "37 17 [OP_ADD]",
        "solution_abst_en": "37 17 [OP_ADD]",
        "solution_code_ko": "var_a = 37\nvar_b = 17\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 37\nvar_b = 17\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "2370": {
        "category": "Geometry",
        "question_ko": "현성이는 수학시간에 색종이로 옆면의 모서리의 길이가 8센티미터(㎝)인 육각뿔을 만들었습니다. 이 각뿔의 모든 모서리의 길이의 합이 120센티미터(㎝)라면, 밑면의 한 변의 길이는 몇이 되겠습니까?",
        "question_en": "Hyeonseong made a hexagonal pyramid with a side edge of 8 centimeters (cm) on colored paper during math class. If the sum of the lengths of all the edges of this pyramid is 120 centimeters (cm), how long is the length of one edge of the base?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "120 8 6 [OP_MUL] [OP_SUB] 6 [OP_DIV]",
        "solution_abst_en": "120 8 6 [OP_MUL] [OP_SUB] 6 [OP_DIV]",
        "solution_code_ko": "var_a = 120\nvar_b = 8\nvar_c = 6\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 6\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 120\nvar_b = 8\nvar_c = 6\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 6\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "2371": {
        "category": "Correspondence",
        "question_ko": "23을 어떤 수에서 빼야하는데 실수로 32를 뺐더니 25가 됐습니다. 바르게 계산하면 얼마입니까?",
        "question_en": "I need to subtract 23 from a number, but I accidentally subtracted 32 and it turned out to be 25. How much do you get if you calculate it right?",
        "answer_ko": "34",
        "answer_en": "34",
        "solution_abst_ko": "25 32 [OP_ADD] 23 [OP_SUB]",
        "solution_abst_en": "25 32 [OP_ADD] 23 [OP_SUB]",
        "solution_code_ko": "var_a = 25\nvar_b = 32\nvar_c = var_a + var_b\nvar_d = 23\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 25\nvar_b = 32\nvar_c = var_a + var_b\nvar_d = 23\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "2372": {
        "category": "Correspondence",
        "question_ko": "상자 안에 사탕이 들어 있습니다. 이 사탕을 30개씩 포장하면 14개가 남고, 50개씩 포장하면 24개가 남고, 70개씩 포장하면 34개가 남습니다. 상자 안에 들어있는 사탕은 최소 몇 개인지 구하시오.",
        "question_en": "There are candies in the box. If you pack 30 of these candies, you have 14 leftovers, if you pack 50 of these candies, you have 24 left over, and if you pack 70 of these candies, you have 34 left over. Find the minimum number of candies in the box.",
        "answer_ko": "524",
        "answer_en": "524",
        "solution_abst_ko": "0 9999 1 [OP_LIST_ARANGE] 30 14 [OP_LIST_DIVIDE_AND_REMAIN] 50 24 [OP_LIST_DIVIDE_AND_REMAIN] 70 34 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MIN]",
        "solution_abst_en": "0 9999 1 [OP_LIST_ARANGE] 30 14 [OP_LIST_DIVIDE_AND_REMAIN] 50 24 [OP_LIST_DIVIDE_AND_REMAIN] 70 34 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 0\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 30\nvar_e = 14\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 50\nvar_g = 24\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 70\nvar_i = 34\nlist_d = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_c:\n    i = int(i)\n    if i%var_h == var_i:\n        list_d.append(i)\nvar_j = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_k = list_e[var_j-1]\nprint(int(var_k))",
        "solution_code_en": "var_a = 0\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 30\nvar_e = 14\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 50\nvar_g = 24\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 70\nvar_i = 34\nlist_d = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_c:\n    i = int(i)\n    if i%var_h == var_i:\n        list_d.append(i)\nvar_j = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_k = list_e[var_j-1]\nprint(int(var_k))"
    },
    "2373": {
        "category": "Possibility",
        "question_ko": "현지, 은정, 미금, 영미 4명의 학생을 한 줄로 세울 때, 현지가 맨 앞 또는 맨 뒤에 서는 경우의 수를 구하여라",
        "question_en": "When 4 students: Hyunji, Eunjeong, Migeum, and Youngmi stand in a line, find the number of cases in which Hyunji stands at the front or at the back.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "[OP_LIST_SOL] 현지 은정 미금 영미 [OP_LIST_EOL] [OP_LIST_SOL] 현지 [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] 앞 뒤 [OP_LIST_EOL] [OP_LIST_LEN] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] Hyunji Eunjeong Migeum Youngmi [OP_LIST_EOL] [OP_LIST_SOL] Hyunji [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] Front Back [OP_LIST_EOL] [OP_LIST_LEN] [OP_MUL]",
        "solution_code_ko": "var_a = '현지'\nvar_b = '은정'\nvar_c = '미금'\nvar_d = '영미'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '현지'\nlist_b= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_f = len(list_c)\nvar_g = len(list_c)\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nvar_i = '앞'\nvar_j = '뒤'\nlist_d= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_d.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_d.append(var_i)\nlist_d.reverse()\nvar_k = len(list_d)\nvar_l = var_h * var_k\nprint(int(var_l))",
        "solution_code_en": "var_a = 'Hyunji'\nvar_b = 'Eunjeong'\nvar_c = 'Migeum'\nvar_d = 'Youngmi'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'Hyunji'\nlist_b= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_f = len(list_c)\nvar_g = len(list_c)\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nvar_i = 'Front'\nvar_j = 'Back'\nlist_d= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_d.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_d.append(var_i)\nlist_d.reverse()\nvar_k = len(list_d)\nvar_l = var_h * var_k\nprint(int(var_l))"
    },
    "2374": {
        "category": "Arithmetic calculation",
        "question_ko": "줄자 24장을 겹쳐서 한 줄로 이어 붙이려고 합니다. 줄자 하나의 길이가 28센티미터(㎝)이며 이어 붙인 길이가 580센티미터(㎝)라면 줄자를 몇 센티미터(㎝)씩 이어 붙인 것인지 구해 보세요.",
        "question_en": "You are going to overlap 24 pieces of a tape measure and connect them in one line. If the length of one tape measure is 28 centimeters (cm), and the length of all connected tape measures is 580 centimeters (cm), find out how many centimeters (cm) a tape measure is connected each.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "28 24 [OP_MUL] 580 [OP_SUB] 24 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "28 24 [OP_MUL] 580 [OP_SUB] 24 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 28\nvar_b = 24\nvar_c = var_a * var_b\nvar_d = 580\nvar_e = var_c - var_d\nvar_f = 24\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 28\nvar_b = 24\nvar_c = var_a * var_b\nvar_d = 580\nvar_e = var_c - var_d\nvar_f = 24\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "2375": {
        "category": "Arithmetic calculation",
        "question_ko": "윤환이는 1달에 182.88리터(L)의 물을 마십니다. 윤환이가 1년 동안 마시는 물의 양은 얼마입니까?",
        "question_en": "When Yunhwan drinks 182.88 liters (L) of water per month, how much water does Yunhwan drink for a year?",
        "answer_ko": "2194.56",
        "answer_en": "2194.56",
        "solution_abst_ko": "182.88 12 [OP_MUL]",
        "solution_abst_en": "182.88 12 [OP_MUL]",
        "solution_code_ko": "var_a = 182.88\nvar_b = 12\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 182.88\nvar_b = 12\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "2376": {
        "category": "Possibility",
        "question_ko": "3,5를 한 번씩만 사용해서 서로 다른 두 자리수를 만드려고 합니다. 이때 만들 수 있는 두 자리 수는 모두 몇 개입니까?",
        "question_en": "You want to create two different digit numbers by using 3 and 5 only once. How many two-digit numbers can you make?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 3 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 3 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 3\nvar_b = 5\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = len(list_b)\nprint(int(var_d))",
        "solution_code_en": "var_a = 3\nvar_b = 5\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = len(list_b)\nprint(int(var_d))"
    },
    "2377": {
        "category": "Arithmetic calculation",
        "question_ko": "28 초과 31 이하인 자연수를 모두 더하면 모두 얼마 입니까",
        "question_en": "What is the sum of all natural numbers greater than 28 and less than or equal to 31?",
        "answer_ko": "90",
        "answer_en": "90",
        "solution_abst_ko": "28 1 [OP_ADD] 31 1 [OP_LIST_ARANGE] [OP_LIST_SUM]",
        "solution_abst_en": "28 1 [OP_ADD] 31 1 [OP_LIST_ARANGE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 28\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 31\nvar_e = 1\nlist_a = [i for i in range(var_c, var_d + 1, var_e)]\nlist_a = [float(i) for i in list_a]\nvar_f = sum(list_a)\nprint(int(var_f))",
        "solution_code_en": "var_a = 28\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 31\nvar_e = 1\nlist_a = [i for i in range(var_c, var_d + 1, var_e)]\nlist_a = [float(i) for i in list_a]\nvar_f = sum(list_a)\nprint(int(var_f))"
    },
    "2378": {
        "category": "Comparison",
        "question_ko": "호석이는 항상 어느 줄의 왼쪽에서 4번째, 오른쪽에서 9번째에 섭니다. 줄넘기를 할 때마다 5줄로 서고 각줄의 학생 수가 같을때 학생들은 모두 몇 명입니까?",
        "question_en": "Hoseok is always 4th from the left and 9th from the right in a row. How many students are there if there are 5 lines every time they jump rope and the number of students in each line is the same?",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "5 4 9 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "5 4 9 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 4\nvar_c = 9\nvar_d = var_b + var_c\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_a * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 4\nvar_c = 9\nvar_d = var_b + var_c\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_a * var_f\nprint(int(var_g))"
    },
    "2379": {
        "category": "Geometry",
        "question_ko": "직각삼각형에서, 어느 빗변의 길이가 10일 때, 빗변이 아닌 한 변의 길이가 6이라면 나머지 한 변의 길이는?",
        "question_en": "In a right triangle, when a hypotenuse is 10, what is the length of the other side of the length of one side other than the hypotenuse is 6?\n",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "10 2 [OP_POW] 6 2 [OP_POW] [OP_SUB] 1/2 [OP_POW]",
        "solution_abst_en": "10 2 [OP_POW] 6 2 [OP_POW] [OP_SUB] 1/2 [OP_POW]",
        "solution_code_ko": "var_a = 10\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c - var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c - var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))"
    },
    "2380": {
        "category": "Comparison",
        "question_ko": "호박의 무게는 2와 9/10킬로그램(㎏), 수박의 무게는 41/10킬로그램(㎏)입니다. 호박과 수박 중 어느 것이 더 무거울까요?",
        "question_en": "A pumpkin weighs 2 and 9/10 of a kilogram (kg), and a watermelon weighs 41/10 kilograms (kg). Which is heavier, the pumpkin or the watermelon?",
        "answer_ko": "수박",
        "answer_en": "watermelon",
        "solution_abst_ko": "[OP_LIST_SOL] 호박 수박 [OP_LIST_EOL] [OP_LIST_SOL] 2 9/10 [OP_ADD] 41/10 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] pumpkin watermelon [OP_LIST_EOL] [OP_LIST_SOL] 2 9/10 [OP_ADD] 41/10 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '호박'\nvar_b = '수박'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nvar_d = 0.9\nvar_e = var_c + var_d\nvar_f = 4.1\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'pumpkin'\nvar_b = 'watermelon'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nvar_d = 0.9\nvar_e = var_c + var_d\nvar_f = 4.1\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "2381": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 가장 큰 수와 2번째로 큰 수의 곱은 얼마입니까?",
        "question_en": "There are five numbers: 10, 11, 12, 13, and 14. What is the product of the largest number and the second largest number?",
        "answer_ko": "182",
        "answer_en": "182",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[-var_h]\nvar_j = var_g * var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[-var_h]\nvar_j = var_g * var_i\nprint(int(var_j))"
    },
    "2382": {
        "category": "Geometry",
        "question_ko": "직사각형에서 직각은 모두 몇 개입니까?",
        "question_en": "How many right angles are there in a rectangle?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "4",
        "solution_abst_en": "4",
        "solution_code_ko": "var_a = 4\nprint(int(var_a))",
        "solution_code_en": "var_a = 4\nprint(int(var_a))"
    },
    "2383": {
        "category": "Arithmetic calculation",
        "question_ko": "연속하는 두 홀수의 합이 48일 때 두 홀수 중 작은 수를 구하시오.",
        "question_en": "Find the smaller one between the two odd numbers when the sum of two consecutive odd numbers is 48.",
        "answer_ko": "23",
        "answer_en": "23",
        "solution_abst_ko": "48 2 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "48 2 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 48\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 48\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "2384": {
        "category": "Correspondence",
        "question_ko": "칠판지우개는 각 반마다 3개씩 있는데 망가진 칠판지우개 12개를 모아서 버렸더니 남은 개수가 60개였다. 반의 수를 3으로 나누고 12를 더한 값을 구하시오.",
        "question_en": "There are three blackboard erasers in each class, but after gathering 12 broken blackboard erasers and throwing them out, there remained 60. Find the number of classes divided by 3 and then added by 12.",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "60 12 [OP_ADD] 3 [OP_DIV] 3 [OP_DIV] 12 [OP_ADD]",
        "solution_abst_en": "60 12 [OP_ADD] 3 [OP_DIV] 3 [OP_DIV] 12 [OP_ADD]",
        "solution_code_ko": "var_a = 60\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = 12\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 60\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = 12\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "2385": {
        "category": "Comparison",
        "question_ko": "윤기는 4, 정국에는 6에서 3을 뺀 수를 모았습니다. 누가 큰 수를 가지고 있나요?",
        "question_en": "Yoongi collected 4 points, and Jungkook collected  6 minus 3 points. Who has the big number?",
        "answer_ko": "윤기",
        "answer_en": "Yoongi",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 6\nvar_e = 3\nvar_f = var_d - var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 6\nvar_e = 3\nvar_f = var_d - var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "2386": {
        "category": "Possibility",
        "question_ko": "A, B, C, D, E 5명이 있을 때, 대표 2명을 뽑는 경우의 수를 구하시오.",
        "question_en": "If there are 5 people A, B, C, D, and E, find the number of ways to select 2 representatives.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "5 2 [OP_COMB]",
        "solution_abst_en": "5 2 [OP_COMB]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))"
    },
    "2387": {
        "category": "Arithmetic calculation",
        "question_ko": "정민이는 매일 300원을 저금하고 시우는 매일 500원을 저금한다고 합니다. 현재 정민이의 통장에는 12000원이 들어있고 시우의 통장에는 4000원이 들어있습니다. 며칠이 지나야 정민이와 시우의 통장에 들어있는 금액이 같아지겠습니까?",
        "question_en": "Jeongmin saves 300 won every day and Siwoo saves 500 won every day. Currently, there are 12,000 won in Jeongmin's bank account and 4,000 won in Siwoo's bank account. How many days have to pass so that the amounts in Jung-min's and Siwoo's bank accounts be the same?",
        "answer_ko": "40",
        "answer_en": "40",
        "solution_abst_ko": "12000 4000 [OP_SUB] 500 300 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "12000 4000 [OP_SUB] 500 300 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 12000\nvar_b = 4000\nvar_c = var_a - var_b\nvar_d = 500\nvar_e = 300\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 12000\nvar_b = 4000\nvar_c = var_a - var_b\nvar_d = 500\nvar_e = 300\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))"
    },
    "2388": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 5, 6, 2로 나누어 떨어질 수 있는 수 중 가장 작은 네 자리 수는 무엇입니까?",
        "question_en": "What is the smallest 4-digit number that is divisible by 3 numbers 5, 6, and 2?",
        "answer_ko": "1020",
        "answer_en": "1020",
        "solution_abst_ko": "1000 9999 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] 6 [OP_LIST_DIVISIBLE] 2 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "1000 9999 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] 6 [OP_LIST_DIVISIBLE] 2 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 6\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 2\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_h = list_e[var_g-1]\nprint(int(var_h))",
        "solution_code_en": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 6\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 2\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_h = list_e[var_g-1]\nprint(int(var_h))"
    },
    "2389": {
        "category": "Geometry",
        "question_ko": "정사각형의 한 대각선의 길이가 12센티미터(㎝)일 때 이 정사각형의 넓이는?",
        "question_en": "If the length of one diagonal of a square is 12 centimeters (cm), what is the area of the square?",
        "answer_ko": "72",
        "answer_en": "72",
        "solution_abst_ko": "12 2 [OP_POW] 2 [OP_DIV]",
        "solution_abst_en": "12 2 [OP_POW] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "2390": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 152를 더해야 할 것을 잘못하여 뺐더니 346이 되었습니다. 바르게 계산하면 얼마인지 구해 보시오.",
        "question_en": "You incorrectly subtracted 152 when you should have added 152 to a number, resulting in 346. Find what the correct number would be.",
        "answer_ko": "650",
        "answer_en": "650",
        "solution_abst_ko": "346 152 [OP_ADD] 152 [OP_ADD]",
        "solution_abst_en": "346 152 [OP_ADD] 152 [OP_ADD]",
        "solution_code_ko": "var_a = 346\nvar_b = 152\nvar_c = var_a + var_b\nvar_d = 152\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 346\nvar_b = 152\nvar_c = var_a + var_b\nvar_d = 152\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "2391": {
        "category": "Comparison",
        "question_ko": "은지는 기차에 100번째로 탔고, 유나는 은지가 탄 후 11번째로 기차에 탔습니다. 유나는 몇 번째로 기차에 탔습니까?",
        "question_en": "Eunji was the 100th person riding the train, and Yuna was the 11th one after Eunji. What place did Yuna take to get on the train out of total people? ",
        "answer_ko": "111",
        "answer_en": "111",
        "solution_abst_ko": "100 11 [OP_ADD]",
        "solution_abst_en": "100 11 [OP_ADD]",
        "solution_code_ko": "var_a = 100\nvar_b = 11\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 100\nvar_b = 11\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "2392": {
        "category": "Geometry",
        "question_ko": "정팔면체에서 한 꼭짓점에 모인 면은 몇 개 인가요?",
        "question_en": "How many faces does a tetrahedron have?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "4",
        "solution_abst_en": "4",
        "solution_code_ko": "var_a = 4\nprint(int(var_a))",
        "solution_code_en": "var_a = 4\nprint(int(var_a))"
    },
    "2393": {
        "category": "Correspondence",
        "question_ko": "백의 자리가 9인 세자리 수가 있습니다. 이 수는 7로 나누어 떨어질때 이러한 세 자리 수는 모두 몇 개입니까?",
        "question_en": "There are three-digit numbers with a hundreds digit of 9. When these numbers are divisible by 7, how many of these three-digit numbers are there?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "9 100 [OP_MUL] 9 100 [OP_MUL] 99 [OP_ADD] 1 [OP_LIST_ARANGE] 7 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "9 100 [OP_MUL] 9 100 [OP_MUL] 99 [OP_ADD] 1 [OP_LIST_ARANGE] 7 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 9\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = 100\nvar_f = var_d * var_e\nvar_g = 99\nvar_h = var_f + var_g\nvar_i = 1\nlist_a = [i for i in range(var_c, var_h + 1, var_i)]\nvar_j = 7\nlist_b = []\nvar_j = int(var_j)\nfor i in list_a:\n    i = int(i)\n    if i % var_j == 0:\n        list_b.append(i)\nvar_k = len(list_b)\nprint(int(var_k))",
        "solution_code_en": "var_a = 9\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = 100\nvar_f = var_d * var_e\nvar_g = 99\nvar_h = var_f + var_g\nvar_i = 1\nlist_a = [i for i in range(var_c, var_h + 1, var_i)]\nvar_j = 7\nlist_b = []\nvar_j = int(var_j)\nfor i in list_a:\n    i = int(i)\n    if i % var_j == 0:\n        list_b.append(i)\nvar_k = len(list_b)\nprint(int(var_k))"
    },
    "2394": {
        "category": "Possibility",
        "question_ko": "5, 6, 4, 7 중에서 4개를 뽑아 한 번씩만 사용하여 네 자리 수를 만들려고 합니다. 만들 수 있는 네 자리 수 중 짝수의 개수를 구하시오.",
        "question_en": "You want to make a four-digit number by drawing four out of 5, 6, 4, and 7 and using them only once. Find the number of even 4-digit numbers that can be made.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "[OP_LIST_SOL] 5 6 4 7 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 2 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 5 6 4 7 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 2 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 5\nvar_b = 6\nvar_c = 4\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 2\nlist_c = []\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nvar_g = len(list_c)\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 6\nvar_c = 4\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 2\nlist_c = []\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nvar_g = len(list_c)\nprint(int(var_g))"
    },
    "2395": {
        "category": "Arithmetic calculation",
        "question_ko": "남준이가 8개의 과자를 먹었고, 호석이에게 7개의 과자를 주었더니 9개의 과자가 남았습니다. 남준이가 처음에 가진 과자는 몇 개입니까?",
        "question_en": "Namjoon ate 8 cookies, and when he gave 7 cookies to Hoseok, there are 9 cookies left. How many cookies did Namjoon have at first?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "9 7 [OP_ADD] 8 [OP_ADD]",
        "solution_abst_en": "9 7 [OP_ADD] 8 [OP_ADD]",
        "solution_code_ko": "var_a = 9\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 8\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 8\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "2396": {
        "category": "Possibility",
        "question_ko": "숫자 1, 2, 3, 4, 5 중 3개를 선택하여 한 번씩 모두 사용하여 1000미만의 수를 만들 때, 만들 수 있는 세 번째 큰 수와 세 번째 작은 수의 합을 구해라.",
        "question_en": "When you select three of the numbers 1, 2, 3, 4, and 5 and use each of them once to make a number less than 1000, find the sum of the third largest number and the third smallest number that you can make.",
        "answer_ko": "666",
        "answer_en": "666",
        "solution_abst_ko": "[OP_LIST_SOL] 1 2 3 4 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1000 [OP_LIST_LESS] 3 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 1 2 3 4 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1000 [OP_LIST_LESS] 3 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 2\nvar_c = 3\nvar_d = 4\nvar_e = 5\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1000\nlist_c = []\nfor i in list_b:\n    if i < var_g:\n        list_c.append(i)\nvar_h = 3\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nvar_j = 3\nlist_e=list_c.copy()\nlist_e.sort()\nvar_k = list_e[var_j-1]\nvar_l = var_i + var_k\nprint(int(var_l))",
        "solution_code_en": "var_a = 1\nvar_b = 2\nvar_c = 3\nvar_d = 4\nvar_e = 5\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1000\nlist_c = []\nfor i in list_b:\n    if i < var_g:\n        list_c.append(i)\nvar_h = 3\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nvar_j = 3\nlist_e=list_c.copy()\nlist_e.sort()\nvar_k = list_e[var_j-1]\nvar_l = var_i + var_k\nprint(int(var_l))"
    },
    "2397": {
        "category": "Correspondence",
        "question_ko": "A, B, C는 한 자리 수입니다. 숫자 A47BC는 4, 5, 9의 배수입니다. A가 될 수 있는 모든 숫자의 개수를 구하시오.",
        "question_en": "A, B, and C are single digit numbers. The number A47BC is a multiple of 4, 5, and 9. Find the number of all possible numbers in A.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "A47BC [OP_GEN_POSSIBLE_LIST] 4 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] A47BC A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_abst_en": "A47BC [OP_GEN_POSSIBLE_LIST] 4 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] A47BC A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 'A47BC'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 4\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 5\nlist_c = []\nvar_c = int(var_c)\nfor i in list_b:\n    i = int(i)\n    if i % var_c == 0:\n        list_c.append(i)\nvar_d = 9\nlist_d = []\nvar_d = int(var_d)\nfor i in list_c:\n    i = int(i)\n    if i % var_d == 0:\n        list_d.append(i)\nvar_e = 'A47BC'\nvar_f = 'A'\nvar_e = str(var_e)\nvar_f = str(var_f)\nunk_idx = var_e.index(var_f)\nlist_e = []\nfor elem in list_d:\n    elem = str(elem)\n    list_e.append(int(elem[unk_idx]))\nlist_e = list(set(list_e))\nvar_g = len(list_e)\nprint(int(var_g))",
        "solution_code_en": "var_a = 'A47BC'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 4\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 5\nlist_c = []\nvar_c = int(var_c)\nfor i in list_b:\n    i = int(i)\n    if i % var_c == 0:\n        list_c.append(i)\nvar_d = 9\nlist_d = []\nvar_d = int(var_d)\nfor i in list_c:\n    i = int(i)\n    if i % var_d == 0:\n        list_d.append(i)\nvar_e = 'A47BC'\nvar_f = 'A'\nvar_e = str(var_e)\nvar_f = str(var_f)\nunk_idx = var_e.index(var_f)\nlist_e = []\nfor elem in list_d:\n    elem = str(elem)\n    list_e.append(int(elem[unk_idx]))\nlist_e = list(set(list_e))\nvar_g = len(list_e)\nprint(int(var_g))"
    },
    "2398": {
        "category": "Correspondence",
        "question_ko": "A는 7로 나누면 몫이 5, 나머지가 3인 수가 이다. 이때 A를 구하여라.",
        "question_en": "When A is divided by 7, the quotient is 5 and the remainder is 3. Find A at this time.",
        "answer_ko": "38",
        "answer_en": "38",
        "solution_abst_ko": "7 5 [OP_MUL] 3 [OP_ADD]",
        "solution_abst_en": "7 5 [OP_MUL] 3 [OP_ADD]",
        "solution_code_ko": "var_a = 7\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 7\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "2399": {
        "category": "Comparison",
        "question_ko": "발표가 진행되는 동안 학생들은 차례대로 발표를 합니다. 뒤에서 6번째는 은정, 7명의 학생은 은정이 앞에 있습니다. 총 몇 명의 학생이 있습니까?",
        "question_en": "During the presentation, students take turns giving their presentations. Eunjeong is 6th from the back, and The 7 students are in front of Eunjung. How many students are there in total?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "6 7 [OP_ADD]",
        "solution_abst_en": "6 7 [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "2400": {
        "category": "Comparison",
        "question_ko": "태형, 민주, 상민, 윤정, 유정 순서로 도서관에서 책을 많이 빌렸습니다. 2번째로 책을 가장 많이 빌린 사람은 누구입니까?",
        "question_en": "Taehyung, Minju, Sangmin, Yoonjeong, and Yoojung borrowed the most books from the library in that order. Who borrowed the second most books?",
        "answer_ko": "민주",
        "answer_en": "Minju",
        "solution_abst_ko": "[OP_LIST_SOL] 태형 민주 상민 윤정 유정 [OP_LIST_EOL] 2 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Taehyung Minju Sangmin Yoonjeong Yoojung [OP_LIST_EOL] 2 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '태형'\nvar_b = '민주'\nvar_c = '상민'\nvar_d = '윤정'\nvar_e = '유정'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nvar_g = list_a[var_f-1]\nprint(var_g)",
        "solution_code_en": "var_a = 'Taehyung'\nvar_b = 'Minju'\nvar_c = 'Sangmin'\nvar_d = 'Yoonjeong'\nvar_e = 'Yoojung'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nvar_g = list_a[var_f-1]\nprint(var_g)"
    },
    "2401": {
        "category": "Arithmetic calculation",
        "question_ko": "모든 상자에는 각각 구슬이 100개씩 들어 있습니다. 상자 10개에는 구슬이 모두 몇 개 들어 있습니까?",
        "question_en": "All boxes contain 100 marbles each. How many marbles are in all 10 boxes?",
        "answer_ko": "1000",
        "answer_en": "1000",
        "solution_abst_ko": "100 10 [OP_MUL]",
        "solution_abst_en": "100 10 [OP_MUL]",
        "solution_code_ko": "var_a = 100\nvar_b = 10\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 100\nvar_b = 10\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "2402": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 268.8미터(m)인 산책로의 한쪽에 6.4미터(m) 간격으로 나무를 심으려고 합니다. 산책로의 처음과 끝에 모두 나무를 심을 때 필요한 나무는 몇 그루입니까?",
        "question_en": "Trees are to be planted at intervals of 6.4 meters (m) on one side of a 268.8-meter (m) long walkway. How many trees will you need if you plant trees at both the beginning and end of the trail?",
        "answer_ko": "43",
        "answer_en": "43",
        "solution_abst_ko": "268.8 6.4 [OP_DIV] 1 [OP_ADD]",
        "solution_abst_en": "268.8 6.4 [OP_DIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 268.8\nvar_b = 6.4\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 268.8\nvar_b = 6.4\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "2403": {
        "category": "Geometry",
        "question_ko": "10, 50, 100원짜리 동전 1개 씩을 던졌을 때, 10원짜리는 앞면이, 100원짜리는 뒷면이 나오는 경우의 수를 구하시오.",
        "question_en": "How much is it when the diameter of a circle is divided by its radius?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "2",
        "solution_abst_en": "2",
        "solution_code_ko": "var_a = 2\nprint(int(var_a))",
        "solution_code_en": "var_a = 2\nprint(int(var_a))"
    },
    "2404": {
        "category": "Geometry",
        "question_ko": "오각형의 한 꼭지점에서 대각선을 그을 때 생기는 삼각형의 개수는?",
        "question_en": "How many triangles are formed when the diagonals of a pentagon are drawn from one vertex?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "5 3 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "5 3 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "2405": {
        "category": "Comparison",
        "question_ko": "주차된 자동차는 모두 20대입니다. 오른쪽에서 16번째에는 검은색 자동차가 있고, 흰색 자동차는 왼쪽에서 11번째에 있다면, 두 자동차 사이에는 몇 대가 주차되어 있습니까?",
        "question_en": "All 20 cars are parked. If a black car is 16th from the right and a white car is 11th from the left, how many cars are parked between the two cars?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "16 11 [OP_ADD] 20 [OP_SUB] 2 [OP_SUB]",
        "solution_abst_en": "16 11 [OP_ADD] 20 [OP_SUB] 2 [OP_SUB]",
        "solution_code_ko": "var_a = 16\nvar_b = 11\nvar_c = var_a + var_b\nvar_d = 20\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 16\nvar_b = 11\nvar_c = var_a + var_b\nvar_d = 20\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "2406": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 테이프의 평균 길이를 구하려 합니다. 각각 35센티미터(cm), 35.5센티미터(cm), 36센티미터(cm), 30.5센티미터(cm)이라면 평균 길이는 몇 센티미터(cm)인지 구하시오.",
        "question_en": "You want to find the average length of 5 tapes. If they are 35 centimeters (cm), 35.5 centimeters (cm), 36 centimeters (cm), and 30.5 centimeters (cm), what is the average length in centimeters (cm)?",
        "answer_ko": "33.20",
        "answer_en": "33.2",
        "solution_abst_ko": "[OP_LIST_SOL] 35 29 35.5 36 30.5 [OP_LIST_EOL] [OP_LIST_MEAN]",
        "solution_abst_en": "[OP_LIST_SOL] 35 29 35.5 36 30.5 [OP_LIST_EOL] [OP_LIST_MEAN]",
        "solution_code_ko": "var_a = 35\nvar_b = 29\nvar_c = 35.5\nvar_d = 36\nvar_e = 30.5\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_f = sum(list_a)/len(list_a)\nprint('{:.2f}'.format(round(var_f+1e-10,2)))",
        "solution_code_en": "var_a = 35\nvar_b = 29\nvar_c = 35.5\nvar_d = 36\nvar_e = 30.5\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_f = sum(list_a)/len(list_a)\nprint('{:.2f}'.format(round(var_f+1e-10,2)))"
    },
    "2407": {
        "category": "Possibility",
        "question_ko": "A, B, C, D, E, F 6명의 학생이 있을 때, 회장 1명, 부회장 1명, 총무 1명, 서기 1명을 뽑는 경우의 수를 구하시오.",
        "question_en": "If there are 6 students A, B, C, D, E, F, find the number of ways to elect 1 president, 1 vice-president, 1 secretary, and 1 secretary.",
        "answer_ko": "360",
        "answer_en": "360",
        "solution_abst_ko": "6 1 1 [OP_ADD] 1 [OP_ADD] 1 [OP_ADD] [OP_PERM]",
        "solution_abst_en": "6 1 1 [OP_ADD] 1 [OP_ADD] 1 [OP_ADD] [OP_PERM]",
        "solution_code_ko": "var_a = 6\nvar_b = 1\nvar_c = 1\nvar_d = var_b + var_c\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = 1\nvar_a = int(var_a)\nvar_h = int(var_h)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i * (var_a-i)\nprint(int(var_i))",
        "solution_code_en": "var_a = 6\nvar_b = 1\nvar_c = 1\nvar_d = var_b + var_c\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = 1\nvar_a = int(var_a)\nvar_h = int(var_h)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i * (var_a-i)\nprint(int(var_i))"
    },
    "2408": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 46을 빼야 하는데 잘못하여 59를 뺐더니 43이 되었습니다. 바르게 계산한 결과를 구하시오.",
        "question_en": "You mistakenly subtracted 59 instead of 46 from a certain number and got 43. Find the result of the correct calculation.",
        "answer_ko": "56",
        "answer_en": "56",
        "solution_abst_ko": "43 59 [OP_ADD] 46 [OP_SUB]",
        "solution_abst_en": "43 59 [OP_ADD] 46 [OP_SUB]",
        "solution_code_ko": "var_a = 43\nvar_b = 59\nvar_c = var_a + var_b\nvar_d = 46\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 43\nvar_b = 59\nvar_c = var_a + var_b\nvar_d = 46\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "2409": {
        "category": "Geometry",
        "question_ko": "정육면체 모양의 상자를 포장하려고 합니다. 겹치지 않고 포장하기 위해서는 포장지의 넓이가 600이어야 할 때, 이 상자의 부피는 얼마인가요?",
        "question_en": "You want to pack a box in the shape of a cube. If the width of the wrapping paper is 600 to wrap without overlapping, what is the volume of this box?",
        "answer_ko": "1000",
        "answer_en": "1000",
        "solution_abst_ko": "600 6 [OP_DIV] 1/2 [OP_POW] 3 [OP_POW]",
        "solution_abst_en": "600 6 [OP_DIV] 1/2 [OP_POW] 3 [OP_POW]",
        "solution_code_ko": "var_a = 600\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 3\nvar_g = var_e ** var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 600\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 3\nvar_g = var_e ** var_f\nprint(int(var_g))"
    },
    "2410": {
        "category": "Geometry",
        "question_ko": "밑면의 두 변의 길이가 각각 7센티미터(㎝), 6센티미터(㎝)인 직육면체의 부피가 16세제곱센티미터(㎤)일 때, 직육면체의 겉넓이는 몇 제곱센티미터(㎠)인가요?",
        "question_en": "If the volume of a rectangular cuboid whose two sides are 7 centimeters (cm) and 6 centimeters (cm) respectively is 16 cubic centimeters (cm2), what is the surface area of the cuboid, in square centimeters (cm2)?",
        "answer_ko": "93.90",
        "answer_en": "93.9",
        "solution_abst_ko": "16 7 [OP_DIV] 6 [OP_DIV] 7 6 [OP_ADD] [OP_MUL] 7 6 [OP_MUL] [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "16 7 [OP_DIV] 6 [OP_DIV] 7 6 [OP_ADD] [OP_MUL] 7 6 [OP_MUL] [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 16\nvar_b = 7\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c / var_d\nvar_f = 7\nvar_g = 6\nvar_h = var_f + var_g\nvar_i = var_e * var_h\nvar_j = 7\nvar_k = 6\nvar_l = var_j * var_k\nvar_m = var_i + var_l\nvar_n = 2\nvar_o = var_m * var_n\nprint('{:.2f}'.format(round(var_o+1e-10,2)))",
        "solution_code_en": "var_a = 16\nvar_b = 7\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c / var_d\nvar_f = 7\nvar_g = 6\nvar_h = var_f + var_g\nvar_i = var_e * var_h\nvar_j = 7\nvar_k = 6\nvar_l = var_j * var_k\nvar_m = var_i + var_l\nvar_n = 2\nvar_o = var_m * var_n\nprint('{:.2f}'.format(round(var_o+1e-10,2)))"
    },
    "2411": {
        "category": "Arithmetic calculation",
        "question_ko": "은영이의 키는 1미터(m) 35센티미터(㎝) 이고, 미선이의 키는 은영이보다 9센티미터(㎝) 더 크다고 합니다. 미선이의 키는 몇 미터(m)인지 소수로 나타내시오.",
        "question_en": "Eun-young is 1 meter (m) 35 centimeters (cm) tall, and Mi-seon is 9 centimeters (cm) taller than Eun-young. How many meters (m) is Mi-seon's height as a decimal number?",
        "answer_ko": "1.44",
        "answer_en": "1.44",
        "solution_abst_ko": "1 35 100 [OP_DIV] [OP_ADD] 9 100 [OP_DIV] [OP_ADD]",
        "solution_abst_en": "1 35 100 [OP_DIV] [OP_ADD] 9 100 [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 35\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 9\nvar_g = 100\nvar_h = var_f / var_g\nvar_i = var_e + var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 35\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 9\nvar_g = 100\nvar_h = var_f / var_g\nvar_i = var_e + var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "2412": {
        "category": "Geometry",
        "question_ko": "밑면은 한 변이 8센티미터(㎝)인 정육각형이고 옆면이 모두 이등변 삼각형인 육각뿔이 있다. 이등변 삼각형의 각 변이 13센티미터(㎝), 13센티미터(㎝), 8센티미터(㎝)라면, 이 육각뿔의 모든 모서리의 합은 몇 센티미터(㎝)인가?",
        "question_en": "There is a hexagonal pyramid whose base is a regular hexagon with one side of 8 centimeters (cm) and the sides are all isosceles triangles. If the sides of an isosceles triangle are 13 centimeters (cm), 13 centimeters (cm), and 8 centimeters (cm), how many centimeters (cm) are the sum of all the edges of the pyramid?",
        "answer_ko": "126",
        "answer_en": "126",
        "solution_abst_ko": "13 6 [OP_MUL] 8 6 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "13 6 [OP_MUL] 8 6 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 13\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = 6\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 13\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = 6\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "2413": {
        "category": "Comparison",
        "question_ko": "정국이의 바구니에는 딸기 5개가 들어있고, 민영이의 바구니에는 딸기 7개가 들어있습니다. 태형이의 바구니에는 정국이보다 딸기의 수가 많고, 민영이보다는 적었습니다. 태형이의 바구니 속 딸기의 개수는 모두 몇 개입니까?",
        "question_en": "Jungkook's basket contains 5 strawberries, and Minyoung's basket contains 7 strawberries. Taehyung's basket had more strawberries than Jungkook's and fewer than Minyoung's. How many strawberries are in Taehyung's basket?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "5 7 [OP_ADD] 2 [OP_FDIV]",
        "solution_abst_en": "5 7 [OP_ADD] 2 [OP_FDIV]",
        "solution_code_ko": "var_a = 5\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "2414": {
        "category": "Arithmetic calculation",
        "question_ko": "작은 통의 물은 7리터(L)이고 큰 통의 물은 5리터(L)입니다. 큰 통에 있던 물 2리터(L)를 작은 통에 따랐을 때, 작은 통의 물은 큰 통보다 몇 리터(L)가 많습니까?",
        "question_en": "The water in the small bucket is 7 liters (L) and the water in the large bucket is 5 liters (L). When 2 liters (L) of water from the large bucket is poured into the small bucket, how many liters (L) of water is more in the small bucket than in the large bucket?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "7 2 [OP_ADD] 5 2 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "7 2 [OP_ADD] 5 2 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 7\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 7\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "2415": {
        "category": "Comparison",
        "question_ko": "지수가 설거지를 하고난 후 접시를 선반의 왼쪽에서 1번째 칸, 오른쪽에서 7번째 칸, 위에서 2번째 칸, 아래에서 4번째 칸에 놓았습니다. 선반의 모든 칸의 개수는 몇 칸입니까?",
        "question_en": "After Jisoo washed the dishes, she put the plate on the shelf 1st from the left, 7th from the right, 2nd from the top, and 4th from the bottom. How many slots are there on the shelf?",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "1 7 [OP_ADD] 1 [OP_SUB] 2 4 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "1 7 [OP_ADD] 1 [OP_SUB] 2 4 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 1\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = 4\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 1\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = 4\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))"
    },
    "2416": {
        "category": "Possibility",
        "question_ko": "다섯 장의 숫자 카드 0, 1, 2, 3, 4 중에서 3 장을 꺼내 세 자리 수를 만들 때, 6의 배수이면서 9의 배수인 수는 모두 몇 가지인가?",
        "question_en": "How many of the three number cards among five number cards 0, 1, 2, 3, and 4 form a three-digit number that are both multiples of 6 and multiples of 9?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 6 9 [OP_LCM] [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 6 9 [OP_LCM] [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 6\nvar_h = 9\nvar_i = var_h * var_g / math.gcd(int(var_h), int(var_g))\nlist_c = []\nvar_i = int(var_i)\nfor i in list_b:\n    i = int(i)\n    if i % var_i == 0:\n        list_c.append(i)\nvar_j = len(list_c)\nprint(int(var_j))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 6\nvar_h = 9\nvar_i = var_h * var_g / math.gcd(int(var_h), int(var_g))\nlist_c = []\nvar_i = int(var_i)\nfor i in list_b:\n    i = int(i)\n    if i % var_i == 0:\n        list_c.append(i)\nvar_j = len(list_c)\nprint(int(var_j))"
    },
    "2417": {
        "category": "Arithmetic calculation",
        "question_ko": "여학생과 남학생이 모두 24명 있습니다. 이 중 여학생에게만 색종이 50장을 똑같이 나누어 주었더니 2장이 남았습니다. 남학생 수가 여학생 수의 2배일 때 여학생은 색종이를 몇 장씩 갖게 됩니까?",
        "question_en": "There are 24 female and male students in total. Among them, 50 sheets of colored paper were equally distributed to female students only, and 2 sheets were left. How many pieces of colored paper will the girls have if there are twice as many boys as girls?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "50 2 [OP_SUB] 24 2 1 [OP_ADD] [OP_FDIV] [OP_FDIV]",
        "solution_abst_en": "50 2 [OP_SUB] 24 2 1 [OP_ADD] [OP_FDIV] [OP_FDIV]",
        "solution_code_ko": "var_a = 50\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 24\nvar_e = 2\nvar_f = 1\nvar_g = var_e + var_f\nvar_h = var_d // var_g\nvar_i = var_c // var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 50\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 24\nvar_e = 2\nvar_f = 1\nvar_g = var_e + var_f\nvar_h = var_d // var_g\nvar_i = var_c // var_h\nprint(int(var_i))"
    },
    "2418": {
        "category": "Comparison",
        "question_ko": "소형차는 200킬로미터(㎞)를 가는 데 4시간이 걸렸고, 중형차는 180킬로미터(㎞)를 가는 데 3시간이 걸렸습니다. 어느 차가 더 빠른지 구하시오.",
        "question_en": "A compact car took 4 hours to drive 200 kilometers (km), and a midsize car took 3 hours to drive 180 kilometers (km). Find which car is faster.",
        "answer_ko": "중형차",
        "answer_en": "midsize",
        "solution_abst_ko": "[OP_LIST_SOL] 소형차 중형차 [OP_LIST_EOL] [OP_LIST_SOL] 200 4 [OP_DIV] 180 3 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] compact midsize [OP_LIST_EOL] [OP_LIST_SOL] 200 4 [OP_DIV] 180 3 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '소형차'\nvar_b = '중형차'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 200\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 180\nvar_g = 3\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'compact'\nvar_b = 'midsize'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 200\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 180\nvar_g = 3\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "2419": {
        "category": "Correspondence",
        "question_ko": "2, 3, 4, 5, 6으로 나누면 모두 1이 남고, 7로 나누면 나누어떨어지는 수가 있다. 이러한 수를 작은 수부터 세었을 때 셋째 번 수를 구하여라.",
        "question_en": "When you divide a particular number by 2, 3, 4, 5, and 6, you get a remainder of 1, and that particular number is divisible by 7. When these numbers are counted from the smallest number, what number will come in the 3rd place?",
        "answer_ko": "1141",
        "answer_en": "1141",
        "solution_abst_ko": "0 9999 1 [OP_LIST_ARANGE] 2 3 [OP_LCM] 4 [OP_LCM] 5 [OP_LCM] 6 [OP_LCM] 1 [OP_LIST_DIVIDE_AND_REMAIN] 7 0 [OP_LIST_DIVIDE_AND_REMAIN] 3 [OP_LIST_MIN]",
        "solution_abst_en": "0 9999 1 [OP_LIST_ARANGE] 2 3 [OP_LCM] 4 [OP_LCM] 5 [OP_LCM] 6 [OP_LCM] 1 [OP_LIST_DIVIDE_AND_REMAIN] 7 0 [OP_LIST_DIVIDE_AND_REMAIN] 3 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 0\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nvar_e = 3\nvar_f = var_e * var_d / math.gcd(int(var_e), int(var_d))\nvar_g = 4\nvar_h = var_g * var_f / math.gcd(int(var_g), int(var_f))\nvar_i = 5\nvar_j = var_i * var_h / math.gcd(int(var_i), int(var_h))\nvar_k = 6\nvar_l = var_k * var_j / math.gcd(int(var_k), int(var_j))\nvar_m = 1\nlist_b = [] \nvar_l = int(var_l)\nvar_m = int(var_m)\nif var_m < 0:\n    var_m = var_m + var_l\nfor i in list_a:\n    i = int(i)\n    if i%var_l == var_m:\n        list_b.append(i)\nvar_n = 7\nvar_o = 0\nlist_c = [] \nvar_n = int(var_n)\nvar_o = int(var_o)\nif var_o < 0:\n    var_o = var_o + var_n\nfor i in list_b:\n    i = int(i)\n    if i%var_n == var_o:\n        list_c.append(i)\nvar_p = 3\nlist_d=list_c.copy()\nlist_d.sort()\nvar_q = list_d[var_p-1]\nprint(int(var_q))",
        "solution_code_en": "var_a = 0\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nvar_e = 3\nvar_f = var_e * var_d / math.gcd(int(var_e), int(var_d))\nvar_g = 4\nvar_h = var_g * var_f / math.gcd(int(var_g), int(var_f))\nvar_i = 5\nvar_j = var_i * var_h / math.gcd(int(var_i), int(var_h))\nvar_k = 6\nvar_l = var_k * var_j / math.gcd(int(var_k), int(var_j))\nvar_m = 1\nlist_b = [] \nvar_l = int(var_l)\nvar_m = int(var_m)\nif var_m < 0:\n    var_m = var_m + var_l\nfor i in list_a:\n    i = int(i)\n    if i%var_l == var_m:\n        list_b.append(i)\nvar_n = 7\nvar_o = 0\nlist_c = [] \nvar_n = int(var_n)\nvar_o = int(var_o)\nif var_o < 0:\n    var_o = var_o + var_n\nfor i in list_b:\n    i = int(i)\n    if i%var_n == var_o:\n        list_c.append(i)\nvar_p = 3\nlist_d=list_c.copy()\nlist_d.sort()\nvar_q = list_d[var_p-1]\nprint(int(var_q))"
    },
    "2420": {
        "category": "Correspondence",
        "question_ko": "사과 68개를 급식으로 주려고 합니다. 14명에게 똑같이 5개씩 나누어 주려면 사과는 몇 개가 더 필요한지 구하시오.",
        "question_en": "I'm going to give you 68 apples for lunch. How many more apples are needed to divide 5 each equally to 14 people?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "14 5 [OP_MUL] 68 [OP_SUB]",
        "solution_abst_en": "14 5 [OP_MUL] 68 [OP_SUB]",
        "solution_code_ko": "var_a = 14\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 68\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 14\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 68\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "2421": {
        "category": "Arithmetic calculation",
        "question_ko": "같은 무게의 사과가 담겨있는 5개의 상자에서 사과를 30킬로그램(㎏)씩 꺼낸 후, 5개의 상자에 남은 사과의 무게를 재어보니 처음 상태의 사과 상자 2개의 무게와 같았습니다. 처음 각 상자에 들어 있던 사과는 몇 킬로그램(㎏)입니까?",
        "question_en": "After taking 30 kilograms (kg) of apples out of 5 boxes containing apples of the same weight, the remaining apples in the 5 boxes were weighed the same as the 2 apple boxes in the initial state. How many kilograms (kg) of apples were in each box initially?",
        "answer_ko": "50",
        "answer_en": "50",
        "solution_abst_ko": "30 5 [OP_MUL] 5 2 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "30 5 [OP_MUL] 5 2 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 30\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 30\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))"
    },
    "2422": {
        "category": "Correspondence",
        "question_ko": "6에서 어떤 수를 뺀 값이 2다. 어떤 수에 2를 빼면 얼마인가?",
        "question_en": "6 minus a certain number equals 2. What is the value of the certain number minus 2?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "6 2 [OP_SUB] 2 [OP_SUB]",
        "solution_abst_en": "6 2 [OP_SUB] 2 [OP_SUB]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "2423": {
        "category": "Correspondence",
        "question_ko": "34AC를 반올림하여 백의 자리까지 나타내면 3400이 됩니다. 가능한 A는 모두 몇 가지인가?",
        "question_en": "Rounding 34AC to the hundred's place gives 3400. How many possible A's are there?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "34AC [OP_GEN_POSSIBLE_LIST] 3400 50 [OP_SUB] [OP_LIST_MORE_EQUAL] 3400 50 [OP_ADD] [OP_LIST_LESS] 34AC A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_abst_en": "34AC [OP_GEN_POSSIBLE_LIST] 3400 50 [OP_SUB] [OP_LIST_MORE_EQUAL] 3400 50 [OP_ADD] [OP_LIST_LESS] 34AC A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '34AC'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 3400\nvar_c = 50\nvar_d = var_b - var_c\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nvar_e = 3400\nvar_f = 50\nvar_g = var_e + var_f\nlist_c = []\nfor i in list_b:\n    if i < var_g:\n        list_c.append(i)\nvar_h = '34AC'\nvar_i = 'A'\nvar_h = str(var_h)\nvar_i = str(var_i)\nunk_idx = var_h.index(var_i)\nlist_d = []\nfor elem in list_c:\n    elem = str(elem)\n    list_d.append(int(elem[unk_idx]))\nlist_d = list(set(list_d))\nvar_j = len(list_d)\nprint(int(var_j))",
        "solution_code_en": "var_a = '34AC'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 3400\nvar_c = 50\nvar_d = var_b - var_c\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nvar_e = 3400\nvar_f = 50\nvar_g = var_e + var_f\nlist_c = []\nfor i in list_b:\n    if i < var_g:\n        list_c.append(i)\nvar_h = '34AC'\nvar_i = 'A'\nvar_h = str(var_h)\nvar_i = str(var_i)\nunk_idx = var_h.index(var_i)\nlist_d = []\nfor elem in list_c:\n    elem = str(elem)\n    list_d.append(int(elem[unk_idx]))\nlist_d = list(set(list_d))\nvar_j = len(list_d)\nprint(int(var_j))"
    },
    "2424": {
        "category": "Arithmetic calculation",
        "question_ko": "0부터 9까지의 숫자 카드로 1이상 300이하의 수를 만드려고 합니다. 숫자 카드 3은 모두 몇 장 필요한지 구하시오.",
        "question_en": "You are trying to make a number between 1 and 300 using number cards from 0 to 9. Find how many number card 3 are needed.",
        "answer_ko": "61",
        "answer_en": "61",
        "solution_abst_ko": "1 300 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 3 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 300 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 3 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 300\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 3\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 300\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 3\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))"
    },
    "2425": {
        "category": "Geometry",
        "question_ko": "삼각형의 변의 개수와 사각형의 변의 개수의 합을 구하시오",
        "question_en": "Find the sum of the number of sides of the triangle and the number of sides of the quadrilateral.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "3 4 [OP_ADD]",
        "solution_abst_en": "3 4 [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 4\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 4\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "2426": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 5로 나누어야 하는데 실수로 8로 나누었더니 몫이 156이고 나머지가 2였습니다. 계산을 제대로 했을 때 나오는 값에서 3을 뺀 값을 구하시오.",
        "question_en": "A number needs to be divided by 5, but when I accidentally divide it by 8, the quotient is 156 and the remainder is 2. Find the value obtained by subtracting 3 from the correctly calculated value.",
        "answer_ko": "247",
        "answer_en": "247",
        "solution_abst_ko": "156 8 [OP_MUL] 2 [OP_ADD] 5 [OP_DIV] 3 [OP_SUB]",
        "solution_abst_en": "156 8 [OP_MUL] 2 [OP_ADD] 5 [OP_DIV] 3 [OP_SUB]",
        "solution_code_ko": "var_a = 156\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = var_e / var_f\nvar_h = 3\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 156\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = var_e / var_f\nvar_h = 3\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "2427": {
        "category": "Arithmetic calculation",
        "question_ko": "태형이가 깃발을 하나 세우는 데에 9초가 걸립니다. 또한 하나의 깃발을 세운 후에는 5초 동안 쉬어야합니다. 도로를 16구간으로 나누고 양 끝 점을 제외한 구간 사이사이에 깃발을 세운다면 걸리는 시간은 모두 몇 초일까요?",
        "question_en": "It takes Taehyung 9 seconds to set up a flag. Also, after raising a flag, he must rest for 5 seconds. If the road is divided into 16 sections and flags are placed between the sections except for the ends, how many seconds will it take in total?",
        "answer_ko": "210",
        "answer_en": "210",
        "solution_abst_ko": "16 1 [OP_SUB] 9 5 [OP_ADD] [OP_MUL]",
        "solution_abst_en": "16 1 [OP_SUB] 9 5 [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 16\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 9\nvar_e = 5\nvar_f = var_d + var_e\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 16\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 9\nvar_e = 5\nvar_f = var_d + var_e\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "2428": {
        "category": "Arithmetic calculation",
        "question_ko": "나무토막 24장을 이어붙여 다리를 만들려고 합니다. 나무토막 한 장의 길이는 28센티미터(㎝)이며 다리의 길이를 580센티미터(㎝)로 만들려고 한다면 몇 센티미터(㎝)씩 겹쳐서 이어 붙여야 할까요?",
        "question_en": "You are trying to make a bridge by joining 24 pieces of wood. If a piece of wood is 28 centimeters (cm) long, and you want to make a bridge 580 centimeters (cm) long, how many centimeters (cm) do you have to overlap each?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "28 24 [OP_MUL] 580 [OP_SUB] 24 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "28 24 [OP_MUL] 580 [OP_SUB] 24 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 28\nvar_b = 24\nvar_c = var_a * var_b\nvar_d = 580\nvar_e = var_c - var_d\nvar_f = 24\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 28\nvar_b = 24\nvar_c = var_a * var_b\nvar_d = 580\nvar_e = var_c - var_d\nvar_f = 24\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "2429": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 10, 11, 12, 13이 있습니다. 그 중에서 2번째로 큰 수와 2번째로 작은 수로 나눈 나머지는 얼마입니까?",
        "question_en": "There are four numbers 10, 11, 12, and 13. What is the remainder of the second largest number divided by the second smallest number?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_MOD]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_MOD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f % var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f % var_h\nprint(int(var_i))"
    },
    "2430": {
        "category": "Arithmetic calculation",
        "question_ko": "무게가 220그램(g)인 작은 가방에 선물을 6개씩 넣은 후 이 작은 가방 9개를 무게가 250그램(g)인 큰 가방에 넣었더니 13.3킬로그램(㎏)이 되었습니다. 각각의 선물이 모두 같은 것이라면 선물 하나의 무게는 몇 그램(g)입니까?",
        "question_en": "After putting 6 gifts in a small bag weighing 220 grams (g), then put 9 of these small bags in a larger bag weighing 250 grams (g), the result was 13.3 kilograms (kg). If each gift is the same, how many grams (g) does each gift weigh?",
        "answer_ko": "205",
        "answer_en": "205",
        "solution_abst_ko": "13.3 1000 [OP_MUL] 250 [OP_SUB] 220 9 [OP_MUL] [OP_SUB] 6 9 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "13.3 1000 [OP_MUL] 250 [OP_SUB] 220 9 [OP_MUL] [OP_SUB] 6 9 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 13.3\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 250\nvar_e = var_c - var_d\nvar_f = 220\nvar_g = 9\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nvar_j = 6\nvar_k = 9\nvar_l = var_j * var_k\nvar_m = var_i / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 13.3\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 250\nvar_e = var_c - var_d\nvar_f = 220\nvar_g = 9\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nvar_j = 6\nvar_k = 9\nvar_l = var_j * var_k\nvar_m = var_i / var_l\nprint(int(var_m))"
    },
    "2431": {
        "category": "Arithmetic calculation",
        "question_ko": "3미터(m)의 테이프를 1/4미터(m)씩 자르면 몇 도막이 됩니까?",
        "question_en": "How many pieces would it be if 3 meters (m) of tape were continuously cut by 1/4 meters (m)?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "3 1/4 [OP_DIV]",
        "solution_abst_en": "3 1/4 [OP_DIV]",
        "solution_code_ko": "var_a = 3\nvar_b = 0.25\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 0.25\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "2432": {
        "category": "Arithmetic calculation",
        "question_ko": "남준이보다 윤기는 3살이 더 적습니다. 올해 남준이가 6살일 때 윤기의 나이는 몇 살입니까?",
        "question_en": "Yoongi is 3 years younger than Namjoon. How old is Yoongi when Namjoon becomes 6 years old this year?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "6 3 [OP_SUB]",
        "solution_abst_en": "6 3 [OP_SUB]",
        "solution_code_ko": "var_a = 6\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "2433": {
        "category": "Arithmetic calculation",
        "question_ko": "네 자리 수 중 3의 배수이면서 5의 배수인 수는 모두 몇 개 입니까?",
        "question_en": "How many four-digit numbers are both multiples of 3 and multiples of 5?",
        "answer_ko": "600",
        "answer_en": "600",
        "solution_abst_ko": "1000 9999 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "1000 9999 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "2434": {
        "category": "Comparison",
        "question_ko": "4개의 숫자 0.8, 1/2, 0.9, 1/3가 있습니다. 0.7보다 큰 수의 합은 얼마인가요?",
        "question_en": "There are four numbers 0.8, 1/2, 0.9, and 1/3. Find the sum of the numbers greater than 0.7.",
        "answer_ko": "1.70",
        "answer_en": "1.7",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.7 [OP_LIST_MORE] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.7 [OP_LIST_MORE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.7\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint('{:.2f}'.format(round(var_f+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.7\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint('{:.2f}'.format(round(var_f+1e-10,2)))"
    },
    "2435": {
        "category": "Arithmetic calculation",
        "question_ko": "10원짜리 동전 80개는 100원짜리 동전 몇 개와 같습니까?",
        "question_en": "How many 100 won coins are equal to 80 10 won coins?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "10 80 [OP_MUL] 100 [OP_DIV]",
        "solution_abst_en": "10 80 [OP_MUL] 100 [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 80\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 80\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "2436": {
        "category": "Geometry",
        "question_ko": "정사각형의 운동장과 직사각형의 농구 코트가 있다. 운동장의 둘레는 36미터(m)이고, 농구 코트의 둘레는 38미터(m)이다. 농구 코트의 가로 길이가 15미터(m)면 운동장과 농구 코트의 넓이 차이를 구하시오.",
        "question_en": "There is a square playground and a rectangular basketball court. The perimeter of the playground is 36 meters (m), and the perimeter of the basketball court is 38 meters (m). If the width of the basketball court is 15 meters (m), find the difference between the area of the playground and that of the basketball court.",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "36 4 [OP_DIV] 2 [OP_POW] 38 2 [OP_DIV] 15 [OP_SUB] 15 [OP_MUL] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "36 4 [OP_DIV] 2 [OP_POW] 38 2 [OP_DIV] 15 [OP_SUB] 15 [OP_MUL] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 36\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 38\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = 15\nvar_j = var_h - var_i\nvar_k = 15\nvar_l = var_j * var_k\nvar_m = var_e - var_l\nvar_n = abs(var_m)\nprint(int(var_n))",
        "solution_code_en": "var_a = 36\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 38\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = 15\nvar_j = var_h - var_i\nvar_k = 15\nvar_l = var_j * var_k\nvar_m = var_e - var_l\nvar_n = abs(var_m)\nprint(int(var_n))"
    },
    "2437": {
        "category": "Arithmetic calculation",
        "question_ko": "윤기의 수학 점수는 82점이고, 국어 점수는 수학 점수보다 5점 높습니다. 국어, 수학, 영어 세 과목의 평균 점수가 89점이 되려면 영어를 몇 점 맞아야 합니까?",
        "question_en": "Yoongi's math score is 82, and his Korean score is 5 points higher than his math score. How many points does he need to get in English to get an average score of 89 in Korean, Mathematics, and English?",
        "answer_ko": "98",
        "answer_en": "98",
        "solution_abst_ko": "89 3 [OP_MUL] 82 [OP_SUB] 82 5 [OP_ADD] [OP_SUB]",
        "solution_abst_en": "89 3 [OP_MUL] 82 [OP_SUB] 82 5 [OP_ADD] [OP_SUB]",
        "solution_code_ko": "var_a = 89\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 82\nvar_e = var_c - var_d\nvar_f = 82\nvar_g = 5\nvar_h = var_f + var_g\nvar_i = var_e - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 89\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 82\nvar_e = var_c - var_d\nvar_f = 82\nvar_g = 5\nvar_h = var_f + var_g\nvar_i = var_e - var_h\nprint(int(var_i))"
    },
    "2438": {
        "category": "Comparison",
        "question_ko": "(가) 장난감은 (나) 장난감보다 크고 (다) 장난감보다 작습니다. (나) 장난감은 (라) 장난감보다 큽니다. (다) 장난감은 (마) 장난감보다 작습니다. 가장 큰 장난감은 어느 장난감입니까?",
        "question_en": "Toy (A) is larger than toy (B) and smaller than a toy (C). Toy (B) is bigger than Toy (D). Toy (C) is smaller than Toy (E). Which toy is the biggest?",
        "answer_ko": "(마)",
        "answer_en": "(E)",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) (다) (라) (마) [OP_LIST_EOL] [OP_LIST_SOL] (가) (나) > (가) (다) < (나) (라) > (다) (마) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (A) (B) (C) (D) (E) [OP_LIST_EOL] [OP_LIST_SOL] (A) (B) > (A) (C) < (B) (D) > (C) (E) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nvar_c = '(다)'\nvar_d = '(라)'\nvar_e = '(마)'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = '(가)'\nvar_g = '(나)'\nvar_h = '>'\nvar_i = '(가)'\nvar_j = '(다)'\nvar_k = '<'\nvar_l = '(나)'\nvar_m = '(라)'\nvar_n = '>'\nvar_o = '(다)'\nvar_p = '(마)'\nvar_q = '<'\nlist_b= []\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_r = 1\nvar_s = list_c[var_r-1]\nprint(var_s)",
        "solution_code_en": "var_a = '(A)'\nvar_b = '(B)'\nvar_c = '(C)'\nvar_d = '(D)'\nvar_e = '(E)'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = '(A)'\nvar_g = '(B)'\nvar_h = '>'\nvar_i = '(A)'\nvar_j = '(C)'\nvar_k = '<'\nvar_l = '(B)'\nvar_m = '(D)'\nvar_n = '>'\nvar_o = '(C)'\nvar_p = '(E)'\nvar_q = '<'\nlist_b= []\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_r = 1\nvar_s = list_c[var_r-1]\nprint(var_s)"
    },
    "2439": {
        "category": "Geometry",
        "question_ko": "두 대각선의 길이가 각각 6센티미터(㎝), 10센티미터(㎝)인 마름모의 넓이를 구하세요.",
        "question_en": "Find the area of a rhombus whose two diagonals are 6 centimeters (cm) and 10 centimeters (cm), respectively.",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "6 10 [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "6 10 [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "2440": {
        "category": "Correspondence",
        "question_ko": "63+6AB=748입니다. B는 얼마인가요?",
        "question_en": "63+6AB=748. How much is B?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "63+6AB=748 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "63+6AB=748 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '63+6AB=748'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '63+6AB=748'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "2441": {
        "category": "Arithmetic calculation",
        "question_ko": "트리 하나를 장식하는 데 반짝이는 줄이 0.84미터(m)가 들어갑니다. 10개의 트리를 장식한 후에 줄이 50센티미터(㎝) 남았다면, 트리를 장식하기 전에는 줄이 몇 미터(m)였습니까?",
        "question_en": "It takes 0.84 meters (m) of shiny string to decorate one tree. If there are 50 centimeters (cm) of rope left after decorating 10 trees, how many meters (m) of rope were there before decorating the tree?",
        "answer_ko": "8.90",
        "answer_en": "8.9",
        "solution_abst_ko": "0.84 10 [OP_MUL] 50 100 [OP_DIV] [OP_ADD]",
        "solution_abst_en": "0.84 10 [OP_MUL] 50 100 [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 0.84\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 50\nvar_e = 100\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 0.84\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 50\nvar_e = 100\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "2442": {
        "category": "Arithmetic calculation",
        "question_ko": "두 지점 A, B 사이를 자전거를 타고 왕복하는데 갈때는 시속 15 킬로미터(㎞)로, 올 때는 시속 10 킬로미터(㎞)로 달렸더니 올 때는 갈 때보다 30분이 더 걸렸다. 갈 때 걸린 시간을 구하시오.",
        "question_en": "I rode a bicycle back and forth between the two points A and B, traveling at 15 kilometers per hour (km) on the way forth and 10 kilometers per hour (km) on the way back. It took 30 minutes longer to come back. Find the time it took to go forth.",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "10 30 60 [OP_DIV] [OP_MUL] 15 10 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "10 30 60 [OP_DIV] [OP_MUL] 15 10 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 30\nvar_c = 60\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 15\nvar_g = 10\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 30\nvar_c = 60\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 15\nvar_g = 10\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "2443": {
        "category": "Arithmetic calculation",
        "question_ko": "40 초과 70 미만인 자연수는 모두 몇 개입니까?",
        "question_en": "How many natural numbers are greater than 40 and less than 70?",
        "answer_ko": "29",
        "answer_en": "29",
        "solution_abst_ko": "70 40 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "70 40 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 70\nvar_b = 40\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 70\nvar_b = 40\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "2444": {
        "category": "Comparison",
        "question_ko": "상자 안에 빨간 공, 파란 공, 노란 공, 초록 공이 있습니다. 이 공들은 모두 합쳐 531개이며, 빨간 공과 파란 공의 개수 합은 노랑 공과 초록 공의 개수 합 보다 31개 더 많습니다. 또, 노랑 공이 초록 공 보다 22개 더 많다고 할 때, 노랑 공은 몇 개가 들어있는지 구하시오.",
        "question_en": "A red ball, blue ball, yellow ball and a green ball are in the box. The total number of these balls is 531, and the sum of the red and blue balls is 31 more than the sum of the yellow and green balls. Also, if there are 22 more yellow balls than green balls, how many yellow balls are there?",
        "answer_ko": "136",
        "answer_en": "136",
        "solution_abst_ko": "531 31 [OP_SUB] 2 [OP_DIV] 22 [OP_SUB] 2 [OP_DIV] 22 [OP_ADD]",
        "solution_abst_en": "531 31 [OP_SUB] 2 [OP_DIV] 22 [OP_SUB] 2 [OP_DIV] 22 [OP_ADD]",
        "solution_code_ko": "var_a = 531\nvar_b = 31\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 22\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nvar_j = 22\nvar_k = var_i + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 531\nvar_b = 31\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 22\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nvar_j = 22\nvar_k = var_i + var_j\nprint(int(var_k))"
    },
    "2445": {
        "category": "Arithmetic calculation",
        "question_ko": "3으로 나누어 떨어질 수 있는 네 자리 수 중 가장 작은 수는?",
        "question_en": "What is the smallest four-digit number that is divisible by 3?",
        "answer_ko": "1002",
        "answer_en": "1002",
        "solution_abst_ko": "1000 9999 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "1000 9999 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nprint(int(var_f))",
        "solution_code_en": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nprint(int(var_f))"
    },
    "2446": {
        "category": "Arithmetic calculation",
        "question_ko": "과학실에서 보건실을 갈 때는 시속 2킬로미터(㎞)로, 보건실에서 과학식을 올 때는 2킬로미터(㎞) 더 먼 길을 시속 3킬로미터(㎞)로 걸어왔다. 총 걸린시간이 4시간이라면 보건실에서 과학실로 온 거리는 얼마인지 구하시오.",
        "question_en": "When I went to the health room from the science room, I walked at 2 kilometers (km) per hour, and when I went to the science room from the health room, I walked 2 kilometers (km) further at 3 kilometers (km) per hour. If it took 4 hours in total, what is the distance from the health room to the science room?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "2 4 [OP_MUL] 2 [OP_ADD] 3 2 [OP_ADD] [OP_DIV] 3 [OP_MUL]",
        "solution_abst_en": "2 4 [OP_MUL] 2 [OP_ADD] 3 2 [OP_ADD] [OP_DIV] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = var_e / var_h\nvar_j = 3\nvar_k = var_i * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = var_e / var_h\nvar_j = 3\nvar_k = var_i * var_j\nprint(int(var_k))"
    },
    "2447": {
        "category": "Possibility",
        "question_ko": "2, 3, 4 중에서 서로 다른 숫자 2개를 뽑아 만들 수 있는 두 자리 수는 모두 몇 개입니까?",
        "question_en": "How many two-digit numbers can be made by selecting two different numbers from 2, 3, and 4?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 2 3 4 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 2 3 4 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = 4\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = 4\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "2448": {
        "category": "Correspondence",
        "question_ko": "신영이는 가지고 있던 사탕의 1/2을 용희에게 주고, 남은 사탕의 1/3보다 5개 많이 한초에게 주었습니다. 남은 사탕이 5개라면, 신영이는 처음에 몇 개의 사탕을 가지고 있었습니까?",
        "question_en": "Shinyoung gave 1/2 of the candy he had to Yonghee, and gave 5 more than 1/3 of the remaining candy to Hancho. If there are 5 candies left, how many candies did Shinyoung have at first?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "5 5 [OP_ADD] 1 1/3 [OP_SUB] [OP_DIV] 1 1/2 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "5 5 [OP_ADD] 1 1/3 [OP_SUB] [OP_DIV] 1 1/2 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 5\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 0.3333333333333333\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 1\nvar_i = 0.5\nvar_j = var_h - var_i\nvar_k = var_g / var_j\nprint(int(eval('{:.2f}'.format(round(var_k+1e-10,2)))))",
        "solution_code_en": "var_a = 5\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 0.3333333333333333\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 1\nvar_i = 0.5\nvar_j = var_h - var_i\nvar_k = var_g / var_j\nprint(int(eval('{:.2f}'.format(round(var_k+1e-10,2)))))"
    },
    "2449": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 6을 곱해야 하는데 잘못하여 뺐더니 51이 되었습니다. 바르게 계산한 결과를 구하시오.",
        "question_en": "A number needs to be multiplied by 6, but you mistakenly subtracted it, and got 51. Find the result of the correct calculation.",
        "answer_ko": "342",
        "answer_en": "342",
        "solution_abst_ko": "51 6 [OP_ADD] 6 [OP_MUL]",
        "solution_abst_en": "51 6 [OP_ADD] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 51\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 51\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "2450": {
        "category": "Possibility",
        "question_ko": "5, 9, 2 중에서 한 번씩만 사용하여 세 자리 수를 만들려고 합니다. 만든 두 수의 차가 가장 크게 될 때, 두 수의 합은 무엇입니까?",
        "question_en": "You want to create a three-digit number using only one of 5, 9, and 2. What is the sum of the two numbers when it has the greatest difference?",
        "answer_ko": "1211",
        "answer_en": "1211",
        "solution_abst_ko": "[OP_LIST_SOL] 5 9 2 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 5 9 2 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 9\nvar_c = 2\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 5\nvar_b = 9\nvar_c = 2\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))"
    },
    "2451": {
        "category": "Geometry",
        "question_ko": "둘레의 길이가 18센티미터(㎝)인 정삼각형이 있습니다. 이 정삼각형의 한 변의 길이는 얼마입니까?",
        "question_en": "When there is an equilateral triangle with a perimeter of 18 centimeters (cm), what is the length of one side of this equilateral triangle?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "18 3 [OP_DIV]",
        "solution_abst_en": "18 3 [OP_DIV]",
        "solution_code_ko": "var_a = 18\nvar_b = 3\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 18\nvar_b = 3\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "2452": {
        "category": "Arithmetic calculation",
        "question_ko": "민지네 모둠 학생 6명이 기차를 타고 서울역에서 광주역까지 가는데 남은 좌석이 4개밖에 없어서 나머지를 입석표로 끊고 돌아가면서 앉기로 하였습니다. 기차를 타는 시간이 3시간 12분이라면 한 사람이 평균 몇 분씩 앉을 수 있는지 구하시오.",
        "question_en": "6 students from Minjine's group were traveling by train from Seoul Station to Gwangju Station, and there were only 4 seats left, so they decided to stand up and take turns sitting on the rest. If the train ride is 3 hours and 12 minutes, find how many minutes each person can sit on average.",
        "answer_ko": "128",
        "answer_en": "128",
        "solution_abst_ko": "3 60 [OP_MUL] 12 [OP_ADD] 6 [OP_DIV] 4 [OP_MUL]",
        "solution_abst_en": "3 60 [OP_MUL] 12 [OP_ADD] 6 [OP_DIV] 4 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = var_c + var_d\nvar_f = 6\nvar_g = var_e / var_f\nvar_h = 4\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 3\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = var_c + var_d\nvar_f = 6\nvar_g = var_e / var_f\nvar_h = 4\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "2453": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 문구점에서 빨간 색종이 210장과 파란 색종이 473장을 섞어서 한 묶음에 100장씩 묶으려고 합니다. 묶을 수 있는 색종이는 최대 몇 묶음입니까?",
        "question_en": "At a stationery store, 210 sheets of red colored paper and 473 sheets of blue colored paper are mixed and 100 sheets are bound in a bundle. How many bundles of colored paper can you bundle at the maximum?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "210 473 [OP_ADD] 100 [OP_FDIV]",
        "solution_abst_en": "210 473 [OP_ADD] 100 [OP_FDIV]",
        "solution_code_ko": "var_a = 210\nvar_b = 473\nvar_c = var_a + var_b\nvar_d = 100\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 210\nvar_b = 473\nvar_c = var_a + var_b\nvar_d = 100\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "2454": {
        "category": "Comparison",
        "question_ko": "윤기는 20명의 친구들과 함께 농구공 많이 넣기 놀이를 하고 있습니다. 11명의 학생들이 윤기보다 공을 많이 넣었을 때, 윤기보다 공을 못넣은 학생은 몇 명입니까?",
        "question_en": "Yoongi is playing a game of throwing basketballs with his 20 friends. When 11 students had goaled more balls than Yoongi, how many students did not goal balls than Yoongi?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "20 11 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "20 11 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "2455": {
        "category": "Arithmetic calculation",
        "question_ko": "연속된 자연수 5개를 더하니 180이 되었습니다. 이 5개의 수 중 가장 큰 수를 구하시오.",
        "question_en": "Adding 5 consecutive natural numbers equals 180. Find the largest of these 5 numbers.",
        "answer_ko": "38",
        "answer_en": "38",
        "solution_abst_ko": "180 5 [OP_DIV] 5 2 [OP_FDIV] [OP_ADD]",
        "solution_abst_en": "180 5 [OP_DIV] 5 2 [OP_FDIV] [OP_ADD]",
        "solution_code_ko": "var_a = 180\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d // var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 180\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d // var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "2456": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 12를 더한 뒤 4로 나누었더니 몫이 12이고 나머지가 3이 되었습니다. 어떤 수를 구하시오.",
        "question_en": "When you add 12 to a number and divide it by 4, the quotient is 12 and the remainder is 3. find some number",
        "answer_ko": "39",
        "answer_en": "39",
        "solution_abst_ko": "12 4 [OP_MUL] 3 [OP_ADD] 12 [OP_SUB]",
        "solution_abst_en": "12 4 [OP_MUL] 3 [OP_ADD] 12 [OP_SUB]",
        "solution_code_ko": "var_a = 12\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = 12\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 12\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = 12\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "2457": {
        "category": "Comparison",
        "question_ko": "1반과 2반이 우승 상품으로 받은 구슬 1000개를 나누어 가졌습니다. 이 때, 2반이 1반보다 50개를 덜 가져갔고, 2반 남학생들이 2반 여학생보다 총 35개를 더 가져갔습니다. 2반 남학생이 17명이고 남학생들끼리는 똑같이 나누어 가질 때, 2반 남학생 한 명이 받는 구슬의 개수와 1반이 가져간 전체 구슬 개수의 차는 얼마입니까?",
        "question_en": "Classes 1 and 2 shared the 1000 marbles they received as a prize. At this time, class 2 took 50 fewer marbles than class 1 did, and male students in class 2 took a total of 35 more than female students in class 2. If there are 17 boys in class 2 and the marbles were shared with that boys equally, what is the difference between the number of marbles each male in class 2 receives and the total number of marbles taken by class 1?",
        "answer_ko": "510",
        "answer_en": "510",
        "solution_abst_ko": "1000 50 [OP_SUB] 2 [OP_DIV] 50 [OP_ADD] 1000 50 [OP_SUB] 2 [OP_DIV] 35 [OP_SUB] 2 [OP_DIV] 35 [OP_ADD] 17 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "1000 50 [OP_SUB] 2 [OP_DIV] 50 [OP_ADD] 1000 50 [OP_SUB] 2 [OP_DIV] 35 [OP_SUB] 2 [OP_DIV] 35 [OP_ADD] 17 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 1000\nvar_b = 50\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 50\nvar_g = var_e + var_f\nvar_h = 1000\nvar_i = 50\nvar_j = var_h - var_i\nvar_k = 2\nvar_l = var_j / var_k\nvar_m = 35\nvar_n = var_l - var_m\nvar_o = 2\nvar_p = var_n / var_o\nvar_q = 35\nvar_r = var_p + var_q\nvar_s = 17\nvar_t = var_r / var_s\nvar_u = var_g - var_t\nprint(int(var_u))",
        "solution_code_en": "var_a = 1000\nvar_b = 50\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 50\nvar_g = var_e + var_f\nvar_h = 1000\nvar_i = 50\nvar_j = var_h - var_i\nvar_k = 2\nvar_l = var_j / var_k\nvar_m = 35\nvar_n = var_l - var_m\nvar_o = 2\nvar_p = var_n / var_o\nvar_q = 35\nvar_r = var_p + var_q\nvar_s = 17\nvar_t = var_r / var_s\nvar_u = var_g - var_t\nprint(int(var_u))"
    },
    "2458": {
        "category": "Comparison",
        "question_ko": "한 판의 피자를 시켜서 신영이는 1/3, 석기는 1/4, 웅이는 1/5를 먹었습니다. 피자를 가장 많이 먹은 사람은 누구입니까?",
        "question_en": "Shinyoung ate 1/3 of the pizza, Seokgi 1/4, and Woong 1/5. Who ate the most pizza?",
        "answer_ko": "신영",
        "answer_en": "Shinyoung",
        "solution_abst_ko": "[OP_LIST_SOL] 신영 석기 웅이 [OP_LIST_EOL] [OP_LIST_SOL] 1/3 1/4 1/5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Shinyoung Seokgi Woong [OP_LIST_EOL] [OP_LIST_SOL] 1/3 1/4 1/5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '신영'\nvar_b = '석기'\nvar_c = '웅이'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.3333333333333333\nvar_e = 0.25\nvar_f = 0.2\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Shinyoung'\nvar_b = 'Seokgi'\nvar_c = 'Woong'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.3333333333333333\nvar_e = 0.25\nvar_f = 0.2\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "2459": {
        "category": "Comparison",
        "question_ko": "귤나무 A, B, C, D가 있습니다. A는 D보다 귤이 많이 열렸고, D는 C보다 귤이 많이 열렸습니다. B는 A보다 귤이 많이 열렸을 때, 가장 많은 귤이 열려있는 귤나무는 무엇일까요?",
        "question_en": "There are tangerine trees A, B, C, and D. A had more tangerines than D, and D had more tangerines than C. If B has more tangerines than A, which tangerine tree has the most tangerines?",
        "answer_ko": "B",
        "answer_en": "B",
        "solution_abst_ko": "[OP_LIST_SOL] A B C D [OP_LIST_EOL] [OP_LIST_SOL] A D > D C > B A > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D [OP_LIST_EOL] [OP_LIST_SOL] A D > D C > B A > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'A'\nvar_f = 'D'\nvar_g = '>'\nvar_h = 'D'\nvar_i = 'C'\nvar_j = '>'\nvar_k = 'B'\nvar_l = 'A'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = 1\nvar_o = list_c[var_n-1]\nprint(var_o)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'A'\nvar_f = 'D'\nvar_g = '>'\nvar_h = 'D'\nvar_i = 'C'\nvar_j = '>'\nvar_k = 'B'\nvar_l = 'A'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = 1\nvar_o = list_c[var_n-1]\nprint(var_o)"
    },
    "2460": {
        "category": "Geometry",
        "question_ko": "집에 있는 철사로 정육면체를 만들었는데, 한 모서리의 길이가 10센티미터(㎝)인 정육면체를 만들었더니 남은 철사가 없었다. 이 정육면체를 남김없이 사용하여 가로가 8센티미터(㎝), 세로가 5센티미터(㎝)인 직육면체를 만든다면, 높이를 몇 센티미터(㎝)로 해야 하는가?",
        "question_en": "You made a cube with wire at home, and there was no wire left when the edge was 10 centimeters (cm) long. If you use all of this wire in the cube to make a cuboid with a length of 8 centimeters (cm) and a width of 5 centimeters (cm), how high should it be in centimeters (cm)?",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "10 12 [OP_MUL] 8 4 [OP_MUL] [OP_SUB] 5 4 [OP_MUL] [OP_SUB] 4 [OP_DIV]",
        "solution_abst_en": "10 12 [OP_MUL] 8 4 [OP_MUL] [OP_SUB] 5 4 [OP_MUL] [OP_SUB] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = 4\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 5\nvar_i = 4\nvar_j = var_h * var_i\nvar_k = var_g - var_j\nvar_l = 4\nvar_m = var_k / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 10\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = 4\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 5\nvar_i = 4\nvar_j = var_h * var_i\nvar_k = var_g - var_j\nvar_l = 4\nvar_m = var_k / var_l\nprint(int(var_m))"
    },
    "2461": {
        "category": "Correspondence",
        "question_ko": "선영이네 반 학생들과 지우네 반 학생들이 운동장에 함께 줄 서있다. 학생들이 한 줄에 4명씩 12줄로 서 있었고 그 뒤에 3명이 서 있었다. 지우네 반 학생은 12명이다. 선영이네 반 학생은 몇 명인지 구하시오.",
        "question_en": "Seonyeong's classmates and Jieun's classmates are lined up together on the playground. Students are standing in 12 rows of 4 students in each line, followed by 3 students. There are 12 students in Jiune's class. Find how many students are in Seonyeong's class.",
        "answer_ko": "39",
        "answer_en": "39",
        "solution_abst_ko": "12 4 [OP_MUL] 3 [OP_ADD] 12 [OP_SUB]",
        "solution_abst_en": "12 4 [OP_MUL] 3 [OP_ADD] 12 [OP_SUB]",
        "solution_code_ko": "var_a = 12\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = 12\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 12\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = 12\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "2462": {
        "category": "Geometry",
        "question_ko": "철사를 이용하여 한 모서리의 길이가 13센티미터(㎝)인 정육면체를 만들려고 합니다. 몇 센티미터(㎝)의 철사를 사용해야 합니까?",
        "question_en": "You are going to make a cube with one edge 13 centimeters (cm) long using wire. How many centimeters (cm) of wire should I use?",
        "answer_ko": "156",
        "answer_en": "156",
        "solution_abst_ko": "13 4 [OP_MUL] 13 4 [OP_MUL] [OP_ADD] 13 4 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "13 4 [OP_MUL] 13 4 [OP_MUL] [OP_ADD] 13 4 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 13\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = 4\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 13\nvar_i = 4\nvar_j = var_h * var_i\nvar_k = var_g + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 13\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = 4\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 13\nvar_i = 4\nvar_j = var_h * var_i\nvar_k = var_g + var_j\nprint(int(var_k))"
    },
    "2463": {
        "category": "Arithmetic calculation",
        "question_ko": "과자 269개를 29명 학생에게 동일하게 나누어 준다고 합니다. 과자 한 개의 가격은 150원이며 모자란 개수만큼 과자를 산다고 할 때 얼마가 필요한지 구해보세요.",
        "question_en": "It is said that 269 cookies are divided equally among 29 students. If the price of one cookie is 150 won and you buy the lacking number of cookies, find out how much money you need.",
        "answer_ko": "1200",
        "answer_en": "1200",
        "solution_abst_ko": "269 29 [OP_MOD] 150 [OP_MUL]",
        "solution_abst_en": "269 29 [OP_MOD] 150 [OP_MUL]",
        "solution_code_ko": "var_a = 269\nvar_b = 29\nvar_c = var_a % var_b\nvar_d = 150\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 269\nvar_b = 29\nvar_c = var_a % var_b\nvar_d = 150\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "2464": {
        "category": "Correspondence",
        "question_ko": "수한이와 민수와 경연이는 계단을 동시에 하나씩 오른다. 수한이가 10번째 계단일 때 민수는 7번째 계단에 있었고, 민수가 5번째 계단에 있을 때 경연이는 32번째 계단에 있었다. 수한이가 12번째 계단에 올라갔을 때 민수와 경연이가 위치한 계단의 합을 구하시오.",
        "question_en": "Suhan, Minsu, and Gyeongyeon climb the stairs one by one at the same time. When Suhan was on the 10th step, Minsu was on the 7th step, and when Minsu was on the 5th step, Gyeongyeon was on the 32nd step. When Suhan was on the 12th stairway, find the sum of the stairs where Minsu and Gyeongyeon are located.",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "7 10 [OP_SUB] 12 [OP_ADD] 32 5 [OP_SUB] 12 [OP_ADD] [OP_ADD]",
        "solution_abst_en": "7 10 [OP_SUB] 12 [OP_ADD] 32 5 [OP_SUB] 12 [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 7\nvar_b = 10\nvar_c = var_a - var_b\nvar_d = 12\nvar_e = var_c + var_d\nvar_f = 32\nvar_g = 5\nvar_h = var_f - var_g\nvar_i = 12\nvar_j = var_h + var_i\nvar_k = var_e + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 7\nvar_b = 10\nvar_c = var_a - var_b\nvar_d = 12\nvar_e = var_c + var_d\nvar_f = 32\nvar_g = 5\nvar_h = var_f - var_g\nvar_i = 12\nvar_j = var_h + var_i\nvar_k = var_e + var_j\nprint(int(var_k))"
    },
    "2465": {
        "category": "Arithmetic calculation",
        "question_ko": "연필 한 타는 12자루입니다. 연필 6타를 8명에게 남김없이 나누어 주려면 한 사람에게 몇 자루씩 주어야 합니까?",
        "question_en": "There are 12 pencils per stroke. How many pencils must be given to each person to distribute all 6 strokes to 8 people?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "12 6 [OP_MUL] 8 [OP_FDIV]",
        "solution_abst_en": "12 6 [OP_MUL] 8 [OP_FDIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "2466": {
        "category": "Geometry",
        "question_ko": "크기가 다른 두 원 가, 나가 있습니다. 가 원의 반지름은 나 원의 반지름의 4배입니다. 가 원의 지름이 80센티미터(㎝)라면 나 원의 반지름은 몇 센티미터(㎝)인지 구해 보시오.",
        "question_en": "There are two circles A, B of different sizes. The radius of circle A is 4 times the radius of circle B. If the diameter of circle A is 80 centimeters (cm), what is the radius of circle B in centimeters (cm)?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "80 4 [OP_DIV] 2 [OP_DIV]",
        "solution_abst_en": "80 4 [OP_DIV] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 80\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 80\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "2467": {
        "category": "Geometry",
        "question_ko": "둘레가 23.6 센티미터(㎝) 인 정팔각형이 있습니다. 이 도형의 한 변의 길이는 몇 센티미터(㎝) 입니까?",
        "question_en": "A regular octagon has a perimeter of 23.6 centimeters (cm). What is the length of one side of this figure in cm (cm)?",
        "answer_ko": "2.95",
        "answer_en": "2.95",
        "solution_abst_ko": "23.6 8 [OP_DIV]",
        "solution_abst_en": "23.6 8 [OP_DIV]",
        "solution_code_ko": "var_a = 23.6\nvar_b = 8\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 23.6\nvar_b = 8\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "2468": {
        "category": "Correspondence",
        "question_ko": "어떤 수보다 133 큰 수가 282일 때, 어떤 수보다 114 작은 수를 구하시오.",
        "question_en": "If the number 133 greater than this number is 282, find the number 114 less than this number.",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "282 133 [OP_SUB] 114 [OP_SUB]",
        "solution_abst_en": "282 133 [OP_SUB] 114 [OP_SUB]",
        "solution_code_ko": "var_a = 282\nvar_b = 133\nvar_c = var_a - var_b\nvar_d = 114\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 282\nvar_b = 133\nvar_c = var_a - var_b\nvar_d = 114\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "2469": {
        "category": "Possibility",
        "question_ko": "상자 안에는 파란 공 3개와 빨간 공 5개가 있습니다. 2개의 빨간 공을 뺐을 때, 상자 안에 파란 공은 몇 개 있습니까?",
        "question_en": "There are 3 blue balls and 5 red balls in the box. When 2 red balls are removed from that box, how many blue balls are in the box?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "3",
        "solution_abst_en": "3",
        "solution_code_ko": "var_a = 3\nprint(int(var_a))",
        "solution_code_en": "var_a = 3\nprint(int(var_a))"
    },
    "2470": {
        "category": "Geometry",
        "question_ko": "여러 개의 작은 정사각형 타일로 큰 정사각형을 만들었더니 20개의 타일이 남았다. 가로 한 변과 세로 한 변을 1열씩 늘리려서 더 큰 정사각형을 만들려고 하였더니 9개의 타일이 부족하였다. 작은 타일의 수는 총 몇 개인지 구하시오.",
        "question_en": "I made a large square out of several small square tiles, and I have 20 tiles left. When I tried to make a bigger square by adding one row to each horizontal and vertical side, 9 tiles were short. Find the total number of small tiles.",
        "answer_ko": "216",
        "answer_en": "216",
        "solution_abst_ko": "20 9 [OP_ADD] 1 [OP_SUB] 2 [OP_DIV] 2 [OP_POW] 20 [OP_ADD]",
        "solution_abst_en": "20 9 [OP_ADD] 1 [OP_SUB] 2 [OP_DIV] 2 [OP_POW] 20 [OP_ADD]",
        "solution_code_ko": "var_a = 20\nvar_b = 9\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 20\nvar_k = var_i + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 20\nvar_b = 9\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 20\nvar_k = var_i + var_j\nprint(int(var_k))"
    },
    "2471": {
        "category": "Correspondence",
        "question_ko": "17AB를 반올림 하여 백의 자리까지 나타내면 1700이 됩니다. 가능한 A는 몇 개입니까?",
        "question_en": "Rounding 17AB to the hundreds place gives 1700. How many possible A are there?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "17AB [OP_GEN_POSSIBLE_LIST] 1700 50 [OP_SUB] [OP_LIST_MORE_EQUAL] 1700 50 [OP_ADD] [OP_LIST_LESS] 17AB A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_abst_en": "17AB [OP_GEN_POSSIBLE_LIST] 1700 50 [OP_SUB] [OP_LIST_MORE_EQUAL] 1700 50 [OP_ADD] [OP_LIST_LESS] 17AB A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '17AB'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 1700\nvar_c = 50\nvar_d = var_b - var_c\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nvar_e = 1700\nvar_f = 50\nvar_g = var_e + var_f\nlist_c = []\nfor i in list_b:\n    if i < var_g:\n        list_c.append(i)\nvar_h = '17AB'\nvar_i = 'A'\nvar_h = str(var_h)\nvar_i = str(var_i)\nunk_idx = var_h.index(var_i)\nlist_d = []\nfor elem in list_c:\n    elem = str(elem)\n    list_d.append(int(elem[unk_idx]))\nlist_d = list(set(list_d))\nvar_j = len(list_d)\nprint(int(var_j))",
        "solution_code_en": "var_a = '17AB'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 1700\nvar_c = 50\nvar_d = var_b - var_c\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nvar_e = 1700\nvar_f = 50\nvar_g = var_e + var_f\nlist_c = []\nfor i in list_b:\n    if i < var_g:\n        list_c.append(i)\nvar_h = '17AB'\nvar_i = 'A'\nvar_h = str(var_h)\nvar_i = str(var_i)\nunk_idx = var_h.index(var_i)\nlist_d = []\nfor elem in list_c:\n    elem = str(elem)\n    list_d.append(int(elem[unk_idx]))\nlist_d = list(set(list_d))\nvar_j = len(list_d)\nprint(int(var_j))"
    },
    "2472": {
        "category": "Geometry",
        "question_ko": "긴 직사각형 탁자의 넓이가 54제곱미터(㎡)이고 가로가 600센티미터(㎝)이다. 탁자의 세로 길이는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "A long rectangular table has an area of 54 square meters (m2) and a width of 600 centimeters (cm). Find the length of the table in centimeters (cm).",
        "answer_ko": "900",
        "answer_en": "900",
        "solution_abst_ko": "54 100 100 [OP_MUL] [OP_MUL] 600 [OP_DIV]",
        "solution_abst_en": "54 100 100 [OP_MUL] [OP_MUL] 600 [OP_DIV]",
        "solution_code_ko": "var_a = 54\nvar_b = 100\nvar_c = 100\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nvar_f = 600\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 54\nvar_b = 100\nvar_c = 100\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nvar_f = 600\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "2473": {
        "category": "Correspondence",
        "question_ko": "41을 5로 나누면 몫이 A, 나머지가 1이 됩니다. 이 때 A의 값을 구하시오.",
        "question_en": "When 41 is divided by 5, the quotient is A and the remainder is 1. Find the value of A at this time.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "41 1 [OP_SUB] 5 [OP_DIV]",
        "solution_abst_en": "41 1 [OP_SUB] 5 [OP_DIV]",
        "solution_code_ko": "var_a = 41\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 41\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "2474": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 852.5미터(m)인 도로 한쪽에 장미가 34.1미터(m) 간격으로 심어져 있습니다. 도로 한쪽에 심어진 장미는 모두 몇 송이인지 구하시오. 단, 장미의 두께는 생각하지 않습니다.",
        "question_en": "Roses are planted at intervals of 34.1 meters (m) on one side of the road that is 852.5 meters (m) long. Find the total number of roses planted on the side of the road. Note that the thickness of the rose doesn't count.",
        "answer_ko": "25",
        "answer_en": "25",
        "solution_abst_ko": "852.5 34.1 [OP_FDIV] 1 [OP_ADD]",
        "solution_abst_en": "852.5 34.1 [OP_FDIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 852.5\nvar_b = 34.1\nvar_c = var_a // var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 852.5\nvar_b = 34.1\nvar_c = var_a // var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "2475": {
        "category": "Arithmetic calculation",
        "question_ko": "0, 3, 5, 6 중에서 서로 다른 숫자 3개를 뽑아 만들 수 있는 세 자리 수 중에서 가장 작은 수를 쓰시오",
        "question_en": "Write the smallest three-digit number that can be formed by drawing three different numbers from 0, 3, 5, and 6.",
        "answer_ko": "305",
        "answer_en": "305",
        "solution_abst_ko": "[OP_LIST_SOL] 0 3 5 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 3 5 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 0\nvar_b = 3\nvar_c = 5\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 0\nvar_b = 3\nvar_c = 5\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nprint(int(var_g))"
    },
    "2476": {
        "category": "Correspondence",
        "question_ko": "20에 어떤 수를 더하려고 합니다. 잘못하여 40에 어떤 수를 뺐더니 결과는 52가 되었습니다. 바르게 계산한 결과는 얼마일까요?",
        "question_en": "We want to add some number to 20. I mistakenly subtracted some number from 40, and the result was 52. What is the correct calculation result?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "20 40 52 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "20 40 52 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 20\nvar_b = 40\nvar_c = 52\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 40\nvar_c = 52\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "2477": {
        "category": "Geometry",
        "question_ko": "직각삼각형의 빗변의 길이가 17, 빗변이 아닌 한 변의 길이가 15이면 나머지 한 변의 길이는 얼마입니까?",
        "question_en": "If the length of the hypotenuse of a right triangle is 17 and the length of the non-hypotenuse is 15, what is the length of the other side?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "17 2 [OP_POW] 15 2 [OP_POW] [OP_SUB] 1/2 [OP_POW]",
        "solution_abst_en": "17 2 [OP_POW] 15 2 [OP_POW] [OP_SUB] 1/2 [OP_POW]",
        "solution_code_ko": "var_a = 17\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 15\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c - var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 17\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 15\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c - var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))"
    },
    "2478": {
        "category": "Arithmetic calculation",
        "question_ko": "수도꼭지에서 시간 당 2+2/3리터(L)씩 물이 흘러나온다. 9시간 동안 수도꼭지에서 흘러 나온 물은 모두 몇 리터(L)인지 구하시오.",
        "question_en": "Water flows out of the faucet at a rate of 2+2/3 liters (L) per hour. Find the total number of water that came out of the faucet for 9 hours in liters (L).",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "2 2/3 [OP_ADD] 9 [OP_MUL]",
        "solution_abst_en": "2 2/3 [OP_ADD] 9 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 0.6666666666666666\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 0.6666666666666666\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "2479": {
        "category": "Geometry",
        "question_ko": "종호는 정구각형 모양의 대왕 과자를 발견했다. 그 둘레는 무려 171밀리미터(㎜)였다. 대왕 과자의 한 변의 길이를 구하라.",
        "question_en": "Jongho found a giant cookie in the shape of a regular nonagon. Its circumference was 171 millimeters (mm). Find the length of one side of the giant cookie.",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "171 9 [OP_DIV]",
        "solution_abst_en": "171 9 [OP_DIV]",
        "solution_code_ko": "var_a = 171\nvar_b = 9\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 171\nvar_b = 9\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "2480": {
        "category": "Comparison",
        "question_ko": "남준이는 2등을 했고, 윤기는 남준이 다음으로 10명 뒤에 들어갔습니다. 윤기는 몇등입니까?",
        "question_en": "Namjoon won second place, and Yoongi was 10 people behind Namjoon. What is Yoongi's rank?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "2 10 [OP_ADD]",
        "solution_abst_en": "2 10 [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 10\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 10\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "2481": {
        "category": "Comparison",
        "question_ko": "슬기는 연필을 9자루 가지고 있고, 현정이는 연필을 12자루 가지고 있습니다. 연필을 더 많이 가지고 있는 사람은 누구입니까?",
        "question_en": "Seulgi has 9 pencils, and Hyeonjeong has 12 pencils. Who has more pencils?",
        "answer_ko": "현정",
        "answer_en": "Hyeonjeong",
        "solution_abst_ko": "[OP_LIST_SOL] 슬기 현정 [OP_LIST_EOL] [OP_LIST_SOL] 9 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Seulgi Hyeonjeong [OP_LIST_EOL] [OP_LIST_SOL] 9 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '슬기'\nvar_b = '현정'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 9\nvar_d = 12\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Seulgi'\nvar_b = 'Hyeonjeong'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 9\nvar_d = 12\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "2482": {
        "category": "Geometry",
        "question_ko": "용량이 36리터(L)인 직육면체 모양의 물 탱크를 가로, 세로, 높이를 모두 2배하면 부피는 얼마가 되는지 구하시오.",
        "question_en": "What is the volume of a cuboid-shaped water tank with a capacity of 36 liters (L) if the length, width, and height are all doubled?",
        "answer_ko": "288",
        "answer_en": "288",
        "solution_abst_ko": "36 2 3 [OP_POW] [OP_MUL]",
        "solution_abst_en": "36 2 3 [OP_POW] [OP_MUL]",
        "solution_code_ko": "var_a = 36\nvar_b = 2\nvar_c = 3\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 36\nvar_b = 2\nvar_c = 3\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nprint(int(var_e))"
    },
    "2483": {
        "category": "Arithmetic calculation",
        "question_ko": "100이하의 자연수 중 7로 나눈 나머지가 2이고 8로 나눈 나머지도 2인 수들의 합을 구하시오.",
        "question_en": "Find the sum of all natural numbers less than or equal to 100 that have a remainder of 2 when divided by 7 and a remainder of 2 when divided by 8.",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "1 100 1 [OP_LIST_ARANGE] 7 2 [OP_LIST_DIVIDE_AND_REMAIN] 8 2 [OP_LIST_DIVIDE_AND_REMAIN] [OP_LIST_SUM]",
        "solution_abst_en": "1 100 1 [OP_LIST_ARANGE] 7 2 [OP_LIST_DIVIDE_AND_REMAIN] 8 2 [OP_LIST_DIVIDE_AND_REMAIN] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 7\nvar_e = 2\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 8\nvar_g = 2\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nlist_c = [float(i) for i in list_c]\nvar_h = sum(list_c)\nprint(int(var_h))",
        "solution_code_en": "var_a = 1\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 7\nvar_e = 2\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 8\nvar_g = 2\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nlist_c = [float(i) for i in list_c]\nvar_h = sum(list_c)\nprint(int(var_h))"
    },
    "2484": {
        "category": "Correspondence",
        "question_ko": "A, B는 서로 다른 두 자연수입니다. A를 29로 나누면 몫은 31, 나머지는 B입니다. B를 가장 작게 만드는 A를 구하세요.",
        "question_en": "A and B are two different natural numbers. When A is divided by 29, the quotient is 31 and the remainder is B. Find A that makes B the smallest.",
        "answer_ko": "900",
        "answer_en": "900",
        "solution_abst_ko": "29 31 [OP_MUL] 1 [OP_ADD]",
        "solution_abst_en": "29 31 [OP_MUL] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 29\nvar_b = 31\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 29\nvar_b = 31\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "2485": {
        "category": "Arithmetic calculation",
        "question_ko": "철사 4미터(m) 로 모빌을 1 개 만들 수 있습니다. 철사 105.8미터(m) 로 같은 크기의 모빌을 여러 개 만들고 남는 철사는 몇 미터(m)입니까?",
        "question_en": "You can make one mobile with 4 meters (m) of wire. How many meters (m) of wire are left after making multiple mobiles of the same size with 105.8 meters (m) of wire?",
        "answer_ko": "1.80",
        "answer_en": "1.8",
        "solution_abst_ko": "105.8 4 [OP_MOD]",
        "solution_abst_en": "105.8 4 [OP_MOD]",
        "solution_code_ko": "var_a = 105.8\nvar_b = 4\nvar_c = var_a % var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 105.8\nvar_b = 4\nvar_c = var_a % var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "2486": {
        "category": "Arithmetic calculation",
        "question_ko": "물 10.4킬로그램(㎏)이 담긴 통이 있습니다. 이 물을 작은 물통 한 개에 0.8 킬로그램(㎏) 씩 나누어 담으려고 할 때, 필요한 물통은 모두 몇 개 인가요?",
        "question_en": "There is a barrel with 10.4 kilograms (kg) of water. If you want to divide this water by 0.8 kg (kg) into one small bucket, how many buckets are needed?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "10.4 0.8 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "10.4 0.8 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 10.4\nvar_b = 0.8\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))",
        "solution_code_en": "var_a = 10.4\nvar_b = 0.8\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))"
    },
    "2487": {
        "category": "Arithmetic calculation",
        "question_ko": "태민, 민호, 기범이가 초콜릿을 나눠가졌습니다. 태민이는 민호가 가진 초콜릿의 5배, 기범이는 민호가 가진 초콜릿의 3배를 가지고 있습니다. 태민이와 기범이가 가진 초콜릿의 수의 합이 160일 때, 민호는 몇 개의 초콜릿을 가지고 있는지 구하세요.",
        "question_en": "Taemin, Minho, and Kibum shared chocolate. Taemin has 5 times as much chocolate as Minho has, and Kibeom has 3 times as much chocolate as Minho has. If the sum of the chocolates that Taemin and Kibum have is 160, find how many chocolates Minho has.",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "160 5 3 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "160 5 3 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 160\nvar_b = 5\nvar_c = 3\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 160\nvar_b = 5\nvar_c = 3\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "2488": {
        "category": "Arithmetic calculation",
        "question_ko": "율기와 가영이가 가지고 있는 용돈의 합은 6000원이고, 두 사람이 가지고 있는 용돈의 차를 용돈의 합에서 빼면 4800원입니다. 율기의 용돈이 가영이의 용돈보다 많다면 율기는 용돈을 얼마 가지고 있습니까?",
        "question_en": "The sum of the pocket money Yulgi and Gayeong have is 6,000 won. If you subtract the difference between the two people's pocket money from the sum of their pocket money, it's 4800 won. If Yulgi has more pocket money than Gayeong, how much pocket money does Yulgi have?",
        "answer_ko": "3600",
        "answer_en": "3600",
        "solution_abst_ko": "6000 4800 2 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "6000 4800 2 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 6000\nvar_b = 4800\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6000\nvar_b = 4800\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "2489": {
        "category": "Correspondence",
        "question_ko": "37에서 어떤 수를 빼면 24가 나온다. 어떤 수에 24를 곱하면 얼마인지 구하시오.",
        "question_en": "Subtracting a certain number from 37 gives 24. What is the value of the certain number multiplied by 24?",
        "answer_ko": "312",
        "answer_en": "312",
        "solution_abst_ko": "37 24 [OP_SUB] 24 [OP_MUL]",
        "solution_abst_en": "37 24 [OP_SUB] 24 [OP_MUL]",
        "solution_code_ko": "var_a = 37\nvar_b = 24\nvar_c = var_a - var_b\nvar_d = 24\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 37\nvar_b = 24\nvar_c = var_a - var_b\nvar_d = 24\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "2490": {
        "category": "Possibility",
        "question_ko": "3장의 카드의 합을 구하려고 합니다. 10, 30, 50이 2장씩 들어 있는 상자에서 카드를 뽑을 때 서로 다른 합이 될 수 있는 경우는 모두 몇 가지입니까?",
        "question_en": "I am trying to find the sum of the 3 cards. When selecting cards from a box where 2 cards of 10, 30, and 50 each are contained, how many different sums can be possibly made?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "[OP_LIST_SOL] 10 30 50 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_MUL] 3 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] 10 30 50 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_MUL] 3 [OP_COMB]",
        "solution_code_ko": "var_a = 10\nvar_b = 30\nvar_c = 50\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = 3\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h / (i+1)\nprint(int(var_h))",
        "solution_code_en": "var_a = 10\nvar_b = 30\nvar_c = 50\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = 3\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h / (i+1)\nprint(int(var_h))"
    },
    "2491": {
        "category": "Geometry",
        "question_ko": "가로에 대한 세로의 비율이 0.875인 직사각형이 있습니다. 이 직사각형의 가로가 24센티미터(㎝)일 때 직사각형의 넓이는 몇 제곱센티미터(㎠)입니까?",
        "question_en": "There is a rectangle with a length to width ratio of 0.875. Given that the width of this rectangle is 24 centimeters (cm), what is the area of the rectangle in square centimeters (cm2)?",
        "answer_ko": "504",
        "answer_en": "504",
        "solution_abst_ko": "24 0.875 [OP_MUL] 24 [OP_MUL]",
        "solution_abst_en": "24 0.875 [OP_MUL] 24 [OP_MUL]",
        "solution_code_ko": "var_a = 24\nvar_b = 0.875\nvar_c = var_a * var_b\nvar_d = 24\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 24\nvar_b = 0.875\nvar_c = var_a * var_b\nvar_d = 24\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "2492": {
        "category": "Possibility",
        "question_ko": "숫자카드 3, 6, 9를 한 번씩 모두 사용하여 세 자리 수를 만들려고 합니다. 만들 수 있는 세 자리 수는 모두 몇 개입니까?",
        "question_en": "You are going to use all of the number cards 3, 6, and 9 once each to create three-digit numbers. How many three-digit numbers can you make?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 3 6 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 3 6 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 3\nvar_b = 6\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 3\nvar_b = 6\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "2493": {
        "category": "Possibility",
        "question_ko": "5, 1, 6, 7 중에서 서로 다른 숫자 2개를 뽑아 만들 수 있는 가장 작은 두 자리 수에서 남은 두 수를 차례로 뺀 값은 얼마입니까?",
        "question_en": "What is the value created by subtracting the remaining two numbers in order from the smallest two-digit number that can be made by picking two different numbers from 5,1,6,7?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 5 1 6 7 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 1 [OP_LIST_MAX] [OP_NUM2LIST] [OP_LIST_SUM] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 5 1 6 7 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 1 [OP_LIST_MAX] [OP_NUM2LIST] [OP_LIST_SUM] [OP_SUB]",
        "solution_code_ko": "var_a = 5\nvar_b = 1\nvar_c = 6\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nlist_e = []\nvar_i = int(var_i)\nwhile var_i//10 > 0:\n    list_e.append(var_i%10)\n    var_i = var_i//10\nlist_e.append(var_i%10)\nlist_e = list_e[::-1]\nlist_e = [float(i) for i in list_e]\nvar_j = sum(list_e)\nvar_k = var_g - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 5\nvar_b = 1\nvar_c = 6\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nlist_e = []\nvar_i = int(var_i)\nwhile var_i//10 > 0:\n    list_e.append(var_i%10)\n    var_i = var_i//10\nlist_e.append(var_i%10)\nlist_e = list_e[::-1]\nlist_e = [float(i) for i in list_e]\nvar_j = sum(list_e)\nvar_k = var_g - var_j\nprint(int(var_k))"
    },
    "2494": {
        "category": "Geometry",
        "question_ko": "정육면체의 꼭짓점의 수와 면의 수를 곱하면 얼마입니까?",
        "question_en": "What is the product of the number of vertices and the number of faces of a cube?",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "6 8 [OP_MUL]",
        "solution_abst_en": "6 8 [OP_MUL]",
        "solution_code_ko": "var_a = 6\nvar_b = 8\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 8\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "2495": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 23으로 나눈 값에서 67을 뺀 후 2를 곱한 값이 102입니다. 어떤 수를 구하시오.",
        "question_en": "A particular number divided by 23, minus 67 and multiplied by 2 is 102. Find out that particular number.",
        "answer_ko": "2714",
        "answer_en": "2714",
        "solution_abst_ko": "102 2 [OP_DIV] 67 [OP_ADD] 23 [OP_MUL]",
        "solution_abst_en": "102 2 [OP_DIV] 67 [OP_ADD] 23 [OP_MUL]",
        "solution_code_ko": "var_a = 102\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 67\nvar_e = var_c + var_d\nvar_f = 23\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 102\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 67\nvar_e = var_c + var_d\nvar_f = 23\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "2496": {
        "category": "Correspondence",
        "question_ko": "42는 어떤 수에 7/12를 곱한 값입니다. 어떤 수에 11/18을 곱하고 4를 뺀 수는 얼마입니까?",
        "question_en": "A certain number is multiplied by 7/12 resulting 42. What is the value when the certain number is multiplied by 11/18 and subtract 4?",
        "answer_ko": "40",
        "answer_en": "40",
        "solution_abst_ko": "42 1 7/12 [OP_DIV] [OP_MUL] 11/18 [OP_MUL] 4 [OP_SUB]",
        "solution_abst_en": "42 1 7/12 [OP_DIV] [OP_MUL] 11/18 [OP_MUL] 4 [OP_SUB]",
        "solution_code_ko": "var_a = 42\nvar_b = 1\nvar_c = 0.5833333333333334\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 0.6111111111111112\nvar_g = var_e * var_f\nvar_h = 4\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 42\nvar_b = 1\nvar_c = 0.5833333333333334\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 0.6111111111111112\nvar_g = var_e * var_f\nvar_h = 4\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "2497": {
        "category": "Correspondence",
        "question_ko": "A는 1000개씩 묶음이 6개, 100개씩있는 묶음이 36개인 수입니다. B는 876에서 197씩 작아지도록 2번 뛰어서 센 수라면, A에서 B를 뺀 값을 구하시오.",
        "question_en": "A is a number of 6 bundles with 1000 and 36 bundles with 100. If B is counted by jumping twice from 876 to 197 smaller, subtract B from A to find the value.",
        "answer_ko": "9118",
        "answer_en": "9118",
        "solution_abst_ko": "1000 6 [OP_MUL] 100 36 [OP_MUL] [OP_ADD] 876 197 2 [OP_MUL] [OP_SUB] [OP_SUB]",
        "solution_abst_en": "1000 6 [OP_MUL] 100 36 [OP_MUL] [OP_ADD] 876 197 2 [OP_MUL] [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 1000\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = 36\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 876\nvar_i = 197\nvar_j = 2\nvar_k = var_i * var_j\nvar_l = var_h - var_k\nvar_m = var_g - var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 1000\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = 36\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 876\nvar_i = 197\nvar_j = 2\nvar_k = var_i * var_j\nvar_l = var_h - var_k\nvar_m = var_g - var_l\nprint(int(var_m))"
    },
    "2498": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 7을 뺐더니 2가 되었습니다. 어떤 수를 구하시오.",
        "question_en": "Subtracting 7 from a particular number gives you 2. Find out that particular number.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "2 7 [OP_ADD]",
        "solution_abst_en": "2 7 [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "2499": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 8.8 센티미터(㎝) 인 나무토막을 0.5 센티미터(㎝) 씩 겹치게 이었더니 이은 나무토막 전체 길이가 282.7 센티미터(㎝) 였습니 다. 이은 나무토막은 모두 몇 장입니까?",
        "question_en": "When the 8.8 centimeters (cm) long block of wood was overlapped by 0.5 centimeters (cm), the total length of the connected block was 282.7 centimeters (cm). How many pieces of wood are there in total?",
        "answer_ko": "34",
        "answer_en": "34",
        "solution_abst_ko": "282.7 8.8 [OP_SUB] 8.8 0.5 [OP_SUB] [OP_DIV] 1 [OP_ADD]",
        "solution_abst_en": "282.7 8.8 [OP_SUB] 8.8 0.5 [OP_SUB] [OP_DIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 282.7\nvar_b = 8.8\nvar_c = var_a - var_b\nvar_d = 8.8\nvar_e = 0.5\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 1\nvar_i = var_g + var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))",
        "solution_code_en": "var_a = 282.7\nvar_b = 8.8\nvar_c = var_a - var_b\nvar_d = 8.8\nvar_e = 0.5\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 1\nvar_i = var_g + var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))"
    },
    "2500": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 2를 더해야 하는데 잘못하여 2를 뺐더니 6이 되었습니다. 어떤 수를 구하시오.",
        "question_en": "You were supposed to add 2 to a number, but mistakenly subtracted 2, thereby getting 6. Find the number should be.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "6 2 [OP_ADD]",
        "solution_abst_en": "6 2 [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "2501": {
        "category": "Arithmetic calculation",
        "question_ko": "사탕이 23개 있었습니다. 그 중에서 유나가 몇 개를 먹었더니 7개가 남았습니다. 유나가 먹은 사탕은 몇 개입니까?",
        "question_en": "There were 23 candies. Yuna ate a few of them, and there were 7 left. How many candies did Yuna eat?",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "23 7 [OP_SUB]",
        "solution_abst_en": "23 7 [OP_SUB]",
        "solution_code_ko": "var_a = 23\nvar_b = 7\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 23\nvar_b = 7\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "2502": {
        "category": "Arithmetic calculation",
        "question_ko": "수영이네 학교에 올해 입학한 1학년 학생 134명에게 사탕 목걸이를 만들어 주려고 합니다. 사탕 목걸이 한 개에 사탕이 7개씩 필요합니다. 한 봉지에 28개씩 들어있는 사탕을 적어도 몇 봉지 사야 합니까?",
        "question_en": "You are going to make candy necklaces for 134 first-year students who entered Suyeong's school this year. Each candy necklace costs 7 candies. How many bags of 28 candies per bag should I buy at least?",
        "answer_ko": "34",
        "answer_en": "34",
        "solution_abst_ko": "134 7 [OP_MUL] 28 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "134 7 [OP_MUL] 28 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 134\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 28\nvar_e = var_c / var_d\nvar_f = 1\nvar_g=int(((var_e+9*10**(var_f-2))//(10**(var_f-1)))*10**(var_f-1))\n\nprint(int(var_g))",
        "solution_code_en": "var_a = 134\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 28\nvar_e = var_c / var_d\nvar_f = 1\nvar_g=int(((var_e+9*10**(var_f-2))//(10**(var_f-1)))*10**(var_f-1))\n\nprint(int(var_g))"
    },
    "2503": {
        "category": "Possibility",
        "question_ko": "빨간 공 3개, 파란 공 2개, 노란 공 5개가 담겨져 있는 상자에서 노란 공 4개를 넣었을 때 때, 빨간 공은 몇 개 있습니까?",
        "question_en": "How many red balls are there when 4 yellow balls are placed inside a box containing 3 red balls, 2 blue balls, and 5 yellow balls?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "3",
        "solution_abst_en": "3",
        "solution_code_ko": "var_a = 3\nprint(int(var_a))",
        "solution_code_en": "var_a = 3\nprint(int(var_a))"
    },
    "2504": {
        "category": "Possibility",
        "question_ko": "연필 40자루를 여러 개의 통에 똑같이 나누어 담으려고 합니다. 연필을 나누어 담는 방법은 모두 몇 가지일까요? (단, 통은 1개보다 많습니다.)",
        "question_en": "You want to divide 40 pencils equally into several bins. How many ways are there to divide the pencils? (However, there are more than one barrel.)",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "40 [OP_LIST_GET_DIVISOR] [OP_LIST_SOL] 1 [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_abst_en": "40 [OP_LIST_GET_DIVISOR] [OP_LIST_SOL] 1 [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 40\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 1\nlist_b= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_b.append(var_b)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_c = len(list_c)\nprint(int(var_c))",
        "solution_code_en": "var_a = 40\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 1\nlist_b= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_b.append(var_b)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_c = len(list_c)\nprint(int(var_c))"
    },
    "2505": {
        "category": "Correspondence",
        "question_ko": "A는 100개씩 묶음이 20개, 10개씩 묶음이 87개인 수입니다. B는 278에서 365씩 커지게 3번 뛰어서 센 수입니다. A+B의 값을 구하시오.",
        "question_en": "A is a number which consists of 20 groups of 100 and 87 groups of 10. B is a number which is counted by jumping 3 times, increasing from 278 to 365. Find the value of A+B.",
        "answer_ko": "4243",
        "answer_en": "4243",
        "solution_abst_ko": "100 20 [OP_MUL] 10 87 [OP_MUL] [OP_ADD] 278 365 3 [OP_MUL] [OP_ADD] [OP_ADD]",
        "solution_abst_en": "100 20 [OP_MUL] 10 87 [OP_MUL] [OP_ADD] 278 365 3 [OP_MUL] [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 100\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 10\nvar_e = 87\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 278\nvar_i = 365\nvar_j = 3\nvar_k = var_i * var_j\nvar_l = var_h + var_k\nvar_m = var_g + var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 100\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 10\nvar_e = 87\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 278\nvar_i = 365\nvar_j = 3\nvar_k = var_i * var_j\nvar_l = var_h + var_k\nvar_m = var_g + var_l\nprint(int(var_m))"
    },
    "2506": {
        "category": "Comparison",
        "question_ko": "빵을 민영이는 13개, 은지는 21개 가지고 있습니다. 빵을 더 많이 가지고 있는 사람은 누구입니까?",
        "question_en": "Minyoung has 13 bread and Eunji has 21. Who has more bread?",
        "answer_ko": "은지",
        "answer_en": "Eunji",
        "solution_abst_ko": "[OP_LIST_SOL] 민영 은지 [OP_LIST_EOL] [OP_LIST_SOL] 13 21 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Minyoung Eunji [OP_LIST_EOL] [OP_LIST_SOL] 13 21 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '민영'\nvar_b = '은지'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 13\nvar_d = 21\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Minyoung'\nvar_b = 'Eunji'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 13\nvar_d = 21\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "2507": {
        "category": "Geometry",
        "question_ko": "가로가 54센티미터(㎝), 세로가 20센티미터(㎝)인 직사각형 모양의 종이를 잘라서 크기가 같은 정사각형 3개를 만들려고 합니다. 가장 큰 정사각형을 만들려면 한 변의 길이를 몇 센티미터(㎝)로 해야합니까?",
        "question_en": "You are going to cut a rectangular paper that is 54 centimeters (cm) long and 20 centimeters (cm) wide to make three equal-sized squares. How many centimeters (cm) must each side be to make the largest square?",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "[OP_LIST_SOL] 54 3 [OP_FDIV] 20 3 [OP_FDIV] [OP_LIST_EOL] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 54 3 [OP_FDIV] 20 3 [OP_FDIV] [OP_LIST_EOL] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 54\nvar_b = 3\nvar_c = var_a // var_b\nvar_d = 20\nvar_e = 3\nvar_f = var_d // var_e\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nlist_a.reverse()\nvar_g = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_h = list_b[-var_g]\nprint(int(var_h))",
        "solution_code_en": "var_a = 54\nvar_b = 3\nvar_c = var_a // var_b\nvar_d = 20\nvar_e = 3\nvar_f = var_d // var_e\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nlist_a.reverse()\nvar_g = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_h = list_b[-var_g]\nprint(int(var_h))"
    },
    "2508": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 11을 나누었더니 결과가 2가 되었습니다. 어떤 수에 6을 곱하면?",
        "question_en": "When you divide a number by 11, the result is 2. What is a number multiplied by 6?",
        "answer_ko": "132",
        "answer_en": "132",
        "solution_abst_ko": "2 11 [OP_MUL] 6 [OP_MUL]",
        "solution_abst_en": "2 11 [OP_MUL] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 11\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 11\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "2509": {
        "category": "Correspondence",
        "question_ko": "만두를 찔 때 한 판에 가로 3개, 세로 3개씩 바둑판 배열로 올려놓고 찐다고 한다. 18개의 만두를 찌기 위해선 몇 개의 판이 필요한가?",
        "question_en": "It is said that when steaming dumplings, they are steamed by placing them in a checkerboard arrangement, 3 horizontally and 3 vertically, on a plate. How many plates are needed to steam 18 dumplings?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "18 3 [OP_DIV] 3 [OP_DIV]",
        "solution_abst_en": "18 3 [OP_DIV] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 18\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 18\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "2510": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 12를 곱하려고 합니다. 잘못하여 14를 나눴을 때의 답이 42라면 바르게 계산한 결과는 얼마일까요?",
        "question_en": "You want to multiply a number by 12. If the answer when mistakenly dividing this number by 14 is 42, what is the correct result?",
        "answer_ko": "7056",
        "answer_en": "7056",
        "solution_abst_ko": "42 14 [OP_MUL] 12 [OP_MUL]",
        "solution_abst_en": "42 14 [OP_MUL] 12 [OP_MUL]",
        "solution_code_ko": "var_a = 42\nvar_b = 14\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 42\nvar_b = 14\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "2511": {
        "category": "Arithmetic calculation",
        "question_ko": "달팽이 5마리와 개구리 2마리가 연못에 있습니다. 연못에 있는 달팽이와 개구리는 몇 마리 일까요?",
        "question_en": "There are 5 snails and 2 frogs in the pond. How many snails and frogs are in the pond?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "5 2 [OP_ADD]",
        "solution_abst_en": "5 2 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "2512": {
        "category": "Arithmetic calculation",
        "question_ko": "10개의 구슬이 담긴 빨간 주머니, 50개의 구슬이 담긴 파란 주머니, 100개의 구슬이 담긴 노란 주머니가 총 12개 있습니다. 총 구슬의 개수는 500개 이며 빨간 주머니와 파란 주머니의 개수는 같다고 할 때, 노란 주머니의 개수는 몇 개 입니까?",
        "question_en": "Red bags contain 10 marbles, and blue bags contain 50 marbles, and yellow bags contain 100 marbles, and there are total 12 bags. If the total number of marbles is 500 and the number of red and blue bags is the same, how many yellow bags are there?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "12 500 100 12 [OP_MUL] [OP_SUB] 10 50 [OP_ADD] 100 2 [OP_MUL] [OP_SUB] [OP_DIV] 2 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "12 500 100 12 [OP_MUL] [OP_SUB] 10 50 [OP_ADD] 100 2 [OP_MUL] [OP_SUB] [OP_DIV] 2 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 12\nvar_b = 500\nvar_c = 100\nvar_d = 12\nvar_e = var_c * var_d\nvar_f = var_b - var_e\nvar_g = 10\nvar_h = 50\nvar_i = var_g + var_h\nvar_j = 100\nvar_k = 2\nvar_l = var_j * var_k\nvar_m = var_i - var_l\nvar_n = var_f / var_m\nvar_o = 2\nvar_p = var_n * var_o\nvar_q = var_a - var_p\nprint(int(var_q))",
        "solution_code_en": "var_a = 12\nvar_b = 500\nvar_c = 100\nvar_d = 12\nvar_e = var_c * var_d\nvar_f = var_b - var_e\nvar_g = 10\nvar_h = 50\nvar_i = var_g + var_h\nvar_j = 100\nvar_k = 2\nvar_l = var_j * var_k\nvar_m = var_i - var_l\nvar_n = var_f / var_m\nvar_o = 2\nvar_p = var_n * var_o\nvar_q = var_a - var_p\nprint(int(var_q))"
    },
    "2513": {
        "category": "Correspondence",
        "question_ko": "172개의 연필을 학생들에게 나누어 주는데 4개 반에 똑같이 나누어 주어야 할 연필을 잘못하여 더 많은 반에 똑같이 나누어주었더니, 원래 반마다 나누어주었어야 하는 연필의 양보다 28개가 더 적게 나누어 주게 되었다. 연필을 똑같이 나누어 주고 7개가 남았다면 연필을 몇 개의 반에 나누어 준 것인지 구하시오.",
        "question_en": "172 pencils were to be distributed to students, but the pencils that should have been distributed equally to 4 classes were distributed equally to more classes by mistake, resulting in 28 fewer pencils per class than the amount originally planned to be given. If the pencils are distributed equally and 7 pencils are remaining, find out how many classes the pencils are divided into.",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "172 7 [OP_SUB] 172 4 [OP_DIV] 28 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "172 7 [OP_SUB] 172 4 [OP_DIV] 28 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 172\nvar_b = 7\nvar_c = var_a - var_b\nvar_d = 172\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = 28\nvar_h = var_f - var_g\nvar_i = var_c / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 172\nvar_b = 7\nvar_c = var_a - var_b\nvar_d = 172\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = 28\nvar_h = var_f - var_g\nvar_i = var_c / var_h\nprint(int(var_i))"
    },
    "2514": {
        "category": "Geometry",
        "question_ko": "어떤 직선 위에 있는 점 4개와 직선 위에 있지 않은 점 1개가 있다. 이 중 두 점을 연결하여 만들수있는 직선의 개수를 구하시오.",
        "question_en": "There are 4 points on a line and 1 point not on a line. Find the number of straight lines that can be made by joining any two of these points.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "4 1 [OP_ADD]",
        "solution_abst_en": "4 1 [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "2515": {
        "category": "Comparison",
        "question_ko": "유정은 책상 위에 색색의 공을 일렬로 늘어놓았다. 빨간색, 파란색, 노란색, 보라색, 흰색 공을 차례로 놓으면 첫 번째 공은 무슨 색입니까?",
        "question_en": "Yujeong arranged colored balls in a row on the desk. If she puts red, blue, yellow, purple, and white balls in order, what color is the first ball?",
        "answer_ko": "빨간색",
        "answer_en": "red",
        "solution_abst_ko": "[OP_LIST_SOL] 빨간색 파란색 노란색 보라색 흰색 [OP_LIST_EOL] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] red blue yellow purple white [OP_LIST_EOL] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '빨간색'\nvar_b = '파란색'\nvar_c = '노란색'\nvar_d = '보라색'\nvar_e = '흰색'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nvar_g = list_a[var_f-1]\nprint(var_g)",
        "solution_code_en": "var_a = 'red'\nvar_b = 'blue'\nvar_c = 'yellow'\nvar_d = 'purple'\nvar_e = 'white'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nvar_g = list_a[var_f-1]\nprint(var_g)"
    },
    "2516": {
        "category": "Geometry",
        "question_ko": "준서는 미술 시간에 색도화지로 넓이가 80제곱센티미터(㎠)인 마름모를 만들었습니다. 준서가 만든 마름모의 한 대각선의 길이가 16 센티미터(㎝)일 때 다른 대각선의 길이는 몇 센티미터(㎝)일까요?",
        "question_en": "In art class, Junseo made a rhombus with an area of 80 square centimeters (cm2) with colored paper. If the length of one diagonal of the rhombus created by Junseo is 16 centimeters (cm), how many centimeters (cm) is the length of the other diagonal?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "80 2 [OP_MUL] 16 [OP_DIV]",
        "solution_abst_en": "80 2 [OP_MUL] 16 [OP_DIV]",
        "solution_code_ko": "var_a = 80\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 16\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 80\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 16\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "2517": {
        "category": "Correspondence",
        "question_ko": "색종이 몇 장을 6사람에게 똑같이 나누어 주었더니 한 사람에게 7장씩 갖게 되고 3장이 남았습니다. 처음에 있던 색종이는 몇 장이었습니까?",
        "question_en": "I divided some pieces of colored paper equally among 6 people, and each person got 7 pieces, leaving 3 pieces. How many sheets of colored paper were there at first?",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "7 6 [OP_MUL] 3 [OP_ADD]",
        "solution_abst_en": "7 6 [OP_MUL] 3 [OP_ADD]",
        "solution_code_ko": "var_a = 7\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 7\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "2518": {
        "category": "Possibility",
        "question_ko": "7개 반이 축구 시합을 하려고 합니다. 모든 반이 다른 반과 한 번씩 경기를 할 때, 경기의 총 횟수를 구하시오.",
        "question_en": "Seven classes are going to play soccer. If every class plays every other class once, find the total number of matches.",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "7 7 1 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "7 7 1 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 7\nvar_b = 7\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 7\nvar_b = 7\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "2519": {
        "category": "Arithmetic calculation",
        "question_ko": "은지는 어제 삼촌에게 받은 용돈의 반으로 공책을 샀습니다. 오늘 어머니에게 용돈 550원을 받아 모두 1,000원이 되었습니다. 삼촌에게 받은 용돈은 얼마입니까?",
        "question_en": "Eunji bought a notebook with half of her pocket money she received from her uncle yesterday. Today, she received 550 won from her mother, so the total is 1,000 won. How much money did she get from your uncle?",
        "answer_ko": "900",
        "answer_en": "900",
        "solution_abst_ko": "1000 550 [OP_SUB] 2 [OP_MUL]",
        "solution_abst_en": "1000 550 [OP_SUB] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 1000\nvar_b = 550\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 1000\nvar_b = 550\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "2520": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 학교의 남학생 수는 여학생 수 보다 124명 더 많다. 학교의 총 학생 수가 1250명 일 때, 여학생은 몇 명인지 구하시오",
        "question_en": "A school has 124 more boys than girls. If the total number of students in the school is 1250, how many girls are there?",
        "answer_ko": "563",
        "answer_en": "563",
        "solution_abst_ko": "1250 124 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "1250 124 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 1250\nvar_b = 124\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 1250\nvar_b = 124\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "2521": {
        "category": "Geometry",
        "question_ko": "넓이가 108제곱센티미터(㎠)인 직사각형과, 이 직사각형과 가로의 비가 8:7, 세로의 비가 9:4인 작은 직사각형이 있습니다. 작은 직사각형의 넓이를 구하시오.",
        "question_en": "There is a rectangle with an area of 108 square centimeters (cm2) and a small rectangle with a width ratio of 8:7 and a height ratio of 9:4. Find the area of the small rectangle.",
        "answer_ko": "42",
        "answer_en": "42",
        "solution_abst_ko": "108 8 [OP_DIV] 7 [OP_MUL] 9 [OP_DIV] 4 [OP_MUL]",
        "solution_abst_en": "108 8 [OP_DIV] 7 [OP_MUL] 9 [OP_DIV] 4 [OP_MUL]",
        "solution_code_ko": "var_a = 108\nvar_b = 8\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c * var_d\nvar_f = 9\nvar_g = var_e / var_f\nvar_h = 4\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 108\nvar_b = 8\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c * var_d\nvar_f = 9\nvar_g = var_e / var_f\nvar_h = 4\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "2522": {
        "category": "Geometry",
        "question_ko": "넓이가 같은 정사각형과 직사각형이 있습니다. 정사각형의 한 변의 길이가 5센티미터(㎝), 직사각형의 한 변의 길이는 4센티미터(㎝)입니다. 이때 직사각형의 다른 한 변의 길이를 구하시오.",
        "question_en": "There are one square and one rectangle with the same area. A side of a square is 5 centimeters (cm), and a side of a rectangle is 4 centimeters (cm). Find the length of the other side of the rectangle.",
        "answer_ko": "6.25",
        "answer_en": "6.25",
        "solution_abst_ko": "5 2 [OP_POW] 4 [OP_DIV]",
        "solution_abst_en": "5 2 [OP_POW] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "2523": {
        "category": "Arithmetic calculation",
        "question_ko": "350원짜리 우유와 500원 짜리 물을 사고 1000원을 줬을 때 받아야할 거스름돈은 얼마입니까?",
        "question_en": "If you buy 350 won milk and 500 won water and give 1000 won, how much change do you have to get?",
        "answer_ko": "150",
        "answer_en": "150",
        "solution_abst_ko": "1000 350 [OP_SUB] 500 [OP_SUB]",
        "solution_abst_en": "1000 350 [OP_SUB] 500 [OP_SUB]",
        "solution_code_ko": "var_a = 1000\nvar_b = 350\nvar_c = var_a - var_b\nvar_d = 500\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 1000\nvar_b = 350\nvar_c = var_a - var_b\nvar_d = 500\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "2524": {
        "category": "Geometry",
        "question_ko": "정십이면체 모양의 상자가 있습니다. 이 상자의 면의 개수는?",
        "question_en": "If there is a box in the shape of a regular dodecahedron, how many sides can be counted?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "12",
        "solution_abst_en": "12",
        "solution_code_ko": "var_a = 12\nprint(int(var_a))",
        "solution_code_en": "var_a = 12\nprint(int(var_a))"
    },
    "2525": {
        "category": "Correspondence",
        "question_ko": "서울에서 부산까지 가는 기차가 있다. 처음 탄 인원의 2/5보다 300명 많은 인원이 첫번째 역에서 내렸고 남은 사람의 1/2보다 200명 적은 인원이 두번째 역에서 내렸다. 나머지 인원은 전부 부산에서 내렸고 부산에서 내린 인원이 총 800명 일 때, 처음 탄 인원은 몇 명인지 구하시오.",
        "question_en": "There is a train from Seoul to Busan. 300 people more than two-fifths of the first boarded people got off at the first station, and 200 people less than one-half of the remaining people got off at the second station. All the rest of the people got off at Busan. If the number of people who got off at Busan is 800 in total, how many people were on board in the beginning?",
        "answer_ko": "2500",
        "answer_en": "2500",
        "solution_abst_ko": "800 200 [OP_SUB] 1 1/2 [OP_SUB] [OP_DIV] 300 [OP_ADD] 1 2/5 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "800 200 [OP_SUB] 1 1/2 [OP_SUB] [OP_DIV] 300 [OP_ADD] 1 2/5 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 800\nvar_b = 200\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = 0.5\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 300\nvar_i = var_g + var_h\nvar_j = 1\nvar_k = 0.4\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 800\nvar_b = 200\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = 0.5\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 300\nvar_i = var_g + var_h\nvar_j = 1\nvar_k = 0.4\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nprint(int(var_m))"
    },
    "2526": {
        "category": "Geometry",
        "question_ko": "21개의 모서리로 이루어진 각기둥이 있습니다. 이 각기둥의 윗면을 그대로 바닥으로 내렸을 때 밑면과 정확히 포개어진다면, 이 각기둥의 꼭짓점은 몇 개입니까?",
        "question_en": "There is a prism with 21 corners. If the top of this prism overlaps exactly with the bottom when it is lowered to the floor, how many vertices does this prism have?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "21 3 [OP_DIV] 2 [OP_MUL]",
        "solution_abst_en": "21 3 [OP_DIV] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 21\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 21\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "2527": {
        "category": "Geometry",
        "question_ko": "평행사변형 ㄱㄴㄷㄹ의 네 변의 길이의 합은 14 센티미터(㎝)입니다. 변 ㄱㄹ의 길이가 5 센티미터(㎝)일 때, 변 ㄱㄴ의 길이는 몇 센티미터(㎝)일까요?",
        "question_en": "The sum of the lengths of the four sides of a parallelogram ABCD is 14 centimeters (cm). If the length of side AD is 5 centimeters (cm), how many centimeters (cm) is the length of side AB?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "14 2 [OP_DIV] 5 [OP_SUB]",
        "solution_abst_en": "14 2 [OP_DIV] 5 [OP_SUB]",
        "solution_code_ko": "var_a = 14\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 5\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 14\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 5\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "2528": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 2575미터(m)인 도로의 양쪽에 25미터(m) 간격으로 가로수를 심으려고 합니다. 도로 양쪽에 심을 가로수는 몇 그루입니까? (단, 도로의 처음과 끝에도 가로수를 심습니다.)",
        "question_en": "You want to plant street trees at intervals of 25 meters (m) on both sides of a road that is 2575 meters (m) long. How many street trees will be planted on both sides of the road? (However, trees are also planted at the beginning and end of the road.)",
        "answer_ko": "208",
        "answer_en": "208",
        "solution_abst_ko": "2575 25 [OP_DIV] 1 [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "2575 25 [OP_DIV] 1 [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 2575\nvar_b = 25\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 2575\nvar_b = 25\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "2529": {
        "category": "Arithmetic calculation",
        "question_ko": "350원짜리 껌 한 개와 500원짜리 각도기 한 개를 사고 1000원을 냈습니다. 받아야 할 거스름돈은 얼마입니까?",
        "question_en": "I bought a piece of gum for 350 won and a protractor for 500 won and paid 1,000 won. How much change should I get?",
        "answer_ko": "150",
        "answer_en": "150",
        "solution_abst_ko": "1000 350 [OP_SUB] 500 [OP_SUB]",
        "solution_abst_en": "1000 350 [OP_SUB] 500 [OP_SUB]",
        "solution_code_ko": "var_a = 1000\nvar_b = 350\nvar_c = var_a - var_b\nvar_d = 500\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 1000\nvar_b = 350\nvar_c = var_a - var_b\nvar_d = 500\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "2530": {
        "category": "Arithmetic calculation",
        "question_ko": "연속된 짝수 3개의 합이 1194일 때, 가장 큰 짝수는 얼마입니까?",
        "question_en": "If the sum of three consecutive even numbers is 1194, what is the largest even number?",
        "answer_ko": "400",
        "answer_en": "400",
        "solution_abst_ko": "1194 0 3 1 [OP_SUB] 2 [OP_MUL] 2 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 3 [OP_DIV] 3 1 [OP_SUB] 2 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "1194 0 3 1 [OP_SUB] 2 [OP_MUL] 2 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 3 [OP_DIV] 3 1 [OP_SUB] 2 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 1194\nvar_b = 0\nvar_c = 3\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = 2\nlist_a = [i for i in range(var_b, var_g + 1, var_h)]\nlist_a = [float(i) for i in list_a]\nvar_i = sum(list_a)\nvar_j = var_a - var_i\nvar_k = 3\nvar_l = var_j / var_k\nvar_m = 3\nvar_n = 1\nvar_o = var_m - var_n\nvar_p = 2\nvar_q = var_o * var_p\nvar_r = var_l + var_q\nprint(int(var_r))",
        "solution_code_en": "var_a = 1194\nvar_b = 0\nvar_c = 3\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = 2\nlist_a = [i for i in range(var_b, var_g + 1, var_h)]\nlist_a = [float(i) for i in list_a]\nvar_i = sum(list_a)\nvar_j = var_a - var_i\nvar_k = 3\nvar_l = var_j / var_k\nvar_m = 3\nvar_n = 1\nvar_o = var_m - var_n\nvar_p = 2\nvar_q = var_o * var_p\nvar_r = var_l + var_q\nprint(int(var_r))"
    },
    "2531": {
        "category": "Possibility",
        "question_ko": "80보다 작은 수 중에서 9의 배수는 모두 몇 개일까요?",
        "question_en": "How many multiples of 9 are there less than 80?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "1 80 1 [OP_SUB] 1 [OP_LIST_ARANGE] 9 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "1 80 1 [OP_SUB] 1 [OP_LIST_ARANGE] 9 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 80\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nvar_f = 9\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 80\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nvar_f = 9\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "2532": {
        "category": "Correspondence",
        "question_ko": "서로 다른 네 수 A, B, C, D가 있습니다. 네 자리 수와 세 자리 수의 뺄셈식 AB82-9C9=493D에서 A를 구하시오.",
        "question_en": "There are four different numbers A, B, C, and D. Find A from the four-digit and three-digit subtraction equation AB82-9C9=493D.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "AB82-9C9=493D A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "AB82-9C9=493D A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'AB82-9C9=493D'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'AB82-9C9=493D'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "2533": {
        "category": "Comparison",
        "question_ko": "유정이가 책상 위에 여러가지 색깔의 공을 한 줄로 놓았습니다. 빨간색, 파란색, 노란색, 보라색, 흰색 공을 차례로 놓았을 때, 첫 번째 공의 색깔은 무엇입니까?",
        "question_en": "Yoojung placed balls of various colors in a row on the desk. If she put the ball in an order of red, blue, yellow, purple, and white, what color is the first ball?",
        "answer_ko": "빨간색",
        "answer_en": "red",
        "solution_abst_ko": "[OP_LIST_SOL] 빨간색 파란색 노란색 보라색 흰색 [OP_LIST_EOL] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] red blue yellow purple white [OP_LIST_EOL] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '빨간색'\nvar_b = '파란색'\nvar_c = '노란색'\nvar_d = '보라색'\nvar_e = '흰색'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nvar_g = list_a[var_f-1]\nprint(var_g)",
        "solution_code_en": "var_a = 'red'\nvar_b = 'blue'\nvar_c = 'yellow'\nvar_d = 'purple'\nvar_e = 'white'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nvar_g = list_a[var_f-1]\nprint(var_g)"
    },
    "2534": {
        "category": "Comparison",
        "question_ko": "1개의 무게가 3그램(g)인 보라색 구슬을 50개씩 담은 상자가 10개 있습니다. 1개의 무게가 2.5그램(g)인 분홍색 구슬을 60개씩 담은 상자가 9개 있습니다. 색깔별 구슬 전체의 무게가 더 무거운 것은 무슨 색 구슬입니까?",
        "question_en": "There are 10 boxes of 50 purple marbles each weighing 3 grams (g). There are 9 boxes of 60 pink marbles each weighing 2.5 grams (g). Which color marble weighs more when the total marbles of each color were weighed?",
        "answer_ko": "보라색",
        "answer_en": "purple",
        "solution_abst_ko": "[OP_LIST_SOL] 보라색 분홍색 [OP_LIST_EOL] [OP_LIST_SOL] 3 50 10 [OP_MUL] [OP_MUL] 2.5 60 9 [OP_MUL] [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] purple pink [OP_LIST_EOL] [OP_LIST_SOL] 3 50 10 [OP_MUL] [OP_MUL] 2.5 60 9 [OP_MUL] [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '보라색'\nvar_b = '분홍색'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nvar_d = 50\nvar_e = 10\nvar_f = var_d * var_e\nvar_g = var_c * var_f\nvar_h = 2.5\nvar_i = 60\nvar_j = 9\nvar_k = var_i * var_j\nvar_l = var_h * var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'purple'\nvar_b = 'pink'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nvar_d = 50\nvar_e = 10\nvar_f = var_d * var_e\nvar_g = var_c * var_f\nvar_h = 2.5\nvar_i = 60\nvar_j = 9\nvar_k = var_i * var_j\nvar_l = var_h * var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "2535": {
        "category": "Comparison",
        "question_ko": "마트에서 지민, 정국, 태형이가 차례대로 줄을 섰습니다. 지민이가 2번째일 때, 태형이는 몇 번째 입니까?",
        "question_en": "At the supermarket, Jimin, Jungkook, and Taehyung lined up one after another. When Jimin is the second one, what number is Taehyung?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "2 [OP_LIST_SOL] 지민 정국 태형 [OP_LIST_EOL] 태형 [OP_LIST_INDEX] 지민 [OP_LIST_INDEX] [OP_SUB] [OP_ADD]",
        "solution_abst_en": "2 [OP_LIST_SOL] Jimin Jungkook Taehyung [OP_LIST_EOL] Taehyung [OP_LIST_INDEX] Jimin [OP_LIST_INDEX] [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = '지민'\nvar_c = '정국'\nvar_d = '태형'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nlist_a.reverse()\nvar_e = '태형'\nvar_f = list_a.index(var_e)+1\nvar_g = '지민'\nvar_h = list_a.index(var_g)+1\nvar_i = var_f - var_h\nvar_j = var_a + var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 2\nvar_b = 'Jimin'\nvar_c = 'Jungkook'\nvar_d = 'Taehyung'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nlist_a.reverse()\nvar_e = 'Taehyung'\nvar_f = list_a.index(var_e)+1\nvar_g = 'Jimin'\nvar_h = list_a.index(var_g)+1\nvar_i = var_f - var_h\nvar_j = var_a + var_i\nprint(int(var_j))"
    },
    "2536": {
        "category": "Arithmetic calculation",
        "question_ko": "(가) 바구니에는 사탕이 8개, (나) 바구니에는 17개 있습니다. 두 바구니에 담긴 사탕의 개수를 같게 하려면 (가) 바구니에 몇 개의 사탕을 더 놓아야하는지 구하시오.",
        "question_en": "There are 8 candies in basket (A) and 17 candies in basket (B). Find how many more candies must be placed in basket (A) to make the number of candies in both baskets equal.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "17 8 [OP_SUB]",
        "solution_abst_en": "17 8 [OP_SUB]",
        "solution_code_ko": "var_a = 17\nvar_b = 8\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 17\nvar_b = 8\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "2537": {
        "category": "Correspondence",
        "question_ko": "22는 어떤 수에서 48을 뺀 수입니다. 어떤 수보다 32작은 숫자는 얼마인가요.",
        "question_en": "22 is the result from a certain number minus 48. What is 32 less than the number?",
        "answer_ko": "38",
        "answer_en": "38",
        "solution_abst_ko": "22 48 [OP_ADD] 32 [OP_SUB]",
        "solution_abst_en": "22 48 [OP_ADD] 32 [OP_SUB]",
        "solution_code_ko": "var_a = 22\nvar_b = 48\nvar_c = var_a + var_b\nvar_d = 32\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 22\nvar_b = 48\nvar_c = var_a + var_b\nvar_d = 32\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "2538": {
        "category": "Comparison",
        "question_ko": "5와 8과 9와 7 중 가장 큰 숫자는 무엇인가요?",
        "question_en": "Among 5, 8, 9, and 7, which is the largest number?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "[OP_LIST_SOL] 5 8 9 7 [OP_LIST_EOL] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 5 8 9 7 [OP_LIST_EOL] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 5\nvar_b = 8\nvar_c = 9\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nprint(int(var_f))",
        "solution_code_en": "var_a = 5\nvar_b = 8\nvar_c = 9\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nprint(int(var_f))"
    },
    "2539": {
        "category": "Possibility",
        "question_ko": "윤기네 학교에서 학예회를 준비하고 있습니다. 8개의 반이 학예회 순서를 정해야 할때 가능한 경우는 모두 몇 가지입니까?",
        "question_en": "Yoongi's school is preparing for a school performance. How many possible cases are there when there are 8 classes to set the order of the school play?",
        "answer_ko": "40320",
        "answer_en": "40320",
        "solution_abst_ko": "8 8 [OP_PERM]",
        "solution_abst_en": "8 8 [OP_PERM]",
        "solution_code_ko": "var_a = 8\nvar_b = 8\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))",
        "solution_code_en": "var_a = 8\nvar_b = 8\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))"
    },
    "2540": {
        "category": "Arithmetic calculation",
        "question_ko": "대형 마트에서 새벽에 진열한 과자를 오전에 3/5만큼 팔았습니다. 오후에는 오전에 팔고 남은 과자와 새로 진열한 과자를 합한 180개의 과자를 모두 팔았습니다. 오전에 판 과자와 오후에 판 과자의 수가 같았다면, 새벽에 진열한 과자는 몇 개입니까?",
        "question_en": "At a large market, in the morning, I sold 3/5 of the snacks that were displayed at dawn. In the afternoon, 180 snacks  in total were sold, including those left from the morning and newly displayed snacks. If the number of snacks sold in the morning and the snack sold in the afternoon was the same, how many snacks were displayed at dawn?",
        "answer_ko": "300",
        "answer_en": "300",
        "solution_abst_ko": "180 3/5 [OP_DIV]",
        "solution_abst_en": "180 3/5 [OP_DIV]",
        "solution_code_ko": "var_a = 180\nvar_b = 0.6\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 180\nvar_b = 0.6\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "2541": {
        "category": "Correspondence",
        "question_ko": "170을 어떤 수로 나누면 나머지가 8이고 120을 어떤 수로 나누면 나머지가 12이며 268에 2를 더하면 어떤 수로 나누어 떨어진다. 가능한 어떤 수 중 가장 큰 값을 구하시오.",
        "question_en": "When 170 is divided by a number, the remainder is 8. When 120 is divided by the number, the remainder is 12. When 268 is added by 2, it is divisible by the number. Among the numbers that are possible, find the largest value.",
        "answer_ko": "54",
        "answer_en": "54",
        "solution_abst_ko": "170 8 [OP_SUB] 268 2 [OP_ADD] [OP_GCD] 120 12 [OP_SUB] [OP_GCD]",
        "solution_abst_en": "170 8 [OP_SUB] 268 2 [OP_ADD] [OP_GCD] 120 12 [OP_SUB] [OP_GCD]",
        "solution_code_ko": "var_a = 170\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 268\nvar_e = 2\nvar_f = var_d + var_e\nvar_g = math.gcd(int(var_f), int(var_c))\nvar_h = 120\nvar_i = 12\nvar_j = var_h - var_i\nvar_k = math.gcd(int(var_j), int(var_g))\nprint(int(var_k))",
        "solution_code_en": "var_a = 170\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 268\nvar_e = 2\nvar_f = var_d + var_e\nvar_g = math.gcd(int(var_f), int(var_c))\nvar_h = 120\nvar_i = 12\nvar_j = var_h - var_i\nvar_k = math.gcd(int(var_j), int(var_g))\nprint(int(var_k))"
    },
    "2542": {
        "category": "Geometry",
        "question_ko": "직육면체를 잘라서 정육면체를 만들려고 한다. 직육면체의 가로는 12센티미터(㎝), 세로는 16센티미터(㎝), 높이는 14센티미터(㎝) 일 때, 가장 큰 정육면체의 겉넓이의 값은?",
        "question_en": "You are trying to make a cube by cutting a cuboid. If the width of the cube is 12 centimeters (cm), the length is 16 centimeters (cm), and the height is 14 centimeters (cm), what is the value of the surface area of the largest cube?",
        "answer_ko": "864",
        "answer_en": "864",
        "solution_abst_ko": "[OP_LIST_SOL] 12 16 14 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_POW] 6 [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 12 16 14 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_POW] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 12\nvar_b = 16\nvar_c = 14\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nvar_f = 2\nvar_g = var_e ** var_f\nvar_h = 6\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 12\nvar_b = 16\nvar_c = 14\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nvar_f = 2\nvar_g = var_e ** var_f\nvar_h = 6\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "2543": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 10, 11, 12, 13이 있습니다. 그 중에서 가장 큰 수와 그 다음으로 큰 수의 합은 얼마입니까?",
        "question_en": "There are four numbers 10, 11, 12, and 13. What is the sum of the largest number and the next largest number?",
        "answer_ko": "25",
        "answer_en": "25",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = var_f + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = var_f + var_h\nprint(int(var_i))"
    },
    "2544": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 꽃집에서 새벽에 들여온 꽃을 오전에 3/5만큼 팔았습니다. 오후에는 오전에 팔고 남은 꽃과 새로 들여온 꽃을 합한 180 송이를 모두 팔았습니다. 오전에 판 꽃의 수와 오후에 판 꽃의 수가 같았다면, 새벽에 들여온 꽃은 몇 송이입니까?",
        "question_en": "A flower shop sold 3/5 of the flowers brought at dawn in the morning. In the afternoon, they sold all 180 flowers, including the remaining flowers after the morning and the newly brought flowers. If the number of flowers sold in the morning and the number of flowers sold in the afternoon were the same, how many flowers did they bring at dawn?",
        "answer_ko": "300",
        "answer_en": "300",
        "solution_abst_ko": "180 3/5 [OP_DIV]",
        "solution_abst_en": "180 3/5 [OP_DIV]",
        "solution_code_ko": "var_a = 180\nvar_b = 0.6\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 180\nvar_b = 0.6\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "2545": {
        "category": "Geometry",
        "question_ko": "한 변이 15센티미터(㎝)인 정오각형의 모든 변의 길이의 합은 몇 센티미터(㎝)입니까?",
        "question_en": "What is the sum of all the sides of a regular pentagon with a side of 15 centimeters (cm) in centimeters (cm)?",
        "answer_ko": "75",
        "answer_en": "75",
        "solution_abst_ko": "15 5 [OP_MUL]",
        "solution_abst_en": "15 5 [OP_MUL]",
        "solution_code_ko": "var_a = 15\nvar_b = 5\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 15\nvar_b = 5\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "2546": {
        "category": "Arithmetic calculation",
        "question_ko": "경린이의 한 뼘의 길이는 약 12센티미터(㎝)입니다. 경린이가 공책의 긴 쪽의 길이를 재었더니 뼘으로 2번이었습니다. 공책의 긴 쪽의 길이는 약 몇 센티미터(㎝)입니까?",
        "question_en": "When Geongrin measured a span of his hand, it was 12 centimeters (cm) long. Gyeongrin measured the length of the long side of the notebook, and it was twice as long as the span. Approximately, how long is the long side of the notebook in centimeters (cm)?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "12 2 [OP_MUL]",
        "solution_abst_en": "12 2 [OP_MUL]",
        "solution_code_ko": "var_a = 12\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 12\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "2547": {
        "category": "Geometry",
        "question_ko": "어떤 사다리꼴의 넓이가 100.62제곱센티미터(㎠)이며, 높이가 5.2센티미터(㎝)이고, 윗변이 아랫변보다 3.4센티미터(㎝) 더 길다고 합니다. 아랫변의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "A trapezoid has an area of 100.62 square centimeters (cm2), a height of 5.2 centimeters (cm), and the top side is 3.4 centimeters (cm) longer than the bottom side. How many centimeters (cm) is the length of the lower side?",
        "answer_ko": "17.65",
        "answer_en": "17.65",
        "solution_abst_ko": "100.62 2 [OP_MUL] 5.2 [OP_DIV] 3.4 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "100.62 2 [OP_MUL] 5.2 [OP_DIV] 3.4 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 100.62\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 5.2\nvar_e = var_c / var_d\nvar_f = 3.4\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 100.62\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 5.2\nvar_e = var_c / var_d\nvar_f = 3.4\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "2548": {
        "category": "Comparison",
        "question_ko": "은지네 반 학생들이 각 줄마다 학생 수가 같도록 3줄로 설 때, 은지는 어느 한 줄의 앞에서 3번째, 뒤에서 6번째에 섭니다. 은지네 반 학생은 총 몇 명인지 구하시오.",
        "question_en": "When Eunji's classmates stand in 3 lines with the same number of students in each line, Eunji stands at the 3rd from the front and the 6th from the back. Find the total number of students in Eunji's class.",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "3 6 [OP_ADD] 1 [OP_SUB] 3 [OP_MUL]",
        "solution_abst_en": "3 6 [OP_ADD] 1 [OP_SUB] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 3\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "2549": {
        "category": "Geometry",
        "question_ko": "사각형에 존재하는 모든 대각선의 개수는?",
        "question_en": "How many diagonals are there in the rectangle?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "4 4 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "4 4 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 4\nvar_b = 4\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 4\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "2550": {
        "category": "Arithmetic calculation",
        "question_ko": "규리는 어떤 일의 1/3을 하는 데 5일 걸리고, 승연이는 같은 일의 1/5을 하는 데 2일 걸립니다. 규리와 승연이가 함께 일을 한다면 일을 끝내는 데 며칠이 걸립니까?",
        "question_en": "Gyuri takes 5 days to do 1/3 of a job, and Seungyeon takes 2 days to do 1/5 of the same job. If Gyuri and Seungyeon work together, how many days will it take to finish the job?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "1 1/3 5 [OP_DIV] 1/5 2 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_abst_en": "1 1/3 5 [OP_DIV] 1/5 2 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 0.3333333333333333\nvar_c = 5\nvar_d = var_b / var_c\nvar_e = 0.2\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = var_a / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))",
        "solution_code_en": "var_a = 1\nvar_b = 0.3333333333333333\nvar_c = 5\nvar_d = var_b / var_c\nvar_e = 0.2\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = var_a / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))"
    },
    "2551": {
        "category": "Arithmetic calculation",
        "question_ko": "3/8, 0.125 총 2개의 숫자가 있습니다. 두 수의 차는?",
        "question_en": "There are 3/8 and 0.125. What is the difference between the two numbers?",
        "answer_ko": "0.25",
        "answer_en": "0.25",
        "solution_abst_ko": "3/8 0.125 [OP_SUB] [OP_ABS]",
        "solution_abst_en": "3/8 0.125 [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 0.375\nvar_b = 0.125\nvar_c = var_a - var_b\nvar_d = abs(var_c)\nprint('{:.2f}'.format(round(var_d+1e-10,2)))",
        "solution_code_en": "var_a = 0.375\nvar_b = 0.125\nvar_c = var_a - var_b\nvar_d = abs(var_c)\nprint('{:.2f}'.format(round(var_d+1e-10,2)))"
    },
    "2552": {
        "category": "Arithmetic calculation",
        "question_ko": "태형이와 남준이는 연필을 각각 10자루씩 샀습니다. 태형이는 그 중 몇 자루를 사용하고 남은 연필 중 3자루를 남준이에게 주었고, 남준이도 몇 자루를 사용하였더니 두 사람이 가지고 있는 연필은 각각 6자루가 되었습니다. 남준이가 사용한 연필은 몇 자루인지 구하시오.",
        "question_en": "Taehyung and Namjoon bought 10 pencils each. Taehyung used some of the pencils and gave 3 of the remaining pencils to Namjoon, and Namjoon also used a few, too. Than the two of them had 6 pencils each. Find how many pencils Namjoon used.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "10 6 3 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "10 6 3 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 6\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 6\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "2553": {
        "category": "Correspondence",
        "question_ko": "17을 6로 나누면 몫이 2, 나머지가 A가 됩니다. 이 때 A의 값을 구하시오.",
        "question_en": "Find A that satisfies the following condition: When 17 is divided by 6, the quotient is 2 and the remainder is A.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "17 6 2 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "17 6 2 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 17\nvar_b = 6\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 17\nvar_b = 6\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "2554": {
        "category": "Correspondence",
        "question_ko": "두 자리 수가 있습니다. 이 수는 6과 9로 나누어떨어지고, 7로 나누면 나머지가 1이 됩니다. 두 자리 수를 구하시오.",
        "question_en": "There is a two digit number. This number is divisible by 6 and 9, and when divided by 7, the remainder is 1. Find this two digit number.",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "10 100 1 [OP_LIST_ARANGE] 6 9 [OP_LCM] 0 [OP_LIST_DIVIDE_AND_REMAIN] 7 1 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "10 100 1 [OP_LIST_ARANGE] 6 9 [OP_LCM] 0 [OP_LIST_DIVIDE_AND_REMAIN] 7 1 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 10\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nvar_e = 9\nvar_f = var_e * var_d / math.gcd(int(var_e), int(var_d))\nvar_g = 0\nlist_b = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_a:\n    i = int(i)\n    if i%var_f == var_g:\n        list_b.append(i)\nvar_h = 7\nvar_i = 1\nlist_c = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_b:\n    i = int(i)\n    if i%var_h == var_i:\n        list_c.append(i)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(int(var_k))",
        "solution_code_en": "var_a = 10\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nvar_e = 9\nvar_f = var_e * var_d / math.gcd(int(var_e), int(var_d))\nvar_g = 0\nlist_b = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_a:\n    i = int(i)\n    if i%var_f == var_g:\n        list_b.append(i)\nvar_h = 7\nvar_i = 1\nlist_c = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_b:\n    i = int(i)\n    if i%var_h == var_i:\n        list_c.append(i)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(int(var_k))"
    },
    "2555": {
        "category": "Arithmetic calculation",
        "question_ko": "양팔 저울의 한쪽에는 동화책 한 권을 올려놓고, 다른 쪽에는 0.5킬로그램(㎏)짜리 추 한 개와 0.3킬로그램(㎏)짜리 추 2개를 올려놓았더니 수평이 되었습니다. 동화책 한 권의 무게는 몇 킬로그램(㎏)입니까?",
        "question_en": "A fairy tale book was placed on one side of the two-arm scale, and a 0.5 kilograms (kg) weight and two 0.3 kilograms (kg) weights were placed on the other side, and it was level. How many kilograms (kg) does one children's book weigh?",
        "answer_ko": "1.10",
        "answer_en": "1.1",
        "solution_abst_ko": "0.5 0.3 2 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "0.5 0.3 2 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 0.5\nvar_b = 0.3\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.5\nvar_b = 0.3\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "2556": {
        "category": "Comparison",
        "question_ko": "진아와 정열이는 가수이다. 진아는 1주일 동안 140시간을 노래했고, 정열이는 2일동안 48시간동안 노래를 했다. 하루에 누가 더 노래를 많이 불렀는가?",
        "question_en": "Jina and Jeongyeol are singers. Jina sang for 140 hours in one week, and Jeongyeol sang for 48 hours in two days. Who sang more in one day?",
        "answer_ko": "정열",
        "answer_en": "Jeongyeol",
        "solution_abst_ko": "[OP_LIST_SOL] 진아 정열 [OP_LIST_EOL] [OP_LIST_SOL] 140 1 7 [OP_MUL] [OP_DIV] 48 2 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jina Jeongyeol [OP_LIST_EOL] [OP_LIST_SOL] 140 1 7 [OP_MUL] [OP_DIV] 48 2 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '진아'\nvar_b = '정열'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 140\nvar_d = 1\nvar_e = 7\nvar_f = var_d * var_e\nvar_g = var_c / var_f\nvar_h = 48\nvar_i = 2\nvar_j = var_h / var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'Jina'\nvar_b = 'Jeongyeol'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 140\nvar_d = 1\nvar_e = 7\nvar_f = var_d * var_e\nvar_g = var_c / var_f\nvar_h = 48\nvar_i = 2\nvar_j = var_h / var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "2557": {
        "category": "Arithmetic calculation",
        "question_ko": "지민이네 반에서 국어를 좋아하는 사람 중 수학도 좋아하는 사람은 32명입니다. 국어를 좋아하는 학생은 38명이고 수학을 좋아하는 학생은 39명이고 모든 학생이 최소 둘 중 하나는 좋아한다고 합니다. 지민이네 반 학생은 모두 몇 명입니까?",
        "question_en": "Among the people in Jimin's class who like Korean, 32 people also like math. There are 38 students who like Korean and 39 students who like math, and all students say they like at least one of the two. How many students are there in Jimin's class?",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "38 39 [OP_ADD] 32 [OP_SUB]",
        "solution_abst_en": "38 39 [OP_ADD] 32 [OP_SUB]",
        "solution_code_ko": "var_a = 38\nvar_b = 39\nvar_c = var_a + var_b\nvar_d = 32\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 38\nvar_b = 39\nvar_c = var_a + var_b\nvar_d = 32\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "2558": {
        "category": "Comparison",
        "question_ko": "A는 32에서 7 더한 수, B는 10개씩 3묶음과 낱개 3개를 더한 수, C는 50에서 9를 뺀 수이다. A, B, C 세 수 중에서 가장 작은 수는 무엇인가?",
        "question_en": "A is 32 plus 7, B is 3 groups of 10 each plus 3 individual pieces, and C is 50 minus 9. Which of the three numbers A, B, and C is the smallest?",
        "answer_ko": "B",
        "answer_en": "B",
        "solution_abst_ko": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] 32 7 [OP_ADD] 3 10 [OP_MUL] 3 [OP_ADD] 50 9 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] 32 7 [OP_ADD] 3 10 [OP_MUL] 3 [OP_ADD] 50 9 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 32\nvar_e = 7\nvar_f = var_d + var_e\nvar_g = 3\nvar_h = 10\nvar_i = var_g * var_h\nvar_j = 3\nvar_k = var_i + var_j\nvar_l = 50\nvar_m = 9\nvar_n = var_l - var_m\nlist_b= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_o = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_p = list_c[var_o-1]\nvar_q = list_b.index(var_p)+1\nvar_r = list_a[var_q-1]\nprint(var_r)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 32\nvar_e = 7\nvar_f = var_d + var_e\nvar_g = 3\nvar_h = 10\nvar_i = var_g * var_h\nvar_j = 3\nvar_k = var_i + var_j\nvar_l = 50\nvar_m = 9\nvar_n = var_l - var_m\nlist_b= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_o = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_p = list_c[var_o-1]\nvar_q = list_b.index(var_p)+1\nvar_r = list_a[var_q-1]\nprint(var_r)"
    },
    "2559": {
        "category": "Arithmetic calculation",
        "question_ko": "연속하는 8개의 짝수를 더하였더니 424가 되었습니다. 8개의 짝수 중 마지막 수를 구하시오.",
        "question_en": "Adding 8 consecutive even numbers gives 424. Find the last number out of 8 even numbers.",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "424 0 8 1 [OP_SUB] 2 [OP_MUL] 2 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 8 [OP_DIV] 8 1 [OP_SUB] 2 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "424 0 8 1 [OP_SUB] 2 [OP_MUL] 2 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 8 [OP_DIV] 8 1 [OP_SUB] 2 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 424\nvar_b = 0\nvar_c = 8\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = 2\nlist_a = [i for i in range(var_b, var_g + 1, var_h)]\nlist_a = [float(i) for i in list_a]\nvar_i = sum(list_a)\nvar_j = var_a - var_i\nvar_k = 8\nvar_l = var_j / var_k\nvar_m = 8\nvar_n = 1\nvar_o = var_m - var_n\nvar_p = 2\nvar_q = var_o * var_p\nvar_r = var_l + var_q\nprint(int(var_r))",
        "solution_code_en": "var_a = 424\nvar_b = 0\nvar_c = 8\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = 2\nlist_a = [i for i in range(var_b, var_g + 1, var_h)]\nlist_a = [float(i) for i in list_a]\nvar_i = sum(list_a)\nvar_j = var_a - var_i\nvar_k = 8\nvar_l = var_j / var_k\nvar_m = 8\nvar_n = 1\nvar_o = var_m - var_n\nvar_p = 2\nvar_q = var_o * var_p\nvar_r = var_l + var_q\nprint(int(var_r))"
    },
    "2560": {
        "category": "Correspondence",
        "question_ko": "어떤 수는 5와 7의 곱입니다. 어떤 수에서 12를 더하고 8을 더하면 얼마인지 구하시오.",
        "question_en": "A number is the product of 5 and 7. What is the numbber added by 12 added by 8?",
        "answer_ko": "55",
        "answer_en": "55",
        "solution_abst_ko": "5 7 [OP_MUL] 12 [OP_ADD] 8 [OP_ADD]",
        "solution_abst_en": "5 7 [OP_MUL] 12 [OP_ADD] 8 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "2561": {
        "category": "Correspondence",
        "question_ko": "소수점 아래 2번째 자리까지 있는 어떤 소수가 있습니다. 이 수를 소수 2번째 자리에서 반올림하면 1.7이 됩니다. 이러한 소수 중 가장 큰 수에서 가장 작은 수를 뺀 값을 소수점을 포함하여 구하시오.",
        "question_en": "There are some decimals up to 2 places after the decimal point. Rounding this number to 2 decimal places gives 1.7. Find the largest of these decimals minus the smallest, including the decimal point.",
        "answer_ko": "0.09",
        "answer_en": "0.09",
        "solution_abst_ko": "1.74 1.65 [OP_SUB]",
        "solution_abst_en": "1.74 1.65 [OP_SUB]",
        "solution_code_ko": "var_a = 1.74\nvar_b = 1.65\nvar_c = var_a - var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 1.74\nvar_b = 1.65\nvar_c = var_a - var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "2562": {
        "category": "Correspondence",
        "question_ko": "6AB3을 반올림하여 천의 자리까지 나타내면 6000이 됩니다. 가능한 A 값들의 합을 구하시오",
        "question_en": "When 6AB3 is rounded to the thousandth, it. is 6000. Find the sum of the possible values of A.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "6AB3 [OP_GEN_POSSIBLE_LIST] 6000 500 [OP_SUB] [OP_LIST_MORE_EQUAL] 6000 500 [OP_ADD] [OP_LIST_LESS] 6AB3 A [OP_LIST_FIND_UNK] [OP_LIST_SUM]",
        "solution_abst_en": "6AB3 [OP_GEN_POSSIBLE_LIST] 6000 500 [OP_SUB] [OP_LIST_MORE_EQUAL] 6000 500 [OP_ADD] [OP_LIST_LESS] 6AB3 A [OP_LIST_FIND_UNK] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = '6AB3'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 6000\nvar_c = 500\nvar_d = var_b - var_c\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nvar_e = 6000\nvar_f = 500\nvar_g = var_e + var_f\nlist_c = []\nfor i in list_b:\n    if i < var_g:\n        list_c.append(i)\nvar_h = '6AB3'\nvar_i = 'A'\nvar_h = str(var_h)\nvar_i = str(var_i)\nunk_idx = var_h.index(var_i)\nlist_d = []\nfor elem in list_c:\n    elem = str(elem)\n    list_d.append(int(elem[unk_idx]))\nlist_d = list(set(list_d))\nlist_d = [float(i) for i in list_d]\nvar_j = sum(list_d)\nprint(int(var_j))",
        "solution_code_en": "var_a = '6AB3'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 6000\nvar_c = 500\nvar_d = var_b - var_c\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nvar_e = 6000\nvar_f = 500\nvar_g = var_e + var_f\nlist_c = []\nfor i in list_b:\n    if i < var_g:\n        list_c.append(i)\nvar_h = '6AB3'\nvar_i = 'A'\nvar_h = str(var_h)\nvar_i = str(var_i)\nunk_idx = var_h.index(var_i)\nlist_d = []\nfor elem in list_c:\n    elem = str(elem)\n    list_d.append(int(elem[unk_idx]))\nlist_d = list(set(list_d))\nlist_d = [float(i) for i in list_d]\nvar_j = sum(list_d)\nprint(int(var_j))"
    },
    "2563": {
        "category": "Geometry",
        "question_ko": "숫자 카드 2장이 있다. 하나는 15가 적혀져 있고, 다른 하나는 처음 카드에 적힌 수에 0.9를 곱한 수가 쓰여 있다. 이 두 카드에 적힌 수를 각각 가로와 세로로 하는 직사각형의 넓이를 구하라.",
        "question_en": "There are 2 number cards. One has 15 written on it, and the other has the value of number on the first card multiplied by 0.9. Find the area of the rectangle whose length and width are the same numbers on these two cards.",
        "answer_ko": "202.50",
        "answer_en": "202.5",
        "solution_abst_ko": "15 15 0.9 [OP_MUL] [OP_MUL]",
        "solution_abst_en": "15 15 0.9 [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 15\nvar_b = 15\nvar_c = 0.9\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 15\nvar_b = 15\nvar_c = 0.9\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "2564": {
        "category": "Arithmetic calculation",
        "question_ko": "은비, 재연, 주은이는 각자의 물병을 가지고 있고, 그 안에는 물이 담겨 있습니다. 세 친구의 물병 속에 담겨 있는 물의 양의 합은 1리터(L) 200밀리리터(㎖)입니다. 주은이가 재연이에게 물 200밀리리터(㎖)를 주고, 은비에게는 물 100밀리리터(㎖)를 줬더니 세 친구가 가진 물의 양이 같아졌다면, 은비의 물병에 처음 담겨 있던 물의 양을 구하시오.",
        "question_en": "Eunbi, Jaeyeon, and Jooeun each have their own water bottles with water in them. The sum of the water in the three friends' water bottles is 1 liter (L) and 200 milliliters (㎖). If Jooeun gave Jaeyeon 200 milliliters (ml) of water and Eunbi 100 milliliters (ml) of water, and the three friends have the same amount of water now, find the amount of water that Eunbi's water bottle initially contained.",
        "answer_ko": "300",
        "answer_en": "300",
        "solution_abst_ko": "1 1000 [OP_MUL] 200 [OP_ADD] 200 [OP_SUB] 100 [OP_SUB] 3 [OP_DIV]",
        "solution_abst_en": "1 1000 [OP_MUL] 200 [OP_ADD] 200 [OP_SUB] 100 [OP_SUB] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 200\nvar_e = var_c + var_d\nvar_f = 200\nvar_g = var_e - var_f\nvar_h = 100\nvar_i = var_g - var_h\nvar_j = 3\nvar_k = var_i / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 1\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 200\nvar_e = var_c + var_d\nvar_f = 200\nvar_g = var_e - var_f\nvar_h = 100\nvar_i = var_g - var_h\nvar_j = 3\nvar_k = var_i / var_j\nprint(int(var_k))"
    },
    "2565": {
        "category": "Geometry",
        "question_ko": "오면체의 면수를 모두 더하면 몇인가요?",
        "question_en": "What is the sum of the number of all the faces of a pentahedron?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "5",
        "solution_abst_en": "5",
        "solution_code_ko": "var_a = 5\nprint(int(var_a))",
        "solution_code_en": "var_a = 5\nprint(int(var_a))"
    },
    "2566": {
        "category": "Comparison",
        "question_ko": "윤기는 4, 정국이는 6에서 3을 나눈 몫 만큼 모았고, 유나는 5만큼 모았습니다. 누가 가장 큰 수를 모았습니까?",
        "question_en": "Yoongi collected 4, and Jungkook collected 6 divided by 3, and Yuna collected 5. Who collected the biggest number?",
        "answer_ko": "유나",
        "answer_en": "Yuna",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 유나 [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_FDIV] 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook Yuna [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_FDIV] 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nvar_c = '유나'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 6\nvar_f = 3\nvar_g = var_e // var_f\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nvar_c = 'Yuna'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 6\nvar_f = 3\nvar_g = var_e // var_f\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "2567": {
        "category": "Arithmetic calculation",
        "question_ko": "은지네 반 학생 중 10명의 키가 각각 145센티미터(㎝), 142센티미터(㎝), 138센티미터(㎝), 136센티미터(㎝), 143센티미터(㎝), 146센티미터(㎝), 138센티미터(㎝), 144센티미터(㎝), 137센티미터(㎝), 141센티미터(㎝)라고 합니다. 이 학생 10명의 평균 키는 몇 센티미터(㎝)입니까?",
        "question_en": "The heights of the 10 students in Eunji's class are 145 centimeters (cm), 142 centimeters (cm), 138 centimeters (cm), 136 centimeters (cm), 143 centimeters (cm), 146 centimeters (cm), 138 centimeters (cm), 144 centimeters (cm), 137 centimeters (cm), 141 centimeters (cm). What is the average height of these 10 students in centimeters (cm)?",
        "answer_ko": "141",
        "answer_en": "141",
        "solution_abst_ko": "[OP_LIST_SOL] 145 142 138 136 143 146 138 144 137 141 [OP_LIST_EOL] [OP_LIST_MEAN]",
        "solution_abst_en": "[OP_LIST_SOL] 145 142 138 136 143 146 138 144 137 141 [OP_LIST_EOL] [OP_LIST_MEAN]",
        "solution_code_ko": "var_a = 145\nvar_b = 142\nvar_c = 138\nvar_d = 136\nvar_e = 143\nvar_f = 146\nvar_g = 138\nvar_h = 144\nvar_i = 137\nvar_j = 141\nlist_a= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_a.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_k = sum(list_a)/len(list_a)\nprint(int(var_k))",
        "solution_code_en": "var_a = 145\nvar_b = 142\nvar_c = 138\nvar_d = 136\nvar_e = 143\nvar_f = 146\nvar_g = 138\nvar_h = 144\nvar_i = 137\nvar_j = 141\nlist_a= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_a.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_k = sum(list_a)/len(list_a)\nprint(int(var_k))"
    },
    "2568": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 1.33으로 나누었더니 48이 되었습니다. 어떤 수는 얼마인지 쓰시오.",
        "question_en": "When we divide a number by 1.33, we get 48. Write what is the number we divided.",
        "answer_ko": "63.84",
        "answer_en": "63.84",
        "solution_abst_ko": "48 1.33 [OP_MUL]",
        "solution_abst_en": "48 1.33 [OP_MUL]",
        "solution_code_ko": "var_a = 48\nvar_b = 1.33\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 48\nvar_b = 1.33\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "2569": {
        "category": "Geometry",
        "question_ko": "어떤 대각형 내부의 한 점에서 다른 꼭짓점으로 선을 그어 만들 수 있는 삼각형의 개수가 최대 20개일 때 이 다각형의 대각선은 몇 개인지 구하시오.",
        "question_en": "If the number of triangles that can be formed by drawing a line from one vertex to another inside a polygon is at most 20, find the number of diagonals of this polygon.",
        "answer_ko": "170",
        "answer_en": "170",
        "solution_abst_ko": "20 20 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "20 20 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 20\nvar_b = 20\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 20\nvar_b = 20\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "2570": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 29를 빼고 64를 더했더니 76이 되었습니다. 어떤 수를 구하시오.",
        "question_en": "I subtracted 29 from a particular number and added 64 and got 76 as a result. Find that particular number.",
        "answer_ko": "41",
        "answer_en": "41",
        "solution_abst_ko": "76 64 [OP_SUB] 29 [OP_ADD]",
        "solution_abst_en": "76 64 [OP_SUB] 29 [OP_ADD]",
        "solution_code_ko": "var_a = 76\nvar_b = 64\nvar_c = var_a - var_b\nvar_d = 29\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 76\nvar_b = 64\nvar_c = var_a - var_b\nvar_d = 29\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "2571": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 2센티미터(㎝)인 어떤 정팔면체가 있습니다. 이 정팔면체의 겉넓이는 몇 제곱센티미터(㎠)일까요?",
        "question_en": "There is a certain regular octahedron with a side length of 2 centimeters (cm). What is the surface area of this regular octahedron in square centimeters (cm2)?",
        "answer_ko": "13.86",
        "answer_en": "13.86",
        "solution_abst_ko": "3 1/2 [OP_POW] 2 [OP_DIV] 2 [OP_MUL] 2 [OP_MUL] 2 [OP_DIV] 8 [OP_MUL]",
        "solution_abst_en": "3 1/2 [OP_POW] 2 [OP_DIV] 2 [OP_MUL] 2 [OP_MUL] 2 [OP_DIV] 8 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 0.5\nvar_c = var_a ** var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = 2\nvar_k = var_i / var_j\nvar_l = 8\nvar_m = var_k * var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))",
        "solution_code_en": "var_a = 3\nvar_b = 0.5\nvar_c = var_a ** var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = 2\nvar_k = var_i / var_j\nvar_l = 8\nvar_m = var_k * var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))"
    },
    "2572": {
        "category": "Geometry",
        "question_ko": "세로가 9.4센티미터(㎝), 가로가 3.7센티미터(㎝)인 직사각형 모양의 포스트잇이 있습니다. 포스트잇의 뒷면의 윗부분에는 이를 붙였다 떼었다 할 수 있도록 하는 접착제가 있는데 이 부분의 길이가 0.6센티미터(㎝)라고 합니다. 접착제가 있는 부분만 다른 포스트잇에 닿도록 포스트잇 15장을 세로로 길게 연결했을 때의 넓이는 얼마입니까?",
        "question_en": "There is a rectangular-shaped post-it note with a length of 9.4 centimeters (cm) and a width of 3.7 centimeters (cm). There is an adhesive on the upper part of the back of the post-it note that allows it to be attached and detached, and this part is 0.6 centimeters (cm) long. What is the area of 15 post-it notes connected vertically so that only the adhesive part touches the other post-it notes?",
        "answer_ko": "490.62",
        "answer_en": "490.62",
        "solution_abst_ko": "9.4 15 [OP_MUL] 15 1 [OP_SUB] 0.6 [OP_MUL] [OP_SUB] 3.7 [OP_MUL]",
        "solution_abst_en": "9.4 15 [OP_MUL] 15 1 [OP_SUB] 0.6 [OP_MUL] [OP_SUB] 3.7 [OP_MUL]",
        "solution_code_ko": "var_a = 9.4\nvar_b = 15\nvar_c = var_a * var_b\nvar_d = 15\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 0.6\nvar_h = var_f * var_g\nvar_i = var_c - var_h\nvar_j = 3.7\nvar_k = var_i * var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 9.4\nvar_b = 15\nvar_c = var_a * var_b\nvar_d = 15\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 0.6\nvar_h = var_f * var_g\nvar_i = var_c - var_h\nvar_j = 3.7\nvar_k = var_i * var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "2573": {
        "category": "Arithmetic calculation",
        "question_ko": "5학년 중 농구 시합에 참가한 학생 수의 6배만큼 6학년 학생이 농구 시합에 참가하였습니다. 5학년 중 12명이 농구 시합에 참가하였다면 농구 시합에 참가한 5학년과 6학년 학생은 모두 몇 명입니까?",
        "question_en": "There are some 6th graders who participated in the basketball game, and the number is 6 times bigger than the number of 5th graders in the game. If there were 12 of 5th graders, what would be a total number of 5th and 6th grade students playing in the basketball game?",
        "answer_ko": "84",
        "answer_en": "84",
        "solution_abst_ko": "12 12 6 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "12 12 6 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 12\nvar_b = 12\nvar_c = 6\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 12\nvar_c = 6\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "2574": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 15를 곱하면 45가 됩니다. 호석이는 어떤 수에서 1을 빼고자 합니다. 호석이가 얻는 결과값은?",
        "question_en": "A number multiplied by 15 equals 45. Hoseok wants to subtract the number by 1. What is the result Hoseok will get?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "45 15 [OP_DIV] 1 [OP_SUB]",
        "solution_abst_en": "45 15 [OP_DIV] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 45\nvar_b = 15\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 45\nvar_b = 15\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "2575": {
        "category": "Comparison",
        "question_ko": "냉장고 안에 우유가 3/8리터(L), 사이다가 7/10리터(L), 오렌지주스가 11/15리터(L) 있습니다. 셋 중에서 양이 가장 많은 것을 구하시오.",
        "question_en": "There are 3/8 liters (L) of Milk, 7/10 liters (L) of Cider, and 11/15 liters (L) of Orange-Juice in the refrigerator. Find the one with the largest amount among the three.",
        "answer_ko": "오렌지주스",
        "answer_en": "Orange-Juice",
        "solution_abst_ko": "[OP_LIST_SOL] 우유 사이다 오렌지주스 [OP_LIST_EOL] [OP_LIST_SOL] 3/8 7/10 11/15 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Milk Cider Orange-Juice [OP_LIST_EOL] [OP_LIST_SOL] 3/8 7/10 11/15 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '우유'\nvar_b = '사이다'\nvar_c = '오렌지주스'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.375\nvar_e = 0.7\nvar_f = 0.7333333333333333\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Milk'\nvar_b = 'Cider'\nvar_c = 'Orange-Juice'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.375\nvar_e = 0.7\nvar_f = 0.7333333333333333\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "2576": {
        "category": "Comparison",
        "question_ko": "7/10, 3/2, 1.8, 3/5, 1.1이 있습니다. 이 중에서 1보다 큰 수를 고른다면 모두 몇 개입니까?",
        "question_en": "There are 7/10, 3/2, 1.8, 3/5, and 1.1. If you pick numbers greater than 1 from these, how many are there?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 7/10 3/2 1.8 3/5 1.1 [OP_LIST_EOL] 1 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 7/10 3/2 1.8 3/5 1.1 [OP_LIST_EOL] 1 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.7\nvar_b = 1.5\nvar_c = 1.8\nvar_d = 0.6\nvar_e = 1.1\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 0.7\nvar_b = 1.5\nvar_c = 1.8\nvar_d = 0.6\nvar_e = 1.1\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "2577": {
        "category": "Comparison",
        "question_ko": "5, 8, 4, 3, 7중에서 2번째로 큰 숫자를 선택합니다.",
        "question_en": "Choose the second largest number among 5, 8, 4, 3, and 7.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "[OP_LIST_SOL] 5 8 4 3 7 [OP_LIST_EOL] 2 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 5 8 4 3 7 [OP_LIST_EOL] 2 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 5\nvar_b = 8\nvar_c = 4\nvar_d = 3\nvar_e = 7\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 8\nvar_c = 4\nvar_d = 3\nvar_e = 7\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nprint(int(var_g))"
    },
    "2578": {
        "category": "Correspondence",
        "question_ko": "69.7제곱센티미터(㎠) 정사각형 모양의 종이가 있다. 가로, 세로를 각각 8등분 하여 나오는 작은 정사각형 1개의 면적을 구하시오.",
        "question_en": "There is a piece of paper in the shape of a square of 69.7 square centimeters (cm2). Find the area of one small square obtained by dividing the length and width into 8 equal parts.",
        "answer_ko": "1.09",
        "answer_en": "1.09",
        "solution_abst_ko": "69.76 8 [OP_DIV] 8 [OP_DIV]",
        "solution_abst_en": "69.76 8 [OP_DIV] 8 [OP_DIV]",
        "solution_code_ko": "var_a = 69.76\nvar_b = 8\nvar_c = var_a / var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 69.76\nvar_b = 8\nvar_c = var_a / var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "2579": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 국가고시의 통과자 20명의 평균은 42점이고 불합격자 20명의 평균은 38점이다. 전체 응시자 평균은 얼마인지 구하시오.",
        "question_en": "The average score of 20 successful candidates for a certain national examination is 42 points, and the average score of 20 candidates who did not pass the examination is 38 points. What is the average of all test takers?",
        "answer_ko": "40",
        "answer_en": "40",
        "solution_abst_ko": "20 42 [OP_MUL] 20 38 [OP_MUL] [OP_ADD] 20 20 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "20 42 [OP_MUL] 20 38 [OP_MUL] [OP_ADD] 20 20 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 20\nvar_b = 42\nvar_c = var_a * var_b\nvar_d = 20\nvar_e = 38\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 20\nvar_i = 20\nvar_j = var_h + var_i\nvar_k = var_g / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 20\nvar_b = 42\nvar_c = var_a * var_b\nvar_d = 20\nvar_e = 38\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 20\nvar_i = 20\nvar_j = var_h + var_i\nvar_k = var_g / var_j\nprint(int(var_k))"
    },
    "2580": {
        "category": "Comparison",
        "question_ko": "마트에서 경품을 추첨하여 남준이는 2등을 했고, 윤기는 4등을 했습니다. 호석이는 윤기보다 높지만 남준이보다 낮습니다. 호석이는 몇 등입니까?",
        "question_en": "In the prize draw at the mart, Namjoon won 2nd place and Yoongi won 4th place. Hoseok is higher than Yoongi, but lower than Namjoon. What is the rank of Hoseok?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "2 4 [OP_ADD] 2 [OP_FDIV]",
        "solution_abst_en": "2 4 [OP_ADD] 2 [OP_FDIV]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "2581": {
        "category": "Geometry",
        "question_ko": "대각선의 길이가 12센티미터(㎝)인 정사각형의 넓이를 구하시오.",
        "question_en": "If the diagonal of square is 12 centimeters (cm), what is the area of this square?",
        "answer_ko": "72",
        "answer_en": "72",
        "solution_abst_ko": "12 2 [OP_POW] 2 [OP_DIV]",
        "solution_abst_en": "12 2 [OP_POW] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "2582": {
        "category": "Arithmetic calculation",
        "question_ko": "지윤이는 암산 연습을 하고 있다. 친구가 앞에서 부른 수들을 모두 더한 값을 말해야 한다. 친구는 36, 17, 32, 54, 28, 3을 불렀다. 지윤이는 어떤 값을 말해야 하는가?",
        "question_en": "Jiyoon is practicing mental arithmetic. She must say the sum of all the numbers that her friend called earlier. Her friend called 36, 17, 32, 54, 28, 3. What value should Jiyoon say?",
        "answer_ko": "170",
        "answer_en": "170",
        "solution_abst_ko": "[OP_LIST_SOL] 36 17 32 54 28 3 [OP_LIST_EOL] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 36 17 32 54 28 3 [OP_LIST_EOL] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 36\nvar_b = 17\nvar_c = 32\nvar_d = 54\nvar_e = 28\nvar_f = 3\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_g = sum(list_a)\nprint(int(var_g))",
        "solution_code_en": "var_a = 36\nvar_b = 17\nvar_c = 32\nvar_d = 54\nvar_e = 28\nvar_f = 3\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_g = sum(list_a)\nprint(int(var_g))"
    },
    "2583": {
        "category": "Comparison",
        "question_ko": "어제 원희는 10과 9/10 시간을 자고, 동일이는 102/10 시간을 잤습니다. 누가 더 오래 잤는지 답을 구하세요.",
        "question_en": "Yesterday, Wonhee slept 10 and 9/10 hours, and Dongil slept 102/10 hours. Find out who slept longer.",
        "answer_ko": "원희",
        "answer_en": "Wonhee",
        "solution_abst_ko": "[OP_LIST_SOL] 원희 동일 [OP_LIST_EOL] [OP_LIST_SOL] 10 9/10 [OP_ADD] 102/10 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Wonhee Dongil [OP_LIST_EOL] [OP_LIST_SOL] 10 9/10 [OP_ADD] 102/10 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '원희'\nvar_b = '동일'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10\nvar_d = 0.9\nvar_e = var_c + var_d\nvar_f = 10.2\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Wonhee'\nvar_b = 'Dongil'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10\nvar_d = 0.9\nvar_e = var_c + var_d\nvar_f = 10.2\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "2584": {
        "category": "Correspondence",
        "question_ko": "철사를 한 도막에 7센티미터(㎝)씩 잘랐더니 12도막이 되고, 4센티미터(㎝)가 남았습니다. 이 철사를 3센티미터(㎝)씩 자르면 몇 도막이 되고, 1센티미터(㎝)가 남습니까?",
        "question_en": "When I cut 7 centimeters (cm) of wire into each piece, it became 12 pieces, leaving 4 centimeters (cm). If you cut this wire by 3 centimeters (cm), how many pieces will there be, leaving 1 centimeter (cm)?",
        "answer_ko": "29",
        "answer_en": "29",
        "solution_abst_ko": "7 12 [OP_MUL] 4 [OP_ADD] 3 [OP_FDIV]",
        "solution_abst_en": "7 12 [OP_MUL] 4 [OP_ADD] 3 [OP_FDIV]",
        "solution_code_ko": "var_a = 7\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e // var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 7\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e // var_f\nprint(int(var_g))"
    },
    "2585": {
        "category": "Correspondence",
        "question_ko": "18을 3으로 나누고 다시 3으로 나눈다면 얼마가 되는지 구하시오.",
        "question_en": "If you divide 18 by 3 and divide it by 3 again, what is the result?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "18 3 [OP_DIV] 3 [OP_DIV]",
        "solution_abst_en": "18 3 [OP_DIV] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 18\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 18\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "2586": {
        "category": "Arithmetic calculation",
        "question_ko": "50.5센티미터(㎝)의 색 테이프를 18센티미터(㎝) 색테이프 3개를 겹쳐서 이어 붙여 만들었습니다. 몇 센티미터(㎝)씩 겹쳐서 이어 붙였나요?",
        "question_en": "A 50.5 centimeters (cm) long color tape was made by overlapping and attaching three 18 centimeters (cm) color tapes. How many centimeters (cm) did you overlap and attach each?",
        "answer_ko": "1.75",
        "answer_en": "1.75",
        "solution_abst_ko": "18 3 [OP_MUL] 50.5 [OP_SUB] 3 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "18 3 [OP_MUL] 50.5 [OP_SUB] 3 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 18\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 50.5\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 18\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 50.5\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "2587": {
        "category": "Geometry",
        "question_ko": "윗변이 아랫변보다 3.6센티미터(㎝) 더 길고, 높이가 5.2센티미터(㎝)인 사다리꼴의 넓이가 96.9제곱센티미터(㎠)입니다. 아랫변은 몇 센티미터(㎝)입니까?",
        "question_en": "A trapezoid with an upper side 3.6 centimeters (cm) longer than a lower side and with a height of 5.2 centimeters (cm) has an area of 96.9 square cm (cm2). How many centimeters (cm) is the lower side?",
        "answer_ko": "16.85",
        "answer_en": "16.85",
        "solution_abst_ko": "96.98 2 [OP_MUL] 5.2 [OP_DIV] 3.6 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "96.98 2 [OP_MUL] 5.2 [OP_DIV] 3.6 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 96.98\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 5.2\nvar_e = var_c / var_d\nvar_f = 3.6\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 96.98\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 5.2\nvar_e = var_c / var_d\nvar_f = 3.6\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "2588": {
        "category": "Arithmetic calculation",
        "question_ko": "딸기맛 사탕과 포도맛 사탕이 합하여 240개가 있습니다. 포도맛 사탕의 개수가 딸기맛 사탕의 개수보다 2개가 적다면 딸기맛 사탕의 개수는 몇 개인가요?",
        "question_en": "There are 240 candies of strawberry and grape flavors in total. If the number of grape-flavored candies is 2 less than the number of strawberry-flavored candies, how many strawberry-flavored candies are there?",
        "answer_ko": "121",
        "answer_en": "121",
        "solution_abst_ko": "240 2 [OP_SUB] 2 [OP_DIV] 2 [OP_ADD]",
        "solution_abst_en": "240 2 [OP_SUB] 2 [OP_DIV] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 240\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 240\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "2589": {
        "category": "Arithmetic calculation",
        "question_ko": "두 자리 수 짝수를 나열했을 때 4는 몇 번 등장하는지 구하시오.",
        "question_en": "Find how many times 4 appears when you list two-digit numbers that are even.",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "11 99 [OP_LIST_EVEN] [OP_LIST2NUM] [OP_NUM2LIST] 4 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "11 99 [OP_LIST_EVEN] [OP_LIST2NUM] [OP_NUM2LIST] 4 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 11\nvar_b = 99\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c=\"\"\nfor i in list_a:\n    i = str(i)\n    var_c = var_c + i\nlist_b = []\nvar_c = int(var_c)\nwhile var_c//10 > 0:\n    list_b.append(var_c%10)\n    var_c = var_c//10\nlist_b.append(var_c%10)\nlist_b = list_b[::-1]\nvar_d = 4\nvar_e = 0\nvar_d = int(var_d)\nfor i in list_b:\n    i = int(i)\n    if i == var_d:\n        var_e = var_e + 1\nprint(int(var_e))",
        "solution_code_en": "var_a = 11\nvar_b = 99\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c=\"\"\nfor i in list_a:\n    i = str(i)\n    var_c = var_c + i\nlist_b = []\nvar_c = int(var_c)\nwhile var_c//10 > 0:\n    list_b.append(var_c%10)\n    var_c = var_c//10\nlist_b.append(var_c%10)\nlist_b = list_b[::-1]\nvar_d = 4\nvar_e = 0\nvar_d = int(var_d)\nfor i in list_b:\n    i = int(i)\n    if i == var_d:\n        var_e = var_e + 1\nprint(int(var_e))"
    },
    "2590": {
        "category": "Comparison",
        "question_ko": "1.4, 9/10, 1.2, 0.5, 13/10 5개 숫자 중에서 1.1보다 큰 숫자를 고르고, 총합을 계산하면 얼마입니까?",
        "question_en": "From 1.4, 9/10, 1.2, 0.5 and 13/10, pick numbers greater than 1.1 and calculate their sum. What is the sum?",
        "answer_ko": "3.90",
        "answer_en": "3.9",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "2591": {
        "category": "Comparison",
        "question_ko": "4학생의 키를 비교하고 있습니다. 유나는 윤기보다 크고, 윤기는 유정보다 크고, 유정은 지민보다 크다면, 키가 가장 작은 학생은 누구입니까?",
        "question_en": "We are comparing the heights of 4 students. If Yuna is taller than Yoongi, Yoongi is taller than Yoojung, and Yoojung is taller than Jimin, who is the shortest student?",
        "answer_ko": "지민",
        "answer_en": "Jimin",
        "solution_abst_ko": "[OP_LIST_SOL] 유나 윤기 유정 지민 [OP_LIST_EOL] [OP_LIST_SOL] 유나 윤기 > 윤기 유정 > 유정 지민 > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yuna Yoongi Yoojung Jimin [OP_LIST_EOL] [OP_LIST_SOL] Yuna Yoongi > Yoongi Yoojung > Yoojung Jimin > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '유나'\nvar_b = '윤기'\nvar_c = '유정'\nvar_d = '지민'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '유나'\nvar_f = '윤기'\nvar_g = '>'\nvar_h = '윤기'\nvar_i = '유정'\nvar_j = '>'\nvar_k = '유정'\nvar_l = '지민'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)",
        "solution_code_en": "var_a = 'Yuna'\nvar_b = 'Yoongi'\nvar_c = 'Yoojung'\nvar_d = 'Jimin'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'Yuna'\nvar_f = 'Yoongi'\nvar_g = '>'\nvar_h = 'Yoongi'\nvar_i = 'Yoojung'\nvar_j = '>'\nvar_k = 'Yoojung'\nvar_l = 'Jimin'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)"
    },
    "2592": {
        "category": "Arithmetic calculation",
        "question_ko": "호석이네 반 학생 수는 40명입니다. 호석, 지민, 윤기의 영어 시험 점수는 각각 95점, 82점, 88점입니다. 이 3명을 제외한 학생들의 영어 평균 점수는 70점입니다. 호석이네 반 영어 평균 점수는 몇 점입니까?",
        "question_en": "There are 40 students in Hoseok's class. Hoseok, Jimin, and Yoongi's English test scores are 95, 82, and 88, respectively. Excluding these three students, the average score of students in English is 70. What is the average English score for Hoseok's class?",
        "answer_ko": "71.38",
        "answer_en": "71.38",
        "solution_abst_ko": "40 3 [OP_SUB] 70 [OP_MUL] 95 [OP_ADD] 82 [OP_ADD] 88 [OP_ADD] 40 [OP_DIV]",
        "solution_abst_en": "40 3 [OP_SUB] 70 [OP_MUL] 95 [OP_ADD] 82 [OP_ADD] 88 [OP_ADD] 40 [OP_DIV]",
        "solution_code_ko": "var_a = 40\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 70\nvar_e = var_c * var_d\nvar_f = 95\nvar_g = var_e + var_f\nvar_h = 82\nvar_i = var_g + var_h\nvar_j = 88\nvar_k = var_i + var_j\nvar_l = 40\nvar_m = var_k / var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))",
        "solution_code_en": "var_a = 40\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 70\nvar_e = var_c * var_d\nvar_f = 95\nvar_g = var_e + var_f\nvar_h = 82\nvar_i = var_g + var_h\nvar_j = 88\nvar_k = var_i + var_j\nvar_l = 40\nvar_m = var_k / var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))"
    },
    "2593": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이는 빨간 공 5개, 파란 공 4개, 노란 공 3개를 가지고 있습니다. 정국이가 윤기에게 파란 공 1개를 주었을 때, 정국이는 빨간 공을 몇 개 가지고 있습니까?",
        "question_en": "Jungkook has 5 red balls, 4 blue balls, and 3 yellow balls. When Jungkook gives Yoongi 1 blue ball, how many red balls does Jungkook have?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "5",
        "solution_abst_en": "5",
        "solution_code_ko": "var_a = 5\nprint(int(var_a))",
        "solution_code_en": "var_a = 5\nprint(int(var_a))"
    },
    "2594": {
        "category": "Comparison",
        "question_ko": "수은이의 줄넘기의 길이는 1.704미터(m)이고 연우의 줄넘기의 길이는 1.74미터(m)입니다. 둘 중 누구의 줄넘기가 더 깁니까?",
        "question_en": "Sueun's jump rope is 1.704 meters (m) long and Yeonwoo's jump rope is 1.74 meters (m) long. Whose jump rope is longer?",
        "answer_ko": "연우",
        "answer_en": "Yeonwoo",
        "solution_abst_ko": "[OP_LIST_SOL] 수은 연우 [OP_LIST_EOL] [OP_LIST_SOL] 1.704 1.74 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Sueun Yeonwoo [OP_LIST_EOL] [OP_LIST_SOL] 1.704 1.74 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '수은'\nvar_b = '연우'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.704\nvar_d = 1.74\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Sueun'\nvar_b = 'Yeonwoo'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.704\nvar_d = 1.74\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "2595": {
        "category": "Arithmetic calculation",
        "question_ko": "몇 명의 학생들에게 공책을 나누어 주려고 한다. 한 학생에게 4권씩 나누어 주면 3권이 남고, 5권씩 나누어 주면 6권이 부족하다고 할 때, 학생 수를 구하시오.",
        "question_en": "You are going to hand out notebooks to a few students. If each student is given 4 books, 3 books are left, and if 5 books are distributed, then 6 books are in short. Find the number of students.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "3 6 [OP_ADD] 5 4 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "3 6 [OP_ADD] 5 4 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 3\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = 4\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 3\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = 4\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))"
    },
    "2596": {
        "category": "Correspondence",
        "question_ko": "등식 691-A87=4이 성립한다고 합니다. A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "The equation 691-A87=4 holds. What number should be in A?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "691-A87=4 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "691-A87=4 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '691-A87=4'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '691-A87=4'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "2597": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 40을 더하여 5를 곱한 값이 555이다. 어떤 수에 7을 곱하고 55를 빼면 얼마인지 구하시오.",
        "question_en": "Add 40 to a number multiplied by 5 to get 555. What is the result of multiplying a number by 7 and subtracting 55?",
        "answer_ko": "442",
        "answer_en": "442",
        "solution_abst_ko": "555 5 [OP_DIV] 40 [OP_SUB] 7 [OP_MUL] 55 [OP_SUB]",
        "solution_abst_en": "555 5 [OP_DIV] 40 [OP_SUB] 7 [OP_MUL] 55 [OP_SUB]",
        "solution_code_ko": "var_a = 555\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 40\nvar_e = var_c - var_d\nvar_f = 7\nvar_g = var_e * var_f\nvar_h = 55\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 555\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 40\nvar_e = var_c - var_d\nvar_f = 7\nvar_g = var_e * var_f\nvar_h = 55\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "2598": {
        "category": "Correspondence",
        "question_ko": "두 자연수 A와 B에 대해 B가 A에 9를 곱하고 13을 더한 수라면 B를 9로 나눈 나머지는 얼마입니까?",
        "question_en": "Given two natural numbers A and B, if B is A multiplied by 9 and plus 13, what is the remainder when B is divided by 9?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "13 9 [OP_SUB]",
        "solution_abst_en": "13 9 [OP_SUB]",
        "solution_code_ko": "var_a = 13\nvar_b = 9\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 13\nvar_b = 9\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "2599": {
        "category": "Comparison",
        "question_ko": "20명의 학생들이 버스를 기다리고 있습니다. 정국이는 윤기 바로 뒤에 왔고, 정국이보다 늦게 온 사람은 11명이라면 윤기보다 먼저 온 사람들은 몇 명입니까?",
        "question_en": "20 students are waiting for the bus. If Jungkook came right after Yoongi, and there are 11 people who came after Jungkook, how many people came before Yoongi?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "20 11 [OP_SUB] 1 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "20 11 [OP_SUB] 1 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "2600": {
        "category": "Geometry",
        "question_ko": "넓이가 30제곱센티미터(㎠)인 원의 반지름을 5배 늘리면 넓이는 얼마인지 구하시오.",
        "question_en": "You multiplied the length of a radius of a 30 square centimeters (cm2) circle by a factor of 5. What will be the area of that newly formed circle?",
        "answer_ko": "750",
        "answer_en": "750",
        "solution_abst_ko": "30 5 5 [OP_MUL] [OP_MUL]",
        "solution_abst_en": "30 5 5 [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 30\nvar_b = 5\nvar_c = 5\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 30\nvar_b = 5\nvar_c = 5\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nprint(int(var_e))"
    },
    "2601": {
        "category": "Correspondence",
        "question_ko": "107.8 을 어떤 수로 나누었더니 9.8 이 되었습니다. 어떤 수는 얼마인지 구하시오.",
        "question_en": "Divide 107.8 by some number to get 9.8. Find out what the number is.",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "107.8 9.8 [OP_DIV]",
        "solution_abst_en": "107.8 9.8 [OP_DIV]",
        "solution_code_ko": "var_a = 107.8\nvar_b = 9.8\nvar_c = var_a / var_b\nprint(int(eval('{:.2f}'.format(round(var_c+1e-10,2)))))",
        "solution_code_en": "var_a = 107.8\nvar_b = 9.8\nvar_c = var_a / var_b\nprint(int(eval('{:.2f}'.format(round(var_c+1e-10,2)))))"
    },
    "2602": {
        "category": "Arithmetic calculation",
        "question_ko": "49, 31, 76, 62가 있습니다. 가장 큰 수에서 가장 작은 수를 뺀 값을 구하시오.",
        "question_en": "There are 49, 31, 76 and 62. Find the value of the largest number minus the smallest number.",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "[OP_LIST_SOL] 49 31 76 62 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 49 31 76 62 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 49\nvar_b = 31\nvar_c = 76\nvar_d = 62\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 49\nvar_b = 31\nvar_c = 76\nvar_d = 62\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))"
    },
    "2603": {
        "category": "Possibility",
        "question_ko": "윤기네 반에서 반장, 부반장 선거에 나온 사람은 4명입니다. 4명 중 반장, 부반장을 뽑는 방법은 모두 몇 가지입니까?",
        "question_en": "In Yoongi's class, there are 4 people who are running for the presidenct and the vice presidenct. How many ways can a class president and vice president be selected out of the four students?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "4 2 [OP_PERM]",
        "solution_abst_en": "4 2 [OP_PERM]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))"
    },
    "2604": {
        "category": "Arithmetic calculation",
        "question_ko": "희주네 학교 학생은 500명입니다. 이 중에서 바다를 좋아하는 학생은 337명이고, 산을 좋아하는 학생은 289명이며, 산과 바다를 둘 다 좋아하지 않는 학생은 56명입니다. 이 때, 산과 바다를 모두 좋아하는 학생의 수는?",
        "question_en": "Heeju's school has 500 students. Among them, 337 students like the sea, 289 students like the mountains, and 56 students do not like either the mountains or the sea. At this time, how many students like both the mountains and the sea?",
        "answer_ko": "182",
        "answer_en": "182",
        "solution_abst_ko": "289 337 [OP_ADD] 500 56 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "289 337 [OP_ADD] 500 56 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 289\nvar_b = 337\nvar_c = var_a + var_b\nvar_d = 500\nvar_e = 56\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 289\nvar_b = 337\nvar_c = var_a + var_b\nvar_d = 500\nvar_e = 56\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "2605": {
        "category": "Correspondence",
        "question_ko": "커다란 아이스크림 통안에 8050그램(g)의 아이스크림이 들어있다. 그 아이스크림 중 일부를 퍼내어 저울에 달았더니 80.5그램(g)이다. 퍼낸 아이스크림은 전체 아이스크림에 대해 어느정도에 해당하는 양인지 구하시오.",
        "question_en": "A large ice cream container contains 8050 grams (g) of ice cream. You scooped out some of the ice cream and weighed it on a scale, and it was 80.5 grams (g). Find the amount of scooped ice cream relative to the total ice cream.",
        "answer_ko": "0.01",
        "answer_en": "0.01",
        "solution_abst_ko": "80.5 8050 [OP_DIV]",
        "solution_abst_en": "80.5 8050 [OP_DIV]",
        "solution_code_ko": "var_a = 80.5\nvar_b = 8050\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 80.5\nvar_b = 8050\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "2606": {
        "category": "Arithmetic calculation",
        "question_ko": "숫자 6, 5, 8, 9로 나누어 떨어질 수 있는 세 자리 수는 모두 몇 개 있습니까?",
        "question_en": "How many three-digit numbers are divisible by 6, 5, 8, and 9?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "100 999 1 [OP_LIST_ARANGE] 6 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "100 999 1 [OP_LIST_ARANGE] 6 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = len(list_e)\nprint(int(var_h))",
        "solution_code_en": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = len(list_e)\nprint(int(var_h))"
    },
    "2607": {
        "category": "Arithmetic calculation",
        "question_ko": "40초과 80 이하인 수 중에서 8의 배수에 해당되는 수는 모두 몇 개입니까?",
        "question_en": "How many numbers greater than 40 and less than or equal to 80 are multiples of 8?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "40 1 [OP_ADD] 80 1 [OP_LIST_ARANGE] 8 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "40 1 [OP_ADD] 80 1 [OP_LIST_ARANGE] 8 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 40\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 80\nvar_e = 1\nlist_a = [i for i in range(var_c, var_d + 1, var_e)]\nvar_f = 8\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 40\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 80\nvar_e = 1\nlist_a = [i for i in range(var_c, var_d + 1, var_e)]\nvar_f = 8\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "2608": {
        "category": "Arithmetic calculation",
        "question_ko": "한 학교에서 3학년과 5학년을 합친 학생 수는 4학년과 6학년을 합친 학생 수와 같다. 3학년과 4학년의 학생 수가 각각 217명, 196명일 때 5학년과 6학년 학생 수의 차를 구하라.",
        "question_en": "The number of students in the 3rd and 5th grades combined in a school is equal to the number of students in the 4th and 6th grades combined. Find the difference between the number of students in the 5th and 6th grades when the number of students in the 3rd and 4th grades is 217 and 196, respectively.",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "217 196 [OP_SUB] [OP_ABS]",
        "solution_abst_en": "217 196 [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 217\nvar_b = 196\nvar_c = var_a - var_b\nvar_d = abs(var_c)\nprint(int(var_d))",
        "solution_code_en": "var_a = 217\nvar_b = 196\nvar_c = var_a - var_b\nvar_d = abs(var_c)\nprint(int(var_d))"
    },
    "2609": {
        "category": "Comparison",
        "question_ko": "(가), (나), (다), (라) 4개의 상자가 있습니다. (나) 상자는 (라) 상자보다 큽니다. (가) 상자는 (라) 상자보다 작습니다. (나) 상자는 (다) 상자보다 작습니다. 크기가 가장 작은 상자는 무엇입니까?",
        "question_en": "There are 4 boxes - (a), (b), (c), and (d). Box (b) is larger than box (d). Box (a) is smaller than box (d). Box (b) is smaller than box (c). Which box is the smallest in size?",
        "answer_ko": "(가)",
        "answer_en": "(a)",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) (다) (라) [OP_LIST_EOL] [OP_LIST_SOL] (나) (라) > (라) (가) > (다) (나) > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (a) (b) (c) (d) [OP_LIST_EOL] [OP_LIST_SOL] (b) (d) > (d) (a) > (c) (b) > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nvar_c = '(다)'\nvar_d = '(라)'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '(나)'\nvar_f = '(라)'\nvar_g = '>'\nvar_h = '(라)'\nvar_i = '(가)'\nvar_j = '>'\nvar_k = '(다)'\nvar_l = '(나)'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)",
        "solution_code_en": "var_a = '(a)'\nvar_b = '(b)'\nvar_c = '(c)'\nvar_d = '(d)'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '(b)'\nvar_f = '(d)'\nvar_g = '>'\nvar_h = '(d)'\nvar_i = '(a)'\nvar_j = '>'\nvar_k = '(c)'\nvar_l = '(b)'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)"
    },
    "2610": {
        "category": "Possibility",
        "question_ko": "900보다 작고 600보다 큰 수 중 6, 4, 9 세 수 모두로 이루어져 있는 세 자리 수는 몇 개입니까?",
        "question_en": "Find out how many three-digit numbers that are less than 900 and greater than 600 are composed of the three numbers 6, 4, and 9.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 6 4 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 600 [OP_LIST_MORE] 900 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 6 4 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 600 [OP_LIST_MORE] 900 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 6\nvar_b = 4\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 600\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = 900\nlist_d = []\nfor i in list_c:\n    if i < var_f:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))",
        "solution_code_en": "var_a = 6\nvar_b = 4\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 600\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = 900\nlist_d = []\nfor i in list_c:\n    if i < var_f:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))"
    },
    "2611": {
        "category": "Possibility",
        "question_ko": "토비는 458의 숫자 위치를 옮겨서 550보다 큰 수를 만들고 싶다. 몇 가지가 가능한가?",
        "question_en": "Toby wants to make a number greater than 550 by moving the digit position of 458. How many are possible?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "458 [OP_NUM2LIST] 3 [OP_LIST_GET_PERM] 550 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "458 [OP_NUM2LIST] 3 [OP_LIST_GET_PERM] 550 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 458\nlist_a = []\nvar_a = int(var_a)\nwhile var_a//10 > 0:\n    list_a.append(var_a%10)\n    var_a = var_a//10\nlist_a.append(var_a%10)\nlist_a = list_a[::-1]\nvar_b = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_b))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_c = 550\nlist_c = []\nfor i in list_b:\n    if i > var_c:\n        list_c.append(i)\nvar_d = len(list_c)\nprint(int(var_d))",
        "solution_code_en": "var_a = 458\nlist_a = []\nvar_a = int(var_a)\nwhile var_a//10 > 0:\n    list_a.append(var_a%10)\n    var_a = var_a//10\nlist_a.append(var_a%10)\nlist_a = list_a[::-1]\nvar_b = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_b))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_c = 550\nlist_c = []\nfor i in list_b:\n    if i > var_c:\n        list_c.append(i)\nvar_d = len(list_c)\nprint(int(var_d))"
    },
    "2612": {
        "category": "Geometry",
        "question_ko": "한 변이 6센티미터(㎝)인 정육각형과 둘레가 같은 정사각형이 있습니다. 정사각형의 한 변은 몇 센티미터(㎝)입니까?",
        "question_en": "There is a square that has the same perimeter as a regular hexagon with a side of 6 centimeters (cm). How long is one side of the square in centimeters (cm)?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "6 6 [OP_MUL] 4 [OP_DIV]",
        "solution_abst_en": "6 6 [OP_MUL] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "2613": {
        "category": "Possibility",
        "question_ko": "3 장의 숫자 카드 1, 2, 7을 모두 한 번씩 사용하여 소수를 만 들려고 합니다. 만들 수 있는 가장 큰 소수 두 자리 수와 가장 작은 소수 한 자리 수의 곱을 구하시오.",
        "question_en": "You want to create decimal numbers by using all three number cards: 1, 2, and 7 once. Find the product of the largest two-digit number and the smallest one-digit number that can be made.",
        "answer_ko": "91.57",
        "answer_en": "91.57",
        "solution_abst_ko": "[OP_LIST_SOL] 1 2 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 10 3 2 [OP_SUB] [OP_POW] [OP_DIV] 1 [OP_LIST_MIN] 10 3 1 [OP_SUB] [OP_POW] [OP_DIV] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 1 2 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 10 3 2 [OP_SUB] [OP_POW] [OP_DIV] 1 [OP_LIST_MIN] 10 3 1 [OP_SUB] [OP_POW] [OP_DIV] [OP_MUL]",
        "solution_code_ko": "var_a = 1\nvar_b = 2\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 10\nvar_h = 3\nvar_i = 2\nvar_j = var_h - var_i\nvar_k = var_g ** var_j\nvar_l = var_f / var_k\nvar_m = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_n = list_d[var_m-1]\nvar_o = 10\nvar_p = 3\nvar_q = 1\nvar_r = var_p - var_q\nvar_s = var_o ** var_r\nvar_t = var_n / var_s\nvar_u = var_l * var_t\nprint('{:.2f}'.format(round(var_u+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 2\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 10\nvar_h = 3\nvar_i = 2\nvar_j = var_h - var_i\nvar_k = var_g ** var_j\nvar_l = var_f / var_k\nvar_m = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_n = list_d[var_m-1]\nvar_o = 10\nvar_p = 3\nvar_q = 1\nvar_r = var_p - var_q\nvar_s = var_o ** var_r\nvar_t = var_n / var_s\nvar_u = var_l * var_t\nprint('{:.2f}'.format(round(var_u+1e-10,2)))"
    },
    "2614": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 28미터(m)인 리본 테이프가 있습니다. 이 리본 테이프를 잘라 1.12미터(m)의 리본을 만든다면 몇 개 만들 수 있습니까?",
        "question_en": "I have a ribbon tape that is 28 meters (m) long. If you cut this ribbon tape to make ribbons, each of which are 1.12 meter (m) long, how many ribbons can you make?",
        "answer_ko": "25",
        "answer_en": "25",
        "solution_abst_ko": "28 1.12 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "28 1.12 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 28\nvar_b = 1.12\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))",
        "solution_code_en": "var_a = 28\nvar_b = 1.12\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))"
    },
    "2615": {
        "category": "Comparison",
        "question_ko": "운동회의 참가자 중 2/7는 백팀, 3/8은 청팀이라고 합니다. 참가자 중 어느 팀이 더 많을까요?",
        "question_en": "It is said that 2/7 of the participants in the sports day are on the white team and 3/8 are on the blue team. Which team will have more participants?",
        "answer_ko": "청팀",
        "answer_en": "blue",
        "solution_abst_ko": "[OP_LIST_SOL] 백팀 청팀 [OP_LIST_EOL] [OP_LIST_SOL] 2/7 3/8 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] white blue [OP_LIST_EOL] [OP_LIST_SOL] 2/7 3/8 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '백팀'\nvar_b = '청팀'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.2857142857142857\nvar_d = 0.375\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'white'\nvar_b = 'blue'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.2857142857142857\nvar_d = 0.375\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "2616": {
        "category": "Arithmetic calculation",
        "question_ko": "12명의 학생이 운동장에 줄을 서려고 합니다. 운동장의 길이는 총 200미터(m)이며 학생들은 20미터(m)의 간격을 유지해야합니다. 총 몇명의 학생이 줄을 설 수 있습니까?",
        "question_en": "We are going to install flags on the playground at intervals of 20 meters (m). If there are 12 flags and the circumference of the field is 200 meters (m), how many flags are left?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "12 200 20 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "12 200 20 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 12\nvar_b = 200\nvar_c = 20\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 200\nvar_c = 20\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "2617": {
        "category": "Possibility",
        "question_ko": "초콜릿 54개를 남는 것 없이 포장하려 한다. 포장할 수 있는 방법은 모두 몇가지인가? (단, 54개를 한번에 포장하는 것은 고려하지 않는다.)",
        "question_en": "You want to wrap 54 chocolates without any leftovers. How many ways can it be packed? (However, packing 54 at once is not considered.)",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "54 [OP_LIST_GET_DIVISOR] [OP_LIST_SOL] 54 [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_abst_en": "54 [OP_LIST_GET_DIVISOR] [OP_LIST_SOL] 54 [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 54\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 54\nlist_b= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_b.append(var_b)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_c = len(list_c)\nprint(int(var_c))",
        "solution_code_en": "var_a = 54\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 54\nlist_b= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_b.append(var_b)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_c = len(list_c)\nprint(int(var_c))"
    },
    "2618": {
        "category": "Comparison",
        "question_ko": "서로 다른 세 사람 A, B, C가 책을 가지고 있습니다. 세 사람이 가지고 있는 책의 평균보다 A, B 두 사람이 가지고 있는 책의 평균이 23권 더 많고, B, C 두 사람이 가지고 있는 책의 평균은 세 사람의 책 평균보다 17권 적습니다. B가 66권을 가지고 있었을 때, A가 가지고 있는 책은 몇 권인지 구하시오.",
        "question_en": "Three different people A, B, and C have books. The average number of books owned by two people, A and B, is 23 more than the average number of books owned by three people. And the average number of books owned by two people, B and C, is 17 less than the average of what three people have. If B has 66 books, find how many books A has.",
        "answer_ko": "88",
        "answer_en": "88",
        "solution_abst_ko": "66 2 [OP_DIV] 17 [OP_ADD] 66 3 [OP_DIV] [OP_SUB] 6 [OP_MUL] 2 [OP_MUL] 23 66 3 [OP_DIV] [OP_ADD] 66 2 [OP_DIV] [OP_SUB] 6 [OP_MUL] [OP_SUB] 3 [OP_DIV]",
        "solution_abst_en": "66 2 [OP_DIV] 17 [OP_ADD] 66 3 [OP_DIV] [OP_SUB] 6 [OP_MUL] 2 [OP_MUL] 23 66 3 [OP_DIV] [OP_ADD] 66 2 [OP_DIV] [OP_SUB] 6 [OP_MUL] [OP_SUB] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 66\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 17\nvar_e = var_c + var_d\nvar_f = 66\nvar_g = 3\nvar_h = var_f / var_g\nvar_i = var_e - var_h\nvar_j = 6\nvar_k = var_i * var_j\nvar_l = 2\nvar_m = var_k * var_l\nvar_n = 23\nvar_o = 66\nvar_p = 3\nvar_q = var_o / var_p\nvar_r = var_n + var_q\nvar_s = 66\nvar_t = 2\nvar_u = var_s / var_t\nvar_v = var_r - var_u\nvar_w = 6\nvar_x = var_v * var_w\nvar_y = var_m - var_x\nvar_z = 3\nvar_A = var_y / var_z\nprint(int(var_A))",
        "solution_code_en": "var_a = 66\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 17\nvar_e = var_c + var_d\nvar_f = 66\nvar_g = 3\nvar_h = var_f / var_g\nvar_i = var_e - var_h\nvar_j = 6\nvar_k = var_i * var_j\nvar_l = 2\nvar_m = var_k * var_l\nvar_n = 23\nvar_o = 66\nvar_p = 3\nvar_q = var_o / var_p\nvar_r = var_n + var_q\nvar_s = 66\nvar_t = 2\nvar_u = var_s / var_t\nvar_v = var_r - var_u\nvar_w = 6\nvar_x = var_v * var_w\nvar_y = var_m - var_x\nvar_z = 3\nvar_A = var_y / var_z\nprint(int(var_A))"
    },
    "2619": {
        "category": "Comparison",
        "question_ko": "25장의 우표를 형과 동생이 가지려고 합니다. 형이 동생의 우표 2배보다 1장 더 많이 가졌다면, 형이 가진 우표는 몇 장입니까?",
        "question_en": "The older brother and younger brother are trying to get 25 stamps. How many stamps does the older brother have if the older brother owns one more than twice the younger brother's stamps?",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "25 1 [OP_SUB] 2 1 [OP_ADD] [OP_DIV] 2 [OP_MUL] 1 [OP_ADD]",
        "solution_abst_en": "25 1 [OP_SUB] 2 1 [OP_ADD] [OP_DIV] 2 [OP_MUL] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 25\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = var_c / var_f\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = 1\nvar_k = var_i + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 25\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = var_c / var_f\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = 1\nvar_k = var_i + var_j\nprint(int(var_k))"
    },
    "2620": {
        "category": "Arithmetic calculation",
        "question_ko": "540에서 10씩 커지게 6번 뛰어서 세면 얼마입니까?",
        "question_en": "What is the number if 540 increases with 10 by 6 times?",
        "answer_ko": "600",
        "answer_en": "600",
        "solution_abst_ko": "540 10 6 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "540 10 6 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 540\nvar_b = 10\nvar_c = 6\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 540\nvar_b = 10\nvar_c = 6\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "2621": {
        "category": "Arithmetic calculation",
        "question_ko": "1초에 288센티미터(㎝) 달리는 지하철이 있습니다. 지하철의 길이는 20미터(m)이며 승강장을 완전히 통과하는데 25초가 걸렸다면 승강장의 길이는 몇 미터(m)입니까?",
        "question_en": "There is a subway that runs at 288 centimeters (cm) per second. If the length of the subway is 20 meters (m), and it takes 25 seconds to completely get through the platform, how long is the platform in meters (m)?",
        "answer_ko": "52",
        "answer_en": "52",
        "solution_abst_ko": "288 100 [OP_DIV] 25 [OP_MUL] 20 [OP_SUB]",
        "solution_abst_en": "288 100 [OP_DIV] 25 [OP_MUL] 20 [OP_SUB]",
        "solution_code_ko": "var_a = 288\nvar_b = 100\nvar_c = var_a / var_b\nvar_d = 25\nvar_e = var_c * var_d\nvar_f = 20\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 288\nvar_b = 100\nvar_c = var_a / var_b\nvar_d = 25\nvar_e = var_c * var_d\nvar_f = 20\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "2622": {
        "category": "Correspondence",
        "question_ko": "493을 17로 나누면 어떤 수가 됩니다. 어떤 수는 얼마입니까?",
        "question_en": "Divide 493 by 17 to get a number. What number is it?",
        "answer_ko": "29",
        "answer_en": "29",
        "solution_abst_ko": "493 17 [OP_DIV]",
        "solution_abst_en": "493 17 [OP_DIV]",
        "solution_code_ko": "var_a = 493\nvar_b = 17\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 493\nvar_b = 17\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "2623": {
        "category": "Geometry",
        "question_ko": "어느 피자의 지름이 30센티미터(㎝)이며, 이 피자의 둘레는 94.2센티미터(㎝)입니다. 피자의 둘레는 지름의 몇 배입니까?",
        "question_en": "A pizza is 30 centimeters (cm) in diameter and its circumference is 94.2 centimeters (cm). How many times the circumference of the pizza is greater than the diameter?",
        "answer_ko": "3.14",
        "answer_en": "3.14",
        "solution_abst_ko": "94.2 30 [OP_DIV]",
        "solution_abst_en": "94.2 30 [OP_DIV]",
        "solution_code_ko": "var_a = 94.2\nvar_b = 30\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 94.2\nvar_b = 30\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "2624": {
        "category": "Comparison",
        "question_ko": "정국이는 0.8, 윤기는 1/2, 유정이는 0.9, 유나는 1/3의 숫자카드를 갖고 있습니다. 0.3보다 작거나 같은 숫자카드를 가지고 있는 사람은 몇 명입니까?",
        "question_en": "Jungkook has a number card 0.8, Yoongi has 1/2, Yoojung has 0.9, and Yuna has 1/3. How many people have number cards less than or equal to 0.3?",
        "answer_ko": "0",
        "answer_en": "0",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.3 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.3 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.3\nlist_b = []\nfor i in list_a:\n    if i <= var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.3\nlist_b = []\nfor i in list_a:\n    if i <= var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "2625": {
        "category": "Possibility",
        "question_ko": "신발 36켤레를 서로 다른 2명의 여학생에게 나누어 주려고 합니다. 여학생은 적어도 신발 1켤레는 받습니다. 신발을 나누어 주는 방법은 모두 몇 가지입니까?",
        "question_en": "You want to distribute 36 pairs of shoes to two different female students. Girls receive at least one pair of shoes. How many ways are there to distribute shoes?",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "36 2 1 [OP_MUL] [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "36 2 1 [OP_MUL] [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 36\nvar_b = 2\nvar_c = 1\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 36\nvar_b = 2\nvar_c = 1\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "2626": {
        "category": "Correspondence",
        "question_ko": "지수네 반 학생수는 36명이다. 지수네 반 학생 수와 성훈이네 반 학생 수를 곱하면 1008이 된다. 성훈이네 반 학생 수를 구하시오.",
        "question_en": "There are 36 students in Jisoo’s class. If you multiply the number of students in Jisoo's class by the number of students in Sunghoon's class, you get 1008. Find the number of students in Sunghoon's class.",
        "answer_ko": "28",
        "answer_en": "28",
        "solution_abst_ko": "1008 36 [OP_DIV]",
        "solution_abst_en": "1008 36 [OP_DIV]",
        "solution_code_ko": "var_a = 1008\nvar_b = 36\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 1008\nvar_b = 36\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "2627": {
        "category": "Possibility",
        "question_ko": "두 개의 동전 A, B를 던질 때, 앞면이 2개 나오는 경우의 수는 몇 가지입니까?",
        "question_en": "If two coins A and B are tossed, how many times can it come up with 2 heads?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "2 [OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_SUB] [OP_POW]",
        "solution_abst_en": "2 [OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_SUB] [OP_POW]",
        "solution_code_ko": "var_a = 2\nvar_b = 'A'\nvar_c = 'B'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = var_a ** var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 2\nvar_b = 'A'\nvar_c = 'B'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = var_a ** var_f\nprint(int(var_g))"
    },
    "2628": {
        "category": "Geometry",
        "question_ko": "정삼각형 1개와 정사각형 1개의 둘레의 길이를 합하였더니 78센티미터(㎝)였습니다. 이때 삼각형의 둘레가 46센티미터(㎝)라면, 정사각형의 한 변의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "The sum of the perimeters of one regular triangle and one square equals 78 centimeters (cm). If the perimeter of the triangle is 46 centimeters (cm), what is the length of one side of the square in centimeters (cm)?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "78 46 [OP_SUB] 4 [OP_DIV]",
        "solution_abst_en": "78 46 [OP_SUB] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 78\nvar_b = 46\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 78\nvar_b = 46\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "2629": {
        "category": "Arithmetic calculation",
        "question_ko": "5부터 29 사이의 짝수 중 가장 큰 수와 가장 작은 수의 차를 구하시오.",
        "question_en": "Find the difference between the largest and smallest even number between 5 and 29.",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "5 29 [OP_LIST_EVEN] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "5 29 [OP_LIST_EVEN] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 5\nvar_b = 29\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[-var_c]\nvar_e = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = var_d - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 29\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[-var_c]\nvar_e = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = var_d - var_f\nprint(int(var_g))"
    },
    "2630": {
        "category": "Arithmetic calculation",
        "question_ko": "샤프 16개가 들어있는 학용품세트 4개를 샀습니다. 샤프는 모두 몇 개인가요?",
        "question_en": "I bought 4 school supplies sets with 16 mechanical pencils each. How many mechanical pencils are there in all?",
        "answer_ko": "64",
        "answer_en": "64",
        "solution_abst_ko": "16 4 [OP_MUL]",
        "solution_abst_en": "16 4 [OP_MUL]",
        "solution_code_ko": "var_a = 16\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 16\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "2631": {
        "category": "Correspondence",
        "question_ko": "실수로 숫자를 18로 나누고 1.8로 나누면 몫은 21이고 나머지는 0.2입니다. 올바른 계산의 나머지를 구하십시오.",
        "question_en": "If you accidentally divide the number by 18 and divide it again by 1.8, the quotient is 21 with the remainder of 0.2. Find the remainder of the correct calculation.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "21 1.8 [OP_MUL] 0.2 [OP_ADD] 18 [OP_MOD]",
        "solution_abst_en": "21 1.8 [OP_MUL] 0.2 [OP_ADD] 18 [OP_MOD]",
        "solution_code_ko": "var_a = 21\nvar_b = 1.8\nvar_c = var_a * var_b\nvar_d = 0.2\nvar_e = var_c + var_d\nvar_f = 18\nvar_g = var_e % var_f\nprint(int(eval('{:.2f}'.format(round(var_g+1e-10,2)))))",
        "solution_code_en": "var_a = 21\nvar_b = 1.8\nvar_c = var_a * var_b\nvar_d = 0.2\nvar_e = var_c + var_d\nvar_f = 18\nvar_g = var_e % var_f\nprint(int(eval('{:.2f}'.format(round(var_g+1e-10,2)))))"
    },
    "2632": {
        "category": "Possibility",
        "question_ko": "두 자리 자연수 중 각 자리 숫자가 다르고, 0, 1, 7, 9로만 구성되어 있는 수는 모두 몇 개인가?",
        "question_en": "How many two-digit natural numbers are there with all digits different, only consisting of 0, 1, 7, and 9?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 7 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 7 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 7\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 7\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "2633": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.9, 1/3 중에서 0.4보다 큰 수는 몇 개입니까?",
        "question_en": "How many of 0.8, 1/2, 0.9, and 1/3 are greater than 0.4?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.4\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.4\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "2634": {
        "category": "Geometry",
        "question_ko": "길이가 40센티미터(㎝)인 철사를 남김없이 모두 사용하여 가장 큰 정팔각형을 1개 만들었습니다. 만든 정팔각형의 한 변은 몇 센티미터(㎝)입니까?",
        "question_en": "Using all of the 40 centimeters (cm) lengths of wire, the largest regular octagons was created. How many centimeters (cm) is one side of the regular octagon you created?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "40 8 [OP_DIV]",
        "solution_abst_en": "40 8 [OP_DIV]",
        "solution_code_ko": "var_a = 40\nvar_b = 8\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 40\nvar_b = 8\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "2635": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중에서 가장 큰 수와 2번째로 큰 수의 곱은 얼마입니까?",
        "question_en": "There are three numbers: 10, 11 and 12. What is the product of the largest number and the second largest number?",
        "answer_ko": "132",
        "answer_en": "132",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = var_e * var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = var_e * var_g\nprint(int(var_h))"
    },
    "2636": {
        "category": "Arithmetic calculation",
        "question_ko": "서로 다른 네 자연수 1, 3, 7, 9중 차가 가장 큰 2장의 합을 구하시오.",
        "question_en": "Find the sum of the two numbers with the greatest difference among the four different natural numbers 1, 3, 7, and 9.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 7 9 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 7 9 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 7\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 7\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))"
    },
    "2637": {
        "category": "Arithmetic calculation",
        "question_ko": "시속 80킬로미터(㎞)의 빠르기로 2시간 36분을 이동한 자동차가 있습니다. 이 자동차는 1킬로미터(㎞)를 가는데 0.08리터(L)의 휘발유를 소모합니다. 소모한 휘발유의 양은 몇 리터(L)인가요?",
        "question_en": "There is a car that traveled 2 hours and 36 minutes at a speed of 80 kilometers (km) per hour. This car consumes 0.08 liters (l) of gasoline to travel 1 kilometer (km). How many liters (L) of gasoline is consumed?",
        "answer_ko": "16.64",
        "answer_en": "16.64",
        "solution_abst_ko": "0.08 80 2 36 60 [OP_DIV] [OP_ADD] [OP_MUL] [OP_MUL]",
        "solution_abst_en": "0.08 80 2 36 60 [OP_DIV] [OP_ADD] [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 0.08\nvar_b = 80\nvar_c = 2\nvar_d = 36\nvar_e = 60\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nvar_h = var_b * var_g\nvar_i = var_a * var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 0.08\nvar_b = 80\nvar_c = 2\nvar_d = 36\nvar_e = 60\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nvar_h = var_b * var_g\nvar_i = var_a * var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "2638": {
        "category": "Arithmetic calculation",
        "question_ko": "올해 아버지의 나이는 딸의 나이의 3배이고, 12년 후에 아버지의 나이는 딸의 나이의 2배가 된다고 한다. 올해 딸의 나이는?",
        "question_en": "This year, the age of the father is three times the age of the daughter, and after 12 years, the age of the father will be twice the age of the daughter. How old is the daughter this year?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "12 2 [OP_MUL] 12 [OP_SUB] 3 2 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "12 2 [OP_MUL] 12 [OP_SUB] 3 2 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = 2\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 12\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = 2\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "2639": {
        "category": "Comparison",
        "question_ko": "모양 (가)은 가로 12센티미터(㎝), 세로 5센티미터(㎝)의 직사각형입니다. 모양 (나)는 둘레가 32센티미터(㎝), 가로가 8센티미터(㎝)인 직사각형입니다. 두 도형 중 어느 것이 더 넓습니까?",
        "question_en": "The shape (A) is a rectangle 12 centimeters (cm) wide and 5 centimeters (cm) long. The shape (B) is a rectangle with a perimeter of 32 centimeters (cm) and a width of 8 centimeters (cm). Which of the two shapes is wider?",
        "answer_ko": "(나)",
        "answer_en": "(B)",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) [OP_LIST_EOL] [OP_LIST_SOL] 4 4 [OP_MUL] 32 8 2 [OP_MUL] [OP_SUB] 2 [OP_DIV] 8 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (A) (B) [OP_LIST_EOL] [OP_LIST_SOL] 4 4 [OP_MUL] 32 8 2 [OP_MUL] [OP_SUB] 2 [OP_DIV] 8 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 4\nvar_e = var_c * var_d\nvar_f = 32\nvar_g = 8\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = var_f - var_i\nvar_k = 2\nvar_l = var_j / var_k\nvar_m = 8\nvar_n = var_l * var_m\nlist_b= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_o = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_p = list_c[-var_o]\nvar_q = list_b.index(var_p)+1\nvar_r = list_a[var_q-1]\nprint(var_r)",
        "solution_code_en": "var_a = '(A)'\nvar_b = '(B)'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 4\nvar_e = var_c * var_d\nvar_f = 32\nvar_g = 8\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = var_f - var_i\nvar_k = 2\nvar_l = var_j / var_k\nvar_m = 8\nvar_n = var_l * var_m\nlist_b= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_o = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_p = list_c[-var_o]\nvar_q = list_b.index(var_p)+1\nvar_r = list_a[var_q-1]\nprint(var_r)"
    },
    "2640": {
        "category": "Correspondence",
        "question_ko": "34를 7로 나눴더니 나머지가 6, 몫이 A가 되었습니다. A에 알맞은 값을 구하시오.",
        "question_en": "When 34 is divided by 7, the remainder is 6 and the quotient is A. Find the right value for A.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "34 6 [OP_SUB] 7 [OP_DIV]",
        "solution_abst_en": "34 6 [OP_SUB] 7 [OP_DIV]",
        "solution_code_ko": "var_a = 34\nvar_b = 6\nvar_c = var_a - var_b\nvar_d = 7\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 34\nvar_b = 6\nvar_c = var_a - var_b\nvar_d = 7\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "2641": {
        "category": "Arithmetic calculation",
        "question_ko": "무게가 각각 같은 로봇 9개와 팽이 7개의 무게를 재어 보니 10.98킬로그램(㎏)이었습니다. 로봇 1개의 무게가 0.8킬로그램(㎏)일 때 팽이 한 개의 무게는 몇 킬로그램(㎏)인지 구하시오.",
        "question_en": "When we weighed 9 robots of the same weight and 7 tops also of the same weight in total, it was 10.98 kilograms (kg). If the weight of one robot is 0.8 kilograms (kg), find the weight of one top in kilograms (kg).",
        "answer_ko": "0.54",
        "answer_en": "0.54",
        "solution_abst_ko": "10.98 0.8 9 [OP_MUL] [OP_SUB] 7 [OP_DIV]",
        "solution_abst_en": "10.98 0.8 9 [OP_MUL] [OP_SUB] 7 [OP_DIV]",
        "solution_code_ko": "var_a = 10.98\nvar_b = 0.8\nvar_c = 9\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 7\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 10.98\nvar_b = 0.8\nvar_c = 9\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 7\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "2642": {
        "category": "Comparison",
        "question_ko": "5개의 수 0.45, 1/2, 0.77, 3/8, 6/8 중에서 가장 큰 수와 가장 작은 수의 합을 구하시오.",
        "question_en": "Find the sum of the largest and smallest of the five numbers 0.45, 1/2, 0.77, 3/8, and 6/8.",
        "answer_ko": "1.15",
        "answer_en": "1.15",
        "solution_abst_ko": "[OP_LIST_SOL] 0.45 1/2 0.77 3/8 6/8 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 0.45 1/2 0.77 3/8 6/8 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 0.45\nvar_b = 0.5\nvar_c = 0.77\nvar_d = 0.375\nvar_e = 0.75\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g + var_i\nprint('{:.2f}'.format(round(var_j+1e-10,2)))",
        "solution_code_en": "var_a = 0.45\nvar_b = 0.5\nvar_c = 0.77\nvar_d = 0.375\nvar_e = 0.75\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g + var_i\nprint('{:.2f}'.format(round(var_j+1e-10,2)))"
    },
    "2643": {
        "category": "Correspondence",
        "question_ko": "등식 57A-B14=364이 성립한다고 합니다. B에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "Say that the equation 57A-B14=364 holds. To make the equation hold, what number should go in B?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "57A-B14=364 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "57A-B14=364 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '57A-B14=364'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '57A-B14=364'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "2644": {
        "category": "Correspondence",
        "question_ko": "상은이는 물건을 사러 가서 첫 번째 가게에서 가지고 있던 돈의 절반과 2000원을 쓰고, 두 번째 가게에서 남은 돈의 절반과 2000원을 썼더니 남은 돈이 없었습니다. 상은이가 처음에 가지고 있던 돈은 얼마인가요?",
        "question_en": "Sangeun goes shopping and spends half of her money and 2,000 won at the first store, then half of her remaining money and 2,000 won at the second store, and she has no money left. How much money did Sangeun have at first?",
        "answer_ko": "12000",
        "answer_en": "12000",
        "solution_abst_ko": "0 2000 [OP_ADD] 2 [OP_MUL] 2000 [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "0 2000 [OP_ADD] 2 [OP_MUL] 2000 [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 0\nvar_b = 2000\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 2000\nvar_g = var_e + var_f\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 0\nvar_b = 2000\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 2000\nvar_g = var_e + var_f\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "2645": {
        "category": "Comparison",
        "question_ko": "석진이는 호석이보다 무겁고 지민이보다 가볍습니다. 남준이는 지민이보다 무겁습니다. 4명 중 가장 가벼운 사람은 누구입니까?",
        "question_en": "Seokjin is heavier than Hoseok but lighter than Jimin. Namjoon is heavier than Jimin. Which of the 4 is the lightest?",
        "answer_ko": "호석",
        "answer_en": "Hoseok",
        "solution_abst_ko": "[OP_LIST_SOL] 석진 호석 지민 남준 [OP_LIST_EOL] [OP_LIST_SOL] 석진 호석 > 석진 지민 < 남준 지민 > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Seokjin Hoseok Jimin Namjoon [OP_LIST_EOL] [OP_LIST_SOL] Seokjin Hoseok > Seokjin Jimin < Namjoon Jimin > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '석진'\nvar_b = '호석'\nvar_c = '지민'\nvar_d = '남준'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '석진'\nvar_f = '호석'\nvar_g = '>'\nvar_h = '석진'\nvar_i = '지민'\nvar_j = '<'\nvar_k = '남준'\nvar_l = '지민'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)",
        "solution_code_en": "var_a = 'Seokjin'\nvar_b = 'Hoseok'\nvar_c = 'Jimin'\nvar_d = 'Namjoon'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'Seokjin'\nvar_f = 'Hoseok'\nvar_g = '>'\nvar_h = 'Seokjin'\nvar_i = 'Jimin'\nvar_j = '<'\nvar_k = 'Namjoon'\nvar_l = 'Jimin'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)"
    },
    "2646": {
        "category": "Correspondence",
        "question_ko": "반올림하면 8000이 되는 네 자리 수 8A42가 있습니다. A에 0부터 9까지 들어갈 수 있을때 가능한 A는 모두 몇 개 입니까?",
        "question_en": "There is a four-digit number 8A42 which, when rounded, is 8000. How many possible A's are there if A range between 0 to 9?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "8A42 [OP_GEN_POSSIBLE_LIST] 8500 [OP_LIST_MORE_EQUAL] 8A42 A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_abst_en": "8A42 [OP_GEN_POSSIBLE_LIST] 8500 [OP_LIST_MORE_EQUAL] 8A42 A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '8A42'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 8500\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = '8A42'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nvar_e = len(list_c)\nprint(int(var_e))",
        "solution_code_en": "var_a = '8A42'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 8500\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = '8A42'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nvar_e = len(list_c)\nprint(int(var_e))"
    },
    "2647": {
        "category": "Geometry",
        "question_ko": "반지름이 5센티미터(㎝)인 원이 있습니다. 반지름을 3배로 늘린 원의 넓이는 처음 원의 넓이의 몇 배가 됩니까?",
        "question_en": "A circle has a radius of 5 centimeters (cm). How many times is the area of the circle whose radius is tripled bigger compared to the area of the original circle?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "3 2 [OP_POW]",
        "solution_abst_en": "3 2 [OP_POW]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = var_a ** var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = var_a ** var_b\nprint(int(var_c))"
    },
    "2648": {
        "category": "Correspondence",
        "question_ko": "46을 어떤 수에서 뺐더니 15가 되었습니다. 29를 어떤 수에 뺀 결과를 구하시오.",
        "question_en": "If you take away 46 from this number it becomes 15. What is the result of subtracting 29 from this number?",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "15 46 [OP_ADD] 29 [OP_SUB]",
        "solution_abst_en": "15 46 [OP_ADD] 29 [OP_SUB]",
        "solution_code_ko": "var_a = 15\nvar_b = 46\nvar_c = var_a + var_b\nvar_d = 29\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 46\nvar_c = var_a + var_b\nvar_d = 29\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "2649": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 8로 나누어야 할 것을 잘못하여 곱했더니 56이 되었습니다. 바르게 계산하면 얼마인지 소수점 둘째자리까지 나타내시오.",
        "question_en": "I have to divide a number by 8, but I multiply it by 8 by mistake, it's 56. If calculated correctly, indicate how much to the second decimal place.",
        "answer_ko": "0.88",
        "answer_en": "0.88",
        "solution_abst_ko": "56 8 [OP_DIV] 8 [OP_DIV]",
        "solution_abst_en": "56 8 [OP_DIV] 8 [OP_DIV]",
        "solution_code_ko": "var_a = 56\nvar_b = 8\nvar_c = var_a / var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 56\nvar_b = 8\nvar_c = var_a / var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "2650": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.9의 숫자가 있다. 이 중 0.6보다 크거나 같은 숫자들 중 가장 작거나 같은 숫자를 구하시오.",
        "question_en": "There are numbers 0.8, 1/2, and 0.9. Find the smallest number that is greater than or equal to 0.6.",
        "answer_ko": "0.80",
        "answer_en": "0.8",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 0.6 [OP_LIST_MORE_EQUAL] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 0.6 [OP_LIST_MORE_EQUAL] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.6\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nprint('{:.2f}'.format(round(var_f+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.6\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nprint('{:.2f}'.format(round(var_f+1e-10,2)))"
    },
    "2651": {
        "category": "Correspondence",
        "question_ko": "51-A3=28라는 식이 성립하려면, A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "What number must go in A to make 51-A3=28?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "51-A3=28 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "51-A3=28 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '51-A3=28'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '51-A3=28'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "2652": {
        "category": "Geometry",
        "question_ko": "길이가 32센티미터(㎝)인 끈으로 마름모를 만들때 한변의 길이는 얼마입니까?",
        "question_en": "What is the length of one side of a rhombus made out of a string of 32 centimeters (cm) in length?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "32 4 [OP_DIV]",
        "solution_abst_en": "32 4 [OP_DIV]",
        "solution_code_ko": "var_a = 32\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 32\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "2653": {
        "category": "Arithmetic calculation",
        "question_ko": "윤기, 은지, 유나가 모여 가지고 있던 책을 공평하게 나눠가지고자 합니다. 윤기가 은지에게 5권을 주고 유나에게 15권을 받고, 은지가 유나에게 10권을 주면 세 사람은 책을 45권씩 가지게 됩니다. 윤기가 처음에 가지고 온 책은 몇 권입니까?",
        "question_en": "We want to share the books that Yoongi, Eunji, and Yuna had together fairly. If Yoongi gives 5 books to Eunji and receives 15 books from Yuna, and Eunji gives 10 books to Yuna, the three of them will each have 45 books. How many books did Yunji bring at first?",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "45 15 [OP_SUB] 5 [OP_ADD]",
        "solution_abst_en": "45 15 [OP_SUB] 5 [OP_ADD]",
        "solution_code_ko": "var_a = 45\nvar_b = 15\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 45\nvar_b = 15\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "2654": {
        "category": "Possibility",
        "question_ko": "서로 다르게 생긴 로봇 장난감 6개가 있다. 가희, 나희, 다희, 라희에게 1개씩 주는 경우의 수를 구하시오.",
        "question_en": "There are 6 robot toys that look different. Find the number of cases in which one is given each to Kahi, Nahee, Dahee, and Rahee.",
        "answer_ko": "360",
        "answer_en": "360",
        "solution_abst_ko": "6 1 1 [OP_ADD] 1 [OP_ADD] 1 [OP_ADD] [OP_PERM]",
        "solution_abst_en": "6 1 1 [OP_ADD] 1 [OP_ADD] 1 [OP_ADD] [OP_PERM]",
        "solution_code_ko": "var_a = 6\nvar_b = 1\nvar_c = 1\nvar_d = var_b + var_c\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = 1\nvar_a = int(var_a)\nvar_h = int(var_h)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i * (var_a-i)\nprint(int(var_i))",
        "solution_code_en": "var_a = 6\nvar_b = 1\nvar_c = 1\nvar_d = var_b + var_c\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = 1\nvar_a = int(var_a)\nvar_h = int(var_h)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i * (var_a-i)\nprint(int(var_i))"
    },
    "2655": {
        "category": "Geometry",
        "question_ko": "정육각형에서 평행인 변은 모두 몇 쌍일까요?",
        "question_en": "How many pairs of parallel sides are there in a regular hexagon?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "6 2 [OP_FDIV]",
        "solution_abst_en": "6 2 [OP_FDIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = var_a // var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = var_a // var_b\nprint(int(var_c))"
    },
    "2656": {
        "category": "Arithmetic calculation",
        "question_ko": "볼펜은 20센티미터(㎝), 연필은 16센티미터(㎝)입니다. 두 필기구의 평균은 몇 센티미터(㎝)입니까?",
        "question_en": "A ballpoint pen is 20 centimeters (cm) long and a pencil is 16 centimeters (cm) long. What is the average of the two writing instruments in centimeters (cm)?",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "20 16 [OP_ADD] 2 [OP_DIV]",
        "solution_abst_en": "20 16 [OP_ADD] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 20\nvar_b = 16\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 16\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "2657": {
        "category": "Correspondence",
        "question_ko": "어떤 수보다 236 작은 수가 397일 때, 어떤 수보다 496 작은 수를 구하시오.",
        "question_en": "If 397 is 236 lesser than a certain number, find the value that is 496 lesser than this certain number.",
        "answer_ko": "137",
        "answer_en": "137",
        "solution_abst_ko": "397 236 [OP_ADD] 496 [OP_SUB]",
        "solution_abst_en": "397 236 [OP_ADD] 496 [OP_SUB]",
        "solution_code_ko": "var_a = 397\nvar_b = 236\nvar_c = var_a + var_b\nvar_d = 496\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 397\nvar_b = 236\nvar_c = var_a + var_b\nvar_d = 496\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "2658": {
        "category": "Possibility",
        "question_ko": "0, 4, 6, 7, 8 중에 한 번씩만 사용하여 만들 수 있는 다섯 자리 수 중에서 세 번째로 큰 수를 구하시오.",
        "question_en": "Find the third largest number among five-digit numbers that can be formed using 0, 4, 6, 7, and 8 only once each.",
        "answer_ko": "87460",
        "answer_en": "87460",
        "solution_abst_ko": "[OP_LIST_SOL] 0 4 6 7 8 [OP_LIST_EOL] 5 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 0 4 6 7 8 [OP_LIST_EOL] 5 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 0\nvar_b = 4\nvar_c = 6\nvar_d = 7\nvar_e = 8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 5\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nprint(int(var_h))",
        "solution_code_en": "var_a = 0\nvar_b = 4\nvar_c = 6\nvar_d = 7\nvar_e = 8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 5\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nprint(int(var_h))"
    },
    "2659": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 20/9센티미터(㎝)인 정삼각형과 둘레가 같은 정오각형의 한 변의 길이는 몇 센티미터(㎝)인지 답을 구하세요.",
        "question_en": "Find how long is the side of a regular pentagon in centimeters (cm) when it has the same perimeter as an equilateral triangle with a side length of 20/9 centimeters (cm).",
        "answer_ko": "1.33",
        "answer_en": "1.33",
        "solution_abst_ko": "20/9 3 [OP_MUL] 5 [OP_DIV]",
        "solution_abst_en": "20/9 3 [OP_MUL] 5 [OP_DIV]",
        "solution_code_ko": "var_a = 2.2222222222222223\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 2.2222222222222223\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "2660": {
        "category": "Comparison",
        "question_ko": "0.11, 0.98, 3/4, 2/3 중 가장 큰 수와 가장 작은 수의 합을 구하시오.",
        "question_en": "Find the sum of the largest and smallest numbers among 0.11, 0.98, 3/4, and 2/3.",
        "answer_ko": "1.09",
        "answer_en": "1.09",
        "solution_abst_ko": "[OP_LIST_SOL] 0.11 0.98 3/4 2/3 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 0.11 0.98 3/4 2/3 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 0.11\nvar_b = 0.98\nvar_c = 0.75\nvar_d = 0.6666666666666666\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f + var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 0.11\nvar_b = 0.98\nvar_c = 0.75\nvar_d = 0.6666666666666666\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f + var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "2661": {
        "category": "Comparison",
        "question_ko": "태형이와 남준이는 어제 동화책을 각각 32쪽, 25쪽 읽었습니다. 오늘 태형이는 어제보다 13쪽 적게 읽었는데, 남준이는 오늘 어제보다 14쪽이나 많이 읽었습니다. 이틀 동안 동화책을 더 많이 읽은 학생은 누구입니까?",
        "question_en": "Taehyung and Namjoon read 32 pages and 25 pages of fairy tales yesterday, respectively. Today Taehyung read 13 pages less than yesterday, but Namjoon read 14 pages more than yesterday. Which student read more fairy tales in two days?",
        "answer_ko": "남준",
        "answer_en": "Namjoon",
        "solution_abst_ko": "[OP_LIST_SOL] 태형 남준 [OP_LIST_EOL] [OP_LIST_SOL] 32 13 [OP_SUB] 32 [OP_ADD] 25 14 [OP_ADD] 25 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Taehyung Namjoon [OP_LIST_EOL] [OP_LIST_SOL] 32 13 [OP_SUB] 32 [OP_ADD] 25 14 [OP_ADD] 25 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '태형'\nvar_b = '남준'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 32\nvar_d = 13\nvar_e = var_c - var_d\nvar_f = 32\nvar_g = var_e + var_f\nvar_h = 25\nvar_i = 14\nvar_j = var_h + var_i\nvar_k = 25\nvar_l = var_j + var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'Taehyung'\nvar_b = 'Namjoon'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 32\nvar_d = 13\nvar_e = var_c - var_d\nvar_f = 32\nvar_g = var_e + var_f\nvar_h = 25\nvar_i = 14\nvar_j = var_h + var_i\nvar_k = 25\nvar_l = var_j + var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "2662": {
        "category": "Arithmetic calculation",
        "question_ko": "1231, 2311, 2131, 1312, 1123, 3112를 큰 수부터 차례로 나열했을 때, 3번째로 큰 수를 쓰시오.",
        "question_en": "When 1231, 2311, 2131, 1312, 1123, and 3112 are arranged in order from largest to smallest, write the third largest number.",
        "answer_ko": "2131",
        "answer_en": "2131",
        "solution_abst_ko": "[OP_LIST_SOL] 1231 2311 2131 1312 1123 3112 [OP_LIST_EOL] 3 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1231 2311 2131 1312 1123 3112 [OP_LIST_EOL] 3 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1231\nvar_b = 2311\nvar_c = 2131\nvar_d = 1312\nvar_e = 1123\nvar_f = 3112\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_h = list_b[-var_g]\nprint(int(var_h))",
        "solution_code_en": "var_a = 1231\nvar_b = 2311\nvar_c = 2131\nvar_d = 1312\nvar_e = 1123\nvar_f = 3112\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_h = list_b[-var_g]\nprint(int(var_h))"
    },
    "2663": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 220을 빼고 4를 곱하여더니 320이 되었습니다. 어떤 수에 5배 한 뒤 3으로 나눈 값을 구하시오.",
        "question_en": "When you subtract 220 from a particular number and then multiply it by 4, you get 320. Find out the value of that particular number multiplied by 5 and then divided by 3.",
        "answer_ko": "500",
        "answer_en": "500",
        "solution_abst_ko": "320 4 [OP_DIV] 220 [OP_ADD] 5 [OP_MUL] 3 [OP_DIV]",
        "solution_abst_en": "320 4 [OP_DIV] 220 [OP_ADD] 5 [OP_MUL] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 320\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 220\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = var_e * var_f\nvar_h = 3\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 320\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 220\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = var_e * var_f\nvar_h = 3\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "2664": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 4킬로미터(㎞)인 정사각형 모양의 땅이 있습니다. 이 땅의 네 변을 각각 똑같게 둘로 나눈 점들을 이어 마름모 모양의 공원을 만들었습니다. 공원의 넓이를 구하시오.",
        "question_en": "There is a square piece of land with a side length of 4 kilometers (km). A rhombus-shaped park was created by connecting the points that divided the four sides of the land into two equally. Find the area of the park.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "4 4 [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "4 4 [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 4\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 4\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "2665": {
        "category": "Correspondence",
        "question_ko": "-0.4의 역수를 A, +5/2의 역수를 B라 할 때, 3/A+2/B의 역수를 구하시오.",
        "question_en": "If A is the reciprocal of -0.4 and B is the reciprocal of +5/2, find the reciprocal of 3/A+2/B.",
        "answer_ko": "0.26",
        "answer_en": "0.26",
        "solution_abst_ko": "1 3 1 -0.4 [OP_DIV] [OP_DIV] 2 1 5/2 [OP_DIV] [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_abst_en": "1 3 1 -0.4 [OP_DIV] [OP_DIV] 2 1 5/2 [OP_DIV] [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 1\nvar_d = -0.4\nvar_e = var_c / var_d\nvar_f = var_b / var_e\nvar_g = 2\nvar_h = 1\nvar_i = 2.5\nvar_j = var_h / var_i\nvar_k = var_g / var_j\nvar_l = var_f + var_k\nvar_m = var_a / var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 1\nvar_d = -0.4\nvar_e = var_c / var_d\nvar_f = var_b / var_e\nvar_g = 2\nvar_h = 1\nvar_i = 2.5\nvar_j = var_h / var_i\nvar_k = var_g / var_j\nvar_l = var_f + var_k\nvar_m = var_a / var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))"
    },
    "2666": {
        "category": "Geometry",
        "question_ko": "정육면체 모양의 선물 상자의 꼭짓점의 개수는?",
        "question_en": "How many vertices does the cube-shaped gift box have?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "4 2 [OP_MUL]",
        "solution_abst_en": "4 2 [OP_MUL]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "2667": {
        "category": "Geometry",
        "question_ko": "둘레는 94.2센티미터(㎝)인 원을 운동장에 그렸을 때, 지름이 30센티미터(㎝)이라면, 이 원의 둘레는 지름의 몇 배입니까?",
        "question_en": "If a circle with a circumference of 94.2 centimeters (cm) is drawn on the field and its diameter is 30 centimeters (cm), how many times the circumference of the circle is greater than the diameter?",
        "answer_ko": "3.14",
        "answer_en": "3.14",
        "solution_abst_ko": "94.2 30 [OP_DIV]",
        "solution_abst_en": "94.2 30 [OP_DIV]",
        "solution_code_ko": "var_a = 94.2\nvar_b = 30\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 94.2\nvar_b = 30\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "2668": {
        "category": "Geometry",
        "question_ko": "네 변의 길이가 모두 같은 사각형의 넓이가 64/5제곱센티미터(㎠)입니다. 한 대각선의 길이가 64/9센티미터(㎝)라면 다른 대각선의 길이는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "The area of a rectangle with the length all four sides being the same is 64/5 square centimeters (cm2). If the length of one diagonal is 64/9 centimeters (cm), what is the length of the other diagonal in cm (cm)?",
        "answer_ko": "3.60",
        "answer_en": "3.6",
        "solution_abst_ko": "64/5 2 [OP_MUL] 64/9 [OP_DIV]",
        "solution_abst_en": "64/5 2 [OP_MUL] 64/9 [OP_DIV]",
        "solution_code_ko": "var_a = 12.8\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 7.111111111111111\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 12.8\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 7.111111111111111\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "2669": {
        "category": "Arithmetic calculation",
        "question_ko": "12 부터 53 까지의 자연수의 평균은 얼마입니까?",
        "question_en": "What is the average of the natural numbers from 12 to 53?",
        "answer_ko": "32.50",
        "answer_en": "32.5",
        "solution_abst_ko": "12 53 1 [OP_LIST_ARANGE] [OP_LIST_MEAN]",
        "solution_abst_en": "12 53 1 [OP_LIST_ARANGE] [OP_LIST_MEAN]",
        "solution_code_ko": "var_a = 12\nvar_b = 53\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_a = [float(i) for i in list_a]\nvar_d = sum(list_a)/len(list_a)\nprint('{:.2f}'.format(round(var_d+1e-10,2)))",
        "solution_code_en": "var_a = 12\nvar_b = 53\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_a = [float(i) for i in list_a]\nvar_d = sum(list_a)/len(list_a)\nprint('{:.2f}'.format(round(var_d+1e-10,2)))"
    },
    "2670": {
        "category": "Possibility",
        "question_ko": "빨간 펜을 포함하는 서로 모두 다른 색인 5개의 펜이 있다. 이 중 2개는 서윤이를 주고 1개는 지우를 줄 때, 빨간 펜을 서윤이를 주는 경우의 수를 구하시오.",
        "question_en": "There are 5 pens, with all different colors, including a red pen. When two of them are given to Seoyoon and one is given to Jiwoo, find the number of cases where the red pen is given to Seoyoon.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "5 1 [OP_SUB] 2 1 [OP_SUB] 1 [OP_ADD] [OP_PERM]",
        "solution_abst_en": "5 1 [OP_SUB] 2 1 [OP_SUB] 1 [OP_ADD] [OP_PERM]",
        "solution_code_ko": "var_a = 5\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = 1\nvar_c = int(var_c)\nvar_h = int(var_h)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i * (var_c-i)\nprint(int(var_i))",
        "solution_code_en": "var_a = 5\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = 1\nvar_c = int(var_c)\nvar_h = int(var_h)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i * (var_c-i)\nprint(int(var_i))"
    },
    "2671": {
        "category": "Comparison",
        "question_ko": "5.21, 2/3 3.21, 3.42, 1/3 중 첫 번째로 작은 수와 두 번째로 작은 수의 곱을 구하면 얼마입니까?",
        "question_en": "Among 5.21, 2/3 3.21, 3.42, and 1/3, what is the product of the smallest number and the second smallest number?",
        "answer_ko": "0.22",
        "answer_en": "0.22",
        "solution_abst_ko": "[OP_LIST_SOL] 5.21 2 3 [OP_DIV] 3.21 3.42 1 3 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 5.21 2 3 [OP_DIV] 3.21 3.42 1 3 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_MUL]",
        "solution_code_ko": "var_a = 5.21\nvar_b = 2\nvar_c = 3\nvar_d = var_b / var_c\nvar_e = 3.21\nvar_f = 3.42\nvar_g = 1\nvar_h = 3\nvar_i = var_g / var_h\nlist_a= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_j = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_k = list_b[var_j-1]\nvar_l = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_m = list_c[var_l-1]\nvar_n = var_k * var_m\nprint('{:.2f}'.format(round(var_n+1e-10,2)))",
        "solution_code_en": "var_a = 5.21\nvar_b = 2\nvar_c = 3\nvar_d = var_b / var_c\nvar_e = 3.21\nvar_f = 3.42\nvar_g = 1\nvar_h = 3\nvar_i = var_g / var_h\nlist_a= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_j = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_k = list_b[var_j-1]\nvar_l = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_m = list_c[var_l-1]\nvar_n = var_k * var_m\nprint('{:.2f}'.format(round(var_n+1e-10,2)))"
    },
    "2672": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 6센티미터(㎝)인 정사각형을 몇 개 이어 붙여서 큰 정사각형을 만들었다. 큰 정사각형의 가로와 세로의 길이가 원래 길이의 3배가 되었다면, 정사각형의 넓이는 얼마나 늘어났는지 구하시오.",
        "question_en": "A large square was made by attaching several squares with a side length of 6 centimeters (cm). Find how much the square's area has increased if the length and width of the large square are three times their original length.",
        "answer_ko": "288",
        "answer_en": "288",
        "solution_abst_ko": "6 3 [OP_MUL] 2 [OP_POW] 6 2 [OP_POW] [OP_SUB]",
        "solution_abst_en": "6 3 [OP_MUL] 2 [OP_POW] 6 2 [OP_POW] [OP_SUB]",
        "solution_code_ko": "var_a = 6\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 6\nvar_g = 2\nvar_h = var_f ** var_g\nvar_i = var_e - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 6\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 6\nvar_g = 2\nvar_h = var_f ** var_g\nvar_i = var_e - var_h\nprint(int(var_i))"
    },
    "2673": {
        "category": "Arithmetic calculation",
        "question_ko": "한 상자에 16개씩 들어있는 오이를 7상자 샀습니다. 그중에서 13개는 썩어서 버리고, 남은 오이를 8봉지에 똑같이 나누어 담으려고 합니다. 한 봉지에 몇 개씩 나누어 담게 됩니까?",
        "question_en": "I bought 7 boxes of cucumbers, 16 in each box. Thirteen of them were rotten and thrown away, and the remaining cucumbers are going to be divided equally into 8 bags. How many pieces should you put in one bag?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "16 7 [OP_MUL] 13 [OP_SUB] 8 [OP_FDIV]",
        "solution_abst_en": "16 7 [OP_MUL] 13 [OP_SUB] 8 [OP_FDIV]",
        "solution_code_ko": "var_a = 16\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = var_e // var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 16\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = var_e // var_f\nprint(int(var_g))"
    },
    "2674": {
        "category": "Correspondence",
        "question_ko": "15를 어떤 수에 곱했더니 45가 되었습니다. 어떤 수에서 1을 빼면 얼마일까요?",
        "question_en": "When 15 is multiplied by a number, it is 45. What number is 1 subtracted from the number?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "45 15 [OP_DIV] 1 [OP_SUB]",
        "solution_abst_en": "45 15 [OP_DIV] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 45\nvar_b = 15\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 45\nvar_b = 15\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "2675": {
        "category": "Geometry",
        "question_ko": "어떤 직육면체를 3등분했더니 한 모서리의 길이가 6세제곱센티미터(㎤)인 정육면체 3개가 되었습니다. 원래 직육면체의 부피는 몇 세제곱센티미터(㎤)인지 구하시오.",
        "question_en": "If you divide a cuboid into 3 equal parts, you get three cubes with each edge measuring 6 centimeters (cm). Find the volume of the original cuboid in cubic centimeters (cm3).",
        "answer_ko": "648",
        "answer_en": "648",
        "solution_abst_ko": "6 3 [OP_POW] 3 [OP_MUL]",
        "solution_abst_en": "6 3 [OP_POW] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 6\nvar_b = 3\nvar_c = var_a ** var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 3\nvar_c = var_a ** var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "2676": {
        "category": "Correspondence",
        "question_ko": "8.9에서 어떤 수를 빼었더니 3.1이 되었습니다. 어떤 수에 3.1을 곱하고 다시 2.5를 곱한 값을 구하시오.",
        "question_en": "Subtracting a number from 8.9 gives 3.1. Multiply a number by 3.1 and then multiply it by 2.5 to find the value.",
        "answer_ko": "44.95",
        "answer_en": "44.95",
        "solution_abst_ko": "8.9 3.1 [OP_SUB] 3.1 [OP_MUL] 2.5 [OP_MUL]",
        "solution_abst_en": "8.9 3.1 [OP_SUB] 3.1 [OP_MUL] 2.5 [OP_MUL]",
        "solution_code_ko": "var_a = 8.9\nvar_b = 3.1\nvar_c = var_a - var_b\nvar_d = 3.1\nvar_e = var_c * var_d\nvar_f = 2.5\nvar_g = var_e * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 8.9\nvar_b = 3.1\nvar_c = var_a - var_b\nvar_d = 3.1\nvar_e = var_c * var_d\nvar_f = 2.5\nvar_g = var_e * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "2677": {
        "category": "Geometry",
        "question_ko": "가로가 262센티미터(㎝)이고 세로가 185센티미터(㎝)인 직사각형 모양의 빈 벽에 한 변이 18센티미터(㎝)인 정사각형 모양의 타일을 될 수 있는 대로 많이 붙이려고 합니다. 몇 장의 타일이 필요한지 구하시오.",
        "question_en": "You are trying to put as many square tiles as possible on a blank wall in the shape of a rectangle with 262 centimeters (cm) long and 185 centimeters (cm) wide. Find the amount of tiles you need.",
        "answer_ko": "140",
        "answer_en": "140",
        "solution_abst_ko": "262 18 [OP_FDIV] 185 18 [OP_FDIV] [OP_MUL]",
        "solution_abst_en": "262 18 [OP_FDIV] 185 18 [OP_FDIV] [OP_MUL]",
        "solution_code_ko": "var_a = 262\nvar_b = 18\nvar_c = var_a // var_b\nvar_d = 185\nvar_e = 18\nvar_f = var_d // var_e\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 262\nvar_b = 18\nvar_c = var_a // var_b\nvar_d = 185\nvar_e = 18\nvar_f = var_d // var_e\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "2678": {
        "category": "Arithmetic calculation",
        "question_ko": "장미, 백합, 튤립이 모두 합해서 100송이 있습니다. 장미는 백합보다 22송이 많고, 장미는 튤립보다 20송이 적습니다. 장미는 몇 송이 있습니까?",
        "question_en": "There are a total of 100 roses, lilies and tulips. There are 22 more roses than lilies and 20 fewer roses than tulips. How many roses are there?",
        "answer_ko": "34",
        "answer_en": "34",
        "solution_abst_ko": "100 22 [OP_ADD] 20 [OP_SUB] 3 [OP_DIV]",
        "solution_abst_en": "100 22 [OP_ADD] 20 [OP_SUB] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 100\nvar_b = 22\nvar_c = var_a + var_b\nvar_d = 20\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 100\nvar_b = 22\nvar_c = var_a + var_b\nvar_d = 20\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "2679": {
        "category": "Possibility",
        "question_ko": "호두 32개를 바구니에 남김없이 똑같이 나누어 담으려고 합니다. 바구니에 나누어 담을 수 있는 방법은 모두 몇 가지일까요? (단, 호두 32개를 바구니 한 개에 모두 담지 않습니다.)",
        "question_en": "We are going to divide 32 walnuts equally into the basket without any remainder. How many different ways can there be in a basket? (However, not all 32 walnuts are placed in one basket.)",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "32 [OP_LIST_GET_DIVISOR] [OP_LIST_SOL] 1 [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_abst_en": "32 [OP_LIST_GET_DIVISOR] [OP_LIST_SOL] 1 [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 32\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 1\nlist_b= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_b.append(var_b)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_c = len(list_c)\nprint(int(var_c))",
        "solution_code_en": "var_a = 32\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 1\nlist_b= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_b.append(var_b)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_c = len(list_c)\nprint(int(var_c))"
    },
    "2680": {
        "category": "Possibility",
        "question_ko": "어떤 수를 5와 6으로 나누면 나누어떨어지고 7로 나누면 나머지가 6이라고 합니다. 어떤 수 중에서 가장 큰 두 자리 수를 구하시오.",
        "question_en": "When a number is divided by 5 and 6, there is no remainder, but when it is divided by 7, 6 remains. Find the largest two-digit number that satisfies the condition.",
        "answer_ko": "90",
        "answer_en": "90",
        "solution_abst_ko": "10 99 1 [OP_LIST_ARANGE] 5 6 [OP_LCM] [OP_LIST_DIVISIBLE] 7 6 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MAX]",
        "solution_abst_en": "10 99 1 [OP_LIST_ARANGE] 5 6 [OP_LCM] [OP_LIST_DIVISIBLE] 7 6 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nvar_e = 6\nvar_f = var_e * var_d / math.gcd(int(var_e), int(var_d))\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nvar_g = 7\nvar_h = 6\nlist_c = [] \nvar_g = int(var_g)\nvar_h = int(var_h)\nif var_h < 0:\n    var_h = var_h + var_g\nfor i in list_b:\n    i = int(i)\n    if i%var_g == var_h:\n        list_c.append(i)\nvar_i = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_j = list_d[-var_i]\nprint(int(var_j))",
        "solution_code_en": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nvar_e = 6\nvar_f = var_e * var_d / math.gcd(int(var_e), int(var_d))\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nvar_g = 7\nvar_h = 6\nlist_c = [] \nvar_g = int(var_g)\nvar_h = int(var_h)\nif var_h < 0:\n    var_h = var_h + var_g\nfor i in list_b:\n    i = int(i)\n    if i%var_g == var_h:\n        list_c.append(i)\nvar_i = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_j = list_d[-var_i]\nprint(int(var_j))"
    },
    "2681": {
        "category": "Comparison",
        "question_ko": "A, B, C, D가 가진 동전의 개수를 비교했을 때, A는 B보다 9개가 더 많은 21개를 가지고 있었고, C는 B보다 17개 더 많이 가지고 있었습니다. A와 B의 동전 개수의 합이 C와 D동전 개수의 합보다 5개 적을 때, D가 가진 동전은 몇 개입니까?",
        "question_en": "When comparing the number of coins that A, B, C, and D have, A has 21 coins, which is 9 more than B, and C has 17 more coins than B. If the sum of the coins of A and B is 5 less than the sum of the coins of C and D, how many coins does D have?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "21 21 9 [OP_SUB] [OP_ADD] 21 9 [OP_SUB] 17 [OP_ADD] [OP_SUB] 5 [OP_ADD]",
        "solution_abst_en": "21 21 9 [OP_SUB] [OP_ADD] 21 9 [OP_SUB] 17 [OP_ADD] [OP_SUB] 5 [OP_ADD]",
        "solution_code_ko": "var_a = 21\nvar_b = 21\nvar_c = 9\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 21\nvar_g = 9\nvar_h = var_f - var_g\nvar_i = 17\nvar_j = var_h + var_i\nvar_k = var_e - var_j\nvar_l = 5\nvar_m = var_k + var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 21\nvar_b = 21\nvar_c = 9\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 21\nvar_g = 9\nvar_h = var_f - var_g\nvar_i = 17\nvar_j = var_h + var_i\nvar_k = var_e - var_j\nvar_l = 5\nvar_m = var_k + var_l\nprint(int(var_m))"
    },
    "2682": {
        "category": "Comparison",
        "question_ko": "은지는 기차에 100번째로 탔고, 유나는 은지보다 11명 앞에서 먼저 기차에 탔습니다. 유나는 몇 번째로 기차에 탔습니까?",
        "question_en": "Eunji was the 100th to get on the train, and Yuna got on the train before 11 people got on the train before Eunji. In what number did Yuna get on the train?",
        "answer_ko": "88",
        "answer_en": "88",
        "solution_abst_ko": "100 11 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "100 11 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 100\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 100\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "2683": {
        "category": "Arithmetic calculation",
        "question_ko": "학교와 효성이네 집 사이의 거리는 2.5 킬로미터(㎞) 입니다. 효성이와 미미는 각각 집과 학교에서 동시에 출발하여 일정한 빠르기로 서로를 향해 걸어갔습니다. 효성이는 1 분에 0.08 킬로미터(㎞) 를 걷고 미미는 한 시간에 2.4 킬로미터(㎞) 를 걷는다면, 15 분 후 두 사람 사이의 거리는 몇 킬로미터(㎞) 일까요?",
        "question_en": "The distance between the school and Hyosung's house is 2.5 kilometers (km). Hyoseong and Mimi started at the same time from home and school, respectively, and walked toward each other at a certain speed. If Hyosung walks at 0.08 kilometers (km) per minute and Mimi walks at 2.4 kilometers (km) per hour, how many kilometers (km) is the distance between the two people after 15 minutes?",
        "answer_ko": "0.70",
        "answer_en": "0.7",
        "solution_abst_ko": "2.5 0.08 15 [OP_MUL] [OP_SUB] 2.4 60 [OP_DIV] 15 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "2.5 0.08 15 [OP_MUL] [OP_SUB] 2.4 60 [OP_DIV] 15 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 2.5\nvar_b = 0.08\nvar_c = 15\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 2.4\nvar_g = 60\nvar_h = var_f / var_g\nvar_i = 15\nvar_j = var_h * var_i\nvar_k = var_e - var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 2.5\nvar_b = 0.08\nvar_c = 15\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 2.4\nvar_g = 60\nvar_h = var_f / var_g\nvar_i = 15\nvar_j = var_h * var_i\nvar_k = var_e - var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "2684": {
        "category": "Possibility",
        "question_ko": "숫자 카드 0, 2, 4, 5, 8 중 2장을 뽑아 만들 수 있는 두 자리 자연수의 개수를 구하시오.",
        "question_en": "Find the number of two-digit natural numbers that can be formed by drawing two of the number cards 0, 2, 4, 5, 8.",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "[OP_LIST_SOL] 0 2 4 5 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 2 4 5 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 2\nvar_c = 4\nvar_d = 5\nvar_e = 8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 0\nvar_b = 2\nvar_c = 4\nvar_d = 5\nvar_e = 8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "2685": {
        "category": "Correspondence",
        "question_ko": "유나는 42에 어떤 수를 나누려고 합니다. 실수로 8에 어떤 수를 곱했을 때의 결과가 56이라면 바르게 계산한 결과를 구하세요.",
        "question_en": "Yuna wants to divide 42 by some number. If the result of accidentally multiplying 8 by some number is 56, find the correct result.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "42 56 8 [OP_DIV] [OP_DIV]",
        "solution_abst_en": "42 56 8 [OP_DIV] [OP_DIV]",
        "solution_code_ko": "var_a = 42\nvar_b = 56\nvar_c = 8\nvar_d = var_b / var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 42\nvar_b = 56\nvar_c = 8\nvar_d = var_b / var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "2686": {
        "category": "Correspondence",
        "question_ko": "12.4A<12.45입니다. 0부터 9까지의 숫자 중에서 A에 쓸 수 있는 숫자는 모두 몇 개입니까?",
        "question_en": "12.4A<12.45. How many digits from 0 to 9 can be used for A?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "12.4A<12.45 A [OP_DIGIT_UNK_SOLVER] [OP_LIST_LEN]",
        "solution_abst_en": "12.4A<12.45 A [OP_DIGIT_UNK_SOLVER] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '12.4A<12.45'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = len(list_a)\nprint(int(var_c))",
        "solution_code_en": "var_a = '12.4A<12.45'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = len(list_a)\nprint(int(var_c))"
    },
    "2687": {
        "category": "Possibility",
        "question_ko": "세 자리 수를 만들기 위해 1, 3, 6, 7를 사용하려 합니다. 각 수는 한 번씩만 사용 가능하다면 만들 수 있는 경우는 총 몇 가지인가요?",
        "question_en": "You want to use 1, 3, 6, and 7 to make a three-digit number. If each number can only be used once, in how many ways can you make it?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 6 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 6 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 6\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 6\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "2688": {
        "category": "Geometry",
        "question_ko": "마름모의 네 변의 길이의 합이 32입니다. 한변의 길이는 얼마입니까?",
        "question_en": "The sum of the lengths of the four sides of a rhombus is 32. What is the length of one side?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "32 4 [OP_DIV]",
        "solution_abst_en": "32 4 [OP_DIV]",
        "solution_code_ko": "var_a = 32\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 32\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "2689": {
        "category": "Correspondence",
        "question_ko": "A76을 백의 자리에서 버림하면 700이 됩니다. A를 구하시오.",
        "question_en": "If you round down A76 from the hundred place, it becomes 700. Find the value of A.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "A76 [OP_GEN_POSSIBLE_LIST] 700 [OP_LIST_MORE_EQUAL] 700 100 [OP_ADD] [OP_LIST_LESS] A76 A [OP_LIST_FIND_UNK]",
        "solution_abst_en": "A76 [OP_GEN_POSSIBLE_LIST] 700 [OP_LIST_MORE_EQUAL] 700 100 [OP_ADD] [OP_LIST_LESS] A76 A [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = 'A76'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 700\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 700\nvar_d = 100\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = 'A76'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))",
        "solution_code_en": "var_a = 'A76'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 700\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 700\nvar_d = 100\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = 'A76'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))"
    },
    "2690": {
        "category": "Geometry",
        "question_ko": "정육면체의 모서리 수를 세려고 합니다. 모서리는 총 몇 개 인가요?",
        "question_en": "You want to count the number of edges of a cube. How many edges are there in total?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "6 2 [OP_SUB] 3 [OP_MUL]",
        "solution_abst_en": "6 2 [OP_SUB] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "2691": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 100까지의 수 중 3으로 나눈 나머지가 1인 값들의 합을 구하시오.",
        "question_en": "Calculate the sum of all numbers from 1 to 100 that have a remainder of 1 when divided by 3.",
        "answer_ko": "1717",
        "answer_en": "1717",
        "solution_abst_ko": "1 100 1 [OP_LIST_ARANGE] 3 1 [OP_LIST_DIVIDE_AND_REMAIN] [OP_LIST_SUM]",
        "solution_abst_en": "1 100 1 [OP_LIST_ARANGE] 3 1 [OP_LIST_DIVIDE_AND_REMAIN] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nvar_e = 1\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nvar_e = 1\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint(int(var_f))"
    },
    "2692": {
        "category": "Arithmetic calculation",
        "question_ko": "403보다 작고 285보다 큰 세 자리 수는 모두 몇 개입니까?",
        "question_en": "How many three digit numbers are there that are less than 403 and greater than 285?",
        "answer_ko": "117",
        "answer_en": "117",
        "solution_abst_ko": "285 1 [OP_ADD] 403 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_LEN]",
        "solution_abst_en": "285 1 [OP_ADD] 403 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 285\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 403\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = len(list_a)\nprint(int(var_h))",
        "solution_code_en": "var_a = 285\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 403\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = len(list_a)\nprint(int(var_h))"
    },
    "2693": {
        "category": "Arithmetic calculation",
        "question_ko": "물 135.1리터(L)가 있습니다. 이것을 7리터(L)들이 물통으로 나누어 담는다면 물통들을 가득 채우고 남는 양은 몇 밀리리터(㎖)입니까?",
        "question_en": "There are 135.1 liters (L) of water. If this is divided into 7 liters (L) buckets of water, how many milliliters (ml) are left after the buckets are full?",
        "answer_ko": "2100",
        "answer_en": "2100",
        "solution_abst_ko": "135.1 7 [OP_MOD] 1000 [OP_MUL]",
        "solution_abst_en": "135.1 7 [OP_MOD] 1000 [OP_MUL]",
        "solution_code_ko": "var_a = 135.1\nvar_b = 7\nvar_c = var_a % var_b\nvar_d = 1000\nvar_e = var_c * var_d\nprint(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))",
        "solution_code_en": "var_a = 135.1\nvar_b = 7\nvar_c = var_a % var_b\nvar_d = 1000\nvar_e = var_c * var_d\nprint(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))"
    },
    "2694": {
        "category": "Geometry",
        "question_ko": "정육면체 모양의 선물 상자의 면에서의 변의 개수는?",
        "question_en": "Find the number of faces in the tetrahedron.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "4",
        "solution_abst_en": "4",
        "solution_code_ko": "var_a = 4\nprint(int(var_a))",
        "solution_code_en": "var_a = 4\nprint(int(var_a))"
    },
    "2695": {
        "category": "Arithmetic calculation",
        "question_ko": "민영이와 호석이는 색종이를 각각 150장씩 가지고 있었습니다. 민영이는 색종이를 32장 더 사고, 호석이는 49장 더 샀다면, 호석이가 가진 색종이는 민영이보다 몇 장 더 많습니까?",
        "question_en": "Minyoung and Hoseok each had 150 pieces of colored paper. If Minyoung bought 32 more pieces of colored paper and Hoseok bought 49 more, how many more pieces of colored paper does Hoseok have than Minyoung?",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "150 49 [OP_ADD] 150 32 [OP_ADD] [OP_SUB]",
        "solution_abst_en": "150 49 [OP_ADD] 150 32 [OP_ADD] [OP_SUB]",
        "solution_code_ko": "var_a = 150\nvar_b = 49\nvar_c = var_a + var_b\nvar_d = 150\nvar_e = 32\nvar_f = var_d + var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 150\nvar_b = 49\nvar_c = var_a + var_b\nvar_d = 150\nvar_e = 32\nvar_f = var_d + var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "2696": {
        "category": "Arithmetic calculation",
        "question_ko": "0.3킬로그램(㎏)의 추 2개와 0.5킬로그램(㎏)짜리 추 한 개를 합한 것과 무게가 같은 추는 몇 킬로그램(㎏)입니까?",
        "question_en": "How many kilograms (kg) is equal to the sum of two weights of 0.3 kilograms (kg) and one weight of 0.5 kilograms (kg)?",
        "answer_ko": "1.10",
        "answer_en": "1.1",
        "solution_abst_ko": "0.5 0.3 2 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "0.5 0.3 2 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 0.5\nvar_b = 0.3\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.5\nvar_b = 0.3\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "2697": {
        "category": "Arithmetic calculation",
        "question_ko": "6년 전에 선경이가 자신과 어머니의 나이를 더하니 48이었습니다. 올해 선경이 어머니 나이는 선경이보다 3배라고 합니다. 어머니는 몇 살입니까?",
        "question_en": "Six years ago, when Sunkyung added her and her mother's ages, it was 48. This year, Sunkyung's mother is said to be three times older than Sunkyung. How old is her mother?",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "48 6 2 [OP_MUL] [OP_ADD] 1 3 [OP_ADD] [OP_DIV] 3 [OP_MUL]",
        "solution_abst_en": "48 6 2 [OP_MUL] [OP_ADD] 1 3 [OP_ADD] [OP_DIV] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 48\nvar_b = 6\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nvar_f = 1\nvar_g = 3\nvar_h = var_f + var_g\nvar_i = var_e / var_h\nvar_j = 3\nvar_k = var_i * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 48\nvar_b = 6\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nvar_f = 1\nvar_g = 3\nvar_h = var_f + var_g\nvar_i = var_e / var_h\nvar_j = 3\nvar_k = var_i * var_j\nprint(int(var_k))"
    },
    "2698": {
        "category": "Possibility",
        "question_ko": "4 장의 숫자 카드 1, 3, 4, 7 중 2 장을 뽑아 한 번씩만 사용하여 두 자리 수를 만들려고 합니다. 만들 수 있는 수 중에서 36 초과 45 이하인 수는 모두 몇 개입니까?",
        "question_en": "You want to create a two-digit number by drawing two of the four number cards 1, 3, 4, and 7, and using each card only once. How many possible numbers are greater than 36 and less than or equal to 45?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 4 7 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 36 [OP_LIST_MORE] 45 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 4 7 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 36 [OP_LIST_MORE] 45 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 4\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 36\nlist_c = []\nfor i in list_b:\n    if i > var_f:\n        list_c.append(i)\nvar_g = 45\nlist_d = []\nfor i in list_c:\n    if i <= var_g:\n        list_d.append(i)\nvar_h = len(list_d)\nprint(int(var_h))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 4\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 36\nlist_c = []\nfor i in list_b:\n    if i > var_f:\n        list_c.append(i)\nvar_g = 45\nlist_d = []\nfor i in list_c:\n    if i <= var_g:\n        list_d.append(i)\nvar_h = len(list_d)\nprint(int(var_h))"
    },
    "2699": {
        "category": "Arithmetic calculation",
        "question_ko": "지민이는 연필 12자루씩 2타와 낱개 7자루를 가지고 있습니다. 유나는 연필 12자루씩 1타와 낱개 9자루를 가지고 있습니다. 지민이와 유나가 가지고 있는 연필은 모두 몇 자루입니까?",
        "question_en": "Jimin has 2 packs of pencils and 7 individual pencils. Yuna has 1 pack of pencils and 9 individual pencils. How many pencils do Jimin and Yuna have? (However, a pack of pencils means 12 pencils.)",
        "answer_ko": "52",
        "answer_en": "52",
        "solution_abst_ko": "2 12 [OP_MUL] 7 [OP_ADD] 1 12 [OP_MUL] [OP_ADD] 9 [OP_ADD]",
        "solution_abst_en": "2 12 [OP_MUL] 7 [OP_ADD] 1 12 [OP_MUL] [OP_ADD] 9 [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c + var_d\nvar_f = 1\nvar_g = 12\nvar_h = var_f * var_g\nvar_i = var_e + var_h\nvar_j = 9\nvar_k = var_i + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 2\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c + var_d\nvar_f = 1\nvar_g = 12\nvar_h = var_f * var_g\nvar_i = var_e + var_h\nvar_j = 9\nvar_k = var_i + var_j\nprint(int(var_k))"
    },
    "2700": {
        "category": "Arithmetic calculation",
        "question_ko": "10리터(L) 들이의 통에 물이 가득 들어있습니다. 이 통에서 1리터(L) 500밀리리터(㎖) 들이의 그릇으로 물을 가득 담아 3번 덜어내고, 1리터(L) 250밀리리터(㎖) 들이의 그릇으로 물을 가득 담아 몇 번 덜어냈더니 1리터(L) 750밀리리터(㎖)의 물이 남았습니다. 1리터(L) 250밀리리터(㎖) 들이의 그릇으로 몇 번 덜어냈습니까?",
        "question_en": "There is a 10 liter (L) container filled with water. In this container, you used a full bowl with a capacity of 1 liter (L) and 500 milliliters (㎖) to take the water out three times from the container. And then you took the water out several times using a bowl with a capacity of 1 liter (L) and 250 milliliters (㎖). When 1 liter (L) and 750 milliliters (mL) of water remained in the container, how many times did you use a bowl of 1 liter (L) and 250 milliliters (㎖)?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "10 1000 [OP_MUL] 1 1000 [OP_MUL] 500 [OP_ADD] 3 [OP_MUL] [OP_SUB] 1 1000 [OP_MUL] 750 [OP_ADD] [OP_SUB] 1 1000 [OP_MUL] 250 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "10 1000 [OP_MUL] 1 1000 [OP_MUL] 500 [OP_ADD] 3 [OP_MUL] [OP_SUB] 1 1000 [OP_MUL] 750 [OP_ADD] [OP_SUB] 1 1000 [OP_MUL] 250 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = 500\nvar_h = var_f + var_g\nvar_i = 3\nvar_j = var_h * var_i\nvar_k = var_c - var_j\nvar_l = 1\nvar_m = 1000\nvar_n = var_l * var_m\nvar_o = 750\nvar_p = var_n + var_o\nvar_q = var_k - var_p\nvar_r = 1\nvar_s = 1000\nvar_t = var_r * var_s\nvar_u = 250\nvar_v = var_t + var_u\nvar_w = var_q / var_v\nprint(int(var_w))",
        "solution_code_en": "var_a = 10\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = 500\nvar_h = var_f + var_g\nvar_i = 3\nvar_j = var_h * var_i\nvar_k = var_c - var_j\nvar_l = 1\nvar_m = 1000\nvar_n = var_l * var_m\nvar_o = 750\nvar_p = var_n + var_o\nvar_q = var_k - var_p\nvar_r = 1\nvar_s = 1000\nvar_t = var_r * var_s\nvar_u = 250\nvar_v = var_t + var_u\nvar_w = var_q / var_v\nprint(int(var_w))"
    },
    "2701": {
        "category": "Arithmetic calculation",
        "question_ko": "같은 양의 설탕이 들어있는 설탕물이 2병 있습니다. 한 병의 농도는 5%이고, 다른 한 병의 농도는 8%이며 이 설탕물은 300그램(g)입니다. 두 병에 들어있는 물의 양은 몇 그램(g) 차이입니까?",
        "question_en": "There are 2 bottles of sugar water with the same amount of sugar. The concentration of one bottle is 5%, the concentration of the other bottle is 8%, and this sugar water is 300 grams (g). What is the difference between the two bottles of water in grams (g)?",
        "answer_ko": "180",
        "answer_en": "180",
        "solution_abst_ko": "300 8 100 [OP_DIV] [OP_MUL] 100 5 [OP_DIV] [OP_MUL] 300 [OP_SUB]",
        "solution_abst_en": "300 8 100 [OP_DIV] [OP_MUL] 100 5 [OP_DIV] [OP_MUL] 300 [OP_SUB]",
        "solution_code_ko": "var_a = 300\nvar_b = 8\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 100\nvar_g = 5\nvar_h = var_f / var_g\nvar_i = var_e * var_h\nvar_j = 300\nvar_k = var_i - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 300\nvar_b = 8\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 100\nvar_g = 5\nvar_h = var_f / var_g\nvar_i = var_e * var_h\nvar_j = 300\nvar_k = var_i - var_j\nprint(int(var_k))"
    },
    "2702": {
        "category": "Correspondence",
        "question_ko": "등식 57A-2B4=364이 성립한다고 합니다. A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "This equation 57A-2B4=364 is valid. What number should go in A?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "57A-2B4=364 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "57A-2B4=364 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '57A-2B4=364'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '57A-2B4=364'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "2703": {
        "category": "Arithmetic calculation",
        "question_ko": "버스가 9대, 트럭이 17대 있습니다. 트럭은 버스보다 몇 대 더 많습니까?",
        "question_en": "There are 9 buses and 17 trucks. How many more trucks are there than buses?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "17 9 [OP_SUB]",
        "solution_abst_en": "17 9 [OP_SUB]",
        "solution_code_ko": "var_a = 17\nvar_b = 9\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 17\nvar_b = 9\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "2704": {
        "category": "Correspondence",
        "question_ko": "어떤 수는 36에 4를 더한 값을 8로 나눈 몫과 17에 2배를 12로 나눈 몫을 더한 값의 2배인 수입니다. 어떤 수를 구하세요.",
        "question_en": "A number is twice the sum of the quotient of 36 added by 4 and then divided by 8 and the quotient of 17 multiplied by 2 divided by 12. Find the number.",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "36 4 [OP_ADD] 8 [OP_FDIV] 17 2 [OP_MUL] 12 [OP_FDIV] [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "36 4 [OP_ADD] 8 [OP_FDIV] 17 2 [OP_MUL] 12 [OP_FDIV] [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 36\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 8\nvar_e = var_c // var_d\nvar_f = 17\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = 12\nvar_j = var_h // var_i\nvar_k = var_e + var_j\nvar_l = 2\nvar_m = var_k * var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 36\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 8\nvar_e = var_c // var_d\nvar_f = 17\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = 12\nvar_j = var_h // var_i\nvar_k = var_e + var_j\nvar_l = 2\nvar_m = var_k * var_l\nprint(int(var_m))"
    },
    "2705": {
        "category": "Geometry",
        "question_ko": "한 변이 40미터(m)인 정사각형 모양의 공원이 있습니다. 태현이가 이 공원의 둘레를 따라 한 바퀴를 뛰었다면 태현이가 뛴 거리는 몇 미터(m)입니까?",
        "question_en": "There is a park in the shape of a square whose side is 40 meters (m). If Taehyung ran one lap along the circumference of this park, how many meters (m) did Taehyung run?",
        "answer_ko": "160",
        "answer_en": "160",
        "solution_abst_ko": "40 4 [OP_MUL]",
        "solution_abst_en": "40 4 [OP_MUL]",
        "solution_code_ko": "var_a = 40\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 40\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "2706": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 5로 나누어야 할 것을 잘못하여 어떤 수에서 5를 뺐더니 35가 되었습니다. 바르게 계산하면 얼마인지 구해보시오.",
        "question_en": "I mistakenly subtracted 5 from a number instead of dividing that number by 5, so I got 35 as a result. Find out how much it is if I calculate it correctly.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "35 5 [OP_ADD] 5 [OP_DIV]",
        "solution_abst_en": "35 5 [OP_ADD] 5 [OP_DIV]",
        "solution_code_ko": "var_a = 35\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 35\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "2707": {
        "category": "Correspondence",
        "question_ko": "지훈이가 자신의 물병에 있는 물을 효주의 물병에 152밀리리터(㎖)만큼 따라 주었다. 그럼에도 여전히 지훈이가 가지고 있는 물의 양이 효주보다 346밀리리터(㎖) 많을 때, 물을 따라주기 전에는 지훈이가 몇 밀리리터(㎖) 더 많은 물을 가지고 있었는지 구하시오.",
        "question_en": "Ji-hoon poured 152 milliliters (ml) of water from his water bottle into Hyo-joo's water bottle. Nevertheless, when Ji-hoon still has 346 milliliters (ml) more water than Hyo-ju, find out how many milliliters (ml) more water Ji-hoon had before pouring the water.",
        "answer_ko": "650",
        "answer_en": "650",
        "solution_abst_ko": "346 152 [OP_ADD] 152 [OP_ADD]",
        "solution_abst_en": "346 152 [OP_ADD] 152 [OP_ADD]",
        "solution_code_ko": "var_a = 346\nvar_b = 152\nvar_c = var_a + var_b\nvar_d = 152\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 346\nvar_b = 152\nvar_c = var_a + var_b\nvar_d = 152\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "2708": {
        "category": "Geometry",
        "question_ko": "정이십면체의 모서리는 모두 몇 개 일까요?",
        "question_en": "How many edges does a regular icosahedron have?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "30",
        "solution_abst_en": "30",
        "solution_code_ko": "var_a = 30\nprint(int(var_a))",
        "solution_code_en": "var_a = 30\nprint(int(var_a))"
    },
    "2709": {
        "category": "Geometry",
        "question_ko": "어떤 직사각형의 가로와 세로의 합이 28의 절반이었다. 이 직사각형의 가로는 6이다. 이 직사각형의 넓이를 구하시오.",
        "question_en": "The sum of the width and length of a rectangle is half of 28. This rectangle has a width of 6. Find the area of this rectangle.",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "28 2 [OP_DIV] 6 [OP_SUB] 6 [OP_MUL]",
        "solution_abst_en": "28 2 [OP_DIV] 6 [OP_SUB] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 28\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c - var_d\nvar_f = 6\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 28\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c - var_d\nvar_f = 6\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "2710": {
        "category": "Possibility",
        "question_ko": "숫자 카드 2, 5, 6, 9 중 하나를 빼고 남은 카드들을 모두 이용하여 세 자리 수를 만들고자 한다. 만들 수 있는 세 번째 큰 수와 세 번째 작은 수의 합을 구하여라.",
        "question_en": "You want to create a three-digit number by removing one from the number cards 2, 5, 6, or 9 and using all remaining ones. Find the sum of the third largest and third smallest possible numbers.",
        "answer_ko": "1221",
        "answer_en": "1221",
        "solution_abst_ko": "[OP_LIST_SOL] 2 5 6 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 2 5 6 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 5\nvar_c = 6\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 2\nvar_b = 5\nvar_c = 6\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))"
    },
    "2711": {
        "category": "Arithmetic calculation",
        "question_ko": "13명의 학생 중 6명은 여학생입니다. 남학생은 몇 명입니까?",
        "question_en": "Of the 13 students, 6 are girls. How many male students are there?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "13 6 [OP_SUB]",
        "solution_abst_en": "13 6 [OP_SUB]",
        "solution_code_ko": "var_a = 13\nvar_b = 6\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 13\nvar_b = 6\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "2712": {
        "category": "Geometry",
        "question_ko": "한 모서리의 길이가 9센티미터(㎝)인 정육면체가 있습니다. 각 꼭짓점에서 한 모서리의 길이가 2센티미터(㎝)인 정육면체를 잘랐을 때, 남은 부분의 겉넓이는 몇 제곱센티미터(㎠)입니까?",
        "question_en": "There is a cube with one edge 9 centimeters (cm) long. If you cut a cube with one edge 2 centimeters (cm) long at each vertex, what is the area in square centimeters (cm2) of the remaining area?",
        "answer_ko": "486",
        "answer_en": "486",
        "solution_abst_ko": "9 9 [OP_MUL] 6 [OP_MUL]",
        "solution_abst_en": "9 9 [OP_MUL] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 9\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "2713": {
        "category": "Comparison",
        "question_ko": "자연수가 적힌 카드를 유나, 유정, 은지가 나누어 가졌습니다. 유나가 가진 카드는 6이 적혀 있고, 유정이가 가진 카드는 8가 적혀 있습니다. 은지의 카드에 적힌 숫자는 유나 보다는 크고 유정 보다는 작습니다. 유나의 숫자 카드에 적힌 숫자는 무엇입니까?",
        "question_en": "Yuna, Yujeong, and Eunji shared cards with natural numbers inscribed. Yuna's card has a 6 written on it, and Yujeong's has an 8 written on it. The number written on Eunji's card is larger than Yuna's and smaller than Yujeong's. What is the number written on Eunji's card?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "6 8 [OP_ADD] 2 [OP_FDIV]",
        "solution_abst_en": "6 8 [OP_ADD] 2 [OP_FDIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "2714": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 9까지의 홀수를 모두 더한 값은 얼마인지 구하시오.",
        "question_en": "What is the sum of all odd numbers from 1 to 9?",
        "answer_ko": "25",
        "answer_en": "25",
        "solution_abst_ko": "1 9 [OP_LIST_ODD] [OP_LIST_SUM]",
        "solution_abst_en": "1 9 [OP_LIST_ODD] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nprint(int(var_c))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nprint(int(var_c))"
    },
    "2715": {
        "category": "Geometry",
        "question_ko": "지름이 14 센티미터(㎝)인 원을 그리려고 합니다. 컴퍼스를 몇 센티미터(㎝)가 되도록 벌려야 할까요?",
        "question_en": "You want to draw a circle with a diameter of 14 centimeters (cm). How many centimeters (cm) should the compass be spread out?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "14 2 [OP_DIV]",
        "solution_abst_en": "14 2 [OP_DIV]",
        "solution_code_ko": "var_a = 14\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 14\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "2716": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이가 자신의 키를 잴 때 잘못하여 소수점을 오른쪽으로 한 자리 옮겨서 쟀더니 원래보다 2.7센티미터(㎝) 커졌습니다. 원래의 정국이의 키를 센티미터(㎝)로 계산하시오.",
        "question_en": "When Jungkook measured his height, he made a mistake and moved the decimal point one place to the right which resulted him to be 2.7 centimeters (cm) taller than he really is. Calculate the original Jungkook's height in centimeters (cm).",
        "answer_ko": "0.30",
        "answer_en": "0.3",
        "solution_abst_ko": "2.7 10 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "2.7 10 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 2.7\nvar_b = 10\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 2.7\nvar_b = 10\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "2717": {
        "category": "Arithmetic calculation",
        "question_ko": "은서는 하나에 350원인 빨간 사탕 3개와 하나에 180원인 파란 사탕 2개를 샀습니다. 은서가 2000원을 냈을 때, 받아야 할 거스름돈은 얼마일까요?",
        "question_en": "Eunseo bought 3 red candies for 350 won each and 2 blue candies for 180 won each. When Eunseo pays 2,000 won, how much change should she receive?",
        "answer_ko": "590",
        "answer_en": "590",
        "solution_abst_ko": "2000 350 3 [OP_MUL] 180 2 [OP_MUL] [OP_ADD] [OP_SUB]",
        "solution_abst_en": "2000 350 3 [OP_MUL] 180 2 [OP_MUL] [OP_ADD] [OP_SUB]",
        "solution_code_ko": "var_a = 2000\nvar_b = 350\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = 180\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = var_d + var_g\nvar_i = var_a - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 2000\nvar_b = 350\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = 180\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = var_d + var_g\nvar_i = var_a - var_h\nprint(int(var_i))"
    },
    "2718": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 3으로 나누어야 할 것을 잘못하여 어떤 수에 3을 곱했더니 18이 되었습니다. 바르게 계산하면 얼마인지 구해보시오.",
        "question_en": "You had to divide a number by 3 but instead multiplied by 3 to get 18. Find the correctly calculated value.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "18 3 [OP_DIV] 3 [OP_DIV]",
        "solution_abst_en": "18 3 [OP_DIV] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 18\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 18\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "2719": {
        "category": "Correspondence",
        "question_ko": "어떤 수로 231.88 을 나누었더니 1.87이 되었습니다. 25로 어떤 수를 나눈 몫은 얼마인지 구하시오.",
        "question_en": "Dividing 231.88 by a certain number gives 1.87. What is the quotient of that certain number divided by 25?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "231.88 1.87 [OP_DIV] 25 [OP_FDIV]",
        "solution_abst_en": "231.88 1.87 [OP_DIV] 25 [OP_FDIV]",
        "solution_code_ko": "var_a = 231.88\nvar_b = 1.87\nvar_c = var_a / var_b\nvar_d = 25\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 231.88\nvar_b = 1.87\nvar_c = var_a / var_b\nvar_d = 25\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "2720": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 20을 곱하고 3을 더해야 할 것을 2만 곱해 22이 나왔습니다. 바르게 계산하면 얼마인가요?",
        "question_en": "If you multiply a number by 2 instead of multiply it by 20 and add 3, you get 22. How much is it when you calculate correctly?",
        "answer_ko": "223",
        "answer_en": "223",
        "solution_abst_ko": "22 2 [OP_DIV] 20 [OP_MUL] 3 [OP_ADD]",
        "solution_abst_en": "22 2 [OP_DIV] 20 [OP_MUL] 3 [OP_ADD]",
        "solution_code_ko": "var_a = 22\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 20\nvar_e = var_c * var_d\nvar_f = 3\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 22\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 20\nvar_e = var_c * var_d\nvar_f = 3\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "2721": {
        "category": "Geometry",
        "question_ko": "정삼각형의 한 변의 길이는 14/8센티미터(㎝)입니다. 이 정삼각형의 세 변의 길이의 합은 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "The length of one side of an equilateral triangle is 14/8 centimeters (cm). Find the sum of the lengths of the three sides of this equilateral triangle in centimeters (cm).",
        "answer_ko": "5.25",
        "answer_en": "5.25",
        "solution_abst_ko": "14/8 3 [OP_MUL]",
        "solution_abst_en": "14/8 3 [OP_MUL]",
        "solution_code_ko": "var_a = 1.75\nvar_b = 3\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 1.75\nvar_b = 3\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "2722": {
        "category": "Correspondence",
        "question_ko": "8을 어떤 수에 곱하였더니 결과로 64를 얻었습니다. 어떤 수에 7을 곱하면 얼마입니까?",
        "question_en": "If you multiply a number by 8, it returns 64. When the number is multiplied by 7, what does it give?",
        "answer_ko": "56",
        "answer_en": "56",
        "solution_abst_ko": "64 8 [OP_DIV] 7 [OP_MUL]",
        "solution_abst_en": "64 8 [OP_DIV] 7 [OP_MUL]",
        "solution_code_ko": "var_a = 64\nvar_b = 8\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 64\nvar_b = 8\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "2723": {
        "category": "Geometry",
        "question_ko": "유진이는 밑변이 7.2센티미터(㎝), 높이가 7센티미터(㎝) 인 삼각형 모양의 액자와 넓이가 같은 직사각형 모양의 액자를 구매하려고 합니다. 직사각형 모양 액자의 가로를 4센티미터(㎝)로 한다면 세로는 몇 센티미터(㎝)로 해야 합니까?",
        "question_en": "Eugene wants to purchase a rectangular frame with the same area as a triangular frame with a base of 7.2 centimeters (cm) and a height of 7 centimeters (cm). If the width of a rectangular picture frame is 4 centimeters (cm), how many centimeters (cm) should the length be?",
        "answer_ko": "6.30",
        "answer_en": "6.3",
        "solution_abst_ko": "7.2 7 [OP_MUL] 2 [OP_DIV] 4 [OP_DIV]",
        "solution_abst_en": "7.2 7 [OP_MUL] 2 [OP_DIV] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 7.2\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 4\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 7.2\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 4\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "2724": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 2를 뺀 후 4를 더했더니 9가 되었습니다. 어떤 수를 구하시오.",
        "question_en": "When you subtract 2 from a number and add 4, you get 9. Find the number.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "9 2 [OP_ADD] 4 [OP_SUB]",
        "solution_abst_en": "9 2 [OP_ADD] 4 [OP_SUB]",
        "solution_code_ko": "var_a = 9\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "2725": {
        "category": "Possibility",
        "question_ko": "교실에서 반장, 부반장 선거에 나온 학생은 모두 4명입니다. 4명 중 반장, 부반장을 뽑을 수 있는 방법은 모두 몇 가지입니까?",
        "question_en": "There are a total of 4 students in the classroom who have appeared in the election for class president and vice president. How many ways can a class president and vice president be selected out of four?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "4 2 [OP_PERM]",
        "solution_abst_en": "4 2 [OP_PERM]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))"
    },
    "2726": {
        "category": "Possibility",
        "question_ko": "1, 2, 6 총 3장의 수 카드 중 2장을 사용하여 두 자리 수를 만들려고 합니다. 만들 수 있는 수 중 3으로 나눠 떨어지는 수는 모두 몇 개일까요?",
        "question_en": "We are trying to make a two-digit number using 2 of our 3 number cards 1, 2, and 6. How many possible numbers are divisible by 3?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 1 2 6 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 2 6 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 2\nvar_c = 6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 3\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 2\nvar_c = 6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 3\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "2727": {
        "category": "Geometry",
        "question_ko": "정사각형 모양의 색종이를 가로와 세로 모두 10장씩 빈틈없이 늘어놓아 정사각형을 만들었습니다. 둘레에 놓인 색종이의 개수를 구하시오.",
        "question_en": "A square was created by arranging 10 square-shaped colored papers for each row and column without gaps. Find the number of colored paper placed at the perimeter.",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "10 4 [OP_MUL] 4 [OP_SUB]",
        "solution_abst_en": "10 4 [OP_MUL] 4 [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "2728": {
        "category": "Comparison",
        "question_ko": "나나의 키는 1.618미터(m) 이고, 가은이의 키는 162.3센티미터(㎝) 입니다. 키가 더 큰 사람은 누구인지 구하시오.",
        "question_en": "Nana is 1.618 meters (m) and Gaeun is 162.3 centimeters (cm). Find out who is taller.",
        "answer_ko": "가은",
        "answer_en": "Gaeun",
        "solution_abst_ko": "[OP_LIST_SOL] 나나 가은 [OP_LIST_EOL] [OP_LIST_SOL] 1.618 100 [OP_MUL] 162.3 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Nana Gaeun [OP_LIST_EOL] [OP_LIST_SOL] 1.618 100 [OP_MUL] 162.3 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '나나'\nvar_b = '가은'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.618\nvar_d = 100\nvar_e = var_c * var_d\nvar_f = 162.3\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Nana'\nvar_b = 'Gaeun'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.618\nvar_d = 100\nvar_e = var_c * var_d\nvar_f = 162.3\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "2729": {
        "category": "Possibility",
        "question_ko": "사과, 복숭아, 배를 조합하여 2개의 과일을 사려고 합니다. 중복을 허용하여 조합할 수 있는 경우의 수는 모두 몇 가지입니까?",
        "question_en": "You want to buy 2 fruits by combining apples, peaches and pears. If duplicates are allowed, how many possible combinations are there?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 복숭아 배 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] apples peaches pears [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '복숭아'\nvar_c = '배'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = var_d + var_e\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = 2\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j / (i+1)\nprint(int(var_j))",
        "solution_code_en": "var_a = 'apples'\nvar_b = 'peaches'\nvar_c = 'pears'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = var_d + var_e\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = 2\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j / (i+1)\nprint(int(var_j))"
    },
    "2730": {
        "category": "Correspondence",
        "question_ko": "20에 어떤 수를 곱하려고 합니다. 잘못하여 10에 어떤 수를 곱했더니 결과는 40이 되었습니다. 바르게 계산한 결과는 얼마일까요?",
        "question_en": "You want to multiply 20 by some number. I mistakenly multiplied 10 by the number, and the result was 40. What is the correct calculation result?",
        "answer_ko": "80",
        "answer_en": "80",
        "solution_abst_ko": "20 40 10 [OP_DIV] [OP_MUL]",
        "solution_abst_en": "20 40 10 [OP_DIV] [OP_MUL]",
        "solution_code_ko": "var_a = 20\nvar_b = 40\nvar_c = 10\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 40\nvar_c = 10\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nprint(int(var_e))"
    },
    "2731": {
        "category": "Possibility",
        "question_ko": "서로 다른 숫자 2개를 1, 4, 7, 9, 중에서 뽑아 두 자리 수를 만들려고 합니다. 그 중 가장 큰 수와 가장 작은 수의 차이를 구하시오.",
        "question_en": "You want to create a two-digit number by drawing two different numbers from among 1, 4, 7, and 9. Find the difference between the largest number and the smallest number.",
        "answer_ko": "83",
        "answer_en": "83",
        "solution_abst_ko": "[OP_LIST_SOL] 1 4 7 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 1 4 7 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 1\nvar_b = 4\nvar_c = 7\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 1\nvar_b = 4\nvar_c = 7\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))"
    },
    "2732": {
        "category": "Comparison",
        "question_ko": "화준이는 수학 시험 25문제 중에 19문제를 맞췄고, 국어 시험 16문제 중에 10문제를 맞췄습니다. 두 과목 중 정답률이 더 높은 과목은 무엇입니까?",
        "question_en": "Hwajun got 19 out of 25 questions right on the Math test and 10 out of 16 questions on the Korean test. Which of the two subjects has the highest percentage of correct answers?",
        "answer_ko": "수학",
        "answer_en": "Math",
        "solution_abst_ko": "[OP_LIST_SOL] 수학 국어 [OP_LIST_EOL] [OP_LIST_SOL] 19 25 [OP_DIV] 10 16 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Math Korean [OP_LIST_EOL] [OP_LIST_SOL] 19 25 [OP_DIV] 10 16 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '수학'\nvar_b = '국어'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 19\nvar_d = 25\nvar_e = var_c / var_d\nvar_f = 10\nvar_g = 16\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Math'\nvar_b = 'Korean'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 19\nvar_d = 25\nvar_e = var_c / var_d\nvar_f = 10\nvar_g = 16\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "2733": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 8로 나눈 후 8을 더하고, 30을 뺀 값에 6을 곱한 값이 12입니다. 어떤 수를 구하시오.",
        "question_en": "Dividing a number by 8, adding 8, subtracting 30, and multiplying by 6 is 12. Find the number.",
        "answer_ko": "192",
        "answer_en": "192",
        "solution_abst_ko": "12 6 [OP_DIV] 30 [OP_ADD] 8 [OP_SUB] 8 [OP_MUL]",
        "solution_abst_en": "12 6 [OP_DIV] 30 [OP_ADD] 8 [OP_SUB] 8 [OP_MUL]",
        "solution_code_ko": "var_a = 12\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 30\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e - var_f\nvar_h = 8\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 12\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 30\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e - var_f\nvar_h = 8\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "2734": {
        "category": "Arithmetic calculation",
        "question_ko": "영진이네 가족은 지하철과 버스를 이용하여 120킬로미터(㎞) 떨어진 할머니 댁에 1시간 50분만에 도착했습니다. 처음에는 지하철을 이용하였고, 나중에는 1시간 10분 동안 버스를 이용했습니다. 이 버스는 40.8킬로미터(㎞)를 가는 데 6리터(L)의 휘발유를 사용하였고, 영진이네 가족이 버스를 타고 있는 동안 14리터(L)의 휘발유를 사용했다면, 영진이네 가족이 지하철을 이용하여 1분 동안 이동한 거리는 몇 킬로미터(㎞)입니까? (지하철에서 버스로 갈아타기 위한 시간과 거리는 고려하지 않습니다.)",
        "question_en": "Youngjin's family arrived at their grandmother's house, which is 120 kilometers away by subway and bus, in 1 hour and 50 minutes. At first, they took the subway, and later they took the bus for 1 hour and 10 minutes. This bus used 6 liters (L) of gasoline to travel 40.8 kilometers (㎞), and if Youngjin's family used 14 liters (L) of gasoline while taking the bus, how many kilometers (km) did Youngjin's family move by taking the subway to get there in 1 minute?  (The time and distance to transfer from the subway to the bus are not taken into account.)",
        "answer_ko": "0.62",
        "answer_en": "0.62",
        "solution_abst_ko": "120 40.8 6 [OP_DIV] 14 [OP_MUL] [OP_SUB] 1 60 [OP_MUL] 50 [OP_ADD] 1 60 [OP_MUL] 10 [OP_ADD] [OP_SUB] [OP_DIV]",
        "solution_abst_en": "120 40.8 6 [OP_DIV] 14 [OP_MUL] [OP_SUB] 1 60 [OP_MUL] 50 [OP_ADD] 1 60 [OP_MUL] 10 [OP_ADD] [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 120\nvar_b = 40.8\nvar_c = 6\nvar_d = var_b / var_c\nvar_e = 14\nvar_f = var_d * var_e\nvar_g = var_a - var_f\nvar_h = 1\nvar_i = 60\nvar_j = var_h * var_i\nvar_k = 50\nvar_l = var_j + var_k\nvar_m = 1\nvar_n = 60\nvar_o = var_m * var_n\nvar_p = 10\nvar_q = var_o + var_p\nvar_r = var_l - var_q\nvar_s = var_g / var_r\nprint('{:.2f}'.format(round(var_s+1e-10,2)))",
        "solution_code_en": "var_a = 120\nvar_b = 40.8\nvar_c = 6\nvar_d = var_b / var_c\nvar_e = 14\nvar_f = var_d * var_e\nvar_g = var_a - var_f\nvar_h = 1\nvar_i = 60\nvar_j = var_h * var_i\nvar_k = 50\nvar_l = var_j + var_k\nvar_m = 1\nvar_n = 60\nvar_o = var_m * var_n\nvar_p = 10\nvar_q = var_o + var_p\nvar_r = var_l - var_q\nvar_s = var_g / var_r\nprint('{:.2f}'.format(round(var_s+1e-10,2)))"
    },
    "2735": {
        "category": "Arithmetic calculation",
        "question_ko": "사탕 72개와 젤리 56개를 네명의 학생에게 나누어 준다면 한 사람이 가지는 사탕과 젤리를 합하면 몇 개인가?",
        "question_en": "If 72 candies and 56 jellies are distributed among 4 students, how many snacks does one person have?",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "72 4 [OP_DIV] 56 4 [OP_DIV] [OP_ADD]",
        "solution_abst_en": "72 4 [OP_DIV] 56 4 [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 72\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 56\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 72\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 56\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "2736": {
        "category": "Correspondence",
        "question_ko": "39는 어떤 수에 5를 곱하고 14를 더해야 하는데 실수로 5를 빼고 14를 더한 결과입니다. 틀리게 계산한 값과 바르게 계산한 값을 더하면 얼마입니까.",
        "question_en": "39 is the wrong result of subtracting 5 and adding 14 to the number, instead of multiplying 5 and adding 14. What is the sum of the incorrect and the correct results?",
        "answer_ko": "203",
        "answer_en": "203",
        "solution_abst_ko": "39 14 [OP_SUB] 5 [OP_ADD] 5 [OP_MUL] 14 [OP_ADD] 39 [OP_ADD]",
        "solution_abst_en": "39 14 [OP_SUB] 5 [OP_ADD] 5 [OP_MUL] 14 [OP_ADD] 39 [OP_ADD]",
        "solution_code_ko": "var_a = 39\nvar_b = 14\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = var_e * var_f\nvar_h = 14\nvar_i = var_g + var_h\nvar_j = 39\nvar_k = var_i + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 39\nvar_b = 14\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = var_e * var_f\nvar_h = 14\nvar_i = var_g + var_h\nvar_j = 39\nvar_k = var_i + var_j\nprint(int(var_k))"
    },
    "2737": {
        "category": "Correspondence",
        "question_ko": "0.46 에 어떤 수를 세 번 더했더니 0.72 가 되었습니다. 어떤 수는 얼마입니까?",
        "question_en": "Adding a certain number to 0.46 three times gives you 0.72. What is the certain number?",
        "answer_ko": "0.66",
        "answer_en": "0.66",
        "solution_abst_ko": "0.72 0.46 [OP_SUB] 0.46 [OP_SUB] 0.46 [OP_SUB]",
        "solution_abst_en": "0.72 0.46 [OP_SUB] 0.46 [OP_SUB] 0.46 [OP_SUB]",
        "solution_code_ko": "var_a = 0.72\nvar_b = 0.46\nvar_c = var_a - var_b\nvar_d = 0.46\nvar_e = var_c - var_d\nvar_f = 0.46\nvar_g = var_e - var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 0.72\nvar_b = 0.46\nvar_c = var_a - var_b\nvar_d = 0.46\nvar_e = var_c - var_d\nvar_f = 0.46\nvar_g = var_e - var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "2738": {
        "category": "Arithmetic calculation",
        "question_ko": "아버지에게 형과 동생이 각각 용돈을 받았습니다. 두 사람이 받은 용돈의 합은 12000원이고, 형이 동생보다 1000원 더 많이 받았다면, 형이 받은 용돈은 얼마입니까?",
        "question_en": "My older brother and younger brother each received pocket money from my father. If the sum of their pocket money is 12,000 won, and the older brother gets 1,000 won more than the younger brother, how much does the older brother get?",
        "answer_ko": "6500",
        "answer_en": "6500",
        "solution_abst_ko": "12000 1000 [OP_SUB] 2 [OP_DIV] 1000 [OP_ADD]",
        "solution_abst_en": "12000 1000 [OP_SUB] 2 [OP_DIV] 1000 [OP_ADD]",
        "solution_code_ko": "var_a = 12000\nvar_b = 1000\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 1000\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 12000\nvar_b = 1000\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 1000\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "2739": {
        "category": "Arithmetic calculation",
        "question_ko": "32의 약수이지만 8의 약수는 아닌 수들중에서 가장 작은 수를 구하시오.",
        "question_en": "Find the smallest number that is a factor of 32 but not a factor of 8.",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "32 [OP_LIST_GET_DIVISOR] 8 [OP_LIST_GET_DIVISOR] [OP_SET_DIFFERENCE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "32 [OP_LIST_GET_DIVISOR] 8 [OP_LIST_GET_DIVISOR] [OP_SET_DIFFERENCE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 32\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 8\nlist_b = []\nnum_sqrt = int(math.sqrt(var_b))\nfor i in range(1, num_sqrt+1):\n    if var_b % i == 0:\n        list_b.append(i)\n        list_b.append(int(var_b/i))\nlist_b = sorted(set(list_b))\nlist_c = list(set(list_a) - set(list_b))\nvar_c = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_d = list_d[var_c-1]\nprint(int(var_d))",
        "solution_code_en": "var_a = 32\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 8\nlist_b = []\nnum_sqrt = int(math.sqrt(var_b))\nfor i in range(1, num_sqrt+1):\n    if var_b % i == 0:\n        list_b.append(i)\n        list_b.append(int(var_b/i))\nlist_b = sorted(set(list_b))\nlist_c = list(set(list_a) - set(list_b))\nvar_c = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_d = list_d[var_c-1]\nprint(int(var_d))"
    },
    "2740": {
        "category": "Arithmetic calculation",
        "question_ko": "검은색 바둑돌은 10개씩 3묶음 있고, 흰색 바둑돌은 낱개 16개가 있습니다. 바둑돌은 모두 몇 개 있습니까?",
        "question_en": "There are 3 groups of 10 black stones and 16 white stones. How many Go stones are there in all?",
        "answer_ko": "46",
        "answer_en": "46",
        "solution_abst_ko": "10 3 [OP_MUL] 16 [OP_ADD]",
        "solution_abst_en": "10 3 [OP_MUL] 16 [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 16\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 16\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "2741": {
        "category": "Arithmetic calculation",
        "question_ko": "37, 45, 26, 51 중에서 두번째로 큰 수보다 크고, 두번째로 작은 수보다 작은 수의 곱은 얼마입니까?",
        "question_en": "What is the product of a number that is greater than the second largest number and another number that is smaller than the second smallest number among 37, 45, 26, 51?",
        "answer_ko": "1326",
        "answer_en": "1326",
        "solution_abst_ko": "[OP_LIST_SOL] 37 45 26 51 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 37 45 26 51 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MUL]",
        "solution_code_ko": "var_a = 37\nvar_b = 45\nvar_c = 26\nvar_d = 51\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 37\nvar_b = 45\nvar_c = 26\nvar_d = 51\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f * var_h\nprint(int(var_i))"
    },
    "2742": {
        "category": "Geometry",
        "question_ko": "정십이면체의 꼭짓점의 개수는?",
        "question_en": "How many vertices of a regular dodecahedron are there?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "20",
        "solution_abst_en": "20",
        "solution_code_ko": "var_a = 20\nprint(int(var_a))",
        "solution_code_en": "var_a = 20\nprint(int(var_a))"
    },
    "2743": {
        "category": "Arithmetic calculation",
        "question_ko": "기차가 1분에 1.6킬로미터(㎞)씩 달리고 있습니다. 길이가 4.85킬로미터(㎞)인 터널을 완전히 통과하는 데 3분 15초가 걸렸다면, 기차의 길이는 몇 미터(m)입니까?",
        "question_en": "A train is running at 1.6 kilometers (km) per minute. If it took 3 minutes and 15 seconds to completely pass through a 4.85 kilometers (km) long tunnel, how long is the train in meters (m)?",
        "answer_ko": "350",
        "answer_en": "350",
        "solution_abst_ko": "1.6 3 15 60 [OP_DIV] [OP_ADD] [OP_MUL] 4.85 [OP_SUB] 1000 [OP_MUL]",
        "solution_abst_en": "1.6 3 15 60 [OP_DIV] [OP_ADD] [OP_MUL] 4.85 [OP_SUB] 1000 [OP_MUL]",
        "solution_code_ko": "var_a = 1.6\nvar_b = 3\nvar_c = 15\nvar_d = 60\nvar_e = var_c / var_d\nvar_f = var_b + var_e\nvar_g = var_a * var_f\nvar_h = 4.85\nvar_i = var_g - var_h\nvar_j = 1000\nvar_k = var_i * var_j\nprint(int(eval('{:.2f}'.format(round(var_k+1e-10,2)))))",
        "solution_code_en": "var_a = 1.6\nvar_b = 3\nvar_c = 15\nvar_d = 60\nvar_e = var_c / var_d\nvar_f = var_b + var_e\nvar_g = var_a * var_f\nvar_h = 4.85\nvar_i = var_g - var_h\nvar_j = 1000\nvar_k = var_i * var_j\nprint(int(eval('{:.2f}'.format(round(var_k+1e-10,2)))))"
    },
    "2744": {
        "category": "Possibility",
        "question_ko": "0, 1, 2, 3, 4의 숫자가 각각 적힌 5장의 카드가 있습니다. 이 카드들을 사용하여 두 자리의 정수를 만들 때 30보다 큰 수인 것은 모두 몇 개입니까?",
        "question_en": "There are 5 cards; each numbered with 0, 1, 2, 3, and 4. If you make two-digit integers using these cards, how many of them are greater than 30?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 4 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 30 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 4 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 30 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 30\nlist_c = []\nfor i in list_b:\n    if i > var_g:\n        list_c.append(i)\nvar_h = len(list_c)\nprint(int(var_h))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 30\nlist_c = []\nfor i in list_b:\n    if i > var_g:\n        list_c.append(i)\nvar_h = len(list_c)\nprint(int(var_h))"
    },
    "2745": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 23으로 나누고 67를 뺐습니다. 마지막으로 2를 곱하면 102가 된다면 어떤 수는 무엇입니까?",
        "question_en": "You divided a particular number by 23 and subtracted 67. When you multiply that by 2, you get 102, what is that particular number?",
        "answer_ko": "2714",
        "answer_en": "2714",
        "solution_abst_ko": "102 2 [OP_DIV] 67 [OP_ADD] 23 [OP_MUL]",
        "solution_abst_en": "102 2 [OP_DIV] 67 [OP_ADD] 23 [OP_MUL]",
        "solution_code_ko": "var_a = 102\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 67\nvar_e = var_c + var_d\nvar_f = 23\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 102\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 67\nvar_e = var_c + var_d\nvar_f = 23\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "2746": {
        "category": "Arithmetic calculation",
        "question_ko": "어머니의 나이는 석진이보다 32살 더 많습니다. 외삼촌의 나이는 어머니보다 3살 더 적습니다. 석진이의 나이가 12살일 때 외삼촌의 나이는 몇 살입니까?",
        "question_en": "Seokjin's mother is 32 years older than Seokjin, and his uncle is 3 years younger than his mother. When Seokjin is 12 years old, how old is his uncle?",
        "answer_ko": "41",
        "answer_en": "41",
        "solution_abst_ko": "12 32 [OP_ADD] 3 [OP_SUB]",
        "solution_abst_en": "12 32 [OP_ADD] 3 [OP_SUB]",
        "solution_code_ko": "var_a = 12\nvar_b = 32\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 32\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "2747": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 48을 뺐더니 22가 되었습니다. 어떤 수에서 32를 빼면 얼마가 되는지 구하시오.",
        "question_en": "Subtracting 48 from a number gives you 22. What is the number obtained when 32 is subtracted from a number?",
        "answer_ko": "38",
        "answer_en": "38",
        "solution_abst_ko": "22 48 [OP_ADD] 32 [OP_SUB]",
        "solution_abst_en": "22 48 [OP_ADD] 32 [OP_SUB]",
        "solution_code_ko": "var_a = 22\nvar_b = 48\nvar_c = var_a + var_b\nvar_d = 32\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 22\nvar_b = 48\nvar_c = var_a + var_b\nvar_d = 32\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "2748": {
        "category": "Correspondence",
        "question_ko": "23으로 나누면 몫이 17이 되고 나머지가 19가 되는 어떤 수가 있습니다. 어떤 수에 10을 곱한뒤 23으로 나눴을때의 몫과 나머지의 합을 구하시오.",
        "question_en": "There is a number that when it is divided by 23, the quotient is 17 and the remainder is 19. When the number is multiplied by 10 and divided by 23, find the sum of the quotient and remainder.",
        "answer_ko": "184",
        "answer_en": "184",
        "solution_abst_ko": "23 17 [OP_MUL] 19 [OP_ADD] 10 [OP_MUL] 23 [OP_FDIV] 23 17 [OP_MUL] 19 [OP_ADD] 10 [OP_MUL] 23 [OP_MOD] [OP_ADD]",
        "solution_abst_en": "23 17 [OP_MUL] 19 [OP_ADD] 10 [OP_MUL] 23 [OP_FDIV] 23 17 [OP_MUL] 19 [OP_ADD] 10 [OP_MUL] 23 [OP_MOD] [OP_ADD]",
        "solution_code_ko": "var_a = 23\nvar_b = 17\nvar_c = var_a * var_b\nvar_d = 19\nvar_e = var_c + var_d\nvar_f = 10\nvar_g = var_e * var_f\nvar_h = 23\nvar_i = var_g // var_h\nvar_j = 23\nvar_k = 17\nvar_l = var_j * var_k\nvar_m = 19\nvar_n = var_l + var_m\nvar_o = 10\nvar_p = var_n * var_o\nvar_q = 23\nvar_r = var_p % var_q\nvar_s = var_i + var_r\nprint(int(var_s))",
        "solution_code_en": "var_a = 23\nvar_b = 17\nvar_c = var_a * var_b\nvar_d = 19\nvar_e = var_c + var_d\nvar_f = 10\nvar_g = var_e * var_f\nvar_h = 23\nvar_i = var_g // var_h\nvar_j = 23\nvar_k = 17\nvar_l = var_j * var_k\nvar_m = 19\nvar_n = var_l + var_m\nvar_o = 10\nvar_p = var_n * var_o\nvar_q = 23\nvar_r = var_p % var_q\nvar_s = var_i + var_r\nprint(int(var_s))"
    },
    "2749": {
        "category": "Geometry",
        "question_ko": "모서리 12개의 합을 구했을 때 180이 되는 정육면체가 존재한다. 이 도형의 겉넓이를 구하면 얼마인가?",
        "question_en": "There exists a cube whose sum of 12 edges is 180 centimeters (cm). What is the total surface area?",
        "answer_ko": "1350",
        "answer_en": "1350",
        "solution_abst_ko": "180 12 [OP_DIV] 180 12 [OP_DIV] [OP_MUL] 6 [OP_MUL]",
        "solution_abst_en": "180 12 [OP_DIV] 180 12 [OP_DIV] [OP_MUL] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 180\nvar_b = 12\nvar_c = var_a / var_b\nvar_d = 180\nvar_e = 12\nvar_f = var_d / var_e\nvar_g = var_c * var_f\nvar_h = 6\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 180\nvar_b = 12\nvar_c = var_a / var_b\nvar_d = 180\nvar_e = 12\nvar_f = var_d / var_e\nvar_g = var_c * var_f\nvar_h = 6\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "2750": {
        "category": "Arithmetic calculation",
        "question_ko": "무게가 똑같은 추 16개를 상자에 넣고 저울에 올렸더니 17.88킬로그램(㎏)이 나왔습니다. 빈 상자의 무게가 0.6킬로그램(㎏)일 때, 추 7개의 무게는 몇 킬로그램(㎏)입니까?",
        "question_en": "When 16 weights that weigh the same were placed in a box, it came out to be 17.88 kilograms (kg). If the empty box weighs 0.6 kilograms (kg), what is the weight of the 7 weights in kilograms (kg)?",
        "answer_ko": "7.56",
        "answer_en": "7.56",
        "solution_abst_ko": "17.88 0.6 [OP_SUB] 16 [OP_DIV] 7 [OP_MUL]",
        "solution_abst_en": "17.88 0.6 [OP_SUB] 16 [OP_DIV] 7 [OP_MUL]",
        "solution_code_ko": "var_a = 17.88\nvar_b = 0.6\nvar_c = var_a - var_b\nvar_d = 16\nvar_e = var_c / var_d\nvar_f = 7\nvar_g = var_e * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 17.88\nvar_b = 0.6\nvar_c = var_a - var_b\nvar_d = 16\nvar_e = var_c / var_d\nvar_f = 7\nvar_g = var_e * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "2751": {
        "category": "Arithmetic calculation",
        "question_ko": "(가) 끈의 길이는 (다) 끈을 6개 붙인 것과 같고, (나) 끈을 5개 붙인 것과 같습니다. (나) 끈의 이가 12미터(m)일 때, (다) 끈의 길이를 구하시오.",
        "question_en": "The length of string A is equal to 6 times of string C and is equal to 5 times of string B. Find the length of string C when the length of string B is 12 meters (m).",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "12 5 [OP_MUL] 6 [OP_FDIV]",
        "solution_abst_en": "12 5 [OP_MUL] 6 [OP_FDIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "2752": {
        "category": "Possibility",
        "question_ko": "2, 4, 6, 8이 적힌 숫자 카드 4장 중 3장을 뽑아 세 자리수를 만들려고 한다. 같은 카드를 여러 번 사용해도 될 때, 만들 수 있는 모든 수들의 합은 얼마인가?",
        "question_en": "I am trying to make a three-digit number by drawing three out of four number cards with the numbers 2, 4, 6, and 8 written on them. If you can use the same card multiple times, what is the sum of all possible numbers?",
        "answer_ko": "35520",
        "answer_en": "35520",
        "solution_abst_ko": "[OP_LIST_SOL] 2 4 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 2 4 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = 6\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = 6\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint(int(var_f))"
    },
    "2753": {
        "category": "Geometry",
        "question_ko": "사각형과 오각형의 꼭짓점을 더한 값은 몇입니까?",
        "question_en": "Find the value of the sum of the vertices of the rectangle and the pentagon.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "4 5 [OP_ADD]",
        "solution_abst_en": "4 5 [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "2754": {
        "category": "Comparison",
        "question_ko": "경석은 국어를 주 7회, 각각 2/3시간씩, 수학을 주 5회, 각각 3/4시간씩 공부한다. 주중에 경석이가 국어와 수학 중 어떤 과목을 더 많이 공부하는지 구하세요.",
        "question_en": "Gyeong-seok studies Korean 7 times a week, 2/3 hours each, and Math 5 times a week, 3/4 hours each. Find out which subject Kyung-seok studies more during the week, Korean or math.",
        "answer_ko": "국어",
        "answer_en": "Korean",
        "solution_abst_ko": "[OP_LIST_SOL] 국어 수학 [OP_LIST_EOL] [OP_LIST_SOL] 2 3 [OP_DIV] 7 [OP_MUL] 3 4 [OP_DIV] 5 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Korean Math [OP_LIST_EOL] [OP_LIST_SOL] 2 3 [OP_DIV] 7 [OP_MUL] 3 4 [OP_DIV] 5 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '국어'\nvar_b = '수학'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = 7\nvar_g = var_e * var_f\nvar_h = 3\nvar_i = 4\nvar_j = var_h / var_i\nvar_k = 5\nvar_l = var_j * var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'Korean'\nvar_b = 'Math'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = 7\nvar_g = var_e * var_f\nvar_h = 3\nvar_i = 4\nvar_j = var_h / var_i\nvar_k = 5\nvar_l = var_j * var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "2755": {
        "category": "Geometry",
        "question_ko": "어떤 각뿔의 밑면이 팔각형일 때, 옆면의 수를 구하시오.",
        "question_en": "If the base of a pyramid is an octagon, find the number of sides.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "8",
        "solution_abst_en": "8",
        "solution_code_ko": "var_a = 8\nprint(int(var_a))",
        "solution_code_en": "var_a = 8\nprint(int(var_a))"
    },
    "2756": {
        "category": "Comparison",
        "question_ko": "학교에서 공원까지의 거리는 396미터(m)이고, 학교에서 약국까지의 거리는 0.389킬로미터(㎞)입니다. 공원과 약국 중 학교에서 더 가까운 곳은 어디입니까?",
        "question_en": "The distance from the school to the park is 396 meters (m), and the distance from the school to the pharmacy is 0.389 kilometers (km). Which park or pharmacy is closer to the school?",
        "answer_ko": "약국",
        "answer_en": "pharmacy",
        "solution_abst_ko": "[OP_LIST_SOL] 공원 약국 [OP_LIST_EOL] [OP_LIST_SOL] 396 0.389 1000 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] park pharmacy [OP_LIST_EOL] [OP_LIST_SOL] 396 0.389 1000 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '공원'\nvar_b = '약국'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 396\nvar_d = 0.389\nvar_e = 1000\nvar_f = var_d * var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'park'\nvar_b = 'pharmacy'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 396\nvar_d = 0.389\nvar_e = 1000\nvar_f = var_d * var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "2757": {
        "category": "Arithmetic calculation",
        "question_ko": "현진이네 학교 1학년 여학생의 수는 1학년 남학생의 수의 3/5입니다. 1학년 학생은 모두 240명일 때 1학년 남학생은 몇 명입니까?",
        "question_en": "The number of first-year female students at Hyunjin's school is 3/5 of the number of first-year male students. If there are 240 first-year students, how many first-year male students are there?",
        "answer_ko": "150",
        "answer_en": "150",
        "solution_abst_ko": "240 1 3/5 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "240 1 3/5 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 240\nvar_b = 1\nvar_c = 0.6\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 240\nvar_b = 1\nvar_c = 0.6\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "2758": {
        "category": "Geometry",
        "question_ko": "길이가 36센티미터(㎝), 42센티미터(㎝), 48센티미터(㎝)인 종이 테이프가 1장씩 있습니다. 이 종이 테이프를 각각 1/6씩 잘라내고, 남은 부분을 겹치는 부분이 같게 하여 길게 이었더니 그 길이가 97센티미터(㎝)가 되었습니다. 몇 센티미터(㎝)씩 겹쳐지게 이었습니까?",
        "question_en": "There are 1 piece of paper tape each measuring 36 centimeters (cm), 42 centimeters (cm), and 48 centimeters (cm). Each of these paper tapes was cut into 1/6 pieces, and the remaining portion was connected in a way that the overlapping portion became the same, and it resulted in a length of 97 centimeters (cm). How many centimeters (cm) did you overlap?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "36 42 [OP_ADD] 48 [OP_ADD] 1 1/6 [OP_SUB] [OP_MUL] 97 [OP_SUB] 3 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "36 42 [OP_ADD] 48 [OP_ADD] 1 1/6 [OP_SUB] [OP_MUL] 97 [OP_SUB] 3 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 36\nvar_b = 42\nvar_c = var_a + var_b\nvar_d = 48\nvar_e = var_c + var_d\nvar_f = 1\nvar_g = 0.16666666666666666\nvar_h = var_f - var_g\nvar_i = var_e * var_h\nvar_j = 97\nvar_k = var_i - var_j\nvar_l = 3\nvar_m = 1\nvar_n = var_l - var_m\nvar_o = var_k / var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 36\nvar_b = 42\nvar_c = var_a + var_b\nvar_d = 48\nvar_e = var_c + var_d\nvar_f = 1\nvar_g = 0.16666666666666666\nvar_h = var_f - var_g\nvar_i = var_e * var_h\nvar_j = 97\nvar_k = var_i - var_j\nvar_l = 3\nvar_m = 1\nvar_n = var_l - var_m\nvar_o = var_k / var_n\nprint(int(var_o))"
    },
    "2759": {
        "category": "Arithmetic calculation",
        "question_ko": "100미터(m) 길이의 도로에 10미터(m) 간격으로 나무를 심으려고 합니다. 도로의 처음과 끝에도 나무를 심는다고 할 때, 도로 양쪽에 모두 심는다면 몇 그루가 필요합니까?",
        "question_en": "You want to plant trees at intervals of 10 meters (m) on a 100-meter (m) long road. If trees are planted at the beginning and end of the road, how many trees are needed if planted on both sides of the road?",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "100 10 [OP_DIV] 1 [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "100 10 [OP_DIV] 1 [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 100\nvar_b = 10\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 100\nvar_b = 10\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "2760": {
        "category": "Possibility",
        "question_ko": "1, 2, 3, 4, 5, 6 중에서 서로 다른 숫자 2개를 뽑아서 두 자리 수를 만들려고 합니다. 서로 다른 두 자리 수를 모두 몇 개 만들 수 있습니까?",
        "question_en": "You want to create a two-digit number by picking two different numbers from 1, 2, 3, 4, 5, and 6. How many different two-digit numbers can you make?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "[OP_LIST_SOL] 1 2 3 4 5 6 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 2 3 4 5 6 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 2\nvar_c = 3\nvar_d = 4\nvar_e = 5\nvar_f = 6\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = len(list_b)\nprint(int(var_h))",
        "solution_code_en": "var_a = 1\nvar_b = 2\nvar_c = 3\nvar_d = 4\nvar_e = 5\nvar_f = 6\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = len(list_b)\nprint(int(var_h))"
    },
    "2761": {
        "category": "Comparison",
        "question_ko": "동국은 물을 하루 5번, 1회 0.2리터(L)씩 마신다. 윤지는 물을 하루 6번, 1회 0.3리터(L)씩 마신다. 희진은 물을 하루 4번, 1회 500밀리리터(㎖)씩 마신다. 하루에 물을 가장 많이 마시는 사람은?",
        "question_en": "Dongguk drinks 0.2 liters (L) of water five times a day. Yoonji drinks 0.3 liters (L) of water six times a day. Heejin drinks 500 milliliters (ml) of water four times a day. Who drinks the most water per day?",
        "answer_ko": "희진",
        "answer_en": "Heejin",
        "solution_abst_ko": "[OP_LIST_SOL] 동국 윤지 희진 [OP_LIST_EOL] [OP_LIST_SOL] 5 0.2 1000 [OP_MUL] [OP_MUL] 6 0.3 1000 [OP_MUL] [OP_MUL] 4 500 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Dongguk Yoonji Heejin [OP_LIST_EOL] [OP_LIST_SOL] 5 0.2 1000 [OP_MUL] [OP_MUL] 6 0.3 1000 [OP_MUL] [OP_MUL] 4 500 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '동국'\nvar_b = '윤지'\nvar_c = '희진'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 5\nvar_e = 0.2\nvar_f = 1000\nvar_g = var_e * var_f\nvar_h = var_d * var_g\nvar_i = 6\nvar_j = 0.3\nvar_k = 1000\nvar_l = var_j * var_k\nvar_m = var_i * var_l\nvar_n = 4\nvar_o = 500\nvar_p = var_n * var_o\nlist_b= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nlist_b.reverse()\nvar_q = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_r = list_c[-var_q]\nvar_s = list_b.index(var_r)+1\nvar_t = list_a[var_s-1]\nprint(var_t)",
        "solution_code_en": "var_a = 'Dongguk'\nvar_b = 'Yoonji'\nvar_c = 'Heejin'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 5\nvar_e = 0.2\nvar_f = 1000\nvar_g = var_e * var_f\nvar_h = var_d * var_g\nvar_i = 6\nvar_j = 0.3\nvar_k = 1000\nvar_l = var_j * var_k\nvar_m = var_i * var_l\nvar_n = 4\nvar_o = 500\nvar_p = var_n * var_o\nlist_b= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nlist_b.reverse()\nvar_q = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_r = list_c[-var_q]\nvar_s = list_b.index(var_r)+1\nvar_t = list_a[var_s-1]\nprint(var_t)"
    },
    "2762": {
        "category": "Arithmetic calculation",
        "question_ko": "7명의 학생이 줄넘기를 하고 있고, 훌라후프를 하는 학생 수는 줄넘기를 하는 학생 수의 5배입니다. 훌라후프를 하는 학생은 몇 명입니까?",
        "question_en": "Seven students are jumping rope, and the number of students doing hula hoops is five times the number of students jumping rope. How many students are doing hula hoops?",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "7 5 [OP_MUL]",
        "solution_abst_en": "7 5 [OP_MUL]",
        "solution_code_ko": "var_a = 7\nvar_b = 5\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 7\nvar_b = 5\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "2763": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 5로 나누는 문제가 있다. 이 문제를 잘못보고 8로 나누어 답을 0.65로 제출했다면 원래 답은 얼마입니까?",
        "question_en": "There is a question to divide a number by 5. I misread this question and divided it by two and submitted 0.65 as an answer. What is the correct answer?",
        "answer_ko": "1.04",
        "answer_en": "1.04",
        "solution_abst_ko": "0.65 8 [OP_MUL] 5 [OP_DIV]",
        "solution_abst_en": "0.65 8 [OP_MUL] 5 [OP_DIV]",
        "solution_code_ko": "var_a = 0.65\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.65\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "2764": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 8로 나누면 나머지가 7이고, 7로 나누면 나머지가 6이다. 또, 이 수에 1을 더하면 5로 나누어 떨어진다고 한다. 이러한 수 중 가장 작은 네 자리 수를 구하여라.",
        "question_en": "When a number is divided by 8, the remainder is 7, and when divided by 7, the remainder is 6. Also, if you add 1 to this number, it is said to be divisible by 5. Find the smallest four-digit number among these numbers.",
        "answer_ko": "1119",
        "answer_en": "1119",
        "solution_abst_ko": "1000 9999 1 [OP_LIST_ARANGE] 8 7 [OP_LIST_DIVIDE_AND_REMAIN] 7 6 [OP_LIST_DIVIDE_AND_REMAIN] 5 -1 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MIN]",
        "solution_abst_en": "1000 9999 1 [OP_LIST_ARANGE] 8 7 [OP_LIST_DIVIDE_AND_REMAIN] 7 6 [OP_LIST_DIVIDE_AND_REMAIN] 5 -1 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 8\nvar_e = 7\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 7\nvar_g = 6\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 5\nvar_i = -1\nlist_d = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_c:\n    i = int(i)\n    if i%var_h == var_i:\n        list_d.append(i)\nvar_j = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_k = list_e[var_j-1]\nprint(int(var_k))",
        "solution_code_en": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 8\nvar_e = 7\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 7\nvar_g = 6\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 5\nvar_i = -1\nlist_d = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_c:\n    i = int(i)\n    if i%var_h == var_i:\n        list_d.append(i)\nvar_j = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_k = list_e[var_j-1]\nprint(int(var_k))"
    },
    "2765": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 100까지의 수 중 3으로 나눈 나머지가 1이면서 4의 배수인 값들의 합을 구하시오.",
        "question_en": "Find the sum of all numbers from 1 to 100 that are multiples of 4 and have a remainder of 1 when divided by 3.",
        "answer_ko": "468",
        "answer_en": "468",
        "solution_abst_ko": "1 100 1 [OP_LIST_ARANGE] 3 1 [OP_LIST_DIVIDE_AND_REMAIN] 4 [OP_LIST_DIVISIBLE] [OP_LIST_SUM]",
        "solution_abst_en": "1 100 1 [OP_LIST_ARANGE] 3 1 [OP_LIST_DIVIDE_AND_REMAIN] 4 [OP_LIST_DIVISIBLE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nvar_e = 1\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 4\nlist_c = []\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nlist_c = [float(i) for i in list_c]\nvar_g = sum(list_c)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nvar_e = 1\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 4\nlist_c = []\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nlist_c = [float(i) for i in list_c]\nvar_g = sum(list_c)\nprint(int(var_g))"
    },
    "2766": {
        "category": "Geometry",
        "question_ko": "사각뿔의 면의 수를 구하시오.",
        "question_en": "Find the number of sides of the quadrangular pyramid.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "4 1 [OP_ADD]",
        "solution_abst_en": "4 1 [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "2767": {
        "category": "Correspondence",
        "question_ko": "식 3A1+2B=327이 있습니다. B에 들어가야 하는 숫자를 구하시오",
        "question_en": "There is an expression 3A1+2B=327. Find the number that goes into B",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "3A1+2B=327 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "3A1+2B=327 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '3A1+2B=327'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '3A1+2B=327'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "2768": {
        "category": "Arithmetic calculation",
        "question_ko": "박물관에 어제 입장한 사람은 247명입니다. 오늘 입장한 사람은 어제보다 131명 더 많습니다. 박물관에 어제와 오늘 입장한 사람은 모두 몇 명입니까?",
        "question_en": "247 people entered the museum yesterday. 131 more people entered today than yesterday. How many people entered the museum yesterday and today in total?",
        "answer_ko": "625",
        "answer_en": "625",
        "solution_abst_ko": "247 247 131 [OP_ADD] [OP_ADD]",
        "solution_abst_en": "247 247 131 [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 247\nvar_b = 247\nvar_c = 131\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 247\nvar_b = 247\nvar_c = 131\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "2769": {
        "category": "Arithmetic calculation",
        "question_ko": "사과 6개를 담은 가방의 무게는 1.82킬로그램(㎏)입니다. 빈 가방의 무게가 0.5킬로그램(㎏)일때 사과 한개의 무게는 몇 킬로그램(㎏)입니까?",
        "question_en": "A bag containing 6 apples weighs 1.82 kilograms (kg). How many kilograms (kg) does one apple weigh if the empty bag weighs 0.5 kilograms (kg)?",
        "answer_ko": "0.22",
        "answer_en": "0.22",
        "solution_abst_ko": "1.82 0.5 [OP_SUB] 6 [OP_DIV]",
        "solution_abst_en": "1.82 0.5 [OP_SUB] 6 [OP_DIV]",
        "solution_code_ko": "var_a = 1.82\nvar_b = 0.5\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 1.82\nvar_b = 0.5\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "2770": {
        "category": "Possibility",
        "question_ko": "5개의 숫자 7, 3, 9, 8, 1을 한 번씩만 사용하여 다섯 자리 수를 만들려고 합니다. 만들 수 있는 다섯 자리 수는 모두 몇 개입니까?",
        "question_en": "You want to create a five-digit number using the five numbers 7, 3, 9, 8, and 1 only once. How many five-digit numbers can you make?",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "[OP_LIST_SOL] 7 3 9 8 1 [OP_LIST_EOL] 5 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 7 3 9 8 1 [OP_LIST_EOL] 5 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 7\nvar_b = 3\nvar_c = 9\nvar_d = 8\nvar_e = 1\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 5\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 7\nvar_b = 3\nvar_c = 9\nvar_d = 8\nvar_e = 1\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 5\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "2771": {
        "category": "Geometry",
        "question_ko": "상우는 종이를 잘라 원 모양의 딱지를 여러 장 만드려고 합니다. 종이는 직사각형 모양으로, 가로, 세로가 각각 20센티미터(㎝), 16센티미터(㎝)입니다. 상우는 반지름이 2센티미터(㎝)인 딱지를 만들고자 할 때, 몇 개까지 만들 수 있습니까?",
        "question_en": "Sangwoo is going to cut paper to make several round-shaped tickets. The paper is rectangular, 20 centimeters (cm) wide and 16 centimeters (cm) long, respectively. If Sangwoo wants to make a ticket with a radius of 2 centimeters (cm), how many can he make?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "20 2 2 [OP_MUL] [OP_FDIV] 16 2 2 [OP_MUL] [OP_FDIV] [OP_MUL]",
        "solution_abst_en": "20 2 2 [OP_MUL] [OP_FDIV] 16 2 2 [OP_MUL] [OP_FDIV] [OP_MUL]",
        "solution_code_ko": "var_a = 20\nvar_b = 2\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a // var_d\nvar_f = 16\nvar_g = 2\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = var_f // var_i\nvar_k = var_e * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 20\nvar_b = 2\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a // var_d\nvar_f = 16\nvar_g = 2\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = var_f // var_i\nvar_k = var_e * var_j\nprint(int(var_k))"
    },
    "2772": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이는 빨간 공 3개, 윤기는 파란 공 4개를 가지고 있습니다. 전체 공의 개수는?",
        "question_en": "Jungkook has 3 red balls and Yoongi has 4 blue balls. What is the total number of balls?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "3 4 [OP_ADD]",
        "solution_abst_en": "3 4 [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 4\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 4\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "2773": {
        "category": "Geometry",
        "question_ko": "한 변이 20센티미터(㎝)인 정사각형을 실을 사용하여 만들었습니다. 이 실을 똑같이 사용하여 직사각형을 만들었습니다. 이 직사각형의 가로가 14센티미터(㎝)라면 세로는 몇 센티미터(㎝)입니까?",
        "question_en": "A square with a side of 20 centimeters (cm) was made using thread. I made a rectangle using the same thread. If the width of this rectangle is 14 centimeters (cm), how many centimeters (cm) is the length?",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "20 4 [OP_MUL] 2 [OP_DIV] 14 [OP_SUB]",
        "solution_abst_en": "20 4 [OP_MUL] 2 [OP_DIV] 14 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 14\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 20\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 14\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "2774": {
        "category": "Geometry",
        "question_ko": "밑변이 25센티미터(㎝)이고 높이가 13센티미터(㎝)인 사다리꼴의 넓이는 286제곱센티미터(㎠)입니다. 이 사다리꼴의 윗변의 길이는 몇 센티미터(㎝)인가요?",
        "question_en": "A trapezoid with a base of 25 centimeters (cm) and a height of 13 centimeters (cm) has an area of 286 square centimeters (cm2). How many centimeters (cm) is the length of the upper side of this trapezoid?",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "286 13 [OP_DIV] 2 [OP_MUL] 25 [OP_SUB]",
        "solution_abst_en": "286 13 [OP_DIV] 2 [OP_MUL] 25 [OP_SUB]",
        "solution_code_ko": "var_a = 286\nvar_b = 13\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 25\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 286\nvar_b = 13\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 25\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "2775": {
        "category": "Possibility",
        "question_ko": "사과, 복숭아, 참외 중 서로 다른 2가지 과일을 골라서 사는 경우는 모두 몇 가지 입니까?",
        "question_en": "In how many ways can you choose and buy two different fruits among an apple, a peach, and a melon?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 복숭아 참외 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] apple peach melon [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '복숭아'\nvar_c = '참외'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f / (i+1)\nprint(int(var_f))",
        "solution_code_en": "var_a = 'apple'\nvar_b = 'peach'\nvar_c = 'melon'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f / (i+1)\nprint(int(var_f))"
    },
    "2776": {
        "category": "Comparison",
        "question_ko": "달리기 시합에서 정국이는 7등을 했고, 민영이는 5등을 했습니다. 태형이는 민영이보다 못했지만 정국이보다는 잘했습니다. 태형이는 몇 등입니까?",
        "question_en": "In the running match, Jungkook placed 7th and Minyoung placed 5th. Taehyung was worse than Minyoung but better than Jungkook. What's Taehyung's ranking?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "7 5 [OP_ADD] 2 [OP_DIV]",
        "solution_abst_en": "7 5 [OP_ADD] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 7\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 7\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "2777": {
        "category": "Geometry",
        "question_ko": "밑면의 넓이가 14/5제곱센티미터(㎠)이고 부피가 28/3세제곱센티미터(㎤)인 어떤 직육면체가 있다. 이 직육면체의 높이를 구하시오.",
        "question_en": "A cuboid has a base area of 14/5 square centimeter (cm2) and a volume of 28/3 cubic centimeter (cm3). Find the height of this cuboid.",
        "answer_ko": "3.33",
        "answer_en": "3.33",
        "solution_abst_ko": "28/3 14/5 [OP_DIV]",
        "solution_abst_en": "28/3 14/5 [OP_DIV]",
        "solution_code_ko": "var_a = 9.333333333333334\nvar_b = 2.8\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 9.333333333333334\nvar_b = 2.8\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "2778": {
        "category": "Geometry",
        "question_ko": "면의 수와 꼭짓점의 수의 합이 16개인 각뿔이 있습니다. 이 각뿔의 모서리의 수는 몇 개입니까?",
        "question_en": "There is a pyramid whose sum of the number of faces and the number of vertices is 16. How many edges does this pyramid have?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "16 2 [OP_DIV] 1 [OP_SUB] 2 [OP_MUL]",
        "solution_abst_en": "16 2 [OP_DIV] 1 [OP_SUB] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 16\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 16\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "2779": {
        "category": "Arithmetic calculation",
        "question_ko": "999 이하의 모든 자연수의 합에서 99 이하의 모든 자연수들의 합을 빼면 어떤 값이 나오는지 구하시오.",
        "question_en": "What is the result of subtracting the sum of all natural numbers less than or equal to 99 from the sum of all natural numbers less than or equal to 999?",
        "answer_ko": "494550",
        "answer_en": "494550",
        "solution_abst_ko": "1 999 1 [OP_LIST_ARANGE] [OP_LIST_SUM] 1 99 1 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB]",
        "solution_abst_en": "1 999 1 [OP_LIST_ARANGE] [OP_LIST_SUM] 1 99 1 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB]",
        "solution_code_ko": "var_a = 1\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_a = [float(i) for i in list_a]\nvar_d = sum(list_a)\nvar_e = 1\nvar_f = 99\nvar_g = 1\nlist_b = [i for i in range(var_e, var_f + 1, var_g)]\nlist_b = [float(i) for i in list_b]\nvar_h = sum(list_b)\nvar_i = var_d - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_a = [float(i) for i in list_a]\nvar_d = sum(list_a)\nvar_e = 1\nvar_f = 99\nvar_g = 1\nlist_b = [i for i in range(var_e, var_f + 1, var_g)]\nlist_b = [float(i) for i in list_b]\nvar_h = sum(list_b)\nvar_i = var_d - var_h\nprint(int(var_i))"
    },
    "2780": {
        "category": "Arithmetic calculation",
        "question_ko": "무게가 똑같은 수박 16개가 들어있는 상자의 무게는 17.88킬로그램(㎏)입니다. 빈 상자의 무게가 0.6킬로그램(㎏)일 때, 수박 7개의 무게는 몇 킬로그램(㎏)입니까?",
        "question_en": "A box containing 16 watermelons of equal weight weighs 17.88 kilograms (kg). If the empty box weighs 0.6 kilograms (kg), how many kilograms (kg) do 7 watermelons weigh?",
        "answer_ko": "7.56",
        "answer_en": "7.56",
        "solution_abst_ko": "17.88 0.6 [OP_SUB] 16 [OP_DIV] 7 [OP_MUL]",
        "solution_abst_en": "17.88 0.6 [OP_SUB] 16 [OP_DIV] 7 [OP_MUL]",
        "solution_code_ko": "var_a = 17.88\nvar_b = 0.6\nvar_c = var_a - var_b\nvar_d = 16\nvar_e = var_c / var_d\nvar_f = 7\nvar_g = var_e * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 17.88\nvar_b = 0.6\nvar_c = var_a - var_b\nvar_d = 16\nvar_e = var_c / var_d\nvar_f = 7\nvar_g = var_e * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "2781": {
        "category": "Arithmetic calculation",
        "question_ko": "2개의 숫자 5.5, 9/2가 있습니다. 이들을 더하면 얼마인가요?",
        "question_en": "There are two numbers 5.5 and 9/2. How much is it when you add them up to?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "5.5 9/2 [OP_ADD]",
        "solution_abst_en": "5.5 9/2 [OP_ADD]",
        "solution_code_ko": "var_a = 5.5\nvar_b = 4.5\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5.5\nvar_b = 4.5\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "2782": {
        "category": "Comparison",
        "question_ko": "석진이가 계단으로 5층까지 가는 동안 호석이는 엘리베이터를 타고 8층에 도착했습니다. 누가 더 높이 올라갔습니까?",
        "question_en": "While Seokjin took the stairs to the 5th floor, Hoseok took the elevator to the 8th floor. Who climbed higher?",
        "answer_ko": "호석",
        "answer_en": "Hoseok",
        "solution_abst_ko": "[OP_LIST_SOL] 석진 호석 [OP_LIST_EOL] [OP_LIST_SOL] 5 8 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Seokjin Hoseok [OP_LIST_EOL] [OP_LIST_SOL] 5 8 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '석진'\nvar_b = '호석'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 5\nvar_d = 8\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Seokjin'\nvar_b = 'Hoseok'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 5\nvar_d = 8\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "2783": {
        "category": "Possibility",
        "question_ko": "0, 1, 2, 3, 4의 수가 각각 적힌 5장의 카드에서 2장을 뽑아 두 자리 정수를 만들 때 홀수는 모두 몇 개인지 구하시오",
        "question_en": " Find how many odd numbers there are when two cards are drawn from a deck of five, each with the numbers 0, 1, 2, 3, and 4, to form a two-digit integer.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 4 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 2 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 4 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 2 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 2\nlist_c = []\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if i % var_g == 0:\n        list_c.append(i)\nlist_d = list(set(list_b) - set(list_c))\nvar_h = len(list_d)\nprint(int(var_h))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 2\nlist_c = []\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if i % var_g == 0:\n        list_c.append(i)\nlist_d = list(set(list_b) - set(list_c))\nvar_h = len(list_d)\nprint(int(var_h))"
    },
    "2784": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 5, 8, 2로 나누어 떨어질 수 있는 수 중 가장 작은 세 자리 수는 무엇입니까?",
        "question_en": "What is the smallest three-digit number divisible by 5, 8, and 2?",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "100 999 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 2 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "100 999 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 2 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 8\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 2\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_h = list_e[var_g-1]\nprint(int(var_h))",
        "solution_code_en": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 8\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 2\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_h = list_e[var_g-1]\nprint(int(var_h))"
    },
    "2785": {
        "category": "Arithmetic calculation",
        "question_ko": "(가) 통에 들어있는 돌은 57개이고 그중 25개가 현무암입니다. (나) 통에 돌이 49개 들어있는데 그중 19개가 현무암입니다. (가), (나) 통에 들어있는 돌 중 현무암이 아닌 돌은 모두 몇 개입니까?",
        "question_en": "There are 57 rocks in box A, 25 of which are basalt. There are 49 rocks in box B, 19 of which are basalt. Find out the total number of the rocks in the box A and B that are not basalt.",
        "answer_ko": "62",
        "answer_en": "62",
        "solution_abst_ko": "57 25 [OP_SUB] 49 19 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "57 25 [OP_SUB] 49 19 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 57\nvar_b = 25\nvar_c = var_a - var_b\nvar_d = 49\nvar_e = 19\nvar_f = var_d - var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 57\nvar_b = 25\nvar_c = var_a - var_b\nvar_d = 49\nvar_e = 19\nvar_f = var_d - var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "2786": {
        "category": "Geometry",
        "question_ko": "사각형과 오각형의 꼭짓점의 수의 합은 몇 개입니까?",
        "question_en": "What is the sum of the vertices of the rectangle and the pentagon?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "4 5 [OP_ADD]",
        "solution_abst_en": "4 5 [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "2787": {
        "category": "Correspondence",
        "question_ko": "여덟 자리 수 757AB384는 357로 나누어떨어지는 수이다. B를 구하시오.",
        "question_en": "The eight-digit number 757AB384 is divisible by 357. Get B.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "757AB384 [OP_GEN_POSSIBLE_LIST] 357 [OP_LIST_DIVISIBLE] 757AB384 B [OP_LIST_FIND_UNK]",
        "solution_abst_en": "757AB384 [OP_GEN_POSSIBLE_LIST] 357 [OP_LIST_DIVISIBLE] 757AB384 B [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = '757AB384'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 357\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = '757AB384'\nvar_d = 'B'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nvar_e = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_e = int(elem[unk_idx])\nprint(int(var_e))",
        "solution_code_en": "var_a = '757AB384'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 357\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = '757AB384'\nvar_d = 'B'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nvar_e = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_e = int(elem[unk_idx])\nprint(int(var_e))"
    },
    "2788": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이는 토끼 5마리, 강아지 2마리를 키웁니다. 정국이가 키우는 토끼와 강아지는 총 몇 마리 인가요?",
        "question_en": "Jungkook raises 5 rabbits and 2 puppies. How many rabbits and puppies does Jungkook raise?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "5 2 [OP_ADD]",
        "solution_abst_en": "5 2 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "2789": {
        "category": "Correspondence",
        "question_ko": "어떤 수는 5로 나누어떨어지고 5로 나눈 몫은 320을 4로 나누고 220을 더한 값과 같다. 어떤 수를 3으로 나눈 값을 구하시오.",
        "question_en": "A particular number is divisible by 5, and its resulting quotient is equal to 320 divided by 4 plus 220. Find out the value of that particular number divided by 3.",
        "answer_ko": "500",
        "answer_en": "500",
        "solution_abst_ko": "320 4 [OP_DIV] 220 [OP_ADD] 5 [OP_MUL] 3 [OP_DIV]",
        "solution_abst_en": "320 4 [OP_DIV] 220 [OP_ADD] 5 [OP_MUL] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 320\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 220\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = var_e * var_f\nvar_h = 3\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 320\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 220\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = var_e * var_f\nvar_h = 3\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "2790": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 1을 더하였을때 5, 7, 8의 배수가 되는 수가 있다. 이러한 수 중 가장 작은 네자리 자연수를 구하시오.",
        "question_en": "A number when 1 is added to it becomes a multiple of 5, 7, and 8. Find the smallest four-digit natural number among these numbers.",
        "answer_ko": "1119",
        "answer_en": "1119",
        "solution_abst_ko": "1000 9999 1 [OP_LIST_ARANGE] 8 7 [OP_LIST_DIVIDE_AND_REMAIN] 7 6 [OP_LIST_DIVIDE_AND_REMAIN] 5 -1 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MIN]",
        "solution_abst_en": "1000 9999 1 [OP_LIST_ARANGE] 8 7 [OP_LIST_DIVIDE_AND_REMAIN] 7 6 [OP_LIST_DIVIDE_AND_REMAIN] 5 -1 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 8\nvar_e = 7\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 7\nvar_g = 6\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 5\nvar_i = -1\nlist_d = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_c:\n    i = int(i)\n    if i%var_h == var_i:\n        list_d.append(i)\nvar_j = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_k = list_e[var_j-1]\nprint(int(var_k))",
        "solution_code_en": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 8\nvar_e = 7\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 7\nvar_g = 6\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 5\nvar_i = -1\nlist_d = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_c:\n    i = int(i)\n    if i%var_h == var_i:\n        list_d.append(i)\nvar_j = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_k = list_e[var_j-1]\nprint(int(var_k))"
    },
    "2791": {
        "category": "Geometry",
        "question_ko": "둘레가 171센티미터(㎝) 인 정구각형이 있습니다. 이 정구각형의 한 변은 몇 센티미터(㎝) 입니까?",
        "question_en": "You have a regular nonagon with a perimeter of 171 centimeters (cm). How many centimeters (cm) is one side of this regular nonagon?",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "171 9 [OP_DIV]",
        "solution_abst_en": "171 9 [OP_DIV]",
        "solution_code_ko": "var_a = 171\nvar_b = 9\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 171\nvar_b = 9\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "2792": {
        "category": "Geometry",
        "question_ko": "가로, 세로, 높이가 1센티미터(㎝)인 정육면체를 가로로 7줄, 세로로 5줄, 높이를 3층으로 쌓아 올렸다면 전체 부피는 얼마인가?",
        "question_en": "If a cube with width, length, and height of 1 cm is stacked in 7 rows horizontally, 5 columns vertically, and 3 floors, what will be the total volume?",
        "answer_ko": "105",
        "answer_en": "105",
        "solution_abst_ko": "1 7 [OP_MUL] 1 5 [OP_MUL] [OP_MUL] 1 3 [OP_MUL] [OP_MUL]",
        "solution_abst_en": "1 7 [OP_MUL] 1 5 [OP_MUL] [OP_MUL] 1 3 [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 1\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = var_c * var_f\nvar_h = 1\nvar_i = 3\nvar_j = var_h * var_i\nvar_k = var_g * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 1\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = var_c * var_f\nvar_h = 1\nvar_i = 3\nvar_j = var_h * var_i\nvar_k = var_g * var_j\nprint(int(var_k))"
    },
    "2793": {
        "category": "Arithmetic calculation",
        "question_ko": "혁찬이네 반 학생 30명은 1번부터 30번까지 자신의 출석 번호를 가지고 있습니다. 혁찬이네 반 학생 중 안경을 쓴 학생은 1번, 3번, 7번, 10번, 23번, 27번 학생이고, 머리를 묶은 학생은 1번, 9번, 11번, 20번, 23번 학생일 때, 안경을 썼거나 머리를 묶은 학생은 몇 명입니까?",
        "question_en": "Thirty students in Hyukchan's class have their own attendance numbers from 1 to 30. Among the students in Hyeokchan's class, the students wearing glasses are students #1, #3, #7, #10, #23, and #27, and the students with hair tied are #1, #9, #11, #20, and #23. How many students wear glasses or tie their hair?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 7 10 23 27 [OP_LIST_EOL] [OP_LIST_SOL] 1 9 11 20 23 [OP_LIST_EOL] [OP_SET_UNION] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 7 10 23 27 [OP_LIST_EOL] [OP_LIST_SOL] 1 9 11 20 23 [OP_LIST_EOL] [OP_SET_UNION] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 7\nvar_d = 10\nvar_e = 23\nvar_f = 27\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 1\nvar_h = 9\nvar_i = 11\nvar_j = 20\nvar_k = 23\nlist_b= []\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nlist_c = list(set(list_a) | set(list_b))\nvar_l = len(list_c)\nprint(int(var_l))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 7\nvar_d = 10\nvar_e = 23\nvar_f = 27\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 1\nvar_h = 9\nvar_i = 11\nvar_j = 20\nvar_k = 23\nlist_b= []\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nlist_c = list(set(list_a) | set(list_b))\nvar_l = len(list_c)\nprint(int(var_l))"
    },
    "2794": {
        "category": "Correspondence",
        "question_ko": "11을 5로 나누면 나머지가 B, 몫이 A가 됩니다. 이 때 A의 값을 구하시오.",
        "question_en": "When 11 is divided by 5, the remainder is B and the quotient is A. Find the value of A at this time.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "11 5 [OP_FDIV]",
        "solution_abst_en": "11 5 [OP_FDIV]",
        "solution_code_ko": "var_a = 11\nvar_b = 5\nvar_c = var_a // var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 11\nvar_b = 5\nvar_c = var_a // var_b\nprint(int(var_c))"
    },
    "2795": {
        "category": "Correspondence",
        "question_ko": "어떤 수는 35보다 크고, 70보다 작습니다. 어떤 수를 6으로 나누면, 나머지가 3입니다. 어떤 수를 7로 나누면, 나머지가 1입니다. 어떤 수를 8로 나누면, 나머지가 1입니다. 어떤 수를 구하시오.",
        "question_en": "A number is greater than 35 and less than 70. When a number is divided by 6, the remainder is 3. When a number is divided by 7, the remainder is 1. When a number is divided by 8, the remainder is 1. Find a number.",
        "answer_ko": "57",
        "answer_en": "57",
        "solution_abst_ko": "35 1 [OP_ADD] 70 1 [OP_SUB] 1 [OP_LIST_ARANGE] 6 3 [OP_LIST_DIVIDE_AND_REMAIN] 7 1 [OP_LIST_DIVIDE_AND_REMAIN] 8 1 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "35 1 [OP_ADD] 70 1 [OP_SUB] 1 [OP_LIST_ARANGE] 6 3 [OP_LIST_DIVIDE_AND_REMAIN] 7 1 [OP_LIST_DIVIDE_AND_REMAIN] 8 1 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 35\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 70\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = 6\nvar_i = 3\nlist_b = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_a:\n    i = int(i)\n    if i%var_h == var_i:\n        list_b.append(i)\nvar_j = 7\nvar_k = 1\nlist_c = [] \nvar_j = int(var_j)\nvar_k = int(var_k)\nif var_k < 0:\n    var_k = var_k + var_j\nfor i in list_b:\n    i = int(i)\n    if i%var_j == var_k:\n        list_c.append(i)\nvar_l = 8\nvar_m = 1\nlist_d = [] \nvar_l = int(var_l)\nvar_m = int(var_m)\nif var_m < 0:\n    var_m = var_m + var_l\nfor i in list_c:\n    i = int(i)\n    if i%var_l == var_m:\n        list_d.append(i)\nvar_n = 1\nvar_o = list_d[var_n-1]\nprint(int(var_o))",
        "solution_code_en": "var_a = 35\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 70\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = 6\nvar_i = 3\nlist_b = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_a:\n    i = int(i)\n    if i%var_h == var_i:\n        list_b.append(i)\nvar_j = 7\nvar_k = 1\nlist_c = [] \nvar_j = int(var_j)\nvar_k = int(var_k)\nif var_k < 0:\n    var_k = var_k + var_j\nfor i in list_b:\n    i = int(i)\n    if i%var_j == var_k:\n        list_c.append(i)\nvar_l = 8\nvar_m = 1\nlist_d = [] \nvar_l = int(var_l)\nvar_m = int(var_m)\nif var_m < 0:\n    var_m = var_m + var_l\nfor i in list_c:\n    i = int(i)\n    if i%var_l == var_m:\n        list_d.append(i)\nvar_n = 1\nvar_o = list_d[var_n-1]\nprint(int(var_o))"
    },
    "2796": {
        "category": "Correspondence",
        "question_ko": "A, B, C는 자연수입니다. A를 7로 나누면 몫이 B고 나머지는 C입니다. 이때 B와 C는 같은 값을 가집니다. A가 될 수 있는 수 중 가장 큰수를 구하세요.",
        "question_en": "A, B, and C are natural numbers. When A is divided by 7, the quotient is B and the remainder is C. B and C here have the same value. Find the largest number that can be A.",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "7 6 [OP_MUL] 6 [OP_ADD]",
        "solution_abst_en": "7 6 [OP_MUL] 6 [OP_ADD]",
        "solution_code_ko": "var_a = 7\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 7\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "2797": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 0.5를 곱한 후 26.1을 더하고, 그 값을 0.4로 나눈 후 35를 빼면 35가 됩니다. 어떤 수를 소수점을 포함하여 구하시오.",
        "question_en": "35 comes out when you multiply a certain number by 0.5, add 26.1, divide that number by 0.4, then subtract 35. Find the number including the decimal point.",
        "answer_ko": "3.80",
        "answer_en": "3.8",
        "solution_abst_ko": "35 35 [OP_ADD] 0.4 [OP_MUL] 26.1 [OP_SUB] 0.5 [OP_DIV]",
        "solution_abst_en": "35 35 [OP_ADD] 0.4 [OP_MUL] 26.1 [OP_SUB] 0.5 [OP_DIV]",
        "solution_code_ko": "var_a = 35\nvar_b = 35\nvar_c = var_a + var_b\nvar_d = 0.4\nvar_e = var_c * var_d\nvar_f = 26.1\nvar_g = var_e - var_f\nvar_h = 0.5\nvar_i = var_g / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 35\nvar_b = 35\nvar_c = var_a + var_b\nvar_d = 0.4\nvar_e = var_c * var_d\nvar_f = 26.1\nvar_g = var_e - var_f\nvar_h = 0.5\nvar_i = var_g / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "2798": {
        "category": "Arithmetic calculation",
        "question_ko": "무게가 각각 같은 축구공 9개와 야구공 7개의 무게를 재어 보니 10.98킬로그램(㎏)이었습니다. 축구공 1개의 무게가 0.8킬로그램(㎏)일 때 팽이 한 개의 무게는 몇 킬로그램(㎏)인지 구하시오.",
        "question_en": "When nine soccer balls and seven baseballs of the same weight were weighed, they were 10.98 kilograms (kg). If one soccer ball weighs 0.8 kilograms (kg), how many kilograms (kg) does one baseball weigh?",
        "answer_ko": "0.54",
        "answer_en": "0.54",
        "solution_abst_ko": "10.98 0.8 9 [OP_MUL] [OP_SUB] 7 [OP_DIV]",
        "solution_abst_en": "10.98 0.8 9 [OP_MUL] [OP_SUB] 7 [OP_DIV]",
        "solution_code_ko": "var_a = 10.98\nvar_b = 0.8\nvar_c = 9\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 7\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 10.98\nvar_b = 0.8\nvar_c = 9\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 7\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "2799": {
        "category": "Comparison",
        "question_ko": "태형이는 유정이보다 키가 큽니다. 유정이는 지민이보다 크고, 태형이는 호석이보다 작습니다. 4명 중 가장 키가 작은 사람은 누구인가요?",
        "question_en": "Taehyung is taller than Yoojung. When Yoojung is taller than Jimin, and Taehyung is shorter than Hoseok, who is the shortest among the 4 people?",
        "answer_ko": "지민",
        "answer_en": "Jimin",
        "solution_abst_ko": "[OP_LIST_SOL] 태형 유정 지민 호석 [OP_LIST_EOL] [OP_LIST_SOL] 태형 유정 > 유정 지민 > 태형 호석 < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Taehyung Yoojung Jimin Hoseok [OP_LIST_EOL] [OP_LIST_SOL] Taehyung Yoojung > Yoojung Jimin > Taehyung Hoseok < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '태형'\nvar_b = '유정'\nvar_c = '지민'\nvar_d = '호석'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '태형'\nvar_f = '유정'\nvar_g = '>'\nvar_h = '유정'\nvar_i = '지민'\nvar_j = '>'\nvar_k = '태형'\nvar_l = '호석'\nvar_m = '<'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)",
        "solution_code_en": "var_a = 'Taehyung'\nvar_b = 'Yoojung'\nvar_c = 'Jimin'\nvar_d = 'Hoseok'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'Taehyung'\nvar_f = 'Yoojung'\nvar_g = '>'\nvar_h = 'Yoojung'\nvar_i = 'Jimin'\nvar_j = '>'\nvar_k = 'Taehyung'\nvar_l = 'Hoseok'\nvar_m = '<'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)"
    },
    "2800": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 가장 큰 수를 2번째로 큰 수로 나눈 값은 얼마입니까?",
        "question_en": "There are five numbers 10, 11, 12, 13, and 14. What is the value of the largest number divided by the second largest number?",
        "answer_ko": "1.08",
        "answer_en": "1.08",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_DIV]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[-var_h]\nvar_j = var_g / var_i\nprint('{:.2f}'.format(round(var_j+1e-10,2)))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[-var_h]\nvar_j = var_g / var_i\nprint('{:.2f}'.format(round(var_j+1e-10,2)))"
    },
    "2801": {
        "category": "Comparison",
        "question_ko": "정국, 윤기, 남준, 유나의 키를 비교하고 있습니다. 정국이가 윤기보다 크고, 남준이가 정국이보다 큽니다. 그런데 남준이가 유나보다 키가 작다면, 4명 중 누가 제일 작습니까?",
        "question_en": "We are comparing the heights of Jungkook, Yoongi, Namjoon, and Yuna. Jungkook is taller than Yoongi, and Namjoon is taller than Jungkook. But if Namjoon is shorter than Yuna, who is the shortest among the four?",
        "answer_ko": "윤기",
        "answer_en": "Yoongi",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 윤기 남준 유나 [OP_LIST_EOL] [OP_LIST_SOL] 정국 윤기 > 남준 정국 > 남준 유나 < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Yoongi Namjoon Yuna [OP_LIST_EOL] [OP_LIST_SOL] Jungkook Yoongi > Namjoon Jungkook > Namjoon Yuna < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '윤기'\nvar_c = '남준'\nvar_d = '유나'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '정국'\nvar_f = '윤기'\nvar_g = '>'\nvar_h = '남준'\nvar_i = '정국'\nvar_j = '>'\nvar_k = '남준'\nvar_l = '유나'\nvar_m = '<'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Yoongi'\nvar_c = 'Namjoon'\nvar_d = 'Yuna'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'Jungkook'\nvar_f = 'Yoongi'\nvar_g = '>'\nvar_h = 'Namjoon'\nvar_i = 'Jungkook'\nvar_j = '>'\nvar_k = 'Namjoon'\nvar_l = 'Yuna'\nvar_m = '<'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)"
    },
    "2802": {
        "category": "Possibility",
        "question_ko": "사과, 복숭아, 배, 참외, 딸기가 각각 1개씩 있는 바구니에서 2개를 뺐습니다. 나온 순서대로 번호를 붙인다면 가능한 경우의 수는 모두 몇 가지입니까?",
        "question_en": "When there is a basket containing each apple, peach, pear, melon, and strawberry, two fruits are taken out. What is the possible number of cases if those combinations are numbered according to the order it comes out?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 복숭아 배 참외 딸기 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] apple peach pear melon strawberry [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '복숭아'\nvar_c = '배'\nvar_d = '참외'\nvar_e = '딸기'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nprint(int(var_h))",
        "solution_code_en": "var_a = 'apple'\nvar_b = 'peach'\nvar_c = 'pear'\nvar_d = 'melon'\nvar_e = 'strawberry'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nprint(int(var_h))"
    },
    "2803": {
        "category": "Arithmetic calculation",
        "question_ko": "6 이하의 짝수를 한 번씩 모두 사용하여 세 자리 자연수를 만들 때, 가장 작은 수는 무엇입니까?",
        "question_en": "When you make three-digit natural numbers using even numbers less than or equal to 6, what is the smallest number?",
        "answer_ko": "204",
        "answer_en": "204",
        "solution_abst_ko": "0 6 [OP_LIST_EVEN] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]",
        "solution_abst_en": "0 6 [OP_LIST_EVEN] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 0\nvar_b = 6\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_e = list_c[var_d-1]\nprint(int(var_e))",
        "solution_code_en": "var_a = 0\nvar_b = 6\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_e = list_c[var_d-1]\nprint(int(var_e))"
    },
    "2804": {
        "category": "Arithmetic calculation",
        "question_ko": "한 바구니에 16개씩 들어있는 고구마를 7바구니 샀습니다. 그중에서 13개는 싹이 나서 버리고, 남은 고구마를 8바구니에 똑같이 나누어 담으려고 합니다. 바구니에 담기지 못하는 고구마는 몇 개입니까?",
        "question_en": "I bought 7 baskets of sweet potatoes with 16 in each basket. Among them, 13 are sprouted and discarded, and the remaining sweet potatoes are divided equally into 8 baskets. How many sweet potatoes can't be put in the basket?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "16 7 [OP_MUL] 13 [OP_SUB] 8 [OP_MOD]",
        "solution_abst_en": "16 7 [OP_MUL] 13 [OP_SUB] 8 [OP_MOD]",
        "solution_code_ko": "var_a = 16\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = var_e % var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 16\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = var_e % var_f\nprint(int(var_g))"
    },
    "2805": {
        "category": "Arithmetic calculation",
        "question_ko": "유정이 가진 나무도막의 길이는 31미터(m)보다 30센티미터(㎝) 짧습니다. 유정이가 가진 나무도막의 길이는 몇 미터(m)인지 구하시오.",
        "question_en": "The length of the wooden block that Yujeong has is 30 centimeters (cm) shorter than 31 meters (m). Find the length of the wooden block that Yujeong has in meters (m).",
        "answer_ko": "30.70",
        "answer_en": "30.7",
        "solution_abst_ko": "31 30 100 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "31 30 100 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 31\nvar_b = 30\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 31\nvar_b = 30\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "2806": {
        "category": "Correspondence",
        "question_ko": "등식 4A+B3=68이 성립한다고 합니다. 이 때, B에 들어갈 수 있는 숫자는 무엇인가요?",
        "question_en": "When the equation 4A+B3=68 holds, what number can go in B?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "4A+B3=68 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "4A+B3=68 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '4A+B3=68'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '4A+B3=68'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "2807": {
        "category": "Arithmetic calculation",
        "question_ko": "연속된 5개의 자연수를 더했더니 100이 되었습니다. 이 중 가장 작은 수는 무엇일까요?",
        "question_en": "When you add 5 consecutive natural numbers, you get 100. Which of these numbers is the smallest?",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "100 5 [OP_DIV] 5 2 [OP_FDIV] [OP_SUB]",
        "solution_abst_en": "100 5 [OP_DIV] 5 2 [OP_FDIV] [OP_SUB]",
        "solution_code_ko": "var_a = 100\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d // var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 100\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d // var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "2808": {
        "category": "Possibility",
        "question_ko": "정국이네 과일 가게는 4종류의 과일을 판매하고 있습니다. 2개를 골라서 사는 경우는 모두 몇 가지입니까?",
        "question_en": "Jungkook's fruit shop sells 4 types of fruit. How many ways can you choose to buy two?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "4 2 [OP_COMB]",
        "solution_abst_en": "4 2 [OP_COMB]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))"
    },
    "2809": {
        "category": "Arithmetic calculation",
        "question_ko": "가로가 3.944미터(m)인 벽에 가로가 29.05센티미터(㎝)인 포스터 8장을 벽의 끝과 포스터, 포스터와 포스터 사이의 간격을 일정하게 하여 한 줄로 붙이려고 합니다. 이때 사이의 간격을 몇 센티미터(㎝)로 하여야 하는지 구하시오.",
        "question_en": "You want to attach 8 posters with 29.05 centimeters (cm) width in a row on a wall with a width of 3.944 meters (m), keeping the distance between the end of the wall and the poster and between the posters constant. Find how many centimeters (cm) should be the distance between them.",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "3.944 100 [OP_MUL] 29.05 8 [OP_MUL] [OP_SUB] 8 1 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "3.944 100 [OP_MUL] 29.05 8 [OP_MUL] [OP_SUB] 8 1 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 3.944\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 29.05\nvar_e = 8\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 8\nvar_i = 1\nvar_j = var_h + var_i\nvar_k = var_g / var_j\nprint(int(eval('{:.2f}'.format(round(var_k+1e-10,2)))))",
        "solution_code_en": "var_a = 3.944\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 29.05\nvar_e = 8\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 8\nvar_i = 1\nvar_j = var_h + var_i\nvar_k = var_g / var_j\nprint(int(eval('{:.2f}'.format(round(var_k+1e-10,2)))))"
    },
    "2810": {
        "category": "Correspondence",
        "question_ko": "지민이는 34에 어떤 수를 더하려고 합니다. 실수로 5에 어떤 수를 곱했을 때의 결과가 60이라면 바르게 계산한 결과를 구하세요.",
        "question_en": "Jimin wants to add a certain number to 34. If he accidentally multiplied 5 by a certain number and the result was 60, find the correct result.",
        "answer_ko": "46",
        "answer_en": "46",
        "solution_abst_ko": "34 60 5 [OP_DIV] [OP_ADD]",
        "solution_abst_en": "34 60 5 [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 34\nvar_b = 60\nvar_c = 5\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 34\nvar_b = 60\nvar_c = 5\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "2811": {
        "category": "Geometry",
        "question_ko": "정육면체가 있을 때, 꼭지점은 총 몇개일까요?",
        "question_en": "Given a cube, how many vertices does it have?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "6 2 [OP_SUB] 2 [OP_MUL]",
        "solution_abst_en": "6 2 [OP_SUB] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "2812": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이는 (가) 물건을 585개 모았고, (가) 물건은 (나) 물건보다 249개 더 많이 모았습니다. 정국이가 모은 (가) 물건과 (나) 물건은 모두 몇 개입니까?",
        "question_en": "Jungkook collected 585 (a) items, and the number of (a) items is 249 more than (b) items. What is the sum of the items (a) and (b) that Jungkook has gathered?",
        "answer_ko": "921",
        "answer_en": "921",
        "solution_abst_ko": "585 585 249 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "585 585 249 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 585\nvar_b = 585\nvar_c = 249\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 585\nvar_b = 585\nvar_c = 249\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "2813": {
        "category": "Comparison",
        "question_ko": "희진이는 농구공을 3개, 배구공을 5개, 야구공을 1개 가지고 있다. 희진이가 제일 많이 가지고 있는 공은 무엇인가?",
        "question_en": "Heejin has 3 Basketballs, 5 Volleyballs, and 1 Baseball. What ball does Heejin have the most?",
        "answer_ko": "배구공",
        "answer_en": "Volleyballs",
        "solution_abst_ko": "[OP_LIST_SOL] 농구공 배구공 야구공 [OP_LIST_EOL] [OP_LIST_SOL] 3 5 1 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Basketballs Volleyballs Baseball [OP_LIST_EOL] [OP_LIST_SOL] 3 5 1 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '농구공'\nvar_b = '배구공'\nvar_c = '야구공'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nvar_e = 5\nvar_f = 1\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Basketballs'\nvar_b = 'Volleyballs'\nvar_c = 'Baseball'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nvar_e = 5\nvar_f = 1\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "2814": {
        "category": "Geometry",
        "question_ko": "34.8센티미터(㎝)인 끈을 모두 사용하여 사각형을 만든다. 사각형의 넓이가 가장 크게 만드려면 한 변의 길이가 얼마여야하는가?",
        "question_en": "Make a square using all the strings that are 34.8 centimeters (cm). What is the length of one side of the rectangle to make it the largest?",
        "answer_ko": "8.70",
        "answer_en": "8.7",
        "solution_abst_ko": "34.8 4 [OP_DIV]",
        "solution_abst_en": "34.8 4 [OP_DIV]",
        "solution_code_ko": "var_a = 34.8\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 34.8\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "2815": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 2를 빼야 할 것을 잘못하여 더했더니 6이 되었습니다. 바르게 계산하면 얼마입니까?",
        "question_en": "When you mistakenly add 2 to a certain number while you had to subtract 2, the result is 6. What is the value if you calculate correctly?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "6 2 [OP_SUB] 2 [OP_SUB]",
        "solution_abst_en": "6 2 [OP_SUB] 2 [OP_SUB]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "2816": {
        "category": "Arithmetic calculation",
        "question_ko": "전시회장에 입장한 사람 1260명 중 7/18은 여자입니다. 입장한 남자 중 6/11이 안경을 썼다면 공원에 방문한 안경 쓴 남자는 모두 몇 명인가요?",
        "question_en": "Of the 1,260 people who entered the exhibition hall, 7/18 were women. If 6/11 of the men who entered wore glasses, how many men that visited the exhibition hall wore glasses? ",
        "answer_ko": "420",
        "answer_en": "420",
        "solution_abst_ko": "1260 1 7/18 [OP_SUB] [OP_MUL] 6/11 [OP_MUL]",
        "solution_abst_en": "1260 1 7/18 [OP_SUB] [OP_MUL] 6/11 [OP_MUL]",
        "solution_code_ko": "var_a = 1260\nvar_b = 1\nvar_c = 0.3888888888888889\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 0.5454545454545454\nvar_g = var_e * var_f\nprint(int(eval('{:.2f}'.format(round(var_g+1e-10,2)))))",
        "solution_code_en": "var_a = 1260\nvar_b = 1\nvar_c = 0.3888888888888889\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 0.5454545454545454\nvar_g = var_e * var_f\nprint(int(eval('{:.2f}'.format(round(var_g+1e-10,2)))))"
    },
    "2817": {
        "category": "Geometry",
        "question_ko": "송이는 한 변의 길이가 13센티미터(㎝)인 정사각형 모양의 색종이를 가지고 있습니다. 이 색종이의 둘레의 길이를 구하시오.",
        "question_en": "Songi has a square-shaped piece of colored paper with a side of 13 centimeters (cm). Find the length of the circumference of this piece of paper.",
        "answer_ko": "52",
        "answer_en": "52",
        "solution_abst_ko": "13 4 [OP_MUL]",
        "solution_abst_en": "13 4 [OP_MUL]",
        "solution_code_ko": "var_a = 13\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 13\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "2818": {
        "category": "Geometry",
        "question_ko": "가로의 길이가 47.3센티미터(㎝)이고, 세로의 길이가 24센티미터(㎝)인 직사각형 모양의 창문이 있습니다. 이 창문의 넓이는 얼마입니까?",
        "question_en": "There is a rectangular window with a length of 47.3 centimeters (cm) and a width of 24 centimeters (cm). What is the area of this window?",
        "answer_ko": "1135.20",
        "answer_en": "1135.2",
        "solution_abst_ko": "47.3 24 [OP_MUL]",
        "solution_abst_en": "47.3 24 [OP_MUL]",
        "solution_code_ko": "var_a = 47.3\nvar_b = 24\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 47.3\nvar_b = 24\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "2819": {
        "category": "Correspondence",
        "question_ko": "정훈이는 어떤 숫자의 소수점 위치를 잘못보고 소수점을 기준으로 왼쪽으로 한 자리씩 이동하여 나타내었더니 원래 숫자와 37.35만큼의 차이가 났습니다. 원래의 숫자는 얼마인지 구하시오.",
        "question_en": "Jeonghoon misread the position of the decimal point in a certain number and moved the decimal point one place to the left of its original position. This resulted in the difference from the original number being 37.35. What is the original number?",
        "answer_ko": "41.5",
        "answer_en": "41.5",
        "solution_abst_ko": "37.35 9 [OP_DIV] 10 [OP_MUL]",
        "solution_abst_en": "37.35 9 [OP_DIV] 10 [OP_MUL]",
        "solution_code_ko": "var_a = 37.35\nvar_b = 9\nvar_c = var_a / var_b\nvar_d = 10\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 37.35\nvar_b = 9\nvar_c = var_a / var_b\nvar_d = 10\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "2820": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 16을 곱하고 8을 더해야 할 것을 잘못하여 16으로 나누었더니 몫이 8이고 나머지가 4였습니다. 바르게 계산한 값을 구하세요.",
        "question_en": "When we should multiply a certain number by 16 and add 8, we mistakenly divide it by 16, and the quotient is 8 and the remainder is 4. Find the correct calculated value.",
        "answer_ko": "2120",
        "answer_en": "2120",
        "solution_abst_ko": "8 16 [OP_MUL] 4 [OP_ADD] 16 [OP_MUL] 8 [OP_ADD]",
        "solution_abst_en": "8 16 [OP_MUL] 4 [OP_ADD] 16 [OP_MUL] 8 [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 16\nvar_g = var_e * var_f\nvar_h = 8\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 8\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 16\nvar_g = var_e * var_f\nvar_h = 8\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "2821": {
        "category": "Correspondence",
        "question_ko": "윤기는 어떤 수에 7을 빼려고 합니다. 하지만 실수로 5를 곱하였더니 결과는 30이 되었습니다. 바르게 계산한 결과를 구하세요.",
        "question_en": "Yoongi tries to subtract 7 from an unknown number. But when he accidentally multiplied it by 5, the result was 30. Find the correct result.",
        "answer_ko": "-1",
        "answer_en": "-1",
        "solution_abst_ko": "30 5 [OP_DIV] 7 [OP_SUB]",
        "solution_abst_en": "30 5 [OP_DIV] 7 [OP_SUB]",
        "solution_code_ko": "var_a = 30\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 30\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "2822": {
        "category": "Comparison",
        "question_ko": "발표회에서 학생들이 차례대로 발표를 합니다. 은정이는 맨 뒤에서 6번째로 발표를 하고 은정이 앞으로 7명의 학생이 발표를 할 것입니다. 발표를 하는 학생은 총 몇 명입니까?",
        "question_en": "At the presentation, students take turns giving presentations. Eunjung will be the 6th speaker from the back, and the seven students in front of Eunjung will make the presentation. How many students are giving presentations?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "6 7 [OP_ADD]",
        "solution_abst_en": "6 7 [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "2823": {
        "category": "Arithmetic calculation",
        "question_ko": "가로가 32센티미터(㎝), 세로가 74센티미터(㎝)인 직사각형 모양의 하얀 종이가 있습니다. 이 종이를 잘라 남는 부분 없이 똑같은 정사각형 모양을 여러 장 만들려고 합니다. 만들 수 있는 가장 큰 정사각형은 몇 장입니까?",
        "question_en": "There is a white piece of paper in the shape of a rectangle measuring 32 centimeters (cm) wide and 74 centimeters (cm) long. You are going to cut this paper to make several identical square shapes without any excess. How many of th elargest squares can you make?",
        "answer_ko": "592",
        "answer_en": "592",
        "solution_abst_ko": "32 32 74 [OP_GCD] [OP_FDIV] 74 32 74 [OP_GCD] [OP_FDIV] [OP_MUL]",
        "solution_abst_en": "32 32 74 [OP_GCD] [OP_FDIV] 74 32 74 [OP_GCD] [OP_FDIV] [OP_MUL]",
        "solution_code_ko": "var_a = 32\nvar_b = 32\nvar_c = 74\nvar_d = math.gcd(int(var_c), int(var_b))\nvar_e = var_a // var_d\nvar_f = 74\nvar_g = 32\nvar_h = 74\nvar_i = math.gcd(int(var_h), int(var_g))\nvar_j = var_f // var_i\nvar_k = var_e * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 32\nvar_b = 32\nvar_c = 74\nvar_d = math.gcd(int(var_c), int(var_b))\nvar_e = var_a // var_d\nvar_f = 74\nvar_g = 32\nvar_h = 74\nvar_i = math.gcd(int(var_h), int(var_g))\nvar_j = var_f // var_i\nvar_k = var_e * var_j\nprint(int(var_k))"
    },
    "2824": {
        "category": "Arithmetic calculation",
        "question_ko": "한 개에 300원인 과자와 500원인 과자를 합하여 8개를 사고 3000원을 냈습니다. 한 개에 500원인 과자는 몇 개 샀습니까?",
        "question_en": "You bought a total of 8 cookies, 300 won each and 500 won each, and paid 3,000 won. How many cookies did you buy that cost 500 won each?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "3000 300 8 [OP_MUL] [OP_SUB] 500 300 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "3000 300 8 [OP_MUL] [OP_SUB] 500 300 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 3000\nvar_b = 300\nvar_c = 8\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 500\nvar_g = 300\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 3000\nvar_b = 300\nvar_c = 8\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 500\nvar_g = 300\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "2825": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 12를 더하고 8로 나눈 수가 9입니다. 35에서 어떤 수를 반으로 나눈 값을 빼면 얼마인지 구하시오.",
        "question_en": "9 is the number you get when you add 12 to this number and divide it by 8. What is 35 minus half this number?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "35 9 8 [OP_MUL] 12 [OP_SUB] 2 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "35 9 8 [OP_MUL] 12 [OP_SUB] 2 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 35\nvar_b = 9\nvar_c = 8\nvar_d = var_b * var_c\nvar_e = 12\nvar_f = var_d - var_e\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = var_a - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 35\nvar_b = 9\nvar_c = 8\nvar_d = var_b * var_c\nvar_e = 12\nvar_f = var_d - var_e\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = var_a - var_h\nprint(int(var_i))"
    },
    "2826": {
        "category": "Arithmetic calculation",
        "question_ko": "형준이는 누나와 2살 차이가 납니다. 남매의 나이를 더했을 때 26살이었을 때, 형준이 누나의 나이는 몇 살입니까?",
        "question_en": "Hyeongjun has a two-year age gap with his older sister. If the ages of the siblings added together were 26, how old is Hyungjun's older sister?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "26 2 [OP_SUB] 2 [OP_DIV] 2 [OP_ADD]",
        "solution_abst_en": "26 2 [OP_SUB] 2 [OP_DIV] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 26\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 26\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "2827": {
        "category": "Possibility",
        "question_ko": "5개의 서로 다른 음료수를 편의점에서 팔고 있다. 그 중 세 종류를 골라 하나는 친구에게, 하나는 동생에게, 하나는 누나에게 주려고 한다. 이 상황에서의 경우의 수를 구하시오.",
        "question_en": "Five different drinks are sold in a convenience store. You are going to pick three of them and give one to your friend, one to your younger brother, and one to your older sister. Find the number of cases in this situation.",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "5 3 [OP_PERM]",
        "solution_abst_en": "5 3 [OP_PERM]",
        "solution_code_ko": "var_a = 5\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))"
    },
    "2828": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 2를 곱하고 37를 뺀 다음 8로 나누기 전에 25를 더하면 5입니다. 어떤 수는 얼마입니까?",
        "question_en": "When you multiply a number by 2, subtract it by 37, and then add it by 25 before dividing it by 8 equals 5. What is the number?",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "5 8 [OP_MUL] 25 [OP_SUB] 37 [OP_ADD] 2 [OP_DIV]",
        "solution_abst_en": "5 8 [OP_MUL] 25 [OP_SUB] 37 [OP_ADD] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 5\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 25\nvar_e = var_c - var_d\nvar_f = 37\nvar_g = var_e + var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 5\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 25\nvar_e = var_c - var_d\nvar_f = 37\nvar_g = var_e + var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "2829": {
        "category": "Geometry",
        "question_ko": "정이십면체 모양의 상자에서 꼭짓점의 개수는 몇 개 일까요?",
        "question_en": "How many vertices are there in a regular icosahedron-shaped box?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "12",
        "solution_abst_en": "12",
        "solution_code_ko": "var_a = 12\nprint(int(var_a))",
        "solution_code_en": "var_a = 12\nprint(int(var_a))"
    },
    "2830": {
        "category": "Geometry",
        "question_ko": "철사로 가로가 480센티미터(㎝), 세로가 360센티미터(㎝)인 직사각형을 만드려면 철사 몇 미터(m)가 필요한지 구하시오.",
        "question_en": "How many meters (m) of wire are needed to make a rectangle with 480 centimeters (cm) width and 360 centimeters (cm) length?",
        "answer_ko": "16.80",
        "answer_en": "16.8",
        "solution_abst_ko": "480 100 [OP_DIV] 360 100 [OP_DIV] [OP_ADD] 2 [OP_MUL] 2 [OP_ROUND]",
        "solution_abst_en": "480 100 [OP_DIV] 360 100 [OP_DIV] [OP_ADD] 2 [OP_MUL] 2 [OP_ROUND]",
        "solution_code_ko": "var_a = 480\nvar_b = 100\nvar_c = var_a / var_b\nvar_d = 360\nvar_e = 100\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = 2\nvar_k = round(float(var_i)+1e-10, var_j)\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 480\nvar_b = 100\nvar_c = var_a / var_b\nvar_d = 360\nvar_e = 100\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = 2\nvar_k = round(float(var_i)+1e-10, var_j)\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "2831": {
        "category": "Correspondence",
        "question_ko": "수근이가 낚시를 하러 갔는데 낚시줄이 너무 길어 잘라서 사용하기로 했습니다. 수근이는 원래 낚시줄을 2.5로 나누어서 사용하려 했으나 실수로 2와 2/5로 나누었더니 15/32센티미터(㎝)가 되었습니다. 수근이가 실수를 하지 않았다면 낚시줄의 길이는 몇 센티미터(㎝)일지 구하시오.",
        "question_en": "Su-geun went fishing, but the fishing line was too long, so he decided to cut it. Su-geun originally intended to divide the fishing line by 2.5, but accidentally divided it into 2 and 2/5, and it became 15/32 centimeters (cm). Find the length of the fishing line in centimeters (cm) when Su-geun did not make a mistake.",
        "answer_ko": "0.45",
        "answer_en": "0.45",
        "solution_abst_ko": "15/32 2 2/5 [OP_ADD] [OP_MUL] 2.5 [OP_DIV]",
        "solution_abst_en": "15/32 2 2/5 [OP_ADD] [OP_MUL] 2.5 [OP_DIV]",
        "solution_code_ko": "var_a = 0.46875\nvar_b = 2\nvar_c = 0.4\nvar_d = var_b + var_c\nvar_e = var_a * var_d\nvar_f = 2.5\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 0.46875\nvar_b = 2\nvar_c = 0.4\nvar_d = var_b + var_c\nvar_e = var_a * var_d\nvar_f = 2.5\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "2832": {
        "category": "Possibility",
        "question_ko": "1부터 9까지의 자연수 중 서로 다른 두 수의 합이 10보다 큰 경우의 수를 구하시오.",
        "question_en": "Find the number of ways in which the sum of two different numbers from 1 to 9 is greater than 10.",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "1 9 1 [OP_LIST_ARANGE] 2 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 10 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "1 9 1 [OP_LIST_ARANGE] 2 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 10 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 10\nlist_d = []\nfor i in list_c:\n    if i > var_f:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 10\nlist_d = []\nfor i in list_c:\n    if i > var_f:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))"
    },
    "2833": {
        "category": "Comparison",
        "question_ko": "태형, 민주, 상민, 윤정, 유정이 차례로 결승선에 진입했다. 가장 먼저 들어온 사람은?",
        "question_en": "Taehyung, Minju, Sangmin, Yoonjung, and Yoojung entered the finish line in this order. Who was the first to enter?",
        "answer_ko": "태형",
        "answer_en": "Taehyung",
        "solution_abst_ko": "[OP_LIST_SOL] 태형 민주 상민 윤정 유정 [OP_LIST_EOL] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Taehyung Minju Sangmin Yoonjung Yoojung [OP_LIST_EOL] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '태형'\nvar_b = '민주'\nvar_c = '상민'\nvar_d = '윤정'\nvar_e = '유정'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nvar_g = list_a[var_f-1]\nprint(var_g)",
        "solution_code_en": "var_a = 'Taehyung'\nvar_b = 'Minju'\nvar_c = 'Sangmin'\nvar_d = 'Yoonjung'\nvar_e = 'Yoojung'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nvar_g = list_a[var_f-1]\nprint(var_g)"
    },
    "2834": {
        "category": "Comparison",
        "question_ko": "블루베리청 3, 2/6숟가락과 자몽청 21/6숟가락으로 에이드를 만들었어요. 에이드는 블루베리청과 자몽청 중 어느 것을 더 많이 포함하는지 구하십시오.",
        "question_en": "I made an ade with 3, 2/6 spoons of blueberry syrup, and 21/6 spoons of grapefruit syrup. Find out which syrup is contained more in the ade, the blueberry syrup or the grapefruit syrup?",
        "answer_ko": "자몽청",
        "answer_en": "grapefruit",
        "solution_abst_ko": "[OP_LIST_SOL] 블루베리청 자몽청 [OP_LIST_EOL] [OP_LIST_SOL] 3 2 6 [OP_DIV] [OP_ADD] 21 6 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] blueberry grapefruit [OP_LIST_EOL] [OP_LIST_SOL] 3 2 6 [OP_DIV] [OP_ADD] 21 6 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '블루베리청'\nvar_b = '자몽청'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nvar_d = 2\nvar_e = 6\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nvar_h = 21\nvar_i = 6\nvar_j = var_h / var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'blueberry'\nvar_b = 'grapefruit'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nvar_d = 2\nvar_e = 6\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nvar_h = 21\nvar_i = 6\nvar_j = var_h / var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "2835": {
        "category": "Arithmetic calculation",
        "question_ko": "보미는 350 원짜리 사탕 한 개와 500 원짜리 초콜릿 한 개를 사고 1000 원을 냈습니다. 보미가 받아야 할 거스름돈은 얼마입니까?",
        "question_en": "Bomi bought candy for 350 won and chocolate for 500 won and paid 1,000 won. How much change should Bomi get?",
        "answer_ko": "150",
        "answer_en": "150",
        "solution_abst_ko": "1000 350 [OP_SUB] 500 [OP_SUB]",
        "solution_abst_en": "1000 350 [OP_SUB] 500 [OP_SUB]",
        "solution_code_ko": "var_a = 1000\nvar_b = 350\nvar_c = var_a - var_b\nvar_d = 500\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 1000\nvar_b = 350\nvar_c = var_a - var_b\nvar_d = 500\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "2836": {
        "category": "Arithmetic calculation",
        "question_ko": "현주는 빨간색 테이프를 3/4미터(m), 파란색 테이프를 4/5미터(m), 노란색 테이프를 2/3미터(m) 가지고 있습니다. 현주가 가지고 있는 색 테이프는 모두 몇 미터(m)인지 구하시오.",
        "question_en": "Hyunjoo has 3/4 meter (m) of red tape, 4/5 meter (m) of blue tape, and 2/3 meter (m) of yellow tape. Find how many meters (m) all the colored tapes Hyeonju has.",
        "answer_ko": "2.22",
        "answer_en": "2.22",
        "solution_abst_ko": "3/4 4/5 [OP_ADD] 2/3 [OP_ADD]",
        "solution_abst_en": "3/4 4/5 [OP_ADD] 2/3 [OP_ADD]",
        "solution_code_ko": "var_a = 0.75\nvar_b = 0.8\nvar_c = var_a + var_b\nvar_d = 0.6666666666666666\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.75\nvar_b = 0.8\nvar_c = var_a + var_b\nvar_d = 0.6666666666666666\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "2837": {
        "category": "Arithmetic calculation",
        "question_ko": "둘레가 1킬로미터(㎞) 500미터(m)인 공원에 나무를 30미터(m) 간격으로 심으려고 합니다. 나무 한 그루의 값이 5000원일 때, 필요한 나무를 사는 데 드는 비용은 얼마입니까?",
        "question_en": "In a park with a circumference of 1 kilometer (km) and 500 meters (m), trees are to be planted at intervals of 30 meters (m). If the cost of one tree is 5,000 mill, how much does it cost to buy the tree you need?",
        "answer_ko": "250000",
        "answer_en": "250000",
        "solution_abst_ko": "1 1000 [OP_MUL] 500 [OP_ADD] 30 [OP_DIV] 5000 [OP_MUL]",
        "solution_abst_en": "1 1000 [OP_MUL] 500 [OP_ADD] 30 [OP_DIV] 5000 [OP_MUL]",
        "solution_code_ko": "var_a = 1\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 500\nvar_e = var_c + var_d\nvar_f = 30\nvar_g = var_e / var_f\nvar_h = 5000\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 500\nvar_e = var_c + var_d\nvar_f = 30\nvar_g = var_e / var_f\nvar_h = 5000\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "2838": {
        "category": "Comparison",
        "question_ko": "버스 정류장에 버스를 기다리는 9명의 학생들이 한 줄로 서 있습니다. 뒤에서 2번째 학생과 앞에서 3번째 학생 사이의 학생은 몇 명입니까?",
        "question_en": "Nine students are standing in a line at the bus stop waiting for the bus. How many students are between the second student from the back and the third student from the front?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "9 3 [OP_SUB] 2 [OP_SUB]",
        "solution_abst_en": "9 3 [OP_SUB] 2 [OP_SUB]",
        "solution_code_ko": "var_a = 9\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "2839": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 30센티미터(㎝)인 양초는 분당 1센티미터(㎝)씩 줄어들고, 길이가 20센티미터(㎝)인 양초는 분당 0.5센티미터(㎝)씩 길이가 줄어든다고 한다. 두 양초의 길이가 같아졌을 때 양초의 길이를 구하여라",
        "question_en": "It is said that a 30 centimeters (cm) long candle shrinks by 1 centimeter (cm) per minute, and a 20 centimeters (cm) long candle shrinks by 0.5 centimeters (cm) per minute. Find the length of the candle when both candles become equally long.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "30 30 20 [OP_SUB] 1 0.5 [OP_SUB] [OP_DIV] [OP_SUB]",
        "solution_abst_en": "30 30 20 [OP_SUB] 1 0.5 [OP_SUB] [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 30\nvar_b = 30\nvar_c = 20\nvar_d = var_b - var_c\nvar_e = 1\nvar_f = 0.5\nvar_g = var_e - var_f\nvar_h = var_d / var_g\nvar_i = var_a - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 30\nvar_b = 30\nvar_c = 20\nvar_d = var_b - var_c\nvar_e = 1\nvar_f = 0.5\nvar_g = var_e - var_f\nvar_h = var_d / var_g\nvar_i = var_a - var_h\nprint(int(var_i))"
    },
    "2840": {
        "category": "Correspondence",
        "question_ko": "15, 18, 29, 21 중 20보다 작은 2의 배수는 무엇인지 구하시오.",
        "question_en": "Which of 15, 18, 29, and 21 is a multiple of 2 that is less than 20?",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "[OP_LIST_SOL] 15 18 29 21 [OP_LIST_EOL] 2 [OP_LIST_DIVISIBLE] 20 [OP_LIST_LESS] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] 15 18 29 21 [OP_LIST_EOL] 2 [OP_LIST_DIVISIBLE] 20 [OP_LIST_LESS] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 15\nvar_b = 18\nvar_c = 29\nvar_d = 21\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = []\nvar_e = int(var_e)\nfor i in list_a:\n    i = int(i)\n    if i % var_e == 0:\n        list_b.append(i)\nvar_f = 20\nlist_c = []\nfor i in list_b:\n    if i < var_f:\n        list_c.append(i)\nvar_g = 1\nvar_h = list_c[var_g-1]\nprint(int(var_h))",
        "solution_code_en": "var_a = 15\nvar_b = 18\nvar_c = 29\nvar_d = 21\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = []\nvar_e = int(var_e)\nfor i in list_a:\n    i = int(i)\n    if i % var_e == 0:\n        list_b.append(i)\nvar_f = 20\nlist_c = []\nfor i in list_b:\n    if i < var_f:\n        list_c.append(i)\nvar_g = 1\nvar_h = list_c[var_g-1]\nprint(int(var_h))"
    },
    "2841": {
        "category": "Geometry",
        "question_ko": "가로 28센티미터(㎝), 세로 24센티미터(㎝), 높이 19센티미터(㎝)인 직육면체가 있다. 이것과 동일한 직육면체를 몇 개 사용해서 새로운 직육면체를 만들었더니, 가로, 세로, 높이가 각각 원래 길이의 2배가 되었다. 부피는 몇 배가 되었을까?",
        "question_en": "There is a rectangular parallelepiped with a width of 28 centimeters (cm), a length of 24 centimeters (cm) and a height of 19 centimeters (cm). I made a new cuboid using these several identical cuboids, and each of the width, length, and height was twice the original length. How many times did the volume increase?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "28 2 [OP_MUL] 24 [OP_MUL] 2 [OP_MUL] 19 [OP_MUL] 2 [OP_MUL] 28 24 [OP_MUL] 19 [OP_MUL] [OP_FDIV]",
        "solution_abst_en": "28 2 [OP_MUL] 24 [OP_MUL] 2 [OP_MUL] 19 [OP_MUL] 2 [OP_MUL] 28 24 [OP_MUL] 19 [OP_MUL] [OP_FDIV]",
        "solution_code_ko": "var_a = 28\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 24\nvar_e = var_c * var_d\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = 19\nvar_i = var_g * var_h\nvar_j = 2\nvar_k = var_i * var_j\nvar_l = 28\nvar_m = 24\nvar_n = var_l * var_m\nvar_o = 19\nvar_p = var_n * var_o\nvar_q = var_k // var_p\nprint(int(var_q))",
        "solution_code_en": "var_a = 28\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 24\nvar_e = var_c * var_d\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = 19\nvar_i = var_g * var_h\nvar_j = 2\nvar_k = var_i * var_j\nvar_l = 28\nvar_m = 24\nvar_n = var_l * var_m\nvar_o = 19\nvar_p = var_n * var_o\nvar_q = var_k // var_p\nprint(int(var_q))"
    },
    "2842": {
        "category": "Geometry",
        "question_ko": "한 모서리의 길이가 2센티미터(㎝)인 쌓기나무를 쌓아서 한 모서리의 길이가 10센티미터(㎝)인 정육면체를 만들었습니다. 만들어진 정육면체 모양의 모든 면에 빨간색 페인트를 칠했을 때, 1개의 면에 색이 칠해진 쌓기나무는 모두 몇 개입니까?",
        "question_en": "I have made a cube with a side of 10 centimeters (cm) by stacking several blocks with a side of 2 centimeters (cm). If I paint all the faces of this cube red, how many blocks have only one coloured face?",
        "answer_ko": "54",
        "answer_en": "54",
        "solution_abst_ko": "10 2 [OP_DIV] 2 [OP_SUB] 2 [OP_POW] 6 [OP_MUL]",
        "solution_abst_en": "10 2 [OP_DIV] 2 [OP_SUB] 2 [OP_POW] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e ** var_f\nvar_h = 6\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e ** var_f\nvar_h = 6\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "2843": {
        "category": "Possibility",
        "question_ko": "세 자리 수중에서 모든 자리 수를 더했을때 25가 되는 수는 모두 몇 개입니까?",
        "question_en": "How many numbers in a three-digit number add up to 25?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "100 1000 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] 25 [OP_LIST_MORE_EQUAL] 25 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "100 1000 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] 25 [OP_LIST_MORE_EQUAL] 25 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 100\nvar_b = 1000\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nlist_b=[]\nfor i in list_a:\n    var_f = 0\n    i = int(i)\n    while i//10 > 0:\n        var_f = var_f + i%10\n        i = i//10\n    var_f = var_f + i%10\n    list_b.append(var_f)\nvar_g = 25\nlist_c = []\nfor i in list_b:\n    if i >= var_g:\n        list_c.append(i)\nvar_h = 25\nlist_d = []\nfor i in list_c:\n    if i <= var_h:\n        list_d.append(i)\nvar_i = len(list_d)\nprint(int(var_i))",
        "solution_code_en": "var_a = 100\nvar_b = 1000\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nlist_b=[]\nfor i in list_a:\n    var_f = 0\n    i = int(i)\n    while i//10 > 0:\n        var_f = var_f + i%10\n        i = i//10\n    var_f = var_f + i%10\n    list_b.append(var_f)\nvar_g = 25\nlist_c = []\nfor i in list_b:\n    if i >= var_g:\n        list_c.append(i)\nvar_h = 25\nlist_d = []\nfor i in list_c:\n    if i <= var_h:\n        list_d.append(i)\nvar_i = len(list_d)\nprint(int(var_i))"
    },
    "2844": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 5, 8, 2로 나누어 떨어질 수 있는 수 중 가장 큰 세 자리 수는?",
        "question_en": "What is the largest three-digit number divisible by 5, 8, and 2?",
        "answer_ko": "960",
        "answer_en": "960",
        "solution_abst_ko": "100 999 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 2 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_abst_en": "100 999 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 2 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 8\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 2\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_h = list_e[-var_g]\nprint(int(var_h))",
        "solution_code_en": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 8\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 2\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_h = list_e[-var_g]\nprint(int(var_h))"
    },
    "2845": {
        "category": "Possibility",
        "question_ko": "4, 2, 1 중에서 서로 다른 숫자 2개를 뽑아 만들 수 있는 가장 큰 두 자리 수를 구하시오.",
        "question_en": "Find the largest two-digit number that can be formed by picking two different numbers from 4, 2, and 1.",
        "answer_ko": "42",
        "answer_en": "42",
        "solution_abst_ko": "[OP_LIST_SOL] 4 2 1 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 4 2 1 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = 1\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = 1\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))"
    },
    "2846": {
        "category": "Possibility",
        "question_ko": "윤기는 5개의 책 중 3개의 책을 읽으려고 합니다. 윤기가 3개의 책을 읽는 경우는 모두 몇 가지인가요?",
        "question_en": "Yoongi wants to read 3 of the 5 different books. Taking into account the order in which he reads them, how many ways can Yoongi read three books?",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "5 3 [OP_PERM]",
        "solution_abst_en": "5 3 [OP_PERM]",
        "solution_code_ko": "var_a = 5\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))"
    },
    "2847": {
        "category": "Correspondence",
        "question_ko": "지민이가 유나에게 감 2개를 주고 민영에게 사과 7개를 주었습니다. 지민이가 나누어준 과일의 수는 몇 개인가요?",
        "question_en": "Jimin gave 2 persimmons to Yuna and 7 apples to Minyoung. How many fruits did Jimin share?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "2 7 [OP_ADD]",
        "solution_abst_en": "2 7 [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "2848": {
        "category": "Correspondence",
        "question_ko": "석진이가 상자에 감 2개를 넣었습니다. 사과 7개를 추가로 상자에 넣었을 때 상자에 들어있는 과일의 수는 몇인가요?",
        "question_en": "Seokjin put 2 persimmons in the box. How many fruits are in the box when 7 more apples are added to the box?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "2 7 [OP_ADD]",
        "solution_abst_en": "2 7 [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "2849": {
        "category": "Comparison",
        "question_ko": "각 줄마다 같은 수의 학생이 서 있을 때, 윤기는 왼쪽에서 7번째 열, 오른쪽에서 13번째 열, 앞에서 8번째 줄, 뒤에서 14번째 줄에 있다. 줄을 서 있는 모든 학생의 수는 몇 명인가?",
        "question_en": "With the same number of students standing in each row, Yoongi is at 7 rows from the left, 13 rows from the right, 8 rows from the front, and 14 rows from the back. What is the total number of students?",
        "answer_ko": "399",
        "answer_en": "399",
        "solution_abst_ko": "7 13 [OP_ADD] 1 [OP_SUB] 8 14 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "7 13 [OP_ADD] 1 [OP_SUB] 8 14 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 7\nvar_b = 13\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = 14\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 7\nvar_b = 13\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = 14\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))"
    },
    "2850": {
        "category": "Correspondence",
        "question_ko": "84는 어떤 수에서 19를 빼고 27을 더해야 할것을 실수로 27을 빼고 19를 더하여 나온 결과입니다. 바르게 계산하면 얼마입니까?",
        "question_en": "84 is the result of subtracting 27 from a certain number and adding 19 by mistake instead of subtracting 19 and adding 27. What is the certain number if you calculate correctly?",
        "answer_ko": "100",
        "answer_en": "100",
        "solution_abst_ko": "84 19 [OP_SUB] 27 [OP_ADD] 19 [OP_SUB] 27 [OP_ADD]",
        "solution_abst_en": "84 19 [OP_SUB] 27 [OP_ADD] 19 [OP_SUB] 27 [OP_ADD]",
        "solution_code_ko": "var_a = 84\nvar_b = 19\nvar_c = var_a - var_b\nvar_d = 27\nvar_e = var_c + var_d\nvar_f = 19\nvar_g = var_e - var_f\nvar_h = 27\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 84\nvar_b = 19\nvar_c = var_a - var_b\nvar_d = 27\nvar_e = var_c + var_d\nvar_f = 19\nvar_g = var_e - var_f\nvar_h = 27\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "2851": {
        "category": "Correspondence",
        "question_ko": "자연수 N개가 있다. 이 자연수들은 1부터 N까지 연속되었으며 이들 중 짝수의 합은 90이고 홀 수의 합은 100이다. N의 값은 무엇인가?",
        "question_en": "There are N natural numbers. These natural numbers are consecutive from 1 to N, and the sum of even numbers in these numbers is 90 and the sum of odd numbers in these numbers is 100. What is the value of N?",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "100 90 [OP_SUB] 2 [OP_MUL] 1 [OP_SUB]",
        "solution_abst_en": "100 90 [OP_SUB] 2 [OP_MUL] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 100\nvar_b = 90\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 1\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 100\nvar_b = 90\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 1\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "2852": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 수가 30이상 50이하라고 한다. 가능한 어떤 수의 총합을 구하시오.",
        "question_en": "A number is said to be not less than 30 and not more than 50. Find the sum of all the possible values of the number.",
        "answer_ko": "840",
        "answer_en": "840",
        "solution_abst_ko": "30 50 1 [OP_LIST_ARANGE] [OP_LIST_SUM]",
        "solution_abst_en": "30 50 1 [OP_LIST_ARANGE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 30\nvar_b = 50\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_a = [float(i) for i in list_a]\nvar_d = sum(list_a)\nprint(int(var_d))",
        "solution_code_en": "var_a = 30\nvar_b = 50\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_a = [float(i) for i in list_a]\nvar_d = sum(list_a)\nprint(int(var_d))"
    },
    "2853": {
        "category": "Arithmetic calculation",
        "question_ko": "준현이는 약속 장소에 가기 위해 2.6킬로미터(㎞) 거리는 버스를 탔고, 5.98킬로미터(㎞)의 거리는 지하철을 탔습니다. 준현이가 대중교통을 탄 거리는 몇 킬로미터(㎞)입니까?",
        "question_en": "Junhyun took a bus for a distance of 2.6 kilometers (km) and a subway for a distance of 5.98 kilometers (km) to go to the meeting place. How many kilometers (km) did Junhyun take public transportation?",
        "answer_ko": "8.58",
        "answer_en": "8.58",
        "solution_abst_ko": "2.6 5.98 [OP_ADD]",
        "solution_abst_en": "2.6 5.98 [OP_ADD]",
        "solution_code_ko": "var_a = 2.6\nvar_b = 5.98\nvar_c = var_a + var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 2.6\nvar_b = 5.98\nvar_c = var_a + var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "2854": {
        "category": "Comparison",
        "question_ko": "학급임원 선거에서는 득표율이 가장 높은 후보가 회장이 됩니다. 반 친구들 30명이 투표에 참여하여 가는 12표, 나는 3표, 다는 15표를 받았습니다. 회장으로 당선된 후보는 누구인가요?",
        "question_en": "In class presidential elections, the candidate with the highest percentage of votes becomes the class representative. 30 classmates voted, A got 12 votes, B got 3 votes, and C got 15 votes. Who is the winner of this election?",
        "answer_ko": "다",
        "answer_en": "C",
        "solution_abst_ko": "[OP_LIST_SOL] 가 나 다 [OP_LIST_EOL] [OP_LIST_SOL] 12 3 15 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] 12 3 15 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '가'\nvar_b = '나'\nvar_c = '다'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 12\nvar_e = 3\nvar_f = 15\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 12\nvar_e = 3\nvar_f = 15\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "2855": {
        "category": "Geometry",
        "question_ko": "밑면이 서로 평행하고 합동인 다각형이며, 옆면은 여섯 개의 직사각형인 입체도형의 꼭짓점의 개수를 구하시오.",
        "question_en": "Find the number of vertices of a solid figure whose bases are parallel and congruent polygons and whose sides are six rectangles.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "6 2 [OP_MUL]",
        "solution_abst_en": "6 2 [OP_MUL]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "2856": {
        "category": "Geometry",
        "question_ko": "둘레의 길이가 16 센티미터(㎝)이고, 가로의 길이가 세로의 길이보다 2 센티미터(㎝)만큼 긴 직사각형의 가로의 길이와 세로의 길이를 구하려고 한다. 가로의 길이는 얼마인가?",
        "question_en": "You want to find the width and length of a rectangle whose perimeter is 16 centimeters (cm) and its width is 2 centimeters (cm) longer than its length. How long is its width?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "16 2 [OP_DIV] 2 [OP_SUB] 2 [OP_DIV] 2 [OP_ADD]",
        "solution_abst_en": "16 2 [OP_DIV] 2 [OP_SUB] 2 [OP_DIV] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 16\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 16\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "2857": {
        "category": "Geometry",
        "question_ko": "마을 A는 가로 6킬로미터(㎞), 세로 9킬로미터(㎞)인 직사각형 모양이고, 마을 B는 가로 8킬로미터(㎞), 세로 8킬로미터(㎞)인 정사각형 모양입니다. 어느 마을의 둘레가 더 긴지 구하시오.",
        "question_en": "Village A is rectangular in shape, measuring 6 kilometers (km) wide and 9 kilometers (km) long, and village B is square, measuring 8 kilometers (km) wide and 8 kilometers (km) long. Find which town has the greater perimeter.",
        "answer_ko": "B",
        "answer_en": "B",
        "solution_abst_ko": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 6 9 [OP_ADD] 8 8 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 6 9 [OP_ADD] 8 8 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 9\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = 8\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 9\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = 8\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "2858": {
        "category": "Arithmetic calculation",
        "question_ko": "12킬로그램(㎏) 400그램(g)의 딸기를 바구니에 나누어 담으려 합니다. 큰 바구니에는 작은 바구니보다 2킬로그램(㎏) 600그램(g) 더 담으려고 할 때 큰 바구니에는 몇 킬로그램(㎏)을 담게 됩니까?",
        "question_en": "You want to divide 12 kilograms (kg) and 400 grams (g) of strawberries into two different baskets. How many kilograms (kg) will the large basket contain if the large basket contains 2 kilograms (kg) 600 grams (g) more than the small basket?",
        "answer_ko": "7.5",
        "answer_en": "7.5",
        "solution_abst_ko": "12 400 1000 [OP_DIV] [OP_ADD] 2 [OP_DIV] 2 600 1000 [OP_DIV] [OP_ADD] 2 [OP_DIV] [OP_ADD]",
        "solution_abst_en": "12 400 1000 [OP_DIV] [OP_ADD] 2 [OP_DIV] 2 600 1000 [OP_DIV] [OP_ADD] 2 [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 12\nvar_b = 400\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = 600\nvar_j = 1000\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = 2\nvar_n = var_l / var_m\nvar_o = var_g + var_n\nprint('{:.2f}'.format(round(var_o+1e-10,2)))",
        "solution_code_en": "var_a = 12\nvar_b = 400\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = 600\nvar_j = 1000\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = 2\nvar_n = var_l / var_m\nvar_o = var_g + var_n\nprint('{:.2f}'.format(round(var_o+1e-10,2)))"
    },
    "2859": {
        "category": "Geometry",
        "question_ko": "가로의 길이가 20센티미터(㎝), 세로의 길이가 8센티미터(㎝)인 직사각형 모양의 종이를 겹치는 부분 없이 이어붙여 최대한 작은 정사각형 모양의 종이를 만들려고 할 때, 종이는 몇 장 필요한지 구하시오.",
        "question_en": "If you want to make the smallest possible square-shaped piece of paper by attaching rectangular pieces of paper with a width of 20 centimeters (cm) and a length of 8 centimeters (cm) without overlapping, find how many sheets of paper you will need.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "20 8 [OP_LCM] 2 [OP_POW] 20 8 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "20 8 [OP_LCM] 2 [OP_POW] 20 8 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 20\nvar_b = 8\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 20\nvar_g = 8\nvar_h = var_f * var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 20\nvar_b = 8\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 20\nvar_g = 8\nvar_h = var_f * var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "2860": {
        "category": "Geometry",
        "question_ko": "정사각형 여러 개를 겹치는 부분 없이 이어 붙여 가로 63센티미터(㎝), 세로 42센티미터(㎝)의 직사각형을 만드려고 합니다. 정사각형의 개수를 최소로 하기 위해서는 정사각형의 한 변의 길이는 몇 센티미터(㎝)로 해야 하는지 구하시오.",
        "question_en": "You want to make a rectangle that is 63 centimeters (cm) wide by 42 centimeters (cm) tall by joining several squares together without overlapping them. To minimize the number of squares, find how many centimeters (cm) each side of the square must be.",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "63 42 [OP_GCD]",
        "solution_abst_en": "63 42 [OP_GCD]",
        "solution_code_ko": "var_a = 63\nvar_b = 42\nvar_c = math.gcd(int(var_b), int(var_a))\nprint(int(var_c))",
        "solution_code_en": "var_a = 63\nvar_b = 42\nvar_c = math.gcd(int(var_b), int(var_a))\nprint(int(var_c))"
    },
    "2861": {
        "category": "Correspondence",
        "question_ko": "서로 다른 두 수 A, B가 있습니다. 두 자리 수끼리의 덧셈식 6A+B2=77에서 B를 구하시오.",
        "question_en": "There are two different one digit numbers A and B. Find B from the two-digit addition formula 6A+B2=77.",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "6A+B2=77 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "6A+B2=77 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '6A+B2=77'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '6A+B2=77'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "2862": {
        "category": "Geometry",
        "question_ko": "한 모서리의 길이가 11센티미터(㎝)인 정육면체의 겉넓이를 구하시오.",
        "question_en": "Find the surface area of a cube whose edges are 11 centimeters (cm) long.",
        "answer_ko": "726",
        "answer_en": "726",
        "solution_abst_ko": "11 2 [OP_POW] 6 [OP_MUL]",
        "solution_abst_en": "11 2 [OP_POW] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 11\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 11\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "2863": {
        "category": "Geometry",
        "question_ko": "점 A, 점 B, 점 C를 꼭짓점으로 갖는 삼각형이 있습니다. 이때 변 AB의 길이는 4.9센티미터(㎝)이고, 이 삼각형의 넓이는 9.31제곱센티미터(㎠)입니다. 점 C에서 변 AB에 수직이 되도록 선을 그었을 때 만나는 점을 D라고 한다면, 선분 CD의 길이는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "A triangle has vertices of point A, point B, and point C. In this case, the length of side AB is 4.9 centimeters (cm), and the area of this triangle is 9.31 square centimeters (cm2). If a line is drawn perpendicular to side AB from point C and D is the point where it intersects, how many centimeters (cm) is the length of the line segment CD?",
        "answer_ko": "3.80",
        "answer_en": "3.8",
        "solution_abst_ko": "9.31 2 [OP_MUL] 4.9 [OP_DIV]",
        "solution_abst_en": "9.31 2 [OP_MUL] 4.9 [OP_DIV]",
        "solution_code_ko": "var_a = 9.31\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 4.9\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 9.31\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 4.9\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "2864": {
        "category": "Correspondence",
        "question_ko": "A를 B로 나눴더니 몫이 C가 되었고, 나머지는 2가 되었습니다. A, B, C는 자연수 입니다. B와 C가 같을 때, 가능한 A 중 가장 작은 수는 무엇인가요?",
        "question_en": "When A is divided by B, the quotient is C and the remainder is 2. A, B, and C are natural numbers. If B and C are equal, what is the smallest possible number of A?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "2 1 [OP_ADD] 2 [OP_POW] 2 [OP_ADD]",
        "solution_abst_en": "2 1 [OP_ADD] 2 [OP_POW] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 2\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "2865": {
        "category": "Arithmetic calculation",
        "question_ko": "마트에 주스는 34병 있고, 생수는 주스의 3/2배보다 3병 더 많이 있습니다. 마트에 있는 생수와 주스를 합하면 모두 몇 병입니까?",
        "question_en": "There are 34 bottles of juice in the market, and there are 3/2 times as many bottles of water as juice plus 3 bottles of water. How many bottles of bottled water and juice are there in total in the market?",
        "answer_ko": "88",
        "answer_en": "88",
        "solution_abst_ko": "34 34 3/2 [OP_MUL] 3 [OP_ADD] [OP_ADD]",
        "solution_abst_en": "34 34 3/2 [OP_MUL] 3 [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 34\nvar_b = 34\nvar_c = 1.5\nvar_d = var_b * var_c\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = var_a + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 34\nvar_b = 34\nvar_c = 1.5\nvar_d = var_b * var_c\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = var_a + var_f\nprint(int(var_g))"
    },
    "2866": {
        "category": "Correspondence",
        "question_ko": "125는 어떤 수에 95를 더해야 하는데 실수로 65를 더했을 때나오는 결과이다. 바르게 계산한 결과를 구하여라.",
        "question_en": "125 is the result when you accidentally add 65 to a certain number that you should add 95 to . Find the result of the correct calculation.",
        "answer_ko": "155",
        "answer_en": "155",
        "solution_abst_ko": "125 65 [OP_SUB] 95 [OP_ADD]",
        "solution_abst_en": "125 65 [OP_SUB] 95 [OP_ADD]",
        "solution_code_ko": "var_a = 125\nvar_b = 65\nvar_c = var_a - var_b\nvar_d = 95\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 125\nvar_b = 65\nvar_c = var_a - var_b\nvar_d = 95\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "2867": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 1/100로 나누고 10배를 하면 2804가 된다. 어떤 수를 구하시오.",
        "question_en": "Divide a certain number by 1/100 and multiply by 10 to get 2804. Find the number.",
        "answer_ko": "2.80",
        "answer_en": "2.8",
        "solution_abst_ko": "2804 10 [OP_DIV] 1/100 [OP_MUL]",
        "solution_abst_en": "2804 10 [OP_DIV] 1/100 [OP_MUL]",
        "solution_code_ko": "var_a = 2804\nvar_b = 10\nvar_c = var_a / var_b\nvar_d = 0.01\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 2804\nvar_b = 10\nvar_c = var_a / var_b\nvar_d = 0.01\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "2868": {
        "category": "Correspondence",
        "question_ko": "백의 자리에서 A76을 버림하면 700이 됩니다. A에 알맞은 숫자를 구하시오.",
        "question_en": "Rounding down A76 to the nearest hundred gives 700. Find the correct number for A.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "A76 [OP_GEN_POSSIBLE_LIST] 700 [OP_LIST_MORE_EQUAL] 700 100 [OP_ADD] [OP_LIST_LESS] A76 A [OP_LIST_FIND_UNK]",
        "solution_abst_en": "A76 [OP_GEN_POSSIBLE_LIST] 700 [OP_LIST_MORE_EQUAL] 700 100 [OP_ADD] [OP_LIST_LESS] A76 A [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = 'A76'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 700\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 700\nvar_d = 100\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = 'A76'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))",
        "solution_code_en": "var_a = 'A76'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 700\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 700\nvar_d = 100\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = 'A76'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))"
    },
    "2869": {
        "category": "Arithmetic calculation",
        "question_ko": "산을 올라갈 때는 시속 3킬로미터(㎞), 내려올 때는 2킬로미터(㎞)더 긴 길을 시속 4킬로미터(㎞)로 내려왔더니 걸린 두 시간의 합이 4시간이었다. 내려간 거리를 구하라.",
        "question_en": "When I went up the mountain at 3 kilometers (km) per hour and came down 2 kilometers (km) longer road at 4 kilometers (km) per hour, the total hour of going up and down took 4 hours. Find the distance for coming down.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "4 2 4 [OP_DIV] [OP_SUB] 1 3 [OP_DIV] 1 4 [OP_DIV] [OP_ADD] [OP_DIV] 2 [OP_ADD]",
        "solution_abst_en": "4 2 4 [OP_DIV] [OP_SUB] 1 3 [OP_DIV] 1 4 [OP_DIV] [OP_ADD] [OP_DIV] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = 3\nvar_h = var_f / var_g\nvar_i = 1\nvar_j = 4\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_e / var_l\nvar_n = 2\nvar_o = var_m + var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = 3\nvar_h = var_f / var_g\nvar_i = 1\nvar_j = 4\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_e / var_l\nvar_n = 2\nvar_o = var_m + var_n\nprint(int(var_o))"
    },
    "2870": {
        "category": "Possibility",
        "question_ko": "모든 방의 번호가 3개로 이루어진 호텔이 있습니다. 방 번호에 3, 0, 6이 모두 들어있는 방 안에 보물을 숨겨두었습니다. 몇 개의 보물을 숨겨두었습니까?",
        "question_en": "There is a hotel where every room has 3-digit numbers. You have hidden a treasure in a room with digits 3, 0, and 6 all in the room number. How many treasures have you hidden?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 3 0 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 3 0 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 3\nvar_b = 0\nvar_c = 6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 3\nvar_b = 0\nvar_c = 6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "2871": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 24를 곱하려고 합니다. 잘못하여 42를 더했을 때의 답이 50이라면 바르게 계산한 결과는 얼마일까요?",
        "question_en": "You want to multiply a number by 24. When you accidentally added 42, the result was 50. What is the correct value?",
        "answer_ko": "192",
        "answer_en": "192",
        "solution_abst_ko": "50 42 [OP_SUB] 24 [OP_MUL]",
        "solution_abst_en": "50 42 [OP_SUB] 24 [OP_MUL]",
        "solution_code_ko": "var_a = 50\nvar_b = 42\nvar_c = var_a - var_b\nvar_d = 24\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 50\nvar_b = 42\nvar_c = var_a - var_b\nvar_d = 24\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "2872": {
        "category": "Possibility",
        "question_ko": "주어진 숫자카드 0, 5, 8를 한 번씩 모두 사용하여 만들 수 있는 가장 작은 수에 십의 자리에 오는 숫자를 구하시오.",
        "question_en": "Find the number in the tens place of the smallest number that can be made by using all of the given number cards 0, 5, and 8 once.",
        "answer_ko": "0",
        "answer_en": "0",
        "solution_abst_ko": "[OP_LIST_SOL] 0 5 8 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 100 [OP_MOD] 10 [OP_FDIV]",
        "solution_abst_en": "[OP_LIST_SOL] 0 5 8 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 100 [OP_MOD] 10 [OP_FDIV]",
        "solution_code_ko": "var_a = 0\nvar_b = 5\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = 100\nvar_h = var_f % var_g\nvar_i = 10\nvar_j = var_h // var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 0\nvar_b = 5\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = 100\nvar_h = var_f % var_g\nvar_i = 10\nvar_j = var_h // var_i\nprint(int(var_j))"
    },
    "2873": {
        "category": "Geometry",
        "question_ko": "직육면체의 모양의 상자가 있습니다. 모든 모서리의 합이 224센티미터(㎝)이며, 상자의 가로는 30센티미터(㎝), 세로는 22센티미터(㎝) 입니다. 이 상자의 높이는 몇 센티미터(㎝)입니까?",
        "question_en": "There is a box in the shape of a cuboid. The sum of all edges is 224 centimeters (cm), and the box's width is 30 centimeters (cm) and its length is 22 centimeters (cm). How many centimeters (cm) is the height of this box?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "224 4 [OP_DIV] 30 [OP_SUB] 22 [OP_SUB]",
        "solution_abst_en": "224 4 [OP_DIV] 30 [OP_SUB] 22 [OP_SUB]",
        "solution_code_ko": "var_a = 224\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 30\nvar_e = var_c - var_d\nvar_f = 22\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 224\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 30\nvar_e = var_c - var_d\nvar_f = 22\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "2874": {
        "category": "Comparison",
        "question_ko": "A, B, C 3개 반이 수학 시험을 봤다. B반의 평균이 A반 보다 높고 C반의 평균이 A반보다 높다고 할 때, 평균이 가장 낮은 반은 어디인지 구하시오.",
        "question_en": "Three classes A, B, and C took a math test. If class B's average is higher than class A's, and class C's average is higher than class A's, find the class with the lowest average.",
        "answer_ko": "A",
        "answer_en": "A",
        "solution_abst_ko": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] B A > C A > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] B A > C A > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'B'\nvar_e = 'A'\nvar_f = '>'\nvar_g = 'C'\nvar_h = 'A'\nvar_i = '>'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = len(list_c)\nvar_k = list_c[var_j-1]\nprint(var_k)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'B'\nvar_e = 'A'\nvar_f = '>'\nvar_g = 'C'\nvar_h = 'A'\nvar_i = '>'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = len(list_c)\nvar_k = list_c[var_j-1]\nprint(var_k)"
    },
    "2875": {
        "category": "Arithmetic calculation",
        "question_ko": "민영이는 꽃 24송이를 가지고 있습니다. 민영이가 가지고 있는 꽃의 수는 유정이가 가진 꽃의 수의 4배입니다. 민영이와 유정이가 가진 꽃은 모두 몇 송이입니까?",
        "question_en": "Minyoung has 24 flowers. The number of flowers that Minyoung has is 4 times the number of flowers that Yoojung has. How many flowers do they have?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "24 24 4 [OP_DIV] [OP_ADD]",
        "solution_abst_en": "24 24 4 [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 24\nvar_b = 24\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 24\nvar_b = 24\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "2876": {
        "category": "Arithmetic calculation",
        "question_ko": "꽃 18송이 중 5송이는 민영이에게 6송이는 유정이에게 주었습니다. 남은 꽃은 몇 송이입니까?",
        "question_en": "Among the 18 flowers, 5 were given to Min-Young and 6 to Yoo-Jeong. How many flowers are left?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "18 5 [OP_SUB] 6 [OP_SUB]",
        "solution_abst_en": "18 5 [OP_SUB] 6 [OP_SUB]",
        "solution_code_ko": "var_a = 18\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 18\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "2877": {
        "category": "Correspondence",
        "question_ko": "41, 43, 45, 47 중 하나를 골랐더니, 43보다 크고 46보다 작은 값이 나왔습니다. 이 수는 무엇입니까?",
        "question_en": "I picked one from 41, 43, 45, and 47, and I got a value greater than 43 and less than 46. What is this number?",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "[OP_LIST_SOL] 41 43 45 47 [OP_LIST_EOL] 43 [OP_LIST_MORE] 46 [OP_LIST_LESS] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] 41 43 45 47 [OP_LIST_EOL] 43 [OP_LIST_MORE] 46 [OP_LIST_LESS] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 41\nvar_b = 43\nvar_c = 45\nvar_d = 47\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 43\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nvar_f = 46\nlist_c = []\nfor i in list_b:\n    if i < var_f:\n        list_c.append(i)\nvar_g = 1\nvar_h = list_c[var_g-1]\nprint(int(var_h))",
        "solution_code_en": "var_a = 41\nvar_b = 43\nvar_c = 45\nvar_d = 47\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 43\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nvar_f = 46\nlist_c = []\nfor i in list_b:\n    if i < var_f:\n        list_c.append(i)\nvar_g = 1\nvar_h = list_c[var_g-1]\nprint(int(var_h))"
    },
    "2878": {
        "category": "Correspondence",
        "question_ko": "유나가 사과 2개를 민영에게 주고, 감 7개를 유정에게 주었더니 남은 과일의 수가 0개입니다. 유나가 가지고 있던 과일의 수는 몇 개인가요?",
        "question_en": "Yuna gave 2 apples to Minyoung and 7 persimmons to Yoojung, and the number of fruits left is 0. How many fruits did Yuna have?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "2 7 [OP_ADD]",
        "solution_abst_en": "2 7 [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "2879": {
        "category": "Arithmetic calculation",
        "question_ko": "성준이는 매일 우유를 조금씩 마십니다. 어제는 1/3병을 마셨고, 오늘은 1/2병을 마셨을 때, 이틀 동안 마신 우유는 몇 병입니까?",
        "question_en": "Sungjun drinks a little milk every day. If he drank 1/3 bottle yesterday and 1/2 bottle today, how many bottles of milk did he drink in two days?",
        "answer_ko": "0.83",
        "answer_en": "0.83",
        "solution_abst_ko": "1/3 1/2 [OP_ADD]",
        "solution_abst_en": "1/3 1/2 [OP_ADD]",
        "solution_code_ko": "var_a = 0.3333333333333333\nvar_b = 0.5\nvar_c = var_a + var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 0.3333333333333333\nvar_b = 0.5\nvar_c = var_a + var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "2880": {
        "category": "Arithmetic calculation",
        "question_ko": "일정한 빠르기로 1분에 2.1킬로미터(㎞)를 달리는 트럭과 4분에 10.5킬로미터(㎞)를 달리는 택시가 있습니다. 택시는 트럭보다 몇 배 더 빠른지 구하시오.",
        "question_en": "There is a truck that runs at a constant speed of 2.1 kilometers (km) in 1 minute, and a taxi that runs at 10.5 kilometers (km) in 4 minutes. Find how many times the taxi is faster than the truck.",
        "answer_ko": "1.25",
        "answer_en": "1.25",
        "solution_abst_ko": "10.5 4 [OP_DIV] 2.1 1 [OP_DIV] [OP_DIV]",
        "solution_abst_en": "10.5 4 [OP_DIV] 2.1 1 [OP_DIV] [OP_DIV]",
        "solution_code_ko": "var_a = 10.5\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2.1\nvar_e = 1\nvar_f = var_d / var_e\nvar_g = var_c / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 10.5\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2.1\nvar_e = 1\nvar_f = var_d / var_e\nvar_g = var_c / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "2881": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 9로 나누고 13을 뺀 후, 7로 나누고 8을 빼면 13이 됩니다. 어떤 수를 구하시오.",
        "question_en": "Divide a number by 9 and subtract 13, then divide by 7 and subtract 8 to get 13. Find the number.",
        "answer_ko": "1440",
        "answer_en": "1440",
        "solution_abst_ko": "13 8 [OP_ADD] 7 [OP_MUL] 13 [OP_ADD] 9 [OP_MUL]",
        "solution_abst_en": "13 8 [OP_ADD] 7 [OP_MUL] 13 [OP_ADD] 9 [OP_MUL]",
        "solution_code_ko": "var_a = 13\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 7\nvar_e = var_c * var_d\nvar_f = 13\nvar_g = var_e + var_f\nvar_h = 9\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 13\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 7\nvar_e = var_c * var_d\nvar_f = 13\nvar_g = var_e + var_f\nvar_h = 9\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "2882": {
        "category": "Arithmetic calculation",
        "question_ko": "농장에서 토끼 64마리를 기르는데 닭보다 17마리가 적습니다. 농장에서 기르는 토끼와 닭은 모두 몇 마리입니까?",
        "question_en": "A farm raises 64 rabbits, which are 17 fewer than chickens. How many rabbits and chickens does this farm have?",
        "answer_ko": "111",
        "answer_en": "111",
        "solution_abst_ko": "64 17 [OP_SUB] 64 [OP_ADD]",
        "solution_abst_en": "64 17 [OP_SUB] 64 [OP_ADD]",
        "solution_code_ko": "var_a = 64\nvar_b = 17\nvar_c = var_a - var_b\nvar_d = 64\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 64\nvar_b = 17\nvar_c = var_a - var_b\nvar_d = 64\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "2883": {
        "category": "Possibility",
        "question_ko": "0, 1, 2, 3, 4의 숫자 중에서 서로 다른 3개의 숫자를 골라 네 자리 수를 만들었다. 이 중에서 2, 3, 5로 나누어 떨어지는 수는 모두 몇 가지인가?",
        "question_en": "From the numbers 0, 1, 2, 3, and 4, three different numbers were chosen to make a three-digit number. How many of these numbers are divisible by 2, 3, and 5?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 3 [OP_LCM] 5 [OP_LCM] [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 3 [OP_LCM] 5 [OP_LCM] [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 2\nvar_h = 3\nvar_i = var_h * var_g / math.gcd(int(var_h), int(var_g))\nvar_j = 5\nvar_k = var_j * var_i / math.gcd(int(var_j), int(var_i))\nlist_c = []\nvar_k = int(var_k)\nfor i in list_b:\n    i = int(i)\n    if i % var_k == 0:\n        list_c.append(i)\nvar_l = len(list_c)\nprint(int(var_l))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 2\nvar_h = 3\nvar_i = var_h * var_g / math.gcd(int(var_h), int(var_g))\nvar_j = 5\nvar_k = var_j * var_i / math.gcd(int(var_j), int(var_i))\nlist_c = []\nvar_k = int(var_k)\nfor i in list_b:\n    i = int(i)\n    if i % var_k == 0:\n        list_c.append(i)\nvar_l = len(list_c)\nprint(int(var_l))"
    },
    "2884": {
        "category": "Geometry",
        "question_ko": "정사각형 모양의 공원이 있습니다. 이 공원의 한 변의 길이가 5킬로미터(㎞)라면, 이 정원의 둘레는 몇 킬로미터(㎞)입니까?",
        "question_en": "There is a park in the shape of a square. If the length of one side of this park is 5 kilometers (km), what is the circumference of this garden in kilometers (km)?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "5 4 [OP_MUL]",
        "solution_abst_en": "5 4 [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "2885": {
        "category": "Correspondence",
        "question_ko": "A, B는 한 자리 수입니다. A는 2보다 4 큰 수이고, B보다 3 작은 수는 1입니다. A와 B의 합을 구하시오.",
        "question_en": "A and B are single digit numbers. A is 4 greater than 2, and 3 less than B is 1. Find the sum of A and B.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "2 4 [OP_ADD] 1 3 [OP_ADD] [OP_ADD]",
        "solution_abst_en": "2 4 [OP_ADD] 1 3 [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "2886": {
        "category": "Possibility",
        "question_ko": "0, 1, 2, 3, 4의 수가 각각 적힌 5장의 카드에서 4장을 뽑아 만들 수 있는 네 자리의 정수의 개수를 구하시오.",
        "question_en": "Find the number of four-digit integers that can be made by drawing 4 cards out of 5 cards with the numbers 0, 1, 2, 3, and 4 written on them.",
        "answer_ko": "96",
        "answer_en": "96",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 4 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 4 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "2887": {
        "category": "Possibility",
        "question_ko": "연속적으로 붙어 있는 A, B, C 3개의 부분을 빨강, 주황, 파랑, 노랑, 초록 5가지 색으로 칠하려고 한다. 색을 한 번씩만 쓸 수 있고, 이웃한 영역은 서로 다른 색을 칠하는 경우의 수를 구하시오.",
        "question_en": "You are going to paint the three parts A, B, and C that are continuously attached with five colors: red, orange, blue, yellow, and green. Find the number of cases in which a color can be used only once and adjacent areas are painted with different colors.",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "5 3 [OP_PERM]",
        "solution_abst_en": "5 3 [OP_PERM]",
        "solution_code_ko": "var_a = 5\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))"
    },
    "2888": {
        "category": "Geometry",
        "question_ko": "가로가 81/4센티미터(㎝), 세로가 148/9센티미터(㎝)인 직사각형 모양의 쟁반이 있습니다. 이 쟁반의 넓이는 몇 제곱센티미터(㎠)니까?",
        "question_en": "There is a tray in the shape of a rectangle measuring 81/4 centimeters (cm) wide and 148/9 centimeters (cm) long. What is the area of this tray in square centimeters (cm2)?",
        "answer_ko": "333",
        "answer_en": "333",
        "solution_abst_ko": "81/4 148/9 [OP_MUL]",
        "solution_abst_en": "81/4 148/9 [OP_MUL]",
        "solution_code_ko": "var_a = 20.25\nvar_b = 16.444444444444443\nvar_c = var_a * var_b\nprint(int(eval('{:.2f}'.format(round(var_c+1e-10,2)))))",
        "solution_code_en": "var_a = 20.25\nvar_b = 16.444444444444443\nvar_c = var_a * var_b\nprint(int(eval('{:.2f}'.format(round(var_c+1e-10,2)))))"
    },
    "2889": {
        "category": "Geometry",
        "question_ko": "철사 12/25미터(m)를 모두 사용하여 만든 정사각형의 한 변의 길이를 구하시오.",
        "question_en": "Find the length of one edge of a square made using all 12/25 meters (m) of wire.",
        "answer_ko": "0.12",
        "answer_en": "0.12",
        "solution_abst_ko": "12/25 4 [OP_DIV]",
        "solution_abst_en": "12/25 4 [OP_DIV]",
        "solution_code_ko": "var_a = 0.48\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 0.48\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "2890": {
        "category": "Geometry",
        "question_ko": "밑변의 길이가 4.9센티미터(㎝)인 삼각형이 있습니다. 이 삼각형의 넓이가 9.31제곱센티미터(㎠)라면 높이는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "You have a triangle whose base is 4.9 centimeters (cm). If the area of this triangle is 9.31 square centimeters (cm2), how many centimeters (cm) is its height?",
        "answer_ko": "3.80",
        "answer_en": "3.8",
        "solution_abst_ko": "9.31 2 [OP_MUL] 4.9 [OP_DIV]",
        "solution_abst_en": "9.31 2 [OP_MUL] 4.9 [OP_DIV]",
        "solution_code_ko": "var_a = 9.31\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 4.9\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 9.31\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 4.9\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "2891": {
        "category": "Arithmetic calculation",
        "question_ko": "두 자리 수끼리의 뺄셈에서 빼어지는 수의 십의 자리 숫자 2를 5로 잘못 보고, 일의 자리 숫자 6을 9로 잘못 보고 계산하였더니 그 값이 44가 되었습니다. 바르게 계산한 결과를 구하시오.",
        "question_en": "In a subtraction between two-digit numbers, the number 2 in the tens digit of the minuend is mistaken for 5, and the number 6 in the ones digit is mistaken for 9, and the result is 44. Find the result of the correct calculation.",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "44 10 2 5 [OP_SUB] [OP_MUL] [OP_ADD] 1 6 9 [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_abst_en": "44 10 2 5 [OP_SUB] [OP_MUL] [OP_ADD] 1 6 9 [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 44\nvar_b = 10\nvar_c = 2\nvar_d = 5\nvar_e = var_c - var_d\nvar_f = var_b * var_e\nvar_g = var_a + var_f\nvar_h = 1\nvar_i = 6\nvar_j = 9\nvar_k = var_i - var_j\nvar_l = var_h * var_k\nvar_m = var_g + var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 44\nvar_b = 10\nvar_c = 2\nvar_d = 5\nvar_e = var_c - var_d\nvar_f = var_b * var_e\nvar_g = var_a + var_f\nvar_h = 1\nvar_i = 6\nvar_j = 9\nvar_k = var_i - var_j\nvar_l = var_h * var_k\nvar_m = var_g + var_l\nprint(int(var_m))"
    },
    "2892": {
        "category": "Geometry",
        "question_ko": "넓이가 9.31제곱센티미터(㎠)이고 밑변이 4.9센티미터(㎝)인 삼각형이 있습니다. 이 삼각형의 높이는 몇 센티미터(㎝)입니까?",
        "question_en": "You have a triangle with an area of 9.31 square centimeters (cm2) and a base of 4.9 centimeters (cm). What is the height of this triangle in centimeters (cm)?",
        "answer_ko": "3.80",
        "answer_en": "3.8",
        "solution_abst_ko": "9.31 2 [OP_MUL] 4.9 [OP_DIV]",
        "solution_abst_en": "9.31 2 [OP_MUL] 4.9 [OP_DIV]",
        "solution_code_ko": "var_a = 9.31\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 4.9\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 9.31\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 4.9\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "2893": {
        "category": "Geometry",
        "question_ko": "둘레가 52센티미터인 정사각형을 한 면으로 갖는 정육면체가 있다면, 이 도형의 겉넓이는 몇인가?",
        "question_en": "If a cube has a square with a perimeter of 52 centimeters (cm) as one side, what is the surface area of the figure?",
        "answer_ko": "1014",
        "answer_en": "1014",
        "solution_abst_ko": "52 4 [OP_DIV] 52 4 [OP_DIV] [OP_MUL] 6 [OP_MUL]",
        "solution_abst_en": "52 4 [OP_DIV] 52 4 [OP_DIV] [OP_MUL] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 52\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 52\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = var_c * var_f\nvar_h = 6\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 52\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 52\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = var_c * var_f\nvar_h = 6\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "2894": {
        "category": "Correspondence",
        "question_ko": "서로 다른 두 수 A, B가 있습니다. 8AA4-BBB=BBBB에서 A와 B의 합을 구하시오.",
        "question_en": "There are two one-digit number A and B. Find the sum of A and B in 8AA4-BBB=BBBB.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "8AA4-BBB=BBBB A [OP_DIGIT_UNK_SOLVER] 8AA4-BBB=BBBB B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_abst_en": "8AA4-BBB=BBBB A [OP_DIGIT_UNK_SOLVER] 8AA4-BBB=BBBB B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_code_ko": "var_a = '8AA4-BBB=BBBB'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '8AA4-BBB=BBBB'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = '8AA4-BBB=BBBB'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '8AA4-BBB=BBBB'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "2895": {
        "category": "Arithmetic calculation",
        "question_ko": "유진이네 반 남학생 20 명의 평균 몸무게는 42 킬로그램(㎏)이고, 여학생 20 명의 평균 몸무게는 38 킬로그램(㎏) 입니다. 유진이네 반 전체 학생들의 평균 몸무게는 몇 킬로그램(㎏) 입니까?",
        "question_en": "The average weight of the 20 male students in Eugene's class is 42 kg, and the average weight of the 20 female students is 38 kg. What is the average weight of all the students in Eugene's class in kilograms (kg)?",
        "answer_ko": "40",
        "answer_en": "40",
        "solution_abst_ko": "20 42 [OP_MUL] 20 38 [OP_MUL] [OP_ADD] 20 20 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "20 42 [OP_MUL] 20 38 [OP_MUL] [OP_ADD] 20 20 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 20\nvar_b = 42\nvar_c = var_a * var_b\nvar_d = 20\nvar_e = 38\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 20\nvar_i = 20\nvar_j = var_h + var_i\nvar_k = var_g / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 20\nvar_b = 42\nvar_c = var_a * var_b\nvar_d = 20\nvar_e = 38\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 20\nvar_i = 20\nvar_j = var_h + var_i\nvar_k = var_g / var_j\nprint(int(var_k))"
    },
    "2896": {
        "category": "Geometry",
        "question_ko": "정사각형 모양의 타일을 빠짐없이 늘어놓아 더 큰 정사각형을 만들었습니다. 둘레에 놓인 타일의 개수가 52개라면 가장 바깥쪽의 한 변에 놓인 타일의 개수를 구하시오.",
        "question_en": "All of the square-shaped tiles are lined up to make a larger square. If the number of tiles on the perimeter is 52, find the number of tiles on the outermost of one side.",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "52 4 [OP_SUB] 4 [OP_DIV] 2 [OP_ADD]",
        "solution_abst_en": "52 4 [OP_SUB] 4 [OP_DIV] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 52\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 52\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "2897": {
        "category": "Arithmetic calculation",
        "question_ko": "지민이네 가족은 과수원을 운영합니다. 사과를 따는데 지민이는 7개, 할아버지는 13개, 남동생은 8개, 여동생은 5개를 땄습니다. 사과를 가장 적게 딴 사람보다 가장 많이 딴 사람은 몇 개를 더 땄습니까?",
        "question_en": "Jimin's family runs an orchard. When picking apples, Jimin picked 7, Grandpa 13, younger brother 8, and younger sister 5. How many more apples did the person who picked the most apples pick than the person who picked the fewest?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "[OP_LIST_SOL] 8 13 7 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 8 13 7 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 8\nvar_b = 13\nvar_c = 7\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 8\nvar_b = 13\nvar_c = 7\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))"
    },
    "2898": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.3 중 0.4보다 크거나 같은 수의 개수를 구하시오.",
        "question_en": "Find the number of numbers greater than or equal to 0.4 among 0.8, 1/2, and 0.3.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.3 [OP_LIST_EOL] 0.4 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.3 [OP_LIST_EOL] 0.4 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.4\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.4\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "2899": {
        "category": "Arithmetic calculation",
        "question_ko": "혜미는 게임방을 갈 때 시속 3킬로미터(㎞)로 갔다. 게임방에서 다시 돌아올 때 마트를 거치며 오느라 2킬로미터(㎞) 더 긴 길로 시속 4킬로미터(㎞)의 속도로 왔다. 가는 시간과 오는 시간을 합쳐보니 4시간이 걸렸다면, 게임방을 갈 때 몇 킬로미터(㎞)를 걸었는가?",
        "question_en": "When Hyemi went to the game room, she went at 3 kilometers per hour (km). When she came back from the game room, she went through the mart, so she came at a speed of 4 km per hour on a 2 km (km) longer road. If the total time to go and return took 4 hours, how many kilometers did she walk to the game room?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "4 2 4 [OP_DIV] [OP_SUB] 1 3 [OP_DIV] 1 4 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_abst_en": "4 2 4 [OP_DIV] [OP_SUB] 1 3 [OP_DIV] 1 4 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = 3\nvar_h = var_f / var_g\nvar_i = 1\nvar_j = 4\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_e / var_l\nprint(int(eval('{:.2f}'.format(round(var_m+1e-10,2)))))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = 3\nvar_h = var_f / var_g\nvar_i = 1\nvar_j = 4\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_e / var_l\nprint(int(eval('{:.2f}'.format(round(var_m+1e-10,2)))))"
    },
    "2900": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.3, 1/3에서 0.4보다 크거나 같은 수 중 가장 작거나 같은 수는?",
        "question_en": "Which number is less than or equal to 0.8, 1/2, 0.3, 1/3 and greater than or equal to 0.4?",
        "answer_ko": "0.50",
        "answer_en": "0.5",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.3 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_MORE_EQUAL] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.3 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_MORE_EQUAL] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.3\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.4\nlist_b = []\nfor i in list_a:\n    if i >= var_e:\n        list_b.append(i)\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.3\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.4\nlist_b = []\nfor i in list_a:\n    if i >= var_e:\n        list_b.append(i)\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "2901": {
        "category": "Arithmetic calculation",
        "question_ko": "백의 자리 숫자가 7, 일의 자리 숫자가 3인 수들 중 3의 배수는 몇 개인지 구하시오.",
        "question_en": "Find the multiples of 3 of the numbers whose hundreds are 7 and whose ones are 3. How many numbers are there?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 7 A 3 [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 7 A 3 [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 7\nvar_b = 'A'\nvar_c = 3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nans_dict = dict()\nvar_d = str(var_d)\nlist_b = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_d) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_b.append(new_elem)\nvar_e = 3\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 7\nvar_b = 'A'\nvar_c = 3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nans_dict = dict()\nvar_d = str(var_d)\nlist_b = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_d) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_b.append(new_elem)\nvar_e = 3\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "2902": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 305를 더하고 다시 16으로 나누면 31이 됩니다. 어떤 수를 구하시오.",
        "question_en": "Adding 305 to a number and then dividing it by 16 results in 31. Find the number.",
        "answer_ko": "191",
        "answer_en": "191",
        "solution_abst_ko": "31 16 [OP_MUL] 305 [OP_SUB]",
        "solution_abst_en": "31 16 [OP_MUL] 305 [OP_SUB]",
        "solution_code_ko": "var_a = 31\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 305\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 31\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 305\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "2903": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 10을 나누었더니 6이 되었습니다. 어떤 수에 15를 뺀 결과를 구하시오.",
        "question_en": "When you divide a certain number by 10, you get 6. Find the result of subtracting 15 from the number.",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "6 10 [OP_MUL] 15 [OP_SUB]",
        "solution_abst_en": "6 10 [OP_MUL] 15 [OP_SUB]",
        "solution_code_ko": "var_a = 6\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 15\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 15\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "2904": {
        "category": "Comparison",
        "question_ko": "한별과 슬기는 공원을 뛰어다닌다. 같은 기간 한별은 10.2킬로미터(㎞)를 100분의 1만큼, 슬기는 100미터(m)를 달렸다. 누가 더 많이 달렸는가?",
        "question_en": "Hanbyul and Seulgi run around the park. During the same period, Hanbyul ran 1/100 of 10.2 kilometers (km), and Seulgi ran 100 meters (m). Who ran more?",
        "answer_ko": "한별",
        "answer_en": "Hanbyul",
        "solution_abst_ko": "[OP_LIST_SOL] 한별 슬기 [OP_LIST_EOL] [OP_LIST_SOL] 10.2 1000 [OP_MUL] 100 [OP_DIV] 100 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Hanbyul Seulgi [OP_LIST_EOL] [OP_LIST_SOL] 10.2 1000 [OP_MUL] 100 [OP_DIV] 100 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '한별'\nvar_b = '슬기'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10.2\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 100\nvar_g = var_e / var_f\nvar_h = 100\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Hanbyul'\nvar_b = 'Seulgi'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10.2\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 100\nvar_g = var_e / var_f\nvar_h = 100\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "2905": {
        "category": "Geometry",
        "question_ko": "어떤 주사위는 한 모서리의 길이가 20센티미터(㎝)입니다. 이 주사위의 겉넓이를 구하시오.",
        "question_en": "There is a dice with one edge  20 centimeters (cm) long. Find the surface area of this dice.",
        "answer_ko": "2400",
        "answer_en": "2400",
        "solution_abst_ko": "20 2 [OP_POW] 6 [OP_MUL]",
        "solution_abst_en": "20 2 [OP_POW] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 20\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "2906": {
        "category": "Arithmetic calculation",
        "question_ko": "2.8, 2.3, 5, 4.3 수가 있을 때, 가장 작은 수와 가장 큰 수의 곱을 구하시오.",
        "question_en": "Among the numbers of 2.8, 2.3, 5, and 4.3, find the product of the smallest number and the largest number.",
        "answer_ko": "11.50",
        "answer_en": "11.5",
        "solution_abst_ko": "[OP_LIST_SOL] 2.8 2.3 5 4.3 [OP_LIST_EOL] 1 [OP_LIST_MIN] 1 [OP_LIST_MAX] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 2.8 2.3 5 4.3 [OP_LIST_EOL] 1 [OP_LIST_MIN] 1 [OP_LIST_MAX] [OP_MUL]",
        "solution_code_ko": "var_a = 2.8\nvar_b = 2.3\nvar_c = 5\nvar_d = 4.3\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = var_f * var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 2.8\nvar_b = 2.3\nvar_c = 5\nvar_d = 4.3\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = var_f * var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "2907": {
        "category": "Geometry",
        "question_ko": "오각기둥의 각 면에 서로 다른 색을 칠하려고 합니다. 한 사람당 한 면을 색칠한다고 할 때, 필요한 사람은 모두 몇 사람입니까?",
        "question_en": "You want to paint each face of the pentagonal prism with a different color. How many people do you need if each person paints one side?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "2 5 [OP_ADD]",
        "solution_abst_en": "2 5 [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "2908": {
        "category": "Correspondence",
        "question_ko": "윤기는 네 자리 수와 57의 뺄셈을 하려 합니다. 윤기는 네 자리 수의 일의 자리 숫자 9를 6으로 잘못 보았습니다. 윤기가 구한 차는 1819 일 때, 바르게 계산한 결과를 구하시오.",
        "question_en": "Yoongi wants to subtract 57 from a four-digit number. Yoongi has mistaken 9 for 6 in the unit place of a four-digit number. When the difference Yoongi gets is 1819, find the correct result.",
        "answer_ko": "1822",
        "answer_en": "1822",
        "solution_abst_ko": "1819 57 [OP_ADD] 6 9 [OP_SUB] [OP_SUB] 57 [OP_SUB]",
        "solution_abst_en": "1819 57 [OP_ADD] 6 9 [OP_SUB] [OP_SUB] 57 [OP_SUB]",
        "solution_code_ko": "var_a = 1819\nvar_b = 57\nvar_c = var_a + var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nvar_h = 57\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1819\nvar_b = 57\nvar_c = var_a + var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nvar_h = 57\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "2909": {
        "category": "Possibility",
        "question_ko": "5개의 1열로 있는 의자에 2학년 3명과 1학년 2명을 앉히려고 한다. 1학년 2명을 연속해서 앉히는 경우를 구하시오.",
        "question_en": "I'm trying to seat three second-graders and two first-graders on five chairs in a row. Find the case where two first-graders are seated consecutively.",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "[OP_LIST_SOL] A B C D E [OP_LIST_EOL] [OP_LIST_SOL] C [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] C D [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D E [OP_LIST_EOL] [OP_LIST_SOL] C [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] C D [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 'C'\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_g = len(list_c)\nvar_h = len(list_c)\nvar_i = 1\nvar_g = int(var_g)\nvar_h = int(var_h)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i * (var_g-i)\nvar_j = 'C'\nvar_k = 'D'\nlist_d= []\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_d.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_d.append(var_j)\nlist_d.reverse()\nvar_l = len(list_d)\nvar_m = len(list_d)\nvar_n = 1\nvar_l = int(var_l)\nvar_m = int(var_m)\nfor i, elem in enumerate(range(var_m)):\n    var_n = var_n * (var_l-i)\nvar_o = var_i * var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 'C'\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_g = len(list_c)\nvar_h = len(list_c)\nvar_i = 1\nvar_g = int(var_g)\nvar_h = int(var_h)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i * (var_g-i)\nvar_j = 'C'\nvar_k = 'D'\nlist_d= []\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_d.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_d.append(var_j)\nlist_d.reverse()\nvar_l = len(list_d)\nvar_m = len(list_d)\nvar_n = 1\nvar_l = int(var_l)\nvar_m = int(var_m)\nfor i, elem in enumerate(range(var_m)):\n    var_n = var_n * (var_l-i)\nvar_o = var_i * var_n\nprint(int(var_o))"
    },
    "2910": {
        "category": "Possibility",
        "question_ko": "0부터 9까지의 숫자 카드를 한 번씩 사용하여 네 자리 수를 만듭니다. 이 수 중 2번째 큰 수와 2번째 작은 수의 차를 구하시오.",
        "question_en": "Make a four-digit number by using the number cards from 0 to 9 once. Find the difference between the 2nd largest number and the 2nd smallest number.",
        "answer_ko": "8851",
        "answer_en": "8851",
        "solution_abst_ko": "0 9 1 [OP_LIST_ARANGE] 4 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "0 9 1 [OP_LIST_ARANGE] 4 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 0\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 2\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f - var_h\nvar_j = abs(var_i)\nprint(int(var_j))",
        "solution_code_en": "var_a = 0\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 2\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f - var_h\nvar_j = abs(var_i)\nprint(int(var_j))"
    },
    "2911": {
        "category": "Geometry",
        "question_ko": "직육면체에서, 어느 한 모서리와 한 점에서 만나는 면의 수를 구하면 모두 몇 개 인가요?",
        "question_en": "How many faces of a regular octahedron meet at one vertex?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "4",
        "solution_abst_en": "4",
        "solution_code_ko": "var_a = 4\nprint(int(var_a))",
        "solution_code_en": "var_a = 4\nprint(int(var_a))"
    },
    "2912": {
        "category": "Geometry",
        "question_ko": "여덟 개의 변으로 이루어진 도형의 모든 변의 길이가 같고, 이 도형의 둘레가 23.6센티미터(㎝)라면 한 변의 길이는 몇 센티미터(㎝)일지 구하시오.",
        "question_en": "If all eight sides of a figure are the same in length and the perimeter of the figure is 23.6 centimeters (cm), what is the length of one side in cm (cm)?",
        "answer_ko": "2.95",
        "answer_en": "2.95",
        "solution_abst_ko": "23.6 8 [OP_DIV]",
        "solution_abst_en": "23.6 8 [OP_DIV]",
        "solution_code_ko": "var_a = 23.6\nvar_b = 8\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 23.6\nvar_b = 8\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "2913": {
        "category": "Arithmetic calculation",
        "question_ko": "사탕을 1번째 날 1249개 팔았습니다. 2번째 날은 1번째 날보다 328개 더 팔았습니다. 3번째 날은 2번째 날보다 275개 더 팔았더니 367개 남았습니다. 처음에 있던 사탕은 몇 개인지 구하시오.",
        "question_en": "You sold 1249 candies on Day 1. On Day 2, you sold 328 more candies than Day 1. On day 3, you sold 275 more candies than Day 2, leaving 367 left. How many candies were there at the beginning?",
        "answer_ko": "5045",
        "answer_en": "5045",
        "solution_abst_ko": "367 1249 [OP_ADD] 1249 328 [OP_ADD] [OP_ADD] 1249 328 [OP_ADD] 275 [OP_ADD] [OP_ADD]",
        "solution_abst_en": "367 1249 [OP_ADD] 1249 328 [OP_ADD] [OP_ADD] 1249 328 [OP_ADD] 275 [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 367\nvar_b = 1249\nvar_c = var_a + var_b\nvar_d = 1249\nvar_e = 328\nvar_f = var_d + var_e\nvar_g = var_c + var_f\nvar_h = 1249\nvar_i = 328\nvar_j = var_h + var_i\nvar_k = 275\nvar_l = var_j + var_k\nvar_m = var_g + var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 367\nvar_b = 1249\nvar_c = var_a + var_b\nvar_d = 1249\nvar_e = 328\nvar_f = var_d + var_e\nvar_g = var_c + var_f\nvar_h = 1249\nvar_i = 328\nvar_j = var_h + var_i\nvar_k = 275\nvar_l = var_j + var_k\nvar_m = var_g + var_l\nprint(int(var_m))"
    },
    "2914": {
        "category": "Arithmetic calculation",
        "question_ko": "태형이의 삼촌 나이는 태형이보다 17살 더 많습니다. 4년 후 태형이의 나이와 삼촌의 나이의 합이 43살이 됩니다. 올해 태형이의 나이는 몇 살입니까?",
        "question_en": "Taehyung's uncle is 17 years older than Taehyung. Four years later, the sum of Taehyung's age and his uncle's age is 43 years old. How old is Taehyung this year?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "43 4 2 [OP_MUL] [OP_SUB] 17 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "43 4 2 [OP_MUL] [OP_SUB] 17 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 43\nvar_b = 4\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 17\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 43\nvar_b = 4\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 17\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "2915": {
        "category": "Arithmetic calculation",
        "question_ko": "희주네 학교 학생은 500명입니다. 이 중에서 라면을 좋아하는 학생은 289명이고, 빵을 좋아하는 학생은 337명입니다. 라면과 빵을 둘 다 좋아하지 않는 학생이 56명일 때, 라면과 빵을 모두 좋아하는 학생은 몇 명인지 구해보시오.",
        "question_en": "Heeju's school has 500 students. Among them, 289 students like ramen and 337 students like bread. If there are 56 students who do not like both ramen and bread, find how many students like both ramen and bread.",
        "answer_ko": "182",
        "answer_en": "182",
        "solution_abst_ko": "289 337 [OP_ADD] 500 56 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "289 337 [OP_ADD] 500 56 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 289\nvar_b = 337\nvar_c = var_a + var_b\nvar_d = 500\nvar_e = 56\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 289\nvar_b = 337\nvar_c = var_a + var_b\nvar_d = 500\nvar_e = 56\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "2916": {
        "category": "Arithmetic calculation",
        "question_ko": "바구니 안에 귤이 19개, 감이 몇 개 들어 있습니다. 바구니 안에 들어 있는 귤과 감이 모두 37개라면 감은 몇 개입니까?",
        "question_en": "There are 19 tangerines and some persimmons in the basket. How many persimmons are there if the total number of tangerines and persimmons is 37 in the basket?",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "37 19 [OP_SUB]",
        "solution_abst_en": "37 19 [OP_SUB]",
        "solution_code_ko": "var_a = 37\nvar_b = 19\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 37\nvar_b = 19\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "2917": {
        "category": "Correspondence",
        "question_ko": "어떤 나무는 1년마다 자라는 길이가 1미터(m)씩 줄어든다. 어떤 나무의 다자란 크기가 91미터(m)일 때, 첫번째 년도에 이 나무가 자란 길이를 구하시오.",
        "question_en": "Some trees lose 1 meter (m) of growth each year. If a tree's full growth is 91 meters (m), find the length the tree grew in the first year.",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "91 2 [OP_MUL] 1/2 [OP_POW] 1 [OP_FLOOR]",
        "solution_abst_en": "91 2 [OP_MUL] 1/2 [OP_POW] 1 [OP_FLOOR]",
        "solution_code_ko": "var_a = 91\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 1\nvar_g=int((var_e//(10**(var_f-1)))*10**(var_f-1))\n\nprint(int(var_g))",
        "solution_code_en": "var_a = 91\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 1\nvar_g=int((var_e//(10**(var_f-1)))*10**(var_f-1))\n\nprint(int(var_g))"
    },
    "2918": {
        "category": "Arithmetic calculation",
        "question_ko": "사과를 한 상자에 12개씩 담으면 55상자가 됩니다. 이 사과를 한 상자에 15개씩 담으면 몇 상자가 될까요?",
        "question_en": "If you put 12 apples in a box, you get 55 boxes. If you put 15 apples in each box, how many boxes will there be?",
        "answer_ko": "44",
        "answer_en": "44",
        "solution_abst_ko": "12 55 [OP_MUL] 15 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "12 55 [OP_MUL] 15 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 12\nvar_b = 55\nvar_c = var_a * var_b\nvar_d = 15\nvar_e = var_c / var_d\nvar_f = 1\nvar_g=int(((var_e+9*10**(var_f-2))//(10**(var_f-1)))*10**(var_f-1))\n\nprint(int(var_g))",
        "solution_code_en": "var_a = 12\nvar_b = 55\nvar_c = var_a * var_b\nvar_d = 15\nvar_e = var_c / var_d\nvar_f = 1\nvar_g=int(((var_e+9*10**(var_f-2))//(10**(var_f-1)))*10**(var_f-1))\n\nprint(int(var_g))"
    },
    "2919": {
        "category": "Geometry",
        "question_ko": "오면체에서 면은 모두 몇개인가요?",
        "question_en": "How many faces are there in the pentahedron?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "5",
        "solution_abst_en": "5",
        "solution_code_ko": "var_a = 5\nprint(int(var_a))",
        "solution_code_en": "var_a = 5\nprint(int(var_a))"
    },
    "2920": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 상자에 각각 사탕을 18개씩 담으면 사탕 3개가 남는다고 할 때, 6개의 상자에 사탕을 똑같이 나누어 담는다면 한 상자에 들어있는 사탕의 최대 개수는 몇 개 입니까?",
        "question_en": "If you put 18 candies in each of the 5 boxes, there is a shortage of 3 candies. If you put the equal amount of candies into 6 boxes, what is the maximum number of candies in one box?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "5 18 [OP_MUL] 3 [OP_ADD] 6 [OP_FDIV]",
        "solution_abst_en": "5 18 [OP_MUL] 3 [OP_ADD] 6 [OP_FDIV]",
        "solution_code_ko": "var_a = 5\nvar_b = 18\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = 6\nvar_g = var_e // var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 18\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = 6\nvar_g = var_e // var_f\nprint(int(var_g))"
    },
    "2921": {
        "category": "Correspondence",
        "question_ko": "식 691-6A7=4이 있습니다. A에 들어가야 하는 숫자를 구하시오",
        "question_en": "There is the expression 691-6A7=4. Find the number that goes into A",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "691-6A7=4 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "691-6A7=4 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '691-6A7=4'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '691-6A7=4'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "2922": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 150센티미터(㎝)인 빵을 1.5센티미터(㎝) 씩 자르려고 합니다. 빵을 모두 몇 개로 자를 수 있습니까?",
        "question_en": "You want to cut a loaf of bread that is 150 centimeters (cm) long by 1.5 centimeters (cm). How many pieces can be cut?",
        "answer_ko": "100",
        "answer_en": "100",
        "solution_abst_ko": "150 1.5 [OP_DIV]",
        "solution_abst_en": "150 1.5 [OP_DIV]",
        "solution_code_ko": "var_a = 150\nvar_b = 1.5\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 150\nvar_b = 1.5\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "2923": {
        "category": "Possibility",
        "question_ko": "2, 3, 7, 9 네 개의 버튼만 작동하는 계산기가 있습니다. 버튼을 한 번씩 눌러서 계산기에 수를 표현할 때, 표현할 수 있는 수 중 두 번째로 큰 수를 구하시오.",
        "question_en": "There is a calculator that only works with four buttons: 2, 3, 7, and 9. When making a four-digit number on the calculator by pressing the button without duplication, find the second largest number that can be made.",
        "answer_ko": "9723",
        "answer_en": "9723",
        "solution_abst_ko": "[OP_LIST_SOL] 2 3 7 9 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 2 3 7 9 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = 7\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint(int(var_g))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = 7\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint(int(var_g))"
    },
    "2924": {
        "category": "Comparison",
        "question_ko": "5개의 수 1.4, 9/10, 1.1, 0.5, 13/10이 있습니다. 이 중에서 0.9보다 큰 수는 모두 몇 개입니까?",
        "question_en": "There are five numbers 1.4, 9/10, 1.1, 0.5, and 13/10. How many of these numbers are greater than 0.9?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.1 0.5 13/10 [OP_LIST_EOL] 0.9 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.1 0.5 13/10 [OP_LIST_EOL] 0.9 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.1\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 0.9\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.1\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 0.9\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "2925": {
        "category": "Arithmetic calculation",
        "question_ko": "16킬로그램(㎏) 땅콩 1/6을 친구들과 나누어 먹으려고 한다. 한 사람이 4/15킬로그램(㎏)씩 먹는다고 하면 몇 명이 먹을 수 있나요?",
        "question_en": "You want to share 1/6 of 16 kilograms (kg) peanuts with your friends. If one person eats 4/15 kilograms (kg), how many people can eat?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "16 6 [OP_DIV] 4/15 [OP_DIV]",
        "solution_abst_en": "16 6 [OP_DIV] 4/15 [OP_DIV]",
        "solution_code_ko": "var_a = 16\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.26666666666666666\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 16\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.26666666666666666\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "2926": {
        "category": "Possibility",
        "question_ko": "1개의 상자에는 3개의 공이 들어 있습니다. 2개의 상자를 가지고 있을 때 전체 공의 개수는?",
        "question_en": "Each box contains 3 balls. If you have 2 boxes, what is the total number of balls?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "3 2 [OP_MUL]",
        "solution_abst_en": "3 2 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "2927": {
        "category": "Geometry",
        "question_ko": "정육면체에서 서로 평행한 면은 모두 몇 쌍 있습니까?",
        "question_en": "How many pairs of parallel faces are there in a cube?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "6 2 [OP_DIV]",
        "solution_abst_en": "6 2 [OP_DIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "2928": {
        "category": "Arithmetic calculation",
        "question_ko": "현경이가 가진 돈은 158760원이고 정연이가 가진 돈은 140원입니다. 현경이가 가진 돈은 정연이가 가진 돈의 몇 배인지 구하세요.",
        "question_en": "It is said that 140 U.S. dollars can be exchanged for 158,760 Korean won. What is the exchange rate of Korean money to the United States' money?",
        "answer_ko": "1134",
        "answer_en": "1134",
        "solution_abst_ko": "158760 140 [OP_DIV]",
        "solution_abst_en": "158760 140 [OP_DIV]",
        "solution_code_ko": "var_a = 158760\nvar_b = 140\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 158760\nvar_b = 140\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "2929": {
        "category": "Arithmetic calculation",
        "question_ko": "3년 전에는 어머니와 아들의 나이의 합이 49살이고 올해는 어머니의 나이가 아들의 4배일 때, 아들은 올해 몇 살 먹었습니까?",
        "question_en": "3 years ago, the sum of the ages of the mother and son was 49, and this year, when the mother is 4 times the age of the son, how old is the son this year?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "49 3 2 [OP_MUL] [OP_ADD] 1 4 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "49 3 2 [OP_MUL] [OP_ADD] 1 4 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 49\nvar_b = 3\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nvar_f = 1\nvar_g = 4\nvar_h = var_f + var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 49\nvar_b = 3\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nvar_f = 1\nvar_g = 4\nvar_h = var_f + var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "2930": {
        "category": "Geometry",
        "question_ko": "한 원의 한 반지름의 길이가 2일 때, 다른 한 반지름의 길이는?",
        "question_en": "If the length of one radius of a circle is 2, what is the length of the other radius?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "2",
        "solution_abst_en": "2",
        "solution_code_ko": "var_a = 2\nprint(int(var_a))",
        "solution_code_en": "var_a = 2\nprint(int(var_a))"
    },
    "2931": {
        "category": "Arithmetic calculation",
        "question_ko": "두 수의 차이가 28이고 큰 수에 13을 더한 값이 작은 수에 13을 더한 값에 두배일 때, 작은 수의 값을 구하시오.",
        "question_en": "Find the value of the smaller number when the difference between the two numbers is 28 and the larger number plus 13 is twice the smaller number plus 13.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "13 28 13 [OP_SUB] 2 [OP_MUL] [OP_ADD] 2 1 [OP_SUB] [OP_DIV] 28 [OP_SUB]",
        "solution_abst_en": "13 28 13 [OP_SUB] 2 [OP_MUL] [OP_ADD] 2 1 [OP_SUB] [OP_DIV] 28 [OP_SUB]",
        "solution_code_ko": "var_a = 13\nvar_b = 28\nvar_c = 13\nvar_d = var_b - var_c\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_a + var_f\nvar_h = 2\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_g / var_j\nvar_l = 28\nvar_m = var_k - var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 13\nvar_b = 28\nvar_c = 13\nvar_d = var_b - var_c\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_a + var_f\nvar_h = 2\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_g / var_j\nvar_l = 28\nvar_m = var_k - var_l\nprint(int(var_m))"
    },
    "2932": {
        "category": "Geometry",
        "question_ko": "넓이가 46제곱센티미터(㎠)인 삼각형 모양의 종이가 있습니다. 이 종이의 밑변이 10센티미터(㎝)라면 높이는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "You have a piece of paper in the shape of a triangle with an area of 46 square centimeters (cm2). If the base is 10 centimeters (cm), what is its height in centimeters (cm)?",
        "answer_ko": "9.20",
        "answer_en": "9.2",
        "solution_abst_ko": "46 2 [OP_MUL] 10 [OP_DIV]",
        "solution_abst_en": "46 2 [OP_MUL] 10 [OP_DIV]",
        "solution_code_ko": "var_a = 46\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 10\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 46\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 10\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "2933": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 왕수학 학원에서 킬로미터(㎞)A 수학학력평가에 120명이 응시하였습니다. 이 중 상장을 받은 학생이 상장을 받지 못한 학생보다 36명이 더 많았다면 상장을 받은 학생은 몇 명입니까?",
        "question_en": "At one Wang mathematical academy, 120 students took the A Mathematical Education Evaluation. If there were 36 more students who received certificates than those who did not receive certificates, how many students received certificates?",
        "answer_ko": "78",
        "answer_en": "78",
        "solution_abst_ko": "120 36 [OP_SUB] 2 [OP_DIV] 36 [OP_ADD]",
        "solution_abst_en": "120 36 [OP_SUB] 2 [OP_DIV] 36 [OP_ADD]",
        "solution_code_ko": "var_a = 120\nvar_b = 36\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 36\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 120\nvar_b = 36\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 36\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "2934": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 268.8미터(m)인 학교의 벽면을 따라 6.4미터(m) 간격으로 화단을 설치하려고 합니다. 학교의 벽면 양쪽 끝에 모두 화단을 설치할 때 필요한 화단의 개수는 몇 개입니까?",
        "question_en": "You want to install flower beds at intervals of 6.4 meters (m) along the wall of a school whose length is 268.8 meters (m). How many flower beds would be needed if flower beds are also installed at the both ends of the school walls?",
        "answer_ko": "43",
        "answer_en": "43",
        "solution_abst_ko": "268.8 6.4 [OP_DIV] 1 [OP_ADD]",
        "solution_abst_en": "268.8 6.4 [OP_DIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 268.8\nvar_b = 6.4\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 268.8\nvar_b = 6.4\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "2935": {
        "category": "Arithmetic calculation",
        "question_ko": "지우개가 총 28개 있습니다. 그 중에서 연주는 1/4만큼 지우개를 받았고 민지는 3/7만큼 지우개를 받았습니다. 남은 지우개의 개수는 몇 개입니까?",
        "question_en": "There are 28 erasers in total. Among them, Yeonju received 1/4 of the eraser and Minji received 3/7 of them. What is the number of remaining erasers?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "28 1 1/4 [OP_SUB] 3/7 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "28 1 1/4 [OP_SUB] 3/7 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 28\nvar_b = 1\nvar_c = 0.25\nvar_d = var_b - var_c\nvar_e = 0.42857142857142855\nvar_f = var_d - var_e\nvar_g = var_a * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 28\nvar_b = 1\nvar_c = 0.25\nvar_d = var_b - var_c\nvar_e = 0.42857142857142855\nvar_f = var_d - var_e\nvar_g = var_a * var_f\nprint(int(var_g))"
    },
    "2936": {
        "category": "Comparison",
        "question_ko": "경수네 모둠 학생들은 멀리뛰기를 하였습니다. 경수가 2.3미터(m), 영희가 9/10미터(m), 진주가 1.8미터(m), 찬호가 2.5미터(m)를 뛰었을 때, 2등은 누구입니까?",
        "question_en": "Kyungsoo's group of students did the long jump. When Kyungsoo jumped 2.3 meters (m), Younghee jumped 9/10 meters (m), Jinju jumped 1.8 meters (m), and Chanho jumped 2.5 meters (m), who came second?",
        "answer_ko": "경수",
        "answer_en": "Kyungsoo",
        "solution_abst_ko": "[OP_LIST_SOL] 경수 영희 진주 찬호 [OP_LIST_EOL] [OP_LIST_SOL] 2.3 9/10 1.8 2.5 [OP_LIST_EOL] 2 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Kyungsoo Younghee Jinju Chanho [OP_LIST_EOL] [OP_LIST_SOL] 2.3 9/10 1.8 2.5 [OP_LIST_EOL] 2 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '경수'\nvar_b = '영희'\nvar_c = '진주'\nvar_d = '찬호'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2.3\nvar_f = 0.9\nvar_g = 1.8\nvar_h = 2.5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Kyungsoo'\nvar_b = 'Younghee'\nvar_c = 'Jinju'\nvar_d = 'Chanho'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2.3\nvar_f = 0.9\nvar_g = 1.8\nvar_h = 2.5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "2937": {
        "category": "Correspondence",
        "question_ko": "2.5로 나눈 값에 10.5를 빼고 다시 0.3을 곱하면 5.85가 된다고 할 때, 이 수는 얼마입니까?",
        "question_en": "If we divide this value by 2.5 and take away 10.5 and then multiply it by 0.3, we get 5.85. What is this number?",
        "answer_ko": "75",
        "answer_en": "75",
        "solution_abst_ko": "5.85 0.3 [OP_DIV] 10.5 [OP_ADD] 2.5 [OP_MUL]",
        "solution_abst_en": "5.85 0.3 [OP_DIV] 10.5 [OP_ADD] 2.5 [OP_MUL]",
        "solution_code_ko": "var_a = 5.85\nvar_b = 0.3\nvar_c = var_a / var_b\nvar_d = 10.5\nvar_e = var_c + var_d\nvar_f = 2.5\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 5.85\nvar_b = 0.3\nvar_c = var_a / var_b\nvar_d = 10.5\nvar_e = var_c + var_d\nvar_f = 2.5\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "2938": {
        "category": "Correspondence",
        "question_ko": "61A+B3=645라는 식이 성립하려면, A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "What single digit number must be placed in A to make the equation 61A+B3=645?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "61A+B3=645 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "61A+B3=645 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '61A+B3=645'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '61A+B3=645'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "2939": {
        "category": "Geometry",
        "question_ko": "밑변이 3.6이고 높이가 밑변의 2.5배인 평행사변형이 있다. 평행사변형의 넓이를 구하시오.",
        "question_en": "There is a parallelogram that has a base of 3.6 and a height of 2.5 times the base. Find the area of this parallelogram.",
        "answer_ko": "32.40",
        "answer_en": "32.4",
        "solution_abst_ko": "3.6 3.6 2.5 [OP_MUL] [OP_MUL]",
        "solution_abst_en": "3.6 3.6 2.5 [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 3.6\nvar_b = 3.6\nvar_c = 2.5\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 3.6\nvar_b = 3.6\nvar_c = 2.5\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "2940": {
        "category": "Possibility",
        "question_ko": "7, 4, 0, 3, 5 중에서 서로 다른 숫자 2개를 뽑아 두 자리 수를 만들려고 합니다. 만들 수 있는 수 중에서 셋째로 큰 수와 셋째로 작은 수의 차를 구하시오.",
        "question_en": "You want to create a two-digit number by drawing two different numbers from 7, 4, 0, 3, and 5. Find the difference between the third largest number and the third smallest number.",
        "answer_ko": "38",
        "answer_en": "38",
        "solution_abst_ko": "[OP_LIST_SOL] 7 4 0 3 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "[OP_LIST_SOL] 7 4 0 3 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 7\nvar_b = 4\nvar_c = 0\nvar_d = 3\nvar_e = 5\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h - var_j\nvar_l = abs(var_k)\nprint(int(var_l))",
        "solution_code_en": "var_a = 7\nvar_b = 4\nvar_c = 0\nvar_d = 3\nvar_e = 5\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h - var_j\nvar_l = abs(var_k)\nprint(int(var_l))"
    },
    "2941": {
        "category": "Comparison",
        "question_ko": "108개의 빨간색 구슬, 파란색 구슬, 흰색 구슬이 있습니다. 파란색 구슬의 수는 빨간색 구슬의 1/3이고 흰색 구슬의 수는 파란색 구슬의 1/2입니다. 구슬의 수가 가장 적은 색은 무엇입니까?",
        "question_en": "There are 108 marbles of red marbles, blue marbles and white marbles. The number of blue marbles is 1/3 of the red marbles and the number of white marbles is 1/2 of the blue marbles. Which color has the least number of marbles?",
        "answer_ko": "흰색",
        "answer_en": "white",
        "solution_abst_ko": "[OP_LIST_SOL] 빨간색 파란색 흰색 [OP_LIST_EOL] [OP_LIST_SOL] 1 1/3 1/3 1/2 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] red blue white [OP_LIST_EOL] [OP_LIST_SOL] 1 1/3 1/3 1/2 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '빨간색'\nvar_b = '파란색'\nvar_c = '흰색'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nvar_e = 0.3333333333333333\nvar_f = 0.3333333333333333\nvar_g = 0.5\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'red'\nvar_b = 'blue'\nvar_c = 'white'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nvar_e = 0.3333333333333333\nvar_f = 0.3333333333333333\nvar_g = 0.5\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "2942": {
        "category": "Geometry",
        "question_ko": "가로가 6센티미터(㎝), 세로가 5센티미터(㎝), 높이가 4센티미터(㎝)인 직육면체의 모든 면에 초록색 물감을 칠하였습니다. 이 직육면체를 한 모서리의 길이가 1센티미터(㎝)인 정육면체 120개로 잘랐습니다. 색칠된 면이 없는 정육면체 조각은 몇 개입니까?",
        "question_en": "A rectangle 6 centimetres (cm) wide, 5 centimetres (cm) long and 4 centimetres (cm) high has been painted green on all sides. This rectangle is cut into 120 cubes, each 1 centimetre (cm) long. How many of the cubes have no coloured faces?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "6 2 [OP_SUB] 5 2 [OP_SUB] [OP_MUL] 4 2 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "6 2 [OP_SUB] 5 2 [OP_SUB] [OP_MUL] 4 2 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = var_c * var_f\nvar_h = 4\nvar_i = 2\nvar_j = var_h - var_i\nvar_k = var_g * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = var_c * var_f\nvar_h = 4\nvar_i = 2\nvar_j = var_h - var_i\nvar_k = var_g * var_j\nprint(int(var_k))"
    },
    "2943": {
        "category": "Geometry",
        "question_ko": "정수네 밭의 넓이가 143.2제곱미터(㎡)인 직사각형 모양이며, 이 밭의 세로가 4미터(m) 일 때, 가로는 몇 미터(m)입니까?",
        "question_en": "How many meters (m) is the width of Jeong Su's field if it is a rectangle with an area of 143.2 square meters (m2) and the length of this field is 4 meters (m)?",
        "answer_ko": "35.80",
        "answer_en": "35.8",
        "solution_abst_ko": "143.2 4 [OP_DIV]",
        "solution_abst_en": "143.2 4 [OP_DIV]",
        "solution_code_ko": "var_a = 143.2\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 143.2\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "2944": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 8을 곱했습니다. 곱한 결과에 64를 더했습니다. 계산의 결과가 336이라면 어떤 수는 얼마입니까?",
        "question_en": "A number multiplied by 8. 64 was added to the multiplied result. If the result of the calculation is 336, what is the number?",
        "answer_ko": "34",
        "answer_en": "34",
        "solution_abst_ko": "336 64 [OP_SUB] 8 [OP_DIV]",
        "solution_abst_en": "336 64 [OP_SUB] 8 [OP_DIV]",
        "solution_code_ko": "var_a = 336\nvar_b = 64\nvar_c = var_a - var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 336\nvar_b = 64\nvar_c = var_a - var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "2945": {
        "category": "Comparison",
        "question_ko": "세 수 A, B, C가 있습니다. A는 18보다 38 큰 수입니다. B는 A보다 26 작은 수입니다. C는 B를 3으로 나눈 몫입니다. 가장 작은 수는 어느 것입니까?",
        "question_en": "There are three numbers A, B and C. A is 38 greater than 18. B is 26 less than A. C is the quotient of B divided by 3. Which number is the smallest?",
        "answer_ko": "C",
        "answer_en": "C",
        "solution_abst_ko": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] 18 38 [OP_ADD] 18 38 [OP_ADD] 26 [OP_SUB] 18 38 [OP_ADD] 26 [OP_SUB] 3 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] 18 38 [OP_ADD] 18 38 [OP_ADD] 26 [OP_SUB] 18 38 [OP_ADD] 26 [OP_SUB] 3 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 18\nvar_e = 38\nvar_f = var_d + var_e\nvar_g = 18\nvar_h = 38\nvar_i = var_g + var_h\nvar_j = 26\nvar_k = var_i - var_j\nvar_l = 18\nvar_m = 38\nvar_n = var_l + var_m\nvar_o = 26\nvar_p = var_n - var_o\nvar_q = 3\nvar_r = var_p / var_q\nlist_b= []\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_s = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_t = list_c[var_s-1]\nvar_u = list_b.index(var_t)+1\nvar_v = list_a[var_u-1]\nprint(var_v)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 18\nvar_e = 38\nvar_f = var_d + var_e\nvar_g = 18\nvar_h = 38\nvar_i = var_g + var_h\nvar_j = 26\nvar_k = var_i - var_j\nvar_l = 18\nvar_m = 38\nvar_n = var_l + var_m\nvar_o = 26\nvar_p = var_n - var_o\nvar_q = 3\nvar_r = var_p / var_q\nlist_b= []\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_s = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_t = list_c[var_s-1]\nvar_u = list_b.index(var_t)+1\nvar_v = list_a[var_u-1]\nprint(var_v)"
    },
    "2946": {
        "category": "Geometry",
        "question_ko": "동전의 반지름의 길이가 7센티미터(㎝)일 때, 동전의 지름의 길이는 몇 센티미터(㎝)인가요?",
        "question_en": "If the coin's radius is 7 centimeters (cm), how many centimeters (cm) is the coin's diameter?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "7 2 [OP_MUL]",
        "solution_abst_en": "7 2 [OP_MUL]",
        "solution_code_ko": "var_a = 7\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 7\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "2947": {
        "category": "Geometry",
        "question_ko": "한 모서리의 길이가 3㎝인 정육면체의 모든 면에 빨간색을 칠하였습니다. 그리고 이 정육면체를 한 모서리의 길이가 1㎝인 작은 정육면체 27개로 잘랐습니다. 3개의 면에 빨간색이 칠해져 있는 작은 정육면체 조각은 몇 개입니까?",
        "question_en": "He painted all the faces of a cube with an edge of 3 cm (cm) red. Then he cut this cube into 27 small cubes, each 1 cm (cm) long. How many of the small cubes have 3 faces painted red?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "8",
        "solution_abst_en": "8",
        "solution_code_ko": "var_a = 8\nprint(int(var_a))",
        "solution_code_en": "var_a = 8\nprint(int(var_a))"
    },
    "2948": {
        "category": "Possibility",
        "question_ko": "석진, 태형, 남준, 유정, 유나가 계산을 하기 위해 줄을 서있습니다. 이 때, 계산을 하는 순서가 달라지게 줄을 서는 방법은 모두 몇 가지가 있습니까?",
        "question_en": "Seokjin, Taehyung, Namjoon, Yoojeong, and Yuna are standing in line to checkout. At this time, how many ways are there to line up so that the order of payment differs?",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "[OP_LIST_SOL] 석진 태형 남준 유정 유나 [OP_LIST_EOL] [OP_LIST_LEN] 5 [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] Seokjin Taehyung Namjoon Yoojeong Yuna [OP_LIST_EOL] [OP_LIST_LEN] 5 [OP_PERM]",
        "solution_code_ko": "var_a = '석진'\nvar_b = '태형'\nvar_c = '남준'\nvar_d = '유정'\nvar_e = '유나'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 5\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nprint(int(var_h))",
        "solution_code_en": "var_a = 'Seokjin'\nvar_b = 'Taehyung'\nvar_c = 'Namjoon'\nvar_d = 'Yoojeong'\nvar_e = 'Yuna'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 5\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nprint(int(var_h))"
    },
    "2949": {
        "category": "Comparison",
        "question_ko": "말, 소, 돼지, 양, 토끼, 다람쥐 순으로 우리 안으로 들어갔습니다. 4위를 차지한 동물은?",
        "question_en": "Horses, cows, pigs, sheep, rabbits, and squirrels entered the pen in this order. Which animal took 4th place?",
        "answer_ko": "양",
        "answer_en": "sheep",
        "solution_abst_ko": "[OP_LIST_SOL] 말 소 돼지 양 토끼 다람쥐 [OP_LIST_EOL] 4 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Horses cows pigs sheep rabbits squirrels [OP_LIST_EOL] 4 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '말'\nvar_b = '소'\nvar_c = '돼지'\nvar_d = '양'\nvar_e = '토끼'\nvar_f = '다람쥐'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 4\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Horses'\nvar_b = 'cows'\nvar_c = 'pigs'\nvar_d = 'sheep'\nvar_e = 'rabbits'\nvar_f = 'squirrels'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 4\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "2950": {
        "category": "Possibility",
        "question_ko": "1, 2, 7의 숫자 카드 중 2장을 사용하여 만들 수 있는 두 자리 수는 모두 몇 개입니까?",
        "question_en": "How many two-digit numbers can be made using two of the number cards 1, 2, and 7?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 1 2 7 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 2 7 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 2\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 2\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "2951": {
        "category": "Geometry",
        "question_ko": "한 전시회장에서 작품을 걸 공간이 부족하여 가벽을 설치하기로 하였습니다. 이 벽의 가로의 길이가 5.4미터(m)이고, 세로의 길이가 2.5미터(m)일 때, 넓이는 몇 제곱미터(㎡)가 되겠습니까?",
        "question_en": "In one exhibition hall, there was not enough space to hang the work, so we decided to install a temporary wall. If the width of this wall is 5.4 meters (m) and the length is 2.5 meters (m), how many square meters (m2) will the area be?",
        "answer_ko": "13.50",
        "answer_en": "13.5",
        "solution_abst_ko": "5.4 2.5 [OP_MUL]",
        "solution_abst_en": "5.4 2.5 [OP_MUL]",
        "solution_code_ko": "var_a = 5.4\nvar_b = 2.5\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 5.4\nvar_b = 2.5\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "2952": {
        "category": "Comparison",
        "question_ko": "높이가 3센티미터(㎝)인 (가) 상자와 높이가 3.5센티미터(㎝)인 (나) 상자가 있습니다. 태형이는 (가) 상자를 쌓았고 윤기는 (나) 상자를 쌓았습니다. 태형이와 윤기가 각각 상자를 16층, 14층으로 쌓았다면, 상자를 더 높이 쌓은 사람은 누구인지 구하시오.",
        "question_en": "There is a box A that is 3 centimeters (cm) high and box B with 3.5 centimeters (cm) high. Taehyung stacked the boxes A and Yoongi stacked the boxes B. If Taehyung and Yoongi each stacked the boxes up to 16th and 14th floors, respectively, find out who stacked the boxes higher.",
        "answer_ko": "윤기",
        "answer_en": "Yoongi",
        "solution_abst_ko": "[OP_LIST_SOL] 태형 윤기 [OP_LIST_EOL] [OP_LIST_SOL] 3 16 [OP_MUL] 3.5 14 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Taehyung Yoongi [OP_LIST_EOL] [OP_LIST_SOL] 3 16 [OP_MUL] 3.5 14 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '태형'\nvar_b = '윤기'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nvar_d = 16\nvar_e = var_c * var_d\nvar_f = 3.5\nvar_g = 14\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Taehyung'\nvar_b = 'Yoongi'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nvar_d = 16\nvar_e = var_c * var_d\nvar_f = 3.5\nvar_g = 14\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "2953": {
        "category": "Correspondence",
        "question_ko": "윤기는 어떤 수에 7을 곱하려고 합니다. 하지만 실수로 9를 더했더니 결과는 30이 되었습니다. 바르게 계산한 결과를 구하세요.",
        "question_en": "Yoongi is going to multiply a number by 7. But when he accidentally added 9, the result was 30. Find the correct calculation result.",
        "answer_ko": "147",
        "answer_en": "147",
        "solution_abst_ko": "30 9 [OP_SUB] 7 [OP_MUL]",
        "solution_abst_en": "30 9 [OP_SUB] 7 [OP_MUL]",
        "solution_code_ko": "var_a = 30\nvar_b = 9\nvar_c = var_a - var_b\nvar_d = 7\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 30\nvar_b = 9\nvar_c = var_a - var_b\nvar_d = 7\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "2954": {
        "category": "Correspondence",
        "question_ko": "민수가 어떤 일의 2/9를 처리하는데 10일이 걸렸다. 그 일의 2/5를 처리하는데 며칠이 걸리는지 구하시오.",
        "question_en": "It took Minsu 10 days to complete 2/9 of the job. Find how many days it will take to complete 2/5 of the work.",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "10 2/9 [OP_DIV] 2/5 [OP_MUL]",
        "solution_abst_en": "10 2/9 [OP_DIV] 2/5 [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 0.2222222222222222\nvar_c = var_a / var_b\nvar_d = 0.4\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 0.2222222222222222\nvar_c = var_a / var_b\nvar_d = 0.4\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "2955": {
        "category": "Possibility",
        "question_ko": "7, 4, 0, 3, 5 중에서 서로 다른 숫자 2개를 뽑아 두 자리 수를 만들려고 합니다. 만들 수 있는 수 중에서 셋째로 큰 수와 셋째로 작은 수의 곱을 구하시오.",
        "question_en": "You want to create a two-digit number by drawing two different numbers from 7, 4, 0, 3, and 5. Find the product of the third largest number and the third smallest number.",
        "answer_ko": "2555",
        "answer_en": "2555",
        "solution_abst_ko": "[OP_LIST_SOL] 7 4 0 3 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 7 4 0 3 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_MUL]",
        "solution_code_ko": "var_a = 7\nvar_b = 4\nvar_c = 0\nvar_d = 3\nvar_e = 5\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 7\nvar_b = 4\nvar_c = 0\nvar_d = 3\nvar_e = 5\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h * var_j\nprint(int(var_k))"
    },
    "2956": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 6을 곱하고 1.5로 나눈 값이 3.8이라고 한다. 어떤 수를 구하시오.",
        "question_en": "A number multiplied by 6 and divided by 1.5 equals 3.8. Find a number.",
        "answer_ko": "0.95",
        "answer_en": "0.95",
        "solution_abst_ko": "3.8 1.5 [OP_MUL] 6 [OP_DIV]",
        "solution_abst_en": "3.8 1.5 [OP_MUL] 6 [OP_DIV]",
        "solution_code_ko": "var_a = 3.8\nvar_b = 1.5\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 3.8\nvar_b = 1.5\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "2957": {
        "category": "Possibility",
        "question_ko": "일곱 개의 숫자 0, 1, 2, 3, 4, 5, 6을 한 번씩 사용하여 일곱 자리 수를 만들었다. 이 수가 55의 배수일 때, 세 번째로 작은 수를 구하여라.",
        "question_en": "The seven digits 0, 1, 2, 3, 4, 5, and 6 are used once to form a seven-digit number. If this number is a multiple of 55, find the third smallest of this number.",
        "answer_ko": "1062435",
        "answer_en": "1062435",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 4 5 6 [OP_LIST_EOL] 7 [OP_LIST_GET_PERM] 55 [OP_LIST_DIVISIBLE] 3 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 4 5 6 [OP_LIST_EOL] 7 [OP_LIST_GET_PERM] 55 [OP_LIST_DIVISIBLE] 3 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nvar_f = 5\nvar_g = 6\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h = 7\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_h))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_i = 55\nlist_c = []\nvar_i = int(var_i)\nfor i in list_b:\n    i = int(i)\n    if i % var_i == 0:\n        list_c.append(i)\nvar_j = 3\nlist_d=list_c.copy()\nlist_d.sort()\nvar_k = list_d[var_j-1]\nprint(int(var_k))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nvar_f = 5\nvar_g = 6\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h = 7\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_h))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_i = 55\nlist_c = []\nvar_i = int(var_i)\nfor i in list_b:\n    i = int(i)\n    if i % var_i == 0:\n        list_c.append(i)\nvar_j = 3\nlist_d=list_c.copy()\nlist_d.sort()\nvar_k = list_d[var_j-1]\nprint(int(var_k))"
    },
    "2958": {
        "category": "Geometry",
        "question_ko": "세 변의 길이가 각각 10 센티미터(㎝), 8 센티미터(㎝), 6 센티미터(㎝)인 직각삼각형의 외접원의 반지름의 길이는?",
        "question_en": "What is the length of the radius of the circumcircle of a right triangle with sides 10 centimeters (cm), 8 centimeters (cm), and 6 centimeters (cm), respectively?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "10 2 [OP_DIV]",
        "solution_abst_en": "10 2 [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 10\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "2959": {
        "category": "Arithmetic calculation",
        "question_ko": "유정이는 가지고 있던 사탕 중에서 언니에게 7개를 주고 동생에게 6개를 주었더니 15개가 남았습니다. 처음에 유정이가 가지고 있던 사탕은 몇 개입니까?",
        "question_en": "As Yoojung gave 7 candies to her older sister and 6 to her younger sister, there were 15 left on hand. Find number of candies Yoojung had at first.",
        "answer_ko": "28",
        "answer_en": "28",
        "solution_abst_ko": "15 6 [OP_ADD] 7 [OP_ADD]",
        "solution_abst_en": "15 6 [OP_ADD] 7 [OP_ADD]",
        "solution_code_ko": "var_a = 15\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 7\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 7\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "2960": {
        "category": "Comparison",
        "question_ko": "호박의 무게는 2킬로그램(㎏)과 9/10킬로그램(㎏)이고 수박의 무게는 41/10킬로그램(㎏)입니다. 호박과 수박 중 어느 것이 더 무겁습니까?",
        "question_en": "A pumpkin weighs 2 kilograms (kg) and 9/10 kilograms (kg), and a watermelon weighs 41/10 kilograms (kg). Which is heavier, pumpkin or watermelon?",
        "answer_ko": "수박",
        "answer_en": "watermelon",
        "solution_abst_ko": "[OP_LIST_SOL] 호박 수박 [OP_LIST_EOL] [OP_LIST_SOL] 2 9 10 [OP_DIV] [OP_ADD] 41 10 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] pumpkin watermelon [OP_LIST_EOL] [OP_LIST_SOL] 2 9 10 [OP_DIV] [OP_ADD] 41 10 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '호박'\nvar_b = '수박'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nvar_d = 9\nvar_e = 10\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nvar_h = 41\nvar_i = 10\nvar_j = var_h / var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'pumpkin'\nvar_b = 'watermelon'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nvar_d = 9\nvar_e = 10\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nvar_h = 41\nvar_i = 10\nvar_j = var_h / var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "2961": {
        "category": "Arithmetic calculation",
        "question_ko": "상헌이의 키는 1.56 미터(m) 입니다. 치호는 상헌이보다 0.14 미터(m) 작고 나라는 치호보다 0.27 미터(m) 크다고 합니 다. 나라의 키는 몇 미터(m)입니까?",
        "question_en": "Sangheon is 1.56 meters (m) tall. Chiho is 0.14 meters (m) shorter than Sangheon, and Nara is 0.27 meters (m) taller than Chiho. How tall is Nara in meters (m)?",
        "answer_ko": "1.69",
        "answer_en": "1.69",
        "solution_abst_ko": "1.56 0.14 [OP_SUB] 0.27 [OP_ADD]",
        "solution_abst_en": "1.56 0.14 [OP_SUB] 0.27 [OP_ADD]",
        "solution_code_ko": "var_a = 1.56\nvar_b = 0.14\nvar_c = var_a - var_b\nvar_d = 0.27\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 1.56\nvar_b = 0.14\nvar_c = var_a - var_b\nvar_d = 0.27\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "2962": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 29를 빼고 64를 더했더니 76이 되었습니다. 어떤 수를 구하시오.",
        "question_en": "Subtract 29 from this number and add 64 to get 76. Find the number.",
        "answer_ko": "41",
        "answer_en": "41",
        "solution_abst_ko": "76 64 [OP_SUB] 29 [OP_ADD]",
        "solution_abst_en": "76 64 [OP_SUB] 29 [OP_ADD]",
        "solution_code_ko": "var_a = 76\nvar_b = 64\nvar_c = var_a - var_b\nvar_d = 29\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 76\nvar_b = 64\nvar_c = var_a - var_b\nvar_d = 29\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "2963": {
        "category": "Comparison",
        "question_ko": "정국에는 6에서 3을 합한 수를 모았고, 윤기는 4, 유나는 5를 모았습니다. 누가 가장 작은 수를 가지고 있나요?",
        "question_en": "Jungkook collected 6 plus 3 points, Yoongi collected 4 points, and Yuna collected 5 points. Who has the smallest number?",
        "answer_ko": "윤기",
        "answer_en": "Yoongi",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 윤기 유나 [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_ADD] 4 5 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Yoongi Yuna [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_ADD] 4 5 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '윤기'\nvar_c = '유나'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 6\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = 4\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Yoongi'\nvar_c = 'Yuna'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 6\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = 4\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "2964": {
        "category": "Correspondence",
        "question_ko": "A, B는 서로 다른 한 자리 수입니다. 다음 곱셈식 AB×6=BBB에서 A+B의 값을 구하시오.",
        "question_en": "A and B are different single-digit numbers. Find the value of A+B that correspond to the following multiplication equation AB×6=BBB.",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "AB×6=BBB A [OP_DIGIT_UNK_SOLVER] AB×6=BBB B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_abst_en": "AB×6=BBB A [OP_DIGIT_UNK_SOLVER] AB×6=BBB B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_code_ko": "var_a = 'AB×6=BBB'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 'AB×6=BBB'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 'AB×6=BBB'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 'AB×6=BBB'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "2965": {
        "category": "Geometry",
        "question_ko": "세로가 3.6킬로미터(㎞)이고 가로가 세로의 2.5배인 직사각형 모양이 농장이 있습니다. 이 농장의 반은 소를 키우는 곳이고, 반은 돼지를 키우는 곳일 때 소를 키우는 곳의 넓이는 몇 ㎢인지 구하시오.",
        "question_en": "There is a farm in the shape of a rectangle with a length of 3.6 kilometers (km) and a width 2.5 times its length. If half of this farm is for cattle and half is for pigs, find the area of the cattle area in square kilometers (km2).",
        "answer_ko": "16.20",
        "answer_en": "16.2",
        "solution_abst_ko": "3.6 3.6 2.5 [OP_MUL] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "3.6 3.6 2.5 [OP_MUL] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 3.6\nvar_b = 3.6\nvar_c = 2.5\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 3.6\nvar_b = 3.6\nvar_c = 2.5\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "2966": {
        "category": "Comparison",
        "question_ko": "우유를 민현이는 6리터(L)의 0.41배만큼 마셨고 진영이는 2.3리터(L)를 마셨습니다. 우유를 누가 몇 더 많이 마셨습니까?",
        "question_en": "Minhyun drank 0.41 times more milk than 6 liters (L) and Jinyoung drank 2.3 liters (L). Who has drunk more milk?",
        "answer_ko": "민현",
        "answer_en": "Minhyun",
        "solution_abst_ko": "[OP_LIST_SOL] 민현 진영 [OP_LIST_EOL] [OP_LIST_SOL] 6 0.41 [OP_MUL] 2.3 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Minhyun Jinyoung [OP_LIST_EOL] [OP_LIST_SOL] 6 0.41 [OP_MUL] 2.3 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '민현'\nvar_b = '진영'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 0.41\nvar_e = var_c * var_d\nvar_f = 2.3\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Minhyun'\nvar_b = 'Jinyoung'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 0.41\nvar_e = var_c * var_d\nvar_f = 2.3\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "2967": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 마라톤 대회에 참가한 사람 수는 1250명입니다. 출발하여 뛰는 도중 포기한 사람이 완주한 사람보다 124명 더 많았다면 완주한 사람은 몇 명입니까?",
        "question_en": "1250 people participated in a marathon. If there were 124 more people who gave up during running than finished people, how many people finished?",
        "answer_ko": "563",
        "answer_en": "563",
        "solution_abst_ko": "1250 124 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "1250 124 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 1250\nvar_b = 124\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 1250\nvar_b = 124\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "2968": {
        "category": "Arithmetic calculation",
        "question_ko": "6명의 학생이 (가) 운동을 하고 있고, (나) 운동을 하는 학생 수는 (가) 운동을 하는 학생 수의 4배입니다. (나) 운동을 하는 학생은 몇 명입니까?",
        "question_en": "There are 6 students playing (a) sports, and the number of students playing (b) sports is 4 times the number of students playing (a) sports. How many students do (b) sports?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "6 4 [OP_MUL]",
        "solution_abst_en": "6 4 [OP_MUL]",
        "solution_code_ko": "var_a = 6\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "2969": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 15까지의 수들 중 홀수만 선택하여 왼쪽부터 작은 순서대로 나열하였다. 오른쪽에서 2번째에 있는 수와 왼쪽에서 2번째에 있는 수를 더한 값을 구하시오.",
        "question_en": "Among the numbers from 1 to 15, only odd numbers were selected and arranged in ascending order from left to right. Find the sum of the second number from the right and the second number from the left.",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "1 15 [OP_LIST_ODD] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "1 15 [OP_LIST_ODD] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 15\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[-var_c]\nvar_e = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = var_d + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 15\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[-var_c]\nvar_e = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = var_d + var_f\nprint(int(var_g))"
    },
    "2970": {
        "category": "Geometry",
        "question_ko": "밑면의 모양이 십이각형인 각뿔이 있습니다. 이 각뿔의 면의 수는 몇 개입니까?",
        "question_en": "There is a pyramid whose base side is a dodecagon. How many faces does this pyramid have?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "12 1 [OP_ADD]",
        "solution_abst_en": "12 1 [OP_ADD]",
        "solution_code_ko": "var_a = 12\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 12\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "2971": {
        "category": "Comparison",
        "question_ko": "호석이와 친구들은 모두 16명입니다. 호석이 오른쪽에 8명이 있을 때 호석이의 왼쪽에는 몇 명이 있습니까?",
        "question_en": "There are 16 of Hoseok and his friends. How many friends are to Hoseok's left when there are 8 friends to Hoseok's right?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "16 8 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "16 8 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 16\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 16\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "2972": {
        "category": "Arithmetic calculation",
        "question_ko": "4의 배수이면서 5의 배수인 수 중 가장 큰 세 자리 수는?",
        "question_en": "What is the largest three-digit number that is a multiple of 4 and a multiple of 5?",
        "answer_ko": "980",
        "answer_en": "980",
        "solution_abst_ko": "100 999 1 [OP_LIST_ARANGE] 4 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_abst_en": "100 999 1 [OP_LIST_ARANGE] 4 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 4\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[-var_f]\nprint(int(var_g))",
        "solution_code_en": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 4\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[-var_f]\nprint(int(var_g))"
    },
    "2973": {
        "category": "Arithmetic calculation",
        "question_ko": "양팔 저울 한 쪽에 무게가 1050그램(g)인 수박 5개를 올려두었습니다. 무게의 합이 4.5킬로그램(㎏)인 같은 무게의 사과 중 2개를 양팔 저울의 반대쪽에 올려두었습니다. 저울의 수평을 맞추기 위해선 사과를 올려둔 쪽에 850그램(g)짜리 멜론을 몇 개 더 올려야 합니까?",
        "question_en": "Five watermelons that weigh 1050 grams (g) each were placed on one side of a pan balance scale. Two of nine apples of equal weight, each weighing 4.5 kilograms (kg), were placed on the opposite side of that scale. How many more melons weighing 850 grams (g) each must be placed on the side of the apples to level the scale?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "1050 5 [OP_MUL] 4.5 1000 [OP_MUL] 9 [OP_DIV] 2 [OP_MUL] [OP_SUB] 850 [OP_DIV]",
        "solution_abst_en": "1050 5 [OP_MUL] 4.5 1000 [OP_MUL] 9 [OP_DIV] 2 [OP_MUL] [OP_SUB] 850 [OP_DIV]",
        "solution_code_ko": "var_a = 1050\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 4.5\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = 9\nvar_h = var_f / var_g\nvar_i = 2\nvar_j = var_h * var_i\nvar_k = var_c - var_j\nvar_l = 850\nvar_m = var_k / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 1050\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 4.5\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = 9\nvar_h = var_f / var_g\nvar_i = 2\nvar_j = var_h * var_i\nvar_k = var_c - var_j\nvar_l = 850\nvar_m = var_k / var_l\nprint(int(var_m))"
    },
    "2974": {
        "category": "Comparison",
        "question_ko": "민영이는 달리기 시합에서 33등으로 결승선을 넘었고, 은지는 민영이보다 11명 앞에서 먼저 결승선을 넘었습니다. 은지의 등수는 몇 등입니까?",
        "question_en": "Minyoung crossed the finish line in 33rd place in the running race, and Eunji crossed the finish line before Minyoung while there are 11 people between them. What is Eunji's rank?",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "33 11 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "33 11 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 33\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 33\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "2975": {
        "category": "Possibility",
        "question_ko": "0, 2, 4, 6 중에서 세 숫자를 골라 세 자리 수를 만들 때, 만들 수 있는 세 자리 수의 합을 구하여라.",
        "question_en": "When choosing three numbers from 0, 2, 4, and 6 to make a three-digit number, find the sum of all the possible three-digit numbers.",
        "answer_ko": "7728",
        "answer_en": "7728",
        "solution_abst_ko": "[OP_LIST_SOL] 0 2 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0 2 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0\nvar_b = 2\nvar_c = 4\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 0\nvar_b = 2\nvar_c = 4\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint(int(var_f))"
    },
    "2976": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이네 아파트 단지에는 1동부터 25동까지 있고, 각 동마다 10층까지 있습니다. 각 층마다 8가구씩 있다면, 정국이네 아파트 단지에는 모두 몇 가구가 살 수 있습니까?",
        "question_en": "There are 1 to 25 buildings in Jungkook's apartment complex, and each building has up to 10 floors. If there are 8 households on each floor, how many households can live in Jungkook's apartment complex?",
        "answer_ko": "2000",
        "answer_en": "2000",
        "solution_abst_ko": "25 10 [OP_MUL] 8 [OP_MUL]",
        "solution_abst_en": "25 10 [OP_MUL] 8 [OP_MUL]",
        "solution_code_ko": "var_a = 25\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 25\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "2977": {
        "category": "Arithmetic calculation",
        "question_ko": "12 초과인 자연수 중에서 가장 작은 수는 얼마인지 구하시오",
        "question_en": "Find the smallest number of natural numbers in excess of 12.",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "12 1 [OP_ADD] 999 1 [OP_LIST_ARANGE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "12 1 [OP_ADD] 999 1 [OP_LIST_ARANGE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 12\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 999\nvar_e = 1\nlist_a = [i for i in range(var_c, var_d + 1, var_e)]\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 12\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 999\nvar_e = 1\nlist_a = [i for i in range(var_c, var_d + 1, var_e)]\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nprint(int(var_g))"
    },
    "2978": {
        "category": "Arithmetic calculation",
        "question_ko": "민정이네 가족은 0.2리터(L)짜리 주스를 매일 3개씩 마십니다. 일주일 동안 민정이네 가족이 마시는 주스는 모두 몇 리터(L)입니까?",
        "question_en": "Minjeong's family drinks 0.2 liters (L) of juices three times every day. How many liters (L) of juice does Minjeong's family drink in a week?",
        "answer_ko": "4.20",
        "answer_en": "4.2",
        "solution_abst_ko": "0.2 3 [OP_MUL] 7 [OP_MUL]",
        "solution_abst_en": "0.2 3 [OP_MUL] 7 [OP_MUL]",
        "solution_code_ko": "var_a = 0.2\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.2\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "2979": {
        "category": "Comparison",
        "question_ko": "키가 다른 32명의 학생을 키가 큰 순서대로 줄 세웠다.지민이는 앞에서 27번째에 서고, 유나는 앞에서 11번째에 섭니다. 지민이와 유나 사이에 서 있는 학생은 몇 명입니까?",
        "question_en": "32 students of different heights are lined up in order from tallest to shortest. Jimin stands 27th from the front, and Yuna stands 11th from the front. How many students are standing between Jimin and Yuna?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "27 11 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "27 11 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 27\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 27\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "2980": {
        "category": "Comparison",
        "question_ko": "4개의 숫자 0.8, 1/2, 0.9, 1/3가 있습니다. 3보다 작은 수의 합은 얼마인가요?",
        "question_en": "There are four numbers: 0.8, 1/2, 0.9, 1/3. What is the sum of numbers less than 3?",
        "answer_ko": "2.53",
        "answer_en": "2.53",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 3 [OP_LIST_LESS] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 3 [OP_LIST_LESS] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = []\nfor i in list_a:\n    if i < var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint('{:.2f}'.format(round(var_f+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = []\nfor i in list_a:\n    if i < var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint('{:.2f}'.format(round(var_f+1e-10,2)))"
    },
    "2981": {
        "category": "Arithmetic calculation",
        "question_ko": "22를 8로 나머지 없이 나누었을 때의 값을 소수로 나타내시오.",
        "question_en": "Express the decimal value when 22 is divided by 8 without remainder.",
        "answer_ko": "2.75",
        "answer_en": "2.75",
        "solution_abst_ko": "22 8 [OP_DIV]",
        "solution_abst_en": "22 8 [OP_DIV]",
        "solution_code_ko": "var_a = 22\nvar_b = 8\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 22\nvar_b = 8\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "2982": {
        "category": "Arithmetic calculation",
        "question_ko": "21을 A로 나눴더니 몫이 B가 되었고 나머지가 5가 되었습니다. A와 B는 자연수입니다. 가능한 B 중 가장 작은 수는 무엇일까요?",
        "question_en": "When 21 is divided by A, the quotient becomes B and the remainder 5. A and B are natural numbers. What is the smallest number out of all possible Bs?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "1",
        "solution_abst_en": "1",
        "solution_code_ko": "var_a = 1\nprint(int(var_a))",
        "solution_code_en": "var_a = 1\nprint(int(var_a))"
    },
    "2983": {
        "category": "Possibility",
        "question_ko": "마트에서 당근, 무, 오이를 판매하고 있는데, 영빈이는 두 종류를 살 수 있는 돈밖에 없습니다. 영빈이가 살 수 있는 가지 수는 몇 개입니까?",
        "question_en": "The supermarket sells carrots, pears, and cucumbers, but Youngbin only has enough money to buy two kinds. How many cases can Youngbin buy?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 당근 오이 무 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] carrots cucumbers pears [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '당근'\nvar_b = '오이'\nvar_c = '무'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f / (i+1)\nprint(int(var_f))",
        "solution_code_en": "var_a = 'carrots'\nvar_b = 'cucumbers'\nvar_c = 'pears'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f / (i+1)\nprint(int(var_f))"
    },
    "2984": {
        "category": "Possibility",
        "question_ko": "6보다 큰 한 자리 자연수들을 한 번씩 모두 사용하여 가장 큰 세 자리 수와 세 번째로 큰 세 자리수의 합을 구하시오.",
        "question_en": "Using all single-digit whole numbers greater than 6 once, find the sum of the largest three-digit number and the third largest three-digit number.",
        "answer_ko": "1884",
        "answer_en": "1884",
        "solution_abst_ko": "6 1 [OP_ADD] 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 3 [OP_LIST_MAX] [OP_ADD]",
        "solution_abst_en": "6 1 [OP_ADD] 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 3 [OP_LIST_MAX] [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = 1\nlist_a = [i for i in range(var_c, var_d + 1, var_e)]\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[-var_i]\nvar_k = var_h + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 6\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = 1\nlist_a = [i for i in range(var_c, var_d + 1, var_e)]\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[-var_i]\nvar_k = var_h + var_j\nprint(int(var_k))"
    },
    "2985": {
        "category": "Arithmetic calculation",
        "question_ko": "둘레가 3킬로미터(㎞)인 호수를 연정이와 동훈이가 자전거를 타고 같은 곳에서 서로 반대 방향으로 동시에 출발하였다. 연정이는 매분 100미터(m)의 속력으로, 동훈이는 매분 150미터(m)의 속력으로 자전거를 탄다. 두 사람이 몇 분 후에 처음으로 다시 만나는지 구하여라",
        "question_en": "Yeonjeong and Donghun rode bicycles on a lake with a circumference of 3 kilometers (km) and started at the same time in opposite directions from the same place. Yeonjeong rides at a speed of 100 meters (m) per minute, and Donghun rides a bicycle at a speed of 150 meters (m) per minute. Find how many minutes later the two meet again for the first time.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "3 100 1000 [OP_DIV] 150 1000 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_abst_en": "3 100 1000 [OP_DIV] 150 1000 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 3\nvar_b = 100\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = 150\nvar_f = 1000\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = var_a / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 3\nvar_b = 100\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = 150\nvar_f = 1000\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = var_a / var_h\nprint(int(var_i))"
    },
    "2986": {
        "category": "Correspondence",
        "question_ko": "123은 어떤 수에 48을 더해야 것을 잘못하여 84를 더하여 나온 결과입니다. 어떤 수를 구하세요.",
        "question_en": "123 is the result of adding 84 by mistake instead of 48 to a number. Find the number.",
        "answer_ko": "39",
        "answer_en": "39",
        "solution_abst_ko": "123 84 [OP_SUB]",
        "solution_abst_en": "123 84 [OP_SUB]",
        "solution_code_ko": "var_a = 123\nvar_b = 84\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 123\nvar_b = 84\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "2987": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 다른 끈이 2개 있습니다. 두 끈의 길이의 합은 64센티미터(㎝)이고 긴 끈은 짧은 끈보다 48센티미터(㎝) 더 깁니다. 긴 끈을 잘라서 짧은 끈과 길이가 같은 끈을 몇 개 만들 수 있는지 구하시오.",
        "question_en": "There are 2 straps of different lengths. The sum of the lengths of the two straps is 64 centimeters (cm), and the longer strap is 48 centimeters (cm) longer than the shorter strap. Find how many pieces of strap that equal the length of the shorter strap can be cut from the longer strap.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "64 48 [OP_SUB] 2 [OP_DIV] 48 [OP_ADD] 64 48 [OP_SUB] 2 [OP_DIV] [OP_DIV]",
        "solution_abst_en": "64 48 [OP_SUB] 2 [OP_DIV] 48 [OP_ADD] 64 48 [OP_SUB] 2 [OP_DIV] [OP_DIV]",
        "solution_code_ko": "var_a = 64\nvar_b = 48\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 48\nvar_g = var_e + var_f\nvar_h = 64\nvar_i = 48\nvar_j = var_h - var_i\nvar_k = 2\nvar_l = var_j / var_k\nvar_m = var_g / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 64\nvar_b = 48\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 48\nvar_g = var_e + var_f\nvar_h = 64\nvar_i = 48\nvar_j = var_h - var_i\nvar_k = 2\nvar_l = var_j / var_k\nvar_m = var_g / var_l\nprint(int(var_m))"
    },
    "2988": {
        "category": "Comparison",
        "question_ko": "어항에 물을 가득 채우려면 각각 가 그릇으로는 7번, 나 그릇으로는 8번, 다 그릇으로는 5번 물을 부어야 합니다. 그릇의 들이가 가장 큰 그릇은 무엇인가요?",
        "question_en": "To fill the fishbowl with water, you need to pour water 7 times with the A bowl, 8 times with the B bowl, and 5 times with the C bowl. Which bowl has the largest capacity?",
        "answer_ko": "다",
        "answer_en": "C",
        "solution_abst_ko": "[OP_LIST_SOL] 가 나 다 [OP_LIST_EOL] [OP_LIST_SOL] 1 7 [OP_DIV] 1 8 [OP_DIV] 1 5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] 1 7 [OP_DIV] 1 8 [OP_DIV] 1 5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '가'\nvar_b = '나'\nvar_c = '다'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nvar_e = 7\nvar_f = var_d / var_e\nvar_g = 1\nvar_h = 8\nvar_i = var_g / var_h\nvar_j = 1\nvar_k = 5\nvar_l = var_j / var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nvar_e = 7\nvar_f = var_d / var_e\nvar_g = 1\nvar_h = 8\nvar_i = var_g / var_h\nvar_j = 1\nvar_k = 5\nvar_l = var_j / var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "2989": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 9를 나누면 8이 됩니다. 윤기는 어떤 수에 11을 더했습니다. 이 값은 얼마입니까?",
        "question_en": "A number divided by 9 is 8. Yoongi added 11 to the number. How much is this value?",
        "answer_ko": "83",
        "answer_en": "83",
        "solution_abst_ko": "8 9 [OP_MUL] 11 [OP_ADD]",
        "solution_abst_en": "8 9 [OP_MUL] 11 [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 11\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 11\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "2990": {
        "category": "Possibility",
        "question_ko": "3장의 숫자 카드 6, 3, 8을 한 번씩만 사용하여 만들 수 있는 세 자리 수 중에서 가장 큰 수와 가장 작은 수의 차를 구하시오.",
        "question_en": "Find the difference between the largest and smallest three-digit numbers that can be formed by using the three number cards 6, 3, and 8 only once.",
        "answer_ko": "495",
        "answer_en": "495",
        "solution_abst_ko": "[OP_LIST_SOL] 6 3 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 6 3 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 6\nvar_b = 3\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 6\nvar_b = 3\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))"
    },
    "2991": {
        "category": "Arithmetic calculation",
        "question_ko": "2개의 수 1/6, 5/12를 합하면 얼마입니까?",
        "question_en": "What is the sum of the two numbers 1/6 and 5/12?",
        "answer_ko": "0.58",
        "answer_en": "0.58",
        "solution_abst_ko": "1/6 5/12 [OP_ADD]",
        "solution_abst_en": "1/6 5/12 [OP_ADD]",
        "solution_code_ko": "var_a = 0.16666666666666666\nvar_b = 0.4166666666666667\nvar_c = var_a + var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 0.16666666666666666\nvar_b = 0.4166666666666667\nvar_c = var_a + var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "2992": {
        "category": "Arithmetic calculation",
        "question_ko": "25개의 연속된 짝수의 합이 750입니다. 이 중 가장 작은 짝수를 쓰시오.",
        "question_en": "The sum of 25 consecutive even numbers is 750. Write the smallest even number among these.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "750 25 [OP_DIV] 25 2 [OP_FDIV] 2 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "750 25 [OP_DIV] 25 2 [OP_FDIV] 2 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 750\nvar_b = 25\nvar_c = var_a / var_b\nvar_d = 25\nvar_e = 2\nvar_f = var_d // var_e\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_c - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 750\nvar_b = 25\nvar_c = var_a / var_b\nvar_d = 25\nvar_e = 2\nvar_f = var_d // var_e\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_c - var_h\nprint(int(var_i))"
    },
    "2993": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 16을 빼면 37로 나누어 떨어지고 몫은 23입니다. 어떤 수는 얼마일지 구하시오.",
        "question_en": "Subtracting 16 from a certain number is divisible by 37, and the quotient is 23. Find what the number is that.",
        "answer_ko": "867",
        "answer_en": "867",
        "solution_abst_ko": "23 37 [OP_MUL] 16 [OP_ADD]",
        "solution_abst_en": "23 37 [OP_MUL] 16 [OP_ADD]",
        "solution_code_ko": "var_a = 23\nvar_b = 37\nvar_c = var_a * var_b\nvar_d = 16\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 23\nvar_b = 37\nvar_c = var_a * var_b\nvar_d = 16\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "2994": {
        "category": "Correspondence",
        "question_ko": "지민이는 34에 어떤 수를 빼려고 합니다. 실수로 20에 어떤 수를 더했을 때의 결과가 60이라면 바르게 계산한 결과를 구하세요.",
        "question_en": "Jimin wanted to subtract by a number from 34 but instead added the number to 20 to get 60. Find the correctly calculated value.",
        "answer_ko": "-6",
        "answer_en": "-6",
        "solution_abst_ko": "34 60 20 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "34 60 20 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 34\nvar_b = 60\nvar_c = 20\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 34\nvar_b = 60\nvar_c = 20\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "2995": {
        "category": "Geometry",
        "question_ko": "부피가 2744세제곱센티미터(㎤)인 정육면체가 있다. 이 정육면체의 밑면의 넓이를 높이로 나누면 몫이 얼마인지 구하시오.",
        "question_en": "A cube has a volume of 2744 cubic centimeters (cm3). If you divide the area of the base of this cube by the height, what is the quotient?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "2744 1/3 [OP_POW]",
        "solution_abst_en": "2744 1/3 [OP_POW]",
        "solution_code_ko": "var_a = 2744\nvar_b = 0.3333333333333333\nvar_c = var_a ** var_b\nprint(int(eval('{:.2f}'.format(round(var_c+1e-10,2)))))",
        "solution_code_en": "var_a = 2744\nvar_b = 0.3333333333333333\nvar_c = var_a ** var_b\nprint(int(eval('{:.2f}'.format(round(var_c+1e-10,2)))))"
    },
    "2996": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 100까지의 짝수의 합을 구하시오.",
        "question_en": "Find the sum of even numbers from 1 to 100.",
        "answer_ko": "2550",
        "answer_en": "2550",
        "solution_abst_ko": "1 100 [OP_LIST_EVEN] [OP_LIST_SUM]",
        "solution_abst_en": "1 100 [OP_LIST_EVEN] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 100\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nprint(int(var_c))",
        "solution_code_en": "var_a = 1\nvar_b = 100\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nprint(int(var_c))"
    },
    "2997": {
        "category": "Possibility",
        "question_ko": "선우는 가지고 있는 숫자 카드를 모두 이용하여 가장 작은 수를 만드는 게임을 하고 있습니다. 선우에게 2와 4가 적힌 카드가 있을 때, 어떤 수를 만들어야 합니까?",
        "question_en": "Sunwoo is playing a game of making the smallest number using all the number cards he has. If Sunwoo has cards with 2 and 4 written on them, what number should he make?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "[OP_LIST_SOL] 2 4 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 2 4 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_e = list_c[var_d-1]\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_e = list_c[var_d-1]\nprint(int(var_e))"
    },
    "2998": {
        "category": "Possibility",
        "question_ko": "4종류의 과일 중 15개를 선택하려고 한다. 각 과일을 2개 이상 선택한다고 할 때 과일을 선택하는 총 가지 수를 구하시오.",
        "question_en": "You want to choose 15 out of 4 types of fruits. Calculate the total number of choices of fruit, if you choose two or more of each fruit.",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "4 15 [OP_ADD] 4 2 [OP_MUL] [OP_SUB] 1 [OP_SUB] 15 4 2 [OP_MUL] [OP_SUB] [OP_COMB]",
        "solution_abst_en": "4 15 [OP_ADD] 4 2 [OP_MUL] [OP_SUB] 1 [OP_SUB] 15 4 2 [OP_MUL] [OP_SUB] [OP_COMB]",
        "solution_code_ko": "var_a = 4\nvar_b = 15\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = 15\nvar_k = 4\nvar_l = 2\nvar_m = var_k * var_l\nvar_n = var_j - var_m\nvar_o = 1\nvar_i = int(var_i)\nvar_n = int(var_n)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o * (var_i-i)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o / (i+1)\nprint(int(var_o))",
        "solution_code_en": "var_a = 4\nvar_b = 15\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = 15\nvar_k = 4\nvar_l = 2\nvar_m = var_k * var_l\nvar_n = var_j - var_m\nvar_o = 1\nvar_i = int(var_i)\nvar_n = int(var_n)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o * (var_i-i)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o / (i+1)\nprint(int(var_o))"
    },
    "2999": {
        "category": "Arithmetic calculation",
        "question_ko": "24명의 학생이 있습니다. 이 중 여학생에게만 색종이 50장을 똑같이 나누어 주었더니 2장이 남았습니다. 남학생의 수가 여학생의 수의 2배라면 여학생은 색종이를 몇 장씩 받게 되는지 구하시오.",
        "question_en": "There are 24 students. Among them, 50 sheets of colored paper were equally distributed to female students only, and 2 sheets were left. If the number of boys is twice the number of girls, how many pieces of colored paper will each girl receive?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "50 2 [OP_SUB] 24 2 1 [OP_ADD] [OP_FDIV] [OP_FDIV]",
        "solution_abst_en": "50 2 [OP_SUB] 24 2 1 [OP_ADD] [OP_FDIV] [OP_FDIV]",
        "solution_code_ko": "var_a = 50\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 24\nvar_e = 2\nvar_f = 1\nvar_g = var_e + var_f\nvar_h = var_d // var_g\nvar_i = var_c // var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 50\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 24\nvar_e = 2\nvar_f = 1\nvar_g = var_e + var_f\nvar_h = var_d // var_g\nvar_i = var_c // var_h\nprint(int(var_i))"
    },
    "3000": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 2.5를 곱한 다음 2.49 를 뺐더니 22.01이 되었습니다. 어떤 수를 2.5로 나눈 다음 2.49를 더하고 2.3을 곱한 후 22.01을 더한 값을 구하시오.",
        "question_en": "Multiply a number by 2.5 then subtract 2.49 to get 22.01. Divide the number by 2.5, add 2.49, multiply by 2.3, and add 22.01 to get the result.",
        "answer_ko": "36.75",
        "answer_en": "36.75",
        "solution_abst_ko": "22.01 2.49 [OP_ADD] 2.5 [OP_DIV] 2.5 [OP_DIV] 2.49 [OP_ADD] 2.3 [OP_MUL] 22.01 [OP_ADD]",
        "solution_abst_en": "22.01 2.49 [OP_ADD] 2.5 [OP_DIV] 2.5 [OP_DIV] 2.49 [OP_ADD] 2.3 [OP_MUL] 22.01 [OP_ADD]",
        "solution_code_ko": "var_a = 22.01\nvar_b = 2.49\nvar_c = var_a + var_b\nvar_d = 2.5\nvar_e = var_c / var_d\nvar_f = 2.5\nvar_g = var_e / var_f\nvar_h = 2.49\nvar_i = var_g + var_h\nvar_j = 2.3\nvar_k = var_i * var_j\nvar_l = 22.01\nvar_m = var_k + var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))",
        "solution_code_en": "var_a = 22.01\nvar_b = 2.49\nvar_c = var_a + var_b\nvar_d = 2.5\nvar_e = var_c / var_d\nvar_f = 2.5\nvar_g = var_e / var_f\nvar_h = 2.49\nvar_i = var_g + var_h\nvar_j = 2.3\nvar_k = var_i * var_j\nvar_l = 22.01\nvar_m = var_k + var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))"
    },
    "3001": {
        "category": "Correspondence",
        "question_ko": "60에 12를 더하고 3으로 나눈 값이 어떤 수에서 12를 빼고 3을 곱한 값과 같다고 한다. 어떤 수를 구하시오.",
        "question_en": "It is said that adding 12 to 60 and then dividing by 3 is equal to a number subtracted by 12 and then multiplied by 3. Find the number.",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "60 12 [OP_ADD] 3 [OP_DIV] 3 [OP_DIV] 12 [OP_ADD]",
        "solution_abst_en": "60 12 [OP_ADD] 3 [OP_DIV] 3 [OP_DIV] 12 [OP_ADD]",
        "solution_code_ko": "var_a = 60\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = 12\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 60\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = 12\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "3002": {
        "category": "Comparison",
        "question_ko": "수 5개 1.4, 9/10, 1.2, 0.5, 13/10 중 1.1보다 큰 숫자를 구하고, 그 중에서 가장 작은 숫자를 구하면 무엇입니까?",
        "question_en": "What is the smallest number among the numbers greater than 1.1 among the numbers 1.4, 9/10, 1.2, 0.5, and 13/10?",
        "answer_ko": "1.20",
        "answer_en": "1.2",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nprint('{:.2f}'.format(round(var_h+1e-10,2)))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nprint('{:.2f}'.format(round(var_h+1e-10,2)))"
    },
    "3003": {
        "category": "Correspondence",
        "question_ko": "윤기는 8에 어떤 수를 곱해 64를 얻었습니다. 어떤 수는 얼마입니까?",
        "question_en": "Yoongi multiplied 8 by some number and got 64. What number is it?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "64 8 [OP_DIV]",
        "solution_abst_en": "64 8 [OP_DIV]",
        "solution_code_ko": "var_a = 64\nvar_b = 8\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 64\nvar_b = 8\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "3004": {
        "category": "Possibility",
        "question_ko": "일곱 개의 숫자 0, 1, 2, 3, 4, 5, 6을 한 번씩 사용하여 일곱 자리 수를 만들었다. 이 수가 55의 배수일 때, 세 번째 큰 수를 구하여라.",
        "question_en": "Each of the seven digits 0, 1, 2, 3, 4, 5, and 6 are used only once to form a seven-digit number. If this number is a multiple of 55, find the third largest number.",
        "answer_ko": "6421305",
        "answer_en": "6421305",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 4 5 6 [OP_LIST_EOL] 7 [OP_LIST_GET_PERM] 55 [OP_LIST_DIVISIBLE] 3 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 4 5 6 [OP_LIST_EOL] 7 [OP_LIST_GET_PERM] 55 [OP_LIST_DIVISIBLE] 3 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nvar_f = 5\nvar_g = 6\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h = 7\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_h))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_i = 55\nlist_c = []\nvar_i = int(var_i)\nfor i in list_b:\n    i = int(i)\n    if i % var_i == 0:\n        list_c.append(i)\nvar_j = 3\nlist_d=list_c.copy()\nlist_d.sort()\nvar_k = list_d[-var_j]\nprint(int(var_k))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nvar_f = 5\nvar_g = 6\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h = 7\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_h))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_i = 55\nlist_c = []\nvar_i = int(var_i)\nfor i in list_b:\n    i = int(i)\n    if i % var_i == 0:\n        list_c.append(i)\nvar_j = 3\nlist_d=list_c.copy()\nlist_d.sort()\nvar_k = list_d[-var_j]\nprint(int(var_k))"
    },
    "3005": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 4배 한 다음 25을 곱하였더니 812가 되었습니다. 어떤 수를 구하시오.",
        "question_en": "A number multiplied by 4 and then multiplied by 25 gives 812. Find the number.",
        "answer_ko": "8.12",
        "answer_en": "8.12",
        "solution_abst_ko": "812 25 [OP_DIV] 4 [OP_DIV]",
        "solution_abst_en": "812 25 [OP_DIV] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 812\nvar_b = 25\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 812\nvar_b = 25\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "3006": {
        "category": "Arithmetic calculation",
        "question_ko": "민철이는 보라색 끈 3/4미터(m), 초록색 끈 4/5미터(m), 흰색 끈 2/3미터(m)를 가지고 있을 때, 민철이가 가지고 있는 끈은 모두 몇 미터(m)인지 구하시오.",
        "question_en": "If Mincheol has 3/4 meter (m) of purple string, 4/5 meter (m) of green string, and 2/3 meter (m) of white string, find out how many meters (m) of string Mincheol has.",
        "answer_ko": "2.22",
        "answer_en": "2.22",
        "solution_abst_ko": "3/4 4/5 [OP_ADD] 2/3 [OP_ADD]",
        "solution_abst_en": "3/4 4/5 [OP_ADD] 2/3 [OP_ADD]",
        "solution_code_ko": "var_a = 0.75\nvar_b = 0.8\nvar_c = var_a + var_b\nvar_d = 0.6666666666666666\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.75\nvar_b = 0.8\nvar_c = var_a + var_b\nvar_d = 0.6666666666666666\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "3007": {
        "category": "Arithmetic calculation",
        "question_ko": "사다리꼴의 밑변의 길이는 6/13미터(m)이고 높이는 2미터(m) 입니다. 사다리꼴의 밑변의 길이는 높이의 몇 배인가요?",
        "question_en": "The length of the base of the trapezoid is 6/13 meters (m), and the height is 2 meters (m). How many times the length of its base is the length of its height?",
        "answer_ko": "0.23",
        "answer_en": "0.23",
        "solution_abst_ko": "6/13 2 [OP_DIV]",
        "solution_abst_en": "6/13 2 [OP_DIV]",
        "solution_code_ko": "var_a = 0.46153846153846156\nvar_b = 2\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 0.46153846153846156\nvar_b = 2\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "3008": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 2를 빼면 5가 됩니다. 어떤 수에 2를 더한 수는 얼마입니까?",
        "question_en": "Subtracting 2 from a certain number gives 5. What is the value of the certain number plus 2?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "5 2 [OP_ADD] 2 [OP_ADD]",
        "solution_abst_en": "5 2 [OP_ADD] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3009": {
        "category": "Correspondence",
        "question_ko": "지훈이네 반 학생수는 35명보단 많고 70명보단 작습니다. 지훈이네 반 학생들이 6명씩 조를 짜면 3명이 남고 8명씩 조를 짜면 1명이 남는다. 지훈이네 반 학생수를 구하시오.",
        "question_en": "The number of students in Jihoon's class is more than 35 and less than 70. If Jihoon's classmates form groups of 6, there will be 3 left, and if they form groups of 8, 1 will remain. Find the number of students in Jihoon's class.",
        "answer_ko": "57",
        "answer_en": "57",
        "solution_abst_ko": "35 70 1 [OP_SUB] 1 [OP_LIST_ARANGE] 6 3 [OP_LIST_DIVIDE_AND_REMAIN] 8 1 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "35 70 1 [OP_SUB] 1 [OP_LIST_ARANGE] 6 3 [OP_LIST_DIVIDE_AND_REMAIN] 8 1 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 35\nvar_b = 70\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nvar_f = 6\nvar_g = 3\nlist_b = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_a:\n    i = int(i)\n    if i%var_f == var_g:\n        list_b.append(i)\nvar_h = 8\nvar_i = 1\nlist_c = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_b:\n    i = int(i)\n    if i%var_h == var_i:\n        list_c.append(i)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(int(var_k))",
        "solution_code_en": "var_a = 35\nvar_b = 70\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nvar_f = 6\nvar_g = 3\nlist_b = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_a:\n    i = int(i)\n    if i%var_f == var_g:\n        list_b.append(i)\nvar_h = 8\nvar_i = 1\nlist_c = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_b:\n    i = int(i)\n    if i%var_h == var_i:\n        list_c.append(i)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(int(var_k))"
    },
    "3010": {
        "category": "Correspondence",
        "question_ko": "박스안에 들어있는 사과를 8개의 바구니에 같은 양으로 나누어 담았더니 바구니마다 6개씩 담고 4개가 남았다. 사과의 개수를 8로 나누면 얼마인가?",
        "question_en": "When the apples in the box were divided into 8 baskets in equal amounts, each basket contained 6 apples, leaving 4 apples. What is the number of apples divided by 8?",
        "answer_ko": "6.50",
        "answer_en": "6.5",
        "solution_abst_ko": "6 8 [OP_MUL] 4 [OP_ADD] 8 [OP_DIV]",
        "solution_abst_en": "6 8 [OP_MUL] 4 [OP_ADD] 8 [OP_DIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 6\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "3011": {
        "category": "Correspondence",
        "question_ko": "윤기는 어떤 수에서 10을 빼 15를 얻었습니다. 어떤 수에 5를 더하면 얼마일까요?",
        "question_en": "Yoongi subtracted 10 from a certain number and got 15. What is the value when 5 is added to the number?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "15 10 [OP_ADD] 5 [OP_ADD]",
        "solution_abst_en": "15 10 [OP_ADD] 5 [OP_ADD]",
        "solution_code_ko": "var_a = 15\nvar_b = 10\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 10\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3012": {
        "category": "Geometry",
        "question_ko": "한 정육면체에서 면과 면이 만나는 곳의 길이를 전부 더하면 108센티미터(㎝)입니다. 이 정육면체에서 한 꼭짓점과 이웃한 꼭짓점을 연결한 선분의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "The sum of all the lengths of the cube where two sides meet is 108 centimetres (cm). In this cube, what is the length in centimetres of the line segment that connects one vertex to the next?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "108 4 3 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "108 4 3 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 108\nvar_b = 4\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 108\nvar_b = 4\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "3013": {
        "category": "Geometry",
        "question_ko": "길이가 28센티미터(㎝)인 철사를 4등분하면 몇 센티미터(㎝)로 나뉘는지 구하시오.",
        "question_en": "Find how many centimeters (cm) a wire of length 28 centimeters (cm) becomes when divided into quarters.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "28 4 [OP_DIV]",
        "solution_abst_en": "28 4 [OP_DIV]",
        "solution_code_ko": "var_a = 28\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 28\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "3014": {
        "category": "Geometry",
        "question_ko": "꼭짓점의 수와 면의 수의 합이 16인 각뿔이 있다. 이 각뿔의 모서리는 모두 몇개인가?",
        "question_en": "There is a pyramid whose sum of the number of vertices and the number of faces is 16. How many edges does this pyramid have?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "16 2 [OP_DIV] 1 [OP_SUB] 2 [OP_MUL]",
        "solution_abst_en": "16 2 [OP_DIV] 1 [OP_SUB] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 16\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 16\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "3015": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 100까지의 자연수 중 6의 배수들의 평균을 구하시오.",
        "question_en": "Find the average of the multiples of 6 among the natural numbers from 1 to 100.",
        "answer_ko": "51",
        "answer_en": "51",
        "solution_abst_ko": "1 100 1 [OP_LIST_ARANGE] 6 [OP_LIST_DIVISIBLE] [OP_LIST_MEAN]",
        "solution_abst_en": "1 100 1 [OP_LIST_ARANGE] 6 [OP_LIST_DIVISIBLE] [OP_LIST_MEAN]",
        "solution_code_ko": "var_a = 1\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)/len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)/len(list_b)\nprint(int(var_e))"
    },
    "3016": {
        "category": "Geometry",
        "question_ko": "다음 도형에서 그을 수 있는 대각선의 개수는 몇 개입니까? : 십오각형",
        "question_en": "How many diagonals can be drawn in the figure below? : Pentadecagon",
        "answer_ko": "90",
        "answer_en": "90",
        "solution_abst_ko": "15 15 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "15 15 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 15\nvar_b = 15\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 15\nvar_b = 15\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "3017": {
        "category": "Geometry",
        "question_ko": "서로 다른 두 점이 있을 때, 이 두 점을 지나는 직선의 수는?",
        "question_en": "Given two distinct points, how many straight lines pass through these two points?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "1",
        "solution_abst_en": "1",
        "solution_code_ko": "var_a = 1\nprint(int(var_a))",
        "solution_code_en": "var_a = 1\nprint(int(var_a))"
    },
    "3018": {
        "category": "Geometry",
        "question_ko": "운동장에 10명의 친구가 십각형을 그리고 서 있습니다. 자신의 양옆에 선 사람을 제외하고 모든 친구들과 악수를 한 번씩 할 때, 악수는 모두 몇 번 이루어집니까?",
        "question_en": "Ten friends are standing on the playground in the shape of a decagon. If you shake hands with all of your friends once, except for the person standing next to you, how many handshakes will you make?",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "10 10 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "10 10 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 10\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 10\nvar_b = 10\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "3019": {
        "category": "Arithmetic calculation",
        "question_ko": "도로에서 자동차들이 앞 뒤로 같은 간격으로 서 있습니다. 맨 앞 자동차와 맨 뒤 자동차의 거리가 242 미터(m)이고, 자동차 사이의 거리가 5.5미터(m)라면 거리에 있는 자동차는 모두 몇 대입니까?",
        "question_en": "Cars are equally spaced from the front and back on the road. If the distance between the first car and the last car is 242 meters (m), and the distance between the cars is 5.5 meters (m), how many cars are on the street?",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "242 5.5 [OP_FDIV] 1 [OP_ADD]",
        "solution_abst_en": "242 5.5 [OP_FDIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 242\nvar_b = 5.5\nvar_c = var_a // var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 242\nvar_b = 5.5\nvar_c = var_a // var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3020": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 273을 더해야 할 것을 잘못해서 빼었더니 477이 되었습니다. 바르게 계산하면 얼마입니까?",
        "question_en": "I have to add 273 to a number, but I accidentally subtract it from a number, and it became 477. How much is it if I calculate it correctly?",
        "answer_ko": "1023",
        "answer_en": "1023",
        "solution_abst_ko": "477 273 [OP_ADD] 273 [OP_ADD]",
        "solution_abst_en": "477 273 [OP_ADD] 273 [OP_ADD]",
        "solution_code_ko": "var_a = 477\nvar_b = 273\nvar_c = var_a + var_b\nvar_d = 273\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 477\nvar_b = 273\nvar_c = var_a + var_b\nvar_d = 273\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3021": {
        "category": "Arithmetic calculation",
        "question_ko": "네 자리 수와 두 자리 수의 덧셈에서 네 자리 수의 일의 자리 숫자 8을 5로 잘못 보고, 두 자리 수의 십의 자리 숫자와 일의 자리 숫자를 바꾸어 63으로 잘못 보고 계산하였더니 그 값이 2708이 되었습니다. 바르게 계산한 결과를 구하시오.",
        "question_en": "When adding a four-digit number to a two-digit number, the 8 in the ones place of the four-digit number was mistaken for 5, and the tens and ones places of the two-digit number were swapped and the number was mistaken for 63. In these circumstances, the result of the calculation was 2708. Find the result of the correct calculation.",
        "answer_ko": "2738",
        "answer_en": "2738",
        "solution_abst_ko": "2708 8 5 [OP_SUB] [OP_ADD] 63 36 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "2708 8 5 [OP_SUB] [OP_ADD] 63 36 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 2708\nvar_b = 8\nvar_c = 5\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 63\nvar_g = 36\nvar_h = var_f - var_g\nvar_i = var_e + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 2708\nvar_b = 8\nvar_c = 5\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 63\nvar_g = 36\nvar_h = var_f - var_g\nvar_i = var_e + var_h\nprint(int(var_i))"
    },
    "3022": {
        "category": "Possibility",
        "question_ko": "5개의 1열로 있는 의자에 2학년 3명과 1학년 2명을 앉히려고 한다. 2학년 3명을 연속해서 앉히는 경우를 구하시오.",
        "question_en": "I'm trying to seat three sophomores and two freshmen in five single-row chairs. Find the case where three sophomores are sitting right next to each other.",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "[OP_LIST_SOL] A B C D E [OP_LIST_EOL] [OP_LIST_SOL] A C [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] A C E [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D E [OP_LIST_EOL] [OP_LIST_SOL] A C [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] A C E [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 'A'\nvar_g = 'C'\nlist_b= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_h = len(list_c)\nvar_i = len(list_c)\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nvar_k = 'A'\nvar_l = 'C'\nvar_m = 'E'\nlist_d= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_d.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_d.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_d.append(var_k)\nlist_d.reverse()\nvar_n = len(list_d)\nvar_o = len(list_d)\nvar_p = 1\nvar_n = int(var_n)\nvar_o = int(var_o)\nfor i, elem in enumerate(range(var_o)):\n    var_p = var_p * (var_n-i)\nvar_q = var_j * var_p\nprint(int(var_q))",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 'A'\nvar_g = 'C'\nlist_b= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_h = len(list_c)\nvar_i = len(list_c)\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nvar_k = 'A'\nvar_l = 'C'\nvar_m = 'E'\nlist_d= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_d.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_d.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_d.append(var_k)\nlist_d.reverse()\nvar_n = len(list_d)\nvar_o = len(list_d)\nvar_p = 1\nvar_n = int(var_n)\nvar_o = int(var_o)\nfor i, elem in enumerate(range(var_o)):\n    var_p = var_p * (var_n-i)\nvar_q = var_j * var_p\nprint(int(var_q))"
    },
    "3023": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 연속된 홀수의 합이 195입니다. 이 연속된 5개의 홀수 중 2번째로 큰 수를 쓰시오.",
        "question_en": "The sum of 5 consecutive odd numbers is 195. Write the 2nd largest of these 5 odd numbers.",
        "answer_ko": "41",
        "answer_en": "41",
        "solution_abst_ko": "195 5 [OP_DIV] 5 2 [OP_FDIV] 2 [OP_MUL] [OP_ADD] 2 [OP_SUB]",
        "solution_abst_en": "195 5 [OP_DIV] 5 2 [OP_FDIV] 2 [OP_MUL] [OP_ADD] 2 [OP_SUB]",
        "solution_code_ko": "var_a = 195\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d // var_e\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_c + var_h\nvar_j = 2\nvar_k = var_i - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 195\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d // var_e\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_c + var_h\nvar_j = 2\nvar_k = var_i - var_j\nprint(int(var_k))"
    },
    "3024": {
        "category": "Arithmetic calculation",
        "question_ko": "낚시에 가서 오전에 (가) 물고기 4마리와 (나) 물고기 3마리를 잡았습니다. 오후에 물고기를 몇 마리 더 잡았더니 오늘 잡은 물고기는 모두 10마리가 되었습니다. 오후에 잡은 물고기는 몇 마리입니까?",
        "question_en": "You went fishing and caught 4 fish (a) and 3 fish (b) in the morning. I caught a few more fish in the afternoon, so today you caught 10 fish in total. How many fish did you catch in the afternoon?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "10 4 3 [OP_ADD] [OP_SUB]",
        "solution_abst_en": "10 4 3 [OP_ADD] [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 4\nvar_c = 3\nvar_d = var_b + var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 4\nvar_c = 3\nvar_d = var_b + var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "3025": {
        "category": "Correspondence",
        "question_ko": "어떤 수는 한 자리 수입니다. 어떤 수는 0보다 크고 2보다 작습니다. 어떤 수를 구하시오.",
        "question_en": "A certain number is a single digit. This number is greater than 0 and less than 2. Find this number.",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "1 9 1 [OP_LIST_ARANGE] 0 [OP_LIST_MORE] 2 [OP_LIST_LESS] 1 [OP_LIST_GET]",
        "solution_abst_en": "1 9 1 [OP_LIST_ARANGE] 0 [OP_LIST_MORE] 2 [OP_LIST_LESS] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 0\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nvar_e = 2\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = 1\nvar_g = list_c[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 0\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nvar_e = 2\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = 1\nvar_g = list_c[var_f-1]\nprint(int(var_g))"
    },
    "3026": {
        "category": "Arithmetic calculation",
        "question_ko": "미선이에게 만 원짜리 지폐가 5장, 천 원짜리 지폐가 3장, 백 원짜리 동전이 9개 있다면, 총 얼마가 있는지 구하시오.",
        "question_en": "If Miseon has 5 10,000 won bills, 3 1,000 won bills, and 9 100 won coins, find how much money he has in total.",
        "answer_ko": "53900",
        "answer_en": "53900",
        "solution_abst_ko": "10000 5 [OP_MUL] 1000 3 [OP_MUL] 100 9 [OP_MUL] [OP_ADD] [OP_ADD]",
        "solution_abst_en": "10000 5 [OP_MUL] 1000 3 [OP_MUL] 100 9 [OP_MUL] [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 10000\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 1000\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = 100\nvar_h = 9\nvar_i = var_g * var_h\nvar_j = var_f + var_i\nvar_k = var_c + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 10000\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 1000\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = 100\nvar_h = 9\nvar_i = var_g * var_h\nvar_j = var_f + var_i\nvar_k = var_c + var_j\nprint(int(var_k))"
    },
    "3027": {
        "category": "Arithmetic calculation",
        "question_ko": "색종이가 몇 장 있었습니다. 그중에서 9장을 사용하였더니 12장이 남았습니다. 처음에 있던 색종이는 몇 장입니까?",
        "question_en": "There were several pieces of colored paper. When 9 of them were used, 12 were left. How many sheets of colored paper were there at the beginning?",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "12 9 [OP_ADD]",
        "solution_abst_en": "12 9 [OP_ADD]",
        "solution_code_ko": "var_a = 12\nvar_b = 9\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 12\nvar_b = 9\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "3028": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 14.25미터(m)인 정사각형 모양의 밭의 넓이는 몇 제곱미터(㎡)입니까?",
        "question_en": "What is the area in square meters (m2) of a square field with a side length of 14.25 meters (m)?",
        "answer_ko": "203.06",
        "answer_en": "203.06",
        "solution_abst_ko": "14.25 2 [OP_POW]",
        "solution_abst_en": "14.25 2 [OP_POW]",
        "solution_code_ko": "var_a = 14.25\nvar_b = 2\nvar_c = var_a ** var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 14.25\nvar_b = 2\nvar_c = var_a ** var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "3029": {
        "category": "Comparison",
        "question_ko": "말, 소, 돼지, 양, 토끼, 다람쥐 순으로 담장에 들어섰다. 4위에 들어간 동물은?",
        "question_en": "A horse, a cow, a pig, a sheep, a rabbit, and a squirrel entered the fence in that order. Which animal came in fourth place?",
        "answer_ko": "양",
        "answer_en": "sheep",
        "solution_abst_ko": "[OP_LIST_SOL] 말 소 돼지 양 토끼 다람쥐 [OP_LIST_EOL] 4 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] horse cow pig sheep rabbit squirrel [OP_LIST_EOL] 4 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '말'\nvar_b = '소'\nvar_c = '돼지'\nvar_d = '양'\nvar_e = '토끼'\nvar_f = '다람쥐'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 4\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'horse'\nvar_b = 'cow'\nvar_c = 'pig'\nvar_d = 'sheep'\nvar_e = 'rabbit'\nvar_f = 'squirrel'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 4\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "3030": {
        "category": "Correspondence",
        "question_ko": "3A-21=14입니다. A는 얼마인가요?",
        "question_en": "3A-21=14. Find the value of A.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "3A-21=14 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "3A-21=14 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '3A-21=14'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '3A-21=14'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "3031": {
        "category": "Correspondence",
        "question_ko": "6은 어떤 수에 15를 곱해야 하는데 실수로 15를 나누어서 나온 결과입니다. 바르게 계산하면 얼마입니까?",
        "question_en": "6 is the result of accidentally dividing a number by 15 when it is supposed to be multiplied by 15. How much do you get if you calculate correctly?",
        "answer_ko": "1350",
        "answer_en": "1350",
        "solution_abst_ko": "15 6 15 [OP_MUL] [OP_MUL]",
        "solution_abst_en": "15 6 15 [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 15\nvar_b = 6\nvar_c = 15\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 6\nvar_c = 15\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nprint(int(var_e))"
    },
    "3032": {
        "category": "Geometry",
        "question_ko": "길이가 30 센티미터(㎝) 인 철사를 모두 사용하여 직사각형 모양을 한 개 만들려고 합니다. 직사각형의 짧은 변을 7센티미터(㎝) 로 할 때, 긴 변은 몇 센티미터(㎝) 로 해야 합니까?",
        "question_en": "You are going to use all of the 30 centimeters (cm) of wire to make one rectangular shape. If the short side of the rectangle is 7 centimeters (cm), how many centimeters (cm) should the long side be?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "30 2 [OP_DIV] 7 [OP_SUB]",
        "solution_abst_en": "30 2 [OP_DIV] 7 [OP_SUB]",
        "solution_code_ko": "var_a = 30\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 30\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3033": {
        "category": "Comparison",
        "question_ko": "3개의 숫자 5, 8, 4 중 두 번째로 큰 숫자는 무엇입니까?",
        "question_en": "Which of the three numbers 5, 8, and 4 is the second largest?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "[OP_LIST_SOL] 5 8 4 [OP_LIST_EOL] 2 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 5 8 4 [OP_LIST_EOL] 2 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 5\nvar_b = 8\nvar_c = 4\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 8\nvar_c = 4\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nprint(int(var_e))"
    },
    "3034": {
        "category": "Geometry",
        "question_ko": "이십각형이 있습니다. 한 꼭짓점에서 그을 수 있는 대각선의 개수는 모두 몇 개 인가요?",
        "question_en": "There is an icosagon. How many diagonals can be drawn from a vertex?",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "20 3 [OP_SUB]",
        "solution_abst_en": "20 3 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 20\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "3035": {
        "category": "Correspondence",
        "question_ko": "A, B, C는 서로 다른 세 자연수이다. A는 11로 나누면 몫이 B, 나머지가 C이다. C가 될 수 있는 수 중에 가장 큰 수를 구하여라.",
        "question_en": "A, B, and C are three different natural numbers. When A is divided by 11, the quotient is B and the remainder is C. Find the largest number that can be C.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "11 1 [OP_SUB]",
        "solution_abst_en": "11 1 [OP_SUB]",
        "solution_code_ko": "var_a = 11\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 11\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "3036": {
        "category": "Correspondence",
        "question_ko": "32를 더해야 하는데 23을 어떤 수에 잘못 더하였더니 68이 됐습니다. 어떤 수를 구하시오.",
        "question_en": "I need to add 32, but I accidently added 23 to some number, and I got 68 as a result. What number is this?",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "68 23 [OP_SUB]",
        "solution_abst_en": "68 23 [OP_SUB]",
        "solution_code_ko": "var_a = 68\nvar_b = 23\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 68\nvar_b = 23\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "3037": {
        "category": "Possibility",
        "question_ko": "5 이하의 홀수를 한 번씩만 이용하여 100이상 1000미만의 수를 만들 때, 가장 큰 수와 세 번째로 작은 수의 차는 얼마인가?",
        "question_en": "What is the difference between the largest number and the third smallest number possible when forming a number greater than or equal to 100 and less than 1000 with using odd numbers less than or equal to 5 only once?",
        "answer_ko": "216",
        "answer_en": "216",
        "solution_abst_ko": "0 5 [OP_LIST_ODD] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "0 5 [OP_LIST_ODD] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 0\nvar_b = 5\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_e = list_c[-var_d]\nvar_f = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_g = list_d[var_f-1]\nvar_h = var_e - var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 0\nvar_b = 5\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_e = list_c[-var_d]\nvar_f = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_g = list_d[var_f-1]\nvar_h = var_e - var_g\nprint(int(var_h))"
    },
    "3038": {
        "category": "Geometry",
        "question_ko": "양변의 길이가 12 센티미터(㎝)이고, 다른 변의 길이가 17 센티미터(㎝)인 이등변삼각형의 둘레의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "What is the perimeter in centimeters (cm) of an isosceles triangle with two sides measuring 12 centimeters (cm) and the other side measuring 17 centimeters (cm)?",
        "answer_ko": "41",
        "answer_en": "41",
        "solution_abst_ko": "12 2 [OP_MUL] 17 [OP_ADD]",
        "solution_abst_en": "12 2 [OP_MUL] 17 [OP_ADD]",
        "solution_code_ko": "var_a = 12\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 17\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 17\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3039": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 16센티미터(㎝)인 정오각형을 실을 사용하여 만들었습니다. 똑같은 실을 사용하여 정팔각형을 만들 때, 정팔각형의 한 모서리의 길이를 구하시오.",
        "question_en": "A regular pentagon with one edge 16 centimetres (cm) long is made with one piece of thread. If the same thread is used to make an octagon, find the length of one edge of the octagon.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "16 5 [OP_MUL] 8 [OP_DIV]",
        "solution_abst_en": "16 5 [OP_MUL] 8 [OP_DIV]",
        "solution_code_ko": "var_a = 16\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 16\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "3040": {
        "category": "Possibility",
        "question_ko": "연필 4종류와 볼펜 6종류가 있다. 연필과 볼펜을 각각 한 종류씩 고르는 경우의 수는?",
        "question_en": "There are 4 types of pencils and 6 types of ballpoint pens. How many ways can you choose one type of pencil and one type of ballpoint pen?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "4 6 [OP_MUL]",
        "solution_abst_en": "4 6 [OP_MUL]",
        "solution_code_ko": "var_a = 4\nvar_b = 6\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 6\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "3041": {
        "category": "Comparison",
        "question_ko": "A와 24는 서로 다른 자연수이다. 이 두 수가 약수 또는 배수 관계일 때 A에 해당하는 두 자리 수 중에서 세번째로 작은 수를 구하여라",
        "question_en": "A and 24 are different natural numbers. If these two numbers are divisors or multiples of each other, find the third smallest of the two-digit numbers corresponding to A.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "24 [OP_LIST_GET_DIVISOR] 24 99 24 [OP_LIST_ARANGE] [OP_SET_UNION] 3 [OP_LIST_MIN]",
        "solution_abst_en": "24 [OP_LIST_GET_DIVISOR] 24 99 24 [OP_LIST_ARANGE] [OP_SET_UNION] 3 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 24\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 24\nvar_c = 99\nvar_d = 24\nlist_b = [i for i in range(var_b, var_c + 1, var_d)]\nlist_c = list(set(list_a) | set(list_b))\nvar_e = 3\nlist_d=list_c.copy()\nlist_d.sort()\nvar_f = list_d[var_e-1]\nprint(int(var_f))",
        "solution_code_en": "var_a = 24\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 24\nvar_c = 99\nvar_d = 24\nlist_b = [i for i in range(var_b, var_c + 1, var_d)]\nlist_c = list(set(list_a) | set(list_b))\nvar_e = 3\nlist_d=list_c.copy()\nlist_d.sort()\nvar_f = list_d[var_e-1]\nprint(int(var_f))"
    },
    "3042": {
        "category": "Possibility",
        "question_ko": "다섯 개의 수 카드가 4, 2, 8, 1, 9로 있다면, 각 수 카드를 한 번씩만 사용하여 몫이 가장 큰 (세 자리 수)/(두 자리 수)를 만들었을 때의 몫이 어떻게 될까요?",
        "question_en": "If there are five number cards 4, 2, 8, 1, and 9, what is the value when each number card is used only once to make the largest quotient from (three-digit number)/(double-digit number)? ",
        "answer_ko": "82",
        "answer_en": "82",
        "solution_abst_ko": "[OP_LIST_SOL] 4 2 8 1 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] [OP_LIST_POP] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] [OP_FDIV]",
        "solution_abst_en": "[OP_LIST_SOL] 4 2 8 1 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] [OP_LIST_POP] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] [OP_FDIV]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = 8\nvar_d = 1\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 2\nlist_d = [str(i) for i in list_a]\nlist_d = list(itertools.permutations(list_d, var_i))\nlist_d = [''.join(num_list) for num_list in list_d]\nlist_d = [str_num for str_num in list_d if str_num[0] != '0']\nlist_d = [float(i) for i in list_d]\nvar_j = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_k = list_e[var_j-1]\nvar_l = var_h // var_k\nprint(int(var_l))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = 8\nvar_d = 1\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 2\nlist_d = [str(i) for i in list_a]\nlist_d = list(itertools.permutations(list_d, var_i))\nlist_d = [''.join(num_list) for num_list in list_d]\nlist_d = [str_num for str_num in list_d if str_num[0] != '0']\nlist_d = [float(i) for i in list_d]\nvar_j = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_k = list_e[var_j-1]\nvar_l = var_h // var_k\nprint(int(var_l))"
    },
    "3043": {
        "category": "Arithmetic calculation",
        "question_ko": "농장에서 토끼 49마리와 개구리 37마리를 기릅니다. 개구리와 닭의 수를 합하면 토끼보다 9마리 많습니다. 닭은 몇 마리입니까?",
        "question_en": "Suppose you have 49 rabbits and 37 frogs on the farm. The total number of frogs and chickens is larger than rabbits by 9. How many chickens do you have?",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "49 9 [OP_ADD] 37 [OP_SUB]",
        "solution_abst_en": "49 9 [OP_ADD] 37 [OP_SUB]",
        "solution_code_ko": "var_a = 49\nvar_b = 9\nvar_c = var_a + var_b\nvar_d = 37\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 49\nvar_b = 9\nvar_c = var_a + var_b\nvar_d = 37\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3044": {
        "category": "Comparison",
        "question_ko": "키가 작은 사람부터 순서대로 9명이 한 줄로 서 있습니다. 호석이가 가장 뒤에 서 있습니다. 키가 큰 사람부터 순서대로 다시 줄을 서면 호석이는 뒤에서부터 몇 번째에 서게 됩니까?",
        "question_en": "Nine people stand in a line in order of shortest to tallest. Hoseok stands at the very back. If you line up again in order of the tallest to the tallest, what number will Hoseok stand from the back?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "9 1 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "9 1 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 9\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3045": {
        "category": "Geometry",
        "question_ko": "밑면의 넓이가 3제곱센티미터(㎠)이고 옆면의 넓이가 6제곱센티미터(㎠)인 삼각뿔이 있다. 이 삼각뿔의 겉넓이를 구하시오.",
        "question_en": "A triangular pyramid has a base area of 3 square centimeters (cm2) and a side area of 6 square centimeters (cm2). Find the surface area of this triangular pyramid.",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "3 6 3 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "3 6 3 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 6\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 3\nvar_b = 6\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "3046": {
        "category": "Possibility",
        "question_ko": "바구니에서 뽑을 수 있는 기회는 2번입니다. 바구니 속에 사과, 복숭아, 배, 참외가 각각 1개씩 들어가 있다면, 뽑을 수 있는 경우의 수는 모두 몇 가지 입니까?",
        "question_en": "You have 2 chances to draw from the basket. If there are 1 apple, 1 peach, 1 pear, and 1 melon in each basket, how many ways can you pick them?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 복숭아 배 참외 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] apple peach pear melon [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '복숭아'\nvar_c = '배'\nvar_d = '참외'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g / (i+1)\nprint(int(var_g))",
        "solution_code_en": "var_a = 'apple'\nvar_b = 'peach'\nvar_c = 'pear'\nvar_d = 'melon'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g / (i+1)\nprint(int(var_g))"
    },
    "3047": {
        "category": "Comparison",
        "question_ko": "(가) 정육면체의 한 모서리의 길이는 5센티미터(㎝)이고, (나) 직육면체의 가로, 세로, 높이의 길이는 각각 4센티미터(㎝), 5센티미터(㎝), 6센티미터(㎝)입니다. (가)와 (나) 중에서 어느 것의 부피가 더 큰지 구하시오.",
        "question_en": "There is a cube whose length is 5 centimeters (cm), and a cuboid B with the width, depth, and height of 4 centimeters (cm), 5 centimeters (cm), and 6 centimeters (cm), respectively. Find which of A and B has the greater volume.",
        "answer_ko": "(가)",
        "answer_en": "A",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) [OP_LIST_EOL] [OP_LIST_SOL] 5 3 [OP_POW] 4 5 6 [OP_MUL] [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 5 3 [OP_POW] 4 5 6 [OP_MUL] [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 5\nvar_d = 3\nvar_e = var_c ** var_d\nvar_f = 4\nvar_g = 5\nvar_h = 6\nvar_i = var_g * var_h\nvar_j = var_f * var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 5\nvar_d = 3\nvar_e = var_c ** var_d\nvar_f = 4\nvar_g = 5\nvar_h = 6\nvar_i = var_g * var_h\nvar_j = var_f * var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "3048": {
        "category": "Arithmetic calculation",
        "question_ko": "어머니께서 주신 용돈 15000원을 규형이와 한별이가 나누어 가졌습니다. 규형이가 한별이보다 2400원 덜 가졌다면 규형이는 얼마를 가졌습니까?",
        "question_en": "Kyuhyung and Hanbyeol shared the 15,000 won allowance that their mother gave them. If Kyuhyung got 2400 won less than Hanbyeol, how much did Kyuhyung get?",
        "answer_ko": "6300",
        "answer_en": "6300",
        "solution_abst_ko": "15000 2400 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "15000 2400 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 15000\nvar_b = 2400\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15000\nvar_b = 2400\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "3049": {
        "category": "Arithmetic calculation",
        "question_ko": "유미가 기존에 있는 숫자를 10씩 작아지도록 4번 뛰어서 셌습니다. 처음 숫자가 320이었다면 유미가 센 수는 얼마입니까?",
        "question_en": "Yumi counted a number by reducing 10 for 4 times. If the original number was 320, what is the value of Yumi counted?",
        "answer_ko": "280",
        "answer_en": "280",
        "solution_abst_ko": "320 10 4 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "320 10 4 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 320\nvar_b = 10\nvar_c = 4\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 320\nvar_b = 10\nvar_c = 4\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "3050": {
        "category": "Possibility",
        "question_ko": "동전을 3번 던져서 신호를 만드려고 합니다. 가능한 신호는 모두 몇 가지입니까?",
        "question_en": "Try to make a signal by throwing a coin 3 times. How many possible signals are there in all?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "2 3 [OP_POW]",
        "solution_abst_en": "2 3 [OP_POW]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = var_a ** var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = var_a ** var_b\nprint(int(var_c))"
    },
    "3051": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 200까지의 수열에서 홀수의 합을 구하시오.",
        "question_en": "Find the sum of odd numbers in the sequence from 1 to 200.",
        "answer_ko": "10000",
        "answer_en": "10000",
        "solution_abst_ko": "1 200 [OP_LIST_ODD] [OP_LIST_SUM]",
        "solution_abst_en": "1 200 [OP_LIST_ODD] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 200\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nprint(int(var_c))",
        "solution_code_en": "var_a = 1\nvar_b = 200\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nprint(int(var_c))"
    },
    "3052": {
        "category": "Comparison",
        "question_ko": "25명의 학생이 한 줄로 서 있습니다. 유나의 뒤에 9명이 서 있을 때, 유나의 앞에는 몇 명의 학생이 서 있습니까?",
        "question_en": "25 students stand in a line. When 9 students are standing behind Yuna, how many students are standing in front of Yuna?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "25 9 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "25 9 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 25\nvar_b = 9\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 25\nvar_b = 9\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3053": {
        "category": "Geometry",
        "question_ko": "어떤 각기둥에서 꼭짓점, 면, 모서리의 수의 합은 44개입니다. 이 각기둥의 모서리의 수는?",
        "question_en": "The sum of the vertices, faces, and edges of a certain prism is 44. How many edges does this prism have?",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "44 2 [OP_SUB] 2 1 [OP_ADD] 3 [OP_ADD] [OP_DIV] 3 [OP_MUL]",
        "solution_abst_en": "44 2 [OP_SUB] 2 1 [OP_ADD] 3 [OP_ADD] [OP_DIV] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 44\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = 3\nvar_h = var_f + var_g\nvar_i = var_c / var_h\nvar_j = 3\nvar_k = var_i * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 44\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = 3\nvar_h = var_f + var_g\nvar_i = var_c / var_h\nvar_j = 3\nvar_k = var_i * var_j\nprint(int(var_k))"
    },
    "3054": {
        "category": "Comparison",
        "question_ko": "동균, 영탁, 승환은 각자 쿠키를 가지고 있습니다. 동균이가 영탁보다 많고 승환이가 동균보다 많다면 누가 쿠키를 가장 많이 가지고 있을까?",
        "question_en": "Each Dongkyun, Youngtak, and Seunghwan have cookies. If Dongkyun has more cookies than Youngtak, and Seunghwan has more cookies than Dongkyun, who has the most cookies?",
        "answer_ko": "승환",
        "answer_en": "Seunghwan",
        "solution_abst_ko": "[OP_LIST_SOL] 동균 영탁 승환 [OP_LIST_EOL] [OP_LIST_SOL] 동균 영탁 > 승환 동균 > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Dongkyun Youngtak Seunghwan [OP_LIST_EOL] [OP_LIST_SOL] Dongkyun Youngtak > Seunghwan Dongkyun > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '동균'\nvar_b = '영탁'\nvar_c = '승환'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '동균'\nvar_e = '영탁'\nvar_f = '>'\nvar_g = '승환'\nvar_h = '동균'\nvar_i = '>'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(var_k)",
        "solution_code_en": "var_a = 'Dongkyun'\nvar_b = 'Youngtak'\nvar_c = 'Seunghwan'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'Dongkyun'\nvar_e = 'Youngtak'\nvar_f = '>'\nvar_g = 'Seunghwan'\nvar_h = 'Dongkyun'\nvar_i = '>'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(var_k)"
    },
    "3055": {
        "category": "Correspondence",
        "question_ko": "6A76을 버림하여 백의 자리까지 나타내면 6800이 됩니다. A를 구하시오.",
        "question_en": "Rounding down 6A76 to the hundreds place gives 6800. Find A.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "6A76 [OP_GEN_POSSIBLE_LIST] 6800 [OP_LIST_MORE_EQUAL] 6800 100 [OP_ADD] [OP_LIST_LESS] 6A76 A [OP_LIST_FIND_UNK]",
        "solution_abst_en": "6A76 [OP_GEN_POSSIBLE_LIST] 6800 [OP_LIST_MORE_EQUAL] 6800 100 [OP_ADD] [OP_LIST_LESS] 6A76 A [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = '6A76'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 6800\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 6800\nvar_d = 100\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = '6A76'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))",
        "solution_code_en": "var_a = '6A76'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 6800\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 6800\nvar_d = 100\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = '6A76'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))"
    },
    "3056": {
        "category": "Geometry",
        "question_ko": "반지름이 15센티미터(㎝)인 원 모양의 접시의 둘레는 90센티미터(㎝)입니다. 접시의 둘레는 지름의 몇 배입니까?",
        "question_en": "A circular plate with a radius of 15 centimeters (cm) has a circumference of 90 centimeters (cm). How many times is the plate's circumference longer than its diameter?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "90 15 2 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "90 15 2 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 90\nvar_b = 15\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 90\nvar_b = 15\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "3057": {
        "category": "Correspondence",
        "question_ko": "예슬이는 가지고 있던 색종이 수의 1/4보다 10장 많게 가영이에게 주고, 나머지 색종이의 3/5보다 5장 적게 상연이에게 주고, 그 나머지 색종이에서 12장을 미술 작품을 만드는 데 사용하고 나니 13장이 남았습니다. 예슬이는 처음에 색종이를 몇 장 가지고 있었습니까?",
        "question_en": "Ye-seul gave Ga-yeong 10 more than 1/4 of the colored papers she had, gave Sang-yeon 5 less than 3/5 of the remaining papers, and used 12 of the remaining papers to make an art piece. There are 13 papers left. How many colored papers did Ye-seul have at first?",
        "answer_ko": "80",
        "answer_en": "80",
        "solution_abst_ko": "13 12 [OP_ADD] 5 [OP_SUB] 1 3/5 [OP_SUB] [OP_DIV] 10 [OP_ADD] 1 1/4 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "13 12 [OP_ADD] 5 [OP_SUB] 1 3/5 [OP_SUB] [OP_DIV] 10 [OP_ADD] 1 1/4 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 13\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = 0.6\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 10\nvar_k = var_i + var_j\nvar_l = 1\nvar_m = 0.25\nvar_n = var_l - var_m\nvar_o = var_k / var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 13\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = 0.6\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 10\nvar_k = var_i + var_j\nvar_l = 1\nvar_m = 0.25\nvar_n = var_l - var_m\nvar_o = var_k / var_n\nprint(int(var_o))"
    },
    "3058": {
        "category": "Geometry",
        "question_ko": "용량이 4리터(L) 436밀리리터(㎖)인 물통 2개와 용량이 1999밀리리터(㎖)인 물통 2개가 있다. 이 물통들에 물을 꽉 담았을때 무게는 몇 킬로그램(㎏)인지 구하시오.",
        "question_en": "There are two water bottles with a capacity of 4 liters (L) and 436 milliliters (ml) and two water bottles with a capacity of 1999 milliliters (ml). Find the weight in kilograms (kg) of these bottles when they are full of water.",
        "answer_ko": "12.87",
        "answer_en": "12.87",
        "solution_abst_ko": "4 436 1000 [OP_DIV] [OP_ADD] 1999 1000 [OP_DIV] [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "4 436 1000 [OP_DIV] [OP_ADD] 1999 1000 [OP_DIV] [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 4\nvar_b = 436\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 1999\nvar_g = 1000\nvar_h = var_f / var_g\nvar_i = var_e + var_h\nvar_j = 2\nvar_k = var_i * var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 4\nvar_b = 436\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 1999\nvar_g = 1000\nvar_h = var_f / var_g\nvar_i = var_e + var_h\nvar_j = 2\nvar_k = var_i * var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "3059": {
        "category": "Arithmetic calculation",
        "question_ko": "책을 4일 안에 읽으려고 합니다. 첫번째 날에 전체의 1/2를 읽고 두 번째 날에 책 전체의 1/4를 읽었습니다. 그리고 세 번째 날에는 책 전체의 1/6을 읽었고 네 번째 날에는 20쪽이 남았습니다. 전체 책은 몇 쪽인지 구하세요.",
        "question_en": "I am about to read the book in 4 days. I read 1/2 of the book on the first day and 1/4 of the book on the second day. Then on the third day, I read 1/6 of the entire book and on the fourth day, I had 20 pages left. Find how many pages are in the entire book.",
        "answer_ko": "240",
        "answer_en": "240",
        "solution_abst_ko": "20 1 1/2 1/4 [OP_ADD] 1/6 [OP_ADD] [OP_SUB] [OP_DIV]",
        "solution_abst_en": "20 1 1/2 1/4 [OP_ADD] 1/6 [OP_ADD] [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 20\nvar_b = 1\nvar_c = 0.5\nvar_d = 0.25\nvar_e = var_c + var_d\nvar_f = 0.16666666666666666\nvar_g = var_e + var_f\nvar_h = var_b - var_g\nvar_i = var_a / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))",
        "solution_code_en": "var_a = 20\nvar_b = 1\nvar_c = 0.5\nvar_d = 0.25\nvar_e = var_c + var_d\nvar_f = 0.16666666666666666\nvar_g = var_e + var_f\nvar_h = var_b - var_g\nvar_i = var_a / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))"
    },
    "3060": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 11로 나눈 값에 156을 더했더니 178이 되었습니다. 어떤 수를 구하시오.",
        "question_en": "When you divide a number by 11 and add 156, you get 178. Find the number.",
        "answer_ko": "242",
        "answer_en": "242",
        "solution_abst_ko": "178 156 [OP_SUB] 11 [OP_MUL]",
        "solution_abst_en": "178 156 [OP_SUB] 11 [OP_MUL]",
        "solution_code_ko": "var_a = 178\nvar_b = 156\nvar_c = var_a - var_b\nvar_d = 11\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 178\nvar_b = 156\nvar_c = var_a - var_b\nvar_d = 11\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "3061": {
        "category": "Correspondence",
        "question_ko": "A00B-50C9=1D93를 만족하는 A와 B와 C와 D의 합을 구하시오. 서로 다른 알파벳은 서로 다른 숫자를 나타냅니다.",
        "question_en": "Find the sum of A, B, C, and D that satisfies A00B-50C9=1D93. Different alphabets represent different single-digit numbers.",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "[OP_LIST_SOL] A00B-50C9=1D93 A [OP_DIGIT_UNK_SOLVER] A00B-50C9=1D93 B [OP_DIGIT_UNK_SOLVER] A00B-50C9=1D93 C [OP_DIGIT_UNK_SOLVER] A00B-50C9=1D93 D [OP_DIGIT_UNK_SOLVER] [OP_LIST_EOL] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] A00B-50C9=1D93 A [OP_DIGIT_UNK_SOLVER] A00B-50C9=1D93 B [OP_DIGIT_UNK_SOLVER] A00B-50C9=1D93 C [OP_DIGIT_UNK_SOLVER] A00B-50C9=1D93 D [OP_DIGIT_UNK_SOLVER] [OP_LIST_EOL] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 'A00B-50C9=1D93'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 'A00B-50C9=1D93'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = 'A00B-50C9=1D93'\nvar_h = 'C'\nans_dict = dict()\nvar_g = var_g.replace('×','*')\nvar_g = var_g.replace('x','*')\nvar_g = var_g.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_g):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_g\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_g):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_i = ans_dict[var_h]\nvar_j = 'A00B-50C9=1D93'\nvar_k = 'D'\nans_dict = dict()\nvar_j = var_j.replace('×','*')\nvar_j = var_j.replace('x','*')\nvar_j = var_j.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_j):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_j\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_j):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_l = ans_dict[var_k]\nlist_a= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_a.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_m = sum(list_a)\nprint(int(var_m))",
        "solution_code_en": "var_a = 'A00B-50C9=1D93'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 'A00B-50C9=1D93'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = 'A00B-50C9=1D93'\nvar_h = 'C'\nans_dict = dict()\nvar_g = var_g.replace('×','*')\nvar_g = var_g.replace('x','*')\nvar_g = var_g.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_g):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_g\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_g):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_i = ans_dict[var_h]\nvar_j = 'A00B-50C9=1D93'\nvar_k = 'D'\nans_dict = dict()\nvar_j = var_j.replace('×','*')\nvar_j = var_j.replace('x','*')\nvar_j = var_j.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_j):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_j\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_j):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_l = ans_dict[var_k]\nlist_a= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_a.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_m = sum(list_a)\nprint(int(var_m))"
    },
    "3062": {
        "category": "Possibility",
        "question_ko": "숫자 1, 5, 9, 4를 한 번씩 사용하여 수를 만들 때, 십의 자리 숫자가 5인 수 중 세 번째로 큰 세 자리수는 얼마입니까?",
        "question_en": "If the numbers 1, 5, 9 and 4 are each used once to make a number, what is the third largest three-digit number with a tens digit of 5?",
        "answer_ko": "459",
        "answer_en": "459",
        "solution_abst_ko": "[OP_LIST_SOL] 1 5 9 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 5 [OP_LIST_SEARCH_FIXED_DIGIT] 3 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1 5 9 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 5 [OP_LIST_SEARCH_FIXED_DIGIT] 3 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1\nvar_b = 5\nvar_c = 9\nvar_d = 4\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 5\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 3\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 5\nvar_c = 9\nvar_d = 4\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 5\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 3\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nprint(int(var_i))"
    },
    "3063": {
        "category": "Arithmetic calculation",
        "question_ko": "해찬이는 20초에 150미터(m)를 달리는 빠르기로 달렸다. 1분 동안 해찬이가 달린 거리는 몇 미터(m)인가?",
        "question_en": "Haechan ran at a speed of 150 meters (m) in 20 seconds. How many meters (m) did Haechan run in 1 minute?",
        "answer_ko": "450",
        "answer_en": "450",
        "solution_abst_ko": "1 60 [OP_MUL] 20 [OP_DIV] 150 [OP_MUL]",
        "solution_abst_en": "1 60 [OP_MUL] 20 [OP_DIV] 150 [OP_MUL]",
        "solution_code_ko": "var_a = 1\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 20\nvar_e = var_c / var_d\nvar_f = 150\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 20\nvar_e = var_c / var_d\nvar_f = 150\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "3064": {
        "category": "Arithmetic calculation",
        "question_ko": "15리터(L)를 채워야 하는 수영장에 물이 7리터(L) 200밀리리터(㎖)만 채워져 있습니다. 여러 개의 호수로 물을 넣을 때 1초에 600밀리리터(㎖)씩 채워진다면, 15리터(L)를 모두 채우기 위해서는 최소 몇 초가 걸립니까?",
        "question_en": "A swimming pool was filled with only 7 liters (L) and 200 milliliters (㎖) of water, which was supposed to have 15 liters (L) of water in it. If the water hose can fill the pool at a rate of 600 milliliters (ml) per second, how many seconds does it take to fill it with all 15 liters (L)?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "15 1000 [OP_MUL] 7 1000 [OP_MUL] 200 [OP_ADD] [OP_SUB] 600 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "15 1000 [OP_MUL] 7 1000 [OP_MUL] 200 [OP_ADD] [OP_SUB] 600 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 15\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = 200\nvar_h = var_f + var_g\nvar_i = var_c - var_h\nvar_j = 600\nvar_k = var_i / var_j\nvar_l = 1\nvar_m=int(((var_k+9*10**(var_l-2))//(10**(var_l-1)))*10**(var_l-1))\n\nprint(int(var_m))",
        "solution_code_en": "var_a = 15\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = 200\nvar_h = var_f + var_g\nvar_i = var_c - var_h\nvar_j = 600\nvar_k = var_i / var_j\nvar_l = 1\nvar_m=int(((var_k+9*10**(var_l-2))//(10**(var_l-1)))*10**(var_l-1))\n\nprint(int(var_m))"
    },
    "3065": {
        "category": "Comparison",
        "question_ko": "지민이는 (가) 상자와 (나) 상자를 선물받았습니다. (나) 상자보다 (가) 상자가 가벼울 때 가벼운 상자는 무엇인가요?",
        "question_en": "Jimin got (a) box and (b) box for presents. When a (a) box is lighter than a (b) box, which box is a lighter box?",
        "answer_ko": "(가)",
        "answer_en": "(a)",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) [OP_LIST_EOL] [OP_LIST_SOL] (가) (나) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (a) (b) [OP_LIST_EOL] [OP_LIST_SOL] (a) (b) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = '(가)'\nvar_d = '(나)'\nvar_e = '<'\nlist_b= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_f = len(list_c)\nvar_g = list_c[var_f-1]\nprint(var_g)",
        "solution_code_en": "var_a = '(a)'\nvar_b = '(b)'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = '(a)'\nvar_d = '(b)'\nvar_e = '<'\nlist_b= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_f = len(list_c)\nvar_g = list_c[var_f-1]\nprint(var_g)"
    },
    "3066": {
        "category": "Comparison",
        "question_ko": "키가 작은 사람부터 순서대로 9명이 한 줄로 서 있습니다. 호석이가 뒤에서부터 5번째에 서 있습니다. 키가 큰 사람부터 순서대로 다시 줄을 서면 호석이는 뒤에서부터 몇 번째에 서게 됩니까?",
        "question_en": "Nine people stand in a line in order from shortest to tallest. Hoseok is standing 5th from the back. If you line up again in order from the tallest to the shortest, what number will Hoseok stand from the back?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "9 5 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "9 5 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 9\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3067": {
        "category": "Geometry",
        "question_ko": "둘레가 27.9 미터(m) 인 원 모양의 텃밭에 3.1 미터(m) 간격으로 나무를 심으려고 합니다. 나무를 몇 그루 심을 수 있는 지 구하시오.",
        "question_en": "You want to plant trees at intervals of 3.1 meters (m) in a circular garden with a circumference of 27.9 meters (m). Find how many trees you can plant.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "27.9 3.1 [OP_DIV]",
        "solution_abst_en": "27.9 3.1 [OP_DIV]",
        "solution_code_ko": "var_a = 27.9\nvar_b = 3.1\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 27.9\nvar_b = 3.1\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "3068": {
        "category": "Arithmetic calculation",
        "question_ko": "구슬을 10줄 놓았습니다. 그중에서 9개 줄에는 8개씩 놓았고, 나머지 1줄에는 4개를 놓았습니다. 구슬은 모두 몇 개입니까?",
        "question_en": "10 rows of marbles are placed. 8 of them were placed in 9 rows, and 4 were placed in the other row. How many marbles are there in all?",
        "answer_ko": "76",
        "answer_en": "76",
        "solution_abst_ko": "9 8 [OP_MUL] 1 4 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "9 8 [OP_MUL] 1 4 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 9\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 4\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 9\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 4\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "3069": {
        "category": "Geometry",
        "question_ko": "팔각형의 한 꼭지점에서 대각선을 그을 때 생기는 삼각형의 개수는?",
        "question_en": "How many triangles are formed by drawing a diagonal from one vertex of an octagon?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "8 3 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "8 3 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3070": {
        "category": "Possibility",
        "question_ko": "은희는 5명의 친구들과 함께 교실 청소를 하려 한다. 교실 바닥 담당 2명, 창문 담당 1명을 뽑는다고 할 때, 은희가 교실 바닥 담당이 되는 경우의 수를 구하시오.",
        "question_en": "Eunhee is about to clean the classroom with her five friends. When she has to select 2 people to be in charge of the classroom floor and 1 person to be in charge of the window, find the number of cases where Eunhee becomes in charge of the classroom floor.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "5 1 [OP_SUB] 2 1 [OP_SUB] 1 [OP_ADD] [OP_PERM]",
        "solution_abst_en": "5 1 [OP_SUB] 2 1 [OP_SUB] 1 [OP_ADD] [OP_PERM]",
        "solution_code_ko": "var_a = 5\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = 1\nvar_c = int(var_c)\nvar_h = int(var_h)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i * (var_c-i)\nprint(int(var_i))",
        "solution_code_en": "var_a = 5\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = 1\nvar_c = int(var_c)\nvar_h = int(var_h)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i * (var_c-i)\nprint(int(var_i))"
    },
    "3071": {
        "category": "Arithmetic calculation",
        "question_ko": "서현이는 총 두 곳에 기부를 합니다. 한 곳에는 100만 원씩 25번을 기부하였고, 다른 한 곳에는 10만 원씩 8번을 기부하였다면, 서현이가 지금까지 기부한 돈은 총 얼마입니까?",
        "question_en": "Seohyun donates to a total of two places. If she had donated 1 million won 25 times to one place and 8 times to the other by 100,000 won, how much money has Seohyun donated so far?",
        "answer_ko": "25800000",
        "answer_en": "25800000",
        "solution_abst_ko": "100 10000 [OP_MUL] 25 [OP_MUL] 10 10000 [OP_MUL] 8 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "100 10000 [OP_MUL] 25 [OP_MUL] 10 10000 [OP_MUL] 8 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 100\nvar_b = 10000\nvar_c = var_a * var_b\nvar_d = 25\nvar_e = var_c * var_d\nvar_f = 10\nvar_g = 10000\nvar_h = var_f * var_g\nvar_i = 8\nvar_j = var_h * var_i\nvar_k = var_e + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 100\nvar_b = 10000\nvar_c = var_a * var_b\nvar_d = 25\nvar_e = var_c * var_d\nvar_f = 10\nvar_g = 10000\nvar_h = var_f * var_g\nvar_i = 8\nvar_j = var_h * var_i\nvar_k = var_e + var_j\nprint(int(var_k))"
    },
    "3072": {
        "category": "Correspondence",
        "question_ko": "지민이는 34에 어떤 수를 더하려고 합니다. 실수로 20에 어떤 수를 뺐을 때의 결과가 60이라면 바르게 계산한 결과를 구하세요.",
        "question_en": "Suppose Jimin wanted to do the addition of a certain number and 34. But she made a mistake by subtracting a number from 20 and got 60. Find the value that Jimin actually wanted to get.",
        "answer_ko": "-6",
        "answer_en": "-6",
        "solution_abst_ko": "34 20 60 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "34 20 60 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 34\nvar_b = 20\nvar_c = 60\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 34\nvar_b = 20\nvar_c = 60\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "3073": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 3을 빼기 전에 2를 더해주었더니 7입니다. 어떤 수를 구하시오.",
        "question_en": "If you add 2 to a number before subtracting 3, you get 7. What number is this?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "7 3 [OP_ADD] 2 [OP_SUB]",
        "solution_abst_en": "7 3 [OP_ADD] 2 [OP_SUB]",
        "solution_code_ko": "var_a = 7\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 7\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3074": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 7로 나누고 12를 더한 값이 36입니다. 어떤 수를 4로 나눈 값을 구하시오.",
        "question_en": "36 is the result adding 12 to a number divided by 7. Find the value of this number divided by 4.",
        "answer_ko": "42",
        "answer_en": "42",
        "solution_abst_ko": "36 12 [OP_SUB] 7 [OP_MUL] 4 [OP_DIV]",
        "solution_abst_en": "36 12 [OP_SUB] 7 [OP_MUL] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 36\nvar_b = 12\nvar_c = var_a - var_b\nvar_d = 7\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 36\nvar_b = 12\nvar_c = var_a - var_b\nvar_d = 7\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "3075": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 29를 뺐다가 64를 더했습니다. 결과가 76이 되기 위한 어떤 수는 얼마입니까?",
        "question_en": "29 is subtracted from and 64 added to this number. What number is required for the result of this to be 76?",
        "answer_ko": "41",
        "answer_en": "41",
        "solution_abst_ko": "76 64 [OP_SUB] 29 [OP_ADD]",
        "solution_abst_en": "76 64 [OP_SUB] 29 [OP_ADD]",
        "solution_code_ko": "var_a = 76\nvar_b = 64\nvar_c = var_a - var_b\nvar_d = 29\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 76\nvar_b = 64\nvar_c = var_a - var_b\nvar_d = 29\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3076": {
        "category": "Correspondence",
        "question_ko": "27을 어떤 수로 나눈 몫이 5이고 나머지가 7이다. 어떤 수와 5의 합으로 나누어떨어지고 몫이 7인 값을 구하시오.",
        "question_en": "When 27 is divided by a number, the quotient is 5 and the remainder is 7. Find the value that is divisible by the sum of the number and 5, and has a quotient of 7.",
        "answer_ko": "63",
        "answer_en": "63",
        "solution_abst_ko": "27 7 [OP_SUB] 5 [OP_DIV] 5 [OP_ADD] 7 [OP_MUL]",
        "solution_abst_en": "27 7 [OP_SUB] 5 [OP_DIV] 5 [OP_ADD] 7 [OP_MUL]",
        "solution_code_ko": "var_a = 27\nvar_b = 7\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c / var_d\nvar_f = 5\nvar_g = var_e + var_f\nvar_h = 7\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 27\nvar_b = 7\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c / var_d\nvar_f = 5\nvar_g = var_e + var_f\nvar_h = 7\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "3077": {
        "category": "Arithmetic calculation",
        "question_ko": "흥부는 농사를 짓기 위해 가족들과 함께 마을 우물에서 물을 10리터(L) 길어오기로 했습니다. 흥부는 1리터(L) 500밀리리터(㎖)의 바가지로 3번 떠왔고 흥부의 아내는 1리터(L) 750밀리리터(㎖)의 바가지로 한 번 떠왔습니다. 남은 물은 흥부의 아들이 떠오기로 했을 때 아들이 가진 바가지가 1리터(L) 250밀리리터(㎖) 짜리라면 아들은 우물에 몇 번 다녀와야 합니까?",
        "question_en": "Heungbu and his family decided to fetch 10 liters (l) of water from the village well for farming. Heungbu scooped up the water three times with a 1 liter (L) and 500 milliliter (㎖) bowl, and Heungbu's wife scooped up the water once with a 1 liter (L) and 750 milliliters (㎖) bowl. When Heungbu's son decided to fetch all the remaining water, how many times did he have to visit the well if he had a bowl of 1 liter (L) and 250 milliliters (㎖)?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "10 1000 [OP_MUL] 1 1000 [OP_MUL] 500 [OP_ADD] 3 [OP_MUL] [OP_SUB] 1 1000 [OP_MUL] 750 [OP_ADD] [OP_SUB] 1 1000 [OP_MUL] 250 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "10 1000 [OP_MUL] 1 1000 [OP_MUL] 500 [OP_ADD] 3 [OP_MUL] [OP_SUB] 1 1000 [OP_MUL] 750 [OP_ADD] [OP_SUB] 1 1000 [OP_MUL] 250 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = 500\nvar_h = var_f + var_g\nvar_i = 3\nvar_j = var_h * var_i\nvar_k = var_c - var_j\nvar_l = 1\nvar_m = 1000\nvar_n = var_l * var_m\nvar_o = 750\nvar_p = var_n + var_o\nvar_q = var_k - var_p\nvar_r = 1\nvar_s = 1000\nvar_t = var_r * var_s\nvar_u = 250\nvar_v = var_t + var_u\nvar_w = var_q / var_v\nprint(int(var_w))",
        "solution_code_en": "var_a = 10\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = 500\nvar_h = var_f + var_g\nvar_i = 3\nvar_j = var_h * var_i\nvar_k = var_c - var_j\nvar_l = 1\nvar_m = 1000\nvar_n = var_l * var_m\nvar_o = 750\nvar_p = var_n + var_o\nvar_q = var_k - var_p\nvar_r = 1\nvar_s = 1000\nvar_t = var_r * var_s\nvar_u = 250\nvar_v = var_t + var_u\nvar_w = var_q / var_v\nprint(int(var_w))"
    },
    "3078": {
        "category": "Arithmetic calculation",
        "question_ko": "(다) 상자 6개의 크기는 (나) 상자 크기와 같고, (나) 상자 4개의 크기는 (가) 상자 크기와 같습니다. (가) 상자는 (다) 상자를 몇 개 넣으면 꽉 찹니까?",
        "question_en": "The size of six box (C) equals the size of box (B), and the size of four box (B) equals the size of box (A). How many box (C) should you put in box (A) to make it full?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "4 6 [OP_MUL] 1 [OP_MUL]",
        "solution_abst_en": "4 6 [OP_MUL] 1 [OP_MUL]",
        "solution_code_ko": "var_a = 4\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 4\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "3079": {
        "category": "Comparison",
        "question_ko": "욕조에 물을 가득 채우기 위해서는 빨간색 물통으로는 7번, 파란색 물통으로는 8번, 초록색 물통으로는 5번 물을 부어야 합니다. 각 병에 물을 채웠을 때 가장 많은 양이 담기는 병의 색깔은 무엇입니까?",
        "question_en": "To fill the bathtub with water, you need to pour 7 times using the red bucket, 8 times of the blue bucket, and 5 times of the green bucket. Which color of the bucket will contain the most water when each of them is filled up with water?",
        "answer_ko": "초록색",
        "answer_en": "green",
        "solution_abst_ko": "[OP_LIST_SOL] 빨간색 파란색 초록색 [OP_LIST_EOL] [OP_LIST_SOL] 1 7 [OP_DIV] 1 8 [OP_DIV] 1 5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] red blue green [OP_LIST_EOL] [OP_LIST_SOL] 1 7 [OP_DIV] 1 8 [OP_DIV] 1 5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '빨간색'\nvar_b = '파란색'\nvar_c = '초록색'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nvar_e = 7\nvar_f = var_d / var_e\nvar_g = 1\nvar_h = 8\nvar_i = var_g / var_h\nvar_j = 1\nvar_k = 5\nvar_l = var_j / var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'red'\nvar_b = 'blue'\nvar_c = 'green'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nvar_e = 7\nvar_f = var_d / var_e\nvar_g = 1\nvar_h = 8\nvar_i = var_g / var_h\nvar_j = 1\nvar_k = 5\nvar_l = var_j / var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "3080": {
        "category": "Comparison",
        "question_ko": "체육시간에 학생들이 키가 큰 순서대로 한 줄로 나란히 섰습니다. 정국이는 7번째이고 민영이는 5번째입니다. 태형이는 민영이보다 키가 크지만 정국이보다는 작습니다. 태형이는 몇번째입니까?",
        "question_en": "During PE class, students lined up in a single line in order of height from the tallest. Jungkook is the 7th and Minyoung is the 5th. Taehyung is taller than Minyoung but shorter than Jungkook. What number is Taehyung?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "5 7 [OP_ADD] 2 [OP_FDIV]",
        "solution_abst_en": "5 7 [OP_ADD] 2 [OP_FDIV]",
        "solution_code_ko": "var_a = 5\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "3081": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 가장 작은 수와 2번째로 작은 수로 나눈 값은 얼마입니까?",
        "question_en": "There are five numbers 10, 11, 12, 13, and 14. Divide the smallest number by the second smallest number.",
        "answer_ko": "0.91",
        "answer_en": "0.91",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_DIV]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g / var_i\nprint('{:.2f}'.format(round(var_j+1e-10,2)))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g / var_i\nprint('{:.2f}'.format(round(var_j+1e-10,2)))"
    },
    "3082": {
        "category": "Arithmetic calculation",
        "question_ko": "2135개의 사탕을 한 상자에 100개씩 담으려고 할 때, 상자는 최소 몇 개 필요합니까?",
        "question_en": "If you want to put 2135 candies in a box with 100 candies each, how many boxes are needed at least?",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "2153 100 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "2153 100 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 2153\nvar_b = 100\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))",
        "solution_code_en": "var_a = 2153\nvar_b = 100\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))"
    },
    "3083": {
        "category": "Arithmetic calculation",
        "question_ko": "1킬로그램(㎏)짜리 상자 48개를 4킬로그램(㎏)까지 실을 수 있는 수레 6개를 동시에 사용해 나른다면 몇 번의 이동이 필요합니까?",
        "question_en": "How many trips are needed to transport 48 crates weighing 1 kg (kg) using 6 carts that can carry up to 4 kg (kg) at the same time?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "48 4 6 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "48 4 6 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 48\nvar_b = 4\nvar_c = 6\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 48\nvar_b = 4\nvar_c = 6\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "3084": {
        "category": "Correspondence",
        "question_ko": "다섯 자리 수 A375B는 24의 배수입니다. A에 알맞은 숫자의 개수를 구하시오.",
        "question_en": "Five digit number A375B is a multiple of 24. Find the number of single digit numbers that fit in A.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "A375B [OP_GEN_POSSIBLE_LIST] 24 [OP_LIST_DIVISIBLE] A375B A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_abst_en": "A375B [OP_GEN_POSSIBLE_LIST] 24 [OP_LIST_DIVISIBLE] A375B A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 'A375B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 24\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 'A375B'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nvar_e = len(list_c)\nprint(int(var_e))",
        "solution_code_en": "var_a = 'A375B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 24\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 'A375B'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nvar_e = len(list_c)\nprint(int(var_e))"
    },
    "3085": {
        "category": "Comparison",
        "question_ko": "은지는 기차에 10번째로 탔고, 유나는 은지 다음으로 11명이 더 탄 뒤에 기차에 탔습니다. 유나는 몇 번째로 기차에 탔습니까?",
        "question_en": "Eunji got on the train in 10th place. 11 more people got on the train following Eunji, and then Yuna got on the train. When did Yuna get on the train? Answer in ordinal number.",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "10 11 [OP_ADD] 1 [OP_ADD]",
        "solution_abst_en": "10 11 [OP_ADD] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3086": {
        "category": "Comparison",
        "question_ko": "정사각형과 삼각형의 넓이를 비교하고 있습니다. 정사각형의 한 변은 4센티미터(cm)입니다. 삼각형은 높이가 4센티미터(cm), 밑변이 6cm(센티미터)일 때, 더 넓은 것을 고르시오.",
        "question_en": "You are comparing the area of a regular square and a regular triangle. A side of a square is 4 centimeters (cm). If the triangle is 4 centimeters (cm) high and the base is 6 centimeters (cm), choose the wider one.",
        "answer_ko": "정사각형",
        "answer_en": "square",
        "solution_abst_ko": "[OP_LIST_SOL] 정사각형 삼각형 [OP_LIST_EOL] [OP_LIST_SOL] 4 2 [OP_POW] 6 4 [OP_MUL] 2 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] square triangle [OP_LIST_EOL] [OP_LIST_SOL] 4 2 [OP_POW] 6 4 [OP_MUL] 2 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정사각형'\nvar_b = '삼각형'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 6\nvar_g = 4\nvar_h = var_f * var_g\nvar_i = 2\nvar_j = var_h / var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'square'\nvar_b = 'triangle'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 6\nvar_g = 4\nvar_h = var_f * var_g\nvar_i = 2\nvar_j = var_h / var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "3087": {
        "category": "Comparison",
        "question_ko": "네 명의 학생 윤기, 정국, 유나, 유정은 각각 7, 6, 9, 8만큼의 숫자를 가지고 있습니다. 누구의 숫자가 가장 큽니까?",
        "question_en": "The four students, Yoongi, Jungkook, Yuna, and Yoojung, each have the numbers 7, 6, 9, and 8. Whose number is the biggest?",
        "answer_ko": "유나",
        "answer_en": "Yuna",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 유나 유정 [OP_LIST_EOL] [OP_LIST_SOL] 7 6 9 8 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook Yuna Yoojung [OP_LIST_EOL] [OP_LIST_SOL] 7 6 9 8 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nvar_c = '유나'\nvar_d = '유정'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 7\nvar_f = 6\nvar_g = 9\nvar_h = 8\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nvar_c = 'Yuna'\nvar_d = 'Yoojung'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 7\nvar_f = 6\nvar_g = 9\nvar_h = 8\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "3088": {
        "category": "Arithmetic calculation",
        "question_ko": "하준이는 학교까지 5번 갔다오는데 1시간 36분이 걸렸습니다. 한 번 갔다오는데 걸리는 시간은 몇 분인가요?",
        "question_en": "Hajun went to school 5 times and it took him 1 hour and 36 minutes. How many minutes does it take to go once?",
        "answer_ko": "19.20",
        "answer_en": "19.2",
        "solution_abst_ko": "1 60 [OP_MUL] 36 [OP_ADD] 5 [OP_DIV]",
        "solution_abst_en": "1 60 [OP_MUL] 36 [OP_ADD] 5 [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 36\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 36\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "3089": {
        "category": "Comparison",
        "question_ko": "24개의 구슬이 있습니다. 이 중 빨간색 구슬은 전체의 1/4이고, 파란색 구슬은 빨간색 구슬보다 6개 많고, 나머지는 노란색 구슬입니다. 어떤 색 구슬이 가장 많이 있습니까?",
        "question_en": "There are 24 marbles. Of these, the red marbles are 1/4 of the total, the amount of blue marbles is 6 more than that of the red marbles, and the rest are yellow marbles. What color marbles do you have the most?",
        "answer_ko": "파란색",
        "answer_en": "blue",
        "solution_abst_ko": "[OP_LIST_SOL] 빨간색 파란색 노란색 [OP_LIST_EOL] [OP_LIST_SOL] 24 4 [OP_DIV] 24 4 [OP_DIV] 6 [OP_ADD] 24 24 4 [OP_DIV] 6 [OP_ADD] [OP_SUB] 24 4 [OP_DIV] [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] red blue yellow [OP_LIST_EOL] [OP_LIST_SOL] 24 4 [OP_DIV] 24 4 [OP_DIV] 6 [OP_ADD] 24 24 4 [OP_DIV] 6 [OP_ADD] [OP_SUB] 24 4 [OP_DIV] [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '빨간색'\nvar_b = '파란색'\nvar_c = '노란색'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 24\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = 24\nvar_h = 4\nvar_i = var_g / var_h\nvar_j = 6\nvar_k = var_i + var_j\nvar_l = 24\nvar_m = 24\nvar_n = 4\nvar_o = var_m / var_n\nvar_p = 6\nvar_q = var_o + var_p\nvar_r = var_l - var_q\nvar_s = 24\nvar_t = 4\nvar_u = var_s / var_t\nvar_v = var_r - var_u\nlist_b= []\nif \"/\" in str(var_v):\n    var_v = eval(str(var_v))\nlist_b.append(var_v)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_w = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_x = list_c[-var_w]\nvar_y = list_b.index(var_x)+1\nvar_z = list_a[var_y-1]\nprint(var_z)",
        "solution_code_en": "var_a = 'red'\nvar_b = 'blue'\nvar_c = 'yellow'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 24\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = 24\nvar_h = 4\nvar_i = var_g / var_h\nvar_j = 6\nvar_k = var_i + var_j\nvar_l = 24\nvar_m = 24\nvar_n = 4\nvar_o = var_m / var_n\nvar_p = 6\nvar_q = var_o + var_p\nvar_r = var_l - var_q\nvar_s = 24\nvar_t = 4\nvar_u = var_s / var_t\nvar_v = var_r - var_u\nlist_b= []\nif \"/\" in str(var_v):\n    var_v = eval(str(var_v))\nlist_b.append(var_v)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_w = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_x = list_c[-var_w]\nvar_y = list_b.index(var_x)+1\nvar_z = list_a[var_y-1]\nprint(var_z)"
    },
    "3090": {
        "category": "Geometry",
        "question_ko": "공터에 나무를 정사각형 모양으로 심었다. 한 변에 5개의 나무를 심는다면 몇 개의 나무를 심어야한는가?",
        "question_en": "Trees were planted in a square shape in the open field. If 5 trees are planted per side, how many trees should be planted?",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "5 4 [OP_MUL] 4 [OP_SUB]",
        "solution_abst_en": "5 4 [OP_MUL] 4 [OP_SUB]",
        "solution_code_ko": "var_a = 5\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3091": {
        "category": "Arithmetic calculation",
        "question_ko": "민찬이는 체육 창고를 정리하고 있습니다. 야구공, 탁구공, 테니스공이 합하여 240개가 있을 때 야구공은 4개씩 35개의 상자에 나누어 담고 테니스공은 3개씩 6상자에 나누어 담았습니다. 남은 공은 전부 탁구공일 때 탁구공의 개수는 몇 개입니까?",
        "question_en": "Minchan is organizing the gym storage. If there are 240 baseballs, ping-pong balls, and tennis balls in total, the baseballs are divided into 35 boxes of 4 each, and the tennis balls are divided into 6 boxes of 3 each. How many ping-pong balls are there if all remaining balls are ping-pong balls?",
        "answer_ko": "82",
        "answer_en": "82",
        "solution_abst_ko": "240 4 35 [OP_MUL] [OP_SUB] 3 6 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "240 4 35 [OP_MUL] [OP_SUB] 3 6 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 240\nvar_b = 4\nvar_c = 35\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 3\nvar_g = 6\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 240\nvar_b = 4\nvar_c = 35\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 3\nvar_g = 6\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nprint(int(var_i))"
    },
    "3092": {
        "category": "Possibility",
        "question_ko": "경수는 친구와 문구점에 갔다. 문구점에 3종류의 연필과 5종류의 볼펜이 있을 때, 경수가 연필 한 개와 볼펜 한 개를 고를 수 있는 경우의 수는?",
        "question_en": "Kyungsoo went to a stationery store with a friend. If there are 3 types of pencils and 5 types of ballpoint pens in the stationery store, in how many ways can Kyungsoo choose one pencil and one ballpoint pen?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "3 1 [OP_COMB] 5 1 [OP_COMB] [OP_MUL]",
        "solution_abst_en": "3 1 [OP_COMB] 5 1 [OP_COMB] [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 1\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nvar_d = 5\nvar_e = 1\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f / (i+1)\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 3\nvar_b = 1\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nvar_d = 5\nvar_e = 1\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f / (i+1)\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "3093": {
        "category": "Comparison",
        "question_ko": "태희는 어제 줄넘기를 23번 했고, 지훈이는 35번 했습니다. 오늘 태희는 어제보다 14번 더 많이 했지만, 지훈이는 어제보다 19번 더 적게 했습니다. 어제와 오늘을 합쳐서 줄넘기를 더 많이 넘은 사람은 누구입니까?",
        "question_en": "Taehee jumped rope 23 times yesterday, and Jihoon did 35 times. Today, Taehee did 14 times more than yesterday, but Jihoon did 19 times less than yesterday. Who jumped more ropes yesterday and today combined?",
        "answer_ko": "태희",
        "answer_en": "Taehee",
        "solution_abst_ko": "[OP_LIST_SOL] 태희 지훈 [OP_LIST_EOL] [OP_LIST_SOL] [OP_LIST_SOL] 23 23 14 [OP_LIST_EOL] [OP_LIST_SUM] [OP_LIST_SOL] 35 35 -19 [OP_LIST_EOL] [OP_LIST_SUM] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_POP] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Taehee Jihoon [OP_LIST_EOL] [OP_LIST_SOL] [OP_LIST_SOL] 23 23 14 [OP_LIST_EOL] [OP_LIST_SUM] [OP_LIST_SOL] 35 35 -19 [OP_LIST_EOL] [OP_LIST_SUM] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_POP] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '태희'\nvar_b = '지훈'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 23\nvar_d = 23\nvar_e = 14\nlist_b= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nvar_g = 35\nvar_h = 35\nvar_i = -19\nlist_c= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_c.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_c.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_c.append(var_g)\nlist_c.reverse()\nlist_c = [float(i) for i in list_c]\nvar_j = sum(list_c)\nlist_d= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_d.append(var_j)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_d.append(var_f)\nlist_d.reverse()\nvar_k = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_l = list_e[-var_k]\nvar_m = list_d.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'Taehee'\nvar_b = 'Jihoon'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 23\nvar_d = 23\nvar_e = 14\nlist_b= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nvar_g = 35\nvar_h = 35\nvar_i = -19\nlist_c= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_c.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_c.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_c.append(var_g)\nlist_c.reverse()\nlist_c = [float(i) for i in list_c]\nvar_j = sum(list_c)\nlist_d= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_d.append(var_j)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_d.append(var_f)\nlist_d.reverse()\nvar_k = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_l = list_e[-var_k]\nvar_m = list_d.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "3094": {
        "category": "Comparison",
        "question_ko": "다음 숫자 카드 1, 3, 4, 6, 7, 9 중에서 한 장을 뽑을 때 9 이하의 수가 적힌 카드가 나올 확률을 구하시오.",
        "question_en": "Find the probability of getting a card with a number less than or equal to 9 when drawing one of the following number cards: 1, 3, 4, 6, 7, and 9.",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 4 6 7 9 [OP_LIST_EOL] 9 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN] [OP_LIST_SOL] 1 3 4 6 7 9 [OP_LIST_EOL] [OP_LIST_LEN] [OP_DIV]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 4 6 7 9 [OP_LIST_EOL] 9 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN] [OP_LIST_SOL] 1 3 4 6 7 9 [OP_LIST_EOL] [OP_LIST_LEN] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 4\nvar_d = 6\nvar_e = 7\nvar_f = 9\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 9\nlist_b = []\nfor i in list_a:\n    if i <= var_g:\n        list_b.append(i)\nvar_h = len(list_b)\nvar_i = 1\nvar_j = 3\nvar_k = 4\nvar_l = 6\nvar_m = 7\nvar_n = 9\nlist_c= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_c.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_c.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_c.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_c.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_c.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_c.append(var_i)\nlist_c.reverse()\nvar_o = len(list_c)\nvar_p = var_h / var_o\nprint(int(var_p))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 4\nvar_d = 6\nvar_e = 7\nvar_f = 9\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 9\nlist_b = []\nfor i in list_a:\n    if i <= var_g:\n        list_b.append(i)\nvar_h = len(list_b)\nvar_i = 1\nvar_j = 3\nvar_k = 4\nvar_l = 6\nvar_m = 7\nvar_n = 9\nlist_c= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_c.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_c.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_c.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_c.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_c.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_c.append(var_i)\nlist_c.reverse()\nvar_o = len(list_c)\nvar_p = var_h / var_o\nprint(int(var_p))"
    },
    "3095": {
        "category": "Geometry",
        "question_ko": "딱지를 가로와 세로 모두 10장씩 빈틈없이 늘어놓아 정사각형을 만들었습니다. 둘레에 놓인 딱지는 뒤집어져 있었고, 안쪽에 놓인 딱지는 안 뒤집어져 있었을 때, 안 뒤집어져 있는 딱지는 모두 몇 개일까요?",
        "question_en": "You made a square by arranging 10 tickets horizontally and vertically without gaps. If the tickets on the perimeter were turned over and the ones on the inside were not turned over, how many of them were not turned over?",
        "answer_ko": "64",
        "answer_en": "64",
        "solution_abst_ko": "10 2 [OP_SUB] 2 [OP_POW]",
        "solution_abst_en": "10 2 [OP_SUB] 2 [OP_POW]",
        "solution_code_ko": "var_a = 10\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint(int(var_e))"
    },
    "3096": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 5를 곱한 다음 24를 더한 후 7로 나누어야 할 것을 잘못하여 어떤 수에 24를 더한 다음 5로 나눈 후 7을 곱했더니 70이 되었습니다. 바르게 계산한 값을 구하시오.",
        "question_en": "You were supposed to multiply a certain number by 5, then add 24, then divide by 7, but you accidentally add 24, divide it by 5, then multiply by 7, and you get 70. Find the correct calculated value.",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "70 7 [OP_DIV] 5 [OP_MUL] 24 [OP_SUB] 5 [OP_MUL] 24 [OP_ADD] 7 [OP_DIV]",
        "solution_abst_en": "70 7 [OP_DIV] 5 [OP_MUL] 24 [OP_SUB] 5 [OP_MUL] 24 [OP_ADD] 7 [OP_DIV]",
        "solution_code_ko": "var_a = 70\nvar_b = 7\nvar_c = var_a / var_b\nvar_d = 5\nvar_e = var_c * var_d\nvar_f = 24\nvar_g = var_e - var_f\nvar_h = 5\nvar_i = var_g * var_h\nvar_j = 24\nvar_k = var_i + var_j\nvar_l = 7\nvar_m = var_k / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 70\nvar_b = 7\nvar_c = var_a / var_b\nvar_d = 5\nvar_e = var_c * var_d\nvar_f = 24\nvar_g = var_e - var_f\nvar_h = 5\nvar_i = var_g * var_h\nvar_j = 24\nvar_k = var_i + var_j\nvar_l = 7\nvar_m = var_k / var_l\nprint(int(var_m))"
    },
    "3097": {
        "category": "Geometry",
        "question_ko": "긴 변의 길이가 1 미터(m)이고, 짧은 변의 길이는 긴 변의 길이보다 2/8미터(m)만큼 짧은 직사각형이 있습니다. 이 직사각형의 네 변의 길이의 합은 몇 미터(m)인지 답을 구해 보세요.",
        "question_en": "There is a rectangle whose long side is 1 meter (m) and its short side is 2/8 meter (m) shorter than its long side. Find the answer in meters (m) equal to the sum of the lengths of the four sides of this rectangle.",
        "answer_ko": "3.50",
        "answer_en": "3.5",
        "solution_abst_ko": "1 1 2/8 [OP_SUB] [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "1 1 2/8 [OP_SUB] [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 1\nvar_b = 1\nvar_c = 0.25\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 1\nvar_c = 0.25\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "3098": {
        "category": "Comparison",
        "question_ko": "지민이는 남준이보다 가볍고 석진이보다는 무겁습니다. 석진이는 호석이보다 무겁습니다. 4명 중 가장 가벼운 사람은 누구입니까?",
        "question_en": "Jimin is lighter than Namjoon and heavier than Seokjin. Seokjin is heavier than Hoseok. Which of the 4 is the lightest?",
        "answer_ko": "호석",
        "answer_en": "Hoseok",
        "solution_abst_ko": "[OP_LIST_SOL] 석진 호석 지민 남준 [OP_LIST_EOL] [OP_LIST_SOL] 석진 호석 > 석진 지민 < 남준 지민 > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Seokjin Hoseok Jimin Namjoon [OP_LIST_EOL] [OP_LIST_SOL] Seokjin Hoseok > Seokjin Jimin < Namjoon Jimin > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '석진'\nvar_b = '호석'\nvar_c = '지민'\nvar_d = '남준'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '석진'\nvar_f = '호석'\nvar_g = '>'\nvar_h = '석진'\nvar_i = '지민'\nvar_j = '<'\nvar_k = '남준'\nvar_l = '지민'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)",
        "solution_code_en": "var_a = 'Seokjin'\nvar_b = 'Hoseok'\nvar_c = 'Jimin'\nvar_d = 'Namjoon'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'Seokjin'\nvar_f = 'Hoseok'\nvar_g = '>'\nvar_h = 'Seokjin'\nvar_i = 'Jimin'\nvar_j = '<'\nvar_k = 'Namjoon'\nvar_l = 'Jimin'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)"
    },
    "3099": {
        "category": "Geometry",
        "question_ko": "어떤 팔면체가 있습니다. 이 팔면체의 면의 개수를 구하시오.",
        "question_en": "There is an octahedron. Find the number of faces of this octahedron.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "8",
        "solution_abst_en": "8",
        "solution_code_ko": "var_a = 8\nprint(int(var_a))",
        "solution_code_en": "var_a = 8\nprint(int(var_a))"
    },
    "3100": {
        "category": "Possibility",
        "question_ko": "길이가 다른 10개의 나무토막 중 3개를 사용하려고 합니다. 나무토막을 선택하는 경우는 모두 몇 가지인가요?",
        "question_en": "You are going to use 3 out of 10 wooden blocks of different lengths. How many ways can you choose 3 blocks out of 10?",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "10 3 [OP_COMB]",
        "solution_abst_en": "10 3 [OP_COMB]",
        "solution_code_ko": "var_a = 10\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))",
        "solution_code_en": "var_a = 10\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))"
    },
    "3101": {
        "category": "Geometry",
        "question_ko": "직사각형 모양의 액자의 둘레가 30센티미터(㎝)이고, 가로의 길이가 10센티미터(㎝)라면, 세로의 길이는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "If the perimeter of a rectangular picture frame is 30 centimeters (cm) and the width is 10 centimeters (cm), how many centimeters (cm) is the length of the picture frame?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "30 2 [OP_DIV] 10 [OP_SUB]",
        "solution_abst_en": "30 2 [OP_DIV] 10 [OP_SUB]",
        "solution_code_ko": "var_a = 30\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 10\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 30\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 10\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3102": {
        "category": "Arithmetic calculation",
        "question_ko": "선생님이 10부터 99까지 수를 칠판에 적을 때, 숫자 8은 모두 몇 번 쓰는지 구하시오.",
        "question_en": "When the teacher writes the numbers 10 through 99 on the board, how many times does the number 8 appear?",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "10 99 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 8 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "10 99 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 8 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 8\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))",
        "solution_code_en": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 8\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))"
    },
    "3103": {
        "category": "Comparison",
        "question_ko": "한별과 슬기가 달리기 운동을 하였다. 한별은 10.2킬로미터(㎞)를 100분의 1만큼, 슬기는 100미터(m)를 달렸다. 누가 더 많이 달렸습니까?",
        "question_en": "Hanbyeol and Seulgi did a running exercise. Hanbyeol ran 10.2 kilometers (km) as much as 1/100, and Seulgi ran 100 meters (m). Who ran more?",
        "answer_ko": "한별",
        "answer_en": "Hanbyeol",
        "solution_abst_ko": "[OP_LIST_SOL] 한별 슬기 [OP_LIST_EOL] [OP_LIST_SOL] 10.2 1000 [OP_MUL] 100 [OP_DIV] 100 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Hanbyeol Seulgi [OP_LIST_EOL] [OP_LIST_SOL] 10.2 1000 [OP_MUL] 100 [OP_DIV] 100 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '한별'\nvar_b = '슬기'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10.2\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 100\nvar_g = var_e / var_f\nvar_h = 100\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Hanbyeol'\nvar_b = 'Seulgi'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10.2\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 100\nvar_g = var_e / var_f\nvar_h = 100\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "3104": {
        "category": "Arithmetic calculation",
        "question_ko": "30명의 학생 중 절반이 여학생이고 그 중 7명이 초등학생이 아니다. 초등학생인 여학생은 몇 명이 있는지 찾으시오.",
        "question_en": "Half of the 30 students are girls, and 7 of them are not elementary school students. Find out how many female students are in elementary school.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "30 2 [OP_DIV] 7 [OP_SUB]",
        "solution_abst_en": "30 2 [OP_DIV] 7 [OP_SUB]",
        "solution_code_ko": "var_a = 30\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 30\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3105": {
        "category": "Arithmetic calculation",
        "question_ko": "남준이는 집에서 학교까지 1.2킬로미터(㎞)를 걸어 다닙니다. 오늘 남준이는 0.3킬로미터(㎞)를 걸어간 후 다시 집으로 돌아가 준비물을 챙긴 후에 학교에 갔습니다. 남준이는 오늘 평소보다 몇 킬로미터(㎞)를 더 많이 걸었는지 소수점을 포함하여 답을 구하시오.",
        "question_en": "Namjoon walks 1.2 kilometers (km) from home to school. Today, Namjoon walked 0.3 kilometers (km), went back home, got things ready, and went to school. How many more kilometers (km) did Namjoon walk than usual today? Find the answer including decimal points.",
        "answer_ko": "0.60",
        "answer_en": "0.6",
        "solution_abst_ko": "1.2 0.3 2 [OP_MUL] [OP_ADD] 1.2 [OP_SUB]",
        "solution_abst_en": "1.2 0.3 2 [OP_MUL] [OP_ADD] 1.2 [OP_SUB]",
        "solution_code_ko": "var_a = 1.2\nvar_b = 0.3\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nvar_f = 1.2\nvar_g = var_e - var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 1.2\nvar_b = 0.3\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nvar_f = 1.2\nvar_g = var_e - var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "3106": {
        "category": "Arithmetic calculation",
        "question_ko": "빨간색 끈의 길이는 8미터(m)입니다. 하얀색 끈의 길이는 빨간색 끈의 5배입니다. 하얀색 끈의 길이는 파란색 끈의 8배입니다. 파란색 끈의 길이는 몇 미터(m)입니까?",
        "question_en": "The length of the red string is 8 metres (m). The length of the white string is 5 times the length of the red string. The white string is 8 times as long as the blue string. How many metres (m) is the blue string?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "8 5 [OP_MUL] 8 [OP_DIV]",
        "solution_abst_en": "8 5 [OP_MUL] 8 [OP_DIV]",
        "solution_code_ko": "var_a = 8\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "3107": {
        "category": "Possibility",
        "question_ko": "숫자 카드 6, 9, 2 중 2장을 한 번씩 모두 사용하여 가장 작은 두 자리 수를 만들 때, 사용하지 않는 카드의 숫자는 무엇입니까?",
        "question_en": "What is the unused card if two of the number cards 6, 9 and 2 are used all at once to make the smallest two-digit number?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "[OP_LIST_SOL] 6 9 2 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] [OP_LIST_POP] [OP_NUM2LIST] [OP_SET_DIFFERENCE] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] 6 9 2 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] [OP_LIST_POP] [OP_NUM2LIST] [OP_SET_DIFFERENCE] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 6\nvar_b = 9\nvar_c = 2\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nlist_d = []\nvar_f = int(var_f)\nwhile var_f//10 > 0:\n    list_d.append(var_f%10)\n    var_f = var_f//10\nlist_d.append(var_f%10)\nlist_d = list_d[::-1]\nlist_e = list(set(list_a) - set(list_d))\nvar_g = 1\nvar_h = list_e[var_g-1]\nprint(int(var_h))",
        "solution_code_en": "var_a = 6\nvar_b = 9\nvar_c = 2\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nlist_d = []\nvar_f = int(var_f)\nwhile var_f//10 > 0:\n    list_d.append(var_f%10)\n    var_f = var_f//10\nlist_d.append(var_f%10)\nlist_d = list_d[::-1]\nlist_e = list(set(list_a) - set(list_d))\nvar_g = 1\nvar_h = list_e[var_g-1]\nprint(int(var_h))"
    },
    "3108": {
        "category": "Arithmetic calculation",
        "question_ko": "240에서 4를 35번 빼고, 3을 6번 빼면 나오는 수는 얼마입니까?",
        "question_en": "What is the number obtained by subtracting 35 times 4 and 6 times 3 from 240?",
        "answer_ko": "82",
        "answer_en": "82",
        "solution_abst_ko": "240 4 35 [OP_MUL] [OP_SUB] 3 6 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "240 4 35 [OP_MUL] [OP_SUB] 3 6 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 240\nvar_b = 4\nvar_c = 35\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 3\nvar_g = 6\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 240\nvar_b = 4\nvar_c = 35\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 3\nvar_g = 6\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nprint(int(var_i))"
    },
    "3109": {
        "category": "Correspondence",
        "question_ko": "어떤 두 자리 자연수에서 이 수의 십의 자리의 숫자와 일의 자리의 숫자를 서로 바꾼 수를 빼면 36이고, 이들 두 수의 합은 68이다. 처음의 두 자리 자연수를 구하시오.",
        "question_en": "Subtracting from a two-digit natural number by exchanging its tens and ones digits is 36, and the sum of these two numbers is 68. Find the first two-digit number.",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "68 36 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "68 36 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 68\nvar_b = 36\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 68\nvar_b = 36\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "3110": {
        "category": "Comparison",
        "question_ko": "(가)는 (나)보다 크며 (다)보다 작다. (마)는 (라)보다 작다. (나)는 (라)보다 크다. (가), (나), (다), (라), (마) 중 가장 작은 수는 무엇인가?",
        "question_en": "(a) is larger than (b) and smaller than (c). (e) is smaller than (d). (b) is greater than (d). Which number is the smallest among (a), (b), (c), (d), and (e)?",
        "answer_ko": "(마)",
        "answer_en": "(e)",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) (다) (라) (마) [OP_LIST_EOL] [OP_LIST_SOL] (가) (나) > (가) (다) < (마) (라) < (나) (라) > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (a) (b) (c) (d) (e) [OP_LIST_EOL] [OP_LIST_SOL] (a) (b) > (a) (c) < (e) (d) < (b) (d) > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nvar_c = '(다)'\nvar_d = '(라)'\nvar_e = '(마)'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = '(가)'\nvar_g = '(나)'\nvar_h = '>'\nvar_i = '(가)'\nvar_j = '(다)'\nvar_k = '<'\nvar_l = '(마)'\nvar_m = '(라)'\nvar_n = '<'\nvar_o = '(나)'\nvar_p = '(라)'\nvar_q = '>'\nlist_b= []\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_r = len(list_c)\nvar_s = list_c[var_r-1]\nprint(var_s)",
        "solution_code_en": "var_a = '(a)'\nvar_b = '(b)'\nvar_c = '(c)'\nvar_d = '(d)'\nvar_e = '(e)'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = '(a)'\nvar_g = '(b)'\nvar_h = '>'\nvar_i = '(a)'\nvar_j = '(c)'\nvar_k = '<'\nvar_l = '(e)'\nvar_m = '(d)'\nvar_n = '<'\nvar_o = '(b)'\nvar_p = '(d)'\nvar_q = '>'\nlist_b= []\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_r = len(list_c)\nvar_s = list_c[var_r-1]\nprint(var_s)"
    },
    "3111": {
        "category": "Correspondence",
        "question_ko": "나는 1부터 9까지의 수를 한번 씩 사용하여 만든 세 자리 수입니다. 나는 십의 자리 숫자는 1, 일의 자리 숫자는 8을 나타냅니다. 나는 358보다 크고 684보다 작습니다. 나는 어떤 수 입니까?",
        "question_en": "I am a three-digit number formed by using the digits 1 to 9 once each. 1 is in the tens place and 8 is in the ones place. I'm greater than 358 and less than 684. What number am I?",
        "answer_ko": "418",
        "answer_en": "418",
        "solution_abst_ko": "1 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] 10 1 [OP_LIST_SEARCH_FIXED_DIGIT] 1 8 [OP_LIST_SEARCH_FIXED_DIGIT] 358 [OP_LIST_MORE] 684 [OP_LIST_LESS] 1 [OP_LIST_GET]",
        "solution_abst_en": "1 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] 10 1 [OP_LIST_SEARCH_FIXED_DIGIT] 1 8 [OP_LIST_SEARCH_FIXED_DIGIT] 358 [OP_LIST_MORE] 684 [OP_LIST_LESS] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 10\nvar_f = 1\nlist_c = [] \nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if (i//var_e)%10 == var_f:\n        list_c.append(i)\nvar_g = 1\nvar_h = 8\nlist_d = [] \nvar_g = int(var_g)\nvar_h = int(var_h)\nfor i in list_c:\n    i = int(i)\n    if (i//var_g)%10 == var_h:\n        list_d.append(i)\nvar_i = 358\nlist_e = []\nfor i in list_d:\n    if i > var_i:\n        list_e.append(i)\nvar_j = 684\nlist_f = []\nfor i in list_e:\n    if i < var_j:\n        list_f.append(i)\nvar_k = 1\nvar_l = list_f[var_k-1]\nprint(int(var_l))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 10\nvar_f = 1\nlist_c = [] \nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if (i//var_e)%10 == var_f:\n        list_c.append(i)\nvar_g = 1\nvar_h = 8\nlist_d = [] \nvar_g = int(var_g)\nvar_h = int(var_h)\nfor i in list_c:\n    i = int(i)\n    if (i//var_g)%10 == var_h:\n        list_d.append(i)\nvar_i = 358\nlist_e = []\nfor i in list_d:\n    if i > var_i:\n        list_e.append(i)\nvar_j = 684\nlist_f = []\nfor i in list_e:\n    if i < var_j:\n        list_f.append(i)\nvar_k = 1\nvar_l = list_f[var_k-1]\nprint(int(var_l))"
    },
    "3112": {
        "category": "Geometry",
        "question_ko": "육각기둥의 꼭지점 개수와 오각기둥의 꼭지점 개수의 차를 구하시오.",
        "question_en": "Find the difference between the number of verticles of a hexagonal prism and the number of vertices of a pentagonal prism.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "6 2 [OP_MUL] 5 2 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "6 2 [OP_MUL] 5 2 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "3113": {
        "category": "Arithmetic calculation",
        "question_ko": "어머니께서 3킬로그램(㎏)짜리 꿀을 4통 사서 이웃 사람들에게 3/4킬로그램(㎏)씩 나누어 주려고 합니다. 몇 명에게 나누어 줄 수 있나요?",
        "question_en": "My mother wants to buy 4 bottles of honey weighing 3kg (kg) and distribute 3/4 kg (kg) to each neighbor. With how many people can she share?",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "3 4 [OP_MUL] 3/4 [OP_FDIV]",
        "solution_abst_en": "3 4 [OP_MUL] 3/4 [OP_FDIV]",
        "solution_code_ko": "var_a = 3\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 0.75\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 3\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 0.75\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "3114": {
        "category": "Arithmetic calculation",
        "question_ko": "12리터(L) 400밀리리터(㎖)의 우유를 두 반에 나누어 주려고 합니다. 1반에는 2반보다 2리터(L) 600밀리리터(㎖)를 더 주려고 할 때 1반에 몇 리터(L)를 주게 됩니까?",
        "question_en": "You want to divide 12 litres (L) 400 millilitres (ml) of milk between two classes. If you give class 1 2 litres (L) 600 millilitres (ml) more than class 2, how many litres (L) will you give to class 1?",
        "answer_ko": "1.30",
        "answer_en": "1.3",
        "solution_abst_ko": "12 400 1000 [OP_DIV] [OP_ADD] 2 600 1000 [OP_DIV] [OP_ADD] 2 [OP_DIV]",
        "solution_abst_en": "12 400 1000 [OP_DIV] [OP_ADD] 2 600 1000 [OP_DIV] [OP_ADD] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 400\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 2\nvar_g = 600\nvar_h = 1000\nvar_i = var_g / var_h\nvar_j = var_f + var_i\nvar_k = 2\nvar_l = var_j / var_k\nprint('{:.2f}'.format(round(var_l+1e-10,2)))",
        "solution_code_en": "var_a = 12\nvar_b = 400\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 2\nvar_g = 600\nvar_h = 1000\nvar_i = var_g / var_h\nvar_j = var_f + var_i\nvar_k = 2\nvar_l = var_j / var_k\nprint('{:.2f}'.format(round(var_l+1e-10,2)))"
    },
    "3115": {
        "category": "Arithmetic calculation",
        "question_ko": "1개의 상자에는 빨간 공 3개와 파란 공 5개가 담겨져 있습니다. 정국이는 2개의 상자를 가지고 있을 때 정국이가 가지고 있는 파란 공의 개수는?",
        "question_en": "Each box contains 3 red balls and 5 blue balls. When Jungkook has 2 boxes, how many blue balls does Jungkook have?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "5 2 [OP_MUL]",
        "solution_abst_en": "5 2 [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "3116": {
        "category": "Comparison",
        "question_ko": "나나와 가은이는 멀리뛰기를 하였습니다. 나나는 1.618 미터(m)를 뛰었고, 가은이는 162.3 센티미터(㎝)를 뛰었습니다. 더 멀리 뛴 사람은 누구일까요?",
        "question_en": "Nana and Gaeun did a long jump. Nana jumped 1.618 meters (m) and Gaeun jumped 162.3 centimeters (cm). Who jumped further?",
        "answer_ko": "가은",
        "answer_en": "Gaeun",
        "solution_abst_ko": "[OP_LIST_SOL] 나나 가은 [OP_LIST_EOL] [OP_LIST_SOL] 1.618 100 [OP_MUL] 162.3 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Nana Gaeun [OP_LIST_EOL] [OP_LIST_SOL] 1.618 100 [OP_MUL] 162.3 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '나나'\nvar_b = '가은'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.618\nvar_d = 100\nvar_e = var_c * var_d\nvar_f = 162.3\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Nana'\nvar_b = 'Gaeun'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.618\nvar_d = 100\nvar_e = var_c * var_d\nvar_f = 162.3\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "3117": {
        "category": "Possibility",
        "question_ko": "A, B, C, D를 사전식으로 ABCD부터 DCBA까지 배열할 때, CABD는 몇 번째에 오는지 구하시오.",
        "question_en": "When A, B, C, and D are arranged lexicographically from ABCD to DCBA, find the number in which CABD comes.",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "[OP_LIST_SOL] A B C D [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] CABD [OP_LIST_INDEX]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] CABD [OP_LIST_INDEX]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = 'CABD'\nvar_i = list_b.index(var_h)+1\nprint(int(var_i))",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = 'CABD'\nvar_i = list_b.index(var_h)+1\nprint(int(var_i))"
    },
    "3118": {
        "category": "Arithmetic calculation",
        "question_ko": "연속하는 6개의 자연수 중에서 가장 큰 수와 가장 작은 수의 차를 구하시오.",
        "question_en": "Find the difference between the largest and smallest of 6 consecutive natural numbers.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "6 1 [OP_SUB]",
        "solution_abst_en": "6 1 [OP_SUB]",
        "solution_code_ko": "var_a = 6\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "3119": {
        "category": "Possibility",
        "question_ko": "9, 4, 3, 5 중에서 서로 다른 숫자 2개를 뽑아 만들 수 있는 두 자리 수 중 가장 큰 수에서 가장 작은 수를 뺀 값을 구하시오.",
        "question_en": "Find the value of subtracting the smallest two-digit number from the largest two-digit number that can be formed by drawing two different numbers from 9, 4, 3, and 5.",
        "answer_ko": "61",
        "answer_en": "61",
        "solution_abst_ko": "[OP_LIST_SOL] 9 4 3 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 9 4 3 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 9\nvar_b = 4\nvar_c = 3\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 9\nvar_b = 4\nvar_c = 3\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))"
    },
    "3120": {
        "category": "Comparison",
        "question_ko": "세 판자 (가), (나), (다)의 높이는 각각 2.4센티미터(㎝), 3.2센티미터(㎝), 2.8센티미터(㎝)입니다. 은지는 (가) 판자를 8개 쌓은 곳 위에 서 있습니다. 남준이는 (나) 판자를 4개 쌓은 곳 위에 서 있습니다. 호석이는 (다) 판자를 5개 쌓은 곳 위에 서 있습니다. 누가 땅에서 가장 낮은 곳에 서 있습니까?",
        "question_en": "The heights of the three planks A, B, and C are 2.4 centimeters (cm), 3.2 centimeters (cm), and 2.8 centimeters (cm), respectively. Eunji is standing on top of a stack of 8 A. Namjoon is standing on top of 4 B, and Hoseok is standing on top of 5 C. Who is standing on the lowest place from the earth?",
        "answer_ko": "남준",
        "answer_en": "Namjoon",
        "solution_abst_ko": "[OP_LIST_SOL] 은지 남준 호석 [OP_LIST_EOL] [OP_LIST_SOL] 2.4 8 [OP_MUL] 3.2 4 [OP_MUL] 2.8 5 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Eunji Namjoon Hoseok [OP_LIST_EOL] [OP_LIST_SOL] 2.4 8 [OP_MUL] 3.2 4 [OP_MUL] 2.8 5 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '은지'\nvar_b = '남준'\nvar_c = '호석'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2.4\nvar_e = 8\nvar_f = var_d * var_e\nvar_g = 3.2\nvar_h = 4\nvar_i = var_g * var_h\nvar_j = 2.8\nvar_k = 5\nvar_l = var_j * var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[var_m-1]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'Eunji'\nvar_b = 'Namjoon'\nvar_c = 'Hoseok'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2.4\nvar_e = 8\nvar_f = var_d * var_e\nvar_g = 3.2\nvar_h = 4\nvar_i = var_g * var_h\nvar_j = 2.8\nvar_k = 5\nvar_l = var_j * var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[var_m-1]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "3121": {
        "category": "Arithmetic calculation",
        "question_ko": "오늘 수학 시간에 태형이는 9개의 문제를 풀고 남아서 7개의 문제를 더 풀었습니다. 오늘 태형이가 푼 수학 문제의 수는 몇 개입니까?",
        "question_en": "In math class, Taehyung solved 9 problems and kept working on doing 7 more problems. How many math problems did Taehyung solve today?",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "9 7 [OP_ADD]",
        "solution_abst_en": "9 7 [OP_ADD]",
        "solution_code_ko": "var_a = 9\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 9\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "3122": {
        "category": "Possibility",
        "question_ko": "승아는 5명의 친구들과 조별과제를 하게 되어 조장 1명, 서기 1명, 발표자 2명을 뽑게 되었다. 승아가 조장을 하게 되는 경우의 수를 구하시오.",
        "question_en": "Seung-a had a group assignment with 5 friends and chose 1 leader, 1 secretary, and 2 presenters. Find the number of cases in which Seung-ah becomes the leader.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "5 1 [OP_SUB] 1 1 1 [OP_SUB] [OP_ADD] 2 [OP_ADD] [OP_PERM] 2 2 [OP_PERM] [OP_DIV]",
        "solution_abst_en": "5 1 [OP_SUB] 1 1 1 [OP_SUB] [OP_ADD] 2 [OP_ADD] [OP_PERM] 2 2 [OP_PERM] [OP_DIV]",
        "solution_code_ko": "var_a = 5\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = 1\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d + var_g\nvar_i = 2\nvar_j = var_h + var_i\nvar_k = 1\nvar_c = int(var_c)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_c-i)\nvar_l = 2\nvar_m = 2\nvar_n = 1\nvar_l = int(var_l)\nvar_m = int(var_m)\nfor i, elem in enumerate(range(var_m)):\n    var_n = var_n * (var_l-i)\nvar_o = var_k / var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 5\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = 1\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d + var_g\nvar_i = 2\nvar_j = var_h + var_i\nvar_k = 1\nvar_c = int(var_c)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_c-i)\nvar_l = 2\nvar_m = 2\nvar_n = 1\nvar_l = int(var_l)\nvar_m = int(var_m)\nfor i, elem in enumerate(range(var_m)):\n    var_n = var_n * (var_l-i)\nvar_o = var_k / var_n\nprint(int(var_o))"
    },
    "3123": {
        "category": "Comparison",
        "question_ko": "두 친구가 운동을 열심히 하기로 했습니다. 예슬이는 13/10시간을, 영준이는 22/15시간을 했을 때, 두 사람 중 더 오래 운동을 한 사람은 누구입니까?",
        "question_en": "Two friends decided to exercise hard. If Yeseul did 13/10 hours and Youngjun did 22/15 hours, which of the two worked out longer?",
        "answer_ko": "영준",
        "answer_en": "Youngjun",
        "solution_abst_ko": "[OP_LIST_SOL] 예슬 영준 [OP_LIST_EOL] [OP_LIST_SOL] 13/10 22/15 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yeseul Youngjun [OP_LIST_EOL] [OP_LIST_SOL] 13/10 22/15 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '예슬'\nvar_b = '영준'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.3\nvar_d = 1.4666666666666666\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Yeseul'\nvar_b = 'Youngjun'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.3\nvar_d = 1.4666666666666666\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "3124": {
        "category": "Arithmetic calculation",
        "question_ko": "사과가 275개 있습니다. 이 사과를 한 상자에 20개씩 담아서 8000원씩 받고 팔려고 합니다. 사과를 담은 상자를 모두 판다면 사과를 판 돈은 얼마입니까?",
        "question_en": "There are 275 apples. I am going to put 20 apples in a box and sell them for 8,000 won each. If you sold all the boxes of apples, how much did you get after selling the apples?",
        "answer_ko": "104000",
        "answer_en": "104000",
        "solution_abst_ko": "275 20 [OP_FDIV] 8000 [OP_MUL]",
        "solution_abst_en": "275 20 [OP_FDIV] 8000 [OP_MUL]",
        "solution_code_ko": "var_a = 275\nvar_b = 20\nvar_c = var_a // var_b\nvar_d = 8000\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 275\nvar_b = 20\nvar_c = var_a // var_b\nvar_d = 8000\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "3125": {
        "category": "Geometry",
        "question_ko": "정육면체 모양의 상자는 한 모서리의 길이가 11센티미터(㎝)입니다. 이 상자의 겉넓이는 얼마입니까?",
        "question_en": "A cube-shaped box measures 11 centimeters (cm) at one edge. What is the surface area of this box?",
        "answer_ko": "726",
        "answer_en": "726",
        "solution_abst_ko": "11 2 [OP_POW] 6 [OP_MUL]",
        "solution_abst_en": "11 2 [OP_POW] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 11\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 11\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "3126": {
        "category": "Geometry",
        "question_ko": "반지름이 2센티미터(㎝)인 구의 겉넓이와 같은 넓이를 가지는 원의 반지름의 길이는?",
        "question_en": "What is the length of the radius of a circle with an area equal to the surface area of a sphere with a radius of 2 cm (cm)?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "4 2 2 [OP_POW] [OP_MUL] 1/2 [OP_POW]",
        "solution_abst_en": "4 2 2 [OP_POW] [OP_MUL] 1/2 [OP_POW]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = 2\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 0.5\nvar_g = var_e ** var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = 2\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 0.5\nvar_g = var_e ** var_f\nprint(int(var_g))"
    },
    "3127": {
        "category": "Arithmetic calculation",
        "question_ko": "찬휘는 한 걸음에 0.75미터(m)를 가고 1분 동안 70걸음을 직진으로 걸어갔다면, 13분 후의 찬휘의 위치는 현재 위치와 몇 미터(m) 차이 납니까?",
        "question_en": "If Chanhui walks 0.75 meters (m) per step and walks 70 steps straight for 1 minute, how many meters (m) does Chanhui's location after 13 minutes differ from his current location?",
        "answer_ko": "682.50",
        "answer_en": "682.5",
        "solution_abst_ko": "0.75 70 [OP_MUL] 13 [OP_MUL]",
        "solution_abst_en": "0.75 70 [OP_MUL] 13 [OP_MUL]",
        "solution_code_ko": "var_a = 0.75\nvar_b = 70\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.75\nvar_b = 70\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "3128": {
        "category": "Possibility",
        "question_ko": "민수는 국어 문제집 2권, 영어 문제집 2권을 책꽂이에 일렬로 꽂으려고 한다. 국어 문제집끼리 나란히 꽂는 방법은 모두 몇 가지인가?",
        "question_en": "Minsu wants to put 2 Korean and 2 English workbooks next to each other on the bookshelf. If each workbook is different, how many ways can he put the Korean workbooks next to each other?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "2 1 [OP_ADD] 2 1 [OP_ADD] [OP_PERM] 2 [OP_MUL]",
        "solution_abst_en": "2 1 [OP_ADD] 2 1 [OP_ADD] [OP_PERM] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = 1\nvar_c = int(var_c)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_c-i)\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 2\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = 1\nvar_c = int(var_c)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_c-i)\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "3129": {
        "category": "Arithmetic calculation",
        "question_ko": "초록색 색종이 9장과 빨간색 색종이 1장을 가지고 있는 은지는 자신이 가진 색종이 중 4장을 유나에게 주었습니다. 은지에게 몇 장의 색종이가 남았을지 구하시오.",
        "question_en": "Eunji, who had 9 pieces of green confetti and 1 piece of red confetti, gave 4 of her confetti to Yuna. How many pieces of confetti does Eunji have now?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "1 9 [OP_ADD] 4 [OP_SUB]",
        "solution_abst_en": "1 9 [OP_ADD] 4 [OP_SUB]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3130": {
        "category": "Comparison",
        "question_ko": "네 명의 학생 윤기, 정국, 유나, 유정은 각각 7, 6, 9, 8만큼의 숫자를 가지고 있습니다. 2번째로 큰 숫자를 가진 사람은 누구입니까?",
        "question_en": "The four students, Yoongi, Jungkook, Yuna, and Yoojung, each have the numbers 7, 6, 9, and 8. Who has the 2nd largest number?",
        "answer_ko": "유정",
        "answer_en": "Yoojung",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 유나 유정 [OP_LIST_EOL] [OP_LIST_SOL] 7 6 9 8 [OP_LIST_EOL] 2 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook Yuna Yoojung [OP_LIST_EOL] [OP_LIST_SOL] 7 6 9 8 [OP_LIST_EOL] 2 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nvar_c = '유나'\nvar_d = '유정'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 7\nvar_f = 6\nvar_g = 9\nvar_h = 8\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nvar_c = 'Yuna'\nvar_d = 'Yoojung'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 7\nvar_f = 6\nvar_g = 9\nvar_h = 8\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "3131": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 -2/3을 곱하고 -4/5를 나누었더니 그 결과가 -1/2이었습니다. 어떤 수를 구하시오.",
        "question_en": "When you multiply a number by -2/3 and divide by -4/5, the result is -1/2. Find the number.",
        "answer_ko": "-0.60",
        "answer_en": "-0.6",
        "solution_abst_ko": "-1/2 -4/5 [OP_MUL] -2/3 [OP_DIV]",
        "solution_abst_en": "-1/2 -4/5 [OP_MUL] -2/3 [OP_DIV]",
        "solution_code_ko": "var_a = -0.5\nvar_b = -0.8\nvar_c = var_a * var_b\nvar_d = -0.6666666666666666\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = -0.5\nvar_b = -0.8\nvar_c = var_a * var_b\nvar_d = -0.6666666666666666\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "3132": {
        "category": "Possibility",
        "question_ko": "정국, 지민, 윤기, 유나, 태형 중에서 2명을 선택해서 줄 세우려고 합니다. 경우의 수는 모두 몇 가지입니까?",
        "question_en": "You are going to choose two people among Jungkook, Jimin, Yoongi, Yuna, and Taehyung and line them up. How many cases are there in all?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 지민 윤기 유나 태형 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Jimin Yoongi Yuna Taehyung [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '지민'\nvar_c = '윤기'\nvar_d = '유나'\nvar_e = '태형'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nprint(int(var_h))",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Jimin'\nvar_c = 'Yoongi'\nvar_d = 'Yuna'\nvar_e = 'Taehyung'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nprint(int(var_h))"
    },
    "3133": {
        "category": "Arithmetic calculation",
        "question_ko": "45보다 크고 54보다 작은 두 자리 수는 모두 몇 개입니까?",
        "question_en": "Find how many two-digit numbers are greater than 45 and less than 54.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "45 1 [OP_ADD] 54 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_LEN]",
        "solution_abst_en": "45 1 [OP_ADD] 54 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 45\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 54\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = len(list_a)\nprint(int(var_h))",
        "solution_code_en": "var_a = 45\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 54\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = len(list_a)\nprint(int(var_h))"
    },
    "3134": {
        "category": "Comparison",
        "question_ko": "유나, 유정, 민영이 은행에서 번호표를 뽑았습니다. 민영이의 번호는 유나보다 작고, 유정의 번호는 유나보다 큽니다. 가장 작은 번호를 가진 사람은 누구입니까?",
        "question_en": "Yuna, Yoojung, and Minyoung took number tickets at the bank. Minyoung's number is lower than Yuna's, and Yoojung's number is greater than Yuna's. Who has the smallest number?",
        "answer_ko": "민영",
        "answer_en": "Minyoung",
        "solution_abst_ko": "[OP_LIST_SOL] 유나 유정 민영 [OP_LIST_EOL] [OP_LIST_SOL] 유나 유정 < 민영 유나 < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yuna Yoojung Minyoung  [OP_LIST_EOL] [OP_LIST_SOL] Yuna Yoojung < Minyoung Yuna < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '유나'\nvar_b = '유정'\nvar_c = '민영'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '유나'\nvar_e = '유정'\nvar_f = '<'\nvar_g = '민영'\nvar_h = '유나'\nvar_i = '<'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = len(list_c)\nvar_k = list_c[var_j-1]\nprint(var_k)",
        "solution_code_en": "var_a = 'Yuna'\nvar_b = 'Yoojung'\nvar_c = 'Minyoung'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'Yuna'\nvar_e = 'Yoojung'\nvar_f = '<'\nvar_g = 'Minyoung'\nvar_h = 'Yuna'\nvar_i = '<'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = len(list_c)\nvar_k = list_c[var_j-1]\nprint(var_k)"
    },
    "3135": {
        "category": "Arithmetic calculation",
        "question_ko": "(가)는 길이가 5미터(m), 무게가 29/8킬로그램(㎏)이고, (나)는 길이가 4미터(m), 무게가 2.8킬로그램(㎏)인 나무도막이다. (가), (나)를 2미터(m)씩 잘라 함께 무게를 재면 몇 킬로그램(㎏)인가?",
        "question_en": "(A) is a wooden block 5 meters (m) long and weighing 29/8 kg (kg), and (B) is a block of wood 4 meters (m) long and weighing 2.8 kg (kg). If you cut (A) and (B) by 2 meters (m) and weigh them together, how many kilograms (kg) are they?",
        "answer_ko": "2.85",
        "answer_en": "2.85",
        "solution_abst_ko": "29/8 5 [OP_DIV] 2 [OP_MUL] 2.8 4 [OP_DIV] 2 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "29/8 5 [OP_DIV] 2 [OP_MUL] 2.8 4 [OP_DIV] 2 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 3.625\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 2.8\nvar_g = 4\nvar_h = var_f / var_g\nvar_i = 2\nvar_j = var_h * var_i\nvar_k = var_e + var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 3.625\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 2.8\nvar_g = 4\nvar_h = var_f / var_g\nvar_i = 2\nvar_j = var_h * var_i\nvar_k = var_e + var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "3136": {
        "category": "Arithmetic calculation",
        "question_ko": "15명의 학생에 구슬을 똑같이 나누어 주려고 합니다. 구슬이 328개 있을 때 몇 개의 구슬이 더 필요합니까?",
        "question_en": "You want to distribute the marbles equally among 15 students. How many more marbles do you need when there are 328 marbles?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "15 328 15 [OP_MOD] [OP_SUB]",
        "solution_abst_en": "15 328 15 [OP_MOD] [OP_SUB]",
        "solution_code_ko": "var_a = 15\nvar_b = 328\nvar_c = 15\nvar_d = var_b % var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 328\nvar_c = 15\nvar_d = var_b % var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "3137": {
        "category": "Arithmetic calculation",
        "question_ko": "1에서 9까지의 숫자가 적힌 숫자카드를 중복 사용하여 세 자리 자연수를 만들 때, 3으로 나눈 나머지가 2인 수들의 평균을 구하시오.",
        "question_en": "When creating a three-digit natural number by repeatedly using number cards with the numbers 1 to 9 written on them, find the average of the numbers whose remainder when divided by 3 is 2.",
        "answer_ko": "555",
        "answer_en": "555",
        "solution_abst_ko": "1 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PRODUCT] 3 2 [OP_LIST_DIVIDE_AND_REMAIN] [OP_LIST_MEAN]",
        "solution_abst_en": "1 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PRODUCT] 3 2 [OP_LIST_DIVIDE_AND_REMAIN] [OP_LIST_MEAN]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 3\nvar_f = 2\nlist_c = [] \nvar_e = int(var_e)\nvar_f = int(var_f)\nif var_f < 0:\n    var_f = var_f + var_e\nfor i in list_b:\n    i = int(i)\n    if i%var_e == var_f:\n        list_c.append(i)\nlist_c = [float(i) for i in list_c]\nvar_g = sum(list_c)/len(list_c)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 3\nvar_f = 2\nlist_c = [] \nvar_e = int(var_e)\nvar_f = int(var_f)\nif var_f < 0:\n    var_f = var_f + var_e\nfor i in list_b:\n    i = int(i)\n    if i%var_e == var_f:\n        list_c.append(i)\nlist_c = [float(i) for i in list_c]\nvar_g = sum(list_c)/len(list_c)\nprint(int(var_g))"
    },
    "3138": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 숫자 5.5, 9/2, 8.51, 1/9가 있습니다. 이들을 모두 더하면 얼마인가요?",
        "question_en": "There are four numbers 5.5, 9/2, 8.51 and 1/9. What is the sum of them all?",
        "answer_ko": "18.62",
        "answer_en": "18.62",
        "solution_abst_ko": "5.5 9/2 [OP_ADD] 8.51 [OP_ADD] 1/9 [OP_ADD]",
        "solution_abst_en": "5.5 9/2 [OP_ADD] 8.51 [OP_ADD] 1/9 [OP_ADD]",
        "solution_code_ko": "var_a = 5.5\nvar_b = 4.5\nvar_c = var_a + var_b\nvar_d = 8.51\nvar_e = var_c + var_d\nvar_f = 0.1111111111111111\nvar_g = var_e + var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 5.5\nvar_b = 4.5\nvar_c = var_a + var_b\nvar_d = 8.51\nvar_e = var_c + var_d\nvar_f = 0.1111111111111111\nvar_g = var_e + var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "3139": {
        "category": "Possibility",
        "question_ko": "서로 다른 다섯 사람 A, B, C, D, E를 한 줄로 세워야 합니다. A가 맨 앞에 오는 경우는 모두 몇가지 입니까?",
        "question_en": "You have to line up five different people A, B, C, D, and E. How many ways can A come first?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "[OP_LIST_SOL] A B C D E [OP_LIST_EOL] [OP_LIST_SOL] A [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D E [OP_LIST_EOL] [OP_LIST_SOL] A [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 'A'\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_g = len(list_c)\nvar_h = len(list_c)\nvar_i = 1\nvar_g = int(var_g)\nvar_h = int(var_h)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i * (var_g-i)\nprint(int(var_i))",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 'A'\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_g = len(list_c)\nvar_h = len(list_c)\nvar_i = 1\nvar_g = int(var_g)\nvar_h = int(var_h)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i * (var_g-i)\nprint(int(var_i))"
    },
    "3140": {
        "category": "Possibility",
        "question_ko": "세 수 0, 2, 5를 한 번씩만 사용하여 만들 수 있는 서로 다른 두 자리 수는 모두 몇 개입니까?",
        "question_en": "How many different two-digit numbers can be formed using the three numbers 0, 2, and 5 only once?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 0 2 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 2 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 2\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 0\nvar_b = 2\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "3141": {
        "category": "Correspondence",
        "question_ko": "어떤수에 16을 곱해야 하는데 실수로 19를 더했더니 50이 됐습니다. 바르게 계산하면 결과가 어떻게 됩니까?",
        "question_en": "A certain number has to be multiplied by 16, but I accidentally added 19 and the result was 50. What is the result if calculated correctly?",
        "answer_ko": "496",
        "answer_en": "496",
        "solution_abst_ko": "16 50 19 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "16 50 19 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 16\nvar_b = 50\nvar_c = 19\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 16\nvar_b = 50\nvar_c = 19\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nprint(int(var_e))"
    },
    "3142": {
        "category": "Geometry",
        "question_ko": "가로, 세로, 높이가 각각 12센티미터(㎝), 16센티미터(㎝), 14센티미터(㎝)인 직육면체가 있다. 직육면체를 잘라서 만들 수 있는 가장 큰 정육면체의 겉넓이의 값은?",
        "question_en": "The widths, depths, and heights of a cuboid are 12 centimeters (cm), 16 centimeters (cm), and 14 centimeters (cm), respectively. What is the perimeter of the largest cube that can be formed by cutting this cuboid?",
        "answer_ko": "864",
        "answer_en": "864",
        "solution_abst_ko": "[OP_LIST_SOL] 12 16 14 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_POW] 6 [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 12 16 14 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_POW] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 12\nvar_b = 16\nvar_c = 14\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nvar_f = 2\nvar_g = var_e ** var_f\nvar_h = 6\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 12\nvar_b = 16\nvar_c = 14\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nvar_f = 2\nvar_g = var_e ** var_f\nvar_h = 6\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "3143": {
        "category": "Arithmetic calculation",
        "question_ko": "민호는 생일잔치에 초대한 8명에게 똑같이 나누어 주려고 사탕을 몇 개 준비하였습니다. 그런데 2명이 참석하지 않아서 1명에게 1개씩 더 주었더니 사탕이 4개 남았습니다. 민호가 준비한 사탕은 모두 몇 개입니까?",
        "question_en": "Minho prepared some candies to give equally to the 8 people invited to the birthday party. However, since 2 people did not come, so he gave 1 extra candy to each person, and there were 4 candies left. How many candies did Minho prepare?",
        "answer_ko": "40",
        "answer_en": "40",
        "solution_abst_ko": "8 2 [OP_SUB] 4 [OP_ADD] 8 8 2 [OP_SUB] [OP_SUB] [OP_FDIV] 8 [OP_MUL]",
        "solution_abst_en": "8 2 [OP_SUB] 4 [OP_ADD] 8 8 2 [OP_SUB] [OP_SUB] [OP_FDIV] 8 [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = 8\nvar_h = 2\nvar_i = var_g - var_h\nvar_j = var_f - var_i\nvar_k = var_e // var_j\nvar_l = 8\nvar_m = var_k * var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 8\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = 8\nvar_h = 2\nvar_i = var_g - var_h\nvar_j = var_f - var_i\nvar_k = var_e // var_j\nvar_l = 8\nvar_m = var_k * var_l\nprint(int(var_m))"
    },
    "3144": {
        "category": "Arithmetic calculation",
        "question_ko": "기태는 문구점에서 한 자루에 1000원인 연필과 한 자루에 1300원인 볼펜을 합하여 12자루를 샀습니다. 기태가 가진 돈 15000원을 모두 사용하였을 때, 기태가 산 연필은 모두 몇 자루일까요?",
        "question_en": "Ki-tae bought 12 pens at a stationery store, including pencils that cost 1,000 won each and ballpoint pens that cost 1,300 won each. How many pencils did Ki-tae buy when he used all his money of 15,000 won?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "1300 12 [OP_MUL] 15000 [OP_SUB] 1300 1000 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "1300 12 [OP_MUL] 15000 [OP_SUB] 1300 1000 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 1300\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 15000\nvar_e = var_c - var_d\nvar_f = 1300\nvar_g = 1000\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1300\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 15000\nvar_e = var_c - var_d\nvar_f = 1300\nvar_g = 1000\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "3145": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 각각 8, 10인 두 정사각형이 있습니다. 두 정사각형의 넓이의 합을 구하시오.",
        "question_en": "There are two squares with side lengths of 8 and 10 respectively. Find the sum of the areas of the two squares.",
        "answer_ko": "164",
        "answer_en": "164",
        "solution_abst_ko": "8 2 [OP_POW] 10 2 [OP_POW] [OP_ADD]",
        "solution_abst_en": "8 2 [OP_POW] 10 2 [OP_POW] [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 10\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 8\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 10\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "3146": {
        "category": "Arithmetic calculation",
        "question_ko": "석민이네 학교에서는 졸업을 앞둔 6학년 학생 134명에게 쿠키를 7개씩 나누어 주었습니다. 쿠키가 한 상자에 28개씩 들어있었다면 학교에서는 몇 상자의 쿠키를 구매했을까요?",
        "question_en": "At Seokmin's school, 7 cookies were distributed to 134 6th grade students who were about to graduate. How many boxes of cookies would the school buy if there were 28 cookies in each box?",
        "answer_ko": "34",
        "answer_en": "34",
        "solution_abst_ko": "134 7 [OP_MUL] 28 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "134 7 [OP_MUL] 28 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 134\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 28\nvar_e = var_c / var_d\nvar_f = 1\nvar_g=int(((var_e+9*10**(var_f-2))//(10**(var_f-1)))*10**(var_f-1))\n\nprint(int(var_g))",
        "solution_code_en": "var_a = 134\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 28\nvar_e = var_c / var_d\nvar_f = 1\nvar_g=int(((var_e+9*10**(var_f-2))//(10**(var_f-1)))*10**(var_f-1))\n\nprint(int(var_g))"
    },
    "3147": {
        "category": "Arithmetic calculation",
        "question_ko": "유정이가 가진 꽃의 4배 만큼 민영이는 꽃을 가지고 있습니다. 민영이가 가진 꽃이 24송이라면 민영이와 유정이가 가진 꽃은 모두 몇 송이입니까?",
        "question_en": "Minyoung has four times as many flowers as Yoojung has. If Minyoung has 24 flowers, how many flowers do Minyoung and Yoojung have?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "24 24 4 [OP_DIV] [OP_ADD]",
        "solution_abst_en": "24 24 4 [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 24\nvar_b = 24\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 24\nvar_b = 24\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "3148": {
        "category": "Possibility",
        "question_ko": "세 자리 자연수 중 0, 1, 3, 5, 6으로 이루어져 있는 수는 몇 개인지 구하시오. 단, 각 자리의 숫자는 달라야 합니다.",
        "question_en": "How many three-digit numbers are made up of 0, 1, 3, 5, and 6? However, each digit must be different.",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 3 5 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 200 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 3 5 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 200 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 3\nvar_d = 5\nvar_e = 6\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 200\nlist_c = []\nfor i in list_b:\n    if i > var_g:\n        list_c.append(i)\nvar_h = len(list_c)\nprint(int(var_h))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 3\nvar_d = 5\nvar_e = 6\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 200\nlist_c = []\nfor i in list_b:\n    if i > var_g:\n        list_c.append(i)\nvar_h = len(list_c)\nprint(int(var_h))"
    },
    "3149": {
        "category": "Arithmetic calculation",
        "question_ko": "아버지의 나이는 태형이의 5배이고, 어머니의 나이는 태형이의 4배입니다. 태형이가 9살이라면 어머니는 아버지보다 몇 살 어립니까?",
        "question_en": "The father is 5 times Taehyung's age, and the mother is 4 times Taehyung's age. If Taehyung is 9 years old, how many years younger is his mother than his father?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "9 5 [OP_MUL] 9 4 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "9 5 [OP_MUL] 9 4 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 9\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = 4\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 9\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = 4\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "3150": {
        "category": "Comparison",
        "question_ko": "일곱 개의 수 1.7, 1/5, 1/5, 1, 3/5, 3/8, 1.4가 있습니다. 크기를 비교하여 가장 큰 수부터 차례로 쓸 때 네 번째에 놓이는 수는 무엇입니까?",
        "question_en": "There are seven numbers 1.7, 1/5, 1/5, 1, 3/5, 3/8, and 1.4. When you write them down from the largest to the smallest, which number comes the fourth?",
        "answer_ko": "0.60",
        "answer_en": "0.6",
        "solution_abst_ko": "[OP_LIST_SOL] 1.7 1/5 1/5 1 3/5 3/8 1.4 [OP_LIST_EOL] 4 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1.7 1/5 1/5 1 3/5 3/8 1.4 [OP_LIST_EOL] 4 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1.7\nvar_b = 0.2\nvar_c = 0.2\nvar_d = 1\nvar_e = 0.6\nvar_f = 0.375\nvar_g = 1.4\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h = 4\nlist_b=list_a.copy()\nlist_b.sort()\nvar_i = list_b[-var_h]\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 1.7\nvar_b = 0.2\nvar_c = 0.2\nvar_d = 1\nvar_e = 0.6\nvar_f = 0.375\nvar_g = 1.4\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h = 4\nlist_b=list_a.copy()\nlist_b.sort()\nvar_i = list_b[-var_h]\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "3151": {
        "category": "Comparison",
        "question_ko": "서로 다른 두 자연수 B와 36은 약수와 배수 관계입니다. B는 3보다 크고 150보다 작습니다. B에 해당하는 수를 작은 수부터 차례대로 썼을 때 오른쪽에서 5번째 수를 구하시오.",
        "question_en": "Two different natural numbers, B and 36, are in a relationship of factors and multiples. B is greater than 3 and less than 150. Find the 5th number from the right when the numbers corresponding to B are written in order from smallest to smallest.",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "36 [OP_LIST_GET_DIVISOR] 36 150 1 [OP_SUB] 36 [OP_LIST_ARANGE] [OP_SET_UNION] 5 [OP_LIST_MAX]",
        "solution_abst_en": "36 [OP_LIST_GET_DIVISOR] 36 150 1 [OP_SUB] 36 [OP_LIST_ARANGE] [OP_SET_UNION] 5 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 36\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 36\nvar_c = 150\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 36\nlist_b = [i for i in range(var_b, var_e + 1, var_f)]\nlist_c = list(set(list_a) | set(list_b))\nvar_g = 5\nlist_d=list_c.copy()\nlist_d.sort()\nvar_h = list_d[-var_g]\nprint(int(var_h))",
        "solution_code_en": "var_a = 36\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 36\nvar_c = 150\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 36\nlist_b = [i for i in range(var_b, var_e + 1, var_f)]\nlist_c = list(set(list_a) | set(list_b))\nvar_g = 5\nlist_d=list_c.copy()\nlist_d.sort()\nvar_h = list_d[-var_g]\nprint(int(var_h))"
    },
    "3152": {
        "category": "Arithmetic calculation",
        "question_ko": "정연이의 하루 용돈은 300원이고 주호의 하루 용돈은 500원입니다. 정연이가 현재 가진 돈은 12000원이고 주호가 가진 돈은 4000원이라면 정연이와 주호가 가진 돈이 같아지려면 며칠이 있어야 하는 지 구하세요.",
        "question_en": "Jeongyeon's daily allowance is 300 won and Juho's daily allowance is 500 won. If Jeongyeon's current money is 12,000 won and Juho's money is 4,000 won, find how many days it will take for Jeongyeon and Juho's money to be the same.",
        "answer_ko": "40",
        "answer_en": "40",
        "solution_abst_ko": "12000 4000 [OP_SUB] 500 300 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "12000 4000 [OP_SUB] 500 300 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 12000\nvar_b = 4000\nvar_c = var_a - var_b\nvar_d = 500\nvar_e = 300\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 12000\nvar_b = 4000\nvar_c = var_a - var_b\nvar_d = 500\nvar_e = 300\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))"
    },
    "3153": {
        "category": "Correspondence",
        "question_ko": "박스 안에 파란색, 노란색, 빨간색의 구슬이 있다. 파란색 구슬의 개수를 노란색 구슬의 개수로 나누면 몫이 1.2로 나누어떨어지고, 노란색 구슬의 개수를 빨간색 구슬의 개수로 나누면 몫이 5/6으로 나누어떨어진다. 파란색 구슬의 개수를 빨간색 구슬의 개수로 나누면 그 몫은 얼마인지 구하시오.",
        "question_en": "Inside the box, there are blue, yellow and red marbles. By dividing the number of blue marbles by the number of yellow marbles, the result is 1.2, and dividing the number of yellow marbles by the number of red marbles, the result is 5/6. What is the result if you divide the number of blue marbles by the number of red marbles?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "1.2 5/6 [OP_MUL]",
        "solution_abst_en": "1.2 5/6 [OP_MUL]",
        "solution_code_ko": "var_a = 1.2\nvar_b = 0.8333333333333334\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 1.2\nvar_b = 0.8333333333333334\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "3154": {
        "category": "Correspondence",
        "question_ko": "A85-2B=364입니다. B는 얼마인가요?",
        "question_en": "What single-digit number fits B in A85-2B=364?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "A85-2B=364 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A85-2B=364 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A85-2B=364'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A85-2B=364'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "3155": {
        "category": "Comparison",
        "question_ko": "영희와 지민이는 산책을 합니다. 영희는 2킬로미터(㎞) 산책을 했고, 지민이는 1300미터(m)를 걸었습니다. 둘 중 더 긴 거리를 산책한 사람은 누구입니까?",
        "question_en": "Younghee and Jimin take a walk. Younghee walked 2 kilometers (km), and Jimin walked 1300 meters (m). Which of the two walked longer?",
        "answer_ko": "영희",
        "answer_en": "Younghee",
        "solution_abst_ko": "[OP_LIST_SOL] 영희 지민 [OP_LIST_EOL] [OP_LIST_SOL] 2 1000 [OP_MUL] 1300 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Younghee Jimin [OP_LIST_EOL] [OP_LIST_SOL] 2 1000 [OP_MUL] 1300 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '영희'\nvar_b = '지민'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 1300\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Younghee'\nvar_b = 'Jimin'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 1300\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "3156": {
        "category": "Possibility",
        "question_ko": "4개의 숫자 카드 0, 1, 4, 8을 한 번 사용하여 일의 자리 숫자가 8인 세 번째로 작은 네 자리 숫자를 구한 다음 각 숫자의 합을 구하시오",
        "question_en": "Use the four number cards 0, 1, 4, and 8 once to form the sixth smallest four-digit number which has 8 in the ones, then find the sum of numbers on each digit.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 4 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 8 [OP_LIST_SEARCH_FIXED_DIGIT] 3 [OP_LIST_MIN] [OP_NUM2LIST] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 4 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 8 [OP_LIST_SEARCH_FIXED_DIGIT] 3 [OP_LIST_MIN] [OP_NUM2LIST] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 4\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nvar_g = 8\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 3\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nlist_e = []\nvar_i = int(var_i)\nwhile var_i//10 > 0:\n    list_e.append(var_i%10)\n    var_i = var_i//10\nlist_e.append(var_i%10)\nlist_e = list_e[::-1]\nlist_e = [float(i) for i in list_e]\nvar_j = sum(list_e)\nprint(int(var_j))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 4\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nvar_g = 8\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 3\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nlist_e = []\nvar_i = int(var_i)\nwhile var_i//10 > 0:\n    list_e.append(var_i%10)\n    var_i = var_i//10\nlist_e.append(var_i%10)\nlist_e = list_e[::-1]\nlist_e = [float(i) for i in list_e]\nvar_j = sum(list_e)\nprint(int(var_j))"
    },
    "3157": {
        "category": "Arithmetic calculation",
        "question_ko": "3,000원짜리 장미 2송이와 2,800원짜리 백합 몇 송이를 사고 25,000원을 내었더니 거스름돈으로 2,200원을 받았습니다. 백합은 몇 송이를 샀는지 구하시오.",
        "question_en": "You bought two roses at \\3,000 each and some lilies at \\2,800 each, paid \\25,000 and got \\2,200 in change. Work out how many lilies you bought.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "25000 2200 [OP_SUB] 3000 2 [OP_MUL] [OP_SUB] 2800 [OP_DIV]",
        "solution_abst_en": "25000 2200 [OP_SUB] 3000 2 [OP_MUL] [OP_SUB] 2800 [OP_DIV]",
        "solution_code_ko": "var_a = 25000\nvar_b = 2200\nvar_c = var_a - var_b\nvar_d = 3000\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 2800\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 25000\nvar_b = 2200\nvar_c = var_a - var_b\nvar_d = 3000\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 2800\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "3158": {
        "category": "Correspondence",
        "question_ko": "어부가 그물에서 물고기를 잡아서 15박스에 담고 6마리가 남았다. 한 박스에 물고기가 20마리가 들어간다. 어부가 잡은 물고기는 모두 몇마리인가?",
        "question_en": "A fisherman catches fish and puts them in 15 boxes, leaving 6 fish. There are 20 fish in one box. How many fish has the fisherman caught?",
        "answer_ko": "306",
        "answer_en": "306",
        "solution_abst_ko": "15 20 [OP_MUL] 6 [OP_ADD]",
        "solution_abst_en": "15 20 [OP_MUL] 6 [OP_ADD]",
        "solution_code_ko": "var_a = 15\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3159": {
        "category": "Comparison",
        "question_ko": "1부터 9까지의 숫자카드 중 3장을 뽑아 735라는 숫자를 만들었다. 뽑은 숫자카드들 중 6보다 작은 수들의 합을 구하시오.",
        "question_en": "Three of the cards of numbers from 1 to 9 were selected to make the number 735. Add up all the numbers that are less than 6 among the selected cards of numbers.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "735 [OP_NUM2LIST] 6 [OP_LIST_LESS] [OP_LIST_SUM]",
        "solution_abst_en": "735 [OP_NUM2LIST] 6 [OP_LIST_LESS] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 735\nlist_a = []\nvar_a = int(var_a)\nwhile var_a//10 > 0:\n    list_a.append(var_a%10)\n    var_a = var_a//10\nlist_a.append(var_a%10)\nlist_a = list_a[::-1]\nvar_b = 6\nlist_b = []\nfor i in list_a:\n    if i < var_b:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_c = sum(list_b)\nprint(int(var_c))",
        "solution_code_en": "var_a = 735\nlist_a = []\nvar_a = int(var_a)\nwhile var_a//10 > 0:\n    list_a.append(var_a%10)\n    var_a = var_a//10\nlist_a.append(var_a%10)\nlist_a = list_a[::-1]\nvar_b = 6\nlist_b = []\nfor i in list_a:\n    if i < var_b:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_c = sum(list_b)\nprint(int(var_c))"
    },
    "3160": {
        "category": "Arithmetic calculation",
        "question_ko": "동물원에서 (가) 동물의 암컷 35마리를 기릅니다. 수컷이 암컷보다 7마리 많습니다. (가) 동물은 모두 몇 마리 있습니까?",
        "question_en": "The zoo keeps 35 female (a) animals. Males outnumber females by 7. How many  (a) animals are there in all?",
        "answer_ko": "77",
        "answer_en": "77",
        "solution_abst_ko": "35 35 7 [OP_ADD] [OP_ADD]",
        "solution_abst_en": "35 35 7 [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 35\nvar_b = 35\nvar_c = 7\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 35\nvar_b = 35\nvar_c = 7\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "3161": {
        "category": "Comparison",
        "question_ko": "국어 시험에서 민영이는 55점을 받았고, 유나는 57점을 받았습니다. 은지는 민영이보다 시험을 잘봤지만 유나보다는 못봤습니다. 은지의 점수는 몇 점입니까?",
        "question_en": "In the Korean test, Minyoung scored 55 points and Yuna scored 57 points. Eunji scored higher than Minyoung but lower than Yuna. If Eunji's score is a natural number, what is it?",
        "answer_ko": "56",
        "answer_en": "56",
        "solution_abst_ko": "55 57 [OP_ADD] 2 [OP_FDIV]",
        "solution_abst_en": "55 57 [OP_ADD] 2 [OP_FDIV]",
        "solution_code_ko": "var_a = 55\nvar_b = 57\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 55\nvar_b = 57\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "3162": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중에서 가장 작은 수와 그 다음으로 작은 수의 곱은 얼마입니까?",
        "question_en": "There are three numbers 10, 11, and 12. What is the value of the multiplication of the smallest number and the next smallest number?",
        "answer_ko": "110",
        "answer_en": "110",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e * var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e * var_g\nprint(int(var_h))"
    },
    "3163": {
        "category": "Arithmetic calculation",
        "question_ko": "일정한 빠르기로 3분 동안 15리터(L)의 물이 빠지는 구멍이 있습니다. 140리터(L)의 물이 다 빠지는 데 몇 분이 걸립니까?",
        "question_en": "There is a machine that produces 15 liters (l) of coke in 3 minutes at a constant rate. How many minutes does it take to get 140 liters (l) of Coke?",
        "answer_ko": "28",
        "answer_en": "28",
        "solution_abst_ko": "140 15 3 [OP_DIV] [OP_DIV]",
        "solution_abst_en": "140 15 3 [OP_DIV] [OP_DIV]",
        "solution_code_ko": "var_a = 140\nvar_b = 15\nvar_c = 3\nvar_d = var_b / var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 140\nvar_b = 15\nvar_c = 3\nvar_d = var_b / var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "3164": {
        "category": "Possibility",
        "question_ko": "네 자연수 7, 6, 2, 0을 사용하여 만들 수 있는 세 자리 수 중 각 자리의 숫자가 모두 다른 세 번째로 큰 수와 각 자리의 숫자가 모두 다른 세 번째로 작은 수의 합을 구하여라.",
        "question_en": "Of the three digit numbers that can be formed using the four natural numbers 7, 6, 2, and 0, find the sum of the third largest number with all different digits and the third smallest number with all different digits.",
        "answer_ko": "986",
        "answer_en": "986",
        "solution_abst_ko": "[OP_LIST_SOL] 7 6 2 0 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 7 6 2 0 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 7\nvar_b = 6\nvar_c = 2\nvar_d = 0\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 7\nvar_b = 6\nvar_c = 2\nvar_d = 0\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))"
    },
    "3165": {
        "category": "Possibility",
        "question_ko": "남준, 윤기, 호석, 민영이 중에서 3명을 뽑아 캐나다, 미국, 일본으로 보내려고 합니다. 보낼 수 있는 가짓수는 몇 개입니까?",
        "question_en": "You want to choose 3 people from Namjoon, Yoonki, Hoseok and Minyeong to send to Canada, the United States and Japan. What is the total number of cases you have selected three people?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "[OP_LIST_SOL] 남준 윤기 호석 민영 [OP_LIST_EOL] [OP_LIST_LEN] 3 [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] Namjoon Yoongi Hoseok Minyoung [OP_LIST_EOL] [OP_LIST_LEN] 3 [OP_PERM]",
        "solution_code_ko": "var_a = '남준'\nvar_b = '윤기'\nvar_c = '호석'\nvar_d = '민영'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 3\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nprint(int(var_g))",
        "solution_code_en": "var_a = 'Namjoon'\nvar_b = 'Yoongi'\nvar_c = 'Hoseok'\nvar_d = 'Minyoung'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 3\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nprint(int(var_g))"
    },
    "3166": {
        "category": "Possibility",
        "question_ko": "1, 2, 6 총 3장의 수 카드 중 2장을 사용하여 두 자리 수를 만들려고 합니다. 만들 수 있는 3의 배수는 모두 몇 개일까요?",
        "question_en": "We are going to use 2 of our 3 number cards 1, 2 and 6 to form a two-digit number. How many multiples of 3 can you make?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 1 2 6 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 2 6 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 2\nvar_c = 6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 3\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 2\nvar_c = 6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 3\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "3167": {
        "category": "Correspondence",
        "question_ko": "국립공원에 있는 얼룩말의 숫자는 현재 725마리이다. 올해 419마리가 새로 태어났고 263마리가 죽거나 잡아먹혔다. 작년에는 몇 마리의 얼룩말이 있었는지 구하시오.",
        "question_en": "The number of zebras in the national park is currently 725. This year, 419 were born and 263 died or were hundred. Find how many zebras there were last year.",
        "answer_ko": "569",
        "answer_en": "569",
        "solution_abst_ko": "725 419 [OP_SUB] 263 [OP_ADD]",
        "solution_abst_en": "725 419 [OP_SUB] 263 [OP_ADD]",
        "solution_code_ko": "var_a = 725\nvar_b = 419\nvar_c = var_a - var_b\nvar_d = 263\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 725\nvar_b = 419\nvar_c = var_a - var_b\nvar_d = 263\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3168": {
        "category": "Arithmetic calculation",
        "question_ko": "두철이는 일정한 빠르기로 공원을 5 바퀴 도는 데 1 시간 36 분이 걸렸습니다. 공원을 한 바퀴 도는 데 걸린 시간은 몇 분인지 소수로 나타내시오.",
        "question_en": "It took Doocheol 1 hour and 36 minutes to circle the park 5 times at a constant speed. Express as a decimal number the number of minutes it took to cycle one lap around the park.",
        "answer_ko": "19.20",
        "answer_en": "19.2",
        "solution_abst_ko": "1 60 [OP_MUL] 36 [OP_ADD] 5 [OP_DIV]",
        "solution_abst_en": "1 60 [OP_MUL] 36 [OP_ADD] 5 [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 36\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 36\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "3169": {
        "category": "Correspondence",
        "question_ko": "21에 어떤 수를 나눠야 할 것을 잘못하여 15에 어떤 수를 나눴더니 5가 되었습니다. 바르게 계산하면 얼마인지 구하시오.",
        "question_en": "I should have divided 21 by a particular number, but mistakingly divided 15 by that particular number, and as a result, I got 5. What is the correctly calculated value?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "21 15 5 [OP_DIV] [OP_DIV]",
        "solution_abst_en": "21 15 5 [OP_DIV] [OP_DIV]",
        "solution_code_ko": "var_a = 21\nvar_b = 15\nvar_c = 5\nvar_d = var_b / var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 21\nvar_b = 15\nvar_c = 5\nvar_d = var_b / var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "3170": {
        "category": "Comparison",
        "question_ko": "길이가 364 미터(m) 인 도로의 한쪽에는 은행나무를 다른 한 쪽에는 소나무를 각각 45.5 미터(m)와 22.75 미터(m) 간격으로 처음부터 끝까지 심었습니다. 소나무와 은행나무 중 어느 것을 더 많이 심었는지 구하시오.",
        "question_en": "Ginkgo trees were planted on one side of a 364 metre (m) long road and pine trees on the other side, at a distance of 45.5 and 22.75 metres from the start and end of the road respectively. Find out which of the pine and ginkgo trees was planted more.",
        "answer_ko": "소나무",
        "answer_en": "pine",
        "solution_abst_ko": "[OP_LIST_SOL] 소나무 은행나무 [OP_LIST_EOL] [OP_LIST_SOL] 364 22.75 [OP_DIV] 364 45.5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] pine ginkgo [OP_LIST_EOL] [OP_LIST_SOL] 364 22.75 [OP_DIV] 364 45.5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '소나무'\nvar_b = '은행나무'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 364\nvar_d = 22.75\nvar_e = var_c / var_d\nvar_f = 364\nvar_g = 45.5\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'pine'\nvar_b = 'ginkgo'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 364\nvar_d = 22.75\nvar_e = var_c / var_d\nvar_f = 364\nvar_g = 45.5\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "3171": {
        "category": "Comparison",
        "question_ko": "유정이는 5, 8을 모았고, 유나는 7과 9를 모았습니다. 누가 모은 수가 더 큰가요?",
        "question_en": "Yu-Jung collected 5 and 8, and Yuna collected 7 and 9. Who has the greater number?",
        "answer_ko": "유나",
        "answer_en": "Yuna",
        "solution_abst_ko": "[OP_LIST_SOL] 유정 유나 [OP_LIST_EOL] [OP_LIST_SOL] 5 8 [OP_ADD] 7 9 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yu-Jung Yuna [OP_LIST_EOL] [OP_LIST_SOL] 5 8 [OP_ADD] 7 9 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '유정'\nvar_b = '유나'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 5\nvar_d = 8\nvar_e = var_c + var_d\nvar_f = 7\nvar_g = 9\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Yu-Jung'\nvar_b = 'Yuna'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 5\nvar_d = 8\nvar_e = var_c + var_d\nvar_f = 7\nvar_g = 9\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "3172": {
        "category": "Comparison",
        "question_ko": "슈퍼마켓에는 28개의 동일한 계란 상자가 있습니다. 각 계란 상자에는 동일한 수의 계란이 있습니다. 달걀판에서 앞에서 14번째, 뒤에서 20번째, 왼쪽에서 3번째, 오른쪽에서 2번째를 선택한다면 이 마트의 달걀판에 있는 달걀의 개수를 구하세요.",
        "question_en": "There are 28 identical cartons of eggs in the supermarket. Each egg carton contains the same number of eggs. If you choose 14th from the front, 20th from the back, 3rd from the left, and 2nd from the right on the carton, find the number of eggs in the egg carton at this supermarket.",
        "answer_ko": "3696",
        "answer_en": "3696",
        "solution_abst_ko": "14 20 [OP_ADD] 1 [OP_SUB] 3 2 [OP_ADD] 1 [OP_SUB] [OP_MUL] 28 [OP_MUL]",
        "solution_abst_en": "14 20 [OP_ADD] 1 [OP_SUB] 3 2 [OP_ADD] 1 [OP_SUB] [OP_MUL] 28 [OP_MUL]",
        "solution_code_ko": "var_a = 14\nvar_b = 20\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nvar_l = 28\nvar_m = var_k * var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 14\nvar_b = 20\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nvar_l = 28\nvar_m = var_k * var_l\nprint(int(var_m))"
    },
    "3173": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 2, 3, 7, 5로 나누어 떨어질 수 있는 세 자리 수는 모두 몇 개 있습니까?",
        "question_en": "How many three-digit numbers are divisible by 2, 3, 7, and 5?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "100 999 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] 7 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "100 999 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] 7 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 3\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 7\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 5\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = len(list_e)\nprint(int(var_h))",
        "solution_code_en": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 3\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 7\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 5\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = len(list_e)\nprint(int(var_h))"
    },
    "3174": {
        "category": "Arithmetic calculation",
        "question_ko": "수영이가 등산을 하는데 올라갈 때는 시속 2 킬로미터(㎞)로 걷고, 같은 길로 내려올 때에는 시속 4 킬로미터(㎞)로 걸었더니 총 3시간이 걸렸다고 한다. 등산로의 길이를 구하시오.",
        "question_en": "It took a total of three hours for Sooyoung to walk at 2 kilometers (km) per hour when she climbed up and 4 kilometers (km) per hour when she came down the same road. Find the length of the hiking trail.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "3 2 4 [OP_GCD] [OP_MUL] 2 4 [OP_GCD] 2 [OP_DIV] 2 4 [OP_GCD] 4 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_abst_en": "3 2 4 [OP_GCD] [OP_MUL] 2 4 [OP_GCD] 2 [OP_DIV] 2 4 [OP_GCD] 4 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = 4\nvar_d = math.gcd(int(var_c), int(var_b))\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = 4\nvar_h = math.gcd(int(var_g), int(var_f))\nvar_i = 2\nvar_j = var_h / var_i\nvar_k = 2\nvar_l = 4\nvar_m = math.gcd(int(var_l), int(var_k))\nvar_n = 4\nvar_o = var_m / var_n\nvar_p = var_j + var_o\nvar_q = var_e / var_p\nprint(int(var_q))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = 4\nvar_d = math.gcd(int(var_c), int(var_b))\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = 4\nvar_h = math.gcd(int(var_g), int(var_f))\nvar_i = 2\nvar_j = var_h / var_i\nvar_k = 2\nvar_l = 4\nvar_m = math.gcd(int(var_l), int(var_k))\nvar_n = 4\nvar_o = var_m / var_n\nvar_p = var_j + var_o\nvar_q = var_e / var_p\nprint(int(var_q))"
    },
    "3175": {
        "category": "Possibility",
        "question_ko": "주어진 숫자 2, 3, 7, 8을 한 번씩 사용하여 두 번째 큰 세 자리 수를 만들 때, 사용하지 않는 숫자는 무엇입니까?",
        "question_en": "When the given numbers 2, 3, 7, and 8 are used once to form the second large three-digit number, which number is not used?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 2 3 7 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] [OP_LIST_POP] [OP_NUM2LIST] [OP_SET_DIFFERENCE] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] 2 3 7 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] [OP_LIST_POP] [OP_NUM2LIST] [OP_SET_DIFFERENCE] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = 7\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nlist_d = []\nvar_g = int(var_g)\nwhile var_g//10 > 0:\n    list_d.append(var_g%10)\n    var_g = var_g//10\nlist_d.append(var_g%10)\nlist_d = list_d[::-1]\nlist_e = list(set(list_a) - set(list_d))\nvar_h = 1\nvar_i = list_e[var_h-1]\nprint(int(var_i))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = 7\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nlist_d = []\nvar_g = int(var_g)\nwhile var_g//10 > 0:\n    list_d.append(var_g%10)\n    var_g = var_g//10\nlist_d.append(var_g%10)\nlist_d = list_d[::-1]\nlist_e = list(set(list_a) - set(list_d))\nvar_h = 1\nvar_i = list_e[var_h-1]\nprint(int(var_i))"
    },
    "3176": {
        "category": "Comparison",
        "question_ko": "달리기 시합에서 남준, 윤기, 호석이가 차례대로 결승선을 넘었습니다. 남준이는 10등을 했고, 호석이는 12등을 했습니다. 윤기는 몇 등입니까?",
        "question_en": "In the race, Namjoon, Yoongi, and Hoseok crossed the finish line in that order. Namjoon placed 10th, and Hoseok placed 12th. What is Yoongi's rank?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "10 12 [OP_ADD] 2 [OP_FDIV]",
        "solution_abst_en": "10 12 [OP_ADD] 2 [OP_FDIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "3177": {
        "category": "Comparison",
        "question_ko": "윤기는 4개의 사과를 가지고 있고 6개의 사과를 가지고 있던 정국이는 3개의 사과를 더 받았습니다. 유나는 5개의 사과를 가지고 있을 때, 누가 가장 사과를 많이 가지고 있습니까?",
        "question_en": "Yoongi has 4 apples and Jungkook who had 6 apples got 3 more. When Yuna has 5 apples, who has the most apples?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 유나 [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_ADD] 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook Yuna [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_ADD] 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nvar_c = '유나'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 6\nvar_f = 3\nvar_g = var_e + var_f\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nvar_c = 'Yuna'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 6\nvar_f = 3\nvar_g = var_e + var_f\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "3178": {
        "category": "Possibility",
        "question_ko": "사과, 복숭아, 배를 판매하는 과일가게에서 중복을 허락하여 2개의 과일을 구매하려고 합니다. 가능한 경우의 수는 몇 가지 일까요?",
        "question_en": "At a fruit store that sells apples, peaches, and pears, you want to purchase two fruits by allowing duplicates. How many possible cases are there?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 복숭아 배 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] apples peaches pears [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '복숭아'\nvar_c = '배'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = var_d + var_e\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = 2\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j / (i+1)\nprint(int(var_j))",
        "solution_code_en": "var_a = 'apples'\nvar_b = 'peaches'\nvar_c = 'pears'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = var_d + var_e\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = 2\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j / (i+1)\nprint(int(var_j))"
    },
    "3179": {
        "category": "Correspondence",
        "question_ko": "172를 4로 나누어야 할 것을 잘못하여 어떤 수로 나누었더니 그 몫은 바르게 계산한 몫보다 28 작고 나머지가 7이었습니다. 어떤 수를 구하시오.",
        "question_en": "I made a mistake of dividing 172 by a certain number when I had to divide by 4, and the resulting quotient was 28 less than the correctly calculated quotient, and the remainder was 7. Find this certain number.",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "172 7 [OP_SUB] 172 4 [OP_DIV] 28 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "172 7 [OP_SUB] 172 4 [OP_DIV] 28 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 172\nvar_b = 7\nvar_c = var_a - var_b\nvar_d = 172\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = 28\nvar_h = var_f - var_g\nvar_i = var_c / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 172\nvar_b = 7\nvar_c = var_a - var_b\nvar_d = 172\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = 28\nvar_h = var_f - var_g\nvar_i = var_c / var_h\nprint(int(var_i))"
    },
    "3180": {
        "category": "Possibility",
        "question_ko": "십의 자리 숫자와 일의 자리 숫자가 다른 100이하의 수 중 0, 1, 7, 9로 이루어진 수는 모두 몇 개인가?",
        "question_en": "How many numbers not more than 100 whose number at tens place and ones place is different have 0, 1, 7, and 9?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 7 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 7 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 7\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 7\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "3181": {
        "category": "Comparison",
        "question_ko": "백의 자리 숫자는 2이고 십의 자리 숫자는 5입니다. 이를 만족하는 세 자리 수중 256보다 큰 수는 몇 개입니까?",
        "question_en": "The hundreds digit is 2, and the tens digit is 5. How many numbers satisfy the condition of three-digit numbers greater than 256?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 2 5 A [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 256 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 2 5 A [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 256 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 2\nvar_b = 5\nvar_c = 'A'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nans_dict = dict()\nvar_d = str(var_d)\nlist_b = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_d) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_b.append(new_elem)\nvar_e = 256\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 2\nvar_b = 5\nvar_c = 'A'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nans_dict = dict()\nvar_d = str(var_d)\nlist_b = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_d) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_b.append(new_elem)\nvar_e = 256\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "3182": {
        "category": "Geometry",
        "question_ko": "삼각형 모양의 종이를 반으로 접었을 때의 넓이가 제곱센티미터(㎠)일 때, 전체 종이의 넓이는 얼마인지 구하시오.",
        "question_en": "If the area of a triangular piece of paper folded in half is 7 square centimeter (cm2), what is the total area of the paper?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "7 2 [OP_MUL]",
        "solution_abst_en": "7 2 [OP_MUL]",
        "solution_code_ko": "var_a = 7\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 7\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "3183": {
        "category": "Comparison",
        "question_ko": "확률을 계산하려고 합니다. 숫자 카드 1, 3, 4, 6, 7, 9 중에서 한 장의 카드를 뽑을 때 9 이하의 수가 적힌 카드가 뽑힐 확률은?",
        "question_en": "I'm trying to calculate probabilities. What is the probability of drawing a card with a number less than or equal to 9 when drawing one from the number cards 1, 3, 4, 6, 7, and 9?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 4 6 7 9 [OP_LIST_EOL] 9 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN] [OP_LIST_SOL] 1 3 4 6 7 9 [OP_LIST_EOL] [OP_LIST_LEN] [OP_DIV]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 4 6 7 9 [OP_LIST_EOL] 9 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN] [OP_LIST_SOL] 1 3 4 6 7 9 [OP_LIST_EOL] [OP_LIST_LEN] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 4\nvar_d = 6\nvar_e = 7\nvar_f = 9\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 9\nlist_b = []\nfor i in list_a:\n    if i <= var_g:\n        list_b.append(i)\nvar_h = len(list_b)\nvar_i = 1\nvar_j = 3\nvar_k = 4\nvar_l = 6\nvar_m = 7\nvar_n = 9\nlist_c= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_c.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_c.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_c.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_c.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_c.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_c.append(var_i)\nlist_c.reverse()\nvar_o = len(list_c)\nvar_p = var_h / var_o\nprint(int(var_p))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 4\nvar_d = 6\nvar_e = 7\nvar_f = 9\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 9\nlist_b = []\nfor i in list_a:\n    if i <= var_g:\n        list_b.append(i)\nvar_h = len(list_b)\nvar_i = 1\nvar_j = 3\nvar_k = 4\nvar_l = 6\nvar_m = 7\nvar_n = 9\nlist_c= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_c.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_c.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_c.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_c.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_c.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_c.append(var_i)\nlist_c.reverse()\nvar_o = len(list_c)\nvar_p = var_h / var_o\nprint(int(var_p))"
    },
    "3184": {
        "category": "Possibility",
        "question_ko": "각기 다른 구슬 3개가 있습니다. 이 중 2개를 골라 같은 모양의 상자에 1개씩 넣는 경우의 수를 구하시오.",
        "question_en": "There are 3 different colored marbles. One is red, one is blue, one is yellow. Find the number of ways to choose two of these and put each of them in each of the boxes of the same shape.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 빨간색 파란색 노란색 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] red blue yellow [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '빨간색'\nvar_b = '파란색'\nvar_c = '노란색'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f / (i+1)\nprint(int(var_f))",
        "solution_code_en": "var_a = 'red'\nvar_b = 'blue'\nvar_c = 'yellow'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f / (i+1)\nprint(int(var_f))"
    },
    "3185": {
        "category": "Correspondence",
        "question_ko": "AB+31=54이 성립합니다. B는 무엇인가요?",
        "question_en": "AB+31=54. What is B?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "AB+31=54 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "AB+31=54 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'AB+31=54'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'AB+31=54'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "3186": {
        "category": "Possibility",
        "question_ko": "0, 1, 2, 3을 중복해서 사용하여 네자리 수를 만들때 각 자리숫자의 합이 10이 되는 경우의 수는 몇 가지인가?",
        "question_en": "How many ways can the sum of the digits be 10 when 0, 1, 2, and 3 are used repeatedly to form a four-digit number?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PRODUCT] [OP_LIST_NUM2SUM] 10 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PRODUCT] [OP_LIST_NUM2SUM] 10 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_f = 0\n    i = int(i)\n    while i//10 > 0:\n        var_f = var_f + i%10\n        i = i//10\n    var_f = var_f + i%10\n    list_c.append(var_f)\nvar_g = 10\nvar_h = 0\nvar_g = int(var_g)\nfor i in list_c:\n    i = int(i)\n    if i == var_g:\n        var_h = var_h + 1\nprint(int(var_h))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_f = 0\n    i = int(i)\n    while i//10 > 0:\n        var_f = var_f + i%10\n        i = i//10\n    var_f = var_f + i%10\n    list_c.append(var_f)\nvar_g = 10\nvar_h = 0\nvar_g = int(var_g)\nfor i in list_c:\n    i = int(i)\n    if i == var_g:\n        var_h = var_h + 1\nprint(int(var_h))"
    },
    "3187": {
        "category": "Arithmetic calculation",
        "question_ko": "귤과 감을 합하여 88킬로그램(㎏)을 샀습니다. 귤의 무게가 감의 무게보다 4킬로그램(㎏)이 더 무겁습니다. 감은 모두 몇 킬로그램(㎏)인지 구하세요.",
        "question_en": "I bought 88 kilograms (kg) of tangerines and persimmons. The weight of a tangerine is 4 kg (kg) heavier than that of a persimmon. Find how many kilograms (kg) are all persimmons.",
        "answer_ko": "42",
        "answer_en": "42",
        "solution_abst_ko": "88 4 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "88 4 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 88\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 88\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "3188": {
        "category": "Arithmetic calculation",
        "question_ko": "강의 다리 위에 가로등이 50미터(m) 간격으로 세워져 있습니다. 다리의 총 길이는 1650미터(m)이고, 다리의 처음과 끝에도 가로등이 세워져 있을 때, 다리의 양쪽에 세워진 가로등의 수는 모두 몇 개입니까?",
        "question_en": "On a bridge over a river, there are street lights every 50 meters (m). If the total length of the bridge is 1650 meters (m) and there are also streetlights at the beginning and end of the bridge, what is the total number of streetlights on each side of the bridge?",
        "answer_ko": "68",
        "answer_en": "68",
        "solution_abst_ko": "1650 50 [OP_DIV] 1 [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "1650 50 [OP_DIV] 1 [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 1650\nvar_b = 50\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1650\nvar_b = 50\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "3189": {
        "category": "Geometry",
        "question_ko": "십각형의 한 꼭짓점에서 그을 수 있는 대각선의 개수를 구하시오.",
        "question_en": "Find the number of diagonals that can be drawn from one vertex of the decagon.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "10 3 [OP_SUB]",
        "solution_abst_en": "10 3 [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 10\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "3190": {
        "category": "Geometry",
        "question_ko": "한 모서리의 길이가 4센티미터(㎝)인 정육면체가 있다. 이 정육면체의 세로와 높이의 길이를 6센티미터(㎝) 늘리고, 높이를 5센티미터 추가로 늘려서 직육면체를 만들었다고 하자. 이렇게 만들어진 도형의 겉넓이는 몇인가?",
        "question_en": "There is a cube with one edge 4 centimeters (cm) long. Suppose that the length and height of this cube are increased by 6 centimeters (cm), and the height is increased by an additional 5 centimeters (cm) to make a cuboid. What is the surface area of this shape? ",
        "answer_ko": "600",
        "answer_en": "600",
        "solution_abst_ko": "4 4 6 [OP_ADD] [OP_MUL] 4 6 [OP_ADD] 5 [OP_ADD] [OP_MUL]",
        "solution_abst_en": "4 4 6 [OP_ADD] [OP_MUL] 4 6 [OP_ADD] 5 [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 4\nvar_b = 4\nvar_c = 6\nvar_d = var_b + var_c\nvar_e = var_a * var_d\nvar_f = 4\nvar_g = 6\nvar_h = var_f + var_g\nvar_i = 5\nvar_j = var_h + var_i\nvar_k = var_e * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 4\nvar_b = 4\nvar_c = 6\nvar_d = var_b + var_c\nvar_e = var_a * var_d\nvar_f = 4\nvar_g = 6\nvar_h = var_f + var_g\nvar_i = 5\nvar_j = var_h + var_i\nvar_k = var_e * var_j\nprint(int(var_k))"
    },
    "3191": {
        "category": "Correspondence",
        "question_ko": "166.08을 4로 두 번 나누었을 때 나오는 값을 구하시오.",
        "question_en": "Find the value when 166.08 is divided by 4 twice.",
        "answer_ko": "10.38",
        "answer_en": "10.38",
        "solution_abst_ko": "166.08 4 [OP_DIV] 4 [OP_DIV]",
        "solution_abst_en": "166.08 4 [OP_DIV] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 166.08\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 166.08\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "3192": {
        "category": "Comparison",
        "question_ko": "공원에 사람들이 체조를 하기 위해 8명씩 4줄을 설 때, 공원에 체조를 하고 있는 사람은 모두 몇 명인지 구하시오.",
        "question_en": "When people in the park form 4 lines of 8 people to do gymnastics, find how many people are doing gymnastics in the park in total.",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "8 4 [OP_MUL]",
        "solution_abst_en": "8 4 [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 8\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "3193": {
        "category": "Geometry",
        "question_ko": "둘레가 52센티미터(㎝)인 사각형 중 넓이가 가장 큰 사각형의 넓이는 얼마입니까?",
        "question_en": "What is the area of the largest rectangle with a perimeter of 52 centimeters (cm)?",
        "answer_ko": "169",
        "answer_en": "169",
        "solution_abst_ko": "52 4 [OP_DIV] 2 [OP_POW]",
        "solution_abst_en": "52 4 [OP_DIV] 2 [OP_POW]",
        "solution_code_ko": "var_a = 52\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 52\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint(int(var_e))"
    },
    "3194": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중에서 가장 큰 수와 가장 작은 수의 곱은 얼마입니까?",
        "question_en": "There are three numbers 10, 11, and 12. What is the value of the multiplication of the largest number and the smallest number?",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e * var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e * var_g\nprint(int(var_h))"
    },
    "3195": {
        "category": "Comparison",
        "question_ko": "5, 8, 4, 3, 2 중에서 2번째로 작은 수를 고르세요.",
        "question_en": "Choose the 2nd smallest number among 5, 8, 4, 3, and 2.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 5 8 4 3 2 [OP_LIST_EOL] 2 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 5 8 4 3 2 [OP_LIST_EOL] 2 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 5\nvar_b = 8\nvar_c = 4\nvar_d = 3\nvar_e = 2\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 8\nvar_c = 4\nvar_d = 3\nvar_e = 2\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nprint(int(var_g))"
    },
    "3196": {
        "category": "Arithmetic calculation",
        "question_ko": "리본 한 개를 만들기 위해 리본 테이프 0.84미터(m)를 사용합니다. 유진이가 가지고 있는 리본 테이프로 리본을 10개 만들었더니 50센티미터(㎝)가 남았다면, 유진이가 처음에 가지고 있던 리본 테이프의 길이는 몇 미터(m)일지 구하시오.",
        "question_en": "It takes 0.84 meters (m) of ribbon tape to make one ribbon. If 50 centimeters (cm) remain after making 10 ribbons with the ribbon tape that Yujin has, find the length in meters (m) of the ribbon tape that Yujin had at first.",
        "answer_ko": "8.90",
        "answer_en": "8.9",
        "solution_abst_ko": "0.84 10 [OP_MUL] 50 100 [OP_DIV] [OP_ADD]",
        "solution_abst_en": "0.84 10 [OP_MUL] 50 100 [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 0.84\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 50\nvar_e = 100\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 0.84\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 50\nvar_e = 100\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "3197": {
        "category": "Comparison",
        "question_ko": "윤철이는 기말고사에서 국어 80점, 수학 94점, 사회 82점, 영어 76점, 과학 100점을 받았습니다. 80점보다 점수가 낮은 과목은 몇 과목입니까?",
        "question_en": "In the final exam, Yooncheol scored 80 in Korean, 94 in Mathematics, 82 in Social studies, 76 in English, and 100 in Science. How many subjects did he score less than 80?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 80 94 82 76 100 [OP_LIST_EOL] 80 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 80 94 82 76 100 [OP_LIST_EOL] 80 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 80\nvar_b = 94\nvar_c = 82\nvar_d = 76\nvar_e = 100\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 80\nlist_b = []\nfor i in list_a:\n    if i < var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 80\nvar_b = 94\nvar_c = 82\nvar_d = 76\nvar_e = 100\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 80\nlist_b = []\nfor i in list_a:\n    if i < var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "3198": {
        "category": "Arithmetic calculation",
        "question_ko": "국어, 영어, 과학의 평균 점수는 95점이고 수학 점수를 포함하면 평균 점수가 3점 떨어진다. 수학 점수는 몇 점인가?",
        "question_en": "The average score for Korean, English, and science is 95 points, and if math scores are included, the average score falls by 3 points. What is math score?",
        "answer_ko": "83",
        "answer_en": "83",
        "solution_abst_ko": "95 3 [OP_SUB] 4 [OP_MUL] 95 3 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "95 3 [OP_SUB] 4 [OP_MUL] 95 3 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 95\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c * var_d\nvar_f = 95\nvar_g = 3\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 95\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c * var_d\nvar_f = 95\nvar_g = 3\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nprint(int(var_i))"
    },
    "3199": {
        "category": "Correspondence",
        "question_ko": "32×A×A×A=B×4를 만족하는 가장 큰 A 값과 가장 큰 B의 값의 합을 구하시오",
        "question_en": "Find the sum of the largest value of A and the largest value of B that satisfies 32×A×A×A=B×4",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "32×A×A×A=B×4 A [OP_NUM_UNK_SOLVER] 1 [OP_LIST_MAX] 32×A×A×A=B×4 B [OP_NUM_UNK_SOLVER] 1 [OP_LIST_MAX] [OP_ADD]",
        "solution_abst_en": "32×A×A×A=B×4 A [OP_NUM_UNK_SOLVER] 1 [OP_LIST_MAX] 32×A×A×A=B×4 B [OP_NUM_UNK_SOLVER] 1 [OP_LIST_MAX] [OP_ADD]",
        "solution_code_ko": "var_a = '32×A×A×A=B×4'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[-var_c]\nvar_e = '32×A×A×A=B×4'\nvar_f = 'B'\nans_dict = dict()\nvar_e = var_e.replace('×','*')\nvar_e = var_e.replace('x','*')\nvar_e = var_e.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_e):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_e\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k].append(int(c[i]))\nlist_c = list(set(ans_dict[var_f]))\nvar_g = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_h = list_d[-var_g]\nvar_i = var_d + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = '32×A×A×A=B×4'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[-var_c]\nvar_e = '32×A×A×A=B×4'\nvar_f = 'B'\nans_dict = dict()\nvar_e = var_e.replace('×','*')\nvar_e = var_e.replace('x','*')\nvar_e = var_e.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_e):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_e\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k].append(int(c[i]))\nlist_c = list(set(ans_dict[var_f]))\nvar_g = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_h = list_d[-var_g]\nvar_i = var_d + var_h\nprint(int(var_i))"
    },
    "3200": {
        "category": "Comparison",
        "question_ko": "유정, 은지는 각각 17층, 25층 아파트에 산다. 더 높은 층에는 누가 사는가?",
        "question_en": "Yujeong and Eunji live on the 17th and 25th floor of the apartment, respectively. Who lives on the higher floor?",
        "answer_ko": "은지",
        "answer_en": "Eunji",
        "solution_abst_ko": "[OP_LIST_SOL] 유정 은지 [OP_LIST_EOL] [OP_LIST_SOL] 17 25 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yujeong Eunji [OP_LIST_EOL] [OP_LIST_SOL] 17 25 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '유정'\nvar_b = '은지'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 17\nvar_d = 25\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Yujeong'\nvar_b = 'Eunji'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 17\nvar_d = 25\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "3201": {
        "category": "Correspondence",
        "question_ko": "20에 어떤 수를 곱하려고 합니다. 잘못하여 40에 어떤 수를 뺐더니 결과는 52가 되었습니다. 바르게 계산한 결과는 얼마일까요?",
        "question_en": "You want to multiply 20 by some number. you mistakenly subtracted some number from 40, and the result was 52. What is the correct calculation result?",
        "answer_ko": "-240",
        "answer_en": "-240",
        "solution_abst_ko": "20 40 52 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "20 40 52 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 20\nvar_b = 40\nvar_c = 52\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 40\nvar_c = 52\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nprint(int(var_e))"
    },
    "3202": {
        "category": "Correspondence",
        "question_ko": "세 자리수 A27을 백의 자리에서 버림하면 200이 됩니다. A를 구하시오.",
        "question_en": "Rounding down the three-digit number A27 to the nearest hundred gives 200. Get a single-digit number A.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "A27 [OP_GEN_POSSIBLE_LIST] 200 [OP_LIST_MORE_EQUAL] 200 100 [OP_ADD] [OP_LIST_LESS] A [OP_LIST_FIND_UNK]",
        "solution_abst_en": "A27 [OP_GEN_POSSIBLE_LIST] 200 [OP_LIST_MORE_EQUAL] 200 100 [OP_ADD] [OP_LIST_LESS] A [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = 'A27'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 200\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 200\nvar_d = 100\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = 'A'\nvar_a = str(var_a)\nvar_f = str(var_f)\nunk_idx = var_a.index(var_f)\nvar_g = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_g = int(elem[unk_idx])\nprint(int(var_g))",
        "solution_code_en": "var_a = 'A27'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 200\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 200\nvar_d = 100\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = 'A'\nvar_a = str(var_a)\nvar_f = str(var_f)\nunk_idx = var_a.index(var_f)\nvar_g = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_g = int(elem[unk_idx])\nprint(int(var_g))"
    },
    "3203": {
        "category": "Arithmetic calculation",
        "question_ko": "농도가 25%인 소금물 200그램(g)과 소금이 60그램(g) 녹아있는 소금물 300그램(g)을 섞으면 소금물의 농도는 얼마입니까?",
        "question_en": "If you mix 200 grams (g) of salt water with a concentration of 25% and 300 grams (g) of salt water in which 60 grams (g) of salt are dissolved, what is the concentration of the salt water?",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "200 25 100 [OP_DIV] [OP_MUL] 60 [OP_ADD] 200 300 [OP_ADD] [OP_DIV] 100 [OP_MUL]",
        "solution_abst_en": "200 25 100 [OP_DIV] [OP_MUL] 60 [OP_ADD] 200 300 [OP_ADD] [OP_DIV] 100 [OP_MUL]",
        "solution_code_ko": "var_a = 200\nvar_b = 25\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 60\nvar_g = var_e + var_f\nvar_h = 200\nvar_i = 300\nvar_j = var_h + var_i\nvar_k = var_g / var_j\nvar_l = 100\nvar_m = var_k * var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 200\nvar_b = 25\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 60\nvar_g = var_e + var_f\nvar_h = 200\nvar_i = 300\nvar_j = var_h + var_i\nvar_k = var_g / var_j\nvar_l = 100\nvar_m = var_k * var_l\nprint(int(var_m))"
    },
    "3204": {
        "category": "Geometry",
        "question_ko": "넓이가 28/3제곱센티미터(㎠)이고, 세로가 14/5센티미터(㎝)인 직사각형의 가로는 몇 센티미터(㎝)입니까?",
        "question_en": "How many centimeters (cm) is the width of a rectangle whose area is 28/3 square centimeter (cm2) and its length is 14/5 centimeters (cm)?",
        "answer_ko": "3.33",
        "answer_en": "3.33",
        "solution_abst_ko": "28/3 14/5 [OP_DIV]",
        "solution_abst_en": "28/3 14/5 [OP_DIV]",
        "solution_code_ko": "var_a = 9.333333333333334\nvar_b = 2.8\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 9.333333333333334\nvar_b = 2.8\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "3205": {
        "category": "Possibility",
        "question_ko": "100이하인 홀수이면서 3의 배수인 수를 모두 종이에 적으면, 숫자 1을 몇 번 적어야 하는지 구하시오.",
        "question_en": "If you write down all odd numbers that are less than 100 and that are multiples of 3 on a piece of paper, how many times do you have to write the number 1?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "1 100 [OP_LIST_ODD] 3 [OP_LIST_DIVISIBLE] [OP_LIST2NUM] [OP_NUM2LIST] 1 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 100 [OP_LIST_ODD] 3 [OP_LIST_DIVISIBLE] [OP_LIST2NUM] [OP_NUM2LIST] 1 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 100\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 3\nlist_b = []\nvar_c = int(var_c)\nfor i in list_a:\n    i = int(i)\n    if i % var_c == 0:\n        list_b.append(i)\nvar_d=\"\"\nfor i in list_b:\n    i = str(i)\n    var_d = var_d + i\nlist_c = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_c.append(var_d%10)\n    var_d = var_d//10\nlist_c.append(var_d%10)\nlist_c = list_c[::-1]\nvar_e = 1\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_c:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 100\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 3\nlist_b = []\nvar_c = int(var_c)\nfor i in list_a:\n    i = int(i)\n    if i % var_c == 0:\n        list_b.append(i)\nvar_d=\"\"\nfor i in list_b:\n    i = str(i)\n    var_d = var_d + i\nlist_c = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_c.append(var_d%10)\n    var_d = var_d//10\nlist_c.append(var_d%10)\nlist_c = list_c[::-1]\nvar_e = 1\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_c:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))"
    },
    "3206": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 125까지 수를 쓸 때, 숫자 2는 모두 몇 번 쓰는지 구하시오.",
        "question_en": "When writing the numbers from 1 to 125, find how many times the number 2 is written.",
        "answer_ko": "29",
        "answer_en": "29",
        "solution_abst_ko": "1 125 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 2 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 125 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 2 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 125\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 2\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 125\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 2\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))"
    },
    "3207": {
        "category": "Correspondence",
        "question_ko": "8은 어떤 수에서 실수로 12를 더한 뒤 8로 나눈 결과입니다. 본래 하려던 계산은 12를 빼고 9를 곱하는 것이었다면, 바르게 계산한 값은 얼마입니까?",
        "question_en": "8 is the result of accidentally adding 12 to a certain number and then dividing by 8. If the original calculation was to subtract 12 and multiply by 9, what is the correct value?",
        "answer_ko": "360",
        "answer_en": "360",
        "solution_abst_ko": "8 8 [OP_MUL] 12 [OP_SUB] 12 [OP_SUB] 9 [OP_MUL]",
        "solution_abst_en": "8 8 [OP_MUL] 12 [OP_SUB] 12 [OP_SUB] 9 [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = var_c - var_d\nvar_f = 12\nvar_g = var_e - var_f\nvar_h = 9\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 8\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = var_c - var_d\nvar_f = 12\nvar_g = var_e - var_f\nvar_h = 9\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "3208": {
        "category": "Comparison",
        "question_ko": "1.4, 9/10, 1.2, 0.5, 13/10에서 1.1보다 큰 숫자를 나열한뒤, 가장 작은 숫자를 구하면 얼마입니까?",
        "question_en": "What is the smallest number in 1.4, 9/10, 1.2, 0.5, and 13/10 after listing the numbers greater than 1.1?",
        "answer_ko": "1.20",
        "answer_en": "1.2",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nprint('{:.2f}'.format(round(var_h+1e-10,2)))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nprint('{:.2f}'.format(round(var_h+1e-10,2)))"
    },
    "3209": {
        "category": "Possibility",
        "question_ko": "A, B, C, D, E 5명이 있을 때, 대표 1명과 부대표2명을 뽑는 경우의 수를 구하시오.",
        "question_en": "If there are 5 members A, B, C, D, and E, find the number of cases in which one representative and two deputies are selected.",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "5 1 [OP_PERM] 5 1 [OP_SUB] 2 [OP_COMB] [OP_ADD]",
        "solution_abst_en": "5 1 [OP_PERM] 5 1 [OP_SUB] 2 [OP_COMB] [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 1\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nvar_d = 5\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 2\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h / (i+1)\nvar_i = var_c + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 5\nvar_b = 1\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nvar_d = 5\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 2\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h / (i+1)\nvar_i = var_c + var_h\nprint(int(var_i))"
    },
    "3210": {
        "category": "Arithmetic calculation",
        "question_ko": "지민이는 공책 33권을 가지고 있었습니다. 아버지가 공책 7권을 더 사주고 어머니가 14권을 더 사주었습니다. 지민이가 가진 공책은 처음보다 몇 권 더 많아졌습니까?",
        "question_en": "Jimin had 33 notebooks. My father bought 7 more notebooks and my mother bought 14 more. How many more notebooks does Jimin have than at first?",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "33 7 [OP_ADD] 14 [OP_ADD] 33 [OP_SUB]",
        "solution_abst_en": "33 7 [OP_ADD] 14 [OP_ADD] 33 [OP_SUB]",
        "solution_code_ko": "var_a = 33\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 14\nvar_e = var_c + var_d\nvar_f = 33\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 33\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 14\nvar_e = var_c + var_d\nvar_f = 33\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "3211": {
        "category": "Geometry",
        "question_ko": "5.9센티미터(㎝), 3센티미터(㎝)는 직사각형의 두 변의 길이입니다. 이 직사각형의 넓이를 구하시오.",
        "question_en": "5.9 centimeters (cm) and 3 centimeters (cm) are the lengths of the two sides of the rectangle. Find the area of this rectangle.",
        "answer_ko": "17.70",
        "answer_en": "17.7",
        "solution_abst_ko": "5.9 3 [OP_MUL]",
        "solution_abst_en": "5.9 3 [OP_MUL]",
        "solution_code_ko": "var_a = 5.9\nvar_b = 3\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 5.9\nvar_b = 3\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "3212": {
        "category": "Correspondence",
        "question_ko": "파란 상자와 빨간 상자에 공이 담겨있다. 빨간 상자의 공을 파란 상자로 152개 옮겼더니 빨간 상자 안의 공의 개수가 파란 상자의 공의 개수 보다 346개 많다고 한다. 공을 옮기기 전에는 두 상자의 공의 개수 차이가 몇 개인지 구하시오.",
        "question_en": "The blue box and the red box contain balls. After moving 152 balls from the red box to the blue box, the number of balls in the red box is 346 more than the number of balls in the blue box. Find the difference between the number of balls in the two boxes before moving the balls.",
        "answer_ko": "650",
        "answer_en": "650",
        "solution_abst_ko": "346 152 [OP_ADD] 152 [OP_ADD]",
        "solution_abst_en": "346 152 [OP_ADD] 152 [OP_ADD]",
        "solution_code_ko": "var_a = 346\nvar_b = 152\nvar_c = var_a + var_b\nvar_d = 152\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 346\nvar_b = 152\nvar_c = var_a + var_b\nvar_d = 152\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3213": {
        "category": "Arithmetic calculation",
        "question_ko": "20미터(m) 길이의 현수막이 있다. 이 현수막을 못으로 고정시킬 생각이다. 현수막 양쪽 끝에서부터 1미터(m) 띄워서 못을 박고 사이에 일정한 간격으로 못을 박았더니 총 7개의 못을 사용하였다. 못과 못 사이의 간격을 구하시오.",
        "question_en": "There is a banner 20 meters (m) long. I'm thinking of fixating this banner with nails. Nails were driven 1 meter (m) apart from both ends of the banner, and the remaining nails were nailed in at regular intervals. A total of 7 nails were used. Find the distance between one nail and another.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "20 1 2 [OP_MUL] [OP_SUB] 7 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "20 1 2 [OP_MUL] [OP_SUB] 7 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 20\nvar_b = 1\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 7\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 20\nvar_b = 1\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 7\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "3214": {
        "category": "Correspondence",
        "question_ko": "서로 다른 두 수 A, B가 있습니다. 덧셈식 AB+640=BBB에서 A와 B의 합을 구하시오.",
        "question_en": "There are two different single-digit numbers A and B. Find the sum of A and B that satisfies the following addition formula AB+640=BBB.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "AB+640=BBB A [OP_DIGIT_UNK_SOLVER] AB+640=BBB B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_abst_en": "AB+640=BBB A [OP_DIGIT_UNK_SOLVER] AB+640=BBB B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_code_ko": "var_a = 'AB+640=BBB'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 'AB+640=BBB'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 'AB+640=BBB'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 'AB+640=BBB'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "3215": {
        "category": "Comparison",
        "question_ko": "민영이보다 수호의 키가 크고 민영이보다 성주의 키가 작습니다. 선미는 성주보다 키가 작습니다. 가장 키가 작은 사람은 누구인지 쓰시오.",
        "question_en": "Suho is taller than Minyoung, and Seongju is shorter than Minyoung. Seonmi is shorter than Seongju. Write down the shortest person.",
        "answer_ko": "선미",
        "answer_en": "Seonmi",
        "solution_abst_ko": "[OP_LIST_SOL] 수호 민영 성주 선미 [OP_LIST_EOL] [OP_LIST_SOL] 수호 민영 > 성주 민영 < 성주 선미 > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Suho Minyoung Seongju Seonmi [OP_LIST_EOL] [OP_LIST_SOL] Suho Minyoung > Seongju Minyoung < Seongju Seonmi > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '수호'\nvar_b = '민영'\nvar_c = '성주'\nvar_d = '선미'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '수호'\nvar_f = '민영'\nvar_g = '>'\nvar_h = '성주'\nvar_i = '민영'\nvar_j = '<'\nvar_k = '성주'\nvar_l = '선미'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)",
        "solution_code_en": "var_a = 'Suho'\nvar_b = 'Minyoung'\nvar_c = 'Seongju'\nvar_d = 'Seonmi'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'Suho'\nvar_f = 'Minyoung'\nvar_g = '>'\nvar_h = 'Seongju'\nvar_i = 'Minyoung'\nvar_j = '<'\nvar_k = 'Seongju'\nvar_l = 'Seonmi'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)"
    },
    "3216": {
        "category": "Possibility",
        "question_ko": "6개의 프로 야구팀이 서로 한 번씩 시합을 가진다면 모두 몇 번의 시합이 이루어지는지 모두 구하시오",
        "question_en": "If 6 professional baseball teams play with each other once, how many matches will there be in total?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "6 2 [OP_COMB]",
        "solution_abst_en": "6 2 [OP_COMB]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))"
    },
    "3217": {
        "category": "Comparison",
        "question_ko": "20명의 학생들의 키를 비교하고 있습니다. 윤기보다 작은 학생이 11명일 때, 윤기보다 큰 학생은 모두 몇 명입니까?",
        "question_en": "You are comparing the heights of 20 students. If there are 11 students taller than Yoongi, how many students are shorter than Yoongi?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "20 11 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "20 11 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3218": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 12를 더하고 27을 뺐더니 24가 되었습니다. 어떤 수를 구하시오.",
        "question_en": "If you add 12 to a number and subtract 27, you get 24. Find the number.",
        "answer_ko": "39",
        "answer_en": "39",
        "solution_abst_ko": "24 27 [OP_ADD] 12 [OP_SUB]",
        "solution_abst_en": "24 27 [OP_ADD] 12 [OP_SUB]",
        "solution_code_ko": "var_a = 24\nvar_b = 27\nvar_c = var_a + var_b\nvar_d = 12\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 24\nvar_b = 27\nvar_c = var_a + var_b\nvar_d = 12\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3219": {
        "category": "Possibility",
        "question_ko": "10원, 50원, 100원 짜리 동전이 각각 한 개씩 있고, 3개의 동전을 동시에 던졌다고 할 때 나오는 경우의 수를 구하시오. (단, 동전은 던져서 앞면 또는 뒷면이 나온다.)",
        "question_en": "If there are 10, 50, and 100 won coins, and three coins are thrown at the same time, find the number of possible outcomes. (However, when a coin is thrown, it comes out either heads or tails.)",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "2 3 [OP_POW]",
        "solution_abst_en": "2 3 [OP_POW]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = var_a ** var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = var_a ** var_b\nprint(int(var_c))"
    },
    "3220": {
        "category": "Correspondence",
        "question_ko": "다섯 자리 수 26AA2는 3의 배수이다. A가 같은 숫자를 나타낼 때, A에 알맞은 숫자는 모두 몇 개인가?",
        "question_en": "The five digit number 26AA2 is a multiple of 3. If single-digit number A represents the same number, how many numbers can be in A?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "26AA2 [OP_GEN_POSSIBLE_LIST] 3 [OP_LIST_DIVISIBLE] 26AA2 A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_abst_en": "26AA2 [OP_GEN_POSSIBLE_LIST] 3 [OP_LIST_DIVISIBLE] 26AA2 A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '26AA2'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 3\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = '26AA2'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nvar_e = len(list_c)\nprint(int(var_e))",
        "solution_code_en": "var_a = '26AA2'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 3\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = '26AA2'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nvar_e = len(list_c)\nprint(int(var_e))"
    },
    "3221": {
        "category": "Arithmetic calculation",
        "question_ko": "윤기의 나이는 호석이의 나이보다 2살 더 적습니다. 윤기와 호석이의 나이의 합은 18살입니다. 윤기는 몇 살입니까?",
        "question_en": "Yoongi's age is 2 years younger than Hoseok's. The sum of the ages of Yoongi and Hoseok is 18 years old. How old is Yoongi?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "18 2 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "18 2 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 18\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 18\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "3222": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 7센티미터(㎝)인 정삼각형의 둘레는 몇 센티미터(㎝)입니까?",
        "question_en": "What is the perimeter of an equilateral triangle with a side of 7 centimeters (cm)?",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "7 3 [OP_MUL]",
        "solution_abst_en": "7 3 [OP_MUL]",
        "solution_code_ko": "var_a = 7\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 7\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "3223": {
        "category": "Correspondence",
        "question_ko": "두자리 수의 연필을 학샐들에게 똑같은 개수로 나누어주는데 6명의 학생들과 9명의 학생들에게 나눠줄 때는 남는 것이 없고, 7명의 학생들에게 나누어 줄때는 1개의 연필이 남는다. 연필은 몇 개인지 구하시오.",
        "question_en": "You are about to distribute the same two-digit number of pencils to the classmates. There is nothing left when distributing to 6 students and 9 students, and 1 pencil is left when distributing to 7 students. Find how many pencils there are.",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "10 100 1 [OP_LIST_ARANGE] 6 9 [OP_LCM] 0 [OP_LIST_DIVIDE_AND_REMAIN] 7 1 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "10 100 1 [OP_LIST_ARANGE] 6 9 [OP_LCM] 0 [OP_LIST_DIVIDE_AND_REMAIN] 7 1 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 10\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nvar_e = 9\nvar_f = var_e * var_d / math.gcd(int(var_e), int(var_d))\nvar_g = 0\nlist_b = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_a:\n    i = int(i)\n    if i%var_f == var_g:\n        list_b.append(i)\nvar_h = 7\nvar_i = 1\nlist_c = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_b:\n    i = int(i)\n    if i%var_h == var_i:\n        list_c.append(i)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(int(var_k))",
        "solution_code_en": "var_a = 10\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nvar_e = 9\nvar_f = var_e * var_d / math.gcd(int(var_e), int(var_d))\nvar_g = 0\nlist_b = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_a:\n    i = int(i)\n    if i%var_f == var_g:\n        list_b.append(i)\nvar_h = 7\nvar_i = 1\nlist_c = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_b:\n    i = int(i)\n    if i%var_h == var_i:\n        list_c.append(i)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(int(var_k))"
    },
    "3224": {
        "category": "Possibility",
        "question_ko": "1, 3, 5, 8 중에서 서로 다른 숫자 2개를 뽑아 만들 수 있는 가장 작은 두 자리 수에 어떤 수를 더하면 88이 됩니다. 어떤 수를 구하시오.",
        "question_en": "Adding a number to the smallest two-digit number you can make from two different numbers from 1, 3, 5, and 8 equals 88. Find the number.",
        "answer_ko": "75",
        "answer_en": "75",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 5 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 88 [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 5 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 88 [OP_SUB]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 5\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = 88\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 5\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = 88\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "3225": {
        "category": "Arithmetic calculation",
        "question_ko": "일주일 동안 수영장을 찾은 사람 중 중 여성은 1518명이고, 이 중에서 학생은 536명이었습니다. 남성은 여성보다 525명이 더 많았고, 이 중에서 학생이 아닌 사람은 1257명이었습니다. 수영장을 찾은 학생은 모두 몇 명입니까?",
        "question_en": "Of the people who visited the pool during the week, 1518 were women, of whom 536 were students. There were 525 more men than women, of whom 1257 were non-students. How many students visited the pool in total?",
        "answer_ko": "1322",
        "answer_en": "1322",
        "solution_abst_ko": "1518 525 [OP_ADD] 1257 [OP_SUB] 536 [OP_ADD]",
        "solution_abst_en": "1518 525 [OP_ADD] 1257 [OP_SUB] 536 [OP_ADD]",
        "solution_code_ko": "var_a = 1518\nvar_b = 525\nvar_c = var_a + var_b\nvar_d = 1257\nvar_e = var_c - var_d\nvar_f = 536\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1518\nvar_b = 525\nvar_c = var_a + var_b\nvar_d = 1257\nvar_e = var_c - var_d\nvar_f = 536\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "3226": {
        "category": "Correspondence",
        "question_ko": "13을 A로 나누면 몫이 4가 되고, 나머지는 B가 됩니다. A와 B는 모두 자연수입니다. 가능한 A 중 가장 큰 수의 값을 구하시오.",
        "question_en": "When 13 is divided by A, the quotient is 4, the remainder is B. A and B are both natural numbers. Find the largest possible value of A.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "13 1 [OP_SUB] 4 [OP_FDIV]",
        "solution_abst_en": "13 1 [OP_SUB] 4 [OP_FDIV]",
        "solution_code_ko": "var_a = 13\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 13\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "3227": {
        "category": "Geometry",
        "question_ko": "정육면체의 모서리의 개수는?",
        "question_en": "How many edges does a cube have?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "6 2 [OP_SUB] 3 [OP_MUL]",
        "solution_abst_en": "6 2 [OP_SUB] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "3228": {
        "category": "Geometry",
        "question_ko": "두 정육면체 모양의 큐브의 겉넓이의 비가 9:25일 때, 큰 큐브는 작은 큐브 부피의 몇 배입니까?",
        "question_en": "If the ratio of the surface areas of two cubes is 9:25, how many times the volume of the larger cube is the smaller one?",
        "answer_ko": "4.63",
        "answer_en": "4.63",
        "solution_abst_ko": "25 1/2 [OP_POW] 3 [OP_POW] 9 1/2 [OP_POW] 3 [OP_POW] [OP_DIV]",
        "solution_abst_en": "25 1/2 [OP_POW] 3 [OP_POW] 9 1/2 [OP_POW] 3 [OP_POW] [OP_DIV]",
        "solution_code_ko": "var_a = 25\nvar_b = 0.5\nvar_c = var_a ** var_b\nvar_d = 3\nvar_e = var_c ** var_d\nvar_f = 9\nvar_g = 0.5\nvar_h = var_f ** var_g\nvar_i = 3\nvar_j = var_h ** var_i\nvar_k = var_e / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 25\nvar_b = 0.5\nvar_c = var_a ** var_b\nvar_d = 3\nvar_e = var_c ** var_d\nvar_f = 9\nvar_g = 0.5\nvar_h = var_f ** var_g\nvar_i = 3\nvar_j = var_h ** var_i\nvar_k = var_e / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "3229": {
        "category": "Comparison",
        "question_ko": "상우의 중간고사 수학 점수는 하나의 점수보다 높고, 윤용이의 수학 점수는 하나의 점수보다 낮습니다. 세 친구 중 중간고사 수학 점수가 가장 높은 친구는 누구입니까?",
        "question_en": "Sangwoo's midterm math score is higher than Hana's score, and Yunyong's math score is lower than Hana's score. Which of the three friends has the highest midterm math score?",
        "answer_ko": "상우",
        "answer_en": "Sangwoo",
        "solution_abst_ko": "[OP_LIST_SOL] 상우 하나 윤용 [OP_LIST_EOL] [OP_LIST_SOL] 상우 하나 > 윤용 하나 < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Sangwoo Hana Yunyong [OP_LIST_EOL] [OP_LIST_SOL] Sangwoo Hana > Yunyong Hana < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '상우'\nvar_b = '하나'\nvar_c = '윤용'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '상우'\nvar_e = '하나'\nvar_f = '>'\nvar_g = '윤용'\nvar_h = '하나'\nvar_i = '<'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(var_k)",
        "solution_code_en": "var_a = 'Sangwoo'\nvar_b = 'Hana'\nvar_c = 'Yunyong'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'Sangwoo'\nvar_e = 'Hana'\nvar_f = '>'\nvar_g = 'Yunyong'\nvar_h = 'Hana'\nvar_i = '<'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(var_k)"
    },
    "3230": {
        "category": "Comparison",
        "question_ko": "태형이와 친구 10명이 한 줄로 서 있습니다. 태형이의 왼쪽에 5명이 서 있다면 태형이의 오른쪽에는 몇 명이 서 있습니까?",
        "question_en": "Taehyung and 10 of his friends are standing in a line. If 5 people are standing to Taehyung's left, how many people are standing to Taehyung's right?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "10 5 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "10 5 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3231": {
        "category": "Correspondence",
        "question_ko": "성준은 1호점에서 돈의 절반과 300원을 쓰고, 2호점에서는 남은 돈의 절반과 300원을 쓰고, 3호점에선 500원을 썼다. 성준이는 처음에 돈을 얼마 가지고 있었는가?",
        "question_en": "Seongjun spent half of his money and 300 won at the first store, half of the remaining money and 300 won at the second store, and 500 won at the third store. How much money did Seongjun have at the beginning?",
        "answer_ko": "4200",
        "answer_en": "4200",
        "solution_abst_ko": "0 400 [OP_ADD] 500 [OP_ADD] 1 1/2 [OP_SUB] [OP_DIV] 300 [OP_ADD] 1 1/2 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "0 400 [OP_ADD] 500 [OP_ADD] 1 1/2 [OP_SUB] [OP_DIV] 300 [OP_ADD] 1 1/2 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 0\nvar_b = 400\nvar_c = var_a + var_b\nvar_d = 500\nvar_e = var_c + var_d\nvar_f = 1\nvar_g = 0.5\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 300\nvar_k = var_i + var_j\nvar_l = 1\nvar_m = 0.5\nvar_n = var_l - var_m\nvar_o = var_k / var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 0\nvar_b = 400\nvar_c = var_a + var_b\nvar_d = 500\nvar_e = var_c + var_d\nvar_f = 1\nvar_g = 0.5\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 300\nvar_k = var_i + var_j\nvar_l = 1\nvar_m = 0.5\nvar_n = var_l - var_m\nvar_o = var_k / var_n\nprint(int(var_o))"
    },
    "3232": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 6으로 나눈 결과는 26입니다. 어떤 수는 얼마입니까?",
        "question_en": "A number divided by 6 is 26. What is the value of the number?",
        "answer_ko": "156",
        "answer_en": "156",
        "solution_abst_ko": "26 6 [OP_MUL]",
        "solution_abst_en": "26 6 [OP_MUL]",
        "solution_code_ko": "var_a = 26\nvar_b = 6\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 26\nvar_b = 6\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "3233": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 8을 더하고 11을 빼야 하는데 9을 빼고 12을 뺐더니 24가 되었습니다. 바르게 계산한 값과 틀리게 계산한 값의 곱은 얼마인지 구하시오.",
        "question_en": "You need to add 8 to a number and subtract 11. But ended up subtracting 9 and 12 by mistake, and got 24. Find the product of the correctly calculated value and the incorrectly calculated value.",
        "answer_ko": "1008",
        "answer_en": "1008",
        "solution_abst_ko": "24 12 [OP_ADD] 9 [OP_ADD] 8 [OP_ADD] 11 [OP_SUB] 24 [OP_MUL]",
        "solution_abst_en": "24 12 [OP_ADD] 9 [OP_ADD] 8 [OP_ADD] 11 [OP_SUB] 24 [OP_MUL]",
        "solution_code_ko": "var_a = 24\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e + var_f\nvar_h = 11\nvar_i = var_g - var_h\nvar_j = 24\nvar_k = var_i * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 24\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e + var_f\nvar_h = 11\nvar_i = var_g - var_h\nvar_j = 24\nvar_k = var_i * var_j\nprint(int(var_k))"
    },
    "3234": {
        "category": "Arithmetic calculation",
        "question_ko": "4일동안 쌀 240킬로그램(㎏)을 가공할 수 있다면 1920킬로그램(㎏)을 가공하려면 며칠이 걸릴까요?",
        "question_en": "If you can process 240 kg (kg) of rice in 4 days, how many days will it take to process 1920 kg (kg)?",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "1920 240 4 [OP_DIV] [OP_FDIV]",
        "solution_abst_en": "1920 240 4 [OP_DIV] [OP_FDIV]",
        "solution_code_ko": "var_a = 1920\nvar_b = 240\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 1920\nvar_b = 240\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a // var_d\nprint(int(var_e))"
    },
    "3235": {
        "category": "Comparison",
        "question_ko": "4명의 학생 중 결승선을 민영이가 윤기보다 빨리 통과했고 윤기는 지민이보다 빨리 통과했습니다. 지민이와 민영이는 유나보다 늦게 통과했다면, 1등은 누구입니까?",
        "question_en": "Among the four students, Minyoung passed the finish line faster than Yoongi, and Yoongi crossed the finish line faster than Jimin. If Jimin and Minyoung got through later than Yuna, who came in first?",
        "answer_ko": "유나",
        "answer_en": "Yuna",
        "solution_abst_ko": "[OP_LIST_SOL] 민영 윤기 지민 유나 [OP_LIST_EOL] [OP_LIST_SOL] 민영 윤기 > 윤기 지민 > 지민 유나 < 민영 유나 < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Minyoung Yoongi Jimin Yuna [OP_LIST_EOL] [OP_LIST_SOL] Minyoung Yoongi > Yoongi Jimin > Jimin Yuna < Minyoung Yuna < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '민영'\nvar_b = '윤기'\nvar_c = '지민'\nvar_d = '유나'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '민영'\nvar_f = '윤기'\nvar_g = '>'\nvar_h = '윤기'\nvar_i = '지민'\nvar_j = '>'\nvar_k = '지민'\nvar_l = '유나'\nvar_m = '<'\nvar_n = '민영'\nvar_o = '유나'\nvar_p = '<'\nlist_b= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_q = 1\nvar_r = list_c[var_q-1]\nprint(var_r)",
        "solution_code_en": "var_a = 'Minyoung'\nvar_b = 'Yoongi'\nvar_c = 'Jimin'\nvar_d = 'Yuna'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'Minyoung'\nvar_f = 'Yoongi'\nvar_g = '>'\nvar_h = 'Yoongi'\nvar_i = 'Jimin'\nvar_j = '>'\nvar_k = 'Jimin'\nvar_l = 'Yuna'\nvar_m = '<'\nvar_n = 'Minyoung'\nvar_o = 'Yuna'\nvar_p = '<'\nlist_b= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_q = 1\nvar_r = list_c[var_q-1]\nprint(var_r)"
    },
    "3236": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 3번째로 작은 수와 2번째로 작은 수의 합은 얼마입니까?",
        "question_en": "There are five numbers 10, 11, 12, 13, and 14. What is the sum of the 3rd and 2nd smallest numbers?",
        "answer_ko": "23",
        "answer_en": "23",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 3 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 3 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))"
    },
    "3237": {
        "category": "Arithmetic calculation",
        "question_ko": "민영이는 바구니에서 귤을 10개 먹고 한 시간 후에 귤을 6개 더 먹었더니 바구니가 비었습니다. 바구니 안에 귤은 모두 몇 개가 있었을까요?",
        "question_en": "Minyoung ate 10 tangerines from the basket. And an hour later, when she ate 6 more tangerines, the basket was empty. How many tangerines were in the basket?",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "10 6 [OP_ADD]",
        "solution_abst_en": "10 6 [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 6\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 10\nvar_b = 6\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "3238": {
        "category": "Geometry",
        "question_ko": "세로가 가로의 0.9배이고, 가로의 길이는 15센티미터(㎝)이다. 이 직사각형의 넓이는 얼마인가?",
        "question_en": "If a rectangle has the width of 0.9 times its length, and the length of 15 centimeters (cm), what is the area of this rectangle?",
        "answer_ko": "202.50",
        "answer_en": "202.5",
        "solution_abst_ko": "15 15 0.9 [OP_MUL] [OP_MUL]",
        "solution_abst_en": "15 15 0.9 [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 15\nvar_b = 15\nvar_c = 0.9\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 15\nvar_b = 15\nvar_c = 0.9\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "3239": {
        "category": "Arithmetic calculation",
        "question_ko": "민하는 하루에 0.39밀리미터(㎜) 씩 머리카락이 자랍니다. 민하 머리카락의 길이가 오늘 32.8 센티미터(㎝) 라면 30일 후의 길이는 몇 센티미터(㎝) 입니까?",
        "question_en": "Minha's hair grows at a rate of 0.39 millimeters (mm) per day. If the length of Minha's hair is 32.8 centimeters (cm) today, how many centimeters (cm) will it be after 30 days?",
        "answer_ko": "33.97",
        "answer_en": "33.97",
        "solution_abst_ko": "0.39 10 [OP_DIV] 30 [OP_MUL] 32.8 [OP_ADD]",
        "solution_abst_en": "0.39 10 [OP_DIV] 30 [OP_MUL] 32.8 [OP_ADD]",
        "solution_code_ko": "var_a = 0.39\nvar_b = 10\nvar_c = var_a / var_b\nvar_d = 30\nvar_e = var_c * var_d\nvar_f = 32.8\nvar_g = var_e + var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 0.39\nvar_b = 10\nvar_c = var_a / var_b\nvar_d = 30\nvar_e = var_c * var_d\nvar_f = 32.8\nvar_g = var_e + var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "3240": {
        "category": "Comparison",
        "question_ko": "1.23, 3/4, 2.34, 2.12, 4.23, 5/3을 크기가 큰 순으로 정렬합니다. 세 번째로 올 수 있는 것은 무엇입니까?",
        "question_en": "Sort 1.23, 3/4, 2.34, 2.12, 4.23, and 5/3 by largest to smallest. What could be the third?",
        "answer_ko": "2.12",
        "answer_en": "2.12",
        "solution_abst_ko": "[OP_LIST_SOL] 1.23 3 4 [OP_DIV] 2.34 2.12 4.23 5 3 [OP_DIV] [OP_LIST_EOL] 3 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1.23 3 4 [OP_DIV] 2.34 2.12 4.23 5 3 [OP_DIV] [OP_LIST_EOL] 3 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1.23\nvar_b = 3\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = 2.34\nvar_f = 2.12\nvar_g = 4.23\nvar_h = 5\nvar_i = 3\nvar_j = var_h / var_i\nlist_a= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_a.append(var_j)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_k = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_l = list_b[-var_k]\nprint('{:.2f}'.format(round(var_l+1e-10,2)))",
        "solution_code_en": "var_a = 1.23\nvar_b = 3\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = 2.34\nvar_f = 2.12\nvar_g = 4.23\nvar_h = 5\nvar_i = 3\nvar_j = var_h / var_i\nlist_a= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_a.append(var_j)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_k = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_l = list_b[-var_k]\nprint('{:.2f}'.format(round(var_l+1e-10,2)))"
    },
    "3241": {
        "category": "Comparison",
        "question_ko": "5명의 사람 주리, 정우, 명현, 석진, 정국이 있습니다. 정우는 주리보다 작고 석진이는 명현이보다 작습니다. 주리는 정국이보다 작습니다. 명현이는 정우보다 작습니다. 키가 가장 큰 사람은 누구입니까?",
        "question_en": "There are 5 people: Juri, Jungwoo, Myunghyun, Seokjin, and Jungkook. Jungwoo is smaller than Juri and Seokjin is smaller than Myunghyun. Juri is shorter than Jungkook. Myunghyun is shorter than Jungwoo. Who is the tallest?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 주리 정우 명현 석진 정국 [OP_LIST_EOL] [OP_LIST_SOL] 주리 정우 > 명현 석진 > 주리 정국 < 명현 정우 < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Juri Jungwoo Myunghyun Seokjin Jungkook [OP_LIST_EOL] [OP_LIST_SOL] Juri Jungwoo > Myunghyun Seokjin > Juri Jungkook < Myunghyun Jungwoo < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '주리'\nvar_b = '정우'\nvar_c = '명현'\nvar_d = '석진'\nvar_e = '정국'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = '주리'\nvar_g = '정우'\nvar_h = '>'\nvar_i = '명현'\nvar_j = '석진'\nvar_k = '>'\nvar_l = '주리'\nvar_m = '정국'\nvar_n = '<'\nvar_o = '명현'\nvar_p = '정우'\nvar_q = '<'\nlist_b= []\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_r = 1\nvar_s = list_c[var_r-1]\nprint(var_s)",
        "solution_code_en": "var_a = 'Juri'\nvar_b = 'Jungwoo'\nvar_c = 'Myunghyun'\nvar_d = 'Seokjin'\nvar_e = 'Jungkook'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 'Juri'\nvar_g = 'Jungwoo'\nvar_h = '>'\nvar_i = 'Myunghyun'\nvar_j = 'Seokjin'\nvar_k = '>'\nvar_l = 'Juri'\nvar_m = 'Jungkook'\nvar_n = '<'\nvar_o = 'Myunghyun'\nvar_p = 'Jungwoo'\nvar_q = '<'\nlist_b= []\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_r = 1\nvar_s = list_c[var_r-1]\nprint(var_s)"
    },
    "3242": {
        "category": "Correspondence",
        "question_ko": "6을 어떤 수에 나누어 줘야 할 것을 잘못하여 7을 어떤 수에 나눈한 결과는 42가 나옵니다. 바르게 계산하면 얼마인가요?",
        "question_en": "The result of dividing a certain number by 7 mistake of dividing a certain number by 6 is 42. How much is it if you calculate it correctly?",
        "answer_ko": "49",
        "answer_en": "49",
        "solution_abst_ko": "42 7 [OP_MUL] 6 [OP_DIV]",
        "solution_abst_en": "42 7 [OP_MUL] 6 [OP_DIV]",
        "solution_code_ko": "var_a = 42\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 42\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "3243": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 17을 빼면 55가 됩니다. 윤기는 어떤 수를 9로 나누고자 합니다. 윤기가 구한 값은 얼마입니까?",
        "question_en": "Subtracting 17 from a number gives 55. If Yoongi wants to divide the number by 9, how much does Yoongi get?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "55 17 [OP_ADD] 9 [OP_DIV]",
        "solution_abst_en": "55 17 [OP_ADD] 9 [OP_DIV]",
        "solution_code_ko": "var_a = 55\nvar_b = 17\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 55\nvar_b = 17\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "3244": {
        "category": "Arithmetic calculation",
        "question_ko": "3의 배수이면서 5의 배수인 수 중 가장 작은 네 자리 수는?",
        "question_en": "What is the smallest 4-digit number that is a multiple of 3 and a multiple of 5?",
        "answer_ko": "1005",
        "answer_en": "1005",
        "solution_abst_ko": "1000 9999 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "1000 9999 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[var_f-1]\nprint(int(var_g))"
    },
    "3245": {
        "category": "Correspondence",
        "question_ko": "선예네 집에 전기가 들어오지않아 성냥에 의존해야한다. 성냥곽 안에는 8개의 성냥이 들어있다고 한다. 선예는 9개의 성냥곽과 7개의 낱개 성냥을 가지고 있다. 하루에 6개씩 성냥을 쓴다면 최대 며칠을 온전히 버틸 수 있을지 구하시오",
        "question_en": "Sunye's house has no electricity, so she has to rely on matches. There are 8 matches in a matchbox. Sunye has 9 matchboxes and 7 single matches. If she uses 6 matches a day, find the maximum number of days she can last completely.",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "8 9 [OP_MUL] 7 [OP_ADD] 6 [OP_FDIV]",
        "solution_abst_en": "8 9 [OP_MUL] 7 [OP_ADD] 6 [OP_FDIV]",
        "solution_code_ko": "var_a = 8\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c + var_d\nvar_f = 6\nvar_g = var_e // var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 8\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c + var_d\nvar_f = 6\nvar_g = var_e // var_f\nprint(int(var_g))"
    },
    "3246": {
        "category": "Arithmetic calculation",
        "question_ko": "물 19리터(L)를 9일 동안 똑같이 나누어 마시려고 합니다. 하루에 마셔야 할 물은 몇 리터(L)인지 구하세요.",
        "question_en": "You want to drink 19 liters (L) of water equally over 9 days. Find how many liters (l) of water you need to drink per day.",
        "answer_ko": "2.11",
        "answer_en": "2.11",
        "solution_abst_ko": "19 9 [OP_DIV]",
        "solution_abst_en": "19 9 [OP_DIV]",
        "solution_code_ko": "var_a = 19\nvar_b = 9\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 19\nvar_b = 9\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "3247": {
        "category": "Arithmetic calculation",
        "question_ko": "몬스터 여러 마리가 공격해서 총을 쏘려고 한다. 몬스터에게 4발씩 쏘니 3발이 남고, 5발씩 쏘니 6발이 부족했다. 몇 마리의 몬스터가 공격하는가?",
        "question_en": "Suppose several monsters are trying to attack. If you shoot 4 times at a monster, 3 shots remain, and if you try to shoot 5 times, then you lack 6 shots. How many monsters are there?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "3 6 [OP_ADD] 5 4 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "3 6 [OP_ADD] 5 4 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 3\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = 4\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 3\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = 4\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))"
    },
    "3248": {
        "category": "Geometry",
        "question_ko": "어떤 평행사변형은 44제곱센티미터(㎠)의 넓이와 11센티미터(㎝)의 높이를 가지고 있습니다. 밑변의 길이는?",
        "question_en": "A parallelogram has an area of 44 square centimeters (cm2) and a height of 11 centimeters (cm). What is the length of the base?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "44 11 [OP_DIV]",
        "solution_abst_en": "44 11 [OP_DIV]",
        "solution_code_ko": "var_a = 44\nvar_b = 11\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 44\nvar_b = 11\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "3249": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 0.42를 빼야 할 것을 잘못하여 더했더니 0.9가 되었습니다. 바르게 계산한 값에 0.5를 더한다면 얼마입니까?",
        "question_en": "You mistakenly added what should have subtracted 0.42 from a number, and ended up with 0.9. What is 0.5 added to the correctly calculated value?",
        "answer_ko": "0.56",
        "answer_en": "0.56",
        "solution_abst_ko": "0.9 0.42 [OP_SUB] 0.42 [OP_SUB] 0.5 [OP_ADD]",
        "solution_abst_en": "0.9 0.42 [OP_SUB] 0.42 [OP_SUB] 0.5 [OP_ADD]",
        "solution_code_ko": "var_a = 0.9\nvar_b = 0.42\nvar_c = var_a - var_b\nvar_d = 0.42\nvar_e = var_c - var_d\nvar_f = 0.5\nvar_g = var_e + var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 0.9\nvar_b = 0.42\nvar_c = var_a - var_b\nvar_d = 0.42\nvar_e = var_c - var_d\nvar_f = 0.5\nvar_g = var_e + var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "3250": {
        "category": "Correspondence",
        "question_ko": "A를 7로 나누면 몫은 5이고 나머지는 3이 됩니다. A를 구하시오.",
        "question_en": "When A is divided by 7, the quotient is 5 and the remainder is 3. Get A.",
        "answer_ko": "38",
        "answer_en": "38",
        "solution_abst_ko": "7 5 [OP_MUL] 3 [OP_ADD]",
        "solution_abst_en": "7 5 [OP_MUL] 3 [OP_ADD]",
        "solution_code_ko": "var_a = 7\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 7\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3251": {
        "category": "Arithmetic calculation",
        "question_ko": "물이 가득 담긴 통의 무게는 320킬로그램(㎏)입니다. 이 중 물 1/2을 쓴 후 통의 무게를 다시 재어 보니 175킬로그램(㎏)입니다. 통만의 무게는 몇 킬로그램(㎏)입니까?",
        "question_en": "A bucket full of water weighs 320 kilograms (kg). After using 1/2 of the water, the bucket weighs 175 kilograms (kg). What is the weight of the empty bucket in kilograms (kg)?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "320 320 175 [OP_SUB] 2 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "320 320 175 [OP_SUB] 2 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 320\nvar_b = 320\nvar_c = 175\nvar_d = var_b - var_c\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_a - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 320\nvar_b = 320\nvar_c = 175\nvar_d = var_b - var_c\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_a - var_f\nprint(int(var_g))"
    },
    "3252": {
        "category": "Arithmetic calculation",
        "question_ko": "한 상자에 16캔씩 들어있는 음료수를 7상자 샀습니다. 그중에서 13개는 운반 도중 캔이 찌그러져서 버리고, 남은 음료수를 8상자에 똑같이 나누어 담으려고 합니다. 한 상자에 몇 개씩 나누어 담으면 됩니까?",
        "question_en": "I bought 7 boxes of soda, each box containing 16 cans. Thirteen of them were discarded because the cans were crushed during transport. I plan to distribute the remaining beverages equally among the eight boxes. How many pieces should I put in each box?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "16 7 [OP_MUL] 13 [OP_SUB] 8 [OP_FDIV]",
        "solution_abst_en": "16 7 [OP_MUL] 13 [OP_SUB] 8 [OP_FDIV]",
        "solution_code_ko": "var_a = 16\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = var_e // var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 16\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = var_e // var_f\nprint(int(var_g))"
    },
    "3253": {
        "category": "Geometry",
        "question_ko": "한 모서리의 길이가 6㎝인 정육면체가 있습니다. 각 면의 한가운데서 한 모서리의 길이가 2㎝인 정육면체를 파내었을 때, 남은 부분의 겉넓이는 몇 제곱센티미터입니까?",
        "question_en": "There is a cube with 6 centimeters (cm) edge. If a smaller cube whose edge is 2 centimeters (cm) is cut out from the middle of each side of the original one, what will be the surface area in square centimeters (cm2)?",
        "answer_ko": "312",
        "answer_en": "312",
        "solution_abst_ko": "6 2 [OP_POW] 6 [OP_MUL] 2 2 [OP_POW] 4 [OP_MUL] 6 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "6 2 [OP_POW] 6 [OP_MUL] 2 2 [OP_POW] 4 [OP_MUL] 6 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = var_c * var_d\nvar_f = 2\nvar_g = 2\nvar_h = var_f ** var_g\nvar_i = 4\nvar_j = var_h * var_i\nvar_k = 6\nvar_l = var_j * var_k\nvar_m = var_e + var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = var_c * var_d\nvar_f = 2\nvar_g = 2\nvar_h = var_f ** var_g\nvar_i = 4\nvar_j = var_h * var_i\nvar_k = 6\nvar_l = var_j * var_k\nvar_m = var_e + var_l\nprint(int(var_m))"
    },
    "3254": {
        "category": "Arithmetic calculation",
        "question_ko": "상자에 초록색 구슬과 보라색 구슬이 모두 23개 들어 있습니다. 초록색 구슬이 보라색 구슬보다 7개 더 많을 때, 초록색 구슬은 몇 개입니까?",
        "question_en": "The box contains 23 green and 23 purple marbles. If there are 7 more green marbles than purple marbles, how many green marbles are there?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "23 7 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "23 7 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 23\nvar_b = 7\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 23\nvar_b = 7\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "3255": {
        "category": "Possibility",
        "question_ko": "7개 반이 축구 경기를 한다. 서로 다른 반과 한번씩 경기를 진행한다면 경기는 총 몇번 진행되는가?",
        "question_en": "Seven classes play soccer. If they play against each other once, how many matches are there in total?",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "7 7 1 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "7 7 1 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 7\nvar_b = 7\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 7\nvar_b = 7\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "3256": {
        "category": "Comparison",
        "question_ko": "한 영화관에 의자가 8개씩 4열이 있을 때, 이 영화관에 있는 모든 의자의 개수는 몇 개 입니까?",
        "question_en": "If a cinema has 4 rows of 8 chairs each, what is the total number of chairs in the cinema?",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "8 4 [OP_MUL]",
        "solution_abst_en": "8 4 [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 8\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "3257": {
        "category": "Comparison",
        "question_ko": "세 사람이 가진 책의 평균은 첫 번째 사람과 두 번째 사람이 가진 책의 평균보다 23권 더 적았고, 두 번째 사람과 세 번째 사람이 가진 책의 평균보다 17권 더 많았다. 두 번째 사람이 가진 책이 66권이었을 때, 첫 번째 사람과 세 번째 사람이 가진 책 권수의 합을 구하여라.",
        "question_en": "The average number of books the three had was 23 fewer than the average of the first and second persons, and 17 more than the average of the second and third persons. If the second person has 66 books, find the sum of the number of books the first person and the third person have.",
        "answer_ko": "96",
        "answer_en": "96",
        "solution_abst_ko": "66 23 [OP_SUB] 17 [OP_ADD] 2 3 [OP_DIV] 66 [OP_MUL] [OP_SUB] 2 3 [OP_DIV] 1 2 [OP_DIV] [OP_SUB] [OP_DIV]",
        "solution_abst_en": "66 23 [OP_SUB] 17 [OP_ADD] 2 3 [OP_DIV] 66 [OP_MUL] [OP_SUB] 2 3 [OP_DIV] 1 2 [OP_DIV] [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 66\nvar_b = 23\nvar_c = var_a - var_b\nvar_d = 17\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = 3\nvar_h = var_f / var_g\nvar_i = 66\nvar_j = var_h * var_i\nvar_k = var_e - var_j\nvar_l = 2\nvar_m = 3\nvar_n = var_l / var_m\nvar_o = 1\nvar_p = 2\nvar_q = var_o / var_p\nvar_r = var_n - var_q\nvar_s = var_k / var_r\nprint(int(eval('{:.2f}'.format(round(var_s+1e-10,2)))))",
        "solution_code_en": "var_a = 66\nvar_b = 23\nvar_c = var_a - var_b\nvar_d = 17\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = 3\nvar_h = var_f / var_g\nvar_i = 66\nvar_j = var_h * var_i\nvar_k = var_e - var_j\nvar_l = 2\nvar_m = 3\nvar_n = var_l / var_m\nvar_o = 1\nvar_p = 2\nvar_q = var_o / var_p\nvar_r = var_n - var_q\nvar_s = var_k / var_r\nprint(int(eval('{:.2f}'.format(round(var_s+1e-10,2)))))"
    },
    "3258": {
        "category": "Possibility",
        "question_ko": "숫자 카드에 1부터 12까지의 숫자가 적혀있습니다. 숫자카드 하나를 뽑았을 때 카드에 적힌 숫자가 3의 배수인 경우의 수는 모두 몇 개인지 구하세요.",
        "question_en": "The number cards have numbers from 1 to 12 written on them. When a number card is drawn, find the number of cases where the number on the card is a multiple of 3.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "1 12 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "1 12 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 12\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 12\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "3259": {
        "category": "Possibility",
        "question_ko": "사과, 복숭아, 배, 참외, 딸기가 각각 하나씩 있는 바구니에서 과일을 꺼낼 기회는 두 번입니다. 나올 수 있는 과일의 순서는 모두 몇 가지입니까?",
        "question_en": "You have two chances to pick fruit from a basket that contains one apple, one peach, one pear, one melon, and one strawberry. How many orders of fruit can there be?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 복숭아 배 참외 딸기 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] apple peach pear melon strawberry [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '복숭아'\nvar_c = '배'\nvar_d = '참외'\nvar_e = '딸기'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nprint(int(var_h))",
        "solution_code_en": "var_a = 'apple'\nvar_b = 'peach'\nvar_c = 'pear'\nvar_d = 'melon'\nvar_e = 'strawberry'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nprint(int(var_h))"
    },
    "3260": {
        "category": "Arithmetic calculation",
        "question_ko": "8월에 만든 (가) 물건을 8배하면 9월에 만든 (가) 물건의 수가 됩니다. 9월에 (가) 물건 72개를 만들었다면 8월 9월 두달 동안 만든 (가) 물건은 모두 몇 개입니까?",
        "question_en": "Multiplying product (a) produced in August by 8 gives you the number of product (a) produced in September. If you produced 72 items in September, how many items did you produce in August and September in total?",
        "answer_ko": "648",
        "answer_en": "648",
        "solution_abst_ko": "72 72 8 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "72 72 8 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 72\nvar_b = 72\nvar_c = 8\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 72\nvar_b = 72\nvar_c = 8\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "3261": {
        "category": "Arithmetic calculation",
        "question_ko": "7개의 수의 평균은 7입니다. 이 중 한 개의 수를 골라 9로 바꾸었더니 평균이 8이 되었습니다. 바꾼 수는 원래 얼마입니까?",
        "question_en": "The average of 7 numbers is 7. If you take one of these numbers and change it to 9, the average is 8. What was the original number before changing?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "7 7 [OP_MUL] 7 8 [OP_MUL] 9 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "7 7 [OP_MUL] 7 8 [OP_MUL] 9 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 7\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = 8\nvar_f = var_d * var_e\nvar_g = 9\nvar_h = var_f - var_g\nvar_i = var_c - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 7\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = 8\nvar_f = var_d * var_e\nvar_g = 9\nvar_h = var_f - var_g\nvar_i = var_c - var_h\nprint(int(var_i))"
    },
    "3262": {
        "category": "Correspondence",
        "question_ko": "윤기는 세 자리 수에 57을 빼던 중, 윤기는 두 자리 수의 일의 자리 숫자 9를 6으로 잘못 보았습니다. 윤기가 구한 차가 819 일 때, 세 자리 수는 무엇일까요?",
        "question_en": "While Yoongi was subtracting 57 from the three-digit number, Yoongi mistakenly saw the units digit of the three-digit number 9 as 6. When Yoongi got the result of 819, what is the three-digit number?",
        "answer_ko": "879",
        "answer_en": "879",
        "solution_abst_ko": "819 57 [OP_ADD] 6 9 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "819 57 [OP_ADD] 6 9 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 819\nvar_b = 57\nvar_c = var_a + var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 819\nvar_b = 57\nvar_c = var_a + var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "3263": {
        "category": "Arithmetic calculation",
        "question_ko": "문구점에서 공책 15묶음을 5일 만에 전부 팔았습니다. 각 묶음에 공책이 40권씩 들어 있었다면, 매일 평균 몇 권씩 팔았습니까?",
        "question_en": "The stationery shop sold all 15 bundles of notebooks in 5 days. If each bundle contained 40 notebooks, how many notebooks did you sell on average per day?",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "15 40 [OP_MUL] 5 [OP_FDIV]",
        "solution_abst_en": "15 40 [OP_MUL] 5 [OP_FDIV]",
        "solution_code_ko": "var_a = 15\nvar_b = 40\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 40\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "3264": {
        "category": "Arithmetic calculation",
        "question_ko": "영수가 강아지를 안고 무게를 달았더니 31킬로그램(㎏)이었고, 가영이가 같은 강아지를 안고 무게를 달았더니 27킬로그램(㎏) 350그램(g)이었습니다. 강아지의 무게가 1킬로그램(㎏) 400그램(g)이라면 영수, 가영, 강아지의 무게의 합은 몇 킬로그램(㎏)입니까?",
        "question_en": "When Young-soo held the puppy and weighed it, it was 31 kilograms (kg), and when Ga-young held the same puppy and weighed it, it was 27 kilograms (kg) and 350 grams (g). If the weight of the dog is 1 kilogram (kg) and 400 grams (g), how many kilograms (kg) is the sum of the weights of Youngsoo, Gayoung, and the dog?",
        "answer_ko": "56.95",
        "answer_en": "56.95",
        "solution_abst_ko": "31 27 350 1000 [OP_DIV] [OP_ADD] [OP_ADD] 1 400 1000 [OP_DIV] [OP_ADD] [OP_SUB]",
        "solution_abst_en": "31 27 350 1000 [OP_DIV] [OP_ADD] [OP_ADD] 1 400 1000 [OP_DIV] [OP_ADD] [OP_SUB]",
        "solution_code_ko": "var_a = 31\nvar_b = 27\nvar_c = 350\nvar_d = 1000\nvar_e = var_c / var_d\nvar_f = var_b + var_e\nvar_g = var_a + var_f\nvar_h = 1\nvar_i = 400\nvar_j = 1000\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_g - var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))",
        "solution_code_en": "var_a = 31\nvar_b = 27\nvar_c = 350\nvar_d = 1000\nvar_e = var_c / var_d\nvar_f = var_b + var_e\nvar_g = var_a + var_f\nvar_h = 1\nvar_i = 400\nvar_j = 1000\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_g - var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))"
    },
    "3265": {
        "category": "Arithmetic calculation",
        "question_ko": "집에서 공항까지는 300킬로미터(㎞) 떨어져있습니다. 진우가 시속 60킬로미터(㎞)의 자동차를 타고 집에서 출발했을 때 2시간 후의 남은 거리는 얼마인지 구하세요.",
        "question_en": "The airport is 300 kilometers (km) away from the house. Find the remaining distance after 2 hours when Jinwoo leaves home in a car traveling at 60 kilometers (km) per hour.",
        "answer_ko": "180",
        "answer_en": "180",
        "solution_abst_ko": "300 60 2 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "300 60 2 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 300\nvar_b = 60\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 300\nvar_b = 60\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "3266": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 2번째로 큰 수와 2번째로 작은 수의 곱은 얼마입니까?",
        "question_en": "There are five numbers 10, 11, 12, 13, and 14. What is the product of the second largest number and the second smallest number?",
        "answer_ko": "143",
        "answer_en": "143",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g * var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g * var_i\nprint(int(var_j))"
    },
    "3267": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 41을 더해야 하는데 잘못해서 14를 더했더니 68이 되었습니다. 어떤 수와 바르게 계산한 값의 합을 구하시오.",
        "question_en": "You need to add 41 to a number, but mistakenly added 14, and got 68. Find the sum of a number and its correctly calculated value.",
        "answer_ko": "149",
        "answer_en": "149",
        "solution_abst_ko": "68 14 [OP_SUB] 68 14 [OP_SUB] 41 [OP_ADD] [OP_ADD]",
        "solution_abst_en": "68 14 [OP_SUB] 68 14 [OP_SUB] 41 [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 68\nvar_b = 14\nvar_c = var_a - var_b\nvar_d = 68\nvar_e = 14\nvar_f = var_d - var_e\nvar_g = 41\nvar_h = var_f + var_g\nvar_i = var_c + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 68\nvar_b = 14\nvar_c = var_a - var_b\nvar_d = 68\nvar_e = 14\nvar_f = var_d - var_e\nvar_g = 41\nvar_h = var_f + var_g\nvar_i = var_c + var_h\nprint(int(var_i))"
    },
    "3268": {
        "category": "Correspondence",
        "question_ko": "14A+2B3=418입니다. A는 얼마인가요?",
        "question_en": "14A+2B3=418. How much is A?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "14A+2B3=418 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "14A+2B3=418 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '14A+2B3=418'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '14A+2B3=418'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "3269": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.3, 1/3 중 0.4보다 작거나 같은 수의 개수를 구하시오.",
        "question_en": "Find the number of numbers less than or equal to 0.4 among 0.8, 1/2, 0.3, and 1/3.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.3 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.3 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.3\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.4\nlist_b = []\nfor i in list_a:\n    if i <= var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.3\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.4\nlist_b = []\nfor i in list_a:\n    if i <= var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "3270": {
        "category": "Geometry",
        "question_ko": "서로 다른 동전 2개를 던졌을 때, 둘 다 뒷면이 나오는 경우는 몇 가지 입니까?",
        "question_en": "When tossing two different coins, calculate the numbers of cases where both tails come up.",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "1",
        "solution_abst_en": "1",
        "solution_code_ko": "var_a = 1\nprint(int(var_a))",
        "solution_code_en": "var_a = 1\nprint(int(var_a))"
    },
    "3271": {
        "category": "Arithmetic calculation",
        "question_ko": "남준이는 자전거를 타고 1.3시간 동안 96.967킬로미터(㎞)를 갔습니다. 남준이가 일정한 빠르기로 갔다면 1 시간 동안 간 거리는 몇 킬로미터(㎞) 입니까?",
        "question_en": "Namjoon rode his bike and traveled 96.967 kilometers (km) in 1.3 hours. If Namjoon went at a steady speed, how many kilometers (km) did he travel in 1 hour?",
        "answer_ko": "74.59",
        "answer_en": "74.59",
        "solution_abst_ko": "96.967 1.3 [OP_DIV] 1 [OP_MUL]",
        "solution_abst_en": "96.967 1.3 [OP_DIV] 1 [OP_MUL]",
        "solution_code_ko": "var_a = 96.967\nvar_b = 1.3\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 96.967\nvar_b = 1.3\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "3272": {
        "category": "Possibility",
        "question_ko": "각 자리수가 3이하의 홀수로만 이루어진 세 자리 수는 총 몇개입니까?",
        "question_en": "How many three-digit numbers are there in which each digit has only odd numbers less than or equal to 3?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "0 3 [OP_LIST_ODD] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_LEN]",
        "solution_abst_en": "0 3 [OP_LIST_ODD] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 3\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = len(list_b)\nprint(int(var_d))",
        "solution_code_en": "var_a = 0\nvar_b = 3\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = len(list_b)\nprint(int(var_d))"
    },
    "3273": {
        "category": "Comparison",
        "question_ko": "지민이는 주스를 0.7리터(L) 마셨습니다. 은지는 지민이보다 1/10리터(L) 더 적게 마셨습니다. 윤기는 4/5리터(L) 마셨고, 유나는 지민이보다 0.2리터(L) 더 많이 마셨습니다. 주스를 가장 많이 마신 사람은 누구입니까?",
        "question_en": "Jimin drank 0.7 liters (L) of juice. Eunji drank 1/10 liter (L) less than Jimin. Yoongi drank 4/5 liters (L), and Yuna drank 0.2 liters (L) more than Jimin. Who drank the most juice?",
        "answer_ko": "유나",
        "answer_en": "Yuna",
        "solution_abst_ko": "[OP_LIST_SOL] 지민 은지 윤기 유나 [OP_LIST_EOL] [OP_LIST_SOL] 0.7 0.7 1 10 [OP_DIV] [OP_SUB] 4 5 [OP_DIV] 0.7 0.2 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jimin Eunji Yoongi Yuna [OP_LIST_EOL] [OP_LIST_SOL] 0.7 0.7 1 10 [OP_DIV] [OP_SUB] 4 5 [OP_DIV] 0.7 0.2 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '지민'\nvar_b = '은지'\nvar_c = '윤기'\nvar_d = '유나'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.7\nvar_f = 0.7\nvar_g = 1\nvar_h = 10\nvar_i = var_g / var_h\nvar_j = var_f - var_i\nvar_k = 4\nvar_l = 5\nvar_m = var_k / var_l\nvar_n = 0.7\nvar_o = 0.2\nvar_p = var_n + var_o\nlist_b= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_q = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_r = list_c[-var_q]\nvar_s = list_b.index(var_r)+1\nvar_t = list_a[var_s-1]\nprint(var_t)",
        "solution_code_en": "var_a = 'Jimin'\nvar_b = 'Eunji'\nvar_c = 'Yoongi'\nvar_d = 'Yuna'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.7\nvar_f = 0.7\nvar_g = 1\nvar_h = 10\nvar_i = var_g / var_h\nvar_j = var_f - var_i\nvar_k = 4\nvar_l = 5\nvar_m = var_k / var_l\nvar_n = 0.7\nvar_o = 0.2\nvar_p = var_n + var_o\nlist_b= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_q = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_r = list_c[-var_q]\nvar_s = list_b.index(var_r)+1\nvar_t = list_a[var_s-1]\nprint(var_t)"
    },
    "3274": {
        "category": "Comparison",
        "question_ko": "지안이는 5000원, 도윤이는 2000원, 하린이는 8000원, 주원이는 4000원을 가지고 있습니다. 3번째로 돈이 많은 사람은 누구인가요?",
        "question_en": "Jian has 5,000 won, Doyun has 2,000 won, Harin has 8,000 won, and Joowon has 4,000 won. Who is the 3rd richest person?",
        "answer_ko": "주원",
        "answer_en": "Joowon",
        "solution_abst_ko": "[OP_LIST_SOL] 지안 도윤 하린 주원 [OP_LIST_EOL] [OP_LIST_SOL] 5000 2000 8000 4000 [OP_LIST_EOL] 3 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jian Doyun Harin Joowon [OP_LIST_EOL] [OP_LIST_SOL] 5000 2000 8000 4000 [OP_LIST_EOL] 3 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '지안'\nvar_b = '도윤'\nvar_c = '하린'\nvar_d = '주원'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 5000\nvar_f = 2000\nvar_g = 8000\nvar_h = 4000\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Jian'\nvar_b = 'Doyun'\nvar_c = 'Harin'\nvar_d = 'Joowon'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 5000\nvar_f = 2000\nvar_g = 8000\nvar_h = 4000\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "3275": {
        "category": "Correspondence",
        "question_ko": "어떤 수의 10배는 17입니다, 어떤 수의 1/100배는 얼마입니까?",
        "question_en": "10 times a number is 17, what is 1/100 times the number?",
        "answer_ko": "0.02",
        "answer_en": "0.02",
        "solution_abst_ko": "17 10 [OP_DIV] 1/100 [OP_MUL]",
        "solution_abst_en": "17 10 [OP_DIV] 1/100 [OP_MUL]",
        "solution_code_ko": "var_a = 17\nvar_b = 10\nvar_c = var_a / var_b\nvar_d = 0.01\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 17\nvar_b = 10\nvar_c = var_a / var_b\nvar_d = 0.01\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "3276": {
        "category": "Arithmetic calculation",
        "question_ko": "우유는 빵보다 18개 적고, 과자는 빵보다 27개 더 많습니다. 빵이 58개 있을 때 빵, 우유, 과자는 모두 몇 개입니까?",
        "question_en": "Bottles of milk are 18 less than slices of bread, and cookies are 27 more than slices of bread. If there are 58 slices of bread, how many bread, bottles of milk, and cookies are there in total?",
        "answer_ko": "183",
        "answer_en": "183",
        "solution_abst_ko": "58 58 18 [OP_SUB] [OP_ADD] 58 27 [OP_ADD] [OP_ADD]",
        "solution_abst_en": "58 58 18 [OP_SUB] [OP_ADD] 58 27 [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 58\nvar_b = 58\nvar_c = 18\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 58\nvar_g = 27\nvar_h = var_f + var_g\nvar_i = var_e + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 58\nvar_b = 58\nvar_c = 18\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 58\nvar_g = 27\nvar_h = var_f + var_g\nvar_i = var_e + var_h\nprint(int(var_i))"
    },
    "3277": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 철물점에서 철사를 0.1미터(m)에 200원씩 판매합니다. 1200원으로는 몇 미터(m)의 철사를 살 수 있습니까?",
        "question_en": "A hardware store sells wire for 200 won for 0.1 meter (m). How many meters (m) of wire can you buy with 1200 won?",
        "answer_ko": "0.60",
        "answer_en": "0.6",
        "solution_abst_ko": "1200 200 [OP_DIV] 0.1 [OP_MUL]",
        "solution_abst_en": "1200 200 [OP_DIV] 0.1 [OP_MUL]",
        "solution_code_ko": "var_a = 1200\nvar_b = 200\nvar_c = var_a / var_b\nvar_d = 0.1\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 1200\nvar_b = 200\nvar_c = var_a / var_b\nvar_d = 0.1\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "3278": {
        "category": "Comparison",
        "question_ko": "유정은 책상 위에 색색의 공을 여러 개 늘어놓았다. 빨간색, 파란색, 노란색, 보라색, 흰색 공을 배열할 때 첫 번째 공은 무슨 색입니까?",
        "question_en": "Yujeong arranged several colored balls on the desk. If the red, blue, yellow, purple and white balls are arranged in this order, what color is the first ball?",
        "answer_ko": "빨간색",
        "answer_en": "red",
        "solution_abst_ko": "[OP_LIST_SOL] 빨간색 파란색 노란색 보라색 흰색 [OP_LIST_EOL] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] red blue yellow purple white [OP_LIST_EOL] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '빨간색'\nvar_b = '파란색'\nvar_c = '노란색'\nvar_d = '보라색'\nvar_e = '흰색'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nvar_g = list_a[var_f-1]\nprint(var_g)",
        "solution_code_en": "var_a = 'red'\nvar_b = 'blue'\nvar_c = 'yellow'\nvar_d = 'purple'\nvar_e = 'white'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nvar_g = list_a[var_f-1]\nprint(var_g)"
    },
    "3279": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 9/20 센티미터(㎝)인 정삼각형과 둘레가 같은 정오각형의 한 변의 센티미터(㎝) 길이를 구하십시오.",
        "question_en": "Find the length in centimeters (cm) of a side of an equilateral triangle with length 9/20 centimeters (cm) and a regular pentagon with the same perimeter.",
        "answer_ko": "0.27",
        "answer_en": "0.27",
        "solution_abst_ko": "9/20 3 [OP_MUL] 5 [OP_DIV]",
        "solution_abst_en": "9/20 3 [OP_MUL] 5 [OP_DIV]",
        "solution_code_ko": "var_a = 0.45\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.45\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "3280": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 8로 나누어야 할 것을 잘못하여 6으로 나누었더니 몫이 124, 나머지가 4가 되었습니다. 바르게 계산한 결과를 구하시오.",
        "question_en": "You should have divided a certain number by 8, but you mistakenly divided it by 6 and got a quotient of 124 and a remainder of 4. Find the answer to the correct calculation.",
        "answer_ko": "93.50",
        "answer_en": "93.5",
        "solution_abst_ko": "124 6 [OP_MUL] 4 [OP_ADD] 8 [OP_DIV]",
        "solution_abst_en": "124 6 [OP_MUL] 4 [OP_ADD] 8 [OP_DIV]",
        "solution_code_ko": "var_a = 124\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 124\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "3281": {
        "category": "Correspondence",
        "question_ko": "우정고등학교에 다니는 1학년 수는 1학년이 아닌 학생 수보다 468명 적다. 1학년이 아닌 학생 수가 954명이면 우정고등학교에 다니는 학생수는 몇 명인가?",
        "question_en": "The number of first-year students attending Woojung High School is 468 less than the number of non-first-year students. If the number of non-first year students is 954, how many students attend Woojung High School?",
        "answer_ko": "1440",
        "answer_en": "1440",
        "solution_abst_ko": "954 468 [OP_SUB] 954 [OP_ADD]",
        "solution_abst_en": "954 468 [OP_SUB] 954 [OP_ADD]",
        "solution_code_ko": "var_a = 954\nvar_b = 468\nvar_c = var_a - var_b\nvar_d = 954\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 954\nvar_b = 468\nvar_c = var_a - var_b\nvar_d = 954\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3282": {
        "category": "Arithmetic calculation",
        "question_ko": "축구공이 68개 있습니다. 축구공은 배구공보다 12개 적고, 농구공보다 23개 많습니다. 축구공, 배구공, 농구공은 모두 몇 개입니까?",
        "question_en": "There are 68 soccer balls, which are 12 less compared to volleyballs and 23 more than basketballs. How many soccer balls, volleyballs, and basketballs are there altogether?",
        "answer_ko": "193",
        "answer_en": "193",
        "solution_abst_ko": "68 12 [OP_ADD] 68 23 [OP_SUB] [OP_ADD] 68 [OP_ADD]",
        "solution_abst_en": "68 12 [OP_ADD] 68 23 [OP_SUB] [OP_ADD] 68 [OP_ADD]",
        "solution_code_ko": "var_a = 68\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 68\nvar_e = 23\nvar_f = var_d - var_e\nvar_g = var_c + var_f\nvar_h = 68\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 68\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 68\nvar_e = 23\nvar_f = var_d - var_e\nvar_g = var_c + var_f\nvar_h = 68\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "3283": {
        "category": "Comparison",
        "question_ko": "1.4, 9/10, 1.2, 0.5, 13/10 중에서 1.1보다 작거나 같은 수를 고르면 몇 개인지 구하시오.",
        "question_en": "Among 1.4, 9/10, 1.2, 0.5, and 13/10, find how many numbers are less than or equal to 1.1.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i <= var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i <= var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "3284": {
        "category": "Possibility",
        "question_ko": "다섯 개의 숫자 0, 1, 2, 3, 4 중에서 3개를 골라 세 자리의 홀수를 만들었다. 같은 수를 여러 번 사용해도 된다면, 만들 수 있는 모든 홀수의 개수는 몇개인가?",
        "question_en": "Three out of five digits 0, 1, 2, 3, and 4 were chosen to make a three-digit odd number. If you can use the same number multiple times, how many odd numbers can you make?",
        "answer_ko": "40",
        "answer_en": "40",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 2 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 2 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 2\nlist_c = []\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if i % var_g == 0:\n        list_c.append(i)\nlist_d = list(set(list_b) - set(list_c))\nvar_h = len(list_d)\nprint(int(var_h))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 2\nlist_c = []\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if i % var_g == 0:\n        list_c.append(i)\nlist_d = list(set(list_b) - set(list_c))\nvar_h = len(list_d)\nprint(int(var_h))"
    },
    "3285": {
        "category": "Geometry",
        "question_ko": "긴 변이 1미터(m)이고 짧은 변이 긴 변보다 2/8미터(m) 짧은 직사각형이 있습니다. 이 직사각형의 네 변의 길이의 합은 몇 미터(m)입니까?",
        "question_en": "Consider a rectangle whose long side is 1 meter (m) and whose short side is 2/8 meter (m) shorter than the long side. What is the sum of the lengths of the four sides of this rectangle in meters (m)?",
        "answer_ko": "3.50",
        "answer_en": "3.5",
        "solution_abst_ko": "1 1 2 8 [OP_DIV] [OP_SUB] [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "1 1 2 8 [OP_DIV] [OP_SUB] [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 1\nvar_b = 1\nvar_c = 2\nvar_d = 8\nvar_e = var_c / var_d\nvar_f = var_b - var_e\nvar_g = var_a + var_f\nvar_h = 2\nvar_i = var_g * var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 1\nvar_c = 2\nvar_d = 8\nvar_e = var_c / var_d\nvar_f = var_b - var_e\nvar_g = var_a + var_f\nvar_h = 2\nvar_i = var_g * var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "3286": {
        "category": "Correspondence",
        "question_ko": "A, B, C는 0에서 9까지의 서로 다른 숫자입니다. 뺄셈식 AAA-BB=AC에서 C를 구하시오.",
        "question_en": "A, B, and C are different numbers from 0 to 9. Find C from the subtraction sentence AAA-BB=AC.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "AAA-BB=AC C [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "AAA-BB=AC C [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'AAA-BB=AC'\nvar_b = 'C'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'AAA-BB=AC'\nvar_b = 'C'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "3287": {
        "category": "Arithmetic calculation",
        "question_ko": "우경이의 키는 은미보다 9센티미터(㎝)가 작습니다. 우경이의 키가 1미터(m) 35센티미터(㎝)라면 은미의 키는 몇 미터(m)인지 소수로 나타내시오.",
        "question_en": "Woo-gyeong is 9 centimeters (cm) shorter than Eun-mi. If Woo-gyeong's height is 1 meter (m) and 35 centimeters (cm), how many meters (m) is Eun-mi's height expressed as a decimal number?",
        "answer_ko": "1.44",
        "answer_en": "1.44",
        "solution_abst_ko": "1 35 100 [OP_DIV] [OP_ADD] 9 100 [OP_DIV] [OP_ADD]",
        "solution_abst_en": "1 35 100 [OP_DIV] [OP_ADD] 9 100 [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 35\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 9\nvar_g = 100\nvar_h = var_f / var_g\nvar_i = var_e + var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 35\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 9\nvar_g = 100\nvar_h = var_f / var_g\nvar_i = var_e + var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "3288": {
        "category": "Geometry",
        "question_ko": "어떤 도형의 꼭지점의 수를 구하려고 합니다. 이 도형이 정육면체일 때 꼭지점의 수를 구하시오.",
        "question_en": "You are trying to find the number of vertices of a shape. If this figure is a cube, find the number of vertices.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "6 2 [OP_SUB] 2 [OP_MUL]",
        "solution_abst_en": "6 2 [OP_SUB] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "3289": {
        "category": "Arithmetic calculation",
        "question_ko": "설악산, 지리산, 한라산, 백두산이 있습니다. 지리산은 설악산보다 207미터(m) 더 높습니다. 한라산은 설악산보다 252미터(m) 더 높습니다. 백두산은 지리산보다 839미터(m) 더 높습니다. 설악산과 백두산의 높이의 차를 구하시오.",
        "question_en": "There are Seoraksan, Jirisan, Hallasan, and Baekdusan. Jirisan is 207 meters (m) higher than Seoraksan. Hallasan is 252 meters (m) higher than Seoraksan. Baekdusan is 839 meters (m) higher than Jirisan. Find the difference in height between Seoraksan and Baekdusan.",
        "answer_ko": "1046",
        "answer_en": "1046",
        "solution_abst_ko": "207 839 [OP_ADD]",
        "solution_abst_en": "207 839 [OP_ADD]",
        "solution_code_ko": "var_a = 207\nvar_b = 839\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 207\nvar_b = 839\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "3290": {
        "category": "Correspondence",
        "question_ko": "A를 9로 나누면 몫은 2이고 나머지는 6이 됩니다. A를 구하시오.",
        "question_en": "When A is divided by 9, the quotient is 2 and the remainder is 6. Find out the value of A.",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "9 2 [OP_MUL] 6 [OP_ADD]",
        "solution_abst_en": "9 2 [OP_MUL] 6 [OP_ADD]",
        "solution_code_ko": "var_a = 9\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3291": {
        "category": "Arithmetic calculation",
        "question_ko": "17개의 사탕, 19개의 사탕을 가진 주머니가 두개 있다. 9명에게 동일하게 사탕을 나누어 준다면 한 사람당 몇 개 가질 수 있는가?",
        "question_en": "There are 17 candies and two pouches with 19 candies. If you divide the candy equally among 9 people, how many can each person get?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "17 19 [OP_ADD] 9 [OP_FDIV]",
        "solution_abst_en": "17 19 [OP_ADD] 9 [OP_FDIV]",
        "solution_code_ko": "var_a = 17\nvar_b = 19\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 17\nvar_b = 19\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "3292": {
        "category": "Possibility",
        "question_ko": "1부터 9까지의 카드 중 하나를 뽑아서 21을 곱했을 때 84에 2를 곱한 값보다 커지는 경우의 수를 구하시오.",
        "question_en": "Find the number of ways in which a card numbered 1 through 9 is drawn and multiplied by 21 is greater than 84 multiplied by 2.",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "1 9 1 [OP_LIST_ARANGE] 84 2 [OP_MUL] 21 [OP_DIV] [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "1 9 1 [OP_LIST_ARANGE] 84 2 [OP_MUL] 21 [OP_DIV] [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 84\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = 21\nvar_h = var_f / var_g\nlist_b = []\nfor i in list_a:\n    if i > var_h:\n        list_b.append(i)\nvar_i = len(list_b)\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 84\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = 21\nvar_h = var_f / var_g\nlist_b = []\nfor i in list_a:\n    if i > var_h:\n        list_b.append(i)\nvar_i = len(list_b)\nprint(int(var_i))"
    },
    "3293": {
        "category": "Arithmetic calculation",
        "question_ko": "600부터 800까지의 짝수들의 집합에서 집합 내의 모든 수의 각 자리 숫자들의 합은 얼마인지 구하여라.",
        "question_en": "In the set of even numbers from 600 to 800, find the sum of the digits of all the numbers in the set.",
        "answer_ko": "1508",
        "answer_en": "1508",
        "solution_abst_ko": "600 800 2 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] [OP_LIST_SUM]",
        "solution_abst_en": "600 800 2 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 600\nvar_b = 800\nvar_c = 2\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_b=[]\nfor i in list_a:\n    var_d = 0\n    i = int(i)\n    while i//10 > 0:\n        var_d = var_d + i%10\n        i = i//10\n    var_d = var_d + i%10\n    list_b.append(var_d)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 600\nvar_b = 800\nvar_c = 2\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_b=[]\nfor i in list_a:\n    var_d = 0\n    i = int(i)\n    while i//10 > 0:\n        var_d = var_d + i%10\n        i = i//10\n    var_d = var_d + i%10\n    list_b.append(var_d)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint(int(var_e))"
    },
    "3294": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 6을 곱했더니 72가 되었습니다. 8을 어떤 수에 더하면 얼마가 되는지 구하시오.",
        "question_en": "When you multiply a number by 6, you get 72. What number do you get when you add 8 to the number?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "72 6 [OP_DIV] 8 [OP_ADD]",
        "solution_abst_en": "72 6 [OP_DIV] 8 [OP_ADD]",
        "solution_code_ko": "var_a = 72\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 8\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 72\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 8\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3295": {
        "category": "Comparison",
        "question_ko": "(가) 장난감은 (나) 보다 크지만 (다) 보다는 작습니다. (나) 장난감이 (라) 장난감보다 크고 (다) 장난감이 (마) 장난감보다 작다면 가장 큰 장난감은 무엇입니까?",
        "question_en": "While Toy (A) is larger than (B), it is smaller than (C). If Toy (B) is bigger than Toy (D) and Toy (C) is smaller than Toy (E), which toy is the biggest?",
        "answer_ko": "(마)",
        "answer_en": "(E)",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) (다) (라) (마) [OP_LIST_EOL] [OP_LIST_SOL] (가) (나) > (가) (다) < (나) (라) > (다) (마) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (A) (B) (C) (D) (E) [OP_LIST_EOL] [OP_LIST_SOL] (A) (B) > (A) (C) < (B) (D) > (C) (E) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nvar_c = '(다)'\nvar_d = '(라)'\nvar_e = '(마)'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = '(가)'\nvar_g = '(나)'\nvar_h = '>'\nvar_i = '(가)'\nvar_j = '(다)'\nvar_k = '<'\nvar_l = '(나)'\nvar_m = '(라)'\nvar_n = '>'\nvar_o = '(다)'\nvar_p = '(마)'\nvar_q = '<'\nlist_b= []\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_r = 1\nvar_s = list_c[var_r-1]\nprint(var_s)",
        "solution_code_en": "var_a = '(A)'\nvar_b = '(B)'\nvar_c = '(C)'\nvar_d = '(D)'\nvar_e = '(E)'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = '(A)'\nvar_g = '(B)'\nvar_h = '>'\nvar_i = '(A)'\nvar_j = '(C)'\nvar_k = '<'\nvar_l = '(B)'\nvar_m = '(D)'\nvar_n = '>'\nvar_o = '(C)'\nvar_p = '(E)'\nvar_q = '<'\nlist_b= []\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_r = 1\nvar_s = list_c[var_r-1]\nprint(var_s)"
    },
    "3296": {
        "category": "Geometry",
        "question_ko": "민영이는 넓이가 400제곱센티미터인 정사각형 안에 그릴 수 있는 가장 큰 원을 그렸습니다. 원주율이 3.1일 때 민영이가 그린 원의 넓이는 몇 제곱센티미터입니까?",
        "question_en": "Minyeong has drawn the largest circle that can be drawn inside a square with an area of 400 square centimeters (cm2). If pi is 3.1, how many square centimeters (cm2) is the area of the circle Minyeong drew?",
        "answer_ko": "310",
        "answer_en": "310",
        "solution_abst_ko": "3.1 400 1/2 [OP_POW] 2 [OP_DIV] 2 [OP_POW] [OP_MUL]",
        "solution_abst_en": "3.1 400 1/2 [OP_POW] 2 [OP_DIV] 2 [OP_POW] [OP_MUL]",
        "solution_code_ko": "var_a = 3.1\nvar_b = 400\nvar_c = 0.5\nvar_d = var_b ** var_c\nvar_e = 2\nvar_f = var_d / var_e\nvar_g = 2\nvar_h = var_f ** var_g\nvar_i = var_a * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 3.1\nvar_b = 400\nvar_c = 0.5\nvar_d = var_b ** var_c\nvar_e = 2\nvar_f = var_d / var_e\nvar_g = 2\nvar_h = var_f ** var_g\nvar_i = var_a * var_h\nprint(int(var_i))"
    },
    "3297": {
        "category": "Geometry",
        "question_ko": "52센티미터(㎝)의 철사로 사각형을 만듭니다. 만들 수 있는 사각형의 최대 넓이는 얼마입니까?",
        "question_en": "Make a rectangle out of a wire that is 52 centimeters (cm) long. What is the maximum area of a rectangle that can be made?",
        "answer_ko": "169",
        "answer_en": "169",
        "solution_abst_ko": "52 4 [OP_DIV] 2 [OP_POW]",
        "solution_abst_en": "52 4 [OP_DIV] 2 [OP_POW]",
        "solution_code_ko": "var_a = 52\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 52\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint(int(var_e))"
    },
    "3298": {
        "category": "Comparison",
        "question_ko": "석진이네 교실에는 가로, 세로 각 줄의 책상 수가 같게 사각형 모양으로 놓여 있습니다. 석진이의 자리는 앞에서 3번째, 뒤에서 5번째, 오른쪽에서 4번째, 왼쪽에서 2번째에 있습니다. 석진이네 교실의 책상은 모두 몇 개입니까?",
        "question_en": "In Seokjin's classroom, the number of desks in each row, both horizontally and vertically, is placed in a square shape. Seokjin's seat is 3rd from the front, 5th from the back, 4th from the right, and 2nd from the left. How many desks are there in Seokjin's classroom?",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "3 5 [OP_ADD] 1 [OP_SUB] 4 2 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "3 5 [OP_ADD] 1 [OP_SUB] 4 2 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 4\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 3\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 4\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))"
    },
    "3299": {
        "category": "Correspondence",
        "question_ko": "다섯 자리 수 ABCDE와 3의 곱은 111111입니다. A, B, C, D, E의 합을 구하시오.",
        "question_en": "The multiplication of the five-digit number ABCDE and 3 is 111111. Find the sum of A, B, C, D, and E.",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "111111 3 [OP_DIV] [OP_NUM2LIST] [OP_LIST_SUM]",
        "solution_abst_en": "111111 3 [OP_DIV] [OP_NUM2LIST] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 111111\nvar_b = 3\nvar_c = var_a / var_b\nlist_a = []\nvar_c = int(var_c)\nwhile var_c//10 > 0:\n    list_a.append(var_c%10)\n    var_c = var_c//10\nlist_a.append(var_c%10)\nlist_a = list_a[::-1]\nlist_a = [float(i) for i in list_a]\nvar_d = sum(list_a)\nprint(int(var_d))",
        "solution_code_en": "var_a = 111111\nvar_b = 3\nvar_c = var_a / var_b\nlist_a = []\nvar_c = int(var_c)\nwhile var_c//10 > 0:\n    list_a.append(var_c%10)\n    var_c = var_c//10\nlist_a.append(var_c%10)\nlist_a = list_a[::-1]\nlist_a = [float(i) for i in list_a]\nvar_d = sum(list_a)\nprint(int(var_d))"
    },
    "3300": {
        "category": "Arithmetic calculation",
        "question_ko": "다섯 자리 수 중 9, 6, 2의 공배수 중 가장 큰 수는?",
        "question_en": "Which of the five-digit numbers is the greatest common multiple of 9, 6, and 2?",
        "answer_ko": "99990",
        "answer_en": "99990",
        "solution_abst_ko": "10000 99999 1 [OP_LIST_ARANGE] 9 [OP_LIST_DIVISIBLE] 6 [OP_LIST_DIVISIBLE] 2 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_abst_en": "10000 99999 1 [OP_LIST_ARANGE] 9 [OP_LIST_DIVISIBLE] 6 [OP_LIST_DIVISIBLE] 2 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 10000\nvar_b = 99999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 9\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 6\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 2\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_h = list_e[-var_g]\nprint(int(var_h))",
        "solution_code_en": "var_a = 10000\nvar_b = 99999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 9\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 6\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 2\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_h = list_e[-var_g]\nprint(int(var_h))"
    },
    "3301": {
        "category": "Comparison",
        "question_ko": "(가), (나), (다), (라)라는 4명의 어린이가 달리기 시합을 합니다. (다)는 (나)보다 빠르고 (나)는 (라)보다 느립니다. (라)가 (가)보다 느리고 (다)는 (라)보다 느릴 때 가장 느린 어린이는 누구입니까?",
        "question_en": "Four children (a), (b), (c), and (d) are competing in a running race. (c) is faster than (b) and (b) is slower than (d). If (d) is slower than (a) and (c) is slower than (d), which child is the slowest?",
        "answer_ko": "(나)",
        "answer_en": "(b)",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) (다) (라) [OP_LIST_EOL] [OP_LIST_SOL] (가) (라) > (다) (라) < (라) (나) > (나) (다) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (a) (b) (c) (d) [OP_LIST_EOL] [OP_LIST_SOL] (a) (d) > (c) (d) < (d) (b) > (b) (c) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nvar_c = '(다)'\nvar_d = '(라)'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '(가)'\nvar_f = '(라)'\nvar_g = '>'\nvar_h = '(다)'\nvar_i = '(라)'\nvar_j = '<'\nvar_k = '(라)'\nvar_l = '(나)'\nvar_m = '>'\nvar_n = '(나)'\nvar_o = '(다)'\nvar_p = '<'\nlist_b= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_q = len(list_c)\nvar_r = list_c[var_q-1]\nprint(var_r)",
        "solution_code_en": "var_a = '(a)'\nvar_b = '(b)'\nvar_c = '(c)'\nvar_d = '(d)'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '(a)'\nvar_f = '(d)'\nvar_g = '>'\nvar_h = '(c)'\nvar_i = '(d)'\nvar_j = '<'\nvar_k = '(d)'\nvar_l = '(b)'\nvar_m = '>'\nvar_n = '(b)'\nvar_o = '(c)'\nvar_p = '<'\nlist_b= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_q = len(list_c)\nvar_r = list_c[var_q-1]\nprint(var_r)"
    },
    "3302": {
        "category": "Arithmetic calculation",
        "question_ko": "줄넘기를 하는 학생의 4배 만큼 농구를 하고 있습니다. 줄넘기를 하는 학생 수가 6명이라면 농구를 하는 학생 수는 몇 명입니까?",
        "question_en": "Students playing basketball are four times as much as students jumping rope. If the number of students jumping rope is 6, how many students are playing basketball?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "6 4 [OP_MUL]",
        "solution_abst_en": "6 4 [OP_MUL]",
        "solution_code_ko": "var_a = 6\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "3303": {
        "category": "Arithmetic calculation",
        "question_ko": "너비가 27.9미터(m)인 텃밭에 3.1미터(m) 간격으로 나무를 심으려고 합니다. 나무를 몇 그루 심을 수 있는 지 구하시오. 단, 나무의 두께는 생각하지 않습니다.",
        "question_en": "You want to plant trees at intervals of 3.1 meters (m) in a garden with a width of 27.9 meters (m). Find how many trees you can plant. However, the thickness of the wood is not considered.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "27.9 3.1 [OP_FDIV] 1 [OP_ADD]",
        "solution_abst_en": "27.9 3.1 [OP_FDIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 27.9\nvar_b = 3.1\nvar_c = var_a // var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 27.9\nvar_b = 3.1\nvar_c = var_a // var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3304": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 4를 곱하였더니 166.08이 되었습니다. 어떤 수를 4로 나눈 값이 얼마인지 구하시오.",
        "question_en": "When you multiply a number by 4, you get 166.08. What is the value of a number divided by 4?",
        "answer_ko": "10.38",
        "answer_en": "10.38",
        "solution_abst_ko": "166.08 4 [OP_DIV] 4 [OP_DIV]",
        "solution_abst_en": "166.08 4 [OP_DIV] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 166.08\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 166.08\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "3305": {
        "category": "Correspondence",
        "question_ko": "호석이는 56에 어떤 수를 더해 110을 얻었습니다. 어떤 수를 구하시오.",
        "question_en": "Hoseok added a number to 56 and got 110. Find the number.",
        "answer_ko": "54",
        "answer_en": "54",
        "solution_abst_ko": "110 56 [OP_SUB]",
        "solution_abst_en": "110 56 [OP_SUB]",
        "solution_code_ko": "var_a = 110\nvar_b = 56\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 110\nvar_b = 56\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "3306": {
        "category": "Correspondence",
        "question_ko": "63+68A=748입니다. A는 얼마인가요?",
        "question_en": "63+68A=748. How much is single-digit number A?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "63+68A=748 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "63+68A=748 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '63+68A=748'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '63+68A=748'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "3307": {
        "category": "Comparison",
        "question_ko": "3개의 숫자 0.8, 1/2, 9가 있습니다. 2보다 큰 수 중 가장 작은 수는 얼마인가요?",
        "question_en": "When there are three numbers: 0.8, 1/2, and 9, what would be the smallest one among the numbers that are greater than 2?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 9 [OP_LIST_EOL] 2 [OP_LIST_MORE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 9 [OP_LIST_EOL] 2 [OP_LIST_MORE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nprint(int(var_f))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nprint(int(var_f))"
    },
    "3308": {
        "category": "Comparison",
        "question_ko": "윤기는 4, 유나는 5, 정국이는 6에서 3을 나눈 몫을 모았습니다. 누가 가장 작은 수를 모았습니까?",
        "question_en": "Yoongi got 4, Yuna 5, and Jungkook got the quotient of 6 divided by 3. Who got the smallest number?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 유나 정국 [OP_LIST_EOL] [OP_LIST_SOL] 4 5 6 3 [OP_FDIV] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Yuna Jungkook [OP_LIST_EOL] [OP_LIST_SOL] 4 5 6 3 [OP_FDIV] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '유나'\nvar_c = '정국'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 5\nvar_f = 6\nvar_g = 3\nvar_h = var_f // var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Yuna'\nvar_c = 'Jungkook'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 5\nvar_f = 6\nvar_g = 3\nvar_h = var_f // var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "3309": {
        "category": "Arithmetic calculation",
        "question_ko": "민주네 반 학생 30명은 1번부터 30번까지 자신의 출석 번호를 가지고 있습니다. 민주네 반 학생 중 키가 160센티미터(㎝) 이상인 학생은 1번, 3번, 7번, 10번, 23번, 27번 학생이고, 몸무게가 50킬로그램(㎏) 이상인 학생은 1번, 9번, 11번, 20번, 23번 학생일 때, 키가 160센티미터(㎝) 이상이거나 몸무게가 50킬로그램(㎏) 이상인 학생은 몇 명입니까?",
        "question_en": "30 students in Minju's class have their own attendance numbers from 1 to 30. Among the students in Minju's class, students who are 160 centimeters (cm) or taller are students 1, 3, 7, 10, 23, and 27, and students who weigh 50 kilograms (kg) or more are students 1, 9, 11, 20, and 23. How many students are 160 centimeters (cm) or taller or 50 kilograms (kg) or heavier?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 7 10 23 27 [OP_LIST_EOL] [OP_LIST_SOL] 1 9 11 20 23 [OP_LIST_EOL] [OP_SET_UNION] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 7 10 23 27 [OP_LIST_EOL] [OP_LIST_SOL] 1 9 11 20 23 [OP_LIST_EOL] [OP_SET_UNION] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 7\nvar_d = 10\nvar_e = 23\nvar_f = 27\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 1\nvar_h = 9\nvar_i = 11\nvar_j = 20\nvar_k = 23\nlist_b= []\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nlist_c = list(set(list_a) | set(list_b))\nvar_l = len(list_c)\nprint(int(var_l))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 7\nvar_d = 10\nvar_e = 23\nvar_f = 27\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 1\nvar_h = 9\nvar_i = 11\nvar_j = 20\nvar_k = 23\nlist_b= []\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nlist_c = list(set(list_a) | set(list_b))\nvar_l = len(list_c)\nprint(int(var_l))"
    },
    "3310": {
        "category": "Correspondence",
        "question_ko": "박스 안에 노란색, 파란색 구슬이 섞여있습니다. 박스 안에 구슬이 총 913개가 있고, 노란색 구슬의 개수는 514개입니다. 노란색 구슬이 파란색 구슬보다 몇 개 더 많은지 구하시오.",
        "question_en": "yellow and blue marbles are mixed in the box. There are a total of 913 marbles in the box, and the number of yellow marbles is 514. Find how many yellow marbles are more than blue marbles.",
        "answer_ko": "115",
        "answer_en": "115",
        "solution_abst_ko": "514 913 514 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "514 913 514 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 514\nvar_b = 913\nvar_c = 514\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 514\nvar_b = 913\nvar_c = 514\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "3311": {
        "category": "Geometry",
        "question_ko": "재웅이 반의 학생들을 가로와 세로 모두 10명씩 정사각형 모양으로 줄세웠습니다. 둘레에 있는 학생은 모두 몇 명인가요?",
        "question_en": "Jaewoong lined up the students in the class in a square shape with 10 people on each row and column. How many students are at the perimeter?",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "10 4 [OP_MUL] 4 [OP_SUB]",
        "solution_abst_en": "10 4 [OP_MUL] 4 [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3312": {
        "category": "Arithmetic calculation",
        "question_ko": "감과 귤이 모두 합해서 129개 있습니다. 감이 귤보다 43개 더 적다면 감은 몇 개 있습니까?",
        "question_en": "There are a total of 129 persimmons and tangerines. How many persimmons are there if there are 43 fewer persimmons than tangerines?",
        "answer_ko": "43",
        "answer_en": "43",
        "solution_abst_ko": "129 43 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "129 43 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 129\nvar_b = 43\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 129\nvar_b = 43\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "3313": {
        "category": "Geometry",
        "question_ko": "부피가 1380000000세제곱센티미터(㎤)인 직육면체가 있습니다. 밑면의 표면적이 115제곱미터(㎡)인 경우 직육면체의 높이는 몇 미터(m)입니까?",
        "question_en": "There is a cuboid with a volume of 1380000000 cubic centimeters (cm3). What is the height of the cuboid in meters (m), if the surface area of its base is 115 square meters (m2)?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "1380000000 100 3 [OP_POW] [OP_DIV] 115 [OP_DIV]",
        "solution_abst_en": "1380000000 100 3 [OP_POW] [OP_DIV] 115 [OP_DIV]",
        "solution_code_ko": "var_a = 1380000000\nvar_b = 100\nvar_c = 3\nvar_d = var_b ** var_c\nvar_e = var_a / var_d\nvar_f = 115\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1380000000\nvar_b = 100\nvar_c = 3\nvar_d = var_b ** var_c\nvar_e = var_a / var_d\nvar_f = 115\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "3314": {
        "category": "Arithmetic calculation",
        "question_ko": "기름 19리터(L)를 자동차는 9킬로미터(㎞)가는 동안 쓰려고 합니다. 1킬로미터(㎞)마다 써야할 기름은 몇 리터(L)인지 구하시오.",
        "question_en": "The car will spend 19 liters (l) of gas while traveling 9 kilometers (km). Find how many liters (l) of gas should be spent per 1 kilometer (km).",
        "answer_ko": "2.11",
        "answer_en": "2.11",
        "solution_abst_ko": "19 9 [OP_DIV]",
        "solution_abst_en": "19 9 [OP_DIV]",
        "solution_code_ko": "var_a = 19\nvar_b = 9\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 19\nvar_b = 9\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "3315": {
        "category": "Geometry",
        "question_ko": "어떤 직사각형 모양의 벽의 가로의 길이를 30센티미터(㎝)로 나누면 8로 나누어떨어지고 세로의 길이를 30센티미터(㎝)로 나누면 5로 나누어 떨어진다. 벽의 크기는 몇 제곱미터(㎡)인지 구하시오.",
        "question_en": "If you divide the width of a rectangular wall by 30 centimeters (cm), it is divided by 8, and if you divide the height by 30 centimeters (cm), it is divided by 5. Find the size of the wall in square meters (m2).",
        "answer_ko": "3.60",
        "answer_en": "3.6",
        "solution_abst_ko": "30 100 [OP_DIV] 2 [OP_POW] 8 [OP_MUL] 5 [OP_MUL]",
        "solution_abst_en": "30 100 [OP_DIV] 2 [OP_POW] 8 [OP_MUL] 5 [OP_MUL]",
        "solution_code_ko": "var_a = 30\nvar_b = 100\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 8\nvar_g = var_e * var_f\nvar_h = 5\nvar_i = var_g * var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 30\nvar_b = 100\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 8\nvar_g = var_e * var_f\nvar_h = 5\nvar_i = var_g * var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "3316": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 20센티미터(㎝)인 정사각형을 밑면으로 갖는 높이 20센티미터(㎝)의 어항에 높이 15센티미터(㎝)만큼의 물을 채워두었다. 이 어항에 한 모서리의 길이가 10센티미터(㎝)인 정육면체 모양의 통에 담겨있는 물을 붓게 되면 물의 높이는 몇 센티미터(㎝) 높아지는지 소수점을 포함하여 구하라.",
        "question_en": "A 20 centimeters (cm) high fishbowl, with a square base and sides of 20 centimeters (cm) has been filled with water a height of 15 centimeters (cm). If you pour water into this fishbowl from a cube-shaped container with an edge of 10 centimeters (cm), how high in centimeters (cm) will the water rise compared to the height before you poured the water in? Find the answer, including the decimal point.",
        "answer_ko": "2.50",
        "answer_en": "2.5",
        "solution_abst_ko": "10 10 [OP_MUL] 10 [OP_MUL] 20 20 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "10 10 [OP_MUL] 10 [OP_MUL] 20 20 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 10\nvar_e = var_c * var_d\nvar_f = 20\nvar_g = 20\nvar_h = var_f * var_g\nvar_i = var_e / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 10\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 10\nvar_e = var_c * var_d\nvar_f = 20\nvar_g = 20\nvar_h = var_f * var_g\nvar_i = var_e / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "3317": {
        "category": "Arithmetic calculation",
        "question_ko": "5의 배수이면서 8의 배수이면서 2의 배수인 수 중 가장 작은 세 자리 수는 무엇입니까?",
        "question_en": "What is the smallest three-digit number that is a multiple of 5 and a multiple of 8 and a multiple of 2?",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "100 999 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 2 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "100 999 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 2 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 8\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 2\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_h = list_e[var_g-1]\nprint(int(var_h))",
        "solution_code_en": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 8\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 2\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_h = list_e[var_g-1]\nprint(int(var_h))"
    },
    "3318": {
        "category": "Correspondence",
        "question_ko": "윤기는 세 자리 수와 두 자리 수의 덧셈을 하려 합니다. 윤기는 세 자리 수의 일의 자리 숫자 9를 6으로 잘못 보았고, 두 자리 수의 십의 자리 숫자와 일의 자리 숫자를 바꾸어 23이라고 잘못 보았습니다. 윤기가 구한 합은 299 일 때, 세 자리 수를 구하시오.",
        "question_en": "Yoongi wants to add a three-digit number and a two-digit number. Yoongi mistakenly thought the 9 in the unit digit of a three-digit number was 6, and by changing the tens and unit digits of a two-digit number, he mistakenly thought it was 23. When the sum obtained by Yoongi is 299, find the three-digit number.",
        "answer_ko": "279",
        "answer_en": "279",
        "solution_abst_ko": "299 23 [OP_SUB] 6 9 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "299 23 [OP_SUB] 6 9 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 299\nvar_b = 23\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 299\nvar_b = 23\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "3319": {
        "category": "Comparison",
        "question_ko": "소라, 희수, 지연이가 있다. 소라는 4와 6이 적힌 카드를, 희수는 7과 5가 적힌 카드를, 지연이는 3과 8이 적힌 카드를 가지고 있다. 카드의 합이 가장 큰 사람은 누구인가?",
        "question_en": "There are Sora, Heesu, and Jiyeon. Sora has cards with 4 and 6 written on them, Heesu has cards with 7 and 5 written on them, and Jiyeon has cards with 3 and 8 written on them. Who has the greatest sum of cards?",
        "answer_ko": "희수",
        "answer_en": "Heesu",
        "solution_abst_ko": "[OP_LIST_SOL] 소라 희수 지연 [OP_LIST_EOL] [OP_LIST_SOL] 4 6 [OP_ADD] 7 5 [OP_ADD] 3 8 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Sora Heesu Jiyeon [OP_LIST_EOL] [OP_LIST_SOL] 4 6 [OP_ADD] 7 5 [OP_ADD] 3 8 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '소라'\nvar_b = '희수'\nvar_c = '지연'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 6\nvar_f = var_d + var_e\nvar_g = 7\nvar_h = 5\nvar_i = var_g + var_h\nvar_j = 3\nvar_k = 8\nvar_l = var_j + var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'Sora'\nvar_b = 'Heesu'\nvar_c = 'Jiyeon'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 6\nvar_f = var_d + var_e\nvar_g = 7\nvar_h = 5\nvar_i = var_g + var_h\nvar_j = 3\nvar_k = 8\nvar_l = var_j + var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "3320": {
        "category": "Arithmetic calculation",
        "question_ko": "장미가 48송이 있습니다. 빨간색 장미는 전체의 3/8입니다. 노란색 장미는 전체의 5/16입니다. 빨간색 장미는 노란색 장미보다 몇 송이 더 많습니까?",
        "question_en": "There are 48 roses. The red rose is 3/8 of the total. Yellow roses are 5/16 of the total. How many more red roses are there than yellow roses?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "48 3/8 [OP_MUL] 48 5/16 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "48 3/8 [OP_MUL] 48 5/16 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 48\nvar_b = 0.375\nvar_c = var_a * var_b\nvar_d = 48\nvar_e = 0.3125\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 48\nvar_b = 0.375\nvar_c = var_a * var_b\nvar_d = 48\nvar_e = 0.3125\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "3321": {
        "category": "Correspondence",
        "question_ko": "네 자리 수와 세 자리 수의 뺄셈식 AB82-9C9=493D이고 A, B, C, D가 서로 다른 수일 때, A를 구하시오",
        "question_en": "If AB82-9C9=493D and A, B, C, D are different numbers, find A.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "AB82-9C9=493D A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "AB82-9C9=493D A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'AB82-9C9=493D'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'AB82-9C9=493D'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "3322": {
        "category": "Comparison",
        "question_ko": "유미네 농장에 있는 닭과 돼지의 다리 수의 합은 48개입니다. 농장에 돼지가 9마리 있다면 닭은 몇 마리인지 구하시오.",
        "question_en": "The sum of the legs of chickens and pigs in Yumi's farm is 48. If there are 9 pigs on the farm, how many chickens are there?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "48 4 9 [OP_MUL] [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "48 4 9 [OP_MUL] [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 48\nvar_b = 4\nvar_c = 9\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 48\nvar_b = 4\nvar_c = 9\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "3323": {
        "category": "Geometry",
        "question_ko": "한 변이 20센티미터(㎝)인 정사각형 모양의 색종이가 있습니다. 각 변의 길이를 3등분하여 작은 색종이로 오려냈습니다. 새롭게 만들어진 작은 색종이의 넓이를 소수점 둘째 자리까지 구하시오.",
        "question_en": "There is a piece of colored paper in the shape of a square with sides of 20 centimeters (cm). I divided the length of each side into thirds and cut them out with small pieces of colored paper. Find the area of the newly created small colored paper to two decimal places.",
        "answer_ko": "44.44",
        "answer_en": "44.44",
        "solution_abst_ko": "20 3 [OP_DIV] 2 [OP_POW]",
        "solution_abst_en": "20 3 [OP_DIV] 2 [OP_POW]",
        "solution_code_ko": "var_a = 20\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 20\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "3324": {
        "category": "Comparison",
        "question_ko": "앞에 숫자를 놓을 수 있는 4개의 칸이 있습니다. 각 칸에 놓인 숫자에 1, 0.1, 0.001을 곱하여 더한 값을 나타냅니다. 차례대로 4, 2, 7을 놓았을 때, 화면에 등장한 수의 100배보다 0.05 큰 수는 얼마입니까?",
        "question_en": "There are 4 cells in front of you in which you can place numbers. The sum of each number multiplied by 1, 0.1, and 0.001 respectively is displayed. When 4, 2, and 7 is placed in that order, what is the number 0.05 greater than 100 times the number dsplayed on the monitor?",
        "answer_ko": "420.75",
        "answer_en": "420.75",
        "solution_abst_ko": "1 4 [OP_MUL] 0.1 2 [OP_MUL] [OP_ADD] 0.001 7 [OP_MUL] [OP_ADD] 100 [OP_MUL] 0.05 [OP_ADD]",
        "solution_abst_en": "1 4 [OP_MUL] 0.1 2 [OP_MUL] [OP_ADD] 0.001 7 [OP_MUL] [OP_ADD] 100 [OP_MUL] 0.05 [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 0.1\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 0.001\nvar_i = 7\nvar_j = var_h * var_i\nvar_k = var_g + var_j\nvar_l = 100\nvar_m = var_k * var_l\nvar_n = 0.05\nvar_o = var_m + var_n\nprint('{:.2f}'.format(round(var_o+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 0.1\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 0.001\nvar_i = 7\nvar_j = var_h * var_i\nvar_k = var_g + var_j\nvar_l = 100\nvar_m = var_k * var_l\nvar_n = 0.05\nvar_o = var_m + var_n\nprint('{:.2f}'.format(round(var_o+1e-10,2)))"
    },
    "3325": {
        "category": "Correspondence",
        "question_ko": "다섯 자리 수 3A3B3은 33의 배수이다. 가능한 B는 몇 개입니까?",
        "question_en": "The five digit number 3A3B3 is a multiple of 33. How many possible Bs are there?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "3A3B3 [OP_GEN_POSSIBLE_LIST] 33 [OP_LIST_DIVISIBLE] 3A3B3 B [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_abst_en": "3A3B3 [OP_GEN_POSSIBLE_LIST] 33 [OP_LIST_DIVISIBLE] 3A3B3 B [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '3A3B3'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 33\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = '3A3B3'\nvar_d = 'B'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nvar_e = len(list_c)\nprint(int(var_e))",
        "solution_code_en": "var_a = '3A3B3'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 33\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = '3A3B3'\nvar_d = 'B'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nvar_e = len(list_c)\nprint(int(var_e))"
    },
    "3326": {
        "category": "Arithmetic calculation",
        "question_ko": "12장의 색종이를 사용하여 학을 접었더니 9장이 남았습니다. 처음에 있던 색종이는 몇 장입니까?",
        "question_en": "You folded the crane using 12 sheets of colored paper, and at the end, only 9 sheets left. Find how many sheets were prepared at the beginning.",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "12 9 [OP_ADD]",
        "solution_abst_en": "12 9 [OP_ADD]",
        "solution_code_ko": "var_a = 12\nvar_b = 9\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 12\nvar_b = 9\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "3327": {
        "category": "Geometry",
        "question_ko": "어떤 정사각형 모양의 색종이를 가로가 5센티미터(㎝), 세로가 7센티미터(㎝)인 직사각형 여러 개로 조각을 내었습니다. 이 때 정사각형 한 변의 최소 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "A square-shaped piece of colored paper was cut into several rectangles measuring 5 centimeters (cm) wide and 7 centimeters (cm) long. What is the minimum length in centimeters (cm) of one side of the square?",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "5 7 [OP_LCM]",
        "solution_abst_en": "5 7 [OP_LCM]",
        "solution_code_ko": "var_a = 5\nvar_b = 7\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 7\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nprint(int(var_c))"
    },
    "3328": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 48을 더해야 하는데 잘못하여 뺐더니 52가 되었습니다. 바르게 계산한 결과를 구하시오.",
        "question_en": "You had to add 48 to a number, but you mistakenly subtract it, and the result was 52. Find the result of the correct calculation.",
        "answer_ko": "148",
        "answer_en": "148",
        "solution_abst_ko": "52 48 [OP_ADD] 48 [OP_ADD]",
        "solution_abst_en": "52 48 [OP_ADD] 48 [OP_ADD]",
        "solution_code_ko": "var_a = 52\nvar_b = 48\nvar_c = var_a + var_b\nvar_d = 48\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 52\nvar_b = 48\nvar_c = var_a + var_b\nvar_d = 48\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3329": {
        "category": "Geometry",
        "question_ko": "모든 변의 길이와, 모든 각의 크기가 같고 변이 18개인 도형의 대각선 개수를구하시오.",
        "question_en": "Find the number of diagonals in an 18-sided figure with all side lengths and all angles equal in measure.",
        "answer_ko": "135",
        "answer_en": "135",
        "solution_abst_ko": "18 18 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "18 18 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 18\nvar_b = 18\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 18\nvar_b = 18\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "3330": {
        "category": "Possibility",
        "question_ko": "울타리 안에 3마리의 거위가 있습니다. 만약 거위들에게 모두 2개 이상의 대나무를 준다고 한다면, 대나무 20개를 나누어 주는 방법은 몇 가지인지 구하시오.",
        "question_en": "There are 3 geese inside the fence. If all geese are given more than 2 bamboos, how many ways are there to distribute 20 bamboos?",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "3 20 [OP_ADD] 3 2 [OP_MUL] [OP_SUB] 1 [OP_SUB] 20 3 2 [OP_MUL] [OP_SUB] [OP_COMB]",
        "solution_abst_en": "3 20 [OP_ADD] 3 2 [OP_MUL] [OP_SUB] 1 [OP_SUB] 20 3 2 [OP_MUL] [OP_SUB] [OP_COMB]",
        "solution_code_ko": "var_a = 3\nvar_b = 20\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = 20\nvar_k = 3\nvar_l = 2\nvar_m = var_k * var_l\nvar_n = var_j - var_m\nvar_o = 1\nvar_i = int(var_i)\nvar_n = int(var_n)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o * (var_i-i)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o / (i+1)\nprint(int(var_o))",
        "solution_code_en": "var_a = 3\nvar_b = 20\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = 20\nvar_k = 3\nvar_l = 2\nvar_m = var_k * var_l\nvar_n = var_j - var_m\nvar_o = 1\nvar_i = int(var_i)\nvar_n = int(var_n)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o * (var_i-i)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o / (i+1)\nprint(int(var_o))"
    },
    "3331": {
        "category": "Geometry",
        "question_ko": "육각형에서 그을 수 있는 대각선의 총 개수는?",
        "question_en": "What is the total number of diagonals that can be drawn in a hexagon?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "6 6 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "6 6 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 6\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 6\nvar_b = 6\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "3332": {
        "category": "Correspondence",
        "question_ko": "A는 한 자리 수입니다. 73A94를 백의 자리에서 반올림하면 74000을 얻을 수 있습니다. A가 될 수 있는 모든 숫자의 개수를 구하시오.",
        "question_en": "A is a single digit number. Rounding 73A94 to the nearest thousand gives it 74000. Find the number of all possible numbers in A.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "73A94 [OP_GEN_POSSIBLE_LIST] 74000 500 [OP_ADD] [OP_LIST_LESS] 74000 500 [OP_SUB] [OP_LIST_MORE_EQUAL] 73A94 A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_abst_en": "73A94 [OP_GEN_POSSIBLE_LIST] 74000 500 [OP_ADD] [OP_LIST_LESS] 74000 500 [OP_SUB] [OP_LIST_MORE_EQUAL] 73A94 A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '73A94'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 74000\nvar_c = 500\nvar_d = var_b + var_c\nlist_b = []\nfor i in list_a:\n    if i < var_d:\n        list_b.append(i)\nvar_e = 74000\nvar_f = 500\nvar_g = var_e - var_f\nlist_c = []\nfor i in list_b:\n    if i >= var_g:\n        list_c.append(i)\nvar_h = '73A94'\nvar_i = 'A'\nvar_h = str(var_h)\nvar_i = str(var_i)\nunk_idx = var_h.index(var_i)\nlist_d = []\nfor elem in list_c:\n    elem = str(elem)\n    list_d.append(int(elem[unk_idx]))\nlist_d = list(set(list_d))\nvar_j = len(list_d)\nprint(int(var_j))",
        "solution_code_en": "var_a = '73A94'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 74000\nvar_c = 500\nvar_d = var_b + var_c\nlist_b = []\nfor i in list_a:\n    if i < var_d:\n        list_b.append(i)\nvar_e = 74000\nvar_f = 500\nvar_g = var_e - var_f\nlist_c = []\nfor i in list_b:\n    if i >= var_g:\n        list_c.append(i)\nvar_h = '73A94'\nvar_i = 'A'\nvar_h = str(var_h)\nvar_i = str(var_i)\nunk_idx = var_h.index(var_i)\nlist_d = []\nfor elem in list_c:\n    elem = str(elem)\n    list_d.append(int(elem[unk_idx]))\nlist_d = list(set(list_d))\nvar_j = len(list_d)\nprint(int(var_j))"
    },
    "3333": {
        "category": "Arithmetic calculation",
        "question_ko": "석진이는 나눗셈을 하는 과정에서 나누는 수 65의 십의 자리 숫자와 일의 자리 숫자를 바꾸어 잘못 보고 계산하였더니 계산한 몫과 나머지가 각각 25이었습니다. 바르게 계산한 몫과 나머지의 합을 구하시오.",
        "question_en": "When Seokjin was doing a division, he misread the tens digit and units digit of the divisor 65 as the opposite to get the quotient of division 25, and the remainder also 25. Find the sum of the correctly calculated quotient and remainder.",
        "answer_ko": "81",
        "answer_en": "81",
        "solution_abst_ko": "56 25 [OP_MUL] 25 [OP_ADD] 65 [OP_FDIV] 56 25 [OP_MUL] 25 [OP_ADD] 65 [OP_MOD] [OP_ADD]",
        "solution_abst_en": "56 25 [OP_MUL] 25 [OP_ADD] 65 [OP_FDIV] 56 25 [OP_MUL] 25 [OP_ADD] 65 [OP_MOD] [OP_ADD]",
        "solution_code_ko": "var_a = 56\nvar_b = 25\nvar_c = var_a * var_b\nvar_d = 25\nvar_e = var_c + var_d\nvar_f = 65\nvar_g = var_e // var_f\nvar_h = 56\nvar_i = 25\nvar_j = var_h * var_i\nvar_k = 25\nvar_l = var_j + var_k\nvar_m = 65\nvar_n = var_l % var_m\nvar_o = var_g + var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 56\nvar_b = 25\nvar_c = var_a * var_b\nvar_d = 25\nvar_e = var_c + var_d\nvar_f = 65\nvar_g = var_e // var_f\nvar_h = 56\nvar_i = 25\nvar_j = var_h * var_i\nvar_k = 25\nvar_l = var_j + var_k\nvar_m = 65\nvar_n = var_l % var_m\nvar_o = var_g + var_n\nprint(int(var_o))"
    },
    "3334": {
        "category": "Arithmetic calculation",
        "question_ko": "12마리의 흰색 토끼와 9마리의 검은색 토끼가 있습니다. 그중에서 8마리가 암컷 토끼일 때 수컷 토끼는 몇 마리입니까?",
        "question_en": "There are 12 white rabbits and 9 black rabbits. If 8 of them are females, how many male rabbits are there?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "12 9 [OP_ADD] 8 [OP_SUB]",
        "solution_abst_en": "12 9 [OP_ADD] 8 [OP_SUB]",
        "solution_code_ko": "var_a = 12\nvar_b = 9\nvar_c = var_a + var_b\nvar_d = 8\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 9\nvar_c = var_a + var_b\nvar_d = 8\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3335": {
        "category": "Possibility",
        "question_ko": "정국이는 2개 공이 들어 있는 상자 3개를 가지고 있습니다. 정국이가 가지고 있는 공의 개수는?",
        "question_en": "Jungkook has 3 boxes with 2 balls in them. How many balls does Jungkook have?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "2 3 [OP_MUL]",
        "solution_abst_en": "2 3 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "3336": {
        "category": "Arithmetic calculation",
        "question_ko": "25, 17, 21, 34, 32의 다섯 개의 숫자가 적혀져 있는 초콜릿이 있다. 이 중 가장 큰 수가 적힌 초콜릿을 형이 먹고, 가장 작은 수가 적혀 있는 초콜릿은 동생이 먹었다. 두 사람이 먹은 초콜릿에 적혀 있던 수의 차이는 얼마인가?",
        "question_en": "There are chocolates with five numbers written on them: 25, 17, 21, 34, and 32. Among them, the older brother ate the chocolate with the largest number written on it, and the younger brother ate the chocolate with the smallest number written on it. What is the difference between the numbers written on the chocolates the two of them ate?",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "[OP_LIST_SOL] 25 17 21 34 32 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 25 17 21 34 32 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 25\nvar_b = 17\nvar_c = 21\nvar_d = 34\nvar_e = 32\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 25\nvar_b = 17\nvar_c = 21\nvar_d = 34\nvar_e = 32\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))"
    },
    "3337": {
        "category": "Comparison",
        "question_ko": "정국이는 0.8, 윤기는 1/2, 유정이는 0.9의 숫자카드를 갖고 있습니다. 0.3보다 작거나 같은 숫자카드를 가지고 있는 사람은 몇 명입니까?",
        "question_en": "Jungkook has 0.8 written on his card, Yoongi has 1/2 written on his card, and Yoojeong has 0.9 written on her card. Find the number of people who have numbers less than or equal to 0.3 written on their cards.",
        "answer_ko": "0",
        "answer_en": "0",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 0.3 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 0.3 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.3\nlist_b = []\nfor i in list_a:\n    if i <= var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.3\nlist_b = []\nfor i in list_a:\n    if i <= var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "3338": {
        "category": "Possibility",
        "question_ko": "집에 파란 카드가 3개, 노란 카드가 5개 있습니다. 하나를 사촌 동생에게 주려고 할 때, 경우의 수는 총 몇 가지입니까? 단, 모든 카드는 구별할 수 있습니다.",
        "question_en": "The house has 3 blue cards and 5 yellow cards. What is the total number of cases when you give one of the cards to your cousin? However, all cards are distinguishable.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "3 5 [OP_ADD]",
        "solution_abst_en": "3 5 [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "3339": {
        "category": "Possibility",
        "question_ko": "0, 3, 5, 7, 8 중에서 서로 다른 숫자 2개를 뽑아서 두자리 숫자를 만드려고 합니다. 그중에서 가장 큰 수와 가장 작은 수를 더하면 얼마입니까?",
        "question_en": "You want to form a two-digit number by picking two different numbers from 0, 3, 5, 7, and 8. What is the sum of the largest number and the smallest number?",
        "answer_ko": "117",
        "answer_en": "117",
        "solution_abst_ko": "[OP_LIST_SOL] 0 3 5 7 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 0 3 5 7 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 0\nvar_b = 3\nvar_c = 5\nvar_d = 7\nvar_e = 8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 0\nvar_b = 3\nvar_c = 5\nvar_d = 7\nvar_e = 8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h + var_j\nprint(int(var_k))"
    },
    "3340": {
        "category": "Possibility",
        "question_ko": "서로 다른 다섯 개의 수 3, 0, 2, 5, 7을 한 번씩만 사용하며 만들 수 있는 세 자리 수 중에서 가장 작은 수는 무엇입니까?",
        "question_en": "What is the smallest three-digit number that can be formed by using the five different numbers 3, 0, 2, 5, and 7 only once?",
        "answer_ko": "203",
        "answer_en": "203",
        "solution_abst_ko": "[OP_LIST_SOL] 3 0 2 5 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 3 0 2 5 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 3\nvar_b = 0\nvar_c = 2\nvar_d = 5\nvar_e = 7\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nprint(int(var_h))",
        "solution_code_en": "var_a = 3\nvar_b = 0\nvar_c = 2\nvar_d = 5\nvar_e = 7\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nprint(int(var_h))"
    },
    "3341": {
        "category": "Comparison",
        "question_ko": "은설이는 사탕 28개를 주머니 4개에 똑같이 나누어 담았고, 수정이는 사탕 18개를 주머니 3개에 똑같이 나누어 담았습니다. 은설이와 수정이 중에서 주머니 한 개에 들어있는 사탕이 더 적은 사람은 누구인지 구하시오.",
        "question_en": "Eunseol divided 28 candies equally into 4 pockets, and Sujeong split 18 candies equally into 3 pockets. Who among Eunseol and Sujeong has fewer candies in one pocket?",
        "answer_ko": "수정",
        "answer_en": "Sujeong",
        "solution_abst_ko": "[OP_LIST_SOL] 은설 수정 [OP_LIST_EOL] [OP_LIST_SOL] 28 4 [OP_DIV] 18 3 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Eunseol Sujeong [OP_LIST_EOL] [OP_LIST_SOL] 28 4 [OP_DIV] 18 3 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '은설'\nvar_b = '수정'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 28\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 18\nvar_g = 3\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Eunseol'\nvar_b = 'Sujeong'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 28\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 18\nvar_g = 3\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "3342": {
        "category": "Geometry",
        "question_ko": "한 모서리의 길이가 7센티미터(㎝)인 정육면체 모양의 통에 물을 가득 채우려면 얼마만큼이 필요한가?",
        "question_en": "How much water is needed to fill a cube-shaped container with one side 7 centimeters (cm) long?",
        "answer_ko": "343",
        "answer_en": "343",
        "solution_abst_ko": "7 3 [OP_POW]",
        "solution_abst_en": "7 3 [OP_POW]",
        "solution_code_ko": "var_a = 7\nvar_b = 3\nvar_c = var_a ** var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 7\nvar_b = 3\nvar_c = var_a ** var_b\nprint(int(var_c))"
    },
    "3343": {
        "category": "Geometry",
        "question_ko": "어떤 삼각형은 세 변의 길이가 14/8센티미터(㎝)로 모두 같습니다. 이 삼각형의 세 변의 길이의 합은 몇 센티미터(㎝)입니까?",
        "question_en": "Some triangles have all three sides equal in length of 14/8 centimeters (cm). What is the sum of the lengths of the three sides of this triangle in centimeters (cm)?",
        "answer_ko": "5.25",
        "answer_en": "5.25",
        "solution_abst_ko": "14/8 3 [OP_MUL]",
        "solution_abst_en": "14/8 3 [OP_MUL]",
        "solution_code_ko": "var_a = 1.75\nvar_b = 3\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 1.75\nvar_b = 3\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "3344": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 9/10, 1.8, 2, 1, 11/5이 있습니다. 이 중에서 1보다 크고 2보다 작은 수를 소수점을 포함하여 답을 쓰시오.",
        "question_en": "There are five numbers 9/10, 1.8, 2, 1, and 11/5. Of these, write the number greater than 1 and less than 2 including the decimal point.",
        "answer_ko": "1.80",
        "answer_en": "1.8",
        "solution_abst_ko": "[OP_LIST_SOL] 9/10 1.8 2 1 11/5 [OP_LIST_EOL] 1 [OP_LIST_MORE] 2 [OP_LIST_LESS] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] 9/10 1.8 2 1 11/5 [OP_LIST_EOL] 1 [OP_LIST_MORE] 2 [OP_LIST_LESS] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 0.9\nvar_b = 1.8\nvar_c = 2\nvar_d = 1\nvar_e = 2.2\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = 2\nlist_c = []\nfor i in list_b:\n    if i < var_g:\n        list_c.append(i)\nvar_h = 1\nvar_i = list_c[var_h-1]\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 0.9\nvar_b = 1.8\nvar_c = 2\nvar_d = 1\nvar_e = 2.2\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = 2\nlist_c = []\nfor i in list_b:\n    if i < var_g:\n        list_c.append(i)\nvar_h = 1\nvar_i = list_c[var_h-1]\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "3345": {
        "category": "Correspondence",
        "question_ko": "A는 한 자리 자연수입니다. 각 자리 수가 A로 이루어진 두 자리 수끼리의 곱셈식 AA×AA=5929에서 A를 구하시오.",
        "question_en": "A is a single digit natural number. Find A from the multiplication formula AA×AA=5929 of two digit numbers where each digit is A.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "AA×AA=5929 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "AA×AA=5929 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'AA×AA=5929'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'AA×AA=5929'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "3346": {
        "category": "Possibility",
        "question_ko": "가연이는 자물쇠를 열고자 합니다. 자물쇠의 비밀번호는 1, 4, 5, 9 중 숫자 세 개만 사용한 세 자리 수이며, 십의 자리가 9인 두 번째 큰 세 자리수라고 합니다. 각 자릿수는 모두 다를 때, 비밀번호는 무엇입니까?",
        "question_en": "Ga-yeon wants to open the lock. The password for the lock is a three-digit number using only three numbers out of 1, 4, 5, and 9, and is said to be the second largest three-digit number with 9 in the tens place. When all digits are different, what is the password?",
        "answer_ko": "591",
        "answer_en": "591",
        "solution_abst_ko": "[OP_LIST_SOL] 1 4 5 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 9 [OP_LIST_SEARCH_FIXED_DIGIT] 2 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1 4 5 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 9 [OP_LIST_SEARCH_FIXED_DIGIT] 2 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1\nvar_b = 4\nvar_c = 5\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 9\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 2\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 4\nvar_c = 5\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 9\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 2\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nprint(int(var_i))"
    },
    "3347": {
        "category": "Comparison",
        "question_ko": "6개의 사과를 가지고 있던 정국이는 3개의 사과를 더 받았습니다. 윤기는 4개, 유나는 5개의 사과를 가지고 있을 때, 누가 가장 사과를 많이 가지고 있습니까?",
        "question_en": "Jungkook had 6 apples, but he got 3 more. When Yoongi has 4 apples and Yuna has 5 apples, who has the most apples?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 윤기 유나 [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_ADD] 4 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Yoongi Yuna [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_ADD] 4 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '윤기'\nvar_c = '유나'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 6\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = 4\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Yoongi'\nvar_c = 'Yuna'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 6\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = 4\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "3348": {
        "category": "Arithmetic calculation",
        "question_ko": "통나무를 16도막으로 자르려고 합니다. 한 번 자르는 데 9초가 걸리고 한 번 자른 후에는 5초 동안 쉬었다가 다시 자른다고 합니다. 이 통나무를 모두 자르는 데 걸리는 시간은 몇 초인가?",
        "question_en": "I am trying to cut a log into 16 slices. It takes 9 seconds to make one cut, and after one cut, it is said to rest for 5 seconds and then cut again. How many seconds will it take to cut all these logs?",
        "answer_ko": "210",
        "answer_en": "210",
        "solution_abst_ko": "16 1 [OP_SUB] 9 5 [OP_ADD] [OP_MUL]",
        "solution_abst_en": "16 1 [OP_SUB] 9 5 [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 16\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 9\nvar_e = 5\nvar_f = var_d + var_e\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 16\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 9\nvar_e = 5\nvar_f = var_d + var_e\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "3349": {
        "category": "Comparison",
        "question_ko": "무게가 같은 100그램(g)짜리 지우개와 저울을 사용하여 물감의 무게를 재었더니 지우개 3개의 무게와 같았고, 크레파스의 무게를 재었더니 지우개 5개의 무게와 같았습니다. 물감과 크레파스 중 더 가벼운 것은 무엇입니까?",
        "question_en": "When the paint was weighed using a scale and a 100 grams (g) eraser of the same weight, it was equal to the weight of 3 erasers, and when the crayons were weighed, it was equal to the weight of 5 erasers. Which is lighter, paint or crayons?",
        "answer_ko": "물감",
        "answer_en": "paint",
        "solution_abst_ko": "[OP_LIST_SOL] 물감 크레파스 [OP_LIST_EOL] [OP_LIST_SOL] 100 3 [OP_MUL] 100 5 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] paint crayons [OP_LIST_EOL] [OP_LIST_SOL] 100 3 [OP_MUL] 100 5 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '물감'\nvar_b = '크레파스'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 100\nvar_d = 3\nvar_e = var_c * var_d\nvar_f = 100\nvar_g = 5\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'paint'\nvar_b = 'crayons'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 100\nvar_d = 3\nvar_e = var_c * var_d\nvar_f = 100\nvar_g = 5\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "3350": {
        "category": "Geometry",
        "question_ko": "어떤 벽이 가로와 세로의 길이가 각각 36센티미터(㎝), 72센티미터(㎝)인 직사각형 모양이다. 이 벽에 가로와 세로의 길이가 각각 3센티미터(㎝), 4센티미터(㎝)인 타일을 빈 공간 없이 붙이려고 합니다. 모두 몇 개를 붙혀야합니까?",
        "question_en": "There is a wall in the shape of a rectangle with dimensions of 36 centimeters (cm) wide and 72 centimeters (cm) long. On this wall, I want to attach tiles that are 3 centimeters (cm) and 4 centimeters (cm) in width and length, respectively, without empty spaces. How many tiles should I glue in all?",
        "answer_ko": "216",
        "answer_en": "216",
        "solution_abst_ko": "36 3 [OP_FDIV] 72 4 [OP_FDIV] [OP_MUL]",
        "solution_abst_en": "36 3 [OP_FDIV] 72 4 [OP_FDIV] [OP_MUL]",
        "solution_code_ko": "var_a = 36\nvar_b = 3\nvar_c = var_a // var_b\nvar_d = 72\nvar_e = 4\nvar_f = var_d // var_e\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 36\nvar_b = 3\nvar_c = var_a // var_b\nvar_d = 72\nvar_e = 4\nvar_f = var_d // var_e\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "3351": {
        "category": "Comparison",
        "question_ko": "총 4개의 숫자 0.8, 1/2, 0.5, 1/3이 있습니다. 이 중 0.1보다 큰 수를 모두 더하면 얼마인가요?",
        "question_en": "There are a total of 4 numbers: 0.8, 1/2, 0.5, 1/3. What is the sum of all numbers greater than 0.1?",
        "answer_ko": "2.13",
        "answer_en": "2.13",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.5 1/3 [OP_LIST_EOL] 0.1 [OP_LIST_MORE] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.5 1/3 [OP_LIST_EOL] 0.1 [OP_LIST_MORE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.5\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.1\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint('{:.2f}'.format(round(var_f+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.5\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.1\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint('{:.2f}'.format(round(var_f+1e-10,2)))"
    },
    "3352": {
        "category": "Possibility",
        "question_ko": "원 위에 서로 다른 5개의 점이 있다. 이때 서로 인접하지 않는 2개의 점을 이어서 만든 선분은 모두 몇 개인지 구하시오.",
        "question_en": "There are five different points on a circle. Find the number of line segments formed by joining two non-contiguous points.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "5 2 [OP_COMB]",
        "solution_abst_en": "5 2 [OP_COMB]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))"
    },
    "3353": {
        "category": "Geometry",
        "question_ko": "직사각형 모양의 농장이 있습니다. 긴 변의 길이는 1킬로미터(㎞)이고, 짧은 변의 길이는 긴 변의 길이보다 2/8킬로미터(㎞) 짧다면, 농장의 총 둘레는 몇 킬로미터(㎞)입니까?",
        "question_en": "There is a rectangular farm. If the length of the long side is 1 kilometer (km) and the length of the short side is 2/8 km (km) shorter than the length of the long side, what is the total circumference of the farm in kilometers (km)?",
        "answer_ko": "3.50",
        "answer_en": "3.5",
        "solution_abst_ko": "1 1 2/8 [OP_SUB] [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "1 1 2/8 [OP_SUB] [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 1\nvar_b = 1\nvar_c = 0.25\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 1\nvar_c = 0.25\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "3354": {
        "category": "Comparison",
        "question_ko": "나이가 많은 순서대로 학생들이 줄을 섰습니다. 유나는 15번째인 유정이보다 나이가 적고 17번째인 은지보다는 나이가 많습니다. 유나는 몇 번째로 나이가 많습니까?",
        "question_en": "Students lined up in order of seniority. Yuna is younger than Yujeong who is 15th oldest and older than Eunji who is 17th oldest. In what number oldest is Yuna?",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "15 17 [OP_ADD] 2 [OP_FDIV]",
        "solution_abst_en": "15 17 [OP_ADD] 2 [OP_FDIV]",
        "solution_code_ko": "var_a = 15\nvar_b = 17\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 17\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "3355": {
        "category": "Possibility",
        "question_ko": "A, B, C, D, E, F 6명의 학생이 있을 때, 대표 3명을 뽑는 경우의 수를 구하시오.",
        "question_en": "If there are 6 students A, B, C, D, E, and F, find the number of ways to select 3 representatives.",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "[OP_LIST_SOL] A B C D E F [OP_LIST_EOL] [OP_LIST_LEN] 3 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D E F [OP_LIST_EOL] [OP_LIST_LEN] 3 [OP_COMB]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nvar_f = 'F'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = len(list_a)\nvar_h = 3\nvar_i = 1\nvar_g = int(var_g)\nvar_h = int(var_h)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i * (var_g-i)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i / (i+1)\nprint(int(var_i))",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nvar_f = 'F'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = len(list_a)\nvar_h = 3\nvar_i = 1\nvar_g = int(var_g)\nvar_h = int(var_h)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i * (var_g-i)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i / (i+1)\nprint(int(var_i))"
    },
    "3356": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.9, 1/3 중에서 0.7보다 작은 수 중 가장 큰 수는 무엇인가요?",
        "question_en": "What is the largest number less than 0.7 among 0.8, 1/2, 0.9, and 1/3?",
        "answer_ko": "0.50",
        "answer_en": "0.5",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.7 [OP_LIST_LESS] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.7 [OP_LIST_LESS] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.7\nlist_b = []\nfor i in list_a:\n    if i < var_e:\n        list_b.append(i)\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.7\nlist_b = []\nfor i in list_a:\n    if i < var_e:\n        list_b.append(i)\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "3357": {
        "category": "Geometry",
        "question_ko": "크기가 같은 작은 정육면체 8개를 큰 정육면체 모양으로 쌓았습니다. 쌓은 정육면체 모양의 부피가 1000세제곱센티미터(㎤)일 때 작은 정육면체의 한 모서리의 길이는 몇 센티미터(㎝) 입니까?",
        "question_en": "Eight smaller cubes of the same size are stacked to form a larger cube. If the volume of the stacked cubes is 1000 cubic centimeters (cm3), how many centimeters (cm) is the length of one edge of the smaller cube?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "1000 8 [OP_DIV] 1/3 [OP_POW]",
        "solution_abst_en": "1000 8 [OP_DIV] 1/3 [OP_POW]",
        "solution_code_ko": "var_a = 1000\nvar_b = 8\nvar_c = var_a / var_b\nvar_d = 0.3333333333333333\nvar_e = var_c ** var_d\nprint(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))",
        "solution_code_en": "var_a = 1000\nvar_b = 8\nvar_c = var_a / var_b\nvar_d = 0.3333333333333333\nvar_e = var_c ** var_d\nprint(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))"
    },
    "3358": {
        "category": "Arithmetic calculation",
        "question_ko": "주차장에 자동차 24대가 있었는데 8대가 나간 후에 또 6대가 나갔습니다. 주차장에 남아있는 자동차는 몇 대입니까?",
        "question_en": "There were 24 cars in the parking lot, and after 8 cars went out, another 6 cars went out. How many cars are left in the parking lot?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "24 8 [OP_SUB] 6 [OP_SUB]",
        "solution_abst_en": "24 8 [OP_SUB] 6 [OP_SUB]",
        "solution_code_ko": "var_a = 24\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 24\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3359": {
        "category": "Possibility",
        "question_ko": "각 자리 수가 홀수인 네 자리 수 중에서 열 번째로 큰 수는 무엇입니까?",
        "question_en": "What is the tenth largest number among four digits with odd digits?",
        "answer_ko": "9971",
        "answer_en": "9971",
        "solution_abst_ko": "1 9 [OP_LIST_ODD] 4 [OP_LIST_GET_PRODUCT] 10 [OP_LIST_MAX]",
        "solution_abst_en": "1 9 [OP_LIST_ODD] 4 [OP_LIST_GET_PRODUCT] 10 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = 10\nlist_c=list_b.copy()\nlist_c.sort()\nvar_e = list_c[-var_d]\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = 10\nlist_c=list_b.copy()\nlist_c.sort()\nvar_e = list_c[-var_d]\nprint(int(var_e))"
    },
    "3360": {
        "category": "Correspondence",
        "question_ko": "호석이는 어떤 수에 36을 더해 71을 얻었습니다. 어떤 수에 10을 더한 값은 얼마입니까?",
        "question_en": "Hoseok added 36 to a certain number and got 71. What is the value of adding 10 to this certain number?",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "71 36 [OP_SUB] 10 [OP_ADD]",
        "solution_abst_en": "71 36 [OP_SUB] 10 [OP_ADD]",
        "solution_code_ko": "var_a = 71\nvar_b = 36\nvar_c = var_a - var_b\nvar_d = 10\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 71\nvar_b = 36\nvar_c = var_a - var_b\nvar_d = 10\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3361": {
        "category": "Comparison",
        "question_ko": "자동차 20대가 한 줄로 주차되어 있습니다. 검은색 자동차는 오른쪽에서 16번째에 있고, 흰색 자동차는 왼쪽에서 11번째에 있습니다. 검은색 자동차와 흰색 자동차 사이에 있는 자동차는 몇 대입니까?",
        "question_en": "20 cars are parked in a row. The black car is 16th from the right, and the white car is 11th from the left. How many cars are between the black and white cars?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "16 11 [OP_ADD] 20 [OP_SUB] 2 [OP_SUB]",
        "solution_abst_en": "16 11 [OP_ADD] 20 [OP_SUB] 2 [OP_SUB]",
        "solution_code_ko": "var_a = 16\nvar_b = 11\nvar_c = var_a + var_b\nvar_d = 20\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 16\nvar_b = 11\nvar_c = var_a + var_b\nvar_d = 20\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "3362": {
        "category": "Arithmetic calculation",
        "question_ko": "태형이는 국어, 영어, 과학의 평균 점수는 95점입니다. 태형이가 수학 시험을 본 후 평균 점수가 3점 떨어졌다고 할 때, 태형이의 수학 점수는 몇 점입니까?",
        "question_en": "Taehyung's average score for Korean, English, and science is 95. When Taehyung says his average score dropped by 3 points after taking the math test, what is his math score?",
        "answer_ko": "83",
        "answer_en": "83",
        "solution_abst_ko": "95 3 [OP_SUB] 4 [OP_MUL] 95 3 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "95 3 [OP_SUB] 4 [OP_MUL] 95 3 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 95\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c * var_d\nvar_f = 95\nvar_g = 3\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 95\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c * var_d\nvar_f = 95\nvar_g = 3\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nprint(int(var_i))"
    },
    "3363": {
        "category": "Geometry",
        "question_ko": "정사면체의 한 면을 선택해 모서리 길이의 합을 구하였더니 18센티미터(㎝)였습니다. 이 정사면체의 한 모서리의 길이는 얼마입니까?",
        "question_en": "Given that the sum of the lengths of the edges of one face of a regular tetrahedron is 18 centimeters (cm), how long is the length of one edge of this tetrahedron?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "18 3 [OP_DIV]",
        "solution_abst_en": "18 3 [OP_DIV]",
        "solution_code_ko": "var_a = 18\nvar_b = 3\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 18\nvar_b = 3\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "3364": {
        "category": "Arithmetic calculation",
        "question_ko": "두 자리 수 중 몇 개의 수를 무작위로 선택하였더니 31, 49, 62, 76이었습니다. 이 수들 중 가장 큰 수와 가장 작은 수의 차를 구하면 얼마입니까?",
        "question_en": "Randomly selected two digit numbers were 31, 49, 62, and 76. What is the difference between the largest and smallest of these numbers?",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "[OP_LIST_SOL] 49 31 76 62 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 49 31 76 62 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 49\nvar_b = 31\nvar_c = 76\nvar_d = 62\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 49\nvar_b = 31\nvar_c = 76\nvar_d = 62\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))"
    },
    "3365": {
        "category": "Geometry",
        "question_ko": "이십오각형이 있습니다. 한 꼭짓점에서 대각선을 그으려고 할 때, 그을 수 있는 대각선의 수는 몇 개 인가요?",
        "question_en": "There is an icosikaipentagon. How many diagonals can you draw from one vertex?",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "25 3 [OP_SUB]",
        "solution_abst_en": "25 3 [OP_SUB]",
        "solution_code_ko": "var_a = 25\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 25\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "3366": {
        "category": "Geometry",
        "question_ko": "재웅이네 집에는 넓이가 143.2제곱미터(㎡)인 직사각형 모양의 수영장이 있습니다. 이 수영장의 세로가 4미터(m) 일 때, 가로는 몇 미터(m)입니까?",
        "question_en": "Jaewoong's house has a rectangular swimming pool with an area of 143.2 square meters (m2). If the length of this pool is 4 meters (m), what is the width in meters (m)?",
        "answer_ko": "35.80",
        "answer_en": "35.8",
        "solution_abst_ko": "143.2 4 [OP_DIV]",
        "solution_abst_en": "143.2 4 [OP_DIV]",
        "solution_code_ko": "var_a = 143.2\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 143.2\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "3367": {
        "category": "Correspondence",
        "question_ko": "A+B+B=814.8입니다. B의 소수점을 오른쪽으로 한 칸 옮기면 A와 같습니다. 소수점을 포함하여 A-B의 값을 구하시오.",
        "question_en": "A+B+B=814.8. When a decimal point of B is moved one place to the right, it becomes equivalent to A. Calculate the value of A-B including the decimal point.",
        "answer_ko": "34.92",
        "answer_en": "34.92",
        "solution_abst_ko": "814.8 10 10 [OP_ADD] 1 [OP_ADD] [OP_DIV] 814.8 10 10 [OP_ADD] 1 [OP_ADD] [OP_DIV] 10 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "814.8 10 10 [OP_ADD] 1 [OP_ADD] [OP_DIV] 814.8 10 10 [OP_ADD] 1 [OP_ADD] [OP_DIV] 10 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 814.8\nvar_b = 10\nvar_c = 10\nvar_d = var_b + var_c\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = var_a / var_f\nvar_h = 814.8\nvar_i = 10\nvar_j = 10\nvar_k = var_i + var_j\nvar_l = 1\nvar_m = var_k + var_l\nvar_n = var_h / var_m\nvar_o = 10\nvar_p = var_n / var_o\nvar_q = var_g - var_p\nprint('{:.2f}'.format(round(var_q+1e-10,2)))",
        "solution_code_en": "var_a = 814.8\nvar_b = 10\nvar_c = 10\nvar_d = var_b + var_c\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = var_a / var_f\nvar_h = 814.8\nvar_i = 10\nvar_j = 10\nvar_k = var_i + var_j\nvar_l = 1\nvar_m = var_k + var_l\nvar_n = var_h / var_m\nvar_o = 10\nvar_p = var_n / var_o\nvar_q = var_g - var_p\nprint('{:.2f}'.format(round(var_q+1e-10,2)))"
    },
    "3368": {
        "category": "Arithmetic calculation",
        "question_ko": "과수원에서 집까지의 거리는 800미터(m)이고, 집에서 약국까지의 거리는 1300미터(m), 약국에서 학교까지의 거리는 1700미터(m)입니다. 과수원에서 집을 거쳐 약국까지의 거리는 약국에서 학교까지의 거리보다 몇 미터(m) 더 멉니까?",
        "question_en": "The distance from the orchard to the house is 800 meters (m), the distance from the house to the pharmacy is 1300 meters (m), and the distance from the pharmacy to the school is 1700 meters (m). How many meters (m) is the distance from the orchard through the house to the pharmacy greater than the distance from the pharmacy to the school?",
        "answer_ko": "400",
        "answer_en": "400",
        "solution_abst_ko": "800 1300 [OP_ADD] 1700 [OP_SUB]",
        "solution_abst_en": "800 1300 [OP_ADD] 1700 [OP_SUB]",
        "solution_code_ko": "var_a = 800\nvar_b = 1300\nvar_c = var_a + var_b\nvar_d = 1700\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 800\nvar_b = 1300\nvar_c = var_a + var_b\nvar_d = 1700\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3369": {
        "category": "Correspondence",
        "question_ko": "ABCD+ABCD=5472입니다. A, B, C, D가 서로 다른 수 일때 D의 값은 무엇인가요?",
        "question_en": "ABCD+ABCD=5472. What is the value of D when A, B, C, and D are different numbers?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "ABCD+ABCD=5472 D [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "ABCD+ABCD=5472 D [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'ABCD+ABCD=5472'\nvar_b = 'D'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'ABCD+ABCD=5472'\nvar_b = 'D'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "3370": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 10, 11, 12, 13이 있습니다. 그 중에서 2번째로 큰 수와 2번째로 작은 수로 나눈 값은 얼마입니까?",
        "question_en": "If there are four numbers 10, 11, 12, and 13, what is the 2nd largest number divided by the 2nd smallest number?",
        "answer_ko": "1.09",
        "answer_en": "1.09",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_DIV]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "3371": {
        "category": "Geometry",
        "question_ko": "육각형 내에 그릴 수 있는 대각선의 개수는?",
        "question_en": "How many diagonals can you draw in a hexagon?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "6 6 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "6 6 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 6\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 6\nvar_b = 6\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "3372": {
        "category": "Arithmetic calculation",
        "question_ko": "40의 약수 중 40을 제외한 약수의 개수를 구하시오.",
        "question_en": "Find how many divisors of 40 are there excluding 40.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "40 [OP_LIST_GET_DIVISOR] [OP_LIST_SOL] 40 [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_abst_en": "40 [OP_LIST_GET_DIVISOR] [OP_LIST_SOL] 40 [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 40\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 40\nlist_b= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_b.append(var_b)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_c = len(list_c)\nprint(int(var_c))",
        "solution_code_en": "var_a = 40\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 40\nlist_b= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_b.append(var_b)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_c = len(list_c)\nprint(int(var_c))"
    },
    "3373": {
        "category": "Arithmetic calculation",
        "question_ko": "마트에 사과 25상자와 배 12상자가 있었습니다. 사과 8상자와 배 8상자를 더 사 왔을 때, 사과는 배보다 몇 상자 더 많아집니까?",
        "question_en": "There were 25 boxes of apples and 12 boxes of pears in the mart. If you buy 8 more boxes of apples and 8 more boxes of pears, how many more boxes of apples there are than boxes of pears?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "25 8 [OP_ADD] 12 8 [OP_ADD] [OP_SUB]",
        "solution_abst_en": "25 8 [OP_ADD] 12 8 [OP_ADD] [OP_SUB]",
        "solution_code_ko": "var_a = 25\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 12\nvar_e = 8\nvar_f = var_d + var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 25\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 12\nvar_e = 8\nvar_f = var_d + var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "3374": {
        "category": "Geometry",
        "question_ko": "직육면체의 부피가 315제곱센티미터(㎠) 입니다. 가로의 길이가 9센티미터(㎝), 세로의 길이가 7센티미터(㎝)이라면 높이는 몇 센티미터(㎝)입니까?",
        "question_en": "The volume of a cuboid is 315 square centimeters (cm2). If the width is 9 centimeters (cm) and the length is 7 centimeters (cm), what is the height in centimeters (cm)?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "315 9 [OP_DIV] 7 [OP_DIV]",
        "solution_abst_en": "315 9 [OP_DIV] 7 [OP_DIV]",
        "solution_code_ko": "var_a = 315\nvar_b = 9\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 315\nvar_b = 9\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "3375": {
        "category": "Correspondence",
        "question_ko": "윤기는 두 자리 수와 53의 차를 구하려 합니다. 윤기는 53의 십의 자리 숫자와 일의 자리 숫자를 잘못 보아 35라고 보았습니다. 윤기가 잘못 계산한 차가 27, 바르게 계산한 결과를 구하시오.",
        "question_en": "Yoongi tries to find the difference between a two-digit number and 53. Yoongi misunderstood the tens and ones digits of 53 and thought it was 35. The difference Yoongi calculated incorrectly is 27. Find the correct result.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "27 35 [OP_ADD] 53 [OP_SUB]",
        "solution_abst_en": "27 35 [OP_ADD] 53 [OP_SUB]",
        "solution_code_ko": "var_a = 27\nvar_b = 35\nvar_c = var_a + var_b\nvar_d = 53\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 27\nvar_b = 35\nvar_c = var_a + var_b\nvar_d = 53\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3376": {
        "category": "Geometry",
        "question_ko": "정육면체의 면의 수와 꼭짓점의 수의 곱을 구하시오.",
        "question_en": "Find the product of the number of faces and the number of vertices of a cube.",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "6 8 [OP_MUL]",
        "solution_abst_en": "6 8 [OP_MUL]",
        "solution_code_ko": "var_a = 6\nvar_b = 8\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 8\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "3377": {
        "category": "Arithmetic calculation",
        "question_ko": "30이하의 자연수 중에서 5의 배수이거나 홀수인 수는 모두 몇 개인지 구하시오.",
        "question_en": "How many natural numbers are there not more than 30 are odd or multiples of 5?",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "1 30 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] 1 30 [OP_LIST_ODD] [OP_SET_UNION] [OP_LIST_LEN]",
        "solution_abst_en": "1 30 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] 1 30 [OP_LIST_ODD] [OP_SET_UNION] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 30\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 1\nvar_f = 30\nlist_c = []\nif var_e%2==0:\n    for i in range(var_e+1, var_f+1, 2):\n        list_c.append(i)\nelse:\n    for i in range(var_e, var_f+1, 2):\n        list_c.append(i)\nlist_d = list(set(list_b) | set(list_c))\nvar_g = len(list_d)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 30\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 1\nvar_f = 30\nlist_c = []\nif var_e%2==0:\n    for i in range(var_e+1, var_f+1, 2):\n        list_c.append(i)\nelse:\n    for i in range(var_e, var_f+1, 2):\n        list_c.append(i)\nlist_d = list(set(list_b) | set(list_c))\nvar_g = len(list_d)\nprint(int(var_g))"
    },
    "3378": {
        "category": "Correspondence",
        "question_ko": "37을 8로 나눴더니 나머지가 B, 몫이 A가 되었습니다. A에 알맞은 값을 구하시오.",
        "question_en": "When we divide 37 by 8, the remainder is B and the quotient is A. Find the right value for A.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "37 8 [OP_FDIV]",
        "solution_abst_en": "37 8 [OP_FDIV]",
        "solution_code_ko": "var_a = 37\nvar_b = 8\nvar_c = var_a // var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 37\nvar_b = 8\nvar_c = var_a // var_b\nprint(int(var_c))"
    },
    "3379": {
        "category": "Comparison",
        "question_ko": "주차장에 세워진 아빠의 차의 앞뒤에는 각각 6, 7줄의 차들이 주차되어 있고, 양옆에는 각각 5, 6줄의 차들이 주차되어 있고,각 줄마다 있는 자동차의 수가 같다고 할 때, 주차장에 세워진 차들은 모두 몇 대입니까?",
        "question_en": "There are 6 and 7 rows each of cars parked in the front and back of the father's car parked in the parking lot, and 5 and 6 rows each of cars parked on either side and the number of cars in each row is the same. How many are there in all?",
        "answer_ko": "168",
        "answer_en": "168",
        "solution_abst_ko": "6 7 [OP_ADD] 1 [OP_ADD] 5 6 [OP_ADD] 1 [OP_ADD] [OP_MUL]",
        "solution_abst_en": "6 7 [OP_ADD] 1 [OP_ADD] 5 6 [OP_ADD] 1 [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 6\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = 6\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h + var_i\nvar_k = var_e * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 6\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = 6\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h + var_i\nvar_k = var_e * var_j\nprint(int(var_k))"
    },
    "3380": {
        "category": "Arithmetic calculation",
        "question_ko": "4일동안 문제집에 있는 문제를 모두 풀려고 한다. 첫 날에 문제의 1/2개를 풀고 두번째 날에는 1/4을 풀고 세번째 날에 1/6을 풀었고 네번째 날에는 20문제가 남았습니다. 문제집에는 모두 몇 문제가 있나요?",
        "question_en": "You are trying to solve all the problems in the workbook in 4 days. You solved 1/2 of the problems were solved on the first day, 1/4 of the problems on the second day, 1/6 of the problems on the third day, and 20 problems left on the fourth day. How many problems are there in the workbook?",
        "answer_ko": "240",
        "answer_en": "240",
        "solution_abst_ko": "20 1 1/2 1/4 [OP_ADD] 1/6 [OP_ADD] [OP_SUB] [OP_DIV]",
        "solution_abst_en": "20 1 1/2 1/4 [OP_ADD] 1/6 [OP_ADD] [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 20\nvar_b = 1\nvar_c = 0.5\nvar_d = 0.25\nvar_e = var_c + var_d\nvar_f = 0.16666666666666666\nvar_g = var_e + var_f\nvar_h = var_b - var_g\nvar_i = var_a / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))",
        "solution_code_en": "var_a = 20\nvar_b = 1\nvar_c = 0.5\nvar_d = 0.25\nvar_e = var_c + var_d\nvar_f = 0.16666666666666666\nvar_g = var_e + var_f\nvar_h = var_b - var_g\nvar_i = var_a / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))"
    },
    "3381": {
        "category": "Comparison",
        "question_ko": "문슬기는 김현정의 할머니입니다. 김미란은 김호현의 딸이고 딸 중에서 가장 먼저 연하인 정재영과 결혼했습니다. 김호현의 자식 중 김현정은 첫째 딸입니다. 5명의 사람 중 나이가 3번째로 많은 사람은 누구입니까?",
        "question_en": "Seulgi is Hyunjung's grandmother. Miran is the daughter of Hohyun and the first daughter to marry Jaeyoung whose younger than her. Among Hohyun's children, Hyunjung is the eldest daughter. Who is the 3rd oldest among 5 people?",
        "answer_ko": "김현정",
        "answer_en": "Hyunjung",
        "solution_abst_ko": "[OP_LIST_SOL] 문슬기 김현정 김미란 김호현 정재영 [OP_LIST_EOL] [OP_LIST_SOL] 문슬기 김현정 > 김미란 김호현 < 김미란 정재영 > 김호현 김현정 > 김현정 김미란 > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 3 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Seulgi Hyunjung Miran Hohyun Jaeyoung [OP_LIST_EOL] [OP_LIST_SOL] Seulgi Hyunjung > Miran Hohyun < Miran Jaeyoung > Hohyun Hyunjung > Hyunjung Miran > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 3 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '문슬기'\nvar_b = '김현정'\nvar_c = '김미란'\nvar_d = '김호현'\nvar_e = '정재영'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = '문슬기'\nvar_g = '김현정'\nvar_h = '>'\nvar_i = '김미란'\nvar_j = '김호현'\nvar_k = '<'\nvar_l = '김미란'\nvar_m = '정재영'\nvar_n = '>'\nvar_o = '김호현'\nvar_p = '김현정'\nvar_q = '>'\nvar_r = '김현정'\nvar_s = '김미란'\nvar_t = '>'\nlist_b= []\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_b.append(var_t)\nif \"/\" in str(var_s):\n    var_s = eval(str(var_s))\nlist_b.append(var_s)\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_u = 3\nvar_v = list_c[var_u-1]\nprint(var_v)",
        "solution_code_en": "var_a = 'Seulgi'\nvar_b = 'Hyunjung'\nvar_c = 'Miran'\nvar_d = 'Hohyun'\nvar_e = 'Jaeyoung'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 'Seulgi'\nvar_g = 'Hyunjung'\nvar_h = '>'\nvar_i = 'Miran'\nvar_j = 'Hohyun'\nvar_k = '<'\nvar_l = 'Miran'\nvar_m = 'Jaeyoung'\nvar_n = '>'\nvar_o = 'Hohyun'\nvar_p = 'Hyunjung'\nvar_q = '>'\nvar_r = 'Hyunjung'\nvar_s = 'Miran'\nvar_t = '>'\nlist_b= []\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_b.append(var_t)\nif \"/\" in str(var_s):\n    var_s = eval(str(var_s))\nlist_b.append(var_s)\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_u = 3\nvar_v = list_c[var_u-1]\nprint(var_v)"
    },
    "3382": {
        "category": "Geometry",
        "question_ko": "형진이와 규준이가 정육면체의 조각상을 만들어 왔다. 형진이의 조각상 한 변의 길이는 100센티미터(㎝), 규준이 조각상의 한 변의 길이는 2미터(m)이다. 두 사람의 조각상 부피는 몇 배 차이인가?",
        "question_en": "Hyungjin and Kyujun have been making a cube statue. The length of one side of the statue of Hyungjin is 100 centimeters (cm), and the length of one side of the statue of Gyujun is 2 meters (m). How many times the volume of the statue is different between the two?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "2 3 [OP_POW] 100 100 [OP_DIV] 3 [OP_POW] [OP_DIV]",
        "solution_abst_en": "2 3 [OP_POW] 100 100 [OP_DIV] 3 [OP_POW] [OP_DIV]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = var_a ** var_b\nvar_d = 100\nvar_e = 100\nvar_f = var_d / var_e\nvar_g = 3\nvar_h = var_f ** var_g\nvar_i = var_c / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = var_a ** var_b\nvar_d = 100\nvar_e = 100\nvar_f = var_d / var_e\nvar_g = 3\nvar_h = var_f ** var_g\nvar_i = var_c / var_h\nprint(int(var_i))"
    },
    "3383": {
        "category": "Arithmetic calculation",
        "question_ko": "마트에 같은 무게의 사과를 담은 상자가 5개 있습니다. 각 상자에서 사과를 30킬로그램(㎏)씩 꺼낸 후, 5개의 상자에 남은 사과의 무게를 재어 보니 원래 상자 2개의 사과의 무게와 같았습니다. 원래 각 상자에 들어 있던 사과는 몇 킬로그램(㎏)입니까?",
        "question_en": "There are 5 boxes of apples of the same weight in the supermarket. After removing 30 kilograms (kg) of apples from each box, the weight of the remaining apples in the five boxes was equal to the weight of the apples in the original two boxes. How many kilograms (kg) of apples were originally in each box?",
        "answer_ko": "50",
        "answer_en": "50",
        "solution_abst_ko": "30 5 [OP_MUL] 5 2 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "30 5 [OP_MUL] 5 2 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 30\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 30\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))"
    },
    "3384": {
        "category": "Comparison",
        "question_ko": "넓이가 각각 48제곱센티미터(㎠), 108제곱센티미터(㎠), 75제곱센티미터(㎠)인 세 원 (가), (나), (다)에서 가장 큰 원의 지름에서 가장 작은 원의 지름을 빼려고 합니다. 원주율을 3으로 계산하면 몇 센티미터(cm)인지 구하시오.",
        "question_en": "You are going to subtract the diameter of the smallest circle from the diameter of the largest circle among three circles (a), (b), and (c) with areas of 48 square centimeters (cm2), 108 square centimeters (cm2), and 75 square centimeters (cm2), respectively. Find the value in centimeter (cm) if pi is 3.\n",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 48 3 [OP_DIV] 1 2 [OP_DIV] [OP_POW] 108 3 [OP_DIV] 1 2 [OP_DIV] [OP_POW] 75 3 [OP_DIV] 1 2 [OP_DIV] [OP_POW] [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB] 2 [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 48 3 [OP_DIV] 1 2 [OP_DIV] [OP_POW] 108 3 [OP_DIV] 1 2 [OP_DIV] [OP_POW] 75 3 [OP_DIV] 1 2 [OP_DIV] [OP_POW] [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 48\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = 2\nvar_f = var_d / var_e\nvar_g = var_c ** var_f\nvar_h = 108\nvar_i = 3\nvar_j = var_h / var_i\nvar_k = 1\nvar_l = 2\nvar_m = var_k / var_l\nvar_n = var_j ** var_m\nvar_o = 75\nvar_p = 3\nvar_q = var_o / var_p\nvar_r = 1\nvar_s = 2\nvar_t = var_r / var_s\nvar_u = var_q ** var_t\nlist_a= []\nif \"/\" in str(var_u):\n    var_u = eval(str(var_u))\nlist_a.append(var_u)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_a.append(var_n)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nlist_a.reverse()\nvar_v = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_w = list_b[-var_v]\nvar_x = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_y = list_c[var_x-1]\nvar_z = var_w - var_y\nvar_A = 2\nvar_B = var_z * var_A\nprint(int(var_B))",
        "solution_code_en": "var_a = 48\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = 2\nvar_f = var_d / var_e\nvar_g = var_c ** var_f\nvar_h = 108\nvar_i = 3\nvar_j = var_h / var_i\nvar_k = 1\nvar_l = 2\nvar_m = var_k / var_l\nvar_n = var_j ** var_m\nvar_o = 75\nvar_p = 3\nvar_q = var_o / var_p\nvar_r = 1\nvar_s = 2\nvar_t = var_r / var_s\nvar_u = var_q ** var_t\nlist_a= []\nif \"/\" in str(var_u):\n    var_u = eval(str(var_u))\nlist_a.append(var_u)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_a.append(var_n)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nlist_a.reverse()\nvar_v = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_w = list_b[-var_v]\nvar_x = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_y = list_c[var_x-1]\nvar_z = var_w - var_y\nvar_A = 2\nvar_B = var_z * var_A\nprint(int(var_B))"
    },
    "3385": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 서로 다른 막대 2개가 있습니다. 긴 막대의 길이는 짧은 막대의 길이보다 18센티미터(㎝) 더 길고, 두 막대의 길이의 합은 30센티미터(㎝)입니다. 긴 막대를 잘라 짧은 막대와 길이가 같은 막대를 몇 개 만들 수 있는지 구해 보시오.",
        "question_en": "There are 2 sticks of different lengths. The length of the long stick is 18 centimeters (cm) longer than the length of the short stick, and the sum of the lengths of the two sticks is 30 centimeters (cm). Find how many sticks with the same length as the shorter sticks can be made by cutting the longer sticks.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "30 18 [OP_SUB] 2 [OP_DIV] 18 [OP_ADD] 30 18 [OP_SUB] 2 [OP_DIV] [OP_DIV]",
        "solution_abst_en": "30 18 [OP_SUB] 2 [OP_DIV] 18 [OP_ADD] 30 18 [OP_SUB] 2 [OP_DIV] [OP_DIV]",
        "solution_code_ko": "var_a = 30\nvar_b = 18\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 18\nvar_g = var_e + var_f\nvar_h = 30\nvar_i = 18\nvar_j = var_h - var_i\nvar_k = 2\nvar_l = var_j / var_k\nvar_m = var_g / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 30\nvar_b = 18\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 18\nvar_g = var_e + var_f\nvar_h = 30\nvar_i = 18\nvar_j = var_h - var_i\nvar_k = 2\nvar_l = var_j / var_k\nvar_m = var_g / var_l\nprint(int(var_m))"
    },
    "3386": {
        "category": "Arithmetic calculation",
        "question_ko": "(가) 나무 수는 (나) 나무 수의 2배이고, (다) 나무는 (가) 나무보다 15그루 더 많습니다. (다) 나무가 47그루 있을 때, (가), (나), (다) 나무는 모두 몇 그루입니까?",
        "question_en": "The number of (a) trees is twice the number of (b) trees, and there are 15 more (c) trees than (a) trees. If there are 47 (c) trees, how many (a), (b), (c) trees are there in total?",
        "answer_ko": "95",
        "answer_en": "95",
        "solution_abst_ko": "47 15 [OP_SUB] 47 15 [OP_SUB] 2 [OP_DIV] [OP_ADD] 47 [OP_ADD]",
        "solution_abst_en": "47 15 [OP_SUB] 47 15 [OP_SUB] 2 [OP_DIV] [OP_ADD] 47 [OP_ADD]",
        "solution_code_ko": "var_a = 47\nvar_b = 15\nvar_c = var_a - var_b\nvar_d = 47\nvar_e = 15\nvar_f = var_d - var_e\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = var_c + var_h\nvar_j = 47\nvar_k = var_i + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 47\nvar_b = 15\nvar_c = var_a - var_b\nvar_d = 47\nvar_e = 15\nvar_f = var_d - var_e\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = var_c + var_h\nvar_j = 47\nvar_k = var_i + var_j\nprint(int(var_k))"
    },
    "3387": {
        "category": "Arithmetic calculation",
        "question_ko": "기차를 타고 유정이는 3정거장, 남준이는 2정거장을 이동하였습니다. 유정이와 남준이가 기차로 이동한 정거장 수는 얼마인가요?",
        "question_en": "On the train, Yoojeong moved 3 stops and Namjoon moved 2 stops. How many stops did Yoojung and Namjoon travel by train?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "3 2 [OP_ADD]",
        "solution_abst_en": "3 2 [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "3388": {
        "category": "Arithmetic calculation",
        "question_ko": "1리터(L)의 우유를 친구들과 나눠 마시기로 했습니다. 이 중에서 명석이가 0.1리터(L)를 마셨고, 민구는 명석이보다 0.2리터(L)를 더 마셨습니다. 잠시 후 민재가 와서 0.3리터(L)의 우유를 마셨다면, 내가 마실 수 있는 우유는 몇 리터(L)입니까?",
        "question_en": "I decided to share 1 liter (L) of milk with my friends. Of these, Myeongseok drank 0.1 liters (L), and Mingu drank 0.2 liters (L) more than Myeongseok. After a while, if Min-jae came and drank 0.3 liters (L) of milk, how many liters (L) of milk could I drink?",
        "answer_ko": "0.30",
        "answer_en": "0.3",
        "solution_abst_ko": "1 0.1 [OP_SUB] 0.1 0.2 [OP_ADD] [OP_SUB] 0.3 [OP_SUB]",
        "solution_abst_en": "1 0.1 [OP_SUB] 0.1 0.2 [OP_ADD] [OP_SUB] 0.3 [OP_SUB]",
        "solution_code_ko": "var_a = 1\nvar_b = 0.1\nvar_c = var_a - var_b\nvar_d = 0.1\nvar_e = 0.2\nvar_f = var_d + var_e\nvar_g = var_c - var_f\nvar_h = 0.3\nvar_i = var_g - var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 0.1\nvar_c = var_a - var_b\nvar_d = 0.1\nvar_e = 0.2\nvar_f = var_d + var_e\nvar_g = var_c - var_f\nvar_h = 0.3\nvar_i = var_g - var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "3389": {
        "category": "Comparison",
        "question_ko": "미나는 콜라를 0.3리터(L)씩 2번 마셨습니다. 석형이는 3/2리터(L) 마셨습니다. 송화는 석형이보다 0.6리터(L) 적게 마셨다면 콜라를 가장 많이 마신 사람은 누구입니까?",
        "question_en": "Mina drank 0.3 liters (l) of Coke twice. Seokhyung drank 3/2 liter (l). If Songhwa drank 0.6 liters (l) less than Seokhyung, who drank the most cola?",
        "answer_ko": "석형",
        "answer_en": "Seokhyung",
        "solution_abst_ko": "[OP_LIST_SOL] 미나 석형 송화 [OP_LIST_EOL] [OP_LIST_SOL] 0.3 2 [OP_MUL] 3 2 [OP_DIV] 3 2 [OP_DIV] 0.6 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Mina Seokhyung Songhwa [OP_LIST_EOL] [OP_LIST_SOL] 0.3 2 [OP_MUL] 3 2 [OP_DIV] 3 2 [OP_DIV] 0.6 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '미나'\nvar_b = '석형'\nvar_c = '송화'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.3\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = 3\nvar_h = 2\nvar_i = var_g / var_h\nvar_j = 3\nvar_k = 2\nvar_l = var_j / var_k\nvar_m = 0.6\nvar_n = var_l - var_m\nlist_b= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_o = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_p = list_c[-var_o]\nvar_q = list_b.index(var_p)+1\nvar_r = list_a[var_q-1]\nprint(var_r)",
        "solution_code_en": "var_a = 'Mina'\nvar_b = 'Seokhyung'\nvar_c = 'Songhwa'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.3\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = 3\nvar_h = 2\nvar_i = var_g / var_h\nvar_j = 3\nvar_k = 2\nvar_l = var_j / var_k\nvar_m = 0.6\nvar_n = var_l - var_m\nlist_b= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_o = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_p = list_c[-var_o]\nvar_q = list_b.index(var_p)+1\nvar_r = list_a[var_q-1]\nprint(var_r)"
    },
    "3390": {
        "category": "Correspondence",
        "question_ko": "7의 배수이면서 2, 3, 4, 5, 6으로 나누면 나머지가 모두 1인 수가 있다. 이러한 수 중에서 셋째로 작은 수를 구하여라.",
        "question_en": "A number that is a multiple of 7, when divided by 2, 3, 4, 5, or 6, has a remainder of 1. Find the third smallest of these numbers.",
        "answer_ko": "1141",
        "answer_en": "1141",
        "solution_abst_ko": "0 9999 1 [OP_LIST_ARANGE] 2 1 [OP_LIST_DIVIDE_AND_REMAIN] 3 1 [OP_LIST_DIVIDE_AND_REMAIN] 4 1 [OP_LIST_DIVIDE_AND_REMAIN] 5 1 [OP_LIST_DIVIDE_AND_REMAIN] 6 1 [OP_LIST_DIVIDE_AND_REMAIN] 7 [OP_LIST_DIVISIBLE] 3 [OP_LIST_MIN]",
        "solution_abst_en": "0 9999 1 [OP_LIST_ARANGE] 2 1 [OP_LIST_DIVIDE_AND_REMAIN] 3 1 [OP_LIST_DIVIDE_AND_REMAIN] 4 1 [OP_LIST_DIVIDE_AND_REMAIN] 5 1 [OP_LIST_DIVIDE_AND_REMAIN] 6 1 [OP_LIST_DIVIDE_AND_REMAIN] 7 [OP_LIST_DIVISIBLE] 3 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 0\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nvar_e = 1\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 3\nvar_g = 1\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 4\nvar_i = 1\nlist_d = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_c:\n    i = int(i)\n    if i%var_h == var_i:\n        list_d.append(i)\nvar_j = 5\nvar_k = 1\nlist_e = [] \nvar_j = int(var_j)\nvar_k = int(var_k)\nif var_k < 0:\n    var_k = var_k + var_j\nfor i in list_d:\n    i = int(i)\n    if i%var_j == var_k:\n        list_e.append(i)\nvar_l = 6\nvar_m = 1\nlist_f = [] \nvar_l = int(var_l)\nvar_m = int(var_m)\nif var_m < 0:\n    var_m = var_m + var_l\nfor i in list_e:\n    i = int(i)\n    if i%var_l == var_m:\n        list_f.append(i)\nvar_n = 7\nlist_g = []\nvar_n = int(var_n)\nfor i in list_f:\n    i = int(i)\n    if i % var_n == 0:\n        list_g.append(i)\nvar_o = 3\nlist_h=list_g.copy()\nlist_h.sort()\nvar_p = list_h[var_o-1]\nprint(int(var_p))",
        "solution_code_en": "var_a = 0\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nvar_e = 1\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 3\nvar_g = 1\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 4\nvar_i = 1\nlist_d = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_c:\n    i = int(i)\n    if i%var_h == var_i:\n        list_d.append(i)\nvar_j = 5\nvar_k = 1\nlist_e = [] \nvar_j = int(var_j)\nvar_k = int(var_k)\nif var_k < 0:\n    var_k = var_k + var_j\nfor i in list_d:\n    i = int(i)\n    if i%var_j == var_k:\n        list_e.append(i)\nvar_l = 6\nvar_m = 1\nlist_f = [] \nvar_l = int(var_l)\nvar_m = int(var_m)\nif var_m < 0:\n    var_m = var_m + var_l\nfor i in list_e:\n    i = int(i)\n    if i%var_l == var_m:\n        list_f.append(i)\nvar_n = 7\nlist_g = []\nvar_n = int(var_n)\nfor i in list_f:\n    i = int(i)\n    if i % var_n == 0:\n        list_g.append(i)\nvar_o = 3\nlist_h=list_g.copy()\nlist_h.sort()\nvar_p = list_h[var_o-1]\nprint(int(var_p))"
    },
    "3391": {
        "category": "Arithmetic calculation",
        "question_ko": "하루에 연필을 370자루씩 생산하는 기계가 있습니다. 이 기계로 연필 1000타를 생산하려면 며칠이 걸립니까?",
        "question_en": "We have a machine that produces 370 pencils a day. How many days will it take to produce 1000 dozen pencils on this machine?",
        "answer_ko": "33",
        "answer_en": "33",
        "solution_abst_ko": "1000 12 [OP_MUL] 370 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "1000 12 [OP_MUL] 370 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 1000\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 370\nvar_e = var_c / var_d\nvar_f = 1\nvar_g=int(((var_e+9*10**(var_f-2))//(10**(var_f-1)))*10**(var_f-1))\n\nprint(int(var_g))",
        "solution_code_en": "var_a = 1000\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 370\nvar_e = var_c / var_d\nvar_f = 1\nvar_g=int(((var_e+9*10**(var_f-2))//(10**(var_f-1)))*10**(var_f-1))\n\nprint(int(var_g))"
    },
    "3392": {
        "category": "Arithmetic calculation",
        "question_ko": "세균은 1분에 2마리로 갈라집니다. 1분 후에는 2마리가 되고, 2분 후에는 4마리가 되는 식으로 늘어난다면, 8분 후에는 몇 마리가 되어있겠습니까?",
        "question_en": "Bacteria split into two in one minute. If after 1 minute it becomes 2, and after 2 minutes it becomes 4, and so on, how many will there be after 8 minutes?",
        "answer_ko": "256",
        "answer_en": "256",
        "solution_abst_ko": "2 8 [OP_POW]",
        "solution_abst_en": "2 8 [OP_POW]",
        "solution_code_ko": "var_a = 2\nvar_b = 8\nvar_c = var_a ** var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 8\nvar_c = var_a ** var_b\nprint(int(var_c))"
    },
    "3393": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 10, 11, 12, 13이 있습니다. 그 중에서 3번째로 큰 수와 2번째로 큰 수로 나눈 나머지는 얼마입니까?",
        "question_en": "There are four numbers 10, 11, 12, and 13. What is the remainder when divided by the 3rd largest number and the 2nd largest number?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 3 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_MOD]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 3 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_MOD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = var_f % var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = var_f % var_h\nprint(int(var_i))"
    },
    "3394": {
        "category": "Geometry",
        "question_ko": "24센티미터(㎝)의 선분 위에 반지름의 길이가 4센티미터(㎝)인 원을 겹치지 않고 몇 개까지 그릴 수 있습니까?",
        "question_en": "How many circles with a radius of 4 centimeters (cm) can be drawn on a line segment of 24 centimeters (cm) without overlapping?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "24 4 2 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "24 4 2 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 24\nvar_b = 4\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 24\nvar_b = 4\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "3395": {
        "category": "Arithmetic calculation",
        "question_ko": "두 도깨비 퐁퐁이와 롱롱이가 있다. 퐁퐁이는 8000에 매일 300씩을 더하고, 롱롱이는 5000에 매일 500씩 더한다. 퐁퐁이와 롱롱이의 숫자가 같은 날 보물을 준다고 한다. 보물은 며칠 후에 받을 수 있는가?",
        "question_en": "There are two goblins, Pongpong and Longlong. Pongpong adds 300 each day to 8000, and Longlong adds 500 each day to 5000. It is said that the treasure will be given on the same day as the number of Pongpong and Longlong. How many days can they get the treasure?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "8000 5000 [OP_SUB] 500 300 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "8000 5000 [OP_SUB] 500 300 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 8000\nvar_b = 5000\nvar_c = var_a - var_b\nvar_d = 500\nvar_e = 300\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 8000\nvar_b = 5000\nvar_c = var_a - var_b\nvar_d = 500\nvar_e = 300\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))"
    },
    "3396": {
        "category": "Comparison",
        "question_ko": "독서대회에 A, B, C 3개의 반이 참가하였습니다. A 반 학생들이 B 반 학생들보다 책을 많이 읽었고 C 반 학생들이 A 반 학생들보다 책을 많이 읽었다면 가장 적은 책을 읽은 반은 어떤 반인지 구하세요.",
        "question_en": "Three classes A, B, and C participated in the reading competition. If the students in class A read more than the students in class B, and the students in class C read more than the students in class A, find which class read the fewest books.",
        "answer_ko": "B",
        "answer_en": "B",
        "solution_abst_ko": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] A B > C A > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] A B > C A > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'A'\nvar_e = 'B'\nvar_f = '>'\nvar_g = 'C'\nvar_h = 'A'\nvar_i = '>'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = len(list_c)\nvar_k = list_c[var_j-1]\nprint(var_k)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'A'\nvar_e = 'B'\nvar_f = '>'\nvar_g = 'C'\nvar_h = 'A'\nvar_i = '>'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = len(list_c)\nvar_k = list_c[var_j-1]\nprint(var_k)"
    },
    "3397": {
        "category": "Correspondence",
        "question_ko": "생선가게에서 점심에 가지고 있던 생선의 절반을 팔았고, 그 나머지의 1/3을 저녁에 팔았더니 12마리가 남았습니다. 생선가게에서 처음 가지고 있던 생선은 모두 몇마리 입니까?",
        "question_en": "The fishmonger sold half of the fish he had for lunch and 1/3 of the rest for dinner, leaving 12 fish. How many fish did they originally have in the shop?",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "12 1 1/3 [OP_SUB] [OP_DIV] 1 1/2 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "12 1 1/3 [OP_SUB] [OP_DIV] 1 1/2 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 1\nvar_c = 0.3333333333333333\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 1\nvar_g = 0.5\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))",
        "solution_code_en": "var_a = 12\nvar_b = 1\nvar_c = 0.3333333333333333\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 1\nvar_g = 0.5\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))"
    },
    "3398": {
        "category": "Comparison",
        "question_ko": "22명을 키가 큰 순서대로 세우려고합니다. 모두의 키가 다를 때 (가)는 뒤에서 13번째이다. 키가 작은 사람부터 다시 세우면 (가)는 몇 번째인가?",
        "question_en": "I'm trying to put 22 people in order of height. When everyone's height is different, (a) is 13th from the back. If you start with the shortest person, what number does (a) stand in?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "22 13 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "22 13 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 22\nvar_b = 13\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 22\nvar_b = 13\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3399": {
        "category": "Correspondence",
        "question_ko": "젤리는 한 봉지에 딸기맛이 3개, 포도맛이 4개가 들어있다고 한다. 오늘 새로운 젤리를 25 봉지 받아서 딸기맛 젤리가 총 150개가 되었을 때, 포도맛 젤리는 몇 개인지 구하시오.",
        "question_en": "Each bag of jellies contains 3 strawberry-flavored jellies and 4 grape-flavored jellies. If you get 25 bags of new jellies today and the total number of strawberry-flavored jellies is 150, how many grape-flavored jellies will there be?",
        "answer_ko": "100",
        "answer_en": "100",
        "solution_abst_ko": "150 3 [OP_DIV] 25 [OP_SUB] 4 [OP_MUL]",
        "solution_abst_en": "150 3 [OP_DIV] 25 [OP_SUB] 4 [OP_MUL]",
        "solution_code_ko": "var_a = 150\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 25\nvar_e = var_c - var_d\nvar_f = 4\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 150\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 25\nvar_e = var_c - var_d\nvar_f = 4\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "3400": {
        "category": "Arithmetic calculation",
        "question_ko": "2리터(L) 100밀리리터(㎖)의 우유를 석기와 지혜가 나누어 마시려고 합니다. 석기가 지혜보다 200밀리리터(㎖) 더 많이 마시려면 석기는 몇 밀리리터(㎖)의 우유를 마셔야 합니까?",
        "question_en": "Seokgi and Jihae shared 2 liters (L) and 100 milliliters (㎖) of milk. How many milliliters (ml) of milk must Seokgi drink if he is to drink 200 milliliters (ml) more than Jihae?",
        "answer_ko": "1150",
        "answer_en": "1150",
        "solution_abst_ko": "2 1000 [OP_MUL] 100 [OP_ADD] 200 [OP_ADD] 2 [OP_DIV]",
        "solution_abst_en": "2 1000 [OP_MUL] 100 [OP_ADD] 200 [OP_ADD] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = var_c + var_d\nvar_f = 200\nvar_g = var_e + var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = var_c + var_d\nvar_f = 200\nvar_g = var_e + var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "3401": {
        "category": "Possibility",
        "question_ko": "지연이는 앞에 놓인 숫자 카드를 한 번씩 이용해 가장 큰 수를 만들고자 합니다. 숫자 카드 1, 4, 5를 가지고 있을 때, 지연이는 어떤 자연수를 만들어야 합니까?",
        "question_en": "Jiyeon wants to make the biggest number by using the number cards in front of her once. Given the number cards 1, 4, and 5, what natural number should she create?",
        "answer_ko": "541",
        "answer_en": "541",
        "solution_abst_ko": "[OP_LIST_SOL] 1 4 5 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1 4 5 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1\nvar_b = 4\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 4\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))"
    },
    "3402": {
        "category": "Comparison",
        "question_ko": "호현이는 키가 162센티미터(㎝)이고 슬기는 키가 159센티미터(㎝)입니다. 키가 더 큰 사람은 누구입니까?",
        "question_en": "Hohyun is 162 centimeters (cm) tall and Seulgi is 159 centimeters (cm) tall. Who is taller?",
        "answer_ko": "호현",
        "answer_en": "Hohyun",
        "solution_abst_ko": "[OP_LIST_SOL] 호현 슬기 [OP_LIST_EOL] [OP_LIST_SOL] 162 159 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Hohyun Seulgi [OP_LIST_EOL] [OP_LIST_SOL] 162 159 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '호현'\nvar_b = '슬기'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 162\nvar_d = 159\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Hohyun'\nvar_b = 'Seulgi'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 162\nvar_d = 159\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "3403": {
        "category": "Arithmetic calculation",
        "question_ko": "유정이 가진 나무도막의 길이는 31미터(m)보다 30센티미터(㎝) 짧습니다. 유정이가 가진 나무도막의 길이를 센티미터(㎝)로 써보시오",
        "question_en": "The length of the wooden block of Yoojung is 30 centimeters (cm) shorter from 31 meters (m). Write the length of the wooden block that she has in centimeters (cm).",
        "answer_ko": "3070",
        "answer_en": "3070",
        "solution_abst_ko": "31 100 [OP_MUL] 30 [OP_SUB]",
        "solution_abst_en": "31 100 [OP_MUL] 30 [OP_SUB]",
        "solution_code_ko": "var_a = 31\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 30\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 31\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 30\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3404": {
        "category": "Possibility",
        "question_ko": "1, 7, 4, 3을 한 번씩 사용하여 십의 자리 숫자가 3인 가장 큰 세 자리 수와 세 번째 큰 세 자리 수의 합을 구하시오.",
        "question_en": "Find the sum of the largest and the third largest three-digit number which has 3 in the tens and that can be made by using 1, 7, 4, and 3 once.",
        "answer_ko": "1465",
        "answer_en": "1465",
        "solution_abst_ko": "[OP_LIST_SOL] 1 7 4 3 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 3 [OP_LIST_SEARCH_FIXED_DIGIT] 1 [OP_LIST_MAX] 3 [OP_LIST_GET] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 1 7 4 3 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 3 [OP_LIST_SEARCH_FIXED_DIGIT] 1 [OP_LIST_MAX] 3 [OP_LIST_GET] [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 7\nvar_c = 4\nvar_d = 3\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 3\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nvar_j = 3\nvar_k = list_c[var_j-1]\nvar_l = var_i + var_k\nprint(int(var_l))",
        "solution_code_en": "var_a = 1\nvar_b = 7\nvar_c = 4\nvar_d = 3\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 3\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nvar_j = 3\nvar_k = list_c[var_j-1]\nvar_l = var_i + var_k\nprint(int(var_l))"
    },
    "3405": {
        "category": "Comparison",
        "question_ko": "동민이네 학교의 운동장은 1105제곱미터(㎡)이며 학생 수는 650명입니다. 용희네 학교의 운동장은 1440제곱미터(㎡)이며 학생 수는 960 명입니다. 한 명당 사용하는 운동장의 넓이는 누구의 학교가 더 넓습니까?",
        "question_en": "The playground of Dongmin's School is 1105 square meters (m2) and has 650 students. The playground at Yonghee's school is 1440 square meters (m2) and has 960 students. Whose school has the largest playground area per student?",
        "answer_ko": "동민",
        "answer_en": "Dongmin",
        "solution_abst_ko": "[OP_LIST_SOL] 동민 용희 [OP_LIST_EOL] [OP_LIST_SOL] 1105 650 [OP_DIV] 1440 960 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Dongmin Yonghee [OP_LIST_EOL] [OP_LIST_SOL] 1105 650 [OP_DIV] 1440 960 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '동민'\nvar_b = '용희'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1105\nvar_d = 650\nvar_e = var_c / var_d\nvar_f = 1440\nvar_g = 960\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Dongmin'\nvar_b = 'Yonghee'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1105\nvar_d = 650\nvar_e = var_c / var_d\nvar_f = 1440\nvar_g = 960\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "3406": {
        "category": "Geometry",
        "question_ko": "넓이가 44제곱센티미터(㎠)이고 높이가 11센티미터(㎝)인 평행사변형이 있습니다. 이 평행사변형의 밑변의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "There is a parallelogram with an area of 44 square centimeters (cm2) and a height of 11 centimeters (cm). What is the length of the base of this parallelogram in centimeters (cm)?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "44 11 [OP_DIV]",
        "solution_abst_en": "44 11 [OP_DIV]",
        "solution_code_ko": "var_a = 44\nvar_b = 11\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 44\nvar_b = 11\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "3407": {
        "category": "Geometry",
        "question_ko": "직사각형 모양의 카드가 있습니다. 이 카드의 네 변의 길이의 합은 46센티미터(㎝)이고, 가로의 길이는 세로의 길이보다 7센티미터(㎝) 길다고 할 때, 이 카드의 가로의 길이는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "There are cards in the shape of a rectangle. If the sum of the lengths of the four sides of this card is 46 centimeters (cm) and the length of the width is 7 centimeters (cm) longer than the length of the length, find the length in centimeters (cm) of the width of this card.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "46 2 [OP_DIV] 7 [OP_SUB] 2 [OP_DIV] 7 [OP_ADD]",
        "solution_abst_en": "46 2 [OP_DIV] 7 [OP_SUB] 2 [OP_DIV] 7 [OP_ADD]",
        "solution_code_ko": "var_a = 46\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 7\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 46\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 7\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "3408": {
        "category": "Correspondence",
        "question_ko": "360÷(A×A×A/B)=5 를 만족하는 가장 작은 자연수 B를 구하시오",
        "question_en": "Find the smallest natural number B such that 360÷(A×A×A/B)=5",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "360÷(A×A×A/B)=5 B [OP_NUM_UNK_SOLVER] 1 [OP_LIST_MIN]",
        "solution_abst_en": "360÷(A×A×A/B)=5 B [OP_NUM_UNK_SOLVER] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = '360÷(A×A×A/B)=5'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[var_c-1]\nprint(int(var_d))",
        "solution_code_en": "var_a = '360÷(A×A×A/B)=5'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[var_c-1]\nprint(int(var_d))"
    },
    "3409": {
        "category": "Arithmetic calculation",
        "question_ko": "9/5과 1/10, 1/2, 1/6이 있습니다. 이들의 총합은 얼마인가요?",
        "question_en": "There are 9/5, 1/10, 1/2, and 1/6. What do you get if you add them all together?",
        "answer_ko": "2.57",
        "answer_en": "2.57",
        "solution_abst_ko": "9/5 1/10 [OP_ADD] 1/2 [OP_ADD] 1/6 [OP_ADD]",
        "solution_abst_en": "9/5 1/10 [OP_ADD] 1/2 [OP_ADD] 1/6 [OP_ADD]",
        "solution_code_ko": "var_a = 1.8\nvar_b = 0.1\nvar_c = var_a + var_b\nvar_d = 0.5\nvar_e = var_c + var_d\nvar_f = 0.16666666666666666\nvar_g = var_e + var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 1.8\nvar_b = 0.1\nvar_c = var_a + var_b\nvar_d = 0.5\nvar_e = var_c + var_d\nvar_f = 0.16666666666666666\nvar_g = var_e + var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "3410": {
        "category": "Comparison",
        "question_ko": "A 공장에선 60대의 기계로 장난간 40680개를 만들었고, B 공장에선 55대의 기계로 장난감 37510개를 만들었습니다. 기계 한 대당 평균적으로 만든 장난감의 개수가 더 많은 공장은 어디입니까?",
        "question_en": "Factory A made 40,680 toys with 60 machines, and Factory B made 37,510 toys with 55 machines. Which factory made more toys per machine on average?",
        "answer_ko": "B",
        "answer_en": "B",
        "solution_abst_ko": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 40680 60 [OP_DIV] 37510 55 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 40680 60 [OP_DIV] 37510 55 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 40680\nvar_d = 60\nvar_e = var_c / var_d\nvar_f = 37510\nvar_g = 55\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 40680\nvar_d = 60\nvar_e = var_c / var_d\nvar_f = 37510\nvar_g = 55\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "3411": {
        "category": "Arithmetic calculation",
        "question_ko": "13마리의 동물 중 6마리는 검은색 동물이고 나머지는 모두 하얀색 동물입니다. 하얀색 동물은 몇 마리입니까?",
        "question_en": "Of the 13 animals, 6 are black and all others are white. How many white animals are there?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "13 6 [OP_SUB]",
        "solution_abst_en": "13 6 [OP_SUB]",
        "solution_code_ko": "var_a = 13\nvar_b = 6\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 13\nvar_b = 6\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "3412": {
        "category": "Possibility",
        "question_ko": "세 장의 숫자카드 1, 7, 3이 있다. 이 중 2개를 사용하여 가장 큰 2자리수를 만들 때, 사용되지 않은 수를 구하여라.",
        "question_en": "There are three number cards 1, 7 and 3. When two of these are used to form the largest two-digit number, find the unused number.",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 1 7 3 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] [OP_LIST_POP] [OP_NUM2LIST] [OP_SET_DIFFERENCE] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] 1 7 3 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] [OP_LIST_POP] [OP_NUM2LIST] [OP_SET_DIFFERENCE] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 1\nvar_b = 7\nvar_c = 3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nlist_d = []\nvar_f = int(var_f)\nwhile var_f//10 > 0:\n    list_d.append(var_f%10)\n    var_f = var_f//10\nlist_d.append(var_f%10)\nlist_d = list_d[::-1]\nlist_e = list(set(list_a) - set(list_d))\nvar_g = 1\nvar_h = list_e[var_g-1]\nprint(int(var_h))",
        "solution_code_en": "var_a = 1\nvar_b = 7\nvar_c = 3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nlist_d = []\nvar_f = int(var_f)\nwhile var_f//10 > 0:\n    list_d.append(var_f%10)\n    var_f = var_f//10\nlist_d.append(var_f%10)\nlist_d = list_d[::-1]\nlist_e = list(set(list_a) - set(list_d))\nvar_g = 1\nvar_h = list_e[var_g-1]\nprint(int(var_h))"
    },
    "3413": {
        "category": "Possibility",
        "question_ko": "0부터 9까지의 숫자 카드를 한 번씩 사용하여 세 자리 수를 만듭니다. 이 수 중 2번째 큰 수와 2번째 작은 수의 합를 구하시오.",
        "question_en": "Make a three-digit number by drawing the number cards from 0 to 9 once. Then, find the sum of the 2nd largest and the 2nd smallest of these numbers.",
        "answer_ko": "1089",
        "answer_en": "1089",
        "solution_abst_ko": "0 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "0 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 0\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 2\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 0\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 2\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))"
    },
    "3414": {
        "category": "Geometry",
        "question_ko": "필통 여러개를 정사각형 모양으로 빈틈없이 정렬하고 보니 6개의 필통이 남았습니다. 그래서 가로 한 변과 세로 한 변을 1열씩 늘리려 하였지만 11개의 필통이 부족하였습니다. 필통을 7열로 줄세운다면 1열에 몇 개의 필통이 있을까요?",
        "question_en": "After arranging several pencil cases into a square shape, there were 6 pencil cases left. So, I tried to increase the width and length by one row, but 11 pencil cases was not enough. If the pencil cases are lined up in 7 rows, how many pencil cases are there in one row?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "6 11 [OP_ADD] 1 [OP_SUB] 2 [OP_DIV] 2 [OP_POW] 6 [OP_ADD] 7 [OP_DIV]",
        "solution_abst_en": "6 11 [OP_ADD] 1 [OP_SUB] 2 [OP_DIV] 2 [OP_POW] 6 [OP_ADD] 7 [OP_DIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 11\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 6\nvar_k = var_i + var_j\nvar_l = 7\nvar_m = var_k / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 6\nvar_b = 11\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 6\nvar_k = var_i + var_j\nvar_l = 7\nvar_m = var_k / var_l\nprint(int(var_m))"
    },
    "3415": {
        "category": "Comparison",
        "question_ko": "5, 8, 4, 3, 7중 2번째로 큰 숫자는 무엇입니까?",
        "question_en": "What is the second largest number among 5, 8, 4, 3, and 7?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "[OP_LIST_SOL] 5 8 4 3 7 [OP_LIST_EOL] 2 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 5 8 4 3 7 [OP_LIST_EOL] 2 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 5\nvar_b = 8\nvar_c = 4\nvar_d = 3\nvar_e = 7\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 8\nvar_c = 4\nvar_d = 3\nvar_e = 7\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nprint(int(var_g))"
    },
    "3416": {
        "category": "Arithmetic calculation",
        "question_ko": "동현이네 반 담임선생님은 반 학생들이 선행을 할 때마다 칭찬 스티커를 나눠줍니다. 10명의 학생이 받은 칭찬 스티커가 각각 5, 6, 5, 5, 6, 4, 5, 5, 6, 7장일 때, 칭찬 스티커를 5장 받은 학생은 몇 명입니까?",
        "question_en": "Donghyeon's class teacher gives away compliment stickers to classmates whenever they do a good deed. If 10 students each received 5, 6, 5, 5, 6, 4, 5, 5, 6, 7 compliment stickers, how many students received 5 compliment stickers?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "[OP_LIST_SOL] 5 6 5 5 6 4 5 5 6 7 [OP_LIST_EOL] 5 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "[OP_LIST_SOL] 5 6 5 5 6 4 5 5 6 7 [OP_LIST_EOL] 5 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 5\nvar_b = 6\nvar_c = 5\nvar_d = 5\nvar_e = 6\nvar_f = 4\nvar_g = 5\nvar_h = 5\nvar_i = 6\nvar_j = 7\nlist_a= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_a.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_k = 5\nvar_l = 0\nvar_k = int(var_k)\nfor i in list_a:\n    i = int(i)\n    if i == var_k:\n        var_l = var_l + 1\nprint(int(var_l))",
        "solution_code_en": "var_a = 5\nvar_b = 6\nvar_c = 5\nvar_d = 5\nvar_e = 6\nvar_f = 4\nvar_g = 5\nvar_h = 5\nvar_i = 6\nvar_j = 7\nlist_a= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_a.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_k = 5\nvar_l = 0\nvar_k = int(var_k)\nfor i in list_a:\n    i = int(i)\n    if i == var_k:\n        var_l = var_l + 1\nprint(int(var_l))"
    },
    "3417": {
        "category": "Possibility",
        "question_ko": "1000보다 작고 100보다 큰 수 중 1, 2, 5 모두로 이루어진 가장 작은 수와 큰 수의 합을 구하시오.",
        "question_en": "Find the sum of the smallest and largest numbers that are made up of 1, 2, and 5 and are greater than 100 and less than 1000.",
        "answer_ko": "646",
        "answer_en": "646",
        "solution_abst_ko": "[OP_LIST_SOL] 1 2 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 1 2 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 2\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 2\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))"
    },
    "3418": {
        "category": "Geometry",
        "question_ko": "가로 40 센티미터(㎝) , 세로 25센티미터(㎝) 인 직사각형 모양의 종이에서 정육면체의 전개도를 오리고 남은 종이의 넓이가 13제곱센티미터(㎠)일 때, 정육면체의 한 모서리는 몇 센티미터(㎝) 입니까?",
        "question_en": "If the area of the remaining paper is 13 square centimeters (cm2) after a cube is cut from a rectangular piece of paper measuring 40 centimeters (cm) long and 25 centimeters (cm) wide, how many centimeters (cm) is one edge of the cube?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "40 25 [OP_MUL] 136 [OP_SUB] 6 [OP_DIV] 1/2 [OP_POW]",
        "solution_abst_en": "40 25 [OP_MUL] 136 [OP_SUB] 6 [OP_DIV] 1/2 [OP_POW]",
        "solution_code_ko": "var_a = 40\nvar_b = 25\nvar_c = var_a * var_b\nvar_d = 136\nvar_e = var_c - var_d\nvar_f = 6\nvar_g = var_e / var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 40\nvar_b = 25\nvar_c = var_a * var_b\nvar_d = 136\nvar_e = var_c - var_d\nvar_f = 6\nvar_g = var_e / var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))"
    },
    "3419": {
        "category": "Correspondence",
        "question_ko": "어느 동아리의 부원 수는 52명이다. 이 중 37명이 남자일 때, 여자인 부원은 몇 명인가?",
        "question_en": "A club has 52 members. If 37 of them are men, how many of them are women?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "52 37 [OP_SUB]",
        "solution_abst_en": "52 37 [OP_SUB]",
        "solution_code_ko": "var_a = 52\nvar_b = 37\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 52\nvar_b = 37\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "3420": {
        "category": "Geometry",
        "question_ko": "마름모 모양의 키 홀더가 있습니다. 키 홀더의 한 대각선의 길이가 7.4센티미터(㎝)이고, 넓이가 21.46제곱센티미터(㎠)라면 다른 대각선은 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "There is a rhombus-shaped key holder. If the length of one diagonal of the key holder is 7.4 centimeters (cm) and the area is 21.46 square centimeters (cm2), how long is the other diagonal in centimeters (cm?)",
        "answer_ko": "5.80",
        "answer_en": "5.8",
        "solution_abst_ko": "21.46 2 [OP_MUL] 7.4 [OP_DIV]",
        "solution_abst_en": "21.46 2 [OP_MUL] 7.4 [OP_DIV]",
        "solution_code_ko": "var_a = 21.46\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 7.4\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 21.46\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 7.4\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "3421": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 4배 한 다음 25을 곱하였더니 812가 되었습니다. 어떤 수를 구하시오.",
        "question_en": "I multiplied a particular number by 4 and then multiplied again by 25 and I got 812. Find that particular number.",
        "answer_ko": "8.12",
        "answer_en": "8.12",
        "solution_abst_ko": "812 25 [OP_DIV] 4 [OP_DIV]",
        "solution_abst_en": "812 25 [OP_DIV] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 812\nvar_b = 25\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 812\nvar_b = 25\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "3422": {
        "category": "Arithmetic calculation",
        "question_ko": "12이상 53이하의 자연수의 평균은 얼마입니까?",
        "question_en": "What is the average of the natural numbers greater than 12 and less than 53?",
        "answer_ko": "32.50",
        "answer_en": "32.5",
        "solution_abst_ko": "12 53 1 [OP_LIST_ARANGE] [OP_LIST_MEAN]",
        "solution_abst_en": "12 53 1 [OP_LIST_ARANGE] [OP_LIST_MEAN]",
        "solution_code_ko": "var_a = 12\nvar_b = 53\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_a = [float(i) for i in list_a]\nvar_d = sum(list_a)/len(list_a)\nprint('{:.2f}'.format(round(var_d+1e-10,2)))",
        "solution_code_en": "var_a = 12\nvar_b = 53\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_a = [float(i) for i in list_a]\nvar_d = sum(list_a)/len(list_a)\nprint('{:.2f}'.format(round(var_d+1e-10,2)))"
    },
    "3423": {
        "category": "Arithmetic calculation",
        "question_ko": "효림이네 학급 6학년 학생들은 졸업을 앞두고 수학여행을 떠나기로 했습니다. 학생 252명과 선생님 8명이 함께 갈 때, 41인승 버스를 한 대 빌리는 값은 300000원이고, 버스 한 대당 고속도로 통행료는 7500이라면 버스를 빌리고 통행료를 내는 데 모두 얼마가 필요합니까?",
        "question_en": "Hyorim's 6th graders decided to go on a field trip ahead of graduation. If 252 students and 8 teachers go together, the cost of renting a 41-seater bus is 300,000 won and the highway toll per bus is 7,500. How much does it cost to rent the bus and pay the toll?",
        "answer_ko": "2152500",
        "answer_en": "2152500",
        "solution_abst_ko": "252 8 [OP_ADD] 41 [OP_DIV] 1 [OP_CEIL] 300000 7500 [OP_ADD] [OP_MUL]",
        "solution_abst_en": "252 8 [OP_ADD] 41 [OP_DIV] 1 [OP_CEIL] 300000 7500 [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 252\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 41\nvar_e = var_c / var_d\nvar_f = 1\nvar_g=int(((var_e+9*10**(var_f-2))//(10**(var_f-1)))*10**(var_f-1))\n\nvar_h = 300000\nvar_i = 7500\nvar_j = var_h + var_i\nvar_k = var_g * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 252\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 41\nvar_e = var_c / var_d\nvar_f = 1\nvar_g=int(((var_e+9*10**(var_f-2))//(10**(var_f-1)))*10**(var_f-1))\n\nvar_h = 300000\nvar_i = 7500\nvar_j = var_h + var_i\nvar_k = var_g * var_j\nprint(int(var_k))"
    },
    "3424": {
        "category": "Correspondence",
        "question_ko": "9는 어떤 수에 2를 빼고 4를 더한 수 입니다. 어떤 수를 구하시오",
        "question_en": "9 is a number that 2 subtracted from the number and added with 4. Find what the number is. ",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "9 2 [OP_ADD] 4 [OP_SUB]",
        "solution_abst_en": "9 2 [OP_ADD] 4 [OP_SUB]",
        "solution_code_ko": "var_a = 9\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3425": {
        "category": "Comparison",
        "question_ko": "우표 25장을 형과 동생이 나누어 가지려고 합니다. 형은 동생이 가지는 우표의 수의 2배보다 1장 더 가진다면 형이 가지는 우표는 몇 장인지 구하시오.",
        "question_en": "The older brother and younger brother are going to share 25 stamps. If the older brother has 1 more stamp than twice the number of stamps the younger brother has, find how many stamps the older brother has.",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "25 1 [OP_SUB] 2 1 [OP_ADD] [OP_DIV] 2 [OP_MUL] 1 [OP_ADD]",
        "solution_abst_en": "25 1 [OP_SUB] 2 1 [OP_ADD] [OP_DIV] 2 [OP_MUL] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 25\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = var_c / var_f\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = 1\nvar_k = var_i + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 25\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = var_c / var_f\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = 1\nvar_k = var_i + var_j\nprint(int(var_k))"
    },
    "3426": {
        "category": "Arithmetic calculation",
        "question_ko": "빨간색 사과 8개, 초록색 사과 5개, 귤 9개가 있습니다. 귤은 사과보다 몇 개 더 적습니까?",
        "question_en": "There are 8 red apples, 5 green apples, and 9 tangerines. How many fewer tangerines than apples?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "8 5 [OP_ADD] 9 [OP_SUB]",
        "solution_abst_en": "8 5 [OP_ADD] 9 [OP_SUB]",
        "solution_code_ko": "var_a = 8\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3427": {
        "category": "Correspondence",
        "question_ko": "어떤 수와 5.46의 차이가 3.97이고 어떤 수가 5.46보다 작다고 할 때, 어떤 수와 5.46의 합을 구하시오.",
        "question_en": "If the gap between a certain number and 5.46 is 3.97 and the number is less than 5.46, find the sum of the number and 5.46.",
        "answer_ko": "6.95",
        "answer_en": "6.95",
        "solution_abst_ko": "5.46 5.46 3.97 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "5.46 5.46 3.97 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 5.46\nvar_b = 5.46\nvar_c = 3.97\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 5.46\nvar_b = 5.46\nvar_c = 3.97\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "3428": {
        "category": "Correspondence",
        "question_ko": "A72-23=549입니다. A는 얼마인가요?",
        "question_en": "When there is an equation, A72-23=549, find the number A.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "A72-23=549 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A72-23=549 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A72-23=549'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A72-23=549'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "3429": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 15.25 센티미터(㎝) 인 마스크 20 장을 겹치게 이어 붙이려고 합니다. 이어 붙인 마스크의 전체 길이가 248 센티미터(㎝) 가 되도록 하려면 모두 몇 센티미터(㎝) 씩 겹치게 이어 붙여야 합니까?",
        "question_en": "I'm going to connect 20 masks, each 15.25 centimeters (cm) long. How many centimeters (cm) do I need to attach the masks so that the total is 248 centimeters (cm)?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "15.25 248 15.25 [OP_SUB] 20 1 [OP_SUB] [OP_DIV] [OP_SUB]",
        "solution_abst_en": "15.25 248 15.25 [OP_SUB] 20 1 [OP_SUB] [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 15.25\nvar_b = 248\nvar_c = 15.25\nvar_d = var_b - var_c\nvar_e = 20\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d / var_g\nvar_i = var_a - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 15.25\nvar_b = 248\nvar_c = 15.25\nvar_d = var_b - var_c\nvar_e = 20\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d / var_g\nvar_i = var_a - var_h\nprint(int(var_i))"
    },
    "3430": {
        "category": "Correspondence",
        "question_ko": "12로 나누어 떨어지는 네 자리 수가 있습니다. 천의 자리 숫자가 2일때 이러한 네 자리 수는 모두 몇 개인가요?",
        "question_en": "There are four-digit numbers that are divisible by 12. If the thousands digit is 2, how many of the four-digit numbers are there?",
        "answer_ko": "83",
        "answer_en": "83",
        "solution_abst_ko": "2 1000 [OP_MUL] 2 1000 [OP_MUL] 999 [OP_ADD] 1 [OP_LIST_ARANGE] 12 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "2 1000 [OP_MUL] 2 1000 [OP_MUL] 999 [OP_ADD] 1 [OP_LIST_ARANGE] 12 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = 999\nvar_h = var_f + var_g\nvar_i = 1\nlist_a = [i for i in range(var_c, var_h + 1, var_i)]\nvar_j = 12\nlist_b = []\nvar_j = int(var_j)\nfor i in list_a:\n    i = int(i)\n    if i % var_j == 0:\n        list_b.append(i)\nvar_k = len(list_b)\nprint(int(var_k))",
        "solution_code_en": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = 999\nvar_h = var_f + var_g\nvar_i = 1\nlist_a = [i for i in range(var_c, var_h + 1, var_i)]\nvar_j = 12\nlist_b = []\nvar_j = int(var_j)\nfor i in list_a:\n    i = int(i)\n    if i % var_j == 0:\n        list_b.append(i)\nvar_k = len(list_b)\nprint(int(var_k))"
    },
    "3431": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 2, 3, 9로 나누어떨어질 수 있는 세 자리 수는 모두 몇 개 있습니까?",
        "question_en": "How many three-digit numbers are divisible by the three numbers 2, 3, and 9?",
        "answer_ko": "50",
        "answer_en": "50",
        "solution_abst_ko": "100 999 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "100 999 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 3\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 9\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))",
        "solution_code_en": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 3\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 9\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))"
    },
    "3432": {
        "category": "Correspondence",
        "question_ko": "36에 어떤 수를 빼야 할 것을 잘못하여 63에 어떤 수를 뺐더니 70이 되었습니다. 바르게 계산하면 얼마인지 구하시오.",
        "question_en": "I mistakenly subtracted a certain number from 63 when I had to subtract this number from 36, and it became 70. How much is it if calculated correctly?",
        "answer_ko": "43",
        "answer_en": "43",
        "solution_abst_ko": "36 63 70 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "36 63 70 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 36\nvar_b = 63\nvar_c = 70\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 36\nvar_b = 63\nvar_c = 70\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "3433": {
        "category": "Geometry",
        "question_ko": "밑면의 한 변의 길이가 13/12미터(m)이며 정삼각기둥 모양인 상자가 있습니다. 이 상자의 둘레를 따라 리본을 두를 때 리본은 최소 몇 미터(m) 필요합니까?",
        "question_en": "There is a box with a base in the shape of an equilateral triangular prism with a side of 13/12 meters (m). What are the minimum meters (m) of ribbon required to wrap the ribbon around the perimeter of this box?",
        "answer_ko": "3.25",
        "answer_en": "3.25",
        "solution_abst_ko": "13/12 3 [OP_MUL]",
        "solution_abst_en": "13/12 3 [OP_MUL]",
        "solution_code_ko": "var_a = 1.0833333333333333\nvar_b = 3\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 1.0833333333333333\nvar_b = 3\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "3434": {
        "category": "Geometry",
        "question_ko": "가로의 길이가 25센티미터(㎝)이고, 세로의 길이가 20센티미터(㎝)인 직사각형의 넓이를 구하시오.",
        "question_en": "Find the area of a rectangle whose width is 25 centimeters (cm) and its length is 20 centimeters (cm).",
        "answer_ko": "500",
        "answer_en": "500",
        "solution_abst_ko": "25 20 [OP_MUL]",
        "solution_abst_en": "25 20 [OP_MUL]",
        "solution_code_ko": "var_a = 25\nvar_b = 20\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 25\nvar_b = 20\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "3435": {
        "category": "Comparison",
        "question_ko": "지우는 1100밀리리터(㎖) 우유와 3리터(L) 400밀리리터(㎖)의 주스를 마셨습니다. 정국이는 4리터(L) 800밀리리터(㎖)의 물을 마셨을 때 누가 더 많이 마셨을까요?",
        "question_en": "Jiwoo drank 1100 milliliters (ml) of milk, 3 liters (l) and 400 milliliters (ml) of juice. When Jungkook drank 4 liters (l) and 800 milliliters (ml) of water, who drank more?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 지우 [OP_LIST_EOL] [OP_LIST_SOL] 4 1000 [OP_MUL] 800 [OP_ADD] 1100 3 1000 [OP_MUL] 400 [OP_ADD] [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Jiwoo [OP_LIST_EOL] [OP_LIST_SOL] 4 1000 [OP_MUL] 800 [OP_ADD] 1100 3 1000 [OP_MUL] 400 [OP_ADD] [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '지우'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 800\nvar_g = var_e + var_f\nvar_h = 1100\nvar_i = 3\nvar_j = 1000\nvar_k = var_i * var_j\nvar_l = 400\nvar_m = var_k + var_l\nvar_n = var_h + var_m\nlist_b= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_o = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_p = list_c[-var_o]\nvar_q = list_b.index(var_p)+1\nvar_r = list_a[var_q-1]\nprint(var_r)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Jiwoo'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 800\nvar_g = var_e + var_f\nvar_h = 1100\nvar_i = 3\nvar_j = 1000\nvar_k = var_i * var_j\nvar_l = 400\nvar_m = var_k + var_l\nvar_n = var_h + var_m\nlist_b= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_o = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_p = list_c[-var_o]\nvar_q = list_b.index(var_p)+1\nvar_r = list_a[var_q-1]\nprint(var_r)"
    },
    "3436": {
        "category": "Comparison",
        "question_ko": "학생들이 한 줄로 서 있습니다. 유정이는 맨 뒤에 서 있습니다. 은정이는 앞에서 5번째에 서 있습니다. 은정이와 유정이 사이에 8명이 서 있을 때, 줄을 서 있는 학생은 모두 몇 명입니까?",
        "question_en": "When students standing in a line, Yoojung was at the very back. And there are 8 students standing between Eunjeong and Yoojung. If Eunjeong was at 5th place from the front, how many students were there?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "5 8 [OP_ADD] 1 [OP_ADD]",
        "solution_abst_en": "5 8 [OP_ADD] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3437": {
        "category": "Geometry",
        "question_ko": "음료수 여러 캔을 정사각형 모양으로 빈틈없이 정렬하니 6개의 캔이 남았습니다. 그래서 가로 한 변과 세로 한 변을 1열씩 늘리려 하였지만 11개의 캔이 부족하였습니다. 이 캔들을 7열로 세운다면 1열에 몇 캔씩 있을까요?",
        "question_en": "After arranging several cans of soda in a square shape, there were 6 cans left. So, I tried to increase the width and length by one row, but 11 cans were inadequate. If you arrange these cans in 7 rows, how many cans are there in one row?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "6 11 [OP_ADD] 1 [OP_SUB] 2 [OP_DIV] 2 [OP_POW] 6 [OP_ADD] 7 [OP_DIV]",
        "solution_abst_en": "6 11 [OP_ADD] 1 [OP_SUB] 2 [OP_DIV] 2 [OP_POW] 6 [OP_ADD] 7 [OP_DIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 11\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 6\nvar_k = var_i + var_j\nvar_l = 7\nvar_m = var_k / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 6\nvar_b = 11\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 6\nvar_k = var_i + var_j\nvar_l = 7\nvar_m = var_k / var_l\nprint(int(var_m))"
    },
    "3438": {
        "category": "Comparison",
        "question_ko": "정국이는 윤기보다 키가 큽니다. 남준이는 정국이보다 키가 크고 유나보다 키가 작습니다. 4명 중 키가 가장 작은 사람은 누구입니까?",
        "question_en": "Jungkook is taller than Yoongi. Namjoon is taller than Jungkook and shorter than Yuna. Which of the 4 people is the shortest?",
        "answer_ko": "윤기",
        "answer_en": "Yoongi",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 윤기 남준 유나 [OP_LIST_EOL] [OP_LIST_SOL] 정국 윤기 > 남준 정국 > 남준 유나 < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Yoongi Namjoon Yuna [OP_LIST_EOL] [OP_LIST_SOL] Jungkook Yoongi > Namjoon Jungkook > Namjoon Yuna < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '윤기'\nvar_c = '남준'\nvar_d = '유나'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '정국'\nvar_f = '윤기'\nvar_g = '>'\nvar_h = '남준'\nvar_i = '정국'\nvar_j = '>'\nvar_k = '남준'\nvar_l = '유나'\nvar_m = '<'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Yoongi'\nvar_c = 'Namjoon'\nvar_d = 'Yuna'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'Jungkook'\nvar_f = 'Yoongi'\nvar_g = '>'\nvar_h = 'Namjoon'\nvar_i = 'Jungkook'\nvar_j = '>'\nvar_k = 'Namjoon'\nvar_l = 'Yuna'\nvar_m = '<'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)"
    },
    "3439": {
        "category": "Correspondence",
        "question_ko": "세 자리 수 A27이 있습니다. 이 수를 백의 자리에서 버림했을 때 200을 얻을 수 있습니다. A를 구하시오.",
        "question_en": "I have a three-digit A27. When I round down this number from the hundreds place, I get 200. Find A.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "A27 [OP_GEN_POSSIBLE_LIST] 200 [OP_LIST_MORE_EQUAL] 200 100 [OP_ADD] [OP_LIST_LESS] A [OP_LIST_FIND_UNK]",
        "solution_abst_en": "A27 [OP_GEN_POSSIBLE_LIST] 200 [OP_LIST_MORE_EQUAL] 200 100 [OP_ADD] [OP_LIST_LESS] A [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = 'A27'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 200\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 200\nvar_d = 100\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = 'A'\nvar_a = str(var_a)\nvar_f = str(var_f)\nunk_idx = var_a.index(var_f)\nvar_g = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_g = int(elem[unk_idx])\nprint(int(var_g))",
        "solution_code_en": "var_a = 'A27'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 200\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 200\nvar_d = 100\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = 'A'\nvar_a = str(var_a)\nvar_f = str(var_f)\nunk_idx = var_a.index(var_f)\nvar_g = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_g = int(elem[unk_idx])\nprint(int(var_g))"
    },
    "3440": {
        "category": "Possibility",
        "question_ko": "4 장의 숫자 카드 1, 3, 4, 7 중 3 장을 뽑아 한 번씩만 사용하여 세 자리 수를 만들려고 합니다. 만들 수 있는 수 중에서 360 초과 455 이하인 수는 모두 몇 개입니까?",
        "question_en": "You are trying to create a three-digit number by drawing 3 of the 4 number cards 1, 3, 4, 7, and using them only once. How many possible numbers are greater than 360 and less than or equal to 455?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 4 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 360 [OP_LIST_MORE] 455 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 4 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 360 [OP_LIST_MORE] 455 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 4\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 360\nlist_c = []\nfor i in list_b:\n    if i > var_f:\n        list_c.append(i)\nvar_g = 455\nlist_d = []\nfor i in list_c:\n    if i <= var_g:\n        list_d.append(i)\nvar_h = len(list_d)\nprint(int(var_h))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 4\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 360\nlist_c = []\nfor i in list_b:\n    if i > var_f:\n        list_c.append(i)\nvar_g = 455\nlist_d = []\nfor i in list_c:\n    if i <= var_g:\n        list_d.append(i)\nvar_h = len(list_d)\nprint(int(var_h))"
    },
    "3441": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 7을 뺐더니 9가 되었습니다. 어떤 수를 5에 곱한 결과값은 얼마일까요?",
        "question_en": "Subtracting 7 from a number gives 9. What is the product of multiplying a number by 5?",
        "answer_ko": "80",
        "answer_en": "80",
        "solution_abst_ko": "9 7 [OP_ADD] 5 [OP_MUL]",
        "solution_abst_en": "9 7 [OP_ADD] 5 [OP_MUL]",
        "solution_code_ko": "var_a = 9\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "3442": {
        "category": "Comparison",
        "question_ko": "3개의 숫자 0.8, 1/2, 9가 있습니다. 2보다 크거나 같은 수 중 가장 작거나 같은 수는 얼마인가요?",
        "question_en": "There are three numbers 0.8, 1/2, and 9. Which of the numbers greater than or equal to 2?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 9 [OP_LIST_EOL] 2 [OP_LIST_MORE_EQUAL] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 9 [OP_LIST_EOL] 2 [OP_LIST_MORE_EQUAL] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nprint(int(var_f))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nprint(int(var_f))"
    },
    "3443": {
        "category": "Comparison",
        "question_ko": "나는 두 반의 학생들에게 지우개를 나누어 주었다. 도훈이네 반은 15명이 지우개 45개를 공유하고, 기훈이네 반은 5명이 지우개 30개를 공유한다. 어떤 반에서 한 학생이 더 많은 지우개를 가지게 됩니까?",
        "question_en": "I handed out erasers to both classes. In Dohun’s class, 15 people share 45 erasers, and in Kihun’s class, 5 people share 30 erasers. In which class will one student have more eraser?",
        "answer_ko": "기훈",
        "answer_en": "Kihun",
        "solution_abst_ko": "[OP_LIST_SOL] 도훈 기훈 [OP_LIST_EOL] [OP_LIST_SOL] 45 15 [OP_DIV] 30 5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Dohun Kihun [OP_LIST_EOL] [OP_LIST_SOL] 45 15 [OP_DIV] 30 5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '도훈'\nvar_b = '기훈'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 45\nvar_d = 15\nvar_e = var_c / var_d\nvar_f = 30\nvar_g = 5\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Dohun'\nvar_b = 'Kihun'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 45\nvar_d = 15\nvar_e = var_c / var_d\nvar_f = 30\nvar_g = 5\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "3444": {
        "category": "Correspondence",
        "question_ko": "A는 634입니다. A는 C보다 593만큼 큽니다. C는 B보다 482만큼 작습니다. B를 구하시오.",
        "question_en": "A is 634. A is 593 greater than C. C is 482 less than B. Get B.",
        "answer_ko": "523",
        "answer_en": "523",
        "solution_abst_ko": "634 593 [OP_SUB] 482 [OP_ADD]",
        "solution_abst_en": "634 593 [OP_SUB] 482 [OP_ADD]",
        "solution_code_ko": "var_a = 634\nvar_b = 593\nvar_c = var_a - var_b\nvar_d = 482\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 634\nvar_b = 593\nvar_c = var_a - var_b\nvar_d = 482\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3445": {
        "category": "Correspondence",
        "question_ko": "윤기는 어떤 숫자에 7을 빼서 9를 얻었습니다. 이 숫자에 3을 곱하면 얼마입니까?",
        "question_en": "Yoongi subtracted 7 from a certain number and got 9. What is this number multiplied by 3?",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "9 7 [OP_ADD] 3 [OP_MUL]",
        "solution_abst_en": "9 7 [OP_ADD] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 9\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "3446": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 46을 뺐더니 15가 되었습니다. 어떤 수에서 29를 빼면 얼마가 되는지 구하시오.",
        "question_en": "Subtracting 46 from a number resulted in 15. Find how much it would be when 29 is subtracted from this number.",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "15 46 [OP_ADD] 29 [OP_SUB]",
        "solution_abst_en": "15 46 [OP_ADD] 29 [OP_SUB]",
        "solution_code_ko": "var_a = 15\nvar_b = 46\nvar_c = var_a + var_b\nvar_d = 29\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 46\nvar_c = var_a + var_b\nvar_d = 29\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3447": {
        "category": "Arithmetic calculation",
        "question_ko": "경훈이가 등산을 하는데 올라갈 때는 시속 3 킬로미터(㎞)로 걷고, 내려올 때는 올라갈 때보다 2 킬로미터(㎞) 더 먼 길을 택하여 시속 4 킬로미터(㎞)로 걸어서 총 4시간이 걸렸다고 한다. 경훈이가 내려간 거리는?",
        "question_en": "Gyeong-hun climbed the mountain, walking at 3 kilometers (km) per hour on the way up and walking at 4 kilometers (km) per hour on the way down, taking an extra 2 kilometers (km) on the way down, for a total of 4 hours. How far did Gyeong-hun go?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "4 2 4 [OP_DIV] [OP_SUB] 1 3 [OP_DIV] 1 4 [OP_DIV] [OP_ADD] [OP_DIV] 2 [OP_ADD]",
        "solution_abst_en": "4 2 4 [OP_DIV] [OP_SUB] 1 3 [OP_DIV] 1 4 [OP_DIV] [OP_ADD] [OP_DIV] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = 3\nvar_h = var_f / var_g\nvar_i = 1\nvar_j = 4\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_e / var_l\nvar_n = 2\nvar_o = var_m + var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = 3\nvar_h = var_f / var_g\nvar_i = 1\nvar_j = 4\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_e / var_l\nvar_n = 2\nvar_o = var_m + var_n\nprint(int(var_o))"
    },
    "3448": {
        "category": "Possibility",
        "question_ko": "1, 3, 7, 9를 한 번씩 사용하여 만든 네 자리 숫자 중 일의 자리가 7인 수는 몇 개입니까?",
        "question_en": "How many four-digit numbers formed by using 1, 3, 7, and 9 once have a 7 in the ones place?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 7 9 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1 7 [OP_LIST_SEARCH_FIXED_DIGIT] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 7 9 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1 7 [OP_LIST_SEARCH_FIXED_DIGIT] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 7\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nvar_g = 7\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = len(list_c)\nprint(int(var_h))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 7\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nvar_g = 7\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = len(list_c)\nprint(int(var_h))"
    },
    "3449": {
        "category": "Arithmetic calculation",
        "question_ko": "28의 약수 중 가장 작은 수는 무엇인지 구하세요",
        "question_en": "Find the smallest divisor of 28.",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "28 [OP_LIST_GET_DIVISOR] 1 [OP_LIST_MIN]",
        "solution_abst_en": "28 [OP_LIST_GET_DIVISOR] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 28\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_c = list_b[var_b-1]\nprint(int(var_c))",
        "solution_code_en": "var_a = 28\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_c = list_b[var_b-1]\nprint(int(var_c))"
    },
    "3450": {
        "category": "Geometry",
        "question_ko": "사각형, 삼각형, 원의 변의 수를 합하면 모두 얼마입니까?",
        "question_en": "What do you get if you add all the numbers of sides of a rectangle, triangle, and a circle?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "0 3 [OP_ADD] 4 [OP_ADD]",
        "solution_abst_en": "0 3 [OP_ADD] 4 [OP_ADD]",
        "solution_code_ko": "var_a = 0\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 0\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3451": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 10, 11, 12, 13이 있습니다. 그 중에서 가장 작은 수와 그 다음으로 작은 수의 합은 얼마입니까?",
        "question_en": "There are four numbers 10, 11, 12, and 13. What is the sum of the smallest number and the next smallest number?",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))"
    },
    "3452": {
        "category": "Possibility",
        "question_ko": "4, 2, 8, 1, 9 수 카드를 한 번씩만 사용하여 몫이 가장 큰 (세 자리 수)÷(두 자리 수)를 만들었을 때의 몫을 구하세요.",
        "question_en": "Find the largest quotient of (three-digit number) ÷ (two-digit number) using the number cards 4, 2, 8, 1, 9 only once.",
        "answer_ko": "82",
        "answer_en": "82",
        "solution_abst_ko": "[OP_LIST_SOL] 4 2 8 1 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] [OP_LIST_POP] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] [OP_FDIV]",
        "solution_abst_en": "[OP_LIST_SOL] 4 2 8 1 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] [OP_LIST_POP] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] [OP_FDIV]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = 8\nvar_d = 1\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 2\nlist_d = [str(i) for i in list_a]\nlist_d = list(itertools.permutations(list_d, var_i))\nlist_d = [''.join(num_list) for num_list in list_d]\nlist_d = [str_num for str_num in list_d if str_num[0] != '0']\nlist_d = [float(i) for i in list_d]\nvar_j = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_k = list_e[var_j-1]\nvar_l = var_h // var_k\nprint(int(var_l))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = 8\nvar_d = 1\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 2\nlist_d = [str(i) for i in list_a]\nlist_d = list(itertools.permutations(list_d, var_i))\nlist_d = [''.join(num_list) for num_list in list_d]\nlist_d = [str_num for str_num in list_d if str_num[0] != '0']\nlist_d = [float(i) for i in list_d]\nvar_j = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_k = list_e[var_j-1]\nvar_l = var_h // var_k\nprint(int(var_l))"
    },
    "3453": {
        "category": "Geometry",
        "question_ko": "가로가 12센티미터(㎝), 세로가 15센티미터(㎝)인 직사각형 모양의 벽돌을 겹치지 않게 늘어놓아 최대한 작은 정사각형을 만들려고 합니다. 벽돌은 모두 몇 장 필요할까요?",
        "question_en": "I am trying to make a square as small as possible by arranging rectangular bricks 12 centimeters (cm) wide and 15 centimeters (cm) long without overlapping. How many bricks will you need altogether?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "12 15 [OP_LCM] 2 [OP_POW] 12 15 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "12 15 [OP_LCM] 2 [OP_POW] 12 15 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 15\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 12\nvar_g = 15\nvar_h = var_f * var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 12\nvar_b = 15\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 12\nvar_g = 15\nvar_h = var_f * var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "3454": {
        "category": "Correspondence",
        "question_ko": "51은 어떤 수에 6을 곱해야 했는데 실수로 빼서 나온 결과입니다. 원래대로 계산한다면 얼마입니까?",
        "question_en": "51 is the result of mistakenly subtracting 6 from a number instead of multipling by 6. How much is it if you calculate it correctly?",
        "answer_ko": "342",
        "answer_en": "342",
        "solution_abst_ko": "51 6 [OP_ADD] 6 [OP_MUL]",
        "solution_abst_en": "51 6 [OP_ADD] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 51\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 51\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "3455": {
        "category": "Correspondence",
        "question_ko": "지훈이는 낚시대를 만들기 위해 낚시줄을 잘라냈습니다. 현재 낚시줄 길이에서 3.1미터(m)를 더하고 3.1배 한 값에서 다시 2.1을 곱한 길이가 원래 낚시줄의 길이였습니다. 지훈이의 낚시대의 낚시줄 길이는 8.9미터(m) 일 때, 원래 낚시줄의 길이는 몇 미터(m)인지 구하시오.",
        "question_en": "Jihoon cut a fishing line to make a fishing rod. When you add 3.1 meters (m) to the current length of this fishing line, multiply it 3.1 times, and then multiply it again by 2.1 it becomes the length of the original fishing line. If the length of the fishing line of Ji-hoon's fishing rod is 8.9 meters (m), find the original length of the fishing line in meters (m).",
        "answer_ko": "78.12",
        "answer_en": "78.12",
        "solution_abst_ko": "8.9 3.1 [OP_ADD] 3.1 [OP_MUL] 2.1 [OP_MUL]",
        "solution_abst_en": "8.9 3.1 [OP_ADD] 3.1 [OP_MUL] 2.1 [OP_MUL]",
        "solution_code_ko": "var_a = 8.9\nvar_b = 3.1\nvar_c = var_a + var_b\nvar_d = 3.1\nvar_e = var_c * var_d\nvar_f = 2.1\nvar_g = var_e * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 8.9\nvar_b = 3.1\nvar_c = var_a + var_b\nvar_d = 3.1\nvar_e = var_c * var_d\nvar_f = 2.1\nvar_g = var_e * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "3456": {
        "category": "Comparison",
        "question_ko": "장난감 19개를 한 줄로 놓았습니다. 장난감 (가)는 오른쪽에서 8번째라면 왼쪽에서는 몇 번째입니까?",
        "question_en": "19 toys are placed in a row. If Toy (A) is 8th from the right, where is toy (A) placed from the left?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "19 8 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "19 8 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 19\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 19\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3457": {
        "category": "Arithmetic calculation",
        "question_ko": "색종이 1묶음은 10장입니다. 정국이가 색종이 3묶음과 낱개 8장을 가지고 있을 때 정국이가 가지고 있는 색종이는 모두 몇 장 인가요?",
        "question_en": "A bundle of colored paper includes 10 sheets. When Jungkook has 3 bundles and 8 more individual sheets, how many sheets of colored paper does Jungkook have?",
        "answer_ko": "38",
        "answer_en": "38",
        "solution_abst_ko": "10 3 [OP_MUL] 8 [OP_ADD]",
        "solution_abst_en": "10 3 [OP_MUL] 8 [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3458": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.9, 1/3 중에서 0.4보다 작은 수를 모두 더하면 얼마일까요?",
        "question_en": "What is the sum of all numbers less than 0.4 among 0.8, 1/2, 0.9, and 1/3?",
        "answer_ko": "0.33",
        "answer_en": "0.33",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_LESS] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_LESS] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.4\nlist_b = []\nfor i in list_a:\n    if i < var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint('{:.2f}'.format(round(var_f+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.4\nlist_b = []\nfor i in list_a:\n    if i < var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint('{:.2f}'.format(round(var_f+1e-10,2)))"
    },
    "3459": {
        "category": "Comparison",
        "question_ko": "유나, 은지, 민영, 유정이가 비행기 멀리 날리기 대회를 하고 있습니다. 민영이는 은지보다, 은지가 유정이보다 비행기를 멀리 날렸고 유나는 유정이보다 비행기를 멀리 날렸습니다. 유정이보다 민영이가 비행기를 멀리 날렸을 때, 대회에서 꼴등한 사람은 누구일까요?",
        "question_en": "Yuna, Eunji, Minyoung, and Yoojeong are having a flying contest. Minyoung flew farther than Eunji, and Eunji flew farther than Yoojeong, and Yuna flew farther than Yoojeong. When Minyoung flew farther than Yoojeong, who came last in the competition?",
        "answer_ko": "유정",
        "answer_en": "Yoojeong",
        "solution_abst_ko": "[OP_LIST_SOL] 유나 은지 민영 유정 [OP_LIST_EOL] [OP_LIST_SOL] 유나 유정 > 민영 은지 > 은지 유정 > 유정 민영 < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yuna Eunji Minyoung Yoojeong [OP_LIST_EOL] [OP_LIST_SOL] Yuna Yoojeong > Minyoung Eunji > Eunji Yoojeong > Yoojeong Minyoung < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '유나'\nvar_b = '은지'\nvar_c = '민영'\nvar_d = '유정'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '유나'\nvar_f = '유정'\nvar_g = '>'\nvar_h = '민영'\nvar_i = '은지'\nvar_j = '>'\nvar_k = '은지'\nvar_l = '유정'\nvar_m = '>'\nvar_n = '유정'\nvar_o = '민영'\nvar_p = '<'\nlist_b= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_q = len(list_c)\nvar_r = list_c[var_q-1]\nprint(var_r)",
        "solution_code_en": "var_a = 'Yuna'\nvar_b = 'Eunji'\nvar_c = 'Minyoung'\nvar_d = 'Yoojeong'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'Yuna'\nvar_f = 'Yoojeong'\nvar_g = '>'\nvar_h = 'Minyoung'\nvar_i = 'Eunji'\nvar_j = '>'\nvar_k = 'Eunji'\nvar_l = 'Yoojeong'\nvar_m = '>'\nvar_n = 'Yoojeong'\nvar_o = 'Minyoung'\nvar_p = '<'\nlist_b= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_q = len(list_c)\nvar_r = list_c[var_q-1]\nprint(var_r)"
    },
    "3460": {
        "category": "Geometry",
        "question_ko": "부피가 1세제곱센티미터(㎤)인 쌓기나무를 쌓아 부피가 3375세제곱센티미터(㎤)인 정육면체를 만들었습니다. 이 정육면체의 쌓기나무는 몇 층으로 쌓여 있습니까?",
        "question_en": "A cube with a volume of 3375 cubic centimeters (cm3) is made by stacking building blocks with a volume of 1 cubic centimeters (cm3). How many layers are there in this building of cubes?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "3375 1/3 [OP_POW]",
        "solution_abst_en": "3375 1/3 [OP_POW]",
        "solution_code_ko": "var_a = 3375\nvar_b = 0.3333333333333333\nvar_c = var_a ** var_b\nprint(int(eval('{:.2f}'.format(round(var_c+1e-10,2)))))",
        "solution_code_en": "var_a = 3375\nvar_b = 0.3333333333333333\nvar_c = var_a ** var_b\nprint(int(eval('{:.2f}'.format(round(var_c+1e-10,2)))))"
    },
    "3461": {
        "category": "Correspondence",
        "question_ko": "A-10=15일 때, A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "If A-10=15, what number should go in A?",
        "answer_ko": "25",
        "answer_en": "25",
        "solution_abst_ko": "A-10=15 A [OP_NUM_UNK_SOLVER]",
        "solution_abst_en": "A-10=15 A [OP_NUM_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A-10=15'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A-10=15'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "3462": {
        "category": "Arithmetic calculation",
        "question_ko": "한 자리수의 짝수 중 6이하의 수의 개수를 구하시오.",
        "question_en": "Find the number of numbers less than or equal to 6 among single-digit even numbers.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "1 9 [OP_LIST_EVEN] 6 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "1 9 [OP_LIST_EVEN] 6 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 6\nlist_b = []\nfor i in list_a:\n    if i <= var_c:\n        list_b.append(i)\nvar_d = len(list_b)\nprint(int(var_d))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 6\nlist_b = []\nfor i in list_a:\n    if i <= var_c:\n        list_b.append(i)\nvar_d = len(list_b)\nprint(int(var_d))"
    },
    "3463": {
        "category": "Arithmetic calculation",
        "question_ko": "네 자리 수 중 1, 2, 4, 6, 5를 이용하여 만들 수 있고, 각 자리가 모두 다른 가장 큰 수는 얼마인가?",
        "question_en": "What is the largest four-digit number that can be formed using 1, 2, 4, 6, and 5, where each digit is different?",
        "answer_ko": "6542",
        "answer_en": "6542",
        "solution_abst_ko": "[OP_LIST_SOL] 1 2 4 6 5 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1 2 4 6 5 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1\nvar_b = 2\nvar_c = 4\nvar_d = 6\nvar_e = 5\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nprint(int(var_h))",
        "solution_code_en": "var_a = 1\nvar_b = 2\nvar_c = 4\nvar_d = 6\nvar_e = 5\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nprint(int(var_h))"
    },
    "3464": {
        "category": "Arithmetic calculation",
        "question_ko": "버스 7대가 주차장에 있었는데 잠시 후 6대의 버스가 더 왔다. 현재 주차장에 있는 버스는 총 몇 대인가?",
        "question_en": "There were 7 buses in the parking lot, but after a while 6 more came. How many buses are currently in the parking lot?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "7 6 [OP_ADD]",
        "solution_abst_en": "7 6 [OP_ADD]",
        "solution_code_ko": "var_a = 7\nvar_b = 6\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 7\nvar_b = 6\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "3465": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 8센티미터(㎝)인 정육면체가 있습니다. 이 정육면체의 겉넓이는 얼마입니까?",
        "question_en": "There is a cube with a side length of 8 centimeters (cm). What is the surface area of this cube?",
        "answer_ko": "384",
        "answer_en": "384",
        "solution_abst_ko": "8 2 [OP_POW] 6 [OP_MUL]",
        "solution_abst_en": "8 2 [OP_POW] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "3466": {
        "category": "Comparison",
        "question_ko": "키가 작은 사람부터 순서대로 9명이 한 줄로 서 있습니다. 호석이는 가장 뒤에 서 있고, 유나는 호석이로부터 5번째 앞에 서 있습니다. 키가 큰 사람부터 순서대로 다시 줄을 서면 유나는 앞에서부터 몇 번째에 서게 됩니까?",
        "question_en": "Nine people are standing in a line in order of height from shortest to tallest. Hoseok is standing at the tail end, and Yuna is standing 5th in front of Hoseok. If you line up again in order from tallest to shortest, in what number from the front will Yuna stand?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "9 9 [OP_SUB] 5 [OP_ADD] 1 [OP_ADD]",
        "solution_abst_en": "9 9 [OP_SUB] 5 [OP_ADD] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 9\nvar_b = 9\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 9\nvar_b = 9\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "3467": {
        "category": "Comparison",
        "question_ko": "파란색 버스는 200킬로미터(㎞)를 가는 데 4시간이 걸리고, 초록색 버스는 180킬로미터(㎞)를 가는 데 3시간이 걸린다고 합니다. 목적지까지 빨리 도착하기 위해선 어떤 색 버스를 이용하는 게 좋을까요?",
        "question_en": "The blue bus takes 4 hours to cover 200 kilometers (km), and the green bus takes 3 hours to cover 180 kilometers (km). What color bus should you use to get to the destination quickly?",
        "answer_ko": "초록색",
        "answer_en": "green",
        "solution_abst_ko": "[OP_LIST_SOL] 파란색 초록색 [OP_LIST_EOL] [OP_LIST_SOL] 200 4 [OP_DIV] 180 3 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] blue green [OP_LIST_EOL] [OP_LIST_SOL] 200 4 [OP_DIV] 180 3 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '파란색'\nvar_b = '초록색'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 200\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 180\nvar_g = 3\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'blue'\nvar_b = 'green'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 200\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 180\nvar_g = 3\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "3468": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 7센티미터(㎝)인 어떤 정사면체가 있습니다. 이 정사면체의 겉넓이는 몇 제곱센티미터(㎠)입니까?",
        "question_en": "There is a regular tetrahedron with a side length of 7 centimeters (cm). What is the surface area of this tetrahedron in square centimeters (cm2)?",
        "answer_ko": "84.87",
        "answer_en": "84.87",
        "solution_abst_ko": "3 1/2 [OP_POW] 7 2 [OP_POW] [OP_MUL]",
        "solution_abst_en": "3 1/2 [OP_POW] 7 2 [OP_POW] [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 0.5\nvar_c = var_a ** var_b\nvar_d = 7\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 3\nvar_b = 0.5\nvar_c = var_a ** var_b\nvar_d = 7\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "3469": {
        "category": "Correspondence",
        "question_ko": "처음 어떤 수에서 50을 빼고 4로 나누었습니다. 여기에 다시 3을 곱하고 28을 더했습니다. 최종 결과가 73일 때 어떤 수를 구하시오.",
        "question_en": "73 is the result when you subtract 50 from a number, divide it by 4, multiply this by 3 again, and then add 28. What is this number?",
        "answer_ko": "110",
        "answer_en": "110",
        "solution_abst_ko": "73 28 [OP_SUB] 3 [OP_DIV] 4 [OP_MUL] 50 [OP_ADD]",
        "solution_abst_en": "73 28 [OP_SUB] 3 [OP_DIV] 4 [OP_MUL] 50 [OP_ADD]",
        "solution_code_ko": "var_a = 73\nvar_b = 28\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = 4\nvar_g = var_e * var_f\nvar_h = 50\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 73\nvar_b = 28\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = 4\nvar_g = var_e * var_f\nvar_h = 50\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "3470": {
        "category": "Correspondence",
        "question_ko": "서로 다른 두 수 A, B가 있습니다. 9A6-BB=BBB에서 A와 B의 합을 구하시오.",
        "question_en": "There are two different numbers A and B. Find the sum of A and B in 9A6-BB=BBB.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "9A6-BB=BBB A [OP_DIGIT_UNK_SOLVER] 9A6-BB=BBB B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_abst_en": "9A6-BB=BBB A [OP_DIGIT_UNK_SOLVER] 9A6-BB=BBB B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_code_ko": "var_a = '9A6-BB=BBB'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '9A6-BB=BBB'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = '9A6-BB=BBB'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '9A6-BB=BBB'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "3471": {
        "category": "Comparison",
        "question_ko": "총 4개의 숫자 0.8, 1/2, 0.5, 1/3이 있습니다. 이 중 3보다 크거나 같은 수는 몇 개 일까요?",
        "question_en": "There are four numbers in total: 0.8, 1/2, 0.5, and 1/3. How many of them are greater than or equal to 3?",
        "answer_ko": "0",
        "answer_en": "0",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.5 1/3 [OP_LIST_EOL] 3 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.5 1/3 [OP_LIST_EOL] 3 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.5\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = []\nfor i in list_a:\n    if i >= var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.5\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = []\nfor i in list_a:\n    if i >= var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "3472": {
        "category": "Comparison",
        "question_ko": "2개의 상자 (가)와 (나)가 배달왔습니다. 유정이는 두 상자 중 작은 상자를 들고 가려고 합니다. (가) 상자가 (나) 상자보다 크다면, 유정이가 들고가야 하는 상자는 무엇입니까?",
        "question_en": "Two boxes A and B have been delivered. Yoojeong is going to take the smaller of the two boxes. If the box A is bigger than the box B, which box should Yoojeong take?",
        "answer_ko": "(나)",
        "answer_en": "B",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) [OP_LIST_EOL] [OP_LIST_SOL] (가) (나) > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] A B > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = '(가)'\nvar_d = '(나)'\nvar_e = '>'\nlist_b= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_f = len(list_c)\nvar_g = list_c[var_f-1]\nprint(var_g)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 'A'\nvar_d = 'B'\nvar_e = '>'\nlist_b= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_f = len(list_c)\nvar_g = list_c[var_f-1]\nprint(var_g)"
    },
    "3473": {
        "category": "Geometry",
        "question_ko": "사각형 내에 그릴 수 있는 대각선의 개수는?",
        "question_en": "How many diagonals can be drawn in a rectangle?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "4 4 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "4 4 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 4\nvar_b = 4\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 4\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "3474": {
        "category": "Comparison",
        "question_ko": "성철이는 세수를 하는 데 5리터(L)의 물을 사용하고, 성철이의 동생은 4900밀리리터(㎖)의 물을 사용했습니다. 물을 더 많이 사용한 사람은 누구인지 구하시오.",
        "question_en": "Seongcheol used 5 liters (l) of water to wash his face, and Seongcheol's younger brother used 4900 milliliters (ml) of water. Find who used more water.",
        "answer_ko": "성철",
        "answer_en": "Seongcheol",
        "solution_abst_ko": "[OP_LIST_SOL] 성철 동생 [OP_LIST_EOL] [OP_LIST_SOL] 5 1000 [OP_MUL] 4900 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Seongcheol brother [OP_LIST_EOL] [OP_LIST_SOL] 5 1000 [OP_MUL] 4900 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '성철'\nvar_b = '동생'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 5\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 4900\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Seongcheol'\nvar_b = 'brother'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 5\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 4900\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "3475": {
        "category": "Arithmetic calculation",
        "question_ko": "남준이네 집에서 학교까지의 거리는 1.2킬로미터(km)입니다. 남준이가 0.3킬로미터(km) 지점에서 집으로 돌아갔다가 학교로 왔다면 평소보다 걸은 거리는 몇 킬로미터(km) 증가했는지 소수점을 포함하여 구하시오.",
        "question_en": "The distance from Namjoon's house to the school is 1.2 kilometers (km). If Namjoon returned home and returned to school at the point of 0.3 kilometers (km), find how many kilometers (km) he walked more than usual, including the decimal point.",
        "answer_ko": "0.60",
        "answer_en": "0.6",
        "solution_abst_ko": "1.2 0.3 2 [OP_MUL] [OP_ADD] 1.2 [OP_SUB]",
        "solution_abst_en": "1.2 0.3 2 [OP_MUL] [OP_ADD] 1.2 [OP_SUB]",
        "solution_code_ko": "var_a = 1.2\nvar_b = 0.3\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nvar_f = 1.2\nvar_g = var_e - var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 1.2\nvar_b = 0.3\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nvar_f = 1.2\nvar_g = var_e - var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "3476": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중에서 2번째로 큰 수와 2번째로 작은 수의 곱은 얼마입니까?",
        "question_en": "There are three numbers 10, 11, and 12. What is the product of the second largest number and the second smallest number?",
        "answer_ko": "121",
        "answer_en": "121",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e * var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e * var_g\nprint(int(var_h))"
    },
    "3477": {
        "category": "Arithmetic calculation",
        "question_ko": "희주네 학교 학생은 500명입니다. 이 중에서 산을 좋아하는 학생은 289명이고, 바다를 좋아하는 학생은 337명입니다. 산과 바다를 둘 다 좋아하지 않는 학생이 56명일 때, 산과 바다를 모두 좋아하는 학생은 몇 명인지 구해보시오.",
        "question_en": "Heeju's school has 500 students. Among them, 289 students like mountains and 337 students like the sea. If there are 56 students who neither like the mountains nor the sea, how many students like both the mountains and the sea?",
        "answer_ko": "182",
        "answer_en": "182",
        "solution_abst_ko": "289 337 [OP_ADD] 500 56 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "289 337 [OP_ADD] 500 56 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 289\nvar_b = 337\nvar_c = var_a + var_b\nvar_d = 500\nvar_e = 56\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 289\nvar_b = 337\nvar_c = var_a + var_b\nvar_d = 500\nvar_e = 56\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "3478": {
        "category": "Possibility",
        "question_ko": "유나, 태형, 지민이 중 2명을 선택하여 청소를 하려고 합니다. 서로 다른 사람이 선택될 경우는 모두 몇 가지일까요?",
        "question_en": "Yuna, Taehyung, and Jimin are going to choose two among them to do the chores. How many different cases are there in all?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 유나 태형 지민 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] Yuna Taehyung Jimin [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '유나'\nvar_b = '태형'\nvar_c = '지민'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f / (i+1)\nprint(int(var_f))",
        "solution_code_en": "var_a = 'Yuna'\nvar_b = 'Taehyung'\nvar_c = 'Jimin'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f / (i+1)\nprint(int(var_f))"
    },
    "3479": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 24를 더하려고 합니다. 잘못하여 42를 더했을 때의 답이 50이라면 바르게 계산한 결과는 얼마일까요?",
        "question_en": "You want to add 24 to some number. If the answer when adding 42 incorrectly is 50, what is the correct calculation result?",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "50 42 [OP_SUB] 24 [OP_ADD]",
        "solution_abst_en": "50 42 [OP_SUB] 24 [OP_ADD]",
        "solution_code_ko": "var_a = 50\nvar_b = 42\nvar_c = var_a - var_b\nvar_d = 24\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 50\nvar_b = 42\nvar_c = var_a - var_b\nvar_d = 24\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3480": {
        "category": "Possibility",
        "question_ko": "은수네 학교에 남자 1명, 여자 1명이 전학을 왔다.은수네 학교에는 남학생은 6개 반, 여학생은 4개 반이 있다. 전학생들이 갈 수 있는 반의 경우의 수는 모두 몇 개인가?",
        "question_en": "One boy and one girl have transferred to Eunsu's school. Eunsu's school has 6 classes for boys and 4 classes for girls. How many classes can transfer students go to?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "4 6 [OP_MUL]",
        "solution_abst_en": "4 6 [OP_MUL]",
        "solution_code_ko": "var_a = 4\nvar_b = 6\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 6\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "3481": {
        "category": "Comparison",
        "question_ko": "석진, 호석, 남준이는 수학 시험을 봤습니다. 남준이의 수학 점수는 호석이의 수학 점수보다 높고, 석진이의 수학 점수는 호석이의 수학 점수보다 높습니다. 석진이의 수학 점수가 남준이의 수학 점수보다 낮다면 수학 점수가 가장 높은 친구는 누구인가요?",
        "question_en": "Seokjin, Hoseok, and Namjoon took a math test. Namjoon's math score is higher than Hoseok's math score, and Seokjin's math score is higher than Hoseok's math score. If Seokjin's math score is lower than Namjoon's math score, who has the highest math score?",
        "answer_ko": "남준",
        "answer_en": "Namjoon",
        "solution_abst_ko": "[OP_LIST_SOL] 석진 호석 남준 [OP_LIST_EOL] [OP_LIST_SOL] 석진 호석 > 남준 호석 > 석진 남준 < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Seokjin Hoseok Namjoon [OP_LIST_EOL] [OP_LIST_SOL] Seokjin Hoseok > Namjoon Hoseok > Seokjin Namjoon < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '석진'\nvar_b = '호석'\nvar_c = '남준'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '석진'\nvar_e = '호석'\nvar_f = '>'\nvar_g = '남준'\nvar_h = '호석'\nvar_i = '>'\nvar_j = '석진'\nvar_k = '남준'\nvar_l = '<'\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_m = 1\nvar_n = list_c[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'Seokjin'\nvar_b = 'Hoseok'\nvar_c = 'Namjoon'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'Seokjin'\nvar_e = 'Hoseok'\nvar_f = '>'\nvar_g = 'Namjoon'\nvar_h = 'Hoseok'\nvar_i = '>'\nvar_j = 'Seokjin'\nvar_k = 'Namjoon'\nvar_l = '<'\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_m = 1\nvar_n = list_c[var_m-1]\nprint(var_n)"
    },
    "3482": {
        "category": "Possibility",
        "question_ko": "숫자 3, 9, 8을 한 번씩 사용하여 850보다 크고, 920보다 작은 세 자리 수는 모두 몇 개입니까?",
        "question_en": "How many three-digit numbers greater than 850 and less than 920 can you make using the numbers 3, 9 and 8?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 3 9 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 850 [OP_LIST_MORE] 920 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 3 9 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 850 [OP_LIST_MORE] 920 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 3\nvar_b = 9\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 850\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = 920\nlist_d = []\nfor i in list_c:\n    if i < var_f:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))",
        "solution_code_en": "var_a = 3\nvar_b = 9\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 850\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = 920\nlist_d = []\nfor i in list_c:\n    if i < var_f:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))"
    },
    "3483": {
        "category": "Geometry",
        "question_ko": "40센티미터(㎝)의 철사로 직사각형을 만들었다. 세로의 길이가 8센티미터(㎝)이면 가로는 몇 센티미터(㎝)인가?",
        "question_en": "A rectangle was made with a 40 centimeters (cm) wire. If the length of one side is 8 centimeters (cm), what is the length of the other side in centimeters (cm)?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "40 2 [OP_DIV] 8 [OP_SUB]",
        "solution_abst_en": "40 2 [OP_DIV] 8 [OP_SUB]",
        "solution_code_ko": "var_a = 40\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 8\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 40\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 8\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3484": {
        "category": "Arithmetic calculation",
        "question_ko": "정류장에서 내린 사람이 탄 사람보다 9명 많았다면 38명이 타있었던 버스에 현재 몇 명이 타있을까요?",
        "question_en": "If 9 more people left the bus than the ones who got on at the stop, how many people are on the bus now given that the bus originally had 38 people on it?",
        "answer_ko": "29",
        "answer_en": "29",
        "solution_abst_ko": "38 9 [OP_SUB]",
        "solution_abst_en": "38 9 [OP_SUB]",
        "solution_code_ko": "var_a = 38\nvar_b = 9\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 38\nvar_b = 9\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "3485": {
        "category": "Possibility",
        "question_ko": "숫자 7, 2, 5, 9를 사용하여 네 자리 수를 만들려고 합니다. 만들 수 있는 네 자리 수는 모두 몇 개입니까? 같은 숫자는 여러 번 등장할 수 있습니다.",
        "question_en": "You want to create four-digit numbers by using the numbers 7, 2, 5, and 9. How many four-digit numbers can you make? The same number can appear multiple times.",
        "answer_ko": "256",
        "answer_en": "256",
        "solution_abst_ko": "[OP_LIST_SOL] 7 2 5 9 [OP_LIST_EOL] 4 [OP_LIST_GET_PRODUCT] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 7 2 5 9 [OP_LIST_EOL] 4 [OP_LIST_GET_PRODUCT] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 7\nvar_b = 2\nvar_c = 5\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 7\nvar_b = 2\nvar_c = 5\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "3486": {
        "category": "Comparison",
        "question_ko": "한 줄로 선 학생들 사이에서 윤기는 왼쪽이 7명이 있고 오른쪽에 5명이 있는 위치에 서 있습니다. 윤기를 포함하여 줄 서 있는 학생은 모두 몇 명입니까?",
        "question_en": "Among the students standing in line, Yoongi is standing where 7 people are on the left and 5 people are on the right. Including Yoongi, how many people are standing in line?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "7 5 [OP_ADD] 1 [OP_ADD]",
        "solution_abst_en": "7 5 [OP_ADD] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 7\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 7\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3487": {
        "category": "Arithmetic calculation",
        "question_ko": "호석이는 보라색 색종이를 138장 가지고 있습니다. 호석이가 가지고 있는 노란색 색종이는 파란색 색종이보다 119장 더 많고, 보라색 색종이는 노란색 색종이보다 185장 더 적습니다. 호석이가 가지고 있는 보라색, 노란색, 파란색 색종이는 모두 몇 장입니까?",
        "question_en": "Hoseok has 138 pieces of purple-colored paper. Hoseok has 119 more yellow-colored paper than blue-colored paper, and 185 less purple-colored paper than yellow-colored paper. How many purple, yellow, and blue-colored paper does Hoseok have in total?",
        "answer_ko": "467",
        "answer_en": "467",
        "solution_abst_ko": "138 138 119 [OP_ADD] [OP_ADD] 138 119 [OP_ADD] 185 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "138 138 119 [OP_ADD] [OP_ADD] 138 119 [OP_ADD] 185 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 138\nvar_b = 138\nvar_c = 119\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nvar_f = 138\nvar_g = 119\nvar_h = var_f + var_g\nvar_i = 185\nvar_j = var_h - var_i\nvar_k = var_e + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 138\nvar_b = 138\nvar_c = 119\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nvar_f = 138\nvar_g = 119\nvar_h = var_f + var_g\nvar_i = 185\nvar_j = var_h - var_i\nvar_k = var_e + var_j\nprint(int(var_k))"
    },
    "3488": {
        "category": "Comparison",
        "question_ko": "지민, 윤기, 태형, 남준이는 서로 다른 개수의 사과를 가지고 있습니다. 태형이는 남준이보다 적고, 지민이는 윤기보다 많고, 윤기는 남준이보다 많을 때, 사과를 가장 적게 가지고 있는 사람은 누구입니까?",
        "question_en": "Jimin, Yoongi, Taehyung, and Namjoon have different numbers of apples. If Taehyung has fewer than Namjoon, Jimin has more than Yoongi, and Yoongi has more than Namjoon, who has the fewest apples?",
        "answer_ko": "태형",
        "answer_en": "Taehyung",
        "solution_abst_ko": "[OP_LIST_SOL] 지민 윤기 태형 남준 [OP_LIST_EOL] [OP_LIST_SOL] 지민 윤기 > 태형 남준 < 윤기 남준 > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jimin Yoongi Taehyung Namjoon [OP_LIST_EOL] [OP_LIST_SOL] Jimin Yoongi > Taehyung Namjoon < Yoongi Namjoon > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '지민'\nvar_b = '윤기'\nvar_c = '태형'\nvar_d = '남준'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '지민'\nvar_f = '윤기'\nvar_g = '>'\nvar_h = '태형'\nvar_i = '남준'\nvar_j = '<'\nvar_k = '윤기'\nvar_l = '남준'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)",
        "solution_code_en": "var_a = 'Jimin'\nvar_b = 'Yoongi'\nvar_c = 'Taehyung'\nvar_d = 'Namjoon'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'Jimin'\nvar_f = 'Yoongi'\nvar_g = '>'\nvar_h = 'Taehyung'\nvar_i = 'Namjoon'\nvar_j = '<'\nvar_k = 'Yoongi'\nvar_l = 'Namjoon'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)"
    },
    "3489": {
        "category": "Arithmetic calculation",
        "question_ko": "태형이와 민영이가 걷기 시합을 했습니다. 1분 후 태형이는 114미터(m)를 걸었고, 민영이는 79미터(m)를 걸었습니다. 1시간 후 태형이는 민영이보다 몇 미터(m)를 더 걸어갔나요?",
        "question_en": "Taehyung and Minyoung had a walking race. One minute later, Taehyung walked 114 meters (m) and Minyoung walked 79 meters (m). After 1 hour, how many meters (m) will Taehyung have walked more than Minyoung?",
        "answer_ko": "2100",
        "answer_en": "2100",
        "solution_abst_ko": "114 79 [OP_SUB] 1 [OP_MUL] 60 [OP_MUL]",
        "solution_abst_en": "114 79 [OP_SUB] 1 [OP_MUL] 60 [OP_MUL]",
        "solution_code_ko": "var_a = 114\nvar_b = 79\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c * var_d\nvar_f = 60\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 114\nvar_b = 79\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c * var_d\nvar_f = 60\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "3490": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 2를 더한 후 6을 빼고, 3을 곱한 값을 4로 나누면 3이 됩니다. 어떤 수를 구하시오.",
        "question_en": "Adding 2 to a particular number and subtracting 6, and multiplying it by 3 and dividing it by 4 equals 3. Find that particular number.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "3 4 [OP_MUL] 3 [OP_DIV] 6 [OP_ADD] 2 [OP_SUB]",
        "solution_abst_en": "3 4 [OP_MUL] 3 [OP_DIV] 6 [OP_ADD] 2 [OP_SUB]",
        "solution_code_ko": "var_a = 3\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = 6\nvar_g = var_e + var_f\nvar_h = 2\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 3\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = 6\nvar_g = var_e + var_f\nvar_h = 2\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "3491": {
        "category": "Correspondence",
        "question_ko": "지호, 상현, 승주 3명의 몸무게를 합친 값이 280보다는 많이 나가고 70으로 나누었을 때 나머지가 30이라면 세 사람의 몸무게의 합의 최소는 얼마인지 구하시오.",
        "question_en": "If the sum of the weights of Jiho, Sanghyeon, and Seungju is greater than 280 and the remainder is 30 when divided by 70, what is the minimum sum of the weights of the three people?",
        "answer_ko": "310",
        "answer_en": "310",
        "solution_abst_ko": "280 30 [OP_ADD]",
        "solution_abst_en": "280 30 [OP_ADD]",
        "solution_code_ko": "var_a = 280\nvar_b = 30\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 280\nvar_b = 30\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "3492": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 4를 곱했더니 28이 되었습니다. 어떤 수를 구하시오.",
        "question_en": "When multiplied by 4, this number became 28. Find this number.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "28 4 [OP_DIV]",
        "solution_abst_en": "28 4 [OP_DIV]",
        "solution_code_ko": "var_a = 28\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 28\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "3493": {
        "category": "Geometry",
        "question_ko": "삼각형의 꼭짓점의 수와 변의 수를 합하면 얼마입니까?",
        "question_en": "What is the sum of the number of vertices and the number of sides of a triangle?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "3 3 [OP_ADD]",
        "solution_abst_en": "3 3 [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 3\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 3\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "3494": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중에서 가장 작은 수와 2번째로 작은 수로 나눈 값은 얼마입니까?",
        "question_en": "There are three numbers 10, 11, and 12. Divide the smallest number by the second smallest number.",
        "answer_ko": "0.91",
        "answer_en": "0.91",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_DIV]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e / var_g\nprint('{:.2f}'.format(round(var_h+1e-10,2)))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e / var_g\nprint('{:.2f}'.format(round(var_h+1e-10,2)))"
    },
    "3495": {
        "category": "Correspondence",
        "question_ko": "어떤 수가 있습니다. 이 수에 2를 더하고 6을 뺐습니다. 다시 3배를 취한다음 4로 나누었더니 3이되었습니다. 어떤 수는 얼마입니까?",
        "question_en": "We added 2 to a certain number and then subtracted 6. Multiply this by 3 and then divide by 4 and we get 3. What is that number?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "3 4 [OP_MUL] 3 [OP_DIV] 6 [OP_ADD] 2 [OP_SUB]",
        "solution_abst_en": "3 4 [OP_MUL] 3 [OP_DIV] 6 [OP_ADD] 2 [OP_SUB]",
        "solution_code_ko": "var_a = 3\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = 6\nvar_g = var_e + var_f\nvar_h = 2\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 3\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = 6\nvar_g = var_e + var_f\nvar_h = 2\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "3496": {
        "category": "Arithmetic calculation",
        "question_ko": "닭이 어제보다 59개의 알을 더 낳았다. 어제 닭이 10개의 알을 낳았다면 오늘은 몇개의 알을 낳았는가?",
        "question_en": "The chicken laid 59 more eggs today than yesterday. If the chicken laid 10 eggs yesterday, how many eggs did it lay today?",
        "answer_ko": "69",
        "answer_en": "69",
        "solution_abst_ko": "10 59 [OP_ADD]",
        "solution_abst_en": "10 59 [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 59\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 10\nvar_b = 59\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "3497": {
        "category": "Correspondence",
        "question_ko": "A를 5로 나누면 몫이 2가 되고, 나머지는 B가 됩니다. A와 B는 모두 자연수입니다. 가능한 B 중 가장 큰 값은?",
        "question_en": "When A is divided by 5, the quotient is 2 and the remainder is B. A and B are both natural numbers. What is the largest possible value of B?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "5 1 [OP_SUB]",
        "solution_abst_en": "5 1 [OP_SUB]",
        "solution_code_ko": "var_a = 5\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "3498": {
        "category": "Geometry",
        "question_ko": "원의 모습을 띄고 있는 어느 호수의 반지름을 구하려고 합니다. 이 호수의 지름이 26미터(m)일 때, 호수의 반지름은 몇 미터(m)인가?",
        "question_en": "I am trying to find the radius of a lake that has the shape of a circle. If the diameter of this lake is 26 meters (m), what is the radius of the lake in meters (m)?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "26 2 [OP_DIV]",
        "solution_abst_en": "26 2 [OP_DIV]",
        "solution_code_ko": "var_a = 26\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 26\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "3499": {
        "category": "Comparison",
        "question_ko": "운동회 참가자 중 2/7는 백팀이고 3/8은 청팀입니다. 참가자가 더 많은 팀은 어디인가요?",
        "question_en": "2/7 of the sports day participants are on the white team and 3/8 are on the blue team. Which team has more participants?",
        "answer_ko": "청팀",
        "answer_en": "blue",
        "solution_abst_ko": "[OP_LIST_SOL] 백팀 청팀 [OP_LIST_EOL] [OP_LIST_SOL] 2 7 [OP_DIV] 3 8 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] white blue [OP_LIST_EOL] [OP_LIST_SOL] 2 7 [OP_DIV] 3 8 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '백팀'\nvar_b = '청팀'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nvar_d = 7\nvar_e = var_c / var_d\nvar_f = 3\nvar_g = 8\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'white'\nvar_b = 'blue'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nvar_d = 7\nvar_e = var_c / var_d\nvar_f = 3\nvar_g = 8\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "3500": {
        "category": "Possibility",
        "question_ko": "사과, 복숭아, 배, 참외, 귤 중에서 서로 다른 2가지 과일을 골라서 사는 경우는 모두 몇 가지입니까?",
        "question_en": "How many cases are available if you choose and buy 2 different fruits among apples, peaches, pears, melons, and tangerines?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 복숭아 배 참외 귤 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] apples peaches pears melons tangerines [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '복숭아'\nvar_c = '배'\nvar_d = '참외'\nvar_e = '귤'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h / (i+1)\nprint(int(var_h))",
        "solution_code_en": "var_a = 'apples'\nvar_b = 'peaches'\nvar_c = 'pears'\nvar_d = 'melons'\nvar_e = 'tangerines'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h / (i+1)\nprint(int(var_h))"
    },
    "3501": {
        "category": "Arithmetic calculation",
        "question_ko": "유정이는 꽃 32송이를 가지고 있습니다. 유정이가 가지고 있는 꽃의 수는 남준이가 가진 꽃의 수의 4배입니다. 유정이와 남준이가 가진 꽃은 모두 몇 송이입니까?",
        "question_en": "Yoojung has 32 flowers. The number of flowers Yoojung has is 4 times the number of flowers Namjoon has. How many flowers do Yoojung and Namjoon have?",
        "answer_ko": "40",
        "answer_en": "40",
        "solution_abst_ko": "32 32 4 [OP_DIV] [OP_ADD]",
        "solution_abst_en": "32 32 4 [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 32\nvar_b = 32\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 32\nvar_b = 32\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "3502": {
        "category": "Arithmetic calculation",
        "question_ko": "한 봉지에 16개씩 들어있는 초콜릿을 7봉지 샀습니다. 그중에서 13개는 뜨거운 햇볕에 녹아버렸고, 남은 초콜릿들을 8봉지에 똑같이 나누어 담으려고 할 때, 봉지에 들어가지 못하고 남은 초콜릿은 몇 개입니까?",
        "question_en": "I bought 7 bags of chocolates, each containing 16 pieces. Thirteen of them melted in the hot sun, and when I try to divide the remaining chocolates equally into 8 bags, how many chocolates are left that cannot fit into the bags?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "16 7 [OP_MUL] 13 [OP_SUB] 8 [OP_MOD]",
        "solution_abst_en": "16 7 [OP_MUL] 13 [OP_SUB] 8 [OP_MOD]",
        "solution_code_ko": "var_a = 16\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = var_e % var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 16\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = var_e % var_f\nprint(int(var_g))"
    },
    "3503": {
        "category": "Geometry",
        "question_ko": "어떤 세 점은 한 직선 위에 있지 않습니다. 이 세 점으로 만들 수 있는 직선의 개수는 무엇입니까?",
        "question_en": "Three points are not in a straight line. How many straight lines can you make with these three points?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "3 2 [OP_COMB]",
        "solution_abst_en": "3 2 [OP_COMB]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))"
    },
    "3504": {
        "category": "Geometry",
        "question_ko": "한변의 길이가 3인 정사각형의 넓이에 밑변이 3이고 높이가 2인 평행사변형의 넓이를 더한 값은 얼마입니까?",
        "question_en": "What is the area of a square with side length 3 plus the area of a parallelogram with base 3 and height 2?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "3 2 [OP_MUL] 3 3 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "3 2 [OP_MUL] 3 3 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "3505": {
        "category": "Geometry",
        "question_ko": "길이가 24 센티미터(㎝) 인 끈으로 가장 큰 정사각형을 만들려고 합니다. 정사각형 한 변의 길이는 몇 센티미터(㎝) 입니까?",
        "question_en": "You are going to make the largest square out of a piece of string that is 24 centimeters (cm) long. How many centimeters (cm) is the length of one side of the square?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "24 4 [OP_DIV]",
        "solution_abst_en": "24 4 [OP_DIV]",
        "solution_code_ko": "var_a = 24\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 24\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "3506": {
        "category": "Arithmetic calculation",
        "question_ko": "가로가 3미터(m) 20센티미터(㎝)인 전시장 벽에 가로가 30센티미터(㎝)인 그림 작품을 일렬로 붙이려고 합니다. 벽의 끝과 작품 사이, 작품과 작품 사이의 간격을 모두 같게 하여 6개를 붙이려면 간격은 몇 센티미터(㎝)로 하여야 합니까?",
        "question_en": "I am going to attach paintings with a width of 30 centimeters (cm) in a row on the wall of an exhibition hall with a width of 3 meters (m) and 20 centimeters (cm). How many centimeters (cm) should be the distance between the end of the wall and the artwork and between the artworks so that all six pieces are put together at the same distance?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "3 100 [OP_MUL] 20 [OP_ADD] 30 6 [OP_MUL] [OP_SUB] 6 1 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "3 100 [OP_MUL] 20 [OP_ADD] 30 6 [OP_MUL] [OP_SUB] 6 1 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 3\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 20\nvar_e = var_c + var_d\nvar_f = 30\nvar_g = 6\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nvar_j = 6\nvar_k = 1\nvar_l = var_j + var_k\nvar_m = var_i / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 3\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 20\nvar_e = var_c + var_d\nvar_f = 30\nvar_g = 6\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nvar_j = 6\nvar_k = 1\nvar_l = var_j + var_k\nvar_m = var_i / var_l\nprint(int(var_m))"
    },
    "3507": {
        "category": "Correspondence",
        "question_ko": "12잔의 커피에 들어간 설탕의 양이 총 84.6그램(g)이라고 한다. 12잔에 동일한 양의 설탕이 들어있다면 커피 한잔에 몇 그램(g)의 설탕이 들어있는지 구하시오.",
        "question_en": "It is said that the total amount of sugar in 12 cups of coffee is 84.6 grams (g). If 12 cups contain the same amount of sugar, find how many grams (g) of sugar are in a cup of coffee.",
        "answer_ko": "7.05",
        "answer_en": "7.05",
        "solution_abst_ko": "84.6 12 [OP_DIV]",
        "solution_abst_en": "84.6 12 [OP_DIV]",
        "solution_code_ko": "var_a = 84.6\nvar_b = 12\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 84.6\nvar_b = 12\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "3508": {
        "category": "Correspondence",
        "question_ko": "어떤 수로 49를 나누면 나머지가 4이고, 66을 나누면 나머지가 6입니다. 이때 어떤 수는 어느 것입니까?",
        "question_en": "When you divide 49 by a number, the remainder is 4, and when you divide the number by 66, the remainder is 6. What number is this?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "49 4 [OP_SUB] 66 6 [OP_SUB] [OP_GCD]",
        "solution_abst_en": "49 4 [OP_SUB] 66 6 [OP_SUB] [OP_GCD]",
        "solution_code_ko": "var_a = 49\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 66\nvar_e = 6\nvar_f = var_d - var_e\nvar_g = math.gcd(int(var_f), int(var_c))\nprint(int(var_g))",
        "solution_code_en": "var_a = 49\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 66\nvar_e = 6\nvar_f = var_d - var_e\nvar_g = math.gcd(int(var_f), int(var_c))\nprint(int(var_g))"
    },
    "3509": {
        "category": "Geometry",
        "question_ko": "한 모서리의 길이가 1센티미터(㎝)인 작은 정육면체 27개를 모두 사용해서 한 모서리의 길이가 3센티미터(㎝)인 큰 정육면체 1개를 만들었습니다. 큰 정육면체의 모든 면에 페인트를 칠하고 다시 작은 정육면체로 분리했습니다. 이 때 3개의 면에 페인트가 칠해져 있는 정육면체는 몇 개인가요?",
        "question_en": "All 27 small cubes with an edge length of 1 centimeter (cm) were used to create one large cube with an edge length of 3 centimeters (cm). I painted all sides of the large cube and then separated it into smaller cubes. How many cubes have three painted faces?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "8",
        "solution_abst_en": "8",
        "solution_code_ko": "var_a = 8\nprint(int(var_a))",
        "solution_code_en": "var_a = 8\nprint(int(var_a))"
    },
    "3510": {
        "category": "Arithmetic calculation",
        "question_ko": "주혜가 가지고 있던 돈의 1/4를 공책을 사는 데 쓰고, 남은 돈의 2/3은 점심을 사 먹었더니 2500원이 남았습니다. 주혜가 처음 가지고 있던 돈은 얼마입니까?",
        "question_en": "Juhye used 1/4 of her money and 2/3 of the money she had left to buy a notebook and lunch, leaving 2,500 won at the end. How much money did Juhye have at first?",
        "answer_ko": "10000",
        "answer_en": "10000",
        "solution_abst_ko": "2500 1 1/4 [OP_SUB] [OP_DIV] 1 2/3 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "2500 1 1/4 [OP_SUB] [OP_DIV] 1 2/3 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 2500\nvar_b = 1\nvar_c = 0.25\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 1\nvar_g = 0.6666666666666666\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 2500\nvar_b = 1\nvar_c = 0.25\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 1\nvar_g = 0.6666666666666666\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "3511": {
        "category": "Arithmetic calculation",
        "question_ko": "10미터(m)간격으로 100미터(m)도로 한쪽에 처음부터 끝까지 나무를 심으려고 할때 몇 그루의 나무가 필요합니까?",
        "question_en": "How many trees are needed if you plant trees from start to finish on one side of a 100-meter (m) road at 10-meter (m) intervals?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "100 10 [OP_DIV] 1 [OP_ADD]",
        "solution_abst_en": "100 10 [OP_DIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 100\nvar_b = 10\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 100\nvar_b = 10\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3512": {
        "category": "Arithmetic calculation",
        "question_ko": "50보다 크고 100보다 작은 수 중에서 8로 나누어 떨어지는 수는 모두 몇 개입니까?",
        "question_en": "How many numbers greater than 50 and less than 100 are divisible by 8?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "50 1 [OP_ADD] 100 1 [OP_SUB] 1 [OP_LIST_ARANGE] 8 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "50 1 [OP_ADD] 100 1 [OP_SUB] 1 [OP_LIST_ARANGE] 8 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 50\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 100\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = 8\nlist_b = []\nvar_h = int(var_h)\nfor i in list_a:\n    i = int(i)\n    if i % var_h == 0:\n        list_b.append(i)\nvar_i = len(list_b)\nprint(int(var_i))",
        "solution_code_en": "var_a = 50\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 100\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = 8\nlist_b = []\nvar_h = int(var_h)\nfor i in list_a:\n    i = int(i)\n    if i % var_h == 0:\n        list_b.append(i)\nvar_i = len(list_b)\nprint(int(var_i))"
    },
    "3513": {
        "category": "Comparison",
        "question_ko": "태형, 민주, 상민, 윤정, 유정이 교대로 결승선을 넘었다. 누가 먼저 들어갔나?",
        "question_en": "Taehyung, Minju, Sangmin, Yoonjung, and Yoojeong crossed the finish line in that order. Who went in first?",
        "answer_ko": "태형",
        "answer_en": "Taehyung",
        "solution_abst_ko": "[OP_LIST_SOL] 태형 민주 상민 윤정 유정 [OP_LIST_EOL] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Taehyung Minju Sangmin Yoonjung Yoojeong [OP_LIST_EOL] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '태형'\nvar_b = '민주'\nvar_c = '상민'\nvar_d = '윤정'\nvar_e = '유정'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nvar_g = list_a[var_f-1]\nprint(var_g)",
        "solution_code_en": "var_a = 'Taehyung'\nvar_b = 'Minju'\nvar_c = 'Sangmin'\nvar_d = 'Yoonjung'\nvar_e = 'Yoojeong'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nvar_g = list_a[var_f-1]\nprint(var_g)"
    },
    "3514": {
        "category": "Arithmetic calculation",
        "question_ko": "3.01보다 작고 30.06을 10으로 나눈 값보다 큰 소수 세 자리 수는 모두 몇 개입니까?",
        "question_en": "How many three-digit prime numbers are there that are less than 3.01 and greater than 30.06 divided by 10?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "0 9 1 [OP_LIST_ARANGE] 6 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "0 9 1 [OP_LIST_ARANGE] 6 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 0\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "3515": {
        "category": "Arithmetic calculation",
        "question_ko": "체육관의 배드민턴 코트는 4000원에 30분을 사용할 수 있습니다. 친구 6명이서 코트 4개를 빌리고 3시간동안 사용하려면 한 사람 당 얼마를 내야할까요?",
        "question_en": "You can use the badminton court in the gym for 30 minutes for 4,000 won. How much would it cost for a person to rent 4 coats and use them for 3 hours with 6 friends?",
        "answer_ko": "16000",
        "answer_en": "16000",
        "solution_abst_ko": "3 60 [OP_MUL] 30 [OP_DIV] 4000 [OP_MUL] 4 [OP_MUL] 6 [OP_DIV]",
        "solution_abst_en": "3 60 [OP_MUL] 30 [OP_DIV] 4000 [OP_MUL] 4 [OP_MUL] 6 [OP_DIV]",
        "solution_code_ko": "var_a = 3\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 30\nvar_e = var_c / var_d\nvar_f = 4000\nvar_g = var_e * var_f\nvar_h = 4\nvar_i = var_g * var_h\nvar_j = 6\nvar_k = var_i / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 3\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 30\nvar_e = var_c / var_d\nvar_f = 4000\nvar_g = var_e * var_f\nvar_h = 4\nvar_i = var_g * var_h\nvar_j = 6\nvar_k = var_i / var_j\nprint(int(var_k))"
    },
    "3516": {
        "category": "Geometry",
        "question_ko": "한 변이 8센티미터(㎝)인 정육각형 하나와, 두 변이 13센티미터(㎝)이고 한 변이 8센티미터(㎝)인 이등변 삼각형 6개로 둘러싸인 다각뿔이 있습니다. 이 다각뿔의 모든 모서리의 합은 몇 센티미터(㎝)입니까?",
        "question_en": "There is a polygonal pyramid surrounded by one regular hexagon with sides of 8 centimeters (cm) and six isosceles triangles with two sides of 13 centimeters (cm) and one side of 8 centimeters (cm). What is the sum of all the edges of this pyramid in centimeters (cm)?",
        "answer_ko": "126",
        "answer_en": "126",
        "solution_abst_ko": "13 6 [OP_MUL] 8 6 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "13 6 [OP_MUL] 8 6 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 13\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = 6\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 13\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = 6\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "3517": {
        "category": "Geometry",
        "question_ko": "원모양 팬케익의 반지름의 길이가 7센티미터(㎝)일 때, 팬케익의 지름의 길이는 몇 센티미터(㎝)인가요?",
        "question_en": "If the radius of a round pancake is 7 centimeters (cm), how many centimeters (cm) is the diameter of the pancake?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "7 2 [OP_MUL]",
        "solution_abst_en": "7 2 [OP_MUL]",
        "solution_code_ko": "var_a = 7\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 7\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "3518": {
        "category": "Geometry",
        "question_ko": "어떤 수에 5를 곱해야 할 것을 실수로 나누었더니 30이 되었다. 바르게 계산한 것을 고르시오.",
        "question_en": "You mistakingly divided a number by 5 that should have been multiplied and you got 30. Choose the one that is calculated correctly.",
        "answer_ko": "750",
        "answer_en": "750",
        "solution_abst_ko": "30 5 5 [OP_MUL] [OP_MUL]",
        "solution_abst_en": "30 5 5 [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 30\nvar_b = 5\nvar_c = 5\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 30\nvar_b = 5\nvar_c = 5\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nprint(int(var_e))"
    },
    "3519": {
        "category": "Geometry",
        "question_ko": "정사각형 여섯 개로 이루어진 각기둥이 있습니다. 이 각기둥의 모든 모서리 길이의 합이 72센티미터(㎝)라면 한 모서리의 길이는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "There is a prism made up of six squares. If the sum of the lengths of all the edges of this prism is 72 centimeters (cm), how many centimeters (cm) is the length of one edge?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "72 4 3 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "72 4 3 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 72\nvar_b = 4\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 72\nvar_b = 4\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "3520": {
        "category": "Comparison",
        "question_ko": "슬기와 현정이는 문방구에 가서 연필을 샀습니다. 슬기는 9자루, 현정이는 12자루를 샀다면, 슬기와 현정이 중 연필을 더 많이 산 사람은 누구입니까?",
        "question_en": "Seulgi and Hyeonjeong went to the stationery store and bought pencils. If Seulgi bought 9 pencils and Hyunjeong bought 12 pencils, who bought more pencils among Seulgi and Hyunjeong?",
        "answer_ko": "현정",
        "answer_en": "Hyeonjeong",
        "solution_abst_ko": "[OP_LIST_SOL] 슬기 현정 [OP_LIST_EOL] [OP_LIST_SOL] 9 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Seulgi Hyeonjeong [OP_LIST_EOL] [OP_LIST_SOL] 9 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '슬기'\nvar_b = '현정'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 9\nvar_d = 12\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Seulgi'\nvar_b = 'Hyeonjeong'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 9\nvar_d = 12\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "3521": {
        "category": "Correspondence",
        "question_ko": "등식 6A5+10B=748이 성립한다고 합니다. A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "Say that the equation 6A5+10B=748 is true. What number should go in A?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "6A5+10B=748 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "6A5+10B=748 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '6A5+10B=748'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '6A5+10B=748'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "3522": {
        "category": "Possibility",
        "question_ko": "정국, 지민, 윤기, 유나 중에서 두 사람을 선택해서 줄 세우려고 합니다. 경우의 수는 모두 몇 가지입니까?",
        "question_en": "I'm going to choose two people from Jungkook, Jimin, Yoongi, and Yuna, and line them up. How many cases are there in all?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 지민 윤기 유나 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Jimin Yoongi Yuna [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '지민'\nvar_c = '윤기'\nvar_d = '유나'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nprint(int(var_g))",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Jimin'\nvar_c = 'Yoongi'\nvar_d = 'Yuna'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nprint(int(var_g))"
    },
    "3523": {
        "category": "Arithmetic calculation",
        "question_ko": "오이를 100그램(g)에 300원씩 팔고 있습니다. 7,500원으로 오이를 몇 킬로그램(㎏) 살 수 있는지 소수점을 포함하여 답을 구하시오.",
        "question_en": "Cucumbers are sold for 300 won per 100 grams (g). Determine how many kilograms (kg) of cucumbers you can buy with 7,500 won, including the decimal point.",
        "answer_ko": "2.50",
        "answer_en": "2.5",
        "solution_abst_ko": "7500 100 300 [OP_DIV] [OP_MUL] 1000 [OP_DIV]",
        "solution_abst_en": "7500 100 300 [OP_DIV] [OP_MUL] 1000 [OP_DIV]",
        "solution_code_ko": "var_a = 7500\nvar_b = 100\nvar_c = 300\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 1000\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 7500\nvar_b = 100\nvar_c = 300\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 1000\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "3524": {
        "category": "Arithmetic calculation",
        "question_ko": "석기에게는 색종이가 82장이 있었습니다. 이 중 몇 장을 사용하여 미술 작품을 만들었을 때 남은 색종이 수가 사용한 색종이 수보다 6장 적다면 사용한 색종이는 몇 장인지 구하시오.",
        "question_en": "Seokgi had 82 sheets of colored paper. If the number of colored paper left is 6 less than the number of pieces of colored paper used for making a piece of art, find how many pieces of colored paper were used.",
        "answer_ko": "44",
        "answer_en": "44",
        "solution_abst_ko": "82 6 [OP_SUB] 2 [OP_DIV] 6 [OP_ADD]",
        "solution_abst_en": "82 6 [OP_SUB] 2 [OP_DIV] 6 [OP_ADD]",
        "solution_code_ko": "var_a = 82\nvar_b = 6\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 6\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 82\nvar_b = 6\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 6\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "3525": {
        "category": "Arithmetic calculation",
        "question_ko": "지혜가 할머니 댁에 가는 데 전체 거리의 1/5은 걷고, 나머지 거리는 버스를 타고 갔습니다. 버스를 타고 간 거리는 전체 거리의 몇 배입니까?",
        "question_en": "To get to her grandmother's house, Wisdom walked one-fifth of the distance and took a bus the rest of the way. How many times the distance travelled by bus is the total distance?",
        "answer_ko": "0.80",
        "answer_en": "0.8",
        "solution_abst_ko": "1 1/5 [OP_SUB]",
        "solution_abst_en": "1 1/5 [OP_SUB]",
        "solution_code_ko": "var_a = 1\nvar_b = 0.2\nvar_c = var_a - var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 0.2\nvar_c = var_a - var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "3526": {
        "category": "Comparison",
        "question_ko": "(나) 상자가 (다) 보다 크지만 (마) 상자보다는 작습니다. (가) 상자와 (라) 상자 중에는 (가) 상자가 작고, (가) 상자와 (마) 상자중에는 (가) 상자가 큽니다. 어떤 상자가 가장 큽니까?",
        "question_en": "Box B is larger than box C but smaller than box E. Among boxes A and D boxes, A is smaller, and between boxes A and E, A is larger. Which box is the largest?",
        "answer_ko": "(라)",
        "answer_en": "D",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) (다) (라) (마) [OP_LIST_EOL] [OP_LIST_SOL] (나) (다) > (나) (마) < (가) (라) < (가) (마) > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D E [OP_LIST_EOL] [OP_LIST_SOL] B C > B E < A D < A E > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nvar_c = '(다)'\nvar_d = '(라)'\nvar_e = '(마)'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = '(나)'\nvar_g = '(다)'\nvar_h = '>'\nvar_i = '(나)'\nvar_j = '(마)'\nvar_k = '<'\nvar_l = '(가)'\nvar_m = '(라)'\nvar_n = '<'\nvar_o = '(가)'\nvar_p = '(마)'\nvar_q = '>'\nlist_b= []\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_r = 1\nvar_s = list_c[var_r-1]\nprint(var_s)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 'B'\nvar_g = 'C'\nvar_h = '>'\nvar_i = 'B'\nvar_j = 'E'\nvar_k = '<'\nvar_l = 'A'\nvar_m = 'D'\nvar_n = '<'\nvar_o = 'A'\nvar_p = 'E'\nvar_q = '>'\nlist_b= []\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_r = 1\nvar_s = list_c[var_r-1]\nprint(var_s)"
    },
    "3527": {
        "category": "Comparison",
        "question_ko": "사과 한 상자의 무게는 3/5킬로그램(㎏)이고 귤 한 상자의 무게는 0.49킬로그램(㎏)입니다. 어떤 상자가 더 무거울까요?",
        "question_en": "A box of apples weighs 3/5 kilograms (kg) and a box of tangerines weighs 0.49 kilograms (kg). Which box is heavier?",
        "answer_ko": "사과",
        "answer_en": "apples",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 귤 [OP_LIST_EOL] [OP_LIST_SOL] 3 5 [OP_DIV] 0.49 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] apples tangerines [OP_LIST_EOL] [OP_LIST_SOL] 3 5 [OP_DIV] 0.49 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '귤'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nvar_d = 5\nvar_e = var_c / var_d\nvar_f = 0.49\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'apples'\nvar_b = 'tangerines'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nvar_d = 5\nvar_e = var_c / var_d\nvar_f = 0.49\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "3528": {
        "category": "Geometry",
        "question_ko": "가로가 24센티미터(㎝), 세로가 18센티미터(㎝)인 직사각형 모양의 반죽을 남는 부분 없이 잘라 같은 크기의 가장 큰 정사각형 모양의 쿠키를 여러 개 만들려고 합니다. 쿠키는 모두 몇 개 만들 수 있습니까?",
        "question_en": "You plan to bake several of the largest cookies by cutting out a rectangle dough measuring 24 centimeters (cm) long and 18 centimeters (cm) wide. How many cookies can you make in all without any leftover?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "24 24 18 [OP_GCD] [OP_FDIV] 18 24 18 [OP_GCD] [OP_FDIV] [OP_MUL]",
        "solution_abst_en": "24 24 18 [OP_GCD] [OP_FDIV] 18 24 18 [OP_GCD] [OP_FDIV] [OP_MUL]",
        "solution_code_ko": "var_a = 24\nvar_b = 24\nvar_c = 18\nvar_d = math.gcd(int(var_c), int(var_b))\nvar_e = var_a // var_d\nvar_f = 18\nvar_g = 24\nvar_h = 18\nvar_i = math.gcd(int(var_h), int(var_g))\nvar_j = var_f // var_i\nvar_k = var_e * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 24\nvar_b = 24\nvar_c = 18\nvar_d = math.gcd(int(var_c), int(var_b))\nvar_e = var_a // var_d\nvar_f = 18\nvar_g = 24\nvar_h = 18\nvar_i = math.gcd(int(var_h), int(var_g))\nvar_j = var_f // var_i\nvar_k = var_e * var_j\nprint(int(var_k))"
    },
    "3529": {
        "category": "Geometry",
        "question_ko": "어떤 정육면체의 한 모서리의 길이가 7센티미터(㎝)이다. 이 정육면체의 겉면에 색종이를 남김없이 붙이려고 한다면, 필요한 색종이의 넓이는 얼마인지 구하시오.",
        "question_en": "The length of one edge of a cube is 7 centimeters (cm). If you are going to glue all the colored paper to the surface of this cube, find the area of the colored paper you will need.",
        "answer_ko": "294",
        "answer_en": "294",
        "solution_abst_ko": "7 2 [OP_POW] 6 [OP_MUL]",
        "solution_abst_en": "7 2 [OP_POW] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 7\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 7\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "3530": {
        "category": "Geometry",
        "question_ko": "길이가 2센티미터(㎝)인 막대기 9개를 모두 사용하여 도형을 만들었습니다. 각 막대기가 이루는 각은 모두 같고, 변이 9개인 이 도형의 둘레를 구하시오.",
        "question_en": "I made a figure using all 9 sticks, each 2 centimeters (cm) long. Find the perimeter of this figure with all the same angles and 9 sides.",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "2 9 [OP_MUL]",
        "solution_abst_en": "2 9 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 9\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 9\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "3531": {
        "category": "Geometry",
        "question_ko": "현호네 반 담임선생님은 24명의 학생들에게 한 변의 길이가 4센티미터(㎝)인 정사각형 모양으로 이름표를 만들어주기 위해서 문구점에서 큰 종이를 샀습니다. 선생님이 길이 계산을 잘못하여 가로의 길이가 34센티미터(㎝)인 종이를 샀고, 이름표를 만든 후 가로의 길이는 2센티미터(㎝)가 남고 세로의 길이는 딱 맞아떨어졌다면, 선생님이 산 종이의 둘레는 몇 센티미터(㎝)였을까요?",
        "question_en": "Hyeonho's class teacher bought a large sheet of paper from a stationery store to make name tags for 24 students in the shape of a square with a side length of 4 centimeters (cm). If the teacher miscalculated the length and bought a piece of paper with a width of 34 centimeters (cm), and after making the name tag, the width of the paper is 2 centimeters (cm) left and the length is just right, how many centimeters (cm) was the perimeter of the paper the teacher bought?",
        "answer_ko": "92",
        "answer_en": "92",
        "solution_abst_ko": "24 34 4 [OP_FDIV] [OP_DIV] 4 [OP_MUL] 34 [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "24 34 4 [OP_FDIV] [OP_DIV] 4 [OP_MUL] 34 [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 24\nvar_b = 34\nvar_c = 4\nvar_d = var_b // var_c\nvar_e = var_a / var_d\nvar_f = 4\nvar_g = var_e * var_f\nvar_h = 34\nvar_i = var_g + var_h\nvar_j = 2\nvar_k = var_i * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 24\nvar_b = 34\nvar_c = 4\nvar_d = var_b // var_c\nvar_e = var_a / var_d\nvar_f = 4\nvar_g = var_e * var_f\nvar_h = 34\nvar_i = var_g + var_h\nvar_j = 2\nvar_k = var_i * var_j\nprint(int(var_k))"
    },
    "3532": {
        "category": "Arithmetic calculation",
        "question_ko": "민수네 반 학생 30명은 1번부터 30번까지 자신의 출석 번호를 가지고 있습니다. 민수네 반 학생 중 안경을 쓴 학생은 1번, 3번, 7번, 10번, 23번, 27번 학생이고, 머리를 묶은 학생은 1번, 9번, 11번, 20번, 23번 학생일 때, 안경을 쓰고 머리를 묶은 학생은 몇 명입니까?",
        "question_en": "The 30 students in Minsu's class have their own attendance numbers from 1 to 30. Among the students in Minsu's class, the students wearing glasses are students 1, 3, 7, 10, 23, and 27, and the students with their hair tied are students 1, 9, 11, 20, and 23. How many students both wear glasses and have their hair tied?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 7 10 23 27 [OP_LIST_EOL] [OP_LIST_SOL] 1 9 11 20 23 [OP_LIST_EOL] [OP_SET_INTERSECT] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 7 10 23 27 [OP_LIST_EOL] [OP_LIST_SOL] 1 9 11 20 23 [OP_LIST_EOL] [OP_SET_INTERSECT] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 7\nvar_d = 10\nvar_e = 23\nvar_f = 27\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 1\nvar_h = 9\nvar_i = 11\nvar_j = 20\nvar_k = 23\nlist_b= []\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nlist_c = list(set(list_a) & set(list_b))\nvar_l = len(list_c)\nprint(int(var_l))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 7\nvar_d = 10\nvar_e = 23\nvar_f = 27\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 1\nvar_h = 9\nvar_i = 11\nvar_j = 20\nvar_k = 23\nlist_b= []\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nlist_c = list(set(list_a) & set(list_b))\nvar_l = len(list_c)\nprint(int(var_l))"
    },
    "3533": {
        "category": "Arithmetic calculation",
        "question_ko": "석진이는 구슬을 3개 가지고 있습니다. 유나는 석진이보다 구슬을 1개 더 적게 가지고 있습니다. 지민이는 석진이보다 구슬을 2배 더 많이 가지고 있습니다. 지민이는 유나보다 구슬을 몇 개 더 많이 가지고 있습니까?",
        "question_en": "Seokjin has 3 marbles. Yuna has 1 less marble than Seokjin. Jimin has 2 times more marbles than Seokjin. How many more marbles does Jimin have than Yuna?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "3 2 [OP_MUL] 3 1 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "3 2 [OP_MUL] 3 1 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "3534": {
        "category": "Arithmetic calculation",
        "question_ko": "31보다 같거나 작으며 28보다 큰 자연수를 모두 더하면 얼마입니까?",
        "question_en": "What do you get when adding all natural numbers that are less than or equal to 31 and greater than 28?",
        "answer_ko": "90",
        "answer_en": "90",
        "solution_abst_ko": "28 1 [OP_ADD] 31 1 [OP_LIST_ARANGE] [OP_LIST_SUM]",
        "solution_abst_en": "28 1 [OP_ADD] 31 1 [OP_LIST_ARANGE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 28\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 31\nvar_e = 1\nlist_a = [i for i in range(var_c, var_d + 1, var_e)]\nlist_a = [float(i) for i in list_a]\nvar_f = sum(list_a)\nprint(int(var_f))",
        "solution_code_en": "var_a = 28\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 31\nvar_e = 1\nlist_a = [i for i in range(var_c, var_d + 1, var_e)]\nlist_a = [float(i) for i in list_a]\nvar_f = sum(list_a)\nprint(int(var_f))"
    },
    "3535": {
        "category": "Possibility",
        "question_ko": "500원짜리 동전 4개, 100원짜리 동전 2개, 10원짜리 동전 5개를 가지고 지불할 수 있는 금액은 모두 몇 가지인지 구하시오. (단, 지불 금액이 0원인 경우는 제외한다.)",
        "question_en": "How many total cases can you pay with 4 500-won coins, 2 100-won coins, and 5 10-won coins (excluding the case where the payment amount is 0 won is)?",
        "answer_ko": "89",
        "answer_en": "89",
        "solution_abst_ko": "4 1 [OP_ADD] 2 1 [OP_ADD] [OP_MUL] 5 1 [OP_ADD] [OP_MUL] 1 [OP_SUB]",
        "solution_abst_en": "4 1 [OP_ADD] 2 1 [OP_ADD] [OP_MUL] 5 1 [OP_ADD] [OP_MUL] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 4\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = var_c * var_f\nvar_h = 5\nvar_i = 1\nvar_j = var_h + var_i\nvar_k = var_g * var_j\nvar_l = 1\nvar_m = var_k - var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 4\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = var_c * var_f\nvar_h = 5\nvar_i = 1\nvar_j = var_h + var_i\nvar_k = var_g * var_j\nvar_l = 1\nvar_m = var_k - var_l\nprint(int(var_m))"
    },
    "3536": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 24를 빼려고 합니다. 잘못하여 42를 더했을 때의 답이 50이라면 바르게 계산한 결과는 얼마일까요?",
        "question_en": "You are going to subtract 24 from a certain number. What is the result of the correct calculation result if you accidentally add 42 and the result is 50?",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "50 42 [OP_SUB] 24 [OP_SUB]",
        "solution_abst_en": "50 42 [OP_SUB] 24 [OP_SUB]",
        "solution_code_ko": "var_a = 50\nvar_b = 42\nvar_c = var_a - var_b\nvar_d = 24\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 50\nvar_b = 42\nvar_c = var_a - var_b\nvar_d = 24\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3537": {
        "category": "Correspondence",
        "question_ko": "10에 A를 더했더니 15가 되었습니다. A는 얼마인가요?",
        "question_en": "If you add A to 10, you get 15. How much is A?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "15 10 [OP_SUB]",
        "solution_abst_en": "15 10 [OP_SUB]",
        "solution_code_ko": "var_a = 15\nvar_b = 10\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 15\nvar_b = 10\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "3538": {
        "category": "Comparison",
        "question_ko": "밑면의 넓이가 8제곱센티미터(㎠)이고 높이가 3센티미터(㎝)인 직육면체 A와 한 변의 길이가 5센티미터(㎝)인 정육면체 B 중 부피가 더 큰 것은 무엇인가요?",
        "question_en": "Which of these has a larger volume, cuboid A with a base area is 8 square centimeters (cm2) and a height of 3 centimeters (cm), or cube B with a side length of 5 centimeters (cm)?",
        "answer_ko": "B",
        "answer_en": "B",
        "solution_abst_ko": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 8 3 [OP_MUL] 5 5 [OP_MUL] 5 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 8 3 [OP_MUL] 5 5 [OP_MUL] 5 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 8\nvar_d = 3\nvar_e = var_c * var_d\nvar_f = 5\nvar_g = 5\nvar_h = var_f * var_g\nvar_i = 5\nvar_j = var_h * var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 8\nvar_d = 3\nvar_e = var_c * var_d\nvar_f = 5\nvar_g = 5\nvar_h = var_f * var_g\nvar_i = 5\nvar_j = var_h * var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "3539": {
        "category": "Correspondence",
        "question_ko": "44을 어떤 수에서 뺐더니 15가 되었습니다. 어떤 수를 얼마입니까?",
        "question_en": "Subtracting 44 from a number gives 15. What number is it?",
        "answer_ko": "59",
        "answer_en": "59",
        "solution_abst_ko": "15 44 [OP_ADD]",
        "solution_abst_en": "15 44 [OP_ADD]",
        "solution_code_ko": "var_a = 15\nvar_b = 44\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 15\nvar_b = 44\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "3540": {
        "category": "Correspondence",
        "question_ko": "A4461B는 여섯 자리 수이고 72의 배수입니다. A+B의 값은 무엇입니까?",
        "question_en": "A4461B is a six-digit number and is a multiple of 72. What is the value of A+B?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "A4461B [OP_GEN_POSSIBLE_LIST] 72 [OP_LIST_DIVISIBLE] A4461B A [OP_LIST_FIND_UNK] A4461B B [OP_LIST_FIND_UNK] [OP_ADD]",
        "solution_abst_en": "A4461B [OP_GEN_POSSIBLE_LIST] 72 [OP_LIST_DIVISIBLE] A4461B A [OP_LIST_FIND_UNK] A4461B B [OP_LIST_FIND_UNK] [OP_ADD]",
        "solution_code_ko": "var_a = 'A4461B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 72\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 'A4461B'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nvar_e = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_e = int(elem[unk_idx])\nvar_f = 'A4461B'\nvar_g = 'B'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nvar_i = var_e + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 'A4461B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 72\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 'A4461B'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nvar_e = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_e = int(elem[unk_idx])\nvar_f = 'A4461B'\nvar_g = 'B'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nvar_i = var_e + var_h\nprint(int(var_i))"
    },
    "3541": {
        "category": "Comparison",
        "question_ko": "도서관에 똑같은 책장이 28개 있습니다. 각 책장은 6층이고, 각 층마다 꽂혀 있는 책의 수는 같습니다. 어느 책장의 한 층에서 맨 앞쪽의 책과 맨 뒤쪽의 책을 뽑았을 때 그 층에 20권이 남았다고 합니다. 도서관의 책장에 꽂혀 있는 책은 모두 몇 권입니까?",
        "question_en": "There are 28 identical bookshelves in the library. Each bookshelf has 6 floors, and the number of books on each floor is the same. It is said that when the first book and the last book were removed from a shelf, there were 20 books left on that floor. How many books are on the shelves in the library?",
        "answer_ko": "3696",
        "answer_en": "3696",
        "solution_abst_ko": "20 2 [OP_ADD] 6 [OP_MUL] 28 [OP_MUL]",
        "solution_abst_en": "20 2 [OP_ADD] 6 [OP_MUL] 28 [OP_MUL]",
        "solution_code_ko": "var_a = 20\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 6\nvar_e = var_c * var_d\nvar_f = 28\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 20\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 6\nvar_e = var_c * var_d\nvar_f = 28\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "3542": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 32를 더해야 하는데 잘못하여 32를 뺐더니 33이 되었습니다. 바르게 계산한 결과를 구하시오.",
        "question_en": "I need to add 32 to a number, but I mistakenly subtracted 32, so I got 33. Find the result of the correct calculation.",
        "answer_ko": "97",
        "answer_en": "97",
        "solution_abst_ko": "33 32 [OP_ADD] 32 [OP_ADD]",
        "solution_abst_en": "33 32 [OP_ADD] 32 [OP_ADD]",
        "solution_code_ko": "var_a = 33\nvar_b = 32\nvar_c = var_a + var_b\nvar_d = 32\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 33\nvar_b = 32\nvar_c = var_a + var_b\nvar_d = 32\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3543": {
        "category": "Geometry",
        "question_ko": "선경이는 팔각형의 대각선을 모두 그었다. 총 몇 개의 선을 그었는가?",
        "question_en": "Sunkyung drew all the diagonals of an octagon. How many lines did she draw in total?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "8 8 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "8 8 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 8\nvar_b = 8\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 8\nvar_b = 8\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "3544": {
        "category": "Possibility",
        "question_ko": "세 자리 수 중 일의 자리, 십의 자리, 백의 자리 숫자의 합이 24인 수는 모두 몇 개일까요?",
        "question_en": "How many three-digit numbers have the sum of the ones, tens, and hundreds digits equal to 24?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "100 1000 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] 24 [OP_LIST_MORE_EQUAL] 24 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "100 1000 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] 24 [OP_LIST_MORE_EQUAL] 24 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 100\nvar_b = 1000\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nlist_b=[]\nfor i in list_a:\n    var_f = 0\n    i = int(i)\n    while i//10 > 0:\n        var_f = var_f + i%10\n        i = i//10\n    var_f = var_f + i%10\n    list_b.append(var_f)\nvar_g = 24\nlist_c = []\nfor i in list_b:\n    if i >= var_g:\n        list_c.append(i)\nvar_h = 24\nlist_d = []\nfor i in list_c:\n    if i <= var_h:\n        list_d.append(i)\nvar_i = len(list_d)\nprint(int(var_i))",
        "solution_code_en": "var_a = 100\nvar_b = 1000\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nlist_b=[]\nfor i in list_a:\n    var_f = 0\n    i = int(i)\n    while i//10 > 0:\n        var_f = var_f + i%10\n        i = i//10\n    var_f = var_f + i%10\n    list_b.append(var_f)\nvar_g = 24\nlist_c = []\nfor i in list_b:\n    if i >= var_g:\n        list_c.append(i)\nvar_h = 24\nlist_d = []\nfor i in list_c:\n    if i <= var_h:\n        list_d.append(i)\nvar_i = len(list_d)\nprint(int(var_i))"
    },
    "3545": {
        "category": "Possibility",
        "question_ko": "8개 반이 농구 시합을 하려고 합니다. 두 팀씩 경기를 하여 패배한 팀은 탈락하고 승리한 팀만 다음 경기를 할 수 있으며, 마지막에 승리한 팀이 우승합니다. 경기의 총 횟수를 구하시오.",
        "question_en": "Eight classes are going to play a basketball game. Two teams play each other, and the losing team is eliminated, and only the winning team can play the next game, and the winning team at the end wins. Find the total number of matches.",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "8/2 8/2 1 [OP_ADD] [OP_MUL] 2 8/2 [OP_MUL] 1 [OP_ADD] [OP_MUL] 6 [OP_DIV]",
        "solution_abst_en": "8/2 8/2 1 [OP_ADD] [OP_MUL] 2 8/2 [OP_MUL] 1 [OP_ADD] [OP_MUL] 6 [OP_DIV]",
        "solution_code_ko": "var_a = 4\nvar_b = 4\nvar_c = 1\nvar_d = var_b + var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = 4\nvar_h = var_f * var_g\nvar_i = 1\nvar_j = var_h + var_i\nvar_k = var_e * var_j\nvar_l = 6\nvar_m = var_k / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 4\nvar_b = 4\nvar_c = 1\nvar_d = var_b + var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = 4\nvar_h = var_f * var_g\nvar_i = 1\nvar_j = var_h + var_i\nvar_k = var_e * var_j\nvar_l = 6\nvar_m = var_k / var_l\nprint(int(var_m))"
    },
    "3546": {
        "category": "Geometry",
        "question_ko": "정육면체 모양의 주사위의 한 변의 길이는 9센티미터(㎝)입니다. 이 주사위의 한 면을 선택해 이 면을 이루는 변의 길이를 모두 합하면 몇 센티미터(㎝)일지 구하시오.",
        "question_en": "The length of one side of a cube-shaped die is 9 centimeters (cm). Choose one side of the die and find how many centimeters (cm) is the sum of the lengths of the sides that make up this side.",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "9 4 [OP_MUL]",
        "solution_abst_en": "9 4 [OP_MUL]",
        "solution_code_ko": "var_a = 9\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 9\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "3547": {
        "category": "Arithmetic calculation",
        "question_ko": "아버지는 유나보다 27살이 많고 할아버지는 아버지보다 23살이 많습니다. 올해 유나가 9살이라면, 올해 할아버지의 나이는 몇 살입니까?",
        "question_en": "Yuna's father is 27 years older than Yuna and her grandfather is 23 years older than her father. If Yuna is 9 years old this year, how old is Yuna's grandfather this year?",
        "answer_ko": "59",
        "answer_en": "59",
        "solution_abst_ko": "9 27 [OP_ADD] 23 [OP_ADD]",
        "solution_abst_en": "9 27 [OP_ADD] 23 [OP_ADD]",
        "solution_code_ko": "var_a = 9\nvar_b = 27\nvar_c = var_a + var_b\nvar_d = 23\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 27\nvar_c = var_a + var_b\nvar_d = 23\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3548": {
        "category": "Arithmetic calculation",
        "question_ko": "사과가 가방에 20개 들어 있습니다. 가방 5개에 들어있는 사과는 모두 몇 개입니까?",
        "question_en": "There are 20 apples in the bag. How many apples are in all 5 bags?",
        "answer_ko": "100",
        "answer_en": "100",
        "solution_abst_ko": "20 5 [OP_MUL]",
        "solution_abst_en": "20 5 [OP_MUL]",
        "solution_code_ko": "var_a = 20\nvar_b = 5\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 20\nvar_b = 5\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "3549": {
        "category": "Possibility",
        "question_ko": "300보다 작은 세자리 자연수 중 각 자리수의 합이 7인 숫자는 몇 개 인지 구하시오.",
        "question_en": "How many three-digit numbers less than 300 satisfiy the following condition that the sum of each digit needs to be 7?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "100 999 1 [OP_LIST_ARANGE] 300 [OP_LIST_LESS] [OP_LIST_NUM2SUM] 7 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "100 999 1 [OP_LIST_ARANGE] 300 [OP_LIST_LESS] [OP_LIST_NUM2SUM] 7 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 300\nlist_b = []\nfor i in list_a:\n    if i < var_d:\n        list_b.append(i)\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 7\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))",
        "solution_code_en": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 300\nlist_b = []\nfor i in list_a:\n    if i < var_d:\n        list_b.append(i)\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 7\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))"
    },
    "3550": {
        "category": "Correspondence",
        "question_ko": "280은 어떤 수에 479를 더해야 하는데 잘못하여 749를 빼서 구한 결과이다. 바르게 계산한 값을 구하여라.",
        "question_en": "I should add 479 to a certain number, but the result I get by accidentally subtracting 749 from a certain number is 280. Find the correct calculated value.",
        "answer_ko": "1508",
        "answer_en": "1508",
        "solution_abst_ko": "280 749 [OP_ADD] 479 [OP_ADD]",
        "solution_abst_en": "280 749 [OP_ADD] 479 [OP_ADD]",
        "solution_code_ko": "var_a = 280\nvar_b = 749\nvar_c = var_a + var_b\nvar_d = 479\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 280\nvar_b = 749\nvar_c = var_a + var_b\nvar_d = 479\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3551": {
        "category": "Geometry",
        "question_ko": "빨간 상자의 부피는 0.01세제곱미터(㎥)이고 노란 상자의 부피는 4800세제곱센티미터(㎤)입니다. 빨간 상자와 노란 상자의 부피의 차는 얼마인지 구하시오.",
        "question_en": "The volume of the red box is 0.01 cubic meters (m3), and the volume of the yellow box is 4800 cubic centimeters (cm3). What is the difference between the volume of the red box and the yellow box?",
        "answer_ko": "5200",
        "answer_en": "5200",
        "solution_abst_ko": "0.01 100 100 100 [OP_MUL] [OP_MUL] [OP_MUL] 4800 [OP_SUB] [OP_ABS]",
        "solution_abst_en": "0.01 100 100 100 [OP_MUL] [OP_MUL] [OP_MUL] 4800 [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 0.01\nvar_b = 100\nvar_c = 100\nvar_d = 100\nvar_e = var_c * var_d\nvar_f = var_b * var_e\nvar_g = var_a * var_f\nvar_h = 4800\nvar_i = var_g - var_h\nvar_j = abs(var_i)\nprint(int(var_j))",
        "solution_code_en": "var_a = 0.01\nvar_b = 100\nvar_c = 100\nvar_d = 100\nvar_e = var_c * var_d\nvar_f = var_b * var_e\nvar_g = var_a * var_f\nvar_h = 4800\nvar_i = var_g - var_h\nvar_j = abs(var_i)\nprint(int(var_j))"
    },
    "3552": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 6센티미터(㎝)이고, 둘레의 길이가 20센티미터(㎝)인 이등변 삼각형의 다른 한 변의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "How many centimeters (cm) is the length of the other side of an isosceles triangle with a side of 6 centimeters (cm) and a perimeter of 20 centimeters (cm)?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "20 6 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "20 6 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 20\nvar_b = 6\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 6\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "3553": {
        "category": "Possibility",
        "question_ko": "숫자 2, 5를 중복으로 사용하여 만들 수 있는 모든 두 자리 수의 합을 구하시오.",
        "question_en": "Find the sum of all two-digit numbers that can be formed by using the numbers 2 and 5 as duplicates.",
        "answer_ko": "154",
        "answer_en": "154",
        "solution_abst_ko": "[OP_LIST_SOL] 2 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PRODUCT] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 2 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PRODUCT] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 2\nvar_b = 5\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_b = [float(i) for i in list_b]\nvar_d = sum(list_b)\nprint(int(var_d))",
        "solution_code_en": "var_a = 2\nvar_b = 5\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_b = [float(i) for i in list_b]\nvar_d = sum(list_b)\nprint(int(var_d))"
    },
    "3554": {
        "category": "Comparison",
        "question_ko": "어느 전시회의 입장료는 1인당 10000원입니다. 입장객을 세어 보니 개장 첫 날에는 350명, 2일차에는 427명, 3일차에는 384명, 4일 차에는 402명, 5일 차에는 431명이 왔습니다. 입장객이 400명 이하였던 날들의 평균 입장료 수입은 얼마입니까?",
        "question_en": "The admission fee for an exhibition is 10,000 won per person. The number of visitors was 350 on the first day of opening, 427 on the second day, 384 on the third day, 402 on the fourth day, and 431 on the fifth day. What is the average ticket revenue for days when there were fewer than 400 visitors?",
        "answer_ko": "3670000",
        "answer_en": "3670000",
        "solution_abst_ko": "[OP_LIST_SOL] 350 427 384 402 431 [OP_LIST_EOL] 400 [OP_LIST_LESS_EQUAL] [OP_LIST_MEAN] 10000 [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 350 427 384 402 431 [OP_LIST_EOL] 400 [OP_LIST_LESS_EQUAL] [OP_LIST_MEAN] 10000 [OP_MUL]",
        "solution_code_ko": "var_a = 350\nvar_b = 427\nvar_c = 384\nvar_d = 402\nvar_e = 431\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 400\nlist_b = []\nfor i in list_a:\n    if i <= var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)/len(list_b)\nvar_h = 10000\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 350\nvar_b = 427\nvar_c = 384\nvar_d = 402\nvar_e = 431\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 400\nlist_b = []\nfor i in list_a:\n    if i <= var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)/len(list_b)\nvar_h = 10000\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "3555": {
        "category": "Comparison",
        "question_ko": "한 학교에 전교생이 1443명이 있습니다. 전체 여학생 수는 남학생 수보다 141명 더 적다고 합니다. 남학생은 이 학교에 몇 명이 있습니까?",
        "question_en": "There are 1443 students in total in one school. The total number of girls is 141 fewer than the number of boys. How many boys are there in this school?",
        "answer_ko": "792",
        "answer_en": "792",
        "solution_abst_ko": "1443 141 [OP_ADD] 2 [OP_DIV]",
        "solution_abst_en": "1443 141 [OP_ADD] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 1443\nvar_b = 141\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 1443\nvar_b = 141\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "3556": {
        "category": "Geometry",
        "question_ko": "정이십면체에서 한 꼭짓점에 모인 면은 모두 몇 개 일까요?",
        "question_en": "How many faces of an icosahedron meet at a vertex?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "5",
        "solution_abst_en": "5",
        "solution_code_ko": "var_a = 5\nprint(int(var_a))",
        "solution_code_en": "var_a = 5\nprint(int(var_a))"
    },
    "3557": {
        "category": "Geometry",
        "question_ko": "민수는 오각기둥의 면을 색칠하려고 합니다. 각 면마다 다른 색을 사용한다고 할 때 필요한 색은 몇 가지입니까?",
        "question_en": "Minsu wants to color the faces of the pentagonal prism. How many colors do you need if you use a different color for each face?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "2 5 [OP_ADD]",
        "solution_abst_en": "2 5 [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "3558": {
        "category": "Arithmetic calculation",
        "question_ko": "서로 다른 5개의 네 자리 수 9867, 8976, 9876, 9687, 9689를 작은 수부터 왼쪽부터 차례로 나열했습니다. 왼쪽에서 4번째에 있는 수는 무엇입니까?",
        "question_en": "The five different four-digit numbers 9867, 8976, 9876, 9687, and 9689 are listed from smallest on the left to largest on the right. What is the 4th number from the left?",
        "answer_ko": "9867",
        "answer_en": "9867",
        "solution_abst_ko": "[OP_LIST_SOL] 9867 8976 9876 9687 9689 [OP_LIST_EOL] 4 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 9867 8976 9876 9687 9689 [OP_LIST_EOL] 4 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 9867\nvar_b = 8976\nvar_c = 9876\nvar_d = 9687\nvar_e = 9689\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 4\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 9867\nvar_b = 8976\nvar_c = 9876\nvar_d = 9687\nvar_e = 9689\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 4\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nprint(int(var_g))"
    },
    "3559": {
        "category": "Possibility",
        "question_ko": "유나는 5장의 숫자 카드 중 3장을 뽑아 일렬로 세우려고 합니다. 숫자 카드를 배치할 수 있는 경우는 모두 몇 가지입니까?",
        "question_en": "Yuna draws 3 out of 5 number cards and tries to line them up. How many ways can a number card be placed?",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "5 3 [OP_PERM]",
        "solution_abst_en": "5 3 [OP_PERM]",
        "solution_code_ko": "var_a = 5\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))"
    },
    "3560": {
        "category": "Geometry",
        "question_ko": "가로의 길이가 81/4센티미터(㎝)이며 세로의 길이가 148/9센티미터(㎝)인 직사각형이 있습니다. 이 직사각형의 넓이는 몇 제곱센티미터(㎠)입니까?",
        "question_en": "A rectangle has a width of 81/4 centimeters (cm) and a height of 148/9 centimeters (cm). What is the area of this rectangle in square centimeters (cm2)?",
        "answer_ko": "333",
        "answer_en": "333",
        "solution_abst_ko": "81/4 148/9 [OP_MUL]",
        "solution_abst_en": "81/4 148/9 [OP_MUL]",
        "solution_code_ko": "var_a = 20.25\nvar_b = 16.444444444444443\nvar_c = var_a * var_b\nprint(int(eval('{:.2f}'.format(round(var_c+1e-10,2)))))",
        "solution_code_en": "var_a = 20.25\nvar_b = 16.444444444444443\nvar_c = var_a * var_b\nprint(int(eval('{:.2f}'.format(round(var_c+1e-10,2)))))"
    },
    "3561": {
        "category": "Geometry",
        "question_ko": "오각기둥의 면의 개수는?",
        "question_en": "What is the number of faces of a pentagonal prism?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "5 2 [OP_ADD]",
        "solution_abst_en": "5 2 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "3562": {
        "category": "Comparison",
        "question_ko": "경수의 그룹 학생들이 멀리뛰기를 했다. 경수가 2.3미터(m), 영희가 9/10미터(m), 진주가 1.8미터(m), 찬호가 2.5미터(m)를 뛰었을 때 2위는?",
        "question_en": "Kyungsoo's group of students did the long jump. Kyungsoo jumped 2.3 meters (m), Younghee jumped 9/10 meters (m), Jinju jumped 1.8 meters (m), and Chanho jumped 2.5 meters (m). Who came as the second?",
        "answer_ko": "경수",
        "answer_en": "Kyungsoo",
        "solution_abst_ko": "[OP_LIST_SOL] 경수 영희 진주 찬호 [OP_LIST_EOL] [OP_LIST_SOL] 2.3 9 10 [OP_DIV] 1.8 2.5 [OP_LIST_EOL] 2 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Kyungsoo Younghee Jinju Chanho [OP_LIST_EOL] [OP_LIST_SOL] 2.3 9 10 [OP_DIV] 1.8 2.5 [OP_LIST_EOL] 2 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '경수'\nvar_b = '영희'\nvar_c = '진주'\nvar_d = '찬호'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2.3\nvar_f = 9\nvar_g = 10\nvar_h = var_f / var_g\nvar_i = 1.8\nvar_j = 2.5\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_k = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'Kyungsoo'\nvar_b = 'Younghee'\nvar_c = 'Jinju'\nvar_d = 'Chanho'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2.3\nvar_f = 9\nvar_g = 10\nvar_h = var_f / var_g\nvar_i = 1.8\nvar_j = 2.5\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_k = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "3563": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중에서 가장 큰 수와 그 다음으로 큰 수의 곱은 얼마입니까?",
        "question_en": "There are three numbers 10, 11, and 12. What is the product of the largest number and the next largest number?",
        "answer_ko": "132",
        "answer_en": "132",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = var_e * var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = var_e * var_g\nprint(int(var_h))"
    },
    "3564": {
        "category": "Comparison",
        "question_ko": "예지는 중간고사에서 국어, 수학, 사회, 과학 네 과목의 시험을 봤습니다. 국어를 수학보다 먼저 보고, 사회는 수학보다는 나중에, 과학보다는 먼저 봤을 때, 가장 나중에 본 과목은 어떤 과목입니까?",
        "question_en": "In the midterm, Yeji took four tests: Korean, Mathematics, Social Studies, and Science. If she took Korean language before math, and social studies later than math but before science, which subject did she take last?",
        "answer_ko": "과학",
        "answer_en": "Science",
        "solution_abst_ko": "[OP_LIST_SOL] 국어 수학 사회 과학 [OP_LIST_EOL] [OP_LIST_SOL] 국어 수학 > 사회 수학 < 사회 과학 > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Korean Mathematics Social Science [OP_LIST_EOL] [OP_LIST_SOL] Korean Mathematics > Social Mathematics < Social Science > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '국어'\nvar_b = '수학'\nvar_c = '사회'\nvar_d = '과학'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '국어'\nvar_f = '수학'\nvar_g = '>'\nvar_h = '사회'\nvar_i = '수학'\nvar_j = '<'\nvar_k = '사회'\nvar_l = '과학'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)",
        "solution_code_en": "var_a = 'Korean'\nvar_b = 'Mathematics'\nvar_c = 'Social'\nvar_d = 'Science'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'Korean'\nvar_f = 'Mathematics'\nvar_g = '>'\nvar_h = 'Social'\nvar_i = 'Mathematics'\nvar_j = '<'\nvar_k = 'Social'\nvar_l = 'Science'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)"
    },
    "3565": {
        "category": "Geometry",
        "question_ko": "원의 모양을 하고 있는 어느 연못의 지름이 14 미터(m)입니다. 연못의 반지름은 몇 미터(m) 인가요?",
        "question_en": "A pond in the shape of a circle has a diameter of 14 meters (m). What is the radius of the pond in meters (m)?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "14 2 [OP_DIV]",
        "solution_abst_en": "14 2 [OP_DIV]",
        "solution_code_ko": "var_a = 14\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 14\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "3566": {
        "category": "Correspondence",
        "question_ko": "어떤 수는 35보다 크고, 70보다 작습니다. 어떤 수를 6으로 나누면, 나머지가 3입니다. 어떤 수를 8로 나누면, 나머지가 1입니다. 어떤 수를 구하시오.",
        "question_en": "A number is greater than 35 and less than 70. When a number is divided by 6, the remainder is 3. When a number is divided by 8, the remainder is 1. Find a number.",
        "answer_ko": "57",
        "answer_en": "57",
        "solution_abst_ko": "35 70 1 [OP_SUB] 1 [OP_LIST_ARANGE] 6 3 [OP_LIST_DIVIDE_AND_REMAIN] 8 1 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "35 70 1 [OP_SUB] 1 [OP_LIST_ARANGE] 6 3 [OP_LIST_DIVIDE_AND_REMAIN] 8 1 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 35\nvar_b = 70\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nvar_f = 6\nvar_g = 3\nlist_b = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_a:\n    i = int(i)\n    if i%var_f == var_g:\n        list_b.append(i)\nvar_h = 8\nvar_i = 1\nlist_c = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_b:\n    i = int(i)\n    if i%var_h == var_i:\n        list_c.append(i)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(int(var_k))",
        "solution_code_en": "var_a = 35\nvar_b = 70\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nvar_f = 6\nvar_g = 3\nlist_b = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_a:\n    i = int(i)\n    if i%var_f == var_g:\n        list_b.append(i)\nvar_h = 8\nvar_i = 1\nlist_c = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_b:\n    i = int(i)\n    if i%var_h == var_i:\n        list_c.append(i)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(int(var_k))"
    },
    "3567": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중에서 2번째로 큰 수와 2번째로 작은 수의 차는 얼마입니까?",
        "question_en": "There are three numbers 10, 11, and 12. What is the difference between the 2nd largest number and the 2nd smallest number?",
        "answer_ko": "0",
        "answer_en": "0",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e - var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e - var_g\nprint(int(var_h))"
    },
    "3568": {
        "category": "Comparison",
        "question_ko": "행도네 반 학생 7명의 몸무게가 35.1킬로그램(㎏), 41.3킬로그램(㎏), 38.6킬로그램(㎏), 40.2킬로그램(㎏), 39.0킬로그램(㎏), 43.7킬로그램(㎏), 38.4킬로그램(㎏)일 때 39킬로그램(㎏) 이상인 학생은 몇 명입니까?",
        "question_en": "The weight of 7 students in Haengdo's class was each 35.1 kilograms (kg), 41.3 kilograms (kg), 38.6 kilograms (kg), 40.2 kilograms (kg), 39.0 kilograms (kg), 43.7 kilograms (kg), 38.4 kilograms (kg). How many students are over 39 kilograms (kg) at the time?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 35.1 41.3 38.6 40.2 39.0 43.7 38.4 [OP_LIST_EOL] 39 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 35.1 41.3 38.6 40.2 39.0 43.7 38.4 [OP_LIST_EOL] 39 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 35.1\nvar_b = 41.3\nvar_c = 38.6\nvar_d = 40.2\nvar_e = 39\nvar_f = 43.7\nvar_g = 38.4\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h = 39\nlist_b = []\nfor i in list_a:\n    if i >= var_h:\n        list_b.append(i)\nvar_i = len(list_b)\nprint(int(var_i))",
        "solution_code_en": "var_a = 35.1\nvar_b = 41.3\nvar_c = 38.6\nvar_d = 40.2\nvar_e = 39\nvar_f = 43.7\nvar_g = 38.4\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h = 39\nlist_b = []\nfor i in list_a:\n    if i >= var_h:\n        list_b.append(i)\nvar_i = len(list_b)\nprint(int(var_i))"
    },
    "3569": {
        "category": "Correspondence",
        "question_ko": "24에 어떤 수를 나누려고 합니다. 잘못하여 40에 어떤 수를 더하였더니 결과는 52가 되었습니다. 바르게 계산한 결과는 얼마일까요?",
        "question_en": "You want to divide 24 by a certain number. However, you mistakenly added some number to 40, and the result was 52. What is the correct calculation result?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "24 52 40 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "24 52 40 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 24\nvar_b = 52\nvar_c = 40\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 24\nvar_b = 52\nvar_c = 40\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "3570": {
        "category": "Possibility",
        "question_ko": "3, 1, 7, 4 가 적힌 4장의 카드를 한 번씩 모두 사용하여 만들 수 있는 가장 큰 소수 두 자리 수와 가장 작은 소수 세 자리 수의 합을 구하시오",
        "question_en": "Find the sum of the largest two-digit decimal number and the smallest three-digit decimal number that can be formed by using all four cards with the numbers 3, 1, 7, and 4 only once.",
        "answer_ko": "75.66",
        "answer_en": "75.66",
        "solution_abst_ko": "[OP_LIST_SOL] 3 1 7 4 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 10 [OP_LIST_POP] [OP_LIST_LEN] 2 [OP_SUB] [OP_POW] [OP_DIV] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 10 [OP_LIST_POP] [OP_LIST_LEN] 1 [OP_SUB] [OP_POW] [OP_DIV] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 3 1 7 4 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 10 [OP_LIST_POP] [OP_LIST_LEN] 2 [OP_SUB] [OP_POW] [OP_DIV] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 10 [OP_LIST_POP] [OP_LIST_LEN] 1 [OP_SUB] [OP_POW] [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 1\nvar_c = 7\nvar_d = 4\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 10\nvar_i = len(list_a)\nvar_j = 2\nvar_k = var_i - var_j\nvar_l = var_h ** var_k\nvar_m = var_g / var_l\nvar_n = 4\nlist_d = [str(i) for i in list_a]\nlist_d = list(itertools.permutations(list_d, var_n))\nlist_d = [''.join(num_list) for num_list in list_d]\nlist_d = [str_num for str_num in list_d if str_num[0] != '0']\nlist_d = [float(i) for i in list_d]\nvar_o = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_p = list_e[var_o-1]\nvar_q = 10\nvar_r = len(list_a)\nvar_s = 1\nvar_t = var_r - var_s\nvar_u = var_q ** var_t\nvar_v = var_p / var_u\nvar_w = var_m + var_v\nprint('{:.2f}'.format(round(var_w+1e-10,2)))",
        "solution_code_en": "var_a = 3\nvar_b = 1\nvar_c = 7\nvar_d = 4\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 10\nvar_i = len(list_a)\nvar_j = 2\nvar_k = var_i - var_j\nvar_l = var_h ** var_k\nvar_m = var_g / var_l\nvar_n = 4\nlist_d = [str(i) for i in list_a]\nlist_d = list(itertools.permutations(list_d, var_n))\nlist_d = [''.join(num_list) for num_list in list_d]\nlist_d = [str_num for str_num in list_d if str_num[0] != '0']\nlist_d = [float(i) for i in list_d]\nvar_o = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_p = list_e[var_o-1]\nvar_q = 10\nvar_r = len(list_a)\nvar_s = 1\nvar_t = var_r - var_s\nvar_u = var_q ** var_t\nvar_v = var_p / var_u\nvar_w = var_m + var_v\nprint('{:.2f}'.format(round(var_w+1e-10,2)))"
    },
    "3571": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 30을 더했더니 결과로 55를 얻었습니다. 어떤 수에서 23을 뺀 값은?",
        "question_en": "When you add 30 to a number, you get 55. What is the value of the number subtracted by 23?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "55 30 [OP_SUB] 23 [OP_SUB]",
        "solution_abst_en": "55 30 [OP_SUB] 23 [OP_SUB]",
        "solution_code_ko": "var_a = 55\nvar_b = 30\nvar_c = var_a - var_b\nvar_d = 23\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 55\nvar_b = 30\nvar_c = var_a - var_b\nvar_d = 23\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3572": {
        "category": "Arithmetic calculation",
        "question_ko": "학교에 농구공이 32개 있습니다. 농구공은 배구공보다 5개 많고, 축구공보다 3개 적습니다. 학교에 있는 농구공, 배구공, 축구공은 모두 몇 개입니까?",
        "question_en": "There are 32 basketballs in the school. The number of basketballs is 5 more than the volleyballs and 3 less than the number of soccer balls. How many basketballs, volleyballs and soccer balls are there in total in the school?",
        "answer_ko": "94",
        "answer_en": "94",
        "solution_abst_ko": "32 32 5 [OP_SUB] [OP_ADD] 32 3 [OP_ADD] [OP_ADD]",
        "solution_abst_en": "32 32 5 [OP_SUB] [OP_ADD] 32 3 [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 32\nvar_b = 32\nvar_c = 5\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 32\nvar_g = 3\nvar_h = var_f + var_g\nvar_i = var_e + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 32\nvar_b = 32\nvar_c = 5\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 32\nvar_g = 3\nvar_h = var_f + var_g\nvar_i = var_e + var_h\nprint(int(var_i))"
    },
    "3573": {
        "category": "Geometry",
        "question_ko": "가로가 120센티미터(㎝), 세로가 96센티미터(㎝)인 벽에 정사각형 모양의 타일을 붙일 때 남는 부분이 없이, 되도록 큰 타일을 붙이려면 타일의 한 변의 길이는 몇 센티미터(㎝)이어야 하는가?",
        "question_en": "When a square tile is attached to a wall measuring 120 centimeters (cm) wide and 96 centimeters (cm) long, how many centimeters (cm) should one side of the tile be in length to attach the largest tile to the wall without any extra space?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "120 96 [OP_GCD]",
        "solution_abst_en": "120 96 [OP_GCD]",
        "solution_code_ko": "var_a = 120\nvar_b = 96\nvar_c = math.gcd(int(var_b), int(var_a))\nprint(int(var_c))",
        "solution_code_en": "var_a = 120\nvar_b = 96\nvar_c = math.gcd(int(var_b), int(var_a))\nprint(int(var_c))"
    },
    "3574": {
        "category": "Correspondence",
        "question_ko": "앞면은 노란색 뒷면은 초록색인 종이가 바닥에 놓여 있다. 이때 학생들이 노란색이 보이는 종이 16개를 뒤집어 초록색이 보이도록 뒤집었다고 한다. 이때 초록색 종이가 노란색 종이보다 64개 많았다면 뒤집기전에는 차이가 얼마였는지 구하시오.",
        "question_en": "There are some sheets of paper, yellow on the front and green on the back on the floor. Students flipped 16 papers that look yellow so that they look green. If there are 64 more green papers than yellow papers, what was the difference before flipping?",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "64 16 [OP_SUB] 16 [OP_SUB]",
        "solution_abst_en": "64 16 [OP_SUB] 16 [OP_SUB]",
        "solution_code_ko": "var_a = 64\nvar_b = 16\nvar_c = var_a - var_b\nvar_d = 16\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 64\nvar_b = 16\nvar_c = var_a - var_b\nvar_d = 16\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3575": {
        "category": "Correspondence",
        "question_ko": "진우가 가진 구슬의 개수는 성현이가 가진 구슬의 개수에 2/3이고, 철수는 72개의 구슬을 가지고 있다. 진우와 철수가 가진 구슬의 합이 성현이가 가진 구슬 개수에 2배일때 진우가 가진 구슬의 개수를 구하시오.",
        "question_en": "The number of marbles Jinwoo has is 2/3 of the number of marbles Seonghyeon has, and Cheolsu has 72 marbles. Find the number of marbles Jinwoo has when the sum of marbles Jinwoo and Cheolsu have is twice the number of marbles Seonghyeon has.",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "72 2 1 2/3 [OP_DIV] [OP_MUL] 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "72 2 1 2/3 [OP_DIV] [OP_MUL] 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 72\nvar_b = 2\nvar_c = 1\nvar_d = 0.6666666666666666\nvar_e = var_c / var_d\nvar_f = var_b * var_e\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_a / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 72\nvar_b = 2\nvar_c = 1\nvar_d = 0.6666666666666666\nvar_e = var_c / var_d\nvar_f = var_b * var_e\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_a / var_h\nprint(int(var_i))"
    },
    "3576": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 6 센티미터(㎝)인 정사각형의 넓이를 구하시오.",
        "question_en": "Find the area of a square with a side of 6 centimeters (cm).",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "6 2 [OP_POW]",
        "solution_abst_en": "6 2 [OP_POW]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = var_a ** var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = var_a ** var_b\nprint(int(var_c))"
    },
    "3577": {
        "category": "Correspondence",
        "question_ko": "14AB는 9의 배수입니다. A, B가 서로 다른 숫자일 때, 가능한 수는 몇 개입니까?",
        "question_en": "14AB is a multiple of 9. If A and B are different numbers, how many possible numbers are there?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "14AB [OP_GEN_POSSIBLE_LIST] 9 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "14AB [OP_GEN_POSSIBLE_LIST] 9 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '14AB'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 9\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))",
        "solution_code_en": "var_a = '14AB'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 9\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))"
    },
    "3578": {
        "category": "Arithmetic calculation",
        "question_ko": "민영이는 공책을 17권 가지고 있었습니다. 그중에서 유정이에게 몇 권을 주었더니 8권이 남았습니다. 유정이에게 준 공책은 몇 권입니까?",
        "question_en": "Minyoung had 17 notebooks. Among them, she gave some to Yujeong, and there were 8 left. How many notebooks did Minyoung give Yujeong?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "17 8 [OP_SUB]",
        "solution_abst_en": "17 8 [OP_SUB]",
        "solution_code_ko": "var_a = 17\nvar_b = 8\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 17\nvar_b = 8\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "3579": {
        "category": "Correspondence",
        "question_ko": "100개의 사탕을 현지네 반 학생들에게 같은 개수로 나누어졌더니 사탕이 하나도 남지 않았을 때, 현지네 반 학생 수로 가능한 수는 몇 개인지 구하시오. (단, 현지네 반에 현지 말고 다른 학생도 있으며, 반 학생 수가 50명이 넘지 않습니다.)",
        "question_en": "If 100 candies are divided into the same amount among Hyunji's classmates and there are no candies left, how many numbers are possible to become the number of Hyunji' classmates? (However, there are students other than Hyunji in Hyunji's class, and the number of students in the class does not exceed 50.)",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "100 [OP_LIST_GET_DIVISOR] 50 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN] 1 [OP_SUB]",
        "solution_abst_en": "100 [OP_LIST_GET_DIVISOR] 50 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 100\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 50\nlist_b = []\nfor i in list_a:\n    if i <= var_b:\n        list_b.append(i)\nvar_c = len(list_b)\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 100\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 50\nlist_b = []\nfor i in list_a:\n    if i <= var_b:\n        list_b.append(i)\nvar_c = len(list_b)\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3580": {
        "category": "Comparison",
        "question_ko": "정국이의 차가 어느 주차장의 한 줄의 오른쪽에서 5번째, 왼쪽에서 4번째에 놓여 있습니다. 각 줄마다 세워져 있는 자동차의 수는 같고 주차장은 10층 입니다. 주차장에 자동차가 총 1600대가 있을 때, 한 층에는 몇 줄이 있습니까?",
        "question_en": "Jungkook's car is 5th from the right and 4th from the left in a row in a parking lot. The number of cars parked in each row is the same, and the parking lot has 10 floors. If there are a total of 1600 cars in the parking lot, how many rows are there on each floor?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "1600 5 4 [OP_ADD] 1 [OP_SUB] 10 [OP_MUL] [OP_FDIV]",
        "solution_abst_en": "1600 5 4 [OP_ADD] 1 [OP_SUB] 10 [OP_MUL] [OP_FDIV]",
        "solution_code_ko": "var_a = 1600\nvar_b = 5\nvar_c = 4\nvar_d = var_b + var_c\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 10\nvar_h = var_f * var_g\nvar_i = var_a // var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1600\nvar_b = 5\nvar_c = 4\nvar_d = var_b + var_c\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 10\nvar_h = var_f * var_g\nvar_i = var_a // var_h\nprint(int(var_i))"
    },
    "3581": {
        "category": "Geometry",
        "question_ko": "꼭짓점이 3개이고 2개의 꼭짓점 사이의 거리가 7센티미터(㎝)로 동일한 도형의 둘레를 구하시오.",
        "question_en": "Find the perimeter of the figure with 3 vertices, and the distance between the 2 vertices is the same as 7 cm (cm).",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "7 3 [OP_MUL]",
        "solution_abst_en": "7 3 [OP_MUL]",
        "solution_code_ko": "var_a = 7\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 7\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "3582": {
        "category": "Comparison",
        "question_ko": "지민이는 주스를 0.7리터(L) 마셨습니다. 은지는 지민이보다 1/10리터(L) 더 적게 마셨습니다. 윤기는 4/5리터(L) 마셨고, 유나는 지민이보다 0.2리터(L) 더 많이 마셨습니다. 주스를 가장 많이 마신 사람은 누구입니까?",
        "question_en": "Jimin drank 0.7 liters (L) of juice. Eunji drank 1/10 liters (L) less than Jimin. Yoongi drank 4/5 liters (L), and Yuna drank 0.2 liters (L) more than Jimin. Who drank the most juice?",
        "answer_ko": "유나",
        "answer_en": "Yuna",
        "solution_abst_ko": "[OP_LIST_SOL] 지민 은지 윤기 유나 [OP_LIST_EOL] [OP_LIST_SOL] 0.7 0.7 1/10 [OP_SUB] 4/5 0.7 0.2 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jimin Eunji Yoongi Yuna [OP_LIST_EOL] [OP_LIST_SOL] 0.7 0.7 1/10 [OP_SUB] 4/5 0.7 0.2 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '지민'\nvar_b = '은지'\nvar_c = '윤기'\nvar_d = '유나'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.7\nvar_f = 0.7\nvar_g = 0.1\nvar_h = var_f - var_g\nvar_i = 0.8\nvar_j = 0.7\nvar_k = 0.2\nvar_l = var_j + var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'Jimin'\nvar_b = 'Eunji'\nvar_c = 'Yoongi'\nvar_d = 'Yuna'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.7\nvar_f = 0.7\nvar_g = 0.1\nvar_h = var_f - var_g\nvar_i = 0.8\nvar_j = 0.7\nvar_k = 0.2\nvar_l = var_j + var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "3583": {
        "category": "Comparison",
        "question_ko": "유정, 태형, 석진 세 사람이 구슬을 가지고 있습니다. 태형이는 유정이보다 구슬을 더 많이 가지고 있습니다. 석진이는 유정이보다 구슬을 더 많이 가지고 있습니다. 태형이는 석진이보다 구슬을 더 많이 가지고 있습니다. 구슬을 가장 많이 가지고 있는 사람은 누구입니까?",
        "question_en": "Yoojeong, Taehyung, and Seokjin have marbles. Taehyung has more marbles than Yoojeong. Seokjin has more marbles than Yoojeong. Taehyung has more marbles than Seokjin. Who has the most marbles?",
        "answer_ko": "태형",
        "answer_en": "Taehyung",
        "solution_abst_ko": "[OP_LIST_SOL] 유정 태형 석진 [OP_LIST_EOL] [OP_LIST_SOL] 유정 태형 < 유정 석진 < 석진 태형 < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoojeong Taehyung Seokjin [OP_LIST_EOL] [OP_LIST_SOL] Yoojeong Taehyung < Yoojeong Seokjin < Seokjin Taehyung < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '유정'\nvar_b = '태형'\nvar_c = '석진'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '유정'\nvar_e = '태형'\nvar_f = '<'\nvar_g = '유정'\nvar_h = '석진'\nvar_i = '<'\nvar_j = '석진'\nvar_k = '태형'\nvar_l = '<'\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_m = 1\nvar_n = list_c[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'Yoojeong'\nvar_b = 'Taehyung'\nvar_c = 'Seokjin'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'Yoojeong'\nvar_e = 'Taehyung'\nvar_f = '<'\nvar_g = 'Yoojeong'\nvar_h = 'Seokjin'\nvar_i = '<'\nvar_j = 'Seokjin'\nvar_k = 'Taehyung'\nvar_l = '<'\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_m = 1\nvar_n = list_c[var_m-1]\nprint(var_n)"
    },
    "3584": {
        "category": "Comparison",
        "question_ko": "지성은 우유 9/25리터(L), 영표는 0.41리터(L)를 마셨습니다. 누가 우유를 더 많이 마셨습니까?",
        "question_en": "Ji-sung drank 9/25 liters (L) of milk, and Young-pyo drank 0.41 liters (L). Who drank more milk?",
        "answer_ko": "영표",
        "answer_en": "Young-pyo",
        "solution_abst_ko": "[OP_LIST_SOL] 지성 영표 [OP_LIST_EOL] [OP_LIST_SOL] 9 25 [OP_DIV] 0.41 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Ji-sung Young-pyo [OP_LIST_EOL] [OP_LIST_SOL] 9 25 [OP_DIV] 0.41 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '지성'\nvar_b = '영표'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 9\nvar_d = 25\nvar_e = var_c / var_d\nvar_f = 0.41\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Ji-sung'\nvar_b = 'Young-pyo'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 9\nvar_d = 25\nvar_e = var_c / var_d\nvar_f = 0.41\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "3585": {
        "category": "Geometry",
        "question_ko": "직육면체 모양의 통이 있습니다. 밑면의 두 변의 길이가 각각 6미터(m) 40센티미터(㎝), 9미터(m)이며, 높이가 5미터(m) 20센티미터(㎝)입니다. 콩이 가득 들어 있을 때, 부피가 1세제곱미터(㎥)인 통 여러 개에 모두 나누어 담으려고 합니다. 통은 적어도 몇 개 필요한지 구해보시오.",
        "question_en": "There is a barrel in the shape of a cuboid. The lengths of the two sides of the base are 6 meters (m) 40 centimeters (cm) and 9 meters (m), respectively, and the height is 5 meters (m) 20 centimeters (cm). This barrel is full of beans, but you want to divide them all into several barrels whose volume is 1 cubic meter (m3). Find at least how many barrels you need.",
        "answer_ko": "300",
        "answer_en": "300",
        "solution_abst_ko": "6 40 100 [OP_DIV] [OP_ADD] 9 [OP_MUL] 5 20 100 [OP_DIV] [OP_ADD] [OP_MUL] 1 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "6 40 100 [OP_DIV] [OP_ADD] 9 [OP_MUL] 5 20 100 [OP_DIV] [OP_ADD] [OP_MUL] 1 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 6\nvar_b = 40\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 9\nvar_g = var_e * var_f\nvar_h = 5\nvar_i = 20\nvar_j = 100\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_g * var_l\nvar_n = 1\nvar_o = var_m / var_n\nvar_p = 1\nvar_q=int(((var_o+9*10**(var_p-2))//(10**(var_p-1)))*10**(var_p-1))\n\nprint(int(var_q))",
        "solution_code_en": "var_a = 6\nvar_b = 40\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 9\nvar_g = var_e * var_f\nvar_h = 5\nvar_i = 20\nvar_j = 100\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_g * var_l\nvar_n = 1\nvar_o = var_m / var_n\nvar_p = 1\nvar_q=int(((var_o+9*10**(var_p-2))//(10**(var_p-1)))*10**(var_p-1))\n\nprint(int(var_q))"
    },
    "3586": {
        "category": "Arithmetic calculation",
        "question_ko": "직사각형의 넓이는 가로와 세로를 곱하여 구한다. 한 변의 길이가 12센티미터(㎝)인 정사각형을, 가로를 3센티미터(㎝)늘리고 세로를 A 센티미터(㎝) 줄여서 만든 직사각형의 넓이가 120제곱센티미터(㎠)일 때, A의 값은 얼마인가",
        "question_en": "The area of a rectangle is found by multiplying its width by its length. What is the value of A if the surface area of a rectangle is 120 square centimeters  which is made by increasing the width by 3 centimeters (cm) and reducing the length by A centimeters (cm)  of a square whose side length is 12 centimeters (cm)?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "12 120 12 3 [OP_ADD] [OP_DIV] [OP_SUB]",
        "solution_abst_en": "12 120 12 3 [OP_ADD] [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 12\nvar_b = 120\nvar_c = 12\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = var_b / var_e\nvar_g = var_a - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 12\nvar_b = 120\nvar_c = 12\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = var_b / var_e\nvar_g = var_a - var_f\nprint(int(var_g))"
    },
    "3587": {
        "category": "Comparison",
        "question_ko": "2개의 상자 (가)와 (나)가 배달왔습니다. 유정이는 두 상자 중 작은 상자를 들고 가려고 합니다. (나) 상자가 (가) 상자보다 작았다면, 유정이가 들고가야 하는 상자는 무엇입니까?",
        "question_en": "Two boxes (a) and (b) have been delivered. Yoojung is going to take the smaller of the two boxes. If (b) box is smaller than (a) box, which box should Yoojung carry?",
        "answer_ko": "(나)",
        "answer_en": "(b)",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) [OP_LIST_EOL] [OP_LIST_SOL] (가) (나) > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (a) (b) [OP_LIST_EOL] [OP_LIST_SOL] (a) (b) > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = '(가)'\nvar_d = '(나)'\nvar_e = '>'\nlist_b= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_f = len(list_c)\nvar_g = list_c[var_f-1]\nprint(var_g)",
        "solution_code_en": "var_a = '(a)'\nvar_b = '(b)'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = '(a)'\nvar_d = '(b)'\nvar_e = '>'\nlist_b= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_f = len(list_c)\nvar_g = list_c[var_f-1]\nprint(var_g)"
    },
    "3588": {
        "category": "Geometry",
        "question_ko": "밑에 놓인 면의 둘레가 32센티미터(㎝)이고, 높이가 9센티미터(㎝)인 직육면체 박스중에 가로, 세로 높이가 모두 1센티미터(㎝)인 초콜릿이 들어갈 수 있는 최대 개수는 몇 개인지 구하시오.",
        "question_en": "Find the maximum number of chocolates that can fit in a rectangular box with a perimeter of 32 centimeters (cm) and a height of 9 centimeters (cm).",
        "answer_ko": "576",
        "answer_en": "576",
        "solution_abst_ko": "32 4 [OP_DIV] 2 [OP_POW] 9 [OP_MUL]",
        "solution_abst_en": "32 4 [OP_DIV] 2 [OP_POW] 9 [OP_MUL]",
        "solution_code_ko": "var_a = 32\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 9\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 32\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 9\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "3589": {
        "category": "Possibility",
        "question_ko": "지안이와 신영이가 가위바위보를 할 때, 지안이가 이기는 경우의 수를 구하시오. (단, 무승부도 나올 수 있다.)",
        "question_en": "When Ji-An and Shin-Young play rock-paper-scissors, find the number of cases in which Ji-An wins. (However, a draw may also come out.)",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "3",
        "solution_abst_en": "3",
        "solution_code_ko": "var_a = 3\nprint(int(var_a))",
        "solution_code_en": "var_a = 3\nprint(int(var_a))"
    },
    "3590": {
        "category": "Arithmetic calculation",
        "question_ko": "국어와 수학의 평균 점수는 88점입니다. 영어 시험을 본 후 평균 점수가 90점입니다. 영어 점수는 몇 점 입니까?",
        "question_en": "The average score for Korean and Mathematics is 88. After taking the English test, the average score became 90 points. How much is the English score?",
        "answer_ko": "94",
        "answer_en": "94",
        "solution_abst_ko": "90 3 [OP_MUL] 88 2 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "90 3 [OP_MUL] 88 2 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 90\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 88\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 90\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 88\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "3591": {
        "category": "Correspondence",
        "question_ko": "23에 37을 곱한 값에 16을 더한 값이 얼마인지 구하시오.",
        "question_en": "What is 23 multiplied by 37 plus 16?",
        "answer_ko": "867",
        "answer_en": "867",
        "solution_abst_ko": "23 37 [OP_MUL] 16 [OP_ADD]",
        "solution_abst_en": "23 37 [OP_MUL] 16 [OP_ADD]",
        "solution_code_ko": "var_a = 23\nvar_b = 37\nvar_c = var_a * var_b\nvar_d = 16\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 23\nvar_b = 37\nvar_c = var_a * var_b\nvar_d = 16\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3592": {
        "category": "Possibility",
        "question_ko": "서로 다른 수 1, 3, 5, 8 중 2개를 뽑아서 두 자리 수를 만들려고 합니다. 이 두 자리 수에 어떤 수를 더하면 88이 되고, 두 자리 수는 만들 수 있는 가장 작은 수입니다. 한번 뽑은 수는 중복해서 뽑을 수 없다면, 어떤 수는 무엇입니까?",
        "question_en": "You want to form a two-digit number by picking two numbers from 1, 3, 5, and 8. If you add a certain number to this two-digit number, you get 88, and the two-digit number is the smallest number you can make. If you cannot pick the number twice, what is that certain number?",
        "answer_ko": "75",
        "answer_en": "75",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 5 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 88 [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 5 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 88 [OP_SUB]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 5\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = 88\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 5\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = 88\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "3593": {
        "category": "Geometry",
        "question_ko": "어떤 사다리꼴의 아랫변이 윗변보다 3.4센티미터(㎝) 더 짧고, 높이가 5.2센티미터(㎝)이라고 합니다. 넓이가 100.62제곱센티미터(㎠)일 때, 아랫변의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "Suppose that there is a trapezoid whose lower side is 3.4 centimeters (cm) shorter than the upper side and has a height of 5.2 centimeters (cm). If the area is 100.62 square centimeters (cm2), how many centimeters (cm) is the length of the lower side?",
        "answer_ko": "17.65",
        "answer_en": "17.65",
        "solution_abst_ko": "100.62 2 [OP_MUL] 5.2 [OP_DIV] 3.4 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "100.62 2 [OP_MUL] 5.2 [OP_DIV] 3.4 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 100.62\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 5.2\nvar_e = var_c / var_d\nvar_f = 3.4\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 100.62\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 5.2\nvar_e = var_c / var_d\nvar_f = 3.4\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "3594": {
        "category": "Possibility",
        "question_ko": "서로 다른 종류의 과일 5개를 3개의 접시에 담으려고 합니다. 이때, 과일이 담기지 않는 접시가 있을 수 있습니다. 과일을 접시에 담는 경우는 모두 몇 가지입니까?",
        "question_en": "You are going to put 5 different types of fruit on 3 plates. At this time, there may be a plate that does not contain fruit. How many number of cases are there for you to put fruit on the plates?",
        "answer_ko": "243",
        "answer_en": "243",
        "solution_abst_ko": "3 5 [OP_POW]",
        "solution_abst_en": "3 5 [OP_POW]",
        "solution_code_ko": "var_a = 3\nvar_b = 5\nvar_c = var_a ** var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 5\nvar_c = var_a ** var_b\nprint(int(var_c))"
    },
    "3595": {
        "category": "Comparison",
        "question_ko": "지석 배낭의 무게는 1.49리터(L)이고 미호 배낭의 무게는 9/20리터(L)입니다. 누구의 배낭이 더 가볍습니까?",
        "question_en": "The weight of Jisuk's backpack is 1.49 kilograms (kg) and the weight of Miho's backpack is 9/20 kilograms (kg). Whose backpack is lighter?",
        "answer_ko": "미호",
        "answer_en": "Miho",
        "solution_abst_ko": "[OP_LIST_SOL] 지석 미호 [OP_LIST_EOL] [OP_LIST_SOL] 1.49 9/20 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jisuk Miho [OP_LIST_EOL] [OP_LIST_SOL] 1.49 9/20 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '지석'\nvar_b = '미호'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.49\nvar_d = 0.45\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Jisuk'\nvar_b = 'Miho'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.49\nvar_d = 0.45\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "3596": {
        "category": "Possibility",
        "question_ko": "서로 다른 숫자를 2개 뽑아서 두 자리 수를 만드려고 합니다. 9, 4, 2, 5 중에서 숫자를 뽑을 때 나올 수 있는 가장 큰 수에서 가장 작은 수를 빼면 얼마가 됩니까?",
        "question_en": "I'm trying to make a two-digit number by picking two different numbers. When you draw a number from 9, 4, 2, or 5, what is the difference between the smallest number and the largest possible number?",
        "answer_ko": "71",
        "answer_en": "71",
        "solution_abst_ko": "[OP_LIST_SOL] 9 4 2 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 9 4 2 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 9\nvar_b = 4\nvar_c = 2\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 9\nvar_b = 4\nvar_c = 2\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))"
    },
    "3597": {
        "category": "Arithmetic calculation",
        "question_ko": "비둘기의 총 마리 수는 21마리입니다. 처음에 있었던 비둘기의 수가 15마리라고 할 때 추가로 날아온 비둘기는 몇 마리입니까?",
        "question_en": "The total number of pigeons is 21. If the initial number of pigeons was 15, how many more pigeons increased?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "21 15 [OP_SUB]",
        "solution_abst_en": "21 15 [OP_SUB]",
        "solution_code_ko": "var_a = 21\nvar_b = 15\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 21\nvar_b = 15\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "3598": {
        "category": "Comparison",
        "question_ko": "백의 자리 숫자가 2, 십의 자리 숫자가 5인 세 자리 수 중에서 256보다 큰 수는 모두 몇 개인지 구하시오.",
        "question_en": "How many three-digit numbers with 2 in the hundreds digit and 5 in the tens digit are greater than 256?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 2 5 A [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 256 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 2 5 A [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 256 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 2\nvar_b = 5\nvar_c = 'A'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nans_dict = dict()\nvar_d = str(var_d)\nlist_b = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_d) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_b.append(new_elem)\nvar_e = 256\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 2\nvar_b = 5\nvar_c = 'A'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nans_dict = dict()\nvar_d = str(var_d)\nlist_b = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_d) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_b.append(new_elem)\nvar_e = 256\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "3599": {
        "category": "Arithmetic calculation",
        "question_ko": "전봇대에 앉아있던 비둘기가 3마리 날아갔습니다. 처음에 전봇대에 앉아있던 비둘기가 8마리일때, 남아있는 비둘기는 몇 마리일까요?",
        "question_en": "Three pigeons sitting on a telephone pole flew away. When there were 8 pigeons sitting on the telephone pole at first, how many pigeons are left?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "8 3 [OP_SUB]",
        "solution_abst_en": "8 3 [OP_SUB]",
        "solution_code_ko": "var_a = 8\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 8\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "3600": {
        "category": "Arithmetic calculation",
        "question_ko": "주차장에 자동차가 25대 있었습니다. 자동차 18대가 나간 후, 다시 12대가 들어왔습니다. 주차장에 자동차는 몇 대 줄었습니까?",
        "question_en": "There were 25 cars in the parking lot. After 18 cars went out, another 12 came in. How many cars fell in number in the parking lot?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "25 25 18 [OP_SUB] 12 [OP_ADD] [OP_SUB]",
        "solution_abst_en": "25 25 18 [OP_SUB] 12 [OP_ADD] [OP_SUB]",
        "solution_code_ko": "var_a = 25\nvar_b = 25\nvar_c = 18\nvar_d = var_b - var_c\nvar_e = 12\nvar_f = var_d + var_e\nvar_g = var_a - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 25\nvar_b = 25\nvar_c = 18\nvar_d = var_b - var_c\nvar_e = 12\nvar_f = var_d + var_e\nvar_g = var_a - var_f\nprint(int(var_g))"
    },
    "3601": {
        "category": "Comparison",
        "question_ko": "정국이는 6에서 3을 곱한 수를 모았고, 윤기는 4, 유나는 5를 모았습니다. 누가 가장 큰 수를 모았나요?",
        "question_en": "Find the one who got the biggest number: Jungkook with 6 times 3, Yoongi with 4, and Yuna with 5.",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 윤기 유나 [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_MUL] 4 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Yoongi Yuna [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_MUL] 4 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '윤기'\nvar_c = '유나'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 6\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = 4\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Yoongi'\nvar_c = 'Yuna'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 6\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = 4\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "3602": {
        "category": "Geometry",
        "question_ko": "가로가 15㎝, 세로가 20㎝인 직육면체 모양의 어항에 10센티미터(㎝) 높이만큼 물이 담겨 있습니다. 돌덩이 1개를 물에 완전히 잠기게 넣고 보니 물의 높이가 15㎝까지 올라갔습니다. 이 돌덩이의 부피는 몇 세제곱센티미터입니까?",
        "question_en": "A cuboid-shaped fishbowl measuring 15 cm (cm) wide and 20 cm (cm) long contains water 10 cm (cm) high. When one stone was completely submerged in the water, the water level rose to 15 cm (cm). What is the volume in cubic centimeters (cm3) of this stone?",
        "answer_ko": "1500",
        "answer_en": "1500",
        "solution_abst_ko": "15 20 [OP_MUL] 15 10 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "15 20 [OP_MUL] 15 10 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 15\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 15\nvar_e = 10\nvar_f = var_d - var_e\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 15\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 15\nvar_e = 10\nvar_f = var_d - var_e\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "3603": {
        "category": "Arithmetic calculation",
        "question_ko": "연속된 자연수 3개를 더했더니 48이 되었다. 이 수들 중 가장 큰 수와 가장 작은 수를 곱하면 얼마인지 구하시오.",
        "question_en": "When you add 3 consecutive natural numbers, you get 48. What is the multiplication of the largest of these numbers and the smallest of these numbers?",
        "answer_ko": "255",
        "answer_en": "255",
        "solution_abst_ko": "48 3 [OP_DIV] 3 2 [OP_FDIV] [OP_ADD] 48 3 [OP_DIV] 3 2 [OP_FDIV] [OP_SUB] [OP_MUL]",
        "solution_abst_en": "48 3 [OP_DIV] 3 2 [OP_FDIV] [OP_ADD] 48 3 [OP_DIV] 3 2 [OP_FDIV] [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 48\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 3\nvar_e = 2\nvar_f = var_d // var_e\nvar_g = var_c + var_f\nvar_h = 48\nvar_i = 3\nvar_j = var_h / var_i\nvar_k = 3\nvar_l = 2\nvar_m = var_k // var_l\nvar_n = var_j - var_m\nvar_o = var_g * var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 48\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 3\nvar_e = 2\nvar_f = var_d // var_e\nvar_g = var_c + var_f\nvar_h = 48\nvar_i = 3\nvar_j = var_h / var_i\nvar_k = 3\nvar_l = 2\nvar_m = var_k // var_l\nvar_n = var_j - var_m\nvar_o = var_g * var_n\nprint(int(var_o))"
    },
    "3604": {
        "category": "Arithmetic calculation",
        "question_ko": "숫자 4, 7, 25 의 곱은 얼마입니까?",
        "question_en": "What is the product of the numbers 4, 7, and 25?",
        "answer_ko": "700",
        "answer_en": "700",
        "solution_abst_ko": "4 7 [OP_MUL] 25 [OP_MUL]",
        "solution_abst_en": "4 7 [OP_MUL] 25 [OP_MUL]",
        "solution_code_ko": "var_a = 4\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 25\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 4\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 25\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "3605": {
        "category": "Geometry",
        "question_ko": "정육면체의 겉넓이가 600제곱센티미터(㎠)입니다. 한 변의 길이를 구하세요.",
        "question_en": "The surface area of a cube is 600 square centimeters (cm2). Find the length of one side.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "600 6 [OP_DIV] 1/2 [OP_POW]",
        "solution_abst_en": "600 6 [OP_DIV] 1/2 [OP_POW]",
        "solution_code_ko": "var_a = 600\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 600\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nprint(int(var_e))"
    },
    "3606": {
        "category": "Geometry",
        "question_ko": "가로가 3+1/4미터(m), 세로가 2+3/4미터(m)인 직사각형 모양의 벽에 한 변의 길이가 25센티미터(㎝)인 정사각형 모양의 타일을 붙이려고 합니다. 이 벽에 붙일 수 있는 타일은 모두 몇 장인지 구하시오.",
        "question_en": "We are going to attach square tiles with a side of 25 centimeters (cm) to a rectangular wall measuring 3+1/4 meters (m) wide and 2+3/4 meters (m) long. How many tiles can you put on this wall?",
        "answer_ko": "143",
        "answer_en": "143",
        "solution_abst_ko": "3 1/4 [OP_ADD] 25 100 [OP_DIV] [OP_FDIV] 2 3/4 [OP_ADD] 25 100 [OP_DIV] [OP_FDIV] [OP_MUL]",
        "solution_abst_en": "3 1/4 [OP_ADD] 25 100 [OP_DIV] [OP_FDIV] 2 3/4 [OP_ADD] 25 100 [OP_DIV] [OP_FDIV] [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 0.25\nvar_c = var_a + var_b\nvar_d = 25\nvar_e = 100\nvar_f = var_d / var_e\nvar_g = var_c // var_f\nvar_h = 2\nvar_i = 0.75\nvar_j = var_h + var_i\nvar_k = 25\nvar_l = 100\nvar_m = var_k / var_l\nvar_n = var_j // var_m\nvar_o = var_g * var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 3\nvar_b = 0.25\nvar_c = var_a + var_b\nvar_d = 25\nvar_e = 100\nvar_f = var_d / var_e\nvar_g = var_c // var_f\nvar_h = 2\nvar_i = 0.75\nvar_j = var_h + var_i\nvar_k = 25\nvar_l = 100\nvar_m = var_k / var_l\nvar_n = var_j // var_m\nvar_o = var_g * var_n\nprint(int(var_o))"
    },
    "3607": {
        "category": "Arithmetic calculation",
        "question_ko": "10.5킬로미터(㎞)의 자전거 코스에서 윤기가 1.5킬로미터(㎞)를 간 후 쉬었고, 3730미터(m)를 또 가면 남은 코스의 길이는 몇 미터(m)입니까?",
        "question_en": "In a 10.5 km bike course, Yoongi took a break after going 1.5 kilometers (km). If he went another 3730 meters (m), how many meters (m) is the length of the remaining course?",
        "answer_ko": "5270",
        "answer_en": "5270",
        "solution_abst_ko": "10.5 1000 [OP_MUL] 1.5 1000 [OP_MUL] [OP_SUB] 3730 [OP_SUB]",
        "solution_abst_en": "10.5 1000 [OP_MUL] 1.5 1000 [OP_MUL] [OP_SUB] 3730 [OP_SUB]",
        "solution_code_ko": "var_a = 10.5\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 1.5\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 3730\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10.5\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 1.5\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 3730\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "3608": {
        "category": "Comparison",
        "question_ko": "과일 바구니에 사과가 3개, 자두가 2개, 복숭아가 5개 있습니다. 현수가 눈을 감고 과일 바구니에서 과일 하나를 무작위로 고를 때 선택될 확률이 가장 높은 과일은 무엇입니까?",
        "question_en": "There are 3 apples, 2 plums, and 5 peaches in the fruit basket. When Hyeonsu closes his eyes and chooses one fruit at random from the fruit basket, which fruit is most likely to be chosen?",
        "answer_ko": "복숭아",
        "answer_en": "peaches",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 자두 복숭아 [OP_LIST_EOL] [OP_LIST_SOL] 3 2 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] apples plums peaches [OP_LIST_EOL] [OP_LIST_SOL] 3 2 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '자두'\nvar_c = '복숭아'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nvar_e = 2\nvar_f = 5\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'apples'\nvar_b = 'plums'\nvar_c = 'peaches'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nvar_e = 2\nvar_f = 5\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "3609": {
        "category": "Arithmetic calculation",
        "question_ko": "서로 다른 세가지 색의 구슬이 있다. 빨간색 구슬과 노란색 구슬 개수의 평균은 26.5이고 파란색 구슬과 노란색 구슬 개수의 평균은 34.5, 빨간색 구슬과 파란색 구슬 개수의 평균은 29이다. 세 구슬 개수의 평균은 얼마인지 구하시오.",
        "question_en": "There are marbles of three different colors. The average number of red and yellow marbles is 26.5, the average number of blue and yellow marbles is 34.5, and the average number of red and blue marbles is 29. What is the average number of the three marbles?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "26.5 34.5 [OP_ADD] 29 [OP_ADD] 3 [OP_DIV]",
        "solution_abst_en": "26.5 34.5 [OP_ADD] 29 [OP_ADD] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 26.5\nvar_b = 34.5\nvar_c = var_a + var_b\nvar_d = 29\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 26.5\nvar_b = 34.5\nvar_c = var_a + var_b\nvar_d = 29\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "3610": {
        "category": "Possibility",
        "question_ko": "공책 7개를 호석이는 누나와 형에게 나누어주려고 합니다. 누나와 형은 각자 적어도 1개의 공책을 받습니다. 공책을 나누어주는 방법은 총 몇 개입니까?",
        "question_en": "Hoseok intends to distribute the 7 notebooks to his older sister and older brother. The older sister and older brother each receive at least one notebook. How many total ways to hand out notebooks?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "7 2 1 [OP_MUL] [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "7 2 1 [OP_MUL] [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 7\nvar_b = 2\nvar_c = 1\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 7\nvar_b = 2\nvar_c = 1\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "3611": {
        "category": "Arithmetic calculation",
        "question_ko": "찹쌀떡 1개를 만드는 데 찹쌀가루가 6.64킬로그램(㎏) 필요합니다. 찹쌀가루 202.66킬로그램(㎏)으로 찹쌀떡을 다 만들고 남은 찹쌀가루는 몇 그램(g)인지 구하시오.",
        "question_en": "It takes 6.64 kg (kg) of glutinous rice flour to make one glutinous rice cake. After making a glutinous rice cake with 202.66 kg (kg) of glutinous rice flour, find how many grams (g) of glutinous rice flour is left.",
        "answer_ko": "3460",
        "answer_en": "3460",
        "solution_abst_ko": "202.66 6.64 [OP_MOD] 1000 [OP_MUL]",
        "solution_abst_en": "202.66 6.64 [OP_MOD] 1000 [OP_MUL]",
        "solution_code_ko": "var_a = 202.66\nvar_b = 6.64\nvar_c = var_a % var_b\nvar_d = 1000\nvar_e = var_c * var_d\nprint(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))",
        "solution_code_en": "var_a = 202.66\nvar_b = 6.64\nvar_c = var_a % var_b\nvar_d = 1000\nvar_e = var_c * var_d\nprint(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))"
    },
    "3612": {
        "category": "Arithmetic calculation",
        "question_ko": "6부터 21까지 자연수의 합을 구하시오",
        "question_en": "Find the sum of the natural numbers from 6 to 21",
        "answer_ko": "216",
        "answer_en": "216",
        "solution_abst_ko": "6 21 1 [OP_LIST_ARANGE] [OP_LIST_SUM]",
        "solution_abst_en": "6 21 1 [OP_LIST_ARANGE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 6\nvar_b = 21\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_a = [float(i) for i in list_a]\nvar_d = sum(list_a)\nprint(int(var_d))",
        "solution_code_en": "var_a = 6\nvar_b = 21\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_a = [float(i) for i in list_a]\nvar_d = sum(list_a)\nprint(int(var_d))"
    },
    "3613": {
        "category": "Correspondence",
        "question_ko": "A78-21B=364라는 식이 성립하려면, B에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "What number must go in B in order to satisfy A78-21B=364?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "A78-21B=364 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A78-21B=364 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A78-21B=364'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A78-21B=364'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "3614": {
        "category": "Arithmetic calculation",
        "question_ko": "1킬로미터(㎞)를 달리는 데 휘발유 0.14리터(L)가 필요한 자동차가 있습니다. 이 자동차로 1시간에 93.6킬로미터(㎞)씩 2시간 30분 동안 달렸습니다. 사용한 휘발유는 모두 몇 리터(L)인지 구하시오.",
        "question_en": "A car needs 0.14 liters (l) of gasoline to travel 1 kilometer (km). This car ran for 2 hours and 30 minutes at 93.6 kilometers (km) per hour. Find how many liters (L) of gasoline were used.",
        "answer_ko": "32.76",
        "answer_en": "32.76",
        "solution_abst_ko": "0.14 93.6 [OP_MUL] 2 30 60 [OP_DIV] [OP_ADD] [OP_MUL]",
        "solution_abst_en": "0.14 93.6 [OP_MUL] 2 30 60 [OP_DIV] [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 0.14\nvar_b = 93.6\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = 30\nvar_f = 60\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = var_c * var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 0.14\nvar_b = 93.6\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = 30\nvar_f = 60\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = var_c * var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "3615": {
        "category": "Possibility",
        "question_ko": "숫자 카드 1, 6, 8를 한 번씩 모두 사용하여 두 번째로 큰 세 자리 수와 세 번째로 큰 세 자리수의 합을 구하시오.",
        "question_en": "Using the number cards 1, 6, and 8 all once, find the sum of the second largest three-digit number and the third largest three-digit number.",
        "answer_ko": "1434",
        "answer_en": "1434",
        "solution_abst_ko": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 3 [OP_LIST_GET] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 3 [OP_LIST_GET] [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 3\nvar_h = list_b[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 3\nvar_h = list_b[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))"
    },
    "3616": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 4센티미터(㎝)인 정사각형 모양의 색종이가 있습니다. 이 색종이의 네 변을 각각 똑같게 둘로 나눈 점들을 이어 마름모 모양을 만들어 잘랐습니다. 이 마름모의 넓이를 구하시오.",
        "question_en": "There is a piece of colored paper in the shape of a square with a side length of 4 centimeters (cm). The four sides of this colored paper were cut into diamond shapes by connecting the two equally divided dots. Find the area of this rhombus.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "4 4 [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "4 4 [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 4\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 4\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "3617": {
        "category": "Correspondence",
        "question_ko": "경연이는 자전거를 타고 전체 경로의 절반을 이동하고 다시 300미터(m)를 이동한 후 버스를 타고 남은 경로의 절반을 이동한 뒤 400미터(m)를 더 갔더니 목적지에 도착했다고 한다. 경연이가 이동한 총 경로는 몇 미터(m)인지 구하시오.",
        "question_en": "Gyeongyeon rides a bicycle for half of the entire route, travels another 300 meters (m), rides a bus to travel half of the remaining route, and then travels another 400 meters (m) before arriving at his destination. Find how many meters (m) is the total path traveled by Gyeongyeon.",
        "answer_ko": "2200",
        "answer_en": "2200",
        "solution_abst_ko": "0 400 [OP_ADD] 1 1/2 [OP_SUB] [OP_DIV] 300 [OP_ADD] 1 1/2 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "0 400 [OP_ADD] 1 1/2 [OP_SUB] [OP_DIV] 300 [OP_ADD] 1 1/2 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 0\nvar_b = 400\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 0.5\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 300\nvar_i = var_g + var_h\nvar_j = 1\nvar_k = 0.5\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 0\nvar_b = 400\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 0.5\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 300\nvar_i = var_g + var_h\nvar_j = 1\nvar_k = 0.5\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nprint(int(var_m))"
    },
    "3618": {
        "category": "Correspondence",
        "question_ko": "서로 다른 두 수 A, B가 있습니다. 두 자리 수끼리의 뺄셈식 A2-5A=B3에서 A×B의 값을 구하시오.",
        "question_en": "There are two different numbers: A and B. Find the value of A×B in the two-digit subtraction formula of A2-5A=B3.",
        "answer_ko": "27",
        "answer_en": "27",
        "solution_abst_ko": "A2-5A=B3 A [OP_DIGIT_UNK_SOLVER] A2-5A=B3 B [OP_DIGIT_UNK_SOLVER] [OP_MUL]",
        "solution_abst_en": "A2-5A=B3 A [OP_DIGIT_UNK_SOLVER] A2-5A=B3 B [OP_DIGIT_UNK_SOLVER] [OP_MUL]",
        "solution_code_ko": "var_a = 'A2-5A=B3'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 'A2-5A=B3'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 'A2-5A=B3'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 'A2-5A=B3'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "3619": {
        "category": "Arithmetic calculation",
        "question_ko": "몇 년 전 지민이가 16살일 때, 아버지는 47살이였습니다. 올해 아버지의 나이가 지민이의 2배라면, 몇 년이 흘렀습니까?",
        "question_en": "A few years ago, when Jimin was 16, his father was 47. If the father is twice Jimin's age this year, how many years have passed?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "47 16 2 [OP_MUL] [OP_SUB] 2 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "47 16 2 [OP_MUL] [OP_SUB] 2 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 47\nvar_b = 16\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 2\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 47\nvar_b = 16\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 2\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "3620": {
        "category": "Possibility",
        "question_ko": "서로 다른 4개의 과일 중에서 2개를 골라서 사는 경우는 모두 몇 가지입니까?",
        "question_en": "How many times can you choose and buy 2 of 4 different fruits?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "4 2 [OP_COMB]",
        "solution_abst_en": "4 2 [OP_COMB]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))"
    },
    "3621": {
        "category": "Possibility",
        "question_ko": "8, 3, 4, 6 중에서 서로 다른 숫자 2개를 뽑아 만들 수 있는 두 자리 수 중에서 가장 큰 수와 가장 작은 수의 차를 구하시오.",
        "question_en": "Find the difference between the largest and smallest two-digit numbers that can be formed by picking two different numbers from 8, 3, 4, and 6.",
        "answer_ko": "52",
        "answer_en": "52",
        "solution_abst_ko": "[OP_LIST_SOL] 8 3 4 6 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 8 3 4 6 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 8\nvar_b = 3\nvar_c = 4\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 8\nvar_b = 3\nvar_c = 4\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))"
    },
    "3622": {
        "category": "Correspondence",
        "question_ko": "어떤 수보다 26 큰 수가 50일 때, 어떤 수의 9배인 수를 구하시오.",
        "question_en": "If the number 26 greater than a number is 50, find the number that is 9 times the number.",
        "answer_ko": "216",
        "answer_en": "216",
        "solution_abst_ko": "50 26 [OP_SUB] 9 [OP_MUL]",
        "solution_abst_en": "50 26 [OP_SUB] 9 [OP_MUL]",
        "solution_code_ko": "var_a = 50\nvar_b = 26\nvar_c = var_a - var_b\nvar_d = 9\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 50\nvar_b = 26\nvar_c = var_a - var_b\nvar_d = 9\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "3623": {
        "category": "Arithmetic calculation",
        "question_ko": "2135개의 구슬을 한 통에 100개씩 담으려고 합니다. 구슬을 담을 통은 최소 몇 개 필요한지 구하시오.",
        "question_en": "We are trying to put 2135 marbles, 100 each in a barrel. Find the minimum number of barrels needed to hold the marbles.",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "2153 100 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "2153 100 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 2153\nvar_b = 100\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))",
        "solution_code_en": "var_a = 2153\nvar_b = 100\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))"
    },
    "3624": {
        "category": "Comparison",
        "question_ko": "연필, 지우개, 볼펜, 자, 공책 순으로 책상위에 있습니다. 볼펜과 공책의 위치를 바꿨을 떄 공책은 몇 번째에 있나요?",
        "question_en": "Pencil, eraser, pen, ruler, and notebook are on the desk in this order. When you swap the positions of the pen and the notebook, in what position (in ordinal number) would the notebook be?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "[OP_LIST_SOL] 연필 지우개 볼펜 자 공책 [OP_LIST_EOL] 공책 [OP_LIST_INDEX]",
        "solution_abst_en": "[OP_LIST_SOL] Pencil eraser pen ruler notebook [OP_LIST_EOL] notebook [OP_LIST_INDEX]",
        "solution_code_ko": "var_a = '연필'\nvar_b = '지우개'\nvar_c = '볼펜'\nvar_d = '자'\nvar_e = '공책'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = '공책'\nvar_g = list_a.index(var_f)+1\nprint(int(var_g))",
        "solution_code_en": "var_a = 'Pencil'\nvar_b = 'eraser'\nvar_c = 'pen'\nvar_d = 'ruler'\nvar_e = 'notebook'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 'notebook'\nvar_g = list_a.index(var_f)+1\nprint(int(var_g))"
    },
    "3625": {
        "category": "Correspondence",
        "question_ko": "A는 238이고 B는 이보다 143만큼 큽니다. B가 C에서 304를 뺀 값일때 A+C를 구하시오.",
        "question_en": "A is 238 and B is 143 greater than that. Find A+C when B is the value of C minus 304.",
        "answer_ko": "637",
        "answer_en": "637",
        "solution_abst_ko": "238 238 143 [OP_SUB] 304 [OP_ADD] [OP_ADD]",
        "solution_abst_en": "238 238 143 [OP_SUB] 304 [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 238\nvar_b = 238\nvar_c = 143\nvar_d = var_b - var_c\nvar_e = 304\nvar_f = var_d + var_e\nvar_g = var_a + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 238\nvar_b = 238\nvar_c = 143\nvar_d = var_b - var_c\nvar_e = 304\nvar_f = var_d + var_e\nvar_g = var_a + var_f\nprint(int(var_g))"
    },
    "3626": {
        "category": "Geometry",
        "question_ko": "태형이는 교실에서 6번째로 키가 작고, 석진이는 그 다음으로 키가 작습니다. 석진이는 몇 번째로 키가 작습니까?",
        "question_en": "Taehyung is the 6th shortest in the class, and Seokjin is the next shortest. In what order is Seokjin short in the classroom?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "6 1 [OP_ADD]",
        "solution_abst_en": "6 1 [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "3627": {
        "category": "Comparison",
        "question_ko": "들이가 1리터(L) 400밀리리터(㎖)인 물병과 들이가 2800밀리리터(㎖)인 주전자에 물을 가득 채운 뒤 대야에 모두 부었더니 대야가 가득 찼습니다. 들이가 4리터(L) 100밀리리터(㎖)인 수조와 대야 중에서 어느 쪽의 들이가 더 많습니까?",
        "question_en": "After filling a 1 liter (l) 400 milliliter (ml) water bottle and a 2800 milliliter (ml) tank full of water, they poured all the water into a basin, and the basin was full. Which one can have more water inside - the basin or a tank with 4 liters (l) and 100 milliliters (ml)?",
        "answer_ko": "대야",
        "answer_en": "basin",
        "solution_abst_ko": "[OP_LIST_SOL] 수조 대야 [OP_LIST_EOL] [OP_LIST_SOL] 4 1000 [OP_MUL] 100 [OP_ADD] 2800 1 1000 [OP_MUL] 400 [OP_ADD] [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] tank basin [OP_LIST_EOL] [OP_LIST_SOL] 4 1000 [OP_MUL] 100 [OP_ADD] 2800 1 1000 [OP_MUL] 400 [OP_ADD] [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '수조'\nvar_b = '대야'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 100\nvar_g = var_e + var_f\nvar_h = 2800\nvar_i = 1\nvar_j = 1000\nvar_k = var_i * var_j\nvar_l = 400\nvar_m = var_k + var_l\nvar_n = var_h + var_m\nlist_b= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_o = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_p = list_c[-var_o]\nvar_q = list_b.index(var_p)+1\nvar_r = list_a[var_q-1]\nprint(var_r)",
        "solution_code_en": "var_a = 'tank'\nvar_b = 'basin'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 100\nvar_g = var_e + var_f\nvar_h = 2800\nvar_i = 1\nvar_j = 1000\nvar_k = var_i * var_j\nvar_l = 400\nvar_m = var_k + var_l\nvar_n = var_h + var_m\nlist_b= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_o = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_p = list_c[-var_o]\nvar_q = list_b.index(var_p)+1\nvar_r = list_a[var_q-1]\nprint(var_r)"
    },
    "3628": {
        "category": "Correspondence",
        "question_ko": "0보다 크고 2보다 작은 한자리 수를 구하시오.",
        "question_en": "Find the single digit number greater than 0 and less than 2.",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "1 9 1 [OP_LIST_ARANGE] 0 [OP_LIST_MORE] 2 [OP_LIST_LESS] 1 [OP_LIST_GET]",
        "solution_abst_en": "1 9 1 [OP_LIST_ARANGE] 0 [OP_LIST_MORE] 2 [OP_LIST_LESS] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 0\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nvar_e = 2\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = 1\nvar_g = list_c[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 0\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nvar_e = 2\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = 1\nvar_g = list_c[var_f-1]\nprint(int(var_g))"
    },
    "3629": {
        "category": "Correspondence",
        "question_ko": "담임선생님은 학생들의 기말고사 점수의 총합이 중간고사 점수의 총합보다 2152점이 오를거라 예상했지만 실제로는 1264점 밖에 오르지 않았습니다. 선생님의 예상과 실제 점수 사이의 차이는 얼마입니까?",
        "question_en": "The homeroom teacher expected the sum of the students' final exam scores to increase by 2152 compared to the sum of their midterm exam scores, but it only increased by 1264. What is the difference between the teacher's estimate and the actual score?",
        "answer_ko": "888",
        "answer_en": "888",
        "solution_abst_ko": "2152 1264 [OP_SUB]",
        "solution_abst_en": "2152 1264 [OP_SUB]",
        "solution_code_ko": "var_a = 2152\nvar_b = 1264\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2152\nvar_b = 1264\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "3630": {
        "category": "Geometry",
        "question_ko": "어떤 평행사변형은 높이가 11센티미터(㎝), 넓이가 44제곱센티미터(㎠)입니다. 이 평행사변형의 밑변의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "A parallelogram has a height of 11 centimeters (cm) and an area of 44 square centimeters (cm2). What is the length of the base of this parallelogram in centimeters (cm)?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "44 11 [OP_DIV]",
        "solution_abst_en": "44 11 [OP_DIV]",
        "solution_code_ko": "var_a = 44\nvar_b = 11\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 44\nvar_b = 11\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "3631": {
        "category": "Possibility",
        "question_ko": "다섯 개의 숫자 0, 1, 2, 3, 4 중에서 3개를 골라 세 자리의 짝수를 만들었다. 같은 수를 여러 번 사용해도 된다면, 만들 수 있는 모든 짝수의 개수는 몇개인가?",
        "question_en": "Three of the five numbers 0, 1, 2, 3, and 4 were used to make a three-digit even number. If you can use the same number multiple times, how many even numbers can you make?",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 2 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 2 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 2\nlist_c = []\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if i % var_g == 0:\n        list_c.append(i)\nvar_h = len(list_c)\nprint(int(var_h))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 2\nlist_c = []\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if i % var_g == 0:\n        list_c.append(i)\nvar_h = len(list_c)\nprint(int(var_h))"
    },
    "3632": {
        "category": "Geometry",
        "question_ko": "두 대각선의 길이가 각각 9센티미터(㎝), 14센티미터(㎝)인 마름모가 있습니다. 이 도형의 넓이를 구하세요.",
        "question_en": "There is a rhombus with two diagonals measuring 9 centimeters (cm) and 14 centimeters (cm), respectively. Find the area of this figure.",
        "answer_ko": "63",
        "answer_en": "63",
        "solution_abst_ko": "9 14 [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "9 14 [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 9\nvar_b = 14\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 14\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "3633": {
        "category": "Arithmetic calculation",
        "question_ko": "가로가 30센티미터(㎝), 세로가 2센티미터(㎝)인 종이 테이프 15장을 연결하여 길게 만들었습니다. 연결할 때 풀칠 부분의 겹쳐진 부분의 길이가 2센티미터(㎝)라면, 만들어진 종이 테이프의 가로의 전체 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "I joined 15 pieces of paper tape, each of which is 30 centimeters (cm) wide and 2 centimeters (cm) long, to each other to extend it. If the length of the overlapping glued part is 2 centimeters (cm) long, what is the total width of the created piece of paper tape in centimeters (cm)?",
        "answer_ko": "422",
        "answer_en": "422",
        "solution_abst_ko": "30 15 [OP_MUL] 15 1 [OP_SUB] 2 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "30 15 [OP_MUL] 15 1 [OP_SUB] 2 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 30\nvar_b = 15\nvar_c = var_a * var_b\nvar_d = 15\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_c - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 30\nvar_b = 15\nvar_c = var_a * var_b\nvar_d = 15\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_c - var_h\nprint(int(var_i))"
    },
    "3634": {
        "category": "Geometry",
        "question_ko": "길이가 25센티미터(㎝)인 밧줄 64개를 서로 묶어 긴 줄을 만드려고 한다. 2개의 밧줄을 서로 묶어서 매듭을 지으면 길이가 3센티미터(㎝)가 줄어든다. 새로 만든 밧줄의 길이는 얼마입니까?",
        "question_en": "We are going to make a long rope by tying 64 ropes each 25 centimeters (cm) in length. By tying two ropes together and making a knot, the length is reduced by 3 centimeters (cm). What is the length of the newly made rope?",
        "answer_ko": "1411",
        "answer_en": "1411",
        "solution_abst_ko": "25 64 [OP_MUL] 3 64 1 [OP_SUB] [OP_MUL] [OP_SUB]",
        "solution_abst_en": "25 64 [OP_MUL] 3 64 1 [OP_SUB] [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 25\nvar_b = 64\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = 64\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_c - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 25\nvar_b = 64\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = 64\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_c - var_h\nprint(int(var_i))"
    },
    "3635": {
        "category": "Geometry",
        "question_ko": "정사각형 모양의 색종이를 가로와 세로 모두 10장씩 빈틈없이 늘어놓아 정사각형을 만들었습니다. 둘레에 놓인 색종이의 색깔은 빨간색이고, 안쪽에 놓인 색종이의 색깔은 노란색일 때, 노란 색종이는 모두 몇 장입니까?",
        "question_en": "A square was created by arranging 10 square-shaped colored papers horizontally and vertically without gaps. If the colored papers on the periphery is red and the colored papers on the inside is yellow, how many yellow colored papers are there?",
        "answer_ko": "64",
        "answer_en": "64",
        "solution_abst_ko": "10 2 [OP_SUB] 2 [OP_POW]",
        "solution_abst_en": "10 2 [OP_SUB] 2 [OP_POW]",
        "solution_code_ko": "var_a = 10\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint(int(var_e))"
    },
    "3636": {
        "category": "Correspondence",
        "question_ko": "6A5+10B=748일 때, B에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "In the addition between three-digit numbers, 6A5+10B=748, what number should go in B?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "6A5+10B=748 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "6A5+10B=748 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '6A5+10B=748'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '6A5+10B=748'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "3637": {
        "category": "Geometry",
        "question_ko": "둘레의 길이가 100센티미터(㎝)인 정사각형 모양의 액자가 있습니다. 이 액자의 한 변에 색테이프를 붙여 장식을 할 때, 색 테이프는 몇 센티미터(㎝) 필요합니까?",
        "question_en": "You have a picture frame in the shape of a square with a perimeter 100 centimeters (cm) long. How many centimeters (cm) of colored tape are needed to decorate one side of this frame?",
        "answer_ko": "25",
        "answer_en": "25",
        "solution_abst_ko": "100 4 [OP_DIV]",
        "solution_abst_en": "100 4 [OP_DIV]",
        "solution_code_ko": "var_a = 100\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 100\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "3638": {
        "category": "Comparison",
        "question_ko": "(가) , (나) 상자는 각각 3센티미터(㎝), 3.5센티미터(㎝)이다. 태형이는 16개의 (가) 상자를, 윤기는 14개의 (나) 상자를 쌓았을 때 더 높이 쌓은 사람은 누구인가요?",
        "question_en": "Box A and B are 3 centimeters (cm) and 3.5 centimeters (cm), respectively. When Taehyung stacked 16 boxes of A and Yoongi stacked 14 boxes of B, who would be the one that piled boxes higher?",
        "answer_ko": "윤기",
        "answer_en": "Yoongi",
        "solution_abst_ko": "[OP_LIST_SOL] 태형 윤기 [OP_LIST_EOL] [OP_LIST_SOL] 3 16 [OP_MUL] 3.5 14 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Taehyung Yoongi [OP_LIST_EOL] [OP_LIST_SOL] 3 16 [OP_MUL] 3.5 14 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '태형'\nvar_b = '윤기'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nvar_d = 16\nvar_e = var_c * var_d\nvar_f = 3.5\nvar_g = 14\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Taehyung'\nvar_b = 'Yoongi'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nvar_d = 16\nvar_e = var_c * var_d\nvar_f = 3.5\nvar_g = 14\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "3639": {
        "category": "Correspondence",
        "question_ko": "A는 9로 나누면 몫이 2이고 나머지가 6인 수이다. 이때 A를 구하여라.",
        "question_en": "When you divide A by 9, the quotient is 2 and the remainder is 6. Find A at this time.",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "9 2 [OP_MUL] 6 [OP_ADD]",
        "solution_abst_en": "9 2 [OP_MUL] 6 [OP_ADD]",
        "solution_code_ko": "var_a = 9\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3640": {
        "category": "Comparison",
        "question_ko": "남준이는 2등을 했고, 윤기는 바로 그 앞에 들어갔습니다. 윤기는 몇등입니까?",
        "question_en": "Namjoon came second, and Yoongi went right in front of him. What's Yoongi's rank?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "2 1 [OP_SUB]",
        "solution_abst_en": "2 1 [OP_SUB]",
        "solution_code_ko": "var_a = 2\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "3641": {
        "category": "Arithmetic calculation",
        "question_ko": "동물원에 있는 새끼 코알라의 몸무게는 2킬로그램(㎏) 하고도 460그램(g) 입니다. 새끼 코알라의 몸무게는 몇 그램(g)입니까?",
        "question_en": "A baby koala in the zoo weighs 2 kilograms (kg) and 460 grams (g). How many grams (g) does the baby koala weigh?",
        "answer_ko": "2460",
        "answer_en": "2460",
        "solution_abst_ko": "2 1000 [OP_MUL] 460 [OP_ADD]",
        "solution_abst_en": "2 1000 [OP_MUL] 460 [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 460\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 460\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3642": {
        "category": "Comparison",
        "question_ko": "0보다 크고 100보다 작은 수 중에서 4와 6의 공배수를 작은 수부터 차례대로 썼습니다. 왼쪽에서 7번째 수를 구하시오.",
        "question_en": "Among the numbers greater than 0 and less than 100, write the common multiples of 4 and 6 in order from smallest. Find the 7th number from the left.",
        "answer_ko": "84",
        "answer_en": "84",
        "solution_abst_ko": "0 1 [OP_ADD] 100 1 [OP_SUB] 1 [OP_LIST_ARANGE] 4 6 [OP_LCM] [OP_LIST_DIVISIBLE] 7 [OP_LIST_GET]",
        "solution_abst_en": "0 1 [OP_ADD] 100 1 [OP_SUB] 1 [OP_LIST_ARANGE] 4 6 [OP_LCM] [OP_LIST_DIVISIBLE] 7 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 100\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = 4\nvar_i = 6\nvar_j = var_i * var_h / math.gcd(int(var_i), int(var_h))\nlist_b = []\nvar_j = int(var_j)\nfor i in list_a:\n    i = int(i)\n    if i % var_j == 0:\n        list_b.append(i)\nvar_k = 7\nvar_l = list_b[var_k-1]\nprint(int(var_l))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 100\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = 4\nvar_i = 6\nvar_j = var_i * var_h / math.gcd(int(var_i), int(var_h))\nlist_b = []\nvar_j = int(var_j)\nfor i in list_a:\n    i = int(i)\n    if i % var_j == 0:\n        list_b.append(i)\nvar_k = 7\nvar_l = list_b[var_k-1]\nprint(int(var_l))"
    },
    "3643": {
        "category": "Comparison",
        "question_ko": "1.4, 9/10, 1.2, 0.5, 13/10 5개 숫자 중에서 1.1보다 작은 숫자를 골라 큰 순서대로 나열했을 때, 가장 앞에 있는 숫자는 무엇입니까?",
        "question_en": "If a number less than 1.1 is selected among 1.4, 9/10, 1.2, 0.5, and 13/10, and arranged in ascending order, which number comes first?",
        "answer_ko": "0.90",
        "answer_en": "0.9",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i < var_f:\n        list_b.append(i)\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nprint('{:.2f}'.format(round(var_h+1e-10,2)))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i < var_f:\n        list_b.append(i)\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nprint('{:.2f}'.format(round(var_h+1e-10,2)))"
    },
    "3644": {
        "category": "Correspondence",
        "question_ko": "어떤 수의 1/100인 수는 31.76보다 0.28 크다고 합니다. 어떤 수를 구하시오.",
        "question_en": "A number that is the 1/100 of that number is said to be 0.28 greater than 31.76. Find that number.",
        "answer_ko": "3204",
        "answer_en": "3204",
        "solution_abst_ko": "31.76 0.28 [OP_ADD] 1 100 [OP_DIV] [OP_DIV]",
        "solution_abst_en": "31.76 0.28 [OP_ADD] 1 100 [OP_DIV] [OP_DIV]",
        "solution_code_ko": "var_a = 31.76\nvar_b = 0.28\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 100\nvar_f = var_d / var_e\nvar_g = var_c / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 31.76\nvar_b = 0.28\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 100\nvar_f = var_d / var_e\nvar_g = var_c / var_f\nprint(int(var_g))"
    },
    "3645": {
        "category": "Geometry",
        "question_ko": "네 변의 길이의 합이 56센티미터(㎝)인 정사각형이 있다. 이 정사각형을 4등분 해서 작은 정사각형을 만들었다. 이 작은 정사각형 441개로 큰 정사각형 하나를 만들 때, 그 정사각형의 둘레를 구하시오.",
        "question_en": "There is a square with the sum of its four sides measuring 56 centimeters (cm). Divide this square into 4 equal parts to make smaller squares. When you make one large square out of these 441 small squares, find the perimeter of that square.",
        "answer_ko": "588",
        "answer_en": "588",
        "solution_abst_ko": "56 4 [OP_DIV] 4 1/2 [OP_POW] [OP_DIV] 441 1/2 [OP_POW] [OP_MUL] 4 [OP_MUL]",
        "solution_abst_en": "56 4 [OP_DIV] 4 1/2 [OP_POW] [OP_DIV] 441 1/2 [OP_POW] [OP_MUL] 4 [OP_MUL]",
        "solution_code_ko": "var_a = 56\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = 0.5\nvar_f = var_d ** var_e\nvar_g = var_c / var_f\nvar_h = 441\nvar_i = 0.5\nvar_j = var_h ** var_i\nvar_k = var_g * var_j\nvar_l = 4\nvar_m = var_k * var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 56\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = 0.5\nvar_f = var_d ** var_e\nvar_g = var_c / var_f\nvar_h = 441\nvar_i = 0.5\nvar_j = var_h ** var_i\nvar_k = var_g * var_j\nvar_l = 4\nvar_m = var_k * var_l\nprint(int(var_m))"
    },
    "3646": {
        "category": "Correspondence",
        "question_ko": "여섯자리 수 12ABC8은 137의 배수이다. 이 때, 세 자리 수 ABC에 알맞은 수는 모두 몇 가지인가?",
        "question_en": "The six-digit number 12ABC8 is a multiple of 137. In this case, how many numbers fit the 3-digit number ABC?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "12ABC8 [OP_GEN_POSSIBLE_LIST] 137 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "12ABC8 [OP_GEN_POSSIBLE_LIST] 137 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '12ABC8'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 137\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))",
        "solution_code_en": "var_a = '12ABC8'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 137\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))"
    },
    "3647": {
        "category": "Arithmetic calculation",
        "question_ko": "20권의 책이 들어가는 박스에 (가) 책과 (나) 책이 가득 들어있다. (가) 책이 (나) 책보다 4권 더 많다고 한다면, (가) 책은 몇 권 있는지 구하시오.",
        "question_en": "The box that holds 20 books is full of books (a) and books (b). If there are 4 more books (a) than books (b), how many books (a) are there?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "20 4 [OP_ADD] 2 [OP_FDIV]",
        "solution_abst_en": "20 4 [OP_ADD] 2 [OP_FDIV]",
        "solution_code_ko": "var_a = 20\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "3648": {
        "category": "Arithmetic calculation",
        "question_ko": "3명이 8킬로그램(㎏)짜리 아령을 1개씩 가지고 있고, 2명은 7킬로그램(㎏)짜리 아령을 1개씩 가지고 있습니다. 5명이 가진 모든 아령의 무게는 몇 킬로그램(㎏)입니까?",
        "question_en": "Three people each have one 8-kilogram (kg) dumbbell, and two people each have one 7-kilogram (kg) dumbbell. How many kilograms (kg) do all 5 dumbbells weigh?",
        "answer_ko": "38",
        "answer_en": "38",
        "solution_abst_ko": "3 8 [OP_MUL] 2 7 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "3 8 [OP_MUL] 2 7 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = 7\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 3\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = 7\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "3649": {
        "category": "Possibility",
        "question_ko": "1부터 9까지의 숫자가 각각 한 개씩 적힌 숫자 카드가 9장 있다. 이 중에서 8장을 꺼내 그 숫자의 합을 구할 때, 나올 수 있는 모든 합들의 총합을 구하여라.",
        "question_en": "There are 9 number cards, one each with a number from 1 to 9 written on it. You take out 8 cards and add all the numbers written on the cards. Find the sum of all possible sums.",
        "answer_ko": "360",
        "answer_en": "360",
        "solution_abst_ko": "1 9 1 [OP_LIST_ARANGE] 8 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] [OP_LIST_SOL] [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_SUM]",
        "solution_abst_en": "1 9 1 [OP_LIST_ARANGE] 8 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] [OP_LIST_SOL] [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 8\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nlist_d= []\nlist_d.reverse()\nlist_e = list(set(list_c) - set(list_d))\nlist_e = [float(i) for i in list_e]\nvar_f = sum(list_e)\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 8\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nlist_d= []\nlist_d.reverse()\nlist_e = list(set(list_c) - set(list_d))\nlist_e = [float(i) for i in list_e]\nvar_f = sum(list_e)\nprint(int(var_f))"
    },
    "3650": {
        "category": "Correspondence",
        "question_ko": "23을 A로 나눴더니 몫은 3이 되었고 나머지는 2가 되었습니다. A는 자연수입니다. 이 때 A는 무엇일까요?",
        "question_en": "When 23 is divided by A, the quotient is 3 and the remainder is 2. If A is a natural number, what is A in this case?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "23 2 [OP_SUB] 3 [OP_DIV]",
        "solution_abst_en": "23 2 [OP_SUB] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 23\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 23\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "3651": {
        "category": "Arithmetic calculation",
        "question_ko": "10초간 전화하면 30원을 낸다고 합니다. 2분 40초 동안 전화를 한다면 얼마를 내야합니까?",
        "question_en": "Suppose you pay 30 won when you call for 10 seconds. How much do you have to pay for 2 minutes 40 seconds phone call?",
        "answer_ko": "480",
        "answer_en": "480",
        "solution_abst_ko": "2 60 [OP_MUL] 40 [OP_ADD] 10 [OP_DIV] 30 [OP_MUL]",
        "solution_abst_en": "2 60 [OP_MUL] 40 [OP_ADD] 10 [OP_DIV] 30 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 40\nvar_e = var_c + var_d\nvar_f = 10\nvar_g = var_e / var_f\nvar_h = 30\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 2\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 40\nvar_e = var_c + var_d\nvar_f = 10\nvar_g = var_e / var_f\nvar_h = 30\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "3652": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 954에 더해야하는데 실수로 빼서 468이 되었습니다. 올바르게 계산했다면 얼마인지 구하세요.",
        "question_en": "I had to add 954 to a number but mistakenly subtracted it to get 468. When the calculation is correctly done, what is the result?",
        "answer_ko": "2376",
        "answer_en": "2376",
        "solution_abst_ko": "468 954 [OP_ADD] 954 [OP_ADD]",
        "solution_abst_en": "468 954 [OP_ADD] 954 [OP_ADD]",
        "solution_code_ko": "var_a = 468\nvar_b = 954\nvar_c = var_a + var_b\nvar_d = 954\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 468\nvar_b = 954\nvar_c = var_a + var_b\nvar_d = 954\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3653": {
        "category": "Geometry",
        "question_ko": "가로가 80센티미터(㎝), 세로가 75센티미터(㎝), 높이가 120센티미터(㎝)인 직육면체 모양의 상자가 있습니다. 이 상자의 모든 변의 길이를 2배로 늘려 새로운 상자를 만들었을 때, 새롭게 만들어진 상자의 부피는 몇 세제곱미터(㎥)일지 구하시오.",
        "question_en": "There is a box in the shape of a cuboid measuring 80 centimeters (cm) wide, 75 centimeters (cm) long, and 120 centimeters (cm) high. If you double the length of all sides of this box to make a new box, find the volume in cubic meters (m3) of the new box.",
        "answer_ko": "5.76",
        "answer_en": "5.76",
        "solution_abst_ko": "80 100 [OP_DIV] 2 [OP_MUL] 75 100 [OP_DIV] 2 [OP_MUL] 120 100 [OP_DIV] 2 [OP_MUL] [OP_MUL] [OP_MUL]",
        "solution_abst_en": "80 100 [OP_DIV] 2 [OP_MUL] 75 100 [OP_DIV] 2 [OP_MUL] 120 100 [OP_DIV] 2 [OP_MUL] [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 80\nvar_b = 100\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 75\nvar_g = 100\nvar_h = var_f / var_g\nvar_i = 2\nvar_j = var_h * var_i\nvar_k = 120\nvar_l = 100\nvar_m = var_k / var_l\nvar_n = 2\nvar_o = var_m * var_n\nvar_p = var_j * var_o\nvar_q = var_e * var_p\nprint('{:.2f}'.format(round(var_q+1e-10,2)))",
        "solution_code_en": "var_a = 80\nvar_b = 100\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 75\nvar_g = 100\nvar_h = var_f / var_g\nvar_i = 2\nvar_j = var_h * var_i\nvar_k = 120\nvar_l = 100\nvar_m = var_k / var_l\nvar_n = 2\nvar_o = var_m * var_n\nvar_p = var_j * var_o\nvar_q = var_e * var_p\nprint('{:.2f}'.format(round(var_q+1e-10,2)))"
    },
    "3654": {
        "category": "Correspondence",
        "question_ko": "AB3+36=269일 때, A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "When AB3+36=269 is said to hold, what number should go in A?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "AB3+36=269 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "AB3+36=269 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'AB3+36=269'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'AB3+36=269'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "3655": {
        "category": "Correspondence",
        "question_ko": "300은 25로 나누어떨어집니다. 300보다 큰 수 중에서 25로 나누었을 때 나머지가 24가 되는 가장 작은 수를 구하세요",
        "question_en": "300 is divisible by 25. Find the smallest number greater than 300 that when divided by 25 has a remainder of 24.",
        "answer_ko": "324",
        "answer_en": "324",
        "solution_abst_ko": "300 24 [OP_ADD]",
        "solution_abst_en": "300 24 [OP_ADD]",
        "solution_code_ko": "var_a = 300\nvar_b = 24\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 300\nvar_b = 24\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "3656": {
        "category": "Possibility",
        "question_ko": "1, 3, 5, 8의 4장의 숫자 카드를 한번씩만 사용하여 두 자리 수를 만들 때 가장 큰 두 자리 수와 가장 작은 두 자리 수의 곱을 구하시오.",
        "question_en": "Find the product of the largest two-digit number and the smallest two-digit number among the two-digit numbers that can be formed using four number cards 1, 3, 5, and 8, only once each.",
        "answer_ko": "1105",
        "answer_en": "1105",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 5 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 5 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MUL]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 5\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g * var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 5\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g * var_i\nprint(int(var_j))"
    },
    "3657": {
        "category": "Comparison",
        "question_ko": "학생들이 한 줄로 서 있습니다. 유정이는 맨 뒤에 서 있습니다. 은정이는 앞에서 5번째에 서 있습니다. 은정이와 유정이 사이에 8명이 서 있을 때, 줄을 서 있는 학생은 모두 몇 명입니까?",
        "question_en": "Students are standing in a line. Yoojung is standing at the very last. Eunjung is standing 5th from the front. When there are 8 students standing between Eunjeong and Yoojeong, how many students are in line?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "5 8 [OP_ADD] 1 [OP_ADD]",
        "solution_abst_en": "5 8 [OP_ADD] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3658": {
        "category": "Possibility",
        "question_ko": "1, 0, 7를 모두 사용하여 만들 수 있는 세 자리 수 중 가장 작은 수는 얼마입니까?",
        "question_en": "What is the smallest three-digit number that can be formed using all 1, 0, and 7?",
        "answer_ko": "107",
        "answer_en": "107",
        "solution_abst_ko": "[OP_LIST_SOL] 1 0 7 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 0 7 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1\nvar_b = 0\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 0\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nprint(int(var_f))"
    },
    "3659": {
        "category": "Geometry",
        "question_ko": "빨간색 색연필과 노란색 색연필을 가로와 세로 모두 10자루씩 빈틈없이 정리였습니다. 둘레에 놓인 색연필은 빨간색이고, 안쪽에 놓인 색연필은 노란색일 때, 노란 색연필은 모두 몇 개일까요?",
        "question_en": "Red and yellow colored pencils were neatly arranged in 10 rows both horizontally and vertically. If the colored pencils placed around the perimeter are red and the colored pencils placed inside are yellow, how many yellow colored pencils are there in all?",
        "answer_ko": "64",
        "answer_en": "64",
        "solution_abst_ko": "10 2 [OP_SUB] 2 [OP_POW]",
        "solution_abst_en": "10 2 [OP_SUB] 2 [OP_POW]",
        "solution_code_ko": "var_a = 10\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint(int(var_e))"
    },
    "3660": {
        "category": "Possibility",
        "question_ko": "4, 3, 7, 9 중 3개를 사용하여 일의 자리 숫자가 3인 두 번째 큰 수는 무엇입니까?",
        "question_en": "Using 3 out of 4, 3, 7, 9, what is the second largest number with the units digit of 3?",
        "answer_ko": "943",
        "answer_en": "943",
        "solution_abst_ko": "[OP_LIST_SOL] 4 3 7 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 3 [OP_LIST_SEARCH_FIXED_DIGIT] 2 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 4 3 7 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 3 [OP_LIST_SEARCH_FIXED_DIGIT] 2 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 4\nvar_b = 3\nvar_c = 7\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nvar_g = 3\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 2\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nprint(int(var_i))",
        "solution_code_en": "var_a = 4\nvar_b = 3\nvar_c = 7\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nvar_g = 3\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 2\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nprint(int(var_i))"
    },
    "3661": {
        "category": "Possibility",
        "question_ko": "윤기는 정국에게 줄 생일 선물로 3개의 장난감을 선택하려고 합니다. 서로 다른 10개의 장난감 중에서 한개씩 선물을 고르려고 할때, 장난감을 고르는 경우는 모두 몇 가지입니까?",
        "question_en": "Yoongi wants to choose three toys for Jungkook's birthday present. When trying to choose one gift out of 10 different toys, how many ways are there in choosing a toy?",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "10 3 [OP_COMB]",
        "solution_abst_en": "10 3 [OP_COMB]",
        "solution_code_ko": "var_a = 10\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))",
        "solution_code_en": "var_a = 10\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))"
    },
    "3662": {
        "category": "Arithmetic calculation",
        "question_ko": "용수철에 추를 매달았더니 용수철의 길이가 추를 매달기 전보다 29.75 센티미터(㎝) 늘어났습니다. 아무것도 매달지 않았을 때의 용수철의 길이가 4.25 센티미터(㎝) 였다면 추를 매달았을 때의 용수철의 길이는 아무것도 매달지 않았을 때의 용수철의 길이의 몇 배입니까?",
        "question_en": "When a weight was hung from the spring, the length of the spring increased by 29.75 centimeters (cm) compared to before the weight was hung. If the length of the spring with nothing hanging is 4.25 centimeters (cm), how many times the length of the spring with the weight is the length of the spring with nothing hanging?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "29.75 4.25 [OP_ADD] 4.25 [OP_DIV]",
        "solution_abst_en": "29.75 4.25 [OP_ADD] 4.25 [OP_DIV]",
        "solution_code_ko": "var_a = 29.75\nvar_b = 4.25\nvar_c = var_a + var_b\nvar_d = 4.25\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 29.75\nvar_b = 4.25\nvar_c = var_a + var_b\nvar_d = 4.25\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "3663": {
        "category": "Comparison",
        "question_ko": "제니는 주스를 지수보다 0.2리터(L) 더 많이 마셨고, 제니는 주스를 9/5리터(L) 마셨습니다. 지수는 로희보다 3/10리터(L) 더 적게 마셨을 때 주스를 가장 적게 마신 사람은 누구입니까?",
        "question_en": "Jennie drank 0.2 liters (L) more juice than Jisoo, and Jennie drank 9/5 liters (L) of juice. Who drank the least juice when Jisoo drank 3/10 of a liter (L) less than Rohee?",
        "answer_ko": "지수",
        "answer_en": "Jisoo",
        "solution_abst_ko": "[OP_LIST_SOL] 제니 지수 로희 [OP_LIST_EOL] [OP_LIST_SOL] 9/5 9/5 0.2 [OP_SUB] 9/5 0.2 [OP_SUB] 3/10 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jennie Jisoo Rohee [OP_LIST_EOL] [OP_LIST_SOL] 9/5 9/5 0.2 [OP_SUB] 9/5 0.2 [OP_SUB] 3/10 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '제니'\nvar_b = '지수'\nvar_c = '로희'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1.8\nvar_e = 1.8\nvar_f = 0.2\nvar_g = var_e - var_f\nvar_h = 1.8\nvar_i = 0.2\nvar_j = var_h - var_i\nvar_k = 0.3\nvar_l = var_j + var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[var_m-1]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'Jennie'\nvar_b = 'Jisoo'\nvar_c = 'Rohee'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1.8\nvar_e = 1.8\nvar_f = 0.2\nvar_g = var_e - var_f\nvar_h = 1.8\nvar_i = 0.2\nvar_j = var_h - var_i\nvar_k = 0.3\nvar_l = var_j + var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[var_m-1]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "3664": {
        "category": "Arithmetic calculation",
        "question_ko": "수영이네 가족이 오늘 우유를 전체의 0.4만큼 마셨더니 남은 우유가 0.69리터(L) 였습니다. 처음에 있던 우유는 몇 리터(L) 인지 구하시오.",
        "question_en": "Suyeong's family drank 0.4 of the total milk today, and the remaining milk was 0.69 liters (L). Find how many liters (L) of milk were in the beginning.",
        "answer_ko": "1.15",
        "answer_en": "1.15",
        "solution_abst_ko": "0.69 1 0.4 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "0.69 1 0.4 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 0.69\nvar_b = 1\nvar_c = 0.4\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.69\nvar_b = 1\nvar_c = 0.4\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "3665": {
        "category": "Correspondence",
        "question_ko": "55에 어떤 수를 더하여 7로 나눈 뒤 40을 더하여 5를 곱한 수가 555입니다. 어떤 수를 구하시오.",
        "question_en": "Add a number to 55, divide it by 7, then add 40 and multiply by 5 is 555. Find a number.",
        "answer_ko": "442",
        "answer_en": "442",
        "solution_abst_ko": "555 5 [OP_DIV] 40 [OP_SUB] 7 [OP_MUL] 55 [OP_SUB]",
        "solution_abst_en": "555 5 [OP_DIV] 40 [OP_SUB] 7 [OP_MUL] 55 [OP_SUB]",
        "solution_code_ko": "var_a = 555\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 40\nvar_e = var_c - var_d\nvar_f = 7\nvar_g = var_e * var_f\nvar_h = 55\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 555\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 40\nvar_e = var_c - var_d\nvar_f = 7\nvar_g = var_e * var_f\nvar_h = 55\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "3666": {
        "category": "Comparison",
        "question_ko": "(가) 나무토막 8개, (나) 나무토막 11개, (다) 나무토막 6개를 각각 한 줄로 높게 쌓으려고 한다. (가), (나), (다) 나무토막의 높이가 각각 2센티미터(㎝), 1.5센티미터(㎝), 2.5센티미터(㎝)일 때 가장 높게 쌓인 나무토막은 어떤 나무토막입니까?",
        "question_en": "We are trying to stack 8 pieces of (a) wood, 11 pieces of (b) wood, and 6 pieces of (c) wood each in a row. If the heights of the blocks (a), (b), (c) are each 2 centimeters (cm), 1.5 centimeters (cm), and 2.5 centimeters (cm) respectively, which of the stacked blocks is the tallest?",
        "answer_ko": "(나)",
        "answer_en": "(b)",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) (다) [OP_LIST_EOL] [OP_LIST_SOL] 2 8 [OP_MUL] 1.5 11 [OP_MUL] 2.5 6 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (a) (b) (c) [OP_LIST_EOL] [OP_LIST_SOL] 2 8 [OP_MUL] 1.5 11 [OP_MUL] 2.5 6 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nvar_c = '(다)'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nvar_e = 8\nvar_f = var_d * var_e\nvar_g = 1.5\nvar_h = 11\nvar_i = var_g * var_h\nvar_j = 2.5\nvar_k = 6\nvar_l = var_j * var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = '(a)'\nvar_b = '(b)'\nvar_c = '(c)'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nvar_e = 8\nvar_f = var_d * var_e\nvar_g = 1.5\nvar_h = 11\nvar_i = var_g * var_h\nvar_j = 2.5\nvar_k = 6\nvar_l = var_j * var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "3667": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 115미터(m) 인 기차가 1 분에 400미터(m) 를 달린다고 합니다. 이 기차가 같은 빠르기로 길이가 1.625킬로미터(㎞) 인 다리를 완전히 통과하려면 몇 분이 걸리겠습니까?",
        "question_en": "A train 115 meters (m) long travels at 400 meters (m) per minute. At the same speed, how many minutes would it take for the train to cross the entire length of the 1.625 km (km) bridge?",
        "answer_ko": "4.35",
        "answer_en": "4.35",
        "solution_abst_ko": "115 1.625 1000 [OP_MUL] [OP_ADD] 400 [OP_DIV]",
        "solution_abst_en": "115 1.625 1000 [OP_MUL] [OP_ADD] 400 [OP_DIV]",
        "solution_code_ko": "var_a = 115\nvar_b = 1.625\nvar_c = 1000\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nvar_f = 400\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 115\nvar_b = 1.625\nvar_c = 1000\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nvar_f = 400\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "3668": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 초등학교에서 나무를 심는데 (가) 반은 225그루를 심었고, (나) 반은 (가) 반보다 48그루 더 많이 심었고, (다) 반은 (가) 반보다 24그루 더 적게 심었습니다. (가), (나), (다) 세 반이 심은 나무의 수는 평균 몇 그루입니까?",
        "question_en": "In an elementary school, class (A) planted 225 trees, class (B) planted 48 trees more than class (A), and class (C) planted 24 fewer trees than class (A). How many trees did the three classes plant on average?",
        "answer_ko": "233",
        "answer_en": "233",
        "solution_abst_ko": "225 225 48 [OP_ADD] [OP_ADD] 225 24 [OP_SUB] [OP_ADD] 3 [OP_DIV]",
        "solution_abst_en": "225 225 48 [OP_ADD] [OP_ADD] 225 24 [OP_SUB] [OP_ADD] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 225\nvar_b = 225\nvar_c = 48\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nvar_f = 225\nvar_g = 24\nvar_h = var_f - var_g\nvar_i = var_e + var_h\nvar_j = 3\nvar_k = var_i / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 225\nvar_b = 225\nvar_c = 48\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nvar_f = 225\nvar_g = 24\nvar_h = var_f - var_g\nvar_i = var_e + var_h\nvar_j = 3\nvar_k = var_i / var_j\nprint(int(var_k))"
    },
    "3669": {
        "category": "Geometry",
        "question_ko": "축척이 1/250000인 지도에서 실제 거리가 5킬로미터(㎞)인 두 지점을 표시했습니다. 이 지점 사이의 거리를 자로 재었을 때 몇 센티미터(㎝)입니까?",
        "question_en": "On a map with a scale of 1/250000, we have marked two points with an actual distance of 5 kilometers (km). How many centimeters (cm) is the distance between these points measured with a ruler?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "5 100 1000 [OP_MUL] [OP_MUL] 1/250000 [OP_MUL]",
        "solution_abst_en": "5 100 1000 [OP_MUL] [OP_MUL] 1/250000 [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 100\nvar_c = 1000\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nvar_f = 4e-06\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 100\nvar_c = 1000\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nvar_f = 4e-06\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "3670": {
        "category": "Arithmetic calculation",
        "question_ko": "정국의 몸무게는 54킬로그램(㎏)보다 13그램(g) 가볍습니다. 정국이의 몸무게를 킬로그램(㎏)로 써보시오.",
        "question_en": "Jungkook's weight is 13 grams (g) lighter than 54 kilograms (kg). Write Jungkook's weight in kilograms (kg).",
        "answer_ko": "53.99",
        "answer_en": "53.99",
        "solution_abst_ko": "54 13 1000 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "54 13 1000 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 54\nvar_b = 13\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 54\nvar_b = 13\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "3671": {
        "category": "Arithmetic calculation",
        "question_ko": "친구들과 색종이 접기 놀이를 하기 위해 지민이는 친구 2명에게 각각 색종이 11장씩을 주고 27장을 새로 샀습니다. 현재 지민이가 가지고 있는 색종이의 수가 63장일 때, 처음에 지민이가 가지고 있던 색종이의 수는 몇 장일까요?",
        "question_en": "To fold colored paper with friends, Jimin gave 11 pieces of it to each of 2 friends and bought 27 new ones. If the number of colored papers Jimin currently has is 63, how many pieces of colored paper did Jimin initially have?",
        "answer_ko": "58",
        "answer_en": "58",
        "solution_abst_ko": "63 11 2 [OP_MUL] [OP_ADD] 27 [OP_SUB]",
        "solution_abst_en": "63 11 2 [OP_MUL] [OP_ADD] 27 [OP_SUB]",
        "solution_code_ko": "var_a = 63\nvar_b = 11\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nvar_f = 27\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 63\nvar_b = 11\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nvar_f = 27\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "3672": {
        "category": "Correspondence",
        "question_ko": "72를 어떤 수로 나누었더니 나누어 떨어졌습니다. 어떤 수를 가지고 48을 나누었더니 또 나누어 떨어졌습니다. 어떤 수에 들어갈 수 있는 값 중 가장 큰 값은 무엇입니까?",
        "question_en": "If a certain number is divisible by 72 without any remainder, then it is also divisible by 48. What is the largest value that can satisfy these conditions?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "72 48 [OP_GCD]",
        "solution_abst_en": "72 48 [OP_GCD]",
        "solution_code_ko": "var_a = 72\nvar_b = 48\nvar_c = math.gcd(int(var_b), int(var_a))\nprint(int(var_c))",
        "solution_code_en": "var_a = 72\nvar_b = 48\nvar_c = math.gcd(int(var_b), int(var_a))\nprint(int(var_c))"
    },
    "3673": {
        "category": "Arithmetic calculation",
        "question_ko": "일의 자리 숫자가 3이고, 소수 첫째 자리 숫자와 소수 둘째 자리 숫자가 0, 소수 셋째 자리 숫자가 6인 수가 있습니다. 이 수보다 큰 수 중에서 3.01보다는 작은 소수 세 자리 수는 모두 몇 개인지 구하시오.",
        "question_en": "There is a number with a one's digit of 3, 1st and 2nd decimal places of 0, and 3rd decimal place of 6. How many three-digit decimal numbers are less than 3.01 but greater than this number?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "0 9 1 [OP_LIST_ARANGE] 6 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "0 9 1 [OP_LIST_ARANGE] 6 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 0\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "3674": {
        "category": "Arithmetic calculation",
        "question_ko": "건물의 엘리베이터에는 1번부터 54번까지의 숫자가 있는 버튼이 있습니다. 이 버튼에 숫자 5가 몇 번 표시되는지 세십시오.",
        "question_en": "The elevators in the building have buttons numbered 1 through 54. Count how many times the digit 5 appears on these buttons.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "1 54 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 5 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 54 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 5 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 54\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 5\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 54\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 5\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))"
    },
    "3675": {
        "category": "Possibility",
        "question_ko": "수학책과 과학책 각각 1권씩을 책꽂이에 한 줄로 꽂는 경우의 수를 구하시오.",
        "question_en": "Find the number of ways to place one math book and one science book in a row on a bookshelf.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 수학책 과학책 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] math science [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM]",
        "solution_code_ko": "var_a = '수학책'\nvar_b = '과학책'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = len(list_a)\nvar_d = len(list_a)\nvar_e = 1\nvar_c = int(var_c)\nvar_d = int(var_d)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e * (var_c-i)\nprint(int(var_e))",
        "solution_code_en": "var_a = 'math'\nvar_b = 'science'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = len(list_a)\nvar_d = len(list_a)\nvar_e = 1\nvar_c = int(var_c)\nvar_d = int(var_d)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e * (var_c-i)\nprint(int(var_e))"
    },
    "3676": {
        "category": "Possibility",
        "question_ko": "정국, 지민, 윤기, 유나 중에서 중복을 허용하여 두 사람을 선택하려고 합니다. 선택할 수 있는 경우는 모두 몇 가지 입니까?",
        "question_en": "Among Jungkook, Jimin, Yoongi, and Yuna, we want to choose two people, including picking the same person. How many options are there in total?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 지민 윤기 유나 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Jimin Yoongi Yuna [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '지민'\nvar_c = '윤기'\nvar_d = '유나'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = var_e + var_f\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = 2\nvar_k = 1\nvar_i = int(var_i)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_i-i)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k / (i+1)\nprint(int(var_k))",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Jimin'\nvar_c = 'Yoongi'\nvar_d = 'Yuna'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = var_e + var_f\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = 2\nvar_k = 1\nvar_i = int(var_i)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_i-i)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k / (i+1)\nprint(int(var_k))"
    },
    "3677": {
        "category": "Comparison",
        "question_ko": "윤기는 7, 정국은 6, 유나는 9만큼 모았습니다. 가장 큰 숫자를 가진 사람은 누구입니까?",
        "question_en": "Yoongi collected 7, Jungkook 6, and Yuna 9. Who has the biggest number?",
        "answer_ko": "유나",
        "answer_en": "Yuna",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 유나 [OP_LIST_EOL] [OP_LIST_SOL] 7 6 9 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook Yuna [OP_LIST_EOL] [OP_LIST_SOL] 7 6 9 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nvar_c = '유나'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 7\nvar_e = 6\nvar_f = 9\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nvar_c = 'Yuna'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 7\nvar_e = 6\nvar_f = 9\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "3678": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 6을 곱했더니 72가 되었습니다. 어떤 수는?",
        "question_en": "When you multiply a particular number by 6, you get 72. what is that number?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "72 6 [OP_DIV]",
        "solution_abst_en": "72 6 [OP_DIV]",
        "solution_code_ko": "var_a = 72\nvar_b = 6\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 72\nvar_b = 6\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "3679": {
        "category": "Geometry",
        "question_ko": "바둑돌을 정사각형이 되도록 빈틈없이 규칙적으로 늘어놓았습니다. 한 변에 놓여있는 돌의 개수가 6개라면, 둘레에 놓인 바둑돌의 개수는 몇 개입니까?",
        "question_en": "The Go stones are arranged regulary without gaps to form a square. If the number of stones on one side is 6, what is the number of Go stones are placed around the perimeter of the square?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "6 4 [OP_MUL] 4 [OP_SUB]",
        "solution_abst_en": "6 4 [OP_MUL] 4 [OP_SUB]",
        "solution_code_ko": "var_a = 6\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3680": {
        "category": "Arithmetic calculation",
        "question_ko": "민아는 현재 달리기 결승점까지 200미터(m)를 앞두고 있고, 현재 1등인 친구는 민아가 있는 곳부터 결승점 사이의 정확히 중간 지점에 있습니다. 1등인 친구는 결승점에 도착하기 위해 몇 미터(m)를 더 뛰어야 합니까?",
        "question_en": "Mina is currently 200 meters (m) away from the finish line, and her friend, who is currently in the first place, is exactly halfway between Mina and the finish line. How many more meters (m) must the first-place friend run to reach the finish line?",
        "answer_ko": "100",
        "answer_en": "100",
        "solution_abst_ko": "200 2 [OP_DIV]",
        "solution_abst_en": "200 2 [OP_DIV]",
        "solution_code_ko": "var_a = 200\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 200\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "3681": {
        "category": "Correspondence",
        "question_ko": "3으로 어떤 수를 나누었더니 결과가 10이 나왔습니다. 어떤 수를 구하시오.",
        "question_en": "Dividing a number by 3 gives 10. Find the number.",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "10 3 [OP_MUL]",
        "solution_abst_en": "10 3 [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 10\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "3682": {
        "category": "Comparison",
        "question_ko": "한줄을 9명의 학생이 섰다. 오른쪽에서 7번째와 오른쪽에서 3번째 사이에 서 있는 학생은 몇 명인가?",
        "question_en": "9 students stood in a line. How many students are standing between 7th from the right and 3rd from the right?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "7 3 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "7 3 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 7\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 7\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3683": {
        "category": "Possibility",
        "question_ko": "빨간 주머니에는 서로 다른 숫자가 적힌 공 3개가 들어있고 파란 주머니에는 서로 다른 숫자가 적힌 공 5개가 들어있습니다. 태민이가 두 개의 주머니에서 각각 공을 한 개씩 고르는 경우의 수를 구하세요.",
        "question_en": "The red bag contains 3 balls with different numbers inscribed, and the blue bag contains 5 balls with different numbers inscribed. Find the number of ways Taemin picks one ball from each of the two pockets.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "3 1 [OP_COMB] 5 1 [OP_COMB] [OP_MUL]",
        "solution_abst_en": "3 1 [OP_COMB] 5 1 [OP_COMB] [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 1\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nvar_d = 5\nvar_e = 1\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f / (i+1)\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 3\nvar_b = 1\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nvar_d = 5\nvar_e = 1\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f / (i+1)\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "3684": {
        "category": "Arithmetic calculation",
        "question_ko": "근배는 매일 전날 줄넘기한 횟수의 두배만큼 줄넘기를 한다고 합니다. 근배가 첫날 15번을 했다면 넷째날에는 몇번을 할 지 구해보세요.",
        "question_en": "It is said that Geun-bae jump ropes twice as many times as he skipped the previous day. If Geun-bae did 15 times on the first day, find out how many times he will do it on the fourth day.",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "15 2 4 1 [OP_SUB] [OP_POW] [OP_MUL]",
        "solution_abst_en": "15 2 4 1 [OP_SUB] [OP_POW] [OP_MUL]",
        "solution_code_ko": "var_a = 15\nvar_b = 2\nvar_c = 4\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = var_b ** var_e\nvar_g = var_a * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 15\nvar_b = 2\nvar_c = 4\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = var_b ** var_e\nvar_g = var_a * var_f\nprint(int(var_g))"
    },
    "3685": {
        "category": "Possibility",
        "question_ko": "숫자 1, 6, 9를 중복하여 사용하여 다섯 자리 수를 만들려고 합니다. 만들 수 있는 두 자리 수는 모두 몇 개 입니까?",
        "question_en": "You want to create a five-digit number by using the digits 1, 6, and 9 allowing duplicates. How many two-digit numbers can you make?",
        "answer_ko": "243",
        "answer_en": "243",
        "solution_abst_ko": "[OP_LIST_SOL] 1 6 9 [OP_LIST_EOL] 5 [OP_LIST_GET_PRODUCT] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 6 9 [OP_LIST_EOL] 5 [OP_LIST_GET_PRODUCT] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 6\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 5\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 6\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 5\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "3686": {
        "category": "Arithmetic calculation",
        "question_ko": "원 모양의 운동장을 건우와 예준이가 서로 반대 방향으로 돌아서 만났다. 운동장의 둘레가 18킬로미터(㎞)이며 건우는 시속 5킬로미터(㎞)로 지아는 시속 4킬로미터(㎞)로 뛰었을 때 건우가 뛴 거리는 얼마인가?",
        "question_en": "Geon-wu and Jia turned in opposite directions at the circular playground and met each other. If the circumference of the field is 18 kilometers (km) and Geon-wu runs at 5 kilometers (km) per hour and Jia runs at 4 kilometers (km) per hour, how far did Gern-wu run?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "18 5 4 [OP_ADD] [OP_DIV] 5 [OP_MUL]",
        "solution_abst_en": "18 5 4 [OP_ADD] [OP_DIV] 5 [OP_MUL]",
        "solution_code_ko": "var_a = 18\nvar_b = 5\nvar_c = 4\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nvar_f = 5\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 18\nvar_b = 5\nvar_c = 4\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nvar_f = 5\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "3687": {
        "category": "Geometry",
        "question_ko": "한 꼭짓점에서 그을 수 있는 대각선의 개수가 1개인 다각형의 변의 개수는?",
        "question_en": "There is a polygon where only one diagonal can be drawn from a single vertex. How many edges does this polygon have?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "1 3 [OP_ADD]",
        "solution_abst_en": "1 3 [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "3688": {
        "category": "Arithmetic calculation",
        "question_ko": "별이네 학교 학생은 모두 1500명이고, 그중 남학생은 전체의 0.4입니다. 별이네 학교 여학생의 0.65가 체육을 좋아하지 않을 때, 체육을 좋아하는 여학생은 몇 명입니까?",
        "question_en": "There are a total of 1500 students at Byul's School, 0.4 of which are male students. If 0.65 of the female students at Byul's School don't like PE, how many girls like PE?",
        "answer_ko": "315",
        "answer_en": "315",
        "solution_abst_ko": "1500 1 0.4 [OP_SUB] [OP_MUL] 1 0.65 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "1500 1 0.4 [OP_SUB] [OP_MUL] 1 0.65 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 1500\nvar_b = 1\nvar_c = 0.4\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 1\nvar_g = 0.65\nvar_h = var_f - var_g\nvar_i = var_e * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1500\nvar_b = 1\nvar_c = 0.4\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 1\nvar_g = 0.65\nvar_h = var_f - var_g\nvar_i = var_e * var_h\nprint(int(var_i))"
    },
    "3689": {
        "category": "Possibility",
        "question_ko": "일곱 개의 숫자 0, 1, 2, 3, 4, 5, 6을 한 번씩 사용하여 일곱 자리 수를 만들었다. 이 수가 55의 배수일 때, 가장 큰 수를 구하여라.",
        "question_en": "The seven digits 0, 1, 2, 3, 4, 5, and 6 are used once to form a seven-digit number. If the number formed is a multiple of 55, find the largest number that can be made.",
        "answer_ko": "6431205",
        "answer_en": "6431205",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 4 5 6 [OP_LIST_EOL] 7 [OP_LIST_GET_PERM] 55 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 4 5 6 [OP_LIST_EOL] 7 [OP_LIST_GET_PERM] 55 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nvar_f = 5\nvar_g = 6\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h = 7\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_h))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_i = 55\nlist_c = []\nvar_i = int(var_i)\nfor i in list_b:\n    i = int(i)\n    if i % var_i == 0:\n        list_c.append(i)\nvar_j = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_k = list_d[-var_j]\nprint(int(var_k))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nvar_f = 5\nvar_g = 6\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h = 7\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_h))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_i = 55\nlist_c = []\nvar_i = int(var_i)\nfor i in list_b:\n    i = int(i)\n    if i % var_i == 0:\n        list_c.append(i)\nvar_j = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_k = list_d[-var_j]\nprint(int(var_k))"
    },
    "3690": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 연속된 홀수의 합은 3개의 홀수 중 가장 큰 홀수보다 28만큼 큽니다. 3개의 홀수 중에서 가장 작은 수를 쓰시오.",
        "question_en": "The sum of 3 consecutive odd numbers is 28 greater than the largest number of the 3 odd numbers. Write the smallest of the three odd numbers.",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "28 2 1 [OP_MUL] 2 2 [OP_MUL] [OP_ADD] [OP_ADD] 3 1 [OP_SUB] [OP_DIV] 2 2 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "28 2 1 [OP_MUL] 2 2 [OP_MUL] [OP_ADD] [OP_ADD] 3 1 [OP_SUB] [OP_DIV] 2 2 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 28\nvar_b = 2\nvar_c = 1\nvar_d = var_b * var_c\nvar_e = 2\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = var_d + var_g\nvar_i = var_a + var_h\nvar_j = 3\nvar_k = 1\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nvar_n = 2\nvar_o = 2\nvar_p = var_n * var_o\nvar_q = var_m - var_p\nprint(int(var_q))",
        "solution_code_en": "var_a = 28\nvar_b = 2\nvar_c = 1\nvar_d = var_b * var_c\nvar_e = 2\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = var_d + var_g\nvar_i = var_a + var_h\nvar_j = 3\nvar_k = 1\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nvar_n = 2\nvar_o = 2\nvar_p = var_n * var_o\nvar_q = var_m - var_p\nprint(int(var_q))"
    },
    "3691": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 200까지의 자연수 중 짝수를 모두 더한 값은 얼마입니까?",
        "question_en": "What is the sum of all even numbers from 1 to 200?",
        "answer_ko": "10100",
        "answer_en": "10100",
        "solution_abst_ko": "1 200 [OP_LIST_EVEN] [OP_LIST_SUM]",
        "solution_abst_en": "1 200 [OP_LIST_EVEN] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 200\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nprint(int(var_c))",
        "solution_code_en": "var_a = 1\nvar_b = 200\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nprint(int(var_c))"
    },
    "3692": {
        "category": "Possibility",
        "question_ko": "100부터 9999까지의 숫자 중 25의 배수이고 각 자리의 숫자의 합이 17인 자연수는 모두 몇 개인가?",
        "question_en": "How many natural numbers from 100 to 9999 are multiples of 25 and the sum of each digit is 17?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "100 9999 1 [OP_LIST_ARANGE] 25 [OP_LIST_DIVISIBLE] [OP_LIST_NUM2SUM] 17 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "100 9999 1 [OP_LIST_ARANGE] 25 [OP_LIST_DIVISIBLE] [OP_LIST_NUM2SUM] 17 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 100\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 25\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 17\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))",
        "solution_code_en": "var_a = 100\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 25\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 17\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))"
    },
    "3693": {
        "category": "Arithmetic calculation",
        "question_ko": "1킬로미터(㎞)를 가는 데 0.08리터(L)의 휘발유를 소모하는 자동차가 있습니다. 이 자동차를 이용하여 1시간에 80킬로미터(㎞)를 움직이는 빠르기로 2시간 36분을 이동하였을 때, 소모한 휘발유의 양은 몇 리터(L)인지 구하시오.",
        "question_en": "There is a car that consumes 0.08 liters (l) of gasoline to travel 1 kilometer (km). Find the amount of gasoline consumed in liters (L) when this car traveled for 2 hours and 36 minutes at a speed of 80 kilometers (km) per hour.",
        "answer_ko": "16.64",
        "answer_en": "16.64",
        "solution_abst_ko": "0.08 80 2 36 60 [OP_DIV] [OP_ADD] [OP_MUL] [OP_MUL]",
        "solution_abst_en": "0.08 80 2 36 60 [OP_DIV] [OP_ADD] [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 0.08\nvar_b = 80\nvar_c = 2\nvar_d = 36\nvar_e = 60\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nvar_h = var_b * var_g\nvar_i = var_a * var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 0.08\nvar_b = 80\nvar_c = 2\nvar_d = 36\nvar_e = 60\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nvar_h = var_b * var_g\nvar_i = var_a * var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "3694": {
        "category": "Geometry",
        "question_ko": "지름이 14 센티미터(㎝)인 훌라후프를 만드려고 합니다. 훌라후프의 반지름의 길이는 몇 센티미터(㎝)인가요?",
        "question_en": "You are going to make a hula hoop that is 14 centimeters (cm) in diameter. How many centimeters (cm) is the radius of the hula hoop?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "14 2 [OP_DIV]",
        "solution_abst_en": "14 2 [OP_DIV]",
        "solution_code_ko": "var_a = 14\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 14\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "3695": {
        "category": "Correspondence",
        "question_ko": "4로 나누어 떨어지고 백의 자리 숫자가 3인 세 자리 수는 모두 몇 개입니까?",
        "question_en": "How many three-digit numbers are there that are divisible by 4 and have a 3 in the hundreds?",
        "answer_ko": "25",
        "answer_en": "25",
        "solution_abst_ko": "3 100 [OP_MUL] 3 100 [OP_MUL] 99 [OP_ADD] 1 [OP_LIST_ARANGE] 4 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "3 100 [OP_MUL] 3 100 [OP_MUL] 99 [OP_ADD] 1 [OP_LIST_ARANGE] 4 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 3\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = 100\nvar_f = var_d * var_e\nvar_g = 99\nvar_h = var_f + var_g\nvar_i = 1\nlist_a = [i for i in range(var_c, var_h + 1, var_i)]\nvar_j = 4\nlist_b = []\nvar_j = int(var_j)\nfor i in list_a:\n    i = int(i)\n    if i % var_j == 0:\n        list_b.append(i)\nvar_k = len(list_b)\nprint(int(var_k))",
        "solution_code_en": "var_a = 3\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = 100\nvar_f = var_d * var_e\nvar_g = 99\nvar_h = var_f + var_g\nvar_i = 1\nlist_a = [i for i in range(var_c, var_h + 1, var_i)]\nvar_j = 4\nlist_b = []\nvar_j = int(var_j)\nfor i in list_a:\n    i = int(i)\n    if i % var_j == 0:\n        list_b.append(i)\nvar_k = len(list_b)\nprint(int(var_k))"
    },
    "3696": {
        "category": "Geometry",
        "question_ko": "한 모서리의 길이가 3센티미터(㎝)인 정육면체가 27개 있습니다. 이 정육면체들을 쌓아서 다시 정육면체를 만든다고 할 때, 쌓여진 정육면체의 겉넓이는 얼마입니까?",
        "question_en": "There are 27 cubes with a side of 3 centimeters (cm). If you stack these cubes to make another cube, what is the surface area of the stacked cubes?",
        "answer_ko": "486",
        "answer_en": "486",
        "solution_abst_ko": "3 27 1/3 [OP_POW] [OP_MUL] 2 [OP_POW] 6 [OP_MUL]",
        "solution_abst_en": "3 27 1/3 [OP_POW] [OP_MUL] 2 [OP_POW] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 27\nvar_c = 0.3333333333333333\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e ** var_f\nvar_h = 6\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 3\nvar_b = 27\nvar_c = 0.3333333333333333\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e ** var_f\nvar_h = 6\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "3697": {
        "category": "Possibility",
        "question_ko": "2가지의 과일을 구매하려고 합니다. 과일 가게에서 판매하는 과일이 사과, 복숭아, 배, 참외라면 가능한 경우의 수는 모두 몇 가지입니까?",
        "question_en": "I would like to buy 2 kinds of fruit. If the fruits sold in the fruit shop are Apples, Peaches, Pears, and Melons, how many possible ways are there?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 복숭아 배 참외 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] Apple Peach Pear Melon [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '복숭아'\nvar_c = '배'\nvar_d = '참외'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g / (i+1)\nprint(int(var_g))",
        "solution_code_en": "var_a = 'Apple'\nvar_b = 'Peach'\nvar_c = 'Pear'\nvar_d = 'Melon'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g / (i+1)\nprint(int(var_g))"
    },
    "3698": {
        "category": "Comparison",
        "question_ko": "털실을 지훈이는 7.8 미터(m), 동준이는 6.9 미터(m), 초원이는 7.2 미터(m) 가지고 있습니다. 가지고 있는 털실의 길이가 가장 긴 사람은 누구인지 답을 구해 보세요.",
        "question_en": "Jihoon has 7.8 meters (m) of yarn, Dongjun has 6.9 meters (m), and Chowon has 7.2 meters (m). Find out who has the longest yarn length.",
        "answer_ko": "지훈",
        "answer_en": "Jihoon",
        "solution_abst_ko": "[OP_LIST_SOL] 지훈 동준 초원 [OP_LIST_EOL] [OP_LIST_SOL] 7.8 6.9 7.2 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jihoon Dongjun Chowon [OP_LIST_EOL] [OP_LIST_SOL] 7.8 6.9 7.2 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '지훈'\nvar_b = '동준'\nvar_c = '초원'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 7.8\nvar_e = 6.9\nvar_f = 7.2\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Jihoon'\nvar_b = 'Dongjun'\nvar_c = 'Chowon'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 7.8\nvar_e = 6.9\nvar_f = 7.2\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "3699": {
        "category": "Comparison",
        "question_ko": "지민이네 반 전체 학생 수는 35명입니다. 지민이가 반에서 10번째로 키가 크다면 지민이보다 키가 작은 학생은 모두 몇 명인지 구하세요.",
        "question_en": "The total number of students in Jimin's class is 35. If Jimin is the 10th tallest student in the class, find how many students are shorter than Jimin.",
        "answer_ko": "25",
        "answer_en": "25",
        "solution_abst_ko": "35 10 [OP_SUB]",
        "solution_abst_en": "35 10 [OP_SUB]",
        "solution_code_ko": "var_a = 35\nvar_b = 10\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 35\nvar_b = 10\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "3700": {
        "category": "Comparison",
        "question_ko": "학생은 모두 13명입니다. 호석이는 오른쪽에서 9번째에 서있고 민영이는 왼쪽에서 8번째에 서있습니다. 호석이와 민영이 사이에는 모두 몇 명이 서있습니까?",
        "question_en": "There are 13 students in all. Hoseok stands 9th from the right and Minyoung stands 8th from the left. Find how many people are in between Hoseok and Minyoung.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "8 9 [OP_ADD] 13 [OP_SUB] 2 [OP_SUB]",
        "solution_abst_en": "8 9 [OP_ADD] 13 [OP_SUB] 2 [OP_SUB]",
        "solution_code_ko": "var_a = 8\nvar_b = 9\nvar_c = var_a + var_b\nvar_d = 13\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 8\nvar_b = 9\nvar_c = var_a + var_b\nvar_d = 13\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "3701": {
        "category": "Correspondence",
        "question_ko": "35에서 어떤 수를 빼고 2를 곱한 뒤 12를 더하여 8로 나눈 수가 9입니다. 어떤 수를 구하시오.",
        "question_en": "Subtracting this number from 35, and then multiplying it by 2, adding 12, and dividing it by 8 is 9. Find this number.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "35 9 8 [OP_MUL] 12 [OP_SUB] 2 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "35 9 8 [OP_MUL] 12 [OP_SUB] 2 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 35\nvar_b = 9\nvar_c = 8\nvar_d = var_b * var_c\nvar_e = 12\nvar_f = var_d - var_e\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = var_a - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 35\nvar_b = 9\nvar_c = 8\nvar_d = var_b * var_c\nvar_e = 12\nvar_f = var_d - var_e\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = var_a - var_h\nprint(int(var_i))"
    },
    "3702": {
        "category": "Comparison",
        "question_ko": "인혁이와 경수는 선물 포장용 끈을 가지고 있습니다. 인혁이가 가지고 있는 끈은 97.5센티미터(㎝)이고, 경수가 가지고 있는 끈은 97센티미터(㎝)보다 3밀리미터(㎜) 더 깁니다. 끈의 길이가 더 짧은 사람은 누구입니까?",
        "question_en": "Inhyuk and Kyungsoo have a gift wrapping string. The string that Inhyeok has is 97.5 centimeters (cm), and the string that Kyungsoo has is 3 millimeters (mm) longer than 97 centimeters (cm). Who has a shorter string?",
        "answer_ko": "경수",
        "answer_en": "Kyungsoo",
        "solution_abst_ko": "[OP_LIST_SOL] 인혁 경수 [OP_LIST_EOL] [OP_LIST_SOL] 97.5 97 3 10 [OP_DIV] [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Inhyuk Kyungsoo [OP_LIST_EOL] [OP_LIST_SOL] 97.5 97 3 10 [OP_DIV] [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '인혁'\nvar_b = '경수'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 97.5\nvar_d = 97\nvar_e = 3\nvar_f = 10\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Inhyuk'\nvar_b = 'Kyungsoo'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 97.5\nvar_d = 97\nvar_e = 3\nvar_f = 10\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "3703": {
        "category": "Geometry",
        "question_ko": "현주네 학급 11명의 학생이 십일각형을 그리고 서 있습니다. 모든 학생이 자신의 양옆에 서 있는 친구를 제외하고 한 번씩 하이파이브를 할 때, 하이파이브는 모두 몇 번 이루어집니까?",
        "question_en": "11 students in Hyeonju's class are standing in a hendecagonal shape. If every student exchanges a high-five once, except for the friend standing next to them, how many high-fives will there be?",
        "answer_ko": "44",
        "answer_en": "44",
        "solution_abst_ko": "11 11 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "11 11 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 11\nvar_b = 11\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 11\nvar_b = 11\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "3704": {
        "category": "Arithmetic calculation",
        "question_ko": "수지는 어제 줄넘기를 247개 했으며, 오늘은 어제보다 131개 더 많이 했습니다. 수지가 이틀 동안 한 줄넘기는 몇 개인지 구하시오.",
        "question_en": "Suzy did 247 jump ropes yesterday and 131 more jumps today than yesterday. Find out how many jump ropes Suzy did in two days.",
        "answer_ko": "625",
        "answer_en": "625",
        "solution_abst_ko": "247 247 131 [OP_ADD] [OP_ADD]",
        "solution_abst_en": "247 247 131 [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 247\nvar_b = 247\nvar_c = 131\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 247\nvar_b = 247\nvar_c = 131\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "3705": {
        "category": "Arithmetic calculation",
        "question_ko": "유정이는 공책을 몇 권 가지고 있었습니다. 그 중에서 언니에게 5권을 주고, 남은 것의 절반을 동생에게 주었습니다. 공책이 4권 남았다면 처음에 유정이는 공책을 몇 권 가지고 있었습니까?",
        "question_en": "Yoojung had several notebooks. Among them, she gave 5 books to her older sister and gave half of the rest to her younger sister. If there are 4 notebooks left, how many notebooks did Yoojung have at first?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "4 2 [OP_MUL] 5 [OP_ADD]",
        "solution_abst_en": "4 2 [OP_MUL] 5 [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3706": {
        "category": "Comparison",
        "question_ko": "학생들이 한 줄로 서 있을 때, 지민이가 석진이보다 뒤에 있으며 석진이의 앞에는 4명이, 지민이의 뒤에는 7명이 서 있습니다. 석진이와 지민이 사이에는 3명이 서 있을 때, 줄을 서 있는 학생은 모두 몇 명입니까?",
        "question_en": "When the students are standing in a line, Jimin is behind Seokjin, with 4 in front of Seokjin and 7 behind Jimin. When 3 people are standing between Seokjin and Jimin, how many students are in line?",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "4 7 [OP_ADD] 3 [OP_ADD] 2 [OP_ADD]",
        "solution_abst_en": "4 7 [OP_ADD] 3 [OP_ADD] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "3707": {
        "category": "Correspondence",
        "question_ko": "두 자리 수 A5-2A=B7이 나옵니다. A, B가 서로 다른 두 수라면 A+B의 값을 구하시오",
        "question_en": "Subtract 2A from the two-digit number A5 to get B7. If A and B are two different numbers, find the value of A+B.",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "A5-2A=B7 A [OP_DIGIT_UNK_SOLVER] A5-2A=B7 B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_abst_en": "A5-2A=B7 A [OP_DIGIT_UNK_SOLVER] A5-2A=B7 B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_code_ko": "var_a = 'A5-2A=B7'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 'A5-2A=B7'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 'A5-2A=B7'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 'A5-2A=B7'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "3708": {
        "category": "Correspondence",
        "question_ko": "A, B는 두 자리 수입니다. 23보다 8작은 A가 있고 B에 7을 더하면 18일때 A-B를 구하시오.",
        "question_en": "A and B are two-digit numbers. Find A-B when A is 8 less than 23, and B plus 7 is 18.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "23 8 [OP_SUB] 18 7 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "23 8 [OP_SUB] 18 7 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 23\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 18\nvar_e = 7\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 23\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 18\nvar_e = 7\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "3709": {
        "category": "Arithmetic calculation",
        "question_ko": "(가) 동물 45마리와 (나) 동물 32마리를 기릅니다. (나) 동물과 (다) 동물을 합하면 (가) 동물보다 8마리 적습니다. (다) 동물은 몇 마리입니까?",
        "question_en": "You have 45 (A) animals and 32 (B) animals. (B) animals and (C) animals are 8 fewer than (A) animals. How many (C) animals are there?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "45 32 [OP_SUB] 8 [OP_SUB]",
        "solution_abst_en": "45 32 [OP_SUB] 8 [OP_SUB]",
        "solution_code_ko": "var_a = 45\nvar_b = 32\nvar_c = var_a - var_b\nvar_d = 8\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 45\nvar_b = 32\nvar_c = var_a - var_b\nvar_d = 8\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3710": {
        "category": "Correspondence",
        "question_ko": "마라톤 대회에 14명의 선수가 참가합니다. 선수당 5병의 물이 필요하다고 합니다. 현재 68병의 물이 있다면 물이 부족하지 않기 위해서 몇 병의 물이 더 필요합니까?",
        "question_en": "14 runners participate in the marathon event. It is said that each player needs 5 bottles of water. If you currently have 68 bottles of water, how many more bottles do you need to avoid running out?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "14 5 [OP_MUL] 68 [OP_SUB]",
        "solution_abst_en": "14 5 [OP_MUL] 68 [OP_SUB]",
        "solution_code_ko": "var_a = 14\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 68\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 14\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 68\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3711": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중에서 가장 큰 수와 그 다음으로 큰 수로 나눈 나머지는 얼마입니까?",
        "question_en": "There are three numbers 10, 11, and 12. What is the remainder when divided by the largest number and the next largest number?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_MOD]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_MOD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = var_e % var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = var_e % var_g\nprint(int(var_h))"
    },
    "3712": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 학교의 학생 수는 1256명이다. 이 중 1학년은 1학년을 제외한 학생 수보다 408명 적습니다. 1학년은 몇 명입니까?",
        "question_en": "If 1256 students are enrolled in a school, the first graders are 408 fewer than the total of students excluding first year. How many students are in first grade?",
        "answer_ko": "424",
        "answer_en": "424",
        "solution_abst_ko": "1256 408 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "1256 408 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 1256\nvar_b = 408\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 1256\nvar_b = 408\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "3713": {
        "category": "Arithmetic calculation",
        "question_ko": "두 자리 수끼리의 뺄셈에서 빼어지는 수의 일의 자리 숫자 3을 5로 잘못 보았습니다. 또 빼는 수의 십의 자리 숫자와 일의 자리 숫자를 바꾸어 25라고 잘못 보고 계산하였더니 그 값이 60이 되었습니다. 바르게 계산한 결과를 구하시오.",
        "question_en": "In a two-digit number subtraction, the unit digit of the minuend was originally 3, but it was mistaken for 5. Also, by changing the tens digit and the unit digit of the subtrahend, mistakenly thought that it was 25 and calculated it as 60. Find the result of the correct calculation.",
        "answer_ko": "31",
        "answer_en": "31",
        "solution_abst_ko": "60 1 3 5 [OP_SUB] [OP_MUL] [OP_ADD] 52 25 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "60 1 3 5 [OP_SUB] [OP_MUL] [OP_ADD] 52 25 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 60\nvar_b = 1\nvar_c = 3\nvar_d = 5\nvar_e = var_c - var_d\nvar_f = var_b * var_e\nvar_g = var_a + var_f\nvar_h = 52\nvar_i = 25\nvar_j = var_h - var_i\nvar_k = var_g - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 60\nvar_b = 1\nvar_c = 3\nvar_d = 5\nvar_e = var_c - var_d\nvar_f = var_b * var_e\nvar_g = var_a + var_f\nvar_h = 52\nvar_i = 25\nvar_j = var_h - var_i\nvar_k = var_g - var_j\nprint(int(var_k))"
    },
    "3714": {
        "category": "Arithmetic calculation",
        "question_ko": "밀가루를 작은 상자에 500그램(g)씩 나누어 담으면 3킬로그램(㎏)이 남습니다. 또 900그램(g)씩 나누어 담으면 200그램(g)이 남습니다. 밀가루는 모두 몇 킬로그램(㎏)있습니까?",
        "question_en": "If you divide the flour into small boxes by 500 grams (g), you have 3 kilograms (kg) left over. Also, 200 grams (g) are left if you divide it into 900 grams (g) each. How many kilograms (kg) is flour in total?",
        "answer_ko": "6.50",
        "answer_en": "6.5",
        "solution_abst_ko": "3 1000 [OP_MUL] 200 [OP_SUB] 900 500 [OP_SUB] [OP_DIV] 500 [OP_MUL] 3 1000 [OP_MUL] [OP_ADD] 1000 [OP_DIV]",
        "solution_abst_en": "3 1000 [OP_MUL] 200 [OP_SUB] 900 500 [OP_SUB] [OP_DIV] 500 [OP_MUL] 3 1000 [OP_MUL] [OP_ADD] 1000 [OP_DIV]",
        "solution_code_ko": "var_a = 3\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 200\nvar_e = var_c - var_d\nvar_f = 900\nvar_g = 500\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 500\nvar_k = var_i * var_j\nvar_l = 3\nvar_m = 1000\nvar_n = var_l * var_m\nvar_o = var_k + var_n\nvar_p = 1000\nvar_q = var_o / var_p\nprint('{:.2f}'.format(round(var_q+1e-10,2)))",
        "solution_code_en": "var_a = 3\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 200\nvar_e = var_c - var_d\nvar_f = 900\nvar_g = 500\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 500\nvar_k = var_i * var_j\nvar_l = 3\nvar_m = 1000\nvar_n = var_l * var_m\nvar_o = var_k + var_n\nvar_p = 1000\nvar_q = var_o / var_p\nprint('{:.2f}'.format(round(var_q+1e-10,2)))"
    },
    "3715": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수의 평균은 8입니다. 이 중 한 개의 수를 골라 8로 바꾸었더니 평균이 9가 되었습니다. 바꾼 수는 원래 얼마입니까?",
        "question_en": "The average of the five numbers is 8. If you take one of these numbers and change it to 8, the average is 9. What is the original number before the change?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "8 5 [OP_MUL] 9 5 [OP_MUL] 8 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "8 5 [OP_MUL] 9 5 [OP_MUL] 8 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 8\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = 8\nvar_h = var_f - var_g\nvar_i = var_c - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 8\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = 8\nvar_h = var_f - var_g\nvar_i = var_c - var_h\nprint(int(var_i))"
    },
    "3716": {
        "category": "Geometry",
        "question_ko": "반지름이 10센티미터(㎝)인 원 안에 딱 맞는 마름모 모양의 색종이가 있다. 이 색종이의 네 변의 한가운데를 모두 이어서 그린 마름모의 넓이를 구하라.",
        "question_en": "There is a colored paper in the shape of a rhombus that fits inside a circle with a radius of 10 centimeters (cm). Find the area of the rhombus drawn by connecting the middles of all four sides of this piece of colored paper.",
        "answer_ko": "100",
        "answer_en": "100",
        "solution_abst_ko": "10 10 [OP_MUL]",
        "solution_abst_en": "10 10 [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 10\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 10\nvar_b = 10\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "3717": {
        "category": "Comparison",
        "question_ko": "1.4, 9/10, 1.2, 0.5, 13/10 5개 숫자 중에서 1.1보다 작거나 같은 숫자를 고르면 총 몇 개 일까요?",
        "question_en": "How many numbers are less than or equal to 1.1 out of five numbers: 1.4, 9/10, 1.2, 0.5, and 13/10?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i <= var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i <= var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "3718": {
        "category": "Arithmetic calculation",
        "question_ko": "(가) 물건이 한 상자에 6개씩 4상자에 들어 있습니다. (가) 물건을 한 상자에 3개씩 넣어서 포장하려면 상자는 몇 개 필요합니까?",
        "question_en": "Item (A)s are divided into 4 boxes with 6 in each box. How many boxes are needed to pack 3 items in a box?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "6 4 [OP_MUL] 3 [OP_DIV]",
        "solution_abst_en": "6 4 [OP_MUL] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "3719": {
        "category": "Correspondence",
        "question_ko": "두 자리 수 A7+3B=73이 나옵니다. 이 때 A의 값으로 가능한 값은 얼마 입니까?",
        "question_en": "You get the two-digit number A7+3B=73. What is the possible value of A at this time?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "A7+3B=73 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A7+3B=73 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A7+3B=73'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A7+3B=73'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "3720": {
        "category": "Correspondence",
        "question_ko": "A는 100개씩 묶음 1개와 10개씩 묶음 23개와 동일한 수입니다. B는 172에서 4번 105씩 커지도록 뛰어서 센 수일 때, A와 B를 더하면 얼마입니까?",
        "question_en": "A is the same as 1 group of 100 and 23 groups of 10. If B is the number that is increased 4 times by 105 from 172, what is the sum of A and B?",
        "answer_ko": "922",
        "answer_en": "922",
        "solution_abst_ko": "100 1 [OP_MUL] 10 23 [OP_MUL] [OP_ADD] 172 105 4 [OP_MUL] [OP_ADD] [OP_ADD]",
        "solution_abst_en": "100 1 [OP_MUL] 10 23 [OP_MUL] [OP_ADD] 172 105 4 [OP_MUL] [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 100\nvar_b = 1\nvar_c = var_a * var_b\nvar_d = 10\nvar_e = 23\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 172\nvar_i = 105\nvar_j = 4\nvar_k = var_i * var_j\nvar_l = var_h + var_k\nvar_m = var_g + var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 100\nvar_b = 1\nvar_c = var_a * var_b\nvar_d = 10\nvar_e = 23\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 172\nvar_i = 105\nvar_j = 4\nvar_k = var_i * var_j\nvar_l = var_h + var_k\nvar_m = var_g + var_l\nprint(int(var_m))"
    },
    "3721": {
        "category": "Geometry",
        "question_ko": "어떤 평행사변형을 잘라서 사다리꼴을 만들었습니다. 이 사다리꼴의 윗변은 15센티미터(㎝)이고, 아랫변은 9센티미터(㎝)입니다. 사다리꼴의 높이가 12센티미터(㎝)일 때, 이 사다리꼴과 같은 넓이를 갖는 정사각형의 한 변의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": " A trapezoid was created by cutting a parallelogram. The upper side of this trapezoid is 15 centimeters (cm) and the lower side is 9 centimeters (cm). If the height of the trapezoid is 12 centimeters (cm), how many centimeters (cm) is the side of a square with the same area as the trapezoid?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "15 9 [OP_ADD] 12 [OP_MUL] 2 [OP_DIV] 1/2 [OP_POW]",
        "solution_abst_en": "15 9 [OP_ADD] 12 [OP_MUL] 2 [OP_DIV] 1/2 [OP_POW]",
        "solution_code_ko": "var_a = 15\nvar_b = 9\nvar_c = var_a + var_b\nvar_d = 12\nvar_e = var_c * var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 15\nvar_b = 9\nvar_c = var_a + var_b\nvar_d = 12\nvar_e = var_c * var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))"
    },
    "3722": {
        "category": "Possibility",
        "question_ko": "옷장에 빨간 옷 3개, 노랑 옷 7개가 있습니다. 입을 수 있는 옷은 모두 몇 가지입니까?",
        "question_en": "There are 3 red clothes and 7 yellow clothes in the closet. How many clothes can you wear?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "3 7 [OP_ADD]",
        "solution_abst_en": "3 7 [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "3723": {
        "category": "Correspondence",
        "question_ko": "111111을 3으로 나눈 몫의 각 자리 수의 합을 구하시오.",
        "question_en": "Find the sum of each digit of the quotient of 111111 divided by 3.",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "111111 3 [OP_DIV] [OP_NUM2LIST] [OP_LIST_SUM]",
        "solution_abst_en": "111111 3 [OP_DIV] [OP_NUM2LIST] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 111111\nvar_b = 3\nvar_c = var_a / var_b\nlist_a = []\nvar_c = int(var_c)\nwhile var_c//10 > 0:\n    list_a.append(var_c%10)\n    var_c = var_c//10\nlist_a.append(var_c%10)\nlist_a = list_a[::-1]\nlist_a = [float(i) for i in list_a]\nvar_d = sum(list_a)\nprint(int(var_d))",
        "solution_code_en": "var_a = 111111\nvar_b = 3\nvar_c = var_a / var_b\nlist_a = []\nvar_c = int(var_c)\nwhile var_c//10 > 0:\n    list_a.append(var_c%10)\n    var_c = var_c//10\nlist_a.append(var_c%10)\nlist_a = list_a[::-1]\nlist_a = [float(i) for i in list_a]\nvar_d = sum(list_a)\nprint(int(var_d))"
    },
    "3724": {
        "category": "Correspondence",
        "question_ko": "선생님이 2학년 학생에게 8204개의 사탕을 같은 수로 주었을 때, 학생 1인당 28개의 사탕을 주었더니 사탕이 하나도 남지 않았습니다. 2학년은 모두 몇 명입니까?",
        "question_en": "When a teacher gave an equal amount of 8204 candies, with 28 candies per student, to the 2nd graders, and there were no candies left. How many 2nd graders are there?",
        "answer_ko": "293",
        "answer_en": "293",
        "solution_abst_ko": "1 28 8204 [OP_DIV] [OP_DIV]",
        "solution_abst_en": "1 28 8204 [OP_DIV] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 28\nvar_c = 8204\nvar_d = var_b / var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 28\nvar_c = 8204\nvar_d = var_b / var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "3725": {
        "category": "Geometry",
        "question_ko": "가로 20센티미터(㎝), 세로 12미터(m), 높이 10센티미터(㎝)인 직육면체 모양의 벽돌이 있습니다. 이 벽돌을 잘라서 만들 수 있는 가장 큰 정육면체 모양의 벽돌의 부피는 얼마입니까?",
        "question_en": "There is a cuboid-shaped brick that is 20 centimeters (cm) long, 12 meters (m) wide, and 10 centimeters (cm) high. What is the volume of the largest cube-shaped brick that can be made by cutting this brick?",
        "answer_ko": "1000",
        "answer_en": "1000",
        "solution_abst_ko": "[OP_LIST_SOL] 20 12 10 [OP_LIST_EOL] 1 [OP_LIST_MIN] 1 [OP_LIST_MIN] 3 [OP_POW]",
        "solution_abst_en": "[OP_LIST_SOL] 20 12 10 [OP_LIST_EOL] 1 [OP_LIST_MIN] 1 [OP_LIST_MIN] 3 [OP_POW]",
        "solution_code_ko": "var_a = 20\nvar_b = 12\nvar_c = 10\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nvar_f = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = 3\nvar_i = var_g ** var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 20\nvar_b = 12\nvar_c = 10\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nvar_f = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = 3\nvar_i = var_g ** var_h\nprint(int(var_i))"
    },
    "3726": {
        "category": "Correspondence",
        "question_ko": "어떤 소수를 12 로 나누어야 할 것을 잘못하여 곱했더니 84.6 이 되었습니다. 어떤 소수를 구하시오.",
        "question_en": "When I mistakenly multiplied a decimal that should be divided by 12, I got 84.6. Find the original decimal.",
        "answer_ko": "7.05",
        "answer_en": "7.05",
        "solution_abst_ko": "84.6 12 [OP_DIV]",
        "solution_abst_en": "84.6 12 [OP_DIV]",
        "solution_code_ko": "var_a = 84.6\nvar_b = 12\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 84.6\nvar_b = 12\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "3727": {
        "category": "Geometry",
        "question_ko": "직육면체 모양의 상자에서 어느 한 모서리와 꼬인 위치에 있는 모서리의 수를 모두 구하면 얼마인가요?",
        "question_en": "How many faces are there in a regular tetrahedron?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "4",
        "solution_abst_en": "4",
        "solution_code_ko": "var_a = 4\nprint(int(var_a))",
        "solution_code_en": "var_a = 4\nprint(int(var_a))"
    },
    "3728": {
        "category": "Arithmetic calculation",
        "question_ko": "민영이는 조미료로 소금 9번, 후추 3번, 다시다를 3번 뿌렸습니다. 유정이는 소금을 7번 뿌리고 후추는 다시다보다 2번 더 적게 뿌렸습니다. 유정이가 뿌린 조미료가 민영이가 뿌린 조미료보다 2번 더 많을 때, 유정이가 뿌린 후추는 몇 번인지 구하시오",
        "question_en": "Min-young used 8 tablespoons of salt, 3 tablespoons of pepper and 3 tablespoons of sugar. Yujeong used 7 tablespoons of salt and 2 tablespoons less than sugar. If Yujeong used twice as much spices as Min-young used, how many spoons of pepper did Yujeong use?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "9 3 [OP_ADD] 5 [OP_ADD] 7 [OP_SUB] 2 [OP_SUB] 2 [OP_FDIV]",
        "solution_abst_en": "9 3 [OP_ADD] 5 [OP_ADD] 7 [OP_SUB] 2 [OP_SUB] 2 [OP_FDIV]",
        "solution_code_ko": "var_a = 9\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 7\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g - var_h\nvar_j = 2\nvar_k = var_i // var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 9\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 7\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g - var_h\nvar_j = 2\nvar_k = var_i // var_j\nprint(int(var_k))"
    },
    "3729": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 연속된 짝수의 합이 240입니다. 이 5개의 수 중 가장 작은 수를 쓰시오.",
        "question_en": "The sum of 5 consecutive even numbers is 240. Write the smallest of these 5 numbers.",
        "answer_ko": "44",
        "answer_en": "44",
        "solution_abst_ko": "240 5 [OP_DIV] 5 2 [OP_FDIV] 2 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "240 5 [OP_DIV] 5 2 [OP_FDIV] 2 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 240\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d // var_e\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_c - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 240\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d // var_e\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_c - var_h\nprint(int(var_i))"
    },
    "3730": {
        "category": "Comparison",
        "question_ko": "어느 목장에 돼지가 소보다 많고 돼지가 닭보다 적다고 한다. 목장에 가장 많은 동물은 무엇인지 구하시오.",
        "question_en": "On a ranch there are more pigs than cows and fewer pigs than chickens. What are the most common animals on a ranch?",
        "answer_ko": "닭",
        "answer_en": "chickens",
        "solution_abst_ko": "[OP_LIST_SOL] 소 돼지 닭 [OP_LIST_EOL] [OP_LIST_SOL] 돼지 소 > 돼지 닭 < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] cows pigs chickens [OP_LIST_EOL] [OP_LIST_SOL] pigs cows > pigs chickens < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '소'\nvar_b = '돼지'\nvar_c = '닭'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '돼지'\nvar_e = '소'\nvar_f = '>'\nvar_g = '돼지'\nvar_h = '닭'\nvar_i = '<'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(var_k)",
        "solution_code_en": "var_a = 'cows'\nvar_b = 'pigs'\nvar_c = 'chickens'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'pigs'\nvar_e = 'cows'\nvar_f = '>'\nvar_g = 'pigs'\nvar_h = 'chickens'\nvar_i = '<'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(var_k)"
    },
    "3731": {
        "category": "Geometry",
        "question_ko": "몇 개의 철사로 부피가 3375세제곱센티미터(㎤)인 정육면체를 만들었습니다. 사용된 철사의 길이를 구하십시오.",
        "question_en": "I used several wires to make a cube with a volume of 3375 cubic centimeters (cm3). Find the length of wires used to make it.",
        "answer_ko": "180",
        "answer_en": "180",
        "solution_abst_ko": "3375 1/3 [OP_POW] 12 [OP_MUL]",
        "solution_abst_en": "3375 1/3 [OP_POW] 12 [OP_MUL]",
        "solution_code_ko": "var_a = 3375\nvar_b = 0.3333333333333333\nvar_c = var_a ** var_b\nvar_d = 12\nvar_e = var_c * var_d\nprint(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))",
        "solution_code_en": "var_a = 3375\nvar_b = 0.3333333333333333\nvar_c = var_a ** var_b\nvar_d = 12\nvar_e = var_c * var_d\nprint(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))"
    },
    "3732": {
        "category": "Arithmetic calculation",
        "question_ko": "가로가 3미터(m) 20센티미터(㎝)인 게시판에 가로가 30센티미터(㎝)인 그림을 일렬로 붙이려고 합니다. 게시판과 그림 사이, 그림과 그림 사이의 간격을 모두 같게 하여 6개를 붙이려면 간격은 몇 센티미터(㎝)로 하여야 합니까?",
        "question_en": "I am trying to hang pictures with a width of 30 centimeters (cm) in a row on a bulletin board that is 3 meters (m) and 20 centimeters (cm) wide. How many centimeters (cm) should the distance between the board and the picture and the distance between the pictures be, if all six pictures are hung at the same distance?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "3 100 [OP_MUL] 20 [OP_ADD] 30 6 [OP_MUL] [OP_SUB] 6 1 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "3 100 [OP_MUL] 20 [OP_ADD] 30 6 [OP_MUL] [OP_SUB] 6 1 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 3\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 20\nvar_e = var_c + var_d\nvar_f = 30\nvar_g = 6\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nvar_j = 6\nvar_k = 1\nvar_l = var_j + var_k\nvar_m = var_i / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 3\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 20\nvar_e = var_c + var_d\nvar_f = 30\nvar_g = 6\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nvar_j = 6\nvar_k = 1\nvar_l = var_j + var_k\nvar_m = var_i / var_l\nprint(int(var_m))"
    },
    "3733": {
        "category": "Geometry",
        "question_ko": "가로의 길이 18센티미터(㎝), 세로의 길이가 12센티미터(㎝), 높이가 9센티미터(㎝)인 벽돌을 쌓아 정육면체를 만들려고 할 때, 필요한 최소의 벽돌의 개수를 구하여라.",
        "question_en": "Find the minimum number of bricks required to make a cube by stacking bricks with a width of 18 centimeters (cm), a depth of 12 centimeters (cm), and a height of 9 cm (cm).",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "18 12 [OP_LCM] 9 [OP_LCM] 18 [OP_DIV] 18 12 [OP_LCM] 9 [OP_LCM] 12 [OP_DIV] 18 12 [OP_LCM] 9 [OP_LCM] 9 [OP_DIV] [OP_MUL] [OP_MUL]",
        "solution_abst_en": "18 12 [OP_LCM] 9 [OP_LCM] 18 [OP_DIV] 18 12 [OP_LCM] 9 [OP_LCM] 12 [OP_DIV] 18 12 [OP_LCM] 9 [OP_LCM] 9 [OP_DIV] [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 18\nvar_b = 12\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nvar_d = 9\nvar_e = var_d * var_c / math.gcd(int(var_d), int(var_c))\nvar_f = 18\nvar_g = var_e / var_f\nvar_h = 18\nvar_i = 12\nvar_j = var_i * var_h / math.gcd(int(var_i), int(var_h))\nvar_k = 9\nvar_l = var_k * var_j / math.gcd(int(var_k), int(var_j))\nvar_m = 12\nvar_n = var_l / var_m\nvar_o = 18\nvar_p = 12\nvar_q = var_p * var_o / math.gcd(int(var_p), int(var_o))\nvar_r = 9\nvar_s = var_r * var_q / math.gcd(int(var_r), int(var_q))\nvar_t = 9\nvar_u = var_s / var_t\nvar_v = var_n * var_u\nvar_w = var_g * var_v\nprint(int(var_w))",
        "solution_code_en": "var_a = 18\nvar_b = 12\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nvar_d = 9\nvar_e = var_d * var_c / math.gcd(int(var_d), int(var_c))\nvar_f = 18\nvar_g = var_e / var_f\nvar_h = 18\nvar_i = 12\nvar_j = var_i * var_h / math.gcd(int(var_i), int(var_h))\nvar_k = 9\nvar_l = var_k * var_j / math.gcd(int(var_k), int(var_j))\nvar_m = 12\nvar_n = var_l / var_m\nvar_o = 18\nvar_p = 12\nvar_q = var_p * var_o / math.gcd(int(var_p), int(var_o))\nvar_r = 9\nvar_s = var_r * var_q / math.gcd(int(var_r), int(var_q))\nvar_t = 9\nvar_u = var_s / var_t\nvar_v = var_n * var_u\nvar_w = var_g * var_v\nprint(int(var_w))"
    },
    "3734": {
        "category": "Comparison",
        "question_ko": "빨간색 색종이가 168장, 노란색 색종이가 173장 있습니다. 어느 색의 색종이가 더 많습니까?",
        "question_en": "There are 168 pieces of red confetti and 173 pieces of yellow confetti. Which color of confetti do you have more?",
        "answer_ko": "노란색",
        "answer_en": "yellow",
        "solution_abst_ko": "[OP_LIST_SOL] 빨간색 노란색 [OP_LIST_EOL] [OP_LIST_SOL] 168 173 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] red yellow [OP_LIST_EOL] [OP_LIST_SOL] 168 173 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '빨간색'\nvar_b = '노란색'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 168\nvar_d = 173\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'red'\nvar_b = 'yellow'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 168\nvar_d = 173\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "3735": {
        "category": "Correspondence",
        "question_ko": "어떤 수의 7/12은 42입니다. 어떤 수의 11/18보다 4 작은 수는 얼마입니까?",
        "question_en": "7/12 of a certain number is 42. What is a value of 4 less than 11/18 of this number?",
        "answer_ko": "40",
        "answer_en": "40",
        "solution_abst_ko": "42 1 7/12 [OP_DIV] [OP_MUL] 11/18 [OP_MUL] 4 [OP_SUB]",
        "solution_abst_en": "42 1 7/12 [OP_DIV] [OP_MUL] 11/18 [OP_MUL] 4 [OP_SUB]",
        "solution_code_ko": "var_a = 42\nvar_b = 1\nvar_c = 0.5833333333333334\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 0.6111111111111112\nvar_g = var_e * var_f\nvar_h = 4\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 42\nvar_b = 1\nvar_c = 0.5833333333333334\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 0.6111111111111112\nvar_g = var_e * var_f\nvar_h = 4\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "3736": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 2센티미터(㎝)이며 변이 총 9개인 도형이 있습니다. 이 도형의 둘레는 몇 센티미터(㎝)입니까?",
        "question_en": "There is a figure with 9 sides with each side length of 2 centimeters (cm). What is the perimeter of this shape in centimeters (cm)?",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "2 9 [OP_MUL]",
        "solution_abst_en": "2 9 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 9\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 9\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "3737": {
        "category": "Arithmetic calculation",
        "question_ko": "지민이는 2시간동안 시속 60킬로미터(㎞)로 이동했습니다. 목적지까지는 300킬로미터(㎞)가 떨어져있다고 할 때, 지민이가 더 가야하는 거리는 얼마인가요?",
        "question_en": "Jimin moved at 60 kilometers (km) per hour for two hours. If the destination is 300 kilometers (km) away, how far does Jimin have to go?",
        "answer_ko": "180",
        "answer_en": "180",
        "solution_abst_ko": "300 60 2 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "300 60 2 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 300\nvar_b = 60\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 300\nvar_b = 60\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "3738": {
        "category": "Geometry",
        "question_ko": "가로가 15센티미터(㎝)이고 세로는 가로의 0.9인 직사각형이 있습니다. 이 직사각형의 넓이는 몇 제곱센티미터(㎠)인지 구하시오.",
        "question_en": "You have a rectangle with a length of 15 centimeters (cm) and a width of 0.9 of its length. Find the area of this rectangle in square centimeters (cm2).",
        "answer_ko": "202.50",
        "answer_en": "202.5",
        "solution_abst_ko": "15 15 0.9 [OP_MUL] [OP_MUL]",
        "solution_abst_en": "15 15 0.9 [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 15\nvar_b = 15\nvar_c = 0.9\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 15\nvar_b = 15\nvar_c = 0.9\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "3739": {
        "category": "Arithmetic calculation",
        "question_ko": "2, 3, 5로 나누어떨어지는 수 중에서 가장 작은 다섯 자리 수를 찾아 쓰시오.",
        "question_en": "Find the smallest five-digit number that is divided into 2, 3, or 5.",
        "answer_ko": "10020",
        "answer_en": "10020",
        "solution_abst_ko": "10000 10000 10 [OP_MUL] 1 [OP_SUB] 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "10000 10000 10 [OP_MUL] 1 [OP_SUB] 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 10000\nvar_b = 10000\nvar_c = 10\nvar_d = var_b * var_c\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_a, var_f + 1, var_g)]\nvar_h = 2\nlist_b = []\nvar_h = int(var_h)\nfor i in list_a:\n    i = int(i)\n    if i % var_h == 0:\n        list_b.append(i)\nvar_i = 3\nlist_c = []\nvar_i = int(var_i)\nfor i in list_b:\n    i = int(i)\n    if i % var_i == 0:\n        list_c.append(i)\nvar_j = 5\nlist_d = []\nvar_j = int(var_j)\nfor i in list_c:\n    i = int(i)\n    if i % var_j == 0:\n        list_d.append(i)\nvar_k = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_l = list_e[var_k-1]\nprint(int(var_l))",
        "solution_code_en": "var_a = 10000\nvar_b = 10000\nvar_c = 10\nvar_d = var_b * var_c\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_a, var_f + 1, var_g)]\nvar_h = 2\nlist_b = []\nvar_h = int(var_h)\nfor i in list_a:\n    i = int(i)\n    if i % var_h == 0:\n        list_b.append(i)\nvar_i = 3\nlist_c = []\nvar_i = int(var_i)\nfor i in list_b:\n    i = int(i)\n    if i % var_i == 0:\n        list_c.append(i)\nvar_j = 5\nlist_d = []\nvar_j = int(var_j)\nfor i in list_c:\n    i = int(i)\n    if i % var_j == 0:\n        list_d.append(i)\nvar_k = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_l = list_e[var_k-1]\nprint(int(var_l))"
    },
    "3740": {
        "category": "Arithmetic calculation",
        "question_ko": "리본 1개를 만들기 위해서는 끈 4미터(m)가 필요합니다. 지민이가 끈 105.8미터(m)를 사왔다면 최대한 많은 리본을 만들고 남은 끈의 길이를 구하세요.",
        "question_en": "To make one ribbon, you need 4 meters (m) of string. If Jimin bought 105.8 meters (m) of string, make as many ribbons as possible and find the length of the remaining string.",
        "answer_ko": "1.80",
        "answer_en": "1.8",
        "solution_abst_ko": "105.8 4 [OP_MOD]",
        "solution_abst_en": "105.8 4 [OP_MOD]",
        "solution_code_ko": "var_a = 105.8\nvar_b = 4\nvar_c = var_a % var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 105.8\nvar_b = 4\nvar_c = var_a % var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "3741": {
        "category": "Geometry",
        "question_ko": "길이가 49센티미터(㎝)인 철사를 7등분하면 길이가 몇 센티미터(㎝)가 되는가?",
        "question_en": "How many centimeters (cm) will be the length of a 49 centimeters (cm) wire if it is divided into 7 equal parts?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "49 7 [OP_DIV]",
        "solution_abst_en": "49 7 [OP_DIV]",
        "solution_code_ko": "var_a = 49\nvar_b = 7\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 49\nvar_b = 7\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "3742": {
        "category": "Geometry",
        "question_ko": "머리 모양이 정육면체인 외계인이 있습니다. 이 외계인 머리의 겉넓이는 150제곱센티미터(㎠)입니다. 머리의 부피를 구하시오.",
        "question_en": "There are aliens with cube-shaped heads. The surface area of this alien's head is 150 square centimeters (cm2). Find the volume of the head.",
        "answer_ko": "125",
        "answer_en": "125",
        "solution_abst_ko": "150 6 [OP_DIV] 1/2 [OP_POW] 3 [OP_POW]",
        "solution_abst_en": "150 6 [OP_DIV] 1/2 [OP_POW] 3 [OP_POW]",
        "solution_code_ko": "var_a = 150\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 3\nvar_g = var_e ** var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 150\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 3\nvar_g = var_e ** var_f\nprint(int(var_g))"
    },
    "3743": {
        "category": "Geometry",
        "question_ko": "삼각형에는 총 3개의 꼭짓점이 있습니다. 이 중 두 개의 꼭짓점을 선택해 이은 선분의 길이가 8센티미터(㎝)이고, 넓이는 24제곱센티미터(㎠)인 삼각형이 있다면, 선택받지 못한 꼭짓점과 선택된 꼭짓점으로 만들어진 선분 사이의 거리는 몇 센티미터(㎝)일지 구하시오.",
        "question_en": "A triangle has a total of 3 vertices. If two of these vertices are selected and the segment connected is a triangle with a length of 8 centimeters (cm) and an area of 24 square centimeters (cm2), how many centimeters is the distance between the unselected vertex and the segment formed by the selected vertex. ",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "24 2 [OP_MUL] 8 [OP_DIV]",
        "solution_abst_en": "24 2 [OP_MUL] 8 [OP_DIV]",
        "solution_code_ko": "var_a = 24\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 24\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "3744": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 가장 작은 수와 그 다음으로 작은 수의 합은 얼마입니까?",
        "question_en": "There are five numbers 10, 11, 12, 13, and 14. What is the sum of the smallest number and the next smallest number?",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))"
    },
    "3745": {
        "category": "Correspondence",
        "question_ko": "서로 다른 수 A, B, C, D가 있습니다. 네 자리 수끼리의 덧셈식 DCBA+ABCD=ABCD0에서 A, B, C, D의 합을 구하시오.",
        "question_en": "There are different numbers A, B, C, and D. Find the sum of A, B, C, and D in the four-digit addition formula DCBA+ABCD=ABCD0.",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "[OP_LIST_SOL] DCBA+ABCD=ABCD0 A [OP_DIGIT_UNK_SOLVER] DCBA+ABCD=ABCD0 B [OP_DIGIT_UNK_SOLVER] DCBA+ABCD=ABCD0 C [OP_DIGIT_UNK_SOLVER] DCBA+ABCD=ABCD0 D [OP_DIGIT_UNK_SOLVER] [OP_LIST_EOL] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] DCBA+ABCD=ABCD0 A [OP_DIGIT_UNK_SOLVER] DCBA+ABCD=ABCD0 B [OP_DIGIT_UNK_SOLVER] DCBA+ABCD=ABCD0 C [OP_DIGIT_UNK_SOLVER] DCBA+ABCD=ABCD0 D [OP_DIGIT_UNK_SOLVER] [OP_LIST_EOL] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 'DCBA+ABCD=ABCD0'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 'DCBA+ABCD=ABCD0'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = 'DCBA+ABCD=ABCD0'\nvar_h = 'C'\nans_dict = dict()\nvar_g = var_g.replace('×','*')\nvar_g = var_g.replace('x','*')\nvar_g = var_g.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_g):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_g\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_g):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_i = ans_dict[var_h]\nvar_j = 'DCBA+ABCD=ABCD0'\nvar_k = 'D'\nans_dict = dict()\nvar_j = var_j.replace('×','*')\nvar_j = var_j.replace('x','*')\nvar_j = var_j.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_j):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_j\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_j):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_l = ans_dict[var_k]\nlist_a= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_a.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_m = sum(list_a)\nprint(int(var_m))",
        "solution_code_en": "var_a = 'DCBA+ABCD=ABCD0'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 'DCBA+ABCD=ABCD0'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = 'DCBA+ABCD=ABCD0'\nvar_h = 'C'\nans_dict = dict()\nvar_g = var_g.replace('×','*')\nvar_g = var_g.replace('x','*')\nvar_g = var_g.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_g):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_g\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_g):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_i = ans_dict[var_h]\nvar_j = 'DCBA+ABCD=ABCD0'\nvar_k = 'D'\nans_dict = dict()\nvar_j = var_j.replace('×','*')\nvar_j = var_j.replace('x','*')\nvar_j = var_j.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_j):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_j\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_j):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_l = ans_dict[var_k]\nlist_a= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_a.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_m = sum(list_a)\nprint(int(var_m))"
    },
    "3746": {
        "category": "Arithmetic calculation",
        "question_ko": "연속된 짝수 3개의 합을 구하였더니 그 중 가장 작은 짝수보다 18이 컸습니다. 3개의 짝 수 중 가장 큰 수는 몇인지 구하시오.",
        "question_en": "The sum of three consecutive even numbers is 18 greater than the smallest even number among those three. What is the largest one among the 3 even numbers?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "18 2 1 [OP_MUL] 2 2 [OP_MUL] [OP_ADD] [OP_SUB] 3 1 [OP_SUB] [OP_DIV] 2 2 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "18 2 1 [OP_MUL] 2 2 [OP_MUL] [OP_ADD] [OP_SUB] 3 1 [OP_SUB] [OP_DIV] 2 2 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 18\nvar_b = 2\nvar_c = 1\nvar_d = var_b * var_c\nvar_e = 2\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = var_d + var_g\nvar_i = var_a - var_h\nvar_j = 3\nvar_k = 1\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nvar_n = 2\nvar_o = 2\nvar_p = var_n * var_o\nvar_q = var_m + var_p\nprint(int(var_q))",
        "solution_code_en": "var_a = 18\nvar_b = 2\nvar_c = 1\nvar_d = var_b * var_c\nvar_e = 2\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = var_d + var_g\nvar_i = var_a - var_h\nvar_j = 3\nvar_k = 1\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nvar_n = 2\nvar_o = 2\nvar_p = var_n * var_o\nvar_q = var_m + var_p\nprint(int(var_q))"
    },
    "3747": {
        "category": "Possibility",
        "question_ko": "4, 5, 8, 9 중 3개를 사용하여 일의 자리 숫자가 5인 두 번째 작은 수는 무엇입니까?",
        "question_en": "Using 3 of 4, 5, 8, and 9, what is the second smallest number whose units digit is 5?",
        "answer_ko": "495",
        "answer_en": "495",
        "solution_abst_ko": "[OP_LIST_SOL] 4 5 8 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 5 [OP_LIST_SEARCH_FIXED_DIGIT] 2 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 4 5 8 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 5 [OP_LIST_SEARCH_FIXED_DIGIT] 2 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 4\nvar_b = 5\nvar_c = 8\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nvar_g = 5\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 2\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nprint(int(var_i))",
        "solution_code_en": "var_a = 4\nvar_b = 5\nvar_c = 8\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nvar_g = 5\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 2\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nprint(int(var_i))"
    },
    "3748": {
        "category": "Geometry",
        "question_ko": "이등변삼각형의 꼭지각에 대해 이등분선을 그었더니 나뉘어진 밑변의 길이가 4 미터(m) 였습니다. 이 때, 밑변의 길이는 몇 미터(m)입니까?",
        "question_en": "If you draw a line bisector of the vertex angle of an isosceles triangle, the length of the each divided base is 4 meters (m). How many meters (m) is the total length of the base?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "4 2 [OP_MUL]",
        "solution_abst_en": "4 2 [OP_MUL]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "3749": {
        "category": "Possibility",
        "question_ko": "2, 7, 0, 9 중에서 서로 다른 숫자 3개를 뽑아 만들 수 있는 세 자리 수 중에서 5번째로 작은 수를 쓰시오.",
        "question_en": "Write the 5th smallest number among three-digit numbers that can be made by drawing three different numbers from 2, 7, 0, and 9.",
        "answer_ko": "290",
        "answer_en": "290",
        "solution_abst_ko": "[OP_LIST_SOL] 2 7 0 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 5 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 2 7 0 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 5 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 2\nvar_b = 7\nvar_c = 0\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 5\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 2\nvar_b = 7\nvar_c = 0\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 5\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nprint(int(var_g))"
    },
    "3750": {
        "category": "Correspondence",
        "question_ko": "예인이는 리본으로 3개의 선물을 포장하기로 했다. 첫 번째 선물을 포장하는데 전체 리본의 1/2을 사용하고, 두 번째 선물을 포장하는데 남은 리본의 1/3을 사용하고, 세번째 선물을 포장하는데 남은 리본의 1/2을 사용했더니 250센티미터(㎝)가 남았습니다. 예인이가 처음 가지고 있던 리본의 양은 얼마입니까?",
        "question_en": "Yein wrapped three presents with ribbon. She used 1/2 of the total ribbon to wrap the first present, 1/3 of the remaining ribbon to wrap the second present, and 1/2 of the remaining ribbon to wrap the third present, leaving 250 centimeters (cm). How much ribbon did Yein have at first? ",
        "answer_ko": "1500",
        "answer_en": "1500",
        "solution_abst_ko": "250 1 1/2 [OP_SUB] [OP_DIV] 1 1/3 [OP_SUB] [OP_DIV] 1 1/2 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "250 1 1/2 [OP_SUB] [OP_DIV] 1 1/3 [OP_SUB] [OP_DIV] 1 1/2 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 250\nvar_b = 1\nvar_c = 0.5\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 1\nvar_g = 0.3333333333333333\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 1\nvar_k = 0.5\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nprint(int(eval('{:.2f}'.format(round(var_m+1e-10,2)))))",
        "solution_code_en": "var_a = 250\nvar_b = 1\nvar_c = 0.5\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 1\nvar_g = 0.3333333333333333\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 1\nvar_k = 0.5\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nprint(int(eval('{:.2f}'.format(round(var_m+1e-10,2)))))"
    },
    "3751": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 28미터(m)인 막대가 있습니다. 이 막대를 1.12미터(m)씩 자르면 몇 도막으로 자를 수 있습니까?",
        "question_en": "You have a stick that is 28 meters (m) long. How many slices can you get if you cut this stick by 1.12 meters (m) each?",
        "answer_ko": "25",
        "answer_en": "25",
        "solution_abst_ko": "28 1.12 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "28 1.12 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 28\nvar_b = 1.12\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))",
        "solution_code_en": "var_a = 28\nvar_b = 1.12\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))"
    },
    "3752": {
        "category": "Arithmetic calculation",
        "question_ko": "참기름이 가득 들어 있는 병의 무게는 3.4 킬로그램(㎏) 입니다. 이 참기름의 1/5 을 사용한 후의 병의 무게가 2.98 킬로그램(㎏) 이라면 빈 병의 무게는 몇 킬로그램(㎏)인지 구하시오.",
        "question_en": "The weight of a full bottle of sesame oil is 3.4 kilograms (kg). If the weight of the bottle after using 1/5 of the sesame oil is 2.98 kilograms (kg), find the weight of the empty bottle in kilograms (kg).",
        "answer_ko": "1.30",
        "answer_en": "1.3",
        "solution_abst_ko": "3.4 3.4 2.98 [OP_SUB] 1/5 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "3.4 3.4 2.98 [OP_SUB] 1/5 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 3.4\nvar_b = 3.4\nvar_c = 2.98\nvar_d = var_b - var_c\nvar_e = 0.2\nvar_f = var_d / var_e\nvar_g = var_a - var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 3.4\nvar_b = 3.4\nvar_c = 2.98\nvar_d = var_b - var_c\nvar_e = 0.2\nvar_f = var_d / var_e\nvar_g = var_a - var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "3753": {
        "category": "Comparison",
        "question_ko": "직사각형은 가로, 세로가 각각 11센티미터(㎝), 8센티미터(㎝)이다. 평행사변형은 밑변 높이가 각각 12센티미터(㎝), 7센티미터(㎝)이다. 넓이가 가장 큰 도형은 어느 것인가?",
        "question_en": "The rectangle is 11 centimeters (cm) wide and 8 centimeters (cm) long. The base and the height of a parallelogram are 12 centimeters (cm) and 7 centimeters (cm), respectively. Which shape has the largest area?",
        "answer_ko": "직사각형",
        "answer_en": "rectangle",
        "solution_abst_ko": "[OP_LIST_SOL] 직사각형 평행사변형 [OP_LIST_EOL] [OP_LIST_SOL] 11 8 [OP_MUL] 12 7 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] rectangle parallelogram [OP_LIST_EOL] [OP_LIST_SOL] 11 8 [OP_MUL] 12 7 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '직사각형'\nvar_b = '평행사변형'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 11\nvar_d = 8\nvar_e = var_c * var_d\nvar_f = 12\nvar_g = 7\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'rectangle'\nvar_b = 'parallelogram'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 11\nvar_d = 8\nvar_e = var_c * var_d\nvar_f = 12\nvar_g = 7\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "3754": {
        "category": "Arithmetic calculation",
        "question_ko": "은지네 반 학생 중 (가) 악기를 칠 수 있는 학생은 24명이고, 이 중 8명은 (나) 악기도 칠 수 있다고 합니다. 은지네 반 학생 중 (가) 악기와 (나) 악기를 모두 칠 수 없는 학생은 없고, (나) 악기를 칠 수 있는 학생이 17명이라면, 은지네 반에는 모두 몇 명의 학생이 있습니까?",
        "question_en": "Among the students in Eunji's class, there are 24 students who can play musical instrument (a), and 8 of them are said to be able to play instrument (b) as well. If not a single student can play both (a) and (b), and 17 students can play instrument (b), how many students are there in Eunji's class?",
        "answer_ko": "33",
        "answer_en": "33",
        "solution_abst_ko": "24 17 [OP_ADD] 8 [OP_SUB]",
        "solution_abst_en": "24 17 [OP_ADD] 8 [OP_SUB]",
        "solution_code_ko": "var_a = 24\nvar_b = 17\nvar_c = var_a + var_b\nvar_d = 8\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 24\nvar_b = 17\nvar_c = var_a + var_b\nvar_d = 8\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3755": {
        "category": "Possibility",
        "question_ko": "7, 6, 2, 0이 그려진 카드 중 하나를 빼고 남은 카드를 모두 사용하여 세 자리 수를 만들 때, 세 번째 큰 수와 세 번째 작은 수의 합을 구하시오.",
        "question_en": "When you remove one of the cards from 7, 6, 2, and 0 and use all remaining cards to make a three-digit number, find the sum of the third largest number and the third smallest number.",
        "answer_ko": "986",
        "answer_en": "986",
        "solution_abst_ko": "[OP_LIST_SOL] 7 6 2 0 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 7 6 2 0 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 7\nvar_b = 6\nvar_c = 2\nvar_d = 0\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 7\nvar_b = 6\nvar_c = 2\nvar_d = 0\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))"
    },
    "3756": {
        "category": "Arithmetic calculation",
        "question_ko": "유찬이는 한 걸음에 0.75미터(m)를 갑니다. 유찬이가 1분에 70걸음씩 13분 동안 직진으로 걸었다면, 유찬이의 현재 위치는 처음 있던 위치와 몇 미터(m)가 차이 나는지 구하시오.",
        "question_en": "Yoochan walks 0.75 meters (m) in one step. If Yoochan walks straight for 13 minutes at 70 steps per minute, find how many meters (m) the current location of Yoochan is from the first location.",
        "answer_ko": "682.50",
        "answer_en": "682.5",
        "solution_abst_ko": "0.75 70 [OP_MUL] 13 [OP_MUL]",
        "solution_abst_en": "0.75 70 [OP_MUL] 13 [OP_MUL]",
        "solution_code_ko": "var_a = 0.75\nvar_b = 70\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.75\nvar_b = 70\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "3757": {
        "category": "Correspondence",
        "question_ko": "네 수 A, B, C, D가 있습니다. 네 자리 수끼리의 뺄셈식 A05B-1C04=30D8에서 A+B-C+D의 값을 구하시오.",
        "question_en": "There are four numbers A, B, C, and D. Find the value of A+B-C+D in the four-digit subtraction formula A05B-1C04=30D8.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "A05B-1C04=30D8 A [OP_DIGIT_UNK_SOLVER] A05B-1C04=30D8 B [OP_DIGIT_UNK_SOLVER] [OP_ADD] A05B-1C04=30D8 C [OP_DIGIT_UNK_SOLVER] [OP_SUB] A05B-1C04=30D8 D [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_abst_en": "A05B-1C04=30D8 A [OP_DIGIT_UNK_SOLVER] A05B-1C04=30D8 B [OP_DIGIT_UNK_SOLVER] [OP_ADD] A05B-1C04=30D8 C [OP_DIGIT_UNK_SOLVER] [OP_SUB] A05B-1C04=30D8 D [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_code_ko": "var_a = 'A05B-1C04=30D8'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 'A05B-1C04=30D8'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nvar_h = 'A05B-1C04=30D8'\nvar_i = 'C'\nans_dict = dict()\nvar_h = var_h.replace('×','*')\nvar_h = var_h.replace('x','*')\nvar_h = var_h.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_h):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_h\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_h):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_j = ans_dict[var_i]\nvar_k = var_g - var_j\nvar_l = 'A05B-1C04=30D8'\nvar_m = 'D'\nans_dict = dict()\nvar_l = var_l.replace('×','*')\nvar_l = var_l.replace('x','*')\nvar_l = var_l.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_l):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_l\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_l):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_n = ans_dict[var_m]\nvar_o = var_k + var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 'A05B-1C04=30D8'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 'A05B-1C04=30D8'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nvar_h = 'A05B-1C04=30D8'\nvar_i = 'C'\nans_dict = dict()\nvar_h = var_h.replace('×','*')\nvar_h = var_h.replace('x','*')\nvar_h = var_h.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_h):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_h\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_h):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_j = ans_dict[var_i]\nvar_k = var_g - var_j\nvar_l = 'A05B-1C04=30D8'\nvar_m = 'D'\nans_dict = dict()\nvar_l = var_l.replace('×','*')\nvar_l = var_l.replace('x','*')\nvar_l = var_l.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_l):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_l\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_l):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_n = ans_dict[var_m]\nvar_o = var_k + var_n\nprint(int(var_o))"
    },
    "3758": {
        "category": "Arithmetic calculation",
        "question_ko": "율기와 가영이가 가지고 있는 용돈을 더하면 6000원이고, 두 사람이 가지고 있는 용돈의 차를 용돈의 합에서 빼면 4800원입니다. 율기의 용돈이 가영이의 용돈보다 많을 때 율기의 용돈은 얼마인지 구하시오.",
        "question_en": "If you add the allowance of Yul-gi and Ga-yeong have, you get 6,000 won. If you subtract the difference between their allowance from the sum of their allowance, you get 4,800 won. If Yul-gi's allowance is more than Ga-yeong's, find out how much Yul-gi's allowance is.",
        "answer_ko": "3600",
        "answer_en": "3600",
        "solution_abst_ko": "6000 4800 2 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "6000 4800 2 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 6000\nvar_b = 4800\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6000\nvar_b = 4800\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "3759": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 수에 7을 곱한 값에 6을 빼고 12을 뺀 값은 어떤 수에 4배와 같다. 어떤 수를 구하시오.",
        "question_en": "A certain number multiplied by 7 minus 6 minus 12 equals the number multiplied by 4. Find the certain number.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "12 6 [OP_ADD] 7 4 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "12 6 [OP_ADD] 7 4 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 7\nvar_e = 4\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 12\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 7\nvar_e = 4\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))"
    },
    "3760": {
        "category": "Arithmetic calculation",
        "question_ko": "민영이는 개 9마리, 고양이 3마리, 토끼 5마리를 기르고 있고, 유정이는 민영이보다 동물을 2마리 더 많이 기르고 있습니다. 유정이가 개를 7마리 키우고 고양이는 토끼보다 2마리 더 적게 기를 때, 유정이가 기르는 고양이는 몇 마리인지 구하시오",
        "question_en": "Minyoung has 9 dogs, 3 cats, and 5 rabbits, and Yoojeong has 2 more animals than Minyoung. If Yoojeong has 7 dogs and 2 fewer cats than rabbits, how many rabbits does Yoojeong have?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "9 3 [OP_ADD] 5 [OP_ADD] 2 [OP_ADD] 7 [OP_SUB] 2 [OP_DIV] 1 [OP_ADD]",
        "solution_abst_en": "9 3 [OP_ADD] 5 [OP_ADD] 2 [OP_ADD] 7 [OP_SUB] 2 [OP_DIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 9\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e + var_f\nvar_h = 7\nvar_i = var_g - var_h\nvar_j = 2\nvar_k = var_i / var_j\nvar_l = 1\nvar_m = var_k + var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 9\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e + var_f\nvar_h = 7\nvar_i = var_g - var_h\nvar_j = 2\nvar_k = var_i / var_j\nvar_l = 1\nvar_m = var_k + var_l\nprint(int(var_m))"
    },
    "3761": {
        "category": "Geometry",
        "question_ko": "직사각형 모양인 목장 울타리의 둘레는 30미터(m)입니다. 울타리의 가로 길이는 세로 길이의 2배라고 합니다. 울타리의 가로 길이는 몇 미터(m)입니까?",
        "question_en": "The rectangular ranch fence has a perimeter of 30 meters (m), and the length of the fence is twice its width. What is the length of the fence in meters (m)?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "30 2 2 1 [OP_ADD] [OP_MUL] [OP_DIV] 2 [OP_MUL]",
        "solution_abst_en": "30 2 2 1 [OP_ADD] [OP_MUL] [OP_DIV] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 30\nvar_b = 2\nvar_c = 2\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = var_b * var_e\nvar_g = var_a / var_f\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 30\nvar_b = 2\nvar_c = 2\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = var_b * var_e\nvar_g = var_a / var_f\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "3762": {
        "category": "Arithmetic calculation",
        "question_ko": "32의 약수 중 두 번째로 큰 값을 구하시오.",
        "question_en": "Find the second largest aliquot of 32.",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "32 [OP_LIST_GET_DIVISOR] 2 [OP_LIST_MAX]",
        "solution_abst_en": "32 [OP_LIST_GET_DIVISOR] 2 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 32\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_c = list_b[-var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 32\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_c = list_b[-var_b]\nprint(int(var_c))"
    },
    "3763": {
        "category": "Correspondence",
        "question_ko": "5716보다 큰 네자리 수 571A가 있습니다. A에 쓸 수 있는 숫자는 모두 몇 개입니까?",
        "question_en": "There is a four-digit number 571A which is greater than 5716. How many digits can you put in A?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "571A [OP_GEN_POSSIBLE_LIST] 5716 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "571A [OP_GEN_POSSIBLE_LIST] 5716 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '571A'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 5716\nlist_b = []\nfor i in list_a:\n    if i < var_b:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))",
        "solution_code_en": "var_a = '571A'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 5716\nlist_b = []\nfor i in list_a:\n    if i < var_b:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))"
    },
    "3764": {
        "category": "Possibility",
        "question_ko": "7, 9, 3, 6 수 카드 4장을 한 번씩만 사용하여 만들 수 있는 가장 큰 네 자리 수를 내림하여 십의 자리까지 나타내어 보세요.",
        "question_en": "Round down the largest four-digit number you can make using four cards 7, 9, 3, and 6 only once each to the nearest tenth.",
        "answer_ko": "9760",
        "answer_en": "9760",
        "solution_abst_ko": "[OP_LIST_SOL] 7 9 3 6 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 2 [OP_FLOOR]",
        "solution_abst_en": "[OP_LIST_SOL] 7 9 3 6 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 2 [OP_FLOOR]",
        "solution_code_ko": "var_a = 7\nvar_b = 9\nvar_c = 3\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 2\nvar_i=int((var_g//(10**(var_h-1)))*10**(var_h-1))\n\nprint(int(var_i))",
        "solution_code_en": "var_a = 7\nvar_b = 9\nvar_c = 3\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 2\nvar_i=int((var_g//(10**(var_h-1)))*10**(var_h-1))\n\nprint(int(var_i))"
    },
    "3765": {
        "category": "Arithmetic calculation",
        "question_ko": "세 자연수 1, 6, 8을 이용하여 만드는 세 자리 자연수들 중, 큰 순서대로 나열하였을 때 세 번째에 위치한 수는 무엇인가?",
        "question_en": "Among the three-digit natural numbers formed by using the three natural numbers 1, 6, and 8, what is the third number when arranged in ascending order?",
        "answer_ko": "681",
        "answer_en": "681",
        "solution_abst_ko": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 3 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 3 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))"
    },
    "3766": {
        "category": "Correspondence",
        "question_ko": "정국이는 3킬로미터(㎞) 7미터(m)를 걷고 나서 몇 미터(m)를 더 걸었습니다. 그리고 다시 840미터(m)를 걸어 전체 6킬로미터(㎞) 30미터(m)를 걸었습니다. 정국이가 중간에 걸은 거리는 몇 미터(m)입니까?",
        "question_en": "After Jungkook walked 3 kilometers (km) and 7 meters (m), he walked a few more meters (m). After a break, he took a walk for 840 meters (m), and it turned out that he walked 6 kilometers (km) and 30 meters (m) in total. How many meters (m) did Jungkook walk before the break?",
        "answer_ko": "2183",
        "answer_en": "2183",
        "solution_abst_ko": "6 1000 [OP_MUL] 30 [OP_ADD] 840 [OP_SUB] 3 1000 [OP_MUL] 7 [OP_ADD] [OP_SUB]",
        "solution_abst_en": "6 1000 [OP_MUL] 30 [OP_ADD] 840 [OP_SUB] 3 1000 [OP_MUL] 7 [OP_ADD] [OP_SUB]",
        "solution_code_ko": "var_a = 6\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 30\nvar_e = var_c + var_d\nvar_f = 840\nvar_g = var_e - var_f\nvar_h = 3\nvar_i = 1000\nvar_j = var_h * var_i\nvar_k = 7\nvar_l = var_j + var_k\nvar_m = var_g - var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 6\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 30\nvar_e = var_c + var_d\nvar_f = 840\nvar_g = var_e - var_f\nvar_h = 3\nvar_i = 1000\nvar_j = var_h * var_i\nvar_k = 7\nvar_l = var_j + var_k\nvar_m = var_g - var_l\nprint(int(var_m))"
    },
    "3767": {
        "category": "Arithmetic calculation",
        "question_ko": "28 초과 31 이하인 자연수를 모두 더하면 모두 얼마 입니까?",
        "question_en": "What is the sum of all natural numbers greater than 28 and less than or equal to 31?",
        "answer_ko": "90",
        "answer_en": "90",
        "solution_abst_ko": "28 1 [OP_ADD] 31 1 [OP_LIST_ARANGE] [OP_LIST_SUM]",
        "solution_abst_en": "28 1 [OP_ADD] 31 1 [OP_LIST_ARANGE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 28\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 31\nvar_e = 1\nlist_a = [i for i in range(var_c, var_d + 1, var_e)]\nlist_a = [float(i) for i in list_a]\nvar_f = sum(list_a)\nprint(int(var_f))",
        "solution_code_en": "var_a = 28\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 31\nvar_e = 1\nlist_a = [i for i in range(var_c, var_d + 1, var_e)]\nlist_a = [float(i) for i in list_a]\nvar_f = sum(list_a)\nprint(int(var_f))"
    },
    "3768": {
        "category": "Comparison",
        "question_ko": "총 4개의 숫자 0.8, 1/2, 0.5, 1/3이 있습니다. 이 중 3보다 작은 수는 몇 개 일까요?",
        "question_en": "There are a total of 4 numbers: 0.8, 1/2, 0.5, 1/3. How many of these numbers are less than 3?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.5 1/3 [OP_LIST_EOL] 3 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.5 1/3 [OP_LIST_EOL] 3 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.5\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = []\nfor i in list_a:\n    if i < var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.5\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = []\nfor i in list_a:\n    if i < var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "3769": {
        "category": "Geometry",
        "question_ko": "동쪽에 있는 호수의 둘레에는 10미터(m) 간격으로 96그루의 나무가 있고 서쪽에 있는 호수의 둘레에는 20미터(m) 간격으로 82그루의 나무가 있습니다. 두 호수의 둘레의 차는 몇 미터(m)입니까?",
        "question_en": "The perimeter of the eastern lake has 96 trees at 10m (m) intervals, and the perimeter of the western lake has 82 trees at 20 m (m) intervals. What is the difference between the circumferences of the two lakes in meters (m)?",
        "answer_ko": "680",
        "answer_en": "680",
        "solution_abst_ko": "10 96 [OP_MUL] 20 82 [OP_MUL] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "10 96 [OP_MUL] 20 82 [OP_MUL] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 10\nvar_b = 96\nvar_c = var_a * var_b\nvar_d = 20\nvar_e = 82\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = abs(var_g)\nprint(int(var_h))",
        "solution_code_en": "var_a = 10\nvar_b = 96\nvar_c = var_a * var_b\nvar_d = 20\nvar_e = 82\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = abs(var_g)\nprint(int(var_h))"
    },
    "3770": {
        "category": "Arithmetic calculation",
        "question_ko": "컵 10개가 들어있는 상자의 무게를 재었더니 3.1킬로그램(㎏)이었습니다. 이 상자에서 컵 1개를 빼고 무게를 재었더니 2.81킬로그램(㎏)이었습니다. 빈 상자의 무게는 몇 킬로그램(㎏)인지 구해보세요",
        "question_en": "When the box containing 10 cups was weighed, it was 3.1 kg (kg). When you removed one cup from this box, its weight changed to 2.81 kilograms (kg). Find the weight of the empty box in kilograms (kg).",
        "answer_ko": "0.20",
        "answer_en": "0.2",
        "solution_abst_ko": "3.1 3.1 2.81 [OP_SUB] 10 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "3.1 3.1 2.81 [OP_SUB] 10 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 3.1\nvar_b = 3.1\nvar_c = 2.81\nvar_d = var_b - var_c\nvar_e = 10\nvar_f = var_d * var_e\nvar_g = var_a - var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 3.1\nvar_b = 3.1\nvar_c = 2.81\nvar_d = var_b - var_c\nvar_e = 10\nvar_f = var_d * var_e\nvar_g = var_a - var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "3771": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 15까지의 홀수 중에서 2번째로 큰 수와 2번째로 작은 수의 합은 얼마입니까?",
        "question_en": "What is the sum of the second largest and second smallest odd numbers from 1 to 15?",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "1 15 [OP_LIST_ODD] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "1 15 [OP_LIST_ODD] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 15\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[-var_c]\nvar_e = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = var_d + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 15\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[-var_c]\nvar_e = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = var_d + var_f\nprint(int(var_g))"
    },
    "3772": {
        "category": "Correspondence",
        "question_ko": "지우와 승혜는 서로 같은 숫자를 봤는데 지우가 그 숫자의 소수점의 위치를 원래의 위치에 비해 오른쪽으로 한칸 있는 곳에 있다고 착각했습니다. 승혜가 본 숫자와 지우가 착각한 숫자의 차가 37.35일때 승혜가 본 숫자는 얼마인지 구하시오.",
        "question_en": "Ji-woo and Seunghye saw the same number, but Jiwoo shifted the decimal point of the number one space to the right by mistake. If the difference of the number Seunghye saw and the number Jiwoo saw is 37.35, what is the number that Seunghye saw?",
        "answer_ko": "4.15",
        "answer_en": "4.15",
        "solution_abst_ko": "37.35 9 [OP_DIV]",
        "solution_abst_en": "37.35 9 [OP_DIV]",
        "solution_code_ko": "var_a = 37.35\nvar_b = 9\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 37.35\nvar_b = 9\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "3773": {
        "category": "Possibility",
        "question_ko": "서로 다른 4개의 의자가 있습니다. 2명이 앉으려고 할 때, 앉을 수 있는 방법은 모두 몇 가지입니까?",
        "question_en": "There are 4 different chairs. When two people want to sit down, in how many ways can they sit?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "4 2 [OP_COMB]",
        "solution_abst_en": "4 2 [OP_COMB]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))"
    },
    "3774": {
        "category": "Geometry",
        "question_ko": "어떤 직육면체 방의 3면의 넓이가 각각 4제곱센티미터(㎠) , 3제곱센티미터(㎠) , 6제곱센티미터(㎠)입니다. 이 방에 모든 벽과 바닥에 1제곱센티미터(㎠)크기의 정사각형 타일을 붙이려면 몇 개가 필요합니까?",
        "question_en": "A rectangular room has sides with three different areas of 4 square centimetres (cm2) , 3 square centimetres (cm2) , and 6 square centimetres (cm2) , respectively. How many square tiles measuring 1 square centimetre (cm2) are needed to cover all the walls, floor, and ceiling of this room?",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "4 3 6 [OP_ADD] [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "4 3 6 [OP_ADD] [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 4\nvar_b = 3\nvar_c = 6\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 3\nvar_c = 6\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "3775": {
        "category": "Correspondence",
        "question_ko": "한 자리 수 A와 B가 있습니다. 이 둘을 이용해 만든 A56B가 36으로 나누어 떨어질 때, A에 알맞은 숫자는 모두 몇 개인지 구하시오.",
        "question_en": "There are single-digit numbers A and B. If A56B made using these two is divisible by 36, how many numbers are there for A?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "A56B [OP_GEN_POSSIBLE_LIST] 36 [OP_LIST_DIVISIBLE] A56B A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_abst_en": "A56B [OP_GEN_POSSIBLE_LIST] 36 [OP_LIST_DIVISIBLE] A56B A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 'A56B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 36\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 'A56B'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nvar_e = len(list_c)\nprint(int(var_e))",
        "solution_code_en": "var_a = 'A56B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 36\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 'A56B'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nvar_e = len(list_c)\nprint(int(var_e))"
    },
    "3776": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 가장 큰 수와 그 다음으로 큰 수로 나눈 나머지는 얼마입니까?",
        "question_en": "There are five numbers 10, 11, 12, 13, and 14. What is the remainder of the largest number divided by the next largest number?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_MOD]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_MOD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[-var_h]\nvar_j = var_g % var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[-var_h]\nvar_j = var_g % var_i\nprint(int(var_j))"
    },
    "3777": {
        "category": "Geometry",
        "question_ko": "어떤 직육면체의 부피가 28세제곱센티미터(㎤) 이고 높이가 4센티미터(㎝)이다. 밑면의 넓이는 얼마입니까?",
        "question_en": "A cuboid has a volume of 28 cubic centimeters (cm3) and a height of 4 centimeters (cm). What is the area of the base?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "28 4 [OP_DIV]",
        "solution_abst_en": "28 4 [OP_DIV]",
        "solution_code_ko": "var_a = 28\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 28\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "3778": {
        "category": "Arithmetic calculation",
        "question_ko": "민지는 오늘 물을 오전에 0.26리터(L) 마셨고 오후에 0.37리터(L) 마셨습니다. 민지가 오늘 마신 물은 모두 몇 리터(L)입니까?",
        "question_en": "Minji drank 0.26 liters (L) of water in the morning and 0.37 liters (L) in the afternoon. How many liters (L) of water did Minji drink today?",
        "answer_ko": "0.63",
        "answer_en": "0.63",
        "solution_abst_ko": "0.26 0.37 [OP_ADD]",
        "solution_abst_en": "0.26 0.37 [OP_ADD]",
        "solution_code_ko": "var_a = 0.26\nvar_b = 0.37\nvar_c = var_a + var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 0.26\nvar_b = 0.37\nvar_c = var_a + var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "3779": {
        "category": "Correspondence",
        "question_ko": "14A+2B3=418일 때, A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "When 14A+2B3=418, what number should go in A?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "14A+2B3=418 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "14A+2B3=418 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '14A+2B3=418'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '14A+2B3=418'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "3780": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 8로 나누어야 하는데 실수로 7로 나누었더니 몫이 12이고 나머지가 5였다. 올바르게 계산했을 때 몫이 얼마일지 구하여라.",
        "question_en": "A number must be divided by 8, but when you accidentally divide it by 7, the quotient is 12 and the remainder is 5. Find what the quotient would be if calculated correctly.",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "12 7 [OP_MUL] 5 [OP_ADD] 8 [OP_FDIV]",
        "solution_abst_en": "12 7 [OP_MUL] 5 [OP_ADD] 8 [OP_FDIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e // var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 12\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e // var_f\nprint(int(var_g))"
    },
    "3781": {
        "category": "Arithmetic calculation",
        "question_ko": "고구마 52.5킬로그램(㎏)을 한 사람 당 5킬로그램(㎏)씩 나누어 줄 때, 나누어 주고 남는 고구마는 몇 그램(g)인지 구하시오.",
        "question_en": "When 52.5 kg (kg) of sweet potato is divided by 5 kg (kg) per person, find how many grams (g) of sweet potato are left after sharing.",
        "answer_ko": "2500",
        "answer_en": "2500",
        "solution_abst_ko": "52.5 5 [OP_MOD] 1000 [OP_MUL]",
        "solution_abst_en": "52.5 5 [OP_MOD] 1000 [OP_MUL]",
        "solution_code_ko": "var_a = 52.5\nvar_b = 5\nvar_c = var_a % var_b\nvar_d = 1000\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 52.5\nvar_b = 5\nvar_c = var_a % var_b\nvar_d = 1000\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "3782": {
        "category": "Comparison",
        "question_ko": "일렬로 선 줄에서 석진이는 앞에서 8번째, 뒤에서 6번째 자리에 서있습니다. 총 몇 명의 친구들이 줄을 서 있는지 구하시오.",
        "question_en": "In the line, Seokjin stands 8th from the front and 6th from the back. Find the total number of students standing in the line.",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "8 6 [OP_ADD] 1 [OP_SUB]",
        "solution_abst_en": "8 6 [OP_ADD] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 8\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3783": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 16을 곱하고 8을 더해야 할 것을 잘못하여 16으로 나누었더니 몫이 8로 나누어떨어졌습니다. 바르게 계산한 값을 구하세요.",
        "question_en": "When you should multiply a number by 16 and add 8, you mistakenly divide it by 16 and the quotient is divided by 8. Find the correct calculated value.",
        "answer_ko": "2056",
        "answer_en": "2056",
        "solution_abst_ko": "8 16 [OP_MUL] 16 [OP_MUL] 8 [OP_ADD]",
        "solution_abst_en": "8 16 [OP_MUL] 16 [OP_MUL] 8 [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 16\nvar_e = var_c * var_d\nvar_f = 8\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 8\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 16\nvar_e = var_c * var_d\nvar_f = 8\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "3784": {
        "category": "Geometry",
        "question_ko": "바둑돌을 가로로 4개씩, 세로로 8개씩 빈틈없이 늘어놓아 직사각형을 만들었습니다. 둘레에 놓인 바둑돌은 몇 개입니까?",
        "question_en": "I made a rectangle by arranging 4 Go stones horizontally on each row and 8 vertically on each column. How many Go stones are at the perimeter?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "4 8 [OP_ADD] 2 [OP_MUL] 4 [OP_SUB]",
        "solution_abst_en": "4 8 [OP_ADD] 2 [OP_MUL] 4 [OP_SUB]",
        "solution_code_ko": "var_a = 4\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "3785": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 7/5을 빼고 5를 곱해야 할 것을 잘못하여 7/5를 더했더니 81/20이 되었습니다. 바르게 계산한 값을 구하시오.",
        "question_en": "I made a mistake and added 7/5 to this particular number, when I had to subtract 7/5 from this number and then multiply it by 5, and it became 81/20. Find the rightly calculated value.",
        "answer_ko": "6.25",
        "answer_en": "6.25",
        "solution_abst_ko": "81/20 7/5 [OP_SUB] 7/5 [OP_SUB] 5 [OP_MUL]",
        "solution_abst_en": "81/20 7/5 [OP_SUB] 7/5 [OP_SUB] 5 [OP_MUL]",
        "solution_code_ko": "var_a = 4.05\nvar_b = 1.4\nvar_c = var_a - var_b\nvar_d = 1.4\nvar_e = var_c - var_d\nvar_f = 5\nvar_g = var_e * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 4.05\nvar_b = 1.4\nvar_c = var_a - var_b\nvar_d = 1.4\nvar_e = var_c - var_d\nvar_f = 5\nvar_g = var_e * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "3786": {
        "category": "Arithmetic calculation",
        "question_ko": "백의 자리 숫자가 4이고 십의 자리 숫자가 8인 세 자리 수 중에서 가장 큰 수와 가장 작은 수의 합을 구하시오.",
        "question_en": "Find the sum of the largest and smallest three-digit numbers whose hundreds digit is 4 and whose tens digit is 8.",
        "answer_ko": "969",
        "answer_en": "969",
        "solution_abst_ko": "[OP_LIST_SOL] 4 8 A [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 4 8 A [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 8\nvar_c = 'A'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nans_dict = dict()\nvar_d = str(var_d)\nlist_b = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_d) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_b.append(new_elem)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 4\nvar_b = 8\nvar_c = 'A'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nans_dict = dict()\nvar_d = str(var_d)\nlist_b = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_d) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_b.append(new_elem)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))"
    },
    "3787": {
        "category": "Geometry",
        "question_ko": "가로의 길이가 9센티미터(㎝), 세로의 길이가 7센티미터(㎝)인 직육면체가 있습니다. 부피가 315제곱센티미터(㎠) 이라면, 이 직육면체의 높이는 몇 센티미터(㎝)입니까?",
        "question_en": "A rectangular parallelepiped is 9 centimeters (cm) wide and 7 centimeters (cm) long. If the volume is 315 square centimeters (cm2), how many centimeters (cm) is the height of this cuboid?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "315 9 [OP_DIV] 7 [OP_DIV]",
        "solution_abst_en": "315 9 [OP_DIV] 7 [OP_DIV]",
        "solution_code_ko": "var_a = 315\nvar_b = 9\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 315\nvar_b = 9\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "3788": {
        "category": "Possibility",
        "question_ko": "서로 다른 2가지 과일을 고르는 경우를 구하려고 합니다. 과일은 사과, 복숭아, 배, 참외, 귤이 있습니다. 이때 경우는 모두 몇 가지입니까?",
        "question_en": "You are trying to find the case of choosing two different fruits. There are fruits including apples, peaches, pears, melons, and tangerines. How many cases are available?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 복숭아 배 참외 귤 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] apples peaches pears melons tangerines [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '복숭아'\nvar_c = '배'\nvar_d = '참외'\nvar_e = '귤'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h / (i+1)\nprint(int(var_h))",
        "solution_code_en": "var_a = 'apples'\nvar_b = 'peaches'\nvar_c = 'pears'\nvar_d = 'melons'\nvar_e = 'tangerines'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h / (i+1)\nprint(int(var_h))"
    },
    "3789": {
        "category": "Arithmetic calculation",
        "question_ko": "장난감 공장에서 기계 A는 12일 동안 288개의 장난감을 만들고, 기계 B는 9일 동안 243개의 장난감을 만든다. 두 기계가 하루에 만든 장난감 개수의 차이를 구하시오.",
        "question_en": "In a toy factory, machine A makes 288 toys in 12 days, and machine B makes 243 toys in 9 days. Find the difference between the number of toys made per day by the two machines.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "288 12 [OP_DIV] 243 9 [OP_DIV] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "288 12 [OP_DIV] 243 9 [OP_DIV] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 288\nvar_b = 12\nvar_c = var_a / var_b\nvar_d = 243\nvar_e = 9\nvar_f = var_d / var_e\nvar_g = var_c - var_f\nvar_h = abs(var_g)\nprint(int(var_h))",
        "solution_code_en": "var_a = 288\nvar_b = 12\nvar_c = var_a / var_b\nvar_d = 243\nvar_e = 9\nvar_f = var_d / var_e\nvar_g = var_c - var_f\nvar_h = abs(var_g)\nprint(int(var_h))"
    },
    "3790": {
        "category": "Arithmetic calculation",
        "question_ko": "크기와 무게가 같은 감을 바구니에 가득 담아 무게를 재었더니 62킬로그램(㎏)이었습니다. 이 중 절반의 감을 덜어낸 후에 바구니와 함께 무게를 재어 보니 34킬로그램(㎏)이 되었습니다. 바구니만의 무게는 몇 킬로그램(㎏)입니까?",
        "question_en": "A basket full of persimmons of the same size and weight weighed 62 kilograms (kg). After removing half of the persimmons, I weighed them together with the basket and found that they weighed 34 kilograms (kg). What is the weight of the basket without the persimmons?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "62 62 34 [OP_SUB] 2 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "62 62 34 [OP_SUB] 2 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 62\nvar_b = 62\nvar_c = 34\nvar_d = var_b - var_c\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_a - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 62\nvar_b = 62\nvar_c = 34\nvar_d = var_b - var_c\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_a - var_f\nprint(int(var_g))"
    },
    "3791": {
        "category": "Geometry",
        "question_ko": "종이접기 시간에 동건이는 밑변이 3센티미터(㎝) 이고 높이가 2센티미터(㎝) 인 삼각형 모양의 종이를 접었고, 지혜는 밑변이 3센티미터(㎝) 이고 높이가 6.02 센티미터(㎝) 인 삼각형을 모양의 종이를 접었습니다. 지혜가 접은 삼각형의 넓이는 동건이가 접은 삼각형의 넓이의 몇 배입니까?",
        "question_en": "During the origami class, Donggeon folded the paper in a triangular shape with a base of 3 centimeters (cm) and a height of 2 centimeters (cm), and Jihye folded the paper in a triangular shape with a base of 3 centimeters (cm) and a height of 6.02 centimeters (cm). How many times the area of the triangle folded by Jihye is the area of the triangle folded by Donggeon?",
        "answer_ko": "3.01",
        "answer_en": "3.01",
        "solution_abst_ko": "3 6.02 [OP_MUL] 2 [OP_DIV] 3 2 [OP_MUL] 2 [OP_DIV] [OP_DIV]",
        "solution_abst_en": "3 6.02 [OP_MUL] 2 [OP_DIV] 3 2 [OP_MUL] 2 [OP_DIV] [OP_DIV]",
        "solution_code_ko": "var_a = 3\nvar_b = 6.02\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 3\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = 2\nvar_j = var_h / var_i\nvar_k = var_e / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 3\nvar_b = 6.02\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 3\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = 2\nvar_j = var_h / var_i\nvar_k = var_e / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "3792": {
        "category": "Correspondence",
        "question_ko": "8050 에 어떤 수를 곱하였더니 80.5 가 되었습니다. 어떤 수는 얼마입니까?",
        "question_en": "8050 multiplied by a number gives 80.5. What number is it?",
        "answer_ko": "0.01",
        "answer_en": "0.01",
        "solution_abst_ko": "80.5 8050 [OP_DIV]",
        "solution_abst_en": "80.5 8050 [OP_DIV]",
        "solution_code_ko": "var_a = 80.5\nvar_b = 8050\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 80.5\nvar_b = 8050\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "3793": {
        "category": "Geometry",
        "question_ko": "가로와 세로의 비가 7:5인 직사각형 모양의 공책이 있습니다. 이 공책의 둘레의 길이가 48센티미터(㎝)라면, 이 공책의 넓이는 몇 제곱센티미터(㎠)인지 구하시오.",
        "question_en": "There is a rectangular notebook with a width to height ratio of 7:5. If the perimeter of this notebook is 48 centimeters (cm), what is the area in square centimeters (cm2) of this notebook?",
        "answer_ko": "140",
        "answer_en": "140",
        "solution_abst_ko": "48 2 [OP_DIV] 7 [OP_MUL] 7 5 [OP_ADD] [OP_DIV] 48 2 [OP_DIV] 5 [OP_MUL] 7 5 [OP_ADD] [OP_DIV] [OP_MUL]",
        "solution_abst_en": "48 2 [OP_DIV] 7 [OP_MUL] 7 5 [OP_ADD] [OP_DIV] 48 2 [OP_DIV] 5 [OP_MUL] 7 5 [OP_ADD] [OP_DIV] [OP_MUL]",
        "solution_code_ko": "var_a = 48\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c * var_d\nvar_f = 7\nvar_g = 5\nvar_h = var_f + var_g\nvar_i = var_e / var_h\nvar_j = 48\nvar_k = 2\nvar_l = var_j / var_k\nvar_m = 5\nvar_n = var_l * var_m\nvar_o = 7\nvar_p = 5\nvar_q = var_o + var_p\nvar_r = var_n / var_q\nvar_s = var_i * var_r\nprint(int(var_s))",
        "solution_code_en": "var_a = 48\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c * var_d\nvar_f = 7\nvar_g = 5\nvar_h = var_f + var_g\nvar_i = var_e / var_h\nvar_j = 48\nvar_k = 2\nvar_l = var_j / var_k\nvar_m = 5\nvar_n = var_l * var_m\nvar_o = 7\nvar_p = 5\nvar_q = var_o + var_p\nvar_r = var_n / var_q\nvar_s = var_i * var_r\nprint(int(var_s))"
    },
    "3794": {
        "category": "Arithmetic calculation",
        "question_ko": "마트에 사과 240킬로그램(㎏)이 있고, 배는 사과의 3배만큼 있습니다. 사과와 배는 모두 몇 킬로그램(㎏) 있습니까?",
        "question_en": "There are 240 kilograms (kg) of apples in the market, and there are three times as many pears as apples. How many kilograms (kg) are there in both apples and pears?",
        "answer_ko": "960",
        "answer_en": "960",
        "solution_abst_ko": "240 240 3 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "240 240 3 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 240\nvar_b = 240\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 240\nvar_b = 240\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "3795": {
        "category": "Correspondence",
        "question_ko": "10-A=6일 때, A에 들어가야 하는 숫자를 구하시오",
        "question_en": "When 10-A=6, find the number that must be in A.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "10-A=6 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "10-A=6 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '10-A=6'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '10-A=6'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "3796": {
        "category": "Correspondence",
        "question_ko": "10으로 어떤 수를 나누었더니 12를 얻었습니다. 어떤 수는?",
        "question_en": "What number divided by 10 gives 12?",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "12 10 [OP_MUL]",
        "solution_abst_en": "12 10 [OP_MUL]",
        "solution_code_ko": "var_a = 12\nvar_b = 10\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 12\nvar_b = 10\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "3797": {
        "category": "Correspondence",
        "question_ko": "서로 다른 수 A, B, C, D가 있습니다. A+C=15, A-B=1, C+C=A, B-D=2입니다. D를 구하시오.",
        "question_en": "There are different numbers A, B, C and D. In the case of A+C=15, A-B=1, C+C=A and B-D=2, get D.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "C+C+C=15 C [OP_NUM_UNK_SOLVER] 2 [OP_MUL] 1 [OP_SUB] 2 [OP_SUB]",
        "solution_abst_en": "C+C+C=15 C [OP_NUM_UNK_SOLVER] 2 [OP_MUL] 1 [OP_SUB] 2 [OP_SUB]",
        "solution_code_ko": "var_a = 'C+C+C=15'\nvar_b = 'C'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 'C+C+C=15'\nvar_b = 'C'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "3798": {
        "category": "Geometry",
        "question_ko": "원 모양의 꽃밭이 있습니다. 원주율이 3이고 꽃밭의 반지름이 0.6미터(m)일 때 꽃밭의 넓이는 몇 제곱센티미터입니까?",
        "question_en": "There is a flower garden in the shape of a circle. Assume the pi as 3 and the radius of the flower garden is 0.6 meters (m), how many square meters (m2) is the area of the flower garden?",
        "answer_ko": "1.08",
        "answer_en": "1.08",
        "solution_abst_ko": "3 0.6 2 [OP_POW] [OP_MUL]",
        "solution_abst_en": "3 0.6 2 [OP_POW] [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 0.6\nvar_c = 2\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 3\nvar_b = 0.6\nvar_c = 2\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "3799": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 기계 A 혼자서 일을 끝 마치는데 10시간이 걸리고 기계 B가 혼자서 일을 끝 마치는데 15시간이 걸린다. A, B가 동시에 이 일을 하면 몇 시간이 걸리는지 구하시오.",
        "question_en": "Machine A alone takes 10 hours to complete the job, and machine B takes 15 hours to complete the job alone. How many hours would it take for A and B to do this at the same time?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "1 1 10 [OP_DIV] 1 15 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_abst_en": "1 1 10 [OP_DIV] 1 15 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 1\nvar_c = 10\nvar_d = var_b / var_c\nvar_e = 1\nvar_f = 15\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = var_a / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))",
        "solution_code_en": "var_a = 1\nvar_b = 1\nvar_c = 10\nvar_d = var_b / var_c\nvar_e = 1\nvar_f = 15\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = var_a / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))"
    },
    "3800": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중에서 가장 큰 수와 그 다음으로 큰 수의 합은 얼마입니까?",
        "question_en": "There are three numbers 10, 11 and 12. What is the sum of the largest number and the next largest number?",
        "answer_ko": "23",
        "answer_en": "23",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = var_e + var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = var_e + var_g\nprint(int(var_h))"
    },
    "3801": {
        "category": "Arithmetic calculation",
        "question_ko": "당근 4개를 토끼 2마리가 하루에 먹습니다. 토끼 3마리가 당근 54개를 먹는 데 며칠이 걸리는가?",
        "question_en": "2 rabbits eat 4 carrots a day. How many days will it take for 3 rabbits to eat 54 carrots?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "54 4 2 [OP_DIV] 3 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "54 4 2 [OP_DIV] 3 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 54\nvar_b = 4\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_a / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 54\nvar_b = 4\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_a / var_f\nprint(int(var_g))"
    },
    "3802": {
        "category": "Possibility",
        "question_ko": "2, 0, 7, 5, 9 중 서로 다른 3개의 숫자를 뽑아 만들 수 있는 세 자리 수 중에서 가장 작은 수와 4번째로 작은 수의 합을 구하시오.",
        "question_en": "Find the sum of the smallest and fourth smallest three-digit numbers that can be made by drawing three different numbers from 2, 0, 7, 5, and 9.",
        "answer_ko": "455",
        "answer_en": "455",
        "solution_abst_ko": "[OP_LIST_SOL] 2 0 7 5 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 4 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 2 0 7 5 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 4 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 0\nvar_c = 7\nvar_d = 5\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = 4\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 2\nvar_b = 0\nvar_c = 7\nvar_d = 5\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = 4\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h + var_j\nprint(int(var_k))"
    },
    "3803": {
        "category": "Correspondence",
        "question_ko": "어떤 수의 3배를 5로 나눈 뒤 220을 빼고 4를 곱하였더니 320이 되었습니다. 어떤 수를 구하시오.",
        "question_en": "Dividing 3 times of a certain number by 5, and subtracting 220, and multiplying that by 4 resulted in 320. Find out that number in question.",
        "answer_ko": "500",
        "answer_en": "500",
        "solution_abst_ko": "320 4 [OP_DIV] 220 [OP_ADD] 5 [OP_MUL] 3 [OP_DIV]",
        "solution_abst_en": "320 4 [OP_DIV] 220 [OP_ADD] 5 [OP_MUL] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 320\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 220\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = var_e * var_f\nvar_h = 3\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 320\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 220\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = var_e * var_f\nvar_h = 3\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "3804": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 8센티미터(㎝)인 정사각형 안에 반지름의 길이가 2센티미터(㎝)인 원을 겹치지 않게 그리려고 합니다. 모두 몇 개 그릴 수 있습니까?",
        "question_en": "We want to draw a circle with a radius of 2 centimeters (cm) inside a square with a side length of 8 centimeters (cm) without overlapping. How many can you draw in all?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "8 2 2 [OP_MUL] [OP_DIV] 2 [OP_POW]",
        "solution_abst_en": "8 2 2 [OP_MUL] [OP_DIV] 2 [OP_POW]",
        "solution_code_ko": "var_a = 8\nvar_b = 2\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nvar_f = 2\nvar_g = var_e ** var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 8\nvar_b = 2\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nvar_f = 2\nvar_g = var_e ** var_f\nprint(int(var_g))"
    },
    "3805": {
        "category": "Possibility",
        "question_ko": "1, 3, 5, 7, 9 다섯 장의 숫자카드가 있다. 이 카드를 사용하여 만들 수 있는 3자리 자연수 중 500초과인 수는 모두 몇 개인지 구하시오. (단, 카드는 중복사용 가능하다.)",
        "question_en": "There are five number cards 1, 3, 5, 7, and 9. How many three-digit natural numbers that can be made using this card are greater than 500? (However, the card can be used repeatedly.)",
        "answer_ko": "75",
        "answer_en": "75",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 5 7 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 500 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 5 7 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 500 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 5\nvar_d = 7\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 500\nlist_c = []\nfor i in list_b:\n    if i > var_g:\n        list_c.append(i)\nvar_h = len(list_c)\nprint(int(var_h))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 5\nvar_d = 7\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 500\nlist_c = []\nfor i in list_b:\n    if i > var_g:\n        list_c.append(i)\nvar_h = len(list_c)\nprint(int(var_h))"
    },
    "3806": {
        "category": "Possibility",
        "question_ko": "4, 5, 8, 9 중 3개를 사용하여 백의 자리 숫자가 5인 두 번째 작은 수는 무엇입니까?",
        "question_en": "Using 3 of 4, 5, 8, and 9, what is the second smallest number whose hundredth place is 5?",
        "answer_ko": "459",
        "answer_en": "459",
        "solution_abst_ko": "[OP_LIST_SOL] 4 5 8 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 5 [OP_LIST_SEARCH_FIXED_DIGIT] 2 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 4 5 8 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 5 [OP_LIST_SEARCH_FIXED_DIGIT] 2 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 4\nvar_b = 5\nvar_c = 8\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 5\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 2\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nprint(int(var_i))",
        "solution_code_en": "var_a = 4\nvar_b = 5\nvar_c = 8\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 5\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 2\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nprint(int(var_i))"
    },
    "3807": {
        "category": "Comparison",
        "question_ko": "유정이는 지우개 4개를 가지고 있었는데 언니에게 3개를 더 받았습니다. 은지는 가지고 있던 지우개 13개 중에서 7개를 동생에게 주었습니다. 유정이와 은지 중 지우개를 더 많이 가지고 있는 사람은 누구입니까?",
        "question_en": "Yujeong had 4 erasers, and she got 3 more from her sister. Eunji gave 7 of the 13 erasers she had to her sister. Who has more erasers, Yujeong or Eunji?",
        "answer_ko": "유정",
        "answer_en": "Yujeong",
        "solution_abst_ko": "[OP_LIST_SOL] 유정 은지 [OP_LIST_EOL] [OP_LIST_SOL] 4 3 [OP_ADD] 13 7 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yujeong Eunji [OP_LIST_EOL] [OP_LIST_SOL] 4 3 [OP_ADD] 13 7 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '유정'\nvar_b = '은지'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = 13\nvar_g = 7\nvar_h = var_f - var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Yujeong'\nvar_b = 'Eunji'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = 13\nvar_g = 7\nvar_h = var_f - var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "3808": {
        "category": "Possibility",
        "question_ko": "4, 0, 9, 8에서 서로 다른 3개를 뽑아 세 자리 수를 만들었을 때, 그중에서 3번째로 작은 수를 구하시오",
        "question_en": "When three different numbers are drawn from 4, 0, 9, and 8 to form a three-digit number, find the third smallest number among them.",
        "answer_ko": "480",
        "answer_en": "480",
        "solution_abst_ko": "[OP_LIST_SOL] 4 0 9 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 3 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 4 0 9 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 3 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 4\nvar_b = 0\nvar_c = 9\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 0\nvar_c = 9\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nprint(int(var_g))"
    },
    "3809": {
        "category": "Comparison",
        "question_ko": "태형이는 집에 13번째로 들어갔고, 석진이는 태형이가 들어가고 난 후 18번째에 들어갔습니다. 석진이는 몇 번째로 집에 들어갔습니까?",
        "question_en": "Taehyung entered the house as the 13th person, and Seokjin entered the house as the 18th person after Taehyung. How many times did Seokjin enter the house?",
        "answer_ko": "31",
        "answer_en": "31",
        "solution_abst_ko": "13 18 [OP_ADD]",
        "solution_abst_en": "13 18 [OP_ADD]",
        "solution_code_ko": "var_a = 13\nvar_b = 18\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 13\nvar_b = 18\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "3810": {
        "category": "Arithmetic calculation",
        "question_ko": "마스크 15개가 들어갈 수 있는 상자 18개가 있습니다. 상자마다 3개씩 마스크가 비어있다면 모든 마스크의 개수는 몇 개 입니까?",
        "question_en": "There are 18 boxes that can fit 15 masks. If there are 3 masks lacking in each box, what is the total number of masks?",
        "answer_ko": "216",
        "answer_en": "216",
        "solution_abst_ko": "15 3 [OP_SUB] 18 [OP_MUL]",
        "solution_abst_en": "15 3 [OP_SUB] 18 [OP_MUL]",
        "solution_code_ko": "var_a = 15\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 18\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 18\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "3811": {
        "category": "Arithmetic calculation",
        "question_ko": "두 자리 숫자를 더하는 연산에서 일의 자리 숫자 7을 1로 잘못보고 십의 자리 숫자 4를 6으로 잘못본 뒤 계산을 했더니 146이 나왔습니다. 바르게 계산하면 얼마입니까?",
        "question_en": "In the calculation of adding two-digit numbers, the number 7 in the ones was mistaken for 1 and the number 4 in the tens was mistaken for 6, and the result was 146. Find out the result when correctly calculated.",
        "answer_ko": "132",
        "answer_en": "132",
        "solution_abst_ko": "146 10 4 6 [OP_SUB] [OP_MUL] [OP_ADD] 1 7 1 [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_abst_en": "146 10 4 6 [OP_SUB] [OP_MUL] [OP_ADD] 1 7 1 [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 146\nvar_b = 10\nvar_c = 4\nvar_d = 6\nvar_e = var_c - var_d\nvar_f = var_b * var_e\nvar_g = var_a + var_f\nvar_h = 1\nvar_i = 7\nvar_j = 1\nvar_k = var_i - var_j\nvar_l = var_h * var_k\nvar_m = var_g + var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 146\nvar_b = 10\nvar_c = 4\nvar_d = 6\nvar_e = var_c - var_d\nvar_f = var_b * var_e\nvar_g = var_a + var_f\nvar_h = 1\nvar_i = 7\nvar_j = 1\nvar_k = var_i - var_j\nvar_l = var_h * var_k\nvar_m = var_g + var_l\nprint(int(var_m))"
    },
    "3812": {
        "category": "Comparison",
        "question_ko": "1/4, 0.2, 1/3, 2/7, 0.25, 1/6 중 0.3보다 작거나 같은 수는 몇 개입니까?",
        "question_en": "Among 1/4, 0.2, 1/3, 2/7, 0.25, and 1/6, how many are less than or equal to 0.3?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "[OP_LIST_SOL] 1/4 0.2 1/3 2/7 0.25 1/6 [OP_LIST_EOL] 0.3 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1/4 0.2 1/3 2/7 0.25 1/6 [OP_LIST_EOL] 0.3 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.25\nvar_b = 0.2\nvar_c = 0.3333333333333333\nvar_d = 0.2857142857142857\nvar_e = 0.25\nvar_f = 0.16666666666666666\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 0.3\nlist_b = []\nfor i in list_a:\n    if i <= var_g:\n        list_b.append(i)\nvar_h = len(list_b)\nprint(int(var_h))",
        "solution_code_en": "var_a = 0.25\nvar_b = 0.2\nvar_c = 0.3333333333333333\nvar_d = 0.2857142857142857\nvar_e = 0.25\nvar_f = 0.16666666666666666\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 0.3\nlist_b = []\nfor i in list_a:\n    if i <= var_g:\n        list_b.append(i)\nvar_h = len(list_b)\nprint(int(var_h))"
    },
    "3813": {
        "category": "Arithmetic calculation",
        "question_ko": "인준이가 달리기 시합을 합니다. 인준이가 20초동안 쉬지 않고 달리면 150미터(m)를 달릴 수 있습니다. 인준이가 쉬지 않고 1분을 달린다면 몇 미터(m)를 달릴 수 있습니까?",
        "question_en": "Injun has a running race. If Injun runs for 20 seconds without stopping, he can run 150 meters (m). How many meters (m) can Injun run for 1 minute without rest?",
        "answer_ko": "450",
        "answer_en": "450",
        "solution_abst_ko": "1 60 [OP_MUL] 20 [OP_DIV] 150 [OP_MUL]",
        "solution_abst_en": "1 60 [OP_MUL] 20 [OP_DIV] 150 [OP_MUL]",
        "solution_code_ko": "var_a = 1\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 20\nvar_e = var_c / var_d\nvar_f = 150\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 20\nvar_e = var_c / var_d\nvar_f = 150\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "3814": {
        "category": "Correspondence",
        "question_ko": "A82+B4=216일 때, A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "If A82+B4=216 is valid, what number should go in A?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "A82+B4=216 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A82+B4=216 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A82+B4=216'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A82+B4=216'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "3815": {
        "category": "Possibility",
        "question_ko": "현지, 은정, 미금, 영미 4명의 학생을 한 줄로 세울 때, 은정이가 맨 앞 또는 맨 뒤에 서는 경우의 수를 구하여라",
        "question_en": "When 4 students who are Hyunji, Eunjeong, Migeum, and Youngmi are lined up in a row, find the number of cases where Eunjeong stands at the front or at the back.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "[OP_LIST_SOL] 현지 은정 미금 영미 [OP_LIST_EOL] [OP_LIST_SOL] 은정 [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] 앞 뒤 [OP_LIST_EOL] [OP_LIST_LEN] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] Hyunji Eunjeong Migeum Youngmi [OP_LIST_EOL] [OP_LIST_SOL] Eunjeong [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] Front Back [OP_LIST_EOL] [OP_LIST_LEN] [OP_MUL]",
        "solution_code_ko": "var_a = '현지'\nvar_b = '은정'\nvar_c = '미금'\nvar_d = '영미'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '은정'\nlist_b= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_f = len(list_c)\nvar_g = len(list_c)\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nvar_i = '앞'\nvar_j = '뒤'\nlist_d= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_d.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_d.append(var_i)\nlist_d.reverse()\nvar_k = len(list_d)\nvar_l = var_h * var_k\nprint(int(var_l))",
        "solution_code_en": "var_a = 'Hyunji'\nvar_b = 'Eunjeong'\nvar_c = 'Migeum'\nvar_d = 'Youngmi'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'Eunjeong'\nlist_b= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_f = len(list_c)\nvar_g = len(list_c)\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nvar_i = 'Front'\nvar_j = 'Back'\nlist_d= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_d.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_d.append(var_i)\nlist_d.reverse()\nvar_k = len(list_d)\nvar_l = var_h * var_k\nprint(int(var_l))"
    },
    "3816": {
        "category": "Correspondence",
        "question_ko": "AB3+36=269입니다. A는 얼마인가요?",
        "question_en": "AB3+36=269. How much is A?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "AB3+36=269 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "AB3+36=269 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'AB3+36=269'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'AB3+36=269'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "3817": {
        "category": "Correspondence",
        "question_ko": "A4+3B=79입니다. A는 무엇일까요?",
        "question_en": "The sum of A4 and 3B is 79. what is A?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "A4+3B=79 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A4+3B=79 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A4+3B=79'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A4+3B=79'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "3818": {
        "category": "Possibility",
        "question_ko": "4개의 숫자 4, 0, 2, 6을 두 번씩 사용하여 여덟 자리 수를 만들려고 합니다. 만들 수 있는 가장 큰 수와 가장 작은 수의 합을 구하시오.",
        "question_en": "You want to create an eight-digit number by using the four numbers 4, 0, 2, and 6 twice. Find the sum of the largest and smallest possible numbers.",
        "answer_ko": "86466666",
        "answer_en": "86466666",
        "solution_abst_ko": "[OP_LIST_SOL] 4 4 0 0 2 2 6 6 [OP_LIST_EOL] 8 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 4 4 0 0 2 2 6 6 [OP_LIST_EOL] 8 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 4\nvar_c = 0\nvar_d = 0\nvar_e = 2\nvar_f = 2\nvar_g = 6\nvar_h = 6\nlist_a= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_i = 8\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_i))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_j = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_k = list_c[-var_j]\nvar_l = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_m = list_d[var_l-1]\nvar_n = var_k + var_m\nprint(int(var_n))",
        "solution_code_en": "var_a = 4\nvar_b = 4\nvar_c = 0\nvar_d = 0\nvar_e = 2\nvar_f = 2\nvar_g = 6\nvar_h = 6\nlist_a= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_i = 8\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_i))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_j = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_k = list_c[-var_j]\nvar_l = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_m = list_d[var_l-1]\nvar_n = var_k + var_m\nprint(int(var_n))"
    },
    "3819": {
        "category": "Possibility",
        "question_ko": "3과 4로 나누어떨어지고 5로 나누면 나머지가 4인 두 자리 수를 찾으려고 합니다. 만들 수 있는 두 자리 수는 모두 몇 개입니까?",
        "question_en": "I'm trying to find a two-digit number that is divisible by 3 and 4 and has a remainder of 4 when divided by 5. How many two-digit numbers can you make?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "10 99 1 [OP_LIST_ARANGE] 3 4 [OP_LCM] [OP_LIST_DIVISIBLE] 5 4 [OP_LIST_DIVIDE_AND_REMAIN] [OP_LIST_LEN]",
        "solution_abst_en": "10 99 1 [OP_LIST_ARANGE] 3 4 [OP_LCM] [OP_LIST_DIVISIBLE] 5 4 [OP_LIST_DIVIDE_AND_REMAIN] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nvar_e = 4\nvar_f = var_e * var_d / math.gcd(int(var_e), int(var_d))\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nvar_g = 5\nvar_h = 4\nlist_c = [] \nvar_g = int(var_g)\nvar_h = int(var_h)\nif var_h < 0:\n    var_h = var_h + var_g\nfor i in list_b:\n    i = int(i)\n    if i%var_g == var_h:\n        list_c.append(i)\nvar_i = len(list_c)\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nvar_e = 4\nvar_f = var_e * var_d / math.gcd(int(var_e), int(var_d))\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nvar_g = 5\nvar_h = 4\nlist_c = [] \nvar_g = int(var_g)\nvar_h = int(var_h)\nif var_h < 0:\n    var_h = var_h + var_g\nfor i in list_b:\n    i = int(i)\n    if i%var_g == var_h:\n        list_c.append(i)\nvar_i = len(list_c)\nprint(int(var_i))"
    },
    "3820": {
        "category": "Correspondence",
        "question_ko": "선생님이 학생들에게 초콜릿을 나누어줍니다. 이때 6명에게 똑같이 나누어 주면 4개가 남고 8명에게 똑같이 나누어 주면 6개가 남고 10명에게 똑같이 나누어 주면 8개가 남는다고 한다. 이떄 선생님이 가지고 있는 초콜릿의 최소 개수는 몇 개입니까?",
        "question_en": "The teacher distributes chocolate to students evenly. There will be the following leftovers when each 6, 8, and 10 are distributed with an equal amount of candies: 4, 6, and 8. What is the minimum number of chocolates the teacher has?",
        "answer_ko": "118",
        "answer_en": "118",
        "solution_abst_ko": "0 9999 1 [OP_LIST_ARANGE] 6 4 [OP_LIST_DIVIDE_AND_REMAIN] 8 6 [OP_LIST_DIVIDE_AND_REMAIN] 10 8 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MIN]",
        "solution_abst_en": "0 9999 1 [OP_LIST_ARANGE] 6 4 [OP_LIST_DIVIDE_AND_REMAIN] 8 6 [OP_LIST_DIVIDE_AND_REMAIN] 10 8 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 0\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nvar_e = 4\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 8\nvar_g = 6\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 10\nvar_i = 8\nlist_d = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_c:\n    i = int(i)\n    if i%var_h == var_i:\n        list_d.append(i)\nvar_j = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_k = list_e[var_j-1]\nprint(int(var_k))",
        "solution_code_en": "var_a = 0\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nvar_e = 4\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 8\nvar_g = 6\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 10\nvar_i = 8\nlist_d = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_c:\n    i = int(i)\n    if i%var_h == var_i:\n        list_d.append(i)\nvar_j = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_k = list_e[var_j-1]\nprint(int(var_k))"
    },
    "3821": {
        "category": "Geometry",
        "question_ko": "정팔면체에서 꼭짓점은 모두 몇 개 일까요?",
        "question_en": "How many vertices are there in a regular octahedron?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "6",
        "solution_abst_en": "6",
        "solution_code_ko": "var_a = 6\nprint(int(var_a))",
        "solution_code_en": "var_a = 6\nprint(int(var_a))"
    },
    "3822": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 10, 11, 12, 13이 있습니다. 그 중에서 가장 큰 수와 그 다음으로 큰 수로 나눈 나머지는 얼마입니까?",
        "question_en": "There are four numbers 10, 11, 12, and 13. What is the remainder of the largest number divided by the next largest number?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_MOD]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_MOD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = var_f % var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = var_f % var_h\nprint(int(var_i))"
    },
    "3823": {
        "category": "Correspondence",
        "question_ko": "913에서 어떤 수를 빼었더니 514가 나왔습니다. 514에서 어떤 수를 빼면 얼마입니까?",
        "question_en": "Subtracting some number from 913 gives 514. How much is 514 minus some number?",
        "answer_ko": "115",
        "answer_en": "115",
        "solution_abst_ko": "514 913 514 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "514 913 514 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 514\nvar_b = 913\nvar_c = 514\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 514\nvar_b = 913\nvar_c = 514\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "3824": {
        "category": "Correspondence",
        "question_ko": "어떤 수는 5의 배수이고 5로 나누었더니 몫이 25 였습니다. 어떤 수에서 17을 뺀 값을 6으로 나눈 값을 구하시오.",
        "question_en": "A number is multiples of 5, and when divided by 5, the quotient is 25. Find the value of subtracting 17 from the number and then divided by 6.",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "25 5 [OP_MUL] 17 [OP_SUB] 6 [OP_DIV]",
        "solution_abst_en": "25 5 [OP_MUL] 17 [OP_SUB] 6 [OP_DIV]",
        "solution_code_ko": "var_a = 25\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 17\nvar_e = var_c - var_d\nvar_f = 6\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 25\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 17\nvar_e = var_c - var_d\nvar_f = 6\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "3825": {
        "category": "Arithmetic calculation",
        "question_ko": "팔찌 235개를 한 봉지에 10개씩 담아 3000원에 팔려고 합니다. 봉지에 담은 팔찌를 팔 때 최대 얼마를 받을 수 있습니까?",
        "question_en": "You are going to put 235 bracelets in a bag of 10 each and sell them for 3,000 won. What is the maximum amount you can get for selling a bagged bracelet?",
        "answer_ko": "69000",
        "answer_en": "69000",
        "solution_abst_ko": "235 10 [OP_FDIV] 3000 [OP_MUL]",
        "solution_abst_en": "235 10 [OP_FDIV] 3000 [OP_MUL]",
        "solution_code_ko": "var_a = 235\nvar_b = 10\nvar_c = var_a // var_b\nvar_d = 3000\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 235\nvar_b = 10\nvar_c = var_a // var_b\nvar_d = 3000\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "3826": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 10, 11, 12, 13이 있습니다. 그 중에서 가장 큰 수와 가장 작은 수의 곱은 얼마입니까?",
        "question_en": "There are four numbers 10, 11, 12, and 13. What is the remainder of the largest number divided by the next largest number?",
        "answer_ko": "130",
        "answer_en": "130",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f * var_h\nprint(int(var_i))"
    },
    "3827": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 2.95를 빼야 할 것을 잘못하여 더했더니 9.28이 되었습니다. 바르게 계산한 값을 구해 보시오.",
        "question_en": "I mistakenly added what should have subtracted 2.95 from a number, and I got 9.28. Find the correct calculated value.",
        "answer_ko": "3.38",
        "answer_en": "3.38",
        "solution_abst_ko": "9.28 2.95 [OP_SUB] 2.95 [OP_SUB]",
        "solution_abst_en": "9.28 2.95 [OP_SUB] 2.95 [OP_SUB]",
        "solution_code_ko": "var_a = 9.28\nvar_b = 2.95\nvar_c = var_a - var_b\nvar_d = 2.95\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 9.28\nvar_b = 2.95\nvar_c = var_a - var_b\nvar_d = 2.95\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "3828": {
        "category": "Arithmetic calculation",
        "question_ko": "달팽이 책상에 놓고 1시간 동안 움직인 거리를 재봤더니 4.25센티미터(㎝)였다. 몇 시간 이후 달팽이가 아까 거리를 쟀던 위치에서 부터 29.75센티미터(㎝)만큼 움직였다. 달팽이를 책상에 놓은지 몇 시간이 지났는지 구하시오.",
        "question_en": "When you put the snail on the table and measured the distance it moved for an hour, it was 4.25 centimeters (cm). After a few hours, the snail moved 29.75 centimeters (cm) from the position where the distance was measured earlier. How many hours have passed since the snail was placed on the table?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "29.75 4.25 [OP_ADD] 4.25 [OP_DIV]",
        "solution_abst_en": "29.75 4.25 [OP_ADD] 4.25 [OP_DIV]",
        "solution_code_ko": "var_a = 29.75\nvar_b = 4.25\nvar_c = var_a + var_b\nvar_d = 4.25\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 29.75\nvar_b = 4.25\nvar_c = var_a + var_b\nvar_d = 4.25\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "3829": {
        "category": "Correspondence",
        "question_ko": "A5-2A=B7이 됩니다. A와 B의 합을 구하시오",
        "question_en": "When you subtract 2A from A5, you get B7. Find the sum of A and B",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "A5-2A=B7 A [OP_DIGIT_UNK_SOLVER] A5-2A=B7 B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_abst_en": "A5-2A=B7 A [OP_DIGIT_UNK_SOLVER] A5-2A=B7 B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_code_ko": "var_a = 'A5-2A=B7'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 'A5-2A=B7'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 'A5-2A=B7'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 'A5-2A=B7'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "3830": {
        "category": "Correspondence",
        "question_ko": "4를 어떤 수에 곱하면 5/2가 된다. 어떤 수를 5/24로 나눈다면 얼마가 되는가?",
        "question_en": "A particular number multiplied by 4 results in 5/2. What number do you get when you divide that particular number by 5/24?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "5/2 4 [OP_DIV] 5/24 [OP_DIV]",
        "solution_abst_en": "5/2 4 [OP_DIV] 5/24 [OP_DIV]",
        "solution_code_ko": "var_a = 2.5\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 0.20833333333333334\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 2.5\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 0.20833333333333334\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "3831": {
        "category": "Arithmetic calculation",
        "question_ko": "물탱크에 13/4리터(L) 만큼의 물이 있다. 이 물탱크에서12/5리터(L) 만큼 퍼내고 11/6리터(L)만큼 다시 집어 넣었다. 물탱크에 남은 물은 몇 리터(L)인지 구하시오.",
        "question_en": "A water tank has 13/4 liters (L) of water. You remove 12/5 liters (L) of water from the tank and then add back 11/6 liters (L) of water. Calculate the remaining amount of water in the tank in liters (L).",
        "answer_ko": "2.68",
        "answer_en": "2.68",
        "solution_abst_ko": "13/4 12/5 [OP_SUB] 11/6 [OP_ADD]",
        "solution_abst_en": "13/4 12/5 [OP_SUB] 11/6 [OP_ADD]",
        "solution_code_ko": "var_a = 3.25\nvar_b = 2.4\nvar_c = var_a - var_b\nvar_d = 1.8333333333333333\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 3.25\nvar_b = 2.4\nvar_c = var_a - var_b\nvar_d = 1.8333333333333333\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "3832": {
        "category": "Possibility",
        "question_ko": "어느 상점에서 판매하는 우유는 초코우유, 딸기우유, 바나나우유, 커피우유 4종류이다. 이 상점에서 우유를 선택할 때, 중복을 허용하여 우유 2팩을 선택하는 방법의 수를 구하시오.",
        "question_en": "There are four types of milk sold at a store: chocolate milk, strawberry milk, banana milk, and coffee milk. When selecting milk from this store, find the number of ways to select 2 cartons of milk, allowing duplicatio.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "[OP_LIST_SOL] 초코우유 딸기우유 바나나우유 커피우유 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] chocolate strawberry banana coffee [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '초코우유'\nvar_b = '딸기우유'\nvar_c = '바나나우유'\nvar_d = '커피우유'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = var_e + var_f\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = 2\nvar_k = 1\nvar_i = int(var_i)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_i-i)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k / (i+1)\nprint(int(var_k))",
        "solution_code_en": "var_a = 'chocolate'\nvar_b = 'strawberry'\nvar_c = 'banana'\nvar_d = 'coffee'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = var_e + var_f\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = 2\nvar_k = 1\nvar_i = int(var_i)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_i-i)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k / (i+1)\nprint(int(var_k))"
    },
    "3833": {
        "category": "Correspondence",
        "question_ko": "등식 A82+3B=216이 성립한다고 합니다. A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "The equation A82+3B=216 holds. What number should go in A?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "A82+3B=216 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A82+3B=216 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A82+3B=216'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A82+3B=216'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "3834": {
        "category": "Possibility",
        "question_ko": "구슬이 빨강, 파랑, 노랑, 보라, 검정 5개가 있다. 이 중 2개를 골라서 하나를 동생에게, 다른 하나는 형에게 선물로 주려고 한다.이 상황에서의 경우의 수를 구하여라.",
        "question_en": "There are 5 marbles: red, blue, yellow, purple, and black. You want to choose two of these and give one to your younger brother and the other to your older brother as a gift. Find the number of cases in this situation.",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "5 2 [OP_PERM]",
        "solution_abst_en": "5 2 [OP_PERM]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))"
    },
    "3835": {
        "category": "Arithmetic calculation",
        "question_ko": "포도 주스 1병에는 1리터(L) 200밀리리터(㎖)가 들어있습니다. 태연, 지민, 지수 세 명의 친구가 포도 주스를 나눠 마시기 위해 잔에 따랐더니 주스의 양이 달라 불평하는 친구가 생겼습니다. 태연이 잔에 든 주스를 지민이 잔으로 200밀리리터(㎖), 지수 잔으로 100밀리리터(㎖) 옮겨 따른 후에야 공평하게 따라졌다면, 지수 잔에는 원래 몇 밀리리터(㎖)의 주스가 있었습니까?",
        "question_en": "One bottle of grape juice contains 1 liter (L) and 200 milliliters (㎖). Three friends, Taeyeon, Jimin, and Jisoo, poured grape juice into a glass to share, and a friend complained about the difference in the amount of juice. If after the 200 milliliters (ml) of juice in Taeyeon's glass was poured into Jimin's glass and 100 milliliters (ml) into Jisoo's glass it became fair, how many milliliters (ml) of juice was originally in Jisoo's glass?",
        "answer_ko": "300",
        "answer_en": "300",
        "solution_abst_ko": "1 1000 [OP_MUL] 200 [OP_ADD] 200 [OP_SUB] 100 [OP_SUB] 3 [OP_DIV]",
        "solution_abst_en": "1 1000 [OP_MUL] 200 [OP_ADD] 200 [OP_SUB] 100 [OP_SUB] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 200\nvar_e = var_c + var_d\nvar_f = 200\nvar_g = var_e - var_f\nvar_h = 100\nvar_i = var_g - var_h\nvar_j = 3\nvar_k = var_i / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 1\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 200\nvar_e = var_c + var_d\nvar_f = 200\nvar_g = var_e - var_f\nvar_h = 100\nvar_i = var_g - var_h\nvar_j = 3\nvar_k = var_i / var_j\nprint(int(var_k))"
    },
    "3836": {
        "category": "Arithmetic calculation",
        "question_ko": "십의 자리 수가 3인 두 자리 자연수가 있다. 이 숫자를 10으로 나눈 몫과, 10으로 나눈 나머지를 각각 A, B라고 하자. B에 10을 곱하고, A를 더한 수는 A에 10을 곱하고 B를 더한 수보다 9만큼 작다고 할 때, 처음 수는 무엇인지 구하라.",
        "question_en": "There is a two-digit natural number whose tens place is 3. Let A and B be the quotient of this number by 10 and the remainder of division by 10, respectively. If B multiplied by 10 plus A is 9 less than A multiplied by 10 plus B, what is the first number?",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "3 10 [OP_MUL] 9 [OP_SUB] 3 [OP_SUB] 10 1 [OP_SUB] [OP_DIV] 3 10 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "3 10 [OP_MUL] 9 [OP_SUB] 3 [OP_SUB] 10 1 [OP_SUB] [OP_DIV] 3 10 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = var_e - var_f\nvar_h = 10\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_g / var_j\nvar_l = 3\nvar_m = 10\nvar_n = var_l * var_m\nvar_o = var_k + var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 3\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = var_e - var_f\nvar_h = 10\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_g / var_j\nvar_l = 3\nvar_m = 10\nvar_n = var_l * var_m\nvar_o = var_k + var_n\nprint(int(var_o))"
    },
    "3837": {
        "category": "Correspondence",
        "question_ko": "네 자리 수 14AB는 9로 나누어떨어지는 수입니다. A, B는 0부터 9까지의 서로 다른 수일 때 14AB가 될 수 있는 수는 모두 몇 개입니까?",
        "question_en": "The four-digit number 14AB is divisible by 9. If A and B are different numbers from 0 to 9, how many numbers can be 14AB?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "14AB [OP_GEN_POSSIBLE_LIST] 9 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "14AB [OP_GEN_POSSIBLE_LIST] 9 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '14AB'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 9\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))",
        "solution_code_en": "var_a = '14AB'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 9\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))"
    },
    "3838": {
        "category": "Correspondence",
        "question_ko": "30을 어떤 수에 더했더니 55가 되었습니다. 23을 어떤 수에 뺀 결과를 구하시오.",
        "question_en": "When you add 30 to a number, you get 55. What is the result of subtracting the number by 23?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "55 30 [OP_SUB] 23 [OP_SUB]",
        "solution_abst_en": "55 30 [OP_SUB] 23 [OP_SUB]",
        "solution_code_ko": "var_a = 55\nvar_b = 30\nvar_c = var_a - var_b\nvar_d = 23\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 55\nvar_b = 30\nvar_c = var_a - var_b\nvar_d = 23\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3839": {
        "category": "Possibility",
        "question_ko": "A, B, C, D 네 명의 학생 중에서 3명을 뽑아 일렬로 세울 때, A 또는 B가 맨 앞에 서게 되는 경우의 수를 구하시오.",
        "question_en": "Find the number of cases in which A or B is at the forefront when three of the four students are selected from A, B, C, and D and placed in a line.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_LEN] 4 1 [OP_SUB] 3 1 [OP_SUB] [OP_COMB] [OP_MUL] 3 1 [OP_SUB] 3 1 [OP_SUB] [OP_PERM] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_LEN] 4 1 [OP_SUB] 3 1 [OP_SUB] [OP_COMB] [OP_MUL] 3 1 [OP_SUB] 3 1 [OP_SUB] [OP_PERM] [OP_MUL]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = len(list_a)\nvar_d = 4\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 3\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = 1\nvar_f = int(var_f)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_f-i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j / (i+1)\nvar_k = var_c * var_j\nvar_l = 3\nvar_m = 1\nvar_n = var_l - var_m\nvar_o = 3\nvar_p = 1\nvar_q = var_o - var_p\nvar_r = 1\nvar_n = int(var_n)\nvar_q = int(var_q)\nfor i, elem in enumerate(range(var_q)):\n    var_r = var_r * (var_n-i)\nvar_s = var_k * var_r\nprint(int(var_s))",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = len(list_a)\nvar_d = 4\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 3\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = 1\nvar_f = int(var_f)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_f-i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j / (i+1)\nvar_k = var_c * var_j\nvar_l = 3\nvar_m = 1\nvar_n = var_l - var_m\nvar_o = 3\nvar_p = 1\nvar_q = var_o - var_p\nvar_r = 1\nvar_n = int(var_n)\nvar_q = int(var_q)\nfor i, elem in enumerate(range(var_q)):\n    var_r = var_r * (var_n-i)\nvar_s = var_k * var_r\nprint(int(var_s))"
    },
    "3840": {
        "category": "Arithmetic calculation",
        "question_ko": "태연이와 유라가 문제집을 풀었습니다. 태연이는 하루에 16문제씩 7일을 풀었고 유라는 하루에 25문제씩 6일을 풀었습니다. 태연이와 유라가 푼 문제는 모두 몇 문제인가요?",
        "question_en": "Taeyeon and Yura solved the problem book. Taeyeon solved 16 questions a day for 7 days and Yura solved 25 questions a day for 6 days. How many problems did Taeyeon and Yura solve?",
        "answer_ko": "262",
        "answer_en": "262",
        "solution_abst_ko": "16 7 [OP_MUL] 25 6 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "16 7 [OP_MUL] 25 6 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 16\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 25\nvar_e = 6\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 16\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 25\nvar_e = 6\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "3841": {
        "category": "Arithmetic calculation",
        "question_ko": "책상을 114미터(m)인 운동장 위에 3미터(m) 간격으로 세우려고 합니다. 운동장 처음과 끝에 반드시 세워져 있다고 할 때 총 몇개의 책상이 필요합니까?",
        "question_en": "You want to place the desks at 3 meter (m) intervals on a 114 meter (m) playground. How many desks will you need in total if you place them at the beginning and at the end of the playground?",
        "answer_ko": "39",
        "answer_en": "39",
        "solution_abst_ko": "114 3 [OP_DIV] 1 [OP_ADD]",
        "solution_abst_en": "114 3 [OP_DIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 114\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 114\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3842": {
        "category": "Arithmetic calculation",
        "question_ko": "세 장의 숫자카드 3, 4, 7을 사용하여 세자리 수를 만든다. 이때 7이 가장 앞에 오는 수들 중 가장 큰 값을 구하시오.(단, 숫자카드를 중복 사용할 수 없다.)",
        "question_en": "Use the three number cards 3, 4, and 7 to create a three-digit number. In here, find the largest value among the numbers with 7 at the front. (However, you cannot use number cards repeatedly.)",
        "answer_ko": "743",
        "answer_en": "743",
        "solution_abst_ko": "[OP_LIST_SOL] 3 4 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 100 7 [OP_LIST_SEARCH_FIXED_DIGIT] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 3 4 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 100 7 [OP_LIST_SEARCH_FIXED_DIGIT] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 3\nvar_b = 4\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 100\nvar_f = 7\nlist_c = [] \nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if (i//var_e)%10 == var_f:\n        list_c.append(i)\nvar_g = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_h = list_d[-var_g]\nprint(int(var_h))",
        "solution_code_en": "var_a = 3\nvar_b = 4\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 100\nvar_f = 7\nlist_c = [] \nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if (i//var_e)%10 == var_f:\n        list_c.append(i)\nvar_g = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_h = list_d[-var_g]\nprint(int(var_h))"
    },
    "3843": {
        "category": "Arithmetic calculation",
        "question_ko": "4명의 친구들이 음식을 먹고 돈을 똑같이 나누어 내려고 합니다. 한 개에 200원인 붕어빵 5개와 하나에 800원인 호떡 7개를 먹었다면 한 사람이 얼마를 내야합니까?",
        "question_en": "Four friends want to eat food and split the money equally. If you ate 5 fish-shaped bread which is 200 won each and 7 hotteoks which is 800 won each, how much would each person pay?",
        "answer_ko": "1650",
        "answer_en": "1650",
        "solution_abst_ko": "200 5 [OP_MUL] 800 7 [OP_MUL] [OP_ADD] 4 [OP_DIV]",
        "solution_abst_en": "200 5 [OP_MUL] 800 7 [OP_MUL] [OP_ADD] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 200\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 800\nvar_e = 7\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 4\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 200\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 800\nvar_e = 7\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 4\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "3844": {
        "category": "Possibility",
        "question_ko": "3, 5, 9의 숫자 중에서 2장을 뽑아 한 번씩만 사용하여 가장 큰 두 자리 수를 만들었습니다. 만든 두 자리 수보다 2배 큰 수를 구하시오.",
        "question_en": "Two of the numbers 3, 5, and 9 were drawn and used only once to create the largest two-digit number. Find the number twice as large as the two-digit number you created.",
        "answer_ko": "190",
        "answer_en": "190",
        "solution_abst_ko": "[OP_LIST_SOL] 3 5 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 2 [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 3 5 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 5\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 2\nvar_h = var_f * var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 3\nvar_b = 5\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 2\nvar_h = var_f * var_g\nprint(int(var_h))"
    },
    "3845": {
        "category": "Arithmetic calculation",
        "question_ko": "유나는 1시간에 380개의 구슬을 꿰었고, 은지는 1시간에 325개의 구슬을 꿰었습니다. 두 사람이 같은 빠르기로 구슬을 8시간 동안 꿰었을 때, 유나는 은지보다 구슬을 몇 개 더 많이 꿰었습니까?",
        "question_en": "Yuna threaded 380 beads in an hour, and Eunji threaded 325 beads in an hour. When the two of them threaded beads at a constant speed for 8 hours, how many more beads did Yuna thread than Eunji?",
        "answer_ko": "440",
        "answer_en": "440",
        "solution_abst_ko": "380 325 [OP_SUB] 8 [OP_MUL]",
        "solution_abst_en": "380 325 [OP_SUB] 8 [OP_MUL]",
        "solution_code_ko": "var_a = 380\nvar_b = 325\nvar_c = var_a - var_b\nvar_d = 8\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 380\nvar_b = 325\nvar_c = var_a - var_b\nvar_d = 8\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "3846": {
        "category": "Comparison",
        "question_ko": "일정한 빠르기로 버스는 17.28킬로미터(㎞) 의 거리를 16 분 동안에 가고, 승용차는 8.52킬로미터(㎞) 의 거리를 6 분 동안에 갑니다. 버스와 승용차가 같은 곳에서 동시에 출발한다 면 15 분 후에는 어느 것이 더 멀리 가겠습니까?",
        "question_en": "At a constant speed, a bus travels a distance of 17.28 kilometers (km) in 16 minutes, and a car travels a distance of 8.52 kilometers (km) in 6 minutes. If a bus and a car start at the same time from the same place, which one will go farther after 15 minutes?",
        "answer_ko": "승용차",
        "answer_en": "car",
        "solution_abst_ko": "[OP_LIST_SOL] 버스 승용차 [OP_LIST_EOL] [OP_LIST_SOL] 17.28 16 [OP_DIV] 15 [OP_MUL] 8.52 6 [OP_DIV] 15 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] bus car [OP_LIST_EOL] [OP_LIST_SOL] 17.28 16 [OP_DIV] 15 [OP_MUL] 8.52 6 [OP_DIV] 15 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '버스'\nvar_b = '승용차'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 17.28\nvar_d = 16\nvar_e = var_c / var_d\nvar_f = 15\nvar_g = var_e * var_f\nvar_h = 8.52\nvar_i = 6\nvar_j = var_h / var_i\nvar_k = 15\nvar_l = var_j * var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'bus'\nvar_b = 'car'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 17.28\nvar_d = 16\nvar_e = var_c / var_d\nvar_f = 15\nvar_g = var_e * var_f\nvar_h = 8.52\nvar_i = 6\nvar_j = var_h / var_i\nvar_k = 15\nvar_l = var_j * var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "3847": {
        "category": "Comparison",
        "question_ko": "1.4, 9/10, 1.2, 0.5, 13/10에서 1.1보다 큰 숫자를 나열한뒤, 합을 계산하면 얼마입니까?",
        "question_en": "What is the sum of the numbers greater than 1.1 in 1.4, 9/10, 1.2, 0.5, and 13/10?",
        "answer_ko": "3.90",
        "answer_en": "3.9",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "3848": {
        "category": "Geometry",
        "question_ko": "태영이와 민지는 똑같은 길이의 철사를 가지고 있습니다. 이 철사를 각각 겹치지 않게 모두 사용하여 태영이는 한 변의 길이가 4센티미터(㎝)인 정육각형을, 민지는 정사각형을 1개씩 만들었습니다. 민지가 만든 정사각형의 넓이는 몇 제곱센티미터(㎠)입니까?",
        "question_en": "Taeyoung and Minji have the same length of wire. Using all of these wires without overlapping each other, Taeyoung made a regular hexagon with a side length of 4 centimeters (cm), and Minji made a square. What is the area of Minji's square in square centimeters (cm2) ?",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "4 6 [OP_MUL] 4 [OP_DIV] 2 [OP_POW]",
        "solution_abst_en": "4 6 [OP_MUL] 4 [OP_DIV] 2 [OP_POW]",
        "solution_code_ko": "var_a = 4\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e ** var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e ** var_f\nprint(int(var_g))"
    },
    "3849": {
        "category": "Possibility",
        "question_ko": "정국, 지민, 윤기 중에 무기명으로 중복을 허용하여 2명에게 투표를 하려고 합니다. 가능한 경우의 수는 몇 가지 일까요?",
        "question_en": "Among Jungkook, Jimin, and Yoongi, you are going to vote 2 people by allowing duplication anonymously. How many possible cases are there?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 지민 윤기 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Jimin Yoongi [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '지민'\nvar_c = '윤기'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = var_d + var_e\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = 2\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j / (i+1)\nprint(int(var_j))",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Jimin'\nvar_c = 'Yoongi'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = var_d + var_e\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = 2\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j / (i+1)\nprint(int(var_j))"
    },
    "3850": {
        "category": "Possibility",
        "question_ko": "7/8 과 크기가 같은 분수 중에서 분모가 두 자리 수인 분수는 모두 몇 개인지 쓰시오.",
        "question_en": "How many fractions with a two-digit denominator have the same magnitude as 7/8?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "10 99 1 [OP_LIST_ARANGE] 8 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "10 99 1 [OP_LIST_ARANGE] 8 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 8\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 8\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "3851": {
        "category": "Geometry",
        "question_ko": "정육면체에 있는 면들 중에 서로 평행한 면은 모두 몇 쌍 입니까?",
        "question_en": "Among faces in a cube, find the number of pairs of faces that are parallel to each other.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "6 2 [OP_DIV]",
        "solution_abst_en": "6 2 [OP_DIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "3852": {
        "category": "Arithmetic calculation",
        "question_ko": "윤재와 민정이가 가진 구슬 개수의 합은 43개이고, 윤재가 민정이보다 5개 더 가지고 있습니다. 민정이가 가지고 있는 구슬은 몇 개인지 구하시오.",
        "question_en": "The sum of the number of marbles that Yunjae and Minjeong have is 43, and Yunjae has 5 more than Minjeong. Find how many marbles Minjeong has.",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "43 5 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "43 5 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 43\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 43\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "3853": {
        "category": "Arithmetic calculation",
        "question_ko": "30이상 50이하인 자연수의 개수를 구하시오.",
        "question_en": "Find the number of natural numbers between 30 and 50.",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "30 50 1 [OP_LIST_ARANGE] [OP_LIST_LEN]",
        "solution_abst_en": "30 50 1 [OP_LIST_ARANGE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 30\nvar_b = 50\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = len(list_a)\nprint(int(var_d))",
        "solution_code_en": "var_a = 30\nvar_b = 50\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = len(list_a)\nprint(int(var_d))"
    },
    "3854": {
        "category": "Arithmetic calculation",
        "question_ko": "48명의 어린이 중에서 (가)를 할 수 있는 어린이는 38명, (나)를 할 수 있는 어린이는 29명입니다. (가)도 할 수 없고 (나)도 할 수 없는 어린이는 한 명도 없을 때, (가)도 할 수 있고 (나)도 할 수 있는 어린이는 몇 명입니까?",
        "question_en": "Among 48 children, 38 children could do A and 29 children could do B. How many children can do both A and B if there is no child who can neither A nor B?",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "38 29 [OP_ADD] 48 [OP_SUB]",
        "solution_abst_en": "38 29 [OP_ADD] 48 [OP_SUB]",
        "solution_code_ko": "var_a = 38\nvar_b = 29\nvar_c = var_a + var_b\nvar_d = 48\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 38\nvar_b = 29\nvar_c = var_a + var_b\nvar_d = 48\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3855": {
        "category": "Correspondence",
        "question_ko": "어떤 수는 70과 80 사이의 두 자리 수입니다. 어떤 수는 8로 나누어떨어집니다. 어떤 수를 구하시오.",
        "question_en": "The number is two digits between 70 and 80. This number is divisible by 8. Find the number.",
        "answer_ko": "72",
        "answer_en": "72",
        "solution_abst_ko": "70 1 [OP_ADD] 80 1 [OP_SUB] 1 [OP_LIST_ARANGE] 8 [OP_LIST_DIVISIBLE] 1 [OP_LIST_GET]",
        "solution_abst_en": "70 1 [OP_ADD] 80 1 [OP_SUB] 1 [OP_LIST_ARANGE] 8 [OP_LIST_DIVISIBLE] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 70\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 80\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = 8\nlist_b = []\nvar_h = int(var_h)\nfor i in list_a:\n    i = int(i)\n    if i % var_h == 0:\n        list_b.append(i)\nvar_i = 1\nvar_j = list_b[var_i-1]\nprint(int(var_j))",
        "solution_code_en": "var_a = 70\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 80\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = 8\nlist_b = []\nvar_h = int(var_h)\nfor i in list_a:\n    i = int(i)\n    if i % var_h == 0:\n        list_b.append(i)\nvar_i = 1\nvar_j = list_b[var_i-1]\nprint(int(var_j))"
    },
    "3856": {
        "category": "Comparison",
        "question_ko": "백의 자리 숫자가 3인 세 자리 수 중에서 306보다 작은 수는 모두 몇 개입니까?",
        "question_en": "How many three-digit numbers with a hundredth digit of 3 and less than 306?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "3 100 [OP_MUL] 3 100 [OP_MUL] 99 [OP_ADD] 1 [OP_LIST_ARANGE] 306 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "3 100 [OP_MUL] 3 100 [OP_MUL] 99 [OP_ADD] 1 [OP_LIST_ARANGE] 306 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 3\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = 100\nvar_f = var_d * var_e\nvar_g = 99\nvar_h = var_f + var_g\nvar_i = 1\nlist_a = [i for i in range(var_c, var_h + 1, var_i)]\nvar_j = 306\nlist_b = []\nfor i in list_a:\n    if i < var_j:\n        list_b.append(i)\nvar_k = len(list_b)\nprint(int(var_k))",
        "solution_code_en": "var_a = 3\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = 100\nvar_f = var_d * var_e\nvar_g = 99\nvar_h = var_f + var_g\nvar_i = 1\nlist_a = [i for i in range(var_c, var_h + 1, var_i)]\nvar_j = 306\nlist_b = []\nfor i in list_a:\n    if i < var_j:\n        list_b.append(i)\nvar_k = len(list_b)\nprint(int(var_k))"
    },
    "3857": {
        "category": "Arithmetic calculation",
        "question_ko": "할아버지께서 사과 15개를 사서 그중에서 7개를 윤기에게 주었습니다. 할아버지에게 남은 사과는 몇 개입니까?",
        "question_en": "Grandpa bought 15 apples and gave 7 of them to Yoongi. How many apples are left for Grandpa?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "15 7 [OP_SUB]",
        "solution_abst_en": "15 7 [OP_SUB]",
        "solution_code_ko": "var_a = 15\nvar_b = 7\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 15\nvar_b = 7\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "3858": {
        "category": "Comparison",
        "question_ko": "세 수 A, B, C가 있습니다. A는 10개씩 4묶음과 낱개 8개인 수입니다. B는 50보다 1 작은 수입니다. C는 40보다 7 큰 수입니다. 가장 큰 수는 어느 것입니까?",
        "question_en": "There are three numbers A, B and C. A is the number of 4 groups of 10 and 8 units. B is one less than 50. C is 7 greater than 40. Which number is the largest?",
        "answer_ko": "B",
        "answer_en": "B",
        "solution_abst_ko": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] 10 4 [OP_MUL] 8 [OP_ADD] 50 1 [OP_SUB] 40 7 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] 10 4 [OP_MUL] 8 [OP_ADD] 50 1 [OP_SUB] 40 7 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 10\nvar_e = 4\nvar_f = var_d * var_e\nvar_g = 8\nvar_h = var_f + var_g\nvar_i = 50\nvar_j = 1\nvar_k = var_i - var_j\nvar_l = 40\nvar_m = 7\nvar_n = var_l + var_m\nlist_b= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nlist_b.reverse()\nvar_o = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_p = list_c[-var_o]\nvar_q = list_b.index(var_p)+1\nvar_r = list_a[var_q-1]\nprint(var_r)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 10\nvar_e = 4\nvar_f = var_d * var_e\nvar_g = 8\nvar_h = var_f + var_g\nvar_i = 50\nvar_j = 1\nvar_k = var_i - var_j\nvar_l = 40\nvar_m = 7\nvar_n = var_l + var_m\nlist_b= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nlist_b.reverse()\nvar_o = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_p = list_c[-var_o]\nvar_q = list_b.index(var_p)+1\nvar_r = list_a[var_q-1]\nprint(var_r)"
    },
    "3859": {
        "category": "Comparison",
        "question_ko": "지민이는 (가) 상자와 (나) 상자를 선물받았습니다. (가) 상자보다 (나) 상자가 무거울 때 가벼운 상자는 무엇인가요?",
        "question_en": "Jimin was presented with (a) box and (b) box. Which box is lighter when (b) box is heavier than (a) box?",
        "answer_ko": "(가)",
        "answer_en": "(a)",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) [OP_LIST_EOL] [OP_LIST_SOL] (가) (나) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (a) (b) [OP_LIST_EOL] [OP_LIST_SOL] (a) (b) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = '(가)'\nvar_d = '(나)'\nvar_e = '<'\nlist_b= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_f = len(list_c)\nvar_g = list_c[var_f-1]\nprint(var_g)",
        "solution_code_en": "var_a = '(a)'\nvar_b = '(b)'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = '(a)'\nvar_d = '(b)'\nvar_e = '<'\nlist_b= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_f = len(list_c)\nvar_g = list_c[var_f-1]\nprint(var_g)"
    },
    "3860": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 가장 작은 수와 그 다음으로 작은 수의 곱은 얼마입니까?",
        "question_en": "There are five numbers 10, 11, 12, 13, and 14. What is the smallest number multiplied by the next smallest number?",
        "answer_ko": "110",
        "answer_en": "110",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g * var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g * var_i\nprint(int(var_j))"
    },
    "3861": {
        "category": "Arithmetic calculation",
        "question_ko": "석기는 가진 돈의 절반으로 학용품을 사고, 남은 돈의 절반으로 과자를 샀습니다. 과자를 사고 남은 돈이 1250원이었다면, 처음에 석기가 가지고 있었던 돈은 얼마입니까?",
        "question_en": "Seokgi buys school supplies with half of his money and sweets with the other half of his remaining money. If Seokgi has 1250 won left over after buying sweets, how much money did he have at the beginning?",
        "answer_ko": "5000",
        "answer_en": "5000",
        "solution_abst_ko": "1250 2 [OP_MUL] 2 [OP_MUL]",
        "solution_abst_en": "1250 2 [OP_MUL] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 1250\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 1250\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "3862": {
        "category": "Geometry",
        "question_ko": "연필과 볼펜을 가로와 세로 모두 10자루씩 정렬하였습니다. 둘레에는 볼펜을 놓고, 안쪽에는 연필을 놓았을 때, 연필은 모두 몇 자루 일까요?",
        "question_en": "Pencils and ballpoint pens were arranged in 10 rows both horizontally and vertically. If you place a ballpoint pen around the perimeter and a pencil inside, how many pencils are there in all?",
        "answer_ko": "64",
        "answer_en": "64",
        "solution_abst_ko": "10 2 [OP_SUB] 2 [OP_POW]",
        "solution_abst_en": "10 2 [OP_SUB] 2 [OP_POW]",
        "solution_code_ko": "var_a = 10\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint(int(var_e))"
    },
    "3863": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 3을 곱해야 할 것을 잘못하여 더했더니 226이 되었습니다. 바르게 계산하면 얼마인지 구해 보시오.",
        "question_en": "When you mistakenly add a certain number that should be multiplied by 3, the result is 226. Find out the value if you calculate it correctly.",
        "answer_ko": "669",
        "answer_en": "669",
        "solution_abst_ko": "226 3 [OP_SUB] 3 [OP_MUL]",
        "solution_abst_en": "226 3 [OP_SUB] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 226\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 226\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "3864": {
        "category": "Correspondence",
        "question_ko": "A345>5555에서 A에 1부터 9까지의 숫자를 쓰려고 합니다. A에 쓸 수 있는 숫자는 모두 몇 개입니까?",
        "question_en": "At A345>5555, we want to write the numbers 1 through 9 in A. How many digits can you write in A?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "A345>5555 A [OP_DIGIT_UNK_SOLVER] [OP_LIST_LEN]",
        "solution_abst_en": "A345>5555 A [OP_DIGIT_UNK_SOLVER] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 'A345>5555'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = len(list_a)\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A345>5555'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = len(list_a)\nprint(int(var_c))"
    },
    "3865": {
        "category": "Arithmetic calculation",
        "question_ko": "신영이네 집에서 동사무소까지는 1킬로미터(㎞) 700미터(m)이고, 동사무소에서 학교까지의 거리는 900미터(m)입니다. 신영이네 집에서 동사무소를 거쳐 학교까지 가는 거리의 중간 지점은 집에서부터 몇 미터(m)가 되겠습니까?",
        "question_en": "It is 1 kilometer (km) 700 meters (m) from Shinyoung's house to the village office, and the distance from the village office to the school is 900 meters (m). How far is the midpoint of the distance starting from Shin-Young's house to the district office through the school, from Shin-Young's house in meters (m)?",
        "answer_ko": "1300",
        "answer_en": "1300",
        "solution_abst_ko": "1 1000 [OP_MUL] 700 [OP_ADD] 900 [OP_ADD] 2 [OP_DIV]",
        "solution_abst_en": "1 1000 [OP_MUL] 700 [OP_ADD] 900 [OP_ADD] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 700\nvar_e = var_c + var_d\nvar_f = 900\nvar_g = var_e + var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 700\nvar_e = var_c + var_d\nvar_f = 900\nvar_g = var_e + var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "3866": {
        "category": "Comparison",
        "question_ko": "1리터(L)의 포도 주스를 도연이는 1100밀리리터(㎖)로, 민규는 850밀리리터(㎖)로 어림하였습니다. 두 사람 중 주스의 양을 가깝게 어림한 사람은 누구입니까?",
        "question_en": "Doyeon estimated 1 liter (L) of grape juice as 1100 milliliters (㎖) and Mingyu estimated it as 850 milliliters (㎖). Which of the two people came closer to estimating the amount of juice?",
        "answer_ko": "도연",
        "answer_en": "Doyeon",
        "solution_abst_ko": "[OP_LIST_SOL] 도연 민규 [OP_LIST_EOL] [OP_LIST_SOL] 1000 1100 [OP_SUB] [OP_ABS] 1000 850 [OP_SUB] [OP_ABS] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Doyeon Mingyu [OP_LIST_EOL] [OP_LIST_SOL] 1000 1100 [OP_SUB] [OP_ABS] 1000 850 [OP_SUB] [OP_ABS] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '도연'\nvar_b = '민규'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1000\nvar_d = 1100\nvar_e = var_c - var_d\nvar_f = abs(var_e)\nvar_g = 1000\nvar_h = 850\nvar_i = var_g - var_h\nvar_j = abs(var_i)\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[var_k-1]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'Doyeon'\nvar_b = 'Mingyu'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1000\nvar_d = 1100\nvar_e = var_c - var_d\nvar_f = abs(var_e)\nvar_g = 1000\nvar_h = 850\nvar_i = var_g - var_h\nvar_j = abs(var_i)\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[var_k-1]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "3867": {
        "category": "Geometry",
        "question_ko": "십팔각형의 모든 대각선의 개수를 구하시오.",
        "question_en": "Find the number of all diagonals of the octadecagon.",
        "answer_ko": "135",
        "answer_en": "135",
        "solution_abst_ko": "18 18 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "18 18 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 18\nvar_b = 18\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 18\nvar_b = 18\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "3868": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 수와 그 수의 3/5인 수를 더했더니 240개가 되었습니다. 어떤 수는 무엇입니까?",
        "question_en": "When you add a number plus 3/5 of that number, you get 240. What number is it?",
        "answer_ko": "150",
        "answer_en": "150",
        "solution_abst_ko": "240 1 3/5 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "240 1 3/5 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 240\nvar_b = 1\nvar_c = 0.6\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 240\nvar_b = 1\nvar_c = 0.6\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "3869": {
        "category": "Comparison",
        "question_ko": "한별과 슬기가 달렸다. 같은 기간 한별은 10.2킬로미터(㎞)를 100분의 1로, 슬기는 100미터(m)를 달렸다. 누가 더 많이 달렸습니까?",
        "question_en": "Hanbyeol and Seulgi ran. During the same period, Hanbyeol ran 10.2 kilometers (km) at 1/100, and Seulgi ran 100 meters (m). Who ran more?",
        "answer_ko": "한별",
        "answer_en": "Hanbyeol",
        "solution_abst_ko": "[OP_LIST_SOL] 한별 슬기 [OP_LIST_EOL] [OP_LIST_SOL] 10.2 1000 [OP_MUL] 100 [OP_DIV] 100 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Hanbyeol Seulgi [OP_LIST_EOL] [OP_LIST_SOL] 10.2 1000 [OP_MUL] 100 [OP_DIV] 100 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '한별'\nvar_b = '슬기'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10.2\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 100\nvar_g = var_e / var_f\nvar_h = 100\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Hanbyeol'\nvar_b = 'Seulgi'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10.2\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 100\nvar_g = var_e / var_f\nvar_h = 100\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "3870": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이는 삼촌보다 12살이 더 어립니다. 3년 후 정국이와 삼촌의 나이를 합하면 38살이 됩니다. 올해 정국이의 나이는 몇 살인지 구하시오.",
        "question_en": "Jungkook is 12 years younger than his uncle. Three years later, Jungkook and his uncle's combined ages will be 38 years old. How old is Jungkook this year?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "38 3 2 [OP_MUL] [OP_SUB] 12 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "38 3 2 [OP_MUL] [OP_SUB] 12 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 38\nvar_b = 3\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 12\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 38\nvar_b = 3\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 12\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "3871": {
        "category": "Arithmetic calculation",
        "question_ko": "주머니에 (가) 사탕이 17개, (나) 사탕이 19개 있습니다. 이 주머니의 사탕을 종류 구분 없이 9명에게 똑같이 나누어 준다면, 한 사람이 몇 개씩 가질 수 있습니까?",
        "question_en": "There are 17 (a) candies and 19 (b) candies in the bag. If you distribute these candies in this bag equally to 9 people regardless of type, how many candies can each person get?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "17 19 [OP_ADD] 9 [OP_FDIV]",
        "solution_abst_en": "17 19 [OP_ADD] 9 [OP_FDIV]",
        "solution_code_ko": "var_a = 17\nvar_b = 19\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 17\nvar_b = 19\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "3872": {
        "category": "Correspondence",
        "question_ko": "A, B, B는 서로 다른 숫자이다. 1은 C보다 8작은 수이고 A에 5를 더하면 B가 된다. 9에서 4를 빼면 A가 될때 B에서 C를 빼면 얼마가 되는가?",
        "question_en": "A, B, and C are different numbers. 1 is 8 less than C, and adding 5 to A is equal to B. If 9 minus 4 is A, what is the difference between B and C?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "9 4 [OP_SUB] 5 [OP_ADD] 8 1 [OP_ADD] [OP_SUB]",
        "solution_abst_en": "9 4 [OP_SUB] 5 [OP_ADD] 8 1 [OP_ADD] [OP_SUB]",
        "solution_code_ko": "var_a = 9\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = var_e - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 9\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = var_e - var_h\nprint(int(var_i))"
    },
    "3873": {
        "category": "Correspondence",
        "question_ko": "ABCDE를 6으로 나누면 몪이 13579고 나머지는 0입니다. 다섯 자리 수 ABCDE의 ABC에 DE를 더하시오.",
        "question_en": "ABCDE divided by 6 equals 13579 with a remainder of 0. Add DE to ABC of the five-digit number ABCDE.",
        "answer_ko": "888",
        "answer_en": "888",
        "solution_abst_ko": "6 13579 [OP_MUL] [OP_NUM2LIST] 1 [OP_LIST_GET] 100 [OP_MUL] 2 [OP_LIST_GET] 10 [OP_MUL] 3 [OP_LIST_GET] [OP_ADD] [OP_ADD] 4 [OP_LIST_GET] 10 [OP_MUL] 5 [OP_LIST_GET] [OP_ADD] [OP_ADD]",
        "solution_abst_en": "6 13579 [OP_MUL] [OP_NUM2LIST] 1 [OP_LIST_GET] 100 [OP_MUL] 2 [OP_LIST_GET] 10 [OP_MUL] 3 [OP_LIST_GET] [OP_ADD] [OP_ADD] 4 [OP_LIST_GET] 10 [OP_MUL] 5 [OP_LIST_GET] [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 13579\nvar_c = var_a * var_b\nlist_a = []\nvar_c = int(var_c)\nwhile var_c//10 > 0:\n    list_a.append(var_c%10)\n    var_c = var_c//10\nlist_a.append(var_c%10)\nlist_a = list_a[::-1]\nvar_d = 1\nvar_e = list_a[var_d-1]\nvar_f = 100\nvar_g = var_e * var_f\nvar_h = 2\nvar_i = list_a[var_h-1]\nvar_j = 10\nvar_k = var_i * var_j\nvar_l = 3\nvar_m = list_a[var_l-1]\nvar_n = var_k + var_m\nvar_o = var_g + var_n\nvar_p = 4\nvar_q = list_a[var_p-1]\nvar_r = 10\nvar_s = var_q * var_r\nvar_t = 5\nvar_u = list_a[var_t-1]\nvar_v = var_s + var_u\nvar_w = var_o + var_v\nprint(int(var_w))",
        "solution_code_en": "var_a = 6\nvar_b = 13579\nvar_c = var_a * var_b\nlist_a = []\nvar_c = int(var_c)\nwhile var_c//10 > 0:\n    list_a.append(var_c%10)\n    var_c = var_c//10\nlist_a.append(var_c%10)\nlist_a = list_a[::-1]\nvar_d = 1\nvar_e = list_a[var_d-1]\nvar_f = 100\nvar_g = var_e * var_f\nvar_h = 2\nvar_i = list_a[var_h-1]\nvar_j = 10\nvar_k = var_i * var_j\nvar_l = 3\nvar_m = list_a[var_l-1]\nvar_n = var_k + var_m\nvar_o = var_g + var_n\nvar_p = 4\nvar_q = list_a[var_p-1]\nvar_r = 10\nvar_s = var_q * var_r\nvar_t = 5\nvar_u = list_a[var_t-1]\nvar_v = var_s + var_u\nvar_w = var_o + var_v\nprint(int(var_w))"
    },
    "3874": {
        "category": "Correspondence",
        "question_ko": "만두 100개에 스님이 100명인데, 큰 스님에게 3개씩 나누어 주고 작은 스님은 세 사람당 1개씩 남김없이 나누어 주었다. 만두를 못 받은 스님이 없을 때 큰 스님은 몇 명인가?",
        "question_en": "There are 100 monks and 100 dumplings, and we handed out 3 dumplings per each great monk and 1 dumpling for every three little monks. When there are no monks that did not receive dumpling, how many great monks are there?",
        "answer_ko": "25",
        "answer_en": "25",
        "solution_abst_ko": "100 3 [OP_MUL] 100 [OP_SUB] 3 3 [OP_MUL] 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "100 3 [OP_MUL] 100 [OP_SUB] 3 3 [OP_MUL] 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 100\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = 3\nvar_h = var_f * var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 100\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = 3\nvar_h = var_f * var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e / var_j\nprint(int(var_k))"
    },
    "3875": {
        "category": "Correspondence",
        "question_ko": "15를 어떤 수에 곱했더니 결과가 45가 되었습니다. 1을 어떤 수에서 뺀 결과는?",
        "question_en": "When 15 is multiplied by a certain number, the result is 45. What is the result of subtracting 1 from the certain number?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "45 15 [OP_DIV] 1 [OP_SUB]",
        "solution_abst_en": "45 15 [OP_DIV] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 45\nvar_b = 15\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 45\nvar_b = 15\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3876": {
        "category": "Comparison",
        "question_ko": "2개의 숫자 0.8, 1/2가 있습니다. 3보다 큰 수는 몇 개입니까?",
        "question_en": "There are two numbers 0.8 and 1/2. How many numbers are greater than 3?",
        "answer_ko": "0",
        "answer_en": "0",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 [OP_LIST_EOL] 3 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 [OP_LIST_EOL] 3 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nlist_b = []\nfor i in list_a:\n    if i > var_c:\n        list_b.append(i)\nvar_d = len(list_b)\nprint(int(var_d))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nlist_b = []\nfor i in list_a:\n    if i > var_c:\n        list_b.append(i)\nvar_d = len(list_b)\nprint(int(var_d))"
    },
    "3877": {
        "category": "Arithmetic calculation",
        "question_ko": "떨어진 높이의 1/3만큼 튀어 오르는 공이 있습니다. 이 공을 2+4/7 미터(m)의 높이에서 떨어뜨렸습니다. 공이 땅에 닿았다가 튀어 올랐을 때의 높이는 몇 미터(m)일까요?",
        "question_en": "There is a ball that bounces 1/3 of the height it fell. The ball was dropped from a height of 2+4/7 meters (m). What is the height in meters (m) when the ball hits the ground and bounces back to its maximum?",
        "answer_ko": "0.86",
        "answer_en": "0.86",
        "solution_abst_ko": "2 4/7 [OP_ADD] 1/3 [OP_MUL]",
        "solution_abst_en": "2 4/7 [OP_ADD] 1/3 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 0.5714285714285714\nvar_c = var_a + var_b\nvar_d = 0.3333333333333333\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 2\nvar_b = 0.5714285714285714\nvar_c = var_a + var_b\nvar_d = 0.3333333333333333\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "3878": {
        "category": "Correspondence",
        "question_ko": "1이 5개, 0.1이 7개, 0.01이 21개, 0.001이 53개인 수는 어떤 수의 1/10과 동일합니다. 소수점을 포함한 어떤 수는 얼마입니까?",
        "question_en": "A number with 5 1s, 7 0.1s, 21 0.01s, and 53 0.001s equals 1/10 of the variable. How much is the variable including the decimal point?",
        "answer_ko": "59.63",
        "answer_en": "59.63",
        "solution_abst_ko": "1 5 [OP_MUL] 0.1 7 [OP_MUL] [OP_ADD] 0.01 21 [OP_MUL] [OP_ADD] 0.001 53 [OP_MUL] [OP_ADD] 1/10 [OP_DIV]",
        "solution_abst_en": "1 5 [OP_MUL] 0.1 7 [OP_MUL] [OP_ADD] 0.01 21 [OP_MUL] [OP_ADD] 0.001 53 [OP_MUL] [OP_ADD] 1/10 [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 0.1\nvar_e = 7\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 0.01\nvar_i = 21\nvar_j = var_h * var_i\nvar_k = var_g + var_j\nvar_l = 0.001\nvar_m = 53\nvar_n = var_l * var_m\nvar_o = var_k + var_n\nvar_p = 0.1\nvar_q = var_o / var_p\nprint('{:.2f}'.format(round(var_q+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 0.1\nvar_e = 7\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 0.01\nvar_i = 21\nvar_j = var_h * var_i\nvar_k = var_g + var_j\nvar_l = 0.001\nvar_m = 53\nvar_n = var_l * var_m\nvar_o = var_k + var_n\nvar_p = 0.1\nvar_q = var_o / var_p\nprint('{:.2f}'.format(round(var_q+1e-10,2)))"
    },
    "3879": {
        "category": "Geometry",
        "question_ko": "현주네 동네에는 직사각형 모양의 공원이 여덟 개 있습니다. 모든 도서관의 세로의 길이는 300미터(m)로 같고, 넓이 역시 같을 때 도서관의 넓이의 합이 0.6제곱킬로미터(㎢)라면 도서관의 가로 길이는 몇 미터(m)입니까?",
        "question_en": "There are eight rectangular-shaped parks in Hyeonju's neighborhood. The length of all libraries is the same with 300 meters (m) and the area is the same as well, and if the sum of the areas of the libraries is 0.6 square kilometers (km2), what is the width of the library in meters (m)?",
        "answer_ko": "250",
        "answer_en": "250",
        "solution_abst_ko": "0.6 1000 1000 [OP_MUL] [OP_MUL] 8 [OP_DIV] 300 [OP_DIV]",
        "solution_abst_en": "0.6 1000 1000 [OP_MUL] [OP_MUL] 8 [OP_DIV] 300 [OP_DIV]",
        "solution_code_ko": "var_a = 0.6\nvar_b = 1000\nvar_c = 1000\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nvar_f = 8\nvar_g = var_e / var_f\nvar_h = 300\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 0.6\nvar_b = 1000\nvar_c = 1000\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nvar_f = 8\nvar_g = var_e / var_f\nvar_h = 300\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "3880": {
        "category": "Correspondence",
        "question_ko": "1부터 100까지 짝수를 쓰려고 합니다. 숫자 0은 모두 몇 번 써야 합니까?",
        "question_en": "You want to write an even number from 1 to 100. How many times should the number 0 be written in all?",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "1 200 [OP_LIST_EVEN] [OP_LIST2NUM] [OP_NUM2LIST] 0 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 200 [OP_LIST_EVEN] [OP_LIST2NUM] [OP_NUM2LIST] 0 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 200\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c=\"\"\nfor i in list_a:\n    i = str(i)\n    var_c = var_c + i\nlist_b = []\nvar_c = int(var_c)\nwhile var_c//10 > 0:\n    list_b.append(var_c%10)\n    var_c = var_c//10\nlist_b.append(var_c%10)\nlist_b = list_b[::-1]\nvar_d = 0\nvar_e = 0\nvar_d = int(var_d)\nfor i in list_b:\n    i = int(i)\n    if i == var_d:\n        var_e = var_e + 1\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 200\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c=\"\"\nfor i in list_a:\n    i = str(i)\n    var_c = var_c + i\nlist_b = []\nvar_c = int(var_c)\nwhile var_c//10 > 0:\n    list_b.append(var_c%10)\n    var_c = var_c//10\nlist_b.append(var_c%10)\nlist_b = list_b[::-1]\nvar_d = 0\nvar_e = 0\nvar_d = int(var_d)\nfor i in list_b:\n    i = int(i)\n    if i == var_d:\n        var_e = var_e + 1\nprint(int(var_e))"
    },
    "3881": {
        "category": "Possibility",
        "question_ko": "5개의 울타리를 각각 3가지 색의 페인트 중 하나를 선택해 칠하려고 합니다. 페인트를 칠할 수 있는 경우는 모두 몇 가지입니까?",
        "question_en": "You want to paint each of the 5 fences with one of 3 different colors of paint. How many ways can you paint?",
        "answer_ko": "243",
        "answer_en": "243",
        "solution_abst_ko": "3 5 [OP_POW]",
        "solution_abst_en": "3 5 [OP_POW]",
        "solution_code_ko": "var_a = 3\nvar_b = 5\nvar_c = var_a ** var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 5\nvar_c = var_a ** var_b\nprint(int(var_c))"
    },
    "3882": {
        "category": "Geometry",
        "question_ko": "어떤 수는 3의 배수이고 동시에 4의 배수이다. 가능한 어떤 수 중 가장 작은 수를 구하시오.",
        "question_en": "Some numbers are multiples of 3 and multiples of 4. Find the smallest of all possible numbers.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "3 4 [OP_LCM]",
        "solution_abst_en": "3 4 [OP_LCM]",
        "solution_code_ko": "var_a = 3\nvar_b = 4\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 4\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nprint(int(var_c))"
    },
    "3883": {
        "category": "Geometry",
        "question_ko": "육각형, 삼각형, 사각형의 변의 수의 합은 몇 개입니까?",
        "question_en": "What is the sum of the sides of a hexagon, triangle, and quadrilateral?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "6 3 [OP_ADD] 4 [OP_ADD]",
        "solution_abst_en": "6 3 [OP_ADD] 4 [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3884": {
        "category": "Comparison",
        "question_ko": "유미는 2시간 동안 8킬로미터(㎞)를 걸었고, 웅이는 3시간 동안 13킬로미터(㎞)를 걸었습니다. 둘 중 걸음이 더 빠른 사람은 누구입니까?",
        "question_en": "Yumi walked 8 kilometers (km) in 2 hours, and Woong walked 13 kilometers (km) in 3 hours. Which of the two walks faster?",
        "answer_ko": "웅이",
        "answer_en": "Woong",
        "solution_abst_ko": "[OP_LIST_SOL] 유미 웅이 [OP_LIST_EOL] [OP_LIST_SOL] 24 2 [OP_DIV] 39 3 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yumi Woong [OP_LIST_EOL] [OP_LIST_SOL] 24 2 [OP_DIV] 39 3 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '유미'\nvar_b = '웅이'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 24\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 39\nvar_g = 3\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Yumi'\nvar_b = 'Woong'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 24\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 39\nvar_g = 3\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "3885": {
        "category": "Correspondence",
        "question_ko": "동일한 구슬 7개를 저울 위에 올려놓았더니 저울의 눈금이 50.68그램(g)을 가리켰습니다. 구슬 1개를 저울 위에 올려놓으면 저울이 어떤 숫자를 가리키는지 구하시오.",
        "question_en": "When 7 identical marbles were placed on a scale, and it read 50.68 grams (g). If you put 1 marble on the scale, what number will the scale indicate?",
        "answer_ko": "7.24",
        "answer_en": "7.24",
        "solution_abst_ko": "50.68 7 [OP_DIV]",
        "solution_abst_en": "50.68 7 [OP_DIV]",
        "solution_code_ko": "var_a = 50.68\nvar_b = 7\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 50.68\nvar_b = 7\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "3886": {
        "category": "Arithmetic calculation",
        "question_ko": "무게가 같은 수박 여러개가 담긴 바구니의 무게를 재었더니 63킬로그램(㎏)이었습니다. 절반의 수박을 덜어낸 후 무게를 재어 보니 34킬로그램(㎏)이 되었습니다. 처음 바구니에 담겨 있던 수박의 무게는 몇 킬로그램(㎏)입니까?",
        "question_en": "When a basket containing several watermelons of the same weight was 63 kilograms (kg), its weight changed to 34 kilograms (kg) after half of the watermelon was removed. What is the weight of watermelons in total?",
        "answer_ko": "58",
        "answer_en": "58",
        "solution_abst_ko": "63 34 [OP_SUB] 2 [OP_MUL]",
        "solution_abst_en": "63 34 [OP_SUB] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 63\nvar_b = 34\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 63\nvar_b = 34\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "3887": {
        "category": "Possibility",
        "question_ko": "숫자 카드 4, 5, 6을 한 번씩 사용하여 560보다 작은 세 자리 수를 만들었을 때, 조건에 맞는 수는 모두 몇 개입니까?",
        "question_en": "If you use the number cards 4, 5, and 6 once to form a 3-digit number less than 560, how many cases match the condition?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 4 5 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 560 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 4 5 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 560 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 4\nvar_b = 5\nvar_c = 6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 560\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 4\nvar_b = 5\nvar_c = 6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 560\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "3888": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이는 색종이를 8장씩 5묶음 가지고 있습니다. 이 색종이를 6장씩 9줄로 늘어놓으려고 합니다. 몇 장의 색종이가 더 필요합니까?",
        "question_en": "Jungkook has 5 bundles of 8 pieces of colored paper. He is going to arrange this colored paper into 9 rows of 6 sheets each. How many more sheets of colored paper does he need?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "6 9 [OP_MUL] 8 5 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "6 9 [OP_MUL] 8 5 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 6\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 6\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "3889": {
        "category": "Geometry",
        "question_ko": "윗변이 10센티미터(㎝)이고, 아랫변 길이는 윗변 길이의 2배인 사다리꼴이 있습니다. 이 사다리꼴의 높이가 5센티미터(㎝)일 때 넓이는 몇 제곱센티미터입니까?",
        "question_en": "There is a trapezoid with an upper side of 10 centimeters (cm) and a lower side that is twice the length of the upper side. If the height of this trapezoid is 5 centimeters (cm), What is the area of this trapezoid in square centimeters (cm2)?",
        "answer_ko": "75",
        "answer_en": "75",
        "solution_abst_ko": "10 10 2 [OP_MUL] [OP_ADD] 5 [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "10 10 2 [OP_MUL] [OP_ADD] 5 [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 10\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nvar_f = 5\nvar_g = var_e * var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 10\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nvar_f = 5\nvar_g = var_e * var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "3890": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 80센티미터(㎝)인 정사각형의 둘레와 세로 길이가 100센티미터(㎝)인 직사각형의 둘레가 같습니다. 직사각형의 가로 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "The perimeter of a square with one side length of 80 centimeters (cm) is equal to the perimeter of a rectangle with a vertical length of 100 centimeters (cm). How many centimeters (cm) is the horizontal length of the rectangle?",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "80 4 [OP_MUL] 2 [OP_DIV] 100 [OP_SUB]",
        "solution_abst_en": "80 4 [OP_MUL] 2 [OP_DIV] 100 [OP_SUB]",
        "solution_code_ko": "var_a = 80\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 100\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 80\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 100\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "3891": {
        "category": "Correspondence",
        "question_ko": "호석이는 어떤 수에 8을 곱해 64를 얻었습니다. 어떤 수에 7을 곱한 결과를 구하시오.",
        "question_en": "Hoseok multiplied a certain number by 8 to get 64. Find the result of multiplying this number by 7.",
        "answer_ko": "56",
        "answer_en": "56",
        "solution_abst_ko": "64 8 [OP_DIV] 7 [OP_MUL]",
        "solution_abst_en": "64 8 [OP_DIV] 7 [OP_MUL]",
        "solution_code_ko": "var_a = 64\nvar_b = 8\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 64\nvar_b = 8\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "3892": {
        "category": "Arithmetic calculation",
        "question_ko": "25개의 사과가 든 상자 12개를 4일 만에 다 팔았다. 하루에 판매된 평균 사과는 몇 개인가?",
        "question_en": "12 boxes of 25 apples were sold in 4 days. On average, how many apples are sold per day?",
        "answer_ko": "75",
        "answer_en": "75",
        "solution_abst_ko": "12 25 [OP_MUL] 4 [OP_DIV]",
        "solution_abst_en": "12 25 [OP_MUL] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 25\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 25\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "3893": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 가장 큰 수를 2번째로 작은 수로 나눈 값은 얼마입니까?",
        "question_en": "There are five numbers 10, 11, 12, 13, and 14. What is the largest number divided by the second smallest number?",
        "answer_ko": "1.27",
        "answer_en": "1.27",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_DIV]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g / var_i\nprint('{:.2f}'.format(round(var_j+1e-10,2)))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g / var_i\nprint('{:.2f}'.format(round(var_j+1e-10,2)))"
    },
    "3894": {
        "category": "Correspondence",
        "question_ko": "1A+4B3=469입니다. B는 얼마인가요?",
        "question_en": "1A+4B3=469. How much is B?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "1A+4B3=469 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "1A+4B3=469 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '1A+4B3=469'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '1A+4B3=469'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "3895": {
        "category": "Comparison",
        "question_ko": "카페에서 3명의 학생이 과자를 주문합니다. 상우는 과자 8개를 주문하였고 재혁이는 10개를 주문했습니다. 민수는 상우보다는 과자를 많이 사고 재혁이보다는 적게 샀습니다. 민수가 산 과자는 모두 몇 개입니까?",
        "question_en": "Three students order snacks at a cafe. Sangwoo ordered 8 snacks and Jaehyuk ordered 10. Minsu bought more snacks than Sangwoo and less than Jaehyuk. How many snacks did Minsu buy?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "8 10 [OP_ADD] 2 [OP_FDIV]",
        "solution_abst_en": "8 10 [OP_ADD] 2 [OP_FDIV]",
        "solution_code_ko": "var_a = 8\nvar_b = 10\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 10\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "3896": {
        "category": "Comparison",
        "question_ko": "두 자리 수끼리의 곱셈에서 곱하는 수의 십의 자리 숫자 5를 3으로 잘못 보고 계산한 값이 1485가 되었습니다. 바르게 계산한 값이 2385일 때, 2개의 두 자리 수 중 더 큰 수를 쓰시오.",
        "question_en": "In the multiplication of two-digit numbers, the number 5 in the tens place of the multiplying number was mistakenly calculated as 3, and the product value was 1485. If the correctly calculated value is 2385, write the larger two-digit numbers.",
        "answer_ko": "53",
        "answer_en": "53",
        "solution_abst_ko": "[OP_LIST_SOL] 1485 2385 [OP_SUB] 3 5 [OP_SUB] 10 [OP_MUL] [OP_DIV] 2385 1485 2385 [OP_SUB] 3 5 [OP_SUB] 10 [OP_MUL] [OP_DIV] [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1485 2385 [OP_SUB] 3 5 [OP_SUB] 10 [OP_MUL] [OP_DIV] 2385 1485 2385 [OP_SUB] 3 5 [OP_SUB] 10 [OP_MUL] [OP_DIV] [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1485\nvar_b = 2385\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = 5\nvar_f = var_d - var_e\nvar_g = 10\nvar_h = var_f * var_g\nvar_i = var_c / var_h\nvar_j = 2385\nvar_k = 1485\nvar_l = 2385\nvar_m = var_k - var_l\nvar_n = 3\nvar_o = 5\nvar_p = var_n - var_o\nvar_q = 10\nvar_r = var_p * var_q\nvar_s = var_m / var_r\nvar_t = var_j / var_s\nlist_a= []\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_a.append(var_t)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nlist_a.reverse()\nvar_u = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_v = list_b[-var_u]\nprint(int(var_v))",
        "solution_code_en": "var_a = 1485\nvar_b = 2385\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = 5\nvar_f = var_d - var_e\nvar_g = 10\nvar_h = var_f * var_g\nvar_i = var_c / var_h\nvar_j = 2385\nvar_k = 1485\nvar_l = 2385\nvar_m = var_k - var_l\nvar_n = 3\nvar_o = 5\nvar_p = var_n - var_o\nvar_q = 10\nvar_r = var_p * var_q\nvar_s = var_m / var_r\nvar_t = var_j / var_s\nlist_a= []\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_a.append(var_t)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nlist_a.reverse()\nvar_u = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_v = list_b[-var_u]\nprint(int(var_v))"
    },
    "3897": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 8을 곱한 다음 5400을 더한 후 12로 나눈 몫이 530이다. 어떤 수를 구하시오.",
        "question_en": "When you multiply a certain number by 8 and add 5400 and divide it by 12, the resulting quotient is 530. Find that number.",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "530 12 [OP_MUL] 5400 [OP_SUB] 8 [OP_DIV]",
        "solution_abst_en": "530 12 [OP_MUL] 5400 [OP_SUB] 8 [OP_DIV]",
        "solution_code_ko": "var_a = 530\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 5400\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 530\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 5400\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "3898": {
        "category": "Comparison",
        "question_ko": "정국, 유정, 석진이 계단에 서 있습니다. 정국이가 서 있는 계단이 19번째 계단입니다. 유정이는 정국이보다 8계단 더 올라갔고, 석진이는 유정이보다 5계단 덜 올라갔을 때, 석진이는 정국이보다 몇 계단 위에 있습니까?",
        "question_en": "Jungkook, Yoojeong, and Seokjin are standing on the stairs. The stairs Jungkook is standing on are the 19th stairs. If Yoojeong climbed 8 steps higher than Jungkook and Seokjin climbed 5 steps less than Yoojung, how many steps is Seokjin higher than Jungkook?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "19 8 [OP_ADD] 5 [OP_SUB] 19 [OP_SUB]",
        "solution_abst_en": "19 8 [OP_ADD] 5 [OP_SUB] 19 [OP_SUB]",
        "solution_code_ko": "var_a = 19\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c - var_d\nvar_f = 19\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 19\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c - var_d\nvar_f = 19\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "3899": {
        "category": "Correspondence",
        "question_ko": "윤기는 어떤 수에서 46을 빼 15를 얻었습니다. 다음으로 호석이는 어떤 수에서 29를 빼어 결과를 얻었습니다. 이 결과값은?",
        "question_en": "Yoongi got 15 after subtracting 46 from a certain number. Next, Hoseok subtracted 29 from this same number to get the result. What is the value of this result?",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "15 46 [OP_ADD] 29 [OP_SUB]",
        "solution_abst_en": "15 46 [OP_ADD] 29 [OP_SUB]",
        "solution_code_ko": "var_a = 15\nvar_b = 46\nvar_c = var_a + var_b\nvar_d = 29\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 46\nvar_c = var_a + var_b\nvar_d = 29\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3900": {
        "category": "Arithmetic calculation",
        "question_ko": "5부터 12까지의 홀수 중 가장 큰 수와 가장 작은 수의 합을 구하시오.",
        "question_en": "Find the sum of the largest and smallest odd numbers from 5 to 12.",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "5 12 [OP_LIST_ODD] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "5 12 [OP_LIST_ODD] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 12\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[-var_c]\nvar_e = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = var_d + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 12\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[-var_c]\nvar_e = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = var_d + var_f\nprint(int(var_g))"
    },
    "3901": {
        "category": "Geometry",
        "question_ko": "오각형이 있습니다. 변의 수와 꼭짓점의 수를 모두 더하면 몇 개 일까요?",
        "question_en": "There is a pentagon. What is the sum of the number of edges and the number of vertices?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "5 5 [OP_ADD]",
        "solution_abst_en": "5 5 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "3902": {
        "category": "Possibility",
        "question_ko": "100이하인 짝수를 모두 종이에 적으면, 숫자 1을 몇 번 적어야 하는지 구하시오.",
        "question_en": "If you write down all the even numbers up to 100 on a piece of paper, how many times should you write down the number 1?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "1 100 [OP_LIST_EVEN] [OP_LIST2NUM] [OP_NUM2LIST] 1 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 100 [OP_LIST_EVEN] [OP_LIST2NUM] [OP_NUM2LIST] 1 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 100\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c=\"\"\nfor i in list_a:\n    i = str(i)\n    var_c = var_c + i\nlist_b = []\nvar_c = int(var_c)\nwhile var_c//10 > 0:\n    list_b.append(var_c%10)\n    var_c = var_c//10\nlist_b.append(var_c%10)\nlist_b = list_b[::-1]\nvar_d = 1\nvar_e = 0\nvar_d = int(var_d)\nfor i in list_b:\n    i = int(i)\n    if i == var_d:\n        var_e = var_e + 1\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 100\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c=\"\"\nfor i in list_a:\n    i = str(i)\n    var_c = var_c + i\nlist_b = []\nvar_c = int(var_c)\nwhile var_c//10 > 0:\n    list_b.append(var_c%10)\n    var_c = var_c//10\nlist_b.append(var_c%10)\nlist_b = list_b[::-1]\nvar_d = 1\nvar_e = 0\nvar_d = int(var_d)\nfor i in list_b:\n    i = int(i)\n    if i == var_d:\n        var_e = var_e + 1\nprint(int(var_e))"
    },
    "3903": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 20으로 나누면 몫은 15이고 나머지는 6입니다. 어떤 수는 얼마일까요?",
        "question_en": "When any number is divided by 20, the quotient is 15 and the remainder is 6. What number is it?",
        "answer_ko": "306",
        "answer_en": "306",
        "solution_abst_ko": "15 20 [OP_MUL] 6 [OP_ADD]",
        "solution_abst_en": "15 20 [OP_MUL] 6 [OP_ADD]",
        "solution_code_ko": "var_a = 15\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3904": {
        "category": "Geometry",
        "question_ko": "한 모서리의 길이가 3센티미터(㎝)인 주사위 27개를 정육면체 모양으로 쌓았습니다. 쌓아 만든 정육면체의 겉넓이는 몇 제곱센티미터(㎠)입니까?",
        "question_en": "Twenty-seven dice with each edge of 3 centimeters (cm) are stacked in the shape of a cube. What is the surface area of the stacked cubes in square centimeters (cm2)?",
        "answer_ko": "486",
        "answer_en": "486",
        "solution_abst_ko": "3 27 1/3 [OP_POW] [OP_MUL] 2 [OP_POW] 6 [OP_MUL]",
        "solution_abst_en": "3 27 1/3 [OP_POW] [OP_MUL] 2 [OP_POW] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 27\nvar_c = 0.3333333333333333\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e ** var_f\nvar_h = 6\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 3\nvar_b = 27\nvar_c = 0.3333333333333333\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e ** var_f\nvar_h = 6\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "3905": {
        "category": "Geometry",
        "question_ko": "정사각형 모양의 쿠키가 있습니다. 이 쿠키의 모든 변의 길이를 다 더했더니 17.8센티미터(㎝)가 나왔습니다. 쿠키의 한 변의 길이를 구하시오.",
        "question_en": "There is a square-shaped cookie. When you add up all the sides of this cookie, you get 17.8 centimeters (cm). Find the length of one side of the cookie.",
        "answer_ko": "4.45",
        "answer_en": "4.45",
        "solution_abst_ko": "17.8 4 [OP_DIV]",
        "solution_abst_en": "17.8 4 [OP_DIV]",
        "solution_code_ko": "var_a = 17.8\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 17.8\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "3906": {
        "category": "Comparison",
        "question_ko": "민영이는 4와 9를 모았습니다. 유나는 5와 6을 모았습니다. 누구의 모은 수의 합이 더 큽니까?",
        "question_en": "Minyoung collected 4 and 9. Yuna collected 5 and 6. Whose sum of numbers is greater?",
        "answer_ko": "민영",
        "answer_en": "Minyoung",
        "solution_abst_ko": "[OP_LIST_SOL] 민영 유나 [OP_LIST_EOL] [OP_LIST_SOL] 4 9 [OP_ADD] 5 6 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Minyoung Yuna [OP_LIST_EOL] [OP_LIST_SOL] 4 9 [OP_ADD] 5 6 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '민영'\nvar_b = '유나'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 9\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = 6\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Minyoung'\nvar_b = 'Yuna'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 9\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = 6\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "3907": {
        "category": "Arithmetic calculation",
        "question_ko": "49 이하의 짝수 중 가장 큰 수와 가장 작은 수의 합을 구하시오.",
        "question_en": "Find the sum of the largest and smallest even numbers less than or equal to 49.",
        "answer_ko": "50",
        "answer_en": "50",
        "solution_abst_ko": "1 49 [OP_LIST_EVEN] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "1 49 [OP_LIST_EVEN] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 49\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[-var_c]\nvar_e = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = var_d + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 49\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[-var_c]\nvar_e = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = var_d + var_f\nprint(int(var_g))"
    },
    "3908": {
        "category": "Possibility",
        "question_ko": "과녁판에 4개의 숫자 2, 5, 6, 9가 적혀있을 때, 이 중 3개를 사용하여 만들 수 있는 세 번째 큰 수와 세 번째 작은 수의 합을 쓰시오.",
        "question_en": "When the four numbers 2, 5, 6, and 9 are written on the target board, write the sum of the third largest number and the third smallest number that can be made using three of them.",
        "answer_ko": "1221",
        "answer_en": "1221",
        "solution_abst_ko": "[OP_LIST_SOL] 2 5 6 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 2 5 6 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 5\nvar_c = 6\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 2\nvar_b = 5\nvar_c = 6\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))"
    },
    "3909": {
        "category": "Arithmetic calculation",
        "question_ko": "(가) 끈의 길이는 (나) 끈의 5배입니다. (가) 끈의 길이는 (다) 끈의 6배입니다. (나) 끈의 길이가 12미터(m)이면 (다) 끈의 길이는 몇 미터(m)입니까?",
        "question_en": "The length of the string A is 5 times the length of the string B, and the length of A is 6 times longer than C. If B is 12 meters (m) long, what is the length of the string C in meters (m)?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "12 5 [OP_MUL] 6 [OP_FDIV]",
        "solution_abst_en": "12 5 [OP_MUL] 6 [OP_FDIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "3910": {
        "category": "Geometry",
        "question_ko": "반지름이 4센티미터(㎝)인 구를 구의 중심을 지나도록 자른 단면은 원이다. 이 원의 지름을 구하시오.",
        "question_en": "The cross-section of a sphere with a radius of 4 centimeters (cm) passing through the center of the sphere is a circle. Find the diameter of this circle.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "4 2 [OP_MUL]",
        "solution_abst_en": "4 2 [OP_MUL]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "3911": {
        "category": "Possibility",
        "question_ko": "5, 2, 8, 0 중에서 3개의 숫자를 사용하여 550보다 크고 850보다 작은 세 자리 수를 모두 만드려고 합니다. 만들 수 있는 세 자리 수의 개수는 모두 몇 개입니까?",
        "question_en": "You want to find three-digit numbers that are greater than 550 and less than 850 by using three numbers from 5, 2, 8, and 0. How many three-digit numbers can you think of?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 5 2 8 0 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 550 [OP_LIST_MORE] 850 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 5 2 8 0 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 550 [OP_LIST_MORE] 850 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = 8\nvar_d = 0\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 550\nlist_c = []\nfor i in list_b:\n    if i > var_f:\n        list_c.append(i)\nvar_g = 850\nlist_d = []\nfor i in list_c:\n    if i < var_g:\n        list_d.append(i)\nvar_h = len(list_d)\nprint(int(var_h))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = 8\nvar_d = 0\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 550\nlist_c = []\nfor i in list_b:\n    if i > var_f:\n        list_c.append(i)\nvar_g = 850\nlist_d = []\nfor i in list_c:\n    if i < var_g:\n        list_d.append(i)\nvar_h = len(list_d)\nprint(int(var_h))"
    },
    "3912": {
        "category": "Geometry",
        "question_ko": "어느 직사각형 모양의 공책의 각형의 넓이가 1.77제곱센티미터(㎠)입니다. 가로의 길이가 3센티미터(㎝)일 때, 세로의 길이는 몇 센티미터(㎝) 입니까?",
        "question_en": "The area of a rectangular notebook is 1.77 square centimeters (cm2). If the width is 3 centimeters (cm), how many centimeters (cm) is the length?",
        "answer_ko": "0.59",
        "answer_en": "0.59",
        "solution_abst_ko": "1.77 3 [OP_DIV]",
        "solution_abst_en": "1.77 3 [OP_DIV]",
        "solution_code_ko": "var_a = 1.77\nvar_b = 3\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 1.77\nvar_b = 3\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "3913": {
        "category": "Arithmetic calculation",
        "question_ko": "25센티미터(㎝)막대를 여러개 만든다고 합니다. 2미터(m) 50센티미터(㎝) 막대가 있다고 할 때 막대를 몇 번 잘라야 하나요?",
        "question_en": "It is said that several 25 centimeters (cm) bars are to be made. If you have a 2 meter (m) 50 centimeters (cm) bar, how many times do you have to cut the bar?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "2 100 [OP_MUL] 50 [OP_ADD] 25 [OP_DIV] 1 [OP_SUB]",
        "solution_abst_en": "2 100 [OP_MUL] 50 [OP_ADD] 25 [OP_DIV] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 2\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 50\nvar_e = var_c + var_d\nvar_f = 25\nvar_g = var_e / var_f\nvar_h = 1\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 2\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 50\nvar_e = var_c + var_d\nvar_f = 25\nvar_g = var_e / var_f\nvar_h = 1\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "3914": {
        "category": "Comparison",
        "question_ko": "정국이는 6에서 3을 곱한 수를 모았고, 윤기는 4를 모았습니다. 누가 더 큰 수를 모았나요?",
        "question_en": "Jungkook collected 6 multiplied by 3, and Yoongi collected 4. Who got the bigger number?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 윤기 [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_MUL] 4 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Yoongi [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_MUL] 4 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '윤기'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 3\nvar_e = var_c * var_d\nvar_f = 4\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Yoongi'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 3\nvar_e = var_c * var_d\nvar_f = 4\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "3915": {
        "category": "Comparison",
        "question_ko": "줄넘기 시합에서 지민이는 6등을 했고, 정국이는 8등을 했습니다. 태형이는 정국이보다 잘했지만 지민이보다는 못했습니다. 태형이의 등수는 몇 등입니까?",
        "question_en": "In the jumping rope competition, Jimin placed 6th and Jungkook placed 8th. Taehyung did better than Jungkook but worse than Jimin. What is Taehyung's rank?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "6 8 [OP_ADD] 2 [OP_FDIV]",
        "solution_abst_en": "6 8 [OP_ADD] 2 [OP_FDIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "3916": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 철사를 120센티미터(㎝)씩 나눴더니 2개로 나뉘고 2.4센티미터(㎝)가 남았다. 이 철사를 3등분하면 몇 센티미터(㎝)의 철사가 나오는지 구하시오.",
        "question_en": "When a wire was divided by intervals of 120 centimeters (cm), it was split into two parts, with 2.4 centimeters (cm) being left. Find how many centimeters (cm) of wire you'll get if you divide this wire into three parts.",
        "answer_ko": "80.80",
        "answer_en": "80.8",
        "solution_abst_ko": "120 2 [OP_MUL] 2.4 [OP_ADD] 3 [OP_DIV]",
        "solution_abst_en": "120 2 [OP_MUL] 2.4 [OP_ADD] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 120\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 2.4\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 120\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 2.4\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "3917": {
        "category": "Arithmetic calculation",
        "question_ko": "상자 안에 딸기맛 사탕이 156개, 레몬맛 사탕이 267개 있었습니다. 이 중에서 115개를 포장하여 친구에게 주었습니다. 친구에게 주고 남은 사탕은 몇 개입니까?",
        "question_en": "There were 156 Strawberry Flavored Candies and 267 Lemon Flavored Candies in the box. I wrapped 115 of these and gave them to a friend. How many candies do I have left after giving my friend?",
        "answer_ko": "308",
        "answer_en": "308",
        "solution_abst_ko": "156 267 [OP_ADD] 115 [OP_SUB]",
        "solution_abst_en": "156 267 [OP_ADD] 115 [OP_SUB]",
        "solution_code_ko": "var_a = 156\nvar_b = 267\nvar_c = var_a + var_b\nvar_d = 115\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 156\nvar_b = 267\nvar_c = var_a + var_b\nvar_d = 115\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3918": {
        "category": "Geometry",
        "question_ko": "어떤 정육면체의 한 모서리의 길이는 9센티미터(㎝)이다. 이 정육면체에서 한 모서리의 길이가 2센티미터(㎝)인 작은 정육면체를 꼭짓점 부분에서 잘라냈다. 남은 부분의 겉넓이는 몇 제곱센티미터(㎠)일까?",
        "question_en": "The length of one edge of a cube is 9 centimeters (cm). From this cube, a small cube with one edge 2 centimeters (cm) long was cut from the vertex. What is the surface area of the remaining part in square centimeters (cm2)?",
        "answer_ko": "486",
        "answer_en": "486",
        "solution_abst_ko": "9 9 [OP_MUL] 6 [OP_MUL]",
        "solution_abst_en": "9 9 [OP_MUL] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 9\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "3919": {
        "category": "Arithmetic calculation",
        "question_ko": "석진이네 반에는 48명의 학생이 있습니다. 어느 날 수학 숙제를 해 온 학생이 37명, 국어 숙제를 해 온 학생이 42명이었습니다. 수학 숙제와 국어 숙제를 모두 하지 않은 학생이 한 명도 없을 때, 수학 숙제와 국어 숙제를 모두 해 온 학생은 몇 명입니까?",
        "question_en": "There are 48 students in Seokjin's class. One day, there were 37 students who did math homework and 42 students who did Korean homework. If there is no student who has not done both math homework and Korean homework, how many students have done both math homework and Korean homework?",
        "answer_ko": "31",
        "answer_en": "31",
        "solution_abst_ko": "37 42 [OP_ADD] 48 [OP_SUB]",
        "solution_abst_en": "37 42 [OP_ADD] 48 [OP_SUB]",
        "solution_code_ko": "var_a = 37\nvar_b = 42\nvar_c = var_a + var_b\nvar_d = 48\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 37\nvar_b = 42\nvar_c = var_a + var_b\nvar_d = 48\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3920": {
        "category": "Correspondence",
        "question_ko": "문구점에 여러 색의 펜이 있습니다. 문구점의 펜 중 3/10은 빨간펜이고 1/5는 검정펜입니다. 문구점에 빨간펜이 12개 있습니다. 문구점에 검정펜은 몇 개인지 구하시오.",
        "question_en": "There are multi-colored pens in the stationery store. 3/10 of the pens in the stationery store are red and 1/5 are black. There are 12 red pens in the stationery store. Find how many black pens are in the stationery store.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "12 3/10 [OP_DIV] 1/5 [OP_MUL]",
        "solution_abst_en": "12 3/10 [OP_DIV] 1/5 [OP_MUL]",
        "solution_code_ko": "var_a = 12\nvar_b = 0.3\nvar_c = var_a / var_b\nvar_d = 0.2\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 0.3\nvar_c = var_a / var_b\nvar_d = 0.2\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "3921": {
        "category": "Arithmetic calculation",
        "question_ko": "유승이가 가진 구슬 수는 한솔이가 가진 구슬 수의 3배이고 한솔이는 영수보다 15개 더 가지고 있습니다. 세 사람이 가진 구슬 수는 165개일 때 유승이가 가진 구슬은 몇 개입니까?",
        "question_en": "Yoo Seung's number of marbles is three times that of Han-sol's, and Han-sol's has 15 more marbles than Young-soo's. If the three of them have 165 marbles, how many marbles does Yoo Seung have?",
        "answer_ko": "108",
        "answer_en": "108",
        "solution_abst_ko": "165 15 [OP_ADD] 3 1 1 [OP_ADD] [OP_ADD] [OP_DIV] 3 [OP_MUL]",
        "solution_abst_en": "165 15 [OP_ADD] 3 1 1 [OP_ADD] [OP_ADD] [OP_DIV] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 165\nvar_b = 15\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 1\nvar_f = 1\nvar_g = var_e + var_f\nvar_h = var_d + var_g\nvar_i = var_c / var_h\nvar_j = 3\nvar_k = var_i * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 165\nvar_b = 15\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 1\nvar_f = 1\nvar_g = var_e + var_f\nvar_h = var_d + var_g\nvar_i = var_c / var_h\nvar_j = 3\nvar_k = var_i * var_j\nprint(int(var_k))"
    },
    "3922": {
        "category": "Comparison",
        "question_ko": "영서, 건욱, 수환 세 사람이 있습니다. 영서는 건욱이보다 무겁고, 수환이는 영서보다 무거울 때, 가장 무거운 사람은 누구입니까?",
        "question_en": "There are three people: Youngseo, Gunuk, and Suhwan. When Youngseo is heavier than Gunwook and Suhwan is heavier than Youngseo, who is the heaviest?",
        "answer_ko": "수환",
        "answer_en": "Suhwan",
        "solution_abst_ko": "[OP_LIST_SOL] 영서 건욱 수환 [OP_LIST_EOL] [OP_LIST_SOL] 영서 건욱 > 수환 영서 > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Youngseo Gunuk Suhwan [OP_LIST_EOL] [OP_LIST_SOL] Youngseo Gunuk > Suhwan Youngseo > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '영서'\nvar_b = '건욱'\nvar_c = '수환'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '영서'\nvar_e = '건욱'\nvar_f = '>'\nvar_g = '수환'\nvar_h = '영서'\nvar_i = '>'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(var_k)",
        "solution_code_en": "var_a = 'Youngseo'\nvar_b = 'Gunuk'\nvar_c = 'Suhwan'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'Youngseo'\nvar_e = 'Gunuk'\nvar_f = '>'\nvar_g = 'Suhwan'\nvar_h = 'Youngseo'\nvar_i = '>'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(var_k)"
    },
    "3923": {
        "category": "Geometry",
        "question_ko": "가로와 세로의 길이 차가 6센티미터(㎝)이고, 둘레의 길이는 68센티미터(㎝)인 직사각형의 넓이를 구하시오.",
        "question_en": "Find the area of a rectangle whose width and length differ by 6 centimeters (cm) and whose perimeter is 68 centimeters (cm).",
        "answer_ko": "280",
        "answer_en": "280",
        "solution_abst_ko": "68 2 [OP_DIV] 6 [OP_SUB] 2 [OP_DIV] 68 2 [OP_DIV] 6 [OP_SUB] 2 [OP_DIV] 6 [OP_ADD] [OP_MUL]",
        "solution_abst_en": "68 2 [OP_DIV] 6 [OP_SUB] 2 [OP_DIV] 68 2 [OP_DIV] 6 [OP_SUB] 2 [OP_DIV] 6 [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 68\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 68\nvar_i = 2\nvar_j = var_h / var_i\nvar_k = 6\nvar_l = var_j - var_k\nvar_m = 2\nvar_n = var_l / var_m\nvar_o = 6\nvar_p = var_n + var_o\nvar_q = var_g * var_p\nprint(int(var_q))",
        "solution_code_en": "var_a = 68\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 68\nvar_i = 2\nvar_j = var_h / var_i\nvar_k = 6\nvar_l = var_j - var_k\nvar_m = 2\nvar_n = var_l / var_m\nvar_o = 6\nvar_p = var_n + var_o\nvar_q = var_g * var_p\nprint(int(var_q))"
    },
    "3924": {
        "category": "Correspondence",
        "question_ko": "호석은 어떤 수에서 7을 빼서 9를 얻었다. 이 수에 3을 곱한 결과는?",
        "question_en": "Hoseok subtracted 7 from a certain number to get 9. What is the result of multiplying this number by 3?",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "9 7 [OP_ADD] 3 [OP_MUL]",
        "solution_abst_en": "9 7 [OP_ADD] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 9\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "3925": {
        "category": "Possibility",
        "question_ko": "정국, 지민, 윤기, 유나 중에서 2사람을 선택하려고 합니다. 선택할 수 있는 경우는 모두 몇 가지 입니까?",
        "question_en": "Among Jungkook, Jimin, Yoongi, and Yuna, I'm trying to choose 2 people. How many options are there in total?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 지민 윤기 유나 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Jimin Yoongi Yuna [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '지민'\nvar_c = '윤기'\nvar_d = '유나'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g / (i+1)\nprint(int(var_g))",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Jimin'\nvar_c = 'Yoongi'\nvar_d = 'Yuna'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g / (i+1)\nprint(int(var_g))"
    },
    "3926": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 36을 빼야 하는데 잘못하여 63을 뺀 결과가 8이 나왔습니다. 바르게 계산한 결과를 구하시오.",
        "question_en": "You had to subtract 36 from a number, but you mistakenly subtracted 63 and got 8 as an answer. Find the answer to the correct calculation.",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "8 63 [OP_ADD] 36 [OP_SUB]",
        "solution_abst_en": "8 63 [OP_ADD] 36 [OP_SUB]",
        "solution_code_ko": "var_a = 8\nvar_b = 63\nvar_c = var_a + var_b\nvar_d = 36\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 63\nvar_c = var_a + var_b\nvar_d = 36\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3927": {
        "category": "Geometry",
        "question_ko": "정육면체 모양의 상자가 있습니다. 이 상자의 모든 모서리의 길이를 다 더했을 때 144센티미터(㎝)라면, 한 모서리의 길이는 몇 센티미터(㎝)일지 구하시오.",
        "question_en": "There is a box in the shape of a cube. If the sum of all the edges of the box is 144 centimeters (cm), how many centimeters (cm) is the length of one edge?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "144 12 [OP_DIV]",
        "solution_abst_en": "144 12 [OP_DIV]",
        "solution_code_ko": "var_a = 144\nvar_b = 12\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 144\nvar_b = 12\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "3928": {
        "category": "Arithmetic calculation",
        "question_ko": "연속하는 두 자연수의 합이 39일 때, 두 자연수 중에 제일 작은 수를 구하시오.",
        "question_en": "If the sum of two consecutive natural numbers is 39, find the smallest of the two natural numbers.",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "39 1 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "39 1 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 39\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 39\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "3929": {
        "category": "Arithmetic calculation",
        "question_ko": "(가) 마을에는 남학생이 204명, 여학생이 468명 있고, (나) 마을에는 남학생이 334명, 여학생이 516명 있고, (다) 마을에는 남학생이 427명, 여학생이 458명 있고, (라) 마을에는 남학생이 549명, 여학생이 239명 있습니다. 네 마을의 남학생 수와 여학생 수의 차는 몇 명입니까?",
        "question_en": "There are 204 male students and 468 female students in (A) village, 334 male students and 516 female students in (B) village, 427 male students and 458 female students in (C) village, and 549 male students and 239 female students in (D) village. What is the difference between the total number of boys and total number of girls in your town?",
        "answer_ko": "167",
        "answer_en": "167",
        "solution_abst_ko": "[OP_LIST_SOL] 204 334 427 549 [OP_LIST_EOL] [OP_LIST_SUM] [OP_LIST_SOL] 468 516 458 239 [OP_LIST_EOL] [OP_LIST_SUM] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "[OP_LIST_SOL] 204 334 427 549 [OP_LIST_EOL] [OP_LIST_SUM] [OP_LIST_SOL] 468 516 458 239 [OP_LIST_EOL] [OP_LIST_SUM] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 204\nvar_b = 334\nvar_c = 427\nvar_d = 549\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_e = sum(list_a)\nvar_f = 468\nvar_g = 516\nvar_h = 458\nvar_i = 239\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nlist_b = [float(i) for i in list_b]\nvar_j = sum(list_b)\nvar_k = var_e - var_j\nvar_l = abs(var_k)\nprint(int(var_l))",
        "solution_code_en": "var_a = 204\nvar_b = 334\nvar_c = 427\nvar_d = 549\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_e = sum(list_a)\nvar_f = 468\nvar_g = 516\nvar_h = 458\nvar_i = 239\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nlist_b = [float(i) for i in list_b]\nvar_j = sum(list_b)\nvar_k = var_e - var_j\nvar_l = abs(var_k)\nprint(int(var_l))"
    },
    "3930": {
        "category": "Arithmetic calculation",
        "question_ko": "진호는 2500원을 가지고 문구점에 가서 120원짜리 지우개 5개를 사고 350원짜리 연필 3개를 샀습니다. 진호가 지우개와 연필을 사고 남은 돈이 얼마인지 구하시오.",
        "question_en": "Jinho went to the stationery store with 2,500 won and bought 5 erasers which cost 120 won each and 3 pencils that cost 350 won each. Find out the remaining money Jinho has after buying erasers and pencils.",
        "answer_ko": "850",
        "answer_en": "850",
        "solution_abst_ko": "2500 120 5 [OP_MUL] 350 3 [OP_MUL] [OP_ADD] [OP_SUB]",
        "solution_abst_en": "2500 120 5 [OP_MUL] 350 3 [OP_MUL] [OP_ADD] [OP_SUB]",
        "solution_code_ko": "var_a = 2500\nvar_b = 120\nvar_c = 5\nvar_d = var_b * var_c\nvar_e = 350\nvar_f = 3\nvar_g = var_e * var_f\nvar_h = var_d + var_g\nvar_i = var_a - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 2500\nvar_b = 120\nvar_c = 5\nvar_d = var_b * var_c\nvar_e = 350\nvar_f = 3\nvar_g = var_e * var_f\nvar_h = var_d + var_g\nvar_i = var_a - var_h\nprint(int(var_i))"
    },
    "3931": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 50을 빼고 4로 나눈 결과를 3을 다시 곱하고 28을 더해주었습니다. 최종 결과가 73이라면 어떤 수는 얼마입니까?",
        "question_en": "We subtracted 50 from a certain number, divided it by 4, multiplied it by 3, and added 28. If the final result is 73, what is the certain number?",
        "answer_ko": "110",
        "answer_en": "110",
        "solution_abst_ko": "73 28 [OP_SUB] 3 [OP_DIV] 4 [OP_MUL] 50 [OP_ADD]",
        "solution_abst_en": "73 28 [OP_SUB] 3 [OP_DIV] 4 [OP_MUL] 50 [OP_ADD]",
        "solution_code_ko": "var_a = 73\nvar_b = 28\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = 4\nvar_g = var_e * var_f\nvar_h = 50\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 73\nvar_b = 28\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = 4\nvar_g = var_e * var_f\nvar_h = 50\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "3932": {
        "category": "Possibility",
        "question_ko": "과일 가게에서 사과, 배, 참외, 감, 수박 중 2가지의 과일을 사려고 할 때, 구매할 수 있는 방법은 모두 몇 가지입니까?",
        "question_en": "How many ways are there for you to buy 2 fruits out of apples, pears, melons, persimmons, and watermelons at the fruit store?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 배 참외 감 수박 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] apples pears melons persimmons watermelons [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '배'\nvar_c = '참외'\nvar_d = '감'\nvar_e = '수박'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h / (i+1)\nprint(int(var_h))",
        "solution_code_en": "var_a = 'apples'\nvar_b = 'pears'\nvar_c = 'melons'\nvar_d = 'persimmons'\nvar_e = 'watermelons'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h / (i+1)\nprint(int(var_h))"
    },
    "3933": {
        "category": "Correspondence",
        "question_ko": "13을 7로 나눴더니 몫이 1이 되었고, 나머지는 A가 되었습니다. 이 때 A의 값을 구하시오.",
        "question_en": "When 13 is divided by 7, the quotient is 1 and the remainder is A. Find the value of A at this time.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "13 7 1 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "13 7 1 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 13\nvar_b = 7\nvar_c = 1\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 13\nvar_b = 7\nvar_c = 1\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "3934": {
        "category": "Possibility",
        "question_ko": "숫자 카드 3, 5, 8, 9 중 3장을 뽑아 만들 수 있는 세 자리 자연수의 개수를 구하시오.",
        "question_en": "Find the number of three-digit natural numbers that can be made by drawing three of the number cards 3, 5, 8, and 9.",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "[OP_LIST_SOL] 3 5 8 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 3 5 8 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 3\nvar_b = 5\nvar_c = 8\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 3\nvar_b = 5\nvar_c = 8\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "3935": {
        "category": "Arithmetic calculation",
        "question_ko": "15마리의 닭 중 암탉은 3마리밖에 없습니다. 병아리의 수와 수탉에서 4마리 뺀 수가 같다면, 병아리는 몇 마리입니까?",
        "question_en": "Out of 15 chickens, there are only 3 hens. If there are 4 chicks fewer than the number of roosters, how many chicks are there?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "15 3 [OP_SUB] 4 [OP_SUB]",
        "solution_abst_en": "15 3 [OP_SUB] 4 [OP_SUB]",
        "solution_code_ko": "var_a = 15\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3936": {
        "category": "Comparison",
        "question_ko": "발표가 진행되는 동안 학생들은 차례대로 발표를 합니다. 뒤에서 6번째는 은정, 7명의 학생은 은정이보다 뒤에서 발표한다. 총 몇 명의 학생이 발표합니까?",
        "question_en": "Students give their presentations taking turns. If Eunjeong's turn is at the 6th from the last, and the 7 students give presentations ahead of Eunjeong. How many students are there in total?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "6 7 [OP_ADD]",
        "solution_abst_en": "6 7 [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "3937": {
        "category": "Correspondence",
        "question_ko": "미술 선생님이 리본 테이프 132.6센티미터(㎝)를 학생들에게 동일한 길이로 나누어 주었더니 한 학생당 13.26센티미터(㎝)를 받게 되었다. 이 학생들에게 0.064미터(m)의 끈을 동일한 길이로 나누어 준다면 한 학생당 몇 미터(m)의 끈을 받는지 구하시오.",
        "question_en": "When the art teacher distributed 132.6 centimeters (cm) of ribbon tape to the students in equal lengths, each student received 13.26 centimeters (cm). If you give these students equal lengths of string of 0.064 meters (m), how many meters (m) of string will each student receive?",
        "answer_ko": "0.64",
        "answer_en": "0.64",
        "solution_abst_ko": "132.6 13.26 [OP_DIV] 0.064 [OP_MUL]",
        "solution_abst_en": "132.6 13.26 [OP_DIV] 0.064 [OP_MUL]",
        "solution_code_ko": "var_a = 132.6\nvar_b = 13.26\nvar_c = var_a / var_b\nvar_d = 0.064\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 132.6\nvar_b = 13.26\nvar_c = var_a / var_b\nvar_d = 0.064\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "3938": {
        "category": "Geometry",
        "question_ko": "어느 각뿔의 모서리는 14개입니다. 이 각뿔의 꼭짓점의 개수를 구하시오.",
        "question_en": "A pyramid has 14 edges. Find the number of vertices of this pyramid.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "14 2 [OP_DIV] 1 [OP_ADD]",
        "solution_abst_en": "14 2 [OP_DIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 14\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 14\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3939": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 36을 빼야 하는데 잘못해서 63을 뺐더니 24가 되었습니다. 바르게 계산한 결과를 구하시오.",
        "question_en": "I was to subtract 36 from a number, but mistakenly subtracted 63, and got 24 as a result. Find out the right answer to the calculation.",
        "answer_ko": "51",
        "answer_en": "51",
        "solution_abst_ko": "24 63 [OP_ADD] 36 [OP_SUB]",
        "solution_abst_en": "24 63 [OP_ADD] 36 [OP_SUB]",
        "solution_code_ko": "var_a = 24\nvar_b = 63\nvar_c = var_a + var_b\nvar_d = 36\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 24\nvar_b = 63\nvar_c = var_a + var_b\nvar_d = 36\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3940": {
        "category": "Arithmetic calculation",
        "question_ko": "(가) 물건 17개와 (나) 물건 몇 개가 있습니다. (가) 물건과 (나) 물건을 합치면 모두 35개입니다. (나) 물건은 몇 개 있습니까?",
        "question_en": "There are 17 (a) objects and  some (b) objects. If you add (a) object and (b) object, there are 35 in total. How many (b) objects do you have?",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "35 17 [OP_SUB]",
        "solution_abst_en": "35 17 [OP_SUB]",
        "solution_code_ko": "var_a = 35\nvar_b = 17\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 35\nvar_b = 17\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "3941": {
        "category": "Comparison",
        "question_ko": "3개의 상자는 각각 1개당 무게가 200그램(g)인 단팥빵 16개를 담고 있다. 또한 1개당 250그램(g)의 소라빵을 12개 담은 상자가 2개도 있다. 빈 상자의 무게가 같을 시 한 상자의 무게가 더 무거운 상자에 포함된 빵은 무엇인가요?",
        "question_en": "Each of the three boxes contains 16 pieces of bread A, each weighing 200 grams (g). There are also two boxes containing 12 pieces of bread B, each weighing 250 grams (g). If the empty boxes weigh the same, which bread is contained in one box whose weight is heavier?",
        "answer_ko": "단팥빵",
        "answer_en": "A",
        "solution_abst_ko": "[OP_LIST_SOL] 단팥빵 소라빵 [OP_LIST_EOL] [OP_LIST_SOL] 200 16 3 3 [OP_DIV] [OP_MUL] [OP_MUL] 250 12 2 2 [OP_DIV] [OP_MUL] [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 200 16 3 3 [OP_DIV] [OP_MUL] [OP_MUL] 250 12 2 2 [OP_DIV] [OP_MUL] [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '단팥빵'\nvar_b = '소라빵'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 200\nvar_d = 16\nvar_e = 3\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = var_d * var_g\nvar_i = var_c * var_h\nvar_j = 250\nvar_k = 12\nvar_l = 2\nvar_m = 2\nvar_n = var_l / var_m\nvar_o = var_k * var_n\nvar_p = var_j * var_o\nlist_b= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nlist_b.reverse()\nvar_q = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_r = list_c[-var_q]\nvar_s = list_b.index(var_r)+1\nvar_t = list_a[var_s-1]\nprint(var_t)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 200\nvar_d = 16\nvar_e = 3\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = var_d * var_g\nvar_i = var_c * var_h\nvar_j = 250\nvar_k = 12\nvar_l = 2\nvar_m = 2\nvar_n = var_l / var_m\nvar_o = var_k * var_n\nvar_p = var_j * var_o\nlist_b= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nlist_b.reverse()\nvar_q = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_r = list_c[-var_q]\nvar_s = list_b.index(var_r)+1\nvar_t = list_a[var_s-1]\nprint(var_t)"
    },
    "3942": {
        "category": "Comparison",
        "question_ko": "태형, 민주, 상민, 윤정, 유정이 차례로 결승선에 진입했다. 가장 먼저 입장한 사람은?",
        "question_en": "Taehyung, Minju, Sangmin, Yoonjung, and Yoojung entered the finish line in that order. Who entered first?",
        "answer_ko": "태형",
        "answer_en": "Taehyung",
        "solution_abst_ko": "[OP_LIST_SOL] 태형 민주 상민 윤정 유정 [OP_LIST_EOL] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Taehyung Minju Sangmin Yoonjung Yoojung [OP_LIST_EOL] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '태형'\nvar_b = '민주'\nvar_c = '상민'\nvar_d = '윤정'\nvar_e = '유정'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nvar_g = list_a[var_f-1]\nprint(var_g)",
        "solution_code_en": "var_a = 'Taehyung'\nvar_b = 'Minju'\nvar_c = 'Sangmin'\nvar_d = 'Yoonjung'\nvar_e = 'Yoojung'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nvar_g = list_a[var_f-1]\nprint(var_g)"
    },
    "3943": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이는 3명의 친구에게 15개의 색종이를 균일하게 나누어주려고 합니다. 각각 몇 개의 색종이를 받습니까?",
        "question_en": "Jungkook wants to equally distribute 15 sheets of colored paper to 3 friends. How many sheets of colored paper do they get each?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "15 3 [OP_DIV]",
        "solution_abst_en": "15 3 [OP_DIV]",
        "solution_code_ko": "var_a = 15\nvar_b = 3\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 15\nvar_b = 3\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "3944": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 -5/12를 더하면 1/3일 때, 어떤 수를 구하시오.",
        "question_en": "What number is 1/3 when you add -5/12 to it?",
        "answer_ko": "0.75",
        "answer_en": "0.75",
        "solution_abst_ko": "1/3 -5/12 [OP_SUB]",
        "solution_abst_en": "1/3 -5/12 [OP_SUB]",
        "solution_code_ko": "var_a = 0.3333333333333333\nvar_b = -0.4166666666666667\nvar_c = var_a - var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 0.3333333333333333\nvar_b = -0.4166666666666667\nvar_c = var_a - var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "3945": {
        "category": "Correspondence",
        "question_ko": "지민이는 34에 어떤 수를 더하려고 합니다. 실수로 96에 어떤 수를 나눴을 때의 결과가 6이라면 바르게 계산한 결과를 구하세요.",
        "question_en": "Jimin wanted to add a particular number to 34. If the result of dividing 96 by that particular number was 6, find the correct result. ",
        "answer_ko": "50",
        "answer_en": "50",
        "solution_abst_ko": "34 96 6 [OP_DIV] [OP_ADD]",
        "solution_abst_en": "34 96 6 [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 34\nvar_b = 96\nvar_c = 6\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 34\nvar_b = 96\nvar_c = 6\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "3946": {
        "category": "Correspondence",
        "question_ko": "6은 어떤 수에 3을 더한 숫자입니다. 어떤 수보다 5 큰 숫자는 얼마인가요?",
        "question_en": "6 is a number added 3 to the number. What number is it that is 5 greater than the number?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "6 3 [OP_SUB] 5 [OP_ADD]",
        "solution_abst_en": "6 3 [OP_SUB] 5 [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3947": {
        "category": "Arithmetic calculation",
        "question_ko": "네 자리 수에서 두 자리 수를 빼는 계산에서 네 자리 수의 일의 자리 숫자는 5로 계산하고, 두 자리 수의 십의 자리 숫자와 일의 자리 숫자를 바꾸어 84로 계산했더니 1781이 되었습니다. 네 자리 수의 일의 자리 숫자가 원래 9였다면, 바르게 계산한 결과는 얼마입니까?",
        "question_en": "In the calculation of subtracting a two-digit number from a four-digit number, I mistook the number in the units place of the four-digit number for 5, and I made an error and understood the two-digit number as 84 because I confused the numbers in the tens place with the units place. The result of this calculation was 1781. If the number in the units place of a four-digit number was originally 9, what would be the correct result?",
        "answer_ko": "1821",
        "answer_en": "1821",
        "solution_abst_ko": "1781 9 5 [OP_SUB] [OP_ADD] 84 48 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "1781 9 5 [OP_SUB] [OP_ADD] 84 48 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 1781\nvar_b = 9\nvar_c = 5\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 84\nvar_g = 48\nvar_h = var_f - var_g\nvar_i = var_e + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1781\nvar_b = 9\nvar_c = 5\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 84\nvar_g = 48\nvar_h = var_f - var_g\nvar_i = var_e + var_h\nprint(int(var_i))"
    },
    "3948": {
        "category": "Arithmetic calculation",
        "question_ko": "정국의 몸무게는 54킬로그램(㎏)보다 154그램(g) 무겁습니다. 유정이의 몸무게를 킬로그램(㎏)로 써보시오",
        "question_en": "Jungkook's weight is 154 grams (g) heavier than 54 kilograms (kg). Write Jungkook's weight in kilograms (kg)",
        "answer_ko": "54.15",
        "answer_en": "54.15",
        "solution_abst_ko": "54 154 1000 [OP_DIV] [OP_ADD]",
        "solution_abst_en": "54 154 1000 [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 54\nvar_b = 154\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 54\nvar_b = 154\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "3949": {
        "category": "Correspondence",
        "question_ko": "40을 어떤 수에 빼야 할 것을 잘못하여 21을 어떤 수에 더한 결과는 52가 나옵니다. 바르게 계산하면 얼마인가요?",
        "question_en": "You were supposed to subtract 40 from a certain number, but you accidentally added 21 and the result was 52. What is the answer to the corrected calculation?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "52 21 [OP_SUB] 40 [OP_SUB]",
        "solution_abst_en": "52 21 [OP_SUB] 40 [OP_SUB]",
        "solution_code_ko": "var_a = 52\nvar_b = 21\nvar_c = var_a - var_b\nvar_d = 40\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 52\nvar_b = 21\nvar_c = var_a - var_b\nvar_d = 40\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3950": {
        "category": "Geometry",
        "question_ko": "가로와 세로의 길이가 각각 36미터(m), 72미터(m)인 직사각형 모양의 공터가 있습니다. 이 공터에 가로가 3미터(m), 세로가 4미터(m)인 직사각형을 밑면으로 하는 박스를 최대 몇 개 보관 할수 있는지 구하시오.",
        "question_en": "There is a rectangular vacant lot with the width and length of 36 meters (m) and 72 meters (m), respectively. Find the maximum number of boxes that can be stored in this clearing, whose base is a rectangle measuring 3 meters (m) wide and 4 meters (m) long.",
        "answer_ko": "216",
        "answer_en": "216",
        "solution_abst_ko": "36 3 [OP_FDIV] 72 4 [OP_FDIV] [OP_MUL]",
        "solution_abst_en": "36 3 [OP_FDIV] 72 4 [OP_FDIV] [OP_MUL]",
        "solution_code_ko": "var_a = 36\nvar_b = 3\nvar_c = var_a // var_b\nvar_d = 72\nvar_e = 4\nvar_f = var_d // var_e\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 36\nvar_b = 3\nvar_c = var_a // var_b\nvar_d = 72\nvar_e = 4\nvar_f = var_d // var_e\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "3951": {
        "category": "Comparison",
        "question_ko": "길이가 364 미터(m) 인 도로의 한쪽에는 약국이 22.75 미터(m) 간격으로, 다른 한쪽에는 편의점이 45.5 미터(m) 간격으로 있습니다. 이 도로에는 약국과 편의점 중 어느 것을 더 많이 있을까요?",
        "question_en": "There are pharmacies every 22.75 meters (m) on one side of the 364 meters (m) long road, and shops every 45.5 meters (m) on the other side. Which are more on this road, pharmacies or shops?",
        "answer_ko": "약국",
        "answer_en": "pharmacies",
        "solution_abst_ko": "[OP_LIST_SOL] 약국 편의점 [OP_LIST_EOL] [OP_LIST_SOL] 364 22.75 [OP_DIV] 364 45.5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] pharmacies shops [OP_LIST_EOL] [OP_LIST_SOL] 364 22.75 [OP_DIV] 364 45.5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '약국'\nvar_b = '편의점'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 364\nvar_d = 22.75\nvar_e = var_c / var_d\nvar_f = 364\nvar_g = 45.5\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'pharmacies'\nvar_b = 'shops'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 364\nvar_d = 22.75\nvar_e = var_c / var_d\nvar_f = 364\nvar_g = 45.5\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "3952": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 숫자 5만을 가지고 사칙연산을 수행했습니다. 먼저 5를 더하고 5를 곱한 이후, 5를 빼주고 다시 5로 나눠주었을 때 5가 되었다면 어떤 수는 얼마입니까?",
        "question_en": "The four arithmetic operations were carried out using only the number 5 up to a certain number. What is the number if you first add 5, then multiply by 5, then subtract 5, then divide by 5 to get 5?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "5 5 [OP_MUL] 5 [OP_ADD] 5 [OP_DIV] 5 [OP_SUB]",
        "solution_abst_en": "5 5 [OP_MUL] 5 [OP_ADD] 5 [OP_DIV] 5 [OP_SUB]",
        "solution_code_ko": "var_a = 5\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = var_e / var_f\nvar_h = 5\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 5\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = var_e / var_f\nvar_h = 5\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "3953": {
        "category": "Arithmetic calculation",
        "question_ko": "마트에서 사과 12상자를 4일 만에 전부 팔았습니다. 각 상자당 사과가 25개씩 들어 있었다면, 하루에 판매된 평균 사과 수를 구하시오.",
        "question_en": "The mart sold all 12 boxes of apples in 4 days. If each crate contained 25 apples, find the average number of apples that were sold per day.",
        "answer_ko": "75",
        "answer_en": "75",
        "solution_abst_ko": "12 25 [OP_MUL] 4 [OP_DIV]",
        "solution_abst_en": "12 25 [OP_MUL] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 25\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 25\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "3954": {
        "category": "Arithmetic calculation",
        "question_ko": "우진이는 하루의 1/3은 잠을 자고 그 나머지의 3/4은 공부를 하고 그 나머지의 1/4은 컴퓨터 게임을 합니다. 우진이가 하루 중 컴퓨터 게임을 하는 시간은 몇 시간입니까?",
        "question_en": "Woojin spends 1/3 of the day sleeping, 3/4 of the remaining time studying, and 1/4 of the rest of the time playing computer games. How many hours does Woojin spend playing computer games in a day?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "24 1 1/3 [OP_SUB] [OP_MUL] 1 3/4 [OP_SUB] [OP_MUL] 1/4 [OP_MUL]",
        "solution_abst_en": "24 1 1/3 [OP_SUB] [OP_MUL] 1 3/4 [OP_SUB] [OP_MUL] 1/4 [OP_MUL]",
        "solution_code_ko": "var_a = 24\nvar_b = 1\nvar_c = 0.3333333333333333\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 1\nvar_g = 0.75\nvar_h = var_f - var_g\nvar_i = var_e * var_h\nvar_j = 0.25\nvar_k = var_i * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 24\nvar_b = 1\nvar_c = 0.3333333333333333\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 1\nvar_g = 0.75\nvar_h = var_f - var_g\nvar_i = var_e * var_h\nvar_j = 0.25\nvar_k = var_i * var_j\nprint(int(var_k))"
    },
    "3955": {
        "category": "Comparison",
        "question_ko": "태희는 줄넘기를 어제는 23번 했고 오늘은 어제보다 14번 더 많이 했습니다. 지훈이는 줄넘기를 어제는 35번 했고 오늘은 어제보다 19번 더 적게 했습니다. 어제와 오늘 합해서 줄넘기를 더 많이 한 사람은 누구입니까?",
        "question_en": "Taehee jumped rope 23 times yesterday and 14 times more today. Jihoon jumped rope 35 times yesterday and 19 fewer times today than yesterday. Who skipped more ropes yesterday and today combined?",
        "answer_ko": "태희",
        "answer_en": "Taehee",
        "solution_abst_ko": "[OP_LIST_SOL] 태희 지훈 [OP_LIST_EOL] [OP_LIST_SOL] [OP_LIST_SOL] 23 23 14 [OP_LIST_EOL] [OP_LIST_SUM] [OP_LIST_SOL] 35 35 -19 [OP_LIST_EOL] [OP_LIST_SUM] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_POP] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Taehee Jihoon [OP_LIST_EOL] [OP_LIST_SOL] [OP_LIST_SOL] 23 23 14 [OP_LIST_EOL] [OP_LIST_SUM] [OP_LIST_SOL] 35 35 -19 [OP_LIST_EOL] [OP_LIST_SUM] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_POP] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '태희'\nvar_b = '지훈'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 23\nvar_d = 23\nvar_e = 14\nlist_b= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nvar_g = 35\nvar_h = 35\nvar_i = -19\nlist_c= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_c.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_c.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_c.append(var_g)\nlist_c.reverse()\nlist_c = [float(i) for i in list_c]\nvar_j = sum(list_c)\nlist_d= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_d.append(var_j)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_d.append(var_f)\nlist_d.reverse()\nvar_k = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_l = list_e[-var_k]\nvar_m = list_d.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'Taehee'\nvar_b = 'Jihoon'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 23\nvar_d = 23\nvar_e = 14\nlist_b= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nvar_g = 35\nvar_h = 35\nvar_i = -19\nlist_c= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_c.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_c.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_c.append(var_g)\nlist_c.reverse()\nlist_c = [float(i) for i in list_c]\nvar_j = sum(list_c)\nlist_d= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_d.append(var_j)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_d.append(var_f)\nlist_d.reverse()\nvar_k = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_l = list_e[-var_k]\nvar_m = list_d.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "3956": {
        "category": "Geometry",
        "question_ko": "한 변이 200미터(m)인 정사각형 모양의 땅이 있습니다. 이 땅의 넓이는 얼마입니까?",
        "question_en": "There is a square piece of land with sides measuring 200 meters (m). What is the area of this land?",
        "answer_ko": "40000",
        "answer_en": "40000",
        "solution_abst_ko": "200 2 [OP_POW]",
        "solution_abst_en": "200 2 [OP_POW]",
        "solution_code_ko": "var_a = 200\nvar_b = 2\nvar_c = var_a ** var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 200\nvar_b = 2\nvar_c = var_a ** var_b\nprint(int(var_c))"
    },
    "3957": {
        "category": "Possibility",
        "question_ko": "4, 3, 1, 7, 9 중 3개를 사용하여 십의 자리 숫자가 3인 두 번째 큰 수는 무엇입니까?",
        "question_en": "What is the second greatest number with 3 in the tens place using 3 numbers out of 4, 3, 1, 7, and 9?",
        "answer_ko": "934",
        "answer_en": "934",
        "solution_abst_ko": "[OP_LIST_SOL] 4 3 1 7 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 3 [OP_LIST_SEARCH_FIXED_DIGIT] 2 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 4 3 1 7 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 3 [OP_LIST_SEARCH_FIXED_DIGIT] 2 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 4\nvar_b = 3\nvar_c = 1\nvar_d = 7\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 10\nvar_h = 3\nlist_c = [] \nvar_g = int(var_g)\nvar_h = int(var_h)\nfor i in list_b:\n    i = int(i)\n    if (i//var_g)%10 == var_h:\n        list_c.append(i)\nvar_i = 2\nlist_d=list_c.copy()\nlist_d.sort()\nvar_j = list_d[-var_i]\nprint(int(var_j))",
        "solution_code_en": "var_a = 4\nvar_b = 3\nvar_c = 1\nvar_d = 7\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 10\nvar_h = 3\nlist_c = [] \nvar_g = int(var_g)\nvar_h = int(var_h)\nfor i in list_b:\n    i = int(i)\n    if (i//var_g)%10 == var_h:\n        list_c.append(i)\nvar_i = 2\nlist_d=list_c.copy()\nlist_d.sort()\nvar_j = list_d[-var_i]\nprint(int(var_j))"
    },
    "3958": {
        "category": "Geometry",
        "question_ko": "한 정육면체의 겉넓이는 150제곱센티미터(㎠)이다. 이 때, 정육면체의 모든 모서리 길이의 합은 얼마인지 구하시오.",
        "question_en": "The surface area of one cube is 150 square centimeters (cm2). In this case, find the sum of the lengths of all the edges of the cube.",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "150 6 [OP_DIV] 1/2 [OP_POW] 4 3 [OP_MUL] [OP_MUL]",
        "solution_abst_en": "150 6 [OP_DIV] 1/2 [OP_POW] 4 3 [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 150\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 4\nvar_g = 3\nvar_h = var_f * var_g\nvar_i = var_e * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 150\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 4\nvar_g = 3\nvar_h = var_f * var_g\nvar_i = var_e * var_h\nprint(int(var_i))"
    },
    "3959": {
        "category": "Comparison",
        "question_ko": "가, 나, 다, 라, 마 다섯 사람이 있다. 이들의 평균 용돈은 2300원이고, 가가와 나나의 평균은 3000원, 나나와 다다의 평균은 2100원, 다다와 라라의 평균은 2750원이다. 그리고 가가는 나나보다 800원 더 많이 받는다. 라라의 용돈을 얼마인가?",
        "question_en": "There are five people: A, B, C, D, E, and F. Their average pocket money is 2,300 won, the average of A and B is 3,000 won, the average of B and C is 2,100 won, and the average of C and D is 2,750 won. And A gets 800 won more than B. How much D's pocket money is?",
        "answer_ko": "3900",
        "answer_en": "3900",
        "solution_abst_ko": "2750 2 [OP_MUL] 2100 2 [OP_MUL] 3000 2 [OP_MUL] 800 [OP_SUB] 2 [OP_DIV] [OP_SUB] [OP_SUB]",
        "solution_abst_en": "2750 2 [OP_MUL] 2100 2 [OP_MUL] 3000 2 [OP_MUL] 800 [OP_SUB] 2 [OP_DIV] [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 2750\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 2100\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = 3000\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = 800\nvar_k = var_i - var_j\nvar_l = 2\nvar_m = var_k / var_l\nvar_n = var_f - var_m\nvar_o = var_c - var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 2750\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 2100\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = 3000\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = 800\nvar_k = var_i - var_j\nvar_l = 2\nvar_m = var_k / var_l\nvar_n = var_f - var_m\nvar_o = var_c - var_n\nprint(int(var_o))"
    },
    "3960": {
        "category": "Comparison",
        "question_ko": "승헌이네 집에서부터 도서관, 공원, 옷가게까지의 거리가 각각 1.912 킬로미터(㎞), 876 미터(m), 1.054 킬로미터(㎞) 입니다.집에서 두 번째로 가까운 곳은 어디인지 답을 구해 보세요.",
        "question_en": "The distances from Seungheon's house to the library, park, and clothing store are 1.912 kilometers (km), 876 meters (m), and 1.054 kilometers (km), respectively. Which is the second closest to the house?",
        "answer_ko": "옷가게",
        "answer_en": "clothing",
        "solution_abst_ko": "[OP_LIST_SOL] 도서관 공원 옷가게 [OP_LIST_EOL] [OP_LIST_SOL] 1.912 876 1000 [OP_DIV] 1.054 [OP_LIST_EOL] 2 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] library park clothing [OP_LIST_EOL] [OP_LIST_SOL] 1.912 876 1000 [OP_DIV] 1.054 [OP_LIST_EOL] 2 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '도서관'\nvar_b = '공원'\nvar_c = '옷가게'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1.912\nvar_e = 876\nvar_f = 1000\nvar_g = var_e / var_f\nvar_h = 1.054\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'library'\nvar_b = 'park'\nvar_c = 'clothing'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1.912\nvar_e = 876\nvar_f = 1000\nvar_g = var_e / var_f\nvar_h = 1.054\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "3961": {
        "category": "Arithmetic calculation",
        "question_ko": "6의 배수이면서 5의 배수이면서 8의 배수이면서 9의 배수인 수 중 가장 큰 세 자리 수는?",
        "question_en": "Which three-digit number is the largest multiple of 6 and multiple of 5 and multiple of 8 and multiple of 9?",
        "answer_ko": "720",
        "answer_en": "720",
        "solution_abst_ko": "100 999 1 [OP_LIST_ARANGE] 6 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_abst_en": "100 999 1 [OP_LIST_ARANGE] 6 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = 1\nlist_f=list_e.copy()\nlist_f.sort()\nvar_i = list_f[-var_h]\nprint(int(var_i))",
        "solution_code_en": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = 1\nlist_f=list_e.copy()\nlist_f.sort()\nvar_i = list_f[-var_h]\nprint(int(var_i))"
    },
    "3962": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 비커에 물을 120밀리리터(㎖) 크기의 물통에 가득 따랐더니 2통을 체우고 2.4밀리리터(㎖)가 남았다. 동일한 양의 물을 3개의 비커에 동일하게 나누어 담으면 몇 밀리리터(㎖)씩 담는지 구하시오.",
        "question_en": "When water in a beaker was poured into a 120 milliliter (ml) bucket, 2 buckets were filled and 2.4 milliliters (ml) remained in the beaker. Calculate how many milliliters (ml) each of the three beakers contains if the same amount of water is equally divided into three beakers.",
        "answer_ko": "80.80",
        "answer_en": "80.8",
        "solution_abst_ko": "120 2 [OP_MUL] 2.4 [OP_ADD] 3 [OP_DIV]",
        "solution_abst_en": "120 2 [OP_MUL] 2.4 [OP_ADD] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 120\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 2.4\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 120\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 2.4\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "3963": {
        "category": "Arithmetic calculation",
        "question_ko": "석진이는 국어 문제 12개를 푼 후에 7개를 더 풀었습니다. 석진이는 국어 문제를 모두 몇 개 풀었습니까?",
        "question_en": "Seokjin solved 12 Korean problems, and he solved 7 more afterwards. How many problems did he solve?",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "12 7 [OP_ADD]",
        "solution_abst_en": "12 7 [OP_ADD]",
        "solution_code_ko": "var_a = 12\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 12\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "3964": {
        "category": "Possibility",
        "question_ko": "0, 2, 4, 6, 8 중 서로 다른 2개의 숫자를 뽑아서 두 자리 수를 만들려고 합니다. 만들 수 있는 두 자리 수는 모두 몇 개입니까?",
        "question_en": "You want to form a two-digit number by picking two different numbers from 0, 2, 4, 6, and 8. How many two-digit numbers can you make?",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "[OP_LIST_SOL] 0 2 4 6 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 2 4 6 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 2\nvar_c = 4\nvar_d = 6\nvar_e = 8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 0\nvar_b = 2\nvar_c = 4\nvar_d = 6\nvar_e = 8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "3965": {
        "category": "Comparison",
        "question_ko": "5개의 숫자 5, 8, 1, 2, 6 중 가장 작은 숫자는 무엇입니까?",
        "question_en": "Which of the five numbers 5, 8, 1, 2, 6 is the smallest?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 5 8 1 2 6 [OP_LIST_EOL] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 5 8 1 2 6 [OP_LIST_EOL] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 5\nvar_b = 8\nvar_c = 1\nvar_d = 2\nvar_e = 6\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 8\nvar_c = 1\nvar_d = 2\nvar_e = 6\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nprint(int(var_g))"
    },
    "3966": {
        "category": "Geometry",
        "question_ko": "가로가 9.4센티미터(㎝), 세로가 3.7센티미터(㎝)인 직사각형 모양의 색 테이프를 가로 부분이 0.6센티미터(㎝)씩 겹치도록 15장을 이어 붙였습니다. 이어 붙인 색 테이프 전체의 넓이를 구하시오.",
        "question_en": "Fifteen pieces of rectangular colored tape, 9.4 cm (cm) wide and 3.7 cm (cm) long, overlap each other by 0.6 centimeters (cm). Find the total area of the entire colored tape joint together, excluding the overlapping area.",
        "answer_ko": "490.62",
        "answer_en": "490.62",
        "solution_abst_ko": "9.4 15 [OP_MUL] 15 1 [OP_SUB] 0.6 [OP_MUL] [OP_SUB] 3.7 [OP_MUL]",
        "solution_abst_en": "9.4 15 [OP_MUL] 15 1 [OP_SUB] 0.6 [OP_MUL] [OP_SUB] 3.7 [OP_MUL]",
        "solution_code_ko": "var_a = 9.4\nvar_b = 15\nvar_c = var_a * var_b\nvar_d = 15\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 0.6\nvar_h = var_f * var_g\nvar_i = var_c - var_h\nvar_j = 3.7\nvar_k = var_i * var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 9.4\nvar_b = 15\nvar_c = var_a * var_b\nvar_d = 15\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 0.6\nvar_h = var_f * var_g\nvar_i = var_c - var_h\nvar_j = 3.7\nvar_k = var_i * var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "3967": {
        "category": "Possibility",
        "question_ko": "숫자 카드 1, 6, 8를 한 번씩 모두 사용하여 세 번째 작은 세 자리 수를 구하시오.",
        "question_en": "Use the number cards 1, 6, and 8 all once to find the third small three-digit number.",
        "answer_ko": "618",
        "answer_en": "618",
        "solution_abst_ko": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 3 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 3 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nprint(int(var_f))"
    },
    "3968": {
        "category": "Geometry",
        "question_ko": "밑변과 높이의 합의 2배가 56인 평행사변형이 있습니다. 밑변이 16센티미터(㎝)이면, 평행사변형의 넓이는 얼마입니까?",
        "question_en": "There is a parallelogram whose 2 times the sum of its base and its height is 56. If the base is 16 centimeters (cm), what is the area of the parallelogram?",
        "answer_ko": "192",
        "answer_en": "192",
        "solution_abst_ko": "56 2 [OP_DIV] 16 [OP_SUB] 16 [OP_MUL]",
        "solution_abst_en": "56 2 [OP_DIV] 16 [OP_SUB] 16 [OP_MUL]",
        "solution_code_ko": "var_a = 56\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 16\nvar_e = var_c - var_d\nvar_f = 16\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 56\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 16\nvar_e = var_c - var_d\nvar_f = 16\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "3969": {
        "category": "Arithmetic calculation",
        "question_ko": "운동장을 한 바퀴 뛸 때 처음에는 시속 15킬로미터(㎞)로 달렸고, 두 번째에는 시속 10킬로미터(㎞)로 달렸더니 처음보다 30분이 더 걸렸다. 두 번째에 운동장을 돈 시간을 구하시오.",
        "question_en": "When I ran one lap around the playground, I ran at 15 kilometers (km) per hour the first time, and ran at 10 kilometers (km) per hour the second time, which took 30 minutes longer than the first time. Find the time to run the playground for the second time.",
        "answer_ko": "1.50",
        "answer_en": "1.5",
        "solution_abst_ko": "10 30 60 [OP_DIV] [OP_MUL] 15 10 [OP_SUB] [OP_DIV] 30 60 [OP_DIV] [OP_ADD]",
        "solution_abst_en": "10 30 60 [OP_DIV] [OP_MUL] 15 10 [OP_SUB] [OP_DIV] 30 60 [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 30\nvar_c = 60\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 15\nvar_g = 10\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 30\nvar_k = 60\nvar_l = var_j / var_k\nvar_m = var_i + var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))",
        "solution_code_en": "var_a = 10\nvar_b = 30\nvar_c = 60\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 15\nvar_g = 10\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 30\nvar_k = 60\nvar_l = var_j / var_k\nvar_m = var_i + var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))"
    },
    "3970": {
        "category": "Arithmetic calculation",
        "question_ko": "큰 통에는 10리터(L)의 주스가 들어 있고 작은 통에는 8리터(L)의 주스가 들어 있었습니다. 작은 통에 들어 있던 주스 3리터(L)를 큰 통에 따랐을 때 큰 통의 주스는 작은 통의 주스보다 몇 리터(L) 더 많습니까?",
        "question_en": "The large barrel contained 10 liters (L) of juice and the small barrel contained 8 liters (L) of juice. When 3 liters (L) of juice from the small barrel is poured into a large barrel, how many more liters (L) of juice is in the large barrel than the juice in the small barrel?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "10 3 [OP_ADD] 8 3 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "10 3 [OP_ADD] 8 3 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 8\nvar_e = 3\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 10\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 8\nvar_e = 3\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "3971": {
        "category": "Geometry",
        "question_ko": "가로가 1120센티미터(㎝), 세로가 630센티미터(㎝)인 직사각형 모양의 대리석을 잘라 마룻바닥을 덮는 데 사용하려고 합니다. 대리석을 한 변의 길이가 70센티미터(㎝)인 정사각형 모양으로 자른다면, 몇 개까지 만들 수 있습니까?",
        "question_en": "A rectangular marble measuring 1120 centimeters (cm) by 630 centimeters (cm) will be cut and used to cover the floor. If you cut marble into squares with sides measuring 70 centimeters (cm), how many can you make?",
        "answer_ko": "144",
        "answer_en": "144",
        "solution_abst_ko": "1120 70 [OP_FDIV] 630 70 [OP_FDIV] [OP_MUL]",
        "solution_abst_en": "1120 70 [OP_FDIV] 630 70 [OP_FDIV] [OP_MUL]",
        "solution_code_ko": "var_a = 1120\nvar_b = 70\nvar_c = var_a // var_b\nvar_d = 630\nvar_e = 70\nvar_f = var_d // var_e\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1120\nvar_b = 70\nvar_c = var_a // var_b\nvar_d = 630\nvar_e = 70\nvar_f = var_d // var_e\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "3972": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 물통에 물이 가득 들어있습니다. 이 물통에서 250밀리리터(㎖) 들이의 컵으로 물을 가득 담아 20번 퍼낸 후, 600밀리리터(㎖) 들이의 컵으로 물을 가득 담아 13번 퍼내었더니 물통이 완전히 비워졌습니다. 이 물통의 들이는 몇 리터(L)입니까?",
        "question_en": "A water bottle is full of water. After scooping out the water 20 times with a 250 milliliter (㎖) cup and 13 times with a 600 milliliter (㎖) cup from this water bottle, the water bottle became completely empty. How many liters (L) does this water bottle hold?",
        "answer_ko": "12.80",
        "answer_en": "12.8",
        "solution_abst_ko": "250 20 [OP_MUL] 600 13 [OP_MUL] [OP_ADD] 1000 [OP_DIV]",
        "solution_abst_en": "250 20 [OP_MUL] 600 13 [OP_MUL] [OP_ADD] 1000 [OP_DIV]",
        "solution_code_ko": "var_a = 250\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 600\nvar_e = 13\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 1000\nvar_i = var_g / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 250\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 600\nvar_e = 13\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 1000\nvar_i = var_g / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "3973": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.3 중 0.4보다 작은 수의 개수를 구하시오.",
        "question_en": "Find how many numbers among 0.8, 1/2, 0.3 are less than 0.4.",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.3 [OP_LIST_EOL] 0.4 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.3 [OP_LIST_EOL] 0.4 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.4\nlist_b = []\nfor i in list_a:\n    if i < var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.4\nlist_b = []\nfor i in list_a:\n    if i < var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "3974": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 11을 곱한 후 6을 더하고, 그 값을 5로 나눈 후 42를 뺀 값이 12입니다. 어떤 수를 구하시오.",
        "question_en": "Multiply a number by 11, add 6, divide that number by 5, then subtract 42 and the result is 12. Find the number.",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "12 42 [OP_ADD] 5 [OP_MUL] 6 [OP_SUB] 11 [OP_DIV]",
        "solution_abst_en": "12 42 [OP_ADD] 5 [OP_MUL] 6 [OP_SUB] 11 [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 42\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c * var_d\nvar_f = 6\nvar_g = var_e - var_f\nvar_h = 11\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 12\nvar_b = 42\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c * var_d\nvar_f = 6\nvar_g = var_e - var_f\nvar_h = 11\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "3975": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.9, 1/3 중에서 0.4보다 작거나 같은 수를 모두 더하면 얼마일까요?",
        "question_en": "What is the sum of all numbers less than or equal to 0.4 among 0.8, 1/2, 0.9, and 1/3?",
        "answer_ko": "0.33",
        "answer_en": "0.33",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_LESS_EQUAL] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_LESS_EQUAL] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.4\nlist_b = []\nfor i in list_a:\n    if i <= var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint('{:.2f}'.format(round(var_f+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.4\nlist_b = []\nfor i in list_a:\n    if i <= var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint('{:.2f}'.format(round(var_f+1e-10,2)))"
    },
    "3976": {
        "category": "Arithmetic calculation",
        "question_ko": "32의 약수의 개수를 구하시오.",
        "question_en": "Find the number of divisors of 32.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "32 [OP_LIST_GET_DIVISOR] [OP_LIST_LEN]",
        "solution_abst_en": "32 [OP_LIST_GET_DIVISOR] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 32\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = len(list_a)\nprint(int(var_b))",
        "solution_code_en": "var_a = 32\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = len(list_a)\nprint(int(var_b))"
    },
    "3977": {
        "category": "Arithmetic calculation",
        "question_ko": "국어, 수학의 평균 점수가 86점이다. 영어가 98점일때 세과목의 평균 점수를 구하여라",
        "question_en": "The average score for Korean and mathematics is 86 points. Find the average score of the three subjects when English is 98 points.",
        "answer_ko": "90",
        "answer_en": "90",
        "solution_abst_ko": "86 2 [OP_MUL] 98 [OP_ADD] 3 [OP_DIV]",
        "solution_abst_en": "86 2 [OP_MUL] 98 [OP_ADD] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 86\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 98\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 86\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 98\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "3978": {
        "category": "Geometry",
        "question_ko": "가로가 20 센티미터(㎝), 세로가 8 센티미터(㎝)인 직사각형 모양의 카드를 겹치지 않게 늘어놓아 최대한 작은 정사각형을 만들려고 합니다. 카드는 모두 몇 장 필요할까요?",
        "question_en": "Try to make a square as small as possible by arranging rectangular cards with a width of 20 centimeters (cm) and a length of 8 centimeters (cm) without overlapping. How many cards will you need in total?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "20 8 [OP_LCM] 2 [OP_POW] 20 8 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "20 8 [OP_LCM] 2 [OP_POW] 20 8 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 20\nvar_b = 8\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 20\nvar_g = 8\nvar_h = var_f * var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 20\nvar_b = 8\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 20\nvar_g = 8\nvar_h = var_f * var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "3979": {
        "category": "Comparison",
        "question_ko": "총 4개의 숫자 0.8, 1/2, 0.5, 1/3이 있습니다. 이 중 3보다 작은 수를 모두 더하면 얼마인가요?",
        "question_en": "There are a total of 4 numbers: 0.8, 1/2, 0.5 and 1/3. What is the sum of all given numbers less than 3?",
        "answer_ko": "2.13",
        "answer_en": "2.13",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.5 1/3 [OP_LIST_EOL] 3 [OP_LIST_LESS] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.5 1/3 [OP_LIST_EOL] 3 [OP_LIST_LESS] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.5\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = []\nfor i in list_a:\n    if i < var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint('{:.2f}'.format(round(var_f+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.5\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = []\nfor i in list_a:\n    if i < var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint('{:.2f}'.format(round(var_f+1e-10,2)))"
    },
    "3980": {
        "category": "Comparison",
        "question_ko": "윤기가 가진 사과가 4개, 정국이는 6개의 사과의 사과를 가지고 있었지만 3개를 먹었습니다. 누가 더 적은 사과를 가지고 있나요?",
        "question_en": "Yoongi has 4 apples and Jungkook had 6 apples, but he has eaten 3. Who has fewer apples?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 6\nvar_e = 3\nvar_f = var_d - var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 6\nvar_e = 3\nvar_f = var_d - var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "3981": {
        "category": "Possibility",
        "question_ko": "숫자 카드 1, 6, 8를 한 번씩 모두 사용하여 두 번째로 큰 세 자리 수와 세 번째로 큰 세 자리수의 차를 구하시오.",
        "question_en": "Using number cards 1, 6, and 8 all once, find the difference between the second largest three-digit number and the third largest three-digit number.",
        "answer_ko": "198",
        "answer_en": "198",
        "solution_abst_ko": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 3 [OP_LIST_GET] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 3 [OP_LIST_GET] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 3\nvar_h = list_b[var_g-1]\nvar_i = var_f - var_h\nvar_j = abs(var_i)\nprint(int(var_j))",
        "solution_code_en": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 3\nvar_h = list_b[var_g-1]\nvar_i = var_f - var_h\nvar_j = abs(var_i)\nprint(int(var_j))"
    },
    "3982": {
        "category": "Geometry",
        "question_ko": "가로가 120센티미터(㎝), 세로가 96센티미터(㎝)인 직사각형 모양의 칠판에 학생들이 그린 정사각형 모양의 그림을 남는 부분 없이 붙일 때, 그림의 크기가 최대가 되려면 한 변의 길이는 몇 센티미터(㎝)가 되어야 하는지 구하시오.",
        "question_en": "When attaching a square picture drawn by students to a rectangular blackboard 120 centimeters (cm) wide and 96 centimeters (cm) long without any remaining parts, find how many centimeters (cm) long a side should be to maximize the size of the picture.",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "120 96 [OP_GCD]",
        "solution_abst_en": "120 96 [OP_GCD]",
        "solution_code_ko": "var_a = 120\nvar_b = 96\nvar_c = math.gcd(int(var_b), int(var_a))\nprint(int(var_c))",
        "solution_code_en": "var_a = 120\nvar_b = 96\nvar_c = math.gcd(int(var_b), int(var_a))\nprint(int(var_c))"
    },
    "3983": {
        "category": "Geometry",
        "question_ko": "삼각형의 세 각 중 두 각의 크기는 각각 30도, 60도였습니다. 이 삼각형의 나머지 한 각의 크기는 몇 도입니까?",
        "question_en": "Two of the triangle's three angles measure 30 degrees and 60 degrees, respectively. What is the measure of the other angle of this triangle in degrees?",
        "answer_ko": "90",
        "answer_en": "90",
        "solution_abst_ko": "180 30 [OP_SUB] 60 [OP_SUB]",
        "solution_abst_en": "180 30 [OP_SUB] 60 [OP_SUB]",
        "solution_code_ko": "var_a = 180\nvar_b = 30\nvar_c = var_a - var_b\nvar_d = 60\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 180\nvar_b = 30\nvar_c = var_a - var_b\nvar_d = 60\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "3984": {
        "category": "Arithmetic calculation",
        "question_ko": "숫자 6, 8, 11의 합은 얼마입니까?",
        "question_en": "What is the sum of the numbers 6, 8 and 11?",
        "answer_ko": "25",
        "answer_en": "25",
        "solution_abst_ko": "6 8 [OP_ADD] 11 [OP_ADD]",
        "solution_abst_en": "6 8 [OP_ADD] 11 [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 11\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 11\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "3985": {
        "category": "Arithmetic calculation",
        "question_ko": "네 개의 수 75, 91, 83, 72 중 가장 큰 수와 2번째로 작은 수를 더한 값을 구하시오.",
        "question_en": "Find the sum of the largest number and the second smallest number among 75, 91, 83, and 72.",
        "answer_ko": "166",
        "answer_en": "166",
        "solution_abst_ko": "[OP_LIST_SOL] 75 91 83 72 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 75 91 83 72 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 75\nvar_b = 91\nvar_c = 83\nvar_d = 72\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 75\nvar_b = 91\nvar_c = 83\nvar_d = 72\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))"
    },
    "3986": {
        "category": "Geometry",
        "question_ko": "둘레의 길이가 16 센티미터(㎝)이고, 세로의 길이가 가로의 길이보다 2 센티미터(㎝)만큼 짧은 직사각형의 가로의 길이와 세로의 길이를 구하려고 한다. 가로의 길이는 얼마인가?",
        "question_en": "You want to find the length and width of a rectangle whose perimeter is 16 centimeters (cm) and whose length is shorter than its width by 2 centimeters (cm). What is the horizontal length?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "16 2 [OP_DIV] 2 [OP_SUB] 2 [OP_DIV] 2 [OP_ADD]",
        "solution_abst_en": "16 2 [OP_DIV] 2 [OP_SUB] 2 [OP_DIV] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 16\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 16\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "3987": {
        "category": "Comparison",
        "question_ko": "유나는 교실에서 5번째로 연필이 많고, 은지의 바로 다음으로 연필이 많습니다. 은지는 몇 번째로 연필이 많습니까?",
        "question_en": "Yuna has the 5th most pencils in her class, right after Eunji. What order does Eunji in when it comes to having the most pencils?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "5 1 [OP_SUB]",
        "solution_abst_en": "5 1 [OP_SUB]",
        "solution_code_ko": "var_a = 5\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "3988": {
        "category": "Geometry",
        "question_ko": "두 밑 면이 합동이고 평행한 어떤 각기둥의 모서리가 21개일 때, 꼭짓점의 개수는 몇 개인지 구하시오.",
        "question_en": "If a prism with two congruent and parallel bases has 21 edges, find the number of vertices.",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "21 3 [OP_DIV] 2 [OP_MUL]",
        "solution_abst_en": "21 3 [OP_DIV] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 21\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 21\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "3989": {
        "category": "Possibility",
        "question_ko": "학교에서 도서관까지 가는 경우의 수가 2가지, 도서관에서 집까지 가는 경우의 수가 3가지이다. 학교에서 도서관을 거쳐 집으로 가는 경우의 수를 구하시오.",
        "question_en": "The number of ways going from school to the library is 2, and the number of ways going from the library to home is 3. Find the number of ways to go home from school via the library.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "2 3 [OP_MUL]",
        "solution_abst_en": "2 3 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "3990": {
        "category": "Comparison",
        "question_ko": "정국이는 6 곱하기 3만큼의 사과를 모았고, 윤기는 4개의 사과를 모았습니다. 누가 더 사과를 많이 가지고 있습니까?",
        "question_en": "Jungkook collected 6 times 3 apples, and Yoongi collected 4 apples. Who has more apples?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 윤기 [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_MUL] 4 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Yoongi [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_MUL] 4 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '윤기'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 3\nvar_e = var_c * var_d\nvar_f = 4\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Yoongi'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 3\nvar_e = var_c * var_d\nvar_f = 4\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "3991": {
        "category": "Geometry",
        "question_ko": "미진이는 한 모서리의 길이가 2센티미터(㎝)인 정육면체 모양의 상자를 가지고 한 모서리의 길이가 10센티미터(㎝)인 정육면체 상자를 만들었습니다. 만들어진 정육면체 모양의 상자의 모든 면에 노란색 색종이를 붙였습니다. 1개의 면에 노란색 색종이가 붙은 작은 정육면체 상자는 모두 몇 개입니까?",
        "question_en": "Mijin took a cube-shaped box with one edge 2 centimeters (cm) long and made a cube box with one edge 10 centimeters (cm) long. yellow colored paper was attached to all sides of the cube-shaped box that was created. How many small cube boxes with yellow confetti on one side?",
        "answer_ko": "54",
        "answer_en": "54",
        "solution_abst_ko": "10 2 [OP_DIV] 2 [OP_SUB] 2 [OP_POW] 6 [OP_MUL]",
        "solution_abst_en": "10 2 [OP_DIV] 2 [OP_SUB] 2 [OP_POW] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e ** var_f\nvar_h = 6\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e ** var_f\nvar_h = 6\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "3992": {
        "category": "Correspondence",
        "question_ko": "1A+4B3=469일 때, A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "When 1A+4B3=469 is true, what number should go in A?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "1A+4B3=469 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "1A+4B3=469 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '1A+4B3=469'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '1A+4B3=469'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "3993": {
        "category": "Arithmetic calculation",
        "question_ko": "민준이는 추석 때 외가에 먼저 들린 후 친가에 가기로 했습니다. 민준이네 집에서 외가까지는 10킬로미터(㎞) 700미터(m)이고, 외가에서 친가까지의 거리는 24킬로미터(㎞) 900미터(m)입니다. 민준이가 외가를 거쳐 친가까지 가는 거리의 중간 지점은 집에서부터 몇 미터(m)인지 구하시오.",
        "question_en": "During Chuseok, Minjun decided to stop by his mother's house first and then go to his father's side. It takes 10 kilometers (km) and 700 meters (m) from Minjun's house to his mother's house, and the distance from the mother's side to the father's side is 24 kilometers (km) and 900 meters (m). Find the distance between Minjun's house and the midpoint of the way from his mother's to his father's house in meters (m).",
        "answer_ko": "12450",
        "answer_en": "12450",
        "solution_abst_ko": "10 1000 [OP_MUL] 700 [OP_ADD] 24 1000 [OP_MUL] 900 [OP_ADD] 2 [OP_DIV]",
        "solution_abst_en": "10 1000 [OP_MUL] 700 [OP_ADD] 24 1000 [OP_MUL] 900 [OP_ADD] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 700\nvar_e = var_c + var_d\nvar_f = 24\nvar_g = 1000\nvar_h = var_f * var_g\nvar_i = 900\nvar_j = var_h + var_i\nvar_k = 2\nvar_l = var_j / var_k\nprint(int(var_l))",
        "solution_code_en": "var_a = 10\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 700\nvar_e = var_c + var_d\nvar_f = 24\nvar_g = 1000\nvar_h = var_f * var_g\nvar_i = 900\nvar_j = var_h + var_i\nvar_k = 2\nvar_l = var_j / var_k\nprint(int(var_l))"
    },
    "3994": {
        "category": "Arithmetic calculation",
        "question_ko": "(가) 동물과 (나) 동물을 합하면 17마리입니다. 그중에서 (나) 동물이 8마리라면 (가) 동물은 몇 마리입니까?",
        "question_en": "If animal (A) and animal (B) are added together, there are 17 animals. If there are 8 (B)s, how many (A)s are there?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "17 8 [OP_SUB]",
        "solution_abst_en": "17 8 [OP_SUB]",
        "solution_code_ko": "var_a = 17\nvar_b = 8\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 17\nvar_b = 8\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "3995": {
        "category": "Possibility",
        "question_ko": "8개의 팀이 농구 경기를 합니다. 두팀이 시합을 하여 진 팀은 떨어지고 이긴팀만 다음 경기를 진행합니다. 마지막에 이긴 팀이 우승을 할때 경기는 총 몇번 진행됩니까?",
        "question_en": "Eight teams will play basketball. The two teams play, the losing team is eliminated and the winning team advances to the next game. How many matches are played when the last team to win wins?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "8 2 [OP_DIV] 8 2 [OP_DIV] 2 [OP_DIV] 8 2 [OP_DIV] 2 [OP_DIV] 2 [OP_DIV] [OP_ADD] [OP_ADD]",
        "solution_abst_en": "8 2 [OP_DIV] 8 2 [OP_DIV] 2 [OP_DIV] 8 2 [OP_DIV] 2 [OP_DIV] 2 [OP_DIV] [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 8\nvar_e = 2\nvar_f = var_d / var_e\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = 8\nvar_j = 2\nvar_k = var_i / var_j\nvar_l = 2\nvar_m = var_k / var_l\nvar_n = 2\nvar_o = var_m / var_n\nvar_p = var_h + var_o\nvar_q = var_c + var_p\nprint(int(var_q))",
        "solution_code_en": "var_a = 8\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 8\nvar_e = 2\nvar_f = var_d / var_e\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = 8\nvar_j = 2\nvar_k = var_i / var_j\nvar_l = 2\nvar_m = var_k / var_l\nvar_n = 2\nvar_o = var_m / var_n\nvar_p = var_h + var_o\nvar_q = var_c + var_p\nprint(int(var_q))"
    },
    "3996": {
        "category": "Correspondence",
        "question_ko": "등식 68A-3=684이 성립한다고 합니다. A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "The equation 68A-3=684 holds. What number should be in A?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "68A-3=684 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "68A-3=684 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '68A-3=684'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '68A-3=684'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "3997": {
        "category": "Possibility",
        "question_ko": "5, 9, 2 중에서 한 번씩만 사용하여 세 자리 수를 만들려고 합니다. 만든 두 수의 차가 가장 크게 될 때, 두 수 중 큰 수는 무엇입니까?",
        "question_en": "You are going to create a three-digit number using only once of 5, 9, and 2. Which of the two numbers is greater when the difference between the two numbers made is greatest?",
        "answer_ko": "952",
        "answer_en": "952",
        "solution_abst_ko": "[OP_LIST_SOL] 5 9 2 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 5 9 2 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 5\nvar_b = 9\nvar_c = 2\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))",
        "solution_code_en": "var_a = 5\nvar_b = 9\nvar_c = 2\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))"
    },
    "3998": {
        "category": "Geometry",
        "question_ko": "지름이 100 미터(m) 인 원 모양의 호수의 둘레는 314 미터(m) 였습니다. 이 호수의 둘레는 지름의 몇 배 인가요?",
        "question_en": "A circular lake with a diameter of 100 meters (m) had a circumference of 314 meters (m). How many times bigger is the circumference of this lake compared to its diameter?",
        "answer_ko": "3.14",
        "answer_en": "3.14",
        "solution_abst_ko": "314 100 [OP_DIV]",
        "solution_abst_en": "314 100 [OP_DIV]",
        "solution_code_ko": "var_a = 314\nvar_b = 100\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 314\nvar_b = 100\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "3999": {
        "category": "Possibility",
        "question_ko": "선생님이 학생에게 1, 0, 5, 7을 모두 사용해서 네 자리 수를 만들어 보라고 시켰습니다. 학생이 말할 수 있는 정답은 모두 몇 가지 입니까?",
        "question_en": "The teacher asks the students to create a four-digit number using all 1, 0, 5, and 7. How many answers can the student give?",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "[OP_LIST_SOL] 1 0 7 5 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 0 7 5 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 0\nvar_c = 7\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 0\nvar_c = 7\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "4000": {
        "category": "Arithmetic calculation",
        "question_ko": "딸기가 1.6킬로그램(㎏) 있었습니다. 딸기를 어제는 0.8킬로그램(㎏)을 먹고 오늘은 0.3킬로그램(㎏)을 먹었습니다. 남은 딸기는 몇 킬로그램(㎏) 입니까?",
        "question_en": "There were 1.6 kg (kg) of strawberries. I ate 0.8 kg (kg) of strawberries yesterday and 0.3 kg (kg) today. How many kilograms (kg) of strawberries are left?",
        "answer_ko": "0.50",
        "answer_en": "0.5",
        "solution_abst_ko": "1.6 0.8 [OP_SUB] 0.3 [OP_SUB]",
        "solution_abst_en": "1.6 0.8 [OP_SUB] 0.3 [OP_SUB]",
        "solution_code_ko": "var_a = 1.6\nvar_b = 0.8\nvar_c = var_a - var_b\nvar_d = 0.3\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 1.6\nvar_b = 0.8\nvar_c = var_a - var_b\nvar_d = 0.3\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "4001": {
        "category": "Geometry",
        "question_ko": "가로의 길이를 세로의 길이로 나눈 값이 0.875인 직사각형이 있습니다. 이 직사각형의 세로의 길이가 24센티미터(㎝)일 때 넓이를 구하시오.",
        "question_en": "A rectangle whose width divided by its height equals 0.875. Find the area of this rectangle when its height is 24 centimeters (cm).",
        "answer_ko": "504",
        "answer_en": "504",
        "solution_abst_ko": "24 0.875 [OP_MUL] 24 [OP_MUL]",
        "solution_abst_en": "24 0.875 [OP_MUL] 24 [OP_MUL]",
        "solution_code_ko": "var_a = 24\nvar_b = 0.875\nvar_c = var_a * var_b\nvar_d = 24\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 24\nvar_b = 0.875\nvar_c = var_a * var_b\nvar_d = 24\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "4002": {
        "category": "Geometry",
        "question_ko": "가로가 36센티미터(㎝)이고 세로가 64 센티미터(㎝)인 직사각형의 네 변의 길이의 합과 네 변의 길이의 합이 같은 정사각형이 있습니다. 이 정사각형의 한 변의 길이는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "There is a rectangle with a width of 36 centimeters (cm) and a length of 64 centimeters (cm) and a square whose sum of four sides is equal to the sum of a rectangle's four sides. Find how many centimeters (cm) the length of one side of this square is.",
        "answer_ko": "50",
        "answer_en": "50",
        "solution_abst_ko": "36 64 [OP_ADD] 2 [OP_MUL] 4 [OP_DIV]",
        "solution_abst_en": "36 64 [OP_ADD] 2 [OP_MUL] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 36\nvar_b = 64\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 36\nvar_b = 64\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "4003": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 도시의 택시 요금이 3킬로미터(㎞)까지는 2400원이고, 3킬로미터(㎞)를 초과하면 200미터(m)에 300원씩 추가된다고 합니다. 한 손님이 4킬로미터(㎞)를 타고 갔을 때, 요금은 얼마를 내야 합니까?",
        "question_en": "It is said that the taxi fare in a city is 2,400 won for up to 3 kilometers (km), and 300 won is added for every 200 meters (km) beyond 3 kilometers (km). When a customer rides 4 kilometers (km), how much does he have to pay?",
        "answer_ko": "3900",
        "answer_en": "3900",
        "solution_abst_ko": "2400 4 3 [OP_SUB] 1000 [OP_MUL] 200 [OP_DIV] 300 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "2400 4 3 [OP_SUB] 1000 [OP_MUL] 200 [OP_DIV] 300 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 2400\nvar_b = 4\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = 200\nvar_h = var_f / var_g\nvar_i = 300\nvar_j = var_h * var_i\nvar_k = var_a + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 2400\nvar_b = 4\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = 200\nvar_h = var_f / var_g\nvar_i = 300\nvar_j = var_h * var_i\nvar_k = var_a + var_j\nprint(int(var_k))"
    },
    "4004": {
        "category": "Arithmetic calculation",
        "question_ko": "6의 배수도 되고 15의 배수도 되는 수 중에서 200보다 작은 수는 모두 몇 개입니까?",
        "question_en": "How many numbers that are both multiples of 6 and 15 are less than 200?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "1 200 1 [OP_LIST_ARANGE] 6 [OP_LIST_DIVISIBLE] 15 [OP_LIST_DIVISIBLE] 200 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "1 200 1 [OP_LIST_ARANGE] 6 [OP_LIST_DIVISIBLE] 15 [OP_LIST_DIVISIBLE] 200 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 200\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 15\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 200\nlist_d = []\nfor i in list_c:\n    if i < var_f:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 200\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 15\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 200\nlist_d = []\nfor i in list_c:\n    if i < var_f:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))"
    },
    "4005": {
        "category": "Geometry",
        "question_ko": "어떤 원의 넓이는 반지름이 2인 원 4개의 넓이의 합과 같다. 원의 반지름을 구하시오.",
        "question_en": "The area of a circle is equal to the sum of the areas of 4 circles of radius 2cm (cm). Find the radius of the circle.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "4 2 2 [OP_POW] [OP_MUL] 1/2 [OP_POW]",
        "solution_abst_en": "4 2 2 [OP_POW] [OP_MUL] 1/2 [OP_POW]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = 2\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 0.5\nvar_g = var_e ** var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = 2\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 0.5\nvar_g = var_e ** var_f\nprint(int(var_g))"
    },
    "4006": {
        "category": "Arithmetic calculation",
        "question_ko": "1000그램(g)의 빵중 보미가 350그램(g)먹고 예준이 500그램(g)을 먹었다면 남은 빵은 몇 그램(g)입니까?",
        "question_en": "Out of 1000 grams (g) of bread, if Bomi ate 350 grams (g) and Yejun ate 500 grams (g), how many grams (g) of bread are left?",
        "answer_ko": "150",
        "answer_en": "150",
        "solution_abst_ko": "1000 350 [OP_SUB] 500 [OP_SUB]",
        "solution_abst_en": "1000 350 [OP_SUB] 500 [OP_SUB]",
        "solution_code_ko": "var_a = 1000\nvar_b = 350\nvar_c = var_a - var_b\nvar_d = 500\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 1000\nvar_b = 350\nvar_c = var_a - var_b\nvar_d = 500\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "4007": {
        "category": "Comparison",
        "question_ko": "정국이는 지우개를 6개 가지고 있습니다. 지민이는 지우개를 정국이보다 4개 더 많이 가지고 있고 석진이는 지민이보다 3개 더 적게 가지고 있습니다. 지우개를 가장 적게 가지고 있는 사람은 누구입니까?",
        "question_en": "Jungkook has 6 erasers. Jimin has 4 more erasers than Jungkook and Seokjin has 3 fewer than Jimin. Who has the fewest erasers?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 지민 석진 [OP_LIST_EOL] [OP_LIST_SOL] 6 6 4 [OP_ADD] 6 4 [OP_ADD] 3 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Jimin Seokjin [OP_LIST_EOL] [OP_LIST_SOL] 6 6 4 [OP_ADD] 6 4 [OP_ADD] 3 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '지민'\nvar_c = '석진'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 6\nvar_e = 6\nvar_f = 4\nvar_g = var_e + var_f\nvar_h = 6\nvar_i = 4\nvar_j = var_h + var_i\nvar_k = 3\nvar_l = var_j - var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[var_m-1]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Jimin'\nvar_c = 'Seokjin'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 6\nvar_e = 6\nvar_f = 4\nvar_g = var_e + var_f\nvar_h = 6\nvar_i = 4\nvar_j = var_h + var_i\nvar_k = 3\nvar_l = var_j - var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[var_m-1]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "4008": {
        "category": "Geometry",
        "question_ko": "예쁜 담요가 있다. 담요의 모양은 정십사각형이다. 모든 모서리의 길이는 154센티미터(㎝)이다. 담요의 한 모서리 길이를 구하시오.",
        "question_en": "There are pretty blankets whose shape is the same as a regular tetradecagon. When the length of all corners is 154 centimeters (cm). Find the length of one edge of the blanket.",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "154 14 [OP_DIV]",
        "solution_abst_en": "154 14 [OP_DIV]",
        "solution_code_ko": "var_a = 154\nvar_b = 14\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 154\nvar_b = 14\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "4009": {
        "category": "Correspondence",
        "question_ko": "세 자리 수인 A63을 7로 나눈 몫은 세 자리 수입니다. A에 쓸 수 있는 숫자는 모두 몇 개입니까?",
        "question_en": "The quotient of the three-digit number A63 divided by 7 is a three-digit number. Find the number of possible A.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "A63 [OP_GEN_POSSIBLE_LIST] 700 [OP_LIST_MORE_EQUAL] 7000 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "A63 [OP_GEN_POSSIBLE_LIST] 700 [OP_LIST_MORE_EQUAL] 7000 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 'A63'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 700\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 7000\nlist_c = []\nfor i in list_b:\n    if i < var_c:\n        list_c.append(i)\nvar_d = len(list_c)\nprint(int(var_d))",
        "solution_code_en": "var_a = 'A63'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 700\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 7000\nlist_c = []\nfor i in list_b:\n    if i < var_c:\n        list_c.append(i)\nvar_d = len(list_c)\nprint(int(var_d))"
    },
    "4010": {
        "category": "Arithmetic calculation",
        "question_ko": "3으로 나누었을 때의 나머지와 5로 나누었을 때의 나머지가 1로 같은 자연수 중 1을 제외하고 가장 작은 수는 얼마입니까?",
        "question_en": "What is the smallest natural number excluding 1 that has the same remainder of 1 when divided by 3 and 5?",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "0 9999 1 [OP_LIST_ARANGE] 3 1 [OP_LIST_DIVIDE_AND_REMAIN] 5 1 [OP_LIST_DIVIDE_AND_REMAIN] 2 [OP_LIST_MIN]",
        "solution_abst_en": "0 9999 1 [OP_LIST_ARANGE] 3 1 [OP_LIST_DIVIDE_AND_REMAIN] 5 1 [OP_LIST_DIVIDE_AND_REMAIN] 2 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 0\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nvar_e = 1\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 5\nvar_g = 1\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 2\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nprint(int(var_i))",
        "solution_code_en": "var_a = 0\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nvar_e = 1\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 5\nvar_g = 1\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 2\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nprint(int(var_i))"
    },
    "4011": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 2, 3, 5, 9, 11로 나누어떨어질 수 있는 4000보다 작은 네 자리 수는 모두 몇 개 있습니까?",
        "question_en": "How many four-digit numbers less than 4000 are divisible by the five numbers of 2, 3, 5, 9, and 11?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "1000 4000 1 [OP_SUB] 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] 11 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "1000 4000 1 [OP_SUB] 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] 11 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1000\nvar_b = 4000\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nvar_f = 2\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nvar_g = 3\nlist_c = []\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if i % var_g == 0:\n        list_c.append(i)\nvar_h = 5\nlist_d = []\nvar_h = int(var_h)\nfor i in list_c:\n    i = int(i)\n    if i % var_h == 0:\n        list_d.append(i)\nvar_i = 5\nlist_e = []\nvar_i = int(var_i)\nfor i in list_d:\n    i = int(i)\n    if i % var_i == 0:\n        list_e.append(i)\nvar_j = 9\nlist_f = []\nvar_j = int(var_j)\nfor i in list_e:\n    i = int(i)\n    if i % var_j == 0:\n        list_f.append(i)\nvar_k = 11\nlist_g = []\nvar_k = int(var_k)\nfor i in list_f:\n    i = int(i)\n    if i % var_k == 0:\n        list_g.append(i)\nvar_l = len(list_g)\nprint(int(var_l))",
        "solution_code_en": "var_a = 1000\nvar_b = 4000\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nvar_f = 2\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nvar_g = 3\nlist_c = []\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if i % var_g == 0:\n        list_c.append(i)\nvar_h = 5\nlist_d = []\nvar_h = int(var_h)\nfor i in list_c:\n    i = int(i)\n    if i % var_h == 0:\n        list_d.append(i)\nvar_i = 5\nlist_e = []\nvar_i = int(var_i)\nfor i in list_d:\n    i = int(i)\n    if i % var_i == 0:\n        list_e.append(i)\nvar_j = 9\nlist_f = []\nvar_j = int(var_j)\nfor i in list_e:\n    i = int(i)\n    if i % var_j == 0:\n        list_f.append(i)\nvar_k = 11\nlist_g = []\nvar_k = int(var_k)\nfor i in list_f:\n    i = int(i)\n    if i % var_k == 0:\n        list_g.append(i)\nvar_l = len(list_g)\nprint(int(var_l))"
    },
    "4012": {
        "category": "Comparison",
        "question_ko": "1.4, 9/10, 1.2, 0.5, 13/10 5개 숫자 중에서 1.1보다 큰 숫자는 모두 몇 개입니까?",
        "question_en": "Among 1.4, 9/10, 1.2, 0.5, and 13/10, how many of these 5 numbers are greater than 1.1?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "4013": {
        "category": "Comparison",
        "question_ko": "재웅, 성민, 은성은 육상선수입니다. 10분 동안 세 명이 달리기를 하였을 때 재웅이는 20킬로미터(㎞), 성민이는 2600미터(m), 은성이는 5000미터(m)를 달렸다. 가장 많이 달린 사람은 누구인가?",
        "question_en": "Jaewoong, Seongmin, and Eunseong are track and field athletes. When three people ran for 10 minutes, Jaewoong ran 20 kilometers (km), Sungmin ran 2600 meters (m), and Eunseong ran 5000 meters (m). Who has run the most?",
        "answer_ko": "재웅",
        "answer_en": "Jaewoong",
        "solution_abst_ko": "[OP_LIST_SOL] 재웅 성민 은성 [OP_LIST_EOL] [OP_LIST_SOL] 20 1000 [OP_MUL] 2600 5000 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jaewoong Seongmin Eunseong [OP_LIST_EOL] [OP_LIST_SOL] 20 1000 [OP_MUL] 2600 5000 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '재웅'\nvar_b = '성민'\nvar_c = '은성'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 20\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = 2600\nvar_h = 5000\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Jaewoong'\nvar_b = 'Seongmin'\nvar_c = 'Eunseong'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 20\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = 2600\nvar_h = 5000\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "4014": {
        "category": "Geometry",
        "question_ko": "겉넓이가 150제곱센티미터(㎠)인 정육면체의 모든 모서리의 길이의 합을 구하시오.",
        "question_en": "Find the sum of the lengths of all the edges of a cube with a surface area of 150 square centimeters (cm2).",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "150 6 [OP_DIV] 1/2 [OP_POW] 4 3 [OP_MUL] [OP_MUL]",
        "solution_abst_en": "150 6 [OP_DIV] 1/2 [OP_POW] 4 3 [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 150\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 4\nvar_g = 3\nvar_h = var_f * var_g\nvar_i = var_e * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 150\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 4\nvar_g = 3\nvar_h = var_f * var_g\nvar_i = var_e * var_h\nprint(int(var_i))"
    },
    "4015": {
        "category": "Comparison",
        "question_ko": "놀이동산에 사람들이 입장하려고 줄을 서 있다. 은지가 뒤에서 6번째에 서있고 은지 앞에 7명이 있을 때, 줄을 서 있는 사람은 모두 몇명인가?",
        "question_en": "People are queuing up to enter the amusement park. If Eunji is standing at the 6th from the back, and there are 7 people in front of Eunji, how many people are all in line?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "6 7 [OP_ADD]",
        "solution_abst_en": "6 7 [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "4016": {
        "category": "Geometry",
        "question_ko": "어느 직육면체의 가로의 길이는 7센티미터(㎝)이고 세로의 길이는 8센티미터(㎝)입니다. 겉넓이가 442제곱센티미터(㎠)라면, 이 직육면체의 높이는 몇 센티미터(㎝)입니까?",
        "question_en": "The width of a rectangular parallelepiped is 7 centimeters (cm) and the length is 8 centimeters (cm). If the surface area is 442 square centimeters (cm2), how many centimeters (cm) is the height of this cuboid?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "442 2 [OP_DIV] 7 8 [OP_MUL] [OP_SUB] 7 8 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "442 2 [OP_DIV] 7 8 [OP_MUL] [OP_SUB] 7 8 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 442\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = 8\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 7\nvar_i = 8\nvar_j = var_h + var_i\nvar_k = var_g / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 442\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = 8\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 7\nvar_i = 8\nvar_j = var_h + var_i\nvar_k = var_g / var_j\nprint(int(var_k))"
    },
    "4017": {
        "category": "Arithmetic calculation",
        "question_ko": "주차장에 자동차가 55대 있었습니다. 자동차 16대가 나간 후, 다시 19대가 들어왔습니다. 주차장에 자동차는 몇 대 더 많아졌습니까?",
        "question_en": "There were 55 cars in the parking lot. After 16 cars went out, another 19 came in. How many more cars are there in the parking lot?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "55 16 [OP_SUB] 19 [OP_ADD] 55 [OP_SUB]",
        "solution_abst_en": "55 16 [OP_SUB] 19 [OP_ADD] 55 [OP_SUB]",
        "solution_code_ko": "var_a = 55\nvar_b = 16\nvar_c = var_a - var_b\nvar_d = 19\nvar_e = var_c + var_d\nvar_f = 55\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 55\nvar_b = 16\nvar_c = var_a - var_b\nvar_d = 19\nvar_e = var_c + var_d\nvar_f = 55\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "4018": {
        "category": "Arithmetic calculation",
        "question_ko": "지민이의 과학 점수는 87점이고, 사회 점수는 과학 점수보다 6점 높습니다. 과학, 사회, 영어 세 과목의 평균 점수가 92점이 되려면 영어를 몇 점 맞아야 합니까?",
        "question_en": "Jimin's science score is 87, and his social studies score is 6 points higher than his science score. How many English points does he need to get an average score of 92 in science, social studies, and English?",
        "answer_ko": "96",
        "answer_en": "96",
        "solution_abst_ko": "92 3 [OP_MUL] 87 87 6 [OP_ADD] [OP_ADD] [OP_SUB]",
        "solution_abst_en": "92 3 [OP_MUL] 87 87 6 [OP_ADD] [OP_ADD] [OP_SUB]",
        "solution_code_ko": "var_a = 92\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 87\nvar_e = 87\nvar_f = 6\nvar_g = var_e + var_f\nvar_h = var_d + var_g\nvar_i = var_c - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 92\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 87\nvar_e = 87\nvar_f = 6\nvar_g = var_e + var_f\nvar_h = var_d + var_g\nvar_i = var_c - var_h\nprint(int(var_i))"
    },
    "4019": {
        "category": "Geometry",
        "question_ko": "사과와 배를 사서 사과는 4개씩 배는 3개씩 나누어주려고 하고 나머지가 없어야 한다. 같은 개수의 사과와 배를 산다면 최소 몇 개를 사야하는지 구하시오.",
        "question_en": "You are about to buy apples and pears, and give out 4 apples and 3 pears, and there should be no leftovers. If you buy the same number of apples and pears, find the minimum number you need to buy.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "3 4 [OP_LCM]",
        "solution_abst_en": "3 4 [OP_LCM]",
        "solution_code_ko": "var_a = 3\nvar_b = 4\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 4\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nprint(int(var_c))"
    },
    "4020": {
        "category": "Geometry",
        "question_ko": "모든 모서리의 길이의 합이 82.8센티미터(㎝)인 정육면체가 있습니다. 이 정육면체의 한 모서리의 길이를 1/3로 줄여서 새로운 정육면체를 만들었습니다. 새로 만든 정육면체의 한 모서리의 길이와 처음 정육면체의 한 모서리의 길이의 합은 몇 센티미터(㎝)입니까?",
        "question_en": "There is a cube with the sum of the lengths of all its edges equal to 82.8 centimeters (cm). A new cube was created by shortening the length of one edge of this cube by 1/3. How many centimeters (cm) is the sum of the length of one edge of the newly created cube and the length of one edge of the original cube?",
        "answer_ko": "9.20",
        "answer_en": "9.2",
        "solution_abst_ko": "82.8 4 3 [OP_MUL] [OP_DIV] 1/3 [OP_MUL] 82.8 4 3 [OP_MUL] [OP_DIV] [OP_ADD]",
        "solution_abst_en": "82.8 4 3 [OP_MUL] [OP_DIV] 1/3 [OP_MUL] 82.8 4 3 [OP_MUL] [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 82.8\nvar_b = 4\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nvar_f = 0.3333333333333333\nvar_g = var_e * var_f\nvar_h = 82.8\nvar_i = 4\nvar_j = 3\nvar_k = var_i * var_j\nvar_l = var_h / var_k\nvar_m = var_g + var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))",
        "solution_code_en": "var_a = 82.8\nvar_b = 4\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nvar_f = 0.3333333333333333\nvar_g = var_e * var_f\nvar_h = 82.8\nvar_i = 4\nvar_j = 3\nvar_k = var_i * var_j\nvar_l = var_h / var_k\nvar_m = var_g + var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))"
    },
    "4021": {
        "category": "Arithmetic calculation",
        "question_ko": "정삼각형의 둘레는 2미터(m)입니다. 이 정삼각형의 한 변의 길이는 몇 미터(m)인지 소수로 나타내어 보세요.",
        "question_en": "The perimeter of an equilateral triangle is 2 meters (m). Find how many meters (m) is the side length of this equilateral triangle in decimal numbers.",
        "answer_ko": "0.67",
        "answer_en": "0.67",
        "solution_abst_ko": "2 3 [OP_DIV]",
        "solution_abst_en": "2 3 [OP_DIV]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "4022": {
        "category": "Arithmetic calculation",
        "question_ko": "바둑돌이 모두 6000개가 있다. 흰 바둑돌이 검은 바둑돌 보다 많고 전체 개수에서 흰 바둑돌과 검은 바둑돌의 개수의 차를 빼면 4800개이다. 흰 바둑돌의 개수는 몇 개 입니까?",
        "question_en": "There are 6000 Go stones in total. There are more white Go stones than black Go stones. When the difference between the number of white and black stones is subtracted from the total number of stones, the result is 4800. How many white Go stones are there?",
        "answer_ko": "3600",
        "answer_en": "3600",
        "solution_abst_ko": "6000 4800 2 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "6000 4800 2 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 6000\nvar_b = 4800\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6000\nvar_b = 4800\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "4023": {
        "category": "Arithmetic calculation",
        "question_ko": "마트에 사과의 3배 만큼의 배가 있습니다. 사과가 240킬로그램(㎏) 있을 때, 사과와 배의 무게는 총 몇 킬로그램(㎏) 있습니까?",
        "question_en": "There are three times as many pears as apples in the supermarket. If there are 240 kilograms (kg) of apples, how many kilograms (kg) do the apples and pears weigh?",
        "answer_ko": "960",
        "answer_en": "960",
        "solution_abst_ko": "240 240 3 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "240 240 3 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 240\nvar_b = 240\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 240\nvar_b = 240\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "4024": {
        "category": "Geometry",
        "question_ko": "사다리꼴 모양의 지붕을 그렸습니다. 지붕의 윗변이 아랫변보다 3.4센티미터(㎝) 더 길고, 높이가 5.2센티미터(㎝)이고 넓이가 100.62제곱센티미터(㎠)입니다. 지붕의 아랫변의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "I painted a trapezoidal roof. The upper side of the roof is 3.4 centimeters (cm) longer than the lower side, the height is 5.2 centimeters (cm) and the area is 100.62 square centimeters (cm2). How many centimeters (cm) is the length of the lower side of the roof?",
        "answer_ko": "17.65",
        "answer_en": "17.65",
        "solution_abst_ko": "100.62 2 [OP_MUL] 5.2 [OP_DIV] 3.4 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "100.62 2 [OP_MUL] 5.2 [OP_DIV] 3.4 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 100.62\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 5.2\nvar_e = var_c / var_d\nvar_f = 3.4\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 100.62\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 5.2\nvar_e = var_c / var_d\nvar_f = 3.4\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "4025": {
        "category": "Arithmetic calculation",
        "question_ko": "30분 동안 180개의 장난감을 만드는 기계가 있다. 이 기계가 1시간 동안 만든 장난감은 몇 개인지 구하시오.",
        "question_en": "There is a machine that makes 180 toys in 30 minutes. Find how many toys this machine made in 1 hour.",
        "answer_ko": "360",
        "answer_en": "360",
        "solution_abst_ko": "1 60 [OP_MUL] 30 [OP_DIV] 180 [OP_MUL]",
        "solution_abst_en": "1 60 [OP_MUL] 30 [OP_DIV] 180 [OP_MUL]",
        "solution_code_ko": "var_a = 1\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 30\nvar_e = var_c / var_d\nvar_f = 180\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 30\nvar_e = var_c / var_d\nvar_f = 180\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "4026": {
        "category": "Comparison",
        "question_ko": "20명의 학생들이 한 줄로 줄을 섰습니다. 윤기의 앞에는 11명의 학생들이 서 있고, 호석이는 윤기 바로 뒤에 서 있습니다. 호석이 뒤에 서 있는 학생은 몇 명입니까?",
        "question_en": "20 students lined up in a single line. Eleven students are standing in front of Yoongi, and Hoseok is standing right behind Yoongi. How many students are standing behind Hoseok?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "20 11 [OP_SUB] 1 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "20 11 [OP_SUB] 1 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "4027": {
        "category": "Correspondence",
        "question_ko": "57A-2B4=364일 때, B에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "When 57A-2B4=364, what number should go in B?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "57A-2B4=364 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "57A-2B4=364 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '57A-2B4=364'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '57A-2B4=364'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "4028": {
        "category": "Geometry",
        "question_ko": "어떤 색종이는 정사각형 모양이고 한 변의 길이가 6센티미터(㎝)라고 합니다. 이 색종이의 넓이는 몇 제곱센티미터(㎠)입니까?",
        "question_en": "There is a square-shaped colored paper with each side measuring 6 centimeters (cm). What is the area in square centimeters (cm2) of this sheet of paper?",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "6 2 [OP_POW]",
        "solution_abst_en": "6 2 [OP_POW]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = var_a ** var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = var_a ** var_b\nprint(int(var_c))"
    },
    "4029": {
        "category": "Correspondence",
        "question_ko": "8A4를 올림하여 십의 자리까지 나타내면 870이 됩니다. A를 구하시오.",
        "question_en": "8A4 rounded up to the tens place is 870. Find A.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "8A4 [OP_GEN_POSSIBLE_LIST] 870 [OP_LIST_LESS_EQUAL] 870 10 [OP_SUB] [OP_LIST_MORE] 8A4 A [OP_LIST_FIND_UNK]",
        "solution_abst_en": "8A4 [OP_GEN_POSSIBLE_LIST] 870 [OP_LIST_LESS_EQUAL] 870 10 [OP_SUB] [OP_LIST_MORE] 8A4 A [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = '8A4'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 870\nlist_b = []\nfor i in list_a:\n    if i <= var_b:\n        list_b.append(i)\nvar_c = 870\nvar_d = 10\nvar_e = var_c - var_d\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = '8A4'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))",
        "solution_code_en": "var_a = '8A4'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 870\nlist_b = []\nfor i in list_a:\n    if i <= var_b:\n        list_b.append(i)\nvar_c = 870\nvar_d = 10\nvar_e = var_c - var_d\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = '8A4'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))"
    },
    "4030": {
        "category": "Comparison",
        "question_ko": "은지는 지우개 13개를 가지고 있다. 유정이는 지우개를 4개 가지고 있었는데 언니에게 3개 더 받았다. 은지는 동생에게 7개의 지우개를 주었다. 유정, 은지 중 지우개를 더 많이 가진 사람은 누구인가",
        "question_en": "Eunji had 13 erasers. Yujeong had 4 erasers, and she got 3 more from her sister. Eunji gave her sister 7 erasers. Who has more erasers among Yujeong and Eunji?",
        "answer_ko": "유정",
        "answer_en": "Yujeong",
        "solution_abst_ko": "[OP_LIST_SOL] 유정 은지 [OP_LIST_EOL] [OP_LIST_SOL] 4 3 [OP_ADD] 13 7 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yujeong Eunji [OP_LIST_EOL] [OP_LIST_SOL] 4 3 [OP_ADD] 13 7 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '유정'\nvar_b = '은지'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = 13\nvar_g = 7\nvar_h = var_f - var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Yujeong'\nvar_b = 'Eunji'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = 13\nvar_g = 7\nvar_h = var_f - var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "4031": {
        "category": "Arithmetic calculation",
        "question_ko": "32와 24의 최대공약수를 구하시오.",
        "question_en": "Find the greatest common divisor of 32 and 24.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "32 24 [OP_GCD]",
        "solution_abst_en": "32 24 [OP_GCD]",
        "solution_code_ko": "var_a = 32\nvar_b = 24\nvar_c = math.gcd(int(var_b), int(var_a))\nprint(int(var_c))",
        "solution_code_en": "var_a = 32\nvar_b = 24\nvar_c = math.gcd(int(var_b), int(var_a))\nprint(int(var_c))"
    },
    "4032": {
        "category": "Arithmetic calculation",
        "question_ko": "15인승 놀이기구를 학생들이 18번에 걸쳐 한번씩 탔습니다. 매번 탈때마다 3자리씩 비어있다면 모든 학생들의 수는 몇 명 입니까?",
        "question_en": "Students rode the 15-seater ride once over 18 times. If each ride has 3 empty seats, what is the total number of students?",
        "answer_ko": "216",
        "answer_en": "216",
        "solution_abst_ko": "15 3 [OP_SUB] 18 [OP_MUL]",
        "solution_abst_en": "15 3 [OP_SUB] 18 [OP_MUL]",
        "solution_code_ko": "var_a = 15\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 18\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 18\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "4033": {
        "category": "Correspondence",
        "question_ko": "서로 다른 세 자연수 A, B, C가 있습니다. A를 11로 나누면 몫은 B이고 나머지는 C가 됩니다. 나머지 C가 될 수 있는 가장 큰 수를 구하시오.",
        "question_en": "There are three different natural numbers A, B, and C. When A is divided by 11, the quotient is B and the remainder is C. Find the largest number that can be C.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "11 1 [OP_SUB]",
        "solution_abst_en": "11 1 [OP_SUB]",
        "solution_code_ko": "var_a = 11\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 11\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "4034": {
        "category": "Comparison",
        "question_ko": "72센티미터(㎝)의 차이가 나는 두 끈이 있습니다. 이 둘을 일렬로 놓고 길이를 재 보니 3미터(m) 48센티미터(㎝)가 나왔습니다. 길이가 긴 끈의 길이는 얼마인지 구하시오",
        "question_en": "There are two straps with a difference of 72 centimeters (cm). When I put these two in a row and measured the length, I got 3 meters (m) and 48 centimeters (cm). Find the length of the longer string.",
        "answer_ko": "210",
        "answer_en": "210",
        "solution_abst_ko": "3 100 [OP_MUL] 48 [OP_ADD] 72 [OP_SUB] 2 [OP_DIV] 72 [OP_ADD]",
        "solution_abst_en": "3 100 [OP_MUL] 48 [OP_ADD] 72 [OP_SUB] 2 [OP_DIV] 72 [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 48\nvar_e = var_c + var_d\nvar_f = 72\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nvar_j = 72\nvar_k = var_i + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 3\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 48\nvar_e = var_c + var_d\nvar_f = 72\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nvar_j = 72\nvar_k = var_i + var_j\nprint(int(var_k))"
    },
    "4035": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 15에서 7을 뺀 값을 곱하면 48이 됩니다. 어떤 수를 구하세요.",
        "question_en": "Suppose that the number multiplied by 15 minus 7 is 48. Find what the number is.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "48 15 7 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "48 15 7 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 48\nvar_b = 15\nvar_c = 7\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 48\nvar_b = 15\nvar_c = 7\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "4036": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 10, 11, 12, 13이 있습니다. 그 중에서 가장 작은 수와 2번째로 작은 수로 나눈 나머지는 얼마입니까?",
        "question_en": "There are four numbers 10, 11, 12, and 13. What is the remainder when divided by the smallest number and the second smallest number?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_MOD]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_MOD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f % var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f % var_h\nprint(int(var_i))"
    },
    "4037": {
        "category": "Geometry",
        "question_ko": "둘레가 23.4센티미터(㎝)인 정오각형이 있습니다. 이 정오각형의 한 변은 몇 센티미터(㎝)입니까?",
        "question_en": "There is a regular pentagon with a perimeter of 23.4 centimeters (cm). How many centimeters (cm) is one side of this regular pentagon?",
        "answer_ko": "4.68",
        "answer_en": "4.68",
        "solution_abst_ko": "23.4 5 [OP_DIV]",
        "solution_abst_en": "23.4 5 [OP_DIV]",
        "solution_code_ko": "var_a = 23.4\nvar_b = 5\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 23.4\nvar_b = 5\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "4038": {
        "category": "Correspondence",
        "question_ko": "네 자리 수 7A2B는 2, 3, 5의 최소공배수로 나누어 떨어지고 A와 B는 서로 다른 숫자를 나타냅니다. 이러한 네 자리 수 중 가장 큰 수를 구하시오",
        "question_en": "The four-digit number 7A2B is divisible by the least common multiple of 2, 3, and 5, and A and B represent different numbers. Find the largest of these four-digit numbers.",
        "answer_ko": "7920",
        "answer_en": "7920",
        "solution_abst_ko": "7A2B [OP_GEN_POSSIBLE_LIST] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_abst_en": "7A2B [OP_GEN_POSSIBLE_LIST] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = '7A2B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 2\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 3\nlist_c = []\nvar_c = int(var_c)\nfor i in list_b:\n    i = int(i)\n    if i % var_c == 0:\n        list_c.append(i)\nvar_d = 5\nlist_d = []\nvar_d = int(var_d)\nfor i in list_c:\n    i = int(i)\n    if i % var_d == 0:\n        list_d.append(i)\nvar_e = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_f = list_e[-var_e]\nprint(int(var_f))",
        "solution_code_en": "var_a = '7A2B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 2\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 3\nlist_c = []\nvar_c = int(var_c)\nfor i in list_b:\n    i = int(i)\n    if i % var_c == 0:\n        list_c.append(i)\nvar_d = 5\nlist_d = []\nvar_d = int(var_d)\nfor i in list_c:\n    i = int(i)\n    if i % var_d == 0:\n        list_d.append(i)\nvar_e = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_f = list_e[-var_e]\nprint(int(var_f))"
    },
    "4039": {
        "category": "Arithmetic calculation",
        "question_ko": "서연이는 숫자가 적힌 블럭 4개를 가지고 있다. 블럭에 적힌 수의 차를 가장 크게 하는 2개의 합을 구하여라. 블럭에는 1, 3, 7, 9가 적혀있다.",
        "question_en": "Seoyeon has 4 blocks with numbers on them. Find the sum of the numbers on two blocks that maximize the difference between the numbers written in the block. The blocks are numbered 1, 3, 7, and 9.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 7 9 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 7 9 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 7\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 7\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))"
    },
    "4040": {
        "category": "Arithmetic calculation",
        "question_ko": "버스 안에 사람이 34명 있었습니다. 이번 정류장에서 11명이 내리고 24명이 탔습니다. 지금 버스 안에 있는 사람은 모두 몇 명입니까?",
        "question_en": "There were 34 people on the bus. At this stop, 11 people got off and 24 people got on. How many people are on the bus right now?",
        "answer_ko": "47",
        "answer_en": "47",
        "solution_abst_ko": "34 11 [OP_SUB] 24 [OP_ADD]",
        "solution_abst_en": "34 11 [OP_SUB] 24 [OP_ADD]",
        "solution_code_ko": "var_a = 34\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 24\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 34\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 24\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "4041": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 14를 더한 후 14를 곱하고, 24를 뺀 값을 24로 나누면 13이 됩니다. 어떤 수를 구하시오.",
        "question_en": "A number plus 14, multiply by 14, subtract by 24, and divide by 24 equals 13. If the calculation proceeds in order, find the initial number.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "13 24 [OP_MUL] 24 [OP_ADD] 14 [OP_DIV] 14 [OP_SUB]",
        "solution_abst_en": "13 24 [OP_MUL] 24 [OP_ADD] 14 [OP_DIV] 14 [OP_SUB]",
        "solution_code_ko": "var_a = 13\nvar_b = 24\nvar_c = var_a * var_b\nvar_d = 24\nvar_e = var_c + var_d\nvar_f = 14\nvar_g = var_e / var_f\nvar_h = 14\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 13\nvar_b = 24\nvar_c = var_a * var_b\nvar_d = 24\nvar_e = var_c + var_d\nvar_f = 14\nvar_g = var_e / var_f\nvar_h = 14\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "4042": {
        "category": "Comparison",
        "question_ko": "백의 자리 숫자가 2, 십의 자리 숫자가 5인 세 자리 수 중에서 256보다 큰 수는 모두 몇 개인지 구하시오.",
        "question_en": "Find how many three-digit numbers with 2 in the hundreds digit and 5 in the tens digit are greater than 256.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 2 5 A [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 256 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 2 5 A [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 256 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 2\nvar_b = 5\nvar_c = 'A'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nans_dict = dict()\nvar_d = str(var_d)\nlist_b = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_d) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_b.append(new_elem)\nvar_e = 256\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 2\nvar_b = 5\nvar_c = 'A'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nans_dict = dict()\nvar_d = str(var_d)\nlist_b = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_d) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_b.append(new_elem)\nvar_e = 256\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "4043": {
        "category": "Arithmetic calculation",
        "question_ko": "민영이는 1개에 90원짜리 사탕을 몇 개 살 수 있는 돈으로 1개에 60원짜리 사탕을 같은 수만큼 샀더니 270원이 남았습니다. 민영이가 가지고 있던 돈은 얼마인지 구하시오.",
        "question_en": "Minyoung bought the same number of candies at 60 won each with the money he could buy same number of candies at 90 won each, and he had 270 won left. Find how much money Minyoung had.",
        "answer_ko": "540",
        "answer_en": "540",
        "solution_abst_ko": "270 90 60 [OP_SUB] [OP_DIV] 60 [OP_MUL]",
        "solution_abst_en": "270 90 60 [OP_SUB] [OP_DIV] 60 [OP_MUL]",
        "solution_code_ko": "var_a = 270\nvar_b = 90\nvar_c = 60\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 60\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 270\nvar_b = 90\nvar_c = 60\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 60\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "4044": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 1264를 빼어야 하는데 잘못하여 2152를 빼었습니다. 바르게 계산한 답과 잘못 계산한 답의 차는 얼마입니까?",
        "question_en": "You originally planned to subtract 1264 from a number, but you mistakenly subtracted 2152. What is the difference between the correct and incorrect answers?",
        "answer_ko": "888",
        "answer_en": "888",
        "solution_abst_ko": "2152 1264 [OP_SUB]",
        "solution_abst_en": "2152 1264 [OP_SUB]",
        "solution_code_ko": "var_a = 2152\nvar_b = 1264\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2152\nvar_b = 1264\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "4045": {
        "category": "Comparison",
        "question_ko": "두 자리 수 곱셈에서 곱하는 수의 십의 자리 숫자 5를 3으로 잘못 보고 계산한 값이 1485가 되었습니다. 바르게 계산한 값이 2385일 때, 2개의 두 자리 수 중 더 작은 수를 쓰시오.",
        "question_en": "In two-digit multiplication, the digit 5 in the tens place of this number was incorrectly considered to be 3, resulting in a computed value of 1485. If the correct value is 2385, write the smaller of the two 2-digit numbers.",
        "answer_ko": "53",
        "answer_en": "53",
        "solution_abst_ko": "[OP_LIST_SOL] 1485 2385 [OP_SUB] 3 5 [OP_SUB] 10 [OP_MUL] [OP_DIV] 2385 1485 2385 [OP_SUB] 3 5 [OP_SUB] 10 [OP_MUL] [OP_DIV] [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1485 2385 [OP_SUB] 3 5 [OP_SUB] 10 [OP_MUL] [OP_DIV] 2385 1485 2385 [OP_SUB] 3 5 [OP_SUB] 10 [OP_MUL] [OP_DIV] [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1485\nvar_b = 2385\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = 5\nvar_f = var_d - var_e\nvar_g = 10\nvar_h = var_f * var_g\nvar_i = var_c / var_h\nvar_j = 2385\nvar_k = 1485\nvar_l = 2385\nvar_m = var_k - var_l\nvar_n = 3\nvar_o = 5\nvar_p = var_n - var_o\nvar_q = 10\nvar_r = var_p * var_q\nvar_s = var_m / var_r\nvar_t = var_j / var_s\nlist_a= []\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_a.append(var_t)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nlist_a.reverse()\nvar_u = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_v = list_b[-var_u]\nprint(int(var_v))",
        "solution_code_en": "var_a = 1485\nvar_b = 2385\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = 5\nvar_f = var_d - var_e\nvar_g = 10\nvar_h = var_f * var_g\nvar_i = var_c / var_h\nvar_j = 2385\nvar_k = 1485\nvar_l = 2385\nvar_m = var_k - var_l\nvar_n = 3\nvar_o = 5\nvar_p = var_n - var_o\nvar_q = 10\nvar_r = var_p * var_q\nvar_s = var_m / var_r\nvar_t = var_j / var_s\nlist_a= []\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_a.append(var_t)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nlist_a.reverse()\nvar_u = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_v = list_b[-var_u]\nprint(int(var_v))"
    },
    "4046": {
        "category": "Arithmetic calculation",
        "question_ko": "물 탱크에 120리터(L) 만큼의 물이 있다. 이 물탱크에 수도꼭지를 열면 분 당 4리터(L)의 물이 흘러나온다. 수도꼭지를 열고 몇 분이 지났을 때, 물탱크 안에 20리터(L)의 물이 남아있었습니다. 몇 분 동안 수도꼭지를 열어 두었는지 구하시오.",
        "question_en": "There are 120 liters (L) of water in the water tank. When you open the faucet in this water tank, 4 liters (L) of water flow out per minute. A few minutes after opening the faucet, 20 liters (L) of water remained in the water tank. Find how many minutes the faucet was left open.",
        "answer_ko": "25",
        "answer_en": "25",
        "solution_abst_ko": "120 20 [OP_SUB] 4 [OP_DIV]",
        "solution_abst_en": "120 20 [OP_SUB] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 120\nvar_b = 20\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 120\nvar_b = 20\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "4047": {
        "category": "Geometry",
        "question_ko": "정육면체 모양의 우유통이 있습니다. 이 우유통을 모두 펼쳤더니 넓이가 600이었습니다. 이 우유통의 부피를 구하시오.",
        "question_en": "There is a milk carton in the shape of a cube. When all of these milk cartons were unfolded, the area was 600. Find the volume of this milk carton.",
        "answer_ko": "1000",
        "answer_en": "1000",
        "solution_abst_ko": "600 6 [OP_DIV] 1/2 [OP_POW] 3 [OP_POW]",
        "solution_abst_en": "600 6 [OP_DIV] 1/2 [OP_POW] 3 [OP_POW]",
        "solution_code_ko": "var_a = 600\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 3\nvar_g = var_e ** var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 600\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 3\nvar_g = var_e ** var_f\nprint(int(var_g))"
    },
    "4048": {
        "category": "Correspondence",
        "question_ko": "주머니 속의 구슬을 96개씩 모아두었더니 5묶음이 나오고 나머지가 17이었습니다. 구슬의 개수에 69를 곱하면 얼마일까요?",
        "question_en": "When you collected 96 marbles in the bag, 5 groups came out, and the remainder was 17. What is the number of marbles multiplied by 69?",
        "answer_ko": "34293",
        "answer_en": "34293",
        "solution_abst_ko": "5 96 [OP_MUL] 17 [OP_ADD] 69 [OP_MUL]",
        "solution_abst_en": "5 96 [OP_MUL] 17 [OP_ADD] 69 [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 96\nvar_c = var_a * var_b\nvar_d = 17\nvar_e = var_c + var_d\nvar_f = 69\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 96\nvar_c = var_a * var_b\nvar_d = 17\nvar_e = var_c + var_d\nvar_f = 69\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "4049": {
        "category": "Possibility",
        "question_ko": "2, 3, 4, 5의 숫자가 각각 적힌 4개의 구슬 중 3개를 뽑아서 만들 수 있는 세 자리 정수의 개수는?",
        "question_en": "How many 3-digit integers can be made by drawing 3 out of 4 marbles numbered 2, 3, 4, 5?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "[OP_LIST_SOL] 2 3 4 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 2 3 4 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = 4\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = 4\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "4050": {
        "category": "Correspondence",
        "question_ko": "36을 어떤 수에 더했더니 결과가 71이 나왔습니다. 어떤 수에 10을 더하면 얼마일까요?",
        "question_en": "When you add 36 to a certain number, you get 71. What is the value when you add 10 to that certain number?",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "71 36 [OP_SUB] 10 [OP_ADD]",
        "solution_abst_en": "71 36 [OP_SUB] 10 [OP_ADD]",
        "solution_code_ko": "var_a = 71\nvar_b = 36\nvar_c = var_a - var_b\nvar_d = 10\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 71\nvar_b = 36\nvar_c = var_a - var_b\nvar_d = 10\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "4051": {
        "category": "Arithmetic calculation",
        "question_ko": "현수네 아버지가 운전하는 자동차로 15.5킬로미터(㎞)를 가는 데에 10분이 걸렸습니다. 이와 같은 빠르기로 46분을 달리면 몇 킬로미터(㎞)를 갈 수 있습니까?",
        "question_en": "It took 10 minutes to go 15.5 kilometers (km) by car driven by Hyun-soo's father. How many kilometers (km) he can go in 46 minutes at this speed?",
        "answer_ko": "71.30",
        "answer_en": "71.3",
        "solution_abst_ko": "15.5 10 [OP_DIV] 46 [OP_MUL]",
        "solution_abst_en": "15.5 10 [OP_DIV] 46 [OP_MUL]",
        "solution_code_ko": "var_a = 15.5\nvar_b = 10\nvar_c = var_a / var_b\nvar_d = 46\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 15.5\nvar_b = 10\nvar_c = var_a / var_b\nvar_d = 46\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "4052": {
        "category": "Comparison",
        "question_ko": "경시반 학생 5명이 수학 시험을 친 결과 평균 점수가 81.6점이었다. 가장 높은 점수를 빼고 평균을 내면 가장 낮은 점수를 빼고 평균을 낸 것보다 6점이 낮다고 한다. 가장 높은 점수와 가장 낮은 점수를 제외한 나머지 3명의 점수가 88점, 84점, 76점이라고 할 때, 가장 낮은 점수를 구하여라.",
        "question_en": "The average math score of 5 students in the competition class was 81.6. Calculating the average without the highest score is said to be 6 points lower than the average without the lowest score. Let's say that the scores of the other 3 people excluding the highest and lowest, are 88, 84, and 76. Find the lowest score.",
        "answer_ko": "68",
        "answer_en": "68",
        "solution_abst_ko": "81.6 5 [OP_MUL] 88 84 [OP_ADD] 76 [OP_ADD] [OP_SUB] 6 4 [OP_MUL] [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "81.6 5 [OP_MUL] 88 84 [OP_ADD] 76 [OP_ADD] [OP_SUB] 6 4 [OP_MUL] [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 81.6\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 88\nvar_e = 84\nvar_f = var_d + var_e\nvar_g = 76\nvar_h = var_f + var_g\nvar_i = var_c - var_h\nvar_j = 6\nvar_k = 4\nvar_l = var_j * var_k\nvar_m = var_i - var_l\nvar_n = 2\nvar_o = var_m / var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 81.6\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 88\nvar_e = 84\nvar_f = var_d + var_e\nvar_g = 76\nvar_h = var_f + var_g\nvar_i = var_c - var_h\nvar_j = 6\nvar_k = 4\nvar_l = var_j * var_k\nvar_m = var_i - var_l\nvar_n = 2\nvar_o = var_m / var_n\nprint(int(var_o))"
    },
    "4053": {
        "category": "Arithmetic calculation",
        "question_ko": "깃대 6개를 일정한 간격으로 거리위에 꽂으려고 합니다. 거리의 길이는 11.5미터(m)이며 양끝에도 깃대를 꼽는다고 합니다. 깃대와 깃대 사이의 거리는 몇 미터(m)로 해야 하나요?",
        "question_en": "You want to place 6 flagpoles on the street at regular intervals. The length of the street is 11.5 meters (m), and it is said that there are flagpoles at both ends. How many meters (m) should the distance between flagpoles be?",
        "answer_ko": "2.30",
        "answer_en": "2.3",
        "solution_abst_ko": "11.5 6 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "11.5 6 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 11.5\nvar_b = 6\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 11.5\nvar_b = 6\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "4054": {
        "category": "Comparison",
        "question_ko": "정욱이는 3.97킬로미터(㎞) 달리고, 용운이는 4028미터(m)를 달렸습니다. 누가 더 긴 거리를 달렸습니까?",
        "question_en": "Jungwook ran 3.97 kilometers (km), and Yongun ran 4028 meters (m). Who ran the longer distance?",
        "answer_ko": "용운",
        "answer_en": "Yongun",
        "solution_abst_ko": "[OP_LIST_SOL] 정욱 용운 [OP_LIST_EOL] [OP_LIST_SOL] 3.97 4028 1000 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungwook Yongun [OP_LIST_EOL] [OP_LIST_SOL] 3.97 4028 1000 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정욱'\nvar_b = '용운'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3.97\nvar_d = 4028\nvar_e = 1000\nvar_f = var_d / var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Jungwook'\nvar_b = 'Yongun'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3.97\nvar_d = 4028\nvar_e = 1000\nvar_f = var_d / var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "4055": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 2의 2배만큼 더하면 6이 된다. 어떤 수는 얼마인가?",
        "question_en": "When 2 times 2 plus the number is equal to 6, what number is it?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "6 2 2 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "6 2 2 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "4056": {
        "category": "Arithmetic calculation",
        "question_ko": "두꺼운 책의 두께는 14/15센티미터(㎝)이고, 얇은 책의 두께는 두꺼운 책의 두께보다 1/10센티미터(㎝) 더 얇습니다. 이때 두 책의 두께의 합은 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "Thick books are 14/15 centimeters (cm) thick, and thin books are 1/10 centimeters (cm) thinner than thick books. Find the sum of the thicknesses of the two books in centimeters (cm).",
        "answer_ko": "1.77",
        "answer_en": "1.77",
        "solution_abst_ko": "14/15 2 [OP_MUL] 1/10 [OP_SUB]",
        "solution_abst_en": "14/15 2 [OP_MUL] 1/10 [OP_SUB]",
        "solution_code_ko": "var_a = 0.9333333333333333\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 0.1\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.9333333333333333\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 0.1\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "4057": {
        "category": "Correspondence",
        "question_ko": "107.8 을 어떤 수로 곱하였더니 9.8 이 되었습니다. 어떤 수는 얼마인지 구하시오.",
        "question_en": "Multiplying 107.8 by some number gives 9.8. Find out what the number is.",
        "answer_ko": "0.09",
        "answer_en": "0.09",
        "solution_abst_ko": "9.8 107.8 [OP_DIV]",
        "solution_abst_en": "9.8 107.8 [OP_DIV]",
        "solution_code_ko": "var_a = 9.8\nvar_b = 107.8\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 9.8\nvar_b = 107.8\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "4058": {
        "category": "Correspondence",
        "question_ko": "어떤 수는 5와 9 사이에 있고, 7보다 큰 한 자리 수입니다. 어떤 수를 구하시오.",
        "question_en": "Some numbers are in between 5 and 9 and are single-digits greater than 7. Find which number satisfies the condition.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "5 1 [OP_ADD] 9 1 [OP_SUB] 1 [OP_LIST_ARANGE] 7 [OP_LIST_MORE] 1 [OP_LIST_GET]",
        "solution_abst_en": "5 1 [OP_ADD] 9 1 [OP_SUB] 1 [OP_LIST_ARANGE] 7 [OP_LIST_MORE] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 5\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = 7\nlist_b = []\nfor i in list_a:\n    if i > var_h:\n        list_b.append(i)\nvar_i = 1\nvar_j = list_b[var_i-1]\nprint(int(var_j))",
        "solution_code_en": "var_a = 5\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = 7\nlist_b = []\nfor i in list_a:\n    if i > var_h:\n        list_b.append(i)\nvar_i = 1\nvar_j = list_b[var_i-1]\nprint(int(var_j))"
    },
    "4059": {
        "category": "Geometry",
        "question_ko": "길이가 52센티미터(㎝)인 철사 2개로 각각 정사각형과 직사각형을 만듭니다. 직사각형의 가로가 15센티미터(㎝)이면 두 도형의 넓이 차가 얼마인지 구하시오.",
        "question_en": "Make each square and rectangle from two pieces of wire of 52 centimeters (cm) long. If the width of the rectangle is 15 centimeters (cm), what is the difference between the areas of the two figures?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "52 4 [OP_DIV] 2 [OP_POW] 52 2 [OP_DIV] 15 [OP_SUB] 15 [OP_MUL] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "52 4 [OP_DIV] 2 [OP_POW] 52 2 [OP_DIV] 15 [OP_SUB] 15 [OP_MUL] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 52\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 52\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = 15\nvar_j = var_h - var_i\nvar_k = 15\nvar_l = var_j * var_k\nvar_m = var_e - var_l\nvar_n = abs(var_m)\nprint(int(var_n))",
        "solution_code_en": "var_a = 52\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 52\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = 15\nvar_j = var_h - var_i\nvar_k = 15\nvar_l = var_j * var_k\nvar_m = var_e - var_l\nvar_n = abs(var_m)\nprint(int(var_n))"
    },
    "4060": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중에서 2번째로 큰 수와 2번째로 작은 수의 합은 얼마입니까?",
        "question_en": "There are three numbers 10, 11 and 12. What is the sum of the second largest number and the second smallest number?",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e + var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e + var_g\nprint(int(var_h))"
    },
    "4061": {
        "category": "Comparison",
        "question_ko": "공 5개를 나란히 놓았습니다. (마) 공은 (다) 공의 오른쪽 옆에, (마)는 (라)의 왼쪽 옆에 놓여있습니다. (가)의 오른쪽 옆에는 (다) 공이, (나)의 왼쪽 옆에는 (라) 공을 놓았습니다. 가장 왼쪽에 놓여진 공은 무엇인지 구하시오.",
        "question_en": "5 balls are placed side by side. (e) ball is placed to the right of (c) and (e) to the left of (d). To the right of (a) is the ball (c), and to the left of (b) is the ball (d). Find the ball that is placed on the far left.",
        "answer_ko": "(가)",
        "answer_en": "(a)",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) (다) (라) (마) [OP_LIST_EOL] [OP_LIST_SOL] (마) (다) > (마) (라) < (다) (가) > (라) (나) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (a) (b) (c) (d) (e) [OP_LIST_EOL] [OP_LIST_SOL] (e) (c) > (e) (d) < (c) (a) > (d) (b) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nvar_c = '(다)'\nvar_d = '(라)'\nvar_e = '(마)'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = '(마)'\nvar_g = '(다)'\nvar_h = '>'\nvar_i = '(마)'\nvar_j = '(라)'\nvar_k = '<'\nvar_l = '(다)'\nvar_m = '(가)'\nvar_n = '>'\nvar_o = '(라)'\nvar_p = '(나)'\nvar_q = '<'\nlist_b= []\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_r = len(list_c)\nvar_s = list_c[var_r-1]\nprint(var_s)",
        "solution_code_en": "var_a = '(a)'\nvar_b = '(b)'\nvar_c = '(c)'\nvar_d = '(d)'\nvar_e = '(e)'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = '(e)'\nvar_g = '(c)'\nvar_h = '>'\nvar_i = '(e)'\nvar_j = '(d)'\nvar_k = '<'\nvar_l = '(c)'\nvar_m = '(a)'\nvar_n = '>'\nvar_o = '(d)'\nvar_p = '(b)'\nvar_q = '<'\nlist_b= []\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_r = len(list_c)\nvar_s = list_c[var_r-1]\nprint(var_s)"
    },
    "4062": {
        "category": "Geometry",
        "question_ko": "한 모서리의 길이가 6센티미터(㎝)인 정육면체 3개를 이어붙여서 하나의 직육면체를 만들 수 있습니다. 붙이고 난 후의 겉넓이는 붙이기 전에 비해서 얼마나 줄어들었습니까?",
        "question_en": "You can make a cuboid by attaching three cubes, each of which has a side of 6 centimeters (cm) long. How much did the surface area after pasting decrease compared to before pasting?",
        "answer_ko": "288",
        "answer_en": "288",
        "solution_abst_ko": "3 6 3 [OP_POW] [OP_MUL] 18 6 [OP_MUL] 6 6 [OP_MUL] [OP_ADD] 6 6 [OP_MUL] [OP_ADD] 2 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "3 6 3 [OP_POW] [OP_MUL] 18 6 [OP_MUL] 6 6 [OP_MUL] [OP_ADD] 6 6 [OP_MUL] [OP_ADD] 2 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 3\nvar_b = 6\nvar_c = 3\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 18\nvar_g = 6\nvar_h = var_f * var_g\nvar_i = 6\nvar_j = 6\nvar_k = var_i * var_j\nvar_l = var_h + var_k\nvar_m = 6\nvar_n = 6\nvar_o = var_m * var_n\nvar_p = var_l + var_o\nvar_q = 2\nvar_r = var_p * var_q\nvar_s = var_e - var_r\nprint(int(var_s))",
        "solution_code_en": "var_a = 3\nvar_b = 6\nvar_c = 3\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 18\nvar_g = 6\nvar_h = var_f * var_g\nvar_i = 6\nvar_j = 6\nvar_k = var_i * var_j\nvar_l = var_h + var_k\nvar_m = 6\nvar_n = 6\nvar_o = var_m * var_n\nvar_p = var_l + var_o\nvar_q = 2\nvar_r = var_p * var_q\nvar_s = var_e - var_r\nprint(int(var_s))"
    },
    "4063": {
        "category": "Possibility",
        "question_ko": "4종류의 치킨과 3종류의 피자 중에서 각각 1종류씩을 선택할 수 있는 치킨피자세트 메뉴가 있다. 은성과 성민이 이 세트 메뉴를 주문할 때, 치킨과 피자 중에서 어느 하나만 서로 같은 것을 주문하는 경우의 수는?",
        "question_en": "There is a chicken pizza set menu in which you can choose one of four kinds of chicken and one of three kinds of pizza. When Eunsung and Sungmin are ordering the set menus, what is the number of cases in which they order only one same kind of menu among pizza and chicken?",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "4 3 2 [OP_PERM] [OP_MUL] 3 4 2 [OP_PERM] [OP_MUL] [OP_ADD]",
        "solution_abst_en": "4 3 2 [OP_PERM] [OP_MUL] 3 4 2 [OP_PERM] [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 3\nvar_c = 2\nvar_d = 1\nvar_b = int(var_b)\nvar_c = int(var_c)\nfor i, elem in enumerate(range(var_c)):\n    var_d = var_d * (var_b-i)\nvar_e = var_a * var_d\nvar_f = 3\nvar_g = 4\nvar_h = 2\nvar_i = 1\nvar_g = int(var_g)\nvar_h = int(var_h)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i * (var_g-i)\nvar_j = var_f * var_i\nvar_k = var_e + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 4\nvar_b = 3\nvar_c = 2\nvar_d = 1\nvar_b = int(var_b)\nvar_c = int(var_c)\nfor i, elem in enumerate(range(var_c)):\n    var_d = var_d * (var_b-i)\nvar_e = var_a * var_d\nvar_f = 3\nvar_g = 4\nvar_h = 2\nvar_i = 1\nvar_g = int(var_g)\nvar_h = int(var_h)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i * (var_g-i)\nvar_j = var_f * var_i\nvar_k = var_e + var_j\nprint(int(var_k))"
    },
    "4064": {
        "category": "Geometry",
        "question_ko": "전교생을 정사각형으로 줄세워서 보니 36명이 남았습니다. 가로 한 열과 세로 한 열을 1열씩 늘려서 줄세웠더니 아직도 3명이 남았습니다. 전교생은 모두 몇 명일까요?",
        "question_en": "When all the students were lined up in a square, there were 36 students left out. I extended the line in width and length by one column but there were still three people left. How many students are there? ",
        "answer_ko": "292",
        "answer_en": "292",
        "solution_abst_ko": "36 3 [OP_SUB] 1 [OP_SUB] 2 [OP_DIV] 2 [OP_POW] 36 [OP_ADD]",
        "solution_abst_en": "36 3 [OP_SUB] 1 [OP_SUB] 2 [OP_DIV] 2 [OP_POW] 36 [OP_ADD]",
        "solution_code_ko": "var_a = 36\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 36\nvar_k = var_i + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 36\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 36\nvar_k = var_i + var_j\nprint(int(var_k))"
    },
    "4065": {
        "category": "Possibility",
        "question_ko": "바구니에서 뽑을 수 있는 기회는 2번입니다. 바구니 속에 사과, 복숭아, 배, 참외, 딸기가 각각 1개씩 들어가있는 바구니에서 차례를 고려하여 과일을 뽑는다면, 가능한 경우의 수는 몇 가지입니까?",
        "question_en": "You have 2 chances to draw from the basket. How many ways exist to draw a fruit from a basket containing 1 apple, 1 peach, 1 pear, 1 melon, and 1 strawberry while also considering the order of draw?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 복숭아 배 참외 딸기 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] apple peach pear melon strawberry [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '복숭아'\nvar_c = '배'\nvar_d = '참외'\nvar_e = '딸기'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nprint(int(var_h))",
        "solution_code_en": "var_a = 'apple'\nvar_b = 'peach'\nvar_c = 'pear'\nvar_d = 'melon'\nvar_e = 'strawberry'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nprint(int(var_h))"
    },
    "4066": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.3에서 0.4보다 크거나 같은 수 중 가장 작거나 같은 수는?",
        "question_en": "Which number is less than or equal to 0.8, 1/2, 0.3 and greater than or equal to 0.4?",
        "answer_ko": "0.50",
        "answer_en": "0.5",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.3 [OP_LIST_EOL] 0.4 [OP_LIST_MORE_EQUAL] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.3 [OP_LIST_EOL] 0.4 [OP_LIST_MORE_EQUAL] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.4\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nprint('{:.2f}'.format(round(var_f+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.4\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nprint('{:.2f}'.format(round(var_f+1e-10,2)))"
    },
    "4067": {
        "category": "Correspondence",
        "question_ko": "7을 어떤 수에서 뺐더니 결과로 9를 얻었습니다. 5를 어떤 수에 곱하면?",
        "question_en": "Subtracting 7 from a number gives 9 as a result. What is the result of the number being multiplied by 5?",
        "answer_ko": "80",
        "answer_en": "80",
        "solution_abst_ko": "9 7 [OP_ADD] 5 [OP_MUL]",
        "solution_abst_en": "9 7 [OP_ADD] 5 [OP_MUL]",
        "solution_code_ko": "var_a = 9\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "4068": {
        "category": "Possibility",
        "question_ko": "0, 2, 4, 6 중에서 3개 뽑아 한 번씩만 사용하여 세 자리 수를 만들려고 합니다. 만들 수 있는 가장 큰 수와 가장 작은 수의 합을 구하시오.",
        "question_en": "You want to create a three-digit number by using three from 0, 2, 4, and 6 and using them only once. Find the value of the sum of the largest and smallest possible numbers.",
        "answer_ko": "846",
        "answer_en": "846",
        "solution_abst_ko": "[OP_LIST_SOL] 0 2 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 0 2 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 0\nvar_b = 2\nvar_c = 4\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 0\nvar_b = 2\nvar_c = 4\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))"
    },
    "4069": {
        "category": "Geometry",
        "question_ko": "윗변이 12센티미터(㎝)이고, 아랫변은 윗변보다 4센티미터(㎝) 더 긴 사다리꼴이 있습니다. 이 사다리꼴의 높이가 10센티미터(㎝)일 때 넓이는 몇 제곱센티미터입니까?",
        "question_en": "There is a trapezoid with an upper side of 12 centimeters (cm) and a lower side that is 4 centimeters (cm) longer than the upper side. If the height of this trapezoid is 10 centimeters (cm), how many square centimeters (cm2) is its area?",
        "answer_ko": "140",
        "answer_en": "140",
        "solution_abst_ko": "12 12 4 [OP_ADD] [OP_ADD] 10 [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "12 12 4 [OP_ADD] [OP_ADD] 10 [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 12\nvar_c = 4\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nvar_f = 10\nvar_g = var_e * var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 12\nvar_b = 12\nvar_c = 4\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nvar_f = 10\nvar_g = var_e * var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "4070": {
        "category": "Arithmetic calculation",
        "question_ko": "동물원에서 (가) 동물의 암컷 35마리를 기릅니다. 암컷은 수컷보다 7마리가 적습니다. (가) 동물은 모두 몇 마리 있습니까?",
        "question_en": "There are 35 female (a) animals at the zoo. The number of female animals is 7 less than the male animals. How many (a) animals are there in all?",
        "answer_ko": "77",
        "answer_en": "77",
        "solution_abst_ko": "35 35 7 [OP_ADD] [OP_ADD]",
        "solution_abst_en": "35 35 7 [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 35\nvar_b = 35\nvar_c = 7\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 35\nvar_b = 35\nvar_c = 7\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "4071": {
        "category": "Arithmetic calculation",
        "question_ko": "200그램(g)이 담긴 컵의 소금물 농도는 25%입니다. 300그램(g)이 담긴 다른 컵에는 소금 60그램(g)이 들어있습니다. 두 컵의 소금물을 섞었을 때 소금물의 농도는 몇 %가 될까요?",
        "question_en": "The salt water concentration in a 200-gram (g) cup is 25%. Another cup containing 300 grams (g) contains 60 grams (g) of salt. What is the concentration of salt water when two cups of salt water are mixed?",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "200 25 100 [OP_DIV] [OP_MUL] 60 [OP_ADD] 200 300 [OP_ADD] [OP_DIV] 100 [OP_MUL]",
        "solution_abst_en": "200 25 100 [OP_DIV] [OP_MUL] 60 [OP_ADD] 200 300 [OP_ADD] [OP_DIV] 100 [OP_MUL]",
        "solution_code_ko": "var_a = 200\nvar_b = 25\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 60\nvar_g = var_e + var_f\nvar_h = 200\nvar_i = 300\nvar_j = var_h + var_i\nvar_k = var_g / var_j\nvar_l = 100\nvar_m = var_k * var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 200\nvar_b = 25\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 60\nvar_g = var_e + var_f\nvar_h = 200\nvar_i = 300\nvar_j = var_h + var_i\nvar_k = var_g / var_j\nvar_l = 100\nvar_m = var_k * var_l\nprint(int(var_m))"
    },
    "4072": {
        "category": "Comparison",
        "question_ko": "은지네 반 학생들은 (가) 운동을 할 때마다 3줄로 서고, 각 줄마다 학생 수가 같습니다. 은지는 항상 어느 한 줄의 앞에서 3번째, 뒤에서 6번째에 섭니다. 은지네 반 학생은 모두 몇 명입니까?",
        "question_en": "The students in Eunji's class stand in three lines with the same number of students in each line each time they do exercise (A). Eunji is always 3rd from the front and 6th from the back in a row. How many students are there in Eunji's class?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "3 6 [OP_ADD] 1 [OP_SUB] 3 [OP_MUL]",
        "solution_abst_en": "3 6 [OP_ADD] 1 [OP_SUB] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 3\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "4073": {
        "category": "Correspondence",
        "question_ko": "서로 다른 세 수 A, B, C가 있습니다. 세 자리 수끼리의 덧셈식 ABC+ABC+ABC=954에서 A를 구하시오.",
        "question_en": "There are three different numbers A, B and C. Find A from the three-digit addition formula ABC+ABC+ABC=954.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "ABC+ABC+ABC=954 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "ABC+ABC+ABC=954 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'ABC+ABC+ABC=954'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'ABC+ABC+ABC=954'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "4074": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 45를 더하고 2를 나눈 다음 다시 2로 나누고 45를 더한 값이 85이다. 어떤 수를 구하시오.",
        "question_en": "Add 45 to a number, divide by 2, then divide by 2 again and add 45 to get 85. Find this number.",
        "answer_ko": "115",
        "answer_en": "115",
        "solution_abst_ko": "85 45 [OP_SUB] 2 [OP_MUL] 2 [OP_MUL] 45 [OP_SUB]",
        "solution_abst_en": "85 45 [OP_SUB] 2 [OP_MUL] 2 [OP_MUL] 45 [OP_SUB]",
        "solution_code_ko": "var_a = 85\nvar_b = 45\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = 45\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 85\nvar_b = 45\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = 45\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "4075": {
        "category": "Possibility",
        "question_ko": "A, B, C, D, E, F 6명을 한 줄로 세울 때, C, D, E를 서로 이웃하게 하여 세우는 경우의 수를 구하시오.",
        "question_en": "When 6 people A, B, C, D, E, and F are to be lined up in a line, find the number of ways to put C, D, E next to each other.",
        "answer_ko": "144",
        "answer_en": "144",
        "solution_abst_ko": "[OP_LIST_SOL] A B C D E F [OP_LIST_EOL] [OP_LIST_SOL] B C [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] C D E [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D E F [OP_LIST_EOL] [OP_LIST_SOL] B C [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] C D E [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nvar_f = 'F'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 'B'\nvar_h = 'C'\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_i = len(list_c)\nvar_j = len(list_c)\nvar_k = 1\nvar_i = int(var_i)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_i-i)\nvar_l = 'C'\nvar_m = 'D'\nvar_n = 'E'\nlist_d= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_d.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_d.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_d.append(var_l)\nlist_d.reverse()\nvar_o = len(list_d)\nvar_p = len(list_d)\nvar_q = 1\nvar_o = int(var_o)\nvar_p = int(var_p)\nfor i, elem in enumerate(range(var_p)):\n    var_q = var_q * (var_o-i)\nvar_r = var_k * var_q\nprint(int(var_r))",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nvar_f = 'F'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 'B'\nvar_h = 'C'\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_i = len(list_c)\nvar_j = len(list_c)\nvar_k = 1\nvar_i = int(var_i)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_i-i)\nvar_l = 'C'\nvar_m = 'D'\nvar_n = 'E'\nlist_d= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_d.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_d.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_d.append(var_l)\nlist_d.reverse()\nvar_o = len(list_d)\nvar_p = len(list_d)\nvar_q = 1\nvar_o = int(var_o)\nvar_p = int(var_p)\nfor i, elem in enumerate(range(var_p)):\n    var_q = var_q * (var_o-i)\nvar_r = var_k * var_q\nprint(int(var_r))"
    },
    "4076": {
        "category": "Possibility",
        "question_ko": "3자리 숫자를 만들기 위해 0, 1, 3, 5 중에서 하나씩 뽑으려고 합니다. 만들 수 있는 수 중에서 가장 큰 수와 가장 작은 수를 뽑아서 더하시오.",
        "question_en": "I am trying to draw one out of 0, 1, 3, and 5 to make a 3-digit number. Add the largest and smallest possible numbers.",
        "answer_ko": "634",
        "answer_en": "634",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 3 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 3 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 3\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 3\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))"
    },
    "4077": {
        "category": "Possibility",
        "question_ko": "초록색 공 1개와 구분이 되지 않는 노란색 공 3개가 있습니다. 이 공 4개를 서로 다르게 한 줄로 놓는 방법은 모두 몇 가지 입니까?",
        "question_en": "There are 1 green ball and 3 indistinguishable yellow balls. How many different ways can you place these 4 balls in a row?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "1 3 [OP_ADD] 1 3 [OP_ADD] [OP_PERM] 3 3 [OP_PERM] [OP_DIV]",
        "solution_abst_en": "1 3 [OP_ADD] 1 3 [OP_ADD] [OP_PERM] 3 3 [OP_PERM] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = 1\nvar_c = int(var_c)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_c-i)\nvar_h = 3\nvar_i = 3\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nvar_k = var_g / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = 1\nvar_c = int(var_c)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_c-i)\nvar_h = 3\nvar_i = 3\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nvar_k = var_g / var_j\nprint(int(var_k))"
    },
    "4078": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 10, 11, 12, 13이 있습니다. 그 중 2번째로 큰 수는 무엇입니까?",
        "question_en": "When there are four numbers 10, 11, 12, and 13, which number is the second largest?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 2 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 2 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nprint(int(var_f))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nprint(int(var_f))"
    },
    "4079": {
        "category": "Possibility",
        "question_ko": "장난감 기차 4개에 7, 6, 8, 5가 적혀 있습니다. 이를 차례로 놓아 네 자리 수를 만들 때, 민들 수 있는 세 번째 큰 수와 세 번째 작은 수의 합은 얼마입니까?",
        "question_en": "The four toy trains are numbered 7, 6, 8, and 5. When you put them in order to make a four-digit number, what is the sum of the third largest number and the third smallest number you can make?",
        "answer_ko": "14443",
        "answer_en": "14443",
        "solution_abst_ko": "[OP_LIST_SOL] 7 6 8 5 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 7 6 8 5 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 7\nvar_b = 6\nvar_c = 8\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 7\nvar_b = 6\nvar_c = 8\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))"
    },
    "4080": {
        "category": "Comparison",
        "question_ko": "각 줄마다 있는 자동차의 수는 같습니다. 빨간색 자동차는 앞에서 14번째 줄, 왼쪽에서 19번째 열, 뒤에서 11번째 줄, 오른쪽에서 16번째 열일때 자동차는 모두 몇 대입니까?",
        "question_en": "There are the same number of cars in each row. Red cars are in the 14th row from the front, 19th row from the left, 11th row from the back, and 16th row from the right. How many cars are there in total?",
        "answer_ko": "816",
        "answer_en": "816",
        "solution_abst_ko": "19 16 [OP_ADD] 1 [OP_SUB] 14 11 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "19 16 [OP_ADD] 1 [OP_SUB] 14 11 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 19\nvar_b = 16\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 14\nvar_g = 11\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 19\nvar_b = 16\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 14\nvar_g = 11\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))"
    },
    "4081": {
        "category": "Comparison",
        "question_ko": "민지는 0.74미터(m), 승연은 13/20미터(m), 혜수는 4/5미터(m)의 색 테이프를 가지고 있다. 누가 가장 긴 색 테이프를 가지고 있습니까?",
        "question_en": "Minji has 0.74 meters (m), Seungyeon has 13/20 meters (m), and Hyesu has 4/5 meters (m) of colored tape. Who has the longest colored tape?",
        "answer_ko": "혜수",
        "answer_en": "Hyesu",
        "solution_abst_ko": "[OP_LIST_SOL] 민지 승연 혜수 [OP_LIST_EOL] [OP_LIST_SOL] 0.74 13 20 [OP_DIV] 4 5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Minji Seungyeon Hyesu [OP_LIST_EOL] [OP_LIST_SOL] 0.74 13 20 [OP_DIV] 4 5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '민지'\nvar_b = '승연'\nvar_c = '혜수'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.74\nvar_e = 13\nvar_f = 20\nvar_g = var_e / var_f\nvar_h = 4\nvar_i = 5\nvar_j = var_h / var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'Minji'\nvar_b = 'Seungyeon'\nvar_c = 'Hyesu'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.74\nvar_e = 13\nvar_f = 20\nvar_g = var_e / var_f\nvar_h = 4\nvar_i = 5\nvar_j = var_h / var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "4082": {
        "category": "Geometry",
        "question_ko": "가로가 112센티미터(㎝), 세로가 63센티미터(㎝)인 직사각형 모양의 나무판자를 잘라 한 변의 길이가 7센티미터(㎝)인 정사각형 모양의 나무판자 조각을 만들려고 합니다. 모두 몇 개를 만들 수 있습니까?",
        "question_en": "You are going to cut a rectangular wooden plank which is 112 centimeters (cm) wide and 63 centimeters (cm) long to make square wooden planks with a side length of 7 centimeters (cm). How many can you make in total?",
        "answer_ko": "144",
        "answer_en": "144",
        "solution_abst_ko": "112 7 [OP_FDIV] 63 7 [OP_FDIV] [OP_MUL]",
        "solution_abst_en": "112 7 [OP_FDIV] 63 7 [OP_FDIV] [OP_MUL]",
        "solution_code_ko": "var_a = 112\nvar_b = 7\nvar_c = var_a // var_b\nvar_d = 63\nvar_e = 7\nvar_f = var_d // var_e\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 112\nvar_b = 7\nvar_c = var_a // var_b\nvar_d = 63\nvar_e = 7\nvar_f = var_d // var_e\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "4083": {
        "category": "Comparison",
        "question_ko": "동균, 영탁, 승환은 과자를 가지고 있습니다. 동균이가 영탁이보다 더 많고 승환이 동균이보다 더 많다면 누가 쿠키를 가장 많이 가지고 있을까요?",
        "question_en": "Dongkyun, Youngtak, and Seunghwan have snacks. If Dongkyun has more cookies than Youngtak and Seunghwan has more than Dongkyun, who has the most cookies?",
        "answer_ko": "승환",
        "answer_en": "Seunghwan",
        "solution_abst_ko": "[OP_LIST_SOL] 동균 영탁 승환 [OP_LIST_EOL] [OP_LIST_SOL] 동균 영탁 > 승환 동균 > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Dongkyun Youngtak Seunghwan [OP_LIST_EOL] [OP_LIST_SOL] Dongkyun Youngtak > Seunghwan Dongkyun > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '동균'\nvar_b = '영탁'\nvar_c = '승환'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '동균'\nvar_e = '영탁'\nvar_f = '>'\nvar_g = '승환'\nvar_h = '동균'\nvar_i = '>'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(var_k)",
        "solution_code_en": "var_a = 'Dongkyun'\nvar_b = 'Youngtak'\nvar_c = 'Seunghwan'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'Dongkyun'\nvar_e = 'Youngtak'\nvar_f = '>'\nvar_g = 'Seunghwan'\nvar_h = 'Dongkyun'\nvar_i = '>'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(var_k)"
    },
    "4084": {
        "category": "Arithmetic calculation",
        "question_ko": "꽃을 지민이는 6송이, 석진이는 14송이, 민영이는 9송이, 태형이는 15송이를 심었습니다. 꽃을 가장 많이 심은 사람은 2번째로 적게 심은 사람보다 몇 송이 더 많이 심었습니까?",
        "question_en": "Jimin planted 6 flowers, Seokjin planted 14 flowers, Minyoung planted 9 flowers, and Taehyung planted 15 flowers. How many more flowers did the person who planted the most plants than the person who planted the second least?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 6 14 9 15 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 6 14 9 15 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 6\nvar_b = 14\nvar_c = 9\nvar_d = 15\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 6\nvar_b = 14\nvar_c = 9\nvar_d = 15\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))"
    },
    "4085": {
        "category": "Geometry",
        "question_ko": "직사각형 모양의 담벼락이 있습니다. 이 담벼락의 가로 길이는 5.4미터(m)이고, 세로 길이는 2.5미터(m)일 때 넓이는 몇 제곱미터(㎡)인지 구하시오.",
        "question_en": "There is a rectangular wall. If the width of this wall is 5.4 meters (m) and the length is 2.5 meters (m), what is the area in square meters (m2)?",
        "answer_ko": "13.50",
        "answer_en": "13.5",
        "solution_abst_ko": "5.4 2.5 [OP_MUL]",
        "solution_abst_en": "5.4 2.5 [OP_MUL]",
        "solution_code_ko": "var_a = 5.4\nvar_b = 2.5\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 5.4\nvar_b = 2.5\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "4086": {
        "category": "Arithmetic calculation",
        "question_ko": "지민이는 책을 27권 가지고 있었습니다. 아버지가 책을 8권 더 사주고 어머니가 12권을 더 사주셨습니다. 지민이가 가진 책은 처음보다 몇 권 더 많아졌습니까?",
        "question_en": "Jimin had 27 books. His father bought 8 more books and his mother bought 12 more books. How many books does Jimin have now compared to the beginning?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "8 12 [OP_ADD]",
        "solution_abst_en": "8 12 [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 12\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 8\nvar_b = 12\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "4087": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 36을 더했더니 결과가 71이 나왔습니다. 어떤 수에 10을 더하면?",
        "question_en": "Adding 36 to a number gives 71. How much is a number plus 10?",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "71 36 [OP_SUB] 10 [OP_ADD]",
        "solution_abst_en": "71 36 [OP_SUB] 10 [OP_ADD]",
        "solution_code_ko": "var_a = 71\nvar_b = 36\nvar_c = var_a - var_b\nvar_d = 10\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 71\nvar_b = 36\nvar_c = var_a - var_b\nvar_d = 10\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "4088": {
        "category": "Correspondence",
        "question_ko": "A에 19를 더했더니 47이 되었습니다. A는 얼마입니까?",
        "question_en": "Adding 19 to A gives 47. How much is A?",
        "answer_ko": "28",
        "answer_en": "28",
        "solution_abst_ko": "47 19 [OP_SUB]",
        "solution_abst_en": "47 19 [OP_SUB]",
        "solution_code_ko": "var_a = 47\nvar_b = 19\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 47\nvar_b = 19\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "4089": {
        "category": "Arithmetic calculation",
        "question_ko": "연못 안에 있는 개구리는 12마리, 연못 밖에 있는 개구리는 6마리입니다. 개구리는 모두 몇 마리 있습니까?",
        "question_en": "There are 12 frogs inside the pond and 6 frogs outside the pond. How many frogs are there in all?",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "12 6 [OP_ADD]",
        "solution_abst_en": "12 6 [OP_ADD]",
        "solution_code_ko": "var_a = 12\nvar_b = 6\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 12\nvar_b = 6\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "4090": {
        "category": "Possibility",
        "question_ko": "2, 6, 9를 한 번만 사용하여 세 자리 수를 만들었을 때, 가장 큰 수는 얼마인가?",
        "question_en": "If 2, 6, and 9 are used only once to form a three-digit number, what is the largest number?",
        "answer_ko": "962",
        "answer_en": "962",
        "solution_abst_ko": "[OP_LIST_SOL] 2 6 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 2 6 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 2\nvar_b = 6\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))",
        "solution_code_en": "var_a = 2\nvar_b = 6\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))"
    },
    "4091": {
        "category": "Arithmetic calculation",
        "question_ko": "철사 4밀리미터(㎜)로 모빌을 1개 만들 수 있습니다. 철사 117.6밀리미터(㎜)로 같은 크기의 모빌을 여러개 만든 후 남은 철사는 몇 센티미터(㎝)입니까?",
        "question_en": "A mobile can be made with 4 millimetres (mm) of wire. After making several mobiles of the same size using 117.6 millimetres (mm) of wire, how many centimetres (cm) of wire are left?",
        "answer_ko": "0.16",
        "answer_en": "0.16",
        "solution_abst_ko": "117.6 4 [OP_MOD] 10 [OP_DIV]",
        "solution_abst_en": "117.6 4 [OP_MOD] 10 [OP_DIV]",
        "solution_code_ko": "var_a = 117.6\nvar_b = 4\nvar_c = var_a % var_b\nvar_d = 10\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 117.6\nvar_b = 4\nvar_c = var_a % var_b\nvar_d = 10\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "4092": {
        "category": "Arithmetic calculation",
        "question_ko": "정혁이의 나이는 삼촌의 나이의 1/4보다 1살이 적고 삼촌의 나이는 정혁이의 나이의 5배보다 5살이 적을 때, 정혁이의 나이는 몇 살입니까?",
        "question_en": "If Jeong-hyeok's age is 1 year less than 1/4 of his uncle's age and his uncle's age is 5 years less than 5 times Jeong-hyeok's age, how old is Jeong-hyeok?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "1/4 5 [OP_MUL] 1 [OP_ADD] 1/4 5 [OP_MUL] 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "1/4 5 [OP_MUL] 1 [OP_ADD] 1/4 5 [OP_MUL] 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 0.25\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 0.25\nvar_g = 5\nvar_h = var_f * var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 0.25\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 0.25\nvar_g = 5\nvar_h = var_f * var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e / var_j\nprint(int(var_k))"
    },
    "4093": {
        "category": "Geometry",
        "question_ko": "가로가 20센티미터(㎝)이고, 세로가 16센티미터(㎝)인 직사각형 모양의 종이에 반지름이 2센티미터(㎝)인 원을 겹치지 않게 그리면 몇 개까지 그릴 수 있습니까?",
        "question_en": "How many circles with a radius of 2 centimeters (cm) can be drawn on a piece of paper that is 20 centimeters (cm) wide and 16 centimeters (cm) long?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "20 2 2 [OP_MUL] [OP_FDIV] 16 2 2 [OP_MUL] [OP_FDIV] [OP_MUL]",
        "solution_abst_en": "20 2 2 [OP_MUL] [OP_FDIV] 16 2 2 [OP_MUL] [OP_FDIV] [OP_MUL]",
        "solution_code_ko": "var_a = 20\nvar_b = 2\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a // var_d\nvar_f = 16\nvar_g = 2\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = var_f // var_i\nvar_k = var_e * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 20\nvar_b = 2\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a // var_d\nvar_f = 16\nvar_g = 2\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = var_f // var_i\nvar_k = var_e * var_j\nprint(int(var_k))"
    },
    "4094": {
        "category": "Geometry",
        "question_ko": "정육면체 모양의 상자에서, 모서리의 개수는?",
        "question_en": "In a cube-shaped box, how many edges are there?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "4 3 [OP_MUL]",
        "solution_abst_en": "4 3 [OP_MUL]",
        "solution_code_ko": "var_a = 4\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "4095": {
        "category": "Comparison",
        "question_ko": "총 4개의 숫자 0.8, 1/2, 0.5, 1/3이 있습니다. 이 중 3보다 작거나 같은 수를 모두 더하면 얼마인가요?",
        "question_en": "There are 4 numbers: 0.8, 1/2, 0.5, and 1/3. What is the sum of all numbers less than or equal to 3?",
        "answer_ko": "2.13",
        "answer_en": "2.13",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.5 1/3 [OP_LIST_EOL] 3 [OP_LIST_LESS_EQUAL] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.5 1/3 [OP_LIST_EOL] 3 [OP_LIST_LESS_EQUAL] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.5\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = []\nfor i in list_a:\n    if i <= var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint('{:.2f}'.format(round(var_f+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.5\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = []\nfor i in list_a:\n    if i <= var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint('{:.2f}'.format(round(var_f+1e-10,2)))"
    },
    "4096": {
        "category": "Arithmetic calculation",
        "question_ko": "리본 고리를 만들기 위해 리본을 0.82킬로미터(㎞)씩 자르려고 합니다. 리본 53.73킬로미터(㎞)로 고리를 만들고 남는 리본은 몇 미터(m)인지 구하시오.",
        "question_en": "To make a ribbon loop, you want to cut the ribbons into 0.82 kilometers (km) long pieces. Find the length of the remaining ribbon length after making ribbon loops out of 53.73 kilometers (km) of ribbon.",
        "answer_ko": "430",
        "answer_en": "430",
        "solution_abst_ko": "53.73 0.82 [OP_MOD] 1000 [OP_MUL]",
        "solution_abst_en": "53.73 0.82 [OP_MOD] 1000 [OP_MUL]",
        "solution_code_ko": "var_a = 53.73\nvar_b = 0.82\nvar_c = var_a % var_b\nvar_d = 1000\nvar_e = var_c * var_d\nprint(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))",
        "solution_code_en": "var_a = 53.73\nvar_b = 0.82\nvar_c = var_a % var_b\nvar_d = 1000\nvar_e = var_c * var_d\nprint(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))"
    },
    "4097": {
        "category": "Arithmetic calculation",
        "question_ko": "두 자리 수끼리의 덧셈에서 더해지는 수의 일의 자리 숫자 9를 2로 잘못 보았습니다. 또 더하는 수의 십의 자리 숫자 3을 6으로 잘못 보고 계산하였더니 그 값이 119가 되었습니다. 바르게 계산한 결과를 구하시오.",
        "question_en": "In two-digit addition, the digit 9 in the ones place of the number added was incorrectly viewed as 2. Also, when the number 3 in the tens place of the number being added was mistakenly calculated as 6, the value was 119. Find the result of the correct calculation.",
        "answer_ko": "96",
        "answer_en": "96",
        "solution_abst_ko": "119 1 9 2 [OP_SUB] [OP_MUL] [OP_ADD] 10 3 6 [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_abst_en": "119 1 9 2 [OP_SUB] [OP_MUL] [OP_ADD] 10 3 6 [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 119\nvar_b = 1\nvar_c = 9\nvar_d = 2\nvar_e = var_c - var_d\nvar_f = var_b * var_e\nvar_g = var_a + var_f\nvar_h = 10\nvar_i = 3\nvar_j = 6\nvar_k = var_i - var_j\nvar_l = var_h * var_k\nvar_m = var_g + var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 119\nvar_b = 1\nvar_c = 9\nvar_d = 2\nvar_e = var_c - var_d\nvar_f = var_b * var_e\nvar_g = var_a + var_f\nvar_h = 10\nvar_i = 3\nvar_j = 6\nvar_k = var_i - var_j\nvar_l = var_h * var_k\nvar_m = var_g + var_l\nprint(int(var_m))"
    },
    "4098": {
        "category": "Geometry",
        "question_ko": "한 모서리의 길이가 12센티미터(㎝)인 주사위에 남는 공간이 없이 정사각형 모양의 색종이를 붙였더니 54장이 되었습니다. 이 색종이의 한 변의 길이를 구하시오.",
        "question_en": "54 square-shaped pieces of colored paper were attached to dice with a side of 12 centimeters (cm) and then there was no empty space. Find the length of one side of this colored paper.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "12 2 [OP_POW] 6 [OP_MUL] 54 [OP_DIV] 1/2 [OP_POW]",
        "solution_abst_en": "12 2 [OP_POW] 6 [OP_MUL] 54 [OP_DIV] 1/2 [OP_POW]",
        "solution_code_ko": "var_a = 12\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = var_c * var_d\nvar_f = 54\nvar_g = var_e / var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 12\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = var_c * var_d\nvar_f = 54\nvar_g = var_e / var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))"
    },
    "4099": {
        "category": "Arithmetic calculation",
        "question_ko": "농장에서 닭 49마리와 오리 37마리를 기릅니다. 오리와 토끼의 수를 합하면 닭보다 9마리 많습니다. 토끼는 몇 마리입니까?",
        "question_en": "A farmer raises 49 chickens and 37 ducks on a farm. The combined number of ducks and rabbits is 9 more than the number of chickens. How many rabbits are there?",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "49 9 [OP_ADD] 37 [OP_SUB]",
        "solution_abst_en": "49 9 [OP_ADD] 37 [OP_SUB]",
        "solution_code_ko": "var_a = 49\nvar_b = 9\nvar_c = var_a + var_b\nvar_d = 37\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 49\nvar_b = 9\nvar_c = var_a + var_b\nvar_d = 37\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "4100": {
        "category": "Geometry",
        "question_ko": "반지름이 3센티미터(㎝)인 구를 칠하는데 사용되는 페인트와 어떤 원을 칠하는데 사용되는 페인트의 양이 같다. 원의 반지름을 구하시오.",
        "question_en": "The amount of paint used to paint a sphere with a radius of 3 centimeters (cm) equals the amount of paint used to paint a circle. Find the radius of the circle.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "4 3 2 [OP_POW] [OP_MUL] 1/2 [OP_POW]",
        "solution_abst_en": "4 3 2 [OP_POW] [OP_MUL] 1/2 [OP_POW]",
        "solution_code_ko": "var_a = 4\nvar_b = 3\nvar_c = 2\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 0.5\nvar_g = var_e ** var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 3\nvar_c = 2\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 0.5\nvar_g = var_e ** var_f\nprint(int(var_g))"
    },
    "4101": {
        "category": "Comparison",
        "question_ko": "1.4, 9/10, 1.2, 0.5, 13/10 5개 숫자 중에서 1.1보다 작거나 같은 숫자를 골라 크거나 같은 순서대로 나열했을 때, 가장 앞에 있는 숫자는 무엇입니까?",
        "question_en": "Among the five numbers 1.4, 9/10, 1.2, 0.5, and 13/10, you picked the number that is smaller than or equal to 1.1. And you arranged them in order of their size. Which number is in the first place?",
        "answer_ko": "0.90",
        "answer_en": "0.9",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS_EQUAL] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS_EQUAL] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i <= var_f:\n        list_b.append(i)\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nprint('{:.2f}'.format(round(var_h+1e-10,2)))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i <= var_f:\n        list_b.append(i)\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nprint('{:.2f}'.format(round(var_h+1e-10,2)))"
    },
    "4102": {
        "category": "Comparison",
        "question_ko": "20명의 학생들의 키를 비교하고 있습니다. 윤기보다 큰 학생이 11명일 때, 윤기보다 작은 학생은 모두 몇 명입니까?",
        "question_en": "You are comparing the heights of 20 students. If there are 11 students shorter than Yoongi, how many students are taller than Yoongi?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "20 11 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "20 11 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "4103": {
        "category": "Correspondence",
        "question_ko": "양초가 현재 48센티미터(㎝)라고 한다. 처음에는 지금의 길이에 1.33배였다고 한다면 처음 양초의 길이를 구하시오.",
        "question_en": "This candle is currently 48 centimeters (cm) long. If it was originally 1.33 times the current length, find the length of the original candle.",
        "answer_ko": "63.84",
        "answer_en": "63.84",
        "solution_abst_ko": "48 1.33 [OP_MUL]",
        "solution_abst_en": "48 1.33 [OP_MUL]",
        "solution_code_ko": "var_a = 48\nvar_b = 1.33\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 48\nvar_b = 1.33\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "4104": {
        "category": "Arithmetic calculation",
        "question_ko": "축구 경기를 보러 온 사람 중 성인은 1518명이었고, 이 중에서 여성은 536명이었습니다. 학생은 성인보다 525명이 더 많았고, 이 중에서 남성은 1257명이었습니다. 축구 경기를 보러 온 여성은 몇 명입니까?",
        "question_en": "Among the people who came to watch the soccer game, there were 1518 adults, and 536 of them were women. There were 525 more students than adults, 1257 of whom were male. How many women came to watch a soccer game?",
        "answer_ko": "1322",
        "answer_en": "1322",
        "solution_abst_ko": "1518 525 [OP_ADD] 1257 [OP_SUB] 536 [OP_ADD]",
        "solution_abst_en": "1518 525 [OP_ADD] 1257 [OP_SUB] 536 [OP_ADD]",
        "solution_code_ko": "var_a = 1518\nvar_b = 525\nvar_c = var_a + var_b\nvar_d = 1257\nvar_e = var_c - var_d\nvar_f = 536\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1518\nvar_b = 525\nvar_c = var_a + var_b\nvar_d = 1257\nvar_e = var_c - var_d\nvar_f = 536\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "4105": {
        "category": "Arithmetic calculation",
        "question_ko": "상의와 하의 잠옷 세트를 3세트를 사고 21000원을 냈습니다. 상의가 하의보다 300원 비싸다고 할 때, 하의의 가격은 얼마인지 구하시오.",
        "question_en": "I bought 3 sets of top and bottom pajama sets and paid 21,000 won. If the top costs 300 won more than the bottom, what is the price of the bottom?",
        "answer_ko": "3350",
        "answer_en": "3350",
        "solution_abst_ko": "21000 3 [OP_DIV] 300 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "21000 3 [OP_DIV] 300 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 21000\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 300\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 21000\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 300\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "4106": {
        "category": "Comparison",
        "question_ko": "서로 다른 세 수 A, B, C가 있습니다. A는 18보다 38 크고, B는 A에서 26을 뺀 수입니다. C가 B를 3으로 나눈 몫과 같다면, 세 수 중 가장 작은 수는 무엇입니까?",
        "question_en": "There are three different numbers A, B, and C. A is 38 greater than 18, and B is A minus 26. If C is equal to the quotient of B divided by 3, which of the three numbers is the smallest?",
        "answer_ko": "C",
        "answer_en": "C",
        "solution_abst_ko": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] 18 38 [OP_ADD] 18 38 [OP_ADD] 26 [OP_SUB] 18 38 [OP_ADD] 26 [OP_SUB] 3 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] 18 38 [OP_ADD] 18 38 [OP_ADD] 26 [OP_SUB] 18 38 [OP_ADD] 26 [OP_SUB] 3 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 18\nvar_e = 38\nvar_f = var_d + var_e\nvar_g = 18\nvar_h = 38\nvar_i = var_g + var_h\nvar_j = 26\nvar_k = var_i - var_j\nvar_l = 18\nvar_m = 38\nvar_n = var_l + var_m\nvar_o = 26\nvar_p = var_n - var_o\nvar_q = 3\nvar_r = var_p / var_q\nlist_b= []\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_s = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_t = list_c[var_s-1]\nvar_u = list_b.index(var_t)+1\nvar_v = list_a[var_u-1]\nprint(var_v)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 18\nvar_e = 38\nvar_f = var_d + var_e\nvar_g = 18\nvar_h = 38\nvar_i = var_g + var_h\nvar_j = 26\nvar_k = var_i - var_j\nvar_l = 18\nvar_m = 38\nvar_n = var_l + var_m\nvar_o = 26\nvar_p = var_n - var_o\nvar_q = 3\nvar_r = var_p / var_q\nlist_b= []\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_s = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_t = list_c[var_s-1]\nvar_u = list_b.index(var_t)+1\nvar_v = list_a[var_u-1]\nprint(var_v)"
    },
    "4107": {
        "category": "Correspondence",
        "question_ko": "B+B+A=814.8입니다. B를 10배하면 A와 같습니다. 소수점을 포함하여 A-B의 값을 구하시오",
        "question_en": "B+B+A=814.8. Multiplying B by 10 equals A. Find the value of A-B including the decimal point.",
        "answer_ko": "34.92",
        "answer_en": "34.92",
        "solution_abst_ko": "814.8 10 10 [OP_ADD] 1 [OP_ADD] [OP_DIV] 814.8 10 10 [OP_ADD] 1 [OP_ADD] [OP_DIV] 10 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "814.8 10 10 [OP_ADD] 1 [OP_ADD] [OP_DIV] 814.8 10 10 [OP_ADD] 1 [OP_ADD] [OP_DIV] 10 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 814.8\nvar_b = 10\nvar_c = 10\nvar_d = var_b + var_c\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = var_a / var_f\nvar_h = 814.8\nvar_i = 10\nvar_j = 10\nvar_k = var_i + var_j\nvar_l = 1\nvar_m = var_k + var_l\nvar_n = var_h / var_m\nvar_o = 10\nvar_p = var_n / var_o\nvar_q = var_g - var_p\nprint('{:.2f}'.format(round(var_q+1e-10,2)))",
        "solution_code_en": "var_a = 814.8\nvar_b = 10\nvar_c = 10\nvar_d = var_b + var_c\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = var_a / var_f\nvar_h = 814.8\nvar_i = 10\nvar_j = 10\nvar_k = var_i + var_j\nvar_l = 1\nvar_m = var_k + var_l\nvar_n = var_h / var_m\nvar_o = 10\nvar_p = var_n / var_o\nvar_q = var_g - var_p\nprint('{:.2f}'.format(round(var_q+1e-10,2)))"
    },
    "4108": {
        "category": "Comparison",
        "question_ko": "정국이는 0.8, 윤기는 1/2, 유정이는 0.9의 숫자카드를 갖고 있습니다. 0.3보다 작은 숫자카드를 가지고 있는 사람은 몇 명입니까?",
        "question_en": "Jungkook has a card with the number 0.8 on it, Yoongi has 1/2, and Yoojeong has 0.9. How many people have number cards less than 0.3?",
        "answer_ko": "0",
        "answer_en": "0",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 0.3 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 0.3 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.3\nlist_b = []\nfor i in list_a:\n    if i < var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.3\nlist_b = []\nfor i in list_a:\n    if i < var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "4109": {
        "category": "Arithmetic calculation",
        "question_ko": "29보다 크고 36보다 작은 두 자리 수는 모두 몇 개입니까?",
        "question_en": "How many two-digit numbers are there that are greater than 29 and less than 36?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "29 1 [OP_ADD] 36 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_LEN]",
        "solution_abst_en": "29 1 [OP_ADD] 36 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 29\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 36\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = len(list_a)\nprint(int(var_h))",
        "solution_code_en": "var_a = 29\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 36\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = len(list_a)\nprint(int(var_h))"
    },
    "4110": {
        "category": "Arithmetic calculation",
        "question_ko": "작년 할아버지가 71살 일 때, 정민이는 8살이였습니다. 올해 할아버지의 나이는 정민이 나이의 몇 배입니까?",
        "question_en": "When the grandpa's age was 71 last year, Jung-min was 8. Find how many times the grandpa's age is Jung-min's age this year.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "71 1 [OP_ADD] 8 1 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "71 1 [OP_ADD] 8 1 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 71\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 8\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = var_c / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 71\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 8\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = var_c / var_f\nprint(int(var_g))"
    },
    "4111": {
        "category": "Comparison",
        "question_ko": "놀이공원에 사람들이 한 줄서기를 하고 있습니다. 은지는 6번째로 놀이기구를 탈 수 있고 은지 뒤에 7명의 사람들이 있을 때 놀기기구를 타기위해 줄을 선 사람은 모두 몇 명인지 구하시오.",
        "question_en": "People are standing in a line at an amusement park. If Eunji is able to ride the ride in 6th place, and there are 7 people behind Eunji, how many people are in line to ride the ride?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "6 7 [OP_ADD]",
        "solution_abst_en": "6 7 [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "4112": {
        "category": "Possibility",
        "question_ko": "숫자 카드 6, 2, 5를 한 번씩 모두 사용하여 만든 가장 큰 세 자리 수와 가장 작은 세 자리 수의 차를 구하시오.",
        "question_en": "Find the difference between the largest three-digit number and the smallest three-digit number made by using the number cards 6, 2, and 5 all once.",
        "answer_ko": "650",
        "answer_en": "650",
        "solution_abst_ko": "[OP_LIST_SOL] 6 2 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] [OP_LIST_POP] 1 [OP_LIST_MIN] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "[OP_LIST_SOL] 6 2 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] [OP_LIST_POP] 1 [OP_LIST_MIN] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 1\nlist_d=list_a.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f - var_h\nvar_j = abs(var_i)\nprint(int(var_j))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 1\nlist_d=list_a.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f - var_h\nvar_j = abs(var_i)\nprint(int(var_j))"
    },
    "4113": {
        "category": "Possibility",
        "question_ko": "4개의 숫자 1, 5, 6, 9를 한 번씩 사용하여 백의 자리 숫자가 5인 두 번째 작은 세 자리 수를 구하시오.",
        "question_en": "Using 1, 5, 6, and 9 once, find the second smaller three-digit number whose hundreds digit is 5.",
        "answer_ko": "519",
        "answer_en": "519",
        "solution_abst_ko": "[OP_LIST_SOL] 1 5 6 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 100 5 [OP_LIST_SEARCH_FIXED_DIGIT] 2 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 5 6 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 100 5 [OP_LIST_SEARCH_FIXED_DIGIT] 2 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1\nvar_b = 5\nvar_c = 6\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 100\nvar_g = 5\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 2\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 5\nvar_c = 6\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 100\nvar_g = 5\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 2\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nprint(int(var_i))"
    },
    "4114": {
        "category": "Correspondence",
        "question_ko": "423에서 어떤 수를 뺐더니 421이 되었습니다. 어떤 수에 423을 곱한 값에 421을 더한 값을 구하시오.",
        "question_en": "You subtracted a particular number from 423 and it became 421. Find the number multiplied by 423 plus 421.",
        "answer_ko": "1267",
        "answer_en": "1267",
        "solution_abst_ko": "421 423 423 421 [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_abst_en": "421 423 423 421 [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 421\nvar_b = 423\nvar_c = 423\nvar_d = 421\nvar_e = var_c - var_d\nvar_f = var_b * var_e\nvar_g = var_a + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 421\nvar_b = 423\nvar_c = 423\nvar_d = 421\nvar_e = var_c - var_d\nvar_f = var_b * var_e\nvar_g = var_a + var_f\nprint(int(var_g))"
    },
    "4115": {
        "category": "Geometry",
        "question_ko": "정국이는 빨간 공 5개, 파란 공 4개, 노란 공 3개를 가지고 있습니다. 윤기가 정국이에게 빨간 공 1개를 주었을 때, 정국이가 가지고 있는 파란 공의 개수는?",
        "question_en": "Jungkook has 5 red balls, 4 blue balls, and 3 yellow balls. When Yoongi gives Jungkook 1 red ball, how many blue balls does Jungkook have?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "4",
        "solution_abst_en": "4",
        "solution_code_ko": "var_a = 4\nprint(int(var_a))",
        "solution_code_en": "var_a = 4\nprint(int(var_a))"
    },
    "4116": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이는 우유 14/3리터(L)를 1/7리터(L)짜리 병에 담으려고 하고, 석진이는 우유 15/6리터(L)를 1/8리터(L)짜리 병에 담으려고 합니다. 우유가 가득 차는 병은 모두 몇 개입니까?",
        "question_en": "Jungkook is trying to put 14/3 liters (l) of milk into several 1/7 liters (l) bottles, and Seokjin is trying to put 15/6 liters (l) of milk into several 1/8 liters (l) bottles. How many bottles can Jungkook and Seokjin fill with milk?",
        "answer_ko": "51",
        "answer_en": "51",
        "solution_abst_ko": "14/3 1/7 [OP_DIV] 0 [OP_FLOOR] 15/6 1/8 [OP_DIV] 0 [OP_FLOOR] [OP_ADD]",
        "solution_abst_en": "14/3 1/7 [OP_DIV] 0 [OP_FLOOR] 15/6 1/8 [OP_DIV] 0 [OP_FLOOR] [OP_ADD]",
        "solution_code_ko": "var_a = 4.666666666666667\nvar_b = 0.14285714285714285\nvar_c = var_a / var_b\nvar_d = 0\nvar_e=int((var_c//(10**(var_d-1)))*10**(var_d-1))\n\nvar_f = 2.5\nvar_g = 0.125\nvar_h = var_f / var_g\nvar_i = 0\nvar_j=int((var_h//(10**(var_i-1)))*10**(var_i-1))\n\nvar_k = var_e + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 4.666666666666667\nvar_b = 0.14285714285714285\nvar_c = var_a / var_b\nvar_d = 0\nvar_e=int((var_c//(10**(var_d-1)))*10**(var_d-1))\n\nvar_f = 2.5\nvar_g = 0.125\nvar_h = var_f / var_g\nvar_i = 0\nvar_j=int((var_h//(10**(var_i-1)))*10**(var_i-1))\n\nvar_k = var_e + var_j\nprint(int(var_k))"
    },
    "4117": {
        "category": "Arithmetic calculation",
        "question_ko": "초콜릿이 한 봉지에 156개씩 담겨 있습니다. 이 초콜릿 봉지 20개를 샀다면 초콜릿은 모두 몇 개인지 구하세요.",
        "question_en": "There are 156 chocolates in each bag. If you bought 20 bags of these chocolates, find how many chocolates there are in all.",
        "answer_ko": "3120",
        "answer_en": "3120",
        "solution_abst_ko": "156 20 [OP_MUL]",
        "solution_abst_en": "156 20 [OP_MUL]",
        "solution_code_ko": "var_a = 156\nvar_b = 20\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 156\nvar_b = 20\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "4118": {
        "category": "Comparison",
        "question_ko": "정국 앞에 2명이 있고, 정국 뒤에 4명이 있고, 각 행, 열의 인원수가 같다면 서있는 사람은 총 몇 명입니까?",
        "question_en": "If there are 2 people in front of Jungkook and 4 people behind Jungkook, and the number of people in each row and column is the same, how many people are there in total?",
        "answer_ko": "56",
        "answer_en": "56",
        "solution_abst_ko": "2 4 [OP_ADD] 1 [OP_ADD] 8 [OP_MUL]",
        "solution_abst_en": "2 4 [OP_ADD] 1 [OP_ADD] 8 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "4119": {
        "category": "Correspondence",
        "question_ko": "주머니 안에 구슬이 있습니다. 이 구슬을 3개씩 나누어 담으면 2개가 남고, 8개씩 나누어 담으면 5개가 남습니다. 이때 가능한 구슬의 개수 중 20번째로 작은 구슬의 개수를 구하시오.",
        "question_en": "There are marbles in the bag. Divide these marbles into groups of 3, so that you have 2 left, and divide them into groups of 8, so that you have 5 left. Find the 20th smallest number of possible marbles.",
        "answer_ko": "461",
        "answer_en": "461",
        "solution_abst_ko": "0 9999 1 [OP_LIST_ARANGE] 3 2 [OP_LIST_DIVIDE_AND_REMAIN] 8 5 [OP_LIST_DIVIDE_AND_REMAIN] 20 [OP_LIST_MIN]",
        "solution_abst_en": "0 9999 1 [OP_LIST_ARANGE] 3 2 [OP_LIST_DIVIDE_AND_REMAIN] 8 5 [OP_LIST_DIVIDE_AND_REMAIN] 20 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 0\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nvar_e = 2\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 8\nvar_g = 5\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 20\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nprint(int(var_i))",
        "solution_code_en": "var_a = 0\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nvar_e = 2\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 8\nvar_g = 5\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 20\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nprint(int(var_i))"
    },
    "4120": {
        "category": "Possibility",
        "question_ko": "숫자 2, 5, 6을 중복으로 사용하여 만들 수 있는 세 자리 수 중 가장 큰 수를 구하시오.",
        "question_en": "Find the largest three-digit number that can be formed by using the numbers 2, 5, and 6 when repetition is allowed.",
        "answer_ko": "666",
        "answer_en": "666",
        "solution_abst_ko": "[OP_LIST_SOL] 2 5 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 2 5 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 2\nvar_b = 5\nvar_c = 6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))",
        "solution_code_en": "var_a = 2\nvar_b = 5\nvar_c = 6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))"
    },
    "4121": {
        "category": "Correspondence",
        "question_ko": "172를 어떤 수로 나눈 몫은 172를 4로 나눈 몫에서 28을 뺀 값과 같다. 172를 어떤 수로 나눈 나머지가 7일 때,어떤 수를 구하시오.",
        "question_en": "The quotient of 172 divided by this number is equal to the quotient of 172 divided by 4 minus 28. Find the number when the remainder of 172 divided by this number is 7.",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "172 7 [OP_SUB] 172 4 [OP_DIV] 28 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "172 7 [OP_SUB] 172 4 [OP_DIV] 28 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 172\nvar_b = 7\nvar_c = var_a - var_b\nvar_d = 172\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = 28\nvar_h = var_f - var_g\nvar_i = var_c / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 172\nvar_b = 7\nvar_c = var_a - var_b\nvar_d = 172\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = 28\nvar_h = var_f - var_g\nvar_i = var_c / var_h\nprint(int(var_i))"
    },
    "4122": {
        "category": "Arithmetic calculation",
        "question_ko": "민지는 오전에 0.26리터(L)의 물을 마셨고 오후에 0.37리터(L)의 물을 마셨습니다. 민지가 하루 동안 마신 물은 몇 리터(L)인지 구하시오.",
        "question_en": "Minji drank 0.26 liters (L) of water in the morning and 0.37 liters (L) in the afternoon. Find how many liters (L) of water Minji drank during the day.",
        "answer_ko": "0.63",
        "answer_en": "0.63",
        "solution_abst_ko": "0.26 0.37 [OP_ADD]",
        "solution_abst_en": "0.26 0.37 [OP_ADD]",
        "solution_code_ko": "var_a = 0.26\nvar_b = 0.37\nvar_c = var_a + var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 0.26\nvar_b = 0.37\nvar_c = var_a + var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "4123": {
        "category": "Correspondence",
        "question_ko": "여섯 자리 수 14A56A는 4의 배수이면서 3의 배수입니다. 이러한 여섯 자리 수를 구하시오.",
        "question_en": "The six-digit number 14A56A is a multiple of 4 and also a multiple of 3. Find this six-digit number.",
        "answer_ko": "144564",
        "answer_en": "144564",
        "solution_abst_ko": "14A56A [OP_GEN_POSSIBLE_LIST] 3 [OP_LIST_DIVISIBLE] 4 [OP_LIST_DIVISIBLE] 1 [OP_LIST_GET]",
        "solution_abst_en": "14A56A [OP_GEN_POSSIBLE_LIST] 3 [OP_LIST_DIVISIBLE] 4 [OP_LIST_DIVISIBLE] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '14A56A'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 3\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 4\nlist_c = []\nvar_c = int(var_c)\nfor i in list_b:\n    i = int(i)\n    if i % var_c == 0:\n        list_c.append(i)\nvar_d = 1\nvar_e = list_c[var_d-1]\nprint(int(var_e))",
        "solution_code_en": "var_a = '14A56A'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 3\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 4\nlist_c = []\nvar_c = int(var_c)\nfor i in list_b:\n    i = int(i)\n    if i % var_c == 0:\n        list_c.append(i)\nvar_d = 1\nvar_e = list_c[var_d-1]\nprint(int(var_e))"
    },
    "4124": {
        "category": "Arithmetic calculation",
        "question_ko": "1256개의 바둑돌 중에서 흰 바둑돌이 검은 바둑돌보다 408개 많다고 한다. 검은 바둑돌의 개수를 구하십시오.",
        "question_en": "It is said that out of 1256 Go stones, there are 408 more white ones than black ones. Find the number of black Go stones.",
        "answer_ko": "424",
        "answer_en": "424",
        "solution_abst_ko": "1256 408 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "1256 408 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 1256\nvar_b = 408\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 1256\nvar_b = 408\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "4125": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이는 감을 25개 땄습니다. 호석이가 딴 감의 3배가 정국이가 딴 감보다 4개 적다면, 호석이가 딴 감은 몇 개입니까?",
        "question_en": "Jungkook picked 25 persimmons. If 3 times the persimmons that Hoseok picked is 4 less than the number of persimmons that Jungkook picked, how many persimmons did Hoseok pick?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "25 4 [OP_SUB] 3 [OP_FDIV]",
        "solution_abst_en": "25 4 [OP_SUB] 3 [OP_FDIV]",
        "solution_code_ko": "var_a = 25\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 25\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "4126": {
        "category": "Correspondence",
        "question_ko": "1부터 9까지의 수 A 중 A345>5555가 되게 하는 A는 모두 몇 개 입니까?",
        "question_en": "How many A's from 1 to 9 make A345>5555 true?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "A345>5555 A [OP_DIGIT_UNK_SOLVER] [OP_LIST_LEN]",
        "solution_abst_en": "A345>5555 A [OP_DIGIT_UNK_SOLVER] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 'A345>5555'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = len(list_a)\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A345>5555'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = len(list_a)\nprint(int(var_c))"
    },
    "4127": {
        "category": "Arithmetic calculation",
        "question_ko": "떨어뜨린 높이의 1/10만큼씩 튀어 오르는 공이 있습니다. 이 공을 15미터(m) 높이에서 떨어뜨렸다면 세 번째로 튀어 오른 공의 높이를 소수 둘째자리에서 반올림하면 몇 미터(m)인지 구하시오.",
        "question_en": "There is a ball that bounces 1/10 of the height it is dropped. If this ball is dropped from a height of 15 meters (m), find the height in meters (m) of the third jump round to two decimal places.",
        "answer_ko": "0.02",
        "answer_en": "0.02",
        "solution_abst_ko": "15 1/10 3 [OP_POW] [OP_MUL] 2 [OP_ROUND]",
        "solution_abst_en": "15 1/10 3 [OP_POW] [OP_MUL] 2 [OP_ROUND]",
        "solution_code_ko": "var_a = 15\nvar_b = 0.1\nvar_c = 3\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = round(float(var_e)+1e-10, var_f)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 15\nvar_b = 0.1\nvar_c = 3\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = round(float(var_e)+1e-10, var_f)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "4128": {
        "category": "Correspondence",
        "question_ko": "A82+3B=216일 때, A를 구하시오.",
        "question_en": "When A82+3B=216 is valid, find A.",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "A82+3B=216 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A82+3B=216 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A82+3B=216'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A82+3B=216'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "4129": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 10센티미터(㎝)인 정삼각형을 밑면으로 하는 각기둥이 있습니다. 이 각기둥의 모든 모서리의 길이의 합이 84센티미터(㎝)일 때 각기둥의 높이는 몇 센티미터(㎝)입니까?",
        "question_en": "There is a prism whose base side is a regular triangle with sides of 10 centimeters (cm). If the sum of the lengths of all the edges of this prism is 84 centimeters (cm), what is the height of the prism in centimeters (cm)?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "84 10 3 [OP_MUL] 2 [OP_MUL] [OP_SUB] 3 [OP_DIV]",
        "solution_abst_en": "84 10 3 [OP_MUL] 2 [OP_MUL] [OP_SUB] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 84\nvar_b = 10\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_a - var_f\nvar_h = 3\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 84\nvar_b = 10\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_a - var_f\nvar_h = 3\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "4130": {
        "category": "Correspondence",
        "question_ko": "5A8-B14=364이 성립합니다. A는 무엇인가요?",
        "question_en": "5A8-B14=364. What is A?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "5A8-B14=364 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "5A8-B14=364 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '5A8-B14=364'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '5A8-B14=364'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "4131": {
        "category": "Comparison",
        "question_ko": "한 변의 길이가 4센티미터(㎝)인 정사각형과 밑변의 길이가 6센티미터(㎝)이고, 높이가 4센티미터(㎝)인 삼각형 중에서 넓이가 더 넓은 것은 어느 도형입니까?",
        "question_en": "Which shape has the greater area: a square with a side of 4 centimeters (cm) or a triangle with a base of 6 centimeters (cm) and a height of 4 centimeters (cm)?",
        "answer_ko": "정사각형",
        "answer_en": "square",
        "solution_abst_ko": "[OP_LIST_SOL] 정사각형 삼각형 [OP_LIST_EOL] [OP_LIST_SOL] 4 2 [OP_POW] 6 4 [OP_MUL] 2 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] square triangle [OP_LIST_EOL] [OP_LIST_SOL] 4 2 [OP_POW] 6 4 [OP_MUL] 2 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정사각형'\nvar_b = '삼각형'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 6\nvar_g = 4\nvar_h = var_f * var_g\nvar_i = 2\nvar_j = var_h / var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'square'\nvar_b = 'triangle'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 6\nvar_g = 4\nvar_h = var_f * var_g\nvar_i = 2\nvar_j = var_h / var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "4132": {
        "category": "Geometry",
        "question_ko": "네모난 책상의 가로가 9센티미터(㎝)이고 둘레가 46센티미터(㎝)이면 책상의 세로는 얼마입니까?",
        "question_en": "If the width of a rectangular desk is 9 centimeters (cm) and the perimeter is 46 centimeters (cm), what is the length of the desk?\n",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "46 2 [OP_DIV] 9 [OP_SUB]",
        "solution_abst_en": "46 2 [OP_DIV] 9 [OP_SUB]",
        "solution_code_ko": "var_a = 46\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 9\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 46\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 9\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "4133": {
        "category": "Geometry",
        "question_ko": "모니터의 가로 길이가 12센티미터(㎝)이고 둘레 길이가 38센티미터(㎝)이다. 모니터의 세로 길이를 구하시오.",
        "question_en": "The width of the monitor is 12 centimeters (cm) and the circumference is 38 centimeters (cm). Find the height of the monitor.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "38 2 [OP_DIV] 12 [OP_SUB]",
        "solution_abst_en": "38 2 [OP_DIV] 12 [OP_SUB]",
        "solution_code_ko": "var_a = 38\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 12\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 38\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 12\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "4134": {
        "category": "Correspondence",
        "question_ko": "윤기는 세 자리 수와 57의 덧셈을 하려 합니다. 윤기는 세 자리 수의 일의 자리 숫자 9를 6으로 잘못 보았습니다. 윤기가 구한 합은 823 일 때, 바르게 계산한 결과를 구하시오.",
        "question_en": "Yoongi tried to add a three-digit number to 57. Yoongi misread the 9 in the ones in the three-digit number as 6. When the sum obtained by Yoongi was 823, find the correct calculation result.",
        "answer_ko": "826",
        "answer_en": "826",
        "solution_abst_ko": "823 57 [OP_SUB] 6 9 [OP_SUB] [OP_SUB] 57 [OP_ADD]",
        "solution_abst_en": "823 57 [OP_SUB] 6 9 [OP_SUB] [OP_SUB] 57 [OP_ADD]",
        "solution_code_ko": "var_a = 823\nvar_b = 57\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nvar_h = 57\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 823\nvar_b = 57\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nvar_h = 57\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "4135": {
        "category": "Arithmetic calculation",
        "question_ko": "주원이는 105.8미터(m)의 철사가 있습니다. 모빌 한 개를 만들기 위해서는 철사 4미터(m)가 필요하다면 주원이가 만들 수 있는 최대한의 모빌을 만들고 남은 철사는 몇 미터(m)인지 구하세요.",
        "question_en": "Juwon has 105.8 meters (m) of wire. If he needs 4 meters (m) of wire to make one mobile, find how many meters (m) of wire are left after making as many mobiles as Juwon can make.",
        "answer_ko": "1.80",
        "answer_en": "1.8",
        "solution_abst_ko": "105.8 4 [OP_MOD]",
        "solution_abst_en": "105.8 4 [OP_MOD]",
        "solution_code_ko": "var_a = 105.8\nvar_b = 4\nvar_c = var_a % var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 105.8\nvar_b = 4\nvar_c = var_a % var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "4136": {
        "category": "Arithmetic calculation",
        "question_ko": "당근 4개와 오이 몇 개가 합해서 모두 10개 있었습니다. 오늘 어머니께서 오이 2개를 더 사 오셨습니다. 지금 오이는 모두 몇 개인지 구하시오.",
        "question_en": "There were 4 carrots and a few cucumbers in a total of 10. Today your mother bought 2 more cucumbers. How many cucumbers are there now?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "10 4 [OP_SUB] 2 [OP_ADD]",
        "solution_abst_en": "10 4 [OP_SUB] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "4137": {
        "category": "Geometry",
        "question_ko": "사각형의 네 각 중 세 각의 크기는 각각 75도, 80도, 120도였습니다. 이 사각형의 나머지 한 각의 크기는 몇 도입니까?",
        "question_en": "Three of the quadrilateral's four angles measure 75 degrees (angle), 80 degrees (angle), and 120 degrees (angle), respectively. What degree (angle) is the other angle of this rectangle?",
        "answer_ko": "85",
        "answer_en": "85",
        "solution_abst_ko": "360 75 [OP_SUB] 80 [OP_SUB] 120 [OP_SUB]",
        "solution_abst_en": "360 75 [OP_SUB] 80 [OP_SUB] 120 [OP_SUB]",
        "solution_code_ko": "var_a = 360\nvar_b = 75\nvar_c = var_a - var_b\nvar_d = 80\nvar_e = var_c - var_d\nvar_f = 120\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 360\nvar_b = 75\nvar_c = var_a - var_b\nvar_d = 80\nvar_e = var_c - var_d\nvar_f = 120\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "4138": {
        "category": "Arithmetic calculation",
        "question_ko": "석진이네 반에서 수학 숙제는 37명, 국어 숙제는 42명이 제출했습니다. 전체 학생 수는 48명이고 두 숙제를 모두 안 한 학생은 없을 때, 숙제를 모두 해 온 학생은 몇 명인지 구하시오.",
        "question_en": "In Seokjin's class, 37 students submitted math homework and 42 Korean language homework. If the total number of students is 48 and no student has missed both homework assignments, how many students have completed both homework assignments?",
        "answer_ko": "31",
        "answer_en": "31",
        "solution_abst_ko": "37 42 [OP_ADD] 48 [OP_SUB]",
        "solution_abst_en": "37 42 [OP_ADD] 48 [OP_SUB]",
        "solution_code_ko": "var_a = 37\nvar_b = 42\nvar_c = var_a + var_b\nvar_d = 48\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 37\nvar_b = 42\nvar_c = var_a + var_b\nvar_d = 48\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "4139": {
        "category": "Possibility",
        "question_ko": "숫자 모양 달고나가 있습니다. 3, 0, 6모양의 3개가 있을 때, 두 개의 달고나를 차례대로 놓아서 두 자리 숫자처럼 보이게 하려고 합니다. 총 몇 가지를 표현할 수 있습니까?",
        "question_en": "There are number-shaped sweets. If there are three in the shape of 3, 0 and 6, you want to put two dalgonas in a row to make it look like a two-digit number. How many can you make in total?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 3 0 6 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 3 0 6 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 3\nvar_b = 0\nvar_c = 6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 3\nvar_b = 0\nvar_c = 6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "4140": {
        "category": "Geometry",
        "question_ko": "면의 수가 15개이고 모서리의 길이가 9센티미터(㎝)로 모두 같은 각뿔이 있습니다. 이 각뿔의 모든 모서리의 길이의 합은 몇 센티미터(㎝)입니까?",
        "question_en": "There is a pyramid that has 15 faces and whose edges are all the same as 9 centimeters (cm). What is the sum of the lengths of the edges of this pyramid in centimeters (cm)?",
        "answer_ko": "126",
        "answer_en": "126",
        "solution_abst_ko": "15 1 [OP_SUB] 9 [OP_MUL]",
        "solution_abst_en": "15 1 [OP_SUB] 9 [OP_MUL]",
        "solution_code_ko": "var_a = 15\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 9\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 9\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "4141": {
        "category": "Geometry",
        "question_ko": "가로의 길이가 8센티미터(㎝), 세로의 길이가 12센티미터(㎝), 높이가 30센티미터(㎝)인 직육면체 모양의 상자를 일정한 방향으로 빈틈없이 쌓아 가능한 한 작은 정육면체를 만들려고 한다. 이때 필요한 상자의 개수를 구하시오.",
        "question_en": "I am trying to make a cube as small as possible by stacking cuboid-shaped boxes that are 8 centimeters (cm) wide, 12 centimeters (cm) long, and 30 centimeters (cm) high in a certain direction. Find the number of boxes needed at this time.",
        "answer_ko": "600",
        "answer_en": "600",
        "solution_abst_ko": "8 12 [OP_LCM] 30 [OP_LCM] 8 [OP_DIV] 8 12 [OP_LCM] 30 [OP_LCM] 12 [OP_DIV] 8 12 [OP_LCM] 30 [OP_LCM] 30 [OP_DIV] [OP_MUL] [OP_MUL]",
        "solution_abst_en": "8 12 [OP_LCM] 30 [OP_LCM] 8 [OP_DIV] 8 12 [OP_LCM] 30 [OP_LCM] 12 [OP_DIV] 8 12 [OP_LCM] 30 [OP_LCM] 30 [OP_DIV] [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 12\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nvar_d = 30\nvar_e = var_d * var_c / math.gcd(int(var_d), int(var_c))\nvar_f = 8\nvar_g = var_e / var_f\nvar_h = 8\nvar_i = 12\nvar_j = var_i * var_h / math.gcd(int(var_i), int(var_h))\nvar_k = 30\nvar_l = var_k * var_j / math.gcd(int(var_k), int(var_j))\nvar_m = 12\nvar_n = var_l / var_m\nvar_o = 8\nvar_p = 12\nvar_q = var_p * var_o / math.gcd(int(var_p), int(var_o))\nvar_r = 30\nvar_s = var_r * var_q / math.gcd(int(var_r), int(var_q))\nvar_t = 30\nvar_u = var_s / var_t\nvar_v = var_n * var_u\nvar_w = var_g * var_v\nprint(int(var_w))",
        "solution_code_en": "var_a = 8\nvar_b = 12\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nvar_d = 30\nvar_e = var_d * var_c / math.gcd(int(var_d), int(var_c))\nvar_f = 8\nvar_g = var_e / var_f\nvar_h = 8\nvar_i = 12\nvar_j = var_i * var_h / math.gcd(int(var_i), int(var_h))\nvar_k = 30\nvar_l = var_k * var_j / math.gcd(int(var_k), int(var_j))\nvar_m = 12\nvar_n = var_l / var_m\nvar_o = 8\nvar_p = 12\nvar_q = var_p * var_o / math.gcd(int(var_p), int(var_o))\nvar_r = 30\nvar_s = var_r * var_q / math.gcd(int(var_r), int(var_q))\nvar_t = 30\nvar_u = var_s / var_t\nvar_v = var_n * var_u\nvar_w = var_g * var_v\nprint(int(var_w))"
    },
    "4142": {
        "category": "Comparison",
        "question_ko": "자동차 A는 시속 92킬로미터(㎞)로 달리고, 자동차 B는 분속 1500미터(m)로 달립니다. A와 B 중 어떤 자동차가 더 속력이 빠릅니까?",
        "question_en": "Car A is traveling at 92 kilometers (km) per hour and car B is traveling at 1500 meters (m) per minute. Which car, A or B, is faster?",
        "answer_ko": "A",
        "answer_en": "A",
        "solution_abst_ko": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 92 1500 1000 [OP_DIV] 60 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 92 1500 1000 [OP_DIV] 60 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 92\nvar_d = 1500\nvar_e = 1000\nvar_f = var_d / var_e\nvar_g = 60\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 92\nvar_d = 1500\nvar_e = 1000\nvar_f = var_d / var_e\nvar_g = 60\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "4143": {
        "category": "Comparison",
        "question_ko": "정국이는 0.8, 윤기는 1/2의 숫자카드를 갖고 있습니다. 0.3보다 큰 숫자카드를 가지고 있는 사람은 몇 명입니까?",
        "question_en": "Jungkook has 0.8 written on a card, and Yoongi has 1/2 written on a card. How many people have number that is greater than 0.3 written on their cards?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 [OP_LIST_EOL] 0.3 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 [OP_LIST_EOL] 0.3 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.3\nlist_b = []\nfor i in list_a:\n    if i > var_c:\n        list_b.append(i)\nvar_d = len(list_b)\nprint(int(var_d))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.3\nlist_b = []\nfor i in list_a:\n    if i > var_c:\n        list_b.append(i)\nvar_d = len(list_b)\nprint(int(var_d))"
    },
    "4144": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 23센티미터(㎝)인 정팔각형의 모든 변의 길이의 합은 몇 미터(m)입니까?",
        "question_en": "What is the sum of the lengths of all the sides of a regular octagon with a side length of 2.3 centimeters (cm), in meters (m)?",
        "answer_ko": "1840",
        "answer_en": "1840",
        "solution_abst_ko": "2.3 100 [OP_DIV] 8 [OP_MUL]",
        "solution_abst_en": "2.3 100 [OP_DIV] 8 [OP_MUL]",
        "solution_code_ko": "var_a = 2.3\nvar_b = 100\nvar_c = var_a / var_b\nvar_d = 8\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 2.3\nvar_b = 100\nvar_c = var_a / var_b\nvar_d = 8\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "4145": {
        "category": "Possibility",
        "question_ko": "네 개의 숫자 카드 0, 1, 4, 8을 한 번 사용하여 첫 번째 숫자가 8인 2번째로 작은 네 자리 숫자를 찾은 다음 각 숫자의 합을 찾습니다.",
        "question_en": "We are going to use four number cards of 0, 1, 4, and 8 once to make the 6th smallest of four-digit numbers which have 8 in the thousands. Then we are going to sum up all the numbers in each digit.",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 4 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 8 [OP_LIST_SEARCH_FIXED_DIGIT] 2 [OP_LIST_MIN] [OP_NUM2LIST] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 4 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 8 [OP_LIST_SEARCH_FIXED_DIGIT] 2 [OP_LIST_MIN] [OP_NUM2LIST] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 4\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nvar_g = 8\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 2\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nlist_e = []\nvar_i = int(var_i)\nwhile var_i//10 > 0:\n    list_e.append(var_i%10)\n    var_i = var_i//10\nlist_e.append(var_i%10)\nlist_e = list_e[::-1]\nlist_e = [float(i) for i in list_e]\nvar_j = sum(list_e)\nprint(int(var_j))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 4\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nvar_g = 8\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 2\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nlist_e = []\nvar_i = int(var_i)\nwhile var_i//10 > 0:\n    list_e.append(var_i%10)\n    var_i = var_i//10\nlist_e.append(var_i%10)\nlist_e = list_e[::-1]\nlist_e = [float(i) for i in list_e]\nvar_j = sum(list_e)\nprint(int(var_j))"
    },
    "4146": {
        "category": "Geometry",
        "question_ko": "가로가 24센티미터(㎝), 세로가 18센티미터(㎝)인 직사각형 모양의 나무 판자를 남는 부분 없이 잘라 같은 크기의 가장 큰 정사각형 모양의 나무 조각을 여러 개 만들려고 합니다. 나무 조각은 모두 몇 개 만들 수 있는지 구하시오.",
        "question_en": "You are going to cut a rectangular wooden board that is 24 centimeters (cm) wide by 18 centimeters (cm) long, without any remaining, to make several pieces of the largest square wooden piece of the same size. How many wooden pieces can you make in all?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "24 24 18 [OP_GCD] [OP_FDIV] 18 24 18 [OP_GCD] [OP_FDIV] [OP_MUL]",
        "solution_abst_en": "24 24 18 [OP_GCD] [OP_FDIV] 18 24 18 [OP_GCD] [OP_FDIV] [OP_MUL]",
        "solution_code_ko": "var_a = 24\nvar_b = 24\nvar_c = 18\nvar_d = math.gcd(int(var_c), int(var_b))\nvar_e = var_a // var_d\nvar_f = 18\nvar_g = 24\nvar_h = 18\nvar_i = math.gcd(int(var_h), int(var_g))\nvar_j = var_f // var_i\nvar_k = var_e * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 24\nvar_b = 24\nvar_c = 18\nvar_d = math.gcd(int(var_c), int(var_b))\nvar_e = var_a // var_d\nvar_f = 18\nvar_g = 24\nvar_h = 18\nvar_i = math.gcd(int(var_h), int(var_g))\nvar_j = var_f // var_i\nvar_k = var_e * var_j\nprint(int(var_k))"
    },
    "4147": {
        "category": "Correspondence",
        "question_ko": "연필 170자루, 공책 268권, 지우개 120개를 가지고 운동장에 있는 학생들에게 각각 똑같이 나누어 주었다. 연필은 8자루가 남았고, 공책은 2권이 모자랐으며 지우개는 12개가 남았다. 운동장에 있던 학생들은 최대 몇 명인가?",
        "question_en": "You handed out 170 pencils, 268 notebooks, and 120 erasers to each of the students on the playground equally. There were 8 pencils left, 2 notebooks short, and 12 erasers left. What is the maximum number of students that were on the playground?",
        "answer_ko": "54",
        "answer_en": "54",
        "solution_abst_ko": "170 8 [OP_SUB] 268 2 [OP_ADD] [OP_GCD] 120 12 [OP_SUB] [OP_GCD]",
        "solution_abst_en": "170 8 [OP_SUB] 268 2 [OP_ADD] [OP_GCD] 120 12 [OP_SUB] [OP_GCD]",
        "solution_code_ko": "var_a = 170\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 268\nvar_e = 2\nvar_f = var_d + var_e\nvar_g = math.gcd(int(var_f), int(var_c))\nvar_h = 120\nvar_i = 12\nvar_j = var_h - var_i\nvar_k = math.gcd(int(var_j), int(var_g))\nprint(int(var_k))",
        "solution_code_en": "var_a = 170\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 268\nvar_e = 2\nvar_f = var_d + var_e\nvar_g = math.gcd(int(var_f), int(var_c))\nvar_h = 120\nvar_i = 12\nvar_j = var_h - var_i\nvar_k = math.gcd(int(var_j), int(var_g))\nprint(int(var_k))"
    },
    "4148": {
        "category": "Possibility",
        "question_ko": "2, 4, 7, 9를 한 번씩 사용하여 세자리 수를 만들려고 한다. 십의 자리 숫자가 7인 수들 중 세 번째로 작은 세 자리 수는 무엇입니까?",
        "question_en": "Try to make a three-digit number by using 2, 4, 7, and 9 once. What is the third least three-digit number with 7 in the tens place?",
        "answer_ko": "472",
        "answer_en": "472",
        "solution_abst_ko": "[OP_LIST_SOL] 2 4 7 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 7 [OP_LIST_SEARCH_FIXED_DIGIT] 3 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 2 4 7 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 7 [OP_LIST_SEARCH_FIXED_DIGIT] 3 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = 7\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 7\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 3\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nprint(int(var_i))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = 7\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 7\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 3\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nprint(int(var_i))"
    },
    "4149": {
        "category": "Comparison",
        "question_ko": "5가지 숫자 1.4, 9/10, 1.2, 0.5, 13/10 중에서 1.1보다 작은 수 중 가장 큰 숫자는 무엇입니까?",
        "question_en": "Which of the five numbers 1.4, 9/10, 1.2, 0.5, and 13/10 is the largest number less than 1.1?",
        "answer_ko": "0.90",
        "answer_en": "0.9",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i < var_f:\n        list_b.append(i)\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nprint('{:.2f}'.format(round(var_h+1e-10,2)))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i < var_f:\n        list_b.append(i)\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nprint('{:.2f}'.format(round(var_h+1e-10,2)))"
    },
    "4150": {
        "category": "Correspondence",
        "question_ko": "14A+B73=418일 때, B에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "When 14A+B73=418, what number should go in B?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "14A+B73=418 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "14A+B73=418 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '14A+B73=418'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '14A+B73=418'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "4151": {
        "category": "Arithmetic calculation",
        "question_ko": "호석이는 1개에 100원짜리 구슬을 몇 개 살 수 있는 돈으로 1개에 80원짜리 구슬을 같은 개수만큼 샀더니 260원이 남았습니다. 호석이는 구슬을 몇 개 샀습니까?",
        "question_en": "Hoseok bought the same number of marbles at 80 won each with the money he could buy for several marbles at 100 won each, and he had 260 won left. How many marbles did Hoseok buy?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "260 100 80 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "260 100 80 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 260\nvar_b = 100\nvar_c = 80\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 260\nvar_b = 100\nvar_c = 80\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "4152": {
        "category": "Arithmetic calculation",
        "question_ko": "15의 약수 중 15를 제외하고 가장 큰 수를 구하시오.",
        "question_en": "Find the largest number other than 15 among the divisors of 15.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "15 [OP_LIST_GET_DIVISOR] 2 [OP_LIST_MAX]",
        "solution_abst_en": "15 [OP_LIST_GET_DIVISOR] 2 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 15\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_c = list_b[-var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 15\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_c = list_b[-var_b]\nprint(int(var_c))"
    },
    "4153": {
        "category": "Comparison",
        "question_ko": "재호와 경환은 같은 시간 산책을 했다. 재호는 10.2킬로미터(㎞)의 100분의 1을 걸었고, 경환은 100미터(m)를 걸었다. 누가 더 많이 걸었을까?",
        "question_en": "Jaeho and Kyunghwan took a walk at the same time. Jaeho walked one hundredth of 10.2 kilometers (km), and Kyunghwan walked 100 meters (m). Who walked more?",
        "answer_ko": "재호",
        "answer_en": "Jaeho",
        "solution_abst_ko": "[OP_LIST_SOL] 재호 경환 [OP_LIST_EOL] [OP_LIST_SOL] 10.2 1000 [OP_MUL] 100 [OP_DIV] 100 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jaeho Kyunghwan [OP_LIST_EOL] [OP_LIST_SOL] 10.2 1000 [OP_MUL] 100 [OP_DIV] 100 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '재호'\nvar_b = '경환'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10.2\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 100\nvar_g = var_e / var_f\nvar_h = 100\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Jaeho'\nvar_b = 'Kyunghwan'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10.2\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 100\nvar_g = var_e / var_f\nvar_h = 100\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "4154": {
        "category": "Arithmetic calculation",
        "question_ko": "18센티미터(㎝)의 나무 토막 3개를 같은 길이씩 겹친 뒤 이어붙여 50.5센티미터(㎝) 다리를 만들려고 합니다. 몇 센티미터(㎝)씩 겹쳐야 할까요?",
        "question_en": "I am going to make a 50.5 centimeters (cm) bridge by overlapping three 18 centimeters (cm) wooden blocks in the same length and then joining them together. How many centimeters (cm) should each overlapping section be?",
        "answer_ko": "1.75",
        "answer_en": "1.75",
        "solution_abst_ko": "18 3 [OP_MUL] 50.5 [OP_SUB] 3 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "18 3 [OP_MUL] 50.5 [OP_SUB] 3 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 18\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 50.5\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 18\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 50.5\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "4155": {
        "category": "Correspondence",
        "question_ko": "백의 자리 수가 8이고 일의 자리 수가 2인 세 자리 수를 십의 자리에서 반올림하면 800이 됩니다. 십의 자리 수가 A라고 한다면, 0부터 9까지의 숫자 중 A에 쓸 수 있는 수들의 합을 구하시오.",
        "question_en": "Rounding the three-digit number 8A2 to the nearest hundred gives 800. Find the sum of the numbers from 0 to 9 that can be A.",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "[OP_LIST_SOL] 8 A 2 [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 850 [OP_LIST_MORE_EQUAL] 8A2 A [OP_LIST_FIND_UNK] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 8 A 2 [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 850 [OP_LIST_MORE_EQUAL] 8A2 A [OP_LIST_FIND_UNK] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 8\nvar_b = 'A'\nvar_c = 2\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nans_dict = dict()\nvar_d = str(var_d)\nlist_b = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_d) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_b.append(new_elem)\nvar_e = 850\nlist_c = []\nfor i in list_b:\n    if i >= var_e:\n        list_c.append(i)\nvar_f = '8A2'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nlist_d = []\nfor elem in list_c:\n    elem = str(elem)\n    list_d.append(int(elem[unk_idx]))\nlist_d = list(set(list_d))\nlist_d = [float(i) for i in list_d]\nvar_h = sum(list_d)\nprint(int(var_h))",
        "solution_code_en": "var_a = 8\nvar_b = 'A'\nvar_c = 2\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nans_dict = dict()\nvar_d = str(var_d)\nlist_b = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_d) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_b.append(new_elem)\nvar_e = 850\nlist_c = []\nfor i in list_b:\n    if i >= var_e:\n        list_c.append(i)\nvar_f = '8A2'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nlist_d = []\nfor elem in list_c:\n    elem = str(elem)\n    list_d.append(int(elem[unk_idx]))\nlist_d = list(set(list_d))\nlist_d = [float(i) for i in list_d]\nvar_h = sum(list_d)\nprint(int(var_h))"
    },
    "4156": {
        "category": "Correspondence",
        "question_ko": "1부터 100까지 자연수를 쓰려고 합니다. 숫자 1은 모두 몇 번 써야 합니까?",
        "question_en": "You are trying to write natural numbers from 1 to 100. How many times should the number 1 be written in all?",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "1 100 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 1 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 100 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 1 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 1\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 1\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))"
    },
    "4157": {
        "category": "Geometry",
        "question_ko": "한 모서리의 길이가 1미터(m)인 정육면체를 가로 방향, 세로 방향, 높이 방향을 따라 각각 3번씩 잘라 나누었더니 64개의 작은 직육면체가 생겼습니다. 이 작은 직육면체들의 겉넓이의 합은 몇 ㎡입니까?",
        "question_en": "A cube with a side length of 1 meter (m) was cut 3 times each along the horizontal, vertical, and height directions, resulting in 64 small cuboids. What is the sum of the surface areas in square meters (m2) of these small cuboids?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "1 4 [OP_DIV] 1 4 [OP_DIV] [OP_MUL] 6 [OP_MUL] 64 [OP_MUL]",
        "solution_abst_en": "1 4 [OP_DIV] 1 4 [OP_DIV] [OP_MUL] 6 [OP_MUL] 64 [OP_MUL]",
        "solution_code_ko": "var_a = 1\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = var_c * var_f\nvar_h = 6\nvar_i = var_g * var_h\nvar_j = 64\nvar_k = var_i * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 1\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = var_c * var_f\nvar_h = 6\nvar_i = var_g * var_h\nvar_j = 64\nvar_k = var_i * var_j\nprint(int(var_k))"
    },
    "4158": {
        "category": "Geometry",
        "question_ko": "큐브는 27개의 작은 정육면체가 모여 이루어진 정육면체 모양의 장난감입니다. 큐브의 모든 모서리의 길이를 더하면 82.8센티미터(㎝)일 때, 큐브의 한 모서리와 큐브를 이루는 작은 정육면체의 한 모서리의 합은 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "Cube is a cube-shaped toy made up of 27 small cubes. If the length of all the edges of the cube is 82.8 centimeters (cm), what is the sum of one edge of the large cube and one edge of the small cube that make up the cube in centimeters (cm)?",
        "answer_ko": "9.20",
        "answer_en": "9.2",
        "solution_abst_ko": "82.8 4 3 [OP_MUL] [OP_DIV] 82.8 4 3 [OP_MUL] [OP_DIV] 1 2 3 [OP_DIV] [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_abst_en": "82.8 4 3 [OP_MUL] [OP_DIV] 82.8 4 3 [OP_MUL] [OP_DIV] 1 2 3 [OP_DIV] [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 82.8\nvar_b = 4\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nvar_f = 82.8\nvar_g = 4\nvar_h = 3\nvar_i = var_g * var_h\nvar_j = var_f / var_i\nvar_k = 1\nvar_l = 2\nvar_m = 3\nvar_n = var_l / var_m\nvar_o = var_k - var_n\nvar_p = var_j * var_o\nvar_q = var_e + var_p\nprint('{:.2f}'.format(round(var_q+1e-10,2)))",
        "solution_code_en": "var_a = 82.8\nvar_b = 4\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nvar_f = 82.8\nvar_g = 4\nvar_h = 3\nvar_i = var_g * var_h\nvar_j = var_f / var_i\nvar_k = 1\nvar_l = 2\nvar_m = 3\nvar_n = var_l / var_m\nvar_o = var_k - var_n\nvar_p = var_j * var_o\nvar_q = var_e + var_p\nprint('{:.2f}'.format(round(var_q+1e-10,2)))"
    },
    "4159": {
        "category": "Possibility",
        "question_ko": "4, 8, 1, 2 중 3개를 사용하여 일의 자리 숫자가 2인 수 중 세 번째로 큰 수는 무엇입니까?",
        "question_en": "What is the third largest number with the ones digit of 2 using 3 of 4, 8, 1, and 2?",
        "answer_ko": "482",
        "answer_en": "482",
        "solution_abst_ko": "[OP_LIST_SOL] 4 8 1 2 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 2 [OP_LIST_SEARCH_FIXED_DIGIT] 3 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 4 8 1 2 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 2 [OP_LIST_SEARCH_FIXED_DIGIT] 3 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 4\nvar_b = 8\nvar_c = 1\nvar_d = 2\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nvar_g = 2\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 3\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nprint(int(var_i))",
        "solution_code_en": "var_a = 4\nvar_b = 8\nvar_c = 1\nvar_d = 2\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nvar_g = 2\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 3\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nprint(int(var_i))"
    },
    "4160": {
        "category": "Correspondence",
        "question_ko": "A, B는 서로 다른 자연수입니다. A를 17로 나누면 몫이 25이며 나머지는 B입니다. B가 될 수 있는 수 중에 가장 큰수 일때 A를 구하세요.",
        "question_en": "A and B are different natural numbers. When A is divided by 17, the quotient is 25 and the remainder is B. Find A when B is the largest number possible.",
        "answer_ko": "441",
        "answer_en": "441",
        "solution_abst_ko": "17 25 [OP_MUL] 16 [OP_ADD]",
        "solution_abst_en": "17 25 [OP_MUL] 16 [OP_ADD]",
        "solution_code_ko": "var_a = 17\nvar_b = 25\nvar_c = var_a * var_b\nvar_d = 16\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 17\nvar_b = 25\nvar_c = var_a * var_b\nvar_d = 16\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "4161": {
        "category": "Comparison",
        "question_ko": "학생 9명이 한 줄로 서 있습니다. 왼쪽에서 3번째와 왼쪽에서 7번째 사이에 서 있는 학생은 몇 명입니까?",
        "question_en": "Nine students stand in a line. How many students are standing between the 3rd from the left and the 7th from the left?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "7 3 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "7 3 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 7\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 7\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "4162": {
        "category": "Arithmetic calculation",
        "question_ko": "네 자리 자연수 5AB0는 4로 나누어 떨어지고 5로도 나누어 떨어진다. 가능한 A,B의 조합은 몇 개 인지 구하시오.",
        "question_en": "The four-digit natural number 5AB0 is divisible by 4 and 5. How many combinations of A and B are possible?",
        "answer_ko": "50",
        "answer_en": "50",
        "solution_abst_ko": "5AB0 [OP_GEN_POSSIBLE_LIST] 4 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "5AB0 [OP_GEN_POSSIBLE_LIST] 4 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '5AB0'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 4\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 5\nlist_c = []\nvar_c = int(var_c)\nfor i in list_b:\n    i = int(i)\n    if i % var_c == 0:\n        list_c.append(i)\nvar_d = len(list_c)\nprint(int(var_d))",
        "solution_code_en": "var_a = '5AB0'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 4\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 5\nlist_c = []\nvar_c = int(var_c)\nfor i in list_b:\n    i = int(i)\n    if i % var_c == 0:\n        list_c.append(i)\nvar_d = len(list_c)\nprint(int(var_d))"
    },
    "4163": {
        "category": "Correspondence",
        "question_ko": "윤기는 두 자리 수와 세 자리 수의 뺄셈을 하려 합니다. 윤기는 두 자리 수의 일의 자리 숫자 9를 6으로 잘못 보았고, 세 자리 수의 백의 자리 숫자와 일의 자리 숫자를 바꾸어 253이라고 잘못 보았습니다. 윤기가 구한 차는 299 일 때, 두 자리 수를 구하시오.",
        "question_en": "Yoongi wants to subtract a two-digit number from a three-digit number. Yoongi has mistaken the unit digit of the two-digit 9 for 6 and changed the three-digit hundreds and ones to make the number 253. If Yoongi's difference is 299, find the two-digit number.",
        "answer_ko": "43",
        "answer_en": "43",
        "solution_abst_ko": "253 299 [OP_SUB] 6 9 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "253 299 [OP_SUB] 6 9 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 253\nvar_b = 299\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 253\nvar_b = 299\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "4164": {
        "category": "Geometry",
        "question_ko": "한 변이 8개가 되도록 크기가 같은 색종이 몇 개를 빈틈없이 늘어놓아 정사각형을 만들었습니다. 이 정사각형의 둘레에 색종이를 더 놓아 한 번 에워싸도록 만들 때, 색종이는 몇 개가 더 필요합니까?",
        "question_en": "A square has been made by arranging several rectangular pieces of colored paper of the same size so that there are 8 pieces on each side. If you place more pieces around the perimeter of this square, how many more pieces will you need?",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "8 4 [OP_MUL] 4 [OP_ADD]",
        "solution_abst_en": "8 4 [OP_MUL] 4 [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "4165": {
        "category": "Possibility",
        "question_ko": "계산기에 7, 6, 2, 0 버튼이 색칠되어 있습니다. 색칠된 버튼의 숫자만 한 번씩 사용하여 만들 수 있는 세 번째 큰 세 자리수와 세 번째 작은 세 자리 수의 합을 구하시오.",
        "question_en": "The buttons 7, 6, 2, 0 are colored on the calculator. Find the sum of the third largest three-digit number and the third smallest three-digit number that can be made by using only the number of the colored button once.",
        "answer_ko": "986",
        "answer_en": "986",
        "solution_abst_ko": "[OP_LIST_SOL] 7 6 2 0 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 7 6 2 0 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 7\nvar_b = 6\nvar_c = 2\nvar_d = 0\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 7\nvar_b = 6\nvar_c = 2\nvar_d = 0\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))"
    },
    "4166": {
        "category": "Comparison",
        "question_ko": "A, B 두 수가 있다. A는 50에서 7더한 수, B는 10개씩 6묶음인 수에서 7을 뺀 수이다. 더 큰 수는 어느 것인가?",
        "question_en": "There are two numbers A and B. A is the number of 50 plus 7, and B is the number of 6 groups of 10 minus 7. Which number is greater?",
        "answer_ko": "A",
        "answer_en": "A",
        "solution_abst_ko": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 50 7 [OP_ADD] 10 6 [OP_MUL] 7 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 50 7 [OP_ADD] 10 6 [OP_MUL] 7 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 50\nvar_d = 7\nvar_e = var_c + var_d\nvar_f = 10\nvar_g = 6\nvar_h = var_f * var_g\nvar_i = 7\nvar_j = var_h - var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 50\nvar_d = 7\nvar_e = var_c + var_d\nvar_f = 10\nvar_g = 6\nvar_h = var_f * var_g\nvar_i = 7\nvar_j = var_h - var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "4167": {
        "category": "Comparison",
        "question_ko": "블루베리청 3과 2/6 숟가락과 자몽청 21/6 숟가락을 넣어 에이드를 만들었습니다. 블루베리청과 자몽청 중 어느 것을 더 많이 넣었는지 답을 구하세요.",
        "question_en": "I made an ade with 3 and 2/6 spoons of blueberry syrup and 21/6 spoons of grapefruit syrup. Find the answer with more blueberry syrup or grapefruit syrup.",
        "answer_ko": "자몽청",
        "answer_en": "grapefruit",
        "solution_abst_ko": "[OP_LIST_SOL] 블루베리청 자몽청 [OP_LIST_EOL] [OP_LIST_SOL] 3 2/6 [OP_ADD] 21/6 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] blueberry grapefruit [OP_LIST_EOL] [OP_LIST_SOL] 3 2/6 [OP_ADD] 21/6 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '블루베리청'\nvar_b = '자몽청'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nvar_d = 0.3333333333333333\nvar_e = var_c + var_d\nvar_f = 3.5\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'blueberry'\nvar_b = 'grapefruit'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nvar_d = 0.3333333333333333\nvar_e = var_c + var_d\nvar_f = 3.5\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "4168": {
        "category": "Arithmetic calculation",
        "question_ko": "무게가 같은 당구공 6개가 들어 있는 상자의 무게는 1.82킬로그램(㎏)입니다. 빈 상자의 무게가 0.5킬로그램(㎏)이라면 당구 공 한 개의 무게는 몇 킬로그램(㎏)인지 답을 구해 보세요.",
        "question_en": "A box with 6 billiard balls of equal weight weighs 1.82 kilograms (kg). Find the weight in kilograms (kg) of one billiard ball if the empty box weighs 0.5 kilograms (kg).",
        "answer_ko": "0.22",
        "answer_en": "0.22",
        "solution_abst_ko": "1.82 0.5 [OP_SUB] 6 [OP_DIV]",
        "solution_abst_en": "1.82 0.5 [OP_SUB] 6 [OP_DIV]",
        "solution_code_ko": "var_a = 1.82\nvar_b = 0.5\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 1.82\nvar_b = 0.5\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "4169": {
        "category": "Possibility",
        "question_ko": "여섯 개의 숫자 0, 1, 2, 3, 4, 5, 8 중에서 3개를 골라 세 자리의 수를 만들었다. 같은 수를 여러 번 사용해도 된다면, 만들 수 있는 모든 수들의 합은 얼마인가?",
        "question_en": "Three of the six numbers 0, 1, 2, 3, 4, 5, and 8 have been chosen to form a three-digit number. If you can use the same number more than once, what is the sum of all the possible numbers?",
        "answer_ko": "123326",
        "answer_en": "123326",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 4 5 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 4 5 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nvar_f = 5\nvar_g = 8\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_h))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_b = [float(i) for i in list_b]\nvar_i = sum(list_b)\nprint(int(var_i))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nvar_f = 5\nvar_g = 8\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_h))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_b = [float(i) for i in list_b]\nvar_i = sum(list_b)\nprint(int(var_i))"
    },
    "4170": {
        "category": "Correspondence",
        "question_ko": "34A5를 버림하여 십의 자리까지 나타내면 3420이 됩니다. A를 구하시오.",
        "question_en": "Rounding off 34A5 to the tens place gives 3420. Find the value of A.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "34A5 [OP_GEN_POSSIBLE_LIST] 3420 [OP_LIST_MORE_EQUAL] 3420 10 [OP_ADD] [OP_LIST_LESS] 34A5 A [OP_LIST_FIND_UNK]",
        "solution_abst_en": "34A5 [OP_GEN_POSSIBLE_LIST] 3420 [OP_LIST_MORE_EQUAL] 3420 10 [OP_ADD] [OP_LIST_LESS] 34A5 A [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = '34A5'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 3420\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 3420\nvar_d = 10\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = '34A5'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))",
        "solution_code_en": "var_a = '34A5'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 3420\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 3420\nvar_d = 10\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = '34A5'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))"
    },
    "4171": {
        "category": "Arithmetic calculation",
        "question_ko": "문구점에서 200원짜리 지우개 5개, 800원짜리 연필 7개를 구매했습니다. 친구 4명이 똑같은 돈을 내려고 합니다. 친구 한 명당 얼마를 내야하는지 구하세요.",
        "question_en": "You bought 5 erasers for 200 won and 7 pencils for 800 won at a stationery store. Four of your friends are willing to pay the same amount. Find out how much you will have to pay per friend.",
        "answer_ko": "1650",
        "answer_en": "1650",
        "solution_abst_ko": "200 5 [OP_MUL] 800 7 [OP_MUL] [OP_ADD] 4 [OP_DIV]",
        "solution_abst_en": "200 5 [OP_MUL] 800 7 [OP_MUL] [OP_ADD] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 200\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 800\nvar_e = 7\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 4\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 200\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 800\nvar_e = 7\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 4\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "4172": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 95를 더해야 하는데 잘못하여 65를 더했더니 125가 되었습니다. 바르게 계산한 결과를 구하시오.",
        "question_en": "I have to add 95 to a number, but I accidentally added 65 to a number, and it became 125. Find the correct result.",
        "answer_ko": "155",
        "answer_en": "155",
        "solution_abst_ko": "125 65 [OP_SUB] 95 [OP_ADD]",
        "solution_abst_en": "125 65 [OP_SUB] 95 [OP_ADD]",
        "solution_code_ko": "var_a = 125\nvar_b = 65\nvar_c = var_a - var_b\nvar_d = 95\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 125\nvar_b = 65\nvar_c = var_a - var_b\nvar_d = 95\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "4173": {
        "category": "Geometry",
        "question_ko": "어떤 직육면체의 밑면이 정사각형이고 둘레가 32센티미터(㎝)이다. 직육면체의 높이가 9센티미터(㎝)이면 부피는 몇 세제곱센티미터(㎤)입니까?",
        "question_en": "A cuboid has a square base and a perimeter of 32 centimeters (cm). If the height of a cuboid is 9 centimeters (cm), how many cubic centimeters (cm3) is its volume?",
        "answer_ko": "576",
        "answer_en": "576",
        "solution_abst_ko": "32 4 [OP_DIV] 2 [OP_POW] 9 [OP_MUL]",
        "solution_abst_en": "32 4 [OP_DIV] 2 [OP_POW] 9 [OP_MUL]",
        "solution_code_ko": "var_a = 32\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 9\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 32\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 9\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "4174": {
        "category": "Arithmetic calculation",
        "question_ko": "세 자리 수 중 4의 배수이면서 5의 배수인 수는 모두 몇 개 입니까?",
        "question_en": "How many three-digit numbers are both multiples of 4 and multiples of 5?",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "100 999 1 [OP_LIST_ARANGE] 4 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "100 999 1 [OP_LIST_ARANGE] 4 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 4\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 4\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "4175": {
        "category": "Geometry",
        "question_ko": "직육면체 모양의 어항이 있다. 이 어항의 가로는 16센티미터(㎝), 세로는 14센티미터(㎝), 높이는 9센티미터(㎝)입니다.이 그릇에 물이 4센티미터(㎝) 높이만큼 들어 있었습니다. 이 그릇에 돌을 넣었더니 물의 높이가 9센티미터(㎝)가 되었습니다. 돌의 부피를 구하시오.",
        "question_en": "There is a fishbowl in the shape of a rectangular cuboid. This fishbowl is 16 centimeters (cm) wide, 14 centimeters (cm) long, and 9 centimeters (cm) high. The water was 4 centimeters (cm) high in this bowl. When a stone was placed in this bowl, the water level rose to 9 centimeters (cm). Find the volume of the stone.",
        "answer_ko": "1120",
        "answer_en": "1120",
        "solution_abst_ko": "16 14 [OP_MUL] 9 4 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "16 14 [OP_MUL] 9 4 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 16\nvar_b = 14\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = 4\nvar_f = var_d - var_e\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 16\nvar_b = 14\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = 4\nvar_f = var_d - var_e\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "4176": {
        "category": "Arithmetic calculation",
        "question_ko": "막대기 11개의 길이의 평균이 145.7센티미터(㎝)이다. 그런데 그 중 2개의 길이의 평균이 142.1센티미터(㎝)라고 하면, 나머지 막대의 길이의 평균을 구하시오.",
        "question_en": "The average length of the 11 sticks is 145.7 centimeters (cm). But if the average of the lengths of two of them is 142.1 centimeters (cm), find the average of the lengths of the remaining bars.",
        "answer_ko": "146.50",
        "answer_en": "146.5",
        "solution_abst_ko": "145.7 11 [OP_MUL] 142.1 2 [OP_MUL] [OP_SUB] 11 2 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "145.7 11 [OP_MUL] 142.1 2 [OP_MUL] [OP_SUB] 11 2 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 145.7\nvar_b = 11\nvar_c = var_a * var_b\nvar_d = 142.1\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 11\nvar_i = 2\nvar_j = var_h - var_i\nvar_k = var_g / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 145.7\nvar_b = 11\nvar_c = var_a * var_b\nvar_d = 142.1\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 11\nvar_i = 2\nvar_j = var_h - var_i\nvar_k = var_g / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "4177": {
        "category": "Comparison",
        "question_ko": "서로 다른 다섯 개의 바구니에 귤이 각각 20개씩 있었습니다. 며칠이 지난 후 보니 몇 개의 귤이 썩어 썩은 귤을 빼자 바구니에 담긴 귤의 개수가 각각 10개, 18개, 17개, 13개, 16개가 되었습니다. 귤이 13개 이하로 담긴 바구니에 있는 귤은 전부 꺼내 새로운 바구니에 담았을 때, 이 바구니에는 몇 개의 귤이 있을지 구하시오.",
        "question_en": "There were 20 tangerines in each of five different baskets. After a few days, you noticed that some of the tangerines were rotten, so when you removed the rotten tangerines, the number of tangerines in the basket became 10, 18, 17, 13, and 16, respectively. If you move the tangerines from the basket containing 13 or less to a new basket, how many tangerines will be in the new basket?",
        "answer_ko": "23",
        "answer_en": "23",
        "solution_abst_ko": "[OP_LIST_SOL] 10 18 17 13 16 [OP_LIST_EOL] 13 [OP_LIST_LESS_EQUAL] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 10 18 17 13 16 [OP_LIST_EOL] 13 [OP_LIST_LESS_EQUAL] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 10\nvar_b = 18\nvar_c = 17\nvar_d = 13\nvar_e = 16\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 13\nlist_b = []\nfor i in list_a:\n    if i <= var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 10\nvar_b = 18\nvar_c = 17\nvar_d = 13\nvar_e = 16\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 13\nlist_b = []\nfor i in list_a:\n    if i <= var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nprint(int(var_g))"
    },
    "4178": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 7센티미터(㎝)인 정사각형을 겹치지 않게 최대한 많이 이어 붙여서 만들 수 있는 가장 큰 정사각형의 둘레의 길이를 구하시오.",
        "question_en": "Find the perimeter of the largest square that can be made by arranging as many squares with sides of 7 centimeters (cm) as possible without overlapping.",
        "answer_ko": "168",
        "answer_en": "168",
        "solution_abst_ko": "36 0.5 [OP_POW] 7 [OP_MUL] 4 [OP_MUL]",
        "solution_abst_en": "36 0.5 [OP_POW] 7 [OP_MUL] 4 [OP_MUL]",
        "solution_code_ko": "var_a = 36\nvar_b = 0.5\nvar_c = var_a ** var_b\nvar_d = 7\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 36\nvar_b = 0.5\nvar_c = var_a ** var_b\nvar_d = 7\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "4179": {
        "category": "Arithmetic calculation",
        "question_ko": "평균이 7인 일곱 개의 수 중에 한개를 9로 바꾸니 평균이 8이 되었다.바꾼수는 원래 얼마인가?",
        "question_en": "There were 7 numbers with an average of 7, and when you changed one of them to 9, the average was 8. What was the original number before changing?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "7 7 [OP_MUL] 7 8 [OP_MUL] 9 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "7 7 [OP_MUL] 7 8 [OP_MUL] 9 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 7\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = 8\nvar_f = var_d * var_e\nvar_g = 9\nvar_h = var_f - var_g\nvar_i = var_c - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 7\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = 8\nvar_f = var_d * var_e\nvar_g = 9\nvar_h = var_f - var_g\nvar_i = var_c - var_h\nprint(int(var_i))"
    },
    "4180": {
        "category": "Geometry",
        "question_ko": "28/3킬로미터(㎞)인 도로를 시속 14/5킬로미터(㎞)로 달리면 얼마가 걸리는지 구하시오.",
        "question_en": "Find how long it would take to drive a road that is 28/3 kilometers (km) at 14/5 kilometers (km) per hour.",
        "answer_ko": "3.33",
        "answer_en": "3.33",
        "solution_abst_ko": "28/3 14/5 [OP_DIV]",
        "solution_abst_en": "28/3 14/5 [OP_DIV]",
        "solution_code_ko": "var_a = 9.333333333333334\nvar_b = 2.8\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 9.333333333333334\nvar_b = 2.8\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "4181": {
        "category": "Comparison",
        "question_ko": "호현이는 노란 구슬을 32개 가지고 있고 미란이는 파란 구슬을 34개 가지고 있습니다. 슬기가 빨간 구슬을 23개 가지고 있을 때 슬기와 호현이 중에 누가 구슬을 더 많이 가지고 있습니까?",
        "question_en": "Hohyun has 32 yellow marbles and Miran has 34 blue marbles. If Seulgi has 23 red marbles, who has more marbles, Seulgi or Hohyun?",
        "answer_ko": "호현",
        "answer_en": "Hohyun",
        "solution_abst_ko": "[OP_LIST_SOL] 슬기 호현 [OP_LIST_EOL] [OP_LIST_SOL] 23 32 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Seulgi Hohyun [OP_LIST_EOL] [OP_LIST_SOL] 23 32 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '슬기'\nvar_b = '호현'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 23\nvar_d = 32\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Seulgi'\nvar_b = 'Hohyun'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 23\nvar_d = 32\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "4182": {
        "category": "Arithmetic calculation",
        "question_ko": "숫자 2, 3, 8, 9로 나누어 떨어질 수 있는 다섯 자리 수 중 가장 작은 수는?",
        "question_en": "What is the smallest five-digit number divisible by the numbers 2, 3, 8, and 9?",
        "answer_ko": "10008",
        "answer_en": "10008",
        "solution_abst_ko": "10000 99999 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "10000 99999 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 10000\nvar_b = 99999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 3\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = 1\nlist_f=list_e.copy()\nlist_f.sort()\nvar_i = list_f[var_h-1]\nprint(int(var_i))",
        "solution_code_en": "var_a = 10000\nvar_b = 99999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 3\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = 1\nlist_f=list_e.copy()\nlist_f.sort()\nvar_i = list_f[var_h-1]\nprint(int(var_i))"
    },
    "4183": {
        "category": "Correspondence",
        "question_ko": "20에 어떤 수를 나눠주려 합니다. 잘못하여 10에 어떤 수를 나눴더니 결과는 2가 되었습니다. 바르게 계산한 결과는 얼마일까요?",
        "question_en": "You are going to divide 20 by a certain number. If you mistakenly divide 10 by the number, the result is 2. What is the correct calculation result?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "20 10 2 [OP_DIV] [OP_DIV]",
        "solution_abst_en": "20 10 2 [OP_DIV] [OP_DIV]",
        "solution_code_ko": "var_a = 20\nvar_b = 10\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 10\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "4184": {
        "category": "Correspondence",
        "question_ko": "A는 14고 B는 24입니다. 어떤 수에 A를 더하고 A를 곱한 후에 B를 빼고 B로 나눠주었더니 13이 되었습니다. 어떤 수를 구하시오.",
        "question_en": "A is 14 and B is 24. If we add A to a particular number and multiply it by A, then subtract B, then divide it by B, we get 13. Find that particular number.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "13 24 [OP_MUL] 24 [OP_ADD] 14 [OP_DIV] 14 [OP_SUB]",
        "solution_abst_en": "13 24 [OP_MUL] 24 [OP_ADD] 14 [OP_DIV] 14 [OP_SUB]",
        "solution_code_ko": "var_a = 13\nvar_b = 24\nvar_c = var_a * var_b\nvar_d = 24\nvar_e = var_c + var_d\nvar_f = 14\nvar_g = var_e / var_f\nvar_h = 14\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 13\nvar_b = 24\nvar_c = var_a * var_b\nvar_d = 24\nvar_e = var_c + var_d\nvar_f = 14\nvar_g = var_e / var_f\nvar_h = 14\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "4185": {
        "category": "Arithmetic calculation",
        "question_ko": "10 이하의 홀수는 몇 개입니까?",
        "question_en": "How many odd numbers are less than 10?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "1 10 [OP_LIST_ODD] [OP_LIST_LEN]",
        "solution_abst_en": "1 10 [OP_LIST_ODD] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 10\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = len(list_a)\nprint(int(var_c))",
        "solution_code_en": "var_a = 1\nvar_b = 10\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = len(list_a)\nprint(int(var_c))"
    },
    "4186": {
        "category": "Arithmetic calculation",
        "question_ko": "려운이와 미연이가 색종이 85장을 나누어 가졌습니다. 려운이는 분홍색 색종이를 갖지 않기로 했고 분홍색 색종이는 모두 11장이었습니다. 다른 색의 색종이는 모두 짝수 장이 있으며 두 친구가 같은 장수로 나누어 가질 때 미연이는 몇 장의 색종이를 가지게 되는지 구하시오.",
        "question_en": "Ryeowoon and Miyeon shared 85 sheets of colored paper. Ryeowoon decided not to have pink-colored paper, and there were 11 sheets of pink-colored paper. Colored paper in every other color was in even numbers to be shared equally by two friends. How many sheets of colored paper did Miyeon get?",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "85 11 [OP_SUB] 2 [OP_DIV] 11 [OP_ADD]",
        "solution_abst_en": "85 11 [OP_SUB] 2 [OP_DIV] 11 [OP_ADD]",
        "solution_code_ko": "var_a = 85\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 11\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 85\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 11\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "4187": {
        "category": "Comparison",
        "question_ko": "유나, 은지, 민영이가 가위바위보게임을 하고 있습니다. 은지는 민영이에게 졌고, 유나는 민영이를 이겼습니다. 꼴찌는 누구일까요?",
        "question_en": "Yuna, Eunji, and Minyoung are playing rock-paper-scissors game. Eunji lost to Minyoung and Yuna defeated Minyoung. Who's in last place?",
        "answer_ko": "은지",
        "answer_en": "Eunji",
        "solution_abst_ko": "[OP_LIST_SOL] 유나 은지 민영 [OP_LIST_EOL] [OP_LIST_SOL] 유나 민영 > 은지 민영 < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yuna Eunji Minyoung [OP_LIST_EOL] [OP_LIST_SOL] Yuna Minyoung > Eunji Minyoung < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '유나'\nvar_b = '은지'\nvar_c = '민영'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '유나'\nvar_e = '민영'\nvar_f = '>'\nvar_g = '은지'\nvar_h = '민영'\nvar_i = '<'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = len(list_c)\nvar_k = list_c[var_j-1]\nprint(var_k)",
        "solution_code_en": "var_a = 'Yuna'\nvar_b = 'Eunji'\nvar_c = 'Minyoung'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'Yuna'\nvar_e = 'Minyoung'\nvar_f = '>'\nvar_g = 'Eunji'\nvar_h = 'Minyoung'\nvar_i = '<'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = len(list_c)\nvar_k = list_c[var_j-1]\nprint(var_k)"
    },
    "4188": {
        "category": "Geometry",
        "question_ko": "직육면체의 어떤 한 면과 수직인 면의 개수는 몇 개일까요?",
        "question_en": "How many faces are perpendicular to any one face of a cube?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "4",
        "solution_abst_en": "4",
        "solution_code_ko": "var_a = 4\nprint(int(var_a))",
        "solution_code_en": "var_a = 4\nprint(int(var_a))"
    },
    "4189": {
        "category": "Correspondence",
        "question_ko": "115.15킬로미터(㎞)를 나눠서 뛰는 계주대회가 있다. 총 구간을 7조가 나눠서 뛰고 각 조에 7명이 나눠서 뛴다. 모든 사람이 똑같은 길이를 나눠서 달릴때 한 명이 뛰는 길이는 얼마인가?",
        "question_en": "There is a relay race that covers 115.15 kilometers (km). The total distance of the race is divided into 7 sections, and 7 people are divided into each group to run each section. If every participants run the same distance, how long does each participant covers?",
        "answer_ko": "2.35",
        "answer_en": "2.35",
        "solution_abst_ko": "115.15 7 [OP_DIV] 7 [OP_DIV]",
        "solution_abst_en": "115.15 7 [OP_DIV] 7 [OP_DIV]",
        "solution_code_ko": "var_a = 115.15\nvar_b = 7\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 115.15\nvar_b = 7\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "4190": {
        "category": "Arithmetic calculation",
        "question_ko": "배 한 개는 0.36킬로그램(㎏)입니다. 바구니 하나에 배가 30개 들어있을 때 바구니 전체의 무게를 재면 11.26킬로그램(㎏)입니다. 빈 바구니의 무게는 몇 킬로그램(㎏)일지 구하세요.",
        "question_en": "Thirty balls each weighing 0.36 kilograms (kg) are placed in a box. Find how many kilograms (kg) the box without the balls is when the box containing the balls weighed 11.26 killograms (kg).",
        "answer_ko": "0.46",
        "answer_en": "0.46",
        "solution_abst_ko": "11.26 0.36 30 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "11.26 0.36 30 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 11.26\nvar_b = 0.36\nvar_c = 30\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 11.26\nvar_b = 0.36\nvar_c = 30\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "4191": {
        "category": "Possibility",
        "question_ko": "빨간색 공, 파란색 공, 검정색 공, 노란색 공이 들어있는 상자에서 공 2개 꺼내려고 합니다. 중복을 허용하여 꺼낼 수 있는 공의 경우의 수는 모두 몇 가지입니까? 단, 공을 꺼내는 순서는 고려하지 않는다.",
        "question_en": "You are trying to get 2 balls out of a box containing a red ball, a blue ball, a black ball, and a yellow ball. How many ways are there for balls can be drawn if allowing duplication? However, the order in which the balls are retrieved is not considered.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "[OP_LIST_SOL] 빨간색 파란색 검정색 노란색 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] red blue black yellow [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '빨간색'\nvar_b = '파란색'\nvar_c = '검정색'\nvar_d = '노란색'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = var_e + var_f\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = 2\nvar_k = 1\nvar_i = int(var_i)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_i-i)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k / (i+1)\nprint(int(var_k))",
        "solution_code_en": "var_a = 'red'\nvar_b = 'blue'\nvar_c = 'black'\nvar_d = 'yellow'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = var_e + var_f\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = 2\nvar_k = 1\nvar_i = int(var_i)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_i-i)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k / (i+1)\nprint(int(var_k))"
    },
    "4192": {
        "category": "Arithmetic calculation",
        "question_ko": "장난감 1000개를 만들려고 합니다. 장난감을 만드는 속도는 매일 같다고 할 때 지금까지 하루에 100개씩 6일 동안 만들었다면 며칠이 남았습니까?",
        "question_en": "I'm trying to make 1000 toys. Assuming that the speed of making toys is the same every day, how many days are left if I have made 100 toys a day for 6 days?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "1000 100 6 [OP_MUL] [OP_SUB] 100 [OP_DIV]",
        "solution_abst_en": "1000 100 6 [OP_MUL] [OP_SUB] 100 [OP_DIV]",
        "solution_code_ko": "var_a = 1000\nvar_b = 100\nvar_c = 6\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 100\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1000\nvar_b = 100\nvar_c = 6\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 100\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "4193": {
        "category": "Arithmetic calculation",
        "question_ko": "연속하는 8개의 짝수를 더하였더니 424가 되었습니다. 8개의 짝수 중 가장 작은 수를 구하시오.",
        "question_en": "Adding 8 consecutive even numbers gives 424. Find the smallest of 8 even numbers.",
        "answer_ko": "46",
        "answer_en": "46",
        "solution_abst_ko": "424 0 8 1 [OP_SUB] 2 [OP_MUL] 2 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 8 [OP_DIV]",
        "solution_abst_en": "424 0 8 1 [OP_SUB] 2 [OP_MUL] 2 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 8 [OP_DIV]",
        "solution_code_ko": "var_a = 424\nvar_b = 0\nvar_c = 8\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = 2\nlist_a = [i for i in range(var_b, var_g + 1, var_h)]\nlist_a = [float(i) for i in list_a]\nvar_i = sum(list_a)\nvar_j = var_a - var_i\nvar_k = 8\nvar_l = var_j / var_k\nprint(int(var_l))",
        "solution_code_en": "var_a = 424\nvar_b = 0\nvar_c = 8\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = 2\nlist_a = [i for i in range(var_b, var_g + 1, var_h)]\nlist_a = [float(i) for i in list_a]\nvar_i = sum(list_a)\nvar_j = var_a - var_i\nvar_k = 8\nvar_l = var_j / var_k\nprint(int(var_l))"
    },
    "4194": {
        "category": "Possibility",
        "question_ko": "자연수 4, 5, 6을 한 번씩 사용하여 560보다 큰 수를 만드는 경우는 몇 가지인가?",
        "question_en": "How many times can you use the natural numbers 4, 5, and 6 once to form a number greater than 560?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 4 5 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 560 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 4 5 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 560 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 4\nvar_b = 5\nvar_c = 6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 560\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 4\nvar_b = 5\nvar_c = 6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 560\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "4195": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 8로 나누어야 할 것을 7로 나누었더니 몫은 13이고 나머지는 1이었습니다. 바르게 계산한 몫과 나머지의 합을 구하시오.",
        "question_en": "When a certain number that should be divided by 8 is divided by 7, the quotient is 13 and the remainder is 1. Find the sum of the correctly calculated quotient and remainder.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "13 7 [OP_MUL] 1 [OP_ADD] 8 [OP_FDIV] 13 7 [OP_MUL] 1 [OP_ADD] 8 [OP_MOD] [OP_ADD]",
        "solution_abst_en": "13 7 [OP_MUL] 1 [OP_ADD] 8 [OP_FDIV] 13 7 [OP_MUL] 1 [OP_ADD] 8 [OP_MOD] [OP_ADD]",
        "solution_code_ko": "var_a = 13\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e // var_f\nvar_h = 13\nvar_i = 7\nvar_j = var_h * var_i\nvar_k = 1\nvar_l = var_j + var_k\nvar_m = 8\nvar_n = var_l % var_m\nvar_o = var_g + var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 13\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e // var_f\nvar_h = 13\nvar_i = 7\nvar_j = var_h * var_i\nvar_k = 1\nvar_l = var_j + var_k\nvar_m = 8\nvar_n = var_l % var_m\nvar_o = var_g + var_n\nprint(int(var_o))"
    },
    "4196": {
        "category": "Geometry",
        "question_ko": "길이가 60센티미터(㎝)인 철사로 가장 큰 정사각형을 만들려고 합니다. 한 변의 길이를 몇 센티미터(㎝)로 해야 합니까?",
        "question_en": "You are going to make the largest square out of 60 centimeters (cm) of wire. How many centimeters (cm) should be the length of one side?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "60 4 [OP_DIV]",
        "solution_abst_en": "60 4 [OP_DIV]",
        "solution_code_ko": "var_a = 60\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 60\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "4197": {
        "category": "Comparison",
        "question_ko": "20명의 학생들이 버스를 기다리고 있습니다. 정국이는 윤기보다 늦게 왔고, 윤기와 정국이 사이에는 5명의 학생이 있습니다. 정국의 앞에는 6명의 학생들이 서 있습니다. 윤기의 뒤에 서 있는 학생은 몇 명입니까?",
        "question_en": "20 students are waiting for the bus. Jungkook came later than Yoongi, and there are 5 students between Yoongi and Jungkook. There are 6 students standing in front of Jungkook. How many students are standing behind Yoongi?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "20 6 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "20 6 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 6\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 6\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "4198": {
        "category": "Possibility",
        "question_ko": "1부터 9까지의 숫자카드 중 중복을 허용하여 세자리 자연수를 만들었다. 이 수들 중 각 자리 숫자의 합이 7인 숫자들은 몇 개인지 구하시오.",
        "question_en": "We created a three-digit natural number among the number cards 1 to 9 and overlaps were allowed. Find how many numbers there are whose sum of each digit is 7.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "1 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_NUM2SUM] 7 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_NUM2SUM] 7 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 7\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 7\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))"
    },
    "4199": {
        "category": "Possibility",
        "question_ko": "1, 4, 5가 적힌 카드를 한 번씩 이용하여 가장 작은 수를 만드시오.",
        "question_en": "Make the smallest number with the number cards of 1, 4, and 5 one at a time.",
        "answer_ko": "145",
        "answer_en": "145",
        "solution_abst_ko": "[OP_LIST_SOL] 1 4 5 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 4 5 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1\nvar_b = 4\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 4\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nprint(int(var_f))"
    },
    "4200": {
        "category": "Comparison",
        "question_ko": "민정이는 주머니에 빨간색 공, 파란색 공, 주황색 공, 검은색 공을 순서대로 집어 넣었습니다. 3번째로 넣은 공의 색깔은 무슨 색입니까?",
        "question_en": "Minjeong put a red ball, a blue ball, an orange ball, and a black ball in order. What is the color of the third ball?",
        "answer_ko": "주황색",
        "answer_en": "orange",
        "solution_abst_ko": "[OP_LIST_SOL] 빨간색 파란색 주황색 검은색 [OP_LIST_EOL] 3 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] red blue orange black [OP_LIST_EOL] 3 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '빨간색'\nvar_b = '파란색'\nvar_c = '주황색'\nvar_d = '검은색'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nvar_f = list_a[var_e-1]\nprint(var_f)",
        "solution_code_en": "var_a = 'red'\nvar_b = 'blue'\nvar_c = 'orange'\nvar_d = 'black'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nvar_f = list_a[var_e-1]\nprint(var_f)"
    },
    "4201": {
        "category": "Possibility",
        "question_ko": "4개의 숫자 카드 0, 1, 4, 8을 한 번씩 사용하여 일의 자리 숫자가 8인 네 번째로 작은 네 자리 수를 구한 후, 각 자리 수의 합을 구하시오.",
        "question_en": "Find the fourth smallest four-digit number with using all 4 number cards of 0, 1, 4, and 8 once whose ones digit is 8, and then find the sum of each digit.",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 4 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 8 [OP_LIST_SEARCH_FIXED_DIGIT] 4 [OP_LIST_MIN] [OP_NUM2LIST] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 4 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 8 [OP_LIST_SEARCH_FIXED_DIGIT] 4 [OP_LIST_MIN] [OP_NUM2LIST] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 4\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nvar_g = 8\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 4\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nlist_e = []\nvar_i = int(var_i)\nwhile var_i//10 > 0:\n    list_e.append(var_i%10)\n    var_i = var_i//10\nlist_e.append(var_i%10)\nlist_e = list_e[::-1]\nlist_e = [float(i) for i in list_e]\nvar_j = sum(list_e)\nprint(int(var_j))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 4\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nvar_g = 8\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 4\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nlist_e = []\nvar_i = int(var_i)\nwhile var_i//10 > 0:\n    list_e.append(var_i%10)\n    var_i = var_i//10\nlist_e.append(var_i%10)\nlist_e = list_e[::-1]\nlist_e = [float(i) for i in list_e]\nvar_j = sum(list_e)\nprint(int(var_j))"
    },
    "4202": {
        "category": "Possibility",
        "question_ko": "1이상 5이하의 홀수를 한 번씩 모두 사용하여 만든 두 번째로 작은 세 자리 수와 세 번째로 작은 세 자리수의 합을 구하시오.",
        "question_en": "Find the sum of the second smallest three-digit number and the third smallest three-digit number formed by using all odd numbers from 1 to 5 once.",
        "answer_ko": "468",
        "answer_en": "468",
        "solution_abst_ko": "1 5 [OP_LIST_ODD] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MIN] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "1 5 [OP_LIST_ODD] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MIN] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 5\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_e = list_c[var_d-1]\nvar_f = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_g = list_d[var_f-1]\nvar_h = var_e + var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 1\nvar_b = 5\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_e = list_c[var_d-1]\nvar_f = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_g = list_d[var_f-1]\nvar_h = var_e + var_g\nprint(int(var_h))"
    },
    "4203": {
        "category": "Geometry",
        "question_ko": "한 모서리가 8센티미터(㎝)인 정육면체의 겉넓이는 몇 제곱센티미터(㎠)입니까?",
        "question_en": "What is the surface area in square centimeters (cm2) of a cube with one edge of 8 centimeters (cm)?",
        "answer_ko": "384",
        "answer_en": "384",
        "solution_abst_ko": "8 2 [OP_POW] 6 [OP_MUL]",
        "solution_abst_en": "8 2 [OP_POW] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "4204": {
        "category": "Correspondence",
        "question_ko": "학생들은 한 조마다 7명씩 앉아있고, 각 반에는 9개의 조가 있다. 이 학교에 13개의 반이 있을 때, 학생은 모두 몇 명인지 구하시오.",
        "question_en": "Students sit in groups of seven, and there are nine groups in each class. If there are 13 classes in this school, how many students are there?",
        "answer_ko": "819",
        "answer_en": "819",
        "solution_abst_ko": "13 9 [OP_MUL] 7 [OP_MUL]",
        "solution_abst_en": "13 9 [OP_MUL] 7 [OP_MUL]",
        "solution_code_ko": "var_a = 13\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 13\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "4205": {
        "category": "Arithmetic calculation",
        "question_ko": "반죽 6.64그램(g)으로 호떡 하나를 만들 수 있습니다. 212.48그램(g)의 반죽을 만들었을 때 이 반죽으로 만들 수 있는 호떡은 몇 개인지 구하세요.",
        "question_en": "You can make one hotteok with 6.64 grams (g) of dough. Find how many hotteoks you can make when you have 212.48 grams (g) of dough.",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "212.48 6.64 [OP_FDIV]",
        "solution_abst_en": "212.48 6.64 [OP_FDIV]",
        "solution_code_ko": "var_a = 212.48\nvar_b = 6.64\nvar_c = var_a // var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 212.48\nvar_b = 6.64\nvar_c = var_a // var_b\nprint(int(var_c))"
    },
    "4206": {
        "category": "Possibility",
        "question_ko": "정사면체에서 면에 있는 변의 개수는 모두 몇개인가요?",
        "question_en": "How many edges are there on a face of a tetrahedron?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "3",
        "solution_abst_en": "3",
        "solution_code_ko": "var_a = 3\nprint(int(var_a))",
        "solution_code_en": "var_a = 3\nprint(int(var_a))"
    },
    "4207": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 14/8센티미터(㎝)인 정삼각형의 둘레의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "What is the perimeter of an equilateral triangle with a side of 14/8 centimeters (cm), in centimeters (cm)?",
        "answer_ko": "5.25",
        "answer_en": "5.25",
        "solution_abst_ko": "14/8 3 [OP_MUL]",
        "solution_abst_en": "14/8 3 [OP_MUL]",
        "solution_code_ko": "var_a = 1.75\nvar_b = 3\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 1.75\nvar_b = 3\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "4208": {
        "category": "Comparison",
        "question_ko": "가을이네 집에서 태권도장까지의 거리는 3킬로미터(㎞)보다 150미터(m) 더 멀고, 피아노학원까지의 거리는 3095미터(m)입니다. 태권도장과 피아노학원 중에서 가을이네 집에서 더 먼 곳은 어느 곳입니까?",
        "question_en": "The distance from Ga-eul's house to the taekwondo gym is 150 meters (m) farther than 3 kilometers (km), and the distance to the piano academy is 3095 meters (m). Which one is farther away from Ga-eul's house between taekwondo gym and piano academy?",
        "answer_ko": "태권도장",
        "answer_en": "taekwondo",
        "solution_abst_ko": "[OP_LIST_SOL] 태권도장 피아노학원 [OP_LIST_EOL] [OP_LIST_SOL] 3 1000 [OP_MUL] 150 [OP_ADD] 3095 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] taekwondo piano [OP_LIST_EOL] [OP_LIST_SOL] 3 1000 [OP_MUL] 150 [OP_ADD] 3095 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '태권도장'\nvar_b = '피아노학원'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 150\nvar_g = var_e + var_f\nvar_h = 3095\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'taekwondo'\nvar_b = 'piano'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 150\nvar_g = var_e + var_f\nvar_h = 3095\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "4209": {
        "category": "Geometry",
        "question_ko": "둘레가 32인 사각형이 가장 넓으려면 한 변의 길이가 몇 센티미터(㎝)이어야 합니까?",
        "question_en": "How many centimeters (cm) must one side of a rectangle with a perimeter of 32 centimeters (cm) be to be the rectangle the largest?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "32 4 [OP_DIV]",
        "solution_abst_en": "32 4 [OP_DIV]",
        "solution_code_ko": "var_a = 32\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 32\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "4210": {
        "category": "Geometry",
        "question_ko": "어떤 정육면체는 한 모서리의 길이가 12센티미터(㎝)입니다. 이 정육면체에 정사각형 모양의 종이를 겹치지 않게 54장 붙였더니 남는 공간이 없었습니다. 이 종이의 한 변의 길이를 구하시오.",
        "question_en": "A cube has an edge that is 12 centimeters (cm) long. I have glued 54 pieces of square paper on this cube without overlapping, and there is no empty space. Find the length of one side of this square paper.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "12 2 [OP_POW] 6 [OP_MUL] 54 [OP_DIV] 1/2 [OP_POW]",
        "solution_abst_en": "12 2 [OP_POW] 6 [OP_MUL] 54 [OP_DIV] 1/2 [OP_POW]",
        "solution_code_ko": "var_a = 12\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = var_c * var_d\nvar_f = 54\nvar_g = var_e / var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 12\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = var_c * var_d\nvar_f = 54\nvar_g = var_e / var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))"
    },
    "4211": {
        "category": "Correspondence",
        "question_ko": "90의 약수의 개수를 구하시오.",
        "question_en": "Find the number of divisors of 90.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "90 [OP_LIST_GET_DIVISOR] [OP_LIST_LEN]",
        "solution_abst_en": "90 [OP_LIST_GET_DIVISOR] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 90\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = len(list_a)\nprint(int(var_b))",
        "solution_code_en": "var_a = 90\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = len(list_a)\nprint(int(var_b))"
    },
    "4212": {
        "category": "Possibility",
        "question_ko": "4,0,2,6 숫자 4개를 두 번씩 사용하여 만들 수 있는 여덟 자리 수 중에서 가장 큰 수와 가장 작은 수를 더하면 얼마입니까?",
        "question_en": "What is the sum of the largest and smallest eight-digit numbers that can be formed by using four numbers(4, 0, 2, 6) twice?",
        "answer_ko": "86466666",
        "answer_en": "86466666",
        "solution_abst_ko": "[OP_LIST_SOL] 4 4 0 0 2 2 6 6 [OP_LIST_EOL] 8 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 4 4 0 0 2 2 6 6 [OP_LIST_EOL] 8 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 4\nvar_c = 0\nvar_d = 0\nvar_e = 2\nvar_f = 2\nvar_g = 6\nvar_h = 6\nlist_a= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_i = 8\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_i))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_j = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_k = list_c[-var_j]\nvar_l = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_m = list_d[var_l-1]\nvar_n = var_k + var_m\nprint(int(var_n))",
        "solution_code_en": "var_a = 4\nvar_b = 4\nvar_c = 0\nvar_d = 0\nvar_e = 2\nvar_f = 2\nvar_g = 6\nvar_h = 6\nlist_a= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_i = 8\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_i))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_j = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_k = list_c[-var_j]\nvar_l = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_m = list_d[var_l-1]\nvar_n = var_k + var_m\nprint(int(var_n))"
    },
    "4213": {
        "category": "Comparison",
        "question_ko": "총 3개의 숫자 0.8, 1/2, 0.5이 있습니다. 이 중 2보다 작은 수 중 가장 큰 수를 구하면 무엇인가요?",
        "question_en": "There are a total of three numbers: 0.8, 1/2, and 0.5. What is the largest out of these numbers that is less than 2?",
        "answer_ko": "0.80",
        "answer_en": "0.8",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.5 [OP_LIST_EOL] 2 [OP_LIST_LESS] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.5 [OP_LIST_EOL] 2 [OP_LIST_LESS] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = []\nfor i in list_a:\n    if i < var_d:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint('{:.2f}'.format(round(var_f+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = []\nfor i in list_a:\n    if i < var_d:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint('{:.2f}'.format(round(var_f+1e-10,2)))"
    },
    "4214": {
        "category": "Arithmetic calculation",
        "question_ko": "사탕을 6명에게 똑같이 나누어 주어야 할 것을 잘못하여 5명에게 똑같이 나누어 주었더니 한 사람당 18개씩 주고 3개가 모자랐습니다. 이 사탕을 6명에게 똑같이 나누어 주면 한 사람당 최대한 몇 개씩 가지게 됩니까?",
        "question_en": "I made a mistake when giving out candies, so I gave them to 5 people instead of 6. I intended to give 18 candies to each person, but I was 3 candies short. If I had given these candies to 6 people, how many would each person have?",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "5 18 [OP_MUL] 3 [OP_ADD] 6 [OP_FDIV] 1 [OP_ADD]",
        "solution_abst_en": "5 18 [OP_MUL] 3 [OP_ADD] 6 [OP_FDIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 18\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = 6\nvar_g = var_e // var_f\nvar_h = 1\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 5\nvar_b = 18\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = 6\nvar_g = var_e // var_f\nvar_h = 1\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "4215": {
        "category": "Arithmetic calculation",
        "question_ko": "태형이는 교실에서 6번째로 키가 작고, 석진이의 바로 다음으로 키가 작습니다. 석진이는 몇 번째로 키가 작습니까?",
        "question_en": "Taehyung is the 6th shortest student in the class, and Seokjin stands right in front of him when they line up in ascending order. In what position will Seokjin's height be in ordinal number?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "6 1 [OP_SUB]",
        "solution_abst_en": "6 1 [OP_SUB]",
        "solution_code_ko": "var_a = 6\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "4216": {
        "category": "Possibility",
        "question_ko": "정국이는 마트에 가서 과자를 고르려고 합니다. 20가지의 과자들 중 5개의 과자를 고르려고 한다면 과자를 고르는 방법은 몇 가지인가요?",
        "question_en": "Jungkook is going to the mart to pick out snacks. If you are trying to choose 5 snacks out of 20, how many ways are possible to choose them?",
        "answer_ko": "42504",
        "answer_en": "42504",
        "solution_abst_ko": "20 1 [OP_SUB] 5 [OP_ADD] 5 [OP_COMB]",
        "solution_abst_en": "20 1 [OP_SUB] 5 [OP_ADD] 5 [OP_COMB]",
        "solution_code_ko": "var_a = 20\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g / (i+1)\nprint(int(var_g))",
        "solution_code_en": "var_a = 20\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g / (i+1)\nprint(int(var_g))"
    },
    "4217": {
        "category": "Comparison",
        "question_ko": "3개의 숫자 0.8, 1/2, 0.9가 있습니다. 3보다 작거나 같은 수는 몇 개입니까?",
        "question_en": "There are three numbers 0.8, 1/2, and 0.9. How many numbers are less than or equal to 3?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 3 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 3 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = []\nfor i in list_a:\n    if i <= var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = []\nfor i in list_a:\n    if i <= var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "4218": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.9의 숫자가 있다. 이 중 0.3보다 큰 숫자들의 합을 구하시오.",
        "question_en": "There are numbers 0.8, 1/2, and 0.9. Find the sum of all numbers greater than 0.3.",
        "answer_ko": "2.20",
        "answer_en": "2.2",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 0.3 [OP_LIST_MORE] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 0.3 [OP_LIST_MORE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.3\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.3\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "4219": {
        "category": "Geometry",
        "question_ko": "길이가 78센티미터(㎝)인 끈을 이용해 가장 큰 정삼각형을 만들었습니다. 이 정삼각형의 한 변은 몇 센티미터(㎝)입니까?",
        "question_en": "The largest equilateral triangle was created by using a 78 centimeters (cm) long string. How many centimeters (cm) is one side of this equilateral triangle?",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "78 3 [OP_DIV]",
        "solution_abst_en": "78 3 [OP_DIV]",
        "solution_code_ko": "var_a = 78\nvar_b = 3\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 78\nvar_b = 3\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "4220": {
        "category": "Possibility",
        "question_ko": "4명의 친구가 서로 다른 사람들과 한번씩 악수를 할때 악수는 총 몇번 이루어 집니까?",
        "question_en": "When 4 friends shake hands with each other once, how many handshakes are made in total?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "3 3 1 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "3 3 1 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 3\nvar_b = 3\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 3\nvar_b = 3\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "4221": {
        "category": "Correspondence",
        "question_ko": "63을 A로 나누었을 때, 몫과 나머지는 각각 B와 C가 됩니다. A, B, C는 자연수 입니다. 몫과 나머지가 같은 경우, 나누는 수 A 중 가장 큰 수를 구하시오.",
        "question_en": "When 63 is divided by A, the quotient and remainder are B and C, respectively. A, B, and C are natural numbers. If the quotient and the remainder are equal, find the largest number among the divisors A.",
        "answer_ko": "62",
        "answer_en": "62",
        "solution_abst_ko": "63 1 [OP_SUB]",
        "solution_abst_en": "63 1 [OP_SUB]",
        "solution_code_ko": "var_a = 63\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 63\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "4222": {
        "category": "Geometry",
        "question_ko": "정육면체 모양의 선물 상자가 있습니다. 이 선물 상자를 겹치지 않고 포장하는데 사용한 포장지의 넓이가 600일때, 이 선물 상자의 부피를 구하시오.",
        "question_en": "There is a cube-shaped gift box. If the area of the wrapping paper used to wrap this gift box without overlapping is 600, find the volume of this gift box.",
        "answer_ko": "1000",
        "answer_en": "1000",
        "solution_abst_ko": "600 6 [OP_DIV] 1/2 [OP_POW] 3 [OP_POW]",
        "solution_abst_en": "600 6 [OP_DIV] 1/2 [OP_POW] 3 [OP_POW]",
        "solution_code_ko": "var_a = 600\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 3\nvar_g = var_e ** var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 600\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 3\nvar_g = var_e ** var_f\nprint(int(var_g))"
    },
    "4223": {
        "category": "Correspondence",
        "question_ko": "2A3-36=197입니다. A는 얼마인가요?",
        "question_en": "2A3-36=197 is true. How much is A?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "2A3-36=197 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "2A3-36=197 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '2A3-36=197'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '2A3-36=197'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "4224": {
        "category": "Correspondence",
        "question_ko": "옷을 만드는 공장에서 하루에 200벌 이상 500벌 이하의 옷을 만든다. 오늘 만든 옷의 개수는 9의 배수이고, 3를 빼면 8의 배수이고, 2를 빼면 5의 배수이다. 오늘 만든 옷의 개수를 구하시오.",
        "question_en": "A factory makes clothes between 200 and 500 clothes a day. The number of clothes made today is a multiple of 9, subtracting 3 is a multiple of 8, subtracting 2 is a multiple of 5. Find the number of clothes made today.",
        "answer_ko": "387",
        "answer_en": "387",
        "solution_abst_ko": "200 500 1 [OP_LIST_ARANGE] 5 2 [OP_LIST_DIVIDE_AND_REMAIN] 8 3 [OP_LIST_DIVIDE_AND_REMAIN] 9 0 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "200 500 1 [OP_LIST_ARANGE] 5 2 [OP_LIST_DIVIDE_AND_REMAIN] 8 3 [OP_LIST_DIVIDE_AND_REMAIN] 9 0 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 200\nvar_b = 500\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nvar_e = 2\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 8\nvar_g = 3\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 9\nvar_i = 0\nlist_d = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_c:\n    i = int(i)\n    if i%var_h == var_i:\n        list_d.append(i)\nvar_j = 1\nvar_k = list_d[var_j-1]\nprint(int(var_k))",
        "solution_code_en": "var_a = 200\nvar_b = 500\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nvar_e = 2\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 8\nvar_g = 3\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 9\nvar_i = 0\nlist_d = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_c:\n    i = int(i)\n    if i%var_h == var_i:\n        list_d.append(i)\nvar_j = 1\nvar_k = list_d[var_j-1]\nprint(int(var_k))"
    },
    "4225": {
        "category": "Arithmetic calculation",
        "question_ko": "통나무를 한 번 자르는 데에는 9초가 걸리고 한 번 자른 후의 휴식시간은 5초입니다. 하나의 통나무를 16도막으로 자르는 데에 걸리는 시간은 몇 초인지 구하세요.",
        "question_en": "It takes 9 seconds to cut a log, and the rest period after one cut is 5 seconds. Find how many seconds it takes to cut a log into 16 slices.",
        "answer_ko": "210",
        "answer_en": "210",
        "solution_abst_ko": "16 1 [OP_SUB] 9 5 [OP_ADD] [OP_MUL]",
        "solution_abst_en": "16 1 [OP_SUB] 9 5 [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 16\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 9\nvar_e = 5\nvar_f = var_d + var_e\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 16\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 9\nvar_e = 5\nvar_f = var_d + var_e\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "4226": {
        "category": "Possibility",
        "question_ko": "다음 수들의 평균은 얼마입니까? 12부터 53까지의 자연수",
        "question_en": "What is the average of the following numbers? Natural numbers from 12 to 53.",
        "answer_ko": "32.50",
        "answer_en": "32.5",
        "solution_abst_ko": "12 53 1 [OP_LIST_ARANGE] [OP_LIST_MEAN]",
        "solution_abst_en": "12 53 1 [OP_LIST_ARANGE] [OP_LIST_MEAN]",
        "solution_code_ko": "var_a = 12\nvar_b = 53\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_a = [float(i) for i in list_a]\nvar_d = sum(list_a)/len(list_a)\nprint('{:.2f}'.format(round(var_d+1e-10,2)))",
        "solution_code_en": "var_a = 12\nvar_b = 53\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_a = [float(i) for i in list_a]\nvar_d = sum(list_a)/len(list_a)\nprint('{:.2f}'.format(round(var_d+1e-10,2)))"
    },
    "4227": {
        "category": "Arithmetic calculation",
        "question_ko": "무게가 220그램(g)인 작은 상자에 책을 각각 6권씩 넣은 후 이 작은 상자 9개를 무게가 250그램(g)인 큰 상자에 넣었더니 13.3킬로그램(㎏)이 되었습니다. 각각의 책의 무게가 같다면 책 한 권의 무게는 몇 그램(g)입니까?",
        "question_en": "After putting 6 books each in a small box weighing 220 grams (g), and then putting 9 of these small boxes in a large box weighing 250 grams (g), the weight was 13.3 kilograms (kg). If each book weighs the same, how many grams (g) does one book weigh?",
        "answer_ko": "205",
        "answer_en": "205",
        "solution_abst_ko": "13.3 1000 [OP_MUL] 250 [OP_SUB] 220 9 [OP_MUL] [OP_SUB] 6 9 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "13.3 1000 [OP_MUL] 250 [OP_SUB] 220 9 [OP_MUL] [OP_SUB] 6 9 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 13.3\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 250\nvar_e = var_c - var_d\nvar_f = 220\nvar_g = 9\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nvar_j = 6\nvar_k = 9\nvar_l = var_j * var_k\nvar_m = var_i / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 13.3\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 250\nvar_e = var_c - var_d\nvar_f = 220\nvar_g = 9\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nvar_j = 6\nvar_k = 9\nvar_l = var_j * var_k\nvar_m = var_i / var_l\nprint(int(var_m))"
    },
    "4228": {
        "category": "Correspondence",
        "question_ko": "34, 35, 36, 37 중에서 34보다 크고 18+18보다 작은 값을 구하시오.",
        "question_en": "Find the value greater than 34 and less than 18+18 among 34, 35, 36, and 37.",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "[OP_LIST_SOL] 34 35 36 37 [OP_LIST_EOL] 34 [OP_LIST_MORE] 18 18 [OP_ADD] [OP_LIST_LESS] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] 34 35 36 37 [OP_LIST_EOL] 34 [OP_LIST_MORE] 18 18 [OP_ADD] [OP_LIST_LESS] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 34\nvar_b = 35\nvar_c = 36\nvar_d = 37\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 34\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nvar_f = 18\nvar_g = 18\nvar_h = var_f + var_g\nlist_c = []\nfor i in list_b:\n    if i < var_h:\n        list_c.append(i)\nvar_i = 1\nvar_j = list_c[var_i-1]\nprint(int(var_j))",
        "solution_code_en": "var_a = 34\nvar_b = 35\nvar_c = 36\nvar_d = 37\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 34\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nvar_f = 18\nvar_g = 18\nvar_h = var_f + var_g\nlist_c = []\nfor i in list_b:\n    if i < var_h:\n        list_c.append(i)\nvar_i = 1\nvar_j = list_c[var_i-1]\nprint(int(var_j))"
    },
    "4229": {
        "category": "Possibility",
        "question_ko": "숫자 2, 3, 8을 사용하여 만들 수 있는 세 자리 수는 모두 몇 개입니까? 단, 같은 숫자가 여러 번 사용될 수 있습니다.",
        "question_en": "How many three-digit numbers can you make using the numbers 2, 3, and 8? However, the same number can be used multiple times.",
        "answer_ko": "27",
        "answer_en": "27",
        "solution_abst_ko": "[OP_LIST_SOL] 2 3 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 2 3 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "4230": {
        "category": "Geometry",
        "question_ko": "삼각기둥에서 꼭짓점의 개수를 A, 모서리의 개수를 B라 할 때, A+B의 값은?",
        "question_en": "If A is the number of vertices and B is the number of edges in a triangular prism, what is the value of A+B?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "3 2 [OP_MUL] 3 3 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "3 2 [OP_MUL] 3 3 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "4231": {
        "category": "Comparison",
        "question_ko": "시험에서 율전이는 명륜이보다 잘했고 천천이 보다 못 했습니다. 명륜이는 9등, 천천이는 7등일 때 율전이는 몇 등 입니까?",
        "question_en": "In the exam, Yul-jeon did better than Myeong-ryun and did worse than Cheon-chun. If Myeong-ryun is the 9th and Cheoncheon is the 7th, what rank is Yul-jeon?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "9 7 [OP_ADD] 2 [OP_FDIV]",
        "solution_abst_en": "9 7 [OP_ADD] 2 [OP_FDIV]",
        "solution_code_ko": "var_a = 9\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "4232": {
        "category": "Geometry",
        "question_ko": "넓이가 3제곱센티미터(㎠)인 직사각형의 가로와 새로의 길이를 각각 5배로 늘리면 넓이는 몇 제곱센티미터(㎠)가 되는지 구하시오.",
        "question_en": "You have multiplied the width and height of a rectangle of 3 square centimetres (cm2) by 5. Find the area in square centimetres (cm2) of this enlarged rectangle.",
        "answer_ko": "750",
        "answer_en": "750",
        "solution_abst_ko": "30 5 5 [OP_MUL] [OP_MUL]",
        "solution_abst_en": "30 5 5 [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 30\nvar_b = 5\nvar_c = 5\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 30\nvar_b = 5\nvar_c = 5\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nprint(int(var_e))"
    },
    "4233": {
        "category": "Arithmetic calculation",
        "question_ko": "영찬이는 사과를 똑같이 3조각으로 나누어 한 조각을 먹었습니다. 민혁이는 같은 크기의 사과를 똑같이 12조각으로 나누었습니다. 영찬이와 같은 양의 사과를 먹으려면 민혁이는 사과를 몇 조각 먹어야 합니까?",
        "question_en": "Yeongchan divided the apple into 3 equal slices and ate one slice. Minhyuk divided an apple of the same size into 12 equal slices. How many slices of apples does Minhyuk need to eat to eat the same amount of apples as Yeongchan?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "12 3 [OP_DIV]",
        "solution_abst_en": "12 3 [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 3\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 12\nvar_b = 3\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "4234": {
        "category": "Correspondence",
        "question_ko": "4와 어떤 수의 곱에서 28을 빼고 7로 나누고 12를 더했더니 36이 되었습니다. 어떤 수를 구하세요.",
        "question_en": "When we subtract 28 from the product of 4 and some number, divide it by 7 and add 12, we get 36. Find this number",
        "answer_ko": "49",
        "answer_en": "49",
        "solution_abst_ko": "36 12 [OP_SUB] 7 [OP_MUL] 28 [OP_ADD] 4 [OP_DIV]",
        "solution_abst_en": "36 12 [OP_SUB] 7 [OP_MUL] 28 [OP_ADD] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 36\nvar_b = 12\nvar_c = var_a - var_b\nvar_d = 7\nvar_e = var_c * var_d\nvar_f = 28\nvar_g = var_e + var_f\nvar_h = 4\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 36\nvar_b = 12\nvar_c = var_a - var_b\nvar_d = 7\nvar_e = var_c * var_d\nvar_f = 28\nvar_g = var_e + var_f\nvar_h = 4\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "4235": {
        "category": "Geometry",
        "question_ko": "길이가 25센티미터(㎝)인 테이프를 다음 테이프와 3센티미터(㎝)씩 겹쳐지게 이으려고 합니다. 64장의 테이프를 이어서 붙이면 전체의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "You want to connect 25 centimeters (cm) long tapes by overlapping the next tape by 3 centimeters (cm). What is the total length in centimeters (cm) of 64 sheets of tape?",
        "answer_ko": "1411",
        "answer_en": "1411",
        "solution_abst_ko": "25 64 [OP_MUL] 3 64 1 [OP_SUB] [OP_MUL] [OP_SUB]",
        "solution_abst_en": "25 64 [OP_MUL] 3 64 1 [OP_SUB] [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 25\nvar_b = 64\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = 64\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_c - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 25\nvar_b = 64\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = 64\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_c - var_h\nprint(int(var_i))"
    },
    "4236": {
        "category": "Comparison",
        "question_ko": "서로 다른 다섯 개의 바구니에 귤이 각각 20개씩 있었습니다. 며칠이 지난 후 보니 몇 개의 귤이 썩어 썩은 귤을 빼자 바구니에 담긴 귤의 개수가 각각 10개, 18개, 17개, 13개, 16개가 되었습니다. 귤이 13개 이하로 담긴 바구니는 몇 개입니까?",
        "question_en": "There were 20 tangerines each in five different baskets. After a few days, I noticed that some of the tangerines were rotten, so when I removed the rotten tangerines, the number of tangerines in the baskets became 10, 18, 17, 13, and 16, respectively. How many baskets contain 13 or fewer tangerines?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 10 18 17 13 16 [OP_LIST_EOL] 13 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 10 18 17 13 16 [OP_LIST_EOL] 13 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 10\nvar_b = 18\nvar_c = 17\nvar_d = 13\nvar_e = 16\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 13\nlist_b = []\nfor i in list_a:\n    if i <= var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 10\nvar_b = 18\nvar_c = 17\nvar_d = 13\nvar_e = 16\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 13\nlist_b = []\nfor i in list_a:\n    if i <= var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "4237": {
        "category": "Correspondence",
        "question_ko": "백의 자리 수가 7, 일의 자리 수가 9인 세 자리 수가 있습니다. 이 수를 십의 자리에서 올림하면 800이 된다고 할 때, 십의 자리에 들어갈 수 있는 숫자는 모두 몇 개입니까?",
        "question_en": "There is a three-digit number whose number in the hundreds place is 7 and in the ones place 9. If it becomes 800 when this number is rounded up from the tens place, how many numbers can fit in the tens place?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "[OP_LIST_SOL] 7 A 9 [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 700 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 7 A 9 [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 700 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 7\nvar_b = 'A'\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nans_dict = dict()\nvar_d = str(var_d)\nlist_b = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_d) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_b.append(new_elem)\nvar_e = 700\nlist_c = []\nfor i in list_b:\n    if i >= var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 7\nvar_b = 'A'\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nans_dict = dict()\nvar_d = str(var_d)\nlist_b = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_d) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_b.append(new_elem)\nvar_e = 700\nlist_c = []\nfor i in list_b:\n    if i >= var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "4238": {
        "category": "Comparison",
        "question_ko": "은지가 왼쪽에서 10번째 열, 오른쪽에서 8번째 열, 앞에서 3번째 줄, 뒤에서 12번째 줄에 서서 줄넘기를 하고 있습니다. 각 줄마다 서 있는 학생의 수가 같다고 할 때, 줄넘기를 하고 있는 학생은 모두 몇 명입니까?",
        "question_en": "Eunji is jumping a rope in the 10th row from the left, the 8th row from the right, the 3rd row from the front, and the 12th row from the back. If the number of students standing in each row is the same, how many students are jumping ropes?",
        "answer_ko": "238",
        "answer_en": "238",
        "solution_abst_ko": "10 8 [OP_ADD] 1 [OP_SUB] 3 12 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "10 8 [OP_ADD] 1 [OP_SUB] 3 12 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = 12\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 10\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = 12\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))"
    },
    "4239": {
        "category": "Comparison",
        "question_ko": "윤기는 7, 정국은 6, 유나는 9, 유정은 8, 태형은 10만큼 모았습니다. 2번째로 작은 숫자를 가진 사람은 누구입니까?",
        "question_en": "Yoongi collected 7 points, Jungkook 6 points, Yuna 9 points, Yoojung 8 points, and Taehyung 10 points. Who would be the one with the 2nd smallest number?",
        "answer_ko": "윤기",
        "answer_en": "Yoongi",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 유나 유정 태형 [OP_LIST_EOL] [OP_LIST_SOL] 7 6 9 8 10 [OP_LIST_EOL] 2 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook Yuna Yoojung Taehyung [OP_LIST_EOL] [OP_LIST_SOL] 7 6 9 8 10 [OP_LIST_EOL] 2 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nvar_c = '유나'\nvar_d = '유정'\nvar_e = '태형'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 7\nvar_g = 6\nvar_h = 9\nvar_i = 8\nvar_j = 10\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_k = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[var_k-1]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nvar_c = 'Yuna'\nvar_d = 'Yoojung'\nvar_e = 'Taehyung'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 7\nvar_g = 6\nvar_h = 9\nvar_i = 8\nvar_j = 10\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_k = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[var_k-1]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "4240": {
        "category": "Possibility",
        "question_ko": "세 자리수 중 8, 0, 7이 한 번씩 사용된 수는 중 가장 큰 수는 무엇입니까?",
        "question_en": "What is the largest number among three-digit numbers that used each of 8, 0, and 7 once?",
        "answer_ko": "870",
        "answer_en": "870",
        "solution_abst_ko": "[OP_LIST_SOL] 0 8 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 0 8 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 0\nvar_b = 8\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))",
        "solution_code_en": "var_a = 0\nvar_b = 8\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))"
    },
    "4241": {
        "category": "Possibility",
        "question_ko": "같은 색의 바둑돌은 구별이 되지 않습니다. 흰색 바둑돌 2개와 검은색 바둑돌 1개를 배열할때 서로 다르게 배열하는 방법은 모두 몇 가지입니까?",
        "question_en": "The same color stones cannot be distinguished. How many ways can you arrange 2 white and 1 black stones differently?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "1 2 [OP_ADD] 1 2 [OP_ADD] [OP_PERM] 2 2 [OP_PERM] [OP_DIV]",
        "solution_abst_en": "1 2 [OP_ADD] 1 2 [OP_ADD] [OP_PERM] 2 2 [OP_PERM] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 2\nvar_f = var_d + var_e\nvar_g = 1\nvar_c = int(var_c)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_c-i)\nvar_h = 2\nvar_i = 2\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nvar_k = var_g / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 1\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 2\nvar_f = var_d + var_e\nvar_g = 1\nvar_c = int(var_c)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_c-i)\nvar_h = 2\nvar_i = 2\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nvar_k = var_g / var_j\nprint(int(var_k))"
    },
    "4242": {
        "category": "Comparison",
        "question_ko": "4개의 숫자 5, 8, 1, 2 중 가장 작은 숫자는 무엇입니까?",
        "question_en": "What is the smallest number among the four numbers 5, 8, 1, and 2?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 5 8 1 2 [OP_LIST_EOL] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 5 8 1 2 [OP_LIST_EOL] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 5\nvar_b = 8\nvar_c = 1\nvar_d = 2\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nprint(int(var_f))",
        "solution_code_en": "var_a = 5\nvar_b = 8\nvar_c = 1\nvar_d = 2\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nprint(int(var_f))"
    },
    "4243": {
        "category": "Geometry",
        "question_ko": "크기가 다른 두 원 A, B가 있습니다. A 원의 지름은 80센티미터(㎝)입니다. A원의 반지름은 B원의 반지름의 4배입니다. B원의 반지름은 무엇입니까?",
        "question_en": "There are two circles A and B of different sizes. The diameter of circle A is 80 centimeters (cm). The radius of circle A is 4 times the radius of circle B. What is the radius of circle B?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "80 4 [OP_DIV] 2 [OP_DIV]",
        "solution_abst_en": "80 4 [OP_DIV] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 80\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 80\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "4244": {
        "category": "Arithmetic calculation",
        "question_ko": "사탕이 25개씩 들어있는 상자가 5개 있습니다. 학생 13명이 사탕을 8개씩 나누어 가지려고 할 때, 나누고 남은 사탕의 개수는 몇 개입니까?",
        "question_en": "There are 5 boxes of 25 candies each. If 13 students try to divide the candy into 8 pieces, how many candies are left after dividing?",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "25 5 [OP_MUL] 13 8 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "25 5 [OP_MUL] 13 8 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 25\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = 8\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 25\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = 8\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "4245": {
        "category": "Geometry",
        "question_ko": "바퀴의 반지름의 길이가 7센티미터(㎝)일 때, 바퀴의 지름의 길이는 몇 센티미터(㎝)인가요?",
        "question_en": "If the radius of the wheel is 7 centimeters (cm), how many centimeters (cm) is the diameter of the wheel?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "7 2 [OP_MUL]",
        "solution_abst_en": "7 2 [OP_MUL]",
        "solution_code_ko": "var_a = 7\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 7\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "4246": {
        "category": "Geometry",
        "question_ko": "정육면체 모양의 주사위에는 1부터 6까지의 수가 적혀 있습니다. 마주 보는 면에 적혀 있는 숫자끼리 더하면 7이 된다고 할 때, 3과 마주보는 면에 적혀있는 수는 무엇일까요?",
        "question_en": "The cube-shaped dice have the numbers 1 through 6 written on them. If the numbers written on the opposite side add up to 7, what is the number written on the side opposite to 3?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "7 3 [OP_SUB]",
        "solution_abst_en": "7 3 [OP_SUB]",
        "solution_code_ko": "var_a = 7\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 7\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "4247": {
        "category": "Geometry",
        "question_ko": "한 꼭짓점에서 1개의 대각선을 그을 수 있는 다각형의 변의 개수를 구하시오.",
        "question_en": "Find the number of sides of a polygon of which one diagonal can be drawn from one vertex.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "1 3 [OP_ADD]",
        "solution_abst_en": "1 3 [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "4248": {
        "category": "Correspondence",
        "question_ko": "A, B는 서로 다른 수입니다. 세 자리 수 7AB는 3으로 나누어떨어질때 7AB가 될 수 있는 수는 모두 몇 개입니까?",
        "question_en": "A and B are different numbers. When the three-digit number 7AB can be divided by 3 without any remainder, how many numbers can satisfy to be 7AB?",
        "answer_ko": "33",
        "answer_en": "33",
        "solution_abst_ko": "7AB [OP_GEN_POSSIBLE_LIST] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "7AB [OP_GEN_POSSIBLE_LIST] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '7AB'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 3\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))",
        "solution_code_en": "var_a = '7AB'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 3\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))"
    },
    "4249": {
        "category": "Arithmetic calculation",
        "question_ko": "화단에 장미 57송이와 튤립 82송이가 있습니다. 튤립은 장미와 백합의 수를 합한 것보다 13송이 더 많이 있습니다. 화단에 있는 백합은 몇 송이입니까?",
        "question_en": "There are 57 roses and 82 tulips in the flower bed. There are 13 more tulips than the sum of roses and lilies. How many lilies are in the flower bed?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "82 13 [OP_SUB] 57 [OP_SUB]",
        "solution_abst_en": "82 13 [OP_SUB] 57 [OP_SUB]",
        "solution_code_ko": "var_a = 82\nvar_b = 13\nvar_c = var_a - var_b\nvar_d = 57\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 82\nvar_b = 13\nvar_c = var_a - var_b\nvar_d = 57\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "4250": {
        "category": "Arithmetic calculation",
        "question_ko": "도로를 16구간으로 나누어 양 끝을 제외한 도로에 깃발을 설치하려고 합니다. 깃발을 하나 설치하는 데에 걸리는 시간은 9초 입니다. 또 하나의 깃발을 설치한 후에는 5초동안 휴식을 취합니다. 깃발을 모두 설치하는 데 걸리는 시간을 구하세요.",
        "question_en": "We are going to divide the road into 16 sections and install flags on the road except for both ends. It takes 9 seconds to plant one flag. We take a rest for 5 seconds after placing another flag. Find the time it takes to place all the flags.",
        "answer_ko": "210",
        "answer_en": "210",
        "solution_abst_ko": "16 1 [OP_SUB] 9 5 [OP_ADD] [OP_MUL]",
        "solution_abst_en": "16 1 [OP_SUB] 9 5 [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 16\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 9\nvar_e = 5\nvar_f = var_d + var_e\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 16\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 9\nvar_e = 5\nvar_f = var_d + var_e\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "4251": {
        "category": "Correspondence",
        "question_ko": "어떤 수는 2와 5 사이에 있고, 4보다 작은 한 자리 수입니다. 어떤 수를 구하시오.",
        "question_en": "The number is in between 2 and 5 and a single digit number less than 4. Find what the number is.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "2 1 [OP_ADD] 5 1 [OP_SUB] 1 [OP_LIST_ARANGE] 4 [OP_LIST_LESS] 1 [OP_LIST_GET]",
        "solution_abst_en": "2 1 [OP_ADD] 5 1 [OP_SUB] 1 [OP_LIST_ARANGE] 4 [OP_LIST_LESS] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 2\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = 4\nlist_b = []\nfor i in list_a:\n    if i < var_h:\n        list_b.append(i)\nvar_i = 1\nvar_j = list_b[var_i-1]\nprint(int(var_j))",
        "solution_code_en": "var_a = 2\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = 4\nlist_b = []\nfor i in list_a:\n    if i < var_h:\n        list_b.append(i)\nvar_i = 1\nvar_j = list_b[var_i-1]\nprint(int(var_j))"
    },
    "4252": {
        "category": "Correspondence",
        "question_ko": "3A3B를 반올림하여 백의 자리까지 나타내면 3400입니다. A는 무엇입니까?",
        "question_en": "3A3B rounded to the hundreds place is 3400. What is A?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "3A3B [OP_GEN_POSSIBLE_LIST] 3400 50 [OP_SUB] [OP_LIST_MORE_EQUAL] 3400 50 [OP_ADD] [OP_LIST_LESS] 3A3B A [OP_LIST_FIND_UNK]",
        "solution_abst_en": "3A3B [OP_GEN_POSSIBLE_LIST] 3400 50 [OP_SUB] [OP_LIST_MORE_EQUAL] 3400 50 [OP_ADD] [OP_LIST_LESS] 3A3B A [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = '3A3B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 3400\nvar_c = 50\nvar_d = var_b - var_c\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nvar_e = 3400\nvar_f = 50\nvar_g = var_e + var_f\nlist_c = []\nfor i in list_b:\n    if i < var_g:\n        list_c.append(i)\nvar_h = '3A3B'\nvar_i = 'A'\nvar_h = str(var_h)\nvar_i = str(var_i)\nunk_idx = var_h.index(var_i)\nvar_j = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_j = int(elem[unk_idx])\nprint(int(var_j))",
        "solution_code_en": "var_a = '3A3B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 3400\nvar_c = 50\nvar_d = var_b - var_c\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nvar_e = 3400\nvar_f = 50\nvar_g = var_e + var_f\nlist_c = []\nfor i in list_b:\n    if i < var_g:\n        list_c.append(i)\nvar_h = '3A3B'\nvar_i = 'A'\nvar_h = str(var_h)\nvar_i = str(var_i)\nunk_idx = var_h.index(var_i)\nvar_j = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_j = int(elem[unk_idx])\nprint(int(var_j))"
    },
    "4253": {
        "category": "Comparison",
        "question_ko": "0.12, 0.23, 0.22 중 가장 큰 수와 가장 작은 수의 차를 구하시오",
        "question_en": "Find the difference between the largest number and the smallest number among 0.12, 0.23, and 0.22.",
        "answer_ko": "0.11",
        "answer_en": "0.11",
        "solution_abst_ko": "[OP_LIST_SOL] 0.12 0.23 0.22 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 0.12 0.23 0.22 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 0.12\nvar_b = 0.23\nvar_c = 0.22\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e - var_g\nprint('{:.2f}'.format(round(var_h+1e-10,2)))",
        "solution_code_en": "var_a = 0.12\nvar_b = 0.23\nvar_c = 0.22\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e - var_g\nprint('{:.2f}'.format(round(var_h+1e-10,2)))"
    },
    "4254": {
        "category": "Comparison",
        "question_ko": "1/4, 0.7, 2/3, 0.4, 2/5 중 0.5보다 큰 수는 몇 개입니까?",
        "question_en": "How many out of 1/4, 0.7, 2/3, 0.4, 2/5 are greater than 0.5?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 1/4 0.7 2/3 0.4 2/5 [OP_LIST_EOL] 0.5 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1/4 0.7 2/3 0.4 2/5 [OP_LIST_EOL] 0.5 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.25\nvar_b = 0.7\nvar_c = 0.6666666666666666\nvar_d = 0.4\nvar_e = 0.4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 0.5\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 0.25\nvar_b = 0.7\nvar_c = 0.6666666666666666\nvar_d = 0.4\nvar_e = 0.4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 0.5\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "4255": {
        "category": "Arithmetic calculation",
        "question_ko": "남준이는 (가) 책을 35권 가지고 있습니다. 또 (나) 책은 (가) 책보다 16권 더 적게 가지고 있고, (다) 책은 (나) 책보다 35권 더 많습니다. 남준이가 가진 책은 모두 몇 권입니까?",
        "question_en": "Namjoon has 35 (a) books. Also, he has 16 fewer (b) books than (a) books, and 35 books more (c) books than (b) books. How many books does Namjoon have in all?",
        "answer_ko": "108",
        "answer_en": "108",
        "solution_abst_ko": "35 35 16 [OP_SUB] [OP_ADD] 35 16 [OP_SUB] 35 [OP_ADD] [OP_ADD]",
        "solution_abst_en": "35 35 16 [OP_SUB] [OP_ADD] 35 16 [OP_SUB] 35 [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 35\nvar_b = 35\nvar_c = 16\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 35\nvar_g = 16\nvar_h = var_f - var_g\nvar_i = 35\nvar_j = var_h + var_i\nvar_k = var_e + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 35\nvar_b = 35\nvar_c = 16\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 35\nvar_g = 16\nvar_h = var_f - var_g\nvar_i = 35\nvar_j = var_h + var_i\nvar_k = var_e + var_j\nprint(int(var_k))"
    },
    "4256": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 정류장에는 1번 버스부터 54번 버스까지 정거를 합니다. 이 정류장에 정거하는 모든 버스 번호들에 대하여 숫자 5가 몇 번 나오는지 구하시오.",
        "question_en": "At one bus stop, buses 1 through 54 stop. Find how many times the number 5 occurs in bus numbers that stop at this stop.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "1 54 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 5 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 54 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 5 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 54\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 5\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 54\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 5\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))"
    },
    "4257": {
        "category": "Arithmetic calculation",
        "question_ko": "2원짜리 8개, 1원짜리 2개가 있다면 총 얼마있나요?",
        "question_en": "If there are 8 2-won bills and 2 1-won bills, how much is the total?",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "2 8 [OP_MUL] 1 2 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "2 8 [OP_MUL] 1 2 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 2\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "4258": {
        "category": "Comparison",
        "question_ko": "체육시간에 학생들이 키가 작은 순서대로 태형, 민지, 지영, 진형, 진국이가 나란히 줄지어 섰습니다. 3번째로 키가 작은 사람은 누구입니까?",
        "question_en": "In PE class, the students lined up in order of shortest height: Taehyung, Minji, Jiyoung, Jinhyung, and Jingook. Who is the 3rd shortest person?",
        "answer_ko": "지영",
        "answer_en": "Jiyoung",
        "solution_abst_ko": "[OP_LIST_SOL] 태형 민지 지영 진형 진국 [OP_LIST_EOL] 3 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Taehyung Minji Jiyoung Jinhyung Jingook [OP_LIST_EOL] 3 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '태형'\nvar_b = '민지'\nvar_c = '지영'\nvar_d = '진형'\nvar_e = '진국'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nvar_g = list_a[var_f-1]\nprint(var_g)",
        "solution_code_en": "var_a = 'Taehyung'\nvar_b = 'Minji'\nvar_c = 'Jiyoung'\nvar_d = 'Jinhyung'\nvar_e = 'Jingook'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nvar_g = list_a[var_f-1]\nprint(var_g)"
    },
    "4259": {
        "category": "Geometry",
        "question_ko": "모서리와 꼭짓점의 수의 합이 30인 각기둥은 총 몇 개의 면으로 이루어져 있는가?",
        "question_en": "How many faces does a prism have if the sum of its edges and vertices is 30?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "30 2 3 [OP_ADD] [OP_DIV] 2 [OP_ADD]",
        "solution_abst_en": "30 2 3 [OP_ADD] [OP_DIV] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 30\nvar_b = 2\nvar_c = 3\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 30\nvar_b = 2\nvar_c = 3\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "4260": {
        "category": "Comparison",
        "question_ko": "건우네 집에서 학교까지는 3.97킬로미터(㎞)이고, 서현이네 집에서 학교까지는 4028미터(m)입니다. 집에서 학교까지의 거리가 더 먼 친구는 누구인지 구하시오.",
        "question_en": "It is 3.97 kilometers (km) from Kunwoo's house to the school, and it is 4028 meters (m) from Seohyeon's house to the school. Find a friend whose distance from home to school is longer.",
        "answer_ko": "서현",
        "answer_en": "Seohyeon",
        "solution_abst_ko": "[OP_LIST_SOL] 건우 서현 [OP_LIST_EOL] [OP_LIST_SOL] 3.97 1000 [OP_MUL] 4028 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Kunwoo Seohyeon [OP_LIST_EOL] [OP_LIST_SOL] 3.97 1000 [OP_MUL] 4028 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '건우'\nvar_b = '서현'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3.97\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 4028\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Kunwoo'\nvar_b = 'Seohyeon'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3.97\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 4028\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "4261": {
        "category": "Comparison",
        "question_ko": "윤기는 4를 모았습니다. 정국에는 6에서 3을 합한 수를 모았다면 누가 더 큰 수를 가지고 있나요?",
        "question_en": "Yoongi collected 4. If Jungkook collected the sum of 6 and 3, who has the bigger number?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 6\nvar_e = 3\nvar_f = var_d + var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 6\nvar_e = 3\nvar_f = var_d + var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "4262": {
        "category": "Correspondence",
        "question_ko": "서로 다른 세 수 A, B C가 있습니다. 세 자리 수끼리의 덧셈식 ABC+ABC+ABC=888에서 A를 구하시오.",
        "question_en": "There are three different numbers A, B, and C. Find A from the three-digit addition formula ABC+ABC+ABC=888.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "ABC+ABC+ABC=888 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "ABC+ABC+ABC=888 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'ABC+ABC+ABC=888'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'ABC+ABC+ABC=888'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "4263": {
        "category": "Possibility",
        "question_ko": "1, 2, 3, 4, 5, 6 중에서 서로 다른 2개의 숫자를 사용하여 만들 수 있는 두 자리 수는 모두 몇 개입니까?",
        "question_en": "What is the number of possible two-digit numbers that you can make using two different numbers from 1, 2, 3, 4, 5, and 6?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "[OP_LIST_SOL] 1 2 3 4 5 6 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 2 3 4 5 6 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 2\nvar_c = 3\nvar_d = 4\nvar_e = 5\nvar_f = 6\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = len(list_b)\nprint(int(var_h))",
        "solution_code_en": "var_a = 1\nvar_b = 2\nvar_c = 3\nvar_d = 4\nvar_e = 5\nvar_f = 6\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = len(list_b)\nprint(int(var_h))"
    },
    "4264": {
        "category": "Comparison",
        "question_ko": "석진 태형은 사탕을 각각 78개, 81개 가지고 있다. 가장 많은 사탕을 가진 사람은 누구인지 구하여라",
        "question_en": "Seokjin and Taehyung have 78 and 81 candies, respectively. Find the one with the most candy.",
        "answer_ko": "태형",
        "answer_en": "Taehyung",
        "solution_abst_ko": "[OP_LIST_SOL] 석진 태형 [OP_LIST_EOL] [OP_LIST_SOL] 78 81 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Seokjin Taehyung [OP_LIST_EOL] [OP_LIST_SOL] 78 81 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '석진'\nvar_b = '태형'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 78\nvar_d = 81\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Seokjin'\nvar_b = 'Taehyung'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 78\nvar_d = 81\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "4265": {
        "category": "Comparison",
        "question_ko": "은지는 빵을 21개, 민영이는 13개를 가지고 있습니다. 누가 빵을 더 많이 가지고 있습니까?",
        "question_en": "Eunji has 21 loaves of bread and Minyoung has 13 loaves. Who has more bread?",
        "answer_ko": "은지",
        "answer_en": "Eunji",
        "solution_abst_ko": "[OP_LIST_SOL] 민영 은지 [OP_LIST_EOL] [OP_LIST_SOL] 13 21 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Minyoung Eunji [OP_LIST_EOL] [OP_LIST_SOL] 13 21 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '민영'\nvar_b = '은지'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 13\nvar_d = 21\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Minyoung'\nvar_b = 'Eunji'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 13\nvar_d = 21\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "4266": {
        "category": "Correspondence",
        "question_ko": "동현이네 목장에는 황소와 검은소가 있다. 황소와 검은소는 모두 3통의 사료를 먹는다. 이 소들을 모두 먹이기 위해 동현이는 15통 묶음 8개와 60통의 낱개 사료를 사왔다. 사료가 부족하지도 많이도 않고 딱 맞는 양이고 황소가 52마리라고 할 때, 검은 소는 몇 마리인지 구하시오.",
        "question_en": "Donghyeon's ranch has bulls and black cows. Bulls and black cows both eat 3 barrels of feed. To feed all these cows, Donghyun bought 8 bundles of 15 and 60 individual feeds. If the feeds are just the right amount, and there are 52 bulls, how many black cows are there?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "15 8 [OP_MUL] 60 [OP_ADD] 3 [OP_DIV] 52 [OP_SUB]",
        "solution_abst_en": "15 8 [OP_MUL] 60 [OP_ADD] 3 [OP_DIV] 52 [OP_SUB]",
        "solution_code_ko": "var_a = 15\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 60\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = 52\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 15\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 60\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = 52\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "4267": {
        "category": "Geometry",
        "question_ko": "한 면의 둘레가 32센티미터(㎝)인 정육면체가 있습니다. 이 정육면체의 부피는 몇 세제곱센티미터입니까?",
        "question_en": "There is a cube whose perimeter of a side are 32 centimeters (cm). What is the volume of this cube in cubic centimeters?",
        "answer_ko": "512",
        "answer_en": "512",
        "solution_abst_ko": "32 4 [OP_DIV] 3 [OP_POW]",
        "solution_abst_en": "32 4 [OP_DIV] 3 [OP_POW]",
        "solution_code_ko": "var_a = 32\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 3\nvar_e = var_c ** var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 32\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 3\nvar_e = var_c ** var_d\nprint(int(var_e))"
    },
    "4268": {
        "category": "Comparison",
        "question_ko": "B는 3보다 크고 150보다 작다. B는 36과 약수 혹은 배수 관계이다. B가 될 수 있는 수를 차례로 작은수부터 적는다면 오른쪽에서 5번째 수는 무엇인가?",
        "question_en": "B is greater than 3 and less than 150, and it is a divisor or multiple of 36. If you were to list all the possible numbers for B, starting with the smallest number, what would be the 5th number from the right?",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "36 [OP_LIST_GET_DIVISOR] 36 150 1 [OP_SUB] 36 [OP_LIST_ARANGE] [OP_SET_UNION] 5 [OP_LIST_MAX]",
        "solution_abst_en": "36 [OP_LIST_GET_DIVISOR] 36 150 1 [OP_SUB] 36 [OP_LIST_ARANGE] [OP_SET_UNION] 5 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 36\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 36\nvar_c = 150\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 36\nlist_b = [i for i in range(var_b, var_e + 1, var_f)]\nlist_c = list(set(list_a) | set(list_b))\nvar_g = 5\nlist_d=list_c.copy()\nlist_d.sort()\nvar_h = list_d[-var_g]\nprint(int(var_h))",
        "solution_code_en": "var_a = 36\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 36\nvar_c = 150\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 36\nlist_b = [i for i in range(var_b, var_e + 1, var_f)]\nlist_c = list(set(list_a) | set(list_b))\nvar_g = 5\nlist_d=list_c.copy()\nlist_d.sort()\nvar_h = list_d[-var_g]\nprint(int(var_h))"
    },
    "4269": {
        "category": "Geometry",
        "question_ko": "정육면체 모양의 상자의 부피가 729세제곱센티미터(㎤)입니다. 이 때, 이 상자의 한 모서리의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "The volume of the cube-shaped box is 729 cubic centimeters (cm). At this time, how many centimeters (cm3) is the length of one corner of the box?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "729 1/3 [OP_POW]",
        "solution_abst_en": "729 1/3 [OP_POW]",
        "solution_code_ko": "var_a = 729\nvar_b = 0.3333333333333333\nvar_c = var_a ** var_b\nprint(int(eval('{:.2f}'.format(round(var_c+1e-10,2)))))",
        "solution_code_en": "var_a = 729\nvar_b = 0.3333333333333333\nvar_c = var_a ** var_b\nprint(int(eval('{:.2f}'.format(round(var_c+1e-10,2)))))"
    },
    "4270": {
        "category": "Possibility",
        "question_ko": "세 자연수 1, 6, 8을 한 개씩 모두 사용하여 1000보다 작은 자연수를 만들 때, 가장 작은 수와 세 번째로 작은 수의 합을 구하시오.",
        "question_en": "When all three natural numbers 1, 6, and 8 are used to form a natural number less than 1000, find the sum of the smallest number and the third smallest number.",
        "answer_ko": "786",
        "answer_en": "786",
        "solution_abst_ko": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))"
    },
    "4271": {
        "category": "Arithmetic calculation",
        "question_ko": "윤기는 개구리 5마리를 잡았습니다. 개구리 2마리를 더 잡았을 때, 윤기가 잡은 개구리는 몇 마리 인가요?",
        "question_en": "Yoongi caught 5 frogs. If he caught 2 more frogs, how many frogs did Yoongi catch?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "5 2 [OP_ADD]",
        "solution_abst_en": "5 2 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "4272": {
        "category": "Comparison",
        "question_ko": "회색 고양이는 흰색 고양이보다 무겁고 검은색 고양이보다 가볍습니다. 노란색 고양이는 가장 가볍습니다. 회색, 흰색, 검은색, 노란색 고양이 중에서 가장 무거운 고양이의 색깔은 무엇입니까?",
        "question_en": "Gray cats are heavier than white cats and lighter than black cats. Yellow cats are the lightest. Which color is the heaviest among gray, white, black and yellow cats?",
        "answer_ko": "검은색",
        "answer_en": "black",
        "solution_abst_ko": "[OP_LIST_SOL] 회색 흰색 검은색 노란색 [OP_LIST_EOL] [OP_LIST_SOL] 회색 흰색 > 회색 검은색 < 노란색 흰색 < 노란색 회색 < 노란색 검은색 < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] gray white black yellow [OP_LIST_EOL] [OP_LIST_SOL] gray white > gray black < yellow white < yellow gray < yellow black < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '회색'\nvar_b = '흰색'\nvar_c = '검은색'\nvar_d = '노란색'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '회색'\nvar_f = '흰색'\nvar_g = '>'\nvar_h = '회색'\nvar_i = '검은색'\nvar_j = '<'\nvar_k = '노란색'\nvar_l = '흰색'\nvar_m = '<'\nvar_n = '노란색'\nvar_o = '회색'\nvar_p = '<'\nvar_q = '노란색'\nvar_r = '검은색'\nvar_s = '<'\nlist_b= []\nif \"/\" in str(var_s):\n    var_s = eval(str(var_s))\nlist_b.append(var_s)\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_t = 1\nvar_u = list_c[var_t-1]\nprint(var_u)",
        "solution_code_en": "var_a = 'gray'\nvar_b = 'white'\nvar_c = 'black'\nvar_d = 'yellow'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'gray'\nvar_f = 'white'\nvar_g = '>'\nvar_h = 'gray'\nvar_i = 'black'\nvar_j = '<'\nvar_k = 'yellow'\nvar_l = 'white'\nvar_m = '<'\nvar_n = 'yellow'\nvar_o = 'gray'\nvar_p = '<'\nvar_q = 'yellow'\nvar_r = 'black'\nvar_s = '<'\nlist_b= []\nif \"/\" in str(var_s):\n    var_s = eval(str(var_s))\nlist_b.append(var_s)\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_t = 1\nvar_u = list_c[var_t-1]\nprint(var_u)"
    },
    "4273": {
        "category": "Geometry",
        "question_ko": "각 길이가 2.7미터(m)인 테이프 5장을 0.3미터(m)씩 겹치는 부분이 있도록 이었습니다. 이 이어 붙인 테이프를 6등분할 때, 각 등분의 길이는 얼마입니까?",
        "question_en": "Five pieces of tape, every 2.7 meters (m) long, were stacked so that there was an overlap of 0.3 meters (m). If you divide this spliced tape into 6 equal parts, what is the length of each equal part?",
        "answer_ko": "2.05",
        "answer_en": "2.05",
        "solution_abst_ko": "2.7 5 [OP_MUL] 0.3 5 1 [OP_SUB] [OP_MUL] [OP_SUB] 6 [OP_DIV]",
        "solution_abst_en": "2.7 5 [OP_MUL] 0.3 5 1 [OP_SUB] [OP_MUL] [OP_SUB] 6 [OP_DIV]",
        "solution_code_ko": "var_a = 2.7\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 0.3\nvar_e = 5\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_c - var_h\nvar_j = 6\nvar_k = var_i / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 2.7\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 0.3\nvar_e = 5\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_c - var_h\nvar_j = 6\nvar_k = var_i / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "4274": {
        "category": "Geometry",
        "question_ko": "어떤 사다리꼴의 넓이가 56제곱센티미터(㎠), 윗변이 5센티미터(㎝), 아랫변이 9센티미터(㎝)이라면, 이 사다리꼴의 높이는 몇 센티미터(㎝)입니까?",
        "question_en": "Given that the area of a trapezoid is 56 square centimeters (cm), the top side is 5 centimeters (cm), and the bottom side is 9 centimeters (cm), what is the height of the trapezoid in centimeters (cm)?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "56 2 [OP_MUL] 5 9 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "56 2 [OP_MUL] 5 9 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 56\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = 9\nvar_f = var_d + var_e\nvar_g = var_c / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 56\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = 9\nvar_f = var_d + var_e\nvar_g = var_c / var_f\nprint(int(var_g))"
    },
    "4275": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 13/5을 더해야 할 것을 잘못하여 빼었더니 9/7가 되었습니다. 바르게 계산하면 얼마입니까?",
        "question_en": "You mistakenly subtracted 13/5 from a number instead of adding 13/5 and got 9/7. How much is it when calculated correctly?",
        "answer_ko": "6.49",
        "answer_en": "6.49",
        "solution_abst_ko": "9/7 13/5 [OP_ADD] 13/5 [OP_ADD]",
        "solution_abst_en": "9/7 13/5 [OP_ADD] 13/5 [OP_ADD]",
        "solution_code_ko": "var_a = 1.2857142857142858\nvar_b = 2.6\nvar_c = var_a + var_b\nvar_d = 2.6\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 1.2857142857142858\nvar_b = 2.6\nvar_c = var_a + var_b\nvar_d = 2.6\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "4276": {
        "category": "Geometry",
        "question_ko": "한 삼각형이 있다. 이 삼각형의 빗변의 길이과 밑변의 길이는 각각 15센티미터(㎝), 9센티미터(㎝)이다. 넓이를 구하라.",
        "question_en": "There is one triangle. The length of the hypotenuse and base of this triangle is 15 centimeters (cm) and 9 centimeters (cm), respectively. Find the area.",
        "answer_ko": "54",
        "answer_en": "54",
        "solution_abst_ko": "15 2 [OP_POW] 9 2 [OP_POW] [OP_SUB] 1/2 [OP_POW] 9 [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "15 2 [OP_POW] 9 2 [OP_POW] [OP_SUB] 1/2 [OP_POW] 9 [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 15\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 9\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c - var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nvar_j = 9\nvar_k = var_i * var_j\nvar_l = 2\nvar_m = var_k / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 15\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 9\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c - var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nvar_j = 9\nvar_k = var_i * var_j\nvar_l = 2\nvar_m = var_k / var_l\nprint(int(var_m))"
    },
    "4277": {
        "category": "Comparison",
        "question_ko": "20명의 학생들이 버스를 기다리고 있습니다. 윤기보다 늦게 온 사람은 11명이라면 윤기보다 먼저 온 사람은 몇 명입니까?",
        "question_en": "20 students are waiting for the bus. If 11 people came after Yoongi, how many people came before Yoongi?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "20 11 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "20 11 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "4278": {
        "category": "Arithmetic calculation",
        "question_ko": "3의 배수이면서 4의 배수인 수 중 가장 작은 다섯 자리 수는?",
        "question_en": "What is the smallest 5-digit number that is a multiple of 3 and a multiple of 4?",
        "answer_ko": "10008",
        "answer_en": "10008",
        "solution_abst_ko": "10000 99999 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 4 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "10000 99999 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 4 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 10000\nvar_b = 99999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 4\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 10000\nvar_b = 99999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 4\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[var_f-1]\nprint(int(var_g))"
    },
    "4279": {
        "category": "Geometry",
        "question_ko": "모서리의 길이가 같은 사각뿔이 있습니다. 모서리의 길이의 합이 14.8미터(m) 일 때 한 모서리의 길이는 몇 미터(m) 입니까?",
        "question_en": "There is a quadrangular pyramid whose edges have the same length. If the sum of the lengths of the edges is 14.8 meters (m), how many meters (m) is the length of one edge?",
        "answer_ko": "1.85",
        "answer_en": "1.85",
        "solution_abst_ko": "14.8 4 2 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "14.8 4 2 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 14.8\nvar_b = 4\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 14.8\nvar_b = 4\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "4280": {
        "category": "Comparison",
        "question_ko": "가, 나, 다 세 사람이 책을 가지고 있습니다. 세 사람이 가지고 있는 책의 평균은, 가, 나 두 사람이 가진 책의 평균보다 23권 더 적고, 나, 다 두 사람이 가진 평균보다 17권 더 많습니다. 나가 가지고 있는 책이 66권일 때, 다가 가지고 있는 책은 몇 권입니까?",
        "question_en": "Three people A, B, and C have books. The average number of books owned by the three people is 23 fewer than the average of the books owned by two people A and B, and 17 more than the average number of books owned by B and C. If B has 66 books, how many books does C have?",
        "answer_ko": "44",
        "answer_en": "44",
        "solution_abst_ko": "66 17 2 [OP_MUL] [OP_SUB] 3 [OP_MUL] 17 23 [OP_ADD] 2 [OP_MUL] [OP_ADD] 66 2 [OP_MUL] [OP_SUB] 2 2 [OP_ADD] 3 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "66 17 2 [OP_MUL] [OP_SUB] 3 [OP_MUL] 17 23 [OP_ADD] 2 [OP_MUL] [OP_ADD] 66 2 [OP_MUL] [OP_SUB] 2 2 [OP_ADD] 3 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 66\nvar_b = 17\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 3\nvar_g = var_e * var_f\nvar_h = 17\nvar_i = 23\nvar_j = var_h + var_i\nvar_k = 2\nvar_l = var_j * var_k\nvar_m = var_g + var_l\nvar_n = 66\nvar_o = 2\nvar_p = var_n * var_o\nvar_q = var_m - var_p\nvar_r = 2\nvar_s = 2\nvar_t = var_r + var_s\nvar_u = 3\nvar_v = var_t - var_u\nvar_w = var_q / var_v\nprint(int(var_w))",
        "solution_code_en": "var_a = 66\nvar_b = 17\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 3\nvar_g = var_e * var_f\nvar_h = 17\nvar_i = 23\nvar_j = var_h + var_i\nvar_k = 2\nvar_l = var_j * var_k\nvar_m = var_g + var_l\nvar_n = 66\nvar_o = 2\nvar_p = var_n * var_o\nvar_q = var_m - var_p\nvar_r = 2\nvar_s = 2\nvar_t = var_r + var_s\nvar_u = 3\nvar_v = var_t - var_u\nvar_w = var_q / var_v\nprint(int(var_w))"
    },
    "4281": {
        "category": "Geometry",
        "question_ko": "길이가 8미터(m)인 나무 막대로 정삼각형 모양의 울타리를 만들려고 합니다. 울타리의 한 변은 몇 미터(m)로 해야 할지 구하시오.",
        "question_en": "You are going to build a fence in the shape of an equilateral triangle with wooden sticks that are 8 meters (m) long. Find how many meters (m) each side of the fence should be.",
        "answer_ko": "2.67",
        "answer_en": "2.67",
        "solution_abst_ko": "8 3 [OP_DIV]",
        "solution_abst_en": "8 3 [OP_DIV]",
        "solution_code_ko": "var_a = 8\nvar_b = 3\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 8\nvar_b = 3\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "4282": {
        "category": "Correspondence",
        "question_ko": "종국이는 매일 우유를 마신다. 첫 째날 3리터(L) 7밀리리터(㎖)를 마시고, 둘째 날 몇 미터(m)를 마시고, 셋째 날 840미터(m)를 마셔서 전체로 6리터(L) 30밀리리터(㎖)를 마셨다. 종국이가 둘째 날 마신 우유의 양은 몇 미터(m)인가?",
        "question_en": "Jongkook drinks milk every day. He drank 3 liters (L) and 7 milliliters (㎖) on the first day, a few milliliters (㎖) on the second day, and 840 milliliters (㎖) on the third day. As he drank 6 liters (L) and 30 milliliters (㎖) in total, how many milliliters (㎖) of milk did Jongkook drink on the second day?",
        "answer_ko": "2183",
        "answer_en": "2183",
        "solution_abst_ko": "6 1000 [OP_MUL] 30 [OP_ADD] 840 [OP_SUB] 3 1000 [OP_MUL] 7 [OP_ADD] [OP_SUB]",
        "solution_abst_en": "6 1000 [OP_MUL] 30 [OP_ADD] 840 [OP_SUB] 3 1000 [OP_MUL] 7 [OP_ADD] [OP_SUB]",
        "solution_code_ko": "var_a = 6\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 30\nvar_e = var_c + var_d\nvar_f = 840\nvar_g = var_e - var_f\nvar_h = 3\nvar_i = 1000\nvar_j = var_h * var_i\nvar_k = 7\nvar_l = var_j + var_k\nvar_m = var_g - var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 6\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 30\nvar_e = var_c + var_d\nvar_f = 840\nvar_g = var_e - var_f\nvar_h = 3\nvar_i = 1000\nvar_j = var_h * var_i\nvar_k = 7\nvar_l = var_j + var_k\nvar_m = var_g - var_l\nprint(int(var_m))"
    },
    "4283": {
        "category": "Arithmetic calculation",
        "question_ko": "(가)와 (나) 중에서 하나도 못 하는 어린이는 없습니다. (가)를 할 수 있는 어린이는 38명, (나)를 할 수 있는 어린이가 29명이고 전체 어린이는 48명일 때, 둘 모두를 할 수 있는 어린이는 몇 명입니까?",
        "question_en": "There is no child who cannot do either of A and B. If there are 38 children who can do A and 29 children who can do B and the total number of children is 48, how many children can do both?",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "38 29 [OP_ADD] 48 [OP_SUB]",
        "solution_abst_en": "38 29 [OP_ADD] 48 [OP_SUB]",
        "solution_code_ko": "var_a = 38\nvar_b = 29\nvar_c = var_a + var_b\nvar_d = 48\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 38\nvar_b = 29\nvar_c = var_a + var_b\nvar_d = 48\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "4284": {
        "category": "Geometry",
        "question_ko": "정사각형 종이조각을 가로와 세로 모두 10장씩 빈틈없이 놓았더니 큰 정사각형이 되었습니다. 둘레에 놓인 종이조각의 수를 구하시오.",
        "question_en": "If you put 10 pieces of square paper in each horizontal and vertical line without gaps, you get a large square. Find the number of pieces of paper placed around the perimeter.",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "10 4 [OP_MUL] 4 [OP_SUB]",
        "solution_abst_en": "10 4 [OP_MUL] 4 [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "4285": {
        "category": "Correspondence",
        "question_ko": "A, B, C는 0에서 9까지의 서로 다른 숫자입니다. 두 자리 수끼리의 덧셈식 AB+BC=BCB에서 A를 구하시오.",
        "question_en": "A, B, C are different numbers from 0 to 9. Find A given the two-digit addition equation AB+BC=BCB.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "AB+BC=BCB A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "AB+BC=BCB A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'AB+BC=BCB'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'AB+BC=BCB'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "4286": {
        "category": "Arithmetic calculation",
        "question_ko": "미주는 모둠 활동에 참여한 첫째 날 11명의 친구들을 새로 만나서 악수를 하였습니다. 미주와 친구들이 서로 한 번씩 악수를 하였다면 악수는 모두 몇 번 하였습니까?",
        "question_en": "On the first day of participating in the group activity, Miju met 11 new friends and shook hands. If Mijoo and her friends shook hands once, how many times did they all shake hands?",
        "answer_ko": "66",
        "answer_en": "66",
        "solution_abst_ko": "11 1 [OP_ADD] 11 [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "11 1 [OP_ADD] 11 [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 11\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 11\nvar_e = var_c * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 11\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 11\nvar_e = var_c * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "4287": {
        "category": "Arithmetic calculation",
        "question_ko": "30보다 같거나 크고 50보다 같거나 작으면서 6의 배수인 수의 총합을 구하시오.",
        "question_en": "Find the sum of all numbers greater than or equal to 30, less than or equal to 50, and that are multiples of 6.",
        "answer_ko": "156",
        "answer_en": "156",
        "solution_abst_ko": "30 50 1 [OP_LIST_ARANGE] 6 [OP_LIST_DIVISIBLE] [OP_LIST_SUM]",
        "solution_abst_en": "30 50 1 [OP_LIST_ARANGE] 6 [OP_LIST_DIVISIBLE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 30\nvar_b = 50\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 30\nvar_b = 50\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint(int(var_e))"
    },
    "4288": {
        "category": "Correspondence",
        "question_ko": "형준이는 페인트 칠을 하면서 전체의 절반을 집을 칠하는데 썼고, 담장을 칠하는데 남은 페인트의 1/3보다 5통 많게 썼습니다. 남은 페인트가 5통이라면 형준이는 처음 몇 통의 페인트를 가지고 있었습니까?",
        "question_en": "While painting, Hyungjun used half of the paint to paint the house and he used 5 more than 1/3 of the remaining paint to paint the fence. If there are 5 cans of paint left, how many cans of paint did Hyeongjun have to begin with?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "5 5 [OP_ADD] 1 1/3 [OP_SUB] [OP_DIV] 1 1/2 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "5 5 [OP_ADD] 1 1/3 [OP_SUB] [OP_DIV] 1 1/2 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 5\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 0.3333333333333333\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 1\nvar_i = 0.5\nvar_j = var_h - var_i\nvar_k = var_g / var_j\nprint(int(eval('{:.2f}'.format(round(var_k+1e-10,2)))))",
        "solution_code_en": "var_a = 5\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 0.3333333333333333\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 1\nvar_i = 0.5\nvar_j = var_h - var_i\nvar_k = var_g / var_j\nprint(int(eval('{:.2f}'.format(round(var_k+1e-10,2)))))"
    },
    "4289": {
        "category": "Possibility",
        "question_ko": "쥐, 소, 호랑이, 토끼, 용, 뱀 다섯 동물이 길을 가고 있습니다. 눈이 제일 좋은 쥐는 맨 앞에 와야 하고, 꼬리가 제일 긴 뱀은 맨 뒤에 와야 합니다. 다섯 동물이 줄을 서는 모든 경우의 수를 구하시오.",
        "question_en": "Five animals are on the way: Rat, Cow, Tiger, Rabbit, Dragon and Snake. The mouse with the best eye sight should come first, and the snake with the longest tail should come last. Find the number of all cases in which five animals form a line.",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "[OP_LIST_SOL] 쥐 소 호랑이 토끼 용 뱀 [OP_LIST_EOL] [OP_LIST_SOL] 쥐 [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_SOL] 뱀 [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] Rat Cow Tiger Rabbit Dragon Snake [OP_LIST_EOL] [OP_LIST_SOL] Rat [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_SOL] Snake [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM]",
        "solution_code_ko": "var_a = '쥐'\nvar_b = '소'\nvar_c = '호랑이'\nvar_d = '토끼'\nvar_e = '용'\nvar_f = '뱀'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = '쥐'\nlist_b= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_h = '뱀'\nlist_d= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_d.append(var_h)\nlist_d.reverse()\nlist_e = list(set(list_c) - set(list_d))\nvar_i = len(list_e)\nvar_j = len(list_e)\nvar_k = 1\nvar_i = int(var_i)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_i-i)\nprint(int(var_k))",
        "solution_code_en": "var_a = 'Rat'\nvar_b = 'Cow'\nvar_c = 'Tiger'\nvar_d = 'Rabbit'\nvar_e = 'Dragon'\nvar_f = 'Snake'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 'Rat'\nlist_b= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_h = 'Snake'\nlist_d= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_d.append(var_h)\nlist_d.reverse()\nlist_e = list(set(list_c) - set(list_d))\nvar_i = len(list_e)\nvar_j = len(list_e)\nvar_k = 1\nvar_i = int(var_i)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_i-i)\nprint(int(var_k))"
    },
    "4290": {
        "category": "Comparison",
        "question_ko": "5가지 숫자 1.4, 9/10, 1.2, 0.5, 13/10 중에서 1.1보다 큰 수들의 합을 구하면 얼마입니까?",
        "question_en": "Among five numbers 1.4, 9/10, 1.2, 0.5, and 13/10, what is the sum of the numbers greater than 1.1?",
        "answer_ko": "3.90",
        "answer_en": "3.9",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "4291": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 공장에서 평균적으로 230개의 티비를 생산한다고 한다. 보름동안 몇 개의 티비를 만드는지 구하시오.",
        "question_en": "It is said that a factory produces 230 TVs on average. Find how many TVs are produced in 15 days.",
        "answer_ko": "3450",
        "answer_en": "3450",
        "solution_abst_ko": "230 15 [OP_MUL]",
        "solution_abst_en": "230 15 [OP_MUL]",
        "solution_code_ko": "var_a = 230\nvar_b = 15\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 230\nvar_b = 15\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "4292": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 3번째로 큰 수와 2번째로 큰 수의 곱은 얼마입니까?",
        "question_en": "There are five numbers 10, 11, 12, 13, and 14. What is the product of the 3rd largest number and the 2nd largest number?",
        "answer_ko": "156",
        "answer_en": "156",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 3 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 3 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[-var_h]\nvar_j = var_g * var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[-var_h]\nvar_j = var_g * var_i\nprint(int(var_j))"
    },
    "4293": {
        "category": "Possibility",
        "question_ko": "하나의 그림을 네 구역으로 나누고, 각자 빨강, 파랑, 초록, 노랑으로 칠하려고 한다. 모두 다른 색으로 칠하는 경우는 몇 가지인가?",
        "question_en": "Divide a picture into four sections, and try to color each one with red, blue, green, and yellow. How many times are there where you paint them all different colors?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "4 4 [OP_PERM]",
        "solution_abst_en": "4 4 [OP_PERM]",
        "solution_code_ko": "var_a = 4\nvar_b = 4\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 4\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))"
    },
    "4294": {
        "category": "Geometry",
        "question_ko": "길이가 63㎝인 철사로 정삼각형을 만들었더니 철사가 남지도 모자라지도 않았습니다. 정삼각형의 한 변의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "I made an equilateral triangle with a wire 63 cm (cm) long, and there was neither excess nor shortage of wire. How many centimeters (cm) is the length of one side of an equilateral triangle?",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "63 3 [OP_DIV]",
        "solution_abst_en": "63 3 [OP_DIV]",
        "solution_code_ko": "var_a = 63\nvar_b = 3\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 63\nvar_b = 3\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "4295": {
        "category": "Arithmetic calculation",
        "question_ko": "100부터 200까지의 수 가 있습니다. 이들 중 홀수들의 합을 구하시오",
        "question_en": "When there are numbers from 100 to 200, what is sum of odd numbers in the range?",
        "answer_ko": "7500",
        "answer_en": "7500",
        "solution_abst_ko": "100 200 [OP_LIST_ODD] [OP_LIST_SUM]",
        "solution_abst_en": "100 200 [OP_LIST_ODD] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 100\nvar_b = 200\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nprint(int(var_c))",
        "solution_code_en": "var_a = 100\nvar_b = 200\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nprint(int(var_c))"
    },
    "4296": {
        "category": "Arithmetic calculation",
        "question_ko": "농장에 오리 45마리, 거위 28마리가 있습니다. 또 암탉은 오리보다 13마리 적고, 수탉은 거위보다 9마리 많습니다. 농장에 있는 닭은 모두 몇 마리입니까?",
        "question_en": "There are 45 ducks and 28 geese on the farm. Also, hens are 13 less than ducks, and roosters are 9 more than geese. How many chickens are there in the farm in total?",
        "answer_ko": "69",
        "answer_en": "69",
        "solution_abst_ko": "45 13 [OP_SUB] 28 9 [OP_ADD] [OP_ADD]",
        "solution_abst_en": "45 13 [OP_SUB] 28 9 [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 45\nvar_b = 13\nvar_c = var_a - var_b\nvar_d = 28\nvar_e = 9\nvar_f = var_d + var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 45\nvar_b = 13\nvar_c = var_a - var_b\nvar_d = 28\nvar_e = 9\nvar_f = var_d + var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "4297": {
        "category": "Comparison",
        "question_ko": "20명의 학생들이 한줄로 섰습니다. 정국이는 3등으로 줄을 섰고, 윤기는 정국이 바로 뒤에 섰습니다. 윤기 뒤에 서 있는 학생은 몇 명입니까?",
        "question_en": "20 students stood in a line. Jungkook stood third in line, and Yoongi stood right behind Jungkook. How many students are standing behind Yoongi?",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "20 3 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "20 3 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "4298": {
        "category": "Possibility",
        "question_ko": "주한이가 내일 쓸 모자 하나와 신을 신발 하나를 고르려고 합니다. 주한이가 가진 모자는 4개이고 주한이가 가진 신발은 3개입니다. 주한이가 모자와 신발을 각각 1종류씩 고르는 경우의 수는 모두 몇가지 인가요?",
        "question_en": "Joohan is about to choose a hat and pair of shoes to wear tomorrow. Joohan has 4 hats and 3 pairs of shoes. In how many ways can Juhan choose one hat and one pair of shoes?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "4 1 [OP_COMB] 3 1 [OP_COMB] [OP_MUL]",
        "solution_abst_en": "4 1 [OP_COMB] 3 1 [OP_COMB] [OP_MUL]",
        "solution_code_ko": "var_a = 4\nvar_b = 1\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nvar_d = 3\nvar_e = 1\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f / (i+1)\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 1\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nvar_d = 3\nvar_e = 1\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f / (i+1)\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "4299": {
        "category": "Arithmetic calculation",
        "question_ko": "찰흙 1그램(g) 당 17.25원의 가격이라고 합니다. 승준이가 1000그램(g)짜리 찰흙 1개와 10그램(g)짜리 찰흙 1개를 살 때, 얼마를 지불해야합니까?",
        "question_en": "The price of clay is 17.25 won per gram (g). If Seungjun buys one 1000 gram (g) clay and one 10 gram (g) clay, how much should he pay?",
        "answer_ko": "17422.50",
        "answer_en": "17422.5",
        "solution_abst_ko": "17.25 1000 [OP_MUL] 17.25 10 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "17.25 1000 [OP_MUL] 17.25 10 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 17.25\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 17.25\nvar_e = 10\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 17.25\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 17.25\nvar_e = 10\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "4300": {
        "category": "Possibility",
        "question_ko": "구별이 가능한 10개의 공 중에서 4개를 선택하려고 합니다. 공을 선택할 수 있는 경우는 모두 몇 가지입니까?",
        "question_en": "We want to select 4 out of 10 distinguishable balls. How many ways are there to choose a ball?",
        "answer_ko": "210",
        "answer_en": "210",
        "solution_abst_ko": "10 4 [OP_COMB]",
        "solution_abst_en": "10 4 [OP_COMB]",
        "solution_code_ko": "var_a = 10\nvar_b = 4\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))",
        "solution_code_en": "var_a = 10\nvar_b = 4\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))"
    },
    "4301": {
        "category": "Geometry",
        "question_ko": "(가) 물건 1개가 들어있는 어항에 물이 16센티미터(㎝) 높이만큼 담겨있었습니다. 어항의 한 모서리의 길이가 20센티미터(㎝)이고, (가) 물건을 뺐더니 높이가 9센티미터(㎝)가 되었다면, (가) 물건의 부피는 얼마인가?",
        "question_en": "A fishbowl containing an object called (A) has been filled with water to a height of 16 centimeters (cm). If the length of one corner of the fishbowl is 20 centimeters (cm) and if (A) is removed, the height is 9 centimeters (cm), then what is the volume of the (A)?",
        "answer_ko": "2800",
        "answer_en": "2800",
        "solution_abst_ko": "20 20 [OP_MUL] 16 9 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "20 20 [OP_MUL] 16 9 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 20\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 16\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 20\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 16\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "4302": {
        "category": "Comparison",
        "question_ko": "(가) 인쇄소에선 60대의 인쇄기로 40680장의 종이를 인쇄했고, (나) 인쇄소에선 55대의 인쇄기로 37510장의 종이를 인쇄했습니다. 인쇄기 하나 당 평균적으로 인쇄한 종이의 장수가 더 많은 인쇄소는 어디입니까?",
        "question_en": "60 presses printed 40680 sheets of paper in print shop A and 55 presses printed 37510 sheets of paper in print shop B. Which printshop printed more sheets per press on average?",
        "answer_ko": "(나)",
        "answer_en": "B",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) [OP_LIST_EOL] [OP_LIST_SOL] 40680 60 [OP_DIV] 37510 55 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 40680 60 [OP_DIV] 37510 55 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 40680\nvar_d = 60\nvar_e = var_c / var_d\nvar_f = 37510\nvar_g = 55\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 40680\nvar_d = 60\nvar_e = var_c / var_d\nvar_f = 37510\nvar_g = 55\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "4303": {
        "category": "Arithmetic calculation",
        "question_ko": "은지는 가지고 있던 돈으로 마트에서 350원짜리 과자를 사고 어머니께 용돈으로 800원을 받았습니다. 남은 돈의 반으로 연필을 샀더니 550원이 남았습니다. 처음에 은지가 가지고 있던 돈은 얼마입니까?",
        "question_en": "Eunji bought a 350 won snack at the mart with the money she had and received 800 won from her mother as an allowance. I bought a pencil with half of the remaining money, and I had 550 won left. How much money did Eunji have at first?",
        "answer_ko": "650",
        "answer_en": "650",
        "solution_abst_ko": "550 2 [OP_MUL] 800 [OP_SUB] 350 [OP_ADD]",
        "solution_abst_en": "550 2 [OP_MUL] 800 [OP_SUB] 350 [OP_ADD]",
        "solution_code_ko": "var_a = 550\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 800\nvar_e = var_c - var_d\nvar_f = 350\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 550\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 800\nvar_e = var_c - var_d\nvar_f = 350\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "4304": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.9, 1/3의 숫자가 있다. 이 중 0.6보다 작은 숫자들 중 가장 큰 수를 구하시오.",
        "question_en": "There are numbers 0.8, 1/2, 0.9, and 1/3. Find the largest of the given numbers that are less than 0.6.",
        "answer_ko": "0.50",
        "answer_en": "0.5",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.6 [OP_LIST_LESS] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.6 [OP_LIST_LESS] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.6\nlist_b = []\nfor i in list_a:\n    if i < var_e:\n        list_b.append(i)\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.6\nlist_b = []\nfor i in list_a:\n    if i < var_e:\n        list_b.append(i)\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "4305": {
        "category": "Possibility",
        "question_ko": "500원짜리 동전 4개, 100원짜리 동전 2개, 10원짜리 동전 10개를 가지고 지불할 수 있는 금액은 모두 몇 가지인지 구하시오. (단, 지불 금액이 0원인 경우는 제외한다.)",
        "question_en": "How many total amounts can you pay with 4 500-won coins, 2 100-won coins, and 10 10-won coins? (However, the case where the payment amount is 0 won is excluded.)",
        "answer_ko": "154",
        "answer_en": "154",
        "solution_abst_ko": "4 1 [OP_ADD] 100 2 [OP_MUL] 10 [OP_FDIV] 10 [OP_ADD] 1 [OP_ADD] [OP_MUL] 1 [OP_SUB]",
        "solution_abst_en": "4 1 [OP_ADD] 100 2 [OP_MUL] 10 [OP_FDIV] 10 [OP_ADD] 1 [OP_ADD] [OP_MUL] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 4\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 100\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = 10\nvar_h = var_f // var_g\nvar_i = 10\nvar_j = var_h + var_i\nvar_k = 1\nvar_l = var_j + var_k\nvar_m = var_c * var_l\nvar_n = 1\nvar_o = var_m - var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 4\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 100\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = 10\nvar_h = var_f // var_g\nvar_i = 10\nvar_j = var_h + var_i\nvar_k = 1\nvar_l = var_j + var_k\nvar_m = var_c * var_l\nvar_n = 1\nvar_o = var_m - var_n\nprint(int(var_o))"
    },
    "4306": {
        "category": "Correspondence",
        "question_ko": "윤기는 네 자리 수와 57의 덧셈을 하려 합니다. 윤기는 네 자리 수의 일의 자리 숫자 9를 6으로 잘못 보았습니다. 윤기가 구한 합은 1823 일 때, 바르게 계산한 결과를 구하시오.",
        "question_en": "Yoongi wants to add a four-digit number to 57. Yoongi confused 9 as a 6 in the units digit of a four-digit number. When the sum obtained by Yoongi is 1823, find the correct calculation result.",
        "answer_ko": "1826",
        "answer_en": "1826",
        "solution_abst_ko": "1823 57 [OP_SUB] 6 9 [OP_SUB] [OP_SUB] 57 [OP_ADD]",
        "solution_abst_en": "1823 57 [OP_SUB] 6 9 [OP_SUB] [OP_SUB] 57 [OP_ADD]",
        "solution_code_ko": "var_a = 1823\nvar_b = 57\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nvar_h = 57\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1823\nvar_b = 57\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nvar_h = 57\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "4307": {
        "category": "Arithmetic calculation",
        "question_ko": "유정이가 처음 가지고 있던 공책에서 5권을 언니에게 주고, 이후 남은 것의 반을 동생에게 주었습니다. 마지막에 남은 공책의 수를 세어 보았더니 4권이었습니다. 유정이가 처음에 가지고 있던 공책의 수는 몇 권일까요?",
        "question_en": "Yoojung gave 5 notebooks she had at first to her older sister, and then gave half of the remaining ones to her younger sister. She counted the number of notebooks left at the end, and it was 4. How many notebooks did Yoojung have at first?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "4 2 [OP_MUL] 5 [OP_ADD]",
        "solution_abst_en": "4 2 [OP_MUL] 5 [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "4308": {
        "category": "Correspondence",
        "question_ko": "1/6×1/3=1/(A×3)=1/B 일 때 A와 B의 합은?",
        "question_en": "When 1/6×1/3=1/(A×3)=1/B, what is the sum of A and B?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "1/6×1/3=1/(A×3)=1/B A [OP_NUM_UNK_SOLVER] 1/6×1/3=1/(A×3)=1/B B [OP_NUM_UNK_SOLVER] [OP_ADD]",
        "solution_abst_en": "1/6×1/3=1/(A×3)=1/B A [OP_NUM_UNK_SOLVER] 1/6×1/3=1/(A×3)=1/B B [OP_NUM_UNK_SOLVER] [OP_ADD]",
        "solution_code_ko": "var_a = '1/6×1/3=1/(A×3)=1/B'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '1/6×1/3=1/(A×3)=1/B'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = '1/6×1/3=1/(A×3)=1/B'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '1/6×1/3=1/(A×3)=1/B'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "4309": {
        "category": "Comparison",
        "question_ko": "네 수 A, B, C, D가 있습니다. A는 D보다 19작은 수입니다. C는 A의 4배입니다. C는 B보다 15 큰 수입니다. A는 3에 3을 곱한 수일 때 A, B, C, D 중 2번째로 큰 수는 무엇입니까?",
        "question_en": "There are four numbers A, B, C, and D. A is 19 less than D. C is 4 times A. C is 15 greater than B. If A is 3 multiplied by 3, what is the second largest number among A, B, C, and D?",
        "answer_ko": "D",
        "answer_en": "D",
        "solution_abst_ko": "[OP_LIST_SOL] A C B D [OP_LIST_EOL] [OP_LIST_SOL] 3 3 [OP_MUL] 3 3 4 [OP_MUL] [OP_MUL] 9 4 19 [OP_MUL] [OP_SUB] 3 3 19 [OP_MUL] [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A C B D [OP_LIST_EOL] [OP_LIST_SOL] 3 3 [OP_MUL] 3 3 4 [OP_MUL] [OP_MUL] 9 4 19 [OP_MUL] [OP_SUB] 3 3 19 [OP_MUL] [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'C'\nvar_c = 'B'\nvar_d = 'D'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nvar_f = 3\nvar_g = var_e * var_f\nvar_h = 3\nvar_i = 3\nvar_j = 4\nvar_k = var_i * var_j\nvar_l = var_h * var_k\nvar_m = 9\nvar_n = 4\nvar_o = 19\nvar_p = var_n * var_o\nvar_q = var_m - var_p\nvar_r = 3\nvar_s = 3\nvar_t = 19\nvar_u = var_s * var_t\nvar_v = var_r + var_u\nlist_b= []\nif \"/\" in str(var_v):\n    var_v = eval(str(var_v))\nlist_b.append(var_v)\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_w = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_x = list_c[-var_w]\nvar_y = list_b.index(var_x)+1\nvar_z = list_a[var_y-1]\nprint(var_z)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'C'\nvar_c = 'B'\nvar_d = 'D'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nvar_f = 3\nvar_g = var_e * var_f\nvar_h = 3\nvar_i = 3\nvar_j = 4\nvar_k = var_i * var_j\nvar_l = var_h * var_k\nvar_m = 9\nvar_n = 4\nvar_o = 19\nvar_p = var_n * var_o\nvar_q = var_m - var_p\nvar_r = 3\nvar_s = 3\nvar_t = 19\nvar_u = var_s * var_t\nvar_v = var_r + var_u\nlist_b= []\nif \"/\" in str(var_v):\n    var_v = eval(str(var_v))\nlist_b.append(var_v)\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_w = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_x = list_c[-var_w]\nvar_y = list_b.index(var_x)+1\nvar_z = list_a[var_y-1]\nprint(var_z)"
    },
    "4310": {
        "category": "Geometry",
        "question_ko": "밑면의 모양이 정육각형이고 옆면의 모서리의 길이가 8센티미터(㎝)인 각뿔이 있습니다. 이 각뿔의 모든 모서리의 길이의 합이 120센티미터(㎝)일 때, 밑면의 한 변의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "There is a pyramid with a regular hexagon at the base and a side edge measuring 8 centimeters (cm). If the sum of the lengths of all the edges of this pyramid is 120 centimeters (cm), what is the length of one edge of the base in centimeters (cm)?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "120 8 6 [OP_MUL] [OP_SUB] 6 [OP_DIV]",
        "solution_abst_en": "120 8 6 [OP_MUL] [OP_SUB] 6 [OP_DIV]",
        "solution_code_ko": "var_a = 120\nvar_b = 8\nvar_c = 6\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 6\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 120\nvar_b = 8\nvar_c = 6\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 6\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "4311": {
        "category": "Correspondence",
        "question_ko": "소수 2번째 자리에서 반올림하면 3.5가 되는 소수 두 자리 수 중 가장 큰 수와 가장 작은 수의 합을 소수점을 포함하여 답을 구하시오.",
        "question_en": "Find the answer, including the decimal point, for the sum of the largest and smallest numbers with two decimals, which give 3.5 when rounded off from two decimal places.",
        "answer_ko": "6.99",
        "answer_en": "6.99",
        "solution_abst_ko": "3.45 3.54 [OP_ADD]",
        "solution_abst_en": "3.45 3.54 [OP_ADD]",
        "solution_code_ko": "var_a = 3.45\nvar_b = 3.54\nvar_c = var_a + var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 3.45\nvar_b = 3.54\nvar_c = var_a + var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "4312": {
        "category": "Possibility",
        "question_ko": "계산기에 0, 1, 2, 3, 4의 수가 각각 적힌 5개의 버튼 중 2개를 눌러 두 자리 정수를 만들 때 홀수는 모두 몇 개인지 구하시오",
        "question_en": "How many odd numbers are there when you press 2 of the 5 buttons which are 0, 1, 2, 3, and 4 on the calculator to create a two-digit integer?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 4 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 2 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 4 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 2 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 2\nlist_c = []\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if i % var_g == 0:\n        list_c.append(i)\nlist_d = list(set(list_b) - set(list_c))\nvar_h = len(list_d)\nprint(int(var_h))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 2\nlist_c = []\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if i % var_g == 0:\n        list_c.append(i)\nlist_d = list(set(list_b) - set(list_c))\nvar_h = len(list_d)\nprint(int(var_h))"
    },
    "4313": {
        "category": "Geometry",
        "question_ko": "한 쌍의 변이 평행한 사각형이 있습니다. 서로 평행한 변들 중 한 변의 길이는 25센티미터(㎝)이고, 두 변 사이의 거리는 13센티미터(㎝)이며, 이 사각형의 넓이가 286제곱센티미터(㎠)라면, 서로 평행한 변들 중 길이가 25센티미터(㎝)가 아닌 변의 길이는 몇 센티미터(㎝)일지 구하시오.",
        "question_en": "A quadrilateral has a pair of parallel sides. The length of one of the parallel sides is 25 centimeters (cm), and the distance between the two sides is 13 centimeters (cm). If the area of this rectangle is 286 square cm (cm2), find the length of the side that is not 25 centimeters (cm) in centimeters (cm).",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "286 13 [OP_DIV] 2 [OP_MUL] 25 [OP_SUB]",
        "solution_abst_en": "286 13 [OP_DIV] 2 [OP_MUL] 25 [OP_SUB]",
        "solution_code_ko": "var_a = 286\nvar_b = 13\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 25\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 286\nvar_b = 13\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 25\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "4314": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 8을 더하고 3을 곱하면 36입니다. 어떤 수를 구하시오.",
        "question_en": "Add 8 to a certain number and multiply by 3 to get 36. Find this particular number.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "36 3 [OP_DIV] 8 [OP_SUB]",
        "solution_abst_en": "36 3 [OP_DIV] 8 [OP_SUB]",
        "solution_code_ko": "var_a = 36\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 8\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 36\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 8\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "4315": {
        "category": "Arithmetic calculation",
        "question_ko": "운동장에 남학생이 57명, 여학생이 82명 있습니다. 여학생은 남학생과 선생님을 합한 것보다 13명 더 많이 있습니다. 운동장에 있는 선생님의 수는 몇 명입니까?",
        "question_en": "When there are 57 boys and 82 girls on the playground, the number of female students is 13 more than male students plus teachers. How many teachers are there in the playground?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "82 13 [OP_SUB] 57 [OP_SUB]",
        "solution_abst_en": "82 13 [OP_SUB] 57 [OP_SUB]",
        "solution_code_ko": "var_a = 82\nvar_b = 13\nvar_c = var_a - var_b\nvar_d = 57\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 82\nvar_b = 13\nvar_c = var_a - var_b\nvar_d = 57\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "4316": {
        "category": "Correspondence",
        "question_ko": "어떤 수는 5로 나누어떨어지고 몫은 96이다. 어떤 수에 17을 더한 다음 69를 곱한 값은 얼마인지 구하시오.",
        "question_en": "A number is divisible by 5 and the quotient is 96. What is the result of adding 17 to the number and then multiplying by 69?",
        "answer_ko": "34293",
        "answer_en": "34293",
        "solution_abst_ko": "5 96 [OP_MUL] 17 [OP_ADD] 69 [OP_MUL]",
        "solution_abst_en": "5 96 [OP_MUL] 17 [OP_ADD] 69 [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 96\nvar_c = var_a * var_b\nvar_d = 17\nvar_e = var_c + var_d\nvar_f = 69\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 96\nvar_c = var_a * var_b\nvar_d = 17\nvar_e = var_c + var_d\nvar_f = 69\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "4317": {
        "category": "Geometry",
        "question_ko": "평행사변형의 두 변의 길이가 각각 10 센티미터(㎝), 7 센티미터(㎝)일 때 네 변의 길이의 합은 몇 센티미터(㎝)일까요?",
        "question_en": "If the lengths of the two sides of a parallelogram are 10 centimeters (cm) and 7 centimeters (cm), how many centimeters (cm) is the sum of the lengths of the four sides?",
        "answer_ko": "34",
        "answer_en": "34",
        "solution_abst_ko": "10 7 [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "10 7 [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "4318": {
        "category": "Correspondence",
        "question_ko": "2와 5사이의 수 중, 4보다 작은 수는 무엇입니까?",
        "question_en": "Which number from 2 to 5 is less than 4?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "2 1 [OP_ADD] 5 1 [OP_SUB] 1 [OP_LIST_ARANGE] 4 [OP_LIST_LESS] 1 [OP_LIST_GET]",
        "solution_abst_en": "2 1 [OP_ADD] 5 1 [OP_SUB] 1 [OP_LIST_ARANGE] 4 [OP_LIST_LESS] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 2\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = 4\nlist_b = []\nfor i in list_a:\n    if i < var_h:\n        list_b.append(i)\nvar_i = 1\nvar_j = list_b[var_i-1]\nprint(int(var_j))",
        "solution_code_en": "var_a = 2\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = 4\nlist_b = []\nfor i in list_a:\n    if i < var_h:\n        list_b.append(i)\nvar_i = 1\nvar_j = list_b[var_i-1]\nprint(int(var_j))"
    },
    "4319": {
        "category": "Possibility",
        "question_ko": "1, 6, 8이 적힌 돌맹이를 각 한번씩 모두 사용하여 세 자리 수를 만들 때, 만들 수 있는 가장 작은 수와 세 번째로 작은 수의 차이를 구하시오.",
        "question_en": "Find the difference between the smallest number and the third smallest number you can make by using all the stones 1, 6, and 8 once each to make a three-digit number.",
        "answer_ko": "450",
        "answer_en": "450",
        "solution_abst_ko": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 3 [OP_LIST_MIN] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 3 [OP_LIST_MIN] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f - var_h\nvar_j = abs(var_i)\nprint(int(var_j))",
        "solution_code_en": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f - var_h\nvar_j = abs(var_i)\nprint(int(var_j))"
    },
    "4320": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.9 중에서 0.4보다 큰 수는 몇 개입니까?",
        "question_en": "How many of 0.8, 1/2, and 0.9 are greater than 0.4?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 0.4 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 0.4 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.4\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.4\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "4321": {
        "category": "Arithmetic calculation",
        "question_ko": "빨간색, 노란색, 파란색 가방에 책이 여러 권씩 들어있습니다. 세 가방 안에 들어있는 책의 무게의 합은 1킬로그램(㎏) 200그램(g)입니다. 파란색 가방에 들어있는 200그램(g)짜리 책 한 권을 노란색 가방으로 옮기고, 100그램(g)짜리 책 한권을 빨간색 가방으로 옮긴다면, 세 가방 안에 들어있는 책의 무게는 같아진다고 합니다. 빨간색 가방에 처음 들어있던 책의 무게의 합을 구하시오.",
        "question_en": "The red, yellow and blue bags contain a number of books. The total weight of the books in the three bags is 1 kilogram (kg) and 200 grams (g). If you move a 200 gram (g) book from a blue bag to a yellow bag and a 100 gram (g) book to a red bag, the books in the three bags will weigh the same. Find the sum of the weights of the books that were originally in the red bag.",
        "answer_ko": "300",
        "answer_en": "300",
        "solution_abst_ko": "1 1000 [OP_MUL] 200 [OP_ADD] 200 [OP_SUB] 100 [OP_SUB] 3 [OP_DIV]",
        "solution_abst_en": "1 1000 [OP_MUL] 200 [OP_ADD] 200 [OP_SUB] 100 [OP_SUB] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 200\nvar_e = var_c + var_d\nvar_f = 200\nvar_g = var_e - var_f\nvar_h = 100\nvar_i = var_g - var_h\nvar_j = 3\nvar_k = var_i / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 1\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 200\nvar_e = var_c + var_d\nvar_f = 200\nvar_g = var_e - var_f\nvar_h = 100\nvar_i = var_g - var_h\nvar_j = 3\nvar_k = var_i / var_j\nprint(int(var_k))"
    },
    "4322": {
        "category": "Possibility",
        "question_ko": "빨간색, 파란색, 노란색, 초록색 네 종류의 구슬에서 중복을 허용하여 21개를 택하되, 각 공을 3개 이상 뽑는 경우의 수를 구하시오.",
        "question_en": "From the four types of marbles - red, blue, yellow, and green, find the number of cases in which you select 21 balls allowing overlaps but draw 3 or more balls from each color.",
        "answer_ko": "220",
        "answer_en": "220",
        "solution_abst_ko": "4 21 [OP_ADD] 4 3 [OP_MUL] [OP_SUB] 1 [OP_SUB] 21 4 3 [OP_MUL] [OP_SUB] [OP_COMB]",
        "solution_abst_en": "4 21 [OP_ADD] 4 3 [OP_MUL] [OP_SUB] 1 [OP_SUB] 21 4 3 [OP_MUL] [OP_SUB] [OP_COMB]",
        "solution_code_ko": "var_a = 4\nvar_b = 21\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = 21\nvar_k = 4\nvar_l = 3\nvar_m = var_k * var_l\nvar_n = var_j - var_m\nvar_o = 1\nvar_i = int(var_i)\nvar_n = int(var_n)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o * (var_i-i)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o / (i+1)\nprint(int(var_o))",
        "solution_code_en": "var_a = 4\nvar_b = 21\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = 21\nvar_k = 4\nvar_l = 3\nvar_m = var_k * var_l\nvar_n = var_j - var_m\nvar_o = 1\nvar_i = int(var_i)\nvar_n = int(var_n)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o * (var_i-i)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o / (i+1)\nprint(int(var_o))"
    },
    "4323": {
        "category": "Comparison",
        "question_ko": "총 4개의 숫자 0.8, 1/2, 0.5, 1/3이 있습니다. 이 중 3보다 작거나 같은 수는 몇 개 일까요?",
        "question_en": "When there are 4 numbers of 0.8, 1/2, 0.5, and 1/3, how many of them are less than or equal to 3?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.5 1/3 [OP_LIST_EOL] 3 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.5 1/3 [OP_LIST_EOL] 3 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.5\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = []\nfor i in list_a:\n    if i <= var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.5\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = []\nfor i in list_a:\n    if i <= var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "4324": {
        "category": "Geometry",
        "question_ko": "높이가 5미터(m) 20센티미터(㎝)이고, 밑면의 두 변이 각각 6미터(m) 40센티미터(㎝), 9미터(m)인 직육면체 모양의 기름통에 기름이 가득 차있습니다. 부피가 1세제곱미터(㎥)인 기름통 여러 개에 모두 나누어 담으려고 합니다. 기름통은 적어도 몇 개 필요한지 구해보시오.",
        "question_en": "An oil drum in the shape of a cuboid with a height of 5 meters (m) and 20 centimeters (cm) and two sides of the bottom each measuring 6 meters (m), 40 centimeters (cm), and 9 meters (m), is filled with oil. We're going to split it up into several barrels of oil into a oil drum with a volume of 1 cubic meter (m3). Find at least how many oil drums you need.",
        "answer_ko": "300",
        "answer_en": "300",
        "solution_abst_ko": "6 40 100 [OP_DIV] [OP_ADD] 9 [OP_MUL] 5 20 100 [OP_DIV] [OP_ADD] [OP_MUL] 1 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "6 40 100 [OP_DIV] [OP_ADD] 9 [OP_MUL] 5 20 100 [OP_DIV] [OP_ADD] [OP_MUL] 1 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 6\nvar_b = 40\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 9\nvar_g = var_e * var_f\nvar_h = 5\nvar_i = 20\nvar_j = 100\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_g * var_l\nvar_n = 1\nvar_o = var_m / var_n\nvar_p = 1\nvar_q=int(((var_o+9*10**(var_p-2))//(10**(var_p-1)))*10**(var_p-1))\n\nprint(int(var_q))",
        "solution_code_en": "var_a = 6\nvar_b = 40\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 9\nvar_g = var_e * var_f\nvar_h = 5\nvar_i = 20\nvar_j = 100\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_g * var_l\nvar_n = 1\nvar_o = var_m / var_n\nvar_p = 1\nvar_q=int(((var_o+9*10**(var_p-2))//(10**(var_p-1)))*10**(var_p-1))\n\nprint(int(var_q))"
    },
    "4325": {
        "category": "Comparison",
        "question_ko": "정국에는 6에서 3을 뺀 수를 모았고, 윤기는 4를 모았습니다. 누구의 수가 작습니까?",
        "question_en": "Jungkook collects the number 6 minus 3, and Yoongi collects 4. Whose number is smaller?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 윤기 [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_SUB] 4 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Yoongi [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_SUB] 4 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '윤기'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 3\nvar_e = var_c - var_d\nvar_f = 4\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Yoongi'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 3\nvar_e = var_c - var_d\nvar_f = 4\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "4326": {
        "category": "Arithmetic calculation",
        "question_ko": "유정이가 처음 가지고 있던 구슬 중 8개를 은지에게 주었더니 24개가 남았습니다. 은지에게 구슬을 주기 전 유정이가 가지고 있던 구슬은 몇 개 입니까?",
        "question_en": "Yoojeong gave Eunji 8 of the marbles she had at first, and there are 24 left. How many marbles did Yoojeong have before giving them to Eunji?",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "24 8 [OP_ADD]",
        "solution_abst_en": "24 8 [OP_ADD]",
        "solution_code_ko": "var_a = 24\nvar_b = 8\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 24\nvar_b = 8\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "4327": {
        "category": "Geometry",
        "question_ko": "직사각형 모양의 천이 있습니다. 이 천의 세로 길이가 150센티미터(㎝)이고 넓이는 3제곱미터(㎡)라면 가로의 길이는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "I have a rectangular piece of cloth. If the length of this cloth is 150 centimeters (cm) and the area is 3 square meters (m2), how many centimeters (cm) is the width?",
        "answer_ko": "200",
        "answer_en": "200",
        "solution_abst_ko": "3 100 2 [OP_POW] [OP_MUL] 150 [OP_DIV]",
        "solution_abst_en": "3 100 2 [OP_POW] [OP_MUL] 150 [OP_DIV]",
        "solution_code_ko": "var_a = 3\nvar_b = 100\nvar_c = 2\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 150\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 3\nvar_b = 100\nvar_c = 2\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 150\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "4328": {
        "category": "Arithmetic calculation",
        "question_ko": "은지네 학교에서 나무를 심는데 (가) 반은 35그루를 심었고, (나) 반은 (가) 반보다 6그루 더 많이 심었고, (다) 반은 (가) 반보다 3그루 더 적게 심었습니다. (가), (나), (다) 세 반이 심은 평균 나무 수는 몇 그루입니까?",
        "question_en": "At Eunji's school, class (A) planted 35 trees, class (B) planted 6 more trees than class (A), and class (C) planted 3 less trees than class (A). What is the average number of trees planted by three classes (A), (B), and (C)?",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "35 35 6 [OP_ADD] [OP_ADD] 35 3 [OP_SUB] [OP_ADD] 3 [OP_DIV]",
        "solution_abst_en": "35 35 6 [OP_ADD] [OP_ADD] 35 3 [OP_SUB] [OP_ADD] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 35\nvar_b = 35\nvar_c = 6\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nvar_f = 35\nvar_g = 3\nvar_h = var_f - var_g\nvar_i = var_e + var_h\nvar_j = 3\nvar_k = var_i / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 35\nvar_b = 35\nvar_c = 6\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nvar_f = 35\nvar_g = 3\nvar_h = var_f - var_g\nvar_i = var_e + var_h\nvar_j = 3\nvar_k = var_i / var_j\nprint(int(var_k))"
    },
    "4329": {
        "category": "Correspondence",
        "question_ko": "40개의 인형 중 4개가 불량품이다. 불량품이 아닌 정상품들을 다른 네 곳의 가게로 동일한 개수를 보낼 때, 한 가게에 몇 개씩 보내야 하는가?",
        "question_en": "4 out of 40 dolls are defective. When you send the non-defective remainder out to four stores equally, how many should you send per store?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "40 4 [OP_SUB] 4 [OP_DIV]",
        "solution_abst_en": "40 4 [OP_SUB] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 40\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 40\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "4330": {
        "category": "Geometry",
        "question_ko": "진수는 한 모서리가 2센티미터(㎝)인 주사위를 125개 가지고 있습니다. 이 주사위를 쌓아 정육면체 모양을 만들었을 때, 이 쌓아 만든 정육면체의 부피는 얼마입니까?",
        "question_en": "Jinsu has 125 dice, each with an edge of 2 centimeters (cm). If these dice are stacked to form a cube, what is the volume of the cube?",
        "answer_ko": "1000",
        "answer_en": "1000",
        "solution_abst_ko": "2 3 [OP_POW] 125 [OP_MUL]",
        "solution_abst_en": "2 3 [OP_POW] 125 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = var_a ** var_b\nvar_d = 125\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = var_a ** var_b\nvar_d = 125\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "4331": {
        "category": "Correspondence",
        "question_ko": "네 자리 수 두 개의 덧셈인 DCBA+ABCD=ABCD0가 있습니다. A, B, C, D가 서로 다른 수라면, A부터 D까지 모두 더한 값은 얼마입니까?",
        "question_en": "We have DCBA+ABCD=ABCD0, which is the addition of two four-digit numbers. If A, B, C, and D are different numbers, what is the sum of A through D?",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "[OP_LIST_SOL] DCBA+ABCD=ABCD0 A [OP_DIGIT_UNK_SOLVER] DCBA+ABCD=ABCD0 B [OP_DIGIT_UNK_SOLVER] DCBA+ABCD=ABCD0 C [OP_DIGIT_UNK_SOLVER] DCBA+ABCD=ABCD0 D [OP_DIGIT_UNK_SOLVER] [OP_LIST_EOL] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] DCBA+ABCD=ABCD0 A [OP_DIGIT_UNK_SOLVER] DCBA+ABCD=ABCD0 B [OP_DIGIT_UNK_SOLVER] DCBA+ABCD=ABCD0 C [OP_DIGIT_UNK_SOLVER] DCBA+ABCD=ABCD0 D [OP_DIGIT_UNK_SOLVER] [OP_LIST_EOL] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 'DCBA+ABCD=ABCD0'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 'DCBA+ABCD=ABCD0'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = 'DCBA+ABCD=ABCD0'\nvar_h = 'C'\nans_dict = dict()\nvar_g = var_g.replace('×','*')\nvar_g = var_g.replace('x','*')\nvar_g = var_g.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_g):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_g\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_g):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_i = ans_dict[var_h]\nvar_j = 'DCBA+ABCD=ABCD0'\nvar_k = 'D'\nans_dict = dict()\nvar_j = var_j.replace('×','*')\nvar_j = var_j.replace('x','*')\nvar_j = var_j.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_j):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_j\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_j):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_l = ans_dict[var_k]\nlist_a= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_a.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_m = sum(list_a)\nprint(int(var_m))",
        "solution_code_en": "var_a = 'DCBA+ABCD=ABCD0'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 'DCBA+ABCD=ABCD0'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = 'DCBA+ABCD=ABCD0'\nvar_h = 'C'\nans_dict = dict()\nvar_g = var_g.replace('×','*')\nvar_g = var_g.replace('x','*')\nvar_g = var_g.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_g):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_g\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_g):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_i = ans_dict[var_h]\nvar_j = 'DCBA+ABCD=ABCD0'\nvar_k = 'D'\nans_dict = dict()\nvar_j = var_j.replace('×','*')\nvar_j = var_j.replace('x','*')\nvar_j = var_j.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_j):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_j\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_j):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_l = ans_dict[var_k]\nlist_a= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_a.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_m = sum(list_a)\nprint(int(var_m))"
    },
    "4332": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 30을 곱해야 할 것을 잘못하여 더했더니 86이 되었습니다. 바르게 계산하면 얼마인지 구해 보시오.",
        "question_en": "When you mistakenly add 30 which should have been multiplied to by number, you get 86. Find out how much it is if you calculate it correctly.",
        "answer_ko": "1680",
        "answer_en": "1680",
        "solution_abst_ko": "86 30 [OP_SUB] 30 [OP_MUL]",
        "solution_abst_en": "86 30 [OP_SUB] 30 [OP_MUL]",
        "solution_code_ko": "var_a = 86\nvar_b = 30\nvar_c = var_a - var_b\nvar_d = 30\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 86\nvar_b = 30\nvar_c = var_a - var_b\nvar_d = 30\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "4333": {
        "category": "Arithmetic calculation",
        "question_ko": "29보다 크고 36보다 작은 두 자리 수는 모두 몇 개입니까?",
        "question_en": "How many two-digit numbers are there that are greater than 29 and less than 36?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "29 1 [OP_ADD] 36 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_LEN]",
        "solution_abst_en": "29 1 [OP_ADD] 36 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 29\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 36\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = len(list_a)\nprint(int(var_h))",
        "solution_code_en": "var_a = 29\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 36\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = len(list_a)\nprint(int(var_h))"
    },
    "4334": {
        "category": "Arithmetic calculation",
        "question_ko": "자동차가 어린이 보호 구역을 시속 27킬로미터(㎞)로 50초 동안 달렸습니다. 자동차가 달린 거리는 몇 미터(m)입니까?",
        "question_en": "The car ran through the school zone at 27 kilometers per hour (km) for 50 seconds. How many meters (m) did the car move?",
        "answer_ko": "375",
        "answer_en": "375",
        "solution_abst_ko": "27 1000 [OP_MUL] 60 2 [OP_POW] [OP_DIV] 50 [OP_MUL]",
        "solution_abst_en": "27 1000 [OP_MUL] 60 2 [OP_POW] [OP_DIV] 50 [OP_MUL]",
        "solution_code_ko": "var_a = 27\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 60\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c / var_f\nvar_h = 50\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 27\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 60\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c / var_f\nvar_h = 50\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "4335": {
        "category": "Correspondence",
        "question_ko": "형욱이의 아버지가 32살일 때 형욱이는 5살이고, 형욱이가 7살일 때 형욱이의 형은 10살입니다. 형이 12살일 때 형욱이와 아버지의 나이의 합을 구하시오.",
        "question_en": "When Hyung-wook's father is 32 years old, Hyung-wook is 5 years old, and when Hyung-wook is 7 years old, Hyung-wook's elder brother is 10 years old. Find the sum of the ages of Hyung-wook and his father when Hyung-wook's elder brother is 12 years old.",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "12 7 10 [OP_SUB] [OP_ADD] 12 7 10 [OP_SUB] [OP_ADD] 32 5 [OP_SUB] [OP_ADD] [OP_ADD]",
        "solution_abst_en": "12 7 10 [OP_SUB] [OP_ADD] 12 7 10 [OP_SUB] [OP_ADD] 32 5 [OP_SUB] [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 12\nvar_b = 7\nvar_c = 10\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 12\nvar_g = 7\nvar_h = 10\nvar_i = var_g - var_h\nvar_j = var_f + var_i\nvar_k = 32\nvar_l = 5\nvar_m = var_k - var_l\nvar_n = var_j + var_m\nvar_o = var_e + var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 12\nvar_b = 7\nvar_c = 10\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 12\nvar_g = 7\nvar_h = 10\nvar_i = var_g - var_h\nvar_j = var_f + var_i\nvar_k = 32\nvar_l = 5\nvar_m = var_k - var_l\nvar_n = var_j + var_m\nvar_o = var_e + var_n\nprint(int(var_o))"
    },
    "4336": {
        "category": "Geometry",
        "question_ko": "옆면이 A개인 각뿔의 밑면은 팔각형입니다. A는?",
        "question_en": "The base of a pyramid with A sides is an octagon. What number fits in A?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "8",
        "solution_abst_en": "8",
        "solution_code_ko": "var_a = 8\nprint(int(var_a))",
        "solution_code_en": "var_a = 8\nprint(int(var_a))"
    },
    "4337": {
        "category": "Correspondence",
        "question_ko": "98개의 사탕을 7개씩 나누어 포장하면 몇 묶음이 나오는지 구하시오.",
        "question_en": "How many packs of candies are there if you pack 98 of them in 7 packs?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "98 7 [OP_DIV]",
        "solution_abst_en": "98 7 [OP_DIV]",
        "solution_code_ko": "var_a = 98\nvar_b = 7\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 98\nvar_b = 7\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "4338": {
        "category": "Possibility",
        "question_ko": "두 자연수 2,4를 모두 이용하여 만들 수 있는 수 중 가장 작은 수는 얼마입니까?",
        "question_en": "What is the smallest number that can be formed by using natural numbers 2 and 4?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "[OP_LIST_SOL] 2 4 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 2 4 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_e = list_c[var_d-1]\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_e = list_c[var_d-1]\nprint(int(var_e))"
    },
    "4339": {
        "category": "Geometry",
        "question_ko": "동건이는 밑변이 3센티미터(㎝) 이고 높이가 6.02 센티미터(㎝) 인 삼각형을 그렸으며, 지혜는 밑변이 3센티미터(㎝) 이고 높이가 2센티미터(㎝) 인 삼각형을 그렸습니다. 동건이가 그린 삼각형의 넓이는 지혜가 그린 삼각형의 넓이의 몇 배입니까?",
        "question_en": "Donggeon drew a triangle with a base of 3 centimeters (cm) and a height of 6.02 centimeters (cm), and Jihye drew a triangle with a base of 3 centimeters (cm) and a height of 2 centimeters (cm). How many times the width of the triangle drawn by Donggeon is the width of the triangle drawn by Jihye?",
        "answer_ko": "3.01",
        "answer_en": "3.01",
        "solution_abst_ko": "3 6.02 [OP_MUL] 2 [OP_DIV] 3 2 [OP_MUL] 2 [OP_DIV] [OP_DIV]",
        "solution_abst_en": "3 6.02 [OP_MUL] 2 [OP_DIV] 3 2 [OP_MUL] 2 [OP_DIV] [OP_DIV]",
        "solution_code_ko": "var_a = 3\nvar_b = 6.02\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 3\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = 2\nvar_j = var_h / var_i\nvar_k = var_e / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 3\nvar_b = 6.02\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 3\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = 2\nvar_j = var_h / var_i\nvar_k = var_e / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "4340": {
        "category": "Arithmetic calculation",
        "question_ko": "동전 1250개가 바닥에 널려있다. 앞면인 동전의 수가 뒷면인 동전의 수보다 124개 더 많을 때, 뒷면인 동전의 개수를 구하시오.",
        "question_en": "1250 coins are scattered on the floor. If the number of coins with heads is 124 more than the number of coins with tails, find the number of coins with tails.",
        "answer_ko": "563",
        "answer_en": "563",
        "solution_abst_ko": "1250 124 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "1250 124 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 1250\nvar_b = 124\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 1250\nvar_b = 124\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "4341": {
        "category": "Arithmetic calculation",
        "question_ko": "미수와 주희가 총 2리터(L) 100밀리리터(㎖)의 우유를 나눠서 배달하려고 합니다. 미수가 주희보다 200밀리리터(㎖) 더 많이 배달하려면 미수는 몇 밀리리터(㎖)의 우유를 배달해야 합니까?",
        "question_en": "Misoo and Joohee are trying to deliver a total of 2 liters (L) and 100 milliliters (㎖) of milk. How many milliliters (ml) of milk must Misoo deliver if Misoo delivers 200 milliliters (ml) more milk than Joohee does?",
        "answer_ko": "1150",
        "answer_en": "1150",
        "solution_abst_ko": "2 1000 [OP_MUL] 100 [OP_ADD] 200 [OP_ADD] 2 [OP_DIV]",
        "solution_abst_en": "2 1000 [OP_MUL] 100 [OP_ADD] 200 [OP_ADD] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = var_c + var_d\nvar_f = 200\nvar_g = var_e + var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = var_c + var_d\nvar_f = 200\nvar_g = var_e + var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "4342": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 300까지의 수를 만드려고 합니다. 0부터 9까지의 숫자 카드 중 숫자 3은 모두 몇 장 있어야 하는지 구하시오.",
        "question_en": "I am trying to make a number from 1 to 300. How many of the number cards from 0 to 9 must contain the number 3?",
        "answer_ko": "61",
        "answer_en": "61",
        "solution_abst_ko": "1 300 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 3 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 300 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 3 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 300\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 3\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 300\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 3\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))"
    },
    "4343": {
        "category": "Geometry",
        "question_ko": "두 종류의 편지지가 있습니다. 편지지 A는 가로 6센티미터(㎝), 세로 9센티미터(㎝)인 직사각형 모양이고, 편지지 B는 가로 8센티미터(㎝), 세로 8센티미터(㎝)인 정사각형 모양입니다. 두 편지지 모두 같은 크기의 스티커를 편지지 둘레를 따라 붙여 꾸민다고 할 때 어느 편지지에 스티커를 더 많이 붙이게 됩니까?",
        "question_en": "There are two types of letter paper. Letter A is a rectangle with a width of 6 centimeters (cm) and a length of 9 centimeters (cm) long, and letter paper B is a square shape with a width of 8 centimeters (cm) and a length of 8 centimeters (cm) long. If both letter papers are decorated with stickers of the same size around the perimeter, which one has more stickers?",
        "answer_ko": "B",
        "answer_en": "B",
        "solution_abst_ko": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 6 9 [OP_ADD] 8 8 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 6 9 [OP_ADD] 8 8 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 9\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = 8\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 9\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = 8\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "4344": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 7을 곱해야 할 것을 잘못하여 6을 나눈 결과는 12가 되었습니다. 바르게 계산한 결과는 얼마인가요?",
        "question_en": "I had to multiply a number by 7 but mistakenly divided it by 6 instead to get 12. What is the correctly calculated value?",
        "answer_ko": "504",
        "answer_en": "504",
        "solution_abst_ko": "12 6 [OP_MUL] 7 [OP_MUL]",
        "solution_abst_en": "12 6 [OP_MUL] 7 [OP_MUL]",
        "solution_code_ko": "var_a = 12\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "4345": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 5를 곱하고 14를 더해야 하는데 잘못하여 5를 빼고 14를 더했더니 39가 되었습니다. 바르게 계산한 값과 틀리게 계산한 값의 합은 얼마인지 구하시오.",
        "question_en": "You need to multiply a number by 5 and then add 14, but you mistakenly subtracted 5 and added 14, getting 39 as an answer. Find the sum of the correctly calculated and incorrectly calculated values.",
        "answer_ko": "203",
        "answer_en": "203",
        "solution_abst_ko": "39 14 [OP_SUB] 5 [OP_ADD] 5 [OP_MUL] 14 [OP_ADD] 39 [OP_ADD]",
        "solution_abst_en": "39 14 [OP_SUB] 5 [OP_ADD] 5 [OP_MUL] 14 [OP_ADD] 39 [OP_ADD]",
        "solution_code_ko": "var_a = 39\nvar_b = 14\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = var_e * var_f\nvar_h = 14\nvar_i = var_g + var_h\nvar_j = 39\nvar_k = var_i + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 39\nvar_b = 14\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = var_e * var_f\nvar_h = 14\nvar_i = var_g + var_h\nvar_j = 39\nvar_k = var_i + var_j\nprint(int(var_k))"
    },
    "4346": {
        "category": "Arithmetic calculation",
        "question_ko": "수환이는 0.2리터(L)짜리 우유를 하루에 3번 마십니다. 수환이가 일주일 동안 마시는 우유는 모두 몇 리터(L)입니까?",
        "question_en": "Suhwan drinks 0.2 liters (L) of milk three times a day. How many liters (L) of milk does Suhwan drink in a week?",
        "answer_ko": "4.20",
        "answer_en": "4.2",
        "solution_abst_ko": "0.2 3 [OP_MUL] 7 [OP_MUL]",
        "solution_abst_en": "0.2 3 [OP_MUL] 7 [OP_MUL]",
        "solution_code_ko": "var_a = 0.2\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.2\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "4347": {
        "category": "Correspondence",
        "question_ko": "A, B는 두 자리 수입니다. A는 23보다 8 작은 수이고, B보다 7 큰 수는 18입니다. A-B의 값을 구하시오.",
        "question_en": "A and B are two-digit numbers. A is 8 less than 23. The number that is 7 greater than B is 18. Find the value of A-B.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "23 8 [OP_SUB] 18 7 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "23 8 [OP_SUB] 18 7 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 23\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 18\nvar_e = 7\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 23\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 18\nvar_e = 7\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "4348": {
        "category": "Geometry",
        "question_ko": "원의 반지름 길이가 4센티미터(㎝)일때, 원의 지름은 몇 센티미터(㎝)인가요?",
        "question_en": "If the radius of a circle is 4 centimeters (cm), what is the diameter of the circle in centimeters (cm)?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "4 2 [OP_MUL]",
        "solution_abst_en": "4 2 [OP_MUL]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "4349": {
        "category": "Arithmetic calculation",
        "question_ko": "5학년 학생과 6학년 학생이 합하여 24명이 있습니다. 이 중에서 5학년 학생에게만 체리 50개를 똑같이 나누어 주었더니 2개가 남았습니다. 6학년 학생의 수는 5학년 학생의 수의 절반일 때, 5학년 학생은 체리를 몇 개씩 받았는지 구하시오.",
        "question_en": "There are 24 students in the 5th and 6th grades together. Of these, 50 cherries were distributed equally to the 5th graders only, leaving 2 cherries. If the number of 6th graders is half the number of 5th graders, how many cherries did the 5th graders get?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "50 2 [OP_SUB] 24 2 1 [OP_ADD] [OP_FDIV] [OP_FDIV]",
        "solution_abst_en": "50 2 [OP_SUB] 24 2 1 [OP_ADD] [OP_FDIV] [OP_FDIV]",
        "solution_code_ko": "var_a = 50\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 24\nvar_e = 2\nvar_f = 1\nvar_g = var_e + var_f\nvar_h = var_d // var_g\nvar_i = var_c // var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 50\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 24\nvar_e = 2\nvar_f = 1\nvar_g = var_e + var_f\nvar_h = var_d // var_g\nvar_i = var_c // var_h\nprint(int(var_i))"
    },
    "4350": {
        "category": "Comparison",
        "question_ko": "풍선 24개가 있습니다. 이 중에서 파란색 풍선은 빨간색 풍선보다 6개 더 많고, 빨간색 풍선은 전체의 1/4이며, 나머지는 노란색 풍선이라고 합니다. 어떤 색의 풍선이 가장 많을까요?",
        "question_en": "There are 24 balloons. Of these, there are 6 more blue balloons than red balloons, red balloons are 1/4 of the total, and the rest are all yellow balloons. What color balloons will be the most?",
        "answer_ko": "파란색",
        "answer_en": "blue",
        "solution_abst_ko": "[OP_LIST_SOL] 빨간색 파란색 노란색 [OP_LIST_EOL] [OP_LIST_SOL] 24 1/4 [OP_MUL] 24 1/4 [OP_MUL] 6 [OP_ADD] 24 24 1/4 [OP_MUL] 6 [OP_ADD] [OP_SUB] 24 1/4 [OP_MUL] [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] red blue yellow [OP_LIST_EOL] [OP_LIST_SOL] 24 1/4 [OP_MUL] 24 1/4 [OP_MUL] 6 [OP_ADD] 24 24 1/4 [OP_MUL] 6 [OP_ADD] [OP_SUB] 24 1/4 [OP_MUL] [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '빨간색'\nvar_b = '파란색'\nvar_c = '노란색'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 24\nvar_e = 0.25\nvar_f = var_d * var_e\nvar_g = 24\nvar_h = 0.25\nvar_i = var_g * var_h\nvar_j = 6\nvar_k = var_i + var_j\nvar_l = 24\nvar_m = 24\nvar_n = 0.25\nvar_o = var_m * var_n\nvar_p = 6\nvar_q = var_o + var_p\nvar_r = var_l - var_q\nvar_s = 24\nvar_t = 0.25\nvar_u = var_s * var_t\nvar_v = var_r - var_u\nlist_b= []\nif \"/\" in str(var_v):\n    var_v = eval(str(var_v))\nlist_b.append(var_v)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_w = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_x = list_c[-var_w]\nvar_y = list_b.index(var_x)+1\nvar_z = list_a[var_y-1]\nprint(var_z)",
        "solution_code_en": "var_a = 'red'\nvar_b = 'blue'\nvar_c = 'yellow'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 24\nvar_e = 0.25\nvar_f = var_d * var_e\nvar_g = 24\nvar_h = 0.25\nvar_i = var_g * var_h\nvar_j = 6\nvar_k = var_i + var_j\nvar_l = 24\nvar_m = 24\nvar_n = 0.25\nvar_o = var_m * var_n\nvar_p = 6\nvar_q = var_o + var_p\nvar_r = var_l - var_q\nvar_s = 24\nvar_t = 0.25\nvar_u = var_s * var_t\nvar_v = var_r - var_u\nlist_b= []\nif \"/\" in str(var_v):\n    var_v = eval(str(var_v))\nlist_b.append(var_v)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_w = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_x = list_c[-var_w]\nvar_y = list_b.index(var_x)+1\nvar_z = list_a[var_y-1]\nprint(var_z)"
    },
    "4351": {
        "category": "Comparison",
        "question_ko": "어느 전시회의 입장객을 세어 보니 개장 첫날에는 350명, 2일 차에는 427명, 3일 차에는 384명, 4일 차에는 402명, 5일 차에는 431명이 왔습니다. 관람객이 400명 이하였던 날은 며칠 있었나요?",
        "question_en": "The number of visitors to an exhibition was 350 on the first day, 427 on the second day, 384 on the third day, 402 on the fourth day, and 431 on the fifth day. How many days were there no more than than 400 visitors?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 350 427 384 402 431 [OP_LIST_EOL] 400 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 350 427 384 402 431 [OP_LIST_EOL] 400 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 350\nvar_b = 427\nvar_c = 384\nvar_d = 402\nvar_e = 431\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 400\nlist_b = []\nfor i in list_a:\n    if i <= var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 350\nvar_b = 427\nvar_c = 384\nvar_d = 402\nvar_e = 431\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 400\nlist_b = []\nfor i in list_a:\n    if i <= var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "4352": {
        "category": "Geometry",
        "question_ko": "크기가 같은 구슬 몇 개를 가지고 한 변이 8개가 되도록 빈틈없이 늘어놓아 정사각형을 만들었습니다. 이 정사각형 둘레에 구슬을 놓아 또 한 번 에워싸도록 만들 때, 구슬은 몇 개가 더 필요합니까?",
        "question_en": "A square is formed by placing several marbles of the same size without gaps so that each side is filled with 8 marbles. How many more marbles do you need to place marbles around this square to enclose it again?",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "8 4 [OP_MUL] 4 [OP_ADD]",
        "solution_abst_en": "8 4 [OP_MUL] 4 [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "4353": {
        "category": "Comparison",
        "question_ko": "5, 8, 4 중에서 2번째로 작은 숫자는 무엇인가요?",
        "question_en": "Which number is the 2nd smallest among 5, 8, and 4?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "[OP_LIST_SOL] 5 8 4 [OP_LIST_EOL] 2 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 5 8 4 [OP_LIST_EOL] 2 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 5\nvar_b = 8\nvar_c = 4\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 8\nvar_c = 4\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nprint(int(var_e))"
    },
    "4354": {
        "category": "Correspondence",
        "question_ko": "수박 10개의 평균 무게는 4.2킬로그램(㎏)이다. 이때 수박 하나를 빼고 무게가 5킬로그램(㎏)인 수박을 바꿔넣으면 수박의 평균 무게가 4.4킬로그램(㎏)이 된다고 한다. 바뀌어 나간 수박의 무게는 몇 킬로그램(㎏)인가?",
        "question_en": "The average weight of 10 watermelons is 4.2 kg. If one of these watermelons is replaced by a watermelon weighing 5 kilograms (kg), the average weight of the watermelons becomes 4.4 kilograms (kg). How many kilograms (kg) is the watermelon that has been replaced?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "5 4.4 4.2 [OP_SUB] 10 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "5 4.4 4.2 [OP_SUB] 10 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 5\nvar_b = 4.4\nvar_c = 4.2\nvar_d = var_b - var_c\nvar_e = 10\nvar_f = var_d * var_e\nvar_g = var_a - var_f\nprint(int(eval('{:.2f}'.format(round(var_g+1e-10,2)))))",
        "solution_code_en": "var_a = 5\nvar_b = 4.4\nvar_c = 4.2\nvar_d = var_b - var_c\nvar_e = 10\nvar_f = var_d * var_e\nvar_g = var_a - var_f\nprint(int(eval('{:.2f}'.format(round(var_g+1e-10,2)))))"
    },
    "4355": {
        "category": "Arithmetic calculation",
        "question_ko": "15리터(L) 들이의 그릇에 7리터(L) 200밀리리터(㎖)의 물이 들어있습니다. 이 그릇에 물을 가득 채우려면 600밀리리터(㎖) 그릇으로 최소한 몇 번 부어야 합니까?",
        "question_en": "A 15 liter (L) bowl contains 7 liters (L) and 200 milliliters (㎖) of water. At least how many times would it take to pour water into a 600-milliliter (mL) bowl to fill this bowl?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "15 1000 [OP_MUL] 7 1000 [OP_MUL] 200 [OP_ADD] [OP_SUB] 600 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "15 1000 [OP_MUL] 7 1000 [OP_MUL] 200 [OP_ADD] [OP_SUB] 600 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 15\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = 200\nvar_h = var_f + var_g\nvar_i = var_c - var_h\nvar_j = 600\nvar_k = var_i / var_j\nvar_l = 1\nvar_m=int(((var_k+9*10**(var_l-2))//(10**(var_l-1)))*10**(var_l-1))\n\nprint(int(var_m))",
        "solution_code_en": "var_a = 15\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = 200\nvar_h = var_f + var_g\nvar_i = var_c - var_h\nvar_j = 600\nvar_k = var_i / var_j\nvar_l = 1\nvar_m=int(((var_k+9*10**(var_l-2))//(10**(var_l-1)))*10**(var_l-1))\n\nprint(int(var_m))"
    },
    "4356": {
        "category": "Possibility",
        "question_ko": "지영이와 신우가 가위바위보를 두 번 했을 때, 신우가 두 번 다 이기지 않는 경우의 수를 구하시오. (단, 무승부도 나올 수 있다.)",
        "question_en": "When Jiyoung and Shinwoo play rock-paper-scissors twice, find the number of cases in which Shinwoo does not win both times. (However, a draw may also come out.)",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "3 3 [OP_ADD] 3 3 [OP_ADD] [OP_MUL]",
        "solution_abst_en": "3 3 [OP_ADD] 3 3 [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 3\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "4357": {
        "category": "Arithmetic calculation",
        "question_ko": "운동장에 형욱이네 반 학생들이 한 줄로 서 있다. 학생들 간의 간격이 25미터(m)이고 맨 앞의 학생과 맨 뒤의 학생 간의 거리가 1500미터(m) 일 때, 형욱이네 반 학생들의 수를 구하시오.",
        "question_en": "Hyung-wook's classmates are standing in a line on the playground. If the distance between students is 25 meters (m) and the distance between the first and last students is 1500 meters (m), find the number of students in Hyung-wook's class.",
        "answer_ko": "61",
        "answer_en": "61",
        "solution_abst_ko": "1500 25 [OP_DIV] 1 [OP_ADD]",
        "solution_abst_en": "1500 25 [OP_DIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 1500\nvar_b = 25\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 1500\nvar_b = 25\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "4358": {
        "category": "Comparison",
        "question_ko": "슬기는 빨간 구슬을 23개 가지고 있습니다. 미란이는 파란 구슬을 34개 가지고 있고, 호현이는 노란 구슬을 32개 가지고 있습니다. 슬기와 호현이 중에서 구슬을 더 많이 가지고 있는 사람은 누구입니까?",
        "question_en": "Seulgi has 23 red marbles. Miran has 34 blue marbles and Hohyun has 32 yellow marbles. Who has more marbles  among Seulgi and Hohyun ?",
        "answer_ko": "호현",
        "answer_en": "Hohyun",
        "solution_abst_ko": "[OP_LIST_SOL] 슬기 호현 [OP_LIST_EOL] [OP_LIST_SOL] 23 32 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Seulgi Hohyun [OP_LIST_EOL] [OP_LIST_SOL] 23 32 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '슬기'\nvar_b = '호현'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 23\nvar_d = 32\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Seulgi'\nvar_b = 'Hohyun'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 23\nvar_d = 32\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "4359": {
        "category": "Arithmetic calculation",
        "question_ko": "굴비가 156두름 있습니다. 굴비 한 두름이 20마리일 때, 굴비는 모두 몇 마리 있는지 풀이 과정을 쓰고 답을 구하세요.",
        "question_en": "There are 156 dureums of gulbis. When there are 20 fish in one dureum, write a solution to find out how many gulbis there are in total and find out the answer.",
        "answer_ko": "3120",
        "answer_en": "3120",
        "solution_abst_ko": "156 20 [OP_MUL]",
        "solution_abst_en": "156 20 [OP_MUL]",
        "solution_code_ko": "var_a = 156\nvar_b = 20\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 156\nvar_b = 20\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "4360": {
        "category": "Possibility",
        "question_ko": "한 아파트 단지에 A, B, C, D, E, F 6명의 부녀회장 후보가 있을 때, 부녀회장대표 3명을 뽑는 경우의 수를 구하시오.",
        "question_en": "If there are 6 women's president candidates A, B, C, D, E, and F in an apartment complex, find the number of ways to select 3 women's president representatives.",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "[OP_LIST_SOL] A B C D E F [OP_LIST_EOL] [OP_LIST_LEN] 3 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D E F [OP_LIST_EOL] [OP_LIST_LEN] 3 [OP_COMB]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nvar_f = 'F'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = len(list_a)\nvar_h = 3\nvar_i = 1\nvar_g = int(var_g)\nvar_h = int(var_h)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i * (var_g-i)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i / (i+1)\nprint(int(var_i))",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nvar_f = 'F'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = len(list_a)\nvar_h = 3\nvar_i = 1\nvar_g = int(var_g)\nvar_h = int(var_h)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i * (var_g-i)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i / (i+1)\nprint(int(var_i))"
    },
    "4361": {
        "category": "Possibility",
        "question_ko": "모든 자리 수의 합이 34인 네 자리 수는 모두 몇 개입니까?",
        "question_en": "How many 4-digit numbers are there where the sum of all digits is 34?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "1000 10000 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] 34 [OP_LIST_MORE_EQUAL] 34 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "1000 10000 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] 34 [OP_LIST_MORE_EQUAL] 34 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1000\nvar_b = 10000\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nlist_b=[]\nfor i in list_a:\n    var_f = 0\n    i = int(i)\n    while i//10 > 0:\n        var_f = var_f + i%10\n        i = i//10\n    var_f = var_f + i%10\n    list_b.append(var_f)\nvar_g = 34\nlist_c = []\nfor i in list_b:\n    if i >= var_g:\n        list_c.append(i)\nvar_h = 34\nlist_d = []\nfor i in list_c:\n    if i <= var_h:\n        list_d.append(i)\nvar_i = len(list_d)\nprint(int(var_i))",
        "solution_code_en": "var_a = 1000\nvar_b = 10000\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nlist_b=[]\nfor i in list_a:\n    var_f = 0\n    i = int(i)\n    while i//10 > 0:\n        var_f = var_f + i%10\n        i = i//10\n    var_f = var_f + i%10\n    list_b.append(var_f)\nvar_g = 34\nlist_c = []\nfor i in list_b:\n    if i >= var_g:\n        list_c.append(i)\nvar_h = 34\nlist_d = []\nfor i in list_c:\n    if i <= var_h:\n        list_d.append(i)\nvar_i = len(list_d)\nprint(int(var_i))"
    },
    "4362": {
        "category": "Possibility",
        "question_ko": "빨간색 공, 파란색 공, 검정색 공, 노란색 공, 흰색 공이 들어있는 상자에서 공 2개 꺼내려고 합니다. 중복을 허용하여 꺼낼 수 있는 공의 경우의 수는 모두 몇 가지입니까?",
        "question_en": "We want to take 2 balls from a box containing a red ball, a blue ball, a black ball, a yellow ball and a white ball. How many balls can we draw if we allow duplicates?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "[OP_LIST_SOL] 빨간색 파란색 검정색 노란색 흰색 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] red blue black yellow white [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '빨간색'\nvar_b = '파란색'\nvar_c = '검정색'\nvar_d = '노란색'\nvar_e = '흰색'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = 2\nvar_l = 1\nvar_j = int(var_j)\nvar_k = int(var_k)\nfor i, elem in enumerate(range(var_k)):\n    var_l = var_l * (var_j-i)\nfor i, elem in enumerate(range(var_k)):\n    var_l = var_l / (i+1)\nprint(int(var_l))",
        "solution_code_en": "var_a = 'red'\nvar_b = 'blue'\nvar_c = 'black'\nvar_d = 'yellow'\nvar_e = 'white'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = 2\nvar_l = 1\nvar_j = int(var_j)\nvar_k = int(var_k)\nfor i, elem in enumerate(range(var_k)):\n    var_l = var_l * (var_j-i)\nfor i, elem in enumerate(range(var_k)):\n    var_l = var_l / (i+1)\nprint(int(var_l))"
    },
    "4363": {
        "category": "Comparison",
        "question_ko": "경시반 학생 5명이 수학 시험을 친 결과 평균 점수가 81.6점이었다. 가장 높은 점수를 빼고 평균을 내면 가장 낮은 점수를 빼고 평균을 낸 것보다 6점이 낮다고 한다. 가장 높은 점수와 가장 낮은 점수를 제외한 나머지 3명의 점수가 88점, 84점, 76점이라고 할 때, 가장 높은 점수를 구하여라.",
        "question_en": "The average math test score of 5 students in the competition class was 81.6. After excluding the highest score, we averaged the scores and it was said to be 6 points lower than averaging the scores after excluding the lowest score. If the scores of the remaining students, excluding the highest and lowest score, are 88, 84, and 76, find the highest score.",
        "answer_ko": "92",
        "answer_en": "92",
        "solution_abst_ko": "81.6 5 [OP_MUL] 88 84 [OP_ADD] 76 [OP_ADD] [OP_SUB] 6 4 [OP_MUL] [OP_ADD] 2 [OP_DIV]",
        "solution_abst_en": "81.6 5 [OP_MUL] 88 84 [OP_ADD] 76 [OP_ADD] [OP_SUB] 6 4 [OP_MUL] [OP_ADD] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 81.6\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 88\nvar_e = 84\nvar_f = var_d + var_e\nvar_g = 76\nvar_h = var_f + var_g\nvar_i = var_c - var_h\nvar_j = 6\nvar_k = 4\nvar_l = var_j * var_k\nvar_m = var_i + var_l\nvar_n = 2\nvar_o = var_m / var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 81.6\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 88\nvar_e = 84\nvar_f = var_d + var_e\nvar_g = 76\nvar_h = var_f + var_g\nvar_i = var_c - var_h\nvar_j = 6\nvar_k = 4\nvar_l = var_j * var_k\nvar_m = var_i + var_l\nvar_n = 2\nvar_o = var_m / var_n\nprint(int(var_o))"
    },
    "4364": {
        "category": "Possibility",
        "question_ko": "지안이와 신영이가 가위바위보를 할 때, 신영이와 지안이가 비긴 경우의 수를 구하시오. (단, 무승부도 나올 수 있다.)",
        "question_en": "Find the number of cases in which Shin-Young and Ji-An tied when Ji-An and Shin-Young play rock-paper-scissors. (However, a draw may also occur.)",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "3",
        "solution_abst_en": "3",
        "solution_code_ko": "var_a = 3\nprint(int(var_a))",
        "solution_code_en": "var_a = 3\nprint(int(var_a))"
    },
    "4365": {
        "category": "Arithmetic calculation",
        "question_ko": "철사 5센티미터(㎝)로 정사각형 1개를 만들 수 있습니다. 철사 48.5센티미터(㎝)로 똑같은 크기의 정사각형을 몇 개 만들 수 있습니까?",
        "question_en": "You can make one square out of 5 centimeters (cm) of wire. How many equally sized squares can you make with 48.5 centimeters (cm) of wire?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "48.5 5 [OP_FDIV]",
        "solution_abst_en": "48.5 5 [OP_FDIV]",
        "solution_code_ko": "var_a = 48.5\nvar_b = 5\nvar_c = var_a // var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 48.5\nvar_b = 5\nvar_c = var_a // var_b\nprint(int(var_c))"
    },
    "4366": {
        "category": "Correspondence",
        "question_ko": "153은 어떤 수에 6을 곱해야하는데 실수로 9를 곱하여 나온 결과입니다. 바르게 계산했을때 결과를 구하세요.",
        "question_en": "153 is the result of accidentally multiplying a certain number by 9 while it had to be multiplied by 6. Find the result when you calculate correctly.",
        "answer_ko": "102",
        "answer_en": "102",
        "solution_abst_ko": "153 9 [OP_DIV] 6 [OP_MUL]",
        "solution_abst_en": "153 9 [OP_DIV] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 153\nvar_b = 9\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 153\nvar_b = 9\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "4367": {
        "category": "Geometry",
        "question_ko": "직사각형 모양의 공원의 가로가 9킬로미터(㎞)이다. 공원을 가장자리를 따라 한바퀴 걸으면 46킬로미터(㎞)를 걷는다. 공원의 세로는 몇 킬로미터(㎞)인가?",
        "question_en": "The width of the rectangular-shaped park is 9 kilometers (km). If you walk around the edge of the park, you walk 46 kilometers (km). How many kilometers (km) is the length of the park?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "46 2 [OP_DIV] 9 [OP_SUB]",
        "solution_abst_en": "46 2 [OP_DIV] 9 [OP_SUB]",
        "solution_code_ko": "var_a = 46\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 9\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 46\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 9\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "4368": {
        "category": "Geometry",
        "question_ko": "가로 47.3센티미터(㎝), 세로 24센티미터(㎝)인 직사각형의 넓이는 얼마가 됩니까?",
        "question_en": "What is the area of a rectangle measuring 47.3 centimeters (cm) long and 24 centimeters (cm) wide?",
        "answer_ko": "1135.20",
        "answer_en": "1135.2",
        "solution_abst_ko": "47.3 24 [OP_MUL]",
        "solution_abst_en": "47.3 24 [OP_MUL]",
        "solution_code_ko": "var_a = 47.3\nvar_b = 24\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 47.3\nvar_b = 24\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "4369": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 5를 빼면 35가 된다. 어떤 수를 5로 나눈 값을 구하시오.",
        "question_en": "Subtracting 5 from a number equals 35. Find the value of that number divided by 5.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "35 5 [OP_ADD] 5 [OP_DIV]",
        "solution_abst_en": "35 5 [OP_ADD] 5 [OP_DIV]",
        "solution_code_ko": "var_a = 35\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 35\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "4370": {
        "category": "Comparison",
        "question_ko": "정국이는 우유를 1.3리터(L) 마셨습니다. 석진이는 11/10리터(L) 마셨고, 윤기는 7/5리터(L) 마셨습니다. 우유를 가장 적게 마신 사람은 누구입니까?",
        "question_en": "Jungkook drank 1.3 liters (l) of milk. Seokjin drank 11/10 liters (l), and Yoongi drank 7/5 liters (l). Who drank the least milk?",
        "answer_ko": "석진",
        "answer_en": "Seokjin",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 석진 윤기 [OP_LIST_EOL] [OP_LIST_SOL] 1.3 11 10 [OP_DIV] 7 5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Seokjin Yoongi [OP_LIST_EOL] [OP_LIST_SOL] 1.3 11 10 [OP_DIV] 7 5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '석진'\nvar_c = '윤기'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1.3\nvar_e = 11\nvar_f = 10\nvar_g = var_e / var_f\nvar_h = 7\nvar_i = 5\nvar_j = var_h / var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[var_k-1]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Seokjin'\nvar_c = 'Yoongi'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1.3\nvar_e = 11\nvar_f = 10\nvar_g = var_e / var_f\nvar_h = 7\nvar_i = 5\nvar_j = var_h / var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[var_k-1]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "4371": {
        "category": "Comparison",
        "question_ko": "효민과 진섭은 같은 수학 문제집을 각각 풀었다. 효민은 4/15를 완전히 풀었고 진섭은 6/15를 완전히 풀었다. 누가 수학 문제를 더 많이 풀었을까?",
        "question_en": "Both Hyomin and Jinseop solved the same math problem book. Hyomin completely solved 4/15, and Jinsub completely solved 6/15. Who has solved more math problems?",
        "answer_ko": "진섭",
        "answer_en": "Jinseop",
        "solution_abst_ko": "[OP_LIST_SOL] 효민 진섭 [OP_LIST_EOL] [OP_LIST_SOL] 4 15 [OP_DIV] 6 15 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Hyomin Jinseop [OP_LIST_EOL] [OP_LIST_SOL] 4 15 [OP_DIV] 6 15 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '효민'\nvar_b = '진섭'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 15\nvar_e = var_c / var_d\nvar_f = 6\nvar_g = 15\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Hyomin'\nvar_b = 'Jinseop'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 15\nvar_e = var_c / var_d\nvar_f = 6\nvar_g = 15\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "4372": {
        "category": "Correspondence",
        "question_ko": "봉건이가 어떤 수를 11로 나눈 결과에 156을 더했더니 178이 정답으로 나왔습니다. 어떤 수를 구하시오.",
        "question_en": "Beong-gun added 156 to the result of dividing a certain number by 11, and he got 178 as the correct answer. Find the number.",
        "answer_ko": "242",
        "answer_en": "242",
        "solution_abst_ko": "178 156 [OP_SUB] 11 [OP_MUL]",
        "solution_abst_en": "178 156 [OP_SUB] 11 [OP_MUL]",
        "solution_code_ko": "var_a = 178\nvar_b = 156\nvar_c = var_a - var_b\nvar_d = 11\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 178\nvar_b = 156\nvar_c = var_a - var_b\nvar_d = 11\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "4373": {
        "category": "Arithmetic calculation",
        "question_ko": "바둑돌이 120개가 있다. 흰 바둑돌이 검은 바둑돌보다 36개가 더 많았다면 흰 바둑돌은 몇 개인지 구하시오.",
        "question_en": "There are 120 go stones. If there are 36 more white go stones than black go stones, how many white go stones are there?",
        "answer_ko": "78",
        "answer_en": "78",
        "solution_abst_ko": "120 36 [OP_SUB] 2 [OP_DIV] 36 [OP_ADD]",
        "solution_abst_en": "120 36 [OP_SUB] 2 [OP_DIV] 36 [OP_ADD]",
        "solution_code_ko": "var_a = 120\nvar_b = 36\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 36\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 120\nvar_b = 36\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 36\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "4374": {
        "category": "Comparison",
        "question_ko": "스티커 25장은 정현이와 예진이가 나누어 가지려고 합니다. 정현이는 예진이가 가지는 스티커의 2배보다 1장 더 가지려고 할 때 정현이는 몇 장의 스티커를 가지게 되는지 구하시오.",
        "question_en": "The 25 stickers are going to be shared by Junghyeon and Yejin. Find how many stickers Junghyeon will have when Junghyeon wants to have 1 more sticker than twice Ye-jin's.",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "25 1 [OP_SUB] 2 1 [OP_ADD] [OP_DIV] 2 [OP_MUL] 1 [OP_ADD]",
        "solution_abst_en": "25 1 [OP_SUB] 2 1 [OP_ADD] [OP_DIV] 2 [OP_MUL] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 25\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = var_c / var_f\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = 1\nvar_k = var_i + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 25\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = var_c / var_f\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = 1\nvar_k = var_i + var_j\nprint(int(var_k))"
    },
    "4375": {
        "category": "Geometry",
        "question_ko": "높이가 8센티미터(㎝)이고, 모든 모서리의 길이의 합이 104센티미터(㎝)인 사각기둥 모양의 상자가 있습니다. 이 상자의 모든 옆면에 한 변의 길이가 4센티미터(㎝)인 정사각형 모양의 색종이를 겹치지 않게 빈틈없이 붙이려고 합니다. 색종이는 모두 몇 장 필요합니까?",
        "question_en": "You have a box in the shape of a square prism with a height of 8 centimeters (cm), and the sum of the lengths of all edges is 104 centimeters (cm). On all sides of this box, you are going to attach pieces of colored paper in a square shape with a side length of 4 centimeters (cm) without overlapping. How many sheets of colored paper do you need in all?\n",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "104 8 4 [OP_MUL] [OP_SUB] 4 2 [OP_MUL] [OP_DIV] 8 [OP_MUL] 4 [OP_MUL] 4 2 [OP_POW] [OP_DIV]",
        "solution_abst_en": "104 8 4 [OP_MUL] [OP_SUB] 4 2 [OP_MUL] [OP_DIV] 8 [OP_MUL] 4 [OP_MUL] 4 2 [OP_POW] [OP_DIV]",
        "solution_code_ko": "var_a = 104\nvar_b = 8\nvar_c = 4\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 4\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_e / var_h\nvar_j = 8\nvar_k = var_i * var_j\nvar_l = 4\nvar_m = var_k * var_l\nvar_n = 4\nvar_o = 2\nvar_p = var_n ** var_o\nvar_q = var_m / var_p\nprint(int(var_q))",
        "solution_code_en": "var_a = 104\nvar_b = 8\nvar_c = 4\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 4\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_e / var_h\nvar_j = 8\nvar_k = var_i * var_j\nvar_l = 4\nvar_m = var_k * var_l\nvar_n = 4\nvar_o = 2\nvar_p = var_n ** var_o\nvar_q = var_m / var_p\nprint(int(var_q))"
    },
    "4376": {
        "category": "Arithmetic calculation",
        "question_ko": "세 자리 자연수들의 합은 얼마인가?",
        "question_en": "What is the sum of the three-digit natural numbers?",
        "answer_ko": "494550",
        "answer_en": "494550",
        "solution_abst_ko": "100 999 1 [OP_LIST_ARANGE] [OP_LIST_SUM]",
        "solution_abst_en": "100 999 1 [OP_LIST_ARANGE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_a = [float(i) for i in list_a]\nvar_d = sum(list_a)\nprint(int(var_d))",
        "solution_code_en": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_a = [float(i) for i in list_a]\nvar_d = sum(list_a)\nprint(int(var_d))"
    },
    "4377": {
        "category": "Arithmetic calculation",
        "question_ko": "기차가 9/45분 동안 704킬로미터(㎞)를 달렸습니다. 이 기차의 빠르기가 일정하다면 12/10분 동안 달린 거리는 몇 킬로미터(㎞) 인지 구하시오.",
        "question_en": "The train covered 704 kilometers (km) in 9/45 minutes. If the speed of this train is constant, find how many kilometers (km) it traveled in 12/10 minutes.",
        "answer_ko": "4224",
        "answer_en": "4224",
        "solution_abst_ko": "704 9/45 [OP_DIV] 12/10 [OP_MUL]",
        "solution_abst_en": "704 9/45 [OP_DIV] 12/10 [OP_MUL]",
        "solution_code_ko": "var_a = 704\nvar_b = 0.2\nvar_c = var_a / var_b\nvar_d = 1.2\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 704\nvar_b = 0.2\nvar_c = var_a / var_b\nvar_d = 1.2\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "4378": {
        "category": "Arithmetic calculation",
        "question_ko": "새 페인트 통의 무게를 쟀더니 24킬로그램(㎏)였습니다. 절반의 페인트를 사용하고 나서 통의 무게를 다시 쟀더니 14킬로그램(㎏)입니다. 통의 무게를 제외한 새 페인트 통에 담겨 있던 페인트의 무게는 몇 킬로그램(㎏)입니까?",
        "question_en": "The new paint can was weighed 24 kilograms (kg). After using half the paint, I reweighed the can and it weighed 14 kilograms (kg). What is the weight in kilograms (kg) of the paint in the new can, excluding the weight of the can?\\",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "24 14 [OP_SUB] 2 [OP_MUL]",
        "solution_abst_en": "24 14 [OP_SUB] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 24\nvar_b = 14\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 24\nvar_b = 14\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "4379": {
        "category": "Comparison",
        "question_ko": "유나와 친구 6명이 한 줄로 서 있습니다. 유나의 앞에 2명이 서 있다면 유나의 뒤에는 몇 명이 서 있습니까?",
        "question_en": "Yuna and six of her friends are standing in a line. If there are 2 people standing in front of Yuna, how many people are standing behind Yuna?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "6 1 [OP_ADD] 2 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "6 1 [OP_ADD] 2 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 6\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 6\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "4380": {
        "category": "Comparison",
        "question_ko": "A, B, C, D 4개의 수가 있고 A는 27입니다. A는 B보다 7 작은 수 입니다. B는 C보다 9 큰 수입니다. D가 C의 2배라면 가장 큰 수는 무엇입니까?",
        "question_en": "There are 4 numbers A, B, C, D and A is 27. A is 7 less than B. B is 9 greater than C. If D is twice C, what is the largest number?",
        "answer_ko": "D",
        "answer_en": "D",
        "solution_abst_ko": "[OP_LIST_SOL] A B C D [OP_LIST_EOL] [OP_LIST_SOL] 27 27 7 [OP_ADD] 27 7 [OP_ADD] 9 [OP_SUB] 27 7 [OP_ADD] 9 [OP_SUB] 2 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D [OP_LIST_EOL] [OP_LIST_SOL] 27 27 7 [OP_ADD] 27 7 [OP_ADD] 9 [OP_SUB] 27 7 [OP_ADD] 9 [OP_SUB] 2 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 27\nvar_f = 27\nvar_g = 7\nvar_h = var_f + var_g\nvar_i = 27\nvar_j = 7\nvar_k = var_i + var_j\nvar_l = 9\nvar_m = var_k - var_l\nvar_n = 27\nvar_o = 7\nvar_p = var_n + var_o\nvar_q = 9\nvar_r = var_p - var_q\nvar_s = 2\nvar_t = var_r * var_s\nlist_b= []\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_b.append(var_t)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_u = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_v = list_c[-var_u]\nvar_w = list_b.index(var_v)+1\nvar_x = list_a[var_w-1]\nprint(var_x)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 27\nvar_f = 27\nvar_g = 7\nvar_h = var_f + var_g\nvar_i = 27\nvar_j = 7\nvar_k = var_i + var_j\nvar_l = 9\nvar_m = var_k - var_l\nvar_n = 27\nvar_o = 7\nvar_p = var_n + var_o\nvar_q = 9\nvar_r = var_p - var_q\nvar_s = 2\nvar_t = var_r * var_s\nlist_b= []\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_b.append(var_t)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_u = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_v = list_c[-var_u]\nvar_w = list_b.index(var_v)+1\nvar_x = list_a[var_w-1]\nprint(var_x)"
    },
    "4381": {
        "category": "Geometry",
        "question_ko": "정삼각형의 모든 변의 길이의 합이 18센티미터(㎝)일 때, 한 변의 길이는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "If the sum of the lengths of all the sides of an equilateral triangle is 18 centimeters (cm), find the length of one side of the equilateral triangle in centimeters (cm).",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "18 3 [OP_DIV]",
        "solution_abst_en": "18 3 [OP_DIV]",
        "solution_code_ko": "var_a = 18\nvar_b = 3\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 18\nvar_b = 3\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "4382": {
        "category": "Arithmetic calculation",
        "question_ko": "오늘의 날짜는 2021년 12월 27일이고, 현재 시각은 12:42분입니다. 오늘의 날짜와 시간을 입력하기 위해선 숫자 2 자판을 몇 번 눌러야 합니까?",
        "question_en": "Today's date is December 27, 2021, and the current time is 12:42. How many times do you have to press the number 2 key to enter today's date and time?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 2 0 2 1 1 2 2 7 1 2 4 2 [OP_LIST_EOL] 2 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "[OP_LIST_SOL] 2 0 2 1 1 2 2 7 1 2 4 2 [OP_LIST_EOL] 2 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 2\nvar_b = 0\nvar_c = 2\nvar_d = 1\nvar_e = 1\nvar_f = 2\nvar_g = 2\nvar_h = 7\nvar_i = 1\nvar_j = 2\nvar_k = 4\nvar_l = 2\nlist_a= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_a.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_a.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_a.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_m = 2\nvar_n = 0\nvar_m = int(var_m)\nfor i in list_a:\n    i = int(i)\n    if i == var_m:\n        var_n = var_n + 1\nprint(int(var_n))",
        "solution_code_en": "var_a = 2\nvar_b = 0\nvar_c = 2\nvar_d = 1\nvar_e = 1\nvar_f = 2\nvar_g = 2\nvar_h = 7\nvar_i = 1\nvar_j = 2\nvar_k = 4\nvar_l = 2\nlist_a= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_a.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_a.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_a.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_m = 2\nvar_n = 0\nvar_m = int(var_m)\nfor i in list_a:\n    i = int(i)\n    if i == var_m:\n        var_n = var_n + 1\nprint(int(var_n))"
    },
    "4383": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.3에서 0.4보다 작거나 같은 수 중 가장 크거나 같은 수는?",
        "question_en": "In 0.8, 1/2, 0.3 to less than or equal to 0.4 which is the largest or the same number?",
        "answer_ko": "0.30",
        "answer_en": "0.3",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.3 [OP_LIST_EOL] 0.4 [OP_LIST_LESS_EQUAL] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.3 [OP_LIST_EOL] 0.4 [OP_LIST_LESS_EQUAL] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.4\nlist_b = []\nfor i in list_a:\n    if i <= var_d:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint('{:.2f}'.format(round(var_f+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.4\nlist_b = []\nfor i in list_a:\n    if i <= var_d:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint('{:.2f}'.format(round(var_f+1e-10,2)))"
    },
    "4384": {
        "category": "Correspondence",
        "question_ko": "4와 어떤 수를 곱하고 23만큼 다시 빼면 33이 된다면 어떤 수는 얼마입니까?",
        "question_en": "If we multiply 4 by a number and subtract 23 again, what is a number if we get 33?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "33 23 [OP_ADD] 4 [OP_DIV]",
        "solution_abst_en": "33 23 [OP_ADD] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 33\nvar_b = 23\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 33\nvar_b = 23\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "4385": {
        "category": "Arithmetic calculation",
        "question_ko": "수영이네 가족이 오늘 마신 우유는 전체의 0.4입니다. 남은 우유가 0.69리터(L)라면 처음에 있던 우유는 몇 리터(L)입니까?",
        "question_en": "The milk that Suyeong's family drank today is 0.4 of the total amount. If the remaining milk is 0.69 liters (L), how many liters (L) of milk were there at the beginning?",
        "answer_ko": "1.15",
        "answer_en": "1.15",
        "solution_abst_ko": "0.69 1 0.4 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "0.69 1 0.4 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 0.69\nvar_b = 1\nvar_c = 0.4\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.69\nvar_b = 1\nvar_c = 0.4\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "4386": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 만두공장에서는 1달에 182.88킬로그램(㎏)의 만두를 만듭니다. 이 공장에서 1년 동안 만든 만두는 몇 킬로그램(㎏)인지 구하시오.",
        "question_en": "A dumpling factory makes 182.88 kilograms (kg) of dumplings per month. Find how many kilograms (kg) of dumplings are made in this factory in one year.",
        "answer_ko": "2194.56",
        "answer_en": "2194.56",
        "solution_abst_ko": "182.88 12 [OP_MUL]",
        "solution_abst_en": "182.88 12 [OP_MUL]",
        "solution_code_ko": "var_a = 182.88\nvar_b = 12\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 182.88\nvar_b = 12\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "4387": {
        "category": "Possibility",
        "question_ko": "가희는 숫자가 적힌 지우개 4개를 문구점에서 구입했다. 지우개에는 각각 0, 2, 4, 6이 적혀 있었는데, 세 개를 골라서 100보다 크고 1000보다 작은 수를 만든다고 할 때 만들 수 있는 숫자들의 총 합은 얼마인가?",
        "question_en": "Kahi bought 4 erasers with numbers on them from a stationery shop. Each eraser had 0, 2, 4, and 6 written on it. If she chooses three of them and makes numbers that are greater than 100 and less than 1000, what is the sum of the total numbers that she can make?",
        "answer_ko": "7728",
        "answer_en": "7728",
        "solution_abst_ko": "[OP_LIST_SOL] 0 2 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0 2 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0\nvar_b = 2\nvar_c = 4\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 0\nvar_b = 2\nvar_c = 4\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint(int(var_f))"
    },
    "4388": {
        "category": "Correspondence",
        "question_ko": "31+6A2=683이 성립합니다. A는 무엇인가요?",
        "question_en": "31+6A2=683 is true. What is A?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "31+6A2=683 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "31+6A2=683 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '31+6A2=683'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '31+6A2=683'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "4389": {
        "category": "Arithmetic calculation",
        "question_ko": "민주와 상현이가 퀴즈에서 맞힌 문제의 수는 43문제이고, 민주가 상현이보다 5문제를 더 맞췄습니다. 상현이가 맞힌 퀴즈는 몇 문제입니까?",
        "question_en": "The number of questions that Min-joo and Sang-hyeon got right in the quiz was 43, and Min-joo got 5 more questions than Sang-hyeon. How many quiz questions did Sanghyun get right?",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "43 5 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "43 5 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 43\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 43\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "4390": {
        "category": "Possibility",
        "question_ko": "1, 7, 0, 3, 5, 6 중에서 4개를 뽑아 한 번씩만 사용하여 네 자리 수를 만들려고 합니다. 만들 수 있는 두 번째로 작은 수와 첫 번째로 작은 수의 차를 구하시오.",
        "question_en": "You want to create a four-digit number by drawing four out of 1, 7, 0, 3, 5, and 6 and using them only once. Find the difference between the second smallest number and the first smallest number that can be made.",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 1 7 0 3 5 6 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 2 [OP_LIST_MIN] 1 [OP_LIST_MIN] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "[OP_LIST_SOL] 1 7 0 3 5 6 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 2 [OP_LIST_MIN] 1 [OP_LIST_MIN] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 1\nvar_b = 7\nvar_c = 0\nvar_d = 3\nvar_e = 5\nvar_f = 6\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_k = list_d[var_j-1]\nvar_l = var_i - var_k\nvar_m = abs(var_l)\nprint(int(var_m))",
        "solution_code_en": "var_a = 1\nvar_b = 7\nvar_c = 0\nvar_d = 3\nvar_e = 5\nvar_f = 6\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_k = list_d[var_j-1]\nvar_l = var_i - var_k\nvar_m = abs(var_l)\nprint(int(var_m))"
    },
    "4391": {
        "category": "Possibility",
        "question_ko": "학생들 3명과 선생님 2명이 줄을 서서 가고 있다. 학생들은 반드시 서로 이웃하여 가는 경우의 수를 구하시오.",
        "question_en": "Three students and two teachers are standing in line. Find the number of cases if students must go next to each other.",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "2 1 [OP_ADD] 2 1 [OP_ADD] [OP_PERM] 3 3 [OP_PERM] [OP_MUL]",
        "solution_abst_en": "2 1 [OP_ADD] 2 1 [OP_ADD] [OP_PERM] 3 3 [OP_PERM] [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = 1\nvar_c = int(var_c)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_c-i)\nvar_h = 3\nvar_i = 3\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nvar_k = var_g * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 2\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = 1\nvar_c = int(var_c)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_c-i)\nvar_h = 3\nvar_i = 3\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nvar_k = var_g * var_j\nprint(int(var_k))"
    },
    "4392": {
        "category": "Possibility",
        "question_ko": "숫자 카드 0, 1, 7, 9 중 2장을 뽑아 만들 수 있는 두 자리의 자연수의 개수를 구하시오.",
        "question_en": "Find the number of two-digit natural numbers that can be made by drawing two of the number cards 0, 1, 7, and 9.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 7 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 7 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 7\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 7\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "4393": {
        "category": "Correspondence",
        "question_ko": "어떤 수는 24보다 크지만 28보다는 작습니다. 20, 23, 26, 29 중 어떤 수를 구하시오.",
        "question_en": "A number is greater than 24 but less than 28. Find out which number it is among 20, 23, 26, and 29.",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "[OP_LIST_SOL] 20 23 26 29 [OP_LIST_EOL] 24 [OP_LIST_MORE] 28 [OP_LIST_LESS] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] 20 23 26 29 [OP_LIST_EOL] 24 [OP_LIST_MORE] 28 [OP_LIST_LESS] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 20\nvar_b = 23\nvar_c = 26\nvar_d = 29\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 24\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nvar_f = 28\nlist_c = []\nfor i in list_b:\n    if i < var_f:\n        list_c.append(i)\nvar_g = 1\nvar_h = list_c[var_g-1]\nprint(int(var_h))",
        "solution_code_en": "var_a = 20\nvar_b = 23\nvar_c = 26\nvar_d = 29\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 24\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nvar_f = 28\nlist_c = []\nfor i in list_b:\n    if i < var_f:\n        list_c.append(i)\nvar_g = 1\nvar_h = list_c[var_g-1]\nprint(int(var_h))"
    },
    "4394": {
        "category": "Comparison",
        "question_ko": "윤기는 4, 유나는 5, 정국에는 6에서 3을 뺀 수를 모았습니다. 누가 가장 작은 수를 가지고 있나요?",
        "question_en": "Yoongi collected 4 points, Yuna collected 5 points, and Jungkook collected 6 minus 3 points. Who has the smallest number?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 유나 정국 [OP_LIST_EOL] [OP_LIST_SOL] 4 5 6 3 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Yuna Jungkook [OP_LIST_EOL] [OP_LIST_SOL] 4 5 6 3 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '유나'\nvar_c = '정국'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 5\nvar_f = 6\nvar_g = 3\nvar_h = var_f - var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Yuna'\nvar_c = 'Jungkook'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 5\nvar_f = 6\nvar_g = 3\nvar_h = var_f - var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "4395": {
        "category": "Comparison",
        "question_ko": "윤기는 4, 정국이는 6에서 3을 곱한 수를 모았습니다. 누구의 수가 더 작나요?",
        "question_en": "Yoongi collected 4 points, and Jungkook collected 6 multiplied by 3 points. Whose number is smaller?",
        "answer_ko": "윤기",
        "answer_en": "Yoongi",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 6\nvar_e = 3\nvar_f = var_d * var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 6\nvar_e = 3\nvar_f = var_d * var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "4396": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 5와 6으로 나누면 나누어떨어지고 7로 나누면 나머지가 6이라고 합니다. 어떤 수 중에서 가장 작은 두 자리 수를 구하시오.",
        "question_en": "When a number is divided by 5 and 6, it is divisible, and when divided by 7, the remainder is 6. Find the smallest two-digit number in any number.",
        "answer_ko": "90",
        "answer_en": "90",
        "solution_abst_ko": "10 99 1 [OP_LIST_ARANGE] 5 6 [OP_LCM] [OP_LIST_DIVISIBLE] 7 6 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MIN]",
        "solution_abst_en": "10 99 1 [OP_LIST_ARANGE] 5 6 [OP_LCM] [OP_LIST_DIVISIBLE] 7 6 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nvar_e = 6\nvar_f = var_e * var_d / math.gcd(int(var_e), int(var_d))\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nvar_g = 7\nvar_h = 6\nlist_c = [] \nvar_g = int(var_g)\nvar_h = int(var_h)\nif var_h < 0:\n    var_h = var_h + var_g\nfor i in list_b:\n    i = int(i)\n    if i%var_g == var_h:\n        list_c.append(i)\nvar_i = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nprint(int(var_j))",
        "solution_code_en": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nvar_e = 6\nvar_f = var_e * var_d / math.gcd(int(var_e), int(var_d))\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nvar_g = 7\nvar_h = 6\nlist_c = [] \nvar_g = int(var_g)\nvar_h = int(var_h)\nif var_h < 0:\n    var_h = var_h + var_g\nfor i in list_b:\n    i = int(i)\n    if i%var_g == var_h:\n        list_c.append(i)\nvar_i = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nprint(int(var_j))"
    },
    "4397": {
        "category": "Comparison",
        "question_ko": "토끼와 오리가 정원에서 뛰어놀고 있습니다. 모든 동물의 다리 수의 합은 48개이고, 토끼가 9마리 있다고 할 때 오리는 몇 마리가 있습니까?",
        "question_en": "Rabbits and ducks are playing in the garden. If the sum of the legs of all animals is 48 and there are 9 rabbits, how many ducks are there?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "48 4 9 [OP_MUL] [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "48 4 9 [OP_MUL] [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 48\nvar_b = 4\nvar_c = 9\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 48\nvar_b = 4\nvar_c = 9\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "4398": {
        "category": "Correspondence",
        "question_ko": "A는 한 자리 숫자입니다. A567을 십의 자리에서 버림하여 2560을 얻었습니다. A를 구하시오.",
        "question_en": "A is a single digit number. If A567 is rounded down in the tens place to get 2560, What is A?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "A567 [OP_GEN_POSSIBLE_LIST] 2560 [OP_LIST_MORE_EQUAL] 2560 10 [OP_ADD] [OP_LIST_LESS] A567 A [OP_LIST_FIND_UNK]",
        "solution_abst_en": "A567 [OP_GEN_POSSIBLE_LIST] 2560 [OP_LIST_MORE_EQUAL] 2560 10 [OP_ADD] [OP_LIST_LESS] A567 A [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = 'A567'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 2560\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 2560\nvar_d = 10\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = 'A567'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))",
        "solution_code_en": "var_a = 'A567'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 2560\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 2560\nvar_d = 10\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = 'A567'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))"
    },
    "4399": {
        "category": "Arithmetic calculation",
        "question_ko": "24의 약수의 개수는 몇 개입니까?",
        "question_en": "How many divisors of 24 are there?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "24 [OP_LIST_GET_DIVISOR] [OP_LIST_LEN]",
        "solution_abst_en": "24 [OP_LIST_GET_DIVISOR] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 24\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = len(list_a)\nprint(int(var_b))",
        "solution_code_en": "var_a = 24\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = len(list_a)\nprint(int(var_b))"
    },
    "4400": {
        "category": "Possibility",
        "question_ko": "주어진 숫자를 한 번씩 사용하여 가장 큰 수를 만들고자 합니다. 숫자 1, 4, 5가 있을 때, 어떤 수를 만들어야 합니까?",
        "question_en": "We want to create the largest number by using a given number once. Given the numbers 1, 4, and 5, what number should we make?",
        "answer_ko": "541",
        "answer_en": "541",
        "solution_abst_ko": "[OP_LIST_SOL] 1 4 5 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1 4 5 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1\nvar_b = 4\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 4\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))"
    },
    "4401": {
        "category": "Comparison",
        "question_ko": "어떤 두 수의 최소공배수가 21입니다. 이 두 수의 공배수를 작은 수부터 차례대로 썼습니다. 왼쪽에서 8번째 수와 12번째 수 사이에 있는 수들의 합은 얼마입니까?",
        "question_en": "The least common multiple of any two numbers is 21. Write the common multiples of these two numbers in order, starting with the smallest number. What is the sum of the numbers between the 8th and the 12th from the left?",
        "answer_ko": "630",
        "answer_en": "630",
        "solution_abst_ko": "21 8 1 [OP_ADD] [OP_MUL] 21 12 -1 [OP_ADD] [OP_MUL] 21 [OP_LIST_ARANGE] [OP_LIST_SUM]",
        "solution_abst_en": "21 8 1 [OP_ADD] [OP_MUL] 21 12 -1 [OP_ADD] [OP_MUL] 21 [OP_LIST_ARANGE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 21\nvar_b = 8\nvar_c = 1\nvar_d = var_b + var_c\nvar_e = var_a * var_d\nvar_f = 21\nvar_g = 12\nvar_h = -1\nvar_i = var_g + var_h\nvar_j = var_f * var_i\nvar_k = 21\nlist_a = [i for i in range(var_e, var_j + 1, var_k)]\nlist_a = [float(i) for i in list_a]\nvar_l = sum(list_a)\nprint(int(var_l))",
        "solution_code_en": "var_a = 21\nvar_b = 8\nvar_c = 1\nvar_d = var_b + var_c\nvar_e = var_a * var_d\nvar_f = 21\nvar_g = 12\nvar_h = -1\nvar_i = var_g + var_h\nvar_j = var_f * var_i\nvar_k = 21\nlist_a = [i for i in range(var_e, var_j + 1, var_k)]\nlist_a = [float(i) for i in list_a]\nvar_l = sum(list_a)\nprint(int(var_l))"
    },
    "4402": {
        "category": "Arithmetic calculation",
        "question_ko": "우유를 1/6만큼 따르고, 남은 우유의 2/5를 따르고, 다시 남은 우유의 2/3을 따랐더니 120밀리리터(㎖)가 남았다면 처음에 있던 우유는 몇 밀리리터(㎖)입니까?",
        "question_en": "If you pour 1/6 of the milk, pour the remaining 2/5 of the milk, and then pour the remaining 2/3 of the milk, you have 120 milliliters (mL) left, how many milliliters (mL) of the original milk were there?",
        "answer_ko": "720",
        "answer_en": "720",
        "solution_abst_ko": "120 1 1/6 [OP_SUB] [OP_DIV] 1 2/5 [OP_SUB] [OP_DIV] 1 2/3 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "120 1 1/6 [OP_SUB] [OP_DIV] 1 2/5 [OP_SUB] [OP_DIV] 1 2/3 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 120\nvar_b = 1\nvar_c = 0.16666666666666666\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 1\nvar_g = 0.4\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 1\nvar_k = 0.6666666666666666\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nprint(int(eval('{:.2f}'.format(round(var_m+1e-10,2)))))",
        "solution_code_en": "var_a = 120\nvar_b = 1\nvar_c = 0.16666666666666666\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 1\nvar_g = 0.4\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 1\nvar_k = 0.6666666666666666\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nprint(int(eval('{:.2f}'.format(round(var_m+1e-10,2)))))"
    },
    "4403": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 14센티미터(㎝)인 정사각형 모양의 종이가 있습니다. 이 종이로 가로가 8센티미터(㎝), 세로가 2센티미터(㎝)인 직사각형 모양의 종이 조각을 최대 몇 개나 오려낼 수 있습니까?",
        "question_en": "You have a square piece of paper with a side of 14 centimeters (cm). How many rectangular pieces of paper that are 8 centimeters (cm) long and 2 centimeters (cm) wide can be cut out of this piece of paper?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "14 2 [OP_POW] 8 2 [OP_MUL] [OP_FDIV]",
        "solution_abst_en": "14 2 [OP_POW] 8 2 [OP_MUL] [OP_FDIV]",
        "solution_code_ko": "var_a = 14\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 8\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c // var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 14\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 8\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c // var_f\nprint(int(var_g))"
    },
    "4404": {
        "category": "Arithmetic calculation",
        "question_ko": "두 선수가 함께 팀을 이뤄 대회에 참가했다. 가가 선수는 보트를 타고 강을 건너야 하고, 나나 선수는 자전거를 타고 터널을 지나가야 한다. 보트는 시속 3킬로미터(㎞)로 움직이고, 자전거는 시속 4킬로미터(㎞)로 탈 수 있다. 터널이 강 보다 2킬로미터(㎞) 더 길었고 두 선수가 걸린 시간의 합이 4시간일 때, 가가 선수가 강을 건넌 시간은?",
        "question_en": "The two players teamed up to participate in the competition. Gaga has to cross the river on a boat, and Nana has to ride a bicycle through a tunnel. Boats move at 3 kilometers (km) per hour, and bicycles move at 4 kilometers (km) per hour. If the tunnel is 2 kilometers (km) longer than the river, and the total time of two players is 4 hours, how long does Gaga cross the river?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "4 2 4 [OP_DIV] [OP_SUB] 1 3 [OP_DIV] 1 4 [OP_DIV] [OP_ADD] [OP_DIV] 3 [OP_DIV]",
        "solution_abst_en": "4 2 4 [OP_DIV] [OP_SUB] 1 3 [OP_DIV] 1 4 [OP_DIV] [OP_ADD] [OP_DIV] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = 3\nvar_h = var_f / var_g\nvar_i = 1\nvar_j = 4\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_e / var_l\nvar_n = 3\nvar_o = var_m / var_n\nprint(int(eval('{:.2f}'.format(round(var_o+1e-10,2)))))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = 3\nvar_h = var_f / var_g\nvar_i = 1\nvar_j = 4\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_e / var_l\nvar_n = 3\nvar_o = var_m / var_n\nprint(int(eval('{:.2f}'.format(round(var_o+1e-10,2)))))"
    },
    "4405": {
        "category": "Geometry",
        "question_ko": "호석이는 가지고 있는 철사로 한 변의 길이가 19센티미터(㎝)인 정삼각형 1개를 만들었더니 철사가 15센티미터(㎝) 남았습니다. 호석이가 처음에 가지고 있던 철사의 길이는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "Hoseok made an equilateral triangle with a side length of 19 centimeters (cm) with the wire he had, and there was 15 centimeters (cm) of wire left. Find the length in centimeters (cm) of the wire that Hoseok had at first.",
        "answer_ko": "72",
        "answer_en": "72",
        "solution_abst_ko": "19 3 [OP_MUL] 15 [OP_ADD]",
        "solution_abst_en": "19 3 [OP_MUL] 15 [OP_ADD]",
        "solution_code_ko": "var_a = 19\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 15\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 19\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 15\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "4406": {
        "category": "Geometry",
        "question_ko": "가로가 34센티미터(㎝)인 직사각형 모양의 종이를 한 변이 4센티미터(㎝)인 정사각형 모양으로 잘랐더니 가로는 2센티미터(㎝)가 남고 정사각형은 모두 24개가 되었습니다. 자르기 전 직사각형의 둘레는 최소 몇 센티미터(㎝)입니까?",
        "question_en": "If you cut a rectangular piece of paper 34 centimeters (cm) wide into squares with a side of 4 centimeters (cm), there are 2 centimeters (cm) are left over and there are 24 squares in total. What is the minimum perimeter of the rectangle in centimeters (cm) before cutting?",
        "answer_ko": "92",
        "answer_en": "92",
        "solution_abst_ko": "24 34 4 [OP_FDIV] [OP_DIV] 4 [OP_MUL] 34 [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "24 34 4 [OP_FDIV] [OP_DIV] 4 [OP_MUL] 34 [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 24\nvar_b = 34\nvar_c = 4\nvar_d = var_b // var_c\nvar_e = var_a / var_d\nvar_f = 4\nvar_g = var_e * var_f\nvar_h = 34\nvar_i = var_g + var_h\nvar_j = 2\nvar_k = var_i * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 24\nvar_b = 34\nvar_c = 4\nvar_d = var_b // var_c\nvar_e = var_a / var_d\nvar_f = 4\nvar_g = var_e * var_f\nvar_h = 34\nvar_i = var_g + var_h\nvar_j = 2\nvar_k = var_i * var_j\nprint(int(var_k))"
    },
    "4407": {
        "category": "Correspondence",
        "question_ko": "0.46 에 어떤 수를 두 번 곱했더니 0.72 가 되었습니다. 어떤 수는 얼마입니까?",
        "question_en": "When you multiply 0.46 by a certain number twice, you get 0.72. What number is that?",
        "answer_ko": "3.40",
        "answer_en": "3.4",
        "solution_abst_ko": "0.72 0.46 [OP_DIV] 0.46 [OP_DIV]",
        "solution_abst_en": "0.72 0.46 [OP_DIV] 0.46 [OP_DIV]",
        "solution_code_ko": "var_a = 0.72\nvar_b = 0.46\nvar_c = var_a / var_b\nvar_d = 0.46\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.72\nvar_b = 0.46\nvar_c = var_a / var_b\nvar_d = 0.46\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "4408": {
        "category": "Arithmetic calculation",
        "question_ko": "5일동안 볼펜 15묶음을 팔았다. 각 묶음에 볼펜이 40개 있다면, 평균 몇 개를 팔았나요?",
        "question_en": "You sold 15 bundles of ballpoint pens in 5 days. If there are 40 ballpoint pens in each bundle, how many did you sell on average?",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "15 40 [OP_MUL] 5 [OP_FDIV]",
        "solution_abst_en": "15 40 [OP_MUL] 5 [OP_FDIV]",
        "solution_code_ko": "var_a = 15\nvar_b = 40\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 40\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "4409": {
        "category": "Comparison",
        "question_ko": "각각 1.7, 1/5, 1/5, 1, 3/5, 3/8, 1.4가 적힌 일곱 장의 숫자 카드가 있습니다. 이 카드들을 숫자의 크기가 큰 카드부터 차례로 배열할 때 네 번째에 놓이는 카드에는 어떤 숫자가 쓰여있겠습니까?",
        "question_en": "There are seven number cards with the numbers 1.7, 1/5, 1/5, 1, 3/5, 3/8, and 1.4 respectively. If you arrange these cards in order from the card with the largest number, what number will be written on the fourth card?",
        "answer_ko": "0.60",
        "answer_en": "0.6",
        "solution_abst_ko": "[OP_LIST_SOL] 1.7 1/5 1/5 1 3 5 [OP_DIV] 3 8 [OP_DIV] 1.4 [OP_LIST_EOL] 4 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1.7 1/5 1/5 1 3 5 [OP_DIV] 3 8 [OP_DIV] 1.4 [OP_LIST_EOL] 4 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1.7\nvar_b = 0.2\nvar_c = 0.2\nvar_d = 1\nvar_e = 3\nvar_f = 5\nvar_g = var_e / var_f\nvar_h = 3\nvar_i = 8\nvar_j = var_h / var_i\nvar_k = 1.4\nlist_a= []\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_a.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_a.append(var_j)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_l = 4\nlist_b=list_a.copy()\nlist_b.sort()\nvar_m = list_b[-var_l]\nprint('{:.2f}'.format(round(var_m+1e-10,2)))",
        "solution_code_en": "var_a = 1.7\nvar_b = 0.2\nvar_c = 0.2\nvar_d = 1\nvar_e = 3\nvar_f = 5\nvar_g = var_e / var_f\nvar_h = 3\nvar_i = 8\nvar_j = var_h / var_i\nvar_k = 1.4\nlist_a= []\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_a.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_a.append(var_j)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_l = 4\nlist_b=list_a.copy()\nlist_b.sort()\nvar_m = list_b[-var_l]\nprint('{:.2f}'.format(round(var_m+1e-10,2)))"
    },
    "4410": {
        "category": "Arithmetic calculation",
        "question_ko": "예지네 학교 5학년 학생 252명과 선생님 8명이 현장 학습을 가려고 합니다. 41인승 버스 한 대를 빌리는 값은 300000원이고 버스 1대당 고속도로 통행료는 7500원이라고 할 때 버스를 빌리고, 통행료를 내는 데 모두 얼마가 필요합니까?",
        "question_en": "252 fifth-grade students and 8 teachers at Yeji's school are going on a field trip. If the cost of renting a 41-seater bus is 300,000 won and the highway toll per bus is 7,500 won, how much does it cost to rent the bus and pay the toll?",
        "answer_ko": "2152500",
        "answer_en": "2152500",
        "solution_abst_ko": "252 8 [OP_ADD] 41 [OP_DIV] 1 [OP_CEIL] 300000 7500 [OP_ADD] [OP_MUL]",
        "solution_abst_en": "252 8 [OP_ADD] 41 [OP_DIV] 1 [OP_CEIL] 300000 7500 [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 252\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 41\nvar_e = var_c / var_d\nvar_f = 1\nvar_g=int(((var_e+9*10**(var_f-2))//(10**(var_f-1)))*10**(var_f-1))\n\nvar_h = 300000\nvar_i = 7500\nvar_j = var_h + var_i\nvar_k = var_g * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 252\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 41\nvar_e = var_c / var_d\nvar_f = 1\nvar_g=int(((var_e+9*10**(var_f-2))//(10**(var_f-1)))*10**(var_f-1))\n\nvar_h = 300000\nvar_i = 7500\nvar_j = var_h + var_i\nvar_k = var_g * var_j\nprint(int(var_k))"
    },
    "4411": {
        "category": "Comparison",
        "question_ko": "1/4, 0.7, 2/3, 0.4, 2/5 중 0.5보다 작은 수 중 가장 큰 수는 무엇입니까?",
        "question_en": "What is the largest number less than 0.5 among 1/4, 0.7, 2/3, 0.4, and 2/5?",
        "answer_ko": "0.40",
        "answer_en": "0.4",
        "solution_abst_ko": "[OP_LIST_SOL] 1/4 0.7 2/3 0.4 2/5 [OP_LIST_EOL] 0.5 [OP_LIST_LESS] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1/4 0.7 2/3 0.4 2/5 [OP_LIST_EOL] 0.5 [OP_LIST_LESS] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 0.25\nvar_b = 0.7\nvar_c = 0.6666666666666666\nvar_d = 0.4\nvar_e = 0.4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 0.5\nlist_b = []\nfor i in list_a:\n    if i < var_f:\n        list_b.append(i)\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nprint('{:.2f}'.format(round(var_h+1e-10,2)))",
        "solution_code_en": "var_a = 0.25\nvar_b = 0.7\nvar_c = 0.6666666666666666\nvar_d = 0.4\nvar_e = 0.4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 0.5\nlist_b = []\nfor i in list_a:\n    if i < var_f:\n        list_b.append(i)\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nprint('{:.2f}'.format(round(var_h+1e-10,2)))"
    },
    "4412": {
        "category": "Geometry",
        "question_ko": "가로, 세로, 높이가 1센티미터(㎝)인 주사위를 가로로 7줄, 세로로 5줄, 높이를 3층으로 쌓아 올렸다면 쌓인 주사위들의 전체 부피는 얼마입니까?",
        "question_en": "What is the total volume of the stacked dice if they are stacked 7 horizontally, 5 vertically, and 3 layers high, each measuring 1 centimeters (cm) in width, length, and height?",
        "answer_ko": "105",
        "answer_en": "105",
        "solution_abst_ko": "1 7 [OP_MUL] 1 5 [OP_MUL] [OP_MUL] 1 3 [OP_MUL] [OP_MUL]",
        "solution_abst_en": "1 7 [OP_MUL] 1 5 [OP_MUL] [OP_MUL] 1 3 [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 1\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = var_c * var_f\nvar_h = 1\nvar_i = 3\nvar_j = var_h * var_i\nvar_k = var_g * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 1\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = var_c * var_f\nvar_h = 1\nvar_i = 3\nvar_j = var_h * var_i\nvar_k = var_g * var_j\nprint(int(var_k))"
    },
    "4413": {
        "category": "Geometry",
        "question_ko": "한 모서리의 길이가 12㎝인 정육면체가 있습니다. 각 모서리의 중간에서 한 모서리의 길이가 4㎝인 정육면체를 잘랐을 때, 남은 부분의 겉넓이는 몇 제곱센티미터입니까?",
        "question_en": "There is a cube with a edge length of 12 centimeters (cm). If you cut a cube from the middle of each edge with one edge being 4 centimeters (cm) long, what square centimeter (cm2) is the surface area of the remaining part?",
        "answer_ko": "1248",
        "answer_en": "1248",
        "solution_abst_ko": "12 12 [OP_MUL] 6 [OP_MUL] 4 4 [OP_MUL] 2 [OP_MUL] 12 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "12 12 [OP_MUL] 6 [OP_MUL] 4 4 [OP_MUL] 2 [OP_MUL] 12 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 12\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = 4\nvar_h = var_f * var_g\nvar_i = 2\nvar_j = var_h * var_i\nvar_k = 12\nvar_l = var_j * var_k\nvar_m = var_e + var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 12\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = 4\nvar_h = var_f * var_g\nvar_i = 2\nvar_j = var_h * var_i\nvar_k = 12\nvar_l = var_j * var_k\nvar_m = var_e + var_l\nprint(int(var_m))"
    },
    "4414": {
        "category": "Possibility",
        "question_ko": "여섯 장의 숫자 카드 8, 3, 6, 5, 0, 7 중 두 장을 뽑아 만든 두 자리 수 중에서 가장 큰 수를 A, 가장 작은 수를 B라고 할 때, (A-B)×6의 값을 구하시오.",
        "question_en": "Among the six number cards 8, 3, 6, 5, 0, and 7, A is the largest two-digit number, and B is the smallest two-digit number. Find the value of (A-B)×6.",
        "answer_ko": "342",
        "answer_en": "342",
        "solution_abst_ko": "[OP_LIST_SOL] 8 3 6 5 0 7 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB] 6 [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 8 3 6 5 0 7 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 3\nvar_c = 6\nvar_d = 5\nvar_e = 0\nvar_f = 7\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_i = list_c[-var_h]\nvar_j = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_k = list_d[var_j-1]\nvar_l = var_i - var_k\nvar_m = 6\nvar_n = var_l * var_m\nprint(int(var_n))",
        "solution_code_en": "var_a = 8\nvar_b = 3\nvar_c = 6\nvar_d = 5\nvar_e = 0\nvar_f = 7\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_i = list_c[-var_h]\nvar_j = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_k = list_d[var_j-1]\nvar_l = var_i - var_k\nvar_m = 6\nvar_n = var_l * var_m\nprint(int(var_n))"
    },
    "4415": {
        "category": "Possibility",
        "question_ko": "사과, 복숭아, 배, 참외가 각각 1개씩 있는 바구니에서 뺄 기회는 2번입니다. 나올 수 있는 과일의 순서는 모두 몇 가지입니까?",
        "question_en": "You have 2 chances to draw from a basket containing 1 apple, 1 peach, 1 pear, and 1 melon. How many orders of fruit can exist while you draw from the basket?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 복숭아 배 참외 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] apple peach pear melon [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '복숭아'\nvar_c = '배'\nvar_d = '참외'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nprint(int(var_g))",
        "solution_code_en": "var_a = 'apple'\nvar_b = 'peach'\nvar_c = 'pear'\nvar_d = 'melon'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nprint(int(var_g))"
    },
    "4416": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 1/100배 해야 할 것을 잘못하여 10배 하였더니 2804가 되었습니다. 바르게 계산하면 얼마입니까?",
        "question_en": "You made a mistake and  multiplied a certain number by 10 when you should have multiplied it by 1/100, and got 2804. How much is it when you calculate correctly?",
        "answer_ko": "2.80",
        "answer_en": "2.8",
        "solution_abst_ko": "2804 10 [OP_DIV] 1/100 [OP_MUL]",
        "solution_abst_en": "2804 10 [OP_DIV] 1/100 [OP_MUL]",
        "solution_code_ko": "var_a = 2804\nvar_b = 10\nvar_c = var_a / var_b\nvar_d = 0.01\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 2804\nvar_b = 10\nvar_c = var_a / var_b\nvar_d = 0.01\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "4417": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 32를 더해야 하는데 잘못해서 23을 더했더니 68이 되었습니다. 어떤 수를 구하시오.",
        "question_en": "I need to add 32 to a number, but I mistakenly added 23, and I got 68. Find out this number",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "68 23 [OP_SUB]",
        "solution_abst_en": "68 23 [OP_SUB]",
        "solution_code_ko": "var_a = 68\nvar_b = 23\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 68\nvar_b = 23\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "4418": {
        "category": "Comparison",
        "question_ko": "1.4, 9/10, 1.2, 0.5, 13/10 중에서 1.1보다 작은 수를 고르면 몇 개인지 구하시오.",
        "question_en": "Find how many numbers are less than 1.1 among 1.4, 9/10, 1.2, 0.5, and 13/10.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i < var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i < var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "4419": {
        "category": "Correspondence",
        "question_ko": "A는 1000개, 100개, 10개씩 묶음이 각각 1개, 16개, 28개인 수입니다. B는 245씩 커지게 3번 뛰었는데, 처음 수는 355였습니다. A-B의 값을 구하시오.",
        "question_en": "A is a number that consists of 1, 16, and 28 times of 1000, 100, and 10, respectively. B jumps 3 times in increments of 245, the starting point being 355. Find the value of A-B.",
        "answer_ko": "1790",
        "answer_en": "1790",
        "solution_abst_ko": "1000 1 [OP_MUL] 100 16 [OP_MUL] [OP_ADD] 10 28 [OP_MUL] [OP_ADD] 355 245 3 [OP_MUL] [OP_ADD] [OP_SUB]",
        "solution_abst_en": "1000 1 [OP_MUL] 100 16 [OP_MUL] [OP_ADD] 10 28 [OP_MUL] [OP_ADD] 355 245 3 [OP_MUL] [OP_ADD] [OP_SUB]",
        "solution_code_ko": "var_a = 1000\nvar_b = 1\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = 16\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 10\nvar_i = 28\nvar_j = var_h * var_i\nvar_k = var_g + var_j\nvar_l = 355\nvar_m = 245\nvar_n = 3\nvar_o = var_m * var_n\nvar_p = var_l + var_o\nvar_q = var_k - var_p\nprint(int(var_q))",
        "solution_code_en": "var_a = 1000\nvar_b = 1\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = 16\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 10\nvar_i = 28\nvar_j = var_h * var_i\nvar_k = var_g + var_j\nvar_l = 355\nvar_m = 245\nvar_n = 3\nvar_o = var_m * var_n\nvar_p = var_l + var_o\nvar_q = var_k - var_p\nprint(int(var_q))"
    },
    "4420": {
        "category": "Possibility",
        "question_ko": "4, 2, 8, 1, 9 수 카드를 한 번씩만 사용하여 몫이 가장 큰 (세 자리 수)/(두 자리 수)를 만들었을 때의 나머지를 구하세요.",
        "question_en": "Find the remainder when the number cards 4, 2, 8, 1, 9 are used only once to get the greatest quotient from the expression (three-digit number)/(two-digit number).",
        "answer_ko": "0",
        "answer_en": "0",
        "solution_abst_ko": "[OP_LIST_SOL] 4 2 8 1 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] [OP_LIST_POP] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] [OP_MOD]",
        "solution_abst_en": "[OP_LIST_SOL] 4 2 8 1 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] [OP_LIST_POP] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] [OP_MOD]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = 8\nvar_d = 1\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 2\nlist_d = [str(i) for i in list_a]\nlist_d = list(itertools.permutations(list_d, var_i))\nlist_d = [''.join(num_list) for num_list in list_d]\nlist_d = [str_num for str_num in list_d if str_num[0] != '0']\nlist_d = [float(i) for i in list_d]\nvar_j = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_k = list_e[var_j-1]\nvar_l = var_h % var_k\nprint(int(var_l))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = 8\nvar_d = 1\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 2\nlist_d = [str(i) for i in list_a]\nlist_d = list(itertools.permutations(list_d, var_i))\nlist_d = [''.join(num_list) for num_list in list_d]\nlist_d = [str_num for str_num in list_d if str_num[0] != '0']\nlist_d = [float(i) for i in list_d]\nvar_j = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_k = list_e[var_j-1]\nvar_l = var_h % var_k\nprint(int(var_l))"
    },
    "4421": {
        "category": "Correspondence",
        "question_ko": "커피에 각설탕을 7개를 넣었더니 커피에 들어간 설탕의 양이 9.8그램(g)이다. 각설탕 하나에 몇 그램(g)인지 구하시오.",
        "question_en": "If you put 7 sugar cubes in the coffee, the amount of sugar in the coffee is 9.8 grams (g). Find how many grams (g) are in one sugar cube.",
        "answer_ko": "1.40",
        "answer_en": "1.4",
        "solution_abst_ko": "9.8 7 [OP_DIV]",
        "solution_abst_en": "9.8 7 [OP_DIV]",
        "solution_code_ko": "var_a = 9.8\nvar_b = 7\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 9.8\nvar_b = 7\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "4422": {
        "category": "Geometry",
        "question_ko": "모서리의 수와 꼭짓점의 수의 합이 40인 각기둥이 있다. 이 각기둥의 면은 모두 몇 개인가?",
        "question_en": "There is a prism whose sum of the number of edges and the number of vertices is 40. How many faces does this prism have?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "40 2 3 [OP_ADD] [OP_DIV] 2 [OP_ADD]",
        "solution_abst_en": "40 2 3 [OP_ADD] [OP_DIV] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 40\nvar_b = 2\nvar_c = 3\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 40\nvar_b = 2\nvar_c = 3\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "4423": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.9, 1/3의 숫자가 있다. 이 중 0.3보다 작거나 같은 숫자들의 합을 구하시오.",
        "question_en": "There are numbers 0.8, 1/2, 0.9, and 1/3. Find the sum of all the numbers less than or equal to 0.3.",
        "answer_ko": "0",
        "answer_en": "0",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.3 [OP_LIST_LESS_EQUAL] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.3 [OP_LIST_LESS_EQUAL] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.3\nlist_b = []\nfor i in list_a:\n    if i <= var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.3\nlist_b = []\nfor i in list_a:\n    if i <= var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint(int(var_f))"
    },
    "4424": {
        "category": "Geometry",
        "question_ko": "준영이네 집에는 가로 50센티미터(㎝), 세로 16센티미터(㎝), 높이 25센티미터(㎝)짜리 어항이 있다. 이 어항에 15센티미터(㎝) 높이만큼 물을 채워넣고, 한 모서리의 길이가 10센티미터(㎝)인 정육면체 모양 나무조각을 물에 완전히 잠기게 넣었다. 이 때 어항의 높이는 몇 센티미터(㎝)가 될지 소수점을 포함하여 구하라.",
        "question_en": "Junyeong's house has a fish tank measuring 50 centimeters (cm) wide, 16 centimeters (cm) long, and 25 centimeters (cm) high. The fishbowl was filled with water to a height of 15 centimeters (cm), and a cube-shaped piece of wood with one corner length of 10 centimeters (cm) was completely submerged in the water. At this time, find the height of the fish tank in centimeters (cm) including the decimal point.",
        "answer_ko": "16.25",
        "answer_en": "16.25",
        "solution_abst_ko": "15 10 10 [OP_MUL] 10 [OP_MUL] 50 16 [OP_MUL] [OP_DIV] [OP_ADD]",
        "solution_abst_en": "15 10 10 [OP_MUL] 10 [OP_MUL] 50 16 [OP_MUL] [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 15\nvar_b = 10\nvar_c = 10\nvar_d = var_b * var_c\nvar_e = 10\nvar_f = var_d * var_e\nvar_g = 50\nvar_h = 16\nvar_i = var_g * var_h\nvar_j = var_f / var_i\nvar_k = var_a + var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 15\nvar_b = 10\nvar_c = 10\nvar_d = var_b * var_c\nvar_e = 10\nvar_f = var_d * var_e\nvar_g = 50\nvar_h = 16\nvar_i = var_g * var_h\nvar_j = var_f / var_i\nvar_k = var_a + var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "4425": {
        "category": "Arithmetic calculation",
        "question_ko": "민영이네 집에서 기르는 닭은 오리 수의 4배이고, 토끼는 오리보다 17마리 적습니다. 민영이네 집에서 기르는 토끼가 8마리일 때, 민영이네 집에서 기르는 닭, 오리, 토끼는 모두 몇 마리입니까?",
        "question_en": "At Minyoung's house, there are four times as many chickens as ducks, and 17 fewer rabbits than ducks. If there are 8 rabbits in Minyoung's house, how many chickens, ducks, and rabbits are there in total in Minyoung's house?",
        "answer_ko": "133",
        "answer_en": "133",
        "solution_abst_ko": "8 8 17 [OP_ADD] [OP_ADD] 4 8 17 [OP_ADD] [OP_MUL] [OP_ADD]",
        "solution_abst_en": "8 8 17 [OP_ADD] [OP_ADD] 4 8 17 [OP_ADD] [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 8\nvar_c = 17\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nvar_f = 4\nvar_g = 8\nvar_h = 17\nvar_i = var_g + var_h\nvar_j = var_f * var_i\nvar_k = var_e + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 8\nvar_b = 8\nvar_c = 17\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nvar_f = 4\nvar_g = 8\nvar_h = 17\nvar_i = var_g + var_h\nvar_j = var_f * var_i\nvar_k = var_e + var_j\nprint(int(var_k))"
    },
    "4426": {
        "category": "Arithmetic calculation",
        "question_ko": "주사위를 5번 던졌더니 나온 값이 순서대로 2, 4, 4, 1, 5였다. 4는 몇 번 나왔는지 구하시오.",
        "question_en": "The dice were thrown 5 times and the values that came out were 2, 4, 4, 1, and 5 in that order. Find how many times 4 came out.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 2 4 4 1 5 [OP_LIST_EOL] 4 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "[OP_LIST_SOL] 2 4 4 1 5 [OP_LIST_EOL] 4 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = 4\nvar_d = 1\nvar_e = 5\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 4\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = 4\nvar_d = 1\nvar_e = 5\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 4\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))"
    },
    "4427": {
        "category": "Correspondence",
        "question_ko": "호석이는 어떤 수에 5를 곱하여 100을 얻었습니다. 어떤 수를 10으로 나누면 얼마입니까?",
        "question_en": "Hoseok multiplied a certain number by 5 and got 100. Find out the value of that certain number divided by 10.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "100 5 [OP_DIV] 10 [OP_DIV]",
        "solution_abst_en": "100 5 [OP_DIV] 10 [OP_DIV]",
        "solution_code_ko": "var_a = 100\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 10\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 100\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 10\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "4428": {
        "category": "Comparison",
        "question_ko": "독서대회에 A, B, C 3개의 반이 참가하였습니다. C 반 학생들이 A 반 학생들보다 책을 많이 읽었고, A 반 학생들이 B 반 학생들보다 책을 많이 읽었다면, 가장 적은 책을 읽은 반은 어떤 반인지 구하세요.",
        "question_en": "Three classes A, B, and C took part in the reading competition. If the students in class C read more books than the students in class A, and the students in class A read more books than the students in class B, find which class read the fewest books.",
        "answer_ko": "B",
        "answer_en": "B",
        "solution_abst_ko": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] A B > C A > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] A B > C A > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'A'\nvar_e = 'B'\nvar_f = '>'\nvar_g = 'C'\nvar_h = 'A'\nvar_i = '>'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = len(list_c)\nvar_k = list_c[var_j-1]\nprint(var_k)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'A'\nvar_e = 'B'\nvar_f = '>'\nvar_g = 'C'\nvar_h = 'A'\nvar_i = '>'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = len(list_c)\nvar_k = list_c[var_j-1]\nprint(var_k)"
    },
    "4429": {
        "category": "Comparison",
        "question_ko": "유나, 은지, 민영이가 가위바위보게임을 하고 있습니다. 유나는 민영이를 이겼고, 은지는 민영이에게 졌습니다. 꼴찌는 누구일까요?",
        "question_en": "Yuna, Eunji, and Minyoung are playing a rock-paper-scissors game. Yuna beat Minyoung and Eunji lost to Minyoung. Who's in last place?",
        "answer_ko": "은지",
        "answer_en": "Eunji",
        "solution_abst_ko": "[OP_LIST_SOL] 유나 은지 민영 [OP_LIST_EOL] [OP_LIST_SOL] 유나 민영 > 은지 민영 < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yuna Eunji Minyoung [OP_LIST_EOL] [OP_LIST_SOL] Yuna Minyoung > Eunji Minyoung < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '유나'\nvar_b = '은지'\nvar_c = '민영'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '유나'\nvar_e = '민영'\nvar_f = '>'\nvar_g = '은지'\nvar_h = '민영'\nvar_i = '<'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = len(list_c)\nvar_k = list_c[var_j-1]\nprint(var_k)",
        "solution_code_en": "var_a = 'Yuna'\nvar_b = 'Eunji'\nvar_c = 'Minyoung'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'Yuna'\nvar_e = 'Minyoung'\nvar_f = '>'\nvar_g = 'Eunji'\nvar_h = 'Minyoung'\nvar_i = '<'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = len(list_c)\nvar_k = list_c[var_j-1]\nprint(var_k)"
    },
    "4430": {
        "category": "Possibility",
        "question_ko": "6, 7, 8이 적혀있는 숫자카드 중 서로 다른 2가지 카드를 이용하여 두 자리 숫자를 만드려고 합니다. 가능한 수는 모두 몇 가지 인가요?",
        "question_en": "I'm trying to make a two-digit number using two different cards among those that have numbers 6, 7, and 8 written on them. How many possible numbers are there?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 6 7 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 6 7 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 6\nvar_b = 7\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 7\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "4431": {
        "category": "Possibility",
        "question_ko": "각 자리 수가 모두 홀수인 세 자리 수의 개수를 구하시오.",
        "question_en": "Find the number of three-digit numbers where each digit is odd.",
        "answer_ko": "125",
        "answer_en": "125",
        "solution_abst_ko": "1 9 [OP_LIST_ODD] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_LEN]",
        "solution_abst_en": "1 9 [OP_LIST_ODD] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = len(list_b)\nprint(int(var_d))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = len(list_b)\nprint(int(var_d))"
    },
    "4432": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 7을 뺀 값은 9와 8의 곱과 같다. 어떤 수를 6으로 나눈 몫을 구하시오.",
        "question_en": "Subtracting 7 from a number equals 9 multiplied by 8. Find the quotient of the number divided by 6.",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "8 9 [OP_MUL] 7 [OP_ADD] 6 [OP_FDIV]",
        "solution_abst_en": "8 9 [OP_MUL] 7 [OP_ADD] 6 [OP_FDIV]",
        "solution_code_ko": "var_a = 8\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c + var_d\nvar_f = 6\nvar_g = var_e // var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 8\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c + var_d\nvar_f = 6\nvar_g = var_e // var_f\nprint(int(var_g))"
    },
    "4433": {
        "category": "Comparison",
        "question_ko": "정국이가 가진 지우개의 개수는 6개입니다. 지민이는 정국이보다는 4개 많고 석진이는 지민이보다 3개 적다면, 누가 가지고 있는 지우개의 수가 가장 적습니까?",
        "question_en": "Jungkook has 6 erasers. If Jimin has 4 more erasers than Jungkook and Seokjin has 3 less than Jimin, who has the fewest erasers?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 지민 석진 [OP_LIST_EOL] [OP_LIST_SOL] 6 6 4 [OP_ADD] 6 4 [OP_ADD] 3 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Jimin Seokjin [OP_LIST_EOL] [OP_LIST_SOL] 6 6 4 [OP_ADD] 6 4 [OP_ADD] 3 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '지민'\nvar_c = '석진'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 6\nvar_e = 6\nvar_f = 4\nvar_g = var_e + var_f\nvar_h = 6\nvar_i = 4\nvar_j = var_h + var_i\nvar_k = 3\nvar_l = var_j - var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[var_m-1]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Jimin'\nvar_c = 'Seokjin'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 6\nvar_e = 6\nvar_f = 4\nvar_g = var_e + var_f\nvar_h = 6\nvar_i = 4\nvar_j = var_h + var_i\nvar_k = 3\nvar_l = var_j - var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[var_m-1]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "4434": {
        "category": "Geometry",
        "question_ko": "어떤 삼각기둥의 밑면은 한 변이 3인 정삼각형이고 높이는 6이다. 옆면의 넓이의 합을 구하시오.",
        "question_en": "The base of a triangular prism is an equilateral triangle with a side of 3 centimeters (cm) and a height of 6 centimeters (cm). Find the sum of the areas of the sides.",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "3 6 3 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "3 6 3 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 6\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 3\nvar_b = 6\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "4435": {
        "category": "Comparison",
        "question_ko": "정국에는 6에서 3을 뺀 수를 모았고, 윤기는 4, 유나는 5를 모았습니다. 누가 가장 큰 수를 가지고 있나요?",
        "question_en": "Jungkook collects the number 6 minus 3, Yoongi collects 4, and Yuna collects 5. Who has the biggest number?",
        "answer_ko": "유나",
        "answer_en": "Yuna",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 윤기 유나 [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_SUB] 4 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Yoongi Yuna [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_SUB] 4 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '윤기'\nvar_c = '유나'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 6\nvar_e = 3\nvar_f = var_d - var_e\nvar_g = 4\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Yoongi'\nvar_c = 'Yuna'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 6\nvar_e = 3\nvar_f = var_d - var_e\nvar_g = 4\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "4436": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 3으로 나눈 몫을 구해야하는데 잘못하여 7로 나누었더니 몫이 12이고 나머지가 4이다. 바르게 계산한 값을 구하시오.",
        "question_en": "I want to find the quotient of a number divided by 3, but I mistakenly divided it by 7, and the quotient became 12 with the remainder 4. Find the correctly calculated value.",
        "answer_ko": "29",
        "answer_en": "29",
        "solution_abst_ko": "7 12 [OP_MUL] 4 [OP_ADD] 3 [OP_FDIV]",
        "solution_abst_en": "7 12 [OP_MUL] 4 [OP_ADD] 3 [OP_FDIV]",
        "solution_code_ko": "var_a = 7\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e // var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 7\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e // var_f\nprint(int(var_g))"
    },
    "4437": {
        "category": "Comparison",
        "question_ko": "윤기네 반 학생들이 줄을 서고 있습니다. 윤기의 앞에는 15명, 뒤에는 12명의 학생이 있다면, 줄을 서고 있는 학생은 모두 몇 명입니까?",
        "question_en": "Yoongi's classmates are queuing up. If there are 15 students in front of Yoongi and 12 students behind him, what is the total number of students in line?",
        "answer_ko": "28",
        "answer_en": "28",
        "solution_abst_ko": "15 1 [OP_ADD] 12 [OP_ADD]",
        "solution_abst_en": "15 1 [OP_ADD] 12 [OP_ADD]",
        "solution_code_ko": "var_a = 15\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 12\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 12\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "4438": {
        "category": "Correspondence",
        "question_ko": "사탕을 한 봉지에 6개씩 담으면 4개가 남고, 8개씩 담으면 6개가 남고, 10개씩 담으면 8개가 남는다고 한다. 사탕은 최소 몇 개인지 구하여라.",
        "question_en": "If you put 6 sweets in bag, there will be 4 left. If you put 8 in a bag, there are 6 left, and if you put 10 in a bag, there are 8 left. Find the smallest number that can be the number of sweets",
        "answer_ko": "118",
        "answer_en": "118",
        "solution_abst_ko": "0 9999 1 [OP_LIST_ARANGE] 6 4 [OP_LIST_DIVIDE_AND_REMAIN] 8 6 [OP_LIST_DIVIDE_AND_REMAIN] 10 8 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MIN]",
        "solution_abst_en": "0 9999 1 [OP_LIST_ARANGE] 6 4 [OP_LIST_DIVIDE_AND_REMAIN] 8 6 [OP_LIST_DIVIDE_AND_REMAIN] 10 8 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 0\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nvar_e = 4\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 8\nvar_g = 6\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 10\nvar_i = 8\nlist_d = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_c:\n    i = int(i)\n    if i%var_h == var_i:\n        list_d.append(i)\nvar_j = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_k = list_e[var_j-1]\nprint(int(var_k))",
        "solution_code_en": "var_a = 0\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nvar_e = 4\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 8\nvar_g = 6\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 10\nvar_i = 8\nlist_d = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_c:\n    i = int(i)\n    if i%var_h == var_i:\n        list_d.append(i)\nvar_j = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_k = list_e[var_j-1]\nprint(int(var_k))"
    },
    "4439": {
        "category": "Correspondence",
        "question_ko": "창현이는 과일 가게에서 사과를 사는데 가진 돈의 절반을 사용하고 봉투값으로 300원을 사용한 후, 생선 가게에서 고등어를 사는데 남은 돈의 절반과 400원을 사용했다면 창현이가 처음 가지고 있던 돈은 얼마인지 구하시오.",
        "question_en": "If Changhyeon spent half of his money on apples at the fruit shop and 300 won on the plastic bag, and then spent half of his remaining money and 400 won on mackerel at the fish shop, how much money did Changhyeon have at the beginning?",
        "answer_ko": "2200",
        "answer_en": "2200",
        "solution_abst_ko": "0 400 [OP_ADD] 1 1/2 [OP_SUB] [OP_DIV] 300 [OP_ADD] 1 1/2 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "0 400 [OP_ADD] 1 1/2 [OP_SUB] [OP_DIV] 300 [OP_ADD] 1 1/2 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 0\nvar_b = 400\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 0.5\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 300\nvar_i = var_g + var_h\nvar_j = 1\nvar_k = 0.5\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 0\nvar_b = 400\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 0.5\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 300\nvar_i = var_g + var_h\nvar_j = 1\nvar_k = 0.5\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nprint(int(var_m))"
    },
    "4440": {
        "category": "Arithmetic calculation",
        "question_ko": "사탕 34개를 7개의 상자에 나누어 담았더니 1개의 사탕이 모자랐습니다. 상자의 개수는 몇 개인가?",
        "question_en": "There were thirty-four candies divided equally among seven boxes, resulting in one candy shortage. How many candies are there in one box?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "34 1 [OP_ADD] 7 [OP_FDIV]",
        "solution_abst_en": "34 1 [OP_ADD] 7 [OP_FDIV]",
        "solution_code_ko": "var_a = 34\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 7\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 34\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 7\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "4441": {
        "category": "Comparison",
        "question_ko": "유나, 은지, 민영이가 키 순서대로 서 있습니다. 유나가 은지보다 키가 크고 민영이가 은지보다 키가 작습니다. 키가 작은 학생이 가장 앞에 서 있다면 맨 앞에 서 있는 학생은 누구인지 구하세요.",
        "question_en": "Yuna, Eunji, and Minyoung are standing in order of height. Yuna is taller than Eunji and Minyoung is shorter than Eunji. If the shortest student is standing at the front, find out who is standing at the front.",
        "answer_ko": "민영",
        "answer_en": "Minyoung",
        "solution_abst_ko": "[OP_LIST_SOL] 유나 은지 민영 [OP_LIST_EOL] [OP_LIST_SOL] 유나 은지 > 민영 은지 < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yuna Eunji Minyoung [OP_LIST_EOL] [OP_LIST_SOL] Yuna Eunji > Minyoung Eunji < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '유나'\nvar_b = '은지'\nvar_c = '민영'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '유나'\nvar_e = '은지'\nvar_f = '>'\nvar_g = '민영'\nvar_h = '은지'\nvar_i = '<'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = len(list_c)\nvar_k = list_c[var_j-1]\nprint(var_k)",
        "solution_code_en": "var_a = 'Yuna'\nvar_b = 'Eunji'\nvar_c = 'Minyoung'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'Yuna'\nvar_e = 'Eunji'\nvar_f = '>'\nvar_g = 'Minyoung'\nvar_h = 'Eunji'\nvar_i = '<'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = len(list_c)\nvar_k = list_c[var_j-1]\nprint(var_k)"
    },
    "4442": {
        "category": "Arithmetic calculation",
        "question_ko": "1이상 6 이하, 11 이상 16 이하의 수 중 홀수의 개수는 몇 개입니까?",
        "question_en": "How many odd numbers are there between 1 and 6 and between 11 and 16?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "1 6 [OP_LIST_ODD] [OP_LIST_LEN] 11 16 [OP_LIST_ODD] [OP_LIST_LEN] [OP_ADD]",
        "solution_abst_en": "1 6 [OP_LIST_ODD] [OP_LIST_LEN] 11 16 [OP_LIST_ODD] [OP_LIST_LEN] [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 6\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = len(list_a)\nvar_d = 11\nvar_e = 16\nlist_b = []\nif var_d%2==0:\n    for i in range(var_d+1, var_e+1, 2):\n        list_b.append(i)\nelse:\n    for i in range(var_d, var_e+1, 2):\n        list_b.append(i)\nvar_f = len(list_b)\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 6\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = len(list_a)\nvar_d = 11\nvar_e = 16\nlist_b = []\nif var_d%2==0:\n    for i in range(var_d+1, var_e+1, 2):\n        list_b.append(i)\nelse:\n    for i in range(var_d, var_e+1, 2):\n        list_b.append(i)\nvar_f = len(list_b)\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "4443": {
        "category": "Correspondence",
        "question_ko": "서로 다른 두 자연수 A, B가 있습니다. A를 29로 나누면 몫은 31이고 나머지는 B가 됩니다. 나머지 B가 가장 작은 수일 때 A를 구하시오.",
        "question_en": "There are two different natural numbers, A and B. When A is divided by 29, the quotient is 31 and the remainder is B. Find A when the remainder B is the smallest number.",
        "answer_ko": "899",
        "answer_en": "899",
        "solution_abst_ko": "29 31 [OP_MUL]",
        "solution_abst_en": "29 31 [OP_MUL]",
        "solution_code_ko": "var_a = 29\nvar_b = 31\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 29\nvar_b = 31\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "4444": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 3 으로 나눈 다음 12 를 더해야 할 것을 잘못하여 3 을 곱한 다음 12 를 뺐더니 60 이 되었습니다. 바르게 계산하면 얼마입니까?",
        "question_en": "You had to divide a number by 3 and then add 12, but mistakenly multiplied 3 and subtracted 12 instead, which resulted in 60. What is the result of the correct calculation?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "60 12 [OP_ADD] 3 [OP_DIV] 3 [OP_DIV] 12 [OP_ADD]",
        "solution_abst_en": "60 12 [OP_ADD] 3 [OP_DIV] 3 [OP_DIV] 12 [OP_ADD]",
        "solution_code_ko": "var_a = 60\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = 12\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 60\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = 12\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "4445": {
        "category": "Geometry",
        "question_ko": "어떤 정사각형 모양의 공원이 있습니다. 이 공원의 한 변의 길이가 30미터(m)일 때, 이 공원의 넓이는 몇 제곱미터(㎡)입니까?",
        "question_en": "There is a park in the shape of a square. If the length of one side of this park is 30 meters (m), what is the area in square meters (m2) of this park?",
        "answer_ko": "900",
        "answer_en": "900",
        "solution_abst_ko": "30 2 [OP_POW]",
        "solution_abst_en": "30 2 [OP_POW]",
        "solution_code_ko": "var_a = 30\nvar_b = 2\nvar_c = var_a ** var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 30\nvar_b = 2\nvar_c = var_a ** var_b\nprint(int(var_c))"
    },
    "4446": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.3, 1/3에서 0.4보다 작거나 같은 수 중 가장 크거나 같은 수는?",
        "question_en": "Which number among 0.8, 1/2, 0.3, 1/3 is less than or equal to 0.4?",
        "answer_ko": "0.33",
        "answer_en": "0.33",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.3 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_LESS_EQUAL] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.3 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_LESS_EQUAL] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.3\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.4\nlist_b = []\nfor i in list_a:\n    if i <= var_e:\n        list_b.append(i)\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.3\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.4\nlist_b = []\nfor i in list_a:\n    if i <= var_e:\n        list_b.append(i)\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "4447": {
        "category": "Correspondence",
        "question_ko": "큰 물통에 작은 컵으로 물을 가득 담아 8번 넣은 후, 다시 5400밀리리터(㎖)의 물을 넣었습니다. 이 물을 12개의 작은 물통에 나누어 담았더니 작은 물통 한 개에 530밀리리터(㎖)씩 담겨졌습니다. 작은 컵의 들이를 구하시오.",
        "question_en": "After filling the large water container by adding a small cup full of water 8 times, another 5400 milliliters (㎖) of water was added again. When this water was divided into 12 small buckets, each small bucket contained 530 milliliters (㎖). Find the volume of the small cup.",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "530 12 [OP_MUL] 5400 [OP_SUB] 8 [OP_DIV]",
        "solution_abst_en": "530 12 [OP_MUL] 5400 [OP_SUB] 8 [OP_DIV]",
        "solution_code_ko": "var_a = 530\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 5400\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 530\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 5400\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "4448": {
        "category": "Geometry",
        "question_ko": "어떤 정육면체 모양의 선물 상자의 넓이가 600일때, 이 선물 상자의 부피를 구하시오.",
        "question_en": "If the surface area of a cube-shaped gift box is 600, find the volume of this gift box.",
        "answer_ko": "1000",
        "answer_en": "1000",
        "solution_abst_ko": "600 6 [OP_DIV] 1/2 [OP_POW] 3 [OP_POW]",
        "solution_abst_en": "600 6 [OP_DIV] 1/2 [OP_POW] 3 [OP_POW]",
        "solution_code_ko": "var_a = 600\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 3\nvar_g = var_e ** var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 600\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 3\nvar_g = var_e ** var_f\nprint(int(var_g))"
    },
    "4449": {
        "category": "Possibility",
        "question_ko": "4, 6, 5, 0 중 3개를 사용하여 십의 자리 숫자가 5인 가장 큰 수는 무엇입니까?",
        "question_en": "What is the largest number using  3 of 4, 6, 5, 0 with 5 in the tens' digit?",
        "answer_ko": "654",
        "answer_en": "654",
        "solution_abst_ko": "[OP_LIST_SOL] 4 6 5 0 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 5 [OP_LIST_SEARCH_FIXED_DIGIT] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 4 6 5 0 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 5 [OP_LIST_SEARCH_FIXED_DIGIT] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 4\nvar_b = 6\nvar_c = 5\nvar_d = 0\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 5\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nprint(int(var_i))",
        "solution_code_en": "var_a = 4\nvar_b = 6\nvar_c = 5\nvar_d = 0\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 5\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nprint(int(var_i))"
    },
    "4450": {
        "category": "Geometry",
        "question_ko": "길이가 50센티미터(㎝)인 철사를 사용하여 한 변이 8센티미터(㎝)인 정육각형을 만들었습니다. 남은 철사의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "Using wire 50 centimeters (cm) long, a regular hexagon whose one side is 8 centimeters (cm) long was made. How many centimeters (cm) is the length of the remaining wire?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "50 8 6 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "50 8 6 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 50\nvar_b = 8\nvar_c = 6\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 50\nvar_b = 8\nvar_c = 6\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "4451": {
        "category": "Comparison",
        "question_ko": "(가), (나), (다), (라) 4개의 구슬이 있습니다. (가) 구슬은 (라) 구슬보다 큽니다. (나) 구슬은 (다) 구슬보다 작습니다. (다) 구슬은 (라) 구슬보다 작습니다. 크기가 가장 작은 구슬은 무엇입니까?",
        "question_en": "There are 4 marbles - (a), (b), (c), (d). (a) Marble is larger than (d) Marble. (b) marble is smaller than (c) marble. (c) marble is smaller than (d) marble. Which marble is the smallest in size?",
        "answer_ko": "(나)",
        "answer_en": "(b)",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) (다) (라) [OP_LIST_EOL] [OP_LIST_SOL] (가) (라) > (나) (다) < (다) (라) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (a) (b) (c) (d) [OP_LIST_EOL] [OP_LIST_SOL] (a) (d) > (b) (c) < (c) (d) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nvar_c = '(다)'\nvar_d = '(라)'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '(가)'\nvar_f = '(라)'\nvar_g = '>'\nvar_h = '(나)'\nvar_i = '(다)'\nvar_j = '<'\nvar_k = '(다)'\nvar_l = '(라)'\nvar_m = '<'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)",
        "solution_code_en": "var_a = '(a)'\nvar_b = '(b)'\nvar_c = '(c)'\nvar_d = '(d)'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '(a)'\nvar_f = '(d)'\nvar_g = '>'\nvar_h = '(b)'\nvar_i = '(c)'\nvar_j = '<'\nvar_k = '(c)'\nvar_l = '(d)'\nvar_m = '<'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)"
    },
    "4452": {
        "category": "Correspondence",
        "question_ko": "A를 7로 나누면 몫은 5이고 나머지는 3이 됩니다. A를 구하시오.",
        "question_en": "When A is divided by 7, the quotient is 5 and the remainder is 3. Find A.",
        "answer_ko": "38",
        "answer_en": "38",
        "solution_abst_ko": "5 7 [OP_MUL] 3 [OP_ADD]",
        "solution_abst_en": "5 7 [OP_MUL] 3 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "4453": {
        "category": "Arithmetic calculation",
        "question_ko": "5의 배수이거나 홀수인 A가 30보다 같거나 작다고 한다. 가능한 A를 모두 더하면 얼마인지 구하시오.",
        "question_en": "An odd number or multiple of 5 is said to be less than or equal to 30. What is the sum of all possible A's?",
        "answer_ko": "285",
        "answer_en": "285",
        "solution_abst_ko": "1 30 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] 1 30 [OP_LIST_ODD] [OP_SET_UNION] [OP_LIST_SUM]",
        "solution_abst_en": "1 30 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] 1 30 [OP_LIST_ODD] [OP_SET_UNION] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 30\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 1\nvar_f = 30\nlist_c = []\nif var_e%2==0:\n    for i in range(var_e+1, var_f+1, 2):\n        list_c.append(i)\nelse:\n    for i in range(var_e, var_f+1, 2):\n        list_c.append(i)\nlist_d = list(set(list_b) | set(list_c))\nlist_d = [float(i) for i in list_d]\nvar_g = sum(list_d)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 30\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 1\nvar_f = 30\nlist_c = []\nif var_e%2==0:\n    for i in range(var_e+1, var_f+1, 2):\n        list_c.append(i)\nelse:\n    for i in range(var_e, var_f+1, 2):\n        list_c.append(i)\nlist_d = list(set(list_b) | set(list_c))\nlist_d = [float(i) for i in list_d]\nvar_g = sum(list_d)\nprint(int(var_g))"
    },
    "4454": {
        "category": "Arithmetic calculation",
        "question_ko": "(가) 자동차는 1시간에 60킬로미터(㎞) 달리고, (나) 자동차는 1시간에 45킬로미터(㎞) 달립니다. (가) 자동차와 (나) 자동차가 같은 빠르기로 5시간 동안 달린다면, (가) 자동차는 (나) 자동차보다 몇 킬로미터(㎞) 더 가겠습니까?",
        "question_en": "(A) car travels at 60 kilometers (km) per hour, and (B) car travels at 45 kilometers (km) per hour. If (A) car and (B) car travel at the same speed for 5 hours, how many kilometers will (A) travel more than (B) car?",
        "answer_ko": "75",
        "answer_en": "75",
        "solution_abst_ko": "60 5 [OP_MUL] 45 5 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "60 5 [OP_MUL] 45 5 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 60\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 45\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 60\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 45\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "4455": {
        "category": "Arithmetic calculation",
        "question_ko": "할머니께서 6킬로그램(㎏)짜리 설탕을 21통 사서 이웃 사람들에게 32/41킬로그램(㎏)씩 나누어 주려고 합니다. 몇 명에게 나누어 줄 수 있습니까?",
        "question_en": "Grandmother wants to buy 21 boxes of 6kilograms (kg) sugar and distribute 32/41kilograms (kg) each to her neighbors. How many people can you share?",
        "answer_ko": "161",
        "answer_en": "161",
        "solution_abst_ko": "6 21 [OP_MUL] 32/41 [OP_FDIV]",
        "solution_abst_en": "6 21 [OP_MUL] 32/41 [OP_FDIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 21\nvar_c = var_a * var_b\nvar_d = 0.7804878048780488\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 21\nvar_c = var_a * var_b\nvar_d = 0.7804878048780488\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "4456": {
        "category": "Arithmetic calculation",
        "question_ko": "A 학교의 남학생 수는 217명, B 학교의 여학생 수는 196명입니다. A 학교 남학생과 B 학교 남학생 수를 합친 것이 A 학교 여학생과 B 학교 여학생을 합친 것과 같을 때, B 학교 남학생 수와 A학교 여학생 수의 차이는 얼마인가?",
        "question_en": "School A has 217 boys and School B has 196 girls. If the sum of the number of male students in school A and the number of male students in school B is equal to the total number of female students in school A and school B, what is the difference between the number of male students in school B and the number of female students in school A?",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "217 196 [OP_SUB] [OP_ABS]",
        "solution_abst_en": "217 196 [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 217\nvar_b = 196\nvar_c = var_a - var_b\nvar_d = abs(var_c)\nprint(int(var_d))",
        "solution_code_en": "var_a = 217\nvar_b = 196\nvar_c = var_a - var_b\nvar_d = abs(var_c)\nprint(int(var_d))"
    },
    "4457": {
        "category": "Geometry",
        "question_ko": "밑면은 다각형이고, 옆면이 삼각형인 뿔 모양의 입체도형의 모서리가 10개라면, 꼭짓점은 몇 개입니까?",
        "question_en": "If a cone-shaped solid figure with a polygonal base and triangular sides has 10 edges, how many vertices are there?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "10 2 [OP_DIV] 1 [OP_ADD]",
        "solution_abst_en": "10 2 [OP_DIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "4458": {
        "category": "Arithmetic calculation",
        "question_ko": "1분마다 처음의 2배로 복제되는 세균이 있습니다. 처음 비커와 비커에 담긴 세균 100마리의 무게의 합은 23.97그램(g)이었고, 5분 후 비커와 비커에 담긴 세균의 무게의 합은 155.1그램(g)이었습니다. 복제된 세균 10000마리의 무게는 몇 그램(g)입니까?",
        "question_en": "There are bacteria that multiply twice as fast as they do every minute. The sum of the weight of the first beaker and the 100 bacteria in it was 23.97 grams (g), and the sum of the weight of the beaker and the bacteria in it after 5 minutes was 155.1 grams (g). How many grams (g) do 10000 cloned bacteria weigh?",
        "answer_ko": "423",
        "answer_en": "423",
        "solution_abst_ko": "155.1 23.97 [OP_SUB] 100 2 5 [OP_POW] [OP_MUL] 100 [OP_SUB] [OP_DIV] 10000 [OP_MUL]",
        "solution_abst_en": "155.1 23.97 [OP_SUB] 100 2 5 [OP_POW] [OP_MUL] 100 [OP_SUB] [OP_DIV] 10000 [OP_MUL]",
        "solution_code_ko": "var_a = 155.1\nvar_b = 23.97\nvar_c = var_a - var_b\nvar_d = 100\nvar_e = 2\nvar_f = 5\nvar_g = var_e ** var_f\nvar_h = var_d * var_g\nvar_i = 100\nvar_j = var_h - var_i\nvar_k = var_c / var_j\nvar_l = 10000\nvar_m = var_k * var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 155.1\nvar_b = 23.97\nvar_c = var_a - var_b\nvar_d = 100\nvar_e = 2\nvar_f = 5\nvar_g = var_e ** var_f\nvar_h = var_d * var_g\nvar_i = 100\nvar_j = var_h - var_i\nvar_k = var_c / var_j\nvar_l = 10000\nvar_m = var_k * var_l\nprint(int(var_m))"
    },
    "4459": {
        "category": "Correspondence",
        "question_ko": "용희가 무게 1킬로그램(㎏) 750그램(g)인 가방을 들고 저울에 올라섰더니 저울의 눈금이 35킬로그램(㎏) 500그램(g)을 가리켰습니다. 용희의 동생이 2킬로그램(㎏) 550그램(g)인 가방을 들고 저울에 올라갔을때 저울의 눈금이 27킬로그램(㎏) 200그램(g)를 가리켰습니다. 용희가 동생을 업고 저울에 올라서면 저울의 눈금은 몇 킬로그램(㎏)을 나타내겠습니까?",
        "question_en": "Yong-hee stood on the scale holding a bag weighing 1 kilogram (kg) and 750 grams (g), and the scale indicated 35 kilograms (kg) and 500 grams (g). When Yong-hee's younger brother climbed on the scale with a bag weighing 2 kilograms (kg) and 550 grams (g), the scale indicated 27 kilograms (kg) and 200 grams (g). How many kilograms (kg) will the scale show when Yong-hee stands on the scale with her younger brother on her back?",
        "answer_ko": "58.40",
        "answer_en": "58.4",
        "solution_abst_ko": "35 500 1000 [OP_DIV] [OP_ADD] 1 750 1000 [OP_DIV] [OP_ADD] [OP_SUB] 27 200 1000 [OP_DIV] [OP_ADD] 2 550 1000 [OP_DIV] [OP_ADD] [OP_SUB] [OP_ADD]",
        "solution_abst_en": "35 500 1000 [OP_DIV] [OP_ADD] 1 750 1000 [OP_DIV] [OP_ADD] [OP_SUB] 27 200 1000 [OP_DIV] [OP_ADD] 2 550 1000 [OP_DIV] [OP_ADD] [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 35\nvar_b = 500\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 1\nvar_g = 750\nvar_h = 1000\nvar_i = var_g / var_h\nvar_j = var_f + var_i\nvar_k = var_e - var_j\nvar_l = 27\nvar_m = 200\nvar_n = 1000\nvar_o = var_m / var_n\nvar_p = var_l + var_o\nvar_q = 2\nvar_r = 550\nvar_s = 1000\nvar_t = var_r / var_s\nvar_u = var_q + var_t\nvar_v = var_p - var_u\nvar_w = var_k + var_v\nprint('{:.2f}'.format(round(var_w+1e-10,2)))",
        "solution_code_en": "var_a = 35\nvar_b = 500\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 1\nvar_g = 750\nvar_h = 1000\nvar_i = var_g / var_h\nvar_j = var_f + var_i\nvar_k = var_e - var_j\nvar_l = 27\nvar_m = 200\nvar_n = 1000\nvar_o = var_m / var_n\nvar_p = var_l + var_o\nvar_q = 2\nvar_r = 550\nvar_s = 1000\nvar_t = var_r / var_s\nvar_u = var_q + var_t\nvar_v = var_p - var_u\nvar_w = var_k + var_v\nprint('{:.2f}'.format(round(var_w+1e-10,2)))"
    },
    "4460": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 2미터(m) 80센티미터(㎝)인 줄자가 있습니다. 이 줄자를 40센티미터(㎝) 길이로 모두 자른다면, 모두 몇 번 잘라야 합니까?",
        "question_en": "There is a tape measure with a length of 2 meters (m) and 80 centimeters (cm). If you cut all the 40 centimeters (cm) lengths of this tape measure, how many times do you have to cut all of them?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "2 100 [OP_MUL] 80 [OP_ADD] 40 [OP_DIV] 1 [OP_SUB]",
        "solution_abst_en": "2 100 [OP_MUL] 80 [OP_ADD] 40 [OP_DIV] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 2\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 80\nvar_e = var_c + var_d\nvar_f = 40\nvar_g = var_e / var_f\nvar_h = 1\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 2\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 80\nvar_e = var_c + var_d\nvar_f = 40\nvar_g = var_e / var_f\nvar_h = 1\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "4461": {
        "category": "Correspondence",
        "question_ko": "423에 어떤 수를 곱해야 할 것을 잘못하여 뺐더니 421이 되었습니다. 바르게 계산한 값과 잘못 계산한 값의 합을 구해 보시오.",
        "question_en": "I mistakenly subtracted what number should be multiplied by 423, and I got 421. Find the sum of the correctly calculated value and the incorrectly calculated value.",
        "answer_ko": "1267",
        "answer_en": "1267",
        "solution_abst_ko": "421 423 423 421 [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_abst_en": "421 423 423 421 [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 421\nvar_b = 423\nvar_c = 423\nvar_d = 421\nvar_e = var_c - var_d\nvar_f = var_b * var_e\nvar_g = var_a + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 421\nvar_b = 423\nvar_c = 423\nvar_d = 421\nvar_e = var_c - var_d\nvar_f = var_b * var_e\nvar_g = var_a + var_f\nprint(int(var_g))"
    },
    "4462": {
        "category": "Arithmetic calculation",
        "question_ko": "오리 7마리와 닭 6마리가 있습니다. 오리와 닭은 모두 몇 마리 있습니까?",
        "question_en": "There are 7 ducks and 6 chickens. How many ducks and chickens are there?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "7 6 [OP_ADD]",
        "solution_abst_en": "7 6 [OP_ADD]",
        "solution_code_ko": "var_a = 7\nvar_b = 6\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 7\nvar_b = 6\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "4463": {
        "category": "Correspondence",
        "question_ko": "가로, 세로가 6미터(m)인 정사각형 모양의 땅이 9개 있다. 전체 땅의 넓이가 몇 제곱미터(㎡)인지 구하시오.",
        "question_en": "There are nine square-shaped plots of land measuring 6 meters (m) in length and width. Find the total area of the land in square meters (m2).",
        "answer_ko": "324",
        "answer_en": "324",
        "solution_abst_ko": "6 6 [OP_MUL] 9 [OP_MUL]",
        "solution_abst_en": "6 6 [OP_MUL] 9 [OP_MUL]",
        "solution_code_ko": "var_a = 6\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "4464": {
        "category": "Possibility",
        "question_ko": "40의 사탕을 여러 바구니에 나누어 담으려고 한다. 바구니에 나누어 담는 방법의 수를 구하시오. (단, 한 바구니에 40개를 모두 담지는 않는다.)",
        "question_en": "Consider 40 candies should be distributed into several baskets. Find the number of ways to divide the candies. (However, all 40 candies should not be put in one basket.)",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "40 [OP_LIST_GET_DIVISOR] [OP_LIST_SOL] 1 [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_abst_en": "40 [OP_LIST_GET_DIVISOR] [OP_LIST_SOL] 1 [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 40\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 1\nlist_b= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_b.append(var_b)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_c = len(list_c)\nprint(int(var_c))",
        "solution_code_en": "var_a = 40\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 1\nlist_b= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_b.append(var_b)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_c = len(list_c)\nprint(int(var_c))"
    },
    "4465": {
        "category": "Arithmetic calculation",
        "question_ko": "윤기는 할아버지가 사오신 사과 15개 중 7개를 먹었습니다. 할아버지께서 사오신 사과는 몇 개 남았을까요?",
        "question_en": "Yoongi ate 7 of the 15 apples his grandfather bought. How many apples did Grandpa buy remain?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "15 7 [OP_SUB]",
        "solution_abst_en": "15 7 [OP_SUB]",
        "solution_code_ko": "var_a = 15\nvar_b = 7\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 15\nvar_b = 7\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "4466": {
        "category": "Arithmetic calculation",
        "question_ko": "찹쌀떡 1개를 만드는 데 찹쌀가루가 6.64그램(g) 필요합니다. 찹쌀가루 202.66그램(g)으로 찹쌀떡을 다 만들고 남은 찹쌀가루는 몇 킬로그램(㎏)인지 구하시오.",
        "question_en": "It takes 6.64 grams (g) of glutinous rice flour to make one glutinous rice cake. Find how many kilograms (kg) of glutinous rice flour are left after making glutinous rice cakes with 202.66 grams (g) of glutinous rice flour.",
        "answer_ko": "0",
        "answer_en": "0",
        "solution_abst_ko": "202.66 6.64 [OP_MOD] 1000 [OP_DIV]",
        "solution_abst_en": "202.66 6.64 [OP_MOD] 1000 [OP_DIV]",
        "solution_code_ko": "var_a = 202.66\nvar_b = 6.64\nvar_c = var_a % var_b\nvar_d = 1000\nvar_e = var_c / var_d\nprint(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))",
        "solution_code_en": "var_a = 202.66\nvar_b = 6.64\nvar_c = var_a % var_b\nvar_d = 1000\nvar_e = var_c / var_d\nprint(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))"
    },
    "4467": {
        "category": "Correspondence",
        "question_ko": "어떤 자연수로 197을 나누면 2가 남고, 160을 나누면 4가 남고, 229를 나누면 5가 부족하다고 한다. 이러한 수 중 가장 큰 수를 구하여라.",
        "question_en": "Dividing 197 by a certain number leaves a remainder of 2, dividing 160 leaves a remainder of 4, and dividing 229 leaves a remainder of 5. Find the largest of these possible numbers.",
        "answer_ko": "39",
        "answer_en": "39",
        "solution_abst_ko": "197 2 [OP_SUB] 160 4 [OP_SUB] [OP_GCD] 229 5 [OP_ADD] [OP_GCD]",
        "solution_abst_en": "197 2 [OP_SUB] 160 4 [OP_SUB] [OP_GCD] 229 5 [OP_ADD] [OP_GCD]",
        "solution_code_ko": "var_a = 197\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 160\nvar_e = 4\nvar_f = var_d - var_e\nvar_g = math.gcd(int(var_f), int(var_c))\nvar_h = 229\nvar_i = 5\nvar_j = var_h + var_i\nvar_k = math.gcd(int(var_j), int(var_g))\nprint(int(var_k))",
        "solution_code_en": "var_a = 197\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 160\nvar_e = 4\nvar_f = var_d - var_e\nvar_g = math.gcd(int(var_f), int(var_c))\nvar_h = 229\nvar_i = 5\nvar_j = var_h + var_i\nvar_k = math.gcd(int(var_j), int(var_g))\nprint(int(var_k))"
    },
    "4468": {
        "category": "Arithmetic calculation",
        "question_ko": "(가) 회사의 경비원은 1명만 고용하는데 경비원이 교체되는 때에는 업무를 알려주기 위해 잠깐동안 2명의 경비원이 같이 일을 하게 됩니다. 그동안 총 3명의 경비원이 있었고 각 경비원이 일한 일수가 217일로 같은데, 첫 번째 경비원이 고용된 날부터 마지막 경비원이 그만두는 날까지가 627일이라면, 첫 번째 경비원과 두 번째 경비원이 같이 일을 한 날짜는 며칠인지 구하시오.",
        "question_en": "Company (A) hires only one security guard, but when the security guard is replaced, two security guards work together for a short time to instruct the work. In the meantime, there were a total of 3 guards, and the number of days each guard worked was the same as 217 days. If the number of days from the day the first guard was hired to the day the last guard quit was 627, find how many days the first and second guards worked together.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "217 3 [OP_MUL] 627 [OP_SUB] 3 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "217 3 [OP_MUL] 627 [OP_SUB] 3 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 217\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 627\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 217\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 627\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "4469": {
        "category": "Arithmetic calculation",
        "question_ko": "도로속 두 개의 인도에 30그루의 나무가 9미터(m) 간격으로 심어져 있다고 합니다. 처음과 끝에도 나무가 심어져 있다고 할 때 이 도로는 몇 미터(m)인가요?",
        "question_en": "30 trees are planted on two pavements in the street, 9 metres (m) apart. If trees are planted at the beginning and at the end, how many metres (m) is this road?",
        "answer_ko": "126",
        "answer_en": "126",
        "solution_abst_ko": "30 2 [OP_DIV] 1 [OP_SUB] 9 [OP_MUL]",
        "solution_abst_en": "30 2 [OP_DIV] 1 [OP_SUB] 9 [OP_MUL]",
        "solution_code_ko": "var_a = 30\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 9\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 30\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 9\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "4470": {
        "category": "Arithmetic calculation",
        "question_ko": "꽃병에 꽃이 13송이 꽂혀 있었습니다. 그중에서 7송이가 시들어서 버렸습니다. 꽃병에 남아 있는 꽃은 몇 송이입니까?",
        "question_en": "There were 13 flowers in the vase. Seven of them withered and were thrown away. How many flowers are left in the vase?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "13 7 [OP_SUB]",
        "solution_abst_en": "13 7 [OP_SUB]",
        "solution_code_ko": "var_a = 13\nvar_b = 7\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 13\nvar_b = 7\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "4471": {
        "category": "Possibility",
        "question_ko": "검은색 볼펜 7자루 중에서 6자루를 고르려고 할 때, 고를 수 있는 방법의 가지수를 구하시오.",
        "question_en": "If you are trying to choose 6 out of 7 black pens, find the number of ways in which you can choose.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "7 6 [OP_COMB]",
        "solution_abst_en": "7 6 [OP_COMB]",
        "solution_code_ko": "var_a = 7\nvar_b = 6\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))",
        "solution_code_en": "var_a = 7\nvar_b = 6\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))"
    },
    "4472": {
        "category": "Comparison",
        "question_ko": "희진이에게는 빨간 풍선이 10개, 파란 풍선이 8개, 노란 풍선이 5개, 초록 풍선이 6개 있습니다. 7개 이상인 풍선 중 개수가 가장 적은 풍선은 몇 개 있습니까?",
        "question_en": "Heejin has 10 red balloons, 8 blue balloons, 5 yellow balloons, and 6 green balloons. Of the 7 or more balloons, how many balloons have the smallest number?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "[OP_LIST_SOL] 10 8 5 6 [OP_LIST_EOL] 7 [OP_LIST_MORE_EQUAL] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 10 8 5 6 [OP_LIST_EOL] 7 [OP_LIST_MORE_EQUAL] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 10\nvar_b = 8\nvar_c = 5\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 7\nlist_b = []\nfor i in list_a:\n    if i >= var_e:\n        list_b.append(i)\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 10\nvar_b = 8\nvar_c = 5\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 7\nlist_b = []\nfor i in list_a:\n    if i >= var_e:\n        list_b.append(i)\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nprint(int(var_g))"
    },
    "4473": {
        "category": "Possibility",
        "question_ko": "지우와 지현이가 동전 1개씩을 가지고 있습니다. 각자 동전을 던질 때, 나올 수 있는 경우의 수는 몇 가지입니까?",
        "question_en": "Ji-woo and Ji-hyeon have one coin each. How many ways can each person flip a coin?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "2 2 [OP_PERM]",
        "solution_abst_en": "2 2 [OP_PERM]",
        "solution_code_ko": "var_a = 2\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))"
    },
    "4474": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 -2/3을 나누고 -4/5를 곱했더니 그 결과가 -1/2이었습니다. 어떤 수를 구하시오.",
        "question_en": "When you divide the number by -2/3 and multiply it by -4/5, the result is -1/2. Find the unknown number at the beginning.",
        "answer_ko": "0.42",
        "answer_en": "0.42",
        "solution_abst_ko": "-1/2 -4/5 [OP_DIV] -2/3 [OP_MUL]",
        "solution_abst_en": "-1/2 -4/5 [OP_DIV] -2/3 [OP_MUL]",
        "solution_code_ko": "var_a = -0.5\nvar_b = -0.8\nvar_c = var_a / var_b\nvar_d = -0.6666666666666666\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = -0.5\nvar_b = -0.8\nvar_c = var_a / var_b\nvar_d = -0.6666666666666666\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "4475": {
        "category": "Correspondence",
        "question_ko": "승민과 효주는 산책을 갔다. 승민이 효주에게 0.43리터(L)의 물을 주었을 때 두 사람이 가진 물의 양의 차이는 0.88리터(L)였다고 한다. 승민이 효주에게 물을 주기 전에 두 사람이 가진 물의 양의 차이를 구하십시오. 단, 승민이 효주보다 물이 많다.",
        "question_en": "Seungmin and Hyoju went for a walk. When Seungmin gave Hyoju 0.43 liters (l) of water, the difference in the amount of water they had was 0.88 liters (l). Find the difference in the amount of water they had before Seungmin gave Hyoju water. However, Seungmin has more water than Heoju.",
        "answer_ko": "1.74",
        "answer_en": "1.74",
        "solution_abst_ko": "0.88 0.43 [OP_ADD] 0.43 [OP_ADD]",
        "solution_abst_en": "0.88 0.43 [OP_ADD] 0.43 [OP_ADD]",
        "solution_code_ko": "var_a = 0.88\nvar_b = 0.43\nvar_c = var_a + var_b\nvar_d = 0.43\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.88\nvar_b = 0.43\nvar_c = var_a + var_b\nvar_d = 0.43\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "4476": {
        "category": "Possibility",
        "question_ko": "1부터 9까지의 홀수를 중복 사용하여 만들 수 있는 3자리 자연수 중 500미만인 수는 모두 몇 개인지 구하시오.",
        "question_en": "Find how many 3-digit natural numbers that can be formed by multiplying odd numbers from 1 to 9 are less than 500.",
        "answer_ko": "12750",
        "answer_en": "12750",
        "solution_abst_ko": "1 9 [OP_LIST_ODD] 3 [OP_LIST_GET_PRODUCT] 500 [OP_LIST_LESS] [OP_LIST_SUM]",
        "solution_abst_en": "1 9 [OP_LIST_ODD] 3 [OP_LIST_GET_PRODUCT] 500 [OP_LIST_LESS] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = 500\nlist_c = []\nfor i in list_b:\n    if i < var_d:\n        list_c.append(i)\nlist_c = [float(i) for i in list_c]\nvar_e = sum(list_c)\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = 500\nlist_c = []\nfor i in list_b:\n    if i < var_d:\n        list_c.append(i)\nlist_c = [float(i) for i in list_c]\nvar_e = sum(list_c)\nprint(int(var_e))"
    },
    "4477": {
        "category": "Arithmetic calculation",
        "question_ko": "12에 3을 더한 수와 12에 A를 뺀 수를 곱하였더니 120이 나왔다. A를 구해라.",
        "question_en": "Multiplying 12 plus 3 by 12 minus A gives 120. Find A.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "12 120 12 3 [OP_ADD] [OP_DIV] [OP_SUB]",
        "solution_abst_en": "12 120 12 3 [OP_ADD] [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 12\nvar_b = 120\nvar_c = 12\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = var_b / var_e\nvar_g = var_a - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 12\nvar_b = 120\nvar_c = 12\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = var_b / var_e\nvar_g = var_a - var_f\nprint(int(var_g))"
    },
    "4478": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.9의 숫자가 있다. 이 중 0.3보다 크거나 같은 숫자들의 합을 구하시오.",
        "question_en": "There are numbers 0.8, 1/2, and 0.9. Find the sum of the numbers greater than or equal to 0.3.",
        "answer_ko": "2.20",
        "answer_en": "2.2",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 0.3 [OP_LIST_MORE_EQUAL] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 0.3 [OP_LIST_MORE_EQUAL] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.3\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.3\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "4479": {
        "category": "Correspondence",
        "question_ko": "A는 10개씩 묶음이 8개와 1개씩 낱개가 13개인 수입니다. B는 30에서 9씩 작아지게 3번 뛰어서 센 수입니다. A를 B로 나눈 몫을 구하시오.",
        "question_en": "A is the number of 8 groups of 10 and 13 groups of 1. B is the number that is decreased by 9 for three times from 30. Find the quotient of A divided by B.",
        "answer_ko": "31",
        "answer_en": "31",
        "solution_abst_ko": "10 8 [OP_MUL] 1 13 [OP_MUL] [OP_ADD] 30 9 3 [OP_MUL] [OP_SUB] [OP_DIV]",
        "solution_abst_en": "10 8 [OP_MUL] 1 13 [OP_MUL] [OP_ADD] 30 9 3 [OP_MUL] [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 13\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 30\nvar_i = 9\nvar_j = 3\nvar_k = var_i * var_j\nvar_l = var_h - var_k\nvar_m = var_g / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 10\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 13\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 30\nvar_i = 9\nvar_j = 3\nvar_k = var_i * var_j\nvar_l = var_h - var_k\nvar_m = var_g / var_l\nprint(int(var_m))"
    },
    "4480": {
        "category": "Correspondence",
        "question_ko": "두 개의 자연수 A와 B가 있습니다. A를 B로 나눈 몫이 9이고 나머지가 13이면 A를 9로 나눈 나머지는 얼마입니까?",
        "question_en": "There are two natural numbers A and B. If the quotient of A divided by B is 9 and the remainder is 13, what is the remainder of A divided by 9?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "13 9 [OP_SUB]",
        "solution_abst_en": "13 9 [OP_SUB]",
        "solution_code_ko": "var_a = 13\nvar_b = 9\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 13\nvar_b = 9\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "4481": {
        "category": "Possibility",
        "question_ko": "정사면체에서 모서리의 개수는 모두 몇개인가요?",
        "question_en": "How many edges are there in a regular tetrahedron?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "3 2 [OP_MUL]",
        "solution_abst_en": "3 2 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "4482": {
        "category": "Correspondence",
        "question_ko": "어떤 수의 절반에서 300을 빼면 350이 된다. 어떤 수에 200을 더하고 그 값에 2배를 하면 얼마인지 구하시오.",
        "question_en": "Subtract 300 from half of a number and you can get 350. What is the vaule of adding 200 to this number and multiplying it by 2?",
        "answer_ko": "3000",
        "answer_en": "3000",
        "solution_abst_ko": "350 300 [OP_ADD] 1 1/2 [OP_SUB] [OP_DIV] 200 [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "350 300 [OP_ADD] 1 1/2 [OP_SUB] [OP_DIV] 200 [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 350\nvar_b = 300\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 0.5\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 200\nvar_i = var_g + var_h\nvar_j = 2\nvar_k = var_i * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 350\nvar_b = 300\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 0.5\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 200\nvar_i = var_g + var_h\nvar_j = 2\nvar_k = var_i * var_j\nprint(int(var_k))"
    },
    "4483": {
        "category": "Comparison",
        "question_ko": "재호와 경환은 같은 시간 산책을 했다. 재호는 10.2킬로미터(㎞)의 1/100만큼 걸었고, 경환은 100미터(m)를 걸었다. 누가 더 멀리 갔는가?",
        "question_en": "Jaeho and Kyunghwan took a walk at the same time. Jaeho walked 1/100 of 10.2 kilometers (km), and Kyunghwan walked 100 meters (m). Who has gone farther?",
        "answer_ko": "재호",
        "answer_en": "Jaeho",
        "solution_abst_ko": "[OP_LIST_SOL] 재호 경환 [OP_LIST_EOL] [OP_LIST_SOL] 10.2 1000 [OP_MUL] 100 [OP_DIV] 100 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jaeho Kyunghwan [OP_LIST_EOL] [OP_LIST_SOL] 10.2 1000 [OP_MUL] 100 [OP_DIV] 100 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '재호'\nvar_b = '경환'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10.2\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 100\nvar_g = var_e / var_f\nvar_h = 100\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Jaeho'\nvar_b = 'Kyunghwan'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10.2\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 100\nvar_g = var_e / var_f\nvar_h = 100\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "4484": {
        "category": "Arithmetic calculation",
        "question_ko": "2개의 수 3, 5로 나누어 떨어질 수 있는 수 중 가장 작은 네 자리 수는?",
        "question_en": "What is the smallest four-digit number divisible by two numbers - 3 and 5?",
        "answer_ko": "1005",
        "answer_en": "1005",
        "solution_abst_ko": "1000 9999 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "1000 9999 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[var_f-1]\nprint(int(var_g))"
    },
    "4485": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 각각 8, 10인 두 정사각형의 넓이의 합을 구하시오.",
        "question_en": "Find the sum of the areas of two squares with side lengths of 8 and 10 respectively.",
        "answer_ko": "164",
        "answer_en": "164",
        "solution_abst_ko": "8 2 [OP_POW] 10 2 [OP_POW] [OP_ADD]",
        "solution_abst_en": "8 2 [OP_POW] 10 2 [OP_POW] [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 10\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 8\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 10\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "4486": {
        "category": "Geometry",
        "question_ko": "정사각형의 네 변의 길이의 합이 24미터(m)라면 한 변의 길이는 몇 미터(m)입니까?",
        "question_en": "If the sum of the lengths of the four sides of a square is 24 meters (m), what is the length of one side of the square in meters (m)?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "24 4 [OP_DIV]",
        "solution_abst_en": "24 4 [OP_DIV]",
        "solution_code_ko": "var_a = 24\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 24\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "4487": {
        "category": "Possibility",
        "question_ko": "1, 3, 7, 8의 숫자가 적혀진 종이 네 장이 있다. 이 중 2 장을 차례로 뽑아 처음 뽑은 것을 십의 자리로, 두 번째 뽑은 수를 일의 자리로 할 때 40이하의 수가 나오는 경우는 총 몇가지인지 구하시오.",
        "question_en": "There are four pieces of paper with the numbers 1, 3, 7, and 8 written on them. If two cards are drawn in order and the first number drawn is the tens place, and the second number drawn is the ones place, how many total numbers are less than 40?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 7 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 40 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 7 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 40 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 7\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 40\nlist_c = []\nfor i in list_b:\n    if i <= var_f:\n        list_c.append(i)\nvar_g = len(list_c)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 7\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 40\nlist_c = []\nfor i in list_b:\n    if i <= var_f:\n        list_c.append(i)\nvar_g = len(list_c)\nprint(int(var_g))"
    },
    "4488": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 1.36 을 곱해야 하는데 잘못하여 나누었더니 몫이 0.5 가 되었습니다. 바르게 계산하면 얼마입니까?",
        "question_en": "A certain number needs to be multiplied by 1.36, but you mistakenly divided it and the quotient is 0.5. How much do you calculate correctly?",
        "answer_ko": "0.92",
        "answer_en": "0.92",
        "solution_abst_ko": "0.5 1.36 [OP_MUL] 1.36 [OP_MUL]",
        "solution_abst_en": "0.5 1.36 [OP_MUL] 1.36 [OP_MUL]",
        "solution_code_ko": "var_a = 0.5\nvar_b = 1.36\nvar_c = var_a * var_b\nvar_d = 1.36\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.5\nvar_b = 1.36\nvar_c = var_a * var_b\nvar_d = 1.36\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "4489": {
        "category": "Correspondence",
        "question_ko": "각 자리의 수가 모두 다르고, 각 자리 수의 합은 9인 세 자리 수는 모두 몇 개입니까?",
        "question_en": "How many 3-digit numbers are there where each digit is different and the sum of each digit is 9?",
        "answer_ko": "34",
        "answer_en": "34",
        "solution_abst_ko": "0 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 9 [OP_LIST_MORE_EQUAL] 9 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "0 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 9 [OP_LIST_MORE_EQUAL] 9 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 9\nlist_d = []\nfor i in list_c:\n    if i >= var_f:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nfor i in list_d:\n    if i <= var_g:\n        list_e.append(i)\nvar_h = len(list_e)\nprint(int(var_h))",
        "solution_code_en": "var_a = 0\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 9\nlist_d = []\nfor i in list_c:\n    if i >= var_f:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nfor i in list_d:\n    if i <= var_g:\n        list_e.append(i)\nvar_h = len(list_e)\nprint(int(var_h))"
    },
    "4490": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 2를 더한 값은 어떤 수의 3배보다 8만큼 작다고 할 때, 어떤 수를 구하시오.",
        "question_en": "When a number plus 2 is 8 less than 3 times the number, find the number.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "2 8 [OP_ADD] 3 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "2 8 [OP_ADD] 3 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 2\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 2\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))"
    },
    "4491": {
        "category": "Correspondence",
        "question_ko": "승우는 여행을 가면서 35리터(L) 500밀리리터(㎖)의 콜라와 27리터(L) 200밀리리터(㎖)의 사이다를 가져갔다. 그 중 콜라 1리터(L) 750밀리리터(㎖)를 마셨다. 승우에게 남은 음료수는 모두 몇 리터(L) 입니까?",
        "question_en": "Seungwoo took 35 liters (L) and 500 milliliters (㎖) of coke and 27 liters (L) and 200 milliliters (㎖) of cider while traveling. Among them, he drank 1 liter (L) and 750 milliliters (㎖) of coke. How many liters (L) are all the drinks left for Seungwoo?",
        "answer_ko": "60.95",
        "answer_en": "60.95",
        "solution_abst_ko": "35 500 1000 [OP_DIV] [OP_ADD] 1 750 1000 [OP_DIV] [OP_ADD] [OP_SUB] 27 200 1000 [OP_DIV] [OP_ADD] [OP_ADD]",
        "solution_abst_en": "35 500 1000 [OP_DIV] [OP_ADD] 1 750 1000 [OP_DIV] [OP_ADD] [OP_SUB] 27 200 1000 [OP_DIV] [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 35\nvar_b = 500\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 1\nvar_g = 750\nvar_h = 1000\nvar_i = var_g / var_h\nvar_j = var_f + var_i\nvar_k = var_e - var_j\nvar_l = 27\nvar_m = 200\nvar_n = 1000\nvar_o = var_m / var_n\nvar_p = var_l + var_o\nvar_q = var_k + var_p\nprint('{:.2f}'.format(round(var_q+1e-10,2)))",
        "solution_code_en": "var_a = 35\nvar_b = 500\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 1\nvar_g = 750\nvar_h = 1000\nvar_i = var_g / var_h\nvar_j = var_f + var_i\nvar_k = var_e - var_j\nvar_l = 27\nvar_m = 200\nvar_n = 1000\nvar_o = var_m / var_n\nvar_p = var_l + var_o\nvar_q = var_k + var_p\nprint('{:.2f}'.format(round(var_q+1e-10,2)))"
    },
    "4492": {
        "category": "Arithmetic calculation",
        "question_ko": "25,000원으로 3,000원짜리 장미 2송이와 2,800원짜리 백합 몇 송이를 샀습니다. 거스름돈으로 2,200원을 받으려면, 백합은 몇 송이를 사야 하는지 구하시오.",
        "question_en": "With 25,000 won, you bought two roses for 3,000 won and several lilies for 2,800 won. To get 2,200 won in change, find how many lilies you need to buy.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "25000 2200 [OP_SUB] 3000 2 [OP_MUL] [OP_SUB] 2800 [OP_DIV]",
        "solution_abst_en": "25000 2200 [OP_SUB] 3000 2 [OP_MUL] [OP_SUB] 2800 [OP_DIV]",
        "solution_code_ko": "var_a = 25000\nvar_b = 2200\nvar_c = var_a - var_b\nvar_d = 3000\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 2800\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 25000\nvar_b = 2200\nvar_c = var_a - var_b\nvar_d = 3000\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 2800\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "4493": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 5센티미터(㎝)인 정육각형의 둘레는 몇 센티미터(㎝)입니까?",
        "question_en": "What is the perimeter of a regular hexagon with a side length of 5 centimeters (cm), in centimeters (cm)?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "5 6 [OP_MUL]",
        "solution_abst_en": "5 6 [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 6\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 6\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "4494": {
        "category": "Comparison",
        "question_ko": "지름의 길이가 10센티미터(㎝)인 원 A와 반지름의 길이가 4센티미터(㎝)인 원 B 중 넓이가 더 넓은 원은 무엇인가요?",
        "question_en": "Which circle has the greater area: circle A with a diameter of 10 centimeters (cm) and circle B with a radius of 4 centimeters (cm)?",
        "answer_ko": "A",
        "answer_en": "A",
        "solution_abst_ko": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 10 2 [OP_DIV] 4 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 10 2 [OP_DIV] 4 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 4\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 4\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "4495": {
        "category": "Arithmetic calculation",
        "question_ko": "100이하의 짝수들의 합과, 30이하의 홀수들의 합의 차를 구하시오.",
        "question_en": "Find the difference between the sum of even numbers less than or equal to 100 and the sum of odd numbers less than or equal to 30.",
        "answer_ko": "2325",
        "answer_en": "2325",
        "solution_abst_ko": "0 100 [OP_LIST_EVEN] [OP_LIST_SUM] 0 30 [OP_LIST_ODD] [OP_LIST_SUM] [OP_SUB]",
        "solution_abst_en": "0 100 [OP_LIST_EVEN] [OP_LIST_SUM] 0 30 [OP_LIST_ODD] [OP_LIST_SUM] [OP_SUB]",
        "solution_code_ko": "var_a = 0\nvar_b = 100\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nvar_d = 0\nvar_e = 30\nlist_b = []\nif var_d%2==0:\n    for i in range(var_d+1, var_e+1, 2):\n        list_b.append(i)\nelse:\n    for i in range(var_d, var_e+1, 2):\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 0\nvar_b = 100\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nvar_d = 0\nvar_e = 30\nlist_b = []\nif var_d%2==0:\n    for i in range(var_d+1, var_e+1, 2):\n        list_b.append(i)\nelse:\n    for i in range(var_d, var_e+1, 2):\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "4496": {
        "category": "Possibility",
        "question_ko": "1부터 9까지 9개의 숫자를 한 번씩 사용하여 아홉 자리 수를 만들었다. 이 수가 55의 배수일 때, 가장 작은 아홉자리 수를 구하여라.",
        "question_en": "Nine digits from 1 to 9 are used once to form a nine-digit number. If this number is a multiple of 55, find the smallest 9-digit number.",
        "answer_ko": "126374985",
        "answer_en": "126374985",
        "solution_abst_ko": "1 9 1 [OP_LIST_ARANGE] 9 [OP_LIST_GET_PERM] 55 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "1 9 1 [OP_LIST_ARANGE] 9 [OP_LIST_GET_PERM] 55 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 9\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 55\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 9\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 55\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[var_f-1]\nprint(int(var_g))"
    },
    "4497": {
        "category": "Possibility",
        "question_ko": "장난감 로봇은 3가지의 형태로 변신할 수 있고, 4가지의 다른 색을 칠할 수 있습니다. 모두 몇 가지의 모양의 로봇이 있습니까?",
        "question_en": "The toy robot can transform into 3 different shapes and can be painted in 4 different colors. How many possible types of robots are there in all?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "3 4 [OP_MUL]",
        "solution_abst_en": "3 4 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "4498": {
        "category": "Geometry",
        "question_ko": "어떤 직사각형의 세로의 길이는 36센티미터(㎝)이고 가로의 길이는 64센티미터(㎝)입니다. 이 직사각형의 둘레의 길이와 같은 둘레의 길이를 갖는 정사각형이 있습니다. 이 정사각형의 둘레의 길이를 4등분했을 때의 값을 구하시오.",
        "question_en": "The height of a rectangle is 36 centimeters (cm) and the length of its width is 64 centimeters (cm). There is a square with a perimeter equal to the perimeter of this rectangle. Find the value of dividing the perimeter of this square into 4 equal parts.",
        "answer_ko": "50",
        "answer_en": "50",
        "solution_abst_ko": "36 64 [OP_ADD] 2 [OP_MUL] 4 [OP_DIV]",
        "solution_abst_en": "36 64 [OP_ADD] 2 [OP_MUL] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 36\nvar_b = 64\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 36\nvar_b = 64\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "4499": {
        "category": "Correspondence",
        "question_ko": "3×A-A=10, B+A=12, C-B=6의 방정식들이 있습니다. A, B, C가 서로 다른 자연수 일때, 방정식을 만족하는 C의 값은 무엇인가요?",
        "question_en": "There are equations of 3×A-A=10, B+A=12, C-B=6. If A, B, and C are different natural numbers, what value of C satisfies the equation?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "12 3×A-A=10 A [OP_NUM_UNK_SOLVER] [OP_SUB] 6 [OP_ADD]",
        "solution_abst_en": "12 3×A-A=10 A [OP_NUM_UNK_SOLVER] [OP_SUB] 6 [OP_ADD]",
        "solution_code_ko": "var_a = 12\nvar_b = '3×A-A=10'\nvar_c = 'A'\nans_dict = dict()\nvar_b = var_b.replace('×','*')\nvar_b = var_b.replace('x','*')\nvar_b = var_b.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_b):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_b\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_d = ans_dict[var_c]\nvar_e = var_a - var_d\nvar_f = 6\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 12\nvar_b = '3×A-A=10'\nvar_c = 'A'\nans_dict = dict()\nvar_b = var_b.replace('×','*')\nvar_b = var_b.replace('x','*')\nvar_b = var_b.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_b):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_b\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_d = ans_dict[var_c]\nvar_e = var_a - var_d\nvar_f = 6\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "4500": {
        "category": "Arithmetic calculation",
        "question_ko": "3/2, 2.3, 1/5, 1.1, 5/2, 4/5의 6 숫자 중 1보다는 크고 2보다는 작은 숫자만 골라서 개수를 세시오.",
        "question_en": "Among the 6 numbers 3/2, 2.3, 1/5, 1.1, 5/2, and 4/5, select the numbers greater than 1 and less than 2 and count them.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 3/2 2.3 1/5 1.1 5/2 4/5 [OP_LIST_EOL] 1 [OP_LIST_MORE] 2 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 3/2 2.3 1/5 1.1 5/2 4/5 [OP_LIST_EOL] 1 [OP_LIST_MORE] 2 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1.5\nvar_b = 2.3\nvar_c = 0.2\nvar_d = 1.1\nvar_e = 2.5\nvar_f = 0.8\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 1\nlist_b = []\nfor i in list_a:\n    if i > var_g:\n        list_b.append(i)\nvar_h = 2\nlist_c = []\nfor i in list_b:\n    if i < var_h:\n        list_c.append(i)\nvar_i = len(list_c)\nprint(int(var_i))",
        "solution_code_en": "var_a = 1.5\nvar_b = 2.3\nvar_c = 0.2\nvar_d = 1.1\nvar_e = 2.5\nvar_f = 0.8\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 1\nlist_b = []\nfor i in list_a:\n    if i > var_g:\n        list_b.append(i)\nvar_h = 2\nlist_c = []\nfor i in list_b:\n    if i < var_h:\n        list_c.append(i)\nvar_i = len(list_c)\nprint(int(var_i))"
    },
    "4501": {
        "category": "Possibility",
        "question_ko": "다섯 개의 숫자 0, 1, 2, 3, 4, 5 중에서 2개를 골라 두 자리의 수를 만들었다. 같은 수를 여러 번 사용해도 된다면, 만들 수 있는 모든 수들은 모두 몇개인가?",
        "question_en": "You chose two of the five numbers 0, 1, 2, 3, 4, and 5 to make two-digit numbers. If you can use the same number multiple times, how many numbers can you make in total?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 4 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PRODUCT] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 4 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PRODUCT] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nvar_f = 5\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = len(list_b)\nprint(int(var_h))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nvar_f = 5\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = len(list_b)\nprint(int(var_h))"
    },
    "4502": {
        "category": "Arithmetic calculation",
        "question_ko": "1이상 100이하의 모든 짝수의 합을 A, 모든 홀수의 합을 B라고 할 때 A와 B의 차는 얼마인가?",
        "question_en": "From 1 to 100, A is the sum of all even numbers, and B is the sum of all odd numbers. What is the difference of A and B?",
        "answer_ko": "50",
        "answer_en": "50",
        "solution_abst_ko": "1 100 [OP_LIST_EVEN] [OP_LIST_SUM] 1 100 [OP_LIST_ODD] [OP_LIST_SUM] [OP_SUB]",
        "solution_abst_en": "1 100 [OP_LIST_EVEN] [OP_LIST_SUM] 1 100 [OP_LIST_ODD] [OP_LIST_SUM] [OP_SUB]",
        "solution_code_ko": "var_a = 1\nvar_b = 100\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nvar_d = 1\nvar_e = 100\nlist_b = []\nif var_d%2==0:\n    for i in range(var_d+1, var_e+1, 2):\n        list_b.append(i)\nelse:\n    for i in range(var_d, var_e+1, 2):\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 100\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nvar_d = 1\nvar_e = 100\nlist_b = []\nif var_d%2==0:\n    for i in range(var_d+1, var_e+1, 2):\n        list_b.append(i)\nelse:\n    for i in range(var_d, var_e+1, 2):\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "4503": {
        "category": "Geometry",
        "question_ko": "세로의 길이가 300미터(m)인 직사각형 모양의 밭이 8개 있습니다. 각각의 밭의 넓이가 모두 같고 밭의 전체 넓이가 0.6제곱킬로미터(㎢)라면 밭의 가로의 길이는 몇 미터(m)입니까?",
        "question_en": "There are 8 rectangular fields with a length of 300 meters (m). If the area of each field is the same and the total area of the fields is 0.6 square kilometers (km2), how many meters (m) is the width of the field?",
        "answer_ko": "250",
        "answer_en": "250",
        "solution_abst_ko": "0.6 1000 1000 [OP_MUL] [OP_MUL] 8 [OP_DIV] 300 [OP_DIV]",
        "solution_abst_en": "0.6 1000 1000 [OP_MUL] [OP_MUL] 8 [OP_DIV] 300 [OP_DIV]",
        "solution_code_ko": "var_a = 0.6\nvar_b = 1000\nvar_c = 1000\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nvar_f = 8\nvar_g = var_e / var_f\nvar_h = 300\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 0.6\nvar_b = 1000\nvar_c = 1000\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nvar_f = 8\nvar_g = var_e / var_f\nvar_h = 300\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "4504": {
        "category": "Arithmetic calculation",
        "question_ko": "선호는 지갑에 있던 돈의 1/4로 간식을 사 먹고, 남은 돈의 2/3은 준비물을 사는 데 썼을 때, 지금 선호가 가진 돈이 2500원이라면 처음 선호의 지갑에 있던 돈은 얼마입니까?",
        "question_en": "Seonho has 2,500 won after spending 1/4 of the money in his wallet to buy snacks and 2/3 of the remaining money to buy food. How much money is in his wallet?",
        "answer_ko": "10000",
        "answer_en": "10000",
        "solution_abst_ko": "2500 1 1/4 [OP_SUB] [OP_DIV] 1 2/3 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "2500 1 1/4 [OP_SUB] [OP_DIV] 1 2/3 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 2500\nvar_b = 1\nvar_c = 0.25\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 1\nvar_g = 0.6666666666666666\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 2500\nvar_b = 1\nvar_c = 0.25\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 1\nvar_g = 0.6666666666666666\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "4505": {
        "category": "Arithmetic calculation",
        "question_ko": "유정이는 손가락을 2개 접었고, 유나는 5개 접었습니다. 두 사람이 접은 손가락은 몇 개입니까?",
        "question_en": "Yoojung folded two fingers, and Yuna folded five. How many fingers do two people fold?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "2 5 [OP_ADD]",
        "solution_abst_en": "2 5 [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "4506": {
        "category": "Arithmetic calculation",
        "question_ko": "호석이의 국어와 수학 두 과목의 평균 점수는 88점입니다. 국어, 수학, 영어 세 과목의 평균 점수가 90점일 때, 호석이의 영어 점수는 몇 점입니까?",
        "question_en": "Hoseok's average score in Korean and Mathematics is 88 points. If the average score of Korean, Mathematics, and English is 90, what is Hoseok's English score?",
        "answer_ko": "94",
        "answer_en": "94",
        "solution_abst_ko": "90 3 [OP_MUL] 88 2 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "90 3 [OP_MUL] 88 2 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 90\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 88\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 90\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 88\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "4507": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 217센티미터(㎝)인 줄 3개를 묶어 길게 이었습니다. 묶인 부분의 줄의 길이는 같고, 이은 줄의 길이가 627센티미터(㎝)이면, 줄이 묶인 부분의 한 개의 길이는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "Three 217 centimeters (cm) long strings are tied together. If the length of the string at the tied part is the same and the length of the tied string is 627 centimeters (cm), find how many centimeters (cm) is the length of one part of the tied part.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "217 3 [OP_MUL] 627 [OP_SUB] 3 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "217 3 [OP_MUL] 627 [OP_SUB] 3 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 217\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 627\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 217\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 627\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "4508": {
        "category": "Arithmetic calculation",
        "question_ko": "1톤짜리 물건 48개를 옮기려고 합니다. 4톤까지 실을 수 있는 트럭을 가득 채워 6대씩 한 번에 이동하여 물건을 나르려면 모두 몇 번 날라야 합니까?",
        "question_en": "48 objects which weigh a one-metric ton (m/t) have to be moved. How many moves are needed to make if trucks can carry up to 4 metric tons (m/t) at a time and 6 trucks move at once?  ",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "48 4 6 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "48 4 6 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 48\nvar_b = 4\nvar_c = 6\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 48\nvar_b = 4\nvar_c = 6\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "4509": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 17을 곱했더니 493이 되었습니다. 어떤 수를 구하시오.",
        "question_en": "When you multiply a number by 17, you get 493. Find the number.",
        "answer_ko": "29",
        "answer_en": "29",
        "solution_abst_ko": "493 17 [OP_DIV]",
        "solution_abst_en": "493 17 [OP_DIV]",
        "solution_code_ko": "var_a = 493\nvar_b = 17\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 493\nvar_b = 17\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "4510": {
        "category": "Geometry",
        "question_ko": "반지름이 2센티미터(㎝)인 원의 넓이의 4배가 어떤 원의 넓이와 같다. 어떤 원의 반지름의 크기를 구하시오.",
        "question_en": "The area of a circle is equal to four times the area of the other circle with a radius of 2 cm. Find the size of the radius of the other circle.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "4 2 2 [OP_POW] [OP_MUL] 1/2 [OP_POW]",
        "solution_abst_en": "4 2 2 [OP_POW] [OP_MUL] 1/2 [OP_POW]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = 2\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 0.5\nvar_g = var_e ** var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = 2\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 0.5\nvar_g = var_e ** var_f\nprint(int(var_g))"
    },
    "4511": {
        "category": "Possibility",
        "question_ko": "연필이 3 종류, 지우개가 2종류, 공책이 5종류가 있을 때, 연필, 지우개, 공책을 각각 1 종류씩 사는 방법을 모두 몇 가지인지 구하시오.",
        "question_en": "If there are 3 types of pencils, 2 types of erasers, and 5 types of notebooks, find how many ways there are to buy 1 type of pencil, 1 type of eraser, and 1 type of notebook.",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "3 2 [OP_MUL] 5 [OP_MUL]",
        "solution_abst_en": "3 2 [OP_MUL] 5 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "4512": {
        "category": "Arithmetic calculation",
        "question_ko": "분속 400미터(m)를 달리는 기차가 있습니다. 1.625킬로미터(㎞)인 다리를 완전히 통과하려면 몇 분 걸리나요? 기차의 길이는 115미터(m)입니다.",
        "question_en": "There is a train that runs at 400 meters (m) per minute. How many minutes does it take to completely cross the 1.625 kilometer (km) bridge? The length of the train is 115 meters (m).",
        "answer_ko": "4.35",
        "answer_en": "4.35",
        "solution_abst_ko": "115 1.625 1000 [OP_MUL] [OP_ADD] 400 [OP_DIV]",
        "solution_abst_en": "115 1.625 1000 [OP_MUL] [OP_ADD] 400 [OP_DIV]",
        "solution_code_ko": "var_a = 115\nvar_b = 1.625\nvar_c = 1000\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nvar_f = 400\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 115\nvar_b = 1.625\nvar_c = 1000\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nvar_f = 400\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "4513": {
        "category": "Possibility",
        "question_ko": "A, B, C, D, E, F 6명의 시민이 있을 때, 국회의원 3명을 뽑는 경우의 수를 구하시오.",
        "question_en": "If there are 6 citizens A, B, C, D, E, and F, find the number of ways to elect 3 members for the National Assembly.",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "[OP_LIST_SOL] A B C D E F [OP_LIST_EOL] [OP_LIST_LEN] 3 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D E F [OP_LIST_EOL] [OP_LIST_LEN] 3 [OP_COMB]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nvar_f = 'F'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = len(list_a)\nvar_h = 3\nvar_i = 1\nvar_g = int(var_g)\nvar_h = int(var_h)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i * (var_g-i)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i / (i+1)\nprint(int(var_i))",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nvar_f = 'F'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = len(list_a)\nvar_h = 3\nvar_i = 1\nvar_g = int(var_g)\nvar_h = int(var_h)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i * (var_g-i)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i / (i+1)\nprint(int(var_i))"
    },
    "4514": {
        "category": "Possibility",
        "question_ko": "숫자 카드 0, 1, 2, 4, 9 중에서 4장을 뽑아 만들 수 있는 자연수의 개수를 구하시오.",
        "question_en": "Find the number of natural numbers that can be made by picking four of the number cards 0, 1, 2, 4, and 9.",
        "answer_ko": "96",
        "answer_en": "96",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 4 9 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 4 9 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 4\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 4\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "4515": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 3번째로 작은 수와 2번째로 작은 수로 나눈 나머지는 얼마입니까?",
        "question_en": "There are five numbers 10, 11, 12, 13, and 14. What is the remainder when the 3rd smallest number is divided by the 2nd smallest number?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 3 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_MOD]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 3 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_MOD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g % var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g % var_i\nprint(int(var_j))"
    },
    "4516": {
        "category": "Correspondence",
        "question_ko": "과수원에서 수확한 132.6킬로그램(㎏)의 사과를 각 트럭에 동일한 무게로 나누어 담았더니 한 트럭당 13.26킬로그램(㎏)을 실었다. 만약 이 트럭들에 6.4킬로그램(㎏)의 바나나를 나눠 담는다면 한 트럭당 몇 킬로그램(㎏)의 바나나를 실겠는가?",
        "question_en": "When 132.6 kilograms (kg) of apples harvested from the orchard were divided into equal weights in each truck, each truck loaded 13.26 kilograms (kg). If 6.4 kilograms (kg) of bananas are divided among these trucks, how many kilograms (kg) of bananas will be loaded per truck?",
        "answer_ko": "0.64",
        "answer_en": "0.64",
        "solution_abst_ko": "6.4 132.6 13.26 [OP_DIV] [OP_DIV]",
        "solution_abst_en": "6.4 132.6 13.26 [OP_DIV] [OP_DIV]",
        "solution_code_ko": "var_a = 6.4\nvar_b = 132.6\nvar_c = 13.26\nvar_d = var_b / var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 6.4\nvar_b = 132.6\nvar_c = 13.26\nvar_d = var_b / var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "4517": {
        "category": "Correspondence",
        "question_ko": "63는 어떤 수에서 29를 빼서 나온 결과입니다. 어떤 수보다 47작은 수를 구하시오.",
        "question_en": "63 is the result of subtracting 29 from a number. Find the value which is 47 less than this number.",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "63 29 [OP_ADD] 47 [OP_SUB]",
        "solution_abst_en": "63 29 [OP_ADD] 47 [OP_SUB]",
        "solution_code_ko": "var_a = 63\nvar_b = 29\nvar_c = var_a + var_b\nvar_d = 47\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 63\nvar_b = 29\nvar_c = var_a + var_b\nvar_d = 47\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "4518": {
        "category": "Geometry",
        "question_ko": "네 변의 길이의 합이 52센티미터(㎝)인 직사각형이 있습니다. 이 중 한 변의 길이가 11센티미터(㎝)라면 넓이는 얼마일지 구하시오.",
        "question_en": "A rectangle has a sum of four sides equal to 52 centimeters (cm). If the length of one of the sides is 11 centimeters (cm), what is the area?",
        "answer_ko": "165",
        "answer_en": "165",
        "solution_abst_ko": "11 52 2 [OP_DIV] 11 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "11 52 2 [OP_DIV] 11 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 11\nvar_b = 52\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = 11\nvar_f = var_d - var_e\nvar_g = var_a * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 11\nvar_b = 52\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = 11\nvar_f = var_d - var_e\nvar_g = var_a * var_f\nprint(int(var_g))"
    },
    "4519": {
        "category": "Possibility",
        "question_ko": "상자 한 세트에는 2개의 공이 들어 있습니다. 3개의 세트를 가졌을 때, 공의 개수는?",
        "question_en": "A set of boxes contains 2 balls. With a set of 3, how many balls are there?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "2 3 [OP_MUL]",
        "solution_abst_en": "2 3 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "4520": {
        "category": "Correspondence",
        "question_ko": "어떤 수의 3/10에서 8을 뺀 값은 12입니다. 어떤 수의 1/5은 얼마인지 구해 보시오.",
        "question_en": "3/10 of this number minus 8 is 12. Find what 1/5 of this number is.",
        "answer_ko": "13.33",
        "answer_en": "13.33",
        "solution_abst_ko": "12 8 [OP_ADD] 3/10 [OP_DIV] 1/5 [OP_MUL]",
        "solution_abst_en": "12 8 [OP_ADD] 3/10 [OP_DIV] 1/5 [OP_MUL]",
        "solution_code_ko": "var_a = 12\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 0.3\nvar_e = var_c / var_d\nvar_f = 0.2\nvar_g = var_e * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 12\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 0.3\nvar_e = var_c / var_d\nvar_f = 0.2\nvar_g = var_e * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "4521": {
        "category": "Possibility",
        "question_ko": "168의 각 자리의 숫자를 움직여 만들 수 있는 수 중 가장 작은 것과 세 번째로 작은 것의 합은 얼마인가?",
        "question_en": "What is the sum of the smallest and third smallest numbers that can be formed by moving each digit in 168?",
        "answer_ko": "786",
        "answer_en": "786",
        "solution_abst_ko": "168 [OP_NUM2LIST] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "168 [OP_NUM2LIST] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 168\nlist_a = []\nvar_a = int(var_a)\nwhile var_a//10 > 0:\n    list_a.append(var_a%10)\n    var_a = var_a//10\nlist_a.append(var_a%10)\nlist_a = list_a[::-1]\nvar_b = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_b))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_c = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_d = list_c[var_c-1]\nvar_e = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_f = list_d[var_e-1]\nvar_g = var_d + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 168\nlist_a = []\nvar_a = int(var_a)\nwhile var_a//10 > 0:\n    list_a.append(var_a%10)\n    var_a = var_a//10\nlist_a.append(var_a%10)\nlist_a = list_a[::-1]\nvar_b = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_b))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_c = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_d = list_c[var_c-1]\nvar_e = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_f = list_d[var_e-1]\nvar_g = var_d + var_f\nprint(int(var_g))"
    },
    "4522": {
        "category": "Comparison",
        "question_ko": "키가 작은 사람부터 순서대로 9명이 한 줄로 서 있습니다. 호석이는 뒤에서부터 4번째에 서 있고, 유나는 호석이로부터 3번째 뒤에 서 있습니다. 키가 큰 사람부터 순서대로 다시 줄을 서면 유나는 앞에서부터 몇 번째에 서게 됩니까?",
        "question_en": "Nine people are standing in a row in order from the short person. Hoseok is standing in second place from the back, and Yuna is standing right behind Hoseok. If you line up again starting with the tall person, which place will Yuna stand from the front?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "4 3 [OP_SUB]",
        "solution_abst_en": "4 3 [OP_SUB]",
        "solution_code_ko": "var_a = 4\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "4523": {
        "category": "Possibility",
        "question_ko": "0, 1, 2, 3, 4의 수가 각각 적힌 5장의 카드에서 3장을 뽑아 만들 수 있는 세 자리의 정수의 개수를 구하시오.",
        "question_en": "Find the number of three-digit integers that can be made by drawing 3 cards from 5 cards each containing the numbers 0, 1, 2, 3, 4.",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "4524": {
        "category": "Correspondence",
        "question_ko": "어느 쌀 가게에서 쌀 750킬로그램(㎏)을 들여 왔습니다. 쌀을 들여 온 첫 주에 쌀을 몇 킬로그램(㎏) 팔았고, 다음 주에 나머지 쌀의 3/5을 팔았고, 그 다음 주에 나머지 쌀의 5/8을 팔았더니 쌀이 75킬로그램(㎏) 남았습니다. 첫 주에는 몇 킬로그램(㎏)의 쌀을 팔았습니까?",
        "question_en": "A rice store bought 750 kilograms (kg) of rice. The first week they bought rice, they sold a few kilograms of rice, the next week they sold 3/5 of the remaining rice, and the next week they sold 5/8 of the remaining rice. 75 kg (kg) of rice was left 75 kg (kg) at the end. How many kilograms (kg) of rice did they sell in the first week?",
        "answer_ko": "250",
        "answer_en": "250",
        "solution_abst_ko": "750 75 1 5/8 [OP_SUB] [OP_DIV] 1 3/5 [OP_SUB] [OP_DIV] [OP_SUB]",
        "solution_abst_en": "750 75 1 5/8 [OP_SUB] [OP_DIV] 1 3/5 [OP_SUB] [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 750\nvar_b = 75\nvar_c = 1\nvar_d = 0.625\nvar_e = var_c - var_d\nvar_f = var_b / var_e\nvar_g = 1\nvar_h = 0.6\nvar_i = var_g - var_h\nvar_j = var_f / var_i\nvar_k = var_a - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 750\nvar_b = 75\nvar_c = 1\nvar_d = 0.625\nvar_e = var_c - var_d\nvar_f = var_b / var_e\nvar_g = 1\nvar_h = 0.6\nvar_i = var_g - var_h\nvar_j = var_f / var_i\nvar_k = var_a - var_j\nprint(int(var_k))"
    },
    "4525": {
        "category": "Arithmetic calculation",
        "question_ko": "장미가 58송이 있습니다. 튤립은 장미보다 15송이 더 적고, 백합은 장미보다 25송이 더 많습니다. 장미, 튤립, 백합 3종류의 꽃은 모두 몇 송이 있습니까?",
        "question_en": "There are 58 roses. The number of tulips is 15 less than the number of roses and the number of lilies is 25 more than the number of roses. What is the total number of roses, tulips, and lilies?",
        "answer_ko": "184",
        "answer_en": "184",
        "solution_abst_ko": "58 58 15 [OP_SUB] [OP_ADD] 58 25 [OP_ADD] [OP_ADD]",
        "solution_abst_en": "58 58 15 [OP_SUB] [OP_ADD] 58 25 [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 58\nvar_b = 58\nvar_c = 15\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 58\nvar_g = 25\nvar_h = var_f + var_g\nvar_i = var_e + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 58\nvar_b = 58\nvar_c = 15\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 58\nvar_g = 25\nvar_h = var_f + var_g\nvar_i = var_e + var_h\nprint(int(var_i))"
    },
    "4526": {
        "category": "Geometry",
        "question_ko": "부피가 49제곱센티미터(㎠)인 직육면체의 높이가 7센티미터(㎝)이다. 밑면의 넓이를 구하시오.",
        "question_en": "The height of a rectangular parallelepiped with a volume of 49 square centimeters (cm2) is 7 centimeters (cm). Find the area of the base.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "49 7 [OP_DIV]",
        "solution_abst_en": "49 7 [OP_DIV]",
        "solution_code_ko": "var_a = 49\nvar_b = 7\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 49\nvar_b = 7\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "4527": {
        "category": "Comparison",
        "question_ko": "밑면의 넓이가 8제곱센티미터(㎠)이고 높이가 3센티미터(㎝)인 직육면체 모양의 명함보관함과 한 변의 길이가 6센티미터(㎝)인 주사위 중 부피가 더 큰 것은 무엇인가요?",
        "question_en": "Which one has the greater volume, a card holder in the shape of a cuboid with a base area of 8 square centimeters (cm2) and a height of 3 centimeters (cm), or a dice with a side length of 6 centimeters (cm)?",
        "answer_ko": "주사위",
        "answer_en": "dice",
        "solution_abst_ko": "[OP_LIST_SOL] 명함보관함 주사위 [OP_LIST_EOL] [OP_LIST_SOL] 8 3 [OP_MUL] 5 5 [OP_MUL] 5 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] holder dice [OP_LIST_EOL] [OP_LIST_SOL] 8 3 [OP_MUL] 5 5 [OP_MUL] 5 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '명함보관함'\nvar_b = '주사위'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 8\nvar_d = 3\nvar_e = var_c * var_d\nvar_f = 5\nvar_g = 5\nvar_h = var_f * var_g\nvar_i = 5\nvar_j = var_h * var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'holder'\nvar_b = 'dice'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 8\nvar_d = 3\nvar_e = var_c * var_d\nvar_f = 5\nvar_g = 5\nvar_h = var_f * var_g\nvar_i = 5\nvar_j = var_h * var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "4528": {
        "category": "Correspondence",
        "question_ko": "한솔이는 기차를 타고 부산에 가고 있습니다. 도중에 승객 263명이 내리고, 419명이 탔습니다. 목적지인 부산에 도착하여 내리는 승객을 세어 보니 725명이었습니다. 처음에 기차에 타고 있던 승객은 몇 명이었습니까?",
        "question_en": "Hansol is going to Busan by train. On the way, 263 passengers got off and 419 got on. When he counted the number of passengers arriving at his destination, Busan, there were 725 passengers. How many passengers were on the train at first?",
        "answer_ko": "569",
        "answer_en": "569",
        "solution_abst_ko": "725 419 [OP_SUB] 263 [OP_ADD]",
        "solution_abst_en": "725 419 [OP_SUB] 263 [OP_ADD]",
        "solution_code_ko": "var_a = 725\nvar_b = 419\nvar_c = var_a - var_b\nvar_d = 263\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 725\nvar_b = 419\nvar_c = var_a - var_b\nvar_d = 263\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "4529": {
        "category": "Comparison",
        "question_ko": "4개의 숫자 5, 8, 3 2중 가장 작은 것은 무엇입니까?",
        "question_en": "Which of the four numbers among 5, 8, 3, 2 is the smallest?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 5 8 3 2 [OP_LIST_EOL] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 5 8 3 2 [OP_LIST_EOL] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 5\nvar_b = 8\nvar_c = 3\nvar_d = 2\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nprint(int(var_f))",
        "solution_code_en": "var_a = 5\nvar_b = 8\nvar_c = 3\nvar_d = 2\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nprint(int(var_f))"
    },
    "4530": {
        "category": "Possibility",
        "question_ko": "여섯 장의 숫자 카드 8, 3, 6, 5, 0, 7 중 두 장을 뽑아 만든 두 자리 수 중에서 두번째로 큰 수를 A, 세번째로 큰 수를 B라고 할 때, (A-B)×6의 값을 구하시오.",
        "question_en": "If you make two-digit numbers by picking two out of six number cards 8, 3, 6, 5, 0, 7, the second largest number is A and the third largest number is B. Find (A-B)×6.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 8 3 6 5 0 7 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 3 [OP_LIST_MAX] [OP_SUB] 6 [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 8 3 6 5 0 7 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 3 [OP_LIST_MAX] [OP_SUB] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 3\nvar_c = 6\nvar_d = 5\nvar_e = 0\nvar_f = 7\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_i = list_c[-var_h]\nvar_j = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_k = list_d[-var_j]\nvar_l = var_i - var_k\nvar_m = 6\nvar_n = var_l * var_m\nprint(int(var_n))",
        "solution_code_en": "var_a = 8\nvar_b = 3\nvar_c = 6\nvar_d = 5\nvar_e = 0\nvar_f = 7\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_i = list_c[-var_h]\nvar_j = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_k = list_d[-var_j]\nvar_l = var_i - var_k\nvar_m = 6\nvar_n = var_l * var_m\nprint(int(var_n))"
    },
    "4531": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 4로 나눠야 할 것을 25를 곱하였더니 812가 되었다. 바르게 계산한 값을 구하시오.",
        "question_en": "I multiplied a particular number by 25, when I should have divided that particular number by 4. As a result, I got 812. Find the correct calculated value.",
        "answer_ko": "8.12",
        "answer_en": "8.12",
        "solution_abst_ko": "812 25 [OP_DIV] 4 [OP_DIV]",
        "solution_abst_en": "812 25 [OP_DIV] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 812\nvar_b = 25\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 812\nvar_b = 25\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "4532": {
        "category": "Correspondence",
        "question_ko": "형이 10살이기 1년 전에 동생은 7살이고, 동생이 5살일 때 어머니는 32살입니다. 형이 12살일 때 동생과 어머니의 나이의 합을 구하시오.",
        "question_en": "One year before my older brother was 10, my younger brother was 7 years old, and my mother was 32 when my younger brother was 5 years old. Find the sum of the ages of the younger brother and mother when the older brother is 12 years old.",
        "answer_ko": "46",
        "answer_en": "46",
        "solution_abst_ko": "12 7 10 1 [OP_SUB] [OP_SUB] [OP_ADD] 12 7 10 [OP_SUB] [OP_ADD] 32 5 [OP_SUB] [OP_ADD] [OP_ADD]",
        "solution_abst_en": "12 7 10 1 [OP_SUB] [OP_SUB] [OP_ADD] 12 7 10 [OP_SUB] [OP_ADD] 32 5 [OP_SUB] [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 12\nvar_b = 7\nvar_c = 10\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = var_b - var_e\nvar_g = var_a + var_f\nvar_h = 12\nvar_i = 7\nvar_j = 10\nvar_k = var_i - var_j\nvar_l = var_h + var_k\nvar_m = 32\nvar_n = 5\nvar_o = var_m - var_n\nvar_p = var_l + var_o\nvar_q = var_g + var_p\nprint(int(var_q))",
        "solution_code_en": "var_a = 12\nvar_b = 7\nvar_c = 10\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = var_b - var_e\nvar_g = var_a + var_f\nvar_h = 12\nvar_i = 7\nvar_j = 10\nvar_k = var_i - var_j\nvar_l = var_h + var_k\nvar_m = 32\nvar_n = 5\nvar_o = var_m - var_n\nvar_p = var_l + var_o\nvar_q = var_g + var_p\nprint(int(var_q))"
    },
    "4533": {
        "category": "Possibility",
        "question_ko": "6개의 축구팀이 서로 한 번씩 시합을 가진다면 모두 몇 번의 시합이 이루어지는지 모두 구하시오",
        "question_en": "If 6 soccer teams play with each other once, how many matches will take place in total?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "6 2 [OP_COMB]",
        "solution_abst_en": "6 2 [OP_COMB]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))"
    },
    "4534": {
        "category": "Comparison",
        "question_ko": "집에서 공원까지의 거리는 3킬로미터(㎞)보다 150미터(m) 더 멀고 집에서 은행까지의 거리는 3095미터(m)입니다. 공원과 은행 중에서 집에서 더 먼 곳은 어느 곳입니까?",
        "question_en": "The distance from the house to the park is 150 meters (m) more than 3 kilometers (km), and the distance from the house to the bank is 3095 meters (m). Which is farther from home, the park or the bank?",
        "answer_ko": "공원",
        "answer_en": "park",
        "solution_abst_ko": "[OP_LIST_SOL] 공원 은행 [OP_LIST_EOL] [OP_LIST_SOL] 3 1000 [OP_MUL] 150 [OP_ADD] 3096 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] park bank [OP_LIST_EOL] [OP_LIST_SOL] 3 1000 [OP_MUL] 150 [OP_ADD] 3096 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '공원'\nvar_b = '은행'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 150\nvar_g = var_e + var_f\nvar_h = 3096\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'park'\nvar_b = 'bank'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 150\nvar_g = var_e + var_f\nvar_h = 3096\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "4535": {
        "category": "Geometry",
        "question_ko": "바닥에 가로가 30센티미터(㎝), 세로가 30센티미터(㎝)인 정사각형 모양의 바둑판을 8개씩 5줄 붙였습니다. 바둑판 위의 평면의 넓이가 몇 제곱미터 (m2)인지 구하시오.",
        "question_en": "5 rows of 8 square-shaped checkerboards that are each 30 centimeters (cm) wide and 30 centimeters (cm) long were attached on the floor. Find the area of the plane on the checkerboard in square centimeters (m2).",
        "answer_ko": "3.60",
        "answer_en": "3.6",
        "solution_abst_ko": "30 100 [OP_DIV] 2 [OP_POW] 8 [OP_MUL] 5 [OP_MUL]",
        "solution_abst_en": "30 100 [OP_DIV] 2 [OP_POW] 8 [OP_MUL] 5 [OP_MUL]",
        "solution_code_ko": "var_a = 30\nvar_b = 100\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 8\nvar_g = var_e * var_f\nvar_h = 5\nvar_i = var_g * var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 30\nvar_b = 100\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 8\nvar_g = var_e * var_f\nvar_h = 5\nvar_i = var_g * var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "4536": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 연속된 홀수의 합은 3개의 홀수 중 가장 큰 홀수보다 52만큼 큽니다. 3개의 홀수 중 가장 작은 수를 쓰시오.",
        "question_en": "The sum of 3 consecutive odd numbers is 52 greater than the largest odd number of 3 odd numbers. Write down the smallest one of the three odd numbers.",
        "answer_ko": "25",
        "answer_en": "25",
        "solution_abst_ko": "52 2 1 [OP_MUL] 2 2 [OP_MUL] [OP_ADD] [OP_ADD] 3 1 [OP_SUB] [OP_DIV] 2 2 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "52 2 1 [OP_MUL] 2 2 [OP_MUL] [OP_ADD] [OP_ADD] 3 1 [OP_SUB] [OP_DIV] 2 2 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 52\nvar_b = 2\nvar_c = 1\nvar_d = var_b * var_c\nvar_e = 2\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = var_d + var_g\nvar_i = var_a + var_h\nvar_j = 3\nvar_k = 1\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nvar_n = 2\nvar_o = 2\nvar_p = var_n * var_o\nvar_q = var_m - var_p\nprint(int(var_q))",
        "solution_code_en": "var_a = 52\nvar_b = 2\nvar_c = 1\nvar_d = var_b * var_c\nvar_e = 2\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = var_d + var_g\nvar_i = var_a + var_h\nvar_j = 3\nvar_k = 1\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nvar_n = 2\nvar_o = 2\nvar_p = var_n * var_o\nvar_q = var_m - var_p\nprint(int(var_q))"
    },
    "4537": {
        "category": "Comparison",
        "question_ko": "6개의 숫자 1, 4, 25, 16, 22, 14가 있습니다. 2번째로 작은 숫자는 무엇입니까?",
        "question_en": "There are 6 numbers 1, 4, 25, 16, 22, and 14. What is the 2nd smallest number?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 1 4 25 16 22 14 [OP_LIST_EOL] 2 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 4 25 16 22 14 [OP_LIST_EOL] 2 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1\nvar_b = 4\nvar_c = 25\nvar_d = 16\nvar_e = 22\nvar_f = 14\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_h = list_b[var_g-1]\nprint(int(var_h))",
        "solution_code_en": "var_a = 1\nvar_b = 4\nvar_c = 25\nvar_d = 16\nvar_e = 22\nvar_f = 14\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_h = list_b[var_g-1]\nprint(int(var_h))"
    },
    "4538": {
        "category": "Comparison",
        "question_ko": "집에서 과수원까지의 거리가 396미터(m)이고, 집에서 마트까지의 거리가 0.389킬로미터(㎞)라고 합니다. 집에서 과수원과 마트 중 어디가 더 가깝습니까?",
        "question_en": "The distance from the house to the orchard is 396 meters (m) and the distance from the house to the market is 0.389 kilometers (km). Which is closer to the house, the orchard or the market?",
        "answer_ko": "마트",
        "answer_en": "mart",
        "solution_abst_ko": "[OP_LIST_SOL] 과수원 마트 [OP_LIST_EOL] [OP_LIST_SOL] 396 0.389 1000 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] orchard mart [OP_LIST_EOL] [OP_LIST_SOL] 396 0.389 1000 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '과수원'\nvar_b = '마트'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 396\nvar_d = 0.389\nvar_e = 1000\nvar_f = var_d * var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'orchard'\nvar_b = 'mart'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 396\nvar_d = 0.389\nvar_e = 1000\nvar_f = var_d * var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "4539": {
        "category": "Correspondence",
        "question_ko": "244.8을 어떤 수로 나누었더니 51 이 되었습니다. 어떤 수에 15를 곱한 값을 구하시오.",
        "question_en": "Divide 244.8 by some number to get 51. Find the value multiplied by 15.",
        "answer_ko": "72",
        "answer_en": "72",
        "solution_abst_ko": "244.8 51 [OP_DIV] 15 [OP_MUL]",
        "solution_abst_en": "244.8 51 [OP_DIV] 15 [OP_MUL]",
        "solution_code_ko": "var_a = 244.8\nvar_b = 51\nvar_c = var_a / var_b\nvar_d = 15\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 244.8\nvar_b = 51\nvar_c = var_a / var_b\nvar_d = 15\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "4540": {
        "category": "Arithmetic calculation",
        "question_ko": "선물 상자 하나에는 사탕이 156개 들어있습니다. 20명의 아이들에게 선물 상자를 하나씩 나누어 주려고 할 때 사탕은 모두 몇 개가 필요할까요?",
        "question_en": "Each gift box contains 156 candies. How many candies will you need in total if you are going to distribute each gift box to 20 children?",
        "answer_ko": "3120",
        "answer_en": "3120",
        "solution_abst_ko": "156 20 [OP_MUL]",
        "solution_abst_en": "156 20 [OP_MUL]",
        "solution_code_ko": "var_a = 156\nvar_b = 20\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 156\nvar_b = 20\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "4541": {
        "category": "Geometry",
        "question_ko": "사다리꼴은 마주 보는 한 쌍의 변이 서로 평행한 사각형입니다. 이 사다리꼴에서 삼각형 모양을 잘라내어 나머지 마주 보는 변도 평행하도록 만들었습니다. 이렇게 만들어진 도형의 밑변이 9.51센티미터(㎝), 높이가 4.8센티미터(㎝)라면 넓이는 얼마인지 구하시오.",
        "question_en": "A trapezoid is a quadrilateral with one pair of opposite sides parallel to each other. A triangle shape was cut out of this trapezoid so that the remaining opposite sides were parallel. If the base of a shape made like this is 9.51 centimeters (cm) and the height is 4.8 centimeters (cm), what is the area?",
        "answer_ko": "45.65",
        "answer_en": "45.65",
        "solution_abst_ko": "9.51 4.8 [OP_MUL]",
        "solution_abst_en": "9.51 4.8 [OP_MUL]",
        "solution_code_ko": "var_a = 9.51\nvar_b = 4.8\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 9.51\nvar_b = 4.8\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "4542": {
        "category": "Arithmetic calculation",
        "question_ko": "다음 여섯 자연수의 총합을 구하시오. 36, 17, 32, 54, 28, 3",
        "question_en": "Find the sum of the following six natural numbers. 36, 17, 32, 54, 28, 3.",
        "answer_ko": "170",
        "answer_en": "170",
        "solution_abst_ko": "[OP_LIST_SOL] 36 17 32 54 28 3 [OP_LIST_EOL] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 36 17 32 54 28 3 [OP_LIST_EOL] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 36\nvar_b = 17\nvar_c = 32\nvar_d = 54\nvar_e = 28\nvar_f = 3\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_g = sum(list_a)\nprint(int(var_g))",
        "solution_code_en": "var_a = 36\nvar_b = 17\nvar_c = 32\nvar_d = 54\nvar_e = 28\nvar_f = 3\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_g = sum(list_a)\nprint(int(var_g))"
    },
    "4543": {
        "category": "Arithmetic calculation",
        "question_ko": "다연이네 반에서 리본 만들기를 하기 위해 10명의 친구들이 리본 테이프를 0.84미터(m)씩 나눠 가졌습니다. 리본 테이프가 나눠 가진 후에 50센티미터(㎝) 남았다면 나눠 가지기 전에는 몇 미터(m)였을까요?",
        "question_en": "To make ribbons in Dayeon's class, 10 students divided the ribbon tapes by 0.84 meters (m). If the ribbon tape had 50 centimeters (cm) left after it was divided, how many meters (m) were it before it was divided?",
        "answer_ko": "8.90",
        "answer_en": "8.9",
        "solution_abst_ko": "0.84 10 [OP_MUL] 50 100 [OP_DIV] [OP_ADD]",
        "solution_abst_en": "0.84 10 [OP_MUL] 50 100 [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 0.84\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 50\nvar_e = 100\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 0.84\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 50\nvar_e = 100\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "4544": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중에서 가장 큰 수를 2번째로 작은 수로 나눈 값은 얼마입니까?",
        "question_en": "There are three numbers 10, 11, and 12. What is the largest number divided by the second smallest number?",
        "answer_ko": "1.09",
        "answer_en": "1.09",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_DIV]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e / var_g\nprint('{:.2f}'.format(round(var_h+1e-10,2)))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e / var_g\nprint('{:.2f}'.format(round(var_h+1e-10,2)))"
    },
    "4545": {
        "category": "Possibility",
        "question_ko": "숫자 카드 1, 6, 8를 한 번씩 모두 사용하여 가장 큰 세 자리 수와 세 번째로 큰 세 자리수의 차를 구하시오.",
        "question_en": "Using the number cards 1, 6, and 8 all at least once, find the difference between the largest three-digit number and the third largest three-digit number.",
        "answer_ko": "243",
        "answer_en": "243",
        "solution_abst_ko": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 3 [OP_LIST_GET] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 3 [OP_LIST_GET] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 3\nvar_h = list_b[var_g-1]\nvar_i = var_f - var_h\nvar_j = abs(var_i)\nprint(int(var_j))",
        "solution_code_en": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 3\nvar_h = list_b[var_g-1]\nvar_i = var_f - var_h\nvar_j = abs(var_i)\nprint(int(var_j))"
    },
    "4546": {
        "category": "Arithmetic calculation",
        "question_ko": "4의 배수이면서 108의 약수인 수 중에서 가장 큰 수는 얼마입니까?",
        "question_en": "What is the largest number that is a multiple of 4 and a factor of 108?",
        "answer_ko": "108",
        "answer_en": "108",
        "solution_abst_ko": "108 [OP_LIST_GET_DIVISOR] 4 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_abst_en": "108 [OP_LIST_GET_DIVISOR] 4 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 108\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 4\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_d = list_c[-var_c]\nprint(int(var_d))",
        "solution_code_en": "var_a = 108\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 4\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_d = list_c[-var_c]\nprint(int(var_d))"
    },
    "4547": {
        "category": "Geometry",
        "question_ko": "68미터(m)의 줄에 4미터(m)마다 두 줄로 표시를 남기기로 하였습니다. 표시로 남겨지는 줄은 몇 개입니까? (단, 줄의 양 끝 역시 표시를 남깁니다.)",
        "question_en": "I have decided to mark two lines every 4 meters (m) on a 68 meter (m) line. How many marks are there? (Note that both ends of the string are also marked).",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "68 4 [OP_DIV] 2 [OP_MUL] 2 [OP_ADD]",
        "solution_abst_en": "68 4 [OP_DIV] 2 [OP_MUL] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 68\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 68\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "4548": {
        "category": "Arithmetic calculation",
        "question_ko": "2부터 20까지의 짝수가 있습니다. 그중에서 3번째로 큰 수에서 4번째로 작은 수를 뺀 값은 얼마입니까?",
        "question_en": "There are even numbers from 2 to 20. What is the 3rd largest number minus the 4th smallest number?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "2 20 [OP_LIST_EVEN] 3 [OP_LIST_MAX] 4 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "2 20 [OP_LIST_EVEN] 3 [OP_LIST_MAX] 4 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 2\nvar_b = 20\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[-var_c]\nvar_e = 4\nlist_c=list_a.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = var_d - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 2\nvar_b = 20\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[-var_c]\nvar_e = 4\nlist_c=list_a.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = var_d - var_f\nprint(int(var_g))"
    },
    "4549": {
        "category": "Correspondence",
        "question_ko": "59에 대해 자연수 A로 나눈 몫은 6, 나머지는 5입니다. A의 값은 무엇일까요?",
        "question_en": "The quotient of 59 divided by the natural number A is 6 and the remainder is 5. What is the value of A?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "59 5 [OP_SUB] 6 [OP_DIV]",
        "solution_abst_en": "59 5 [OP_SUB] 6 [OP_DIV]",
        "solution_code_ko": "var_a = 59\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 59\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "4550": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 3으로 나누었더니 나누어준 값과 같은 수가 나왔습니다. 어떤 수는 얼마입니까?",
        "question_en": "When you divide a certain number by 3, you get a result equal to the number you divided. What number is it?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "3 3 [OP_MUL]",
        "solution_abst_en": "3 3 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "4551": {
        "category": "Geometry",
        "question_ko": "넓이가 108제곱센티미터인 평행사변형의 높이가 9센티미터(㎝)라고 할 때, 밑변의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "If the height of a parallelogram with an area of 108 square centimeters is 9 centimeters (cm), what is the length of the base in centimeters (cm)?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "108 9 [OP_DIV]",
        "solution_abst_en": "108 9 [OP_DIV]",
        "solution_code_ko": "var_a = 108\nvar_b = 9\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 108\nvar_b = 9\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "4552": {
        "category": "Arithmetic calculation",
        "question_ko": "크기와 무게가 같은 수박을 바구니에 가득 담아 무게를 재었더니 63킬로그램(㎏)이었습니다. 이 중 절반의 수박을 덜어낸 후에 바구니와 함께 무게를 재어 보니 34킬로그램(㎏)이 되었습니다. 원래 있던 수박만의 무게는 몇 킬로그램(㎏)입니까?",
        "question_en": "Watermelons of the same size and weight were filled in a basket, and the basket weighed 63 kilograms (kg). After removing half of the watermelons, the basket weighed 34 kilograms (kg). What was the weight of the watermelons without the basket before they were removed?",
        "answer_ko": "58",
        "answer_en": "58",
        "solution_abst_ko": "63 34 [OP_SUB] 2 [OP_MUL]",
        "solution_abst_en": "63 34 [OP_SUB] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 63\nvar_b = 34\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 63\nvar_b = 34\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "4553": {
        "category": "Comparison",
        "question_ko": "지우의 키는 1.32미터(m)이고, 희진이의 키는 1.3미터(m)입니다. 두 사람의 학급은 키가 작은 사람부터 키 번호를 매긴다고 할 때, 지우와 희진이 중 키 번호가 큰 사람은 누구입니까?",
        "question_en": "Jiwoo is 1.32 meters (m) tall and Heejin is 1.3 meters (m) tall. If the class numbers students from the shortest to the tallest, which of Jiwoo's and Heejin's numbers is higher?",
        "answer_ko": "지우",
        "answer_en": "Jiwoo",
        "solution_abst_ko": "[OP_LIST_SOL] 지우 희진 [OP_LIST_EOL] [OP_LIST_SOL] 1.32 1.3 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jiwoo Heejin [OP_LIST_EOL] [OP_LIST_SOL] 1.32 1.3 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '지우'\nvar_b = '희진'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.32\nvar_d = 1.3\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Jiwoo'\nvar_b = 'Heejin'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.32\nvar_d = 1.3\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "4554": {
        "category": "Comparison",
        "question_ko": "크기가 서로 다른 상자 45개를 작은 것부터 크기순으로 나열하였을 때 빨간색 상자는 오른쪽에서 29번째에 있습니다. 상자를 큰 것부터 다시 크기순으로 나열 하였다면 빨간색 상자는 오른쪽에서 몇 번째에 놓입니까?",
        "question_en": "When 45 boxes of different sizes are arranged in order from smallest to largest, the red box is 29th from the right. If the boxes are arranged in order of size starting from the largest, how far from the right should the red box be?",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "45 29 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "45 29 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 45\nvar_b = 29\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 45\nvar_b = 29\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "4555": {
        "category": "Geometry",
        "question_ko": "10개의 각으로 이루어진 도형의 대각선은 몇 개입니까?",
        "question_en": "How many diagonals are there in a figure composed of ten angles?",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "10 10 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "10 10 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 10\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 10\nvar_b = 10\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "4556": {
        "category": "Arithmetic calculation",
        "question_ko": "유나네 가족이 오늘 우유를 전체의 0.4만큼 마신 우유의 양이 0.69리터(L)였습니다. 처음에 있던 우유는 몇 리터(L)인지 구하시오.",
        "question_en": "Yuna's family drank 0.4 of the milk today, and the amount of milk was 0.69 liters (L). Find how many liters (L) of milk were in the beginning.",
        "answer_ko": "1.73",
        "answer_en": "1.73",
        "solution_abst_ko": "0.69 0.4 [OP_DIV]",
        "solution_abst_en": "0.69 0.4 [OP_DIV]",
        "solution_code_ko": "var_a = 0.69\nvar_b = 0.4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 0.69\nvar_b = 0.4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "4557": {
        "category": "Arithmetic calculation",
        "question_ko": "연속하는 두 자연수의 합이 39일 때, 두 자연수 중 큰 수를 구하시오.",
        "question_en": "If the sum of two consecutive natural numbers is 39, find the larger of the two natural numbers.",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "39 1 [OP_ADD] 2 [OP_DIV]",
        "solution_abst_en": "39 1 [OP_ADD] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 39\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 39\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "4558": {
        "category": "Arithmetic calculation",
        "question_ko": "화단에 튤립이 3송이, 카네이션이 4송이 있습니다. 화단에 있는 전체 꽃의 개수는?",
        "question_en": "There are 3 tulips and 4 carnations in the flower bed. How many flowers are there in the flower bed in total?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "3 4 [OP_ADD]",
        "solution_abst_en": "3 4 [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 4\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 4\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "4559": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 30으로 나누면 14가 남고 50으로 나누면 24가 남고 70으로 나누면 34가 남는다고 한다. 이 조건을 만족하는 수들 중 가장 작은 수를 구하시오.",
        "question_en": "When a number is divided by 30, it leaves a remainder of 14, when divided by 50, it leaves a remainder of 24, and when divided by 70, it leaves a remainder of 34. Find the smallest number that satisfies this condition.",
        "answer_ko": "524",
        "answer_en": "524",
        "solution_abst_ko": "0 9999 1 [OP_LIST_ARANGE] 30 14 [OP_LIST_DIVIDE_AND_REMAIN] 50 24 [OP_LIST_DIVIDE_AND_REMAIN] 70 34 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MIN]",
        "solution_abst_en": "0 9999 1 [OP_LIST_ARANGE] 30 14 [OP_LIST_DIVIDE_AND_REMAIN] 50 24 [OP_LIST_DIVIDE_AND_REMAIN] 70 34 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 0\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 30\nvar_e = 14\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 50\nvar_g = 24\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 70\nvar_i = 34\nlist_d = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_c:\n    i = int(i)\n    if i%var_h == var_i:\n        list_d.append(i)\nvar_j = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_k = list_e[var_j-1]\nprint(int(var_k))",
        "solution_code_en": "var_a = 0\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 30\nvar_e = 14\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 50\nvar_g = 24\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 70\nvar_i = 34\nlist_d = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_c:\n    i = int(i)\n    if i%var_h == var_i:\n        list_d.append(i)\nvar_j = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_k = list_e[var_j-1]\nprint(int(var_k))"
    },
    "4560": {
        "category": "Possibility",
        "question_ko": "동빈이는 6, 2, 5를 하나씩 모두 사용하여 세 자리 수를 만들고 있습니다. 동빈이가 만들 수 있는 수 중 가장 큰 수와 가장 작은 수의 차이는 얼마입니까?",
        "question_en": "Dongbin uses 6, 2, and 5 to make a three-digit number. What is the difference between the largest number and the smallest number Dongbin can make?",
        "answer_ko": "396",
        "answer_en": "396",
        "solution_abst_ko": "[OP_LIST_SOL] 6 2 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 6 2 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))"
    },
    "4561": {
        "category": "Arithmetic calculation",
        "question_ko": "지민이는 국어 87점, 수학 98점을 받았습니다. 지민이가 국어, 수학, 영어 시험 평균 점수로 95점을 얻으려면 영어를 몇 점 받아야 합니까?",
        "question_en": "Jimin got 87 points in Korean and 98 points in math. How many English points should Jimin get in order to get an average point of 95 on the Korean, Math, and English tests?",
        "answer_ko": "100",
        "answer_en": "100",
        "solution_abst_ko": "95 3 [OP_MUL] 98 [OP_SUB] 87 [OP_SUB]",
        "solution_abst_en": "95 3 [OP_MUL] 98 [OP_SUB] 87 [OP_SUB]",
        "solution_code_ko": "var_a = 95\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 98\nvar_e = var_c - var_d\nvar_f = 87\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 95\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 98\nvar_e = var_c - var_d\nvar_f = 87\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "4562": {
        "category": "Arithmetic calculation",
        "question_ko": "비둘기가 15마리 있었습니다. 잠시 후 비둘기가 몇 마리 더 날아와 모두 21마리가 되었습니다. 날아온 비둘기는 몇 마리입니까?",
        "question_en": "There were 15 pigeons. After a while, a few more pigeons flew in, bringing the total to 21. How many pigeons flew by?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "21 15 [OP_SUB]",
        "solution_abst_en": "21 15 [OP_SUB]",
        "solution_code_ko": "var_a = 21\nvar_b = 15\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 21\nvar_b = 15\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "4563": {
        "category": "Possibility",
        "question_ko": "숫자 3, 5를 한 번씩만 사용하여 두 자리 수를 만들려고 합니다. 만들 수 있는 두 자리 수는 모두 몇 개입니까?",
        "question_en": "You are going to create a two-digit number using the numbers 3 and 5 only once. How many two-digit numbers can you make?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 3 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 3 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 3\nvar_b = 5\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = len(list_b)\nprint(int(var_d))",
        "solution_code_en": "var_a = 3\nvar_b = 5\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = len(list_b)\nprint(int(var_d))"
    },
    "4564": {
        "category": "Comparison",
        "question_ko": "토끼와 거북이가 경주를 합니다. 같은 시간 동안 토끼는 10.2킬로미터(㎞)의 1/100배를 달렸고, 거북이는 100미터(m)를 달렸습니다. 토끼와 거북이 중 누가 더 많이 달렸습니까?",
        "question_en": "A rabbit and a tortoise are racing. During the same time, the rabbit ran 1/100 of 10.2 kilometers (km), and the tortoise ran 100 meters (m). Who ran more, the rabbit or the tortoise?",
        "answer_ko": "토끼",
        "answer_en": "rabbit",
        "solution_abst_ko": "[OP_LIST_SOL] 토끼 거북이 [OP_LIST_EOL] [OP_LIST_SOL] 10.2 1000 [OP_MUL] 1/100 [OP_MUL] 100 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] rabbit tortoise [OP_LIST_EOL] [OP_LIST_SOL] 10.2 1000 [OP_MUL] 1/100 [OP_MUL] 100 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '토끼'\nvar_b = '거북이'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10.2\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 0.01\nvar_g = var_e * var_f\nvar_h = 100\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'rabbit'\nvar_b = 'tortoise'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10.2\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 0.01\nvar_g = var_e * var_f\nvar_h = 100\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "4565": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 9까지의 수 중 홀수는 몇 개인지 구하시오.",
        "question_en": "Find the number of odd numbers from 1 to 9.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "1 9 [OP_LIST_ODD] [OP_LIST_LEN]",
        "solution_abst_en": "1 9 [OP_LIST_ODD] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = len(list_a)\nprint(int(var_c))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = len(list_a)\nprint(int(var_c))"
    },
    "4566": {
        "category": "Possibility",
        "question_ko": "서로 다른 셔츠 3벌과 바지 4벌을 조합하여 입는 방법은 몇 가지 입니까?",
        "question_en": "How many ways can you wear 3 different shirts and 4 pants in combination?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "3 4 [OP_MUL]",
        "solution_abst_en": "3 4 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "4567": {
        "category": "Arithmetic calculation",
        "question_ko": "서울시 한 지역의 초등학교 학생 수를 조사하였더니, (가) 초등학교 786명, (나) 초등학교 777명, (다) 초등학교 762명, (라) 초등학교 819명, (마) 초등학교 493명이었습니다. 학생 수가 짝수인 학교는 몇 곳입니까?",
        "question_en": "You surveyed regarding the number of elementary school students in one area of Seoul, and found out that there are 786 students at (A) school, 777 for (B) school, 762 for (C) school, 819 for (D) school, and 493 for (E) school. How many schools have an even number of students?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 786 777 762 819 493 [OP_LIST_EOL] 2 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 786 777 762 819 493 [OP_LIST_EOL] 2 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 786\nvar_b = 777\nvar_c = 762\nvar_d = 819\nvar_e = 493\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 786\nvar_b = 777\nvar_c = 762\nvar_d = 819\nvar_e = 493\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "4568": {
        "category": "Arithmetic calculation",
        "question_ko": "호석이가 사과를 8개, 배를 5개, 귤을 12개, 레몬을 17개, 수박을 10개 먹었다. 레몬을 먹은 개수에서 배를 먹은 개수를 뺀 값을 구하여라.",
        "question_en": "Hoseok ate 8 apples, 5 pears, 12 tangerines, 17 lemons, and 10 watermelons. Find the number of lemons eaten minus the number of pears eaten.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "17 5 [OP_SUB]",
        "solution_abst_en": "17 5 [OP_SUB]",
        "solution_code_ko": "var_a = 17\nvar_b = 5\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 17\nvar_b = 5\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "4569": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 가장 큰 수를 가장 작은 수로 나눈 값은 얼마입니까?",
        "question_en": "There are five numbers 10, 11, 12, 13, and 14. What is the largest number divided by the smallest number?",
        "answer_ko": "1.40",
        "answer_en": "1.4",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_DIV]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g / var_i\nprint('{:.2f}'.format(round(var_j+1e-10,2)))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g / var_i\nprint('{:.2f}'.format(round(var_j+1e-10,2)))"
    },
    "4570": {
        "category": "Arithmetic calculation",
        "question_ko": "동그라미를 한 개 그리려면 철사 4미터(m)가 필요합니다. 태민이가 가진 철사의 길이가 105.8미터(m)라면 동그라미를 몇 개 그릴 수 있습니까?",
        "question_en": "You will need 4 meters (m) of wire to draw one circle. If Taemin's wire is 105.8 meters (m) long, how many circles can he draw?",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "105.8 4 [OP_FDIV]",
        "solution_abst_en": "105.8 4 [OP_FDIV]",
        "solution_code_ko": "var_a = 105.8\nvar_b = 4\nvar_c = var_a // var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 105.8\nvar_b = 4\nvar_c = var_a // var_b\nprint(int(var_c))"
    },
    "4571": {
        "category": "Correspondence",
        "question_ko": "A85-2B=364일 때, B에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "If A85-2B=364, what number should go in B?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "A85-2B=364 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A85-2B=364 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A85-2B=364'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A85-2B=364'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "4572": {
        "category": "Correspondence",
        "question_ko": "2에 어떤 수를 곱해야 할 것을 잘못하여 5에 어떤 수를 곱했더니 40이 되었습니다. 바르게 계산하면 얼마인지 구하시오.",
        "question_en": "You had to multiply 2 by a number but mistakenly multiplied 5 by the number instead to get 40. Find the correctly calculated value.",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "40 5 [OP_DIV] 2 [OP_MUL]",
        "solution_abst_en": "40 5 [OP_DIV] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 40\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 40\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "4573": {
        "category": "Geometry",
        "question_ko": "둘레가 54 센티미터(㎝)인 직사각형이 있다. 세로의 길이가 가로의 길이보다 3 센티미터(㎝) 더 짧을 때, 가로의 길이는 무엇인가?",
        "question_en": "You have a rectangle with a perimeter of 54 centimeters (cm). If the vertical length is 3 centimeters (cm) shorter than the horizontal length, what is the horizontal length?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "54 2 [OP_DIV] 3 [OP_SUB] 2 [OP_DIV] 3 [OP_ADD]",
        "solution_abst_en": "54 2 [OP_DIV] 3 [OP_SUB] 2 [OP_DIV] 3 [OP_ADD]",
        "solution_code_ko": "var_a = 54\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 3\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 3\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 54\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 3\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 3\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "4574": {
        "category": "Geometry",
        "question_ko": "육면체가 있을 때, 면의 수를 구하시오.",
        "question_en": "Given a hexahedron, find the number of its faces.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "6",
        "solution_abst_en": "6",
        "solution_code_ko": "var_a = 6\nprint(int(var_a))",
        "solution_code_en": "var_a = 6\nprint(int(var_a))"
    },
    "4575": {
        "category": "Geometry",
        "question_ko": "어느 세 점은 한 직선 위에 있지 않습니다. 이 세 점에 대하여 반직선의 개수는?",
        "question_en": "Three points are not in a straight line. How many rays are there for these three points?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "3 2 [OP_PERM]",
        "solution_abst_en": "3 2 [OP_PERM]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))"
    },
    "4576": {
        "category": "Arithmetic calculation",
        "question_ko": "일정한 빠르기로 3분에 5미터(m)를 가는 지네와 2분에 5미터(m)를 가는 지렁이가 있습니다. 이 지네가 지렁이보다 20미터(m) 앞에서 동시에 같은 방향으로 출발했다면 몇 분 후에 지네와 지렁이가 만나는지 구해 보시오.",
        "question_en": "There is a centipede that travels 5 meters (m) in 3 minutes and an earthworm that travels 5 meters (m) in 2 minutes at a constant speed. If this centipede started 20 meters (m) ahead of the worm in the same direction at the same time, find out what time in minutes the centipede and the worm meet.",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "20 5 2 [OP_DIV] 5 3 [OP_DIV] [OP_SUB] [OP_DIV]",
        "solution_abst_en": "20 5 2 [OP_DIV] 5 3 [OP_DIV] [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 20\nvar_b = 5\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = 5\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = var_d - var_g\nvar_i = var_a / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))",
        "solution_code_en": "var_a = 20\nvar_b = 5\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = 5\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = var_d - var_g\nvar_i = var_a / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))"
    },
    "4577": {
        "category": "Arithmetic calculation",
        "question_ko": "43, 92, 71, 64 중에서 가장 큰 수 빼기 가장 작은 수를 하면 얼마가 됩니까?",
        "question_en": "There are 43, 92, 71, and 64. What is the largest number minus the smallest number?",
        "answer_ko": "49",
        "answer_en": "49",
        "solution_abst_ko": "[OP_LIST_SOL] 43 92 71 64 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 43 92 71 64 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 43\nvar_b = 92\nvar_c = 71\nvar_d = 64\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 43\nvar_b = 92\nvar_c = 71\nvar_d = 64\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))"
    },
    "4578": {
        "category": "Possibility",
        "question_ko": "1부터 5까지의 숫자가 각각 한 개씩 적힌 숫자 카드가 5장 있다. 이 중에서 3장을 꺼내 그 숫자의 합을 구할 때, 나올 수 있는 모든 경우의 수는 얼마인가.",
        "question_en": "There are 5 number cards, one each with a number from 1 to 5 written on it. What is the number of all cases that can come out when taking out three of these and calculating the sum of each number?",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "1 5 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] [OP_LIST_LEN]",
        "solution_abst_en": "1 5 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 5\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 5\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "4579": {
        "category": "Arithmetic calculation",
        "question_ko": "13을 A로 나누면 몫이 4가 되고, 나머지는 B가 됩니다. A와 B는 모두 자연수입니다. 가능한 B 중 가장 작은 수의 값을 구하시오.",
        "question_en": "Divide 13 by A, and you get 4 as the quotient and B as the remainder. Both A, B are natural numbers. Find the smallest possible value of B.",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "1",
        "solution_abst_en": "1",
        "solution_code_ko": "var_a = 1\nprint(int(var_a))",
        "solution_code_en": "var_a = 1\nprint(int(var_a))"
    },
    "4580": {
        "category": "Arithmetic calculation",
        "question_ko": "6분 동안 21리터(L)의 에탄올을 플라스크에 넣었다. 플라스크에는 1분 동안 0.3리터(L)의 에탄올이 빠져나가며 가득 채우는데 22분 30초가 걸렸다. 처음 플라스크에 있던 들이는 몇 리터(L)인지 구하여라",
        "question_en": "21 liters (L) of ethanol was added to the flask for 6 minutes. The flask took 22 minutes and 30 seconds to be filled, with 0.3 liters (L) of ethanol draining out per minute. Find how many liters (L) the volume of the first flask was.",
        "answer_ko": "72",
        "answer_en": "72",
        "solution_abst_ko": "21 6 [OP_DIV] 0.3 [OP_SUB] 22 30 60 [OP_DIV] [OP_ADD] [OP_MUL]",
        "solution_abst_en": "21 6 [OP_DIV] 0.3 [OP_SUB] 22 30 60 [OP_DIV] [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 21\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.3\nvar_e = var_c - var_d\nvar_f = 22\nvar_g = 30\nvar_h = 60\nvar_i = var_g / var_h\nvar_j = var_f + var_i\nvar_k = var_e * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 21\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.3\nvar_e = var_c - var_d\nvar_f = 22\nvar_g = 30\nvar_h = 60\nvar_i = var_g / var_h\nvar_j = var_f + var_i\nvar_k = var_e * var_j\nprint(int(var_k))"
    },
    "4581": {
        "category": "Correspondence",
        "question_ko": "초원이는 이틀간 박스를 포장하면서 어제 전체 테이프에 1/5를 사용하였고, 오늘 나머지의 3/4을 사용하였습니다. 남은 테이프의 길이가 1미터(m) 50센티미터(㎝)라면, 초원이가 처음 가지고 있던 테이프의 길이는 몇 미터(m)입니까?",
        "question_en": "Chowon used 1/5 of the entire tape yesterday while packing the box for two days, and used 3/4 of the remaining tape today. If the length of the remaining tape is 1 meter (m) and 50 centimeters (cm), how long is the length of the tape that Chowon originally had in meters (m)?",
        "answer_ko": "7.50",
        "answer_en": "7.5",
        "solution_abst_ko": "1 50 100 [OP_DIV] [OP_ADD] 1 3/4 [OP_SUB] [OP_DIV] 1 1/5 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "1 50 100 [OP_DIV] [OP_ADD] 1 3/4 [OP_SUB] [OP_DIV] 1 1/5 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 50\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 1\nvar_g = 0.75\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 1\nvar_k = 0.2\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 50\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 1\nvar_g = 0.75\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 1\nvar_k = 0.2\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))"
    },
    "4582": {
        "category": "Arithmetic calculation",
        "question_ko": "등산을 할 때는 두 가지의 길이 있다. 하나는 짧은 길이고 하나는 2킬로미터(㎞) 더 긴 길이다. 올라갈 때는 짧은 길로 시속 3킬로미터(㎞)로 걸었고, 내려올 때는 긴 길로 시속 4킬로미터(㎞)로 내려왔다. 등산은 총 4시간이 걸렸다. 걸어간 거리는 총 몇 킬로미터(㎞)인가?",
        "question_en": "When it comes to mountain climbing, there are two routes. One is a shorter route, and the other one is 2 kilometers (km) longer than the short one. When you went up, you walked at 3 kilometers (km) per hour on a short path, and a long path at 4 kilometers (km) per hour on the way down. If it took 4 hours in total, how many kilometers (km) did you walk?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "4 2 4 [OP_DIV] [OP_SUB] 1 3 [OP_DIV] 1 4 [OP_DIV] [OP_ADD] [OP_DIV] 2 [OP_MUL] 2 [OP_ADD]",
        "solution_abst_en": "4 2 4 [OP_DIV] [OP_SUB] 1 3 [OP_DIV] 1 4 [OP_DIV] [OP_ADD] [OP_DIV] 2 [OP_MUL] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = 3\nvar_h = var_f / var_g\nvar_i = 1\nvar_j = 4\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_e / var_l\nvar_n = 2\nvar_o = var_m * var_n\nvar_p = 2\nvar_q = var_o + var_p\nprint(int(eval('{:.2f}'.format(round(var_q+1e-10,2)))))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = 3\nvar_h = var_f / var_g\nvar_i = 1\nvar_j = 4\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_e / var_l\nvar_n = 2\nvar_o = var_m * var_n\nvar_p = 2\nvar_q = var_o + var_p\nprint(int(eval('{:.2f}'.format(round(var_q+1e-10,2)))))"
    },
    "4583": {
        "category": "Arithmetic calculation",
        "question_ko": "반 학생 수 30명 중 4명의 수학 점수가 각각 90점, 85점, 88점, 80점이고 나머지 26명의 수학 평균 점수는 82점입니다. 반 전체의 수학 평균 점수는 몇 점인지 소수점을 포함하여 답을 구하시오.",
        "question_en": "Of the 30 students in the class, 4 have math scores of 90, 85, 88, and 80, respectively, and the average math score of the other 26 is 82. What is the average score in math for the whole class? Answer including decimal points.",
        "answer_ko": "82.50",
        "answer_en": "82.5",
        "solution_abst_ko": "26 82 [OP_MUL] 90 [OP_ADD] 85 [OP_ADD] 88 [OP_ADD] 80 [OP_ADD] 30 [OP_DIV]",
        "solution_abst_en": "26 82 [OP_MUL] 90 [OP_ADD] 85 [OP_ADD] 88 [OP_ADD] 80 [OP_ADD] 30 [OP_DIV]",
        "solution_code_ko": "var_a = 26\nvar_b = 82\nvar_c = var_a * var_b\nvar_d = 90\nvar_e = var_c + var_d\nvar_f = 85\nvar_g = var_e + var_f\nvar_h = 88\nvar_i = var_g + var_h\nvar_j = 80\nvar_k = var_i + var_j\nvar_l = 30\nvar_m = var_k / var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))",
        "solution_code_en": "var_a = 26\nvar_b = 82\nvar_c = var_a * var_b\nvar_d = 90\nvar_e = var_c + var_d\nvar_f = 85\nvar_g = var_e + var_f\nvar_h = 88\nvar_i = var_g + var_h\nvar_j = 80\nvar_k = var_i + var_j\nvar_l = 30\nvar_m = var_k / var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))"
    },
    "4584": {
        "category": "Correspondence",
        "question_ko": "율기는 어제 가지고 있던 돈의 2/5보다 300원 더 많이 사용하였고, 오늘 나머지 돈의 1/2보다 200원 적게 사용하였습니다. 남은 돈이 800원이라면, 율기가 어제 가지고 있던 돈은 얼마입니까?",
        "question_en": "Yulgi spent 300 won more than 2/5 of the money he had yesterday, and 200 won less than 1/2 of the rest today. If the remaining money is 800 won, how much money did Yulgi have yesterday?",
        "answer_ko": "2500",
        "answer_en": "2500",
        "solution_abst_ko": "800 200 [OP_SUB] 1 1/2 [OP_SUB] [OP_DIV] 300 [OP_ADD] 1 2/5 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "800 200 [OP_SUB] 1 1/2 [OP_SUB] [OP_DIV] 300 [OP_ADD] 1 2/5 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 800\nvar_b = 200\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = 0.5\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 300\nvar_i = var_g + var_h\nvar_j = 1\nvar_k = 0.4\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 800\nvar_b = 200\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = 0.5\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 300\nvar_i = var_g + var_h\nvar_j = 1\nvar_k = 0.4\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nprint(int(var_m))"
    },
    "4585": {
        "category": "Possibility",
        "question_ko": "1, 0, 5, 8, 6 중에서 3개를 뽑아 한 번씩만 사용하여 세 자리 수를 만들려고 합니다. 만들 수 있는 가장 큰 수와 네 번째로 작은 수의 차를 구하시오.",
        "question_en": "You want to form a three-digit number by picking three out of 1, 0, 5, 8, and 6 and using them only once. Find the difference between the largest number and the fourth smallest number that can be made.",
        "answer_ko": "715",
        "answer_en": "715",
        "solution_abst_ko": "[OP_LIST_SOL] 1 0 5 8 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 4 [OP_LIST_MIN] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "[OP_LIST_SOL] 1 0 5 8 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 4 [OP_LIST_MIN] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 1\nvar_b = 0\nvar_c = 5\nvar_d = 8\nvar_e = 6\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 4\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h - var_j\nvar_l = abs(var_k)\nprint(int(var_l))",
        "solution_code_en": "var_a = 1\nvar_b = 0\nvar_c = 5\nvar_d = 8\nvar_e = 6\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 4\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h - var_j\nvar_l = abs(var_k)\nprint(int(var_l))"
    },
    "4586": {
        "category": "Possibility",
        "question_ko": "1, 7, 4, 3을 한 번씩 사용하여 십의 자리 숫자가 3인 가장 큰 세 자리 수와 세 번째 큰 세 자리 수의 차를 구하시오.",
        "question_en": "Using 1, 7, 4, and 3 only once, find the difference between the largest three-digit number whose tens digit is 3 and the third largest three-digit number.",
        "answer_ko": "297",
        "answer_en": "297",
        "solution_abst_ko": "[OP_LIST_SOL] 1 7 4 3 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 3 [OP_LIST_SEARCH_FIXED_DIGIT] 1 [OP_LIST_MAX] 3 [OP_LIST_MAX] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "[OP_LIST_SOL] 1 7 4 3 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 3 [OP_LIST_SEARCH_FIXED_DIGIT] 1 [OP_LIST_MAX] 3 [OP_LIST_MAX] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 1\nvar_b = 7\nvar_c = 4\nvar_d = 3\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 3\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nvar_j = 3\nlist_e=list_c.copy()\nlist_e.sort()\nvar_k = list_e[-var_j]\nvar_l = var_i - var_k\nvar_m = abs(var_l)\nprint(int(var_m))",
        "solution_code_en": "var_a = 1\nvar_b = 7\nvar_c = 4\nvar_d = 3\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 3\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nvar_j = 3\nlist_e=list_c.copy()\nlist_e.sort()\nvar_k = list_e[-var_j]\nvar_l = var_i - var_k\nvar_m = abs(var_l)\nprint(int(var_m))"
    },
    "4587": {
        "category": "Arithmetic calculation",
        "question_ko": "5명이 원형 식탁에 앉아있다. 5명이 양 옆으로 인접하지 않은 사람들과 악수를 한다면 몇 번의 악수를 하게 되겠는가?",
        "question_en": "Five people are sitting at a round table. If 5 people shake hands with people who are not next to each other, how many handshakes will they make?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "5 5 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "5 5 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 5\nvar_b = 5\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 5\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "4588": {
        "category": "Arithmetic calculation",
        "question_ko": "민영이는 사과 9개, 배 3개, 감 5개를 샀고, 유정이는 민영이보다 과일을 2개 더 많이 샀습니다. 유정이가 사과를 7개 사고 배는 감보다 2개 더 적게 샀을 때, 유정이가 산 배는 몇 개인지 구하시오.",
        "question_en": "Minyoung bought 9 apples, 3 pears, and 5 persimmons, and Yoojeong bought 2 more fruits than Minyoung. If Yoojeong bought 7 apples and bought 2 fewer pears than persimmons, how many pears did Yoojeong buy?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "9 3 [OP_ADD] 5 [OP_ADD] 2 [OP_ADD] 7 [OP_SUB] 2 [OP_DIV] 1 [OP_ADD]",
        "solution_abst_en": "9 3 [OP_ADD] 5 [OP_ADD] 2 [OP_ADD] 7 [OP_SUB] 2 [OP_DIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 9\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e + var_f\nvar_h = 7\nvar_i = var_g - var_h\nvar_j = 2\nvar_k = var_i / var_j\nvar_l = 1\nvar_m = var_k + var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 9\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e + var_f\nvar_h = 7\nvar_i = var_g - var_h\nvar_j = 2\nvar_k = var_i / var_j\nvar_l = 1\nvar_m = var_k + var_l\nprint(int(var_m))"
    },
    "4589": {
        "category": "Geometry",
        "question_ko": "동전 2개를 하늘 높이 던집니다. 땅에 떨어졌을 때, 두 동전 모두 앞면이 위를 향하는 경우는 몇 가지입니까?",
        "question_en": "Toss 2 coins high into the sky. How many numbers of cases are there for both coins to land on heads?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "1",
        "solution_abst_en": "1",
        "solution_code_ko": "var_a = 1\nprint(int(var_a))",
        "solution_code_en": "var_a = 1\nprint(int(var_a))"
    },
    "4590": {
        "category": "Geometry",
        "question_ko": "크기가 같은 구슬을 가로와 세로 모두 12개씩 빈틈없이 늘어놓아 정사각형을 만들었습니다. 둘레에 놓인 구슬의 개수는 몇 개입니까?",
        "question_en": "A square is made by arranging 12 marbles of the same size without gaps in both the width and length. How many marbles are placed around the perimeter?",
        "answer_ko": "44",
        "answer_en": "44",
        "solution_abst_ko": "12 2 [OP_SUB] 4 [OP_MUL] 4 [OP_ADD]",
        "solution_abst_en": "12 2 [OP_SUB] 4 [OP_MUL] 4 [OP_ADD]",
        "solution_code_ko": "var_a = 12\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 12\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "4591": {
        "category": "Geometry",
        "question_ko": "철사를 가지고 한 모서리의 길이가 10센티미터(㎝)인 정육면체를 만들었습니다. 이 철사를 모두 사용하여 가로가 8센티미터(㎝), 세로가 5센티미터(㎝)인 직육면체를 만들려고 할 때, 높이는 몇 센티미터(㎝)입니까?",
        "question_en": "You have used a piece of wire to make a cube whose side is 10 centimetres (cm) long. If you use the same wire to make a cube that is 8 cm long and 5 cm wide, what is its height in centimetres (cm)?",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "10 12 [OP_MUL] 8 4 [OP_MUL] [OP_SUB] 5 4 [OP_MUL] [OP_SUB] 4 [OP_DIV]",
        "solution_abst_en": "10 12 [OP_MUL] 8 4 [OP_MUL] [OP_SUB] 5 4 [OP_MUL] [OP_SUB] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = 4\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 5\nvar_i = 4\nvar_j = var_h * var_i\nvar_k = var_g - var_j\nvar_l = 4\nvar_m = var_k / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 10\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = 4\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 5\nvar_i = 4\nvar_j = var_h * var_i\nvar_k = var_g - var_j\nvar_l = 4\nvar_m = var_k / var_l\nprint(int(var_m))"
    },
    "4592": {
        "category": "Comparison",
        "question_ko": "은행, 학교, 문구점, 편의점, 공원 순으로 거리가 가깝습니다. 2번째로 거리가 가까운 건물은 무엇인가요?",
        "question_en": "Bank, school, stationery store, convenience store, and park is in the order of distance that is closest. Which building is the second closest?",
        "answer_ko": "학교",
        "answer_en": "school",
        "solution_abst_ko": "[OP_LIST_SOL] 은행 학교 문구점 편의점 공원 [OP_LIST_EOL] 2 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Bank school stationery convenience park [OP_LIST_EOL] 2 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '은행'\nvar_b = '학교'\nvar_c = '문구점'\nvar_d = '편의점'\nvar_e = '공원'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nvar_g = list_a[var_f-1]\nprint(var_g)",
        "solution_code_en": "var_a = 'Bank'\nvar_b = 'school'\nvar_c = 'stationery'\nvar_d = 'convenience'\nvar_e = 'park'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nvar_g = list_a[var_f-1]\nprint(var_g)"
    },
    "4593": {
        "category": "Comparison",
        "question_ko": "트럭에 (가), (나) 2개의 상자를 실었습니다. (가) 상자는 (나) 상자보다 작습니다. 두 상자 중 큰 상자는 무엇입니까?",
        "question_en": "The truck is loaded with two boxes, (a) and (b). Box (a) is smaller than box (b). Which of the two boxes is the larger one?",
        "answer_ko": "(나)",
        "answer_en": "(b)",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) [OP_LIST_EOL] [OP_LIST_SOL] (가) (나) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (a) (b) [OP_LIST_EOL] [OP_LIST_SOL] (a) (b) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = '(가)'\nvar_d = '(나)'\nvar_e = '<'\nlist_b= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_f = 1\nvar_g = list_c[var_f-1]\nprint(var_g)",
        "solution_code_en": "var_a = '(a)'\nvar_b = '(b)'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = '(a)'\nvar_d = '(b)'\nvar_e = '<'\nlist_b= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_f = 1\nvar_g = list_c[var_f-1]\nprint(var_g)"
    },
    "4594": {
        "category": "Possibility",
        "question_ko": "세훈이는 한 자리 자연수 0,2,9를 한 번 씩 사용하여 세 자리 수를 만들고자 한다. 만들 수 있는 수는 총 몇 개인가?",
        "question_en": "Sehun wants to make a three-digit number by using the single-digit natural numbers 0, 2, and 9 once each. How many total can he make?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 0 2 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 2 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 2\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 0\nvar_b = 2\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "4595": {
        "category": "Geometry",
        "question_ko": "모서리의 길이가 같은 정육각기둥과 정사각뿔이 있습니다. 육각기둥의 모든 모서리의 길이의 합은 81센티미터(㎝)입니다. 사각뿔의 모든 모서리의 길이의 합은 몇 센티미터(㎝)입니까?",
        "question_en": "There are regular hexagonal prisms and square pyramids with the same edges. The sum of the lengths of all the edges of the hexagonal prism is 81 centimeters (cm). What is the sum of the lengths of all the edges of the pyramid in centimeters (cm)?",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "81 6 3 [OP_MUL] [OP_DIV] 4 2 [OP_MUL] [OP_MUL]",
        "solution_abst_en": "81 6 3 [OP_MUL] [OP_DIV] 4 2 [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 81\nvar_b = 6\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nvar_f = 4\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_e * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 81\nvar_b = 6\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nvar_f = 4\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_e * var_h\nprint(int(var_i))"
    },
    "4596": {
        "category": "Comparison",
        "question_ko": "윤기는 4, 정국이는 6에서 3을 뺀 수를 모았고, 유나는 5를 모았습니다. 누가 가장 작은 수를 가지고 있나요?",
        "question_en": "While Yoongi, Jungkook, and Yuna have following numbers: 4, 6 minus 3, and 5, who has the smallest number?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 유나 [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_SUB] 5 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook Yuna [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_SUB] 5 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nvar_c = '유나'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 6\nvar_f = 3\nvar_g = var_e - var_f\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nvar_c = 'Yuna'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 6\nvar_f = 3\nvar_g = var_e - var_f\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "4597": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.9, 1/3의 숫자가 있다. 이 중 0.6보다 크거나 같은 숫자들 중 가장 작거나 같은 숫자를 구하시오.",
        "question_en": "There are numbers 0.8, 1/2, 0.9, and 1/3. Find the smallest number that is greater than or equal to 0.6.",
        "answer_ko": "0.80",
        "answer_en": "0.8",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.6 [OP_LIST_MORE_EQUAL] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.6 [OP_LIST_MORE_EQUAL] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.6\nlist_b = []\nfor i in list_a:\n    if i >= var_e:\n        list_b.append(i)\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.6\nlist_b = []\nfor i in list_a:\n    if i >= var_e:\n        list_b.append(i)\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "4598": {
        "category": "Correspondence",
        "question_ko": "56-1A=39일 때, A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "What number is A in 56-1A=39?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "56-1A=39 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "56-1A=39 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '56-1A=39'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '56-1A=39'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "4599": {
        "category": "Arithmetic calculation",
        "question_ko": "두 개의 물통이 있습니다. 왼쪽 물통에는 물이 2800리터(L), 오른쪽 물통에는 물이 1500리터(L) 있습니다. 왼쪽 물통에 있는 물을 오른쪽 물통에 옮겨 담았더니 왼쪽 물통에 들어있는 물은 오른쪽 물통보다 360리터(L)가 많았습니다. 오른쪽 물통으로 옮긴 물은 몇 리터(L)인지 구하세요",
        "question_en": "There are two buckets of water. The left bucket holds 2800 litres (L) of water and the right bucket holds 1500 L of water. When the water in the left bucket was transferred to the right bucket, the left bucket contained 360 litres (L) more water than the right bucket. Find the number of litres (L) of water transferred to the right bucket.",
        "answer_ko": "470",
        "answer_en": "470",
        "solution_abst_ko": "2800 1500 [OP_SUB] 360 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "2800 1500 [OP_SUB] 360 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 2800\nvar_b = 1500\nvar_c = var_a - var_b\nvar_d = 360\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 2800\nvar_b = 1500\nvar_c = var_a - var_b\nvar_d = 360\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "4600": {
        "category": "Correspondence",
        "question_ko": "6A5+B03=748입니다. A는 얼마인가요?",
        "question_en": "6A5+B03=748. How much is A?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "6A5+B03=748 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "6A5+B03=748 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '6A5+B03=748'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '6A5+B03=748'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "4601": {
        "category": "Comparison",
        "question_ko": "하겸이네 학교에 키가 150센티미터(㎝)가 넘는 학생은 221명, 150센티미터(㎝)가 넘지 않는 학생은 255명입니다. 명훈이네 학교에 안경을 쓴 학생은 275명, 안경을 쓰지 않은 학생은 226명입니다. 누구네 학교의 학생이 더 많습니까?",
        "question_en": "At Ha-gyeom's school, there are 221 students who are taller than 150 centimeters (cm) and 255 students who are not taller than 150 centimeters (cm). At Myeonghun's school, there are 275 students who wear glasses and 226 students who do not wear glasses. Which school has more students?",
        "answer_ko": "명훈이네",
        "answer_en": "Myeonghun",
        "solution_abst_ko": "[OP_LIST_SOL] 하겸이네 명훈이네 [OP_LIST_EOL] [OP_LIST_SOL] 221 255 [OP_ADD] 275 226 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Ha-gyeom Myeonghun [OP_LIST_EOL] [OP_LIST_SOL] 221 255 [OP_ADD] 275 226 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '하겸이네'\nvar_b = '명훈이네'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 221\nvar_d = 255\nvar_e = var_c + var_d\nvar_f = 275\nvar_g = 226\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Ha-gyeom'\nvar_b = 'Myeonghun'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 221\nvar_d = 255\nvar_e = var_c + var_d\nvar_f = 275\nvar_g = 226\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "4602": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 12를 곱하려고 합니다. 잘못하여 14를 곱했을 때의 답이 42라면 바르게 계산한 결과는 얼마일까요?",
        "question_en": "You want to multiply a number by 12. When you mistakenly multiplied by 14 to get 42, what is the correctly calculated value?",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "42 14 [OP_DIV] 12 [OP_MUL]",
        "solution_abst_en": "42 14 [OP_DIV] 12 [OP_MUL]",
        "solution_code_ko": "var_a = 42\nvar_b = 14\nvar_c = var_a / var_b\nvar_d = 12\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 42\nvar_b = 14\nvar_c = var_a / var_b\nvar_d = 12\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "4603": {
        "category": "Comparison",
        "question_ko": "1.4, 9/10, 1.2, 0.5, 13/10 중에서 1.1보다 큰 숫자를 고르고, 선택된 숫자들의 개수를 구하세요",
        "question_en": "Choose a number greater than 1.1 among 1.4, 9/10, 1.2, 0.5, and 13/10, and count the number of selected numbers.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "4604": {
        "category": "Possibility",
        "question_ko": "2, 4, 5, 1, 3, 7, 6, 0 수 카드를 모두 한 번씩만 사용하여 가장 작은 수를 찾으시오",
        "question_en": "Numbers are given: 2, 4, 5, 1, 3, 7, 6, and 0. Find the smallest number using all cards only once.",
        "answer_ko": "10234567",
        "answer_en": "10234567",
        "solution_abst_ko": "[OP_LIST_SOL] 2 4 5 1 3 7 6 0 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 2 4 5 1 3 7 6 0 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = 5\nvar_d = 1\nvar_e = 3\nvar_f = 7\nvar_g = 6\nvar_h = 0\nlist_a= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_i = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_i))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_j = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_k = list_c[var_j-1]\nprint(int(var_k))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = 5\nvar_d = 1\nvar_e = 3\nvar_f = 7\nvar_g = 6\nvar_h = 0\nlist_a= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_i = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_i))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_j = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_k = list_c[var_j-1]\nprint(int(var_k))"
    },
    "4605": {
        "category": "Correspondence",
        "question_ko": "632-AB1=41이 성립합니다. B는 무엇인가요?",
        "question_en": "632-AB1=41 is valid. What is B?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "632-AB1=41 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "632-AB1=41 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '632-AB1=41'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '632-AB1=41'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "4606": {
        "category": "Possibility",
        "question_ko": "1에서 9까지의 숫자 카드 중 3개를 선택하고 19가 되는 숫자 조합의 수를 찾으세요.",
        "question_en": "Choose 3 of the number cards from 1 to 9 and find the number of combination of numbers that makes 19.",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "1 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 19 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 19 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 19\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 19\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))"
    },
    "4607": {
        "category": "Arithmetic calculation",
        "question_ko": "다섯 자리 수 중 3과 5의 공배수 중 가장 작은 수는?",
        "question_en": "Which five-digit number is the smallest common multiple of 3 and 5?",
        "answer_ko": "10005",
        "answer_en": "10005",
        "solution_abst_ko": "10000 99999 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "10000 99999 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 10000\nvar_b = 99999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 10000\nvar_b = 99999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[var_f-1]\nprint(int(var_g))"
    },
    "4608": {
        "category": "Possibility",
        "question_ko": "서로 다른 상자 3개 안에 각각 네 종류의 공이 들어 있습니다. 용우가 공을 고르는 경우의 수를 구하시오.",
        "question_en": "3 different boxes each contain 4 types of balls. Find the number of ways Yongwoo chooses the ball.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "3 4 [OP_MUL]",
        "solution_abst_en": "3 4 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "4609": {
        "category": "Possibility",
        "question_ko": "여섯 장의 숫자 카드 8, 3, 6, 5, 0, 7 중 세 장을 뽑아 만든 세 자리 수 중에서 가장 큰 수를 A, 가장 작은 수를 B라고 할 때, (A-B)×6의 값을 구하시오.",
        "question_en": "If A is the largest and B is the smallest three-digit number made by drawing three out of six number cards 8, 3, 6, 5, 0, 7, find the value of (A-B) × 6 .",
        "answer_ko": "3426",
        "answer_en": "3426",
        "solution_abst_ko": "[OP_LIST_SOL] 8 3 6 5 0 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB] 6 [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 8 3 6 5 0 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 3\nvar_c = 6\nvar_d = 5\nvar_e = 0\nvar_f = 7\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_i = list_c[-var_h]\nvar_j = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_k = list_d[var_j-1]\nvar_l = var_i - var_k\nvar_m = 6\nvar_n = var_l * var_m\nprint(int(var_n))",
        "solution_code_en": "var_a = 8\nvar_b = 3\nvar_c = 6\nvar_d = 5\nvar_e = 0\nvar_f = 7\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_i = list_c[-var_h]\nvar_j = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_k = list_d[var_j-1]\nvar_l = var_i - var_k\nvar_m = 6\nvar_n = var_l * var_m\nprint(int(var_n))"
    },
    "4610": {
        "category": "Possibility",
        "question_ko": "한 개의 주사위를 던졌을 때, 4, 5, 6의 눈이 나오는 경우의 수는?",
        "question_en": "How many number of cases do you get a 4, 5, or 6 when you throw a die?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "1 6 1 [OP_LIST_ARANGE] [OP_LIST_SOL] 4 5 6 [OP_LIST_EOL] [OP_SET_INTERSECT] [OP_LIST_LEN]",
        "solution_abst_en": "1 6 1 [OP_LIST_ARANGE] [OP_LIST_SOL] 4 5 6 [OP_LIST_EOL] [OP_SET_INTERSECT] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 6\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 4\nvar_e = 5\nvar_f = 6\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nlist_c = list(set(list_a) & set(list_b))\nvar_g = len(list_c)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 6\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 4\nvar_e = 5\nvar_f = 6\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nlist_c = list(set(list_a) & set(list_b))\nvar_g = len(list_c)\nprint(int(var_g))"
    },
    "4611": {
        "category": "Possibility",
        "question_ko": "숫자 9, 4, 1, 5를 한 번씩 사용하여 만들 수 있는 가장 큰 네 자리수를 구하시오.",
        "question_en": "Find the largest four-digit number that can be formed by using the numbers 9, 4, 1, and 5 once each.",
        "answer_ko": "9541",
        "answer_en": "9541",
        "solution_abst_ko": "[OP_LIST_SOL] 1 4 9 5 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1 4 9 5 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1\nvar_b = 4\nvar_c = 9\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 4\nvar_c = 9\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint(int(var_g))"
    },
    "4612": {
        "category": "Comparison",
        "question_ko": "여러 명의 아이들이 같은 간격으로 둥글게 서 있습니다. 한 아이를 기준으로 시계 방향으로 6번째 아이와 11번째 아이가 마주 보고 서 있습니다. 아이들은 모두 몇 명입니까?",
        "question_en": "Several children are standing in a circle equally spaced apart. Based on one child, the 6th child and the 11th child are standing facing each other in a clockwise direction. How many children are there in total?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "11 6 [OP_SUB] 2 [OP_MUL]",
        "solution_abst_en": "11 6 [OP_SUB] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 11\nvar_b = 6\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 11\nvar_b = 6\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "4613": {
        "category": "Arithmetic calculation",
        "question_ko": "해빈이와 11명의 친구들이 서로 한 번씩 하이파이브를 하였을 때, 하이파이브는 모두 몇 번 이루어졌습니까?",
        "question_en": "When Haebin and 11 of his friends high-five each other once, how many high-fives are there?",
        "answer_ko": "66",
        "answer_en": "66",
        "solution_abst_ko": "11 1 [OP_ADD] 11 [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "11 1 [OP_ADD] 11 [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 11\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 11\nvar_e = var_c * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 11\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 11\nvar_e = var_c * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "4614": {
        "category": "Arithmetic calculation",
        "question_ko": "민형이가 친구들과 달리기를 했습니다. 민형이가 150미터(m)를 달리려면 20초의 시간이 걸릴 때, 1분동안은 몇 미터(m)를 달릴 수 있는지 구하세요.",
        "question_en": "Minhyung went for a run with his friends. If it takes 20 seconds for Minhyung to run 150 meters (m), find how many meters (m) he can run in 1 minute.",
        "answer_ko": "450",
        "answer_en": "450",
        "solution_abst_ko": "1 60 [OP_MUL] 20 [OP_DIV] 150 [OP_MUL]",
        "solution_abst_en": "1 60 [OP_MUL] 20 [OP_DIV] 150 [OP_MUL]",
        "solution_code_ko": "var_a = 1\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 20\nvar_e = var_c / var_d\nvar_f = 150\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 20\nvar_e = var_c / var_d\nvar_f = 150\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "4615": {
        "category": "Comparison",
        "question_ko": "은지는 10번째로 학교에 도착했습니다. 은지 다음에는 태형이가 도착했고 그 다음에는 남준이가 도착했다면 남준이는 몇 번째로 도착했을까요?",
        "question_en": "Eunji was the 10th to arrive at school. If Taehyung arrived after Eunji and then Namjoon arrived, in which order did Namjoon arrive at school?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "10 1 [OP_ADD] 1 [OP_ADD]",
        "solution_abst_en": "10 1 [OP_ADD] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "4616": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이는 3개, 윤기는 2개의 공을 소유하고 있습니다. 두 명이 가지고 있는 공의 개수는 몇 개입니까?",
        "question_en": "Jungkook owns 3 balls and Yoongi owns 2 balls. How many balls are the two players owning?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "3 2 [OP_ADD]",
        "solution_abst_en": "3 2 [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "4617": {
        "category": "Geometry",
        "question_ko": "가로 12개씩, 세로 12개씩 크기가 같은 구슬을 빈틈없이 늘어놓아 정사각형을 만들었습니다. 한 변에 놓인 구슬은 몇 개입니까?",
        "question_en": "A square was made by arranging 12 beads of the same size, 12 by 12, without gaps. How many marbles are on one side?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "12",
        "solution_abst_en": "12",
        "solution_code_ko": "var_a = 12\nprint(int(var_a))",
        "solution_code_en": "var_a = 12\nprint(int(var_a))"
    },
    "4618": {
        "category": "Arithmetic calculation",
        "question_ko": "도로에서 자동차들이 앞 뒤로 같은 간격으로 서 있다. 맨 앞 자동차와 맨 뒤 자동차의 거리가 242 미터(m)이고, 자동차 사이의 거리가 5.5미터(m)라면 거리에 있는 자동차는 모두 몇 대인가?",
        "question_en": "On the road, cars stand equally spaced from the front to the back. If the distance between the first car and the last car is 242 meters (m), and the distance between the cars is 5.5 meters (m), how many cars are there in the street?",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "242 5.5 [OP_FDIV] 1 [OP_ADD]",
        "solution_abst_en": "242 5.5 [OP_FDIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 242\nvar_b = 5.5\nvar_c = var_a // var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 242\nvar_b = 5.5\nvar_c = var_a // var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "4619": {
        "category": "Possibility",
        "question_ko": "사과, 복숭아, 배, 참외 과일 바구니에서 중복을 허락하여 총 3개의 과일을 순서대로 꺼낼 때, 가능한 경우의 수는 모두 몇 가지 입니까?",
        "question_en": "From a fruit basket containing apple, peach, pear and melon, when a total of 3 fruits are taken out in order, allowing picking the same type of fruit, how many possible cases are there?",
        "answer_ko": "64",
        "answer_en": "64",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 복숭아 배 참외 [OP_LIST_EOL] [OP_LIST_LEN] 3 [OP_POW]",
        "solution_abst_en": "[OP_LIST_SOL] apple peach pear melon [OP_LIST_EOL] [OP_LIST_LEN] 3 [OP_POW]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '복숭아'\nvar_c = '배'\nvar_d = '참외'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 3\nvar_g = var_e ** var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 'apple'\nvar_b = 'peach'\nvar_c = 'pear'\nvar_d = 'melon'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 3\nvar_g = var_e ** var_f\nprint(int(var_g))"
    },
    "4620": {
        "category": "Possibility",
        "question_ko": "승아는 5명의 친구들과 조별과제를 하게 되어 조장 1명, 서기 1명, 발표자 2명을 뽑게 되었다. 승아가 서기를 하게 되는 경우의 수를 구하시오.",
        "question_en": "Seung-a had a group assignment with 5 friends and had to choose 1 leader, 1 secretary, and 2 presenters. Find the number of cases in which Seung-a becomes a clerk.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "5 1 [OP_SUB] 1 1 1 [OP_SUB] [OP_ADD] 2 [OP_ADD] [OP_PERM] 2 2 [OP_PERM] [OP_DIV]",
        "solution_abst_en": "5 1 [OP_SUB] 1 1 1 [OP_SUB] [OP_ADD] 2 [OP_ADD] [OP_PERM] 2 2 [OP_PERM] [OP_DIV]",
        "solution_code_ko": "var_a = 5\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = 1\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d + var_g\nvar_i = 2\nvar_j = var_h + var_i\nvar_k = 1\nvar_c = int(var_c)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_c-i)\nvar_l = 2\nvar_m = 2\nvar_n = 1\nvar_l = int(var_l)\nvar_m = int(var_m)\nfor i, elem in enumerate(range(var_m)):\n    var_n = var_n * (var_l-i)\nvar_o = var_k / var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 5\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = 1\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d + var_g\nvar_i = 2\nvar_j = var_h + var_i\nvar_k = 1\nvar_c = int(var_c)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_c-i)\nvar_l = 2\nvar_m = 2\nvar_n = 1\nvar_l = int(var_l)\nvar_m = int(var_m)\nfor i, elem in enumerate(range(var_m)):\n    var_n = var_n * (var_l-i)\nvar_o = var_k / var_n\nprint(int(var_o))"
    },
    "4621": {
        "category": "Arithmetic calculation",
        "question_ko": "집합 A의 원소는 1/2, 1/3, 1/5이고, 집합 B의 원소는 0.2, 0.4, 0.5, 0.7일 때 A와 B의 교집합의 원소의 개수를 구하시오.",
        "question_en": "If the elements of set A are 1/2, 1/3, 1/5 and the elements of set B are 0.2, 0.4, 0.5, 0.7, find the number of elements in the intersection of set A and B.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 1/2 1/3 1/5 [OP_LIST_EOL] [OP_LIST_SOL] 0.2 0.4 0.5 0.7 [OP_LIST_EOL] [OP_SET_INTERSECT] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1/2 1/3 1/5 [OP_LIST_EOL] [OP_LIST_SOL] 0.2 0.4 0.5 0.7 [OP_LIST_EOL] [OP_SET_INTERSECT] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.5\nvar_b = 0.3333333333333333\nvar_c = 0.2\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.2\nvar_e = 0.4\nvar_f = 0.5\nvar_g = 0.7\nlist_b= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nlist_c = list(set(list_a) & set(list_b))\nvar_h = len(list_c)\nprint(int(var_h))",
        "solution_code_en": "var_a = 0.5\nvar_b = 0.3333333333333333\nvar_c = 0.2\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.2\nvar_e = 0.4\nvar_f = 0.5\nvar_g = 0.7\nlist_b= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nlist_c = list(set(list_a) & set(list_b))\nvar_h = len(list_c)\nprint(int(var_h))"
    },
    "4622": {
        "category": "Possibility",
        "question_ko": "사과, 감, 배, 귤 4종류의 과일 중 15개를 선택하려고 한다. 각 과일을 2개 이상 선택한다고 할 때 과일을 선택하는 총 가지 수를 구하시오.",
        "question_en": "I want to choose 15 fruits from 4 types of fruits: apples, persimmons, pears, and tangerines. When I am trying to choose at least two from each type of fruit, how many ways can i choose?",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "4 15 [OP_ADD] 4 2 [OP_MUL] [OP_SUB] 1 [OP_SUB] 15 4 2 [OP_MUL] [OP_SUB] [OP_COMB]",
        "solution_abst_en": "4 15 [OP_ADD] 4 2 [OP_MUL] [OP_SUB] 1 [OP_SUB] 15 4 2 [OP_MUL] [OP_SUB] [OP_COMB]",
        "solution_code_ko": "var_a = 4\nvar_b = 15\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = 15\nvar_k = 4\nvar_l = 2\nvar_m = var_k * var_l\nvar_n = var_j - var_m\nvar_o = 1\nvar_i = int(var_i)\nvar_n = int(var_n)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o * (var_i-i)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o / (i+1)\nprint(int(var_o))",
        "solution_code_en": "var_a = 4\nvar_b = 15\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = 15\nvar_k = 4\nvar_l = 2\nvar_m = var_k * var_l\nvar_n = var_j - var_m\nvar_o = 1\nvar_i = int(var_i)\nvar_n = int(var_n)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o * (var_i-i)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o / (i+1)\nprint(int(var_o))"
    },
    "4623": {
        "category": "Geometry",
        "question_ko": "사각뿔이 있을 때, 면의 개수는?",
        "question_en": "If there is a quadrangular pyramid, what is the number of faces?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "4 1 [OP_ADD]",
        "solution_abst_en": "4 1 [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "4624": {
        "category": "Arithmetic calculation",
        "question_ko": "시경이네 모둠 6명이 가지고 있는 사탕 수는 16, 22, 30, 26, 18, 20개 입니다. 시경이네 모둠이 가진 사탕은 평균 몇 개인가?",
        "question_en": "There are 16, 22, 30, 26, 18, and 20 candies each of the 6 members of the Si-gyeong's group have. On average, how many candies does Si-gyeong's group have?",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "[OP_LIST_SOL] 16 22 30 26 18 20 [OP_LIST_EOL] [OP_LIST_MEAN]",
        "solution_abst_en": "[OP_LIST_SOL] 16 22 30 26 18 20 [OP_LIST_EOL] [OP_LIST_MEAN]",
        "solution_code_ko": "var_a = 16\nvar_b = 22\nvar_c = 30\nvar_d = 26\nvar_e = 18\nvar_f = 20\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_g = sum(list_a)/len(list_a)\nprint(int(var_g))",
        "solution_code_en": "var_a = 16\nvar_b = 22\nvar_c = 30\nvar_d = 26\nvar_e = 18\nvar_f = 20\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_g = sum(list_a)/len(list_a)\nprint(int(var_g))"
    },
    "4625": {
        "category": "Comparison",
        "question_ko": "학생들이 코로나 검사를 받기 위해 한 줄로 서 있습니다. 정수 바로 뒤에는 연지가 서 있고 정수는 뒤에서 24번째에 서 있고 연지는 앞에서 18번째에 서 있습니다. 몇 명의 학생들이 줄을 서 있는지 구하시오.",
        "question_en": "Students are standing in a line to get tested for corona. Yeonji stands right behind Jeongsu, Jeongsu stands 24th from the back, and Yeonji stands 18th from the front. Find how many students are in line.",
        "answer_ko": "42",
        "answer_en": "42",
        "solution_abst_ko": "18 24 [OP_ADD]",
        "solution_abst_en": "18 24 [OP_ADD]",
        "solution_code_ko": "var_a = 18\nvar_b = 24\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 18\nvar_b = 24\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "4626": {
        "category": "Comparison",
        "question_ko": "20명의 학생들이 한줄로 섰습니다. 정국이는 1등으로 줄을 섰고, 윤기는 정국이 바로 뒤에 섰습니다. 윤기 뒤에 서 있는 학생은 몇 명입니까?",
        "question_en": "20 students were lined up, and Jungkook took the first place in the line. Yoongi stood right behind Jungkook. Find the number of students standing behind Yoongi.",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "20 1 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "20 1 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "4627": {
        "category": "Arithmetic calculation",
        "question_ko": "주아네 아파트 단지에는 15층짜리 건물이 8동 있습니다. 이 건물 중 절반은 한 층에 4가구씩 살고 있고, 나머지는 한 층에 5가구씩 살고 있습니다. 한 가구에 비상 손전등이 2개씩 설치되어 있다고 할 때 주아네 아파트 단지에 설치되어 있는 비상 손전등은 모두 몇 개인지 구해 보시오.",
        "question_en": "There are eight 15-story buildings in Joa's apartment complex. Half of these buildings have four families per floor, and the rest have five families per floor. If each household has two emergency flashlights installed, find out how many emergency flashlights are installed in Joa's apartment complex.",
        "answer_ko": "1080",
        "answer_en": "1080",
        "solution_abst_ko": "15 8 [OP_MUL] 2 [OP_DIV] 4 [OP_MUL] 15 8 [OP_MUL] 2 [OP_DIV] 5 [OP_MUL] [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "15 8 [OP_MUL] 2 [OP_DIV] 4 [OP_MUL] 15 8 [OP_MUL] 2 [OP_DIV] 5 [OP_MUL] [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 15\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 4\nvar_g = var_e * var_f\nvar_h = 15\nvar_i = 8\nvar_j = var_h * var_i\nvar_k = 2\nvar_l = var_j / var_k\nvar_m = 5\nvar_n = var_l * var_m\nvar_o = var_g + var_n\nvar_p = 2\nvar_q = var_o * var_p\nprint(int(var_q))",
        "solution_code_en": "var_a = 15\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 4\nvar_g = var_e * var_f\nvar_h = 15\nvar_i = 8\nvar_j = var_h * var_i\nvar_k = 2\nvar_l = var_j / var_k\nvar_m = 5\nvar_n = var_l * var_m\nvar_o = var_g + var_n\nvar_p = 2\nvar_q = var_o * var_p\nprint(int(var_q))"
    },
    "4628": {
        "category": "Comparison",
        "question_ko": "도서관에 똑같은 책장이 28개 있습니다. 각 책장은 6층이고, 각 층마다 꽂혀 있는 책의 수는 19개로 같습니다. 도서관에 있는 책은 모두 몇 권입니까?",
        "question_en": "There are 28 identical bookcases in the library. Each bookcase has 6 shelves, and the number of books on each shelf is the same at 19. How many books are there in the library?",
        "answer_ko": "3192",
        "answer_en": "3192",
        "solution_abst_ko": "28 6 [OP_MUL] 19 [OP_MUL]",
        "solution_abst_en": "28 6 [OP_MUL] 19 [OP_MUL]",
        "solution_code_ko": "var_a = 28\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 19\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 28\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 19\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "4629": {
        "category": "Geometry",
        "question_ko": "밑면의 두 변의 길이가 각각 6미터(m) 40센티미터(㎝), 9미터(m)이고 높이가 5미터(m) 20센티미터(㎝)인 직육면체 모양의 통에 가득 들어 있는 팥을 부피가 1세제곱미터(㎥)인 상자 여러 개에 모두 나누어 담으려고 합니다. 상자는 적어도 몇 개 필요한지 구해보시오.",
        "question_en": "We are trying to divide red beans filled in a rectangular parallelepiped container with two side lengths of the bottom each 6 meters (m) 40 centimeters (cm) and 9 meters (m) into several boxes whose volume is 1 cubic meter (m3).  Find at least how many boxes you need.",
        "answer_ko": "300",
        "answer_en": "300",
        "solution_abst_ko": "6 40 100 [OP_DIV] [OP_ADD] 9 [OP_MUL] 5 20 100 [OP_DIV] [OP_ADD] [OP_MUL] 1 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "6 40 100 [OP_DIV] [OP_ADD] 9 [OP_MUL] 5 20 100 [OP_DIV] [OP_ADD] [OP_MUL] 1 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 6\nvar_b = 40\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 9\nvar_g = var_e * var_f\nvar_h = 5\nvar_i = 20\nvar_j = 100\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_g * var_l\nvar_n = 1\nvar_o = var_m / var_n\nvar_p = 1\nvar_q=int(((var_o+9*10**(var_p-2))//(10**(var_p-1)))*10**(var_p-1))\n\nprint(int(var_q))",
        "solution_code_en": "var_a = 6\nvar_b = 40\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 9\nvar_g = var_e * var_f\nvar_h = 5\nvar_i = 20\nvar_j = 100\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_g * var_l\nvar_n = 1\nvar_o = var_m / var_n\nvar_p = 1\nvar_q=int(((var_o+9*10**(var_p-2))//(10**(var_p-1)))*10**(var_p-1))\n\nprint(int(var_q))"
    },
    "4630": {
        "category": "Correspondence",
        "question_ko": "과일가게에 사과가 82개, 배가 90개, 귤이 88개, 참외가 84개가 있으며 수박은 몇 개가 있는지 모릅니다. 과일가게에 있는 과일의 총 개수를 88로 나누면 몫이 5로 나누어떨어진다. 수박의 개수를 구하시오.",
        "question_en": "There are 82 apples, 90 pears, 88 tangerines, and 84 melons at the fruit store, and the number of watermelons is unknown. If you divide the total number of fruits in the fruit store by 88, the quotient is 5 with no remainder. Find the number of watermelons.",
        "answer_ko": "96",
        "answer_en": "96",
        "solution_abst_ko": "88 5 [OP_MUL] 82 [OP_SUB] 90 [OP_SUB] 88 [OP_SUB] 84 [OP_SUB]",
        "solution_abst_en": "88 5 [OP_MUL] 82 [OP_SUB] 90 [OP_SUB] 88 [OP_SUB] 84 [OP_SUB]",
        "solution_code_ko": "var_a = 88\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 82\nvar_e = var_c - var_d\nvar_f = 90\nvar_g = var_e - var_f\nvar_h = 88\nvar_i = var_g - var_h\nvar_j = 84\nvar_k = var_i - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 88\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 82\nvar_e = var_c - var_d\nvar_f = 90\nvar_g = var_e - var_f\nvar_h = 88\nvar_i = var_g - var_h\nvar_j = 84\nvar_k = var_i - var_j\nprint(int(var_k))"
    },
    "4631": {
        "category": "Geometry",
        "question_ko": "넓이가 59.6제곱센티미터(㎠)인 직사각형 모양의 액자가 있습니다. 이 액자에 크기가 같은 사진 4장을 겹치지 않고 끼워 넣을 때, 한 장의 크기는 최대 몇 제곱센티미터(㎠)가 될 수 있는지 구하시오.",
        "question_en": "I have a picture frame in the shape of a rectangle measuring 59.6 square centimeters (cm²). When four photos of the same size are inserted into this frame without overlapping, find the maximum size in square centimeters (cm2) of one photo.",
        "answer_ko": "14.90",
        "answer_en": "14.9",
        "solution_abst_ko": "59.6 4 [OP_DIV]",
        "solution_abst_en": "59.6 4 [OP_DIV]",
        "solution_code_ko": "var_a = 59.6\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 59.6\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "4632": {
        "category": "Comparison",
        "question_ko": "20명의 학생들이 한 줄로 줄을 섰습니다. 윤기의 앞에는 11명의 학생들이 서 있고, 호석이는 윤기 바로 앞에 서 있습니다. 호석이 뒤에 서 있는 학생은 몇 명입니까?",
        "question_en": "20 students were lined up. Eleven students are standing in front of Yoongi, and Hoseok is standing right in front of Yoongi. How many students are standing behind Hoseok?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "20 11 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "20 11 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "4633": {
        "category": "Possibility",
        "question_ko": "1, 4, 7, 9 중에서 서로 다른 숫자 2개를 뽑아 만들 수 있는 두 자리 수 중에서 가장 큰 수에서 가장 작은 수를 뺀 값은 얼마입니까?",
        "question_en": "What is the value of the smallest subtracted from the largest two-digit number that can be formed by drawing two different numbers from 1, 4, 7, and 9?",
        "answer_ko": "83",
        "answer_en": "83",
        "solution_abst_ko": "[OP_LIST_SOL] 1 4 7 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 1 4 7 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 1\nvar_b = 4\nvar_c = 7\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 1\nvar_b = 4\nvar_c = 7\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))"
    },
    "4634": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 7을 곱하고 14를 뺀 값이 115.15였습니다. 어떤 수를 7로 나누면 얼마입니까?",
        "question_en": "A number that is multiplied by 7 and subtracted 14 was 115.15. How much is it when this number is divided by 7?",
        "answer_ko": "2.64",
        "answer_en": "2.64",
        "solution_abst_ko": "115.15 14 [OP_ADD] 7 [OP_DIV] 7 [OP_DIV]",
        "solution_abst_en": "115.15 14 [OP_ADD] 7 [OP_DIV] 7 [OP_DIV]",
        "solution_code_ko": "var_a = 115.15\nvar_b = 14\nvar_c = var_a + var_b\nvar_d = 7\nvar_e = var_c / var_d\nvar_f = 7\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 115.15\nvar_b = 14\nvar_c = var_a + var_b\nvar_d = 7\nvar_e = var_c / var_d\nvar_f = 7\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "4635": {
        "category": "Arithmetic calculation",
        "question_ko": "18, 15, 11, 19, 10중에서 15보다 작은 수는 모두 몇 개입니까?",
        "question_en": "How many out of 18, 15, 11, 19, and 10 are less than 15?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 18 15 11 19 10 [OP_LIST_EOL] 15 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 18 15 11 19 10 [OP_LIST_EOL] 15 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 18\nvar_b = 15\nvar_c = 11\nvar_d = 19\nvar_e = 10\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 15\nlist_b = []\nfor i in list_a:\n    if i < var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 18\nvar_b = 15\nvar_c = 11\nvar_d = 19\nvar_e = 10\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 15\nlist_b = []\nfor i in list_a:\n    if i < var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "4636": {
        "category": "Geometry",
        "question_ko": "한 쌍의 변이 평행한 사각형이 있습니다. 평행한 두 변 중 한 변의 길이가 23센티미터(㎝)이고, 두 변 사이의 거리가 12센티미터(㎝)이며, 이 사각형의 넓이가 222제곱센티미터(㎠)일 때, 나머지 한 변의 길이는 몇 센티미터(㎝)일지 구하시오.",
        "question_en": "A quadrilateral has a pair of parallel sides. If the length of one of the two parallel sides is 23 centimeters (cm), the distance between the two sides is 12 centimeters (cm), and the area of this rectangle is 222 square cm (cm2), how many centimeters (cm) is the length of the other side?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "222 2 [OP_MUL] 12 [OP_DIV] 23 [OP_SUB]",
        "solution_abst_en": "222 2 [OP_MUL] 12 [OP_DIV] 23 [OP_SUB]",
        "solution_code_ko": "var_a = 222\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = var_c / var_d\nvar_f = 23\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 222\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = var_c / var_d\nvar_f = 23\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "4637": {
        "category": "Geometry",
        "question_ko": "가로 4센티미터(㎝), 세로 6센티미터(㎝), 높이 5센티미터(㎝)인 직육면체를 잘라서 만들 수 있는 가장 큰 정육면체의 부피는 얼마인가?",
        "question_en": "What is the volume of the largest cube that can be made by cutting a cuboid measuring 4 centimeters (cm) wide by 6 centimeters (cm) long by 5 centimeters (cm) high?",
        "answer_ko": "64",
        "answer_en": "64",
        "solution_abst_ko": "[OP_LIST_SOL] 4 6 4 [OP_LIST_EOL] 1 [OP_LIST_MIN] 1 [OP_LIST_MIN] 3 [OP_POW]",
        "solution_abst_en": "[OP_LIST_SOL] 4 6 4 [OP_LIST_EOL] 1 [OP_LIST_MIN] 1 [OP_LIST_MIN] 3 [OP_POW]",
        "solution_code_ko": "var_a = 4\nvar_b = 6\nvar_c = 4\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nvar_f = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = 3\nvar_i = var_g ** var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 4\nvar_b = 6\nvar_c = 4\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nvar_f = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = 3\nvar_i = var_g ** var_h\nprint(int(var_i))"
    },
    "4638": {
        "category": "Correspondence",
        "question_ko": "서준이는 옆반에서 피자 7/3판을 받아오라는 선생님의 말을 잘못 알아듣고 옆반에 피자 7/3판을 줬더니 현재 서준이가 가진 피자는 3/2판이다. 서준이가 선생님의 심부름을 제대로 했다면 서준이가 가진 피자는 몇 판이어야 하는가?",
        "question_en": "Seojun misunderstood the teacher's words to bring a 7/3 pizza from the next class and gave the 7/3 pizza to the next class. After giving the pizza, Seojun now has 3/2 pizza. If Seojun did the teacher's errand correctly, how many pizzas should Seojun have?",
        "answer_ko": "6.17",
        "answer_en": "6.17",
        "solution_abst_ko": "3/2 7/3 [OP_ADD] 7/3 [OP_ADD]",
        "solution_abst_en": "3/2 7/3 [OP_ADD] 7/3 [OP_ADD]",
        "solution_code_ko": "var_a = 1.5\nvar_b = 2.3333333333333335\nvar_c = var_a + var_b\nvar_d = 2.3333333333333335\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 1.5\nvar_b = 2.3333333333333335\nvar_c = var_a + var_b\nvar_d = 2.3333333333333335\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "4639": {
        "category": "Arithmetic calculation",
        "question_ko": "딸기 3킬로그램(㎏) 300그램(g) 있습니다. 그중에서 1킬로그램(㎏) 900그램(g)을 친구에게 주었을 시 남은 딸기는 몇 그램(g)일까요?",
        "question_en": "There are 3 kilograms (kg) and 300 grams (g) of strawberries. How many grams (g) of strawberries will be left if you give 1 kg (kg) and 900 grams (g) to your friend?",
        "answer_ko": "1400",
        "answer_en": "1400",
        "solution_abst_ko": "3 1000 [OP_MUL] 300 [OP_ADD] 1 1000 [OP_MUL] 900 [OP_ADD] [OP_SUB]",
        "solution_abst_en": "3 1000 [OP_MUL] 300 [OP_ADD] 1 1000 [OP_MUL] 900 [OP_ADD] [OP_SUB]",
        "solution_code_ko": "var_a = 3\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 300\nvar_e = var_c + var_d\nvar_f = 1\nvar_g = 1000\nvar_h = var_f * var_g\nvar_i = 900\nvar_j = var_h + var_i\nvar_k = var_e - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 3\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 300\nvar_e = var_c + var_d\nvar_f = 1\nvar_g = 1000\nvar_h = var_f * var_g\nvar_i = 900\nvar_j = var_h + var_i\nvar_k = var_e - var_j\nprint(int(var_k))"
    },
    "4640": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 8로 나누고 7을 더해야하는데 잘못하여 8을 곱하고 8을 더했더니 56이 되었습니다. 바르게 계산하면 얼마인지 소수점 둘째자리까지 나타내시오.",
        "question_en": "You were supposed to divide a certain number by 8 and add 7, but you mistakenly multiply by 8 and add 8, and you get 56. If you calculate correctly, find a value indicating the number to two decimal places.",
        "answer_ko": "7.75",
        "answer_en": "7.75",
        "solution_abst_ko": "56 8 [OP_SUB] 8 [OP_DIV] 8 [OP_DIV] 7 [OP_ADD]",
        "solution_abst_en": "56 8 [OP_SUB] 8 [OP_DIV] 8 [OP_DIV] 7 [OP_ADD]",
        "solution_code_ko": "var_a = 56\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 8\nvar_e = var_c / var_d\nvar_f = 8\nvar_g = var_e / var_f\nvar_h = 7\nvar_i = var_g + var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 56\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 8\nvar_e = var_c / var_d\nvar_f = 8\nvar_g = var_e / var_f\nvar_h = 7\nvar_i = var_g + var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "4641": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 엘리베이터가 지상 120미터(m)에서 출발하여, 한 번도 멈추지 않고 초속 4미터(m)의 속도로 내려올 때, 출발한 지 20초 후 엘리베이터의 높이는 지상 몇 미터(m)인지 구하시오.",
        "question_en": "If an elevator starts at 120 meters (m) above the ground and descends at a speed of 4 meters (m) per second without stopping once, find the height of the elevator 20 seconds after starting in meters (m).",
        "answer_ko": "40",
        "answer_en": "40",
        "solution_abst_ko": "120 4 20 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "120 4 20 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 120\nvar_b = 4\nvar_c = 20\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 120\nvar_b = 4\nvar_c = 20\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "4642": {
        "category": "Geometry",
        "question_ko": "도화지에 직각삼각형을 그렸습니다. 빗변이 아닌 한 변의 길이를 5로, 나머지 빗변이 아닌 한 변의 길이를 12로 그렸을 때 빗변은 얼마로 그렸을까요?",
        "question_en": "You drew a right triangle on drawing paper. If the length of one non-hypotenuse is 5 and the length of the other non-hypotenuse is 12, how much would the hypotenuse's length be?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "12 2 [OP_POW] 5 2 [OP_POW] [OP_ADD] 1/2 [OP_POW]",
        "solution_abst_en": "12 2 [OP_POW] 5 2 [OP_POW] [OP_ADD] 1/2 [OP_POW]",
        "solution_code_ko": "var_a = 12\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c + var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 12\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c + var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))"
    },
    "4643": {
        "category": "Correspondence",
        "question_ko": "9/7에 어떤 수를 더하면 13/5이다 어떤 수에 13/5를 더하면 얼마입니까?",
        "question_en": "A number added to 9/7 is 13/5. What do you get when 13/5 is added to the number?",
        "answer_ko": "3.91",
        "answer_en": "3.91",
        "solution_abst_ko": "13/5 9/7 [OP_SUB] 13/5 [OP_ADD]",
        "solution_abst_en": "13/5 9/7 [OP_SUB] 13/5 [OP_ADD]",
        "solution_code_ko": "var_a = 2.6\nvar_b = 1.2857142857142858\nvar_c = var_a - var_b\nvar_d = 2.6\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 2.6\nvar_b = 1.2857142857142858\nvar_c = var_a - var_b\nvar_d = 2.6\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "4644": {
        "category": "Arithmetic calculation",
        "question_ko": "총 55명의 학생이 모두 경기를 참여하였는데, (가) 경기와 (나) 경기에 각각 참여한 학생 수를 세어보니 38명, 42명이었습니다. (가) 시합과 (나) 시합에 모두 참가한 학생은 몇 명인지 구하세요.",
        "question_en": "A total of 55 students participated in the game, and when counted the number of students who participated in A and B game, there were 38 and 42 students respectively. Find how many students participated in both A and B game.",
        "answer_ko": "25",
        "answer_en": "25",
        "solution_abst_ko": "38 42 [OP_ADD] 55 [OP_SUB]",
        "solution_abst_en": "38 42 [OP_ADD] 55 [OP_SUB]",
        "solution_code_ko": "var_a = 38\nvar_b = 42\nvar_c = var_a + var_b\nvar_d = 55\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 38\nvar_b = 42\nvar_c = var_a + var_b\nvar_d = 55\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "4645": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 10, 11, 12, 13이 있습니다. 그 중에서 가장 작은 수와 2번째로 작은 수의 합은 얼마입니까?",
        "question_en": "There are four numbers: 10, 11, 12, and 13. What is the sum of the smallest number and the second smallest number?",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))"
    },
    "4646": {
        "category": "Correspondence",
        "question_ko": "백의 자리 숫자가 5인 세 자리 수이면서 12의 배수 중 가장 큰 수는 얼마입니까?",
        "question_en": "What is the largest multiple of 12, a three-digit number with 5 in the hundreds place?",
        "answer_ko": "588",
        "answer_en": "588",
        "solution_abst_ko": "5 100 [OP_MUL] 5 1 [OP_ADD] 100 [OP_MUL] 1 [OP_SUB] 1 [OP_LIST_ARANGE] 12 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_abst_en": "5 100 [OP_MUL] 5 1 [OP_ADD] 100 [OP_MUL] 1 [OP_SUB] 1 [OP_LIST_ARANGE] 12 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 5\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = 100\nvar_h = var_f * var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = 1\nlist_a = [i for i in range(var_c, var_j + 1, var_k)]\nvar_l = 12\nlist_b = []\nvar_l = int(var_l)\nfor i in list_a:\n    i = int(i)\n    if i % var_l == 0:\n        list_b.append(i)\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nprint(int(var_n))",
        "solution_code_en": "var_a = 5\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = 100\nvar_h = var_f * var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = 1\nlist_a = [i for i in range(var_c, var_j + 1, var_k)]\nvar_l = 12\nlist_b = []\nvar_l = int(var_l)\nfor i in list_a:\n    i = int(i)\n    if i % var_l == 0:\n        list_b.append(i)\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nprint(int(var_n))"
    },
    "4647": {
        "category": "Correspondence",
        "question_ko": "ABC+ABC+ABC+ABC=1436입니다. A, B, C는 서로 다른 세 수일 때 A+B+C를 구하시오.",
        "question_en": "ABC+ABC+ABC+ABC=1436. Find A+B+C when A, B, and C are three different numbers.",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "[OP_LIST_SOL] ABC+ABC+ABC+ABC=1436 A [OP_DIGIT_UNK_SOLVER] ABC+ABC+ABC+ABC=1436 B [OP_DIGIT_UNK_SOLVER] ABC+ABC+ABC+ABC=1436 C [OP_DIGIT_UNK_SOLVER] [OP_LIST_EOL] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] ABC+ABC+ABC+ABC=1436 A [OP_DIGIT_UNK_SOLVER] ABC+ABC+ABC+ABC=1436 B [OP_DIGIT_UNK_SOLVER] ABC+ABC+ABC+ABC=1436 C [OP_DIGIT_UNK_SOLVER] [OP_LIST_EOL] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 'ABC+ABC+ABC+ABC=1436'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 'ABC+ABC+ABC+ABC=1436'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = 'ABC+ABC+ABC+ABC=1436'\nvar_h = 'C'\nans_dict = dict()\nvar_g = var_g.replace('×','*')\nvar_g = var_g.replace('x','*')\nvar_g = var_g.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_g):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_g\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_g):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_i = ans_dict[var_h]\nlist_a= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_j = sum(list_a)\nprint(int(var_j))",
        "solution_code_en": "var_a = 'ABC+ABC+ABC+ABC=1436'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 'ABC+ABC+ABC+ABC=1436'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = 'ABC+ABC+ABC+ABC=1436'\nvar_h = 'C'\nans_dict = dict()\nvar_g = var_g.replace('×','*')\nvar_g = var_g.replace('x','*')\nvar_g = var_g.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_g):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_g\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_g):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_i = ans_dict[var_h]\nlist_a= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_j = sum(list_a)\nprint(int(var_j))"
    },
    "4648": {
        "category": "Arithmetic calculation",
        "question_ko": "농장에서 암탉 52마리를 기릅니다. 암탉은 수탉보다 16마리 적습니다. 농장에 있는 닭은 모두 몇 마리입니까?",
        "question_en": "There are 52 hens on the farm. Hens are 16 fewer than roosters. How many chickens are there on the farm?",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "52 52 16 [OP_ADD] [OP_ADD]",
        "solution_abst_en": "52 52 16 [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 52\nvar_b = 52\nvar_c = 16\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 52\nvar_b = 52\nvar_c = 16\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "4649": {
        "category": "Geometry",
        "question_ko": "가로가 18센티미터(㎝), 세로가 6센티미터(㎝), 높이가 6센티미터(㎝)인 직육면체 모양의 나무토막을 한 모서리의 길이가 6센티미터(㎝)인 정육면체 3개로 잘랐을 때, 겉넓이는 몇 c㎡ 늘어납니까?",
        "question_en": "When a cuboid-shaped block of wood measuring 18 centimeters (cm) wide, 6 centimeters (cm) long, and 6 cm (height) is cut into three cubes with a side of 6 centimeters (cm) long,  How many the surface area cm2 does it increase?",
        "answer_ko": "288",
        "answer_en": "288",
        "solution_abst_ko": "3 6 3 [OP_POW] [OP_MUL] 18 6 [OP_MUL] 6 6 [OP_MUL] [OP_ADD] 6 6 [OP_MUL] [OP_ADD] 2 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "3 6 3 [OP_POW] [OP_MUL] 18 6 [OP_MUL] 6 6 [OP_MUL] [OP_ADD] 6 6 [OP_MUL] [OP_ADD] 2 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 3\nvar_b = 6\nvar_c = 3\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 18\nvar_g = 6\nvar_h = var_f * var_g\nvar_i = 6\nvar_j = 6\nvar_k = var_i * var_j\nvar_l = var_h + var_k\nvar_m = 6\nvar_n = 6\nvar_o = var_m * var_n\nvar_p = var_l + var_o\nvar_q = 2\nvar_r = var_p * var_q\nvar_s = var_e - var_r\nprint(int(var_s))",
        "solution_code_en": "var_a = 3\nvar_b = 6\nvar_c = 3\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 18\nvar_g = 6\nvar_h = var_f * var_g\nvar_i = 6\nvar_j = 6\nvar_k = var_i * var_j\nvar_l = var_h + var_k\nvar_m = 6\nvar_n = 6\nvar_o = var_m * var_n\nvar_p = var_l + var_o\nvar_q = 2\nvar_r = var_p * var_q\nvar_s = var_e - var_r\nprint(int(var_s))"
    },
    "4650": {
        "category": "Geometry",
        "question_ko": "가로가 18미터(m), 세로가 10미터(m), 높이가 2미터(m)인 직육면체 모양의 연못을 만들었습니다. 연못 안쪽 전체를 페인트로 칠하려고 할 때, 색을 칠할 부분의 넓이는 몇 ㎡입니까?",
        "question_en": "You built a cuboid-shaped pond with a length of 18 meters (m), a width of 10 meters (m), and a height of 2 meters (m). If you are going to paint the inner side of the pond, how many square meters (㎡) of the pond could be painted?",
        "answer_ko": "292",
        "answer_en": "292",
        "solution_abst_ko": "18 10 [OP_MUL] 10 2 [OP_MUL] 2 18 [OP_MUL] [OP_ADD] 2 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "18 10 [OP_MUL] 10 2 [OP_MUL] 2 18 [OP_MUL] [OP_ADD] 2 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 18\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 10\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = 2\nvar_h = 18\nvar_i = var_g * var_h\nvar_j = var_f + var_i\nvar_k = 2\nvar_l = var_j * var_k\nvar_m = var_c + var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 18\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 10\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = 2\nvar_h = 18\nvar_i = var_g * var_h\nvar_j = var_f + var_i\nvar_k = 2\nvar_l = var_j * var_k\nvar_m = var_c + var_l\nprint(int(var_m))"
    },
    "4651": {
        "category": "Comparison",
        "question_ko": "정국이는 4와 4를 모았습니다. 지민이는 3과 6을 모았습니다. 누가 모은 수가 더 큽니까?",
        "question_en": "Jungkook puts 4 and 4 together. Jimin puts 3 and 6 together. Who has the greater number?",
        "answer_ko": "지민",
        "answer_en": "Jimin",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 지민 [OP_LIST_EOL] [OP_LIST_SOL] 4 4 [OP_ADD] 3 6 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Jimin [OP_LIST_EOL] [OP_LIST_SOL] 4 4 [OP_ADD] 3 6 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '지민'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = 6\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Jimin'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = 6\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "4652": {
        "category": "Comparison",
        "question_ko": "주희와 준성이는 25개의 초콜릿을 나누어 먹으려고 합니다. 주희가 준성이가 먹는 초콜릿의 2배보다 1개 더 먹었을 때 주희는 몇 개의 초콜릿을 먹었는지 구하시오.",
        "question_en": "Joo-hee and Jun-seong want to share 25 chocolates. Find how many chocolates Joo-hee ate when Joo-hee ate 1 more chocolate than twice Jun-seong ate.",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "25 1 [OP_SUB] 2 1 [OP_ADD] [OP_DIV] 2 [OP_MUL] 1 [OP_ADD]",
        "solution_abst_en": "25 1 [OP_SUB] 2 1 [OP_ADD] [OP_DIV] 2 [OP_MUL] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 25\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = var_c / var_f\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = 1\nvar_k = var_i + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 25\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = var_c / var_f\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = 1\nvar_k = var_i + var_j\nprint(int(var_k))"
    },
    "4653": {
        "category": "Geometry",
        "question_ko": "재웅이가 그린 마름모 모양의 지붕은 한 대각선의 길이가 16 센티미터(㎝)이고, 넓이가 80제곱센티미터(㎠)입니다. 이 지붕의 다른 대각선의 길이는 몇 센티미터(㎝)일까요?",
        "question_en": "The diamond-shaped roof drawn by Jaewoong has a diagonal of 16 centimeters (cm) and an area of 80 square centimeters (cm2). How many centimeters (cm) is the length of the other diagonal of this roof?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "80 2 [OP_MUL] 16 [OP_DIV]",
        "solution_abst_en": "80 2 [OP_MUL] 16 [OP_DIV]",
        "solution_code_ko": "var_a = 80\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 16\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 80\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 16\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "4654": {
        "category": "Arithmetic calculation",
        "question_ko": "두 자리 수 중 36보다 작고 29보다 큰 수는 모두 몇 개입니까?",
        "question_en": "How many two-digit numbers are less than 36 and greater than 29?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "29 1 [OP_ADD] 36 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_LEN]",
        "solution_abst_en": "29 1 [OP_ADD] 36 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 29\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 36\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = len(list_a)\nprint(int(var_h))",
        "solution_code_en": "var_a = 29\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 36\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = len(list_a)\nprint(int(var_h))"
    },
    "4655": {
        "category": "Correspondence",
        "question_ko": "A는 한 자리 수입니다. 한 자리 수끼리의 곱셈식 A×A×A=21A 을 만족할 때 A를 구하시오.",
        "question_en": "A is a single-digit number. Find A when the multiplication of single-digit numbers A×A×A is the same as 21A.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "A×A×A=21A A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A×A×A=21A A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A×A×A=21A'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A×A×A=21A'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "4656": {
        "category": "Arithmetic calculation",
        "question_ko": "박물관에 남자가 194명, 여자가 235명 관람 중이고, 그중에서 무료입장한 사람이 68명입니다. 박물관에 유료입장한 사람은 무료입장한 사람보다 몇 명 더 많은지 구하시오.",
        "question_en": "There are 194 men and 235 women in the museum, and 68 of them got free admission. Find how many more people paid for admission to the museum than those who got free admission.",
        "answer_ko": "293",
        "answer_en": "293",
        "solution_abst_ko": "194 235 [OP_ADD] 68 [OP_SUB] 68 [OP_SUB]",
        "solution_abst_en": "194 235 [OP_ADD] 68 [OP_SUB] 68 [OP_SUB]",
        "solution_code_ko": "var_a = 194\nvar_b = 235\nvar_c = var_a + var_b\nvar_d = 68\nvar_e = var_c - var_d\nvar_f = 68\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 194\nvar_b = 235\nvar_c = var_a + var_b\nvar_d = 68\nvar_e = var_c - var_d\nvar_f = 68\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "4657": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.3, 1/3 중 0.4보다 큰 수의 개수를 구하시오.",
        "question_en": "Find the number of numbers greater than 0.4 among 0.8, 1/2, 0.3, and 1/3.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.3 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.3 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.3\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.4\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.3\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.4\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "4658": {
        "category": "Correspondence",
        "question_ko": "네 수 A, B, C, D가 네 자리 수 뺄셈식 A05B-1C04=30D8을 만족한다면, A+B-C+D를 했을 때의 결과를 구하시오.",
        "question_en": "If the four numbers A, B, C, and D satisfy the four-digit subtraction formula A05B-1C04=30D8, find the value of A+B-C+D.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "A05B-1C04=30D8 A [OP_DIGIT_UNK_SOLVER] A05B-1C04=30D8 B [OP_DIGIT_UNK_SOLVER] [OP_ADD] A05B-1C04=30D8 C [OP_DIGIT_UNK_SOLVER] [OP_SUB] A05B-1C04=30D8 D [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_abst_en": "A05B-1C04=30D8 A [OP_DIGIT_UNK_SOLVER] A05B-1C04=30D8 B [OP_DIGIT_UNK_SOLVER] [OP_ADD] A05B-1C04=30D8 C [OP_DIGIT_UNK_SOLVER] [OP_SUB] A05B-1C04=30D8 D [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_code_ko": "var_a = 'A05B-1C04=30D8'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 'A05B-1C04=30D8'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nvar_h = 'A05B-1C04=30D8'\nvar_i = 'C'\nans_dict = dict()\nvar_h = var_h.replace('×','*')\nvar_h = var_h.replace('x','*')\nvar_h = var_h.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_h):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_h\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_h):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_j = ans_dict[var_i]\nvar_k = var_g - var_j\nvar_l = 'A05B-1C04=30D8'\nvar_m = 'D'\nans_dict = dict()\nvar_l = var_l.replace('×','*')\nvar_l = var_l.replace('x','*')\nvar_l = var_l.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_l):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_l\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_l):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_n = ans_dict[var_m]\nvar_o = var_k + var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 'A05B-1C04=30D8'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 'A05B-1C04=30D8'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nvar_h = 'A05B-1C04=30D8'\nvar_i = 'C'\nans_dict = dict()\nvar_h = var_h.replace('×','*')\nvar_h = var_h.replace('x','*')\nvar_h = var_h.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_h):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_h\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_h):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_j = ans_dict[var_i]\nvar_k = var_g - var_j\nvar_l = 'A05B-1C04=30D8'\nvar_m = 'D'\nans_dict = dict()\nvar_l = var_l.replace('×','*')\nvar_l = var_l.replace('x','*')\nvar_l = var_l.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_l):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_l\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_l):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_n = ans_dict[var_m]\nvar_o = var_k + var_n\nprint(int(var_o))"
    },
    "4659": {
        "category": "Possibility",
        "question_ko": "상자 안에는 파란 공 3개와 빨간 공 5개가 있습니다. 2개의 빨간 공을 넣었을 때, 상자 안의 파란 공의 개수는?",
        "question_en": "There are 3 blue balls and 5 red balls in the box. When 2 red balls are placed inside the box, how many blue balls are in the box?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "3",
        "solution_abst_en": "3",
        "solution_code_ko": "var_a = 3\nprint(int(var_a))",
        "solution_code_en": "var_a = 3\nprint(int(var_a))"
    },
    "4660": {
        "category": "Correspondence",
        "question_ko": "영수가 효근이에게 200원, 효근이가 웅이에게 500원, 웅이가 영수에게 1000원을 차례대로 주었더니, 세 사람이 갖게 된 돈은 각각 2000원입니다. 영수가 처음에 갖고 있던 돈은 얼마입니까?",
        "question_en": "Yeongsoo gave Hyogeun 200 won, Hyogeun gave Woong 500 won, and Woong gave Yeongsoo 1000 won. As a result, they have 2000 won respectively. How much money did Yeongsoo have at first?",
        "answer_ko": "1200",
        "answer_en": "1200",
        "solution_abst_ko": "2000 1000 [OP_SUB] 200 [OP_ADD]",
        "solution_abst_en": "2000 1000 [OP_SUB] 200 [OP_ADD]",
        "solution_code_ko": "var_a = 2000\nvar_b = 1000\nvar_c = var_a - var_b\nvar_d = 200\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 2000\nvar_b = 1000\nvar_c = var_a - var_b\nvar_d = 200\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "4661": {
        "category": "Geometry",
        "question_ko": "축척이 1/250000인 지도가 있을 때, 실제 거리가 5 킬로미터(㎞)인 두 지점의 지도에서의 거리(센티미터(㎝))를 구하시오.",
        "question_en": "Given a map with a scale of 1/250000, find the distance in centimeters (cm) on the map of two points whose actual distance is 5 kilometers (km).",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "5 100 1000 [OP_MUL] [OP_MUL] 1/250000 [OP_MUL]",
        "solution_abst_en": "5 100 1000 [OP_MUL] [OP_MUL] 1/250000 [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 100\nvar_c = 1000\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nvar_f = 4e-06\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 100\nvar_c = 1000\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nvar_f = 4e-06\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "4662": {
        "category": "Geometry",
        "question_ko": "어떤 수에 2를 곱한 값을 16으로 나누면 몫이 25이다. 어떤 수를 구하시오.",
        "question_en": "If you multiply a number by 2 and divide it by 16, the quotient is 25. Find what the number is.",
        "answer_ko": "200",
        "answer_en": "200",
        "solution_abst_ko": "25 16 [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "25 16 [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 25\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 25\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "4663": {
        "category": "Geometry",
        "question_ko": "직사각형 모양의 농장이 있습니다. 긴 변의 길이는 1킬로미터(㎞)이고, 짧은 변의 길이는 긴 변의 길이보다 2/8킬로미터(㎞) 짧습니다. 농장 둘레를 따라 한 바퀴 걷는다면 몇 킬로미터(㎞)를 걸어야 합니까?",
        "question_en": "There is a rectangular farm. The length of the long side is 1 kilometer (km), and the length of the short side is 2/8 km (km) shorter than the length of the long side. How many kilometers (km) will you have to walk if you walk around the farm once?",
        "answer_ko": "3.50",
        "answer_en": "3.5",
        "solution_abst_ko": "1 1 2/8 [OP_SUB] [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "1 1 2/8 [OP_SUB] [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 1\nvar_b = 1\nvar_c = 0.25\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 1\nvar_c = 0.25\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "4664": {
        "category": "Geometry",
        "question_ko": "미향이는 색종이를 한 변의 길이가 5센티미터(㎝)가 되도록 정육각형 모양으로 잘랐습니다. 이 정육각형의 둘레는 몇 센티미터(㎝)입니까?",
        "question_en": "Mihyang cut the colored paper into regular hexagons so that each side is 5 centimeters (cm) long. What is the perimeter of this regular hexagon in centimeters (cm)?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "5 6 [OP_MUL]",
        "solution_abst_en": "5 6 [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 6\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 6\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "4665": {
        "category": "Geometry",
        "question_ko": "넓이가 24.48제곱센티미터(㎠)인 마름모가 있습니다. 이 마름모의 한 대각선이 8센티미터(㎝)일 때 이 대각선과 다른 대각선의 길이의 차를 구하시오.",
        "question_en": "There is a rhombus with an area of 24.48 square centimeters (cm2). If one diagonal of this rhombus is 8 centimeters (cm), find the difference between the length of this diagonal and the other diagonal.",
        "answer_ko": "1.88",
        "answer_en": "1.88",
        "solution_abst_ko": "8 24.48 2 [OP_MUL] 8 [OP_DIV] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "8 24.48 2 [OP_MUL] 8 [OP_DIV] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 8\nvar_b = 24.48\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = 8\nvar_f = var_d / var_e\nvar_g = var_a - var_f\nvar_h = abs(var_g)\nprint('{:.2f}'.format(round(var_h+1e-10,2)))",
        "solution_code_en": "var_a = 8\nvar_b = 24.48\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = 8\nvar_f = var_d / var_e\nvar_g = var_a - var_f\nvar_h = abs(var_g)\nprint('{:.2f}'.format(round(var_h+1e-10,2)))"
    },
    "4666": {
        "category": "Comparison",
        "question_ko": "총 4개의 숫자 0.8, 1/2, 0.5, 1/3이 있습니다. 이 중 3보다 작은 수 중 가장 큰 수를 구하면 무엇인가요?",
        "question_en": "There are a total of 4 numbers: 0.8, 1/2, 0.5, 1/3. What is the largest of these numbers that are less than 3?",
        "answer_ko": "0.80",
        "answer_en": "0.8",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.5 1/3 [OP_LIST_EOL] 3 [OP_LIST_LESS] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.5 1/3 [OP_LIST_EOL] 3 [OP_LIST_LESS] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.5\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = []\nfor i in list_a:\n    if i < var_e:\n        list_b.append(i)\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.5\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = []\nfor i in list_a:\n    if i < var_e:\n        list_b.append(i)\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "4667": {
        "category": "Comparison",
        "question_ko": "석진이와 태형이는 어제와 오늘 이틀동안 줄넘기를 했습니다. 석진이는 어제보다 오늘 15개 많이 했고, 태형이는 어제보타 오늘 12번 더 적게 했습니다. 석진이와 태형이가 어제 한 줄넘기의 수가 각각 32번, 58번이라면, 오늘 줄넘기를 더 많이 넘은 사람은 누구인지 구하시오.",
        "question_en": "Seokjin and Taehyung jumped ropes for two days yesterday and today. Seokjin did 15 more today than yesterday, and Taehyung did 12 fewer today than yesterday. If Seokjin and Taehyung jumped ropes 32 times and 58 times respectively yesterday, then find out who skipped more ropes today.",
        "answer_ko": "석진",
        "answer_en": "Seokjin",
        "solution_abst_ko": "[OP_LIST_SOL] 석진 태형 [OP_LIST_EOL] [OP_LIST_SOL] 32 15 [OP_ADD] 58 12 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Seokjin Taehyung [OP_LIST_EOL] [OP_LIST_SOL] 32 15 [OP_ADD] 58 12 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '석진'\nvar_b = '태형'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 32\nvar_d = 15\nvar_e = var_c + var_d\nvar_f = 58\nvar_g = 12\nvar_h = var_f - var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Seokjin'\nvar_b = 'Taehyung'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 32\nvar_d = 15\nvar_e = var_c + var_d\nvar_f = 58\nvar_g = 12\nvar_h = var_f - var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "4668": {
        "category": "Arithmetic calculation",
        "question_ko": "똑같은 동화책 12권이 들어있는 상자의 무게를 재어 보니 11.48킬로그램(㎏)이었습니다. 이 상자에서 동화책 4권을 뺀 다음 다시 무게를 재었더니 8.12킬로그램(㎏) 이 되었습니다. 빈 상자의 무게는 몇 킬로그램(㎏)인지 구하시오.",
        "question_en": "The box, which had 12 identical children's books inside, weighed 11.48 kilograms (kg). When 4 children's books were removed from the box, it weighed 8.12 kilograms (kg). What is the weight of the empty box in kilograms (kg)?",
        "answer_ko": "1.40",
        "answer_en": "1.4",
        "solution_abst_ko": "11.48 11.48 8.12 [OP_SUB] 4 [OP_DIV] 12 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "11.48 11.48 8.12 [OP_SUB] 4 [OP_DIV] 12 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 11.48\nvar_b = 11.48\nvar_c = 8.12\nvar_d = var_b - var_c\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = 12\nvar_h = var_f * var_g\nvar_i = var_a - var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 11.48\nvar_b = 11.48\nvar_c = 8.12\nvar_d = var_b - var_c\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = 12\nvar_h = var_f * var_g\nvar_i = var_a - var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "4669": {
        "category": "Comparison",
        "question_ko": "일의 자리 숫자가 3 이고, 소수 첫째 자리 숫자와 소수 둘째 자리 숫자가 0, 소수 셋째 자리 숫자가 6 인 수보다 큰 수 중에서 3.01 보다 작은 소수 세 자리 수는 모두 몇 개입니까?",
        "question_en": "Find out how many three-digit prime numbers exist, which are less than 3.01 but greater than 3, and have 3 as its units digit, 0 and 6 as the 1st and 2nd decimal place, and 6 as the 3rd decimal place.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "0 9 1 [OP_LIST_ARANGE] 6 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "0 9 1 [OP_LIST_ARANGE] 6 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 0\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "4670": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 50까지 종이에 차례대로 한 번씩 쓸 때, 1은 몇 번 쓰게 되는지 구하시오.",
        "question_en": "If you write down the numbers 1 through 50 once on a piece of paper, find how many times you write 1.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "1 50 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 1 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 50 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 1 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 50\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 1\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 50\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 1\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))"
    },
    "4671": {
        "category": "Possibility",
        "question_ko": "정국이는 빨간 공 3개가 들어 있는 상자 2개를 샀습니다. 정국이가 가지고 있는 빨간 공의 개수는?",
        "question_en": "Jungkook bought two boxes each containing three red balls. How many red balls does Jungkook have?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "3 2 [OP_MUL]",
        "solution_abst_en": "3 2 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "4672": {
        "category": "Arithmetic calculation",
        "question_ko": "귤 24개와 사과 18개를 한 박스에 담아 포장하려한다. 남는 사과나 귤이 없고 박스마다 똑같은 개수로 담는다고 할 때, 최대 몇 박스를 만들 수 있는지 구하시오.",
        "question_en": "You are trying to pack 24 tangerines and 18 apples in one box. If there are no remaining apples or tangerines and each box contains the same number, find the maximum number of boxes you can make.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "24 18 [OP_GCD]",
        "solution_abst_en": "24 18 [OP_GCD]",
        "solution_code_ko": "var_a = 24\nvar_b = 18\nvar_c = math.gcd(int(var_b), int(var_a))\nprint(int(var_c))",
        "solution_code_en": "var_a = 24\nvar_b = 18\nvar_c = math.gcd(int(var_b), int(var_a))\nprint(int(var_c))"
    },
    "4673": {
        "category": "Geometry",
        "question_ko": "준영이는 지름이 50센티미터(㎝)인 굴렁쇠를 갖고 있습니다. 이 굴렁쇠를 몇 바퀴 굴렸더니 6미터(m) 28센티미터(㎝)만큼 앞으로 나아갔습니다. 원주율이 3.14라면, 굴렁쇠를 몇 바퀴 굴려야 합니까?",
        "question_en": "Junyoung has a hoop with a diameter of 50 centimeters (cm). After rolling this hoop several times, it moved forward by 6 meters (m) and 28 centimeters (cm). If the pi is 3.14, how many times does the hoop need to be rolled?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "6 100 [OP_MUL] 28 [OP_ADD] 50 3.14 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "6 100 [OP_MUL] 28 [OP_ADD] 50 3.14 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 28\nvar_e = var_c + var_d\nvar_f = 50\nvar_g = 3.14\nvar_h = var_f * var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 6\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 28\nvar_e = var_c + var_d\nvar_f = 50\nvar_g = 3.14\nvar_h = var_f * var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "4674": {
        "category": "Arithmetic calculation",
        "question_ko": "유정이 이모는 조카 윤기에게 당근을 3개 주었습니다. 윤기의 누나는 윤기에게 2개를 주었습니다. 윤기가 가진 당근은 몇 개입니까?",
        "question_en": "Aunt Yujeong gave three carrots to her nephew, Yoongi. Yoongi's older sister received 4, but she gave 2 to Yoongi again. How many carrots does Yoongi have?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "3 2 [OP_ADD]",
        "solution_abst_en": "3 2 [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "4675": {
        "category": "Correspondence",
        "question_ko": "지민이는 34에 어떤 수를 빼려고 합니다. 실수로 96에 어떤 수를 나눴을 때의 결과가 6이라면 바르게 계산한 결과를 구하세요.",
        "question_en": "Jimin is trying to subtract a number from 34. If the result of mistakenly dividing 96 by a number is 6, find the correct result.",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "34 96 6 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "34 96 6 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 34\nvar_b = 96\nvar_c = 6\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 34\nvar_b = 96\nvar_c = 6\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "4676": {
        "category": "Possibility",
        "question_ko": "0부터 9까지의 숫자 중 겹치는 것 없이 네 개를 뽑고 이것으로 네 자리 수를 만들었습니다. 만들 수 있는 경우 중 두 번째로 큰 수와 두 번째로 작은 수의 차는 얼마입니까?",
        "question_en": "Four non-overlapping numbers from 0 to 9 were drawn and made a four-digit number. What is the difference between the second largest and the second smallest possible cases?",
        "answer_ko": "8851",
        "answer_en": "8851",
        "solution_abst_ko": "0 9 1 [OP_LIST_ARANGE] 4 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "0 9 1 [OP_LIST_ARANGE] 4 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 0\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 2\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 0\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 2\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))"
    },
    "4677": {
        "category": "Possibility",
        "question_ko": "6명의 학생이 강당에 있을 때, 반장 1명, 사회자 1명, 부반장 1명, 부사회자 1명을 뽑는 경우의 수를 구하시오.",
        "question_en": "If there are 6 students in the auditorium, find the number of cases in which 1 class president, 1 moderator, 1 vice-president, and 1 assistant moderator are selected.",
        "answer_ko": "360",
        "answer_en": "360",
        "solution_abst_ko": "6 1 1 [OP_ADD] 1 [OP_ADD] 1 [OP_ADD] [OP_PERM]",
        "solution_abst_en": "6 1 1 [OP_ADD] 1 [OP_ADD] 1 [OP_ADD] [OP_PERM]",
        "solution_code_ko": "var_a = 6\nvar_b = 1\nvar_c = 1\nvar_d = var_b + var_c\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = 1\nvar_a = int(var_a)\nvar_h = int(var_h)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i * (var_a-i)\nprint(int(var_i))",
        "solution_code_en": "var_a = 6\nvar_b = 1\nvar_c = 1\nvar_d = var_b + var_c\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = 1\nvar_a = int(var_a)\nvar_h = int(var_h)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i * (var_a-i)\nprint(int(var_i))"
    },
    "4678": {
        "category": "Comparison",
        "question_ko": "0.9, 5/10, 1, 7/10, 1.2 중 0.8보다 큰 수는 몇 개입니까?",
        "question_en": "How many of 0.9, 5/10, 1, 7/10, and 1.2 are greater than 0.8?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 0.9 5/10 1 7/10 1.2 [OP_LIST_EOL] 0.8 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.9 5/10 1 7/10 1.2 [OP_LIST_EOL] 0.8 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.9\nvar_b = 0.5\nvar_c = 1\nvar_d = 0.7\nvar_e = 1.2\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 0.8\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 0.9\nvar_b = 0.5\nvar_c = 1\nvar_d = 0.7\nvar_e = 1.2\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 0.8\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "4679": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.9의 숫자가 있다. 이 중 0.6보다 작거나 같은 숫자들 중 가장 크거나 같은 수를 구하시오.",
        "question_en": "There are numbers 0.8, 1/2, and 0.9. Find the greatest number among the given numbers less than or equal to 0.6.",
        "answer_ko": "0.50",
        "answer_en": "0.5",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 0.6 [OP_LIST_LESS_EQUAL] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 0.6 [OP_LIST_LESS_EQUAL] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.6\nlist_b = []\nfor i in list_a:\n    if i <= var_d:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint('{:.2f}'.format(round(var_f+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.6\nlist_b = []\nfor i in list_a:\n    if i <= var_d:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint('{:.2f}'.format(round(var_f+1e-10,2)))"
    },
    "4680": {
        "category": "Possibility",
        "question_ko": "자판기에서 숫자 젤리 3개를 뽑았더니 0, 1, 5가 나왔습니다. 3개의 젤리 중 2개를 사용하여 만들 수 있는 두 자리 수는 모두 몇 개 입니까?",
        "question_en": "You took three number jellies from the vending machine and they were numbered 0, 1, and 5. If you use two out of three jellies, how many two-digit numbers can you create?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "4681": {
        "category": "Geometry",
        "question_ko": "가로 8센티미터(㎝), 세로 5센티미터(㎝), 높이 10센티미터(㎝)인 직육면체의 겉넓이는 얼마입니까?",
        "question_en": "What is the surface area of a cuboid that is 8 centimeters (cm) wide, 5 centimeters (cm) long, and 10 centimeters (cm) height?",
        "answer_ko": "340",
        "answer_en": "340",
        "solution_abst_ko": "8 5 [OP_MUL] 8 10 [OP_MUL] [OP_ADD] 5 10 [OP_MUL] [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "8 5 [OP_MUL] 8 10 [OP_MUL] [OP_ADD] 5 10 [OP_MUL] [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = 10\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 5\nvar_i = 10\nvar_j = var_h * var_i\nvar_k = var_g + var_j\nvar_l = 2\nvar_m = var_k * var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 8\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = 10\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 5\nvar_i = 10\nvar_j = var_h * var_i\nvar_k = var_g + var_j\nvar_l = 2\nvar_m = var_k * var_l\nprint(int(var_m))"
    },
    "4682": {
        "category": "Comparison",
        "question_ko": "수 5개 1.4, 9/10, 1.2, 0.5, 13/10 중 1.1보다 크거나 같은 숫자를 구하고, 그 숫자들의 합을 구하면 얼마입니까?",
        "question_en": "Find the sum of the numbers that are greater than or equal to 1.1 among the five numbers 1.4, 9/10, 1.2, 0.5, and 13/10.",
        "answer_ko": "3.90",
        "answer_en": "3.9",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE_EQUAL] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE_EQUAL] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i >= var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i >= var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "4683": {
        "category": "Geometry",
        "question_ko": "직각삼각형에서, 빗변이 아닌 한 변의 길이가 6이고, 빗변의 길이가 10이면, 나머지 한 변의 길이는 얼마입니까?",
        "question_en": "In a right triangle, if the length of the non-hypotenuse is 6 and the length of the hypotenuse is 10, what is the length of the other side?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "10 2 [OP_POW] 6 2 [OP_POW] [OP_SUB] 1/2 [OP_POW]",
        "solution_abst_en": "10 2 [OP_POW] 6 2 [OP_POW] [OP_SUB] 1/2 [OP_POW]",
        "solution_code_ko": "var_a = 10\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c - var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c - var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))"
    },
    "4684": {
        "category": "Arithmetic calculation",
        "question_ko": "일정한 빠르기로 1분에 2.1킬로미터(㎞)를 달리는 트럭과 4분에 10.5킬로미터(㎞)를 달리는 택시가 있습니다. 택시와 트럭 중 더 빠른 것은 몇 배나 더 빠른가?",
        "question_en": "A truck travels 2.1 kilometers (km) in 1 minute at a constant speed, while a taxi covers 10.5 km in 4 minutes. Which vehicle is quicker, the taxi or truck, by how many times?",
        "answer_ko": "1.25",
        "answer_en": "1.25",
        "solution_abst_ko": "10.5 4 [OP_DIV] 2.1 1 [OP_DIV] [OP_DIV]",
        "solution_abst_en": "10.5 4 [OP_DIV] 2.1 1 [OP_DIV] [OP_DIV]",
        "solution_code_ko": "var_a = 10.5\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2.1\nvar_e = 1\nvar_f = var_d / var_e\nvar_g = var_c / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 10.5\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2.1\nvar_e = 1\nvar_f = var_d / var_e\nvar_g = var_c / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "4685": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 2를 두번 빼면 5가 됩니다. 어떤 수는 얼마인지 구하시오.",
        "question_en": "Subtracting 2 twice from a certain number results in 5. What is the certain number?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "5 2 [OP_ADD] 2 [OP_ADD]",
        "solution_abst_en": "5 2 [OP_ADD] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "4686": {
        "category": "Comparison",
        "question_ko": "승민이는 밤을 4.56킬로그램(㎏) 주웠고 혜인이는 462그램(g)의 10 배 만큼 주웠습니다. 승민이와 혜인이 중에서 누가 밤을 더 많이 주웠습니까?",
        "question_en": "Seungmin picked up 4.56 kilograms (kg) of chestnuts and Hyein picked up 10 times as much as 462 grams (g). Who picked up more chestnuts, Seungmin or Hyein?",
        "answer_ko": "혜인",
        "answer_en": "Hyein",
        "solution_abst_ko": "[OP_LIST_SOL] 승민 혜인 [OP_LIST_EOL] [OP_LIST_SOL] 4.56 462 10 [OP_MUL] 1000 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Seungmin Hyein [OP_LIST_EOL] [OP_LIST_SOL] 4.56 462 10 [OP_MUL] 1000 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '승민'\nvar_b = '혜인'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4.56\nvar_d = 462\nvar_e = 10\nvar_f = var_d * var_e\nvar_g = 1000\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Seungmin'\nvar_b = 'Hyein'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4.56\nvar_d = 462\nvar_e = 10\nvar_f = var_d * var_e\nvar_g = 1000\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "4687": {
        "category": "Correspondence",
        "question_ko": "윤기는 네 자리 수에 57을 빼던 중, 윤기는 네 자리 수의 일의 자리 숫자 9를 6으로 잘못 봤습니다. 윤기가 구한 차가 1819라고 하면, 바르게 계산한 결과는 무엇인가요?",
        "question_en": "While Yoongi was subtracting 57 from the four digit number, Yoongi mistakenly saw the 9 in the ones digit of the four digit number as 6. If Yoongi got 1819 from this, what is the correct calculation result?",
        "answer_ko": "1822",
        "answer_en": "1822",
        "solution_abst_ko": "1819 57 [OP_ADD] 6 9 [OP_SUB] [OP_SUB] 57 [OP_SUB]",
        "solution_abst_en": "1819 57 [OP_ADD] 6 9 [OP_SUB] [OP_SUB] 57 [OP_SUB]",
        "solution_code_ko": "var_a = 1819\nvar_b = 57\nvar_c = var_a + var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nvar_h = 57\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1819\nvar_b = 57\nvar_c = var_a + var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nvar_h = 57\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "4688": {
        "category": "Geometry",
        "question_ko": "호석이는 철사를 몇 센티미터(㎝) 구입해서 한 변의 길이가 19센티미터(㎝)인 정삼각형의 둘레의 길이만큼을 잘라냈다. 잘라내고 남은 철사가 15센티미터(㎝)라면, 호석이가 구입한 철사의 길이는 몇 센티미터(㎝)인가?",
        "question_en": "Hosok bought a few centimeters (cm) of wire and cut a length equal to the circumference of an equilateral triangle with a side length of 19 centimeters (cm). If the wire left after cutting is 15 centimeters (cm), what is the length in centimeters (cm) of the wire that Hoseok bought?",
        "answer_ko": "72",
        "answer_en": "72",
        "solution_abst_ko": "19 3 [OP_MUL] 15 [OP_ADD]",
        "solution_abst_en": "19 3 [OP_MUL] 15 [OP_ADD]",
        "solution_code_ko": "var_a = 19\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 15\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 19\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 15\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "4689": {
        "category": "Comparison",
        "question_ko": "희진이와 희철이는 책을 모으고 있습니다. 희철이가 희진이보다 책을 2권 더 많이 가지고 있습니다. 동균이가 가진 책은 희진이가 가진 책의 수보다 적습니다. 세 명 중 가장 많은 책을 가진 사람은 누구입니까?",
        "question_en": "Heejin and Heechul are collecting books. Heechul has 2 more books than Heejin. Dongkyun has fewer books than Heejin. Which of the three has the most books?",
        "answer_ko": "희철",
        "answer_en": "Heechul",
        "solution_abst_ko": "[OP_LIST_SOL] 희진 희철 동균 [OP_LIST_EOL] [OP_LIST_SOL] 희철 희진 > 동균 희진 < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Heejin Heechul Dongkyun [OP_LIST_EOL] [OP_LIST_SOL] Heechul Heejin > Dongkyun Heejin < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '희진'\nvar_b = '희철'\nvar_c = '동균'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '희철'\nvar_e = '희진'\nvar_f = '>'\nvar_g = '동균'\nvar_h = '희진'\nvar_i = '<'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(var_k)",
        "solution_code_en": "var_a = 'Heejin'\nvar_b = 'Heechul'\nvar_c = 'Dongkyun'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'Heechul'\nvar_e = 'Heejin'\nvar_f = '>'\nvar_g = 'Dongkyun'\nvar_h = 'Heejin'\nvar_i = '<'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(var_k)"
    },
    "4690": {
        "category": "Arithmetic calculation",
        "question_ko": "4%의 설탕물 300그램(g)에서 몇 그램(g)의 물을 증발시키면 10%의 설탕물이 되는지 구하여라",
        "question_en": "Find how many grams (g) of water evaporated from 300 grams (g) of 4% sugar water to make 10% sugar water.",
        "answer_ko": "180",
        "answer_en": "180",
        "solution_abst_ko": "300 300 4 100 [OP_DIV] [OP_MUL] 100 10 [OP_DIV] [OP_MUL] [OP_SUB]",
        "solution_abst_en": "300 300 4 100 [OP_DIV] [OP_MUL] 100 10 [OP_DIV] [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 300\nvar_b = 300\nvar_c = 4\nvar_d = 100\nvar_e = var_c / var_d\nvar_f = var_b * var_e\nvar_g = 100\nvar_h = 10\nvar_i = var_g / var_h\nvar_j = var_f * var_i\nvar_k = var_a - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 300\nvar_b = 300\nvar_c = 4\nvar_d = 100\nvar_e = var_c / var_d\nvar_f = var_b * var_e\nvar_g = 100\nvar_h = 10\nvar_i = var_g / var_h\nvar_j = var_f * var_i\nvar_k = var_a - var_j\nprint(int(var_k))"
    },
    "4691": {
        "category": "Geometry",
        "question_ko": "정육면체의 각 모서리의 길이를 2배로 늘리면 정육면체의 겉넓이는 몇 배가 되는가?",
        "question_en": "If you double the length of each edge of a cube, how many times bigger does the cube's surface area become?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "2 2 [OP_POW]",
        "solution_abst_en": "2 2 [OP_POW]",
        "solution_code_ko": "var_a = 2\nvar_b = 2\nvar_c = var_a ** var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 2\nvar_c = var_a ** var_b\nprint(int(var_c))"
    },
    "4692": {
        "category": "Arithmetic calculation",
        "question_ko": "9의 배수이면서 6의 배수이면서 2의 배수인 수 중 가장 작은 다섯 자리 수는 무엇입니까?",
        "question_en": "What is the smallest five-digit number that is a multiple of 9 and a multiple of 6 and a multiple of 2?",
        "answer_ko": "10008",
        "answer_en": "10008",
        "solution_abst_ko": "10000 99999 1 [OP_LIST_ARANGE] 9 [OP_LIST_DIVISIBLE] 6 [OP_LIST_DIVISIBLE] 2 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "10000 99999 1 [OP_LIST_ARANGE] 9 [OP_LIST_DIVISIBLE] 6 [OP_LIST_DIVISIBLE] 2 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 10000\nvar_b = 99999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 9\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 6\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 2\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_h = list_e[var_g-1]\nprint(int(var_h))",
        "solution_code_en": "var_a = 10000\nvar_b = 99999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 9\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 6\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 2\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_h = list_e[var_g-1]\nprint(int(var_h))"
    },
    "4693": {
        "category": "Arithmetic calculation",
        "question_ko": "진하기가 25 %인 소금물 200 그램(g)이 있고, 다른 소금물 300 그램(g)에는 소금이 60 그램(g) 녹아 있습니다. 이 두 소금물을 섞었을 때 소금물의 진하기는 몇 %입니까?",
        "question_en": "You have 200 grams (g) of salt water with a concentration of 25%, and 60 grams (g) of salt are dissolved in another 300 grams (g) of salt water. What is the percent concentration of the salt water when these two salt water are mixed?",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "200 25 100 [OP_DIV] [OP_MUL] 60 [OP_ADD] 200 300 [OP_ADD] [OP_DIV] 100 [OP_MUL]",
        "solution_abst_en": "200 25 100 [OP_DIV] [OP_MUL] 60 [OP_ADD] 200 300 [OP_ADD] [OP_DIV] 100 [OP_MUL]",
        "solution_code_ko": "var_a = 200\nvar_b = 25\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 60\nvar_g = var_e + var_f\nvar_h = 200\nvar_i = 300\nvar_j = var_h + var_i\nvar_k = var_g / var_j\nvar_l = 100\nvar_m = var_k * var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 200\nvar_b = 25\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 60\nvar_g = var_e + var_f\nvar_h = 200\nvar_i = 300\nvar_j = var_h + var_i\nvar_k = var_g / var_j\nvar_l = 100\nvar_m = var_k * var_l\nprint(int(var_m))"
    },
    "4694": {
        "category": "Arithmetic calculation",
        "question_ko": "지하철이 1분에 1.6킬로미터(㎞)씩 이동하고 있습니다. 전 역과 이번 역의 사이 거리가 4.85킬로미터(㎞)일 때 전 역에서 출발해 이번 역을 완전히 지나치는 데 3분 15초가 걸렸다면, 지하철의 길이는 몇 미터(m)일까요?",
        "question_en": "The subway is moving 1.6 kilometers (km) per minute. If the distance between the previous station and this station is 4.85 kilometers (km), and it took 3 minutes and 15 seconds to pass this station completely from the previous station, how long is the subway in meters (m)?",
        "answer_ko": "350",
        "answer_en": "350",
        "solution_abst_ko": "1.6 3 15 60 [OP_DIV] [OP_ADD] [OP_MUL] 4.85 [OP_SUB] 1000 [OP_MUL]",
        "solution_abst_en": "1.6 3 15 60 [OP_DIV] [OP_ADD] [OP_MUL] 4.85 [OP_SUB] 1000 [OP_MUL]",
        "solution_code_ko": "var_a = 1.6\nvar_b = 3\nvar_c = 15\nvar_d = 60\nvar_e = var_c / var_d\nvar_f = var_b + var_e\nvar_g = var_a * var_f\nvar_h = 4.85\nvar_i = var_g - var_h\nvar_j = 1000\nvar_k = var_i * var_j\nprint(int(eval('{:.2f}'.format(round(var_k+1e-10,2)))))",
        "solution_code_en": "var_a = 1.6\nvar_b = 3\nvar_c = 15\nvar_d = 60\nvar_e = var_c / var_d\nvar_f = var_b + var_e\nvar_g = var_a * var_f\nvar_h = 4.85\nvar_i = var_g - var_h\nvar_j = 1000\nvar_k = var_i * var_j\nprint(int(eval('{:.2f}'.format(round(var_k+1e-10,2)))))"
    },
    "4695": {
        "category": "Arithmetic calculation",
        "question_ko": "민석이가 동화책을 읽기 시작하여 어제는 전체의 1/3을, 오늘은 전체의 2/5를 읽었습니다. 안 읽은 부분은 전체의 얼마인지 구하시오.",
        "question_en": "Minseok started reading a storybook and read 1/3 of it yesterday and 2/5 of it today. What is the total number of unread parts?",
        "answer_ko": "0.27",
        "answer_en": "0.27",
        "solution_abst_ko": "1 1/3 [OP_SUB] 2/5 [OP_SUB]",
        "solution_abst_en": "1 1/3 [OP_SUB] 2/5 [OP_SUB]",
        "solution_code_ko": "var_a = 1\nvar_b = 0.3333333333333333\nvar_c = var_a - var_b\nvar_d = 0.4\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 0.3333333333333333\nvar_c = var_a - var_b\nvar_d = 0.4\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "4696": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 27을 뺐더니 46이 되었습니다. 어떤 수에 46을 곱하면 얼마인지 구하시오.",
        "question_en": "Subtracting 27 from a number gives 46. What is the number multiplied by 46?",
        "answer_ko": "3358",
        "answer_en": "3358",
        "solution_abst_ko": "27 46 [OP_ADD] 46 [OP_MUL]",
        "solution_abst_en": "27 46 [OP_ADD] 46 [OP_MUL]",
        "solution_code_ko": "var_a = 27\nvar_b = 46\nvar_c = var_a + var_b\nvar_d = 46\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 27\nvar_b = 46\nvar_c = var_a + var_b\nvar_d = 46\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "4697": {
        "category": "Correspondence",
        "question_ko": "19배를 한 결과가 3439가 되기 위해서는 어떤 수에서 174를 빼야합니다. 어떤 수는 무엇입니까?",
        "question_en": "Subtracting 174 from a number and multiplying it by 19 yields 3439. What is a number?",
        "answer_ko": "355",
        "answer_en": "355",
        "solution_abst_ko": "3439 19 [OP_DIV] 174 [OP_ADD]",
        "solution_abst_en": "3439 19 [OP_DIV] 174 [OP_ADD]",
        "solution_code_ko": "var_a = 3439\nvar_b = 19\nvar_c = var_a / var_b\nvar_d = 174\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 3439\nvar_b = 19\nvar_c = var_a / var_b\nvar_d = 174\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "4698": {
        "category": "Correspondence",
        "question_ko": "서로 다른 수 A, B, C, D가 있습니다. A+A=6, B-A=4, C+B=9, D-C=7입니다. D를 구하시오.",
        "question_en": "There are different numbers A, B, C, and D. Given that A+A=6, BA=4, C+B=9, and D-C=7. Find out what D is.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "A+A=6 A [OP_NUM_UNK_SOLVER] 4 [OP_ADD] 9 [OP_SUB] 7 [OP_SUB] -1 [OP_MUL]",
        "solution_abst_en": "A+A=6 A [OP_NUM_UNK_SOLVER] 4 [OP_ADD] 9 [OP_SUB] 7 [OP_SUB] -1 [OP_MUL]",
        "solution_code_ko": "var_a = 'A+A=6'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 9\nvar_g = var_e - var_f\nvar_h = 7\nvar_i = var_g - var_h\nvar_j = -1\nvar_k = var_i * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 'A+A=6'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 9\nvar_g = var_e - var_f\nvar_h = 7\nvar_i = var_g - var_h\nvar_j = -1\nvar_k = var_i * var_j\nprint(int(var_k))"
    },
    "4699": {
        "category": "Correspondence",
        "question_ko": "복숭아 40개와 체리 34개를 각각 다른 봉투에 담아서 가져간다. 복숭아는 8개, 체리는 5개씩 봉투에 담는데 남는 것들은 봉투에 담지 않는다. 복숭아와 체리를 담은 봉투에 손잡이는 모두 몇 개인지 구하시오.",
        "question_en": "You can take 40 peaches and 34 cherries in separate bags. I am going to put 8 peaches and 5 cherries in bags, but I will not put the leftovers in bags. Find how many handles there are in the bags full of peaches and cherries.",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "40 8 [OP_FDIV] 34 12 [OP_FDIV] [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "40 8 [OP_FDIV] 34 12 [OP_FDIV] [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 40\nvar_b = 8\nvar_c = var_a // var_b\nvar_d = 34\nvar_e = 12\nvar_f = var_d // var_e\nvar_g = var_c + var_f\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 40\nvar_b = 8\nvar_c = var_a // var_b\nvar_d = 34\nvar_e = 12\nvar_f = var_d // var_e\nvar_g = var_c + var_f\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "4700": {
        "category": "Possibility",
        "question_ko": "초등학생 2명을 포함한 학생 5명을 한 줄로 세운다고 할 때, 초등학생이 양 끝에 서게 되는 경우의 수는?",
        "question_en": "If 5 students, 2 of whom are elementary school students, are lined up, how many ways can the elementary school students stand at either end?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "5 2 [OP_SUB] 5 2 [OP_SUB] [OP_PERM] 2 [OP_MUL]",
        "solution_abst_en": "5 2 [OP_SUB] 5 2 [OP_SUB] [OP_PERM] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = 1\nvar_c = int(var_c)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_c-i)\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = 1\nvar_c = int(var_c)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_c-i)\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "4701": {
        "category": "Geometry",
        "question_ko": "오각기둥의 꼭짓점 개수를 구하세요.",
        "question_en": "Find the number of vertices of a pentagonal prism.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "5 2 [OP_MUL]",
        "solution_abst_en": "5 2 [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "4702": {
        "category": "Possibility",
        "question_ko": "다음 숫자 카드 5, 3, 6, 8 중 3 장을 골라 세 자리 수를 만듭니다. 작은 수부터 차례로 쓸 때, 10번째 수를 구하시오.",
        "question_en": "Choose 3 of the following number cards 5, 3, 6, 8 to form a three-digit number. When writing the numbers in order from smallest, find the 10th number.",
        "answer_ko": "568",
        "answer_en": "568",
        "solution_abst_ko": "[OP_LIST_SOL] 5 3 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 5 3 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 5\nvar_b = 3\nvar_c = 6\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 3\nvar_c = 6\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nprint(int(var_g))"
    },
    "4703": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 3을 곱해야 하는데 실수로 6을 곱했더니 42가 됐습니다. 바르게 계산한 결과는 무엇입니까?",
        "question_en": "A number needs to be multiplied by 3, but you accidentally multiplied it by 6 and it ended up being 42. What is the correct calculation result?",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "42 6 [OP_DIV] 3 [OP_MUL]",
        "solution_abst_en": "42 6 [OP_DIV] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 42\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 42\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "4704": {
        "category": "Correspondence",
        "question_ko": "3×4<3×A<40, 4/3>4/A>4/6인 A는 몇 개입니까?",
        "question_en": "How many A's are there when 3×4<3×A<40, and 4/3>4/A>4/6?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "3×4<3×A<40 A [OP_NUM_UNK_SOLVER] 4/3>4/A>4/6 A [OP_NUM_UNK_SOLVER] [OP_SET_INTERSECT] [OP_LIST_LEN]",
        "solution_abst_en": "3×4<3×A<40 A [OP_NUM_UNK_SOLVER] 4/3>4/A>4/6 A [OP_NUM_UNK_SOLVER] [OP_SET_INTERSECT] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '3×4<3×A<40'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = '4/3>4/A>4/6'\nvar_d = 'A'\nans_dict = dict()\nvar_c = var_c.replace('×','*')\nvar_c = var_c.replace('x','*')\nvar_c = var_c.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_c):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_c\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k].append(int(c[i]))\nlist_b = list(set(ans_dict[var_d]))\nlist_c = list(set(list_a) & set(list_b))\nvar_e = len(list_c)\nprint(int(var_e))",
        "solution_code_en": "var_a = '3×4<3×A<40'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = '4/3>4/A>4/6'\nvar_d = 'A'\nans_dict = dict()\nvar_c = var_c.replace('×','*')\nvar_c = var_c.replace('x','*')\nvar_c = var_c.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_c):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_c\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k].append(int(c[i]))\nlist_b = list(set(ans_dict[var_d]))\nlist_c = list(set(list_a) & set(list_b))\nvar_e = len(list_c)\nprint(int(var_e))"
    },
    "4705": {
        "category": "Correspondence",
        "question_ko": "승우네 농장에 돼지와 닭이 있습니다. 닭은 돼지보다 12마리가 많습니다. 또한 닭의 수와 돼지의 수의 합은 12보다 40만큼 많습니다. 닭의 수와 돼지의 수의 곱을 구하시오.",
        "question_en": "There are pigs and chickens on Seungwoo's farm. Chickens outnumber pigs by 12. Also, the sum of the number of chickens and the number of pigs is 40 more than 12. Find the product of the number of chickens and the number of pigs.",
        "answer_ko": "640",
        "answer_en": "640",
        "solution_abst_ko": "40 2 [OP_DIV] 12 [OP_ADD] 40 2 [OP_DIV] [OP_MUL]",
        "solution_abst_en": "40 2 [OP_DIV] 12 [OP_ADD] 40 2 [OP_DIV] [OP_MUL]",
        "solution_code_ko": "var_a = 40\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 12\nvar_e = var_c + var_d\nvar_f = 40\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = var_e * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 40\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 12\nvar_e = var_c + var_d\nvar_f = 40\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = var_e * var_h\nprint(int(var_i))"
    },
    "4706": {
        "category": "Correspondence",
        "question_ko": "혜진이의 월말평가 성적이 도덕 82점, 국어 90점, 과학 88점, 사회 84점이며 수학의 성적은 모릅니다. 평균점수는 88점일때 수학 성적은 몇 점입니까?",
        "question_en": "Hyejin's monthly evaluation score is 82 for ethics, 90 for Korean language, 88 for science, and 84 for social studies. The score for mathematics is unknown. When the average score is 88, what is the score for mathematics?",
        "answer_ko": "96",
        "answer_en": "96",
        "solution_abst_ko": "88 5 [OP_MUL] 82 [OP_SUB] 90 [OP_SUB] 88 [OP_SUB] 84 [OP_SUB]",
        "solution_abst_en": "88 5 [OP_MUL] 82 [OP_SUB] 90 [OP_SUB] 88 [OP_SUB] 84 [OP_SUB]",
        "solution_code_ko": "var_a = 88\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 82\nvar_e = var_c - var_d\nvar_f = 90\nvar_g = var_e - var_f\nvar_h = 88\nvar_i = var_g - var_h\nvar_j = 84\nvar_k = var_i - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 88\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 82\nvar_e = var_c - var_d\nvar_f = 90\nvar_g = var_e - var_f\nvar_h = 88\nvar_i = var_g - var_h\nvar_j = 84\nvar_k = var_i - var_j\nprint(int(var_k))"
    },
    "4707": {
        "category": "Comparison",
        "question_ko": "지수와 윤기는 자전거를 탔습니다. 두 사람은 같은 곳에서 출발하여 윤기는 1시간 동안 22킬로미터(㎞)를 달렸고 지수는 1시간 동안 19000미터(m)를 달렸습니다. 누가 더 많이 달렸습니까?",
        "question_en": "Jisoo and Yoongi rode bicycles. The two started from the same place, Yoongi ran 22 kilometers (km) in one hour, and Jisoo ran 19,000 meters (m) in one hour. Who rode more?",
        "answer_ko": "지수",
        "answer_en": "Jisoo",
        "solution_abst_ko": "[OP_LIST_SOL] 지수 윤기 [OP_LIST_EOL] [OP_LIST_SOL] 22 1000 [OP_MUL] 19000 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jisoo Yoongi [OP_LIST_EOL] [OP_LIST_SOL] 22 1000 [OP_MUL] 19000 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '지수'\nvar_b = '윤기'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 22\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 19000\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Jisoo'\nvar_b = 'Yoongi'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 22\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 19000\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "4708": {
        "category": "Geometry",
        "question_ko": "어떤 다각형은 한 꼭짓점에서 6개의 대각선을 그을 수 있다고 합니다. 이 다각형의 꼭짓점의 개수는?",
        "question_en": "Some polygons are said to have six diagonals drawn from one vertex. How many vertices does this polygon have?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "6 3 [OP_ADD]",
        "solution_abst_en": "6 3 [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 3\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 3\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "4709": {
        "category": "Geometry",
        "question_ko": "가로의 길이가 3센티미터(㎝)이고 넓이가 1.77제곱센티미터(㎠)인 지폐가 있습니다. 이 지폐의 세로의 길이는 몇 센티미터(㎝) 입니까?",
        "question_en": "There is a bill with a width of 3 centimeters (cm) and an area of 1.77 square centimeters (cm2). How many centimeters (cm) is the length of this bill?",
        "answer_ko": "0.59",
        "answer_en": "0.59",
        "solution_abst_ko": "1.77 3 [OP_DIV]",
        "solution_abst_en": "1.77 3 [OP_DIV]",
        "solution_code_ko": "var_a = 1.77\nvar_b = 3\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 1.77\nvar_b = 3\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "4710": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 9까지의 숫자카드 중 3장을 뽑아 735라는 숫자를 만들었다. 뽑은 숫자카드들 중 4보다 큰 값은 몇 개인지 구하시오.",
        "question_en": "Three of the number cards from 1 to 9 were drawn to make the number 735. How many number cards drawn have a value greater than 4? ",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "735 [OP_NUM2LIST] 4 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "735 [OP_NUM2LIST] 4 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 735\nlist_a = []\nvar_a = int(var_a)\nwhile var_a//10 > 0:\n    list_a.append(var_a%10)\n    var_a = var_a//10\nlist_a.append(var_a%10)\nlist_a = list_a[::-1]\nvar_b = 4\nlist_b = []\nfor i in list_a:\n    if i > var_b:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))",
        "solution_code_en": "var_a = 735\nlist_a = []\nvar_a = int(var_a)\nwhile var_a//10 > 0:\n    list_a.append(var_a%10)\n    var_a = var_a//10\nlist_a.append(var_a%10)\nlist_a = list_a[::-1]\nvar_b = 4\nlist_b = []\nfor i in list_a:\n    if i > var_b:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))"
    },
    "4711": {
        "category": "Geometry",
        "question_ko": "어떤 색종이는 한 변이 30센티미터(㎝)인 정사각형 모양입니다. 이 색종이의 넓이는?",
        "question_en": "One piece of colored paper is a square with sides measuring 30 centimeters (cm). What is the area of this piece of colored paper?",
        "answer_ko": "900",
        "answer_en": "900",
        "solution_abst_ko": "30 2 [OP_POW]",
        "solution_abst_en": "30 2 [OP_POW]",
        "solution_code_ko": "var_a = 30\nvar_b = 2\nvar_c = var_a ** var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 30\nvar_b = 2\nvar_c = var_a ** var_b\nprint(int(var_c))"
    },
    "4712": {
        "category": "Correspondence",
        "question_ko": "등식 A85-2B=364이 성립한다고 합니다. A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "The equation A85-2B=364 makes. What number should go in A?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "A85-2B=364 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A85-2B=364 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A85-2B=364'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A85-2B=364'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "4713": {
        "category": "Geometry",
        "question_ko": "어느 원의 지름이 26센티미터(㎝)입니다. 이 때, 반지름의 길이는 몇 센티미터(㎝)인가요?",
        "question_en": "The diameter of a circle is 26 centimeters (cm). Then how long is the radius in centimeters (cm)?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "26 2 [OP_DIV]",
        "solution_abst_en": "26 2 [OP_DIV]",
        "solution_code_ko": "var_a = 26\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 26\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "4714": {
        "category": "Comparison",
        "question_ko": "4명의 학생이 숫자를 말했습니다. 합은 총 531이고, 첫 번째 학생과 두 번째 학생이 말한 숫자의 합은 세 번째 학생과 네 번째 학생이 말한 숫자의 합보다 31더 크고, 세 번째 학생은 네 번째 학생보다 22 더 큰 수를 말했습니다. 세 번째 학생이 말한 수는 얼마입니까?",
        "question_en": "4 students said one number each. The sum is 531, and the sum of the numbers uttered by the first student and the second student is 31 greater than the sum of the numbers spoken by the third and fourth students, and the third student said a number 22 greater than that of the fourth student. What number did the third student say?",
        "answer_ko": "136",
        "answer_en": "136",
        "solution_abst_ko": "531 31 [OP_SUB] 2 [OP_DIV] 22 [OP_SUB] 2 [OP_DIV] 22 [OP_ADD]",
        "solution_abst_en": "531 31 [OP_SUB] 2 [OP_DIV] 22 [OP_SUB] 2 [OP_DIV] 22 [OP_ADD]",
        "solution_code_ko": "var_a = 531\nvar_b = 31\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 22\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nvar_j = 22\nvar_k = var_i + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 531\nvar_b = 31\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 22\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nvar_j = 22\nvar_k = var_i + var_j\nprint(int(var_k))"
    },
    "4715": {
        "category": "Arithmetic calculation",
        "question_ko": "아버지의 나이를 아들의 나이로 나누면 3이였던 때가 7년전입니다. 8년 후에는 둘의 나이가 합쳐서 74살이라면, 8년 후 아버지의 춘추를 구하십시오.",
        "question_en": "If we divide the father's age by the son's age, the result was 3, 7 years ago. Their ages will combine to 74 after 8 years. What will be the age of the father in 8 years' time?",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "74 8 2 [OP_MUL] [OP_SUB] 7 2 [OP_MUL] [OP_SUB] 3 1 [OP_ADD] [OP_FDIV] 3 [OP_MUL] 7 [OP_ADD] 8 [OP_ADD]",
        "solution_abst_en": "74 8 2 [OP_MUL] [OP_SUB] 7 2 [OP_MUL] [OP_SUB] 3 1 [OP_ADD] [OP_FDIV] 3 [OP_MUL] 7 [OP_ADD] 8 [OP_ADD]",
        "solution_code_ko": "var_a = 74\nvar_b = 8\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 7\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nvar_j = 3\nvar_k = 1\nvar_l = var_j + var_k\nvar_m = var_i // var_l\nvar_n = 3\nvar_o = var_m * var_n\nvar_p = 7\nvar_q = var_o + var_p\nvar_r = 8\nvar_s = var_q + var_r\nprint(int(var_s))",
        "solution_code_en": "var_a = 74\nvar_b = 8\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 7\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nvar_j = 3\nvar_k = 1\nvar_l = var_j + var_k\nvar_m = var_i // var_l\nvar_n = 3\nvar_o = var_m * var_n\nvar_p = 7\nvar_q = var_o + var_p\nvar_r = 8\nvar_s = var_q + var_r\nprint(int(var_s))"
    },
    "4716": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 32를 빼야 하는데 잘못하여 23을 뺐더니 14가 되었습니다. 어떤 수를 구하시오.",
        "question_en": "I need to subtract 32 from a certain number, but I mistakenly subtracted 23, so I got 14. Find the number.",
        "answer_ko": "37",
        "answer_en": "37",
        "solution_abst_ko": "14 23 [OP_ADD]",
        "solution_abst_en": "14 23 [OP_ADD]",
        "solution_code_ko": "var_a = 14\nvar_b = 23\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 14\nvar_b = 23\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "4717": {
        "category": "Correspondence",
        "question_ko": "A3B-41=591라는 식이 성립하려면, B에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "What number must be in B to make A3B-41=591?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "A3B-41=591 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A3B-41=591 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A3B-41=591'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A3B-41=591'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "4718": {
        "category": "Geometry",
        "question_ko": "한 직선 위에 있지 않는 세 점이 있습니다. 이 세 점으로 가능한 직선의 개수는?",
        "question_en": "There are three points that are not on a straight line. How many straight lines are possible with these three points?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "3 2 [OP_COMB]",
        "solution_abst_en": "3 2 [OP_COMB]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))"
    },
    "4719": {
        "category": "Possibility",
        "question_ko": "숫자 카드 7, 3을 한 번씩 모두 사용하여 만들 수 있는 가장 큰 수는 얼마입니까?",
        "question_en": "What is the largest number that can be made by using the number cards 7 and 3 all once?",
        "answer_ko": "73",
        "answer_en": "73",
        "solution_abst_ko": "[OP_LIST_SOL] 7 3 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 7 3 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 7\nvar_b = 3\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_e = list_c[-var_d]\nprint(int(var_e))",
        "solution_code_en": "var_a = 7\nvar_b = 3\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_e = list_c[-var_d]\nprint(int(var_e))"
    },
    "4720": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 5를 곱하고 7을 곱했더니 5와 4/9가 되었습니다. 어떤 수가 얼마인지 소수 2번째 자리까지 나타내어 보세요.",
        "question_en": "If you multiply a variable by 5 and then by 7, you get 5 and 4/9. Find the variable to two decimal places.",
        "answer_ko": "0.16",
        "answer_en": "0.16",
        "solution_abst_ko": "5 4/9 [OP_ADD] 7 [OP_DIV] 5 [OP_DIV]",
        "solution_abst_en": "5 4/9 [OP_ADD] 7 [OP_DIV] 5 [OP_DIV]",
        "solution_code_ko": "var_a = 5\nvar_b = 0.4444444444444444\nvar_c = var_a + var_b\nvar_d = 7\nvar_e = var_c / var_d\nvar_f = 5\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 5\nvar_b = 0.4444444444444444\nvar_c = var_a + var_b\nvar_d = 7\nvar_e = var_c / var_d\nvar_f = 5\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "4721": {
        "category": "Arithmetic calculation",
        "question_ko": "3의 배수이면서 5의 배수인 수 중 가장 큰 두 자리 수는?",
        "question_en": "What is the largest two-digit number that is both a multiple of 3 and a multiple of 5?",
        "answer_ko": "90",
        "answer_en": "90",
        "solution_abst_ko": "10 99 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_abst_en": "10 99 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[-var_f]\nprint(int(var_g))",
        "solution_code_en": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[-var_f]\nprint(int(var_g))"
    },
    "4722": {
        "category": "Possibility",
        "question_ko": "한자리 자연수 A, B, C중 A + B + C < 7을 만족하는 A,B,C의 개수를 구하시오.",
        "question_en": "Among the single-digit natural numbers A, B, and C, count the number of A, B, and C that satisfies  A + B + C < 7.",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "1 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_NUM2SUM] 7 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "1 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_NUM2SUM] 7 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 7\nlist_d = []\nfor i in list_c:\n    if i < var_f:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 7\nlist_d = []\nfor i in list_c:\n    if i < var_f:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))"
    },
    "4723": {
        "category": "Geometry",
        "question_ko": "가로가 5미터(m)이고, 세로가 17/20미터(m)인 직사각형 모양의 꽃밭이 있습니다. 이 꽃밭의 넓이는 몇 제곱센티미터(㎠)지 구하시오.",
        "question_en": "There is a flower garden in the shape of a rectangle measuring 5 meters (m) long and 17/20 meters (m) wide. Find the area in square centimeters (cm2) of this flower field.",
        "answer_ko": "42500",
        "answer_en": "42500",
        "solution_abst_ko": "5 17/20 [OP_MUL] 100 100 [OP_MUL] [OP_MUL]",
        "solution_abst_en": "5 17/20 [OP_MUL] 100 100 [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 0.85\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = 100\nvar_f = var_d * var_e\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 0.85\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = 100\nvar_f = var_d * var_e\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "4724": {
        "category": "Arithmetic calculation",
        "question_ko": "6개의 수 3/2, 2.3, 1/5, 1.1, 5/2, 4/5가 있습니다. 이 중에서 1보다 크고 2보다 작은 수는 모두 몇 개입니까?",
        "question_en": "There are six numbers 3/2, 2.3, 1/5, 1.1, 5/2, 4/5. How many of these numbers are greater than 1 and less than 2?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 3/2 2.3 1/5 1.1 5/2 4/5 [OP_LIST_EOL] 1 [OP_LIST_MORE] 2 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 3/2 2.3 1/5 1.1 5/2 4/5 [OP_LIST_EOL] 1 [OP_LIST_MORE] 2 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1.5\nvar_b = 2.3\nvar_c = 0.2\nvar_d = 1.1\nvar_e = 2.5\nvar_f = 0.8\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 1\nlist_b = []\nfor i in list_a:\n    if i > var_g:\n        list_b.append(i)\nvar_h = 2\nlist_c = []\nfor i in list_b:\n    if i < var_h:\n        list_c.append(i)\nvar_i = len(list_c)\nprint(int(var_i))",
        "solution_code_en": "var_a = 1.5\nvar_b = 2.3\nvar_c = 0.2\nvar_d = 1.1\nvar_e = 2.5\nvar_f = 0.8\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 1\nlist_b = []\nfor i in list_a:\n    if i > var_g:\n        list_b.append(i)\nvar_h = 2\nlist_c = []\nfor i in list_b:\n    if i < var_h:\n        list_c.append(i)\nvar_i = len(list_c)\nprint(int(var_i))"
    },
    "4725": {
        "category": "Correspondence",
        "question_ko": "소수 2번째 자리에서 반올림하면 1.7이 되는 소수 두 자리 수 중 가장 큰 수에서 가장 작은 수를 뺀 값을 소수점을 포함하여 구하시오.",
        "question_en": "Find the value, including the decimal point, of subtracting the possible smallest from the largest of the two decimal numbers that becomes 1.7 when rounded to two decimal places.",
        "answer_ko": "0.09",
        "answer_en": "0.09",
        "solution_abst_ko": "1.74 1.65 [OP_SUB]",
        "solution_abst_en": "1.74 1.65 [OP_SUB]",
        "solution_code_ko": "var_a = 1.74\nvar_b = 1.65\nvar_c = var_a - var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 1.74\nvar_b = 1.65\nvar_c = var_a - var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "4726": {
        "category": "Arithmetic calculation",
        "question_ko": "100개씩 묶음 8개와 10개씩 묶음 7개를 합한 수에서 10씩 커지게 5번 뛰어서 세면 얼마입니까?",
        "question_en": "What is the sum of 8 groups of 100 and 7 groups of 10 and count it 5 jumps in increments of 10?",
        "answer_ko": "920",
        "answer_en": "920",
        "solution_abst_ko": "100 8 [OP_MUL] 10 7 [OP_MUL] [OP_ADD] 10 5 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "100 8 [OP_MUL] 10 7 [OP_MUL] [OP_ADD] 10 5 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 100\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 10\nvar_e = 7\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 10\nvar_i = 5\nvar_j = var_h * var_i\nvar_k = var_g + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 100\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 10\nvar_e = 7\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 10\nvar_i = 5\nvar_j = var_h * var_i\nvar_k = var_g + var_j\nprint(int(var_k))"
    },
    "4727": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 100까지의 자연수 중 5로 나누었을 때 나머지가 2인 수는 몇 개입니까?",
        "question_en": "How many natural numbers from 1 to 100 have a remainder of 2 when divided by 5?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "1 100 1 [OP_LIST_ARANGE] 5 2 [OP_LIST_DIVIDE_AND_REMAIN] [OP_LIST_LEN]",
        "solution_abst_en": "1 100 1 [OP_LIST_ARANGE] 5 2 [OP_LIST_DIVIDE_AND_REMAIN] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nvar_e = 2\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nvar_e = 2\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "4728": {
        "category": "Arithmetic calculation",
        "question_ko": "(가) 기계는 제품을 1분에 8개씩 만들고, (나) 기계는 1분에 10개씩 만든다. 동시에 제품을 만들기 시작했을 때 (나) 기계가 100개의 제품을 만들었다. (나) 기계는 (가) 기계보다 제품을 몇 개 더 많이 만들었는가?",
        "question_en": "Machine A makes 8 products per minute, and machine B makes 10 products per minute. When started making products at the same time, machine B made 100 products. How many more products did machine B make than machine A?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "100 100 10 [OP_DIV] 8 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "100 100 10 [OP_DIV] 8 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 100\nvar_b = 100\nvar_c = 10\nvar_d = var_b / var_c\nvar_e = 8\nvar_f = var_d * var_e\nvar_g = var_a - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 100\nvar_b = 100\nvar_c = 10\nvar_d = var_b / var_c\nvar_e = 8\nvar_f = var_d * var_e\nvar_g = var_a - var_f\nprint(int(var_g))"
    },
    "4729": {
        "category": "Comparison",
        "question_ko": "정국이는 6에서 3을 나눈 몫 만큼 모았고, 윤기는 4, 유나는 5만큼 모았습니다. 누가 가장 큰 수를 모았습니까?",
        "question_en": "Jungkook collected 6 divided by 3, Yoongi collected 4, and Yuna collected 5. Who got the biggest number?",
        "answer_ko": "유나",
        "answer_en": "Yuna",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 윤기 유나 [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_FDIV] 4 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Yoongi Yuna [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_FDIV] 4 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '윤기'\nvar_c = '유나'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 6\nvar_e = 3\nvar_f = var_d // var_e\nvar_g = 4\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Yoongi'\nvar_c = 'Yuna'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 6\nvar_e = 3\nvar_f = var_d // var_e\nvar_g = 4\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "4730": {
        "category": "Comparison",
        "question_ko": "52와 어떤 자연수 사이에는 연속된 자연수가 15개 있습니다. 어떤 수는 52보다 큰 수일 때, 52와 어떤 수 사이에 있는 수 중 한가운데 있는 수는 무엇입니까?",
        "question_en": "There are 15 consecutive natural numbers between 52 and a certain number. If the certain number is greater than 52, which number is in the middle between 52 and the certain number?",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "52 15 [OP_ADD] 1 [OP_ADD] 52 [OP_ADD] 2 [OP_DIV]",
        "solution_abst_en": "52 15 [OP_ADD] 1 [OP_ADD] 52 [OP_ADD] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 52\nvar_b = 15\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 52\nvar_g = var_e + var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 52\nvar_b = 15\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 52\nvar_g = var_e + var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "4731": {
        "category": "Comparison",
        "question_ko": "학원은 7층입니다. 독서실은 학원보다 4층 높고, 서점은 독서실보다 9층 낮습니다. 서점은 몇 층입니까?",
        "question_en": "The academy is on the 7th floor. The reading room is 4 floors higher than the academy, and the bookstore is 9 floors lower than the reading room. What floor is the bookstore on?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "7 4 [OP_ADD] 9 [OP_SUB]",
        "solution_abst_en": "7 4 [OP_ADD] 9 [OP_SUB]",
        "solution_code_ko": "var_a = 7\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 7\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "4732": {
        "category": "Arithmetic calculation",
        "question_ko": "동우네 모둠 6명이 이번 쪽지 시험에서 맞춘 문제의 수는 16, 22, 30, 26, 18, 20개입니다. 동우네 모둠이 맞춘 문제는 평균 몇 개입니까?",
        "question_en": "The number of questions answered by 6 people in Dongwoo's group is 16, 22, 30, 26, 18, and 20. On average, how many questions did Dongwoo's group get right?",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "[OP_LIST_SOL] 16 22 30 26 18 20 [OP_LIST_EOL] [OP_LIST_MEAN]",
        "solution_abst_en": "[OP_LIST_SOL] 16 22 30 26 18 20 [OP_LIST_EOL] [OP_LIST_MEAN]",
        "solution_code_ko": "var_a = 16\nvar_b = 22\nvar_c = 30\nvar_d = 26\nvar_e = 18\nvar_f = 20\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_g = sum(list_a)/len(list_a)\nprint(int(var_g))",
        "solution_code_en": "var_a = 16\nvar_b = 22\nvar_c = 30\nvar_d = 26\nvar_e = 18\nvar_f = 20\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_g = sum(list_a)/len(list_a)\nprint(int(var_g))"
    },
    "4733": {
        "category": "Correspondence",
        "question_ko": "네 자리 수 2A3A는 9의 배수이다. A는 무엇인가?",
        "question_en": "The four-digit number 2A3A is a multiple of 9. What is A?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "2A3A [OP_GEN_POSSIBLE_LIST] 9 [OP_LIST_DIVISIBLE] 2A3A A [OP_LIST_FIND_UNK]",
        "solution_abst_en": "2A3A [OP_GEN_POSSIBLE_LIST] 9 [OP_LIST_DIVISIBLE] 2A3A A [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = '2A3A'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 9\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = '2A3A'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nvar_e = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_e = int(elem[unk_idx])\nprint(int(var_e))",
        "solution_code_en": "var_a = '2A3A'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 9\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = '2A3A'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nvar_e = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_e = int(elem[unk_idx])\nprint(int(var_e))"
    },
    "4734": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 263을 빼고 419를 더하면 725이다. 어떤 수를 구하시오.",
        "question_en": "Subtract 263 from a certain number and add 419, resulting in 725. Find the number.",
        "answer_ko": "569",
        "answer_en": "569",
        "solution_abst_ko": "725 419 [OP_SUB] 263 [OP_ADD]",
        "solution_abst_en": "725 419 [OP_SUB] 263 [OP_ADD]",
        "solution_code_ko": "var_a = 725\nvar_b = 419\nvar_c = var_a - var_b\nvar_d = 263\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 725\nvar_b = 419\nvar_c = var_a - var_b\nvar_d = 263\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "4735": {
        "category": "Correspondence",
        "question_ko": "공장에서 연필을 포장하려고 하는데 5개씩 포장하면 4개가 남고, 7개씩 포장하면 6개가 남고, 8개씩 포장하면 7개가 남는다고 한다. 이 공장이 만든 연필의 개수가 1000이상 9999이하의 자연수 중 가장 작은 수라고 할때 연필의 개수는 몇 개인지 구하시오.",
        "question_en": "A factory is trying to pack pencils, but if you pack them in 5 units, 4 will remain, if you pack in 7 units, 6 units will remain, and if you pack in 8 units, 7 units will remain. If the number of pencils made by this factory is the smallest natural number between 1000 and 9999, how many pencils are there?",
        "answer_ko": "1119",
        "answer_en": "1119",
        "solution_abst_ko": "1000 9999 1 [OP_LIST_ARANGE] 8 7 [OP_LIST_DIVIDE_AND_REMAIN] 7 6 [OP_LIST_DIVIDE_AND_REMAIN] 5 -1 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MIN]",
        "solution_abst_en": "1000 9999 1 [OP_LIST_ARANGE] 8 7 [OP_LIST_DIVIDE_AND_REMAIN] 7 6 [OP_LIST_DIVIDE_AND_REMAIN] 5 -1 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 8\nvar_e = 7\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 7\nvar_g = 6\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 5\nvar_i = -1\nlist_d = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_c:\n    i = int(i)\n    if i%var_h == var_i:\n        list_d.append(i)\nvar_j = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_k = list_e[var_j-1]\nprint(int(var_k))",
        "solution_code_en": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 8\nvar_e = 7\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 7\nvar_g = 6\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 5\nvar_i = -1\nlist_d = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_c:\n    i = int(i)\n    if i%var_h == var_i:\n        list_d.append(i)\nvar_j = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_k = list_e[var_j-1]\nprint(int(var_k))"
    },
    "4736": {
        "category": "Geometry",
        "question_ko": "친구가 태원이에게 다음과 같은 문제를 냈습니다. \"정육각뿔의 모서리 중 하나는 8센티미터(㎝)고, 다른 하나는 13센티미터(㎝)야. 그럼 정육각뿔의 모든 모서리의 합은 얼마일까?\" 태원이는 문제를 맞히기 위해서 뭐라고 대답해야 합니까?",
        "question_en": "A friend gave the following problem to Taewon. \"One of the edges of the regular hexagonal pyramid is 8 centimeters (cm) and the other is 13 centimeters (cm). So what is the sum of all the edges of the regular hexagonal pyramid?\" What should Taewon answer to get the problem right?",
        "answer_ko": "126",
        "answer_en": "126",
        "solution_abst_ko": "13 6 [OP_MUL] 8 6 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "13 6 [OP_MUL] 8 6 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 13\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = 6\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 13\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = 6\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "4737": {
        "category": "Comparison",
        "question_ko": "네 명의 학생 지민, 윤기, 태형, 남준이가 줄을 서고 있습니다. 윤기는 남준이보다 앞에 있고, 지민이는 윤기보다 앞에 있습니다. 태형이는 남준이보다 뒤에 있다면, 가장 뒤에 있는 학생은 누구입니까?",
        "question_en": "Four students: Jimin, Yoongi, Taehyung, and Namjoon, are standing in a line. Yoongi stands ahead of Namjoon, and Jimin is ahead of Yoongi. If Taehyung is behind Namjoon, who stands at the very last?",
        "answer_ko": "태형",
        "answer_en": "Taehyung",
        "solution_abst_ko": "[OP_LIST_SOL] 지민 윤기 태형 남준 [OP_LIST_EOL] [OP_LIST_SOL] 지민 윤기 > 태형 남준 < 윤기 남준 > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jimin Yoongi Taehyung Namjoon [OP_LIST_EOL] [OP_LIST_SOL] Jimin Yoongi > Taehyung Namjoon < Yoongi Namjoon > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '지민'\nvar_b = '윤기'\nvar_c = '태형'\nvar_d = '남준'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '지민'\nvar_f = '윤기'\nvar_g = '>'\nvar_h = '태형'\nvar_i = '남준'\nvar_j = '<'\nvar_k = '윤기'\nvar_l = '남준'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)",
        "solution_code_en": "var_a = 'Jimin'\nvar_b = 'Yoongi'\nvar_c = 'Taehyung'\nvar_d = 'Namjoon'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'Jimin'\nvar_f = 'Yoongi'\nvar_g = '>'\nvar_h = 'Taehyung'\nvar_i = 'Namjoon'\nvar_j = '<'\nvar_k = 'Yoongi'\nvar_l = 'Namjoon'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)"
    },
    "4738": {
        "category": "Arithmetic calculation",
        "question_ko": "지민이는 할로윈을 맞아 유나에게 사탕 25개를 주고 남은 13개의 사탕을 모두 동생에게 주었습니다. 처음에 지민이가 가지고 있던 사탕은 몇 개입니까?",
        "question_en": "On Halloween, Jimin gave 25 candies to Yuna and gave all the remaining 13 candies to her sister. How many candies did Jimin have at first?",
        "answer_ko": "38",
        "answer_en": "38",
        "solution_abst_ko": "13 25 [OP_ADD]",
        "solution_abst_en": "13 25 [OP_ADD]",
        "solution_code_ko": "var_a = 13\nvar_b = 25\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 13\nvar_b = 25\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "4739": {
        "category": "Correspondence",
        "question_ko": "6AB3을 올림하여 백의 자리까지 나타내면 6200이 됩니다. A는 무엇입니까?",
        "question_en": "Rounding 6AB3 to the nearest hundred results in 6200. What does 'A' refer to?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "6AB3 [OP_GEN_POSSIBLE_LIST] 6200 100 [OP_SUB] [OP_LIST_MORE] 6200 [OP_LIST_LESS_EQUAL] 6AB3 A [OP_LIST_FIND_UNK]",
        "solution_abst_en": "6AB3 [OP_GEN_POSSIBLE_LIST] 6200 100 [OP_SUB] [OP_LIST_MORE] 6200 [OP_LIST_LESS_EQUAL] 6AB3 A [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = '6AB3'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 6200\nvar_c = 100\nvar_d = var_b - var_c\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nvar_e = 6200\nlist_c = []\nfor i in list_b:\n    if i <= var_e:\n        list_c.append(i)\nvar_f = '6AB3'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))",
        "solution_code_en": "var_a = '6AB3'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 6200\nvar_c = 100\nvar_d = var_b - var_c\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nvar_e = 6200\nlist_c = []\nfor i in list_b:\n    if i <= var_e:\n        list_c.append(i)\nvar_f = '6AB3'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))"
    },
    "4740": {
        "category": "Comparison",
        "question_ko": "동우, 민엽이, 성정이는 각각 같은 양의 쿠키가 들어있는 쿠키 상자를 선물로 받았습니다. 동우는 7번에 나눠 먹고 민엽이는 8번에 나눠 먹고 성정이는 5번에 나눠 먹었다면 한 번 먹을 때 가장 많은 개수의 쿠키를 먹은 사람은 누구입니까?",
        "question_en": "Dongwoo, Minyeop, and Seongjeong each received a cookie box containing equal amounts of cookies. If Dongwoo shared it with 7 meals, Minyeop with 8 meals, and Seongjeong with 5 meals, who ate the most cookies at one time?",
        "answer_ko": "성정",
        "answer_en": "Seongjeong",
        "solution_abst_ko": "[OP_LIST_SOL] 동우 민엽 성정 [OP_LIST_EOL] [OP_LIST_SOL] 1 7 [OP_DIV] 1 8 [OP_DIV] 1 5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Dongwoo Minyeop Seongjeong [OP_LIST_EOL] [OP_LIST_SOL] 1 7 [OP_DIV] 1 8 [OP_DIV] 1 5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '동우'\nvar_b = '민엽'\nvar_c = '성정'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nvar_e = 7\nvar_f = var_d / var_e\nvar_g = 1\nvar_h = 8\nvar_i = var_g / var_h\nvar_j = 1\nvar_k = 5\nvar_l = var_j / var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'Dongwoo'\nvar_b = 'Minyeop'\nvar_c = 'Seongjeong'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nvar_e = 7\nvar_f = var_d / var_e\nvar_g = 1\nvar_h = 8\nvar_i = var_g / var_h\nvar_j = 1\nvar_k = 5\nvar_l = var_j / var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "4741": {
        "category": "Comparison",
        "question_ko": "유나는 총 20일의 여름 방학을 보내고 있습니다. 오늘을 제외한 방학을 보낸 날의 수가 11일일 때, 오늘을 제외한 방학이 남은 날의 수는 며칠입니까?",
        "question_en": "Yuna is having a total of 20 days of summer vacation. If the number of vacation days excluding today is 11, how many vacation days are left excluding today?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "20 11 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "20 11 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "4742": {
        "category": "Geometry",
        "question_ko": "가로가 9센티미터(㎝), 세로가 4센티미터(㎝), 높이가 7센티미터(㎝)인 벽돌이 있을 때, 이 벽돌의 부피는 몇 세제곱센티미터(㎤)입니까?",
        "question_en": "If a brick is 9 centimeters (cm) wide, 4 centimeters (cm) long, and 7 centimeters (cm) high, how many cubic centimeters (cm3) of volume does it have?",
        "answer_ko": "252",
        "answer_en": "252",
        "solution_abst_ko": "9 4 [OP_MUL] 7 [OP_MUL]",
        "solution_abst_en": "9 4 [OP_MUL] 7 [OP_MUL]",
        "solution_code_ko": "var_a = 9\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "4743": {
        "category": "Correspondence",
        "question_ko": "네 자리 수 A614에서 6으로 나눈 몫이 네 자리 수 일 때, A에 들어갈 수 있는 숫자의 개수를 구하시오.",
        "question_en": "If the quotient of the four-digit number A614 divided by 6 is a four-digit number, find how many numbers fit in A.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "A614 [OP_GEN_POSSIBLE_LIST] 6000 [OP_LIST_MORE_EQUAL] 60000 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "A614 [OP_GEN_POSSIBLE_LIST] 6000 [OP_LIST_MORE_EQUAL] 60000 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 'A614'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 6000\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 60000\nlist_c = []\nfor i in list_b:\n    if i < var_c:\n        list_c.append(i)\nvar_d = len(list_c)\nprint(int(var_d))",
        "solution_code_en": "var_a = 'A614'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 6000\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 60000\nlist_c = []\nfor i in list_b:\n    if i < var_c:\n        list_c.append(i)\nvar_d = len(list_c)\nprint(int(var_d))"
    },
    "4744": {
        "category": "Comparison",
        "question_ko": "27과 45의 공배수를 작은 수부터 차례대로 썼을 때 왼쪽에서 7번째 수와 10번째 수 사이에 있는 수들을 모두 곱하면 얼마가 됩니까?",
        "question_en": "If the common multiples of 27 and 45 are written in order from smallest to largest, what is the product of all the numbers between the 7th and 10th numbers from the left?",
        "answer_ko": "1312200",
        "answer_en": "1312200",
        "solution_abst_ko": "27 45 [OP_LCM] 8 [OP_MUL] 27 45 [OP_LCM] 9 [OP_MUL] [OP_MUL]",
        "solution_abst_en": "27 45 [OP_LCM] 8 [OP_MUL] 27 45 [OP_LCM] 9 [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 27\nvar_b = 45\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nvar_d = 8\nvar_e = var_c * var_d\nvar_f = 27\nvar_g = 45\nvar_h = var_g * var_f / math.gcd(int(var_g), int(var_f))\nvar_i = 9\nvar_j = var_h * var_i\nvar_k = var_e * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 27\nvar_b = 45\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nvar_d = 8\nvar_e = var_c * var_d\nvar_f = 27\nvar_g = 45\nvar_h = var_g * var_f / math.gcd(int(var_g), int(var_f))\nvar_i = 9\nvar_j = var_h * var_i\nvar_k = var_e * var_j\nprint(int(var_k))"
    },
    "4745": {
        "category": "Comparison",
        "question_ko": "A 자동차는 시속 92킬로미터(㎞)로 달리고, B 자동차는 분속 1500미터(m)로 달립니다. 두 자동차 중 속력이 더 빠른 자동차는 어느 것입니까?",
        "question_en": "A car runs at 92 kilometers (km) per hour, and B car runs at 1500 meters (m) per minute. Which of the two is faster?",
        "answer_ko": "A",
        "answer_en": "A",
        "solution_abst_ko": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 92 1500 1000 [OP_DIV] 60 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 92 1500 1000 [OP_DIV] 60 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 92\nvar_d = 1500\nvar_e = 1000\nvar_f = var_d / var_e\nvar_g = 60\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 92\nvar_d = 1500\nvar_e = 1000\nvar_f = var_d / var_e\nvar_g = 60\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "4746": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 5로 나누었더니 몫이 248이고 나머지가 4가 되었습니다. 어떤 수를 9로 나누면 몫과 나머지의 합은 얼마입니까?",
        "question_en": "When a number is divided by 5, the quotient is 248 and the remainder is 4. When this number is divided by 9, what is the sum of the quotient and the remainder?",
        "answer_ko": "140",
        "answer_en": "140",
        "solution_abst_ko": "248 5 [OP_MUL] 4 [OP_ADD] 9 [OP_FDIV] 248 5 [OP_MUL] 4 [OP_ADD] 9 [OP_MOD] [OP_ADD]",
        "solution_abst_en": "248 5 [OP_MUL] 4 [OP_ADD] 9 [OP_FDIV] 248 5 [OP_MUL] 4 [OP_ADD] 9 [OP_MOD] [OP_ADD]",
        "solution_code_ko": "var_a = 248\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 9\nvar_g = var_e // var_f\nvar_h = 248\nvar_i = 5\nvar_j = var_h * var_i\nvar_k = 4\nvar_l = var_j + var_k\nvar_m = 9\nvar_n = var_l % var_m\nvar_o = var_g + var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 248\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 9\nvar_g = var_e // var_f\nvar_h = 248\nvar_i = 5\nvar_j = var_h * var_i\nvar_k = 4\nvar_l = var_j + var_k\nvar_m = 9\nvar_n = var_l % var_m\nvar_o = var_g + var_n\nprint(int(var_o))"
    },
    "4747": {
        "category": "Possibility",
        "question_ko": "현정, 슬기, 미란, 호철이가 한 줄로 서려고 합니다. 서로 다르게 한 줄로 서는 방법은 모두 몇 가지입니까?",
        "question_en": "Hyeonjeong, Seulgi, Miran, and Hocheol are trying to stand in one line. How many different ways are there to line up?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "[OP_LIST_SOL] 현정 슬기 미란 호철 [OP_LIST_EOL] [OP_LIST_LEN] 4 [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] Hyeonjeong Seulgi Miran Hocheol [OP_LIST_EOL] [OP_LIST_LEN] 4 [OP_PERM]",
        "solution_code_ko": "var_a = '현정'\nvar_b = '슬기'\nvar_c = '미란'\nvar_d = '호철'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 4\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nprint(int(var_g))",
        "solution_code_en": "var_a = 'Hyeonjeong'\nvar_b = 'Seulgi'\nvar_c = 'Miran'\nvar_d = 'Hocheol'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 4\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nprint(int(var_g))"
    },
    "4748": {
        "category": "Arithmetic calculation",
        "question_ko": "10부터 99까지 수를 쓸 때, 숫자 8은 모두 몇 번 쓰는지 구하시오.",
        "question_en": "When writing the numbers 10 through 99, find how many times the number 8 is written.",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "10 99 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 8 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "10 99 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 8 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 8\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))",
        "solution_code_en": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 8\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))"
    },
    "4749": {
        "category": "Comparison",
        "question_ko": "예나와 예솔이는 다이어트를 하고 있습니다. 한 달 동안 예나는 6킬로그램(㎏)의 0.41배만큼 살이 빠졌고, 예솔이는 2.3킬로그램(㎏)이 빠졌습니다. 살을 더 많이 뺀 사람은 누구입니까?",
        "question_en": "Yena and Yesol are following a dietary plan. Within a month, Yena lost 0.41 times 6 kilograms (kg) and Yesol lost 2.3 kilograms (kg). Which of them has lost more weight?",
        "answer_ko": "예나",
        "answer_en": "Yena",
        "solution_abst_ko": "[OP_LIST_SOL] 예나 예솔 [OP_LIST_EOL] [OP_LIST_SOL] 6 0.41 [OP_MUL] 2.3 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yena Yesol [OP_LIST_EOL] [OP_LIST_SOL] 6 0.41 [OP_MUL] 2.3 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '예나'\nvar_b = '예솔'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 0.41\nvar_e = var_c * var_d\nvar_f = 2.3\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Yena'\nvar_b = 'Yesol'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 0.41\nvar_e = var_c * var_d\nvar_f = 2.3\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "4750": {
        "category": "Geometry",
        "question_ko": "어느 공장에서 가로의 길이가 8센티미터(㎝), 세로의 길이가 12센티미터(㎝), 높이가 30센티미터(㎝)인 직육면체 모양의 부품 상자를 빈틈없이 쌓아 정육면체 모양의 방을 채웠습니다. 이때 방의 크기는 가능한 최소의 크기라고 할 때, 몇 개의 상자를 쌓았을지 구하시오.",
        "question_en": "In a factory, cuboid-shaped parts boxes measuring 8 centimeters (cm) in width, 12 centimeters (cm) in length, and 30 centimeters (cm) in height were stacked tightly to fill a cube-shaped room. At this time, if the size of the room is the smallest possible size, find how many boxes are stacked.",
        "answer_ko": "600",
        "answer_en": "600",
        "solution_abst_ko": "8 12 [OP_LCM] 30 [OP_LCM] 8 [OP_DIV] 8 12 [OP_LCM] 30 [OP_LCM] 12 [OP_DIV] 8 12 [OP_LCM] 30 [OP_LCM] 30 [OP_DIV] [OP_MUL] [OP_MUL]",
        "solution_abst_en": "8 12 [OP_LCM] 30 [OP_LCM] 8 [OP_DIV] 8 12 [OP_LCM] 30 [OP_LCM] 12 [OP_DIV] 8 12 [OP_LCM] 30 [OP_LCM] 30 [OP_DIV] [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 12\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nvar_d = 30\nvar_e = var_d * var_c / math.gcd(int(var_d), int(var_c))\nvar_f = 8\nvar_g = var_e / var_f\nvar_h = 8\nvar_i = 12\nvar_j = var_i * var_h / math.gcd(int(var_i), int(var_h))\nvar_k = 30\nvar_l = var_k * var_j / math.gcd(int(var_k), int(var_j))\nvar_m = 12\nvar_n = var_l / var_m\nvar_o = 8\nvar_p = 12\nvar_q = var_p * var_o / math.gcd(int(var_p), int(var_o))\nvar_r = 30\nvar_s = var_r * var_q / math.gcd(int(var_r), int(var_q))\nvar_t = 30\nvar_u = var_s / var_t\nvar_v = var_n * var_u\nvar_w = var_g * var_v\nprint(int(var_w))",
        "solution_code_en": "var_a = 8\nvar_b = 12\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nvar_d = 30\nvar_e = var_d * var_c / math.gcd(int(var_d), int(var_c))\nvar_f = 8\nvar_g = var_e / var_f\nvar_h = 8\nvar_i = 12\nvar_j = var_i * var_h / math.gcd(int(var_i), int(var_h))\nvar_k = 30\nvar_l = var_k * var_j / math.gcd(int(var_k), int(var_j))\nvar_m = 12\nvar_n = var_l / var_m\nvar_o = 8\nvar_p = 12\nvar_q = var_p * var_o / math.gcd(int(var_p), int(var_o))\nvar_r = 30\nvar_s = var_r * var_q / math.gcd(int(var_r), int(var_q))\nvar_t = 30\nvar_u = var_s / var_t\nvar_v = var_n * var_u\nvar_w = var_g * var_v\nprint(int(var_w))"
    },
    "4751": {
        "category": "Possibility",
        "question_ko": "1부터 6까지 숫자 카드가 있다. 윤이가 짝수 카드를 고르는 경우의 수를 구하시오.",
        "question_en": "There are cards with numbers from 1 to 6. Find the number of ways Yuni chooses a card with an even number inscribed.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "3",
        "solution_abst_en": "3",
        "solution_code_ko": "var_a = 3\nprint(int(var_a))",
        "solution_code_en": "var_a = 3\nprint(int(var_a))"
    },
    "4752": {
        "category": "Geometry",
        "question_ko": "가로가 5센티미터(㎝), 세로가 7센티미터(㎝)인 직사각형 모양의 카드를 겹치지 않게 빈틈없이 늘어놓아 가장 작은 정사각형을 만들려고 합니다. 이 정사각형의 한 변을 몇 센티미터(㎝)로 하면 됩니까?",
        "question_en": "I am trying to make the smallest square by arranging rectangular cards that are 5 centimeters (cm) wide and 7 centimeters (cm) tall without overlapping them. How many centimeters (cm) is one side of this square?",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "5 7 [OP_LCM]",
        "solution_abst_en": "5 7 [OP_LCM]",
        "solution_code_ko": "var_a = 5\nvar_b = 7\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 7\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nprint(int(var_c))"
    },
    "4753": {
        "category": "Geometry",
        "question_ko": "모서리의 길이의 합이 240센티미터(㎝)인 정팔각기둥이 있다. 이 각기둥의 높이가 12센티미터(㎝)일 때, 밑면의 한 변의 길이는 얼마입니까?",
        "question_en": "There is a regular octagonal prism whose sum of the lengths of its edges is 240 centimeters (cm). If the height of this prism is 12 centimeters (cm), what is the length of one side of the base?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "240 12 8 [OP_MUL] [OP_SUB] 8 [OP_DIV] 2 [OP_DIV]",
        "solution_abst_en": "240 12 8 [OP_MUL] [OP_SUB] 8 [OP_DIV] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 240\nvar_b = 12\nvar_c = 8\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 8\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 240\nvar_b = 12\nvar_c = 8\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 8\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "4754": {
        "category": "Comparison",
        "question_ko": "1.4, 9/10, 1, 0.5, 13/10 5개의 수 중 1보다 큰 수는 몇 개입니까?",
        "question_en": "Among five numbers of 1.4, 9/10, 1, 0.5, 13/10, how many are greater than 1?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1 0.5 13/10 [OP_LIST_EOL] 1 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1 0.5 13/10 [OP_LIST_EOL] 1 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "4755": {
        "category": "Possibility",
        "question_ko": "2, 0, 5, 9, 6 중에서 3개를 뽑아 한 번씩만 사용하여 세 자리 수를 만들려고 합니다. 만들 수 있는 가장 큰 수와 가장 작은 수의 곱을 구하시오.",
        "question_en": "You want to create a three-digit number by drawing three of 2, 0, 5, 9, and 6 and using them only once. Find the product of the largest number and the smallest number that can be made.",
        "answer_ko": "197825",
        "answer_en": "197825",
        "solution_abst_ko": "[OP_LIST_SOL] 2 0 5 9 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 2 0 5 9 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 0\nvar_c = 5\nvar_d = 9\nvar_e = 6\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 2\nvar_b = 0\nvar_c = 5\nvar_d = 9\nvar_e = 6\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h * var_j\nprint(int(var_k))"
    },
    "4756": {
        "category": "Arithmetic calculation",
        "question_ko": "40센티미터(㎝) 나무토막이 필요합니다. 2미터(m) 80센티미터(㎝) 나무토막이 있을 때 모두 몇 번 잘라야 합니까?",
        "question_en": "You will need a 40 centimeters (cm) block of wood. If you have a block of wood which is 2 meters (m) 80 centimeters (cm) long, how many times do you have to cut it?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "2 100 [OP_MUL] 80 [OP_ADD] 40 [OP_DIV] 1 [OP_SUB]",
        "solution_abst_en": "2 100 [OP_MUL] 80 [OP_ADD] 40 [OP_DIV] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 2\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 80\nvar_e = var_c + var_d\nvar_f = 40\nvar_g = var_e / var_f\nvar_h = 1\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 2\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 80\nvar_e = var_c + var_d\nvar_f = 40\nvar_g = var_e / var_f\nvar_h = 1\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "4757": {
        "category": "Comparison",
        "question_ko": "두 자리 수끼리의 곱셈에서 곱하는 수의 일의 자리 숫자 5를 2로 잘못 보고 계산한 값이 704가 되었습니다. 바르게 계산한 값이 800일 때, 2개의 두 자리 수 중 더 큰 수를 쓰시오.",
        "question_en": "In the multiplication of two-digit numbers, the 5 in the ones place of the number was misinterpreted as 2, so you mismultiplied it, resulting 704. If the correctly calculated value is 800, write the larger digit of the two two-digit numbers.",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "[OP_LIST_SOL] 704 800 [OP_SUB] 2 5 [OP_SUB] [OP_DIV] 800 704 800 [OP_SUB] 2 5 [OP_SUB] [OP_DIV] [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 704 800 [OP_SUB] 2 5 [OP_SUB] [OP_DIV] 800 704 800 [OP_SUB] 2 5 [OP_SUB] [OP_DIV] [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 704\nvar_b = 800\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = 5\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 800\nvar_i = 704\nvar_j = 800\nvar_k = var_i - var_j\nvar_l = 2\nvar_m = 5\nvar_n = var_l - var_m\nvar_o = var_k / var_n\nvar_p = var_h / var_o\nlist_a= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_a.append(var_p)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nlist_a.reverse()\nvar_q = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_r = list_b[-var_q]\nprint(int(var_r))",
        "solution_code_en": "var_a = 704\nvar_b = 800\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = 5\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 800\nvar_i = 704\nvar_j = 800\nvar_k = var_i - var_j\nvar_l = 2\nvar_m = 5\nvar_n = var_l - var_m\nvar_o = var_k / var_n\nvar_p = var_h / var_o\nlist_a= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_a.append(var_p)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nlist_a.reverse()\nvar_q = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_r = list_b[-var_q]\nprint(int(var_r))"
    },
    "4758": {
        "category": "Arithmetic calculation",
        "question_ko": "은지는 (가) 시험 12문제와 (나) 시험 15문제를 풀었습니다. (가) 시험은 4문제를 틀렸고, (나) 시험은 (가) 시험보다 2문제 더 많이 맞혔습니다. 은지가 (가) 시험과 (나) 시험에서 틀린 문제는 모두 몇 문제인지 구하시오.",
        "question_en": "Eunji solved 12 questions in the exam A and 15 questions in the exam B. She got 4 questions wrong in the exam A, and got 2 more questions right in exam B than in exam A. How many questions did Eunji get wrong in exam A and exam B in total?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "4 15 12 4 [OP_SUB] 2 [OP_ADD] [OP_SUB] [OP_ADD]",
        "solution_abst_en": "4 15 12 4 [OP_SUB] 2 [OP_ADD] [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 15\nvar_c = 12\nvar_d = 4\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e + var_f\nvar_h = var_b - var_g\nvar_i = var_a + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 4\nvar_b = 15\nvar_c = 12\nvar_d = 4\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e + var_f\nvar_h = var_b - var_g\nvar_i = var_a + var_h\nprint(int(var_i))"
    },
    "4759": {
        "category": "Arithmetic calculation",
        "question_ko": "색종이를 지민이는 41장 가지고 있고, 지민이는 석진이보다 1장 더 많이 가지고 있습니다. 석진이가 가지고 있는 색종이는 몇 장입니까?",
        "question_en": "Jimin has 41 pieces of colored paper, and Jimin has 1 more than Seokjin. How many pieces of colored paper does Seokjin have?",
        "answer_ko": "40",
        "answer_en": "40",
        "solution_abst_ko": "41 1 [OP_SUB]",
        "solution_abst_en": "41 1 [OP_SUB]",
        "solution_code_ko": "var_a = 41\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 41\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "4760": {
        "category": "Arithmetic calculation",
        "question_ko": "남준이가 윤기에게 사탕 18개를 주었더니 16개가 남았습니다. 처음에 남준이가 가지고 있던 사탕은 몇 개입니까?",
        "question_en": "Namjoon gave Yoongi 18 candies, and there are 16 left over. How many candies did Namjoon have in the beginning?",
        "answer_ko": "34",
        "answer_en": "34",
        "solution_abst_ko": "18 16 [OP_ADD]",
        "solution_abst_en": "18 16 [OP_ADD]",
        "solution_code_ko": "var_a = 18\nvar_b = 16\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 18\nvar_b = 16\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "4761": {
        "category": "Arithmetic calculation",
        "question_ko": "둘레의 길이가 3킬로미터(㎞)인 호수의 둘레를 연정이와 동훈이가 같은 곳에서 동시에 출발하여 서로 반대 방향으로 걸었다. 연정이는 매분 100미터(m)의 속력으로, 동훈이는 매분 150미터(m)의 속력으로 걸었다면 몇 분 후에 처음으로 다시 만나는지 구하여라",
        "question_en": "Yeonjeong and Donghun started at the same place and walked in opposite directions around the circumference of the lake with a circumference of 3 kilometers (km). If Yeonjeong walks at a speed of 100 meters (m) per minute and Donghun walks at a speed of 150 meters (m) per minute, find how many minutes later they meet again for the first time.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "3 100 1000 [OP_DIV] 150 1000 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_abst_en": "3 100 1000 [OP_DIV] 150 1000 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 3\nvar_b = 100\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = 150\nvar_f = 1000\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = var_a / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 3\nvar_b = 100\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = 150\nvar_f = 1000\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = var_a / var_h\nprint(int(var_i))"
    },
    "4762": {
        "category": "Possibility",
        "question_ko": "민지가 수학여행에서 입을 상의와 하의를 고르고 있습니다. 상의는 3종류가 있고 하의는 5종류가 있을 때, 민지가 입을 수 있는 옷의 조합은 모두 몇 가지인지 고르세요.",
        "question_en": "Minji wants to choose a top and a bottom to wear on a field trip. If there are 3 types of tops and 5 types of bottoms, choose how many combinations of clothes Minji can wear.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "3 1 [OP_COMB] 5 1 [OP_COMB] [OP_MUL]",
        "solution_abst_en": "3 1 [OP_COMB] 5 1 [OP_COMB] [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 1\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nvar_d = 5\nvar_e = 1\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f / (i+1)\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 3\nvar_b = 1\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nvar_d = 5\nvar_e = 1\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f / (i+1)\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "4763": {
        "category": "Possibility",
        "question_ko": "6 장의 숫자 카드 0, 1, 3, 5, 7, 9를 한 번씩 사용하여 만들 수 있는 가장 작은 여섯 자리 수를 올림하여 천의 자리까지 나타내어 보시오.",
        "question_en": "Round up the smallest six-digit number that you can make by using the six number cards 0, 1, 3, 5, 7, and 9 once, to the thousandth place.",
        "answer_ko": "104000",
        "answer_en": "104000",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 3 5 7 9 [OP_LIST_EOL] 6 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 4 [OP_CEIL]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 3 5 7 9 [OP_LIST_EOL] 6 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 4 [OP_CEIL]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 3\nvar_d = 5\nvar_e = 7\nvar_f = 9\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 6\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = 4\nvar_k=int(((var_i+9*10**(var_j-2))//(10**(var_j-1)))*10**(var_j-1))\n\nprint(int(var_k))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 3\nvar_d = 5\nvar_e = 7\nvar_f = 9\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 6\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = 4\nvar_k=int(((var_i+9*10**(var_j-2))//(10**(var_j-1)))*10**(var_j-1))\n\nprint(int(var_k))"
    },
    "4764": {
        "category": "Arithmetic calculation",
        "question_ko": "과자가 16개 담긴 상자가 4개 있습니다. 과자는 모두 몇 개 인가요?",
        "question_en": "There are 4 crates with 16 sweets each. How many sweets are there in all?",
        "answer_ko": "64",
        "answer_en": "64",
        "solution_abst_ko": "16 4 [OP_MUL]",
        "solution_abst_en": "16 4 [OP_MUL]",
        "solution_code_ko": "var_a = 16\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 16\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "4765": {
        "category": "Possibility",
        "question_ko": "배구공, 축구공, 농구공, 야구공이 1개씩 있습니다. 4개의 공 중에서 서로 다른 2개의 공을 고르는 방법은 모두 몇 가지입니까?",
        "question_en": "There is one volleyball, one soccerball, one basketball, and one baseball. How many different ways can there be to choose 2 different balls out of 4 balls?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 배구공 축구공 농구공 야구공 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] volleyball soccerball basketball baseball [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '배구공'\nvar_b = '축구공'\nvar_c = '농구공'\nvar_d = '야구공'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g / (i+1)\nprint(int(var_g))",
        "solution_code_en": "var_a = 'volleyball'\nvar_b = 'soccerball'\nvar_c = 'basketball'\nvar_d = 'baseball'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g / (i+1)\nprint(int(var_g))"
    },
    "4766": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이의 국어, 수학, 과학의 평균 점수는 92점입니다. 정국이가 영어 시험을 본 후 평균 점수가 2점 올랐다고 할 때, 정국이의 영어 점수는 몇 점입니까?",
        "question_en": "Jungkook's average score in Korean, math, and science is 92 points. If Jungkook's average score increased by 2 points after taking the English test, what is Jungkook's English score?",
        "answer_ko": "100",
        "answer_en": "100",
        "solution_abst_ko": "92 2 [OP_ADD] 4 [OP_MUL] 92 3 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "92 2 [OP_ADD] 4 [OP_MUL] 92 3 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 92\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c * var_d\nvar_f = 92\nvar_g = 3\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 92\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c * var_d\nvar_f = 92\nvar_g = 3\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nprint(int(var_i))"
    },
    "4767": {
        "category": "Correspondence",
        "question_ko": "목장에 양이 닭의 6/11만큼 있고, 소가 양의 1/8만큼 있다. 닭이 48마리이면 소는 몇 마리입니까?",
        "question_en": "The number of sheep is 6/11 of chickens, and the number of cows is 1/8 of sheeps in the farm. If there are 48 chickens, how many cows are there?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "48 6/11 [OP_DIV] 1/8 [OP_MUL]",
        "solution_abst_en": "48 6/11 [OP_DIV] 1/8 [OP_MUL]",
        "solution_code_ko": "var_a = 48\nvar_b = 0.5454545454545454\nvar_c = var_a / var_b\nvar_d = 0.125\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 48\nvar_b = 0.5454545454545454\nvar_c = var_a / var_b\nvar_d = 0.125\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "4768": {
        "category": "Possibility",
        "question_ko": "1부터 9까지의 자연수 중에서 서로 다른 두 수를 동시에 뽑으려고 합니다. 두 수의 합이 9보다 작은 경우의 수를 구하시오.",
        "question_en": "I am trying to draw two different numbers at the same time from the natural numbers from 1 to 9. Find the number of cases the sum of two numbers is less than 9.",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "1 9 1 [OP_LIST_ARANGE] 2 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 9 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "1 9 1 [OP_LIST_ARANGE] 2 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 9 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 9\nlist_d = []\nfor i in list_c:\n    if i < var_f:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 9\nlist_d = []\nfor i in list_c:\n    if i < var_f:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))"
    },
    "4769": {
        "category": "Geometry",
        "question_ko": "여러 개의 직육면체가 있습니다. 모든 직육면체의 모서리의 수와 면의 수의 합이 216일 때 모든 직육면체의 꼭짓점의 수의 합을 구하시오.",
        "question_en": "There are several cuboids. When the sum of the number of edges and the number of faces of all cuboids is 216, find the sum of the number of vertices of all cuboids.",
        "answer_ko": "96",
        "answer_en": "96",
        "solution_abst_ko": "216 12 6 [OP_ADD] [OP_DIV] 8 [OP_MUL]",
        "solution_abst_en": "216 12 6 [OP_ADD] [OP_DIV] 8 [OP_MUL]",
        "solution_code_ko": "var_a = 216\nvar_b = 12\nvar_c = 6\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nvar_f = 8\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 216\nvar_b = 12\nvar_c = 6\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nvar_f = 8\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "4770": {
        "category": "Arithmetic calculation",
        "question_ko": "희수네 학교의 3학년 학생 수는 총 240명입니다. 3학년 학생 중 안경을 쓴 학생은 안경을 쓰지 않은 학생의 3/5일 때, 안경을 쓰지 않은 3학년 학생은 몇 명인지 구하시오.",
        "question_en": "There are 240 third grade students at Heesu's school. If the number of third grade students who were glasses is 3/5 of the number of students who do not were glasses, how may third grade students do not were glasses?",
        "answer_ko": "150",
        "answer_en": "150",
        "solution_abst_ko": "240 1 3/5 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "240 1 3/5 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 240\nvar_b = 1\nvar_c = 0.6\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 240\nvar_b = 1\nvar_c = 0.6\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "4771": {
        "category": "Arithmetic calculation",
        "question_ko": "국화 5송이, 장미 2송이가 화분에 있습니다. 화분에 있는 꽃은 총 몇 송이 인가요?",
        "question_en": "Five chrysanthemums and two roses are in the pot. How many flowers are in the pot?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "5 2 [OP_ADD]",
        "solution_abst_en": "5 2 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "4772": {
        "category": "Comparison",
        "question_ko": "형준이네 반 학생 7명의 키가 161.5센티미터(㎝), 154.3센티미터(㎝), 143.7센티미터(㎝), 160.1센티미터(㎝), 158.0센티미터(㎝), 153.5센티미터(㎝), 147.8센티미터(㎝)일 때, 이 중에서 1미터(m) 50센티미터(㎝)가 넘는 학생은 몇 명인지 구하시오.",
        "question_en": "The height of the seven students in Hyungjun's class is 161.5 centimeters (cm), 154.3 centimeters (cm), 143.7 centimeters (cm), 160.1 centimeters (cm), 158.0 centimeters (cm), 153.5 centimeters (cm), 147.8 centimeters (cm) Find out how many of these students are over 1 meter (m) and 50 centimeters (cm).",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "[OP_LIST_SOL] 161.5 154.3 143.7 160.1 158.0 153.5 147.8 [OP_LIST_EOL] 1 100 [OP_MUL] 50 [OP_ADD] [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 161.5 154.3 143.7 160.1 158.0 153.5 147.8 [OP_LIST_EOL] 1 100 [OP_MUL] 50 [OP_ADD] [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 161.5\nvar_b = 154.3\nvar_c = 143.7\nvar_d = 160.1\nvar_e = 158\nvar_f = 153.5\nvar_g = 147.8\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h = 1\nvar_i = 100\nvar_j = var_h * var_i\nvar_k = 50\nvar_l = var_j + var_k\nlist_b = []\nfor i in list_a:\n    if i > var_l:\n        list_b.append(i)\nvar_m = len(list_b)\nprint(int(var_m))",
        "solution_code_en": "var_a = 161.5\nvar_b = 154.3\nvar_c = 143.7\nvar_d = 160.1\nvar_e = 158\nvar_f = 153.5\nvar_g = 147.8\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h = 1\nvar_i = 100\nvar_j = var_h * var_i\nvar_k = 50\nvar_l = var_j + var_k\nlist_b = []\nfor i in list_a:\n    if i > var_l:\n        list_b.append(i)\nvar_m = len(list_b)\nprint(int(var_m))"
    },
    "4773": {
        "category": "Geometry",
        "question_ko": "철사로 가로가 10센티미터(㎝), 세로가 8센티미터(㎝), 높이가 5센티미터(㎝)인 직육면체를 만들려고 합니다. 철사는 적어도 몇 센티미터(㎝)가 필요합니까?",
        "question_en": "We are going to make a rectangular parallelepiped 10 centimeters (cm) wide, 8 centimeters (cm) long, and 5 centimeters (cm) high with wire. At least how many centimeters (cm) of wire do you need?",
        "answer_ko": "92",
        "answer_en": "92",
        "solution_abst_ko": "10 4 [OP_MUL] 8 4 [OP_MUL] [OP_ADD] 5 4 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "10 4 [OP_MUL] 8 4 [OP_MUL] [OP_ADD] 5 4 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = 4\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 5\nvar_i = 4\nvar_j = var_h * var_i\nvar_k = var_g + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 10\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = 4\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 5\nvar_i = 4\nvar_j = var_h * var_i\nvar_k = var_g + var_j\nprint(int(var_k))"
    },
    "4774": {
        "category": "Geometry",
        "question_ko": "어떤 마름모를 둘러싸고 있는 가장 작은 원을 그리고, 원을 둘러싸고 있는 가장 작은 정사각형을 그렸습니다. 이 정사각형의 한 변의 길이가 16센티미터(㎝)라면, 마름모의 넓이는 몇인지 구하시오.",
        "question_en": "I drew the smallest circle enclosing a rhombus and the smallest square enclosing the circle. If the side of this square is 16 centimeters (cm), what is the area of the rhombus?",
        "answer_ko": "128",
        "answer_en": "128",
        "solution_abst_ko": "16 16 [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "16 16 [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 16\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 16\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "4775": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 74를 뺀 뒤 15를 곱하여 5로 나눈 뒤 16을 더한 후 15을 빼면 58입니다. 어떤 수를 구하시오.",
        "question_en": "Subtract 74 from a number, multiply by 15, divide by 5, add 16, then subtract 15 to get 58. Find this number.",
        "answer_ko": "93",
        "answer_en": "93",
        "solution_abst_ko": "58 15 [OP_ADD] 16 [OP_SUB] 5 [OP_MUL] 15 [OP_DIV] 74 [OP_ADD]",
        "solution_abst_en": "58 15 [OP_ADD] 16 [OP_SUB] 5 [OP_MUL] 15 [OP_DIV] 74 [OP_ADD]",
        "solution_code_ko": "var_a = 58\nvar_b = 15\nvar_c = var_a + var_b\nvar_d = 16\nvar_e = var_c - var_d\nvar_f = 5\nvar_g = var_e * var_f\nvar_h = 15\nvar_i = var_g / var_h\nvar_j = 74\nvar_k = var_i + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 58\nvar_b = 15\nvar_c = var_a + var_b\nvar_d = 16\nvar_e = var_c - var_d\nvar_f = 5\nvar_g = var_e * var_f\nvar_h = 15\nvar_i = var_g / var_h\nvar_j = 74\nvar_k = var_i + var_j\nprint(int(var_k))"
    },
    "4776": {
        "category": "Arithmetic calculation",
        "question_ko": "유나네 집에는 감이 12개 있습니다. 유정이가 이 중 3개를 먹었다면 유나네 집에 있는 감은 몇 개일까요?",
        "question_en": "In Yuna's house, there are 12 tangerines. If Yoo-jung ate 3 of them, how many tangerines are there at Yuna's house?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "12 3 [OP_SUB]",
        "solution_abst_en": "12 3 [OP_SUB]",
        "solution_code_ko": "var_a = 12\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 12\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "4777": {
        "category": "Correspondence",
        "question_ko": "등식 632-AB1=41이 성립한다고 합니다. A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "It is said that the equation 632-AB1=41 holds. What number should be in A?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "632-AB1=41 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "632-AB1=41 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '632-AB1=41'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '632-AB1=41'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "4778": {
        "category": "Arithmetic calculation",
        "question_ko": "빨간색 색연필이 전체의 5/9이고, 파란색 색연필이 전체의 5/12입니다. 전체 색연필의 수가 36자루라면, 빨간색 색연필 수에서 파란색 색연필 수를 빼면 몇 자루입니까?",
        "question_en": "The red colored pencil is 5/9 of the total, and the blue colored pencil is 5/12 of the total. If the total number of colored pencils is 36, what is the number of red colored pencils minus the number of blue colored pencils?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "36 5/9 [OP_MUL] 36 5/12 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "36 5/9 [OP_MUL] 36 5/12 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 36\nvar_b = 0.5555555555555556\nvar_c = var_a * var_b\nvar_d = 36\nvar_e = 0.4166666666666667\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 36\nvar_b = 0.5555555555555556\nvar_c = var_a * var_b\nvar_d = 36\nvar_e = 0.4166666666666667\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "4779": {
        "category": "Arithmetic calculation",
        "question_ko": "2153개의 의자를 화물차에 실어 나르려고 합니다. 한 번에 100개까지 실을 수 있을 때 화물차는 최소 몇 번을 날라야 할까요?",
        "question_en": "We are trying to load 2153 chairs onto a truck. How many times should a truck carry at least if it can load up to 100 at a time?",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "2153 100 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "2153 100 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 2153\nvar_b = 100\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))",
        "solution_code_en": "var_a = 2153\nvar_b = 100\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))"
    },
    "4780": {
        "category": "Comparison",
        "question_ko": "현수, 승아, 기윤 세 사람이 있습니다. 현수는 기윤이보다 키가 크고, 기윤이는 승아보다 키가 클 때, 키가 가장 큰 사람은 누구입니까?",
        "question_en": "There are three people: Hyunsoo, Seungah, and Kiyoon. Hyunsoo is taller than Kiyoon, and Kiyoon is taller than Seungah. Who is the tallest?",
        "answer_ko": "현수",
        "answer_en": "Hyunsoo",
        "solution_abst_ko": "[OP_LIST_SOL] 현수 승아 기윤 [OP_LIST_EOL] [OP_LIST_SOL] 현수 기윤 > 기윤 승아 > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Hyunsoo Seungah Kiyoon [OP_LIST_EOL] [OP_LIST_SOL] Hyunsoo Kiyoon > Kiyoon Seungah > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '현수'\nvar_b = '승아'\nvar_c = '기윤'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '현수'\nvar_e = '기윤'\nvar_f = '>'\nvar_g = '기윤'\nvar_h = '승아'\nvar_i = '>'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(var_k)",
        "solution_code_en": "var_a = 'Hyunsoo'\nvar_b = 'Seungah'\nvar_c = 'Kiyoon'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'Hyunsoo'\nvar_e = 'Kiyoon'\nvar_f = '>'\nvar_g = 'Kiyoon'\nvar_h = 'Seungah'\nvar_i = '>'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(var_k)"
    },
    "4781": {
        "category": "Comparison",
        "question_ko": "8명의 사람이 줄을 섰다. 뒤에서 4번째에 서 있는 사람과 앞에서 1번째에 서 있는 사람 사이에는 모두 몇 명이 있나요?",
        "question_en": "8 people lined up. How many people are there between the person standing 4th from the back and the person standing 1st from the front?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "8 1 [OP_SUB] 4 [OP_SUB]",
        "solution_abst_en": "8 1 [OP_SUB] 4 [OP_SUB]",
        "solution_code_ko": "var_a = 8\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "4782": {
        "category": "Geometry",
        "question_ko": "길이가 32센티미터(㎝) 인 끈으로 사각형을 만들었습니다. 만든 사각형의 넓이의 최대값은 몇 제곱센티미터(㎠) 입니까?",
        "question_en": "A square was made from a piece of string that is 32 centimeters (cm) long. What is the maximum area of the rectangle created in square centimeters (cm2)?",
        "answer_ko": "64",
        "answer_en": "64",
        "solution_abst_ko": "32 4 [OP_DIV] 2 [OP_POW]",
        "solution_abst_en": "32 4 [OP_DIV] 2 [OP_POW]",
        "solution_code_ko": "var_a = 32\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 32\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint(int(var_e))"
    },
    "4783": {
        "category": "Arithmetic calculation",
        "question_ko": "2개의 상자에 각각 3개, 4개의 공이 있습니다. 2개의 상자 안에 있는 공의 개수는 모두 몇 개입니까?",
        "question_en": "There are 2 boxes with 3 and 4 balls respectively. How many balls are there in both boxes?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "3 4 [OP_ADD]",
        "solution_abst_en": "3 4 [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 4\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 4\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "4784": {
        "category": "Correspondence",
        "question_ko": "두 자연수 A, B에 대하여 A를 B로 나누었을 때 몫이 9이고, 나머지가 13이었다면, A를 9로 나누었을 때의 나머지는 얼마입니까?",
        "question_en": "For two natural numbers A and B, if the quotient of A divided by B is 9 and the remainder is 13, what is the remainder if A is divided by 9?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "13 9 [OP_MOD]",
        "solution_abst_en": "13 9 [OP_MOD]",
        "solution_code_ko": "var_a = 13\nvar_b = 9\nvar_c = var_a % var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 13\nvar_b = 9\nvar_c = var_a % var_b\nprint(int(var_c))"
    },
    "4785": {
        "category": "Arithmetic calculation",
        "question_ko": "아버지는 닭 45마리를 기르고 있습니다. 오리가 닭보다 8마리 적다면, 아버지가 기르는 닭과 오리는 모두 몇 마리입니까?",
        "question_en": "My father has 45 chickens. If there are 8 fewer ducks than chickens, how many chickens and ducks does the father have?",
        "answer_ko": "82",
        "answer_en": "82",
        "solution_abst_ko": "45 45 8 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "45 45 8 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 45\nvar_b = 45\nvar_c = 8\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 45\nvar_b = 45\nvar_c = 8\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "4786": {
        "category": "Possibility",
        "question_ko": "123의 배수중 1620006보다 같거나 크고 1629996보다 같거나 작은 수가 있다. 이러한 수 중 가장 큰 수를 구하시오.",
        "question_en": "There are multiples of 123 that are greater than or equal to 1620006 and less than or equal to 1629996. Find the largest of these numbers.",
        "answer_ko": "1629996",
        "answer_en": "1629996",
        "solution_abst_ko": "1620006 1629996 1 [OP_LIST_ARANGE] 123 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_abst_en": "1620006 1629996 1 [OP_LIST_ARANGE] 123 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1620006\nvar_b = 1629996\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 123\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))",
        "solution_code_en": "var_a = 1620006\nvar_b = 1629996\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 123\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))"
    },
    "4787": {
        "category": "Arithmetic calculation",
        "question_ko": "남자가 23명, 여자가 9명 있습니다. 남자는 여자보다 몇 명 더 많습니까?",
        "question_en": "There are 23 males and 9 females. How many more men are there than women?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "23 9 [OP_SUB]",
        "solution_abst_en": "23 9 [OP_SUB]",
        "solution_code_ko": "var_a = 23\nvar_b = 9\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 23\nvar_b = 9\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "4788": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 2를 곱해야 할 것을 잘못하여 어떤 수에 5를 곱했더니 40이 되었습니다. 바르게 계산하면 얼마인지 구하시오.",
        "question_en": "You had to multiply a number by 2 but instead multiplied by 5 to get 40. Find the correctly calculated vlaue.",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "40 5 [OP_DIV] 2 [OP_MUL]",
        "solution_abst_en": "40 5 [OP_DIV] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 40\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 40\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "4789": {
        "category": "Comparison",
        "question_ko": "나은, 이준, 윤서, 서현, 소율 순으로 면접을 봅니다. 윤서와 서현이가 순서를 바꾸었을 때 4번째로 면접을 보는 사람은 누구인가요?",
        "question_en": "Naeun, Leejun, Yoonseo, Seohyun, and Soyul are interviewed in order. When Yoonseo and Seohyeon switched, who will be the 4th person being interviewed?",
        "answer_ko": "윤서",
        "answer_en": "Yoonseo",
        "solution_abst_ko": "[OP_LIST_SOL] 나은 이준 서현 윤서 소율 [OP_LIST_EOL] 4 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Naeun Leejun Seohyun Yoonseo Soyul [OP_LIST_EOL] 4 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '나은'\nvar_b = '이준'\nvar_c = '서현'\nvar_d = '윤서'\nvar_e = '소율'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 4\nvar_g = list_a[var_f-1]\nprint(var_g)",
        "solution_code_en": "var_a = 'Naeun'\nvar_b = 'Leejun'\nvar_c = 'Seohyun'\nvar_d = 'Yoonseo'\nvar_e = 'Soyul'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 4\nvar_g = list_a[var_f-1]\nprint(var_g)"
    },
    "4790": {
        "category": "Arithmetic calculation",
        "question_ko": "승찬이는 어제 가진 돈은 3/5를 사용했고, 오는 남은 돈의 2/3을 사용했다. 남은 돈은 처음 가지고 있던 돈의 몇 분의 몇 인가?",
        "question_en": "Seungchan used 3/5 of the money he had yesterday and used 2/3 of the remaining money today. How many fractions of the money he had left?",
        "answer_ko": "0.13",
        "answer_en": "0.13",
        "solution_abst_ko": "1 3/5 [OP_SUB] 1 2/3 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "1 3/5 [OP_SUB] 1 2/3 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 1\nvar_b = 0.6\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = 0.6666666666666666\nvar_f = var_d - var_e\nvar_g = var_c * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 0.6\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = 0.6666666666666666\nvar_f = var_d - var_e\nvar_g = var_c * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "4791": {
        "category": "Possibility",
        "question_ko": "수학, 과학, 국어, 사회, 음악 과목 중에서 3가지의 과목을 고르는 경우는 모두 몇 가지입니까?",
        "question_en": "How many times do you choose 3 subjects out of math, science, Korean, social studies, and music?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "5 3 [OP_COMB]",
        "solution_abst_en": "5 3 [OP_COMB]",
        "solution_code_ko": "var_a = 5\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))"
    },
    "4792": {
        "category": "Correspondence",
        "question_ko": "5A+13=64일 때, A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "If 5A+13=64, what number should be in A?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "5A+13=64 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "5A+13=64 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '5A+13=64'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '5A+13=64'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "4793": {
        "category": "Arithmetic calculation",
        "question_ko": "문제집에 있는 문제를 모두 풀기 위해 4일이 걸렸다. 첫째 날에는 전체의 1/2를 풀었고, 둘째 날에는 전체의 1/4를 풀었으며 셋째 날에는 전체 문제의 1/6을 풀었습니다. 마지막 날 20문제를 풀었을 때, 문제집에 있는 전체 문제의 개수를 구하세요.",
        "question_en": "It took 4 days to solve all the problems in the workbook. On the first day, I solved 1/2 of the total. On the second day, I solved 1/4 of the total. On the third day, I solved 1/6 of the total. When I solved 20 problems on the last day, find the total number of problems in the workbook.",
        "answer_ko": "240",
        "answer_en": "240",
        "solution_abst_ko": "20 1 1/2 1/4 [OP_ADD] 1/6 [OP_ADD] [OP_SUB] [OP_DIV]",
        "solution_abst_en": "20 1 1/2 1/4 [OP_ADD] 1/6 [OP_ADD] [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 20\nvar_b = 1\nvar_c = 0.5\nvar_d = 0.25\nvar_e = var_c + var_d\nvar_f = 0.16666666666666666\nvar_g = var_e + var_f\nvar_h = var_b - var_g\nvar_i = var_a / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))",
        "solution_code_en": "var_a = 20\nvar_b = 1\nvar_c = 0.5\nvar_d = 0.25\nvar_e = var_c + var_d\nvar_f = 0.16666666666666666\nvar_g = var_e + var_f\nvar_h = var_b - var_g\nvar_i = var_a / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))"
    },
    "4794": {
        "category": "Correspondence",
        "question_ko": "생선가게에 고등어가 조기의 6/11만큼 있고, 조기가 참치의 1/8만큼 있다. 고등어가 48마리 있을 때 참치는 몇 마리 있는지 구하시오.",
        "question_en": "The number of mackerel is 6/11 of croakers in the fish shop, and the number of croakers is 1/8 of tunas in the fish market. Find how many tunas are there when there are 48 mackerels.",
        "answer_ko": "704",
        "answer_en": "704",
        "solution_abst_ko": "48 6/11 [OP_DIV] 1/8 [OP_DIV]",
        "solution_abst_en": "48 6/11 [OP_DIV] 1/8 [OP_DIV]",
        "solution_code_ko": "var_a = 48\nvar_b = 0.5454545454545454\nvar_c = var_a / var_b\nvar_d = 0.125\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 48\nvar_b = 0.5454545454545454\nvar_c = var_a / var_b\nvar_d = 0.125\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "4795": {
        "category": "Possibility",
        "question_ko": "흰색 바둑돌 2개와 검은색 바둑돌 1개를 서로 다르게 한 줄로 놓는 방법은 모두 몇 가지입니까?",
        "question_en": "How many different ways can you place 2 white and 1 black go stones in a row?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "2 1 [OP_ADD] 2 [OP_COMB]",
        "solution_abst_en": "2 1 [OP_ADD] 2 [OP_COMB]",
        "solution_code_ko": "var_a = 2\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = 1\nvar_c = int(var_c)\nvar_d = int(var_d)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e * (var_c-i)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e / (i+1)\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = 1\nvar_c = int(var_c)\nvar_d = int(var_d)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e * (var_c-i)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e / (i+1)\nprint(int(var_e))"
    },
    "4796": {
        "category": "Possibility",
        "question_ko": "공항에서 외국인 3명과 한국인 2명이 검문소에서 줄을 서고 있다. 이때 외국인끼리는 연속해서 지나가야한다고 할 때, 경우의 수를 구하시오.",
        "question_en": "At the airport, 3 foreigners and 2 Koreans are lining up at the checkpoint. At this time, when it is said that foreigners must pass continuously, find the number of cases.",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "2 1 [OP_ADD] 2 1 [OP_ADD] [OP_PERM] 3 3 [OP_PERM] [OP_MUL]",
        "solution_abst_en": "2 1 [OP_ADD] 2 1 [OP_ADD] [OP_PERM] 3 3 [OP_PERM] [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = 1\nvar_c = int(var_c)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_c-i)\nvar_h = 3\nvar_i = 3\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nvar_k = var_g * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 2\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = 1\nvar_c = int(var_c)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_c-i)\nvar_h = 3\nvar_i = 3\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nvar_k = var_g * var_j\nprint(int(var_k))"
    },
    "4797": {
        "category": "Arithmetic calculation",
        "question_ko": "5, 1, 9, 0, 6, 8이 있습니다. 그중에서 4와 8 사이에 있는 수는 모두 몇 개입니까?",
        "question_en": "There are 5, 1, 9, 0, 6, and 8. How many of them are between 4 and 8?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 5 1 9 0 6 8 [OP_LIST_EOL] 4 [OP_LIST_MORE_EQUAL] 8 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 5 1 9 0 6 8 [OP_LIST_EOL] 4 [OP_LIST_MORE_EQUAL] 8 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 5\nvar_b = 1\nvar_c = 9\nvar_d = 0\nvar_e = 6\nvar_f = 8\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 4\nlist_b = []\nfor i in list_a:\n    if i >= var_g:\n        list_b.append(i)\nvar_h = 8\nlist_c = []\nfor i in list_b:\n    if i <= var_h:\n        list_c.append(i)\nvar_i = len(list_c)\nprint(int(var_i))",
        "solution_code_en": "var_a = 5\nvar_b = 1\nvar_c = 9\nvar_d = 0\nvar_e = 6\nvar_f = 8\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 4\nlist_b = []\nfor i in list_a:\n    if i >= var_g:\n        list_b.append(i)\nvar_h = 8\nlist_c = []\nfor i in list_b:\n    if i <= var_h:\n        list_c.append(i)\nvar_i = len(list_c)\nprint(int(var_i))"
    },
    "4798": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 30센티미터(㎝)인 정사각형 모양의 색상지 6장을 7센티미터(㎝)씩 한 줄로 겹쳐 놓고 풀로 칠하였습니다. 연결된 색상지의 넓이는 몇 제곱센티미터(㎠)인지 구하시오.",
        "question_en": "Six sheets of colored paper in the shape of a square with a side length of 30 centimeters (cm) were overlapped in a row by 7 centimeters (cm) and painted with glue. Find the area of the connected colored paper in square centimeters (cm2).",
        "answer_ko": "4350",
        "answer_en": "4350",
        "solution_abst_ko": "30 6 [OP_MUL] 7 6 1 [OP_SUB] [OP_MUL] [OP_SUB] 30 [OP_MUL]",
        "solution_abst_en": "30 6 [OP_MUL] 7 6 1 [OP_SUB] [OP_MUL] [OP_SUB] 30 [OP_MUL]",
        "solution_code_ko": "var_a = 30\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = 6\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_c - var_h\nvar_j = 30\nvar_k = var_i * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 30\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = 6\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_c - var_h\nvar_j = 30\nvar_k = var_i * var_j\nprint(int(var_k))"
    },
    "4799": {
        "category": "Correspondence",
        "question_ko": "10으로 어떤 수를 나누었더니 결과가 6이 되었습니다. 15를 어떤 수에서 빼면 얼마일까요?",
        "question_en": "When you divide a certain number by 10, the result is 6. What is the value of the certain number minus 15?",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "6 10 [OP_MUL] 15 [OP_SUB]",
        "solution_abst_en": "6 10 [OP_MUL] 15 [OP_SUB]",
        "solution_code_ko": "var_a = 6\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 15\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 15\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "4800": {
        "category": "Geometry",
        "question_ko": "사각기둥의 한 밑면의 수보다 팔각기둥의 한 밑면의 수가 몇 개 많나요?",
        "question_en": "How many more bases are there in an octagonal prism than there are bases in a square prism?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "8 4 [OP_SUB]",
        "solution_abst_en": "8 4 [OP_SUB]",
        "solution_code_ko": "var_a = 8\nvar_b = 4\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 8\nvar_b = 4\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "4801": {
        "category": "Arithmetic calculation",
        "question_ko": "유나는 3층에서 엘리베이터를 타고 2층 더 위로 올라갔습니다. 유나는 몇 층에 있을까요?",
        "question_en": "Yuna took the elevator from the third floor and went up two more floors. What floor is Yuna on?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "3 2 [OP_ADD]",
        "solution_abst_en": "3 2 [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "4802": {
        "category": "Correspondence",
        "question_ko": "한 자리 수 A, B로 이루어진 A2468B는 55로 나누어 떨어집니다. A2468이 될 수 있는 수의 개수를 구하시오.",
        "question_en": "A2468B, consisting of single digits A and B, is divisible by 55. Find the number of numbers that can be A2468.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "A2468B [OP_GEN_POSSIBLE_LIST] 55 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "A2468B [OP_GEN_POSSIBLE_LIST] 55 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 'A2468B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 55\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A2468B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 55\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))"
    },
    "4803": {
        "category": "Arithmetic calculation",
        "question_ko": "농장에 돼지는 42마리, 양은 48마리 있고, 돼지와 개의 수는 같습니다. 돼지와 개를 합친 수는 양보다 몇 마리 더 많이 있습니까?",
        "question_en": "There are 42 pigs and 48 sheep on the farm, and the number of pigs and dogs is the same. How many more pigs and dogs are there altogether than the number sheeps?",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "42 42 [OP_ADD] 48 [OP_SUB]",
        "solution_abst_en": "42 42 [OP_ADD] 48 [OP_SUB]",
        "solution_code_ko": "var_a = 42\nvar_b = 42\nvar_c = var_a + var_b\nvar_d = 48\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 42\nvar_b = 42\nvar_c = var_a + var_b\nvar_d = 48\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "4804": {
        "category": "Correspondence",
        "question_ko": "691-6A7=4이 성립합니다. A는 무엇인가요?",
        "question_en": "691-6A7=4. What is A?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "691-6A7=4 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "691-6A7=4 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '691-6A7=4'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '691-6A7=4'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "4805": {
        "category": "Correspondence",
        "question_ko": "637은 어떤 수에서 382를 빼야하는데 실수로 238을 더하여 나온 결과입니다. 바르게 계산하면 얼마입니까?",
        "question_en": "637 is the result of adding 238 to a number by mistake, which was supposed to subtract 382 from a number. How much do you get from a correct calculation?\n",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "637 238 [OP_SUB] 382 [OP_SUB]",
        "solution_abst_en": "637 238 [OP_SUB] 382 [OP_SUB]",
        "solution_code_ko": "var_a = 637\nvar_b = 238\nvar_c = var_a - var_b\nvar_d = 382\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 637\nvar_b = 238\nvar_c = var_a - var_b\nvar_d = 382\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "4806": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 가게에서 파는 수박이 5천원보다 2백원 쌀 때, 수박의 가격을 천원 단위로 구하시오.",
        "question_en": "If a watermelon sold at a store is 200 won cheaper than 5,000 won, find the price of the watermelon in units of 1,000 won.",
        "answer_ko": "4.80",
        "answer_en": "4.8",
        "solution_abst_ko": "5 2 10 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "5 2 10 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = 10\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = 10\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "4807": {
        "category": "Correspondence",
        "question_ko": "14에 대해 3으로 나눈 몫은 4, 나머지는 A입니다. A의 값은 무엇일까요?",
        "question_en": "The quotient of 14 divided by 3 is 4, and the remainder is A. What is the value of A?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "14 3 4 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "14 3 4 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 14\nvar_b = 3\nvar_c = 4\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 14\nvar_b = 3\nvar_c = 4\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "4808": {
        "category": "Arithmetic calculation",
        "question_ko": "들이가 2리터(L) 인 물통에 들이가 200밀리리터(㎖) 인 컵으로 물을 가득 채워 3 번 부었습니다. 물통에 물이 가득 차게 하려면 이 컵으로 적어도 몇 번을 더 부어야 하는지 구하시오.",
        "question_en": "A 2 liter (L) water bottle was filled with water in a 200 milliliter (㎖) cup and poured three times. Find at least how many more times you need to pour this cup to fill the bucket with water.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "2 1000 [OP_MUL] 200 3 [OP_MUL] [OP_SUB] 200 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "2 1000 [OP_MUL] 200 3 [OP_MUL] [OP_SUB] 200 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 200\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 200\nvar_i = var_g / var_h\nvar_j = 1\nvar_k=int(((var_i+9*10**(var_j-2))//(10**(var_j-1)))*10**(var_j-1))\n\nprint(int(var_k))",
        "solution_code_en": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 200\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 200\nvar_i = var_g / var_h\nvar_j = 1\nvar_k=int(((var_i+9*10**(var_j-2))//(10**(var_j-1)))*10**(var_j-1))\n\nprint(int(var_k))"
    },
    "4809": {
        "category": "Arithmetic calculation",
        "question_ko": "6년 전에 아버지 나이는 아들 나이의 5배였습니다. 올해부터 6년 후에 아버지와 아들의 나이의 합은 78살이 됩니다. 올해 아버지의 나이는 몇 살입니까?",
        "question_en": "Six years ago, the age of the father was five times the age of the son. Six years from this year, the sum of the ages of father and son will be 78. How old is the father this year?",
        "answer_ko": "51",
        "answer_en": "51",
        "solution_abst_ko": "78 6 2 [OP_MUL] [OP_SUB] 6 2 [OP_MUL] [OP_SUB] 5 1 [OP_ADD] [OP_FDIV] 5 [OP_MUL] 6 [OP_ADD]",
        "solution_abst_en": "78 6 2 [OP_MUL] [OP_SUB] 6 2 [OP_MUL] [OP_SUB] 5 1 [OP_ADD] [OP_FDIV] 5 [OP_MUL] 6 [OP_ADD]",
        "solution_code_ko": "var_a = 78\nvar_b = 6\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 6\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nvar_j = 5\nvar_k = 1\nvar_l = var_j + var_k\nvar_m = var_i // var_l\nvar_n = 5\nvar_o = var_m * var_n\nvar_p = 6\nvar_q = var_o + var_p\nprint(int(var_q))",
        "solution_code_en": "var_a = 78\nvar_b = 6\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 6\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nvar_j = 5\nvar_k = 1\nvar_l = var_j + var_k\nvar_m = var_i // var_l\nvar_n = 5\nvar_o = var_m * var_n\nvar_p = 6\nvar_q = var_o + var_p\nprint(int(var_q))"
    },
    "4810": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 세 자리 수의 백의 자리 숫자는 2이고 일의 자리 숫자는 7입니다. 가능한 가장 큰 수에 가장 작은 수를 더하면 얼마입니까?",
        "question_en": "In the hundreds place of the three-digit number ABC is 2 and in the units place is 7. What is the sum of the largest and smallest number of possible ABCs?",
        "answer_ko": "504",
        "answer_en": "504",
        "solution_abst_ko": "[OP_LIST_SOL] 2 A 7 [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 2 A 7 [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 'A'\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nans_dict = dict()\nvar_d = str(var_d)\nlist_b = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_d) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_b.append(new_elem)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 2\nvar_b = 'A'\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nans_dict = dict()\nvar_d = str(var_d)\nlist_b = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_d) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_b.append(new_elem)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))"
    },
    "4811": {
        "category": "Comparison",
        "question_ko": "(가), (나), (다), (라) 구슬의 크기를 비교해 보았더니 (가) 구슬은 (나) 구슬보다 크고 (나) 구슬은 (다) 구슬보다, (다) 구슬은 (라) 구슬보다 작았습니다. 이 중 크기가 가장 작은 구슬은 무엇이겠습니까?",
        "question_en": "We compared the sizes of beads - (a), (b), (c), (d). (a) bead is larger than (b) bead, (b) bead is smaller than (c) bead, and (c) bead is smaller than (d) bead.Which of these marbles is the smallest?",
        "answer_ko": "(나)",
        "answer_en": "(b)",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) (다) (라) [OP_LIST_EOL] [OP_LIST_SOL] (가) (라) > (나) (다) < (다) (라) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (a) (b) (c) (d) [OP_LIST_EOL] [OP_LIST_SOL] (a) (d) > (b) (c) < (c) (d) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nvar_c = '(다)'\nvar_d = '(라)'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '(가)'\nvar_f = '(라)'\nvar_g = '>'\nvar_h = '(나)'\nvar_i = '(다)'\nvar_j = '<'\nvar_k = '(다)'\nvar_l = '(라)'\nvar_m = '<'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)",
        "solution_code_en": "var_a = '(a)'\nvar_b = '(b)'\nvar_c = '(c)'\nvar_d = '(d)'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '(a)'\nvar_f = '(d)'\nvar_g = '>'\nvar_h = '(b)'\nvar_i = '(c)'\nvar_j = '<'\nvar_k = '(c)'\nvar_l = '(d)'\nvar_m = '<'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)"
    },
    "4812": {
        "category": "Arithmetic calculation",
        "question_ko": "작년에 호석이의 나이는 5살이었고 어머니는 35살이었습니다. 현재로부터 4년 후에 어머니의 나이는 호석이 나이의 몇 배입니까?",
        "question_en": "Last year, Hoseok was 5 years old and his mother was 35 years old. How many times would the mother's age be Hoseok's age 4 years from now?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "35 1 [OP_ADD] 4 [OP_ADD] 5 1 [OP_ADD] 4 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "35 1 [OP_ADD] 4 [OP_ADD] 5 1 [OP_ADD] 4 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 35\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = 4\nvar_j = var_h + var_i\nvar_k = var_e / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 35\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = 4\nvar_j = var_h + var_i\nvar_k = var_e / var_j\nprint(int(var_k))"
    },
    "4813": {
        "category": "Geometry",
        "question_ko": "지우는 어떤 퀴즈를 풀고 있었는데, 육각형의 내각의 크기의 합만큼 손잡이를 돌리라고 되어 있엇다. 손잡이를 몇 도(°)만큼 돌려야 하는가?",
        "question_en": "Jiwoo is solving a quiz, and she is told to turn the knob by the sum of the degrees of the interior angles of the hexagon. How many degrees (°) should the knob be turned?",
        "answer_ko": "720",
        "answer_en": "720",
        "solution_abst_ko": "6 2 [OP_SUB] 180 [OP_MUL]",
        "solution_abst_en": "6 2 [OP_SUB] 180 [OP_MUL]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 180\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 180\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "4814": {
        "category": "Arithmetic calculation",
        "question_ko": "41명의 3학년 학생 중 남학생이 여학생보다 3명이 더 많습니다. 남학생은 몇 명인지 구하시오.",
        "question_en": "Of the 41 third-grade students, there are three more male students than female students. Find how many male students there are.",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "41 3 [OP_SUB] 2 [OP_DIV] 3 [OP_ADD]",
        "solution_abst_en": "41 3 [OP_SUB] 2 [OP_DIV] 3 [OP_ADD]",
        "solution_code_ko": "var_a = 41\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 3\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 41\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 3\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "4815": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 초등학교의 3학년 학생 수는 217명, 4학년 학생 수는 196명입니다. 3학년과 5학년을 합한 학생의 수와 4학년과 6학년을 합한 학생 수가 같을 때, 5학년과 6학년 학생 수의 차는 몇 명입니까?",
        "question_en": "An elementary school has 217 3rd-grade students and 196 4th-grade students. If the number of students in grades 3 and 5 combined is equal to the number of students in grades 4 and 6 combined, what is the difference between the number of students in grades 5 and 6?",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "217 196 [OP_SUB] [OP_ABS]",
        "solution_abst_en": "217 196 [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 217\nvar_b = 196\nvar_c = var_a - var_b\nvar_d = abs(var_c)\nprint(int(var_d))",
        "solution_code_en": "var_a = 217\nvar_b = 196\nvar_c = var_a - var_b\nvar_d = abs(var_c)\nprint(int(var_d))"
    },
    "4816": {
        "category": "Geometry",
        "question_ko": "팔각형의 한 꼭짓점에서 다른 꼭짓점들에게 대각선을 그었습니다. 이때 생기는 삼각형의 개수를 구하시오.",
        "question_en": "Diagonals were drawn from one vertex of the octagon to the other vertices. Find the number of triangles formed in this case.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "8 3 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "8 3 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "4817": {
        "category": "Arithmetic calculation",
        "question_ko": "두 지점 A, B 사이를 자전거를 타고 왕복하는데 갈때는 시속 15 킬로미터(㎞)로, 올 때는 시속 10 킬로미터(㎞)로 달렸더니 올 때는 갈 때보다 30분이 더 걸렸다. 두 지점 A, B 사이의 거리를 구하시오.",
        "question_en": "I made a roundtrip between two points A and B by bicycle, traveling at 15 kilometers (km) per hour on the way and 10 kilometers (km) per hour on the way back. It took 30 minutes longer on the way back. Find the distance between two points A and B.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "30 60 [OP_DIV] 1 10 [OP_DIV] 1 15 [OP_DIV] [OP_SUB] [OP_DIV]",
        "solution_abst_en": "30 60 [OP_DIV] 1 10 [OP_DIV] 1 15 [OP_DIV] [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 30\nvar_b = 60\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = 10\nvar_f = var_d / var_e\nvar_g = 1\nvar_h = 15\nvar_i = var_g / var_h\nvar_j = var_f - var_i\nvar_k = var_c / var_j\nprint(int(eval('{:.2f}'.format(round(var_k+1e-10,2)))))",
        "solution_code_en": "var_a = 30\nvar_b = 60\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = 10\nvar_f = var_d / var_e\nvar_g = 1\nvar_h = 15\nvar_i = var_g / var_h\nvar_j = var_f - var_i\nvar_k = var_c / var_j\nprint(int(eval('{:.2f}'.format(round(var_k+1e-10,2)))))"
    },
    "4818": {
        "category": "Geometry",
        "question_ko": "한 꼭짓점에서 6개의 대각선을 그을 수 잇는 다격형의 꼭짓점의 개수를 구하시오.",
        "question_en": "Find the number of vertices of a polyhedron such that 6 diagonals can be drawn from one vertex.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "6 3 [OP_ADD]",
        "solution_abst_en": "6 3 [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 3\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 3\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "4819": {
        "category": "Correspondence",
        "question_ko": "구슬이 32개가 들어있는 세트 3개를 사서 학생들에게 4개씩 나누어주었더니 남는 것 없이 모두 나누어 주었다고 한다. 학생들은 모두 몇 명인지 구하시오.",
        "question_en": "You bought three sets of marbles with 32 marbles in each and handed four of them out to each student. When there are no marbles left, find how many students there are.",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "32 3 [OP_MUL] 4 [OP_DIV]",
        "solution_abst_en": "32 3 [OP_MUL] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 32\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 32\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "4820": {
        "category": "Arithmetic calculation",
        "question_ko": "배나무가 56그루 있습니다. 배나무는 사과나무보다 18그루 많고, 귤나무는 사과나무보다 12그루 적습니다. 귤나무는 모두 몇 그루입니까?",
        "question_en": "There are 56 pear trees. There are 18 more pear trees than apple trees, and 12 fewer tangerine trees than apple trees. How many tangerine trees are there in all?",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "56 18 [OP_SUB] 12 [OP_SUB]",
        "solution_abst_en": "56 18 [OP_SUB] 12 [OP_SUB]",
        "solution_code_ko": "var_a = 56\nvar_b = 18\nvar_c = var_a - var_b\nvar_d = 12\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 56\nvar_b = 18\nvar_c = var_a - var_b\nvar_d = 12\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "4821": {
        "category": "Comparison",
        "question_ko": "정국이는 6 나누기 3만큼 사과를 모았고, 윤기는 4개의 사과를 모았습니다. 사과의 개수가 더 큰 사람은 누구입니까?",
        "question_en": "Jungkook collected 6 divided by 3 apples, and Yoongi collected 4 apples. Who has the greater number of apples?",
        "answer_ko": "윤기",
        "answer_en": "Yoongi",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 윤기 [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_FDIV] 4 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Yoongi [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_FDIV] 4 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '윤기'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 3\nvar_e = var_c // var_d\nvar_f = 4\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Yoongi'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 3\nvar_e = var_c // var_d\nvar_f = 4\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "4822": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 9, 6, 2로 나누어 떨어질 수 있는 수 중 가장 큰 다섯 자리 수는?",
        "question_en": "Which 5-digit number is the largest number divisible by 9, 6, and 2?",
        "answer_ko": "99990",
        "answer_en": "99990",
        "solution_abst_ko": "10000 99999 1 [OP_LIST_ARANGE] 9 [OP_LIST_DIVISIBLE] 6 [OP_LIST_DIVISIBLE] 2 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_abst_en": "10000 99999 1 [OP_LIST_ARANGE] 9 [OP_LIST_DIVISIBLE] 6 [OP_LIST_DIVISIBLE] 2 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 10000\nvar_b = 99999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 9\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 6\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 2\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_h = list_e[-var_g]\nprint(int(var_h))",
        "solution_code_en": "var_a = 10000\nvar_b = 99999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 9\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 6\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 2\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_h = list_e[-var_g]\nprint(int(var_h))"
    },
    "4823": {
        "category": "Arithmetic calculation",
        "question_ko": "여학생이 127명이고 윤기네 학교 학생 수는 총 280명일때 여학생은 남학생보다 몇 명 더 적나요?",
        "question_en": "If there are 127 female students and the total number of students at Yoongi's school is 280, how many fewer female students than male students are there?",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "280 127 [OP_SUB] 127 [OP_SUB]",
        "solution_abst_en": "280 127 [OP_SUB] 127 [OP_SUB]",
        "solution_code_ko": "var_a = 280\nvar_b = 127\nvar_c = var_a - var_b\nvar_d = 127\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 280\nvar_b = 127\nvar_c = var_a - var_b\nvar_d = 127\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "4824": {
        "category": "Geometry",
        "question_ko": "어떤 수에 6을 곱하여야 하는데 잘못하여 6을 더하고 2를 곱하였더니 28이었다고 한다. 바르게 계산한 값을 구하시오.",
        "question_en": "I was supposed to multiply a certain number by 6, but by mistake, adding 6 to it and multiplying it by 2 resulted in 28. Find the correct calculated value.",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "28 2 [OP_DIV] 6 [OP_SUB] 6 [OP_MUL]",
        "solution_abst_en": "28 2 [OP_DIV] 6 [OP_SUB] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 28\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c - var_d\nvar_f = 6\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 28\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c - var_d\nvar_f = 6\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "4825": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이가 책을 펼쳤는데 두 쪽수의 합이 185였습니다. 정국이가 펼친 두 쪽수 중 작은 수를 쓰시오.",
        "question_en": "Jungkook opened the book and the sum of the two pages was 185. Write the smaller of the two pages that Jungkook unfolded.",
        "answer_ko": "92",
        "answer_en": "92",
        "solution_abst_ko": "185 2 [OP_FDIV]",
        "solution_abst_en": "185 2 [OP_FDIV]",
        "solution_code_ko": "var_a = 185\nvar_b = 2\nvar_c = var_a // var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 185\nvar_b = 2\nvar_c = var_a // var_b\nprint(int(var_c))"
    },
    "4826": {
        "category": "Correspondence",
        "question_ko": "어떤 두 수를 더해야 할 것을 잘못하여 뺐더니 12가 되었습니다. 이것은 바르게 계산했을 때의 정답과 40만큼 차이가 납니다. 어떤 두 수의 곱을 구하시오.",
        "question_en": "You mistakenly subtracted what two numbers should be added to, and got 12. This is different by 40 from the correct answer. Find the product of those two numbers.",
        "answer_ko": "640",
        "answer_en": "640",
        "solution_abst_ko": "40 2 [OP_DIV] 12 [OP_ADD] 40 2 [OP_DIV] [OP_MUL]",
        "solution_abst_en": "40 2 [OP_DIV] 12 [OP_ADD] 40 2 [OP_DIV] [OP_MUL]",
        "solution_code_ko": "var_a = 40\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 12\nvar_e = var_c + var_d\nvar_f = 40\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = var_e * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 40\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 12\nvar_e = var_c + var_d\nvar_f = 40\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = var_e * var_h\nprint(int(var_i))"
    },
    "4827": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 3인 정사면체의 모서리 길이의 합에서 3을 더한 값을 구하시오.",
        "question_en": "Find the sum of the lengths of the edges of a regular tetrahedron with a side length of 3 centimeters (cm) plus 3.",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "3 6 3 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "3 6 3 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 6\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 3\nvar_b = 6\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "4828": {
        "category": "Correspondence",
        "question_ko": "윤기는 두 자리 수와 네 자리 수의 뺄셈을 하려 합니다. 윤기는 두 자리 수의 십의 자리 숫자와 일의 자리 숫자를 바꾸어 23이라고 잘못 보았고, 네 자리 수의 일의 자리 숫자 9를 6으로 잘못 보았습니다. 윤기가 구한 차는 1299 일 때, 네 자리 수를 구하시오.",
        "question_en": "Yoongi wants to do a subtraction with a two-digit number and a four-digit number. Yoongi confused the tens and units digits of the two-digit number to get 23, and the four-digit number's units digit 9 was misread as 6. When the difference Yoongi got is 1299, find the four-digit number.",
        "answer_ko": "1273",
        "answer_en": "1273",
        "solution_abst_ko": "23 1299 [OP_SUB] 6 9 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "23 1299 [OP_SUB] 6 9 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 23\nvar_b = 1299\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 23\nvar_b = 1299\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "4829": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 각각 30센티미터(㎝), 20센티미터(㎝)인 두 양초 A, B에 동시에 불을 붙였다. 양초 A는 1분에 1센티미터(㎝)씩 길이가 줄어들고, 양초 B는 1분에 0.5센티미터(㎝)씩 길이가 줄어든다고 한다. 두 양초의 길이가 같아졌을 때의 양초의 길이를 구하여라.",
        "question_en": "Two candles A and B, each 30 centimeters (cm) and 20 centimeters (cm) long, were lit at the same time. Candle A is said to lose 1 centimeter (cm) per minute, and candle B is said to lose 0.5 centimeters (cm) per minute. Find the length of the candle when both candles are equal in length.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "30 30 20 [OP_SUB] 1 0.5 [OP_SUB] [OP_DIV] [OP_SUB]",
        "solution_abst_en": "30 30 20 [OP_SUB] 1 0.5 [OP_SUB] [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 30\nvar_b = 30\nvar_c = 20\nvar_d = var_b - var_c\nvar_e = 1\nvar_f = 0.5\nvar_g = var_e - var_f\nvar_h = var_d / var_g\nvar_i = var_a - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 30\nvar_b = 30\nvar_c = 20\nvar_d = var_b - var_c\nvar_e = 1\nvar_f = 0.5\nvar_g = var_e - var_f\nvar_h = var_d / var_g\nvar_i = var_a - var_h\nprint(int(var_i))"
    },
    "4830": {
        "category": "Comparison",
        "question_ko": "20명의 학생들의 키를 비교하고 있습니다. 정국이는 윤기보다 키가 크고, 윤기와 정국이 사이에는 5명의 학생이 있습니다. 정국이보다 키가 큰 학생은 모두 6명입니다. 윤기보다 작은 학생은 몇 명입니까?",
        "question_en": "You are comparing the heights of 20 students. Jungkook is taller than Yoongi, and there are 5 students between Yoongi and Jungkook. There are 6 students who are taller than Jungkook. How many students are shorter than Yoongi?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "20 6 [OP_SUB] 1 [OP_SUB] 5 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "20 6 [OP_SUB] 1 [OP_SUB] 5 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 6\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 5\nvar_g = var_e - var_f\nvar_h = 1\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 20\nvar_b = 6\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 5\nvar_g = var_e - var_f\nvar_h = 1\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "4831": {
        "category": "Arithmetic calculation",
        "question_ko": "남준이가 가진 꽃의 4배 만큼 유정이가 꽃을 가지고 있습니다. 유정이가 가진 꽃의 수가 32송이라면 유정이와 남준이가 가진 꽃은 모두 몇 송이입니까?",
        "question_en": "Yoojung has 4 times as many flowers as Namjoon. If Yoojung has 32 flowers, how many flowers do Yoojung and Namjoon have?",
        "answer_ko": "40",
        "answer_en": "40",
        "solution_abst_ko": "32 32 4 [OP_DIV] [OP_ADD]",
        "solution_abst_en": "32 32 4 [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 32\nvar_b = 32\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 32\nvar_b = 32\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "4832": {
        "category": "Arithmetic calculation",
        "question_ko": "양동이에 담겨 있는 13/4리터(L)의 물 중에서 12/5리터(L)를 청소하는 데 사용하고, 11/6리터(L)만큼의 물을 양동이에 다시 채웠습니다. 양동이에 남은 물은 몇 리터(L)인지 구하시오.",
        "question_en": "Of the 13/4 liters (l) of water in the bucket, 12/5 liters (l) were used for cleaning, and 11/6 liters (l) of water was refilled into the bucket. Find how many liters (l) of water are left in the bucket.",
        "answer_ko": "2.68",
        "answer_en": "2.68",
        "solution_abst_ko": "13/4 12/5 [OP_SUB] 11/6 [OP_ADD]",
        "solution_abst_en": "13/4 12/5 [OP_SUB] 11/6 [OP_ADD]",
        "solution_code_ko": "var_a = 3.25\nvar_b = 2.4\nvar_c = var_a - var_b\nvar_d = 1.8333333333333333\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 3.25\nvar_b = 2.4\nvar_c = var_a - var_b\nvar_d = 1.8333333333333333\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "4833": {
        "category": "Possibility",
        "question_ko": "숫자 카드 2, 5, 8을 한 번씩 사용하여 만들 수 있는 세 자리 수 중에서 가장 큰 수와 가장 작은 수의 차에 두 번째로 큰 수를 곱하면 얼마가 됩니까?",
        "question_en": "Find the difference between the largest and smallest three-digit number that can be formed using the number cards 2, 5, and 8 once. What is the answer when multiplying that by the second largest number?",
        "answer_ko": "490050",
        "answer_en": "490050",
        "solution_abst_ko": "[OP_LIST_SOL] 2 5 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB] [OP_ABS] 2 [OP_LIST_MAX] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 2 5 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB] [OP_ABS] 2 [OP_LIST_MAX] [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 5\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f - var_h\nvar_j = abs(var_i)\nvar_k = 2\nlist_e=list_b.copy()\nlist_e.sort()\nvar_l = list_e[-var_k]\nvar_m = var_j * var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 2\nvar_b = 5\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f - var_h\nvar_j = abs(var_i)\nvar_k = 2\nlist_e=list_b.copy()\nlist_e.sort()\nvar_l = list_e[-var_k]\nvar_m = var_j * var_l\nprint(int(var_m))"
    },
    "4834": {
        "category": "Correspondence",
        "question_ko": "과일선물세트에 10개의 사과가 들어있다. 과일 선물세트에 2/9가 사과이고 2/5가 배라고 할 때, 과일선물세트에 들어있는 배의 개수를 구하시오.",
        "question_en": "There are 10 apples in the fruit gift set. If 2/9 of the fruit gift set is apples and 2/5 is pears, find the number of pears in the fruit gift set.",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "10 2/9 [OP_DIV] 2/5 [OP_MUL]",
        "solution_abst_en": "10 2/9 [OP_DIV] 2/5 [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 0.2222222222222222\nvar_c = var_a / var_b\nvar_d = 0.4\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 0.2222222222222222\nvar_c = var_a / var_b\nvar_d = 0.4\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "4835": {
        "category": "Correspondence",
        "question_ko": "8은 어떤 수에 12를 곱해야하는데 실수로 나누어서 나온 결과입니다. 바르게 계산한 결과를 구하세요.",
        "question_en": "A particular number should have been multiplied by 12, but the result was 8 because it was divided by mistake. Find the correct calculation result.",
        "answer_ko": "1152",
        "answer_en": "1152",
        "solution_abst_ko": "8 12 [OP_MUL] 12 [OP_MUL]",
        "solution_abst_en": "8 12 [OP_MUL] 12 [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "4836": {
        "category": "Arithmetic calculation",
        "question_ko": "돼지 저금통에 동전을 8개 더 넣었더니 모두 29개가 되었습니다. 돼지 저금통에는 처음 몇 개의 동전이 있었을까요?",
        "question_en": "I put 8 more coins in the piggy bank, and there are 29 coins in total. How many coins were there in the first place?",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "29 8 [OP_SUB]",
        "solution_abst_en": "29 8 [OP_SUB]",
        "solution_code_ko": "var_a = 29\nvar_b = 8\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 29\nvar_b = 8\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "4837": {
        "category": "Geometry",
        "question_ko": "한 모서리의 길이가 60㎝인 정육면체 모양의 상자가 있습니다. 가로와 세로가 각각 5㎝인 색종이를 상자의 바깥쪽 겉면에 빈틈없이 붙이려고 할 때, 색종이는 적어도 몇 장 필요합니까?",
        "question_en": "There is a box in the shape of a cube with one edge 60 centimeters (cm) long. How many pieces of colored paper are needed to glue 5 centimeters (cm) wide and 5 centimeters (cm) long colored paper to the outer surface of the box without any gap?",
        "answer_ko": "864",
        "answer_en": "864",
        "solution_abst_ko": "60 2 [OP_POW] 6 [OP_MUL] 5 2 [OP_POW] [OP_DIV]",
        "solution_abst_en": "60 2 [OP_POW] 6 [OP_MUL] 5 2 [OP_POW] [OP_DIV]",
        "solution_code_ko": "var_a = 60\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = var_c * var_d\nvar_f = 5\nvar_g = 2\nvar_h = var_f ** var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 60\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = var_c * var_d\nvar_f = 5\nvar_g = 2\nvar_h = var_f ** var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "4838": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 1/3, 5/24, 8.16, 1/8이 있습니다. 총합은?",
        "question_en": "Find the total of four numbers 1/3, 5/24, 8.16, and 1/8. ",
        "answer_ko": "8.83",
        "answer_en": "8.83",
        "solution_abst_ko": "1/3 5/24 [OP_ADD] 8.16 [OP_ADD] 1/8 [OP_ADD]",
        "solution_abst_en": "1/3 5/24 [OP_ADD] 8.16 [OP_ADD] 1/8 [OP_ADD]",
        "solution_code_ko": "var_a = 0.3333333333333333\nvar_b = 0.20833333333333334\nvar_c = var_a + var_b\nvar_d = 8.16\nvar_e = var_c + var_d\nvar_f = 0.125\nvar_g = var_e + var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 0.3333333333333333\nvar_b = 0.20833333333333334\nvar_c = var_a + var_b\nvar_d = 8.16\nvar_e = var_c + var_d\nvar_f = 0.125\nvar_g = var_e + var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "4839": {
        "category": "Comparison",
        "question_ko": "앞에서 7번째 줄, 뒤에서 16번째 줄, 오른쪽에서 13번째, 왼쪽에서 9번째 열에 장미가 심어져 있습니다. 각 열에 같은 수의 꽃이 심어져 있다고 할 때, 꽃의 수는 총 몇 송이인지 구하시오.",
        "question_en": "A rose is planted in the 7th row from the front, the 16th row from the back, the 13th row from the right, and the 9th row from the left. Assuming the same number of flowers are planted in each row, find the total number of flowers.",
        "answer_ko": "462",
        "answer_en": "462",
        "solution_abst_ko": "7 16 [OP_ADD] 1 [OP_SUB] 9 13 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "7 16 [OP_ADD] 1 [OP_SUB] 9 13 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 7\nvar_b = 16\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 9\nvar_g = 13\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 7\nvar_b = 16\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 9\nvar_g = 13\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))"
    },
    "4840": {
        "category": "Arithmetic calculation",
        "question_ko": "3의 배수 중 가장 작은 두 자리 수는?",
        "question_en": "What is the smallest two-digit multiple of 3?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "10 99 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "10 99 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nprint(int(var_f))",
        "solution_code_en": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nprint(int(var_f))"
    },
    "4841": {
        "category": "Correspondence",
        "question_ko": "4개의 그물안에 21개씩 축구공이 들어있습니다. 모든 축구공을 똑같은 개수로 축구부부원 12명에게 나누어준다면 한 명은 몇 개의 축구공을 가지게 되는지 구하시오.",
        "question_en": "There are 21 soccer balls in the four nets. If all soccer balls are handed out equally to 12 soccer team members, how many soccer balls will each player have?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "4 21 [OP_MUL] 12 [OP_DIV]",
        "solution_abst_en": "4 21 [OP_MUL] 12 [OP_DIV]",
        "solution_code_ko": "var_a = 4\nvar_b = 21\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 4\nvar_b = 21\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "4842": {
        "category": "Correspondence",
        "question_ko": "윤수네 반 학생들 24명에게 셔틀콕을 똑같이 나누어 주었을 때, 학생당 19개씩 나누어주고 남은 셔틀콕이 없었다고 한다. 윤수네 반 학생들에게 나누어 준 셔틀콕의 개수는 모두 몇 개인지 구하시오.",
        "question_en": "When the shuttlecocks were distributed equally to 24 students in Yunsu's class, 19 shuttlecocks were distributed to each student and there were no shuttlecocks left. Find the total number of shuttlecocks distributed to the students in Yunsu's class.",
        "answer_ko": "456",
        "answer_en": "456",
        "solution_abst_ko": "19 24 [OP_MUL]",
        "solution_abst_en": "19 24 [OP_MUL]",
        "solution_code_ko": "var_a = 19\nvar_b = 24\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 19\nvar_b = 24\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "4843": {
        "category": "Comparison",
        "question_ko": "(가), (나), (다), (라) 4개의 꽃병이 있습니다. (다) 꽃병은 (가) 꽃병보다 큽니다. (라) 꽃병은 (가) 꽃병보다 작습니다. (다) 꽃병은 (나) 꽃병보다 작습니다. 크기가 가장 큰 꽃병은 무엇입니까?",
        "question_en": "There are 4 vases, (a), (b), (c), and (d). Vase (c) is larger than vase (a). Vase (d) is smaller than vase (a). Vase (c) is smaller than vase (b). What is the largest vase?",
        "answer_ko": "(나)",
        "answer_en": "(b)",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) (다) (라) [OP_LIST_EOL] [OP_LIST_SOL] (다) (가) > (라) (가) < (다) (나) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (a) (b) (c) (d) [OP_LIST_EOL] [OP_LIST_SOL] (c) (a) > (d) (a) < (c) (b) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nvar_c = '(다)'\nvar_d = '(라)'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '(다)'\nvar_f = '(가)'\nvar_g = '>'\nvar_h = '(라)'\nvar_i = '(가)'\nvar_j = '<'\nvar_k = '(다)'\nvar_l = '(나)'\nvar_m = '<'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = 1\nvar_o = list_c[var_n-1]\nprint(var_o)",
        "solution_code_en": "var_a = '(a)'\nvar_b = '(b)'\nvar_c = '(c)'\nvar_d = '(d)'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '(c)'\nvar_f = '(a)'\nvar_g = '>'\nvar_h = '(d)'\nvar_i = '(a)'\nvar_j = '<'\nvar_k = '(c)'\nvar_l = '(b)'\nvar_m = '<'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = 1\nvar_o = list_c[var_n-1]\nprint(var_o)"
    },
    "4844": {
        "category": "Correspondence",
        "question_ko": "한수는 시험에서 7로 나누어야하는 문제를 잘못보고 곱하여서 115.15라는 답을 제출했다. 한수가 푼 문제의 정답은 얼마인가?",
        "question_en": "Hansoo multiplied the value by 7, which should have been divided by 7, by mistake. So he submitted the wrong answer of 115.15. What should be the correct answer to the problem?",
        "answer_ko": "2.35",
        "answer_en": "2.35",
        "solution_abst_ko": "115.15 7 [OP_DIV] 7 [OP_DIV]",
        "solution_abst_en": "115.15 7 [OP_DIV] 7 [OP_DIV]",
        "solution_code_ko": "var_a = 115.15\nvar_b = 7\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 115.15\nvar_b = 7\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "4845": {
        "category": "Comparison",
        "question_ko": "네 수 중 가장 큰 것과 작은 것의 차를 구하시오. 2.5 , 22/13, 0.7, 32/33.",
        "question_en": "Find the difference between the largest and the smallest of the four numbers 2.5, 22/13, 0.7, and 32/33.",
        "answer_ko": "1.80",
        "answer_en": "1.8",
        "solution_abst_ko": "[OP_LIST_SOL] 2.5 22/13 0.7 32/33 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 2.5 22/13 0.7 32/33 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 2.5\nvar_b = 1.6923076923076923\nvar_c = 0.7\nvar_d = 0.9696969696969697\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f - var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 2.5\nvar_b = 1.6923076923076923\nvar_c = 0.7\nvar_d = 0.9696969696969697\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f - var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "4846": {
        "category": "Arithmetic calculation",
        "question_ko": "12보다 큰 자연수 중에서 가장 작은 자연수는 얼마인지 구하시오",
        "question_en": "What is the smallest natural number greater than 12?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "12 1 [OP_ADD] 999 1 [OP_LIST_ARANGE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "12 1 [OP_ADD] 999 1 [OP_LIST_ARANGE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 12\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 999\nvar_e = 1\nlist_a = [i for i in range(var_c, var_d + 1, var_e)]\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 12\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 999\nvar_e = 1\nlist_a = [i for i in range(var_c, var_d + 1, var_e)]\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nprint(int(var_g))"
    },
    "4847": {
        "category": "Possibility",
        "question_ko": "정육면체 모양의 상자에서 한 꼭짓점에 모인 면의 개수는 몇 개 일까요?",
        "question_en": "How many faces of a cube-shaped box meet at one vertex?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "3",
        "solution_abst_en": "3",
        "solution_code_ko": "var_a = 3\nprint(int(var_a))",
        "solution_code_en": "var_a = 3\nprint(int(var_a))"
    },
    "4848": {
        "category": "Comparison",
        "question_ko": "흰색 서랍장의 부피는 2세제곱미터(㎥)이고 검정색 서랍장의 부피는 85000세제곱센티미터(㎤)입니다. 둘 중 부피가 큰 서랍장의 색깔은 무엇입니까?",
        "question_en": "The white chest of drawers has a volume of 2 cubic meters (m3) and the black chest of drawers has a volume of 85000 cubic centimeters (cm3). Which color chest of drawers is more bulky?",
        "answer_ko": "흰색",
        "answer_en": "white",
        "solution_abst_ko": "[OP_LIST_SOL] 흰색 검정색 [OP_LIST_EOL] [OP_LIST_SOL] 2 850000 100 3 [OP_POW] [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] white black [OP_LIST_EOL] [OP_LIST_SOL] 2 850000 100 3 [OP_POW] [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '흰색'\nvar_b = '검정색'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nvar_d = 850000\nvar_e = 100\nvar_f = 3\nvar_g = var_e ** var_f\nvar_h = var_d / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'white'\nvar_b = 'black'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nvar_d = 850000\nvar_e = 100\nvar_f = 3\nvar_g = var_e ** var_f\nvar_h = var_d / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "4849": {
        "category": "Arithmetic calculation",
        "question_ko": "수학이 82점이고 국어는 5점 더 높다. 국어, 영어, 수학의 평균이 89점일 때 영어는 몇 점인가?",
        "question_en": "Mathematics is 82 points, Korean language is 5 points higher. If the average score in Korean, English, and Mathematics is 89, what is the English score?",
        "answer_ko": "98",
        "answer_en": "98",
        "solution_abst_ko": "89 3 [OP_MUL] 82 [OP_SUB] 82 5 [OP_ADD] [OP_SUB]",
        "solution_abst_en": "89 3 [OP_MUL] 82 [OP_SUB] 82 5 [OP_ADD] [OP_SUB]",
        "solution_code_ko": "var_a = 89\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 82\nvar_e = var_c - var_d\nvar_f = 82\nvar_g = 5\nvar_h = var_f + var_g\nvar_i = var_e - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 89\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 82\nvar_e = var_c - var_d\nvar_f = 82\nvar_g = 5\nvar_h = var_f + var_g\nvar_i = var_e - var_h\nprint(int(var_i))"
    },
    "4850": {
        "category": "Arithmetic calculation",
        "question_ko": "구슬이 62개 있습니다. 몇 개의 구슬을 더하면 남는 것 없이 8명에게 똑같이 나누어 줄 수 있습니다. 필요한 구슬의 최소 개수를 구하시오.",
        "question_en": "There are 62 marbles. Add a few more marbles and you'll have no leftover and hand it out equally to 8 people. Find the minimum number of marbles required.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "8 62 8 [OP_MOD] [OP_SUB]",
        "solution_abst_en": "8 62 8 [OP_MOD] [OP_SUB]",
        "solution_code_ko": "var_a = 8\nvar_b = 62\nvar_c = 8\nvar_d = var_b % var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 62\nvar_c = 8\nvar_d = var_b % var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "4851": {
        "category": "Correspondence",
        "question_ko": "40을 어떤 수에 더해야 할 것을 잘못하여 6을 어떤 수에 나눈 결과는 52가 나옵니다. 바르게 계산하면 얼마인가요?",
        "question_en": "You have to add 40 to a number. But you divided a number by 6 by mistake and obtained a result of 52. What is the correct result of the calculation?",
        "answer_ko": "352",
        "answer_en": "352",
        "solution_abst_ko": "52 6 [OP_MUL] 40 [OP_ADD]",
        "solution_abst_en": "52 6 [OP_MUL] 40 [OP_ADD]",
        "solution_code_ko": "var_a = 52\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 40\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 52\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 40\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "4852": {
        "category": "Arithmetic calculation",
        "question_ko": "태양이네 학교에서 수학여행을 가기 위해 버스를 빌리기로 하였습니다. 버스 한 대에 30명까지 탈 수 있을 때 학생 1284명이 전부 타기 위해서는 버스를 적어도 몇 대 빌려야 할까요?",
        "question_en": "Taeyang's school decided to rent a bus to go on a school trip. When a bus can accommodate up to 30 students, how many buses should the school rent to accommodate all 1284 students?",
        "answer_ko": "43",
        "answer_en": "43",
        "solution_abst_ko": "1284 30 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "1284 30 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 1284\nvar_b = 30\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))",
        "solution_code_en": "var_a = 1284\nvar_b = 30\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))"
    },
    "4853": {
        "category": "Possibility",
        "question_ko": "5, 0, 1, 8, 7 중에서 서로 다른 숫자 4개를 뽑아 만들 수 있는 네 자리 수 중에서 3번째로 작은 수를 쓰시오.",
        "question_en": "Write down the 3rd smallest number among four-digit numbers that can be formed from four different numbers among 5, 0, 1, 8, and 7.",
        "answer_ko": "1075",
        "answer_en": "1075",
        "solution_abst_ko": "[OP_LIST_SOL] 5 0 1 8 7 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 3 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 5 0 1 8 7 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 3 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 5\nvar_b = 0\nvar_c = 1\nvar_d = 8\nvar_e = 7\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nprint(int(var_h))",
        "solution_code_en": "var_a = 5\nvar_b = 0\nvar_c = 1\nvar_d = 8\nvar_e = 7\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nprint(int(var_h))"
    },
    "4854": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 10, 11, 12, 13이 있습니다. 그 중에서 가장 큰 수와 그 다음으로 큰 수의 곱은 얼마입니까?",
        "question_en": "There are four numbers 10, 11, 12, and 13. What is the product of the largest number and the next largest number?",
        "answer_ko": "156",
        "answer_en": "156",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = var_f * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = var_f * var_h\nprint(int(var_i))"
    },
    "4855": {
        "category": "Arithmetic calculation",
        "question_ko": "학생들이 8줄로 서 있습니다. 그중에서 7개의 줄에는 6명씩 서 있고, 나머지 1줄에는 5명이 서 있습니다. 학생들은 모두 몇 명입니까?",
        "question_en": "The students are standing in eight rows. Among them, there are six people standing in each of the seven rows, and five people are standing in last row. How many students are there in total?",
        "answer_ko": "47",
        "answer_en": "47",
        "solution_abst_ko": "7 6 [OP_MUL] 1 5 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "7 6 [OP_MUL] 1 5 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 7\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 7\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "4856": {
        "category": "Possibility",
        "question_ko": "5개의 숫자 2, 0, 3, 5, 8을 이용하여 네 자리 수를 만들고자 한다. 만들 수 있는 수 중 가장 큰 수와 가장 작은 수의 차이를 구하시오.",
        "question_en": "We want to create a four-digit number using the five numbers 2, 0, 3, 5, and 8. Find the difference between the largest and smallest possible numbers.",
        "answer_ko": "6497",
        "answer_en": "6497",
        "solution_abst_ko": "[OP_LIST_SOL] 2 0 3 5 8 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 2 0 3 5 8 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 2\nvar_b = 0\nvar_c = 3\nvar_d = 5\nvar_e = 8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 2\nvar_b = 0\nvar_c = 3\nvar_d = 5\nvar_e = 8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h - var_j\nprint(int(var_k))"
    },
    "4857": {
        "category": "Comparison",
        "question_ko": "(가), (나) 2개의 상자가 배달왔습니다. 지민이는 두 상자 중 작은 상자를 들고 가려고 합니다. (가) 상자보다 (나) 상자가 작았다면, 지민이가 들고가야 하는 상자는 무엇입니까?",
        "question_en": "Two boxes (A), (B) have been delivered. Jimin tries to carry the smaller of the two boxes. If box (A) is smaller than box (B), which box does Jimin have to carry?",
        "answer_ko": "(나)",
        "answer_en": "(B)",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) [OP_LIST_EOL] [OP_LIST_SOL] (가) (나) > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (A) (B) [OP_LIST_EOL] [OP_LIST_SOL] (A) (B) > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = '(가)'\nvar_d = '(나)'\nvar_e = '>'\nlist_b= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_f = len(list_c)\nvar_g = list_c[var_f-1]\nprint(var_g)",
        "solution_code_en": "var_a = '(A)'\nvar_b = '(B)'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = '(A)'\nvar_d = '(B)'\nvar_e = '>'\nlist_b= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_f = len(list_c)\nvar_g = list_c[var_f-1]\nprint(var_g)"
    },
    "4858": {
        "category": "Correspondence",
        "question_ko": "23를 6으로 나누면 몫과 나머지가 각각 A와 5가 나옵니다. 이 때 A를 구하시오.",
        "question_en": "When 23 is divided by 6, the quotient and remainder are A and 5, respectively. Find A at here.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "23 5 [OP_SUB] 6 [OP_DIV]",
        "solution_abst_en": "23 5 [OP_SUB] 6 [OP_DIV]",
        "solution_code_ko": "var_a = 23\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 23\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "4859": {
        "category": "Correspondence",
        "question_ko": "AB2-41=591일 때, A를 구하시오.",
        "question_en": "When AB2-41=591, find A.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "AB2-41=591 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "AB2-41=591 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'AB2-41=591'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'AB2-41=591'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "4860": {
        "category": "Comparison",
        "question_ko": "소현, 소민, 지수는 같은 양의 수학 숙제를 받았습니다. 세 사람이 풀고 남은 수학 문제의 수가 수현이는 전체의 1/4, 소민이는 전체의 1/8, 지수는 전체의 1/5입니다. 현재 가장 많은 양의 문제를 푼 사람은 누구입니까?",
        "question_en": "Suhyeon, Somin, and Jisoo received the same amount of math homework. The number of math problems remaining after the three solved them is 1/4 for Sohyeon, 1/8 for Somin, and 1/5 for Jisoo. Who currently has the highest amount of problems solved?",
        "answer_ko": "소민",
        "answer_en": "Somin",
        "solution_abst_ko": "[OP_LIST_SOL] 소현 소민 지수 [OP_LIST_EOL] [OP_LIST_SOL] 1 1/4 [OP_SUB] 1 1/8 [OP_SUB] 1 1/5 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Suhyeon Somin Jisoo [OP_LIST_EOL] [OP_LIST_SOL] 1 1/4 [OP_SUB] 1 1/8 [OP_SUB] 1 1/5 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '소현'\nvar_b = '소민'\nvar_c = '지수'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nvar_e = 0.25\nvar_f = var_d - var_e\nvar_g = 1\nvar_h = 0.125\nvar_i = var_g - var_h\nvar_j = 1\nvar_k = 0.2\nvar_l = var_j - var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'Suhyeon'\nvar_b = 'Somin'\nvar_c = 'Jisoo'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nvar_e = 0.25\nvar_f = var_d - var_e\nvar_g = 1\nvar_h = 0.125\nvar_i = var_g - var_h\nvar_j = 1\nvar_k = 0.2\nvar_l = var_j - var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "4861": {
        "category": "Arithmetic calculation",
        "question_ko": "연속된 짝수 3개의 합이 1194일 때, 가장 작은 짝수와 가장 큰 짝수의 합은 얼마입니까?",
        "question_en": "If the sum of three consecutive even numbers is 1194, what is the sum of the smallest and largest even numbers?",
        "answer_ko": "796",
        "answer_en": "796",
        "solution_abst_ko": "1194 0 3 1 [OP_SUB] 2 [OP_MUL] 2 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 3 [OP_DIV] 2 [OP_MUL] 3 1 [OP_SUB] 2 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "1194 0 3 1 [OP_SUB] 2 [OP_MUL] 2 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 3 [OP_DIV] 2 [OP_MUL] 3 1 [OP_SUB] 2 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 1194\nvar_b = 0\nvar_c = 3\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = 2\nlist_a = [i for i in range(var_b, var_g + 1, var_h)]\nlist_a = [float(i) for i in list_a]\nvar_i = sum(list_a)\nvar_j = var_a - var_i\nvar_k = 3\nvar_l = var_j / var_k\nvar_m = 2\nvar_n = var_l * var_m\nvar_o = 3\nvar_p = 1\nvar_q = var_o - var_p\nvar_r = 2\nvar_s = var_q * var_r\nvar_t = var_n + var_s\nprint(int(var_t))",
        "solution_code_en": "var_a = 1194\nvar_b = 0\nvar_c = 3\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = 2\nlist_a = [i for i in range(var_b, var_g + 1, var_h)]\nlist_a = [float(i) for i in list_a]\nvar_i = sum(list_a)\nvar_j = var_a - var_i\nvar_k = 3\nvar_l = var_j / var_k\nvar_m = 2\nvar_n = var_l * var_m\nvar_o = 3\nvar_p = 1\nvar_q = var_o - var_p\nvar_r = 2\nvar_s = var_q * var_r\nvar_t = var_n + var_s\nprint(int(var_t))"
    },
    "4862": {
        "category": "Comparison",
        "question_ko": "민호의 나이는 수홍이의 나이의 3배이고, 민아의 나이는 수홍이의 나이의 2배보다 2살 적습니다. 세 사람의 나이의 합이 34살일 때, 민아의 나이는 몇 살인지 구하시오.",
        "question_en": "Minho's age is three times Suhong's age, and Mina's age is two years younger than twice the Suhong's age. If the sum of the ages of the three is 34, how old is Mina?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "34 2 [OP_ADD] 3 1 [OP_ADD] 2 [OP_ADD] [OP_DIV] 2 [OP_MUL] 2 [OP_SUB]",
        "solution_abst_en": "34 2 [OP_ADD] 3 1 [OP_ADD] 2 [OP_ADD] [OP_DIV] 2 [OP_MUL] 2 [OP_SUB]",
        "solution_code_ko": "var_a = 34\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = var_c / var_h\nvar_j = 2\nvar_k = var_i * var_j\nvar_l = 2\nvar_m = var_k - var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 34\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = var_c / var_h\nvar_j = 2\nvar_k = var_i * var_j\nvar_l = 2\nvar_m = var_k - var_l\nprint(int(var_m))"
    },
    "4863": {
        "category": "Correspondence",
        "question_ko": "서로 다른 두 수 A, B가 있습니다. 곱셈식 AB×6=BBB에서 A와 B의 차를 구하시오.",
        "question_en": "There are two different numbers A and B. Find the difference between A and B in the multiplication equation AB×6=BBB.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "AB×6=BBB A [OP_DIGIT_UNK_SOLVER] AB×6=BBB B [OP_DIGIT_UNK_SOLVER] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "AB×6=BBB A [OP_DIGIT_UNK_SOLVER] AB×6=BBB B [OP_DIGIT_UNK_SOLVER] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 'AB×6=BBB'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 'AB×6=BBB'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c - var_f\nvar_h = abs(var_g)\nprint(int(var_h))",
        "solution_code_en": "var_a = 'AB×6=BBB'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 'AB×6=BBB'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c - var_f\nvar_h = abs(var_g)\nprint(int(var_h))"
    },
    "4864": {
        "category": "Possibility",
        "question_ko": "1, 2, 3, 4 ..., 998, 999를 차례로 이어 써서 1234567891011121314...998999를 만들었다. 이 수의 각 자리 숫자들의 총합을 구하여라.",
        "question_en": "1, 2, 3, 4 ..., 998, 999 were written sequentially to make 1234567891011121314...998999. Find the sum of each digit in this number.",
        "answer_ko": "13500",
        "answer_en": "13500",
        "solution_abst_ko": "1 999 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] [OP_LIST_SUM]",
        "solution_abst_en": "1 999 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_b=[]\nfor i in list_a:\n    var_d = 0\n    i = int(i)\n    while i//10 > 0:\n        var_d = var_d + i%10\n        i = i//10\n    var_d = var_d + i%10\n    list_b.append(var_d)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_b=[]\nfor i in list_a:\n    var_d = 0\n    i = int(i)\n    while i//10 > 0:\n        var_d = var_d + i%10\n        i = i//10\n    var_d = var_d + i%10\n    list_b.append(var_d)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint(int(var_e))"
    },
    "4865": {
        "category": "Arithmetic calculation",
        "question_ko": "현서는 우리나라 돈을 중국 돈으로 환전하려고 합니다. 중국 돈 1위안을 얻으려면 우리나라 돈 161.5원이 필요합니다. 우리나라 돈 17만원을 중국 돈 1000위안과 10위안으로 바꾸려 할 때, 1000위안으로 최대한 많이 바꾼다면 10위안은 몇 장으로 바꿀 수 있는 지 구하세요.",
        "question_en": "Hyunseo wants to exchange Korean money for Chinese money. It takes 161.5 Korean won to get 1 Chinese yuan. If you want to change 170,000 won in Korean money into 1000 yuan and 10 yuan in Chinese money, find how many 10 yuan you can get when you exchange as many 1000 yuan as possible.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "17 10000 [OP_MUL] 161.5 1000 [OP_MUL] [OP_MOD] 161.5 10 [OP_MUL] [OP_FDIV]",
        "solution_abst_en": "17 10000 [OP_MUL] 161.5 1000 [OP_MUL] [OP_MOD] 161.5 10 [OP_MUL] [OP_FDIV]",
        "solution_code_ko": "var_a = 17\nvar_b = 10000\nvar_c = var_a * var_b\nvar_d = 161.5\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = var_c % var_f\nvar_h = 161.5\nvar_i = 10\nvar_j = var_h * var_i\nvar_k = var_g // var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 17\nvar_b = 10000\nvar_c = var_a * var_b\nvar_d = 161.5\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = var_c % var_f\nvar_h = 161.5\nvar_i = 10\nvar_j = var_h * var_i\nvar_k = var_g // var_j\nprint(int(var_k))"
    },
    "4866": {
        "category": "Arithmetic calculation",
        "question_ko": "처음 윤기가 가지고 있는 돈이 3800원일때, 오늘부터 매일 100원씩 받으면 7일후에 윤기가 가지고 있는 돈은 모두 얼마가 됩니까?",
        "question_en": "If Yoongi's initial money is 3,800 won, and he receives 100 won every day from today, how much money will he have after 7 days?",
        "answer_ko": "4500",
        "answer_en": "4500",
        "solution_abst_ko": "3800 100 7 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "3800 100 7 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 3800\nvar_b = 100\nvar_c = 7\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 3800\nvar_b = 100\nvar_c = 7\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "4867": {
        "category": "Comparison",
        "question_ko": "서윤이네 학교의 강당은 1105제곱미터(㎡)이며 학생 수는 650명입니다. 예림이네 학교의 강당은 1440제곱미터(㎡)이며 학생 수는 960 명입니다. 한 명당 사용하는 강당의 넓이가 더 넓은 학교는 누구네 학교입니까?",
        "question_en": "The auditorium of Seoyoon's school is 1105 square meters (㎡), and the school has 650 students. The auditorium of Yerim's school is measured as 1440 square meters (㎡), and 960 students are attending the school. Which school has a larger auditorium per student?",
        "answer_ko": "서윤",
        "answer_en": "Seoyoon",
        "solution_abst_ko": "[OP_LIST_SOL] 서윤 예림 [OP_LIST_EOL] [OP_LIST_SOL] 1105 650 [OP_DIV] 1440 960 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Seoyoon Yerim [OP_LIST_EOL] [OP_LIST_SOL] 1105 650 [OP_DIV] 1440 960 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '서윤'\nvar_b = '예림'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1105\nvar_d = 650\nvar_e = var_c / var_d\nvar_f = 1440\nvar_g = 960\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Seoyoon'\nvar_b = 'Yerim'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1105\nvar_d = 650\nvar_e = var_c / var_d\nvar_f = 1440\nvar_g = 960\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "4868": {
        "category": "Correspondence",
        "question_ko": "25를 4로 나눴을 때 몫이 A, 나머지가 B 였습니다. 이 때 A는 무엇인가요?",
        "question_en": "When 25 is divided by 4, the quotient is A and the remainder is B. What is A in this case?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "25 4 [OP_FDIV]",
        "solution_abst_en": "25 4 [OP_FDIV]",
        "solution_code_ko": "var_a = 25\nvar_b = 4\nvar_c = var_a // var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 25\nvar_b = 4\nvar_c = var_a // var_b\nprint(int(var_c))"
    },
    "4869": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 34를 더하고 53을 뺐더니 28이 되었습니다. 어떤 수를 구하시오.",
        "question_en": "Adding 34 to a certain number and subtracting 53 results in 28. Find the certain number.",
        "answer_ko": "47",
        "answer_en": "47",
        "solution_abst_ko": "28 53 [OP_ADD] 34 [OP_SUB]",
        "solution_abst_en": "28 53 [OP_ADD] 34 [OP_SUB]",
        "solution_code_ko": "var_a = 28\nvar_b = 53\nvar_c = var_a + var_b\nvar_d = 34\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 28\nvar_b = 53\nvar_c = var_a + var_b\nvar_d = 34\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "4870": {
        "category": "Arithmetic calculation",
        "question_ko": "빨간 공 3개, 파란 공 2개, 노란 공 5개가 담겨져 있는 상자에서 파란 공 1개를 뺐을 때, 노란 공의 개수는?",
        "question_en": "If 1 blue ball is removed from a box containing 3 red balls, 2 blue balls, and 5 yellow balls, what is the number of yellow balls?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "5",
        "solution_abst_en": "5",
        "solution_code_ko": "var_a = 5\nprint(int(var_a))",
        "solution_code_en": "var_a = 5\nprint(int(var_a))"
    },
    "4871": {
        "category": "Possibility",
        "question_ko": "1부터 9까지의 자연수가 적힌 공들이 있다. 이 중 3개를 꺼내서 공에 적힌 숫자의 합이 19가 되게 하는 방법은 모두 몇 가지인지 구하라.",
        "question_en": "There are balls with numbers from 1 to 9 written on them. Find how many ways there are when you pick 3 of them in order to make 19 by adding the numbers on the ball.",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "1 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 19 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 19 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 19\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 19\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))"
    },
    "4872": {
        "category": "Geometry",
        "question_ko": "정육면체의 꼭지점의 개수는?",
        "question_en": "How many vertices does the cube have?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "6 2 [OP_SUB] 2 [OP_MUL]",
        "solution_abst_en": "6 2 [OP_SUB] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "4873": {
        "category": "Possibility",
        "question_ko": "1, 2, 4, 6 중에서 서로 다른 숫자 2개를 뽑아 만들 수 있는 두 자리 수 중에서 가장 큰 수를 쓰시오.",
        "question_en": "Write the largest two-digit number that can be formed by drawing two different numbers from 1, 2, 4, and 6.",
        "answer_ko": "64",
        "answer_en": "64",
        "solution_abst_ko": "[OP_LIST_SOL] 1 2 4 6 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1 2 4 6 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1\nvar_b = 2\nvar_c = 4\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 2\nvar_c = 4\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint(int(var_g))"
    },
    "4874": {
        "category": "Arithmetic calculation",
        "question_ko": "현철이는 가진 돈의 절반으로 젤리를 사고, 남은 돈의 절반으로 사탕을 샀습니다. 남은 돈이 1250원이었다면, 처음에 현철이가 가지고 있던 돈을 얼마일까요?",
        "question_en": "Hyeoncheol bought jelly with half of the money he had, and candy with half of the money he had left. If the remaining money was 1250 won, how much money did Hyuncheol have at the beginning?",
        "answer_ko": "5000",
        "answer_en": "5000",
        "solution_abst_ko": "1250 2 [OP_MUL] 2 [OP_MUL]",
        "solution_abst_en": "1250 2 [OP_MUL] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 1250\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 1250\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "4875": {
        "category": "Geometry",
        "question_ko": "직사각형 모양의 책을 정면에서 봤을 때 둘레는 100센티미터(㎝)이고, 가로의 길이는 20센티미터(㎝)라면, 이 책의 세로의 길이는 얼마일지 구하시오.",
        "question_en": "If the circumference of a rectangular book is 100 centimeters (cm) and the width is 20 centimeters (cm) when viewed from the front, what is the length of this book?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "100 2 [OP_DIV] 20 [OP_SUB]",
        "solution_abst_en": "100 2 [OP_DIV] 20 [OP_SUB]",
        "solution_code_ko": "var_a = 100\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 20\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 100\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 20\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "4876": {
        "category": "Arithmetic calculation",
        "question_ko": "1번째 날 장난감을 40개 팔았습니다. 2번째 날에는 1번째 날에 판 장난감 수의 4배만큼 팔았습니다. 2번째 날 판 장난감은 1번째 날 판 장난감보다 몇 개 더 많습니까?",
        "question_en": "You sold 40 toys on Day 1. On Day 2, you sold 4 times the number of toys sold on Day 1. Find out the number of toys you sold more on Day 2 compared to Day 1.",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "40 4 [OP_MUL] 40 [OP_SUB]",
        "solution_abst_en": "40 4 [OP_MUL] 40 [OP_SUB]",
        "solution_code_ko": "var_a = 40\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 40\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 40\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 40\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "4877": {
        "category": "Arithmetic calculation",
        "question_ko": "지민이네 반 학생 중에서 국어를 좋아하는 학생은 38명이고, 수학을 좋아하는 학생은 39명이고, 국어와 수학을 모두 좋아하는 학생은 32명입니다. 국어와 수학을 모두 좋아하지 않는 학생이 한 명도 없을 때, 지민이네 반 학생은 모두 몇 명입니까?",
        "question_en": "Among the students in Jimin's class, 38 students like Korean, 39 students like math, and 32 students like both Korean and math. If there is no student who does not like both Korean and math, how many students are in Jimin's class?",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "38 39 [OP_ADD] 32 [OP_SUB]",
        "solution_abst_en": "38 39 [OP_ADD] 32 [OP_SUB]",
        "solution_code_ko": "var_a = 38\nvar_b = 39\nvar_c = var_a + var_b\nvar_d = 32\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 38\nvar_b = 39\nvar_c = var_a + var_b\nvar_d = 32\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "4878": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 4로 나누고 25를 더한 뒤 3을 곱하였더니 150이 되었습니다. 어떤 수를 구하시오.",
        "question_en": "Dividing a certain number by 4, adding 25, and multiplying by 3, results in 150. Find the certain number.",
        "answer_ko": "100",
        "answer_en": "100",
        "solution_abst_ko": "150 3 [OP_DIV] 25 [OP_SUB] 4 [OP_MUL]",
        "solution_abst_en": "150 3 [OP_DIV] 25 [OP_SUB] 4 [OP_MUL]",
        "solution_code_ko": "var_a = 150\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 25\nvar_e = var_c - var_d\nvar_f = 4\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 150\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 25\nvar_e = var_c - var_d\nvar_f = 4\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "4879": {
        "category": "Comparison",
        "question_ko": "20명의 학생들이 한줄로 섰습니다. 정국이는 1등으로 줄을 섰고, 윤기와 정국이 사이에는 5명의 학생이 있습니다. 윤기 뒤에 서 있는 학생은 몇 명입니까?",
        "question_en": "20 students stood in a line. Jungkook is in line for first place, and there are 5 students between Yoongi and Jungkook. How many students are standing behind Yoongi?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "20 1 [OP_SUB] 5 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "20 1 [OP_SUB] 5 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 20\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "4880": {
        "category": "Geometry",
        "question_ko": "영진이는 가지고 있는 10원짜리 동전 전부를 빈틈없이 규칙적으로 늘어놓아 정사각형을 만들었습니다. 둘레에 놓인 동전의 개수가 96개였다면, 영진이가 가지고 있는 돈은 모두 얼마입니까?",
        "question_en": "Young-jin arranged all the 10-won coins in his possession in a regular manner to form a square. If the number of coins placed around is 96, how much money does Young-jin have?",
        "answer_ko": "6250",
        "answer_en": "6250",
        "solution_abst_ko": "96 4 [OP_ADD] 4 [OP_DIV] 2 [OP_POW] 10 [OP_MUL]",
        "solution_abst_en": "96 4 [OP_ADD] 4 [OP_DIV] 2 [OP_POW] 10 [OP_MUL]",
        "solution_code_ko": "var_a = 96\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e ** var_f\nvar_h = 10\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 96\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e ** var_f\nvar_h = 10\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "4881": {
        "category": "Correspondence",
        "question_ko": "A는 한 자리 수입니다. 백의 자리에서 A27을 버림하면 200이 됩니다. A는 무엇입니까?",
        "question_en": "A is a single-digit number. Rounding down A27 from the hundreds place results in 200. What is A?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "A27 [OP_GEN_POSSIBLE_LIST] 200 [OP_LIST_MORE_EQUAL] 200 100 [OP_ADD] [OP_LIST_LESS] A [OP_LIST_FIND_UNK]",
        "solution_abst_en": "A27 [OP_GEN_POSSIBLE_LIST] 200 [OP_LIST_MORE_EQUAL] 200 100 [OP_ADD] [OP_LIST_LESS] A [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = 'A27'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 200\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 200\nvar_d = 100\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = 'A'\nvar_a = str(var_a)\nvar_f = str(var_f)\nunk_idx = var_a.index(var_f)\nvar_g = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_g = int(elem[unk_idx])\nprint(int(var_g))",
        "solution_code_en": "var_a = 'A27'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 200\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 200\nvar_d = 100\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = 'A'\nvar_a = str(var_a)\nvar_f = str(var_f)\nunk_idx = var_a.index(var_f)\nvar_g = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_g = int(elem[unk_idx])\nprint(int(var_g))"
    },
    "4882": {
        "category": "Arithmetic calculation",
        "question_ko": "사과 24개와 귤 36개를 최대한 많은 학생에게 똑같이 나눠줄 때, 몇 명의 학생에게 나누어 줄 수 있는지 구하시오.",
        "question_en": "If you hand out 24 apples and 36 tangerines equally to many students as possible, how many students can you give?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "24 [OP_LIST_GET_DIVISOR] 36 [OP_LIST_GET_DIVISOR] [OP_SET_INTERSECT] 1 [OP_LIST_MAX]",
        "solution_abst_en": "24 [OP_LIST_GET_DIVISOR] 36 [OP_LIST_GET_DIVISOR] [OP_SET_INTERSECT] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 24\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 36\nlist_b = []\nnum_sqrt = int(math.sqrt(var_b))\nfor i in range(1, num_sqrt+1):\n    if var_b % i == 0:\n        list_b.append(i)\n        list_b.append(int(var_b/i))\nlist_b = sorted(set(list_b))\nlist_c = list(set(list_a) & set(list_b))\nvar_c = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_d = list_d[-var_c]\nprint(int(var_d))",
        "solution_code_en": "var_a = 24\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 36\nlist_b = []\nnum_sqrt = int(math.sqrt(var_b))\nfor i in range(1, num_sqrt+1):\n    if var_b % i == 0:\n        list_b.append(i)\n        list_b.append(int(var_b/i))\nlist_b = sorted(set(list_b))\nlist_c = list(set(list_a) & set(list_b))\nvar_c = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_d = list_d[-var_c]\nprint(int(var_d))"
    },
    "4883": {
        "category": "Geometry",
        "question_ko": "반지름이 4센티미터(㎝)인 반원을 지름을 기준으로 하여 한 번 돌려 얻는 입체도형의 지름은 몇 센티미터(㎝)입니까?",
        "question_en": "What is the diameter in centimeters (cm) of a solid figure obtained by rotating a semicircle with a radius of 4 centimeters (cm) once around its diameter?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "4 2 [OP_MUL]",
        "solution_abst_en": "4 2 [OP_MUL]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "4884": {
        "category": "Comparison",
        "question_ko": "은지는 왼쪽에서 8번째 열, 오른쪽에서 14번째 열, 앞에서 7번째 줄, 뒤에서 15번째 줄에 서서 체조를 하고 있습니다. 각 줄마다 서 있는 학생의 수가 같다고 할 때, 체조를 하고 있는 학생은 모두 몇 명입니까?",
        "question_en": "Eunji is standing in the 8th column from the left, the 14th column from the right, the 7th row from the front, and the 15th row from the back and doing gymnastics. If the number of students standing in each row is the same, how many students are doing gymnastics?",
        "answer_ko": "441",
        "answer_en": "441",
        "solution_abst_ko": "8 14 [OP_ADD] 1 [OP_SUB] 7 15 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "8 14 [OP_ADD] 1 [OP_SUB] 7 15 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 14\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 7\nvar_g = 15\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 8\nvar_b = 14\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 7\nvar_g = 15\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))"
    },
    "4885": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 10, 11, 12, 13이 있습니다. 그 중에서 가장 작은 수와 2번째로 작은 수의 곱은 얼마입니까?",
        "question_en": "There are four numbers 10, 11, 12, and 13. What do you get if you multiply the smallest number by the second smallest number?",
        "answer_ko": "110",
        "answer_en": "110",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f * var_h\nprint(int(var_i))"
    },
    "4886": {
        "category": "Comparison",
        "question_ko": "태형, 민주, 상민, 윤정, 유정이 차례로 결승선을 통과하였다. 누가 가장 먼저 들어왔나?",
        "question_en": "Given that Taehyung, Minju, Sangmin, Yoonjung, and Yoojung crossed the end line of the race, who got in first?",
        "answer_ko": "태형",
        "answer_en": "Taehyung",
        "solution_abst_ko": "[OP_LIST_SOL] 태형 민주 상민 윤정 유정 [OP_LIST_EOL] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Taehyung Minju Sangmin Yoonjung Yoojung [OP_LIST_EOL] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '태형'\nvar_b = '민주'\nvar_c = '상민'\nvar_d = '윤정'\nvar_e = '유정'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nvar_g = list_a[var_f-1]\nprint(var_g)",
        "solution_code_en": "var_a = 'Taehyung'\nvar_b = 'Minju'\nvar_c = 'Sangmin'\nvar_d = 'Yoonjung'\nvar_e = 'Yoojung'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nvar_g = list_a[var_f-1]\nprint(var_g)"
    },
    "4887": {
        "category": "Correspondence",
        "question_ko": "14를 3로 나눴더니 몫이 A가 되었고, 나머지는 2가 되었습니다. 이 때 A를 구하시오.",
        "question_en": "When 14 is divided by 3, the quotient is A and the remainder is 2. Find A.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "14 2 [OP_SUB] 3 [OP_DIV]",
        "solution_abst_en": "14 2 [OP_SUB] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 14\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 14\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "4888": {
        "category": "Geometry",
        "question_ko": "길이가 12센티미터(㎝)인 선분 AB에 대하여 점 M은 선분 AB의 중점이고, 점 N은 선분 AM의 중점일 때, 선분 NM의 길이를 구하시오.",
        "question_en": "For line segment AB with a length of 12 centimeters (cm), if point M is the midpoint of line segment AB and point N is the midpoint of line segment AM, find the length of segment NM.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "12 2 [OP_DIV] 2 [OP_DIV]",
        "solution_abst_en": "12 2 [OP_DIV] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "4889": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 36을 더했더니 71이 되었습니다. 어떤 수에 10을 더하면 얼마가 되는지 구하시오.",
        "question_en": "I added 36 to a number and it resulted in 71. Find the result of adding 10 to the number.",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "71 36 [OP_SUB] 10 [OP_ADD]",
        "solution_abst_en": "71 36 [OP_SUB] 10 [OP_ADD]",
        "solution_code_ko": "var_a = 71\nvar_b = 36\nvar_c = var_a - var_b\nvar_d = 10\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 71\nvar_b = 36\nvar_c = var_a - var_b\nvar_d = 10\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "4890": {
        "category": "Geometry",
        "question_ko": "어떤 다각형은 한 꼭짓점에서 1개의 대각선을 그을 수 있다고 합니다. 이 다각형의 변의 개수를 구하시오.",
        "question_en": "It is said that a polygon can draw one diagonal from one vertex. Find the number of sides of this polygon.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "1 3 [OP_ADD]",
        "solution_abst_en": "1 3 [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "4891": {
        "category": "Geometry",
        "question_ko": "가로가 5/6미터(m), 세로가 4/6미터(m)인 직사각형이 있습니다. 이 직사각형의 가로는 세로보다 몇 미터(m)더 깁니까?",
        "question_en": "A rectangle is 5/6 meters (m) wide and 4/6 meters (m) long. How many meters (m) longer is the width of this rectangle than its length?",
        "answer_ko": "0.17",
        "answer_en": "0.17",
        "solution_abst_ko": "5/6 4/6 [OP_SUB]",
        "solution_abst_en": "5/6 4/6 [OP_SUB]",
        "solution_code_ko": "var_a = 0.8333333333333334\nvar_b = 0.6666666666666666\nvar_c = var_a - var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 0.8333333333333334\nvar_b = 0.6666666666666666\nvar_c = var_a - var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "4892": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 박물관에 500개의 그림이 있습니다. 모든 그림에는 1부터 500까지의 번호가 차례로 적혀있을 때, 숫자 4는 모두 몇 번 적혀 있는지 구하시오.",
        "question_en": "The museum has 500 paintings. If all pictures are numbered from 1 to 500 in order, find how many times the number 4 is written in each picture.",
        "answer_ko": "200",
        "answer_en": "200",
        "solution_abst_ko": "1 500 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 4 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 500 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 4 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 500\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 4\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 500\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 4\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))"
    },
    "4893": {
        "category": "Arithmetic calculation",
        "question_ko": "기차의 첫번째 정차역에서 58명이 내리고 다음 역에서 37명이 탔습니다. 처음 기차에 있던 사람이 123명 일 때, 현재 남아 있는 사람을 몇 명입니까?",
        "question_en": "58 people got off at the train's first stop and 37 got on at the next station. If there were 123 people on the train at first, how many people are still left?",
        "answer_ko": "102",
        "answer_en": "102",
        "solution_abst_ko": "123 58 [OP_SUB] 37 [OP_ADD]",
        "solution_abst_en": "123 58 [OP_SUB] 37 [OP_ADD]",
        "solution_code_ko": "var_a = 123\nvar_b = 58\nvar_c = var_a - var_b\nvar_d = 37\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 123\nvar_b = 58\nvar_c = var_a - var_b\nvar_d = 37\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "4894": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 5미터(m), 무게가 29/8킬로그램(㎏)의 가방과 길이가 4미터(m), 무게가 2.8킬로그램(㎏)인 의자가 있다. 가방과 의자를 2미터(m)씩 잘라 함께 무게를 재면 몇 킬로그램(㎏)입니까?",
        "question_en": "There is a bag that is 5 meters (m) long and weighs 29/8 kilograms (kg) and a chair that is 4 meters (m) long and weighs 2.8 kilograms (kg). How many kilograms (kg) are the bag and chair if they are cut into 2 meters (m) and weighed together?",
        "answer_ko": "2.85",
        "answer_en": "2.85",
        "solution_abst_ko": "29/8 5 [OP_DIV] 2 [OP_MUL] 2.8 4 [OP_DIV] 2 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "29/8 5 [OP_DIV] 2 [OP_MUL] 2.8 4 [OP_DIV] 2 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 3.625\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 2.8\nvar_g = 4\nvar_h = var_f / var_g\nvar_i = 2\nvar_j = var_h * var_i\nvar_k = var_e + var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 3.625\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 2.8\nvar_g = 4\nvar_h = var_f / var_g\nvar_i = 2\nvar_j = var_h * var_i\nvar_k = var_e + var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "4895": {
        "category": "Arithmetic calculation",
        "question_ko": "7년 전에 아버지 나이는 아들 나이의 3배였습니다. 올해부터 8년 후에 아버지와 아들의 나이 합은 74살이 됩니다. 8년 후의 아버지 나이는 몇 살입니까?",
        "question_en": "Seven years ago, the father's age was three times the son's age. Eight years from this year, the sum of the ages of father and son will be 74. How old is the father after 8 years from now?",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "74 8 2 [OP_MUL] [OP_SUB] 7 2 [OP_MUL] [OP_SUB] 3 1 [OP_ADD] [OP_FDIV] 3 [OP_MUL] 7 [OP_ADD] 8 [OP_ADD]",
        "solution_abst_en": "74 8 2 [OP_MUL] [OP_SUB] 7 2 [OP_MUL] [OP_SUB] 3 1 [OP_ADD] [OP_FDIV] 3 [OP_MUL] 7 [OP_ADD] 8 [OP_ADD]",
        "solution_code_ko": "var_a = 74\nvar_b = 8\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 7\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nvar_j = 3\nvar_k = 1\nvar_l = var_j + var_k\nvar_m = var_i // var_l\nvar_n = 3\nvar_o = var_m * var_n\nvar_p = 7\nvar_q = var_o + var_p\nvar_r = 8\nvar_s = var_q + var_r\nprint(int(var_s))",
        "solution_code_en": "var_a = 74\nvar_b = 8\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 7\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nvar_j = 3\nvar_k = 1\nvar_l = var_j + var_k\nvar_m = var_i // var_l\nvar_n = 3\nvar_o = var_m * var_n\nvar_p = 7\nvar_q = var_o + var_p\nvar_r = 8\nvar_s = var_q + var_r\nprint(int(var_s))"
    },
    "4896": {
        "category": "Arithmetic calculation",
        "question_ko": "석진이의 국어 점수는 93점이고, 영어 점수는 91점입니다. 국어, 영어, 수학 세 과목의 평균 점수가 89점일 때, 수학 점수는 몇 점입니까?",
        "question_en": "Seokjin's Korean score is 93 points, and his English score is 91 points. If the average score of Korean, English, and Math is 89, what is his math score?",
        "answer_ko": "83",
        "answer_en": "83",
        "solution_abst_ko": "89 3 [OP_MUL] 93 [OP_SUB] 91 [OP_SUB]",
        "solution_abst_en": "89 3 [OP_MUL] 93 [OP_SUB] 91 [OP_SUB]",
        "solution_code_ko": "var_a = 89\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 93\nvar_e = var_c - var_d\nvar_f = 91\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 89\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 93\nvar_e = var_c - var_d\nvar_f = 91\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "4897": {
        "category": "Arithmetic calculation",
        "question_ko": "98개의 귤을 12명에게 똑같이 나누어 주려고 하였더니 몇 개가 모자랐습니다. 귤을 남김없이 똑같이 나누어 주기 위해 귤을 몇 개 더 사려고 합니다. 귤 한 개 가격이 450원 일 때, 최소 얼마가 더 필요합니까?",
        "question_en": "I tried to hand out 98 tangerines equally to 12 people, but a few tangerines were short. I want to buy a few more tangerines so that I can hand them out equally. If the price of one tangerine is 450 won, at least how much more do I need?",
        "answer_ko": "4500",
        "answer_en": "4500",
        "solution_abst_ko": "12 98 12 [OP_MOD] [OP_SUB] 450 [OP_MUL]",
        "solution_abst_en": "12 98 12 [OP_MOD] [OP_SUB] 450 [OP_MUL]",
        "solution_code_ko": "var_a = 12\nvar_b = 98\nvar_c = 12\nvar_d = var_b % var_c\nvar_e = var_a - var_d\nvar_f = 450\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 12\nvar_b = 98\nvar_c = 12\nvar_d = var_b % var_c\nvar_e = var_a - var_d\nvar_f = 450\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "4898": {
        "category": "Geometry",
        "question_ko": "빗변의 길이가 13, 빗변이 아닌 한 변의 길이가 12인 직각삼각형 모양의 종이가 있습니다. 나머지 한 변의 길이는 얼마입니까?",
        "question_en": "A piece of paper is in the shape of a right triangle with a hypotenuse length of 13 and the non-hypotenuse side length of 12. What is the length of the other side?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "13 2 [OP_POW] 12 2 [OP_POW] [OP_SUB] 1/2 [OP_POW]",
        "solution_abst_en": "13 2 [OP_POW] 12 2 [OP_POW] [OP_SUB] 1/2 [OP_POW]",
        "solution_code_ko": "var_a = 13\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 12\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c - var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 13\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 12\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c - var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))"
    },
    "4899": {
        "category": "Geometry",
        "question_ko": "직육면체의 가로가 12센티미터(㎝), 세로가 16센티미터(㎝), 높이가 14센티미터(㎝) 일 때, 이 직육면체를 잘라서 만들 수 있는 가장 큰 정육면체의 겉넓이의 값을 구하시오.",
        "question_en": "If the width of a cube is 12 centimeters (cm), the length is 16 centimeters (cm), and the height is 14 centimeters (cm), find the value of the surface area of the largest cube that can be made by cutting the cube.",
        "answer_ko": "864",
        "answer_en": "864",
        "solution_abst_ko": "[OP_LIST_SOL] 12 16 14 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_POW] 6 [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 12 16 14 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_POW] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 12\nvar_b = 16\nvar_c = 14\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nvar_f = 2\nvar_g = var_e ** var_f\nvar_h = 6\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 12\nvar_b = 16\nvar_c = 14\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nvar_f = 2\nvar_g = var_e ** var_f\nvar_h = 6\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "4900": {
        "category": "Arithmetic calculation",
        "question_ko": "꽃병이 5개 있습니다. 꽃병 5개에는 각각 4송이의 꽃이 있고, 꽃병 6개에는 1개의 꽃이 있습니다. 꽃병에 있는 꽃은 모두 몇 송이입니까?",
        "question_en": "There are 5 vases. Each of the 5 vases has 4 flowers, and the 6 vases have 1 flower. How many flowers are there in the vase?",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "4 5 [OP_MUL] 1 6 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "4 5 [OP_MUL] 1 6 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 6\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 6\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "4901": {
        "category": "Arithmetic calculation",
        "question_ko": "15 명 초과 30 명 이하의 사람이 타야 출발하는 버스가 있습니다. 지금 버스에 타고 있는 사람이 9 명이라면 적어도 몇 명이 더 타야 출발할 수 있는지 구하시오.",
        "question_en": "There are buses that depart only when there are more than 15 and no more than 30 people. If there are 9 people on the bus right now, find out how many more people need to get on the bus before it starts.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "15 1 [OP_ADD] 9 [OP_SUB]",
        "solution_abst_en": "15 1 [OP_ADD] 9 [OP_SUB]",
        "solution_code_ko": "var_a = 15\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "4902": {
        "category": "Correspondence",
        "question_ko": "철수의 몸무게는 어머니의 몸무게의 2/3이고, 아버지의 몸무게는 72킬로그램(㎏)입니다. 철수와 아버지의 몸무게의 합이 어머니의 몸무게의 2배와 같을 때, 철수의 몸무게는 몇 킬로그램(㎏)인지 구하시오.",
        "question_en": "Cheolsu's weight is 2/3 of his mother's weight, and his father's weight is 72 kilograms (kg). If the sum of Cheolsu's and his father's weight is equal to twice the mother's weight, find how many kilograms (kg) Cheolsu weighs.",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "72 2 1 2/3 [OP_DIV] [OP_MUL] 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "72 2 1 2/3 [OP_DIV] [OP_MUL] 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 72\nvar_b = 2\nvar_c = 1\nvar_d = 0.6666666666666666\nvar_e = var_c / var_d\nvar_f = var_b * var_e\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_a / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 72\nvar_b = 2\nvar_c = 1\nvar_d = 0.6666666666666666\nvar_e = var_c / var_d\nvar_f = var_b * var_e\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_a / var_h\nprint(int(var_i))"
    },
    "4903": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 0.42 를 빼야 할 것을 잘못하여 더했더니 0.9 이 되었습니다. 바르게 계산하면 얼마가 되겠습니까?",
        "question_en": "I mistakenly added 0.42 which should have subtracted from a number, and I ended up with 0.9. How much would it be if I counted correctly?",
        "answer_ko": "0.06",
        "answer_en": "0.06",
        "solution_abst_ko": "0.9 0.42 [OP_SUB] 0.42 [OP_SUB]",
        "solution_abst_en": "0.9 0.42 [OP_SUB] 0.42 [OP_SUB]",
        "solution_code_ko": "var_a = 0.9\nvar_b = 0.42\nvar_c = var_a - var_b\nvar_d = 0.42\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.9\nvar_b = 0.42\nvar_c = var_a - var_b\nvar_d = 0.42\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "4904": {
        "category": "Correspondence",
        "question_ko": "식 14A+2B3=418이 있습니다. B에 들어가야 하는 숫자를 구하시오",
        "question_en": "We have the expression 14A+2B3=418. Find the number that goes into B.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "14A+2B3=418 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "14A+2B3=418 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '14A+2B3=418'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '14A+2B3=418'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "4905": {
        "category": "Possibility",
        "question_ko": "19를 네 개의 다른 자연수의 합으로 표현할 수 있는 방법은 몇 가지입니까?",
        "question_en": "How many ways can 19 be expressed as the sum of four different natural numbers?",
        "answer_ko": "264",
        "answer_en": "264",
        "solution_abst_ko": "1 9 1 [OP_LIST_ARANGE] 4 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 19 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 9 1 [OP_LIST_ARANGE] 4 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 19 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 19\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 19\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))"
    },
    "4906": {
        "category": "Arithmetic calculation",
        "question_ko": "올해 어머니 나이는 아들 나이의 4배입니다. 3년 전에 어머니와 아들의 나이의 합은 49살이었습니다. 올해 아들의 나이는 몇 살입니까?",
        "question_en": "This year, the age of the mother is four times the age of the son. Three years ago, the combined ages of mother and son were 49. How old is her son this year?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "49 3 2 [OP_MUL] [OP_ADD] 1 4 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "49 3 2 [OP_MUL] [OP_ADD] 1 4 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 49\nvar_b = 3\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nvar_f = 1\nvar_g = 4\nvar_h = var_f + var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 49\nvar_b = 3\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nvar_f = 1\nvar_g = 4\nvar_h = var_f + var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "4907": {
        "category": "Geometry",
        "question_ko": "어떤 정육면체를 잘라서 한 모서리의 길이가 4센티미터(㎝)인 정육면체 27개를 만들었다. 자르기 전의 정육면체의 겉넓이는 몇 제곱센티미터(㎠)인지 구하시오.",
        "question_en": "A cube was cut to make 27 cubes with each edge being 4 centimeters (cm) long. Find the surface area of the original cube in square centimeters (cm2).",
        "answer_ko": "864",
        "answer_en": "864",
        "solution_abst_ko": "4 27 1 3 [OP_DIV] [OP_POW] [OP_MUL] 2 [OP_POW] 6 [OP_MUL]",
        "solution_abst_en": "4 27 1 3 [OP_DIV] [OP_POW] [OP_MUL] 2 [OP_POW] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 4\nvar_b = 27\nvar_c = 1\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = var_b ** var_e\nvar_g = var_a * var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 6\nvar_k = var_i * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 4\nvar_b = 27\nvar_c = 1\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = var_b ** var_e\nvar_g = var_a * var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 6\nvar_k = var_i * var_j\nprint(int(var_k))"
    },
    "4908": {
        "category": "Possibility",
        "question_ko": "5, 9, 2 중에서 한 번씩만 사용하여 세 자리 수를 만들려고 합니다. 만든 두 수의 차가 가장 크게 될 때, 두 수 중 작은 수는 무엇입니까?",
        "question_en": "There is a three-digit number made of 5, 9, and 2. When the difference between the two possible numbers is the greatest, which of the two numbers is smaller?",
        "answer_ko": "259",
        "answer_en": "259",
        "solution_abst_ko": "[OP_LIST_SOL] 5 9 2 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 5 9 2 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 5\nvar_b = 9\nvar_c = 2\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nprint(int(var_f))",
        "solution_code_en": "var_a = 5\nvar_b = 9\nvar_c = 2\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nprint(int(var_f))"
    },
    "4909": {
        "category": "Comparison",
        "question_ko": "주리는 정우보다 큽니다. 명현이는 석진이보다 큽니다. 주리는 정국이보다 작습니다. 명현이는 정우보다 작습니다. 키가 가장 큰 사람은 누구입니까?",
        "question_en": "Juri is taller than Jungwoo. Myunghyun is taller than Seokjin. Juri is shorter than Jungkook. Myunghyun is shorter than Jungwoo. Who is the tallest person?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 주리 정우 명현 석진 정국 [OP_LIST_EOL] [OP_LIST_SOL] 주리 정우 > 명현 석진 > 주리 정국 < 명현 정우 < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Juri Jungwoo Myunghyun Seokjin Jungkook [OP_LIST_EOL] [OP_LIST_SOL] Juri Jungwoo > Myunghyun Seokjin > Juri Jungkook < Myunghyun Jungwoo < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '주리'\nvar_b = '정우'\nvar_c = '명현'\nvar_d = '석진'\nvar_e = '정국'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = '주리'\nvar_g = '정우'\nvar_h = '>'\nvar_i = '명현'\nvar_j = '석진'\nvar_k = '>'\nvar_l = '주리'\nvar_m = '정국'\nvar_n = '<'\nvar_o = '명현'\nvar_p = '정우'\nvar_q = '<'\nlist_b= []\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_r = 1\nvar_s = list_c[var_r-1]\nprint(var_s)",
        "solution_code_en": "var_a = 'Juri'\nvar_b = 'Jungwoo'\nvar_c = 'Myunghyun'\nvar_d = 'Seokjin'\nvar_e = 'Jungkook'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 'Juri'\nvar_g = 'Jungwoo'\nvar_h = '>'\nvar_i = 'Myunghyun'\nvar_j = 'Seokjin'\nvar_k = '>'\nvar_l = 'Juri'\nvar_m = 'Jungkook'\nvar_n = '<'\nvar_o = 'Myunghyun'\nvar_p = 'Jungwoo'\nvar_q = '<'\nlist_b= []\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_r = 1\nvar_s = list_c[var_r-1]\nprint(var_s)"
    },
    "4910": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 12를 뺀 후 9를 곱해야 할 것을 잘못하여 어떤 수에 12를 더한 후 8로 나누었더니 8이 되었습니다. 바르게 계산한 값을 구하시오.",
        "question_en": "You were supposed to subtract 12 from a certain number and multiply by 9, but accidentally add 12 and divide by 8. Find the correctly calculated value.",
        "answer_ko": "360",
        "answer_en": "360",
        "solution_abst_ko": "8 8 [OP_MUL] 12 [OP_SUB] 12 [OP_SUB] 9 [OP_MUL]",
        "solution_abst_en": "8 8 [OP_MUL] 12 [OP_SUB] 12 [OP_SUB] 9 [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = var_c - var_d\nvar_f = 12\nvar_g = var_e - var_f\nvar_h = 9\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 8\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = var_c - var_d\nvar_f = 12\nvar_g = var_e - var_f\nvar_h = 9\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "4911": {
        "category": "Correspondence",
        "question_ko": "어느 공대에 모든 학생의 수는 928명이고 남학생의 수는 713명이다. 남학생이 여학생보다 몇 명이 더 믾은지 구하시오.",
        "question_en": "An engineering school has 928 students and 713 of those are male students. Find how many male students outnumber female students.",
        "answer_ko": "498",
        "answer_en": "498",
        "solution_abst_ko": "713 928 713 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "713 928 713 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 713\nvar_b = 928\nvar_c = 713\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 713\nvar_b = 928\nvar_c = 713\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "4912": {
        "category": "Correspondence",
        "question_ko": "A, B는 서로 다른 0에서 9까지의 수입니다. 곱셈식 AB×6=BBB가 참일 때 A와 B의 합은 무엇입니까?",
        "question_en": "A and B are different numbers ranging from 0 to 9. What is the sum of A and B when the multiplication expression AB×6=BBB is true?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "AB×6=BBB A [OP_DIGIT_UNK_SOLVER] AB×6=BBB B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_abst_en": "AB×6=BBB A [OP_DIGIT_UNK_SOLVER] AB×6=BBB B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_code_ko": "var_a = 'AB×6=BBB'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 'AB×6=BBB'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 'AB×6=BBB'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 'AB×6=BBB'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "4913": {
        "category": "Arithmetic calculation",
        "question_ko": "3.3, 7/2, 1.9, 14/5, 2.1에서 어떤 수들이 2보다 크고 3보다 작은지 확인하고, 개수를 세시오.",
        "question_en": "Identify which numbers are greater than 2 and less than 3 among 3.3, 7/2, 1.9, 14/5, and 2.1, and count how many of them are.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 3.3 7/2 1.9 14/5 2.1 [OP_LIST_EOL] 2 [OP_LIST_MORE] 3 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 3.3 7/2 1.9 14/5 2.1 [OP_LIST_EOL] 2 [OP_LIST_MORE] 3 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 3.3\nvar_b = 3.5\nvar_c = 1.9\nvar_d = 2.8\nvar_e = 2.1\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = 3\nlist_c = []\nfor i in list_b:\n    if i < var_g:\n        list_c.append(i)\nvar_h = len(list_c)\nprint(int(var_h))",
        "solution_code_en": "var_a = 3.3\nvar_b = 3.5\nvar_c = 1.9\nvar_d = 2.8\nvar_e = 2.1\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = 3\nlist_c = []\nfor i in list_b:\n    if i < var_g:\n        list_c.append(i)\nvar_h = len(list_c)\nprint(int(var_h))"
    },
    "4914": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 4.372를 빼야 할 것을 잘못하여 43.72를 빼었더니 16.398이 되었습니다. 바르게 계산하면 얼마가 되겠습니까?",
        "question_en": "Made the mistake of subtracting 43.72 from a certain number, when I should subtract 4.372, and I got 16.398. How much would it be if I calculated it correctly?",
        "answer_ko": "55.75",
        "answer_en": "55.75",
        "solution_abst_ko": "16.398 43.72 [OP_ADD] 4.372 [OP_SUB]",
        "solution_abst_en": "16.398 43.72 [OP_ADD] 4.372 [OP_SUB]",
        "solution_code_ko": "var_a = 16.398\nvar_b = 43.72\nvar_c = var_a + var_b\nvar_d = 4.372\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 16.398\nvar_b = 43.72\nvar_c = var_a + var_b\nvar_d = 4.372\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "4915": {
        "category": "Geometry",
        "question_ko": "트럭은 서울에서 인천으로 가면서 배추를 나르고 인천에서 서울로 가면서 무를 나른다. 한번 옮길 때 배추가 4킬로그램(㎏) 436그램(g), 무가 1999그램(g) 실려있다. 트럭이 인천과 서울을 2번 왕복하면 트럭이 옮긴 채소는 총 몇 킬로그램(㎏)인가?",
        "question_en": "The truck carries cabbages from Seoul to Incheon and radishes from Incheon to Seoul. When transported once, 4 kilograms (kg) and 436 grams (g) of cabbage and 1999 grams (g) of radish are loaded. If the truck goes back and forth between Incheon and Seoul twice, what is the total amount of both vegetables the truck carries in kilograms (kg)?",
        "answer_ko": "12.87",
        "answer_en": "12.87",
        "solution_abst_ko": "4 436 1000 [OP_DIV] [OP_ADD] 1999 1000 [OP_DIV] [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "4 436 1000 [OP_DIV] [OP_ADD] 1999 1000 [OP_DIV] [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 4\nvar_b = 436\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 1999\nvar_g = 1000\nvar_h = var_f / var_g\nvar_i = var_e + var_h\nvar_j = 2\nvar_k = var_i * var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 4\nvar_b = 436\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 1999\nvar_g = 1000\nvar_h = var_f / var_g\nvar_i = var_e + var_h\nvar_j = 2\nvar_k = var_i * var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "4916": {
        "category": "Geometry",
        "question_ko": "넓이가 46제곱센티미터(㎠)인 삼각형의 밑변이 10센티미터(㎝)이면, 높이는 몇 센티미터(㎝)입니까?",
        "question_en": "If the base of a triangle with an area of 46 square centimeters (cm2) is 10 centimeters (cm), how many centimeters (cm) is its height?",
        "answer_ko": "9.20",
        "answer_en": "9.2",
        "solution_abst_ko": "46 2 [OP_MUL] 10 [OP_DIV]",
        "solution_abst_en": "46 2 [OP_MUL] 10 [OP_DIV]",
        "solution_code_ko": "var_a = 46\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 10\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 46\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 10\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "4917": {
        "category": "Arithmetic calculation",
        "question_ko": "긴 막대의 길이가 14/15미터(m)이고, 짧은 막대의 길이는 긴 막대의 길이보다 1/10미터(m) 더 짧습니다. 이때 두 막대의 길이의 합은 몇 미터(m)인지 구하시오.",
        "question_en": "The length of the long rod is 14/15 meters (m), and the length of the short rod is 1/10 meter (m) shorter than the length of the long rod. Find the sum of the lengths of the two rods in meters (m).",
        "answer_ko": "1.77",
        "answer_en": "1.77",
        "solution_abst_ko": "14/15 2 [OP_MUL] 1/10 [OP_SUB]",
        "solution_abst_en": "14/15 2 [OP_MUL] 1/10 [OP_SUB]",
        "solution_code_ko": "var_a = 0.9333333333333333\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 0.1\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.9333333333333333\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 0.1\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "4918": {
        "category": "Possibility",
        "question_ko": "정희, 철수, 은수, 민준 4명이 야구장에 갔다. 이때, 은수와 민준은 사이가 좋지 않아 이웃하여 앉지 않는다고 할 때, 네 명이 한 줄로 앉는 경우의 수를 구하시오. (단, 좌석은 네 좌석이며 모두 붙어있다.)",
        "question_en": "Jeonghee, Cheolsu, Eunsu, and Minjun went to the baseball field. If Eunsu and Minjun do not sit next to each other because they are not on good terms, find the number of cases in which four people sit in a row. (However, there are four seats and all are attached.)",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "[OP_LIST_SOL] 정희 철수 은수 민준 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] 은수 [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] 은수 민준 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] Jeonghee Cheolsu Eunsu Minjun [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] Eunsu [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] Eunsu Minjun [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = '정희'\nvar_b = '철수'\nvar_c = '은수'\nvar_d = '민준'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = len(list_a)\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nvar_h = '은수'\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_i = len(list_c)\nvar_j = len(list_c)\nvar_k = 1\nvar_i = int(var_i)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_i-i)\nvar_l = '은수'\nvar_m = '민준'\nlist_d= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_d.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_d.append(var_l)\nlist_d.reverse()\nvar_n = len(list_d)\nvar_o = len(list_d)\nvar_p = 1\nvar_n = int(var_n)\nvar_o = int(var_o)\nfor i, elem in enumerate(range(var_o)):\n    var_p = var_p * (var_n-i)\nvar_q = var_k * var_p\nvar_r = var_g - var_q\nprint(int(var_r))",
        "solution_code_en": "var_a = 'Jeonghee'\nvar_b = 'Cheolsu'\nvar_c = 'Eunsu'\nvar_d = 'Minjun'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = len(list_a)\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nvar_h = 'Eunsu'\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_i = len(list_c)\nvar_j = len(list_c)\nvar_k = 1\nvar_i = int(var_i)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_i-i)\nvar_l = 'Eunsu'\nvar_m = 'Minjun'\nlist_d= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_d.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_d.append(var_l)\nlist_d.reverse()\nvar_n = len(list_d)\nvar_o = len(list_d)\nvar_p = 1\nvar_n = int(var_n)\nvar_o = int(var_o)\nfor i, elem in enumerate(range(var_o)):\n    var_p = var_p * (var_n-i)\nvar_q = var_k * var_p\nvar_r = var_g - var_q\nprint(int(var_r))"
    },
    "4919": {
        "category": "Geometry",
        "question_ko": "모서리의 길이가 1미터(m)인 정육면체를 잘라서 64개의 작은 정육면체를 만들었다. 작은 정육면체들의 겉넓이의 합을 구하면 몇 제곱미터(m2)인가?",
        "question_en": "A cube with a side length of 1 metre was cut into 64 cubes of equal size. What is the total surface area, in square centimetres (m²), of the smaller cubes?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "1 4 [OP_DIV] 1 4 [OP_DIV] [OP_MUL] 6 [OP_MUL] 64 [OP_MUL]",
        "solution_abst_en": "1 4 [OP_DIV] 1 4 [OP_DIV] [OP_MUL] 6 [OP_MUL] 64 [OP_MUL]",
        "solution_code_ko": "var_a = 1\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = var_c * var_f\nvar_h = 6\nvar_i = var_g * var_h\nvar_j = 64\nvar_k = var_i * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 1\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = var_c * var_f\nvar_h = 6\nvar_i = var_g * var_h\nvar_j = 64\nvar_k = var_i * var_j\nprint(int(var_k))"
    },
    "4920": {
        "category": "Possibility",
        "question_ko": "옷장에 옷이 바지와 치마가 있다. 바지는 4벌이 있으며, 바지 또는 치마를 입는 경우가 7가지이다. 이 때, 치마는 몇 벌이 있는가?",
        "question_en": "There are pants and skirts in the closet. There are 4 pants, and 7 possible ways to wear pants or skirts. At this time, how many skirts are there?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "7 4 [OP_SUB]",
        "solution_abst_en": "7 4 [OP_SUB]",
        "solution_code_ko": "var_a = 7\nvar_b = 4\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 7\nvar_b = 4\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "4921": {
        "category": "Arithmetic calculation",
        "question_ko": "훈정이는 가지고 있는 구슬 중 0.2만큼을 버리고 남은 양의 0.35만큼을 친구에게 주었더니 남은 구슬이 130개 라고 한다. 훈정이가 처음에 가지고 있던 구슬은 몇 개인지 구하시오.",
        "question_en": "Hoonjeong threw away 0.2 of the marbles he had and gave 0.35 of the remaining amount to his friend so that there are 130 marbles left. Find how many marbles Hoonjeong had at first.",
        "answer_ko": "250",
        "answer_en": "250",
        "solution_abst_ko": "130 1 0.35 [OP_SUB] [OP_DIV] 1 0.2 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "130 1 0.35 [OP_SUB] [OP_DIV] 1 0.2 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 130\nvar_b = 1\nvar_c = 0.35\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 1\nvar_g = 0.2\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 130\nvar_b = 1\nvar_c = 0.35\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 1\nvar_g = 0.2\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "4922": {
        "category": "Comparison",
        "question_ko": "학생들이 한 줄로 서있습니다. 서윤이의 위치는 왼쪽에서 5번째, 오른쪽에서 3번째입니다. 줄을 서 있는 학생들은 모두 몇 명입니까?",
        "question_en": "Students are in a line. Suppose Seoyoon's position is at the 5th from the left and 3rd from the right, how many students are in the line?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "5 3 [OP_ADD] 1 [OP_SUB]",
        "solution_abst_en": "5 3 [OP_ADD] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 5\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "4923": {
        "category": "Arithmetic calculation",
        "question_ko": "농장에 병아리가 37마리 있었습니다. 1번째 날 병아리 23마리를 더 사 오고, 2번째 날 병아리 12마리를 더 사 왔다면 병아리는 모두 몇 마리가 늘어났습니까?",
        "question_en": "There were 37 chicks on the farm. If you bought 23 more chicks on day 1 and 12 more chicks on day 2, how many more chicks are there?",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "23 12 [OP_ADD]",
        "solution_abst_en": "23 12 [OP_ADD]",
        "solution_code_ko": "var_a = 23\nvar_b = 12\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 23\nvar_b = 12\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "4924": {
        "category": "Comparison",
        "question_ko": "A 보트는 시속 92킬로미터(㎞)의 빠르기로 운행하고, B 보트는 분속 1500미터(m)의 빠르기로 운행합니다. 두 보트 중 어떤 보트의 속력이 더 빠릅니까?",
        "question_en": "Boat A travels at a speed of 92 kilometers (km) per hour, and boat B travels at a speed of 1500 meters (m) per minute. Which of the two boats is faster?",
        "answer_ko": "A",
        "answer_en": "A",
        "solution_abst_ko": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 92 1500 1000 [OP_DIV] 60 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 92 1500 1000 [OP_DIV] 60 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 92\nvar_d = 1500\nvar_e = 1000\nvar_f = var_d / var_e\nvar_g = 60\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 92\nvar_d = 1500\nvar_e = 1000\nvar_f = var_d / var_e\nvar_g = 60\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "4925": {
        "category": "Comparison",
        "question_ko": "2.1, 3.2, 32, 12, 3.4, 2.5 중 첫 번째로 큰 수와 두 번째로 큰 수의 곱을 구하시오",
        "question_en": "Find the value of multiplication the first largest number by the second largest number among 2.1, 3.2, 32, 12, 3.4, and 2.5.",
        "answer_ko": "384",
        "answer_en": "384",
        "solution_abst_ko": "[OP_LIST_SOL] 2.1 3.2 32 12 3.4 2.5 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 2.1 3.2 32 12 3.4 2.5 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_MUL]",
        "solution_code_ko": "var_a = 2.1\nvar_b = 3.2\nvar_c = 32\nvar_d = 12\nvar_e = 3.4\nvar_f = 2.5\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_h = list_b[-var_g]\nvar_i = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = var_h * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 2.1\nvar_b = 3.2\nvar_c = 32\nvar_d = 12\nvar_e = 3.4\nvar_f = 2.5\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_h = list_b[-var_g]\nvar_i = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = var_h * var_j\nprint(int(var_k))"
    },
    "4926": {
        "category": "Comparison",
        "question_ko": "구슬이 24개 있습니다. 이 중에서 빨간색 구슬은 전체의 1/4이고, 파란색 구슬은 빨간색 구슬보다 6개 더 많고, 나머지는 노란색 구슬입니다. 어떤 색의 구슬이 가장 많습니까?",
        "question_en": "There are 24 marbles. Of these, red marbles account for 1/4 of the total. There are 6 more blue marbles than red marbles, and the rest are yellow marbles. What color beads do you have the most?",
        "answer_ko": "파란색",
        "answer_en": "blue",
        "solution_abst_ko": "[OP_LIST_SOL] 빨간색 파란색 노란색 [OP_LIST_EOL] [OP_LIST_SOL] 24 1/4 [OP_MUL] 24 1/4 [OP_MUL] 6 [OP_ADD] 24 24 1/4 [OP_MUL] 6 [OP_ADD] [OP_SUB] 24 1/4 [OP_MUL] [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] red blue yellow [OP_LIST_EOL] [OP_LIST_SOL] 24 1/4 [OP_MUL] 24 1/4 [OP_MUL] 6 [OP_ADD] 24 24 1/4 [OP_MUL] 6 [OP_ADD] [OP_SUB] 24 1/4 [OP_MUL] [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '빨간색'\nvar_b = '파란색'\nvar_c = '노란색'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 24\nvar_e = 0.25\nvar_f = var_d * var_e\nvar_g = 24\nvar_h = 0.25\nvar_i = var_g * var_h\nvar_j = 6\nvar_k = var_i + var_j\nvar_l = 24\nvar_m = 24\nvar_n = 0.25\nvar_o = var_m * var_n\nvar_p = 6\nvar_q = var_o + var_p\nvar_r = var_l - var_q\nvar_s = 24\nvar_t = 0.25\nvar_u = var_s * var_t\nvar_v = var_r - var_u\nlist_b= []\nif \"/\" in str(var_v):\n    var_v = eval(str(var_v))\nlist_b.append(var_v)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_w = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_x = list_c[-var_w]\nvar_y = list_b.index(var_x)+1\nvar_z = list_a[var_y-1]\nprint(var_z)",
        "solution_code_en": "var_a = 'red'\nvar_b = 'blue'\nvar_c = 'yellow'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 24\nvar_e = 0.25\nvar_f = var_d * var_e\nvar_g = 24\nvar_h = 0.25\nvar_i = var_g * var_h\nvar_j = 6\nvar_k = var_i + var_j\nvar_l = 24\nvar_m = 24\nvar_n = 0.25\nvar_o = var_m * var_n\nvar_p = 6\nvar_q = var_o + var_p\nvar_r = var_l - var_q\nvar_s = 24\nvar_t = 0.25\nvar_u = var_s * var_t\nvar_v = var_r - var_u\nlist_b= []\nif \"/\" in str(var_v):\n    var_v = eval(str(var_v))\nlist_b.append(var_v)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_w = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_x = list_c[-var_w]\nvar_y = list_b.index(var_x)+1\nvar_z = list_a[var_y-1]\nprint(var_z)"
    },
    "4927": {
        "category": "Arithmetic calculation",
        "question_ko": "민영이는 올해 10살이고 할머니는 올해 65세 입니다. 민영이가 7살이었을 때 할머니의 나이는 몇 세였습니까?",
        "question_en": "Minyoung is 10 years old this year and her grandmother is 65 years old this year. How old was her grandmother when Minyoung was 7 years old?",
        "answer_ko": "62",
        "answer_en": "62",
        "solution_abst_ko": "65 10 7 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "65 10 7 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 65\nvar_b = 10\nvar_c = 7\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 65\nvar_b = 10\nvar_c = 7\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "4928": {
        "category": "Arithmetic calculation",
        "question_ko": "서로 다른 여섯 개의 수 9, 2, 4, 1, 5, 6이 있습니다. 이 중에서 가장 큰 수와 두번째로 큰 수의 차는 몇인지 구하시오.",
        "question_en": "There are six different numbers: 9, 2, 4, 1, 5, and 6. Find the difference between the largest number and the second largest number.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 6 2 4 1 5 9 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 6 2 4 1 5 9 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_SUB]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = 4\nvar_d = 1\nvar_e = 5\nvar_f = 9\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_h = list_b[-var_g]\nvar_i = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = var_h - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = 4\nvar_d = 1\nvar_e = 5\nvar_f = 9\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_h = list_b[-var_g]\nvar_i = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = var_h - var_j\nprint(int(var_k))"
    },
    "4929": {
        "category": "Possibility",
        "question_ko": "정수는 숫자 카드를 한 번씩 사용하여 숫자 만들기 게임을 하고 있습니다. 숫자가 작을수록 높은 점수를 얻을 떄, 숫자 1, 4, 5가 주어진다면 어떤 수를 만드는 것이 좋습니까?",
        "question_en": "Jungsoo was playing a game making a number using number cards once. Given the numbers 1, 4, and 5, he gets a higher score as the number gets smaller. Which number would be better for him to make?",
        "answer_ko": "145",
        "answer_en": "145",
        "solution_abst_ko": "[OP_LIST_SOL] 1 4 5 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 4 5 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1\nvar_b = 4\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 4\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nprint(int(var_f))"
    },
    "4930": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 382를 빼야 하는데 잘못하여 238을 더했더니 637이 되었습니다. 바르게 계산한 결과를 구하시오.",
        "question_en": "I was supposed to subtract 382 from a number, but I mistakenly added 238 to it and get 637. What is the result of the correct calculation?",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "637 238 [OP_SUB] 382 [OP_SUB]",
        "solution_abst_en": "637 238 [OP_SUB] 382 [OP_SUB]",
        "solution_code_ko": "var_a = 637\nvar_b = 238\nvar_c = var_a - var_b\nvar_d = 382\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 637\nvar_b = 238\nvar_c = var_a - var_b\nvar_d = 382\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "4931": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 12미터(m)인 정사각형 모양의 운동장이 있다. 서윤이가 이 운동장의 둘레를 걷는 데에 걸린 시간이 가로의 길이가 9미터(m)인 직사각형 모양의 운동장의 둘레를 걷는 데에 걸린 시간과 동일했다. 동일한 속도로 걸었다고 한다면, 직사각형 모양의 운동장의 세로의 길이는 몇 미터(m)입니까?",
        "question_en": "A playground is in the shape of a square with sides measuring 12 meters (m). The time it took for Seoyoon to walk around the playground was the same as the time it took for Seoyoon to walk around the 9 meters (m) rectangular playground. If you walk at the same speed, what is the vertical length of the rectangular playground in meters (m)?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "12 4 [OP_MUL] 2 [OP_DIV] 9 [OP_SUB]",
        "solution_abst_en": "12 4 [OP_MUL] 2 [OP_DIV] 9 [OP_SUB]",
        "solution_code_ko": "var_a = 12\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 9\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 12\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 9\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "4932": {
        "category": "Geometry",
        "question_ko": "어떤 정사각형의 넓이를 구했더니 324제곱미터(㎡)였다. 정사각형의 둘레를 구하시오.",
        "question_en": "The area of a certain square was found to be 324 square meters (m2). Find the perimeter of the square.",
        "answer_ko": "72",
        "answer_en": "72",
        "solution_abst_ko": "324 1/2 [OP_POW] 4 [OP_MUL]",
        "solution_abst_en": "324 1/2 [OP_POW] 4 [OP_MUL]",
        "solution_code_ko": "var_a = 324\nvar_b = 0.5\nvar_c = var_a ** var_b\nvar_d = 4\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 324\nvar_b = 0.5\nvar_c = var_a ** var_b\nvar_d = 4\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "4933": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 7배 한 수에 37을 더했더니 100이 되었습니다. 어떤 수를 구하시오.",
        "question_en": "When you multiply a number by 7 and add 37, you get 100. Find this number.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "100 37 [OP_SUB] 7 [OP_DIV]",
        "solution_abst_en": "100 37 [OP_SUB] 7 [OP_DIV]",
        "solution_code_ko": "var_a = 100\nvar_b = 37\nvar_c = var_a - var_b\nvar_d = 7\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 100\nvar_b = 37\nvar_c = var_a - var_b\nvar_d = 7\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "4934": {
        "category": "Comparison",
        "question_ko": "석진이는 줄넘기를 어제는 32번 했고, 오늘은 어제보다 15번 더 많이 했습니다. 태형이는 줄넘기를 어제는 58번 했고, 오늘은 어제보다 12번 더 적게 했습니다. 오늘 줄넘기를 더 많이 한 사람은 누구입니까?",
        "question_en": "Seokjin jumped ropes 32 times yesterday, and today he jumped 15 times more than yesterday. Taehyung jumped ropes 58 times yesterday, and today he jumped 12 times fewer than yesterday. Who jumped more ropes today?",
        "answer_ko": "석진",
        "answer_en": "Seokjin",
        "solution_abst_ko": "[OP_LIST_SOL] 석진 태형 [OP_LIST_EOL] [OP_LIST_SOL] 32 15 [OP_ADD] 58 12 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Seokjin Taehyung [OP_LIST_EOL] [OP_LIST_SOL] 32 15 [OP_ADD] 58 12 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '석진'\nvar_b = '태형'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 32\nvar_d = 15\nvar_e = var_c + var_d\nvar_f = 58\nvar_g = 12\nvar_h = var_f - var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Seokjin'\nvar_b = 'Taehyung'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 32\nvar_d = 15\nvar_e = var_c + var_d\nvar_f = 58\nvar_g = 12\nvar_h = var_f - var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "4935": {
        "category": "Arithmetic calculation",
        "question_ko": "은지는 빨간색 색종이 1장과 초록색 색종이 9장을 모았습니다. 모은 색종이 중 4장을 유나에게 주면 은지에게 남는 색종이는 몇 장인지 구하시오.",
        "question_en": "Eunji collected 1 piece of red confetti and 9 pieces of green confetti. If she gives 4 pieces of collected confetti to Yuna, find how many pieces are left with Eunji.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "1 9 [OP_ADD] 4 [OP_SUB]",
        "solution_abst_en": "1 9 [OP_ADD] 4 [OP_SUB]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "4936": {
        "category": "Possibility",
        "question_ko": "4개의 숫자 카드 0, 1, 4, 8을 한 번씩 사용하여 일의 자리 숫자가 8인 세 번째 큰 세 자리 수를 구한 후, 각 자리 수의 합을 구하시오.",
        "question_en": "Use the four number cards 0, 1, 4, and 8 once to find the third largest three-digit number whose units digit is 8, then find the sum of each digit.",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 4 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 8 [OP_LIST_SEARCH_FIXED_DIGIT] 3 [OP_LIST_MAX] [OP_NUM2LIST] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 4 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 8 [OP_LIST_SEARCH_FIXED_DIGIT] 3 [OP_LIST_MAX] [OP_NUM2LIST] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 4\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nvar_g = 8\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 3\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nlist_e = []\nvar_i = int(var_i)\nwhile var_i//10 > 0:\n    list_e.append(var_i%10)\n    var_i = var_i//10\nlist_e.append(var_i%10)\nlist_e = list_e[::-1]\nlist_e = [float(i) for i in list_e]\nvar_j = sum(list_e)\nprint(int(var_j))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 4\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nvar_g = 8\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 3\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nlist_e = []\nvar_i = int(var_i)\nwhile var_i//10 > 0:\n    list_e.append(var_i%10)\n    var_i = var_i//10\nlist_e.append(var_i%10)\nlist_e = list_e[::-1]\nlist_e = [float(i) for i in list_e]\nvar_j = sum(list_e)\nprint(int(var_j))"
    },
    "4937": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 수를 105로 나눈 몫이 14이고 나머지가 84이다. 어떤 수를 6으로 나누고 나온 몫을 다시 7로 나눈 몫이 얼마인지 구하시오.",
        "question_en": "The quotient of this number divided by 105 is 14 and the remainder is 84. What is the value of dividing this number by 6, and then dividing the quotient by 7 again?",
        "answer_ko": "33",
        "answer_en": "33",
        "solution_abst_ko": "105 14 [OP_MUL] 84 [OP_SUB] 6 7 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "105 14 [OP_MUL] 84 [OP_SUB] 6 7 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 105\nvar_b = 14\nvar_c = var_a * var_b\nvar_d = 84\nvar_e = var_c - var_d\nvar_f = 6\nvar_g = 7\nvar_h = var_f * var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 105\nvar_b = 14\nvar_c = var_a * var_b\nvar_d = 84\nvar_e = var_c - var_d\nvar_f = 6\nvar_g = 7\nvar_h = var_f * var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "4938": {
        "category": "Correspondence",
        "question_ko": "3개씩 포장되어있는 과자가 있다. 현우는 이 포장된 과자 226개 중 3개를 친구에게 주었습니다. 현우가 가진 과자는 낱개로 모두 몇 개인지 구하시오.",
        "question_en": "There are cookies that are packed in 3 pieces. Hyunwoo gave 3 of these 226 packed cookies to his friend. Find how many pieces of cookies Hyunwoo has.",
        "answer_ko": "669",
        "answer_en": "669",
        "solution_abst_ko": "226 3 [OP_SUB] 3 [OP_MUL]",
        "solution_abst_en": "226 3 [OP_SUB] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 226\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 226\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "4939": {
        "category": "Arithmetic calculation",
        "question_ko": "우식이는 줄넘기의 횟수를 매일 2배씩 늘려가려 합니다. 첫째날에 줄넘기를 18회 넘었다면 넷째날에는 모두 몇 회를 넘겠습니까?",
        "question_en": "Woosik tries to double the number of jump ropes every day. If you jump rope 18 times on day 1, how many times will you jump rope on day 4?",
        "answer_ko": "144",
        "answer_en": "144",
        "solution_abst_ko": "18 2 4 1 [OP_SUB] [OP_POW] [OP_MUL]",
        "solution_abst_en": "18 2 4 1 [OP_SUB] [OP_POW] [OP_MUL]",
        "solution_code_ko": "var_a = 18\nvar_b = 2\nvar_c = 4\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = var_b ** var_e\nvar_g = var_a * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 18\nvar_b = 2\nvar_c = 4\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = var_b ** var_e\nvar_g = var_a * var_f\nprint(int(var_g))"
    },
    "4940": {
        "category": "Comparison",
        "question_ko": "5와 8과 9와 7 중 2번째로 작은 숫자는 무엇인가요?",
        "question_en": "Which number is the second smallest among 5, 8, 9, and 7?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "[OP_LIST_SOL] 5 8 9 7 [OP_LIST_EOL] 2 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 5 8 9 7 [OP_LIST_EOL] 2 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 5\nvar_b = 8\nvar_c = 9\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nprint(int(var_f))",
        "solution_code_en": "var_a = 5\nvar_b = 8\nvar_c = 9\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nprint(int(var_f))"
    },
    "4941": {
        "category": "Possibility",
        "question_ko": "1, 2, 3, 4 ..., 55를 차례로 이어 써서 1234567891011121314...535455를 만들었다. 이 수의 각 자리 숫자들의 총합을 구하여라.",
        "question_en": "1, 2, 3, 4 ..., 55 were written sequentially to make 1234567891011121314...535455. Find the sum of each digit in this number.",
        "answer_ko": "370",
        "answer_en": "370",
        "solution_abst_ko": "1 55 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] [OP_LIST_SUM]",
        "solution_abst_en": "1 55 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 55\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_b=[]\nfor i in list_a:\n    var_d = 0\n    i = int(i)\n    while i//10 > 0:\n        var_d = var_d + i%10\n        i = i//10\n    var_d = var_d + i%10\n    list_b.append(var_d)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 55\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_b=[]\nfor i in list_a:\n    var_d = 0\n    i = int(i)\n    while i//10 > 0:\n        var_d = var_d + i%10\n        i = i//10\n    var_d = var_d + i%10\n    list_b.append(var_d)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint(int(var_e))"
    },
    "4942": {
        "category": "Correspondence",
        "question_ko": "어떤 소수의 소수점을 왼쪽으로 두 칸 옮기면 원래 소수에서 1.485를 뺀 값이 됩니다. 원래의 소수를 구하시오.",
        "question_en": "Moving a decimal point two places to the left equals the original decimal minus 1.485. Find the original decimal number.",
        "answer_ko": "1.50",
        "answer_en": "1.5",
        "solution_abst_ko": "1.485 0.99 [OP_DIV]",
        "solution_abst_en": "1.485 0.99 [OP_DIV]",
        "solution_code_ko": "var_a = 1.485\nvar_b = 0.99\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 1.485\nvar_b = 0.99\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "4943": {
        "category": "Arithmetic calculation",
        "question_ko": "선주는 매일 2+2/3킬로미터(㎞)씩 달렸습니다. 선주가 9일 동안 달린 거리는 모두 킬로미터(㎞)일까요?",
        "question_en": "Seonju ran 2+2/3 kilometers (km) every day. How many kilometers (km) did Seonju run for 9 days?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "2 2/3 [OP_ADD] 9 [OP_MUL]",
        "solution_abst_en": "2 2/3 [OP_ADD] 9 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 0.6666666666666666\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 0.6666666666666666\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "4944": {
        "category": "Possibility",
        "question_ko": "복숭아, 사과, 배, 참외, 감 중에서 2가지의 과일을 골라서 사는 경우는 모두 몇 가지입니까?",
        "question_en": "How ways are there to choose and buy two fruits out of peaches, apples, pears, melons, and persimmons?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "5 2 [OP_COMB]",
        "solution_abst_en": "5 2 [OP_COMB]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))"
    },
    "4945": {
        "category": "Arithmetic calculation",
        "question_ko": "영어 서적 1장을 번역하는데 준석이는 4시간이 걸리고 윤열이는 12시간이 걸린다. 둘이 번역을 함께한다면 1장을 번역하는데 몇시간이 걸리는지 구하시오.",
        "question_en": "It takes Jun-seok 4 hours to translate a chapter of an English book and it takes Yoon-yeol 12 hours. If the two of them work together, how many hours will it take to translate one chapter?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "1 1 4 [OP_DIV] 1 12 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_abst_en": "1 1 4 [OP_DIV] 1 12 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 1\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = 1\nvar_f = 12\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = var_a / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 1\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = 1\nvar_f = 12\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = var_a / var_h\nprint(int(var_i))"
    },
    "4946": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 100까지의 자연수 중 2로 나누었을 때 나머지가 1인 것들의 합과 0인 것들의 합의 차를 구하시오.",
        "question_en": "What is the difference between the sum of numbers whose remainder is 1 and the sum of numbers whose remainder is 0 when divided by 2 from 1 to 100?",
        "answer_ko": "50",
        "answer_en": "50",
        "solution_abst_ko": "1 100 [OP_LIST_EVEN] [OP_LIST_SUM] 1 100 [OP_LIST_ODD] [OP_LIST_SUM] [OP_SUB]",
        "solution_abst_en": "1 100 [OP_LIST_EVEN] [OP_LIST_SUM] 1 100 [OP_LIST_ODD] [OP_LIST_SUM] [OP_SUB]",
        "solution_code_ko": "var_a = 1\nvar_b = 100\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nvar_d = 1\nvar_e = 100\nlist_b = []\nif var_d%2==0:\n    for i in range(var_d+1, var_e+1, 2):\n        list_b.append(i)\nelse:\n    for i in range(var_d, var_e+1, 2):\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 100\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nvar_d = 1\nvar_e = 100\nlist_b = []\nif var_d%2==0:\n    for i in range(var_d+1, var_e+1, 2):\n        list_b.append(i)\nelse:\n    for i in range(var_d, var_e+1, 2):\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "4947": {
        "category": "Correspondence",
        "question_ko": "닭장 안에 병아리와 닭이 모두 합쳐 86마리가 있고 병아리는 30마리이다. 닭들이 하루에 3개의 알을 낳는다면 이 닭장에서 30일동안 얻을 수 있는 달걀의 개수를 구하시오.",
        "question_en": "There are a total of 86 chicks and chickens in the coop and 30 chicks. If hens lay 3 eggs per day, how many eggs can you get from this henhouse in 30 days?",
        "answer_ko": "5040",
        "answer_en": "5040",
        "solution_abst_ko": "86 30 [OP_SUB] 3 [OP_MUL] 30 [OP_MUL]",
        "solution_abst_en": "86 30 [OP_SUB] 3 [OP_MUL] 30 [OP_MUL]",
        "solution_code_ko": "var_a = 86\nvar_b = 30\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c * var_d\nvar_f = 30\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 86\nvar_b = 30\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c * var_d\nvar_f = 30\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "4948": {
        "category": "Geometry",
        "question_ko": "가로가 3센티미터(㎝) , 세로가 4 센티미터(㎝) , 높이가 5센티미터(㎝) 인 직육면체의 겉넓이를 구하시오.",
        "question_en": "Find the surface area of a cuboid whose width is 3 centimeters (cm), length is 4 centimeters (cm), and height is 5 centimeters (cm).",
        "answer_ko": "94",
        "answer_en": "94",
        "solution_abst_ko": "3 4 [OP_MUL] 3 5 [OP_MUL] 4 5 [OP_MUL] [OP_ADD] [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "3 4 [OP_MUL] 3 5 [OP_MUL] 4 5 [OP_MUL] [OP_ADD] [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = 4\nvar_h = 5\nvar_i = var_g * var_h\nvar_j = var_f + var_i\nvar_k = var_c + var_j\nvar_l = 2\nvar_m = var_k * var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 3\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = 4\nvar_h = 5\nvar_i = var_g * var_h\nvar_j = var_f + var_i\nvar_k = var_c + var_j\nvar_l = 2\nvar_m = var_k * var_l\nprint(int(var_m))"
    },
    "4949": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 30센티미터(㎝)인 정사각형 종이가 있습니다. 반지름이 3센티미터(㎝)인 원을 최대 몇 개 만들 수 있습니까?",
        "question_en": "You have a square piece of paper with a side of 30 centimeters (cm). How many circles that has a radius of 3 centimeters (cm) can you make?",
        "answer_ko": "25",
        "answer_en": "25",
        "solution_abst_ko": "30 3 2 [OP_MUL] [OP_FDIV] 2 [OP_POW]",
        "solution_abst_en": "30 3 2 [OP_MUL] [OP_FDIV] 2 [OP_POW]",
        "solution_code_ko": "var_a = 30\nvar_b = 3\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a // var_d\nvar_f = 2\nvar_g = var_e ** var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 30\nvar_b = 3\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a // var_d\nvar_f = 2\nvar_g = var_e ** var_f\nprint(int(var_g))"
    },
    "4950": {
        "category": "Comparison",
        "question_ko": "20명의 학생들이 버스를 기다리고 있습니다. 정국이는 윤기보다 늦게 왔고, 윤기와 정국이 사이에는 5명의 학생이 있습니다. 정국의 뒤에는 6명의 학생들이 서 있습니다. 윤기의 앞에 서 있는 학생은 몇 명입니까?",
        "question_en": "20 students are waiting for the bus. Jungkook came later than Yoongi, and there are 5 students between Yoongi and Jungkook. There are 6 students standing behind Jungkook. How many students are standing in front of Yoongi?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "20 6 [OP_SUB] 1 [OP_SUB] 5 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "20 6 [OP_SUB] 1 [OP_SUB] 5 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 6\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 5\nvar_g = var_e - var_f\nvar_h = 1\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 20\nvar_b = 6\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 5\nvar_g = var_e - var_f\nvar_h = 1\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "4951": {
        "category": "Arithmetic calculation",
        "question_ko": "27, 103, 78, 35, 97이 있습니다. 5개의 수 중 가장 큰 수와 작은 수의 차는 얼마입니까?",
        "question_en": "There are 27, 103, 78, 35, and 97. What is the difference between the largest and the smallest of five numbers?",
        "answer_ko": "76",
        "answer_en": "76",
        "solution_abst_ko": "[OP_LIST_SOL] 27 103 78 35 97 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 27 103 78 35 97 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 27\nvar_b = 103\nvar_c = 78\nvar_d = 35\nvar_e = 97\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 27\nvar_b = 103\nvar_c = 78\nvar_d = 35\nvar_e = 97\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))"
    },
    "4952": {
        "category": "Geometry",
        "question_ko": "서로 평행한 두 면이 합동인 다각형이고 옆면이 직사각형 6개로 이루어진 입체도형의 꼭짓점은 몇 개인지 답을 구해보세요.",
        "question_en": "Find the answer to how many vertices there are in a three-dimensional figure with two parallel sides congruent polygons and six rectangular sides.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "6 2 [OP_MUL]",
        "solution_abst_en": "6 2 [OP_MUL]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "4953": {
        "category": "Arithmetic calculation",
        "question_ko": "유정이가 민영이에게 공책 17권 중 몇 권을 빌려갔더니 민영이에게 공책 8권이 남았습니다. 유정이가 빌려간 공책은 몇 권일까요?",
        "question_en": "Yoo-jeong borrowed some of the 17 notebooks from Min-young, and Min-young had 8 notebooks left. How many notebooks did Yoo-jeong borrow?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "17 8 [OP_SUB]",
        "solution_abst_en": "17 8 [OP_SUB]",
        "solution_code_ko": "var_a = 17\nvar_b = 8\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 17\nvar_b = 8\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "4954": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 29를 빼고 다시 13으로 나누면 15가 됩니다. 어떤 수를 구하시오.",
        "question_en": "Subtracting 29 from any number and dividing it by 13 gives you 15. Find any number.",
        "answer_ko": "224",
        "answer_en": "224",
        "solution_abst_ko": "15 13 [OP_MUL] 29 [OP_ADD]",
        "solution_abst_en": "15 13 [OP_MUL] 29 [OP_ADD]",
        "solution_code_ko": "var_a = 15\nvar_b = 13\nvar_c = var_a * var_b\nvar_d = 29\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 13\nvar_c = var_a * var_b\nvar_d = 29\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "4955": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 광물 1그램(g) 당 17.25원의 가격이라고 합니다. 양팔 저울에 1000그램(g)짜리 분동 1개와 10그램(g)짜리 분동 1개를 올리고 반대 편에 광물 덩어리를 올렸더니 수평이 맞았다. 광물의 가치는 얼마입니까?",
        "question_en": "It is said that the price is 17.25 won per 1 gram (g) of a certain mineral. When one 1000 gram (g) weight and one 10 gram (g) weight were placed on a balance, and a lump of the mineral was placed on the other side, it was level. How much is a mineral worth?",
        "answer_ko": "17422.50",
        "answer_en": "17422.5",
        "solution_abst_ko": "17.25 1000 [OP_MUL] 17.25 10 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "17.25 1000 [OP_MUL] 17.25 10 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 17.25\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 17.25\nvar_e = 10\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 17.25\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 17.25\nvar_e = 10\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "4956": {
        "category": "Geometry",
        "question_ko": "어떤 직사각형의 둘레가 30센티미터(㎝)이고 가로는 10센티미터(㎝)입니다. 이 직사각형의 세로의 길이는 얼마입니까?",
        "question_en": "A rectangle has a perimeter of 30 centimeters (cm) and a width of 10 centimeters (cm). How long is the length of this rectangle?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "30 2 [OP_DIV] 10 [OP_SUB]",
        "solution_abst_en": "30 2 [OP_DIV] 10 [OP_SUB]",
        "solution_code_ko": "var_a = 30\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 10\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 30\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 10\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "4957": {
        "category": "Geometry",
        "question_ko": "현수는 운동장에서 반지름이 50미터(m)인 원 모양으로 산책을 하고 있었습니다. 산책을 하면서 7.85미터(m)마다 엑스 표시를 해두려고 합니다. 원주율을 3.14로 계산한다면, 현수가 한 바퀴를 돌았을 때 몇 개의 엑스 표시가 있겠습니까?",
        "question_en": "Hyeonsu was walking in the shape of a circle with a radius of 50 meters (m) in the playground. He takes a walk and tries to mark every 7.85 meters (m) with an X. If the pi is calculated as 3.14, how many X marks will there be when Hyeonsu makes a turn?",
        "answer_ko": "40",
        "answer_en": "40",
        "solution_abst_ko": "50 2 [OP_MUL] 3.14 [OP_MUL] 7.85 [OP_FDIV]",
        "solution_abst_en": "50 2 [OP_MUL] 3.14 [OP_MUL] 7.85 [OP_FDIV]",
        "solution_code_ko": "var_a = 50\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 3.14\nvar_e = var_c * var_d\nvar_f = 7.85\nvar_g = var_e // var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 50\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 3.14\nvar_e = var_c * var_d\nvar_f = 7.85\nvar_g = var_e // var_f\nprint(int(var_g))"
    },
    "4958": {
        "category": "Geometry",
        "question_ko": "아랫변이 9센티미터(㎝)이고 윗변이 5센티미터(㎝)인 사다리꼴이 있습니다. 넓이를 구했더니 56제곱센티미터(㎠)이라면, 이 사다리꼴의 높이는 몇 센티미터(㎝)일까요?",
        "question_en": "You have a trapezoid with a lower side of 9 centimeters (cm) and an upper side of 5 centimeters (cm). If the area is 56 square centimeters (cm2), how many centimeters (cm) is the height of this trapezoid?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "56 2 [OP_MUL] 5 9 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "56 2 [OP_MUL] 5 9 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 56\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = 9\nvar_f = var_d + var_e\nvar_g = var_c / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 56\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = 9\nvar_f = var_d + var_e\nvar_g = var_c / var_f\nprint(int(var_g))"
    },
    "4959": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 3번째로 큰 수와 2번째로 큰 수로 나눈 값은 얼마입니까?",
        "question_en": "There are five numbers 10, 11, 12, 13, and 14. What is the result when you divide the 3rd largest number by the 2nd largest number?",
        "answer_ko": "0.92",
        "answer_en": "0.92",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 3 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_DIV]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 3 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[-var_h]\nvar_j = var_g / var_i\nprint('{:.2f}'.format(round(var_j+1e-10,2)))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[-var_h]\nvar_j = var_g / var_i\nprint('{:.2f}'.format(round(var_j+1e-10,2)))"
    },
    "4960": {
        "category": "Arithmetic calculation",
        "question_ko": "9/10, 1.8, 2, 1, 11/5 5개의 수 중에서 1보다 크고 2보다 작은 수를 소수점을 포함하여 답을 쓰시오.",
        "question_en": "Among the five numbers 9/10, 1.8, 2, 1, 11/5 , write the number greater than 1 and less than 2 including the decimal point.",
        "answer_ko": "1.80",
        "answer_en": "1.8",
        "solution_abst_ko": "[OP_LIST_SOL] 9/10 1.8 2 1 11/5 [OP_LIST_EOL] 1 [OP_LIST_MORE] 2 [OP_LIST_LESS] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] 9/10 1.8 2 1 11/5 [OP_LIST_EOL] 1 [OP_LIST_MORE] 2 [OP_LIST_LESS] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 0.9\nvar_b = 1.8\nvar_c = 2\nvar_d = 1\nvar_e = 2.2\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = 2\nlist_c = []\nfor i in list_b:\n    if i < var_g:\n        list_c.append(i)\nvar_h = 1\nvar_i = list_c[var_h-1]\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 0.9\nvar_b = 1.8\nvar_c = 2\nvar_d = 1\nvar_e = 2.2\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = 2\nlist_c = []\nfor i in list_b:\n    if i < var_g:\n        list_c.append(i)\nvar_h = 1\nvar_i = list_c[var_h-1]\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "4961": {
        "category": "Arithmetic calculation",
        "question_ko": "44개의 탁구공을 4개로 바구니에 나누어 담을 때 총 몇 개의 바구니가 필요한가?",
        "question_en": "How many baskets are needed to divide 44 ping pong balls into 4 baskets?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "44 4 [OP_DIV]",
        "solution_abst_en": "44 4 [OP_DIV]",
        "solution_code_ko": "var_a = 44\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 44\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "4962": {
        "category": "Geometry",
        "question_ko": "큰 구슬의 반지름은 6센티미터(㎝)이고, 작은 구슬의 반지름은 3센티미터(㎝)일 때, 큰 구슬의 겉넓이는 작은 구슬의 겉넓이의 몇 배인지 구하시오.",
        "question_en": "If the radius of the large marble is 6 centimeters (cm) and the radius of the small marble is 3 centimeters (cm), how many times the surface area of the large marble is the surface area of the small marble?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "6 3 [OP_DIV] 2 [OP_POW]",
        "solution_abst_en": "6 3 [OP_DIV] 2 [OP_POW]",
        "solution_code_ko": "var_a = 6\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint(int(var_e))"
    },
    "4963": {
        "category": "Comparison",
        "question_ko": "음악실에 똑같은 피아노가 28대 있습니다. 각 피아노마다 가진 건반의 수는 같습니다. 어느 피아노에서 앞에서 14번째, 뒤에서 20번째 건반을 눌렀을 때, 이 음악실 안에 있는 피아노들의 건반 수를 모두 구하시오.",
        "question_en": "There are 28 identical pianos in the music room. Each piano has the same number of keys. When you press the 14th key from the front and the 20th key from the back of a certain piano, find the number of keys on all the pianos in this music room.",
        "answer_ko": "924",
        "answer_en": "924",
        "solution_abst_ko": "14 20 [OP_ADD] 1 [OP_SUB] 28 [OP_MUL]",
        "solution_abst_en": "14 20 [OP_ADD] 1 [OP_SUB] 28 [OP_MUL]",
        "solution_code_ko": "var_a = 14\nvar_b = 20\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 28\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 14\nvar_b = 20\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 28\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "4964": {
        "category": "Geometry",
        "question_ko": "가로 16센티미터(㎝), 세로 14센티미터(㎝), 높이 9센티미터(㎝)인 직육면체 모양의 그릇에 물이 4센티미터(㎝) 높이만큼 들어 있었습니다. 이 그릇에 돌을 넣었더니 물의 높이가 9센티미터(㎝)가 되었습니다. 돌의 부피는 몇 세제곱센티미터(㎤)입니까?",
        "question_en": "There is a rectangular cuboid-shaped bowl measuring 16 centimeters (cm) wide, 14 centimeters (cm) long, and 9 centimeters (cm) high containing water 4 centimeters (cm) high. When a stone was placed in this bowl, the water level rose to 9 centimeters (cm). What is the volume of the stone in cubic centimeters (cm3)?",
        "answer_ko": "1120",
        "answer_en": "1120",
        "solution_abst_ko": "16 14 [OP_MUL] 9 4 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "16 14 [OP_MUL] 9 4 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 16\nvar_b = 14\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = 4\nvar_f = var_d - var_e\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 16\nvar_b = 14\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = 4\nvar_f = var_d - var_e\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "4965": {
        "category": "Comparison",
        "question_ko": "3개의 숫자 0.8, 1/2, 0.9가 있습니다. 2보다 크거나 같은 수는 몇 개입니까?",
        "question_en": "There are three numbers 0.8, 1/2, and 0.9. How many numbers are greater than or equal to 2?",
        "answer_ko": "0",
        "answer_en": "0",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 2 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 2 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "4966": {
        "category": "Arithmetic calculation",
        "question_ko": "작은 구의 반지름은 큰 구의 반지름의 1/4입니다. 큰 구의 부피는 작은 구의 부피의 몇 배인지 구하세요.",
        "question_en": "The radius of the smaller sphere is 1/4 of the radius of the larger sphere. Find how many times bigger the volume of the larger sphere is compared to the volume of the smaller sphere.",
        "answer_ko": "64",
        "answer_en": "64",
        "solution_abst_ko": "1 1/4 3 [OP_POW] [OP_DIV]",
        "solution_abst_en": "1 1/4 3 [OP_POW] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 0.25\nvar_c = 3\nvar_d = var_b ** var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 0.25\nvar_c = 3\nvar_d = var_b ** var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "4967": {
        "category": "Comparison",
        "question_ko": "도서관에 똑같은 책장이 28개 있습니다. 각 책장은 6층이고, 각 층마다 꽂혀 있는 책의 수는 같습니다. 영어책은 어느 책장의 한 층의 왼쪽에서 9번째, 오른쪽에서 11번째에 꽂혀 있습니다. 도서관의 책장에 꽂혀 있는 책은 모두 몇 권입니까?",
        "question_en": "There are 28 identical bookshelves in the library. Each bookshelf has 6 floors, and the number of books on each floor is the same. An English book is placed 9th from the left and 11th from the right on one floor of a bookshelf. How many books are on the shelves in the library?",
        "answer_ko": "3192",
        "answer_en": "3192",
        "solution_abst_ko": "9 11 [OP_ADD] 1 [OP_SUB] 6 [OP_MUL] 28 [OP_MUL]",
        "solution_abst_en": "9 11 [OP_ADD] 1 [OP_SUB] 6 [OP_MUL] 28 [OP_MUL]",
        "solution_code_ko": "var_a = 9\nvar_b = 11\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 6\nvar_g = var_e * var_f\nvar_h = 28\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 9\nvar_b = 11\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 6\nvar_g = var_e * var_f\nvar_h = 28\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "4968": {
        "category": "Geometry",
        "question_ko": "높이가 5미터(m) 20센티미터(㎝)이고 밑면이 각각 6미터(m) 40센티미터(㎝), 9미터(m)인 쌀이 가득 들어있는 직육면체 모양의 쌀통이 있습니다. 쌀을 부피가 1세제곱미터(㎥)인 쌀통 여러 개에 모두 나누어 담으려고 합니다. 쌀통은 적어도 몇 개 필요한지 구해보시오.",
        "question_en": "There is a cuboid-shaped rice container full of rice with a height of 5 meters (m) 20 centimeters (cm) and a base with side lengths of 6 meters (m) 40 centimeters (cm) and 9 meters (m) respectively. You want to divide the rice into several rice bins of 1 cubic meter (m3) in volume. Find how many boxes of rice you need at least.",
        "answer_ko": "300",
        "answer_en": "300",
        "solution_abst_ko": "6 40 100 [OP_DIV] [OP_ADD] 9 [OP_MUL] 5 20 100 [OP_DIV] [OP_ADD] [OP_MUL] 1 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "6 40 100 [OP_DIV] [OP_ADD] 9 [OP_MUL] 5 20 100 [OP_DIV] [OP_ADD] [OP_MUL] 1 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 6\nvar_b = 40\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 9\nvar_g = var_e * var_f\nvar_h = 5\nvar_i = 20\nvar_j = 100\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_g * var_l\nvar_n = 1\nvar_o = var_m / var_n\nvar_p = 1\nvar_q=int(((var_o+9*10**(var_p-2))//(10**(var_p-1)))*10**(var_p-1))\n\nprint(int(var_q))",
        "solution_code_en": "var_a = 6\nvar_b = 40\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 9\nvar_g = var_e * var_f\nvar_h = 5\nvar_i = 20\nvar_j = 100\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_g * var_l\nvar_n = 1\nvar_o = var_m / var_n\nvar_p = 1\nvar_q=int(((var_o+9*10**(var_p-2))//(10**(var_p-1)))*10**(var_p-1))\n\nprint(int(var_q))"
    },
    "4969": {
        "category": "Comparison",
        "question_ko": "과일가게에서 태형, 남준, 지민이가 사과를 샀습니다. 지민이는 태형이보다 사과를 많이 샀고, 태형이는 남준이보다 사과를 많이 샀다면, 사과를 가장 많이 산 학생은 누구인가요?",
        "question_en": "Taehyung, Namjoon, and Jimin bought apples at the fruit shop. If Jimin bought more apples than Taehyung and Taehyung bought more apples than Namjoon, who bought the most apples?",
        "answer_ko": "지민",
        "answer_en": "Jimin",
        "solution_abst_ko": "[OP_LIST_SOL] 태형 남준 지민 [OP_LIST_EOL] [OP_LIST_SOL] 태형 남준 > 지민 태형 > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Taehyung Namjoon Jimin [OP_LIST_EOL] [OP_LIST_SOL] Taehyung Namjoon > Jimin Taehyung > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '태형'\nvar_b = '남준'\nvar_c = '지민'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '태형'\nvar_e = '남준'\nvar_f = '>'\nvar_g = '지민'\nvar_h = '태형'\nvar_i = '>'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(var_k)",
        "solution_code_en": "var_a = 'Taehyung'\nvar_b = 'Namjoon'\nvar_c = 'Jimin'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'Taehyung'\nvar_e = 'Namjoon'\nvar_f = '>'\nvar_g = 'Jimin'\nvar_h = 'Taehyung'\nvar_i = '>'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(var_k)"
    },
    "4970": {
        "category": "Correspondence",
        "question_ko": "8A-B2=45라고 합니다. A, B가 서로 다른 두 수 일 때, A+B는 무엇인가요?",
        "question_en": "Taking B2 from 8A made it 45. What is A+B?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "8A-B2=45 A [OP_DIGIT_UNK_SOLVER] 8A-B2=45 B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_abst_en": "8A-B2=45 A [OP_DIGIT_UNK_SOLVER] 8A-B2=45 B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_code_ko": "var_a = '8A-B2=45'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '8A-B2=45'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = '8A-B2=45'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '8A-B2=45'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "4971": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 468을 더하면 954가 나온다. 어떤 수에서 3을 빼면 얼마인지 구하시오.",
        "question_en": "Adding 468 to a certain number gives 954. What is the result when subtracting 3 from this number?",
        "answer_ko": "483",
        "answer_en": "483",
        "solution_abst_ko": "954 468 [OP_SUB] 3 [OP_SUB]",
        "solution_abst_en": "954 468 [OP_SUB] 3 [OP_SUB]",
        "solution_code_ko": "var_a = 954\nvar_b = 468\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 954\nvar_b = 468\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "4972": {
        "category": "Possibility",
        "question_ko": "A, B, C, D, E, F 6명을 한 줄로 세울 때, C, D를 서로 이웃하게 하여 세우는 경우의 수를 구하시오.",
        "question_en": "Find the number of ways to put C and D next to each other when 6 people A, B, C, D, E and F are lined up in a line.",
        "answer_ko": "240",
        "answer_en": "240",
        "solution_abst_ko": "[OP_LIST_SOL] A B C D E F [OP_LIST_EOL] [OP_LIST_SOL] A [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] C D [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D E F [OP_LIST_EOL] [OP_LIST_SOL] A [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] C D [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nvar_f = 'F'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 'A'\nlist_b= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_h = len(list_c)\nvar_i = len(list_c)\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nvar_k = 'C'\nvar_l = 'D'\nlist_d= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_d.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_d.append(var_k)\nlist_d.reverse()\nvar_m = len(list_d)\nvar_n = len(list_d)\nvar_o = 1\nvar_m = int(var_m)\nvar_n = int(var_n)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o * (var_m-i)\nvar_p = var_j * var_o\nprint(int(var_p))",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nvar_f = 'F'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 'A'\nlist_b= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_h = len(list_c)\nvar_i = len(list_c)\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nvar_k = 'C'\nvar_l = 'D'\nlist_d= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_d.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_d.append(var_k)\nlist_d.reverse()\nvar_m = len(list_d)\nvar_n = len(list_d)\nvar_o = 1\nvar_m = int(var_m)\nvar_n = int(var_n)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o * (var_m-i)\nvar_p = var_j * var_o\nprint(int(var_p))"
    },
    "4973": {
        "category": "Geometry",
        "question_ko": "팔각형에서 그을 수 있는 모든 대각선의 개수와 칠각형에서 그을 수 있는 모든 대각선의 개수의 차를 구하시오.",
        "question_en": "Find the difference between the number of diagonals in the octagon and the number of diagonals in the heptagon.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "8 8 3 [OP_SUB] [OP_MUL] 2 [OP_DIV] 7 7 3 [OP_SUB] [OP_MUL] 2 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "8 8 3 [OP_SUB] [OP_MUL] 2 [OP_DIV] 7 7 3 [OP_SUB] [OP_MUL] 2 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 8\nvar_b = 8\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 7\nvar_i = 7\nvar_j = 3\nvar_k = var_i - var_j\nvar_l = var_h * var_k\nvar_m = 2\nvar_n = var_l / var_m\nvar_o = var_g - var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 8\nvar_b = 8\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 7\nvar_i = 7\nvar_j = 3\nvar_k = var_i - var_j\nvar_l = var_h * var_k\nvar_m = 2\nvar_n = var_l / var_m\nvar_o = var_g - var_n\nprint(int(var_o))"
    },
    "4974": {
        "category": "Geometry",
        "question_ko": "성호네 교실의 칠판은 가로가 5.4미터(m), 세로가 2.5미터(m)인 직사각형 모양입니다. 이 칠판의 넓이는 몇 제곱미터(㎡)입니까?",
        "question_en": "The shape of the blackboard in Seongho's classroom is a rectangle with a width of 5.4 meters (m) and a height of 2.5 meters (m). What is the area of this blackboard in square meters (m2)?",
        "answer_ko": "13.50",
        "answer_en": "13.5",
        "solution_abst_ko": "5.4 2.5 [OP_MUL]",
        "solution_abst_en": "5.4 2.5 [OP_MUL]",
        "solution_code_ko": "var_a = 5.4\nvar_b = 2.5\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 5.4\nvar_b = 2.5\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "4975": {
        "category": "Correspondence",
        "question_ko": "A5+2B=68이 성립할 때, B에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "When A5+2B=68, what number should go into B?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "A5+2B=68 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A5+2B=68 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A5+2B=68'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A5+2B=68'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "4976": {
        "category": "Correspondence",
        "question_ko": "3.6과 어떤 수의 곱은 10.08입니다. 어떤 수에 15를 곱한값을 구하시오.",
        "question_en": "The product of 3.6 and a number is 10.08. Find the value multiplied by 15.",
        "answer_ko": "42",
        "answer_en": "42",
        "solution_abst_ko": "10.08 3.6 [OP_DIV] 15 [OP_MUL]",
        "solution_abst_en": "10.08 3.6 [OP_DIV] 15 [OP_MUL]",
        "solution_code_ko": "var_a = 10.08\nvar_b = 3.6\nvar_c = var_a / var_b\nvar_d = 15\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10.08\nvar_b = 3.6\nvar_c = var_a / var_b\nvar_d = 15\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "4977": {
        "category": "Comparison",
        "question_ko": "유정이와 은지는 같은 아파트에 삽니다. 유정이는 17층에 살고 은지는 25층에 삽니다. 누가 더 높은 층에 삽니까?",
        "question_en": "Yoojung and Eunji live in the same apartment. Yoojung lives on the 17th floor and Eunji lives on the 25th floor. Who lives on the higher floor?",
        "answer_ko": "은지",
        "answer_en": "Eunji",
        "solution_abst_ko": "[OP_LIST_SOL] 유정 은지 [OP_LIST_EOL] [OP_LIST_SOL] 17 25 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoojung Eunji [OP_LIST_EOL] [OP_LIST_SOL] 17 25 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '유정'\nvar_b = '은지'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 17\nvar_d = 25\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Yoojung'\nvar_b = 'Eunji'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 17\nvar_d = 25\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "4978": {
        "category": "Comparison",
        "question_ko": "밭의 2/7에는 배추, 3/8에는 가지를 심었습니다. 배추와 가지 중 어느 부분이 더 넓습니까?",
        "question_en": "I planted cabbage on 2/7 of the field, and eggplant on 3/8. Which part is wider, cabbage or eggplant?",
        "answer_ko": "가지",
        "answer_en": "eggplant",
        "solution_abst_ko": "[OP_LIST_SOL] 배추 가지 [OP_LIST_EOL] [OP_LIST_SOL] 2 7 [OP_DIV] 3 8 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] cabbage eggplant [OP_LIST_EOL] [OP_LIST_SOL] 2 7 [OP_DIV] 3 8 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '배추'\nvar_b = '가지'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nvar_d = 7\nvar_e = var_c / var_d\nvar_f = 3\nvar_g = 8\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'cabbage'\nvar_b = 'eggplant'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nvar_d = 7\nvar_e = var_c / var_d\nvar_f = 3\nvar_g = 8\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "4979": {
        "category": "Arithmetic calculation",
        "question_ko": "무게가 똑같은 사과가 12개 들어있는 바구니의 무게를 재어 보니 11.48킬로그램(㎏)이었습니다. 바구니에서 사과를 4개 꺼내어 먹은 후 다시 무게를 재었더니 8.12킬로그램(㎏)이 되었습니다. 빈 바구니의 무게는 몇 킬로그램(㎏)인지 구하시오.",
        "question_en": "A basket containing 12 apples of the same weight weighed 11.48 kilograms (kg). I took four appes out of the basket and ate them, and the basket weighed 8.12 kilograms (kg) this time. Find the weight in kilograms (kg) of the empty basket.",
        "answer_ko": "1.40",
        "answer_en": "1.4",
        "solution_abst_ko": "11.48 11.48 8.12 [OP_SUB] 4 [OP_DIV] 12 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "11.48 11.48 8.12 [OP_SUB] 4 [OP_DIV] 12 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 11.48\nvar_b = 11.48\nvar_c = 8.12\nvar_d = var_b - var_c\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = 12\nvar_h = var_f * var_g\nvar_i = var_a - var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 11.48\nvar_b = 11.48\nvar_c = 8.12\nvar_d = var_b - var_c\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = 12\nvar_h = var_f * var_g\nvar_i = var_a - var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "4980": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 156미터(m)인 도로의 한쪽에 처음부터 끝까지 6미터(m) 간격으로 나무를 심으려고 합니다. 필요한 나무는 모두 몇 그루인지 구해 보시오.",
        "question_en": "You want to plant trees at intervals of 6 meters (m) from start to finish on one side of a road that is 156 meters (m) long. Find how many trees you need in all.",
        "answer_ko": "27",
        "answer_en": "27",
        "solution_abst_ko": "156 6 [OP_DIV] 1 [OP_ADD]",
        "solution_abst_en": "156 6 [OP_DIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 156\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 156\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "4981": {
        "category": "Correspondence",
        "question_ko": "서로 다른 두 수 A, B가 있습니다. 두 자리 수끼리의 덧셈식 2A+B2=89에서 A-B의 값을 구하시오.",
        "question_en": "There are two different numbers A and B. Find the value of A-B from the two-digit addition formula 2A+B2=89.",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "2A+B2=89 A [OP_DIGIT_UNK_SOLVER] 2A+B2=89 B [OP_DIGIT_UNK_SOLVER] [OP_SUB]",
        "solution_abst_en": "2A+B2=89 A [OP_DIGIT_UNK_SOLVER] 2A+B2=89 B [OP_DIGIT_UNK_SOLVER] [OP_SUB]",
        "solution_code_ko": "var_a = '2A+B2=89'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '2A+B2=89'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = '2A+B2=89'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '2A+B2=89'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "4982": {
        "category": "Geometry",
        "question_ko": "준서는 색도화지로 만든 마름는 한 대각선의 길이가 16 센티미터(㎝)이며, 넓이가 80제곱센티미터(㎠)입니다. 준서가 만든 마름모의 다른 대각선의 길이는 몇 센티미터(㎝)일까요?",
        "question_en": "A diamond made of colored paper is 16 centimeters (cm) long with an area of 80 square cm (cm2). What is the length of the other diagonal of the rhombus created by Junseo in centimeters (cm)?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "80 2 [OP_MUL] 16 [OP_DIV]",
        "solution_abst_en": "80 2 [OP_MUL] 16 [OP_DIV]",
        "solution_code_ko": "var_a = 80\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 16\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 80\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 16\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "4983": {
        "category": "Possibility",
        "question_ko": "10이상 40이하의 수 중 1, 3, 8, 7로 이루어진 수는 몇 개인지 구하시오.",
        "question_en": "How many numbers between 10 and 40 has 1, 3, 8, and 7 in them?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 7 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 40 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 7 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 40 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 7\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 40\nlist_c = []\nfor i in list_b:\n    if i <= var_f:\n        list_c.append(i)\nvar_g = len(list_c)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 7\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 40\nlist_c = []\nfor i in list_b:\n    if i <= var_f:\n        list_c.append(i)\nvar_g = len(list_c)\nprint(int(var_g))"
    },
    "4984": {
        "category": "Comparison",
        "question_ko": "두자리 자연수들 중 일의 자리수가 7이고 50보다 작은 값들은 모두 몇 개 인지 구하시오.",
        "question_en": "How many two-digit natural numbers have the unit digit equal to 7 and are less than 50?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "10 99 1 [OP_LIST_ARANGE] 1 7 [OP_LIST_SEARCH_FIXED_DIGIT] 50 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "10 99 1 [OP_LIST_ARANGE] 1 7 [OP_LIST_SEARCH_FIXED_DIGIT] 50 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 1\nvar_e = 7\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i in list_a:\n    i = int(i)\n    if (i//var_d)%10 == var_e:\n        list_b.append(i)\nvar_f = 50\nlist_c = []\nfor i in list_b:\n    if i < var_f:\n        list_c.append(i)\nvar_g = len(list_c)\nprint(int(var_g))",
        "solution_code_en": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 1\nvar_e = 7\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i in list_a:\n    i = int(i)\n    if (i//var_d)%10 == var_e:\n        list_b.append(i)\nvar_f = 50\nlist_c = []\nfor i in list_b:\n    if i < var_f:\n        list_c.append(i)\nvar_g = len(list_c)\nprint(int(var_g))"
    },
    "4985": {
        "category": "Arithmetic calculation",
        "question_ko": "구슬 328개를 15명의 학생에게 똑같이 나누어 주려고 하였더니 몇 개가 모자랐습니다. 구슬을 남김없이 똑같이 나누어 주려면 구슬은 적어도 몇 개 더 필요한지 구해 보시오.",
        "question_en": "When you tried to divide 328 marbles equally among 15 students, a few marbles were in short. Find at least how many more marbles are needed to distribute all the marbles equally.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "15 328 15 [OP_MOD] [OP_SUB]",
        "solution_abst_en": "15 328 15 [OP_MOD] [OP_SUB]",
        "solution_code_ko": "var_a = 15\nvar_b = 328\nvar_c = 15\nvar_d = var_b % var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 328\nvar_c = 15\nvar_d = var_b % var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "4986": {
        "category": "Correspondence",
        "question_ko": "장난감 68개를 14명에게 5개씩 똑같이 나누어 주려고 합니다. 장난감이 모자라지 않도록 하려면 장난감은 몇 개가 더 필요합니까?",
        "question_en": "You want to divide 68 toys equally, 5 each among 14 people. How many more toys do you need to keep them from running out?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "14 5 [OP_MUL] 68 [OP_SUB]",
        "solution_abst_en": "14 5 [OP_MUL] 68 [OP_SUB]",
        "solution_code_ko": "var_a = 14\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 68\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 14\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 68\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "4987": {
        "category": "Possibility",
        "question_ko": "10미만의 짝수들을 모두 한 번씩 이용하여 만들 수 있는 네 자리 수 중 두 번째로 큰 것과 세 번째로 작은 것의 차는?",
        "question_en": "What is the difference between the second largest and the third smallest four-digit numbers that can be formed by using one time of all even numbers less than 10?",
        "answer_ko": "6576",
        "answer_en": "6576",
        "solution_abst_ko": "0 10 1 [OP_SUB] [OP_LIST_EVEN] 4 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "0 10 1 [OP_SUB] [OP_LIST_EVEN] 4 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 0\nvar_b = 10\nvar_c = 1\nvar_d = var_b - var_c\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_d+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_d+1, 2):\n        list_a.append(i)\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 0\nvar_b = 10\nvar_c = 1\nvar_d = var_b - var_c\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_d+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_d+1, 2):\n        list_a.append(i)\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))"
    },
    "4988": {
        "category": "Correspondence",
        "question_ko": "정훈이의 월말평가 시험지가 찢어져 수학 점수를 알 수가 없다. 다른 과목들의 성적은 도덕 82점, 국어 90점, 과학 88점, 사회 84점이다. 평균점수는 88점일때 수학 성적은 몇 점입니까?",
        "question_en": "Jeonghoon's monthly evaluation paper is torn, so he can't find out his math score. The scores for other subjects are 82 points for ethics, 90 points for Korean language, 88 points for science, and 84 points for social studies. What is his math score when the average score is 88?",
        "answer_ko": "96",
        "answer_en": "96",
        "solution_abst_ko": "88 5 [OP_MUL] 82 [OP_SUB] 90 [OP_SUB] 88 [OP_SUB] 84 [OP_SUB]",
        "solution_abst_en": "88 5 [OP_MUL] 82 [OP_SUB] 90 [OP_SUB] 88 [OP_SUB] 84 [OP_SUB]",
        "solution_code_ko": "var_a = 88\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 82\nvar_e = var_c - var_d\nvar_f = 90\nvar_g = var_e - var_f\nvar_h = 88\nvar_i = var_g - var_h\nvar_j = 84\nvar_k = var_i - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 88\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 82\nvar_e = var_c - var_d\nvar_f = 90\nvar_g = var_e - var_f\nvar_h = 88\nvar_i = var_g - var_h\nvar_j = 84\nvar_k = var_i - var_j\nprint(int(var_k))"
    },
    "4989": {
        "category": "Comparison",
        "question_ko": "일정한 빠르기로 1분에 2.1킬로미터(㎞)를 달리는 자동차 A와 4분에 10.5킬로미터(㎞)를 달리는 자동차 B가 있습니다. 목적지까지 빨리 도착하기 위해선 어느 자동차를 타야 하는지 구하시오.",
        "question_en": "Car A travels at a constant speed of 2.1 kilometers (km) in 1 minute, and car B travels at 10.5 kilometers (km) in 4 minutes. Find out which car to take to get to your destination faster.",
        "answer_ko": "B",
        "answer_en": "B",
        "solution_abst_ko": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 2.1 1 [OP_DIV] 10.5 4 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 2.1 1 [OP_DIV] 10.5 4 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2.1\nvar_d = 1\nvar_e = var_c / var_d\nvar_f = 10.5\nvar_g = 4\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2.1\nvar_d = 1\nvar_e = var_c / var_d\nvar_f = 10.5\nvar_g = 4\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "4990": {
        "category": "Geometry",
        "question_ko": "직사각형 가와 정사각형 나의 넓이는 같습니다. 직사각형의 두 변의 길이가 각각 9센티미터(㎝), 16센티미터(㎝)일 때, 정사각형 나의 한 변의 길이는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "The area of the rectangle (a) is equal to the area of the square (b). If the lengths of the two sides of the rectangle (a) are 9 centimeters (cm) and 16 centimeters (cm) respectively, how many centimeters (cm) is the length of one side of the square (b)?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "9 16 [OP_MUL] 1/2 [OP_POW]",
        "solution_abst_en": "9 16 [OP_MUL] 1/2 [OP_POW]",
        "solution_code_ko": "var_a = 9\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nprint(int(var_e))"
    },
    "4991": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이와 석진이는 책을 각각 28권씩 가지고 있었습니다. 정국이는 책을 18권 더 사고 석진이는 책을 11권 더 샀다면, 정국이가 가진 책은 석진이보다 몇 권 더 많습니까?",
        "question_en": "Jungkook and Seokjin each had 28 books. If Jungkook bought 18 more books and Seokjin bought 11 more books, how many more books does Jungkook have than Seokjin?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "28 18 [OP_ADD] 28 11 [OP_ADD] [OP_SUB]",
        "solution_abst_en": "28 18 [OP_ADD] 28 11 [OP_ADD] [OP_SUB]",
        "solution_code_ko": "var_a = 28\nvar_b = 18\nvar_c = var_a + var_b\nvar_d = 28\nvar_e = 11\nvar_f = var_d + var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 28\nvar_b = 18\nvar_c = var_a + var_b\nvar_d = 28\nvar_e = 11\nvar_f = var_d + var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "4992": {
        "category": "Comparison",
        "question_ko": "어떤 두 수로 모두 나누어 떨어지는 수 중에서 21이 가장 작습니다. 두 수의 공배수 중 8번째로 큰 수와 12번째로 큰 수 사이에 있는 수들의 합을 구하시오.",
        "question_en": "21 is the smallest number that is divisible by any two numbers. Find the sum of the numbers between the 8th largest and 12th largest common multiples of the two numbers.",
        "answer_ko": "630",
        "answer_en": "630",
        "solution_abst_ko": "21 8 1 [OP_ADD] [OP_MUL] 21 12 -1 [OP_ADD] [OP_MUL] 21 [OP_LIST_ARANGE] [OP_LIST_SUM]",
        "solution_abst_en": "21 8 1 [OP_ADD] [OP_MUL] 21 12 -1 [OP_ADD] [OP_MUL] 21 [OP_LIST_ARANGE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 21\nvar_b = 8\nvar_c = 1\nvar_d = var_b + var_c\nvar_e = var_a * var_d\nvar_f = 21\nvar_g = 12\nvar_h = -1\nvar_i = var_g + var_h\nvar_j = var_f * var_i\nvar_k = 21\nlist_a = [i for i in range(var_e, var_j + 1, var_k)]\nlist_a = [float(i) for i in list_a]\nvar_l = sum(list_a)\nprint(int(var_l))",
        "solution_code_en": "var_a = 21\nvar_b = 8\nvar_c = 1\nvar_d = var_b + var_c\nvar_e = var_a * var_d\nvar_f = 21\nvar_g = 12\nvar_h = -1\nvar_i = var_g + var_h\nvar_j = var_f * var_i\nvar_k = 21\nlist_a = [i for i in range(var_e, var_j + 1, var_k)]\nlist_a = [float(i) for i in list_a]\nvar_l = sum(list_a)\nprint(int(var_l))"
    },
    "4993": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 2번째로 큰 수와 가장 작은 수로 나눈 나머지는 얼마입니까?",
        "question_en": "Five numbers 10, 11, 12, 13, and 14 are given. What is the remainder if the second largest number is divided by the smallest number?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 2 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MOD]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 2 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MOD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g % var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g % var_i\nprint(int(var_j))"
    },
    "4994": {
        "category": "Comparison",
        "question_ko": "도연이네 반 학생 7명의 키가 161.5센티미터(㎝), 154.3센티미터(㎝), 143.7센티미터(㎝), 160.1센티미터(㎝), 158.0센티미터(㎝), 153.5센티미터(㎝), 147.8센티미터(㎝)일 때, 이 중에서 평균보다 큰 학생 중 가장 작은 학생의 키를 구하시오.",
        "question_en": "The height of the seven students in Doyeon's class is 161.5 centimeters (cm), 154.3 centimeters (cm), 143.7 centimeters (cm), 160.1 centimeters (cm), 158.0 centimeters (cm), 153.5 centimeters (cm), 147.8 centimeters (cm). Find the height of the tallest student among the students who are taller than the average.",
        "answer_ko": "154.30",
        "answer_en": "154.3",
        "solution_abst_ko": "[OP_LIST_SOL] 161.5 154.3 143.7 160.1 158.0 153.5 147.8 [OP_LIST_EOL] [OP_LIST_MEAN] [OP_LIST_MORE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 161.5 154.3 143.7 160.1 158.0 153.5 147.8 [OP_LIST_EOL] [OP_LIST_MEAN] [OP_LIST_MORE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 161.5\nvar_b = 154.3\nvar_c = 143.7\nvar_d = 160.1\nvar_e = 158\nvar_f = 153.5\nvar_g = 147.8\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_h = sum(list_a)/len(list_a)\nlist_b = []\nfor i in list_a:\n    if i > var_h:\n        list_b.append(i)\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nprint('{:.2f}'.format(round(var_j+1e-10,2)))",
        "solution_code_en": "var_a = 161.5\nvar_b = 154.3\nvar_c = 143.7\nvar_d = 160.1\nvar_e = 158\nvar_f = 153.5\nvar_g = 147.8\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_h = sum(list_a)/len(list_a)\nlist_b = []\nfor i in list_a:\n    if i > var_h:\n        list_b.append(i)\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nprint('{:.2f}'.format(round(var_j+1e-10,2)))"
    },
    "4995": {
        "category": "Possibility",
        "question_ko": "서진이네 집에서 축구장까지 도보로 가는 방법은 3가지, 차도가 4가지 있다. 집에서 축구장까지 가는 경우의 수를 구하시오.",
        "question_en": "There are 3 ways to walk from Seojin's house to the soccer field, and 4 ways to drive. Find the number of ways to get from your house to the soccer field.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "3 4 [OP_ADD]",
        "solution_abst_en": "3 4 [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 4\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 4\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "4996": {
        "category": "Possibility",
        "question_ko": "서로 다른 다섯 장의 숫자 카드 중 3장을 뽑아 만들 수 있는 세 자리 자연수의 개수는 얼마입니까? 각 숫자 카드에는 2, 4, 6, 7, 9 가 적혀 있습니다.",
        "question_en": "How many three-digit natural numbers can be formed by drawing three out of five different number cards? Each number card has the numbers 2, 4, 6, 7, and 9 written on it.",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "[OP_LIST_SOL] 2 4 6 7 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 2 4 6 7 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = 6\nvar_d = 7\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = 6\nvar_d = 7\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "4997": {
        "category": "Geometry",
        "question_ko": "어떤 정사각형과 직사각형이 있습니다. 정사각형의 한 변의 길이는 8센티미터(㎝)이고, 직사각형은 한 변의 길이가 10센티미터(㎝), 나머지 한 변의 길이가 5센티미터(㎝)입니다. 이 정사각형과 직사각형의 넓이의 차는 몇 제곱센티미터(㎠)입니까?",
        "question_en": "There are some squares and rectangles. Consider a square has a side of 8 centimeters (cm), and a rectangle has a side of 10 centimeters (cm) and 5 centimeters (cm). What is the difference between the area of this square and the rectangle in square centimeters (cm2)?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "8 2 [OP_POW] 10 5 [OP_MUL] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "8 2 [OP_POW] 10 5 [OP_MUL] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 8\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 10\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = abs(var_g)\nprint(int(var_h))",
        "solution_code_en": "var_a = 8\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 10\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = abs(var_g)\nprint(int(var_h))"
    },
    "4998": {
        "category": "Arithmetic calculation",
        "question_ko": "총 길이가 10.5킬로미터(㎞)인 자전거 코스에서 윤기가 1.5킬로미터(㎞)를 간 후, 3730미터(m)를 또 간다면 남은 코스의 길이는 몇 미터(m)입니까?",
        "question_en": "In a bicycle course with a total length of 10.5 kilometers (km), if Yoongi goes 1.5 kilometers (km) and then goes another 3730 meters (m), how many meters (m) of the course remains?",
        "answer_ko": "5270",
        "answer_en": "5270",
        "solution_abst_ko": "10.5 1000 [OP_MUL] 1.5 1000 [OP_MUL] [OP_SUB] 3730 [OP_SUB]",
        "solution_abst_en": "10.5 1000 [OP_MUL] 1.5 1000 [OP_MUL] [OP_SUB] 3730 [OP_SUB]",
        "solution_code_ko": "var_a = 10.5\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 1.5\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 3730\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10.5\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 1.5\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 3730\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "4999": {
        "category": "Arithmetic calculation",
        "question_ko": "30이하의 자연수 중에서 5의 배수이거나 짝수인 수는 모두 몇 개인지 구하시오.",
        "question_en": "How many natural numbers less than or equal to 30 are multiples of 5 or even?",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "1 30 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] 1 30 [OP_LIST_EVEN] [OP_SET_UNION] [OP_LIST_LEN]",
        "solution_abst_en": "1 30 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] 1 30 [OP_LIST_EVEN] [OP_SET_UNION] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 30\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 1\nvar_f = 30\nlist_c = []\nif var_e%2!=0:\n    for i in range(var_e+1, var_f+1, 2):\n        list_c.append(i)\nelse:\n    for i in range(var_e, var_f+1, 2):\n        list_c.append(i)\nlist_d = list(set(list_b) | set(list_c))\nvar_g = len(list_d)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 30\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 1\nvar_f = 30\nlist_c = []\nif var_e%2!=0:\n    for i in range(var_e+1, var_f+1, 2):\n        list_c.append(i)\nelse:\n    for i in range(var_e, var_f+1, 2):\n        list_c.append(i)\nlist_d = list(set(list_b) | set(list_c))\nvar_g = len(list_d)\nprint(int(var_g))"
    },
    "5000": {
        "category": "Geometry",
        "question_ko": "둘레가 56센티미터(㎝)인 정사각형 안에 원 4개를 맞닿게 그릴 수 있었습니다. 이와 같은 방법으로 이 원과 크기가 같은 원 441개를 그릴 수 있는 정사각형 중 가장 작은 정사각형의 둘레는 몇 센티미터(㎝)입니까?",
        "question_en": "You were able to draw four adjacent circles within a square with a circumference of 56 centimeters (cm). Of the squares that can be drawn in the same way, 441 circles of the same size as this circle, what is the circumference in centimeters (cm) of the smallest square?",
        "answer_ko": "588",
        "answer_en": "588",
        "solution_abst_ko": "56 4 [OP_DIV] 4 1/2 [OP_POW] [OP_DIV] 441 1/2 [OP_POW] [OP_MUL] 4 [OP_MUL]",
        "solution_abst_en": "56 4 [OP_DIV] 4 1/2 [OP_POW] [OP_DIV] 441 1/2 [OP_POW] [OP_MUL] 4 [OP_MUL]",
        "solution_code_ko": "var_a = 56\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = 0.5\nvar_f = var_d ** var_e\nvar_g = var_c / var_f\nvar_h = 441\nvar_i = 0.5\nvar_j = var_h ** var_i\nvar_k = var_g * var_j\nvar_l = 4\nvar_m = var_k * var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 56\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = 0.5\nvar_f = var_d ** var_e\nvar_g = var_c / var_f\nvar_h = 441\nvar_i = 0.5\nvar_j = var_h ** var_i\nvar_k = var_g * var_j\nvar_l = 4\nvar_m = var_k * var_l\nprint(int(var_m))"
    },
    "5001": {
        "category": "Comparison",
        "question_ko": "선풍기 (가), (나), (다), (라)가 틀어져 있습니다. (나)는 (가)보다 바람세기가 세고, (라)는 (가)보다 바람세기가 약합니다. (가)는 (다)보다 바람세기가 약할 때, 가장 약한 바람세기로 틀어져 있는 선풍기는 무엇일까요?",
        "question_en": "Fans A, B, C, D are turned on. B is stronger than A, and D is weaker than A. When A is weaker than C, which fan is turned at the weakest wind speed?",
        "answer_ko": "(라)",
        "answer_en": "D",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) (다) (라) [OP_LIST_EOL] [OP_LIST_SOL] (나) (가) > (가) (다) < (라) (가) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D [OP_LIST_EOL] [OP_LIST_SOL] B A > A C < D A < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nvar_c = '(다)'\nvar_d = '(라)'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '(나)'\nvar_f = '(가)'\nvar_g = '>'\nvar_h = '(가)'\nvar_i = '(다)'\nvar_j = '<'\nvar_k = '(라)'\nvar_l = '(가)'\nvar_m = '<'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'B'\nvar_f = 'A'\nvar_g = '>'\nvar_h = 'A'\nvar_i = 'C'\nvar_j = '<'\nvar_k = 'D'\nvar_l = 'A'\nvar_m = '<'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)"
    },
    "5002": {
        "category": "Comparison",
        "question_ko": "송희는 12일 동안 288쪽의 책을 읽었고, 은주는 9일 동 안 243쪽의 책을 읽었습니다. 하루 동안 누가 더 많이 읽었습니까?",
        "question_en": "Songhee read 288 pages in 12 days, and Eunju read 243 pages in 9 days. Who read more in one day?",
        "answer_ko": "은주",
        "answer_en": "Eunju",
        "solution_abst_ko": "[OP_LIST_SOL] 송희 은주 [OP_LIST_EOL] [OP_LIST_SOL] 288 12 [OP_DIV] 243 9 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Songhee Eunju [OP_LIST_EOL] [OP_LIST_SOL] 288 12 [OP_DIV] 243 9 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '송희'\nvar_b = '은주'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 288\nvar_d = 12\nvar_e = var_c / var_d\nvar_f = 243\nvar_g = 9\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Songhee'\nvar_b = 'Eunju'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 288\nvar_d = 12\nvar_e = var_c / var_d\nvar_f = 243\nvar_g = 9\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "5003": {
        "category": "Possibility",
        "question_ko": "0, 4, 6, 7, 8 중에 한 번씩만 사용하여 만들 수 있는 다섯 자리 수 중에서 가장 큰 수를 구하시오.",
        "question_en": "Find the largest five-digit number that can be formed using 0, 4, 6, 7, and 8 only once.",
        "answer_ko": "87640",
        "answer_en": "87640",
        "solution_abst_ko": "[OP_LIST_SOL] 0 4 6 7 8 [OP_LIST_EOL] 5 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 0 4 6 7 8 [OP_LIST_EOL] 5 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 0\nvar_b = 4\nvar_c = 6\nvar_d = 7\nvar_e = 8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 5\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nprint(int(var_h))",
        "solution_code_en": "var_a = 0\nvar_b = 4\nvar_c = 6\nvar_d = 7\nvar_e = 8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 5\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nprint(int(var_h))"
    },
    "5004": {
        "category": "Comparison",
        "question_ko": "정호네 농장에는 닭과 돼지가 있습니다. 다리 수의 합은 48개이고, 돼지가 9마리 있다면 농장에는 닭이 몇 마리 있습니까?",
        "question_en": "Jeongho's farm has chickens and pigs. If the sum of all the legs is 48, and there are 9 pigs, how many chickens are there on the farm?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "48 4 9 [OP_MUL] [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "48 4 9 [OP_MUL] [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 48\nvar_b = 4\nvar_c = 9\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 48\nvar_b = 4\nvar_c = 9\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "5005": {
        "category": "Comparison",
        "question_ko": "세 사람이 케이크를 먹고 있다. 신영은 1/3, 석기는 1/4, 웅이은 1/5을 먹었다. 케이크를 가장 많이 먹은 사람은?",
        "question_en": "Three people are eating cake. Shinyoung ate 1/3, Seokgi 1/4, and Woong ate 1/5 of it. Who ate the most cake?",
        "answer_ko": "신영",
        "answer_en": "Shinyoung",
        "solution_abst_ko": "[OP_LIST_SOL] 신영 석기 웅이 [OP_LIST_EOL] [OP_LIST_SOL] 1 3 [OP_DIV] 1 4 [OP_DIV] 1 5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Shinyoung Seokgi Woong [OP_LIST_EOL] [OP_LIST_SOL] 1 3 [OP_DIV] 1 4 [OP_DIV] 1 5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '신영'\nvar_b = '석기'\nvar_c = '웅이'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nvar_e = 3\nvar_f = var_d / var_e\nvar_g = 1\nvar_h = 4\nvar_i = var_g / var_h\nvar_j = 1\nvar_k = 5\nvar_l = var_j / var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'Shinyoung'\nvar_b = 'Seokgi'\nvar_c = 'Woong'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nvar_e = 3\nvar_f = var_d / var_e\nvar_g = 1\nvar_h = 4\nvar_i = var_g / var_h\nvar_j = 1\nvar_k = 5\nvar_l = var_j / var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "5006": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 건물 엘리베이터에 1층부터 54층까지 수가 쓰인 버튼이 있습니다. 이 버튼에는 숫자 5가 몇 번 나오는지 구하시오.",
        "question_en": "An elevator in a building has buttons with numbers from the 1st floor to the 54th floor. Find out how many times the number 5 appears on the button.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "1 54 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 5 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 54 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 5 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 54\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 5\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 54\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 5\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))"
    },
    "5007": {
        "category": "Arithmetic calculation",
        "question_ko": "한 바구니에 46개씩 들어있는 자두 바구니 19개와 한 바구니에 170개씩 들어있는 블루베리 몇 바구니가 있습니다. 바구니에 담긴 과일의 개수를 모두 합하면 1894개일 때, 블루베리 바구니는 몇 개입니까?",
        "question_en": "There are 19 boxes with 46 books in each box and several boxes with 170 pencils in each box. If the number of books and pencils is 1894 in total, how many boxes of pencils are there?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "1894 46 19 [OP_MUL] [OP_SUB] 170 [OP_FDIV]",
        "solution_abst_en": "1894 46 19 [OP_MUL] [OP_SUB] 170 [OP_FDIV]",
        "solution_code_ko": "var_a = 1894\nvar_b = 46\nvar_c = 19\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 170\nvar_g = var_e // var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1894\nvar_b = 46\nvar_c = 19\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 170\nvar_g = var_e // var_f\nprint(int(var_g))"
    },
    "5008": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 1000까지의 자연수 중에서 각 자릿수의 합이 11일 때, 가장 큰 수와 가장 작은 수의 차이는 무엇입니까?",
        "question_en": "What is the difference between the largest and smallest natural numbers from 1 to 1000, when the sum of each digit of this number is 11?",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "1 1000 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] 11 [OP_LIST_FIND_NUM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "1 1000 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] 11 [OP_LIST_FIND_NUM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 1\nvar_b = 1000\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_b=[]\nfor i in list_a:\n    var_d = 0\n    i = int(i)\n    while i//10 > 0:\n        var_d = var_d + i%10\n        i = i//10\n    var_d = var_d + i%10\n    list_b.append(var_d)\nvar_e = 11\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 1\nvar_b = 1000\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_b=[]\nfor i in list_a:\n    var_d = 0\n    i = int(i)\n    while i//10 > 0:\n        var_d = var_d + i%10\n        i = i//10\n    var_d = var_d + i%10\n    list_b.append(var_d)\nvar_e = 11\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h - var_j\nprint(int(var_k))"
    },
    "5009": {
        "category": "Correspondence",
        "question_ko": "상철이가 병지에게 딱지를 2개 주었더니 상철이와 병지가 가진 딱지의 차이가 6개입니다. 상철이가 병지에게 딱지를 주기 전에는 둘의 차이가 얼마였는지 구하시오. 단, 병지가 가진 딱지의 개수다 상철이가 가진 개수보다 더 많다.",
        "question_en": "Sang-cheol gave Byeong-ji 2 battle cards, and the difference between Sang-cheol and Byeong-ji was 6. Find the difference between the two before Sang-cheol gave Byeong-ji battle cards. However, the number of battle cards Byeong-ji has is more than the number Sang-cheol has.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "6 2 [OP_SUB] 2 [OP_SUB]",
        "solution_abst_en": "6 2 [OP_SUB] 2 [OP_SUB]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "5010": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 동아리에 여학생이 남학생보다 6명이 더 많다. 동아리 총 인원이 82명 일 때, 여학생이 몇 명인지 구하시오.",
        "question_en": "There are 6 more female students than male students in a club. If the total number of the club is 82, how many female students are there?",
        "answer_ko": "44",
        "answer_en": "44",
        "solution_abst_ko": "82 6 [OP_SUB] 2 [OP_DIV] 6 [OP_ADD]",
        "solution_abst_en": "82 6 [OP_SUB] 2 [OP_DIV] 6 [OP_ADD]",
        "solution_code_ko": "var_a = 82\nvar_b = 6\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 6\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 82\nvar_b = 6\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 6\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "5011": {
        "category": "Geometry",
        "question_ko": "구각형에서 서로 이웃하지 않은 두 꼭짓점을 이은 선분의 개수는 몇 개입니까?",
        "question_en": "How many line segments in a nonagon join any two vertices that are not adjacent to each other?",
        "answer_ko": "27",
        "answer_en": "27",
        "solution_abst_ko": "9 9 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "9 9 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 9\nvar_b = 9\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 9\nvar_b = 9\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "5012": {
        "category": "Comparison",
        "question_ko": "5, 8, 4, 3, 7중에서 2번째로 작은 숫자를 선택합니다.",
        "question_en": "Choose the second smallest number among 5, 8, 4, 3, and 7.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 5 8 4 3 7 [OP_LIST_EOL] 2 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 5 8 4 3 7 [OP_LIST_EOL] 2 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 5\nvar_b = 8\nvar_c = 4\nvar_d = 3\nvar_e = 7\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 8\nvar_c = 4\nvar_d = 3\nvar_e = 7\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nprint(int(var_g))"
    },
    "5013": {
        "category": "Correspondence",
        "question_ko": "A는 한 자리 수입니다. 두 자리 수끼리의 덧셈식 AA+AA=132에서 A를 구하시오.",
        "question_en": "A is a single digit number. Find A from the two-digit addition formula AA+AA=132.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "AA+AA=132 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "AA+AA=132 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'AA+AA=132'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'AA+AA=132'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "5014": {
        "category": "Correspondence",
        "question_ko": "윤기는 어떤 수에 7을 더하려고 합니다. 하지만 실수로 9를 더하였더니 결과는 30이 되었습니다. 바르게 계산한 결과를 구하세요.",
        "question_en": "Yoongi wanted to add 7 to a number but instead added 9 to get 30. Find the correct calculated value.",
        "answer_ko": "28",
        "answer_en": "28",
        "solution_abst_ko": "30 9 [OP_SUB] 7 [OP_ADD]",
        "solution_abst_en": "30 9 [OP_SUB] 7 [OP_ADD]",
        "solution_code_ko": "var_a = 30\nvar_b = 9\nvar_c = var_a - var_b\nvar_d = 7\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 30\nvar_b = 9\nvar_c = var_a - var_b\nvar_d = 7\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "5015": {
        "category": "Arithmetic calculation",
        "question_ko": "네 자리 수 중 3과 5의 공배수는 모두 몇 개 입니까?",
        "question_en": "How many 4-digit numbers are common multiples of 3 and 5?",
        "answer_ko": "600",
        "answer_en": "600",
        "solution_abst_ko": "1000 9999 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "1000 9999 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "5016": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 수에 3.6을 곱하고 2로 나누어야 하는데 잘못하여 3.6으로 나누었더니 2.5가 되었다. 바르게 게산한 값을 구하시오.",
        "question_en": "A certain number should be multiplied by 3.6 and divided by 2, but when I mistakenly divided by 3.6, it became 2.5. Find the correctly calculated value.",
        "answer_ko": "16.20",
        "answer_en": "16.2",
        "solution_abst_ko": "3.6 3.6 2.5 [OP_MUL] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "3.6 3.6 2.5 [OP_MUL] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 3.6\nvar_b = 3.6\nvar_c = 2.5\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 3.6\nvar_b = 3.6\nvar_c = 2.5\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "5017": {
        "category": "Arithmetic calculation",
        "question_ko": "10 분에 15.5킬로미터(㎞) 를 달리는 기차가 46 분 동안 쉬지 않고 같은 빠르기로 달리면 몇 킬로미터(㎞)를 달린 것입니까?",
        "question_en": "If a train that travels 15.5 kilometers (km) in 10 minutes runs at a constant speed without stopping for 46 minutes, how many kilometers (km) will it travel?",
        "answer_ko": "71.30",
        "answer_en": "71.3",
        "solution_abst_ko": "15.5 10 [OP_DIV] 46 [OP_MUL]",
        "solution_abst_en": "15.5 10 [OP_DIV] 46 [OP_MUL]",
        "solution_code_ko": "var_a = 15.5\nvar_b = 10\nvar_c = var_a / var_b\nvar_d = 46\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 15.5\nvar_b = 10\nvar_c = var_a / var_b\nvar_d = 46\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "5018": {
        "category": "Arithmetic calculation",
        "question_ko": "연속하는 5개의 자연수의 합이 60입니다 세번째 수를 구하시오",
        "question_en": "The sum of five consecutive natural numbers is 60. Find the third number.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "60 0 5 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 5 [OP_DIV] 3 1 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "60 0 5 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 5 [OP_DIV] 3 1 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 60\nvar_b = 0\nvar_c = 5\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nlist_a = [i for i in range(var_b, var_e + 1, var_f)]\nlist_a = [float(i) for i in list_a]\nvar_g = sum(list_a)\nvar_h = var_a - var_g\nvar_i = 5\nvar_j = var_h / var_i\nvar_k = 3\nvar_l = 1\nvar_m = var_k - var_l\nvar_n = var_j + var_m\nprint(int(var_n))",
        "solution_code_en": "var_a = 60\nvar_b = 0\nvar_c = 5\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nlist_a = [i for i in range(var_b, var_e + 1, var_f)]\nlist_a = [float(i) for i in list_a]\nvar_g = sum(list_a)\nvar_h = var_a - var_g\nvar_i = 5\nvar_j = var_h / var_i\nvar_k = 3\nvar_l = 1\nvar_m = var_k - var_l\nvar_n = var_j + var_m\nprint(int(var_n))"
    },
    "5019": {
        "category": "Correspondence",
        "question_ko": "수학 선생님이 마지막 문제로 두 자리 수 덧셈식 A7+30=77 을 내줬다. 유나가 정답을 맞췄다고 할 때, 유나가 정답으로 낸 A는 무엇인가요?",
        "question_en": "The math teacher gave us the two-digit addition formula A7+30=77 for the last problem. When Yuna says she got the answer right, what is the A that Yuna gave as the correct answer?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "A7+30=77 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A7+30=77 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A7+30=77'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A7+30=77'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "5020": {
        "category": "Geometry",
        "question_ko": "어떤 정육면체의 겉넓이는 96제곱센티미터(㎠)입니다. 이 정육면체 8개를 이용해 큰 정육면체를 만들었습니다. 만들어진 큰 정육면체의 부피를 구하시오.",
        "question_en": "The surface area of a cube is 96 square centimeters (cm2). I used 8 of these cubes to make a large cube. Find the volume of the large cube made.",
        "answer_ko": "512",
        "answer_en": "512",
        "solution_abst_ko": "96 6 [OP_DIV] 1/2 [OP_POW] 8 2 [OP_DIV] 2 [OP_DIV] [OP_MUL] 3 [OP_POW]",
        "solution_abst_en": "96 6 [OP_DIV] 1/2 [OP_POW] 8 2 [OP_DIV] 2 [OP_DIV] [OP_MUL] 3 [OP_POW]",
        "solution_code_ko": "var_a = 96\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 8\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = 2\nvar_j = var_h / var_i\nvar_k = var_e * var_j\nvar_l = 3\nvar_m = var_k ** var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 96\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 8\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = 2\nvar_j = var_h / var_i\nvar_k = var_e * var_j\nvar_l = 3\nvar_m = var_k ** var_l\nprint(int(var_m))"
    },
    "5021": {
        "category": "Comparison",
        "question_ko": "100보다 작은 자연수 중 4와 6의 공배수를 작은 순서대로 왼쪽부터 썼습니다. 왼쪽에서 7번째에 있는 수는 무엇입니까?",
        "question_en": "Among the natural numbers less than 100, the common multiples of 4 and 6 are written from left in order of magnitude. What is the 7th number from the left?",
        "answer_ko": "84",
        "answer_en": "84",
        "solution_abst_ko": "0 1 [OP_ADD] 100 1 [OP_SUB] 1 [OP_LIST_ARANGE] 4 6 [OP_LCM] [OP_LIST_DIVISIBLE] 7 [OP_LIST_GET]",
        "solution_abst_en": "0 1 [OP_ADD] 100 1 [OP_SUB] 1 [OP_LIST_ARANGE] 4 6 [OP_LCM] [OP_LIST_DIVISIBLE] 7 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 100\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = 4\nvar_i = 6\nvar_j = var_i * var_h / math.gcd(int(var_i), int(var_h))\nlist_b = []\nvar_j = int(var_j)\nfor i in list_a:\n    i = int(i)\n    if i % var_j == 0:\n        list_b.append(i)\nvar_k = 7\nvar_l = list_b[var_k-1]\nprint(int(var_l))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 100\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = 4\nvar_i = 6\nvar_j = var_i * var_h / math.gcd(int(var_i), int(var_h))\nlist_b = []\nvar_j = int(var_j)\nfor i in list_a:\n    i = int(i)\n    if i % var_j == 0:\n        list_b.append(i)\nvar_k = 7\nvar_l = list_b[var_k-1]\nprint(int(var_l))"
    },
    "5022": {
        "category": "Arithmetic calculation",
        "question_ko": "유정이 그린 직선은 31센티미터(㎝)보다 3밀리미터(㎜) 짧습니다. 유정이 그은 직선의 길이를 밀리미터(㎜)로 써보시오",
        "question_en": "The straight line drawn by the Yoojeong is 3 millimeters (mm) shorter than 31 centimeters (cm). Write the length of the straight line drawn by Yoojeong in millimeters (mm).",
        "answer_ko": "307",
        "answer_en": "307",
        "solution_abst_ko": "31 10 [OP_MUL] 3 [OP_SUB]",
        "solution_abst_en": "31 10 [OP_MUL] 3 [OP_SUB]",
        "solution_code_ko": "var_a = 31\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 31\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "5023": {
        "category": "Arithmetic calculation",
        "question_ko": "현수는 사과 농장에서 사과를 수확하고 8상자에 똑같이 나누어 담으려 하였습니다. 그런데 상자가 2개 부족해서 한 상자에 1개씩 사과를 더 담았더니 사과가 4개 남았습니다. 현수가 수확한 사과는 모두 몇 개입니까?",
        "question_en": "Hyunsu harvested apples from the apple farm and tried to divide them equally into 8 boxes. But 8 boxes were not enough, and he needed 2 more boxes. So he put 1 more apple in each box, and now there are 4 apples left. How many apples did Hyunsu harvest?",
        "answer_ko": "40",
        "answer_en": "40",
        "solution_abst_ko": "8 2 [OP_SUB] 4 [OP_ADD] 8 8 2 [OP_SUB] [OP_SUB] [OP_FDIV] 8 [OP_MUL]",
        "solution_abst_en": "8 2 [OP_SUB] 4 [OP_ADD] 8 8 2 [OP_SUB] [OP_SUB] [OP_FDIV] 8 [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = 8\nvar_h = 2\nvar_i = var_g - var_h\nvar_j = var_f - var_i\nvar_k = var_e // var_j\nvar_l = 8\nvar_m = var_k * var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 8\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = 8\nvar_h = 2\nvar_i = var_g - var_h\nvar_j = var_f - var_i\nvar_k = var_e // var_j\nvar_l = 8\nvar_m = var_k * var_l\nprint(int(var_m))"
    },
    "5024": {
        "category": "Arithmetic calculation",
        "question_ko": "주머니 5개에는 구슬이 5개씩 들어 있고, 다른 주머니 1개에는 구슬이 8개 들어 있습니다. 6개의 주머니에 들어 있는 구슬은 모두 몇 개입니까?",
        "question_en": "Five bags each contain 5 marbles, and another bag contains 8 marbles. How many marbles are in all 6 bags?",
        "answer_ko": "33",
        "answer_en": "33",
        "solution_abst_ko": "5 5 [OP_MUL] 1 8 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "5 5 [OP_MUL] 1 8 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 8\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 8\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "5025": {
        "category": "Arithmetic calculation",
        "question_ko": "500보다 큰 7의 배수 중 최소값을 구하시오.",
        "question_en": "Find the smallest multiple of 7 greater than 500.",
        "answer_ko": "504",
        "answer_en": "504",
        "solution_abst_ko": "1 9999 1 [OP_LIST_ARANGE] 500 [OP_LIST_MORE] 7 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "1 9999 1 [OP_LIST_ARANGE] 500 [OP_LIST_MORE] 7 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 500\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nvar_e = 7\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 500\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nvar_e = 7\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[var_f-1]\nprint(int(var_g))"
    },
    "5026": {
        "category": "Possibility",
        "question_ko": "두 수 3과 6으로 만드는 가장 큰 두 자리 수는 얼마입니까? 단, 같은 숫자를 여러 번 쓸 수 없습니다.",
        "question_en": "What is the largest two-digit number made by the two numbers 3 and 6? Note: you cannot use the same number multiple times.",
        "answer_ko": "63",
        "answer_en": "63",
        "solution_abst_ko": "[OP_LIST_SOL] 6 3 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 6 3 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 6\nvar_b = 3\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_e = list_c[-var_d]\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 3\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_e = list_c[-var_d]\nprint(int(var_e))"
    },
    "5027": {
        "category": "Geometry",
        "question_ko": "모서리가 14개이고, 각뿔의 모양을 한 모자가 있습니다. 이 모자의 꼭짓점 개수를 구하시오.",
        "question_en": "There is a hat that has 14 corners and shaped like a pyramid. Find the number of vertices of this hat.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "14 2 [OP_DIV] 1 [OP_ADD]",
        "solution_abst_en": "14 2 [OP_DIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 14\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 14\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "5028": {
        "category": "Geometry",
        "question_ko": "4변의 길이의 합이 50센티미터(㎝)인 직사각형이 있습니다. 이 직사각형의 세로의 길이가 13센티미터(㎝)일 때, 직사각형의 넓이는 몇 제곱센티미터(㎠)입니까?",
        "question_en": "The sum of 4 sides of a rectangle is equal to 50 centimeters (cm). If the length of this rectangle is 13 centimeters (cm), how many square centimeters (cm2) is the area of the rectangle?",
        "answer_ko": "156",
        "answer_en": "156",
        "solution_abst_ko": "50 2 [OP_DIV] 13 [OP_SUB] 13 [OP_MUL]",
        "solution_abst_en": "50 2 [OP_DIV] 13 [OP_SUB] 13 [OP_MUL]",
        "solution_code_ko": "var_a = 50\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 13\nvar_e = var_c - var_d\nvar_f = 13\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 50\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 13\nvar_e = var_c - var_d\nvar_f = 13\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "5029": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 3을 더하고 5를 곱한 뒤 8로 나누었더니 몫이 156이고 나머지가 2였습니다. 어떤 수를 구하시오.",
        "question_en": "When you add 3 to a number, multiply it by 5, and divide it by 8, the quotient is 156 and the remainder is 2. Find the number.",
        "answer_ko": "247",
        "answer_en": "247",
        "solution_abst_ko": "156 8 [OP_MUL] 2 [OP_ADD] 5 [OP_DIV] 3 [OP_SUB]",
        "solution_abst_en": "156 8 [OP_MUL] 2 [OP_ADD] 5 [OP_DIV] 3 [OP_SUB]",
        "solution_code_ko": "var_a = 156\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = var_e / var_f\nvar_h = 3\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 156\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = var_e / var_f\nvar_h = 3\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "5030": {
        "category": "Possibility",
        "question_ko": "기영이와 기철이는 숫자 자석 1, 6, 8로 세 자리 수를 만드는 놀이를 하고 있습니다. 기영이는 만들 수 있는 가장 큰 수를 만들었고, 기철이는 세 번째로 작은 수를 만들었을 때, 기영이과 기철이가 만든 수의 합을 구하시오.",
        "question_en": "Kiyoung and Gicheol are playing a game of making three-digit numbers with number magnets 1, 6, and 8. When Kiyoung made the largest possible number, and Kicheol made the third smallest number, find the sum of the numbers made by Kiyoung and Kicheol.",
        "answer_ko": "1479",
        "answer_en": "1479",
        "solution_abst_ko": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))"
    },
    "5031": {
        "category": "Possibility",
        "question_ko": "6과 9의 공통된 세 자리 배수 중 각 자리가 4이하 0 이상이고 , 각 자리의 숫자가 모두 다른 수는 총 몇 가지인가?",
        "question_en": "How many common three-digit multiples of 6 and 9 are 4 or less and 0 or more and different in each digit?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 6 9 [OP_LCM] [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 6 9 [OP_LCM] [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 6\nvar_h = 9\nvar_i = var_h * var_g / math.gcd(int(var_h), int(var_g))\nlist_c = []\nvar_i = int(var_i)\nfor i in list_b:\n    i = int(i)\n    if i % var_i == 0:\n        list_c.append(i)\nvar_j = len(list_c)\nprint(int(var_j))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 6\nvar_h = 9\nvar_i = var_h * var_g / math.gcd(int(var_h), int(var_g))\nlist_c = []\nvar_i = int(var_i)\nfor i in list_b:\n    i = int(i)\n    if i % var_i == 0:\n        list_c.append(i)\nvar_j = len(list_c)\nprint(int(var_j))"
    },
    "5032": {
        "category": "Comparison",
        "question_ko": "흰둥이, 검둥이, 누렁이, 점박이 이렇게 4마리의 강아지가 있습니다. 검둥이는 흰둥이보다 무겁고 누렁이보다 가볍습니다. 점박이는 누렁이보다 무겁습니다. 가장 가벼운 강아지는 어느 강아지입니까?",
        "question_en": "There are 4 puppies: White, Black, Yellowy, and Spotted. Black is heavier than White and lighter than Yellowy. Spotted is heavier than Yellowy. Which puppy is the lightest?",
        "answer_ko": "흰둥이",
        "answer_en": "White",
        "solution_abst_ko": "[OP_LIST_SOL] 흰둥이 검둥이 누렁이 점박이 [OP_LIST_EOL] [OP_LIST_SOL] 검둥이 흰둥이 > 검둥이 누렁이 < 점박이 누렁이 > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] White Black Yellowy Spotted [OP_LIST_EOL] [OP_LIST_SOL] Black White > Black Yellowy < Spotted Yellowy > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '흰둥이'\nvar_b = '검둥이'\nvar_c = '누렁이'\nvar_d = '점박이'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '검둥이'\nvar_f = '흰둥이'\nvar_g = '>'\nvar_h = '검둥이'\nvar_i = '누렁이'\nvar_j = '<'\nvar_k = '점박이'\nvar_l = '누렁이'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)",
        "solution_code_en": "var_a = 'White'\nvar_b = 'Black'\nvar_c = 'Yellowy'\nvar_d = 'Spotted'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'Black'\nvar_f = 'White'\nvar_g = '>'\nvar_h = 'Black'\nvar_i = 'Yellowy'\nvar_j = '<'\nvar_k = 'Spotted'\nvar_l = 'Yellowy'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)"
    },
    "5033": {
        "category": "Possibility",
        "question_ko": "숫자 카드 1, 6, 8를 한 번씩 모두 사용하여 가장 작은 세 자리 수와 세 번째로 작은 세 자리 수의 합을 구하시오.",
        "question_en": "Using the number cards 1, 6, and 8 all once, find the sum of the smallest three-digit number and the third smallest three-digit number.",
        "answer_ko": "786",
        "answer_en": "786",
        "solution_abst_ko": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 3 [OP_LIST_GET] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 3 [OP_LIST_GET] [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = 3\nvar_h = list_b[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = 3\nvar_h = list_b[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))"
    },
    "5034": {
        "category": "Arithmetic calculation",
        "question_ko": "X는 10개씩 2묶음과 낱개가 6개인 수이고, Y는 10개씩 4묶음과 낱개가 1개인 수입니다. X와 Y의 합을 구하시오.",
        "question_en": "X is the number of 2 groups of 10 and 6 units, and Y is the number of 4 groups of 10 and 1 unit. Find the sum of X and Y.",
        "answer_ko": "67",
        "answer_en": "67",
        "solution_abst_ko": "10 2 [OP_MUL] 6 [OP_ADD] 10 4 [OP_MUL] 1 [OP_ADD] [OP_ADD]",
        "solution_abst_en": "10 2 [OP_MUL] 6 [OP_ADD] 10 4 [OP_MUL] 1 [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c + var_d\nvar_f = 10\nvar_g = 4\nvar_h = var_f * var_g\nvar_i = 1\nvar_j = var_h + var_i\nvar_k = var_e + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 10\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c + var_d\nvar_f = 10\nvar_g = 4\nvar_h = var_f * var_g\nvar_i = 1\nvar_j = var_h + var_i\nvar_k = var_e + var_j\nprint(int(var_k))"
    },
    "5035": {
        "category": "Possibility",
        "question_ko": "정국, 지민, 윤기 중에서 중복을 허용하여 두 사람을 선택하려고 합니다. 선택할 수 있는 경우는 모두 몇 가지 입니까?",
        "question_en": "Among Jungkook, Jimin, and Yoongi, we want to choose two people by allowing duplicates. How many options are there in all?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 지민 윤기 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Jimin Yoongi [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '지민'\nvar_c = '윤기'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = var_d + var_e\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = 2\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j / (i+1)\nprint(int(var_j))",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Jimin'\nvar_c = 'Yoongi'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = var_d + var_e\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = 2\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j / (i+1)\nprint(int(var_j))"
    },
    "5036": {
        "category": "Possibility",
        "question_ko": "정국, 지민, 석진, 태형, 남준 5명의 학생 중에서 대표 1명과 부대표 1명을 뽑을 때, 선출하는 방법은 모두 몇 가지인가?",
        "question_en": "When selecting one representative and one vice-president from among the five students, Jungkook, Jimin, Seokjin, Taehyung, and Namjoon, how many ways are there to select them?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "5 2 [OP_PERM]",
        "solution_abst_en": "5 2 [OP_PERM]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))"
    },
    "5037": {
        "category": "Arithmetic calculation",
        "question_ko": "두 자루에 (가), (나)에 담겨 있는 구슬은 72개입니다. (가) 자루에 담긴 구슬이 42개일 때, (가) 자루에 담긴 사과는 (나) 자루에 담긴 사과보다 몇 개 더 많습니까?",
        "question_en": "There are 72 marbles in the two bags, (a) and (b). If there are 42 marbles in sack (A), how many more marbles are in sack (A) than in sack (B)?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "42 72 42 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "42 72 42 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 42\nvar_b = 72\nvar_c = 42\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 42\nvar_b = 72\nvar_c = 42\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "5038": {
        "category": "Arithmetic calculation",
        "question_ko": "혁수는 어제 하루 고기를 지난달에 2.6킬로그램(㎏)의 고기를 먹었고, 오늘은 5.98킬로그램(㎏)의 고기를 먹었습니다. 혁수가 이틀 동안 먹은 고기는 모두 몇 킬로그램(㎏)입니까?",
        "question_en": "Hyuksu ate 2.6 kilograms (kg) of meat yesterday, and 5.98 kilograms (kg) of meat today. How many kilograms (kg) of meat did Hyuksu eat in two days?",
        "answer_ko": "8.58",
        "answer_en": "8.58",
        "solution_abst_ko": "2.6 5.98 [OP_ADD]",
        "solution_abst_en": "2.6 5.98 [OP_ADD]",
        "solution_code_ko": "var_a = 2.6\nvar_b = 5.98\nvar_c = var_a + var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 2.6\nvar_b = 5.98\nvar_c = var_a + var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "5039": {
        "category": "Geometry",
        "question_ko": "다섯 개의 각으로 이루어진 도형의 모든 각의 크기가 같고, 이 도형의 둘레가 23.4센티미터(㎝)라면 한 변의 길이는 몇 센티미터(㎝)일지 구하시오.",
        "question_en": "If all five angles of a figure are the same and the perimeter of the figure is 23.4 centimeters (cm), find how many centimeters (cm) is the length of one side of the figure.",
        "answer_ko": "4.68",
        "answer_en": "4.68",
        "solution_abst_ko": "23.4 5 [OP_DIV]",
        "solution_abst_en": "23.4 5 [OP_DIV]",
        "solution_code_ko": "var_a = 23.4\nvar_b = 5\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 23.4\nvar_b = 5\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "5040": {
        "category": "Arithmetic calculation",
        "question_ko": "두 권이 한 세트로 된 책이 있습니다. 이 책을 3세트 사고 21000원을 냈습니다. 세트를 구성하는 한 권의 값이 다른 한 권의 값보다 300원 더 비싸다면 값이 싼 책은 얼마입니까?",
        "question_en": "There are two books in one set. I bought 3 sets of this book and paid 21,000 won. If one book in the set costs 300 won more than the other, how much is the cheaper book?",
        "answer_ko": "3350",
        "answer_en": "3350",
        "solution_abst_ko": "21000 3 [OP_DIV] 300 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "21000 3 [OP_DIV] 300 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 21000\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 300\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 21000\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 300\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "5041": {
        "category": "Correspondence",
        "question_ko": "36에 어떤 수를 더해야 할 것을 잘못하여 63에 어떤 수를 더했더니 70이 되었습니다. 바르게 계산하면 얼마인지 구하시오.",
        "question_en": "You made the mistake of adding a number to 36, so when you added the number to 63, you got 70. How much is it if you calculate it correctly?",
        "answer_ko": "43",
        "answer_en": "43",
        "solution_abst_ko": "36 70 63 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "36 70 63 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 36\nvar_b = 70\nvar_c = 63\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 36\nvar_b = 70\nvar_c = 63\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "5042": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 6으로 나누었더니 몫이 124, 나머지가 4가 되었습니다. 어떤 수에 24를 더하고 8로 나눈 결과를 구하시오.",
        "question_en": "When a number is divided by 6, the quotient is 124 and the remainder is 4. What is the result of adding 24 to the number and dividing it by 8?",
        "answer_ko": "96.50",
        "answer_en": "96.5",
        "solution_abst_ko": "124 6 [OP_MUL] 4 [OP_ADD] 24 [OP_ADD] 8 [OP_DIV]",
        "solution_abst_en": "124 6 [OP_MUL] 4 [OP_ADD] 24 [OP_ADD] 8 [OP_DIV]",
        "solution_code_ko": "var_a = 124\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 24\nvar_g = var_e + var_f\nvar_h = 8\nvar_i = var_g / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 124\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 24\nvar_g = var_e + var_f\nvar_h = 8\nvar_i = var_g / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "5043": {
        "category": "Correspondence",
        "question_ko": "1반 학생들에게 2명씩 짝을 지어주었더니 8개의 짝이 생겼다. 1반 학생들에게 4명씩 조를 짜라고 한다면 몇 개의 조가 생기는가?",
        "question_en": "When the students in class 1 were paired with two students, there were eight pairs. If you ask the students in class 1 to form groups of four, how many groups will form?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "8 2 [OP_MUL] 4 [OP_DIV]",
        "solution_abst_en": "8 2 [OP_MUL] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 8\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "5044": {
        "category": "Comparison",
        "question_ko": "태형이는 집에 345번째로 들어갔고, 석진이는 태형이 앞으로 110명보다 더 먼저 집에 들어갔습니다. 석진이는 몇 번째로 집에 들어갔습니까?",
        "question_en": "Taehyung entered the house for the 345th place, and Seokjin entered the house before Taehyung by 110 people. What place did Seokjin take?",
        "answer_ko": "234",
        "answer_en": "234",
        "solution_abst_ko": "345 110 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "345 110 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 345\nvar_b = 110\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 345\nvar_b = 110\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "5045": {
        "category": "Comparison",
        "question_ko": "정국에는 6 곱하기 3만큼 사과를 모았고, 윤기는 4개, 유나는 5개의 사과를 모았습니다. 누가 가장 사과를 적게 가지고 있습니까?",
        "question_en": "Jungkook collected 6 times 3 apples, Yoongi collected 4 apples, and Yuna collected 5 apples. Who has the fewest apples?",
        "answer_ko": "윤기",
        "answer_en": "Yoongi",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 윤기 유나 [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_MUL] 4 5 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Yoongi Yuna [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_MUL] 4 5 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '윤기'\nvar_c = '유나'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 6\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = 4\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Yoongi'\nvar_c = 'Yuna'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 6\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = 4\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "5046": {
        "category": "Comparison",
        "question_ko": "석진이는 시험에서 8번째로 점수를 잘 받았고, 태형이는 그 다음으로 점수를 잘 받았습니다. 태형이는 몇 번째로 점수를 잘 받았습니까?",
        "question_en": "Seokjin placed 8th on a test, and Taehyung ranked right below Seokjin. Find out the rank of Taehyung's score in ordinal number. ",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "8 1 [OP_ADD]",
        "solution_abst_en": "8 1 [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 8\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "5047": {
        "category": "Correspondence",
        "question_ko": "어떤 소수를 1000배 한 후, 소수점을 왼쪽으로 두 칸 옮기면 12.5가 됩니다. 원래의 소수를 구하시오.",
        "question_en": "After multiplying a decimal by 1000, moving the decimal two places to the left equals 12.5. Find the original decimal.",
        "answer_ko": "1.25",
        "answer_en": "1.25",
        "solution_abst_ko": "12.5 10 2 [OP_POW] [OP_MUL] 1000 [OP_DIV]",
        "solution_abst_en": "12.5 10 2 [OP_POW] [OP_MUL] 1000 [OP_DIV]",
        "solution_code_ko": "var_a = 12.5\nvar_b = 10\nvar_c = 2\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 1000\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 12.5\nvar_b = 10\nvar_c = 2\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 1000\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "5048": {
        "category": "Possibility",
        "question_ko": "숫자 카드 6, 2, 5를 한 번씩 모두 사용하여 만든 가장 큰 세 자리 수와 가장 작은 세 자리 수의 합을 구하시오.",
        "question_en": "Find the sum of the largest three-digit number and the smallest three-digit number made by using the number cards 6, 2, and 5 all once.",
        "answer_ko": "654",
        "answer_en": "654",
        "solution_abst_ko": "[OP_LIST_SOL] 6 2 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] [OP_LIST_POP] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 6 2 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] [OP_LIST_POP] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 1\nlist_d=list_a.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 1\nlist_d=list_a.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))"
    },
    "5049": {
        "category": "Comparison",
        "question_ko": "유나는 달리기 시합에서 6등을 했고, 민영이는 유나가 결승선을 넘은 후 5번째로 결승선을 넘었습니다. 유나의 등수는 몇 등입니까?",
        "question_en": "Yuna placed 6th in the running event, and Min-Young came in as the 5th person after Yuna crossed the finish line. What is Min-Young's rank?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "6 5 [OP_ADD]",
        "solution_abst_en": "6 5 [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "5050": {
        "category": "Correspondence",
        "question_ko": "66 에서 어떤 수를 빼고 21 을 더해야 할 것을 66 에 어떤 수를 더했더니 93 이 되었습니다. 바르게 계산하면 얼마입니까?",
        "question_en": " We need to subtract a number from 66 and add 21, but we accidently added this number to 66 and 93 came out. How much do you get when you calculate correctly? ",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "66 93 66 [OP_SUB] [OP_SUB] 21 [OP_ADD]",
        "solution_abst_en": "66 93 66 [OP_SUB] [OP_SUB] 21 [OP_ADD]",
        "solution_code_ko": "var_a = 66\nvar_b = 93\nvar_c = 66\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nvar_f = 21\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 66\nvar_b = 93\nvar_c = 66\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nvar_f = 21\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "5051": {
        "category": "Correspondence",
        "question_ko": "-0.4의 역수가 A이고 +5/2의 역수가 B이면 3/A+2/B의 역수를 찾으십시오.",
        "question_en": "If the reciprocal of -0.4 is A and the reciprocal of +5/2 is B, find the reciprocal of 3/A+2/B.",
        "answer_ko": "0.26",
        "answer_en": "0.26",
        "solution_abst_ko": "1 3 1 -0.4 [OP_DIV] [OP_DIV] 2 1 5/2 [OP_DIV] [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_abst_en": "1 3 1 -0.4 [OP_DIV] [OP_DIV] 2 1 5/2 [OP_DIV] [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 1\nvar_d = -0.4\nvar_e = var_c / var_d\nvar_f = var_b / var_e\nvar_g = 2\nvar_h = 1\nvar_i = 2.5\nvar_j = var_h / var_i\nvar_k = var_g / var_j\nvar_l = var_f + var_k\nvar_m = var_a / var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 1\nvar_d = -0.4\nvar_e = var_c / var_d\nvar_f = var_b / var_e\nvar_g = 2\nvar_h = 1\nvar_i = 2.5\nvar_j = var_h / var_i\nvar_k = var_g / var_j\nvar_l = var_f + var_k\nvar_m = var_a / var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))"
    },
    "5052": {
        "category": "Geometry",
        "question_ko": "어떤 정육면체의 한 면의 넓이가 64제곱센티미터(㎠)일 때, 이 정육면체의 부피는 몇 세제곱센티미터(㎤)입니까?",
        "question_en": "If the area of one side of a cube is 64 square centimeters (cm2), what is the volume of this cube in cubic centimeters (cm3)?",
        "answer_ko": "512",
        "answer_en": "512",
        "solution_abst_ko": "64 1/2 [OP_POW] 3 [OP_POW]",
        "solution_abst_en": "64 1/2 [OP_POW] 3 [OP_POW]",
        "solution_code_ko": "var_a = 64\nvar_b = 0.5\nvar_c = var_a ** var_b\nvar_d = 3\nvar_e = var_c ** var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 64\nvar_b = 0.5\nvar_c = var_a ** var_b\nvar_d = 3\nvar_e = var_c ** var_d\nprint(int(var_e))"
    },
    "5053": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 19를 더했더니 47이 되었습니다. 어떤 수를 구하시오.",
        "question_en": "When you add 19 to a number, you get 47. Find the number.",
        "answer_ko": "28",
        "answer_en": "28",
        "solution_abst_ko": "47 19 [OP_SUB]",
        "solution_abst_en": "47 19 [OP_SUB]",
        "solution_code_ko": "var_a = 47\nvar_b = 19\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 47\nvar_b = 19\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "5054": {
        "category": "Arithmetic calculation",
        "question_ko": "책 한 권을 모두 읽는 데 4일이 걸렸다. 첫째 날에는 전체의 1/2, 둘째 날에는 전체의 1/4, 셋째 날에는 전체의 1/6, 넷째 날에는 20쪽을 읽었다. 이 책의 전체 쪽수를 구하여라",
        "question_en": "It took me 4 days to read an entire book. I read 1/2 of the total on the first day, 1/4 of the total on the second day, 1/6 of the total on the third day, and 20 pages on the fourth day. Find the total number of pages of this book.",
        "answer_ko": "240",
        "answer_en": "240",
        "solution_abst_ko": "20 1 1/2 1/4 [OP_ADD] 1/6 [OP_ADD] [OP_SUB] [OP_DIV]",
        "solution_abst_en": "20 1 1/2 1/4 [OP_ADD] 1/6 [OP_ADD] [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 20\nvar_b = 1\nvar_c = 0.5\nvar_d = 0.25\nvar_e = var_c + var_d\nvar_f = 0.16666666666666666\nvar_g = var_e + var_f\nvar_h = var_b - var_g\nvar_i = var_a / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))",
        "solution_code_en": "var_a = 20\nvar_b = 1\nvar_c = 0.5\nvar_d = 0.25\nvar_e = var_c + var_d\nvar_f = 0.16666666666666666\nvar_g = var_e + var_f\nvar_h = var_b - var_g\nvar_i = var_a / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))"
    },
    "5055": {
        "category": "Comparison",
        "question_ko": "강아지의 무게는 4.56킬로그램(㎏)이고 고양이의 무게는 462그램(g)의 10배입니다. 강아지와 고양이 중 더 무거운 동물은 무엇입니까?",
        "question_en": "A dog weighs 4.56 kilograms (kg) and a cat weighs 10 times 462 grams (g). Which animal is heavier, a dog or a cat?",
        "answer_ko": "고양이",
        "answer_en": "cat",
        "solution_abst_ko": "[OP_LIST_SOL] 강아지 고양이 [OP_LIST_EOL] [OP_LIST_SOL] 4.56 462 10 [OP_MUL] 1000 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] dog cat [OP_LIST_EOL] [OP_LIST_SOL] 4.56 462 10 [OP_MUL] 1000 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '강아지'\nvar_b = '고양이'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4.56\nvar_d = 462\nvar_e = 10\nvar_f = var_d * var_e\nvar_g = 1000\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'dog'\nvar_b = 'cat'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4.56\nvar_d = 462\nvar_e = 10\nvar_f = var_d * var_e\nvar_g = 1000\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "5056": {
        "category": "Arithmetic calculation",
        "question_ko": "연속하는 두 자연수의 합이 39일 때, 두 자연수 중에 제일 큰 수를 구하시오.",
        "question_en": "If the sum of two consecutive natural numbers is 39, find the largest of the two natural numbers.",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "39 1 [OP_ADD] 2 [OP_DIV]",
        "solution_abst_en": "39 1 [OP_ADD] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 39\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 39\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "5057": {
        "category": "Geometry",
        "question_ko": "예쁜 타일이 있다. 타일은 평행사변형의 모양으로, 각 변의 길이가 18센티미터(㎝), 12센티미터(㎝)이다. 타일의 둘레를 구하라.",
        "question_en": "There is a pretty tile. The tile is in the shape of a parallelogram, with each side measuring 18 centimeters (cm) and 12 centimeters (cm). Find the perimeter of the tile.",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "18 12 [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "18 12 [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 18\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 18\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "5058": {
        "category": "Possibility",
        "question_ko": "주사위를 2번 던져서 나온 눈의 합이 8이 되도록 하는 경우의 수를 구하시오.",
        "question_en": "Find the number of ways to throw a dice twice so that the sum of the results is 8.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "1 6 1 [OP_LIST_ARANGE] 2 [OP_LIST_GET_PRODUCT] [OP_LIST_NUM2SUM] 8 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 6 1 [OP_LIST_ARANGE] 2 [OP_LIST_GET_PRODUCT] [OP_LIST_NUM2SUM] 8 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 6\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 8\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 6\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 8\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))"
    },
    "5059": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 2번째로 큰 수를 2번째로 작은 수로 나눈 몫은 얼마입니까?",
        "question_en": "There are five numbers 10, 11, 12, 13, and 14. What is the quotient of the second largest number divided by the second smallest number?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_FDIV]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_FDIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g // var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g // var_i\nprint(int(var_j))"
    },
    "5060": {
        "category": "Arithmetic calculation",
        "question_ko": "아버지께서 사오신 귤 27개 중 18개를 은지가 먹었습니다. 남은 귤의 수는 몇 개입니까?",
        "question_en": "Eunji ate 18 of the 27 tangerines her father bought. How many tangerines are left?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "27 18 [OP_SUB]",
        "solution_abst_en": "27 18 [OP_SUB]",
        "solution_code_ko": "var_a = 27\nvar_b = 18\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 27\nvar_b = 18\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "5061": {
        "category": "Comparison",
        "question_ko": "20명의 학생들이 버스를 기다리고 있습니다. 정국이는 윤기 바로 앞에 왔고, 정국이보다 늦게 온 사람은 11명이라면 윤기보다 먼저 온 사람들은 몇 명입니까?",
        "question_en": "20 students are waiting for the bus. If Jungkook came right before Yoongi, and there are 11 people who came after Jungkook, how many people came before Yoongi?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "20 11 [OP_SUB] 1 [OP_ADD] 1 [OP_SUB]",
        "solution_abst_en": "20 11 [OP_SUB] 1 [OP_ADD] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 1\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 1\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "5062": {
        "category": "Correspondence",
        "question_ko": "비커 안에 액체가 들어있다. 그런데 액체에 먼지가 들어가서 액체를 5밀리리터(㎖)를 덜어내었더니 비커 안의 용액이 35밀리리터(㎖)가 남았다. 만약 비커에 용액을 덜어내지 않고 비커 안의 용액을 다른 5개의 컵에 똑같이 나누어 부었다면 한컵에 몇 밀리리터(㎖)가 들어갔을지 구하시오.",
        "question_en": "The beaker is containing liquid. Dust got into the liquid so I removed 5 milliliters (ml) of the liquid, and there remained 35 milliliters (ml) of the solution in the beaker. Find how many milliliters (ml) would have been in one cup if the solution in the beaker had been not removed and equally poured into 5 different cups.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "35 5 [OP_ADD] 5 [OP_DIV]",
        "solution_abst_en": "35 5 [OP_ADD] 5 [OP_DIV]",
        "solution_code_ko": "var_a = 35\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 35\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "5063": {
        "category": "Geometry",
        "question_ko": "가로가 3센티미터(㎝) , 세로가 4 센티미터(㎝) , 높이가 5센티미터(㎝) 인 직육면체의 전개도를 그렸을 때, 전개도가 차지하는 면적을 구하시오.",
        "question_en": "Find the area of a planar figure of a cuboid that is 3 centimeters (cm) wide, 4 centimeters (cm) long, and 5 centimeters (cm) high.",
        "answer_ko": "94",
        "answer_en": "94",
        "solution_abst_ko": "3 4 [OP_MUL] 3 5 [OP_MUL] 4 5 [OP_MUL] [OP_ADD] [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "3 4 [OP_MUL] 3 5 [OP_MUL] 4 5 [OP_MUL] [OP_ADD] [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = 4\nvar_h = 5\nvar_i = var_g * var_h\nvar_j = var_f + var_i\nvar_k = var_c + var_j\nvar_l = 2\nvar_m = var_k * var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 3\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = 4\nvar_h = 5\nvar_i = var_g * var_h\nvar_j = var_f + var_i\nvar_k = var_c + var_j\nvar_l = 2\nvar_m = var_k * var_l\nprint(int(var_m))"
    },
    "5064": {
        "category": "Arithmetic calculation",
        "question_ko": "백의 자리 숫자가 2이고 일의 자리 숫자가 7인 세 자리 수 중에서 가장 큰 수와 가장 작은 수의 합을 구하시오.",
        "question_en": "Find the sum of the largest and smallest three-digit numbers with 2 in the hundreds and 7 in the ones.",
        "answer_ko": "504",
        "answer_en": "504",
        "solution_abst_ko": "[OP_LIST_SOL] 2 A 7 [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 2 A 7 [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 'A'\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nans_dict = dict()\nvar_d = str(var_d)\nlist_b = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_d) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_b.append(new_elem)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 2\nvar_b = 'A'\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nans_dict = dict()\nvar_d = str(var_d)\nlist_b = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_d) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_b.append(new_elem)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))"
    },
    "5065": {
        "category": "Correspondence",
        "question_ko": "예은이네 반 전체 학생의 2/9는 혈액형이 A형이고, 예은이네 반 전체 학생의 2/5는 B형입니다. A형인 학생이 10명일 때 B형인 학생은 몇 명인지 구해 보시오.",
        "question_en": "2/9 of all students in Yeeun's class are blood type A, and 2/5 of all students in Yeeun's class are type B. If there are 10 students with type A, how many students with type B are there?",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "10 2/9 [OP_DIV] 2/5 [OP_MUL]",
        "solution_abst_en": "10 2/9 [OP_DIV] 2/5 [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 0.2222222222222222\nvar_c = var_a / var_b\nvar_d = 0.4\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 0.2222222222222222\nvar_c = var_a / var_b\nvar_d = 0.4\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "5066": {
        "category": "Geometry",
        "question_ko": "가로 4센티미터(㎝), 세로 3센티미터(㎝), 높이 3센티미터(㎝)인 직육면체 모양의 물건의 모든 면에 파란색 페인트를 칠했다. 이 물건을 모두 동일한 크기의 정육면체 36개로 잘라냈다. 2개의 면에만 페인트가 칠해져있는 조각은 몇 개일까?",
        "question_en": "All sides of a cuboid-shaped object measuring 4 centimeters (cm) in width, 3 centimeters (cm) in length, and 3 centimeters (cm) in height was painted blue. This figure was cut into 36 cubes, all of the same size. How many pieces have paint on only two sides?",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "4 2 [OP_SUB] 3 2 [OP_SUB] [OP_ADD] 3 2 [OP_SUB] [OP_ADD] 4 [OP_MUL]",
        "solution_abst_en": "4 2 [OP_SUB] 3 2 [OP_SUB] [OP_ADD] 3 2 [OP_SUB] [OP_ADD] 4 [OP_MUL]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = var_c + var_f\nvar_h = 3\nvar_i = 2\nvar_j = var_h - var_i\nvar_k = var_g + var_j\nvar_l = 4\nvar_m = var_k * var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = var_c + var_f\nvar_h = 3\nvar_i = 2\nvar_j = var_h - var_i\nvar_k = var_g + var_j\nvar_l = 4\nvar_m = var_k * var_l\nprint(int(var_m))"
    },
    "5067": {
        "category": "Comparison",
        "question_ko": "키가 작은 순서대로 학생들이 줄을 섰습니다. 호석이는 3번째인 남준이보다 키가 크지만 5번째인 윤기보다는 키가 작습니다. 호석이는 몇 번째로 키가 작습니까?",
        "question_en": "Students lined up in ascending order according to their heights. Hoseok is taller than Namjoon, who is standing in the 3rd place, but shorter than Yoongi, who is standing in the 5th place. How tall is Hoseok? Answer in ordinal number.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "3 5 [OP_ADD] 2 [OP_FDIV]",
        "solution_abst_en": "3 5 [OP_ADD] 2 [OP_FDIV]",
        "solution_code_ko": "var_a = 3\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 3\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "5068": {
        "category": "Comparison",
        "question_ko": "민영, 민주, 민기, 민지가 우유를 하나씩 먹었습니다. 우유곽의 밑에는 숫자가 적혀 있었습니다. 민영이의 숫자는 21, 민주의 숫자는 민영이보다 9 작았고 민기의 숫자는 민영이보다 17 컸습니다. 민영이와 민주의 숫자를 합한 것에다 민기의 숫자를 빼면 민지 숫자에 5를 뺀 것과 같을 때, 민지 우유에 적혀 있던 수는 얼마입니까?",
        "question_en": "Min-young, Min-ju, Min-gi, and Min-ji each drank milk, and realized there was a number written on the bottom of the milk carton. Min-young's number was 21, Min-ju's number was 9 less than Min-young's, and Min-gi's number was 17 more than Min-young's. When the sum of Min-young's and Min-ju's numbers minus Min-gi's number is equal to Min-ji's number minus 5, what is the number written on Min-ji's milk?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "21 21 9 [OP_SUB] [OP_ADD] 21 9 [OP_SUB] 17 [OP_ADD] [OP_SUB] 5 [OP_ADD]",
        "solution_abst_en": "21 21 9 [OP_SUB] [OP_ADD] 21 9 [OP_SUB] 17 [OP_ADD] [OP_SUB] 5 [OP_ADD]",
        "solution_code_ko": "var_a = 21\nvar_b = 21\nvar_c = 9\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 21\nvar_g = 9\nvar_h = var_f - var_g\nvar_i = 17\nvar_j = var_h + var_i\nvar_k = var_e - var_j\nvar_l = 5\nvar_m = var_k + var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 21\nvar_b = 21\nvar_c = 9\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 21\nvar_g = 9\nvar_h = var_f - var_g\nvar_i = 17\nvar_j = var_h + var_i\nvar_k = var_e - var_j\nvar_l = 5\nvar_m = var_k + var_l\nprint(int(var_m))"
    },
    "5069": {
        "category": "Possibility",
        "question_ko": "흰색 구슬, 검은색 구슬, 보라색 구슬, 초록색 구슬, 빨간색 구슬이 1개씩 있습니다. 이 구슬 중 서로 다른 2개의 구슬을 고르는 방법은 모두 몇 가지입니까?",
        "question_en": "There are 1 white marble, 1 black marble, 1 purple marble, 1 green marble and 1 red marble. How many different ways can there be to choose 2 different marbles?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "[OP_LIST_SOL] 흰색 검은색 보라색 초록색 빨간색 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] white black purple green red [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '흰색'\nvar_b = '검은색'\nvar_c = '보라색'\nvar_d = '초록색'\nvar_e = '빨간색'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h / (i+1)\nprint(int(var_h))",
        "solution_code_en": "var_a = 'white'\nvar_b = 'black'\nvar_c = 'purple'\nvar_d = 'green'\nvar_e = 'red'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h / (i+1)\nprint(int(var_h))"
    },
    "5070": {
        "category": "Arithmetic calculation",
        "question_ko": "8과 12의 모든 공약수의 합을 구하시오.",
        "question_en": "Find the sum of all common divisors of 8 and 12.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "8 [OP_LIST_GET_DIVISOR] 12 [OP_LIST_GET_DIVISOR] [OP_SET_INTERSECT] [OP_LIST_SUM]",
        "solution_abst_en": "8 [OP_LIST_GET_DIVISOR] 12 [OP_LIST_GET_DIVISOR] [OP_SET_INTERSECT] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 8\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 12\nlist_b = []\nnum_sqrt = int(math.sqrt(var_b))\nfor i in range(1, num_sqrt+1):\n    if var_b % i == 0:\n        list_b.append(i)\n        list_b.append(int(var_b/i))\nlist_b = sorted(set(list_b))\nlist_c = list(set(list_a) & set(list_b))\nlist_c = [float(i) for i in list_c]\nvar_c = sum(list_c)\nprint(int(var_c))",
        "solution_code_en": "var_a = 8\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 12\nlist_b = []\nnum_sqrt = int(math.sqrt(var_b))\nfor i in range(1, num_sqrt+1):\n    if var_b % i == 0:\n        list_b.append(i)\n        list_b.append(int(var_b/i))\nlist_b = sorted(set(list_b))\nlist_c = list(set(list_a) & set(list_b))\nlist_c = [float(i) for i in list_c]\nvar_c = sum(list_c)\nprint(int(var_c))"
    },
    "5071": {
        "category": "Correspondence",
        "question_ko": "다른 두 자연수 A,B가 있습니다. A를 13으로 나누면 나머지가 B이고 몫이 33입니다. B를 가장 크게 만드는 A를 구하세요.",
        "question_en": "Consider A and B are two other natural numbers. If A divides by 13 is 33 with a remainder of B, find A that makes B the largest.",
        "answer_ko": "441",
        "answer_en": "441",
        "solution_abst_ko": "13 33 [OP_MUL] 12 [OP_ADD]",
        "solution_abst_en": "13 33 [OP_MUL] 12 [OP_ADD]",
        "solution_code_ko": "var_a = 13\nvar_b = 33\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 13\nvar_b = 33\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "5072": {
        "category": "Correspondence",
        "question_ko": "백의 자리까지 AB19를 올림하면 7300이 됩니다. 이 AB19를 십의 자리까지 버림한 값을 구하시오.",
        "question_en": "AB19 rounded up to the hundreds place gives 7300. Find the value obtained by rounding down AB19 to the tens place.",
        "answer_ko": "7210",
        "answer_en": "7210",
        "solution_abst_ko": "AB19 [OP_GEN_POSSIBLE_LIST] 7300 100 [OP_SUB] [OP_LIST_MORE] 7300 [OP_LIST_LESS_EQUAL] AB19 A [OP_LIST_FIND_UNK] 1000 [OP_MUL] AB19 B [OP_LIST_FIND_UNK] 100 [OP_MUL] [OP_ADD] 19 [OP_ADD] 2 [OP_FLOOR]",
        "solution_abst_en": "AB19 [OP_GEN_POSSIBLE_LIST] 7300 100 [OP_SUB] [OP_LIST_MORE] 7300 [OP_LIST_LESS_EQUAL] AB19 A [OP_LIST_FIND_UNK] 1000 [OP_MUL] AB19 B [OP_LIST_FIND_UNK] 100 [OP_MUL] [OP_ADD] 19 [OP_ADD] 2 [OP_FLOOR]",
        "solution_code_ko": "var_a = 'AB19'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 7300\nvar_c = 100\nvar_d = var_b - var_c\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nvar_e = 7300\nlist_c = []\nfor i in list_b:\n    if i <= var_e:\n        list_c.append(i)\nvar_f = 'AB19'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nvar_i = 1000\nvar_j = var_h * var_i\nvar_k = 'AB19'\nvar_l = 'B'\nvar_k = str(var_k)\nvar_l = str(var_l)\nunk_idx = var_k.index(var_l)\nvar_m = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_m = int(elem[unk_idx])\nvar_n = 100\nvar_o = var_m * var_n\nvar_p = var_j + var_o\nvar_q = 19\nvar_r = var_p + var_q\nvar_s = 2\nvar_t=int((var_r//(10**(var_s-1)))*10**(var_s-1))\n\nprint(int(var_t))",
        "solution_code_en": "var_a = 'AB19'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 7300\nvar_c = 100\nvar_d = var_b - var_c\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nvar_e = 7300\nlist_c = []\nfor i in list_b:\n    if i <= var_e:\n        list_c.append(i)\nvar_f = 'AB19'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nvar_i = 1000\nvar_j = var_h * var_i\nvar_k = 'AB19'\nvar_l = 'B'\nvar_k = str(var_k)\nvar_l = str(var_l)\nunk_idx = var_k.index(var_l)\nvar_m = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_m = int(elem[unk_idx])\nvar_n = 100\nvar_o = var_m * var_n\nvar_p = var_j + var_o\nvar_q = 19\nvar_r = var_p + var_q\nvar_s = 2\nvar_t=int((var_r//(10**(var_s-1)))*10**(var_s-1))\n\nprint(int(var_t))"
    },
    "5073": {
        "category": "Geometry",
        "question_ko": "어떤 정삼각형의 둘레의 길이는 가로가 125센티미터(㎝)이고 세로가 115센티미터(㎝)인 어떤 직사각형의 네 변의 길이의 합과 같다. 어떤 달팽이가 1초에 1센티미터씩 나아간다고 한다면, 정삼각형의 한 변의 길이만큼 나아가기 위해서는 몇 초가 걸리겠는가?",
        "question_en": "The perimeter of an equilateral triangle is the same as the sum of four sides of an rectangle which is 125 centimeters (cm) wide and 115 centimeters (cm) long. If a snail moves one centimeter (cm) per second, how many seconds does it take to move forward by the length of one side of this equilateral triangle?",
        "answer_ko": "160",
        "answer_en": "160",
        "solution_abst_ko": "125 115 [OP_ADD] 2 [OP_MUL] 3 [OP_DIV]",
        "solution_abst_en": "125 115 [OP_ADD] 2 [OP_MUL] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 125\nvar_b = 115\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 3\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 125\nvar_b = 115\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 3\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "5074": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 소수의 소수점을 오른쪽으로 두 자리 옮겼더니 원래보다 3.7만큼 더 커졌습니다. 원래의 소수를 구하시오.",
        "question_en": "Moving a decimal point two places to the right makes a certain number 3.7 larger than it should be. Find what the original decimal number is.",
        "answer_ko": "0.04",
        "answer_en": "0.04",
        "solution_abst_ko": "3.7 10 2 [OP_POW] 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "3.7 10 2 [OP_POW] 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 3.7\nvar_b = 10\nvar_c = 2\nvar_d = var_b ** var_c\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_a / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 3.7\nvar_b = 10\nvar_c = 2\nvar_d = var_b ** var_c\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_a / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "5075": {
        "category": "Possibility",
        "question_ko": "3, 9, 5, 8 중에서 서로 다른 숫자 2개를 뽑아 만들 수 있는 가장 큰 두 자리 수에 남은 두 수를 차례로 더하면 얼마입니까?",
        "question_en": "What is the largest two-digit number that can be formed by drawing two different numbers from 3, 9, 5, and 8 and then adding the remaining two numbers?",
        "answer_ko": "106",
        "answer_en": "106",
        "solution_abst_ko": "[OP_LIST_SOL] 3 9 5 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_NUM2LIST] [OP_LIST_SUM] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 3 9 5 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_NUM2LIST] [OP_LIST_SUM] [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 9\nvar_c = 5\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nlist_e = []\nvar_i = int(var_i)\nwhile var_i//10 > 0:\n    list_e.append(var_i%10)\n    var_i = var_i//10\nlist_e.append(var_i%10)\nlist_e = list_e[::-1]\nlist_e = [float(i) for i in list_e]\nvar_j = sum(list_e)\nvar_k = var_g + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 3\nvar_b = 9\nvar_c = 5\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nlist_e = []\nvar_i = int(var_i)\nwhile var_i//10 > 0:\n    list_e.append(var_i%10)\n    var_i = var_i//10\nlist_e.append(var_i%10)\nlist_e = list_e[::-1]\nlist_e = [float(i) for i in list_e]\nvar_j = sum(list_e)\nvar_k = var_g + var_j\nprint(int(var_k))"
    },
    "5076": {
        "category": "Comparison",
        "question_ko": "(가), (나), (다), (라), (마) 5마리의 개가 있다. (가) 개는 (다) 개보다 작다. (라) 개는 (나) 개보다 크다. 또한 (라)개는 (가) 개보다 작다. (나) 개가 (마) 개보다 클 경우 가장 큰 개는 누구인가?",
        "question_en": "There are five dogs: A, B, C, D, and E. A dog is smaller than C dog. D dog is bigger than B dog. Also, D dog is smaller than A dog. If B dog is bigger than E dog, which is the biggest dog?",
        "answer_ko": "(다)",
        "answer_en": "C",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) (다) (라) (마) [OP_LIST_EOL] [OP_LIST_SOL] (라) (나) > (라) (가) < (나) (마) > (가) (다) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D E [OP_LIST_EOL] [OP_LIST_SOL] D B > D A < B E > A C < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nvar_c = '(다)'\nvar_d = '(라)'\nvar_e = '(마)'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = '(라)'\nvar_g = '(나)'\nvar_h = '>'\nvar_i = '(라)'\nvar_j = '(가)'\nvar_k = '<'\nvar_l = '(나)'\nvar_m = '(마)'\nvar_n = '>'\nvar_o = '(가)'\nvar_p = '(다)'\nvar_q = '<'\nlist_b= []\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_r = 1\nvar_s = list_c[var_r-1]\nprint(var_s)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 'D'\nvar_g = 'B'\nvar_h = '>'\nvar_i = 'D'\nvar_j = 'A'\nvar_k = '<'\nvar_l = 'B'\nvar_m = 'E'\nvar_n = '>'\nvar_o = 'A'\nvar_p = 'C'\nvar_q = '<'\nlist_b= []\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_r = 1\nvar_s = list_c[var_r-1]\nprint(var_s)"
    },
    "5077": {
        "category": "Arithmetic calculation",
        "question_ko": "스카이 콩콩은 떨어진 높이의 1/10만큼 튀어오릅니다. 15미터(m) 높이에서 떨어진다면 세 번째로 튀어 오른 공의 높이를 소수 둘째자리에서 반올림하면 몇 미터(m)인지 구하시오.",
        "question_en": "A ball bounces 1/10 of the height it is dropped. If the ball falls from a height of 15 meters (m), find out how many meters (m) it is if you round the height of the third jump from the second decimal place.",
        "answer_ko": "0.02",
        "answer_en": "0.02",
        "solution_abst_ko": "15 1/10 3 [OP_POW] [OP_MUL] 2 [OP_ROUND]",
        "solution_abst_en": "15 1/10 3 [OP_POW] [OP_MUL] 2 [OP_ROUND]",
        "solution_code_ko": "var_a = 15\nvar_b = 0.1\nvar_c = 3\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = round(float(var_e)+1e-10, var_f)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 15\nvar_b = 0.1\nvar_c = 3\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = round(float(var_e)+1e-10, var_f)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "5078": {
        "category": "Arithmetic calculation",
        "question_ko": "1.84, 5.23, 2.41, 8.64의 총합은 얼마입니까?",
        "question_en": "What is the sum of 1.84, 5.23, 2.41, and 8.64?",
        "answer_ko": "18.12",
        "answer_en": "18.12",
        "solution_abst_ko": "1.84 5.23 [OP_ADD] 2.41 [OP_ADD] 8.64 [OP_ADD]",
        "solution_abst_en": "1.84 5.23 [OP_ADD] 2.41 [OP_ADD] 8.64 [OP_ADD]",
        "solution_code_ko": "var_a = 1.84\nvar_b = 5.23\nvar_c = var_a + var_b\nvar_d = 2.41\nvar_e = var_c + var_d\nvar_f = 8.64\nvar_g = var_e + var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 1.84\nvar_b = 5.23\nvar_c = var_a + var_b\nvar_d = 2.41\nvar_e = var_c + var_d\nvar_f = 8.64\nvar_g = var_e + var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "5079": {
        "category": "Geometry",
        "question_ko": "넓이가 54.3제곱센티미터(㎠)인 직사각형의 사진이 있습니다. 가로가 6센티미터(㎝) 일 때, 세로는 몇 센티미터(㎝) 입니까?",
        "question_en": "There is a picture of a rectangle with an area of 54.3 square centimeters (cm2). If the width is 6 centimeters (cm), how many centimeters (cm) is the length?",
        "answer_ko": "9.05",
        "answer_en": "9.05",
        "solution_abst_ko": "54.3 6 [OP_DIV]",
        "solution_abst_en": "54.3 6 [OP_DIV]",
        "solution_code_ko": "var_a = 54.3\nvar_b = 6\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 54.3\nvar_b = 6\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "5080": {
        "category": "Geometry",
        "question_ko": "길이가 32센티미터(㎝) 인 끈으로 가장 큰 정사각형을 만들었습니다. 만든 정사각형의 넓이는 몇 제곱센티미터(㎠) 입니까?",
        "question_en": "The largest square was made with a piece of string 32 centimeters (cm) long. What is the area of the square created in square centimeters (cm2)?",
        "answer_ko": "64",
        "answer_en": "64",
        "solution_abst_ko": "32 4 [OP_DIV] 2 [OP_POW]",
        "solution_abst_en": "32 4 [OP_DIV] 2 [OP_POW]",
        "solution_code_ko": "var_a = 32\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 32\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint(int(var_e))"
    },
    "5081": {
        "category": "Correspondence",
        "question_ko": "A2468B은 한 자리 수 A, B로 이루어져 있습니다. A2468B가 55로 나누어 떨어질 때 이 수가 될 수 있는 수는 모두 몇 개입니까?",
        "question_en": "A2468B consists of single digits A and B. How many possible numbers are there when A2468B is divisible by 55?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "A2468B [OP_GEN_POSSIBLE_LIST] 55 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "A2468B [OP_GEN_POSSIBLE_LIST] 55 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 'A2468B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 55\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A2468B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 55\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))"
    },
    "5082": {
        "category": "Comparison",
        "question_ko": "하은이는 1/2미터(m) 길이의 색 테이프를 가지고 있고, 민경이는 2/3미터(m)의 색 테이프를 가지고 있습니다. 둘 중 누구의 색 테이프가 더 긴지 구하시오.",
        "question_en": "Haeun has a 1/2 meter (m) long colored tape, and Minkyung has a 2/3 meters (m) long colored tape. Find whose color tape is longer.",
        "answer_ko": "민경",
        "answer_en": "Minkyung",
        "solution_abst_ko": "[OP_LIST_SOL] 하은 민경 [OP_LIST_EOL] [OP_LIST_SOL] 1/2 2/3 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Haeun Minkyung [OP_LIST_EOL] [OP_LIST_SOL] 1/2 2/3 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '하은'\nvar_b = '민경'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.5\nvar_d = 0.6666666666666666\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Haeun'\nvar_b = 'Minkyung'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.5\nvar_d = 0.6666666666666666\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "5083": {
        "category": "Geometry",
        "question_ko": "밑면의 가로가 4센티미터(㎝)이고, 세로가 가로보다 6센티미터(㎝) 길고, 높이가 세로보다 5센티미터(㎝) 긴 직육면체가 있습니다. 이 직육면체의 겉넓이는 몇 제곱센티미터입니까?",
        "question_en": "There is a rectangular parallelepiped whose width of base is 4 centimeters (cm), length 6 centimeters (cm) longer than width, and height 5 centimeters (cm) longer than length. What is the surface area of this cuboid in square centimeters (cm2)?",
        "answer_ko": "500",
        "answer_en": "500",
        "solution_abst_ko": "4 4 6 [OP_ADD] [OP_MUL] 4 4 6 [OP_ADD] [OP_ADD] 4 6 5 [OP_ADD] [OP_ADD] [OP_MUL] [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "4 4 6 [OP_ADD] [OP_MUL] 4 4 6 [OP_ADD] [OP_ADD] 4 6 5 [OP_ADD] [OP_ADD] [OP_MUL] [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 4\nvar_b = 4\nvar_c = 6\nvar_d = var_b + var_c\nvar_e = var_a * var_d\nvar_f = 4\nvar_g = 4\nvar_h = 6\nvar_i = var_g + var_h\nvar_j = var_f + var_i\nvar_k = 4\nvar_l = 6\nvar_m = 5\nvar_n = var_l + var_m\nvar_o = var_k + var_n\nvar_p = var_j * var_o\nvar_q = var_e + var_p\nvar_r = 2\nvar_s = var_q * var_r\nprint(int(var_s))",
        "solution_code_en": "var_a = 4\nvar_b = 4\nvar_c = 6\nvar_d = var_b + var_c\nvar_e = var_a * var_d\nvar_f = 4\nvar_g = 4\nvar_h = 6\nvar_i = var_g + var_h\nvar_j = var_f + var_i\nvar_k = 4\nvar_l = 6\nvar_m = 5\nvar_n = var_l + var_m\nvar_o = var_k + var_n\nvar_p = var_j * var_o\nvar_q = var_e + var_p\nvar_r = 2\nvar_s = var_q * var_r\nprint(int(var_s))"
    },
    "5084": {
        "category": "Comparison",
        "question_ko": "지석의 배낭 무게는 1.49킬로그램(㎏), 미호의 배낭 무게는 9/20킬로그램(㎏)이다. 누구의 배낭이 더 가벼울까요?",
        "question_en": "Jiseok's backpack weighs 1.49 kilograms (kg), and Miho's backpack weighs 9/20 kilograms (kg). Whose backpack is lighter?",
        "answer_ko": "미호",
        "answer_en": "Miho",
        "solution_abst_ko": "[OP_LIST_SOL] 지석 미호 [OP_LIST_EOL] [OP_LIST_SOL] 1.49 9 20 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jiseok Miho [OP_LIST_EOL] [OP_LIST_SOL] 1.49 9 20 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '지석'\nvar_b = '미호'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.49\nvar_d = 9\nvar_e = 20\nvar_f = var_d / var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Jiseok'\nvar_b = 'Miho'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.49\nvar_d = 9\nvar_e = 20\nvar_f = var_d / var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "5085": {
        "category": "Comparison",
        "question_ko": "태형이와 반 친구들 10명이 서 있을 때, 태형이 왼쪽에 선 학생이 5명입니다. 오른쪽에는 몇 명의 학생이 서 있습니까?",
        "question_en": "When Taehyung and 10 of his classmates are standing, Taehyung has 5 students standing to his left. How many students are standing to his right?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "10 5 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "10 5 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "5086": {
        "category": "Arithmetic calculation",
        "question_ko": "닭은 오리 수의 5배이고, 토끼는 오리보다 12마리 더 적습니다. 토끼가 4마리일 때, 닭, 오리, 토끼는 모두 몇 마리입니까?",
        "question_en": "There are 5 times as many chickens as ducks, and 12 fewer rabbits than ducks. If there are 4 rabbits, what is the total number of chickens, ducks and rabbits are there?",
        "answer_ko": "100",
        "answer_en": "100",
        "solution_abst_ko": "4 4 12 [OP_ADD] [OP_ADD] 5 4 12 [OP_ADD] [OP_MUL] [OP_ADD]",
        "solution_abst_en": "4 4 12 [OP_ADD] [OP_ADD] 5 4 12 [OP_ADD] [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 4\nvar_c = 12\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nvar_f = 5\nvar_g = 4\nvar_h = 12\nvar_i = var_g + var_h\nvar_j = var_f * var_i\nvar_k = var_e + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 4\nvar_b = 4\nvar_c = 12\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nvar_f = 5\nvar_g = 4\nvar_h = 12\nvar_i = var_g + var_h\nvar_j = var_f * var_i\nvar_k = var_e + var_j\nprint(int(var_k))"
    },
    "5087": {
        "category": "Possibility",
        "question_ko": "숫자 1, 6, 8을 한 번씩 모두 골라 세 자리수를 만들고, 그만큼 돈을 준다고 합니다. 이 때, 받을 수 있는 두 번째로 큰 돈과 세 번째로 작은 돈의 합을 구하시오.",
        "question_en": "Pick the numbers 1, 6, and 8 once to make a three-digit number and pay that amount. In this case, find the sum of the second largest and third smallest money that can be received.",
        "answer_ko": "1434",
        "answer_en": "1434",
        "solution_abst_ko": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))"
    },
    "5088": {
        "category": "Arithmetic calculation",
        "question_ko": "원형의 산책로를 따라 30미터(m) 간격으로 나무가 심어져 있습니다. 산책로의 길이가 1킬로미터(㎞) 200미터(m)라면, 나무는 모두 몇 그루 심어진 것입니까?",
        "question_en": "Trees are planted at intervals of 30 meters (m) along the circular promenade. If the length of the trail is 1 kilometer (km) and 200 meters (m), how many trees were planted in all?",
        "answer_ko": "40",
        "answer_en": "40",
        "solution_abst_ko": "1 1000 [OP_MUL] 200 [OP_ADD] 30 [OP_DIV]",
        "solution_abst_en": "1 1000 [OP_MUL] 200 [OP_ADD] 30 [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 200\nvar_e = var_c + var_d\nvar_f = 30\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 200\nvar_e = var_c + var_d\nvar_f = 30\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "5089": {
        "category": "Geometry",
        "question_ko": "한별은 한 변의 길이가 8.5센티미터(㎝)인 정사각형 색종이를 3.2장 갖고 있습니다. 이 색종이를 빈틈없이 붙일 때 얻을 수 있는 넓이를 구하시오.",
        "question_en": "Hanbyeol has 3.2 pieces of square colored paper with a side length of 8.5 cm. Find the area he could get when gluing this colored paper together without any gap.",
        "answer_ko": "231.20",
        "answer_en": "231.2",
        "solution_abst_ko": "8.5 2 [OP_POW] 3.2 [OP_MUL]",
        "solution_abst_en": "8.5 2 [OP_POW] 3.2 [OP_MUL]",
        "solution_code_ko": "var_a = 8.5\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 3.2\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 8.5\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 3.2\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "5090": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 5를 뺐더니 2가 되었습니다. 어떤 수에 3을 더하면 얼마입니까?",
        "question_en": "When you subtract 5 from a number, the answer is 2. What will you get from the number plus 3?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "2 5 [OP_ADD] 3 [OP_ADD]",
        "solution_abst_en": "2 5 [OP_ADD] 3 [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "5091": {
        "category": "Correspondence",
        "question_ko": "1.87 에 어떤 수를 곱하였더니 231.88 이 되었습니다. 어떤 수를 25 로 나눈 몫은 얼마인지 구하시오.",
        "question_en": "You get 231.88 when you multiply 1.87 by a particular number. What is the quotient of that particular number divided by 25?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "231.88 1.87 [OP_DIV] 25 [OP_FDIV]",
        "solution_abst_en": "231.88 1.87 [OP_DIV] 25 [OP_FDIV]",
        "solution_code_ko": "var_a = 231.88\nvar_b = 1.87\nvar_c = var_a / var_b\nvar_d = 25\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 231.88\nvar_b = 1.87\nvar_c = var_a / var_b\nvar_d = 25\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "5092": {
        "category": "Geometry",
        "question_ko": "사각뿔대의 면의 개수는?",
        "question_en": "What is the number of faces of a truncated quadrangular pyramid?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "4 2 [OP_ADD]",
        "solution_abst_en": "4 2 [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "5093": {
        "category": "Arithmetic calculation",
        "question_ko": "참나무가 56그루 있습니다. 은행나무는 배나무보다 18그루 적고, 은행나무는 단풍나무보다 12그루 많습니다. 단풍나무는 모두 몇 그루입니까?",
        "question_en": "There are 56 oak trees. There are 18 fewer ginkgo trees than pear trees, and 12 more ginkgo trees than maple trees. How many maple trees are there in all?",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "56 18 [OP_SUB] 12 [OP_SUB]",
        "solution_abst_en": "56 18 [OP_SUB] 12 [OP_SUB]",
        "solution_code_ko": "var_a = 56\nvar_b = 18\nvar_c = var_a - var_b\nvar_d = 12\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 56\nvar_b = 18\nvar_c = var_a - var_b\nvar_d = 12\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "5094": {
        "category": "Comparison",
        "question_ko": "노란색 테이프 길이가 0.309미터(m) 이고, 빨간색 테이프의 길이가 48.2센티미터(㎝)입니다. 어느 색의 길이가 더 깁니까?",
        "question_en": "The length of the yellow tape is 0.309 meters (m), and the length of the red tape is 48.2 centimeters (cm). Which color is longer?",
        "answer_ko": "빨간색",
        "answer_en": "red",
        "solution_abst_ko": "[OP_LIST_SOL] 노란색 빨간색 [OP_LIST_EOL] [OP_LIST_SOL] 0.309 48.2 100 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] yellow red [OP_LIST_EOL] [OP_LIST_SOL] 0.309 48.2 100 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '노란색'\nvar_b = '빨간색'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.309\nvar_d = 48.2\nvar_e = 100\nvar_f = var_d * var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'yellow'\nvar_b = 'red'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.309\nvar_d = 48.2\nvar_e = 100\nvar_f = var_d * var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "5095": {
        "category": "Arithmetic calculation",
        "question_ko": "과자 19개를 9일동안 나누어 먹으려고 합니다. 하루에 먹어야 할 양은 얼마인가요?",
        "question_en": "I'm going to eat 19 cookies for 9 days. How many cookies should I eat per day?",
        "answer_ko": "2.11",
        "answer_en": "2.11",
        "solution_abst_ko": "19 9 [OP_DIV]",
        "solution_abst_en": "19 9 [OP_DIV]",
        "solution_code_ko": "var_a = 19\nvar_b = 9\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 19\nvar_b = 9\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "5096": {
        "category": "Comparison",
        "question_ko": "학생 25명이 한 줄로 서 있습니다. 유나의 뒤에 9명이 서 있습니다. 유나의 앞에 서 있는 학생은 몇 명입니까?",
        "question_en": "25 students stand in a line. There are 9 people behind Yuna. How many students are standing in front of Yuna?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "25 9 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "25 9 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 25\nvar_b = 9\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 25\nvar_b = 9\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "5097": {
        "category": "Possibility",
        "question_ko": "3, 5, 6, 7 총 4장의 수 카드 중 2장을 사용하여 두 자리 수를 만들려고 합니다. 만들 수 있는 7의 배수 중 가장 큰 수는 무엇인가요?",
        "question_en": "You are going to use 2 of your 4 number cards 3, 5, 6, 7 to create a two-digit number. What is the largest multiple of 7 that can be made?",
        "answer_ko": "63",
        "answer_en": "63",
        "solution_abst_ko": "[OP_LIST_SOL] 3 5 6 7 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 7 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 3 5 6 7 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 7 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 3\nvar_b = 5\nvar_c = 6\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 7\nlist_c = []\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nvar_g = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_h = list_d[-var_g]\nprint(int(var_h))",
        "solution_code_en": "var_a = 3\nvar_b = 5\nvar_c = 6\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 7\nlist_c = []\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nvar_g = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_h = list_d[-var_g]\nprint(int(var_h))"
    },
    "5098": {
        "category": "Arithmetic calculation",
        "question_ko": "두꺼비가 연못 안에 12마리, 연못 밖에 6마리 있습니다. 두꺼비는 모두 몇 마리 입니까?",
        "question_en": "There are 12 toads in the pond and 6 outside the pond. How many toads are there in all?",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "12 6 [OP_ADD]",
        "solution_abst_en": "12 6 [OP_ADD]",
        "solution_code_ko": "var_a = 12\nvar_b = 6\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 12\nvar_b = 6\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "5099": {
        "category": "Geometry",
        "question_ko": "삼각형 1개와 육각형 3개가 있습니다. 도형들의 꼭짓점 수를 모두 더하면 몇 개입니까?",
        "question_en": "There are 1 triangle and 3 hexagons. What is the sum of all vertices of the shapes?",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "3 6 3 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "3 6 3 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 6\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 3\nvar_b = 6\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "5100": {
        "category": "Arithmetic calculation",
        "question_ko": "18센티미터(㎝)인 색 테이프 3개를 같은 길이씩 겹쳐서 이어 붙였더니 50.5센티미터(㎝)가 나왔습니다. 몇 센티미터(㎝)씩 겹쳐서 이어 붙였는지 답을 구해 보세요.",
        "question_en": "When three 18 centimeters (cm) long colored tapes were overlapped and attached at the same length, it became 50.5 centimeters (cm) long. Find the answer by how many centimeters (cm) were overlapped and connected.",
        "answer_ko": "1.75",
        "answer_en": "1.75",
        "solution_abst_ko": "18 3 [OP_MUL] 50.5 [OP_SUB] 3 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "18 3 [OP_MUL] 50.5 [OP_SUB] 3 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 18\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 50.5\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 18\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 50.5\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "5101": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 9/5, 3/5, 1.7, 3/2, 0.4, 9/10가 있습니다. 이 중에서 1보다 작은 수는 모두 몇 개입니까?",
        "question_en": "There are six numbers 9/5, 3/5, 1.7, 3/2, 0.4, and 9/10. How many of these numbers are less than 1?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 9/5 3/5 1.7 3/2 0.4 9/10 [OP_LIST_EOL] 1 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 9/5 3/5 1.7 3/2 0.4 9/10 [OP_LIST_EOL] 1 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1.8\nvar_b = 0.6\nvar_c = 1.7\nvar_d = 1.5\nvar_e = 0.4\nvar_f = 0.9\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 1\nlist_b = []\nfor i in list_a:\n    if i < var_g:\n        list_b.append(i)\nvar_h = len(list_b)\nprint(int(var_h))",
        "solution_code_en": "var_a = 1.8\nvar_b = 0.6\nvar_c = 1.7\nvar_d = 1.5\nvar_e = 0.4\nvar_f = 0.9\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 1\nlist_b = []\nfor i in list_a:\n    if i < var_g:\n        list_b.append(i)\nvar_h = len(list_b)\nprint(int(var_h))"
    },
    "5102": {
        "category": "Arithmetic calculation",
        "question_ko": "연지가 달리기를 하려고 합니다. 연지는 3미터(m)를 달리는데 4초가 걸리고 출발선부터 도착점까지의 거리가 0.09킬로미터(㎞)라면 연지가 출발선부터 도착점까지 달리는데 걸린 시간은 모두 몇 초인지 구하세요.",
        "question_en": "Yeonji wants to run. If it takes 4 seconds for Yeonji to run 3 meters (m) and the distance from the starting line to the finish point is 0.09 km (km), find how many seconds it took Yeonji to run from the starting line to the finish line.",
        "answer_ko": "124",
        "answer_en": "124",
        "solution_abst_ko": "0.09 1000 [OP_MUL] 3 [OP_ADD] 3 [OP_DIV] 4 [OP_MUL]",
        "solution_abst_en": "0.09 1000 [OP_MUL] 3 [OP_ADD] 3 [OP_DIV] 4 [OP_MUL]",
        "solution_code_ko": "var_a = 0.09\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = 4\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 0.09\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = 4\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "5103": {
        "category": "Geometry",
        "question_ko": "종이끈을 만들기 위해 6장의 종이를 7센티미터(㎝) 씩 겹치게 두고 풀을 칠했습니다. 이 종이는 한 변의 길이가 30센티미터(㎝)인 정사각형 모양입니다. 만들어진 끈의 넓이를 구하시오.",
        "question_en": "To make a paper string, 6 sheets of paper were overlapped by 7 centimeters (cm) and glued. This piece of paper has the shape of a square with each side measuring 30 centimeters (cm). Find the area of the string made.",
        "answer_ko": "4350",
        "answer_en": "4350",
        "solution_abst_ko": "30 6 [OP_MUL] 7 6 1 [OP_SUB] [OP_MUL] [OP_SUB] 30 [OP_MUL]",
        "solution_abst_en": "30 6 [OP_MUL] 7 6 1 [OP_SUB] [OP_MUL] [OP_SUB] 30 [OP_MUL]",
        "solution_code_ko": "var_a = 30\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = 6\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_c - var_h\nvar_j = 30\nvar_k = var_i * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 30\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = 6\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_c - var_h\nvar_j = 30\nvar_k = var_i * var_j\nprint(int(var_k))"
    },
    "5104": {
        "category": "Correspondence",
        "question_ko": "준형이는 여행 중 첫째날에는 전체 거리의 1/5를 이동하였고, 둘째날에는 나머지의 거리의 3/4을 이동하였습니다. 셋째날에 1킬로미터(㎞) 500미터(m)를 이동하고 여행을 마무리했다면 준형이가 여행 중 이동한 전체 거리는 몇 킬로미터(㎞)인지 구하시오.",
        "question_en": "Junhyung traveled 1/5 of the total distance on the first day of the trip, and 3/4 of the remaining distance on the second day. If the trip was completed after moving 1 kilometer (km) and 500 meters (m) on the third day, what is the total distance of Junhyung's trip in kilometers (km)?",
        "answer_ko": "7.50",
        "answer_en": "7.5",
        "solution_abst_ko": "1 500 1000 [OP_DIV] [OP_ADD] 1 3/4 [OP_SUB] [OP_DIV] 1 1/5 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "1 500 1000 [OP_DIV] [OP_ADD] 1 3/4 [OP_SUB] [OP_DIV] 1 1/5 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 500\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 1\nvar_g = 0.75\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 1\nvar_k = 0.2\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 500\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 1\nvar_g = 0.75\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 1\nvar_k = 0.2\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))"
    },
    "5105": {
        "category": "Geometry",
        "question_ko": "가로가 172센티미터(㎝)이고 세로가 295센티미터(㎝)인 직사각형 모양의 큰 도화지를 오려서 한 변이 24센티미터(㎝)인 정사각형 모양의 작은 종이를 될 수 있는 대로 많이 만들려고 합니다. 정사각형 모양의 종이는 모두 몇 장까지 만들 수 있는지 구해 보시오.",
        "question_en": "I am going to make as many small square pieces as possible by cutting out a large rectangular piece of paper that is 172 centimeters (cm) wide and 295 centimeters (cm) long. Find how many square pieces of paper you can make.",
        "answer_ko": "84",
        "answer_en": "84",
        "solution_abst_ko": "172 24 [OP_FDIV] 295 24 [OP_FDIV] [OP_MUL]",
        "solution_abst_en": "172 24 [OP_FDIV] 295 24 [OP_FDIV] [OP_MUL]",
        "solution_code_ko": "var_a = 172\nvar_b = 24\nvar_c = var_a // var_b\nvar_d = 295\nvar_e = 24\nvar_f = var_d // var_e\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 172\nvar_b = 24\nvar_c = var_a // var_b\nvar_d = 295\nvar_e = 24\nvar_f = var_d // var_e\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "5106": {
        "category": "Arithmetic calculation",
        "question_ko": "상자의 무게가 0.5킬로그램(㎏)입니다. 상자에 무게가 같은 당구공 6개를 넣었더니 상자의 무게는 1.82킬로그램(㎏)이 되었습니다. 당구 공 한 개의 무게는 몇 킬로그램(㎏)입니까?",
        "question_en": "The weight of the box is 0.5 kilograms (kg). When six billiard balls of the same weight were placed in a box, the box weighed 1.82 kilograms (kg). How many kilograms (kg) does one billiard ball weigh?",
        "answer_ko": "0.22",
        "answer_en": "0.22",
        "solution_abst_ko": "1.82 0.5 [OP_SUB] 6 [OP_DIV]",
        "solution_abst_en": "1.82 0.5 [OP_SUB] 6 [OP_DIV]",
        "solution_code_ko": "var_a = 1.82\nvar_b = 0.5\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 1.82\nvar_b = 0.5\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "5107": {
        "category": "Arithmetic calculation",
        "question_ko": "올해 아버지 나이는 딸 나이의 4배입니다. 5년 후에 아버지와 딸의 나이의 합은 50살이 됩니다. 올해 아버지의 나이는 몇 살입니까?",
        "question_en": "This year, the age of the father is four times the age of the daughter. After 5 years, the sum of the ages of father and daughter will be 50. How old is your father this year?",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "50 5 2 [OP_MUL] [OP_SUB] 1 4 [OP_ADD] [OP_DIV] 4 [OP_MUL]",
        "solution_abst_en": "50 5 2 [OP_MUL] [OP_SUB] 1 4 [OP_ADD] [OP_DIV] 4 [OP_MUL]",
        "solution_code_ko": "var_a = 50\nvar_b = 5\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = 4\nvar_h = var_f + var_g\nvar_i = var_e / var_h\nvar_j = 4\nvar_k = var_i * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 50\nvar_b = 5\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = 4\nvar_h = var_f + var_g\nvar_i = var_e / var_h\nvar_j = 4\nvar_k = var_i * var_j\nprint(int(var_k))"
    },
    "5108": {
        "category": "Comparison",
        "question_ko": "(가) 과일은 (나) 과일보다 가볍습니다. (다) 과일은 (가) 과일보다 가볍습니다. 가장 무거운 과일은 무엇입니까?",
        "question_en": "Fruit (a) is lighter than fruit (b). Fruit (c) is lighter than fruit (a). What is the heaviest fruit?",
        "answer_ko": "(나)",
        "answer_en": "(b)",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) (다) [OP_LIST_EOL] [OP_LIST_SOL] (가) (나) < (다) (가) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (a) (b) (c) [OP_LIST_EOL] [OP_LIST_SOL] (a) (b) < (c) (a) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nvar_c = '(다)'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '(가)'\nvar_e = '(나)'\nvar_f = '<'\nvar_g = '(다)'\nvar_h = '(가)'\nvar_i = '<'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(var_k)",
        "solution_code_en": "var_a = '(a)'\nvar_b = '(b)'\nvar_c = '(c)'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '(a)'\nvar_e = '(b)'\nvar_f = '<'\nvar_g = '(c)'\nvar_h = '(a)'\nvar_i = '<'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(var_k)"
    },
    "5109": {
        "category": "Arithmetic calculation",
        "question_ko": "5, 1, 9, 0, 6, 8의 수 중 4보다 크고 8보다 작은 수는 모두 몇 개인가요?",
        "question_en": "How many of the numbers 5, 1, 9, 0, 6, and 8 are greater than 4 and less than 8?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 5 1 9 0 6 8 [OP_LIST_EOL] 4 [OP_LIST_MORE_EQUAL] 8 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 5 1 9 0 6 8 [OP_LIST_EOL] 4 [OP_LIST_MORE_EQUAL] 8 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 5\nvar_b = 1\nvar_c = 9\nvar_d = 0\nvar_e = 6\nvar_f = 8\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 4\nlist_b = []\nfor i in list_a:\n    if i >= var_g:\n        list_b.append(i)\nvar_h = 8\nlist_c = []\nfor i in list_b:\n    if i <= var_h:\n        list_c.append(i)\nvar_i = len(list_c)\nprint(int(var_i))",
        "solution_code_en": "var_a = 5\nvar_b = 1\nvar_c = 9\nvar_d = 0\nvar_e = 6\nvar_f = 8\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 4\nlist_b = []\nfor i in list_a:\n    if i >= var_g:\n        list_b.append(i)\nvar_h = 8\nlist_c = []\nfor i in list_b:\n    if i <= var_h:\n        list_c.append(i)\nvar_i = len(list_c)\nprint(int(var_i))"
    },
    "5110": {
        "category": "Geometry",
        "question_ko": "폴라로이드 사진의 둘레가 40센티미터(㎝)이다. 가로가 8센티미터(㎝)일때 세로의 길이를 구하시오.",
        "question_en": "The circumference of a Polaroid photo is 40 centimeters (cm). Find the length of the length when the width is 8 centimeters (cm).",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "40 2 [OP_DIV] 8 [OP_SUB]",
        "solution_abst_en": "40 2 [OP_DIV] 8 [OP_SUB]",
        "solution_code_ko": "var_a = 40\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 8\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 40\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 8\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "5111": {
        "category": "Correspondence",
        "question_ko": "57A-B14=364가 성립하기 위한 A는 얼마인가요?",
        "question_en": "What number A is to make 57A-B14=364?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "57A-B14=364 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "57A-B14=364 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '57A-B14=364'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '57A-B14=364'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "5112": {
        "category": "Geometry",
        "question_ko": "도화지에 지름이 14 센티미터(㎝)인 원을 그렸을 때, 반지름의 길이가 몇 센티미터(㎝) 일까요?",
        "question_en": "If you draw a circle with a diameter of 14 centimeters (cm) on a piece of paper, what is the length of its radius in centimeters (cm)?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "14 2 [OP_DIV]",
        "solution_abst_en": "14 2 [OP_DIV]",
        "solution_code_ko": "var_a = 14\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 14\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "5113": {
        "category": "Arithmetic calculation",
        "question_ko": "호석이는 줄넘기를 월요일에 88번, 화요일에 75번, 수요일에 62번, 목요일에 91번, 금요일에 80번 했습니다. 호석이가 줄넘기를 가장 많이 한 요일과 가장 적게 한 요일의 줄넘기 횟수의 차를 구하시오.",
        "question_en": "Hosok jumped rope 88 times on Monday, 75 times on Tuesday, 62 times on Wednesday, 91 times on Thursday, and 80 times on Friday. Find the difference between the number of jumps on the days of the most and the least jumps.",
        "answer_ko": "29",
        "answer_en": "29",
        "solution_abst_ko": "[OP_LIST_SOL] 88 75 62 91 80 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 88 75 62 91 80 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 88\nvar_b = 75\nvar_c = 62\nvar_d = 91\nvar_e = 80\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 88\nvar_b = 75\nvar_c = 62\nvar_d = 91\nvar_e = 80\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))"
    },
    "5114": {
        "category": "Arithmetic calculation",
        "question_ko": "지영이는 동생과 같이 엄마의 심부름을 하고 용돈을 받았습니다. 두 사람이 받은 용돈의 합은 12000원이고, 동생이 지영이보다 1000원 덜 받았다면, 지영이가 받은 용돈은 얼마입니까?",
        "question_en": "Ji-young and her sister ran errands for their mother and received pocket money. If the sum of their pocket money is 12,000 won and the younger sister received 1,000 won less than Ji-young, how much money did Ji-young receive?",
        "answer_ko": "6500",
        "answer_en": "6500",
        "solution_abst_ko": "12000 1000 [OP_SUB] 2 [OP_DIV] 1000 [OP_ADD]",
        "solution_abst_en": "12000 1000 [OP_SUB] 2 [OP_DIV] 1000 [OP_ADD]",
        "solution_code_ko": "var_a = 12000\nvar_b = 1000\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 1000\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 12000\nvar_b = 1000\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 1000\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "5115": {
        "category": "Comparison",
        "question_ko": "초록색 의자의 높이는 0.309미터(m)이고, 파란색 의자의 높이는 48.2센티미터(㎝)입니다. 높이가 더 높은 의자는 어느 색입니까?",
        "question_en": "The height of the green chair is 0.309 meters (m) and the height of the blue chair is 48.2 centimeters (cm). Which color is the taller chair?",
        "answer_ko": "파란색",
        "answer_en": "blue",
        "solution_abst_ko": "[OP_LIST_SOL] 초록색 파란색 [OP_LIST_EOL] [OP_LIST_SOL] 0.309 48.2 100 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] green blue [OP_LIST_EOL] [OP_LIST_SOL] 0.309 48.2 100 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '초록색'\nvar_b = '파란색'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.309\nvar_d = 48.2\nvar_e = 100\nvar_f = var_d * var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'green'\nvar_b = 'blue'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.309\nvar_d = 48.2\nvar_e = 100\nvar_f = var_d * var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "5116": {
        "category": "Geometry",
        "question_ko": "오각기둥의 모서리 개수를 구하세요.",
        "question_en": "Find the number of corners of the pentagonal prism.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "5 3 [OP_MUL]",
        "solution_abst_en": "5 3 [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "5117": {
        "category": "Geometry",
        "question_ko": "원 모양 호수의 반지름의 길이가 7미터(m)일 때, 호수의 지름의 길이는 몇 미터(m)인가요?",
        "question_en": "If the radius of a circular lake is 7 meters (m), what is the diameter of the lake in meters (m)?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "7 2 [OP_MUL]",
        "solution_abst_en": "7 2 [OP_MUL]",
        "solution_code_ko": "var_a = 7\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 7\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "5118": {
        "category": "Geometry",
        "question_ko": "어떤 직육면체는 한 밑면의 넓이가 14제곱센티미터(㎠)이고 높이가 13센티미터(㎝)라고 합니다. 이 직육면체의 부피는 몇 세제곱센티미터(㎤)입니까?",
        "question_en": "A cuboid is said to have a base area of 14 square centimeters (cm2) and a height of 13 centimeters (cm). What is the volume of this cuboid in cubic centimeters (cm)?",
        "answer_ko": "182",
        "answer_en": "182",
        "solution_abst_ko": "14 13 [OP_MUL]",
        "solution_abst_en": "14 13 [OP_MUL]",
        "solution_code_ko": "var_a = 14\nvar_b = 13\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 14\nvar_b = 13\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "5119": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 영화관에 500개의 의자가 있습니다. 모든 의자에는 1부터 500까지의 번호가 차례로 적혀있을 때, 숫자 4는 모두 몇 번 적혀 있는지 구하시오.",
        "question_en": "A movie theater has 500 chairs. If all chairs are numbered from 1 to 500 in order, how many times is the number 4 written on them?",
        "answer_ko": "200",
        "answer_en": "200",
        "solution_abst_ko": "1 500 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 4 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 500 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 4 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 500\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 4\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 500\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 4\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))"
    },
    "5120": {
        "category": "Arithmetic calculation",
        "question_ko": "6, 2, 4, 1, 5, 9가 있습니다. 그중에서 가장 큰 수는 2번째로 큰 수보다 몇 큰 수인지 구하시오.",
        "question_en": "There are 6, 2, 4, 1, 5, and 9. Find out how many of the largest numbers are larger than the second largest.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 6 2 4 1 5 9 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 6 2 4 1 5 9 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_SUB]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = 4\nvar_d = 1\nvar_e = 5\nvar_f = 9\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_h = list_b[-var_g]\nvar_i = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = var_h - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = 4\nvar_d = 1\nvar_e = 5\nvar_f = 9\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_h = list_b[-var_g]\nvar_i = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = var_h - var_j\nprint(int(var_k))"
    },
    "5121": {
        "category": "Comparison",
        "question_ko": "놀이공원에 사람들이 한 줄서기를 하고 있습니다. 은지는 맨 뒤에서 6번째로 놀이기구를 탈 수 있고 은지 앞에 7명의 사람들이 있을 때 놀기기구를 타기위해 줄을 선 사람은 모두 몇 명인지 구하시오.",
        "question_en": "People are standing in a line at an amusement park. If Eunji can ride the ride 6th from the back and there are 7 people in front of Eunji, how many people are in line to ride the ride?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "6 7 [OP_ADD]",
        "solution_abst_en": "6 7 [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "5122": {
        "category": "Geometry",
        "question_ko": "32킬로미터(㎞)의 끈으로 사각형을 만들면 그 땅을 모두 준다고 한다. 받을 수 있는 땅의 넓이 중 가장 넓은 크기는 몇 제곱킬로미터(㎢)인가?",
        "question_en": "If you make a square with 32 kilometers (km) of string, you will be given all the land. What is the largest size of land you could possibly get in square kilometers (km²)?",
        "answer_ko": "64",
        "answer_en": "64",
        "solution_abst_ko": "32 4 [OP_DIV] 2 [OP_POW]",
        "solution_abst_en": "32 4 [OP_DIV] 2 [OP_POW]",
        "solution_code_ko": "var_a = 32\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 32\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint(int(var_e))"
    },
    "5123": {
        "category": "Correspondence",
        "question_ko": "3/9=6/A=B/63 을 만족하는 A와 B의 곱을 구하시오",
        "question_en": "Find the product of A and B that satisfy 3/9=6/A=B/63",
        "answer_ko": "378",
        "answer_en": "378",
        "solution_abst_ko": "3/9=6/A=B/63 A [OP_NUM_UNK_SOLVER] 3/9=6/A=B/63 B [OP_NUM_UNK_SOLVER] [OP_MUL]",
        "solution_abst_en": "3/9=6/A=B/63 A [OP_NUM_UNK_SOLVER] 3/9=6/A=B/63 B [OP_NUM_UNK_SOLVER] [OP_MUL]",
        "solution_code_ko": "var_a = '3/9=6/A=B/63'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '3/9=6/A=B/63'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = '3/9=6/A=B/63'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '3/9=6/A=B/63'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "5124": {
        "category": "Geometry",
        "question_ko": "어떤 팔각형이 있습니다. 이 팔각형 안에 그을 수 있는 모든 대각선의 개수를 구하시오.",
        "question_en": "There is some octagon. Find the number of all diagonals that can be drawn within this octagon.",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "8 8 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "8 8 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 8\nvar_b = 8\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 8\nvar_b = 8\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "5125": {
        "category": "Possibility",
        "question_ko": "3, 0, 2, 5, 7 중에서 서로 다른 숫자 3개를 뽑아 만들 수 있는 세 자리 수 중에서 가장 작은 수를 쓰시오.",
        "question_en": "Write the smallest three-digit number that can be formed by drawing three different numbers from 3, 0, 2, 5, and 7.",
        "answer_ko": "203",
        "answer_en": "203",
        "solution_abst_ko": "[OP_LIST_SOL] 3 0 2 5 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 3 0 2 5 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 3\nvar_b = 0\nvar_c = 2\nvar_d = 5\nvar_e = 7\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nprint(int(var_h))",
        "solution_code_en": "var_a = 3\nvar_b = 0\nvar_c = 2\nvar_d = 5\nvar_e = 7\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nprint(int(var_h))"
    },
    "5126": {
        "category": "Comparison",
        "question_ko": "윤기는 7, 정국은 6, 유나는 9, 유정은 8, 태형은 10만큼 모았습니다. 2번째로 큰 숫자를 가진 사람은 누구입니까?",
        "question_en": "Yoongi collected 7 points, Jungkook 6 points, Yuna 9 points, Yoojung 8 points, and Taehyung 10 points. Who has the 2nd largest number?",
        "answer_ko": "유나",
        "answer_en": "Yuna",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 유나 유정 태형 [OP_LIST_EOL] [OP_LIST_SOL] 7 6 9 8 10 [OP_LIST_EOL] 2 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook Yuna Yoojung Taehyung [OP_LIST_EOL] [OP_LIST_SOL] 7 6 9 8 10 [OP_LIST_EOL] 2 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nvar_c = '유나'\nvar_d = '유정'\nvar_e = '태형'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 7\nvar_g = 6\nvar_h = 9\nvar_i = 8\nvar_j = 10\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_k = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nvar_c = 'Yuna'\nvar_d = 'Yoojung'\nvar_e = 'Taehyung'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 7\nvar_g = 6\nvar_h = 9\nvar_i = 8\nvar_j = 10\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_k = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "5127": {
        "category": "Comparison",
        "question_ko": "사과 상자의 무게는 3/5킬로그램(㎏) , 귤 상자의 무게는 0.49킬로그램(㎏) 입니다. 어느 상자가 더 무겁습니까?",
        "question_en": "The weight of the apple box is 3/5 kilograms (kg), and the weight of the tangerine box is 0.49 kilograms (kg). Which box is heavier?",
        "answer_ko": "사과",
        "answer_en": "apple",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 귤 [OP_LIST_EOL] [OP_LIST_SOL] 3/5 0.49 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] apple tangerine [OP_LIST_EOL] [OP_LIST_SOL] 3/5 0.49 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '귤'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.6\nvar_d = 0.49\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'apple'\nvar_b = 'tangerine'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.6\nvar_d = 0.49\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "5128": {
        "category": "Geometry",
        "question_ko": "가로가 112센티미터(㎝), 세로가 63센티미터(㎝)인 직사각형 모양의 종이를 잘라 한 변의 길이가 7센티미터(㎝)인 정사각형을 만들려고 합니다. 모두 몇 개를 만들 수 있습니까?",
        "question_en": "You want to make a square with a side of 7 centimeters (cm) by cutting a rectangular paper that is 112 centimeters (cm) wide and 63 centimeters (cm) long. How many squares can you make in total?",
        "answer_ko": "144",
        "answer_en": "144",
        "solution_abst_ko": "112 7 [OP_FDIV] 63 7 [OP_FDIV] [OP_MUL]",
        "solution_abst_en": "112 7 [OP_FDIV] 63 7 [OP_FDIV] [OP_MUL]",
        "solution_code_ko": "var_a = 112\nvar_b = 7\nvar_c = var_a // var_b\nvar_d = 63\nvar_e = 7\nvar_f = var_d // var_e\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 112\nvar_b = 7\nvar_c = var_a // var_b\nvar_d = 63\nvar_e = 7\nvar_f = var_d // var_e\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "5129": {
        "category": "Possibility",
        "question_ko": "주사위를 던져 나온 수 세 개를 한 번씩 모두 이용해 340보다 작은 세 자리 수를 만들고자 합니다. 2, 4, 3이 나왔을 때, 몇개의 수를 만들 수 있습니까?",
        "question_en": "You want to use all three dice rolls at least once to create a three-digit number less than 340. When 2, 4, and 3 are rolled, how many numbers can you make?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 2 4 3 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 340 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 2 4 3 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 340 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = 3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 340\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = 3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 340\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "5130": {
        "category": "Correspondence",
        "question_ko": "서로 다른 수 A, B, C가 있습니다. A는 9보다 4 작은 수이고, B는 A보다 5 큰 수이고, C보다 8 작은 수는 1입니다. B에서 C를 뺀 값은 얼마입니까?",
        "question_en": "A, B, and C are three different numbers. A is 4 less than 9, B is 5 greater than A, and 8 less than C is 1. What is B minus C?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "9 4 [OP_SUB] 5 [OP_ADD] 8 1 [OP_ADD] [OP_SUB]",
        "solution_abst_en": "9 4 [OP_SUB] 5 [OP_ADD] 8 1 [OP_ADD] [OP_SUB]",
        "solution_code_ko": "var_a = 9\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = var_e - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 9\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = var_e - var_h\nprint(int(var_i))"
    },
    "5131": {
        "category": "Comparison",
        "question_ko": "자동차 24대가 있습니다. 이 중에서 빨간색 자동차는 전체의 1/4이고, 파란색 자동차는 빨간색 자동차보다 6대 더 많고, 나머지는 노란색 자동차입니다. 어떤 색의 자동차가 가장 많을까요?",
        "question_en": "There are 24 cars. Of these cars, red cars make up 1/4 of the total, blue cars outnumber red cars by 6, and the rest are yellow cars. What color cars do you have the most?",
        "answer_ko": "파란색",
        "answer_en": "blue",
        "solution_abst_ko": "[OP_LIST_SOL] 빨간색 파란색 노란색 [OP_LIST_EOL] [OP_LIST_SOL] 24 1/4 [OP_MUL] 24 1/4 [OP_MUL] 6 [OP_ADD] 24 24 1/4 [OP_MUL] 6 [OP_ADD] [OP_SUB] 24 1/4 [OP_MUL] [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] red blue yellow [OP_LIST_EOL] [OP_LIST_SOL] 24 1/4 [OP_MUL] 24 1/4 [OP_MUL] 6 [OP_ADD] 24 24 1/4 [OP_MUL] 6 [OP_ADD] [OP_SUB] 24 1/4 [OP_MUL] [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '빨간색'\nvar_b = '파란색'\nvar_c = '노란색'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 24\nvar_e = 0.25\nvar_f = var_d * var_e\nvar_g = 24\nvar_h = 0.25\nvar_i = var_g * var_h\nvar_j = 6\nvar_k = var_i + var_j\nvar_l = 24\nvar_m = 24\nvar_n = 0.25\nvar_o = var_m * var_n\nvar_p = 6\nvar_q = var_o + var_p\nvar_r = var_l - var_q\nvar_s = 24\nvar_t = 0.25\nvar_u = var_s * var_t\nvar_v = var_r - var_u\nlist_b= []\nif \"/\" in str(var_v):\n    var_v = eval(str(var_v))\nlist_b.append(var_v)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_w = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_x = list_c[-var_w]\nvar_y = list_b.index(var_x)+1\nvar_z = list_a[var_y-1]\nprint(var_z)",
        "solution_code_en": "var_a = 'red'\nvar_b = 'blue'\nvar_c = 'yellow'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 24\nvar_e = 0.25\nvar_f = var_d * var_e\nvar_g = 24\nvar_h = 0.25\nvar_i = var_g * var_h\nvar_j = 6\nvar_k = var_i + var_j\nvar_l = 24\nvar_m = 24\nvar_n = 0.25\nvar_o = var_m * var_n\nvar_p = 6\nvar_q = var_o + var_p\nvar_r = var_l - var_q\nvar_s = 24\nvar_t = 0.25\nvar_u = var_s * var_t\nvar_v = var_r - var_u\nlist_b= []\nif \"/\" in str(var_v):\n    var_v = eval(str(var_v))\nlist_b.append(var_v)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_w = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_x = list_c[-var_w]\nvar_y = list_b.index(var_x)+1\nvar_z = list_a[var_y-1]\nprint(var_z)"
    },
    "5132": {
        "category": "Geometry",
        "question_ko": "한 모서리의 길이가 20센티미터(㎝)인 정육면체 모양의 수족관이 있습니다. 이 수족관의 겉넓이는 몇 제곱센티미터(㎠)입니까?",
        "question_en": "You have an aquarium in the shape of a cube with one corner measuring 20 centimeters (cm). What is the surface area of this aquarium in square centimeters (cm2)?",
        "answer_ko": "2400",
        "answer_en": "2400",
        "solution_abst_ko": "20 2 [OP_POW] 6 [OP_MUL]",
        "solution_abst_en": "20 2 [OP_POW] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 20\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "5133": {
        "category": "Correspondence",
        "question_ko": "천의 자리 숫자가 2인 네 자리 수를 12로 나누면 나누어떨어집니다. 이런 네 자리 수는 모두 몇 개입니까?",
        "question_en": "There are four-digit numbers with 2 in the thousands digit which are divisible by 12. How many of these four-digit numbers are there?",
        "answer_ko": "83",
        "answer_en": "83",
        "solution_abst_ko": "2 1000 [OP_MUL] 2 1000 [OP_MUL] 999 [OP_ADD] 1 [OP_LIST_ARANGE] 12 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "2 1000 [OP_MUL] 2 1000 [OP_MUL] 999 [OP_ADD] 1 [OP_LIST_ARANGE] 12 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = 999\nvar_h = var_f + var_g\nvar_i = 1\nlist_a = [i for i in range(var_c, var_h + 1, var_i)]\nvar_j = 12\nlist_b = []\nvar_j = int(var_j)\nfor i in list_a:\n    i = int(i)\n    if i % var_j == 0:\n        list_b.append(i)\nvar_k = len(list_b)\nprint(int(var_k))",
        "solution_code_en": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = 999\nvar_h = var_f + var_g\nvar_i = 1\nlist_a = [i for i in range(var_c, var_h + 1, var_i)]\nvar_j = 12\nlist_b = []\nvar_j = int(var_j)\nfor i in list_a:\n    i = int(i)\n    if i % var_j == 0:\n        list_b.append(i)\nvar_k = len(list_b)\nprint(int(var_k))"
    },
    "5134": {
        "category": "Arithmetic calculation",
        "question_ko": "3과 4로 나누어떨어지고 5로 나누면 나머지가 4인 두 자리 수를 찾으려고 합니다. 만들 수 있는 두 자리 수 중 가장 큰 수는 무엇입니까?",
        "question_en": "You are trying to find a two-digit number that is divisible by 3 and 4 and that has a remainder of 4 when divided by 5. What is the largest two-digit number you can make?",
        "answer_ko": "84",
        "answer_en": "84",
        "solution_abst_ko": "10 99 1 [OP_LIST_ARANGE] 3 4 [OP_LCM] [OP_LIST_DIVISIBLE] 5 4 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MAX]",
        "solution_abst_en": "10 99 1 [OP_LIST_ARANGE] 3 4 [OP_LCM] [OP_LIST_DIVISIBLE] 5 4 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nvar_e = 4\nvar_f = var_e * var_d / math.gcd(int(var_e), int(var_d))\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nvar_g = 5\nvar_h = 4\nlist_c = [] \nvar_g = int(var_g)\nvar_h = int(var_h)\nif var_h < 0:\n    var_h = var_h + var_g\nfor i in list_b:\n    i = int(i)\n    if i%var_g == var_h:\n        list_c.append(i)\nvar_i = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_j = list_d[-var_i]\nprint(int(var_j))",
        "solution_code_en": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nvar_e = 4\nvar_f = var_e * var_d / math.gcd(int(var_e), int(var_d))\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nvar_g = 5\nvar_h = 4\nlist_c = [] \nvar_g = int(var_g)\nvar_h = int(var_h)\nif var_h < 0:\n    var_h = var_h + var_g\nfor i in list_b:\n    i = int(i)\n    if i%var_g == var_h:\n        list_c.append(i)\nvar_i = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_j = list_d[-var_i]\nprint(int(var_j))"
    },
    "5135": {
        "category": "Comparison",
        "question_ko": "지민이는 (가) 상자와 (가) 상자보다 무거운 (나) 상자를 선물받았습니다. 무거운 상자를 먼저 열어보려고 할 때, 먼저 열어볼 상자는 무엇인가요?",
        "question_en": "Jimin received box A and a box B that was heavier than box A. When he wants to open a heavy box first, which box is to open first?",
        "answer_ko": "(나)",
        "answer_en": "B",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) [OP_LIST_EOL] [OP_LIST_SOL] (가) (나) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] A B < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = '(가)'\nvar_d = '(나)'\nvar_e = '<'\nlist_b= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_f = 1\nvar_g = list_c[var_f-1]\nprint(var_g)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 'A'\nvar_d = 'B'\nvar_e = '<'\nlist_b= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_f = 1\nvar_g = list_c[var_f-1]\nprint(var_g)"
    },
    "5136": {
        "category": "Correspondence",
        "question_ko": "A, B는 한 자리 수입니다. A4461B가 72의 배수일 때, A와 B의 합을 구하시오.",
        "question_en": "A and B are single digit numbers. If A4461B is a multiple of 72, find the sum of A and B.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "A4461B [OP_GEN_POSSIBLE_LIST] 72 [OP_LIST_DIVISIBLE] A4461B A [OP_LIST_FIND_UNK] A4461B B [OP_LIST_FIND_UNK] [OP_ADD]",
        "solution_abst_en": "A4461B [OP_GEN_POSSIBLE_LIST] 72 [OP_LIST_DIVISIBLE] A4461B A [OP_LIST_FIND_UNK] A4461B B [OP_LIST_FIND_UNK] [OP_ADD]",
        "solution_code_ko": "var_a = 'A4461B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 72\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 'A4461B'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nvar_e = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_e = int(elem[unk_idx])\nvar_f = 'A4461B'\nvar_g = 'B'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nvar_i = var_e + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 'A4461B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 72\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 'A4461B'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nvar_e = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_e = int(elem[unk_idx])\nvar_f = 'A4461B'\nvar_g = 'B'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nvar_i = var_e + var_h\nprint(int(var_i))"
    },
    "5137": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이가 16살에 군대를 갔는데, 당시 어머니는 46살이었습니다. 어머니 나이에서 정국이의 나이를 나눈 값이 4였을 때는 몇 년 전이였습니까?",
        "question_en": "Jungkook went to the army at the age of 16, his mother was 46 at the time. How many years ago was Jungkook's age divided by his mother's age equal to 4?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "16 4 [OP_MUL] 46 [OP_SUB] 4 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "16 4 [OP_MUL] 46 [OP_SUB] 4 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 16\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 46\nvar_e = var_c - var_d\nvar_f = 4\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 16\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 46\nvar_e = var_c - var_d\nvar_f = 4\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "5138": {
        "category": "Geometry",
        "question_ko": "어떤 정사각형은 한 변의 길이가 8센티미터(㎝)이고, 다른 정사각형은 한 변의 길이가 10센티미터(㎝)입니다. 두 정사각형의 넓이의 합을 구하시오.",
        "question_en": "A square has sides of 8 centimeters (cm), and the other one has sides of 10 centimeters (cm). Find the sum of the areas of the two squares.",
        "answer_ko": "164",
        "answer_en": "164",
        "solution_abst_ko": "8 2 [OP_POW] 10 2 [OP_POW] [OP_ADD]",
        "solution_abst_en": "8 2 [OP_POW] 10 2 [OP_POW] [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 10\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 8\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 10\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "5139": {
        "category": "Arithmetic calculation",
        "question_ko": "달리기 시합에서 선수들이 차례대로 11.4초, 15.553초, 22.6초, 124초, 166초에 결승선을 넘었습니다. 이 중에서 가장 빠르게 들어온 선수와 가장 느리게 들어온 선수의 시간 차는 얼마입니까?",
        "question_en": "In the running competition, the runners crossed the finish line in 11.4 seconds, 15.553 seconds, 22.6 seconds, 124 seconds, and 166 seconds in order. What is the difference between the fastest and slowest runners?",
        "answer_ko": "154.60",
        "answer_en": "154.6",
        "solution_abst_ko": "[OP_LIST_SOL] 11.4 15.553 22.6 124 166 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "[OP_LIST_SOL] 11.4 15.553 22.6 124 166 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 11.4\nvar_b = 15.553\nvar_c = 22.6\nvar_d = 124\nvar_e = 166\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g - var_i\nvar_k = abs(var_j)\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 11.4\nvar_b = 15.553\nvar_c = 22.6\nvar_d = 124\nvar_e = 166\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g - var_i\nvar_k = abs(var_j)\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "5140": {
        "category": "Geometry",
        "question_ko": "가로가 500 센티미터(㎝) , 세로가 800 센티미터(㎝) 인 직사각형 모양의 철판이 있습니다. 이 철판의 넓이는 몇 제곱미터(㎡) 입니까?",
        "question_en": "There is a rectangular iron plate with a width of 500 centimeters (cm) and a length of 800 centimeters (cm). What is the area in square meters (m2) of this iron plate?",
        "answer_ko": "40",
        "answer_en": "40",
        "solution_abst_ko": "500 100 [OP_DIV] 800 100 [OP_DIV] [OP_MUL]",
        "solution_abst_en": "500 100 [OP_DIV] 800 100 [OP_DIV] [OP_MUL]",
        "solution_code_ko": "var_a = 500\nvar_b = 100\nvar_c = var_a / var_b\nvar_d = 800\nvar_e = 100\nvar_f = var_d / var_e\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 500\nvar_b = 100\nvar_c = var_a / var_b\nvar_d = 800\nvar_e = 100\nvar_f = var_d / var_e\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "5141": {
        "category": "Correspondence",
        "question_ko": "과수원에서 수확한 사과와 배가 있습니다. 사과와 배의 개수의 합은 913개이고 사과의 개수는 514입니다. 사과와 배의 개수의 차이를 구하십시오.",
        "question_en": "There are apples and pears harvested from the orchard. The sum of the number of apples and pears is 913 and the number of apples is 514. Find the difference between the number of apples and pears.",
        "answer_ko": "115",
        "answer_en": "115",
        "solution_abst_ko": "514 913 514 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "514 913 514 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 514\nvar_b = 913\nvar_c = 514\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 514\nvar_b = 913\nvar_c = 514\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "5142": {
        "category": "Correspondence",
        "question_ko": "2×B+B=12, A-D=5, C-B=5, D+C=12를 만족할 때, A는 얼마입니까?",
        "question_en": "When 2×B+B=12, AD=5, CB=5, D+C=12, what is A?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "12 2×B+B=12 B [OP_NUM_UNK_SOLVER] 5 [OP_ADD] [OP_SUB] 5 [OP_ADD]",
        "solution_abst_en": "12 2×B+B=12 B [OP_NUM_UNK_SOLVER] 5 [OP_ADD] [OP_SUB] 5 [OP_ADD]",
        "solution_code_ko": "var_a = 12\nvar_b = '2×B+B=12'\nvar_c = 'B'\nans_dict = dict()\nvar_b = var_b.replace('×','*')\nvar_b = var_b.replace('x','*')\nvar_b = var_b.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_b):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_b\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_d = ans_dict[var_c]\nvar_e = 5\nvar_f = var_d + var_e\nvar_g = var_a - var_f\nvar_h = 5\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 12\nvar_b = '2×B+B=12'\nvar_c = 'B'\nans_dict = dict()\nvar_b = var_b.replace('×','*')\nvar_b = var_b.replace('x','*')\nvar_b = var_b.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_b):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_b\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_d = ans_dict[var_c]\nvar_e = 5\nvar_f = var_d + var_e\nvar_g = var_a - var_f\nvar_h = 5\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "5143": {
        "category": "Arithmetic calculation",
        "question_ko": "사탕 67개를 학생들에게 나누어주려고 합니다. 모든 학생이 사탕을 4개씩 가져갔더니 3개의 사탕이 남았습니다. 학생 수는 몇 명입니까?",
        "question_en": "You want to distribute 67 candies to students. Each student took 4 candies, so there are 3 candies left. How many students do you have?",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "67 3 [OP_SUB] 4 [OP_DIV]",
        "solution_abst_en": "67 3 [OP_SUB] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 67\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 67\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "5144": {
        "category": "Comparison",
        "question_ko": "1.4, 9/10, 1.2, 0.5, 13/10에서 1.1보다 큰 숫자를 고르면 몇 개인가요?",
        "question_en": "How many numbers greater than 1.1 are there in 1.4, 9/10, 1.2, 0.5, and 13/10?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "5145": {
        "category": "Geometry",
        "question_ko": "바둑돌을 빈틈없이 규칙적으로 늘어놓아 정사각형을 만들었습니다. 둘레에 놓인 바둑돌의 개수가 84개였다면, 가장 바깥쪽의 한 변에 놓인 바둑돌의 개수는 몇 개입니까?",
        "question_en": "I made a square by arranging Go stones regularly without any gaps. If the number of Go stones on the perimeter is 84, how many Go stones are on one outermost side?",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "84 4 [OP_SUB] 4 [OP_DIV] 2 [OP_ADD]",
        "solution_abst_en": "84 4 [OP_SUB] 4 [OP_DIV] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 84\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 84\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "5146": {
        "category": "Geometry",
        "question_ko": "가로 15센티미터(㎝), 세로 6센티미터(㎝), 높이 4센티미터(㎝)인 직육면체의 부피는?",
        "question_en": "What is the volume of a rectangular parallelepiped that is 15 centimeters (cm) wide, 6 centimeters (cm) long, and 4 centimeters (cm) high?",
        "answer_ko": "360",
        "answer_en": "360",
        "solution_abst_ko": "15 6 [OP_MUL] 4 [OP_MUL]",
        "solution_abst_en": "15 6 [OP_MUL] 4 [OP_MUL]",
        "solution_code_ko": "var_a = 15\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "5147": {
        "category": "Arithmetic calculation",
        "question_ko": "운동장에 학생 30명이 일렬로 서 있다. 학생들 간의 간격이 3미터(m) 일 때, 첫번째 학생과 마지막 학생 사이의 거리를 구하시오.",
        "question_en": "Thirty students are standing in a line on the playground. If the distance between students is 3 meters (m), find what the distance of the first student and the last student is.",
        "answer_ko": "87",
        "answer_en": "87",
        "solution_abst_ko": "3 30 1 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "3 30 1 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 30\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 3\nvar_b = 30\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nprint(int(var_e))"
    },
    "5148": {
        "category": "Geometry",
        "question_ko": "부피가 28/3세제곱센티미터(㎤)인 어떤 직육면체가 있다. 이 직육면체에 물을 초 당 14/5밀리리터(㎖)씩 부으면 꽉 차는데 몇 초가 걸릴지 구하시오.",
        "question_en": "A certain cuboid has a volume of 28/3 cubic centimeters (cm3). If water is poured into this cuboid at a rate of 14/5 milliliters (ml) per second, find how many seconds it will take for the cube to be full.",
        "answer_ko": "3.33",
        "answer_en": "3.33",
        "solution_abst_ko": "28/3 14/5 [OP_DIV]",
        "solution_abst_en": "28/3 14/5 [OP_DIV]",
        "solution_code_ko": "var_a = 9.333333333333334\nvar_b = 2.8\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 9.333333333333334\nvar_b = 2.8\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "5149": {
        "category": "Arithmetic calculation",
        "question_ko": "무게가 220그램(g)인 작은 상자에 사과를 각각 6개 넣은 후 이 작은 상자 9개를 무게가 250그램(g)인 큰 상자에 넣었더니 13.3킬로그램(㎏)이 되었습니다. 사과 한 개의 무게는 몇 그램(g)입니까? (단, 각각의 사과 무게는 같습니다.)",
        "question_en": "After putting 6 apples each in a small box weighing 220 grams (g), and then putting 9 of these small boxes in a large box weighing 250 grams (g), the result was 13.3 kilograms (kg). How many grams (g) does one apple weigh? (However, each apple weighs the same.)",
        "answer_ko": "205",
        "answer_en": "205",
        "solution_abst_ko": "13.3 1000 [OP_MUL] 250 [OP_SUB] 220 9 [OP_MUL] [OP_SUB] 6 9 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "13.3 1000 [OP_MUL] 250 [OP_SUB] 220 9 [OP_MUL] [OP_SUB] 6 9 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 13.3\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 250\nvar_e = var_c - var_d\nvar_f = 220\nvar_g = 9\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nvar_j = 6\nvar_k = 9\nvar_l = var_j * var_k\nvar_m = var_i / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 13.3\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 250\nvar_e = var_c - var_d\nvar_f = 220\nvar_g = 9\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nvar_j = 6\nvar_k = 9\nvar_l = var_j * var_k\nvar_m = var_i / var_l\nprint(int(var_m))"
    },
    "5150": {
        "category": "Comparison",
        "question_ko": "유나는 교실에서 5번째로 연필이 많고, 은지는 그 다음으로 연필이 많습니다. 은지는 몇 번째로 연필이 많습니까?",
        "question_en": "Yuna is the 5th one having the most pencils in the class, and Eunji is the next most. How many pencils does Eunji have?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "5 1 [OP_ADD]",
        "solution_abst_en": "5 1 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "5151": {
        "category": "Correspondence",
        "question_ko": "A는 한 자리 수입니다. 한 자리 수끼리의 곱셈식 A×A×A=21A에서 A를 구하시오.",
        "question_en": "A is a single-digit number. Find A from the single-digit numbers' multiplication equation A×A×A=21A.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "A×A×A=21A A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A×A×A=21A A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A×A×A=21A'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A×A×A=21A'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "5152": {
        "category": "Correspondence",
        "question_ko": "37을 8로 나눴더니 나머지가 B, 몫이 A가 되었습니다. B에 알맞은 값을 구하시오.",
        "question_en": "Given that the equation of 37 is divided by 8, the remainder is B and the quotient is A. Find the right value for B.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "37 8 [OP_MOD]",
        "solution_abst_en": "37 8 [OP_MOD]",
        "solution_code_ko": "var_a = 37\nvar_b = 8\nvar_c = var_a % var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 37\nvar_b = 8\nvar_c = var_a % var_b\nprint(int(var_c))"
    },
    "5153": {
        "category": "Geometry",
        "question_ko": "정십이면체의 모서리의 개수는?",
        "question_en": "How many edges does a regular dodecahedron have?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "30",
        "solution_abst_en": "30",
        "solution_code_ko": "var_a = 30\nprint(int(var_a))",
        "solution_code_en": "var_a = 30\nprint(int(var_a))"
    },
    "5154": {
        "category": "Geometry",
        "question_ko": "창고의 한쪽 벽의 가로는 6미터(m) 이고 세로는 4미터(m) 입니다. 이 벽에 가로가 60센티미터(㎝) , 세로가 20 센티미터(㎝) 인 직사각형 모양의 타일을 빈틈없이 겹치지 않게 붙인다면 필요한 타일은 모두 몇 개입니까?",
        "question_en": "One wall of the warehouse is 6 meters (m) wide and 4 meters (m) long. How many tiles are needed if you attach rectangular tiles measuring 60 centimeters (cm) wide and 20 centimeters (cm) tall on this wall without overlapping any gaps?",
        "answer_ko": "200",
        "answer_en": "200",
        "solution_abst_ko": "6 100 [OP_MUL] 4 100 [OP_MUL] [OP_MUL] 60 20 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "6 100 [OP_MUL] 4 100 [OP_MUL] [OP_MUL] 60 20 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = 100\nvar_f = var_d * var_e\nvar_g = var_c * var_f\nvar_h = 60\nvar_i = 20\nvar_j = var_h * var_i\nvar_k = var_g / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 6\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = 100\nvar_f = var_d * var_e\nvar_g = var_c * var_f\nvar_h = 60\nvar_i = 20\nvar_j = var_h * var_i\nvar_k = var_g / var_j\nprint(int(var_k))"
    },
    "5155": {
        "category": "Arithmetic calculation",
        "question_ko": "바구니 5개에는 감이 5개씩 들어 있고, 다른 바구니 1개에는 감이 8개 들어 있습니다. 6개의 바구니에 들어 있는 감은 모두 몇 개입니까?",
        "question_en": "Five baskets contain 5 persimmons, and another basket contains 8 persimmons. How many persimmons are in all 6 baskets?",
        "answer_ko": "33",
        "answer_en": "33",
        "solution_abst_ko": "5 5 [OP_MUL] 1 8 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "5 5 [OP_MUL] 1 8 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 8\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 8\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "5156": {
        "category": "Arithmetic calculation",
        "question_ko": "형이 동생에게 용든을 주었더니 형이 동생보다 360원을 더 가지게 되었습니다. 형이 가지고 있던 돈은 2800원이고 동생이 가지고 있던 돈이 1500원이었다면 형이 동생에게 얼마를 주었을 지 구하세요.",
        "question_en": "The older brother gave the younger brother pocket money, and the older brother got 360 won more than the younger brother. If the older brother had 2800 won and the younger brother had 1500 won, how much money would the older brother give to the younger brother?",
        "answer_ko": "470",
        "answer_en": "470",
        "solution_abst_ko": "2800 1500 [OP_SUB] 360 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "2800 1500 [OP_SUB] 360 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 2800\nvar_b = 1500\nvar_c = var_a - var_b\nvar_d = 360\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 2800\nvar_b = 1500\nvar_c = var_a - var_b\nvar_d = 360\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "5157": {
        "category": "Geometry",
        "question_ko": "부피가 2744세제곱센티미터(㎤)인 정육면체의 한 모서리는 몇 센티미터(㎝) 입니까?",
        "question_en": "How many centimeters (cm) is one edge of a cube with a volume of 2744 cubic centimeters (cm3)?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "2744 1/3 [OP_POW]",
        "solution_abst_en": "2744 1/3 [OP_POW]",
        "solution_code_ko": "var_a = 2744\nvar_b = 0.3333333333333333\nvar_c = var_a ** var_b\nprint(int(eval('{:.2f}'.format(round(var_c+1e-10,2)))))",
        "solution_code_en": "var_a = 2744\nvar_b = 0.3333333333333333\nvar_c = var_a ** var_b\nprint(int(eval('{:.2f}'.format(round(var_c+1e-10,2)))))"
    },
    "5158": {
        "category": "Geometry",
        "question_ko": "세로가 10센티미터(㎝)인 직사각형의 둘레의 길이와 빗변의 길이가 16(㎝)인 정삼각형의 세 변의 길이의 합이 같았습니다. 이 직사각형의 가로의 길이는 몇 센티미터(㎝)이겠습니까?",
        "question_en": "The length of the perimeter of a rectangle with a length of 10 centimeters (cm) is equal to the sum of the lengths of the three sides of an equilateral triangle with a hypotenuse of length 16 centimeters (cm). What is the width of this rectangle in centimeters (cm)?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "16 3 [OP_MUL] 2 [OP_DIV] 10 [OP_SUB]",
        "solution_abst_en": "16 3 [OP_MUL] 2 [OP_DIV] 10 [OP_SUB]",
        "solution_code_ko": "var_a = 16\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 10\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 16\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 10\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "5159": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 14를 더하였더니 56이 되었습니다. 어떤 수에 3을 곱하면 얼마가 되는지 구하시오.",
        "question_en": "When you add 14 to a particular number, you get 56. What is the result when that particular number is multiplied by 3?",
        "answer_ko": "126",
        "answer_en": "126",
        "solution_abst_ko": "56 14 [OP_SUB] 3 [OP_MUL]",
        "solution_abst_en": "56 14 [OP_SUB] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 56\nvar_b = 14\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 56\nvar_b = 14\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "5160": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 연속된 짝수의 합이 92입니다. 이 4개의 수 중에서 가장 큰 수를 쓰시오.",
        "question_en": "The sum of 4 consecutive even numbers is 92. Write the largest of these four numbers.",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "92 4 [OP_DIV] 4 2 [OP_FDIV] 2 [OP_MUL] [OP_ADD] 1 [OP_SUB]",
        "solution_abst_en": "92 4 [OP_DIV] 4 2 [OP_FDIV] 2 [OP_MUL] [OP_ADD] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 92\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = 2\nvar_f = var_d // var_e\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_c + var_h\nvar_j = 1\nvar_k = var_i - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 92\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = 2\nvar_f = var_d // var_e\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_c + var_h\nvar_j = 1\nvar_k = var_i - var_j\nprint(int(var_k))"
    },
    "5161": {
        "category": "Geometry",
        "question_ko": "구각형 모양의 땅이 있습니다. 한 꼭짓점에서 이웃하지 않은 꼭짓점으로 선을 그어 땅을 나눈다면 몇 개의 땅으로 나누어집니까?",
        "question_en": "There is a nonagon-shaped piece of land. If you divide a land by drawing a line from one vertex to a non-neighboring vertex, how many lands is it divided into?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "9 3 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "9 3 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 9\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "5162": {
        "category": "Arithmetic calculation",
        "question_ko": "일웅이가 보고 있는 책의 두 쪽수 중 큰 값을 구하려 한다. 두 쪽수의 합이 125이라면 답은 무엇인가?",
        "question_en": "Il-Woong is trying to find the larger of the two pages of the book he is looking at. If the sum of the two pages is 125, what is the answer?",
        "answer_ko": "63",
        "answer_en": "63",
        "solution_abst_ko": "125 2 [OP_FDIV] 1 [OP_ADD]",
        "solution_abst_en": "125 2 [OP_FDIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 125\nvar_b = 2\nvar_c = var_a // var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 125\nvar_b = 2\nvar_c = var_a // var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "5163": {
        "category": "Arithmetic calculation",
        "question_ko": "옷가게에서 어제 팔고 남은 티셔츠를 오늘 오전에 3/5만큼 팔았습니다. 오후에는 오전에 팔고도 남은 티셔츠와 새로 들여온 티셔츠를 합한 180장을 전부 팔았습니다. 오전에 판 티셔츠의 장수와 오후에 판 티셔츠가 장수가 같다면 어제 팔고 남은 티셔츠는 몇 장입니까?",
        "question_en": "The clothing store sold 3/5 of the T-shirts that were left from yesterday's sale this morning. In the afternoon, we sold 180 T-shirts in total, including surplus T-shirts of this morning and new T-shirts. If the number of T-shirts sold in the morning is equal to the number of T-shirts sold in the afternoon, how many T-shirts were left after selling yesterday?",
        "answer_ko": "300",
        "answer_en": "300",
        "solution_abst_ko": "180 3/5 [OP_DIV]",
        "solution_abst_en": "180 3/5 [OP_DIV]",
        "solution_code_ko": "var_a = 180\nvar_b = 0.6\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 180\nvar_b = 0.6\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "5164": {
        "category": "Possibility",
        "question_ko": "5 장의 숫자 카드 0, 1, 5, 7, 9를 한 번씩 사용하여 만들 수 있는 가장 큰 다섯 자리 수를 올림하여 백의 자리까지 나타내어 보시오.",
        "question_en": "Round up the largest five-digit number you can make by using the five number cards 0, 1, 5, 7, and 9 once to the hundredth digit.",
        "answer_ko": "97600",
        "answer_en": "97600",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 5 7 9 [OP_LIST_EOL] 5 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 3 [OP_CEIL]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 5 7 9 [OP_LIST_EOL] 5 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 3 [OP_CEIL]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 5\nvar_d = 7\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 5\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 3\nvar_j=int(((var_h+9*10**(var_i-2))//(10**(var_i-1)))*10**(var_i-1))\n\nprint(int(var_j))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 5\nvar_d = 7\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 5\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 3\nvar_j=int(((var_h+9*10**(var_i-2))//(10**(var_i-1)))*10**(var_i-1))\n\nprint(int(var_j))"
    },
    "5165": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 대하여 7로 나눈 몫이 12이고 나머지가 4이다. 어떤 수를 3으로 나눈다면 몫이 얼마일지 구하시오.",
        "question_en": "The quotient of a number divided by 7 is 12 and the remainder is 4. If this number is divided by 3, what is the quotient?",
        "answer_ko": "29",
        "answer_en": "29",
        "solution_abst_ko": "7 12 [OP_MUL] 4 [OP_ADD] 3 [OP_FDIV]",
        "solution_abst_en": "7 12 [OP_MUL] 4 [OP_ADD] 3 [OP_FDIV]",
        "solution_code_ko": "var_a = 7\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e // var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 7\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e // var_f\nprint(int(var_g))"
    },
    "5166": {
        "category": "Possibility",
        "question_ko": "민형이의 옷장에 상의가 2벌 있습니다. 오늘 4벌을 더 구매했다면 민형이가 내일 입을 상의를 고르는 경우의 수는 얼마인가요?",
        "question_en": "There are two tops in Minhyung's closet. If he bought 4 more today, how many cases of Minhyung choosing the top to wear tomorrow are there?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "2 4 [OP_ADD] 1 [OP_COMB]",
        "solution_abst_en": "2 4 [OP_ADD] 1 [OP_COMB]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 1\nvar_c = int(var_c)\nvar_d = int(var_d)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e * (var_c-i)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e / (i+1)\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 1\nvar_c = int(var_c)\nvar_d = int(var_d)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e * (var_c-i)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e / (i+1)\nprint(int(var_e))"
    },
    "5167": {
        "category": "Arithmetic calculation",
        "question_ko": "9 이하의 홀수 중 차가 가장 큰 두 숫자를 고르고, 고른 수의 곱을 구하시오.",
        "question_en": "Find the product of the two odd numbers that are not greater than 9 with the greatest difference.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "0 9 [OP_LIST_ODD] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MUL]",
        "solution_abst_en": "0 9 [OP_LIST_ODD] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MUL]",
        "solution_code_ko": "var_a = 0\nvar_b = 9\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[-var_c]\nvar_e = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = var_d * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 0\nvar_b = 9\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[-var_c]\nvar_e = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = var_d * var_f\nprint(int(var_g))"
    },
    "5168": {
        "category": "Arithmetic calculation",
        "question_ko": "오리 수의 5배 만큼 닭이 있고, 오리가 토끼보다 12마리 더 많습니다. 토끼가 4마리일 때, 닭, 오리, 토끼는 모두 몇 마리입니까?",
        "question_en": "There are five times as many chickens as ducks, and there are 12 more ducks than rabbits. If there are 4 rabbits, how many total number of chickens, ducks and rabbits are there?",
        "answer_ko": "100",
        "answer_en": "100",
        "solution_abst_ko": "4 4 12 [OP_ADD] [OP_ADD] 5 4 12 [OP_ADD] [OP_MUL] [OP_ADD]",
        "solution_abst_en": "4 4 12 [OP_ADD] [OP_ADD] 5 4 12 [OP_ADD] [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 4\nvar_c = 12\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nvar_f = 5\nvar_g = 4\nvar_h = 12\nvar_i = var_g + var_h\nvar_j = var_f * var_i\nvar_k = var_e + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 4\nvar_b = 4\nvar_c = 12\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nvar_f = 5\nvar_g = 4\nvar_h = 12\nvar_i = var_g + var_h\nvar_j = var_f * var_i\nvar_k = var_e + var_j\nprint(int(var_k))"
    },
    "5169": {
        "category": "Arithmetic calculation",
        "question_ko": "동훈이와 연정이는 둘레가 3킬로미터(㎞)인 운동장을 같은 곳에서 동시에 출발하여 서로 반대 방향으로 걸었다. 동훈이는 매분 100미터(m)의 속력으로, 연정이는 매분 150미터(m)의 속력으로 걸었을 때, 몇 분 후에 동훈이와 연정이가 처음으로 다시 만나는지 구하여라",
        "question_en": "Dong-hoon and Yeon-jeong started at the same place at the same time on a playground with a circumference of 3 km (km) and walked in opposite directions. When Donghun walks at a speed of 100 meters per minute (m) and Yeonjeong walks at a speed of 150 meters per minute (m), find how many minutes later Donghun and Yeonjeong meet again for the first time.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "3 100 1000 [OP_DIV] 150 1000 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_abst_en": "3 100 1000 [OP_DIV] 150 1000 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 3\nvar_b = 100\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = 150\nvar_f = 1000\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = var_a / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 3\nvar_b = 100\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = 150\nvar_f = 1000\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = var_a / var_h\nprint(int(var_i))"
    },
    "5170": {
        "category": "Correspondence",
        "question_ko": "영하는 집부터 목적지로 가는 길에 전체의 3/8을 버스로 가고, 나머지의 1/3을 택시를 타고 이동하고, 또 그 나머지의 4/5를 자전거를 타고 이동했더니 남은 거리가 1킬로미터(㎞) 200미터(m)였다. 이때 영하의 집부터 목적지까지의 거리 몇 미터(m)입니까?",
        "question_en": "On the way from the house to the destination, Youngha took a bus for 3/8 of the total, took a taxi for the remaining 1/3, and rode a bicycle for the remaining 4/5, so the remaining distance was 1 kilometer (km) was 200 meters (m). At this time, how many meters is the distance from Youngha's house to the destination?",
        "answer_ko": "14400",
        "answer_en": "14400",
        "solution_abst_ko": "1 1000 [OP_MUL] 200 [OP_ADD] 1 4/5 [OP_SUB] [OP_DIV] 1 1/3 [OP_SUB] [OP_DIV] 1 3/8 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "1 1000 [OP_MUL] 200 [OP_ADD] 1 4/5 [OP_SUB] [OP_DIV] 1 1/3 [OP_SUB] [OP_DIV] 1 3/8 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 200\nvar_e = var_c + var_d\nvar_f = 1\nvar_g = 0.8\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 1\nvar_k = 0.3333333333333333\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nvar_n = 1\nvar_o = 0.375\nvar_p = var_n - var_o\nvar_q = var_m / var_p\nprint(int(var_q))",
        "solution_code_en": "var_a = 1\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 200\nvar_e = var_c + var_d\nvar_f = 1\nvar_g = 0.8\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 1\nvar_k = 0.3333333333333333\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nvar_n = 1\nvar_o = 0.375\nvar_p = var_n - var_o\nvar_q = var_m / var_p\nprint(int(var_q))"
    },
    "5171": {
        "category": "Arithmetic calculation",
        "question_ko": "한 상자에 공책이 9권씩 들어있습니다. 공책이 모두 27권이라면 공책은 몇 상자입니까?",
        "question_en": "Each box contains 9 notebooks. If there are 27 notebooks in total, how many boxes are there?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "27 9 [OP_FDIV]",
        "solution_abst_en": "27 9 [OP_FDIV]",
        "solution_code_ko": "var_a = 27\nvar_b = 9\nvar_c = var_a // var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 27\nvar_b = 9\nvar_c = var_a // var_b\nprint(int(var_c))"
    },
    "5172": {
        "category": "Geometry",
        "question_ko": "수족관에서 새 수조를 구입했는데, 이 수조는 가로 20미터(m), 세로 12미터(m), 깊이 2미터(m)인 직육면체 모양이다. 수조는 위쪽을 제외한 나머지 면이 모두 유리로 되어있다. 유리로 되어있는 부분의 넓이는 모두 몇 제곱미터(㎡)인지 구하라.",
        "question_en": "You bought a new tank from the aquarium, and this tank is in the shape of a cuboid measuring 20 meters (m) long by 12 meters (m) wide and 2 meters (m) deep. The tank is made of glass on all sides except for the top. Find the area in square meters (m2) of all the glass parts.",
        "answer_ko": "368",
        "answer_en": "368",
        "solution_abst_ko": "20 12 [OP_MUL] 20 2 [OP_MUL] 2 [OP_MUL] [OP_ADD] 12 2 [OP_MUL] 2 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "20 12 [OP_MUL] 20 2 [OP_MUL] 2 [OP_MUL] [OP_ADD] 12 2 [OP_MUL] 2 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 20\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 20\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_c + var_h\nvar_j = 12\nvar_k = 2\nvar_l = var_j * var_k\nvar_m = 2\nvar_n = var_l * var_m\nvar_o = var_i + var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 20\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 20\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_c + var_h\nvar_j = 12\nvar_k = 2\nvar_l = var_j * var_k\nvar_m = 2\nvar_n = var_l * var_m\nvar_o = var_i + var_n\nprint(int(var_o))"
    },
    "5173": {
        "category": "Arithmetic calculation",
        "question_ko": "유정이네 반 학생 수는 30명입니다. 그중 26명의 영어 평균 점수는 82점입니다. 나머지 4명의 영어 점수가 각각 90점, 85점, 88점, 80점일 때, 유정이네 반 영어 평균 점수는 몇 점인지 소수점을 포함하여 답을 구하시오.",
        "question_en": "There are 30 students in Yujeong's class. The average English score of 26 of them is 82 points. If the English scores of the other four students are 90, 85, 88, and 80, respectively, find the answer what is the average English score of Yujeong's class including the decimal point.",
        "answer_ko": "82.50",
        "answer_en": "82.5",
        "solution_abst_ko": "26 82 [OP_MUL] 90 [OP_ADD] 85 [OP_ADD] 88 [OP_ADD] 80 [OP_ADD] 30 [OP_DIV]",
        "solution_abst_en": "26 82 [OP_MUL] 90 [OP_ADD] 85 [OP_ADD] 88 [OP_ADD] 80 [OP_ADD] 30 [OP_DIV]",
        "solution_code_ko": "var_a = 26\nvar_b = 82\nvar_c = var_a * var_b\nvar_d = 90\nvar_e = var_c + var_d\nvar_f = 85\nvar_g = var_e + var_f\nvar_h = 88\nvar_i = var_g + var_h\nvar_j = 80\nvar_k = var_i + var_j\nvar_l = 30\nvar_m = var_k / var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))",
        "solution_code_en": "var_a = 26\nvar_b = 82\nvar_c = var_a * var_b\nvar_d = 90\nvar_e = var_c + var_d\nvar_f = 85\nvar_g = var_e + var_f\nvar_h = 88\nvar_i = var_g + var_h\nvar_j = 80\nvar_k = var_i + var_j\nvar_l = 30\nvar_m = var_k / var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))"
    },
    "5174": {
        "category": "Correspondence",
        "question_ko": "어떤 수는 5.46에서 3.97을 뺀 값이다. 어떤 수에 5.46을 더하면 얼마인가?",
        "question_en": "A certain number equals 5.46 minus 3.97. What is the value of adding 5.46 to the certain number?",
        "answer_ko": "6.95",
        "answer_en": "6.95",
        "solution_abst_ko": "5.46 5.46 3.97 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "5.46 5.46 3.97 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 5.46\nvar_b = 5.46\nvar_c = 3.97\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 5.46\nvar_b = 5.46\nvar_c = 3.97\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "5175": {
        "category": "Correspondence",
        "question_ko": "승효는 병원에서 약을 426밀리리터(㎖) 받아왔습니다. 의사 선생님께서 하루에 전체 약의 0.06만큼 먹으라고 하셨습니다. 승효는 하루에 몇 밀리리터(㎖)의 약을 먹어야할까요?",
        "question_en": "Seunghyo received 426 milliliters (ml) of medicine from the hospital. The doctor prescribed to take 0.06 of the total medicine per day. How many milliliters (ml) should Seunghyo take?",
        "answer_ko": "25.56",
        "answer_en": "25.56",
        "solution_abst_ko": "426 0.06 [OP_MUL]",
        "solution_abst_en": "426 0.06 [OP_MUL]",
        "solution_code_ko": "var_a = 426\nvar_b = 0.06\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 426\nvar_b = 0.06\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "5176": {
        "category": "Possibility",
        "question_ko": "2, 4, 5, 3을 각각 한 번씩 사용하여 만든 네 자리 수들의 총합을 구하여라.",
        "question_en": "Find the sum of the four-digit numbers formed by using 2, 4, 5, and 3 once each.",
        "answer_ko": "93324",
        "answer_en": "93324",
        "solution_abst_ko": "[OP_LIST_SOL] 2 4 5 3 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 2 4 5 3 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = 5\nvar_d = 3\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = 5\nvar_d = 3\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint(int(var_f))"
    },
    "5177": {
        "category": "Arithmetic calculation",
        "question_ko": "학생 254명을 버스에 나눠 태우려고 합니다. 버스 한 대에 30명씩 태우고 남는 자리 없이 학생을 태우려고 한다면 학생 몇 명을 더 태워야 하나요?",
        "question_en": "254 students are going to be assigned to several buses. If there are 30 people on each bus and there are no seats left, how many more students are needed?",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "30 254 30 [OP_MOD] [OP_SUB]",
        "solution_abst_en": "30 254 30 [OP_MOD] [OP_SUB]",
        "solution_code_ko": "var_a = 30\nvar_b = 254\nvar_c = 30\nvar_d = var_b % var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 30\nvar_b = 254\nvar_c = 30\nvar_d = var_b % var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "5178": {
        "category": "Arithmetic calculation",
        "question_ko": "일웅이네 드라이브에는 1번부터 25번 폴더까지 있고, 각 폴더마다 10개의 하위폴더가 있습니다. 각 하위폴더마다 8개의 파일이 있다면, 일웅이네 드라이브에는 모두 몇 개의 파일이 있습니까?",
        "question_en": "In Ilwoong's drive, there are folders numbered 1 to 25, and each folder has 10 subfolders. If there are 8 files in each subfolder, how many files are there in Ilwoong's drive?",
        "answer_ko": "2000",
        "answer_en": "2000",
        "solution_abst_ko": "25 10 [OP_MUL] 8 [OP_MUL]",
        "solution_abst_en": "25 10 [OP_MUL] 8 [OP_MUL]",
        "solution_code_ko": "var_a = 25\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 25\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "5179": {
        "category": "Possibility",
        "question_ko": "5마리의 토끼가 호수에 소풍을 가려고 합니다. 이때, 2개의 호수가 있을 때 토끼가 호수를 선택하는 경우는 모두 몇 가지입니까?",
        "question_en": "Five rabbits are going to have a picnic at the lake. In this case, if there are 2 lakes, how many ways can a rabbit choose a lake?",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "2 5 [OP_POW]",
        "solution_abst_en": "2 5 [OP_POW]",
        "solution_code_ko": "var_a = 2\nvar_b = 5\nvar_c = var_a ** var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 5\nvar_c = var_a ** var_b\nprint(int(var_c))"
    },
    "5180": {
        "category": "Correspondence",
        "question_ko": "상준은 경제 분야 책을 전체 책의 4분의 1보다 10권 더 많이 갖고 있다, 사회 분야 책은 나머지 책의 3/5보다 5권 덜 가지고 있고, 12권은 과학 분야 책이다. 상준이가 경제학, 사회, 과학이 아닌 책을 13권 가지고 있다면, 상준은 총 몇 권의 책을 가지고 있습니까?",
        "question_en": "Sang-jun has 10 more books on economics than a quarter of his total books, 5 fewer books on social studies than 3/5 of the rest, and 12 books on science. If Sang-jun has 13 books that are not economics, social studies, or science, how many books does Sang-jun have in total?",
        "answer_ko": "80",
        "answer_en": "80",
        "solution_abst_ko": "13 12 [OP_ADD] 5 [OP_SUB] 1 3/5 [OP_SUB] [OP_DIV] 10 [OP_ADD] 1 1 4 [OP_DIV] [OP_SUB] [OP_DIV]",
        "solution_abst_en": "13 12 [OP_ADD] 5 [OP_SUB] 1 3/5 [OP_SUB] [OP_DIV] 10 [OP_ADD] 1 1 4 [OP_DIV] [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 13\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = 0.6\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 10\nvar_k = var_i + var_j\nvar_l = 1\nvar_m = 1\nvar_n = 4\nvar_o = var_m / var_n\nvar_p = var_l - var_o\nvar_q = var_k / var_p\nprint(int(var_q))",
        "solution_code_en": "var_a = 13\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = 0.6\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 10\nvar_k = var_i + var_j\nvar_l = 1\nvar_m = 1\nvar_n = 4\nvar_o = var_m / var_n\nvar_p = var_l - var_o\nvar_q = var_k / var_p\nprint(int(var_q))"
    },
    "5181": {
        "category": "Arithmetic calculation",
        "question_ko": "인형 공장에 기계가 2대 있습니다. 인형을 (가) 기계는 4시간에 256개, (나) 기계는 3시간에 111개를 만듭니다. 같은 빠르기로 3시간 동안 (가) 기계와 (나) 기계를 같이 돌리면 인형을 모두 몇 개 만들 수 있습니까?",
        "question_en": "There are 2 machines in the doll factory. (A) machine makes 256 dolls in 4 hours, and (B) machine makes 111 dolls in 3 hours. How many dolls can you make if you run (A) machine and (B) together for 3 hours at the same speed?",
        "answer_ko": "303",
        "answer_en": "303",
        "solution_abst_ko": "256 3 4 [OP_DIV] [OP_MUL] 111 [OP_ADD]",
        "solution_abst_en": "256 3 4 [OP_DIV] [OP_MUL] 111 [OP_ADD]",
        "solution_code_ko": "var_a = 256\nvar_b = 3\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 111\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 256\nvar_b = 3\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 111\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "5182": {
        "category": "Possibility",
        "question_ko": "7, 4, 0, 3, 5 중에서 서로 다른 숫자 2개를 뽑아 두 자리 수를 만들려고 합니다. 만들 수 있는 수 중에서 셋째로 큰 수와 셋째로 작은 수의 합을 구하시오.",
        "question_en": "You want to create a two-digit number by selecting two different numbers from 7, 4, 0, 3, and 5. Find the sum of the third largest number and the third smallest number possible.",
        "answer_ko": "108",
        "answer_en": "108",
        "solution_abst_ko": "[OP_LIST_SOL] 7 4 0 3 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 7 4 0 3 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 7\nvar_b = 4\nvar_c = 0\nvar_d = 3\nvar_e = 5\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 7\nvar_b = 4\nvar_c = 0\nvar_d = 3\nvar_e = 5\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h + var_j\nprint(int(var_k))"
    },
    "5183": {
        "category": "Arithmetic calculation",
        "question_ko": "같은 무게의 아령이 16개 든 상자의 무게는 17.88킬로그램(㎏)입니다. 빈 상자의 무게가 0.6킬로그램(㎏)이라면 아령 7개는 몇 킬로그램(㎏)일까요?",
        "question_en": "There is a box of 16 dumbbells weighing 17.88 kilograms (kg). If the empty box weighs 0.6 kilograms (kg) and all dumbbells weigh the same, how many kilograms (kg) are 7 dumbbells?",
        "answer_ko": "7.56",
        "answer_en": "7.56",
        "solution_abst_ko": "17.88 0.6 [OP_SUB] 16 [OP_DIV] 7 [OP_MUL]",
        "solution_abst_en": "17.88 0.6 [OP_SUB] 16 [OP_DIV] 7 [OP_MUL]",
        "solution_code_ko": "var_a = 17.88\nvar_b = 0.6\nvar_c = var_a - var_b\nvar_d = 16\nvar_e = var_c / var_d\nvar_f = 7\nvar_g = var_e * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 17.88\nvar_b = 0.6\nvar_c = var_a - var_b\nvar_d = 16\nvar_e = var_c / var_d\nvar_f = 7\nvar_g = var_e * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "5184": {
        "category": "Geometry",
        "question_ko": "네 변의 길이의 합이 38센티미터(㎝)이고 가로가 15센티미터(㎝)인 직사각형과 네 변의 길이의 합이 36센티미터(㎝)인 직사각형의 넓이의 차를 구하시오.",
        "question_en": "Find the difference between the area of a rectangle whose sum of its sides is 38 centimeters (cm) and its width is 15 centimeters (cm) and the rectangle whose sum of its sides is 36 centimeters (cm).",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "36 4 [OP_DIV] 2 [OP_POW] 38 2 [OP_DIV] 15 [OP_SUB] 15 [OP_MUL] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "36 4 [OP_DIV] 2 [OP_POW] 38 2 [OP_DIV] 15 [OP_SUB] 15 [OP_MUL] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 36\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 38\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = 15\nvar_j = var_h - var_i\nvar_k = 15\nvar_l = var_j * var_k\nvar_m = var_e - var_l\nvar_n = abs(var_m)\nprint(int(var_n))",
        "solution_code_en": "var_a = 36\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 38\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = 15\nvar_j = var_h - var_i\nvar_k = 15\nvar_l = var_j * var_k\nvar_m = var_e - var_l\nvar_n = abs(var_m)\nprint(int(var_n))"
    },
    "5185": {
        "category": "Arithmetic calculation",
        "question_ko": "장난감 공장에서 기계 A는 장난감 1개를 만드는데 3시간이 걸리고, 기계 B는 장난감 1개를 만드는데 5시간이 걸린다. 두 기계로 장난감 16개를 만드는데 걸린 시간이 얼마인지 구하시오.",
        "question_en": "In a toy factory, machine A takes 3 hours to make 1 toy, and machine B takes 5 hours to make 1 toy. Find the time it took to make 16 toys with the two machines.",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "1 16 [OP_MUL] 1 5 [OP_DIV] 1 3 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_abst_en": "1 16 [OP_MUL] 1 5 [OP_DIV] 1 3 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 5\nvar_f = var_d / var_e\nvar_g = 1\nvar_h = 3\nvar_i = var_g / var_h\nvar_j = var_f + var_i\nvar_k = var_c / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 1\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 5\nvar_f = var_d / var_e\nvar_g = 1\nvar_h = 3\nvar_i = var_g / var_h\nvar_j = var_f + var_i\nvar_k = var_c / var_j\nprint(int(var_k))"
    },
    "5186": {
        "category": "Arithmetic calculation",
        "question_ko": "A,B,C 세 학교가 있습니다. A와 C학교 학생수의 합은 210입니다. A학교의 학생수는 B학교 학생수의 4배이고, C학교의 학생수는 B학교 학생수의 3배일때 B학교 학생수는 몇 명인가?",
        "question_en": "There are three schools A, B and C. The sum of the students in schools A and C is 210. If the number of students in school A is 4 times the number of students in school B, and the number of students in school C is 3 times the number of students in school B, what is the number of students in school B?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "210 4 3 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "210 4 3 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 210\nvar_b = 4\nvar_c = 3\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 210\nvar_b = 4\nvar_c = 3\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "5187": {
        "category": "Comparison",
        "question_ko": "지민이네 집에서 학교까지의 거리는 2킬로미터(㎞) 280미터(m)이고, 병원까지의 거리는 4125미터(m)입니다. 병원과 학교 중 지민이네 집에서 더 먼 곳은 어디입니까?",
        "question_en": "The distance from Jimin's house to the school is 2 kilometers (km) and 280 meters (m), and the distance to the hospital is 4125 meters (m). Which is farther from Jimin's house, the hospital or the school?",
        "answer_ko": "병원",
        "answer_en": "hospital",
        "solution_abst_ko": "[OP_LIST_SOL] 학교 병원 [OP_LIST_EOL] [OP_LIST_SOL] 2 1000 [OP_MUL] 280 [OP_ADD] 4125 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] school hospital [OP_LIST_EOL] [OP_LIST_SOL] 2 1000 [OP_MUL] 280 [OP_ADD] 4125 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '학교'\nvar_b = '병원'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 280\nvar_g = var_e + var_f\nvar_h = 4125\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'school'\nvar_b = 'hospital'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 280\nvar_g = var_e + var_f\nvar_h = 4125\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "5188": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 5와 6으로 나누면 나누어떨어지고 7로 나누면 나머지가 6이라고 합니다. 어떤 수 중에서 가장 큰 네 자리 수를 구하시오.",
        "question_en": "If you divide a number by 5 and 6, you divide it and if you divide by 7, the rest is 6. Find the largest four-digit number in any number.",
        "answer_ko": "9960",
        "answer_en": "9960",
        "solution_abst_ko": "1000 9999 1 [OP_LIST_ARANGE] 5 6 [OP_LCM] [OP_LIST_DIVISIBLE] 7 6 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MAX]",
        "solution_abst_en": "1000 9999 1 [OP_LIST_ARANGE] 5 6 [OP_LCM] [OP_LIST_DIVISIBLE] 7 6 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nvar_e = 6\nvar_f = var_e * var_d / math.gcd(int(var_e), int(var_d))\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nvar_g = 7\nvar_h = 6\nlist_c = [] \nvar_g = int(var_g)\nvar_h = int(var_h)\nif var_h < 0:\n    var_h = var_h + var_g\nfor i in list_b:\n    i = int(i)\n    if i%var_g == var_h:\n        list_c.append(i)\nvar_i = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_j = list_d[-var_i]\nprint(int(var_j))",
        "solution_code_en": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nvar_e = 6\nvar_f = var_e * var_d / math.gcd(int(var_e), int(var_d))\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nvar_g = 7\nvar_h = 6\nlist_c = [] \nvar_g = int(var_g)\nvar_h = int(var_h)\nif var_h < 0:\n    var_h = var_h + var_g\nfor i in list_b:\n    i = int(i)\n    if i%var_g == var_h:\n        list_c.append(i)\nvar_i = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_j = list_d[-var_i]\nprint(int(var_j))"
    },
    "5189": {
        "category": "Comparison",
        "question_ko": "28개씩 들어있는 쿠키 상자는 40상자를 팔았고, 15개씩 들어있는 마카롱 상자는 65상자를 팔았습니다. 쿠키와 마카롱 중 더 많이 팔린 것은 무엇입니까?",
        "question_en": "A bakery sold 40 boxes of cookies maintaining 28 for each, and 65 boxes of macarons that have 15 for each. Which item was sold more: cookies or macarons?",
        "answer_ko": "쿠키",
        "answer_en": "cookies",
        "solution_abst_ko": "[OP_LIST_SOL] 쿠키 마카롱 [OP_LIST_EOL] [OP_LIST_SOL] 28 40 [OP_MUL] 15 65 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] cookies macarons [OP_LIST_EOL] [OP_LIST_SOL] 28 40 [OP_MUL] 15 65 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '쿠키'\nvar_b = '마카롱'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 28\nvar_d = 40\nvar_e = var_c * var_d\nvar_f = 15\nvar_g = 65\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'cookies'\nvar_b = 'macarons'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 28\nvar_d = 40\nvar_e = var_c * var_d\nvar_f = 15\nvar_g = 65\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "5190": {
        "category": "Arithmetic calculation",
        "question_ko": "호석이의 국어, 영어, 과학의 평균 점수는 89점입니다. 호석이가 사회 시험을 본 후 평균 점수가 1점 올랐다고 할 때, 호석이의 사회 점수는 몇 점입니까?",
        "question_en": "Hoseok's average score in Korean, English, and Science is 89. If Hoseok's average score increases by 1 after taking the Social studies test, what is the score of Social studies?",
        "answer_ko": "93",
        "answer_en": "93",
        "solution_abst_ko": "89 1 [OP_ADD] 4 [OP_MUL] 89 3 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "89 1 [OP_ADD] 4 [OP_MUL] 89 3 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 89\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c * var_d\nvar_f = 89\nvar_g = 3\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 89\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c * var_d\nvar_f = 89\nvar_g = 3\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nprint(int(var_i))"
    },
    "5191": {
        "category": "Geometry",
        "question_ko": "정호는 한 변의 길이가 24센티미터(㎝)인 정사각형 모양의 종이를 많이 모으려고 한다. 가로 172센티미터(㎝), 세로 295센티미터(㎝)인 도화지를 잘라서 만드려고 할 때, 몇 개까지 만들 수 있는가?",
        "question_en": "Jeong-ho wants to collect lots of square-shaped papers with sides measuring 24 centimeters (cm). How many pieces can you make by cutting a piece of drawing paper that is 172 centimeters (cm) wide and 295 centimeters (cm) long?",
        "answer_ko": "84",
        "answer_en": "84",
        "solution_abst_ko": "172 24 [OP_FDIV] 295 24 [OP_FDIV] [OP_MUL]",
        "solution_abst_en": "172 24 [OP_FDIV] 295 24 [OP_FDIV] [OP_MUL]",
        "solution_code_ko": "var_a = 172\nvar_b = 24\nvar_c = var_a // var_b\nvar_d = 295\nvar_e = 24\nvar_f = var_d // var_e\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 172\nvar_b = 24\nvar_c = var_a // var_b\nvar_d = 295\nvar_e = 24\nvar_f = var_d // var_e\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "5192": {
        "category": "Comparison",
        "question_ko": "석진이는 수영 시합에 나갔는데 8번째로 들어왔습니다. 석진이보다 빨리 들어온 사람은 몇 명입니까?",
        "question_en": "Seokjin went to the swimming competition and came in 8th. What is the number of people who came in faster than Seokjin?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "8 1 [OP_SUB]",
        "solution_abst_en": "8 1 [OP_SUB]",
        "solution_code_ko": "var_a = 8\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 8\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "5193": {
        "category": "Correspondence",
        "question_ko": "360÷(A×A×A/B)=5의 식을 만족하는 가장 작은 자연수 A를 구하여라.",
        "question_en": "Find the smallest natural number A that satisfies the equation 360÷(A×A×A/B)=5.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "360÷(A×A×A/B)=5 A [OP_NUM_UNK_SOLVER] 1 [OP_LIST_MIN]",
        "solution_abst_en": "360÷(A×A×A/B)=5 A [OP_NUM_UNK_SOLVER] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = '360÷(A×A×A/B)=5'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[var_c-1]\nprint(int(var_d))",
        "solution_code_en": "var_a = '360÷(A×A×A/B)=5'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[var_c-1]\nprint(int(var_d))"
    },
    "5194": {
        "category": "Comparison",
        "question_ko": "유나는 마트에서 7번째로 줄을 섰고, 유정이는 바로 뒤에 줄을 섰습니다. 유정이는 몇 번째로 섰습니까?",
        "question_en": "Yuna was 7th in line at the mart, and Yoojeong was right behind her. What number of position is Yoojung standing?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "7 1 [OP_ADD]",
        "solution_abst_en": "7 1 [OP_ADD]",
        "solution_code_ko": "var_a = 7\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 7\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "5195": {
        "category": "Correspondence",
        "question_ko": "소수 두 자리 수 12.4A<12.45보다 작다고 할 때, A에 들어갈 수 있는 숫자의 개수는 몇 개입니까?",
        "question_en": "If the two decimal numbers 12.4A is less than 12.45, how many digits can fit in A?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "12.4A<12.45 A [OP_DIGIT_UNK_SOLVER] [OP_LIST_LEN]",
        "solution_abst_en": "12.4A<12.45 A [OP_DIGIT_UNK_SOLVER] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '12.4A<12.45'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = len(list_a)\nprint(int(var_c))",
        "solution_code_en": "var_a = '12.4A<12.45'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = len(list_a)\nprint(int(var_c))"
    },
    "5196": {
        "category": "Arithmetic calculation",
        "question_ko": "빨간색 종이테이프는 20센티미터(㎝)이고, 보라색 종이테이프는 16센티미터(㎝)입니다. 두 종이테이프는 평균 몇 센티미터(㎝)입니까?",
        "question_en": "A red paper tape is 20 centimeters (cm) long and a purple paper tape is 16 centimeters (cm) long. Find out the average length of the two paper tapes in centimeters (cm).",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "20 16 [OP_ADD] 2 [OP_DIV]",
        "solution_abst_en": "20 16 [OP_ADD] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 20\nvar_b = 16\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 16\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "5197": {
        "category": "Geometry",
        "question_ko": "길이가 100센티미터(㎝)인 색테이프로 정사각형 모양을 만들려고 합니다. 한 변의 길이는 몇 센티미터(㎝)로 해야 합니까?",
        "question_en": "You are going to make a square shape with colored tape that is 100 centimeters (cm) long. How many centimeters (cm) should each side be?",
        "answer_ko": "25",
        "answer_en": "25",
        "solution_abst_ko": "100 4 [OP_DIV]",
        "solution_abst_en": "100 4 [OP_DIV]",
        "solution_code_ko": "var_a = 100\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 100\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "5198": {
        "category": "Correspondence",
        "question_ko": "7개의 선물을 포장하면서 동일한 길이의 리본을 사용했습니다. 사용한 리본의 길이는 50.68센티미터(㎝) 입니다. 하나의 선물을 포장하는데 사용한 리본은 몇 센티미터(㎝)인지 구하십시오.",
        "question_en": "I used the same length of ribbon while wrapping 7 presents. The length of the ribbon used is 50.68 centimeters (cm). Find how many centimeters (cm) of ribbon were used to wrap one gift.",
        "answer_ko": "7.24",
        "answer_en": "7.24",
        "solution_abst_ko": "50.68 7 [OP_DIV]",
        "solution_abst_en": "50.68 7 [OP_DIV]",
        "solution_code_ko": "var_a = 50.68\nvar_b = 7\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 50.68\nvar_b = 7\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "5199": {
        "category": "Arithmetic calculation",
        "question_ko": "유나의 국어와 영어의 평균 점수는 92점입니다. 유나가 수학 시험을 본 후, 유나의 전체 평균 점수가 2점 올랐다고 할 때, 유나의 수학 점수는 몇 점입니까?",
        "question_en": "Yuna's average score in Korean and English is 92 points. If Yuna's overall average score increases by 2 points after taking the math test, what is Yuna's math score?",
        "answer_ko": "98",
        "answer_en": "98",
        "solution_abst_ko": "92 2 [OP_ADD] 3 [OP_MUL] 92 2 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "92 2 [OP_ADD] 3 [OP_MUL] 92 2 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 92\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c * var_d\nvar_f = 92\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 92\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c * var_d\nvar_f = 92\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nprint(int(var_i))"
    },
    "5200": {
        "category": "Arithmetic calculation",
        "question_ko": "연필 1타는 12자루입니다. 연필 3타를 학생 11명이 3자루씩 나누어 가졌습니다. 학생들이 나누어 가지고 남은 연필은 몇 자루입니까?",
        "question_en": "One dozen of pencils is 12 pencils. 11 students took 3 pencils each from 3 dozen pencils. How many pencils are left after students took them?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "12 3 [OP_MUL] 11 3 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "12 3 [OP_MUL] 11 3 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 12\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 11\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 12\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 11\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "5201": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 31까지 숫자 3은 몇 번 등장합니까?",
        "question_en": "How many times does the number 3 appear from 1 to 31?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "1 31 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 3 [OP_LIST_FIND_NUM] 1 [OP_ADD]",
        "solution_abst_en": "1 31 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 3 [OP_LIST_FIND_NUM] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 31\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 3\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nvar_g = 1\nvar_h = var_f + var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 1\nvar_b = 31\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 3\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nvar_g = 1\nvar_h = var_f + var_g\nprint(int(var_h))"
    },
    "5202": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 8.5센티미터(㎝)인 정사각형 3.2개를 일렬로 붙여서 만들 수 있는 직사각형의 넓이는 몇 제곱센티미터(㎠)입니까?",
        "question_en": "What is the area in square centimeters (cm2) of a rectangle that can be formed by attaching 3.2 squares with sides of 8.5 centimeters (cm) in a row?",
        "answer_ko": "231.20",
        "answer_en": "231.2",
        "solution_abst_ko": "8.5 2 [OP_POW] 3.2 [OP_MUL]",
        "solution_abst_en": "8.5 2 [OP_POW] 3.2 [OP_MUL]",
        "solution_code_ko": "var_a = 8.5\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 3.2\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 8.5\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 3.2\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "5203": {
        "category": "Arithmetic calculation",
        "question_ko": "색종이 24장, 도화지 18장을 될 수 있는 대로 많은 학생들에게 남김없이 똑같이 나누어 주려고 합니다. 몇 명에게 나누어 줄 수 있을까요?",
        "question_en": "24 sheets of colored paper and 18 sheets of drawing paper will be distributed equally to as many students as possible. How many people can get the papers?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "24 18 [OP_GCD]",
        "solution_abst_en": "24 18 [OP_GCD]",
        "solution_code_ko": "var_a = 24\nvar_b = 18\nvar_c = math.gcd(int(var_b), int(var_a))\nprint(int(var_c))",
        "solution_code_en": "var_a = 24\nvar_b = 18\nvar_c = math.gcd(int(var_b), int(var_a))\nprint(int(var_c))"
    },
    "5204": {
        "category": "Comparison",
        "question_ko": "27명이 서있는 줄에서 민영이는 뒤에서 13번째에 서있을 때, 앞에서는 몇 번째인지 구하시오.",
        "question_en": "In a line of 27 people, if Minyoung is standing in the13th from the back, where is she placed from the front?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "27 13 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "27 13 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 27\nvar_b = 13\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 27\nvar_b = 13\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "5205": {
        "category": "Possibility",
        "question_ko": "빨간 공 3개, 파란 공 2개, 노란 공 5개가 담겨져 있는 상자에서 파란 공 1개를 뺐을 때, 빨간 공의 개수는?",
        "question_en": "If one blue ball is removed from a box containing 3 red balls, 2 blue balls and 5 yellow balls, what is the number of red balls?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "3",
        "solution_abst_en": "3",
        "solution_code_ko": "var_a = 3\nprint(int(var_a))",
        "solution_code_en": "var_a = 3\nprint(int(var_a))"
    },
    "5206": {
        "category": "Possibility",
        "question_ko": "9 이하의 짝수를 한 번씩 모두 사용하여 만들 수 있는 네 자리 수는 총 몇 가지 입니까?",
        "question_en": "How many four-digit numbers can be formed by using all even numbers less than or equal to 9 once?",
        "answer_ko": "96",
        "answer_en": "96",
        "solution_abst_ko": "0 9 [OP_LIST_EVEN] 4 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "0 9 [OP_LIST_EVEN] 4 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 9\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = len(list_b)\nprint(int(var_d))",
        "solution_code_en": "var_a = 0\nvar_b = 9\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = len(list_b)\nprint(int(var_d))"
    },
    "5207": {
        "category": "Arithmetic calculation",
        "question_ko": "바구니에 귤이 몇 개 있었습니다. 은지가 9개를 먹고 어머니께서 5개를 바구니에 더 넣었더니 20개가 되었습니다. 처음에 바구니에 있던 귤은 몇 개입니까?",
        "question_en": "There were some tangerines in the basket. Eunji ate 9 pieces, and mother put 5 more in the basket, and it became 20 pieces. How many tangerines were in the basket at the beginning?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "20 9 [OP_ADD] 5 [OP_SUB]",
        "solution_abst_en": "20 9 [OP_ADD] 5 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 9\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 9\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "5208": {
        "category": "Comparison",
        "question_ko": "달에서 몸무게를 재면 지구에서 재는 몸무게의 1/6이라고 합니다. 연진이는 지구에서 몸무게를 쟀더니 50킬로그램(㎏)이었고, 호동이는 달에서 쟀더니 몸무게가 8과 4/6킬로그램(㎏)이었습니다. 달에서 잰 몸무게는 누가 더 많이 나가는지 답을 구하세요.",
        "question_en": "If you weigh on the moon, it is said to be 1/6 of your weight on Earth. Yeonjin weighed 50 kilograms (kg) on Earth, and Hodong weighed 8 and 4/6 kilograms (kg) when measured on the moon. Find the answer of who weighs more on the moon.",
        "answer_ko": "호동",
        "answer_en": "Hodong",
        "solution_abst_ko": "[OP_LIST_SOL] 연진 호동 [OP_LIST_EOL] [OP_LIST_SOL] 50 1/6 [OP_MUL] 8 4/6 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yeonjin Hodong [OP_LIST_EOL] [OP_LIST_SOL] 50 1/6 [OP_MUL] 8 4/6 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '연진'\nvar_b = '호동'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 50\nvar_d = 0.16666666666666666\nvar_e = var_c * var_d\nvar_f = 8\nvar_g = 0.6666666666666666\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Yeonjin'\nvar_b = 'Hodong'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 50\nvar_d = 0.16666666666666666\nvar_e = var_c * var_d\nvar_f = 8\nvar_g = 0.6666666666666666\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "5209": {
        "category": "Correspondence",
        "question_ko": "200이상 500이하의 자연수 중 5로 나눈 나머지가 2이고, 8로 나눈 나머지가 3이고 9로 나눈 나머지가 0인 값을 구하시오.",
        "question_en": "Among the natural numbers between 200 and 500, find the value whose remainder when divided by 5 is 2, when divided by 8 is 3, and when divided by 9 is 0.",
        "answer_ko": "387",
        "answer_en": "387",
        "solution_abst_ko": "200 500 1 [OP_LIST_ARANGE] 5 2 [OP_LIST_DIVIDE_AND_REMAIN] 8 3 [OP_LIST_DIVIDE_AND_REMAIN] 9 0 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "200 500 1 [OP_LIST_ARANGE] 5 2 [OP_LIST_DIVIDE_AND_REMAIN] 8 3 [OP_LIST_DIVIDE_AND_REMAIN] 9 0 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 200\nvar_b = 500\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nvar_e = 2\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 8\nvar_g = 3\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 9\nvar_i = 0\nlist_d = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_c:\n    i = int(i)\n    if i%var_h == var_i:\n        list_d.append(i)\nvar_j = 1\nvar_k = list_d[var_j-1]\nprint(int(var_k))",
        "solution_code_en": "var_a = 200\nvar_b = 500\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nvar_e = 2\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 8\nvar_g = 3\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 9\nvar_i = 0\nlist_d = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_c:\n    i = int(i)\n    if i%var_h == var_i:\n        list_d.append(i)\nvar_j = 1\nvar_k = list_d[var_j-1]\nprint(int(var_k))"
    },
    "5210": {
        "category": "Possibility",
        "question_ko": "0, 1, 2중 다른 2개를 골라 만들 수 있는 두 자리 자연수의 개수는 몇 가지입니까?",
        "question_en": "How many two-digit natural numbers can be formed by choosing two figures among 0, 1, and 2?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "5211": {
        "category": "Correspondence",
        "question_ko": "세 자리 수 A76을 백의 자리에서 버림한 값은 700입니다. A의 값을 구하시오.",
        "question_en": "The three-digit number A76 rounded down to the hundreds place is 700. Find the value of A.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "A76 [OP_GEN_POSSIBLE_LIST] 700 [OP_LIST_MORE_EQUAL] 700 100 [OP_ADD] [OP_LIST_LESS] A76 A [OP_LIST_FIND_UNK]",
        "solution_abst_en": "A76 [OP_GEN_POSSIBLE_LIST] 700 [OP_LIST_MORE_EQUAL] 700 100 [OP_ADD] [OP_LIST_LESS] A76 A [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = 'A76'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 700\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 700\nvar_d = 100\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = 'A76'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))",
        "solution_code_en": "var_a = 'A76'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 700\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 700\nvar_d = 100\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = 'A76'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))"
    },
    "5212": {
        "category": "Correspondence",
        "question_ko": "어떤 세 자리 수는 백의 자리가 9이고, 7로 나누면 나누어떨어진다고 할 때, 이것을 만족하는 세 자리 수는 모두 몇 개인지 구하시오.",
        "question_en": "If a three-digit number has a hundredth place of 9 and is divisible by 7, how many three-digit numbers satisfy this condition?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "9 100 [OP_MUL] 9 100 [OP_MUL] 99 [OP_ADD] 1 [OP_LIST_ARANGE] 7 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "9 100 [OP_MUL] 9 100 [OP_MUL] 99 [OP_ADD] 1 [OP_LIST_ARANGE] 7 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 9\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = 100\nvar_f = var_d * var_e\nvar_g = 99\nvar_h = var_f + var_g\nvar_i = 1\nlist_a = [i for i in range(var_c, var_h + 1, var_i)]\nvar_j = 7\nlist_b = []\nvar_j = int(var_j)\nfor i in list_a:\n    i = int(i)\n    if i % var_j == 0:\n        list_b.append(i)\nvar_k = len(list_b)\nprint(int(var_k))",
        "solution_code_en": "var_a = 9\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = 100\nvar_f = var_d * var_e\nvar_g = 99\nvar_h = var_f + var_g\nvar_i = 1\nlist_a = [i for i in range(var_c, var_h + 1, var_i)]\nvar_j = 7\nlist_b = []\nvar_j = int(var_j)\nfor i in list_a:\n    i = int(i)\n    if i % var_j == 0:\n        list_b.append(i)\nvar_k = len(list_b)\nprint(int(var_k))"
    },
    "5213": {
        "category": "Possibility",
        "question_ko": "서로 다른 과자 5개 중 3개를 골라 사려고 할 때, 경우의 수를 구하시오.",
        "question_en": "Find the number of possibilities when choosing to buy 3 out of 5 different sweets.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "5 3 [OP_COMB]",
        "solution_abst_en": "5 3 [OP_COMB]",
        "solution_code_ko": "var_a = 5\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))"
    },
    "5214": {
        "category": "Geometry",
        "question_ko": "정수네 집에는 넓이가 143.2제곱미터(㎡)인 직사각형 모양의 꽃밭이 있습니다. 이 꽃밭의 세로가 4미터(m) 일 때, 가로는 몇 미터(m)입니까?",
        "question_en": "Jeong Su's house has a rectangular flower garden with an area of 143.2 square meters (㎡). If the length of this flower field is 4 meters (m), how many meters (m) is the width?",
        "answer_ko": "35.80",
        "answer_en": "35.8",
        "solution_abst_ko": "143.2 4 [OP_DIV]",
        "solution_abst_en": "143.2 4 [OP_DIV]",
        "solution_code_ko": "var_a = 143.2\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 143.2\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "5215": {
        "category": "Geometry",
        "question_ko": "16개의 사탕이 들어있는 봉지를 25개 샀습니다. 현지와 수현이가 사탕을 똑같이 나눠가지면 현지가 가지는 사탕은 몇 개입니까?",
        "question_en": "Hyunji bought 25 bags having 16 candies. If Hyunji shared candy with Soohyeon equally, how many candies did Hyunji get?",
        "answer_ko": "200",
        "answer_en": "200",
        "solution_abst_ko": "25 16 [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "25 16 [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 25\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 25\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "5216": {
        "category": "Arithmetic calculation",
        "question_ko": "(가) 반 학생들 중에서 사회를 좋아하는 학생은 25명이고, 음악을 좋아하는 학생은 32명이고, 사회와 음악을 모두 좋아하는 학생은 27명입니다. 사회와 음악을 모두 좋아하지 않는 학생이 한 명도 없을 때, (가) 반 학생은 모두 몇 명입니까?",
        "question_en": "Among the students in class (A), 25 students like social studies, 32 students like music, and 27 students like both social studies and music. If there is no student who dislikes both social studies and music, how many students are in class (A)?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "25 32 [OP_ADD] 27 [OP_SUB]",
        "solution_abst_en": "25 32 [OP_ADD] 27 [OP_SUB]",
        "solution_code_ko": "var_a = 25\nvar_b = 32\nvar_c = var_a + var_b\nvar_d = 27\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 25\nvar_b = 32\nvar_c = var_a + var_b\nvar_d = 27\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "5217": {
        "category": "Arithmetic calculation",
        "question_ko": "마트에 같은 무게의 사과 상자가 7개 있습니다. 각 상자에서 사과를 20킬로그램(㎏)씩 꺼낸 후 7개의 사과 상자의 무게를 재어 보니 원래 사과 상자 3개의 무게와 같았습니다. 원래 사과 상자 1개의 무게는 몇 킬로그램(㎏)입니까?",
        "question_en": "There are 7 crates of apples of the same weight in the mart. After removing 20 kilograms (kg) of apples from each box, the weight of the 7 boxes of apples was equal to the weight of the original 3 boxes of apples. How many kilograms (kg) does one original box of apples weigh?",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "20 7 [OP_MUL] 7 3 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "20 7 [OP_MUL] 7 3 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 20\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = 3\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 20\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = 3\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))"
    },
    "5218": {
        "category": "Correspondence",
        "question_ko": "철수가 어떤 수에 -5/12를 더하고 다시 -5/2를 빼었더니 1/3이 되었습니다. 어떤 수를 구하시오.",
        "question_en": "Cheolsu adds -5/12 to a certain number and then subtracted -5/2 from it and got 1/3. Find out that certain number.",
        "answer_ko": "-1.75",
        "answer_en": "-1.75",
        "solution_abst_ko": "1/3 -5/2 [OP_ADD] -5/12 [OP_SUB]",
        "solution_abst_en": "1/3 -5/2 [OP_ADD] -5/12 [OP_SUB]",
        "solution_code_ko": "var_a = 0.3333333333333333\nvar_b = -2.5\nvar_c = var_a + var_b\nvar_d = -0.4166666666666667\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.3333333333333333\nvar_b = -2.5\nvar_c = var_a + var_b\nvar_d = -0.4166666666666667\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "5219": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 수학 학원에서 수학 올림피아드에 120명이 참가하였습니다. 이 중 상장을 받은 학생이 상장을 받지 못한 학생보다 36명 더 많다면 상장을 받은 학생은 몇 명인지 구하시오.",
        "question_en": "At a math academy, 120 students participated in a math olympiad. If there are 36 more students who received certificates than those who did not, find how many students received certificates.",
        "answer_ko": "78",
        "answer_en": "78",
        "solution_abst_ko": "120 36 [OP_SUB] 2 [OP_DIV] 36 [OP_ADD]",
        "solution_abst_en": "120 36 [OP_SUB] 2 [OP_DIV] 36 [OP_ADD]",
        "solution_code_ko": "var_a = 120\nvar_b = 36\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 36\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 120\nvar_b = 36\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 36\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "5220": {
        "category": "Correspondence",
        "question_ko": "딸기 66개와 포도알 49개를 봉투에 똑같이 나눠 담으면 딸기는 6개가 남고 포도알은 4개가 남는다. 봉투는 몇 개인지 구하시오.",
        "question_en": "If you divide 66 strawberries and 49 grapes equally into a bag, there will be 6 strawberries left and 4 grapes left. Find how many bags there are.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "49 4 [OP_SUB] 66 6 [OP_SUB] [OP_GCD]",
        "solution_abst_en": "49 4 [OP_SUB] 66 6 [OP_SUB] [OP_GCD]",
        "solution_code_ko": "var_a = 49\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 66\nvar_e = 6\nvar_f = var_d - var_e\nvar_g = math.gcd(int(var_f), int(var_c))\nprint(int(var_g))",
        "solution_code_en": "var_a = 49\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 66\nvar_e = 6\nvar_f = var_d - var_e\nvar_g = math.gcd(int(var_f), int(var_c))\nprint(int(var_g))"
    },
    "5221": {
        "category": "Geometry",
        "question_ko": "10개의 공이 들어 있는 상자에서 3개의 공을 뺐을 때, 남아 있는 공의 개수는?",
        "question_en": "How many balls are left when 3 balls are removed from a box of 10 balls?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "10 3 [OP_SUB]",
        "solution_abst_en": "10 3 [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 10\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "5222": {
        "category": "Geometry",
        "question_ko": "예진이가 책을 꺼내기 위해 상자를 53센티미터(㎝) 7밀리미터(㎜) 만큼 쌓고 그 위에 올라가 바닥에서부터 키를 재었더니 190센티미터(㎝)였습니다. 하지만 높이가 부족해 상자를 더 쌓고 그 위에 올라서서 바닥에서부터 키를 재었더니 232센티미터(㎝) 5밀리미터(㎜)였다면 현재 상자가 쌓인 높이는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "Ye-jin stacked boxes 53 centimeters (cm) 7 millimeters (mm) high to take out books, climbed on top of them, and measured her height from the floor. It was 190 centimeters (cm). However, if the height is not enough, pile up more boxes, stand on top of them, and measure her height from the floor. It was 232 centimeters (cm) and 5 millimeters (mm), find out how tall the boxes are now stacked.",
        "answer_ko": "96.20",
        "answer_en": "96.2",
        "solution_abst_ko": "232 5 10 [OP_DIV] [OP_ADD] 190 [OP_SUB] 53 7 10 [OP_DIV] [OP_ADD] [OP_ADD]",
        "solution_abst_en": "232 5 10 [OP_DIV] [OP_ADD] 190 [OP_SUB] 53 7 10 [OP_DIV] [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 232\nvar_b = 5\nvar_c = 10\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 190\nvar_g = var_e - var_f\nvar_h = 53\nvar_i = 7\nvar_j = 10\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_g + var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))",
        "solution_code_en": "var_a = 232\nvar_b = 5\nvar_c = 10\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 190\nvar_g = var_e - var_f\nvar_h = 53\nvar_i = 7\nvar_j = 10\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_g + var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))"
    },
    "5223": {
        "category": "Geometry",
        "question_ko": "밑면의 두 변의 길이가 각각 6미터(m) 40센티미터(㎝), 9미터(m)이고 높이가 5미터(m) 20센티미터(㎝)인 직육면체 모양의 물통에 물이 가득 차있습니다. 물을 부피가 1세제곱미터(㎥)인 물통 여러 개에 모두 나누어 담으려고 합니다. 물통은 적어도 몇 개가 필요한가요?",
        "question_en": "A  rectangular parallelepiped water container with two sides of the base each measuring 6 meters (m) 40 centimeters (cm) and 9 meters (m), and a height of 5 meters (m) 20 centimeters (cm) is filled with water. You want to divide water into several water containers whose volume is 1 cubic meter (m3). How many water containers do you need at least?",
        "answer_ko": "300",
        "answer_en": "300",
        "solution_abst_ko": "6 40 100 [OP_DIV] [OP_ADD] 9 [OP_MUL] 5 20 100 [OP_DIV] [OP_ADD] [OP_MUL] 1 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "6 40 100 [OP_DIV] [OP_ADD] 9 [OP_MUL] 5 20 100 [OP_DIV] [OP_ADD] [OP_MUL] 1 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 6\nvar_b = 40\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 9\nvar_g = var_e * var_f\nvar_h = 5\nvar_i = 20\nvar_j = 100\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_g * var_l\nvar_n = 1\nvar_o = var_m / var_n\nvar_p = 1\nvar_q=int(((var_o+9*10**(var_p-2))//(10**(var_p-1)))*10**(var_p-1))\n\nprint(int(var_q))",
        "solution_code_en": "var_a = 6\nvar_b = 40\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 9\nvar_g = var_e * var_f\nvar_h = 5\nvar_i = 20\nvar_j = 100\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_g * var_l\nvar_n = 1\nvar_o = var_m / var_n\nvar_p = 1\nvar_q=int(((var_o+9*10**(var_p-2))//(10**(var_p-1)))*10**(var_p-1))\n\nprint(int(var_q))"
    },
    "5224": {
        "category": "Arithmetic calculation",
        "question_ko": "파란 공 3개, 빨간 공 2개 들어 있는 상자가 있습니다. 상자 안에는 공이 몇 개 있습니까?",
        "question_en": "There is a box containing 3 blue balls and 2 red balls. How many balls are in the box?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "3 2 [OP_ADD]",
        "solution_abst_en": "3 2 [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "5225": {
        "category": "Arithmetic calculation",
        "question_ko": "1초마다 처음의 2배로 복제되는 바이러스가 있습니다. 처음에 비커와 비커에 담긴 바이러스 100마리의 무게의 합은 23.97그램(g)이었고, 5초 후 비커와 비커에 담긴 바이러스의 무게의 합은 155.1그램(g)이었습니다. 복제된 바이러스 10000마리는 몇 그램(g)일까요?",
        "question_en": "There is a virus that reproduces twice as many times as the first time every second. Initially, the sum of the weight of the beaker and 100 viruses contained in the beaker was 23.97 grams (g), and after 5 seconds, the sum of the weight of the beaker and the viruses contained in the beaker was 155.1 grams (g). How many grams (g) are 10000 replicated viruses?",
        "answer_ko": "423",
        "answer_en": "423",
        "solution_abst_ko": "155.1 23.97 [OP_SUB] 100 2 5 [OP_POW] [OP_MUL] 100 [OP_SUB] [OP_DIV] 10000 [OP_MUL]",
        "solution_abst_en": "155.1 23.97 [OP_SUB] 100 2 5 [OP_POW] [OP_MUL] 100 [OP_SUB] [OP_DIV] 10000 [OP_MUL]",
        "solution_code_ko": "var_a = 155.1\nvar_b = 23.97\nvar_c = var_a - var_b\nvar_d = 100\nvar_e = 2\nvar_f = 5\nvar_g = var_e ** var_f\nvar_h = var_d * var_g\nvar_i = 100\nvar_j = var_h - var_i\nvar_k = var_c / var_j\nvar_l = 10000\nvar_m = var_k * var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 155.1\nvar_b = 23.97\nvar_c = var_a - var_b\nvar_d = 100\nvar_e = 2\nvar_f = 5\nvar_g = var_e ** var_f\nvar_h = var_d * var_g\nvar_i = 100\nvar_j = var_h - var_i\nvar_k = var_c / var_j\nvar_l = 10000\nvar_m = var_k * var_l\nprint(int(var_m))"
    },
    "5226": {
        "category": "Possibility",
        "question_ko": "1부터 9까지의 9장의 카드 중에서 합이 홀수가 되도록 두 장의 카드를 뽑는 방법의 수를 구하십시오.",
        "question_en": "Find the number of ways to draw two cards out of nine cards numbered 1 through 9 so that the sum becomes an odd number.",
        "answer_ko": "40",
        "answer_en": "40",
        "solution_abst_ko": "1 9 1 [OP_LIST_ARANGE] 2 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 2 1 [OP_LIST_DIVIDE_AND_REMAIN] [OP_LIST_LEN]",
        "solution_abst_en": "1 9 1 [OP_LIST_ARANGE] 2 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 2 1 [OP_LIST_DIVIDE_AND_REMAIN] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 2\nvar_g = 1\nlist_d = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_c:\n    i = int(i)\n    if i%var_f == var_g:\n        list_d.append(i)\nvar_h = len(list_d)\nprint(int(var_h))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 2\nvar_g = 1\nlist_d = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_c:\n    i = int(i)\n    if i%var_f == var_g:\n        list_d.append(i)\nvar_h = len(list_d)\nprint(int(var_h))"
    },
    "5227": {
        "category": "Arithmetic calculation",
        "question_ko": "세 친구가 딸기 주스를 나누어 마시려고 합니다. 성숙이가 전체의 1/6을 마시고 나머지의 2/5를 시연이가 마셨습니다. 그리고 남은 주스의 2/3을 영민이가 마시고 난 후의 주스의 양이 120밀리리터(㎖)였다면, 처음에 있던 딸기 주스의 양은 몇 밀리리터(㎖)입니까?",
        "question_en": "Three friends are about to share a strawberry juice. Seonghwa drank 1/6 of the total and Siyeon drank 2/5 of the rest. And if the amount of juice after Youngmin drank 2/3 of the remaining juice was 120 milliliters (㎖), how many milliliters (㎖) of strawberry juice was there at the beginning?",
        "answer_ko": "720",
        "answer_en": "720",
        "solution_abst_ko": "120 1 1/6 [OP_SUB] [OP_DIV] 1 2/5 [OP_SUB] [OP_DIV] 1 2/3 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "120 1 1/6 [OP_SUB] [OP_DIV] 1 2/5 [OP_SUB] [OP_DIV] 1 2/3 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 120\nvar_b = 1\nvar_c = 0.16666666666666666\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 1\nvar_g = 0.4\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 1\nvar_k = 0.6666666666666666\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nprint(int(eval('{:.2f}'.format(round(var_m+1e-10,2)))))",
        "solution_code_en": "var_a = 120\nvar_b = 1\nvar_c = 0.16666666666666666\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 1\nvar_g = 0.4\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 1\nvar_k = 0.6666666666666666\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nprint(int(eval('{:.2f}'.format(round(var_m+1e-10,2)))))"
    },
    "5228": {
        "category": "Arithmetic calculation",
        "question_ko": "운동장 1바퀴를 도는데 정우는 5분이 걸리고 신지는 3분이 걸린다. 둘이 합쳐 16 바퀴를 돌려면 몇 분이 걸리는지 구하시오.",
        "question_en": "It takes 5 minutes for Jeong-woo and 3 minutes for Shin-ji to complete one lap around the playground. In a situation where Jeong-woo and Shin-ji add their number of completed laps, how many minutes will it take them to reach a total of 16 laps?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "1 16 [OP_MUL] 1 5 [OP_DIV] 1 3 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_abst_en": "1 16 [OP_MUL] 1 5 [OP_DIV] 1 3 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 5\nvar_f = var_d / var_e\nvar_g = 1\nvar_h = 3\nvar_i = var_g / var_h\nvar_j = var_f + var_i\nvar_k = var_c / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 1\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 5\nvar_f = var_d / var_e\nvar_g = 1\nvar_h = 3\nvar_i = var_g / var_h\nvar_j = var_f + var_i\nvar_k = var_c / var_j\nprint(int(var_k))"
    },
    "5229": {
        "category": "Geometry",
        "question_ko": "현우네 학교의 도서관은 한 변의 길이가 14.25미터(m)인 정사각형 모양입니다. 도서관의 넓이를 구하시오.",
        "question_en": "The library at Hyunwoo's school is square with a side measuring 14.25 meters (m). Find the area of the library.",
        "answer_ko": "203.06",
        "answer_en": "203.06",
        "solution_abst_ko": "14.25 2 [OP_POW]",
        "solution_abst_en": "14.25 2 [OP_POW]",
        "solution_code_ko": "var_a = 14.25\nvar_b = 2\nvar_c = var_a ** var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 14.25\nvar_b = 2\nvar_c = var_a ** var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "5230": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 4.372를 더하고 43.72를 빼었더니 16.398이 되었습니다. 어떤 수는 얼마인지 구하시오.",
        "question_en": "Adding 4.372 to a number and subtracting 43.72 gives us 16.398. Find out what the number is.",
        "answer_ko": "55.75",
        "answer_en": "55.75",
        "solution_abst_ko": "16.398 43.72 [OP_ADD] 4.372 [OP_SUB]",
        "solution_abst_en": "16.398 43.72 [OP_ADD] 4.372 [OP_SUB]",
        "solution_code_ko": "var_a = 16.398\nvar_b = 43.72\nvar_c = var_a + var_b\nvar_d = 4.372\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 16.398\nvar_b = 43.72\nvar_c = var_a + var_b\nvar_d = 4.372\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "5231": {
        "category": "Possibility",
        "question_ko": "4, 2, 8, 1, 9 수 카드를 한 번씩만 사용하여 몫이 가장 작은 (세 자리 수)/(두 자리 수)를 만들었을 때의 몫을 구하세요.",
        "question_en": "Find the quotient of making the smallest quotient (three digit number)/(double digit number) using the cards 4, 2, 8, 1, 9 and each card can be used only once.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "[OP_LIST_SOL] 4 2 8 1 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] [OP_LIST_POP] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] [OP_FDIV]",
        "solution_abst_en": "[OP_LIST_SOL] 4 2 8 1 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] [OP_LIST_POP] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] [OP_FDIV]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = 8\nvar_d = 1\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = 2\nlist_d = [str(i) for i in list_a]\nlist_d = list(itertools.permutations(list_d, var_i))\nlist_d = [''.join(num_list) for num_list in list_d]\nlist_d = [str_num for str_num in list_d if str_num[0] != '0']\nlist_d = [float(i) for i in list_d]\nvar_j = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_k = list_e[var_j-1]\nvar_l = var_h // var_k\nprint(int(var_l))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = 8\nvar_d = 1\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = 2\nlist_d = [str(i) for i in list_a]\nlist_d = list(itertools.permutations(list_d, var_i))\nlist_d = [''.join(num_list) for num_list in list_d]\nlist_d = [str_num for str_num in list_d if str_num[0] != '0']\nlist_d = [float(i) for i in list_d]\nvar_j = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_k = list_e[var_j-1]\nvar_l = var_h // var_k\nprint(int(var_l))"
    },
    "5232": {
        "category": "Geometry",
        "question_ko": "크기가 같은 색종이를 빈틈없이 늘어놓아 정사각형을 만들었습니다. 이 정사각형의 둘레에 놓인 색종이는 총 36개입니다. 가장 바깥쪽의 한 변에 놓인 색종이의 개수는?",
        "question_en": "I made a square by arranging colored paper of the same size without gaps. There are a total of 36 colored paper placed around the perimeter of this square. How many pieces of colored paper are on the outermost of one side?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "36 4 [OP_DIV] 1 [OP_ADD]",
        "solution_abst_en": "36 4 [OP_DIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 36\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 36\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "5233": {
        "category": "Geometry",
        "question_ko": "서로 다른 카드 2장이 있습니다. 똑바로 세워놓고 손을 뗄 때, 두 카드 모두 앞면이 위를 보게 쓰러지는 경우는 몇 가지 입니까?",
        "question_en": "There are 2 different cards. When held upright and released, how many cases will be there for the cards to fall facing up?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "1",
        "solution_abst_en": "1",
        "solution_code_ko": "var_a = 1\nprint(int(var_a))",
        "solution_code_en": "var_a = 1\nprint(int(var_a))"
    },
    "5234": {
        "category": "Geometry",
        "question_ko": "유진이네 집 거실은 직사각형 모양이라고 합니다. 거실의 가로 길이가 14미터(m)이고, 넓이가 215.6제곱미터(㎡)라면, 거실의 세로 길이는 몇 미터(m)일지 구하시오.",
        "question_en": "The living room of Eugene's house is said to be rectangular. If the width of the living room is 14 meters (m) and the area is 215.6 square meters (m2), what is the length of the living room in meters (m)?",
        "answer_ko": "15.40",
        "answer_en": "15.4",
        "solution_abst_ko": "215.6 14 [OP_DIV]",
        "solution_abst_en": "215.6 14 [OP_DIV]",
        "solution_code_ko": "var_a = 215.6\nvar_b = 14\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 215.6\nvar_b = 14\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "5235": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 24를 빼려고 합니다. 잘못하여 42를 뺐을 때의 답이 50이라면 바르게 계산한 결과는 얼마일까요?",
        "question_en": "You want to subtract 24 from a number. If the answer when you mistakenly subtract 42 from it is 50, what would be the result if you correctly calculate it?",
        "answer_ko": "68",
        "answer_en": "68",
        "solution_abst_ko": "50 42 [OP_ADD] 24 [OP_SUB]",
        "solution_abst_en": "50 42 [OP_ADD] 24 [OP_SUB]",
        "solution_code_ko": "var_a = 50\nvar_b = 42\nvar_c = var_a + var_b\nvar_d = 24\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 50\nvar_b = 42\nvar_c = var_a + var_b\nvar_d = 24\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "5236": {
        "category": "Comparison",
        "question_ko": "여러 명의 아이들이 같은 간격으로 둥글게 서 있습니다. 한 아이를 기준으로 반시계 방향으로 11번째에 있는 아이와 6번째에 있는 아이가 서로 마주보고 있습니다. 아이들은 모두 몇 명입니까?",
        "question_en": "Several children stand in a circle equally spaced apart. The 11th child and the 6th child are facing each other counterclockwise from one child. How many children are there in total?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "11 6 [OP_SUB] 2 [OP_MUL]",
        "solution_abst_en": "11 6 [OP_SUB] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 11\nvar_b = 6\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 11\nvar_b = 6\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "5237": {
        "category": "Arithmetic calculation",
        "question_ko": "100개의 구슬을 가진 상자가 10개 있다면 총 구슬의 개수는?",
        "question_en": "If there are 10 boxes and there are 100 marbles per box, what is the total number of marbles?",
        "answer_ko": "1000",
        "answer_en": "1000",
        "solution_abst_ko": "100 10 [OP_MUL]",
        "solution_abst_en": "100 10 [OP_MUL]",
        "solution_code_ko": "var_a = 100\nvar_b = 10\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 100\nvar_b = 10\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "5238": {
        "category": "Comparison",
        "question_ko": "24개의 색연필이 있습니다. 빨간색 색연필은 전체의 1/4, 파란색 색연필은 빨간색 색연필보다 6개, 나머지는 노란색 색연필입니다. 어떤 색연필이 가장 많은지 구하십시오.",
        "question_en": "There are 24 colored pencils. The red colored pencils are 1/4 of the total, the blue colored pencils are 6 more than the red colored pencils, and the rest are yellow colored pencils. Find which colored pencils have the most.",
        "answer_ko": "파란색",
        "answer_en": "blue",
        "solution_abst_ko": "[OP_LIST_SOL] 빨간색 파란색 노란색 [OP_LIST_EOL] [OP_LIST_SOL] 24 4 [OP_DIV] 24 4 [OP_DIV] 6 [OP_ADD] 24 24 4 [OP_DIV] 6 [OP_ADD] [OP_SUB] 24 4 [OP_DIV] [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] red blue yellow [OP_LIST_EOL] [OP_LIST_SOL] 24 4 [OP_DIV] 24 4 [OP_DIV] 6 [OP_ADD] 24 24 4 [OP_DIV] 6 [OP_ADD] [OP_SUB] 24 4 [OP_DIV] [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '빨간색'\nvar_b = '파란색'\nvar_c = '노란색'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 24\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = 24\nvar_h = 4\nvar_i = var_g / var_h\nvar_j = 6\nvar_k = var_i + var_j\nvar_l = 24\nvar_m = 24\nvar_n = 4\nvar_o = var_m / var_n\nvar_p = 6\nvar_q = var_o + var_p\nvar_r = var_l - var_q\nvar_s = 24\nvar_t = 4\nvar_u = var_s / var_t\nvar_v = var_r - var_u\nlist_b= []\nif \"/\" in str(var_v):\n    var_v = eval(str(var_v))\nlist_b.append(var_v)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_w = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_x = list_c[-var_w]\nvar_y = list_b.index(var_x)+1\nvar_z = list_a[var_y-1]\nprint(var_z)",
        "solution_code_en": "var_a = 'red'\nvar_b = 'blue'\nvar_c = 'yellow'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 24\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = 24\nvar_h = 4\nvar_i = var_g / var_h\nvar_j = 6\nvar_k = var_i + var_j\nvar_l = 24\nvar_m = 24\nvar_n = 4\nvar_o = var_m / var_n\nvar_p = 6\nvar_q = var_o + var_p\nvar_r = var_l - var_q\nvar_s = 24\nvar_t = 4\nvar_u = var_s / var_t\nvar_v = var_r - var_u\nlist_b= []\nif \"/\" in str(var_v):\n    var_v = eval(str(var_v))\nlist_b.append(var_v)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_w = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_x = list_c[-var_w]\nvar_y = list_b.index(var_x)+1\nvar_z = list_a[var_y-1]\nprint(var_z)"
    },
    "5239": {
        "category": "Possibility",
        "question_ko": "초등학생 2명, 중학생 2명을 한 줄로 세우려고 한다. 초등학생이 나란히 서 있는 방법은 모두 몇 가지인지 구하시오.",
        "question_en": "I'm trying to line up two elementary school students and two middle school students. In how many ways can elementary school students stand side by side?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "2 1 [OP_ADD] 2 1 [OP_ADD] [OP_PERM] 2 [OP_MUL]",
        "solution_abst_en": "2 1 [OP_ADD] 2 1 [OP_ADD] [OP_PERM] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = 1\nvar_c = int(var_c)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_c-i)\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 2\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = 1\nvar_c = int(var_c)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_c-i)\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "5240": {
        "category": "Comparison",
        "question_ko": "키가 작은 사람부터 순서대로 9명이 한 줄로 서 있습니다. 호석이는 가장 앞에 서 있고, 유나는 호석이 바로 뒤에 서 있습니다. 키가 큰 사람부터 순서대로 다시 줄을 서면 유나는 앞에서부터 몇 번째에 서게 됩니까?",
        "question_en": "Nine people stand in a line in order from shortest to tallest. Hoseok stands at the front, and Yuna stands right behind Hoseok. If they line up again in order of tallest people, what number will Yuna stand from the front?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "9 1 [OP_SUB] 1 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "9 1 [OP_SUB] 1 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 9\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 9\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "5241": {
        "category": "Arithmetic calculation",
        "question_ko": "숫자 36, 17, 32, 54, 28, 3 이 있습니다. 숫자의 총합을 구하시오",
        "question_en": "There are numbers 36, 17, 32, 54, 28, and 3. Find the sum of the numbers.",
        "answer_ko": "170",
        "answer_en": "170",
        "solution_abst_ko": "[OP_LIST_SOL] 36 17 32 54 28 3 [OP_LIST_EOL] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 36 17 32 54 28 3 [OP_LIST_EOL] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 36\nvar_b = 17\nvar_c = 32\nvar_d = 54\nvar_e = 28\nvar_f = 3\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_g = sum(list_a)\nprint(int(var_g))",
        "solution_code_en": "var_a = 36\nvar_b = 17\nvar_c = 32\nvar_d = 54\nvar_e = 28\nvar_f = 3\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_g = sum(list_a)\nprint(int(var_g))"
    },
    "5242": {
        "category": "Correspondence",
        "question_ko": "96에 어떤 수를 나누야 할 것을 잘못하여 9에 어떤 수를 뺐더니 3이 되었습니다. 바르게 계산하면 얼마인지 구하시오.",
        "question_en": "I had to divide 96 by a number but mistakenly subtracted 9 by the number to get 3. Find the correctly calculated value.",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "96 9 3 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "96 9 3 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 96\nvar_b = 9\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 96\nvar_b = 9\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "5243": {
        "category": "Possibility",
        "question_ko": "민형이네 반에서 반장과 부반장을 뽑으려고 합니다. 반장 후보는 3명이고 부반장 후보는 5명입니다. 반장 한 명과 부반장 한 명을 고르는 경우의 수는 얼마입니까?",
        "question_en": "I'm trying to pick the class president and vice president from Minhyung's class. There are 3 candidates for class president and 5 candidates for vice president. How many ways can you choose one class president and one vice president?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "3 1 [OP_COMB] 5 1 [OP_COMB] [OP_MUL]",
        "solution_abst_en": "3 1 [OP_COMB] 5 1 [OP_COMB] [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 1\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nvar_d = 5\nvar_e = 1\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f / (i+1)\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 3\nvar_b = 1\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nvar_d = 5\nvar_e = 1\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f / (i+1)\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "5244": {
        "category": "Arithmetic calculation",
        "question_ko": "서준이가 숙제를 어제는 전체의 1/3을, 오늘은 전체의 2/5를 했습니다. 남은 숙제는 전체의 얼마인지 구하시오.",
        "question_en": "Seojun did 1/3 of the homework yesterday and 2/5 of the total today. Find the total amount of homework remaining.",
        "answer_ko": "0.27",
        "answer_en": "0.27",
        "solution_abst_ko": "1 1/3 [OP_SUB] 2/5 [OP_SUB]",
        "solution_abst_en": "1 1/3 [OP_SUB] 2/5 [OP_SUB]",
        "solution_code_ko": "var_a = 1\nvar_b = 0.3333333333333333\nvar_c = var_a - var_b\nvar_d = 0.4\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 0.3333333333333333\nvar_c = var_a - var_b\nvar_d = 0.4\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "5245": {
        "category": "Comparison",
        "question_ko": "총 20명의 학생들이 달리기 경기를 하고 있습니다. 윤기는 11명의 학생들보다 결승점에 먼저 들어왔습니다. 윤기보다 먼저 들어온 학생은 몇 명입니까?",
        "question_en": "A total of 20 students are running a race. Yoongi reached the finish line before the 11 students. How many students came in before Yoongi?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "20 11 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "20 11 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "5246": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 90센티미터(㎝)인 끈이 있습니다. 이 중에서 30센티미터(㎝)는 유정이에게 주고 나머지의 8/15은 상자를 묶는데 사용했습니다. 상자를 묶는데 사용한 끈의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "There is a string that is 90 centimeters (cm) long. 30 centimeters (cm) of the string was given to Yoojung, and 8/15 of the remaining string was used to tie the box. How many centimeters (cm) is the string used to tie the box?",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "90 30 [OP_SUB] 8/15 [OP_MUL]",
        "solution_abst_en": "90 30 [OP_SUB] 8/15 [OP_MUL]",
        "solution_code_ko": "var_a = 90\nvar_b = 30\nvar_c = var_a - var_b\nvar_d = 0.5333333333333333\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 90\nvar_b = 30\nvar_c = var_a - var_b\nvar_d = 0.5333333333333333\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "5247": {
        "category": "Arithmetic calculation",
        "question_ko": "두 지점 A, B 사이를 자전거를 타고 왕복하는데 갈때는 시속 15 킬로미터(㎞)로, 올 때는 시속 10 킬로미터(㎞)로 달렸더니 올 때는 갈 때보다 30분이 더 걸렸다. 올 때 걸린 시간을 구하시오.",
        "question_en": "I rode a bicycle back and forth between the two points A and B, traveling at 15 kilometers per hour (km) on the way and 10 kilometers (km) per hour on the way back, and it took 30 minutes longer to come back. Find the total time it took to come back.",
        "answer_ko": "1.50",
        "answer_en": "1.5",
        "solution_abst_ko": "10 30 60 [OP_DIV] [OP_MUL] 15 10 [OP_SUB] [OP_DIV] 30 60 [OP_DIV] [OP_ADD]",
        "solution_abst_en": "10 30 60 [OP_DIV] [OP_MUL] 15 10 [OP_SUB] [OP_DIV] 30 60 [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 30\nvar_c = 60\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 15\nvar_g = 10\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 30\nvar_k = 60\nvar_l = var_j / var_k\nvar_m = var_i + var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))",
        "solution_code_en": "var_a = 10\nvar_b = 30\nvar_c = 60\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 15\nvar_g = 10\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 30\nvar_k = 60\nvar_l = var_j / var_k\nvar_m = var_i + var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))"
    },
    "5248": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이가 가진 구슬은 지민이가 가진 구슬보다 4개 더 적습니다. 정국이가 구슬을 3개 가지고 있다면 두 사람이 가지고 있는 구슬은 모두 몇 개입니까?",
        "question_en": "Jungkook has 4 fewer marbles than Jimin. If Jungkook has 3 marbles, how many marbles do both of them have?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "3 3 4 [OP_ADD] [OP_ADD]",
        "solution_abst_en": "3 3 4 [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 3\nvar_c = 4\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 3\nvar_b = 3\nvar_c = 4\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "5249": {
        "category": "Correspondence",
        "question_ko": "선우는 35개의 연필과 5개의 지우개을 합쳐서 5명의 친구들에게 똑같은 개수로 나누어 주려고 한다. 몇 개씩 나누어주면 되는지 구하여라.",
        "question_en": "Seonwoo wants to combine 35 pencils and 5 erasers and hand them out to 5 friends in equal numbers. Find how many of them should he hand out to each friend.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "35 5 [OP_ADD] 5 [OP_DIV]",
        "solution_abst_en": "35 5 [OP_ADD] 5 [OP_DIV]",
        "solution_code_ko": "var_a = 35\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 35\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "5250": {
        "category": "Comparison",
        "question_ko": "들이가 1리터(L) 400밀리리터(㎖)인 꽃병과 들이가 2800밀리리터(㎖)인 우유병에 물을 가득 채운 뒤 대야에 모두 부었더니 대야가 가득 찼습니다. 들이가 4리터(L) 100밀리리터(㎖)인 수조와 대야 중에서 어느 쪽의 들이가 더 많습니까?",
        "question_en": "We filled a 1 liter (l) 400 milliliter (ml) vase and a 2800 milliliter (ml) milk bottle with water, and then poured it all into a basin, which made the basin full. Between this basin a tank with 4 liters (L) and 100 milliliters (ml), which one can have more water inside?",
        "answer_ko": "대야",
        "answer_en": "basin",
        "solution_abst_ko": "[OP_LIST_SOL] 수조 대야 [OP_LIST_EOL] [OP_LIST_SOL] 4 1000 [OP_MUL] 100 [OP_ADD] 2800 1 1000 [OP_MUL] 400 [OP_ADD] [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] tank basin [OP_LIST_EOL] [OP_LIST_SOL] 4 1000 [OP_MUL] 100 [OP_ADD] 2800 1 1000 [OP_MUL] 400 [OP_ADD] [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '수조'\nvar_b = '대야'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 100\nvar_g = var_e + var_f\nvar_h = 2800\nvar_i = 1\nvar_j = 1000\nvar_k = var_i * var_j\nvar_l = 400\nvar_m = var_k + var_l\nvar_n = var_h + var_m\nlist_b= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_o = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_p = list_c[-var_o]\nvar_q = list_b.index(var_p)+1\nvar_r = list_a[var_q-1]\nprint(var_r)",
        "solution_code_en": "var_a = 'tank'\nvar_b = 'basin'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 100\nvar_g = var_e + var_f\nvar_h = 2800\nvar_i = 1\nvar_j = 1000\nvar_k = var_i * var_j\nvar_l = 400\nvar_m = var_k + var_l\nvar_n = var_h + var_m\nlist_b= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_o = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_p = list_c[-var_o]\nvar_q = list_b.index(var_p)+1\nvar_r = list_a[var_q-1]\nprint(var_r)"
    },
    "5251": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 6, 5, 8, 9로 나누어 떨어질 수 있는 세 자리 수는 모두 몇 개 있습니까?",
        "question_en": "How many three-digit numbers are divisible by the four numbers 6, 5, 8, and 9?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "100 999 1 [OP_LIST_ARANGE] 6 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "100 999 1 [OP_LIST_ARANGE] 6 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = len(list_e)\nprint(int(var_h))",
        "solution_code_en": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = len(list_e)\nprint(int(var_h))"
    },
    "5252": {
        "category": "Comparison",
        "question_ko": "삼각기둥, 사각기둥, 삼각뿔, 사각뿔, 사각뿔대 이렇게 다섯 종류의 도형이 있습니다. 각 도형에 있는 면의 중심에 스티커를 붙인다고 할 때 스티커가 가장 적게 필요한 도형은 무엇입니까?",
        "question_en": "There are five types of shapes: triangular-prism, quadrangular-prism, triangular-pyramid, quadrangular-pyramid, and truncated-quadrangular-pyramid. Given that you place a sticker on the center of each face of each shape, which shape needs the least number of stickers?",
        "answer_ko": "삼각뿔",
        "answer_en": "triangular-pyramid",
        "solution_abst_ko": "[OP_LIST_SOL] 삼각기둥 사각기둥 삼각뿔 사각뿔 사각뿔대 [OP_LIST_EOL] [OP_LIST_SOL] 3 2 [OP_ADD] 4 2 [OP_ADD] 3 1 [OP_ADD] 4 1 [OP_ADD] 4 2 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] triangular-prism quadrangular-prism triangular-pyramid quadrangular-pyramid truncated-quadrangular-pyramid [OP_LIST_EOL] [OP_LIST_SOL] 3 2 [OP_ADD] 4 2 [OP_ADD] 3 1 [OP_ADD] 4 1 [OP_ADD] 4 2 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '삼각기둥'\nvar_b = '사각기둥'\nvar_c = '삼각뿔'\nvar_d = '사각뿔'\nvar_e = '사각뿔대'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = 4\nvar_j = 2\nvar_k = var_i + var_j\nvar_l = 3\nvar_m = 1\nvar_n = var_l + var_m\nvar_o = 4\nvar_p = 1\nvar_q = var_o + var_p\nvar_r = 4\nvar_s = 2\nvar_t = var_r + var_s\nlist_b= []\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_b.append(var_t)\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nlist_b.reverse()\nvar_u = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_v = list_c[var_u-1]\nvar_w = list_b.index(var_v)+1\nvar_x = list_a[var_w-1]\nprint(var_x)",
        "solution_code_en": "var_a = 'triangular-prism'\nvar_b = 'quadrangular-prism'\nvar_c = 'triangular-pyramid'\nvar_d = 'quadrangular-pyramid'\nvar_e = 'truncated-quadrangular-pyramid'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = 4\nvar_j = 2\nvar_k = var_i + var_j\nvar_l = 3\nvar_m = 1\nvar_n = var_l + var_m\nvar_o = 4\nvar_p = 1\nvar_q = var_o + var_p\nvar_r = 4\nvar_s = 2\nvar_t = var_r + var_s\nlist_b= []\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_b.append(var_t)\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nlist_b.reverse()\nvar_u = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_v = list_c[var_u-1]\nvar_w = list_b.index(var_v)+1\nvar_x = list_a[var_w-1]\nprint(var_x)"
    },
    "5253": {
        "category": "Geometry",
        "question_ko": "크기가 다른 두 개의 정육면체가 있습니다. 큰 정육면체의 모든 모서리의 길이의 합이 82.8센티미터(㎝)이고, 작은 정육면체의 한 모서리의 길이는 큰 정육면체의 한 모서리의 길이의 1/3일 때, 두 정육면체의 모서리 중 하나씩을 선택해 그 길이를 더하면 몇 센티미터(㎝)입니까?",
        "question_en": "There are two cubes of different sizes. When the sum of the lengths of all edges of the large cube is 82.8 centimeters (cm), and the length of one edge of the small cube is 1/3 of the length of one edge of the large cube, select each one of the edges of the two cubes and determine its length. Add up to how many centimeters (cm)?",
        "answer_ko": "9.20",
        "answer_en": "9.2",
        "solution_abst_ko": "82.8 4 3 [OP_MUL] [OP_DIV] 1/3 [OP_MUL] 82.8 4 3 [OP_MUL] [OP_DIV] [OP_ADD]",
        "solution_abst_en": "82.8 4 3 [OP_MUL] [OP_DIV] 1/3 [OP_MUL] 82.8 4 3 [OP_MUL] [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 82.8\nvar_b = 4\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nvar_f = 0.3333333333333333\nvar_g = var_e * var_f\nvar_h = 82.8\nvar_i = 4\nvar_j = 3\nvar_k = var_i * var_j\nvar_l = var_h / var_k\nvar_m = var_g + var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))",
        "solution_code_en": "var_a = 82.8\nvar_b = 4\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nvar_f = 0.3333333333333333\nvar_g = var_e * var_f\nvar_h = 82.8\nvar_i = 4\nvar_j = 3\nvar_k = var_i * var_j\nvar_l = var_h / var_k\nvar_m = var_g + var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))"
    },
    "5254": {
        "category": "Arithmetic calculation",
        "question_ko": "네 자리 수 중 5, 6, 2의 공배수 중 가장 작은 수는 무엇입니까?",
        "question_en": "Which four-digit number is the smallest common multiple of 5, 6, and 2?",
        "answer_ko": "1020",
        "answer_en": "1020",
        "solution_abst_ko": "1000 9999 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] 6 [OP_LIST_DIVISIBLE] 2 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "1000 9999 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] 6 [OP_LIST_DIVISIBLE] 2 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 6\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 2\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_h = list_e[var_g-1]\nprint(int(var_h))",
        "solution_code_en": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 6\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 2\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_h = list_e[var_g-1]\nprint(int(var_h))"
    },
    "5255": {
        "category": "Correspondence",
        "question_ko": "윤기는 세 자리 수와 57의 뺄셈을 하려 합니다. 윤기는 세 자리 수의 일의 자리 숫자 9를 6으로 잘못 보았습니다. 윤기가 구한 차는 819 일 때, 바르게 계산한 결과를 구하시오.",
        "question_en": "Yoongi wants to subtract 57 from a three-digit number. Yoongi misread the three-digit ones digit 9 as a 6. When Yoongi's car is 819, find the correct calculation result.",
        "answer_ko": "822",
        "answer_en": "822",
        "solution_abst_ko": "819 57 [OP_ADD] 6 9 [OP_SUB] [OP_SUB] 57 [OP_SUB]",
        "solution_abst_en": "819 57 [OP_ADD] 6 9 [OP_SUB] [OP_SUB] 57 [OP_SUB]",
        "solution_code_ko": "var_a = 819\nvar_b = 57\nvar_c = var_a + var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nvar_h = 57\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 819\nvar_b = 57\nvar_c = var_a + var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nvar_h = 57\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "5256": {
        "category": "Comparison",
        "question_ko": "철사를 수지는 9센티미터(㎝) 8밀리미터(㎜), 영주는 8.9센티미터(㎝), 영호는 9.3센티미터(㎝)가지고 있습니다. 가지고 있는 철사의 길이가 가장 짧은 사람은 누구입니까?",
        "question_en": "Suzy has a wire of 9 centimeters (cm) 8 millimeters (mm), Yeongju has 8.9 centimeters (cm), and Youngho has 9.3 centimeters (cm). Who has the shortest wire length?",
        "answer_ko": "영주",
        "answer_en": "Yeongju",
        "solution_abst_ko": "[OP_LIST_SOL] 수지 영주 영호 [OP_LIST_EOL] [OP_LIST_SOL] 9 8 10 [OP_DIV] [OP_ADD] 8.9 9.3 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Suzy Yeongju Youngho [OP_LIST_EOL] [OP_LIST_SOL] 9 8 10 [OP_DIV] [OP_ADD] 8.9 9.3 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '수지'\nvar_b = '영주'\nvar_c = '영호'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 9\nvar_e = 8\nvar_f = 10\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = 8.9\nvar_j = 9.3\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[var_k-1]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'Suzy'\nvar_b = 'Yeongju'\nvar_c = 'Youngho'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 9\nvar_e = 8\nvar_f = 10\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = 8.9\nvar_j = 9.3\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[var_k-1]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "5257": {
        "category": "Comparison",
        "question_ko": "정국이는 0.8, 윤기는 1/2, 유정이는 0.9, 유나는 1/3의 숫자카드를 갖고 있습니다. 0.3보다 작은 숫자카드를 가지고 있는 사람은 몇 명입니까?",
        "question_en": "Jungkook has 0.8, Yoongi has 1/2, Yoojeong has 0.9, and Yuna has 1/3 written on their cards. How many people have cards with numbers less than 0.3 written? ",
        "answer_ko": "0",
        "answer_en": "0",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.3 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.3 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.3\nlist_b = []\nfor i in list_a:\n    if i < var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.3\nlist_b = []\nfor i in list_a:\n    if i < var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "5258": {
        "category": "Arithmetic calculation",
        "question_ko": "지민이가 가진 돈을 세어보니 100원짜리 동전이 5개, 50원짜리 동전이 1개였습니다. 옆에 있던 석진이는 100원짜리 동전 2개와 10원짜리 동전 7개를 가지고 있다면 두 사람이 가지고 있는 돈으로 살 수 있는 가장 비싼 물건은 얼마입니까?",
        "question_en": "When Jimin counted the money he had, there were 5 100 won coins and 1 50 won coin. If Seok-jin, who was next to him, had 2 100-won coins and 7 10-won coins, what would be the most expensive item the two of them could buy with the money they had?",
        "answer_ko": "820",
        "answer_en": "820",
        "solution_abst_ko": "100 5 [OP_MUL] 50 1 [OP_MUL] [OP_ADD] 100 2 [OP_MUL] [OP_ADD] 10 7 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "100 5 [OP_MUL] 50 1 [OP_MUL] [OP_ADD] 100 2 [OP_MUL] [OP_ADD] 10 7 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 100\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 50\nvar_e = 1\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 100\nvar_i = 2\nvar_j = var_h * var_i\nvar_k = var_g + var_j\nvar_l = 10\nvar_m = 7\nvar_n = var_l * var_m\nvar_o = var_k + var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 100\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 50\nvar_e = 1\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 100\nvar_i = 2\nvar_j = var_h * var_i\nvar_k = var_g + var_j\nvar_l = 10\nvar_m = 7\nvar_n = var_l * var_m\nvar_o = var_k + var_n\nprint(int(var_o))"
    },
    "5259": {
        "category": "Arithmetic calculation",
        "question_ko": "3과 4로 나누어떨어지고 5로 나누면 나머지가 4인 두 자리 수를 찾으려고 합니다. 만들 수 있는 두 자리 수 중 가장 작은 수는 무엇입니까?",
        "question_en": "You are trying to find a two-digit number that is divisible by 3 and 4 and divided by 5 has a remainder of 4. What is the smallest two-digit number you can make?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "10 99 1 [OP_LIST_ARANGE] 3 4 [OP_LCM] [OP_LIST_DIVISIBLE] 5 4 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MIN]",
        "solution_abst_en": "10 99 1 [OP_LIST_ARANGE] 3 4 [OP_LCM] [OP_LIST_DIVISIBLE] 5 4 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nvar_e = 4\nvar_f = var_e * var_d / math.gcd(int(var_e), int(var_d))\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nvar_g = 5\nvar_h = 4\nlist_c = [] \nvar_g = int(var_g)\nvar_h = int(var_h)\nif var_h < 0:\n    var_h = var_h + var_g\nfor i in list_b:\n    i = int(i)\n    if i%var_g == var_h:\n        list_c.append(i)\nvar_i = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nprint(int(var_j))",
        "solution_code_en": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nvar_e = 4\nvar_f = var_e * var_d / math.gcd(int(var_e), int(var_d))\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nvar_g = 5\nvar_h = 4\nlist_c = [] \nvar_g = int(var_g)\nvar_h = int(var_h)\nif var_h < 0:\n    var_h = var_h + var_g\nfor i in list_b:\n    i = int(i)\n    if i%var_g == var_h:\n        list_c.append(i)\nvar_i = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nprint(int(var_j))"
    },
    "5260": {
        "category": "Possibility",
        "question_ko": "1, 7, 9, 2를 한 번씩 모두 사용하여 두 자리 수끼리의 덧셈식을 만들 때, 나올 수 있는 가장 큰 합은 무엇입니까?",
        "question_en": "What is the largest possible sum that can be calculated in an addition expression comprised of two-digit numbers that were made using 1, 7, 9, and 2 once? ",
        "answer_ko": "163",
        "answer_en": "163",
        "solution_abst_ko": "[OP_LIST_SOL] 1 7 9 2 [OP_LIST_EOL] 1 [OP_LIST_MAX] 10 [OP_MUL] 1 [OP_LIST_MIN] [OP_ADD] 2 [OP_LIST_MAX] 10 [OP_MUL] 2 [OP_LIST_MIN] [OP_ADD] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 1 7 9 2 [OP_LIST_EOL] 1 [OP_LIST_MAX] 10 [OP_MUL] 1 [OP_LIST_MIN] [OP_ADD] 2 [OP_LIST_MAX] 10 [OP_MUL] 2 [OP_LIST_MIN] [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 7\nvar_c = 9\nvar_d = 2\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 10\nvar_h = var_f * var_g\nvar_i = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = var_h + var_j\nvar_l = 2\nlist_d=list_a.copy()\nlist_d.sort()\nvar_m = list_d[-var_l]\nvar_n = 10\nvar_o = var_m * var_n\nvar_p = 2\nlist_e=list_a.copy()\nlist_e.sort()\nvar_q = list_e[var_p-1]\nvar_r = var_o + var_q\nvar_s = var_k + var_r\nprint(int(var_s))",
        "solution_code_en": "var_a = 1\nvar_b = 7\nvar_c = 9\nvar_d = 2\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 10\nvar_h = var_f * var_g\nvar_i = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = var_h + var_j\nvar_l = 2\nlist_d=list_a.copy()\nlist_d.sort()\nvar_m = list_d[-var_l]\nvar_n = 10\nvar_o = var_m * var_n\nvar_p = 2\nlist_e=list_a.copy()\nlist_e.sort()\nvar_q = list_e[var_p-1]\nvar_r = var_o + var_q\nvar_s = var_k + var_r\nprint(int(var_s))"
    },
    "5261": {
        "category": "Comparison",
        "question_ko": "1000개의 구슬을 1반과 2반이 나누어 가지는데 1반이 50개 더 가졌습니다. 그리고 2반 학생들은 남학생과 여학생 두 팀으로 나누어서 가져온 구슬을 다시 나누어 가지는데 남학생 팀이 35개 더 가졌습니다. 2반 남학생 17명이 구슬을 똑같이 나누어 가질 때, 2반 남학생 한 명이 가지는 구슬은 몇 개인지 구하시오.",
        "question_en": "1000 marbles are divided between class 1 and 2, but class 1 has 50 more marbles. Then, the students in class 2 were divided into two teams of boys and girls and shared the marbles they brought, and the boys got 35 more. If 17 male students in class 2 share the marbles equally, find how many marbles each male student in class 2 has.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "1000 50 [OP_SUB] 2 [OP_DIV] 35 [OP_SUB] 2 [OP_DIV] 35 [OP_ADD] 17 [OP_DIV]",
        "solution_abst_en": "1000 50 [OP_SUB] 2 [OP_DIV] 35 [OP_SUB] 2 [OP_DIV] 35 [OP_ADD] 17 [OP_DIV]",
        "solution_code_ko": "var_a = 1000\nvar_b = 50\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 35\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nvar_j = 35\nvar_k = var_i + var_j\nvar_l = 17\nvar_m = var_k / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 1000\nvar_b = 50\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 35\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nvar_j = 35\nvar_k = var_i + var_j\nvar_l = 17\nvar_m = var_k / var_l\nprint(int(var_m))"
    },
    "5262": {
        "category": "Correspondence",
        "question_ko": "632-AB1=41일 때, B에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "When 632-AB1=41, what number should go in B?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "632-AB1=41 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "632-AB1=41 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '632-AB1=41'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '632-AB1=41'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "5263": {
        "category": "Arithmetic calculation",
        "question_ko": "민영이가 물을 7/9리터(L), 유나는 2리터(L) 마셨습니다. 민영이가 마신 물의 양은 유나가 마신 물의 양의 몇 배인지 구하시오.",
        "question_en": "Minyoung drank 7/9 liters (L) of water, and Yuna drank 2 liters (L). Find how many times the amount of water Minyoung drank compared to the amount of water Yuna drank.",
        "answer_ko": "0.39",
        "answer_en": "0.39",
        "solution_abst_ko": "7/9 2 [OP_DIV]",
        "solution_abst_en": "7/9 2 [OP_DIV]",
        "solution_code_ko": "var_a = 0.7777777777777778\nvar_b = 2\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 0.7777777777777778\nvar_b = 2\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "5264": {
        "category": "Comparison",
        "question_ko": "총 3개의 숫자 0.8, 1/2, 0.5이 있습니다. 이 중 3보다 작거나 같은 수는 몇 개 일까요?",
        "question_en": "There are a total of three numbers: 0.8, 1/2, and 0.5. How many of these numbers are less than or equal to 3?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.5 [OP_LIST_EOL] 3 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.5 [OP_LIST_EOL] 3 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = []\nfor i in list_a:\n    if i <= var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = []\nfor i in list_a:\n    if i <= var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "5265": {
        "category": "Correspondence",
        "question_ko": "어떤 수와 143을 더한 값의 27배는 9693입니다. 어떤 수를 구하시오.",
        "question_en": "27 times a number plus 143 is 9693. Find the number.",
        "answer_ko": "216",
        "answer_en": "216",
        "solution_abst_ko": "9693 27 [OP_DIV] 143 [OP_SUB]",
        "solution_abst_en": "9693 27 [OP_DIV] 143 [OP_SUB]",
        "solution_code_ko": "var_a = 9693\nvar_b = 27\nvar_c = var_a / var_b\nvar_d = 143\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9693\nvar_b = 27\nvar_c = var_a / var_b\nvar_d = 143\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "5266": {
        "category": "Arithmetic calculation",
        "question_ko": "율기와 동민이가 가지고 있던 돈의 합은 5000원이었습니다. 율기는 가지고 있던 돈을 모두 냈고, 동민이는 율기보다 300원을 더 내어 4500원짜리 인형 하나를 샀습니다. 동민이가 처음에 가지고 있던 돈은 얼마입니까?",
        "question_en": "Yulgi and Dongmin had 5,000 won in total. Yulgi paid all the money he had, and Dongmin paid 300 won more than Yulgi to buy a doll of 4,500 won. How much money did Dongmin have at first?",
        "answer_ko": "2900",
        "answer_en": "2900",
        "solution_abst_ko": "5000 4500 300 [OP_SUB] 2 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "5000 4500 300 [OP_SUB] 2 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 5000\nvar_b = 4500\nvar_c = 300\nvar_d = var_b - var_c\nvar_e = 2\nvar_f = var_d / var_e\nvar_g = var_a - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 5000\nvar_b = 4500\nvar_c = 300\nvar_d = var_b - var_c\nvar_e = 2\nvar_f = var_d / var_e\nvar_g = var_a - var_f\nprint(int(var_g))"
    },
    "5267": {
        "category": "Arithmetic calculation",
        "question_ko": "수탉은 암탉보다 16마리 많습니다. 암탉이 52마리 일 때 농장에 있는 닭은 모두 몇 마리입니까?",
        "question_en": "Roosters outnumber hens by 16. How many chickens are there on the farm when there are 52 hens?",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "52 52 16 [OP_ADD] [OP_ADD]",
        "solution_abst_en": "52 52 16 [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 52\nvar_b = 52\nvar_c = 16\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 52\nvar_b = 52\nvar_c = 16\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "5268": {
        "category": "Arithmetic calculation",
        "question_ko": "가로등이 50미터(m) 간격으로 1650미터(m)인 강의 다리위에 세워져있습니다. 다리의 처음부터 끝까지 가로등이 세워져 있을 때, 다리의 양쪽에 세워진 가로등의 수는 모두 몇 개 입니까?",
        "question_en": "Street lamps are erected on a bridge over a river that is 1650 meters (m) at intervals of 50 meters (m). If there are street lamps from the beginning to the end of the bridge, how many lamps are there on both sides of the bridge?",
        "answer_ko": "68",
        "answer_en": "68",
        "solution_abst_ko": "1650 50 [OP_DIV] 1 [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "1650 50 [OP_DIV] 1 [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 1650\nvar_b = 50\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1650\nvar_b = 50\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "5269": {
        "category": "Comparison",
        "question_ko": "키가 작은 사람부터 순서대로 9명이 한 줄로 서 있습니다. 호석이는 가장 키가 크고, 유나는 호석이로부터 5번째 앞에 서 있습니다. 키가 큰 사람부터 순서대로 다시 줄을 서면 유나는 앞에서부터 몇 번째에 서게 됩니까?",
        "question_en": "Nine people stand in a line in order from shortest to tallest. Hoseok is the tallest, and Yuna stands 5th ahead of Hoseok. If you line up again in order of tallest people, what number will Yuna stand from the front?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "9 9 [OP_SUB] 5 [OP_ADD] 1 [OP_ADD]",
        "solution_abst_en": "9 9 [OP_SUB] 5 [OP_ADD] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 9\nvar_b = 9\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 9\nvar_b = 9\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "5270": {
        "category": "Correspondence",
        "question_ko": "A, B는 한 자리 수입니다. A는 5보다 3 큰 수이고, B는 A보다 2 작은 수입니다. A와 B의 합을 구하시오.",
        "question_en": "A and B are single-digit numbers. A is 3 greater than 5, and B is 2 less than A. Calculate the sum of A and B.",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "5 3 [OP_ADD] 5 3 [OP_ADD] 2 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "5 3 [OP_ADD] 5 3 [OP_ADD] 2 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = 2\nvar_h = var_f - var_g\nvar_i = var_c + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 5\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = 2\nvar_h = var_f - var_g\nvar_i = var_c + var_h\nprint(int(var_i))"
    },
    "5271": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 2를 더해야 하는데 잘못해서 빼었더니 5가 되었다. 바르게 계산하면 얼마인지 구하시오.",
        "question_en": "You had to add 2 to a certain number, but you mistakenly subtracted it, and the result was 5. What is the value if it is correctly calculated?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "5 2 [OP_ADD] 2 [OP_ADD]",
        "solution_abst_en": "5 2 [OP_ADD] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "5272": {
        "category": "Geometry",
        "question_ko": "전교생을 큰 정사각형으로 줄세웠더니 둘레에 세워진 학생이 240명이었습니다. 전교생은 모두 몇 명일까요?",
        "question_en": "When the entire school students were arranged in a large square, there were 240 students standing at the perimeter. How many students were there in all?",
        "answer_ko": "3721",
        "answer_en": "3721",
        "solution_abst_ko": "240 4 [OP_DIV] 1 [OP_ADD] 2 [OP_POW]",
        "solution_abst_en": "240 4 [OP_DIV] 1 [OP_ADD] 2 [OP_POW]",
        "solution_code_ko": "var_a = 240\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e ** var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 240\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e ** var_f\nprint(int(var_g))"
    },
    "5273": {
        "category": "Geometry",
        "question_ko": "정사각형 모양의 타일을 빈틈없이 규칙적으로 늘어놓아 큰 정사각형을 만들었습니다. 둘레에 놓인 타일의 개수가 240개였다면, 사용한 타일 전체의 개수는 몇 개입니까?",
        "question_en": "A large square was created by arranging the square-shaped tiles regularly without any gaps. If the number of tiles arranged at the perimeter was 240, how many tiles in total were used?",
        "answer_ko": "3721",
        "answer_en": "3721",
        "solution_abst_ko": "240 4 [OP_DIV] 1 [OP_ADD] 2 [OP_POW]",
        "solution_abst_en": "240 4 [OP_DIV] 1 [OP_ADD] 2 [OP_POW]",
        "solution_code_ko": "var_a = 240\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e ** var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 240\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e ** var_f\nprint(int(var_g))"
    },
    "5274": {
        "category": "Arithmetic calculation",
        "question_ko": "콜라 원액이 2.3리터(L) 있다. 콜라 원액 400밀리리터(㎖)로 콜라 3병을 만든다고 한다. 콜라 몇 병을 만들 수 있는가?(단, 콜라는 한번에 3병씩 만든다.)",
        "question_en": "There are 2.3 liters (L) of Coke extract. It is said that 3 bottles of cola are made with 400 milliliters (ml) of cola extract. How many bottles of Coke can you make? (However, 3 bottles of Coke can be made at a time.)",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "2.3 1000 [OP_MUL] 400 [OP_FDIV] 3 [OP_MUL]",
        "solution_abst_en": "2.3 1000 [OP_MUL] 400 [OP_FDIV] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 2.3\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 400\nvar_e = var_c // var_d\nvar_f = 3\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 2.3\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 400\nvar_e = var_c // var_d\nvar_f = 3\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "5275": {
        "category": "Arithmetic calculation",
        "question_ko": "공책 400권을 노랑반, 빨강반, 파랑반 학생들에게 4권씩 나누어주려고 합니다. 각 반의 학생 수가 각각 30명, 27명, 28명 이라고 할 때 남은 공책은 몇 권입니까?",
        "question_en": "I'm going to distribute 400 notebooks to each of the Yellow, Red, and Blue class students. If the number of students in each class is 30, 27, and 28, how many notebooks are left?",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "400 30 27 [OP_ADD] 28 [OP_ADD] 4 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "400 30 27 [OP_ADD] 28 [OP_ADD] 4 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 400\nvar_b = 30\nvar_c = 27\nvar_d = var_b + var_c\nvar_e = 28\nvar_f = var_d + var_e\nvar_g = 4\nvar_h = var_f * var_g\nvar_i = var_a - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 400\nvar_b = 30\nvar_c = 27\nvar_d = var_b + var_c\nvar_e = 28\nvar_f = var_d + var_e\nvar_g = 4\nvar_h = var_f * var_g\nvar_i = var_a - var_h\nprint(int(var_i))"
    },
    "5276": {
        "category": "Arithmetic calculation",
        "question_ko": "6으로 나누어 떨어지고 30이상 50이하인 자연수들의 평균을 구하시오.",
        "question_en": "Find the average of the natural numbers that are divisible by 6 and are between 30 and 50.",
        "answer_ko": "39",
        "answer_en": "39",
        "solution_abst_ko": "30 50 1 [OP_LIST_ARANGE] 6 [OP_LIST_DIVISIBLE] [OP_LIST_MEAN]",
        "solution_abst_en": "30 50 1 [OP_LIST_ARANGE] 6 [OP_LIST_DIVISIBLE] [OP_LIST_MEAN]",
        "solution_code_ko": "var_a = 30\nvar_b = 50\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)/len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 30\nvar_b = 50\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)/len(list_b)\nprint(int(var_e))"
    },
    "5277": {
        "category": "Comparison",
        "question_ko": "(다) 과일은 (나) 과일보다 무겁고 (가) 과일보다 가볍습니다. 가장 무거운 과일은 무엇입니까?",
        "question_en": "(c) fruit is heavier than (b) fruit and lighter than (a) fruit. What is the heaviest fruit?",
        "answer_ko": "(가)",
        "answer_en": "(a)",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) (다) [OP_LIST_EOL] [OP_LIST_SOL] (다) (나) > (다) (가) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (a) (b) (c) [OP_LIST_EOL] [OP_LIST_SOL] (c) (b) > (c) (a) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nvar_c = '(다)'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '(다)'\nvar_e = '(나)'\nvar_f = '>'\nvar_g = '(다)'\nvar_h = '(가)'\nvar_i = '<'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(var_k)",
        "solution_code_en": "var_a = '(a)'\nvar_b = '(b)'\nvar_c = '(c)'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '(c)'\nvar_e = '(b)'\nvar_f = '>'\nvar_g = '(c)'\nvar_h = '(a)'\nvar_i = '<'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(var_k)"
    },
    "5278": {
        "category": "Comparison",
        "question_ko": "1.4, 9/10, 1.2, 0.5, 13/10 중에서 1.1보다 작은 숫자를 고르고, 선택된 숫자들의 합을 구하세요",
        "question_en": "Choose a number less than 1.1 from 1.4, 9/10, 1.2, 0.5, 13/10 and find the sum of the selected numbers",
        "answer_ko": "1.40",
        "answer_en": "1.4",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i < var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i < var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "5279": {
        "category": "Geometry",
        "question_ko": "모서리와 꼭짓점의 수의 합이 30인 각기둥이 있다. 이 각기둥의 옆면의 개수에 2를 더하면 얼마인가?",
        "question_en": "There is a prism with the sum of the number of edges and vertices equal to 30. What is the number of sides of this prism plus 2?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "30 2 3 [OP_ADD] [OP_DIV] 2 [OP_ADD]",
        "solution_abst_en": "30 2 3 [OP_ADD] [OP_DIV] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 30\nvar_b = 2\nvar_c = 3\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 30\nvar_b = 2\nvar_c = 3\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "5280": {
        "category": "Correspondence",
        "question_ko": "A는 1부터 9까지의 수입니다. 0.4<0.A, 6.A<6.8, 3.A<A.4가 참이 되는 모든 A의 합을 구하면 얼마입니까?",
        "question_en": "A is a number from 1 to 9. What is the sum of all As that satisfy 0.4<0.A, 6.A<6.8, and 3.A<A.4?",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "0.4<0.A A [OP_DIGIT_UNK_SOLVER] 6.A<6.8 A [OP_DIGIT_UNK_SOLVER] [OP_SET_INTERSECT] 3.A<A.4 A [OP_DIGIT_UNK_SOLVER] [OP_SET_INTERSECT] [OP_LIST_SUM]",
        "solution_abst_en": "0.4<0.A A [OP_DIGIT_UNK_SOLVER] 6.A<6.8 A [OP_DIGIT_UNK_SOLVER] [OP_SET_INTERSECT] 3.A<A.4 A [OP_DIGIT_UNK_SOLVER] [OP_SET_INTERSECT] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = '0.4<0.A'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = '6.A<6.8'\nvar_d = 'A'\nans_dict = dict()\nvar_c = var_c.replace('×','*')\nvar_c = var_c.replace('x','*')\nvar_c = var_c.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_c):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_c\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_c):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_b = list(set(ans_dict[var_d]))\nlist_c = list(set(list_a) & set(list_b))\nvar_e = '3.A<A.4'\nvar_f = 'A'\nans_dict = dict()\nvar_e = var_e.replace('×','*')\nvar_e = var_e.replace('x','*')\nvar_e = var_e.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_e):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_e\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_e):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_d = list(set(ans_dict[var_f]))\nlist_e = list(set(list_c) & set(list_d))\nlist_e = [float(i) for i in list_e]\nvar_g = sum(list_e)\nprint(int(var_g))",
        "solution_code_en": "var_a = '0.4<0.A'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = '6.A<6.8'\nvar_d = 'A'\nans_dict = dict()\nvar_c = var_c.replace('×','*')\nvar_c = var_c.replace('x','*')\nvar_c = var_c.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_c):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_c\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_c):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_b = list(set(ans_dict[var_d]))\nlist_c = list(set(list_a) & set(list_b))\nvar_e = '3.A<A.4'\nvar_f = 'A'\nans_dict = dict()\nvar_e = var_e.replace('×','*')\nvar_e = var_e.replace('x','*')\nvar_e = var_e.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_e):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_e\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_e):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_d = list(set(ans_dict[var_f]))\nlist_e = list(set(list_c) & set(list_d))\nlist_e = [float(i) for i in list_e]\nvar_g = sum(list_e)\nprint(int(var_g))"
    },
    "5281": {
        "category": "Comparison",
        "question_ko": "일정한 빠르기로 택시는 17.28킬로미터(㎞)의 거리를 16분 동안에 가고, 승용차는 8.52킬로미터(㎞)의 거리를 6분 동안에 갑니다. 같은 곳에서 출발해서 15분 동안 달린다면 택시와 승용차 중 어느 것이 더 멀리 위치하겠습니까?",
        "question_en": "At a constant speed, a taxi travels a distance of 17.28 kilometers (km) in 16 minutes, and a car travels a distance of 8.52 kilometers (km) in 6 minutes. If you start from the same place and drive for 15 minutes, which goes farther: a taxi or a car?",
        "answer_ko": "승용차",
        "answer_en": "car",
        "solution_abst_ko": "[OP_LIST_SOL] 택시 승용차 [OP_LIST_EOL] [OP_LIST_SOL] 17.28 16 [OP_DIV] 15 [OP_MUL] 8.52 6 [OP_DIV] 15 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] taxi car [OP_LIST_EOL] [OP_LIST_SOL] 17.28 16 [OP_DIV] 15 [OP_MUL] 8.52 6 [OP_DIV] 15 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '택시'\nvar_b = '승용차'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 17.28\nvar_d = 16\nvar_e = var_c / var_d\nvar_f = 15\nvar_g = var_e * var_f\nvar_h = 8.52\nvar_i = 6\nvar_j = var_h / var_i\nvar_k = 15\nvar_l = var_j * var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'taxi'\nvar_b = 'car'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 17.28\nvar_d = 16\nvar_e = var_c / var_d\nvar_f = 15\nvar_g = var_e * var_f\nvar_h = 8.52\nvar_i = 6\nvar_j = var_h / var_i\nvar_k = 15\nvar_l = var_j * var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "5282": {
        "category": "Correspondence",
        "question_ko": "9A3B를 올림하여 십의 자리까지 나타내었더니 9430이었다. A는 무엇인가?",
        "question_en": "When 9A3B was rounded up to the tens place, it was 9430. What is A?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "9A3B [OP_GEN_POSSIBLE_LIST] 9430 [OP_LIST_MORE_EQUAL] 9430 10 [OP_ADD] [OP_LIST_LESS] 9A3B A [OP_LIST_FIND_UNK]",
        "solution_abst_en": "9A3B [OP_GEN_POSSIBLE_LIST] 9430 [OP_LIST_MORE_EQUAL] 9430 10 [OP_ADD] [OP_LIST_LESS] 9A3B A [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = '9A3B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 9430\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 9430\nvar_d = 10\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = '9A3B'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))",
        "solution_code_en": "var_a = '9A3B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 9430\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 9430\nvar_d = 10\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = '9A3B'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))"
    },
    "5283": {
        "category": "Arithmetic calculation",
        "question_ko": "줄넘기를 호석이는 34번, 민영이는 51번 넘었습니다. 호석이가 몇 번을 더 넘어야 민영이의 줄넘기 횟수와 같아집니까?",
        "question_en": "Hoseok jumped the rope 34 times and Minyoung jumped it 51 times. How many more times does Hoseok have to jump to get the same number of jumps as Minyoung?",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "51 34 [OP_SUB]",
        "solution_abst_en": "51 34 [OP_SUB]",
        "solution_code_ko": "var_a = 51\nvar_b = 34\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 51\nvar_b = 34\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "5284": {
        "category": "Arithmetic calculation",
        "question_ko": "합이 100이 되는 연속된 5개의 자연수가 있습니다. 이 중에서 가장 작은 수는 얼마입니까?",
        "question_en": "There are 5 consecutive natural numbers whose sum is 100. What is the smallest of these numbers?",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "100 5 [OP_DIV] 5 2 [OP_FDIV] [OP_SUB]",
        "solution_abst_en": "100 5 [OP_DIV] 5 2 [OP_FDIV] [OP_SUB]",
        "solution_code_ko": "var_a = 100\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d // var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 100\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d // var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "5285": {
        "category": "Comparison",
        "question_ko": "(가), (나), (다), (라), (마) 5개의 상자가 있습니다. (라) 상자는 (나) 상자보다 크고 (가) 상자보다 작습니다. (나) 상자는 (마) 상자보다 큽니다. (가) 상자는 (다) 상자보다 작습니다. 가장 큰 상자는 어느 상자입니까?",
        "question_en": "There are five boxes: A, B, C, D, and E. D box is larger than B box and smaller than A box. B box is larger than E box. A box is smaller than C box. Which box is the largest?",
        "answer_ko": "(다)",
        "answer_en": "C",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) (다) (라) (마) [OP_LIST_EOL] [OP_LIST_SOL] (라) (나) > (라) (가) < (나) (마) > (가) (다) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D E [OP_LIST_EOL] [OP_LIST_SOL] D B > D A < B E > A C < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nvar_c = '(다)'\nvar_d = '(라)'\nvar_e = '(마)'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = '(라)'\nvar_g = '(나)'\nvar_h = '>'\nvar_i = '(라)'\nvar_j = '(가)'\nvar_k = '<'\nvar_l = '(나)'\nvar_m = '(마)'\nvar_n = '>'\nvar_o = '(가)'\nvar_p = '(다)'\nvar_q = '<'\nlist_b= []\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_r = 1\nvar_s = list_c[var_r-1]\nprint(var_s)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 'D'\nvar_g = 'B'\nvar_h = '>'\nvar_i = 'D'\nvar_j = 'A'\nvar_k = '<'\nvar_l = 'B'\nvar_m = 'E'\nvar_n = '>'\nvar_o = 'A'\nvar_p = 'C'\nvar_q = '<'\nlist_b= []\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_r = 1\nvar_s = list_c[var_r-1]\nprint(var_s)"
    },
    "5286": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 8로 나눈 몫이 0.65입니다. 어떤 수를 5로 나눈 몫에 7을 곱하면 얼마인지 구해보세요.",
        "question_en": "The quotient of a number divided by 8 is 0.65. Find the value of the quotient of the number divided by 5 multiplied by 7.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "0.65 8 [OP_MUL] 5 [OP_FDIV] 7 [OP_MUL]",
        "solution_abst_en": "0.65 8 [OP_MUL] 5 [OP_FDIV] 7 [OP_MUL]",
        "solution_code_ko": "var_a = 0.65\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c // var_d\nvar_f = 7\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 0.65\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c // var_d\nvar_f = 7\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "5287": {
        "category": "Arithmetic calculation",
        "question_ko": "주차장에 7대의 버스가 있었는데 몇 분 후 6대의 버스가 더 왔습니다. 지금 주차장에 있는 버스는 모두 몇 대입니까?",
        "question_en": "There were 7 buses in the parking lot and 6 more came a few minutes later. How many buses are in the parking lot right now?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "7 6 [OP_ADD]",
        "solution_abst_en": "7 6 [OP_ADD]",
        "solution_code_ko": "var_a = 7\nvar_b = 6\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 7\nvar_b = 6\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "5288": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 5를 뺀 것의 4배는 어떤 수에서 2를 곱한 것과 같다. 어떤 수를 구하시오.",
        "question_en": "A number subtracted by 5 multiplied by 4 equals the number multiplied by 2. Find the number.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "5 4 [OP_MUL] 4 2 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "5 4 [OP_MUL] 4 2 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 5\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))"
    },
    "5289": {
        "category": "Arithmetic calculation",
        "question_ko": "바다에 물고기 5마리와 고래 2마리가 있습니다. 바다에는 총 몇 마리의 물고기가 있나요?",
        "question_en": "There are 5 tuna and 2 spearfish in the sea. What is the total number of fish in the sea?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "5 2 [OP_ADD]",
        "solution_abst_en": "5 2 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "5290": {
        "category": "Geometry",
        "question_ko": "크기가 같은 주사위 8개로 큰 정육면체 한 개를 만들었습니다. 주사위 한 개의 겉넓이가 96제곱센티미터(㎠)일 때 만든 정육면체의 부피는 몇 세제곱센티미터(㎤)인지 구하시오.",
        "question_en": "A large cube was made out of eight dices of the same size. If the surface area of one die is 96 square centimeters (cm2), find the volume in cubic centimeters (cm3) of the cube created.",
        "answer_ko": "512",
        "answer_en": "512",
        "solution_abst_ko": "96 6 [OP_DIV] 1/2 [OP_POW] 8 2 [OP_DIV] 2 [OP_DIV] [OP_MUL] 3 [OP_POW]",
        "solution_abst_en": "96 6 [OP_DIV] 1/2 [OP_POW] 8 2 [OP_DIV] 2 [OP_DIV] [OP_MUL] 3 [OP_POW]",
        "solution_code_ko": "var_a = 96\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 8\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = 2\nvar_j = var_h / var_i\nvar_k = var_e * var_j\nvar_l = 3\nvar_m = var_k ** var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 96\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 8\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = 2\nvar_j = var_h / var_i\nvar_k = var_e * var_j\nvar_l = 3\nvar_m = var_k ** var_l\nprint(int(var_m))"
    },
    "5291": {
        "category": "Comparison",
        "question_ko": "세정이네 학교 학생 수는 1443명입니다. 그런데 남학생 수는 여학생 수보다 141명 더 많다고 합니다. 남학생의 수는 몇 명입니까?",
        "question_en": "The number of students at Sejeong's School is 1443. However, there are 141 more male students than female students. How many male students are there?",
        "answer_ko": "792",
        "answer_en": "792",
        "solution_abst_ko": "1443 141 [OP_SUB] 2 [OP_DIV] 141 [OP_ADD]",
        "solution_abst_en": "1443 141 [OP_SUB] 2 [OP_DIV] 141 [OP_ADD]",
        "solution_code_ko": "var_a = 1443\nvar_b = 141\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 141\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1443\nvar_b = 141\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 141\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "5292": {
        "category": "Arithmetic calculation",
        "question_ko": "태형이는 동생보다 5살이 많고 올해 태형이 동생은 7살입니다. 태형이와 어머니의 나이차가 31살일때 어머니는 몇 살입니까?",
        "question_en": "Taehyung is 5 years older than his younger brother, and this year Taehyung's younger brother is 7 years old. How old is his mother when the age difference between Taehyung and his mother is 31 years?",
        "answer_ko": "43",
        "answer_en": "43",
        "solution_abst_ko": "7 5 [OP_ADD] 31 [OP_ADD]",
        "solution_abst_en": "7 5 [OP_ADD] 31 [OP_ADD]",
        "solution_code_ko": "var_a = 7\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 31\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 7\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 31\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "5293": {
        "category": "Correspondence",
        "question_ko": "두 자연수 A, B가 있습니다. B는 A에서 9를 곱한 후 13을 더했을 때 나오는 숫자라면, B를 9로 나누었을 때의 나머지는 얼마입니까?",
        "question_en": "A and B are two natural numbers. If B is the number obtained by multiplying A by 9 and then adding 13, what is the remainder when B is divided by 9?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "13 9 [OP_MOD]",
        "solution_abst_en": "13 9 [OP_MOD]",
        "solution_code_ko": "var_a = 13\nvar_b = 9\nvar_c = var_a % var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 13\nvar_b = 9\nvar_c = var_a % var_b\nprint(int(var_c))"
    },
    "5294": {
        "category": "Possibility",
        "question_ko": "1, 3, 5, 7, 9 중 세 개를 뽑아 세 자리 자연수를 만들 때, 가능한 모든 경우의 수는 얼마입니까?",
        "question_en": "How many ways are possible to make a three-digit number by selecting three of 1, 3, 5, 7, and 9?",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 5 7 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 5 7 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 5\nvar_d = 7\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 5\nvar_d = 7\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "5295": {
        "category": "Possibility",
        "question_ko": "정국이는 빨간 공 5개, 파란 공 4개, 노란 공 3개를 가지고 있습니다. 윤기가 정국이에게 빨간 공 1개를 주었을 때, 정국이가 가지고 있는 노란 공의 개수는?",
        "question_en": "Jungkook has 5 red balls, 4 blue balls, and 3 yellow balls. When Yoongi gives Jungkook one red ball, how many yellow balls does Jungkook have?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "3",
        "solution_abst_en": "3",
        "solution_code_ko": "var_a = 3\nprint(int(var_a))",
        "solution_code_en": "var_a = 3\nprint(int(var_a))"
    },
    "5296": {
        "category": "Geometry",
        "question_ko": "길이가 12센티미터(㎝)인 철사를 절반으로 구부리고, 구부린 철사를 다시 절반으로 구부렸다면, 현재 철사의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "If you bend a 12 centimeters (cm) wire in half, and then bend the bent wire in half again, how many centimeters (cm) is the current length of the wire?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "12 2 [OP_DIV] 2 [OP_DIV]",
        "solution_abst_en": "12 2 [OP_DIV] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "5297": {
        "category": "Correspondence",
        "question_ko": "A에 10을 더했더니 15가 되었습니다. A는 얼마인가요?",
        "question_en": "If you add 10 to A, you get 15. How much is A?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "15 10 [OP_SUB]",
        "solution_abst_en": "15 10 [OP_SUB]",
        "solution_code_ko": "var_a = 15\nvar_b = 10\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 15\nvar_b = 10\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "5298": {
        "category": "Correspondence",
        "question_ko": "운동장에 학생들이 줄을 맞춰 서려고 한다. 5줄로 섰더니 2명이 남고, 8줄로 섰더니 3명이 남고, 9줄로 섰더니 꼭 맞았다. 학생수는 모두 몇 명인지 구하여라. 단, 운동장에 있는 학생수는 200 이상 500명 이하이다.",
        "question_en": "Students are trying to line up on the playground. When they are stood in 5 lines, 2 students were left out, when stood in 8 lines, 3 students were left, and when stood in 9 lines, it fit perfectly. Find how many students there are in total. However, the number of students in the playground is between 200 and 500.",
        "answer_ko": "387",
        "answer_en": "387",
        "solution_abst_ko": "200 500 1 [OP_LIST_ARANGE] 5 2 [OP_LIST_DIVIDE_AND_REMAIN] 8 3 [OP_LIST_DIVIDE_AND_REMAIN] 9 0 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "200 500 1 [OP_LIST_ARANGE] 5 2 [OP_LIST_DIVIDE_AND_REMAIN] 8 3 [OP_LIST_DIVIDE_AND_REMAIN] 9 0 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 200\nvar_b = 500\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nvar_e = 2\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 8\nvar_g = 3\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 9\nvar_i = 0\nlist_d = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_c:\n    i = int(i)\n    if i%var_h == var_i:\n        list_d.append(i)\nvar_j = 1\nvar_k = list_d[var_j-1]\nprint(int(var_k))",
        "solution_code_en": "var_a = 200\nvar_b = 500\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nvar_e = 2\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 8\nvar_g = 3\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 9\nvar_i = 0\nlist_d = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_c:\n    i = int(i)\n    if i%var_h == var_i:\n        list_d.append(i)\nvar_j = 1\nvar_k = list_d[var_j-1]\nprint(int(var_k))"
    },
    "5299": {
        "category": "Arithmetic calculation",
        "question_ko": "(가) 동물 6마리, (나) 동물 8마리, (다) 동물 4마리가 있습니다. 동물은 모두 몇 마리입니까?",
        "question_en": "There are 6 (A) animals, 8 (B) animals, and 4 (C) animals. How many animals are there in all?",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "6 8 [OP_ADD] 4 [OP_ADD]",
        "solution_abst_en": "6 8 [OP_ADD] 4 [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "5300": {
        "category": "Geometry",
        "question_ko": "한 면의 넓이가 64제곱센티미터(㎠)인 정육면체가 있습니다. 이 정육면체의 부피는 얼마입니까?",
        "question_en": "There is a cube with a side with an area of 64 square centimeters (cm2). What is the volume of this cube?",
        "answer_ko": "512",
        "answer_en": "512",
        "solution_abst_ko": "64 1/2 [OP_POW] 3 [OP_POW]",
        "solution_abst_en": "64 1/2 [OP_POW] 3 [OP_POW]",
        "solution_code_ko": "var_a = 64\nvar_b = 0.5\nvar_c = var_a ** var_b\nvar_d = 3\nvar_e = var_c ** var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 64\nvar_b = 0.5\nvar_c = var_a ** var_b\nvar_d = 3\nvar_e = var_c ** var_d\nprint(int(var_e))"
    },
    "5301": {
        "category": "Correspondence",
        "question_ko": "어떤 수의 3배를 5로 나눈 뒤 220을 빼고 4를 곱하고 40을 더했더니 360이 되었습니다. 어떤 수를 구하시오.",
        "question_en": "Divide 3 times a number by 5, subtract 220, multiply by 4, add 40, and you get 360. Find the number.",
        "answer_ko": "500",
        "answer_en": "500",
        "solution_abst_ko": "360 40 [OP_SUB] 4 [OP_DIV] 220 [OP_ADD] 5 [OP_MUL] 3 [OP_DIV]",
        "solution_abst_en": "360 40 [OP_SUB] 4 [OP_DIV] 220 [OP_ADD] 5 [OP_MUL] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 360\nvar_b = 40\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 220\nvar_g = var_e + var_f\nvar_h = 5\nvar_i = var_g * var_h\nvar_j = 3\nvar_k = var_i / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 360\nvar_b = 40\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 220\nvar_g = var_e + var_f\nvar_h = 5\nvar_i = var_g * var_h\nvar_j = 3\nvar_k = var_i / var_j\nprint(int(var_k))"
    },
    "5302": {
        "category": "Comparison",
        "question_ko": "석진이는 우유를 11/10리터(L) 마셨고, 정국이는 1.3리터(L) 마셨습니다. 윤기는 7/5리터(L) 마셨을 때 우유를 가장 적게 마신 사람은 누구입니까?",
        "question_en": "Seokjin drank 11/10 liters (l) of milk, and Jungkook drank 1.3 liters (l). When Yoongi drank 7/6 liters (l), who drank the least amount of milk?",
        "answer_ko": "석진",
        "answer_en": "Seokjin",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 석진 윤기 [OP_LIST_EOL] [OP_LIST_SOL] 1.3 11 10 [OP_DIV] 7 5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Seokjin Yoongi [OP_LIST_EOL] [OP_LIST_SOL] 1.3 11 10 [OP_DIV] 7 5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '석진'\nvar_c = '윤기'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1.3\nvar_e = 11\nvar_f = 10\nvar_g = var_e / var_f\nvar_h = 7\nvar_i = 5\nvar_j = var_h / var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[var_k-1]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Seokjin'\nvar_c = 'Yoongi'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1.3\nvar_e = 11\nvar_f = 10\nvar_g = var_e / var_f\nvar_h = 7\nvar_i = 5\nvar_j = var_h / var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[var_k-1]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "5303": {
        "category": "Comparison",
        "question_ko": "어느 공장에서 축구공은 30분에 500개가 만들어지고, 농구공은 1시간에 800개가 만들어진다면, 5시간 후에는 어떤 공이 더 많이 만들어질지 구하시오.",
        "question_en": "If a factory produces 500 soccer balls in 30 minutes and 800 basketball balls in 1 hour, which ball will be produced more after 5 hours?",
        "answer_ko": "축구공",
        "answer_en": "soccer",
        "solution_abst_ko": "[OP_LIST_SOL] 축구공 농구공 [OP_LIST_EOL] [OP_LIST_SOL] 5 60 [OP_MUL] 30 [OP_FDIV] 500 [OP_MUL] 5 60 [OP_MUL] 60 [OP_FDIV] 800 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] soccer basketball [OP_LIST_EOL] [OP_LIST_SOL] 5 60 [OP_MUL] 30 [OP_FDIV] 500 [OP_MUL] 5 60 [OP_MUL] 60 [OP_FDIV] 800 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '축구공'\nvar_b = '농구공'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 5\nvar_d = 60\nvar_e = var_c * var_d\nvar_f = 30\nvar_g = var_e // var_f\nvar_h = 500\nvar_i = var_g * var_h\nvar_j = 5\nvar_k = 60\nvar_l = var_j * var_k\nvar_m = 60\nvar_n = var_l // var_m\nvar_o = 800\nvar_p = var_n * var_o\nlist_b= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nlist_b.reverse()\nvar_q = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_r = list_c[-var_q]\nvar_s = list_b.index(var_r)+1\nvar_t = list_a[var_s-1]\nprint(var_t)",
        "solution_code_en": "var_a = 'soccer'\nvar_b = 'basketball'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 5\nvar_d = 60\nvar_e = var_c * var_d\nvar_f = 30\nvar_g = var_e // var_f\nvar_h = 500\nvar_i = var_g * var_h\nvar_j = 5\nvar_k = 60\nvar_l = var_j * var_k\nvar_m = 60\nvar_n = var_l // var_m\nvar_o = 800\nvar_p = var_n * var_o\nlist_b= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nlist_b.reverse()\nvar_q = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_r = list_c[-var_q]\nvar_s = list_b.index(var_r)+1\nvar_t = list_a[var_s-1]\nprint(var_t)"
    },
    "5304": {
        "category": "Correspondence",
        "question_ko": "3×7=7×A=B 일 때 A와 B의 합은 무엇인가?",
        "question_en": "When 3×7=7×A=B, what is the sum of A and B?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "3×7=7×A=B A [OP_NUM_UNK_SOLVER] 3×7=7×A=B B [OP_NUM_UNK_SOLVER] [OP_ADD]",
        "solution_abst_en": "3×7=7×A=B A [OP_NUM_UNK_SOLVER] 3×7=7×A=B B [OP_NUM_UNK_SOLVER] [OP_ADD]",
        "solution_code_ko": "var_a = '3×7=7×A=B'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '3×7=7×A=B'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = '3×7=7×A=B'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '3×7=7×A=B'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "5305": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 6으로 나눈 값이 1/10입니다. 어떤 수를 3/25으로 나눈 값을 구하시오.",
        "question_en": "A number divided by 6 equals 1/10. Find the value of the number divided by 3/25.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "1/10 6 [OP_MUL] 3/25 [OP_DIV]",
        "solution_abst_en": "1/10 6 [OP_MUL] 3/25 [OP_DIV]",
        "solution_code_ko": "var_a = 0.1\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 0.12\nvar_e = var_c / var_d\nprint(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))",
        "solution_code_en": "var_a = 0.1\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 0.12\nvar_e = var_c / var_d\nprint(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))"
    },
    "5306": {
        "category": "Possibility",
        "question_ko": "A, B, C, D, E 5명이 있을 때, 대표 3명을 뽑는 경우의 수를 구하시오.",
        "question_en": "If there are 5 people A, B, C, D, and E, find the number of ways to select 3 representatives.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "5 3 [OP_COMB]",
        "solution_abst_en": "5 3 [OP_COMB]",
        "solution_code_ko": "var_a = 5\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))"
    },
    "5307": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 마을에 있는 시계탑의 종은 매시간 정각에 종을 한 번씩 울립니다. 1년을 365일로 계산한다면 이 시계탑의 종은 1년 동안 몇 번을 울리는지 구해 보시오.",
        "question_en": "A clock tower bell in a village rings once every hour on the hour. If a year is counted as 365 days, how many times does the clock tower bell ring in a year?",
        "answer_ko": "8760",
        "answer_en": "8760",
        "solution_abst_ko": "24 365 [OP_MUL]",
        "solution_abst_en": "24 365 [OP_MUL]",
        "solution_code_ko": "var_a = 24\nvar_b = 365\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 24\nvar_b = 365\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "5308": {
        "category": "Possibility",
        "question_ko": "네 개의 숫자 1, 5, 6, 9를 한 번만 사용한 두자리 수의 십의자리 숫자가 5일 때, 두 번째로 작은 두 자리 숫자를 구하시오.",
        "question_en": "Using the four numbers 1, 5, 6, and 9 once, find the second smallest two-digit number when the hundredth number is 5.",
        "answer_ko": "56",
        "answer_en": "56",
        "solution_abst_ko": "[OP_LIST_SOL] 1 5 6 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 10 5 [OP_LIST_SEARCH_FIXED_DIGIT] 2 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 5 6 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 10 5 [OP_LIST_SEARCH_FIXED_DIGIT] 2 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1\nvar_b = 5\nvar_c = 6\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 5\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 2\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 5\nvar_c = 6\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 5\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 2\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nprint(int(var_i))"
    },
    "5309": {
        "category": "Geometry",
        "question_ko": "긴 끈으로 정사각형을 만들었더니 한 변의 길이가 21센티미터(㎝)가 되었습니다. 이 끈으로 세 변의 길이가 같은 삼각형 중에서 가장 큰 삼각형을 만든다면, 한 변의 길이는 몇 센티미터(㎝)가 되겠습니까?",
        "question_en": "I made a square with a long piece of string, and each side was 21 centimeters (cm). If you use this string to make the largest triangle among triangles with a length of the three sides equal, how many centimeters (cm) will each lengths of a side be?",
        "answer_ko": "28",
        "answer_en": "28",
        "solution_abst_ko": "21 4 [OP_MUL] 3 [OP_DIV]",
        "solution_abst_en": "21 4 [OP_MUL] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 21\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 21\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "5310": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 9867, 8976, 9876, 9687, 9689를 작은 수부터 차례대로 나열했을 때, 4번째로 작은 수를 쓰시오.",
        "question_en": "When the five numbers 9867, 8976, 9876, 9687, and 9689 are arranged from smallest to largest, write the 4th smallest number.",
        "answer_ko": "9867",
        "answer_en": "9867",
        "solution_abst_ko": "[OP_LIST_SOL] 9867 8976 9876 9687 9689 [OP_LIST_EOL] 4 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 9867 8976 9876 9687 9689 [OP_LIST_EOL] 4 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 9867\nvar_b = 8976\nvar_c = 9876\nvar_d = 9687\nvar_e = 9689\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 4\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 9867\nvar_b = 8976\nvar_c = 9876\nvar_d = 9687\nvar_e = 9689\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 4\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nprint(int(var_g))"
    },
    "5311": {
        "category": "Correspondence",
        "question_ko": "B에서 A를 뺀 값은 211.5입니다. 소수 A를 10배 하면 B와 같습니다. 소수점을 포함하여 A를 구하시오.",
        "question_en": "B minus A equals 211.5. Multiplying the decimal number A by 10 equals B. Calculate A, including the decimal point.",
        "answer_ko": "23.50",
        "answer_en": "23.5",
        "solution_abst_ko": "211.5 10 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "211.5 10 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 211.5\nvar_b = 10\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 211.5\nvar_b = 10\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "5312": {
        "category": "Correspondence",
        "question_ko": "A, B, C는 서로 다른 한자리 수 자연수입니다. AB+CB=CC6을 만족하는 B는 무엇인가요?",
        "question_en": "A, B, and C are all different single-digit natural numbers. What is B that satisfies AB+CB=CC6?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "AB+CB=CC6 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "AB+CB=CC6 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'AB+CB=CC6'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'AB+CB=CC6'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "5313": {
        "category": "Arithmetic calculation",
        "question_ko": "무게가 똑같은 농구공이 16개가 들어있는 상자의 무게는 17.88킬로그램(㎏)입니다. 빈 상자의 무게가 0.6킬로그램(㎏)일 때, 농구공 7개의 무게는 몇 킬로그램(㎏)입니까?",
        "question_en": "A box with 16 basketballs of the same weight weighs 17.88 kilograms (kg). Consider that the empty box weighs 0.6 kilograms (kg), find out how much 7 basketballs weigh in kilograms (kg).",
        "answer_ko": "7.56",
        "answer_en": "7.56",
        "solution_abst_ko": "17.88 0.6 [OP_SUB] 16 [OP_DIV] 7 [OP_MUL]",
        "solution_abst_en": "17.88 0.6 [OP_SUB] 16 [OP_DIV] 7 [OP_MUL]",
        "solution_code_ko": "var_a = 17.88\nvar_b = 0.6\nvar_c = var_a - var_b\nvar_d = 16\nvar_e = var_c / var_d\nvar_f = 7\nvar_g = var_e * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 17.88\nvar_b = 0.6\nvar_c = var_a - var_b\nvar_d = 16\nvar_e = var_c / var_d\nvar_f = 7\nvar_g = var_e * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "5314": {
        "category": "Correspondence",
        "question_ko": "ABCD+ABCD=5472입니다. 서로 다른 알파벳이 다른 숫자를 의미한다면, D는 얼마입니까?",
        "question_en": "ABCD+ABCD=5472. If different letters mean different numbers, what is D?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "ABCD+ABCD=5472 D [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "ABCD+ABCD=5472 D [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'ABCD+ABCD=5472'\nvar_b = 'D'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'ABCD+ABCD=5472'\nvar_b = 'D'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "5315": {
        "category": "Arithmetic calculation",
        "question_ko": "효성이네 집에서 미미네 집까지의 거리는 2.5 킬로미터(㎞) 입니다. 두 사람이 각자의 집에서 동시에 출발하여 일정한 빠르기로 서로의 집을 향해 걸어갔습니다. 효성이는 1 분에 0.08 킬로미터(㎞) 를 걷고 미미는 한 시간에 2.4 킬로미터(㎞) 를 걸을 때 15 분 후 두 사람 사이의 거리는 몇 킬로미터(㎞) 입니까?",
        "question_en": "The distance from Hyoseong's house to Mimi's house is 2.5 kilometers. The two started at the same time from their respective homes and walked towards each other at a steady pace. If Hyosung walks at 0.08 kilometers (km) per minute and Mimi walks at 2.4 kilometers (km) per hour, how many kilometers (km) is the distance between the two after 15 minutes?",
        "answer_ko": "0.70",
        "answer_en": "0.7",
        "solution_abst_ko": "2.5 0.08 15 [OP_MUL] [OP_SUB] 2.4 60 [OP_DIV] 15 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "2.5 0.08 15 [OP_MUL] [OP_SUB] 2.4 60 [OP_DIV] 15 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 2.5\nvar_b = 0.08\nvar_c = 15\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 2.4\nvar_g = 60\nvar_h = var_f / var_g\nvar_i = 15\nvar_j = var_h * var_i\nvar_k = var_e - var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 2.5\nvar_b = 0.08\nvar_c = 15\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 2.4\nvar_g = 60\nvar_h = var_f / var_g\nvar_i = 15\nvar_j = var_h * var_i\nvar_k = var_e - var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "5316": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2 중에서 0.4보다 크거나 같은 수는 몇 개입니까?",
        "question_en": "How many numbers are greater than or equal to 0.4 out of 0.8 and 1/2?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 [OP_LIST_EOL] 0.4 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 [OP_LIST_EOL] 0.4 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.4\nlist_b = []\nfor i in list_a:\n    if i >= var_c:\n        list_b.append(i)\nvar_d = len(list_b)\nprint(int(var_d))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.4\nlist_b = []\nfor i in list_a:\n    if i >= var_c:\n        list_b.append(i)\nvar_d = len(list_b)\nprint(int(var_d))"
    },
    "5317": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 25센티미터(㎝)인 심지가 있습니다. 이 심지에 불을 붙이면 10초에 1.75센티미터(㎝)씩 탄다고 합니다. 불을 붙힌 뒤 몇 초 후 심지의 길이가 11센티미터(㎝)가 되겠습니까?",
        "question_en": "There are wicks that are 25 centimeters (cm) long. If you light this wick, it is said to burn 1.75 centimeters (cm) in 10 seconds. How many seconds after lighting will the wick be 11 centimeters (cm) long?",
        "answer_ko": "80",
        "answer_en": "80",
        "solution_abst_ko": "25 11 [OP_SUB] 1.75 10 [OP_DIV] [OP_DIV]",
        "solution_abst_en": "25 11 [OP_SUB] 1.75 10 [OP_DIV] [OP_DIV]",
        "solution_code_ko": "var_a = 25\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1.75\nvar_e = 10\nvar_f = var_d / var_e\nvar_g = var_c / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 25\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1.75\nvar_e = 10\nvar_f = var_d / var_e\nvar_g = var_c / var_f\nprint(int(var_g))"
    },
    "5318": {
        "category": "Correspondence",
        "question_ko": "서로 다른 두 수 A, B가 있습니다. 두 자리 수끼리의 덧셈식 4A+B4=86에서 A와 B의 합을 구하시오.",
        "question_en": "You are given two different numbers, A and B. Find the sum of A and B in the two-digit addition equation 4A+B4=86.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "4A+B4=86 A [OP_DIGIT_UNK_SOLVER] 4A+B4=86 B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_abst_en": "4A+B4=86 A [OP_DIGIT_UNK_SOLVER] 4A+B4=86 B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_code_ko": "var_a = '4A+B4=86'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '4A+B4=86'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = '4A+B4=86'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '4A+B4=86'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "5319": {
        "category": "Comparison",
        "question_ko": "달리기를 하던 중 윤기가 7등으로 달리다가 4명을 앞질렀습니다. 9명의 학생이 달리기 시합을 하고 있을 때, 윤기 뒤에 학생의 수는 몇 명입니까?",
        "question_en": "While running, Yoongi was in 7th place and passed 4 others students. When 9 students are running in total , how many students are behind Yoongi?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "9 7 4 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "9 7 4 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 9\nvar_b = 7\nvar_c = 4\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 7\nvar_c = 4\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "5320": {
        "category": "Possibility",
        "question_ko": "가위 7개를 윤기와 호석이에게 나누어 주려고 합니다. 윤기와 호석이는 적어도 1개의 가위를 받습니다. 가위를 나누어주는 방법은 모두 몇 개입니까?",
        "question_en": "I'm going to give 7 scissors to Yoongi and Hoseok. Yoongi and Hoseok take at least one pair of scissors. How many ways are there to distribute scissors?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "7 2 1 [OP_MUL] [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "7 2 1 [OP_MUL] [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 7\nvar_b = 2\nvar_c = 1\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 7\nvar_b = 2\nvar_c = 1\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "5321": {
        "category": "Geometry",
        "question_ko": "정육면체의 한 면의 둘레는 24센티미터(㎝)입니다. 이 정육면체의 겉넓이는 몇 제곱센티미터입니까?",
        "question_en": "The perimeter of one side of the cube is 24 centimeters (cm). What is the surface area of this cube in square centimeters?",
        "answer_ko": "216",
        "answer_en": "216",
        "solution_abst_ko": "24 4 [OP_DIV] 24 4 [OP_DIV] [OP_MUL] 6 [OP_MUL]",
        "solution_abst_en": "24 4 [OP_DIV] 24 4 [OP_DIV] [OP_MUL] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 24\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 24\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = var_c * var_f\nvar_h = 6\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 24\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 24\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = var_c * var_f\nvar_h = 6\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "5322": {
        "category": "Correspondence",
        "question_ko": "빛나초등학교에서 모든 학생들에게 연필을 11자루씩 나눠 주기로했다. 빛나초등학교에서 모두 10395개의 연필을 구매해서 학생들에게 나누어주었다면 빛나초등학교의 학생들은 모두 몇 명인가?",
        "question_en": "Bitna Elementary School decided to hand out 11 pencils to all students. If Bitna Elementary School purchased 10395 pencils and distributed them to students, how many students would there be in Bitna Elementary School?",
        "answer_ko": "945",
        "answer_en": "945",
        "solution_abst_ko": "10395 11 [OP_DIV]",
        "solution_abst_en": "10395 11 [OP_DIV]",
        "solution_code_ko": "var_a = 10395\nvar_b = 11\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 10395\nvar_b = 11\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "5323": {
        "category": "Geometry",
        "question_ko": "가로가 10센티미터(㎝)이고 세로가 8센티미터(㎝)인 직사각형이 있습니다. 이 직사각형과 둘레가 같은 정사각형을 그리려고 합니다. 정사각형의 한 변의 길이는 몇 센티미터(㎝)로 해야 합니까?",
        "question_en": "There is a rectangle with a length of 10 centimeters (cm) and a width of 8 centimeters (cm). We want to draw a square with the same perimeter as this rectangle. How many centimeters (cm) should be the length of one side of the square?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "10 8 [OP_ADD] 2 [OP_MUL] 4 [OP_DIV]",
        "solution_abst_en": "10 8 [OP_ADD] 2 [OP_MUL] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 10\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "5324": {
        "category": "Arithmetic calculation",
        "question_ko": "28의 약수 중 가장 큰 수는 무엇인지 구하세요",
        "question_en": "Find the greatest divisor of 28.",
        "answer_ko": "28",
        "answer_en": "28",
        "solution_abst_ko": "28 [OP_LIST_GET_DIVISOR] 1 [OP_LIST_MAX]",
        "solution_abst_en": "28 [OP_LIST_GET_DIVISOR] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 28\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_c = list_b[-var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 28\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_c = list_b[-var_b]\nprint(int(var_c))"
    },
    "5325": {
        "category": "Possibility",
        "question_ko": "1부터 9까지의 숫자가 있는 9장의 카드 중에서 두 장의 카드의 합이 홀수가 되도록 뽑는 방법의 수를 구하십시오.",
        "question_en": "Find the number of ways to draw an odd number of two cards out of nine cards numbered 1 through 9.",
        "answer_ko": "40",
        "answer_en": "40",
        "solution_abst_ko": "1 9 1 [OP_LIST_ARANGE] 2 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 2 1 [OP_LIST_DIVIDE_AND_REMAIN] [OP_LIST_LEN]",
        "solution_abst_en": "1 9 1 [OP_LIST_ARANGE] 2 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 2 1 [OP_LIST_DIVIDE_AND_REMAIN] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 2\nvar_g = 1\nlist_d = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_c:\n    i = int(i)\n    if i%var_f == var_g:\n        list_d.append(i)\nvar_h = len(list_d)\nprint(int(var_h))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 2\nvar_g = 1\nlist_d = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_c:\n    i = int(i)\n    if i%var_f == var_g:\n        list_d.append(i)\nvar_h = len(list_d)\nprint(int(var_h))"
    },
    "5326": {
        "category": "Arithmetic calculation",
        "question_ko": "수현이의 한 걸음은 0.75미터(m)입니다. 수현이가 집에서 출발해 편의점을 다녀오는 데 70걸음이 걸린다면, 편의점을 13번 다녀왔을 때 수현이가 걸은 거리는 모두 몇 미터(m)인지 구하시오.",
        "question_en": "Suhyeon's one step is 0.75 meters (m). If it takes Suhyeon 70 steps to go to the convenience store from home, find the total distance in meters (m) Suhyeon walked when she went to the convenience store 13 times.",
        "answer_ko": "682.50",
        "answer_en": "682.5",
        "solution_abst_ko": "0.75 70 [OP_MUL] 13 [OP_MUL]",
        "solution_abst_en": "0.75 70 [OP_MUL] 13 [OP_MUL]",
        "solution_code_ko": "var_a = 0.75\nvar_b = 70\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.75\nvar_b = 70\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "5327": {
        "category": "Arithmetic calculation",
        "question_ko": "경훈이가 등산을 하는데 올라갈 때는 시속 3 킬로미터(㎞)로 걷고, 내려올 때는 올라갈 때보다 2 킬로미터(㎞) 더 먼 길을 택하여 시속 4 킬로미터(㎞)로 걸어서 총 4시간이 걸렸다고 한다. 경훈이가 올라간 거리는?",
        "question_en": "Gyeong-hun climbed the mountain, walking at 3 kilometers per hour (km) when going up, and walking at 4 kilometers (km) per hour when going down, taking a 2 kilometers (km) longer route when going down, for a total of 4 hours. How long distance did Gyeong-hun climb?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "4 2 4 [OP_DIV] [OP_SUB] 1 3 [OP_DIV] 1 4 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_abst_en": "4 2 4 [OP_DIV] [OP_SUB] 1 3 [OP_DIV] 1 4 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = 3\nvar_h = var_f / var_g\nvar_i = 1\nvar_j = 4\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_e / var_l\nprint(int(eval('{:.2f}'.format(round(var_m+1e-10,2)))))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = 3\nvar_h = var_f / var_g\nvar_i = 1\nvar_j = 4\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_e / var_l\nprint(int(eval('{:.2f}'.format(round(var_m+1e-10,2)))))"
    },
    "5328": {
        "category": "Arithmetic calculation",
        "question_ko": "근배는 줄넘기를 첫째 날에는 15번을 하고, 둘째 날에는 첫째 날의 2배, 셋째 날에는 둘째 날의 2배를 하기로 했습니다. 근배가 같은 방법으로 줄넘기를 한다면 넷째 날에는 모두 몇 번 해야 하는지 구해보시오.",
        "question_en": "Keun-bae decided to jump rope 15 times on the first day, twice the first day on the second day, and twice the second day on the third day. If Keun-bae jumps rope in the same pattern, how many times will he have to do on the fourth day?",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "15 2 4 1 [OP_SUB] [OP_POW] [OP_MUL]",
        "solution_abst_en": "15 2 4 1 [OP_SUB] [OP_POW] [OP_MUL]",
        "solution_code_ko": "var_a = 15\nvar_b = 2\nvar_c = 4\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = var_b ** var_e\nvar_g = var_a * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 15\nvar_b = 2\nvar_c = 4\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = var_b ** var_e\nvar_g = var_a * var_f\nprint(int(var_g))"
    },
    "5329": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 29를 뺐더니 63이 되었습니다. 어떤 수에서 47을 빼면 얼마가 되는지 구하시오.",
        "question_en": "Subtracting 29 from a number gives you 63. What is the number obtained when 47 is subtracted from the number?",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "63 29 [OP_ADD] 47 [OP_SUB]",
        "solution_abst_en": "63 29 [OP_ADD] 47 [OP_SUB]",
        "solution_code_ko": "var_a = 63\nvar_b = 29\nvar_c = var_a + var_b\nvar_d = 47\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 63\nvar_b = 29\nvar_c = var_a + var_b\nvar_d = 47\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "5330": {
        "category": "Arithmetic calculation",
        "question_ko": "15/14를 어떤 수로 나누었더니 9/14가 되었습니다. 어떤 수를 구하시오.",
        "question_en": "When you divide 15/14 by a particular number, you get 9/14. Find that particular number. ",
        "answer_ko": "1.67",
        "answer_en": "1.67",
        "solution_abst_ko": "15/14 9/14 [OP_DIV]",
        "solution_abst_en": "15/14 9/14 [OP_DIV]",
        "solution_code_ko": "var_a = 1.0714285714285714\nvar_b = 0.6428571428571429\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 1.0714285714285714\nvar_b = 0.6428571428571429\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "5331": {
        "category": "Comparison",
        "question_ko": "성국이네 과수원에서는 귤나무 60 그루에서 귤을 40680 개 땄고, 혁준이네 과수원에서는 귤나무 55 그루 에서 귤을 37510 개 땄습니다. 누구네 과수원이 귤나무 한 그루당 평균적으로 귤을 더 많이 딴 셈입니까?",
        "question_en": "Seongkuk's orchard picked 40680 tangerines from 60 tangerine trees, and Hyukjun's orchard picked 37510 tangerines from 55 tangerine trees. Whose orchard averaged more tangerines per tangerine tree?",
        "answer_ko": "혁준",
        "answer_en": "Hyukjun",
        "solution_abst_ko": "[OP_LIST_SOL] 성국 혁준 [OP_LIST_EOL] [OP_LIST_SOL] 40680 60 [OP_DIV] 37510 55 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Seongkuk Hyukjun [OP_LIST_EOL] [OP_LIST_SOL] 40680 60 [OP_DIV] 37510 55 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '성국'\nvar_b = '혁준'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 40680\nvar_d = 60\nvar_e = var_c / var_d\nvar_f = 37510\nvar_g = 55\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Seongkuk'\nvar_b = 'Hyukjun'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 40680\nvar_d = 60\nvar_e = var_c / var_d\nvar_f = 37510\nvar_g = 55\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "5332": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.9 중에서 0.4보다 작은 수는 몇 개입니까?",
        "question_en": "How many of 0.8, 1/2, and 0.9 are less than 0.4?",
        "answer_ko": "0",
        "answer_en": "0",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 0.4 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 0.4 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.4\nlist_b = []\nfor i in list_a:\n    if i < var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.4\nlist_b = []\nfor i in list_a:\n    if i < var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "5333": {
        "category": "Geometry",
        "question_ko": "10개의 공이 들어 있는 상자 안에서 정국이가 3개의 공을 뺐을 때 남은 공의 개수는?",
        "question_en": "How many balls are left when Jungkook removes 3 balls from a box containing 10 balls?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "10 3 [OP_SUB]",
        "solution_abst_en": "10 3 [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 10\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "5334": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 5로 나누었더니 2가 되었습니다. 어떤 수에서 6을 빼면 얼마입니까?",
        "question_en": "When you divide a number by 5, you get 2. What do you get if you subtract 6 from this number?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "5 2 [OP_MUL] 6 [OP_SUB]",
        "solution_abst_en": "5 2 [OP_MUL] 6 [OP_SUB]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "5335": {
        "category": "Arithmetic calculation",
        "question_ko": "두 자리수의 홀수와 한 자리 수의 짝수는 모두 몇 개인지 구하시오.",
        "question_en": "How many odd two-digit numbers and even single-digit numbers exist?",
        "answer_ko": "49",
        "answer_en": "49",
        "solution_abst_ko": "10 99 [OP_LIST_ODD] 1 9 [OP_LIST_EVEN] [OP_SET_UNION] [OP_LIST_LEN]",
        "solution_abst_en": "10 99 [OP_LIST_ODD] 1 9 [OP_LIST_EVEN] [OP_SET_UNION] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 10\nvar_b = 99\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 1\nvar_d = 9\nlist_b = []\nif var_c%2!=0:\n    for i in range(var_c+1, var_d+1, 2):\n        list_b.append(i)\nelse:\n    for i in range(var_c, var_d+1, 2):\n        list_b.append(i)\nlist_c = list(set(list_a) | set(list_b))\nvar_e = len(list_c)\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 99\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 1\nvar_d = 9\nlist_b = []\nif var_c%2!=0:\n    for i in range(var_c+1, var_d+1, 2):\n        list_b.append(i)\nelse:\n    for i in range(var_c, var_d+1, 2):\n        list_b.append(i)\nlist_c = list(set(list_a) | set(list_b))\nvar_e = len(list_c)\nprint(int(var_e))"
    },
    "5336": {
        "category": "Correspondence",
        "question_ko": "윤기는 세 자리 수에 57을 더하던 중, 윤기는 세 자리 수의 일의 자리 숫자 9를 6으로 잘못 봤습니다. 윤기가 구한 합이 823이라고 하면, 바르게 계산한 결과는 무엇인가요?",
        "question_en": "While Yoongi was adding 57 to the three-digit number, he mistook the three-digit units digit 9 for a 6. If the sum obtained by Yoongi is 823, what is the correct calculation result?",
        "answer_ko": "826",
        "answer_en": "826",
        "solution_abst_ko": "823 57 [OP_SUB] 6 9 [OP_SUB] [OP_SUB] 57 [OP_ADD]",
        "solution_abst_en": "823 57 [OP_SUB] 6 9 [OP_SUB] [OP_SUB] 57 [OP_ADD]",
        "solution_code_ko": "var_a = 823\nvar_b = 57\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nvar_h = 57\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 823\nvar_b = 57\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nvar_h = 57\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "5337": {
        "category": "Comparison",
        "question_ko": "삼각기둥, 사각기둥, 삼각뿔, 사각뿔, 사각뿔대 중 면의 개수가 가장 적은 것은?",
        "question_en": "Which one has the least number of faces among a triangular-prism, quadrangular-prism, triangular-pyramid, quadrangular-pyramid, and truncated-quadrangular-pyramid?",
        "answer_ko": "삼각뿔",
        "answer_en": "triangular-pyramid",
        "solution_abst_ko": "[OP_LIST_SOL] 삼각기둥 사각기둥 삼각뿔 사각뿔 사각뿔대 [OP_LIST_EOL] [OP_LIST_SOL] 3 2 [OP_ADD] 4 2 [OP_ADD] 3 1 [OP_ADD] 4 1 [OP_ADD] 4 2 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] triangular-prism quadrangular-prism triangular-pyramid quadrangular-pyramid truncated-quadrangular-pyramid [OP_LIST_EOL] [OP_LIST_SOL] 3 2 [OP_ADD] 4 2 [OP_ADD] 3 1 [OP_ADD] 4 1 [OP_ADD] 4 2 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '삼각기둥'\nvar_b = '사각기둥'\nvar_c = '삼각뿔'\nvar_d = '사각뿔'\nvar_e = '사각뿔대'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = 4\nvar_j = 2\nvar_k = var_i + var_j\nvar_l = 3\nvar_m = 1\nvar_n = var_l + var_m\nvar_o = 4\nvar_p = 1\nvar_q = var_o + var_p\nvar_r = 4\nvar_s = 2\nvar_t = var_r + var_s\nlist_b= []\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_b.append(var_t)\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nlist_b.reverse()\nvar_u = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_v = list_c[var_u-1]\nvar_w = list_b.index(var_v)+1\nvar_x = list_a[var_w-1]\nprint(var_x)",
        "solution_code_en": "var_a = 'triangular-prism'\nvar_b = 'quadrangular-prism'\nvar_c = 'triangular-pyramid'\nvar_d = 'quadrangular-pyramid'\nvar_e = 'truncated-quadrangular-pyramid'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = 4\nvar_j = 2\nvar_k = var_i + var_j\nvar_l = 3\nvar_m = 1\nvar_n = var_l + var_m\nvar_o = 4\nvar_p = 1\nvar_q = var_o + var_p\nvar_r = 4\nvar_s = 2\nvar_t = var_r + var_s\nlist_b= []\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_b.append(var_t)\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nlist_b.reverse()\nvar_u = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_v = list_c[var_u-1]\nvar_w = list_b.index(var_v)+1\nvar_x = list_a[var_w-1]\nprint(var_x)"
    },
    "5338": {
        "category": "Comparison",
        "question_ko": "민철, 태훈, 채정 세 학생이 일렬로 서있습니다. 태훈이가 민철이보다는 뒤에, 채정이보다는 앞에 서 있을 때, 맨 뒤에 서있는 학생은 누구입니까?",
        "question_en": "Mincheol, Taehoon, and Chaejeong are standing in a row. When Taehoon is behind Mincheol and in front of Chaejeong, who is the student standing at the very back?",
        "answer_ko": "채정",
        "answer_en": "Chaejeong",
        "solution_abst_ko": "[OP_LIST_SOL] 민철 태훈 채정 [OP_LIST_EOL] [OP_LIST_SOL] 태훈 민철 < 태훈 채정 > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Mincheol Taehoon Chaejeong [OP_LIST_EOL] [OP_LIST_SOL] Taehoon Mincheol < Taehoon Chaejeong > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '민철'\nvar_b = '태훈'\nvar_c = '채정'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '태훈'\nvar_e = '민철'\nvar_f = '<'\nvar_g = '태훈'\nvar_h = '채정'\nvar_i = '>'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = len(list_c)\nvar_k = list_c[var_j-1]\nprint(var_k)",
        "solution_code_en": "var_a = 'Mincheol'\nvar_b = 'Taehoon'\nvar_c = 'Chaejeong'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'Taehoon'\nvar_e = 'Mincheol'\nvar_f = '<'\nvar_g = 'Taehoon'\nvar_h = 'Chaejeong'\nvar_i = '>'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = len(list_c)\nvar_k = list_c[var_j-1]\nprint(var_k)"
    },
    "5339": {
        "category": "Arithmetic calculation",
        "question_ko": "은지는 윤기보다 수학점수가 25점 낮고 유나는 은지보다 수학점수가 20점 낮습니다. 유나의 수학점수가 8점일 때 윤기의 수학점수는 몇 점입니까?",
        "question_en": "Eunji's math score is 25 points lower than Yoongi's, and Yuna's math score is 20 points lower than Eunji's. If Yuna's math score is 8, what score did Yoongi get?",
        "answer_ko": "53",
        "answer_en": "53",
        "solution_abst_ko": "8 20 [OP_ADD] 25 [OP_ADD]",
        "solution_abst_en": "8 20 [OP_ADD] 25 [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 20\nvar_c = var_a + var_b\nvar_d = 25\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 20\nvar_c = var_a + var_b\nvar_d = 25\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "5340": {
        "category": "Comparison",
        "question_ko": "수 5개 1.4, 9/10, 1.2, 0.5, 13/10 중 1.1보다 작은 숫자를 구하고, 그 숫자들의 합을 구하면 얼마입니까?",
        "question_en": "What is the sum of the numbers among 1.4, 9/10, 1.2, 0.5, and 13/10 that is less than 1.1?",
        "answer_ko": "1.40",
        "answer_en": "1.4",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i < var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i < var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "5341": {
        "category": "Arithmetic calculation",
        "question_ko": "8명이서 5개의 자전거를 돌아가면서 타기로 했다. 자전거를 탄 시간이 2시간 32분이라면 한 사람이 자전거를 탄 시간은 평균 몇 분입니까?",
        "question_en": "8 people decided to take turns riding 5 bikes. If the riding time is 2 hours 32 minutes, how long does one person ride the bike on average in minutes?",
        "answer_ko": "95",
        "answer_en": "95",
        "solution_abst_ko": "2 60 [OP_MUL] 32 [OP_ADD] 8 [OP_DIV] 5 [OP_MUL]",
        "solution_abst_en": "2 60 [OP_MUL] 32 [OP_ADD] 8 [OP_DIV] 5 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 32\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e / var_f\nvar_h = 5\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 2\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 32\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e / var_f\nvar_h = 5\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "5342": {
        "category": "Possibility",
        "question_ko": "2, 4, 7, 9를 한 번씩 사용하여 두자리 수를 만들려고 한다. 십의 자리 숫자가 7인 수들 중 세번째로 작은 두 자리 수는 무엇입니까?",
        "question_en": "We are trying to make a two-digit number by using 2, 4, 7, and 9 once each. What is the third smallest two-digit number with 7 in the tens place?",
        "answer_ko": "79",
        "answer_en": "79",
        "solution_abst_ko": "[OP_LIST_SOL] 2 4 7 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 10 7 [OP_LIST_SEARCH_FIXED_DIGIT] 3 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 2 4 7 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 10 7 [OP_LIST_SEARCH_FIXED_DIGIT] 3 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = 7\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 7\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 3\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nprint(int(var_i))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = 7\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 7\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 3\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nprint(int(var_i))"
    },
    "5343": {
        "category": "Geometry",
        "question_ko": "가로가 30센티미터(㎝), 세로가 24센티미터(㎝)인 직사각형 모양의 종이에 반지름이 3센티미터(㎝)인 원을 겹치지 않게 최대한 많이 그리려고 합니다. 원을 몇 개까지 그릴 수 있습니까?",
        "question_en": "You are trying to draw as many circles with a radius of 3 cm on a piece of paper that is 30 centimeters (cm) wide and 24 centimeters (cm) long, without overlapping them. How many circles can you draw?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "30 3 2 [OP_MUL] [OP_DIV] 24 3 2 [OP_MUL] [OP_DIV] [OP_MUL]",
        "solution_abst_en": "30 3 2 [OP_MUL] [OP_DIV] 24 3 2 [OP_MUL] [OP_DIV] [OP_MUL]",
        "solution_code_ko": "var_a = 30\nvar_b = 3\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nvar_f = 24\nvar_g = 3\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = var_f / var_i\nvar_k = var_e * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 30\nvar_b = 3\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nvar_f = 24\nvar_g = 3\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = var_f / var_i\nvar_k = var_e * var_j\nprint(int(var_k))"
    },
    "5344": {
        "category": "Arithmetic calculation",
        "question_ko": "물 탱크에 120리터(L) 만큼의 물이 있다. 이 물탱크에 수도꼭지를 열면 분 당 4리터(L)의 물이 흘러나온다. 수도꼭지를 열고 20 분이 지났을 때, 물탱크 안에 몇 리터(L)의 물이 남아있습니까?",
        "question_en": "There are 120 liters (L) of water in the water tank. When you open the faucet in this water tank, 4 liters (L) of water flow out per minute. How many liters (L) of water are left in the water tank after 20 minutes you open the faucet?",
        "answer_ko": "40",
        "answer_en": "40",
        "solution_abst_ko": "120 4 20 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "120 4 20 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 120\nvar_b = 4\nvar_c = 20\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 120\nvar_b = 4\nvar_c = 20\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "5345": {
        "category": "Possibility",
        "question_ko": "550보다 큰 수를 만드려고 한다. 4, 5, 8로 이루어져 있고 각 자리의 숫자가 모두 다른 수들은 몇 개인가?",
        "question_en": "I am trying to make a number that is bigger than 550. Think of ways in which a number is made up of 4, 5, and 8, and the figure in each digit is different from each other. How many numbers are there?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 4 5 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 550 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 4 5 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 550 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 4\nvar_b = 5\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 550\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 4\nvar_b = 5\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 550\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "5346": {
        "category": "Geometry",
        "question_ko": "평형사변형의 밑변의 길이는 3.8미터(m)이며 높이는 6.36미터(m)일 때, 넓이는 얼마가 됩니까?",
        "question_en": "If the base of a parallelogram is 3.8 meters (m) and the height is 6.36 meters (m), what is the area?",
        "answer_ko": "24.17",
        "answer_en": "24.17",
        "solution_abst_ko": "3.8 6.36 [OP_MUL]",
        "solution_abst_en": "3.8 6.36 [OP_MUL]",
        "solution_code_ko": "var_a = 3.8\nvar_b = 6.36\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 3.8\nvar_b = 6.36\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "5347": {
        "category": "Arithmetic calculation",
        "question_ko": "오이가 18개 있고, 오이는 수박보다 8개 더 적습니다. 수박과 오이는 모두 몇 개입니까?",
        "question_en": "There are a total of 18 cucumbers, and the number of watermelons is 8 more than that of cucumbers. What is the total number of watermelons and cucumbers?",
        "answer_ko": "44",
        "answer_en": "44",
        "solution_abst_ko": "18 18 8 [OP_ADD] [OP_ADD]",
        "solution_abst_en": "18 18 8 [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 18\nvar_b = 18\nvar_c = 8\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 18\nvar_b = 18\nvar_c = 8\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "5348": {
        "category": "Possibility",
        "question_ko": "보라색 사탕 2개, 흰색 사탕 1개, 빨간색 사탕 1개를 가지고 있습니다. 같은 색의 사탕은 각각 구별이 되지 않는다고 할 때, 사탕 4개를 서로 다르게 한 줄로 놓는 방법은 모두 몇 가지입니까?",
        "question_en": "You have 2 purple candies, 1 white candy, and 1 red candy. If candies of the same color are indistinguishable from each other, how many different ways can you place 4 different candies in a row?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "2 1 [OP_ADD] 1 [OP_ADD] 2 1 [OP_ADD] 1 [OP_ADD] [OP_PERM] 2 [OP_DIV]",
        "solution_abst_en": "2 1 [OP_ADD] 1 [OP_ADD] 2 1 [OP_ADD] 1 [OP_ADD] [OP_PERM] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 2\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h + var_i\nvar_k = 1\nvar_e = int(var_e)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_e-i)\nvar_l = 2\nvar_m = var_k / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 2\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h + var_i\nvar_k = 1\nvar_e = int(var_e)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_e-i)\nvar_l = 2\nvar_m = var_k / var_l\nprint(int(var_m))"
    },
    "5349": {
        "category": "Arithmetic calculation",
        "question_ko": "제2 외국어에는 일본어, 중국어, 프랑스어를 선택할 수 있다. 일본어 선택자 수는 중국어 선택자 수의 3배이고 중국어 선택자 수는 프랑스어 선택자 수보다 15명이 더 많다. 모든 학생이 165명 일 때, 일본어 선택자 수를 구하시오.",
        "question_en": "As a second foreign language, Japanese, Chinese, and French can be selected. The number of Japanese selectors is three times the number of Chinese selectors, and the number of Chinese selectors is 15 more than the number of French selectors. When the number of all students is 165, find the number of Japanese selectors.",
        "answer_ko": "108",
        "answer_en": "108",
        "solution_abst_ko": "165 15 [OP_ADD] 3 1 1 [OP_ADD] [OP_ADD] [OP_DIV] 3 [OP_MUL]",
        "solution_abst_en": "165 15 [OP_ADD] 3 1 1 [OP_ADD] [OP_ADD] [OP_DIV] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 165\nvar_b = 15\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 1\nvar_f = 1\nvar_g = var_e + var_f\nvar_h = var_d + var_g\nvar_i = var_c / var_h\nvar_j = 3\nvar_k = var_i * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 165\nvar_b = 15\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 1\nvar_f = 1\nvar_g = var_e + var_f\nvar_h = var_d + var_g\nvar_i = var_c / var_h\nvar_j = 3\nvar_k = var_i * var_j\nprint(int(var_k))"
    },
    "5350": {
        "category": "Comparison",
        "question_ko": "5개의 숫자 1, 4, 25, 16, 22가 있습니다. 2번째로 큰 숫자는 무엇입니까?",
        "question_en": "There are 5 numbers 1, 4, 25, 16 and 22. What is the 2nd largest number?",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "[OP_LIST_SOL] 1 4 25 16 22 [OP_LIST_EOL] 2 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1 4 25 16 22 [OP_LIST_EOL] 2 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1\nvar_b = 4\nvar_c = 25\nvar_d = 16\nvar_e = 22\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 4\nvar_c = 25\nvar_d = 16\nvar_e = 22\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nprint(int(var_g))"
    },
    "5351": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 23을 빼야 하는데 잘못하여 32를 뺐더니 25가 되었습니다. 바르게 계산한 결과를 구하시오.",
        "question_en": "I need to subtract 23 from a certain number, but I mistakenly took 32 away, so I got 25. Find the correctly calculated value.",
        "answer_ko": "34",
        "answer_en": "34",
        "solution_abst_ko": "25 32 [OP_ADD] 23 [OP_SUB]",
        "solution_abst_en": "25 32 [OP_ADD] 23 [OP_SUB]",
        "solution_code_ko": "var_a = 25\nvar_b = 32\nvar_c = var_a + var_b\nvar_d = 23\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 25\nvar_b = 32\nvar_c = var_a + var_b\nvar_d = 23\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "5352": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 18센티미터(㎝) 이고, 다른 한 변의 길이가 12센티미터(㎝) 인 평행사변형의 둘레는 몇 센티미터(㎝) 인지 구하시오.",
        "question_en": "Find the perimeter in centimeters (cm) of a parallelogram with one side measuring 18 centimeters (cm) and the other side measuring 12 centimeters (cm).",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "18 12 [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "18 12 [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 18\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 18\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "5353": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 2미터(m) 80센티미터(㎝)인 철사가 있습니다. 이 철사를 40센티미터(㎝) 길이로 모두 자른다면, 모두 몇 번 잘라야 합니까?",
        "question_en": "You have a piece of wire that is 2 meters (m) 80 centimeters (cm) long. If you cut all the 40 centimeters (cm) lengths of this wire, how many cuts will you have to make?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "2 100 [OP_MUL] 80 [OP_ADD] 40 [OP_DIV] 1 [OP_SUB]",
        "solution_abst_en": "2 100 [OP_MUL] 80 [OP_ADD] 40 [OP_DIV] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 2\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 80\nvar_e = var_c + var_d\nvar_f = 40\nvar_g = var_e / var_f\nvar_h = 1\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 2\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 80\nvar_e = var_c + var_d\nvar_f = 40\nvar_g = var_e / var_f\nvar_h = 1\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "5354": {
        "category": "Arithmetic calculation",
        "question_ko": "민하의 머리카락은 하루에 0.39밀리미터(㎜)씩 자랍니다. 민하의 머리카락이 오늘 32.8센티미터(㎝)였다면 30일 후에는 몇 센티미터(㎝)가 되어있을지 구하시오.",
        "question_en": "Minha's hair grows at a rate of 0.39 millimeters (mm) per day. If Minha's hair was 32.8 centimeters (cm) today, find how many centimeters (cm) it will be in 30 days.",
        "answer_ko": "33.97",
        "answer_en": "33.97",
        "solution_abst_ko": "0.39 10 [OP_DIV] 30 [OP_MUL] 32.8 [OP_ADD]",
        "solution_abst_en": "0.39 10 [OP_DIV] 30 [OP_MUL] 32.8 [OP_ADD]",
        "solution_code_ko": "var_a = 0.39\nvar_b = 10\nvar_c = var_a / var_b\nvar_d = 30\nvar_e = var_c * var_d\nvar_f = 32.8\nvar_g = var_e + var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 0.39\nvar_b = 10\nvar_c = var_a / var_b\nvar_d = 30\nvar_e = var_c * var_d\nvar_f = 32.8\nvar_g = var_e + var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "5355": {
        "category": "Geometry",
        "question_ko": "정육면체의 모양의 선물 상자의 면의 개수는?",
        "question_en": "How many faces does a cube-shaped gift box have?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "6",
        "solution_abst_en": "6",
        "solution_code_ko": "var_a = 6\nprint(int(var_a))",
        "solution_code_en": "var_a = 6\nprint(int(var_a))"
    },
    "5356": {
        "category": "Arithmetic calculation",
        "question_ko": "엄마에게 돈을 맡기면 매일 300원씩 주고, 아빠에게 돈을 맡기면 매일 500원씩 준다. 규원이는 엄마에게 8000원을 , 석기는 아빠에게 5000원을 맡겼다. 각자가 돈을 다시 돌려받을 때 규원이와 석기의 돈이 같으려면 며칠을 맡겨야 하는가?",
        "question_en": "If you leave money with your mother, you get 300 won every day, and if you leave money with your father, you get 500 won every day. Kyu-won gave 8,000 won to her mother, and Seok-gi left 5,000 won to her father. If you want Kyu-won and Seok-gi to have the same amount of money when they each get their money back, how many days are needned?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "8000 5000 [OP_SUB] 500 300 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "8000 5000 [OP_SUB] 500 300 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 8000\nvar_b = 5000\nvar_c = var_a - var_b\nvar_d = 500\nvar_e = 300\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 8000\nvar_b = 5000\nvar_c = var_a - var_b\nvar_d = 500\nvar_e = 300\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))"
    },
    "5357": {
        "category": "Arithmetic calculation",
        "question_ko": "노란색 물고기가 445마리 있고, 파란색 물고기는 노란색 물고기보다 38마리 더 많습니다. 노란색 물고기와 파란색 물고기는 모두 몇 마리입니까?",
        "question_en": "There are 445 yellow fish and 38 more blue fish than yellow fish. How many yellow and blue fish are there?",
        "answer_ko": "928",
        "answer_en": "928",
        "solution_abst_ko": "445 445 38 [OP_ADD] [OP_ADD]",
        "solution_abst_en": "445 445 38 [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 445\nvar_b = 445\nvar_c = 38\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 445\nvar_b = 445\nvar_c = 38\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "5358": {
        "category": "Arithmetic calculation",
        "question_ko": "식용유 3리터(L)를 갑, 을, 병 세 사람에게 나누어 주려고 합니다. 갑은 을보다 200밀리리터(㎖) 많게, 을은 병보다 200밀리리터(㎖) 많게 나누어 준다면, 을에게 몇 밀리리터(㎖)의 식용유를 나누어 주어야 합니까?",
        "question_en": "You would like to distribute 3 liters (L) of cooking oil to three people: A, B, and C. If you gives A 200 milliliters (㎖) more than B, and B 200 milliliters (㎖) more than C, how many milliliters (㎖) of cooking oil should be given to B?",
        "answer_ko": "1000",
        "answer_en": "1000",
        "solution_abst_ko": "3 1000 [OP_MUL] 200 [OP_ADD] 200 [OP_SUB] 3 [OP_DIV]",
        "solution_abst_en": "3 1000 [OP_MUL] 200 [OP_ADD] 200 [OP_SUB] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 3\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 200\nvar_e = var_c + var_d\nvar_f = 200\nvar_g = var_e - var_f\nvar_h = 3\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 3\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 200\nvar_e = var_c + var_d\nvar_f = 200\nvar_g = var_e - var_f\nvar_h = 3\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "5359": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 200까지의 짝수의 합을 구하시오.",
        "question_en": "Find the sum of even numbers from 1 to 200.",
        "answer_ko": "10100",
        "answer_en": "10100",
        "solution_abst_ko": "1 200 [OP_LIST_EVEN] [OP_LIST_SUM]",
        "solution_abst_en": "1 200 [OP_LIST_EVEN] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 200\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nprint(int(var_c))",
        "solution_code_en": "var_a = 1\nvar_b = 200\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nprint(int(var_c))"
    },
    "5360": {
        "category": "Geometry",
        "question_ko": "넓이가 64/5제곱센티미터(㎠)인 마름모가 있습니다. 한 대각선이 64/9센티미터(㎝)일 때, 다른 대각선은 몇 센티미터(㎝)입니까?",
        "question_en": "There is a rhombus with an area of 64/5 square centimeters (cm2). If one diagonal is 64/9 centimeters (cm), how long is the other diagonal in cm (cm)?",
        "answer_ko": "3.60",
        "answer_en": "3.6",
        "solution_abst_ko": "64/5 2 [OP_MUL] 64/9 [OP_DIV]",
        "solution_abst_en": "64/5 2 [OP_MUL] 64/9 [OP_DIV]",
        "solution_code_ko": "var_a = 12.8\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 7.111111111111111\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 12.8\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 7.111111111111111\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "5361": {
        "category": "Possibility",
        "question_ko": "정이십면체의 면에서 변은 몇 개 일까요?",
        "question_en": "How many edges are there on a face of an icosahedron?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "3",
        "solution_abst_en": "3",
        "solution_code_ko": "var_a = 3\nprint(int(var_a))",
        "solution_code_en": "var_a = 3\nprint(int(var_a))"
    },
    "5362": {
        "category": "Geometry",
        "question_ko": "마름모의 각 대각선의 길이가 14센티미터(㎝), 24센티미터(㎝)라면, 마름모의 넓이는 얼마인가?",
        "question_en": "If the lengths of each diagonal of a rhombus are 14 centimeters (cm) and 24 centimeters (cm), what is the area of the rhombus?",
        "answer_ko": "168",
        "answer_en": "168",
        "solution_abst_ko": "14 24 [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "14 24 [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 14\nvar_b = 24\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 14\nvar_b = 24\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "5363": {
        "category": "Arithmetic calculation",
        "question_ko": "백의 자리 숫자가 4, 십의 자리 숫자가 8인 세 자리 수가 있다. 일의 자리 숫자를 A라고 하고, A에는 0에서 9까지의 숫자를 사용할 수 있다. 이 때 만들 수 있는 가장 큰 수와 작은 수의 합은 얼마인가?",
        "question_en": "There is a three-digit number with 4 in the hundreds digit and 8 in the tens digit. The ones digit is called A, and any number from 0 to 9 can be used for A. What is the sum of the largest and smallest possible numbers?",
        "answer_ko": "969",
        "answer_en": "969",
        "solution_abst_ko": "[OP_LIST_SOL] 4 8 A [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 4 8 A [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 8\nvar_c = 'A'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nans_dict = dict()\nvar_d = str(var_d)\nlist_b = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_d) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_b.append(new_elem)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 4\nvar_b = 8\nvar_c = 'A'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nans_dict = dict()\nvar_d = str(var_d)\nlist_b = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_d) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_b.append(new_elem)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))"
    },
    "5364": {
        "category": "Arithmetic calculation",
        "question_ko": "10조각으로 나뉘어져 있는 피자를 민영이와 유정이가 나누어 먹으려고 합니다. 민영이가 유정이보다 2개 더 많이 먹는다면 유정이는 피자를 몇 조각 먹게 됩니까?",
        "question_en": "If there is a pizza divided into 10 pieces, Minyoung and Yoojung plan to share it. If Minyoung eats 2 more pizzas than Yoojung, find how many slices of pizza Yoojung takes.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "10 2 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "10 2 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "5365": {
        "category": "Geometry",
        "question_ko": "정팔면체의 면의 개수를 구하시오.",
        "question_en": "Find the number of faces of the regular octahedron.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "8",
        "solution_abst_en": "8",
        "solution_code_ko": "var_a = 8\nprint(int(var_a))",
        "solution_code_en": "var_a = 8\nprint(int(var_a))"
    },
    "5366": {
        "category": "Arithmetic calculation",
        "question_ko": "민형이의 아버지는 한 시간에 3.8킬로미터(㎞) 를 걷습니다. 민형이의 아버지께서 일정한 빠르기로 2 시간 45 분 동안 걸은 거리는 몇 킬로미터(㎞)입니까?",
        "question_en": "Minhyung's father walks 3.8 kilometers (km) an hour. How many kilometers (km) did Minhyeong's father walk for 2 hours and 45 minutes at a constant pace?",
        "answer_ko": "10.45",
        "answer_en": "10.45",
        "solution_abst_ko": "3.8 2 45 60 [OP_DIV] [OP_ADD] [OP_MUL]",
        "solution_abst_en": "3.8 2 45 60 [OP_DIV] [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 3.8\nvar_b = 2\nvar_c = 45\nvar_d = 60\nvar_e = var_c / var_d\nvar_f = var_b + var_e\nvar_g = var_a * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 3.8\nvar_b = 2\nvar_c = 45\nvar_d = 60\nvar_e = var_c / var_d\nvar_f = var_b + var_e\nvar_g = var_a * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "5367": {
        "category": "Correspondence",
        "question_ko": "A는 0이 아니고, A와 B는 한 자리 수입니다. AB40C가 45의 배수라고 할 때, 가능한 모든 숫자의 개수를 구하시오.",
        "question_en": "A is not a zero, and A and B are single digits. Given that AB40C is a multiple of 45, find the number of all possible numbers.",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "AB40C [OP_GEN_POSSIBLE_LIST] 45 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "AB40C [OP_GEN_POSSIBLE_LIST] 45 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 'AB40C'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 45\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))",
        "solution_code_en": "var_a = 'AB40C'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 45\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))"
    },
    "5368": {
        "category": "Geometry",
        "question_ko": "빨간 공 3개, 파란 공 2개, 노란 공 5개가 담겨져 있는 상자가 6개 있습니다. 노란 공의 전체 개수는 몇 개 입니까?",
        "question_en": "There are 6 boxes containing 3 red balls, 2 blue balls and 5 yellow balls. What is the total number of yellow balls?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "5 6 [OP_MUL]",
        "solution_abst_en": "5 6 [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 6\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 6\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "5369": {
        "category": "Correspondence",
        "question_ko": "여섯 자리 수 A15B94가 99의 배수일 때, A를 구하시오",
        "question_en": "If the six-digit number A15B94 is a multiple of 99, find A.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "A15B94 [OP_GEN_POSSIBLE_LIST] 99 [OP_LIST_DIVISIBLE] A15B94 A [OP_LIST_FIND_UNK]",
        "solution_abst_en": "A15B94 [OP_GEN_POSSIBLE_LIST] 99 [OP_LIST_DIVISIBLE] A15B94 A [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = 'A15B94'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 99\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 'A15B94'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nvar_e = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_e = int(elem[unk_idx])\nprint(int(var_e))",
        "solution_code_en": "var_a = 'A15B94'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 99\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 'A15B94'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nvar_e = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_e = int(elem[unk_idx])\nprint(int(var_e))"
    },
    "5370": {
        "category": "Arithmetic calculation",
        "question_ko": "철사 4미터(m)로 모빌을 1개 만들 수 있습니다. 철사 105.8미터(m)로 같은 크기의 모빌을 몇 개 만들 수 있는지 구하시오.",
        "question_en": "One mobile is made with 4 meters (m) of wire. How many mobiles of the same size can be made with 105.8 meters (m) of wire?",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "105.8 4 [OP_FDIV]",
        "solution_abst_en": "105.8 4 [OP_FDIV]",
        "solution_code_ko": "var_a = 105.8\nvar_b = 4\nvar_c = var_a // var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 105.8\nvar_b = 4\nvar_c = var_a // var_b\nprint(int(var_c))"
    },
    "5371": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 17을 더한 수를 5로 나누었더니 25가 되었습니다. 어떤 수를 6으로 나눈 값을 구하시오.",
        "question_en": "When you add 17 to a number and divide it by 5, you get 25. Find the value of the number divided by 6.",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "25 5 [OP_MUL] 17 [OP_SUB] 6 [OP_DIV]",
        "solution_abst_en": "25 5 [OP_MUL] 17 [OP_SUB] 6 [OP_DIV]",
        "solution_code_ko": "var_a = 25\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 17\nvar_e = var_c - var_d\nvar_f = 6\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 25\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 17\nvar_e = var_c - var_d\nvar_f = 6\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "5372": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 3을 곱하여 45를 뺀 수가 159입니다. 어떤 수에 32를 더하고 12를 곱한 값을 구하시오.",
        "question_en": "159 is a number you can get when you subtract 45 from a number multiplied by 3. Find the value of adding 32 to this number and multiplying it by 12. ",
        "answer_ko": "1200",
        "answer_en": "1200",
        "solution_abst_ko": "159 45 [OP_ADD] 3 [OP_DIV] 32 [OP_ADD] 12 [OP_MUL]",
        "solution_abst_en": "159 45 [OP_ADD] 3 [OP_DIV] 32 [OP_ADD] 12 [OP_MUL]",
        "solution_code_ko": "var_a = 159\nvar_b = 45\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = 32\nvar_g = var_e + var_f\nvar_h = 12\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 159\nvar_b = 45\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = 32\nvar_g = var_e + var_f\nvar_h = 12\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "5373": {
        "category": "Geometry",
        "question_ko": "길이가 60센티미터(㎝)인 철사를 사용하여 한 변이 9센티미터(㎝)인 정사각형을 만들었습니다. 남은 철사의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "60 centimeters (cm) long wire was used to make a square with a side of 9 centimeters (cm). How many centimeters (cm) is the length of the remaining wire?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "60 9 4 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "60 9 4 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 60\nvar_b = 9\nvar_c = 4\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 60\nvar_b = 9\nvar_c = 4\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "5374": {
        "category": "Possibility",
        "question_ko": "정국, 지민, 호석 3명의 학생들에게 농구공 12개를 나누어 주려고 한다. 각 학생들은 모두 1개 이상의 공을 받는다면 공을 나누어 줄 수 있는 방법은 총 몇 가지인가?",
        "question_en": "I am going to distribute 12 basketballs to 3 students, Jungkook, Jimin, and Hoseok. If each student receives at least one ball, how many different ways can the balls be distributed?",
        "answer_ko": "55",
        "answer_en": "55",
        "solution_abst_ko": "3 12 [OP_ADD] 3 1 [OP_MUL] [OP_SUB] 1 [OP_SUB] 12 3 1 [OP_MUL] [OP_SUB] [OP_COMB]",
        "solution_abst_en": "3 12 [OP_ADD] 3 1 [OP_MUL] [OP_SUB] 1 [OP_SUB] 12 3 1 [OP_MUL] [OP_SUB] [OP_COMB]",
        "solution_code_ko": "var_a = 3\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 1\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = 12\nvar_k = 3\nvar_l = 1\nvar_m = var_k * var_l\nvar_n = var_j - var_m\nvar_o = 1\nvar_i = int(var_i)\nvar_n = int(var_n)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o * (var_i-i)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o / (i+1)\nprint(int(var_o))",
        "solution_code_en": "var_a = 3\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 1\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = 12\nvar_k = 3\nvar_l = 1\nvar_m = var_k * var_l\nvar_n = var_j - var_m\nvar_o = 1\nvar_i = int(var_i)\nvar_n = int(var_n)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o * (var_i-i)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o / (i+1)\nprint(int(var_o))"
    },
    "5375": {
        "category": "Arithmetic calculation",
        "question_ko": "버스 안에 사람이 35명 있었습니다. 이번 정류장에서 18명이 내리고 15명이 탔습니다. 지금 버스 안에 있는 사람은 처음보다 몇 명 줄었습니까?",
        "question_en": "There were 35 people on the bus. At this stop, 18 people got off and 15 got on. How many fewer people are on the bus now than at the beginning?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "35 35 18 [OP_SUB] 15 [OP_ADD] [OP_SUB]",
        "solution_abst_en": "35 35 18 [OP_SUB] 15 [OP_ADD] [OP_SUB]",
        "solution_code_ko": "var_a = 35\nvar_b = 35\nvar_c = 18\nvar_d = var_b - var_c\nvar_e = 15\nvar_f = var_d + var_e\nvar_g = var_a - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 35\nvar_b = 35\nvar_c = 18\nvar_d = var_b - var_c\nvar_e = 15\nvar_f = var_d + var_e\nvar_g = var_a - var_f\nprint(int(var_g))"
    },
    "5376": {
        "category": "Geometry",
        "question_ko": "반지름이 3센티미터(㎝)인 원 모양의 쿠키가 있습니다. 이 쿠키를 가로 30센티미터(㎝), 세로 24센티미터(㎝) 크기를 갖는 직사각형 모양의 종이 위에 올려두려고 합니다. 쿠키를 겹치지 않게 최대한 많이 올려두려고 한다면, 몇 개까지 올려둘 수 있습니까?",
        "question_en": "You have a cookie in the shape of a circle with a radius of 3 centimeters (cm). You are going to place this cookie on a rectangular piece of paper measuring 30 centimeters (cm) wide by 24 centimeters (cm) long. If you want to stack as many cookies as possible without overlapping, how many can you stack?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "30 3 2 [OP_MUL] [OP_DIV] 24 3 2 [OP_MUL] [OP_DIV] [OP_MUL]",
        "solution_abst_en": "30 3 2 [OP_MUL] [OP_DIV] 24 3 2 [OP_MUL] [OP_DIV] [OP_MUL]",
        "solution_code_ko": "var_a = 30\nvar_b = 3\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nvar_f = 24\nvar_g = 3\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = var_f / var_i\nvar_k = var_e * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 30\nvar_b = 3\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nvar_f = 24\nvar_g = 3\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = var_f / var_i\nvar_k = var_e * var_j\nprint(int(var_k))"
    },
    "5377": {
        "category": "Geometry",
        "question_ko": "하늘이네 초등학교의 이름표는 한 변의 길이가 11센티미터(㎝)인 정사각형 모양이라고 합니다. 이름표 하나의 넓이는 얼마입니까?",
        "question_en": "The name tag of Hanuel's elementary school is in a square with one side measuring 11 centimeters (cm). What is the area of one name tag?",
        "answer_ko": "121",
        "answer_en": "121",
        "solution_abst_ko": "11 2 [OP_POW]",
        "solution_abst_en": "11 2 [OP_POW]",
        "solution_code_ko": "var_a = 11\nvar_b = 2\nvar_c = var_a ** var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 11\nvar_b = 2\nvar_c = var_a ** var_b\nprint(int(var_c))"
    },
    "5378": {
        "category": "Correspondence",
        "question_ko": "A45+27B=418일 때, B에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "If A45+27B=418 is true, what number should go in B?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "A45+27B=418 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A45+27B=418 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A45+27B=418'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A45+27B=418'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "5379": {
        "category": "Comparison",
        "question_ko": "수 5개 1.4, 9/10, 1.2, 0.5, 13/10 중 1.1보다 크거나 같은 숫자를 구하고, 그 숫자들의 개수를 구하세요.",
        "question_en": "Find the number greater than or equal to 1.1 among the five numbers 1.4, 9/10, 1.2, 0.5, 13/10, and find the number of those numbers.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i >= var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i >= var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "5380": {
        "category": "Geometry",
        "question_ko": "우물 바닥의 달팽이가 낮에 25센티미터(㎝)만큼 기어올라오고 밤에 3센티미터(㎝)만큼 미끄러진다고 한다. 64일째 낮에 달팽이가 25센티미터(cm)를 기어 우물 밖으로 나왔을 때, 우물의 깊이를 구하시오.",
        "question_en": "It is said that the snail at the bottom of the well climbs 25 centimeters (cm) during the day and slides 3 centimeters (cm) at night. On day 64, find the depth of the well when the snail crawled 25 centimeters (cm) out of the well during the day.",
        "answer_ko": "1411",
        "answer_en": "1411",
        "solution_abst_ko": "25 64 [OP_MUL] 3 64 1 [OP_SUB] [OP_MUL] [OP_SUB]",
        "solution_abst_en": "25 64 [OP_MUL] 3 64 1 [OP_SUB] [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 25\nvar_b = 64\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = 64\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_c - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 25\nvar_b = 64\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = 64\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_c - var_h\nprint(int(var_i))"
    },
    "5381": {
        "category": "Arithmetic calculation",
        "question_ko": "서랍 안에 있는 구슬 6개와 책상 위에 있는 구슬 몇 개를 전부 더했더니 구슬이 모두 8개였습니다. 책상 위에 있는 구슬은 몇 개입니까?",
        "question_en": "If you add 6 marbles in the drawer and the marbles on the desk, you have 8 marbles in all. How many marbles are on the desk?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "8 6 [OP_SUB]",
        "solution_abst_en": "8 6 [OP_SUB]",
        "solution_code_ko": "var_a = 8\nvar_b = 6\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 8\nvar_b = 6\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "5382": {
        "category": "Arithmetic calculation",
        "question_ko": "3과 4로 나누어떨어지고 5로 나누면 나머지가 4인 세 자리 수를 찾으려고 합니다. 만들 수 있는 세 자리 수는 모두 몇 개입니까?",
        "question_en": "You are trying to find a three-digit number that is divisible by 3 and 4 and dividing by 5 gives a remainder of 4. How many three-digit numbers can you make?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "100 999 1 [OP_LIST_ARANGE] 3 4 [OP_LCM] [OP_LIST_DIVISIBLE] 5 4 [OP_LIST_DIVIDE_AND_REMAIN] [OP_LIST_LEN]",
        "solution_abst_en": "100 999 1 [OP_LIST_ARANGE] 3 4 [OP_LCM] [OP_LIST_DIVISIBLE] 5 4 [OP_LIST_DIVIDE_AND_REMAIN] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nvar_e = 4\nvar_f = var_e * var_d / math.gcd(int(var_e), int(var_d))\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nvar_g = 5\nvar_h = 4\nlist_c = [] \nvar_g = int(var_g)\nvar_h = int(var_h)\nif var_h < 0:\n    var_h = var_h + var_g\nfor i in list_b:\n    i = int(i)\n    if i%var_g == var_h:\n        list_c.append(i)\nvar_i = len(list_c)\nprint(int(var_i))",
        "solution_code_en": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nvar_e = 4\nvar_f = var_e * var_d / math.gcd(int(var_e), int(var_d))\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nvar_g = 5\nvar_h = 4\nlist_c = [] \nvar_g = int(var_g)\nvar_h = int(var_h)\nif var_h < 0:\n    var_h = var_h + var_g\nfor i in list_b:\n    i = int(i)\n    if i%var_g == var_h:\n        list_c.append(i)\nvar_i = len(list_c)\nprint(int(var_i))"
    },
    "5383": {
        "category": "Geometry",
        "question_ko": "키가 작은 사람부터 순서대로 9명이 한 줄로 서 있습니다. 호석이는 4번째로 키가 작습니다. 키가 큰 사람부터 순서대로 다시 줄을 서면 호석이는 뒤에서부터 몇 번째에 서게 됩니까?",
        "question_en": "Nine people are standing in a line, in order from shortest to tallest. Hoseok is the fourth shortest person. If they were to line up again in order from tallest to shortest, where would Hoseok be standing from the back?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "4",
        "solution_abst_en": "4",
        "solution_code_ko": "var_a = 4\nprint(int(var_a))",
        "solution_code_en": "var_a = 4\nprint(int(var_a))"
    },
    "5384": {
        "category": "Possibility",
        "question_ko": "사과, 복숭아, 배, 참외가 각각 하나씩 있는 바구니에서 2개를 뺐습니다. 바구니에 남아있는 과일의 경우의 수는 모두 몇 가지입니까?",
        "question_en": "Two were removed from a basket containing one each of apple, peach, pear, and melon. How many cases of fruit are left in the basket?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 복숭아 배 참외 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] apple peach pear melon [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '복숭아'\nvar_c = '배'\nvar_d = '참외'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g / (i+1)\nprint(int(var_g))",
        "solution_code_en": "var_a = 'apple'\nvar_b = 'peach'\nvar_c = 'pear'\nvar_d = 'melon'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g / (i+1)\nprint(int(var_g))"
    },
    "5385": {
        "category": "Correspondence",
        "question_ko": "A를 3으로 나눴을 때 몫이 8, 나머지가 2 였습니다. A는 자연수입니다. 이 때 A는 무엇인가요?",
        "question_en": "When A is divided by 3, the quotient is 8 and the remainder is 2. A is a natural number. What is A?",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "3 8 [OP_MUL] 2 [OP_ADD]",
        "solution_abst_en": "3 8 [OP_MUL] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 3\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "5386": {
        "category": "Comparison",
        "question_ko": "철수는 식용유를 230밀리리터(㎖), 지민이는 123밀리리터(㎖) 구입했습니다. 누가 더 식용유를 많이 샀습니까?",
        "question_en": "Cheolsu bought 230 milliliters (ml) of cooking oil, and Jimin bought 123 milliliters (ml). Who bought more cooking oil?",
        "answer_ko": "철수",
        "answer_en": "Cheolsu",
        "solution_abst_ko": "[OP_LIST_SOL] 철수 지민 [OP_LIST_EOL] [OP_LIST_SOL] 230 123 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Cheolsu Jimin [OP_LIST_EOL] [OP_LIST_SOL] 230 123 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '철수'\nvar_b = '지민'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 230\nvar_d = 123\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Cheolsu'\nvar_b = 'Jimin'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 230\nvar_d = 123\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "5387": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 9를 나누었더니 8의 결과값을 얻었습니다. 어떤 수에 11을 더하면?",
        "question_en": "When you divide a number by 9, you get a result of 8. What do you get from adding 11 to the number?",
        "answer_ko": "83",
        "answer_en": "83",
        "solution_abst_ko": "8 9 [OP_MUL] 11 [OP_ADD]",
        "solution_abst_en": "8 9 [OP_MUL] 11 [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 11\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 11\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "5388": {
        "category": "Arithmetic calculation",
        "question_ko": "동물원에 있는 개는 32마리 입니다. 그중에서 수컷은 전체의 5/8입니다. 수컷 중에서 치와와는 수컷 전체의 3/4입니다. 동물원에 있는 전체 개 중에서 치와와가 아닌 수컷은 몇 마리입니까?",
        "question_en": "There are 32 dogs in the zoo. Among them, males make up 5/8 of the total. Among males, Chihuahuas account for 3/4 of all males. Of the total dogs in the zoo, how many are non-Chihuahua males?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "32 5/8 [OP_MUL] 1 3/4 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "32 5/8 [OP_MUL] 1 3/4 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 32\nvar_b = 0.625\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 0.75\nvar_f = var_d - var_e\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 32\nvar_b = 0.625\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 0.75\nvar_f = var_d - var_e\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "5389": {
        "category": "Arithmetic calculation",
        "question_ko": "유나는 문구점에 갔습니다. 가지고 간 돈의 절반으로 공책을 사고, 연필을 사는데 나머지 돈의 절반을 썼습니다. 남은 돈이 800원이라면 처음에 유나가 가지고 간 돈은 얼마입니까?",
        "question_en": "Yuna went to the stationery store. She bought a notebook with half of the money she took, and she spent half of the remaining money on a pencil. If the remaining money is 800 won, how much money did Yuna take at the beginning?",
        "answer_ko": "3200",
        "answer_en": "3200",
        "solution_abst_ko": "800 2 [OP_MUL] 2 [OP_MUL]",
        "solution_abst_en": "800 2 [OP_MUL] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 800\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 800\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "5390": {
        "category": "Possibility",
        "question_ko": "10미만 짝수들을 한 번씩 이용하여 만들 수 있는 네 자리 수 중 3의 배수는 모두 몇 개인가?",
        "question_en": "How many four-digit numbers can be formed by using even numbers less than 10 once?",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "0 10 1 [OP_SUB] [OP_LIST_EVEN] 4 [OP_LIST_GET_PERM] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "0 10 1 [OP_SUB] [OP_LIST_EVEN] 4 [OP_LIST_GET_PERM] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 10\nvar_c = 1\nvar_d = var_b - var_c\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_d+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_d+1, 2):\n        list_a.append(i)\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c = []\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nvar_g = len(list_c)\nprint(int(var_g))",
        "solution_code_en": "var_a = 0\nvar_b = 10\nvar_c = 1\nvar_d = var_b - var_c\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_d+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_d+1, 2):\n        list_a.append(i)\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c = []\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nvar_g = len(list_c)\nprint(int(var_g))"
    },
    "5391": {
        "category": "Arithmetic calculation",
        "question_ko": "3.05미터(m)에서 떨어진 공은 높이의 0.7만큼 튀어오릅니다. 이 공이 세번째로 땅에 닿을때까지 움직인 거리는 몇 미터(m)입니까?",
        "question_en": "A ball dropped from 3.05 meters (m) bounces 0.7 of its height. Find how many meters (m) the ball moves until it hits the ground for the third time.",
        "answer_ko": "10.31",
        "answer_en": "10.31",
        "solution_abst_ko": "3.05 3.05 0.7 [OP_MUL] 2 [OP_MUL] [OP_ADD] 3.05 0.7 2 [OP_POW] [OP_MUL] 2 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "3.05 3.05 0.7 [OP_MUL] 2 [OP_MUL] [OP_ADD] 3.05 0.7 2 [OP_POW] [OP_MUL] 2 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 3.05\nvar_b = 3.05\nvar_c = 0.7\nvar_d = var_b * var_c\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_a + var_f\nvar_h = 3.05\nvar_i = 0.7\nvar_j = 2\nvar_k = var_i ** var_j\nvar_l = var_h * var_k\nvar_m = 2\nvar_n = var_l * var_m\nvar_o = var_g + var_n\nprint('{:.2f}'.format(round(var_o+1e-10,2)))",
        "solution_code_en": "var_a = 3.05\nvar_b = 3.05\nvar_c = 0.7\nvar_d = var_b * var_c\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_a + var_f\nvar_h = 3.05\nvar_i = 0.7\nvar_j = 2\nvar_k = var_i ** var_j\nvar_l = var_h * var_k\nvar_m = 2\nvar_n = var_l * var_m\nvar_o = var_g + var_n\nprint('{:.2f}'.format(round(var_o+1e-10,2)))"
    },
    "5392": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중 2번째로 큰 수는 무엇입니까?",
        "question_en": "There are five numbers 10, 11, 12, 13, and 14. Which number is the second largest?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 2 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 2 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nprint(int(var_g))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nprint(int(var_g))"
    },
    "5393": {
        "category": "Possibility",
        "question_ko": "숫자 카드 1, 6, 8를 한 번씩 모두 사용하여 가장 큰 세 자리 수와 세 번째로 큰 세 자리수의 합을 구하시오.",
        "question_en": "Find the sum of the largest and the third largest three-digit number that can be made using the all the numbers 1, 6, and 8 once.",
        "answer_ko": "1479",
        "answer_en": "1479",
        "solution_abst_ko": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 3 [OP_LIST_GET] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 3 [OP_LIST_GET] [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 3\nvar_h = list_b[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 3\nvar_h = list_b[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))"
    },
    "5394": {
        "category": "Arithmetic calculation",
        "question_ko": "3의 배수 중 가장 큰 네 자리 수는?",
        "question_en": "Which four-digit number is the largest among multiples of 3?",
        "answer_ko": "9999",
        "answer_en": "9999",
        "solution_abst_ko": "1000 9999 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_abst_en": "1000 9999 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))",
        "solution_code_en": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))"
    },
    "5395": {
        "category": "Arithmetic calculation",
        "question_ko": "호떡 하나는 반죽 6.64그램(g)이 필요합니다. 반죽 212.48그램(g)을 사용하여 만들 수 있는 호떡의 최대 개수를 구하세요.",
        "question_en": "One hotteok requires 6.64 grams (g) of dough. Find the maximum number of hotteok you can make using 212.48 grams (g) of dough.",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "212.48 6.64 [OP_FDIV]",
        "solution_abst_en": "212.48 6.64 [OP_FDIV]",
        "solution_code_ko": "var_a = 212.48\nvar_b = 6.64\nvar_c = var_a // var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 212.48\nvar_b = 6.64\nvar_c = var_a // var_b\nprint(int(var_c))"
    },
    "5396": {
        "category": "Arithmetic calculation",
        "question_ko": "쌀이 52킬로그램(㎏) 있었습니다. 3일 동안 매일 9킬로그램(㎏)씩 먹었습니다. 쌀은 몇 킬로그램(㎏) 남아 있습니까?",
        "question_en": "There were 52 kilograms (kg) of rice. I ate 9 kilograms (kg) each day for 3 days. How many kilograms (kg) of rice are left?",
        "answer_ko": "25",
        "answer_en": "25",
        "solution_abst_ko": "52 3 9 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "52 3 9 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 52\nvar_b = 3\nvar_c = 9\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 52\nvar_b = 3\nvar_c = 9\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "5397": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중 가장 작은 수는 무엇입니까?",
        "question_en": "There are three numbers 10, 11 and 12. Which number is the smallest?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nprint(int(var_e))"
    },
    "5398": {
        "category": "Possibility",
        "question_ko": "윤기는 서점에서 5개의 책 중 3개의 책을 사려고 합니다. 윤기가 3개의 책을 사는 경우는 모두 몇 가지입니까?",
        "question_en": "Yoongi wants to buy 3 out of 5 books at the bookstore. How many possible ways can Yoongi buy 3 books?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "5 3 [OP_COMB]",
        "solution_abst_en": "5 3 [OP_COMB]",
        "solution_code_ko": "var_a = 5\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))"
    },
    "5399": {
        "category": "Comparison",
        "question_ko": "수영장을 가기 위해 학생들이 줄을 섰습니다. 유정이는 5번째에 서 있고 호석이는 유정이 바로 뒤에 서 있습니다. 호석이는 몇 번째에 서 있을까요?",
        "question_en": "Students lined up to go to the pool. Yoojeong stands in the 5th position, and Hoseok stands right behind Yoojeong. What number does Hoseok stand on?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "5 1 [OP_ADD]",
        "solution_abst_en": "5 1 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "5400": {
        "category": "Arithmetic calculation",
        "question_ko": "주사위를 던져서 나온 수가 홀수이면서 3의 배수인 경우의 수를 구하시오.",
        "question_en": "Find the number of cases when a dice is rolled, and the number that comes up is an odd number and a multiple of 3.",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "1 6 [OP_LIST_ODD] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "1 6 [OP_LIST_ODD] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 6\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 3\nlist_b = []\nvar_c = int(var_c)\nfor i in list_a:\n    i = int(i)\n    if i % var_c == 0:\n        list_b.append(i)\nvar_d = len(list_b)\nprint(int(var_d))",
        "solution_code_en": "var_a = 1\nvar_b = 6\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 3\nlist_b = []\nvar_c = int(var_c)\nfor i in list_a:\n    i = int(i)\n    if i % var_c == 0:\n        list_b.append(i)\nvar_d = len(list_b)\nprint(int(var_d))"
    },
    "5401": {
        "category": "Possibility",
        "question_ko": "민영이네 집에는 공룡 인형이 3개, 물고기 인형이 2개, 장난감 자동차가 1개 있습니다. 공룡 인형은 몇 개가 있습니까?",
        "question_en": "In Minyoung's house there are 3 dinosaur dolls, 2 fish dolls, and 1 toy car. How many dinosaur dolls are there?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "3",
        "solution_abst_en": "3",
        "solution_code_ko": "var_a = 3\nprint(int(var_a))",
        "solution_code_en": "var_a = 3\nprint(int(var_a))"
    },
    "5402": {
        "category": "Geometry",
        "question_ko": "가로 50미터(m), 세로 35(m), 깊이 40(m)인 직육면체 모양의 수영장이 있습니다. 이 수영장의 안쪽에 한 변의 길이가 1미터(m)인 타일을 빈틈없이 붙이려고 한다면, 적어도 몇 개의 타일을 붙여야 합니까?",
        "question_en": "There is a cuboid-shaped swimming pool with a width of 50 meters (m), a length of 35 meters (m), and a depth of 40 meters (m). If you are going to put tiles with a side length of 1 meter (m) on the inside of this swimming pool without any gap, how many tiles will you have to put at least?",
        "answer_ko": "10300",
        "answer_en": "10300",
        "solution_abst_ko": "2 50 35 [OP_MUL] 50 40 [OP_MUL] [OP_ADD] 35 40 [OP_MUL] [OP_ADD] [OP_MUL] 1 1 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "2 50 35 [OP_MUL] 50 40 [OP_MUL] [OP_ADD] 35 40 [OP_MUL] [OP_ADD] [OP_MUL] 1 1 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 2\nvar_b = 50\nvar_c = 35\nvar_d = var_b * var_c\nvar_e = 50\nvar_f = 40\nvar_g = var_e * var_f\nvar_h = var_d + var_g\nvar_i = 35\nvar_j = 40\nvar_k = var_i * var_j\nvar_l = var_h + var_k\nvar_m = var_a * var_l\nvar_n = 1\nvar_o = 1\nvar_p = var_n * var_o\nvar_q = var_m / var_p\nprint(int(var_q))",
        "solution_code_en": "var_a = 2\nvar_b = 50\nvar_c = 35\nvar_d = var_b * var_c\nvar_e = 50\nvar_f = 40\nvar_g = var_e * var_f\nvar_h = var_d + var_g\nvar_i = 35\nvar_j = 40\nvar_k = var_i * var_j\nvar_l = var_h + var_k\nvar_m = var_a * var_l\nvar_n = 1\nvar_o = 1\nvar_p = var_n * var_o\nvar_q = var_m / var_p\nprint(int(var_q))"
    },
    "5403": {
        "category": "Geometry",
        "question_ko": "직육면체의 가로가 30센티미터(㎝), 세로가 22센티미터(㎝) 입니다. 이 직육면체의 모든 모서리의 합이 224센티미터(㎝)라면, 높이는 몇 센티미터(㎝)입니까?",
        "question_en": "The width of a rectangular parallelepiped is 30 centimeters (cm), and the length is 22 centimeters (cm). If the sum of all the edges of this cuboid is 224 centimeters (cm), what is the height in centimeters (cm)?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "224 4 [OP_DIV] 30 [OP_SUB] 22 [OP_SUB]",
        "solution_abst_en": "224 4 [OP_DIV] 30 [OP_SUB] 22 [OP_SUB]",
        "solution_code_ko": "var_a = 224\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 30\nvar_e = var_c - var_d\nvar_f = 22\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 224\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 30\nvar_e = var_c - var_d\nvar_f = 22\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "5404": {
        "category": "Geometry",
        "question_ko": "오각형의 한 꼭지점에서 대각선을 그으면 몇 개의 삼각형이 생길까요?",
        "question_en": "How many triangles will there be if you draw the diagonals from a vertex of the pentagon?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "5 3 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "5 3 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "5405": {
        "category": "Arithmetic calculation",
        "question_ko": "민영이는 1시간에 125개의 당근을 뽑았고, 유정이는 1시간에 137개의 당근을 뽑았습니다. 두 사람이 같은 빠르기로 당근을 6시간 동안 뽑았을 때, 유정이는 민영이보다 당근을 몇 개 더 많이 뽑았습니까?",
        "question_en": "Minyoung picked 125 carrots in an hour, and Yoojung picked 137 carrots in an hour. When the two of them pulled carrots at the same speed for 6 hours, how many more carrots did Yoojung pull than Minyoung?",
        "answer_ko": "72",
        "answer_en": "72",
        "solution_abst_ko": "137 125 [OP_SUB] 6 [OP_MUL]",
        "solution_abst_en": "137 125 [OP_SUB] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 137\nvar_b = 125\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 137\nvar_b = 125\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "5406": {
        "category": "Correspondence",
        "question_ko": "132.6미터(m) 거리를 경찰들이 나눠서 순찰다닌다. 1명의 경찰이 담당하는 구역이 13.26미터(m)라고 한다. 동일한 인원에게 6.4킬로미터(㎞)의 순찰을 맡길 때, 한명의 경찰관이 몇 킬로미터(㎞)의 구역을 담당하게 되는지 구하시오.",
        "question_en": "A street of 132.6 meters (m) is evenly divided between police officers. The area covered by a single officer is said to be 13.26 meters (m). If the same number of officers are assigned to patrol 6.4 kilometers (km), find how many kilometers (km) of area will be covered by one officer.",
        "answer_ko": "0.64",
        "answer_en": "0.64",
        "solution_abst_ko": "6.4 132.6 13.26 [OP_DIV] [OP_DIV]",
        "solution_abst_en": "6.4 132.6 13.26 [OP_DIV] [OP_DIV]",
        "solution_code_ko": "var_a = 6.4\nvar_b = 132.6\nvar_c = 13.26\nvar_d = var_b / var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 6.4\nvar_b = 132.6\nvar_c = 13.26\nvar_d = var_b / var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "5407": {
        "category": "Possibility",
        "question_ko": "지혜는 숫자 카드 8, 6, 1을 한 번씩 모두 사용하여 세 자리 자연수를 만들고자 한다. 이 때, 만들 수 있는 세 자리 수 중 큰 순서대로 3개를 고르고, 그 중 가장 큰 것을 뺀 나머지의 합을 구하였다. 답은 얼마인가?",
        "question_en": "Jihye wants to form a three-digit natural number by using all three number cards, 8, 6, and 1, once each. She chose the three biggest numbers among the possible three-digit numbers and then calculated the sum of them except the biggest one. What is the result?",
        "answer_ko": "1497",
        "answer_en": "1497",
        "solution_abst_ko": "[OP_LIST_SOL] 8 6 1 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 3 [OP_LIST_MAX] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 8 6 1 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 3 [OP_LIST_MAX] [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 6\nvar_c = 1\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[-var_g]\nvar_i = var_f + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 8\nvar_b = 6\nvar_c = 1\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[-var_g]\nvar_i = var_f + var_h\nprint(int(var_i))"
    },
    "5408": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 4를 곱하고 다시 4를 곱하면 32가 됩니다. 어떤 수는 얼마인지 구하시오.",
        "question_en": "A number multiplied by 4 and then multiplied by 4 again is 32. Find out what number this is.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "32 4 [OP_DIV] 4 [OP_DIV]",
        "solution_abst_en": "32 4 [OP_DIV] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 32\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 32\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "5409": {
        "category": "Arithmetic calculation",
        "question_ko": "2부터 연속하는 짝수 123개의 합을 구하시오.",
        "question_en": "Find the sum of 123 consecutive even numbers from 2.",
        "answer_ko": "15252",
        "answer_en": "15252",
        "solution_abst_ko": "2 123 1 [OP_SUB] 2 [OP_MUL] 2 [OP_ADD] 2 [OP_LIST_ARANGE] [OP_LIST_SUM]",
        "solution_abst_en": "2 123 1 [OP_SUB] 2 [OP_MUL] 2 [OP_ADD] 2 [OP_LIST_ARANGE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 2\nvar_b = 123\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = 2\nlist_a = [i for i in range(var_a, var_h + 1, var_i)]\nlist_a = [float(i) for i in list_a]\nvar_j = sum(list_a)\nprint(int(var_j))",
        "solution_code_en": "var_a = 2\nvar_b = 123\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = 2\nlist_a = [i for i in range(var_a, var_h + 1, var_i)]\nlist_a = [float(i) for i in list_a]\nvar_j = sum(list_a)\nprint(int(var_j))"
    },
    "5410": {
        "category": "Comparison",
        "question_ko": "정국에는 6에서 3을 뺀 수를 모았고, 윤기는 4를 모았습니다. 누가 큰 수를 가지고 있나요?",
        "question_en": "Considering Jungkook has a number of 6 minus 3, and Yoongi has 4. Find the one with the bigger number.",
        "answer_ko": "윤기",
        "answer_en": "Yoongi",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 윤기 [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_SUB] 4 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Yoongi [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_SUB] 4 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '윤기'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 3\nvar_e = var_c - var_d\nvar_f = 4\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Yoongi'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 3\nvar_e = var_c - var_d\nvar_f = 4\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "5411": {
        "category": "Geometry",
        "question_ko": "서로 다른 점이 두 개 있습니다. 이 두 점을 지나는 직선의 수를 구하시오.",
        "question_en": "There are two distinct points. Find the number of straight lines passing through these two points.",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "1",
        "solution_abst_en": "1",
        "solution_code_ko": "var_a = 1\nprint(int(var_a))",
        "solution_code_en": "var_a = 1\nprint(int(var_a))"
    },
    "5412": {
        "category": "Arithmetic calculation",
        "question_ko": "지민이는 일주일 안에 220개의 딱지를 접으려고 합니다. 하루에 접어야하는 딱지의 수는 적어도 얼마인지 구하세요.",
        "question_en": "Jimin wants to fold 220 scabs within a week. Find at least how many scabs she have to fold in a day.",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "220 7 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "220 7 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 220\nvar_b = 7\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))",
        "solution_code_en": "var_a = 220\nvar_b = 7\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))"
    },
    "5413": {
        "category": "Geometry",
        "question_ko": "한 직선 위에 있지 않은 세 점에 대하여 선분의 개수를 구하시오.",
        "question_en": "Find the number of line segments for three points not on a straight line.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "3 2 [OP_COMB]",
        "solution_abst_en": "3 2 [OP_COMB]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))"
    },
    "5414": {
        "category": "Correspondence",
        "question_ko": "어머니가 어제는 집에 있던 식용유의 2/5보다 300그램(g) 더 많이 사용했고, 오늘은 나머지 식용유의 1/2보다 200그램(g) 더 적게 사용했습니다. 남은 식용유가 800그램(g)이라면, 어제 어머니가 사용하기 전 집에 있던 식용유는 몇 킬로그램(㎏)입니까?",
        "question_en": "My mother used 300 grams (g) more than 2/5 of the cooking oil in the house yesterday, and 200 grams (g) less than 1/2 of the remaining cooking oil today. If the remaining cooking oil is 800 grams (g), how many kilograms (kg) of cooking oil were there before mother used it yesterday?",
        "answer_ko": "2.50",
        "answer_en": "2.5",
        "solution_abst_ko": "800 200 [OP_SUB] 1 1/2 [OP_SUB] [OP_DIV] 300 [OP_ADD] 1 2/5 [OP_SUB] [OP_DIV] 1000 [OP_DIV]",
        "solution_abst_en": "800 200 [OP_SUB] 1 1/2 [OP_SUB] [OP_DIV] 300 [OP_ADD] 1 2/5 [OP_SUB] [OP_DIV] 1000 [OP_DIV]",
        "solution_code_ko": "var_a = 800\nvar_b = 200\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = 0.5\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 300\nvar_i = var_g + var_h\nvar_j = 1\nvar_k = 0.4\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nvar_n = 1000\nvar_o = var_m / var_n\nprint('{:.2f}'.format(round(var_o+1e-10,2)))",
        "solution_code_en": "var_a = 800\nvar_b = 200\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = 0.5\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 300\nvar_i = var_g + var_h\nvar_j = 1\nvar_k = 0.4\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nvar_n = 1000\nvar_o = var_m / var_n\nprint('{:.2f}'.format(round(var_o+1e-10,2)))"
    },
    "5415": {
        "category": "Arithmetic calculation",
        "question_ko": "56, 72의 공약수 중 4의 배수는 모두 몇 개인지 구하세요",
        "question_en": "How many of the common divisors of 56 and 72 are multiples of 4?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "56 [OP_LIST_GET_DIVISOR] 72 [OP_LIST_GET_DIVISOR] [OP_SET_INTERSECT] 4 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "56 [OP_LIST_GET_DIVISOR] 72 [OP_LIST_GET_DIVISOR] [OP_SET_INTERSECT] 4 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 56\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 72\nlist_b = []\nnum_sqrt = int(math.sqrt(var_b))\nfor i in range(1, num_sqrt+1):\n    if var_b % i == 0:\n        list_b.append(i)\n        list_b.append(int(var_b/i))\nlist_b = sorted(set(list_b))\nlist_c = list(set(list_a) & set(list_b))\nvar_c = 4\nlist_d = []\nvar_c = int(var_c)\nfor i in list_c:\n    i = int(i)\n    if i % var_c == 0:\n        list_d.append(i)\nvar_d = len(list_d)\nprint(int(var_d))",
        "solution_code_en": "var_a = 56\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 72\nlist_b = []\nnum_sqrt = int(math.sqrt(var_b))\nfor i in range(1, num_sqrt+1):\n    if var_b % i == 0:\n        list_b.append(i)\n        list_b.append(int(var_b/i))\nlist_b = sorted(set(list_b))\nlist_c = list(set(list_a) & set(list_b))\nvar_c = 4\nlist_d = []\nvar_c = int(var_c)\nfor i in list_c:\n    i = int(i)\n    if i % var_c == 0:\n        list_d.append(i)\nvar_d = len(list_d)\nprint(int(var_d))"
    },
    "5416": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 14를 더했더니 결과가 56이 되었습니다. 어떤 수에 3을 곱하면?",
        "question_en": "When you add 14 to a certain number, the result is 56. What is the value of the certain number multiplied by 3?",
        "answer_ko": "126",
        "answer_en": "126",
        "solution_abst_ko": "56 14 [OP_SUB] 3 [OP_MUL]",
        "solution_abst_en": "56 14 [OP_SUB] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 56\nvar_b = 14\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 56\nvar_b = 14\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "5417": {
        "category": "Comparison",
        "question_ko": "하나의 케익을 신영이는 전체의 1/3, 석기는 전체의 1/4, 웅이는 전체의 1/5을 먹었습니다. 케익을 가장 많이 먹은 사람은 누구입니까?",
        "question_en": "Shinyoung ate 1/3 of the cake, Seokgi ate 1/4, and Woong ate 1/5. Who ate the most cake?",
        "answer_ko": "신영",
        "answer_en": "Shinyoung",
        "solution_abst_ko": "[OP_LIST_SOL] 신영 석기 웅이 [OP_LIST_EOL] [OP_LIST_SOL] 1/3 1/4 1/5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Shinyoung Seokgi Woong [OP_LIST_EOL] [OP_LIST_SOL] 1/3 1/4 1/5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '신영'\nvar_b = '석기'\nvar_c = '웅이'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.3333333333333333\nvar_e = 0.25\nvar_f = 0.2\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Shinyoung'\nvar_b = 'Seokgi'\nvar_c = 'Woong'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.3333333333333333\nvar_e = 0.25\nvar_f = 0.2\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "5418": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 양계장에서 하루에 평균 230 개의 달걀을 생산한다고 합니다. 15 일 동안에는 모두 몇 개의 달걀을 생산 하겠습니까?",
        "question_en": "A chicken farm produces an average of 230 eggs per day. How many eggs will you produce in 15 days?",
        "answer_ko": "3450",
        "answer_en": "3450",
        "solution_abst_ko": "230 15 [OP_MUL]",
        "solution_abst_en": "230 15 [OP_MUL]",
        "solution_code_ko": "var_a = 230\nvar_b = 15\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 230\nvar_b = 15\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "5419": {
        "category": "Possibility",
        "question_ko": "커피와 빵을 각각 하나씩 고르려 하는데 커피의 종류가 2가지, 빵의 종류가 3가지이다. 경우의 수를 구하시오.",
        "question_en": "There are 2 types of coffee and 3 types of bread, and you want to choose one coffee and one bread. Find the number of cases.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "2 3 [OP_MUL]",
        "solution_abst_en": "2 3 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "5420": {
        "category": "Geometry",
        "question_ko": "정육면체는 12개의 모서리가 있고, 이 모서리의 합은 96센티미터(㎝)입니다. 한 모서리의 길이는 얼마입니까?",
        "question_en": "A cube has 12 edges, and the sum of these edges is 96 centimeters (cm). What is the length of one edge?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "96 12 [OP_DIV]",
        "solution_abst_en": "96 12 [OP_DIV]",
        "solution_code_ko": "var_a = 96\nvar_b = 12\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 96\nvar_b = 12\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "5421": {
        "category": "Arithmetic calculation",
        "question_ko": "5명이 (가) 물건을 모았습니다. 3명은 각각 8킬로그램(㎏)씩 모았고, 2명은 각각 7킬로그램(㎏)씩 모았습니다. 5명이 모은 (가) 물건은 모두 몇 킬로그램(㎏)입니까?",
        "question_en": "5 people collected items. Three people collected 8 kilograms (kg) each, and two people each collected 7 kilograms (kg). How many kilograms (kg) are all the objects the 5 people collected in total?",
        "answer_ko": "38",
        "answer_en": "38",
        "solution_abst_ko": "3 8 [OP_MUL] 2 7 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "3 8 [OP_MUL] 2 7 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = 7\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 3\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = 7\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "5422": {
        "category": "Geometry",
        "question_ko": "오각뿔의 면의 개수는?",
        "question_en": "What is the number of faces of a pentagonal pyramid?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "5 1 [OP_ADD]",
        "solution_abst_en": "5 1 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "5423": {
        "category": "Geometry",
        "question_ko": "진아는 한 변의 길이가 10센티미터(㎝)인 정사각형 모양의 색종이를 갖고 있습니다. 이 색종이를 가로가 1센티미터(㎝), 높이가 3센티미터(㎝)인 직각삼각형 모양으로 여러개 자르려고 합니다. 직각삼각형 모양의 색종이는 최대 몇 개를 가질 수 있겠습니까?",
        "question_en": "Jina has a piece of colored paper in the shape of a square with a side length of 10 centimeters (cm). She is going to cut this piece of colored paper into several pieces of right triangles with a width of 1 centimeter (cm) and a height of 3 centimeters (cm). How many right triangle-shaped pieces can she have?",
        "answer_ko": "66",
        "answer_en": "66",
        "solution_abst_ko": "10 2 [OP_POW] 1 3 [OP_MUL] [OP_FDIV] 2 [OP_MUL]",
        "solution_abst_en": "10 2 [OP_POW] 1 3 [OP_MUL] [OP_FDIV] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 1\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c // var_f\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 1\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c // var_f\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "5424": {
        "category": "Correspondence",
        "question_ko": "어떤 수의 3/4에서 24를 빼고 7로 나눈 뒤 50을 더한 후 2로 나누면 100이 됩니다. 어떤 수를 구하시오.",
        "question_en": "When you subtract 24 from 3/4 of a number, and then divide by 7, and then add 50 and divide by 2, you get 100. What is that number in question?",
        "answer_ko": "1432",
        "answer_en": "1432",
        "solution_abst_ko": "100 2 [OP_MUL] 50 [OP_SUB] 7 [OP_MUL] 24 [OP_ADD] 3/4 [OP_DIV]",
        "solution_abst_en": "100 2 [OP_MUL] 50 [OP_SUB] 7 [OP_MUL] 24 [OP_ADD] 3/4 [OP_DIV]",
        "solution_code_ko": "var_a = 100\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 50\nvar_e = var_c - var_d\nvar_f = 7\nvar_g = var_e * var_f\nvar_h = 24\nvar_i = var_g + var_h\nvar_j = 0.75\nvar_k = var_i / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 100\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 50\nvar_e = var_c - var_d\nvar_f = 7\nvar_g = var_e * var_f\nvar_h = 24\nvar_i = var_g + var_h\nvar_j = 0.75\nvar_k = var_i / var_j\nprint(int(var_k))"
    },
    "5425": {
        "category": "Arithmetic calculation",
        "question_ko": "호석이는 감을 35개 땄습니다. 호석이가 딴 감은 정국이가 딴 감의 수의 4배보다 3개가 더 많다고 합니다. 정국이가 딴 감은 몇 개입니까?",
        "question_en": "Hoseok picked 35 persimmons. It is said that the number of persimmons picked by Hoseok is 3 more than 4 times the number of persimmons picked by Jungkook. How many persimmons did Jungkook pick?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "35 3 [OP_SUB] 4 [OP_DIV]",
        "solution_abst_en": "35 3 [OP_SUB] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 35\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 35\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "5426": {
        "category": "Correspondence",
        "question_ko": "ABCD+ABCD=2478과 같은 네 자리 수 덧셈식이 있습니다. 여기서 A, B, C, D의 합은 얼마인가요?",
        "question_en": "There are four-digit addition expressions such as ABCD+ABCD=2478. What is the sum of A, B, C, and D?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "2478 2 [OP_DIV] [OP_NUM2LIST] [OP_LIST_SUM]",
        "solution_abst_en": "2478 2 [OP_DIV] [OP_NUM2LIST] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 2478\nvar_b = 2\nvar_c = var_a / var_b\nlist_a = []\nvar_c = int(var_c)\nwhile var_c//10 > 0:\n    list_a.append(var_c%10)\n    var_c = var_c//10\nlist_a.append(var_c%10)\nlist_a = list_a[::-1]\nlist_a = [float(i) for i in list_a]\nvar_d = sum(list_a)\nprint(int(var_d))",
        "solution_code_en": "var_a = 2478\nvar_b = 2\nvar_c = var_a / var_b\nlist_a = []\nvar_c = int(var_c)\nwhile var_c//10 > 0:\n    list_a.append(var_c%10)\n    var_c = var_c//10\nlist_a.append(var_c%10)\nlist_a = list_a[::-1]\nlist_a = [float(i) for i in list_a]\nvar_d = sum(list_a)\nprint(int(var_d))"
    },
    "5427": {
        "category": "Geometry",
        "question_ko": "세로 길이가 12센티미터(㎝)이고 둘레의 길이가 38센티미터(㎝)인 액자가 있다. 액자의 가로 길이를 구하시오.",
        "question_en": "There is a picture frame with a height length of 12 centimeters (cm) and a circumference of 38 centimeters (cm). Find the width of the frame.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "38 2 [OP_DIV] 12 [OP_SUB]",
        "solution_abst_en": "38 2 [OP_DIV] 12 [OP_SUB]",
        "solution_code_ko": "var_a = 38\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 12\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 38\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 12\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "5428": {
        "category": "Arithmetic calculation",
        "question_ko": "빨간 공 10개를 5개의 상자에 똑같이 나누어 담았습니다. 1개의 상자에 들어 있는 빨간 공의 개수는?",
        "question_en": "10 red balls are divided equally into 5 boxes. How many red balls are in 1 box?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "10 5 [OP_DIV]",
        "solution_abst_en": "10 5 [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 5\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 10\nvar_b = 5\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "5429": {
        "category": "Arithmetic calculation",
        "question_ko": "2살 차이 나는 형과 동생의 나이의 합이 26살이다. 형의 나이는?",
        "question_en": "The sum of the ages of the older brother and the younger brother, who have a two-year age difference, is 26 years old. How old is the brother?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "26 2 [OP_SUB] 2 [OP_DIV] 2 [OP_ADD]",
        "solution_abst_en": "26 2 [OP_SUB] 2 [OP_DIV] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 26\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 26\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "5430": {
        "category": "Geometry",
        "question_ko": "94센티미터(㎝)의 화장지를 중간이 겹치도록 접어 68센티미터(㎝)로 만들었을 때, 겹쳐진 부분의 길이를 구하시오.",
        "question_en": "When 94 centimeters (cm) toilet paper is folded so that the middle overlaps to make 68 centimeters (cm), find the length of the overlapped part.",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "94 68 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "94 68 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 94\nvar_b = 68\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 94\nvar_b = 68\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "5431": {
        "category": "Comparison",
        "question_ko": "투호놀이에 참가하려고 43명이 왔는데 그중에서 11명씩 2팀으로 나누어 투호놀이를 하고 나머지는 대기하기 위해 줄을 섰습니다. 줄을 선 학생은 모두 몇 명인지 알아봅시다.",
        "question_en": "43 people came to participate in the tuho game. They were divided into two teams of 11 to play tuho, and the rest lined up to wait. Find out how many students were in line.",
        "answer_ko": "25",
        "answer_en": "25",
        "solution_abst_ko": "43 11 2 [OP_MUL] [OP_SUB] 4 [OP_ADD]",
        "solution_abst_en": "43 11 2 [OP_MUL] [OP_SUB] 4 [OP_ADD]",
        "solution_code_ko": "var_a = 43\nvar_b = 11\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 4\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 43\nvar_b = 11\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 4\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "5432": {
        "category": "Possibility",
        "question_ko": "빨간색 구슬, 파란색 구슬, 노란색 구슬이 1개씩 있습니다. 이 중 2개를 골라서 (가)와 (나)가 하나씩 가지려고 할 때, 몇 가지 경우의 수가 있을지 구하시오.",
        "question_en": "There is 1 red bead, 1 blue bead, and 1 yellow bead each. Choose two of these and find out how many cases there are when A and B try to have one.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 빨간색 파란색 노란색 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] red blue yellow [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_code_ko": "var_a = '빨간색'\nvar_b = '파란색'\nvar_c = '노란색'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nprint(int(var_f))",
        "solution_code_en": "var_a = 'red'\nvar_b = 'blue'\nvar_c = 'yellow'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nprint(int(var_f))"
    },
    "5433": {
        "category": "Comparison",
        "question_ko": "3200보다 크고 4300보다 작은 수는 모두 몇 개입니까?",
        "question_en": "How many numbers are greater than 3200 and less than 4300?",
        "answer_ko": "1099",
        "answer_en": "1099",
        "solution_abst_ko": "3200 1 [OP_ADD] 4300 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_LEN]",
        "solution_abst_en": "3200 1 [OP_ADD] 4300 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 3200\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 4300\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = len(list_a)\nprint(int(var_h))",
        "solution_code_en": "var_a = 3200\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 4300\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = len(list_a)\nprint(int(var_h))"
    },
    "5434": {
        "category": "Correspondence",
        "question_ko": "43은 어떤 수에 5를 곱해야 하는데 실수로 5를 더하여 나온 결과입니다. 바르게 계산하면 얼마입니까?",
        "question_en": "43 is the result of accidentally adding 5 to a number that should be multiplied by 5. How much do you calculate correctly?",
        "answer_ko": "190",
        "answer_en": "190",
        "solution_abst_ko": "43 5 [OP_SUB] 5 [OP_MUL]",
        "solution_abst_en": "43 5 [OP_SUB] 5 [OP_MUL]",
        "solution_code_ko": "var_a = 43\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 43\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "5435": {
        "category": "Correspondence",
        "question_ko": "30을 어떤 수로 나누었을 때, 나누어떨어지게 하는 수는 모두 몇 개입니까?",
        "question_en": "When 30 can divided by some numbers, how many divisible numbers are there?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "30 [OP_LIST_GET_DIVISOR] [OP_LIST_LEN]",
        "solution_abst_en": "30 [OP_LIST_GET_DIVISOR] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 30\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = len(list_a)\nprint(int(var_b))",
        "solution_code_en": "var_a = 30\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = len(list_a)\nprint(int(var_b))"
    },
    "5436": {
        "category": "Possibility",
        "question_ko": "과녁판에 숫자 2, 5, 6, 9가 적혀 있다. 이 중 3개를 사용하여 만들 수 있는 세 번째로 큰 수와 세 번째로 작은 수의 합은 얼마인가?",
        "question_en": "The numbers 2, 5, 6, and 9 are written on the target board. What is the sum of the third largest and third smallest numbers that can be made using three of these?",
        "answer_ko": "1221",
        "answer_en": "1221",
        "solution_abst_ko": "[OP_LIST_SOL] 2 5 6 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 2 5 6 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 5\nvar_c = 6\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 2\nvar_b = 5\nvar_c = 6\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))"
    },
    "5437": {
        "category": "Arithmetic calculation",
        "question_ko": "민수는 세 자리 수로 어떤 수를 나누려고 합니다. 이 때 나누는 수의 일의 자리에 있는 0을 보지 못하고 이를 12로 잘못 보고 계산한 결과, 몫이 210 이었습니다. 바르게 계산한 몫을 구하시오.",
        "question_en": "Minsu wants to divide a number by a three-digit number. At this time, he did not see the 0 in the units digit of the divisor and miscalculated it as 12, and as a result, the quotient was 210. Find the correctly calculated quotient.",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "210 12 [OP_MUL] 120 [OP_FDIV]",
        "solution_abst_en": "210 12 [OP_MUL] 120 [OP_FDIV]",
        "solution_code_ko": "var_a = 210\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 120\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 210\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 120\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "5438": {
        "category": "Comparison",
        "question_ko": "꽃밭의 2/7에는 장미와 3/8에는 해바라기를 심었습니다. 어느 꽃 영역이 더 넓습니까?",
        "question_en": "I planted roses in 2/7 of the flower garden and sunflowers in 3/8. Which flower is planted in the larger area?",
        "answer_ko": "해바라기",
        "answer_en": "sunflowers",
        "solution_abst_ko": "[OP_LIST_SOL] 장미 해바라기 [OP_LIST_EOL] [OP_LIST_SOL] 2/7 3/8 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] roses sunflowers [OP_LIST_EOL] [OP_LIST_SOL] 2/7 3/8 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '장미'\nvar_b = '해바라기'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.2857142857142857\nvar_d = 0.375\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'roses'\nvar_b = 'sunflowers'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.2857142857142857\nvar_d = 0.375\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "5439": {
        "category": "Arithmetic calculation",
        "question_ko": "숲에 11그루의 대나무가 있다. 이 대나무들의 길이의 평균이 145.7센티미터(㎝)이고 대나무 중 2개의 길이의 평균은 142.1센티미터(㎝)이다. 나머지 막대의 길이의 평균을 구하시오.",
        "question_en": "There are 11 bamboo trees in the forest. The average length of these bamboos is 145.7 centimeters (cm) and the average length of two of the bamboos is 142.1 centimeters (cm). Find the average of the lengths of the remaining bamboos.",
        "answer_ko": "146.50",
        "answer_en": "146.5",
        "solution_abst_ko": "145.7 11 [OP_MUL] 142.1 2 [OP_MUL] [OP_SUB] 11 2 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "145.7 11 [OP_MUL] 142.1 2 [OP_MUL] [OP_SUB] 11 2 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 145.7\nvar_b = 11\nvar_c = var_a * var_b\nvar_d = 142.1\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 11\nvar_i = 2\nvar_j = var_h - var_i\nvar_k = var_g / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 145.7\nvar_b = 11\nvar_c = var_a * var_b\nvar_d = 142.1\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 11\nvar_i = 2\nvar_j = var_h - var_i\nvar_k = var_g / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "5440": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 3으로 나누었더니 27이 되었습니다. 어떤 수를 9로 나눈 값을 구하시오.",
        "question_en": "When you divide a number by 3, you get 27. Find the value of a number divided by 9.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "27 3 [OP_MUL] 9 [OP_DIV]",
        "solution_abst_en": "27 3 [OP_MUL] 9 [OP_DIV]",
        "solution_code_ko": "var_a = 27\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 27\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "5441": {
        "category": "Correspondence",
        "question_ko": "41은 어떤 수에서 27을 빼고 15를 더해야 하는데 실수로 15를 빼고 27을 더하여 나온 결과이다. 바르게 계산하면 어떻게 되는가?",
        "question_en": "41 is the result of mistakenly subtracting 15 from a certain number and adding 27, instead of subtracting 27 and adding 15. What do you get when you calculate correctly?",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "41 27 [OP_SUB] 15 [OP_ADD] 27 [OP_SUB] 15 [OP_ADD]",
        "solution_abst_en": "41 27 [OP_SUB] 15 [OP_ADD] 27 [OP_SUB] 15 [OP_ADD]",
        "solution_code_ko": "var_a = 41\nvar_b = 27\nvar_c = var_a - var_b\nvar_d = 15\nvar_e = var_c + var_d\nvar_f = 27\nvar_g = var_e - var_f\nvar_h = 15\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 41\nvar_b = 27\nvar_c = var_a - var_b\nvar_d = 15\nvar_e = var_c + var_d\nvar_f = 27\nvar_g = var_e - var_f\nvar_h = 15\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "5442": {
        "category": "Comparison",
        "question_ko": "두 수 A, B가 있습니다. A는 50보다 7 큰 수입니다. B는 10개씩 6묶음인 수보다 7 작은 수입니다. 더 큰 수는 어느 것입니까?",
        "question_en": "Suppose that there are two numbers A and B. A is 7 greater than 50. B is 7 less than 6 groups of 10. Which number is greater?",
        "answer_ko": "A",
        "answer_en": "A",
        "solution_abst_ko": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 50 7 [OP_ADD] 10 6 [OP_MUL] 7 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 50 7 [OP_ADD] 10 6 [OP_MUL] 7 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 50\nvar_d = 7\nvar_e = var_c + var_d\nvar_f = 10\nvar_g = 6\nvar_h = var_f * var_g\nvar_i = 7\nvar_j = var_h - var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 50\nvar_d = 7\nvar_e = var_c + var_d\nvar_f = 10\nvar_g = 6\nvar_h = var_f * var_g\nvar_i = 7\nvar_j = var_h - var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "5443": {
        "category": "Possibility",
        "question_ko": "1, 3, 5, 7, 9 다섯 장의 숫자카드가 있다. 이 카드를 사용하여 만들 수 있는 3자리 자연수 중 500미만인 수는 모두 몇 개인지 구하시오. (단, 카드는 중복사용 가능하다.)",
        "question_en": "There are five number cards 1, 3, 5, 7, and 9. How many 3-digit natural numbers can be made using this card that are less than 500? (The card can be used repeatedly.)",
        "answer_ko": "50",
        "answer_en": "50",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 5 7 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 500 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 5 7 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 500 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 5\nvar_d = 7\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 500\nlist_c = []\nfor i in list_b:\n    if i < var_g:\n        list_c.append(i)\nvar_h = len(list_c)\nprint(int(var_h))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 5\nvar_d = 7\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 500\nlist_c = []\nfor i in list_b:\n    if i < var_g:\n        list_c.append(i)\nvar_h = len(list_c)\nprint(int(var_h))"
    },
    "5444": {
        "category": "Possibility",
        "question_ko": "두 수 12, 36의 공배수 중에서 150보다 작은 수는 모두 몇 개인지 구하세요.",
        "question_en": "Find the number of common multiples of 12 and 36 that are less than 150.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "36 150 36 [OP_LIST_ARANGE] [OP_LIST_LEN]",
        "solution_abst_en": "36 150 36 [OP_LIST_ARANGE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 36\nvar_b = 150\nvar_c = 36\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = len(list_a)\nprint(int(var_d))",
        "solution_code_en": "var_a = 36\nvar_b = 150\nvar_c = 36\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = len(list_a)\nprint(int(var_d))"
    },
    "5445": {
        "category": "Correspondence",
        "question_ko": "A를 8으로 나누면 몫과 나머지가 각각 2과 7이 나옵니다. A는 자연수입니다. 이 때 A를 구하시오.",
        "question_en": "When A is divided by 8, the quotient and remainder are 2 and 7, respectively. A is a natural number. Find A at this time.",
        "answer_ko": "23",
        "answer_en": "23",
        "solution_abst_ko": "8 2 [OP_MUL] 7 [OP_ADD]",
        "solution_abst_en": "8 2 [OP_MUL] 7 [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "5446": {
        "category": "Correspondence",
        "question_ko": "1부터 어떤 자연수까지 모두 더하면 91이 됩니다. 어떤 자연수를 구하시오.",
        "question_en": "If you add all the natural numbers from 1 to a natural number, you get 91. Find a natural number.",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "91 2 [OP_MUL] 1/2 [OP_POW] 1 [OP_FLOOR]",
        "solution_abst_en": "91 2 [OP_MUL] 1/2 [OP_POW] 1 [OP_FLOOR]",
        "solution_code_ko": "var_a = 91\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 1\nvar_g=int((var_e//(10**(var_f-1)))*10**(var_f-1))\n\nprint(int(var_g))",
        "solution_code_en": "var_a = 91\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 1\nvar_g=int((var_e//(10**(var_f-1)))*10**(var_f-1))\n\nprint(int(var_g))"
    },
    "5447": {
        "category": "Geometry",
        "question_ko": "구각형의 대각선의 개수를 구하시오.",
        "question_en": "Find the number of diagonals of the nonagon.",
        "answer_ko": "27",
        "answer_en": "27",
        "solution_abst_ko": "9 9 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "9 9 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 9\nvar_b = 9\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 9\nvar_b = 9\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "5448": {
        "category": "Arithmetic calculation",
        "question_ko": "다현이가 숙제로 수학 문제를 풀고 있습니다. 어제는 전체의 1/3을 풀었고, 오늘은 전체의 1/2를 풀었다면 이틀 동안 푼 수학 문제는 전체 문제의 몇 배입니까?",
        "question_en": "Dahyun is solving a math problem for homework. If she solved 1/3 of the total yesterday and 1/2 of the total today, how many times did the total number of math problems she solved in two days?",
        "answer_ko": "0.83",
        "answer_en": "0.83",
        "solution_abst_ko": "1/3 1/2 [OP_ADD]",
        "solution_abst_en": "1/3 1/2 [OP_ADD]",
        "solution_code_ko": "var_a = 0.3333333333333333\nvar_b = 0.5\nvar_c = var_a + var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 0.3333333333333333\nvar_b = 0.5\nvar_c = var_a + var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "5449": {
        "category": "Geometry",
        "question_ko": "정사각형 모양의 카드를 빈틈없이 규칙적으로 늘어놓아 큰 정사각형을 만들었습니다. 둘레에 놓인 카드의 개수가 240개였다면, 사용한 카드 전체의 개수는 몇 개입니까?",
        "question_en": "The square-shaped cards are regularly arranged without gaps to form a large square. If the number of cards laid at the perimeter was 240, how many total cards in total were used?",
        "answer_ko": "3721",
        "answer_en": "3721",
        "solution_abst_ko": "240 4 [OP_DIV] 1 [OP_ADD] 2 [OP_POW]",
        "solution_abst_en": "240 4 [OP_DIV] 1 [OP_ADD] 2 [OP_POW]",
        "solution_code_ko": "var_a = 240\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e ** var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 240\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e ** var_f\nprint(int(var_g))"
    },
    "5450": {
        "category": "Geometry",
        "question_ko": "둘레의 길이가 12/25센티미터(㎝)인 정사각형이 있습니다. 이 정사각형의 한 변의 길이를 구하시오.",
        "question_en": "You have a square with a perimeter of 12/25 centimeters (cm). Find the length of one side of this square.",
        "answer_ko": "0.12",
        "answer_en": "0.12",
        "solution_abst_ko": "12/25 4 [OP_DIV]",
        "solution_abst_en": "12/25 4 [OP_DIV]",
        "solution_code_ko": "var_a = 0.48\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 0.48\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "5451": {
        "category": "Correspondence",
        "question_ko": "21+AB=54입니다. B는 얼마인가요?",
        "question_en": "According to the equation, 21+AB=54, what number fits B?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "21+AB=54 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "21+AB=54 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '21+AB=54'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '21+AB=54'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "5452": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 24를 곱하려고 합니다. 잘못하여 42를 뺐을 때의 답이 50이라면 바르게 계산한 결과는 얼마일까요?",
        "question_en": "You want to multiply a number by 24. If the result you get when you mistakenly subtract 42 from this number is 50, what would be the correct result?",
        "answer_ko": "2208",
        "answer_en": "2208",
        "solution_abst_ko": "50 42 [OP_ADD] 24 [OP_MUL]",
        "solution_abst_en": "50 42 [OP_ADD] 24 [OP_MUL]",
        "solution_code_ko": "var_a = 50\nvar_b = 42\nvar_c = var_a + var_b\nvar_d = 24\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 50\nvar_b = 42\nvar_c = var_a + var_b\nvar_d = 24\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "5453": {
        "category": "Arithmetic calculation",
        "question_ko": "현경이는 훌라후프를 첫째 날에는 18번을 하고, 둘째 날에는 첫째 날의 2배, 셋째 날에는 둘째 날의 2배를 하기로 했습니다. 현경이가 같은 방법으로 훌라후프를 한다면 넷째 날에는 모두 몇 번 해야 하는지 구해 보시오.",
        "question_en": "Hyungyeong decided to do 18 hula hoops on the first day, twice the first day on the second day, and twice the second day on the third day. If Hyungyeong does the hula hoop in the same way, find out how many times she should do on the fourth day.",
        "answer_ko": "144",
        "answer_en": "144",
        "solution_abst_ko": "18 2 4 1 [OP_SUB] [OP_POW] [OP_MUL]",
        "solution_abst_en": "18 2 4 1 [OP_SUB] [OP_POW] [OP_MUL]",
        "solution_code_ko": "var_a = 18\nvar_b = 2\nvar_c = 4\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = var_b ** var_e\nvar_g = var_a * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 18\nvar_b = 2\nvar_c = 4\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = var_b ** var_e\nvar_g = var_a * var_f\nprint(int(var_g))"
    },
    "5454": {
        "category": "Geometry",
        "question_ko": "평행사변형의 밑변의 길이는 9센티미터(㎝)이고 넓이는 33.3제곱센티미터(㎠)일 때, 이 평행사변형의 높이를 구하시오.",
        "question_en": "If the length of the base of the parallelogram is 9 centimeters (cm) and the area is 33.3 square centimeters (cm2), find the height of the parallelogram.",
        "answer_ko": "3.70",
        "answer_en": "3.7",
        "solution_abst_ko": "33.3 9 [OP_DIV]",
        "solution_abst_en": "33.3 9 [OP_DIV]",
        "solution_code_ko": "var_a = 33.3\nvar_b = 9\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 33.3\nvar_b = 9\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "5455": {
        "category": "Geometry",
        "question_ko": "밑변이 3센티미터(㎝) 이고 높이가 2센티미터(㎝) 인 삼각형 A와 밑변이 3센티미터(㎝) 이고 높이가 6.02 센티미터(㎝) 인 삼각형 B가 있습니다. A의 넓이는 B의 넓이의 몇 배일까요?",
        "question_en": "There is a triangle A with a base of 3 centimeters (cm) and a height of 2 centimeters (cm) and a triangle B with a base of 3 centimeters (cm) and a height of 6.02 centimeters (cm). How many times the area of A is the area of B?",
        "answer_ko": "3.01",
        "answer_en": "3.01",
        "solution_abst_ko": "3 6.02 [OP_MUL] 2 [OP_DIV] 3 2 [OP_MUL] 2 [OP_DIV] [OP_DIV]",
        "solution_abst_en": "3 6.02 [OP_MUL] 2 [OP_DIV] 3 2 [OP_MUL] 2 [OP_DIV] [OP_DIV]",
        "solution_code_ko": "var_a = 3\nvar_b = 6.02\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 3\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = 2\nvar_j = var_h / var_i\nvar_k = var_e / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 3\nvar_b = 6.02\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 3\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = 2\nvar_j = var_h / var_i\nvar_k = var_e / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "5456": {
        "category": "Correspondence",
        "question_ko": "서로 다른 두 수 A, B가 있습니다. 두 자리 수끼리의 뺄셈식 7A-B5=34에서 A와 B의 합을 구하시오.",
        "question_en": "There are two different numbers A and B. Find the sum of A and B in the two-digit subtraction equation 7A-B5=34.",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "7A-B5=34 A [OP_DIGIT_UNK_SOLVER] 7A-B5=34 B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_abst_en": "7A-B5=34 A [OP_DIGIT_UNK_SOLVER] 7A-B5=34 B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_code_ko": "var_a = '7A-B5=34'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '7A-B5=34'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = '7A-B5=34'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '7A-B5=34'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "5457": {
        "category": "Arithmetic calculation",
        "question_ko": "332명이 타고 있는 기차의 첫번째 정류장에서 119명이 타고 113명이 내렸으며 두번째 정류장에서는 95명이 내리고 86명이 탔습니다. 현재 기차에 남아 있는 사람은 몇 명일까요?",
        "question_en": "At the first station of the train with 332 people, 119 people got on and 113 got off, and at the secone station 95 got off and 86 got on. How many people are currently on the train?",
        "answer_ko": "329",
        "answer_en": "329",
        "solution_abst_ko": "332 119 113 [OP_SUB] [OP_ADD] 86 95 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "332 119 113 [OP_SUB] [OP_ADD] 86 95 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 332\nvar_b = 119\nvar_c = 113\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 86\nvar_g = 95\nvar_h = var_f - var_g\nvar_i = var_e + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 332\nvar_b = 119\nvar_c = 113\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 86\nvar_g = 95\nvar_h = var_f - var_g\nvar_i = var_e + var_h\nprint(int(var_i))"
    },
    "5458": {
        "category": "Comparison",
        "question_ko": "반에 세 명의 학생을 불러 생각나는 숫자를 말해보게 했다. 세 사람이 말한 수의 평균보다 앞의 두 사람이 말한 수의 평균이 23 더 컸고, 뒤의 두 사람이 말한 평균은 전체의 평균보다 17 작았다. 두 번째 사람이 66을 말했을 때, 세 번째 학생은 얼마를 말하였는가?",
        "question_en": "Invite three students to class and ask them to name a number that comes to mind. The average of the numbers spoken by the first two people was 23 greater than the average of the numbers spoken by the three people, and the average of the numbers spoken by the next two people was 17 less than the average of the total. When the second person said 66, how much did the third student say?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "23 6 [OP_MUL] 66 [OP_SUB] 2 [OP_MUL] 66 -1 [OP_MUL] 17 6 [OP_MUL] -1 [OP_MUL] [OP_ADD] [OP_ADD] 3 -1 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "23 6 [OP_MUL] 66 [OP_SUB] 2 [OP_MUL] 66 -1 [OP_MUL] 17 6 [OP_MUL] -1 [OP_MUL] [OP_ADD] [OP_ADD] 3 -1 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 23\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 66\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = 66\nvar_i = -1\nvar_j = var_h * var_i\nvar_k = 17\nvar_l = 6\nvar_m = var_k * var_l\nvar_n = -1\nvar_o = var_m * var_n\nvar_p = var_j + var_o\nvar_q = var_g + var_p\nvar_r = 3\nvar_s = -1\nvar_t = var_r * var_s\nvar_u = var_q / var_t\nprint(int(var_u))",
        "solution_code_en": "var_a = 23\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 66\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = 66\nvar_i = -1\nvar_j = var_h * var_i\nvar_k = 17\nvar_l = 6\nvar_m = var_k * var_l\nvar_n = -1\nvar_o = var_m * var_n\nvar_p = var_j + var_o\nvar_q = var_g + var_p\nvar_r = 3\nvar_s = -1\nvar_t = var_r * var_s\nvar_u = var_q / var_t\nprint(int(var_u))"
    },
    "5459": {
        "category": "Comparison",
        "question_ko": "아침에 책을 지우는 32쪽, 희수는 39쪽 읽었다.저녁에 지우는 아침보다 12쪽 더 많이 읽고, 희수는 아침보다 9쪽 덜 읽었다. 오늘 동화책을 가장 덜 읽은 사람은 누구인가?",
        "question_en": "Jiwoo read 32 pages and Heesu read 39 pages in the morning. In the evening, Jiwoo read 12 more pages than in the morning, and Heesu read 9 fewer pages than in the morning. Who read less children's books today in total?",
        "answer_ko": "희수",
        "answer_en": "Heesu",
        "solution_abst_ko": "[OP_LIST_SOL] 지우 희수 [OP_LIST_EOL] [OP_LIST_SOL] 32 32 12 [OP_ADD] [OP_ADD] 39 39 9 [OP_SUB] [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jiwoo Heesu [OP_LIST_EOL] [OP_LIST_SOL] 32 32 12 [OP_ADD] [OP_ADD] 39 39 9 [OP_SUB] [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '지우'\nvar_b = '희수'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 32\nvar_d = 32\nvar_e = 12\nvar_f = var_d + var_e\nvar_g = var_c + var_f\nvar_h = 39\nvar_i = 39\nvar_j = 9\nvar_k = var_i - var_j\nvar_l = var_h + var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[var_m-1]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'Jiwoo'\nvar_b = 'Heesu'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 32\nvar_d = 32\nvar_e = 12\nvar_f = var_d + var_e\nvar_g = var_c + var_f\nvar_h = 39\nvar_i = 39\nvar_j = 9\nvar_k = var_i - var_j\nvar_l = var_h + var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[var_m-1]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "5460": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 12를 빼고 5를 곱하면 40이 됩니다. 어떤 수를 구하시오.",
        "question_en": "If you subtract 12 from a number and multiply it by 5, you get 40. Find the number.",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "40 5 [OP_DIV] 12 [OP_ADD]",
        "solution_abst_en": "40 5 [OP_DIV] 12 [OP_ADD]",
        "solution_code_ko": "var_a = 40\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 12\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 40\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 12\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "5461": {
        "category": "Arithmetic calculation",
        "question_ko": "색 도화지 98장을 12명의 학생에게 똑같이 나누어 주려고 하였더니 몇 장이 모자랐습니다. 색 도화지를 남김없이 똑같이 나누어 주기 위해 색 도화지를 더 사려고 합니다. 색 도화지 한 장이 450원이라면 적어도 얼마가 필요합니까?",
        "question_en": "When I tried to hand out 98 sheets of colored drawing paper equally to 12 students, I was short of a few sheets. I'm going to buy more sheets of colored drawing paper to hand out the colored drawing paper equally. If a sheet of colored drawing paper costs 450 won, at least how much do I need?",
        "answer_ko": "4500",
        "answer_en": "4500",
        "solution_abst_ko": "12 98 12 [OP_MOD] [OP_SUB] 450 [OP_MUL]",
        "solution_abst_en": "12 98 12 [OP_MOD] [OP_SUB] 450 [OP_MUL]",
        "solution_code_ko": "var_a = 12\nvar_b = 98\nvar_c = 12\nvar_d = var_b % var_c\nvar_e = var_a - var_d\nvar_f = 450\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 12\nvar_b = 98\nvar_c = 12\nvar_d = var_b % var_c\nvar_e = var_a - var_d\nvar_f = 450\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "5462": {
        "category": "Geometry",
        "question_ko": "긴 대각선의 길이가 5/6미터(m)이고, 짧은 대각선의 길이가 4/6미터(m)인 마름모가 있습니다. 이 마름모의 대각선 길이의 차는 몇 미터(m)인지 구하시오.",
        "question_en": "A rhombus has a long diagonal of 5/6 meters (m) and a short diagonal of 4/6 meters (m). Find the difference in meters (m) between the diagonals of this rhombus.",
        "answer_ko": "0.17",
        "answer_en": "0.17",
        "solution_abst_ko": "5/6 4/6 [OP_SUB]",
        "solution_abst_en": "5/6 4/6 [OP_SUB]",
        "solution_code_ko": "var_a = 0.8333333333333334\nvar_b = 0.6666666666666666\nvar_c = var_a - var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 0.8333333333333334\nvar_b = 0.6666666666666666\nvar_c = var_a - var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "5463": {
        "category": "Geometry",
        "question_ko": "어떤 주사위는 한 모서리의 길이가 15센티미터(㎝)라고 합니다. 이 주사위의 모든 모서리의 길이의 합을 구하시오.",
        "question_en": "One edge in some dice is 15 centimeters (cm) long. Find the sum of the lengths of all edges of this dice.",
        "answer_ko": "180",
        "answer_en": "180",
        "solution_abst_ko": "15 4 3 [OP_MUL] [OP_MUL]",
        "solution_abst_en": "15 4 3 [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 15\nvar_b = 4\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 4\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nprint(int(var_e))"
    },
    "5464": {
        "category": "Arithmetic calculation",
        "question_ko": "(가) 반 학생들을 8개 조로 나누었습니다. 그중 6개 조는 각각 6명이고, 나머지 2개 조는 각각 7명입니다. (가) 반 학생은 모두 몇 명입니까?",
        "question_en": "The students were divided into 8 groups in class (A). Six of them have six people each, and the other two groups have 7 people each. How many students are in class (A)?",
        "answer_ko": "50",
        "answer_en": "50",
        "solution_abst_ko": "6 6 [OP_MUL] 2 7 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "6 6 [OP_MUL] 2 7 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = 7\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 6\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = 7\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "5465": {
        "category": "Possibility",
        "question_ko": "1, 4, 9를 중복으로 사용하여 만들 수 있는 세 자리의 짝수는 모두 몇 개입니까?",
        "question_en": "How many three-digit even numbers can be formed by using 1, 4, and 9 and allowing overlaps?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "[OP_LIST_SOL] 1 4 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 2 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 4 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 2 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 4\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 4\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "5466": {
        "category": "Correspondence",
        "question_ko": "어떤 수는 34보다 크고 18+18의 값보다 작습니다. 34, 35, 36, 37 중 어떤 수를 구하시오.",
        "question_en": "A certain number is greater than 34 and less than the value of 18+18. Find the number out of 34, 35, 36, and 37.",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "[OP_LIST_SOL] 34 35 36 37 [OP_LIST_EOL] 34 [OP_LIST_MORE] 18 18 [OP_ADD] [OP_LIST_LESS] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] 34 35 36 37 [OP_LIST_EOL] 34 [OP_LIST_MORE] 18 18 [OP_ADD] [OP_LIST_LESS] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 34\nvar_b = 35\nvar_c = 36\nvar_d = 37\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 34\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nvar_f = 18\nvar_g = 18\nvar_h = var_f + var_g\nlist_c = []\nfor i in list_b:\n    if i < var_h:\n        list_c.append(i)\nvar_i = 1\nvar_j = list_c[var_i-1]\nprint(int(var_j))",
        "solution_code_en": "var_a = 34\nvar_b = 35\nvar_c = 36\nvar_d = 37\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 34\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nvar_f = 18\nvar_g = 18\nvar_h = var_f + var_g\nlist_c = []\nfor i in list_b:\n    if i < var_h:\n        list_c.append(i)\nvar_i = 1\nvar_j = list_c[var_i-1]\nprint(int(var_j))"
    },
    "5467": {
        "category": "Possibility",
        "question_ko": "지철이는 0, 1, 2, 3, 4가 적혀 있는 숫자 카드를 가지고 있다. 이 중 카드 세 장을 골라 세 자리 수를 만들고자 한다. 만들었을 때 2, 3, 5로 나누어 떨어지는 수는 모두 몇 가지인가?",
        "question_en": "Jicheol has number cards with the numbers 0, 1, 2, 3, and 4 written on them. Of these, he chooses three cards to form a three-digit number. How many numbers are divisible by 2, 3, and 5?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 3 [OP_LCM] 5 [OP_LCM] [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 3 [OP_LCM] 5 [OP_LCM] [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 2\nvar_h = 3\nvar_i = var_h * var_g / math.gcd(int(var_h), int(var_g))\nvar_j = 5\nvar_k = var_j * var_i / math.gcd(int(var_j), int(var_i))\nlist_c = []\nvar_k = int(var_k)\nfor i in list_b:\n    i = int(i)\n    if i % var_k == 0:\n        list_c.append(i)\nvar_l = len(list_c)\nprint(int(var_l))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 2\nvar_h = 3\nvar_i = var_h * var_g / math.gcd(int(var_h), int(var_g))\nvar_j = 5\nvar_k = var_j * var_i / math.gcd(int(var_j), int(var_i))\nlist_c = []\nvar_k = int(var_k)\nfor i in list_b:\n    i = int(i)\n    if i % var_k == 0:\n        list_c.append(i)\nvar_l = len(list_c)\nprint(int(var_l))"
    },
    "5468": {
        "category": "Correspondence",
        "question_ko": "어떤 수로 49를 나누면 나머지가 4이고, 66을 나누면 나머지가 6입니다. 이때 어떤 수를 구하시오.",
        "question_en": "When you divide 49 by a certain number, the remainder is 4, and when you divide 66, the remainder is 6. Find what the certain number is.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "49 4 [OP_SUB] 66 6 [OP_SUB] [OP_GCD]",
        "solution_abst_en": "49 4 [OP_SUB] 66 6 [OP_SUB] [OP_GCD]",
        "solution_code_ko": "var_a = 49\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 66\nvar_e = 6\nvar_f = var_d - var_e\nvar_g = math.gcd(int(var_f), int(var_c))\nprint(int(var_g))",
        "solution_code_en": "var_a = 49\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 66\nvar_e = 6\nvar_f = var_d - var_e\nvar_g = math.gcd(int(var_f), int(var_c))\nprint(int(var_g))"
    },
    "5469": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 180 로 나누어야 할 것을 잘못하여 18 로 나누었더니 몫은 210 이고, 나머지는 2 가 되었습니다. 바르게 계산했을 때의 나머지를 구하시오.",
        "question_en": "You mistakenly divided a number by 180, so when you divided it by 18, the quotient was 210 and the remainder was 2. Find the remainder when calculated correctly.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "210 18 [OP_MUL] 2 [OP_ADD] 180 [OP_MOD]",
        "solution_abst_en": "210 18 [OP_MUL] 2 [OP_ADD] 180 [OP_MOD]",
        "solution_code_ko": "var_a = 210\nvar_b = 18\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c + var_d\nvar_f = 180\nvar_g = var_e % var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 210\nvar_b = 18\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c + var_d\nvar_f = 180\nvar_g = var_e % var_f\nprint(int(var_g))"
    },
    "5470": {
        "category": "Geometry",
        "question_ko": "주사위에서 마주 보는 면의 눈의 수의 합은 7입니다. 3의 눈이 그려진 면과 마주 보는 면의 눈의 수를 구하시오.",
        "question_en": "The sum of the numbers on the opposite sides of a dice is 7. Find the number of eyes on the side opposite to the side on which the eyes of 3 are drawn.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "7 3 [OP_SUB]",
        "solution_abst_en": "7 3 [OP_SUB]",
        "solution_code_ko": "var_a = 7\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 7\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "5471": {
        "category": "Correspondence",
        "question_ko": "A는 509입니다. A는 B보다 197만큼 큽니다. C는 B보다 125만큼 작습니다. C를 구하시오.",
        "question_en": "A is 509. A is greater than B by 197. C is less than B by 125. Find C.",
        "answer_ko": "187",
        "answer_en": "187",
        "solution_abst_ko": "509 197 [OP_SUB] 125 [OP_SUB]",
        "solution_abst_en": "509 197 [OP_SUB] 125 [OP_SUB]",
        "solution_code_ko": "var_a = 509\nvar_b = 197\nvar_c = var_a - var_b\nvar_d = 125\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 509\nvar_b = 197\nvar_c = var_a - var_b\nvar_d = 125\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "5472": {
        "category": "Comparison",
        "question_ko": "28 초과 31 이하인 자연수 중 둘째로 큰 수는 얼마인지 구하시오.",
        "question_en": "What is the second largest natural number greater than 28 and less than or equal to 31?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "28 1 [OP_ADD] 31 1 [OP_LIST_ARANGE] 2 [OP_LIST_MAX]",
        "solution_abst_en": "28 1 [OP_ADD] 31 1 [OP_LIST_ARANGE] 2 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 28\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 31\nvar_e = 1\nlist_a = [i for i in range(var_c, var_d + 1, var_e)]\nvar_f = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nprint(int(var_g))",
        "solution_code_en": "var_a = 28\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 31\nvar_e = 1\nlist_a = [i for i in range(var_c, var_d + 1, var_e)]\nvar_f = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nprint(int(var_g))"
    },
    "5473": {
        "category": "Correspondence",
        "question_ko": "연못에 물고기와 새가 합쳐서 93마리가 있다. 물고기는 66마리가 있고 새는 하루에 1마리씩 물고기를 잡아먹는다. 다음날 물고기 21마리가 새로 연못에 들어왔고 새들이 물고기를 잡아먹었다면 연못에 물고기는 몇 마리가 있습니까?",
        "question_en": "There are 93 fish and birds in the pond. There are 66 fish and the bird eats one fish per day. If 21 new fish came into the pond the next day and the birds ate the fish, how many fish are in the pond?",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "66 93 66 [OP_SUB] [OP_SUB] 21 [OP_ADD]",
        "solution_abst_en": "66 93 66 [OP_SUB] [OP_SUB] 21 [OP_ADD]",
        "solution_code_ko": "var_a = 66\nvar_b = 93\nvar_c = 66\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nvar_f = 21\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 66\nvar_b = 93\nvar_c = 66\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nvar_f = 21\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "5474": {
        "category": "Possibility",
        "question_ko": "딸기, 배, 포도 중에 2종류의 과일을 골라 키우려고 합니다. 과일을 고르는 총 몇 가지 경우가 있을까요?",
        "question_en": "You are trying to pick and grow two kinds of fruits out of strawberries, pears, and grapes. How many cases are there in total to choose the fruit?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 딸기 배 포도 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] strawberries pears grapes [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '딸기'\nvar_b = '배'\nvar_c = '포도'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f / (i+1)\nprint(int(var_f))",
        "solution_code_en": "var_a = 'strawberries'\nvar_b = 'pears'\nvar_c = 'grapes'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f / (i+1)\nprint(int(var_f))"
    },
    "5475": {
        "category": "Arithmetic calculation",
        "question_ko": "4개 반의 국어 시험 평균이 각각 64, 73, 69, 82라고 한다. 평균이 70점을 못 넘는 반의 평균 점수의 합을 구하시오.",
        "question_en": "It is said that the average of the four classes of Korean exams is 64, 73, 69, and 82, respectively. Find the sum of the average scores of the classes whose average was less than 70.",
        "answer_ko": "133",
        "answer_en": "133",
        "solution_abst_ko": "[OP_LIST_SOL] 64 73 69 82 [OP_LIST_EOL] 70 [OP_LIST_LESS] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 64 73 69 82 [OP_LIST_EOL] 70 [OP_LIST_LESS] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 64\nvar_b = 73\nvar_c = 69\nvar_d = 82\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 70\nlist_b = []\nfor i in list_a:\n    if i < var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 64\nvar_b = 73\nvar_c = 69\nvar_d = 82\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 70\nlist_b = []\nfor i in list_a:\n    if i < var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint(int(var_f))"
    },
    "5476": {
        "category": "Possibility",
        "question_ko": "4, 5, 8 숫자카드를 한 번씩 모두 사용하였을 때, 550보다 큰 세 자리 수의 개수를 구하시오.",
        "question_en": " Find the number of three-digit numbers greater than 550, when all 4, 5, and 8 figures are used once.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 4 5 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 550 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 4 5 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 550 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 4\nvar_b = 5\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 550\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 4\nvar_b = 5\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 550\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "5477": {
        "category": "Arithmetic calculation",
        "question_ko": "가민이는 숫자가 적힌 로봇을 일렬로 배열해 세 자리의 수를 표현하는 활동을 하고 있다. 2, 3, 5가 적힌 로봇으로는 만들 수 있는 가장 큰 수를 만들었고, 4, 0, 6이 적힌 로봇을 사용해서는 가장 작은 수를 만들었다. 두 수의 차이는 얼마인지 구하시오.",
        "question_en": "Gamin is doing an activity to express a three-digit number by arranging robots with numbers written on them in a row. The robots with 2, 3, and 5 made the largest possible number, and the robots with 4, 0, and 6 made the smallest possible number. Find the value of difference between the two numbers.",
        "answer_ko": "126",
        "answer_en": "126",
        "solution_abst_ko": "[OP_LIST_SOL] 2 3 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] [OP_LIST_SOL] 4 0 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 2 3 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] [OP_LIST_SOL] 4 0 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 4\nvar_h = 0\nvar_i = 6\nlist_d= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_d.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_d.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_d.append(var_g)\nlist_d.reverse()\nvar_j = 3\nlist_e = [str(i) for i in list_d]\nlist_e = list(itertools.permutations(list_e, var_j))\nlist_e = [''.join(num_list) for num_list in list_e]\nlist_e = [str_num for str_num in list_e if str_num[0] != '0']\nlist_e = [float(i) for i in list_e]\nvar_k = 1\nlist_f=list_e.copy()\nlist_f.sort()\nvar_l = list_f[var_k-1]\nvar_m = var_f - var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 4\nvar_h = 0\nvar_i = 6\nlist_d= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_d.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_d.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_d.append(var_g)\nlist_d.reverse()\nvar_j = 3\nlist_e = [str(i) for i in list_d]\nlist_e = list(itertools.permutations(list_e, var_j))\nlist_e = [''.join(num_list) for num_list in list_e]\nlist_e = [str_num for str_num in list_e if str_num[0] != '0']\nlist_e = [float(i) for i in list_e]\nvar_k = 1\nlist_f=list_e.copy()\nlist_f.sort()\nvar_l = list_f[var_k-1]\nvar_m = var_f - var_l\nprint(int(var_m))"
    },
    "5478": {
        "category": "Correspondence",
        "question_ko": "윤기는 두 자리 수와 57의 덧셈을 하려 합니다. 윤기는 두 자리 수의 일의 자리 숫자 9를 6으로 잘못 보았습니다. 윤기가 구한 합은 123 일 때, 두 자리 수를 구하시오.",
        "question_en": "Yoongi wants to add a two-digit number to 57. Yoongi misread 9 in the units digit of the two-digit number as 6. When Yoongi got a result of 123, find the two-digit number.",
        "answer_ko": "69",
        "answer_en": "69",
        "solution_abst_ko": "123 57 [OP_SUB] 6 9 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "123 57 [OP_SUB] 6 9 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 123\nvar_b = 57\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 123\nvar_b = 57\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "5479": {
        "category": "Comparison",
        "question_ko": "1.4, 9/10, 1.2, 0.5, 13/10에서 1.1보다 작은 숫자는 몇 개 일까요?",
        "question_en": "How many numbers are less than 1.1 in 1.4, 9/10, 1.2, 0.5, 13/10?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i < var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i < var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "5480": {
        "category": "Correspondence",
        "question_ko": "서로 다른 두 수 A, B가 있습니다. 두 자리 수끼리의 덧셈식 A4+3B=79에서 A를 구하시오.",
        "question_en": "There are two different numbers A and B. Find A from the two-digit addition equation A4+3B=79.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "A4+3B=79 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A4+3B=79 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A4+3B=79'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A4+3B=79'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "5481": {
        "category": "Geometry",
        "question_ko": "직육면체의 어느 한 면에서의 대각선을 그었습니다. 이 대각선과 꼬인 위치에 있는 선분은 모두 몇 개일까요?",
        "question_en": "A diagonal line is drawn from one side of the cuboid. How many line segments skew to this diagonal are there?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "6",
        "solution_abst_en": "6",
        "solution_code_ko": "var_a = 6\nprint(int(var_a))",
        "solution_code_en": "var_a = 6\nprint(int(var_a))"
    },
    "5482": {
        "category": "Comparison",
        "question_ko": "미란이는 색종이를 6장 가지고 있고, 정아는 색종이를 13장 가지고 있고, 민수는 색종이를 10장 가지고 있습니다. 색종이를 가장 적게 가지고 있는 사람은 누구입니까?",
        "question_en": "Miran has 6 pieces of colored paper, Junga has 13 pieces of colored paper, and Minsu has 10 pieces of colored paper. Who has the fewest colored paper?",
        "answer_ko": "미란",
        "answer_en": "Miran",
        "solution_abst_ko": "[OP_LIST_SOL] 미란 정아 민수 [OP_LIST_EOL] [OP_LIST_SOL] 6 13 10 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Miran Junga Minsu [OP_LIST_EOL] [OP_LIST_SOL] 6 13 10 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '미란'\nvar_b = '정아'\nvar_c = '민수'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 6\nvar_e = 13\nvar_f = 10\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Miran'\nvar_b = 'Junga'\nvar_c = 'Minsu'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 6\nvar_e = 13\nvar_f = 10\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "5483": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 5를 뺀 것의 4배는 다시 어떤 수와 같아집니다. 어떤 수를 구하시오.",
        "question_en": "If you subtract 5 from a number and mulitpy 4 to that value, it equals this number again. Find this number. ",
        "answer_ko": "6.67",
        "answer_en": "6.67",
        "solution_abst_ko": "5 4 [OP_MUL] 4 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "5 4 [OP_MUL] 4 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 5\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 5\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "5484": {
        "category": "Geometry",
        "question_ko": "기민이는 한 모서리의 길이가 1미터(m)인 정육면체를 가지고 있고, 기영이는 가로 50센티미터(㎝), 세로 50센티미터(㎝), 높이 20센티미터(㎝)인 직육면체를 가지고 있습니다. 기민이가 가진 정육면체의 부피는 기영이가 가진 직육면체의 부피의 몇 배입니까?",
        "question_en": "Ki-min has a cube with one edge 1 meter (m) long, and Ki-young has a cuboid with a width of 50 centimeters (cm), a length of 50 centimeters (cm) and a height of 20 centimeters (cm). How many times the volume of Ki-min's cube is the volume of Ki-yeong's cuboid?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "1 100 [OP_MUL] 3 [OP_POW] 50 50 [OP_MUL] 20 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "1 100 [OP_MUL] 3 [OP_POW] 50 50 [OP_MUL] 20 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c ** var_d\nvar_f = 50\nvar_g = 50\nvar_h = var_f * var_g\nvar_i = 20\nvar_j = var_h * var_i\nvar_k = var_e / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 1\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c ** var_d\nvar_f = 50\nvar_g = 50\nvar_h = var_f * var_g\nvar_i = 20\nvar_j = var_h * var_i\nvar_k = var_e / var_j\nprint(int(var_k))"
    },
    "5485": {
        "category": "Arithmetic calculation",
        "question_ko": "동환이는 100개가 들어있는 구슬 상자에서 11개의 구슬을 꺼냈습니다. 동환이가 꺼낸 구슬 전체 구슬의 얼마인지 소수로 나타내시오.",
        "question_en": "Donghwan took out 11 marbles from a box of 100 marbles. Express how many marbles Donghwan took out of all the marbles as a decimal number.",
        "answer_ko": "0.11",
        "answer_en": "0.11",
        "solution_abst_ko": "11 100 [OP_DIV]",
        "solution_abst_en": "11 100 [OP_DIV]",
        "solution_code_ko": "var_a = 11\nvar_b = 100\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 11\nvar_b = 100\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "5486": {
        "category": "Arithmetic calculation",
        "question_ko": "자전거를 타고 일정한 빠르기로 혜미는 20분에 1.25킬로미터(㎞)를 가고 태수는 15분에 0.96킬로미터(㎞)를 갑니다. 두 사람이 같은 곳에서 서로 반대 방향으로 동시에 출발하면 1시간 후에 두 사람 사이의 거리는 몇 킬로미터(㎞)인지 구해 보시오.",
        "question_en": "When riding a bicycle at a constant speed, Hyemi travels 1.25 kilometers (km) in 20 minutes and Taesu travels 0.96 kilometers (km) in 15 minutes. If two people ride a bicycle in opposite directions starting at the same place and same time, find the distance in kilometers (km) between them after 1 hour.",
        "answer_ko": "7.59",
        "answer_en": "7.59",
        "solution_abst_ko": "1.25 20 60 [OP_DIV] [OP_DIV] 0.96 15 60 [OP_DIV] [OP_DIV] [OP_ADD]",
        "solution_abst_en": "1.25 20 60 [OP_DIV] [OP_DIV] 0.96 15 60 [OP_DIV] [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 1.25\nvar_b = 20\nvar_c = 60\nvar_d = var_b / var_c\nvar_e = var_a / var_d\nvar_f = 0.96\nvar_g = 15\nvar_h = 60\nvar_i = var_g / var_h\nvar_j = var_f / var_i\nvar_k = var_e + var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 1.25\nvar_b = 20\nvar_c = 60\nvar_d = var_b / var_c\nvar_e = var_a / var_d\nvar_f = 0.96\nvar_g = 15\nvar_h = 60\nvar_i = var_g / var_h\nvar_j = var_f / var_i\nvar_k = var_e + var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "5487": {
        "category": "Arithmetic calculation",
        "question_ko": "모든 세 자리 수의 합을 구하시오",
        "question_en": "Find the sum of all three-digit numbers.",
        "answer_ko": "494550",
        "answer_en": "494550",
        "solution_abst_ko": "100 999 1 [OP_LIST_ARANGE] [OP_LIST_SUM]",
        "solution_abst_en": "100 999 1 [OP_LIST_ARANGE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_a = [float(i) for i in list_a]\nvar_d = sum(list_a)\nprint(int(var_d))",
        "solution_code_en": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_a = [float(i) for i in list_a]\nvar_d = sum(list_a)\nprint(int(var_d))"
    },
    "5488": {
        "category": "Correspondence",
        "question_ko": "2, 3, 4, 5, 중 3이 아닌 4보다 작은 수를 구하시오.",
        "question_en": "Among 2, 3, 4, and 5, find the number less than 4 that is not 3.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 2 3 4 5 [OP_LIST_EOL] 4 [OP_LIST_LESS] [OP_LIST_SOL] 3 [OP_LIST_EOL] [OP_SET_DIFFERENCE] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] 2 3 4 5 [OP_LIST_EOL] 4 [OP_LIST_LESS] [OP_LIST_SOL] 3 [OP_LIST_EOL] [OP_SET_DIFFERENCE] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = 4\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = []\nfor i in list_a:\n    if i < var_e:\n        list_b.append(i)\nvar_f = 3\nlist_c= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_c.append(var_f)\nlist_c.reverse()\nlist_d = list(set(list_b) - set(list_c))\nvar_g = 1\nvar_h = list_d[var_g-1]\nprint(int(var_h))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = 4\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = []\nfor i in list_a:\n    if i < var_e:\n        list_b.append(i)\nvar_f = 3\nlist_c= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_c.append(var_f)\nlist_c.reverse()\nlist_d = list(set(list_b) - set(list_c))\nvar_g = 1\nvar_h = list_d[var_g-1]\nprint(int(var_h))"
    },
    "5489": {
        "category": "Correspondence",
        "question_ko": "서로 다른 두 수 A, B가 있습니다. 두 자리 수끼리의 뺄셈식 7A-B6=23에서 A와 B의 합을 구하시오.",
        "question_en": "There are two different numbers, A and B. Find the sum of A and B in the two-digit subtraction equation 7A-B6=23.",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "7A-B6=23 A [OP_DIGIT_UNK_SOLVER] 7A-B6=23 B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_abst_en": "7A-B6=23 A [OP_DIGIT_UNK_SOLVER] 7A-B6=23 B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_code_ko": "var_a = '7A-B6=23'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '7A-B6=23'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = '7A-B6=23'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '7A-B6=23'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "5490": {
        "category": "Correspondence",
        "question_ko": "세 자리 수 7AB는 3으로 나누어떨어지는 수입니다. A, B는 0부터 9까지의 서로 다른 수일 때 7AB가 될 수 있는 수는 모두 몇 개입니까?",
        "question_en": "The three-digit number 7AB is divisible by 3. If A and B are different numbers from 0 to 9, how many possible ways are there to be 7AB?",
        "answer_ko": "33",
        "answer_en": "33",
        "solution_abst_ko": "7AB [OP_GEN_POSSIBLE_LIST] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "7AB [OP_GEN_POSSIBLE_LIST] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '7AB'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 3\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))",
        "solution_code_en": "var_a = '7AB'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 3\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))"
    },
    "5491": {
        "category": "Arithmetic calculation",
        "question_ko": "오렌지 주스 한 병에는 1리터(L)가 들어있습니다. 한 병으로 세 친구가 나눠 먹기로 했는데, 영인이가 0.1리터(L)를 마셨고 나린이가 영인이보다 0.2리터(L)를 더 마셨습니다. 나린이가 동우에게 병을 건네주려는 순간 주스를 쏟고 말았습니다. 남은 오렌지 주스가 0.3리터(L)라면 쏟아진 주스는 몇 리터(L)입니까?",
        "question_en": "A bottle of orange juice contains 1 liter (L) of juice. Three friends decided to share one bottle, but Youngin drank only 0.1 liters (L), and Narin drank 0.2 liters (L) more than Youngin. The moment Narin was about to hand the bottle to Dongwoo, the juice spilled out. If there are 0.3 liters (L) of orange juice left, how many liters (L) of juice was spilled?",
        "answer_ko": "0.30",
        "answer_en": "0.3",
        "solution_abst_ko": "1 0.1 [OP_SUB] 0.1 0.2 [OP_ADD] [OP_SUB] 0.3 [OP_SUB]",
        "solution_abst_en": "1 0.1 [OP_SUB] 0.1 0.2 [OP_ADD] [OP_SUB] 0.3 [OP_SUB]",
        "solution_code_ko": "var_a = 1\nvar_b = 0.1\nvar_c = var_a - var_b\nvar_d = 0.1\nvar_e = 0.2\nvar_f = var_d + var_e\nvar_g = var_c - var_f\nvar_h = 0.3\nvar_i = var_g - var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 0.1\nvar_c = var_a - var_b\nvar_d = 0.1\nvar_e = 0.2\nvar_f = var_d + var_e\nvar_g = var_c - var_f\nvar_h = 0.3\nvar_i = var_g - var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "5492": {
        "category": "Comparison",
        "question_ko": "상원이의 한 뼘은 19센티미터(㎝) 8밀리미터(㎜)이고, 도윤이의 한 뼘은 18.9센티미터(㎝)이며, 창혁이의 한 뼘은 19.3센티미터(㎝)입니다. 한 뼘의 길이가 가장 짧은 사람은 누구입니까?",
        "question_en": "Sangwon's handspan is 19 centimeters (cm) 8 millimeters (mm), Doyoon's handspan is 18.9 centimeters (cm), and Changhyeok's handspan is 19.3 centimeters (cm). Whose handspan is shortest?",
        "answer_ko": "도윤",
        "answer_en": "Doyoon",
        "solution_abst_ko": "[OP_LIST_SOL] 상원 도윤 창혁 [OP_LIST_EOL] [OP_LIST_SOL] 19 8 10 [OP_DIV] [OP_ADD] 18.9 19.3 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Sangwon Doyoon Changhyeok [OP_LIST_EOL] [OP_LIST_SOL] 19 8 10 [OP_DIV] [OP_ADD] 18.9 19.3 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '상원'\nvar_b = '도윤'\nvar_c = '창혁'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 19\nvar_e = 8\nvar_f = 10\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = 18.9\nvar_j = 19.3\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[var_k-1]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'Sangwon'\nvar_b = 'Doyoon'\nvar_c = 'Changhyeok'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 19\nvar_e = 8\nvar_f = 10\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = 18.9\nvar_j = 19.3\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[var_k-1]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "5493": {
        "category": "Correspondence",
        "question_ko": "24를 A로 나누면 몫이 B가 되고, 나머지는 4가 됩니다. A와 B는 모두 자연수입니다. 가능한 A 중 가장 큰 수의 값을 구하시오.",
        "question_en": "When 24 can be divided by A, the quotient is B, and the remainder is 4. A and B are both natural numbers. Find the possible largest value of A.",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "24 4 [OP_SUB]",
        "solution_abst_en": "24 4 [OP_SUB]",
        "solution_code_ko": "var_a = 24\nvar_b = 4\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 24\nvar_b = 4\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "5494": {
        "category": "Comparison",
        "question_ko": "형제의 키 차이는 12센티미터(㎝)이고, 합은 3미터(m) 8센티미터(㎝)입니다. 동생의 키가 더 작을 때, 동생의 키는 얼마입니까?",
        "question_en": "The difference in height between the brothers is 12 centimeters (cm), and the sum is 3 meters (m) and 8 centimeters (cm). What is the younger brother's height when the younger brother is shorter?",
        "answer_ko": "148",
        "answer_en": "148",
        "solution_abst_ko": "3 100 [OP_MUL] 8 [OP_ADD] 12 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "3 100 [OP_MUL] 8 [OP_ADD] 12 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 3\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c + var_d\nvar_f = 12\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 3\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c + var_d\nvar_f = 12\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "5495": {
        "category": "Possibility",
        "question_ko": "1, 4, 5을 한 번씩 모두 사용하여 만들 수 있는 가장 작은 수를 구하시오.",
        "question_en": "Find the smallest number that can be made by using 1, 4, and 5 once.",
        "answer_ko": "145",
        "answer_en": "145",
        "solution_abst_ko": "[OP_LIST_SOL] 1 4 5 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 4 5 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1\nvar_b = 4\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 4\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nprint(int(var_f))"
    },
    "5496": {
        "category": "Correspondence",
        "question_ko": "3으로 나누면 2가 남고, 8로 나누면 5가 남는 수 중에서 20째로 작은 수를 구하여라.",
        "question_en": "Find the 20th smallest number that leaves a remainder of 2 when divided by 3 and a remainder of 5 when divided by 8.",
        "answer_ko": "461",
        "answer_en": "461",
        "solution_abst_ko": "0 9999 1 [OP_LIST_ARANGE] 3 2 [OP_LIST_DIVIDE_AND_REMAIN] 8 5 [OP_LIST_DIVIDE_AND_REMAIN] 20 [OP_LIST_MIN]",
        "solution_abst_en": "0 9999 1 [OP_LIST_ARANGE] 3 2 [OP_LIST_DIVIDE_AND_REMAIN] 8 5 [OP_LIST_DIVIDE_AND_REMAIN] 20 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 0\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nvar_e = 2\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 8\nvar_g = 5\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 20\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nprint(int(var_i))",
        "solution_code_en": "var_a = 0\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nvar_e = 2\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 8\nvar_g = 5\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 20\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nprint(int(var_i))"
    },
    "5497": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 4를 곱하고 23을 뺐더니 33이 되었습니다. 어떤 수를 구하시오.",
        "question_en": "When you multiply a number by 4 and subtract 23, you get 33. Find a number.",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "33 23 [OP_ADD] 4 [OP_DIV]",
        "solution_abst_en": "33 23 [OP_ADD] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 33\nvar_b = 23\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 33\nvar_b = 23\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "5498": {
        "category": "Correspondence",
        "question_ko": "윤기는 어떤 수에 37을 빼려고 합니다. 하지만 실수로 9를 나누었더니 결과는 30이 되었습니다. 바르게 계산한 결과를 구하세요.",
        "question_en": "Yoongi wants to subtract 37 from some number. But when he accidentally divided by 9, the result was 30. Find the correct calculation result.",
        "answer_ko": "233",
        "answer_en": "233",
        "solution_abst_ko": "30 9 [OP_MUL] 37 [OP_SUB]",
        "solution_abst_en": "30 9 [OP_MUL] 37 [OP_SUB]",
        "solution_code_ko": "var_a = 30\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 37\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 30\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 37\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "5499": {
        "category": "Correspondence",
        "question_ko": "한 자리 수 A, B로 여섯 자리 수 7ABABA를 만들었습니다. 이 수가 6의 배수일 때 이 수가 될 수 있는 모든 수의 개수는 무엇입니까?",
        "question_en": "The single digit numbers A and B make the six digit number 7ABABA. If this number is a multiple of 6, what is the number of all possible cases that this number can be?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "7ABABA [OP_GEN_POSSIBLE_LIST] 6 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "7ABABA [OP_GEN_POSSIBLE_LIST] 6 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '7ABABA'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 6\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))",
        "solution_code_en": "var_a = '7ABABA'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 6\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))"
    },
    "5500": {
        "category": "Comparison",
        "question_ko": "물고기 A, B, C, D가 먹이를 먹고 있습니다. A는 D보다 많은 먹이를 먹었고, C는 A보다 적은 먹이를 먹었습니다. B는 A보다 많은 먹이를 먹었을 때, 가장 많은 먹이를 먹은 물고기는 무엇인가요?",
        "question_en": "Fish A, B, C, and D are feeding. A ate more food than D, and C ate less food than A. If B ate more food than A, which fish ate the most?",
        "answer_ko": "B",
        "answer_en": "B",
        "solution_abst_ko": "[OP_LIST_SOL] A B C D [OP_LIST_EOL] [OP_LIST_SOL] A D > C A < B A > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D [OP_LIST_EOL] [OP_LIST_SOL] A D > C A < B A > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'A'\nvar_f = 'D'\nvar_g = '>'\nvar_h = 'C'\nvar_i = 'A'\nvar_j = '<'\nvar_k = 'B'\nvar_l = 'A'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = 1\nvar_o = list_c[var_n-1]\nprint(var_o)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'A'\nvar_f = 'D'\nvar_g = '>'\nvar_h = 'C'\nvar_i = 'A'\nvar_j = '<'\nvar_k = 'B'\nvar_l = 'A'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = 1\nvar_o = list_c[var_n-1]\nprint(var_o)"
    },
    "5501": {
        "category": "Arithmetic calculation",
        "question_ko": "2킬로그램(㎏)의 방울토마토가 들어있는 상자에 560그램(g)의 방울토마토를 더 넣었습니다. 방울토마토의 무게는 모두 몇 그램(g)입니까?",
        "question_en": "In a box containing 2 kilograms (kg) of cherry tomatoes, 560 grams (g) of extra cherry tomatoes were added. How many grams (g) do all the cherry tomatoes weigh?",
        "answer_ko": "2560",
        "answer_en": "2560",
        "solution_abst_ko": "2 1000 [OP_MUL] 560 [OP_ADD]",
        "solution_abst_en": "2 1000 [OP_MUL] 560 [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 560\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 560\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "5502": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 5센티미터(㎝)인 정삼각형의 둘레는 몇 센티미터(㎝)입니까?",
        "question_en": "What is the perimeter of an equilateral triangle with a side of 5 centimeters (cm)?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "5 3 [OP_MUL]",
        "solution_abst_en": "5 3 [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "5503": {
        "category": "Correspondence",
        "question_ko": "유나는 42에 어떤 수를 나누려고 합니다. 실수로 35에 어떤 수를 나눴을 때의 결과가 5라면 바르게 계산한 결과를 구하세요.",
        "question_en": "Yuna wants to divide 42 by a number. When she accidentally divided 35 by the number and the result was 5, Find the correct result.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "42 35 5 [OP_DIV] [OP_DIV]",
        "solution_abst_en": "42 35 5 [OP_DIV] [OP_DIV]",
        "solution_code_ko": "var_a = 42\nvar_b = 35\nvar_c = 5\nvar_d = var_b / var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 42\nvar_b = 35\nvar_c = 5\nvar_d = var_b / var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "5504": {
        "category": "Arithmetic calculation",
        "question_ko": "1개에 150원인 사탕 269개를 29명의 학생에게 똑같이 나누어 주려고 하였더니 몇 개가 모자랐습니다. 모자란 사탕을 사려면 적어도 얼마가 더 필요한지 구해 보시오.",
        "question_en": "I tried to hand out 269 candies, which costs 150 won each, equally to 29 students, but a few candies were short. Find at least how much more money I need to buy the lacking candies.",
        "answer_ko": "3150",
        "answer_en": "3150",
        "solution_abst_ko": "29 269 29 [OP_MOD] [OP_SUB] 150 [OP_MUL]",
        "solution_abst_en": "29 269 29 [OP_MOD] [OP_SUB] 150 [OP_MUL]",
        "solution_code_ko": "var_a = 29\nvar_b = 269\nvar_c = 29\nvar_d = var_b % var_c\nvar_e = var_a - var_d\nvar_f = 150\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 29\nvar_b = 269\nvar_c = 29\nvar_d = var_b % var_c\nvar_e = var_a - var_d\nvar_f = 150\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "5505": {
        "category": "Arithmetic calculation",
        "question_ko": "민호는 빈대떡을 똑같이 5조각으로 나누어 한 조각을 먹었습니다. 윤아는 같은 크기의 빈대떡을 똑같이 10조각으로 나누었습니다. 민호와 같은 양을 먹으려면 윤아는 몇 조각을 먹어야 합니까?",
        "question_en": "Minho divided the bindaetteok into 5 equal pieces and ate one. Yoona divided the same size of bindaetteok into 10 equal pieces. How many pieces will Yoona have to eat, to eat the same amount as Minho?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "10 5 [OP_DIV]",
        "solution_abst_en": "10 5 [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 5\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 10\nvar_b = 5\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "5506": {
        "category": "Comparison",
        "question_ko": "기윤이와 서연이가 1000미터(m)인 도로의 길이를 어림했습니다. 기윤이는 940미터(m)로 어림했고 서연이는 1080미터(m)로 어림했다면 실제와 더 가깝게 어림한 사람은 누구입니까?",
        "question_en": "Kiyoon and Seoyeon estimated the length of a road that is 1000 meters (m). If Kiyoon's estimate was 940 meters (m) and Seoyeon's estimate was 1080 meters (m), who made the estimate closer to reality?",
        "answer_ko": "기윤",
        "answer_en": "Kiyoon",
        "solution_abst_ko": "[OP_LIST_SOL] 기윤 서연 [OP_LIST_EOL] [OP_LIST_SOL] 1000 940 [OP_SUB] [OP_ABS] 1000 1080 [OP_SUB] [OP_ABS] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Kiyoon Seoyeon [OP_LIST_EOL] [OP_LIST_SOL] 1000 940 [OP_SUB] [OP_ABS] 1000 1080 [OP_SUB] [OP_ABS] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '기윤'\nvar_b = '서연'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1000\nvar_d = 940\nvar_e = var_c - var_d\nvar_f = abs(var_e)\nvar_g = 1000\nvar_h = 1080\nvar_i = var_g - var_h\nvar_j = abs(var_i)\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[var_k-1]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'Kiyoon'\nvar_b = 'Seoyeon'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1000\nvar_d = 940\nvar_e = var_c - var_d\nvar_f = abs(var_e)\nvar_g = 1000\nvar_h = 1080\nvar_i = var_g - var_h\nvar_j = abs(var_i)\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[var_k-1]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "5507": {
        "category": "Correspondence",
        "question_ko": "백의 자리 수와 일의 자리 수가 모두 5인 세 자리 수를 십의 자리에서 버림하면 500이 됩니다. 십의 자리 수를 A라고 할 때, 0부터 9까지의 숫자 중 A에 쓸 수 있는 수들의 합을 구하시오.",
        "question_en": "When you round down the three-digit number 5A5 to the tens place, it becomes 500. Find the sum of the numbers from 0 to 9 that can be used for A.",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "[OP_LIST_SOL] 5 A 5 [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 600 [OP_LIST_LESS_EQUAL] A [OP_LIST_FIND_UNK] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 5 A 5 [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 600 [OP_LIST_LESS_EQUAL] A [OP_LIST_FIND_UNK] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 5\nvar_b = 'A'\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nans_dict = dict()\nvar_d = str(var_d)\nlist_b = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_d) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_b.append(new_elem)\nvar_e = 600\nlist_c = []\nfor i in list_b:\n    if i <= var_e:\n        list_c.append(i)\nvar_f = 'A'\nvar_d = str(var_d)\nvar_f = str(var_f)\nunk_idx = var_d.index(var_f)\nlist_d = []\nfor elem in list_c:\n    elem = str(elem)\n    list_d.append(int(elem[unk_idx]))\nlist_d = list(set(list_d))\nlist_d = [float(i) for i in list_d]\nvar_g = sum(list_d)\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 'A'\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nans_dict = dict()\nvar_d = str(var_d)\nlist_b = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_d) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_b.append(new_elem)\nvar_e = 600\nlist_c = []\nfor i in list_b:\n    if i <= var_e:\n        list_c.append(i)\nvar_f = 'A'\nvar_d = str(var_d)\nvar_f = str(var_f)\nunk_idx = var_d.index(var_f)\nlist_d = []\nfor elem in list_c:\n    elem = str(elem)\n    list_d.append(int(elem[unk_idx]))\nlist_d = list(set(list_d))\nlist_d = [float(i) for i in list_d]\nvar_g = sum(list_d)\nprint(int(var_g))"
    },
    "5508": {
        "category": "Correspondence",
        "question_ko": "8을 어떤 수에 더했더니 결과가 88이 되었습니다. 어떤 수를 10으로 나누면 얼마인가요?",
        "question_en": "When 8 is added to a number, the result is 88. What is the result when the number is divided by 10?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "88 8 [OP_SUB] 10 [OP_DIV]",
        "solution_abst_en": "88 8 [OP_SUB] 10 [OP_DIV]",
        "solution_code_ko": "var_a = 88\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 10\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 88\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 10\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "5509": {
        "category": "Geometry",
        "question_ko": "지혜는 밑변이 3센티미터(㎝) 이고 높이가 2센티미터(㎝) 인 삼각형을 그렸고, 동건이는 밑변이 3센티미터(㎝) 이고 높이가 6.02 센티미터(㎝) 인 삼각형을 그렸습니다. 동건이가 그린 삼각형의 넓이는 지혜가 그린 삼각형의 넓이의 몇 배입니까?",
        "question_en": "Jihye drew a triangle with a base of 3 cm (cm) and a height of 2 cm (cm), and Donggeon drew a triangle with a base of 3 cm (cm) and a height of 6.02 cm (cm). How many times the area of the triangle drawn by Donggeon is the area of the triangle drawn by Jihye?",
        "answer_ko": "3.01",
        "answer_en": "3.01",
        "solution_abst_ko": "3 6.02 [OP_MUL] 2 [OP_DIV] 3 2 [OP_MUL] 2 [OP_DIV] [OP_DIV]",
        "solution_abst_en": "3 6.02 [OP_MUL] 2 [OP_DIV] 3 2 [OP_MUL] 2 [OP_DIV] [OP_DIV]",
        "solution_code_ko": "var_a = 3\nvar_b = 6.02\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 3\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = 2\nvar_j = var_h / var_i\nvar_k = var_e / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 3\nvar_b = 6.02\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 3\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = 2\nvar_j = var_h / var_i\nvar_k = var_e / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "5510": {
        "category": "Arithmetic calculation",
        "question_ko": "드라마를 1초 동안 상영하려면 그림 30장이 필요합니다. 드라마를 25초 상영하려면 그림이 몇 장 필요할까요?",
        "question_en": "When it takes 30 pictures to play a drama for 1 second, how many pictures are needed to play 25 seconds?",
        "answer_ko": "750",
        "answer_en": "750",
        "solution_abst_ko": "30 25 [OP_MUL]",
        "solution_abst_en": "30 25 [OP_MUL]",
        "solution_code_ko": "var_a = 30\nvar_b = 25\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 30\nvar_b = 25\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "5511": {
        "category": "Geometry",
        "question_ko": "두 대각선이 각 14센티미터(㎝), 24센티미터(㎝)인 마름모의 넓이를 구하시오.",
        "question_en": "Find the area of a rhombus whose two diagonals are 14 centimeters (cm) and 24 centimeters (cm).",
        "answer_ko": "168",
        "answer_en": "168",
        "solution_abst_ko": "14 24 [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "14 24 [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 14\nvar_b = 24\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 14\nvar_b = 24\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "5512": {
        "category": "Possibility",
        "question_ko": "사과, 복숭아, 배가 각각 하나씩 있는 바구니에서 뺄 기회는 2번입니다. 나올 수 있는 과일의 순서는 모두 몇 가지입니까?",
        "question_en": "You have 2 chances to draw from a basket that has one apple, one peach, and one pear each. How many orders of fruit can there be?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 복숭아 배 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] apple peach pear [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '복숭아'\nvar_c = '배'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nprint(int(var_f))",
        "solution_code_en": "var_a = 'apple'\nvar_b = 'peach'\nvar_c = 'pear'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nprint(int(var_f))"
    },
    "5513": {
        "category": "Correspondence",
        "question_ko": "25를 A로 나눴더니 몫이 3이 되었고 나머지가 B가 되었습니다. A와 B는 자연수입니다. 가능한 A중 가장 큰 수는 무엇일까요?",
        "question_en": "When 25 is divided by A, the quotient is 3 and the remainder is B. A and B are natural numbers. What is the largest possible number A?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "25 1 [OP_SUB] 3 [OP_FDIV]",
        "solution_abst_en": "25 1 [OP_SUB] 3 [OP_FDIV]",
        "solution_code_ko": "var_a = 25\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 25\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "5514": {
        "category": "Geometry",
        "question_ko": "유리네 집 티비는 가로가 1.25미터(m)이고, 세로가 0.75미터(m)인 직사각형 모양이라고 합니다. 유리네 집 티비의 넓이는 몇 제곱미터(㎡)입니까?",
        "question_en": "Yuri's TV is said to be a shape of rectangular with a width of 1.25 meters (m) and a length of 0.75 meters (m). How many square meters (m2) is the TV at Yuri's House?",
        "answer_ko": "0.94",
        "answer_en": "0.94",
        "solution_abst_ko": "1.25 0.75 [OP_MUL]",
        "solution_abst_en": "1.25 0.75 [OP_MUL]",
        "solution_code_ko": "var_a = 1.25\nvar_b = 0.75\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 1.25\nvar_b = 0.75\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "5515": {
        "category": "Comparison",
        "question_ko": "나이가 적은 순서대로 학생들이 줄을 섰습니다. 유나는 5번째인 유정이보다 나이가 많고 7번째인 은지보다는 나이가 적습니다. 유나는 줄에서 몇 번째에 서 있습니까?",
        "question_en": "Students are lined up in the order of their age. Yuna is older than Yujeong who is in the fifth, and younger than Eunji, who is in the seventh. In which place is Yuna standing in that line?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "5 7 [OP_ADD] 2 [OP_FDIV]",
        "solution_abst_en": "5 7 [OP_ADD] 2 [OP_FDIV]",
        "solution_code_ko": "var_a = 5\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "5516": {
        "category": "Geometry",
        "question_ko": "반지름이 각각 6센티미터(㎝), 3센티미터(㎝)인 구가 2개 있습니다. 둘 중 큰 구의 겉넓이를 작은 구의 겉넓이로 나눈 몫을 구하시오.",
        "question_en": "There are two spheres with a radius of 6 centimeters (cm) and 3 centimeters (cm) respectively. Find the quotient of the surface area of the larger sphere divided by the surface area of the smaller sphere.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "6 3 [OP_DIV] 2 [OP_POW]",
        "solution_abst_en": "6 3 [OP_DIV] 2 [OP_POW]",
        "solution_code_ko": "var_a = 6\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint(int(var_e))"
    },
    "5517": {
        "category": "Arithmetic calculation",
        "question_ko": "가로 24센티미터(㎝), 세로 15센티미터(㎝), 높이 28센티미터(㎝)인 상자가 있습니다. 이 상자에 가로 4센티미터(㎝), 세로 5센티미터(㎝), 높이 7센티미터(㎝)인 주스팩이 빈틈없이 들어 있다면 상자에 들어 있는 주스팩은 모두 몇 개입니까?",
        "question_en": "There is a box with a width of 24 centimeters (cm), a length of 15 centimeters (cm), and a height of 28 centimeters (cm). How many juice packs with a width of 4 centimeters (cm), a length of 5 centimeters (cm), and a height of 7 centimeters (cm) are there in the box if there are no gaps in this box ?",
        "answer_ko": "72",
        "answer_en": "72",
        "solution_abst_ko": "24 15 [OP_MUL] 28 [OP_MUL] 4 5 [OP_MUL] 7 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "24 15 [OP_MUL] 28 [OP_MUL] 4 5 [OP_MUL] 7 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 24\nvar_b = 15\nvar_c = var_a * var_b\nvar_d = 28\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = 5\nvar_h = var_f * var_g\nvar_i = 7\nvar_j = var_h * var_i\nvar_k = var_e / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 24\nvar_b = 15\nvar_c = var_a * var_b\nvar_d = 28\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = 5\nvar_h = var_f * var_g\nvar_i = 7\nvar_j = var_h * var_i\nvar_k = var_e / var_j\nprint(int(var_k))"
    },
    "5518": {
        "category": "Geometry",
        "question_ko": "정구각형 모양의 딱지 둘레는 171센티미터(㎝)입니다. 딱지의 한 변의 길이를 구하시오.",
        "question_en": "The circumference of the regular nonagon-shaped shell is 171 centimeters (cm). Find the length of one side of the shell.",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "171 9 [OP_DIV]",
        "solution_abst_en": "171 9 [OP_DIV]",
        "solution_code_ko": "var_a = 171\nvar_b = 9\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 171\nvar_b = 9\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "5519": {
        "category": "Correspondence",
        "question_ko": "8로 나누어 떨어지는 70과 80사이의 두 자리수는 무엇인가?",
        "question_en": "What two-digit number between 70 and 80 is divisible by 8?",
        "answer_ko": "72",
        "answer_en": "72",
        "solution_abst_ko": "70 1 [OP_ADD] 80 1 [OP_SUB] 1 [OP_LIST_ARANGE] 8 [OP_LIST_DIVISIBLE] 1 [OP_LIST_GET]",
        "solution_abst_en": "70 1 [OP_ADD] 80 1 [OP_SUB] 1 [OP_LIST_ARANGE] 8 [OP_LIST_DIVISIBLE] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 70\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 80\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = 8\nlist_b = []\nvar_h = int(var_h)\nfor i in list_a:\n    i = int(i)\n    if i % var_h == 0:\n        list_b.append(i)\nvar_i = 1\nvar_j = list_b[var_i-1]\nprint(int(var_j))",
        "solution_code_en": "var_a = 70\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 80\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = 8\nlist_b = []\nvar_h = int(var_h)\nfor i in list_a:\n    i = int(i)\n    if i % var_h == 0:\n        list_b.append(i)\nvar_i = 1\nvar_j = list_b[var_i-1]\nprint(int(var_j))"
    },
    "5520": {
        "category": "Possibility",
        "question_ko": "꽃이 장미, 백합, 튤립, 국화, 카네이션 각각 1송이씩 있습니다. 이 중에서 2송이를 뽑아 서로 다른 두 개의 꽃병에 1송이씩 꽂으려고 합니다. 꽃병에 서로 다르게 꽃을 꽂는 방법은 모두 몇 가지인지 구하시오.",
        "question_en": "There is a rose, lily, tulip chrysanthemum, and carnation. I'm going to pick 2 of these and put them in 2 different vases. How many different ways are there when placing flowers in a vase?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "[OP_LIST_SOL] 장미 백합 튤립 국화 카네이션 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] rose lily tulip chrysanthemum carnation [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_code_ko": "var_a = '장미'\nvar_b = '백합'\nvar_c = '튤립'\nvar_d = '국화'\nvar_e = '카네이션'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nprint(int(var_h))",
        "solution_code_en": "var_a = 'rose'\nvar_b = 'lily'\nvar_c = 'tulip'\nvar_d = 'chrysanthemum'\nvar_e = 'carnation'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nprint(int(var_h))"
    },
    "5521": {
        "category": "Possibility",
        "question_ko": "4장의 숫자 카드 3, 1, 9, 7 중 차가 가장 큰 2 장을 찾아 합하시오.",
        "question_en": "Among the four number cards 3, 1, 9, and 7, find the two cards with the greatest difference and add them together.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "[OP_LIST_SOL] 3 1 9 7 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD}",
        "solution_abst_en": "[OP_LIST_SOL] 3 1 9 7 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD}",
        "solution_code_ko": "var_a = 3\nvar_b = 1\nvar_c = 9\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = '[OP_ADD}'\nprint(var_i)",
        "solution_code_en": "var_a = 3\nvar_b = 1\nvar_c = 9\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = '[OP_ADD}'\nprint(var_i)"
    },
    "5522": {
        "category": "Arithmetic calculation",
        "question_ko": "은행에서 100만 원짜리 수표를 25장, 10만 원짜리 수표를 8장 찾았습니다. 은행에서 찾은 돈은 모두 얼마입니까?",
        "question_en": "At the bank, you found 25 checks for 1 million won and 8 checks for 100,000 won. How much is all the money you find in the bank?",
        "answer_ko": "25800000",
        "answer_en": "25800000",
        "solution_abst_ko": "100 10000 [OP_MUL] 25 [OP_MUL] 10 10000 [OP_MUL] 8 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "100 10000 [OP_MUL] 25 [OP_MUL] 10 10000 [OP_MUL] 8 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 100\nvar_b = 10000\nvar_c = var_a * var_b\nvar_d = 25\nvar_e = var_c * var_d\nvar_f = 10\nvar_g = 10000\nvar_h = var_f * var_g\nvar_i = 8\nvar_j = var_h * var_i\nvar_k = var_e + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 100\nvar_b = 10000\nvar_c = var_a * var_b\nvar_d = 25\nvar_e = var_c * var_d\nvar_f = 10\nvar_g = 10000\nvar_h = var_f * var_g\nvar_i = 8\nvar_j = var_h * var_i\nvar_k = var_e + var_j\nprint(int(var_k))"
    },
    "5523": {
        "category": "Comparison",
        "question_ko": "수호는 민영이보다 키가 큽니다. 성주는 민영이보다 키가 작습니다. 성주는 선미보다 키가 큽니다. 키가 가장 작은 사람은 누구입니까?",
        "question_en": "Suho is taller than Minyoung. Seongju is shorter than Minyoung. Seongju is taller than Seonmi. Who is the shortest person?",
        "answer_ko": "선미",
        "answer_en": "Seonmi",
        "solution_abst_ko": "[OP_LIST_SOL] 수호 민영 성주 선미 [OP_LIST_EOL] [OP_LIST_SOL] 수호 민영 > 성주 민영 < 성주 선미 > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Suho Minyoung Seongju Seonmi [OP_LIST_EOL] [OP_LIST_SOL] Suho Minyoung > Seongju Minyoung < Seongju Seonmi > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '수호'\nvar_b = '민영'\nvar_c = '성주'\nvar_d = '선미'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '수호'\nvar_f = '민영'\nvar_g = '>'\nvar_h = '성주'\nvar_i = '민영'\nvar_j = '<'\nvar_k = '성주'\nvar_l = '선미'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)",
        "solution_code_en": "var_a = 'Suho'\nvar_b = 'Minyoung'\nvar_c = 'Seongju'\nvar_d = 'Seonmi'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'Suho'\nvar_f = 'Minyoung'\nvar_g = '>'\nvar_h = 'Seongju'\nvar_i = 'Minyoung'\nvar_j = '<'\nvar_k = 'Seongju'\nvar_l = 'Seonmi'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)"
    },
    "5524": {
        "category": "Arithmetic calculation",
        "question_ko": "송희는 12일 동안 288쪽의 책을 읽었고, 은주는 9일 동안 243쪽의 책을 읽었습니다. 두 학생이 하루 동안 읽은 책 쪽수의 차이는 얼마인가요?",
        "question_en": "Songhee read 288 pages in 12 days, and Eunju read 243 pages in 9 days. What is the difference between the number of pages the two students read in a day?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "288 12 [OP_DIV] 243 9 [OP_DIV] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "288 12 [OP_DIV] 243 9 [OP_DIV] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 288\nvar_b = 12\nvar_c = var_a / var_b\nvar_d = 243\nvar_e = 9\nvar_f = var_d / var_e\nvar_g = var_c - var_f\nvar_h = abs(var_g)\nprint(int(var_h))",
        "solution_code_en": "var_a = 288\nvar_b = 12\nvar_c = var_a / var_b\nvar_d = 243\nvar_e = 9\nvar_f = var_d / var_e\nvar_g = var_c - var_f\nvar_h = abs(var_g)\nprint(int(var_h))"
    },
    "5525": {
        "category": "Possibility",
        "question_ko": "동아리에 여학생 4명, 남학생 6명이 있다. 남학생과 여학생 중 한명씩 대표를 뽑을 때, 뽑힐 수 있는 대표의 경우의 수를 구하시오.",
        "question_en": "There are 4 female students and 6 male students in the club. When selecting a representative from the male students amd the female students each, find the number of cases in which a representative can be selected.",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "4 6 [OP_MUL]",
        "solution_abst_en": "4 6 [OP_MUL]",
        "solution_code_ko": "var_a = 4\nvar_b = 6\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 6\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "5526": {
        "category": "Geometry",
        "question_ko": "길이가 10센티미터(㎝)인 종이 20장을 길게 이어 붙였습니다. 연결 부분의 길이가 5밀리미터(㎜)로 모두 같다면 이어 붙인 전체의 길이는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "Twenty sheets of paper each 10 centimeters (cm) long were glued together. If the length of the connected parts is 5 millimeters (mm) each, find the length in centimeters (cm) of the whole joined papers.",
        "answer_ko": "190.50",
        "answer_en": "190.5",
        "solution_abst_ko": "10 20 [OP_MUL] 5 10 [OP_DIV] 20 1 [OP_SUB] [OP_MUL] [OP_SUB]",
        "solution_abst_en": "10 20 [OP_MUL] 5 10 [OP_DIV] 20 1 [OP_SUB] [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = 10\nvar_f = var_d / var_e\nvar_g = 20\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = var_f * var_i\nvar_k = var_c - var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 10\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = 10\nvar_f = var_d / var_e\nvar_g = 20\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = var_f * var_i\nvar_k = var_c - var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "5527": {
        "category": "Comparison",
        "question_ko": "학생들이 한 줄로 서 있습니다. 그중 윤기는 왼쪽에서 7번째, 오른쪽에서 5번째에 서 있습니다. 줄을 서 있는 학생은 모두 몇 명입니까?",
        "question_en": "Students are standing in a line. Yoongi is standing 7th from the left and 5th from the right. How many students are standing in line?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "7 5 [OP_ADD] 1 [OP_SUB]",
        "solution_abst_en": "7 5 [OP_ADD] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 7\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 7\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "5528": {
        "category": "Correspondence",
        "question_ko": "32에서 16을 뺀 값이 어떤 수에 4를 곱한 값과 같다고 한다. 어떤 수를 4로 나누고 16을 더하면 얼마가 되는지 구하시오.",
        "question_en": "32 minus 16 equals a number multiplied by 4. What is the result of dividing the number by 4 and adding 16?",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "32 16 [OP_SUB] 4 [OP_DIV] 4 [OP_DIV] 16 [OP_ADD]",
        "solution_abst_en": "32 16 [OP_SUB] 4 [OP_DIV] 4 [OP_DIV] 16 [OP_ADD]",
        "solution_code_ko": "var_a = 32\nvar_b = 16\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 4\nvar_g = var_e / var_f\nvar_h = 16\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 32\nvar_b = 16\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 4\nvar_g = var_e / var_f\nvar_h = 16\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "5529": {
        "category": "Comparison",
        "question_ko": "남준이는 12등을 했고, 윤기는 남준이보다 10명 앞에서 먼저 들어갔습니다. 윤기는 몇 등입니까?",
        "question_en": "Namjoon placed 12th, and Yoongi entered earlier than Namjoon, with 10 people between them. If we rank people according to their entrance time, what rank is Yoongi in?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "12 10 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "12 10 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 12\nvar_b = 10\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 10\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "5530": {
        "category": "Possibility",
        "question_ko": "숫자 카드 7, 0, 1, 5을 한 번 씩 모두 사용하여 만들 수 있는 네 자리 수는 몇 개입니까? 단, 수의 가장 높은 자리에 0이 올 수 없습니다.",
        "question_en": "How many four-digit numbers can be made by using all of each number cards 7, 0, 1, and 5 once? Note that 0 cannot be in the highest digit of the number.",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "[OP_LIST_SOL] 7 0 1 5 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 7 0 1 5 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 7\nvar_b = 0\nvar_c = 1\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 7\nvar_b = 0\nvar_c = 1\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "5531": {
        "category": "Possibility",
        "question_ko": "주어진 숫자카드 6, 3를 한 번씩 모두 사용하여 만들 수 있는 가장 큰 수를 쓰시오.",
        "question_en": "Write the largest number that can be made by using all the given number cards 6 and 3 once.",
        "answer_ko": "63",
        "answer_en": "63",
        "solution_abst_ko": "[OP_LIST_SOL] 6 3 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 6 3 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 6\nvar_b = 3\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_e = list_c[-var_d]\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 3\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_e = list_c[-var_d]\nprint(int(var_e))"
    },
    "5532": {
        "category": "Correspondence",
        "question_ko": "14를 어떤 수에 더해 56을 얻었습니다. 3을 어떤 수에 곱하면 얼마입니까?",
        "question_en": "Add 14 to a number to get 56. What is the value of the number multiplied by 3?",
        "answer_ko": "126",
        "answer_en": "126",
        "solution_abst_ko": "56 14 [OP_SUB] 3 [OP_MUL]",
        "solution_abst_en": "56 14 [OP_SUB] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 56\nvar_b = 14\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 56\nvar_b = 14\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "5533": {
        "category": "Possibility",
        "question_ko": "3장의 숫자 카드 6, 3, 8을 한 번씩만 사용하여 만들 수 있는 세 자리 수 중에서 가장 큰 수와 가장 작은 수의 합을 구하시오.",
        "question_en": "Find the sum of the largest and smallest three-digit numbers that can be formed by using the three number cards 6, 3, and 8 only once.",
        "answer_ko": "1231",
        "answer_en": "1231",
        "solution_abst_ko": "[OP_LIST_SOL] 6 3 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 6 3 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 3\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 6\nvar_b = 3\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))"
    },
    "5534": {
        "category": "Arithmetic calculation",
        "question_ko": "동그라미를 한 개 그리려면 철사 4미터(m)가 필요합니다. 태민이가 가진 철사의 길이가 105.8미터(m)라면 동그라미를 여러 개 그리고 남은 철사는 몇 미터(m)입니까?",
        "question_en": "You will need 4 meters (m) of wire to draw one circle. If the length of Taemin's wire is 105.8 meters (m), how many meters (m) of wire are left after making several circles?",
        "answer_ko": "1.80",
        "answer_en": "1.8",
        "solution_abst_ko": "105.8 4 [OP_MOD]",
        "solution_abst_en": "105.8 4 [OP_MOD]",
        "solution_code_ko": "var_a = 105.8\nvar_b = 4\nvar_c = var_a % var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 105.8\nvar_b = 4\nvar_c = var_a % var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "5535": {
        "category": "Correspondence",
        "question_ko": "서로 다른 수 A, B, C, D가 있습니다. 두 자리 수 CD와 세 자리 수 ACD와 네 자리 수 ABCD의 합이 2967입니다. A를 구하시오.",
        "question_en": "There are different digits A, B, C, and D. The sum of two-digit CD, three-digit ACD, and four-digit ABCD is 2967. Find A.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] CD + ACD + ABCD = 2967 [OP_LIST_EOL] [OP_LIST2NUM] A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "[OP_LIST_SOL] CD + ACD + ABCD = 2967 [OP_LIST_EOL] [OP_LIST2NUM] A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'CD'\nvar_b = '+'\nvar_c = 'ACD'\nvar_d = '+'\nvar_e = 'ABCD'\nvar_f = '='\nvar_g = 2967\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h=\"\"\nfor i in list_a:\n    i = str(i)\n    var_h = var_h + i\nvar_i = 'A'\nans_dict = dict()\nvar_h = var_h.replace('×','*')\nvar_h = var_h.replace('x','*')\nvar_h = var_h.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_h):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_h\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_h):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_j = ans_dict[var_i]\nprint(int(var_j))",
        "solution_code_en": "var_a = 'CD'\nvar_b = '+'\nvar_c = 'ACD'\nvar_d = '+'\nvar_e = 'ABCD'\nvar_f = '='\nvar_g = 2967\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h=\"\"\nfor i in list_a:\n    i = str(i)\n    var_h = var_h + i\nvar_i = 'A'\nans_dict = dict()\nvar_h = var_h.replace('×','*')\nvar_h = var_h.replace('x','*')\nvar_h = var_h.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_h):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_h\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_h):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_j = ans_dict[var_i]\nprint(int(var_j))"
    },
    "5536": {
        "category": "Comparison",
        "question_ko": "학생들에게 지우개를 나누어 주려고 합니다. 동훈이네 반은 지우개 45개를 학생 15명이 나누어 갖고, 기훈이네 반은 지우개 30개를 5명이 나누어 갖습니다. 누구네 반의 학생이 각각 더 많은 지우개를 나누어 받습니까?",
        "question_en": "We are going to hand out erasers to the students. In Donghun's class, 15 students share 45 erasers, and in Kihoon's class, 5 students share 30 erasers. Whose class of students each gets more erasers?",
        "answer_ko": "기훈",
        "answer_en": "Kihoon",
        "solution_abst_ko": "[OP_LIST_SOL] 동훈 기훈 [OP_LIST_EOL] [OP_LIST_SOL] 45 15 [OP_DIV] 30 5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Donghun Kihoon [OP_LIST_EOL] [OP_LIST_SOL] 45 15 [OP_DIV] 30 5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '동훈'\nvar_b = '기훈'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 45\nvar_d = 15\nvar_e = var_c / var_d\nvar_f = 30\nvar_g = 5\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Donghun'\nvar_b = 'Kihoon'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 45\nvar_d = 15\nvar_e = var_c / var_d\nvar_f = 30\nvar_g = 5\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "5537": {
        "category": "Arithmetic calculation",
        "question_ko": "수학시험을 5월에 본것과 4월에 본 것의 평균은 89점이다. 4,5,6월에 본 평균이 88점이라면 6월에 본 시험은 몇 점인가?",
        "question_en": "The average score on the math test taken in May and April is 89. If the average score on the math test taken in April, May, and June is 88, what is the score on the math test taken in June?",
        "answer_ko": "86",
        "answer_en": "86",
        "solution_abst_ko": "88 3 [OP_MUL] 89 [OP_SUB] 89 [OP_SUB]",
        "solution_abst_en": "88 3 [OP_MUL] 89 [OP_SUB] 89 [OP_SUB]",
        "solution_code_ko": "var_a = 88\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 89\nvar_e = var_c - var_d\nvar_f = 89\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 88\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 89\nvar_e = var_c - var_d\nvar_f = 89\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "5538": {
        "category": "Comparison",
        "question_ko": "무게가 각각 1.2킬로그램(㎏), 3.1킬로그램(㎏), 2.4킬로그램(㎏), 3.0킬로그램(㎏), 1.8킬로그램(㎏)인 가방이 있습니다. 2킬로그램(㎏)이 넘는 가방 중 가장 가벼운 가방은 몇 킬로그램(㎏)입니까?",
        "question_en": "There are bags weighing 1.2 kilograms (kg), 3.1 kilograms (kg), 2.4 kilograms (kg), 3.0 kilograms (kg), and 1.8 kilograms (kg), respectively. Of the bags that weigh more than 2 kilograms (kg), how many kilograms (kg) is the lightest?",
        "answer_ko": "2.40",
        "answer_en": "2.4",
        "solution_abst_ko": "[OP_LIST_SOL] 1.2 3.1 2.4 3.0 1.8 [OP_LIST_EOL] 2 [OP_LIST_MORE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 1.2 3.1 2.4 3.0 1.8 [OP_LIST_EOL] 2 [OP_LIST_MORE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1.2\nvar_b = 3.1\nvar_c = 2.4\nvar_d = 3\nvar_e = 1.8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nprint('{:.2f}'.format(round(var_h+1e-10,2)))",
        "solution_code_en": "var_a = 1.2\nvar_b = 3.1\nvar_c = 2.4\nvar_d = 3\nvar_e = 1.8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nprint('{:.2f}'.format(round(var_h+1e-10,2)))"
    },
    "5539": {
        "category": "Possibility",
        "question_ko": "4, 6, 7을 한 번씩만 사용하여 만들 수 있는 세 자리 수 중에서 670보다 큰 수의 합과 500보다 작은 수의 합의 차를 구하시오.",
        "question_en": "Find the sum of the numbers larger than 670 and the sum of the numbers smaller than 500 among three digits that can be made using 4, 6, and 7 only once.  ",
        "answer_ko": "1241",
        "answer_en": "1241",
        "solution_abst_ko": "[OP_LIST_SOL] 4 6 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 670 [OP_LIST_MORE] [OP_LIST_SUM] [OP_LIST_POP] 500 [OP_LIST_LESS] [OP_LIST_SUM] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "[OP_LIST_SOL] 4 6 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 670 [OP_LIST_MORE] [OP_LIST_SUM] [OP_LIST_POP] 500 [OP_LIST_LESS] [OP_LIST_SUM] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 4\nvar_b = 6\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 670\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nlist_c = [float(i) for i in list_c]\nvar_f = sum(list_c)\nvar_g = 500\nlist_d = []\nfor i in list_b:\n    if i < var_g:\n        list_d.append(i)\nlist_d = [float(i) for i in list_d]\nvar_h = sum(list_d)\nvar_i = var_f - var_h\nvar_j = abs(var_i)\nprint(int(var_j))",
        "solution_code_en": "var_a = 4\nvar_b = 6\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 670\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nlist_c = [float(i) for i in list_c]\nvar_f = sum(list_c)\nvar_g = 500\nlist_d = []\nfor i in list_b:\n    if i < var_g:\n        list_d.append(i)\nlist_d = [float(i) for i in list_d]\nvar_h = sum(list_d)\nvar_i = var_f - var_h\nvar_j = abs(var_i)\nprint(int(var_j))"
    },
    "5540": {
        "category": "Arithmetic calculation",
        "question_ko": "지민이가 유나에게 사탕 25개를 주었더니 13개가 남았습니다. 처음에 지민이가 가진 사탕은 몇 개입니까?",
        "question_en": "Jimin gave Yuna 25 candies, and there are 13 left over. How many candies does Jimin have at the start?",
        "answer_ko": "38",
        "answer_en": "38",
        "solution_abst_ko": "13 25 [OP_ADD]",
        "solution_abst_en": "13 25 [OP_ADD]",
        "solution_code_ko": "var_a = 13\nvar_b = 25\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 13\nvar_b = 25\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "5541": {
        "category": "Arithmetic calculation",
        "question_ko": "한 송이에 500원인 장미가 있다. 200송이의 장미를 25묶음으로 나누어 팔때 한 묶음 당 얼마인가?",
        "question_en": "A rose's price is 500 won. If you are going to sell 200 roses parceling into 25 bundles, how much is a bundle?",
        "answer_ko": "4000",
        "answer_en": "4000",
        "solution_abst_ko": "200 25 [OP_DIV] 500 [OP_MUL]",
        "solution_abst_en": "200 25 [OP_DIV] 500 [OP_MUL]",
        "solution_code_ko": "var_a = 200\nvar_b = 25\nvar_c = var_a / var_b\nvar_d = 500\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 200\nvar_b = 25\nvar_c = var_a / var_b\nvar_d = 500\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "5542": {
        "category": "Geometry",
        "question_ko": "6센티미터(㎝), 세로 4센티미터(㎝), 높이 1센티미터(㎝) 인 직육면체 모양의 큰 상자가 가로 가로 30 센티미터(㎝) , 세로 20 센티미터(㎝) , 높이 5센티미터(㎝) 로 부피가 커졌을 때, 몇 배가 커진전지 구하시오.",
        "question_en": "When a large box in the shape of a cuboid measuring 6 centimeters (cm) wide, 4 centimeters (cm) long, and 1 centimeters (cm) high became larger into a volume of 30 centimeters (cm) wide, 20 centimeters (cm) long, and 5 centimeters (cm) high, find how many times it has grown.",
        "answer_ko": "125",
        "answer_en": "125",
        "solution_abst_ko": "30 20 [OP_MUL] 5 [OP_MUL] 6 4 [OP_MUL] 1 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "30 20 [OP_MUL] 5 [OP_MUL] 6 4 [OP_MUL] 1 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 30\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c * var_d\nvar_f = 6\nvar_g = 4\nvar_h = var_f * var_g\nvar_i = 1\nvar_j = var_h * var_i\nvar_k = var_e / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 30\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c * var_d\nvar_f = 6\nvar_g = 4\nvar_h = var_f * var_g\nvar_i = 1\nvar_j = var_h * var_i\nvar_k = var_e / var_j\nprint(int(var_k))"
    },
    "5543": {
        "category": "Comparison",
        "question_ko": "어느 꽃밭이 있습니다. 이 꽃밭의 3/8에는 봉선화가 심어져 있으며, 2/7에는 채송화가 심어져 있습니다. 어느 꽃을 심은 부분이 더 넓을까요?",
        "question_en": "There is a flower garden. 3/8 of this flower garden is planted with snapweed, and 2/7 is planted with sunplant. Which part of the area is larger: snapweed or sunplant?",
        "answer_ko": "봉선화",
        "answer_en": "snapweed",
        "solution_abst_ko": "[OP_LIST_SOL] 채송화 봉선화 [OP_LIST_EOL] [OP_LIST_SOL] 2/7 3/8 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] sunplant snapweed [OP_LIST_EOL] [OP_LIST_SOL] 2/7 3/8 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '채송화'\nvar_b = '봉선화'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.2857142857142857\nvar_d = 0.375\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'sunplant'\nvar_b = 'snapweed'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.2857142857142857\nvar_d = 0.375\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "5544": {
        "category": "Correspondence",
        "question_ko": "처음 수에 9를 빼면 5입니다. 처음 수를 구하시오.",
        "question_en": "Subtracting 9 from a certain number results 5. Find the certain number.",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "5 9 [OP_ADD]",
        "solution_abst_en": "5 9 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 9\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 9\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "5545": {
        "category": "Arithmetic calculation",
        "question_ko": "(가) 반 학생들은 모두 미술, 음악 수업 중 최소 한 개 이상에 참여하고 있습니다. 미술 수업에 참여하는 학생이 35명이고 음악 수업에 참여하는 학생은 32명입니다. 두 수업 모두 참여하는 학생 수는 19명일 때, (가) 반의 학생 수는 몇 명입니까?",
        "question_en": "All students in the (a) class are participating in at least one art or music class. There are 35 students in the art class and 32 students in the music class. If the number of students participating in both classes is 19, how many students are in the  (a) class?",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "35 32 [OP_ADD] 19 [OP_SUB]",
        "solution_abst_en": "35 32 [OP_ADD] 19 [OP_SUB]",
        "solution_code_ko": "var_a = 35\nvar_b = 32\nvar_c = var_a + var_b\nvar_d = 19\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 35\nvar_b = 32\nvar_c = var_a + var_b\nvar_d = 19\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "5546": {
        "category": "Comparison",
        "question_ko": "실제 들이가 1리터(L)인 그릇을 미애는 1100밀리리터(㎖), 효리는 850밀리리터(㎖)로 어림하였습니다. 두 사람 중 그릇의 들이를 가장 가깝게 어림한 사람은 누구인가?",
        "question_en": "A bowl with a volume of 1 liter (L) was estimated as 1100 milliliters (㎖) by Miae and 850 milliliters (㎖) by Hyori. Which of the two people gave the closest estimate of the volume of the bowl?",
        "answer_ko": "미애",
        "answer_en": "Miae",
        "solution_abst_ko": "[OP_LIST_SOL] 미애 효리 [OP_LIST_EOL] [OP_LIST_SOL] 1000 1100 [OP_SUB] [OP_ABS] 1000 850 [OP_SUB] [OP_ABS] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Miae Hyori [OP_LIST_EOL] [OP_LIST_SOL] 1000 1100 [OP_SUB] [OP_ABS] 1000 850 [OP_SUB] [OP_ABS] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '미애'\nvar_b = '효리'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1000\nvar_d = 1100\nvar_e = var_c - var_d\nvar_f = abs(var_e)\nvar_g = 1000\nvar_h = 850\nvar_i = var_g - var_h\nvar_j = abs(var_i)\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[var_k-1]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'Miae'\nvar_b = 'Hyori'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1000\nvar_d = 1100\nvar_e = var_c - var_d\nvar_f = abs(var_e)\nvar_g = 1000\nvar_h = 850\nvar_i = var_g - var_h\nvar_j = abs(var_i)\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[var_k-1]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "5547": {
        "category": "Correspondence",
        "question_ko": "서로 다른 두 수 A, B가 있습니다. 두 자리 수끼리의 덧셈식 29+AB=B6에서 B-A의 값을 구하시오.",
        "question_en": "There are two different numbers A and B. Find the value of B-A from 29+AB=B6.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "29+AB=B6 B [OP_DIGIT_UNK_SOLVER] 29+AB=B6 A [OP_DIGIT_UNK_SOLVER] [OP_SUB]",
        "solution_abst_en": "29+AB=B6 B [OP_DIGIT_UNK_SOLVER] 29+AB=B6 A [OP_DIGIT_UNK_SOLVER] [OP_SUB]",
        "solution_code_ko": "var_a = '29+AB=B6'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '29+AB=B6'\nvar_e = 'A'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = '29+AB=B6'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '29+AB=B6'\nvar_e = 'A'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "5548": {
        "category": "Arithmetic calculation",
        "question_ko": "다섯 자리 수 중 9, 6, 2의 공배수인 수는 모두 몇 개 입니까?",
        "question_en": "How many five-digit numbers are common multiples of 9, 6, and 2?",
        "answer_ko": "5000",
        "answer_en": "5000",
        "solution_abst_ko": "10000 99999 1 [OP_LIST_ARANGE] 9 [OP_LIST_DIVISIBLE] 6 [OP_LIST_DIVISIBLE] 2 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "10000 99999 1 [OP_LIST_ARANGE] 9 [OP_LIST_DIVISIBLE] 6 [OP_LIST_DIVISIBLE] 2 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 10000\nvar_b = 99999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 9\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 6\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 2\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))",
        "solution_code_en": "var_a = 10000\nvar_b = 99999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 9\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 6\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 2\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))"
    },
    "5549": {
        "category": "Possibility",
        "question_ko": "주사위를 던져 나온 숫자가 2, 3, 4입니다. 나온 숫자를 한 번씩 모두 사용하여 만든 세 자리 수 중 340보다 큰 수는 모두 몇 개입니까?",
        "question_en": "The dice was rolled and the numbers 2, 3, and 4 came out. How many three-digit numbers made by using all these numbers once are greater than 340?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 2 3 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 340 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 2 3 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 340 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = 4\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 340\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = 4\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 340\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "5550": {
        "category": "Geometry",
        "question_ko": "가로 30 센티미터(㎝) , 세로 20 센티미터(㎝) , 높이 5센티미터(㎝) 인 직육면체 모양의 수조가 있다. 가로 6센티미터(㎝), 세로 4센티미터(㎝), 높이 1센티미터(㎝) 인 직육면체 모양의 그릇으로 물을 퍼서 수조에 채울 떄, 몇 번을 퍼야 수조가 꽉 찰지 구하시오.",
        "question_en": "There is a tank in the shape of a cuboid which is 30 centimeters (cm) wide, 20 centimeters (cm) long, and 5 centimeters (cm) high. When pouring water into the tank with a cuboid-shaped bowl measuring 6 centimeters (cm) wide, 4 centimeters (cm) long, and 1 cm (cm high), find out how many times it takes to fill the tank.",
        "answer_ko": "125",
        "answer_en": "125",
        "solution_abst_ko": "30 20 [OP_MUL] 5 [OP_MUL] 6 4 [OP_MUL] 1 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "30 20 [OP_MUL] 5 [OP_MUL] 6 4 [OP_MUL] 1 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 30\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c * var_d\nvar_f = 6\nvar_g = 4\nvar_h = var_f * var_g\nvar_i = 1\nvar_j = var_h * var_i\nvar_k = var_e / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 30\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c * var_d\nvar_f = 6\nvar_g = 4\nvar_h = var_f * var_g\nvar_i = 1\nvar_j = var_h * var_i\nvar_k = var_e / var_j\nprint(int(var_k))"
    },
    "5551": {
        "category": "Correspondence",
        "question_ko": "일곱자리 수 25AB33C는 8의 배수이고 9의 배수이면서, 11의 배수라고 한다. B를 구하시오.",
        "question_en": "The seven-digit number 25AB33C is said to be both a multiple of 8, and a multiple of 9, and a multiple of 11. get B.",
        "answer_ko": "0",
        "answer_en": "0",
        "solution_abst_ko": "25AB33C [OP_GEN_POSSIBLE_LIST] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] 11 [OP_LIST_DIVISIBLE] 25AB33C B [OP_LIST_FIND_UNK]",
        "solution_abst_en": "25AB33C [OP_GEN_POSSIBLE_LIST] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] 11 [OP_LIST_DIVISIBLE] 25AB33C B [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = '25AB33C'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 8\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 9\nlist_c = []\nvar_c = int(var_c)\nfor i in list_b:\n    i = int(i)\n    if i % var_c == 0:\n        list_c.append(i)\nvar_d = 11\nlist_d = []\nvar_d = int(var_d)\nfor i in list_c:\n    i = int(i)\n    if i % var_d == 0:\n        list_d.append(i)\nvar_e = '25AB33C'\nvar_f = 'B'\nvar_e = str(var_e)\nvar_f = str(var_f)\nunk_idx = var_e.index(var_f)\nvar_g = 0\nfor elem in list_d:\n    elem = str(elem)\n    var_g = int(elem[unk_idx])\nprint(int(var_g))",
        "solution_code_en": "var_a = '25AB33C'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 8\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 9\nlist_c = []\nvar_c = int(var_c)\nfor i in list_b:\n    i = int(i)\n    if i % var_c == 0:\n        list_c.append(i)\nvar_d = 11\nlist_d = []\nvar_d = int(var_d)\nfor i in list_c:\n    i = int(i)\n    if i % var_d == 0:\n        list_d.append(i)\nvar_e = '25AB33C'\nvar_f = 'B'\nvar_e = str(var_e)\nvar_f = str(var_f)\nunk_idx = var_e.index(var_f)\nvar_g = 0\nfor elem in list_d:\n    elem = str(elem)\n    var_g = int(elem[unk_idx])\nprint(int(var_g))"
    },
    "5552": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 가장 작은 수와 2번째로 작은 수의 차는 얼마입니까?",
        "question_en": "There are five numbers 10, 11, 12, 13, and 14. What is the difference between the smallest number and the second smallest number?",
        "answer_ko": "-1",
        "answer_en": "-1",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))"
    },
    "5553": {
        "category": "Arithmetic calculation",
        "question_ko": "시우는 30분 동안 180개의 학을 접는다. 시우가 이와 같은 속도로 1시간 동안 만든 학의 개수는 몇 개일지 구하시오.",
        "question_en": "Siwoo folds 180 cranes in 30 minutes. Find how many cranes Siwoo made in 1 hour at this speed.",
        "answer_ko": "360",
        "answer_en": "360",
        "solution_abst_ko": "1 60 [OP_MUL] 30 [OP_DIV] 180 [OP_MUL]",
        "solution_abst_en": "1 60 [OP_MUL] 30 [OP_DIV] 180 [OP_MUL]",
        "solution_code_ko": "var_a = 1\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 30\nvar_e = var_c / var_d\nvar_f = 180\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 30\nvar_e = var_c / var_d\nvar_f = 180\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "5554": {
        "category": "Comparison",
        "question_ko": "총 3개의 숫자 0.8, 1/2, 0.5이 있습니다. 이 중 0.1보다 큰 수를 모두 더하면 얼마인가요?",
        "question_en": "If there are three numbers 0.8, 1/2, and 0.5, what is the sum of all numbers greater than 0.1?",
        "answer_ko": "1.80",
        "answer_en": "1.8",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.5 [OP_LIST_EOL] 0.1 [OP_LIST_MORE] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.5 [OP_LIST_EOL] 0.1 [OP_LIST_MORE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.1\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.1\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "5555": {
        "category": "Geometry",
        "question_ko": "꼭짓점의 개수와 선분의 개수를 각각 A, B라 할 때, 오각형에 대한 A+B의 값은?",
        "question_en": "If A and B are the numbers of vertices and the numbers of edges, what is the value of A+B for a pentagon?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "5 5 [OP_ADD]",
        "solution_abst_en": "5 5 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "5556": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중에서 가장 큰 수와 가장 작은 수의 합은 얼마입니까?",
        "question_en": "There are three numbers 10, 11, and 12. What is the sum of the largest and smallest numbers?",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e + var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e + var_g\nprint(int(var_h))"
    },
    "5557": {
        "category": "Geometry",
        "question_ko": "한 모서리의 길이가 8센티미터(㎝)인 정육면체 3개를 모두 사용해서 1개의 직육면체를 만들었습니다. 이 직육면체의 겉넓이를 구하시오.",
        "question_en": "A cuboid was created using three cubes, each of which has a length of 8 centimeters (cm). Find the surface area of this cuboid.",
        "answer_ko": "896",
        "answer_en": "896",
        "solution_abst_ko": "8 8 [OP_MUL] 6 3 [OP_MUL] 4 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "8 8 [OP_MUL] 6 3 [OP_MUL] 4 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = 4\nvar_h = var_f - var_g\nvar_i = var_c * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 8\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = 4\nvar_h = var_f - var_g\nvar_i = var_c * var_h\nprint(int(var_i))"
    },
    "5558": {
        "category": "Geometry",
        "question_ko": "꼭짓점이 11개인 도형의 모든 대각선의 개수를 구하시오.",
        "question_en": "Find the number of all diagonals of a figure with 11 vertices.",
        "answer_ko": "44",
        "answer_en": "44",
        "solution_abst_ko": "11 11 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "11 11 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 11\nvar_b = 11\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 11\nvar_b = 11\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "5559": {
        "category": "Correspondence",
        "question_ko": "0.46 에 어떤 수를 더했더니 0.72 가 되었습니다. 어떤 수는 얼마입니까?",
        "question_en": "Adding a particular number to 0.46 gives 0.72. What is that particular number?",
        "answer_ko": "0.26",
        "answer_en": "0.26",
        "solution_abst_ko": "0.72 0.46 [OP_SUB]",
        "solution_abst_en": "0.72 0.46 [OP_SUB]",
        "solution_code_ko": "var_a = 0.72\nvar_b = 0.46\nvar_c = var_a - var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 0.72\nvar_b = 0.46\nvar_c = var_a - var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "5560": {
        "category": "Correspondence",
        "question_ko": "56-1A=39입니다. A는 얼마인가요?",
        "question_en": "56-1A=39 is true. If A is one-digit number, how much is A?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "56-1A=39 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "56-1A=39 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '56-1A=39'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '56-1A=39'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "5561": {
        "category": "Correspondence",
        "question_ko": "24는 어떤 수에서 36을 빼야할 것을 잘못하여 63을 빼서 나온 결과입니다. 바르게 계산한 결과를 구하시오.",
        "question_en": "24 is a result of subtracting 63 from a particular number by mistake when the original calculation was to subtract 36 from that particular number. Find the result of the original calculation.",
        "answer_ko": "51",
        "answer_en": "51",
        "solution_abst_ko": "24 63 [OP_ADD] 36 [OP_SUB]",
        "solution_abst_en": "24 63 [OP_ADD] 36 [OP_SUB]",
        "solution_code_ko": "var_a = 24\nvar_b = 63\nvar_c = var_a + var_b\nvar_d = 36\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 24\nvar_b = 63\nvar_c = var_a + var_b\nvar_d = 36\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "5562": {
        "category": "Arithmetic calculation",
        "question_ko": "호준이가 빵을 어제는 전체의 1/3을, 오늘은 전체의 2/5를 먹었습니다. 남은 부분은 전체의 얼마인지 구하시오.",
        "question_en": "Hojun ate 1/3 of the bread yesterday and 2/5 of it today. What is the remaining part of the whole?",
        "answer_ko": "0.27",
        "answer_en": "0.27",
        "solution_abst_ko": "1 1/3 [OP_SUB] 2/5 [OP_SUB]",
        "solution_abst_en": "1 1/3 [OP_SUB] 2/5 [OP_SUB]",
        "solution_code_ko": "var_a = 1\nvar_b = 0.3333333333333333\nvar_c = var_a - var_b\nvar_d = 0.4\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 0.3333333333333333\nvar_c = var_a - var_b\nvar_d = 0.4\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "5563": {
        "category": "Possibility",
        "question_ko": "숫자 카드 1, 6, 8을 한 번씩 모두 사용하여 가장 작은 세 자리수와 두 번째로 작은 세 자리수의 차를 구하시오.",
        "question_en": "Find the difference between the smallest 3-digit number and the second smallest 3-digit number using the number cards 1, 6, and 8 all once.",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = 2\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f - var_h\nvar_j = abs(var_i)\nprint(int(var_j))",
        "solution_code_en": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = 2\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f - var_h\nvar_j = abs(var_i)\nprint(int(var_j))"
    },
    "5564": {
        "category": "Comparison",
        "question_ko": "윤기는 4개, 유나는 5개, 정국이는 6 나누기 3만큼 사과를 가졌습니다. 누가 가진 사과가 가장 많습니까?",
        "question_en": "Yoongi has 4 apples, Yuna has 5, and Jungkook has 6 divided by 3 apples. Who has the most apples?",
        "answer_ko": "유나",
        "answer_en": "Yuna",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 유나 정국 [OP_LIST_EOL] [OP_LIST_SOL] 4 5 6 3 [OP_FDIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Yuna Jungkook [OP_LIST_EOL] [OP_LIST_SOL] 4 5 6 3 [OP_FDIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '유나'\nvar_c = '정국'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 5\nvar_f = 6\nvar_g = 3\nvar_h = var_f // var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Yuna'\nvar_c = 'Jungkook'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 5\nvar_f = 6\nvar_g = 3\nvar_h = var_f // var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "5565": {
        "category": "Arithmetic calculation",
        "question_ko": "과일가게에서 오전에 전체 사과의 3/10을 팔았고, 오후에 전체의 4/10을 팔았습니다. 오늘 판 사과의 수가 140개라면 어제 과일 가게에 있던 사과는 모두 몇 개인지 구하시오.",
        "question_en": "The fruit shop sold 3/10 of the total apples in the morning and 4/10 of the total in the afternoon. If the number of apples sold today is 140, how many apples were there in the fruit shop yesterday?",
        "answer_ko": "200",
        "answer_en": "200",
        "solution_abst_ko": "140 3/10 4/10 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "140 3/10 4/10 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 140\nvar_b = 0.3\nvar_c = 0.4\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 140\nvar_b = 0.3\nvar_c = 0.4\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "5566": {
        "category": "Arithmetic calculation",
        "question_ko": "창고에는 1번부터 22번 박스가 있고 각 박스마다 6부분으로 나뉘어져 있습니다. 각 부분마다 노트북이 5개씩 담겨져 있다면, 이 창고에는 모두 몇 개의 노트북이 있습니까?",
        "question_en": "There are boxes numbered 1 to 22 in the warehouse, and each box is divided into 6 parts. If each section contains 5 notebooks, how many notebooks are there in this warehouse?",
        "answer_ko": "660",
        "answer_en": "660",
        "solution_abst_ko": "22 6 [OP_MUL] 5 [OP_MUL]",
        "solution_abst_en": "22 6 [OP_MUL] 5 [OP_MUL]",
        "solution_code_ko": "var_a = 22\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 22\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "5567": {
        "category": "Arithmetic calculation",
        "question_ko": "3으로 나누어 떨어질 수 있는 네 자리 수는 모두 몇 개 있습니까?",
        "question_en": "How many four-digit numbers are divisible by 3?",
        "answer_ko": "3000",
        "answer_en": "3000",
        "solution_abst_ko": "1000 9999 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "1000 9999 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "5568": {
        "category": "Comparison",
        "question_ko": "A, B, C, D 중 A가 36이고, B는 27보다 5 큽니다. C는 10개씩 3묶음과 낱개 1개가 있는 수이고, D는 40보다 3 작습니다. 어떤 수가 가장 작습니까?",
        "question_en": "Of A, B, C, and D, A is 36, and B is 5 greater than 27. C is the number with 3 groups of 10,and D is 3 less than 40. Which number is the smallest?",
        "answer_ko": "C",
        "answer_en": "C",
        "solution_abst_ko": "[OP_LIST_SOL] A B C D [OP_LIST_EOL] [OP_LIST_SOL] 36 27 5 [OP_ADD] 3 10 [OP_MUL] 1 [OP_ADD] 40 3 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D [OP_LIST_EOL] [OP_LIST_SOL] 36 27 5 [OP_ADD] 3 10 [OP_MUL] 1 [OP_ADD] 40 3 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 36\nvar_f = 27\nvar_g = 5\nvar_h = var_f + var_g\nvar_i = 3\nvar_j = 10\nvar_k = var_i * var_j\nvar_l = 1\nvar_m = var_k + var_l\nvar_n = 40\nvar_o = 3\nvar_p = var_n - var_o\nlist_b= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_q = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_r = list_c[var_q-1]\nvar_s = list_b.index(var_r)+1\nvar_t = list_a[var_s-1]\nprint(var_t)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 36\nvar_f = 27\nvar_g = 5\nvar_h = var_f + var_g\nvar_i = 3\nvar_j = 10\nvar_k = var_i * var_j\nvar_l = 1\nvar_m = var_k + var_l\nvar_n = 40\nvar_o = 3\nvar_p = var_n - var_o\nlist_b= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_q = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_r = list_c[var_q-1]\nvar_s = list_b.index(var_r)+1\nvar_t = list_a[var_s-1]\nprint(var_t)"
    },
    "5569": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 8을 더했더니 88이 되었습니다. 10을 어떤 수에서 나눈 결과를 구하시오.",
        "question_en": "When you add 8 to a number, you get 88. Find the result of dividing 10 by the number.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "88 8 [OP_SUB] 10 [OP_DIV]",
        "solution_abst_en": "88 8 [OP_SUB] 10 [OP_DIV]",
        "solution_code_ko": "var_a = 88\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 10\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 88\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 10\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "5570": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 46을 뺐더니 15를 얻었습니다. 어떤 수에서 29를 빼면 얼마입니까?",
        "question_en": "Subtracting 46 from a number gives you 15. What is the subtraction of 29 from this number?",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "15 46 [OP_ADD] 29 [OP_SUB]",
        "solution_abst_en": "15 46 [OP_ADD] 29 [OP_SUB]",
        "solution_code_ko": "var_a = 15\nvar_b = 46\nvar_c = var_a + var_b\nvar_d = 29\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 46\nvar_c = var_a + var_b\nvar_d = 29\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "5571": {
        "category": "Comparison",
        "question_ko": "키가 작은 사람부터 순서대로 9명이 한 줄로 서 있습니다. 호석이가 가장 키가 큽니다. 키가 큰 사람부터 순서대로 다시 줄을 서면 호석이는 앞에서부터 몇 번째에 서게 됩니까?",
        "question_en": "Nine people are standing in a line in the order of shortest to tallest. Hoseok is the tallest. If they were lined up again in the order of tallest to shortest, in what position will Hoseok be from the very front? Answer in ordinal number.",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "9 9 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "9 9 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 9\nvar_b = 9\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 9\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "5572": {
        "category": "Correspondence",
        "question_ko": "등식 32+A7B=705이 성립한다고 합니다. A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "Say that the equation 32+A7B=705 holds. What number should be in A?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "32+A7B=705 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "32+A7B=705 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '32+A7B=705'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '32+A7B=705'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "5573": {
        "category": "Arithmetic calculation",
        "question_ko": "고양이는 키가 92cm이고 개는 키가 94cm이다. 고양이, 개, 새의 평균 키가 95cm일때 새의 키는 몇 cm인가?",
        "question_en": "The cat is 92 centimeters (cm) tall and the dog is 94 centimeters (cm) tall. If the average height of a cat, dog, or bird is 95 centimeters (cm), how tall is the bird in centimeters (cm)?",
        "answer_ko": "99",
        "answer_en": "99",
        "solution_abst_ko": "95 3 [OP_MUL] 92 [OP_SUB] 94 [OP_SUB]",
        "solution_abst_en": "95 3 [OP_MUL] 92 [OP_SUB] 94 [OP_SUB]",
        "solution_code_ko": "var_a = 95\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 92\nvar_e = var_c - var_d\nvar_f = 94\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 95\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 92\nvar_e = var_c - var_d\nvar_f = 94\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "5574": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 8센티미터(㎝)인 정사각형 상자 안에 반지름의 길이가 2센티미터(㎝)인 시계를 겹치지 않게 넣으려고 합니다. 한 층에 시계는 모두 몇 개를 넣을 수 있습니까?",
        "question_en": "A clock with a radius of 2 centimeters (cm) is placed inside a square box with a side length of 8 centimeters (cm), without overlapping it. How many clocks can you fit on one floor?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "8 2 2 [OP_MUL] [OP_DIV] 2 [OP_POW]",
        "solution_abst_en": "8 2 2 [OP_MUL] [OP_DIV] 2 [OP_POW]",
        "solution_code_ko": "var_a = 8\nvar_b = 2\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nvar_f = 2\nvar_g = var_e ** var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 8\nvar_b = 2\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nvar_f = 2\nvar_g = var_e ** var_f\nprint(int(var_g))"
    },
    "5575": {
        "category": "Geometry",
        "question_ko": "넓이가 215.6제곱미터(㎡)인 직사각형 모양의 땅이 있습니다. 가로가 14미터(m)이면 세로는 몇 미터(m)입니까?",
        "question_en": "There is a rectangular piece of land with an area of 215.6 square meters (m2). If the width is 14 meters (m), how many meters (m) is the length?",
        "answer_ko": "15.40",
        "answer_en": "15.4",
        "solution_abst_ko": "215.6 14 [OP_DIV]",
        "solution_abst_en": "215.6 14 [OP_DIV]",
        "solution_code_ko": "var_a = 215.6\nvar_b = 14\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 215.6\nvar_b = 14\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "5576": {
        "category": "Arithmetic calculation",
        "question_ko": "500쪽 짜리 책이 있습니다. 모든 쪽에는 1부터 500까지의 번호가 차례로 적혀있을 때, 숫자 4는 모두 몇 번 적혀 있는지 구하시오.",
        "question_en": "I have a book of 500 pages. If all pages are numbered from 1 to 500 in order, find how many times the number 4 is written on all pages.",
        "answer_ko": "200",
        "answer_en": "200",
        "solution_abst_ko": "1 500 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 4 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 500 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 4 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 500\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 4\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 500\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 4\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))"
    },
    "5577": {
        "category": "Comparison",
        "question_ko": "도서관에 똑같은 책장이 28개 있습니다. 각 책장은 6층이고, 각 층마다 꽂혀 있는 책의 수는 같습니다. 어느 책장의 한 층에 19개의 책이 꽂혀 있습니다. 도서관의 책장에 꽂혀 있는 책은 모두 몇 권입니까?",
        "question_en": "There are 28 identical bookshelves in the library. Each bookshelf has 6 floors, and the number of books on each floor is the same. There are 19 books on one floor of a bookshelf. How many books are on the shelves in the library?",
        "answer_ko": "3192",
        "answer_en": "3192",
        "solution_abst_ko": "28 6 [OP_MUL] 19 [OP_MUL]",
        "solution_abst_en": "28 6 [OP_MUL] 19 [OP_MUL]",
        "solution_code_ko": "var_a = 28\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 19\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 28\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 19\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "5578": {
        "category": "Comparison",
        "question_ko": "처음 석진이와 태형이가 각각 10장씩 도화지를 선물 받았습니다. 석진이가 5장을 사용하는 동안 태형이는 4장을 사용했습니다. 지금 도화지를 더 많이 갖고 있는 사람은 누구입니까?",
        "question_en": "In the beginning, Seokjin and Taehyung each received 10 pieces of drawing paper. While Seokjin used 5 pieces, Taehyung used 4. Who has more drawing paper now?",
        "answer_ko": "태형",
        "answer_en": "Taehyung",
        "solution_abst_ko": "[OP_LIST_SOL] 석진 태형 [OP_LIST_EOL] [OP_LIST_SOL] 10 5 [OP_SUB] 10 4 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Seokjin Taehyung [OP_LIST_EOL] [OP_LIST_SOL] 10 5 [OP_SUB] 10 4 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '석진'\nvar_b = '태형'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10\nvar_d = 5\nvar_e = var_c - var_d\nvar_f = 10\nvar_g = 4\nvar_h = var_f - var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Seokjin'\nvar_b = 'Taehyung'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10\nvar_d = 5\nvar_e = var_c - var_d\nvar_f = 10\nvar_g = 4\nvar_h = var_f - var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "5579": {
        "category": "Comparison",
        "question_ko": "놀이동산에 사람들이 줄을 서 있다. 은지가 여섯 번째로 탈 수 있고 뒤에 7명이 있을 때, 몇 명이 타기 위해 줄을 서고 있는지 구하시오.",
        "question_en": "People are standing in line at the amusement park. When Eunji can ride at sixth place and there are seven people behind her, find how many people are in line to ride.",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "6 7 [OP_ADD]",
        "solution_abst_en": "6 7 [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "5580": {
        "category": "Arithmetic calculation",
        "question_ko": "과자는 한 개에 300원이고 사탕은 한 개에 500원입니다. 과자와 사탕을 합하여 8개 사고 3000원을 사용했다면 사탕은 몇 개 샀을지 구하세요.",
        "question_en": "Snacks cost 300 won each and candies cost 500 won each. If you buy 8 of them in total and spend 3,000 won, what is the number of candies you buy?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "3000 300 8 [OP_MUL] [OP_SUB] 500 300 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "3000 300 8 [OP_MUL] [OP_SUB] 500 300 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 3000\nvar_b = 300\nvar_c = 8\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 500\nvar_g = 300\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 3000\nvar_b = 300\nvar_c = 8\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 500\nvar_g = 300\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "5581": {
        "category": "Arithmetic calculation",
        "question_ko": "리본 1개를 만들기 위해서는 끈 4미터(m)가 필요합니다. 지민이가 끈 105.8미터(m)를 사왔다면 리본을 몇 개 만들 수 있나요?",
        "question_en": "To make one ribbon, you need 4 meters (m) of string. If Jimin bought 105.8 meters (m) of string, how many ribbons can he make?",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "105.8 4 [OP_FDIV]",
        "solution_abst_en": "105.8 4 [OP_FDIV]",
        "solution_code_ko": "var_a = 105.8\nvar_b = 4\nvar_c = var_a // var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 105.8\nvar_b = 4\nvar_c = var_a // var_b\nprint(int(var_c))"
    },
    "5582": {
        "category": "Arithmetic calculation",
        "question_ko": "65센티미터(㎝)의 테이프 중 125밀리미터(㎜)를 지민이에게 주고 미술 시간에 153밀리미터(㎜)를 사용했습니다. 정국이에게 남아있는 테이프의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "Jungkook gave 125 mm (mm) of the 65 centimeters (cm) tape to Jimin and used 153 mm (mm) in art class. How long is the remaining tape in centimeters (cm) with Jungkook?",
        "answer_ko": "37.20",
        "answer_en": "37.2",
        "solution_abst_ko": "65 125 10 [OP_DIV] [OP_SUB] 153 10 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "65 125 10 [OP_DIV] [OP_SUB] 153 10 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 65\nvar_b = 125\nvar_c = 10\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nvar_f = 153\nvar_g = 10\nvar_h = var_f / var_g\nvar_i = var_e - var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 65\nvar_b = 125\nvar_c = 10\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nvar_f = 153\nvar_g = 10\nvar_h = var_f / var_g\nvar_i = var_e - var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "5583": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 10, 11, 12, 13이 있습니다. 그 중에서 가장 큰 수와 2번째로 큰 수로 나눈 나머지는 얼마입니까?",
        "question_en": "There are four numbers 10, 11, 12, and 13. What do you get as a remainder when you divide the largest number by the second largest number?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_MOD]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_MOD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = var_f % var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = var_f % var_h\nprint(int(var_i))"
    },
    "5584": {
        "category": "Correspondence",
        "question_ko": "기차가 15분에 4.5킬로미터(㎞)를 갔다고 한다. 이 기차가 5분 동안 간 거리는 몇 킬로미터(㎞)인가?",
        "question_en": "It is said that the train traveled 4.5 kilometers (km) in 15 minutes. How many kilometers (km) did this train travel in 5 minutes?",
        "answer_ko": "1.50",
        "answer_en": "1.5",
        "solution_abst_ko": "4.5 15 [OP_DIV] 5 [OP_MUL]",
        "solution_abst_en": "4.5 15 [OP_DIV] 5 [OP_MUL]",
        "solution_code_ko": "var_a = 4.5\nvar_b = 15\nvar_c = var_a / var_b\nvar_d = 5\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 4.5\nvar_b = 15\nvar_c = var_a / var_b\nvar_d = 5\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "5585": {
        "category": "Arithmetic calculation",
        "question_ko": "1학년과 2학년이 모두 95명 있습니다. 1학년이 32명일 때 2학년은 1학년보다 몇 명 더 많습니까?",
        "question_en": "There are 95 students in both first and second year classes. If there are 32 first graders, how many more sophomores are there than first graders?",
        "answer_ko": "31",
        "answer_en": "31",
        "solution_abst_ko": "95 32 [OP_SUB] 32 [OP_SUB]",
        "solution_abst_en": "95 32 [OP_SUB] 32 [OP_SUB]",
        "solution_code_ko": "var_a = 95\nvar_b = 32\nvar_c = var_a - var_b\nvar_d = 32\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 95\nvar_b = 32\nvar_c = var_a - var_b\nvar_d = 32\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "5586": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 3.1을 곱해야 할 것을 잘못하여 3.1을 더했더니 8.9가 되었습니다. 바르게 계산한 값에 2.5를 곱하면 얼마입니까?",
        "question_en": "I made the mistake of adding a number by 3.1 to get 8.9, which was supposed to be multiplied by 3.1. What is the correctly calculated value multiplied by 2.5?",
        "answer_ko": "44.95",
        "answer_en": "44.95",
        "solution_abst_ko": "8.9 3.1 [OP_SUB] 3.1 [OP_MUL] 2.5 [OP_MUL]",
        "solution_abst_en": "8.9 3.1 [OP_SUB] 3.1 [OP_MUL] 2.5 [OP_MUL]",
        "solution_code_ko": "var_a = 8.9\nvar_b = 3.1\nvar_c = var_a - var_b\nvar_d = 3.1\nvar_e = var_c * var_d\nvar_f = 2.5\nvar_g = var_e * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 8.9\nvar_b = 3.1\nvar_c = var_a - var_b\nvar_d = 3.1\nvar_e = var_c * var_d\nvar_f = 2.5\nvar_g = var_e * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "5587": {
        "category": "Comparison",
        "question_ko": "호현, 슬기는 각각 키가 162센티미터(㎝), 159센티미터(㎝)이라면 키가 가장 큰 사람은 누구인가?",
        "question_en": "If Hohyeon and Seulgi are 162 centimeters (cm) and 159 centimeters (cm) respectively, who is the tallest person?",
        "answer_ko": "호현",
        "answer_en": "Hohyeon",
        "solution_abst_ko": "[OP_LIST_SOL] 호현 슬기 [OP_LIST_EOL] [OP_LIST_SOL] 162 159 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Hohyeon Seulgi [OP_LIST_EOL] [OP_LIST_SOL] 162 159 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '호현'\nvar_b = '슬기'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 162\nvar_d = 159\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Hohyeon'\nvar_b = 'Seulgi'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 162\nvar_d = 159\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "5588": {
        "category": "Geometry",
        "question_ko": "사각형에 대해 하나의 대각선을 그으면, A각형이 B개 만들어집니다. A×B의 값은?",
        "question_en": "If you one diagonals from a rectangle, you can made A polygon with B edges. What is the value of A×B ?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "2 3 [OP_MUL]",
        "solution_abst_en": "2 3 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "5589": {
        "category": "Comparison",
        "question_ko": "정국이는 0.8, 윤기는 1/2, 유정이는 0.9의 숫자카드를 갖고 있습니다. 0.3보다 크거나 같은 숫자카드를 가지고 있는 사람은 몇 명입니까?",
        "question_en": "Jungkook has 0.8, Yoongi has 1/2, and Yoojung has 0.9. How many people have number cards greater than or equal to 0.3?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 0.3 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 0.3 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.3\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.3\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "5590": {
        "category": "Comparison",
        "question_ko": "5, 8, 9, 7 중에서 2번째로 작은 수는 무엇인가요?",
        "question_en": "What is the 2nd smallest number among 5, 8, 9, and 7?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "[OP_LIST_SOL] 5 8 9 7 [OP_LIST_EOL] 2 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 5 8 9 7 [OP_LIST_EOL] 2 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 5\nvar_b = 8\nvar_c = 9\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nprint(int(var_f))",
        "solution_code_en": "var_a = 5\nvar_b = 8\nvar_c = 9\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nprint(int(var_f))"
    },
    "5591": {
        "category": "Possibility",
        "question_ko": "5명의 학생들이 학교, 집, 수영장 세 가지 장소 중 한곳을 선택해 방문하려고 합니다. 학생들이 장소를 선택하는 경우는 모두 몇 가지입니까?",
        "question_en": "Five students want to visit one of three locations: school, home, or swimming pool. How many ways are there for students to choose the location?",
        "answer_ko": "243",
        "answer_en": "243",
        "solution_abst_ko": "3 5 [OP_POW]",
        "solution_abst_en": "3 5 [OP_POW]",
        "solution_code_ko": "var_a = 3\nvar_b = 5\nvar_c = var_a ** var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 5\nvar_c = var_a ** var_b\nprint(int(var_c))"
    },
    "5592": {
        "category": "Arithmetic calculation",
        "question_ko": "오리와 닭이 모두 95마리 있습니다. 오리가 32마리일 때 닭은 오리보다 몇 마리 더 많은지 구하시오.",
        "question_en": "There are 95 ducks and chickens in all. If there are 32 ducks, find how many more chickens are there than ducks?",
        "answer_ko": "31",
        "answer_en": "31",
        "solution_abst_ko": "95 32 [OP_SUB] 32 [OP_SUB]",
        "solution_abst_en": "95 32 [OP_SUB] 32 [OP_SUB]",
        "solution_code_ko": "var_a = 95\nvar_b = 32\nvar_c = var_a - var_b\nvar_d = 32\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 95\nvar_b = 32\nvar_c = var_a - var_b\nvar_d = 32\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "5593": {
        "category": "Comparison",
        "question_ko": "5가지 숫자 1.4, 9/10, 1.2, 0.5, 13/10 중에서 1.1보다 큰 수 중 가장 작은 숫자는 무엇입니까?",
        "question_en": "Find the smallest number that is greater than 1.1 out of the five numbers 1.4, 9/10, 1.2, 0.5, and 13/10.",
        "answer_ko": "1.20",
        "answer_en": "1.2",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nprint('{:.2f}'.format(round(var_h+1e-10,2)))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nprint('{:.2f}'.format(round(var_h+1e-10,2)))"
    },
    "5594": {
        "category": "Comparison",
        "question_ko": "총 3개의 숫자 0.8, 1/2, 0.5이 있습니다. 이 중 3보다 작은 수는 몇 개 일까요?",
        "question_en": "There are three numbers in total: 0.8, 1/2, and 0.5. How many of these numbers are less than 3?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.5 [OP_LIST_EOL] 3 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.5 [OP_LIST_EOL] 3 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = []\nfor i in list_a:\n    if i < var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = []\nfor i in list_a:\n    if i < var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "5595": {
        "category": "Comparison",
        "question_ko": "개당 200그램(g)인 귤이 담겨있는 상자가 5개 있습니다. 450그램(g)짜리 사과가 담겨있는 상자는 3개, 1개의 무게가 800그램(g)인 배가 담겨있는 상자는 4개 있습니다. 한 상자에 귤은 30개씩, 사과는 20개씩, 배는 15개씩 담겨있다고 한다면, 가장 수가 많은 과일은 무엇인지 구하시오.",
        "question_en": "There are 5 boxes containing tangerines that weigh 200 grams (g) each. There are 3 boxes containing apples that weigh 450 grams (g) each and 4 boxes containing pears that weigh 800 grams (g) each. If a box contains 30 tangerines, 20 apples, and 15 pears, what is the most numerous fruit?",
        "answer_ko": "귤",
        "answer_en": "tangerines",
        "solution_abst_ko": "[OP_LIST_SOL] 귤 사과 배 [OP_LIST_EOL] [OP_LIST_SOL] 30 5 [OP_MUL] 20 3 [OP_MUL] 15 4 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] tangerines apples pears [OP_LIST_EOL] [OP_LIST_SOL] 30 5 [OP_MUL] 20 3 [OP_MUL] 15 4 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '귤'\nvar_b = '사과'\nvar_c = '배'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 30\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = 20\nvar_h = 3\nvar_i = var_g * var_h\nvar_j = 15\nvar_k = 4\nvar_l = var_j * var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'tangerines'\nvar_b = 'apples'\nvar_c = 'pears'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 30\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = 20\nvar_h = 3\nvar_i = var_g * var_h\nvar_j = 15\nvar_k = 4\nvar_l = var_j * var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "5596": {
        "category": "Comparison",
        "question_ko": "1.4, 9/10, 1.2, 0.5, 13/10 중에서 1.1보다 크거나 같은 숫자를 고르고, 선택된 숫자들의 합을 구하세요",
        "question_en": "Choose all the numbers greater than or equal to 1.1 from among 1.4, 9/10, 1.2, 0.5, and 13/10, and find the sum of the selected numbers.",
        "answer_ko": "3.90",
        "answer_en": "3.9",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE_EQUAL] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE_EQUAL] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i >= var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i >= var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "5597": {
        "category": "Arithmetic calculation",
        "question_ko": "30미터(m)에 있는 돌은 초당 1미터(m)씩 떨어지고, 20미터(m)에 있는 돌은 초당 0.5미터(m)씩 떨어진다고 합니다. 두 돌의 높이가 같아졌을때의 높이를 구하여라",
        "question_en": "A stone that is 30 meters (m) high from the ground is said to fall at 1 meter (m) per second, and a stone 20 meters (m) high from the ground is said to fall at 0.5 meters (m) per second. Find the height of the two stones when they are at the same height.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "30 30 20 [OP_SUB] 1 0.5 [OP_SUB] [OP_DIV] [OP_SUB]",
        "solution_abst_en": "30 30 20 [OP_SUB] 1 0.5 [OP_SUB] [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 30\nvar_b = 30\nvar_c = 20\nvar_d = var_b - var_c\nvar_e = 1\nvar_f = 0.5\nvar_g = var_e - var_f\nvar_h = var_d / var_g\nvar_i = var_a - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 30\nvar_b = 30\nvar_c = 20\nvar_d = var_b - var_c\nvar_e = 1\nvar_f = 0.5\nvar_g = var_e - var_f\nvar_h = var_d / var_g\nvar_i = var_a - var_h\nprint(int(var_i))"
    },
    "5598": {
        "category": "Possibility",
        "question_ko": "7, 2, 5, 9라는 4종류의 숫자를 사용하여 네 자리 수를 만드려고 합니다. 만들 수 있는 네 자리 수는 모두 몇 개입니까?",
        "question_en": "You are trying to create a four-digit number using the four types of numbers: 7, 2, 5, and 9. How many four-digit numbers can you make?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "[OP_LIST_SOL] 7 2 5 9 [OP_LIST_EOL] [OP_LIST_LEN] 4 [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] 7 2 5 9 [OP_LIST_EOL] [OP_LIST_LEN] 4 [OP_PERM]",
        "solution_code_ko": "var_a = 7\nvar_b = 2\nvar_c = 5\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 4\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nprint(int(var_g))",
        "solution_code_en": "var_a = 7\nvar_b = 2\nvar_c = 5\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 4\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nprint(int(var_g))"
    },
    "5599": {
        "category": "Geometry",
        "question_ko": "세로가 3.6미터(m) 이고 가로가 세로의 2.5 배인 직사각형 모양의 밭이 있습니다. 이 밭의 절반에 토마토를 심었다면 토마토를 심은 밭의 넓이는 몇 제곱미터(㎡)입니까?",
        "question_en": "There is a rectangular-shaped field with a length of 3.6 meters (m) and a width 2.5 times its length. If you planted tomatoes in half of this field, what is the area of the field where tomatoes are planted in square meters (m2)?",
        "answer_ko": "16.20",
        "answer_en": "16.2",
        "solution_abst_ko": "3.6 3.6 2.5 [OP_MUL] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "3.6 3.6 2.5 [OP_MUL] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 3.6\nvar_b = 3.6\nvar_c = 2.5\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 3.6\nvar_b = 3.6\nvar_c = 2.5\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "5600": {
        "category": "Correspondence",
        "question_ko": "A3B-41=591일 때, A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "If A3B-41=591, what number should go in A?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "A3B-41=591 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A3B-41=591 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A3B-41=591'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A3B-41=591'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "5601": {
        "category": "Comparison",
        "question_ko": "왼쪽 버튼에는 21/5가, 오른쪽 버튼에는 4.9가 적혀 있습니다. 더 큰 수가 적힌 버튼을 누를 때, 어느 쪽 버튼을 눌러야 합니까?",
        "question_en": "The left button is written as 21/5 and the right button as 4.9. If you have to press the button with the higher number, which button would you choose to press?",
        "answer_ko": "오른쪽",
        "answer_en": "right",
        "solution_abst_ko": "[OP_LIST_SOL] 왼쪽 오른쪽 [OP_LIST_EOL] [OP_LIST_SOL] 21/5 4.9 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] left right [OP_LIST_EOL] [OP_LIST_SOL] 21/5 4.9 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '왼쪽'\nvar_b = '오른쪽'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4.2\nvar_d = 4.9\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'left'\nvar_b = 'right'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4.2\nvar_d = 4.9\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "5602": {
        "category": "Possibility",
        "question_ko": "6개의 배구팀이 서로 한 번씩 시합을 가진다면 모두 몇 번의 시합이 이루어지는지 모두 구하시오",
        "question_en": "If 6 volleyball teams play with each other once, how many matches will take place?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "6 2 [OP_COMB]",
        "solution_abst_en": "6 2 [OP_COMB]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))"
    },
    "5603": {
        "category": "Arithmetic calculation",
        "question_ko": "같은 모양의 책장을 8개 샀습니다. 이 책장은 5층으로 되어 있고 각 층마다 책을 85권씩 넣을 수 있습니다. 새로 산 책장에 넣을 수 있는 책은 모두 몇 권입니까?",
        "question_en": "I bought 8 bookshelves of the same shape. This bookshelf has 5 layers, and each layer can hold 85 books. How many books can I put in my new bookcase?",
        "answer_ko": "3400",
        "answer_en": "3400",
        "solution_abst_ko": "8 5 [OP_MUL] 85 [OP_MUL]",
        "solution_abst_en": "8 5 [OP_MUL] 85 [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 85\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 85\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "5604": {
        "category": "Geometry",
        "question_ko": "전시장에 한 모서리의 길이가 15센티미터(㎝)인 정육면체가 전시되어 있습니다. 이 정육면체의 모든 모서리의 길이의 합은?",
        "question_en": "A cube with one edge that is 15 centimeters (cm) long is displayed in the exhibition hall. What is the sum of the lengths of all the edges of this cube?",
        "answer_ko": "180",
        "answer_en": "180",
        "solution_abst_ko": "15 4 3 [OP_MUL] [OP_MUL]",
        "solution_abst_en": "15 4 3 [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 15\nvar_b = 4\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 4\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nprint(int(var_e))"
    },
    "5605": {
        "category": "Arithmetic calculation",
        "question_ko": "6의 배수 중 가장 큰 세 자리 수는?",
        "question_en": "What is the largest three-digit multiple of 6?",
        "answer_ko": "996",
        "answer_en": "996",
        "solution_abst_ko": "100 999 1 [OP_LIST_ARANGE] 6 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_abst_en": "100 999 1 [OP_LIST_ARANGE] 6 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))",
        "solution_code_en": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))"
    },
    "5606": {
        "category": "Geometry",
        "question_ko": "민호는 밑변이 15센티미터(㎝)이고 높이가 20센티미터(㎝)인 삼각형 모양의 삼각자를 갖고 있습니다. 이 삼각자의 겉을 따라서 삼각형을 그렸을 때, 그려진 삼각형의 넓이는 몇 제곱센티미터(㎠)인지 구하시오.",
        "question_en": "Minho has a triangular ruler with a base of 15 centimeters (cm) and a height of 20 centimeters (cm). When a triangle is drawn along the surface of this triangular ruler, find the area of the drawn triangle in square centimeters (cm2).",
        "answer_ko": "150",
        "answer_en": "150",
        "solution_abst_ko": "15 20 [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "15 20 [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 15\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "5607": {
        "category": "Comparison",
        "question_ko": "5마리의 물고기 (가), (나), (다), (라), (마)가 헤엄치는 속도를 비교해 보았습니다. (가)는 (나)보다 빠르지만 (다)보다는 느립니다. (라)는 (바)보다는 빠르지만 (나)보다는 느립니다. 이 중에서 가장 느린 물고기는 무엇입니까?",
        "question_en": "We compared the swimming speeds of five fish A, B, C, D, and E. A is faster than B but slower than C. D is faster than E but slower than B. Which of these fish is the slowest?",
        "answer_ko": "(마)",
        "answer_en": "E",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) (다) (라) (마) [OP_LIST_EOL] [OP_LIST_SOL] (가) (나) > (가) (다) < (마) (라) < (나) (라) > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D E [OP_LIST_EOL] [OP_LIST_SOL] A B > A C < E D < B D > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nvar_c = '(다)'\nvar_d = '(라)'\nvar_e = '(마)'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = '(가)'\nvar_g = '(나)'\nvar_h = '>'\nvar_i = '(가)'\nvar_j = '(다)'\nvar_k = '<'\nvar_l = '(마)'\nvar_m = '(라)'\nvar_n = '<'\nvar_o = '(나)'\nvar_p = '(라)'\nvar_q = '>'\nlist_b= []\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_r = len(list_c)\nvar_s = list_c[var_r-1]\nprint(var_s)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 'A'\nvar_g = 'B'\nvar_h = '>'\nvar_i = 'A'\nvar_j = 'C'\nvar_k = '<'\nvar_l = 'E'\nvar_m = 'D'\nvar_n = '<'\nvar_o = 'B'\nvar_p = 'D'\nvar_q = '>'\nlist_b= []\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_r = len(list_c)\nvar_s = list_c[var_r-1]\nprint(var_s)"
    },
    "5608": {
        "category": "Geometry",
        "question_ko": "작은 정사각형 모양의 공책을 빈틈없이 늘어놓아 큰 정사각형을 만들었더니 20개의 공책이 남았습니다. 가로 한 변과 세로 한 변을 1열씩 늘리려고 하였더니 9개의 공책이 부족하였습니다. 공책의 개수는 총 몇 개입니까?",
        "question_en": "When the small square-shaped notebooks are arraged without gaps to form a large square, there are 20 notebooks left. When I tried to increase the width and height by one row each, 9 notebooks were short. How many notebooks are there in total?",
        "answer_ko": "216",
        "answer_en": "216",
        "solution_abst_ko": "20 9 [OP_ADD] 1 [OP_SUB] 2 [OP_DIV] 2 [OP_POW] 20 [OP_ADD]",
        "solution_abst_en": "20 9 [OP_ADD] 1 [OP_SUB] 2 [OP_DIV] 2 [OP_POW] 20 [OP_ADD]",
        "solution_code_ko": "var_a = 20\nvar_b = 9\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 20\nvar_k = var_i + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 20\nvar_b = 9\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 20\nvar_k = var_i + var_j\nprint(int(var_k))"
    },
    "5609": {
        "category": "Correspondence",
        "question_ko": "A47BC는 다섯 자리 수이고 4, 5, 9의 배수입니다. A47BC에서 A가 될 수 있는 숫자는 모두 몇 개입니까?",
        "question_en": "A47BC is a five-digit number and is a multiple of 4, 5, or 9. How many possible numbers can be A in A47BC?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "A47BC [OP_GEN_POSSIBLE_LIST] 4 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] A47BC A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_abst_en": "A47BC [OP_GEN_POSSIBLE_LIST] 4 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] A47BC A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 'A47BC'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 4\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 5\nlist_c = []\nvar_c = int(var_c)\nfor i in list_b:\n    i = int(i)\n    if i % var_c == 0:\n        list_c.append(i)\nvar_d = 9\nlist_d = []\nvar_d = int(var_d)\nfor i in list_c:\n    i = int(i)\n    if i % var_d == 0:\n        list_d.append(i)\nvar_e = 'A47BC'\nvar_f = 'A'\nvar_e = str(var_e)\nvar_f = str(var_f)\nunk_idx = var_e.index(var_f)\nlist_e = []\nfor elem in list_d:\n    elem = str(elem)\n    list_e.append(int(elem[unk_idx]))\nlist_e = list(set(list_e))\nvar_g = len(list_e)\nprint(int(var_g))",
        "solution_code_en": "var_a = 'A47BC'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 4\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 5\nlist_c = []\nvar_c = int(var_c)\nfor i in list_b:\n    i = int(i)\n    if i % var_c == 0:\n        list_c.append(i)\nvar_d = 9\nlist_d = []\nvar_d = int(var_d)\nfor i in list_c:\n    i = int(i)\n    if i % var_d == 0:\n        list_d.append(i)\nvar_e = 'A47BC'\nvar_f = 'A'\nvar_e = str(var_e)\nvar_f = str(var_f)\nunk_idx = var_e.index(var_f)\nlist_e = []\nfor elem in list_d:\n    elem = str(elem)\n    list_e.append(int(elem[unk_idx]))\nlist_e = list(set(list_e))\nvar_g = len(list_e)\nprint(int(var_g))"
    },
    "5610": {
        "category": "Geometry",
        "question_ko": "둘레가 48센티미터(㎝)인 정사각형의 넓이는 얼마인가?",
        "question_en": "What is the area of a square with a perimeter of 48 centimeters (cm)?",
        "answer_ko": "144",
        "answer_en": "144",
        "solution_abst_ko": "48 4 [OP_DIV] 2 [OP_POW]",
        "solution_abst_en": "48 4 [OP_DIV] 2 [OP_POW]",
        "solution_code_ko": "var_a = 48\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 48\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint(int(var_e))"
    },
    "5611": {
        "category": "Arithmetic calculation",
        "question_ko": "파란 펜과 빨간 펜이 합쳐서 82개 있다. 파란 펜이 빨간 펜보다 6개 많을 때 파란 펜은 몇 개인지 구하시오.",
        "question_en": "There are 82 blue and red pens in total. Find the number of blue pens when there are 6 more blue pens than red pens.",
        "answer_ko": "44",
        "answer_en": "44",
        "solution_abst_ko": "82 6 [OP_SUB] 2 [OP_DIV] 6 [OP_ADD]",
        "solution_abst_en": "82 6 [OP_SUB] 2 [OP_DIV] 6 [OP_ADD]",
        "solution_code_ko": "var_a = 82\nvar_b = 6\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 6\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 82\nvar_b = 6\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 6\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "5612": {
        "category": "Geometry",
        "question_ko": "27개의 정육면체 주사위가 있고, 이 주사위들의 한 모서리의 길이는 3센티미터(㎝)입니다. 이 주사위들을 쌓아 정육면체를 만들었을 때, 쌓아 만든 정육면체의 겉넓이는?",
        "question_en": "There are 27 cube dice, and each side is 3 centimeters (cm) long. When these dice are stacked to form a cube, what is the surface area of the cube?",
        "answer_ko": "486",
        "answer_en": "486",
        "solution_abst_ko": "3 27 1/3 [OP_POW] [OP_MUL] 2 [OP_POW] 6 [OP_MUL]",
        "solution_abst_en": "3 27 1/3 [OP_POW] [OP_MUL] 2 [OP_POW] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 27\nvar_c = 0.3333333333333333\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e ** var_f\nvar_h = 6\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 3\nvar_b = 27\nvar_c = 0.3333333333333333\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e ** var_f\nvar_h = 6\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "5613": {
        "category": "Geometry",
        "question_ko": "육각형의 여섯 내각의 크기의 합은 몇 도입니까?",
        "question_en": "What is the sum of the measures of the six interior angles of a hexagon?",
        "answer_ko": "720",
        "answer_en": "720",
        "solution_abst_ko": "6 2 [OP_SUB] 180 [OP_MUL]",
        "solution_abst_en": "6 2 [OP_SUB] 180 [OP_MUL]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 180\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 180\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "5614": {
        "category": "Comparison",
        "question_ko": "빨간색 버스는 200킬로미터(㎞)를 가는데 4시간이 걸렸고, 노란색 버스는 180킬로미터(㎞)를 가는 데 3시간이 걸렸습니다. 어느 버스가 더 빠른가요?",
        "question_en": "The red bus took 4 hours to drive 200 kilometers (km), and the yellow bus took 3 hours to drive 180 kilometers (km). Which bus is faster?",
        "answer_ko": "노란색",
        "answer_en": "yellow",
        "solution_abst_ko": "[OP_LIST_SOL] 빨간색 노란색 [OP_LIST_EOL] [OP_LIST_SOL] 200 4 [OP_DIV] 180 3 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] red yellow [OP_LIST_EOL] [OP_LIST_SOL] 200 4 [OP_DIV] 180 3 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '빨간색'\nvar_b = '노란색'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 200\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 180\nvar_g = 3\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'red'\nvar_b = 'yellow'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 200\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 180\nvar_g = 3\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "5615": {
        "category": "Correspondence",
        "question_ko": "8로 나누었을 떄 나머지가 5이면서 3으로 나눈 나머지가 2인 수가 있다. 이러한 수를 작은 수부터 세었을 때 20째 수를 구하여라",
        "question_en": "There are numbers when divided by 8, the remainder is 5, and when divided by 3, the remainder is 2. When these numbers are counted from the smallest to largest, find the 20th number.",
        "answer_ko": "461",
        "answer_en": "461",
        "solution_abst_ko": "0 9999 1 [OP_LIST_ARANGE] 3 2 [OP_LIST_DIVIDE_AND_REMAIN] 8 5 [OP_LIST_DIVIDE_AND_REMAIN] 20 [OP_LIST_MIN]",
        "solution_abst_en": "0 9999 1 [OP_LIST_ARANGE] 3 2 [OP_LIST_DIVIDE_AND_REMAIN] 8 5 [OP_LIST_DIVIDE_AND_REMAIN] 20 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 0\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nvar_e = 2\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 8\nvar_g = 5\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 20\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nprint(int(var_i))",
        "solution_code_en": "var_a = 0\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nvar_e = 2\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 8\nvar_g = 5\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 20\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nprint(int(var_i))"
    },
    "5616": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 30을 빼면 70의 배수이다. 가능한 어떤 수 중 가장 작은 값을 구하시오. 단, 어떤 수는 280 이상이다.",
        "question_en": "Subtracting 30 from a number is a multiple of 70. Find the smallest value of any possible number. However, a number is greater than 280.",
        "answer_ko": "310",
        "answer_en": "310",
        "solution_abst_ko": "280 30 [OP_ADD]",
        "solution_abst_en": "280 30 [OP_ADD]",
        "solution_code_ko": "var_a = 280\nvar_b = 30\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 280\nvar_b = 30\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "5617": {
        "category": "Possibility",
        "question_ko": "주어진 숫자 카드 7, 5, 2를 한 번씩 모두 사용하여 530보다 크고 710보다 작은 수를 만들 때, 십의 자리에 올 수 있는 숫자를 쓰시오.",
        "question_en": "When using the given number cards 7, 5, and 2 all once to make a number greater than 530 and less than 710, write the number that can be in the tens place.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "[OP_LIST_SOL] 7 5 2 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 530 [OP_LIST_MORE] 710 [OP_LIST_LESS] 1 [OP_LIST_GET] 100 [OP_MOD] 10 [OP_FDIV]",
        "solution_abst_en": "[OP_LIST_SOL] 7 5 2 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 530 [OP_LIST_MORE] 710 [OP_LIST_LESS] 1 [OP_LIST_GET] 100 [OP_MOD] 10 [OP_FDIV]",
        "solution_code_ko": "var_a = 7\nvar_b = 5\nvar_c = 2\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 530\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = 710\nlist_d = []\nfor i in list_c:\n    if i < var_f:\n        list_d.append(i)\nvar_g = 1\nvar_h = list_d[var_g-1]\nvar_i = 100\nvar_j = var_h % var_i\nvar_k = 10\nvar_l = var_j // var_k\nprint(int(var_l))",
        "solution_code_en": "var_a = 7\nvar_b = 5\nvar_c = 2\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 530\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = 710\nlist_d = []\nfor i in list_c:\n    if i < var_f:\n        list_d.append(i)\nvar_g = 1\nvar_h = list_d[var_g-1]\nvar_i = 100\nvar_j = var_h % var_i\nvar_k = 10\nvar_l = var_j // var_k\nprint(int(var_l))"
    },
    "5618": {
        "category": "Possibility",
        "question_ko": "숫자 카드 1, 4, 9, 5를 한 번씩 모두 사용하여 합이 가장 작은 값을 구하시오.",
        "question_en": "Figure out the smallest sum of numbers that are made out of the number cards 1, 4, 9, and 5 using only once.",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "1 4 [OP_ADD] 9 [OP_ADD] 5 [OP_ADD]",
        "solution_abst_en": "1 4 [OP_ADD] 9 [OP_ADD] 5 [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "5619": {
        "category": "Arithmetic calculation",
        "question_ko": "초코 우유가 1.6리터(L) 있었습니다. 어제 0.8리터(L) 마시고 오늘 0.3리터(L) 마셨다면, 남은 초코 우유는 몇 리터(L)입니까?",
        "question_en": "There were 1.6 liters (L) of chocolate milk. If you drank 0.8 liters (L) yesterday and 0.3 liters (L) today, how many liters (L) of chocolate milk are left?",
        "answer_ko": "0.50",
        "answer_en": "0.5",
        "solution_abst_ko": "1.6 0.8 [OP_SUB] 0.3 [OP_SUB]",
        "solution_abst_en": "1.6 0.8 [OP_SUB] 0.3 [OP_SUB]",
        "solution_code_ko": "var_a = 1.6\nvar_b = 0.8\nvar_c = var_a - var_b\nvar_d = 0.3\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 1.6\nvar_b = 0.8\nvar_c = var_a - var_b\nvar_d = 0.3\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "5620": {
        "category": "Comparison",
        "question_ko": "5, 9, 10, 2 중에서 가장 작은 숫자를 선택하십시오.",
        "question_en": "Choose the smallest number among 5, 9, 10, and 2.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 5 9 10 2 [OP_LIST_EOL] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 5 9 10 2 [OP_LIST_EOL] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 5\nvar_b = 9\nvar_c = 10\nvar_d = 2\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nprint(int(var_f))",
        "solution_code_en": "var_a = 5\nvar_b = 9\nvar_c = 10\nvar_d = 2\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nprint(int(var_f))"
    },
    "5621": {
        "category": "Geometry",
        "question_ko": "길이 18센티미터(㎝)인 종이 테이프 12장을 겹쳐 둘레 210센티미터(㎝)의 둥근 고리를 만들었습니다. 겹친 부분의 길이는 같을 때, 얼마인지 밀리미터(㎜)로 나타내시오.",
        "question_en": "There are some pieces of paper tape of 18 centimeters (cm) each, and 12 pieces of it are overlapped to form a round ring with a circumference of 210 centimeters (cm). If the length of the overlapped part is the same, write down how much is it in millimeters (mm).\n",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "18 12 [OP_MUL] 210 [OP_SUB] 12 [OP_DIV] 10 [OP_MUL]",
        "solution_abst_en": "18 12 [OP_MUL] 210 [OP_SUB] 12 [OP_DIV] 10 [OP_MUL]",
        "solution_code_ko": "var_a = 18\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 210\nvar_e = var_c - var_d\nvar_f = 12\nvar_g = var_e / var_f\nvar_h = 10\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 18\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 210\nvar_e = var_c - var_d\nvar_f = 12\nvar_g = var_e / var_f\nvar_h = 10\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "5622": {
        "category": "Geometry",
        "question_ko": "한 모서리의 길이가 3㎝인 정육면체가 있습니다. 각 면의 한가운데서 한 모서리의 길이가 1㎝인 정육면체를 파내었을 때, 남은 부분의 부피는 몇 세제곱센티미터입니까?",
        "question_en": "There is a cube with each edge 3 centimeters (cm) long. If one digs out cubes with its edge 1 centimeters (cm) long from each center of the faces of the cube, what is the volume in cubic centimeters (cm3) of the remaining part?",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "3 3 [OP_POW] 1 3 [OP_POW] 6 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "3 3 [OP_POW] 1 3 [OP_POW] 6 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 3\nvar_b = 3\nvar_c = var_a ** var_b\nvar_d = 1\nvar_e = 3\nvar_f = var_d ** var_e\nvar_g = 6\nvar_h = var_f * var_g\nvar_i = var_c - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 3\nvar_b = 3\nvar_c = var_a ** var_b\nvar_d = 1\nvar_e = 3\nvar_f = var_d ** var_e\nvar_g = 6\nvar_h = var_f * var_g\nvar_i = var_c - var_h\nprint(int(var_i))"
    },
    "5623": {
        "category": "Comparison",
        "question_ko": "13명의 학생이 줄넘기 시합을 했습니다. 시합이 끝나고, 남준이 보다 개수가 적은 사람은 4명이었습니다. 남준이는 몇 등일까요?",
        "question_en": "Thirteen students competed in jumping rope. After the match, there were 4 people who did fewer jump ropes than Namjoon. What rank is Namjoon?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "13 4 [OP_SUB]",
        "solution_abst_en": "13 4 [OP_SUB]",
        "solution_code_ko": "var_a = 13\nvar_b = 4\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 13\nvar_b = 4\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "5624": {
        "category": "Arithmetic calculation",
        "question_ko": "소와 돼지의 합의 2배가 32이다. 소가 7마리이면 돼지는 몇마리인가?",
        "question_en": "2 times the sum of cows and pigs is 32. If there are 7 cows, how many pigs are there?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "32 2 [OP_DIV] 7 [OP_SUB]",
        "solution_abst_en": "32 2 [OP_DIV] 7 [OP_SUB]",
        "solution_code_ko": "var_a = 32\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 32\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "5625": {
        "category": "Correspondence",
        "question_ko": "여섯 자리 수 A2468B은 55로 나누어떨어지는 수이다. A2468B이 될 수 있는 수는 모두 몇 개인가?",
        "question_en": "The six-digit number A2468B is divisible by 55. How many possible numbers can be A2468B?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "A2468B [OP_GEN_POSSIBLE_LIST] 55 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "A2468B [OP_GEN_POSSIBLE_LIST] 55 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 'A2468B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 55\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A2468B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 55\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))"
    },
    "5626": {
        "category": "Arithmetic calculation",
        "question_ko": "유나네 반 학생 중에서 국어를 좋아하는 학생은 28명, 수학을 좋아하는 학생은 27명, 국어와 수학을 모두 좋아하는 학생은 22명입니다. 국어와 수학을 모두 좋아하지 않는 학생이 한 명도 없을 때, 유나네 반 학생은 모두 몇 명입니까?",
        "question_en": "Among the students in Yuna's class, there are 28 students who like Korean, 27 students who like math, and 22 students who like both Korean and math. If there is no student who does not like both Korean and math, how many students are there in Yuna's class?",
        "answer_ko": "33",
        "answer_en": "33",
        "solution_abst_ko": "28 27 [OP_ADD] 22 [OP_SUB]",
        "solution_abst_en": "28 27 [OP_ADD] 22 [OP_SUB]",
        "solution_code_ko": "var_a = 28\nvar_b = 27\nvar_c = var_a + var_b\nvar_d = 22\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 28\nvar_b = 27\nvar_c = var_a + var_b\nvar_d = 22\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "5627": {
        "category": "Possibility",
        "question_ko": "일곱 개의 숫자 0, 1, 2, 3, 4, 5, 6을 한 번씩 사용하여 일곱 자리 수를 만들었다. 이 수가 55의 배수일 때, 가장 작은 수를 구하여라.",
        "question_en": "The seven digits 0, 1, 2, 3, 4, 5, and 6 are used once to form a seven-digit number. If this number is a multiple of 55, find the smallest number.",
        "answer_ko": "1042635",
        "answer_en": "1042635",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 4 5 6 [OP_LIST_EOL] 7 [OP_LIST_GET_PERM] 55 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 4 5 6 [OP_LIST_EOL] 7 [OP_LIST_GET_PERM] 55 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nvar_f = 5\nvar_g = 6\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h = 7\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_h))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_i = 55\nlist_c = []\nvar_i = int(var_i)\nfor i in list_b:\n    i = int(i)\n    if i % var_i == 0:\n        list_c.append(i)\nvar_j = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_k = list_d[var_j-1]\nprint(int(var_k))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nvar_f = 5\nvar_g = 6\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h = 7\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_h))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_i = 55\nlist_c = []\nvar_i = int(var_i)\nfor i in list_b:\n    i = int(i)\n    if i % var_i == 0:\n        list_c.append(i)\nvar_j = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_k = list_d[var_j-1]\nprint(int(var_k))"
    },
    "5628": {
        "category": "Correspondence",
        "question_ko": "9A7을 버림하여 십의 자리까지 나타내면 930이다. A의 값을 구하시오.",
        "question_en": "If you round down 9A7 to the tens place, you get 930. Find the value of A.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "9A7 [OP_GEN_POSSIBLE_LIST] 930 [OP_LIST_MORE_EQUAL] 930 10 [OP_ADD] [OP_LIST_LESS] 9A7 A [OP_LIST_FIND_UNK]",
        "solution_abst_en": "9A7 [OP_GEN_POSSIBLE_LIST] 930 [OP_LIST_MORE_EQUAL] 930 10 [OP_ADD] [OP_LIST_LESS] 9A7 A [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = '9A7'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 930\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 930\nvar_d = 10\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = '9A7'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))",
        "solution_code_en": "var_a = '9A7'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 930\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 930\nvar_d = 10\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = '9A7'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))"
    },
    "5629": {
        "category": "Comparison",
        "question_ko": "주스 1리터(L)와 주스 3리터(L)를 모양과 크기가 같은 컵에 각각 똑같이 나누어 마시려고 합니다. 주스 1리터(L)를 컵 가 2개에, 주스 3리터(L)를 컵 나 4개에 똑같이 나누어 담을 때, 컵 가와 컵 나 중 어느 컵에 주스가 더 많을까요?",
        "question_en": "You want to drink 1 liter (L) of juice and 3 liters (L) of juice equally divided into cups of the same shape and size. If 1 liter (L) of juice is divided equally into 2 A cups and 3 liters (L) of juice is divided equally into 4 B cups, which cup has more juice, Cup A or Cup B?",
        "answer_ko": "나",
        "answer_en": "B",
        "solution_abst_ko": "[OP_LIST_SOL] 가 나 [OP_LIST_EOL] [OP_LIST_SOL] 1 2 [OP_MUL] 3 4 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 1 2 [OP_MUL] 3 4 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '가'\nvar_b = '나'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 3\nvar_g = 4\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 3\nvar_g = 4\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "5630": {
        "category": "Correspondence",
        "question_ko": "12를 A로 나눴더니 몫이 B가 되었고, 나머지는 C가 되었습니다. A, B, C는 자연수 입니다. 몫과 나머지가 같을 때, 가능한 A 중 가장 큰 수는 무엇인가요?",
        "question_en": "When 12 is divided by A, the quotient is B and the remainder is C. A, B, and C are natural numbers. If the quotient and the remainder are equal, what is the largest possible A?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "12 1 [OP_SUB]",
        "solution_abst_en": "12 1 [OP_SUB]",
        "solution_code_ko": "var_a = 12\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 12\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "5631": {
        "category": "Geometry",
        "question_ko": "어떤 정사각형의 가로를 0.8배, 세로를 5배로 하여 새로운 직사각형을 만들었더니 그 넓이가 처음 정사각형의 넓이보다 15.18제곱센티미터(㎠)만큼 늘었습니다. 처음 정사각형의 넓이는 몇 제곱센티미터(㎠)입니까?",
        "question_en": "If you multiply the width of a square by 0.8 and the length by 5 to create a new rectangle, its area increases by 15.18 square centimeters (cm2) than the area of the original square. What is the area of the first square in square centimeters (cm2)?",
        "answer_ko": "5.06",
        "answer_en": "5.06",
        "solution_abst_ko": "15.18 0.8 5 [OP_MUL] 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "15.18 0.8 5 [OP_MUL] 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 15.18\nvar_b = 0.8\nvar_c = 5\nvar_d = var_b * var_c\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_a / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 15.18\nvar_b = 0.8\nvar_c = 5\nvar_d = var_b * var_c\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_a / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "5632": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 5를 곱한 다음 10을 곱해야 할 것을 잘못하여 15를 곱하였더니 45가 되었습니다. 바르게 계산한 결과를 구하시오.",
        "question_en": "You had to multiply a number by 5 and then multiply by 10, but mistakenly multiplied 15 instead to get 45. Find the correctly calculated value.",
        "answer_ko": "150",
        "answer_en": "150",
        "solution_abst_ko": "45 15 [OP_DIV] 5 [OP_MUL] 10 [OP_MUL]",
        "solution_abst_en": "45 15 [OP_DIV] 5 [OP_MUL] 10 [OP_MUL]",
        "solution_code_ko": "var_a = 45\nvar_b = 15\nvar_c = var_a / var_b\nvar_d = 5\nvar_e = var_c * var_d\nvar_f = 10\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 45\nvar_b = 15\nvar_c = var_a / var_b\nvar_d = 5\nvar_e = var_c * var_d\nvar_f = 10\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "5633": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.9, 1/3 중에서 0.4보다 작거나 같은 수는 몇 개입니까?",
        "question_en": "How many of 0.8, 1/2, 0.9, and 1/3 are less than or equal to 0.4?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.4\nlist_b = []\nfor i in list_a:\n    if i <= var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.4\nlist_b = []\nfor i in list_a:\n    if i <= var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "5634": {
        "category": "Comparison",
        "question_ko": "10원짜리 동전, 50원짜리 동전, 100원짜리 동전이 모두 108개 있습니다. 50원짜리 동전은 10원짜리 동전의 1/3개 있고, 100원짜리 동전은 50원짜리 동전의 1/2개 있습니다. 몇 원짜리 동전이 가장 적게 있습니까?",
        "question_en": "A total of 108 coins consists of 10-won coins, 50-won coins, and 100-won coins. The amount of the 50-won coins is 1/3 of the amount of the 10-won coins, and the amount of the 100-won coins is 1/2 of that of the 50-won coins. What kind of won-coins do you have the least?",
        "answer_ko": "100원",
        "answer_en": "100-won",
        "solution_abst_ko": "[OP_LIST_SOL] 10원 50원 100원 [OP_LIST_EOL] [OP_LIST_SOL] 1 1 3 [OP_DIV] 1 3 [OP_DIV] 2 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] 10-won 50-won 100-won [OP_LIST_EOL] [OP_LIST_SOL] 1 1 3 [OP_DIV] 1 3 [OP_DIV] 2 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '10원'\nvar_b = '50원'\nvar_c = '100원'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nvar_e = 1\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = 1\nvar_i = 3\nvar_j = var_h / var_i\nvar_k = 2\nvar_l = var_j / var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[var_m-1]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = '10-won'\nvar_b = '50-won'\nvar_c = '100-won'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nvar_e = 1\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = 1\nvar_i = 3\nvar_j = var_h / var_i\nvar_k = 2\nvar_l = var_j / var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[var_m-1]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "5635": {
        "category": "Geometry",
        "question_ko": "사각형이 있을 때 두 개의 대각선을 그을경우 A각형이 B개, 직각 A각형이 C개 만들어진다. A×(B+C)는?",
        "question_en": "If you draw two diagonals from a square, you get B polygons having A sides and C right-angled polygons having A sides. What is A×(B+C)?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "3 8 [OP_MUL]",
        "solution_abst_en": "3 8 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 8\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 8\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "5636": {
        "category": "Arithmetic calculation",
        "question_ko": "큰 통 속에 밀가루가 10.4킬로그램(㎏) 있습니다. 이 밀가루를 여러 개의 그릇에 나누어 담으려고 할 때, 그릇 한 개에 0.8킬로그램(㎏) 씩 나누어 담으려면 그릇은 모두 몇 개가 필요할까요?",
        "question_en": "There are 10.4 kilograms (kg) of flour in a large barrel. If you want to divide this flour into several bowls, how many bowls will you need to divide 0.8 kg (kg) into each bowl?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "10.4 0.8 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "10.4 0.8 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 10.4\nvar_b = 0.8\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))",
        "solution_code_en": "var_a = 10.4\nvar_b = 0.8\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))"
    },
    "5637": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 4로 나누었더니 결과가 12가 나왔습니다. 3으로 어떤 수를 나눈 결과는 무엇입니까?",
        "question_en": "When you divide a number by 4, you get 12. What is the result of dividing the number by 3?",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "12 4 [OP_MUL] 3 [OP_DIV]",
        "solution_abst_en": "12 4 [OP_MUL] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "5638": {
        "category": "Correspondence",
        "question_ko": "A는 한 자리 수입니다. AA×AA=5929를 만족하는, A를 구하시오.",
        "question_en": "A is a single digit number. Find A when the multiplication expression AA×AA of two digit numbers is 5929.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "AA×AA=5929 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "AA×AA=5929 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'AA×AA=5929'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'AA×AA=5929'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "5639": {
        "category": "Geometry",
        "question_ko": "직사각형의 텃밭이 있습니다. 이 텃밭의 둘레가 48미터(m)이고 텃밭의 가로에 2미터(m)를 더하면 세로의 길이이다. 텃밭의 가로의 길이는 얼마인지 구하시오.",
        "question_en": "There is a rectangular garden. The perimeter of this garden is 48 meters (m), and the length of the garden is 2 meters (m) added to its width. Find the width of the garden.",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "48 2 [OP_DIV] 2 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "48 2 [OP_DIV] 2 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 48\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 48\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "5640": {
        "category": "Comparison",
        "question_ko": "화분 (가)는 오른쪽에서부터 14번째, 화분 (나)는 왼쪽으로부터 29번째에 있습니다. 전체 화분의 수가 33개라면, (가) 화분과 (나) 화분사이에는 몇 개가 있습니까?",
        "question_en": "Flowerpot A is 14th from the right, and flowerpot B is 29th from the left. If the total number of pots is 33, how many are there between A and B?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "14 29 [OP_ADD] 33 [OP_SUB] 2 [OP_SUB]",
        "solution_abst_en": "14 29 [OP_ADD] 33 [OP_SUB] 2 [OP_SUB]",
        "solution_code_ko": "var_a = 14\nvar_b = 29\nvar_c = var_a + var_b\nvar_d = 33\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 14\nvar_b = 29\nvar_c = var_a + var_b\nvar_d = 33\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "5641": {
        "category": "Arithmetic calculation",
        "question_ko": "2부터 7까지의 홀수 중 가장 작은 수를 구하시오.",
        "question_en": "Find the smallest odd number between 2 and 7.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "2 7 [OP_LIST_ODD] 1 [OP_LIST_MIN]",
        "solution_abst_en": "2 7 [OP_LIST_ODD] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 2\nvar_b = 7\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[var_c-1]\nprint(int(var_d))",
        "solution_code_en": "var_a = 2\nvar_b = 7\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[var_c-1]\nprint(int(var_d))"
    },
    "5642": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 30센티미터(㎝)인 선분 위에 5센티미터(㎝) 간격으로 점을 찍으려고 합니다. 선분의 처음과 끝에는 점을 찍지 않을 때, 점은 몇 번 찍어야 합니까?",
        "question_en": "You want to draw points at intervals of 5 centimeters (cm) on a line that is 30 centimeters (cm) long. How many times should a dot be drawn when there is no dot at the beginning and end of a line?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "30 5 [OP_DIV] 1 [OP_SUB]",
        "solution_abst_en": "30 5 [OP_DIV] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 30\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 30\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "5643": {
        "category": "Correspondence",
        "question_ko": "주머니 속에 구슬이 총 60개가 들어있습니다. 검은색 구슬이 32개, 빨간색 구슬이 10개, 초록색 구슬이 5개 있습니다. 주머니 속 구슬의 색깔이 검은색, 빨간색, 초록색, 흰색이 있을 경우 흰색 구슬은 몇 개가 있나요?",
        "question_en": "There are a total of 60 marbles in the bag. There are 32 black marbles, 10 red marbles, and 5 green marbles. If the marbles in the bag are black, red, green, and white, how many white marbles are there?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "60 32 [OP_SUB] 10 [OP_SUB] 5 [OP_SUB]",
        "solution_abst_en": "60 32 [OP_SUB] 10 [OP_SUB] 5 [OP_SUB]",
        "solution_code_ko": "var_a = 60\nvar_b = 32\nvar_c = var_a - var_b\nvar_d = 10\nvar_e = var_c - var_d\nvar_f = 5\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 60\nvar_b = 32\nvar_c = var_a - var_b\nvar_d = 10\nvar_e = var_c - var_d\nvar_f = 5\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "5644": {
        "category": "Possibility",
        "question_ko": "각 자리의 수가 홀수인 세 자리 수는 모두 몇 개입니까?",
        "question_en": "How many three-digit numbers are there where each digit is odd?",
        "answer_ko": "125",
        "answer_en": "125",
        "solution_abst_ko": "1 9 [OP_LIST_ODD] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_LEN]",
        "solution_abst_en": "1 9 [OP_LIST_ODD] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = len(list_b)\nprint(int(var_d))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = len(list_b)\nprint(int(var_d))"
    },
    "5645": {
        "category": "Arithmetic calculation",
        "question_ko": "1, 4, 0, 7, 5, 2, 8이 있습니다. 왼쪽에서 2번째와 7번째 사이에 있는 수를 한 번씩만 사용하여 네 자리 수를 만들려고 합니다. 만들 수 있는 수 중에서 4번째로 큰 수를 구하시오.",
        "question_en": "There are 1, 4, 0, 7, 5, 2, and 8. You want to create a four-digit number by using the numbers between the 2nd and 7th from the left only once. Find the 4th largest number that can be made.",
        "answer_ko": "7520",
        "answer_en": "7520",
        "solution_abst_ko": "[OP_LIST_SOL] 4 0 7 5 2 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 4 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 4 0 7 5 2 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 4 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 4\nvar_b = 0\nvar_c = 7\nvar_d = 5\nvar_e = 2\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 4\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nprint(int(var_h))",
        "solution_code_en": "var_a = 4\nvar_b = 0\nvar_c = 7\nvar_d = 5\nvar_e = 2\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 4\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nprint(int(var_h))"
    },
    "5646": {
        "category": "Comparison",
        "question_ko": "정국이는 6 나누기 3만큼 사과를 모았고, 윤기는 사과를 4개 모았습니다. 누가 더 사과가 적습니까?",
        "question_en": "Jungkook collected 6 divided by 3 apples, and Yoongi collected 4 apples. Who has fewer apples?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 윤기 [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_FDIV] 4 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Yoongi [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_FDIV] 4 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '윤기'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 3\nvar_e = var_c // var_d\nvar_f = 4\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Yoongi'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 3\nvar_e = var_c // var_d\nvar_f = 4\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "5647": {
        "category": "Possibility",
        "question_ko": "6보다 작은 소수 두 자리 수를 만드려고 합니다. 이때2, 4, 6과 소수점을 한번씩만 쓸 수 있다면 모두 몇 개를 만들 수 있습니까?",
        "question_en": "You want to create a number with two decimal places less than 6. How many can you make if you can only use 2, 4, 6 and the decimal point once?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 2 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 6 10 3 1 [OP_SUB] [OP_POW] [OP_MUL] [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 2 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 6 10 3 1 [OP_SUB] [OP_POW] [OP_MUL] [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = 6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 6\nvar_f = 10\nvar_g = 3\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = var_f ** var_i\nvar_k = var_e * var_j\nlist_c = []\nfor i in list_b:\n    if i < var_k:\n        list_c.append(i)\nvar_l = len(list_c)\nprint(int(var_l))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = 6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 6\nvar_f = 10\nvar_g = 3\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = var_f ** var_i\nvar_k = var_e * var_j\nlist_c = []\nfor i in list_b:\n    if i < var_k:\n        list_c.append(i)\nvar_l = len(list_c)\nprint(int(var_l))"
    },
    "5648": {
        "category": "Arithmetic calculation",
        "question_ko": "집에서 300 킬로미터(㎞) 떨어진 공항까지 자동차를 타고 시속 60 킬로미터(㎞)로 출발한 지 2시간 지났을 때 남은 거리를 구하시오.",
        "question_en": "Find the distance left after 2 hours of driving to an airport which is 300 kilometers (km) from home at 60 kilometers (km) per hour.",
        "answer_ko": "180",
        "answer_en": "180",
        "solution_abst_ko": "300 60 2 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "300 60 2 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 300\nvar_b = 60\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 300\nvar_b = 60\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "5649": {
        "category": "Geometry",
        "question_ko": "한변의 길이가 2센티미터(㎝)인 정팔면체의 겉넓이는?",
        "question_en": "What is the surface area of an octahedron with sides of 2 centimeters (cm)?",
        "answer_ko": "10.39",
        "answer_en": "10.39",
        "solution_abst_ko": "3 3 1/2 [OP_POW] [OP_MUL] 2 [OP_DIV] 2 2 [OP_POW] [OP_MUL]",
        "solution_abst_en": "3 3 1/2 [OP_POW] [OP_MUL] 2 [OP_DIV] 2 2 [OP_POW] [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 3\nvar_c = 0.5\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = 2\nvar_j = var_h ** var_i\nvar_k = var_g * var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 3\nvar_b = 3\nvar_c = 0.5\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = 2\nvar_j = var_h ** var_i\nvar_k = var_g * var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "5650": {
        "category": "Geometry",
        "question_ko": "가로가 262킬로미터(㎞)이고 세로가 185킬로미터(㎞)인 직사각형 모양의 빈 땅에 정사각형 모양의 땅으로 나눠 아파트 단지를 건설할 생각이다. 아파트 단지의 한 변이 18킬로미터(㎞)라면 몇 개의 아파트단지를 지을 수 있는지 구하시오.",
        "question_en": "You want to build an apartment complex on a rectangular piece of empty land that is 262 kilometers (km) wide and 185 km long, divided into squares. If one side of the apartment complex is 18 kilometers (km), find how many apartment complexes can be built.",
        "answer_ko": "140",
        "answer_en": "140",
        "solution_abst_ko": "262 18 [OP_FDIV] 185 18 [OP_FDIV] [OP_MUL]",
        "solution_abst_en": "262 18 [OP_FDIV] 185 18 [OP_FDIV] [OP_MUL]",
        "solution_code_ko": "var_a = 262\nvar_b = 18\nvar_c = var_a // var_b\nvar_d = 185\nvar_e = 18\nvar_f = var_d // var_e\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 262\nvar_b = 18\nvar_c = var_a // var_b\nvar_d = 185\nvar_e = 18\nvar_f = var_d // var_e\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "5651": {
        "category": "Arithmetic calculation",
        "question_ko": "2의 배수이면서 3의 배수이면서 8의 배수이면서 9의 배수인 수 중 가장 큰 다섯 자리 수는?",
        "question_en": "What is the largest five-digit number that is a multiple of 2 and a multiple of 3 and a multiple of 8 and a multiple of 9?",
        "answer_ko": "99936",
        "answer_en": "99936",
        "solution_abst_ko": "10000 99999 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_abst_en": "10000 99999 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 10000\nvar_b = 99999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 3\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = 1\nlist_f=list_e.copy()\nlist_f.sort()\nvar_i = list_f[-var_h]\nprint(int(var_i))",
        "solution_code_en": "var_a = 10000\nvar_b = 99999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 3\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = 1\nlist_f=list_e.copy()\nlist_f.sort()\nvar_i = list_f[-var_h]\nprint(int(var_i))"
    },
    "5652": {
        "category": "Possibility",
        "question_ko": "1부터 5까지의 숫자가 각각 한 개씩 적힌 숫자 카드가 5장 있다. 이 중에서 3장을 꺼내 그 숫자의 합을 구할 때, 나올 수 있는 모든 합들의 총합을 구하여라.",
        "question_en": "There are 5 number cards, each with a number from 1 to 5 written on it. When you take out 3 of these and find the sum of the numbers, find the sum of all possible sums.",
        "answer_ko": "63",
        "answer_en": "63",
        "solution_abst_ko": "1 5 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] [OP_LIST_SOL] [OP_LIST_EOL] [OP_SET_UNION] [OP_LIST_SUM]",
        "solution_abst_en": "1 5 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] [OP_LIST_SOL] [OP_LIST_EOL] [OP_SET_UNION] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 5\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nlist_d= []\nlist_d.reverse()\nlist_e = list(set(list_c) | set(list_d))\nlist_e = [float(i) for i in list_e]\nvar_f = sum(list_e)\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 5\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nlist_d= []\nlist_d.reverse()\nlist_e = list(set(list_c) | set(list_d))\nlist_e = [float(i) for i in list_e]\nvar_f = sum(list_e)\nprint(int(var_f))"
    },
    "5653": {
        "category": "Possibility",
        "question_ko": "0, 4, 6, 7, 8 중에 한 번씩만 사용하여 만들 수 있는 다섯 자리 수 중에서 여섯 번째로 작은 수를 구하시오.",
        "question_en": "Find the sixth smallest number among five digits that can be formed using 0, 4, 6, 7, and 8 only once.",
        "answer_ko": "40876",
        "answer_en": "40876",
        "solution_abst_ko": "[OP_LIST_SOL] 0 4 6 7 8 [OP_LIST_EOL] 5 [OP_LIST_GET_PERM] 6 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 4 6 7 8 [OP_LIST_EOL] 5 [OP_LIST_GET_PERM] 6 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 0\nvar_b = 4\nvar_c = 6\nvar_d = 7\nvar_e = 8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 5\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 6\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nprint(int(var_h))",
        "solution_code_en": "var_a = 0\nvar_b = 4\nvar_c = 6\nvar_d = 7\nvar_e = 8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 5\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 6\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nprint(int(var_h))"
    },
    "5654": {
        "category": "Correspondence",
        "question_ko": "A, B는 한 자리 수입니다. A는 5보다 3 큰 수이고, B는 A보다 2 작은 수입니다. A와 B의 합을 구하시오.",
        "question_en": "A and B are single-digit numbers. A is 3 greater than 5, and B is 2 less than A. Find the sum of A and B.",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "5 3 [OP_ADD] 5 3 [OP_ADD] 2 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "5 3 [OP_ADD] 5 3 [OP_ADD] 2 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = 2\nvar_h = var_f - var_g\nvar_i = var_c + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 5\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = 2\nvar_h = var_f - var_g\nvar_i = var_c + var_h\nprint(int(var_i))"
    },
    "5655": {
        "category": "Comparison",
        "question_ko": "현진이네 학교에는 여학생이 324명, 남학생이 541명 있고, 선주네 학교에는 여학생이 416명, 남학생이 253명 있습니다. 누구의 학교에 학생이 더 많은지 구하시오.",
        "question_en": "Hyunjin's school has 324 female students and 541 male students, and Seonju's school has 416 female students and 253 male students. Find whose school has more students.",
        "answer_ko": "현진",
        "answer_en": "Hyunjin",
        "solution_abst_ko": "[OP_LIST_SOL] 현진 선주 [OP_LIST_EOL] [OP_LIST_SOL] 324 541 [OP_ADD] 416 253 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Hyunjin Seonju [OP_LIST_EOL] [OP_LIST_SOL] 324 541 [OP_ADD] 416 253 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '현진'\nvar_b = '선주'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 324\nvar_d = 541\nvar_e = var_c + var_d\nvar_f = 416\nvar_g = 253\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Hyunjin'\nvar_b = 'Seonju'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 324\nvar_d = 541\nvar_e = var_c + var_d\nvar_f = 416\nvar_g = 253\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "5656": {
        "category": "Arithmetic calculation",
        "question_ko": "수학이 100점이고 국어, 영어의 평균점수가 88점일때 세 과목 평균 점수는 몇 점인가",
        "question_en": "Find the average score of three subjects when Math is 100, and the average score of Korean and English is 88.",
        "answer_ko": "92",
        "answer_en": "92",
        "solution_abst_ko": "88 2 [OP_MUL] 100 [OP_ADD] 2 1 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "88 2 [OP_MUL] 100 [OP_ADD] 2 1 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 88\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 88\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "5657": {
        "category": "Arithmetic calculation",
        "question_ko": "32의 약수 중 두 번째로 작은 값을 구하시오.",
        "question_en": "Find the second smallest factor of 32.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "32 [OP_LIST_GET_DIVISOR] 2 [OP_LIST_MIN]",
        "solution_abst_en": "32 [OP_LIST_GET_DIVISOR] 2 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 32\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_c = list_b[var_b-1]\nprint(int(var_c))",
        "solution_code_en": "var_a = 32\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_c = list_b[var_b-1]\nprint(int(var_c))"
    },
    "5658": {
        "category": "Arithmetic calculation",
        "question_ko": "파인애플 하나를 가족들이 나눠 먹기로 하였습니다. 할아버지께서 전체의 1/6을 드시고, 할머니께서 남은 파인애플의 2/5를 드셨습니다. 할아버지와 할머니께서 드시고 남은 파인애플의 2/3을 채영이가 먹은 후 남아 있는 파인애플이 120그램(g)이라면, 처음 파인애플의 무게는 몇 그램(g)이었을까요?",
        "question_en": "A family decided to share one pineapple. Grandpa ate 1/6 of the whole, and Grandma ate 2/5 of the remaining pineapple. If the remaining pineapple after Chaeyoung ate 2/3 of the pineapple left after Grandpa and Grandma ate was 120 grams (g), how many grams (g) did the first pineapple weigh?",
        "answer_ko": "720",
        "answer_en": "720",
        "solution_abst_ko": "120 1 1/6 [OP_SUB] [OP_DIV] 1 2/5 [OP_SUB] [OP_DIV] 1 2/3 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "120 1 1/6 [OP_SUB] [OP_DIV] 1 2/5 [OP_SUB] [OP_DIV] 1 2/3 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 120\nvar_b = 1\nvar_c = 0.16666666666666666\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 1\nvar_g = 0.4\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 1\nvar_k = 0.6666666666666666\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nprint(int(eval('{:.2f}'.format(round(var_m+1e-10,2)))))",
        "solution_code_en": "var_a = 120\nvar_b = 1\nvar_c = 0.16666666666666666\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 1\nvar_g = 0.4\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 1\nvar_k = 0.6666666666666666\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nprint(int(eval('{:.2f}'.format(round(var_m+1e-10,2)))))"
    },
    "5659": {
        "category": "Geometry",
        "question_ko": "지름이 26센티미터(㎝)인 원의 반지름의 길이는 몇 센티미터(㎝)인가?",
        "question_en": "What is the length in centimeters (cm) of the radius of a circle whose diameter are 26 centimeters (cm)?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "26 2 [OP_DIV]",
        "solution_abst_en": "26 2 [OP_DIV]",
        "solution_code_ko": "var_a = 26\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 26\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "5660": {
        "category": "Arithmetic calculation",
        "question_ko": "올해 석진이는 7살이고 석진이 어머니는 33살입니다. 5년 후에 석진이 어머니는 석진이보다 몇 살 더 많습니까?",
        "question_en": "This year Seokjin is 7 years old and Seokjin's mother is 33 years old. After 5 years, how many years is Seokjin's mother older than Seokjin?",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "33 5 [OP_ADD] 7 5 [OP_ADD] [OP_SUB]",
        "solution_abst_en": "33 5 [OP_ADD] 7 5 [OP_ADD] [OP_SUB]",
        "solution_code_ko": "var_a = 33\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 7\nvar_e = 5\nvar_f = var_d + var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 33\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 7\nvar_e = 5\nvar_f = var_d + var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "5661": {
        "category": "Arithmetic calculation",
        "question_ko": "한 상자에 16개씩 들어 있는 오이를 7상자 샀습니다. 그 중에서 13개는 썩어서 버리고, 남은 오이를 8봉지에 똑같이 나누어 담으려고 합니다. 봉지에 들어가지 못한 남은 오이는 몇 개가 됩니까?",
        "question_en": "I bought 7 boxes of cucumbers, 16 in each box. Thirteen of them are rotten and discarded, and the remaining cucumbers are divided equally into 8 bags. How many cucumbers are left that didn't fit in the bag?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "16 7 [OP_MUL] 13 [OP_SUB] 8 [OP_MOD]",
        "solution_abst_en": "16 7 [OP_MUL] 13 [OP_SUB] 8 [OP_MOD]",
        "solution_code_ko": "var_a = 16\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = var_e % var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 16\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = var_e % var_f\nprint(int(var_g))"
    },
    "5662": {
        "category": "Possibility",
        "question_ko": "사탕 8개를 유나와 호석이에게 나누어 주려고 합니다. 유나와 호석이는 적어도 사탕 1개를 받습니다. 사탕을 나누어 주는 방법은 모두 몇 가지입니까?",
        "question_en": "You are going to give 8 candies to Yuna and Hoseok. If Yuna and Hoseok take at least 1 candy, then how many different ways can candy be distributed?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "8 2 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "8 2 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "5663": {
        "category": "Arithmetic calculation",
        "question_ko": "석진이는 가지고 있는 돈으로 500원짜리 공책을 2권 사고, 270원짜리 연필을 1자루 샀더니 230원이 남았습니다. 처음에 석진이가 가지고 있던 돈은 얼마입니까?",
        "question_en": "Seokjin bought two notebooks for 500 won with the money he had and a pencil for 270 won, he finally had 230 won left. How much money did Seokjin have at first?",
        "answer_ko": "1500",
        "answer_en": "1500",
        "solution_abst_ko": "230 270 1 [OP_MUL] [OP_ADD] 500 2 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "230 270 1 [OP_MUL] [OP_ADD] 500 2 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 230\nvar_b = 270\nvar_c = 1\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nvar_f = 500\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_e + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 230\nvar_b = 270\nvar_c = 1\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nvar_f = 500\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_e + var_h\nprint(int(var_i))"
    },
    "5664": {
        "category": "Arithmetic calculation",
        "question_ko": "두 자리 수와 네 자리 수를 더하는 계산에서 네 자리 수의 일의 자리 숫자를 5로 잘못 보았습니다. 또 두 자리 숫자의 십의 자리 수와 일의 자리 수를 바꾸어 보았더니 63이 되었습니다. 잘못 보고 계산한 결과가 2708이었고, 원래 네 자리 수의 일의 자리 숫자가 8이었다면, 바르게 계산한 결과는 얼마입니까?",
        "question_en": "In a calculation that adds a two-digit number to a four-digit number, the digit in the ones place of the four-digit number is incorrectly seen as 5. Also, when we mistook and switched the digits in the tens and ones place of a two-digit number, we got 63. If the incorrect calculation resulted in 2708, and the original four-digit number has 8 in the ones place, what is the correct result of the calculation?",
        "answer_ko": "2738",
        "answer_en": "2738",
        "solution_abst_ko": "2708 8 5 [OP_SUB] [OP_ADD] 63 36 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "2708 8 5 [OP_SUB] [OP_ADD] 63 36 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 2708\nvar_b = 8\nvar_c = 5\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 63\nvar_g = 36\nvar_h = var_f - var_g\nvar_i = var_e + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 2708\nvar_b = 8\nvar_c = 5\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 63\nvar_g = 36\nvar_h = var_f - var_g\nvar_i = var_e + var_h\nprint(int(var_i))"
    },
    "5665": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 은행에 1부터 54까지 수가 쓰인 대기표가 있습니다. 이 대기표에는 숫자 5가 몇 번 나오는지 구하시오.",
        "question_en": "A bank has a waiting list with numbers ranging from 1 to 54. Find how many times the number 5 appears in this waiting list.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "1 54 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 5 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 54 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 5 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 54\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 5\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 54\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 5\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))"
    },
    "5666": {
        "category": "Correspondence",
        "question_ko": "수도꼭지를 열면 1초에 9밀리리터(㎖)의 물이 쏟아진다. 물이 담기지 않은 큰 수통에 8초 동안 물을 받고 7밀리리터(㎖)를 추가로 더 넣었다. 이 수통에 담긴 물을 작은 수통에 6밀리리터(㎖)씩 나눈다면 최대 몇 개의 수통이 필요하겠는가?",
        "question_en": "When you open a faucet, 9 milliliters (ml) of water pours out in one second. Water was poured in for 8 seconds and after that, an additional 7 milliliters (ml) was added in a large canteen that was empty. If the water contained in this canteen is divided by 6 milliliters (ml) into small canteens, how many canteens will be needed at most?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "8 9 [OP_MUL] 7 [OP_ADD] 6 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "8 9 [OP_MUL] 7 [OP_ADD] 6 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 8\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c + var_d\nvar_f = 6\nvar_g = var_e / var_f\nvar_h = 1\nvar_i=int(((var_g+9*10**(var_h-2))//(10**(var_h-1)))*10**(var_h-1))\n\nprint(int(var_i))",
        "solution_code_en": "var_a = 8\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c + var_d\nvar_f = 6\nvar_g = var_e / var_f\nvar_h = 1\nvar_i=int(((var_g+9*10**(var_h-2))//(10**(var_h-1)))*10**(var_h-1))\n\nprint(int(var_i))"
    },
    "5667": {
        "category": "Arithmetic calculation",
        "question_ko": "대형 마트에 과자가 1238개, 라면은 과자보다 374개 더 많이 있었습니다. 이 중에서 과자가 몇 개 팔리고, 라면을 276개 사들였더니 라면과 과자를 합하여 2527개가 되었습니다. 팔린 과자는 몇 개입니까?",
        "question_en": "There were 1238 snacks and 374 more ramens than snacks in the market. Of these, some snacks were sold, and 276 ramen were bought, so the total of ramen and snacks was 2527. How many sweets were sold?",
        "answer_ko": "599",
        "answer_en": "599",
        "solution_abst_ko": "1238 2527 1238 374 [OP_ADD] 276 [OP_ADD] [OP_SUB] [OP_SUB]",
        "solution_abst_en": "1238 2527 1238 374 [OP_ADD] 276 [OP_ADD] [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 1238\nvar_b = 2527\nvar_c = 1238\nvar_d = 374\nvar_e = var_c + var_d\nvar_f = 276\nvar_g = var_e + var_f\nvar_h = var_b - var_g\nvar_i = var_a - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1238\nvar_b = 2527\nvar_c = 1238\nvar_d = 374\nvar_e = var_c + var_d\nvar_f = 276\nvar_g = var_e + var_f\nvar_h = var_b - var_g\nvar_i = var_a - var_h\nprint(int(var_i))"
    },
    "5668": {
        "category": "Correspondence",
        "question_ko": "160에서 4를 뺀 수와 197에서 2를 뺀 수를 배수로 가지는 어떤 수가 있다. 어떤 수로 229를 나누면 5가 부족하다고 한다. 이러한 수 중 가장 큰 자연수를 구하여라.",
        "question_en": "There is a number whose multiples are 160 minus 4 and 197 minus 2. If you divide that number by 229, it is said to be short of 5. Find the largest natural number among these numbers.",
        "answer_ko": "39",
        "answer_en": "39",
        "solution_abst_ko": "197 2 [OP_SUB] 160 4 [OP_SUB] [OP_GCD] 229 5 [OP_ADD] [OP_GCD]",
        "solution_abst_en": "197 2 [OP_SUB] 160 4 [OP_SUB] [OP_GCD] 229 5 [OP_ADD] [OP_GCD]",
        "solution_code_ko": "var_a = 197\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 160\nvar_e = 4\nvar_f = var_d - var_e\nvar_g = math.gcd(int(var_f), int(var_c))\nvar_h = 229\nvar_i = 5\nvar_j = var_h + var_i\nvar_k = math.gcd(int(var_j), int(var_g))\nprint(int(var_k))",
        "solution_code_en": "var_a = 197\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 160\nvar_e = 4\nvar_f = var_d - var_e\nvar_g = math.gcd(int(var_f), int(var_c))\nvar_h = 229\nvar_i = 5\nvar_j = var_h + var_i\nvar_k = math.gcd(int(var_j), int(var_g))\nprint(int(var_k))"
    },
    "5669": {
        "category": "Possibility",
        "question_ko": "반장, 부반장을 뽑으려고 합니다. 정국, 지민, 윤기 중에서 선출하는 경우는 모두 몇 가지입니까?",
        "question_en": "A class president and vice president is going to be elected. How many possible cases of the election are there out of Jungkook, Jimin, and Yoongi.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 지민 윤기 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Jimin Yoongi [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '지민'\nvar_c = '윤기'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nprint(int(var_f))",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Jimin'\nvar_c = 'Yoongi'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nprint(int(var_f))"
    },
    "5670": {
        "category": "Arithmetic calculation",
        "question_ko": "주사위를 던졌을 때 3의 배수 혹은 2의 배수가 나오는 경우의 수를 구하시오.",
        "question_en": "Find the number of ways in which a multiple of 3 or 2 comes up when a die is thrown.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "1 6 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 1 6 [OP_LIST_EVEN] [OP_SET_UNION] [OP_LIST_LEN]",
        "solution_abst_en": "1 6 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 1 6 [OP_LIST_EVEN] [OP_SET_UNION] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 6\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 1\nvar_f = 6\nlist_c = []\nif var_e%2!=0:\n    for i in range(var_e+1, var_f+1, 2):\n        list_c.append(i)\nelse:\n    for i in range(var_e, var_f+1, 2):\n        list_c.append(i)\nlist_d = list(set(list_b) | set(list_c))\nvar_g = len(list_d)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 6\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 1\nvar_f = 6\nlist_c = []\nif var_e%2!=0:\n    for i in range(var_e+1, var_f+1, 2):\n        list_c.append(i)\nelse:\n    for i in range(var_e, var_f+1, 2):\n        list_c.append(i)\nlist_d = list(set(list_b) | set(list_c))\nvar_g = len(list_d)\nprint(int(var_g))"
    },
    "5671": {
        "category": "Correspondence",
        "question_ko": "몇 개의 카트에 골프공 66개와 테니스공 49를 나눠 담으려 한다. 각각의 카트에 들어간 골프공의 개수와 테니스 공의 개수는 서로 모두 같다. 골프공이 6개가 남고 테니스공이 4개가 남는다면 카트의 개수는 몇 개 입니까?",
        "question_en": "You want to divide 66 golf balls and 49 tennis balls among several carts. The number of golf balls in each cart and the number of tennis balls in each cart are the same. How many carts will there be if there are 6 golf balls left and 4 tennis balls left?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "49 4 [OP_SUB] 66 6 [OP_SUB] [OP_GCD]",
        "solution_abst_en": "49 4 [OP_SUB] 66 6 [OP_SUB] [OP_GCD]",
        "solution_code_ko": "var_a = 49\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 66\nvar_e = 6\nvar_f = var_d - var_e\nvar_g = math.gcd(int(var_f), int(var_c))\nprint(int(var_g))",
        "solution_code_en": "var_a = 49\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 66\nvar_e = 6\nvar_f = var_d - var_e\nvar_g = math.gcd(int(var_f), int(var_c))\nprint(int(var_g))"
    },
    "5672": {
        "category": "Geometry",
        "question_ko": "어떤 정삼각형을 만들기 위해서 63센티미터(㎝)짜리 철사를 사용했습니다. 이 정삼각형의 한 변을 만들기 위해 필요한 철사는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "I used 63 centimeters (cm) of wire to make an equilateral triangle. Find how many centimeters (cm) of wire are needed to make one side of this equilateral triangle.",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "63 3 [OP_DIV]",
        "solution_abst_en": "63 3 [OP_DIV]",
        "solution_code_ko": "var_a = 63\nvar_b = 3\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 63\nvar_b = 3\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "5673": {
        "category": "Correspondence",
        "question_ko": "12A3을 반올림하여 백의 자리까지 나타내면 1300이 됩니다. A가 될 수 있는 수는 모두 몇 개인가?",
        "question_en": "Rounding 12A3 to the hundreds place gives 1300. How many possible numbers are A?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "12A3 [OP_GEN_POSSIBLE_LIST] 1300 50 [OP_SUB] [OP_LIST_MORE_EQUAL] 1300 50 [OP_ADD] [OP_LIST_LESS] 12A3 A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_abst_en": "12A3 [OP_GEN_POSSIBLE_LIST] 1300 50 [OP_SUB] [OP_LIST_MORE_EQUAL] 1300 50 [OP_ADD] [OP_LIST_LESS] 12A3 A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '12A3'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 1300\nvar_c = 50\nvar_d = var_b - var_c\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nvar_e = 1300\nvar_f = 50\nvar_g = var_e + var_f\nlist_c = []\nfor i in list_b:\n    if i < var_g:\n        list_c.append(i)\nvar_h = '12A3'\nvar_i = 'A'\nvar_h = str(var_h)\nvar_i = str(var_i)\nunk_idx = var_h.index(var_i)\nlist_d = []\nfor elem in list_c:\n    elem = str(elem)\n    list_d.append(int(elem[unk_idx]))\nlist_d = list(set(list_d))\nvar_j = len(list_d)\nprint(int(var_j))",
        "solution_code_en": "var_a = '12A3'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 1300\nvar_c = 50\nvar_d = var_b - var_c\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nvar_e = 1300\nvar_f = 50\nvar_g = var_e + var_f\nlist_c = []\nfor i in list_b:\n    if i < var_g:\n        list_c.append(i)\nvar_h = '12A3'\nvar_i = 'A'\nvar_h = str(var_h)\nvar_i = str(var_i)\nunk_idx = var_h.index(var_i)\nlist_d = []\nfor elem in list_c:\n    elem = str(elem)\n    list_d.append(int(elem[unk_idx]))\nlist_d = list(set(list_d))\nvar_j = len(list_d)\nprint(int(var_j))"
    },
    "5674": {
        "category": "Arithmetic calculation",
        "question_ko": "6/5과 1/10, 그리고 1.56이 있습니다. 이들의 총합은 얼마인가요?",
        "question_en": "There are 6/5, 1/10, and 1.56. What is the sum of these?",
        "answer_ko": "2.86",
        "answer_en": "2.86",
        "solution_abst_ko": "6/5 1/10 [OP_ADD] 1.56 [OP_ADD]",
        "solution_abst_en": "6/5 1/10 [OP_ADD] 1.56 [OP_ADD]",
        "solution_code_ko": "var_a = 1.2\nvar_b = 0.1\nvar_c = var_a + var_b\nvar_d = 1.56\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 1.2\nvar_b = 0.1\nvar_c = var_a + var_b\nvar_d = 1.56\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "5675": {
        "category": "Arithmetic calculation",
        "question_ko": "두 자리 수 중 3과 5의 공배수는 모두 몇 개 입니까?",
        "question_en": "How many two-digit numbers are common multiples of 3 and 5?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "10 99 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "10 99 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "5676": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.9 중에서 0.4보다 작거나 같은 수를 모두 더하면 얼마일까요?",
        "question_en": "What is the sum of all numbers less than or equal to 0.4 among 0.8, 1/2, and 0.9?",
        "answer_ko": "0",
        "answer_en": "0",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 0.4 [OP_LIST_LESS_EQUAL] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 0.4 [OP_LIST_LESS_EQUAL] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.4\nlist_b = []\nfor i in list_a:\n    if i <= var_d:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.4\nlist_b = []\nfor i in list_a:\n    if i <= var_d:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint(int(var_e))"
    },
    "5677": {
        "category": "Possibility",
        "question_ko": "3개의 서로 다른 문양에 서로 다른 색 5가지를 칠하려고 합니다. 문양은 동그라미, 세모, 네모입니다. 칠할 수 있는 모든 방법은 몇 가지입니까?",
        "question_en": "You are going to paint 5 different colors on a circle, triangle, and square. How many ways are there to paint them?",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "5 [OP_LIST_SOL] 동그라미 세모 네모 [OP_LIST_EOL] [OP_LIST_LEN] [OP_PERM]",
        "solution_abst_en": "5 [OP_LIST_SOL] circle triangle square [OP_LIST_EOL] [OP_LIST_LEN] [OP_PERM]",
        "solution_code_ko": "var_a = 5\nvar_b = '동그라미'\nvar_c = '세모'\nvar_d = '네모'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 1\nvar_a = int(var_a)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_a-i)\nprint(int(var_f))",
        "solution_code_en": "var_a = 5\nvar_b = 'circle'\nvar_c = 'triangle'\nvar_d = 'square'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 1\nvar_a = int(var_a)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_a-i)\nprint(int(var_f))"
    },
    "5678": {
        "category": "Correspondence",
        "question_ko": "아쿠아리움 수조에는 비단 잉어와 붕어가 있다. 비단 잉어와 붕어 모두 3봉지의 사료를 먹는다. 이 물고기들을 모두 먹이기 위해 사육사는 60봉지의 낱개 사료와 15봉지의 사료묶음 8개를 준비한다. 수조에 비단잉어는 52마리가 있다. 수조에 붕어는 몇 마리있는지 구하시오.",
        "question_en": "There are colored carps and crucian carps in the aquarium tank. Both of them eat 3 bags of feed. To feed all these fish, the keepers prepare 60 bags of individual feed and 15 bags of 8 packets of feeds. There are 52 colored carps in the tank. Find how many crucian carps are in the tank.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "15 8 [OP_MUL] 60 [OP_ADD] 3 [OP_DIV] 52 [OP_SUB]",
        "solution_abst_en": "15 8 [OP_MUL] 60 [OP_ADD] 3 [OP_DIV] 52 [OP_SUB]",
        "solution_code_ko": "var_a = 15\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 60\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = 52\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 15\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 60\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = 52\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "5679": {
        "category": "Geometry",
        "question_ko": "어떤 직육면체 모양의 가방이 있습니다. 이 가방의 가로가 9센티미터(㎝), 세로가 4센티미터(㎝), 높이가 7센티미터(㎝)일 때, 가방의 부피는 몇 세제곱센티미터(㎤)입니까?",
        "question_en": "There is a bag in the shape of a cuboid. If the bag is 9 centimeters (cm) wide, 4 centimeters (cm) long, and 7 centimeters (cm) high, what is the volume in cubic centimeters (cm3) of the bag?",
        "answer_ko": "252",
        "answer_en": "252",
        "solution_abst_ko": "9 4 [OP_MUL] 7 [OP_MUL]",
        "solution_abst_en": "9 4 [OP_MUL] 7 [OP_MUL]",
        "solution_code_ko": "var_a = 9\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "5680": {
        "category": "Geometry",
        "question_ko": "철사를 사용하여 한 변이 20센티미터(㎝)인 정사각형 모양 1개를 만들었습니다. 이 철사를 다시 펴서 남김없이 모두 사용하여 직사각형 모양 1개를 만들려고 합니다. 직사각형의 가로를 14센티미터(㎝)로 한다면 세로는 몇 센티미터(㎝)인가?",
        "question_en": "You used wire to make one square shape with a side of 20 centimeters (cm). You are going to re-stretch this wire and use it all to make one rectangular shape. If the width of the rectangle is 14 centimeters (cm), how many centimeters (cm) is the length?",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "20 4 [OP_MUL] 2 [OP_DIV] 14 [OP_SUB]",
        "solution_abst_en": "20 4 [OP_MUL] 2 [OP_DIV] 14 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 14\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 20\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 14\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "5681": {
        "category": "Possibility",
        "question_ko": "5보다 짝은 짝수를 이용하여 만들 수 있는 두 자리 자연수 중, 각 자리의 숫자가 다른 것은 모두 몇 개인가?",
        "question_en": "How many two-digit natural numbers can be formed using even numbers smaller than 5 and with different digits?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "0 5 1 [OP_SUB] [OP_LIST_EVEN] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "0 5 1 [OP_SUB] [OP_LIST_EVEN] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 5\nvar_c = 1\nvar_d = var_b - var_c\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_d+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_d+1, 2):\n        list_a.append(i)\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 0\nvar_b = 5\nvar_c = 1\nvar_d = var_b - var_c\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_d+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_d+1, 2):\n        list_a.append(i)\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "5682": {
        "category": "Arithmetic calculation",
        "question_ko": "기계 하나에서 1시간에 8개의 장난감을 만든다고 합니다. 기계 5개로 200개의 장난감을 만들이 위해선 몇 시간이 필요합니까?",
        "question_en": "It is said that one machine makes eight toys per hour. How many hours does it take to make 200 toys with 5 machines?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "200 8 5 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "200 8 5 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 200\nvar_b = 8\nvar_c = 5\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 200\nvar_b = 8\nvar_c = 5\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "5683": {
        "category": "Comparison",
        "question_ko": "0보다 크고 100보다 작은 3의 배수를 차례대로 썼습니다. 왼쪽에서 21번째 수와 24번째 수 사이에 있는 수들의 곱은 얼마입니까?",
        "question_en": "Multiples of 3 greater than 0 and less than 100 are written sequentially. What is the product of the 22st and 23th numbers from the left?",
        "answer_ko": "4554",
        "answer_en": "4554",
        "solution_abst_ko": "0 3 [OP_ADD] 100 3 [OP_LIST_ARANGE] 22 [OP_LIST_MIN] 23 [OP_LIST_MIN] [OP_MUL]",
        "solution_abst_en": "0 3 [OP_ADD] 100 3 [OP_LIST_ARANGE] 22 [OP_LIST_MIN] 23 [OP_LIST_MIN] [OP_MUL]",
        "solution_code_ko": "var_a = 0\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 100\nvar_e = 3\nlist_a = [i for i in range(var_c, var_d + 1, var_e)]\nvar_f = 22\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nvar_h = 23\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g * var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 0\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 100\nvar_e = 3\nlist_a = [i for i in range(var_c, var_d + 1, var_e)]\nvar_f = 22\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nvar_h = 23\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g * var_i\nprint(int(var_j))"
    },
    "5684": {
        "category": "Comparison",
        "question_ko": "3/7, 4/11, 5/9, 6/13, 9/20 중 1/2보다 큰 분수의 합은 무엇입니까?",
        "question_en": "What is the sum of the fractions greater than 1/2 of 3/7, 4/11, 5/9, 6/13, and 9/20?",
        "answer_ko": "0.56",
        "answer_en": "0.56",
        "solution_abst_ko": "[OP_LIST_SOL] 3/7 4/11 5/9 6/13 9/20 [OP_LIST_EOL] 1/2 [OP_LIST_MORE] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 3/7 4/11 5/9 6/13 9/20 [OP_LIST_EOL] 1/2 [OP_LIST_MORE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0.42857142857142855\nvar_b = 0.36363636363636365\nvar_c = 0.5555555555555556\nvar_d = 0.46153846153846156\nvar_e = 0.45\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 0.5\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 0.42857142857142855\nvar_b = 0.36363636363636365\nvar_c = 0.5555555555555556\nvar_d = 0.46153846153846156\nvar_e = 0.45\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 0.5\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "5685": {
        "category": "Possibility",
        "question_ko": "길이가 10센티미터(㎝)인 철사를 1센티미터(㎝), 2센티미터(㎝), 3센티미터(㎝)의 길이인 철사들로 나누어 자르려고 한다. 자르는 방법은 모두 몇 가지인가?",
        "question_en": "A wire of 10 centimeters (cm) in length is to be cut into pieces of 1 centimeter (cm), 2 centimeters (cm), and 3 centimeters (cm) lengths. How many cutting methods are there in all?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PRODUCT] [OP_LIST_NUM2SUM] 10 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PRODUCT] [OP_LIST_NUM2SUM] 10 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_f = 0\n    i = int(i)\n    while i//10 > 0:\n        var_f = var_f + i%10\n        i = i//10\n    var_f = var_f + i%10\n    list_c.append(var_f)\nvar_g = 10\nvar_h = 0\nvar_g = int(var_g)\nfor i in list_c:\n    i = int(i)\n    if i == var_g:\n        var_h = var_h + 1\nprint(int(var_h))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_f = 0\n    i = int(i)\n    while i//10 > 0:\n        var_f = var_f + i%10\n        i = i//10\n    var_f = var_f + i%10\n    list_c.append(var_f)\nvar_g = 10\nvar_h = 0\nvar_g = int(var_g)\nfor i in list_c:\n    i = int(i)\n    if i == var_g:\n        var_h = var_h + 1\nprint(int(var_h))"
    },
    "5686": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 10.4 센티미터(㎝) 인 색 테이프 16 개를 3.5 센티미터(㎝) 씩 겹 치게 하여 원 모양으로 이어 붙였습니다. 이어 붙인 원 모양의 색 테이프의 전체 길이는 몇 센티미터(㎝) 입니까?",
        "question_en": "Sixteen strips of colored tape, each 10.4 centimeters (cm) long, were joined together in a circle with overlaps of 3.5 centimeters (cm). How many centimeters (cm) is the total length of the circle-shaped colored tape that was joined together?",
        "answer_ko": "110.40",
        "answer_en": "110.4",
        "solution_abst_ko": "10.4 3.5 [OP_SUB] 16 [OP_MUL]",
        "solution_abst_en": "10.4 3.5 [OP_SUB] 16 [OP_MUL]",
        "solution_code_ko": "var_a = 10.4\nvar_b = 3.5\nvar_c = var_a - var_b\nvar_d = 16\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 10.4\nvar_b = 3.5\nvar_c = var_a - var_b\nvar_d = 16\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "5687": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 4로 나누어야 할 것을 잘못하여 곱하였더니 166.08이 되었습니다. 바르게 계산한 결과를 구하시오.",
        "question_en": "When you mistakenly multiply a number that should be divided by 4, the result was 166.08. Find the result of the correct calculation.",
        "answer_ko": "10.38",
        "answer_en": "10.38",
        "solution_abst_ko": "166.08 4 [OP_DIV] 4 [OP_DIV]",
        "solution_abst_en": "166.08 4 [OP_DIV] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 166.08\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 166.08\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "5688": {
        "category": "Correspondence",
        "question_ko": "서로 다른 네 수 A, B, C, D가 있습니다. 네 자리 수끼리의 덧셈식 ABCD+ABCD=7314에서 ABCD를 구하시오.",
        "question_en": "There are four different numbers A, B, C, and D. Find ABCD from the four-digit formula ABCD+ABCD=7314.",
        "answer_ko": "3657",
        "answer_en": "3657",
        "solution_abst_ko": "[OP_LIST_SOL] ABCD+ABCD=7314 A [OP_DIGIT_UNK_SOLVER] ABCD+ABCD=7314 B [OP_DIGIT_UNK_SOLVER] ABCD+ABCD=7314 C [OP_DIGIT_UNK_SOLVER] ABCD+ABCD=7314 D [OP_DIGIT_UNK_SOLVER] [OP_LIST_EOL] [OP_LIST2NUM]",
        "solution_abst_en": "[OP_LIST_SOL] ABCD+ABCD=7314 A [OP_DIGIT_UNK_SOLVER] ABCD+ABCD=7314 B [OP_DIGIT_UNK_SOLVER] ABCD+ABCD=7314 C [OP_DIGIT_UNK_SOLVER] ABCD+ABCD=7314 D [OP_DIGIT_UNK_SOLVER] [OP_LIST_EOL] [OP_LIST2NUM]",
        "solution_code_ko": "var_a = 'ABCD+ABCD=7314'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 'ABCD+ABCD=7314'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = 'ABCD+ABCD=7314'\nvar_h = 'C'\nans_dict = dict()\nvar_g = var_g.replace('×','*')\nvar_g = var_g.replace('x','*')\nvar_g = var_g.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_g):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_g\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_g):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_i = ans_dict[var_h]\nvar_j = 'ABCD+ABCD=7314'\nvar_k = 'D'\nans_dict = dict()\nvar_j = var_j.replace('×','*')\nvar_j = var_j.replace('x','*')\nvar_j = var_j.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_j):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_j\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_j):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_l = ans_dict[var_k]\nlist_a= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_a.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nlist_a.reverse()\nvar_m=\"\"\nfor i in list_a:\n    i = str(i)\n    var_m = var_m + i\nprint(int(var_m))",
        "solution_code_en": "var_a = 'ABCD+ABCD=7314'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 'ABCD+ABCD=7314'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = 'ABCD+ABCD=7314'\nvar_h = 'C'\nans_dict = dict()\nvar_g = var_g.replace('×','*')\nvar_g = var_g.replace('x','*')\nvar_g = var_g.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_g):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_g\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_g):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_i = ans_dict[var_h]\nvar_j = 'ABCD+ABCD=7314'\nvar_k = 'D'\nans_dict = dict()\nvar_j = var_j.replace('×','*')\nvar_j = var_j.replace('x','*')\nvar_j = var_j.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_j):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_j\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_j):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_l = ans_dict[var_k]\nlist_a= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_a.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nlist_a.reverse()\nvar_m=\"\"\nfor i in list_a:\n    i = str(i)\n    var_m = var_m + i\nprint(int(var_m))"
    },
    "5689": {
        "category": "Comparison",
        "question_ko": "1부터 9까지의 카드 중 하나를 뽑아서 21을 곱했을 때 84에 2를 곱한 값보다 커지는 수들을 모두 더한 값을 구하시오.",
        "question_en": "Draw one of the cards numbered 1 through 9 and find the sum of all the numbers that, when multiplied by 21, are greater than 84 multiplied by 2.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "1 9 1 [OP_LIST_ARANGE] 84 2 [OP_MUL] 21 [OP_DIV] [OP_LIST_MORE] [OP_LIST_SUM]",
        "solution_abst_en": "1 9 1 [OP_LIST_ARANGE] 84 2 [OP_MUL] 21 [OP_DIV] [OP_LIST_MORE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 84\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = 21\nvar_h = var_f / var_g\nlist_b = []\nfor i in list_a:\n    if i > var_h:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_i = sum(list_b)\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 84\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = 21\nvar_h = var_f / var_g\nlist_b = []\nfor i in list_a:\n    if i > var_h:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_i = sum(list_b)\nprint(int(var_i))"
    },
    "5690": {
        "category": "Arithmetic calculation",
        "question_ko": "주현이는 3000원으로 하나에 300원인 사탕과 하나에 500원인 과자를 샀습니다. 사탕과 과자를 모두 8개 샀다면 주현이는 과자를 모두 몇 개 샀을까요?",
        "question_en": "Joohyeon bought candies that cost 300 won each and snacks that cost 500 won each using 3,000 won. If he bought a total of 8, how many snacks did Joohyeon buy?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "3000 300 8 [OP_MUL] [OP_SUB] 500 300 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "3000 300 8 [OP_MUL] [OP_SUB] 500 300 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 3000\nvar_b = 300\nvar_c = 8\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 500\nvar_g = 300\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 3000\nvar_b = 300\nvar_c = 8\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 500\nvar_g = 300\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "5691": {
        "category": "Geometry",
        "question_ko": "리본으로 한 변의 길이가 20/9센티미터(㎝)인 정삼각형을 만들었습니다. 이 리본을 풀러 정오각형을 만든다면 한 변의 길이가 몇 센티미터(㎝)일지 구하시오.",
        "question_en": "You made a regular triangle using ribbon with a side length of 20/9 centimeters (cm). If you unroll this ribbon to make a regular pentagon, find how many centimeters (cm) the length of one side is.",
        "answer_ko": "1.33",
        "answer_en": "1.33",
        "solution_abst_ko": "20/9 3 [OP_MUL] 5 [OP_DIV]",
        "solution_abst_en": "20/9 3 [OP_MUL] 5 [OP_DIV]",
        "solution_code_ko": "var_a = 2.2222222222222223\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 2.2222222222222223\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "5692": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 5.9센티미터(㎝)이고 다른 한 변의 길이가 3센티미터(㎝)인 직사각형의 넓이는 얼마입니까?",
        "question_en": "What is the area of a rectangle with one side measuring 5.9 centimeters (cm) and the other side measuring 3 centimeters (cm)?",
        "answer_ko": "17.70",
        "answer_en": "17.7",
        "solution_abst_ko": "5.9 3 [OP_MUL]",
        "solution_abst_en": "5.9 3 [OP_MUL]",
        "solution_code_ko": "var_a = 5.9\nvar_b = 3\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 5.9\nvar_b = 3\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "5693": {
        "category": "Arithmetic calculation",
        "question_ko": "사과 138개를 한 상자에 18개씩 담아 포장하고, 남은 것은 바구니에 넣기로 하였습니다. 바구니에 담긴 사과는 몇 개인지 구하시오",
        "question_en": "I decided to pack 138 apples in a box with 18 apples each and put the rest in a basket. Find how many apples are in the basket.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "138 18 [OP_MOD]",
        "solution_abst_en": "138 18 [OP_MOD]",
        "solution_code_ko": "var_a = 138\nvar_b = 18\nvar_c = var_a % var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 138\nvar_b = 18\nvar_c = var_a % var_b\nprint(int(var_c))"
    },
    "5694": {
        "category": "Arithmetic calculation",
        "question_ko": "올해 정국이는 16살이고 어머니는 46살입니다. 어머니 나이가 정국이 나이의 4배였을 때는 몇 년 전입니까?",
        "question_en": "This year, Jungkook is 16 years old and his mother is 46 years old. How many years ago was Jungkook's mother's age four times Jungkook's?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "16 4 [OP_MUL] 46 [OP_SUB] 4 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "16 4 [OP_MUL] 46 [OP_SUB] 4 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 16\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 46\nvar_e = var_c - var_d\nvar_f = 4\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 16\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 46\nvar_e = var_c - var_d\nvar_f = 4\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "5695": {
        "category": "Correspondence",
        "question_ko": "211.5는 B에서 A를 뺀 값입니다. B는 소수 A를 10배한 값일때 소수점을 포함하여 A를 구하시오.",
        "question_en": "211.5 is B minus A. When B is the value of multiplying the decimal A by 10, find A including the decimal point.",
        "answer_ko": "23.50",
        "answer_en": "23.5",
        "solution_abst_ko": "211.5 10 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "211.5 10 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 211.5\nvar_b = 10\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 211.5\nvar_b = 10\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "5696": {
        "category": "Geometry",
        "question_ko": "밑면이 5/6미터(m), 높이가 4/6미터(m)인 삼각형이 있습니다. 이 삼각형의 밑면은 높이보다 몇 미터(m) 깁니까?",
        "question_en": "You have a triangle with a base of 5/6 meters (m) and a height of 4/6 meters (m). How many meters (m) is the base of this triangle greater than its height?",
        "answer_ko": "0.17",
        "answer_en": "0.17",
        "solution_abst_ko": "5/6 4/6 [OP_SUB]",
        "solution_abst_en": "5/6 4/6 [OP_SUB]",
        "solution_code_ko": "var_a = 0.8333333333333334\nvar_b = 0.6666666666666666\nvar_c = var_a - var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 0.8333333333333334\nvar_b = 0.6666666666666666\nvar_c = var_a - var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "5697": {
        "category": "Correspondence",
        "question_ko": "각 자리 수를 모두 더했을 때의 값이 9이고, 5로 나누어 떨어지는 세 자리 수는 모두 몇 개 있습니까?",
        "question_en": "How many three-digit numbers are there when the sum of all the digits is 9 and is divisible by 5?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "100 1000 1 [OP_SUB] 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] [OP_LIST_NUM2SUM] 9 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "100 1000 1 [OP_SUB] 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] [OP_LIST_NUM2SUM] 9 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 100\nvar_b = 1000\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nvar_f = 5\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nlist_c=[]\nfor i in list_b:\n    var_g = 0\n    i = int(i)\n    while i//10 > 0:\n        var_g = var_g + i%10\n        i = i//10\n    var_g = var_g + i%10\n    list_c.append(var_g)\nvar_h = 9\nvar_i = 0\nvar_h = int(var_h)\nfor i in list_c:\n    i = int(i)\n    if i == var_h:\n        var_i = var_i + 1\nprint(int(var_i))",
        "solution_code_en": "var_a = 100\nvar_b = 1000\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nvar_f = 5\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nlist_c=[]\nfor i in list_b:\n    var_g = 0\n    i = int(i)\n    while i//10 > 0:\n        var_g = var_g + i%10\n        i = i//10\n    var_g = var_g + i%10\n    list_c.append(var_g)\nvar_h = 9\nvar_i = 0\nvar_h = int(var_h)\nfor i in list_c:\n    i = int(i)\n    if i == var_h:\n        var_i = var_i + 1\nprint(int(var_i))"
    },
    "5698": {
        "category": "Possibility",
        "question_ko": "1에서 12까지의 숫자가 적힌 카드 12장 중 한장을 뽑는 행동을 2번하여 첫 번째는 3의 배수가 나오고, 두 번째는 4의 배수가 나오는 경우의 수를 구하시오.",
        "question_en": "Find the number of ways in which a multiple of 3 comes out the first time and a multiple of 4 comes out the second time by doing the action of drawing a card out of 12 cards with numbers from 1 to 12 written twice.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "1 12 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] [OP_LIST_POP] 4 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] [OP_MUL]",
        "solution_abst_en": "1 12 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] [OP_LIST_POP] 4 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] [OP_MUL]",
        "solution_code_ko": "var_a = 1\nvar_b = 12\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = len(list_b)\nvar_f = 4\nlist_c = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nvar_g = len(list_c)\nvar_h = var_e * var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 1\nvar_b = 12\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = len(list_b)\nvar_f = 4\nlist_c = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nvar_g = len(list_c)\nvar_h = var_e * var_g\nprint(int(var_h))"
    },
    "5699": {
        "category": "Possibility",
        "question_ko": "범진이가 책장에 수학책 2권과 영어책 2권을 올려놓으려고 할 때, 수학책을 몇 번이나 나란히 놓을까?",
        "question_en": "When Bumjin wants to put two math books and two English books on his bookshelf, how many times does he put the math books next to each other?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "3 3 [OP_PERM] 2 [OP_MUL]",
        "solution_abst_en": "3 3 [OP_PERM] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 3\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "5700": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 5.46에 더해야 하는데 잘못하여 빼서 3.97을 얻었습니다. 올바른 계산의 결과를 구하십시오.",
        "question_en": "You need to add 5.46 to a number but mistakenly subtracted it and got 3.97. Find the result of the correct calculation.",
        "answer_ko": "6.95",
        "answer_en": "6.95",
        "solution_abst_ko": "5.46 3.97 [OP_SUB] 5.46 [OP_ADD]",
        "solution_abst_en": "5.46 3.97 [OP_SUB] 5.46 [OP_ADD]",
        "solution_code_ko": "var_a = 5.46\nvar_b = 3.97\nvar_c = var_a - var_b\nvar_d = 5.46\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 5.46\nvar_b = 3.97\nvar_c = var_a - var_b\nvar_d = 5.46\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "5701": {
        "category": "Arithmetic calculation",
        "question_ko": "5미터(m)의 무게가 15.3킬로그램(㎏)인 철근 11미터(m)의 무게는 몇 킬로그램(㎏)인지 구하시오.",
        "question_en": "Find the weight of 11 meters (m) of rebar, weighing 15.3 kilograms (kg) when it's 5 meters (m), in kilograms (kg).",
        "answer_ko": "33.66",
        "answer_en": "33.66",
        "solution_abst_ko": "15.3 5 [OP_DIV] 11 [OP_MUL]",
        "solution_abst_en": "15.3 5 [OP_DIV] 11 [OP_MUL]",
        "solution_code_ko": "var_a = 15.3\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 11\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 15.3\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 11\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "5702": {
        "category": "Possibility",
        "question_ko": "6명의 학생이 반 안에 있을 때, 팀장 1명, 총무 1명, 서기 1명을 뽑는 경우의 수를 구하시오.",
        "question_en": "If there are 6 students in the class, find how many cases are there to select 1 team leader, 1 manager, and 1 clerk.",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "6 1 1 [OP_ADD] 1 [OP_ADD] [OP_PERM]",
        "solution_abst_en": "6 1 1 [OP_ADD] 1 [OP_ADD] [OP_PERM]",
        "solution_code_ko": "var_a = 6\nvar_b = 1\nvar_c = 1\nvar_d = var_b + var_c\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = 1\nvar_a = int(var_a)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_a-i)\nprint(int(var_g))",
        "solution_code_en": "var_a = 6\nvar_b = 1\nvar_c = 1\nvar_d = var_b + var_c\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = 1\nvar_a = int(var_a)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_a-i)\nprint(int(var_g))"
    },
    "5703": {
        "category": "Arithmetic calculation",
        "question_ko": "찬희의 한 걸음은 0.45미터(m)입니다. 찬희가 1분에 90걸음씩 걸어서 13분 걸었다면, 찬희는 모두 몇 미터(m)를 걸은 것인지 구하시오.",
        "question_en": "Chanhee goes 0.45 meters (m) for one step. If Chanhee walked for 13 minutes by 90 steps per minute, find how many meters (m) she walked in total.",
        "answer_ko": "526.50",
        "answer_en": "526.5",
        "solution_abst_ko": "0.45 90 [OP_MUL] 13 [OP_MUL]",
        "solution_abst_en": "0.45 90 [OP_MUL] 13 [OP_MUL]",
        "solution_code_ko": "var_a = 0.45\nvar_b = 90\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.45\nvar_b = 90\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "5704": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이는 빨간 자전거 3대, 윤기는 파란 자전거 4대를 가지고 있습니다. 전체 자전거의 개수는?",
        "question_en": "Jungkook has 3 red bikes and Yoongi has 4 blue bikes. How many bikes are there in total?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "3 4 [OP_ADD]",
        "solution_abst_en": "3 4 [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 4\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 4\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "5705": {
        "category": "Arithmetic calculation",
        "question_ko": "2에서 355까지 세 자리 수의 수를 구하십시오.",
        "question_en": "Find the number of three-digit numbers from 2 to 355.",
        "answer_ko": "256",
        "answer_en": "256",
        "solution_abst_ko": "100 355 1 [OP_LIST_ARANGE] [OP_LIST_LEN]",
        "solution_abst_en": "100 355 1 [OP_LIST_ARANGE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 100\nvar_b = 355\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = len(list_a)\nprint(int(var_d))",
        "solution_code_en": "var_a = 100\nvar_b = 355\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = len(list_a)\nprint(int(var_d))"
    },
    "5706": {
        "category": "Arithmetic calculation",
        "question_ko": "회사에 사람은 8명인데 컴퓨터가 5대라 돌아가면서 사용을 해야 합니다. 근무 시간이 2시간 32분이라면, 한사람이 컴퓨터를 사용한 시간은 평균 몇 분입니까?",
        "question_en": "There are 8 people in the company, but there are 5 computers, so they have to take turns using them. If the working day is 2 hours and 32 minutes, how many minutes per person spend on the computer on average?",
        "answer_ko": "95",
        "answer_en": "95",
        "solution_abst_ko": "2 60 [OP_MUL] 32 [OP_ADD] 8 [OP_DIV] 5 [OP_MUL]",
        "solution_abst_en": "2 60 [OP_MUL] 32 [OP_ADD] 8 [OP_DIV] 5 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 32\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e / var_f\nvar_h = 5\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 2\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 32\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e / var_f\nvar_h = 5\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "5707": {
        "category": "Possibility",
        "question_ko": "4, 0, 9, 8 중에서 서로 다른 숫자 3개를 뽑아 만들 수 있는 세 자리 수 중에서 3번째로 작은 수를 쓰시오.",
        "question_en": "Write the 3rd smallest number among three-digit numbers that can be made by drawing three different numbers from 4, 0, 9, and 8.",
        "answer_ko": "480",
        "answer_en": "480",
        "solution_abst_ko": "[OP_LIST_SOL] 4 0 9 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 3 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 4 0 9 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 3 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 4\nvar_b = 0\nvar_c = 9\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 0\nvar_c = 9\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nprint(int(var_g))"
    },
    "5708": {
        "category": "Arithmetic calculation",
        "question_ko": "은지가 책을 펼쳤는데 두 쪽수의 합이 137이었습니다. 은지가 펼친 두 쪽수 중 큰 수를 쓰시오.",
        "question_en": "Eunji opened the book and the sum of the two pages was 137. Write the larger of the two pages Eunji has opened.",
        "answer_ko": "69",
        "answer_en": "69",
        "solution_abst_ko": "137 2 [OP_FDIV] 1 [OP_ADD]",
        "solution_abst_en": "137 2 [OP_FDIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 137\nvar_b = 2\nvar_c = var_a // var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 137\nvar_b = 2\nvar_c = var_a // var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "5709": {
        "category": "Comparison",
        "question_ko": "정국이는 0.8, 윤기는 1/2, 유정이는 0.9의 숫자카드를 갖고 있습니다. 0.3보다 큰 숫자카드를 가지고 있는 사람은 몇 명입니까?",
        "question_en": "Jungkook has a 0.8 number card, Yoongi has a 1/2 number, and Yoojung has a 0.9 number card. How many people have a number card greater than 0.3?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 0.3 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 0.3 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.3\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.3\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "5710": {
        "category": "Correspondence",
        "question_ko": "네 자리 수 6A42를 백의 자리에서 반올림하면 6000이 됩니다. 0부터 9까지의 숫자 중 A에 쓸 수 있는 숫자는 모두 몇 개입니까?",
        "question_en": "When you round the four-digit number 6A42 to the thousands place, it becomes 6000. How many digits from 0 to 9 can be written as A?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "6A42 [OP_GEN_POSSIBLE_LIST] 6500 [OP_LIST_MORE_EQUAL] 6A42 A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_abst_en": "6A42 [OP_GEN_POSSIBLE_LIST] 6500 [OP_LIST_MORE_EQUAL] 6A42 A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '6A42'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 6500\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = '6A42'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nvar_e = len(list_c)\nprint(int(var_e))",
        "solution_code_en": "var_a = '6A42'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 6500\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = '6A42'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nvar_e = len(list_c)\nprint(int(var_e))"
    },
    "5711": {
        "category": "Comparison",
        "question_ko": "색 테이프를 민지는 0.74미터(m) , 승연이는 13/20 미터(m) , 혜수는 4/5 미터(m) 가지고 있습니다. 누가 가장 긴 색 테이프를 가지고 있습니까?",
        "question_en": "Minji has 0.74 meters (m) of color tape, Seungyeon has 13/20 meters (m), and Hyesu has 4/5 meters (m). Who has the longest colored tape?",
        "answer_ko": "혜수",
        "answer_en": "Hyesu",
        "solution_abst_ko": "[OP_LIST_SOL] 민지 승연 혜수 [OP_LIST_EOL] [OP_LIST_SOL] 0.74 13/20 4/5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Minji Seungyeon Hyesu [OP_LIST_EOL] [OP_LIST_SOL] 0.74 13/20 4/5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '민지'\nvar_b = '승연'\nvar_c = '혜수'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.74\nvar_e = 0.65\nvar_f = 0.8\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Minji'\nvar_b = 'Seungyeon'\nvar_c = 'Hyesu'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.74\nvar_e = 0.65\nvar_f = 0.8\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "5712": {
        "category": "Correspondence",
        "question_ko": "어떤 일을 완성하는데 언니는 10일, 동생은 20일 걸린다고 한다. 이 일을 언니가 혼자 4일간 한 후에 자매가 같이 협력하여 일을 끝냈다고 한다. 자매가 함께 일한 기간은 며칠인가?",
        "question_en": "It takes 10 days for an older sister and 20 days for a younger sister to complete a certain task. After the older sister did this task alone for four days, the sisters worked together to finish the task. How many days did the sisters work together?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "1 4 10 [OP_DIV] [OP_SUB] 1 10 [OP_DIV] 1 20 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_abst_en": "1 4 10 [OP_DIV] [OP_SUB] 1 10 [OP_DIV] 1 20 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 4\nvar_c = 10\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = 10\nvar_h = var_f / var_g\nvar_i = 1\nvar_j = 20\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_e / var_l\nprint(int(eval('{:.2f}'.format(round(var_m+1e-10,2)))))",
        "solution_code_en": "var_a = 1\nvar_b = 4\nvar_c = 10\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = 10\nvar_h = var_f / var_g\nvar_i = 1\nvar_j = 20\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_e / var_l\nprint(int(eval('{:.2f}'.format(round(var_m+1e-10,2)))))"
    },
    "5713": {
        "category": "Correspondence",
        "question_ko": "14를 어떤 수에 더했더니 결과가 56이 나왔습니다. 3을 어떤 수에 곱한 결과를 구하시오.",
        "question_en": "When you add 14 to a number, you get 56. Find the result of multiplying the number by 3.",
        "answer_ko": "126",
        "answer_en": "126",
        "solution_abst_ko": "56 14 [OP_SUB] 3 [OP_MUL]",
        "solution_abst_en": "56 14 [OP_SUB] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 56\nvar_b = 14\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 56\nvar_b = 14\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "5714": {
        "category": "Arithmetic calculation",
        "question_ko": "A를 B로 나눴더니 몫이 6이 되었고 나머지가 3이 되었습니다. A와 B는 자연수입니다. 나누는 수 B 중 가장 작은 수는 무엇일까요?",
        "question_en": "When A is divided by B, the quotient is 6 and the remainder is 3. A and B are natural numbers. What is the smallest among the divisor B?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "3 1 [OP_ADD]",
        "solution_abst_en": "3 1 [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "5715": {
        "category": "Arithmetic calculation",
        "question_ko": "(가), (나), (다) 세 개의 컵에 물이 담겨 있습니다. 세 컵의 물의 양의 합은 1리터(L) 200밀리리터(㎖)입니다. (다) 컵에서 (나) 컵으로 200밀리리터(㎖), (가) 컵으로 100밀리리터(㎖)의 물을 옮기면 세 개의 컵에 담긴 물의 양은 같아진다고 합니다. (가) 컵에 처음 담겨 있었던 물의 양을 구하시오.",
        "question_en": "There are three cups (a), (b), (c) filled with water. The sum of the water in these three cups is 1 liter (L) and 200 milliliters (㎖). If you transfer 200 milliliters (㎖) from cup (c) to cup (b), and 100 milliliters (㎖) from cup (c) to cup (a), the amount of water in the three cups becomes the same. Find the amount of water that was initially contained in the cup (a).",
        "answer_ko": "300",
        "answer_en": "300",
        "solution_abst_ko": "1 1000 [OP_MUL] 200 [OP_ADD] 200 [OP_SUB] 100 [OP_SUB] 3 [OP_DIV]",
        "solution_abst_en": "1 1000 [OP_MUL] 200 [OP_ADD] 200 [OP_SUB] 100 [OP_SUB] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 200\nvar_e = var_c + var_d\nvar_f = 200\nvar_g = var_e - var_f\nvar_h = 100\nvar_i = var_g - var_h\nvar_j = 3\nvar_k = var_i / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 1\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 200\nvar_e = var_c + var_d\nvar_f = 200\nvar_g = var_e - var_f\nvar_h = 100\nvar_i = var_g - var_h\nvar_j = 3\nvar_k = var_i / var_j\nprint(int(var_k))"
    },
    "5716": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 10까지의 홀수 중 2번째로 작은 수를 구하시오.",
        "question_en": "Find the second smallest odd number from 1 to 10.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "1 10 [OP_LIST_ODD] 2 [OP_LIST_MIN]",
        "solution_abst_en": "1 10 [OP_LIST_ODD] 2 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1\nvar_b = 10\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[var_c-1]\nprint(int(var_d))",
        "solution_code_en": "var_a = 1\nvar_b = 10\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[var_c-1]\nprint(int(var_d))"
    },
    "5717": {
        "category": "Comparison",
        "question_ko": "5개의 공 (가), (나), (다), (라), (마)를 나란히 놓았습니다. (마)는 (다)의 오른쪽 옆에 놓여 있고, (마)는 (라)의 왼쪽 옆에 놓여 있습니다. 또 (가)의 오른쪽 옆에 (다)가 있고, (나)의 왼쪽 옆에 (라)가 있습니다. 가장 왼쪽에 놓여진 공은 무엇입니까?",
        "question_en": "Five balls (a), (b), (c), (d), and (e) are placed side by side. (e) is placed to the right of (c), and (e) is placed to the left of (d). Also, (c) is on the right side of (a), and (d) is on the left side of (b). Which ball is placed to the far left?",
        "answer_ko": "(가)",
        "answer_en": "(a)",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) (다) (라) (마) [OP_LIST_EOL] [OP_LIST_SOL] (마) (다) > (마) (라) < (다) (가) > (라) (나) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (a) (b) (c) (d) (e) [OP_LIST_EOL] [OP_LIST_SOL] (e) (c) > (e) (d) < (c) (a) > (d) (b) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nvar_c = '(다)'\nvar_d = '(라)'\nvar_e = '(마)'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = '(마)'\nvar_g = '(다)'\nvar_h = '>'\nvar_i = '(마)'\nvar_j = '(라)'\nvar_k = '<'\nvar_l = '(다)'\nvar_m = '(가)'\nvar_n = '>'\nvar_o = '(라)'\nvar_p = '(나)'\nvar_q = '<'\nlist_b= []\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_r = len(list_c)\nvar_s = list_c[var_r-1]\nprint(var_s)",
        "solution_code_en": "var_a = '(a)'\nvar_b = '(b)'\nvar_c = '(c)'\nvar_d = '(d)'\nvar_e = '(e)'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = '(e)'\nvar_g = '(c)'\nvar_h = '>'\nvar_i = '(e)'\nvar_j = '(d)'\nvar_k = '<'\nvar_l = '(c)'\nvar_m = '(a)'\nvar_n = '>'\nvar_o = '(d)'\nvar_p = '(b)'\nvar_q = '<'\nlist_b= []\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_r = len(list_c)\nvar_s = list_c[var_r-1]\nprint(var_s)"
    },
    "5718": {
        "category": "Comparison",
        "question_ko": "3명의 학생이 주머니에서 숫자가 적힌 구슬을 꺼냈습니다. 정국이가 뽑은 구슬엔 7이 적혀있고 민영이가 뽑은 구슬엔 5가 적혀있습니다. 태형이가 뽑은 구슬의 숫자는 민영이보다 크지만 정국이보다는 작습니다. 태형이가 가진 구슬의 숫자는 무엇입니까?",
        "question_en": "Three students pulled marbles with numbers from their pockets. The marble that Jungkook picked has a 7 written on it, and the marble that Minyoung picked has a 5 written on it. Taehyung's number of marble is greater than Minyoung's but less than Jungkook's. What is the number of marble Taehyung has?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "5 7 [OP_ADD] 2 [OP_FDIV]",
        "solution_abst_en": "5 7 [OP_ADD] 2 [OP_FDIV]",
        "solution_code_ko": "var_a = 5\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "5719": {
        "category": "Arithmetic calculation",
        "question_ko": "두 자리 수 중 3과 5의 공배수 중 가장 큰 수는?",
        "question_en": "Find the greatest possible two-digit number that is common multiple of 3 and 5.",
        "answer_ko": "90",
        "answer_en": "90",
        "solution_abst_ko": "10 99 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_abst_en": "10 99 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[-var_f]\nprint(int(var_g))",
        "solution_code_en": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[-var_f]\nprint(int(var_g))"
    },
    "5720": {
        "category": "Arithmetic calculation",
        "question_ko": "무게가 같은 사과 9개의 무게의 총합은 4.5킬로그램(㎏)입니다. 사과 2개와 무게가 850그램(g)인 멜론 몇 개를 양팔 저울 한쪽에 올려놓고, 다른 쪽에는 무게가 1050그램(g)인 수박 5개를 올려놓았더니 수평을 이루었습니다. 올려놓은 멜론은 몇 개입니까?",
        "question_en": "The total weight of 9 apples of the same weight is 4.5 kilograms (kg). Several melons weighing 850 grams (g) and two apples were placed on one side of the pan balance scale, and five watermelons weighing 1050 grams (g) were placed on the other side, and they were level. How many melons are there?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "1050 5 [OP_MUL] 4.5 1000 [OP_MUL] 9 [OP_DIV] 2 [OP_MUL] [OP_SUB] 850 [OP_DIV]",
        "solution_abst_en": "1050 5 [OP_MUL] 4.5 1000 [OP_MUL] 9 [OP_DIV] 2 [OP_MUL] [OP_SUB] 850 [OP_DIV]",
        "solution_code_ko": "var_a = 1050\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 4.5\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = 9\nvar_h = var_f / var_g\nvar_i = 2\nvar_j = var_h * var_i\nvar_k = var_c - var_j\nvar_l = 850\nvar_m = var_k / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 1050\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 4.5\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = 9\nvar_h = var_f / var_g\nvar_i = 2\nvar_j = var_h * var_i\nvar_k = var_c - var_j\nvar_l = 850\nvar_m = var_k / var_l\nprint(int(var_m))"
    },
    "5721": {
        "category": "Possibility",
        "question_ko": "1보다 큰 한 자리 홀수를 모두 한 번씩 사용하여 네 자리수를 만들고자 한다. 만들 수 있는 수들의 총합을 구하여라.",
        "question_en": "We want to create a four-digit number by using all single-digit odd numbers greater than 1 once. Find the sum of the possible numbers.",
        "answer_ko": "159984",
        "answer_en": "159984",
        "solution_abst_ko": "1 1 [OP_ADD] 9 [OP_LIST_ODD] 4 [OP_LIST_GET_PERM] [OP_LIST_SUM]",
        "solution_abst_en": "1 1 [OP_ADD] 9 [OP_LIST_ODD] 4 [OP_LIST_GET_PERM] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 9\nlist_a = []\nif var_c%2==0:\n    for i in range(var_c+1, var_d+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_c, var_d+1, 2):\n        list_a.append(i)\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 9\nlist_a = []\nif var_c%2==0:\n    for i in range(var_c+1, var_d+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_c, var_d+1, 2):\n        list_a.append(i)\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint(int(var_f))"
    },
    "5722": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중에서 가장 큰 수와 그 다음으로 큰 수로 나눈 몫은 얼마입니까?",
        "question_en": "There are three numbers 10, 11, and 12. What is the quotient of the largest number divided by the second largest number?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_FDIV]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_FDIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = var_e // var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = var_e // var_g\nprint(int(var_h))"
    },
    "5723": {
        "category": "Arithmetic calculation",
        "question_ko": "수현, 기윤, 태훈, 화준 네 명의 친구가 있습니다. 기윤이는 수현이보다 207밀리미터(㎜) 더 큽니다. 태훈이는 수현이보다 252밀리미터(㎜) 더 큽니다. 화준이는 기윤이보다 839밀리미터(㎜) 더 큽니다. 수현이와 화준이의 키 차이는 몇 밀리미터(㎜)입니까?",
        "question_en": "There are four friends, Soohyun, Kiyoon, Taehun, and Hwajun. Kiyoon is 207 millimeters (mm) taller than Soohyun. Taehun is 252 millimeters (mm) taller than Soohyun. Hwajun is 839 millimeters (mm) taller than Kiyoon. How many millimeters (mm) is the difference in height between Soohyun and Hwajun?",
        "answer_ko": "1046",
        "answer_en": "1046",
        "solution_abst_ko": "207 839 [OP_ADD]",
        "solution_abst_en": "207 839 [OP_ADD]",
        "solution_code_ko": "var_a = 207\nvar_b = 839\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 207\nvar_b = 839\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "5724": {
        "category": "Possibility",
        "question_ko": "A, B, C, D, E 5명이 있을 때, 회장 1명, 부회장 1명을 뽑는 경우의 수를 구하시오.",
        "question_en": "If there are 5 people A, B, C, D, E, find the number of ways to select 1 president and 1 vice president.",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "5 1 1 [OP_ADD] [OP_PERM]",
        "solution_abst_en": "5 1 1 [OP_ADD] [OP_PERM]",
        "solution_code_ko": "var_a = 5\nvar_b = 1\nvar_c = 1\nvar_d = var_b + var_c\nvar_e = 1\nvar_a = int(var_a)\nvar_d = int(var_d)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e * (var_a-i)\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 1\nvar_c = 1\nvar_d = var_b + var_c\nvar_e = 1\nvar_a = int(var_a)\nvar_d = int(var_d)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e * (var_a-i)\nprint(int(var_e))"
    },
    "5725": {
        "category": "Comparison",
        "question_ko": "슬기의 키는 159센티미터(㎝)이고 호현이는 키는 162센티미터(㎝)입니다. 둘 중 키가 더 큰 사람은 누구입니까?",
        "question_en": "Seulgi is 159 centimeters (cm) tall and Hohyeon is 162 centimeters (cm) tall. Which of the two is taller?",
        "answer_ko": "호현",
        "answer_en": "Hohyeon",
        "solution_abst_ko": "[OP_LIST_SOL] 호현 슬기 [OP_LIST_EOL] [OP_LIST_SOL] 162 159 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Seulgi Hohyeon [OP_LIST_EOL] [OP_LIST_SOL] 159 162 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '호현'\nvar_b = '슬기'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 162\nvar_d = 159\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Seulgi'\nvar_b = 'Hohyeon'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 159\nvar_d = 162\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "5726": {
        "category": "Comparison",
        "question_ko": "학교에서 학생들은 교대로 발표를 합니다. 6번째는 은정이고 7명의 학생이 뒤를 이었다. 총 몇 명의 학생이 출석합니까?",
        "question_en": "At school, students take turns giving presentations. Eunjung was in sixth place, followed by seven students. How many students are there in total?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "6 7 [OP_ADD]",
        "solution_abst_en": "6 7 [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "5727": {
        "category": "Comparison",
        "question_ko": "똑같은 동화책을 신영이는 전체의 1/3, 석기는 전체의 1/4, 웅이는 전체의 1/5를 읽었습니다. 동화책을 가장 많이 읽은 사람은 누구입니까?",
        "question_en": "Shinyoung read 1/3 of the children's book, Seokgi 1/4, and Woong 1/5. Who has read the most of the children's book?",
        "answer_ko": "신영",
        "answer_en": "Shinyoung",
        "solution_abst_ko": "[OP_LIST_SOL] 신영 석기 웅이 [OP_LIST_EOL] [OP_LIST_SOL] 1/3 1/4 1/5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Shinyoung Seokgi Woong [OP_LIST_EOL] [OP_LIST_SOL] 1/3 1/4 1/5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '신영'\nvar_b = '석기'\nvar_c = '웅이'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.3333333333333333\nvar_e = 0.25\nvar_f = 0.2\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Shinyoung'\nvar_b = 'Seokgi'\nvar_c = 'Woong'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.3333333333333333\nvar_e = 0.25\nvar_f = 0.2\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "5728": {
        "category": "Arithmetic calculation",
        "question_ko": "희선이네 반 학생 20명은 1번부터 20번까지 자신의 출석 번호를 가지고 있습니다. 희선이네 반 학생 중 여학생은 1번, 3번, 4번, 6번, 7번, 10번, 11번, 13번, 16번, 17번, 18번, 20번 학생이고, 외동인 학생은 1번, 4번, 5번, 8번, 11번, 14번, 17번, 20번 학생일 때, 외동인 여학생은 몇 명입니까?",
        "question_en": "The 20 students in Heesun's class have their own attendance numbers ranging from 1 to 20. Among the students in Heesun's class, the female students numbers are 1, 3, 4, 6, 7, 10, 11, 13, 16, 17, 18, and 20, and the student who is an only child is numbered 1, 4, 5, 8, 11, 14, 17 and 20. Find out the number of students who are female and at the same time, an only child.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 4 6 7 10 11 13 16 17 18 20 [OP_LIST_EOL] [OP_LIST_SOL] 1 4 5 8 11 14 17 20 [OP_LIST_EOL] [OP_SET_INTERSECT] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 4 6 7 10 11 13 16 17 18 20 [OP_LIST_EOL] [OP_LIST_SOL] 1 4 5 8 11 14 17 20 [OP_LIST_EOL] [OP_SET_INTERSECT] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 4\nvar_d = 6\nvar_e = 7\nvar_f = 10\nvar_g = 11\nvar_h = 13\nvar_i = 16\nvar_j = 17\nvar_k = 18\nvar_l = 20\nlist_a= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_a.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_a.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_a.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_m = 1\nvar_n = 4\nvar_o = 5\nvar_p = 8\nvar_q = 11\nvar_r = 14\nvar_s = 17\nvar_t = 20\nlist_b= []\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_b.append(var_t)\nif \"/\" in str(var_s):\n    var_s = eval(str(var_s))\nlist_b.append(var_s)\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nlist_b.reverse()\nlist_c = list(set(list_a) & set(list_b))\nvar_u = len(list_c)\nprint(int(var_u))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 4\nvar_d = 6\nvar_e = 7\nvar_f = 10\nvar_g = 11\nvar_h = 13\nvar_i = 16\nvar_j = 17\nvar_k = 18\nvar_l = 20\nlist_a= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_a.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_a.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_a.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_m = 1\nvar_n = 4\nvar_o = 5\nvar_p = 8\nvar_q = 11\nvar_r = 14\nvar_s = 17\nvar_t = 20\nlist_b= []\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_b.append(var_t)\nif \"/\" in str(var_s):\n    var_s = eval(str(var_s))\nlist_b.append(var_s)\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nlist_b.reverse()\nlist_c = list(set(list_a) & set(list_b))\nvar_u = len(list_c)\nprint(int(var_u))"
    },
    "5729": {
        "category": "Possibility",
        "question_ko": "3, 5, 8, 9중 세 개를 뽑아 세 자리 자연수를 만들 때, 가능한 모든 수들의 개수는 몇개입니까?",
        "question_en": "If three of 3, 5, 8, and 9 are drawn to form a three-digit natural number, how many possible numbers are there?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "[OP_LIST_SOL] 3 5 8 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 3 5 8 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 3\nvar_b = 5\nvar_c = 8\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 3\nvar_b = 5\nvar_c = 8\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "5730": {
        "category": "Arithmetic calculation",
        "question_ko": "투명한 병에는 12리터(L) 400밀리리터(㎖)의 물이 들어있고, 불투명한 병에는 물이 7600밀리리터(㎖)가 들어있습니다. 두 병에 들어있는 물의 양이 같아지려면 투명한 병에서 불투명한 병으로 몇 리터(L)를 옮겨야 합니까?",
        "question_en": "The transparent bottle contains 12 liters (L) and 400 milliliters (ml) of water, and the opaque bottle contains 7600 milliliters (ml) of water. How many liters (l) must be transferred from the transparent bottle to the opaque bottle to equalize the volume of water in the two bottles?",
        "answer_ko": "2.40",
        "answer_en": "2.4",
        "solution_abst_ko": "12 400 1000 [OP_DIV] [OP_ADD] 7600 1000 [OP_DIV] [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "12 400 1000 [OP_DIV] [OP_ADD] 7600 1000 [OP_DIV] [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 400\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 7600\nvar_g = 1000\nvar_h = var_f / var_g\nvar_i = var_e - var_h\nvar_j = 2\nvar_k = var_i / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 12\nvar_b = 400\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 7600\nvar_g = 1000\nvar_h = var_f / var_g\nvar_i = var_e - var_h\nvar_j = 2\nvar_k = var_i / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "5731": {
        "category": "Correspondence",
        "question_ko": "A+B=84이고 B+C=60이고 A=B+B+B+B+B+B입니다. A, B, C는 서로 다른 세 자연수일 때 A-C를 구하세요.",
        "question_en": "A+B=84 and B+C=60 and A=B+B+B+B+B+B. Find A-C when A, B, and C are three different natural numbers.",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "84 7 [OP_DIV] 6 [OP_MUL] 60 84 7 [OP_DIV] [OP_SUB] [OP_SUB]",
        "solution_abst_en": "84 7 [OP_DIV] 6 [OP_MUL] 60 84 7 [OP_DIV] [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 84\nvar_b = 7\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c * var_d\nvar_f = 60\nvar_g = 84\nvar_h = 7\nvar_i = var_g / var_h\nvar_j = var_f - var_i\nvar_k = var_e - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 84\nvar_b = 7\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c * var_d\nvar_f = 60\nvar_g = 84\nvar_h = 7\nvar_i = var_g / var_h\nvar_j = var_f - var_i\nvar_k = var_e - var_j\nprint(int(var_k))"
    },
    "5732": {
        "category": "Arithmetic calculation",
        "question_ko": "준회는 134.5센티미터(㎝)의 철사를 가졌습니다. 유진이가 가진 철사의 길이는 준회가 가진 철사의 1.06배라면 유진이가 가진 철사는 몇 센티미터(㎝) 인지 구하세요.",
        "question_en": "Junhoe had a wire measuring 134.5 cm (cm). If the length of Yujin's wire was 1.06 times the length of Junhoe's wire, how many centimeters (cm) long is Yujin's wire?",
        "answer_ko": "142.57",
        "answer_en": "142.57",
        "solution_abst_ko": "134.5 1.06 [OP_MUL]",
        "solution_abst_en": "134.5 1.06 [OP_MUL]",
        "solution_code_ko": "var_a = 134.5\nvar_b = 1.06\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 134.5\nvar_b = 1.06\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "5733": {
        "category": "Comparison",
        "question_ko": "기차 안에는 어른들이 이린이보다 17명 더 많습니다. 다음 역에서 어른 57명, 어린이 18명이 타고 44명이 내렸습니다. 현재 기차 안에는 502명이 있을 때 처음에 기차 안에 있던 어른들은 몇 명입니까?",
        "question_en": "There are 17 more adults on the train compared to the children. At the next station, 57 adults and 18 children got on and 44 got off. How many adults were on the train initially, provided there are 502 people on the train now?",
        "answer_ko": "244",
        "answer_en": "244",
        "solution_abst_ko": "502 18 57 [OP_ADD] 44 [OP_SUB] [OP_SUB] 17 [OP_ADD] 2 [OP_DIV]",
        "solution_abst_en": "502 18 57 [OP_ADD] 44 [OP_SUB] [OP_SUB] 17 [OP_ADD] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 502\nvar_b = 18\nvar_c = 57\nvar_d = var_b + var_c\nvar_e = 44\nvar_f = var_d - var_e\nvar_g = var_a - var_f\nvar_h = 17\nvar_i = var_g + var_h\nvar_j = 2\nvar_k = var_i / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 502\nvar_b = 18\nvar_c = 57\nvar_d = var_b + var_c\nvar_e = 44\nvar_f = var_d - var_e\nvar_g = var_a - var_f\nvar_h = 17\nvar_i = var_g + var_h\nvar_j = 2\nvar_k = var_i / var_j\nprint(int(var_k))"
    },
    "5734": {
        "category": "Possibility",
        "question_ko": "0, 2, 4, 6, 8, 9 수 카드를 모두 한 번씩만 사용하여 두 번째로 작은 수를 찾으시오",
        "question_en": "Find the second smallest number using all 0, 2, 4, 6, 8, and 9 cards only once.",
        "answer_ko": "204698",
        "answer_en": "204698",
        "solution_abst_ko": "[OP_LIST_SOL] 0 2 4 6 8 9 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 2 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 2 4 6 8 9 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 2 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 0\nvar_b = 2\nvar_c = 4\nvar_d = 6\nvar_e = 8\nvar_f = 9\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nprint(int(var_i))",
        "solution_code_en": "var_a = 0\nvar_b = 2\nvar_c = 4\nvar_d = 6\nvar_e = 8\nvar_f = 9\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nprint(int(var_i))"
    },
    "5735": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 10까지의 홀수 중 6미만인 수들의 평균은 얼마입니까?",
        "question_en": "Find the average of the odd numbers from 1 to 10 that are less than 6.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "1 10 [OP_LIST_ODD] 6 [OP_LIST_LESS] [OP_LIST_MEAN]",
        "solution_abst_en": "1 10 [OP_LIST_ODD] 6 [OP_LIST_LESS] [OP_LIST_MEAN]",
        "solution_code_ko": "var_a = 1\nvar_b = 10\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 6\nlist_b = []\nfor i in list_a:\n    if i < var_c:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_d = sum(list_b)/len(list_b)\nprint(int(var_d))",
        "solution_code_en": "var_a = 1\nvar_b = 10\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 6\nlist_b = []\nfor i in list_a:\n    if i < var_c:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_d = sum(list_b)/len(list_b)\nprint(int(var_d))"
    },
    "5736": {
        "category": "Possibility",
        "question_ko": "지민이는 마트의 과일 코너에 왔습니다. 과일 코너에는 사과, 배, 참외 세 종류가 있습니다. 이 과일들로 6개의 과일들을 사는 방법은 모두 몇 가지인가요?",
        "question_en": "Jimin came to the fruit section of the supermarket. In the fruit section, there are three types of fruits, apple, pear, and melon. How many ways are there to buy all 6 fruits with these fruits?",
        "answer_ko": "28",
        "answer_en": "28",
        "solution_abst_ko": "3 1 [OP_SUB] 6 [OP_ADD] 6 [OP_COMB]",
        "solution_abst_en": "3 1 [OP_SUB] 6 [OP_ADD] 6 [OP_COMB]",
        "solution_code_ko": "var_a = 3\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = var_c + var_d\nvar_f = 6\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g / (i+1)\nprint(int(var_g))",
        "solution_code_en": "var_a = 3\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = var_c + var_d\nvar_f = 6\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g / (i+1)\nprint(int(var_g))"
    },
    "5737": {
        "category": "Arithmetic calculation",
        "question_ko": "40부터 50사이의 짝수 중에서 7로 나눈 나머지가 2인 수를 구하시오.",
        "question_en": "Find an even number between 40 and 50 that has a remainder of 2 when divided by 7.",
        "answer_ko": "44",
        "answer_en": "44",
        "solution_abst_ko": "40 50 [OP_LIST_EVEN] 7 2 [OP_LIST_DIVIDE_AND_REMAIN] [OP_LIST_SUM]",
        "solution_abst_en": "40 50 [OP_LIST_EVEN] 7 2 [OP_LIST_DIVIDE_AND_REMAIN] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 40\nvar_b = 50\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 7\nvar_d = 2\nlist_b = [] \nvar_c = int(var_c)\nvar_d = int(var_d)\nif var_d < 0:\n    var_d = var_d + var_c\nfor i in list_a:\n    i = int(i)\n    if i%var_c == var_d:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 40\nvar_b = 50\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 7\nvar_d = 2\nlist_b = [] \nvar_c = int(var_c)\nvar_d = int(var_d)\nif var_d < 0:\n    var_d = var_d + var_c\nfor i in list_a:\n    i = int(i)\n    if i%var_c == var_d:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint(int(var_e))"
    },
    "5738": {
        "category": "Geometry",
        "question_ko": "길이가 18센티미터(㎝)인 종이 테이프 12장을 겹치는 부분의 길이가 같도록 풀로 붙여서 둥근 고리 모양을 만들었습니다. 이 둥근 고리 모양의 둘레의 길이가 210센티미터(㎝)라면, 겹쳐진 부분의 길이는 몇 밀리미터(㎜)입니까?",
        "question_en": "There is a perimeter of 210 centimeters (m) round ring made by connecting 12 sheets of paper tape whose length is 18 centimeters (cm). If the overlapped parts of the tape is the same, find how much is overlapped in millimeters (mm).",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "18 12 [OP_MUL] 210 [OP_SUB] 12 [OP_DIV] 10 [OP_MUL]",
        "solution_abst_en": "18 12 [OP_MUL] 210 [OP_SUB] 12 [OP_DIV] 10 [OP_MUL]",
        "solution_code_ko": "var_a = 18\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 210\nvar_e = var_c - var_d\nvar_f = 12\nvar_g = var_e / var_f\nvar_h = 10\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 18\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 210\nvar_e = var_c - var_d\nvar_f = 12\nvar_g = var_e / var_f\nvar_h = 10\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "5739": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 100까지의 자연수 중에서 모든 짝수의 합과 모든 홀수의 합의 차를 구하시오",
        "question_en": "Find the difference between the sum of all even numbers and the sum of all odd numbers from 1 to 100.",
        "answer_ko": "50",
        "answer_en": "50",
        "solution_abst_ko": "1 100 [OP_LIST_EVEN] [OP_LIST_SUM] 1 100 [OP_LIST_ODD] [OP_LIST_SUM] [OP_SUB]",
        "solution_abst_en": "1 100 [OP_LIST_EVEN] [OP_LIST_SUM] 1 100 [OP_LIST_ODD] [OP_LIST_SUM] [OP_SUB]",
        "solution_code_ko": "var_a = 1\nvar_b = 100\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nvar_d = 1\nvar_e = 100\nlist_b = []\nif var_d%2==0:\n    for i in range(var_d+1, var_e+1, 2):\n        list_b.append(i)\nelse:\n    for i in range(var_d, var_e+1, 2):\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 100\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nvar_d = 1\nvar_e = 100\nlist_b = []\nif var_d%2==0:\n    for i in range(var_d+1, var_e+1, 2):\n        list_b.append(i)\nelse:\n    for i in range(var_d, var_e+1, 2):\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "5740": {
        "category": "Possibility",
        "question_ko": "흰색 모자가 1개, 구분안되는 검은색 모자가 4개있습니다. 이 모자들을 서로 다르게 한 줄로 배열하는 방법은 모두 몇 가지입니까?",
        "question_en": "There is 1 white hat and 4 indistinguishable black hats. How many different ways can you arrange these hats in a row?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "4 1 [OP_ADD]",
        "solution_abst_en": "4 1 [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "5741": {
        "category": "Comparison",
        "question_ko": "수영장에서 수영 시합을 했습니다. 2등은 남준이, 4등은 윤기입니다. 호석이는 남준이보다 느리고 윤기보다 빨랐습니다. 호석이는 몇 등입니까?",
        "question_en": "We had a swimming competition in the pool. 2nd place is Namjoon, 4th place is Yoongi. Hoseok was slower than Namjoon and faster than Yoongi. What is the rank of Hoseok?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "2 4 [OP_ADD] 2 [OP_FDIV]",
        "solution_abst_en": "2 4 [OP_ADD] 2 [OP_FDIV]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "5742": {
        "category": "Arithmetic calculation",
        "question_ko": "사과 상자 7개에 모두 같은 무게의 사과가 담겨있습니다. 각 상자에서 사과를 20킬로그램(㎏)씩 꺼낸 후 7개 사과 상자의 무게를 재어보니 처음 사과 상자 3개의 무게와 같았습니다. 처음 사과 상자 1개의 무게를 구하시오.",
        "question_en": "All seven boxes of apples contain the same weight of apples. After taking out 20 kilograms (kg) of apples from each box, the weight of the seven apple boxes was equal to the weight of the first three apple boxes. Find the weight of the first box of apples.",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "20 7 [OP_MUL] 7 3 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "20 7 [OP_MUL] 7 3 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 20\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = 3\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 20\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = 3\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))"
    },
    "5743": {
        "category": "Possibility",
        "question_ko": "숫자 카드 1, 6, 8를 한 번씩 모두 사용하여 두 번째로 작은 세 자리 수와 세 번째로 작은 세 자리수의 차를 구하시오.",
        "question_en": "Find the difference between the second smallest three-digit number and the third smallest three-digit number using all number cards 1, 6, and 8 once.",
        "answer_ko": "432",
        "answer_en": "432",
        "solution_abst_ko": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MIN] 3 [OP_LIST_GET] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MIN] 3 [OP_LIST_GET] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = 3\nvar_h = list_b[var_g-1]\nvar_i = var_f - var_h\nvar_j = abs(var_i)\nprint(int(var_j))",
        "solution_code_en": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = 3\nvar_h = list_b[var_g-1]\nvar_i = var_f - var_h\nvar_j = abs(var_i)\nprint(int(var_j))"
    },
    "5744": {
        "category": "Correspondence",
        "question_ko": "서로 다른 두 수 A, B가 있습니다. 두 자리 수끼리의 덧셈식 A7+3B=73에서 A를 구하시오.",
        "question_en": "There are two different numbers: A and B. Find A from the two-digit addition formula of A7+3B=73.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "A7+3B=73 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A7+3B=73 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A7+3B=73'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A7+3B=73'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "5745": {
        "category": "Comparison",
        "question_ko": "4개의 숫자 0.8, 1/2, 0.9, 1/3가 있습니다. 3보다 작거나 같은 수 중 가장 크거나 같은 숫자는 얼마인가요?",
        "question_en": "There are four numbers 0.8, 1/2, 0.9, and 1/3. Which number is the greatest among the numbers that are smaller than or equal to 3?",
        "answer_ko": "0.90",
        "answer_en": "0.9",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 3 [OP_LIST_LESS_EQUAL] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 3 [OP_LIST_LESS_EQUAL] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = []\nfor i in list_a:\n    if i <= var_e:\n        list_b.append(i)\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = []\nfor i in list_a:\n    if i <= var_e:\n        list_b.append(i)\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "5746": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 267을 빼야 할 것을 잘못하여 더했더니 821이 되었습니다. 바르게 계산하면 얼마인지 구해 보시오.",
        "question_en": "I mistakenly added 267 which should have subtracted from a number, and I got 821. Find out how much it is if you calculate it correctly.",
        "answer_ko": "287",
        "answer_en": "287",
        "solution_abst_ko": "821 267 [OP_SUB] 267 [OP_SUB]",
        "solution_abst_en": "821 267 [OP_SUB] 267 [OP_SUB]",
        "solution_code_ko": "var_a = 821\nvar_b = 267\nvar_c = var_a - var_b\nvar_d = 267\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 821\nvar_b = 267\nvar_c = var_a - var_b\nvar_d = 267\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "5747": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 가게에서 파는 연필이 5천원보다 2백원 비쌀 때, 연필의 가격을 만원 단위로 구하시오.",
        "question_en": "If a pencil sold at a store is 200 won more expensive than 5,000 won, find the price of the pencil in units of 10,000 won.",
        "answer_ko": "0.52",
        "answer_en": "0.52",
        "solution_abst_ko": "5000 200 [OP_ADD] 10000 [OP_DIV]",
        "solution_abst_en": "5000 200 [OP_ADD] 10000 [OP_DIV]",
        "solution_code_ko": "var_a = 5000\nvar_b = 200\nvar_c = var_a + var_b\nvar_d = 10000\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 5000\nvar_b = 200\nvar_c = var_a + var_b\nvar_d = 10000\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "5748": {
        "category": "Geometry",
        "question_ko": "밑면이 팔각형인 각뿔이 있습니다. 옆면은 몇 개 일까요?",
        "question_en": "There is a pyramid with an octagonal base. How many sides are there?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "8",
        "solution_abst_en": "8",
        "solution_code_ko": "var_a = 8\nprint(int(var_a))",
        "solution_code_en": "var_a = 8\nprint(int(var_a))"
    },
    "5749": {
        "category": "Comparison",
        "question_ko": "20명의 학생들이 한줄로 섰습니다. 정국이는 꼴지로 줄을 섰고, 윤기와 정국이 사이에는 5명의 학생이 있습니다. 윤기 뒤에 서 있는 학생은 몇 명입니까?",
        "question_en": "When 20 students stood in a line, Jungkook is the last, and there are 5 students between Yoongi and Jungkook. How many students are standing behind Yoongi?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "20 20 [OP_SUB] 1 [OP_ADD] 5 [OP_ADD]",
        "solution_abst_en": "20 20 [OP_SUB] 1 [OP_ADD] 5 [OP_ADD]",
        "solution_code_ko": "var_a = 20\nvar_b = 20\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 20\nvar_b = 20\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "5750": {
        "category": "Comparison",
        "question_ko": "수학 시험에서 정국이는 5등을 했고, 광수는 3등을 했습니다. 미주는 정국이보다 시험 점수가 높았지만 광수보다는 시험 점수가 낮았습니다. 미주는 몇 등입니까?",
        "question_en": "In the math test, Jungkook placed the 5th, and Kwangsoo placed the 3rd. If Mijoo had a higher score than Jungkook, but a lower score than Kwangsoo, what rank would Mijoo be?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "5 3 [OP_ADD] 2 [OP_FDIV]",
        "solution_abst_en": "5 3 [OP_ADD] 2 [OP_FDIV]",
        "solution_code_ko": "var_a = 5\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "5751": {
        "category": "Correspondence",
        "question_ko": "A+A=6, B-A=4, C+B=9, D-C=7을 만족하는 서로 다른 네 수 A, B, C, D 중 D의 값은 무엇인지 구하시오.",
        "question_en": "What is the value of D among the four different numbers A, B, C, and D that satisfy A+A=6, B-A=4, C+B=9, and D-C=7?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "A+A=6 A [OP_NUM_UNK_SOLVER] 4 [OP_ADD] 9 [OP_SUB] 7 [OP_SUB] -1 [OP_MUL]",
        "solution_abst_en": "A+A=6 A [OP_NUM_UNK_SOLVER] 4 [OP_ADD] 9 [OP_SUB] 7 [OP_SUB] -1 [OP_MUL]",
        "solution_code_ko": "var_a = 'A+A=6'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 9\nvar_g = var_e - var_f\nvar_h = 7\nvar_i = var_g - var_h\nvar_j = -1\nvar_k = var_i * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 'A+A=6'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 9\nvar_g = var_e - var_f\nvar_h = 7\nvar_i = var_g - var_h\nvar_j = -1\nvar_k = var_i * var_j\nprint(int(var_k))"
    },
    "5752": {
        "category": "Possibility",
        "question_ko": "A, B를 포함한 6명의 사람을 일렬로 세울 때, A, B가 이웃하도록 일렬로 세우는 경우의 수는?",
        "question_en": "When 6 people including A and B are lined up, in how many ways can A and B be lined up next to each other?",
        "answer_ko": "240",
        "answer_en": "240",
        "solution_abst_ko": "6 [OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_LEN] 1 [OP_SUB] [OP_SUB] 6 [OP_LIST_LEN] 1 [OP_SUB] [OP_SUB] [OP_PERM] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL]",
        "solution_abst_en": "6 [OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_LEN] 1 [OP_SUB] [OP_SUB] 6 [OP_LIST_LEN] 1 [OP_SUB] [OP_SUB] [OP_PERM] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL]",
        "solution_code_ko": "var_a = 6\nvar_b = 'A'\nvar_c = 'B'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_a - var_f\nvar_h = 6\nvar_i = len(list_a)\nvar_j = 1\nvar_k = var_i - var_j\nvar_l = var_h - var_k\nvar_m = 1\nvar_g = int(var_g)\nvar_l = int(var_l)\nfor i, elem in enumerate(range(var_l)):\n    var_m = var_m * (var_g-i)\nvar_n = len(list_a)\nvar_o = len(list_a)\nvar_p = 1\nvar_n = int(var_n)\nvar_o = int(var_o)\nfor i, elem in enumerate(range(var_o)):\n    var_p = var_p * (var_n-i)\nvar_q = var_m * var_p\nprint(int(var_q))",
        "solution_code_en": "var_a = 6\nvar_b = 'A'\nvar_c = 'B'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_a - var_f\nvar_h = 6\nvar_i = len(list_a)\nvar_j = 1\nvar_k = var_i - var_j\nvar_l = var_h - var_k\nvar_m = 1\nvar_g = int(var_g)\nvar_l = int(var_l)\nfor i, elem in enumerate(range(var_l)):\n    var_m = var_m * (var_g-i)\nvar_n = len(list_a)\nvar_o = len(list_a)\nvar_p = 1\nvar_n = int(var_n)\nvar_o = int(var_o)\nfor i, elem in enumerate(range(var_o)):\n    var_p = var_p * (var_n-i)\nvar_q = var_m * var_p\nprint(int(var_q))"
    },
    "5753": {
        "category": "Correspondence",
        "question_ko": "민영이가 귤 2개와 사과 7개를 팔았을 때, 민영이가 판 과일의 개수는 몇 개일까요?",
        "question_en": "When Minyoung sells 2 tangerines and 7 apples, how many fruits does Minyoung sell?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "2 7 [OP_ADD]",
        "solution_abst_en": "2 7 [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "5754": {
        "category": "Comparison",
        "question_ko": "민수는 재혁, 경환, 재호에게 공책 30권을 나누어주었습니다. 재혁이는 12개의 공책을, 경환이는 3권의 공책을, 재호는 15권의 공책을 받았습니다. 어떤 친구가 제일 많은 공책을 받았습니까?",
        "question_en": "Minsu gave 30 notebooks to Jaehyuk, Kyunghwan, and Jaeho. Jaehyeok received 12 notebooks, Kyunghwan received 3 notebooks, and Jaeho received 15 notebooks. Which friend got the most notebooks?",
        "answer_ko": "재호",
        "answer_en": "Jaeho",
        "solution_abst_ko": "[OP_LIST_SOL] 재혁 경환 재호 [OP_LIST_EOL] [OP_LIST_SOL] 12 3 15 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jaehyuk Kyunghwan Jaeho [OP_LIST_EOL] [OP_LIST_SOL] 12 3 15 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '재혁'\nvar_b = '경환'\nvar_c = '재호'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 12\nvar_e = 3\nvar_f = 15\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Jaehyuk'\nvar_b = 'Kyunghwan'\nvar_c = 'Jaeho'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 12\nvar_e = 3\nvar_f = 15\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "5755": {
        "category": "Possibility",
        "question_ko": "숫자 2, 4, 6, 8을 한 번씩 모두 이용하여 만들 수 있는 세 번째로 큰 네 자리 수와 네 번째로 큰 네 자리 수의 차를 구하시오.",
        "question_en": "Find the difference between the third largest four-digit number and the fourth largest four-digit number that can be formed by using the numbers 2, 4, 6, and 8 once each.",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "[OP_LIST_SOL] 2 4 6 8 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] 4 [OP_LIST_MAX] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 2 4 6 8 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] 4 [OP_LIST_MAX] [OP_SUB]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = 6\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 4\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nvar_j = var_g - var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = 6\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 4\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nvar_j = var_g - var_i\nprint(int(var_j))"
    },
    "5756": {
        "category": "Arithmetic calculation",
        "question_ko": "국어,영어 평균이 92점이며 수학 점수도 고려하면 평균 2점이 오른다. 수학은 몇 점인가?",
        "question_en": "The average score for Korean and English tests is 92 points, and the average score rises by 2 points when math scores are also considered. What is the score for the math test?",
        "answer_ko": "98",
        "answer_en": "98",
        "solution_abst_ko": "92 2 [OP_ADD] 3 [OP_MUL] 92 2 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "92 2 [OP_ADD] 3 [OP_MUL] 92 2 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 92\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c * var_d\nvar_f = 92\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 92\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c * var_d\nvar_f = 92\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nprint(int(var_i))"
    },
    "5757": {
        "category": "Geometry",
        "question_ko": "둘레가 43.56센티미터(㎝)인 정육각형의 한 변의 길이는 얼마입니까?",
        "question_en": "What is the length of one side of a regular hexagon with a perimeter of 43.56 centimeters (cm)?",
        "answer_ko": "7.26",
        "answer_en": "7.26",
        "solution_abst_ko": "43.56 6 [OP_DIV]",
        "solution_abst_en": "43.56 6 [OP_DIV]",
        "solution_code_ko": "var_a = 43.56\nvar_b = 6\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 43.56\nvar_b = 6\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "5758": {
        "category": "Geometry",
        "question_ko": "어떤 주사위의 한 면의 넓이는 64제곱센티미터(㎠)입니다. 이 주사위의 부피를 구하시오.",
        "question_en": "The area of one side of a die is 64 square centimeters (cm2). Find the volume of this die.",
        "answer_ko": "512",
        "answer_en": "512",
        "solution_abst_ko": "64 1/2 [OP_POW] 3 [OP_POW]",
        "solution_abst_en": "64 1/2 [OP_POW] 3 [OP_POW]",
        "solution_code_ko": "var_a = 64\nvar_b = 0.5\nvar_c = var_a ** var_b\nvar_d = 3\nvar_e = var_c ** var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 64\nvar_b = 0.5\nvar_c = var_a ** var_b\nvar_d = 3\nvar_e = var_c ** var_d\nprint(int(var_e))"
    },
    "5759": {
        "category": "Possibility",
        "question_ko": "각 자리 수가 모두 홀수인 세 자리 수 중 500보다 작은 수의 개수를 구하시오.",
        "question_en": "Find the number of numbers less than 500 among three digit numbers where each digit is a odd number.",
        "answer_ko": "50",
        "answer_en": "50",
        "solution_abst_ko": "1 9 [OP_LIST_ODD] 3 [OP_LIST_GET_PRODUCT] 500 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "1 9 [OP_LIST_ODD] 3 [OP_LIST_GET_PRODUCT] 500 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = 500\nlist_c = []\nfor i in list_b:\n    if i < var_d:\n        list_c.append(i)\nvar_e = len(list_c)\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = 500\nlist_c = []\nfor i in list_b:\n    if i < var_d:\n        list_c.append(i)\nvar_e = len(list_c)\nprint(int(var_e))"
    },
    "5760": {
        "category": "Comparison",
        "question_ko": "한울 초등학교의 1학년 학생은 168명이고, 2학년 학생은 173명입니다. 몇 학년 학생이 더 많은지 구하시오.",
        "question_en": "Hanul Elementary School has 168 first grade students and 173 second grade students. Find out which grade has more students.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 1 2 [OP_LIST_EOL] [OP_LIST_SOL] 168 173 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] 1 2 [OP_LIST_EOL] [OP_LIST_SOL] 168 173 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 1\nvar_b = 2\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 168\nvar_d = 173\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(int(var_h))",
        "solution_code_en": "var_a = 1\nvar_b = 2\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 168\nvar_d = 173\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(int(var_h))"
    },
    "5761": {
        "category": "Geometry",
        "question_ko": "정십이면체 모양의 상자가 있습니다. 이 상장의 면에 있는 변의 개수는?",
        "question_en": "There is a box in the shape of a regular icosahedron. How many edges are there on a face of this box?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "5",
        "solution_abst_en": "5",
        "solution_code_ko": "var_a = 5\nprint(int(var_a))",
        "solution_code_en": "var_a = 5\nprint(int(var_a))"
    },
    "5762": {
        "category": "Geometry",
        "question_ko": "둘레가 28센티미터(㎝)이고, 가로가 9센티미터(㎝)인 직사각형의 넓이는 몇 제곱센티미터입니까?",
        "question_en": "What is the area of a rectangle with a perimeter of 28 centimeters (cm) and a length of 9 centimeters (cm) in square centimeters (cm2)?",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "28 9 2 [OP_MUL] [OP_SUB] 2 [OP_DIV] 9 [OP_MUL]",
        "solution_abst_en": "28 9 2 [OP_MUL] [OP_SUB] 2 [OP_DIV] 9 [OP_MUL]",
        "solution_code_ko": "var_a = 28\nvar_b = 9\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 9\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 28\nvar_b = 9\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 9\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "5763": {
        "category": "Possibility",
        "question_ko": "남희의 생일은 6월 18일이다. 자신의 생일에 나오는 숫자를 모두 이용하여 세 자리 수를 만들고자 한다. 만들 수 있는 수 중 두 번째로 작은 수와 세 번째로 작은 수의 차이를 구하시오.",
        "question_en": "Namhee's birthday is on June 18th. He wants to create a three-digit number using all the numbers from his birthday. Find the difference between the second smallest and third smallest possible numbers.",
        "answer_ko": "432",
        "answer_en": "432",
        "solution_abst_ko": "[OP_LIST_SOL] 6 1 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MIN] 3 [OP_LIST_MIN] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "[OP_LIST_SOL] 6 1 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MIN] 3 [OP_LIST_MIN] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 6\nvar_b = 1\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f - var_h\nvar_j = abs(var_i)\nprint(int(var_j))",
        "solution_code_en": "var_a = 6\nvar_b = 1\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f - var_h\nvar_j = abs(var_i)\nprint(int(var_j))"
    },
    "5764": {
        "category": "Possibility",
        "question_ko": "강아지 2마리, 고양이 2마리를 한 줄로 세우려고 한다. 고양이끼리 연속으로 서 있는 경우는 모두 몇 가지인가?",
        "question_en": "I'm trying to put 2 dogs and 2 cats in a line. In how many ways can cats stand in a row?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "2 1 [OP_ADD] 2 1 [OP_ADD] [OP_PERM] 2 [OP_MUL]",
        "solution_abst_en": "2 1 [OP_ADD] 2 1 [OP_ADD] [OP_PERM] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = 1\nvar_c = int(var_c)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_c-i)\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 2\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = 1\nvar_c = int(var_c)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_c-i)\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "5765": {
        "category": "Correspondence",
        "question_ko": "A5-2B=68이 성립할 때, A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "When A5-2B=68, what number should go into A?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "A5-2B=68 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A5-2B=68 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A5-2B=68'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A5-2B=68'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "5766": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 10을 빼면 15가 됩니다. 호석이는 어떤 수에 5를 더하고자 합니다. 호석이가 구한 값은?",
        "question_en": "Subtracting 10 from a certain number results in 15. Hoseok wants to add 5 to the certain number. What value will Hoseok get?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "15 10 [OP_ADD] 5 [OP_ADD]",
        "solution_abst_en": "15 10 [OP_ADD] 5 [OP_ADD]",
        "solution_code_ko": "var_a = 15\nvar_b = 10\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 10\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "5767": {
        "category": "Arithmetic calculation",
        "question_ko": "은지네 반 학생 중 10명을 무작위로 선택해서 키를 물어보았더니, 각각 145센티미터(㎝), 142센티미터(㎝), 138센티미터(㎝), 136센티미터(㎝), 143센티미터(㎝), 146센티미터(㎝), 138센티미터(㎝), 144센티미터(㎝), 137센티미터(㎝), 141센티미터(㎝)였습니다. 이 학생들의 평균 키는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "Ten students in Eunji's class were randomly selected and asked about their heights, which were 145 centimeters (cm), 142 centimeters (cm), 138 centimeters (cm), 136 centimeters (cm), 143 centimeters (cm), 146 centimeters (cm), 138 centimeters (cm), 144 centimeters (cm), 137 centimeters (cm), and 141 centimeters (cm). Find the average height of these students in centimeters (cm).",
        "answer_ko": "141",
        "answer_en": "141",
        "solution_abst_ko": "[OP_LIST_SOL] 145 142 138 136 143 146 138 144 137 141 [OP_LIST_EOL] [OP_LIST_MEAN]",
        "solution_abst_en": "[OP_LIST_SOL] 145 142 138 136 143 146 138 144 137 141 [OP_LIST_EOL] [OP_LIST_MEAN]",
        "solution_code_ko": "var_a = 145\nvar_b = 142\nvar_c = 138\nvar_d = 136\nvar_e = 143\nvar_f = 146\nvar_g = 138\nvar_h = 144\nvar_i = 137\nvar_j = 141\nlist_a= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_a.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_k = sum(list_a)/len(list_a)\nprint(int(var_k))",
        "solution_code_en": "var_a = 145\nvar_b = 142\nvar_c = 138\nvar_d = 136\nvar_e = 143\nvar_f = 146\nvar_g = 138\nvar_h = 144\nvar_i = 137\nvar_j = 141\nlist_a= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_a.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_k = sum(list_a)/len(list_a)\nprint(int(var_k))"
    },
    "5768": {
        "category": "Correspondence",
        "question_ko": "CD, ACD, ABCD의 합이 2967일때 A를 구하시오",
        "question_en": "Find A when CD+ACD+ABCD=2967.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] CD + ACD + ABCD = 2967 [OP_LIST_EOL] [OP_LIST2NUM] A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "[OP_LIST_SOL] CD+ACD+ABCD= 2967 [OP_LIST_EOL] [OP_LIST2NUM] A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'CD'\nvar_b = '+'\nvar_c = 'ACD'\nvar_d = '+'\nvar_e = 'ABCD'\nvar_f = '='\nvar_g = 2967\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h=\"\"\nfor i in list_a:\n    i = str(i)\n    var_h = var_h + i\nvar_i = 'A'\nans_dict = dict()\nvar_h = var_h.replace('×','*')\nvar_h = var_h.replace('x','*')\nvar_h = var_h.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_h):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_h\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_h):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_j = ans_dict[var_i]\nprint(int(var_j))",
        "solution_code_en": "var_a = 'CD+ACD+ABCD='\nvar_b = 2967\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c=\"\"\nfor i in list_a:\n    i = str(i)\n    var_c = var_c + i\nvar_d = 'A'\nans_dict = dict()\nvar_c = var_c.replace('×','*')\nvar_c = var_c.replace('x','*')\nvar_c = var_c.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_c):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_c\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_c):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_e = ans_dict[var_d]\nprint(int(var_e))"
    },
    "5769": {
        "category": "Possibility",
        "question_ko": "승아는 5명의 친구들과 강릉으로 여행을 가게 되어 숙소를 정하게 되었다. A룸 1명, B룸 1명, C룸에 2명이 자게 되었다고 할 때, 승아가 A룸에서 자게 되는 경우의 수를 구하시오.",
        "question_en": "Seung-a went on a trip to Gangneung with 5 friends and decided a place to stay. If 1 person sleeps in Room A, 1 person in Room B, and 2 people sleep in Room C, find the number of cases in which Seung-a will sleep in Room A.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "5 1 [OP_SUB] 1 1 1 [OP_SUB] [OP_ADD] 2 [OP_ADD] [OP_PERM] 2 2 [OP_PERM] [OP_DIV]",
        "solution_abst_en": "5 1 [OP_SUB] 1 1 1 [OP_SUB] [OP_ADD] 2 [OP_ADD] [OP_PERM] 2 2 [OP_PERM] [OP_DIV]",
        "solution_code_ko": "var_a = 5\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = 1\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d + var_g\nvar_i = 2\nvar_j = var_h + var_i\nvar_k = 1\nvar_c = int(var_c)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_c-i)\nvar_l = 2\nvar_m = 2\nvar_n = 1\nvar_l = int(var_l)\nvar_m = int(var_m)\nfor i, elem in enumerate(range(var_m)):\n    var_n = var_n * (var_l-i)\nvar_o = var_k / var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 5\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = 1\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d + var_g\nvar_i = 2\nvar_j = var_h + var_i\nvar_k = 1\nvar_c = int(var_c)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_c-i)\nvar_l = 2\nvar_m = 2\nvar_n = 1\nvar_l = int(var_l)\nvar_m = int(var_m)\nfor i, elem in enumerate(range(var_m)):\n    var_n = var_n * (var_l-i)\nvar_o = var_k / var_n\nprint(int(var_o))"
    },
    "5770": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중에서 2번째로 큰 수와 가장 작은 수의 합은 얼마입니까?",
        "question_en": "There are three numbers 10, 11, and 12. What is the sum of the second-largest number and the smallest number?",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 2 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 2 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e + var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e + var_g\nprint(int(var_h))"
    },
    "5771": {
        "category": "Geometry",
        "question_ko": "어느 직사각형 모양의 놀이공원 이용권은 넓이가 1.77제곱센티미터(㎠)이고 가로의 길이가 3센티미터(㎝)입니다. 이 이용권의 세로의 길이는 몇 센티미터(㎝) 입니까?",
        "question_en": "A rectangular amusement park ticket is 3 centimeters (cm) wide and its area of it is 1.77 square centimeters (cm2). How many centimeters (cm) is the vertical length of this ticket?",
        "answer_ko": "0.59",
        "answer_en": "0.59",
        "solution_abst_ko": "1.77 3 [OP_DIV]",
        "solution_abst_en": "1.77 3 [OP_DIV]",
        "solution_code_ko": "var_a = 1.77\nvar_b = 3\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 1.77\nvar_b = 3\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "5772": {
        "category": "Comparison",
        "question_ko": "20명의 학생들이 한 줄로 줄을 섰습니다. 윤기의 뒤에는 11명의 학생들이 서 있고, 호석이는 윤기 바로 앞에 서 있습니다. 호석이 앞에 서 있는 학생은 몇 명입니까?",
        "question_en": "20 students are lined up in a single line. 11 students are standing behind Yoongi, and Hoseok is standing right in front of Yoongi. How many students are standing in front of Hoseok?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "20 11 [OP_SUB] 1 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "20 11 [OP_SUB] 1 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "5773": {
        "category": "Arithmetic calculation",
        "question_ko": "지연이는 우리나라 돈 17만원을 중국 돈 1000위안과 10위안짜리로 바꾸려고 합니다. 1000위안짜리로 바꿀 수 있는 돈을 모두 바꾼 후 남은 돈을 10위안짜리로 바꾸려고 하고 우리나라 돈 161.5원이 중국 돈 1위안이라면, 10위안짜리는 몇 장을 바꿀 수 있습니까?",
        "question_en": "Ji-yeon wants to exchange 170,000 won in Korean money in 1,000 yuan and 10 yuan in Chinese money. After changing all the money that can be exchanged for 1000 yuan bills, if you want to exchange the remaining money for 10 yuan bills, and 161.5 won of Korean money is 1 yuan of Chinese money, how many 10 yuan bills can you get?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "17 10000 [OP_MUL] 161.5 1000 [OP_MUL] [OP_MOD] 161.5 10 [OP_MUL] [OP_FDIV]",
        "solution_abst_en": "17 10000 [OP_MUL] 161.5 1000 [OP_MUL] [OP_MOD] 161.5 10 [OP_MUL] [OP_FDIV]",
        "solution_code_ko": "var_a = 17\nvar_b = 10000\nvar_c = var_a * var_b\nvar_d = 161.5\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = var_c % var_f\nvar_h = 161.5\nvar_i = 10\nvar_j = var_h * var_i\nvar_k = var_g // var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 17\nvar_b = 10000\nvar_c = var_a * var_b\nvar_d = 161.5\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = var_c % var_f\nvar_h = 161.5\nvar_i = 10\nvar_j = var_h * var_i\nvar_k = var_g // var_j\nprint(int(var_k))"
    },
    "5774": {
        "category": "Comparison",
        "question_ko": "어제 원희는 10시간과 9/10시간, 동일은 102/10시간을 잤다. 누가 가장 오래 잤는지 구하세요.",
        "question_en": "Yesterday, Wonhee slept 10 hours and 9/10 hours, and Dong-il slept 102/10 hours. Find out who slept the longest.",
        "answer_ko": "원희",
        "answer_en": "Wonhee",
        "solution_abst_ko": "[OP_LIST_SOL] 원희 동일 [OP_LIST_EOL] [OP_LIST_SOL] 10 9/10 [OP_ADD] 102/10 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Wonhee Dong-il [OP_LIST_EOL] [OP_LIST_SOL] 10 9/10 [OP_ADD] 102/10 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '원희'\nvar_b = '동일'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10\nvar_d = 0.9\nvar_e = var_c + var_d\nvar_f = 10.2\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Wonhee'\nvar_b = 'Dong-il'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10\nvar_d = 0.9\nvar_e = var_c + var_d\nvar_f = 10.2\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "5775": {
        "category": "Geometry",
        "question_ko": "한 모서리의 길이가 같은 육각기둥과 사각뿔이 있습니다. 육각기둥의 모든 모서리의 길이의 합은 81미터(m) 이고 모든 모서리의 길이가 같습니다. 사각뿔의 모든 모서리의 길이가 같을 때 사각뿔의 모든 모서리의 길이의 합은 몇 미터(m) 인지 구하시오.",
        "question_en": "There are hexagonal prisms and quadrangular pyramids with the same length of one edge. The sum of the lengths of all edges of a hexagonal prism is 81 meters (m), and all edges are the same length. Find the sum of the lengths of all the edges of the quadrangular pyramid, in meters (m), when all the edges of the quadrangular pyramid are the same length.",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "81 6 3 [OP_MUL] [OP_DIV] 4 2 [OP_MUL] [OP_MUL]",
        "solution_abst_en": "81 6 3 [OP_MUL] [OP_DIV] 4 2 [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 81\nvar_b = 6\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nvar_f = 4\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_e * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 81\nvar_b = 6\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nvar_f = 4\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_e * var_h\nprint(int(var_i))"
    },
    "5776": {
        "category": "Possibility",
        "question_ko": "기훈과 상우를 포함한 6명을 일렬로 세울 때, 기훈과 상우가 이웃하도록 일렬로 세우는 경우의 수를 구하시오.",
        "question_en": "In a situation where 6 people including Kihoon and Sangwoo are lined up, find the number of cases in which Kihoon and Sangwoo are lined up next to each other.",
        "answer_ko": "240",
        "answer_en": "240",
        "solution_abst_ko": "6 [OP_LIST_SOL] 기훈 상우 [OP_LIST_EOL] [OP_LIST_LEN] 1 [OP_SUB] [OP_SUB] 6 [OP_LIST_LEN] 1 [OP_SUB] [OP_SUB] [OP_PERM] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL]",
        "solution_abst_en": "6 [OP_LIST_SOL] Kihoon Sangwoo [OP_LIST_EOL] [OP_LIST_LEN] 1 [OP_SUB] [OP_SUB] 6 [OP_LIST_LEN] 1 [OP_SUB] [OP_SUB] [OP_PERM] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL]",
        "solution_code_ko": "var_a = 6\nvar_b = '기훈'\nvar_c = '상우'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_a - var_f\nvar_h = 6\nvar_i = len(list_a)\nvar_j = 1\nvar_k = var_i - var_j\nvar_l = var_h - var_k\nvar_m = 1\nvar_g = int(var_g)\nvar_l = int(var_l)\nfor i, elem in enumerate(range(var_l)):\n    var_m = var_m * (var_g-i)\nvar_n = len(list_a)\nvar_o = len(list_a)\nvar_p = 1\nvar_n = int(var_n)\nvar_o = int(var_o)\nfor i, elem in enumerate(range(var_o)):\n    var_p = var_p * (var_n-i)\nvar_q = var_m * var_p\nprint(int(var_q))",
        "solution_code_en": "var_a = 6\nvar_b = 'Kihoon'\nvar_c = 'Sangwoo'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_a - var_f\nvar_h = 6\nvar_i = len(list_a)\nvar_j = 1\nvar_k = var_i - var_j\nvar_l = var_h - var_k\nvar_m = 1\nvar_g = int(var_g)\nvar_l = int(var_l)\nfor i, elem in enumerate(range(var_l)):\n    var_m = var_m * (var_g-i)\nvar_n = len(list_a)\nvar_o = len(list_a)\nvar_p = 1\nvar_n = int(var_n)\nvar_o = int(var_o)\nfor i, elem in enumerate(range(var_o)):\n    var_p = var_p * (var_n-i)\nvar_q = var_m * var_p\nprint(int(var_q))"
    },
    "5777": {
        "category": "Correspondence",
        "question_ko": "우주네 반 수학평균은 42점이었는데 우주의 점수가 다시 채점되어 50으로 오르자 반 평균이 44가 되었다. 우주네 반 학생이 모두 10명일 때,우주가 처음 받은 성적은 얼마인지 구하여라",
        "question_en": "The math average of the Woojoo's class was 42, but when the Woojoo's score was re-scored and raised to 50, the class average was 44. If there are 10 students in Woojoo's classes, what Woojoo initially received?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "50 44 42 [OP_SUB] 10 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "50 44 42 [OP_SUB] 10 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 50\nvar_b = 44\nvar_c = 42\nvar_d = var_b - var_c\nvar_e = 10\nvar_f = var_d * var_e\nvar_g = var_a - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 50\nvar_b = 44\nvar_c = 42\nvar_d = var_b - var_c\nvar_e = 10\nvar_f = var_d * var_e\nvar_g = var_a - var_f\nprint(int(var_g))"
    },
    "5778": {
        "category": "Comparison",
        "question_ko": "호현, 슬기, 현정이가 다트 게임을 하고 있습니다. 호현이는 1번째에 23점, 2번째에 28점을 얻었습니다. 현정와 슬기는 각각 1번째에 32점과 27점을 얻었습니다. 현정이가 2번째에 얻은 점수가 17점일 때, 슬기가 단독 1등을 하기 위해서는 2번째에 적어도 몇 점을 얻어야 합니까?",
        "question_en": "Hohyeon, Seulgi, and Hyunjeong are playing darts. Hohyeon scored 23 points in the first and 28 points in the second. Hyunjeong and Seulgi scored 32 and 27 points in the first round, respectively. If Hyeonjeong's 2nd score is 17 points, how many points does Seulgi need to score 2nd in order to win first alone?",
        "answer_ko": "25",
        "answer_en": "25",
        "solution_abst_ko": "[OP_LIST_SOL] 호현 슬기 현정 [OP_LIST_EOL] [OP_LIST_SOL] 23 28 [OP_ADD] 32 17 [OP_ADD] 27 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] Hohyeon Seulgi Hyunjeong [OP_LIST_EOL] [OP_LIST_SOL] 23 28 [OP_ADD] 32 17 [OP_ADD] 27 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = '호현'\nvar_b = '슬기'\nvar_c = '현정'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 23\nvar_e = 28\nvar_f = var_d + var_e\nvar_g = 32\nvar_h = 17\nvar_i = var_g + var_h\nvar_j = 27\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_n = list_d[var_m-1]\nvar_o = var_l - var_n\nvar_p = 1\nvar_q = var_o + var_p\nprint(int(var_q))",
        "solution_code_en": "var_a = 'Hohyeon'\nvar_b = 'Seulgi'\nvar_c = 'Hyunjeong'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 23\nvar_e = 28\nvar_f = var_d + var_e\nvar_g = 32\nvar_h = 17\nvar_i = var_g + var_h\nvar_j = 27\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_n = list_d[var_m-1]\nvar_o = var_l - var_n\nvar_p = 1\nvar_q = var_o + var_p\nprint(int(var_q))"
    },
    "5779": {
        "category": "Possibility",
        "question_ko": "숫자 카드 2, 4, 6, 8을 사용하여 세 자리 수를 만들려고 한다. 같은 숫자 카드를 여러 번 사용해도 된다고 할 때, 만들 수 있는 모든 수들의 합을 구하여라.",
        "question_en": "Try to create a three-digit number using the number cards 2, 4, 6, and 8. Assuming you can use the same number card multiple times, find the sum of all possible numbers.",
        "answer_ko": "35520",
        "answer_en": "35520",
        "solution_abst_ko": "[OP_LIST_SOL] 2 4 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 2 4 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = 6\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = 6\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint(int(var_f))"
    },
    "5780": {
        "category": "Arithmetic calculation",
        "question_ko": "과자 72개와 사탕 56개를 각각 네 사람에게 똑같이 나누어 주려고 합니다. 한 사람이 가지는 과자와 사탕은 모두 몇 개인지 구하시오.",
        "question_en": "You want to divide 72 sweets and 56 candies equally among four people. Find the total number of sweets and candies that each person gets.",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "72 4 [OP_DIV] 56 4 [OP_DIV] [OP_ADD]",
        "solution_abst_en": "72 4 [OP_DIV] 56 4 [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 72\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 56\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 72\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 56\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "5781": {
        "category": "Possibility",
        "question_ko": "흰색 바둑돌 2개와 검은색 바둑돌 1개가 있습니다. 같은 색의 바둑돌은 각각 구별이 되지 않는다고 할 때, 바둑돌 3개를 서로 다르게 한 줄로 놓는 방법은 모두 몇 가지입니까?",
        "question_en": "There are 2 white stones and 1 black stone. How many different ways can you place 3 stones in a row, given that same color stones are indistinguishable from each other?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "1 2 [OP_ADD] 1 2 [OP_ADD] [OP_PERM] 2 2 [OP_PERM] [OP_DIV]",
        "solution_abst_en": "1 2 [OP_ADD] 1 2 [OP_ADD] [OP_PERM] 2 2 [OP_PERM] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 2\nvar_f = var_d + var_e\nvar_g = 1\nvar_c = int(var_c)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_c-i)\nvar_h = 2\nvar_i = 2\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nvar_k = var_g / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 1\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 2\nvar_f = var_d + var_e\nvar_g = 1\nvar_c = int(var_c)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_c-i)\nvar_h = 2\nvar_i = 2\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nvar_k = var_g / var_j\nprint(int(var_k))"
    },
    "5782": {
        "category": "Comparison",
        "question_ko": "밑면의 넓이가 8제곱센티미터(㎠)이고 높이가 7센티미터(㎝)인 직육면체 모양의 빨간색 상자와 한 변의 길이가 8센티미터(㎝)인 정육면체 모양의 파란색 상자에 크기가 같은 사탕을 채워 넣는다고 하면 어느 상자에 사탕이 더 많이 담길지 구하시오.",
        "question_en": "Suppose you fill in candies of the same size into a red rectangular cuboid-shaped box with a base area of 8 cubic centimeters (cm2) and a height of 7 centimeters (cm), and a blue cube-shaped box with a side length of 8 centimeters (cm). Find which box will contain more candies.",
        "answer_ko": "파란색",
        "answer_en": "blue",
        "solution_abst_ko": "[OP_LIST_SOL] 빨간색 파란색 [OP_LIST_EOL] [OP_LIST_SOL] 8 7 [OP_MUL] 8 8 [OP_MUL] 8 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] red blue [OP_LIST_EOL] [OP_LIST_SOL] 8 7 [OP_MUL] 8 8 [OP_MUL] 8 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '빨간색'\nvar_b = '파란색'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 8\nvar_d = 7\nvar_e = var_c * var_d\nvar_f = 8\nvar_g = 8\nvar_h = var_f * var_g\nvar_i = 8\nvar_j = var_h * var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'red'\nvar_b = 'blue'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 8\nvar_d = 7\nvar_e = var_c * var_d\nvar_f = 8\nvar_g = 8\nvar_h = var_f * var_g\nvar_i = 8\nvar_j = var_h * var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "5783": {
        "category": "Geometry",
        "question_ko": "길이 18센티미터(㎝)인 젤리 12개를, 겹치는 길이가 같도록 하여 겹쳐서 둥근 고리 모양으로 만들었다. 그 둘레가 210센티미터(㎝)일 때, 젤리의 겹쳐진 부분은 총 몇 밀리미터(㎜)인가?",
        "question_en": "Twelve jellies, each 18 centimeters (cm) long, were overlapped the same amount to form a round ring. If its circumference is 210 centimeters (cm), how many millimeters (mm) is the overlapping portion of jelly?",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "18 12 [OP_MUL] 210 [OP_SUB] 10 [OP_MUL]",
        "solution_abst_en": "18 12 [OP_MUL] 210 [OP_SUB] 10 [OP_MUL]",
        "solution_code_ko": "var_a = 18\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 210\nvar_e = var_c - var_d\nvar_f = 10\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 18\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 210\nvar_e = var_c - var_d\nvar_f = 10\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "5784": {
        "category": "Correspondence",
        "question_ko": "바둑알의 개수를 7로 나눈 뒤 40을 더하여 5를 곱한 수가 555이다. 이 중, 검은 바둑돌이 55개이면 흰 바둑돌의 개수는 얼마인가?",
        "question_en": "Divide the number of go stones by 7, add 40 and multiply by 5 to get 555. Of these, if there are 55 black go stones, how many white go stones?",
        "answer_ko": "442",
        "answer_en": "442",
        "solution_abst_ko": "555 5 [OP_DIV] 40 [OP_SUB] 7 [OP_MUL] 55 [OP_SUB]",
        "solution_abst_en": "555 5 [OP_DIV] 40 [OP_SUB] 7 [OP_MUL] 55 [OP_SUB]",
        "solution_code_ko": "var_a = 555\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 40\nvar_e = var_c - var_d\nvar_f = 7\nvar_g = var_e * var_f\nvar_h = 55\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 555\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 40\nvar_e = var_c - var_d\nvar_f = 7\nvar_g = var_e * var_f\nvar_h = 55\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "5785": {
        "category": "Correspondence",
        "question_ko": "세 자리 수 2AB는 2와 3으로 나누어 떨어진다. 가능한 A는 모두 몇 가지입니까?",
        "question_en": "A three-digit number 2AB is divisible by both 2 and 3. How many possible A's are there?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "2AB [OP_GEN_POSSIBLE_LIST] 2 3 [OP_LCM] [OP_LIST_DIVISIBLE] 2AB A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_abst_en": "2AB [OP_GEN_POSSIBLE_LIST] 2 3 [OP_LCM] [OP_LIST_DIVISIBLE] 2AB A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '2AB'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 2\nvar_c = 3\nvar_d = var_c * var_b / math.gcd(int(var_c), int(var_b))\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = '2AB'\nvar_f = 'A'\nvar_e = str(var_e)\nvar_f = str(var_f)\nunk_idx = var_e.index(var_f)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nvar_g = len(list_c)\nprint(int(var_g))",
        "solution_code_en": "var_a = '2AB'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 2\nvar_c = 3\nvar_d = var_c * var_b / math.gcd(int(var_c), int(var_b))\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = '2AB'\nvar_f = 'A'\nvar_e = str(var_e)\nvar_f = str(var_f)\nunk_idx = var_e.index(var_f)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nvar_g = len(list_c)\nprint(int(var_g))"
    },
    "5786": {
        "category": "Comparison",
        "question_ko": "오늘 운동을 예슬이는 13/10시간, 영준이는 22/15시간 동안 하였습니다. 예슬이와 영준이 중에서 운동을 더 오랫동안 한 사람은 누구입니까?",
        "question_en": "Yeseul exercised 13/10 hours today, and Youngjun did 22/15 hours. Among Yeseul and Youngjun, who exercised longer?",
        "answer_ko": "영준",
        "answer_en": "Youngjun",
        "solution_abst_ko": "[OP_LIST_SOL] 예슬 영준 [OP_LIST_EOL] [OP_LIST_SOL] 13/10 22/15 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yeseul Youngjun [OP_LIST_EOL] [OP_LIST_SOL] 13/10 22/15 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '예슬'\nvar_b = '영준'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.3\nvar_d = 1.4666666666666666\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Yeseul'\nvar_b = 'Youngjun'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.3\nvar_d = 1.4666666666666666\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "5787": {
        "category": "Arithmetic calculation",
        "question_ko": "10미터(m)간격으로 100미터(m)도로 양쪽에 처음부터 끝까지 나무를 심으려고 할때 몇 그루의 나무가 필요합니까?",
        "question_en": "How many trees are needed to plant trees on both sides of a 100-meter (m) road at 10-meter (m) intervals from start to finish?",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "100 10 [OP_DIV] 1 [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "100 10 [OP_DIV] 1 [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 100\nvar_b = 10\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 100\nvar_b = 10\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "5788": {
        "category": "Geometry",
        "question_ko": "둘레가 52센티미터(㎝)인 정사각형이 있습니다. 이 정사각형의 넓이는 몇 제곱센티미터(㎠)일까요?",
        "question_en": "You have a square with a perimeter of 52 centimeters (cm). What is the area of this square in square centimeters (cm2)?",
        "answer_ko": "169",
        "answer_en": "169",
        "solution_abst_ko": "52 4 [OP_DIV] 2 [OP_POW]",
        "solution_abst_en": "52 4 [OP_DIV] 2 [OP_POW]",
        "solution_code_ko": "var_a = 52\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 52\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint(int(var_e))"
    },
    "5789": {
        "category": "Comparison",
        "question_ko": "영희의 몸무게는 55.6킬로그램(㎏)이고, 철수의 몸무게는 88.2킬로그램(㎏)입니다. 영희와 철수 중 더 가벼운 사람은 누구입니까?",
        "question_en": "Younghee's weight is 55.6 kilograms (kg), and Cheolsu's weight is 88.2 kilograms (kg). Who is lighter between Younghee and Cheolsu?",
        "answer_ko": "영희",
        "answer_en": "Younghee",
        "solution_abst_ko": "[OP_LIST_SOL] 영희 철수 [OP_LIST_EOL] [OP_LIST_SOL] 55.6 88.2 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Younghee Cheolsu [OP_LIST_EOL] [OP_LIST_SOL] 55.6 88.2 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '영희'\nvar_b = '철수'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 55.6\nvar_d = 88.2\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Younghee'\nvar_b = 'Cheolsu'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 55.6\nvar_d = 88.2\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "5790": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 10까지의 수 중 짝수는 몇 개인지 구하시오.",
        "question_en": "Find the number of even numbers from 1 to 10.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "1 10 [OP_LIST_EVEN] [OP_LIST_LEN]",
        "solution_abst_en": "1 10 [OP_LIST_EVEN] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 10\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = len(list_a)\nprint(int(var_c))",
        "solution_code_en": "var_a = 1\nvar_b = 10\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = len(list_a)\nprint(int(var_c))"
    },
    "5791": {
        "category": "Comparison",
        "question_ko": "창고에 똑같은 선반이 28개 있습니다. 각 선반은 6칸이고, 각 칸마다 꽂혀 있는 책의 수는 같습니다. 어느 선반의 한 칸에 19개의 책이 꽂혀 있습니다. 창고의 선반에 꽂혀 있는 책은 모두 몇 권입니까?",
        "question_en": "There are 28 identical shelves in the warehouse. Each shelf has 6 spaces with the same number of books in it. If 19 books are on one shelf, what is a total number of books on the shelf in the warehouse?",
        "answer_ko": "3192",
        "answer_en": "3192",
        "solution_abst_ko": "28 6 [OP_MUL] 19 [OP_MUL]",
        "solution_abst_en": "28 6 [OP_MUL] 19 [OP_MUL]",
        "solution_code_ko": "var_a = 28\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 19\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 28\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 19\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "5792": {
        "category": "Possibility",
        "question_ko": "여학생 2명, 남학생 3명을 한 줄로 세울 때, 남학생끼리는 반드시 이웃하게 세우는 경우의 수를 구하시오.",
        "question_en": "When 2 female students and 3 male students are lined up in a line, find the number of cases in which the male students must be next to each other.",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "2 1 [OP_ADD] 2 1 [OP_ADD] [OP_PERM] 3 3 [OP_PERM] [OP_MUL]",
        "solution_abst_en": "2 1 [OP_ADD] 2 1 [OP_ADD] [OP_PERM] 3 3 [OP_PERM] [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = 1\nvar_c = int(var_c)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_c-i)\nvar_h = 3\nvar_i = 3\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nvar_k = var_g * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 2\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = 1\nvar_c = int(var_c)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_c-i)\nvar_h = 3\nvar_i = 3\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nvar_k = var_g * var_j\nprint(int(var_k))"
    },
    "5793": {
        "category": "Geometry",
        "question_ko": "길이가 25센티미터(㎝)인 색 테이프 15장을 0.5센티미터(㎝)씩 겹치게 이어 붙였습니다. 이은 색 테이프 전체의 길이는 몇 미터(m)입니까?",
        "question_en": "Fifteen sheets of colored tape, each 25 centimeters (cm) long, were joined together overlapping each other by 0.5 centimeters (cm). How many meters (m) is the total length of the attached color tape?",
        "answer_ko": "3.68",
        "answer_en": "3.68",
        "solution_abst_ko": "25 15 [OP_MUL] 0.5 15 1 [OP_SUB] [OP_MUL] [OP_SUB] 100 [OP_DIV]",
        "solution_abst_en": "25 15 [OP_MUL] 0.5 15 1 [OP_SUB] [OP_MUL] [OP_SUB] 100 [OP_DIV]",
        "solution_code_ko": "var_a = 25\nvar_b = 15\nvar_c = var_a * var_b\nvar_d = 0.5\nvar_e = 15\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_c - var_h\nvar_j = 100\nvar_k = var_i / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 25\nvar_b = 15\nvar_c = var_a * var_b\nvar_d = 0.5\nvar_e = 15\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_c - var_h\nvar_j = 100\nvar_k = var_i / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "5794": {
        "category": "Arithmetic calculation",
        "question_ko": "25, 41, 13, 32가 있습니다. 가장 큰 수와 가장 작은 수의 합을 구하시오.",
        "question_en": "There are 25, 41, 13, and 32. Find the sum of the largest and smallest numbers.",
        "answer_ko": "54",
        "answer_en": "54",
        "solution_abst_ko": "[OP_LIST_SOL] 25 41 13 32 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 25 41 13 32 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 25\nvar_b = 41\nvar_c = 13\nvar_d = 32\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 25\nvar_b = 41\nvar_c = 13\nvar_d = 32\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))"
    },
    "5795": {
        "category": "Arithmetic calculation",
        "question_ko": "30미터(m) 짜리 빵에서 지민이가 150센티미터(㎝)를 먹고, 태형이가 1.65미터(m)를 먹었을 때, 남은 빵의 길이는 몇 미터(m)인가요?",
        "question_en": "If Jimin eats 150 centimeters (cm) and Taehyung eats 1.65 m (m) of the 30 m (m) bread, how many meters (m) are left over?",
        "answer_ko": "26.85",
        "answer_en": "26.85",
        "solution_abst_ko": "30 150 100 [OP_DIV] [OP_SUB] 1.65 [OP_SUB]",
        "solution_abst_en": "30 150 100 [OP_DIV] [OP_SUB] 1.65 [OP_SUB]",
        "solution_code_ko": "var_a = 30\nvar_b = 150\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nvar_f = 1.65\nvar_g = var_e - var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 30\nvar_b = 150\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nvar_f = 1.65\nvar_g = var_e - var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "5796": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 10을 곱해야 할 것을 잘못하여 더했더니 그 결과가 21입니다. 바르게 계산하면 얼마입니까?",
        "question_en": "If you mistakenly add 10 to a number that should be multiplied by 10, the result is 21. How much do you get when you calculate correctly?",
        "answer_ko": "110",
        "answer_en": "110",
        "solution_abst_ko": "21 10 [OP_SUB] 10 [OP_MUL]",
        "solution_abst_en": "21 10 [OP_SUB] 10 [OP_MUL]",
        "solution_code_ko": "var_a = 21\nvar_b = 10\nvar_c = var_a - var_b\nvar_d = 10\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 21\nvar_b = 10\nvar_c = var_a - var_b\nvar_d = 10\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "5797": {
        "category": "Correspondence",
        "question_ko": "윤기는 두 자리 수와 세 자리 수를 더하던 중, 윤기는 두 자리 수의 일의 자리 숫자 9를 6으로 잘못 보았고, 세 자리 수의 일의 자리 숫자와 백의 자리 숫자를 바꾸어 253이라고 잘못 보았습니다. 이때, 윤기가 구한 합이 299라고 하면, 두 자리 수는 무엇인가요?",
        "question_en": "While adding the two-digit and three-digit numbers, Yoongi mistook the two-digit number's units digit 9 for 6, and changed the units and hundreds digits of the three-digit number to make it 253. At this time, if the sum obtained by Yoongi is 299, what is the two-digit number?",
        "answer_ko": "49",
        "answer_en": "49",
        "solution_abst_ko": "299 253 [OP_SUB] 6 9 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "299 253 [OP_SUB] 6 9 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 299\nvar_b = 253\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 299\nvar_b = 253\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "5798": {
        "category": "Arithmetic calculation",
        "question_ko": "태훈이는 하루의 1/3은 잠을 자고 그 나머지의 3/4는 학교에서 시간을 보내고 그 나머지의 1/4는 피아노 학원을 갑나다. 태훈이가 하루 중 피아노 학원에서 보내는 시간을 구하시오.",
        "question_en": "Taehoon sleeps 1/3 of the day, spends the remaining 3/4 at school, and goes to the piano academy for the remaining 1/4. Find the amount of time Taehoon spends at the piano academy during the day.",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "24 1 1/3 [OP_SUB] [OP_MUL] 1 3/4 [OP_SUB] [OP_MUL] 1/4 [OP_MUL]",
        "solution_abst_en": "24 1 1/3 [OP_SUB] [OP_MUL] 1 3/4 [OP_SUB] [OP_MUL] 1/4 [OP_MUL]",
        "solution_code_ko": "var_a = 24\nvar_b = 1\nvar_c = 0.3333333333333333\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 1\nvar_g = 0.75\nvar_h = var_f - var_g\nvar_i = var_e * var_h\nvar_j = 0.25\nvar_k = var_i * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 24\nvar_b = 1\nvar_c = 0.3333333333333333\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 1\nvar_g = 0.75\nvar_h = var_f - var_g\nvar_i = var_e * var_h\nvar_j = 0.25\nvar_k = var_i * var_j\nprint(int(var_k))"
    },
    "5799": {
        "category": "Possibility",
        "question_ko": "0, 2, 9를 이용하여 만들 수 있는 세 자리 수는 총 몇 개인가? 같은 숫자를 여러 번 써도 된다.",
        "question_en": "How many three-digit numbers can be made using 0, 2, and 9? You can use the same number multiple times.",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "[OP_LIST_SOL] 0 2 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 2 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 2\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 0\nvar_b = 2\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "5800": {
        "category": "Comparison",
        "question_ko": "검사 결과, 세 사람의 평균 키는 143센티미터(㎝)이다. B와 C의 평균 키는 A의 키에 4.5센티미터(㎝)를 더한 값과 같다. B가 C보다 3센티미터(㎝)더 클 때, C의 키는 얼마인지 구하시오.",
        "question_en": "As a result of the examination, the average height of the three people is 143 centimeters (cm). The average height of B and C is equal to A's height plus 4.5 centimeters (cm). If B is 3 centimeters (cm) taller than C, what is the height of C?",
        "answer_ko": "143",
        "answer_en": "143",
        "solution_abst_ko": "143 3 [OP_MUL] 4.5 [OP_ADD] 3 [OP_DIV] 2 [OP_MUL] 3 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "143 3 [OP_MUL] 4.5 [OP_ADD] 3 [OP_DIV] 2 [OP_MUL] 3 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 143\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 4.5\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = 3\nvar_k = var_i - var_j\nvar_l = 2\nvar_m = var_k / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 143\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 4.5\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = 3\nvar_k = var_i - var_j\nvar_l = 2\nvar_m = var_k / var_l\nprint(int(var_m))"
    },
    "5801": {
        "category": "Possibility",
        "question_ko": "윤기네 반에서 이어달리기 시합을 준비하려고 합니다. 5명의 후보 중 3명을 선택해 달리는 순서를 정하는 방법은 모두 몇 가지입니까?",
        "question_en": "Yoongi's class is preparing for the relay race. How many ways are there to determine the running order of 3 out of 5 candidates?",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "5 3 [OP_PERM]",
        "solution_abst_en": "5 3 [OP_PERM]",
        "solution_code_ko": "var_a = 5\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))"
    },
    "5802": {
        "category": "Comparison",
        "question_ko": "트럭에 (가), (나) 2개의 상자를 실었습니다. (가) 상자는 (나) 상자보다 작습니다. 목적지에 도착하였더니, 두 상자 중 큰 상자가 분실되었다면 분실된 상자는 무엇입니까?",
        "question_en": "The truck is loaded with (a) and (b) two boxes. (a) box is smaller than (b) box. If you arrive at your destination and the larger of the two boxes is missing, what is the missing box?",
        "answer_ko": "(나)",
        "answer_en": "(b)",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) [OP_LIST_EOL] [OP_LIST_SOL] (가) (나) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (a) (b) [OP_LIST_EOL] [OP_LIST_SOL] (a) (b) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = '(가)'\nvar_d = '(나)'\nvar_e = '<'\nlist_b= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_f = 1\nvar_g = list_c[var_f-1]\nprint(var_g)",
        "solution_code_en": "var_a = '(a)'\nvar_b = '(b)'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = '(a)'\nvar_d = '(b)'\nvar_e = '<'\nlist_b= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_f = 1\nvar_g = list_c[var_f-1]\nprint(var_g)"
    },
    "5803": {
        "category": "Possibility",
        "question_ko": "5, 0, 8, 6, 2 중 서로 다른 3개의 숫자를 뽑아 세자리 수를 만들 때, 2번째로 큰 수와 3번째로 작은 수의 차는 몇인지 구하시오.",
        "question_en": "Find the difference between the 2nd largest number and the 3rd smallest number when selecting 3 different numbers from 5, 0, 8, 6, 2 to make a 3-digit number.",
        "answer_ko": "654",
        "answer_en": "654",
        "solution_abst_ko": "[OP_LIST_SOL] 5 0 8 6 2 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 5 0 8 6 2 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 5\nvar_b = 0\nvar_c = 8\nvar_d = 6\nvar_e = 2\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 5\nvar_b = 0\nvar_c = 8\nvar_d = 6\nvar_e = 2\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h - var_j\nprint(int(var_k))"
    },
    "5804": {
        "category": "Comparison",
        "question_ko": "두 수 A, B가 있습니다. A는 10개씩 3묶음과 낱개 7개인 수입니다. B는 40보다 1 작은 수입니다. 더 작은 수는 어느 것입니까?",
        "question_en": "There are two numbers A and B. A is 3 groups of 10 and 7 units. B is one less than 40. Which number is smaller?",
        "answer_ko": "A",
        "answer_en": "A",
        "solution_abst_ko": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 10 3 [OP_MUL] 7 [OP_ADD] 40 1 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 10 3 [OP_MUL] 7 [OP_ADD] 40 1 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10\nvar_d = 3\nvar_e = var_c * var_d\nvar_f = 7\nvar_g = var_e + var_f\nvar_h = 40\nvar_i = 1\nvar_j = var_h - var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[var_k-1]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10\nvar_d = 3\nvar_e = var_c * var_d\nvar_f = 7\nvar_g = var_e + var_f\nvar_h = 40\nvar_i = 1\nvar_j = var_h - var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[var_k-1]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "5805": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 7 사이의 홀수 중 가장 큰 수를 구하시오.",
        "question_en": "Find the largest odd number between 1 and 7.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "1 7 [OP_LIST_ODD] 1 [OP_LIST_MAX]",
        "solution_abst_en": "1 7 [OP_LIST_ODD] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1\nvar_b = 7\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[-var_c]\nprint(int(var_d))",
        "solution_code_en": "var_a = 1\nvar_b = 7\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[-var_c]\nprint(int(var_d))"
    },
    "5806": {
        "category": "Correspondence",
        "question_ko": "A는 520입니다. A는 C보다 204만큼 작습니다. C는 B보다 179만큼 큽니다. B를 구하시오.",
        "question_en": "A is 520. A is less than C by 204. C is greater than B by 179. Find out B.",
        "answer_ko": "545",
        "answer_en": "545",
        "solution_abst_ko": "520 204 [OP_ADD] 179 [OP_SUB]",
        "solution_abst_en": "520 204 [OP_ADD] 179 [OP_SUB]",
        "solution_code_ko": "var_a = 520\nvar_b = 204\nvar_c = var_a + var_b\nvar_d = 179\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 520\nvar_b = 204\nvar_c = var_a + var_b\nvar_d = 179\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "5807": {
        "category": "Possibility",
        "question_ko": "A, B, C, D, E 5명이 있을 때, 회장 1명, 부회장 1명, 총무 1명을 뽑는 경우의 수를 구하시오.",
        "question_en": "If there are 5 members A, B, C, D, and E, find the number of cases in which one president, one vice president, and one manager are selected.",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "5 1 1 [OP_ADD] 1 [OP_ADD] [OP_PERM]",
        "solution_abst_en": "5 1 1 [OP_ADD] 1 [OP_ADD] [OP_PERM]",
        "solution_code_ko": "var_a = 5\nvar_b = 1\nvar_c = 1\nvar_d = var_b + var_c\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = 1\nvar_a = int(var_a)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_a-i)\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 1\nvar_c = 1\nvar_d = var_b + var_c\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = 1\nvar_a = int(var_a)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_a-i)\nprint(int(var_g))"
    },
    "5808": {
        "category": "Possibility",
        "question_ko": "4, 8, 1, 2 중 3개를 사용하여 일의 자리 숫자가 2인 수들 중에 가장 큰 수는 무엇입니까?",
        "question_en": "Using 3 of 4, 8, 1, 2, what is the largest number with a ones digit of 2?",
        "answer_ko": "842",
        "answer_en": "842",
        "solution_abst_ko": "[OP_LIST_SOL] 4 8 1 2 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 2 [OP_LIST_SEARCH_FIXED_DIGIT] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 4 8 1 2 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 2 [OP_LIST_SEARCH_FIXED_DIGIT] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 4\nvar_b = 8\nvar_c = 1\nvar_d = 2\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nvar_g = 2\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nprint(int(var_i))",
        "solution_code_en": "var_a = 4\nvar_b = 8\nvar_c = 1\nvar_d = 2\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nvar_g = 2\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nprint(int(var_i))"
    },
    "5809": {
        "category": "Comparison",
        "question_ko": "영화관에 손님들이 일렬로 나열된 의자에 차례대로 앉았습니다. 맨 왼쪽에 앉은 손님과 맨 오른쪽에 앉은 손님 사이에 30 명이 의자에 앉아 있다면 손님들이 앉은 의자의 개수는 모두 몇 개 입니까?",
        "question_en": "At the cinema, guests were seated in rows. If there are 30 chairs between the guest sitting on the far left and the guest sitting on the far right, how many chairs are occupied with guests?",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "30 2 [OP_ADD]",
        "solution_abst_en": "30 2 [OP_ADD]",
        "solution_code_ko": "var_a = 30\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 30\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "5810": {
        "category": "Arithmetic calculation",
        "question_ko": "무게가 같은 9개의 추의 무게가 4.5킬로그램(㎏)입니다. 이 추 2개와 무게가 850그램(g)인 필통 몇 개를 양팔 저울의 한쪽에 올려놓고, 다른 쪽에는 무게가 1050그램(g)인 사전을 5권 올려놓았더니 수평을 이루었습니다. 올려놓은 필통은 몇 개입니까?",
        "question_en": "Nine weights of the same weight weigh a total of 4.5 kilograms (kg). Two of these weights and several pencil cases that weigh 850 grams (g) each were placed on one side of a pan balance scale, and five dictionaries that weigh 1050 grams (g) each were placed on the other side, and they were level. How many pencil cases are there?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "1050 5 [OP_MUL] 4.5 1000 [OP_MUL] 9 [OP_DIV] 2 [OP_MUL] [OP_SUB] 850 [OP_DIV]",
        "solution_abst_en": "1050 5 [OP_MUL] 4.5 1000 [OP_MUL] 9 [OP_DIV] 2 [OP_MUL] [OP_SUB] 850 [OP_DIV]",
        "solution_code_ko": "var_a = 1050\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 4.5\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = 9\nvar_h = var_f / var_g\nvar_i = 2\nvar_j = var_h * var_i\nvar_k = var_c - var_j\nvar_l = 850\nvar_m = var_k / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 1050\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 4.5\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = 9\nvar_h = var_f / var_g\nvar_i = 2\nvar_j = var_h * var_i\nvar_k = var_c - var_j\nvar_l = 850\nvar_m = var_k / var_l\nprint(int(var_m))"
    },
    "5811": {
        "category": "Arithmetic calculation",
        "question_ko": "39개의 연속된 홀수의 합이 1989입니다. 이 중 가장 큰 홀수를 쓰시오.",
        "question_en": "The sum of 39 consecutive odd numbers is 1989. Write the largest odd number among these.",
        "answer_ko": "89",
        "answer_en": "89",
        "solution_abst_ko": "1989 39 [OP_DIV] 39 2 [OP_FDIV] 2 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "1989 39 [OP_DIV] 39 2 [OP_FDIV] 2 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 1989\nvar_b = 39\nvar_c = var_a / var_b\nvar_d = 39\nvar_e = 2\nvar_f = var_d // var_e\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_c + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1989\nvar_b = 39\nvar_c = var_a / var_b\nvar_d = 39\nvar_e = 2\nvar_f = var_d // var_e\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_c + var_h\nprint(int(var_i))"
    },
    "5812": {
        "category": "Correspondence",
        "question_ko": "2개씩 포장되어있던 초콜릿을 4개씩 다시 포장하려한다. 8개의 포장된 초콜릿이 있다면 다시 포장했을때 몇 묶음이 나오는지 구하시오.",
        "question_en": "I'm going to repack the chocolate that was packaged two by four. If you have eight packaged chocolates, find how many bundles come out when repackaged.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "8 2 [OP_MUL] 4 [OP_DIV]",
        "solution_abst_en": "8 2 [OP_MUL] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 8\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "5813": {
        "category": "Arithmetic calculation",
        "question_ko": "태형이는 나무막대 21/11킬로그램(㎏)를 한 상자에 7/11킬로그램(㎏)씩 나누어 담고, 호석이는 나무막대 8/17킬로그램(㎏)를 한 상자에 2/17킬로그램(㎏)씩 나누어 담으려고 합니다. 태형이와 호석이가 각자 가지고 있는 나무막대를 남김없이 상자에 나누어 담으려면 상자는 모두 몇 개 필요합니까?",
        "question_en": "Taehyung divided 21/11 kilograms (kg) of wooden sticks in each box by 7/11 kilograms (kg), and Hoseok puts 8/17 kilograms (kg) of wooden sticks in each box by 2/17 kilograms (kg). If they are trying to distribute all wooden sticks into boxes without any remains, how many boxes will be needed?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "21/11 7/11 [OP_DIV] 1 [OP_CEIL] 8/17 2/17 [OP_DIV] 1 [OP_CEIL] [OP_ADD]",
        "solution_abst_en": "21/11 7/11 [OP_DIV] 1 [OP_CEIL] 8/17 2/17 [OP_DIV] 1 [OP_CEIL] [OP_ADD]",
        "solution_code_ko": "var_a = 1.9090909090909092\nvar_b = 0.6363636363636364\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nvar_f = 0.47058823529411764\nvar_g = 0.11764705882352941\nvar_h = var_f / var_g\nvar_i = 1\nvar_j=int(((var_h+9*10**(var_i-2))//(10**(var_i-1)))*10**(var_i-1))\n\nvar_k = var_e + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 1.9090909090909092\nvar_b = 0.6363636363636364\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nvar_f = 0.47058823529411764\nvar_g = 0.11764705882352941\nvar_h = var_f / var_g\nvar_i = 1\nvar_j=int(((var_h+9*10**(var_i-2))//(10**(var_i-1)))*10**(var_i-1))\n\nvar_k = var_e + var_j\nprint(int(var_k))"
    },
    "5814": {
        "category": "Arithmetic calculation",
        "question_ko": "민지는 매일 0.6 시간씩 집안 청소를 합니다. 민지가 3 주일 동안 집안 청소를 한 시간은 모두 몇 시간입니까?",
        "question_en": "Minji cleans the house for 0.6 hours every day. How many total hours did Minji spend cleaning the house in 3 weeks?",
        "answer_ko": "12.60",
        "answer_en": "12.6",
        "solution_abst_ko": "0.6 7 [OP_MUL] 3 [OP_MUL]",
        "solution_abst_en": "0.6 7 [OP_MUL] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 0.6\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.6\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "5815": {
        "category": "Arithmetic calculation",
        "question_ko": "유나가 같은 반 학생들을 대상으로 조사를 했을 때, 수학을 좋아한다고 말한 학생은 27명이었지만 국어를 좋아한다고 말한 학생은 28명이었습니다. 수학을 좋아한다고 했던 친구들 중 22명이 국어도 좋아한다고 말했을 때, 유나의 물음에 답한 학생은 모두 몇 명입니까?",
        "question_en": "When Yuna surveyed her classmates, 27 students said they liked math, but 28 students said they liked Korean. When 22 of the friends who said they liked math said they also liked Korean, how many students answered Yuna's question?",
        "answer_ko": "33",
        "answer_en": "33",
        "solution_abst_ko": "28 27 [OP_ADD] 22 [OP_SUB]",
        "solution_abst_en": "28 27 [OP_ADD] 22 [OP_SUB]",
        "solution_code_ko": "var_a = 28\nvar_b = 27\nvar_c = var_a + var_b\nvar_d = 22\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 28\nvar_b = 27\nvar_c = var_a + var_b\nvar_d = 22\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "5816": {
        "category": "Comparison",
        "question_ko": "5, 8, 4, 3, 7중 2번째로 작은 숫자는 무엇입니까?",
        "question_en": "What is the 2nd smallest of 5, 8, 4, 3, and 7?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 5 8 4 3 7 [OP_LIST_EOL] 2 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 5 8 4 3 7 [OP_LIST_EOL] 2 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 5\nvar_b = 8\nvar_c = 4\nvar_d = 3\nvar_e = 7\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 8\nvar_c = 4\nvar_d = 3\nvar_e = 7\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nprint(int(var_g))"
    },
    "5817": {
        "category": "Possibility",
        "question_ko": "100보다 크고 1000보다 작은 수 중 2와 3으로만 이루어진 수는 몇 개입니까?",
        "question_en": "How many numbers greater than 100 and less than 1000 consist of only numbers 2 and 3?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "[OP_LIST_SOL] 2 3 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 2 3 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = len(list_b)\nprint(int(var_d))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = len(list_b)\nprint(int(var_d))"
    },
    "5818": {
        "category": "Comparison",
        "question_ko": "3개의 숫자 5, 8, 4 중 가장 작은 수를 고르세요.",
        "question_en": "Choose the smallest of the three numbers 5, 8, and 4.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 5 8 4 [OP_LIST_EOL] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 5 8 4 [OP_LIST_EOL] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 5\nvar_b = 8\nvar_c = 4\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 8\nvar_c = 4\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nprint(int(var_e))"
    },
    "5819": {
        "category": "Correspondence",
        "question_ko": "서로 다른 두 수 A, B가 있습니다. 네 자리 수와 세 자리 수의 뺄셈식 2A32-BBB=1BBB에서 B-A의 값을 구하시오.",
        "question_en": "There are two different numbers A and B. Find the value of B-A from the 4-digit and 3-digit subtraction formula: 2A32-BBB=1BBB.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "2A32-BBB=1BBB B [OP_DIGIT_UNK_SOLVER] 2A32-BBB=1BBB A [OP_DIGIT_UNK_SOLVER] [OP_SUB]",
        "solution_abst_en": "2A32-BBB=1BBB B [OP_DIGIT_UNK_SOLVER] 2A32-BBB=1BBB A [OP_DIGIT_UNK_SOLVER] [OP_SUB]",
        "solution_code_ko": "var_a = '2A32-BBB=1BBB'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '2A32-BBB=1BBB'\nvar_e = 'A'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = '2A32-BBB=1BBB'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '2A32-BBB=1BBB'\nvar_e = 'A'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "5820": {
        "category": "Arithmetic calculation",
        "question_ko": "한 개에 1000원인 사과와 한 개에 2000원인 복숭아를 합하여 모두 15개를 사는 데 22000원을 썼다. 복숭아를 몇 개 샀는지 구하시오.",
        "question_en": "I spent 22,000 won on buying 15 apples that cost 1,000 won each and peaches that cost 2,000 won each. Find how many peaches were bought.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "22000 1000 15 [OP_MUL] [OP_SUB] 2000 1000 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "22000 1000 15 [OP_MUL] [OP_SUB] 2000 1000 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 22000\nvar_b = 1000\nvar_c = 15\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 2000\nvar_g = 1000\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 22000\nvar_b = 1000\nvar_c = 15\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 2000\nvar_g = 1000\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "5821": {
        "category": "Correspondence",
        "question_ko": "고장난 계산기가 있다. 이 계산기는 곱하기 버튼을 누르면 나누고, 나누기 버튼을 누르면 곱한다고 한다. 지우가 이 계산기가 고장난줄 모르고 어떤 수에 1.36을 곱하여 계산했을때 0.5가 나왔다고 한다. 지우가 원래 구하려던 답은 얼마입니까?",
        "question_en": "There is a broken calculator. This calculator divides when you press the multiply button, and multiplies when you press the divide button. Jiwoo didn't know that the calculator was broken, so he multiplied a number by 2, and he got 0.5 with the calculator. What is the answer Jiwoo was originally trying to find?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "0.5 2 [OP_MUL] 2 [OP_MUL]",
        "solution_abst_en": "0.5 2 [OP_MUL] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 0.5\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 0.5\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "5822": {
        "category": "Geometry",
        "question_ko": "윗변이 15센티미터(㎝), 아랫변이 9센티미터(㎝), 높이가 12센티미터(㎝)인 사다리꼴이 있습니다. 이 사다리꼴과 넓이가 같은 정사각형의 한 변의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "You have a trapezoid with an upper side of 15 centimeters (cm), a lower side of 9 centimeters (cm), and a height of 12 centimeters (cm). How many centimeters (cm) is the side of a square with the same area as the trapezoid?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "15 9 [OP_ADD] 12 [OP_MUL] 2 [OP_DIV] 1/2 [OP_POW]",
        "solution_abst_en": "15 9 [OP_ADD] 12 [OP_MUL] 2 [OP_DIV] 1/2 [OP_POW]",
        "solution_code_ko": "var_a = 15\nvar_b = 9\nvar_c = var_a + var_b\nvar_d = 12\nvar_e = var_c * var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 15\nvar_b = 9\nvar_c = var_a + var_b\nvar_d = 12\nvar_e = var_c * var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))"
    },
    "5823": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중에서 가장 작은 수와 그 다음으로 작은 수의 합은 얼마입니까?",
        "question_en": "There are three numbers 10, 11, and 12. What is the sum of the smallest number and the next smallest number?",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e + var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e + var_g\nprint(int(var_h))"
    },
    "5824": {
        "category": "Possibility",
        "question_ko": "숫자 카드 1, 7, 0 중 2 장을 한 번씩 사용하여 가장 큰 두 자리 수를 만들 때, 사용하지 않는 카드의 숫자는 무엇입니까?",
        "question_en": "When two of the number cards 1, 7, and 0 are used once to form the largest two-digit number, what is the unused number?",
        "answer_ko": "0",
        "answer_en": "0",
        "solution_abst_ko": "[OP_LIST_SOL] 1 7 0 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] [OP_LIST_POP] [OP_NUM2LIST] [OP_SET_DIFFERENCE] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] 1 7 0 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] [OP_LIST_POP] [OP_NUM2LIST] [OP_SET_DIFFERENCE] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 1\nvar_b = 7\nvar_c = 0\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nlist_d = []\nvar_f = int(var_f)\nwhile var_f//10 > 0:\n    list_d.append(var_f%10)\n    var_f = var_f//10\nlist_d.append(var_f%10)\nlist_d = list_d[::-1]\nlist_e = list(set(list_a) - set(list_d))\nvar_g = 1\nvar_h = list_e[var_g-1]\nprint(int(var_h))",
        "solution_code_en": "var_a = 1\nvar_b = 7\nvar_c = 0\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nlist_d = []\nvar_f = int(var_f)\nwhile var_f//10 > 0:\n    list_d.append(var_f%10)\n    var_f = var_f//10\nlist_d.append(var_f%10)\nlist_d = list_d[::-1]\nlist_e = list(set(list_a) - set(list_d))\nvar_g = 1\nvar_h = list_e[var_g-1]\nprint(int(var_h))"
    },
    "5825": {
        "category": "Possibility",
        "question_ko": "숫자 자석 586의 순서를 바꾸어가며 다른 세 자리 수를 만들 때, 가장 큰 수는 무엇입니까?",
        "question_en": "When reordering the number magnet 586 to create another three-digit number, what is the largest number that can be made?",
        "answer_ko": "865",
        "answer_en": "865",
        "solution_abst_ko": "586 [OP_NUM2LIST] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_abst_en": "586 [OP_NUM2LIST] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 586\nlist_a = []\nvar_a = int(var_a)\nwhile var_a//10 > 0:\n    list_a.append(var_a%10)\n    var_a = var_a//10\nlist_a.append(var_a%10)\nlist_a = list_a[::-1]\nvar_b = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_b))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_c = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_d = list_c[-var_c]\nprint(int(var_d))",
        "solution_code_en": "var_a = 586\nlist_a = []\nvar_a = int(var_a)\nwhile var_a//10 > 0:\n    list_a.append(var_a%10)\n    var_a = var_a//10\nlist_a.append(var_a%10)\nlist_a = list_a[::-1]\nvar_b = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_b))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_c = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_d = list_c[-var_c]\nprint(int(var_d))"
    },
    "5826": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 10, 11, 12, 13이 있습니다. 그 중에서 가장 작은 수와 2번째로 작은 수의 차는 얼마입니까?",
        "question_en": "There are four numbers 10, 11, 12, and 13. What is the difference between the smallest number and the second smallest number?",
        "answer_ko": "-1",
        "answer_en": "-1",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))"
    },
    "5827": {
        "category": "Arithmetic calculation",
        "question_ko": "경환이는 할머니 집에 가기 위해 전체 거리의 1/3은 버스를 탔고, 1/2는 지하철을 탔습니다. 남은 거리는 걸어갔다면, 경환이가 대중교통을 타고 간 거리는 전체 거리의 몇 배입니까?",
        "question_en": "To go to her grandmother's house, Kyunghwan took a bus for 1/3 of the distance and the subway for 1/2 of the distance. If the remaining distance was walked, how many times the total distance he traveled on public transportation?",
        "answer_ko": "0.83",
        "answer_en": "0.83",
        "solution_abst_ko": "1/3 1/2 [OP_ADD]",
        "solution_abst_en": "1/3 1/2 [OP_ADD]",
        "solution_code_ko": "var_a = 0.3333333333333333\nvar_b = 0.5\nvar_c = var_a + var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 0.3333333333333333\nvar_b = 0.5\nvar_c = var_a + var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "5828": {
        "category": "Correspondence",
        "question_ko": "한 자리 수 A, B, C가 있습니다. A47BC가 4, 5, 9로 나누어 떨어집니다. A에 들어갈 수 있는 숫자의 개수를 모두 구하시오.",
        "question_en": "There are single digits A, B, and C. A47BC is divided by 4, 5, and 9. Find all the number of numbers that can fit in A.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "A47BC [OP_GEN_POSSIBLE_LIST] 4 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] A47BC A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_abst_en": "A47BC [OP_GEN_POSSIBLE_LIST] 4 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] A47BC A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 'A47BC'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 4\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 5\nlist_c = []\nvar_c = int(var_c)\nfor i in list_b:\n    i = int(i)\n    if i % var_c == 0:\n        list_c.append(i)\nvar_d = 9\nlist_d = []\nvar_d = int(var_d)\nfor i in list_c:\n    i = int(i)\n    if i % var_d == 0:\n        list_d.append(i)\nvar_e = 'A47BC'\nvar_f = 'A'\nvar_e = str(var_e)\nvar_f = str(var_f)\nunk_idx = var_e.index(var_f)\nlist_e = []\nfor elem in list_d:\n    elem = str(elem)\n    list_e.append(int(elem[unk_idx]))\nlist_e = list(set(list_e))\nvar_g = len(list_e)\nprint(int(var_g))",
        "solution_code_en": "var_a = 'A47BC'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 4\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 5\nlist_c = []\nvar_c = int(var_c)\nfor i in list_b:\n    i = int(i)\n    if i % var_c == 0:\n        list_c.append(i)\nvar_d = 9\nlist_d = []\nvar_d = int(var_d)\nfor i in list_c:\n    i = int(i)\n    if i % var_d == 0:\n        list_d.append(i)\nvar_e = 'A47BC'\nvar_f = 'A'\nvar_e = str(var_e)\nvar_f = str(var_f)\nunk_idx = var_e.index(var_f)\nlist_e = []\nfor elem in list_d:\n    elem = str(elem)\n    list_e.append(int(elem[unk_idx]))\nlist_e = list(set(list_e))\nvar_g = len(list_e)\nprint(int(var_g))"
    },
    "5829": {
        "category": "Arithmetic calculation",
        "question_ko": "상헌이의 키는 1.56미터(m) 입니다. 치호는 상헌이보다 0.14미터(m) 작고 나라는 치호보다 0.27미터(m) 크다고 합니 다. 나라의 키는 몇 미터(m)입니까?",
        "question_en": "Sangheon is 1.56 meters (m) tall. Chiho is 0.14meters (m) shorter than Sangheon, and Nara is 0.27meters (m) taller than Chiho. How tall is Nara in meters (m)?",
        "answer_ko": "1.69",
        "answer_en": "1.69",
        "solution_abst_ko": "1.56 0.14 [OP_SUB] 0.27 [OP_ADD]",
        "solution_abst_en": "1.56 0.14 [OP_SUB] 0.27 [OP_ADD]",
        "solution_code_ko": "var_a = 1.56\nvar_b = 0.14\nvar_c = var_a - var_b\nvar_d = 0.27\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 1.56\nvar_b = 0.14\nvar_c = var_a - var_b\nvar_d = 0.27\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "5830": {
        "category": "Geometry",
        "question_ko": "정사각형 모양의 천에 단추를 빈틈없이 규칙적으로 달았습니다. 둘레에 있는 단추의 개수가 84개라면, 가장 바깥쪽의 한 변에 있는 단추의 개수는 몇 개인지 구하시오.",
        "question_en": "The square-shaped fabric was buttoned regularly without gaps. If the number of buttons on the perimeter is 84, how many buttons are on one outermost side?",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "84 4 [OP_SUB] 4 [OP_DIV] 2 [OP_ADD]",
        "solution_abst_en": "84 4 [OP_SUB] 4 [OP_DIV] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 84\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 84\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "5831": {
        "category": "Arithmetic calculation",
        "question_ko": "다섯 자리 수 중 8의 배수는 모두 몇 개 있습니까?",
        "question_en": "How many multiples of 8 are there in a five-digit number?",
        "answer_ko": "11250",
        "answer_en": "11250",
        "solution_abst_ko": "10000 99999 1 [OP_LIST_ARANGE] 8 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "10000 99999 1 [OP_LIST_ARANGE] 8 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 10000\nvar_b = 99999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 8\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 10000\nvar_b = 99999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 8\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "5832": {
        "category": "Comparison",
        "question_ko": "호석이는 앞에서 4번째에 서 있습니다. 윤기와 호석이 사이에 5명의 학생이 있다면, 윤기는 앞에서 몇 번째에 서 있습니까?",
        "question_en": "Hoseok is standing at the 4th from the front. Consider that there are 5 students between Yoongi and Hoseok, where is Yoongi at counting from the front?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "4 5 [OP_ADD] 1 [OP_ADD]",
        "solution_abst_en": "4 5 [OP_ADD] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 4\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "5833": {
        "category": "Geometry",
        "question_ko": "한 모서리가 12센티미터(㎝) 인 정육면체 모양의 상자에 크기가 일정한 정사각형 모양의 색종이를 겹치지 않게 54 장 붙였더니 빈틈없이 붙일 수 있었습니다. 이 색종이의 한 변은 몇 센티미터(㎝) 입니까?",
        "question_en": "In a cube-shaped box with one edge measuring 12 centimeters (cm), 54 pieces of colored paper in the shape of a square of a certain size were attached without overlapping and then there was no empty space. How many centimeters (cm) is one edge of this piece of colored paper?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "12 2 [OP_POW] 6 [OP_MUL] 54 [OP_DIV] 1/2 [OP_POW]",
        "solution_abst_en": "12 2 [OP_POW] 6 [OP_MUL] 54 [OP_DIV] 1/2 [OP_POW]",
        "solution_code_ko": "var_a = 12\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = var_c * var_d\nvar_f = 54\nvar_g = var_e / var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 12\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = var_c * var_d\nvar_f = 54\nvar_g = var_e / var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))"
    },
    "5834": {
        "category": "Geometry",
        "question_ko": "혜영이네 집 근처 산책로의 길이는 6킬로미터(㎞)입니다. 혜영이는 산책로의 시작점부터 절반 지점까지 걸어갔고, 혜영이의 동생은 시작점부터 혜영이가 걸어간 곳까지의 절반 지점까지 걸어갔을 때, 혜영이가 걸은 거리는 몇 킬로미터(㎞)인지 구하시오.",
        "question_en": "The length of the promenade near Hyeyoung's house is 6 kilometers (km). While Hyeyoung walked from the starting point to the halfway point of the trail, and Hyeyoung's younger brother walked from the starting point to the half of where Hyeyoung stopped, find how many kilometers (km) Hyeyoung walked.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "6 2 [OP_DIV]",
        "solution_abst_en": "6 2 [OP_DIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "5835": {
        "category": "Correspondence",
        "question_ko": "9와 어떤 자연수 사이에는 연속된 자연수가 6개 있습니다. 어떤 수는 9보다 클 때 어떤 수는 얼마입니까?",
        "question_en": "There are 6 consecutive natural numbers between 9 and a certain number. What is a certain number when it is greater than 9?",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "9 6 [OP_ADD] 1 [OP_ADD]",
        "solution_abst_en": "9 6 [OP_ADD] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 9\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "5836": {
        "category": "Correspondence",
        "question_ko": "10+AB=64일 때, A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "When 10+AB=64 is correct, what number should go in A?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "10+AB=64 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "10+AB=64 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '10+AB=64'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '10+AB=64'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "5837": {
        "category": "Arithmetic calculation",
        "question_ko": "운동장의 직선 주로의 한쪽에 3미터(m) 간격으로 깃발을 30개 꽂았습니다. 직선 주로의 총 길이를 구하시오. (단, 직선 주로의 처음과 끝에도 깃발을 꽂습니다.)",
        "question_en": "Thirty flags were planted every 3 meters (m) on the straight track of the playground. Find the total length of the straight track. (However, flags are also planted at the beginning and the end of straight tracks.)",
        "answer_ko": "87",
        "answer_en": "87",
        "solution_abst_ko": "3 30 1 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "3 30 1 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 30\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 3\nvar_b = 30\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nprint(int(var_e))"
    },
    "5838": {
        "category": "Geometry",
        "question_ko": "부피가 3375세제곱센티미터(㎤)인 정육면체의 한 모서리를 구하시오",
        "question_en": "Find the edge of a cube whose volume is 3375 cubic centimeters (cm3).",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "3375 1/3 [OP_POW]",
        "solution_abst_en": "3375 1/3 [OP_POW]",
        "solution_code_ko": "var_a = 3375\nvar_b = 0.3333333333333333\nvar_c = var_a ** var_b\nprint(int(eval('{:.2f}'.format(round(var_c+1e-10,2)))))",
        "solution_code_en": "var_a = 3375\nvar_b = 0.3333333333333333\nvar_c = var_a ** var_b\nprint(int(eval('{:.2f}'.format(round(var_c+1e-10,2)))))"
    },
    "5839": {
        "category": "Correspondence",
        "question_ko": "형준이가 실험을 하면서 비커에 있던 액체를 200밀리리터(㎖) 버리고 새로운 액체 1000밀리리터(㎖)를 받았다. 현재 비커에 담긴 용액이 2000밀리리터(㎖)일때 비커에 처음 담겨 있던 용액을 몇 밀리리터(㎖)인지 구하시오.",
        "question_en": "During the experiment, Hyungjun threw away 200 milliliters (ml) of the liquid from the beaker and added 1000 milliliters (ml) of the new liquid. If the current solution in the beaker is 2000 milliliters (ml), find the amount of the solution in milliliters (ml) that was initially contained in the beaker.",
        "answer_ko": "1200",
        "answer_en": "1200",
        "solution_abst_ko": "2000 1000 [OP_SUB] 200 [OP_ADD]",
        "solution_abst_en": "2000 1000 [OP_SUB] 200 [OP_ADD]",
        "solution_code_ko": "var_a = 2000\nvar_b = 1000\nvar_c = var_a - var_b\nvar_d = 200\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 2000\nvar_b = 1000\nvar_c = var_a - var_b\nvar_d = 200\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "5840": {
        "category": "Possibility",
        "question_ko": "V, W, X, Y, Z 5명을 한 줄로 세울 때, X를 제일 앞에, Y와 Z를 이웃하게 세우는 경우의 수를 구하시오.",
        "question_en": "When 5 people V, W, X, Y, and Z are lined up, find the number of ways to put X first and Y and Z next to each other.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "[OP_LIST_SOL] V W X Y Z [OP_LIST_EOL] [OP_LIST_SOL] X [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_SOL] Y [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] Y Z [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] V W X Y Z [OP_LIST_EOL] [OP_LIST_SOL] X [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_SOL] Y [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] Y Z [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL]",
        "solution_code_ko": "var_a = 'V'\nvar_b = 'W'\nvar_c = 'X'\nvar_d = 'Y'\nvar_e = 'Z'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 'X'\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_g = 'Y'\nlist_d= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_d.append(var_g)\nlist_d.reverse()\nlist_e = list(set(list_c) - set(list_d))\nvar_h = len(list_e)\nvar_i = len(list_e)\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nvar_k = 'Y'\nvar_l = 'Z'\nlist_f= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_f.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_f.append(var_k)\nlist_f.reverse()\nvar_m = len(list_f)\nvar_n = len(list_f)\nvar_o = 1\nvar_m = int(var_m)\nvar_n = int(var_n)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o * (var_m-i)\nvar_p = var_j * var_o\nprint(int(var_p))",
        "solution_code_en": "var_a = 'V'\nvar_b = 'W'\nvar_c = 'X'\nvar_d = 'Y'\nvar_e = 'Z'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 'X'\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_g = 'Y'\nlist_d= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_d.append(var_g)\nlist_d.reverse()\nlist_e = list(set(list_c) - set(list_d))\nvar_h = len(list_e)\nvar_i = len(list_e)\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nvar_k = 'Y'\nvar_l = 'Z'\nlist_f= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_f.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_f.append(var_k)\nlist_f.reverse()\nvar_m = len(list_f)\nvar_n = len(list_f)\nvar_o = 1\nvar_m = int(var_m)\nvar_n = int(var_n)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o * (var_m-i)\nvar_p = var_j * var_o\nprint(int(var_p))"
    },
    "5841": {
        "category": "Geometry",
        "question_ko": "정사각형 모양의 상자 바닥에 유리구슬을 빈틈없이 규칙적으로 채워 넣었습니다. 벽면에 접촉하여 놓인 구슬에 개수가 84개였다면, 한 벽면과 접촉한 구슬의 개수는 몇 개인지 구하시오.",
        "question_en": "The bottom of the square box is filled regularly with glass marbles. If the number of marbles placed in contact with the wall is 84, how many marbles are in contact with one wall?",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "84 4 [OP_SUB] 4 [OP_DIV] 2 [OP_ADD]",
        "solution_abst_en": "84 4 [OP_SUB] 4 [OP_DIV] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 84\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 84\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "5842": {
        "category": "Arithmetic calculation",
        "question_ko": "나무막대 9/16미터(m)의 무게가 1/9킬로그램(㎏) 입니다. 나무 막대 3미터(m)의 무게는 몇 킬로그램(㎏)인지 구하시오.",
        "question_en": "The 9/16 meters (m) of a wooden stick weighs 1/9 kilogram (kg). Find the weight of a 3 meters (m) wooden stick in kilograms (kg).",
        "answer_ko": "0.59",
        "answer_en": "0.59",
        "solution_abst_ko": "1/9 9/16 [OP_DIV] 3 [OP_MUL]",
        "solution_abst_en": "1/9 9/16 [OP_DIV] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 0.1111111111111111\nvar_b = 0.5625\nvar_c = var_a / var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.1111111111111111\nvar_b = 0.5625\nvar_c = var_a / var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "5843": {
        "category": "Arithmetic calculation",
        "question_ko": "지민, 석진, 민영, 태형 4명의 사람이 각각 6, 14, 9, 15송이의 꽃을 심었습니다. 이들 중 가장 꽃을 많이 심은 사람과 2번째로 적게 심은 사람의 심은 송이의 개수 차이는 얼마입니까?",
        "question_en": "Four people, Jimin, Seokjin, Minyoung, and Taehyung, planted 6, 14, 9, and 15 flowers, respectively. How many is different between the number of flowers planted by the person who planted the most flowers and the person who planted the second fewest?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 6 14 9 15 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 6 14 9 15 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 6\nvar_b = 14\nvar_c = 9\nvar_d = 15\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 6\nvar_b = 14\nvar_c = 9\nvar_d = 15\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))"
    },
    "5844": {
        "category": "Comparison",
        "question_ko": "세 수 A, B, C가 있습니다. A는 10에 2를 곱하고 9를 더한 값입니다. A는 B보다 16 큰 수입니다. B에 3을 곱한 값이 C입니다. 가장 큰 수에서 가장 작은 수를 뺀 값은 얼마입니까?",
        "question_en": "There are three numbers A, B and C. A is 10 multiplied by 2 plus 9. A is 16 greater than B. B multiplied by 3 is C. What is the largest minus the smallest number?",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "[OP_LIST_SOL] 10 2 [OP_MUL] 9 [OP_ADD] 10 2 [OP_MUL] 9 [OP_ADD] 16 [OP_SUB] 10 2 [OP_MUL] 9 [OP_ADD] 16 [OP_SUB] 3 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] 3 [OP_LIST_MAX] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 10 2 [OP_MUL] 9 [OP_ADD] 10 2 [OP_MUL] 9 [OP_ADD] 16 [OP_SUB] 10 2 [OP_MUL] 9 [OP_ADD] 16 [OP_SUB] 3 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] 3 [OP_LIST_MAX] [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = var_c + var_d\nvar_f = 10\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = 9\nvar_j = var_h + var_i\nvar_k = 16\nvar_l = var_j - var_k\nvar_m = 10\nvar_n = 2\nvar_o = var_m * var_n\nvar_p = 9\nvar_q = var_o + var_p\nvar_r = 16\nvar_s = var_q - var_r\nvar_t = 3\nvar_u = var_s * var_t\nlist_a= []\nif \"/\" in str(var_u):\n    var_u = eval(str(var_u))\nlist_a.append(var_u)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_a.append(var_l)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nlist_a.reverse()\nvar_v = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_w = list_b[-var_v]\nvar_x = 3\nlist_c=list_a.copy()\nlist_c.sort()\nvar_y = list_c[-var_x]\nvar_z = var_w - var_y\nprint(int(var_z))",
        "solution_code_en": "var_a = 10\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = var_c + var_d\nvar_f = 10\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = 9\nvar_j = var_h + var_i\nvar_k = 16\nvar_l = var_j - var_k\nvar_m = 10\nvar_n = 2\nvar_o = var_m * var_n\nvar_p = 9\nvar_q = var_o + var_p\nvar_r = 16\nvar_s = var_q - var_r\nvar_t = 3\nvar_u = var_s * var_t\nlist_a= []\nif \"/\" in str(var_u):\n    var_u = eval(str(var_u))\nlist_a.append(var_u)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_a.append(var_l)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nlist_a.reverse()\nvar_v = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_w = list_b[-var_v]\nvar_x = 3\nlist_c=list_a.copy()\nlist_c.sort()\nvar_y = list_c[-var_x]\nvar_z = var_w - var_y\nprint(int(var_z))"
    },
    "5845": {
        "category": "Possibility",
        "question_ko": "지안이와 신영이가 가위바위보를 두 번 했을 때, 신영이가 두 번 다 이기는 경우의 수를 구하시오. (단, 무승부도 나올 수 있다.)",
        "question_en": "When Ji An and Shin Young play rock-paper-scissors twice, find the number of cases in which Shin-Young wins both times. (However, a draw may also come out.)",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "3 3 [OP_MUL]",
        "solution_abst_en": "3 3 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "5846": {
        "category": "Correspondence",
        "question_ko": "5로 나누면 2가 되는 어떤 수가 있습니다. 이 수에서 6을 빼면 얼마입니까?",
        "question_en": "There is a number that equals 2 when divided by 5. What is the result of this number minus 6?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "5 2 [OP_MUL] 6 [OP_SUB]",
        "solution_abst_en": "5 2 [OP_MUL] 6 [OP_SUB]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "5847": {
        "category": "Correspondence",
        "question_ko": "어떤 수는 75보다 작지만 35의 두 배 값보다 큽니다. 70, 71, 75, 78 중에서 어떤 수를 구하시오.",
        "question_en": "A certain number is less than 75 but greater than twice 35. Which number is it among 70, 71, 75, and 78?",
        "answer_ko": "71",
        "answer_en": "71",
        "solution_abst_ko": "[OP_LIST_SOL] 70 71 75 78 [OP_LIST_EOL] 75 [OP_LIST_LESS] 35 2 [OP_MUL] [OP_LIST_MORE] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] 70 71 75 78 [OP_LIST_EOL] 75 [OP_LIST_LESS] 35 2 [OP_MUL] [OP_LIST_MORE] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 70\nvar_b = 71\nvar_c = 75\nvar_d = 78\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 75\nlist_b = []\nfor i in list_a:\n    if i < var_e:\n        list_b.append(i)\nvar_f = 35\nvar_g = 2\nvar_h = var_f * var_g\nlist_c = []\nfor i in list_b:\n    if i > var_h:\n        list_c.append(i)\nvar_i = 1\nvar_j = list_c[var_i-1]\nprint(int(var_j))",
        "solution_code_en": "var_a = 70\nvar_b = 71\nvar_c = 75\nvar_d = 78\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 75\nlist_b = []\nfor i in list_a:\n    if i < var_e:\n        list_b.append(i)\nvar_f = 35\nvar_g = 2\nvar_h = var_f * var_g\nlist_c = []\nfor i in list_b:\n    if i > var_h:\n        list_c.append(i)\nvar_i = 1\nvar_j = list_c[var_i-1]\nprint(int(var_j))"
    },
    "5848": {
        "category": "Arithmetic calculation",
        "question_ko": "13을 A로 나눴을 때 몫이 B, 나머지가 3이 였습니다. A와 B는 모두 자연수입니다. 이 때, 가능한 B 중 가장 작은 수는 무엇인가요?",
        "question_en": "When 13 is divided by A, the quotient is B and the remainder is 3. A and B are both natural numbers. What is the smallest number of possible Bs?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "1",
        "solution_abst_en": "1",
        "solution_code_ko": "var_a = 1\nprint(int(var_a))",
        "solution_code_en": "var_a = 1\nprint(int(var_a))"
    },
    "5849": {
        "category": "Possibility",
        "question_ko": "어떤 책이 413쪽까지 있다고 한다. 이 책에 쪽 수를 인쇄할 때 4는 몇 번 인쇄되는지 구하시오.",
        "question_en": "A book is said to have up to 413 pages. How many times will 4 be printed when page numbers are printed in this book?",
        "answer_ko": "95",
        "answer_en": "95",
        "solution_abst_ko": "1 413 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 4 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 413 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 4 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 413\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 4\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 413\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 4\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))"
    },
    "5850": {
        "category": "Geometry",
        "question_ko": "어떤 직사각형의 가로의 길이가 세로의 길이보다 2 센티미터(㎝)만큼 길고, 둘레의 길이가 16 센티미터(㎝)이다. 가로의 길이는 얼마인가?",
        "question_en": "The width of a rectangle is 2 centimeters (cm) longer than its length, and its perimeter is 16 centimeters (cm). What is length of the width?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "16 2 [OP_DIV] 2 [OP_SUB] 2 [OP_DIV] 2 [OP_ADD]",
        "solution_abst_en": "16 2 [OP_DIV] 2 [OP_SUB] 2 [OP_DIV] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 16\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 16\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "5851": {
        "category": "Comparison",
        "question_ko": "윤기는 4, 정국이는 6에서 3을 곱한 수를 모았고, 유나는 5를 모았습니다. 누가 가장 작은 수를 모았나요?",
        "question_en": "Yoongi collected 4, Jungkook collected 6 multiplied by 3, and Yuna collected 5. Who got the smallest number?",
        "answer_ko": "윤기",
        "answer_en": "Yoongi",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 유나 [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_MUL] 5 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook Yuna [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_MUL] 5 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nvar_c = '유나'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 6\nvar_f = 3\nvar_g = var_e * var_f\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nvar_c = 'Yuna'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 6\nvar_f = 3\nvar_g = var_e * var_f\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "5852": {
        "category": "Arithmetic calculation",
        "question_ko": "숫자 7.52, 12.23에 대한 합은 얼마인가요?",
        "question_en": "What is the sum of the numbers 7.52 and 12.23?",
        "answer_ko": "19.75",
        "answer_en": "19.75",
        "solution_abst_ko": "7.52 12.23 [OP_ADD]",
        "solution_abst_en": "7.52 12.23 [OP_ADD]",
        "solution_code_ko": "var_a = 7.52\nvar_b = 12.23\nvar_c = var_a + var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 7.52\nvar_b = 12.23\nvar_c = var_a + var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "5853": {
        "category": "Possibility",
        "question_ko": "0, 2, 4, 5, 8이 적힌 다섯 장의 종이 중 2장을 뽑아 100이하의 자연수를 만들 때, 총 몇 가지 경우가 가능한 지 구하시오.",
        "question_en": "How many possible ways are there to create a natural number less than or equal to 100 by selecting two out of five pieces of paper with the numbers 0, 2, 4, 5, and 8 written on them?",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "[OP_LIST_SOL] 0 2 4 5 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 100 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 2 4 5 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 100 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 2\nvar_c = 4\nvar_d = 5\nvar_e = 8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 100\nlist_c = []\nfor i in list_b:\n    if i <= var_g:\n        list_c.append(i)\nvar_h = len(list_c)\nprint(int(var_h))",
        "solution_code_en": "var_a = 0\nvar_b = 2\nvar_c = 4\nvar_d = 5\nvar_e = 8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 100\nlist_c = []\nfor i in list_b:\n    if i <= var_g:\n        list_c.append(i)\nvar_h = len(list_c)\nprint(int(var_h))"
    },
    "5854": {
        "category": "Possibility",
        "question_ko": "80보다 작은 수 중에서 9의 배수의 각 자릿수의 합의 합을 구하시오.",
        "question_en": "Find the total sum of each digit of numbers that are a multiple of 9, and less than 80.",
        "answer_ko": "72",
        "answer_en": "72",
        "solution_abst_ko": "1 80 1 [OP_SUB] 1 [OP_LIST_ARANGE] 9 [OP_LIST_DIVISIBLE] [OP_LIST2NUM] [OP_NUM2LIST] [OP_LIST_SUM]",
        "solution_abst_en": "1 80 1 [OP_SUB] 1 [OP_LIST_ARANGE] 9 [OP_LIST_DIVISIBLE] [OP_LIST2NUM] [OP_NUM2LIST] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 80\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nvar_f = 9\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nvar_g=\"\"\nfor i in list_b:\n    i = str(i)\n    var_g = var_g + i\nlist_c = []\nvar_g = int(var_g)\nwhile var_g//10 > 0:\n    list_c.append(var_g%10)\n    var_g = var_g//10\nlist_c.append(var_g%10)\nlist_c = list_c[::-1]\nlist_c = [float(i) for i in list_c]\nvar_h = sum(list_c)\nprint(int(var_h))",
        "solution_code_en": "var_a = 1\nvar_b = 80\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nvar_f = 9\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nvar_g=\"\"\nfor i in list_b:\n    i = str(i)\n    var_g = var_g + i\nlist_c = []\nvar_g = int(var_g)\nwhile var_g//10 > 0:\n    list_c.append(var_g%10)\n    var_g = var_g//10\nlist_c.append(var_g%10)\nlist_c = list_c[::-1]\nlist_c = [float(i) for i in list_c]\nvar_h = sum(list_c)\nprint(int(var_h))"
    },
    "5855": {
        "category": "Arithmetic calculation",
        "question_ko": "민규의 휴대 전화 영상 통화료는 10초당 30원입니다. 민규가 할머니와 2분 40초 동안 영상 통화를 했다면 영상 통화료는 얼마입니까?",
        "question_en": "Mingyu's mobile phone charges 30 won per ten seconds for a video call. If Mingyu made a video call with her grandmother for 2 minutes and 40 seconds, how much would it cost?",
        "answer_ko": "480",
        "answer_en": "480",
        "solution_abst_ko": "2 60 [OP_MUL] 40 [OP_ADD] 10 [OP_DIV] 30 [OP_MUL]",
        "solution_abst_en": "2 60 [OP_MUL] 40 [OP_ADD] 10 [OP_DIV] 30 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 40\nvar_e = var_c + var_d\nvar_f = 10\nvar_g = var_e / var_f\nvar_h = 30\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 2\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 40\nvar_e = var_c + var_d\nvar_f = 10\nvar_g = var_e / var_f\nvar_h = 30\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "5856": {
        "category": "Possibility",
        "question_ko": "버튼 1, 2, 3을 한 번씩 누른다고 할 때 순서를 다르게 누르는 방법은 모두 몇 가지입니까?",
        "question_en": "When you press buttons 1, 2, and 3 once, how many different ways can you press them in a different order?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 1 2 3 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 2 3 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 2\nvar_c = 3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 2\nvar_c = 3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "5857": {
        "category": "Correspondence",
        "question_ko": "17A7을 버림하여 십의 자리까지 나타내면 1710이 됩니다. A를 구하시오.",
        "question_en": "Rounding down 17A7 to the tens place gives 1710. Get A.",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "17A7 [OP_GEN_POSSIBLE_LIST] 1710 [OP_LIST_MORE_EQUAL] 1710 10 [OP_ADD] [OP_LIST_LESS] 17A7 A [OP_LIST_FIND_UNK]",
        "solution_abst_en": "17A7 [OP_GEN_POSSIBLE_LIST] 1710 [OP_LIST_MORE_EQUAL] 1710 10 [OP_ADD] [OP_LIST_LESS] 17A7 A [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = '17A7'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 1710\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 1710\nvar_d = 10\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = '17A7'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))",
        "solution_code_en": "var_a = '17A7'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 1710\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 1710\nvar_d = 10\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = '17A7'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))"
    },
    "5858": {
        "category": "Arithmetic calculation",
        "question_ko": "진희는 한 권에 220쪽이 되는 동화책을 일주일 동안 다 읽으려고 한다. 하루에 적어도 몇 쪽씩 읽어야 하는가?",
        "question_en": "Jinhee tries to read the entire 220-page children's book in a week. How many pages at least should she read a day?",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "220 7 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "220 7 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 220\nvar_b = 7\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))",
        "solution_code_en": "var_a = 220\nvar_b = 7\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))"
    },
    "5859": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 각각 8미터(m), 10미터(m)인 정사각형 모양의 공원이 있습니다. 두 공원의 넓이의 합을 구하시오.",
        "question_en": "There is a park in the shape of a square with sides measuring 8 meters (m) and 10 meters (m). Find the sum of the areas of the two parks.",
        "answer_ko": "164",
        "answer_en": "164",
        "solution_abst_ko": "8 2 [OP_POW] 10 2 [OP_POW] [OP_ADD]",
        "solution_abst_en": "8 2 [OP_POW] 10 2 [OP_POW] [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 10\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 8\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 10\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "5860": {
        "category": "Possibility",
        "question_ko": "0, 1, 3, 5 중에서 서로 다른 숫자 3개를 뽑아 세 자리 수를 만들려고 합니다. 만들 수 있는 수 중에서 가장 큰 수와 가장 작은 수의 합을 구하시오.",
        "question_en": "You want to create a three-digit number by drawing three different numbers from 0, 1, 3, and 5. Find the sum of the largest and smallest possible numbers.",
        "answer_ko": "634",
        "answer_en": "634",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 3 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 3 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 3\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 3\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))"
    },
    "5861": {
        "category": "Geometry",
        "question_ko": "길이가 50센티미터(㎝)인 끈으로 직사각형을 만들었습니다. 가로의 길이가 13센티미터(㎝)입니다. 세로의 길이는 얼마입니까?",
        "question_en": "A rectangle was made from a piece of string that was 50 centimeters (cm) long. The horizontal length is 13 centimeters (cm). What is the vertical length?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "50 2 [OP_DIV] 13 [OP_SUB]",
        "solution_abst_en": "50 2 [OP_DIV] 13 [OP_SUB]",
        "solution_code_ko": "var_a = 50\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 13\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 50\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 13\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "5862": {
        "category": "Arithmetic calculation",
        "question_ko": "동화책이 한 상자에 20권씩 들어 있습니다. 5상자에 들어 있는 동화책은 모두 몇 권입니까?",
        "question_en": "There are 20 children's books in a box. How many children's books are in the 5 boxes?",
        "answer_ko": "100",
        "answer_en": "100",
        "solution_abst_ko": "20 5 [OP_MUL]",
        "solution_abst_en": "20 5 [OP_MUL]",
        "solution_code_ko": "var_a = 20\nvar_b = 5\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 20\nvar_b = 5\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "5863": {
        "category": "Arithmetic calculation",
        "question_ko": "색종이 45장을 접은 후 다시 18장을 더 접었습니다. 접은 색종이는 모두 몇 장입니까?",
        "question_en": "After folding 45 sheets of colored paper, folded 18 more. How many sheets of colored paper are all folded?",
        "answer_ko": "63",
        "answer_en": "63",
        "solution_abst_ko": "45 18 [OP_ADD]",
        "solution_abst_en": "45 18 [OP_ADD]",
        "solution_code_ko": "var_a = 45\nvar_b = 18\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 45\nvar_b = 18\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "5864": {
        "category": "Arithmetic calculation",
        "question_ko": "두 자리 수끼리의 곱셈에서 곱하는 수의 십의 자리 숫자 2를 6으로 잘못 보고 계산한 값이 2496이 되었습니다. 바르게 계산한 값이 936일 때, 2개의 두 자리 수의 합을 구하시오.",
        "question_en": "In the multiplication of two-digit numbers, the number 2 in the tens digit of the number being multiplied was misinterpreted as 6, resulting in a calculated value of 2496. When the correctly calculated value is 936, find the sum of the two two-digit numbers.",
        "answer_ko": "63",
        "answer_en": "63",
        "solution_abst_ko": "[OP_LIST_SOL] 2496 936 [OP_SUB] 6 2 [OP_SUB] 10 [OP_MUL] [OP_DIV] 936 2496 936 [OP_SUB] 6 2 [OP_SUB] 10 [OP_MUL] [OP_DIV] [OP_DIV] [OP_LIST_EOL] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 2496 936 [OP_SUB] 6 2 [OP_SUB] 10 [OP_MUL] [OP_DIV] 936 2496 936 [OP_SUB] 6 2 [OP_SUB] 10 [OP_MUL] [OP_DIV] [OP_DIV] [OP_LIST_EOL] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 2496\nvar_b = 936\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = 10\nvar_h = var_f * var_g\nvar_i = var_c / var_h\nvar_j = 936\nvar_k = 2496\nvar_l = 936\nvar_m = var_k - var_l\nvar_n = 6\nvar_o = 2\nvar_p = var_n - var_o\nvar_q = 10\nvar_r = var_p * var_q\nvar_s = var_m / var_r\nvar_t = var_j / var_s\nlist_a= []\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_a.append(var_t)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_u = sum(list_a)\nprint(int(var_u))",
        "solution_code_en": "var_a = 2496\nvar_b = 936\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = 10\nvar_h = var_f * var_g\nvar_i = var_c / var_h\nvar_j = 936\nvar_k = 2496\nvar_l = 936\nvar_m = var_k - var_l\nvar_n = 6\nvar_o = 2\nvar_p = var_n - var_o\nvar_q = 10\nvar_r = var_p * var_q\nvar_s = var_m / var_r\nvar_t = var_j / var_s\nlist_a= []\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_a.append(var_t)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_u = sum(list_a)\nprint(int(var_u))"
    },
    "5865": {
        "category": "Geometry",
        "question_ko": "정사각형 모양의 색종이 54장으로 한 모서리가 12센티미터(㎝)인 정육면체의 면을 빈틈없이 덮을 수 있습니다. 이 색종이의 한 변의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "There are 54 square-shaped pieces of colored paper that can cover the face of a cube with edges measuring 12 centimeters (cm) without gaps. How many centimeters (cm) is one side of this sheet of paper?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "12 2 [OP_POW] 6 [OP_MUL] 54 [OP_DIV] 1/2 [OP_POW]",
        "solution_abst_en": "12 2 [OP_POW] 6 [OP_MUL] 54 [OP_DIV] 1/2 [OP_POW]",
        "solution_code_ko": "var_a = 12\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = var_c * var_d\nvar_f = 54\nvar_g = var_e / var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 12\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = var_c * var_d\nvar_f = 54\nvar_g = var_e / var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))"
    },
    "5866": {
        "category": "Geometry",
        "question_ko": "팔을 양쪽으로 쭉 벌렸을 때의 길이가 1미터(m) 70센티미터(㎝)인 남성이 5명 있습니다. 이 남성들이 직사각형 모양의 수영장의 긴 쪽 벽면을 따라 팔을 벌리고 손끝이 이어지도록 나란히 섰을 때 수영장의 벽면보다 80센티미터(㎝)가 짧았다면, 수영장의 긴 쪽 벽면의 길이는 몇 미터(m)입니까?",
        "question_en": "There are 5 men whose arms are 1 meter (m) 70 centimeters (cm) when they are stretched out to the sides. If these men stand side by side with their arms extended and their fingertips connected along the long side of a rectangular swimming pool, and it is 80 centimeters (cm) shorter than the pool wall, how long is the longer side of the pool, in meters (m)?",
        "answer_ko": "9.3",
        "answer_en": "9.3",
        "solution_abst_ko": "1 100 [OP_MUL] 70 [OP_ADD] 5 [OP_MUL] 80 [OP_ADD] 100 [OP_DIV]",
        "solution_abst_en": "1 100 [OP_MUL] 70 [OP_ADD] 5 [OP_MUL] 80 [OP_ADD] 100 [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 70\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = var_e * var_f\nvar_h = 80\nvar_i = var_g + var_h\nvar_j = 100\nvar_k = var_i / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 70\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = var_e * var_f\nvar_h = 80\nvar_i = var_g + var_h\nvar_j = 100\nvar_k = var_i / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "5867": {
        "category": "Comparison",
        "question_ko": "두 자리 수끼리의 곱셈에서 바르게 계산한 값이 912입니다. 이때 곱하는 수의 십의 자리 숫자 2를 6으로 잘못 보고 계산한 값은 2432입니다. 2개의 두 자리 수 중 더 작은 수를 쓰시오.",
        "question_en": "912 is the value calculated correctly from multiplication of two digits. The calculated value is 2432 when the number 2 in the tens place of the multiplication number is incorrectly calculated as 6. Write the smaller one of the two two digit numbers.",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "[OP_LIST_SOL] 2432 912 [OP_SUB] 6 2 [OP_SUB] 10 [OP_MUL] [OP_DIV] 912 2432 912 [OP_SUB] 6 2 [OP_SUB] 10 [OP_MUL] [OP_DIV] [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 2432 912 [OP_SUB] 6 2 [OP_SUB] 10 [OP_MUL] [OP_DIV] 912 2432 912 [OP_SUB] 6 2 [OP_SUB] 10 [OP_MUL] [OP_DIV] [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 2432\nvar_b = 912\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = 10\nvar_h = var_f * var_g\nvar_i = var_c / var_h\nvar_j = 912\nvar_k = 2432\nvar_l = 912\nvar_m = var_k - var_l\nvar_n = 6\nvar_o = 2\nvar_p = var_n - var_o\nvar_q = 10\nvar_r = var_p * var_q\nvar_s = var_m / var_r\nvar_t = var_j / var_s\nlist_a= []\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_a.append(var_t)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nlist_a.reverse()\nvar_u = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_v = list_b[var_u-1]\nprint(int(var_v))",
        "solution_code_en": "var_a = 2432\nvar_b = 912\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = 10\nvar_h = var_f * var_g\nvar_i = var_c / var_h\nvar_j = 912\nvar_k = 2432\nvar_l = 912\nvar_m = var_k - var_l\nvar_n = 6\nvar_o = 2\nvar_p = var_n - var_o\nvar_q = 10\nvar_r = var_p * var_q\nvar_s = var_m / var_r\nvar_t = var_j / var_s\nlist_a= []\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_a.append(var_t)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nlist_a.reverse()\nvar_u = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_v = list_b[var_u-1]\nprint(int(var_v))"
    },
    "5868": {
        "category": "Arithmetic calculation",
        "question_ko": "한 봉지에 46개씩 넣은 사탕 봉지가 19개, 한 통에 170알씩 들어있는 해바라기 씨 통이 몇 개 있습니다. 사탕과 해바라기 씨의 개수를 모두 더했을 때 1894라는 숫자가 나왔다면, 해바라기 씨는 몇 통 있습니까?",
        "question_en": "There are 19 candy bags of 46 each, and several tins of sunflower seeds, each containing 170 seeds. If the number of candies and sunflower seeds added together gives the number 1894, how many tins of sunflower seeds are there?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "1894 46 19 [OP_MUL] [OP_SUB] 170 [OP_FDIV]",
        "solution_abst_en": "1894 46 19 [OP_MUL] [OP_SUB] 170 [OP_FDIV]",
        "solution_code_ko": "var_a = 1894\nvar_b = 46\nvar_c = 19\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 170\nvar_g = var_e // var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1894\nvar_b = 46\nvar_c = 19\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 170\nvar_g = var_e // var_f\nprint(int(var_g))"
    },
    "5869": {
        "category": "Geometry",
        "question_ko": "십오각형에서 그을 수 있는 모든 대각선의 개수를 구하시오.",
        "question_en": "Find the number of diagonals that can be drawn from the pentadecagon.",
        "answer_ko": "90",
        "answer_en": "90",
        "solution_abst_ko": "15 15 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "15 15 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 15\nvar_b = 15\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 15\nvar_b = 15\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "5870": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 5, 8, 2로 나누어 떨어질 수 있는 세 자리 수는 모두 몇 개 있습니까?",
        "question_en": "How many three-digit numbers are divisible by the both three numbers 5, 8, and 2?",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "100 999 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 2 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "100 999 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 2 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 8\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 2\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))",
        "solution_code_en": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 8\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 2\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))"
    },
    "5871": {
        "category": "Correspondence",
        "question_ko": "A는 1부터 9까지의 자연수입니다. 63×2>21×A일 때, A에 들어갈 수 있는 수를 모두 찾아 합을 구하시오.",
        "question_en": "A is a natural number from 1 to 9. When 63×2>21×A, find the sum of all the numbers that can fit in A.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "63×2>21×A A [OP_DIGIT_UNK_SOLVER] [OP_LIST_SUM]",
        "solution_abst_en": "63×2>21×A A [OP_DIGIT_UNK_SOLVER] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = '63×2>21×A'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nprint(int(var_c))",
        "solution_code_en": "var_a = '63×2>21×A'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nprint(int(var_c))"
    },
    "5872": {
        "category": "Arithmetic calculation",
        "question_ko": "동물원에 있는 아빠 판다의 몸무게는 145/4킬로그램(㎏)이고, 엄마 판다는 아빠 판다보다 47/10킬로그램(㎏) 더 가볍습니다. 엄마 판다의 몸무게는 몇 킬로그램(㎏)입니까?",
        "question_en": "The father panda in the zoo weighs 145/4 kilograms (kg), and the mother panda is 47/10 kilograms (kg) lighter than the father panda. How many kilograms (kg) does the mother panda weigh?",
        "answer_ko": "31.55",
        "answer_en": "31.55",
        "solution_abst_ko": "145/4 47/10 [OP_SUB]",
        "solution_abst_en": "145/4 47/10 [OP_SUB]",
        "solution_code_ko": "var_a = 36.25\nvar_b = 4.7\nvar_c = var_a - var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 36.25\nvar_b = 4.7\nvar_c = var_a - var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "5873": {
        "category": "Arithmetic calculation",
        "question_ko": "마트에서 사과 180개를 6개의 바구니에 똑같이 나누어 담아 팔려고 합니다. 사과를 한 개에 200원에 판다면, 한 바구니에 담은 사과는 얼마입니까?",
        "question_en": "You want to sell 180 apples in a mart divided equally into 6 baskets. If you sell apples for 200 won each, how much are the apples in a basket?",
        "answer_ko": "6000",
        "answer_en": "6000",
        "solution_abst_ko": "180 6 [OP_DIV] 200 [OP_MUL]",
        "solution_abst_en": "180 6 [OP_DIV] 200 [OP_MUL]",
        "solution_code_ko": "var_a = 180\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 200\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 180\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 200\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "5874": {
        "category": "Comparison",
        "question_ko": "어느 김밥 가게에서 기본 김밥은 2000원, 참치 김밥은 3500원, 고추 김밥은 3000원, 소고기 김밥은 4000원, 누드 김밥은 3500원일 때 3500원 이상인 김밥을 모두 두 개씩 샀다면 얼마를 내야 합니까?",
        "question_en": "At a Gimbap shop, basic Gimbap is 2,000 won, tuna Gimbap is 3,500 won, red pepper Gimbap is 3,000 won, beef Gimbap is 4,000 won, and nude Gimbap is 3,500 won. how much would you have to pay if you bought two gimbaps each that cost more than or equal to 3500 won?",
        "answer_ko": "22000",
        "answer_en": "22000",
        "solution_abst_ko": "[OP_LIST_SOL] 2000 3500 3000 4000 3500 [OP_LIST_EOL] 3500 [OP_LIST_MORE_EQUAL] [OP_LIST_SUM] 2 [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 2000 3500 3000 4000 3500 [OP_LIST_EOL] 3500 [OP_LIST_MORE_EQUAL] [OP_LIST_SUM] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 2000\nvar_b = 3500\nvar_c = 3000\nvar_d = 4000\nvar_e = 3500\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3500\nlist_b = []\nfor i in list_a:\n    if i >= var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 2000\nvar_b = 3500\nvar_c = 3000\nvar_d = 4000\nvar_e = 3500\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3500\nlist_b = []\nfor i in list_a:\n    if i >= var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "5875": {
        "category": "Arithmetic calculation",
        "question_ko": "정국의 몸무게는 54킬로그램(㎏)보다 154그램(g) 무겁습니다. 정국이의 몸무게를 그램(g)으로 써보시오",
        "question_en": "Jungkook's weight is 154 grams (g) heavier than 54 kilograms (kg). Write Jungkook's weight in grams (g).",
        "answer_ko": "54154",
        "answer_en": "54154",
        "solution_abst_ko": "54 1000 [OP_MUL] 154 [OP_ADD]",
        "solution_abst_en": "54 1000 [OP_MUL] 154 [OP_ADD]",
        "solution_code_ko": "var_a = 54\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 154\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 54\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 154\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "5876": {
        "category": "Arithmetic calculation",
        "question_ko": "3의 배수 중 가장 큰 두 자리 수는?",
        "question_en": "What is the greatest two-digit multiple of 3?",
        "answer_ko": "99",
        "answer_en": "99",
        "solution_abst_ko": "10 99 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_abst_en": "10 99 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))",
        "solution_code_en": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))"
    },
    "5877": {
        "category": "Comparison",
        "question_ko": "석진이는 마트에서 15번째 줄에 서있고, 남준이는 석진이보다 6명 앞에 있습니다. 남준이는 몇 번째에 서 있습니까?",
        "question_en": "Seokjin is 15th in line at the mart, and Namjoon is 6 people ahead of Seokjin. What number is Namjoon on?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "15 6 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "15 6 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 15\nvar_b = 6\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 6\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "5878": {
        "category": "Possibility",
        "question_ko": "숫자 카드 1, 4, 9, 5를 한 번씩 모두 사용하여 합이 가장 큰 값을 구하시오.",
        "question_en": "Use the number cards 1, 4, 9, and 5 once each to form the biggest number.",
        "answer_ko": "9541",
        "answer_en": "9541",
        "solution_abst_ko": "[OP_LIST_SOL] 1 4 9 5 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1 4 9 5 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1\nvar_b = 4\nvar_c = 9\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 4\nvar_c = 9\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint(int(var_g))"
    },
    "5879": {
        "category": "Arithmetic calculation",
        "question_ko": "같은 모양의 찬장을 8개 샀습니다. 이 찬장은 5칸으로 되어있고 각 칸마다 85개의 찻잔을 놓을 수 있습니다. 새로 산 찬장에 놓을 수 있는 찻잔은 모두 몇 잔입니까?",
        "question_en": "I bought 8 cupboards of the same shape. This cupboard has 5 compartments and each compartment can hold 85 tea cups. How many teacups can I put in my new cupboard?",
        "answer_ko": "3400",
        "answer_en": "3400",
        "solution_abst_ko": "8 5 [OP_MUL] 85 [OP_MUL]",
        "solution_abst_en": "8 5 [OP_MUL] 85 [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 85\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 85\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "5880": {
        "category": "Arithmetic calculation",
        "question_ko": "0부터 9까지의 숫자 카드로 1부터 300까지의 수를 만드려고 합니다. 숫자 카드 3은 모두 몇 장 필요한지 구하시오.",
        "question_en": "I am trying to create numbers from 1 to 300 with number cards from 0 to 9. How many number card 3 are needed in all?",
        "answer_ko": "61",
        "answer_en": "61",
        "solution_abst_ko": "1 300 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 3 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 300 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 3 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 300\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 3\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 300\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 3\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))"
    },
    "5881": {
        "category": "Arithmetic calculation",
        "question_ko": "감의 총 무게는 3킬로그램(㎏)이다. 감 5개의 무게가 1킬로그램(㎏)이라면 감은 모두 몇 개 있는가?",
        "question_en": "The total weight of persimmon is 3 kg (kg). If the weight of 5 persimmons is 1 kg, how many persimmons are there in all?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "5 1 [OP_MUL] 3 [OP_MUL]",
        "solution_abst_en": "5 1 [OP_MUL] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 1\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 1\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "5882": {
        "category": "Comparison",
        "question_ko": "학교에서 국어 시험을 본 결과 태형, 민주, 상민, 윤정, 유정 순서로 점수가 높았습니다. 가장 높은 점수를 받은 사람은 누구입니까?",
        "question_en": "As a result of the Korean test at school, Taehyung, Minju, Sangmin, Yoonjung, and Yoojung scored higher in the order of name. Who has the highest score?",
        "answer_ko": "태형",
        "answer_en": "Taehyung",
        "solution_abst_ko": "[OP_LIST_SOL] 태형 민주 상민 윤정 유정 [OP_LIST_EOL] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Taehyung Minju Sangmin Yoonjung Yoojung [OP_LIST_EOL] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '태형'\nvar_b = '민주'\nvar_c = '상민'\nvar_d = '윤정'\nvar_e = '유정'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nvar_g = list_a[var_f-1]\nprint(var_g)",
        "solution_code_en": "var_a = 'Taehyung'\nvar_b = 'Minju'\nvar_c = 'Sangmin'\nvar_d = 'Yoonjung'\nvar_e = 'Yoojung'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nvar_g = list_a[var_f-1]\nprint(var_g)"
    },
    "5883": {
        "category": "Correspondence",
        "question_ko": "식 3A+B82=216이 있습니다. B에 들어가야 하는 숫자를 구하시오",
        "question_en": "We have the expression 3A+B82=216. Find the number that goes into B",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "3A+B82=216 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "3A+B82=216 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '3A+B82=216'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '3A+B82=216'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "5884": {
        "category": "Arithmetic calculation",
        "question_ko": "7, 1, 3, 2, 4, 9, 5가 있습니다. 그중에서 2와 6 사이에 있는 수는 모두 몇 개입니까?",
        "question_en": "There are 7, 1, 3, 2, 4, 9 and 5. How many of them are between 2 and 6?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 7 1 3 2 4 9 5 [OP_LIST_EOL] 2 [OP_LIST_MORE_EQUAL] 6 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 7 1 3 2 4 9 5 [OP_LIST_EOL] 2 [OP_LIST_MORE_EQUAL] 6 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 7\nvar_b = 1\nvar_c = 3\nvar_d = 2\nvar_e = 4\nvar_f = 9\nvar_g = 5\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h = 2\nlist_b = []\nfor i in list_a:\n    if i >= var_h:\n        list_b.append(i)\nvar_i = 6\nlist_c = []\nfor i in list_b:\n    if i <= var_i:\n        list_c.append(i)\nvar_j = len(list_c)\nprint(int(var_j))",
        "solution_code_en": "var_a = 7\nvar_b = 1\nvar_c = 3\nvar_d = 2\nvar_e = 4\nvar_f = 9\nvar_g = 5\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h = 2\nlist_b = []\nfor i in list_a:\n    if i >= var_h:\n        list_b.append(i)\nvar_i = 6\nlist_c = []\nfor i in list_b:\n    if i <= var_i:\n        list_c.append(i)\nvar_j = len(list_c)\nprint(int(var_j))"
    },
    "5885": {
        "category": "Comparison",
        "question_ko": "1개의 무게가 200그램(g)인 귤을 30개씩 담은 상자가 5개 있습니다. 1개의 무게가 450그램(g)인 사과를 20개씩 담은 상자는 3개 있습니다. 또 1개의 무게가 800그램(g)인 배를 15개씩 담은 상자는 4개 있습니다. 개수가 가장 많은 과일은 무엇입니까?",
        "question_en": "There are 5 boxes of 30 tangerines, each weighing 200 grams (g). There are 3 boxes of 20 apples, each weighing 450 grams (g). In addition, there are 4 boxes containing 15 pears, each weighing 800 grams (g). Which fruit has the highest frequency?",
        "answer_ko": "귤",
        "answer_en": "tangerines",
        "solution_abst_ko": "[OP_LIST_SOL] 귤 사과 배 [OP_LIST_EOL] [OP_LIST_SOL] 30 5 [OP_MUL] 20 3 [OP_MUL] 15 4 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] tangerines apples pears [OP_LIST_EOL] [OP_LIST_SOL] 30 5 [OP_MUL] 20 3 [OP_MUL] 15 4 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '귤'\nvar_b = '사과'\nvar_c = '배'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 30\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = 20\nvar_h = 3\nvar_i = var_g * var_h\nvar_j = 15\nvar_k = 4\nvar_l = var_j * var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'tangerines'\nvar_b = 'apples'\nvar_c = 'pears'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 30\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = 20\nvar_h = 3\nvar_i = var_g * var_h\nvar_j = 15\nvar_k = 4\nvar_l = var_j * var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "5886": {
        "category": "Comparison",
        "question_ko": "윤기가 가진 사과가 4개, 정국이는 6개의 사과의 사과를 가지고 있었지만 3개를 먹었습니다. 누가 더 많은 사과를 가지고 있나요?",
        "question_en": "Yoongi had 4 apples and Jungkook had 6 apples, but he ate 3 of them. Who has more apples?",
        "answer_ko": "윤기",
        "answer_en": "Yoongi",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 6\nvar_e = 3\nvar_f = var_d - var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 6\nvar_e = 3\nvar_f = var_d - var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "5887": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 50까지의 수 중 홀수의 합을 구하시오.",
        "question_en": "Find the sum of odd numbers from 1 to 50.",
        "answer_ko": "625",
        "answer_en": "625",
        "solution_abst_ko": "1 50 [OP_LIST_ODD] [OP_LIST_SUM]",
        "solution_abst_en": "1 50 [OP_LIST_ODD] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 50\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nprint(int(var_c))",
        "solution_code_en": "var_a = 1\nvar_b = 50\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nprint(int(var_c))"
    },
    "5888": {
        "category": "Arithmetic calculation",
        "question_ko": "빨간색 공 60개와 파란색 공 30개가 있습니다. 빨간색 공은 파란색 공과 흰색 공을 합한 것보다 5개 더 많습니다. 흰색 공은 몇 개입니까?",
        "question_en": "There are 60 red balls and 30 blue balls. If there are 5 more number of red balls than the number of blue and white balls combined. How many white balls are there?",
        "answer_ko": "25",
        "answer_en": "25",
        "solution_abst_ko": "60 30 [OP_SUB] 5 [OP_SUB]",
        "solution_abst_en": "60 30 [OP_SUB] 5 [OP_SUB]",
        "solution_code_ko": "var_a = 60\nvar_b = 30\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 60\nvar_b = 30\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "5889": {
        "category": "Geometry",
        "question_ko": "둘레의 길이가 32센티미터(㎝)인 정사각형을 밑면과 옆면으로 갖는 사각기둥의 부피를 구하시오.",
        "question_en": "Find the volume of a quadrangular prism whose base and sides are squares with a perimeter of 32 centimeters (cm).",
        "answer_ko": "512",
        "answer_en": "512",
        "solution_abst_ko": "32 4 [OP_DIV] 3 [OP_POW]",
        "solution_abst_en": "32 4 [OP_DIV] 3 [OP_POW]",
        "solution_code_ko": "var_a = 32\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 3\nvar_e = var_c ** var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 32\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 3\nvar_e = var_c ** var_d\nprint(int(var_e))"
    },
    "5890": {
        "category": "Arithmetic calculation",
        "question_ko": "한별이와 한솔이의 몸무게의 합은 88킬로그램(㎏)입니다. 한별이가 한솔이보다 4킬로그램(㎏) 더 무겁다면 한솔이의 몸무게는 몇 킬로그램(㎏)입니까?",
        "question_en": "The total weight of Hanbyul and Hansol is 88 kg (kg). If Hanbyul is 4 kilograms (kg) heavier than Hansol, how many kilograms (kg) does Hansol weigh?",
        "answer_ko": "42",
        "answer_en": "42",
        "solution_abst_ko": "88 4 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "88 4 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 88\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 88\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "5891": {
        "category": "Geometry",
        "question_ko": "정십각형의 내각의 크기의 합을 내각의 개수로 나누면 얼마인지 구하라.",
        "question_en": "Find the sum of the interior angles of a regular decagon divided by the number of interior angles.",
        "answer_ko": "144",
        "answer_en": "144",
        "solution_abst_ko": "10 2 [OP_SUB] 180 [OP_MUL] 10 [OP_DIV]",
        "solution_abst_en": "10 2 [OP_SUB] 180 [OP_MUL] 10 [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 180\nvar_e = var_c * var_d\nvar_f = 10\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 10\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 180\nvar_e = var_c * var_d\nvar_f = 10\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "5892": {
        "category": "Arithmetic calculation",
        "question_ko": "호수길에 가로등이 50미터(m) 간격으로 세워져 있습니다. 호수길의 총 길이는 1650미터(m)이고, 다리의 처음과 끝에도 가로등이 세워져 있을 때, 호수길 양쪽에 세워진 가로등의 수는 모두 몇 개입니까?",
        "question_en": "Street lamps are erected at 50 meter (m) intervals along the both sides of lake road. If the total length of the lake road is 1650 meters (m) and there are street lamps at the beginning and end of the bridge, how many street lamps are there on both sides of the lake road?",
        "answer_ko": "68",
        "answer_en": "68",
        "solution_abst_ko": "1650 50 [OP_DIV] 1 [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "1650 50 [OP_DIV] 1 [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 1650\nvar_b = 50\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1650\nvar_b = 50\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "5893": {
        "category": "Possibility",
        "question_ko": "숫자 카드 1, 6, 3, 9를 한 번씩 모두 사용해서 가장 큰 수와 가장 작은 수의 합을 구하시오.",
        "question_en": "Use number cards 1, 6, 3, and 9 all and once to find the sum of the largest and smallest numbers that can be made.",
        "answer_ko": "11000",
        "answer_en": "11000",
        "solution_abst_ko": "[OP_LIST_SOL] 1 6 3 9 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 1 6 3 9 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 6\nvar_c = 3\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 1\nvar_b = 6\nvar_c = 3\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))"
    },
    "5894": {
        "category": "Correspondence",
        "question_ko": "어느 회사에 직원 수는 928명이다. 국내에서 근무하는 직원이 713명일 때, 해외에서 근무하는 직원은 국내에서 근무하는 직원보다 몇 명이 더 적은지 구하시오.",
        "question_en": "A company has 928 employees. If 713 employees of those are working in Korea,  find how many fewer employees work abroad than those working in Korea?",
        "answer_ko": "498",
        "answer_en": "498",
        "solution_abst_ko": "713 928 713 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "713 928 713 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 713\nvar_b = 928\nvar_c = 713\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 713\nvar_b = 928\nvar_c = 713\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "5895": {
        "category": "Arithmetic calculation",
        "question_ko": "태형이는 12000원을 가지고 있고 민우는 4000원을 가지고 있습니다. 태형이는 매일 300원의 용돈을 받고 민우는 매일 500원의 용돈을 받습니다. 태형이와 민우가 가진 돈이 같아지는 때는 며칠 후입니까?",
        "question_en": "Taehyung has 12,000 won and Minwoo has 4,000 won. Taehyung gets an allowance of 300 won every day and Minwoo gets an allowance of 500 won every day. How many days later will Taehyung and Minwoo have the same amount of money?",
        "answer_ko": "40",
        "answer_en": "40",
        "solution_abst_ko": "12000 4000 [OP_SUB] 500 300 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "12000 4000 [OP_SUB] 500 300 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 12000\nvar_b = 4000\nvar_c = var_a - var_b\nvar_d = 500\nvar_e = 300\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 12000\nvar_b = 4000\nvar_c = var_a - var_b\nvar_d = 500\nvar_e = 300\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))"
    },
    "5896": {
        "category": "Correspondence",
        "question_ko": "11로 어떤 수를 나누었더니 2가 되었습니다. 6을 어떤 수에 곱하면 얼마가 되는지 구하시오.",
        "question_en": "Divide a number by 11 and get 2. Find the result of 6 multiplied by a number.",
        "answer_ko": "132",
        "answer_en": "132",
        "solution_abst_ko": "2 11 [OP_MUL] 6 [OP_MUL]",
        "solution_abst_en": "2 11 [OP_MUL] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 11\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 11\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "5897": {
        "category": "Comparison",
        "question_ko": "윤주네 학교 강당에는 가로, 세로 각 줄의 의자 수가 같게 사각형 모양으로 놓여 있습니다. 윤주가 앉을 자리는 앞에서 2번째, 뒤에서 5번째, 오른쪽에서 3번째, 왼쪽에서 4번째에 있습니다. 윤주네 학교 강당에 있는 의자는 모두 몇 개입니까?",
        "question_en": "In the auditorium at Yunju's school, the number of chairs in each row is the same in a square shape. The seat for Yunju is 2nd from the front, 5th from the back, 3rd from the right, and 4th from the left. How many chairs are there in the auditorium at Yunju's school?",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "2 5 [OP_ADD] 1 [OP_SUB] 3 4 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "2 5 [OP_ADD] 1 [OP_SUB] 3 4 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = 4\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 2\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = 4\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))"
    },
    "5898": {
        "category": "Correspondence",
        "question_ko": "AB2-41=591이 성립하기 위해 A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "What number must go into A to make AB2-41=591 valid?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "AB2-41=591 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "AB2-41=591 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'AB2-41=591'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'AB2-41=591'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "5899": {
        "category": "Comparison",
        "question_ko": "진아는 가지고 있던 귤 12개 중에서 4개를 동화에게 주었고, 영호는 가지고 있던 귤 15개 중에서 6개를 동화에게 주었습니다. 동화는 진아와 영호에게 받은 귤만 있을 때 귤을 가장 많이 가지고 있는 사람은 누구입니까?",
        "question_en": "Jina gave Donghwa 4 out of 12 tangerines, and Youngho gave Donghwa 6 out of 15 tangerines. Who has the most tangerines when Donghwa has only the tangerines that were given by Jina and Youngho?",
        "answer_ko": "동화",
        "answer_en": "Donghwa",
        "solution_abst_ko": "[OP_LIST_SOL] 진아 영호 동화 [OP_LIST_EOL] [OP_LIST_SOL] 12 4 [OP_SUB] 15 6 [OP_SUB] 4 6 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jina Youngho Donghwa [OP_LIST_EOL] [OP_LIST_SOL] 12 4 [OP_SUB] 15 6 [OP_SUB] 4 6 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '진아'\nvar_b = '영호'\nvar_c = '동화'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 12\nvar_e = 4\nvar_f = var_d - var_e\nvar_g = 15\nvar_h = 6\nvar_i = var_g - var_h\nvar_j = 4\nvar_k = 6\nvar_l = var_j + var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'Jina'\nvar_b = 'Youngho'\nvar_c = 'Donghwa'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 12\nvar_e = 4\nvar_f = var_d - var_e\nvar_g = 15\nvar_h = 6\nvar_i = var_g - var_h\nvar_j = 4\nvar_k = 6\nvar_l = var_j + var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "5900": {
        "category": "Comparison",
        "question_ko": "남준이는 2등을 했고, 윤기는 바로 그 뒤에 들어갔습니다. 호석이는 윤기 뒤 3번째에 들어갔습니다. 호석이는 몇등입니까?",
        "question_en": "Namjoon came second, and Yoongi came right behind him. 3 people came after Yoongi and after them, Hoseok came. What's Hoseok's ranking?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "2 1 [OP_ADD] 3 [OP_ADD]",
        "solution_abst_en": "2 1 [OP_ADD] 3 [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "5901": {
        "category": "Comparison",
        "question_ko": "4개의 숫자 0.8, 1/2, 0.9, 1/3가 있습니다. 3보다 작은 수 중 가장 큰 숫자는 얼마인가요?",
        "question_en": "There are four numbers 0.8, 1/2, 0.9, and1/3. What is the largest number less than 3?",
        "answer_ko": "0.90",
        "answer_en": "0.9",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 3 [OP_LIST_LESS] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 3 [OP_LIST_LESS] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = []\nfor i in list_a:\n    if i < var_e:\n        list_b.append(i)\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = []\nfor i in list_a:\n    if i < var_e:\n        list_b.append(i)\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "5902": {
        "category": "Comparison",
        "question_ko": "무게가 각각 1.2킬로그램(㎏), 3.1킬로그램(㎏), 2.4킬로그램(㎏), 3.0킬로그램(㎏), 1.8킬로그램(㎏)인 가방이 있습니다. 2킬로그램(㎏)이 넘는 가방은 모두 몇 개입니까?",
        "question_en": "There are bags weighing 1.2 kilograms (kg), 3.1 kilograms (kg), 2.4 kilograms (kg), 3.0 kilograms (kg), and 1.8 kilograms (kg), respectively. How many bags are there weighing more than 2 kilograms (kg)?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 1.2 3.1 2.4 3.0 1.8 [OP_LIST_EOL] 2 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1.2 3.1 2.4 3.0 1.8 [OP_LIST_EOL] 2 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1.2\nvar_b = 3.1\nvar_c = 2.4\nvar_d = 3\nvar_e = 1.8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1.2\nvar_b = 3.1\nvar_c = 2.4\nvar_d = 3\nvar_e = 1.8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "5903": {
        "category": "Geometry",
        "question_ko": "어떤 원의 지름을 반지름으로 나눈 값은 몇입니까?",
        "question_en": "The radius of a circle is 2 centimeters (cm). What is the other radius of this circle in centimeters (cm)?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "2",
        "solution_abst_en": "2",
        "solution_code_ko": "var_a = 2\nprint(int(var_a))",
        "solution_code_en": "var_a = 2\nprint(int(var_a))"
    },
    "5904": {
        "category": "Arithmetic calculation",
        "question_ko": "백의 자리가 7인 세 자리수 중 가장 큰 수는 얼마입니까?",
        "question_en": "What is the largest three-digit number with 7 in the hundreds place?",
        "answer_ko": "799",
        "answer_en": "799",
        "solution_abst_ko": "7AB [OP_GEN_POSSIBLE_LIST] 1 [OP_LIST_MAX]",
        "solution_abst_en": "7AB [OP_GEN_POSSIBLE_LIST] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = '7AB'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_c = list_b[-var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '7AB'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_c = list_b[-var_b]\nprint(int(var_c))"
    },
    "5905": {
        "category": "Arithmetic calculation",
        "question_ko": "석진, 태형, 은지의 수학 시험 평균 점수는 92점입니다. 또 민영이와 호석이의 점수는 각각 90점, 95점입니다. 이 다섯 명의 수학 시험 평균 점수는 몇 점인지 소수점을 포함하여 답을 구하시오.",
        "question_en": "Seokjin, Taehyung, and Eunji's math test average score is 92. Also, Min-young and Hoseok's scores are 90 and 95, respectively. Find the average score of these five students on the math test, including decimal points.",
        "answer_ko": "92.20",
        "answer_en": "92.2",
        "solution_abst_ko": "92 3 [OP_MUL] 90 [OP_ADD] 95 [OP_ADD] 5 [OP_DIV]",
        "solution_abst_en": "92 3 [OP_MUL] 90 [OP_ADD] 95 [OP_ADD] 5 [OP_DIV]",
        "solution_code_ko": "var_a = 92\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 90\nvar_e = var_c + var_d\nvar_f = 95\nvar_g = var_e + var_f\nvar_h = 5\nvar_i = var_g / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 92\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 90\nvar_e = var_c + var_d\nvar_f = 95\nvar_g = var_e + var_f\nvar_h = 5\nvar_i = var_g / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "5906": {
        "category": "Arithmetic calculation",
        "question_ko": "선아는 여행을 가는데 전체 거리의 7/15은 기차를 탔고, 나머지 거리의 5/8는 버스를 탔으며, 그 나머지 거리의 2/3는 택시를 탔다. 또 그 나머지 거리 2.6킬로미터(㎞)는 걸어서 갔다. 선아가 여행한 거리는 모두 몇 킬로미터(㎞)인가?",
        "question_en": "Suna traveled 7/15 of the total distance by train, 5/8 of the remaining distance by bus, and 2/3 of the remaining distance by taxi. The rest of the distance was 2.6 kilometers (km) on foot. How many kilometers (km) did Suna travel?",
        "answer_ko": "39",
        "answer_en": "39",
        "solution_abst_ko": "2.6 1 7/15 [OP_SUB] 1 5/8 [OP_SUB] [OP_MUL] 1 2/3 [OP_SUB] [OP_MUL] [OP_DIV]",
        "solution_abst_en": "2.6 1 7/15 [OP_SUB] 1 5/8 [OP_SUB] [OP_MUL] 1 2/3 [OP_SUB] [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 2.6\nvar_b = 1\nvar_c = 0.4666666666666667\nvar_d = var_b - var_c\nvar_e = 1\nvar_f = 0.625\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = 1\nvar_j = 0.6666666666666666\nvar_k = var_i - var_j\nvar_l = var_h * var_k\nvar_m = var_a / var_l\nprint(int(eval('{:.2f}'.format(round(var_m+1e-10,2)))))",
        "solution_code_en": "var_a = 2.6\nvar_b = 1\nvar_c = 0.4666666666666667\nvar_d = var_b - var_c\nvar_e = 1\nvar_f = 0.625\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = 1\nvar_j = 0.6666666666666666\nvar_k = var_i - var_j\nvar_l = var_h * var_k\nvar_m = var_a / var_l\nprint(int(eval('{:.2f}'.format(round(var_m+1e-10,2)))))"
    },
    "5907": {
        "category": "Geometry",
        "question_ko": "여러 개의 직육면체가 있을 때 모든 직육면체의 면의수와 모서리의 수를 합하면 216입니다. 모든 직육면체의 꼭짓점의 수의 합을 구하시오.",
        "question_en": "When there are several cuboids, the sum of the number of faces and the number of edges of all the cuboids is 216. Find the sum of the number of vertices of all the cuboids.",
        "answer_ko": "96",
        "answer_en": "96",
        "solution_abst_ko": "216 12 6 [OP_ADD] [OP_DIV] 8 [OP_MUL]",
        "solution_abst_en": "216 12 6 [OP_ADD] [OP_DIV] 8 [OP_MUL]",
        "solution_code_ko": "var_a = 216\nvar_b = 12\nvar_c = 6\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nvar_f = 8\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 216\nvar_b = 12\nvar_c = 6\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nvar_f = 8\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "5908": {
        "category": "Geometry",
        "question_ko": "규형이는 정사각형 모양의 카드를 여러 장 가지고 있습니다. 이 카드를 빈틈없이 늘어놓아 큰 정사각형 모양을 만들었더니 3장의 카드가 남았습니다. 만든 정사각형의 가로 한 변과 세로 한 변을 2열씩 늘리려면 44장의 카드가 더 필요하다고 합니다. 규형이는 카드 몇 장을 가지고 있습니까?",
        "question_en": "Kyuhyung has several square-shaped cards. The cards are laid out neatly to form a large square, and there are 3 cards left. It is said that 44 more cards are needed to increase to fill the outer perimeter with cards. How many cards does Kyuhyung have?",
        "answer_ko": "103",
        "answer_en": "103",
        "solution_abst_ko": "44 4 [OP_SUB] 4 [OP_DIV] 2 [OP_POW] 3 [OP_ADD]",
        "solution_abst_en": "44 4 [OP_SUB] 4 [OP_DIV] 2 [OP_POW] 3 [OP_ADD]",
        "solution_code_ko": "var_a = 44\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e ** var_f\nvar_h = 3\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 44\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e ** var_f\nvar_h = 3\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "5909": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 세 자리 수를 20으로 나누었을 때의 나머지와 25로 나누었을 때의 나머지는 같습니다. 나머지가 7이라고 한다면, 어떤 수가 될 수 있는 수 중 가장 큰 수는 얼마입니까?",
        "question_en": "The remainder when a certain three-digit number is divided by 20 is the same as the remainder when divided by 25. If the remainder is 7, what is the possible largest number of the certain number?",
        "answer_ko": "907",
        "answer_en": "907",
        "solution_abst_ko": "100 999 1 [OP_LIST_ARANGE] 20 7 [OP_LIST_DIVIDE_AND_REMAIN] 25 7 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MAX]",
        "solution_abst_en": "100 999 1 [OP_LIST_ARANGE] 20 7 [OP_LIST_DIVIDE_AND_REMAIN] 25 7 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 20\nvar_e = 7\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 25\nvar_g = 7\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nprint(int(var_i))",
        "solution_code_en": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 20\nvar_e = 7\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 25\nvar_g = 7\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nprint(int(var_i))"
    },
    "5910": {
        "category": "Comparison",
        "question_ko": "키가 작은 사람부터 순서대로 9명이 한 줄로 서 있습니다. 호석이는 중간에 서 있습니다. 키가 큰 사람부터 순서대로 다시 줄을 서면 호석이는 뒤에서부터 몇 번째에 서게 됩니까?",
        "question_en": "9 people are standing in a line in order from the shortest to the tallest. Hoseok is standing in the middle. If you line them up again in order from the tallest to the shortest, what number will Hoseok stand from the back?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "9 2 [OP_FDIV] 1 [OP_ADD]",
        "solution_abst_en": "9 2 [OP_FDIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 9\nvar_b = 2\nvar_c = var_a // var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 2\nvar_c = var_a // var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "5911": {
        "category": "Arithmetic calculation",
        "question_ko": "6년 후에 아버지의 나이와 아들의 나이의 합은 68살입니다. 올해는 아버지가 아들 나의의 6배입니다. 올해 아들의 나이는 몇 살입니까?",
        "question_en": "After 6 years, the father's age plus the son's age is 68 years old. This year, the father ages six times the son does. How old is the son this year?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "68 6 2 [OP_MUL] [OP_SUB] 1 6 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "68 6 2 [OP_MUL] [OP_SUB] 1 6 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 68\nvar_b = 6\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = 6\nvar_h = var_f + var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 68\nvar_b = 6\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = 6\nvar_h = var_f + var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "5912": {
        "category": "Arithmetic calculation",
        "question_ko": "연필 1타는 12자루입니다. 태형이는 연필을 2타 사서 남준이와 나누어 가졌는데 남준이가 태형이보다 4자루 더 많이 가졌습니다. 남준이가 가진 연필은 몇 자루입니까?",
        "question_en": "A dozen of pencils means 12 pencils. Taehyung bought 2 dozen pencils and shared them with Namjoon, but Namjoon got 4 more than Taehyung. How many pencils does Namjoon have?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "12 2 [OP_MUL] 4 [OP_SUB] 2 [OP_DIV] 4 [OP_ADD]",
        "solution_abst_en": "12 2 [OP_MUL] 4 [OP_SUB] 2 [OP_DIV] 4 [OP_ADD]",
        "solution_code_ko": "var_a = 12\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 4\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 12\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 4\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "5913": {
        "category": "Comparison",
        "question_ko": "현수가 탄 자동차는 일정한 빠르기로 16분 동안 17.28킬로미터(㎞)를 가고, 예준이가 탄 자동차는 일정한 빠르기로 6분 동안 8.52킬로미터(㎞)를 갑니다. 현수와 예준이가 같은 곳에서 자동차를 타고 출발하였다면 15분 후에 더 멀리 있는 사람은 누구입니까?",
        "question_en": "Hyeonsoo's car travels 17.28 kilometers (km) in 16 minutes at a constant speed, and Yejun's car travels 8.52 kilometers (km) in 6 minutes at a constant speed. If Hyeonsoo and Yejun started from the same place by car, who is further away 15 minutes later?",
        "answer_ko": "예준",
        "answer_en": "Yejun",
        "solution_abst_ko": "[OP_LIST_SOL] 현수 예준 [OP_LIST_EOL] [OP_LIST_SOL] 17.28 16 [OP_DIV] 15 [OP_MUL] 8.52 6 [OP_DIV] 15 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Hyeonsoo Yejun [OP_LIST_EOL] [OP_LIST_SOL] 17.28 16 [OP_DIV] 15 [OP_MUL] 8.52 6 [OP_DIV] 15 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '현수'\nvar_b = '예준'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 17.28\nvar_d = 16\nvar_e = var_c / var_d\nvar_f = 15\nvar_g = var_e * var_f\nvar_h = 8.52\nvar_i = 6\nvar_j = var_h / var_i\nvar_k = 15\nvar_l = var_j * var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'Hyeonsoo'\nvar_b = 'Yejun'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 17.28\nvar_d = 16\nvar_e = var_c / var_d\nvar_f = 15\nvar_g = var_e * var_f\nvar_h = 8.52\nvar_i = 6\nvar_j = var_h / var_i\nvar_k = 15\nvar_l = var_j * var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "5914": {
        "category": "Geometry",
        "question_ko": "이십각형의 한 꼭짓점에서 대각선을 그으려고 합니다. 몇 개의 대각선을 그을 수 있을까요?",
        "question_en": "You are trying to draw a diagonal from one vertex of an icosahedron. How many diagonal lines can you draw?",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "20 3 [OP_SUB]",
        "solution_abst_en": "20 3 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 20\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "5915": {
        "category": "Geometry",
        "question_ko": "한 모서리의 길이가 2센티미터(㎝)인 주사위를 쌓아 한 모서리가 10센티미터(㎝)인 정육면체를 만들었습니다. 정육면체의 모든 면에 색종이를 붙였습니다. 1개의 면에 색종이가 붙은 주사위는 모두 몇 개일까요?",
        "question_en": "Dice with an edge of 2 centimeters (cm) are stacked to form a cube with an edge of 10 centimeters (cm). I put confetti on all sides of the cube. How many dices have confetti on one side?",
        "answer_ko": "54",
        "answer_en": "54",
        "solution_abst_ko": "10 2 [OP_DIV] 2 [OP_SUB] 2 [OP_POW] 6 [OP_MUL]",
        "solution_abst_en": "10 2 [OP_DIV] 2 [OP_SUB] 2 [OP_POW] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e ** var_f\nvar_h = 6\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e ** var_f\nvar_h = 6\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "5916": {
        "category": "Geometry",
        "question_ko": "삼각형의 한 꼭지점에서 밑변의 중선을 그었을 때 나뉘어진 삼각형의 넓이가 7제곱센티미터(㎠)인 경우, 전체 삼각형의 넓이를 구하시오.",
        "question_en": "If a triangle is divided in two by a median line of the base from one vertex, and the area of a divided triangle is 7 square centimeters (cm2), find the area of the entire triangle.",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "7 2 [OP_MUL]",
        "solution_abst_en": "7 2 [OP_MUL]",
        "solution_code_ko": "var_a = 7\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 7\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "5917": {
        "category": "Comparison",
        "question_ko": "0.2, 0.8, 1/2, 0.9, 1/3의 숫자가 있다. 이 중 0.3보다 작은 숫자들의 합을 구하시오.",
        "question_en": "There are numbers 0.8, 1/2, 0.9, 0.2 and 1/3. Find the sum of all numbers less than 0.3.",
        "answer_ko": "0.2",
        "answer_en": "0.2",
        "solution_abst_ko": "[OP_LIST_SOL] 0.2 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.3 [OP_LIST_LESS] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0.2 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.3 [OP_LIST_LESS] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0.2\nvar_b = 0.8\nvar_c = 0.5\nvar_d = 0.9\nvar_e = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 0.3\nlist_b = []\nfor i in list_a:\n    if i < var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 0.2\nvar_b = 0.8\nvar_c = 0.5\nvar_d = 0.9\nvar_e = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 0.3\nlist_b = []\nfor i in list_a:\n    if i < var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "5918": {
        "category": "Arithmetic calculation",
        "question_ko": "일정한 빠르기로 버스는 17.28킬로미터(㎞)의 거리를 16분 동안에 가고, 승용차는 8.52킬로미터(㎞)의 거리를 6분 동안에 갑니다. 버스와 승용차가 같은 곳에서 동시에 출발한다면 15분 후에는 어느 것이 얼마나 더 멀리 가겠습니까?",
        "question_en": "At a constant speed, a bus travels a distance of 17.28 kilometers (km) in 16 minutes, and a car travels a distance of 8.52 kilometers (km) in 6 minutes. If a bus and a car start at the same time from the same place, which one and how farther will it go after 15 minutes?",
        "answer_ko": "5.10",
        "answer_en": "5.1",
        "solution_abst_ko": "17.28 16 [OP_DIV] 15 [OP_MUL] 8.52 6 [OP_DIV] 15 [OP_MUL] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "17.28 16 [OP_DIV] 15 [OP_MUL] 8.52 6 [OP_DIV] 15 [OP_MUL] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 17.28\nvar_b = 16\nvar_c = var_a / var_b\nvar_d = 15\nvar_e = var_c * var_d\nvar_f = 8.52\nvar_g = 6\nvar_h = var_f / var_g\nvar_i = 15\nvar_j = var_h * var_i\nvar_k = var_e - var_j\nvar_l = abs(var_k)\nprint('{:.2f}'.format(round(var_l+1e-10,2)))",
        "solution_code_en": "var_a = 17.28\nvar_b = 16\nvar_c = var_a / var_b\nvar_d = 15\nvar_e = var_c * var_d\nvar_f = 8.52\nvar_g = 6\nvar_h = var_f / var_g\nvar_i = 15\nvar_j = var_h * var_i\nvar_k = var_e - var_j\nvar_l = abs(var_k)\nprint('{:.2f}'.format(round(var_l+1e-10,2)))"
    },
    "5919": {
        "category": "Comparison",
        "question_ko": "태형이는 유정이보다 무겁습니다. 유정이는 지민이보다 무겁습니다. 태형이는 호석이보다 가볍습니다. 4명 중 가장 가벼운 사람은 누구입니까?",
        "question_en": "Taehyung is heavier than Yoojung. Yoojung is heavier than Jimin. Taehyung is lighter than Hoseok. Which of the 4 is the lightest?",
        "answer_ko": "지민",
        "answer_en": "Jimin",
        "solution_abst_ko": "[OP_LIST_SOL] 태형 유정 지민 호석 [OP_LIST_EOL] [OP_LIST_SOL] 태형 유정 > 유정 지민 > 태형 호석 < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Taehyung Yoojung Jimin Hoseok [OP_LIST_EOL] [OP_LIST_SOL] Taehyung Yoojung > Yoojung Jimin > Taehyung Hoseok < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '태형'\nvar_b = '유정'\nvar_c = '지민'\nvar_d = '호석'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '태형'\nvar_f = '유정'\nvar_g = '>'\nvar_h = '유정'\nvar_i = '지민'\nvar_j = '>'\nvar_k = '태형'\nvar_l = '호석'\nvar_m = '<'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)",
        "solution_code_en": "var_a = 'Taehyung'\nvar_b = 'Yoojung'\nvar_c = 'Jimin'\nvar_d = 'Hoseok'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'Taehyung'\nvar_f = 'Yoojung'\nvar_g = '>'\nvar_h = 'Yoojung'\nvar_i = 'Jimin'\nvar_j = '>'\nvar_k = 'Taehyung'\nvar_l = 'Hoseok'\nvar_m = '<'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)"
    },
    "5920": {
        "category": "Possibility",
        "question_ko": "1부터 9까지의 숫자가 적힌 숫자 카드가 9장 있는데, 그 중에서 3장을 뽑아서 합이 17이 되도록 하는 방법은 모두 몇 가지입니까?",
        "question_en": "If there are 9 number cards written from 1 to 9, how many ways can you make the sum of cards as 17 by drawing 3 of them?",
        "answer_ko": "42",
        "answer_en": "42",
        "solution_abst_ko": "1 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 17 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 17 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 17\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 17\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))"
    },
    "5921": {
        "category": "Comparison",
        "question_ko": "우유가 9/10리터(L) 있습니다. 수연이가 전체의 1/3을 마셨고, 현우가 전체의 4/9를 마셨습니다. 수연이와 현우 중에서 누가 우유를 더 많이 마셨습니까?",
        "question_en": "There are 9/10 liters (L) of milk. Suyeon drank 1/3 of the total, and Hyunwoo drank 4/9 of the total. Who drank more milk, Suyeon or Hyunwoo?",
        "answer_ko": "현우",
        "answer_en": "Hyunwoo",
        "solution_abst_ko": "[OP_LIST_SOL] 수연 현우 [OP_LIST_EOL] [OP_LIST_SOL] 1/3 4/9 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Suyeon Hyunwoo [OP_LIST_EOL] [OP_LIST_SOL] 1/3 4/9 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '수연'\nvar_b = '현우'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.3333333333333333\nvar_d = 0.4444444444444444\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Suyeon'\nvar_b = 'Hyunwoo'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.3333333333333333\nvar_d = 0.4444444444444444\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "5922": {
        "category": "Comparison",
        "question_ko": "사전에서 갑, 을, 병 세글자를 찾으려고 한다. 갑보다는 을이 뒤에 있고, 병보다 을이 뒤에 있을 때, 사전에서 가장 뒤에 있는 글자는 무엇인지 구하시오.",
        "question_en": "You are trying to find the three letters (a), (b), and (c) in the dictionary. When (b) is behind (a) and (b) is behind (c), what is the last letter in the dictionary?",
        "answer_ko": "을",
        "answer_en": "(b)",
        "solution_abst_ko": "[OP_LIST_SOL] 갑 을 병 [OP_LIST_EOL] [OP_LIST_SOL] 갑 을 < 병 을 < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (a) (b) (c) [OP_LIST_EOL] [OP_LIST_SOL] (a) (b) < (c) (b) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '갑'\nvar_b = '을'\nvar_c = '병'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '갑'\nvar_e = '을'\nvar_f = '<'\nvar_g = '병'\nvar_h = '을'\nvar_i = '<'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(var_k)",
        "solution_code_en": "var_a = '(a)'\nvar_b = '(b)'\nvar_c = '(c)'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '(a)'\nvar_e = '(b)'\nvar_f = '<'\nvar_g = '(c)'\nvar_h = '(b)'\nvar_i = '<'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(var_k)"
    },
    "5923": {
        "category": "Comparison",
        "question_ko": "4마리의 동물 (가), (나), (다), (라)가 있습니다. (라) 동물은 (가) 동물보다 작고 (나) 동물보다 큽니다. (다) 동물은 (가) 동물보다 클 때 가장 큰 동물은 무엇입니까?",
        "question_en": "There are 4 animals A, B, C and D. D animals are smaller than A animals and larger than B animals. Which animal is the largest when C animals are larger than A animals?",
        "answer_ko": "(다)",
        "answer_en": "C",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) (다) (라) [OP_LIST_EOL] [OP_LIST_SOL] (가) (다) < (라) (나) > (라) (가) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D [OP_LIST_EOL] [OP_LIST_SOL] A C < D B > D A < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nvar_c = '(다)'\nvar_d = '(라)'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '(가)'\nvar_f = '(다)'\nvar_g = '<'\nvar_h = '(라)'\nvar_i = '(나)'\nvar_j = '>'\nvar_k = '(라)'\nvar_l = '(가)'\nvar_m = '<'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = 1\nvar_o = list_c[var_n-1]\nprint(var_o)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'A'\nvar_f = 'C'\nvar_g = '<'\nvar_h = 'D'\nvar_i = 'B'\nvar_j = '>'\nvar_k = 'D'\nvar_l = 'A'\nvar_m = '<'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = 1\nvar_o = list_c[var_n-1]\nprint(var_o)"
    },
    "5924": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 7을 빼 결과값 9를 얻었습니다. 어떤 수에 5를 곱하면 얼마입니까?",
        "question_en": "You subtracted 7 from a number and got 9. What is the value of the number multiplied by 5?",
        "answer_ko": "80",
        "answer_en": "80",
        "solution_abst_ko": "9 7 [OP_ADD] 5 [OP_MUL]",
        "solution_abst_en": "9 7 [OP_ADD] 5 [OP_MUL]",
        "solution_code_ko": "var_a = 9\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "5925": {
        "category": "Correspondence",
        "question_ko": "두 자리 소수 3.A7은 3.A7>3.27를 만족합니다. A에 들어갈 수 있는 숫자의 개수를 쓰시오. 단, A에는 0부터 9까지의 수를 쓸 수 있습니다.",
        "question_en": "A two-digit decimal 3.A7 is greater than 3.27. Write how many numbers can fit in A. However, A can contain any number from 0 to 9.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "3.A7>3.27 A [OP_DIGIT_UNK_SOLVER] [OP_LIST_LEN]",
        "solution_abst_en": "3.A7>3.27 A [OP_DIGIT_UNK_SOLVER] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '3.A7>3.27'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = len(list_a)\nprint(int(var_c))",
        "solution_code_en": "var_a = '3.A7>3.27'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = len(list_a)\nprint(int(var_c))"
    },
    "5926": {
        "category": "Arithmetic calculation",
        "question_ko": "야구공 43개를 6개의 반에 똑같이 나누어 주고, 남는 야구공이 가장 적게 하려고 합니다. 이 때 남는 야구공은 몇 개입니까?",
        "question_en": "We want to distribute 43 baseballs equally among 6 classes, with the fewest remaining baseballs. How many baseballs should be left?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "43 6 [OP_MOD]",
        "solution_abst_en": "43 6 [OP_MOD]",
        "solution_code_ko": "var_a = 43\nvar_b = 6\nvar_c = var_a % var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 43\nvar_b = 6\nvar_c = var_a % var_b\nprint(int(var_c))"
    },
    "5927": {
        "category": "Correspondence",
        "question_ko": "1/4×1/8=1/(4×A)=1/B 일 때 A와 B의 합은?",
        "question_en": "When 1/4×1/8=1/(4×A)=1/B, what is the sum of A and B?",
        "answer_ko": "40",
        "answer_en": "40",
        "solution_abst_ko": "1/4×1/8=1/(4×A)=1/B A [OP_NUM_UNK_SOLVER] 1/4×1/8=1/(4×A)=1/B B [OP_NUM_UNK_SOLVER] [OP_ADD]",
        "solution_abst_en": "1/4×1/8=1/(4×A)=1/B A [OP_NUM_UNK_SOLVER] 1/4×1/8=1/(4×A)=1/B B [OP_NUM_UNK_SOLVER] [OP_ADD]",
        "solution_code_ko": "var_a = '1/4×1/8=1/(4×A)=1/B'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '1/4×1/8=1/(4×A)=1/B'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = '1/4×1/8=1/(4×A)=1/B'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '1/4×1/8=1/(4×A)=1/B'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "5928": {
        "category": "Possibility",
        "question_ko": "A에는 1부터 9까지의 자연수가 들어갈 수 있습니다. 44×A<55×4일 때, 가능한 A의 합을 구하시오.",
        "question_en": "A can contain natural numbers from 1 to 9. If 44×A<55×4, find the sum of all the numbers that can be A.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "1 9 1 [OP_LIST_ARANGE] 55 4 [OP_MUL] 44 [OP_DIV] [OP_LIST_LESS] [OP_LIST_SUM]",
        "solution_abst_en": "1 9 1 [OP_LIST_ARANGE] 55 4 [OP_MUL] 44 [OP_DIV] [OP_LIST_LESS] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 55\nvar_e = 4\nvar_f = var_d * var_e\nvar_g = 44\nvar_h = var_f / var_g\nlist_b = []\nfor i in list_a:\n    if i < var_h:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_i = sum(list_b)\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 55\nvar_e = 4\nvar_f = var_d * var_e\nvar_g = 44\nvar_h = var_f / var_g\nlist_b = []\nfor i in list_a:\n    if i < var_h:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_i = sum(list_b)\nprint(int(var_i))"
    },
    "5929": {
        "category": "Arithmetic calculation",
        "question_ko": "민지는 매일 방 청소를 하기 위해 0.6시간을 씁니다. 민지가 3주 동안 방 청소를 위해 쓴 시간은 몇 시간인지 구하시오.",
        "question_en": "Minji spends 0.6 hours cleaning her room every day. Find how many hours Minji spent cleaning her room in 3 weeks.",
        "answer_ko": "12.60",
        "answer_en": "12.6",
        "solution_abst_ko": "0.6 7 [OP_MUL] 3 [OP_MUL]",
        "solution_abst_en": "0.6 7 [OP_MUL] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 0.6\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.6\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "5930": {
        "category": "Arithmetic calculation",
        "question_ko": "세 자리 수 중 6, 5, 8, 9의 공배수인 수는 모두 몇 개 입니까?",
        "question_en": "How many three-digit numbers are common multiples of 6, 5, 8, and 9?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "100 999 1 [OP_LIST_ARANGE] 6 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "100 999 1 [OP_LIST_ARANGE] 6 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = len(list_e)\nprint(int(var_h))",
        "solution_code_en": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = len(list_e)\nprint(int(var_h))"
    },
    "5931": {
        "category": "Geometry",
        "question_ko": "민진이는 철사를 이용해서 한 변의 길이가 80센티미터(㎝)인 정사각형 모양을 만들었습니다. 동일한 길이의 철사를 사용하여 세로 길이가 100센티미터(㎝)인 직사각형 모양을 만들었다고 한다면, 이 직사각형의 가로 길이를 구하시오.",
        "question_en": "Minjin made a square shape with one side length of 80 centimeters (cm) using wire. If you use the same length of wire to make a rectangular shape with a vertical length of 100 centimeters (cm), find the horizontal length of this rectangle.",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "80 4 [OP_MUL] 2 [OP_DIV] 100 [OP_SUB]",
        "solution_abst_en": "80 4 [OP_MUL] 2 [OP_DIV] 100 [OP_SUB]",
        "solution_code_ko": "var_a = 80\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 100\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 80\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 100\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "5932": {
        "category": "Possibility",
        "question_ko": "공책, 연필, 지우개 중 서로 다른 2가지 학용품을 사려고 합니다. 서로 다른 학용품을 선택할 경우의 수는 몇 개 인가요?",
        "question_en": "You want to buy 2 different school supplies: a notebook, a pencil, and an eraser. If you choose different ones, how many ways are there?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 공책 연필 지우개 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] notebook pencil eraser [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '공책'\nvar_b = '연필'\nvar_c = '지우개'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f / (i+1)\nprint(int(var_f))",
        "solution_code_en": "var_a = 'notebook'\nvar_b = 'pencil'\nvar_c = 'eraser'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f / (i+1)\nprint(int(var_f))"
    },
    "5933": {
        "category": "Geometry",
        "question_ko": "오면체의 면의 개수는?",
        "question_en": "How many faces does a pentahedron have?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "5",
        "solution_abst_en": "5",
        "solution_code_ko": "var_a = 5\nprint(int(var_a))",
        "solution_code_en": "var_a = 5\nprint(int(var_a))"
    },
    "5934": {
        "category": "Geometry",
        "question_ko": "정육면체 모양의 상자의 각 모서리의 길이를 2배로 늘렸습니다. 이 상자의 겉넓이는 몇 배가 될까요?",
        "question_en": "I doubled the length of each corner of a cube-shaped box. How many times bigger will the surface area of this box become?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "2 2 [OP_POW]",
        "solution_abst_en": "2 2 [OP_POW]",
        "solution_code_ko": "var_a = 2\nvar_b = 2\nvar_c = var_a ** var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 2\nvar_c = var_a ** var_b\nprint(int(var_c))"
    },
    "5935": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 4로 나누면 12가 됩니다. 호석이는 어떤 수를 3으로 나누고자 합니다. 기대하는 결과 값은 무엇입니까?",
        "question_en": "A number divided by 4 is 12. Hoseok wants to divide a number by 3. What is the expected result value?",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "12 4 [OP_MUL] 3 [OP_DIV]",
        "solution_abst_en": "12 4 [OP_MUL] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "5936": {
        "category": "Correspondence",
        "question_ko": "5A8-21B=364일 때, B에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "If 5A8-21B=364, what number should go in B?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "5A8-21B=364 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "5A8-21B=364 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '5A8-21B=364'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '5A8-21B=364'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "5937": {
        "category": "Correspondence",
        "question_ko": "A15B94는 99로 나누어 떨어지는 여섯 자리 수입니다. B를 구하시오.",
        "question_en": "A15B94 is a six-digit number divisible by 99. If A15B94 is a multiple of 99, find B.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "A15B94 [OP_GEN_POSSIBLE_LIST] 99 [OP_LIST_DIVISIBLE] A15B94 B [OP_LIST_FIND_UNK]",
        "solution_abst_en": "A15B94 [OP_GEN_POSSIBLE_LIST] 99 [OP_LIST_DIVISIBLE] A15B94 B [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = 'A15B94'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 99\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 'A15B94'\nvar_d = 'B'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nvar_e = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_e = int(elem[unk_idx])\nprint(int(var_e))",
        "solution_code_en": "var_a = 'A15B94'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 99\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 'A15B94'\nvar_d = 'B'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nvar_e = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_e = int(elem[unk_idx])\nprint(int(var_e))"
    },
    "5938": {
        "category": "Comparison",
        "question_ko": "과자가 30개 있습니다. 민수는 12개, 재영이는 3개, 희수는 15개를 받았습니다. 과자를 가장 많이 받은 사람은 누구입니까?",
        "question_en": "There are 30 sweets. Minsu received 12, Jaeyoung 3, and Heesu 15. Who received the most sweets?",
        "answer_ko": "희수",
        "answer_en": "Heesu",
        "solution_abst_ko": "[OP_LIST_SOL] 민수 재영 희수 [OP_LIST_EOL] [OP_LIST_SOL] 12 3 15 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Minsu Jaeyoung Heesu [OP_LIST_EOL] [OP_LIST_SOL] 12 3 15 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '민수'\nvar_b = '재영'\nvar_c = '희수'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 12\nvar_e = 3\nvar_f = 15\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Minsu'\nvar_b = 'Jaeyoung'\nvar_c = 'Heesu'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 12\nvar_e = 3\nvar_f = 15\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "5939": {
        "category": "Geometry",
        "question_ko": "한 모서리의 길이가 4센티미터(㎝)인 정육면체 27개를 붙여 하나의 큰 정육면체를 만들었습니다. 이 큰 정육면체의 겉넓이는 몇 ㎠입니까?",
        "question_en": "Twenty-seven cubes with each edge being 4 centimeters (cm) long were glued together to form a one large cube. What is the surface area of this large cube in cm2 (cm2)?",
        "answer_ko": "864",
        "answer_en": "864",
        "solution_abst_ko": "4 27 1 3 [OP_DIV] [OP_POW] [OP_MUL] 2 [OP_POW] 6 [OP_MUL]",
        "solution_abst_en": "4 27 1 3 [OP_DIV] [OP_POW] [OP_MUL] 2 [OP_POW] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 4\nvar_b = 27\nvar_c = 1\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = var_b ** var_e\nvar_g = var_a * var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 6\nvar_k = var_i * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 4\nvar_b = 27\nvar_c = 1\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = var_b ** var_e\nvar_g = var_a * var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 6\nvar_k = var_i * var_j\nprint(int(var_k))"
    },
    "5940": {
        "category": "Geometry",
        "question_ko": "10개의 변의 길이가 서로 같고, 10개의 각의 크기가 서로 같은 도형의 한 꼭짓점에서 그을 수 있는 대각선의 개수는 몇 개인지 구하시오.",
        "question_en": "How many diagonals can be drawn from a vertex in a figure with 10 sides equal in length and 10 angles equal in measure?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "10 3 [OP_SUB]",
        "solution_abst_en": "10 3 [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 10\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "5941": {
        "category": "Correspondence",
        "question_ko": "124를 더하면 각자리 숫자가 모두 같아지는 수가 있습니다. 이숫자의 백의 자리 수와 일의 자리 수의 합은 5이고 십의 자리 숫자는 3입니다. 이 세자리 수의 각자리는 모두 다르다고 할때 세 자리수를 구하시오.",
        "question_en": "When you add 124, each digit is the same number. The sum of the hundreds and ones digits of this number is 5, and the tens digit is 3. If each of these three digit numbers is different, find the three digit number.",
        "answer_ko": "431",
        "answer_en": "431",
        "solution_abst_ko": "[OP_LIST_SOL] [OP_LIST_SOL] A 3 B + 124 = C C C [OP_LIST_EOL] [OP_LIST2NUM] A [OP_DIGIT_UNK_SOLVER] 3 [OP_LIST_SOL] A 3 B + 124 = C C C [OP_LIST_EOL] [OP_LIST2NUM] B [OP_DIGIT_UNK_SOLVER] [OP_LIST_EOL] [OP_LIST2NUM]",
        "solution_abst_en": "[OP_LIST_SOL] [OP_LIST_SOL] A 3 B + 124 = C C C [OP_LIST_EOL] [OP_LIST2NUM] A [OP_DIGIT_UNK_SOLVER] 3 [OP_LIST_SOL] A 3 B + 124 = C C C [OP_LIST_EOL] [OP_LIST2NUM] B [OP_DIGIT_UNK_SOLVER] [OP_LIST_EOL] [OP_LIST2NUM]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 3\nvar_c = 'B'\nvar_d = '+'\nvar_e = 124\nvar_f = '='\nvar_g = 'C'\nvar_h = 'C'\nvar_i = 'C'\nlist_a= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_j=\"\"\nfor i in list_a:\n    i = str(i)\n    var_j = var_j + i\nvar_k = 'A'\nans_dict = dict()\nvar_j = var_j.replace('×','*')\nvar_j = var_j.replace('x','*')\nvar_j = var_j.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_j):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_j\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_j):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_l = ans_dict[var_k]\nvar_m = 3\nvar_n = 'A'\nvar_o = 3\nvar_p = 'B'\nvar_q = '+'\nvar_r = 124\nvar_s = '='\nvar_t = 'C'\nvar_u = 'C'\nvar_v = 'C'\nlist_b= []\nif \"/\" in str(var_v):\n    var_v = eval(str(var_v))\nlist_b.append(var_v)\nif \"/\" in str(var_u):\n    var_u = eval(str(var_u))\nlist_b.append(var_u)\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_b.append(var_t)\nif \"/\" in str(var_s):\n    var_s = eval(str(var_s))\nlist_b.append(var_s)\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nlist_b.reverse()\nvar_w=\"\"\nfor i in list_b:\n    i = str(i)\n    var_w = var_w + i\nvar_x = 'B'\nans_dict = dict()\nvar_w = var_w.replace('×','*')\nvar_w = var_w.replace('x','*')\nvar_w = var_w.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_w):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_w\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_w):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_y = ans_dict[var_x]\nlist_c= []\nif \"/\" in str(var_y):\n    var_y = eval(str(var_y))\nlist_c.append(var_y)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_c.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_c.append(var_l)\nlist_c.reverse()\nvar_z=\"\"\nfor i in list_c:\n    i = str(i)\n    var_z = var_z + i\nprint(int(var_z))",
        "solution_code_en": "var_a = 'A'\nvar_b = 3\nvar_c = 'B'\nvar_d = '+'\nvar_e = 124\nvar_f = '='\nvar_g = 'C'\nvar_h = 'C'\nvar_i = 'C'\nlist_a= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_j=\"\"\nfor i in list_a:\n    i = str(i)\n    var_j = var_j + i\nvar_k = 'A'\nans_dict = dict()\nvar_j = var_j.replace('×','*')\nvar_j = var_j.replace('x','*')\nvar_j = var_j.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_j):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_j\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_j):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_l = ans_dict[var_k]\nvar_m = 3\nvar_n = 'A'\nvar_o = 3\nvar_p = 'B'\nvar_q = '+'\nvar_r = 124\nvar_s = '='\nvar_t = 'C'\nvar_u = 'C'\nvar_v = 'C'\nlist_b= []\nif \"/\" in str(var_v):\n    var_v = eval(str(var_v))\nlist_b.append(var_v)\nif \"/\" in str(var_u):\n    var_u = eval(str(var_u))\nlist_b.append(var_u)\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_b.append(var_t)\nif \"/\" in str(var_s):\n    var_s = eval(str(var_s))\nlist_b.append(var_s)\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nlist_b.reverse()\nvar_w=\"\"\nfor i in list_b:\n    i = str(i)\n    var_w = var_w + i\nvar_x = 'B'\nans_dict = dict()\nvar_w = var_w.replace('×','*')\nvar_w = var_w.replace('x','*')\nvar_w = var_w.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_w):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_w\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_w):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_y = ans_dict[var_x]\nlist_c= []\nif \"/\" in str(var_y):\n    var_y = eval(str(var_y))\nlist_c.append(var_y)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_c.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_c.append(var_l)\nlist_c.reverse()\nvar_z=\"\"\nfor i in list_c:\n    i = str(i)\n    var_z = var_z + i\nprint(int(var_z))"
    },
    "5942": {
        "category": "Arithmetic calculation",
        "question_ko": "500보다 크고 7로 나눈 나머지가 3인 자연수 중 2번째로 작은 값을 구하시오.",
        "question_en": "Find the second smallest natural number that is greater than 500, and that has 3 as a remainder when divided by 7.",
        "answer_ko": "514",
        "answer_en": "514",
        "solution_abst_ko": "1 9999 1 [OP_LIST_ARANGE] 500 [OP_LIST_MORE] 7 3 [OP_LIST_DIVIDE_AND_REMAIN] 2 [OP_LIST_MIN]",
        "solution_abst_en": "1 9999 1 [OP_LIST_ARANGE] 500 [OP_LIST_MORE] 7 3 [OP_LIST_DIVIDE_AND_REMAIN] 2 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 500\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nvar_e = 7\nvar_f = 3\nlist_c = [] \nvar_e = int(var_e)\nvar_f = int(var_f)\nif var_f < 0:\n    var_f = var_f + var_e\nfor i in list_b:\n    i = int(i)\n    if i%var_e == var_f:\n        list_c.append(i)\nvar_g = 2\nlist_d=list_c.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nprint(int(var_h))",
        "solution_code_en": "var_a = 1\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 500\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nvar_e = 7\nvar_f = 3\nlist_c = [] \nvar_e = int(var_e)\nvar_f = int(var_f)\nif var_f < 0:\n    var_f = var_f + var_e\nfor i in list_b:\n    i = int(i)\n    if i%var_e == var_f:\n        list_c.append(i)\nvar_g = 2\nlist_d=list_c.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nprint(int(var_h))"
    },
    "5943": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 1미터(m) 50센티미터(㎝)인 철사를 석기와 예슬이가 나누어 가지려고 합니다. 석기가 예슬이보다 16센티미터(㎝) 더 짧게 가지려면 석기는 몇 센티미터(㎝)를 가지면 됩니까?",
        "question_en": "Seokgi and Yeseul are trying to share a wire with a length of 1 meter (m) and 50 centimeters (cm). How many centimeters (cm) of wire must Seokgi take in order for Seokgi's wire to be 16 centimeters (cm) shorter than Yeseul's?",
        "answer_ko": "67",
        "answer_en": "67",
        "solution_abst_ko": "1 100 [OP_MUL] 50 [OP_ADD] 16 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "1 100 [OP_MUL] 50 [OP_ADD] 16 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 50\nvar_e = var_c + var_d\nvar_f = 16\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 50\nvar_e = var_c + var_d\nvar_f = 16\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "5944": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 13/12미터(m)인 정삼각형이 있습니다. 이 삼각형의 둘레의 길이는 얼마입니까?",
        "question_en": "There is an equilateral triangle with a side length of 13/12 meters (m). What is the perimeter of this triangle?",
        "answer_ko": "3.25",
        "answer_en": "3.25",
        "solution_abst_ko": "13/12 3 [OP_MUL]",
        "solution_abst_en": "13/12 3 [OP_MUL]",
        "solution_code_ko": "var_a = 1.0833333333333333\nvar_b = 3\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 1.0833333333333333\nvar_b = 3\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "5945": {
        "category": "Comparison",
        "question_ko": "원 모양의 피자가 4개 있습니다. 원주율이 3.1일 때 (가) 피자의 넓이는 314제곱센티미터(㎠)이고, (나) 피자의 원주는 99.2센티미터(㎝)입니다. 또, (다) 피자의 지름은 16센티미터(㎝)이고, (라) 피자의 반지름은 12센티미터(㎝)입니다. 4개의 피자를 넓이가 작은 것부터 차례대로 늘어놓았을 때, 오른쪽에서 2번째에 놓인 피자는 어느 것입니까?",
        "question_en": "There are 4 pizzas in the shape of a circle. When the pi is 3.1, the area of pizza  (a) is 314 cm2 (cm2), and the circumference of pizza (b) is 99.2 cm (cm). Also, the diameter of pizza (c) is 16 cm (cm), and the radius of pizza (d) is 12 centimeters (cm). When 4 pizzas are arranged in order from smallest to largest, which pizza is second from the right?",
        "answer_ko": "(가)",
        "answer_en": "(a)",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) (다) (라) [OP_LIST_EOL] [OP_LIST_SOL] 314 99.2 3.1 [OP_DIV] 2 [OP_DIV] 2 [OP_POW] 3.1 [OP_MUL] 16 2 [OP_DIV] 2 [OP_POW] 3.1 [OP_MUL] 12 2 [OP_POW] 3.1 [OP_MUL] [OP_LIST_EOL] 2 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (a) (b) (c) (d) [OP_LIST_EOL] [OP_LIST_SOL] 314 99.2 3.1 [OP_DIV] 2 [OP_DIV] 2 [OP_POW] 3.1 [OP_MUL] 16 2 [OP_DIV] 2 [OP_POW] 3.1 [OP_MUL] 12 2 [OP_POW] 3.1 [OP_MUL] [OP_LIST_EOL] 2 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nvar_c = '(다)'\nvar_d = '(라)'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 314\nvar_f = 99.2\nvar_g = 3.1\nvar_h = var_f / var_g\nvar_i = 2\nvar_j = var_h / var_i\nvar_k = 2\nvar_l = var_j ** var_k\nvar_m = 3.1\nvar_n = var_l * var_m\nvar_o = 16\nvar_p = 2\nvar_q = var_o / var_p\nvar_r = 2\nvar_s = var_q ** var_r\nvar_t = 3.1\nvar_u = var_s * var_t\nvar_v = 12\nvar_w = 2\nvar_x = var_v ** var_w\nvar_y = 3.1\nvar_z = var_x * var_y\nlist_b= []\nif \"/\" in str(var_z):\n    var_z = eval(str(var_z))\nlist_b.append(var_z)\nif \"/\" in str(var_u):\n    var_u = eval(str(var_u))\nlist_b.append(var_u)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_A = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_B = list_c[var_A-1]\nvar_C = list_b.index(var_B)+1\nvar_D = list_a[var_C-1]\nprint(var_D)",
        "solution_code_en": "var_a = '(a)'\nvar_b = '(b)'\nvar_c = '(c)'\nvar_d = '(d)'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 314\nvar_f = 99.2\nvar_g = 3.1\nvar_h = var_f / var_g\nvar_i = 2\nvar_j = var_h / var_i\nvar_k = 2\nvar_l = var_j ** var_k\nvar_m = 3.1\nvar_n = var_l * var_m\nvar_o = 16\nvar_p = 2\nvar_q = var_o / var_p\nvar_r = 2\nvar_s = var_q ** var_r\nvar_t = 3.1\nvar_u = var_s * var_t\nvar_v = 12\nvar_w = 2\nvar_x = var_v ** var_w\nvar_y = 3.1\nvar_z = var_x * var_y\nlist_b= []\nif \"/\" in str(var_z):\n    var_z = eval(str(var_z))\nlist_b.append(var_z)\nif \"/\" in str(var_u):\n    var_u = eval(str(var_u))\nlist_b.append(var_u)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_A = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_B = list_c[var_A-1]\nvar_C = list_b.index(var_B)+1\nvar_D = list_a[var_C-1]\nprint(var_D)"
    },
    "5946": {
        "category": "Correspondence",
        "question_ko": "18에 어떤 수를 더하여 3으로 나눈 뒤 10을 더하여 5로 나눈 수에 3을 뺀 값이 1입니다. 어떤 수를 구하시오.",
        "question_en": "A number added by 18 divided by 3 added by 10 divided by 5 subtracted by 3 equals 1. Find the number.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "1 3 [OP_ADD] 5 [OP_MUL] 10 [OP_SUB] 3 [OP_MUL] 18 [OP_SUB]",
        "solution_abst_en": "1 3 [OP_ADD] 5 [OP_MUL] 10 [OP_SUB] 3 [OP_MUL] 18 [OP_SUB]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c * var_d\nvar_f = 10\nvar_g = var_e - var_f\nvar_h = 3\nvar_i = var_g * var_h\nvar_j = 18\nvar_k = var_i - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c * var_d\nvar_f = 10\nvar_g = var_e - var_f\nvar_h = 3\nvar_i = var_g * var_h\nvar_j = 18\nvar_k = var_i - var_j\nprint(int(var_k))"
    },
    "5947": {
        "category": "Comparison",
        "question_ko": "남준이는 서점에서 43번째로 책을 샀고, 태형이는 남준이 앞으로 10명보다 더 먼저 책을 샀습니다. 태형이는 몇 번째로 책을 샀습니까?",
        "question_en": "Namjoon was the 43th customer to buy the book at the bookstore, and there were 10 people in front of Namjoon when Taehyung bought the book. In this order, in which position did Taehyung buy the book?",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "43 10 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "43 10 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 43\nvar_b = 10\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 43\nvar_b = 10\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "5948": {
        "category": "Correspondence",
        "question_ko": "다음 식 360÷(A×A×A/B)=5이 가능하게 하는 자연수 B 중 가장 작은 수는 무엇입니까?",
        "question_en": "What is the smallest natural number B that makes the following expression 360÷(A×A×A/B)=5 possible?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "360÷(A×A×A/B)=5 B [OP_NUM_UNK_SOLVER] 1 [OP_LIST_MIN]",
        "solution_abst_en": "360÷(A×A×A/B)=5 B [OP_NUM_UNK_SOLVER] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = '360÷(A×A×A/B)=5'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[var_c-1]\nprint(int(var_d))",
        "solution_code_en": "var_a = '360÷(A×A×A/B)=5'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[var_c-1]\nprint(int(var_d))"
    },
    "5949": {
        "category": "Geometry",
        "question_ko": "몇 개의 작은 정사각형 타일을 가지고 빈틈없이 늘어놓아 큰 정사각형을 만들고 보니 20개의 타일이 남아서 가로 한 변과 세로 한 변을 1열씩 늘리려고 하였더니 9개의 타일이 부족하였습니다. 타일의 개수는 몇 개입니까?",
        "question_en": "When I arranged a few small square tiles without gaps to make a large square, there were 20 tiles left, so I tried to extend each horizontal and vertical side by 1 row to make a larger square, an there were 9 tiles short. How many tiles are there?",
        "answer_ko": "216",
        "answer_en": "216",
        "solution_abst_ko": "20 9 [OP_ADD] 1 [OP_SUB] 2 [OP_DIV] 2 [OP_POW] 20 [OP_ADD]",
        "solution_abst_en": "20 9 [OP_ADD] 1 [OP_SUB] 2 [OP_DIV] 2 [OP_POW] 20 [OP_ADD]",
        "solution_code_ko": "var_a = 20\nvar_b = 9\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 20\nvar_k = var_i + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 20\nvar_b = 9\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 20\nvar_k = var_i + var_j\nprint(int(var_k))"
    },
    "5950": {
        "category": "Arithmetic calculation",
        "question_ko": "도로에 신호등을 설치하려고 합니다. 0.35킬로미터(㎞) 지점에서 0.37킬로미터(㎞) 지점까지 똑같이 4구간으로 나누어 처음부터 끝까지 신호등을 설치한다면 네 번째 지점에 설치하는 신호등의 위치는 몇 킬로미터(㎞) 지점인지 소수로 나타내시오.",
        "question_en": "I want to install traffic lights on the road. If traffic lights are installed from the beginning to the end by dividing them into 4 sections equally from the 0.35 kilometer (km) point to the 0.37 kilometer (km) point, indicate the kilometers (km) of the location of the traffic light installed at the fourth point as a decimal number.",
        "answer_ko": "0.37",
        "answer_en": "0.37",
        "solution_abst_ko": "0.35 0.37 0.35 [OP_SUB] 4 [OP_DIV] 4 1 [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_abst_en": "0.35 0.37 0.35 [OP_SUB] 4 [OP_DIV] 4 1 [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 0.35\nvar_b = 0.37\nvar_c = 0.35\nvar_d = var_b - var_c\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = 4\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = var_f * var_i\nvar_k = var_a + var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 0.35\nvar_b = 0.37\nvar_c = 0.35\nvar_d = var_b - var_c\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = 4\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = var_f * var_i\nvar_k = var_a + var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "5951": {
        "category": "Geometry",
        "question_ko": "작은 정사각형 모양의 수첩을 빈틈없이 늘어놓아 큰 정사각형을 만들었더니 20개의 수첩이 남았습니다. 가로 한 변과 세로 한 변을 1열씩 늘리려고 하였더니 9개의 수첩이 부족하였습니다. 수첩의 개수는 총 몇 개입니까?",
        "question_en": "When the small square-shaped notebooks were arranged to form a large square, there were 20 notebooks left. When I tried to increase the width and height by one row each, 9 notebooks were short. How many notebooks are there in total?",
        "answer_ko": "216",
        "answer_en": "216",
        "solution_abst_ko": "20 9 [OP_ADD] 1 [OP_SUB] 2 [OP_DIV] 2 [OP_POW] 20 [OP_ADD]",
        "solution_abst_en": "20 9 [OP_ADD] 1 [OP_SUB] 2 [OP_DIV] 2 [OP_POW] 20 [OP_ADD]",
        "solution_code_ko": "var_a = 20\nvar_b = 9\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 20\nvar_k = var_i + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 20\nvar_b = 9\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 20\nvar_k = var_i + var_j\nprint(int(var_k))"
    },
    "5952": {
        "category": "Correspondence",
        "question_ko": "33은 어떤 수에 32를 더해야 하는데 잘못하여 빼서 나온 결과이다. 바르게 계산한 결과를 구하여라.",
        "question_en": "33 is the result of subtracting 32 from a number by mistake instead of adding it. Find the result of the correct calculation.",
        "answer_ko": "97",
        "answer_en": "97",
        "solution_abst_ko": "33 32 [OP_ADD] 32 [OP_ADD]",
        "solution_abst_en": "33 32 [OP_ADD] 32 [OP_ADD]",
        "solution_code_ko": "var_a = 33\nvar_b = 32\nvar_c = var_a + var_b\nvar_d = 32\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 33\nvar_b = 32\nvar_c = var_a + var_b\nvar_d = 32\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "5953": {
        "category": "Geometry",
        "question_ko": "100원짜리 동전을 가로로 6개씩, 세로로 4개씩 빈틈없이 늘어놓아 직사각형을 만들었습니다. 둘레에 놓인 동전의 금액은 얼마입니까?",
        "question_en": "A rectangle was created by arranging 6 100-won coins horizontally and 4 vertically. How much amount of money is when you sum up the coins placed around the circumference?",
        "answer_ko": "1600",
        "answer_en": "1600",
        "solution_abst_ko": "6 4 [OP_ADD] 2 [OP_MUL] 4 [OP_SUB] 100 [OP_MUL]",
        "solution_abst_en": "6 4 [OP_ADD] 2 [OP_MUL] 4 [OP_SUB] 100 [OP_MUL]",
        "solution_code_ko": "var_a = 6\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e - var_f\nvar_h = 100\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 6\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e - var_f\nvar_h = 100\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "5954": {
        "category": "Correspondence",
        "question_ko": "A를 5로 나눴을 때 몫이 B, 나머지가 C 였습니다. A, B, C는 자연수 입니다. B와 C가 같을 때, 가능한 A 중 가장 큰 수를 구하시오.",
        "question_en": "When A is divided by 5, the quotient is B and the remainder is C. A, B, and C is natural numbers. If B and C are equal, find the largest possible number of A.",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "5 1 [OP_SUB] 5 [OP_MUL] 5 1 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "5 1 [OP_SUB] 5 [OP_MUL] 5 1 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c * var_d\nvar_f = 5\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 5\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c * var_d\nvar_f = 5\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e + var_h\nprint(int(var_i))"
    },
    "5955": {
        "category": "Arithmetic calculation",
        "question_ko": "겨울철, 배를 굶고 있는 다람쥐 가족을 보았다. 내 주머니에 들어 있는 도토리를 주려고 하니, 한 마리당 4개씩 줄 경우 3개의 도토리가 남았고 5개씩 주자니 6개가 더 필요했다. 내 주머니 속에 들어있는 도토리는 몇 개인가?",
        "question_en": "In winter, you saw a family of hungry squirrels and you are to give the acorns in your pocket. If you give them 4 acorns each, 3 acorns will be left, and if you gave them 5 acrons each, you will need 6 acorns more. How many acorns are there in your pocket?",
        "answer_ko": "39",
        "answer_en": "39",
        "solution_abst_ko": "3 6 [OP_ADD] 5 4 [OP_SUB] [OP_DIV] 4 [OP_MUL] 3 [OP_ADD]",
        "solution_abst_en": "3 6 [OP_ADD] 5 4 [OP_SUB] [OP_DIV] 4 [OP_MUL] 3 [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = 4\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 4\nvar_i = var_g * var_h\nvar_j = 3\nvar_k = var_i + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 3\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = 4\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 4\nvar_i = var_g * var_h\nvar_j = 3\nvar_k = var_i + var_j\nprint(int(var_k))"
    },
    "5956": {
        "category": "Geometry",
        "question_ko": "직사각형의 가로가 4센티미터(㎝)이고 세로가 8센티미터(㎝)인 직사각형이 있다. 직사각형의 둘레에서 4만큼을 빼면 얼마인지 구하시오.",
        "question_en": "There is a rectangle with a width of 4 centimeters (cm) and a length of 8 centimeters (cm). What is the value of the perimeter of the rectangle subtracted by 4?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "4 8 [OP_ADD] 2 [OP_MUL] 4 [OP_SUB]",
        "solution_abst_en": "4 8 [OP_ADD] 2 [OP_MUL] 4 [OP_SUB]",
        "solution_code_ko": "var_a = 4\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "5957": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 6을 곱해야 할 것을 잘못하여 어떤 수를 6으로 나누었더니 몫이 9가 되었습니다. 바르게 계산하면 얼마입니까?",
        "question_en": "I made the mistake of dividing a number by 6, when I should multiply a number by 6, and the quotient was 9. How much do you get when you calculate correctly?",
        "answer_ko": "324",
        "answer_en": "324",
        "solution_abst_ko": "9 6 [OP_MUL] 6 [OP_MUL]",
        "solution_abst_en": "9 6 [OP_MUL] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 9\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "5958": {
        "category": "Possibility",
        "question_ko": "빨간색 공, 파란색 공, 검정색 공이 들어있는 상자에서 공 2개 꺼내려고 합니다. 중복을 허용하여 꺼낼 수 있는 공의 경우의 수는 모두 몇 가지입니까?",
        "question_en": "You want to take 2 balls out of a box that contains a red ball, a blue ball, and a black ball. What is the total number of cases of balls you can take out, allowing for duplicates?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 빨간색 파란색 검정색 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] red blue black [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '빨간색'\nvar_b = '파란색'\nvar_c = '검정색'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = var_d + var_e\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = 2\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j / (i+1)\nprint(int(var_j))",
        "solution_code_en": "var_a = 'red'\nvar_b = 'blue'\nvar_c = 'black'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = var_d + var_e\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = 2\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j / (i+1)\nprint(int(var_j))"
    },
    "5959": {
        "category": "Arithmetic calculation",
        "question_ko": "전체 밧줄의 0.4만큼을 사용하였더니 남은 길이가 0.69미터(m)였다. 처음의 밧줄 길이는 몇 미터(m)인지 구하시오.",
        "question_en": "When 0.4 of the total rope was used, the remaining length was 0.69 m (m). Find the length of the first rope in meters (m).",
        "answer_ko": "1.15",
        "answer_en": "1.15",
        "solution_abst_ko": "0.69 1 0.4 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "0.69 1 0.4 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 0.69\nvar_b = 1\nvar_c = 0.4\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.69\nvar_b = 1\nvar_c = 0.4\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "5960": {
        "category": "Geometry",
        "question_ko": "어떤 정육면체의 부피는 1000세제곱센티미터(㎤)입니다. 이 정육면체를 8개의 정육면체로 나누었을 때, 나눠진 정육면체의 한 모서리의 길이를 구하시오.",
        "question_en": "The volume of a cube is 1000 cubic centimeters (cm3). When this cube is divided into 8 cubes, find the length of one edge of the divided cube.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "1000 8 [OP_DIV] 1/3 [OP_POW]",
        "solution_abst_en": "1000 8 [OP_DIV] 1/3 [OP_POW]",
        "solution_code_ko": "var_a = 1000\nvar_b = 8\nvar_c = var_a / var_b\nvar_d = 0.3333333333333333\nvar_e = var_c ** var_d\nprint(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))",
        "solution_code_en": "var_a = 1000\nvar_b = 8\nvar_c = var_a / var_b\nvar_d = 0.3333333333333333\nvar_e = var_c ** var_d\nprint(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))"
    },
    "5961": {
        "category": "Geometry",
        "question_ko": "서로 다른 세 면의 넓이가 각각 4제곱센티미터(㎠) , 3제곱센티미터(㎠) , 6제곱센티미터(㎠)인 직육면체가 있습니다. 이 직육면체의 겉넓이는 몇 제곱센티미터(㎠)입니까?",
        "question_en": "A rectangular parallelepiped has three distinct sides with each surface area of 4 square centimeters (cm2), 3 square centimeters (cm2), and 6 square centimeters (cm2). What is the surface area of this cuboid in square centimeters (cm2)?",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "4 3 6 [OP_ADD] [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "4 3 6 [OP_ADD] [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 4\nvar_b = 3\nvar_c = 6\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 3\nvar_c = 6\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "5962": {
        "category": "Comparison",
        "question_ko": "지민이는 줄넘기를 세 번의 세트 동안 각각 80번, 75번, 85번 하였습니다. 석진이는 줄넘기를 첫번재 세트와 두번째 세트에 각각 78번, 74번 하였다면 석진이가 지민이보다 줄넘기를 많이 하기 위해선 세번째 세트에 몇 번을 해야 합니까?",
        "question_en": "Jimin jumped rope 80, 75, and 85 times during the three sets, respectively. If Seokjin jumped rope 78 times in the first set and 74 times in the second set, then how many times does Seokjin need to jump rope in the third set in order to jump rope more than Jimin?",
        "answer_ko": "89",
        "answer_en": "89",
        "solution_abst_ko": "80 75 [OP_ADD] 85 [OP_ADD] 78 74 [OP_ADD] [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "80 75 [OP_ADD] 85 [OP_ADD] 78 74 [OP_ADD] [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 80\nvar_b = 75\nvar_c = var_a + var_b\nvar_d = 85\nvar_e = var_c + var_d\nvar_f = 78\nvar_g = 74\nvar_h = var_f + var_g\nvar_i = var_e - var_h\nvar_j = 1\nvar_k = var_i + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 80\nvar_b = 75\nvar_c = var_a + var_b\nvar_d = 85\nvar_e = var_c + var_d\nvar_f = 78\nvar_g = 74\nvar_h = var_f + var_g\nvar_i = var_e - var_h\nvar_j = 1\nvar_k = var_i + var_j\nprint(int(var_k))"
    },
    "5963": {
        "category": "Correspondence",
        "question_ko": "A85-B1=364입니다. A는 얼마인가요?",
        "question_en": "A85-B1=364 is true. How much is A?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "A85-B1=364 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A85-B1=364 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A85-B1=364'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A85-B1=364'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "5964": {
        "category": "Arithmetic calculation",
        "question_ko": "기차가 정차하는 첫번재 역에서 17명이 타고 29명이 내렸습니다. 다음 역에서 27명이 내리고 35명이 탄 후 기차에 타고 있는 사람의 수를 세보았더니 116명이었습니다. 처음에 출발할 때 기차에 타고 있던 사람은 몇 명입니까?",
        "question_en": "At the first station where the train stops, 17 people got on and 29 got off. At the next station, after 27 people got off and 35 got on, I counted the number of people on the train, which was 116. How many people were on the train at first?",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "116 29 [OP_ADD] 17 [OP_SUB] 27 [OP_ADD] 35 [OP_SUB]",
        "solution_abst_en": "116 29 [OP_ADD] 17 [OP_SUB] 27 [OP_ADD] 35 [OP_SUB]",
        "solution_code_ko": "var_a = 116\nvar_b = 29\nvar_c = var_a + var_b\nvar_d = 17\nvar_e = var_c - var_d\nvar_f = 27\nvar_g = var_e + var_f\nvar_h = 35\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 116\nvar_b = 29\nvar_c = var_a + var_b\nvar_d = 17\nvar_e = var_c - var_d\nvar_f = 27\nvar_g = var_e + var_f\nvar_h = 35\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "5965": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 10미터(m)인 정삼각형 모양의 놀이터가 있습니다. 놀이터의 둘레에 3미터(m) 간격으로 가로등을 설치한다고 할 때, 모두 몇 개의 가로등이 설치되는지 구하시오.",
        "question_en": "There is a playground in the shape of an equilateral triangle with a side length of 10 meters (m). If street lights are installed at intervals of 3 meters (m) around the playground, find how many street lights have to be installed in all.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "10 3 [OP_MUL] 3 [OP_FDIV]",
        "solution_abst_en": "10 3 [OP_MUL] 3 [OP_FDIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "5966": {
        "category": "Correspondence",
        "question_ko": "숫자 A567을 십의 자리에서 버림하면 2560의 값을 얻을 수 있습니다. A는 어떤 값입니까?",
        "question_en": "If we round down the number A567 to the nearest tens, we get a value of 2560. What value is A?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "A567 [OP_GEN_POSSIBLE_LIST] 2560 [OP_LIST_MORE_EQUAL] 2560 10 [OP_ADD] [OP_LIST_LESS] A567 A [OP_LIST_FIND_UNK]",
        "solution_abst_en": "A567 [OP_GEN_POSSIBLE_LIST] 2560 [OP_LIST_MORE_EQUAL] 2560 10 [OP_ADD] [OP_LIST_LESS] A567 A [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = 'A567'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 2560\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 2560\nvar_d = 10\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = 'A567'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))",
        "solution_code_en": "var_a = 'A567'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 2560\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 2560\nvar_d = 10\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = 'A567'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))"
    },
    "5967": {
        "category": "Comparison",
        "question_ko": "동균이는 정국이보다 키가 크며 동욱이는 정국이보다 키가 큽니다. 동욱이와 동균이의 키를 비교했더니 동욱이가 더 작았다면 키가 가장 큰 사람은 누구입니까?",
        "question_en": "Dongkyun is taller than Jungkook and Dongwook is taller than Jungkook. If you compared the heights of Dongwook and Dongkyun, and Dongwook was shorter, who was the tallest?",
        "answer_ko": "동균",
        "answer_en": "Dongkyun",
        "solution_abst_ko": "[OP_LIST_SOL] 동균 정국 동욱 [OP_LIST_EOL] [OP_LIST_SOL] 동균 정국 > 동욱 정국 > 동욱 동균 < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Dongkyun Jungkook Dongwook [OP_LIST_EOL] [OP_LIST_SOL] Dongkyun Jungkook > Dongwook Jungkook > Dongwook Dongkyun < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '동균'\nvar_b = '정국'\nvar_c = '동욱'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '동균'\nvar_e = '정국'\nvar_f = '>'\nvar_g = '동욱'\nvar_h = '정국'\nvar_i = '>'\nvar_j = '동욱'\nvar_k = '동균'\nvar_l = '<'\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_m = 1\nvar_n = list_c[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'Dongkyun'\nvar_b = 'Jungkook'\nvar_c = 'Dongwook'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'Dongkyun'\nvar_e = 'Jungkook'\nvar_f = '>'\nvar_g = 'Dongwook'\nvar_h = 'Jungkook'\nvar_i = '>'\nvar_j = 'Dongwook'\nvar_k = 'Dongkyun'\nvar_l = '<'\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_m = 1\nvar_n = list_c[var_m-1]\nprint(var_n)"
    },
    "5968": {
        "category": "Arithmetic calculation",
        "question_ko": "한 반에 있는 학생들에게 인형을 주려고 한다. 한 명당 4개씩 주니 3개의 인형이 남았고, 5개씩 주니 6개가 부족했다. 이 반에 있는 학생은 총 몇 명인가?",
        "question_en": "You want to give dolls to students in a class. There were 3 dolls left when 4 dolls were distributed to each person, and 6 were in short when 5 dolls were given to each one. What is the total number of students in this class?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "3 6 [OP_ADD] 5 4 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "3 6 [OP_ADD] 5 4 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 3\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = 4\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 3\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = 4\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))"
    },
    "5969": {
        "category": "Geometry",
        "question_ko": "상자에는 10개의 공이 있습니다. 윤기가 상자에서 공을 3개 가져갔을 때, 남은 공의 개수는 몇 개입니까?",
        "question_en": "There are 10 balls in the box. When Yoongi takes 3 balls from the box, how many balls are left?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "10 3 [OP_SUB]",
        "solution_abst_en": "10 3 [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 10\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "5970": {
        "category": "Possibility",
        "question_ko": "오영이는 연재 잡지를 1월에서 5월까지 총 5권을 샀다. 1월호, 3월호, 5월호를 순서대로 책꽂이에 제일 오른쪽에 꽂을 때, 5권의 책을 책꽃이에 한 줄로 꽂는 경우의 수를 구하시오. (단, 책꽂이는 1줄이다.)",
        "question_en": "Ohyoung bought a total of 5 serial magazines from January to May. Find the number of cases in which 5 books are placed in a row on the shelf when the January, March, and May issues are placed on the rightmost shelf in that order. (However, there is only one row of bookshelves.)",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "5 [OP_LIST_SOL] 1 3 5 [OP_LIST_EOL] [OP_LIST_LEN] [OP_SUB] 5 [OP_LIST_SOL] 1 3 5 [OP_LIST_EOL] [OP_LIST_LEN] [OP_SUB] [OP_PERM]",
        "solution_abst_en": "5 [OP_LIST_SOL] 1 3 5 [OP_LIST_EOL] [OP_LIST_LEN] [OP_SUB] 5 [OP_LIST_SOL] 1 3 5 [OP_LIST_EOL] [OP_LIST_LEN] [OP_SUB] [OP_PERM]",
        "solution_code_ko": "var_a = 5\nvar_b = 1\nvar_c = 3\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = var_a - var_e\nvar_g = 5\nvar_h = 1\nvar_i = 3\nvar_j = 5\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nlist_b.reverse()\nvar_k = len(list_b)\nvar_l = var_g - var_k\nvar_m = 1\nvar_f = int(var_f)\nvar_l = int(var_l)\nfor i, elem in enumerate(range(var_l)):\n    var_m = var_m * (var_f-i)\nprint(int(var_m))",
        "solution_code_en": "var_a = 5\nvar_b = 1\nvar_c = 3\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = var_a - var_e\nvar_g = 5\nvar_h = 1\nvar_i = 3\nvar_j = 5\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nlist_b.reverse()\nvar_k = len(list_b)\nvar_l = var_g - var_k\nvar_m = 1\nvar_f = int(var_f)\nvar_l = int(var_l)\nfor i, elem in enumerate(range(var_l)):\n    var_m = var_m * (var_f-i)\nprint(int(var_m))"
    },
    "5971": {
        "category": "Correspondence",
        "question_ko": "네 자리 수 5716은 571A보다 큽니다. A는 일의 자리 숫자이고 A에는 0부터 9까지의 숫자를 쓸 수 있습니다. A에 쓸 수 있는 숫자는 모두 몇 개입니까?",
        "question_en": "The four digit number 5716 is greater than 571A. Given that A is the ones digit and can contain any number from 0 to 9, how many digits can be written in A?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "571A [OP_GEN_POSSIBLE_LIST] 5716 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "571A [OP_GEN_POSSIBLE_LIST] 5716 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '571A'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 5716\nlist_b = []\nfor i in list_a:\n    if i < var_b:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))",
        "solution_code_en": "var_a = '571A'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 5716\nlist_b = []\nfor i in list_a:\n    if i < var_b:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))"
    },
    "5972": {
        "category": "Arithmetic calculation",
        "question_ko": "탁구공 2개씩 7묶음을 하나의 상자에 넣어서 보관하여 한다. 탁구공이 182개 일 때, 상자가 몇 개가 필요할지 구하시오.",
        "question_en": "7 bundles of 2 ping-pong balls are put into one box and stored. If there are 182 ping-pong balls, how many boxes are needed?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "182 7 2 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "182 7 2 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 182\nvar_b = 7\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 182\nvar_b = 7\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "5973": {
        "category": "Comparison",
        "question_ko": "경석이는 일주일에 국어를 2/3시간씩 7번 공부하고 수학을 3/4시간씩 5번 공부합니다. 경석이는 일주일 동안 국어와 수학 중 어느 과목을 더 공부하는지 구하시오.",
        "question_en": "Kyung-seok studies Korean 7 times a week for 2/3 hours and Math 5 times a week for 3/4 hours. Find out which subject Kyung-seok studies more during the week, Korean or Math.",
        "answer_ko": "국어",
        "answer_en": "Korean",
        "solution_abst_ko": "[OP_LIST_SOL] 국어 수학 [OP_LIST_EOL] [OP_LIST_SOL] 2/3 7 [OP_MUL] 3/4 5 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Korean Math [OP_LIST_EOL] [OP_LIST_SOL] 2/3 7 [OP_MUL] 3/4 5 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '국어'\nvar_b = '수학'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.6666666666666666\nvar_d = 7\nvar_e = var_c * var_d\nvar_f = 0.75\nvar_g = 5\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Korean'\nvar_b = 'Math'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.6666666666666666\nvar_d = 7\nvar_e = var_c * var_d\nvar_f = 0.75\nvar_g = 5\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "5974": {
        "category": "Arithmetic calculation",
        "question_ko": "36보다 작고 29보다 큰 두 자리 수는 모두 몇 개입니까?",
        "question_en": "Find out how many two-digit numbers exist that are less than 36 and greater than 29.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "29 1 [OP_ADD] 36 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_LEN]",
        "solution_abst_en": "29 1 [OP_ADD] 36 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 29\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 36\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = len(list_a)\nprint(int(var_h))",
        "solution_code_en": "var_a = 29\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 36\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = len(list_a)\nprint(int(var_h))"
    },
    "5975": {
        "category": "Geometry",
        "question_ko": "원의 지름의 길이를 구하려고 합니다. 반지름의 길이가 7센티미터(㎝)일 때, 지름의 길이는 몇 센티미터(㎝)인가요?",
        "question_en": "You want to find the length of the diameter of a circle. If the length of the radius is 7 centimeters (cm), what is the length of the diameter in centimeters (cm)?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "7 2 [OP_MUL]",
        "solution_abst_en": "7 2 [OP_MUL]",
        "solution_code_ko": "var_a = 7\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 7\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "5976": {
        "category": "Possibility",
        "question_ko": "숫자 카드 1, 6, 8를 한 번씩 모두 사용하여 두 번째로 작은 세 자리 수와 세 번째로 작은 세 자리수의 합을 구하시오.",
        "question_en": "Using the number cards 1, 6, and 8 all once, find the sum of the second smallest three-digit number and the third smallest three-digit number.",
        "answer_ko": "804",
        "answer_en": "804",
        "solution_abst_ko": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MIN] 3 [OP_LIST_GET] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MIN] 3 [OP_LIST_GET] [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = 3\nvar_h = list_b[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = 3\nvar_h = list_b[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))"
    },
    "5977": {
        "category": "Possibility",
        "question_ko": "1, 3, 4 중에서 서로 다른 숫자 2개를 뽑아 만들 수 있는 두 자리 수는 모두 몇 개입니까?",
        "question_en": "How many two-digit numbers can be formed by selecting two different numbers from 1, 3, and 4?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 4 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 4 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 4\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 4\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "5978": {
        "category": "Correspondence",
        "question_ko": "901개의 바둑알이 있다. 오목 한판을 하기 위해 총 53개의 바둑알이 필요하다고 하면 동시에 몇 판의 오목을 진행할 수 있는지 구하시오.",
        "question_en": "There are 901 Go stones. If a total of 53 Go stones are required to play a round of Gomok, how many rounds of Gomok can be played at the same time?",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "901 53 [OP_DIV]",
        "solution_abst_en": "901 53 [OP_DIV]",
        "solution_code_ko": "var_a = 901\nvar_b = 53\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 901\nvar_b = 53\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "5979": {
        "category": "Possibility",
        "question_ko": "천의 자리 숫자가 3이고, 각 자리 숫자에 3, 4, 9, 8이 모두 들어있는 네 자리 수는 모두 몇 개 입니까?",
        "question_en": "How many four-digit numbers that contain all digits of 3, 4, 9, 8 and with 3 in the thousands digit are there?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 3 4 9 8 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1000 3 [OP_LIST_SEARCH_FIXED_DIGIT] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 3 4 9 8 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1000 3 [OP_LIST_SEARCH_FIXED_DIGIT] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 3\nvar_b = 4\nvar_c = 9\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1000\nvar_g = 3\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = len(list_c)\nprint(int(var_h))",
        "solution_code_en": "var_a = 3\nvar_b = 4\nvar_c = 9\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1000\nvar_g = 3\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = len(list_c)\nprint(int(var_h))"
    },
    "5980": {
        "category": "Comparison",
        "question_ko": "윤기는 4, 정국이는 6에서 3을 나눈 몫을 모았습니다. 누가 더 작은 수를 모았습니까?",
        "question_en": "Yoongi has 4, and Jungkook has the number that is calculated by 6 divided by 3. Who got the smaller number?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_FDIV] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_FDIV] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 6\nvar_e = 3\nvar_f = var_d // var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 6\nvar_e = 3\nvar_f = var_d // var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "5981": {
        "category": "Correspondence",
        "question_ko": "A, B는 한 자리 수입니다. 다섯 자리 수 A835B는 12의 배수입니다. 가능한 A835B의 수 중에서 가장 큰 수와 가장 작은 수의 차는 무엇입니까?",
        "question_en": "A and B are single digit numbers, and five-digit number of A835B is a multiple of 12. What is the difference between the largest and smallest of the possible numbers of A835B?",
        "answer_ko": "69996",
        "answer_en": "69996",
        "solution_abst_ko": "A835B [OP_GEN_POSSIBLE_LIST] 12 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "A835B [OP_GEN_POSSIBLE_LIST] 12 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 'A835B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 12\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_d = list_c[-var_c]\nvar_e = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_f = list_d[var_e-1]\nvar_g = var_d - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 'A835B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 12\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_d = list_c[-var_c]\nvar_e = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_f = list_d[var_e-1]\nvar_g = var_d - var_f\nprint(int(var_g))"
    },
    "5982": {
        "category": "Geometry",
        "question_ko": "넓이가 215.6제곱미터(㎡)인 직사각형 모양의 방이 있습니다. 이 방의 가로 길이를 쟀더니 14미터(m)가 나왔고, 세로 길이를 재려는 순간 줄자가 고장났습니다. 방의 넓이가 215.6제곱미터(㎡)라는 정보를 이용해 세로 길이를 구하면 얼마입니까?",
        "question_en": "There is a rectangular room with an area of 215.6 square meters (m2). When I measured the width of this room, it came out to be 14 meters (m), and the moment I tried to measure the length, the tape measure broke. If you use the information that the area of the room is 215.6 square meters (m2), how much is the vertical length?",
        "answer_ko": "15.40",
        "answer_en": "15.4",
        "solution_abst_ko": "215.6 14 [OP_DIV]",
        "solution_abst_en": "215.6 14 [OP_DIV]",
        "solution_code_ko": "var_a = 215.6\nvar_b = 14\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 215.6\nvar_b = 14\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "5983": {
        "category": "Geometry",
        "question_ko": "미영은 한 변의 길이가 10센티미터(㎝)인 정사각형 모양의 초콜릿을 가지고 있습니다. 이 초콜릿을 가로가 1센티미터(㎝), 높이가 3센티미터(㎝)인 직각삼각형 모양으로 여러개 잘라 친구들에게 나누어주려고 합니다. 최대 몇 개의 직각삼각형 모양 초콜릿을 나누어줄 수 있겠습니까?",
        "question_en": "Miyoung has a square-shaped piece of chocolate with a side measuring 10 centimeters (cm). She is going to cut this chocolate into right triangle-shaped pieces with a width of 1 centimeter (cm) and a height of 3 centimeters (cm) and hand them out to her friends. How many right triangle-shaped chocolate pieces can she hand out?",
        "answer_ko": "66",
        "answer_en": "66",
        "solution_abst_ko": "10 2 [OP_POW] 1 3 [OP_MUL] [OP_FDIV] 2 [OP_MUL]",
        "solution_abst_en": "10 2 [OP_POW] 1 3 [OP_MUL] [OP_FDIV] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 1\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c // var_f\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 1\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c // var_f\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "5984": {
        "category": "Arithmetic calculation",
        "question_ko": "아이스크림을 사기 위해 가게 앞에 사람들이 한 줄로 줄을 섰습니다. 맨 앞에 서 있는 사람과 맨 뒤에 서있는 사람 사이에 5명이 서 있습니다. 줄을 선 사람은 모두 몇 명입니까?",
        "question_en": "People lined up in front of the store to buy ice cream. Five people stand between the person standing at the front and the person standing at the last. How many people are in line?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "5 2 [OP_ADD]",
        "solution_abst_en": "5 2 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "5985": {
        "category": "Correspondence",
        "question_ko": "우유 160병, 사과 197개, 빵 229개를 마을 사람들에게 똑같이 나누어주면 우유는 4병이 남고, 사과는 2개가 남고, 빵은 5개가 부족하다고 한다. 이떄 마을 사람들은 최대 몇 명인가?",
        "question_en": "If you distribute 160 bottles of milk, 197 apples, and 229 bread equally to the villagers, you will have 4 bottles of milk left, 2 apples left, and 5 bread short. How many villagers are there at this time?",
        "answer_ko": "39",
        "answer_en": "39",
        "solution_abst_ko": "197 2 [OP_SUB] 160 4 [OP_SUB] [OP_GCD] 229 5 [OP_ADD] [OP_GCD]",
        "solution_abst_en": "197 2 [OP_SUB] 160 4 [OP_SUB] [OP_GCD] 229 5 [OP_ADD] [OP_GCD]",
        "solution_code_ko": "var_a = 197\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 160\nvar_e = 4\nvar_f = var_d - var_e\nvar_g = math.gcd(int(var_f), int(var_c))\nvar_h = 229\nvar_i = 5\nvar_j = var_h + var_i\nvar_k = math.gcd(int(var_j), int(var_g))\nprint(int(var_k))",
        "solution_code_en": "var_a = 197\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 160\nvar_e = 4\nvar_f = var_d - var_e\nvar_g = math.gcd(int(var_f), int(var_c))\nvar_h = 229\nvar_i = 5\nvar_j = var_h + var_i\nvar_k = math.gcd(int(var_j), int(var_g))\nprint(int(var_k))"
    },
    "5986": {
        "category": "Arithmetic calculation",
        "question_ko": "시장에서 생선을 살 때 8000원어치를 사면 1200원을 할인해 준다고 합니다. 생선을 15000원어치 사면 얼마를 할인받을 수 있을까요?",
        "question_en": "When you buy fish at the market, if you buy 8,000 won worth of fish, you get a 1,200 won discount. How much discount can I get if I buy 15,000 won worth of fish?",
        "answer_ko": "2250",
        "answer_en": "2250",
        "solution_abst_ko": "1200 8000 [OP_DIV] 15000 [OP_MUL]",
        "solution_abst_en": "1200 8000 [OP_DIV] 15000 [OP_MUL]",
        "solution_code_ko": "var_a = 1200\nvar_b = 8000\nvar_c = var_a / var_b\nvar_d = 15000\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 1200\nvar_b = 8000\nvar_c = var_a / var_b\nvar_d = 15000\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "5987": {
        "category": "Correspondence",
        "question_ko": "어떤 소수의 소수점을 오른쪽으로 두 칸 옮기면 원래 소수에서 138.6을 더한 값이 됩니다. 원래의 소수를 구하시오.",
        "question_en": "Moving a decimal point two places to the right equals 138.6 added to the original decimal. Find the original prime number.",
        "answer_ko": "1.40",
        "answer_en": "1.4",
        "solution_abst_ko": "138.6 10 2 [OP_POW] 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "138.6 10 2 [OP_POW] 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 138.6\nvar_b = 10\nvar_c = 2\nvar_d = var_b ** var_c\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_a / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 138.6\nvar_b = 10\nvar_c = 2\nvar_d = var_b ** var_c\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_a / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "5988": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 가게에서 파는 수박이 5만원보다 2천원 쌀 때, 수박의 가격을 만원 단위로 구하시오.",
        "question_en": "If a watermelon sold at a store is 2,000 won cheaper than 50,000 won, find the price of the watermelon in the unit of ten thousand won.",
        "answer_ko": "4.80",
        "answer_en": "4.8",
        "solution_abst_ko": "5 2 10 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "5 2 10 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = 10\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = 10\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "5989": {
        "category": "Geometry",
        "question_ko": "밑에 놓인 면의 둘레가 32센티미터(㎝)이고, 높이가 9센티미터(㎝)인 직육면체 중에서 밑에 놓인 면의 넓이가 가장 큰 직육면체의 부피는 몇 세제곱센티미터(㎤)입니까?",
        "question_en": "What is the volume, in cubic centimeters (cm³), of the rectangular prism with a base perimeter of 32 centimeters (cm) and a height of 9 centimeters (cm), where the base has the maximum possible area?",
        "answer_ko": "576",
        "answer_en": "576",
        "solution_abst_ko": "32 4 [OP_DIV] 2 [OP_POW] 9 [OP_MUL]",
        "solution_abst_en": "32 4 [OP_DIV] 2 [OP_POW] 9 [OP_MUL]",
        "solution_code_ko": "var_a = 32\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 9\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 32\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 9\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "5990": {
        "category": "Correspondence",
        "question_ko": "3+68A=691일 때, A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "When 3+68A=691, what number should be in A, where 68A is three-digit number?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "3+68A=691 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "3+68A=691 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '3+68A=691'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '3+68A=691'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "5991": {
        "category": "Correspondence",
        "question_ko": "어떤 수와 6의 곱에 17을 더한 수를 5로 나누었더니 25가 되었습니다. 어떤 수에서 14를 뺀 값을 구하시오.",
        "question_en": "A number multiplied by 6 plus 17 divided by 5 equals 25. Find the value of a number minus 14.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "25 5 [OP_MUL] 17 [OP_SUB] 6 [OP_DIV] 14 [OP_SUB]",
        "solution_abst_en": "25 5 [OP_MUL] 17 [OP_SUB] 6 [OP_DIV] 14 [OP_SUB]",
        "solution_code_ko": "var_a = 25\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 17\nvar_e = var_c - var_d\nvar_f = 6\nvar_g = var_e / var_f\nvar_h = 14\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 25\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 17\nvar_e = var_c - var_d\nvar_f = 6\nvar_g = var_e / var_f\nvar_h = 14\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "5992": {
        "category": "Comparison",
        "question_ko": "무게가 0.2킬로그램(㎏)인 바구니에 무게가 같은 메론 3 개를 담으면 바구니의 무게는 2.51킬로그램(㎏) 이며, 무게가 같은 사과 5 개를 담으면 바구니의 무게는 2.9킬로그램(㎏)입니다. 사과 한 개와 메론 한 개 중 어느 것이 더 무거운지 구하시오.",
        "question_en": "If a basket weighing 0.2 kilograms (kg) contains 3 melons of the same weight, the basket weighs 2.51 kilograms (kg), and if it contains 5 apples of the same weight, the basket weighs 2.9 kilograms (kg). Find which is heavier: an apple or a melon.",
        "answer_ko": "메론",
        "answer_en": "melon",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 메론 [OP_LIST_EOL] [OP_LIST_SOL] 2.9 0.2 [OP_SUB] 5 [OP_DIV] 2.51 0.2 [OP_SUB] 3 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] apple melon [OP_LIST_EOL] [OP_LIST_SOL] 2.9 0.2 [OP_SUB] 5 [OP_DIV] 2.51 0.2 [OP_SUB] 3 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '메론'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2.9\nvar_d = 0.2\nvar_e = var_c - var_d\nvar_f = 5\nvar_g = var_e / var_f\nvar_h = 2.51\nvar_i = 0.2\nvar_j = var_h - var_i\nvar_k = 3\nvar_l = var_j / var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'apple'\nvar_b = 'melon'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2.9\nvar_d = 0.2\nvar_e = var_c - var_d\nvar_f = 5\nvar_g = var_e / var_f\nvar_h = 2.51\nvar_i = 0.2\nvar_j = var_h - var_i\nvar_k = 3\nvar_l = var_j / var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "5993": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 37로 나누면 몫은 2이고 나머지가 26이다. 48에서 어떤 수를 4로 나눈 몫을 뺀 값을 구하시오.",
        "question_en": "When a number is divided by 37, the quotient is 2 and the remainder is 26. Find the value of 48 minus the quotient of a number divided by 4.",
        "answer_ko": "23",
        "answer_en": "23",
        "solution_abst_ko": "48 37 2 [OP_MUL] 26 [OP_ADD] 4 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "48 37 2 [OP_MUL] 26 [OP_ADD] 4 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 48\nvar_b = 37\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = 26\nvar_f = var_d + var_e\nvar_g = 4\nvar_h = var_f / var_g\nvar_i = var_a - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 48\nvar_b = 37\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = 26\nvar_f = var_d + var_e\nvar_g = 4\nvar_h = var_f / var_g\nvar_i = var_a - var_h\nprint(int(var_i))"
    },
    "5994": {
        "category": "Comparison",
        "question_ko": "남준이는 시험에서 2등을 했고, 남준이가 들어가고 난 후 4번째에 윤기가 들어갔습니다. 윤기 뒤의 3번째에 호석이가 들어왔습니다. 호석이는 몇 등입니까?",
        "question_en": "In the running race, Namjoon came in second, and after Namjoon came in, four more people came in, and then Yoongi came in. Hoseok came in after Yoongi and three more people came in. What is Hoseok's rank?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "2 4 [OP_ADD] 3 [OP_ADD]",
        "solution_abst_en": "2 4 [OP_ADD] 3 [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "5995": {
        "category": "Comparison",
        "question_ko": "0.34, 2/4, 9/11, 0.22, 0.76 중 가장 큰 수와 가장 작은 수의 곱을 구합니다.",
        "question_en": "Find the product of the largest number and smallest number multiplied among 0.34, 2/4, 9/11, 0.22, and 0.76.",
        "answer_ko": "0.18",
        "answer_en": "0.18",
        "solution_abst_ko": "[OP_LIST_SOL] 0.34 2 4 [OP_DIV] 9 11 [OP_DIV] 0.22 0.76 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 0.34 2 4 [OP_DIV] 9 11 [OP_DIV] 0.22 0.76 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MUL]",
        "solution_code_ko": "var_a = 0.34\nvar_b = 2\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = 9\nvar_f = 11\nvar_g = var_e / var_f\nvar_h = 0.22\nvar_i = 0.76\nlist_a= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_j = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_k = list_b[-var_j]\nvar_l = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_m = list_c[var_l-1]\nvar_n = var_k * var_m\nprint('{:.2f}'.format(round(var_n+1e-10,2)))",
        "solution_code_en": "var_a = 0.34\nvar_b = 2\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = 9\nvar_f = 11\nvar_g = var_e / var_f\nvar_h = 0.22\nvar_i = 0.76\nlist_a= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_j = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_k = list_b[-var_j]\nvar_l = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_m = list_c[var_l-1]\nvar_n = var_k * var_m\nprint('{:.2f}'.format(round(var_n+1e-10,2)))"
    },
    "5996": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 15로 나눈 다음 74를 더해야하는데 잘못하여 5로 나눈 다음 16을 더했더니 58이 나왔습니다. 바르게 계산한 값을 구하시오.",
        "question_en": "You get a wrong answer 58 when the division of a number by 5 is added by 16. If the correct calculation should be a number divided by 15 and then added by 74, what would be the right answer?",
        "answer_ko": "88",
        "answer_en": "88",
        "solution_abst_ko": "58 16 [OP_SUB] 5 [OP_MUL] 15 [OP_DIV] 74 [OP_ADD]",
        "solution_abst_en": "58 16 [OP_SUB] 5 [OP_MUL] 15 [OP_DIV] 74 [OP_ADD]",
        "solution_code_ko": "var_a = 58\nvar_b = 16\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c * var_d\nvar_f = 15\nvar_g = var_e / var_f\nvar_h = 74\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 58\nvar_b = 16\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c * var_d\nvar_f = 15\nvar_g = var_e / var_f\nvar_h = 74\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "5997": {
        "category": "Comparison",
        "question_ko": "무게가 250그램(g)인 상자에 모래를 가득 넣어 무게를 재었더니 1킬로그램(㎏) 780그램(g)이었고 무게가 460그램(g)인 통에 모래를 가득 넣어 무게를 재었더니 2킬로그램(㎏) 250그램(g)이었습니다. 상자와 통 중 어느 것에 들어 있는 모래가 더 무겁습니까?",
        "question_en": "When a box weighing 250 grams (g) was filled with sand and weighed, it was 1 kg (kg) 780 grams (g). When a bucket weighing 460 grams (g) was filled with sand and weighed, it was 2 kg (kg) 250 grams (g). Which is heavier, the sand in the box or that in the bucket?",
        "answer_ko": "통",
        "answer_en": "bucket",
        "solution_abst_ko": "[OP_LIST_SOL] 상자 통 [OP_LIST_EOL] [OP_LIST_SOL] 1 1000 [OP_MUL] 780 [OP_ADD] 250 [OP_SUB] 2 1000 [OP_MUL] 250 [OP_ADD] 460 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] box bucket [OP_LIST_EOL] [OP_LIST_SOL] 1 1000 [OP_MUL] 780 [OP_ADD] 250 [OP_SUB] 2 1000 [OP_MUL] 250 [OP_ADD] 460 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '상자'\nvar_b = '통'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 780\nvar_g = var_e + var_f\nvar_h = 250\nvar_i = var_g - var_h\nvar_j = 2\nvar_k = 1000\nvar_l = var_j * var_k\nvar_m = 250\nvar_n = var_l + var_m\nvar_o = 460\nvar_p = var_n - var_o\nlist_b= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nlist_b.reverse()\nvar_q = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_r = list_c[-var_q]\nvar_s = list_b.index(var_r)+1\nvar_t = list_a[var_s-1]\nprint(var_t)",
        "solution_code_en": "var_a = 'box'\nvar_b = 'bucket'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 780\nvar_g = var_e + var_f\nvar_h = 250\nvar_i = var_g - var_h\nvar_j = 2\nvar_k = 1000\nvar_l = var_j * var_k\nvar_m = 250\nvar_n = var_l + var_m\nvar_o = 460\nvar_p = var_n - var_o\nlist_b= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nlist_b.reverse()\nvar_q = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_r = list_c[-var_q]\nvar_s = list_b.index(var_r)+1\nvar_t = list_a[var_s-1]\nprint(var_t)"
    },
    "5998": {
        "category": "Geometry",
        "question_ko": "밑면의 넓이가 10제곱센티미터(㎠)이고, 높이가 각각 4센티미터(㎝), 7센티미터(㎝), 6센티미터(㎝), 9센티미터(㎝), 2센티미터(㎝)인 직육면체가 5개 있습니다. 이 중 부피가 50세제곱센티미터(㎤) 이하인 도형은 몇 개입니까?",
        "question_en": "There are five cuboids each with a height of 4 centimeters (cm), 7 centimeters (cm), 6 centimeters (cm), 9 centimeters (cm), and 2 centimeters (cm), and with a base area of 10 square centimeters (cm2). How many of these cuboids have a volume of 50 cubic centimeters (cm3) or less?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 4 7 6 9 2 [OP_LIST_EOL] 50 10 [OP_DIV] [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 4 7 6 9 2 [OP_LIST_EOL] 50 10 [OP_DIV] [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 4\nvar_b = 7\nvar_c = 6\nvar_d = 9\nvar_e = 2\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 50\nvar_g = 10\nvar_h = var_f / var_g\nlist_b = []\nfor i in list_a:\n    if i <= var_h:\n        list_b.append(i)\nvar_i = len(list_b)\nprint(int(var_i))",
        "solution_code_en": "var_a = 4\nvar_b = 7\nvar_c = 6\nvar_d = 9\nvar_e = 2\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 50\nvar_g = 10\nvar_h = var_f / var_g\nlist_b = []\nfor i in list_a:\n    if i <= var_h:\n        list_b.append(i)\nvar_i = len(list_b)\nprint(int(var_i))"
    },
    "5999": {
        "category": "Correspondence",
        "question_ko": "4는 23에 어떤 수를 곱해야하는데 실수로 빼서 나온 결과입니다. 바르게 계산하면 얼마가 됩니까?",
        "question_en": "4 is the result of mistakenly subtracted 23 from a number when you should have multiplied by 23. Find the value when you calculate correctly?",
        "answer_ko": "621",
        "answer_en": "621",
        "solution_abst_ko": "23 23 4 [OP_ADD] [OP_MUL]",
        "solution_abst_en": "23 23 4 [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 23\nvar_b = 23\nvar_c = 4\nvar_d = var_b + var_c\nvar_e = var_a * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 23\nvar_b = 23\nvar_c = 4\nvar_d = var_b + var_c\nvar_e = var_a * var_d\nprint(int(var_e))"
    },
    "6000": {
        "category": "Correspondence",
        "question_ko": "82.04를 어떤 수로 나누었더니 몫이 28로 나누어 떨어졌습니다. 어떤 수는 얼마입니까?",
        "question_en": "When 82.04 is divided by a certain number, it is divisible and the quotient was 28. What number is that certain number?",
        "answer_ko": "2.93",
        "answer_en": "2.93",
        "solution_abst_ko": "82.04 28 [OP_DIV]",
        "solution_abst_en": "82.04 28 [OP_DIV]",
        "solution_code_ko": "var_a = 82.04\nvar_b = 28\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 82.04\nvar_b = 28\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "6001": {
        "category": "Arithmetic calculation",
        "question_ko": "바구니에 귤이 10개 있습니다. 민영이가 바구니에 귤 6개를 더 넣었습니다. 바구니 안에 있는 귤은 모두 몇 개입니까?",
        "question_en": "There are 10 tangerines in the basket. Minyoung put 6 more tangerines in the basket. Find the number of tangerines.",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "10 6 [OP_ADD]",
        "solution_abst_en": "10 6 [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 6\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 10\nvar_b = 6\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "6002": {
        "category": "Arithmetic calculation",
        "question_ko": "태원이는 일주일동안 문제집에 있는 문제를 220문제 풀려고 합니다. 태원이가 하루에 풀어야하는 문제는 적어도 몇 문제인가요?",
        "question_en": "Taewon tries to solve 220 problems in the workbook for a week. How many problems does Taewon have to solve in a day?",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "220 7 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "220 7 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 220\nvar_b = 7\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))",
        "solution_code_en": "var_a = 220\nvar_b = 7\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))"
    },
    "6003": {
        "category": "Comparison",
        "question_ko": "일주일 동안 서울의 최저 기온은 18도, 20도, 15도, 19도, 14도, 13도, 17도였습니다. 일주일 동안 17도 이하로 떨어진 날은 몇 번 있었나요?",
        "question_en": "The lowest temperatures in Seoul during the week were 18 degrees, 20 degrees, 15 degrees, 19 degrees, 14 degrees, 13 degrees, and 17 degrees. How many days did the temperature drop below 17 degrees in one week?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 18 20 15 19 14 13 17 [OP_LIST_EOL] 17 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 18 20 15 19 14 13 17 [OP_LIST_EOL] 17 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 18\nvar_b = 20\nvar_c = 15\nvar_d = 19\nvar_e = 14\nvar_f = 13\nvar_g = 17\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h = 17\nlist_b = []\nfor i in list_a:\n    if i <= var_h:\n        list_b.append(i)\nvar_i = len(list_b)\nprint(int(var_i))",
        "solution_code_en": "var_a = 18\nvar_b = 20\nvar_c = 15\nvar_d = 19\nvar_e = 14\nvar_f = 13\nvar_g = 17\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h = 17\nlist_b = []\nfor i in list_a:\n    if i <= var_h:\n        list_b.append(i)\nvar_i = len(list_b)\nprint(int(var_i))"
    },
    "6004": {
        "category": "Arithmetic calculation",
        "question_ko": "크기와 무게가 같은 물고기가 가득 담긴 통의 무게를 재었더니 54킬로그램(㎏)이었습니다. 이 중 절반의 물고기를 덜어낸 후 통의 무게를 재어 보니 29킬로그램(㎏)이었습니다. 원래 있던 물고기만의 무게는 몇 킬로그램(㎏)입니까?",
        "question_en": "A barrel full of fish of the same size and weight was weighed and found to be 54 kilograms (kg). After removing half of the fish from the barrel, it turned out to be 29 kilograms (kg). How many kilograms (kg) was the fish in the first place?",
        "answer_ko": "50",
        "answer_en": "50",
        "solution_abst_ko": "54 29 [OP_SUB] 2 [OP_MUL]",
        "solution_abst_en": "54 29 [OP_SUB] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 54\nvar_b = 29\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 54\nvar_b = 29\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "6005": {
        "category": "Geometry",
        "question_ko": "길이가 10.4센티미터(㎝)인 색 테이프 16개를 3.5센티미터(㎝)씩 겹치게 하여 원 모양으로 이어 붙였습니다. 이어 붙인 원 모양의 색 테이프의 전체 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "16 pieces of colored tape, each 10.4 centimeters (cm) long, were overlapped by 3.5 centimeters (cm) and connected in a circle shape. What is the total length in centimeters (cm) of the circle-shaped colored tapes that were connected together?",
        "answer_ko": "110.40",
        "answer_en": "110.4",
        "solution_abst_ko": "10.4 16 [OP_MUL] 3.5 16 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "10.4 16 [OP_MUL] 3.5 16 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 10.4\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 3.5\nvar_e = 16\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 10.4\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 3.5\nvar_e = 16\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "6006": {
        "category": "Possibility",
        "question_ko": "숫자 카드 2, 4가 주어졌을 때, 주어진 숫자 카드를 한 번씩 모두 사용하여 만들 수 있는 수 중 가장 작은 수를 구하시오.",
        "question_en": "When number cards 2 and 4 are given, find the smallest number that can be made by using all number cards once.",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "[OP_LIST_SOL] 2 4 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 2 4 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_e = list_c[var_d-1]\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_e = list_c[var_d-1]\nprint(int(var_e))"
    },
    "6007": {
        "category": "Comparison",
        "question_ko": "석진이는 사탕을 78개 가지고 있습니다. 태형이는 사탕을 81개 가지고 있습니다. 사탕을 더 많이 가지고 있는 사람은 누구입니까?",
        "question_en": "Seokjin has 78 candies, and Taehyung has 81 candies. Who has more candies?",
        "answer_ko": "태형",
        "answer_en": "Taehyung",
        "solution_abst_ko": "[OP_LIST_SOL] 석진 태형 [OP_LIST_EOL] [OP_LIST_SOL] 78 81 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Seokjin Taehyung [OP_LIST_EOL] [OP_LIST_SOL] 78 81 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '석진'\nvar_b = '태형'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 78\nvar_d = 81\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Seokjin'\nvar_b = 'Taehyung'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 78\nvar_d = 81\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "6008": {
        "category": "Arithmetic calculation",
        "question_ko": "호스 A는 욕조를 가득 체우는데 10시간이 걸리고, 호스 B는 욕조를 가득 체우는데 15시간이 걸린다. 두 개의 호스를 모두 사용하면 욕조를 가득 체우는데 몇 시간이 걸리는지 구하시오.",
        "question_en": "Hose A takes 10 hours to fill the bathtub, and Hose B takes 15 hours to fill the bathtub. Determine how many hours it will take to fill the bathtub if both hoses are used.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "1 1 10 [OP_DIV] 1 15 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_abst_en": "1 1 10 [OP_DIV] 1 15 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 1\nvar_c = 10\nvar_d = var_b / var_c\nvar_e = 1\nvar_f = 15\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = var_a / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))",
        "solution_code_en": "var_a = 1\nvar_b = 1\nvar_c = 10\nvar_d = var_b / var_c\nvar_e = 1\nvar_f = 15\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = var_a / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))"
    },
    "6009": {
        "category": "Arithmetic calculation",
        "question_ko": "대준이는 156개의 구슬이 담긴 주머니 20개를 선물받았습니다. 대준이가 가진 구슬의 개수는 모두 몇 개입니까?",
        "question_en": "Daejun was presented with 20 bags containing 156 marbles. How many marbles does Daejun have?",
        "answer_ko": "3120",
        "answer_en": "3120",
        "solution_abst_ko": "156 20 [OP_MUL]",
        "solution_abst_en": "156 20 [OP_MUL]",
        "solution_code_ko": "var_a = 156\nvar_b = 20\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 156\nvar_b = 20\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "6010": {
        "category": "Possibility",
        "question_ko": "윤기는 방과후수업으로 10개의 수업 중 3개를 선택할 수 있습니다. 윤기가 수업을 들을 수 있는 경우의 수는 모두 몇 가지입니까?",
        "question_en": "Yoongi can choose 3 out of 10 classes for after-school classes. How many ways can Yoongi take classes?",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "10 3 [OP_COMB]",
        "solution_abst_en": "10 3 [OP_COMB]",
        "solution_code_ko": "var_a = 10\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))",
        "solution_code_en": "var_a = 10\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))"
    },
    "6011": {
        "category": "Correspondence",
        "question_ko": "7개씩 포장되어있는 어떤 제품이 있다. 현수는 이 제품을 12개의 묶음과 5개의 낱개를 가지고 있다. 이 제품을 8개씩 다시 포장한다면 현수는 몇 개의 묶음을 만들 수 있는지 구하시오.",
        "question_en": "There is a product that is packaged in 7 pieces. Hyeonsu has 12 bundles and 5 individual pieces of this product. If this product is repackaged in units of 8, how many bundles can be made?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "12 7 [OP_MUL] 5 [OP_ADD] 8 [OP_FDIV]",
        "solution_abst_en": "12 7 [OP_MUL] 5 [OP_ADD] 8 [OP_FDIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e // var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 12\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e // var_f\nprint(int(var_g))"
    },
    "6012": {
        "category": "Arithmetic calculation",
        "question_ko": "아버지는 34살이고 어머니는 30살입니다. 아버지와 어머니의 나이의 합이 100살이 되는 해의 아버지의 나이는 몇 살입니까?",
        "question_en": "My father is 34 years old and my mother is 30 years old. What is the age of my father in the year when the sum of the ages of my father and mother becomes 100?",
        "answer_ko": "52",
        "answer_en": "52",
        "solution_abst_ko": "34 100 34 30 [OP_ADD] [OP_SUB] 2 [OP_DIV] [OP_ADD]",
        "solution_abst_en": "34 100 34 30 [OP_ADD] [OP_SUB] 2 [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 34\nvar_b = 100\nvar_c = 34\nvar_d = 30\nvar_e = var_c + var_d\nvar_f = var_b - var_e\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = var_a + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 34\nvar_b = 100\nvar_c = 34\nvar_d = 30\nvar_e = var_c + var_d\nvar_f = var_b - var_e\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = var_a + var_h\nprint(int(var_i))"
    },
    "6013": {
        "category": "Arithmetic calculation",
        "question_ko": "혜지는 하루에 물을 2리터(L)씩 마시기로 하였습니다. 오늘 마셔야 하는 물을 다 마신 후에 매운 것을 먹어 460밀리리터(㎖)를 더 마셨다면, 혜지가 오늘 마신 물은 몇 밀리리터(㎖)일까요?",
        "question_en": "Hyeji decided to drink 2 liters (L) of water a day. If she drank 460 milliliters (ml) more by eating spicy food after drinking all the water she needs to drink today, how many milliliters (ml) of water Hyeji drank today?",
        "answer_ko": "2460",
        "answer_en": "2460",
        "solution_abst_ko": "2 1000 [OP_MUL] 460 [OP_ADD]",
        "solution_abst_en": "2 1000 [OP_MUL] 460 [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 460\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 460\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "6014": {
        "category": "Geometry",
        "question_ko": "철사로 가장 넓은 크기의 사각형을 만들었더니 그 크기가 324제곱센티미터(㎠)입니다. 철사의 길이를 구하시오.",
        "question_en": "I made the widest square out of wire, and its size is 324 square centimeters (cm2). Find the length of the wire.",
        "answer_ko": "72",
        "answer_en": "72",
        "solution_abst_ko": "324 1/2 [OP_POW] 4 [OP_MUL]",
        "solution_abst_en": "324 1/2 [OP_POW] 4 [OP_MUL]",
        "solution_code_ko": "var_a = 324\nvar_b = 0.5\nvar_c = var_a ** var_b\nvar_d = 4\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 324\nvar_b = 0.5\nvar_c = var_a ** var_b\nvar_d = 4\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "6015": {
        "category": "Arithmetic calculation",
        "question_ko": "2개의 수 3, 4로 나누어 떨어질 수 있는 다섯 자리 수는 모두 몇 개 있습니까?",
        "question_en": "How many five-digit numbers are divisible by the two numbers 3 and 4?",
        "answer_ko": "7500",
        "answer_en": "7500",
        "solution_abst_ko": "10000 99999 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 4 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "10000 99999 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 4 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 10000\nvar_b = 99999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 4\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 10000\nvar_b = 99999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 4\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "6016": {
        "category": "Arithmetic calculation",
        "question_ko": "현준이는 집에서 학교에 가기 위해 2킬로미터(㎞)는 마을버스를 타고 560미터(m)는 걸어갑니다. 현준이가 학교에 가기 위해 이동한 총 거리는 몇 미터(m)입니까?",
        "question_en": "Hyeonjun takes a bus for 2 kilometers (km) and walks 560 meters (m) to go to school from home. How many meters (m) does Hyunjun travel to go to school?",
        "answer_ko": "2560",
        "answer_en": "2560",
        "solution_abst_ko": "2 1000 [OP_MUL] 560 [OP_ADD]",
        "solution_abst_en": "2 1000 [OP_MUL] 560 [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 560\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 560\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "6017": {
        "category": "Arithmetic calculation",
        "question_ko": "어제 석진이는 물고기 10마리를 구매하고 3,000원을 지불했습니다. 같은 가게에서 더 많은 수의 물고기를 구매했더니 어제보다 6,000원을 더 냈습니다. 석진이가 어제와 오늘 구매한 물고기는 총 몇 마리인지 구하시오.",
        "question_en": "Yesterday Seok-jin bought 10 fish and paid 3,000 won. He paid 6,000 won more than yesterday because he bought more fish from the same store. Find the total number of fish that Seok-jin bought yesterday and today.",
        "answer_ko": "40",
        "answer_en": "40",
        "solution_abst_ko": "3000 6000 [OP_ADD] 3000 10 [OP_DIV] [OP_DIV] 10 [OP_ADD]",
        "solution_abst_en": "3000 6000 [OP_ADD] 3000 10 [OP_DIV] [OP_DIV] 10 [OP_ADD]",
        "solution_code_ko": "var_a = 3000\nvar_b = 6000\nvar_c = var_a + var_b\nvar_d = 3000\nvar_e = 10\nvar_f = var_d / var_e\nvar_g = var_c / var_f\nvar_h = 10\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 3000\nvar_b = 6000\nvar_c = var_a + var_b\nvar_d = 3000\nvar_e = 10\nvar_f = var_d / var_e\nvar_g = var_c / var_f\nvar_h = 10\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "6018": {
        "category": "Correspondence",
        "question_ko": "695에서 329를 뺀 값과 어떤 수에서 254를 뺀 값이 같다. 어떤 수를 구하시오.",
        "question_en": "695 minus 329 equals a number minus 254. Find the number.",
        "answer_ko": "620",
        "answer_en": "620",
        "solution_abst_ko": "695 329 [OP_SUB] 254 [OP_ADD]",
        "solution_abst_en": "695 329 [OP_SUB] 254 [OP_ADD]",
        "solution_code_ko": "var_a = 695\nvar_b = 329\nvar_c = var_a - var_b\nvar_d = 254\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 695\nvar_b = 329\nvar_c = var_a - var_b\nvar_d = 254\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "6019": {
        "category": "Arithmetic calculation",
        "question_ko": "은행에서 중국 돈 1 위안은 일본 돈으로 17.25 엔으로 바꿔 준다고 합니다. 세영이는 1000 위안짜리 지폐 1 장과 10 위안짜리 동전 1 개를 가지고 있습니다. 세영 이가 가진 중국 돈은 일본 돈으로 얼마입니까?",
        "question_en": "At the bank, 1 yuan in Chinese money is exchanged for 17.25 yen in Japanese money. Saeyoung has one 1000 yuan bill and one 10 yuan coin. How much is Seyoung's Chinese money in Japanese money?",
        "answer_ko": "17422.50",
        "answer_en": "17422.5",
        "solution_abst_ko": "17.25 1000 [OP_MUL] 17.25 10 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "17.25 1000 [OP_MUL] 17.25 10 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 17.25\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 17.25\nvar_e = 10\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 17.25\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 17.25\nvar_e = 10\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "6020": {
        "category": "Arithmetic calculation",
        "question_ko": "5%의 설탕물이 200그램(g) 있습니다. 이 설탕물에서 물이 증발하여 8%의 설탕물이 되었다면, 증발된 물은 몇 그램(g)인지 구하시오.",
        "question_en": "There are 200 grams (g) of 5% sugar water. If water evaporated from this sugar water to make it 8% sugar water, find how many grams (g) of water has evaporated.",
        "answer_ko": "75",
        "answer_en": "75",
        "solution_abst_ko": "200 200 5 100 [OP_DIV] [OP_MUL] 100 8 [OP_DIV] [OP_MUL] [OP_SUB]",
        "solution_abst_en": "200 200 5 100 [OP_DIV] [OP_MUL] 100 8 [OP_DIV] [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 200\nvar_b = 200\nvar_c = 5\nvar_d = 100\nvar_e = var_c / var_d\nvar_f = var_b * var_e\nvar_g = 100\nvar_h = 8\nvar_i = var_g / var_h\nvar_j = var_f * var_i\nvar_k = var_a - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 200\nvar_b = 200\nvar_c = 5\nvar_d = 100\nvar_e = var_c / var_d\nvar_f = var_b * var_e\nvar_g = 100\nvar_h = 8\nvar_i = var_g / var_h\nvar_j = var_f * var_i\nvar_k = var_a - var_j\nprint(int(var_k))"
    },
    "6021": {
        "category": "Correspondence",
        "question_ko": "A78-2B4=364라는 식이 성립하려면, A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "What number must go in A to make A78-2B4=364?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "A78-2B4=364 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A78-2B4=364 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A78-2B4=364'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A78-2B4=364'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "6022": {
        "category": "Arithmetic calculation",
        "question_ko": "찹쌀떡 3.8킬로그램(㎏)를 만드는 데 찹쌀가루 1.2킬로그램(㎏)이 필요하다고 합니다. 가게에서 만드는 총 찹쌀떡의 무게는 53.2킬로그램(㎏)이고 한 통에 들어있는 찹쌀가루의 양은 3킬로그램(㎏)입니다. 가게의 찹쌀떡을 모두 만드려면 찹쌀가루는 모두 몇 통이 필요합니까?",
        "question_en": "1.2 kg (kg) of glutinous rice flour is needed to make 3.8 kg (kg) of chapsalttock. The total weight of chapsalttocks made in the store is 53.2 kg (kg), and the amount of glutinous rice flour in a box is 3 kg (kg). How many boxes of glutinous rice flour do they need to make all the chapsalttocks in the store?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "1.2 3.8 [OP_DIV] 53.2 [OP_MUL] 3 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "1.2 3.8 [OP_DIV] 53.2 [OP_MUL] 3 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 1.2\nvar_b = 3.8\nvar_c = var_a / var_b\nvar_d = 53.2\nvar_e = var_c * var_d\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = 1\nvar_i=int(((var_g+9*10**(var_h-2))//(10**(var_h-1)))*10**(var_h-1))\n\nprint(int(var_i))",
        "solution_code_en": "var_a = 1.2\nvar_b = 3.8\nvar_c = var_a / var_b\nvar_d = 53.2\nvar_e = var_c * var_d\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = 1\nvar_i=int(((var_g+9*10**(var_h-2))//(10**(var_h-1)))*10**(var_h-1))\n\nprint(int(var_i))"
    },
    "6023": {
        "category": "Geometry",
        "question_ko": "반지름이 10센티미터(㎝)인 원 안에 가장 큰 마름모를 그렸을 때 마름모의 대각선 길이는 몇 센티미터(㎝) 입니까?",
        "question_en": "If the largest rhombus is drawn inside a circle with a radius of 10 centimeters (cm), how long centimeters (cm) is the diagonal of the rhombus?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "2 10 [OP_MUL]",
        "solution_abst_en": "2 10 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 10\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 10\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "6024": {
        "category": "Arithmetic calculation",
        "question_ko": "270원짜리 풀 1개와 210원짜리 연필 몇 자루를 사고 1,000원을 내었더니 거스름돈으로 100원을 받았습니다. 연필은 몇 자루를 샀는지 구하시오.",
        "question_en": "I paid 1,000 won after buying a glue for 270 won and pencils for 210 won and received 100 won as change. How many pencils did I buy?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "1000 100 [OP_SUB] 270 1 [OP_MUL] [OP_SUB] 210 [OP_DIV]",
        "solution_abst_en": "1000 100 [OP_SUB] 270 1 [OP_MUL] [OP_SUB] 210 [OP_DIV]",
        "solution_code_ko": "var_a = 1000\nvar_b = 100\nvar_c = var_a - var_b\nvar_d = 270\nvar_e = 1\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 210\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1000\nvar_b = 100\nvar_c = var_a - var_b\nvar_d = 270\nvar_e = 1\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 210\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "6025": {
        "category": "Correspondence",
        "question_ko": "수민이가 가진 캔디는 딸기맛과 포도맛 2가지이다. 캔디가 모두 821개이고 딸기맛 캔디는 267개이면 포도맛 캔디와 딸기맛 캔디의 개수 차를 구하시오.",
        "question_en": "Sumin's candies are in two flavors, strawberry and grape. If there are 821 candies and 267 strawberry candies, find the difference between the number of grape and strawberry candies.",
        "answer_ko": "287",
        "answer_en": "287",
        "solution_abst_ko": "821 267 [OP_SUB] 267 [OP_SUB]",
        "solution_abst_en": "821 267 [OP_SUB] 267 [OP_SUB]",
        "solution_code_ko": "var_a = 821\nvar_b = 267\nvar_c = var_a - var_b\nvar_d = 267\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 821\nvar_b = 267\nvar_c = var_a - var_b\nvar_d = 267\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "6026": {
        "category": "Geometry",
        "question_ko": "정사각형 모양의 수첩이 있습니다. 이 수첩을 빈틈없이 정사각형 모양으로 늘여놓았더니 총 36개의 수첩이 남았습니다. 가로 한 변과 세로 한 변을 1열씩 늘렸더니 아직도 3개의 수첩이 남았습니다. 수첩은 모두 몇 개일까요?",
        "question_en": "I have square notebooks. When these notebooks were laid out in a big square shape without gaps, a total of 36 notebooks were left over. I then increased one horizontal and one vertical side by one column, and there were still three notebooks left over. How many notebooks did I have?",
        "answer_ko": "397",
        "answer_en": "397",
        "solution_abst_ko": "36 3 [OP_ADD] 1 [OP_ADD] 2 [OP_DIV] 2 [OP_POW] 3 [OP_SUB]",
        "solution_abst_en": "36 3 [OP_ADD] 1 [OP_ADD] 2 [OP_DIV] 2 [OP_POW] 3 [OP_SUB]",
        "solution_code_ko": "var_a = 36\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 3\nvar_k = var_i - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 36\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 3\nvar_k = var_i - var_j\nprint(int(var_k))"
    },
    "6027": {
        "category": "Possibility",
        "question_ko": "4장의 숫자 카드 8, 4, 6, 9 중 3장을 골라 세 자리 수를 만들 때, 500보다 작은 수의 개수를 구하시오",
        "question_en": "Find the number of numbers less than 500 when choosing 3 out of 4 number cards 8, 4, 6, 9 to make a three-digit number.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 8 4 6 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 500 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 8 4 6 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 500 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 8\nvar_b = 4\nvar_c = 6\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 500\nlist_c = []\nfor i in list_b:\n    if i < var_f:\n        list_c.append(i)\nvar_g = len(list_c)\nprint(int(var_g))",
        "solution_code_en": "var_a = 8\nvar_b = 4\nvar_c = 6\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 500\nlist_c = []\nfor i in list_b:\n    if i < var_f:\n        list_c.append(i)\nvar_g = len(list_c)\nprint(int(var_g))"
    },
    "6028": {
        "category": "Geometry",
        "question_ko": "둘레가 52센티미터(㎝) 인 정사각형과 가로가 15센티미터(㎝) 이고, 둘레가 52센티미터(㎝) 인 직사각형이 있습니다. 두 도형의 넓이의 차는 몇 입니까?",
        "question_en": "There is a square with a perimeter of 52 centimeters (cm), and a rectangle with a length of 15 centimeters (cm) and a perimeter of 52 centimeters (cm). What is the difference between the areas of the two shapes?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "52 4 [OP_DIV] 2 [OP_POW] 52 2 [OP_DIV] 15 [OP_SUB] 15 [OP_MUL] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "52 4 [OP_DIV] 2 [OP_POW] 52 2 [OP_DIV] 15 [OP_SUB] 15 [OP_MUL] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 52\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 52\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = 15\nvar_j = var_h - var_i\nvar_k = 15\nvar_l = var_j * var_k\nvar_m = var_e - var_l\nvar_n = abs(var_m)\nprint(int(var_n))",
        "solution_code_en": "var_a = 52\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 52\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = 15\nvar_j = var_h - var_i\nvar_k = 15\nvar_l = var_j * var_k\nvar_m = var_e - var_l\nvar_n = abs(var_m)\nprint(int(var_n))"
    },
    "6029": {
        "category": "Possibility",
        "question_ko": "0, 1, 3, 5, 7, 9로 이루어진 두 자리 수 중 각 자리의 숫자를 바꾸었을 때 달라지는 숫자의 개수는 모두 몇 개인가?",
        "question_en": "How many numbers among the two-digit numbers consisting of 0, 1, 3, 5, 7, and 9 change when each digit is rearranged?",
        "answer_ko": "25",
        "answer_en": "25",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 3 5 7 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 3 5 7 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 3\nvar_d = 5\nvar_e = 7\nvar_f = 9\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = len(list_b)\nprint(int(var_h))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 3\nvar_d = 5\nvar_e = 7\nvar_f = 9\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = len(list_b)\nprint(int(var_h))"
    },
    "6030": {
        "category": "Arithmetic calculation",
        "question_ko": "주차장에 12대의 자동차가 있었는데 추가로 들어온 자동차는 없고, 현재 9대의 자동차가 남아있다고 할 때, 주차장에서 나간 자동차는 몇 대입니까?",
        "question_en": "If there are 12 cars in the parking lot, but no additional cars have entered, and there are currently 9 cars remaining, how many cars have left the parking lot?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "12 9 [OP_SUB]",
        "solution_abst_en": "12 9 [OP_SUB]",
        "solution_code_ko": "var_a = 12\nvar_b = 9\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 12\nvar_b = 9\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "6031": {
        "category": "Correspondence",
        "question_ko": "360÷(A×A×A/B)=5의 식을 만족하는 가장 작은 자연수 B를 구하여라.",
        "question_en": "Find the smallest natural number B that satisfies the equation 360÷(A×A×A/B)=5.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "360÷(A×A×A/B)=5 B [OP_NUM_UNK_SOLVER] 1 [OP_LIST_MIN]",
        "solution_abst_en": "360÷(A×A×A/B)=5 B [OP_NUM_UNK_SOLVER] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = '360÷(A×A×A/B)=5'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[var_c-1]\nprint(int(var_d))",
        "solution_code_en": "var_a = '360÷(A×A×A/B)=5'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[var_c-1]\nprint(int(var_d))"
    },
    "6032": {
        "category": "Correspondence",
        "question_ko": "90.1을 어떤 숫자로 나누면 5.3이 됩니다. 어떤 숫자는 얼마입니까?",
        "question_en": "Dividing 90.1 by a number gets you 5.3. What number is it?",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "1 5.3 90.1 [OP_DIV] [OP_DIV]",
        "solution_abst_en": "1 5.3 90.1 [OP_DIV] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 5.3\nvar_c = 90.1\nvar_d = var_b / var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 5.3\nvar_c = 90.1\nvar_d = var_b / var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "6033": {
        "category": "Comparison",
        "question_ko": "지민이는 3시간 30분동안 운동장 30바퀴를 돌았고 동국이는 1시간 동안 10바퀴를 돌았습니다. 두 명중 누가 더 빠르게 돌았습니까?",
        "question_en": "Jimin did 30 laps in 3 hours and 30 minutes and Dongguk did 10 laps in 1 hour. Which of the two ran faster?",
        "answer_ko": "동국",
        "answer_en": "Dongguk",
        "solution_abst_ko": "[OP_LIST_SOL] 지민 동국 [OP_LIST_EOL] [OP_LIST_SOL] 30 3 60 [OP_MUL] 30 [OP_ADD] [OP_DIV] 10 1 60 [OP_MUL] [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jimin Dongguk [OP_LIST_EOL] [OP_LIST_SOL] 30 3 60 [OP_MUL] 30 [OP_ADD] [OP_DIV] 10 1 60 [OP_MUL] [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '지민'\nvar_b = '동국'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 30\nvar_d = 3\nvar_e = 60\nvar_f = var_d * var_e\nvar_g = 30\nvar_h = var_f + var_g\nvar_i = var_c / var_h\nvar_j = 10\nvar_k = 1\nvar_l = 60\nvar_m = var_k * var_l\nvar_n = var_j / var_m\nlist_b= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nlist_b.reverse()\nvar_o = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_p = list_c[-var_o]\nvar_q = list_b.index(var_p)+1\nvar_r = list_a[var_q-1]\nprint(var_r)",
        "solution_code_en": "var_a = 'Jimin'\nvar_b = 'Dongguk'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 30\nvar_d = 3\nvar_e = 60\nvar_f = var_d * var_e\nvar_g = 30\nvar_h = var_f + var_g\nvar_i = var_c / var_h\nvar_j = 10\nvar_k = 1\nvar_l = 60\nvar_m = var_k * var_l\nvar_n = var_j / var_m\nlist_b= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nlist_b.reverse()\nvar_o = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_p = list_c[-var_o]\nvar_q = list_b.index(var_p)+1\nvar_r = list_a[var_q-1]\nprint(var_r)"
    },
    "6034": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 26을 빼고 2로 나눈 수가 37입니다. 어떤 수를 4로 나눈 뒤 48에서 뺀 값을 구하시오.",
        "question_en": "Subtract 26 from any number and divide by 2 is 37. Find the value of dividing a number by 4 and subtracting it from 48.",
        "answer_ko": "23",
        "answer_en": "23",
        "solution_abst_ko": "48 37 2 [OP_MUL] 26 [OP_ADD] 4 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "48 37 2 [OP_MUL] 26 [OP_ADD] 4 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 48\nvar_b = 37\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = 26\nvar_f = var_d + var_e\nvar_g = 4\nvar_h = var_f / var_g\nvar_i = var_a - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 48\nvar_b = 37\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = 26\nvar_f = var_d + var_e\nvar_g = 4\nvar_h = var_f / var_g\nvar_i = var_a - var_h\nprint(int(var_i))"
    },
    "6035": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 16센티미터(㎝)이고, 모든 변의 길이가 같은 도형의 둘레는 80센티미터(㎝)입니다. 이 도형은 총 몇 개의 각으로 이루어져 있습니까?",
        "question_en": "A figure with one side of 16 centimeters (cm) and all sides of the same length has a perimeter of 80 centimeters (cm). How many angles does this shape have?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "80 16 [OP_DIV]",
        "solution_abst_en": "80 16 [OP_DIV]",
        "solution_code_ko": "var_a = 80\nvar_b = 16\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 80\nvar_b = 16\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "6036": {
        "category": "Correspondence",
        "question_ko": "24에서 AB를 빼면 6입니다. A는 얼마인가요?",
        "question_en": "24 minus AB equals 6. What is the value of A, where AB is two-digit number?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "6 24 [OP_ADD] 10 [OP_FDIV]",
        "solution_abst_en": "6 24 [OP_ADD] 10 [OP_FDIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 24\nvar_c = var_a + var_b\nvar_d = 10\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 24\nvar_c = var_a + var_b\nvar_d = 10\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "6037": {
        "category": "Correspondence",
        "question_ko": "AB19를 올림하여 백의 자리까지 나타내면 7300입니다. AB19를 버림하여 십의 자리까지 나타내시오.",
        "question_en": "AB19 rounded up to the hundreds place equals 7300. Round down AB19 to the tens place.",
        "answer_ko": "7210",
        "answer_en": "7210",
        "solution_abst_ko": "AB19 [OP_GEN_POSSIBLE_LIST] 7200 [OP_LIST_MORE] 7300 [OP_LIST_LESS_EQUAL] AB19 A [OP_LIST_FIND_UNK] 1000 [OP_MUL] AB19 B [OP_LIST_FIND_UNK] 100 [OP_MUL] [OP_ADD] 19 [OP_ADD] 2 [OP_FLOOR]",
        "solution_abst_en": "AB19 [OP_GEN_POSSIBLE_LIST] 7200 [OP_LIST_MORE] 7300 [OP_LIST_LESS_EQUAL] AB19 A [OP_LIST_FIND_UNK] 1000 [OP_MUL] AB19 B [OP_LIST_FIND_UNK] 100 [OP_MUL] [OP_ADD] 19 [OP_ADD] 2 [OP_FLOOR]",
        "solution_code_ko": "var_a = 'AB19'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 7200\nlist_b = []\nfor i in list_a:\n    if i > var_b:\n        list_b.append(i)\nvar_c = 7300\nlist_c = []\nfor i in list_b:\n    if i <= var_c:\n        list_c.append(i)\nvar_d = 'AB19'\nvar_e = 'A'\nvar_d = str(var_d)\nvar_e = str(var_e)\nunk_idx = var_d.index(var_e)\nvar_f = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_f = int(elem[unk_idx])\nvar_g = 1000\nvar_h = var_f * var_g\nvar_i = 'AB19'\nvar_j = 'B'\nvar_i = str(var_i)\nvar_j = str(var_j)\nunk_idx = var_i.index(var_j)\nvar_k = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_k = int(elem[unk_idx])\nvar_l = 100\nvar_m = var_k * var_l\nvar_n = var_h + var_m\nvar_o = 19\nvar_p = var_n + var_o\nvar_q = 2\nvar_r=int((var_p//(10**(var_q-1)))*10**(var_q-1))\n\nprint(int(var_r))",
        "solution_code_en": "var_a = 'AB19'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 7200\nlist_b = []\nfor i in list_a:\n    if i > var_b:\n        list_b.append(i)\nvar_c = 7300\nlist_c = []\nfor i in list_b:\n    if i <= var_c:\n        list_c.append(i)\nvar_d = 'AB19'\nvar_e = 'A'\nvar_d = str(var_d)\nvar_e = str(var_e)\nunk_idx = var_d.index(var_e)\nvar_f = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_f = int(elem[unk_idx])\nvar_g = 1000\nvar_h = var_f * var_g\nvar_i = 'AB19'\nvar_j = 'B'\nvar_i = str(var_i)\nvar_j = str(var_j)\nunk_idx = var_i.index(var_j)\nvar_k = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_k = int(elem[unk_idx])\nvar_l = 100\nvar_m = var_k * var_l\nvar_n = var_h + var_m\nvar_o = 19\nvar_p = var_n + var_o\nvar_q = 2\nvar_r=int((var_p//(10**(var_q-1)))*10**(var_q-1))\n\nprint(int(var_r))"
    },
    "6038": {
        "category": "Comparison",
        "question_ko": "구슬을 민정이는 6개, 주환이는 7개 가지고 있습니다. 구슬을 민정이는 선호보다 1개 더 많이 가지고 있고, 진영이는 주환이보다 3개 더 적게 가지고 있습니다. 구슬을 가장 적게 가지고 있는 사람은 누구입니까?",
        "question_en": "Minjeong has 6 marbles and Joohwan has 7. Minjeong has 1 more marble than Sunho, and Jinyoung has 3 fewer marbles than Joohwan. Who has the fewest marbles?",
        "answer_ko": "진영",
        "answer_en": "Jinyoung",
        "solution_abst_ko": "[OP_LIST_SOL] 민정 주환 선호 진영 [OP_LIST_EOL] [OP_LIST_SOL] 6 7 6 1 [OP_SUB] 7 3 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Minjeong Joohwan Sunho Jinyoung [OP_LIST_EOL] [OP_LIST_SOL] 6 7 6 1 [OP_SUB] 7 3 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '민정'\nvar_b = '주환'\nvar_c = '선호'\nvar_d = '진영'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 6\nvar_f = 7\nvar_g = 6\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = 7\nvar_k = 3\nvar_l = var_j - var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[var_m-1]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'Minjeong'\nvar_b = 'Joohwan'\nvar_c = 'Sunho'\nvar_d = 'Jinyoung'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 6\nvar_f = 7\nvar_g = 6\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = 7\nvar_k = 3\nvar_l = var_j - var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[var_m-1]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "6039": {
        "category": "Arithmetic calculation",
        "question_ko": "한 상자에는 감이 100개씩 들어있습니다. 6개의 상자 안에 있는 감은 모두 몇 개일까요?",
        "question_en": "Each box contains 100 persimmons. How many persimmons are there in all 6 boxes?",
        "answer_ko": "600",
        "answer_en": "600",
        "solution_abst_ko": "100 6 [OP_MUL]",
        "solution_abst_en": "100 6 [OP_MUL]",
        "solution_code_ko": "var_a = 100\nvar_b = 6\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 100\nvar_b = 6\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "6040": {
        "category": "Correspondence",
        "question_ko": "어떤 나무 판자를 하나 색 칠하는데 13/5 통의 물감이 필요했다. 동일한 나무 판자를 하나 더 색칠하고 남은 페인트의 양이 9/7통이다. 처음에 있던 페인트의 양은 몇 통인지 구하시오.",
        "question_en": "It took 13/5 tins of paint to paint one wooden board. Another identical wooden plank is painted and the amount of paint remaining is 9/7 tins. Find how many cans of paint were in the beginning.",
        "answer_ko": "6.49",
        "answer_en": "6.49",
        "solution_abst_ko": "9/7 13/5 [OP_ADD] 13/5 [OP_ADD]",
        "solution_abst_en": "9/7 13/5 [OP_ADD] 13/5 [OP_ADD]",
        "solution_code_ko": "var_a = 1.2857142857142858\nvar_b = 2.6\nvar_c = var_a + var_b\nvar_d = 2.6\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 1.2857142857142858\nvar_b = 2.6\nvar_c = var_a + var_b\nvar_d = 2.6\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "6041": {
        "category": "Correspondence",
        "question_ko": "윤기는 11을 어떤 수에서 나누어 2를 얻었습니다. 다음으로 어떤 수에 6을 곱하고자 합니다. 이 결과 값은 얼마입니까?",
        "question_en": "Yoongi divided 11 by some number and got 2. Next, he wants to multiply some number by 6. What is the value of this result?",
        "answer_ko": "132",
        "answer_en": "132",
        "solution_abst_ko": "2 11 [OP_MUL] 6 [OP_MUL]",
        "solution_abst_en": "2 11 [OP_MUL] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 11\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 11\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "6042": {
        "category": "Correspondence",
        "question_ko": "미술시간에 철수와 영희가 찰흙을 가져왔는데 철수의 찰흙이 영희의 찰흙보다 더 무거웠습니다. 영희가 자신의 찰흙에서 7/5그램(g)을 때어내어 철수의 찰흙에 붙혔더니 영희의 찰흙이 철수의 찰흙보다 81/20그램(g) 더 가벼웠습니다. 처음 철수와 영희가 가져온 찰흙의 무게 차이는 얼마였는지 구하시오.",
        "question_en": "In art class, Cheol-su and Young-hee brought clay, but Cheol-su's clay was heavier than Young-hee's. When Young-hee removed 7/5 grams (g) from her clay and stuck it to Cheol-su’s clay, Young-hee’s clay was 81/20 grams (g) lighter than Cheol-su’s clay. Find the difference in weight between the clay that Cheol-su and Young-hee brought at first.",
        "answer_ko": "6.85",
        "answer_en": "6.85",
        "solution_abst_ko": "81/20 7/5 [OP_ADD] 7/5 [OP_ADD]",
        "solution_abst_en": "81/20 7/5 [OP_ADD] 7/5 [OP_ADD]",
        "solution_code_ko": "var_a = 4.05\nvar_b = 1.4\nvar_c = var_a + var_b\nvar_d = 1.4\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 4.05\nvar_b = 1.4\nvar_c = var_a + var_b\nvar_d = 1.4\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "6043": {
        "category": "Correspondence",
        "question_ko": "36에 어떤 수를 더해야 할 것을 잘못하여 7에 어떤 수를 곱했더니 70이 되었습니다. 바르게 계산하면 얼마인지 구하시오.",
        "question_en": "You had to add a number to 36 but added 7 to the number by mistake and the result was 70. How much is it if you calculate it correctly?",
        "answer_ko": "46",
        "answer_en": "46",
        "solution_abst_ko": "36 70 7 [OP_DIV] [OP_ADD]",
        "solution_abst_en": "36 70 7 [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 36\nvar_b = 70\nvar_c = 7\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 36\nvar_b = 70\nvar_c = 7\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "6044": {
        "category": "Arithmetic calculation",
        "question_ko": "우유가 9개씩 들어있는 박스가 7개 있다. 이 중 7개의 우유는 먹고, 남은 우유를 8명에게 똑같이 나누려면 몇 개 씩 주면 되는가?",
        "question_en": "There are 7 boxes with each box containing 9 bottles of milk. If you eat 7 of these bottles of milk and divide the remaining milk equally among 8 people, Find how many bottles of milk you should give per person.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "9 7 [OP_MUL] 7 [OP_SUB] 8 [OP_DIV]",
        "solution_abst_en": "9 7 [OP_MUL] 7 [OP_SUB] 8 [OP_DIV]",
        "solution_code_ko": "var_a = 9\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 9\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "6045": {
        "category": "Correspondence",
        "question_ko": "14A+B73=418일 때, A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "When 14A+B73=418, what number should be in A, where 14A and B73 are three-digit numbers?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "14A+B73=418 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "14A+B73=418 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '14A+B73=418'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '14A+B73=418'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "6046": {
        "category": "Comparison",
        "question_ko": "학급 임원 선거에서 30명이 투표에 참여하였습니다. 가는 12표, 나는 3표, 다는 15표를 받았습니다. 득표율이 가장 높은 후보가 회장이 된다고 합니다. 회장에 당선된 후보는 누구인지 써 보세요.",
        "question_en": "Thirty people voted in the Class Representative Election. A got 12 votes, 3 votes for B, and C got 15 votes. The candidate with the most votes is said to be the class president. Write down who is the candidate who won the election.",
        "answer_ko": "다",
        "answer_en": "C",
        "solution_abst_ko": "[OP_LIST_SOL] 가 나 다 [OP_LIST_EOL] [OP_LIST_SOL] 12 3 15 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] 12 3 15 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '가'\nvar_b = '나'\nvar_c = '다'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 12\nvar_e = 3\nvar_f = 15\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 12\nvar_e = 3\nvar_f = 15\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "6047": {
        "category": "Comparison",
        "question_ko": "세 수 A, B, C가 있습니다. A는 32보다 7 큰 수입니다. B는 10개씩 3묶음과 낱개 3개인 수입니다. C는 50보다 9 작은 수입니다. 가장 작은 수는 어느 것입니까?",
        "question_en": "There are three numbers A, B, and C. A is 7 greater than 32. B is a number of 3 groups of 10 and 3 units. C is 9 less than 50. Which number is the smallest?",
        "answer_ko": "B",
        "answer_en": "B",
        "solution_abst_ko": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] 32 7 [OP_ADD] 3 10 [OP_MUL] 3 [OP_ADD] 50 9 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] 32 7 [OP_ADD] 3 10 [OP_MUL] 3 [OP_ADD] 50 9 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 32\nvar_e = 7\nvar_f = var_d + var_e\nvar_g = 3\nvar_h = 10\nvar_i = var_g * var_h\nvar_j = 3\nvar_k = var_i + var_j\nvar_l = 50\nvar_m = 9\nvar_n = var_l - var_m\nlist_b= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_o = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_p = list_c[var_o-1]\nvar_q = list_b.index(var_p)+1\nvar_r = list_a[var_q-1]\nprint(var_r)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 32\nvar_e = 7\nvar_f = var_d + var_e\nvar_g = 3\nvar_h = 10\nvar_i = var_g * var_h\nvar_j = 3\nvar_k = var_i + var_j\nvar_l = 50\nvar_m = 9\nvar_n = var_l - var_m\nlist_b= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_o = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_p = list_c[var_o-1]\nvar_q = list_b.index(var_p)+1\nvar_r = list_a[var_q-1]\nprint(var_r)"
    },
    "6048": {
        "category": "Geometry",
        "question_ko": "여덟 개의 각으로 이루어진 도형의 모든 각의 크기가 같고, 이 도형의 둘레가 23.6센티미터(㎝)라면 한 변의 길이는 몇 센티미터(㎝)일지 구하시오.",
        "question_en": "If all the angles of a figure with eight angles are in the same size and the perimeter of the figure is 23.6 centimeters (cm), how long is one side of the figure in centimeters (cm)?",
        "answer_ko": "2.95",
        "answer_en": "2.95",
        "solution_abst_ko": "23.6 8 [OP_DIV]",
        "solution_abst_en": "23.6 8 [OP_DIV]",
        "solution_code_ko": "var_a = 23.6\nvar_b = 8\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 23.6\nvar_b = 8\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "6049": {
        "category": "Arithmetic calculation",
        "question_ko": "버스 안에 사람이 38명 있었습니다. 이번 정류장에서 내린 사람이 탄 사람보다 9명 많았다면 지금 버스 안에 있는 사람은 몇 명입니까?",
        "question_en": "There were 38 people in the bus. If 9 more people stepped off at the stop than those who got on at the stop, how many people are on the bus now?",
        "answer_ko": "29",
        "answer_en": "29",
        "solution_abst_ko": "38 9 [OP_SUB]",
        "solution_abst_en": "38 9 [OP_SUB]",
        "solution_code_ko": "var_a = 38\nvar_b = 9\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 38\nvar_b = 9\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "6050": {
        "category": "Arithmetic calculation",
        "question_ko": "무게가 같은 감이 가득 담긴 바구니의 무게가 62킬로그램(㎏)이었다. 절반의 감만 남긴 후 바구니와 함께 무게를 재어보니 34킬로그램(㎏)이 되었다. 바구니만의 무게는 몇 킬로그램(㎏)인가?",
        "question_en": "A basket full of persimmons of the same weight weighed 62 kilograms (kg). After leaving only half of the persimmons, I weighed it with the basket and it was 34 kilograms (kg). How many kilograms (kg) does the basket alone weigh?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "62 62 34 [OP_SUB] 2 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "62 62 34 [OP_SUB] 2 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 62\nvar_b = 62\nvar_c = 34\nvar_d = var_b - var_c\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_a - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 62\nvar_b = 62\nvar_c = 34\nvar_d = var_b - var_c\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_a - var_f\nprint(int(var_g))"
    },
    "6051": {
        "category": "Possibility",
        "question_ko": "16개의 팀이 축구 경기를 합니다. 두 팀중 패배한 팀은 탈락하고 승리한 팀은 다음 경기를 진행합니다. 마지막에 승리한 팀이 우승을 할때 경기는 총 몇번 이루어집니까?",
        "question_en": "16 teams are having a soccer game. The losing team is eliminated and the winning team advances to the next match. How many matches are played in total when the last winning team wins the game?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "16 1 [OP_SUB]",
        "solution_abst_en": "16 1 [OP_SUB]",
        "solution_code_ko": "var_a = 16\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 16\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "6052": {
        "category": "Correspondence",
        "question_ko": "모든 자리 수의 합이 12인 세 자리 수는 모두 몇 개입니까?",
        "question_en": "How many three-digit numbers are there where the sum of all the digits is 12?",
        "answer_ko": "66",
        "answer_en": "66",
        "solution_abst_ko": "100 1000 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] 12 [OP_LIST_MORE_EQUAL] 12 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "100 1000 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] 12 [OP_LIST_MORE_EQUAL] 12 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 100\nvar_b = 1000\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nlist_b=[]\nfor i in list_a:\n    var_f = 0\n    i = int(i)\n    while i//10 > 0:\n        var_f = var_f + i%10\n        i = i//10\n    var_f = var_f + i%10\n    list_b.append(var_f)\nvar_g = 12\nlist_c = []\nfor i in list_b:\n    if i >= var_g:\n        list_c.append(i)\nvar_h = 12\nlist_d = []\nfor i in list_c:\n    if i <= var_h:\n        list_d.append(i)\nvar_i = len(list_d)\nprint(int(var_i))",
        "solution_code_en": "var_a = 100\nvar_b = 1000\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nlist_b=[]\nfor i in list_a:\n    var_f = 0\n    i = int(i)\n    while i//10 > 0:\n        var_f = var_f + i%10\n        i = i//10\n    var_f = var_f + i%10\n    list_b.append(var_f)\nvar_g = 12\nlist_c = []\nfor i in list_b:\n    if i >= var_g:\n        list_c.append(i)\nvar_h = 12\nlist_d = []\nfor i in list_c:\n    if i <= var_h:\n        list_d.append(i)\nvar_i = len(list_d)\nprint(int(var_i))"
    },
    "6053": {
        "category": "Comparison",
        "question_ko": "학생들은 줄넘기를 할 때마다 5줄로 서고, 각 줄마다 학생 수가 같습니다. 호석이는 항상 어느 한 줄의 왼쪽에서 4번째, 오른쪽에서 9번째에 섭니다. 학생들은 모두 몇 명입니까?",
        "question_en": "Students line up in five lines every time they jump rope, with an equal number of students in each line. Hoseok is always 4th from the left and 9th from the right in a row. How many students are there in all?",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "5 4 9 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "5 4 9 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 4\nvar_c = 9\nvar_d = var_b + var_c\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_a * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 4\nvar_c = 9\nvar_d = var_b + var_c\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_a * var_f\nprint(int(var_g))"
    },
    "6054": {
        "category": "Correspondence",
        "question_ko": "11을 3으로 나누면 나머지가 2, 몫이 A가 됩니다. 이 때 A의 값을 구하시오.",
        "question_en": "When 11 is divided by 3, the remainder is 2 and the quotient is A. Find the value of A at this time.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "11 2 [OP_SUB] 3 [OP_DIV]",
        "solution_abst_en": "11 2 [OP_SUB] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 11\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 11\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "6055": {
        "category": "Comparison",
        "question_ko": "두 수 A, B가 있습니다. A는 49보다 33 큰 수입니다. B는 9를 9배 한 수입니다. 더 큰 수는 어느 것입니까?",
        "question_en": "There are two numbers, A and B. A is 33 greater than 49. B is 9 multiplied by 9. Which number is greater?",
        "answer_ko": "A",
        "answer_en": "A",
        "solution_abst_ko": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 49 33 [OP_ADD] 9 9 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 49 33 [OP_ADD] 9 9 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 49\nvar_d = 33\nvar_e = var_c + var_d\nvar_f = 9\nvar_g = 9\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 49\nvar_d = 33\nvar_e = var_c + var_d\nvar_f = 9\nvar_g = 9\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "6056": {
        "category": "Arithmetic calculation",
        "question_ko": "정우는 150미터(m)를 달리는데 20초가 걸립니다. 정우가 1분동안 달린다면 갈 수 있는 거리는 몇 미터(m)인지 구하세요.",
        "question_en": "Jungwoo takes 20 seconds to run 150 meters (m). If Jungwoo runs for 1 minute, find how many meters (m) he can run.",
        "answer_ko": "450",
        "answer_en": "450",
        "solution_abst_ko": "1 60 [OP_MUL] 20 [OP_DIV] 150 [OP_MUL]",
        "solution_abst_en": "1 60 [OP_MUL] 20 [OP_DIV] 150 [OP_MUL]",
        "solution_code_ko": "var_a = 1\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 20\nvar_e = var_c / var_d\nvar_f = 150\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 20\nvar_e = var_c / var_d\nvar_f = 150\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "6057": {
        "category": "Correspondence",
        "question_ko": "세 자리 수 3AB는 3의 배수이다. 가능한 B는 모두 몇 가지인가?",
        "question_en": "The three digit number 3AB is a multiple of 3. How many possible B's are there?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "3AB [OP_GEN_POSSIBLE_LIST] 3 [OP_LIST_DIVISIBLE] 3AB B [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_abst_en": "3AB [OP_GEN_POSSIBLE_LIST] 3 [OP_LIST_DIVISIBLE] 3AB B [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '3AB'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 3\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = '3AB'\nvar_d = 'B'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nvar_e = len(list_c)\nprint(int(var_e))",
        "solution_code_en": "var_a = '3AB'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 3\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = '3AB'\nvar_d = 'B'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nvar_e = len(list_c)\nprint(int(var_e))"
    },
    "6058": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이가 수학 문제를 15문제 풀었습니다. 2점짜리 8문제와 1점짜리 2문제를 맞히고, 나머지 문제는 틀려서 점수를 얻지 못했습니다. 정국이가 얻은 점수는 몇 점입니까?",
        "question_en": "Jungkook solved 15 math problems. He got 8 questions worth 2 points and 2 questions worth 1 point correct, and he got the rest wrong, so no points were awarded for that. How many points did Jungkook get?",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "2 8 [OP_MUL] 1 2 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "2 8 [OP_MUL] 1 2 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 2\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "6059": {
        "category": "Possibility",
        "question_ko": "3, 5, 9의 숫자 중에서 2장을 뽑아 한 번씩만 사용하여 가장 큰 두 자리 수를 만들었습니다. 만든 두 자리 수보다 27 작은 수를 구하시오.",
        "question_en": "Two of the numbers 3, 5, and 9 were drawn and used only once to create the largest two-digit number. Find the number 27 less than the two digit number you created.",
        "answer_ko": "68",
        "answer_en": "68",
        "solution_abst_ko": "[OP_LIST_SOL] 3 5 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 27 [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 3 5 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 27 [OP_SUB]",
        "solution_code_ko": "var_a = 3\nvar_b = 5\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 27\nvar_h = var_f - var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 3\nvar_b = 5\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 27\nvar_h = var_f - var_g\nprint(int(var_h))"
    },
    "6060": {
        "category": "Arithmetic calculation",
        "question_ko": "다음 범위내의 자연수의 합을 구하시오. 6과 21.",
        "question_en": "Find what the sum of the natural numbers is in the range of 6 and 21.",
        "answer_ko": "216",
        "answer_en": "216",
        "solution_abst_ko": "6 21 1 [OP_LIST_ARANGE] [OP_LIST_SUM]",
        "solution_abst_en": "6 21 1 [OP_LIST_ARANGE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 6\nvar_b = 21\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_a = [float(i) for i in list_a]\nvar_d = sum(list_a)\nprint(int(var_d))",
        "solution_code_en": "var_a = 6\nvar_b = 21\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_a = [float(i) for i in list_a]\nvar_d = sum(list_a)\nprint(int(var_d))"
    },
    "6061": {
        "category": "Comparison",
        "question_ko": "현지는 3.97킬로미터(㎞)를 걸었고, 가영이는 4028미터(m)를 걸었습니다. 더 많은 거리를 걸은 사람은 누구입니까?",
        "question_en": "Hyunji walked 3.97 kilometers (km), and Gayoung walked 4028 meters (m). Who has walked more distances?",
        "answer_ko": "가영",
        "answer_en": "Gayoung",
        "solution_abst_ko": "[OP_LIST_SOL] 현지 가영 [OP_LIST_EOL] [OP_LIST_SOL] 3.97 4028 1000 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Hyunji Gayoung [OP_LIST_EOL] [OP_LIST_SOL] 3.97 4028 1000 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '현지'\nvar_b = '가영'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3.97\nvar_d = 4028\nvar_e = 1000\nvar_f = var_d / var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Hyunji'\nvar_b = 'Gayoung'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3.97\nvar_d = 4028\nvar_e = 1000\nvar_f = var_d / var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "6062": {
        "category": "Arithmetic calculation",
        "question_ko": "호석이는 (가) 운동을 월요일에 8번, 화요일에 5번, 수요일에 12번, 목요일에 17번, 금요일에 10번 했습니다. 목요일에 운동한 횟수에서 화요일에 운동한 횟수를 뺀 값을 구하시오.",
        "question_en": "Hoseok did 8 workouts on Monday, 5 on Tuesday, 12 on Wednesday, 17 on Thursday, and 10 on Friday. Find the number of times he worked out on Thursday minus the number of times he worked out on Tuesday.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "17 5 [OP_SUB]",
        "solution_abst_en": "17 5 [OP_SUB]",
        "solution_code_ko": "var_a = 17\nvar_b = 5\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 17\nvar_b = 5\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "6063": {
        "category": "Comparison",
        "question_ko": "유나, 민영, 유정이가 우유를 마시고 있습니다. 유정이가 가장 많은 우유를 마셨고, 민영이는 유나보다 적은 우유를 마셨습니다. 가장 적은 우유를 마신 사람은 누구일까요?",
        "question_en": "Yuna, Minyoung, and Yoojeong are drinking milk. Yoojeong drank the most milk, and Minyoung drank less milk than Yuna. Who drank the least milk?",
        "answer_ko": "민영",
        "answer_en": "Minyoung",
        "solution_abst_ko": "[OP_LIST_SOL] 유나 민영 유정 [OP_LIST_EOL] [OP_LIST_SOL] 유정 민영 > 유정 유나 > 민영 유나 < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yuna Minyoung Yoojeong [OP_LIST_EOL] [OP_LIST_SOL] Yoojeong Minyoung > Yoojeong Yuna > Minyoung Yuna < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '유나'\nvar_b = '민영'\nvar_c = '유정'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '유정'\nvar_e = '민영'\nvar_f = '>'\nvar_g = '유정'\nvar_h = '유나'\nvar_i = '>'\nvar_j = '민영'\nvar_k = '유나'\nvar_l = '<'\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_m = len(list_c)\nvar_n = list_c[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'Yuna'\nvar_b = 'Minyoung'\nvar_c = 'Yoojeong'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'Yoojeong'\nvar_e = 'Minyoung'\nvar_f = '>'\nvar_g = 'Yoojeong'\nvar_h = 'Yuna'\nvar_i = '>'\nvar_j = 'Minyoung'\nvar_k = 'Yuna'\nvar_l = '<'\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_m = len(list_c)\nvar_n = list_c[var_m-1]\nprint(var_n)"
    },
    "6064": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 15 를 곱해야 할 것을 잘못하여 51 을 곱하였더니 244.8 이 되었습니다. 바르게 계산한 값을 구하시오.",
        "question_en": "A number has to be multiplied by 15, but I accidentally multiplied by 51 and it became 244.8. Find the correct value.",
        "answer_ko": "72",
        "answer_en": "72",
        "solution_abst_ko": "244.8 51 [OP_DIV] 15 [OP_MUL]",
        "solution_abst_en": "244.8 51 [OP_DIV] 15 [OP_MUL]",
        "solution_code_ko": "var_a = 244.8\nvar_b = 51\nvar_c = var_a / var_b\nvar_d = 15\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 244.8\nvar_b = 51\nvar_c = var_a / var_b\nvar_d = 15\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "6065": {
        "category": "Comparison",
        "question_ko": "어머니는 쌀을 씻는 데 5리터(L) 의 물을 사용하고, 아버지는 4900밀리리터(㎖) 의 물을 사용했다고 합니다. 물을 더 많이 사용한 사람은 누구입니까?",
        "question_en": "It is said that Mother used 5 liters (L) of water to wash rice, and Father used 4900 milliliters (㎖) of water. Who used more water?",
        "answer_ko": "어머니",
        "answer_en": "Mother",
        "solution_abst_ko": "[OP_LIST_SOL] 어머니 아버지 [OP_LIST_EOL] [OP_LIST_SOL] 5 1000 [OP_MUL] 4900 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Mother Father [OP_LIST_EOL] [OP_LIST_SOL] 5 1000 [OP_MUL] 4900 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '어머니'\nvar_b = '아버지'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 5\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 4900\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Mother'\nvar_b = 'Father'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 5\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 4900\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "6066": {
        "category": "Arithmetic calculation",
        "question_ko": "혜진이는 저금통에 100원짜리만 모으고 있습니다. 저금통에 100원짜리를 24개 더 넣으면 현재 들어있는 금액의 4배가 됩니다. 혜진이의 저금통에는 현재 얼마가 있을까요?",
        "question_en": "Hyejin only has 100 won coins in her piggy bank. If you put 24 more 100 wons in the piggy bank, it will be 4 times the current amount. How many coins is currently in Hyejin's piggy bank?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "24 4 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "24 4 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 24\nvar_b = 4\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 24\nvar_b = 4\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "6067": {
        "category": "Comparison",
        "question_ko": "밑면이 정사각형처럼 보이는 상자가 하나 있습니다. 이 상자의 밑면이 실제로도 정사각형인지 조사하기 위해 가로와 세로의 길이를 재본 결과 가로의 길이는 1.618미터(m), 세로의 길이는 162.3센티미터(㎝)로 정사각형이 아닌 것으로 밝혀졌습니다. 이 상자의 가로와 세로 중 길이가 더 긴 것은 어느 쪽입니까?",
        "question_en": "There is one box whose base looks like a square. To investigate whether the bottom of the box is actually square, the horizontal length and vertical length were measured, and it turned out that the box was not square as it measured 1.618 meters (m) wide and 162.3 centimeters (cm) long. Which is longer, the horizontal lenght or the vertical length?",
        "answer_ko": "세로",
        "answer_en": "vertical",
        "solution_abst_ko": "[OP_LIST_SOL] 가로 세로 [OP_LIST_EOL] [OP_LIST_SOL] 1.618 100 [OP_MUL] 162.3 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] horizontal vertical [OP_LIST_EOL] [OP_LIST_SOL] 1.618 100 [OP_MUL] 162.3 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '가로'\nvar_b = '세로'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.618\nvar_d = 100\nvar_e = var_c * var_d\nvar_f = 162.3\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'horizontal'\nvar_b = 'vertical'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.618\nvar_d = 100\nvar_e = var_c * var_d\nvar_f = 162.3\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "6068": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.3에서 0.4보다 큰 수 중 가장 작은 수는?",
        "question_en": "Find the smallest number greater than 0.4 from 0.8, 1/2, and 0.3.",
        "answer_ko": "0.50",
        "answer_en": "0.5",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.3 [OP_LIST_EOL] 0.4 [OP_LIST_MORE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.3 [OP_LIST_EOL] 0.4 [OP_LIST_MORE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.4\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nprint('{:.2f}'.format(round(var_f+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.4\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nprint('{:.2f}'.format(round(var_f+1e-10,2)))"
    },
    "6069": {
        "category": "Comparison",
        "question_ko": "윤기가 가진 사과가 4개, 정국이는 6개의 사과의 사과를 가지고 있었지만 3개를 먹었습니다. 유나가 가진 사과가 5개라면 누가 가장 적은 사과를 가지고 있나요?",
        "question_en": "Yoongi had 4 apples, Jungkook had 6 apples, but he ate 3. If Yuna has 5 apples, who has the fewest?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 유나 [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_SUB] 5 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook Yuna [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_SUB] 5 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nvar_c = '유나'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 6\nvar_f = 3\nvar_g = var_e - var_f\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nvar_c = 'Yuna'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 6\nvar_f = 3\nvar_g = var_e - var_f\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "6070": {
        "category": "Geometry",
        "question_ko": "정십이면체의 면의 개수는?",
        "question_en": "How many faces are in a regular dodecahedron?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "12",
        "solution_abst_en": "12",
        "solution_code_ko": "var_a = 12\nprint(int(var_a))",
        "solution_code_en": "var_a = 12\nprint(int(var_a))"
    },
    "6071": {
        "category": "Arithmetic calculation",
        "question_ko": "예지네 반 학생 30명은 1번부터 30번까지 자신의 출석 번호를 가지고 있습니다. 예지네 반 학생 중 오늘 반팔을 입은 학생은 1번, 3번, 7번, 10번, 23번, 27번 학생이고, 오늘 반바지를 입은 학생은 1번, 9번, 11번, 20번, 23번 학생일 때, 오늘 반팔을 입었지만 반바지는 입지 않은 학생은 몇 명입니까?",
        "question_en": "The 30 students in Yejin's class have their own attendance numbers from 1 to 30. Among the students in Yejin's class, students wearing short sleeves today are students number 1, 3, 7, 10, 23, and 27, and students number 1, 9, 11, 20, and 23 are wearing short pants today, how many students were wearing short sleeves but not short pants today?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 7 10 23 27 [OP_LIST_EOL] [OP_LIST_SOL] 1 9 11 20 23 [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 7 10 23 27 [OP_LIST_EOL] [OP_LIST_SOL] 1 9 11 20 23 [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 7\nvar_d = 10\nvar_e = 23\nvar_f = 27\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 1\nvar_h = 9\nvar_i = 11\nvar_j = 20\nvar_k = 23\nlist_b= []\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_l = len(list_c)\nprint(int(var_l))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 7\nvar_d = 10\nvar_e = 23\nvar_f = 27\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 1\nvar_h = 9\nvar_i = 11\nvar_j = 20\nvar_k = 23\nlist_b= []\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_l = len(list_c)\nprint(int(var_l))"
    },
    "6072": {
        "category": "Possibility",
        "question_ko": "정국, 지민, 윤기, 유나 중에서 반장, 부반장을 뽑으려고 합니다. 가능한 경우의 수는 모두 몇 가지 입니까",
        "question_en": "We are trying to pick a class president and a vice president from Jungkook, Jimin, Yoongi, and Yuna. How many possible cases are there?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 지민 윤기 유나 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Jimin Yoongi Yuna [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '지민'\nvar_c = '윤기'\nvar_d = '유나'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nprint(int(var_g))",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Jimin'\nvar_c = 'Yoongi'\nvar_d = 'Yuna'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nprint(int(var_g))"
    },
    "6073": {
        "category": "Comparison",
        "question_ko": "영빈이 뒤에 13명의 학생이 있다. 총 25명의 학생이 한 줄로 서 있다면 영빈이 앞에 있는 학생의 수는 몇 명인가?",
        "question_en": "There are 13 students behind Youngbin. If a total of 25 students are standing in a line, how many students are in front of Youngbin?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "25 13 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "25 13 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 25\nvar_b = 13\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 25\nvar_b = 13\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "6074": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이는 빨간 공 5개, 파란 공 4개, 노란 공 3개를 가지고 있습니다. 윤기가 정국이에게 노란 공 1개를 주었을 때, 정국이는 빨간 공을 몇 개 가지고 있습니까?",
        "question_en": "Jungkook has 5 red balls, 4 blue balls, and 3 yellow balls. When Yoongi gives 1 yellow ball to Jungkook, how many red balls does Jungkook have?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "5",
        "solution_abst_en": "5",
        "solution_code_ko": "var_a = 5\nprint(int(var_a))",
        "solution_code_en": "var_a = 5\nprint(int(var_a))"
    },
    "6075": {
        "category": "Comparison",
        "question_ko": "태인이네 학교 1학년 여학생은 221명, 1학년 남학생은 255명이고, 2학년 여학생은 275명, 2학년 남학생은 226명입니다. 몇 학년 학생이 더 많은지 구하시오.",
        "question_en": "There are 221 first-year female students, and 255 first-year male students at Taein's School, 275 second-year female students and 226 second-year male students. Find which grade has more students.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 1 2 [OP_LIST_EOL] [OP_LIST_SOL] 221 255 [OP_ADD] 275 226 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] 1 2 [OP_LIST_EOL] [OP_LIST_SOL] 221 255 [OP_ADD] 275 226 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 1\nvar_b = 2\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 221\nvar_d = 255\nvar_e = var_c + var_d\nvar_f = 275\nvar_g = 226\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(int(var_l))",
        "solution_code_en": "var_a = 1\nvar_b = 2\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 221\nvar_d = 255\nvar_e = var_c + var_d\nvar_f = 275\nvar_g = 226\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(int(var_l))"
    },
    "6076": {
        "category": "Arithmetic calculation",
        "question_ko": "꽃 13송이 중 7송이가 시들어서 버렸습니다. 살아 있는 꽃은 몇 송이입니까?",
        "question_en": "7 out of 13 flowers are withered and discarded. How many live flowers are there?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "13 7 [OP_SUB]",
        "solution_abst_en": "13 7 [OP_SUB]",
        "solution_code_ko": "var_a = 13\nvar_b = 7\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 13\nvar_b = 7\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "6077": {
        "category": "Comparison",
        "question_ko": "어떤 수는 52보다 큰 자연수입니다. 52와 어떤 자연수 사이에 연속된 자연수가 15개 있을때 52와 어떤 수 사이에 있는 수 중 한가운데 있는 수는 무엇인가요?",
        "question_en": "A certain number is a natural number greater than 52. If there are 15 consecutive natural numbers between 52 and the certain number, which number is in the middle of the numbers between 52 and the certain number?",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "52 15 [OP_ADD] 1 [OP_ADD] 52 [OP_ADD] 2 [OP_DIV]",
        "solution_abst_en": "52 15 [OP_ADD] 1 [OP_ADD] 52 [OP_ADD] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 52\nvar_b = 15\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 52\nvar_g = var_e + var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 52\nvar_b = 15\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 52\nvar_g = var_e + var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "6078": {
        "category": "Geometry",
        "question_ko": "어떤 다각형은 한 꼭짓점에서 1개의 대각선만 그을 수 있다. 이 다각형의 변의 개수는?",
        "question_en": "A polygon can draw only one diagonal from one vertex. How many sides does this polygon have?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "1 3 [OP_ADD]",
        "solution_abst_en": "1 3 [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "6079": {
        "category": "Correspondence",
        "question_ko": "812를 어떤 수로 나눈 값이 25이다. 어떤 수를 4로 나누면 얼마인지 구하시오.",
        "question_en": "812 divided by a particular number equals 25. Find out the value when that particular number is divided by 4.",
        "answer_ko": "8.12",
        "answer_en": "8.12",
        "solution_abst_ko": "812 25 [OP_DIV] 4 [OP_DIV]",
        "solution_abst_en": "812 25 [OP_DIV] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 812\nvar_b = 25\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 812\nvar_b = 25\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "6080": {
        "category": "Comparison",
        "question_ko": "6학년 1반 학생 7명의 키가 161.5센티미터(㎝), 154.3센티미터(㎝), 143.7센티미터(㎝), 160.1센티미터(㎝), 158.0센티미터(㎝), 153.5센티미터(㎝), 147.8센티미터(㎝)일 때, 이 중에서 평균보다 큰 학생은 몇 명인지 구하시오.",
        "question_en": "The heights of 7 students in class 1 of 6th grade are 161.5 centimeters (cm), 154.3 centimeters (cm), 143.7 centimeters (cm), 160.1 centimeters (cm), 158.0 centimeters (cm), 153.5 centimeters (cm), 147.8 centimeters (cm). Find how many of these students are above average.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 161.5 154.3 143.7 160.1 158.0 153.5 147.8 [OP_LIST_EOL] [OP_LIST_MEAN] [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 161.5 154.3 143.7 160.1 158.0 153.5 147.8 [OP_LIST_EOL] [OP_LIST_MEAN] [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 161.5\nvar_b = 154.3\nvar_c = 143.7\nvar_d = 160.1\nvar_e = 158\nvar_f = 153.5\nvar_g = 147.8\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_h = sum(list_a)/len(list_a)\nlist_b = []\nfor i in list_a:\n    if i > var_h:\n        list_b.append(i)\nvar_i = len(list_b)\nprint(int(var_i))",
        "solution_code_en": "var_a = 161.5\nvar_b = 154.3\nvar_c = 143.7\nvar_d = 160.1\nvar_e = 158\nvar_f = 153.5\nvar_g = 147.8\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_h = sum(list_a)/len(list_a)\nlist_b = []\nfor i in list_a:\n    if i > var_h:\n        list_b.append(i)\nvar_i = len(list_b)\nprint(int(var_i))"
    },
    "6081": {
        "category": "Comparison",
        "question_ko": "5, 8 중에서 가장 큰 숫자는 무엇인가요?",
        "question_en": "What is the largest number between 5 and 8?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "[OP_LIST_SOL] 5 8 [OP_LIST_EOL] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 5 8 [OP_LIST_EOL] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 5\nvar_b = 8\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[-var_c]\nprint(int(var_d))",
        "solution_code_en": "var_a = 5\nvar_b = 8\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[-var_c]\nprint(int(var_d))"
    },
    "6082": {
        "category": "Possibility",
        "question_ko": "2가지 과일을 사려고 합니다. 고를 수 있는 과일의 종류가 4개라면, 살 수 있는 경우의 수는 모두 몇 가지입니까?",
        "question_en": "You would like to buy 2 fruits. If there are 4 types of fruit to choose from, how many ways are there for you to buy?\n",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "4 2 [OP_COMB]",
        "solution_abst_en": "4 2 [OP_COMB]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))"
    },
    "6083": {
        "category": "Possibility",
        "question_ko": "1에서 999까지의 숫자를 차례로 이어 써서 1234567891011121314...998999를 만들었다. 이 수의 각 자리 숫자들의 총합을 구하여라.",
        "question_en": "1234567891011121314...998999 was created by writing the numbers from 1 to 999 in order. Find the sum of each digit in this number.",
        "answer_ko": "13500",
        "answer_en": "13500",
        "solution_abst_ko": "1 999 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] [OP_LIST_SUM]",
        "solution_abst_en": "1 999 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_b=[]\nfor i in list_a:\n    var_d = 0\n    i = int(i)\n    while i//10 > 0:\n        var_d = var_d + i%10\n        i = i//10\n    var_d = var_d + i%10\n    list_b.append(var_d)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_b=[]\nfor i in list_a:\n    var_d = 0\n    i = int(i)\n    while i//10 > 0:\n        var_d = var_d + i%10\n        i = i//10\n    var_d = var_d + i%10\n    list_b.append(var_d)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint(int(var_e))"
    },
    "6084": {
        "category": "Possibility",
        "question_ko": "A, B, C, D, E, F 6명의 학생이 있을 때, 회장 1명, 서기 1명을 뽑는 경우의 수를 구하시오.",
        "question_en": "When there are 6 students A, B, C, D, E, and F, find the number of ways to select 1 president and 1 secretary.",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "6 1 1 [OP_ADD] [OP_PERM]",
        "solution_abst_en": "6 1 1 [OP_ADD] [OP_PERM]",
        "solution_code_ko": "var_a = 6\nvar_b = 1\nvar_c = 1\nvar_d = var_b + var_c\nvar_e = 1\nvar_a = int(var_a)\nvar_d = int(var_d)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e * (var_a-i)\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 1\nvar_c = 1\nvar_d = var_b + var_c\nvar_e = 1\nvar_a = int(var_a)\nvar_d = int(var_d)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e * (var_a-i)\nprint(int(var_e))"
    },
    "6085": {
        "category": "Geometry",
        "question_ko": "길이가 10.4센티미터(㎝)인 색종이 16개를 3.5센티미터(㎝)씩 겹치게 이어 붙여 목걸이를 만들었습니다. 색종이로 만든 목걸이의 전체 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "A necklace is made by attaching 16 pieces of colored paper each 10.4 centimeters (cm) in length, overlapping each other by 3.5 centimeters (cm). How many centimeters (cm) is the total length of the necklace made of colored paper?",
        "answer_ko": "110.40",
        "answer_en": "110.4",
        "solution_abst_ko": "10.4 16 [OP_MUL] 3.5 16 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "10.4 16 [OP_MUL] 3.5 16 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 10.4\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 3.5\nvar_e = 16\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 10.4\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 3.5\nvar_e = 16\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "6086": {
        "category": "Geometry",
        "question_ko": "미영이는 겉넓이가 96제곱센티미터(㎠)인 정육면체 모양의 상자 8개를 이용해 큰 정육면체를 만들었습니다. 이 큰 정육면체의 부피는?",
        "question_en": "Miyoung made a large cube using 8 cube-shaped boxes with a surface area of 96 square centimeters (㎠). What is the volume of this large cube?",
        "answer_ko": "512",
        "answer_en": "512",
        "solution_abst_ko": "96 6 [OP_DIV] 1/2 [OP_POW] 8 2 [OP_DIV] 2 [OP_DIV] [OP_MUL] 3 [OP_POW]",
        "solution_abst_en": "96 6 [OP_DIV] 1/2 [OP_POW] 8 2 [OP_DIV] 2 [OP_DIV] [OP_MUL] 3 [OP_POW]",
        "solution_code_ko": "var_a = 96\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 8\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = 2\nvar_j = var_h / var_i\nvar_k = var_e * var_j\nvar_l = 3\nvar_m = var_k ** var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 96\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 8\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = 2\nvar_j = var_h / var_i\nvar_k = var_e * var_j\nvar_l = 3\nvar_m = var_k ** var_l\nprint(int(var_m))"
    },
    "6087": {
        "category": "Correspondence",
        "question_ko": "세 자리 수 식으로 표현된 AB9=459 에서 A를 구하시오.",
        "question_en": "Find A from this formula AB9=459 which is expressed as a three-digit number.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "AB9=459 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "AB9=459 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'AB9=459'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'AB9=459'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "6088": {
        "category": "Correspondence",
        "question_ko": "세 자리 수 751은 7A5보다 작습니다. A는 십의 자리 숫자이고 A에는 0부터 9까지의 숫자를 쓸 수 있습니다. A에 쓸 수 있는 숫자는 모두 몇 개입니까?",
        "question_en": "The three-digit number 751 is less than 7A5. A is a tens digit and can contain any number from 0 to 9. How many digits can you write in A?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "7A5 [OP_GEN_POSSIBLE_LIST] 751 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "7A5 [OP_GEN_POSSIBLE_LIST] 751 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '7A5'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 751\nlist_b = []\nfor i in list_a:\n    if i < var_b:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))",
        "solution_code_en": "var_a = '7A5'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 751\nlist_b = []\nfor i in list_a:\n    if i < var_b:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))"
    },
    "6089": {
        "category": "Arithmetic calculation",
        "question_ko": "주스가 6병 들어있는 상자가 7개 있었는데 상자를 옮기다가 상자 세 개에 담겨 있는 주스 병들을 깼다. 남아 있는 주스는 모두 몇 병일까?",
        "question_en": "There were 7 crates containing 6 bottles of juice each, and I broke the juice bottles in 3 of the crates while moving the crates. How many bottles of juice are left?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "7 3 [OP_SUB] 6 [OP_MUL]",
        "solution_abst_en": "7 3 [OP_SUB] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 7\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 7\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "6090": {
        "category": "Correspondence",
        "question_ko": "어떤 소수의 소수점을 왼쪽으로 한 자리 옮기면 원래의 소수보다 0.72만큼 작아집니다. 원래의 소수를 구하시오.",
        "question_en": "Moving a decimal point to the left by one place makes a particular decimal number 0.72 less than it originally was. Find the original decimal.",
        "answer_ko": "0.80",
        "answer_en": "0.8",
        "solution_abst_ko": "0.72 0.9 [OP_DIV]",
        "solution_abst_en": "0.72 0.9 [OP_DIV]",
        "solution_code_ko": "var_a = 0.72\nvar_b = 0.9\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 0.72\nvar_b = 0.9\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "6091": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 4로 나누어야 할 것을 잘못하여 어떤 수에 4를 곱했더니 32가 되었습니다. 바르게 계산하면 얼마인지 구해 보시오.",
        "question_en": "I made the mistake of multiplying a number by 4, when I should have divided this number by 4. I got 32 from this miscalculation. Find out how much it is if I calculate it correctly.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "32 4 [OP_DIV] 4 [OP_DIV]",
        "solution_abst_en": "32 4 [OP_DIV] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 32\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 32\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "6092": {
        "category": "Geometry",
        "question_ko": "윤석이를 포함한 12명의 친구가 십이각형을 그리고 서 있습니다. 모든 학생들이 자신의 양옆 친구를 제외하고 모든 친구와 한 번씩 악수를 했습니다. 윤석이는 몇 번의 악수를 했습니까?",
        "question_en": "12 friends, including Yoonseok, are standing as a dodecagon. Every student shook hands once with every friend except for the friend on either side of them. How many handshakes did Yoonseok shake?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "12 3 [OP_SUB]",
        "solution_abst_en": "12 3 [OP_SUB]",
        "solution_code_ko": "var_a = 12\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 12\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "6093": {
        "category": "Comparison",
        "question_ko": "두 원 (가), (나)가 있습니다. (가)의 넓이는 25제곱센티미터(㎠)이고, (나)의 넓이는 49제곱센티미터(㎠)입니다. 원주율을 3.1로 계산할 때 더 큰 원의 지름의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "There are two circles A and B. The area of A is 25 square centimeters (cm2), and the area of B is 49 square centimeters (cm2). How many centimeters (cm) is the diameter of the larger circle when pi is calculated as 3.1?",
        "answer_ko": "7.95",
        "answer_en": "7.95",
        "solution_abst_ko": "[OP_LIST_SOL] 25 49 [OP_LIST_EOL] 1 [OP_LIST_MAX] 3.1 [OP_DIV] 0.5 [OP_POW] 2 [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 25 49 [OP_LIST_EOL] 1 [OP_LIST_MAX] 3.1 [OP_DIV] 0.5 [OP_POW] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 25\nvar_b = 49\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[-var_c]\nvar_e = 3.1\nvar_f = var_d / var_e\nvar_g = 0.5\nvar_h = var_f ** var_g\nvar_i = 2\nvar_j = var_h * var_i\nprint('{:.2f}'.format(round(var_j+1e-10,2)))",
        "solution_code_en": "var_a = 25\nvar_b = 49\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[-var_c]\nvar_e = 3.1\nvar_f = var_d / var_e\nvar_g = 0.5\nvar_h = var_f ** var_g\nvar_i = 2\nvar_j = var_h * var_i\nprint('{:.2f}'.format(round(var_j+1e-10,2)))"
    },
    "6094": {
        "category": "Comparison",
        "question_ko": "윤기는 4개, 정국이는 6에 3을 합한 개수의 사과를 가지고 있습니다. 누가 더 사과를 적게 가지고 있습니까?",
        "question_en": "Yoongi has 4 apples and Jungkook has 6 plus 3 apples. Who has fewer apples?",
        "answer_ko": "윤기",
        "answer_en": "Yoongi",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 6\nvar_e = 3\nvar_f = var_d + var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 6\nvar_e = 3\nvar_f = var_d + var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "6095": {
        "category": "Possibility",
        "question_ko": "주어진 숫자 카드 7, 5, 2를 한 번씩 모두 사용하여 530보다 크고 710보다 작은 수를 만들 때, 일의 자리에 올 수 있는 숫자를 쓰시오.",
        "question_en": "When using all of the given number cards 7, 5, and 2 once to make a number greater than 530 and less than 710, write the number that can be placed in the ones place.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 7 5 2 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 530 [OP_LIST_MORE] 710 [OP_LIST_LESS] 1 [OP_LIST_GET] 100 [OP_MOD] 10 [OP_MOD]",
        "solution_abst_en": "[OP_LIST_SOL] 7 5 2 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 530 [OP_LIST_MORE] 710 [OP_LIST_LESS] 1 [OP_LIST_GET] 100 [OP_MOD] 10 [OP_MOD]",
        "solution_code_ko": "var_a = 7\nvar_b = 5\nvar_c = 2\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 530\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = 710\nlist_d = []\nfor i in list_c:\n    if i < var_f:\n        list_d.append(i)\nvar_g = 1\nvar_h = list_d[var_g-1]\nvar_i = 100\nvar_j = var_h % var_i\nvar_k = 10\nvar_l = var_j % var_k\nprint(int(var_l))",
        "solution_code_en": "var_a = 7\nvar_b = 5\nvar_c = 2\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 530\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = 710\nlist_d = []\nfor i in list_c:\n    if i < var_f:\n        list_d.append(i)\nvar_g = 1\nvar_h = list_d[var_g-1]\nvar_i = 100\nvar_j = var_h % var_i\nvar_k = 10\nvar_l = var_j % var_k\nprint(int(var_l))"
    },
    "6096": {
        "category": "Arithmetic calculation",
        "question_ko": "1묶음의 개수는 10개입니다. X는 2묶음에 낱개로 6개 있고, Y는 4묶을에 낱개로 1개 있다면, X와 Y의 합은 얼마입니까?",
        "question_en": "A one bundle means 10. If X is comprised of 6 plus 2 bundles, and Y is comprised of 1 plus 4 bundles, what is the sum of X and Y?",
        "answer_ko": "67",
        "answer_en": "67",
        "solution_abst_ko": "10 2 [OP_MUL] 6 [OP_ADD] 10 4 [OP_MUL] 1 [OP_ADD] [OP_ADD]",
        "solution_abst_en": "10 2 [OP_MUL] 6 [OP_ADD] 10 4 [OP_MUL] 1 [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c + var_d\nvar_f = 10\nvar_g = 4\nvar_h = var_f * var_g\nvar_i = 1\nvar_j = var_h + var_i\nvar_k = var_e + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 10\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c + var_d\nvar_f = 10\nvar_g = 4\nvar_h = var_f * var_g\nvar_i = 1\nvar_j = var_h + var_i\nvar_k = var_e + var_j\nprint(int(var_k))"
    },
    "6097": {
        "category": "Arithmetic calculation",
        "question_ko": "민지는 기차를 타고 선경이는 자동차를 타고 출발했습니다. 자동차는 1시간에 65킬로미터(km)를 가고 기차는 1시간에 95킬로미터(km)를 타고 간다면, 8시간 후 민진이와 선경이의 거리는 얼마나 차이납니까?",
        "question_en": "Minji took the train and Seonkyung took the car. If the car travels 65 kilometers (km) per hour and the train travels 95 kilometers (km) per hour, how long is the distance between Minjin and Seonkyung after 8 hours?",
        "answer_ko": "240",
        "answer_en": "240",
        "solution_abst_ko": "95 65 [OP_SUB] 8 [OP_MUL]",
        "solution_abst_en": "95 65 [OP_SUB] 8 [OP_MUL]",
        "solution_code_ko": "var_a = 95\nvar_b = 65\nvar_c = var_a - var_b\nvar_d = 8\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 95\nvar_b = 65\nvar_c = var_a - var_b\nvar_d = 8\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "6098": {
        "category": "Correspondence",
        "question_ko": "6A5+10B=748이 성립합니다. B는 무엇인가요?",
        "question_en": "Find the number B that satisfies 6A5+10B=748, where 6A5 and 10B are three-digit numbers.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "6A5+10B=748 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "6A5+10B=748 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '6A5+10B=748'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '6A5+10B=748'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "6099": {
        "category": "Comparison",
        "question_ko": "28 초과 31 이하인 자연수를 모두 평균 내면 모두 얼마인가요?",
        "question_en": "What is the average of all natural numbers greater than 28 and less than or equal to 31?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "28 1 [OP_ADD] 31 1 [OP_LIST_ARANGE] [OP_LIST_MEAN]",
        "solution_abst_en": "28 1 [OP_ADD] 31 1 [OP_LIST_ARANGE] [OP_LIST_MEAN]",
        "solution_code_ko": "var_a = 28\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 31\nvar_e = 1\nlist_a = [i for i in range(var_c, var_d + 1, var_e)]\nlist_a = [float(i) for i in list_a]\nvar_f = sum(list_a)/len(list_a)\nprint(int(var_f))",
        "solution_code_en": "var_a = 28\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 31\nvar_e = 1\nlist_a = [i for i in range(var_c, var_d + 1, var_e)]\nlist_a = [float(i) for i in list_a]\nvar_f = sum(list_a)/len(list_a)\nprint(int(var_f))"
    },
    "6100": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 43을 더했더니 81이 되었습니다. 어떤 수에 25를 더하면 얼마가 되는지 구하시오.",
        "question_en": "When you add 43 to a number, you get 81. What is the result of adding 25 to this number?",
        "answer_ko": "63",
        "answer_en": "63",
        "solution_abst_ko": "81 43 [OP_SUB] 25 [OP_ADD]",
        "solution_abst_en": "81 43 [OP_SUB] 25 [OP_ADD]",
        "solution_code_ko": "var_a = 81\nvar_b = 43\nvar_c = var_a - var_b\nvar_d = 25\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 81\nvar_b = 43\nvar_c = var_a - var_b\nvar_d = 25\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "6101": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 소수의 소수점을 오른쪽으로 두 자리 옮기면 원래보다 29.7만큼 커집니다. 원래의 소수를 구하시오.",
        "question_en": "Moving any decimal point two places to the right increases it by 29.7. Find the original decimal.",
        "answer_ko": "0.30",
        "answer_en": "0.3",
        "solution_abst_ko": "29.7 10 2 [OP_POW] 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "29.7 10 2 [OP_POW] 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 29.7\nvar_b = 10\nvar_c = 2\nvar_d = var_b ** var_c\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_a / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 29.7\nvar_b = 10\nvar_c = 2\nvar_d = var_b ** var_c\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_a / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "6102": {
        "category": "Arithmetic calculation",
        "question_ko": "수박 3개, 사과 7개가 있다. 참외는 수박과 사과의 개수의 합의 두 배 일때 참외는 몇개 있는가?",
        "question_en": "There are 3 watermelons and 7 apples. How many melons are there when the number of melons is twice the sum of the number of watermelons and apples?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "3 7 [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "3 7 [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 3\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "6103": {
        "category": "Possibility",
        "question_ko": "0, 2, 4, 6 중에서 3개 뽑아 한 번씩만 사용하여 세 자리 수를 만들려고 합니다. 만들 수 있는 가장 큰 수와 가장 작은 수의 합을 구하시오.",
        "question_en": "You want to create a three-digit number by drawing three from 0, 2, 4, and 6 and using them only once. Find the sum of the largest and smallest possible numbers.",
        "answer_ko": "846",
        "answer_en": "846",
        "solution_abst_ko": "[OP_LIST_SOL] 0 2 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 0 2 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 0\nvar_b = 2\nvar_c = 4\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 0\nvar_b = 2\nvar_c = 4\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))"
    },
    "6104": {
        "category": "Comparison",
        "question_ko": "유나는 마트에서 77번째로 줄을 섰고, 유정이는 유나보다 15명 앞에 줄을 섰습니다. 유정이는 몇 번째로 섰습니까?",
        "question_en": "Yuna was 77th in line at a market, there were 15 people between Yuna and Yoojeong, who was ahead of Yuna. In what place is Yoojeong standing in line? Express in ordinal number.",
        "answer_ko": "61",
        "answer_en": "61",
        "solution_abst_ko": "77 15 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "77 15 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 77\nvar_b = 15\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 77\nvar_b = 15\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "6105": {
        "category": "Correspondence",
        "question_ko": "호석이는 7을 어떤 수에서 빼 9를 얻었고, 이 수에 3을 곱했습니다. 호석이가 구한 결과는 얼마입니까?",
        "question_en": "Hoseok subtracted 7 from a number to get 9, then multiplied this number by 3. What is the result Hoseok would get?",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "9 7 [OP_ADD] 3 [OP_MUL]",
        "solution_abst_en": "9 7 [OP_ADD] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 9\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "6106": {
        "category": "Arithmetic calculation",
        "question_ko": "신영이는 어머니께서 주신 용돈의 1/2를 저축하고, 그 나머지의 3/8으로 학용품을 샀더니 2500원이 남았습니다. 신영이가 저축한 돈은 얼마입니까?",
        "question_en": "Shinyoung saved 1/2 of her mother's pocket money and bought school supplies with the remaining 3/8, leaving 2,500 won. How much money does Shinyoung save?",
        "answer_ko": "4000",
        "answer_en": "4000",
        "solution_abst_ko": "2500 1 3/8 [OP_SUB] [OP_DIV] 1/2 [OP_DIV] 1/2 [OP_MUL]",
        "solution_abst_en": "2500 1 3/8 [OP_SUB] [OP_DIV] 1/2 [OP_DIV] 1/2 [OP_MUL]",
        "solution_code_ko": "var_a = 2500\nvar_b = 1\nvar_c = 0.375\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 0.5\nvar_g = var_e / var_f\nvar_h = 0.5\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 2500\nvar_b = 1\nvar_c = 0.375\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 0.5\nvar_g = var_e / var_f\nvar_h = 0.5\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "6107": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 -2/3을 곱하고 -4/5를 나누면 -1/2일 때, 어떤 수를 구하시오.",
        "question_en": "If a number multiplied by -2/3 and divided by -4/5 equals -1/2, what number is it?",
        "answer_ko": "-0.6",
        "answer_en": "-0.6",
        "solution_abst_ko": "-1/2 -4/5 [OP_MUL] -2/3 [OP_DIV]",
        "solution_abst_en": "-1/2 -4/5 [OP_MUL] -2/3 [OP_DIV]",
        "solution_code_ko": "var_a = -0.5\nvar_b = -0.8\nvar_c = var_a * var_b\nvar_d = -0.6666666666666666\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = -0.5\nvar_b = -0.8\nvar_c = var_a * var_b\nvar_d = -0.6666666666666666\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "6108": {
        "category": "Possibility",
        "question_ko": "여학생 4명과 남학생 3명이 있습니다. 여학생 한 명과 남학생 한 명이 주번이 되려고 한다면 가능한 주번의 종류는 몇 가지 인가요?",
        "question_en": "There are 4 female students and 3 male students. If one female student and one male student want to be in charge of weekly duty, in how many ways can you choose students to be in charge of weekly duty?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "4 1 [OP_COMB] 3 1 [OP_COMB] [OP_MUL]",
        "solution_abst_en": "4 1 [OP_COMB] 3 1 [OP_COMB] [OP_MUL]",
        "solution_code_ko": "var_a = 4\nvar_b = 1\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nvar_d = 3\nvar_e = 1\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f / (i+1)\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 1\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nvar_d = 3\nvar_e = 1\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f / (i+1)\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "6109": {
        "category": "Arithmetic calculation",
        "question_ko": "1.48, 2.32, 8.45의 총합은 얼마입니까?",
        "question_en": "What is the sum of 1.48, 2.32, and 8.45?",
        "answer_ko": "12.25",
        "answer_en": "12.25",
        "solution_abst_ko": "1.48 2.32 [OP_ADD] 8.45 [OP_ADD]",
        "solution_abst_en": "1.48 2.32 [OP_ADD] 8.45 [OP_ADD]",
        "solution_code_ko": "var_a = 1.48\nvar_b = 2.32\nvar_c = var_a + var_b\nvar_d = 8.45\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 1.48\nvar_b = 2.32\nvar_c = var_a + var_b\nvar_d = 8.45\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "6110": {
        "category": "Arithmetic calculation",
        "question_ko": "수도에서 물이 분당 36.6리터(L)나온다고 합니다. 또한 분당 2.4리터(L)의 물이 증발한다고 합니다. 처음에는 물이 10리터(L) 있었다면 7분 45초 후에는 몇 리터(L)있을까요?",
        "question_en": "It is said that water comes out of the faucet at 36.6 liters (L) per minute. It is also said that 2.4 liters (L) of water evaporates per minute. If there were 10 liters (L) of water at the beginning, how many liters (L) will there be after 7 minutes and 45 seconds?",
        "answer_ko": "275.05",
        "answer_en": "275.05",
        "solution_abst_ko": "10 36.6 2.4 [OP_SUB] 7 45 60 [OP_DIV] [OP_ADD] [OP_MUL] [OP_ADD]",
        "solution_abst_en": "10 36.6 2.4 [OP_SUB] 7 45 60 [OP_DIV] [OP_ADD] [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 36.6\nvar_c = 2.4\nvar_d = var_b - var_c\nvar_e = 7\nvar_f = 45\nvar_g = 60\nvar_h = var_f / var_g\nvar_i = var_e + var_h\nvar_j = var_d * var_i\nvar_k = var_a + var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 10\nvar_b = 36.6\nvar_c = 2.4\nvar_d = var_b - var_c\nvar_e = 7\nvar_f = 45\nvar_g = 60\nvar_h = var_f / var_g\nvar_i = var_e + var_h\nvar_j = var_d * var_i\nvar_k = var_a + var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "6111": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 소수의 소수점을 왼쪽으로 세 자리 옮겼더니 원래보다 2.71만큼 더 작아졌습니다. 원래의 소수를 구하시오.",
        "question_en": "Moving the decimal point of a decimal number three digits left makes it 2.71 smaller than it originally was. Find the original decimal number.",
        "answer_ko": "2.71",
        "answer_en": "2.71",
        "solution_abst_ko": "2.71 1 0.1 3 [OP_POW] [OP_SUB] [OP_DIV]",
        "solution_abst_en": "2.71 1 0.1 3 [OP_POW] [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 2.71\nvar_b = 1\nvar_c = 0.1\nvar_d = 3\nvar_e = var_c ** var_d\nvar_f = var_b - var_e\nvar_g = var_a / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 2.71\nvar_b = 1\nvar_c = 0.1\nvar_d = 3\nvar_e = var_c ** var_d\nvar_f = var_b - var_e\nvar_g = var_a / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "6112": {
        "category": "Arithmetic calculation",
        "question_ko": "태형이는 161문제가 있는 문제집을 7일 동안 풀었습니다. 태형이가 하루에 푼 문제는 평균 몇 문제인지 구하세요.",
        "question_en": "Taehyung solved the workbook with 161 problems for 7 days. Find the average number of problems Taehyung solved per day.",
        "answer_ko": "23",
        "answer_en": "23",
        "solution_abst_ko": "161 7 [OP_DIV]",
        "solution_abst_en": "161 7 [OP_DIV]",
        "solution_code_ko": "var_a = 161\nvar_b = 7\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 161\nvar_b = 7\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "6113": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 8 을 뺀 값은 5 와 7 의 곱에 12 를 더한 값과 같습니다. 어떤 수는 얼마인지 구하시오.",
        "question_en": "A number minus 8 equals 5 times 7 plus 12. Find the value of the number.",
        "answer_ko": "55",
        "answer_en": "55",
        "solution_abst_ko": "5 7 [OP_MUL] 12 [OP_ADD] 8 [OP_ADD]",
        "solution_abst_en": "5 7 [OP_MUL] 12 [OP_ADD] 8 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "6114": {
        "category": "Arithmetic calculation",
        "question_ko": "윤기네 학교 학생 수는 280명이고 그중에서 여학생은 127명입니다. 윤기네 학교는 남학생이 여학생보다 몇 명 더 많은지 구하시오.",
        "question_en": "Yoongi's school has 280 students, 127 of which are female students. Find how many more male students than female students in Yoongi's school.",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "280 127 [OP_SUB] 127 [OP_SUB]",
        "solution_abst_en": "280 127 [OP_SUB] 127 [OP_SUB]",
        "solution_code_ko": "var_a = 280\nvar_b = 127\nvar_c = var_a - var_b\nvar_d = 127\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 280\nvar_b = 127\nvar_c = var_a - var_b\nvar_d = 127\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "6115": {
        "category": "Arithmetic calculation",
        "question_ko": "민기네 수학 시험의 범위는 교과서 8쪽부터 21쪽 까지이다. 총 몇 장인가?",
        "question_en": "Mingi's math test covers from page 8 to page 21 of the textbook. How many pages is it in total?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "8 21 1 [OP_LIST_ARANGE] [OP_LIST_LEN]",
        "solution_abst_en": "8 21 1 [OP_LIST_ARANGE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 8\nvar_b = 21\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = len(list_a)\nprint(int(var_d))",
        "solution_code_en": "var_a = 8\nvar_b = 21\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = len(list_a)\nprint(int(var_d))"
    },
    "6116": {
        "category": "Correspondence",
        "question_ko": "7A5+B7C=D38에서 A부터 D는 서로 다른 수입니다. D는 얼마입니까?",
        "question_en": "In the three-digit addition expression 7A5+B7C=D38, A through D are different numbers. How much is D?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "7A5+B7C=D38 D [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "7A5+B7C=D38 D [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '7A5+B7C=D38'\nvar_b = 'D'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '7A5+B7C=D38'\nvar_b = 'D'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "6117": {
        "category": "Comparison",
        "question_ko": "수영 시합에서 누나는 51등으로 결승선을 넘었고, 할아버지는 53등으로 결승선을 넘었습니다. 나는 할아버지보다 잘했지만 누나보다는 못했습니다. 나의 등수는 몇 등입니까?",
        "question_en": "In the swimming competition, my sister crossed the finish line in 51st place, and my grandfather crossed the finish line in 53rd place. I was better than my grandfather but worse than my sister. What is my rank?",
        "answer_ko": "52",
        "answer_en": "52",
        "solution_abst_ko": "51 53 [OP_ADD] 2 [OP_FDIV]",
        "solution_abst_en": "51 53 [OP_ADD] 2 [OP_FDIV]",
        "solution_code_ko": "var_a = 51\nvar_b = 53\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 51\nvar_b = 53\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "6118": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 가장 큰 수를 가장 작은 수로 나눈 몫은 얼마입니까?",
        "question_en": "When there are five different numbers: 10, 11, 12, 13, and 14, what is the quotient of the largest number divided by the smallest number?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_FDIV]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_FDIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g // var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g // var_i\nprint(int(var_j))"
    },
    "6119": {
        "category": "Comparison",
        "question_ko": "윤기는 4, 유나는 5, 정국에는 6에서 3을 뺀 수를 모았습니다. 누가 가장 큰 수를 가지고 있나요?",
        "question_en": "Yoongi has 4, and Yuna has 5, and Jungkook has 6 minus 3. Who has the biggest number?",
        "answer_ko": "유나",
        "answer_en": "Yuna",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 유나 정국 [OP_LIST_EOL] [OP_LIST_SOL] 4 5 6 3 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Yuna Jungkook [OP_LIST_EOL] [OP_LIST_SOL] 4 5 6 3 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '유나'\nvar_c = '정국'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 5\nvar_f = 6\nvar_g = 3\nvar_h = var_f - var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Yuna'\nvar_c = 'Jungkook'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 5\nvar_f = 6\nvar_g = 3\nvar_h = var_f - var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "6120": {
        "category": "Arithmetic calculation",
        "question_ko": "15.58, 21.32, 642.51 51.51의 총합은 얼마입니까?",
        "question_en": "What is the sum of 15.58, 21.32, 642.51, and 51.51?",
        "answer_ko": "730.92",
        "answer_en": "730.92",
        "solution_abst_ko": "15.58 21.32 [OP_ADD] 642.51 [OP_ADD] 51.51 [OP_ADD]",
        "solution_abst_en": "15.58 21.32 [OP_ADD] 642.51 [OP_ADD] 51.51 [OP_ADD]",
        "solution_code_ko": "var_a = 15.58\nvar_b = 21.32\nvar_c = var_a + var_b\nvar_d = 642.51\nvar_e = var_c + var_d\nvar_f = 51.51\nvar_g = var_e + var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 15.58\nvar_b = 21.32\nvar_c = var_a + var_b\nvar_d = 642.51\nvar_e = var_c + var_d\nvar_f = 51.51\nvar_g = var_e + var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "6121": {
        "category": "Comparison",
        "question_ko": "20명의 학생들이 버스를 기다리고 있습니다. 정국이는 윤기보다 먼저 왔고, 윤기와 정국이 사이에는 5명의 학생이 있습니다. 정국의 앞에는 6명의 학생들이 서 있습니다. 윤기의 뒤에 서 있는 학생은 몇 명입니까?",
        "question_en": "20 students are waiting for the bus. Jungkook came before Yoongi, and there are 5 students between Yoongi and Jungkook. There are 6 students standing in front of Jungkook. How many students are standing behind Yoongi?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "20 6 [OP_SUB] 1 [OP_SUB] 5 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "20 6 [OP_SUB] 1 [OP_SUB] 5 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 6\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 5\nvar_g = var_e - var_f\nvar_h = 1\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 20\nvar_b = 6\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 5\nvar_g = var_e - var_f\nvar_h = 1\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "6122": {
        "category": "Possibility",
        "question_ko": "A, B, C, D, E 5명이 있을 때, C, D를 이웃하여 세우는 경우의 수를 구하시오.",
        "question_en": "If there are 5 people, A, B, C, D, and E, find the number of ways to put C and D next to each other.",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "[OP_LIST_SOL] A B C D E [OP_LIST_EOL] [OP_LIST_SOL] C [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] C D [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D E [OP_LIST_EOL] [OP_LIST_SOL] C [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] C D [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 'C'\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_g = len(list_c)\nvar_h = len(list_c)\nvar_i = 1\nvar_g = int(var_g)\nvar_h = int(var_h)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i * (var_g-i)\nvar_j = 'C'\nvar_k = 'D'\nlist_d= []\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_d.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_d.append(var_j)\nlist_d.reverse()\nvar_l = len(list_d)\nvar_m = len(list_d)\nvar_n = 1\nvar_l = int(var_l)\nvar_m = int(var_m)\nfor i, elem in enumerate(range(var_m)):\n    var_n = var_n * (var_l-i)\nvar_o = var_i * var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 'C'\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_g = len(list_c)\nvar_h = len(list_c)\nvar_i = 1\nvar_g = int(var_g)\nvar_h = int(var_h)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i * (var_g-i)\nvar_j = 'C'\nvar_k = 'D'\nlist_d= []\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_d.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_d.append(var_j)\nlist_d.reverse()\nvar_l = len(list_d)\nvar_m = len(list_d)\nvar_n = 1\nvar_l = int(var_l)\nvar_m = int(var_m)\nfor i, elem in enumerate(range(var_m)):\n    var_n = var_n * (var_l-i)\nvar_o = var_i * var_n\nprint(int(var_o))"
    },
    "6123": {
        "category": "Correspondence",
        "question_ko": "혜진이의 나이와 혜진이 동생의 나이를 곱하였더니 12가 되었을 때, 혜진이의 나이로 가능한 수는 몇 개입니까?",
        "question_en": "When Hyejin's age is multiplied by Hyejin's younger sister's age, and the result is 12, how many possible numbers can there be with Hyejin's age?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "12 [OP_LIST_GET_DIVISOR] [OP_LIST_LEN] 2 [OP_FDIV]",
        "solution_abst_en": "12 [OP_LIST_GET_DIVISOR] [OP_LIST_LEN] 2 [OP_FDIV]",
        "solution_code_ko": "var_a = 12\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = len(list_a)\nvar_c = 2\nvar_d = var_b // var_c\nprint(int(var_d))",
        "solution_code_en": "var_a = 12\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = len(list_a)\nvar_c = 2\nvar_d = var_b // var_c\nprint(int(var_d))"
    },
    "6124": {
        "category": "Possibility",
        "question_ko": "숫자 카드 1, 2, 4, 8, 9 중에서 3장을 뽑아 만들 수 있는 자연수의 개수를 구하시오.",
        "question_en": "Find the number of natural numbers that can be made with three of the number cards 1, 2, 4, 8, and 9.",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "[OP_LIST_SOL] 1 2 4 8 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 2 4 8 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 2\nvar_c = 4\nvar_d = 8\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 2\nvar_c = 4\nvar_d = 8\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "6125": {
        "category": "Comparison",
        "question_ko": "체육시간에 미주의 양옆에는 각각 5, 6줄의 학생들이 섰고, 앞뒤에는 각각 6, 7줄의 학생들이 섰다면 각 줄마다 있는 학생의 수가 같다고 할 때, 체육수업을 듣는 학생은 모두 몇 명입니까?",
        "question_en": "In a PE class, if there are 5 and 6 rows of students on either side of Mijoo, and 6 and 7 rows of students in front of and behind her, respectively, and the number of students in each row is the same, how many students are in PE class in total?",
        "answer_ko": "168",
        "answer_en": "168",
        "solution_abst_ko": "5 6 [OP_ADD] 1 [OP_ADD] 6 7 [OP_ADD] 1 [OP_ADD] [OP_MUL]",
        "solution_abst_en": "5 6 [OP_ADD] 1 [OP_ADD] 6 7 [OP_ADD] 1 [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 6\nvar_g = 7\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h + var_i\nvar_k = var_e * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 5\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 6\nvar_g = 7\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h + var_i\nvar_k = var_e * var_j\nprint(int(var_k))"
    },
    "6126": {
        "category": "Comparison",
        "question_ko": "귤은 한 바구니에 28개씩 40바구니가 있고, 자두는 한 바구니에 15개씩 65바구니가 있습니다. 귤과 자두 중 어떤 것이 더 많습니까?",
        "question_en": "There are 40 baskets of tangerines, 28 each, and 65 baskets of plums, 15 each. Which one has the bigger number among tangerines and plums?",
        "answer_ko": "귤",
        "answer_en": "tangerines",
        "solution_abst_ko": "[OP_LIST_SOL] 귤 자두 [OP_LIST_EOL] [OP_LIST_SOL] 28 40 [OP_MUL] 15 65 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] tangerines plums [OP_LIST_EOL] [OP_LIST_SOL] 28 40 [OP_MUL] 15 65 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '귤'\nvar_b = '자두'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 28\nvar_d = 40\nvar_e = var_c * var_d\nvar_f = 15\nvar_g = 65\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'tangerines'\nvar_b = 'plums'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 28\nvar_d = 40\nvar_e = var_c * var_d\nvar_f = 15\nvar_g = 65\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "6127": {
        "category": "Comparison",
        "question_ko": "칠판에 5개의 숫자 1.4, 9/10, 1.1, 0.5, 13/10가 적혀 있습니다. 칠판에 적힌 수 중에서 0.9보다 큰 수는 몇 개입니까?",
        "question_en": "The five numbers 1.4, 9/10, 1.1, 0.5, and 13/10 are written on the blackboard. How many of the numbers written on the board are greater than 0.9?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.1 0.5 13/10 [OP_LIST_EOL] 0.9 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.1 0.5 13/10 [OP_LIST_EOL] 0.9 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.1\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 0.9\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.1\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 0.9\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "6128": {
        "category": "Arithmetic calculation",
        "question_ko": "50이상 100이하인 수 중에서 8로 나누었을 때 나머지가 4인 수는 모두 몇 개입니까?",
        "question_en": "How many numbers that are greater than 50 and less than 100 have a remainder of 4 when divided by 8?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "50 100 1 [OP_LIST_ARANGE] 8 4 [OP_LIST_DIVIDE_AND_REMAIN] [OP_LIST_LEN]",
        "solution_abst_en": "50 100 1 [OP_LIST_ARANGE] 8 4 [OP_LIST_DIVIDE_AND_REMAIN] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 50\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 8\nvar_e = 4\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 50\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 8\nvar_e = 4\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "6129": {
        "category": "Correspondence",
        "question_ko": "8명이 사용하던 젓가락을 4개씩 나누면 몇 묶음이 나오는가?",
        "question_en": "If you divide the chopsticks used by 8 people into 4 groups, how many bundles will you get?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "8 2 [OP_MUL] 4 [OP_DIV]",
        "solution_abst_en": "8 2 [OP_MUL] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 8\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "6130": {
        "category": "Geometry",
        "question_ko": "가로의 길이가 세로의 길이보다 3 센티미터(㎝) 더 긴 직사각형의 둘레의 길이가 54 센티미터(㎝)일 때, 가로의 길이를 구하시오.",
        "question_en": "If the perimeter of a rectangle whose width is 3 centimeters (cm) longer than its length is 54 centimeters (cm), find the length of its width.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "54 2 [OP_DIV] 3 [OP_SUB] 2 [OP_DIV] 3 [OP_ADD]",
        "solution_abst_en": "54 2 [OP_DIV] 3 [OP_SUB] 2 [OP_DIV] 3 [OP_ADD]",
        "solution_code_ko": "var_a = 54\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 3\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 3\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 54\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 3\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 3\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "6131": {
        "category": "Possibility",
        "question_ko": "0, 1, 2, 3, 4, 5의 숫자가 각각 적힌 6장의 카드 중 3개를 뽑아서 만들 수 있는 세 자리 정수의 개수는?",
        "question_en": "How many three-digit integers can be made by drawing 3 out of 6 cards with the numbers 0, 1, 2, 3, 4, and 5 written on them?",
        "answer_ko": "100",
        "answer_en": "100",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 4 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 4 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nvar_f = 5\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = len(list_b)\nprint(int(var_h))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nvar_f = 5\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = len(list_b)\nprint(int(var_h))"
    },
    "6132": {
        "category": "Correspondence",
        "question_ko": "석기는 가지고 있던 사탕의 1/2를 예슬이에게 주고, 그 나머지의 1/3을 동민이에게 주었더니 12개가 남았습니다. 석기는 처음에 몇 개의 사탕을 가지고 있었습니까?",
        "question_en": "Seokgi gave 1/2 of the candies he had to Yeseul, and gave the remaining 1/3 to Dongmin, leaving 12 candies. How many candies did Seokgi originally have at first?",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "12 1 1/3 [OP_SUB] [OP_DIV] 1 1/2 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "12 1 1/3 [OP_SUB] [OP_DIV] 1 1/2 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 1\nvar_c = 0.3333333333333333\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 1\nvar_g = 0.5\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))",
        "solution_code_en": "var_a = 12\nvar_b = 1\nvar_c = 0.3333333333333333\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 1\nvar_g = 0.5\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))"
    },
    "6133": {
        "category": "Arithmetic calculation",
        "question_ko": "한 자동차가 366.8킬로미터(㎞)를 달리는 데 휘발유 12.2리터(L)이 필요하고, 한 기름통에 들어있는 휘발유의 양은 3리터(L)입니다. 이 자동차가 533.32킬로미터(㎞)를 달리는 데 필요한 기름통은 모두 몇 통이 필요합니까?",
        "question_en": "A car needs 12.2 liters (L) of gasoline to run 366.8 kilometers (km), and the amount of gasoline in one oil drum is 3 liters (L). How many barrels of oil are needed to drive 533.32 kilometers (km)?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "12.2 366.8 [OP_DIV] 533.32 [OP_MUL] 3 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "12.2 366.8 [OP_DIV] 533.32 [OP_MUL] 3 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 12.2\nvar_b = 366.8\nvar_c = var_a / var_b\nvar_d = 533.32\nvar_e = var_c * var_d\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = 1\nvar_i=int(((var_g+9*10**(var_h-2))//(10**(var_h-1)))*10**(var_h-1))\n\nprint(int(var_i))",
        "solution_code_en": "var_a = 12.2\nvar_b = 366.8\nvar_c = var_a / var_b\nvar_d = 533.32\nvar_e = var_c * var_d\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = 1\nvar_i=int(((var_g+9*10**(var_h-2))//(10**(var_h-1)))*10**(var_h-1))\n\nprint(int(var_i))"
    },
    "6134": {
        "category": "Correspondence",
        "question_ko": "서로 다른 두 수 A, B가 있다. 8AA4-BBB=BBBB일 때 A+B는 무엇인가?",
        "question_en": "There are two different numbers A and B. What is A+B when BBB+BBBB=8AA4?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "8AA4-BBB=BBBB A [OP_DIGIT_UNK_SOLVER] 8AA4-BBB=BBBB B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_abst_en": "8AA4-BBB=BBBB A [OP_DIGIT_UNK_SOLVER] 8AA4-BBB=BBBB B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_code_ko": "var_a = '8AA4-BBB=BBBB'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '8AA4-BBB=BBBB'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = '8AA4-BBB=BBBB'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '8AA4-BBB=BBBB'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "6135": {
        "category": "Arithmetic calculation",
        "question_ko": "54보다 작고 45보다 큰 두 자리 수는 모두 몇 개입니까?",
        "question_en": "How many two-digit numbers are there that are between 45 and 54?\n",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "45 1 [OP_ADD] 54 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_LEN]",
        "solution_abst_en": "45 1 [OP_ADD] 54 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 45\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 54\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = len(list_a)\nprint(int(var_h))",
        "solution_code_en": "var_a = 45\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 54\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = len(list_a)\nprint(int(var_h))"
    },
    "6136": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중에서 2번째로 큰 수와 가장 작은 수로 나눈 나머지는 얼마입니까?",
        "question_en": "There are three numbers: 10, 11 and 12. What is the remainder when you divide the second largest number by the smallest number?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 2 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MOD]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 2 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MOD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e % var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e % var_g\nprint(int(var_h))"
    },
    "6137": {
        "category": "Geometry",
        "question_ko": "사각형의 네 변의 길이가 모두 같고 네 변의 길이의 합이 32이다. 한변의 길이가 얼마인가?",
        "question_en": "The length of all four sides of a quadrilateral is the same and the sum of the lengths of the four sides is 32. What is the length of one side?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "32 4 [OP_DIV]",
        "solution_abst_en": "32 4 [OP_DIV]",
        "solution_code_ko": "var_a = 32\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 32\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "6138": {
        "category": "Possibility",
        "question_ko": "학교에서 놀이터로 가는 길은 두 가지가 있습니다. 승아, 정혁, 형준이 학교에서 놀이터로 가는 경우의 수를 구하시오.",
        "question_en": "There are two ways to get to the playground from school. Find the number of cases in which Seung-a, Jeong-hyeok, and Hyeong-jun go from school to the playground.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "2 3 [OP_POW]",
        "solution_abst_en": "2 3 [OP_POW]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = var_a ** var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = var_a ** var_b\nprint(int(var_c))"
    },
    "6139": {
        "category": "Geometry",
        "question_ko": "반지름의 길이가 4센티미터(㎝)인 원 여러 개를 가로로 나란히 붙여서 그린 전체 도형의 가로 길이가 24센티미터(㎝)라면, 몇 개의 원을 그렸을까요?",
        "question_en": "If the horizontal length of the entire figure drawn by attaching several circles with a radius of 4 centimeters (cm) side by side is 24 centimeters (cm), how many circles are drawn?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "24 4 2 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "24 4 2 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 24\nvar_b = 4\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 24\nvar_b = 4\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "6140": {
        "category": "Arithmetic calculation",
        "question_ko": "파란 구슬은 빨간 구슬의 5배만큼 있습니다. 노란 구슬은 빨간 구슬의 3배만큼 있습니다. 파란 구슬과 노란 구슬의 개수가 모두 160개일 때, 빨간 구슬은 몇 개있을까요?",
        "question_en": "There are 5 times as many blue marbles as red marbles, and yellow marbles are three times more than red marbles. If the total number of blue marbles and yellow marbles is 160, how many red marbles are there?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "160 5 3 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "160 5 3 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 160\nvar_b = 5\nvar_c = 3\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 160\nvar_b = 5\nvar_c = 3\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "6141": {
        "category": "Arithmetic calculation",
        "question_ko": "(가) 물건을 8640개 만들었습니다. 작은 상자 1개에는 (가) 물건을 12개씩 넣고, 이렇게 만든 작은 상자를 큰 상자에 6개씩 넣어 포장했습니다. 포장한 큰 상자는 모두 몇 개입니까?",
        "question_en": "I made 8640 of (a) items. I put 12 items in each small box, and put 6 of these small boxes in a big box. How many big boxes did I pack in total?",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "8640 12 [OP_DIV] 6 [OP_DIV]",
        "solution_abst_en": "8640 12 [OP_DIV] 6 [OP_DIV]",
        "solution_code_ko": "var_a = 8640\nvar_b = 12\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8640\nvar_b = 12\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "6142": {
        "category": "Arithmetic calculation",
        "question_ko": "농장에 오리가 40마리, 토끼가 30마리 있습니다. 또 암탉은 오리보다 20마리 많고, 수탉은 토끼보다 10마리 적습니다. 농장에 있는 닭은 모두 몇 마리입니까?",
        "question_en": "There are 40 ducks and 30 rabbits on the farm. Also, the number of hens is 20 more than ducks, and the number of roosters is 10 fewer than rabbits. How many chickens are there in the farm totally?",
        "answer_ko": "80",
        "answer_en": "80",
        "solution_abst_ko": "40 20 [OP_ADD] 30 10 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "40 20 [OP_ADD] 30 10 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 40\nvar_b = 20\nvar_c = var_a + var_b\nvar_d = 30\nvar_e = 10\nvar_f = var_d - var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 40\nvar_b = 20\nvar_c = var_a + var_b\nvar_d = 30\nvar_e = 10\nvar_f = var_d - var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "6143": {
        "category": "Arithmetic calculation",
        "question_ko": "동생의 키는 민경이보다 28센티미터(㎝) 작고, 아버지의 키는 민경이보다 35센티미터(㎝) 큽니다. 아버지의 키가 1미터(m) 72센티미터(㎝)라면, 동생의 키는 몇 센티미터(㎝)일까요?",
        "question_en": "The younger brother is 28 centimeters (cm) shorter than Minkyung, and the father is 35 centimeters (cm) taller than Minkyung. If the father's height is 1 meter (m) 72 centimeters (cm), how tall is the younger brother in centimeters (cm)?",
        "answer_ko": "109",
        "answer_en": "109",
        "solution_abst_ko": "1 100 [OP_MUL] 72 [OP_ADD] 35 [OP_SUB] 28 [OP_SUB]",
        "solution_abst_en": "1 100 [OP_MUL] 72 [OP_ADD] 35 [OP_SUB] 28 [OP_SUB]",
        "solution_code_ko": "var_a = 1\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 72\nvar_e = var_c + var_d\nvar_f = 35\nvar_g = var_e - var_f\nvar_h = 28\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 72\nvar_e = var_c + var_d\nvar_f = 35\nvar_g = var_e - var_f\nvar_h = 28\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "6144": {
        "category": "Correspondence",
        "question_ko": "자연수 A에 대해 3<2×A<19를 만족하는 A의 모든 합을 구하시오",
        "question_en": "For the natural number A, find all sums of A such that 3<2×A<19",
        "answer_ko": "44",
        "answer_en": "44",
        "solution_abst_ko": "3<2×A<19 A [OP_NUM_UNK_SOLVER] [OP_LIST_SUM]",
        "solution_abst_en": "3<2×A<19 A [OP_NUM_UNK_SOLVER] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = '3<2×A<19'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nprint(int(var_c))",
        "solution_code_en": "var_a = '3<2×A<19'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nprint(int(var_c))"
    },
    "6145": {
        "category": "Possibility",
        "question_ko": "동현이는 0~9까지의 수가 적힌 숫자 카드 중 서로 다른 3장을 골라 모두 사용하여 세 자리 수를 만들고 있습니다. 이 때, 세 번째로 작은 수를 만들었습니다. 이 만든 수의 십의 자리는 1일 때 백의 자리 숫자와 일의 자리 숫자의 합은 얼마입니까?",
        "question_en": "Donghyun chooses three different number cards from 0 to 9 and uses them all to make a three-digit number. This time, he made the third smallest number where the tens digit of this number is 1. What is the sum of the hundreds digit and the ones digit?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "0 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] 3 [OP_LIST_MIN] [OP_NUM2LIST] 2 [OP_LIST_GET] 3 [OP_LIST_GET] [OP_ADD]",
        "solution_abst_en": "0 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] 3 [OP_LIST_MIN] [OP_NUM2LIST] 2 [OP_LIST_GET] 3 [OP_LIST_GET] [OP_ADD]",
        "solution_code_ko": "var_a = 0\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nlist_d = []\nvar_f = int(var_f)\nwhile var_f//10 > 0:\n    list_d.append(var_f%10)\n    var_f = var_f//10\nlist_d.append(var_f%10)\nlist_d = list_d[::-1]\nvar_g = 2\nvar_h = list_d[var_g-1]\nvar_i = 3\nvar_j = list_d[var_i-1]\nvar_k = var_h + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 0\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nlist_d = []\nvar_f = int(var_f)\nwhile var_f//10 > 0:\n    list_d.append(var_f%10)\n    var_f = var_f//10\nlist_d.append(var_f%10)\nlist_d = list_d[::-1]\nvar_g = 2\nvar_h = list_d[var_g-1]\nvar_i = 3\nvar_j = list_d[var_i-1]\nvar_k = var_h + var_j\nprint(int(var_k))"
    },
    "6146": {
        "category": "Arithmetic calculation",
        "question_ko": "민규는 문구점에서 350원짜리 지우개 3개와 180원짜리 연필 2자루를 사고 2000원을 냈습니다. 민규가 받아야 할 거스름돈은 얼마인지 구해 보시오.",
        "question_en": "Mingyu bought 3 erasers for 350 won each and 2 pencils for 180 won each at the stationery store and paid 2,000 won. Find how much change Mingyu should receive.",
        "answer_ko": "590",
        "answer_en": "590",
        "solution_abst_ko": "2000 350 3 [OP_MUL] 180 2 [OP_MUL] [OP_ADD] [OP_SUB]",
        "solution_abst_en": "2000 350 3 [OP_MUL] 180 2 [OP_MUL] [OP_ADD] [OP_SUB]",
        "solution_code_ko": "var_a = 2000\nvar_b = 350\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = 180\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = var_d + var_g\nvar_i = var_a - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 2000\nvar_b = 350\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = 180\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = var_d + var_g\nvar_i = var_a - var_h\nprint(int(var_i))"
    },
    "6147": {
        "category": "Possibility",
        "question_ko": "7/8 과 크기가 같은 분수 중에서 분모가 두 자리 수인 분수는 모두 몇 개입니까?",
        "question_en": "How many fractions of the same size as 7/8 have two-digit denominators?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "10 99 1 [OP_LIST_ARANGE] 8 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "10 99 1 [OP_LIST_ARANGE] 8 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 8\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 8\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "6148": {
        "category": "Arithmetic calculation",
        "question_ko": "두 자리 수 중 3의 배수이면서 5의 배수인 수는 모두 몇 개 입니까?",
        "question_en": "How many two-digit numbers are both multiples of 3 and multiples of 5?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "10 99 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "10 99 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "6149": {
        "category": "Arithmetic calculation",
        "question_ko": "총 72명의 학생들이 방과후 활동에 참여하고 있습니다. 이 중 4분의 1은 방과후 영어 수업을 듣고, 방과후 영어 수업을 듣는 학생의 3분의 1은 6학년 학생들입니다. 6학년 학생들은 방과 후 영어를 몇 명이나 듣습니까?",
        "question_en": "72 students in total are participating in after-school activities. Of these, one-fourth are taking the after-school English class, and one-third of the students taking the after-school English classes are 6th-grade students. How many 6th-grade students are taking the after-school English class?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "72 1 4 [OP_DIV] [OP_MUL] 1 3 [OP_DIV] [OP_MUL]",
        "solution_abst_en": "72 1 4 [OP_DIV] [OP_MUL] 1 3 [OP_DIV] [OP_MUL]",
        "solution_code_ko": "var_a = 72\nvar_b = 1\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 1\nvar_g = 3\nvar_h = var_f / var_g\nvar_i = var_e * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 72\nvar_b = 1\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 1\nvar_g = 3\nvar_h = var_f / var_g\nvar_i = var_e * var_h\nprint(int(var_i))"
    },
    "6150": {
        "category": "Geometry",
        "question_ko": "크기가 같은 동전을 빈틈없이 규칙적으로 가로와 세로 모두 12개씩 늘어놓아 정사각형을 만들었습니다. 둘레에 놓인 구슬의 개수는 몇 개입니까?",
        "question_en": "A square was created by arranging 12 coins of the same size regularly, horizontally and vertically, without any gaps. How many coins are placed around the perimeter?",
        "answer_ko": "44",
        "answer_en": "44",
        "solution_abst_ko": "12 2 [OP_SUB] 4 [OP_MUL] 4 [OP_ADD]",
        "solution_abst_en": "12 2 [OP_SUB] 4 [OP_MUL] 4 [OP_ADD]",
        "solution_code_ko": "var_a = 12\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 12\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "6151": {
        "category": "Arithmetic calculation",
        "question_ko": "윤기는 강아지와 고양이를 각각 5마리, 2마리 키우고 있습니다. 윤기가 키우는 강아지와 고양이는 몇 마리 인가요?",
        "question_en": "Yoongi has 5 dogs and 2 cats, respectively. How many dogs and cats do Yoongi have?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "5 2 [OP_ADD]",
        "solution_abst_en": "5 2 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "6152": {
        "category": "Correspondence",
        "question_ko": "9로 나누어떨어지는 네 자리 수 7AA1이 있습니다. 가능한 네 자리 수를 구하시오",
        "question_en": "There is a four-digit number 7AA1 that is divisible by 9 without any remainder. Find the possible four digit number.",
        "answer_ko": "7551",
        "answer_en": "7551",
        "solution_abst_ko": "7AA1 [OP_GEN_POSSIBLE_LIST] 9 [OP_LIST_DIVISIBLE] [OP_LIST2NUM]",
        "solution_abst_en": "7AA1 [OP_GEN_POSSIBLE_LIST] 9 [OP_LIST_DIVISIBLE] [OP_LIST2NUM]",
        "solution_code_ko": "var_a = '7AA1'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 9\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c=\"\"\nfor i in list_b:\n    i = str(i)\n    var_c = var_c + i\nprint(int(var_c))",
        "solution_code_en": "var_a = '7AA1'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 9\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c=\"\"\nfor i in list_b:\n    i = str(i)\n    var_c = var_c + i\nprint(int(var_c))"
    },
    "6153": {
        "category": "Geometry",
        "question_ko": "정육면체의 반찬통을 포장하려고 합니다. 이 반찬통을 겹치지 않고 포장하기 위해서는 넓이가 600인 포장지가 필요합니다. 이 반찬통의 부피를 구하시오.",
        "question_en": "You are trying to wrap a cube-shaped side dish container. In order to wrap this side dish container without overlapping, wrapping paper with a width of 600 is required. Find the volume of this side dish container.",
        "answer_ko": "1000",
        "answer_en": "1000",
        "solution_abst_ko": "600 6 [OP_DIV] 1/2 [OP_POW] 3 [OP_POW]",
        "solution_abst_en": "600 6 [OP_DIV] 1/2 [OP_POW] 3 [OP_POW]",
        "solution_code_ko": "var_a = 600\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 3\nvar_g = var_e ** var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 600\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 3\nvar_g = var_e ** var_f\nprint(int(var_g))"
    },
    "6154": {
        "category": "Arithmetic calculation",
        "question_ko": "10부터 99까지 수를 쓸 때, 숫자 8은 모두 몇 번 등장합니까?",
        "question_en": "How many times does the number 8 appear in the numbers 10 through 99?",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "10 99 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 8 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "10 99 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 8 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 8\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))",
        "solution_code_en": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 8\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))"
    },
    "6155": {
        "category": "Correspondence",
        "question_ko": "수영장에 물을 꽉 채우면 8050리터(L)가 들어간다. 현재 빈 수영장에 80.5리터(L)의 물을 채웠으면 수영장의 얼만큼 물이 찼는지 구하시오.",
        "question_en": "If you fill the pool full of water, it will take 8050 liters (L). If the currently empty swimming pool is filled with 80.5 liters (L) of water, find how full the pool is.",
        "answer_ko": "0.01",
        "answer_en": "0.01",
        "solution_abst_ko": "80.5 8050 [OP_DIV]",
        "solution_abst_en": "80.5 8050 [OP_DIV]",
        "solution_code_ko": "var_a = 80.5\nvar_b = 8050\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 80.5\nvar_b = 8050\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "6156": {
        "category": "Comparison",
        "question_ko": "0보다 크고 100보다 작은 4의 배수를 차례대로 썼습니다. 왼쪽에서 5번째 수와 오른쪽에서 8번째 수 사이에 있는 수는 모두 몇 개입니까?",
        "question_en": "Multiples of 4 that are greater than 0 and less than 100 are written sequentially. How many natural numbers are between the 5th number and the 8th number?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "0 1 [OP_ADD] 100 1 [OP_SUB] 1 [OP_LIST_ARANGE] 4 [OP_LIST_DIVISIBLE] 5 [OP_LIST_MIN] 8 [OP_LIST_MAX] [OP_LIST_LESS] [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "0 1 [OP_ADD] 100 1 [OP_SUB] 1 [OP_LIST_ARANGE] 4 [OP_LIST_DIVISIBLE] 5 [OP_LIST_MIN] 8 [OP_LIST_MAX] [OP_LIST_LESS] [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 100\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = 4\nlist_b = []\nvar_h = int(var_h)\nfor i in list_a:\n    i = int(i)\n    if i % var_h == 0:\n        list_b.append(i)\nvar_i = 5\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = 8\nlist_d=list_b.copy()\nlist_d.sort()\nvar_l = list_d[-var_k]\nlist_e = []\nfor i in list_b:\n    if i < var_l:\n        list_e.append(i)\nlist_f = []\nfor i in list_e:\n    if i > var_j:\n        list_f.append(i)\nvar_m = len(list_f)\nprint(int(var_m))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 100\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = 4\nlist_b = []\nvar_h = int(var_h)\nfor i in list_a:\n    i = int(i)\n    if i % var_h == 0:\n        list_b.append(i)\nvar_i = 5\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = 8\nlist_d=list_b.copy()\nlist_d.sort()\nvar_l = list_d[-var_k]\nlist_e = []\nfor i in list_b:\n    if i < var_l:\n        list_e.append(i)\nlist_f = []\nfor i in list_e:\n    if i > var_j:\n        list_f.append(i)\nvar_m = len(list_f)\nprint(int(var_m))"
    },
    "6157": {
        "category": "Arithmetic calculation",
        "question_ko": "다섯 자리 수 중 2, 3, 8, 9의 공배수인 수는 모두 몇 개 입니까?",
        "question_en": "How many five-digit numbers are common multiples of 2, 3, 8, and 9?",
        "answer_ko": "1250",
        "answer_en": "1250",
        "solution_abst_ko": "10000 99999 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "10000 99999 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 10000\nvar_b = 99999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 3\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = len(list_e)\nprint(int(var_h))",
        "solution_code_en": "var_a = 10000\nvar_b = 99999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 3\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = len(list_e)\nprint(int(var_h))"
    },
    "6158": {
        "category": "Arithmetic calculation",
        "question_ko": "구슬을 8개의 자루에 나누어 담았습니다. 그중 6개의 자루에는 각각 6개를 담았고, 나머지 2자루에는 각각 7개를 담았습니다. 구슬은 모두 몇 개입니까?",
        "question_en": "The marbles were divided into 8 bags. If six of these bags held 6 marbles, but the other two bags each held 7 marbles, what would be a total number of marbles?",
        "answer_ko": "50",
        "answer_en": "50",
        "solution_abst_ko": "6 6 [OP_MUL] 2 7 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "6 6 [OP_MUL] 2 7 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = 7\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 6\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = 7\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "6159": {
        "category": "Arithmetic calculation",
        "question_ko": "영찬이네 모둠은 7 명입니다. 한 사람이 종이학을 1 분에 2 마리씩 접을 수 있습니다. 영찬이네 모둠이 종이학 182 마리를 접으려면 몇 분이 걸립니까?",
        "question_en": "Yeongchan's group consists of 7 people. One person can fold two paper cranes in one minute. How many minutes will it take Yeongchan's group to fold 182 paper cranes?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "182 7 2 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "182 7 2 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 182\nvar_b = 7\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 182\nvar_b = 7\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "6160": {
        "category": "Possibility",
        "question_ko": "아버지, 어머니, 민지 그리고 동생이 사진을 찍으러 갔습니다. 어머니는 동생을 업고 찍으시겠다고 합니다. 서로 다르게 나란히 서서 찍는 방법은 모두 몇 가지입니까?",
        "question_en": "Father, Mother, Minji and younger brother went to take pictures. Mother says she will take pictures with the younger brother on her back. How many different ways are there to take pictures side by side?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 아버지 어머니 민지 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] Father Mother Minji [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM]",
        "solution_code_ko": "var_a = '아버지'\nvar_b = '어머니'\nvar_c = '민지'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = len(list_a)\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nprint(int(var_f))",
        "solution_code_en": "var_a = 'Father'\nvar_b = 'Mother'\nvar_c = 'Minji'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = len(list_a)\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nprint(int(var_f))"
    },
    "6161": {
        "category": "Arithmetic calculation",
        "question_ko": "학생 36명 중 안경을 낀 학생은 안경을 끼지 않은 학생보다 24명이 더 적습니다. 안경을 낀 학생은 몇 명입니까?",
        "question_en": "Of the 36 students, 24 fewer students wear glasses than students who do not wear glasses. How many students wear glasses?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "36 24 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "36 24 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 36\nvar_b = 24\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 36\nvar_b = 24\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "6162": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 53, 98, 69, 84가 있습니다. 그중에서 가장 큰 수와 가장 작은 수의 차는 얼마입니까?",
        "question_en": "There are four numbers 53, 98, 69, and 84. What is the difference between the largest number and the smallest number?",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "[OP_LIST_SOL] 53 98 69 84 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 53 98 69 84 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 53\nvar_b = 98\nvar_c = 69\nvar_d = 84\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 53\nvar_b = 98\nvar_c = 69\nvar_d = 84\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))"
    },
    "6163": {
        "category": "Correspondence",
        "question_ko": "여섯 자리 수 ABCDEF와 5의 곱은 665655입니다. A, B, C, D, E, F의 합을 구하시오.",
        "question_en": "The value of the multiplication of the six-digit number ABCDEF and 5 is 665655. Find the sum of A, B, C, D, E, and F.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "665655 5 [OP_DIV] [OP_NUM2LIST] [OP_LIST_SUM]",
        "solution_abst_en": "665655 5 [OP_DIV] [OP_NUM2LIST] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 665655\nvar_b = 5\nvar_c = var_a / var_b\nlist_a = []\nvar_c = int(var_c)\nwhile var_c//10 > 0:\n    list_a.append(var_c%10)\n    var_c = var_c//10\nlist_a.append(var_c%10)\nlist_a = list_a[::-1]\nlist_a = [float(i) for i in list_a]\nvar_d = sum(list_a)\nprint(int(var_d))",
        "solution_code_en": "var_a = 665655\nvar_b = 5\nvar_c = var_a / var_b\nlist_a = []\nvar_c = int(var_c)\nwhile var_c//10 > 0:\n    list_a.append(var_c%10)\n    var_c = var_c//10\nlist_a.append(var_c%10)\nlist_a = list_a[::-1]\nlist_a = [float(i) for i in list_a]\nvar_d = sum(list_a)\nprint(int(var_d))"
    },
    "6164": {
        "category": "Possibility",
        "question_ko": "학교에서 집까지는 버스 또는 지하철을 타야만 갈 수 있다. 총 7가지 방법으로 갈 수 있으며, 버스로 가는 방법은 4가지이다. 지하철을 이용하여 가는 방법은 몇가지인가?",
        "question_en": "You can only get to home from school by bus or subway. There are a total of 7 ways to get there, and 4 for them is to take the bus. How many ways are there to take subway?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "7 4 [OP_SUB]",
        "solution_abst_en": "7 4 [OP_SUB]",
        "solution_code_ko": "var_a = 7\nvar_b = 4\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 7\nvar_b = 4\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "6165": {
        "category": "Correspondence",
        "question_ko": "16, 18, 20, 25 중 2와 5로 나누어 떨어지면서 17보다 큰 수를 구하시오.",
        "question_en": "Among 16, 18, 20, and 25, find the number that is divisible by 2 and 5 and is greater than 17.",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "[OP_LIST_SOL] 16 18 20 25 [OP_LIST_EOL] 17 [OP_LIST_MORE] 2 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] 16 18 20 25 [OP_LIST_EOL] 17 [OP_LIST_MORE] 2 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 16\nvar_b = 18\nvar_c = 20\nvar_d = 25\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 17\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nvar_f = 2\nlist_c = []\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nvar_g = 5\nlist_d = []\nvar_g = int(var_g)\nfor i in list_c:\n    i = int(i)\n    if i % var_g == 0:\n        list_d.append(i)\nvar_h = 1\nvar_i = list_d[var_h-1]\nprint(int(var_i))",
        "solution_code_en": "var_a = 16\nvar_b = 18\nvar_c = 20\nvar_d = 25\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 17\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nvar_f = 2\nlist_c = []\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nvar_g = 5\nlist_d = []\nvar_g = int(var_g)\nfor i in list_c:\n    i = int(i)\n    if i % var_g == 0:\n        list_d.append(i)\nvar_h = 1\nvar_i = list_d[var_h-1]\nprint(int(var_i))"
    },
    "6166": {
        "category": "Geometry",
        "question_ko": "한 면의 넓이가 64제곱센티미터(㎠)인 정육면체의 부피는 몇 세제곱센티미터(㎤)인가요?",
        "question_en": "What is the volume of a cube with a side of an area of 64 square centimeters (cm2) in cubic centimeters (cm3)?",
        "answer_ko": "512",
        "answer_en": "512",
        "solution_abst_ko": "64 1/2 [OP_POW] 3 [OP_POW]",
        "solution_abst_en": "64 1/2 [OP_POW] 3 [OP_POW]",
        "solution_code_ko": "var_a = 64\nvar_b = 0.5\nvar_c = var_a ** var_b\nvar_d = 3\nvar_e = var_c ** var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 64\nvar_b = 0.5\nvar_c = var_a ** var_b\nvar_d = 3\nvar_e = var_c ** var_d\nprint(int(var_e))"
    },
    "6167": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 3으로 나누었더니 3이 되었습니다. 어떤 수를 구하시오.",
        "question_en": "When you divide a number by 3, you get 3. Find this number. ",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "3 3 [OP_MUL]",
        "solution_abst_en": "3 3 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "6168": {
        "category": "Possibility",
        "question_ko": "12보다 작은 정수 중에 3의 배수의 개수는 얼마입니까?",
        "question_en": "How many integers less than 12 are multiples of 3?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "1 11 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "1 11 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 11\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 11\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "6169": {
        "category": "Comparison",
        "question_ko": "과일가게에서 태형, 남준, 지민이가 사과를 샀습니다. 태형이는 남준이보다 사과를 많이 샀고 지민이는 태형이보다 사과를 많이 샀다면 사과를 가장 많이 산 학생은 누구인가요?",
        "question_en": "Taehyung, Namjoon, and Jimin bought apples at the fruit shop. If Taehyung bought more apples than Namjoon and Jimin bought more apples than Taehyung, who bought the most apples?",
        "answer_ko": "지민",
        "answer_en": "Jimin",
        "solution_abst_ko": "[OP_LIST_SOL] 태형 남준 지민 [OP_LIST_EOL] [OP_LIST_SOL] 태형 남준 > 지민 태형 > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Taehyung Namjoon Jimin [OP_LIST_EOL] [OP_LIST_SOL] Taehyung Namjoon > Jimin Taehyung > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '태형'\nvar_b = '남준'\nvar_c = '지민'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '태형'\nvar_e = '남준'\nvar_f = '>'\nvar_g = '지민'\nvar_h = '태형'\nvar_i = '>'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(var_k)",
        "solution_code_en": "var_a = 'Taehyung'\nvar_b = 'Namjoon'\nvar_c = 'Jimin'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'Taehyung'\nvar_e = 'Namjoon'\nvar_f = '>'\nvar_g = 'Jimin'\nvar_h = 'Taehyung'\nvar_i = '>'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(var_k)"
    },
    "6170": {
        "category": "Arithmetic calculation",
        "question_ko": "만화책 한 권의 대여료는 30분에 4000원입니다. 6명의 학생이 책 4권을 3시간동안 빌리려고 합니다. 이 학생들이 모두 같은 돈을 내려고 할 때, 한 학생이 내야할 돈을 구하세요.",
        "question_en": "The rental fee for a comic book is 4,000 won for 30 minutes. 6 students want to borrow 4 books in total for 3 hours. If all of these students are willing to pay the same amount, find the amount of money that a student should pay.",
        "answer_ko": "16000",
        "answer_en": "16000",
        "solution_abst_ko": "3 60 [OP_MUL] 30 [OP_DIV] 4000 [OP_MUL] 4 [OP_MUL] 6 [OP_DIV]",
        "solution_abst_en": "3 60 [OP_MUL] 30 [OP_DIV] 4000 [OP_MUL] 4 [OP_MUL] 6 [OP_DIV]",
        "solution_code_ko": "var_a = 3\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 30\nvar_e = var_c / var_d\nvar_f = 4000\nvar_g = var_e * var_f\nvar_h = 4\nvar_i = var_g * var_h\nvar_j = 6\nvar_k = var_i / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 3\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 30\nvar_e = var_c / var_d\nvar_f = 4000\nvar_g = var_e * var_f\nvar_h = 4\nvar_i = var_g * var_h\nvar_j = 6\nvar_k = var_i / var_j\nprint(int(var_k))"
    },
    "6171": {
        "category": "Geometry",
        "question_ko": "4변의 길이의 합이 50센티미터(㎝)인 직사각형이 있습니다. 이 직사각형의 세로의 길이가 13센티미터(㎝)일 때, 가로의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "The sum of 4 sides of a rectangle equals 50 centimeters (cm). If the length of this rectangle is 13 centimeters (cm), what is the length of its width in centimeters (cm)?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "50 2 [OP_DIV] 13 [OP_SUB]",
        "solution_abst_en": "50 2 [OP_DIV] 13 [OP_SUB]",
        "solution_code_ko": "var_a = 50\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 13\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 50\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 13\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "6172": {
        "category": "Correspondence",
        "question_ko": "20보다 작지만 2로 나뉘어 떨어지지 않는 어떤 수가 있습니다. 16, 18, 19, 21 중 어떤 수는 무엇입니까?",
        "question_en": "There are some numbers smaller than 20 that are not divisible by 2. Which number is it among 16, 18, 19, and 21?",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "[OP_LIST_SOL] 16 18 19 21 [OP_LIST_EOL] 2 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] 20 [OP_LIST_LESS] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] 16 18 19 21 [OP_LIST_EOL] 2 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] 20 [OP_LIST_LESS] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 16\nvar_b = 18\nvar_c = 19\nvar_d = 21\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = []\nvar_e = int(var_e)\nfor i in list_a:\n    i = int(i)\n    if i % var_e == 0:\n        list_b.append(i)\nlist_c = list(set(list_a) - set(list_b))\nvar_f = 20\nlist_d = []\nfor i in list_c:\n    if i < var_f:\n        list_d.append(i)\nvar_g = 1\nvar_h = list_d[var_g-1]\nprint(int(var_h))",
        "solution_code_en": "var_a = 16\nvar_b = 18\nvar_c = 19\nvar_d = 21\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = []\nvar_e = int(var_e)\nfor i in list_a:\n    i = int(i)\n    if i % var_e == 0:\n        list_b.append(i)\nlist_c = list(set(list_a) - set(list_b))\nvar_f = 20\nlist_d = []\nfor i in list_c:\n    if i < var_f:\n        list_d.append(i)\nvar_g = 1\nvar_h = list_d[var_g-1]\nprint(int(var_h))"
    },
    "6173": {
        "category": "Arithmetic calculation",
        "question_ko": "정연이와 주현이가 키를 쟀습니다. 정연이의 키는 주현이의 키의 1.06배이고 주현이는 134.5센티미터(㎝)입니다. 정연이의 키를 구하세요.",
        "question_en": "Jeongyeon and Joohyun have their heights measured. Jeongyeon's height is 1.06 times that of Joohyun, and Joohyun's height is 134.5 cm (cm). How tall is Jeongyeon?",
        "answer_ko": "142.57",
        "answer_en": "142.57",
        "solution_abst_ko": "134.5 1.06 [OP_MUL]",
        "solution_abst_en": "134.5 1.06 [OP_MUL]",
        "solution_code_ko": "var_a = 134.5\nvar_b = 1.06\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 134.5\nvar_b = 1.06\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "6174": {
        "category": "Correspondence",
        "question_ko": "어떤 소수점 아래 세 자리 소수를 소수 2번째 자리에서 반올림하였더니 3.5가 되었습니다. 이러한 소수 중에서 가장 큰 수와 가장 작은 수의 합을 소수점을 포함하여 답을 구하시오.",
        "question_en": "When you round a 3-digit decimal to one decimal place, you get 3.5. Find the sum of the largest and smallest of these decimal numbers, including the decimal point.",
        "answer_ko": "6.99",
        "answer_en": "6.99",
        "solution_abst_ko": "3.54 3.45 [OP_ADD]",
        "solution_abst_en": "3.54 3.45 [OP_ADD]",
        "solution_code_ko": "var_a = 3.54\nvar_b = 3.45\nvar_c = var_a + var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 3.54\nvar_b = 3.45\nvar_c = var_a + var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "6175": {
        "category": "Arithmetic calculation",
        "question_ko": "학생 18명에게 간식을 6개씩 주면 남고, 7개씩 주면 모자란다고 할 때 간식의 최대 개수는 몇 개입니까?",
        "question_en": "If you give 6 snacks to each of the 18 students, it's left, and if you give 7 snacks to each student, it's not enough. What is the maximum number of snacks?",
        "answer_ko": "125",
        "answer_en": "125",
        "solution_abst_ko": "18 7 [OP_MUL] 1 [OP_SUB]",
        "solution_abst_en": "18 7 [OP_MUL] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 18\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 18\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "6176": {
        "category": "Possibility",
        "question_ko": "168의 각 자리에 있는 숫자의 순서를 바꾸어 다른 수를 만들 때, 만들 수 있는 가장 큰 수와 세 번째로 작은 수의 차이를 구하시오.",
        "question_en": "Find the difference between the largest number and the third smallest number that can be made by changing the order of the digits in each place of 168.",
        "answer_ko": "243",
        "answer_en": "243",
        "solution_abst_ko": "168 [OP_NUM2LIST] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "168 [OP_NUM2LIST] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 168\nlist_a = []\nvar_a = int(var_a)\nwhile var_a//10 > 0:\n    list_a.append(var_a%10)\n    var_a = var_a//10\nlist_a.append(var_a%10)\nlist_a = list_a[::-1]\nvar_b = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_b))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_c = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_d = list_c[-var_c]\nvar_e = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_f = list_d[var_e-1]\nvar_g = var_d - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 168\nlist_a = []\nvar_a = int(var_a)\nwhile var_a//10 > 0:\n    list_a.append(var_a%10)\n    var_a = var_a//10\nlist_a.append(var_a%10)\nlist_a = list_a[::-1]\nvar_b = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_b))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_c = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_d = list_c[-var_c]\nvar_e = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_f = list_d[var_e-1]\nvar_g = var_d - var_f\nprint(int(var_g))"
    },
    "6177": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 72를 더한 값이 어떤 수에 2/3를 나눈 값에 2배와 같다고 한다. 어떤 수를 구하여라.",
        "question_en": "It is said that a number plus 72 is equal to twice the number divided by 2/3. Find the number.",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "72 2 1 2/3 [OP_DIV] [OP_MUL] 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "72 2 1 2/3 [OP_DIV] [OP_MUL] 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 72\nvar_b = 2\nvar_c = 1\nvar_d = 0.6666666666666666\nvar_e = var_c / var_d\nvar_f = var_b * var_e\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_a / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 72\nvar_b = 2\nvar_c = 1\nvar_d = 0.6666666666666666\nvar_e = var_c / var_d\nvar_f = var_b * var_e\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_a / var_h\nprint(int(var_i))"
    },
    "6178": {
        "category": "Arithmetic calculation",
        "question_ko": "세희가 친구들과 빵을 만드는 데 15리터(L)의 우유가 필요합니다. 현재 집에는 우유가 7리터(L) 200밀리리터(㎖)밖에 없다면, 600밀리리터(㎖)로 된 우유를 최소 몇 개는 사야 합니까?",
        "question_en": "Sehee needs 15 liters of milk to make bread with friends. If Sehee currently has only 7 liters (L) and 200 milliliters (mL) of milk at home, how many 600 milliliters (mL) of milk should she buy at least?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "15 1000 [OP_MUL] 7 1000 [OP_MUL] 200 [OP_ADD] [OP_SUB] 600 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "15 1000 [OP_MUL] 7 1000 [OP_MUL] 200 [OP_ADD] [OP_SUB] 600 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 15\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = 200\nvar_h = var_f + var_g\nvar_i = var_c - var_h\nvar_j = 600\nvar_k = var_i / var_j\nvar_l = 1\nvar_m=int(((var_k+9*10**(var_l-2))//(10**(var_l-1)))*10**(var_l-1))\n\nprint(int(var_m))",
        "solution_code_en": "var_a = 15\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = 200\nvar_h = var_f + var_g\nvar_i = var_c - var_h\nvar_j = 600\nvar_k = var_i / var_j\nvar_l = 1\nvar_m=int(((var_k+9*10**(var_l-2))//(10**(var_l-1)))*10**(var_l-1))\n\nprint(int(var_m))"
    },
    "6179": {
        "category": "Comparison",
        "question_ko": "(가) 정육면체는 한 모서리의 길이가 5센티미터(㎝)입니다. (나) 직육면체는 가로, 세로, 높이가 각각 4센티미터(㎝), 5센티미터(㎝), 6센티미터(㎝)입니다. (가), (나) 중에서 부피가 더 큰 도형은 어느 것입니까?",
        "question_en": "The length of one edge of a cube (a) is 5 centimeters (cm). A rectangular parallelepiped (b) is 4 centimeters (cm), 5 centimeters (cm), and 6 centimeters (cm) in width, length, and height, respectively. Which of the shapes (a) and (b) has the larger volume?",
        "answer_ko": "(가)",
        "answer_en": "(a)",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) [OP_LIST_EOL] [OP_LIST_SOL] 5 3 [OP_POW] 4 5 6 [OP_MUL] [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (a) (b) [OP_LIST_EOL] [OP_LIST_SOL] 5 3 [OP_POW] 4 5 6 [OP_MUL] [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 5\nvar_d = 3\nvar_e = var_c ** var_d\nvar_f = 4\nvar_g = 5\nvar_h = 6\nvar_i = var_g * var_h\nvar_j = var_f * var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = '(a)'\nvar_b = '(b)'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 5\nvar_d = 3\nvar_e = var_c ** var_d\nvar_f = 4\nvar_g = 5\nvar_h = 6\nvar_i = var_g * var_h\nvar_j = var_f * var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "6180": {
        "category": "Arithmetic calculation",
        "question_ko": "주연이는 하루에 215미터(m)를 달립니다. 오늘은 주연이가 평소의 0.32배를 달렸다면 오늘 달린 거리는 몇 미터(m)입니까?",
        "question_en": "Juyeon runs 215 meters (m) a day. If Juyeon ran 0.32 times her usual speed today, how many meters (m) did she run today?",
        "answer_ko": "68.80",
        "answer_en": "68.8",
        "solution_abst_ko": "215 0.32 [OP_MUL]",
        "solution_abst_en": "215 0.32 [OP_MUL]",
        "solution_code_ko": "var_a = 215\nvar_b = 0.32\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 215\nvar_b = 0.32\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "6181": {
        "category": "Geometry",
        "question_ko": "팔각형일 때, 총 몇 개의 대각선을 그을 수 있습니까?",
        "question_en": "How many diagonals can you draw in an octagon?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "8 8 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "8 8 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 8\nvar_b = 8\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 8\nvar_b = 8\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "6182": {
        "category": "Arithmetic calculation",
        "question_ko": "둥그런 탁자에 4명이 앉아있다. 양옆으로 인접하지 않는 사람들과 악수를 한번씩하려면 악수를 모두 몇 번 하는지 구하시오.",
        "question_en": "There are four people sitting at a round table, and you want to shake hands with people who are not neighboring with you once. Find the number that you shake hands.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "4 4 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "4 4 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 4\nvar_b = 4\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 4\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "6183": {
        "category": "Possibility",
        "question_ko": "경주, 포항, 부산, 건천, 김해 다섯 개의 도시를 여행할 계획을 짜고 있습니다. 도시를 한 번씩만 차례대로 들른다고 할 때, 몇 가지 방법을 세울 수 있습니까? 단, 경주는 가장 먼저 들러야 합니다.",
        "question_en": "You are planning a trip to five cities: Gyeongju, Pohang, Busan, Geoncheon, and Gimhae. If you visit each city only once, how many orders can you make to visit the city? However, Gyeongju must be visited first.",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "[OP_LIST_SOL] 경주 포항 부산 건천 김해 [OP_LIST_EOL] [OP_LIST_SOL] 경주 [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] Gyeongju Pohang Busan Geoncheon Gimhae [OP_LIST_EOL] [OP_LIST_SOL] Gyeongju [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM]",
        "solution_code_ko": "var_a = '경주'\nvar_b = '포항'\nvar_c = '부산'\nvar_d = '건천'\nvar_e = '김해'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = '경주'\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_g = len(list_c)\nvar_h = len(list_c)\nvar_i = 1\nvar_g = int(var_g)\nvar_h = int(var_h)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i * (var_g-i)\nprint(int(var_i))",
        "solution_code_en": "var_a = 'Gyeongju'\nvar_b = 'Pohang'\nvar_c = 'Busan'\nvar_d = 'Geoncheon'\nvar_e = 'Gimhae'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 'Gyeongju'\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_g = len(list_c)\nvar_h = len(list_c)\nvar_i = 1\nvar_g = int(var_g)\nvar_h = int(var_h)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i * (var_g-i)\nprint(int(var_i))"
    },
    "6184": {
        "category": "Arithmetic calculation",
        "question_ko": "할아버지께서 3리터(L)짜리 물을 12통 사서 학생들에게 3/4리터(L)씩 나누어 주려고 합니다. 몇 명에게 나누어 줄 수 있습니까?",
        "question_en": "Grandpa wants to buy 12 bottles of 3-liter (L) water and distribute 3/4 liter (L) to each student. How many students can he share?",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "3 12 [OP_MUL] 3/4 [OP_FDIV]",
        "solution_abst_en": "3 12 [OP_MUL] 3/4 [OP_FDIV]",
        "solution_code_ko": "var_a = 3\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 0.75\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 3\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 0.75\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "6185": {
        "category": "Arithmetic calculation",
        "question_ko": "한솔이의 키는 134.5 센티미터(㎝) 입니다. 한초의 키가 한솔이의 키의 1.06 배라면 한초의 키는 몇 센티미터(㎝) 입니까?",
        "question_en": "Hansol's height is 134.5 centimeters (cm). If Hancho's height is 1.06 times Hansol's height, how tall is Hancho in centimeters (cm)?",
        "answer_ko": "142.57",
        "answer_en": "142.57",
        "solution_abst_ko": "134.5 1.06 [OP_MUL]",
        "solution_abst_en": "134.5 1.06 [OP_MUL]",
        "solution_code_ko": "var_a = 134.5\nvar_b = 1.06\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 134.5\nvar_b = 1.06\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "6186": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중 가장 작은 수는 무엇입니까?",
        "question_en": "There are five numbers 10, 11, 12, 13, and 14. Which number is the smallest?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nprint(int(var_g))"
    },
    "6187": {
        "category": "Arithmetic calculation",
        "question_ko": "세 자리 수 중 137보다 크고 285보다 작은 수의 개수는 얼마인지 구하시오.",
        "question_en": "How many three-digit numbers are greater than 137 and less than 285?",
        "answer_ko": "147",
        "answer_en": "147",
        "solution_abst_ko": "137 1 [OP_ADD] 285 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_LEN]",
        "solution_abst_en": "137 1 [OP_ADD] 285 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 137\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 285\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = len(list_a)\nprint(int(var_h))",
        "solution_code_en": "var_a = 137\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 285\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = len(list_a)\nprint(int(var_h))"
    },
    "6188": {
        "category": "Correspondence",
        "question_ko": "한 자리 수 A가 있습니다. 십의 자리까지 7A7을 올림하면 730이 됩니다. A에 알맞은 값은?",
        "question_en": "There is a single digit number A. When 7A7 is rounded up to the tens place is 730. What is the right value for A?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "7A7 [OP_GEN_POSSIBLE_LIST] 730 [OP_LIST_LESS_EQUAL] 730 10 [OP_SUB] [OP_LIST_MORE] 7A7 A [OP_LIST_FIND_UNK]",
        "solution_abst_en": "7A7 [OP_GEN_POSSIBLE_LIST] 730 [OP_LIST_LESS_EQUAL] 730 10 [OP_SUB] [OP_LIST_MORE] 7A7 A [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = '7A7'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 730\nlist_b = []\nfor i in list_a:\n    if i <= var_b:\n        list_b.append(i)\nvar_c = 730\nvar_d = 10\nvar_e = var_c - var_d\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = '7A7'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))",
        "solution_code_en": "var_a = '7A7'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 730\nlist_b = []\nfor i in list_a:\n    if i <= var_b:\n        list_b.append(i)\nvar_c = 730\nvar_d = 10\nvar_e = var_c - var_d\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = '7A7'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))"
    },
    "6189": {
        "category": "Arithmetic calculation",
        "question_ko": "기차가 출발하여 1번째 역에서 29명이 내리고 17명이 탔습니다. 2번째 역에서 27명이 내리고 35명이 탔습니다. 지금 기차에 타고 있는 사람은 116명입니다. 기차가 처음 출발할 때 타고 있던 사람은 몇 명입니까?",
        "question_en": "After the train departed, 29 people got off at the first station 17 people got on. At the second station, 27 people got off and 35 got on. There are 116 people on the train right now. How many people were on the train when it first departed?",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "116 29 [OP_ADD] 17 [OP_SUB] 27 [OP_ADD] 35 [OP_SUB]",
        "solution_abst_en": "116 29 [OP_ADD] 17 [OP_SUB] 27 [OP_ADD] 35 [OP_SUB]",
        "solution_code_ko": "var_a = 116\nvar_b = 29\nvar_c = var_a + var_b\nvar_d = 17\nvar_e = var_c - var_d\nvar_f = 27\nvar_g = var_e + var_f\nvar_h = 35\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 116\nvar_b = 29\nvar_c = var_a + var_b\nvar_d = 17\nvar_e = var_c - var_d\nvar_f = 27\nvar_g = var_e + var_f\nvar_h = 35\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "6190": {
        "category": "Possibility",
        "question_ko": "숫자 카드 1, 2, 3 중 2장을 뽑아 만들 수 있는 두 자리 자연수의 개수를 구하시오.",
        "question_en": "Find the number of two-digit natural numbers that can be made by drawing two from the number cards 1, 2, and 3.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 1 2 3 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 2 3 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 2\nvar_c = 3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 2\nvar_c = 3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "6191": {
        "category": "Geometry",
        "question_ko": "정육면체 모양의 방이 있습니다. 이 방의 한 변의 길이가 5미터(m)라면, 이 방의 바닥의 둘레는 몇 미터(m)입니까?",
        "question_en": "There is a room in the shape of a cube. If the length of one side of this room is 5 meters (m), what is the circumference of the floor of this room in meters (m)?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "5 4 [OP_MUL]",
        "solution_abst_en": "5 4 [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "6192": {
        "category": "Comparison",
        "question_ko": "총 4개의 숫자 0.8, 1/2, 0.5, 1/3이 있습니다. 이 중 0.1보다 크거나 같은 수를 모두 더하면 얼마인가요?",
        "question_en": "There are 4 numbers: 0.8, 1/2, 0.5, and 1/3. What is the sum of all numbers greater than or equal to 0.1?",
        "answer_ko": "2.13",
        "answer_en": "2.13",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.5 1/3 [OP_LIST_EOL] 0.1 [OP_LIST_MORE_EQUAL] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.5 1/3 [OP_LIST_EOL] 0.1 [OP_LIST_MORE_EQUAL] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.5\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.1\nlist_b = []\nfor i in list_a:\n    if i >= var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint('{:.2f}'.format(round(var_f+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.5\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.1\nlist_b = []\nfor i in list_a:\n    if i >= var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint('{:.2f}'.format(round(var_f+1e-10,2)))"
    },
    "6193": {
        "category": "Arithmetic calculation",
        "question_ko": "숫자 3, 5로 나누어 떨어질 수 있는 두 자리 수는 모두 몇 개 있습니까?",
        "question_en": "How many two-digit numbers are divisible by 3 and 5?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "10 99 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "10 99 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "6194": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 22를 더해야 하는데 잘못하여 12를 더했더니 48이 되었습니다. 바르게 계산한 결과를 구하시오.",
        "question_en": "I need to add 22 to a number, but I mistakenly added 12 and got 48. Find the result of the correct calculation.",
        "answer_ko": "58",
        "answer_en": "58",
        "solution_abst_ko": "48 12 [OP_SUB] 22 [OP_ADD]",
        "solution_abst_en": "48 12 [OP_SUB] 22 [OP_ADD]",
        "solution_code_ko": "var_a = 48\nvar_b = 12\nvar_c = var_a - var_b\nvar_d = 22\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 48\nvar_b = 12\nvar_c = var_a - var_b\nvar_d = 22\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "6195": {
        "category": "Correspondence",
        "question_ko": "지민이는 페인트를 가지고 있는데 본인 집과 친구 집을 칠하는데 각각 4.3리터(L) 씩 사용했고 남은 페인트가 8.8리터(L) 이다. 지민이가 처음에 가지고 있던 페인트는 몇 리터(L)인지 구하시오.",
        "question_en": "Jimin has paint, and he used 4.3 liters (L) of each to paint his house and his friend's house, and the remaining paint is 8.8 liters (L). Find how many liters (L) of paint Jimin had at the beginning.",
        "answer_ko": "17.40",
        "answer_en": "17.4",
        "solution_abst_ko": "8.8 4.3 [OP_ADD] 4.3 [OP_ADD]",
        "solution_abst_en": "8.8 4.3 [OP_ADD] 4.3 [OP_ADD]",
        "solution_code_ko": "var_a = 8.8\nvar_b = 4.3\nvar_c = var_a + var_b\nvar_d = 4.3\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 8.8\nvar_b = 4.3\nvar_c = var_a + var_b\nvar_d = 4.3\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "6196": {
        "category": "Correspondence",
        "question_ko": "28은 어떤 수에 7/8을 곱한 수입니다. 어떤 수에 16을 더하고 5/16을 곱한 수는 얼마입니까?",
        "question_en": "It is 28 when you multiply a number by 7/8. How much is it when you add 16 to that number and multiply 5/16?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "28 8 7 [OP_DIV] [OP_MUL] 16 [OP_ADD] 5 16 [OP_DIV] [OP_MUL]",
        "solution_abst_en": "28 8 7 [OP_DIV] [OP_MUL] 16 [OP_ADD] 5 16 [OP_DIV] [OP_MUL]",
        "solution_code_ko": "var_a = 28\nvar_b = 8\nvar_c = 7\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 16\nvar_g = var_e + var_f\nvar_h = 5\nvar_i = 16\nvar_j = var_h / var_i\nvar_k = var_g * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 28\nvar_b = 8\nvar_c = 7\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 16\nvar_g = var_e + var_f\nvar_h = 5\nvar_i = 16\nvar_j = var_h / var_i\nvar_k = var_g * var_j\nprint(int(var_k))"
    },
    "6197": {
        "category": "Correspondence",
        "question_ko": "성준이와 승아는 딱지치기 놀이를 하고 있습니다. 성준의 딱지의 개수의 3/4에서 25를 뺀 값이 승아의 딱지의 개수에서 50을 빼고 7을 곱한 값과 같다고 합니다. 승아가 100개의 딱지를 가지고 있다면 성준이의 딱지의 개수는 몇 개인지 구하시오.",
        "question_en": "Seongjun and Seungah are playing slap-match. It is said that the number of Seongjun's ttakji multiplied by 3/4 subtracted by 25 equals the number of Seunga's ttakji subtracted by 50 multiplied by 7. When Seunga has 100 ttakjis, find how many ttakji Seongjun has.",
        "answer_ko": "500",
        "answer_en": "500",
        "solution_abst_ko": "100 50 [OP_SUB] 7 [OP_MUL] 25 [OP_ADD] 3/4 [OP_DIV]",
        "solution_abst_en": "100 50 [OP_SUB] 7 [OP_MUL] 25 [OP_ADD] 3/4 [OP_DIV]",
        "solution_code_ko": "var_a = 100\nvar_b = 50\nvar_c = var_a - var_b\nvar_d = 7\nvar_e = var_c * var_d\nvar_f = 25\nvar_g = var_e + var_f\nvar_h = 0.75\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 100\nvar_b = 50\nvar_c = var_a - var_b\nvar_d = 7\nvar_e = var_c * var_d\nvar_f = 25\nvar_g = var_e + var_f\nvar_h = 0.75\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "6198": {
        "category": "Geometry",
        "question_ko": "넓이가 59.6제곱센티미터(㎠)인 직사각형 모양의 빵을 4 등분하였습니다. 빵 하나의 넓이는 얼마입니까?",
        "question_en": "A rectangular slice of bread with an area of 59.6 square centimeters (cm2) is divided into 4 equal parts. What is the area of one part?",
        "answer_ko": "14.90",
        "answer_en": "14.9",
        "solution_abst_ko": "59.6 4 [OP_DIV]",
        "solution_abst_en": "59.6 4 [OP_DIV]",
        "solution_code_ko": "var_a = 59.6\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 59.6\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "6199": {
        "category": "Correspondence",
        "question_ko": "90.1 을 어떤 수로 나누었더니 5.3 이 되었습니다. 어떤 수에 0.2를 곱하면 얼마인지 구하시오",
        "question_en": "Divide 90.1 by some number to get 5.3. What is the number multiplied by 0.2?",
        "answer_ko": "3.40",
        "answer_en": "3.4",
        "solution_abst_ko": "90.1 5.3 [OP_DIV] 0.2 [OP_MUL]",
        "solution_abst_en": "90.1 5.3 [OP_DIV] 0.2 [OP_MUL]",
        "solution_code_ko": "var_a = 90.1\nvar_b = 5.3\nvar_c = var_a / var_b\nvar_d = 0.2\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 90.1\nvar_b = 5.3\nvar_c = var_a / var_b\nvar_d = 0.2\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "6200": {
        "category": "Comparison",
        "question_ko": "차가 480인 두 자연수가 있습니다. 큰 수를 작은 수로 나누면 몫이 4이고 나머지는 30일 때, 큰 수를 구하시오.",
        "question_en": "There are two natural numbers whose difference is 480. If the larger number divided by the smaller number gives the quotient of 4 and the remainder of 30, find the larger number.",
        "answer_ko": "630",
        "answer_en": "630",
        "solution_abst_ko": "480 30 [OP_SUB] 4 1 [OP_SUB] [OP_DIV] 4 [OP_MUL] 30 [OP_ADD]",
        "solution_abst_en": "480 30 [OP_SUB] 4 1 [OP_SUB] [OP_DIV] 4 [OP_MUL] 30 [OP_ADD]",
        "solution_code_ko": "var_a = 480\nvar_b = 30\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 4\nvar_i = var_g * var_h\nvar_j = 30\nvar_k = var_i + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 480\nvar_b = 30\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 4\nvar_i = var_g * var_h\nvar_j = 30\nvar_k = var_i + var_j\nprint(int(var_k))"
    },
    "6201": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이가 4월, 5월에 본 수학 시험 평균 점수는 89점입니다. 정국이가 4월, 5월, 6월 3달 동안 본 수학 시험 평균 점수가 88점일 때, 6월에 본 수학 시험 점수는 몇 점입니까?",
        "question_en": "The average score on Jungkook's math test in April and May is 89 points. If Jungkook's average score on the math test in April, May, and June is 88, how many points did Jungkook take on the math test in June?",
        "answer_ko": "86",
        "answer_en": "86",
        "solution_abst_ko": "88 3 [OP_MUL] 89 [OP_SUB] 89 [OP_SUB]",
        "solution_abst_en": "88 3 [OP_MUL] 89 [OP_SUB] 89 [OP_SUB]",
        "solution_code_ko": "var_a = 88\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 89\nvar_e = var_c - var_d\nvar_f = 89\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 88\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 89\nvar_e = var_c - var_d\nvar_f = 89\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "6202": {
        "category": "Correspondence",
        "question_ko": "현지가 산에 오르면서 가져온 물의 2/5보다 300밀리리터(㎖) 많은 물은 친구가 마셨고 남은 물의 1/2보다 200밀리리터(㎖) 많은 물은 현지가 마셨다. 남은 물이 800밀리리터(㎖)라면 현지가 처음 가져온 물의 양은 몇 리터(L)인지 구하시오.",
        "question_en": "A friend drank 300 milliliters (ml) more than 2/5 of the water Hyun-ji brought while climbing the mountain, and Hyun-ji drank 200 milliliters (ml) more than 1/2 of the remaining water. If the remaining water is 800 milliliters (ml), how many liters (l) is the amount of water Hyun-ji brought first?",
        "answer_ko": "2.50",
        "answer_en": "2.5",
        "solution_abst_ko": "800 200 [OP_SUB] 1 1/2 [OP_SUB] [OP_DIV] 300 [OP_ADD] 1 2/5 [OP_SUB] [OP_DIV] 1000 [OP_DIV]",
        "solution_abst_en": "800 200 [OP_SUB] 1 1/2 [OP_SUB] [OP_DIV] 300 [OP_ADD] 1 2/5 [OP_SUB] [OP_DIV] 1000 [OP_DIV]",
        "solution_code_ko": "var_a = 800\nvar_b = 200\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = 0.5\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 300\nvar_i = var_g + var_h\nvar_j = 1\nvar_k = 0.4\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nvar_n = 1000\nvar_o = var_m / var_n\nprint('{:.2f}'.format(round(var_o+1e-10,2)))",
        "solution_code_en": "var_a = 800\nvar_b = 200\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = 0.5\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 300\nvar_i = var_g + var_h\nvar_j = 1\nvar_k = 0.4\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nvar_n = 1000\nvar_o = var_m / var_n\nprint('{:.2f}'.format(round(var_o+1e-10,2)))"
    },
    "6203": {
        "category": "Geometry",
        "question_ko": "육각형 내에 대각선을 그리려고 합니다. 이 때의 대각선의 수를 구하시오.",
        "question_en": "You are trying to draw a diagonal line within a hexagon. Find the number of diagonals in this case.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "6 6 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "6 6 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 6\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 6\nvar_b = 6\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "6204": {
        "category": "Possibility",
        "question_ko": "80보다 작은 수 중에서 9의 배수들의 개수를 구하시오.",
        "question_en": "Find the number of multiples of 9 in numbers less than 80.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "1 80 1 [OP_SUB] 1 [OP_LIST_ARANGE] 9 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "1 80 1 [OP_SUB] 1 [OP_LIST_ARANGE] 9 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 80\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nvar_f = 9\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 80\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nvar_f = 9\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "6205": {
        "category": "Arithmetic calculation",
        "question_ko": "불고기 버거와 치킨 버거 세트 3개 가격이 21000원이다. 불고기 버거가 치킨버거보다 300원 비싸다면 치킨버거 하나의 가격은 얼마입니까?",
        "question_en": "A set of three bulgogi burgers and chicken burgers costs 21,000 won. If a bulgogi burger is 300 won more expensive than a chicken burger, how much does a chicken burger cost?",
        "answer_ko": "3350",
        "answer_en": "3350",
        "solution_abst_ko": "21000 3 [OP_DIV] 300 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "21000 3 [OP_DIV] 300 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 21000\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 300\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 21000\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 300\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "6206": {
        "category": "Correspondence",
        "question_ko": "여섯 자리 수 A15B94가 99의 배수일 때, B를 구하시오",
        "question_en": "If the six-digit number A15B94 is a multiple of 99, find B",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "A15B94 [OP_GEN_POSSIBLE_LIST] 99 [OP_LIST_DIVISIBLE] A15B94 B [OP_LIST_FIND_UNK]",
        "solution_abst_en": "A15B94 [OP_GEN_POSSIBLE_LIST] 99 [OP_LIST_DIVISIBLE] A15B94 B [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = 'A15B94'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 99\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 'A15B94'\nvar_d = 'B'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nvar_e = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_e = int(elem[unk_idx])\nprint(int(var_e))",
        "solution_code_en": "var_a = 'A15B94'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 99\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 'A15B94'\nvar_d = 'B'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nvar_e = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_e = int(elem[unk_idx])\nprint(int(var_e))"
    },
    "6207": {
        "category": "Geometry",
        "question_ko": "한 모서리의 길이가 3㎝인 정육면체가 있습니다. 각 꼭짓점에서 한 모서리의 길이가 1㎝인 정육면체를 잘랐을 때, 남은 부분의 부피는 몇 세제곱센티미터입니까?",
        "question_en": "There is a cube with one edge 3 centimeters (cm) long. If you cut a cube with one edge of 1 centimeters (cm) at each vertex, what is the volume in cubic centimeters (cm3) of the remaining part?",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "3 3 [OP_POW] 1 3 [OP_POW] 8 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "3 3 [OP_POW] 1 3 [OP_POW] 8 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 3\nvar_b = 3\nvar_c = var_a ** var_b\nvar_d = 1\nvar_e = 3\nvar_f = var_d ** var_e\nvar_g = 8\nvar_h = var_f * var_g\nvar_i = var_c - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 3\nvar_b = 3\nvar_c = var_a ** var_b\nvar_d = 1\nvar_e = 3\nvar_f = var_d ** var_e\nvar_g = 8\nvar_h = var_f * var_g\nvar_i = var_c - var_h\nprint(int(var_i))"
    },
    "6208": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 7을 곱했더니 50.68이 되었습니다. 어떤 수를 구하시오.",
        "question_en": "When you multiply a number by 7, you get 50.68. find this number.",
        "answer_ko": "7.24",
        "answer_en": "7.24",
        "solution_abst_ko": "50.68 7 [OP_DIV]",
        "solution_abst_en": "50.68 7 [OP_DIV]",
        "solution_code_ko": "var_a = 50.68\nvar_b = 7\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 50.68\nvar_b = 7\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "6209": {
        "category": "Correspondence",
        "question_ko": "일곱자리 수 25AB33C는 8의 배수이고 9의 배수이면서, 11의 배수라고 한다. A, B, C의 합을 구하시오",
        "question_en": "The seven-digit number 25AB33C is said to be a multiple of 8, a multiple of 9, and a multiple of 11. Find the sum of A, B, and C",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "25AB33C [OP_GEN_POSSIBLE_LIST] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] 11 [OP_LIST_DIVISIBLE] 25AB33C A [OP_LIST_FIND_UNK] 25AB33C B [OP_LIST_FIND_UNK] [OP_ADD] 25AB33C C [OP_LIST_FIND_UNK] [OP_ADD]",
        "solution_abst_en": "25AB33C [OP_GEN_POSSIBLE_LIST] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] 11 [OP_LIST_DIVISIBLE] 25AB33C A [OP_LIST_FIND_UNK] 25AB33C B [OP_LIST_FIND_UNK] [OP_ADD] 25AB33C C [OP_LIST_FIND_UNK] [OP_ADD]",
        "solution_code_ko": "var_a = '25AB33C'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 8\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 9\nlist_c = []\nvar_c = int(var_c)\nfor i in list_b:\n    i = int(i)\n    if i % var_c == 0:\n        list_c.append(i)\nvar_d = 11\nlist_d = []\nvar_d = int(var_d)\nfor i in list_c:\n    i = int(i)\n    if i % var_d == 0:\n        list_d.append(i)\nvar_e = '25AB33C'\nvar_f = 'A'\nvar_e = str(var_e)\nvar_f = str(var_f)\nunk_idx = var_e.index(var_f)\nvar_g = 0\nfor elem in list_d:\n    elem = str(elem)\n    var_g = int(elem[unk_idx])\nvar_h = '25AB33C'\nvar_i = 'B'\nvar_h = str(var_h)\nvar_i = str(var_i)\nunk_idx = var_h.index(var_i)\nvar_j = 0\nfor elem in list_d:\n    elem = str(elem)\n    var_j = int(elem[unk_idx])\nvar_k = var_g + var_j\nvar_l = '25AB33C'\nvar_m = 'C'\nvar_l = str(var_l)\nvar_m = str(var_m)\nunk_idx = var_l.index(var_m)\nvar_n = 0\nfor elem in list_d:\n    elem = str(elem)\n    var_n = int(elem[unk_idx])\nvar_o = var_k + var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = '25AB33C'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 8\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 9\nlist_c = []\nvar_c = int(var_c)\nfor i in list_b:\n    i = int(i)\n    if i % var_c == 0:\n        list_c.append(i)\nvar_d = 11\nlist_d = []\nvar_d = int(var_d)\nfor i in list_c:\n    i = int(i)\n    if i % var_d == 0:\n        list_d.append(i)\nvar_e = '25AB33C'\nvar_f = 'A'\nvar_e = str(var_e)\nvar_f = str(var_f)\nunk_idx = var_e.index(var_f)\nvar_g = 0\nfor elem in list_d:\n    elem = str(elem)\n    var_g = int(elem[unk_idx])\nvar_h = '25AB33C'\nvar_i = 'B'\nvar_h = str(var_h)\nvar_i = str(var_i)\nunk_idx = var_h.index(var_i)\nvar_j = 0\nfor elem in list_d:\n    elem = str(elem)\n    var_j = int(elem[unk_idx])\nvar_k = var_g + var_j\nvar_l = '25AB33C'\nvar_m = 'C'\nvar_l = str(var_l)\nvar_m = str(var_m)\nunk_idx = var_l.index(var_m)\nvar_n = 0\nfor elem in list_d:\n    elem = str(elem)\n    var_n = int(elem[unk_idx])\nvar_o = var_k + var_n\nprint(int(var_o))"
    },
    "6210": {
        "category": "Possibility",
        "question_ko": "숫자 카드 2, 5, 8을 한 번씩 사용하여 만들 수 있는 세 자리 수 중에서 가장 큰 수와 가장 작은 수의 합에 두 번째로 큰 수를 더하면 얼마가 됩니까?",
        "question_en": "What is the value of adding the second largest number to the sum of the largest and smallest three-digit number that can be formed by using the number cards 2, 5, and 8 only once?",
        "answer_ko": "1935",
        "answer_en": "1935",
        "solution_abst_ko": "[OP_LIST_SOL] 2 5 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD] 2 [OP_LIST_MAX] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 2 5 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD] 2 [OP_LIST_MAX] [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 5\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nvar_j = 2\nlist_e=list_b.copy()\nlist_e.sort()\nvar_k = list_e[-var_j]\nvar_l = var_i + var_k\nprint(int(var_l))",
        "solution_code_en": "var_a = 2\nvar_b = 5\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nvar_j = 2\nlist_e=list_b.copy()\nlist_e.sort()\nvar_k = list_e[-var_j]\nvar_l = var_i + var_k\nprint(int(var_l))"
    },
    "6211": {
        "category": "Geometry",
        "question_ko": "종이 위에 100원짜리 4개를 맞닿게 늘어놓고 그 개의 동전을 담는 가장 작은 정사각형을 그렸더니 정사각형의 둘레가 56센티미터(㎝)였다. 100원짜리 동전 441개를 포함하는 가장 작은 정사각형의 둘레는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "You laid out four 100-won coins on a piece of paper and drew the smallest square containing the coins. The perimeter of the square was 56 centimeters (cm). Find the perimeter in centimeters (cm) of the smallest square containing 441 100-won coins.",
        "answer_ko": "588",
        "answer_en": "588",
        "solution_abst_ko": "56 4 [OP_DIV] 4 1/2 [OP_POW] [OP_DIV] 441 1/2 [OP_POW] [OP_MUL] 4 [OP_MUL]",
        "solution_abst_en": "56 4 [OP_DIV] 4 1/2 [OP_POW] [OP_DIV] 441 1/2 [OP_POW] [OP_MUL] 4 [OP_MUL]",
        "solution_code_ko": "var_a = 56\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = 0.5\nvar_f = var_d ** var_e\nvar_g = var_c / var_f\nvar_h = 441\nvar_i = 0.5\nvar_j = var_h ** var_i\nvar_k = var_g * var_j\nvar_l = 4\nvar_m = var_k * var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 56\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = 0.5\nvar_f = var_d ** var_e\nvar_g = var_c / var_f\nvar_h = 441\nvar_i = 0.5\nvar_j = var_h ** var_i\nvar_k = var_g * var_j\nvar_l = 4\nvar_m = var_k * var_l\nprint(int(var_m))"
    },
    "6212": {
        "category": "Comparison",
        "question_ko": "호현, 슬기, 현정이가 제기차기 시합을 합니다. 호현이는 1번째에 23번, 2번째에 28번을 찼습니다. 현정이는 1번째에 32번, 2번째에 17번을 찼습니다. 슬기는 1번째에 27번을 찼습니다. 슬기가 혼자서 1등을 하려면 2번째에 적어도 몇 번을 차야 합니까?",
        "question_en": "Hohyeon, Seulgi, and Hyunjeong are competing in kicking jegi. Hohyeon kicked 23 times in the first and 28 times in the second. Hyunjeong kicked 32 times in the first and 17 times in the second. Seulgi kicked 27 times in the first. At least how many times does Seulgi need to kick in the 2nd to win first alone?",
        "answer_ko": "25",
        "answer_en": "25",
        "solution_abst_ko": "[OP_LIST_SOL] 호현 슬기 현정 [OP_LIST_EOL] [OP_LIST_SOL] 23 28 [OP_ADD] 32 17 [OP_ADD] 27 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] Hohyeon Seulgi Hyunjeong [OP_LIST_EOL] [OP_LIST_SOL] 23 28 [OP_ADD] 32 17 [OP_ADD] 27 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = '호현'\nvar_b = '슬기'\nvar_c = '현정'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 23\nvar_e = 28\nvar_f = var_d + var_e\nvar_g = 32\nvar_h = 17\nvar_i = var_g + var_h\nvar_j = 27\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_n = list_d[var_m-1]\nvar_o = var_l - var_n\nvar_p = 1\nvar_q = var_o + var_p\nprint(int(var_q))",
        "solution_code_en": "var_a = 'Hohyeon'\nvar_b = 'Seulgi'\nvar_c = 'Hyunjeong'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 23\nvar_e = 28\nvar_f = var_d + var_e\nvar_g = 32\nvar_h = 17\nvar_i = var_g + var_h\nvar_j = 27\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_n = list_d[var_m-1]\nvar_o = var_l - var_n\nvar_p = 1\nvar_q = var_o + var_p\nprint(int(var_q))"
    },
    "6213": {
        "category": "Arithmetic calculation",
        "question_ko": "숫자 5, 6, 2로 나누어 떨어질 수 있는 네 자리 수 중 가장 큰 수는 무엇입니까?",
        "question_en": "What is the largest four-digit number divisible by 5, 6, and 2?",
        "answer_ko": "9990",
        "answer_en": "9990",
        "solution_abst_ko": "1000 9999 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] 6 [OP_LIST_DIVISIBLE] 2 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_abst_en": "1000 9999 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] 6 [OP_LIST_DIVISIBLE] 2 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 6\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 2\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_h = list_e[-var_g]\nprint(int(var_h))",
        "solution_code_en": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 6\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 2\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_h = list_e[-var_g]\nprint(int(var_h))"
    },
    "6214": {
        "category": "Possibility",
        "question_ko": "10개의 숫자 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 중 서로 다른 세 개를 택하여 일렬로 나열하여 만든 세 자리의 자연수 중 300 이하의 짝수 중 가장 큰 값을 구하시오.",
        "question_en": "All possible three-digit natural numbers were made by picking three out of the ten digits 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9 and arranging them in a row. Among these, find the largest even number of no more than 300. ",
        "answer_ko": "298",
        "answer_en": "298",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 4 5 6 7 8 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 300 [OP_LIST_LESS_EQUAL] 2 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 4 5 6 7 8 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 300 [OP_LIST_LESS_EQUAL] 2 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nvar_f = 5\nvar_g = 6\nvar_h = 7\nvar_i = 8\nvar_j = 9\nlist_a= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_a.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_k = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_k))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_l = 300\nlist_c = []\nfor i in list_b:\n    if i <= var_l:\n        list_c.append(i)\nvar_m = 2\nlist_d = []\nvar_m = int(var_m)\nfor i in list_c:\n    i = int(i)\n    if i % var_m == 0:\n        list_d.append(i)\nvar_n = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_o = list_e[-var_n]\nprint(int(var_o))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nvar_f = 5\nvar_g = 6\nvar_h = 7\nvar_i = 8\nvar_j = 9\nlist_a= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_a.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_k = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_k))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_l = 300\nlist_c = []\nfor i in list_b:\n    if i <= var_l:\n        list_c.append(i)\nvar_m = 2\nlist_d = []\nvar_m = int(var_m)\nfor i in list_c:\n    i = int(i)\n    if i % var_m == 0:\n        list_d.append(i)\nvar_n = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_o = list_e[-var_n]\nprint(int(var_o))"
    },
    "6215": {
        "category": "Arithmetic calculation",
        "question_ko": "집을 6채 일정한 간격으로 11.5킬로미터(㎞) 도시에 지으려고 합니다. 도시의 양 끝에도 집을 짓는다고 할 때 집과 집사이의 거리는 몇 킬로미터(㎞)이어야 하나요?",
        "question_en": "We plan to build six houses at regular intervals in a city of 11.5 kilometers (km). If you build houses at both ends of the city, how many kilometers (km) apart should the houses be?",
        "answer_ko": "2.30",
        "answer_en": "2.3",
        "solution_abst_ko": "11.5 6 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "11.5 6 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 11.5\nvar_b = 6\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 11.5\nvar_b = 6\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "6216": {
        "category": "Possibility",
        "question_ko": "1부터 9까지의 숫자 카드를 한 번씩 사용하여 세 자리 수를 만듭니다. 큰 수부터 차례로 늘어놓을 때, 964는 몇 번째 수입니까?",
        "question_en": "Use the number cards 1 through 9 once each to create three-digit numbers. If these numbers are arranged from the largest to smallest, in what place would 964 come?",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "7 7 [OP_ADD] 4 [OP_ADD]",
        "solution_abst_en": "7 7 [OP_ADD] 4 [OP_ADD]",
        "solution_code_ko": "var_a = 7\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 7\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "6217": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 15미터(m)인 코끼리 열차가 1초에 275센티미터(㎝)씩 달리고 있습니다. 이 열차가 다리를 완전히 통과하는 데 48초가 걸렸다면 다리의 길이는 몇 미터(m)인지 구하시오.",
        "question_en": "An elephant train with a length of 15 meters (m) is running at 275 centimeters (cm) per second. If it took 48 seconds for this train to pass completely through the bridge, find the length in meters (m) of the bridge.",
        "answer_ko": "117",
        "answer_en": "117",
        "solution_abst_ko": "275 100 [OP_DIV] 48 [OP_MUL] 15 [OP_SUB]",
        "solution_abst_en": "275 100 [OP_DIV] 48 [OP_MUL] 15 [OP_SUB]",
        "solution_code_ko": "var_a = 275\nvar_b = 100\nvar_c = var_a / var_b\nvar_d = 48\nvar_e = var_c * var_d\nvar_f = 15\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 275\nvar_b = 100\nvar_c = var_a / var_b\nvar_d = 48\nvar_e = var_c * var_d\nvar_f = 15\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "6218": {
        "category": "Arithmetic calculation",
        "question_ko": "창고에 첫 째날에는 318개의 상자가 들어오고 둘 째날에는 312개의 상자가 들어오고 셋 째 날에는 180개와 162개가 나뉘어 들어왔습니다. 셋 째날까지 들어온 상자의 평균 개수는 몇 개입니까?",
        "question_en": "The warehouse received 318 boxes on the first day, 312 boxes on the second day, and 180 and 162 boxes separately on the third day. What is the average number of boxes received per day by the third day?",
        "answer_ko": "324",
        "answer_en": "324",
        "solution_abst_ko": "318 312 [OP_ADD] 180 162 [OP_ADD] [OP_ADD] 3 [OP_DIV]",
        "solution_abst_en": "318 312 [OP_ADD] 180 162 [OP_ADD] [OP_ADD] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 318\nvar_b = 312\nvar_c = var_a + var_b\nvar_d = 180\nvar_e = 162\nvar_f = var_d + var_e\nvar_g = var_c + var_f\nvar_h = 3\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 318\nvar_b = 312\nvar_c = var_a + var_b\nvar_d = 180\nvar_e = 162\nvar_f = var_d + var_e\nvar_g = var_c + var_f\nvar_h = 3\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "6219": {
        "category": "Arithmetic calculation",
        "question_ko": "종이 꽃가루를 만들기 위해 종이띠를 0.3센티미터(㎝)씩 자르려고 합니다. 종이띠 15.7센티미터(㎝)로 종이 꽃가루를 최대한 만들고 남는 종이띠는 몇 미터(㎝) 입니까?",
        "question_en": "To make confetti, you are going to cut a strip of paper 0.3 cm (cm) at a time. How many centimeters (cm) of paper strips are left after making confetti from a 15.7 cm (cm) paper strip?",
        "answer_ko": "0.1",
        "answer_en": "0.1",
        "solution_abst_ko": "15.7 0.3 [OP_MOD]",
        "solution_abst_en": "15.7 0.3 [OP_MOD]",
        "solution_code_ko": "var_a = 15.7\nvar_b = 0.3\nvar_c = var_a % var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 15.7\nvar_b = 0.3\nvar_c = var_a % var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "6220": {
        "category": "Comparison",
        "question_ko": "(가), (나), (다), (라) 4개의 상자가 있습니다. (나) 상자는 (라) 상자보다 작습니다. (가) 상자는 (라) 상자보다 큽니다. (나) 상자는 (다) 상자보다 큽니다. 크기가 가장 작은 상자는 무엇입니까?",
        "question_en": "There are 4 boxes (A), (B), (C), and (D). Box (B) is smaller than box (D). Box is (A) larger than box (D). Box (B) is larger than box (C). Which box is the smallest in size?",
        "answer_ko": "(다)",
        "answer_en": "(C)",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) (다) (라) [OP_LIST_EOL] [OP_LIST_SOL] (나) (라) < (가) (라) > (나) (다) > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (A) (B) (C) (D) [OP_LIST_EOL] [OP_LIST_SOL] (B) (D) < (A) (D) > (B) (C) > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nvar_c = '(다)'\nvar_d = '(라)'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '(나)'\nvar_f = '(라)'\nvar_g = '<'\nvar_h = '(가)'\nvar_i = '(라)'\nvar_j = '>'\nvar_k = '(나)'\nvar_l = '(다)'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)",
        "solution_code_en": "var_a = '(A)'\nvar_b = '(B)'\nvar_c = '(C)'\nvar_d = '(D)'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '(B)'\nvar_f = '(D)'\nvar_g = '<'\nvar_h = '(A)'\nvar_i = '(D)'\nvar_j = '>'\nvar_k = '(B)'\nvar_l = '(C)'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)"
    },
    "6221": {
        "category": "Geometry",
        "question_ko": "사다리꼴의 밑 변의 길이는 25센티미터(㎝)이고, 윗 변의 길이는 (가)센티미터(㎝)입니다. 두 변 사이의 거리는 13센티미터(㎝)이고, 이 사다리꼴의 넓이는 286제곱센티미터(㎠)라면, (가)에 알맞은 숫자는 무엇입니까?",
        "question_en": "The length of the base of the trapezoid is 25 centimeters (cm), and the length of the top side is (a) centimeters (cm). If the distance between the two sides is 13 centimeters (cm), and the area of this trapezoid is 286 square centimeters (cm2), what is the correct number for (a)?",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "286 13 [OP_DIV] 2 [OP_MUL] 25 [OP_SUB]",
        "solution_abst_en": "286 13 [OP_DIV] 2 [OP_MUL] 25 [OP_SUB]",
        "solution_code_ko": "var_a = 286\nvar_b = 13\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 25\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 286\nvar_b = 13\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 25\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "6222": {
        "category": "Comparison",
        "question_ko": "현정이는 빨간 상자 15개를, 슬기는 노란 상자 20개를 높이 쌓았다 .빨간 상자, 노란 상자의 1개의 높이는 각각 4.2센티미터(㎝), 3.3센티미터(㎝) 일때 상자를 가장 높이 쌓은 사람인 누구인지 구하시오.",
        "question_en": "Hyunjeong stacked up 15 red boxes and Seulgi stacked up 20 yellow boxes. When the heights of one red box and one yellow box are 4.2 cm and 3.3 cm respectively, find out who stacked up the box the highest.",
        "answer_ko": "슬기",
        "answer_en": "Seulgi",
        "solution_abst_ko": "[OP_LIST_SOL] 현정 슬기 [OP_LIST_EOL] [OP_LIST_SOL] 4.2 15 [OP_MUL] 3.3 20 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Hyunjeong Seulgi [OP_LIST_EOL] [OP_LIST_SOL] 4.2 15 [OP_MUL] 3.3 20 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '현정'\nvar_b = '슬기'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4.2\nvar_d = 15\nvar_e = var_c * var_d\nvar_f = 3.3\nvar_g = 20\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Hyunjeong'\nvar_b = 'Seulgi'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4.2\nvar_d = 15\nvar_e = var_c * var_d\nvar_f = 3.3\nvar_g = 20\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "6223": {
        "category": "Arithmetic calculation",
        "question_ko": "10리터(L)짜리 물통에 물이 7/10만큼 남아 있습니다. 남은 물을 물병 4개에 똑같이 나누어 담으려면 물병 한 개에 담아야 할 물은 몇 리터(L)인가요?",
        "question_en": "7/10 of the water remains in the 10 liter (L) bucket. How many liters (liters) of water do you need to fill in one bottle to divide the remaining water equally into 4 bottles?",
        "answer_ko": "1.75",
        "answer_en": "1.75",
        "solution_abst_ko": "10 7/10 [OP_MUL] 4 [OP_DIV]",
        "solution_abst_en": "10 7/10 [OP_MUL] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 0.7\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 10\nvar_b = 0.7\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "6224": {
        "category": "Comparison",
        "question_ko": "20명의 학생들이 한 줄로 줄을 섰습니다. 윤기의 앞에 11명의 학생들이 서 있습니다. 윤기의 뒤에 서 있는 학생은 몇 명입니까?",
        "question_en": "20 students lined up in a single line. Eleven students are standing in front of Yoongi. How many students are standing behind Yoongi?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "20 11 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "20 11 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "6225": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 농구팀이 서로 두번씩 경기를 한다면 경기는 모두 몇 번있는가?",
        "question_en": "If 5 basketball teams play each other twice, how many games are there altogether?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "5 5 1 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "5 5 1 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 5\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 5\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nprint(int(var_e))"
    },
    "6226": {
        "category": "Arithmetic calculation",
        "question_ko": "32의 약수들의 총합을 구하시오.",
        "question_en": "Find the sum of the factors of 32.",
        "answer_ko": "63",
        "answer_en": "63",
        "solution_abst_ko": "32 [OP_LIST_GET_DIVISOR] [OP_LIST_SUM]",
        "solution_abst_en": "32 [OP_LIST_GET_DIVISOR] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 32\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nlist_a = [float(i) for i in list_a]\nvar_b = sum(list_a)\nprint(int(var_b))",
        "solution_code_en": "var_a = 32\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nlist_a = [float(i) for i in list_a]\nvar_b = sum(list_a)\nprint(int(var_b))"
    },
    "6227": {
        "category": "Possibility",
        "question_ko": "1부터 9까지의 숫자가 적힌 9장의 숫자 카드가 있다. 이 중에서 3장의 카드를 꺼내 합이 17이 되게 하는 방법은 모두 몇 가지인가?",
        "question_en": "There are nine number cards with numbers from 1 to 9 written on them. How many ways can you draw 3 of these cards so that the sum is 17?",
        "answer_ko": "42",
        "answer_en": "42",
        "solution_abst_ko": "1 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 17 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 17 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 17\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 17\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))"
    },
    "6228": {
        "category": "Arithmetic calculation",
        "question_ko": "5년 전에 어머니 나이는 딸 나이의 4배였습니다. 올해부터 8년 후 어머니와 딸의 나이의 합은 71살이 됩니다. 올해 어머니의 나이는 몇 살입니까?",
        "question_en": "Five years ago, the mother was four times the daughter's age. Eight years from this year, the sum of the ages of mother and daughter will be 71. How old is the mother this year?",
        "answer_ko": "41",
        "answer_en": "41",
        "solution_abst_ko": "71 8 2 [OP_MUL] [OP_SUB] 5 2 [OP_MUL] [OP_SUB] 4 1 [OP_ADD] [OP_FDIV] 4 [OP_MUL] 5 [OP_ADD]",
        "solution_abst_en": "71 8 2 [OP_MUL] [OP_SUB] 5 2 [OP_MUL] [OP_SUB] 4 1 [OP_ADD] [OP_FDIV] 4 [OP_MUL] 5 [OP_ADD]",
        "solution_code_ko": "var_a = 71\nvar_b = 8\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 5\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nvar_j = 4\nvar_k = 1\nvar_l = var_j + var_k\nvar_m = var_i // var_l\nvar_n = 4\nvar_o = var_m * var_n\nvar_p = 5\nvar_q = var_o + var_p\nprint(int(var_q))",
        "solution_code_en": "var_a = 71\nvar_b = 8\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 5\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nvar_j = 4\nvar_k = 1\nvar_l = var_j + var_k\nvar_m = var_i // var_l\nvar_n = 4\nvar_o = var_m * var_n\nvar_p = 5\nvar_q = var_o + var_p\nprint(int(var_q))"
    },
    "6229": {
        "category": "Correspondence",
        "question_ko": "호석이가 감 2개와 사과 7개를 샀을 때, 호석이가 산 과일의 수는 몇인가요?",
        "question_en": "When Hoseok bought 2 persimmons and 7 apples, how many fruits did Hoseok buy?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "2 7 [OP_ADD]",
        "solution_abst_en": "2 7 [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "6230": {
        "category": "Possibility",
        "question_ko": "1에서 12까지의 숫자 중 3의 배수는 모두 몇 개인지 구하세요.",
        "question_en": "Find how many numbers from 1 to 12 are multiples of 3.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "1 12 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "1 12 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 12\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 12\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "6231": {
        "category": "Possibility",
        "question_ko": "서로 다른 3개의 공을 각각 1개 이상씩 뽑으면서 중복을 허용하여 9개를 뽑는 경우의 수를 구하시오.",
        "question_en": "Find the number of cases of selecting 9 balls using at least 1 of each of the 3 different balls and allowing duplicates.",
        "answer_ko": "28",
        "answer_en": "28",
        "solution_abst_ko": "3 9 [OP_ADD] 3 1 [OP_MUL] [OP_SUB] 1 [OP_SUB] 9 3 1 [OP_MUL] [OP_SUB] [OP_COMB]",
        "solution_abst_en": "3 9 [OP_ADD] 3 1 [OP_MUL] [OP_SUB] 1 [OP_SUB] 9 3 1 [OP_MUL] [OP_SUB] [OP_COMB]",
        "solution_code_ko": "var_a = 3\nvar_b = 9\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 1\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = 9\nvar_k = 3\nvar_l = 1\nvar_m = var_k * var_l\nvar_n = var_j - var_m\nvar_o = 1\nvar_i = int(var_i)\nvar_n = int(var_n)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o * (var_i-i)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o / (i+1)\nprint(int(var_o))",
        "solution_code_en": "var_a = 3\nvar_b = 9\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 1\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = 9\nvar_k = 3\nvar_l = 1\nvar_m = var_k * var_l\nvar_n = var_j - var_m\nvar_o = 1\nvar_i = int(var_i)\nvar_n = int(var_n)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o * (var_i-i)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o / (i+1)\nprint(int(var_o))"
    },
    "6232": {
        "category": "Arithmetic calculation",
        "question_ko": "냉장고에 주스가 있었습니다. 이 중에서 아버지가 전체의 1/6을 마시고, 나머지 2/5를 어머니가 마셨습니다. 아버지와 어머니가 마시고 남은 주스의 2/3을 효근이가 마시고 난 후, 남은 주스의 양이 120밀리리터(㎖)였다면 처음에 냉장고에 있었던 주스의 양은 몇 밀리리터(㎖)입니까?",
        "question_en": "There was juice in the fridge. Of this, the father drank 1/6 of the total, and the mother drank the remaining 2/5. After Hyo-geun drank 2/3 of the remaining juice from father and mother, if the amount of juice remaining was 120 milliliters (ml), how many milliliters (ml) of juice was initially in the refrigerator?",
        "answer_ko": "720",
        "answer_en": "720",
        "solution_abst_ko": "120 1 1/6 [OP_SUB] [OP_DIV] 1 2/5 [OP_SUB] [OP_DIV] 1 2/3 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "120 1 1/6 [OP_SUB] [OP_DIV] 1 2/5 [OP_SUB] [OP_DIV] 1 2/3 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 120\nvar_b = 1\nvar_c = 0.16666666666666666\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 1\nvar_g = 0.4\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 1\nvar_k = 0.6666666666666666\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nprint(int(eval('{:.2f}'.format(round(var_m+1e-10,2)))))",
        "solution_code_en": "var_a = 120\nvar_b = 1\nvar_c = 0.16666666666666666\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 1\nvar_g = 0.4\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 1\nvar_k = 0.6666666666666666\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nprint(int(eval('{:.2f}'.format(round(var_m+1e-10,2)))))"
    },
    "6233": {
        "category": "Correspondence",
        "question_ko": "다섯 자리 수 AB40C은 45의 배수이다. 이러한 다섯 자리 수는 모두 몇 가지인지 구하여라.",
        "question_en": "The five-digit number AB40C is a multiple of 45. Think of five-digit numbers like this. How many can you find?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "AB40C [OP_GEN_POSSIBLE_LIST] 45 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "AB40C [OP_GEN_POSSIBLE_LIST] 45 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 'AB40C'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 45\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))",
        "solution_code_en": "var_a = 'AB40C'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 45\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))"
    },
    "6234": {
        "category": "Correspondence",
        "question_ko": "90개의 구슬을 몇 개씩 포장하려하는데 포장하고 남는 구슬이 없어야 한다. 한 개의 포장에 들어갈 수 있는 수의 개수를 구하시오.",
        "question_en": "I'm going to pack 90 beads, but there should be no beads left after packing them. Find how many can fit in one package.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "90 [OP_LIST_GET_DIVISOR] [OP_LIST_LEN]",
        "solution_abst_en": "90 [OP_LIST_GET_DIVISOR] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 90\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = len(list_a)\nprint(int(var_b))",
        "solution_code_en": "var_a = 90\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = len(list_a)\nprint(int(var_b))"
    },
    "6235": {
        "category": "Geometry",
        "question_ko": "석준이는 둘레가 96센티미터(㎝)인 정사각형의 각 변의 한가운데 점을 이어 마름모를 그렸습니다. 그린 마름모의 넓이는 몇 제곱센티미터입니까?",
        "question_en": "Seokjun drew a rhombus by connecting the dots in the middle of each side of a square with a circumference of 96 centimeters (cm). What is the area, in square centimeters (cm2), of the rhombus you drew?",
        "answer_ko": "288",
        "answer_en": "288",
        "solution_abst_ko": "96 4 [OP_DIV] 2 [OP_POW] 2 [OP_DIV]",
        "solution_abst_en": "96 4 [OP_DIV] 2 [OP_POW] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 96\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 96\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "6236": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 260미터(m)인 도로의 양쪽에 처음부터 끝까지 4미터(m) 간격으로 가로등을 세우려고 합니다. 필요한 가로등은 모두 몇 개인지 구해 보시오.",
        "question_en": "Streetlights are to be erected at intervals of 4 meters (m) from start to finish on both sides of a road that is 260 meters (m) long. Find how many streetlights you need.",
        "answer_ko": "132",
        "answer_en": "132",
        "solution_abst_ko": "260 4 [OP_DIV] 1 [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "260 4 [OP_DIV] 1 [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 260\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 260\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "6237": {
        "category": "Arithmetic calculation",
        "question_ko": "성재네 반 학생은 한 모둠에 6명씩 7모둠입니다. 한 묶음에 105장인 색종이 14묶음을 성재네 반 학생들에게 똑같이 나누어 주었더니 84장이 남았습니다. 한 사람에게 나누어 준 색종이는 몇 장입니까?",
        "question_en": "Seongjae's class is made up of 7 groups, with 6 students in each group. 14 bundles of 105 sheets of colored paper were distributed equally to Seongjae's classmates, and there were 84 sheets left. How many pieces of colored paper were handed out to each person?",
        "answer_ko": "33",
        "answer_en": "33",
        "solution_abst_ko": "105 14 [OP_MUL] 84 [OP_SUB] 6 7 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "105 14 [OP_MUL] 84 [OP_SUB] 6 7 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 105\nvar_b = 14\nvar_c = var_a * var_b\nvar_d = 84\nvar_e = var_c - var_d\nvar_f = 6\nvar_g = 7\nvar_h = var_f * var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 105\nvar_b = 14\nvar_c = var_a * var_b\nvar_d = 84\nvar_e = var_c - var_d\nvar_f = 6\nvar_g = 7\nvar_h = var_f * var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "6238": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 268.8미터(m)인 도로의 한쪽에 6.4미터(m) 간격으로 가로수를 심으려고 합니다. 도로의 처음과 끝에 모두 나무를 심는다면 나무는 몇 그루 필요합니까??",
        "question_en": "Street trees are to be planted every 6.4 meters (m) on one side of a road with a length of 268.8 meters (m). Find the number of trees needed if you plant trees at both the beginning and end of the road.",
        "answer_ko": "43",
        "answer_en": "43",
        "solution_abst_ko": "268.8 6.4 [OP_DIV] 1 [OP_ADD]",
        "solution_abst_en": "268.8 6.4 [OP_DIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 268.8\nvar_b = 6.4\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 268.8\nvar_b = 6.4\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "6239": {
        "category": "Geometry",
        "question_ko": "모서리의 길이가 모두 같은 사각기둥이 있습니다. 이 사각기둥의 모든 모서리의 길이의 합이 72센티미터(㎝)일 때 한 모서리의 길이는 몇 센티미터(㎝)인지 구해 보세요.",
        "question_en": "There is a rectangular prism that has all its edges the same length. If the sum of the lengths of all the edges of this square prism is 72 centimeters (cm), how many centimeters (cm) is the length of one edge?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "72 4 3 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "72 4 3 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 72\nvar_b = 4\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 72\nvar_b = 4\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "6240": {
        "category": "Arithmetic calculation",
        "question_ko": "긴 낚시대의 길이는 14/15미터(m)이고, 짧은 낚시대보다 1/10미터(m) 길다면, 긴 낚시대와 짧은 낚시대의 길이의 합은 몇 미터(m)일까요?",
        "question_en": "If the length of the long rod is 14/15 meters (m), and it is 1/10 meter (m) longer than the short rod, how many meters (m) is the sum of the lengths of the long rod and the short rod?",
        "answer_ko": "1.77",
        "answer_en": "1.77",
        "solution_abst_ko": "14/15 2 [OP_MUL] 1/10 [OP_SUB]",
        "solution_abst_en": "14/15 2 [OP_MUL] 1/10 [OP_SUB]",
        "solution_code_ko": "var_a = 0.9333333333333333\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 0.1\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.9333333333333333\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 0.1\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "6241": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2 중에서 0.4보다 작거나 같은 수는 몇 개입니까?",
        "question_en": "How many numbers between 0.8, 1/2 are less than or equal to 0.4?",
        "answer_ko": "0",
        "answer_en": "0",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 [OP_LIST_EOL] 0.4 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 [OP_LIST_EOL] 0.4 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.4\nlist_b = []\nfor i in list_a:\n    if i <= var_c:\n        list_b.append(i)\nvar_d = len(list_b)\nprint(int(var_d))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.4\nlist_b = []\nfor i in list_a:\n    if i <= var_c:\n        list_b.append(i)\nvar_d = len(list_b)\nprint(int(var_d))"
    },
    "6242": {
        "category": "Comparison",
        "question_ko": "꽃병은 어느 선반의 한 층의 오른쪽에서 5번째, 왼쪽에서 4번째에 놓여 있습니다. 각 층마다 놓여 있는 꽃병의 수는 같고 선반은 10층 입니다. 꽃 가게에 꽃병이 총 1600개가 있을 때, 선반은 모두 몇 개 입니까?",
        "question_en": "The vase is placed 5th from the right and 4th from the left on one level of a shelf. The number of vases on each floor is the same, and there are 10 shelves. If the flower shop has a total of 1600 vases, how many shelves are there in total?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "1600 5 4 [OP_ADD] 1 [OP_SUB] 10 [OP_MUL] [OP_FDIV]",
        "solution_abst_en": "1600 5 4 [OP_ADD] 1 [OP_SUB] 10 [OP_MUL] [OP_FDIV]",
        "solution_code_ko": "var_a = 1600\nvar_b = 5\nvar_c = 4\nvar_d = var_b + var_c\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 10\nvar_h = var_f * var_g\nvar_i = var_a // var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1600\nvar_b = 5\nvar_c = 4\nvar_d = var_b + var_c\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 10\nvar_h = var_f * var_g\nvar_i = var_a // var_h\nprint(int(var_i))"
    },
    "6243": {
        "category": "Comparison",
        "question_ko": "20명의 학생들이 버스를 기다리고 있습니다. 윤기보다 먼저 온 사람은 11명이라면 윤기보다 늦게 온 사람은 몇 명입니까?",
        "question_en": "20 students are waiting for the bus. If 11 people came before Yoongi, how many people came later than Yoongi?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "20 11 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "20 11 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "6244": {
        "category": "Arithmetic calculation",
        "question_ko": "연필이 7묶음 있습니다. 연필이 색연필 보다 3자루 더 적습니다. 연필 1묶음에 10자루일 때 색연필은 몇 자루인지 구하시오",
        "question_en": "There are 7 packs of pencils. There are 3 fewer pencils than colored pencils. If there are 10 pencils in a pack of pencils, how many colored pencils are there?",
        "answer_ko": "73",
        "answer_en": "73",
        "solution_abst_ko": "7 10 [OP_MUL] 3 [OP_ADD]",
        "solution_abst_en": "7 10 [OP_MUL] 3 [OP_ADD]",
        "solution_code_ko": "var_a = 7\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 7\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "6245": {
        "category": "Arithmetic calculation",
        "question_ko": "수희의 키는 1미터(m) 35센티미터(㎝)이고, 수희가 9센티미터(㎝)를 자라면 오빠와 키가 같아진다고 합니다. 수희의 오빠의 키는 몇 미터(m)인지 소수로 나타내시오.",
        "question_en": "Su-hee's height is 1 meter (m) 35 centimeters (cm), and when Su-hee grows by 9 centimeters (cm), she will be the same height as her brother. Express the height in meters (m) of Su-hee's brother as a decimal number.",
        "answer_ko": "1.44",
        "answer_en": "1.44",
        "solution_abst_ko": "1 35 100 [OP_DIV] [OP_ADD] 9 100 [OP_DIV] [OP_ADD]",
        "solution_abst_en": "1 35 100 [OP_DIV] [OP_ADD] 9 100 [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 35\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 9\nvar_g = 100\nvar_h = var_f / var_g\nvar_i = var_e + var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 35\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 9\nvar_g = 100\nvar_h = var_f / var_g\nvar_i = var_e + var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "6246": {
        "category": "Geometry",
        "question_ko": "둘레의 길이가 54 센티미터(㎝)인 직사각형이 있다. 이 때, 가로의 길이가 세로의 길이보다 3 센티미터(㎝) 더 길다. 가로의 길이를 구하시오.",
        "question_en": "You have a rectangle with a perimeter of 54 centimeters (cm). At this time, the horizontal length is 3 centimeters (cm) longer than the vertical length. Find the horizontal length.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "54 2 [OP_DIV] 3 [OP_SUB] 2 [OP_DIV] 3 [OP_ADD]",
        "solution_abst_en": "54 2 [OP_DIV] 3 [OP_SUB] 2 [OP_DIV] 3 [OP_ADD]",
        "solution_code_ko": "var_a = 54\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 3\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 3\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 54\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 3\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 3\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "6247": {
        "category": "Geometry",
        "question_ko": "넓이가 81.12제곱센티미터(㎠)인 정육각형 모양의 쿠키가 있습니다. 이 쿠키를 6명의 친구가 등분하여 나누어 먹었다면, 한 명이 먹은 쿠키의 넓이는 몇 제곱센티미터(㎠)일지 구하시오.",
        "question_en": "You have a cookie in the shape of a regular hexagon with an area of 81.12 square centimeters (cm2). If 6 friends divide the cookie into equal parts and eat it, find the area in square centimeters (cm2) of the cookie eaten by one person.",
        "answer_ko": "13.52",
        "answer_en": "13.52",
        "solution_abst_ko": "81.12 6 [OP_DIV]",
        "solution_abst_en": "81.12 6 [OP_DIV]",
        "solution_code_ko": "var_a = 81.12\nvar_b = 6\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 81.12\nvar_b = 6\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "6248": {
        "category": "Arithmetic calculation",
        "question_ko": "등산을 하는데 올라갈 때는 시속 2 킬로미터(㎞)로, 내려올 때는 올라갈 때보다 2 킬로미터(㎞) 더 먼 길을 시속 3 킬로미터(㎞)로 걸어내려 왔더니, 4시간이 걸렸다. 내려온 거리는 얼마인가?",
        "question_en": "I climbed the mountain at 2 kilometers per hour (km), and when I came down, I walked 2 kilometers (km) further than when I went up, at 3 kilometers (km) per hour, and it took 4 hours. What is the distance of climbing down the mountain?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "2 4 [OP_MUL] 2 [OP_ADD] 3 2 [OP_ADD] [OP_DIV] 3 [OP_MUL]",
        "solution_abst_en": "2 4 [OP_MUL] 2 [OP_ADD] 3 2 [OP_ADD] [OP_DIV] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = var_e / var_h\nvar_j = 3\nvar_k = var_i * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = var_e / var_h\nvar_j = 3\nvar_k = var_i * var_j\nprint(int(var_k))"
    },
    "6249": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 6센티미터(㎝)인 정사각형이 있습니다. 정사각형의 네 변의 길이를 각각 1 센티미터(㎝) 씩 늘이면 정사각형의 넓이는 몇 제곱센티미터(㎠) 늘어납니까?",
        "question_en": "There is a square with a side of 6 centimeters (cm). By how many square centimeters (cm2) does the area of the square increase if the length of each side of the square is increased by 1 centimeter (cm)?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "6 1 [OP_ADD] 2 [OP_POW] 6 2 [OP_POW] [OP_SUB]",
        "solution_abst_en": "6 1 [OP_ADD] 2 [OP_POW] 6 2 [OP_POW] [OP_SUB]",
        "solution_code_ko": "var_a = 6\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 6\nvar_g = 2\nvar_h = var_f ** var_g\nvar_i = var_e - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 6\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 6\nvar_g = 2\nvar_h = var_f ** var_g\nvar_i = var_e - var_h\nprint(int(var_i))"
    },
    "6250": {
        "category": "Arithmetic calculation",
        "question_ko": "휘발유 0.14리터(L)를 이용하면 1킬로미터(㎞)를 이동할 수 있습니다. 1시간에 93.6킬로미터(㎞)씩 2시간 30분을 이동하기 위해선 휘발유가 몇 리터(L) 필요할까요?",
        "question_en": "Using 0.14 liters (L) of gasoline, you can travel 1 kilometer (km). How many liters (l) of gasoline do you need to travel 2 hours 30 minutes at 93.6 kilometers (km) in 1 hour?",
        "answer_ko": "32.76",
        "answer_en": "32.76",
        "solution_abst_ko": "0.14 93.6 [OP_MUL] 2 30 60 [OP_DIV] [OP_ADD] [OP_MUL]",
        "solution_abst_en": "0.14 93.6 [OP_MUL] 2 30 60 [OP_DIV] [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 0.14\nvar_b = 93.6\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = 30\nvar_f = 60\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = var_c * var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 0.14\nvar_b = 93.6\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = 30\nvar_f = 60\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = var_c * var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "6251": {
        "category": "Arithmetic calculation",
        "question_ko": "현아는 1시간에 7000미터(m)를 걷습니다. 현아가 100000미터(m)를 걸으려면 적어도 몇 시간을 걸어야 할 지 정수로 나타내세요.",
        "question_en": "Hyuna walks 7000 meters (m) in an hour. Express as an integer of how many hours Hyuna must walk to reach 100000 meters (m).",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "100000 7000 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "100000 7000 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 100000\nvar_b = 7000\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))",
        "solution_code_en": "var_a = 100000\nvar_b = 7000\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))"
    },
    "6252": {
        "category": "Correspondence",
        "question_ko": "34과 어떤 수를 더한 값에 53을 빼면 28일 때, 어떤 수는 얼마입니까?",
        "question_en": "If 34 plus a certain number minus 53 is 28, what number is that?",
        "answer_ko": "47",
        "answer_en": "47",
        "solution_abst_ko": "28 53 [OP_ADD] 34 [OP_SUB]",
        "solution_abst_en": "28 53 [OP_ADD] 34 [OP_SUB]",
        "solution_code_ko": "var_a = 28\nvar_b = 53\nvar_c = var_a + var_b\nvar_d = 34\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 28\nvar_b = 53\nvar_c = var_a + var_b\nvar_d = 34\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "6253": {
        "category": "Geometry",
        "question_ko": "빨간색 색종이는 한 변의 길이가 8센티미터(㎝)인 정사각형 모양이고 노란색 색종이는 한 변의 길이가 10센티미터(㎝), 나머지 한 변의 길이가 5센티미터(㎝)인 직사각형 모양입니다. 빨간색 색종이와 노란색 색종이의 넓이의 차를 구하시오.",
        "question_en": "The red confetti is a square shape whose side is 8 centimeters (cm), and the yellow confetti is a rectangle shape whose side is 10 centimeters (cm) and 5 centimeters (cm). Find the difference between the areas of the red confetti and the yellow confetti.",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "8 2 [OP_POW] 10 5 [OP_MUL] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "8 2 [OP_POW] 10 5 [OP_MUL] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 8\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 10\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = abs(var_g)\nprint(int(var_h))",
        "solution_code_en": "var_a = 8\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 10\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = abs(var_g)\nprint(int(var_h))"
    },
    "6254": {
        "category": "Arithmetic calculation",
        "question_ko": "자루 안에 흰 구슬이 19개, 검은 구슬이 몇 개 들어 있습니다. 자루 안에 들어 있는 흰 구슬과 검은 구슬이 모두 37개라면 검은 구슬은 몇 개입니까?",
        "question_en": "There are 19 white marbles and some black marbles in a bag. How many black marbles are there if the total number of white and black marbles is 37 in the bag?",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "37 19 [OP_SUB]",
        "solution_abst_en": "37 19 [OP_SUB]",
        "solution_code_ko": "var_a = 37\nvar_b = 19\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 37\nvar_b = 19\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "6255": {
        "category": "Geometry",
        "question_ko": "세로가 3.6미터(m)이고 가로가 세로의 2.5배인 직사각형 모양의 바닥이 있는 방이 있습니다. 이 방의 바닥의 절반은 노란색 타일을 깔았을 때, 노란색 타일이 깔린 바닥의 넓이는 몇 제곱미터(㎡)입니까?",
        "question_en": "You have a room with a rectangular floor with a length of 3.6 meters (m) and a width 2.5 times its length. If half of the floor in this room is tiled in yellow, what is the area of the yellow tiled floor in square meters (m2)?",
        "answer_ko": "16.20",
        "answer_en": "16.2",
        "solution_abst_ko": "3.6 3.6 2.5 [OP_MUL] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "3.6 3.6 2.5 [OP_MUL] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 3.6\nvar_b = 3.6\nvar_c = 2.5\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 3.6\nvar_b = 3.6\nvar_c = 2.5\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "6256": {
        "category": "Possibility",
        "question_ko": "234의 각 자릿수를 움직여 다른 수를 만들고자 합니다. 340보다 큰 경우는 몇 가지입니까?",
        "question_en": "We want to create a new number by moving each digit of 234. How many cases are there where you make a new number that is greater than 340? ",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "234 [OP_NUM2LIST] [OP_LIST_LEN] [OP_LIST_GET_PERM] 340 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "234 [OP_NUM2LIST] [OP_LIST_LEN] [OP_LIST_GET_PERM] 340 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 234\nlist_a = []\nvar_a = int(var_a)\nwhile var_a//10 > 0:\n    list_a.append(var_a%10)\n    var_a = var_a//10\nlist_a.append(var_a%10)\nlist_a = list_a[::-1]\nvar_b = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_b))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_c = 340\nlist_c = []\nfor i in list_b:\n    if i > var_c:\n        list_c.append(i)\nvar_d = len(list_c)\nprint(int(var_d))",
        "solution_code_en": "var_a = 234\nlist_a = []\nvar_a = int(var_a)\nwhile var_a//10 > 0:\n    list_a.append(var_a%10)\n    var_a = var_a//10\nlist_a.append(var_a%10)\nlist_a = list_a[::-1]\nvar_b = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_b))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_c = 340\nlist_c = []\nfor i in list_b:\n    if i > var_c:\n        list_c.append(i)\nvar_d = len(list_c)\nprint(int(var_d))"
    },
    "6257": {
        "category": "Correspondence",
        "question_ko": "공장에서 하루에 만드는 인형들 중 불량품을 제외한 인형의 개수는 4800개이고 하루에 만드는 모든 인형의 개수는 정상품 개수의 1.33배라고 한다. 공장에서 하루에 만드는 인형은 모두 몇 개 인지 구하시오.",
        "question_en": "Among the dolls made in a factory per day, the number of dolls excluding the defective ones is 4800, and the number of the total dolls made per day is 1.33 times the number of normal products. Find how many dolls the factory makes per day.",
        "answer_ko": "6384",
        "answer_en": "6384",
        "solution_abst_ko": "4800 1.33 [OP_MUL]",
        "solution_abst_en": "4800 1.33 [OP_MUL]",
        "solution_code_ko": "var_a = 4800\nvar_b = 1.33\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 4800\nvar_b = 1.33\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "6258": {
        "category": "Comparison",
        "question_ko": "정국이는 지우개를 6개 가지고 있습니다. 지민이는 지우개를 정국이보다 4개 더 많이 가지고 있고 석진이는 지민이보다 3개 더 적게 가지고 있습니다. 지우개를 가장 적게 가지고 있는 사람은 누구입니까?",
        "question_en": "Jungkook has 6 erasers. Jimin has 4 more erasers than Jungkook, and Seokjin has 3 fewer than Jimin. Who has the fewest erasers?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 지민 석진 [OP_LIST_EOL] [OP_LIST_SOL] 6 6 4 [OP_ADD] 6 4 [OP_ADD] 3 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Jimin Seokjin [OP_LIST_EOL] [OP_LIST_SOL] 6 6 4 [OP_ADD] 6 4 [OP_ADD] 3 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '지민'\nvar_c = '석진'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 6\nvar_e = 6\nvar_f = 4\nvar_g = var_e + var_f\nvar_h = 6\nvar_i = 4\nvar_j = var_h + var_i\nvar_k = 3\nvar_l = var_j - var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[var_m-1]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Jimin'\nvar_c = 'Seokjin'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 6\nvar_e = 6\nvar_f = 4\nvar_g = var_e + var_f\nvar_h = 6\nvar_i = 4\nvar_j = var_h + var_i\nvar_k = 3\nvar_l = var_j - var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[var_m-1]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "6259": {
        "category": "Comparison",
        "question_ko": "학생들이 한 줄로 서 있습니다. 태형이의 앞에는 9명, 뒤에는 16명이 서 있습니다. 줄을 서 있는 학생은 모두 몇 명입니까?",
        "question_en": "Students are standing in a line. There are 9 people in front of Taehyung and 16 people behind him. How many students are standing in a line?",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "9 16 [OP_ADD] 1 [OP_ADD]",
        "solution_abst_en": "9 16 [OP_ADD] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 9\nvar_b = 16\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 16\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "6260": {
        "category": "Correspondence",
        "question_ko": "두 자연수 A, B에 대하여 B는 A에서 9를 곱한 후 13을 더했을 때 나오는 숫자라면, B를 9로 나누었을 때의 나머지는 얼마입니까?",
        "question_en": "Given two natural numbers A and B, if B is the number obtained when A is multiplied by 9 and then added to 13, what is the remainder when you divide B by 9?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "13 9 [OP_MOD]",
        "solution_abst_en": "13 9 [OP_MOD]",
        "solution_code_ko": "var_a = 13\nvar_b = 9\nvar_c = var_a % var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 13\nvar_b = 9\nvar_c = var_a % var_b\nprint(int(var_c))"
    },
    "6261": {
        "category": "Geometry",
        "question_ko": "한 모서리의 길이가 11 센티미터(㎝) 인 정육면체 모양의 상자가 있습니다. 상자의 겉넓이는 몇 제곱센티미터(㎠)인가요?",
        "question_en": "You have a cube-shaped box with one edge measuring 11 centimeters (cm). What is the surface area of the box in square centimeters (cm2)?",
        "answer_ko": "726",
        "answer_en": "726",
        "solution_abst_ko": "11 2 [OP_POW] 6 [OP_MUL]",
        "solution_abst_en": "11 2 [OP_POW] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 11\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 11\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "6262": {
        "category": "Arithmetic calculation",
        "question_ko": "2리터(L)의 냄비를 물로 채우기 위해서 200밀리리터(㎖) 용량의 컵으로 물을 3번 부었다면, 앞으로 최대 몇 번 더 부어야 하는지 구하시오.",
        "question_en": "If you pour water into a 200 ml (㎖) cup 3 times to fill a 2 liter (L) pot with water, find the maximum number of times you need to pour water in the future.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "2 1000 [OP_MUL] 200 3 [OP_MUL] [OP_SUB] 200 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "2 1000 [OP_MUL] 200 3 [OP_MUL] [OP_SUB] 200 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 200\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 200\nvar_i = var_g / var_h\nvar_j = 1\nvar_k=int(((var_i+9*10**(var_j-2))//(10**(var_j-1)))*10**(var_j-1))\n\nprint(int(var_k))",
        "solution_code_en": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 200\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 200\nvar_i = var_g / var_h\nvar_j = 1\nvar_k=int(((var_i+9*10**(var_j-2))//(10**(var_j-1)))*10**(var_j-1))\n\nprint(int(var_k))"
    },
    "6263": {
        "category": "Arithmetic calculation",
        "question_ko": "올해 할아버지 나이는 손자 나이의 6배입니다. 4년 후에 할아버지와 손자 나이의 합은 78살이 됩니다. 올해 손자의 나이는 몇 살입니까?",
        "question_en": "Grandpa's age this year is 6 times the age of his grandson. After 4 years, the sum of the ages of the grandfather and grandson will be 78. How old is the grandson this year?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "78 4 2 [OP_MUL] [OP_SUB] 1 6 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "78 4 2 [OP_MUL] [OP_SUB] 1 6 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 78\nvar_b = 4\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = 6\nvar_h = var_f + var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 78\nvar_b = 4\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = 6\nvar_h = var_f + var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "6264": {
        "category": "Arithmetic calculation",
        "question_ko": "사과가 17개, 배가 9개 있습니다. 사과는 배보다 몇 개 더 많습니까?",
        "question_en": "There are 17 apples and 9 pears. How many more apples than pears?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "17 9 [OP_SUB]",
        "solution_abst_en": "17 9 [OP_SUB]",
        "solution_code_ko": "var_a = 17\nvar_b = 9\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 17\nvar_b = 9\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "6265": {
        "category": "Arithmetic calculation",
        "question_ko": "아들은 5살이고 올해 아버지는 35살입니다. 시간이 지나고 아버지와 아들의 나이의 합이 60살이 된다면 얼마나 시간이 지나야 합니까?",
        "question_en": "Given that the age of the son and father is each 5 and 35 this year, how long will it take for the sum of their ages become 60?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "60 35 5 [OP_ADD] [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "60 35 5 [OP_ADD] [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 60\nvar_b = 35\nvar_c = 5\nvar_d = var_b + var_c\nvar_e = var_a - var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 60\nvar_b = 35\nvar_c = 5\nvar_d = var_b + var_c\nvar_e = var_a - var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "6266": {
        "category": "Possibility",
        "question_ko": "4명의 친구가 만나서 모든 사람이 다른 사람과 한 번씩 악수를 하였습니다. 악수의 총 횟수를 구하시오.",
        "question_en": "Four friends met and everyone shook hands with each other once. Find the total number of handshakes.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "4 4 1 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "4 4 1 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 4\nvar_b = 4\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 4\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "6267": {
        "category": "Correspondence",
        "question_ko": "식 31+6A2=683이 있습니다. A에 들어가야 하는 숫자를 구하시오",
        "question_en": "We have an expression of 31+6A2=683. Find the number that must go into A.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "31+6A2=683 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "31+6A2=683 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '31+6A2=683'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '31+6A2=683'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "6268": {
        "category": "Comparison",
        "question_ko": "마트에서 남준, 윤기, 호석이가 한 줄로 섰습니다. 남준이는 33번째에 섰고, 호석이는 35번째에 섰습니다. 윤기는 몇 번째입니까?",
        "question_en": "Namjoon, Yoongi, and Hoseok stood in a line at the supermarket. Namjoon stood at the 33rd, and Hoseok stood at the 35th. What about Yoongi?",
        "answer_ko": "34",
        "answer_en": "34",
        "solution_abst_ko": "33 35 [OP_ADD] 2 [OP_FDIV]",
        "solution_abst_en": "33 35 [OP_ADD] 2 [OP_FDIV]",
        "solution_code_ko": "var_a = 33\nvar_b = 35\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 33\nvar_b = 35\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "6269": {
        "category": "Arithmetic calculation",
        "question_ko": "한 상자에 책이 46권씩 들어있는 상자가 19개가 있고 한 상자에 연필이 170자루씩 들어있는 상자가 몇 개 있습니다. 책과 연필의 개수를 더했더니 1894였다면, 연필이 든 상자는 몇 개입니까?",
        "question_en": "There are 19 baskets of plums with 46 in each basket and several baskets of blueberries with 170 in each basket. If the total number of fruits in the basket is 1894, how many baskets of blueberries are there?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "1894 46 19 [OP_MUL] [OP_SUB] 170 [OP_FDIV]",
        "solution_abst_en": "1894 46 19 [OP_MUL] [OP_SUB] 170 [OP_FDIV]",
        "solution_code_ko": "var_a = 1894\nvar_b = 46\nvar_c = 19\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 170\nvar_g = var_e // var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1894\nvar_b = 46\nvar_c = 19\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 170\nvar_g = var_e // var_f\nprint(int(var_g))"
    },
    "6270": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 일을 윤경이 혼자서 완성하는 데 3일이 걸린다. 윤경이가 하루 동안 할 수 있는 일의 양은 전체의 얼마인가?",
        "question_en": "It takes 3 days for Yunkyung to complete a certain task by herself. What is the total amount of work Yunkyung can do in a day?",
        "answer_ko": "0.33",
        "answer_en": "0.33",
        "solution_abst_ko": "1 3 [OP_DIV]",
        "solution_abst_en": "1 3 [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "6271": {
        "category": "Geometry",
        "question_ko": "두 직사각형의 가로의 비가 8:7이고, 세로의 비가 9:4입니다. 큰 직사각형의 넓이가 108제곱센티미터(㎠)일 때, 작은 직사각형의 넓이를 구하시오.",
        "question_en": "The horizontal ratio of the two rectangles is 8:7, and the vertical ratio is 9:4. If the area of the larger rectangle is 108 square centimeters (cm2), find the area of the smaller rectangle.",
        "answer_ko": "42",
        "answer_en": "42",
        "solution_abst_ko": "108 8 [OP_DIV] 7 [OP_MUL] 9 [OP_DIV] 4 [OP_MUL]",
        "solution_abst_en": "108 8 [OP_DIV] 7 [OP_MUL] 9 [OP_DIV] 4 [OP_MUL]",
        "solution_code_ko": "var_a = 108\nvar_b = 8\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c * var_d\nvar_f = 9\nvar_g = var_e / var_f\nvar_h = 4\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 108\nvar_b = 8\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c * var_d\nvar_f = 9\nvar_g = var_e / var_f\nvar_h = 4\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "6272": {
        "category": "Comparison",
        "question_ko": "미영이는 어느 학급에서 수학 점수로 앞에서 12등, 뒤에서 12등입니다. 미영이가 다니는 학교에는 총 3개의 학년이 있고, 각 학년에는 12개의 학급이 있고, 각 학급의 학생 수는 모두 같습니다. 이 학교의 학생 수는 모두 몇 명입니까?",
        "question_en": "Miyoung is ranked 12th from the front and 12th from the back in math scores of her class. Miyoung's school has a total of 3 grades, each grade has 12 classes, and each class has the same number of students. How many students are there in this school?",
        "answer_ko": "828",
        "answer_en": "828",
        "solution_abst_ko": "12 12 [OP_ADD] 1 [OP_SUB] 12 [OP_MUL] 3 [OP_MUL]",
        "solution_abst_en": "12 12 [OP_ADD] 1 [OP_SUB] 12 [OP_MUL] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 12\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 12\nvar_g = var_e * var_f\nvar_h = 3\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 12\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 12\nvar_g = var_e * var_f\nvar_h = 3\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "6273": {
        "category": "Geometry",
        "question_ko": "크기가 같은 동전을 빈틈없이 규칙적으로 늘어놓아 정사각형을 만들었습니다. 둘레에 놓인 동전의 개수가 36개였다면, 가장 바깥쪽의 한 변에 놓인 동전의 개수는 몇 개입니까?",
        "question_en": "Coins of the same size are arranged in a regular pattern without gaps to form a square. If the number of coins on the circumference was 36, how many coins were on the outermost of one side?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "36 4 [OP_DIV] 1 [OP_ADD]",
        "solution_abst_en": "36 4 [OP_DIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 36\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 36\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "6274": {
        "category": "Geometry",
        "question_ko": "도화지에 사다리꼴을 그렸습니다. 아랫변이 윗변보다 3.6센티미터(㎝) 더 짧고, 높이가 5.2센티미터(㎝)이며, 지붕의 넓이가 96.98제곱센티미터(㎠)입니다. 이 지붕의 아랫변은 몇 센티미터(㎝)입니까?",
        "question_en": "I painted a trapezoid on drawing paper. The lower side is 3.6 centimeters (cm) shorter than the upper side, the height is 5.2 centimeters (cm), and the area of the roof is 96.98 square cm (cm2). How many centimeters (cm) is the lower edge of this trapezoid?",
        "answer_ko": "16.85",
        "answer_en": "16.85",
        "solution_abst_ko": "96.98 2 [OP_MUL] 5.2 [OP_DIV] 3.6 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "96.98 2 [OP_MUL] 5.2 [OP_DIV] 3.6 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 96.98\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 5.2\nvar_e = var_c / var_d\nvar_f = 3.6\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 96.98\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 5.2\nvar_e = var_c / var_d\nvar_f = 3.6\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "6275": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이네 집에는 감이 5개 들어있는 상자가 4개 있습니다. 정국이네 집에 있는 감은 모두 몇 개인가요?",
        "question_en": "There are 4 boxes of 5 persimmons in Jungkook's house. How many persimmons are there in Jungkook's house?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "5 4 [OP_MUL]",
        "solution_abst_en": "5 4 [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "6276": {
        "category": "Arithmetic calculation",
        "question_ko": "남준이는 색종이 250장을 가지고 있었습니다. 남준이가 유나에게 색종이 60장을 주었더니 남준이가 유나보다 20장 더 적게 되었습니다. 유나가 처음에 가지고 있던 색종이는 몇 장입니까?",
        "question_en": "Namjoon had 250 pieces of colored paper. Namjoon gave Yuna 60 pieces of colored paper, resulting Namjoon had 20 fewer than Yuna. How many pieces of colored paper did Yuna have at first?",
        "answer_ko": "150",
        "answer_en": "150",
        "solution_abst_ko": "250 60 [OP_SUB] 60 [OP_SUB] 20 [OP_ADD]",
        "solution_abst_en": "250 60 [OP_SUB] 60 [OP_SUB] 20 [OP_ADD]",
        "solution_code_ko": "var_a = 250\nvar_b = 60\nvar_c = var_a - var_b\nvar_d = 60\nvar_e = var_c - var_d\nvar_f = 20\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 250\nvar_b = 60\nvar_c = var_a - var_b\nvar_d = 60\nvar_e = var_c - var_d\nvar_f = 20\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "6277": {
        "category": "Correspondence",
        "question_ko": "시우는 가진 과자의 3/10을 친구에게 나누어 주었고 남은 과자는 12개입니다. 시우가 처음 가지고 있었던 과자의 1/5는 얼마인지 구하시오.",
        "question_en": "Siwoo gave 3/10 of the cookies he had to his friend, and there are 12 cookies left. Find how much is 1/5 of the cookies Siwoo had at the beginning.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "12 3/10 [OP_DIV] 1/5 [OP_MUL]",
        "solution_abst_en": "12 3/10 [OP_DIV] 1/5 [OP_MUL]",
        "solution_code_ko": "var_a = 12\nvar_b = 0.3\nvar_c = var_a / var_b\nvar_d = 0.2\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 0.3\nvar_c = var_a / var_b\nvar_d = 0.2\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "6278": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 100까지의 자연수 중 2의 배수이면서 3의 배수인 수들의 합을 구하시오.",
        "question_en": "Find the sum of all natural numbers from 1 to 100 that are multiples of 2 and are also multiples of 3.",
        "answer_ko": "816",
        "answer_en": "816",
        "solution_abst_ko": "1 100 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] [OP_LIST_SUM]",
        "solution_abst_en": "1 100 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 3\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nlist_c = [float(i) for i in list_c]\nvar_f = sum(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 3\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nlist_c = [float(i) for i in list_c]\nvar_f = sum(list_c)\nprint(int(var_f))"
    },
    "6279": {
        "category": "Comparison",
        "question_ko": "아침에 지민이는 줄넘기를 20번, 은지는 18번 했다. 저녁에 지민이가 줄넘기를 14번 했다면 은지가 지민이보다 줄넘기를 더 많이 하려면 최소 몇 번 해야하는가?",
        "question_en": "In the morning, Jimin jumped rope 20 times and Eunji 18 times. If Jimin jumped rope 14 times in the evening, how many times should Eunji jump rope at least to do more than Jimin?",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "20 14 [OP_ADD] 18 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "20 14 [OP_ADD] 18 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 20\nvar_b = 14\nvar_c = var_a + var_b\nvar_d = 18\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 20\nvar_b = 14\nvar_c = var_a + var_b\nvar_d = 18\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "6280": {
        "category": "Geometry",
        "question_ko": "한 모서리의 길이가 6센티미터(㎝)인 정육면체 3개를 붙여 하나의 직육면체로 만들었습니다. 이 직육면체의 부피는 몇 세제곱센티미터입니까?",
        "question_en": "Three cubes with a corner length of 6 centimeters (cm) are attached to form a single cuboid. What is the volume of this cuboid in cubic centimeters (cm3)?",
        "answer_ko": "648",
        "answer_en": "648",
        "solution_abst_ko": "6 3 [OP_POW] 3 [OP_MUL]",
        "solution_abst_en": "6 3 [OP_POW] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 6\nvar_b = 3\nvar_c = var_a ** var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 3\nvar_c = var_a ** var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "6281": {
        "category": "Possibility",
        "question_ko": "0, 3, 4, 8, 9를 한 번씩만 사용하여 만들 수 있는 다섯 자리 수 중에서 가장 큰 수를 쓰시오.",
        "question_en": "Write the largest five-digit number that can be formed by using 0, 3, 4, 8, and 9 only once.",
        "answer_ko": "98430",
        "answer_en": "98430",
        "solution_abst_ko": "[OP_LIST_SOL] 0 3 4 8 9 [OP_LIST_EOL] 5 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 0 3 4 8 9 [OP_LIST_EOL] 5 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 0\nvar_b = 3\nvar_c = 4\nvar_d = 8\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 5\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nprint(int(var_h))",
        "solution_code_en": "var_a = 0\nvar_b = 3\nvar_c = 4\nvar_d = 8\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 5\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nprint(int(var_h))"
    },
    "6282": {
        "category": "Correspondence",
        "question_ko": "5를 어떤 수에 곱했더니 결과가 100이 되었습니다. 어떤 수를 10으로 나눈 값은?",
        "question_en": "When you multiply a number by 5, the result is 100. What number is divided by 10?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "100 5 [OP_DIV] 10 [OP_DIV]",
        "solution_abst_en": "100 5 [OP_DIV] 10 [OP_DIV]",
        "solution_code_ko": "var_a = 100\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 10\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 100\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 10\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "6283": {
        "category": "Possibility",
        "question_ko": "1g, 2g, 4g, 8g 저울추를 가지고 만들 수 있는 서로 다른 무게는 몇 가지입니까?",
        "question_en": "How many different weights can you make with 1g (g), 2g (g), 4g (g), and 8g (g) weights?",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "2 4 [OP_POW]",
        "solution_abst_en": "2 4 [OP_POW]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = var_a ** var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = var_a ** var_b\nprint(int(var_c))"
    },
    "6284": {
        "category": "Correspondence",
        "question_ko": "성준이가 잡은 물고기는 지운이가 잡은 물고기보다 21.52센티미터(㎝)가 더 크고 지운이가 잡은 물고기는 성우가 잡은 물고기 보다 12.64센티미터(㎝)가 더 작다. 성준이가 잡은 물고기와 성우가 잡은 물고기의 크기 차이는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "The fish Seongjun caught was 21.52 centimeters (cm) larger than the fish Jiwoon caught, and the fish Jiwoon caught was 12.64 centimeters (cm) smaller than the fish Sungwoo caught. Find the size difference in centimeters (cm) between the Seongjun's fish and the Sungwoo's fish.",
        "answer_ko": "8.88",
        "answer_en": "8.88",
        "solution_abst_ko": "21.52 12.64 [OP_SUB]",
        "solution_abst_en": "21.52 12.64 [OP_SUB]",
        "solution_code_ko": "var_a = 21.52\nvar_b = 12.64\nvar_c = var_a - var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 21.52\nvar_b = 12.64\nvar_c = var_a - var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "6285": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 2.3미터(m)인 정팔각형의 모든 변의 길이의 합은 몇 센티미터(㎝)입니까?",
        "question_en": "How many centimeters (cm) is the sum of all the side lengths of a regular octagon with a side length of 2.3 meters (m)?",
        "answer_ko": "1840",
        "answer_en": "1840",
        "solution_abst_ko": "2.3 8 [OP_MUL] 100 [OP_MUL]",
        "solution_abst_en": "2.3 8 [OP_MUL] 100 [OP_MUL]",
        "solution_code_ko": "var_a = 2.3\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = var_c * var_d\nprint(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))",
        "solution_code_en": "var_a = 2.3\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = var_c * var_d\nprint(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))"
    },
    "6286": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 36을 빼야 할 것을 잘못하여 63을 더한 결과는 8이 되었습니다. 바르게 계산한 결과는 얼마인가요?",
        "question_en": "You added 63 to a number by mistake when you should have subtracted 36, and the result was 8. What is the correct result?",
        "answer_ko": "91",
        "answer_en": "91",
        "solution_abst_ko": "8 63 [OP_SUB] 36 [OP_SUB]",
        "solution_abst_en": "8 63 [OP_SUB] 36 [OP_SUB]",
        "solution_code_ko": "var_a = 8\nvar_b = 63\nvar_c = var_a - var_b\nvar_d = 36\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 63\nvar_c = var_a - var_b\nvar_d = 36\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "6287": {
        "category": "Arithmetic calculation",
        "question_ko": "경훈이가 등산을 하는데 올라갈 때는 시속 3 킬로미터(㎞)로 걷고, 내려올 때는 올라갈 때보다 2 킬로미터(㎞) 더 먼 길을 택하여 시속 4 킬로미터(㎞)로 걸어서 총 4시간이 걸렸다고 한다. 경훈이가 내려가는 데 걸린 시간은?",
        "question_en": "Kyunghoon walked at 3 kilometers (km) per hour on the way up to the mountain and then took a 2 kilometer (km) longer route down than the one he took up, walking at 4 km per hour for a total of 4 hours. How long did it take Kyunghoon to go down?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "4 2 4 [OP_DIV] [OP_SUB] 1 3 [OP_DIV] 1 4 [OP_DIV] [OP_ADD] [OP_DIV] 2 [OP_ADD] 4 [OP_DIV]",
        "solution_abst_en": "4 2 4 [OP_DIV] [OP_SUB] 1 3 [OP_DIV] 1 4 [OP_DIV] [OP_ADD] [OP_DIV] 2 [OP_ADD] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = 3\nvar_h = var_f / var_g\nvar_i = 1\nvar_j = 4\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_e / var_l\nvar_n = 2\nvar_o = var_m + var_n\nvar_p = 4\nvar_q = var_o / var_p\nprint(int(var_q))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = 3\nvar_h = var_f / var_g\nvar_i = 1\nvar_j = 4\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_e / var_l\nvar_n = 2\nvar_o = var_m + var_n\nvar_p = 4\nvar_q = var_o / var_p\nprint(int(var_q))"
    },
    "6288": {
        "category": "Correspondence",
        "question_ko": "한 자리 수 A, B가 있을 때 다섯 자리 수 A375B는 24로 나누어 떨어집니다. A가 될 수 있는 숫자의 개수를 구하시오.",
        "question_en": "Given single-digit numbers A and B, the five-digit number A375B is divisible by 24. Find the number of digits that can be A.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "A375B [OP_GEN_POSSIBLE_LIST] 24 [OP_LIST_DIVISIBLE] A375B A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_abst_en": "A375B [OP_GEN_POSSIBLE_LIST] 24 [OP_LIST_DIVISIBLE] A375B A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 'A375B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 24\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 'A375B'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nvar_e = len(list_c)\nprint(int(var_e))",
        "solution_code_en": "var_a = 'A375B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 24\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 'A375B'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nvar_e = len(list_c)\nprint(int(var_e))"
    },
    "6289": {
        "category": "Arithmetic calculation",
        "question_ko": "서로 다른 세 수가 있습니다. 서로 다른 두 수끼리의 평균이 각각 26.5 , 34.5 , 29 일 때, 세 수의 평균을 구하시오",
        "question_en": "There are three different numbers. If the averages of two different numbers are 26.5, 34.5, and 29, find the average of the three numbers.",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "26.5 34.5 [OP_ADD] 29 [OP_ADD] 3 [OP_DIV]",
        "solution_abst_en": "26.5 34.5 [OP_ADD] 29 [OP_ADD] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 26.5\nvar_b = 34.5\nvar_c = var_a + var_b\nvar_d = 29\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 26.5\nvar_b = 34.5\nvar_c = var_a + var_b\nvar_d = 29\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "6290": {
        "category": "Correspondence",
        "question_ko": "2804를 어떤 수로 나누면 10이 나온다. 어떤 수에 1/100을 곱하면 얼마인지 구하시오.",
        "question_en": "Divide 2804 by a number to get 10. What is the number multiplied by 1/100?",
        "answer_ko": "2.80",
        "answer_en": "2.8",
        "solution_abst_ko": "2804 10 [OP_DIV] 1/100 [OP_MUL]",
        "solution_abst_en": "2804 10 [OP_DIV] 1/100 [OP_MUL]",
        "solution_code_ko": "var_a = 2804\nvar_b = 10\nvar_c = var_a / var_b\nvar_d = 0.01\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 2804\nvar_b = 10\nvar_c = var_a / var_b\nvar_d = 0.01\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "6291": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이는 빨간 공 3개, 윤기는 파란 공 2개를 가지고 있습니다. 정국이가 빨간 공 1개를 윤기에게 주었을 때, 정국이가 가지고 있는 파란 공의 개수는?",
        "question_en": "Jungkook has 3 red balls and Yoonki has 2 blue balls. If Jungkook gives 1 red ball to Yoonki, how many blue balls does Jungkook have?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "2",
        "solution_abst_en": "2",
        "solution_code_ko": "var_a = 2\nprint(int(var_a))",
        "solution_code_en": "var_a = 2\nprint(int(var_a))"
    },
    "6292": {
        "category": "Comparison",
        "question_ko": "3개의 숫자 0.8, 1/2, 0.9가 있습니다. 0.7보다 큰 수의 합은 얼마인가요?",
        "question_en": "There are three numbers 0.8, 1/2, and 0.9. What is the sum of the numbers greater than 0.7?",
        "answer_ko": "1.70",
        "answer_en": "1.7",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 0.7 [OP_LIST_MORE] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 0.7 [OP_LIST_MORE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.7\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.7\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "6293": {
        "category": "Arithmetic calculation",
        "question_ko": "지원이는 한 번에 90걸음씩 13번을 걸었습니다. 지원이가 한 걸음에 0.45미터(m) 움직일 수 있다면 지원이는 모두 몇 미터(m)를 걸었나요?",
        "question_en": "Jiwon took 13 times of 90 steps at a time. If Jiwon can move 0.45 meters (m) per step, how long did she walk in meters (m)?",
        "answer_ko": "526.50",
        "answer_en": "526.5",
        "solution_abst_ko": "0.45 90 [OP_MUL] 13 [OP_MUL]",
        "solution_abst_en": "0.45 90 [OP_MUL] 13 [OP_MUL]",
        "solution_code_ko": "var_a = 0.45\nvar_b = 90\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.45\nvar_b = 90\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "6294": {
        "category": "Geometry",
        "question_ko": "한변의 길이가 자연수인 정사각형의 둘레의 길이가 35센티미터(㎝)를 넘지 않아야 한다. 정사각형의 둘레가 35센티미터(㎝)와 얼마나 차이가 나는지 구하시오.",
        "question_en": "The perimeter of a square whose side length is a natural number shall not exceed 35 centimeters (cm). Calculate the difference between the perimeter of the square and 35 centimeters (cm).",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "35 4 [OP_MOD]",
        "solution_abst_en": "35 4 [OP_MOD]",
        "solution_code_ko": "var_a = 35\nvar_b = 4\nvar_c = var_a % var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 35\nvar_b = 4\nvar_c = var_a % var_b\nprint(int(var_c))"
    },
    "6295": {
        "category": "Arithmetic calculation",
        "question_ko": "작년에 윤기는 6살이었고 할아버지는 62살이었습니다. 올해 할아버지의 나이는 윤기 나이의 몇 배입니까?",
        "question_en": "Last year, Yoongi was 6 years old and his grandfather was 62 years old. How many times is his grandfather as old as Yoongi this year?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "62 1 [OP_ADD] 6 1 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "62 1 [OP_ADD] 6 1 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 62\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 6\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = var_c / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 62\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 6\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = var_c / var_f\nprint(int(var_g))"
    },
    "6296": {
        "category": "Comparison",
        "question_ko": "동균, 영탁, 승환이가 과자를 갖고 있다. 동균이가 영탁보다 많이 갖고있고 승환이가 동균보다 많다면 누가 쿠키를 가장 많이 가지고 있을까요?",
        "question_en": "Dongkyun, Youngtak, and Seunghwan have snacks. If Dongkyun has more than Youngtak and Seunghwan has more than Dongkyun, who has the most cookies?",
        "answer_ko": "승환",
        "answer_en": "Seunghwan",
        "solution_abst_ko": "[OP_LIST_SOL] 동균 영탁 승환 [OP_LIST_EOL] [OP_LIST_SOL] 동균 영탁 > 승환 동균 > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Dongkyun Youngtak Seunghwan [OP_LIST_EOL] [OP_LIST_SOL] Dongkyun Youngtak > Seunghwan Dongkyun > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '동균'\nvar_b = '영탁'\nvar_c = '승환'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '동균'\nvar_e = '영탁'\nvar_f = '>'\nvar_g = '승환'\nvar_h = '동균'\nvar_i = '>'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(var_k)",
        "solution_code_en": "var_a = 'Dongkyun'\nvar_b = 'Youngtak'\nvar_c = 'Seunghwan'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'Dongkyun'\nvar_e = 'Youngtak'\nvar_f = '>'\nvar_g = 'Seunghwan'\nvar_h = 'Dongkyun'\nvar_i = '>'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(var_k)"
    },
    "6297": {
        "category": "Geometry",
        "question_ko": "직육면체의 부피가 36.48세제곱센티미터(㎤)이고 밑면의 넓이가 6.0제곱센티미터(㎠)라면 높이는 얼마인지 구하시오.",
        "question_en": "If the volume of the cuboid is 36.48 cubic centimeters (cm3) and the area of the base is 6.0 square centimeters (cm2), what is the height?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "36.48 6.08 [OP_DIV]",
        "solution_abst_en": "36.48 6.08 [OP_DIV]",
        "solution_code_ko": "var_a = 36.48\nvar_b = 6.08\nvar_c = var_a / var_b\nprint(int(eval('{:.2f}'.format(round(var_c+1e-10,2)))))",
        "solution_code_en": "var_a = 36.48\nvar_b = 6.08\nvar_c = var_a / var_b\nprint(int(eval('{:.2f}'.format(round(var_c+1e-10,2)))))"
    },
    "6298": {
        "category": "Correspondence",
        "question_ko": "13+AB=58입니다. A는 얼마인가요?",
        "question_en": "13+AB=58 is true. How much is A?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "13+AB=58 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "13+AB=58 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '13+AB=58'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '13+AB=58'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "6299": {
        "category": "Correspondence",
        "question_ko": "AB-21=14입니다. B는 얼마인가요?",
        "question_en": "AB-21=14. How much is B, where AB is twe-digit number?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "AB-21=14 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "AB-21=14 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'AB-21=14'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'AB-21=14'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "6300": {
        "category": "Possibility",
        "question_ko": "다윤이는 2596의 각 숫자의 위치를 바꾸어 네 자리 수를 만드려고 한다. 처음의 숫자를 포함하여 모두 몇 개를 만들 수 있는가?",
        "question_en": "Dayoon is trying to make a four-digit number by rearranging the position of each digit in 2596. Including the initial number, how many numbers can he make?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "2596 [OP_NUM2LIST] 4 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "2596 [OP_NUM2LIST] 4 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 2596\nlist_a = []\nvar_a = int(var_a)\nwhile var_a//10 > 0:\n    list_a.append(var_a%10)\n    var_a = var_a//10\nlist_a.append(var_a%10)\nlist_a = list_a[::-1]\nvar_b = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_b))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_c = len(list_b)\nprint(int(var_c))",
        "solution_code_en": "var_a = 2596\nlist_a = []\nvar_a = int(var_a)\nwhile var_a//10 > 0:\n    list_a.append(var_a%10)\n    var_a = var_a//10\nlist_a.append(var_a%10)\nlist_a = list_a[::-1]\nvar_b = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_b))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_c = len(list_b)\nprint(int(var_c))"
    },
    "6301": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 16미터(m)인 테이프로 (가) 물건을 포장했습니다. (가) 물건 1개를 포장하는데 5미터(m)를 사용했다면, (가) 물건 2개를 포장하고 남은 테이프는 몇 미터(m)입니까?",
        "question_en": "An item was wrapped with tape measuring 16 meters (m) in length. If 5 meters (m) were used to wrap the 1 item, how many meters (m) of tape are left after wrapping 2 items?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "16 5 2 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "16 5 2 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 16\nvar_b = 5\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 16\nvar_b = 5\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "6302": {
        "category": "Arithmetic calculation",
        "question_ko": "사과 1개를 먹으려면 30원이 필요합니다. 사과 25개를 먹는다면 얼마가 필요하나요?",
        "question_en": "It costs 30 won to eat an apple. If you eat 25 apples, how much do you need?",
        "answer_ko": "750",
        "answer_en": "750",
        "solution_abst_ko": "30 25 [OP_MUL]",
        "solution_abst_en": "30 25 [OP_MUL]",
        "solution_code_ko": "var_a = 30\nvar_b = 25\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 30\nvar_b = 25\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "6303": {
        "category": "Possibility",
        "question_ko": "사과 10개를 4명의 학생에게 나누어 주려고 한다. 학생당 최소 1개의 사과는 준다고 할 때, 가능한 경우의 수를 구하시오.",
        "question_en": "You want to distribute 10 apples among 4 students. Given that at least one apple is given to each student, find the number of possible cases.",
        "answer_ko": "84",
        "answer_en": "84",
        "solution_abst_ko": "1 9 1 [OP_LIST_ARANGE] 4 [OP_LIST_GET_PRODUCT] [OP_LIST_NUM2SUM] 10 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 9 1 [OP_LIST_ARANGE] 4 [OP_LIST_GET_PRODUCT] [OP_LIST_NUM2SUM] 10 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 10\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 10\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))"
    },
    "6304": {
        "category": "Correspondence",
        "question_ko": "57A-B14=364가 성립하기 위한 B를 구하시오.",
        "question_en": "Find B to satisfy 57A-B14=364.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "57A-B14=364 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "57A-B14=364 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '57A-B14=364'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '57A-B14=364'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "6305": {
        "category": "Arithmetic calculation",
        "question_ko": "지민이는 12개의 귤을 가지고 있었습니다. 그중에서 7개를 먹었습니다. 지민이에게 남은 귤은 몇 개입니까?",
        "question_en": "Jimin had 12 tangerines. 7 of them were eaten. How many tangerines are left to Jimin?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "12 7 [OP_SUB]",
        "solution_abst_en": "12 7 [OP_SUB]",
        "solution_code_ko": "var_a = 12\nvar_b = 7\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 12\nvar_b = 7\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "6306": {
        "category": "Geometry",
        "question_ko": "직육면체의 겉넓이가 442제곱센티미터(㎠) 입니다. 가로의 길이가 7센티미터(㎝), 세로의 길이가 8센티미터(㎝)이라면 높이는 몇 센티미터(㎝)입니까?",
        "question_en": "The surface area of a rectangular cuboid is 442 square centimeters (cm2). If the width is 7 centimeters (cm) and the length is 8 centimeters (cm), how many centimeters (cm) is the height?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "442 2 [OP_DIV] 7 8 [OP_MUL] [OP_SUB] 7 8 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "442 2 [OP_DIV] 7 8 [OP_MUL] [OP_SUB] 7 8 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 442\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = 8\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 7\nvar_i = 8\nvar_j = var_h + var_i\nvar_k = var_g / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 442\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = 8\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 7\nvar_i = 8\nvar_j = var_h + var_i\nvar_k = var_g / var_j\nprint(int(var_k))"
    },
    "6307": {
        "category": "Arithmetic calculation",
        "question_ko": "동생의 키는 1.1미터(m)이며, 나는 동생보다 0.2미터(m) 크고, 형은 나보다 1/10미터(m) 큽니다. 형의 키는 몇 미터(m)입니까?",
        "question_en": "Your younger brother is 1.1 meters (m) taller, you are 0.2 meters (m) taller than your younger brother, and your older brother is 1/10 meter (m) taller than you. How tall is your brother in meters (m)?",
        "answer_ko": "1.40",
        "answer_en": "1.4",
        "solution_abst_ko": "0.2 1.1 [OP_ADD] 1/10 [OP_ADD]",
        "solution_abst_en": "0.2 1.1 [OP_ADD] 1/10 [OP_ADD]",
        "solution_code_ko": "var_a = 0.2\nvar_b = 1.1\nvar_c = var_a + var_b\nvar_d = 0.1\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.2\nvar_b = 1.1\nvar_c = var_a + var_b\nvar_d = 0.1\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "6308": {
        "category": "Possibility",
        "question_ko": "세 장의 숫자 카드로 만든 수 중 세 번째로 작은 수와 두 번째로 작은 수의 차를 구하고 싶다. 1, 6, 8이 적힌 카드가 있을 때, 구하고 싶은 답은 얼마인가?",
        "question_en": "You want to find the difference between the third smallest and the second smallest number of three number cards. If you have cards with 1, 6, and 8 written on them, what is the difference?",
        "answer_ko": "432",
        "answer_en": "432",
        "solution_abst_ko": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 3 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 3 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = 2\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = 2\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))"
    },
    "6309": {
        "category": "Geometry",
        "question_ko": "밑면의 두 변 길이가 각각 44센티미터(㎝), 35센티미터(㎝)인 직육면체 모양의 수조에 장난감 기차를 완전히 잠기도록 넣었더니 물의 높이가 7센티미터(㎝) 늘어났고, 거기에 장난감 자동차를 완전히 잠기게 넣었더니 물의 높이가 3센티미터(㎝) 늘어났습니다. 장난감 기차와 자동차의 부피의 합은 몇 세제곱센티미터(㎤) 인지 구하시오.",
        "question_en": "When the toy train was completely submerged in a cuboid-shaped water tank whose two sides of the bottom is 44 centimeters (cm) and 35 centimeters (cm), respectively, the height of the water increased by 7 centimeters (cm). And then the toy car was completely submerged, which increased the height of the water by 3 centimeters (cm). Find the sum of the volumes of the toy train and the car in cubic centimeters (cm3).",
        "answer_ko": "15400",
        "answer_en": "15400",
        "solution_abst_ko": "44 35 [OP_MUL] 7 3 [OP_ADD] [OP_MUL]",
        "solution_abst_en": "44 35 [OP_MUL] 7 3 [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 44\nvar_b = 35\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 44\nvar_b = 35\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "6310": {
        "category": "Correspondence",
        "question_ko": "66은 어떤 수에 3을 곱하고 49를 더해야 하는데 실수로 3을 빼고 49를 더한 결과입니다. 틀리게 계산한 값과 바르게 계산한 값의 차를 구하시오.",
        "question_en": "66 is the result of mistakenly subtracting 3 and adding 49 when should have multiplifed the number by 3 and adding 49. Find the difference between the incorrectly calculated value and the correct calculated value.",
        "answer_ko": "43",
        "answer_en": "43",
        "solution_abst_ko": "66 49 [OP_SUB] 3 [OP_ADD] 3 [OP_MUL] 49 [OP_ADD] 66 [OP_SUB]",
        "solution_abst_en": "66 49 [OP_SUB] 3 [OP_ADD] 3 [OP_MUL] 49 [OP_ADD] 66 [OP_SUB]",
        "solution_code_ko": "var_a = 66\nvar_b = 49\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e * var_f\nvar_h = 49\nvar_i = var_g + var_h\nvar_j = 66\nvar_k = var_i - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 66\nvar_b = 49\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e * var_f\nvar_h = 49\nvar_i = var_g + var_h\nvar_j = 66\nvar_k = var_i - var_j\nprint(int(var_k))"
    },
    "6311": {
        "category": "Possibility",
        "question_ko": "1, 3, 5, 8의 4장의 숫자 카드를 중복을 사용하여 세 자리 수를 만들 때 가장 큰 세 자리 수와 가장 작은 세 자리 수의 곱을 구하시오.",
        "question_en": "Find the product of the largest three-digit number and the smallest three-digit number when numbers can be formed of 4 number cards 1, 3, 5, and 8 allowing the duplicates.",
        "answer_ko": "98568",
        "answer_en": "98568",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 5 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 5 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MUL]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 5\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g * var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 5\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g * var_i\nprint(int(var_j))"
    },
    "6312": {
        "category": "Comparison",
        "question_ko": "지민, 태형, 호석이는 각각 똑같은 사탕을 1봉지씩 사서 먹었습니다. 지민이는 전체의 1/9을, 태형이는 전체의 1/3을, 호석이는 전체의 1/6을 먹었습니다. 사탕이 가장 많이 남아 있는 사람은 누구입니까?",
        "question_en": "Jimin, Taehyung, and Hoseok each bought and ate a bag of the same candy. Jimin ate 1/9 of the total, Taehyung ate 1/3 of the total, and Hoseok ate 1/6 of the total. Who has the most candy left?",
        "answer_ko": "지민",
        "answer_en": "Jimin",
        "solution_abst_ko": "[OP_LIST_SOL] 지민 태형 호석 [OP_LIST_EOL] [OP_LIST_SOL] 1/9 1/3 1/6 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jimin Taehyung Hoseok [OP_LIST_EOL] [OP_LIST_SOL] 1/9 1/3 1/6 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '지민'\nvar_b = '태형'\nvar_c = '호석'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.1111111111111111\nvar_e = 0.3333333333333333\nvar_f = 0.16666666666666666\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Jimin'\nvar_b = 'Taehyung'\nvar_c = 'Hoseok'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.1111111111111111\nvar_e = 0.3333333333333333\nvar_f = 0.16666666666666666\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "6313": {
        "category": "Possibility",
        "question_ko": "4개의 숫자 1, 4, 5, 9를 한 번씩 사용하여 십의 자리 숫자가 9인 두 번째 큰 세 자리수 를 만들어 보시오.",
        "question_en": "Using the four digits 1, 4, 5, and 9 once, find the second large three-digit number with 9 in the tens place.",
        "answer_ko": "591",
        "answer_en": "591",
        "solution_abst_ko": "[OP_LIST_SOL] 1 4 5 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 9 [OP_LIST_SEARCH_FIXED_DIGIT] 2 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1 4 5 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 9 [OP_LIST_SEARCH_FIXED_DIGIT] 2 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1\nvar_b = 4\nvar_c = 5\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 9\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 2\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 4\nvar_c = 5\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 9\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 2\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nprint(int(var_i))"
    },
    "6314": {
        "category": "Geometry",
        "question_ko": "가로의 길이가 5미터(m)이고, 세로의 길이가 17/20미터(m)인 직사각형 모양의 담벼락의 넓이를 구하시오.",
        "question_en": "Find the area of a rectangular wall whose sides are 5 meters (m) long and 17/20 meters (m) wide.",
        "answer_ko": "4.25",
        "answer_en": "4.25",
        "solution_abst_ko": "5 17/20 [OP_MUL]",
        "solution_abst_en": "5 17/20 [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 0.85\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 5\nvar_b = 0.85\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "6315": {
        "category": "Arithmetic calculation",
        "question_ko": "공책이 28권 있습니다. 연주에게 28권의 1/4만큼을 주었고, 민지에게 28권의 3/7만큼을 주었습니다. 남은 공책은 몇 권인지 구해 보시오.",
        "question_en": "There are 28 notebooks. I gave 1/4 of the 28 books to Yeonju, and 3/7 of the 28 books to Minji. Find how many notebooks are left.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "28 1 1/4 [OP_SUB] 3/7 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "28 1 1/4 [OP_SUB] 3/7 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 28\nvar_b = 1\nvar_c = 0.25\nvar_d = var_b - var_c\nvar_e = 0.42857142857142855\nvar_f = var_d - var_e\nvar_g = var_a * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 28\nvar_b = 1\nvar_c = 0.25\nvar_d = var_b - var_c\nvar_e = 0.42857142857142855\nvar_f = var_d - var_e\nvar_g = var_a * var_f\nprint(int(var_g))"
    },
    "6316": {
        "category": "Geometry",
        "question_ko": "사람들이 한 줄에 5명씩 5줄로 서 있다. 둘레에 서 있는 사람들의 수는 몇 명입니까?",
        "question_en": "People are standing in 5 rows of 5 people. How many people are standing on the circumference?",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "5 4 [OP_MUL] 4 [OP_SUB]",
        "solution_abst_en": "5 4 [OP_MUL] 4 [OP_SUB]",
        "solution_code_ko": "var_a = 5\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "6317": {
        "category": "Comparison",
        "question_ko": "정국이네 반 학생은 모두 28명이고 각각의 키가 다릅니다. 이 학생들을 키가 큰 학생부터 순서대로 줄을 세우면 정국이는 앞에서 14번째에 서고 은지는 앞에서 20번째에 섭니다. 정국이와 은지 사이에 서 있는 학생은 몇 명입니까?",
        "question_en": "There are 28 students in Jungkook's class, and each is a different height. If you line up these students in order of height, Jungkook will be 14th from the front and Eunji will be 20th from the front. How many students are standing between Jungkook and Eunji?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "20 14 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "20 14 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 14\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 14\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "6318": {
        "category": "Possibility",
        "question_ko": "2, 3, 5, 7 중에서 서로 다른 숫자 3개를 뽑아 세 자리 수를 만들 때, 3과 5로 나누어떨어지는 모든 수의 합을 구하시오.",
        "question_en": "Find the sum of all numbers that are divisible by 3 and 5 when choosing three different numbers from 2, 3, 5, and 7 to make a three-digit number.",
        "answer_ko": "1110",
        "answer_en": "1110",
        "solution_abst_ko": "[OP_LIST_SOL] 2 5 3 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 2 5 3 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 2\nvar_b = 5\nvar_c = 3\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c = []\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nvar_g = 5\nlist_d = []\nvar_g = int(var_g)\nfor i in list_c:\n    i = int(i)\n    if i % var_g == 0:\n        list_d.append(i)\nlist_d = [float(i) for i in list_d]\nvar_h = sum(list_d)\nprint(int(var_h))",
        "solution_code_en": "var_a = 2\nvar_b = 5\nvar_c = 3\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c = []\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nvar_g = 5\nlist_d = []\nvar_g = int(var_g)\nfor i in list_c:\n    i = int(i)\n    if i % var_g == 0:\n        list_d.append(i)\nlist_d = [float(i) for i in list_d]\nvar_h = sum(list_d)\nprint(int(var_h))"
    },
    "6319": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 아파트 단지에는 1동부터 22동까지 있고, 각 동마다 6층까지 있습니다. 각 층마다 5가구씩 있다면, 이 아파트 단지에는 모두 몇 가구가 살 수 있습니까?",
        "question_en": "Some apartment complex has 1 to 22 apartment buildings, each with up to 6 floors. If there are 5 apartments on each floor, how many apartments can live in this apartment complex?",
        "answer_ko": "660",
        "answer_en": "660",
        "solution_abst_ko": "22 6 [OP_MUL] 5 [OP_MUL]",
        "solution_abst_en": "22 6 [OP_MUL] 5 [OP_MUL]",
        "solution_code_ko": "var_a = 22\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 22\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "6320": {
        "category": "Correspondence",
        "question_ko": "55는 어떤 수에서 45를 더하고 62를 뺀 수이다. 어떤 수에 7을 곱하면 얼마가 되는가?",
        "question_en": "55 is a number obtained by adding 45 to some number and subtracting 62 from it. What is the result when 7 is multiplied by this number?",
        "answer_ko": "504",
        "answer_en": "504",
        "solution_abst_ko": "55 45 [OP_SUB] 62 [OP_ADD] 7 [OP_MUL]",
        "solution_abst_en": "55 45 [OP_SUB] 62 [OP_ADD] 7 [OP_MUL]",
        "solution_code_ko": "var_a = 55\nvar_b = 45\nvar_c = var_a - var_b\nvar_d = 62\nvar_e = var_c + var_d\nvar_f = 7\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 55\nvar_b = 45\nvar_c = var_a - var_b\nvar_d = 62\nvar_e = var_c + var_d\nvar_f = 7\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "6321": {
        "category": "Comparison",
        "question_ko": "학생들이 한 줄로 서 있습니다. 유정이는 맨 뒤에 서 있습니다. 유정이 앞에 8명이 서 있을 때, 줄을 서 있는 학생은 모두 몇 명입니까?",
        "question_en": "Students are standing in a line. Yoojeong is standing at the very back. When 8 people are standing in front of Yoojeong, how many students are standing in the line?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "8 1 [OP_ADD]",
        "solution_abst_en": "8 1 [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 8\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "6322": {
        "category": "Arithmetic calculation",
        "question_ko": "6미터(m)간격으로 길이가 156미터(m)인 도로 한쪽에 나무를 심으려고 합니다. 처음과 끝에도 나무를 심는다고 할 때 필요한 나무는 모두 몇 그루입니까?",
        "question_en": "You want to plant trees on one side of a road that is 156 meters (m) long at 6 meters (m) intervals. How many trees will you need if you plant trees at the beginning and at the end?",
        "answer_ko": "27",
        "answer_en": "27",
        "solution_abst_ko": "156 6 [OP_DIV] 1 [OP_ADD]",
        "solution_abst_en": "156 6 [OP_DIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 156\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 156\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "6323": {
        "category": "Arithmetic calculation",
        "question_ko": "카네이션 200송이를 25묶음으로 똑같이 나누어 팔려고 합니다. 카네이션 1송이에 500원이라면 한 묶음은 얼마입니까?",
        "question_en": "I am going to sell 200 carnations parceling into 25 bundles. If 1 carnation is 500 won, how much is a bundle?",
        "answer_ko": "4000",
        "answer_en": "4000",
        "solution_abst_ko": "200 25 [OP_DIV] 500 [OP_MUL]",
        "solution_abst_en": "200 25 [OP_DIV] 500 [OP_MUL]",
        "solution_code_ko": "var_a = 200\nvar_b = 25\nvar_c = var_a / var_b\nvar_d = 500\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 200\nvar_b = 25\nvar_c = var_a / var_b\nvar_d = 500\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "6324": {
        "category": "Geometry",
        "question_ko": "가로, 세로, 높이가 각각 350센티미터(㎝), 260센티미터(㎝), 165센티미터(㎝)이고, 직육면체 모양의 기름 탱크에 휘발유를 가득 채웠습니다. 휘발유가 1리터(L)에 1600원이라면 기름 탱크를 가득 채우는 데 필요한 금액은 얼마입니까?",
        "question_en": "Gasoline was filled in a cuboid-shaped oil tank with dimensions of 350 centimeters (cm), 260 centimeters (cm), and 165 centimeters (cm) in width, length, and height, respectively. If gasoline is 1,600 won per liter (L), how much money is needed to fill the gas tank?",
        "answer_ko": "24024000",
        "answer_en": "24024000",
        "solution_abst_ko": "350 260 [OP_MUL] 165 [OP_MUL] 1000 [OP_DIV] 1600 [OP_MUL]",
        "solution_abst_en": "350 260 [OP_MUL] 165 [OP_MUL] 1000 [OP_DIV] 1600 [OP_MUL]",
        "solution_code_ko": "var_a = 350\nvar_b = 260\nvar_c = var_a * var_b\nvar_d = 165\nvar_e = var_c * var_d\nvar_f = 1000\nvar_g = var_e / var_f\nvar_h = 1600\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 350\nvar_b = 260\nvar_c = var_a * var_b\nvar_d = 165\nvar_e = var_c * var_d\nvar_f = 1000\nvar_g = var_e / var_f\nvar_h = 1600\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "6325": {
        "category": "Possibility",
        "question_ko": "1이상 100이하의 수 중 40 이하이고, 각 자리의 수가 같지 않으며 1, 3, 7, 8로만 이루어져 있는 경우는 몇 가지인지 구하시오.",
        "question_en": "Find the number of ways where numbers from 1 to 100 are smaller than 40 and each digit is not equal to one another and consists of only 1, 3, 7, and 8?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 7 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 40 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 7 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 40 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 7\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 40\nlist_c = []\nfor i in list_b:\n    if i <= var_f:\n        list_c.append(i)\nvar_g = len(list_c)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 7\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 40\nlist_c = []\nfor i in list_b:\n    if i <= var_f:\n        list_c.append(i)\nvar_g = len(list_c)\nprint(int(var_g))"
    },
    "6326": {
        "category": "Arithmetic calculation",
        "question_ko": "유나와 할머니는 각각 12살, 72살입니다. 몇 년 후, 할머니의 나이가 유나 나이의 5배가 되었습니다. 할머니는 몇 살입니까?",
        "question_en": "Yuna and her grandmother are 12 and 72 years old, respectively. A few years later, grandmother's age is 5 times Yuna's age. How old is your grandmother at that year?",
        "answer_ko": "75",
        "answer_en": "75",
        "solution_abst_ko": "72 12 [OP_SUB] 5 [OP_MUL] 5 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "72 12 [OP_SUB] 5 [OP_MUL] 5 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 72\nvar_b = 12\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c * var_d\nvar_f = 5\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 72\nvar_b = 12\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c * var_d\nvar_f = 5\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "6327": {
        "category": "Arithmetic calculation",
        "question_ko": "380개의 구슬을 유나가, 325개의 구슬을 은지가 1시간동안 꿰었다. 8시간동안 같은 빠르기로 두 사람이 꿰었을 때, 유나는 은지보다 몇 개의 구슬을 더 꿰었는가?",
        "question_en": "Yuna threaded 380 beads and Eunji threaded 325 beads in 1 hour. How many beads did Yuna thread more than Eunji when the two of them threaded at a constant speed for 8 hours?",
        "answer_ko": "440",
        "answer_en": "440",
        "solution_abst_ko": "380 325 [OP_SUB] 8 [OP_MUL]",
        "solution_abst_en": "380 325 [OP_SUB] 8 [OP_MUL]",
        "solution_code_ko": "var_a = 380\nvar_b = 325\nvar_c = var_a - var_b\nvar_d = 8\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 380\nvar_b = 325\nvar_c = var_a - var_b\nvar_d = 8\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "6328": {
        "category": "Geometry",
        "question_ko": "사각 기둥의 면의 개수는 몇 개인지 구하시오.",
        "question_en": "Find the number of faces of a square pillar.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "4 2 [OP_ADD]",
        "solution_abst_en": "4 2 [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "6329": {
        "category": "Arithmetic calculation",
        "question_ko": "크기와 무게가 모두 같은 감이 있습니다. 감 5개의 무게는 1킬로그램(㎏)입니다. 감이 모두 3킬로그램(㎏) 있다면 감은 모두 몇 개입니까?",
        "question_en": "There are persimmons of the same size and weight. Five persimmons weigh 1 kilogram (kg). How many persimmons are there if all persimmons are 3 kg (kg)?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "5 1 [OP_MUL] 3 [OP_MUL]",
        "solution_abst_en": "5 1 [OP_MUL] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 1\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 1\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "6330": {
        "category": "Geometry",
        "question_ko": "밑면의 두 변의 길이가 각각 6미터(m) 40센티미터(㎝), 9미터(m)이고 높이가 5미터(m) 20센티미터(㎝)인 직육면체 모양의 통에 가득 들어 있는 모레를 부피가 1세제곱미터(㎥)인 통 여러 개에 모두 나누어 담으려고 합니다. 통은 적어도 몇 개 필요한지 구해보시오.",
        "question_en": "A rectangular parallelepiped barrel with the lengths of the bottom two sides measuring 6 meters (m) 40 centimeters (cm) and 9 meters (m) respectively and the height measuring 5 meters (m) 20 centimeters (cm) is filled with sand. We want to divide this sand into several barrels whose volume is one cubic meter (m3). Find at least how many barrels you need.",
        "answer_ko": "300",
        "answer_en": "300",
        "solution_abst_ko": "6 40 100 [OP_DIV] [OP_ADD] 9 [OP_MUL] 5 20 100 [OP_DIV] [OP_ADD] [OP_MUL] 1 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "6 40 100 [OP_DIV] [OP_ADD] 9 [OP_MUL] 5 20 100 [OP_DIV] [OP_ADD] [OP_MUL] 1 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 6\nvar_b = 40\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 9\nvar_g = var_e * var_f\nvar_h = 5\nvar_i = 20\nvar_j = 100\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_g * var_l\nvar_n = 1\nvar_o = var_m / var_n\nvar_p = 1\nvar_q=int(((var_o+9*10**(var_p-2))//(10**(var_p-1)))*10**(var_p-1))\n\nprint(int(var_q))",
        "solution_code_en": "var_a = 6\nvar_b = 40\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 9\nvar_g = var_e * var_f\nvar_h = 5\nvar_i = 20\nvar_j = 100\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_g * var_l\nvar_n = 1\nvar_o = var_m / var_n\nvar_p = 1\nvar_q=int(((var_o+9*10**(var_p-2))//(10**(var_p-1)))*10**(var_p-1))\n\nprint(int(var_q))"
    },
    "6331": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 2배 한 것에 3을 빼면 7이다. 어떤 수를 구하시오",
        "question_en": "A number multiplied by 2 subtracted by 3 equals 7. Find the number.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "7 3 [OP_ADD] 2 [OP_DIV]",
        "solution_abst_en": "7 3 [OP_ADD] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 7\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 7\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "6332": {
        "category": "Correspondence",
        "question_ko": "철사를 한 도막에 7센티미터(㎝)씩 잘랐더니 12도막이 되고, 4센티미터(㎝)가 남았습니다. 이 철사를 3센티미터(㎝)씩 자르면 몇 센티미터(㎝)가 남습니까?",
        "question_en": "When I cut wire into pieces of 7 centimeters (cm), it becomes 12 pieces leaving 4 centimeters (cm). If you cut this wire into pieces of 3 centimeters (cm), how many centimeters (cm) remains?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "7 12 [OP_MUL] 4 [OP_ADD] 3 [OP_MOD]",
        "solution_abst_en": "7 12 [OP_MUL] 4 [OP_ADD] 3 [OP_MOD]",
        "solution_code_ko": "var_a = 7\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e % var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 7\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e % var_f\nprint(int(var_g))"
    },
    "6333": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 2번째로 큰 수와 2번째로 작은 수로 나눈 나머지는 얼마입니까?",
        "question_en": "There are five numbers 10, 11, 12, 13, and 14. What is the remainder of the second largest number divided by the second smallest number?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_MOD]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_MOD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g % var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g % var_i\nprint(int(var_j))"
    },
    "6334": {
        "category": "Geometry",
        "question_ko": "바둑돌을 빈틈없이 늘어놓아 정사각형을 만들었습니다. 둘레에 놓인 바둑돌의 개수가 52개라면, 가장 바깥쪽의 한 변에 놓인 바둑돌의 개수는 몇 개입니까?",
        "question_en": "I made a square by arranging go stones without gaps. If the number of go stones on the perimeter is 52, how many go stones are on the outermost of one side?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "52 4 [OP_SUB] 4 [OP_DIV] 2 [OP_ADD]",
        "solution_abst_en": "52 4 [OP_SUB] 4 [OP_DIV] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 52\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 52\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "6335": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 각각 11센티미터(㎝), 5센티미터(㎝)인 두 정사각형의 넓이의 합은 몇 제곱센티미터(㎠)입니까?",
        "question_en": "How many square centimeters (cm2) is the sum of the widths of two squares, every 11 centimeters (cm) and 5 centimeters (cm) long?\n",
        "answer_ko": "146",
        "answer_en": "146",
        "solution_abst_ko": "11 2 [OP_POW] 5 2 [OP_POW] [OP_ADD]",
        "solution_abst_en": "11 2 [OP_POW] 5 2 [OP_POW] [OP_ADD]",
        "solution_code_ko": "var_a = 11\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 11\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "6336": {
        "category": "Possibility",
        "question_ko": "주머니에 5, 1, 7, 6이 적힌 카드가 한 장씩 들어있다. 이를 모두 뽑아 7보다 큰 소수 세 자리 수를 만들려고 할 때, 모두 몇 개 만들 수 있습니까?",
        "question_en": "There are one card 5, one card 1, one card 7, and one card 6 in the pocket. When you want to make decimal numbers with three decimal places bigger than 7 with all of each card, how many can you make?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 5 1 7 6 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 7 10 4 1 [OP_SUB] [OP_POW] [OP_MUL] [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 5 1 7 6 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 7 10 4 1 [OP_SUB] [OP_POW] [OP_MUL] [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 5\nvar_b = 1\nvar_c = 7\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 7\nvar_g = 10\nvar_h = 4\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_g ** var_j\nvar_l = var_f * var_k\nlist_c = []\nfor i in list_b:\n    if i > var_l:\n        list_c.append(i)\nvar_m = len(list_c)\nprint(int(var_m))",
        "solution_code_en": "var_a = 5\nvar_b = 1\nvar_c = 7\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 7\nvar_g = 10\nvar_h = 4\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_g ** var_j\nvar_l = var_f * var_k\nlist_c = []\nfor i in list_b:\n    if i > var_l:\n        list_c.append(i)\nvar_m = len(list_c)\nprint(int(var_m))"
    },
    "6337": {
        "category": "Comparison",
        "question_ko": "A는 10개씩 4묶음과 낱개 8개를 더한 수이다. B는 50에서 1을 뺀 수이다. C는 40에서 7을 더한 수이다. 세 수 A, B, C 중 가장 큰 수는 무엇인가?",
        "question_en": "A is the sum of 4 groups of 10 and 8 units. B is 50 minus 1. C is 40 plus 7. Which of the three numbers A, B, and C is the greatest?",
        "answer_ko": "B",
        "answer_en": "B",
        "solution_abst_ko": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] 10 4 [OP_MUL] 8 [OP_ADD] 50 1 [OP_SUB] 40 7 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] 10 4 [OP_MUL] 8 [OP_ADD] 50 1 [OP_SUB] 40 7 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 10\nvar_e = 4\nvar_f = var_d * var_e\nvar_g = 8\nvar_h = var_f + var_g\nvar_i = 50\nvar_j = 1\nvar_k = var_i - var_j\nvar_l = 40\nvar_m = 7\nvar_n = var_l + var_m\nlist_b= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nlist_b.reverse()\nvar_o = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_p = list_c[-var_o]\nvar_q = list_b.index(var_p)+1\nvar_r = list_a[var_q-1]\nprint(var_r)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 10\nvar_e = 4\nvar_f = var_d * var_e\nvar_g = 8\nvar_h = var_f + var_g\nvar_i = 50\nvar_j = 1\nvar_k = var_i - var_j\nvar_l = 40\nvar_m = 7\nvar_n = var_l + var_m\nlist_b= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nlist_b.reverse()\nvar_o = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_p = list_c[-var_o]\nvar_q = list_b.index(var_p)+1\nvar_r = list_a[var_q-1]\nprint(var_r)"
    },
    "6338": {
        "category": "Arithmetic calculation",
        "question_ko": "지연이는 용돈의 1/2을 가지고 떡볶이를 사먹었습니다. 그리고 나머지의 3/8은 연필을 사는 데 사용했습니다. 남은 돈이 2500원일 때 지연이가 사먹은 떡볶이는 얼마입니까?",
        "question_en": "Ji-yeon bought tteokbokki with 1/2 of her pocket money. And she used 3/8 of the rest to buy pencils. How much is the tteokbokki Jiyeon bought when the remaining money is 2,500 won?",
        "answer_ko": "4000",
        "answer_en": "4000",
        "solution_abst_ko": "2500 1 3/8 [OP_SUB] [OP_DIV] 1/2 [OP_DIV] 1/2 [OP_MUL]",
        "solution_abst_en": "2500 1 3/8 [OP_SUB] [OP_DIV] 1/2 [OP_DIV] 1/2 [OP_MUL]",
        "solution_code_ko": "var_a = 2500\nvar_b = 1\nvar_c = 0.375\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 0.5\nvar_g = var_e / var_f\nvar_h = 0.5\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 2500\nvar_b = 1\nvar_c = 0.375\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 0.5\nvar_g = var_e / var_f\nvar_h = 0.5\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "6339": {
        "category": "Geometry",
        "question_ko": "어떤 정육면체를 이어 붙여서 직육면체를 만들었는데, 밑면의 세로와 가로의 길이가 높이의 2배가 되도록 하였다. 이 직육면체의 모든 모서리의 길이의 합이 100센티미터(㎝)라면, 겉넓이는 몇이겠는가?",
        "question_en": "I made a rectangular parallelepiped by attaching certain cubes, and the length and width of its base were twice the height. If the sum of the lengths of all the edges of this rectangular parallelepiped is 100 centimeters (cm), what is the surface area of this rectangular parallelepiped?",
        "answer_ko": "400",
        "answer_en": "400",
        "solution_abst_ko": "100 4 [OP_DIV] 2 2 [OP_ADD] 1 [OP_ADD] [OP_DIV] 2 [OP_POW] 2 2 [OP_MUL] 2 [OP_MUL] 1 2 [OP_MUL] 2 [OP_MUL] 1 2 [OP_MUL] 2 [OP_MUL] [OP_ADD] [OP_ADD] [OP_MUL]",
        "solution_abst_en": "100 4 [OP_DIV] 2 2 [OP_ADD] 1 [OP_ADD] [OP_DIV] 2 [OP_POW] 2 2 [OP_MUL] 2 [OP_MUL] 1 2 [OP_MUL] 2 [OP_MUL] 1 2 [OP_MUL] 2 [OP_MUL] [OP_ADD] [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 100\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = 2\nvar_f = var_d + var_e\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = var_c / var_h\nvar_j = 2\nvar_k = var_i ** var_j\nvar_l = 2\nvar_m = 2\nvar_n = var_l * var_m\nvar_o = 2\nvar_p = var_n * var_o\nvar_q = 1\nvar_r = 2\nvar_s = var_q * var_r\nvar_t = 2\nvar_u = var_s * var_t\nvar_v = 1\nvar_w = 2\nvar_x = var_v * var_w\nvar_y = 2\nvar_z = var_x * var_y\nvar_A = var_u + var_z\nvar_B = var_p + var_A\nvar_C = var_k * var_B\nprint(int(var_C))",
        "solution_code_en": "var_a = 100\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = 2\nvar_f = var_d + var_e\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = var_c / var_h\nvar_j = 2\nvar_k = var_i ** var_j\nvar_l = 2\nvar_m = 2\nvar_n = var_l * var_m\nvar_o = 2\nvar_p = var_n * var_o\nvar_q = 1\nvar_r = 2\nvar_s = var_q * var_r\nvar_t = 2\nvar_u = var_s * var_t\nvar_v = 1\nvar_w = 2\nvar_x = var_v * var_w\nvar_y = 2\nvar_z = var_x * var_y\nvar_A = var_u + var_z\nvar_B = var_p + var_A\nvar_C = var_k * var_B\nprint(int(var_C))"
    },
    "6340": {
        "category": "Comparison",
        "question_ko": "버스를 타기 위해 9명의 학생들이 한 줄로 서 있습니다. 앞에서 3번째에 서 있는 학생과 뒤에서 2번째에 서 있는 학생 사이에는 모두 몇 명의 학생이 서 있습니까?",
        "question_en": "Nine students are standing in a line to get on the bus. How many students are standing between the student standing third from the front and the student standing second from the back?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "9 3 [OP_SUB] 2 [OP_SUB]",
        "solution_abst_en": "9 3 [OP_SUB] 2 [OP_SUB]",
        "solution_code_ko": "var_a = 9\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "6341": {
        "category": "Arithmetic calculation",
        "question_ko": "도현이의 키는 1.46미터(m)이고, 형의 키는 도현이의 키의 1.15배입니다. 형의 키는 몇 미터(m)인가?",
        "question_en": "Dohyeon is 1.46 meters (m) tall, and his older brother's height is 1.15 times of Dohyeon's. How tall is his brother in meters (m)?",
        "answer_ko": "1.68",
        "answer_en": "1.68",
        "solution_abst_ko": "1.46 1.15 [OP_MUL]",
        "solution_abst_en": "1.46 1.15 [OP_MUL]",
        "solution_code_ko": "var_a = 1.46\nvar_b = 1.15\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 1.46\nvar_b = 1.15\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "6342": {
        "category": "Geometry",
        "question_ko": "정육면체 모양의 상자의 넓이가 600일때, 이 상자의 부피는?",
        "question_en": "If the area of a cube-shaped box is 600, what is the volume of this box?",
        "answer_ko": "1000",
        "answer_en": "1000",
        "solution_abst_ko": "600 6 [OP_DIV] 1/2 [OP_POW] 3 [OP_POW]",
        "solution_abst_en": "600 6 [OP_DIV] 1/2 [OP_POW] 3 [OP_POW]",
        "solution_code_ko": "var_a = 600\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 3\nvar_g = var_e ** var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 600\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 3\nvar_g = var_e ** var_f\nprint(int(var_g))"
    },
    "6343": {
        "category": "Possibility",
        "question_ko": "6개의 농구팀이 서로 한 번씩 시합을 가진다면 모두 몇 번의 시합이 이루어지는지 모두 구하시오",
        "question_en": "If 6 basketball teams play with each other once, how many matches will there be in total?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "6 2 [OP_COMB]",
        "solution_abst_en": "6 2 [OP_COMB]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))"
    },
    "6344": {
        "category": "Correspondence",
        "question_ko": "윤기는 네 자리 수와 57의 덧셈을 하려 합니다. 윤기는 네 자리 수의 일의 자리 숫자 9를 6으로 잘못 보았습니다. 윤기가 구한 합은 1823 일 때, 네 자리 수를 구하시오.",
        "question_en": "Yoongi wants to add a four-digit number to 57. Yoongi saw 9 in the ones place of a four-digit number wrong, and saw it as 6. When the sum Yoongi got is 1823, find this four-digit number.",
        "answer_ko": "1769",
        "answer_en": "1769",
        "solution_abst_ko": "1823 57 [OP_SUB] 6 9 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "1823 57 [OP_SUB] 6 9 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 1823\nvar_b = 57\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1823\nvar_b = 57\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "6345": {
        "category": "Arithmetic calculation",
        "question_ko": "두 자리 수끼리의 곱셈을 할때 곱하는 수의 십의 자리 숫자 2를 6으로 보고 계산한 값이 2496이고, 바르게 계산한 값이 936일 때, 2개의 두 자리 수의 합을 구하시오.",
        "question_en": "When performing multiplication between two-digit numbers, when the tens digit of the multiplier is mistakenly considered as 6 instead of 2, the calculated value is 2496. However, the correct calculation yields 936. What is the sum of these two two-digit numbers?",
        "answer_ko": "63",
        "answer_en": "63",
        "solution_abst_ko": "[OP_LIST_SOL] 2496 936 [OP_SUB] 6 2 [OP_SUB] 10 [OP_MUL] [OP_DIV] 936 2496 936 [OP_SUB] 6 2 [OP_SUB] 10 [OP_MUL] [OP_DIV] [OP_DIV] [OP_LIST_EOL] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 2496 936 [OP_SUB] 6 2 [OP_SUB] 10 [OP_MUL] [OP_DIV] 936 2496 936 [OP_SUB] 6 2 [OP_SUB] 10 [OP_MUL] [OP_DIV] [OP_DIV] [OP_LIST_EOL] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 2496\nvar_b = 936\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = 10\nvar_h = var_f * var_g\nvar_i = var_c / var_h\nvar_j = 936\nvar_k = 2496\nvar_l = 936\nvar_m = var_k - var_l\nvar_n = 6\nvar_o = 2\nvar_p = var_n - var_o\nvar_q = 10\nvar_r = var_p * var_q\nvar_s = var_m / var_r\nvar_t = var_j / var_s\nlist_a= []\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_a.append(var_t)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_u = sum(list_a)\nprint(int(var_u))",
        "solution_code_en": "var_a = 2496\nvar_b = 936\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = 10\nvar_h = var_f * var_g\nvar_i = var_c / var_h\nvar_j = 936\nvar_k = 2496\nvar_l = 936\nvar_m = var_k - var_l\nvar_n = 6\nvar_o = 2\nvar_p = var_n - var_o\nvar_q = 10\nvar_r = var_p * var_q\nvar_s = var_m / var_r\nvar_t = var_j / var_s\nlist_a= []\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_a.append(var_t)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_u = sum(list_a)\nprint(int(var_u))"
    },
    "6346": {
        "category": "Arithmetic calculation",
        "question_ko": "축구공이 한 상자에 12개씩 8상자 있고, 농구공이 한 상자에 12개씩 5상자 있습니다. 축구공은 농구공보다 몇 개 더 많습니까?",
        "question_en": "There are 8 boxes of soccer balls of 12 each, and 5 boxes of basketballs of 12 each. How many more soccer balls are there than basketballs?",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "12 8 [OP_MUL] 12 5 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "12 8 [OP_MUL] 12 5 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 12\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 12\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "6347": {
        "category": "Possibility",
        "question_ko": "1부터 9까지의 카드 중 하나를 뽑아서 65을 곱했을 때 57에 7을 곱한 값보다 커지는 경우의 수를 구하시오.",
        "question_en": "Find the number of ways when the value of one of the cards numbered from 1 to 9 is drawn and multiplied by 65, and is greater than the value of 57 multiplied by 7.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "1 9 1 [OP_LIST_ARANGE] 57 7 [OP_MUL] 65 [OP_DIV] [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "1 9 1 [OP_LIST_ARANGE] 57 7 [OP_MUL] 65 [OP_DIV] [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 57\nvar_e = 7\nvar_f = var_d * var_e\nvar_g = 65\nvar_h = var_f / var_g\nlist_b = []\nfor i in list_a:\n    if i < var_h:\n        list_b.append(i)\nvar_i = len(list_b)\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 57\nvar_e = 7\nvar_f = var_d * var_e\nvar_g = 65\nvar_h = var_f / var_g\nlist_b = []\nfor i in list_a:\n    if i < var_h:\n        list_b.append(i)\nvar_i = len(list_b)\nprint(int(var_i))"
    },
    "6348": {
        "category": "Comparison",
        "question_ko": "1.4, 9/10, 1.2, 0.5, 13/10 중에서 1.1보다 크거나 같은 숫자를 고르고, 선택된 숫자들의 개수를 구하세요",
        "question_en": "Choose a number greater than or equal to 1.1 from 1.4, 9/10, 1.2, 0.5, and 13/10, and count the number of selected numbers.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i >= var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i >= var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "6349": {
        "category": "Arithmetic calculation",
        "question_ko": "현수는 4시간을 걸어서 산책길을 한바퀴 돌았다. 현수가 1시간 동안 걸은 거리는 전체 산책길의 얼마입니까?",
        "question_en": "Hyeonsu went around the promenade for 4 hours. What is the ratio of the distance Hyeonsoo walked in 1 hour on the walking trail?",
        "answer_ko": "0.25",
        "answer_en": "0.25",
        "solution_abst_ko": "1 4 [OP_DIV]",
        "solution_abst_en": "1 4 [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "6350": {
        "category": "Geometry",
        "question_ko": "미호는 한 변의 길이가 6미터(m)인 밭을 가지고 있습니다. 이 밭의 넓이는 얼마입니까?",
        "question_en": "Miho has a field with a side measuring 6 meters (m). How big is this field?",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "6 2 [OP_POW]",
        "solution_abst_en": "6 2 [OP_POW]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = var_a ** var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = var_a ** var_b\nprint(int(var_c))"
    },
    "6351": {
        "category": "Possibility",
        "question_ko": "2, 4, 7, 9를 한 번씩 사용하여 백의 자리 숫자가 7인 세자리 수 중 세번째로 큰 수는 무엇입니까?",
        "question_en": "What is the third largest three-digit number with 7 in the hundreds place using 2, 4, 7, and 9 once?",
        "answer_ko": "749",
        "answer_en": "749",
        "solution_abst_ko": "[OP_LIST_SOL] 2 4 7 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 100 7 [OP_LIST_SEARCH_FIXED_DIGIT] 3 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 2 4 7 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 100 7 [OP_LIST_SEARCH_FIXED_DIGIT] 3 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = 7\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 100\nvar_g = 7\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 3\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nprint(int(var_i))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = 7\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 100\nvar_g = 7\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 3\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nprint(int(var_i))"
    },
    "6352": {
        "category": "Geometry",
        "question_ko": "어떤 모니터의 가로가 9센티미터(㎝)이다. 둘레가 46센티미터(㎝)이면 모니터의 세로는 몇 센티미터(㎝)입니까?",
        "question_en": "The width of a monitor is 9 centimeters (cm). If the circumference is 46 centimeters (cm), how long is the length of a monitor in centimeters (cm)?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "46 2 [OP_DIV] 9 [OP_SUB]",
        "solution_abst_en": "46 2 [OP_DIV] 9 [OP_SUB]",
        "solution_code_ko": "var_a = 46\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 9\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 46\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 9\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "6353": {
        "category": "Comparison",
        "question_ko": "슬기는 연필을 9자루 가지고 있고, 현정이는 연필을 12자루 가지고 있습니다. 연필을 더 많이 가지고 있는 사람은 누구입니까?",
        "question_en": "Seulgi has 9 pencils, and Hyeonjeong has 12 pencils. Who has more pencils?",
        "answer_ko": "현정",
        "answer_en": "Hyeonjeong",
        "solution_abst_ko": "[OP_LIST_SOL] 슬기 현정 [OP_LIST_EOL] [OP_LIST_SOL] 9 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Seulgi Hyeonjeong [OP_LIST_EOL] [OP_LIST_SOL] 9 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '슬기'\nvar_b = '현정'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 9\nvar_d = 12\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Seulgi'\nvar_b = 'Hyeonjeong'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 9\nvar_d = 12\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "6354": {
        "category": "Possibility",
        "question_ko": "당근, 오이, 무가 각각 1개씩 있습니다. 이 중 2가지를 골라서 사는 방법은 모두 몇 가지입니까?",
        "question_en": "There are one carrot, one cucumber, and one radish each. How many ways can you choose to buy 2 of these?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 당근 오이 무 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] carrot cucumber radish [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '당근'\nvar_b = '오이'\nvar_c = '무'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f / (i+1)\nprint(int(var_f))",
        "solution_code_en": "var_a = 'carrot'\nvar_b = 'cucumber'\nvar_c = 'radish'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f / (i+1)\nprint(int(var_f))"
    },
    "6355": {
        "category": "Comparison",
        "question_ko": "원 모양의 피자 (가), (나), (다), (라)가 있습니다. (가) 피자의 넓이는 314제곱센티미터(㎠)이고 (나)피자의 원주는 99.2센티미터(㎝)입니다. (다) 피자의 지름은 16센티미터(㎝)이고 (라)피자의 반지름은 12센티미터(㎝)입니다. 피자를 넓이가 작은 순서대로 왼쪽부터 정렬하면, 오른쪽에서 2번째에 있는 피자는 어느 것인지 구하시오. 단, 원주율은 3.1이라고 가정합니다.",
        "question_en": "There are circle-shaped pizzas (a), (b), (c), and (d). The area of the pizza (a) is 314 square centimeters (㎠) and the circumference of the pizza (b) is 99.2 centimeters (㎝). The diameter of the pizza (c) is 16 centimeters (cm) and the radius of the pizza (d) is 12 centimeters (cm). If the pizzas are sorted from the left in order from smallest to largest, find the pizza that is second from the right. It is assumed that the pi ratio is 3.1.",
        "answer_ko": "(가)",
        "answer_en": "(a)",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) (다) (라) [OP_LIST_EOL] [OP_LIST_SOL] 314 99.2 3.1 [OP_DIV] 2 [OP_DIV] 2 [OP_POW] 3.1 [OP_MUL] 16 2 [OP_DIV] 2 [OP_POW] 3.1 [OP_MUL] 12 2 [OP_POW] 3.1 [OP_MUL] [OP_LIST_EOL] 2 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (a) (b) (c) (d) [OP_LIST_EOL] [OP_LIST_SOL] 314 99.2 3.1 [OP_DIV] 2 [OP_DIV] 2 [OP_POW] 3.1 [OP_MUL] 16 2 [OP_DIV] 2 [OP_POW] 3.1 [OP_MUL] 12 2 [OP_POW] 3.1 [OP_MUL] [OP_LIST_EOL] 2 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nvar_c = '(다)'\nvar_d = '(라)'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 314\nvar_f = 99.2\nvar_g = 3.1\nvar_h = var_f / var_g\nvar_i = 2\nvar_j = var_h / var_i\nvar_k = 2\nvar_l = var_j ** var_k\nvar_m = 3.1\nvar_n = var_l * var_m\nvar_o = 16\nvar_p = 2\nvar_q = var_o / var_p\nvar_r = 2\nvar_s = var_q ** var_r\nvar_t = 3.1\nvar_u = var_s * var_t\nvar_v = 12\nvar_w = 2\nvar_x = var_v ** var_w\nvar_y = 3.1\nvar_z = var_x * var_y\nlist_b= []\nif \"/\" in str(var_z):\n    var_z = eval(str(var_z))\nlist_b.append(var_z)\nif \"/\" in str(var_u):\n    var_u = eval(str(var_u))\nlist_b.append(var_u)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_A = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_B = list_c[var_A-1]\nvar_C = list_b.index(var_B)+1\nvar_D = list_a[var_C-1]\nprint(var_D)",
        "solution_code_en": "var_a = '(a)'\nvar_b = '(b)'\nvar_c = '(c)'\nvar_d = '(d)'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 314\nvar_f = 99.2\nvar_g = 3.1\nvar_h = var_f / var_g\nvar_i = 2\nvar_j = var_h / var_i\nvar_k = 2\nvar_l = var_j ** var_k\nvar_m = 3.1\nvar_n = var_l * var_m\nvar_o = 16\nvar_p = 2\nvar_q = var_o / var_p\nvar_r = 2\nvar_s = var_q ** var_r\nvar_t = 3.1\nvar_u = var_s * var_t\nvar_v = 12\nvar_w = 2\nvar_x = var_v ** var_w\nvar_y = 3.1\nvar_z = var_x * var_y\nlist_b= []\nif \"/\" in str(var_z):\n    var_z = eval(str(var_z))\nlist_b.append(var_z)\nif \"/\" in str(var_u):\n    var_u = eval(str(var_u))\nlist_b.append(var_u)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_A = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_B = list_c[var_A-1]\nvar_C = list_b.index(var_B)+1\nvar_D = list_a[var_C-1]\nprint(var_D)"
    },
    "6356": {
        "category": "Correspondence",
        "question_ko": "14A+B73=418입니다. A는 얼마인가요?",
        "question_en": "14A+B73=418. How much is A, where 14A and B73 are three-digit numbers?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "14A+B73=418 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "14A+B73=418 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '14A+B73=418'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '14A+B73=418'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "6357": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 10, 11, 12, 13이 있습니다. 그 중에서 3번째로 작은 수와 2번째로 작은 수로 나눈 몫은 얼마입니까?",
        "question_en": "There are four numbers 10, 11, 12, and 13. What is the quotient if you divide the 3rd smallest number by the 2nd smallest number?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 3 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_FDIV]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 3 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_FDIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f // var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f // var_h\nprint(int(var_i))"
    },
    "6358": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 4로 나누고 16을 더해야 할 것을 잘못하여 어떤 수에 4를 곱하고 16을 더했더니 32가 되었습니다. 바르게 계산하면 얼마인지 구해 보시오.",
        "question_en": "You have to divide a number by 4 and add 16, but if you accidentally multiplied a number by 4 and added 16 to get 32. Find out how much it is if you calculate it correctly.",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "32 16 [OP_SUB] 4 [OP_DIV] 4 [OP_DIV] 16 [OP_ADD]",
        "solution_abst_en": "32 16 [OP_SUB] 4 [OP_DIV] 4 [OP_DIV] 16 [OP_ADD]",
        "solution_code_ko": "var_a = 32\nvar_b = 16\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 4\nvar_g = var_e / var_f\nvar_h = 16\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 32\nvar_b = 16\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 4\nvar_g = var_e / var_f\nvar_h = 16\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "6359": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 143을 더하고 다시 27을 곱하면 9693이 됩니다. 어떤 수를 구하시오.",
        "question_en": "Add 143 to a number and multiply it by 27 to get 9693. Find the number.",
        "answer_ko": "216",
        "answer_en": "216",
        "solution_abst_ko": "9693 27 [OP_DIV] 143 [OP_SUB]",
        "solution_abst_en": "9693 27 [OP_DIV] 143 [OP_SUB]",
        "solution_code_ko": "var_a = 9693\nvar_b = 27\nvar_c = var_a / var_b\nvar_d = 143\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9693\nvar_b = 27\nvar_c = var_a / var_b\nvar_d = 143\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "6360": {
        "category": "Arithmetic calculation",
        "question_ko": "2킬로그램(㎏)이 넘어야 무게를 잴 수 있는 저울이 있습니다. 지금까지 200그램(g)의 추를 3개 올렸을 때 무게를 재기 위해서는 몇 개의 추를 더 올려야 하는지 구하시오.",
        "question_en": "There is a scale that can weigh more than 2 kilograms (kg). If you have lifted 3 weights of 200 grams (g) so far, find how many more weights you need to lift to measure the weight.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "2 1000 [OP_MUL] 200 3 [OP_MUL] [OP_SUB] 200 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "2 1000 [OP_MUL] 200 3 [OP_MUL] [OP_SUB] 200 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 200\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 200\nvar_i = var_g / var_h\nvar_j = 1\nvar_k=int(((var_i+9*10**(var_j-2))//(10**(var_j-1)))*10**(var_j-1))\n\nprint(int(var_k))",
        "solution_code_en": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 200\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 200\nvar_i = var_g / var_h\nvar_j = 1\nvar_k=int(((var_i+9*10**(var_j-2))//(10**(var_j-1)))*10**(var_j-1))\n\nprint(int(var_k))"
    },
    "6361": {
        "category": "Arithmetic calculation",
        "question_ko": "지우개 254자루를 한 상자에 30개씩 포장하여 팔려고 합니다. 지우개를 남김없이 포장하여 팔려면 지우개가 적어도 몇 개 더 있어야 할까요?",
        "question_en": "I plan to sell 254 erasers by packing 30 in each box. How many more erasers would you need to pack and sell if there should be no leftover erasers?",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "30 254 30 [OP_MOD] [OP_SUB]",
        "solution_abst_en": "30 254 30 [OP_MOD] [OP_SUB]",
        "solution_code_ko": "var_a = 30\nvar_b = 254\nvar_c = 30\nvar_d = var_b % var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 30\nvar_b = 254\nvar_c = 30\nvar_d = var_b % var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "6362": {
        "category": "Comparison",
        "question_ko": "선호는 민정이 보다 구슬을 1개 더 많이 가지고 있다. 진영이는 주환이보다 3개 더 적으며 민정이는 6개, 주환이는 7개 가지고 있다. 이들 중 가장 적은 구슬을 가진 사람은 누구인가?",
        "question_en": "Seonho has 1 more marble than Minjeong. Jinyoung has 3 fewer than Joohwan , Minjeong has 6 marbles, and Joohwan has 7 marbles. Which of these has the fewest marbles?",
        "answer_ko": "진영",
        "answer_en": "Jinyoung",
        "solution_abst_ko": "[OP_LIST_SOL] 민정 주환 선호 진영 [OP_LIST_EOL] [OP_LIST_SOL] 6 7 6 1 [OP_SUB] 7 3 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Minjeong Joohwan Seonho Jinyoung [OP_LIST_EOL] [OP_LIST_SOL] 6 7 6 1 [OP_SUB] 7 3 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '민정'\nvar_b = '주환'\nvar_c = '선호'\nvar_d = '진영'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 6\nvar_f = 7\nvar_g = 6\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = 7\nvar_k = 3\nvar_l = var_j - var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[var_m-1]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'Minjeong'\nvar_b = 'Joohwan'\nvar_c = 'Seonho'\nvar_d = 'Jinyoung'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 6\nvar_f = 7\nvar_g = 6\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = 7\nvar_k = 3\nvar_l = var_j - var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[var_m-1]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "6363": {
        "category": "Arithmetic calculation",
        "question_ko": "밀가루 10.4 킬로그램(㎏) 을 그릇 한 개에 0.8 킬로그램(㎏) 씩 나누어 담으려고 합니다. 필요한 그릇은 몇 개입니까?",
        "question_en": "You want to divide 10.4 kilograms (kg) of flour into 0.8 kilograms (kg) of each bowl. How many bowls do you need?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "10.4 0.8 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "10.4 0.8 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 10.4\nvar_b = 0.8\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))",
        "solution_code_en": "var_a = 10.4\nvar_b = 0.8\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))"
    },
    "6364": {
        "category": "Correspondence",
        "question_ko": "ABC+ABC+ABC=888입니다. A, B, C가 모두 다른 한 자리 수라면, A는 얼마입니까?",
        "question_en": "ABC+ABC+ABC=888. If A, B, and C are all different single digit numbers, what is A?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "ABC+ABC+ABC=888 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "ABC+ABC+ABC=888 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'ABC+ABC+ABC=888'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'ABC+ABC+ABC=888'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "6365": {
        "category": "Arithmetic calculation",
        "question_ko": "색종이를 4명에게 똑같이 나누어 주어야 할 것을 잘못하여 5명에게 똑같이 나누어 주었더니 한 사람당 15장씩 주고 2장이 남았습니다. 이 색종이를 4명에게 똑같이 나누어 주면 한 사람당 최대한 몇 장씩 가지게 됩니까?",
        "question_en": "You mistakenly distributed colored papers equally to 5 people instead of to 4 people, and each person got 15 papers and 2 papers were left. If you divide these papers equally to 4 people, how many papers will each person recieve at the maximum?",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "5 15 [OP_MUL] 2 [OP_ADD] 4 [OP_FDIV]",
        "solution_abst_en": "5 15 [OP_MUL] 2 [OP_ADD] 4 [OP_FDIV]",
        "solution_code_ko": "var_a = 5\nvar_b = 15\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c + var_d\nvar_f = 4\nvar_g = var_e // var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 15\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c + var_d\nvar_f = 4\nvar_g = var_e // var_f\nprint(int(var_g))"
    },
    "6366": {
        "category": "Geometry",
        "question_ko": "바둑돌을 빈틈없이 늘어놓아 큰 정사각형을 만들었더니 3개의 바둑돌이 남았습니다. 만든 정사각형의 가로 한 변과 세로 한 변을 2열씩 늘리려면 44개의 바둑돌이 더 필요하다고 합니다. 바둑돌은 모두 몇 개입니까?",
        "question_en": "When the go stones are lined up without gaps to form a large square, there are three go stones left. It is said that 44 more go stones are needed to increase each horizontal and vertical side of the square by 2 columns. How many go stones are there in all?",
        "answer_ko": "103",
        "answer_en": "103",
        "solution_abst_ko": "44 4 [OP_SUB] 4 [OP_DIV] 2 [OP_POW] 3 [OP_ADD]",
        "solution_abst_en": "44 4 [OP_SUB] 4 [OP_DIV] 2 [OP_POW] 3 [OP_ADD]",
        "solution_code_ko": "var_a = 44\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e ** var_f\nvar_h = 3\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 44\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e ** var_f\nvar_h = 3\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "6367": {
        "category": "Arithmetic calculation",
        "question_ko": "노란색 물고기가 445마리 있고, 노란색 물고기는 파란색 물고기보다 38마리 더 적습니다. 노란색 물고기와 파란색 물고기는 모두 몇 마리입니까?",
        "question_en": "There are 445 yellow fish, which is 38 fewer than blue fish. How many yellow and blue fish are there altogether?",
        "answer_ko": "928",
        "answer_en": "928",
        "solution_abst_ko": "445 445 38 [OP_ADD] [OP_ADD]",
        "solution_abst_en": "445 445 38 [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 445\nvar_b = 445\nvar_c = 38\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 445\nvar_b = 445\nvar_c = 38\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "6368": {
        "category": "Possibility",
        "question_ko": "0, 1, 2, 3, 4, 5, 6의 숫자 중 서로 다른 4개의 숫자를 한 번씩만 사용하여 네 자리 수를 만들 때, 가장 큰 짝수와 가장 작은 홀수의 차를 구하시오.",
        "question_en": "Find the difference between the largest even number and the smallest odd number when forming a four-digit number using each of the four numbers 0, 1, 2, 3, 4, 5, and 6 only once.",
        "answer_ko": "5519",
        "answer_en": "5519",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 4 5 6 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 2 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX] [OP_SET_DIFFERENCE] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 4 5 6 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 2 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX] [OP_SET_DIFFERENCE] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nvar_f = 5\nvar_g = 6\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_h))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_i = 2\nlist_c = []\nvar_i = int(var_i)\nfor i in list_b:\n    i = int(i)\n    if i % var_i == 0:\n        list_c.append(i)\nvar_j = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_k = list_d[-var_j]\nlist_e = list(set(list_b) - set(list_c))\nvar_l = 1\nlist_f=list_e.copy()\nlist_f.sort()\nvar_m = list_f[var_l-1]\nvar_n = var_k - var_m\nprint(int(var_n))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nvar_f = 5\nvar_g = 6\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_h))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_i = 2\nlist_c = []\nvar_i = int(var_i)\nfor i in list_b:\n    i = int(i)\n    if i % var_i == 0:\n        list_c.append(i)\nvar_j = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_k = list_d[-var_j]\nlist_e = list(set(list_b) - set(list_c))\nvar_l = 1\nlist_f=list_e.copy()\nlist_f.sort()\nvar_m = list_f[var_l-1]\nvar_n = var_k - var_m\nprint(int(var_n))"
    },
    "6369": {
        "category": "Correspondence",
        "question_ko": "9를 어떤 수에서 나누었더니 8이 되었습니다. 11을 어떤 수에 더하면 얼마가 되는지 구하시오.",
        "question_en": "When this number is divided by 9, the result came out as 8. What do you get when you add 11 to this number?",
        "answer_ko": "83",
        "answer_en": "83",
        "solution_abst_ko": "8 9 [OP_MUL] 11 [OP_ADD]",
        "solution_abst_en": "8 9 [OP_MUL] 11 [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 11\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 11\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "6370": {
        "category": "Arithmetic calculation",
        "question_ko": "빨간색 구슬이 한 상자에 14개씩 5상자 있고, 파란색 구슬이 한 상자에 14개씩 9상자 있습니다. 파란색 구슬은 빨간색 구슬보다 몇 개 더 많습니까?",
        "question_en": "There are 5 boxes of 14 red marbles per box and 9 boxes of 14 blue marbles per box. How many more blue marbles are there than red marbles?",
        "answer_ko": "56",
        "answer_en": "56",
        "solution_abst_ko": "14 9 [OP_MUL] 14 5 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "14 9 [OP_MUL] 14 5 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 14\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 14\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 14\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 14\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "6371": {
        "category": "Comparison",
        "question_ko": "버스 정류장에 학생들이 한 줄로 서있습니다. 민석이는 앞에서 12번째에 서 있고 준호는 뒤에서 9번째에 서 있을 때, 민석이 바로 뒤에 준호가 서 있습니다. 버스 정류장에 줄을 서 있는 학생은 총 몇 명인지 구하시오.",
        "question_en": "Students are standing in a line at the bus stop. When Minseok is standing 12th from the front and Junho is standing 9th from the back, Junho is standing right behind Minseok. Find the total number of students standing in line at the bus stop.",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "12 9 [OP_ADD]",
        "solution_abst_en": "12 9 [OP_ADD]",
        "solution_code_ko": "var_a = 12\nvar_b = 9\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 12\nvar_b = 9\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "6372": {
        "category": "Arithmetic calculation",
        "question_ko": "구슬이 8개 있었는데 주머니에 6개만 들어있었습니다. 잃어버린 구슬은 몇 개입니까?",
        "question_en": "There were 8 marbles before, but only 6 are in the bag now. How many marbles are lost?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "8 6 [OP_SUB]",
        "solution_abst_en": "8 6 [OP_SUB]",
        "solution_code_ko": "var_a = 8\nvar_b = 6\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 8\nvar_b = 6\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "6373": {
        "category": "Geometry",
        "question_ko": "가로의 길이가 18센티미터(㎝), 세로의 길이가 12센티미터(㎝), 높이가 9센티미터(㎝)인 직육면체 모양의 상자를 쌓아 정육면체를 만들려고 할 때 필요한 상자의 개수는 최소 몇 개인지 구하시오.",
        "question_en": "How many boxes are needed to make a cube by stacking cuboid-shaped boxes with a width of 18 centimeters (cm), a length of 12 centimeters (cm), and a height of 9 centimeters (cm), in minimum?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "18 12 [OP_LCM] 9 [OP_LCM] 18 [OP_DIV] 18 12 [OP_LCM] 9 [OP_LCM] 12 [OP_DIV] 18 12 [OP_LCM] 9 [OP_LCM] 9 [OP_DIV] [OP_MUL] [OP_MUL]",
        "solution_abst_en": "18 12 [OP_LCM] 9 [OP_LCM] 18 [OP_DIV] 18 12 [OP_LCM] 9 [OP_LCM] 12 [OP_DIV] 18 12 [OP_LCM] 9 [OP_LCM] 9 [OP_DIV] [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 18\nvar_b = 12\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nvar_d = 9\nvar_e = var_d * var_c / math.gcd(int(var_d), int(var_c))\nvar_f = 18\nvar_g = var_e / var_f\nvar_h = 18\nvar_i = 12\nvar_j = var_i * var_h / math.gcd(int(var_i), int(var_h))\nvar_k = 9\nvar_l = var_k * var_j / math.gcd(int(var_k), int(var_j))\nvar_m = 12\nvar_n = var_l / var_m\nvar_o = 18\nvar_p = 12\nvar_q = var_p * var_o / math.gcd(int(var_p), int(var_o))\nvar_r = 9\nvar_s = var_r * var_q / math.gcd(int(var_r), int(var_q))\nvar_t = 9\nvar_u = var_s / var_t\nvar_v = var_n * var_u\nvar_w = var_g * var_v\nprint(int(var_w))",
        "solution_code_en": "var_a = 18\nvar_b = 12\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nvar_d = 9\nvar_e = var_d * var_c / math.gcd(int(var_d), int(var_c))\nvar_f = 18\nvar_g = var_e / var_f\nvar_h = 18\nvar_i = 12\nvar_j = var_i * var_h / math.gcd(int(var_i), int(var_h))\nvar_k = 9\nvar_l = var_k * var_j / math.gcd(int(var_k), int(var_j))\nvar_m = 12\nvar_n = var_l / var_m\nvar_o = 18\nvar_p = 12\nvar_q = var_p * var_o / math.gcd(int(var_p), int(var_o))\nvar_r = 9\nvar_s = var_r * var_q / math.gcd(int(var_r), int(var_q))\nvar_t = 9\nvar_u = var_s / var_t\nvar_v = var_n * var_u\nvar_w = var_g * var_v\nprint(int(var_w))"
    },
    "6374": {
        "category": "Arithmetic calculation",
        "question_ko": "마트에 오이가 15개 있습니다. 오이 수의 3배만큼 무가 있습니다. 당근은 9개 있습니다. 무의 수는 당근 수의 몇 배입니까?",
        "question_en": "There are 15 cucumbers in the mart. There are three times as many radishes as there are cucumbers. There are 9 carrots. How many times the number of radishes is equal to the number of carrots?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "15 3 [OP_MUL] 9 [OP_DIV]",
        "solution_abst_en": "15 3 [OP_MUL] 9 [OP_DIV]",
        "solution_code_ko": "var_a = 15\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "6375": {
        "category": "Possibility",
        "question_ko": "5명의 학생을 한 줄로 세우는 방법은 모두 몇 가지입니까?",
        "question_en": "How many ways are there to line up 5 students?",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "5 5 [OP_PERM]",
        "solution_abst_en": "5 5 [OP_PERM]",
        "solution_code_ko": "var_a = 5\nvar_b = 5\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 5\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))"
    },
    "6376": {
        "category": "Correspondence",
        "question_ko": "A는 1에서 9까지의 수, B는 0에서 9까지의 수이고, AB40C는 45의 배수입니다. 이러한 다섯 자리 수는 모두 몇 개입니까?",
        "question_en": "A is a number from 1 to 9, and B is a number from 0 to 9, and AB40C is a multiple of 45. How many five-digit numbers like this can you think of?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "AB40C [OP_GEN_POSSIBLE_LIST] 45 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "AB40C [OP_GEN_POSSIBLE_LIST] 45 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 'AB40C'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 45\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))",
        "solution_code_en": "var_a = 'AB40C'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 45\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))"
    },
    "6377": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 가장 큰 수와 2번째로 큰 수로 나눈 몫은 얼마입니까?",
        "question_en": "There are five numbers 10, 11, 12, 13, and 14. What is the quotient of the largest number divided by the second largest number?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_FDIV]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_FDIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[-var_h]\nvar_j = var_g // var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[-var_h]\nvar_j = var_g // var_i\nprint(int(var_j))"
    },
    "6378": {
        "category": "Arithmetic calculation",
        "question_ko": "찹쌀떡 1개를 만드는 데 찹쌀가루가 6.64킬로그램(㎏) 필요합니다. 찹쌀가루 212.48킬로그램(㎏)으로 만들 수 있는 찹쌀떡은 모두 몇 개입니까?",
        "question_en": "It takes 6.64 kg (kg) of glutinous rice flour to make one glutinous rice cake. How many glutinous rice cakes can you make with 212.48 kg (kg) of glutinous rice flour?",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "212.48 6.64 [OP_FDIV]",
        "solution_abst_en": "212.48 6.64 [OP_FDIV]",
        "solution_code_ko": "var_a = 212.48\nvar_b = 6.64\nvar_c = var_a // var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 212.48\nvar_b = 6.64\nvar_c = var_a // var_b\nprint(int(var_c))"
    },
    "6379": {
        "category": "Comparison",
        "question_ko": "아현이네 집에서 할머니댁까지의 거리는 7150미터(m)이고, 이모댁까지의 거리는 6킬로미터(㎞) 720미터(m)입니다. 할머니 댁과 이모 댁 중 아현이네 집에서 더 가까운 곳은 어디인지 구하시오.",
        "question_en": "The distance from Ahyeon's house to grandma's house is 7150 meters (m), and the distance to aunt's house is 6 kilometers (km) and 720 meters (m). Find out which of grandmother's house or aunt's house is closer to Ahyeon's house.",
        "answer_ko": "이모댁",
        "answer_en": "aunt",
        "solution_abst_ko": "[OP_LIST_SOL] 할머니댁 이모댁 [OP_LIST_EOL] [OP_LIST_SOL] 7150 6 1000 [OP_MUL] 720 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] grandma aunt [OP_LIST_EOL] [OP_LIST_SOL] 7150 6 1000 [OP_MUL] 720 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '할머니댁'\nvar_b = '이모댁'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 7150\nvar_d = 6\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = 720\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'grandma'\nvar_b = 'aunt'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 7150\nvar_d = 6\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = 720\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "6380": {
        "category": "Arithmetic calculation",
        "question_ko": "준영이는 줄넘기를 한달에 56번씩 3달 동안 했고 남영이는 한달에 35번씩 4달 동안 했습니다. 준영이와 남영이가 한 줄넘기의 횟수는 모두 몇 번입니까?",
        "question_en": "Joonyoung jumped rope 56 times a month for 3 months and Namyoung did 35 times a month for 4 months. How many times did Junyoung and Namyeong jump rope?",
        "answer_ko": "308",
        "answer_en": "308",
        "solution_abst_ko": "56 3 [OP_MUL] 35 4 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "56 3 [OP_MUL] 35 4 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 56\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 35\nvar_e = 4\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 56\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 35\nvar_e = 4\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "6381": {
        "category": "Comparison",
        "question_ko": "일곱 개의 수 1.7, 1/5, 1/5, 1, 3/5, 3/8, 1.4가 있습니다. 이 중 네 번째로 큰 수는 무엇입니까?",
        "question_en": "Suppose there are seven numbers 1.7, 1/5, 1/5, 1, 3/5, 3/8, and 1.4. Which of these numbers is the fourth largest?",
        "answer_ko": "0.60",
        "answer_en": "0.6",
        "solution_abst_ko": "[OP_LIST_SOL] 1.7 1/5 1/5 1 3/5 3/8 1.4 [OP_LIST_EOL] 4 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1.7 1/5 1/5 1 3/5 3/8 1.4 [OP_LIST_EOL] 4 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1.7\nvar_b = 0.2\nvar_c = 0.2\nvar_d = 1\nvar_e = 0.6\nvar_f = 0.375\nvar_g = 1.4\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h = 4\nlist_b=list_a.copy()\nlist_b.sort()\nvar_i = list_b[-var_h]\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 1.7\nvar_b = 0.2\nvar_c = 0.2\nvar_d = 1\nvar_e = 0.6\nvar_f = 0.375\nvar_g = 1.4\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h = 4\nlist_b=list_a.copy()\nlist_b.sort()\nvar_i = list_b[-var_h]\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "6382": {
        "category": "Geometry",
        "question_ko": "바닥에 가로가 30센티미터(㎝), 세로가 30센티미터(㎝)인 정사각형 모양의 타일을 8개씩 5줄 붙였습니다. 타일을 붙인 바닥의 넓이는 몇 제곱미터(㎡)입니까?",
        "question_en": "Five rows of eight square tiles each measuring 30 centimeters (cm) in width and 30 centimeters (cm) in length were attached to the floor. How many square meters (m2) is the tiled floor?",
        "answer_ko": "3.60",
        "answer_en": "3.6",
        "solution_abst_ko": "30 100 [OP_DIV] 2 [OP_POW] 8 [OP_MUL] 5 [OP_MUL]",
        "solution_abst_en": "30 100 [OP_DIV] 2 [OP_POW] 8 [OP_MUL] 5 [OP_MUL]",
        "solution_code_ko": "var_a = 30\nvar_b = 100\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 8\nvar_g = var_e * var_f\nvar_h = 5\nvar_i = var_g * var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 30\nvar_b = 100\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 8\nvar_g = var_e * var_f\nvar_h = 5\nvar_i = var_g * var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "6383": {
        "category": "Possibility",
        "question_ko": "1부터 9까지가 적혀 있는 카드 9장 중 2장을 동시에 뽑을 때, 두 장의 합이 3이 나오는 경우의 수를 구하시오.",
        "question_en": "You are to pick 2 cards at the same time out of 9 cards numbered 1 through 9. Find how many ways there are the sum of the two cards is 3.",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "1 9 1 [OP_LIST_ARANGE] 2 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 3 [OP_LIST_FIND_NUM] 2 [OP_DIV]",
        "solution_abst_en": "1 9 1 [OP_LIST_ARANGE] 2 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 3 [OP_LIST_FIND_NUM] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 3\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 3\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "6384": {
        "category": "Arithmetic calculation",
        "question_ko": "20미터(m)간격으로 운동장에 깃발을 설치하려고 합니다. 깃발이 총 12개있으며 운동장의 둘레는 200미터(m)일때 깃발은 몇 개 남습니까?",
        "question_en": "Twelve students are about to line up on the playground. The total length of the playground is 200 meters (m) and students must keep 20 meters (m) apart. How many students can line up in total?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "12 200 20 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "12 200 20 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 12\nvar_b = 200\nvar_c = 20\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 200\nvar_c = 20\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "6385": {
        "category": "Arithmetic calculation",
        "question_ko": "운동장을 호석이는 51바퀴, 민영이는 34바퀴 돌았습니다. 민영이가 몇 바퀴를 더 돌아야 호석이가 돈 횟수와 같아집니까?",
        "question_en": "Ho-seok and Min-yeong ran 34 laps around the playground. How many more laps does Min-yeong have to make to equal the number of times Hoseok ran?",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "51 34 [OP_SUB]",
        "solution_abst_en": "51 34 [OP_SUB]",
        "solution_code_ko": "var_a = 51\nvar_b = 34\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 51\nvar_b = 34\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "6386": {
        "category": "Geometry",
        "question_ko": "미진이는 철사를 사용하여 한 변의 길이가 16센티미터(㎝)인 정오각형을 만들었습니다. 이 철사를 다시 펴서 남김없이 모두 사용하여 정팔각형을 만들 때, 이 정팔각형의 한 변의 길이를 구하시오.",
        "question_en": "Mijin made a regular pentagon with a side of 16 centimeters (cm) long using wire. When she stretches out this wire again and uses all of it to make a regular octagon, find the length of one side of this regular octagon.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "16 5 [OP_MUL] 8 [OP_DIV]",
        "solution_abst_en": "16 5 [OP_MUL] 8 [OP_DIV]",
        "solution_code_ko": "var_a = 16\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 16\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "6387": {
        "category": "Correspondence",
        "question_ko": "6보다 작은 수 중 4와 9 사이에 있는 수를 구하시오.",
        "question_en": "Find the number between 4 and 9 that is less than 6.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "4 9 1 [OP_LIST_ARANGE] 6 [OP_LIST_LESS] 1 [OP_LIST_GET]",
        "solution_abst_en": "4 9 1 [OP_LIST_ARANGE] 6 [OP_LIST_LESS] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 4\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nfor i in list_a:\n    if i < var_d:\n        list_b.append(i)\nvar_e = 1\nvar_f = list_b[var_e-1]\nprint(int(var_f))",
        "solution_code_en": "var_a = 4\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nfor i in list_a:\n    if i < var_d:\n        list_b.append(i)\nvar_e = 1\nvar_f = list_b[var_e-1]\nprint(int(var_f))"
    },
    "6388": {
        "category": "Comparison",
        "question_ko": "진호와 영수가 각자 연필을 가지고 있습니다. 진호가 연필 9자루 중 3자루를 잃어버렸고, 영수는 연필 14자루 중 7자루를 동생에게 주었습니다. 진호와 영수 중 누가 더 많은 연필을 가지고 있습니까?",
        "question_en": "Jinho and Youngsu have a pencil respectively. Jinho lost 3 out of 9 pencils, and Youngsu gave 7 out of 14 pencils to his younger brother. Who has more pencils between Jinho and Youngsu?",
        "answer_ko": "영수",
        "answer_en": "Youngsu",
        "solution_abst_ko": "[OP_LIST_SOL] 진호 영수 [OP_LIST_EOL] [OP_LIST_SOL] 9 3 [OP_SUB] 14 7 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jinho Youngsu [OP_LIST_EOL] [OP_LIST_SOL] 9 3 [OP_SUB] 14 7 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '진호'\nvar_b = '영수'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 9\nvar_d = 3\nvar_e = var_c - var_d\nvar_f = 14\nvar_g = 7\nvar_h = var_f - var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Jinho'\nvar_b = 'Youngsu'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 9\nvar_d = 3\nvar_e = var_c - var_d\nvar_f = 14\nvar_g = 7\nvar_h = var_f - var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "6389": {
        "category": "Arithmetic calculation",
        "question_ko": "문구점에 간 유나는 가지고 간 돈의 절반으로 공책을 사고, 나머지 돈의 절반으로 연필을 구매했더니 800원이 남았습니다. 처음에 유나가 가지고 간 돈은 얼마입니까?",
        "question_en": "Yuna went to the stationery store and bought a notebook with half of the money she took, and a pencil with half of the rest, and she had 800 won left. How much money did Yuna take with her in the beginning?",
        "answer_ko": "3200",
        "answer_en": "3200",
        "solution_abst_ko": "800 2 [OP_MUL] 2 [OP_MUL]",
        "solution_abst_en": "800 2 [OP_MUL] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 800\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 800\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "6390": {
        "category": "Comparison",
        "question_ko": "여러 명의 아이들이 같은 간격으로 둥글게 앉아 있습니다. 한 아이를 기준으로 시계 방향으로 15번째 아이는 기준인 아이와 마주 보고 앉아 있습니다. 아이들은 모두 몇 명입니까?",
        "question_en": "Several children are sitting in a circle equally spaced. The 15th child sitting clockwise from a standard child is facing the child who is the standard. How many children are there in total?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "15 1 [OP_SUB] 2 [OP_MUL] 2 [OP_ADD]",
        "solution_abst_en": "15 1 [OP_SUB] 2 [OP_MUL] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 15\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 15\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "6391": {
        "category": "Correspondence",
        "question_ko": "6A-B2=36을 만족하는 서로 다른 두 수 A와 B가 있다고 할 때, A에서 B를 뺀 값은 무엇인지 구하시오.",
        "question_en": "Given two different numbers A and B that satisfy 6A-B2=36, what is the value of subtracting B from A?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "6A-B2=36 A [OP_DIGIT_UNK_SOLVER] 6A-B2=36 B [OP_DIGIT_UNK_SOLVER] [OP_SUB]",
        "solution_abst_en": "6A-B2=36 A [OP_DIGIT_UNK_SOLVER] 6A-B2=36 B [OP_DIGIT_UNK_SOLVER] [OP_SUB]",
        "solution_code_ko": "var_a = '6A-B2=36'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '6A-B2=36'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = '6A-B2=36'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '6A-B2=36'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "6392": {
        "category": "Possibility",
        "question_ko": "숫자가 적힌 4개의 공 1, 2, 3, 5이 있습니다. 공 중에서 2개를 골라 한 번씩만 사용하여 두 자리 수를 만들었을 때 7로 나눠지는 수들의 합을 구하세요.",
        "question_en": "There are 4 balls numbered 1, 2, 3 and 5. Find the sum of the numbers divisible by 7 when you pick two balls and use them only once to form a two-digit number.",
        "answer_ko": "56",
        "answer_en": "56",
        "solution_abst_ko": "[OP_LIST_SOL] 1 2 3 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 7 [OP_LIST_DIVISIBLE] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 1 2 3 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 7 [OP_LIST_DIVISIBLE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 2\nvar_c = 3\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 7\nlist_c = []\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nlist_c = [float(i) for i in list_c]\nvar_g = sum(list_c)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 2\nvar_c = 3\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 7\nlist_c = []\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nlist_c = [float(i) for i in list_c]\nvar_g = sum(list_c)\nprint(int(var_g))"
    },
    "6393": {
        "category": "Comparison",
        "question_ko": "냉장고에 음식이 담긴 A, B, C 그릇이 들어있습니다. B 그릇에는 A 그릇보다 많은 음식이 담겨있고 C 그릇에는 B 그릇보다 많은 음식이 담겨있습니다. 가장 적은 음식이 담겨있는 그릇을 먼저 비우려고 할 때, 먼저 비워지는 그릇은 무엇일까요?",
        "question_en": "There is a refrigerator that has bowl A, B, and C full of food. Bowl B has more food than bowl A, and bowl C has more food than bowl B. When you try to empty the bowl with the least food in it, which bowl is emptied first?",
        "answer_ko": "A",
        "answer_en": "A",
        "solution_abst_ko": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] B A > C B > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] B A > C B > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'B'\nvar_e = 'A'\nvar_f = '>'\nvar_g = 'C'\nvar_h = 'B'\nvar_i = '>'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = len(list_c)\nvar_k = list_c[var_j-1]\nprint(var_k)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'B'\nvar_e = 'A'\nvar_f = '>'\nvar_g = 'C'\nvar_h = 'B'\nvar_i = '>'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = len(list_c)\nvar_k = list_c[var_j-1]\nprint(var_k)"
    },
    "6394": {
        "category": "Arithmetic calculation",
        "question_ko": "기린 6마리, 돼지 8마리, 개 4마리가 있습니다. 동물은 모두 몇 마리입니까?",
        "question_en": "There are 6 giraffes, 8 pigs and 4 dogs. How many animals are there in total?",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "6 8 [OP_ADD] 4 [OP_ADD]",
        "solution_abst_en": "6 8 [OP_ADD] 4 [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "6395": {
        "category": "Geometry",
        "question_ko": "부피가 1세제곱센티미터(㎤)인 쌓기나무를 한 층에 36개씩 쌓아 부피가 252세제곱센티미터(㎤)인 직육면체를 만들었습니다. 이 직육면체의 쌓기나무는 몇 층으로 쌓여 있습니까?",
        "question_en": "A rectangular prism with a volume of 252 cubic centimeters (cm3) was made by stacking 36 stacking blocks with a volume of 1 cubic centimeter (cm3). How many layers are there in this cuboid's stacking blocks?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "252 36 1 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "252 36 1 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 252\nvar_b = 36\nvar_c = 1\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 252\nvar_b = 36\nvar_c = 1\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "6396": {
        "category": "Possibility",
        "question_ko": "2개의 숫자 1, 9를 중복하여 사용하여 두 자리 수를 만들려고 합니다. 만들 수 있는 두 자리 수는 모두 몇 개 입니까?",
        "question_en": "I am trying to create a two-digit number by using two numbers 1 and 9 allowing for repetition. How many two-digit numbers can you make?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 1 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PRODUCT] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PRODUCT] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = len(list_b)\nprint(int(var_d))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = len(list_b)\nprint(int(var_d))"
    },
    "6397": {
        "category": "Possibility",
        "question_ko": "A, B, C, D, E, F 6명의 학생이 있을 때, 회장 1명, 부회장 1명, 총무 1명을 뽑는 경우의 수를 구하시오.",
        "question_en": "If there are 6 students A, B, C, D, E, and F, find the number of ways to elect 1 president, 1 vice president, and 1 manager.",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "6 1 1 [OP_ADD] 1 [OP_ADD] [OP_PERM]",
        "solution_abst_en": "6 1 1 [OP_ADD] 1 [OP_ADD] [OP_PERM]",
        "solution_code_ko": "var_a = 6\nvar_b = 1\nvar_c = 1\nvar_d = var_b + var_c\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = 1\nvar_a = int(var_a)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_a-i)\nprint(int(var_g))",
        "solution_code_en": "var_a = 6\nvar_b = 1\nvar_c = 1\nvar_d = var_b + var_c\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = 1\nvar_a = int(var_a)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_a-i)\nprint(int(var_g))"
    },
    "6398": {
        "category": "Geometry",
        "question_ko": "정육각뿔의 꼭짓점의 개수를 구하시오.",
        "question_en": "Find the number of vertices of the regular hexagonal pyramid.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "6 1 [OP_ADD]",
        "solution_abst_en": "6 1 [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "6399": {
        "category": "Arithmetic calculation",
        "question_ko": "7500원을 가지고 오이를 사려고 합니다. 오이는 현재 100그램(그램(g))에 300원으로 판매를 하고 있습니다. 현재 가지고 있는 돈으로 오이를 몇 킬로그램(㎏)살 수 있는지 소수점을 포함하여 답을 구하시오",
        "question_en": "You want to buy cucumbers for 7,500 won. Cucumbers are currently sold at 300 won per 100 grams (g). Find how many kilograms (kg) of cucumbers you can buy with your current money, including the digits after the decimal point.",
        "answer_ko": "2.50",
        "answer_en": "2.5",
        "solution_abst_ko": "7500 100 300 [OP_DIV] [OP_MUL] 1000 [OP_DIV]",
        "solution_abst_en": "7500 100 300 [OP_DIV] [OP_MUL] 1000 [OP_DIV]",
        "solution_code_ko": "var_a = 7500\nvar_b = 100\nvar_c = 300\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 1000\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 7500\nvar_b = 100\nvar_c = 300\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 1000\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "6400": {
        "category": "Geometry",
        "question_ko": "사다리꼴의 넓이가 96.9제곱센티미터(㎠)입니다. 윗변이 아랫변보다 3.6센티미터(㎝) 더 길고, 높이가 5.2센티미터(㎝)이라면, 아랫변의 길이는 센티미터(㎝)일까요?",
        "question_en": "The area of a trapezoid is 96.9 square centimeters (cm2). If the top side is 3.6 centimeters (cm) longer than the bottom side and the height is 5.2 centimeters (cm), what is the length of the bottom side in centimeters (cm)?",
        "answer_ko": "16.85",
        "answer_en": "16.85",
        "solution_abst_ko": "96.98 2 [OP_MUL] 5.2 [OP_DIV] 3.6 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "96.98 2 [OP_MUL] 5.2 [OP_DIV] 3.6 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 96.98\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 5.2\nvar_e = var_c / var_d\nvar_f = 3.6\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 96.98\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 5.2\nvar_e = var_c / var_d\nvar_f = 3.6\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "6401": {
        "category": "Possibility",
        "question_ko": "동그라미, 세모, 네모 모양이 1개씩 겹치지 않게 그려져 있습니다. 한 모양에는 한 가지 색으로만 색칠할 때, 다섯 가지 색의 색연필을 사용하여 이 3개의 모양을 서로 다른 색으로 칠할 수 있는 방법은 모두 몇 가지입니까?",
        "question_en": "A circle, triangle, and square are drawn without overlapping one by one. If each shape is only colored with one color, how many different ways can you color these three shapes with different colors using five colored pencils?",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "5 [OP_LIST_SOL] 동그라미 세모 네모 [OP_LIST_EOL] [OP_LIST_LEN] [OP_PERM]",
        "solution_abst_en": "5 [OP_LIST_SOL] circle triangle square [OP_LIST_EOL] [OP_LIST_LEN] [OP_PERM]",
        "solution_code_ko": "var_a = 5\nvar_b = '동그라미'\nvar_c = '세모'\nvar_d = '네모'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 1\nvar_a = int(var_a)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_a-i)\nprint(int(var_f))",
        "solution_code_en": "var_a = 5\nvar_b = 'circle'\nvar_c = 'triangle'\nvar_d = 'square'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 1\nvar_a = int(var_a)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_a-i)\nprint(int(var_f))"
    },
    "6402": {
        "category": "Possibility",
        "question_ko": "세 수 1, 2, 7을 한 번씩만 사용하여 만들 수 있는 서로 다른 세 자리 수는 모두 몇 개입니까?",
        "question_en": "How many different three-digit numbers can be formed using the three numbers 1, 2, and 7 only once?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 1 2 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 2 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 2\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 2\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "6403": {
        "category": "Comparison",
        "question_ko": "5가지 숫자 1.4, 9/10, 1.2, 0.5, 13/10 중에서 1.1보다 작거나 같은 수는 몇 개 인가요?",
        "question_en": "How many of the five numbers 1.4, 9/10, 1.2, 0.5, and 13/10 are less than or equal to 1.1?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i <= var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i <= var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "6404": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 16.4미터(m) 인 직선 도로의 양쪽에 가로등 18개를 같은 간격으로 설치하려고 합니다. 도로의 시작과 끝에도 가로등을 설치한다면 가로등 사이의 간격을 몇 미터(m) 로 해야 하나요?",
        "question_en": "You want to install 18 street lights equally on both sides of a straight road with a length of 16.4 meters (m). If street lights are installed at the beginning and end of the road, how many meters (m) should the distance between the street lights be?",
        "answer_ko": "2.05",
        "answer_en": "2.05",
        "solution_abst_ko": "16.4 18 2 [OP_DIV] 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "16.4 18 2 [OP_DIV] 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 16.4\nvar_b = 18\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_a / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 16.4\nvar_b = 18\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_a / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "6405": {
        "category": "Geometry",
        "question_ko": "운동장에 지름이 100 센티미터(㎝) 이고 둘레가 314 센티미터(㎝)인 원을 그렸습니다. 이 원의 둘레는 지름의 몇 배 입니까?",
        "question_en": "A circle with a diameter of 100 centimeters (cm) and a circumference of 314 centimeters (cm) is drawn on the playing field. How many times bigger is the circumference compared to its diameter?",
        "answer_ko": "3.14",
        "answer_en": "3.14",
        "solution_abst_ko": "314 100 [OP_DIV]",
        "solution_abst_en": "314 100 [OP_DIV]",
        "solution_code_ko": "var_a = 314\nvar_b = 100\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 314\nvar_b = 100\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "6406": {
        "category": "Arithmetic calculation",
        "question_ko": "A을 6로 나눴을 때 몫이 3, 나머지가 B이 였습니다. A와 B는 모두 자연수입니다. 이 때, 가능한 B 중 가장 큰 수는 무엇인가요?",
        "question_en": "When A is divided by 6, the quotient is 3 and the remainder is B. A and B are both natural numbers. What is the largest number of possible Bs?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "6 1 [OP_SUB]",
        "solution_abst_en": "6 1 [OP_SUB]",
        "solution_code_ko": "var_a = 6\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "6407": {
        "category": "Geometry",
        "question_ko": "민아는 한 변의 길이가 8센티미터(㎝)인 정사각형 모양의 칠판을 가지고 있고 송아는 한 변의 길이가 10센티미터(㎝), 다른 한 변의 길이가 5센티미터(㎝)인 직사각형 모양의 칠판을 가지고 있습니다. 두 칠판의 넓이의 차를 구하시오.",
        "question_en": "Minah has a square blackboard with one side of 8 centimeters (cm), and Songa has a rectangular blackboard with one side of 10 centimeters (cm) and the other of 5 centimeters (cm). Find the difference between the areas of the two boards.",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "8 2 [OP_POW] 10 5 [OP_MUL] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "8 2 [OP_POW] 10 5 [OP_MUL] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 8\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 10\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = abs(var_g)\nprint(int(var_h))",
        "solution_code_en": "var_a = 8\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 10\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = abs(var_g)\nprint(int(var_h))"
    },
    "6408": {
        "category": "Arithmetic calculation",
        "question_ko": "6.64그램(g)의 밀가루로 빵 한 개가 만들어집니다. 밀가루를 212.48그램(g) 샀다면 빵은 모두 몇 개를 만들 수 있나요?",
        "question_en": "One loaf of bread is made with 6.64 grams (g) of flour. How many loaves can you make if you bought 212.48 grams (g) of flour?",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "212.48 6.64 [OP_FDIV]",
        "solution_abst_en": "212.48 6.64 [OP_FDIV]",
        "solution_code_ko": "var_a = 212.48\nvar_b = 6.64\nvar_c = var_a // var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 212.48\nvar_b = 6.64\nvar_c = var_a // var_b\nprint(int(var_c))"
    },
    "6409": {
        "category": "Correspondence",
        "question_ko": "A3+61B=695일 때, A를 구하시오.",
        "question_en": "When A3+61B=695 is valid, where A3 and 61B are each two-digit and three-digit numbers. Find A.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "A3+61B=695 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A3+61B=695 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A3+61B=695'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A3+61B=695'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "6410": {
        "category": "Correspondence",
        "question_ko": "300은 25의 배수이다. 300보다 큰 자연수인 어떤 수가 있다. 어떤 수는 25로 나누었을 때 나머지가 24이다. 어떤 수 중 가장 작은 수를 구하세요.",
        "question_en": "300 is a multiple of 25. There are some numbers that are natural numbers greater than 300. When some numbers are divided by 25, the remainder is 24. Find the smallest of some numbers.",
        "answer_ko": "324",
        "answer_en": "324",
        "solution_abst_ko": "300 24 [OP_ADD]",
        "solution_abst_en": "300 24 [OP_ADD]",
        "solution_code_ko": "var_a = 300\nvar_b = 24\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 300\nvar_b = 24\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "6411": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 가게에서 파는 연필이 5천원보다 2십원 비쌀 때, 연필의 가격을 만원 단위로 구하시오.",
        "question_en": "If a pencil at a store costs 20 won more than 5,000 won, find the price of the pencil in units of 10,000 won.",
        "answer_ko": "0.50",
        "answer_en": "0.5",
        "solution_abst_ko": "5000 20 [OP_ADD] 10000 [OP_DIV]",
        "solution_abst_en": "5000 20 [OP_ADD] 10000 [OP_DIV]",
        "solution_code_ko": "var_a = 5000\nvar_b = 20\nvar_c = var_a + var_b\nvar_d = 10000\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 5000\nvar_b = 20\nvar_c = var_a + var_b\nvar_d = 10000\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "6412": {
        "category": "Possibility",
        "question_ko": "3, 5, 9의 숫자 중에서 3장을 뽑아 한 번씩만 사용하여 가장 큰 세 자리 수를 만들었습니다. 만든 세 자리 수보다 27 작은 수를 구하시오.",
        "question_en": "Three of the numbers 3, 5, and 9 were drawn and used only once to create the largest three-digit number. Find the number that is 27 less than the three digit number you created.",
        "answer_ko": "926",
        "answer_en": "926",
        "solution_abst_ko": "[OP_LIST_SOL] 3 5 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 27 [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 3 5 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 27 [OP_SUB]",
        "solution_code_ko": "var_a = 3\nvar_b = 5\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 27\nvar_h = var_f - var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 3\nvar_b = 5\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 27\nvar_h = var_f - var_g\nprint(int(var_h))"
    },
    "6413": {
        "category": "Possibility",
        "question_ko": "1이상 9이하의 자연수가 있다. 이들중 두 수를 동시에 뽑았다. 두 수를 더했을 시 9보다 작은 경우는 몇 가지 인가?",
        "question_en": "There are natural numbers from 1 to 9. Two of them were drawn at the same time. When two numbers are added, how many cases are there that it is less than 9?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "1 9 1 [OP_LIST_ARANGE] 2 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 9 [OP_LIST_LESS] [OP_LIST_LEN] 2 [OP_DIV]",
        "solution_abst_en": "1 9 1 [OP_LIST_ARANGE] 2 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 9 [OP_LIST_LESS] [OP_LIST_LEN] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 9\nlist_d = []\nfor i in list_c:\n    if i < var_f:\n        list_d.append(i)\nvar_g = len(list_d)\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 9\nlist_d = []\nfor i in list_c:\n    if i < var_f:\n        list_d.append(i)\nvar_g = len(list_d)\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "6414": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 10, 11, 12, 13이 있습니다. 그 중에서 가장 큰 수와 그 다음으로 큰 수의 차는 얼마입니까?",
        "question_en": "There are four numbers 10, 11, 12, and 13. What is the difference between the largest number and the next largest number after that?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = var_f - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = var_f - var_h\nprint(int(var_i))"
    },
    "6415": {
        "category": "Geometry",
        "question_ko": "길이가 35센티미터(㎝) 인 실을 사용하여 한 변의 길이 자연수인 가장 큰 정사각형 모양 을 만들었습니다. 정사각형을 만들고 남은 실의 길이는 몇 센티미터(㎝) 입니까?",
        "question_en": "Using yarn of 35 centimeters (cm) long, you created the largest square shape with a side length of a natural number. How many centimeters (cm) is the length of left yarn after making the square?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "35 4 [OP_MOD]",
        "solution_abst_en": "35 4 [OP_MOD]",
        "solution_code_ko": "var_a = 35\nvar_b = 4\nvar_c = var_a % var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 35\nvar_b = 4\nvar_c = var_a % var_b\nprint(int(var_c))"
    },
    "6416": {
        "category": "Arithmetic calculation",
        "question_ko": "병에 오렌지 주스가 가득 들어있었습니다. 호민이는 어제 병에 든 주스를 2/5만큼 마시고 병의 무게를 재어 봤더니 144그램(g)이었습니다. 오늘 호민이가 남은 주스의 2/3을 마시고 다시 병의 무게를 재어 보니 96그램(g)이었다면, 오렌지 주스를 모두 비운 후의 병의 무게만 쟀을 때는 몇 그램(g)일까요?",
        "question_en": "The bottle was full of orange juice. Homin drank 2/5 of the juice from the bottle yesterday and weighed the bottle and it was 144 grams (g). If Homin drank 2/3 of the remaining juice today and weighed the bottle again, it was 96 grams (g), how many grams (g) would it be if he only weighed the bottle after emptying all the orange juice?",
        "answer_ko": "72",
        "answer_en": "72",
        "solution_abst_ko": "144 144 96 [OP_SUB] 1 2/5 [OP_SUB] [OP_DIV] 2/3 [OP_DIV] 1 2/5 [OP_SUB] [OP_MUL] [OP_SUB]",
        "solution_abst_en": "144 144 96 [OP_SUB] 1 2/5 [OP_SUB] [OP_DIV] 2/3 [OP_DIV] 1 2/5 [OP_SUB] [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 144\nvar_b = 144\nvar_c = 96\nvar_d = var_b - var_c\nvar_e = 1\nvar_f = 0.4\nvar_g = var_e - var_f\nvar_h = var_d / var_g\nvar_i = 0.6666666666666666\nvar_j = var_h / var_i\nvar_k = 1\nvar_l = 0.4\nvar_m = var_k - var_l\nvar_n = var_j * var_m\nvar_o = var_a - var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 144\nvar_b = 144\nvar_c = 96\nvar_d = var_b - var_c\nvar_e = 1\nvar_f = 0.4\nvar_g = var_e - var_f\nvar_h = var_d / var_g\nvar_i = 0.6666666666666666\nvar_j = var_h / var_i\nvar_k = 1\nvar_l = 0.4\nvar_m = var_k - var_l\nvar_n = var_j * var_m\nvar_o = var_a - var_n\nprint(int(var_o))"
    },
    "6417": {
        "category": "Arithmetic calculation",
        "question_ko": "한영이는 주형이보다 4킬로그램(㎏)이 더 가볍습니다. 한영이의 몸무게와 주형이의 몸무게를 더하면 88킬로그램(㎏)라고 할 때, 한영이의 몸무게를 구하세요.",
        "question_en": "Hanyoung is 4 kg (kg) lighter than Joohyung. Find the weight of Hanyoung when the sum of Hanyoung's weight and Joohyung's weight is 88 kg (kg).",
        "answer_ko": "42",
        "answer_en": "42",
        "solution_abst_ko": "88 4 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "88 4 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 88\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 88\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "6418": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중에서 3번째로 큰 수와 2번째로 큰 수로 나눈 몫은 얼마입니까?",
        "question_en": "There are three numbers 10, 11 and 12. What is the quotient of the third largest number divided by the second largest number?",
        "answer_ko": "0",
        "answer_en": "0",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 3 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_FDIV]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 3 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_FDIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = var_e // var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = var_e // var_g\nprint(int(var_h))"
    },
    "6419": {
        "category": "Correspondence",
        "question_ko": "윤기는 세 자리 수와 두 자리 수의 뺄셈을 하려 합니다. 윤기는 두 자리 수의 일의 자리 숫자 9를 6으로 잘못 보았고, 세 자리 수의 백의 자리 숫자와 일의 자리 숫자를 바꾸어 353이라고 잘못 보았습니다. 윤기가 구한 차는 297 일 때, 두 자리 수를 구하시오.",
        "question_en": "Yoongi wanted to subtract a three-digit number from a two-digit number. Yoongi saw the number in the wrong way the ones digit of two-digit units as 6, which is 9, and the three-digit number as 353 by changing the hundredth and ones digits. When Yoongi got the difference of 297, find the two-digit number.",
        "answer_ko": "59",
        "answer_en": "59",
        "solution_abst_ko": "353 297 [OP_SUB] 6 9 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "353 297 [OP_SUB] 6 9 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 353\nvar_b = 297\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 353\nvar_b = 297\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "6420": {
        "category": "Comparison",
        "question_ko": "동국이는 하루에 5번 물을 마시고 1회에 0.2리터(L)를 마신다. 윤지는 하루에 6번 물을 마시고 1회에 0.3리터(L)를 마신다. 희진은 물을 하루 4번, 1회 500밀리리터(㎖)씩 마신다. 하루에 물을 가장 많이 마시는 사람은?",
        "question_en": "Dongguk drinks water 5 times a day and drinks 0.2 liters (L) each time. Yoonji drinks water 6 times a day and drinks 0.3 liters (L) each time. Heejin drinks 500 milliliters (ml) of water four times a day. Who drinks the most water per day?",
        "answer_ko": "희진",
        "answer_en": "Heejin",
        "solution_abst_ko": "[OP_LIST_SOL] 동국 윤지 희진 [OP_LIST_EOL] [OP_LIST_SOL] 5 0.2 1000 [OP_MUL] [OP_MUL] 6 0.3 1000 [OP_MUL] [OP_MUL] 4 500 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Dongguk Yoonji Heejin [OP_LIST_EOL] [OP_LIST_SOL] 5 0.2 1000 [OP_MUL] [OP_MUL] 6 0.3 1000 [OP_MUL] [OP_MUL] 4 500 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '동국'\nvar_b = '윤지'\nvar_c = '희진'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 5\nvar_e = 0.2\nvar_f = 1000\nvar_g = var_e * var_f\nvar_h = var_d * var_g\nvar_i = 6\nvar_j = 0.3\nvar_k = 1000\nvar_l = var_j * var_k\nvar_m = var_i * var_l\nvar_n = 4\nvar_o = 500\nvar_p = var_n * var_o\nlist_b= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nlist_b.reverse()\nvar_q = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_r = list_c[-var_q]\nvar_s = list_b.index(var_r)+1\nvar_t = list_a[var_s-1]\nprint(var_t)",
        "solution_code_en": "var_a = 'Dongguk'\nvar_b = 'Yoonji'\nvar_c = 'Heejin'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 5\nvar_e = 0.2\nvar_f = 1000\nvar_g = var_e * var_f\nvar_h = var_d * var_g\nvar_i = 6\nvar_j = 0.3\nvar_k = 1000\nvar_l = var_j * var_k\nvar_m = var_i * var_l\nvar_n = 4\nvar_o = 500\nvar_p = var_n * var_o\nlist_b= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nlist_b.reverse()\nvar_q = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_r = list_c[-var_q]\nvar_s = list_b.index(var_r)+1\nvar_t = list_a[var_s-1]\nprint(var_t)"
    },
    "6421": {
        "category": "Possibility",
        "question_ko": "상자 안에 빨간 도화지와 파란 도화지가 각각 2개, 3개 있습니다. 호석이가 2개의 상자를 가지고 있을 때 빨간 도화지의 개수는 몇 개입니까?",
        "question_en": "In the box, there are 2 red and 3 blue drawing paper respectively. How many red drawing papers will Hoseok have if he has 2 boxes?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "2 2 [OP_MUL]",
        "solution_abst_en": "2 2 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "6422": {
        "category": "Comparison",
        "question_ko": "피자 한판을 주문했는데 신영이가 1/3, 석기가 1/4, 웅이가 1/5을 먹었다. 피자를 가장 많이 먹은 사람은?",
        "question_en": "You ordered a pizza, but Shinyoung ate 1/3, Seokgi ate 1/4, and Woong ate 1/5. Who ate the most pizza?",
        "answer_ko": "신영",
        "answer_en": "Shinyoung",
        "solution_abst_ko": "[OP_LIST_SOL] 신영 석기 웅이 [OP_LIST_EOL] [OP_LIST_SOL] 1 3 [OP_DIV] 1 4 [OP_DIV] 1 5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Shinyoung Seokgi Woong [OP_LIST_EOL] [OP_LIST_SOL] 1 3 [OP_DIV] 1 4 [OP_DIV] 1 5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '신영'\nvar_b = '석기'\nvar_c = '웅이'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nvar_e = 3\nvar_f = var_d / var_e\nvar_g = 1\nvar_h = 4\nvar_i = var_g / var_h\nvar_j = 1\nvar_k = 5\nvar_l = var_j / var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'Shinyoung'\nvar_b = 'Seokgi'\nvar_c = 'Woong'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nvar_e = 3\nvar_f = var_d / var_e\nvar_g = 1\nvar_h = 4\nvar_i = var_g / var_h\nvar_j = 1\nvar_k = 5\nvar_l = var_j / var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "6423": {
        "category": "Possibility",
        "question_ko": "1부터 9까지 9개의 숫자를 한 번씩 사용하여 만든 아홉 자리 수가 55의 배수라면, 가장 작은 아홉자리 수는 무엇일까요?",
        "question_en": "If a nine-digit number formed by using the nine digits 1 through 9 once is a multiple of 55, what is the smallest nine-digit number?",
        "answer_ko": "126374985",
        "answer_en": "126374985",
        "solution_abst_ko": "1 9 1 [OP_LIST_ARANGE] 9 [OP_LIST_GET_PERM] 55 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "1 9 1 [OP_LIST_ARANGE] 9 [OP_LIST_GET_PERM] 55 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 9\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 55\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 9\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 55\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[var_f-1]\nprint(int(var_g))"
    },
    "6424": {
        "category": "Geometry",
        "question_ko": "밑면의 넓이가 50제곱센티미터(㎠)이고, 높이가 100센티미터(㎝)인 직육면체가 있습니다. 이 직육면체의 윗부분을 잘라 작은 직육면체를 만들었을 때 부피가 2000세제곱센티미터(㎤)가 되게 하려면 작은 직육면체의 높이는 몇 센티미터(㎝)가 되도록 잘라야 하는지 구하시오.",
        "question_en": "A rectangular prism has a base area of 50 square centimeters (cm2) and a height of 100 centimeters (cm). When the upper part of this rectangular prism is cut to make a small rectangular prism, find how many centimeters (cm) the height of the small rectangular prism must be cut so that the volume is 2000 cubic centimeters (cm3).",
        "answer_ko": "40",
        "answer_en": "40",
        "solution_abst_ko": "2000 50 [OP_DIV]",
        "solution_abst_en": "2000 50 [OP_DIV]",
        "solution_code_ko": "var_a = 2000\nvar_b = 50\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2000\nvar_b = 50\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "6425": {
        "category": "Arithmetic calculation",
        "question_ko": "신혜와 종국이는 영어 문제를 18문제씩 풀었습니다. 신혜는 모든 문제를 맞혀서 100점이고, 종국이는 6점짜리 8문제와 5점짜리 6문제를 맞히고, 나머지 문제는 틀려서 점수를 얻지 못했습니다. 종국이가 얻은 점수는 몇 점입니까?",
        "question_en": "Shinhye and Jongkook solved 18 English problems each. Shinhye got 100 points by getting all the questions right, Jongkook got 8 questions of 6 points and 6 questions of 5 points correctly, and the rest of the questions were wrong, so she didn't get any points. How many points did Jongkook get?",
        "answer_ko": "78",
        "answer_en": "78",
        "solution_abst_ko": "6 8 [OP_MUL] 5 6 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "6 8 [OP_MUL] 5 6 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = 6\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 6\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = 6\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "6426": {
        "category": "Arithmetic calculation",
        "question_ko": "자동차를 타고 100킬로미터(㎞)를 가는 데 1시간 15분이 걸렸습니다. 1시간 동안 간 평균 거리는 몇 킬로미터(㎞)입니까?",
        "question_en": "It took 1 hour and 15 minutes to drive 100 kilometers (km) by car. What is the average distance traveled in 1 hour in kilometers (km)?",
        "answer_ko": "80",
        "answer_en": "80",
        "solution_abst_ko": "100 1 15 60 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_abst_en": "100 1 15 60 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 100\nvar_b = 1\nvar_c = 15\nvar_d = 60\nvar_e = var_c / var_d\nvar_f = var_b + var_e\nvar_g = var_a / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 100\nvar_b = 1\nvar_c = 15\nvar_d = 60\nvar_e = var_c / var_d\nvar_f = var_b + var_e\nvar_g = var_a / var_f\nprint(int(var_g))"
    },
    "6427": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 36을 곱해야 할 것을 잘못하여 63을 더한 결과는 8이 되었습니다. 바르게 계산한 결과는 얼마인가요?",
        "question_en": "You mistakenly added 63 instead of multiplying a number by 36, and got 8. What is the correct calculation result?",
        "answer_ko": "-1980",
        "answer_en": "-1980",
        "solution_abst_ko": "8 63 [OP_SUB] 36 [OP_MUL]",
        "solution_abst_en": "8 63 [OP_SUB] 36 [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 63\nvar_c = var_a - var_b\nvar_d = 36\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 63\nvar_c = var_a - var_b\nvar_d = 36\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "6428": {
        "category": "Correspondence",
        "question_ko": "A-B-B-B=303.1입니다. 소수 B를 10배 하면 A와 같습니다. A를 구하시오.",
        "question_en": "A-B-B-B=303.1. Multiplying the decimal number B by 10 equals A. get A.",
        "answer_ko": "433",
        "answer_en": "433",
        "solution_abst_ko": "303.1 10 3 [OP_SUB] [OP_DIV] 10 [OP_MUL]",
        "solution_abst_en": "303.1 10 3 [OP_SUB] [OP_DIV] 10 [OP_MUL]",
        "solution_code_ko": "var_a = 303.1\nvar_b = 10\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 10\nvar_g = var_e * var_f\nprint(int(eval('{:.2f}'.format(round(var_g+1e-10,2)))))",
        "solution_code_en": "var_a = 303.1\nvar_b = 10\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 10\nvar_g = var_e * var_f\nprint(int(eval('{:.2f}'.format(round(var_g+1e-10,2)))))"
    },
    "6429": {
        "category": "Geometry",
        "question_ko": "가로 172센티미터(㎝), 세로 295센티미터(㎝)인 큰 종이를 한 변이 24센티미터(㎝)인 정사각형을 나누려고 한다. 몇 개까지 나눌 수 있는가?",
        "question_en": "You want to divide a large piece of paper that is 172 centimeters (cm) wide by 295 centimeters (cm) long into squares with sides measuring 24 centimeters (cm). How many can you divide?",
        "answer_ko": "84",
        "answer_en": "84",
        "solution_abst_ko": "172 24 [OP_FDIV] 295 24 [OP_FDIV] [OP_MUL]",
        "solution_abst_en": "172 24 [OP_FDIV] 295 24 [OP_FDIV] [OP_MUL]",
        "solution_code_ko": "var_a = 172\nvar_b = 24\nvar_c = var_a // var_b\nvar_d = 295\nvar_e = 24\nvar_f = var_d // var_e\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 172\nvar_b = 24\nvar_c = var_a // var_b\nvar_d = 295\nvar_e = 24\nvar_f = var_d // var_e\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "6430": {
        "category": "Possibility",
        "question_ko": "4장의 숫자 카드 1, 2, 3, 5가 있습니다. 카드 중에서 2장을 골라 한 번씩만 사용하여 두 자리 수를 만들었을 때 7로 나눠지는 수들의 합을 구하세요.",
        "question_en": "There are 4 number cards 1, 2, 3, 5. Find the sum of the numbers divisible by 7 when two cards are selected and used only once to form a two-digit number.",
        "answer_ko": "56",
        "answer_en": "56",
        "solution_abst_ko": "[OP_LIST_SOL] 1 2 3 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 7 [OP_LIST_DIVISIBLE] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 1 2 3 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 7 [OP_LIST_DIVISIBLE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 2\nvar_c = 3\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 7\nlist_c = []\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nlist_c = [float(i) for i in list_c]\nvar_g = sum(list_c)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 2\nvar_c = 3\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 7\nlist_c = []\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nlist_c = [float(i) for i in list_c]\nvar_g = sum(list_c)\nprint(int(var_g))"
    },
    "6431": {
        "category": "Comparison",
        "question_ko": "키가 작은 사람부터 순서대로 9명이 한 줄로 서 있습니다. 호석이는 5번째로 키가 작습니다. 키가 큰 사람부터 순서대로 다시 줄을 서면 호석이는 앞에서부터 몇 번째에 서게 됩니까?",
        "question_en": "Nine people stand in a line in order from shortest to tallest. Hoseok is the 5th shortest. If you line up again in order from tallest to shortest, what number will Hoseok stand from the front?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "9 5 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "9 5 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 9\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "6432": {
        "category": "Correspondence",
        "question_ko": "영기는 수지에게 5분의 2가 넘는 돈 300원을 주고, 200원은 남은 돈의 1/2도 안 되는 돈을 주었다. 남은 금액이 800원이라면 영기는 먼저 얼마를 받았을까?",
        "question_en": "Young-gi gave Su-ji 300 won which is more than two-fifths of the money, and 200 won which is less than 1/2 of the remaining money. If the remaining money t is 800 won, how much did Yeong-gi had at first?",
        "answer_ko": "2500",
        "answer_en": "2500",
        "solution_abst_ko": "800 200 [OP_SUB] 1 1/2 [OP_SUB] [OP_DIV] 300 [OP_ADD] 1 2 5 [OP_DIV] [OP_SUB] [OP_DIV]",
        "solution_abst_en": "800 200 [OP_SUB] 1 1/2 [OP_SUB] [OP_DIV] 300 [OP_ADD] 1 2 5 [OP_DIV] [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 800\nvar_b = 200\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = 0.5\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 300\nvar_i = var_g + var_h\nvar_j = 1\nvar_k = 2\nvar_l = 5\nvar_m = var_k / var_l\nvar_n = var_j - var_m\nvar_o = var_i / var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 800\nvar_b = 200\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = 0.5\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 300\nvar_i = var_g + var_h\nvar_j = 1\nvar_k = 2\nvar_l = 5\nvar_m = var_k / var_l\nvar_n = var_j - var_m\nvar_o = var_i / var_n\nprint(int(var_o))"
    },
    "6433": {
        "category": "Arithmetic calculation",
        "question_ko": "수빈이는 매일 2/5리터(L)의 우유를 마십니다. 10일 동안 수빈이가 마신 우유는 몇 리터(L)인지 구하시오.",
        "question_en": "Subin drinks 2/5 liters (L) of milk every day. Find how many liters (L) of milk he drinks for 10 days.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "2/5 10 [OP_MUL]",
        "solution_abst_en": "2/5 10 [OP_MUL]",
        "solution_code_ko": "var_a = 0.4\nvar_b = 10\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 0.4\nvar_b = 10\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "6434": {
        "category": "Arithmetic calculation",
        "question_ko": "민영이의 나이는 24년 뒤에 현재 나이의 4배가 된다고 합니다. 현재 민영이의 나이는 몇 살입니까?",
        "question_en": "It is said that Min-young's age will be four times her current age in 24 years. How old is Min-young now?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "24 4 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "24 4 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 24\nvar_b = 4\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 24\nvar_b = 4\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "6435": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 10, 11, 12, 13이 있습니다. 그 중에서 2번째로 큰 수와 가장 작은 수의 합은 얼마입니까?",
        "question_en": "There are four numbers 10, 11, 12, and 13. What is the sum of the second largest number and the smallest number?",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 2 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 2 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))"
    },
    "6436": {
        "category": "Correspondence",
        "question_ko": "다섯 자리 수 752AB가 3으로 나누어떨어지고 A와 B에는 0부터 9까지의 숫자가 들어갈 수 있습니다. 이러한 수는 모두 몇 개입니까?",
        "question_en": "The five-digit number 752AB is divisible by 3, and A and B can contain any number from 0 to 9. How many of these numbers are there?",
        "answer_ko": "33",
        "answer_en": "33",
        "solution_abst_ko": "752AB [OP_GEN_POSSIBLE_LIST] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "752AB [OP_GEN_POSSIBLE_LIST] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '752AB'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 3\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))",
        "solution_code_en": "var_a = '752AB'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 3\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))"
    },
    "6437": {
        "category": "Arithmetic calculation",
        "question_ko": "유나가 5월, 6월에 본 수학 시험의 평균 점수는 84점입니다. 유나가 7월에 본 수학 시험 점수가 96점일 때, 세 달 동안의 수학 시험 평균 점수는 몇 점입니까?",
        "question_en": "Yuna's average score on the math test in May and June is 84. If Yuna's math test score in July is 96, what is her average math score over the three months?",
        "answer_ko": "88",
        "answer_en": "88",
        "solution_abst_ko": "84 84 [OP_ADD] 96 [OP_ADD] 3 [OP_DIV]",
        "solution_abst_en": "84 84 [OP_ADD] 96 [OP_ADD] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 84\nvar_b = 84\nvar_c = var_a + var_b\nvar_d = 96\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 84\nvar_b = 84\nvar_c = var_a + var_b\nvar_d = 96\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "6438": {
        "category": "Comparison",
        "question_ko": "108개의 빨간색 공, 파란색 공, 하얀색 공이 있습니다. 파란색 공의 수는 빨간색 공의 1/3이고 하얀색 공의 수는 파란색 공의 절반입니다. 어떤 색의 공이 가장 적습니까?",
        "question_en": "There are 108 red balls, blue balls and white balls. The number of blue balls is 1/3 of the number of red balls, and the number of white balls is half of the number of blue balls. Which color ball has the fewest?",
        "answer_ko": "하얀색",
        "answer_en": "white",
        "solution_abst_ko": "[OP_LIST_SOL] 빨간색 파란색 하얀색 [OP_LIST_EOL] [OP_LIST_SOL] 1 1/3 1/3 2 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] red blue white [OP_LIST_EOL] [OP_LIST_SOL] 1 1/3 1/3 2 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '빨간색'\nvar_b = '파란색'\nvar_c = '하얀색'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nvar_e = 0.3333333333333333\nvar_f = 0.3333333333333333\nvar_g = 2\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'red'\nvar_b = 'blue'\nvar_c = 'white'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nvar_e = 0.3333333333333333\nvar_f = 0.3333333333333333\nvar_g = 2\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "6439": {
        "category": "Arithmetic calculation",
        "question_ko": "석기는 가지고 있던 색종이 82장 중 몇 장을 사용하여 미술 작품을 만들었습니다. 남은 색종이 수가 사용한 색종이 수보다 6장 적다면 사용한 색종이는 몇 장입니까?",
        "question_en": "Seokgi used some sheets of paper from 82 sheets of colored paper that he had to create an art work. If the number of paper remaining is 6 less than the number of paper used, how many sheets of paper did Seokgi used?",
        "answer_ko": "44",
        "answer_en": "44",
        "solution_abst_ko": "82 6 [OP_SUB] 2 [OP_DIV] 6 [OP_ADD]",
        "solution_abst_en": "82 6 [OP_SUB] 2 [OP_DIV] 6 [OP_ADD]",
        "solution_code_ko": "var_a = 82\nvar_b = 6\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 6\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 82\nvar_b = 6\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 6\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "6440": {
        "category": "Arithmetic calculation",
        "question_ko": "고양이와 개를 각각 30마리 18마리 기릅니다. 개와 소의 수를 합하면 고양이보다 4마리 적습니다. 소는 몇 마리 있습니까?",
        "question_en": "You have 30 cats and 18 dogs each. The combined number of dogs and cows is 4 fewer than the number of cats. How many cows do you have?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "45 32 [OP_SUB] 8 [OP_SUB]",
        "solution_abst_en": "45 32 [OP_SUB] 8 [OP_SUB]",
        "solution_code_ko": "var_a = 45\nvar_b = 32\nvar_c = var_a - var_b\nvar_d = 8\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 45\nvar_b = 32\nvar_c = var_a - var_b\nvar_d = 8\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "6441": {
        "category": "Comparison",
        "question_ko": "신발끈은 지희가 1미터(m)와 1/5미터(m), 지희가 8/5미터(m)를 사용했다. 누가 신발끈을 더 많이 사용했는지 알아보세요.",
        "question_en": "Jihee used 1 meter (m) and 1/5 meters (m) of shoelaces, and Hyun 8/5 meters (m). Figure out who used more of the shoelaces.",
        "answer_ko": "현지",
        "answer_en": "Hyun",
        "solution_abst_ko": "[OP_LIST_SOL] 지희 현지 [OP_LIST_EOL] [OP_LIST_SOL] 1 1 5 [OP_DIV] [OP_ADD] 8 5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jihee Hyun [OP_LIST_EOL] [OP_LIST_SOL] 1 1 5 [OP_DIV] [OP_ADD] 8 5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '지희'\nvar_b = '현지'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1\nvar_d = 1\nvar_e = 5\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nvar_h = 8\nvar_i = 5\nvar_j = var_h / var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'Jihee'\nvar_b = 'Hyun'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1\nvar_d = 1\nvar_e = 5\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nvar_h = 8\nvar_i = 5\nvar_j = var_h / var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "6442": {
        "category": "Geometry",
        "question_ko": "정구각형 모양의 동전이 있습니다. 이 동전의 모든 변을 합하면 171밀리미터(㎜)가 나옵니다. 동전 한 변의 길이를 구하시오.",
        "question_en": "There are coins in the shape of a regular nonagon. The sum of all sides of this coin is 171 millimeters (mm). Find the length of one side of the coin.",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "171 9 [OP_DIV]",
        "solution_abst_en": "171 9 [OP_DIV]",
        "solution_code_ko": "var_a = 171\nvar_b = 9\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 171\nvar_b = 9\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "6443": {
        "category": "Correspondence",
        "question_ko": "6을 어떤 수에 곱해야 할 것을 잘못하여 7을 어떤 수에 나눈한 결과는 49가 나옵니다. 바르게 계산하면 얼마인가요?",
        "question_en": "When you mistakenly divide a number by 7 when instead you have to multiply a number by 6, the result is 49. How much do you get when you calculate correctly?",
        "answer_ko": "2058",
        "answer_en": "2058",
        "solution_abst_ko": "49 7 [OP_MUL] 6 [OP_MUL]",
        "solution_abst_en": "49 7 [OP_MUL] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 49\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 49\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "6444": {
        "category": "Possibility",
        "question_ko": "1, 3, 5, 7, 9 다섯 장의 숫자카드가 있다. 이 카드를 사용하여 만들 수 있는 3자리 자연수 중 500미만인 수의 평균은 얼마인지 구하시오. (단, 카드는 중복사용 가능하다.)",
        "question_en": "There are five number cards 1, 3, 5, 7, and 9. What is the average of the 3-digit numbers that can be made using this card that are less than 500? (The card can be used repeatedly.)",
        "answer_ko": "255",
        "answer_en": "255",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 5 7 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 500 [OP_LIST_LESS] [OP_LIST_MEAN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 5 7 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 500 [OP_LIST_LESS] [OP_LIST_MEAN]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 5\nvar_d = 7\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 500\nlist_c = []\nfor i in list_b:\n    if i < var_g:\n        list_c.append(i)\nlist_c = [float(i) for i in list_c]\nvar_h = sum(list_c)/len(list_c)\nprint(int(var_h))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 5\nvar_d = 7\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 500\nlist_c = []\nfor i in list_b:\n    if i < var_g:\n        list_c.append(i)\nlist_c = [float(i) for i in list_c]\nvar_h = sum(list_c)/len(list_c)\nprint(int(var_h))"
    },
    "6445": {
        "category": "Comparison",
        "question_ko": "지민이는 1과 7을 모았고 남준이는 6과 3을 모았습니다. 모은 수의 합이 더 큰 사람은 누구입니까?",
        "question_en": "Jimin collected 1 and 7 and Namjoon collected 6 and 3. Who has the greater sum of the numbers gathered?",
        "answer_ko": "남준",
        "answer_en": "Namjoon",
        "solution_abst_ko": "[OP_LIST_SOL] 남준 지민 [OP_LIST_EOL] [OP_LIST_SOL] [OP_LIST_SOL] 3 6 [OP_LIST_EOL] [OP_LIST_SUM] [OP_LIST_SOL] 7 1 [OP_LIST_EOL] [OP_LIST_SUM] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_POP] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Namjoon Jimin [OP_LIST_EOL] [OP_LIST_SOL] [OP_LIST_SOL] 3 6 [OP_LIST_EOL] [OP_LIST_SUM] [OP_LIST_SOL] 7 1 [OP_LIST_EOL] [OP_LIST_SUM] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_POP] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '남준'\nvar_b = '지민'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nvar_d = 6\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nvar_f = 7\nvar_g = 1\nlist_c= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_c.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_c.append(var_f)\nlist_c.reverse()\nlist_c = [float(i) for i in list_c]\nvar_h = sum(list_c)\nlist_d= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_d.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_d.append(var_e)\nlist_d.reverse()\nvar_i = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_j = list_e[-var_i]\nvar_k = list_d.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Namjoon'\nvar_b = 'Jimin'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nvar_d = 6\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nvar_f = 7\nvar_g = 1\nlist_c= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_c.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_c.append(var_f)\nlist_c.reverse()\nlist_c = [float(i) for i in list_c]\nvar_h = sum(list_c)\nlist_d= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_d.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_d.append(var_e)\nlist_d.reverse()\nvar_i = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_j = list_e[-var_i]\nvar_k = list_d.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "6446": {
        "category": "Geometry",
        "question_ko": "가로가 3+1/4미터(m), 세로가 2+3/4미터(m)인 직사각형 모양의 종이를 한 변의 길이가 25센티미터(㎝)인 정사각형 모양의 종이로 나누어 자르려고 합니다. 최대한 많은 개수의 정사각형을 만들면 몇 개를 만들 수 있는지 구하시오.",
        "question_en": "I am going to cut a rectangular piece of paper measuring 3+1/4 meters (m) wide and 2+3/4 meters (m) long by dividing it into square pieces with a side length of 25 centimeters (cm). Find how many squares you can make if you cut as many squares as possible.",
        "answer_ko": "143",
        "answer_en": "143",
        "solution_abst_ko": "3 1/4 [OP_ADD] 25 100 [OP_DIV] [OP_FDIV] 2 3/4 [OP_ADD] 25 100 [OP_DIV] [OP_FDIV] [OP_MUL]",
        "solution_abst_en": "3 1/4 [OP_ADD] 25 100 [OP_DIV] [OP_FDIV] 2 3/4 [OP_ADD] 25 100 [OP_DIV] [OP_FDIV] [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 0.25\nvar_c = var_a + var_b\nvar_d = 25\nvar_e = 100\nvar_f = var_d / var_e\nvar_g = var_c // var_f\nvar_h = 2\nvar_i = 0.75\nvar_j = var_h + var_i\nvar_k = 25\nvar_l = 100\nvar_m = var_k / var_l\nvar_n = var_j // var_m\nvar_o = var_g * var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 3\nvar_b = 0.25\nvar_c = var_a + var_b\nvar_d = 25\nvar_e = 100\nvar_f = var_d / var_e\nvar_g = var_c // var_f\nvar_h = 2\nvar_i = 0.75\nvar_j = var_h + var_i\nvar_k = 25\nvar_l = 100\nvar_m = var_k / var_l\nvar_n = var_j // var_m\nvar_o = var_g * var_n\nprint(int(var_o))"
    },
    "6447": {
        "category": "Arithmetic calculation",
        "question_ko": "세 자리 수와 두 자리 수를 곱하는 연산에서 세 자리 수의 십의 자리 1을 빠뜨렸더니 17이 됐습니다. 이 수와 두 자리 수를 곱하여서 476이 나왔을때 바르게 계산하면 얼마입니까",
        "question_en": "In a calculation of multiplying a three-digit number by a two-digit number, you omitted 1 in the tens place of the three-digit number, resulting in 17. If you multiply this number by a two-digit number and get 476, what is the correct calculation?",
        "answer_ko": "3276",
        "answer_en": "3276",
        "solution_abst_ko": "476 17 [OP_DIV] 117 [OP_MUL]",
        "solution_abst_en": "476 17 [OP_DIV] 117 [OP_MUL]",
        "solution_code_ko": "var_a = 476\nvar_b = 17\nvar_c = var_a / var_b\nvar_d = 117\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 476\nvar_b = 17\nvar_c = var_a / var_b\nvar_d = 117\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "6448": {
        "category": "Comparison",
        "question_ko": "5명의 친구들이 있는데, 오늘 시험을 치고 점수를 비교했다. 전체의 평균은 81.6이다. 1등부터 4등까지 점수의 평균은 2등부터 5등까지 점수의 평균보다 6점 높았고, 2등, 3등, 4등의 점수는 88, 84, 76점이라고 한다. 1등의 점수는 몇 점인가?",
        "question_en": "I have 5 friends, and we compared out scores after taking an exam. The overall average was 81.6. The average of the scores from 1st to 4th is 6 points higher than the average of the scores from 2nd to 5th, and the scores for 2nd, 3rd and 4th are said to be 88, 84, and 76. How many points is 1st place worth?",
        "answer_ko": "92",
        "answer_en": "92",
        "solution_abst_ko": "81.6 5 [OP_MUL] 88 84 [OP_ADD] 76 [OP_ADD] [OP_SUB] 6 4 [OP_MUL] [OP_ADD] 2 [OP_DIV]",
        "solution_abst_en": "81.6 5 [OP_MUL] 88 84 [OP_ADD] 76 [OP_ADD] [OP_SUB] 6 4 [OP_MUL] [OP_ADD] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 81.6\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 88\nvar_e = 84\nvar_f = var_d + var_e\nvar_g = 76\nvar_h = var_f + var_g\nvar_i = var_c - var_h\nvar_j = 6\nvar_k = 4\nvar_l = var_j * var_k\nvar_m = var_i + var_l\nvar_n = 2\nvar_o = var_m / var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 81.6\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 88\nvar_e = 84\nvar_f = var_d + var_e\nvar_g = 76\nvar_h = var_f + var_g\nvar_i = var_c - var_h\nvar_j = 6\nvar_k = 4\nvar_l = var_j * var_k\nvar_m = var_i + var_l\nvar_n = 2\nvar_o = var_m / var_n\nprint(int(var_o))"
    },
    "6449": {
        "category": "Arithmetic calculation",
        "question_ko": "2의 배수이면서 3의 배수이면서 8의 배수이면서 9의 배수인 수 중 가장 큰 네 자리 수는?",
        "question_en": "What is the largest four-digit number that is a multiple of 2 and a multiple of 3 and a multiple of 8 and a multiple of 9?",
        "answer_ko": "9936",
        "answer_en": "9936",
        "solution_abst_ko": "1000 9999 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_abst_en": "1000 9999 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 3\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = 1\nlist_f=list_e.copy()\nlist_f.sort()\nvar_i = list_f[-var_h]\nprint(int(var_i))",
        "solution_code_en": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 3\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = 1\nlist_f=list_e.copy()\nlist_f.sort()\nvar_i = list_f[-var_h]\nprint(int(var_i))"
    },
    "6450": {
        "category": "Arithmetic calculation",
        "question_ko": "연필, 자, 지우개가 있다. 연필의 가격이 100원, 자의 가격이 95원이며 평균 가격은 90원일때 지우개의 가격은 얼마인가?",
        "question_en": "There is a pencil, a ruler, and an eraser. If the price of the pencil is 100 won and that of the ruler is 95, and the average price is 90 won, how much is the eraser?",
        "answer_ko": "90",
        "answer_en": "90",
        "solution_abst_ko": "95 3 [OP_MUL] 100 [OP_SUB] 95 [OP_SUB]",
        "solution_abst_en": "95 3 [OP_MUL] 100 [OP_SUB] 95 [OP_SUB]",
        "solution_code_ko": "var_a = 95\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = var_c - var_d\nvar_f = 95\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 95\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = var_c - var_d\nvar_f = 95\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "6451": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 4로 나누어야 할 것을 32로 잘못 나누었더니 몫이 3으로 나누어떨어졌다고 한다. 바르게 계산한 값을 구하시오.",
        "question_en": "When a number that should be divided by 4 is mistakenly divided by 32, the quotient is 3 with no remainder. Find the correct calculated value.",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "32 3 [OP_MUL] 4 [OP_DIV]",
        "solution_abst_en": "32 3 [OP_MUL] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 32\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 32\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "6452": {
        "category": "Arithmetic calculation",
        "question_ko": "태형이가 동화책을 전체의 0.4만큼 읽은 쪽수가 16쪽이었습니다. 이 책의 전체 쪽수는 모두 몇 쪽인지 구하시오.",
        "question_en": "The number of pages Taehyung read as much as 0.4 of the total was 16 pages. Find the total number of pages in this book.",
        "answer_ko": "40",
        "answer_en": "40",
        "solution_abst_ko": "16 0.4 [OP_DIV]",
        "solution_abst_en": "16 0.4 [OP_DIV]",
        "solution_code_ko": "var_a = 16\nvar_b = 0.4\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 16\nvar_b = 0.4\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "6453": {
        "category": "Arithmetic calculation",
        "question_ko": "15 명 초과 30 명 이하의 사람이 타야 출발하는 유람선이 있습니다. 지금 유람선에 타고 있는 사람이 9 명이라면 적어도 몇 명이 더 타야 출발할 수 있는지 구하시오.",
        "question_en": "There are cruise ships that depart only when there are more than 15 people and no more than 30 people. If there are 9 people on the cruise ship right now, find out how many more people need to board before it can depart.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "15 1 [OP_ADD] 9 [OP_SUB]",
        "solution_abst_en": "15 1 [OP_ADD] 9 [OP_SUB]",
        "solution_code_ko": "var_a = 15\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "6454": {
        "category": "Comparison",
        "question_ko": "윤기는 4, 정국이는 6에서 3을 곱한 수를 모았고, 유나는 5를 모았습니다. 누가 가장 큰 수를 모았나요?",
        "question_en": "Yoongi collected 4, Jungkook collected 6 multiplied by 3, and Yuna collected 5. Who got the biggest number?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 유나 [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_MUL] 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook Yuna [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_MUL] 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nvar_c = '유나'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 6\nvar_f = 3\nvar_g = var_e * var_f\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nvar_c = 'Yuna'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 6\nvar_f = 3\nvar_g = var_e * var_f\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "6455": {
        "category": "Arithmetic calculation",
        "question_ko": "연필 37자루를 사 온 후 다시 17자루를 더 사 왔습니다. 연필은 모두 몇 자루입니까?",
        "question_en": "After buying 37 pencils, I bought 17 more. How many pencils are there in all?",
        "answer_ko": "54",
        "answer_en": "54",
        "solution_abst_ko": "37 17 [OP_ADD]",
        "solution_abst_en": "37 17 [OP_ADD]",
        "solution_code_ko": "var_a = 37\nvar_b = 17\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 37\nvar_b = 17\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "6456": {
        "category": "Comparison",
        "question_ko": "엄마, 아빠, 할아버지가 백화점에서 옷을 구매했습니다. 엄마보다 아빠가 옷을 더 많이 샀고, 아빠보다 할아버지가 옷을 더 많이 샀습니다. 아빠는 몇 번째로 옷을 적게 샀습니까?",
        "question_en": "Mom, Dad, and Grandfather bought clothes at the department store. Dad bought more clothes than Mom, and Grandfather bought more clothes than Dad. What is the order in which Dad bought the least amount of clothes?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 엄마 아빠 할아버지 [OP_LIST_EOL] 아빠 [OP_LIST_INDEX]",
        "solution_abst_en": "[OP_LIST_SOL] Mom Dad Grandpa [OP_LIST_EOL] Dad [OP_LIST_INDEX]",
        "solution_code_ko": "var_a = '엄마'\nvar_b = '아빠'\nvar_c = '할아버지'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '아빠'\nvar_e = list_a.index(var_d)+1\nprint(int(var_e))",
        "solution_code_en": "var_a = 'Mom'\nvar_b = 'Dad'\nvar_c = 'Grandpa'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'Dad'\nvar_e = list_a.index(var_d)+1\nprint(int(var_e))"
    },
    "6457": {
        "category": "Correspondence",
        "question_ko": "A는 1000개씩 묶음이 6개, 100개씩 묶음이 36개인 수입니다. B는 876에서 197씩 작아지게 2번 뛰어서 센 수입니다. A-B의 값을 구하시오.",
        "question_en": "A is a number with 6 groups of 1000 and 36 groups of 100. B is the count of 2 jumps from 876 to 197 smaller. Find the value of A-B.",
        "answer_ko": "9118",
        "answer_en": "9118",
        "solution_abst_ko": "1000 6 [OP_MUL] 100 36 [OP_MUL] [OP_ADD] 876 197 2 [OP_MUL] [OP_SUB] [OP_SUB]",
        "solution_abst_en": "1000 6 [OP_MUL] 100 36 [OP_MUL] [OP_ADD] 876 197 2 [OP_MUL] [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 1000\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = 36\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 876\nvar_i = 197\nvar_j = 2\nvar_k = var_i * var_j\nvar_l = var_h - var_k\nvar_m = var_g - var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 1000\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = 36\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 876\nvar_i = 197\nvar_j = 2\nvar_k = var_i * var_j\nvar_l = var_h - var_k\nvar_m = var_g - var_l\nprint(int(var_m))"
    },
    "6458": {
        "category": "Arithmetic calculation",
        "question_ko": "보트를 한 번 운행할 때 30명이 탑승할 수 있습니다. 학생 1284명이 모두 한 번씩 타 보려면 보트는 적어도 몇 번 운행해야 합니까?",
        "question_en": "The boat can carry 30 people in one run. At least how many boat trips will it take for all 1284 students to ride once?",
        "answer_ko": "43",
        "answer_en": "43",
        "solution_abst_ko": "1284 30 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "1284 30 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 1284\nvar_b = 30\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))",
        "solution_code_en": "var_a = 1284\nvar_b = 30\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))"
    },
    "6459": {
        "category": "Arithmetic calculation",
        "question_ko": "모든 물건의 합은 35개입니다. (가) 물건과 (나) 물건이 있을 때, (가) 물건이 17개라면 (나) 물건은 몇 개 있습니까?",
        "question_en": "The sum of all objects is 35. When there are (a) objects and (b) objects, if  there are 17 (a) objects, (b) how many objects are there?",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "35 17 [OP_SUB]",
        "solution_abst_en": "35 17 [OP_SUB]",
        "solution_code_ko": "var_a = 35\nvar_b = 17\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 35\nvar_b = 17\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "6460": {
        "category": "Geometry",
        "question_ko": "우유통의 가로가 9센티미터(㎝), 세로가 4센티미터(㎝), 높이가 7센티미터(㎝)입니다. 이 우유통의 부피는 몇 세제곱센티미터(㎤)입니까?",
        "question_en": "The milk carton is 9 centimeters (cm) wide, 4 centimeters (cm) long, and 7 centimeters (cm) high. What is this milk carton's volume in cubic centimeters (cm3)?",
        "answer_ko": "252",
        "answer_en": "252",
        "solution_abst_ko": "9 4 [OP_MUL] 7 [OP_MUL]",
        "solution_abst_en": "9 4 [OP_MUL] 7 [OP_MUL]",
        "solution_code_ko": "var_a = 9\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "6461": {
        "category": "Comparison",
        "question_ko": "1.4, 9/10, 1.2, 0.5, 13/10 5개 숫자 중에서 1.1보다 작은 숫자를 고르고, 총합을 계산하면 얼마입니까?",
        "question_en": "Among 1.4, 9/10, 1.2, 0.5, and 13/10, pick a number less than 1.1, and calculate the total. What is the answer?",
        "answer_ko": "1.40",
        "answer_en": "1.4",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i < var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i < var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "6462": {
        "category": "Comparison",
        "question_ko": "유나와 친구 13명이 한 줄로 서 있습니다. 유나는 왼쪽에서 4번째에 서 있습니다. 유나의 오른쪽에 서 있는 사람은 왼쪽에 서 있는 사람보다 몇 명 더 많습니까?",
        "question_en": "Yuna and 13 friends are standing in a line. Yuna is standing 4th from the left. How many more people are standing to Yuna's right than the people standing to her left?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "13 4 [OP_SUB] 3 [OP_SUB]",
        "solution_abst_en": "13 4 [OP_SUB] 3 [OP_SUB]",
        "solution_code_ko": "var_a = 13\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 13\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "6463": {
        "category": "Comparison",
        "question_ko": "기차역에 기차가 총 3대 있습니다. 각 기차는 12칸으로 이루어져 있고, 각 칸의 좌석 수는 24개로 모두 같습니다. 기차역에 있는 기차들의 모든 좌석 수를 구하시오.",
        "question_en": "There are a total of 3 trains at the train station. Each train has 12 cars, and each car has the same number of seats with 24. Find the number of all seats on the trains at the station.",
        "answer_ko": "864",
        "answer_en": "864",
        "solution_abst_ko": "3 12 [OP_MUL] 24 [OP_MUL]",
        "solution_abst_en": "3 12 [OP_MUL] 24 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 24\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 3\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 24\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "6464": {
        "category": "Possibility",
        "question_ko": "서로 다른 숫자 2개를 1, 3, 4 중에서 뽑아 두 자리 수를 만들려고 할때, 가능한 두 자리 수는 총 몇 개입니까?",
        "question_en": "If you are trying to make a two-digit number by choosing two different numbers from 1, 3, and 4, how many possible two-digit numbers are there?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 4 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 4 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 4\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 4\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "6465": {
        "category": "Comparison",
        "question_ko": "4개의 숫자 0.8, 1/2, 0.9, 1/3가 있습니다. 0.7보다 크거나 같은 수의 합은 얼마인가요?",
        "question_en": "There are four numbers: 0.8, 1/2, 0.9, 1/3. What is the sum of the numbers greater than or equal to 0.7?",
        "answer_ko": "1.70",
        "answer_en": "1.7",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.7 [OP_LIST_MORE_EQUAL] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.7 [OP_LIST_MORE_EQUAL] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.7\nlist_b = []\nfor i in list_a:\n    if i >= var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint('{:.2f}'.format(round(var_f+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.7\nlist_b = []\nfor i in list_a:\n    if i >= var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint('{:.2f}'.format(round(var_f+1e-10,2)))"
    },
    "6466": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 가정에서 6월 1일부터 1500원짜리 우유를 매일 한 개씩 배달하여 먹고 있었는데, 중간에 값이 올라 1600원씩 내고 먹고 있습니다. 6월 한 달 동안의 우유값으로 46200원을 냈다면 우유는 6월 며칠부터 값이 올랐습니까?",
        "question_en": "The family has been eating milk for 1,500 won every day since June 1st, but the price went up in the middle, thereby paying 1,600 won each. If they paid 46,200 won for milk in June, On what day in June did the price of milk increase?",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "30 46200 1500 30 [OP_MUL] [OP_SUB] 1600 1500 [OP_SUB] [OP_DIV] [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "30 46200 1500 30 [OP_MUL] [OP_SUB] 1600 1500 [OP_SUB] [OP_DIV] [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 30\nvar_b = 46200\nvar_c = 1500\nvar_d = 30\nvar_e = var_c * var_d\nvar_f = var_b - var_e\nvar_g = 1600\nvar_h = 1500\nvar_i = var_g - var_h\nvar_j = var_f / var_i\nvar_k = var_a - var_j\nvar_l = 1\nvar_m = var_k + var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 30\nvar_b = 46200\nvar_c = 1500\nvar_d = 30\nvar_e = var_c * var_d\nvar_f = var_b - var_e\nvar_g = 1600\nvar_h = 1500\nvar_i = var_g - var_h\nvar_j = var_f / var_i\nvar_k = var_a - var_j\nvar_l = 1\nvar_m = var_k + var_l\nprint(int(var_m))"
    },
    "6467": {
        "category": "Geometry",
        "question_ko": "정육면체 모양의 선물 상자 겉넓이가 600제곱센티미터(㎠)입니다. 이 선물 상자의 한 변의 길이는?",
        "question_en": "The surface area of a cube-shaped gift box is 600 square centimeters (cm2). What is the length of one side of this gift box?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "600 6 [OP_DIV] 1/2 [OP_POW]",
        "solution_abst_en": "600 6 [OP_DIV] 1/2 [OP_POW]",
        "solution_code_ko": "var_a = 600\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 600\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nprint(int(var_e))"
    },
    "6468": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 36을 빼고 22를 곱하면 748이 됩니다. 어떤 수를 구하시오.",
        "question_en": "Subtracting 36 from a number and multipling by 22 gets you 748. Find the number.",
        "answer_ko": "70",
        "answer_en": "70",
        "solution_abst_ko": "748 22 [OP_DIV] 36 [OP_ADD]",
        "solution_abst_en": "748 22 [OP_DIV] 36 [OP_ADD]",
        "solution_code_ko": "var_a = 748\nvar_b = 22\nvar_c = var_a / var_b\nvar_d = 36\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 748\nvar_b = 22\nvar_c = var_a / var_b\nvar_d = 36\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "6469": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 1.4를 더한 후 3으로 나누고, 0.7을 뺀 값에 9를 곱하면 5.4가 됩니다. 어떤 수를 소수점을 포함하여 구하시오.",
        "question_en": "Add 1.4 to a number, divide by 3, subtract 0.7, multiply by 9, and you get 5.4. Calculate the number including the decimal point.",
        "answer_ko": "2.50",
        "answer_en": "2.5",
        "solution_abst_ko": "5.4 9 [OP_DIV] 0.7 [OP_ADD] 3 [OP_MUL] 1.4 [OP_SUB]",
        "solution_abst_en": "5.4 9 [OP_DIV] 0.7 [OP_ADD] 3 [OP_MUL] 1.4 [OP_SUB]",
        "solution_code_ko": "var_a = 5.4\nvar_b = 9\nvar_c = var_a / var_b\nvar_d = 0.7\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e * var_f\nvar_h = 1.4\nvar_i = var_g - var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 5.4\nvar_b = 9\nvar_c = var_a / var_b\nvar_d = 0.7\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e * var_f\nvar_h = 1.4\nvar_i = var_g - var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "6470": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이는 감을 25개 땄습니다. 정국이가 딴 감은 호석이가 딴 감의 수의 3배보다 4개가 더 많다고 합니다. 호석이가 딴 감은 몇 개입니까?",
        "question_en": "Jungkook picked 25 persimmons. It is said that Jungkook picked 4 more persimoons than 3 times the number of persimmons that Hoseok picked. How many persimmons did Hoseok pick?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "25 4 [OP_SUB] 3 [OP_FDIV]",
        "solution_abst_en": "25 4 [OP_SUB] 3 [OP_FDIV]",
        "solution_code_ko": "var_a = 25\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 25\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "6471": {
        "category": "Possibility",
        "question_ko": "울타리 안에 3마리의 거위가 있습니다. 만약 거위들에게 적어도 2개 이상의 대나무를 준다고 한다면, 대나무 20개를 나누어 주는 방법은 몇 가지입니까?",
        "question_en": "There are 3 geese inside the fence. If you give the geese at least 2 bamboos, how many ways are there to distribute 20 bamboos?",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "3 20 [OP_ADD] 3 2 [OP_MUL] [OP_SUB] 1 [OP_SUB] 20 3 2 [OP_MUL] [OP_SUB] [OP_COMB]",
        "solution_abst_en": "3 20 [OP_ADD] 3 2 [OP_MUL] [OP_SUB] 1 [OP_SUB] 20 3 2 [OP_MUL] [OP_SUB] [OP_COMB]",
        "solution_code_ko": "var_a = 3\nvar_b = 20\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = 20\nvar_k = 3\nvar_l = 2\nvar_m = var_k * var_l\nvar_n = var_j - var_m\nvar_o = 1\nvar_i = int(var_i)\nvar_n = int(var_n)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o * (var_i-i)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o / (i+1)\nprint(int(var_o))",
        "solution_code_en": "var_a = 3\nvar_b = 20\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = 20\nvar_k = 3\nvar_l = 2\nvar_m = var_k * var_l\nvar_n = var_j - var_m\nvar_o = 1\nvar_i = int(var_i)\nvar_n = int(var_n)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o * (var_i-i)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o / (i+1)\nprint(int(var_o))"
    },
    "6472": {
        "category": "Comparison",
        "question_ko": "나는 두 반의 학생들에게 지우개를 나누어 주었다. 도훈이네 반 학생 15명에게는 지우개 45개를 균등하게, 기훈이네 반 5명에게는 지우개 30개를 균등하게 나누어 주었다. 어떤 반에서 한 학생이 더 많은 지우개를 가지게 됩니까?",
        "question_en": "I handed out erasers to both classes. 15 students in Dohoon's class were given 45 erasers equally, and 5 students in Kihoon's class were given 30 erasers equally. In which class will one student have more erasers?",
        "answer_ko": "기훈",
        "answer_en": "Kihoon",
        "solution_abst_ko": "[OP_LIST_SOL] 도훈 기훈 [OP_LIST_EOL] [OP_LIST_SOL] 45 15 [OP_DIV] 30 5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Dohoon Kihoon [OP_LIST_EOL] [OP_LIST_SOL] 45 15 [OP_DIV] 30 5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '도훈'\nvar_b = '기훈'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 45\nvar_d = 15\nvar_e = var_c / var_d\nvar_f = 30\nvar_g = 5\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Dohoon'\nvar_b = 'Kihoon'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 45\nvar_d = 15\nvar_e = var_c / var_d\nvar_f = 30\nvar_g = 5\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "6473": {
        "category": "Arithmetic calculation",
        "question_ko": "연속하는 7개의 자연수의 합이 63입니다 세번째 수를 구하시오",
        "question_en": "The sum of 7 consecutive natural numbers is 63. Find the third number.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "63 0 7 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 7 [OP_DIV] 3 1 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "63 0 7 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 7 [OP_DIV] 3 1 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 63\nvar_b = 0\nvar_c = 7\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nlist_a = [i for i in range(var_b, var_e + 1, var_f)]\nlist_a = [float(i) for i in list_a]\nvar_g = sum(list_a)\nvar_h = var_a - var_g\nvar_i = 7\nvar_j = var_h / var_i\nvar_k = 3\nvar_l = 1\nvar_m = var_k - var_l\nvar_n = var_j + var_m\nprint(int(var_n))",
        "solution_code_en": "var_a = 63\nvar_b = 0\nvar_c = 7\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nlist_a = [i for i in range(var_b, var_e + 1, var_f)]\nlist_a = [float(i) for i in list_a]\nvar_g = sum(list_a)\nvar_h = var_a - var_g\nvar_i = 7\nvar_j = var_h / var_i\nvar_k = 3\nvar_l = 1\nvar_m = var_k - var_l\nvar_n = var_j + var_m\nprint(int(var_n))"
    },
    "6474": {
        "category": "Correspondence",
        "question_ko": "형의 나이와 동생의 나이의 차는 12입니다. 형의 나이와 동생의 나이의 합은 차보다 40이 많습니다. 형과 동생의 나이의 곱을 구하시오.",
        "question_en": "The difference of the age of the older brother and the younger brother is 12. The sum of the older brother's age and younger brother's age is 40 more than the difference. Find the product of the ages of the brothers.",
        "answer_ko": "640",
        "answer_en": "640",
        "solution_abst_ko": "40 2 [OP_DIV] 12 [OP_ADD] 40 2 [OP_DIV] [OP_MUL]",
        "solution_abst_en": "40 2 [OP_DIV] 12 [OP_ADD] 40 2 [OP_DIV] [OP_MUL]",
        "solution_code_ko": "var_a = 40\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 12\nvar_e = var_c + var_d\nvar_f = 40\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = var_e * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 40\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 12\nvar_e = var_c + var_d\nvar_f = 40\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = var_e * var_h\nprint(int(var_i))"
    },
    "6475": {
        "category": "Arithmetic calculation",
        "question_ko": "320킬로그램(㎏)의 물이 담긴 통에서 절반의 물을 쓴 후 통의 무게를 다시 재어 보니 175킬로그램(㎏)입니다. 통만의 무게는 몇 킬로그램(㎏)인지 구하시오.",
        "question_en": "When the bucket containing 320 kilograms (kg) of water was weighed again after using half of the water, it. became 175 kilograms (kg). Find the weight of the empty bucket in kilograms (kg).",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "320 320 175 [OP_SUB] 2 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "320 320 175 [OP_SUB] 2 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 320\nvar_b = 320\nvar_c = 175\nvar_d = var_b - var_c\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_a - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 320\nvar_b = 320\nvar_c = 175\nvar_d = var_b - var_c\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_a - var_f\nprint(int(var_g))"
    },
    "6476": {
        "category": "Arithmetic calculation",
        "question_ko": "삼촌의 나이는 41살입니다. 유나는 은지보다 3살이 많고 은지는 삼촌보다 25살이 적을때 은지와 유나의 나이 합은 몇 살인가요?",
        "question_en": "My uncle is 41 years old. If Yuna is 3 years older than Eunji and Eunji is 25 years younger than my uncle, what is the sum of the ages of Eunji and Yuna?",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "41 25 [OP_SUB] 41 25 [OP_SUB] 3 [OP_ADD] [OP_ADD]",
        "solution_abst_en": "41 25 [OP_SUB] 41 25 [OP_SUB] 3 [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 41\nvar_b = 25\nvar_c = var_a - var_b\nvar_d = 41\nvar_e = 25\nvar_f = var_d - var_e\nvar_g = 3\nvar_h = var_f + var_g\nvar_i = var_c + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 41\nvar_b = 25\nvar_c = var_a - var_b\nvar_d = 41\nvar_e = 25\nvar_f = var_d - var_e\nvar_g = 3\nvar_h = var_f + var_g\nvar_i = var_c + var_h\nprint(int(var_i))"
    },
    "6477": {
        "category": "Arithmetic calculation",
        "question_ko": "30리터(L) 짜리 물통에서 지민이가 150밀리리터(㎖)를 마시고, 태형이가 1.65밀리리터(㎖)를 먹었을 때, 남은 물의 양은 몇 리터(L)인지 구하시오.",
        "question_en": "When Jimin drinks 150 milliliters (㎖) and Taehyung drinks 1.65 liter (L) from a 30 liter (L) bucket, find how many liters (L) of water are left.",
        "answer_ko": "28.20",
        "answer_en": "28.2",
        "solution_abst_ko": "30 150 1000 [OP_DIV] [OP_SUB] 1.65 [OP_SUB]",
        "solution_abst_en": "30 150 1000 [OP_DIV] [OP_SUB] 1.65 [OP_SUB]",
        "solution_code_ko": "var_a = 30\nvar_b = 150\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nvar_f = 1.65\nvar_g = var_e - var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 30\nvar_b = 150\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nvar_f = 1.65\nvar_g = var_e - var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "6478": {
        "category": "Correspondence",
        "question_ko": "-0.4의 역수가 A이고 +5/2의 역수가 B이면 3 / A + 2 / B의 역수를 찾으십시오.",
        "question_en": "If the reciprocal of -0.4 is A and the reciprocal of +5/2 is B, find the reciprocal of 3/A + 2/B.",
        "answer_ko": "0.26",
        "answer_en": "0.26",
        "solution_abst_ko": "1 3 1 -0.4 [OP_DIV] [OP_DIV] 2 1 5/2 [OP_DIV] [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_abst_en": "1 3 1 -0.4 [OP_DIV] [OP_DIV] 2 1 5/2 [OP_DIV] [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 1\nvar_d = -0.4\nvar_e = var_c / var_d\nvar_f = var_b / var_e\nvar_g = 2\nvar_h = 1\nvar_i = 2.5\nvar_j = var_h / var_i\nvar_k = var_g / var_j\nvar_l = var_f + var_k\nvar_m = var_a / var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 1\nvar_d = -0.4\nvar_e = var_c / var_d\nvar_f = var_b / var_e\nvar_g = 2\nvar_h = 1\nvar_i = 2.5\nvar_j = var_h / var_i\nvar_k = var_g / var_j\nvar_l = var_f + var_k\nvar_m = var_a / var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))"
    },
    "6479": {
        "category": "Correspondence",
        "question_ko": "등식 23+A72=695이 성립한다고 합니다. A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "Given the equation 23+A72=695. What number is A?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "23+A72=695 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "23+A72=695 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '23+A72=695'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '23+A72=695'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "6480": {
        "category": "Comparison",
        "question_ko": "20명의 학생들이 한 줄로 줄을 섰습니다. 윤기의 앞에는 정국이가 서있고, 정국이 앞에는 11명의 학생들이 서 있습니다. 윤기의 뒤에 서 있는 학생은 몇 명입니까?",
        "question_en": "20 students lined up in a single line. Jungkook is standing right in front of Yoongi, and 11 students are standing in front of Jungkook. How many students are standing behind Yoongi?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "20 11 [OP_SUB] 1 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "20 11 [OP_SUB] 1 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "6481": {
        "category": "Arithmetic calculation",
        "question_ko": "유나네 가족이 오늘 우유를 전체의 0.4만큼 마셨더니 남은 우유가 0.69리터(L)였습니다. 처음에 있던 우유는 몇 리터(L)인지 구하시오.",
        "question_en": "Yuna's family drank 0.4 of the total milk today, and the leftover milk was 0.69 liters (L). Find how many liters (L) of milk were there at first.",
        "answer_ko": "1.15",
        "answer_en": "1.15",
        "solution_abst_ko": "0.69 1 0.4 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "0.69 1 0.4 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 0.69\nvar_b = 1\nvar_c = 0.4\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.69\nvar_b = 1\nvar_c = 0.4\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "6482": {
        "category": "Possibility",
        "question_ko": "정국, 지민, 윤기, 유정이 중에 무기명으로 중복을 허용하여 2명에게 투표를 하려고 합니다. 가능한 경우의 수는 몇 가지 일까요?",
        "question_en": "Among Jungkook, Jimin, Yoongi, and Yoojung, I'm going to vote for 2 people by allowing anonymous duplication. How many cases can possibly occur?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 지민 윤기 유정 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Jimin Yoongi Yoojung [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '지민'\nvar_c = '윤기'\nvar_d = '유정'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = var_e + var_f\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = 2\nvar_k = 1\nvar_i = int(var_i)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_i-i)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k / (i+1)\nprint(int(var_k))",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Jimin'\nvar_c = 'Yoongi'\nvar_d = 'Yoojung'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = var_e + var_f\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = 2\nvar_k = 1\nvar_i = int(var_i)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_i-i)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k / (i+1)\nprint(int(var_k))"
    },
    "6483": {
        "category": "Comparison",
        "question_ko": "축구공이 50개, 농구공이 26개, 야구공이 농구공보다 8개 더 있습니다. 어떤 공이 가장 많이 있습니까?",
        "question_en": "There are 50 soccerballs, 26 basketballs, and 8 more baseballs than basketballs. Which ball has the most of the three?",
        "answer_ko": "축구공",
        "answer_en": "soccerballs",
        "solution_abst_ko": "[OP_LIST_SOL] 축구공 농구공 야구공 [OP_LIST_EOL] [OP_LIST_SOL] 50 26 26 8 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] soccerballs basketballs baseballs [OP_LIST_EOL] [OP_LIST_SOL] 50 26 26 8 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '축구공'\nvar_b = '농구공'\nvar_c = '야구공'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 50\nvar_e = 26\nvar_f = 26\nvar_g = 8\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'soccerballs'\nvar_b = 'basketballs'\nvar_c = 'baseballs'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 50\nvar_e = 26\nvar_f = 26\nvar_g = 8\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "6484": {
        "category": "Arithmetic calculation",
        "question_ko": "백의 자리가 7이고, 십의 자리가 5인 네 자리 수 중 홀수의 개수를 구하시오.",
        "question_en": "Find the number of 4-digit odd numbers that has 7 in the hundreds place and 5 in the tens place.",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "[OP_LIST_SOL] A 7 5 B [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 1000 10000 [OP_LIST_ODD] [OP_SET_INTERSECT] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] A 7 5 B [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 1000 10000 [OP_LIST_ODD] [OP_SET_INTERSECT] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 7\nvar_c = 5\nvar_d = 'B'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e=\"\"\nfor i in list_a:\n    i = str(i)\n    var_e = var_e + i\nans_dict = dict()\nvar_e = str(var_e)\nlist_b = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_e):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_e\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_e) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_b.append(new_elem)\nvar_f = 1000\nvar_g = 10000\nlist_c = []\nif var_f%2==0:\n    for i in range(var_f+1, var_g+1, 2):\n        list_c.append(i)\nelse:\n    for i in range(var_f, var_g+1, 2):\n        list_c.append(i)\nlist_d = list(set(list_b) & set(list_c))\nvar_h = len(list_d)\nprint(int(var_h))",
        "solution_code_en": "var_a = 'A'\nvar_b = 7\nvar_c = 5\nvar_d = 'B'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e=\"\"\nfor i in list_a:\n    i = str(i)\n    var_e = var_e + i\nans_dict = dict()\nvar_e = str(var_e)\nlist_b = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_e):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_e\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_e) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_b.append(new_elem)\nvar_f = 1000\nvar_g = 10000\nlist_c = []\nif var_f%2==0:\n    for i in range(var_f+1, var_g+1, 2):\n        list_c.append(i)\nelse:\n    for i in range(var_f, var_g+1, 2):\n        list_c.append(i)\nlist_d = list(set(list_b) & set(list_c))\nvar_h = len(list_d)\nprint(int(var_h))"
    },
    "6485": {
        "category": "Arithmetic calculation",
        "question_ko": "줄넘기를 하는 학생 수의 5배만큼 훌라후프를 하고 있습니다. 줄넘기를 하는 학생이 7명이라면 훌라후프를 하는 학생은 몇 명입니까?",
        "question_en": "There are five times more students doing hula hoops than the number of students jumping rope. If there are 7 students jumping rope, how many students are doing hula hoops?",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "7 5 [OP_MUL]",
        "solution_abst_en": "7 5 [OP_MUL]",
        "solution_code_ko": "var_a = 7\nvar_b = 5\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 7\nvar_b = 5\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "6486": {
        "category": "Possibility",
        "question_ko": "1부터 3까지의 자연수를 이용하여 10000미만 1000이상의 자연수를 만들고자 한다. 이 때, 만들 수 있는 모든 수의 합은 얼마인가?",
        "question_en": "We want to create natural numbers less than 10000 and greater than 1000 using the natural numbers from 1 to 3. What is the sum of all possible numbers at this time?",
        "answer_ko": "179982",
        "answer_en": "179982",
        "solution_abst_ko": "[OP_LIST_SOL] 1 2 3 [OP_LIST_EOL] 4 [OP_LIST_GET_PRODUCT] 10000 [OP_LIST_LESS] 1000 [OP_LIST_MORE_EQUAL] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 1 2 3 [OP_LIST_EOL] 4 [OP_LIST_GET_PRODUCT] 10000 [OP_LIST_LESS] 1000 [OP_LIST_MORE_EQUAL] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 2\nvar_c = 3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 10000\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = 1000\nlist_d = []\nfor i in list_c:\n    if i >= var_f:\n        list_d.append(i)\nlist_d = [float(i) for i in list_d]\nvar_g = sum(list_d)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 2\nvar_c = 3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 10000\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = 1000\nlist_d = []\nfor i in list_c:\n    if i >= var_f:\n        list_d.append(i)\nlist_d = [float(i) for i in list_d]\nvar_g = sum(list_d)\nprint(int(var_g))"
    },
    "6487": {
        "category": "Geometry",
        "question_ko": "가로가 5미터(m)이고, 세로가 17/20미터(m)인 직사각형 모양의 화장실의 넓이는 몇 제곱미터(㎡)입니까?",
        "question_en": "What is the area in square meters (m2) of a rectangular toilet with a length of 5 meters (m) and a width of 17/20 meters (m)?",
        "answer_ko": "4.25",
        "answer_en": "4.25",
        "solution_abst_ko": "5 17/20 [OP_MUL]",
        "solution_abst_en": "5 17/20 [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 0.85\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 5\nvar_b = 0.85\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "6488": {
        "category": "Correspondence",
        "question_ko": "40을 어떤 수에 빼야 할 것을 잘못하여 21을 어떤 수에 뺀 결과는 52가 나옵니다. 바르게 계산하면 얼마인가요?",
        "question_en": "It was 40 that should be subtracted from, but mistakenly subtracting 21 from a number yields 52. How much do you get when you calculate it correctly?",
        "answer_ko": "33",
        "answer_en": "33",
        "solution_abst_ko": "52 21 [OP_ADD] 40 [OP_SUB]",
        "solution_abst_en": "52 21 [OP_ADD] 40 [OP_SUB]",
        "solution_code_ko": "var_a = 52\nvar_b = 21\nvar_c = var_a + var_b\nvar_d = 40\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 52\nvar_b = 21\nvar_c = var_a + var_b\nvar_d = 40\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "6489": {
        "category": "Comparison",
        "question_ko": "태형의 집은 아파트 위쪽에서 7번째 층, 아래쪽에서 13번째 층에 있고, 각 층마다 15채의 집이 있을 때, 이 아파트에 모여있는 집은 모두 몇 채입니까?",
        "question_en": "Taehyung's house is on the 7th floor from the top and the 13th floor from the bottom of the apartment, and if there are 15 houses on each floor, how many houses are there in this apartment?",
        "answer_ko": "315",
        "answer_en": "315",
        "solution_abst_ko": "7 13 [OP_ADD] 1 [OP_ADD] 15 [OP_MUL]",
        "solution_abst_en": "7 13 [OP_ADD] 1 [OP_ADD] 15 [OP_MUL]",
        "solution_code_ko": "var_a = 7\nvar_b = 13\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 15\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 7\nvar_b = 13\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 15\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "6490": {
        "category": "Arithmetic calculation",
        "question_ko": "유정이는 피자를 똑같이 3조각으로 나누어 한 조각을 먹었습니다. 민우는 같은 크기의 피자를 똑같이 15조각으로 나누었습니다. 유정이와 같은 양을 먹으려면 민우는 몇 조각을 먹어야 합니까?",
        "question_en": "Yujeong divided the pizza into 3 equal slices and ate one slice. Minwoo divided the same size pizza into 15 equal slices. How many slices does Minwoo need to eat to eat the same amount as Yujeong?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "15 3 [OP_DIV]",
        "solution_abst_en": "15 3 [OP_DIV]",
        "solution_code_ko": "var_a = 15\nvar_b = 3\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 15\nvar_b = 3\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "6491": {
        "category": "Possibility",
        "question_ko": "숫자 1, 6, 8을 한 번씩 모두 사용할 때, 100보다 크고 1000보다 작은 수 중 두 번째로 큰 수와 세 번째로 작은 수의 합을 구하시오.",
        "question_en": "Find the sum of the second largest and third smallest numbers greater than 100 and less than 1000, using the numbers 1, 6, and 8 once.",
        "answer_ko": "1434",
        "answer_en": "1434",
        "solution_abst_ko": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))"
    },
    "6492": {
        "category": "Arithmetic calculation",
        "question_ko": "민영이와 태형이가 각각 사탕 9개, 3개를 가지고 있습니다. 둘이 가진 사탕의 수가 같아지려면 태형이는 민영이에게 사탕을 몇 개 받아야 할까요?",
        "question_en": "Minyoung and Taehyung have 9 and 3 candies, respectively. How many candies should Taehyung take from Minyeong to keep the number of candies equal?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "9 3 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "9 3 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 9\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "6493": {
        "category": "Arithmetic calculation",
        "question_ko": "강당에 남학생 24명과 여학생 14명이 있었습니다. 잠시 후에 남학생과 여학생이 같은 수만큼 강당에서 나갔습니다. 강당에 남아 있는 학생이 30명이라면 강당에서 나간 여학생은 몇 명인지 구하시오.",
        "question_en": "There were 24 boys and 14 girls in the auditorium. After a while, an equal number of boys and girls left the auditorium. If only 30 students remained in the auditorium, how many girls left earlier?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "24 14 [OP_ADD] 30 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "24 14 [OP_ADD] 30 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 24\nvar_b = 14\nvar_c = var_a + var_b\nvar_d = 30\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 24\nvar_b = 14\nvar_c = var_a + var_b\nvar_d = 30\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "6494": {
        "category": "Possibility",
        "question_ko": "빨간색 구슬 1개, 초록색 구슬 1개, 파란색 구슬 1개, 보라색 구슬 1개가 있습니다. 구슬 4개를 서로 다르게 한 줄로 놓는 방법은 모두 몇 가지입니까?",
        "question_en": "There are 1 red marble, 1 green marble, 1 blue marble and 1 purple marble. In how many different ways can you place 4 marbles in a row?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "[OP_LIST_SOL] 빨간색 초록색 파란색 보라색 [OP_LIST_EOL] [OP_LIST_LEN] 4 [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] red green blue purple [OP_LIST_EOL] [OP_LIST_LEN] 4 [OP_PERM]",
        "solution_code_ko": "var_a = '빨간색'\nvar_b = '초록색'\nvar_c = '파란색'\nvar_d = '보라색'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 4\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nprint(int(var_g))",
        "solution_code_en": "var_a = 'red'\nvar_b = 'green'\nvar_c = 'blue'\nvar_d = 'purple'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 4\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nprint(int(var_g))"
    },
    "6495": {
        "category": "Geometry",
        "question_ko": "빗변이 아닌 한 변의 길이가 3이고, 빗변의 길이가 5인 직각삼각형에서 나머지 한 변의 길이를 구하시오.",
        "question_en": "Find the length of the other side of a right triangle with one non-hypotenuse of length 3 and hypotenuse of length 5.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "5 2 [OP_POW] 3 2 [OP_POW] [OP_SUB] 1/2 [OP_POW]",
        "solution_abst_en": "5 2 [OP_POW] 3 2 [OP_POW] [OP_SUB] 1/2 [OP_POW]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 3\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c - var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 3\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c - var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))"
    },
    "6496": {
        "category": "Arithmetic calculation",
        "question_ko": "테이프 4개를 동일한 길이 만큼 겹쳐서 이어 붙였더니 925센티미터(㎝)가 되었습니다. 테이프 한 개의 길이가 250센티미터(㎝)라면 겹쳐진 부분의 각 길이는 몇 센티미터(㎝)가 되나요?",
        "question_en": "When 4 pieces of tape were overlapped and attached to the same length, it became 925 centimeters (cm). If the length of one piece of tape is 250 centimeters (cm), how many centimeters (cm) is the length of each of the overlapping parts?",
        "answer_ko": "25",
        "answer_en": "25",
        "solution_abst_ko": "250 4 [OP_MUL] 925 [OP_SUB] 4 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "250 4 [OP_MUL] 925 [OP_SUB] 4 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 250\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 925\nvar_e = var_c - var_d\nvar_f = 4\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 250\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 925\nvar_e = var_c - var_d\nvar_f = 4\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "6497": {
        "category": "Arithmetic calculation",
        "question_ko": "12개의 귤 중 7개를 지민이가 먹었습니다. 남아 있는 귤은 몇 개입니까?",
        "question_en": "Jimin ate 7 of the 12 tangerines. How many tangerines are left?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "12 7 [OP_SUB]",
        "solution_abst_en": "12 7 [OP_SUB]",
        "solution_code_ko": "var_a = 12\nvar_b = 7\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 12\nvar_b = 7\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "6498": {
        "category": "Possibility",
        "question_ko": "정사각형의 한 변의 길이가 2센티미터(cm)라고 할 때, 이 정사각형 210개를 모두 붙여서 서로 다른 직사각형을 만들려고 합니다. 만든 직사각형을 돌려 같은 모양인 경우 한 가지로 본다고 할 때, 직사각형을 만들 수 있는 방법은 모두 몇 가지인지 구하시오.",
        "question_en": "Provided that the length of one side of the square is 2 centimeters (cm), we want to make a different rectangle by attaching all 210 of these squares. In case you rotate the rectangle that you made and when it has the same shape, you consider it as the same one, find how many ways you can make the rectangle.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "210 [OP_LIST_GET_DIVISOR] [OP_LIST_LEN] 2 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "210 [OP_LIST_GET_DIVISOR] [OP_LIST_LEN] 2 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 210\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = len(list_a)\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = 1\nvar_f=int(((var_d+9*10**(var_e-2))//(10**(var_e-1)))*10**(var_e-1))\n\nprint(int(var_f))",
        "solution_code_en": "var_a = 210\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = len(list_a)\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = 1\nvar_f=int(((var_d+9*10**(var_e-2))//(10**(var_e-1)))*10**(var_e-1))\n\nprint(int(var_f))"
    },
    "6499": {
        "category": "Geometry",
        "question_ko": "어떤 각기둥의 옆면은 직사각형 여섯 개로 이루어져 있습니다. 이 각기둥의 꼭짓점은 몇 개입니까?",
        "question_en": "The sides of a prism are made up of six rectangles. How many vertices does this prism have?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "6 2 [OP_MUL]",
        "solution_abst_en": "6 2 [OP_MUL]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "6500": {
        "category": "Arithmetic calculation",
        "question_ko": "0, 1, 2, 3 중 서로 다른 숫자 2개를 뽑아 만들 수 있는 두 자리 수 중에서 4로 나누어떨어지는 수는 모두 몇 개입니까?",
        "question_en": "How many two-digit numbers that can be formed by drawing two different numbers from 0, 1, 2, and 3 are divisible by 4?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 4 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 4 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 4\nlist_c = []\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nvar_g = len(list_c)\nprint(int(var_g))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 4\nlist_c = []\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nvar_g = len(list_c)\nprint(int(var_g))"
    },
    "6501": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 45를 더해야 하는데 잘못하여 54를 더했더니 78이 되었습니다. 바르게 계산한 결과를 구하시오.",
        "question_en": "You need to add 45 to a number, but mistakenly added 54, and got 78. Find the result of the correct calculation.",
        "answer_ko": "69",
        "answer_en": "69",
        "solution_abst_ko": "78 54 [OP_SUB] 45 [OP_ADD]",
        "solution_abst_en": "78 54 [OP_SUB] 45 [OP_ADD]",
        "solution_code_ko": "var_a = 78\nvar_b = 54\nvar_c = var_a - var_b\nvar_d = 45\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 78\nvar_b = 54\nvar_c = var_a - var_b\nvar_d = 45\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "6502": {
        "category": "Geometry",
        "question_ko": "가로의 길이가 세로의 길이의 0.875배인 직사각형이 있습니다. 세로의 길이가 24센티미터(㎝)라면, 넓이는 몇 제곱센티미터(㎠)일지 구하시오.",
        "question_en": "There is a rectangle whose width is 0.875 times its length. If the length is 24 centimeters (cm), find the area in square centimeters (cm2).",
        "answer_ko": "504",
        "answer_en": "504",
        "solution_abst_ko": "24 0.875 [OP_MUL] 24 [OP_MUL]",
        "solution_abst_en": "24 0.875 [OP_MUL] 24 [OP_MUL]",
        "solution_code_ko": "var_a = 24\nvar_b = 0.875\nvar_c = var_a * var_b\nvar_d = 24\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 24\nvar_b = 0.875\nvar_c = var_a * var_b\nvar_d = 24\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "6503": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 10까지의 짝수 중 6이하의 수의 총합을 구하시오.",
        "question_en": "Find the sum of the even numbers from 1 to 10 that are less than or equal to 6.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "1 10 [OP_LIST_EVEN] 6 [OP_LIST_LESS_EQUAL] [OP_LIST_SUM]",
        "solution_abst_en": "1 10 [OP_LIST_EVEN] 6 [OP_LIST_LESS_EQUAL] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 10\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 6\nlist_b = []\nfor i in list_a:\n    if i <= var_c:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_d = sum(list_b)\nprint(int(var_d))",
        "solution_code_en": "var_a = 1\nvar_b = 10\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 6\nlist_b = []\nfor i in list_a:\n    if i <= var_c:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_d = sum(list_b)\nprint(int(var_d))"
    },
    "6504": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 2, 3, 8, 9로 나누어 떨어질 수 있는 네 자리 수는 모두 몇 개 있습니까?",
        "question_en": "How many four-digit numbers are divisible by the four numbers 2, 3, 8, and 9?",
        "answer_ko": "125",
        "answer_en": "125",
        "solution_abst_ko": "1000 9999 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "1000 9999 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 3\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = len(list_e)\nprint(int(var_h))",
        "solution_code_en": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 3\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = len(list_e)\nprint(int(var_h))"
    },
    "6505": {
        "category": "Correspondence",
        "question_ko": "52에 어떤 수를 더하여 3을 곱한 뒤 60을 빼고 8로 나누었더니 15가 되었습니다. 어떤 수를 구하시오.",
        "question_en": "Add a number to 52, multiply by 3, subtract 60, and divide by 8, and get 15.Find the number.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "15 8 [OP_MUL] 60 [OP_ADD] 3 [OP_DIV] 52 [OP_SUB]",
        "solution_abst_en": "15 8 [OP_MUL] 60 [OP_ADD] 3 [OP_DIV] 52 [OP_SUB]",
        "solution_code_ko": "var_a = 15\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 60\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = 52\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 15\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 60\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = 52\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "6506": {
        "category": "Arithmetic calculation",
        "question_ko": "문구점에서 750원으로 공책 3권을 샀습니다. 같은 공책 9권을 산다면 얼마를 내야 합니까?",
        "question_en": "I bought 3 notebooks at a stationery store for 750 won. How much should I pay if I buy 9 copies of the same notebook?",
        "answer_ko": "2250",
        "answer_en": "2250",
        "solution_abst_ko": "750 3 [OP_DIV] 9 [OP_MUL]",
        "solution_abst_en": "750 3 [OP_DIV] 9 [OP_MUL]",
        "solution_code_ko": "var_a = 750\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 9\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 750\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 9\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "6507": {
        "category": "Geometry",
        "question_ko": "어떤 직육면체의 모든 모서리의 길이의 합은 256센티미터(㎝)입니다. 밑면의 세로 길이는 가로 길이의 4배이고, 높이는 가로 길이의 3배입니다. 이 직육면체의 세로 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "The sum of the lengths of all the edges of a regular prism is 256 centimeters (cm). The length of the base is 4 times the width, and the height is 3 times the width. What is the length of this rectangular prism in centimeters (cm)?",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "256 4 [OP_DIV] 4 3 [OP_ADD] 1 [OP_ADD] [OP_DIV] 4 [OP_MUL]",
        "solution_abst_en": "256 4 [OP_DIV] 4 3 [OP_ADD] 1 [OP_ADD] [OP_DIV] 4 [OP_MUL]",
        "solution_code_ko": "var_a = 256\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = var_c / var_h\nvar_j = 4\nvar_k = var_i * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 256\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = var_c / var_h\nvar_j = 4\nvar_k = var_i * var_j\nprint(int(var_k))"
    },
    "6508": {
        "category": "Geometry",
        "question_ko": "직육면체 모양의 어항이 있다. 각 모서리의 길이는 4센티미터(㎝), 6센티미터(㎝), 15센티미터(㎝)일 때, 어항의 부피를 구하시오.",
        "question_en": "There is a fishbowl in the shape of a cuboid. When the length of each corner is 4 centimeters (cm), 6 centimeters (cm), and 15 centimeters (cm), find the volume of the fish tank.",
        "answer_ko": "360",
        "answer_en": "360",
        "solution_abst_ko": "15 6 [OP_MUL] 4 [OP_MUL]",
        "solution_abst_en": "15 6 [OP_MUL] 4 [OP_MUL]",
        "solution_code_ko": "var_a = 15\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "6509": {
        "category": "Correspondence",
        "question_ko": "한 자리 수 A, B로 만들 수 있는 여섯 자리 수 A15B94가 있습니다. 이 수가 99의 배수일 때 B가 될 수 있는 값을 구하시오.",
        "question_en": "There is a six-digit number A15B94 that can be made with the single-digit numbers A and B. When this number is divisible by 99, find the value that can be B.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "A15B94 [OP_GEN_POSSIBLE_LIST] 99 [OP_LIST_DIVISIBLE] A15B94 B [OP_LIST_FIND_UNK]",
        "solution_abst_en": "A15B94 [OP_GEN_POSSIBLE_LIST] 99 [OP_LIST_DIVISIBLE] A15B94 B [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = 'A15B94'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 99\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 'A15B94'\nvar_d = 'B'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nvar_e = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_e = int(elem[unk_idx])\nprint(int(var_e))",
        "solution_code_en": "var_a = 'A15B94'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 99\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 'A15B94'\nvar_d = 'B'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nvar_e = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_e = int(elem[unk_idx])\nprint(int(var_e))"
    },
    "6510": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 9를 곱한 후 3으로 나누었더니 27이 됩니다. 어떤 수를 구하시오.",
        "question_en": "When a number is multiplied by 9 and then divided by 3, it is 27. Find the number.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "27 3 [OP_MUL] 9 [OP_DIV]",
        "solution_abst_en": "27 3 [OP_MUL] 9 [OP_DIV]",
        "solution_code_ko": "var_a = 27\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 27\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "6511": {
        "category": "Arithmetic calculation",
        "question_ko": "장난감이 한 상자에 8개씩 6상자에 들어 있습니다. 장난감을 한 상자에 4개씩 넣어서 포장하려면 상자는 몇 개 필요합니까?",
        "question_en": "Toys come in 6 boxes, 8 in each box. How many boxes are needed to pack 4 toys in a box?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "8 6 [OP_MUL] 4 [OP_FDIV]",
        "solution_abst_en": "8 6 [OP_MUL] 4 [OP_FDIV]",
        "solution_code_ko": "var_a = 8\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "6512": {
        "category": "Possibility",
        "question_ko": "숫자 카드 4, 5, 6 중 2장을 한 번씩 모두 사용하여 가장 작은 두 자리 수를 만들 때, 사용하지 않는 카드의 숫자는 무엇입니까?",
        "question_en": "When two of the number cards 4, 5, and 6 are used once to form the smallest two-digit number, what is the number of unused cards?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 4 5 6 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] [OP_LIST_POP] [OP_NUM2LIST]  [OP_SET_DIFFERENCE] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] 4 5 6 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] [OP_LIST_POP] [OP_NUM2LIST]  [OP_SET_DIFFERENCE] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 4\nvar_b = 5\nvar_c = 6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nlist_d = []\nvar_f = int(var_f)\nwhile var_f//10 > 0:\n    list_d.append(var_f%10)\n    var_f = var_f//10\nlist_d.append(var_f%10)\nlist_d = list_d[::-1]\nlist_e = list(set(list_a) - set(list_d))\nvar_g = 1\nvar_h = list_e[var_g-1]\nprint(int(var_h))",
        "solution_code_en": "var_a = 4\nvar_b = 5\nvar_c = 6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nlist_d = []\nvar_f = int(var_f)\nwhile var_f//10 > 0:\n    list_d.append(var_f%10)\n    var_f = var_f//10\nlist_d.append(var_f%10)\nlist_d = list_d[::-1]\nlist_e = list(set(list_a) - set(list_d))\nvar_g = 1\nvar_h = list_e[var_g-1]\nprint(int(var_h))"
    },
    "6513": {
        "category": "Comparison",
        "question_ko": "다음은 네 사람의 멀리뛰기 기록이다. 경수 2.3미터(m), 영희 9/10미터(m), 진주 1.8미터(m), 찬호 2.5미터(m). 다음 중 두 번째로 멀리 뛴 사람을 구하시오.",
        "question_en": "The following is the long jump record of four people : Kyungsoo 2.3 meters (m), Younghee 9/10 meters (m), Jinju 1.8 meters (m), Chanho 2.5 meters (m). Who among these following people jumped the second furthest?",
        "answer_ko": "경수",
        "answer_en": "Kyungsoo",
        "solution_abst_ko": "[OP_LIST_SOL] 경수 영희 진주 찬호 [OP_LIST_EOL] [OP_LIST_SOL] 2.3 9/10 1.8 2.5 [OP_LIST_EOL] 2 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Kyungsoo Younghee Jinju Chanho [OP_LIST_EOL] [OP_LIST_SOL] 2.3 9/10 1.8 2.5 [OP_LIST_EOL] 2 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '경수'\nvar_b = '영희'\nvar_c = '진주'\nvar_d = '찬호'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2.3\nvar_f = 0.9\nvar_g = 1.8\nvar_h = 2.5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Kyungsoo'\nvar_b = 'Younghee'\nvar_c = 'Jinju'\nvar_d = 'Chanho'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2.3\nvar_f = 0.9\nvar_g = 1.8\nvar_h = 2.5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "6514": {
        "category": "Correspondence",
        "question_ko": "A를 B로 나눴을 때 몫이 C, 나머지가 4 였습니다. A, B, C는 자연수 입니다. B와 C가 같을 때, 가능한 A 중 가장 작은 수를 구하시오.",
        "question_en": "When A is divided by B, the quotient is C and the remainder is 4. A, B, and C are natural numbers. If B and C are equal, find the smallest possible number of A.",
        "answer_ko": "29",
        "answer_en": "29",
        "solution_abst_ko": "4 1 [OP_ADD] 2 [OP_POW] 4 [OP_ADD]",
        "solution_abst_en": "4 1 [OP_ADD] 2 [OP_POW] 4 [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 4\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 4\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "6515": {
        "category": "Correspondence",
        "question_ko": "민수는 28일 동안 자전거 여행을 떠날 계획이다. 여행해야 하는 총 거리가 82.04킬로미터(㎞)이고 하루에 같은 거리를 여행하는 경우 하루에 몇킬로미터(㎞)를 여행해야 하는지 구하십시오.",
        "question_en": "Minsu plans to go on a bicycle trip for 28 days. If he must travel a total distance of 82.04 kilometers (km) and the same distance a day, find how many kilometers (km) are required to take in one day.",
        "answer_ko": "2.93",
        "answer_en": "2.93",
        "solution_abst_ko": "1 28 82.04 [OP_DIV] [OP_DIV]",
        "solution_abst_en": "1 28 82.04 [OP_DIV] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 28\nvar_c = 82.04\nvar_d = var_b / var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 28\nvar_c = 82.04\nvar_d = var_b / var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "6516": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 14.25미터(m)인 정사각형 모양의 강당이 있습니다. 이 강당의 넓이는 몇 제곱미터(㎡)인지 구하시오.",
        "question_en": "There is an auditorium in the shape of a square with a side length of 14.25 meters (m). Find the area in square meters (m2) of this auditorium.",
        "answer_ko": "203.06",
        "answer_en": "203.06",
        "solution_abst_ko": "14.25 2 [OP_POW]",
        "solution_abst_en": "14.25 2 [OP_POW]",
        "solution_code_ko": "var_a = 14.25\nvar_b = 2\nvar_c = var_a ** var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 14.25\nvar_b = 2\nvar_c = var_a ** var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "6517": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 1500미터(m)인 도로의 한쪽에 25미터(m) 간격으로 가로수를 심으려고 합니다. 가로수는 몇 그루가 필요합니까? (단, 도로의 처음과 끝에도 나무를 심습니다.)",
        "question_en": "You want to plant street trees on one side of a road that is 1500 meters (m) long at intervals of 25 meters (m). How many street trees do you need? (Note: trees are planted at the beginning and end of the road as well.)",
        "answer_ko": "61",
        "answer_en": "61",
        "solution_abst_ko": "1500 25 [OP_DIV] 1 [OP_ADD]",
        "solution_abst_en": "1500 25 [OP_DIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 1500\nvar_b = 25\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 1500\nvar_b = 25\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "6518": {
        "category": "Arithmetic calculation",
        "question_ko": "지훈이는 이번 달에 책을 3권 읽었고, 태연이는 2권, 동엽이는 5권, 한해는 3권, 기범이는 1권 읽었습니다. 이번 달에 책을 3권 읽은 친구는 몇 명입니까?",
        "question_en": "Jihoon read 3 books this month, Taeyeon read 2 books, Dongyeop 5 books, Hanhae 3 books, and Kibum 1 book. How many of them have read 3 books this month?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 3 2 5 3 1 [OP_LIST_EOL] 3 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 3 2 5 3 1 [OP_LIST_EOL] 3 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = 5\nvar_d = 3\nvar_e = 1\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = []\nfor i in list_a:\n    if i >= var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = 5\nvar_d = 3\nvar_e = 1\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = []\nfor i in list_a:\n    if i >= var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "6519": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이네 학교에 18명의 학생이 결석했습니다. 남학생은 848명이고 여학생은 남학생보다 49명 더 적다고 할 때, 오늘 학교에 온 학생은 모두 몇 명입니까?",
        "question_en": "There are 18 absent students are absent in Jungkook's school. If there are 848 male students and 49 fewer female students than male students, how many students came to school today?",
        "answer_ko": "1629",
        "answer_en": "1629",
        "solution_abst_ko": "848 848 49 [OP_SUB] [OP_ADD] 18 [OP_SUB]",
        "solution_abst_en": "848 848 49 [OP_SUB] [OP_ADD] 18 [OP_SUB]",
        "solution_code_ko": "var_a = 848\nvar_b = 848\nvar_c = 49\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 18\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 848\nvar_b = 848\nvar_c = 49\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 18\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "6520": {
        "category": "Possibility",
        "question_ko": "숫자 1, 2, 3를 이용하여 세 자리 자연수를 만들고자 한다. 같은 수를 사용해도 될 때, 만들어지는 모든 수의 합을 구하여라.",
        "question_en": "We want to create a three-digit natural number using the numbers 1, 2, and 3. When you can use the same number, find the sum of all numbers that can be made.",
        "answer_ko": "5994",
        "answer_en": "5994",
        "solution_abst_ko": "[OP_LIST_SOL] 1 2 3 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 1 2 3 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 2\nvar_c = 3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 2\nvar_c = 3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint(int(var_e))"
    },
    "6521": {
        "category": "Correspondence",
        "question_ko": "초콜릿 15 봉지에 초콜릿이 45개가 들어있습니다. 5 봉지에는 몇 개가 들어있는지 구하시오.",
        "question_en": "There are 45 chocolates 15 bags. 5 Find how many chocolates are in 5 bags.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "45 15 [OP_DIV] 5 [OP_MUL]",
        "solution_abst_en": "45 15 [OP_DIV] 5 [OP_MUL]",
        "solution_code_ko": "var_a = 45\nvar_b = 15\nvar_c = var_a / var_b\nvar_d = 5\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 45\nvar_b = 15\nvar_c = var_a / var_b\nvar_d = 5\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "6522": {
        "category": "Arithmetic calculation",
        "question_ko": "연속하는 두 짝수의 합이 46일 때 두 짝수 중 큰 수를 구하시오.",
        "question_en": "If the sum of two consecutive even numbers is 46, find the larger of the two even numbers.",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "46 2 [OP_DIV] 1 [OP_ADD]",
        "solution_abst_en": "46 2 [OP_DIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 46\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 46\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "6523": {
        "category": "Correspondence",
        "question_ko": "100보다 작거나 같은 짝수를 쓰려고 합니다. 숫자 0은 모두 몇번 써야 합니까?",
        "question_en": "You want to write an even number less than or equal to 100. How many times do you write the number 0 in all?",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "1 200 [OP_LIST_EVEN] [OP_LIST2NUM] [OP_NUM2LIST] 0 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 200 [OP_LIST_EVEN] [OP_LIST2NUM] [OP_NUM2LIST] 0 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 200\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c=\"\"\nfor i in list_a:\n    i = str(i)\n    var_c = var_c + i\nlist_b = []\nvar_c = int(var_c)\nwhile var_c//10 > 0:\n    list_b.append(var_c%10)\n    var_c = var_c//10\nlist_b.append(var_c%10)\nlist_b = list_b[::-1]\nvar_d = 0\nvar_e = 0\nvar_d = int(var_d)\nfor i in list_b:\n    i = int(i)\n    if i == var_d:\n        var_e = var_e + 1\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 200\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c=\"\"\nfor i in list_a:\n    i = str(i)\n    var_c = var_c + i\nlist_b = []\nvar_c = int(var_c)\nwhile var_c//10 > 0:\n    list_b.append(var_c%10)\n    var_c = var_c//10\nlist_b.append(var_c%10)\nlist_b = list_b[::-1]\nvar_d = 0\nvar_e = 0\nvar_d = int(var_d)\nfor i in list_b:\n    i = int(i)\n    if i == var_d:\n        var_e = var_e + 1\nprint(int(var_e))"
    },
    "6524": {
        "category": "Comparison",
        "question_ko": "냉장고에 음식이 담긴 A, B, C 그릇이 들어있습니다. C 그릇에는 B 그릇보다 많은 음식이 담겨있고, B 그릇에는 A 그릇보다 많은 음식이 담겨있습니다. 가장 적은 음식이 담겨있는 그릇을 먼저 비울 때, 먼저 비워지는 그릇은 무엇일까요?",
        "question_en": "There are three bowls A, B, and C containing food in a refrigerator. Bowl C has more food than bowl B, and bowl B has more food than bowl A. When the bowl with the least amount of food is emptied first, which bowl is emptied first?",
        "answer_ko": "A",
        "answer_en": "A",
        "solution_abst_ko": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] B A > C B > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] B A > C B > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'B'\nvar_e = 'A'\nvar_f = '>'\nvar_g = 'C'\nvar_h = 'B'\nvar_i = '>'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = len(list_c)\nvar_k = list_c[var_j-1]\nprint(var_k)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'B'\nvar_e = 'A'\nvar_f = '>'\nvar_g = 'C'\nvar_h = 'B'\nvar_i = '>'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = len(list_c)\nvar_k = list_c[var_j-1]\nprint(var_k)"
    },
    "6525": {
        "category": "Arithmetic calculation",
        "question_ko": "한 사람당 피자를 2/5판씩 먹으려고 한다면, 10명이 먹기 위해서는 피자를 몇 판 시켜야 합니까?",
        "question_en": "If each person wants to eat 2/5 pizzas, how many pizzas you should buy to share it with 10 people?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "2/5 10 [OP_MUL]",
        "solution_abst_en": "2/5 10 [OP_MUL]",
        "solution_code_ko": "var_a = 0.4\nvar_b = 10\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 0.4\nvar_b = 10\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "6526": {
        "category": "Possibility",
        "question_ko": "정국이는 서로 다른 과일을 구매해서 지민과 윤기에게 선물하려고 합니다. 과일 가게에서 판매하는 과일이 사과, 복숭아, 배, 참외라면 선물할 수 있는 경우의 수는 모두 몇 가지입니까?",
        "question_en": "Jungkook wants to buy different fruits and give a present to Jimin and Yoongi. If the fruit shop sells apples, peaches, pears, and melons, how many number of ways are there for him to give a gift?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 복숭아 배 참외 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] apples peaches pears melons [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '복숭아'\nvar_c = '배'\nvar_d = '참외'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nprint(int(var_g))",
        "solution_code_en": "var_a = 'apples'\nvar_b = 'peaches'\nvar_c = 'pears'\nvar_d = 'melons'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nprint(int(var_g))"
    },
    "6527": {
        "category": "Geometry",
        "question_ko": "어떤 세 점을 잇는 직선을 그릴 수 없습니다. 이 세 점으로 만들 수 있는 반직선의 개수는 무엇입니까?",
        "question_en": "You cannot draw a straight line between certain three points. How many semi-straight line can you make with these three points?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "3 2 [OP_PERM]",
        "solution_abst_en": "3 2 [OP_PERM]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))"
    },
    "6528": {
        "category": "Possibility",
        "question_ko": "3, 5, 7, 8 중에서 서로 다른 숫자 2개를 뽑아 만들 수 있는 두 자리 수 중에서 가장 큰 수와 가장 작은 수의 합을 구하시오.",
        "question_en": "Find the sum of the largest and smallest of the two-digit numbers that can be formed by drawing two different numbers from 3, 5, 7, and 8.",
        "answer_ko": "122",
        "answer_en": "122",
        "solution_abst_ko": "[OP_LIST_SOL] 3 5 7 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 3 5 7 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 5\nvar_c = 7\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 3\nvar_b = 5\nvar_c = 7\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))"
    },
    "6529": {
        "category": "Arithmetic calculation",
        "question_ko": "공책 27권을 한 상자에 9권씩 나눠 담기 위해서는 상자가 몇 개 필요한지 구하시오.",
        "question_en": "How many boxes are needed to store 27 notebooks in 9 boxes?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "27 9 [OP_FDIV]",
        "solution_abst_en": "27 9 [OP_FDIV]",
        "solution_code_ko": "var_a = 27\nvar_b = 9\nvar_c = var_a // var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 27\nvar_b = 9\nvar_c = var_a // var_b\nprint(int(var_c))"
    },
    "6530": {
        "category": "Correspondence",
        "question_ko": "십의 자리 숫자는 3이고, 일의 자리 수와 백의 자리 수의 합은 5인 세 자리 수가 있습니다. 이 세 자리 수의 각 자리 숫자는 모두 다르고, 이 수에 124를 더하면 각 자리 숫자가 모두 같아집니다. 세 자리 수를 구하시오.",
        "question_en": "There are three digit numbers where the tens digit is 3 and the sum of the ones digit and the hundreds digit is 5. Each digit in this three-digit number is different, and when you add 124 to this number, all digits are equal. Find a three digit number.",
        "answer_ko": "431",
        "answer_en": "431",
        "solution_abst_ko": "[OP_LIST_SOL] [OP_LIST_SOL] A 3 B + 124 = C C C [OP_LIST_EOL] [OP_LIST2NUM] A [OP_DIGIT_UNK_SOLVER] 3 [OP_LIST_SOL] A 3 B + 124 = C C C [OP_LIST_EOL] [OP_LIST2NUM] B [OP_DIGIT_UNK_SOLVER] [OP_LIST_EOL] [OP_LIST2NUM]",
        "solution_abst_en": "[OP_LIST_SOL] [OP_LIST_SOL] A 3 B + 124 = C C C [OP_LIST_EOL] [OP_LIST2NUM] A [OP_DIGIT_UNK_SOLVER] 3 [OP_LIST_SOL] A 3 B + 124 = C C C [OP_LIST_EOL] [OP_LIST2NUM] B [OP_DIGIT_UNK_SOLVER] [OP_LIST_EOL] [OP_LIST2NUM]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 3\nvar_c = 'B'\nvar_d = '+'\nvar_e = 124\nvar_f = '='\nvar_g = 'C'\nvar_h = 'C'\nvar_i = 'C'\nlist_a= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_j=\"\"\nfor i in list_a:\n    i = str(i)\n    var_j = var_j + i\nvar_k = 'A'\nans_dict = dict()\nvar_j = var_j.replace('×','*')\nvar_j = var_j.replace('x','*')\nvar_j = var_j.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_j):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_j\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_j):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_l = ans_dict[var_k]\nvar_m = 3\nvar_n = 'A'\nvar_o = 3\nvar_p = 'B'\nvar_q = '+'\nvar_r = 124\nvar_s = '='\nvar_t = 'C'\nvar_u = 'C'\nvar_v = 'C'\nlist_b= []\nif \"/\" in str(var_v):\n    var_v = eval(str(var_v))\nlist_b.append(var_v)\nif \"/\" in str(var_u):\n    var_u = eval(str(var_u))\nlist_b.append(var_u)\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_b.append(var_t)\nif \"/\" in str(var_s):\n    var_s = eval(str(var_s))\nlist_b.append(var_s)\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nlist_b.reverse()\nvar_w=\"\"\nfor i in list_b:\n    i = str(i)\n    var_w = var_w + i\nvar_x = 'B'\nans_dict = dict()\nvar_w = var_w.replace('×','*')\nvar_w = var_w.replace('x','*')\nvar_w = var_w.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_w):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_w\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_w):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_y = ans_dict[var_x]\nlist_c= []\nif \"/\" in str(var_y):\n    var_y = eval(str(var_y))\nlist_c.append(var_y)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_c.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_c.append(var_l)\nlist_c.reverse()\nvar_z=\"\"\nfor i in list_c:\n    i = str(i)\n    var_z = var_z + i\nprint(int(var_z))",
        "solution_code_en": "var_a = 'A'\nvar_b = 3\nvar_c = 'B'\nvar_d = '+'\nvar_e = 124\nvar_f = '='\nvar_g = 'C'\nvar_h = 'C'\nvar_i = 'C'\nlist_a= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_j=\"\"\nfor i in list_a:\n    i = str(i)\n    var_j = var_j + i\nvar_k = 'A'\nans_dict = dict()\nvar_j = var_j.replace('×','*')\nvar_j = var_j.replace('x','*')\nvar_j = var_j.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_j):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_j\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_j):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_l = ans_dict[var_k]\nvar_m = 3\nvar_n = 'A'\nvar_o = 3\nvar_p = 'B'\nvar_q = '+'\nvar_r = 124\nvar_s = '='\nvar_t = 'C'\nvar_u = 'C'\nvar_v = 'C'\nlist_b= []\nif \"/\" in str(var_v):\n    var_v = eval(str(var_v))\nlist_b.append(var_v)\nif \"/\" in str(var_u):\n    var_u = eval(str(var_u))\nlist_b.append(var_u)\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_b.append(var_t)\nif \"/\" in str(var_s):\n    var_s = eval(str(var_s))\nlist_b.append(var_s)\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nlist_b.reverse()\nvar_w=\"\"\nfor i in list_b:\n    i = str(i)\n    var_w = var_w + i\nvar_x = 'B'\nans_dict = dict()\nvar_w = var_w.replace('×','*')\nvar_w = var_w.replace('x','*')\nvar_w = var_w.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_w):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_w\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_w):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_y = ans_dict[var_x]\nlist_c= []\nif \"/\" in str(var_y):\n    var_y = eval(str(var_y))\nlist_c.append(var_y)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_c.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_c.append(var_l)\nlist_c.reverse()\nvar_z=\"\"\nfor i in list_c:\n    i = str(i)\n    var_z = var_z + i\nprint(int(var_z))"
    },
    "6531": {
        "category": "Possibility",
        "question_ko": "0, 1, 2, 3, 5 중 서로 다른 3개의 숫자를 뽑아서 세 자리 수를 만들려고 합니다. 만들 수 있는 세 자리 수는 모두 몇 개입니까?",
        "question_en": "You want to create a three-digit number by picking three different numbers from 0, 1, 2, 3, and 5. How many three-digit numbers can you make?",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 5\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 5\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "6532": {
        "category": "Arithmetic calculation",
        "question_ko": "규리에게 자두가 1.6킬로그램(㎏) 있었습니다. 성민이에게 0.8킬로그램(㎏) 나눠주고 동주에게 0.3킬로그램(㎏) 나눠줬습니다. 규리에게 남은 자두는 몇 킬로그램(㎏)입니까?",
        "question_en": "Gyuri had 1.6 kg (kg) of plums. She gave 0.8 kg (kg) to Sungmin and 0.3 kg (kg) to Dongju. How many remaining kilograms (kg) of plums does Gyuri have?",
        "answer_ko": "0.50",
        "answer_en": "0.5",
        "solution_abst_ko": "1.6 0.8 [OP_SUB] 0.3 [OP_SUB]",
        "solution_abst_en": "1.6 0.8 [OP_SUB] 0.3 [OP_SUB]",
        "solution_code_ko": "var_a = 1.6\nvar_b = 0.8\nvar_c = var_a - var_b\nvar_d = 0.3\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 1.6\nvar_b = 0.8\nvar_c = var_a - var_b\nvar_d = 0.3\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "6533": {
        "category": "Arithmetic calculation",
        "question_ko": "노란 구슬과 파란 구슬이 모두 240개 있습니다. 파란 구슬이 노란 구슬보다 2개 적다면 노란 구슬은 몇 개입니까?",
        "question_en": "There are total 240 marbles of yellow and blue marbles. How many yellow marbles are there if there are 2 fewer blue marbles than yellow marbles?",
        "answer_ko": "121",
        "answer_en": "121",
        "solution_abst_ko": "240 2 [OP_SUB] 2 [OP_DIV] 2 [OP_ADD]",
        "solution_abst_en": "240 2 [OP_SUB] 2 [OP_DIV] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 240\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 240\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "6534": {
        "category": "Arithmetic calculation",
        "question_ko": "나무에서 6/11리터(L)의 수액을 채취하는 데 30분이 걸립니다. 같은 나무의 수액을 8리터(L) 채취하는 데 걸리는 시간은 몇 분인가요?",
        "question_en": "It takes 30 minutes to collect 6/11 liters (l) of sap from a tree. How many minutes does it take to collect 8 liters (l) of sap from the same tree?",
        "answer_ko": "440",
        "answer_en": "440",
        "solution_abst_ko": "30 6/11 [OP_DIV] 8 [OP_MUL]",
        "solution_abst_en": "30 6/11 [OP_DIV] 8 [OP_MUL]",
        "solution_code_ko": "var_a = 30\nvar_b = 0.5454545454545454\nvar_c = var_a / var_b\nvar_d = 8\nvar_e = var_c * var_d\nprint(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))",
        "solution_code_en": "var_a = 30\nvar_b = 0.5454545454545454\nvar_c = var_a / var_b\nvar_d = 8\nvar_e = var_c * var_d\nprint(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))"
    },
    "6535": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이는 한 시간 동안 2.7킬로미터(㎞)를 갈 수 있습니다. 지민이가 같은 빠르기로 4.86킬로미터(㎞)를 가는 데 몇 시간이 걸리겠습니까?",
        "question_en": "Jungkook can travel 2.7 kilometers (km) per hour. How many hours will it take Jimin to travel 4.86 kilometers (km) at the same speed?",
        "answer_ko": "1.80",
        "answer_en": "1.8",
        "solution_abst_ko": "1 2.7 [OP_DIV] 4.86 [OP_MUL]",
        "solution_abst_en": "1 2.7 [OP_DIV] 4.86 [OP_MUL]",
        "solution_code_ko": "var_a = 1\nvar_b = 2.7\nvar_c = var_a / var_b\nvar_d = 4.86\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 2.7\nvar_c = var_a / var_b\nvar_d = 4.86\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "6536": {
        "category": "Arithmetic calculation",
        "question_ko": "사과가 45개 있습니다. 사과는 배보다 21개 많습니다. 귤이 배보다 18개 더 많다면 귤은 몇 개입니까?",
        "question_en": "There are 45 apples. There are 21 more apples than pears. If there are 18 more tangerines than pears, how many tangerines are there?",
        "answer_ko": "42",
        "answer_en": "42",
        "solution_abst_ko": "45 21 [OP_SUB] 18 [OP_ADD]",
        "solution_abst_en": "45 21 [OP_SUB] 18 [OP_ADD]",
        "solution_code_ko": "var_a = 45\nvar_b = 21\nvar_c = var_a - var_b\nvar_d = 18\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 45\nvar_b = 21\nvar_c = var_a - var_b\nvar_d = 18\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "6537": {
        "category": "Arithmetic calculation",
        "question_ko": "리본 고리를 만들기 위해 리본을 0.82미터(m)씩 자르려고 합니다. 리본 53.73미터(m)로 고리를 만들고 남는 리본은 몇 밀리미터(㎜)인지 구하시오.",
        "question_en": "You want to cut a ribbon into 0.82 meter (m) each in order to make ribbon loops. Make a loop with 53.73 meters (m) of ribbon and find how many millimeters (mm) of this ribbon are left.",
        "answer_ko": "430",
        "answer_en": "430",
        "solution_abst_ko": "53.73 0.82 [OP_MOD] 1000 [OP_MUL]",
        "solution_abst_en": "53.73 0.82 [OP_MOD] 1000 [OP_MUL]",
        "solution_code_ko": "var_a = 53.73\nvar_b = 0.82\nvar_c = var_a % var_b\nvar_d = 1000\nvar_e = var_c * var_d\nprint(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))",
        "solution_code_en": "var_a = 53.73\nvar_b = 0.82\nvar_c = var_a % var_b\nvar_d = 1000\nvar_e = var_c * var_d\nprint(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))"
    },
    "6538": {
        "category": "Possibility",
        "question_ko": "서로 다른 한 자리 수 5개를 이용하여 세 자리 수를 만들고자 한다. 각 자리수가 모두 다른 경우는 몇 가지인가?",
        "question_en": "You want to create a three-digit number using five different single-digit numbers. How many ways are there to have different digits?",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "1 5 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "1 5 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 5\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 5\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "6539": {
        "category": "Geometry",
        "question_ko": "가로 6센티미터(㎝), 세로 5센티미터(㎝), 높이 4센티미터(㎝)인 직육면체의 겉면에 포장지를 빈틈없이 붙였습니다. 이 직육면체를 부피가 1세제곱센티미터(㎤)인 정육면체 120개로 잘랐을 때, 포장지가 붙어있지 않은 정육면체 조각의 개수를 구하시오.",
        "question_en": "Wrapping paper was attached to the outer surface of a cuboid measuring 6 centimeters (cm) wide, 5 centimeters (cm) long, and 4 centimeters (cm) high. When this cuboid is cut into 120 cubes with a volume of 1 cubic centimeter (cm3), find the number of cubes without wrapping paper attached.",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "6 2 [OP_SUB] 5 2 [OP_SUB] [OP_MUL] 4 2 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "6 2 [OP_SUB] 5 2 [OP_SUB] [OP_MUL] 4 2 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = var_c * var_f\nvar_h = 4\nvar_i = 2\nvar_j = var_h - var_i\nvar_k = var_g * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = var_c * var_f\nvar_h = 4\nvar_i = 2\nvar_j = var_h - var_i\nvar_k = var_g * var_j\nprint(int(var_k))"
    },
    "6540": {
        "category": "Possibility",
        "question_ko": "서로 다른 바지 4벌과 치마 2벌이 있다. 이 중 3벌을 뽑아 각자 다른 포장지 3개에 각각 포장하고 싶다. 몇 가지 경우가 생길 수 있는가?",
        "question_en": "There are 4 different pairs of pants and 2 skirts. You want to wrap 3 of these in 3 different wrapping paper. How many cases can be made?",
        "answer_ko": "720",
        "answer_en": "720",
        "solution_abst_ko": "4 2 [OP_ADD] 3 [OP_PERM] 3 3 [OP_PERM] [OP_MUL]",
        "solution_abst_en": "4 2 [OP_ADD] 3 [OP_PERM] 3 3 [OP_PERM] [OP_MUL]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 1\nvar_c = int(var_c)\nvar_d = int(var_d)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e * (var_c-i)\nvar_f = 3\nvar_g = 3\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nvar_i = var_e * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 1\nvar_c = int(var_c)\nvar_d = int(var_d)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e * (var_c-i)\nvar_f = 3\nvar_g = 3\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nvar_i = var_e * var_h\nprint(int(var_i))"
    },
    "6541": {
        "category": "Comparison",
        "question_ko": "갑은 을보다 키가 작으며 을은 병보다 큽니다. 또한 갑은 정보다 키가 작으며 병은 정보다 큽니다. 키가 가장 작은 사람은 누구인가요",
        "question_en": "(A) is shorter than (B), and (B) is taller than (C). Also, (A) is shorter than (D) and the (C) is taller than (D). Find who is the shortest.",
        "answer_ko": "갑",
        "answer_en": "(A)",
        "solution_abst_ko": "[OP_LIST_SOL] 갑 을 병 정 [OP_LIST_EOL] [OP_LIST_SOL] 갑 을 < 을 병 > 갑 정 < 병 정 > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (A) (B) (C) (D) [OP_LIST_EOL] [OP_LIST_SOL] [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '갑'\nvar_b = '을'\nvar_c = '병'\nvar_d = '정'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '갑'\nvar_f = '을'\nvar_g = '<'\nvar_h = '을'\nvar_i = '병'\nvar_j = '>'\nvar_k = '갑'\nvar_l = '정'\nvar_m = '<'\nvar_n = '병'\nvar_o = '정'\nvar_p = '>'\nlist_b= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_q = len(list_c)\nvar_r = list_c[var_q-1]\nprint(var_r)",
        "solution_code_en": "var_a = '(A)'\nvar_b = '(B)'\nvar_c = '(C)'\nvar_d = '(D)'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_b= []\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_e = len(list_c)\nvar_f = list_c[var_e-1]\nprint(var_f)"
    },
    "6542": {
        "category": "Correspondence",
        "question_ko": "11을 4로 나누면 나머지가 A, 몫이 2가 됩니다. 이 때 A의 값을 구하시오.",
        "question_en": "When 11 is divided by 4, the remainder is A and the quotient is 2. Find the value of A.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "11 4 2 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "11 4 2 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 11\nvar_b = 4\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 11\nvar_b = 4\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "6543": {
        "category": "Arithmetic calculation",
        "question_ko": "학을 혜린이는 하루에 16개씩 7일 동안 접었고, 태영이는 하루에 25개씩 6일 동안 접었습니다. 혜린이와 태영이가 접은 학은 모두 몇 개인지 구해 보시오.",
        "question_en": "Hyerin folded 16 cranes a day for 7 days, and Taeyeong folded 25 cranes a day for 6 days. Find how many cranes Hyerin and Taeyeong folded.",
        "answer_ko": "262",
        "answer_en": "262",
        "solution_abst_ko": "16 7 [OP_MUL] 25 6 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "16 7 [OP_MUL] 25 6 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 16\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 25\nvar_e = 6\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 16\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 25\nvar_e = 6\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "6544": {
        "category": "Correspondence",
        "question_ko": "백의 자리 수가 8, 십의 자리 수가 A, 일의 자리 수가 2인 세자리 수가 있습니다. 이를 십의 자리에서 반올림하면 800이 됩니다. A에 쓸 수 있는 수들의 합을 구하시오",
        "question_en": "A three-digit number has an 8 in the hundreds, an A in the tens, and 2 in the ones. Rounding this to the nearest hundred makes it 800. Find the sum of the numbers that can be A.",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "[OP_LIST_SOL] 8 A 2 [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 850 [OP_LIST_MORE_EQUAL] 8A2 A [OP_LIST_FIND_UNK] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 8 A 2 [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 850 [OP_LIST_MORE_EQUAL] 8A2 A [OP_LIST_FIND_UNK] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 8\nvar_b = 'A'\nvar_c = 2\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nans_dict = dict()\nvar_d = str(var_d)\nlist_b = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_d) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_b.append(new_elem)\nvar_e = 850\nlist_c = []\nfor i in list_b:\n    if i >= var_e:\n        list_c.append(i)\nvar_f = '8A2'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nlist_d = []\nfor elem in list_c:\n    elem = str(elem)\n    list_d.append(int(elem[unk_idx]))\nlist_d = list(set(list_d))\nlist_d = [float(i) for i in list_d]\nvar_h = sum(list_d)\nprint(int(var_h))",
        "solution_code_en": "var_a = 8\nvar_b = 'A'\nvar_c = 2\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nans_dict = dict()\nvar_d = str(var_d)\nlist_b = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_d) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_b.append(new_elem)\nvar_e = 850\nlist_c = []\nfor i in list_b:\n    if i >= var_e:\n        list_c.append(i)\nvar_f = '8A2'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nlist_d = []\nfor elem in list_c:\n    elem = str(elem)\n    list_d.append(int(elem[unk_idx]))\nlist_d = list(set(list_d))\nlist_d = [float(i) for i in list_d]\nvar_h = sum(list_d)\nprint(int(var_h))"
    },
    "6545": {
        "category": "Geometry",
        "question_ko": "가로가 80센티미터(㎝), 세로가 75센티미터(㎝), 높이가 120센티미터(㎝)인 직육면체보다 가로, 세로, 높이의 길이가 각각 2배인 직육면체의 부피는 몇 세제곱미터(㎥)입니까?",
        "question_en": "What is the volume in cubic meters (m3) of a cuboid whose width is 80 centimeters (cm), its length is 75 centimeters (cm), and its height is 120 centimeters (cm), and its length, width, and height are twice each?",
        "answer_ko": "5.76",
        "answer_en": "5.76",
        "solution_abst_ko": "80 100 [OP_DIV] 2 [OP_MUL] 75 100 [OP_DIV] 2 [OP_MUL] 120 100 [OP_DIV] 2 [OP_MUL] [OP_MUL] [OP_MUL]",
        "solution_abst_en": "80 100 [OP_DIV] 2 [OP_MUL] 75 100 [OP_DIV] 2 [OP_MUL] 120 100 [OP_DIV] 2 [OP_MUL] [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 80\nvar_b = 100\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 75\nvar_g = 100\nvar_h = var_f / var_g\nvar_i = 2\nvar_j = var_h * var_i\nvar_k = 120\nvar_l = 100\nvar_m = var_k / var_l\nvar_n = 2\nvar_o = var_m * var_n\nvar_p = var_j * var_o\nvar_q = var_e * var_p\nprint('{:.2f}'.format(round(var_q+1e-10,2)))",
        "solution_code_en": "var_a = 80\nvar_b = 100\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 75\nvar_g = 100\nvar_h = var_f / var_g\nvar_i = 2\nvar_j = var_h * var_i\nvar_k = 120\nvar_l = 100\nvar_m = var_k / var_l\nvar_n = 2\nvar_o = var_m * var_n\nvar_p = var_j * var_o\nvar_q = var_e * var_p\nprint('{:.2f}'.format(round(var_q+1e-10,2)))"
    },
    "6546": {
        "category": "Geometry",
        "question_ko": "가로가 30센티미터(㎝), 세로가 30센티미터(㎝)인 정사각형 모양의 딱지를 5명이 8개씩 가지고 있습니다. 딱지를 바닥에 서로 겹치지않게 펼쳐놓았을 때 딱지가 차지하는 공간은 몇 제곱미터(㎡)인지 구하시오.",
        "question_en": "5 people each have 8 tickets in the shape of a square which is 30 centimeters (cm) wide and 30 centimeters (cm) long. Find how many square meters (m2) of space the tickets occupy when they are spread out on the floor without overlapping each other.",
        "answer_ko": "3.60",
        "answer_en": "3.6",
        "solution_abst_ko": "30 100 [OP_DIV] 2 [OP_POW] 8 [OP_MUL] 5 [OP_MUL]",
        "solution_abst_en": "30 100 [OP_DIV] 2 [OP_POW] 8 [OP_MUL] 5 [OP_MUL]",
        "solution_code_ko": "var_a = 30\nvar_b = 100\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 8\nvar_g = var_e * var_f\nvar_h = 5\nvar_i = var_g * var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 30\nvar_b = 100\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 8\nvar_g = var_e * var_f\nvar_h = 5\nvar_i = var_g * var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "6547": {
        "category": "Arithmetic calculation",
        "question_ko": "10미터(m)간격으로 도로의 한쪽에 10그루의 나무가 심어져있습니다. 도로의 처음에만 나무가 심어져있다면 도로의 길이는 몇 미터(m)인지 구해 보시오.",
        "question_en": "Ten trees are planted on one side of the road at intervals of 10 meters (m). If trees are planted only at the beginning of the road, find the length in meters (m) of the road.",
        "answer_ko": "90",
        "answer_en": "90",
        "solution_abst_ko": "10 1 [OP_SUB] 10 [OP_MUL]",
        "solution_abst_en": "10 1 [OP_SUB] 10 [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 10\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 10\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "6548": {
        "category": "Correspondence",
        "question_ko": "A와 B는 한 자리 자연수입니다. 4/23<A/23<32/43을 만족하고, 0.23<1/B<0.6을 만족하는 모든 A의 개수와 B의 개수의 합은 얼마입니까?",
        "question_en": "A and B are single-digit whole numbers. What is the sum of all A's and B's such that satisfy both 4/23<A/23<32/43 and 0.23<1/B<0.6?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "4/23<A/23<32/43 A [OP_DIGIT_UNK_SOLVER] [OP_LIST_LEN] 0.23<1/B<0.6 B [OP_DIGIT_UNK_SOLVER] [OP_LIST_LEN] [OP_ADD]",
        "solution_abst_en": "4/23<A/23<32/43 A [OP_DIGIT_UNK_SOLVER] [OP_LIST_LEN] 0.23<1/B<0.6 B [OP_DIGIT_UNK_SOLVER] [OP_LIST_LEN] [OP_ADD]",
        "solution_code_ko": "var_a = '4/23<A/23<32/43'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = len(list_a)\nvar_d = '0.23<1/B<0.6'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_b = list(set(ans_dict[var_e]))\nvar_f = len(list_b)\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = '4/23<A/23<32/43'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = len(list_a)\nvar_d = '0.23<1/B<0.6'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_b = list(set(ans_dict[var_e]))\nvar_f = len(list_b)\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "6549": {
        "category": "Correspondence",
        "question_ko": "세 자리 수 ABC를 17로 나누었을 때 몫이 28이고 나머지가 9였습니다. A, B, C의 합을 구하시오.",
        "question_en": "When three-digit number ABC is divided by 17, the quotient and the remainder is 28 and 9. Find the sum of A, B, and C.",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "17 28 [OP_MUL] 9 [OP_ADD] [OP_NUM2LIST] [OP_LIST_SUM]",
        "solution_abst_en": "17 28 [OP_MUL] 9 [OP_ADD] [OP_NUM2LIST] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 17\nvar_b = 28\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = var_c + var_d\nlist_a = []\nvar_e = int(var_e)\nwhile var_e//10 > 0:\n    list_a.append(var_e%10)\n    var_e = var_e//10\nlist_a.append(var_e%10)\nlist_a = list_a[::-1]\nlist_a = [float(i) for i in list_a]\nvar_f = sum(list_a)\nprint(int(var_f))",
        "solution_code_en": "var_a = 17\nvar_b = 28\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = var_c + var_d\nlist_a = []\nvar_e = int(var_e)\nwhile var_e//10 > 0:\n    list_a.append(var_e%10)\n    var_e = var_e//10\nlist_a.append(var_e%10)\nlist_a = list_a[::-1]\nlist_a = [float(i) for i in list_a]\nvar_f = sum(list_a)\nprint(int(var_f))"
    },
    "6550": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 3.4, 7/2, 1.7, 27/10, 2.9가 있습니다. 이 중에서 가장 작은 수를 소수점을 포함하여 답을 쓰시오.",
        "question_en": "There are five numbers 3.4, 7/2, 1.7, 27/10, and 2.9. Write the smallest number including the decimal point.",
        "answer_ko": "1.70",
        "answer_en": "1.7",
        "solution_abst_ko": "[OP_LIST_SOL] 3.4 7/2 1.7 27/10 2.9 [OP_LIST_EOL] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 3.4 7/2 1.7 27/10 2.9 [OP_LIST_EOL] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 3.4\nvar_b = 3.5\nvar_c = 1.7\nvar_d = 2.7\nvar_e = 2.9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 3.4\nvar_b = 3.5\nvar_c = 1.7\nvar_d = 2.7\nvar_e = 2.9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "6551": {
        "category": "Comparison",
        "question_ko": "학생들이 한 줄로 서 있습니다. 은지의 앞에는 6명, 뒤에는 5명이 서 있습니다. 줄을 서 있는 학생은 모두 몇 명입니까?",
        "question_en": "As some students are lined up, there are 6 people in front of Eunji and 5 people behind her. Find the total number of students in the line.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "6 1 [OP_ADD] 5 [OP_ADD]",
        "solution_abst_en": "6 1 [OP_ADD] 5 [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "6552": {
        "category": "Geometry",
        "question_ko": "가로가 3센티미터(㎝) , 세로가 4 센티미터(㎝) , 높이가 5센티미터(㎝) 인 직육면체의 페인트 통에 담갔다가 뺐을 때, 패인트가 묻은 면적을 구하시오.",
        "question_en": "Calculate the area covered by the paint when a cuboid with a width of 3 centimeters (cm), a length of 4 centimeters (cm), and a height of 5 centimeters (cm) is put in a paint bucket and removed.",
        "answer_ko": "94",
        "answer_en": "94",
        "solution_abst_ko": "3 4 [OP_MUL] 3 5 [OP_MUL] 4 5 [OP_MUL] [OP_ADD] [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "3 4 [OP_MUL] 3 5 [OP_MUL] 4 5 [OP_MUL] [OP_ADD] [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = 4\nvar_h = 5\nvar_i = var_g * var_h\nvar_j = var_f + var_i\nvar_k = var_c + var_j\nvar_l = 2\nvar_m = var_k * var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 3\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = 4\nvar_h = 5\nvar_i = var_g * var_h\nvar_j = var_f + var_i\nvar_k = var_c + var_j\nvar_l = 2\nvar_m = var_k * var_l\nprint(int(var_m))"
    },
    "6553": {
        "category": "Possibility",
        "question_ko": "10개의 숫자 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 중 서로 다른 세 개를 택하여 일렬로 나열하여 만든 세 자리의 자연수 중 300 이하의 홀수의 개수를 구하시오.",
        "question_en": "Among the three-digit natural numbers formed by three different digits picked from the following ten digits 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9, find the number of odd numbers less than or equal to 300.",
        "answer_ko": "72",
        "answer_en": "72",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 4 5 6 7 8 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 300 [OP_LIST_LESS_EQUAL] 2 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 4 5 6 7 8 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 300 [OP_LIST_LESS_EQUAL] 2 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nvar_f = 5\nvar_g = 6\nvar_h = 7\nvar_i = 8\nvar_j = 9\nlist_a= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_a.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_k = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_k))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_l = 300\nlist_c = []\nfor i in list_b:\n    if i <= var_l:\n        list_c.append(i)\nvar_m = 2\nlist_d = []\nvar_m = int(var_m)\nfor i in list_c:\n    i = int(i)\n    if i % var_m == 0:\n        list_d.append(i)\nlist_e = list(set(list_c) - set(list_d))\nvar_n = len(list_e)\nprint(int(var_n))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nvar_f = 5\nvar_g = 6\nvar_h = 7\nvar_i = 8\nvar_j = 9\nlist_a= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_a.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_k = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_k))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_l = 300\nlist_c = []\nfor i in list_b:\n    if i <= var_l:\n        list_c.append(i)\nvar_m = 2\nlist_d = []\nvar_m = int(var_m)\nfor i in list_c:\n    i = int(i)\n    if i % var_m == 0:\n        list_d.append(i)\nlist_e = list(set(list_c) - set(list_d))\nvar_n = len(list_e)\nprint(int(var_n))"
    },
    "6554": {
        "category": "Geometry",
        "question_ko": "반지름의 길이가 3센티미터(㎝)인 원을 한 변의 길이가 30센티미터(㎝)인 정사각형 안에 겹치지 않게 만들려고 합니다. 원은 모두 몇 개를 만들 수 있나요?",
        "question_en": "We want to make a circle with a radius of 3 centimeters (cm) in a square with a side length of 30 centimeters (cm) with no overlapping of circles. How many circles can you make in all?",
        "answer_ko": "25",
        "answer_en": "25",
        "solution_abst_ko": "30 3 2 [OP_MUL] [OP_FDIV] 2 [OP_POW]",
        "solution_abst_en": "30 3 2 [OP_MUL] [OP_FDIV] 2 [OP_POW]",
        "solution_code_ko": "var_a = 30\nvar_b = 3\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a // var_d\nvar_f = 2\nvar_g = var_e ** var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 30\nvar_b = 3\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a // var_d\nvar_f = 2\nvar_g = var_e ** var_f\nprint(int(var_g))"
    },
    "6555": {
        "category": "Correspondence",
        "question_ko": "25A7를 올림하여 십의 자리까지 나타내면 2570이 됩니다. A를 구하시오.",
        "question_en": "25A7 rounded up to the nearest tens is 2570. Find A.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "25A7 [OP_GEN_POSSIBLE_LIST] 2570 [OP_LIST_LESS_EQUAL] 2570 10 [OP_SUB] [OP_LIST_MORE] 25A7 A [OP_LIST_FIND_UNK]",
        "solution_abst_en": "25A7 [OP_GEN_POSSIBLE_LIST] 2570 [OP_LIST_LESS_EQUAL] 2570 10 [OP_SUB] [OP_LIST_MORE] 25A7 A [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = '25A7'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 2570\nlist_b = []\nfor i in list_a:\n    if i <= var_b:\n        list_b.append(i)\nvar_c = 2570\nvar_d = 10\nvar_e = var_c - var_d\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = '25A7'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))",
        "solution_code_en": "var_a = '25A7'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 2570\nlist_b = []\nfor i in list_a:\n    if i <= var_b:\n        list_b.append(i)\nvar_c = 2570\nvar_d = 10\nvar_e = var_c - var_d\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = '25A7'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))"
    },
    "6556": {
        "category": "Correspondence",
        "question_ko": "윤기는 4로 어떤 수를 나누어 12를 얻었습니다. 어떤 수를 3으로 나누면?",
        "question_en": "Yoongi divides some number by 4 to get 12. What does he get when the number divides by 3?",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "12 4 [OP_MUL] 3 [OP_DIV]",
        "solution_abst_en": "12 4 [OP_MUL] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "6557": {
        "category": "Possibility",
        "question_ko": "1000부터 2000까지의 수를 차례로 적었다. 쓰여진 각 자리의 숫자를 모두 더하면 얼마가 되는지 구하여라.",
        "question_en": "I wrote the numbers from 1000 to 2000 sequentially. Find the sum of all the digits written.",
        "answer_ko": "14502",
        "answer_en": "14502",
        "solution_abst_ko": "1000 2000 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] [OP_LIST_SUM]",
        "solution_abst_en": "1000 2000 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1000\nvar_b = 2000\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_b=[]\nfor i in list_a:\n    var_d = 0\n    i = int(i)\n    while i//10 > 0:\n        var_d = var_d + i%10\n        i = i//10\n    var_d = var_d + i%10\n    list_b.append(var_d)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 1000\nvar_b = 2000\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_b=[]\nfor i in list_a:\n    var_d = 0\n    i = int(i)\n    while i//10 > 0:\n        var_d = var_d + i%10\n        i = i//10\n    var_d = var_d + i%10\n    list_b.append(var_d)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint(int(var_e))"
    },
    "6558": {
        "category": "Correspondence",
        "question_ko": "상우는 자신이 가진 12개의 공책과 34개의 연필 중 몇 개를 친구들에게 나누어 주기로 하였다. 상우는 몇 개의 공책과 그것의 3배 만큼의 연필을 친구들에게 나누어 주었다. 남은 연필과 공책의 개수가 총 30개일 때, 나누어준 공책은 몇 개인지 구하시오.",
        "question_en": "Sang-woo decided to share some of his 12 notebooks and 34 pencils with his friends. Sang-woo gave away several notebooks and three times as many pencils to his friends. If the total number of pencils and notebooks left is 30, find how many notebooks were distributed.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "12 34 [OP_ADD] 30 [OP_SUB] 1 3 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "12 34 [OP_ADD] 30 [OP_SUB] 1 3 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 34\nvar_c = var_a + var_b\nvar_d = 30\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = 3\nvar_h = var_f + var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 12\nvar_b = 34\nvar_c = var_a + var_b\nvar_d = 30\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = 3\nvar_h = var_f + var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "6559": {
        "category": "Arithmetic calculation",
        "question_ko": "유정이 가진 나무도막의 길이는 31미터(m)보다 30센티미터(㎝) 깁니다. 유정이가 가진 나무도막의 길이를 센티미터(㎝)로 써보시오",
        "question_en": "The length of the wooden block in Yoojung has is 30 centimeters (cm) longer than 31 meters (m). Write the length of the wooden block that Yoojung has in centimeters (cm).",
        "answer_ko": "3130",
        "answer_en": "3130",
        "solution_abst_ko": "31 100 [OP_MUL] 30 [OP_ADD]",
        "solution_abst_en": "31 100 [OP_MUL] 30 [OP_ADD]",
        "solution_code_ko": "var_a = 31\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 30\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 31\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 30\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "6560": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 2번째로 큰 수와 가장 작은 수로 나눈 값은 얼마입니까?",
        "question_en": "There are five numbers 10, 11, 12, 13, and 14. What is the value of the second largest number divided by the smallest number?",
        "answer_ko": "1.30",
        "answer_en": "1.3",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 2 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_DIV]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 2 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g / var_i\nprint('{:.2f}'.format(round(var_j+1e-10,2)))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g / var_i\nprint('{:.2f}'.format(round(var_j+1e-10,2)))"
    },
    "6561": {
        "category": "Correspondence",
        "question_ko": "A3-41=52이 성립합니다. A는 무엇인가요?",
        "question_en": "A3-41=52, where A3 is two-digit number. What is A?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "A3-41=52 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A3-41=52 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A3-41=52'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A3-41=52'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "6562": {
        "category": "Arithmetic calculation",
        "question_ko": "경호는 자전거 타기를 좋아한다. 경호가 집에서 시속 3킬로미터(㎞)로 자전거를 타고 산책을 나가, 시청에서 다시 집으로 시속 4킬로미터(㎞)로 돌아왔다. 돌아올 때는 갈 때보다 2킬로미터(㎞)더 긴 길을 골라서 왔고, 집에 돌아오니 가기 전보다 4시간이 지나 있었다. 돌아올 때 걸린 시간을 구하라.",
        "question_en": "Kyungho likes to ride a bike. The guard rode a bicycle at 3 kilometers (km) per hour from home and went for a walk, and returned home from city hall at 4 kilometers (km) per hour. When he returned, he chose a road that was 2 kilometers (km) longer than when he went, and when he returned home, 4 hours had passed since before he left. Find the time taken to return.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "4 2 4 [OP_DIV] [OP_SUB] 1 3 [OP_DIV] 1 4 [OP_DIV] [OP_ADD] [OP_DIV] 2 [OP_ADD] 4 [OP_DIV]",
        "solution_abst_en": "4 2 4 [OP_DIV] [OP_SUB] 1 3 [OP_DIV] 1 4 [OP_DIV] [OP_ADD] [OP_DIV] 2 [OP_ADD] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = 3\nvar_h = var_f / var_g\nvar_i = 1\nvar_j = 4\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_e / var_l\nvar_n = 2\nvar_o = var_m + var_n\nvar_p = 4\nvar_q = var_o / var_p\nprint(int(var_q))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = 3\nvar_h = var_f / var_g\nvar_i = 1\nvar_j = 4\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_e / var_l\nvar_n = 2\nvar_o = var_m + var_n\nvar_p = 4\nvar_q = var_o / var_p\nprint(int(var_q))"
    },
    "6563": {
        "category": "Geometry",
        "question_ko": "한 모서리가 20센티미터(㎝) 인 정육면체의 겉넓이는 몇 제곱센티미터(㎠)입니까?",
        "question_en": "What is the surface area in square centimeters (cm2) of a cube with one edge of 20 centimeters (cm)?",
        "answer_ko": "2400",
        "answer_en": "2400",
        "solution_abst_ko": "20 2 [OP_POW] 6 [OP_MUL]",
        "solution_abst_en": "20 2 [OP_POW] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 20\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "6564": {
        "category": "Geometry",
        "question_ko": "높이가 13센티미터(㎝), 한 밑면의 넓이가 14제곱센티미터(㎠)인 직육면체가 있습니다. 이 직육면체의 부피는 얼마입니까?",
        "question_en": "There is a cuboid with a height of 13 centimeters (cm) and a base area of 14 square centimeters (cm2). What is the volume of this cuboid?",
        "answer_ko": "182",
        "answer_en": "182",
        "solution_abst_ko": "14 13 [OP_MUL]",
        "solution_abst_en": "14 13 [OP_MUL]",
        "solution_code_ko": "var_a = 14\nvar_b = 13\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 14\nvar_b = 13\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "6565": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 공장에서 (가) 기계는 (다) 물건을 1분에 5개씩 만들고, (나) 기계는 (다) 물건을 1분에 8개씩 만듭니다. 동시에 (다) 물건을 만들기 시작하여 (나) 기계가 (다) 물건을 40개 만들었다면 (가) 기계가 (나) 기계보다 (다) 물건을 몇 개 더 적게 만들었는지 구하시오.",
        "question_en": "In a factory, (a) machines make 5 product (c) per minute, and (b) machines make 8 product (c) per minute. If the two machines startd to make product (c) at the same time and (b) machine made 40 product (c), how many fewer product (c) did (a) machines make than the (b) machines?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "40 5 40 8 [OP_DIV] [OP_MUL] [OP_SUB]",
        "solution_abst_en": "40 5 40 8 [OP_DIV] [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 40\nvar_b = 5\nvar_c = 40\nvar_d = 8\nvar_e = var_c / var_d\nvar_f = var_b * var_e\nvar_g = var_a - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 40\nvar_b = 5\nvar_c = 40\nvar_d = 8\nvar_e = var_c / var_d\nvar_f = var_b * var_e\nvar_g = var_a - var_f\nprint(int(var_g))"
    },
    "6566": {
        "category": "Possibility",
        "question_ko": "1부터 9까지의 자연수가 적힌 공이 있습니다. 이 중 3개를 꺼내 공에 있는 숫자의 합이 19가 되도록 하는 방법의 총합이 몇 개인지 구하십시오.",
        "question_en": "There are balls with the numbers 1 through 9 written on them. Take out 3 of them and find the total number of ways where the numbers on the ball can add up to 19.",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "1 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 19 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 19 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 19\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 19\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))"
    },
    "6567": {
        "category": "Correspondence",
        "question_ko": "자연수 A, B는 15=3×A=5×B를 만족한다. A를 구하시오.",
        "question_en": "The natural numbers A and B satisfy 15 = 3 × A = 5 × B. Find A.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "15=3×A=5×B A [OP_NUM_UNK_SOLVER]",
        "solution_abst_en": "15=3×A=5×B A [OP_NUM_UNK_SOLVER]",
        "solution_code_ko": "var_a = '15=3×A=5×B'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '15=3×A=5×B'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "6568": {
        "category": "Correspondence",
        "question_ko": "20에 어떤 수를 나눠주려 합니다. 잘못하여 10에 어떤 수를 곱했을 때의 결과는 50이 되었습니다. 바르게 계산한 결과는 얼마일까요?",
        "question_en": "You are going to divide a number 20. When you mistakenly multiply the number by 10, the answer is 50. What is the correct calculation result?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "20 50 10 [OP_DIV] [OP_DIV]",
        "solution_abst_en": "20 50 10 [OP_DIV] [OP_DIV]",
        "solution_code_ko": "var_a = 20\nvar_b = 50\nvar_c = 10\nvar_d = var_b / var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 50\nvar_c = 10\nvar_d = var_b / var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "6569": {
        "category": "Comparison",
        "question_ko": "말, 소, 돼지, 양, 토끼, 다람쥐의 순서로 울타리에 들어섰다. 4위를 차지한 동물은?",
        "question_en": "Horses, cows, pigs, sheep, rabbits, and squirrels entered the fence in that order. Which animal came in the fence at 4th place?",
        "answer_ko": "양",
        "answer_en": "sheep",
        "solution_abst_ko": "[OP_LIST_SOL] 말 소 돼지 양 토끼 다람쥐 [OP_LIST_EOL] 4 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Horses cows pigs sheep rabbits squirrels [OP_LIST_EOL] 4 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '말'\nvar_b = '소'\nvar_c = '돼지'\nvar_d = '양'\nvar_e = '토끼'\nvar_f = '다람쥐'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 4\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Horses'\nvar_b = 'cows'\nvar_c = 'pigs'\nvar_d = 'sheep'\nvar_e = 'rabbits'\nvar_f = 'squirrels'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 4\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "6570": {
        "category": "Geometry",
        "question_ko": "민수는 한 변의 길이가 4센티미터(㎝)인 정육각형을 만들 때 사용했던 철사를 가지고 정사각형을 만들려고 합니다. 만들어진 정사각형의 넓이를 구하시오.",
        "question_en": "Minsu is trying to make a square with once used wire to make a regular hexagon whose side is 4 centimeters (cm) long. Find the area of the square.",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "4 6 [OP_MUL] 4 [OP_DIV] 2 [OP_POW]",
        "solution_abst_en": "4 6 [OP_MUL] 4 [OP_DIV] 2 [OP_POW]",
        "solution_code_ko": "var_a = 4\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e ** var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e ** var_f\nprint(int(var_g))"
    },
    "6571": {
        "category": "Geometry",
        "question_ko": "음료수를 가로와 세로 모두 10 캔씩 정사각형 모양으로 정리하였습니다. 둘레에 있는 음료수 캔은 모두 몇 개인가요?",
        "question_en": "Beverages were arranged in a square shape with 10 cans on each row and column. How many beverage cans are there at the perimeter?",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "10 4 [OP_MUL] 4 [OP_SUB]",
        "solution_abst_en": "10 4 [OP_MUL] 4 [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "6572": {
        "category": "Possibility",
        "question_ko": "동전을 두 번 던지고 그 이후에 주사위를 한 번 던진다. 두 번 던져서 나온 동전이 같은 면이고 주사위의 눈이 3의 배수인 경우의 수는 얼마인가?",
        "question_en": "Toss the coin twice, then roll the dice once. In how many ways can two tosses of a coin come up the same side and the dice roll is a multiple of 3?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "2 1 6 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] [OP_MUL]",
        "solution_abst_en": "2 1 6 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 1\nvar_c = 6\nvar_d = 1\nlist_a = [i for i in range(var_b, var_c + 1, var_d)]\nvar_e = 3\nlist_b = []\nvar_e = int(var_e)\nfor i in list_a:\n    i = int(i)\n    if i % var_e == 0:\n        list_b.append(i)\nvar_f = len(list_b)\nvar_g = var_a * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 2\nvar_b = 1\nvar_c = 6\nvar_d = 1\nlist_a = [i for i in range(var_b, var_c + 1, var_d)]\nvar_e = 3\nlist_b = []\nvar_e = int(var_e)\nfor i in list_a:\n    i = int(i)\n    if i % var_e == 0:\n        list_b.append(i)\nvar_f = len(list_b)\nvar_g = var_a * var_f\nprint(int(var_g))"
    },
    "6573": {
        "category": "Correspondence",
        "question_ko": "A는 100개씩 묶음이 1개와 10개씩 묶음이 23개인 수입니다. B는 172에서 105씩 커지게 4번 뛰어서 센 수입니다. A와 B의 합을 구하시오.",
        "question_en": "A is the number of 23 groups of 10 and 1 of 100 groups. B is the number that can be counted by jumping from 172 to 105 four times. Find the sum of A and B.",
        "answer_ko": "922",
        "answer_en": "922",
        "solution_abst_ko": "100 1 [OP_MUL] 10 23 [OP_MUL] [OP_ADD] 172 105 4 [OP_MUL] [OP_ADD] [OP_ADD]",
        "solution_abst_en": "100 1 [OP_MUL] 10 23 [OP_MUL] [OP_ADD] 172 105 4 [OP_MUL] [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 100\nvar_b = 1\nvar_c = var_a * var_b\nvar_d = 10\nvar_e = 23\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 172\nvar_i = 105\nvar_j = 4\nvar_k = var_i * var_j\nvar_l = var_h + var_k\nvar_m = var_g + var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 100\nvar_b = 1\nvar_c = var_a * var_b\nvar_d = 10\nvar_e = 23\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 172\nvar_i = 105\nvar_j = 4\nvar_k = var_i * var_j\nvar_l = var_h + var_k\nvar_m = var_g + var_l\nprint(int(var_m))"
    },
    "6574": {
        "category": "Geometry",
        "question_ko": "오각형의 변과 꼭짓점의 수를 구하고 이를 모두 더한 값을 구하시오.",
        "question_en": "Find the number of sides and vertices of the pentagon and find the sum of them all.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "5 5 [OP_ADD]",
        "solution_abst_en": "5 5 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "6575": {
        "category": "Comparison",
        "question_ko": "도형 A는 가로가 15센티미터(㎝), 세로가 8센티미터(㎝)인 직사각형입니다. 도형 B는 가로가 10센티미터(㎝), 세로가 13센티미터(㎝)인 직사각형입니다. 두 도형 중 넓이가 더 넓은 것은 무엇입니까?",
        "question_en": "Figure A is a rectangle that is 15 centimeters (cm) wide and 8 centimeters (cm) long. Figure B is a rectangle with a width of 10 centimeters (cm) and a length of 13 centimeters (cm). Which of the two shapes has greater area?",
        "answer_ko": "B",
        "answer_en": "B",
        "solution_abst_ko": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 15 8 [OP_MUL] 10 13 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 15 8 [OP_MUL] 10 13 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 15\nvar_d = 8\nvar_e = var_c * var_d\nvar_f = 10\nvar_g = 13\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 15\nvar_d = 8\nvar_e = var_c * var_d\nvar_f = 10\nvar_g = 13\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "6576": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.3 중 0.4보다 크거나 같은 수의 총합은?",
        "question_en": "What is the sum of the numbers greater than or equal to 0.4 among 0.8, 1/2, and 0.3?",
        "answer_ko": "1.30",
        "answer_en": "1.3",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.3 [OP_LIST_EOL] 0.4 [OP_LIST_MORE_EQUAL] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.3 [OP_LIST_EOL] 0.4 [OP_LIST_MORE_EQUAL] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.4\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.4\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "6577": {
        "category": "Geometry",
        "question_ko": "어떤 정팔면체는 한 변의 길이가 2센티미터(㎝)입니다. 이 정팔면체의 겉넓이는 몇 제곱센티미터(㎠)입니까?",
        "question_en": "An octahedron has a side length of 2 centimeters (cm). What is the surface area of this regular octahedron in square centimeters (cm2)?",
        "answer_ko": "10.39",
        "answer_en": "10.39",
        "solution_abst_ko": "3 3 1/2 [OP_POW] [OP_MUL] 2 [OP_DIV] 2 2 [OP_POW] [OP_MUL]",
        "solution_abst_en": "3 3 1/2 [OP_POW] [OP_MUL] 2 [OP_DIV] 2 2 [OP_POW] [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 3\nvar_c = 0.5\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = 2\nvar_j = var_h ** var_i\nvar_k = var_g * var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 3\nvar_b = 3\nvar_c = 0.5\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = 2\nvar_j = var_h ** var_i\nvar_k = var_g * var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "6578": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 100, -1, 2가 있습니다. 그 중에서 가장 큰 수와 가장 작은 수의 차는 얼마입니까?",
        "question_en": "There are three numbers 100, -1, and 2. What is the difference between the largest number and the smallest number?",
        "answer_ko": "101",
        "answer_en": "101",
        "solution_abst_ko": "[OP_LIST_SOL] 100 -1 2 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 100 -1 2 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 100\nvar_b = -1\nvar_c = 2\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e - var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 100\nvar_b = -1\nvar_c = 2\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e - var_g\nprint(int(var_h))"
    },
    "6579": {
        "category": "Possibility",
        "question_ko": "가, 나, 다, 라의 사람 중 2명을 뽑아 한 명은 회장을 , 다른 한 명은 부회장을 하기로 한다. 가능한 경우의 수를 구하시오.",
        "question_en": "Among the people of A, B, C, and D, two people are selected, one to be the president and the other to be the vice president. Find the number of possible cases.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "[OP_LIST_SOL] 가 나 다 라 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_code_ko": "var_a = '가'\nvar_b = '나'\nvar_c = '다'\nvar_d = '라'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nprint(int(var_g))",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nprint(int(var_g))"
    },
    "6580": {
        "category": "Geometry",
        "question_ko": "정사각형에서 한 대각선의 길이가 12센티미터(㎝)라면 이 정사각형의 넓이는 얼마인가요?",
        "question_en": "What is the area of a square when one diagonal is 12 meters (m) long?",
        "answer_ko": "72",
        "answer_en": "72",
        "solution_abst_ko": "12 2 [OP_POW] 2 [OP_DIV]",
        "solution_abst_en": "12 2 [OP_POW] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "6581": {
        "category": "Arithmetic calculation",
        "question_ko": "일주일 동안 영화관을 찾은 사람 중 중 여성은 1518명이고, 이 중에서 직장인은 536명이었습니다. 남성은 여성보다 525명이 더 많았고, 이 중에서 직장인이 아닌 사람은 1257명이었습니다. 영화관을 찾은 직장인은 모두 몇 명입니까?",
        "question_en": "Among the people who visited the cinema during the week, 1518 were women, and among them, 536 were office workers. There were 525 more males than females, and among them, 1257 were non-workers. How many office workers visited the cinema in total?",
        "answer_ko": "1322",
        "answer_en": "1322",
        "solution_abst_ko": "1518 525 [OP_ADD] 1257 [OP_SUB] 536 [OP_ADD]",
        "solution_abst_en": "1518 525 [OP_ADD] 1257 [OP_SUB] 536 [OP_ADD]",
        "solution_code_ko": "var_a = 1518\nvar_b = 525\nvar_c = var_a + var_b\nvar_d = 1257\nvar_e = var_c - var_d\nvar_f = 536\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1518\nvar_b = 525\nvar_c = var_a + var_b\nvar_d = 1257\nvar_e = var_c - var_d\nvar_f = 536\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "6582": {
        "category": "Arithmetic calculation",
        "question_ko": "방과후 활동을 하는 학생과 방과후 활동을 하지 않는 학생이 합하여 24명이 있습니다. 이 중에서 방과후 활동을 하는 학생에게만 사탕 50개를 똑같이 나누어 주었더니 2개가 남았습니다. 방과후 활동을 하는 학생은 방과후 활동을 하지 않는 학생의 2배일 때, 방과후 활동을 하는 학생은 사탕을 몇 개씩 받았는지 구하시오.",
        "question_en": "There are a total of 24 students with and without after-school activities. Of these, 50 candies were distributed equally only to students doing after-school activities, leaving 2 candies. When students who do after-school activities are twice as many students who do not do after-school activities, how many candies do students who do after-school activities get?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "50 2 [OP_SUB] 24 2 1 [OP_ADD] [OP_FDIV] [OP_FDIV]",
        "solution_abst_en": "50 2 [OP_SUB] 24 2 1 [OP_ADD] [OP_FDIV] [OP_FDIV]",
        "solution_code_ko": "var_a = 50\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 24\nvar_e = 2\nvar_f = 1\nvar_g = var_e + var_f\nvar_h = var_d // var_g\nvar_i = var_c // var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 50\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 24\nvar_e = 2\nvar_f = 1\nvar_g = var_e + var_f\nvar_h = var_d // var_g\nvar_i = var_c // var_h\nprint(int(var_i))"
    },
    "6583": {
        "category": "Geometry",
        "question_ko": "사각형에서 그을 수 있는 대각선의 개수는?",
        "question_en": "How many diagonals can be drawn in a tetragon?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "4 4 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "4 4 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 4\nvar_b = 4\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 4\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "6584": {
        "category": "Correspondence",
        "question_ko": "예찬이는 테이프의 길이를 2.5로 나누어서 사용하려했는데 잘못하여 2와 2/5로 나누었더니 15/32센티미터(㎝)가 되었습니다. 예찬이가 원래 사용하려 했던 테이프의 길이는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "Yechan was supposed to divide the tape by 2.5, but he divided it into 2 and 2/5 by mistake, and it became 15/32 centimeters (cm). Find the length in centimeters (cm) of the tape that Yechan originally intended to use.",
        "answer_ko": "0.45",
        "answer_en": "0.45",
        "solution_abst_ko": "15/32 2 2/5 [OP_ADD] [OP_MUL] 2.5 [OP_DIV]",
        "solution_abst_en": "15/32 2 2/5 [OP_ADD] [OP_MUL] 2.5 [OP_DIV]",
        "solution_code_ko": "var_a = 0.46875\nvar_b = 2\nvar_c = 0.4\nvar_d = var_b + var_c\nvar_e = var_a * var_d\nvar_f = 2.5\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 0.46875\nvar_b = 2\nvar_c = 0.4\nvar_d = var_b + var_c\nvar_e = var_a * var_d\nvar_f = 2.5\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "6585": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 275센티미터(㎝)인 테이프 2개를 겹쳐서 붙였더니 전체의 길이가 512센티미터(㎝)가 되었습니다. 겹쳐진 부분의 길이는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "Two 275 centimeters (cm) long tapes are overlapped and attached, resulting in a total length of 512 centimeters (cm). Find the length of the overlapped part in centimeters (cm).",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "275 275 [OP_ADD] 512 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "275 275 [OP_ADD] 512 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 275\nvar_b = 275\nvar_c = var_a + var_b\nvar_d = 512\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 275\nvar_b = 275\nvar_c = var_a + var_b\nvar_d = 512\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "6586": {
        "category": "Possibility",
        "question_ko": "1부터 9까지 9개의 숫자를 한 번씩 사용하여 아홉 자리 수를 만들었다. 이 수가 55의 배수일 때, 가장 큰 아홉자리 수를 구하여라.",
        "question_en": "Nine digits from 1 to 9 are used once to form a nine-digit number. If this number is a multiple of 55, find the largest 9-digit number.",
        "answer_ko": "987642315",
        "answer_en": "987642315",
        "solution_abst_ko": "1 9 1 [OP_LIST_ARANGE] 9 [OP_LIST_GET_PERM] 55 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_abst_en": "1 9 1 [OP_LIST_ARANGE] 9 [OP_LIST_GET_PERM] 55 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 9\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 55\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[-var_f]\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 9\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 55\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[-var_f]\nprint(int(var_g))"
    },
    "6587": {
        "category": "Arithmetic calculation",
        "question_ko": "30장짜리 공책 3권을 만들려고 할 때 100장의 종이가 있다면 몇 장이 남습니까?",
        "question_en": "If you have 100 sheets of paper to make 3 notebooks of 30 sheets, how many sheets are left?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "100 30 3 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "100 30 3 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 100\nvar_b = 30\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 100\nvar_b = 30\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "6588": {
        "category": "Possibility",
        "question_ko": "5명의 사람을 한 줄로 세우는 경우의 수를 구하여라.",
        "question_en": "Find the number of ways to put 5 people in a line.",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "5 5 [OP_PERM]",
        "solution_abst_en": "5 5 [OP_PERM]",
        "solution_code_ko": "var_a = 5\nvar_b = 5\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 5\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))"
    },
    "6589": {
        "category": "Comparison",
        "question_ko": "정국이는 0.8, 윤기는 1/2의 숫자카드를 갖고 있습니다. 0.3보다 작거나 같은 숫자카드를 가지고 있는 사람은 몇 명입니까?",
        "question_en": "Jungkook has 0.8 and Yoongi has 1/2 number cards. How many people have number cards less than or equal to 0.3?",
        "answer_ko": "0",
        "answer_en": "0",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 [OP_LIST_EOL] 0.3 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 [OP_LIST_EOL] 0.3 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.3\nlist_b = []\nfor i in list_a:\n    if i <= var_c:\n        list_b.append(i)\nvar_d = len(list_b)\nprint(int(var_d))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.3\nlist_b = []\nfor i in list_a:\n    if i <= var_c:\n        list_b.append(i)\nvar_d = len(list_b)\nprint(int(var_d))"
    },
    "6590": {
        "category": "Arithmetic calculation",
        "question_ko": "5킬로그램(㎏) 간격으로 숫자가 쓰여 있는 체중계가 표시할 수 있는 최소 무게는 0킬로그램(㎏)이고, 최대 무게는 199킬로그램(㎏)일 때, 이 체중계에는 0이 몇 번 쓰여 있는지 구하시오.",
        "question_en": "If the minimum weight that a scale with numbers written at 5 kilograms (kg) intervals can display is 0 kilograms (kg) and the maximum weight is 199 kilograms (kg), find how many times 0 is written on this scale.",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "0 199 5 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 0 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "0 199 5 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 0 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 0\nvar_b = 199\nvar_c = 5\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 0\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))",
        "solution_code_en": "var_a = 0\nvar_b = 199\nvar_c = 5\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 0\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))"
    },
    "6591": {
        "category": "Correspondence",
        "question_ko": "37에 어떤 수를 더하였더니 52가 되었습니다. 어떤 수는 얼마입니까?",
        "question_en": "Adding some number to 37 gives 52. What number is it?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "52 37 [OP_SUB]",
        "solution_abst_en": "52 37 [OP_SUB]",
        "solution_code_ko": "var_a = 52\nvar_b = 37\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 52\nvar_b = 37\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "6592": {
        "category": "Comparison",
        "question_ko": "똑같은 동화책을 석기는 전체의 1/4, 신영이는 전체의 1/3, 웅이는 전체의 1/5를 읽었습니다. 동화책을 가장 많이 읽은 사람을 구하시오.",
        "question_en": "Seokgi read 1/4 of the children's book, Shinyoung read 1/3 of it, and Woong read 1/5 of it. Find the person who has read the most of the children's book.",
        "answer_ko": "신영",
        "answer_en": "Shinyoung",
        "solution_abst_ko": "[OP_LIST_SOL] 신영 석기 웅이 [OP_LIST_EOL] [OP_LIST_SOL] 1/3 1/4 1/5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Shinyoung Seokgi Woong [OP_LIST_EOL] [OP_LIST_SOL] 1/3 1/4 1/5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '신영'\nvar_b = '석기'\nvar_c = '웅이'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.3333333333333333\nvar_e = 0.25\nvar_f = 0.2\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Shinyoung'\nvar_b = 'Seokgi'\nvar_c = 'Woong'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.3333333333333333\nvar_e = 0.25\nvar_f = 0.2\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "6593": {
        "category": "Arithmetic calculation",
        "question_ko": "대현이의 가방에는 책이 3권, 동길이의 가방에는 2권, 민주의 가방에는 5권, 하은이의 가방에는 3권, 소영이의 가방에는 1권 들어있습니다. 책을 3권 가지고 있는 친구는 몇 명입니까?",
        "question_en": "There are 3 books in Daehyun's bag, 2 books in Donggil's bag, 5 books in Minjoo's bag, 3 books in Haeun's bag, and 1 book in Soyeong's bag. How many of them have 3 books?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 3 2 5 3 1 [OP_LIST_EOL] 3 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "[OP_LIST_SOL] 3 2 5 3 1 [OP_LIST_EOL] 3 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = 5\nvar_d = 3\nvar_e = 1\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = 5\nvar_d = 3\nvar_e = 1\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))"
    },
    "6594": {
        "category": "Arithmetic calculation",
        "question_ko": "국어, 수학, 과학, 영어 중 영어 시험을 보기 전의 평균 점수는 92점이고 영어 시험을 본 후의 평균 점수를 94점입니다. 영어 점수는 몇 점입니까?",
        "question_en": "Among Korean, Mathematics, Science, and English, the average score before taking the English test was 92 points, and the average score after taking the English test turned to 94 points. What is your English score?",
        "answer_ko": "100",
        "answer_en": "100",
        "solution_abst_ko": "92 2 [OP_ADD] 4 [OP_MUL] 92 3 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "92 2 [OP_ADD] 4 [OP_MUL] 92 3 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 92\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c * var_d\nvar_f = 92\nvar_g = 3\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 92\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c * var_d\nvar_f = 92\nvar_g = 3\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nprint(int(var_i))"
    },
    "6595": {
        "category": "Arithmetic calculation",
        "question_ko": "일정한 빠르기로 3분 동안 15리터(L)의 콜라가 나오는 기계가 있습니다. 140리터(L)의 콜라를 받기 위해선 몇 분이 필요합니까?",
        "question_en": "There is a hole through which 15 liters (l) of water is drained in 3 minutes at a constant rate. How many minutes does it take for 140 liters (l) of water to drain?",
        "answer_ko": "28",
        "answer_en": "28",
        "solution_abst_ko": "140 15 3 [OP_DIV] [OP_DIV]",
        "solution_abst_en": "140 15 3 [OP_DIV] [OP_DIV]",
        "solution_code_ko": "var_a = 140\nvar_b = 15\nvar_c = 3\nvar_d = var_b / var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 140\nvar_b = 15\nvar_c = 3\nvar_d = var_b / var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "6596": {
        "category": "Correspondence",
        "question_ko": "네 자리 수 연산식 A2B2+1C1D=3333 에서 A를 구하시오.",
        "question_en": "Find A from the 4-digit equation A2B2+1C1D=3333.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "A2B2+1C1D=3333 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A2B2+1C1D=3333 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A2B2+1C1D=3333'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A2B2+1C1D=3333'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "6597": {
        "category": "Comparison",
        "question_ko": "학교에서 학생들이 차례대로 발표를 합니다. 은정이는 6번째로 발표를 하고 은정이 다음으로 7명의 학생이 발표를 할 것입니다. 발표를 하는 학생은 총 몇 명입니까?",
        "question_en": "At school, students take turns giving presentations. Eunjeong will be the 6th speaker, followed by 7 other students. How many students are giving presentations?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "6 7 [OP_ADD]",
        "solution_abst_en": "6 7 [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "6598": {
        "category": "Comparison",
        "question_ko": "남준이는 3과 6을 모았습니다. 지민이는 7과 1을 모았습니다. 누구의 모은 수의 합이 더 큽니까?",
        "question_en": "Namjoon gathered 3 and 6 together. Jimin gathered 7 and 1 together. Whose sum of numbers is greater?",
        "answer_ko": "남준",
        "answer_en": "Namjoon",
        "solution_abst_ko": "[OP_LIST_SOL] 남준 지민 [OP_LIST_EOL] [OP_LIST_SOL] [OP_LIST_SOL] 3 6 [OP_LIST_EOL] [OP_LIST_SUM] [OP_LIST_SOL] 7 1 [OP_LIST_EOL] [OP_LIST_SUM] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_POP] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Namjoon Jimin [OP_LIST_EOL] [OP_LIST_SOL] [OP_LIST_SOL] 3 6 [OP_LIST_EOL] [OP_LIST_SUM] [OP_LIST_SOL] 7 1 [OP_LIST_EOL] [OP_LIST_SUM] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_POP] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '남준'\nvar_b = '지민'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nvar_d = 6\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nvar_f = 7\nvar_g = 1\nlist_c= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_c.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_c.append(var_f)\nlist_c.reverse()\nlist_c = [float(i) for i in list_c]\nvar_h = sum(list_c)\nlist_d= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_d.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_d.append(var_e)\nlist_d.reverse()\nvar_i = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_j = list_e[-var_i]\nvar_k = list_d.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Namjoon'\nvar_b = 'Jimin'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nvar_d = 6\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nvar_f = 7\nvar_g = 1\nlist_c= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_c.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_c.append(var_f)\nlist_c.reverse()\nlist_c = [float(i) for i in list_c]\nvar_h = sum(list_c)\nlist_d= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_d.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_d.append(var_e)\nlist_d.reverse()\nvar_i = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_j = list_e[-var_i]\nvar_k = list_d.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "6599": {
        "category": "Geometry",
        "question_ko": "높이가 8센티미터(㎝)이고, 넓이가 24제곱센티미터(㎠)인 삼각형의 밑변의 길이는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "Find the length in centimeters (cm) of the base of a triangle with a height of 8 centimeters (cm) and an area of 24 square centimeters (cm2).",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "24 2 [OP_MUL] 8 [OP_DIV]",
        "solution_abst_en": "24 2 [OP_MUL] 8 [OP_DIV]",
        "solution_code_ko": "var_a = 24\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 24\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "6600": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 44, 16, 2, 77, 241이 있습니다. 주어진 5개 숫자들의 합과 평균의 차를 구하시오.",
        "question_en": "There are five numbers 44, 16, 2, 77, and 241. Find the difference between the sum and the average of the five numbers given.",
        "answer_ko": "304",
        "answer_en": "304",
        "solution_abst_ko": "[OP_LIST_SOL] 44 16 2 77 241 [OP_LIST_EOL] [OP_LIST_SUM] [OP_LIST_MEAN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 44 16 2 77 241 [OP_LIST_EOL] [OP_LIST_SUM] [OP_LIST_MEAN] [OP_SUB]",
        "solution_code_ko": "var_a = 44\nvar_b = 16\nvar_c = 2\nvar_d = 77\nvar_e = 241\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_f = sum(list_a)\nlist_a = [float(i) for i in list_a]\nvar_g = sum(list_a)/len(list_a)\nvar_h = var_f - var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 44\nvar_b = 16\nvar_c = 2\nvar_d = 77\nvar_e = 241\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_f = sum(list_a)\nlist_a = [float(i) for i in list_a]\nvar_g = sum(list_a)/len(list_a)\nvar_h = var_f - var_g\nprint(int(var_h))"
    },
    "6601": {
        "category": "Geometry",
        "question_ko": "정십각형의 한 각의 크기는 몇 도입니까?",
        "question_en": "How many degrees is the measure of one angle of a regular decagon?",
        "answer_ko": "144",
        "answer_en": "144",
        "solution_abst_ko": "10 2 [OP_SUB] 180 [OP_MUL] 10 [OP_DIV]",
        "solution_abst_en": "10 2 [OP_SUB] 180 [OP_MUL] 10 [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 180\nvar_e = var_c * var_d\nvar_f = 10\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 10\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 180\nvar_e = var_c * var_d\nvar_f = 10\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "6602": {
        "category": "Comparison",
        "question_ko": "신발끈은 지희가 1미터(m)와 1/5미터(m), 현지가 8/5미터(m)를 사용했다. 누가 신발끈을 더 많이 사용했는지 구하시오.",
        "question_en": "Jihee used 1 meter (m) and 1/5 meters (m), and Hyun used 8/5 meters (m) of shoelaces. Find out who used more shoelaces.",
        "answer_ko": "현지",
        "answer_en": "Hyun",
        "solution_abst_ko": "[OP_LIST_SOL] 지희 현지 [OP_LIST_EOL] [OP_LIST_SOL] 1 1 5 [OP_DIV] [OP_ADD] 8 5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jihee Hyun [OP_LIST_EOL] [OP_LIST_SOL] 1 1 5 [OP_DIV] [OP_ADD] 8 5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '지희'\nvar_b = '현지'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1\nvar_d = 1\nvar_e = 5\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nvar_h = 8\nvar_i = 5\nvar_j = var_h / var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'Jihee'\nvar_b = 'Hyun'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1\nvar_d = 1\nvar_e = 5\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nvar_h = 8\nvar_i = 5\nvar_j = var_h / var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "6603": {
        "category": "Comparison",
        "question_ko": "나이의 합이 34살인 세 형제가 있습니다. 첫째의 나이는 막내의 나이의 3배이고, 둘째의 나이는 막내 나이의 2배보다 2살 어립니다. 둘째의 나이는 얼마입니까?",
        "question_en": "I have three brothers, and when they add up their ages, it becomes 34. The age of the oldest brother is 3 times the age of the youngest brother, and the age of the second oldest brother is 2 years younger than twice the age of the youngest brother. How old is the second oldest brother?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "34 2 [OP_ADD] 3 1 [OP_ADD] 2 [OP_ADD] [OP_DIV] 2 [OP_MUL] 2 [OP_SUB]",
        "solution_abst_en": "34 2 [OP_ADD] 3 1 [OP_ADD] 2 [OP_ADD] [OP_DIV] 2 [OP_MUL] 2 [OP_SUB]",
        "solution_code_ko": "var_a = 34\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = var_c / var_h\nvar_j = 2\nvar_k = var_i * var_j\nvar_l = 2\nvar_m = var_k - var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 34\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = var_c / var_h\nvar_j = 2\nvar_k = var_i * var_j\nvar_l = 2\nvar_m = var_k - var_l\nprint(int(var_m))"
    },
    "6604": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 6센티미터(㎝)인 삼각형이 있습니다. 이 삼각형의 나머지 두 변의 길이가 같고, 모든 변의 길이의 합이 20센티미터(㎝)일 때 길이가 같은 두 변 중 한 변의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "There is a triangle with a side length of 6 centimeters (cm). If the other two sides of the triangle are equal in length and the sum of all sides is 20 centimeters (cm), how many centimeters (cm) is the length of one of the two equal sides?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "20 6 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "20 6 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 20\nvar_b = 6\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 6\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "6605": {
        "category": "Correspondence",
        "question_ko": "자연수 A를 5로 나눴더니 나머지가 4, 몫이 6이 되었습니다. A에 알맞은 값을 구하시오.",
        "question_en": "When we divide the natural number A by 5, we get a remainder of 4 and a quotient of 6. Find the right value for A.",
        "answer_ko": "34",
        "answer_en": "34",
        "solution_abst_ko": "5 6 [OP_MUL] 4 [OP_ADD]",
        "solution_abst_en": "5 6 [OP_MUL] 4 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "6606": {
        "category": "Comparison",
        "question_ko": "학생들이 한 줄로 서 있습니다. 유정이는 맨 앞에 서 있습니다. 은정이는 뒤에서 5번째에 서 있습니다. 유정이와 은정이 사이에 30명이 서 있을 때, 줄을 선 학생은 모두 몇 명입니까?",
        "question_en": "When students stand in a line, Yoojung is at the front, and Eunjung is standing at the 5th from the back. If 30 students are standing between Yoojung and Eunjeong, how many students are in a line?",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "5 30 [OP_ADD] 1 [OP_ADD]",
        "solution_abst_en": "5 30 [OP_ADD] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 30\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 30\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "6607": {
        "category": "Possibility",
        "question_ko": "숫자 카드 1, 6, 8를 한 번씩 모두 사용하여 두 번째로 큰 세 자리 수와 세 번째로 작은 세 자리수의 차를 구하시오.",
        "question_en": "Using the number cards 1, 6, and 8 all once, find the difference between the second largest three-digit number and the third smallest three-digit number.",
        "answer_ko": "198",
        "answer_en": "198",
        "solution_abst_ko": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f - var_h\nvar_j = abs(var_i)\nprint(int(var_j))",
        "solution_code_en": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f - var_h\nvar_j = abs(var_i)\nprint(int(var_j))"
    },
    "6608": {
        "category": "Possibility",
        "question_ko": "파란색 연필 4자루와 빨간색 연필 1자루가 있습니다. 연필 5자루를 서로 다르게 한 줄로 놓는 방법은 모두 몇 가지입니까?",
        "question_en": "You have 4 blue pencils and 1 red pencil. How many different ways can you place 5 pencils in a row?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "4 1 [OP_ADD] 4 [OP_COMB]",
        "solution_abst_en": "4 1 [OP_ADD] 4 [OP_COMB]",
        "solution_code_ko": "var_a = 4\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = 1\nvar_c = int(var_c)\nvar_d = int(var_d)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e * (var_c-i)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e / (i+1)\nprint(int(var_e))",
        "solution_code_en": "var_a = 4\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = 1\nvar_c = int(var_c)\nvar_d = int(var_d)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e * (var_c-i)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e / (i+1)\nprint(int(var_e))"
    },
    "6609": {
        "category": "Geometry",
        "question_ko": "가로 10센티미터(㎝), 세로 12센티미터(㎝), 높이 10센티미터(㎝)인 직육면체 어항에 높이가 5센티미터(㎝)가 되도록 물을 넣고 싶다. 넣어야 하는 물의 부피를 구하라.",
        "question_en": "I want to put 5 cm (cm) height of water into a cuboid shaped fishbowl that is 10 cm (cm) width, 12 cm (cm) length, and 10 cm (cm) height. Find the volume of water that needs to be added.",
        "answer_ko": "600",
        "answer_en": "600",
        "solution_abst_ko": "10 12 [OP_MUL] 5 [OP_MUL]",
        "solution_abst_en": "10 12 [OP_MUL] 5 [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "6610": {
        "category": "Arithmetic calculation",
        "question_ko": "14.23÷4.7 의 값을 반올림하여 소수 둘째 자리까지 구하시오.",
        "question_en": "Round the value of 14.23÷4.7 to two decimal places.",
        "answer_ko": "3.03",
        "answer_en": "3.03",
        "solution_abst_ko": "14.23 4.7 [OP_DIV] 2 [OP_ROUND]",
        "solution_abst_en": "14.23 4.7 [OP_DIV] 2 [OP_ROUND]",
        "solution_code_ko": "var_a = 14.23\nvar_b = 4.7\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = round(float(var_c)+1e-10, var_d)\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 14.23\nvar_b = 4.7\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = round(float(var_c)+1e-10, var_d)\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "6611": {
        "category": "Arithmetic calculation",
        "question_ko": "강희와 호재가 2킬로그램(㎏) 100그램(g)의 수박을 나눠 먹었습니다. 강희가 호재보다 200그램(g) 더 많이 먹었다면, 강희가 먹은 수박은 몇 킬로그램(㎏)입니까?",
        "question_en": "Kanghee and Hojae shared a 2kg (kg) and 100g (g) watermelon. If Kanghee ate 200 grams (g) more than Hojae did, how many kilograms (kg) of watermelon did Kanghee eat?",
        "answer_ko": "1.15",
        "answer_en": "1.15",
        "solution_abst_ko": "2 1000 [OP_MUL] 100 [OP_ADD] 200 [OP_ADD] 2 [OP_DIV] 1000 [OP_DIV]",
        "solution_abst_en": "2 1000 [OP_MUL] 100 [OP_ADD] 200 [OP_ADD] 2 [OP_DIV] 1000 [OP_DIV]",
        "solution_code_ko": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = var_c + var_d\nvar_f = 200\nvar_g = var_e + var_f\nvar_h = 2\nvar_i = var_g / var_h\nvar_j = 1000\nvar_k = var_i / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = var_c + var_d\nvar_f = 200\nvar_g = var_e + var_f\nvar_h = 2\nvar_i = var_g / var_h\nvar_j = 1000\nvar_k = var_i / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "6612": {
        "category": "Arithmetic calculation",
        "question_ko": "다음 범위 사이의 자연수 개수를 구하시오. 8 이상 21 이하.",
        "question_en": "Find the number of natural numbers in the following range: 8 or more and 21 or less.",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "8 21 1 [OP_LIST_ARANGE] [OP_LIST_LEN]",
        "solution_abst_en": "8 21 1 [OP_LIST_ARANGE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 8\nvar_b = 21\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = len(list_a)\nprint(int(var_d))",
        "solution_code_en": "var_a = 8\nvar_b = 21\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = len(list_a)\nprint(int(var_d))"
    },
    "6613": {
        "category": "Geometry",
        "question_ko": "밑면이 정육각형인 각뿔의 꼭짓점은 총 몇 개인가?",
        "question_en": "How many vertices does a pyramid with a regular hexagonal base have?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "6 1 [OP_ADD]",
        "solution_abst_en": "6 1 [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "6614": {
        "category": "Correspondence",
        "question_ko": "172를 4로 나눈 뒤 28을 빼고 어떤 수를 곱한 뒤 7을 더하면 172가 된다. 어떤 수를 구하시오.",
        "question_en": "Divide 172 by 4, subtract 28, and then multiply by this number, and add 7 to get 172. Find this number.",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "172 7 [OP_SUB] 172 4 [OP_DIV] 28 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "172 7 [OP_SUB] 172 4 [OP_DIV] 28 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 172\nvar_b = 7\nvar_c = var_a - var_b\nvar_d = 172\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = 28\nvar_h = var_f - var_g\nvar_i = var_c / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 172\nvar_b = 7\nvar_c = var_a - var_b\nvar_d = 172\nvar_e = 4\nvar_f = var_d / var_e\nvar_g = 28\nvar_h = var_f - var_g\nvar_i = var_c / var_h\nprint(int(var_i))"
    },
    "6615": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 일을 진수가 혼자서 완성하는 데 4시간이 걸린다. 진수가 한 시간 동안 할 수 있는 일의 양은 전체의 얼마인가?",
        "question_en": "It takes Jinsu 4 hours to complete a task by himself. What is the amount of work that Jinsu can do in one hour?",
        "answer_ko": "0.25",
        "answer_en": "0.25",
        "solution_abst_ko": "1 4 [OP_DIV]",
        "solution_abst_en": "1 4 [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "6616": {
        "category": "Correspondence",
        "question_ko": "A, B는 한 자리 수이다. 2에 4를 더하면 A가 되고 3에서 1을 빼면 B가 된다. 이때 A+B를 구하여라.",
        "question_en": "A and B are single digit numbers. Add 4 to 2 to get A, subtract 1 from 3 to get B. Find A+B at this time.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "2 4 [OP_ADD] 1 3 [OP_ADD] [OP_ADD]",
        "solution_abst_en": "2 4 [OP_ADD] 1 3 [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "6617": {
        "category": "Correspondence",
        "question_ko": "어떤 자연수와 81 사이에는 연속된 자연수가 15개 있습니다. 어떤 수는 81보다 작은 자연수일 때 어떤 수는 얼마입니까?",
        "question_en": "Between a certain natural number and 81, there are 15 consecutive natural numbers. What is this certain number if it is a natural number less than 81?",
        "answer_ko": "65",
        "answer_en": "65",
        "solution_abst_ko": "81 15 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "81 15 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 81\nvar_b = 15\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 81\nvar_b = 15\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "6618": {
        "category": "Possibility",
        "question_ko": "3종류의 치킨과 2종류의 음료수가 있을 때, 하나씩 골라서 점심에 먹으려고 합니다. 몇 가지의 선택을 할 수 있습니까?",
        "question_en": "There are 3 kinds of chicken and 2 kinds of drinks, and you want to choose one from each to eat for lunch. How many choices can you make?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "3 2 [OP_MUL]",
        "solution_abst_en": "3 2 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "6619": {
        "category": "Comparison",
        "question_ko": "국어, 사회, 수학, 영어, 과학 시험을 순서대로 봤을 때, 3번째로 치른 시험은 무슨 과목입니까?",
        "question_en": "When you took the exam of Korean, Social, Mathematics, English, and Science in order, what subject did you take third?",
        "answer_ko": "수학",
        "answer_en": "Mathematics",
        "solution_abst_ko": "[OP_LIST_SOL] 국어 사회 수학 영어 과학 [OP_LIST_EOL] 3 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Korean Social Mathematics English Science [OP_LIST_EOL] 3 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '국어'\nvar_b = '사회'\nvar_c = '수학'\nvar_d = '영어'\nvar_e = '과학'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nvar_g = list_a[var_f-1]\nprint(var_g)",
        "solution_code_en": "var_a = 'Korean'\nvar_b = 'Social'\nvar_c = 'Mathematics'\nvar_d = 'English'\nvar_e = 'Science'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nvar_g = list_a[var_f-1]\nprint(var_g)"
    },
    "6620": {
        "category": "Arithmetic calculation",
        "question_ko": "덧셈왕에게 두 수를 말해주면 그 사이의 모든 수를 빠르게 더할 수 있다. 6와 21을 말해주었을 때, 덧셈왕의 대답은?",
        "question_en": "If you tell the King of Addition any two numbers, he can quickly add all the numbers in between of that two. When you told him 6 and 21, what would be the answer of the King of Addition?",
        "answer_ko": "216",
        "answer_en": "216",
        "solution_abst_ko": "6 21 1 [OP_LIST_ARANGE] [OP_LIST_SUM]",
        "solution_abst_en": "6 21 1 [OP_LIST_ARANGE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 6\nvar_b = 21\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_a = [float(i) for i in list_a]\nvar_d = sum(list_a)\nprint(int(var_d))",
        "solution_code_en": "var_a = 6\nvar_b = 21\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_a = [float(i) for i in list_a]\nvar_d = sum(list_a)\nprint(int(var_d))"
    },
    "6621": {
        "category": "Possibility",
        "question_ko": "12개의 카네이션이 있습니다. 2명의 선생님께 각각 카네이션 한 송이씩 드렸습니다. 그다음 다시 남은 카네이션을 2명의 선생님들께 나누어 드리려고 합니다. 카네이션을 나누어 드리는 방법은 모두 몇 가지인지 구하시오.",
        "question_en": "There are 12 carnations. You gave one carnation to each of the two teachers. Then, you would like to distribute the remaining carnations to two teachers. How many ways are there?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "12 2 1 [OP_MUL] [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "12 2 1 [OP_MUL] [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 12\nvar_b = 2\nvar_c = 1\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 12\nvar_b = 2\nvar_c = 1\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "6622": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 수는 20으로 나누어도 7이 남고, 25로 나누어도 7이 남는 세 자리 수 중에서 가장 작은 수입니다. 어떤 수는 얼마입니까?",
        "question_en": "A certain number is the smallest three-digit number that leaves a remainder of 7 when divided by 20 and a remainder of 7 when divided by 25. What number is it?",
        "answer_ko": "107",
        "answer_en": "107",
        "solution_abst_ko": "100 999 1 [OP_LIST_ARANGE] 20 7 [OP_LIST_DIVIDE_AND_REMAIN] 25 7 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MIN]",
        "solution_abst_en": "100 999 1 [OP_LIST_ARANGE] 20 7 [OP_LIST_DIVIDE_AND_REMAIN] 25 7 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 20\nvar_e = 7\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 25\nvar_g = 7\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nprint(int(var_i))",
        "solution_code_en": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 20\nvar_e = 7\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 25\nvar_g = 7\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nprint(int(var_i))"
    },
    "6623": {
        "category": "Correspondence",
        "question_ko": "A7B+23=695라는 식이 성립하려면, B에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "What number must be in B to make A7B+23=695, where 27B is three-digit number?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "A7B+23=695 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A7B+23=695 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A7B+23=695'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A7B+23=695'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "6624": {
        "category": "Arithmetic calculation",
        "question_ko": "연속하는 5개의 자연수의 합이 60입니다 마지막 수를 구하시오",
        "question_en": "The sum of 5 consecutive natural numbers is 60. Find the last number.",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "60 0 5 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 5 [OP_DIV] 5 1 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "60 0 5 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 5 [OP_DIV] 5 1 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 60\nvar_b = 0\nvar_c = 5\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nlist_a = [i for i in range(var_b, var_e + 1, var_f)]\nlist_a = [float(i) for i in list_a]\nvar_g = sum(list_a)\nvar_h = var_a - var_g\nvar_i = 5\nvar_j = var_h / var_i\nvar_k = 5\nvar_l = 1\nvar_m = var_k - var_l\nvar_n = var_j + var_m\nprint(int(var_n))",
        "solution_code_en": "var_a = 60\nvar_b = 0\nvar_c = 5\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nlist_a = [i for i in range(var_b, var_e + 1, var_f)]\nlist_a = [float(i) for i in list_a]\nvar_g = sum(list_a)\nvar_h = var_a - var_g\nvar_i = 5\nvar_j = var_h / var_i\nvar_k = 5\nvar_l = 1\nvar_m = var_k - var_l\nvar_n = var_j + var_m\nprint(int(var_n))"
    },
    "6625": {
        "category": "Arithmetic calculation",
        "question_ko": "24년이 지난 후의 민수의 나이는 현재 나이의 4배입니다. 현재 민수는 몇 살일까요?",
        "question_en": "After 24 years, Minsu's age will have been four times his current age. How old is Minsu now?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "24 4 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "24 4 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 24\nvar_b = 4\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 24\nvar_b = 4\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "6626": {
        "category": "Correspondence",
        "question_ko": "2A3을 버림하여 십의 자리까지 나타내면 280이 됩니다. A를 구하시오.",
        "question_en": "Rounding down 2A3 to the nearest ten makes it 280. What is A?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "2A3 [OP_GEN_POSSIBLE_LIST] 280 [OP_LIST_MORE_EQUAL] 280 10 [OP_ADD] [OP_LIST_LESS] 2A3 A [OP_LIST_FIND_UNK]",
        "solution_abst_en": "2A3 [OP_GEN_POSSIBLE_LIST] 280 [OP_LIST_MORE_EQUAL] 280 10 [OP_ADD] [OP_LIST_LESS] 2A3 A [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = '2A3'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 280\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 280\nvar_d = 10\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = '2A3'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))",
        "solution_code_en": "var_a = '2A3'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 280\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 280\nvar_d = 10\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = '2A3'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))"
    },
    "6627": {
        "category": "Arithmetic calculation",
        "question_ko": "(가) 아파트 단지에는 4개의 동이 있습니다. 각 동마다 6층까지 있고, 각 동의 1층에는 두 가구, 그리고 2층부터 6층까지에는 각 층마다 세 가구씩 있습니다. (가) 아파트 단지에는 몇 가구가 살 수 있습니까?",
        "question_en": "(A) apartment complex has four buildings. Each building has up to 6 floors, and there are two households on the first floor of each building, and three households on each floor from the second to sixth floor. How many households can live in (A) apartment complex?",
        "answer_ko": "68",
        "answer_en": "68",
        "solution_abst_ko": "4 1 2 [OP_MUL] 6 2 [OP_SUB] 1 [OP_ADD] 3 [OP_MUL] [OP_ADD] [OP_MUL]",
        "solution_abst_en": "4 1 2 [OP_MUL] 6 2 [OP_SUB] 1 [OP_ADD] 3 [OP_MUL] [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 4\nvar_b = 1\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = 6\nvar_f = 2\nvar_g = var_e - var_f\nvar_h = 1\nvar_i = var_g + var_h\nvar_j = 3\nvar_k = var_i * var_j\nvar_l = var_d + var_k\nvar_m = var_a * var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 4\nvar_b = 1\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = 6\nvar_f = 2\nvar_g = var_e - var_f\nvar_h = 1\nvar_i = var_g + var_h\nvar_j = 3\nvar_k = var_i * var_j\nvar_l = var_d + var_k\nvar_m = var_a * var_l\nprint(int(var_m))"
    },
    "6628": {
        "category": "Geometry",
        "question_ko": "넓이의 비가 9:25인 정사각형이 두 개 있습니다. 각각의 정사각형과 크기가 같은 정사각형들을 이용해 정육면체를 두 개 만들었을 때 만들어진 정육면체 중 큰 정육면체의 부피는 작은 정육면체의 부피의 몇 배인지 구하시오.",
        "question_en": "There are two squares whose area ratio is 9:25. When two cubes are made using these squares of the same size as each square, find how many times the volume of the larger cube is the volume of the smaller cube.",
        "answer_ko": "4.63",
        "answer_en": "4.63",
        "solution_abst_ko": "25 1/2 [OP_POW] 3 [OP_POW] 9 1/2 [OP_POW] 3 [OP_POW] [OP_DIV]",
        "solution_abst_en": "25 1/2 [OP_POW] 3 [OP_POW] 9 1/2 [OP_POW] 3 [OP_POW] [OP_DIV]",
        "solution_code_ko": "var_a = 25\nvar_b = 0.5\nvar_c = var_a ** var_b\nvar_d = 3\nvar_e = var_c ** var_d\nvar_f = 9\nvar_g = 0.5\nvar_h = var_f ** var_g\nvar_i = 3\nvar_j = var_h ** var_i\nvar_k = var_e / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 25\nvar_b = 0.5\nvar_c = var_a ** var_b\nvar_d = 3\nvar_e = var_c ** var_d\nvar_f = 9\nvar_g = 0.5\nvar_h = var_f ** var_g\nvar_i = 3\nvar_j = var_h ** var_i\nvar_k = var_e / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "6629": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 10, 11, 12, 13이 있습니다. 그 중에서 가장 큰 수와 2번째로 작은 수의 합은 얼마입니까?",
        "question_en": "There are four numbers 10, 11, 12, and 13. What do you get if you combine the largest number and the second smallest number?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))"
    },
    "6630": {
        "category": "Arithmetic calculation",
        "question_ko": "우유 한 통의 무게가 8킬로그램(㎏)이었습니다. 우유를 절반만큼 쓴 후에 무게를 다시 재어 보니 5킬로그램(㎏)이 되었습니다. 빈 우유통의 무게는 몇 킬로그램(㎏)입니까?",
        "question_en": "A carton of milk weighed eight kilograms (kg). After using half the milk, I weighed it again and it was 5 kilograms (kg). How many kilograms (kg) does an empty milk carton weigh?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "8 8 5 [OP_SUB] 1 [OP_MUL] 1/2 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "8 8 5 [OP_SUB] 1 [OP_MUL] 1/2 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 8\nvar_b = 8\nvar_c = 5\nvar_d = var_b - var_c\nvar_e = 1\nvar_f = var_d * var_e\nvar_g = 0.5\nvar_h = var_f / var_g\nvar_i = var_a - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 8\nvar_b = 8\nvar_c = 5\nvar_d = var_b - var_c\nvar_e = 1\nvar_f = var_d * var_e\nvar_g = 0.5\nvar_h = var_f / var_g\nvar_i = var_a - var_h\nprint(int(var_i))"
    },
    "6631": {
        "category": "Comparison",
        "question_ko": "명석이의 가방에는 0.26킬로그램(㎏)의 책이 4권 있고, 민구의 가방에는 1.2킬로그램(㎏)의 책이 1권 있습니다. 두 사람의 가방의 무게가 같다면 누구의 가방이 더 무겁습니까?",
        "question_en": "There are 4 books weighing 0.26 kg (kg) in Myeongseok's bag, and 1 book weighing 1.2 kg (kg) is in Mingu's bag. If two people's bags weigh the same, whose bag is heavier?",
        "answer_ko": "민구",
        "answer_en": "Mingu",
        "solution_abst_ko": "[OP_LIST_SOL] 명석 민구 [OP_LIST_EOL] [OP_LIST_SOL] 4 0.26 [OP_MUL] 1.2 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Myeongseok Mingu [OP_LIST_EOL] [OP_LIST_SOL] 4 0.26 [OP_MUL] 1.2 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '명석'\nvar_b = '민구'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 0.26\nvar_e = var_c * var_d\nvar_f = 1.2\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Myeongseok'\nvar_b = 'Mingu'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 0.26\nvar_e = var_c * var_d\nvar_f = 1.2\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "6632": {
        "category": "Geometry",
        "question_ko": "정십이각형의 대각선 개수와 변 개수를 더하면, 얼마가 나오는가?",
        "question_en": "If you add the number of diagonals and the number of sides of a regular dodecagon, what will you get?",
        "answer_ko": "66",
        "answer_en": "66",
        "solution_abst_ko": "12 12 3 [OP_SUB] [OP_MUL] 2 [OP_DIV] 12 [OP_ADD]",
        "solution_abst_en": "12 12 3 [OP_SUB] [OP_MUL] 2 [OP_DIV] 12 [OP_ADD]",
        "solution_code_ko": "var_a = 12\nvar_b = 12\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 12\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 12\nvar_b = 12\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 12\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "6633": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 156미터(m)인 운동장에 학생들이 6미터(m)간격으로 줄을 서려고 합니다. 처음과 끝에도 학생들이 선다고 할 때 몇 명의 학생이 줄을 설 수 있나요?",
        "question_en": "Students are trying to line up at intervals of 6 meters (m) on a playground that is 156 meters (m) long. How many students can line up at the beginning and end when students are said to line up?",
        "answer_ko": "27",
        "answer_en": "27",
        "solution_abst_ko": "156 6 [OP_DIV] 1 [OP_ADD]",
        "solution_abst_en": "156 6 [OP_DIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 156\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 156\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "6634": {
        "category": "Arithmetic calculation",
        "question_ko": "6의 배수이면서 5의 배수이면서 8의 배수이면서 9의 배수인 수 중 가장 작은 세 자리 수는 무엇입니까?",
        "question_en": "What is the smallest three-digit number that is a multiple of 6 and that of 5, 8, and 9?",
        "answer_ko": "360",
        "answer_en": "360",
        "solution_abst_ko": "100 999 1 [OP_LIST_ARANGE] 6 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "100 999 1 [OP_LIST_ARANGE] 6 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = 1\nlist_f=list_e.copy()\nlist_f.sort()\nvar_i = list_f[var_h-1]\nprint(int(var_i))",
        "solution_code_en": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = 1\nlist_f=list_e.copy()\nlist_f.sort()\nvar_i = list_f[var_h-1]\nprint(int(var_i))"
    },
    "6635": {
        "category": "Correspondence",
        "question_ko": "다섯 자리 수 62A94를 백의 자리에서 반올림하면 63000이 됩니다. 0부터 9까지의 숫자 중 A에 쓸 수 있는 수들의 합을 구하시오.",
        "question_en": "Rounding the five-digit number 62A94 to the hundred's place is 63000. Find the sum of the numbers from 0 to 9 that can be used for A.",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "62A94 [OP_GEN_POSSIBLE_LIST] 62500 [OP_LIST_MORE_EQUAL] 62A94 A [OP_LIST_FIND_UNK] [OP_LIST_SUM]",
        "solution_abst_en": "62A94 [OP_GEN_POSSIBLE_LIST] 62500 [OP_LIST_MORE_EQUAL] 62A94 A [OP_LIST_FIND_UNK] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = '62A94'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 62500\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = '62A94'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nlist_c = [float(i) for i in list_c]\nvar_e = sum(list_c)\nprint(int(var_e))",
        "solution_code_en": "var_a = '62A94'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 62500\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = '62A94'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nlist_c = [float(i) for i in list_c]\nvar_e = sum(list_c)\nprint(int(var_e))"
    },
    "6636": {
        "category": "Correspondence",
        "question_ko": "3A5-2B=364에서 A에서 들어갈 수 있는 숫자는 무엇인가요?",
        "question_en": "What numbers can be put in A if 3A5-2B=364?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "3A5-2B=364 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "3A5-2B=364 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '3A5-2B=364'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '3A5-2B=364'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "6637": {
        "category": "Correspondence",
        "question_ko": "514에서 어떤 수를 빼어야 할 것을 잘못하여 더하였더니 913이 되었습니다. 바르게 계산하면 얼마입니까?",
        "question_en": "I have to subtract a number from 514, but I accidentally added a number and it became 913. How much is it if I calculate it correctly?",
        "answer_ko": "115",
        "answer_en": "115",
        "solution_abst_ko": "514 913 514 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "514 913 514 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 514\nvar_b = 913\nvar_c = 514\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 514\nvar_b = 913\nvar_c = 514\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "6638": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 4로 나누었더니 12가 됩니다. 3으로 어떤 수를 나누면 얼마입니까?",
        "question_en": "A number divided by 4 is 12. What is the value when the number is divided by 3?",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "12 4 [OP_MUL] 3 [OP_DIV]",
        "solution_abst_en": "12 4 [OP_MUL] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "6639": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 0.55로 나누어야 할 것을 잘못하여 곱하였더니 4.235가 되었습니다. 바르게 계산했을 때의 몫은 얼마입니까?",
        "question_en": "When you wrongly multiply a number that should have been divided by 0.55, you get 4.235. What is the quotient when calculated correctly?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "4.235 0.55 [OP_DIV] 0.55 [OP_DIV]",
        "solution_abst_en": "4.235 0.55 [OP_DIV] 0.55 [OP_DIV]",
        "solution_code_ko": "var_a = 4.235\nvar_b = 0.55\nvar_c = var_a / var_b\nvar_d = 0.55\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 4.235\nvar_b = 0.55\nvar_c = var_a / var_b\nvar_d = 0.55\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "6640": {
        "category": "Possibility",
        "question_ko": "서로 다른 숫자 2개를 9, 4, 3, 5 중에서 뽑아 두 자리 수를 만들었다. 가장 큰 수와 가장 작은 수의 차는 몇인가?",
        "question_en": "Two different numbers were drawn from 9, 4, 3, and 5 to form a two-digit number. What is the difference between the largest number and the smallest number?",
        "answer_ko": "61",
        "answer_en": "61",
        "solution_abst_ko": "[OP_LIST_SOL] 9 4 3 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 9 4 3 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 9\nvar_b = 4\nvar_c = 3\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 9\nvar_b = 4\nvar_c = 3\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))"
    },
    "6641": {
        "category": "Possibility",
        "question_ko": "사과 32개를 남김없이 나누어 상자에 담는 방법은 모두 몇 가지입니까?(단, 사과 32개를 하나에 보관하는 경우는 고려하지 않는다.)",
        "question_en": "How many ways are there to divide all 32 apples and put them in a box without any remainder? (However, putting 32 apples in one box is not considered.)",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "32 [OP_LIST_GET_DIVISOR] [OP_LIST_SOL] 1 [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_abst_en": "32 [OP_LIST_GET_DIVISOR] [OP_LIST_SOL] 1 [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 32\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 1\nlist_b= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_b.append(var_b)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_c = len(list_c)\nprint(int(var_c))",
        "solution_code_en": "var_a = 32\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 1\nlist_b= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_b.append(var_b)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_c = len(list_c)\nprint(int(var_c))"
    },
    "6642": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중에서 가장 큰 수를 2번째로 작은 수로 나눈 나머지는 얼마입니까?",
        "question_en": "There are three numbers 10, 11, and 12. What is the remainder when the largest number is divided by the second smallest number?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_MOD]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_MOD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e % var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e % var_g\nprint(int(var_h))"
    },
    "6643": {
        "category": "Geometry",
        "question_ko": "어떤 정육면체는 겉넓이가 96제곱센티미터(㎠)인 작은 정육면체 8개를 쌓아 올려 만들어졌습니다. 이 쌓아 만들어진 정육면체의 부피는 얼마입니까?",
        "question_en": "One cube is made by stacking 8 small cubes with a surface area of 96 square centimeters (cm2). What is the volume of this stacked cube?",
        "answer_ko": "512",
        "answer_en": "512",
        "solution_abst_ko": "96 6 [OP_DIV] 1/2 [OP_POW] 8 2 [OP_DIV] 2 [OP_DIV] [OP_MUL] 3 [OP_POW]",
        "solution_abst_en": "96 6 [OP_DIV] 1/2 [OP_POW] 8 2 [OP_DIV] 2 [OP_DIV] [OP_MUL] 3 [OP_POW]",
        "solution_code_ko": "var_a = 96\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 8\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = 2\nvar_j = var_h / var_i\nvar_k = var_e * var_j\nvar_l = 3\nvar_m = var_k ** var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 96\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 8\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = 2\nvar_j = var_h / var_i\nvar_k = var_e * var_j\nvar_l = 3\nvar_m = var_k ** var_l\nprint(int(var_m))"
    },
    "6644": {
        "category": "Arithmetic calculation",
        "question_ko": "식빵 3개를 만드는 데 밀가루 400그램(g)이 필요합니다. 밀가루 2.3킬로그램(㎏)으로는 식빵을 몇 개까지 만들 수 있습니까? (단, 식빵은 한번에 3개씩만 만들 수 있습니다.)",
        "question_en": "It takes 400 grams (g) of flour to make 3 loaves of bread. How many slices of bread can you make with 2.3 kilograms (kg) of flour? (However, you can only make 3 slices of bread at a time.)",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "2.3 1000 [OP_MUL] 400 [OP_FDIV] 3 [OP_MUL]",
        "solution_abst_en": "2.3 1000 [OP_MUL] 400 [OP_FDIV] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 2.3\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 400\nvar_e = var_c // var_d\nvar_f = 3\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 2.3\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 400\nvar_e = var_c // var_d\nvar_f = 3\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "6645": {
        "category": "Comparison",
        "question_ko": "5명의 친구가 키를 쟀습니다. 석진이는 명현이보다 작고 주리는 정국이보다 작습니다. 정우는 명현이보다 클 때, 키가 가장 큰 사람은?",
        "question_en": "5 students measured their heights. Seokjin is shorter than Myeonghyeon, and Juri is shorter than Jungkook. If Jungwoo is taller than Myeonghyeon, who is the tallest?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 주리 정우 명현 석진 정국 [OP_LIST_EOL] [OP_LIST_SOL] 주리 정우 > 명현 석진 > 주리 정국 < 명현 정우 < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Juri Jungwoo Myeonghyeon Seokjin Jungkook [OP_LIST_EOL] [OP_LIST_SOL] Juri Jungwoo > Myeonghyeon Seokjin > Juri Jungkook < Myeonghyeon Jungwoo < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '주리'\nvar_b = '정우'\nvar_c = '명현'\nvar_d = '석진'\nvar_e = '정국'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = '주리'\nvar_g = '정우'\nvar_h = '>'\nvar_i = '명현'\nvar_j = '석진'\nvar_k = '>'\nvar_l = '주리'\nvar_m = '정국'\nvar_n = '<'\nvar_o = '명현'\nvar_p = '정우'\nvar_q = '<'\nlist_b= []\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_r = 1\nvar_s = list_c[var_r-1]\nprint(var_s)",
        "solution_code_en": "var_a = 'Juri'\nvar_b = 'Jungwoo'\nvar_c = 'Myeonghyeon'\nvar_d = 'Seokjin'\nvar_e = 'Jungkook'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 'Juri'\nvar_g = 'Jungwoo'\nvar_h = '>'\nvar_i = 'Myeonghyeon'\nvar_j = 'Seokjin'\nvar_k = '>'\nvar_l = 'Juri'\nvar_m = 'Jungkook'\nvar_n = '<'\nvar_o = 'Myeonghyeon'\nvar_p = 'Jungwoo'\nvar_q = '<'\nlist_b= []\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_r = 1\nvar_s = list_c[var_r-1]\nprint(var_s)"
    },
    "6646": {
        "category": "Arithmetic calculation",
        "question_ko": "15의 약수 중 1과 자기 자신을 제외하고 가장 큰 수와 가장 작은 수의 합을 구하시오.",
        "question_en": "Find the sum of the largest and smallest divisors of 15 excluding 1 and itself.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "15 [OP_LIST_GET_DIVISOR] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "15 [OP_LIST_GET_DIVISOR] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 15\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_c = list_b[-var_b]\nvar_d = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_e = list_c[var_d-1]\nvar_f = var_c + var_e\nprint(int(var_f))",
        "solution_code_en": "var_a = 15\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_c = list_b[-var_b]\nvar_d = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_e = list_c[var_d-1]\nvar_f = var_c + var_e\nprint(int(var_f))"
    },
    "6647": {
        "category": "Arithmetic calculation",
        "question_ko": "유나는 영어 문제를 하루에 8문제씩 풀었습니다. 유나가 1주일 동안 푼 영어 문제는 모두 몇 문제입니까?",
        "question_en": "Yuna solved 8 English problems a day. How many English questions did Yuna solve in one week?",
        "answer_ko": "56",
        "answer_en": "56",
        "solution_abst_ko": "7 8 [OP_MUL]",
        "solution_abst_en": "7 8 [OP_MUL]",
        "solution_code_ko": "var_a = 7\nvar_b = 8\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 7\nvar_b = 8\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "6648": {
        "category": "Possibility",
        "question_ko": "1, 7, 3이 적힌 카드 세 장을 모두 한 번씩 이용하여 만들 수 있는 세 자리 수 중 두 번째로 작은 수와 세 번째로 작은 수의 차를 구하시오.",
        "question_en": "Find the difference between the second smallest number and third smallest number from three digit numbers that can be made by using all three cards with the numbers 1, 7, and 3 written once.",
        "answer_ko": "144",
        "answer_en": "144",
        "solution_abst_ko": "[OP_LIST_SOL] 1 7 3 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MIN] 3 [OP_LIST_MIN] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "[OP_LIST_SOL] 1 7 3 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MIN] 3 [OP_LIST_MIN] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 1\nvar_b = 7\nvar_c = 3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f - var_h\nvar_j = abs(var_i)\nprint(int(var_j))",
        "solution_code_en": "var_a = 1\nvar_b = 7\nvar_c = 3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f - var_h\nvar_j = abs(var_i)\nprint(int(var_j))"
    },
    "6649": {
        "category": "Arithmetic calculation",
        "question_ko": "성민이는 1시간에 10.8킬로미터(㎞)를 이동하는 일정한 속력으로 1시간 24분 동안 자전거를 탔습니다. 이때 성민이가 이동한 전체 거리는 몇 킬로미터(㎞)인지 구하시오.",
        "question_en": "Seongmin rode a bicycle for 1 hour and 24 minutes at a constant speed of 10.8 kilometers (km) per hour. At this time, find the total distance traveled by Seongmin in kilometers (km).",
        "answer_ko": "15.12",
        "answer_en": "15.12",
        "solution_abst_ko": "10.8 1 24 60 [OP_DIV] [OP_ADD] [OP_MUL]",
        "solution_abst_en": "10.8 1 24 60 [OP_DIV] [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 10.8\nvar_b = 1\nvar_c = 24\nvar_d = 60\nvar_e = var_c / var_d\nvar_f = var_b + var_e\nvar_g = var_a * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 10.8\nvar_b = 1\nvar_c = 24\nvar_d = 60\nvar_e = var_c / var_d\nvar_f = var_b + var_e\nvar_g = var_a * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "6650": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 254를 뺀 후 329를 더하면 695가 됩니다. 어떤 수를 구하시오.",
        "question_en": "Subtract 254 from a number and add 329 to get 695. Find the number.",
        "answer_ko": "620",
        "answer_en": "620",
        "solution_abst_ko": "695 329 [OP_SUB] 254 [OP_ADD]",
        "solution_abst_en": "695 329 [OP_SUB] 254 [OP_ADD]",
        "solution_code_ko": "var_a = 695\nvar_b = 329\nvar_c = var_a - var_b\nvar_d = 254\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 695\nvar_b = 329\nvar_c = var_a - var_b\nvar_d = 254\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "6651": {
        "category": "Geometry",
        "question_ko": "밑면이 같은 두 직육면체가 있다. 밑면은 가로가 44센티미터(㎝), 세로가 35센티미터(㎝)이다. 두 직육면체의 높이가 각각 7센티미터(㎝), 3센티미터(㎝)일 때, 두 직육면체의 부피의 합을 구하시오.",
        "question_en": "There are two cuboids with the same base. The base is 44 centimeters (cm) long and 35 centimeters (cm) wide. When the heights of the two cuboids are 7 centimeters (cm) and 3 centimeters (cm), find the sum of the volumes of the two cuboids.",
        "answer_ko": "15400",
        "answer_en": "15400",
        "solution_abst_ko": "44 35 [OP_MUL] 7 3 [OP_ADD] [OP_MUL]",
        "solution_abst_en": "44 35 [OP_MUL] 7 3 [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 44\nvar_b = 35\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 44\nvar_b = 35\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "6652": {
        "category": "Comparison",
        "question_ko": "어느 공원 화단에는 장미가 튤립보다 많고, 튤립이 코스모스보다 많으며, 코스모스가 해바라기보다 많습니다. 화단에 꽃을 더 심어서 종류별로 꽃의 수를 맞추려고 할 때, 가장 많이 심어야 하는 꽃은 무엇입니까?",
        "question_en": "In a garden, there are more roses than tulips, more tulips than cosmoses, and more cosmoses than sunflowers. If you are trying to equal the number of flowers per type by planting more flowers in the garden, which flower should be planted the most?",
        "answer_ko": "해바라기",
        "answer_en": "sunflowers",
        "solution_abst_ko": "[OP_LIST_SOL] 장미 튤립 코스모스 해바라기 [OP_LIST_EOL] [OP_LIST_SOL] 장미 튤립 > 튤립 코스모스 > 코스모스 해바라기 > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] roses tulips cosmoses sunflowers [OP_LIST_EOL] [OP_LIST_SOL] roses tulips > tulips cosmoses > cosmoses sunflowers > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '장미'\nvar_b = '튤립'\nvar_c = '코스모스'\nvar_d = '해바라기'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '장미'\nvar_f = '튤립'\nvar_g = '>'\nvar_h = '튤립'\nvar_i = '코스모스'\nvar_j = '>'\nvar_k = '코스모스'\nvar_l = '해바라기'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)",
        "solution_code_en": "var_a = 'roses'\nvar_b = 'tulips'\nvar_c = 'cosmoses'\nvar_d = 'sunflowers'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'roses'\nvar_f = 'tulips'\nvar_g = '>'\nvar_h = 'tulips'\nvar_i = 'cosmoses'\nvar_j = '>'\nvar_k = 'cosmoses'\nvar_l = 'sunflowers'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)"
    },
    "6653": {
        "category": "Possibility",
        "question_ko": "1, 4, 0을 두 번씩 사용하여 여섯자리 수를 만드려고 합니다. 만들 수 있는 숫자 중에서 가장 큰수에서 가장 작은 수를 빼면 얼마가 됩니까?",
        "question_en": "You want to create a six-digit number by using 1, 4, and 0 twice. What is the difference between the largest number and the smallest possible number possible?",
        "answer_ko": "340956",
        "answer_en": "340956",
        "solution_abst_ko": "[OP_LIST_SOL] 1 1 4 4 0 0 [OP_LIST_EOL] 6 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 1 1 4 4 0 0 [OP_LIST_EOL] 6 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 1\nvar_b = 1\nvar_c = 4\nvar_d = 4\nvar_e = 0\nvar_f = 0\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 6\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_i = list_c[-var_h]\nvar_j = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_k = list_d[var_j-1]\nvar_l = var_i - var_k\nprint(int(var_l))",
        "solution_code_en": "var_a = 1\nvar_b = 1\nvar_c = 4\nvar_d = 4\nvar_e = 0\nvar_f = 0\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 6\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_i = list_c[-var_h]\nvar_j = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_k = list_d[var_j-1]\nvar_l = var_i - var_k\nprint(int(var_l))"
    },
    "6654": {
        "category": "Arithmetic calculation",
        "question_ko": "트럭 (가)는 63.45킬로그램(㎏)의 무게의 상자를 실을 수 있고, 트럭 (나)는 13.6킬로그램(㎏)의 무게 상자를 실을 수 있습니다. 각 트럭이 20대씩 있으면 모두 몇 킬로그램(㎏)의 상자를 실을 수 있는지 구하시오.",
        "question_en": "Truck A can carry a crate weighing 63.45 kg (kg), and truck B can load a crate weighing 13.6 kg (kg). If there are 20 trucks each, find how many kilograms (kg) each truck can carry.",
        "answer_ko": "1541",
        "answer_en": "1541",
        "solution_abst_ko": "63.45 20 [OP_MUL] 13.6 20 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "63.45 20 [OP_MUL] 13.6 20 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 63.45\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 13.6\nvar_e = 20\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 63.45\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 13.6\nvar_e = 20\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "6655": {
        "category": "Arithmetic calculation",
        "question_ko": "물이 시간당 200밀리리터(㎖) 나오는 수도를 24시간 틀어놓았습니다. 4000밀리리터(㎖)의 물탱크에 담는다고 할 때 흘러넘친 물의 양은 몇 밀리리터(㎖)입니까?",
        "question_en": "I turned on the tap that produces 200 milliliters (ml) of water per hour for 24 hours. How many milliliters (ml) of water overflows if you fill this water in a 4000 milliliter (ml) water tank?",
        "answer_ko": "800",
        "answer_en": "800",
        "solution_abst_ko": "200 24 [OP_MUL] 4000 [OP_SUB] [OP_ABS]",
        "solution_abst_en": "200 24 [OP_MUL] 4000 [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 200\nvar_b = 24\nvar_c = var_a * var_b\nvar_d = 4000\nvar_e = var_c - var_d\nvar_f = abs(var_e)\nprint(int(var_f))",
        "solution_code_en": "var_a = 200\nvar_b = 24\nvar_c = var_a * var_b\nvar_d = 4000\nvar_e = var_c - var_d\nvar_f = abs(var_e)\nprint(int(var_f))"
    },
    "6656": {
        "category": "Geometry",
        "question_ko": "가로가 8센티미터(㎝), 세로가 5센티미터(㎝), 높이가 10센티미터(㎝)인 직육면체의 전개도를 그렸습니다. 직육면체의 전개도의 넓이는 몇 제곱센티미터입니까?",
        "question_en": "There is a planar figure of a rectangular parallelepiped measuring 8 centimeters (cm) wide, 5 centimeters (cm) long, and 10 centimeters (cm) high. What is the area, in square centimeters (cm2), of the planar figure of the cuboid?",
        "answer_ko": "340",
        "answer_en": "340",
        "solution_abst_ko": "8 5 [OP_MUL] 8 10 [OP_MUL] [OP_ADD] 5 10 [OP_MUL] [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "8 5 [OP_MUL] 8 10 [OP_MUL] [OP_ADD] 5 10 [OP_MUL] [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = 10\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 5\nvar_i = 10\nvar_j = var_h * var_i\nvar_k = var_g + var_j\nvar_l = 2\nvar_m = var_k * var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 8\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = 10\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 5\nvar_i = 10\nvar_j = var_h * var_i\nvar_k = var_g + var_j\nvar_l = 2\nvar_m = var_k * var_l\nprint(int(var_m))"
    },
    "6657": {
        "category": "Correspondence",
        "question_ko": "72와 48을 각각 어떤 수로 나누었더니 모두 나누어떨어졌습니다. 어떤 수가 될 수 있는 수 중에서 가장 큰 수는 얼마입니까?",
        "question_en": "When 72 and 48 were divided by a certain number, there was no remainder. What is the largest possible number?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "72 48 [OP_GCD]",
        "solution_abst_en": "72 48 [OP_GCD]",
        "solution_code_ko": "var_a = 72\nvar_b = 48\nvar_c = math.gcd(int(var_b), int(var_a))\nprint(int(var_c))",
        "solution_code_en": "var_a = 72\nvar_b = 48\nvar_c = math.gcd(int(var_b), int(var_a))\nprint(int(var_c))"
    },
    "6658": {
        "category": "Correspondence",
        "question_ko": "세 자리 수와 두 자리 수의 뺄셈식 9A6-BB=BBB이 나옵니다. A, B가 서로 다른 두 수일 때, A+B의 값을 구하시오",
        "question_en": "There is a three-digit and two-digit number subtraction equation 9A6 - BB=BBB. If A and B are two different numbers, find the value of A+B",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "9A6-BB=BBB A [OP_DIGIT_UNK_SOLVER] 9A6-BB=BBB B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_abst_en": "9A6-BB=BBB A [OP_DIGIT_UNK_SOLVER] 9A6-BB=BBB B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_code_ko": "var_a = '9A6-BB=BBB'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '9A6-BB=BBB'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = '9A6-BB=BBB'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = '9A6-BB=BBB'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "6659": {
        "category": "Correspondence",
        "question_ko": "지혜는 가지고 있던 돈의 반보다 200원 많은 돈으로 학용품을 사고, 그 나머지 돈의 반보다 300원 많은 돈을 저축하였더니 350원이 남았습니다. 지혜가 처음에 가지고 있던 돈은 얼마입니까?",
        "question_en": "Jihyae bought school supplies by the amount that is 200 won more than half of the money she had, saved 300 won more than half of the rest, and was left with 350 won. How much money did Jihyae have at first?",
        "answer_ko": "3000",
        "answer_en": "3000",
        "solution_abst_ko": "350 300 [OP_ADD] 1 1/2 [OP_SUB] [OP_DIV] 200 [OP_ADD] 1 1/2 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "350 300 [OP_ADD] 1 1/2 [OP_SUB] [OP_DIV] 200 [OP_ADD] 1 1/2 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 350\nvar_b = 300\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 0.5\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 200\nvar_i = var_g + var_h\nvar_j = 1\nvar_k = 0.5\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 350\nvar_b = 300\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 0.5\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 200\nvar_i = var_g + var_h\nvar_j = 1\nvar_k = 0.5\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nprint(int(var_m))"
    },
    "6660": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 9를 곱해야 할 것을 나누었더니 몫이 25이고 나머지가 7이었습니다. 바르게 계산하면 얼마가 됩니까?",
        "question_en": "When you divide a number by 9 what should be multiplied, the quotient is 25 and the remainder is 7. How much do you get when you calculate correctly?",
        "answer_ko": "2088",
        "answer_en": "2088",
        "solution_abst_ko": "25 9 [OP_MUL] 7 [OP_ADD] 9 [OP_MUL]",
        "solution_abst_en": "25 9 [OP_MUL] 7 [OP_ADD] 9 [OP_MUL]",
        "solution_code_ko": "var_a = 25\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c + var_d\nvar_f = 9\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 25\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c + var_d\nvar_f = 9\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "6661": {
        "category": "Correspondence",
        "question_ko": "어떤 수와 5와의 합에 7을 곱해야 하는 것을 잘못하여 어떤 수와 5의 곱에 7을 더하였더니 27이 되었습니다. 바르게 계산한 값을 구하시오.",
        "question_en": "There was a mistake in the calculation, multiplying the number by 5 and then adding 7 instead of multiplying the sum of the number and 5 by 7. Then, the wrong result came out as 27. Find the correct calculated value.",
        "answer_ko": "63",
        "answer_en": "63",
        "solution_abst_ko": "27 7 [OP_SUB] 5 [OP_DIV] 5 [OP_ADD] 7 [OP_MUL]",
        "solution_abst_en": "27 7 [OP_SUB] 5 [OP_DIV] 5 [OP_ADD] 7 [OP_MUL]",
        "solution_code_ko": "var_a = 27\nvar_b = 7\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c / var_d\nvar_f = 5\nvar_g = var_e + var_f\nvar_h = 7\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 27\nvar_b = 7\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c / var_d\nvar_f = 5\nvar_g = var_e + var_f\nvar_h = 7\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "6662": {
        "category": "Geometry",
        "question_ko": "오각기둥과 육각기둥의 꼭지점의 합은 몇 개인지 구하시오.",
        "question_en": "Find the sum of the vertices of a pentagonal prism and a hexagonal prism.",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "5 2 [OP_MUL] 6 2 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "5 2 [OP_MUL] 6 2 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "6663": {
        "category": "Geometry",
        "question_ko": "크키가 같은 동전 몇 개를 가지고 한 변이 8개가 되도록 빈틈없이 늘어놓아 정사각형을 만들었습니다. 이 정사각형의 둘레에 동전을 놓아 한 변의 길이가 1 더 큰 정사각형을 만들 때, 동전은 몇 개가 더 필요합니까?",
        "question_en": "I took several coins of the same size and lined them up so that there were 8 coins on each side, making a square. If you place coins around the perimeter of this square to make a square with a side 1 greater, how many more coins are needed?",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "8 2 [OP_MUL] 1 [OP_ADD]",
        "solution_abst_en": "8 2 [OP_MUL] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "6664": {
        "category": "Possibility",
        "question_ko": "1, 3, 7로 이루어져 있는 수 중 세 자리이고 각 자리의 숫자가 다르며, 150이상 700이하의 수는 총 몇 개인가?",
        "question_en": "Among the numbers 1, 3, and 7, how many are three digits which each digit is different and between 150 and 700?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 7 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 150 [OP_LIST_MORE_EQUAL] 700 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 7 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 150 [OP_LIST_MORE_EQUAL] 700 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 150\nlist_c = []\nfor i in list_b:\n    if i >= var_e:\n        list_c.append(i)\nvar_f = 700\nlist_d = []\nfor i in list_c:\n    if i <= var_f:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 150\nlist_c = []\nfor i in list_b:\n    if i >= var_e:\n        list_c.append(i)\nvar_f = 700\nlist_d = []\nfor i in list_c:\n    if i <= var_f:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))"
    },
    "6665": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중 2번째로 큰 수는 무엇입니까?",
        "question_en": "There are three numbers 10, 11, and 12. Which number is the second largest?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 2 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 2 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nprint(int(var_e))"
    },
    "6666": {
        "category": "Comparison",
        "question_ko": "총 4개의 숫자 0.8, 1/2, 0.5, 1/3이 있습니다. 이 중 0.1보다 크거나 같은 수 중 가장 작거나 같은 수를 구하면 무엇인가요?",
        "question_en": "There are a total of 4 numbers: 0.8, 1/2, 0.5, 1/3. What is the smallest number or the number that is equal to 0.1 out of numbers that are greater than or equal to 0.1?",
        "answer_ko": "0.33",
        "answer_en": "0.33",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.5 1/3 [OP_LIST_EOL] 0.1 [OP_LIST_MORE_EQUAL] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.5 1/3 [OP_LIST_EOL] 0.1 [OP_LIST_MORE_EQUAL] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.5\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.1\nlist_b = []\nfor i in list_a:\n    if i >= var_e:\n        list_b.append(i)\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.5\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.1\nlist_b = []\nfor i in list_a:\n    if i >= var_e:\n        list_b.append(i)\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "6667": {
        "category": "Correspondence",
        "question_ko": "6을 어떤 수에 곱했더니 72가 되었습니다. 어떤 수에 8을 더한 결과를 구하시오.",
        "question_en": "When you multiply a particular number by 6, you get 72. Find the result of adding 8 to that particular number.",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "72 6 [OP_DIV] 8 [OP_ADD]",
        "solution_abst_en": "72 6 [OP_DIV] 8 [OP_ADD]",
        "solution_code_ko": "var_a = 72\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 8\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 72\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 8\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "6668": {
        "category": "Arithmetic calculation",
        "question_ko": "1231, 2311, 2131, 1312, 1123, 3112에서 3번째로 큰 수는 무엇입니까?",
        "question_en": "What is the third largest number in 1231, 2311, 2131, 1312, 1123, 3112?",
        "answer_ko": "2131",
        "answer_en": "2131",
        "solution_abst_ko": "[OP_LIST_SOL] 1231 2311 2131 1312 1123 3112 [OP_LIST_EOL] 3 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1231 2311 2131 1312 1123 3112 [OP_LIST_EOL] 3 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1231\nvar_b = 2311\nvar_c = 2131\nvar_d = 1312\nvar_e = 1123\nvar_f = 3112\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_h = list_b[-var_g]\nprint(int(var_h))",
        "solution_code_en": "var_a = 1231\nvar_b = 2311\nvar_c = 2131\nvar_d = 1312\nvar_e = 1123\nvar_f = 3112\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_h = list_b[-var_g]\nprint(int(var_h))"
    },
    "6669": {
        "category": "Geometry",
        "question_ko": "길 한쪽에 60미터(m) 간격으로 가로등이 45개 서 있습니다. 처음 가로등에서 마지막 가로등까지의 거리는 몇 킬로미터(㎞)입니까?",
        "question_en": "There are 45 streetlights on one side of the road, spaced at 60 meters (m) intervals. What is the distance in kilometers (km) from the first street lamp to the last lamp?",
        "answer_ko": "2.64",
        "answer_en": "2.64",
        "solution_abst_ko": "60 1000 [OP_DIV] 45 1 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "60 1000 [OP_DIV] 45 1 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 60\nvar_b = 1000\nvar_c = var_a / var_b\nvar_d = 45\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_c * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 60\nvar_b = 1000\nvar_c = var_a / var_b\nvar_d = 45\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_c * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "6670": {
        "category": "Correspondence",
        "question_ko": "10을 어떤 수에서 뺐더니 결과값으로 15를 얻었습니다. 어떤 수에 5를 더하면 얼마입니까?",
        "question_en": "Subtracting 10 from a number resulted in 15. What is the result when the number is added by 5?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "15 10 [OP_ADD] 5 [OP_ADD]",
        "solution_abst_en": "15 10 [OP_ADD] 5 [OP_ADD]",
        "solution_code_ko": "var_a = 15\nvar_b = 10\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 10\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "6671": {
        "category": "Comparison",
        "question_ko": "3.006보다 크고 3.01보다 작은 소수 세 자리 수는 모두 몇 개 입니까?",
        "question_en": "How many three-digit decimal numbers exist that are greater than 3.006 and less than 3.01?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "0 9 1 [OP_LIST_ARANGE] 6 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "0 9 1 [OP_LIST_ARANGE] 6 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 0\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "6672": {
        "category": "Arithmetic calculation",
        "question_ko": "숫자 5, 8, 2로 나누어 떨어질 수 있는 세 자리 수는 모두 몇 개 있습니까?",
        "question_en": "How many three-digit numbers are divisible by the numbers 5, 8, and 2?",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "100 999 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 2 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "100 999 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 2 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 8\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 2\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))",
        "solution_code_en": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 8\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 2\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))"
    },
    "6673": {
        "category": "Arithmetic calculation",
        "question_ko": "장난감 기차는 5미터(m)를 가는데 3분이 걸립니다. 장난감 자동차는 같은 거리를 2분에 갈 수 있습니다. 장난감 자동차의 출발선이 기차보다 20미터(m) 뒤에 있고 동시에 두 장난감을 출발시킨다면 두 장난감이 만나게 되는 시간은 몇 분 후 인지 구하세요.",
        "question_en": "A toy train takes 3 minutes to travel 5 meters (m). A toy car can travel the same distance in 2 minutes. If the start line of the toy car is 20 meters (m) behind the train and both toys start at the same time, how many minutes will it be before the two toys meet?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "20 5 2 [OP_DIV] 5 3 [OP_DIV] [OP_SUB] [OP_DIV]",
        "solution_abst_en": "20 5 2 [OP_DIV] 5 3 [OP_DIV] [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 20\nvar_b = 5\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = 5\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = var_d - var_g\nvar_i = var_a / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))",
        "solution_code_en": "var_a = 20\nvar_b = 5\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = 5\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = var_d - var_g\nvar_i = var_a / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))"
    },
    "6674": {
        "category": "Geometry",
        "question_ko": "직각삼각형에서, 빗변이 17, 빗변이 아닌 한 변이 15의 길이를 갖는다면 나머지 한 변의 길이는 얼마일까요?",
        "question_en": "In a right triangle, if the hypotenuse is 17 and the non-hypotenuse has length 15, what is the length of the other side?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "17 2 [OP_POW] 15 2 [OP_POW] [OP_SUB] 1/2 [OP_POW]",
        "solution_abst_en": "17 2 [OP_POW] 15 2 [OP_POW] [OP_SUB] 1/2 [OP_POW]",
        "solution_code_ko": "var_a = 17\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 15\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c - var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 17\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 15\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c - var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))"
    },
    "6675": {
        "category": "Comparison",
        "question_ko": "현우의 키는 1.32미터(m)이고, 진희의 키는 1.3미터(m)입니다. 키가 더 큰 사람은 누구입니까?",
        "question_en": "Hyunwoo is 1.32 meters (m) tall, and Jinhee is 1.3 meters (m) tall. Who is taller?",
        "answer_ko": "현우",
        "answer_en": "Hyunwoo",
        "solution_abst_ko": "[OP_LIST_SOL] 현우 진희 [OP_LIST_EOL] [OP_LIST_SOL] 1.32 1.3 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Hyunwoo Jinhee [OP_LIST_EOL] [OP_LIST_SOL] 1.32 1.3 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '현우'\nvar_b = '진희'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.32\nvar_d = 1.3\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Hyunwoo'\nvar_b = 'Jinhee'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.32\nvar_d = 1.3\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "6676": {
        "category": "Correspondence",
        "question_ko": "지호는 생선가게에서 가지고 있던 돈의 1/2을 썻고,과일가게에서 남은 돈의 1/3보다 5000원 많게 썼습니다. 남은 금액이 5000원이라면 지호가 처음 가지고 있던 돈은 얼마입니까?",
        "question_en": "Jiho spent 1/2 of the money he had at the fish shop and spent 5,000 won more than 1/3 of the remaining money at the fruit shop. If the amount of money left is 5,000 won, how much money did Jiho initially have?",
        "answer_ko": "30000",
        "answer_en": "30000",
        "solution_abst_ko": "5000 5000 [OP_ADD] 1 1/3 [OP_SUB] [OP_DIV] 1 1/2 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "5000 5000 [OP_ADD] 1 1/3 [OP_SUB] [OP_DIV] 1 1/2 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 5000\nvar_b = 5000\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 0.3333333333333333\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 1\nvar_i = 0.5\nvar_j = var_h - var_i\nvar_k = var_g / var_j\nprint(int(eval('{:.2f}'.format(round(var_k+1e-10,2)))))",
        "solution_code_en": "var_a = 5000\nvar_b = 5000\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 0.3333333333333333\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 1\nvar_i = 0.5\nvar_j = var_h - var_i\nvar_k = var_g / var_j\nprint(int(eval('{:.2f}'.format(round(var_k+1e-10,2)))))"
    },
    "6677": {
        "category": "Correspondence",
        "question_ko": "3+A=4에서 A에 알맞은 수를 쓰시오.",
        "question_en": "Write down the correct number for A in 3+A=4.",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "4 3 [OP_SUB]",
        "solution_abst_en": "4 3 [OP_SUB]",
        "solution_code_ko": "var_a = 4\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "6678": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 12를 나누려고 합니다. 잘못하여 42를 뺐을 때의 답이 30이라면 바르게 계산한 결과는 얼마일까요?",
        "question_en": "You want to divide 12 by some number. If the answer when you mistakenly subtract 42 is 30, what is the correct calculation result?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "30 42 [OP_ADD] 12 [OP_DIV]",
        "solution_abst_en": "30 42 [OP_ADD] 12 [OP_DIV]",
        "solution_code_ko": "var_a = 30\nvar_b = 42\nvar_c = var_a + var_b\nvar_d = 12\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 30\nvar_b = 42\nvar_c = var_a + var_b\nvar_d = 12\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "6679": {
        "category": "Correspondence",
        "question_ko": "3+6AB=691일 때, A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "When 3+6AB=691, what number should go in A, where 6AB is a three-digit number?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "3+6AB=691 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "3+6AB=691 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '3+6AB=691'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '3+6AB=691'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "6680": {
        "category": "Possibility",
        "question_ko": "A, B, C, D, E, F 6명을 한 줄로 세울 때, E, F를 서로 이웃하게 하여 세우는 경우의 수를 구하시오.",
        "question_en": "When 6 people A, B, C, D, E, F are lined up in a line, find the number of ways to put E and F next to each other.",
        "answer_ko": "240",
        "answer_en": "240",
        "solution_abst_ko": "[OP_LIST_SOL] A B C D E F [OP_LIST_EOL] [OP_LIST_SOL] A [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] E F [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D E F [OP_LIST_EOL] [OP_LIST_SOL] A [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] E F [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nvar_f = 'F'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 'A'\nlist_b= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_h = len(list_c)\nvar_i = len(list_c)\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nvar_k = 'E'\nvar_l = 'F'\nlist_d= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_d.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_d.append(var_k)\nlist_d.reverse()\nvar_m = len(list_d)\nvar_n = len(list_d)\nvar_o = 1\nvar_m = int(var_m)\nvar_n = int(var_n)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o * (var_m-i)\nvar_p = var_j * var_o\nprint(int(var_p))",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nvar_f = 'F'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 'A'\nlist_b= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_h = len(list_c)\nvar_i = len(list_c)\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nvar_k = 'E'\nvar_l = 'F'\nlist_d= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_d.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_d.append(var_k)\nlist_d.reverse()\nvar_m = len(list_d)\nvar_n = len(list_d)\nvar_o = 1\nvar_m = int(var_m)\nvar_n = int(var_n)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o * (var_m-i)\nvar_p = var_j * var_o\nprint(int(var_p))"
    },
    "6681": {
        "category": "Arithmetic calculation",
        "question_ko": "길준이는 1.05킬로미터(㎞)를 달렸고, 시연이는 길준이보다 460미터(m) 더 적게 달렸습니다. 시연이는 몇 킬로미터(㎞)를 달렸습니까?",
        "question_en": "Giljun ran 1.05 kilometers (km), and Siyeon ran 460 meters (m) less than Giljun. How many kilometers did Siyeon run?",
        "answer_ko": "0.59",
        "answer_en": "0.59",
        "solution_abst_ko": "1.05 460 1000 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "1.05 460 1000 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 1.05\nvar_b = 460\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 1.05\nvar_b = 460\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "6682": {
        "category": "Arithmetic calculation",
        "question_ko": "정민이가 키우는 강아지의 몸무게는 2킬로그램(㎏) 600그램(g)이고, 고양이의 무게는 3700그램(g)입니다. 정민이가 기르는 동물의 무게의 합은 몇 그램(g)인지 구하시오.",
        "question_en": "Bomin walked 2 kilometers (km) and 600 meters (m) today, and Yunshik walked 3700 meters (m). How many meters (m) did Bomin and Yoonshik walk today?",
        "answer_ko": "6300",
        "answer_en": "6300",
        "solution_abst_ko": "2 1000 [OP_MUL] 600 [OP_ADD] 3700 [OP_ADD]",
        "solution_abst_en": "2 1000 [OP_MUL] 600 [OP_ADD] 3700 [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 600\nvar_e = var_c + var_d\nvar_f = 3700\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 600\nvar_e = var_c + var_d\nvar_f = 3700\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "6683": {
        "category": "Comparison",
        "question_ko": "정국이는 19번째 계단에 서 있습니다. 유정이는 정국이보다 8계단 위에 서 있고, 석진이는 유정이보다 5계단 아래에 서 있습니다. 석진이는 정국이보다 몇 계단 위에 서 있습니까?",
        "question_en": "Jungkook is standing on the 19th stair. Yoojeong is 8 steps above Jungkook, and Seokjin is 5 steps below Yoojeong. How many steps does Seokjin stand above Jungkook?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "19 8 [OP_ADD] 5 [OP_SUB] 19 [OP_SUB]",
        "solution_abst_en": "19 8 [OP_ADD] 5 [OP_SUB] 19 [OP_SUB]",
        "solution_code_ko": "var_a = 19\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c - var_d\nvar_f = 19\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 19\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c - var_d\nvar_f = 19\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "6684": {
        "category": "Arithmetic calculation",
        "question_ko": "남준이는 구슬을 6개씩 6 상자에 나누어 담으려고 합니다. 현재 남준이는 7개씩 담긴 구슬 묶음이 3개 있을 때, 몇 개의 구슬이 모자랍니까?",
        "question_en": "Namjoon wants to divide the marbles into 6 boxes of 6 each. If Namjoon currently has 3 sets of 7 marbles, how many marbles are missing?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "6 6 [OP_MUL] 7 3 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "6 6 [OP_MUL] 7 3 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 6\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 6\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "6685": {
        "category": "Possibility",
        "question_ko": "민수는 국어 문제집 2권, 영어 문제집 2권을 책꽂이에 일렬로 꽂으려고 한다. 영어 문제집끼리 나란히 꽂는 방법은 모두 몇 가지인가?",
        "question_en": "Minsu tries to put 2 Korean and 2 English workbooks in a row on the bookshelf. How many ways are there to put English workbooks side by side?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "2 1 [OP_ADD] 2 1 [OP_ADD] [OP_PERM] 2 [OP_MUL]",
        "solution_abst_en": "2 1 [OP_ADD] 2 1 [OP_ADD] [OP_PERM] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = 1\nvar_c = int(var_c)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_c-i)\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 2\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = 1\nvar_c = int(var_c)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_c-i)\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "6686": {
        "category": "Arithmetic calculation",
        "question_ko": "승훈이네 집과 학교 사이의 거리는 1.05킬로미터(㎞)이고, 영준이네 집과 학교 사이의 거리는 승훈이네 집과 학교 사이의 거리보다 460미터(m) 더 가깝습니다. 영준이네 집과 학교 사이의 거리는 몇 킬로미터(㎞)입니까?",
        "question_en": "The distance between Seunghun's house and school is 1.05 kilometers (km), and the distance between Youngjun's house and school is 460 meters (m) closer than the distance between Seunghun's house and school. How many kilometers (km) is the distance between Youngjun's house and the school?",
        "answer_ko": "0.59",
        "answer_en": "0.59",
        "solution_abst_ko": "1.05 460 1000 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "1.05 460 1000 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 1.05\nvar_b = 460\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 1.05\nvar_b = 460\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "6687": {
        "category": "Possibility",
        "question_ko": "4, 5, 8, 9 중 3개를 사용하여 십의 자리 숫자가 5인 두 번째 작은 수는 무엇입니까?",
        "question_en": "Using 3 of 4, 5, 8, and 9, what is the second smallest number whose tens place is 5?",
        "answer_ko": "459",
        "answer_en": "459",
        "solution_abst_ko": "[OP_LIST_SOL] 4 5 8 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 5 [OP_LIST_SEARCH_FIXED_DIGIT] 2 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 4 5 8 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 5 [OP_LIST_SEARCH_FIXED_DIGIT] 2 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 4\nvar_b = 5\nvar_c = 8\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 5\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 2\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nprint(int(var_i))",
        "solution_code_en": "var_a = 4\nvar_b = 5\nvar_c = 8\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 5\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 2\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nprint(int(var_i))"
    },
    "6688": {
        "category": "Arithmetic calculation",
        "question_ko": "석기는 가지고 있던 돈 16000원의 4/5보다 2800원 적은 돈으로 800원짜리 바나나와 400원짜리 키위를 합하여 18개 샀습니다. 바나나를 사는 데 든 돈은 얼마인지 구하시오.",
        "question_en": "Seokgi bought bananas for 800 won and kiwis for 400 won, and he bought 18 bananas and kiwis in total. He used 2,800 won less than 4/5 of the 16,000 won he had. Find how much money it cost to buy bananas.",
        "answer_ko": "5600",
        "answer_en": "5600",
        "solution_abst_ko": "16000 4/5 [OP_MUL] 2800 [OP_SUB] 400 18 [OP_MUL] [OP_SUB] 800 400 [OP_SUB] [OP_DIV] 800 [OP_MUL]",
        "solution_abst_en": "16000 4/5 [OP_MUL] 2800 [OP_SUB] 400 18 [OP_MUL] [OP_SUB] 800 400 [OP_SUB] [OP_DIV] 800 [OP_MUL]",
        "solution_code_ko": "var_a = 16000\nvar_b = 0.8\nvar_c = var_a * var_b\nvar_d = 2800\nvar_e = var_c - var_d\nvar_f = 400\nvar_g = 18\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nvar_j = 800\nvar_k = 400\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nvar_n = 800\nvar_o = var_m * var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 16000\nvar_b = 0.8\nvar_c = var_a * var_b\nvar_d = 2800\nvar_e = var_c - var_d\nvar_f = 400\nvar_g = 18\nvar_h = var_f * var_g\nvar_i = var_e - var_h\nvar_j = 800\nvar_k = 400\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nvar_n = 800\nvar_o = var_m * var_n\nprint(int(var_o))"
    },
    "6689": {
        "category": "Comparison",
        "question_ko": "4대의 버스 A, B, C, D가 있습니다. 버스 D에는 가장 적은 승객들이 타고 있고, 버스 B가 버스 A보다 많은 승객을 태우고 있고, 버스 A는 버스 C보다 많은 승객들이 타고 있습니다. 가장 많은 승객을 태운 버스는 무엇일까요?",
        "question_en": "There are 4 buses A, B, C, and D. Bus D has the fewest passengers, and bus B has more passengers than bus A, and bus A has more passengers than bus C. Which bus has the most passengers?",
        "answer_ko": "B",
        "answer_en": "B",
        "solution_abst_ko": "[OP_LIST_SOL] A B C D [OP_LIST_EOL] [OP_LIST_SOL] A C > B A > D A < D B < D C < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D [OP_LIST_EOL] [OP_LIST_SOL] A C > B A > D A < D B < D C < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'A'\nvar_f = 'C'\nvar_g = '>'\nvar_h = 'B'\nvar_i = 'A'\nvar_j = '>'\nvar_k = 'D'\nvar_l = 'A'\nvar_m = '<'\nvar_n = 'D'\nvar_o = 'B'\nvar_p = '<'\nvar_q = 'D'\nvar_r = 'C'\nvar_s = '<'\nlist_b= []\nif \"/\" in str(var_s):\n    var_s = eval(str(var_s))\nlist_b.append(var_s)\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_t = 1\nvar_u = list_c[var_t-1]\nprint(var_u)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'A'\nvar_f = 'C'\nvar_g = '>'\nvar_h = 'B'\nvar_i = 'A'\nvar_j = '>'\nvar_k = 'D'\nvar_l = 'A'\nvar_m = '<'\nvar_n = 'D'\nvar_o = 'B'\nvar_p = '<'\nvar_q = 'D'\nvar_r = 'C'\nvar_s = '<'\nlist_b= []\nif \"/\" in str(var_s):\n    var_s = eval(str(var_s))\nlist_b.append(var_s)\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_t = 1\nvar_u = list_c[var_t-1]\nprint(var_u)"
    },
    "6690": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 연속된 짝수의 합은 3개의 짝수 중 가장 작은 짝수보다 18만큼 큽니다. 3개의 짝수 중에서 가장 큰 수를 쓰시오.",
        "question_en": "The sum of 3 consecutive even numbers is 18 greater than the smallest of the 3 even numbers. Write the largest of the three even numbers.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "18 2 1 [OP_MUL] 2 2 [OP_MUL] [OP_ADD] [OP_SUB] 3 1 [OP_SUB] [OP_DIV] 2 2 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "18 2 1 [OP_MUL] 2 2 [OP_MUL] [OP_ADD] [OP_SUB] 3 1 [OP_SUB] [OP_DIV] 2 2 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 18\nvar_b = 2\nvar_c = 1\nvar_d = var_b * var_c\nvar_e = 2\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = var_d + var_g\nvar_i = var_a - var_h\nvar_j = 3\nvar_k = 1\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nvar_n = 2\nvar_o = 2\nvar_p = var_n * var_o\nvar_q = var_m + var_p\nprint(int(var_q))",
        "solution_code_en": "var_a = 18\nvar_b = 2\nvar_c = 1\nvar_d = var_b * var_c\nvar_e = 2\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = var_d + var_g\nvar_i = var_a - var_h\nvar_j = 3\nvar_k = 1\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nvar_n = 2\nvar_o = 2\nvar_p = var_n * var_o\nvar_q = var_m + var_p\nprint(int(var_q))"
    },
    "6691": {
        "category": "Comparison",
        "question_ko": "정사각형, 정삼각형, 원이 있습니다. 정사각형 한 변의 길이는 7센티미터(cm), 정삼각형의 한 변의 길이는 9센티미터(cm), 원의 반지름은 5센티미터(cm) 입니다. 원주율을 3으로 계산 할 때 둘레의 길이가 가장 긴 도형은 어느 것입니까?",
        "question_en": "There is a square, equilateral-triangle, and circle. The length of a side of a square is 7 centimeters (cm), the length of a side of an equilateral-triangle is 9 centimeters (cm), and the radius of a circle is 5 centimeters (cm). Which shape has the longest perimeter when the circumference of a circle is 3?",
        "answer_ko": "원",
        "answer_en": "circle",
        "solution_abst_ko": "[OP_LIST_SOL] 정사각형 정삼각형 원 [OP_LIST_EOL] [OP_LIST_SOL] 7 4 [OP_MUL] 9 3 [OP_MUL] 5 3 2 [OP_MUL] [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] square equilateral-triangle circle [OP_LIST_EOL] [OP_LIST_SOL] 7 4 [OP_MUL] 9 3 [OP_MUL] 5 3 2 [OP_MUL] [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정사각형'\nvar_b = '정삼각형'\nvar_c = '원'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 7\nvar_e = 4\nvar_f = var_d * var_e\nvar_g = 9\nvar_h = 3\nvar_i = var_g * var_h\nvar_j = 5\nvar_k = 3\nvar_l = 2\nvar_m = var_k * var_l\nvar_n = var_j * var_m\nlist_b= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_o = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_p = list_c[-var_o]\nvar_q = list_b.index(var_p)+1\nvar_r = list_a[var_q-1]\nprint(var_r)",
        "solution_code_en": "var_a = 'square'\nvar_b = 'equilateral-triangle'\nvar_c = 'circle'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 7\nvar_e = 4\nvar_f = var_d * var_e\nvar_g = 9\nvar_h = 3\nvar_i = var_g * var_h\nvar_j = 5\nvar_k = 3\nvar_l = 2\nvar_m = var_k * var_l\nvar_n = var_j * var_m\nlist_b= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_o = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_p = list_c[-var_o]\nvar_q = list_b.index(var_p)+1\nvar_r = list_a[var_q-1]\nprint(var_r)"
    },
    "6692": {
        "category": "Possibility",
        "question_ko": "서로 색을 가진 4개의 공을 2개의 바구니에 담으려고 합니다. 이때, 바구니에 공이 담기지 않을 수 있습니다. 공을 바구니에 담는 경우는 모두 몇 가지입니까?",
        "question_en": "You are trying to put 4 balls of different colors into 2 baskets. At this time, the ball may not be put in the basket. How many ways are there for you to put the ball into the basket?",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "2 4 [OP_POW]",
        "solution_abst_en": "2 4 [OP_POW]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = var_a ** var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = var_a ** var_b\nprint(int(var_c))"
    },
    "6693": {
        "category": "Possibility",
        "question_ko": "일렬로 있는 6개의 의자에 남학생 3명과 여학생 3명이 각자 앉는다. 여학생 3명이 연속하여 앉아 있을 확률을 구하시오.",
        "question_en": "Three male students and three female students sit on six chairs in a row. Figure out the probability of 3 female students sitting in a row.",
        "answer_ko": "144",
        "answer_en": "144",
        "solution_abst_ko": "3 3 [OP_ADD] 3 1 [OP_SUB] [OP_SUB] 3 3 [OP_ADD] 3 1 [OP_SUB] [OP_SUB] [OP_PERM] 3 3 [OP_PERM] [OP_MUL]",
        "solution_abst_en": "3 3 [OP_ADD] 3 1 [OP_SUB] [OP_SUB] 3 3 [OP_ADD] 3 1 [OP_SUB] [OP_SUB] [OP_PERM] 3 3 [OP_PERM] [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nvar_h = 3\nvar_i = 3\nvar_j = var_h + var_i\nvar_k = 3\nvar_l = 1\nvar_m = var_k - var_l\nvar_n = var_j - var_m\nvar_o = 1\nvar_g = int(var_g)\nvar_n = int(var_n)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o * (var_g-i)\nvar_p = 3\nvar_q = 3\nvar_r = 1\nvar_p = int(var_p)\nvar_q = int(var_q)\nfor i, elem in enumerate(range(var_q)):\n    var_r = var_r * (var_p-i)\nvar_s = var_o * var_r\nprint(int(var_s))",
        "solution_code_en": "var_a = 3\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nvar_h = 3\nvar_i = 3\nvar_j = var_h + var_i\nvar_k = 3\nvar_l = 1\nvar_m = var_k - var_l\nvar_n = var_j - var_m\nvar_o = 1\nvar_g = int(var_g)\nvar_n = int(var_n)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o * (var_g-i)\nvar_p = 3\nvar_q = 3\nvar_r = 1\nvar_p = int(var_p)\nvar_q = int(var_q)\nfor i, elem in enumerate(range(var_q)):\n    var_r = var_r * (var_p-i)\nvar_s = var_o * var_r\nprint(int(var_s))"
    },
    "6694": {
        "category": "Correspondence",
        "question_ko": "지수는 6000원 중 3200원으로는 볼펜을 사고 1000원으로 지우개를 사고 500원으로는 사탕을 샀다. 남은 돈은 모두 저금했다고 할 때, 지수가 저금한 금액을 구하시오.",
        "question_en": "Jisoo had 6,000 won and she bought a ballpoint pen for 3,200 won, an eraser for 1,000 won, and candy for 500 won. Assuming that all remaining money is saved, find the amount saved.",
        "answer_ko": "1300",
        "answer_en": "1300",
        "solution_abst_ko": "6000 3200 [OP_SUB] 1000 [OP_SUB] 500 [OP_SUB]",
        "solution_abst_en": "6000 3200 [OP_SUB] 1000 [OP_SUB] 500 [OP_SUB]",
        "solution_code_ko": "var_a = 6000\nvar_b = 3200\nvar_c = var_a - var_b\nvar_d = 1000\nvar_e = var_c - var_d\nvar_f = 500\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 6000\nvar_b = 3200\nvar_c = var_a - var_b\nvar_d = 1000\nvar_e = var_c - var_d\nvar_f = 500\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "6695": {
        "category": "Arithmetic calculation",
        "question_ko": "연필 1타는 12자루입니다. 남준이는 연필을 2타 가지고 있었습니다. 남준이가 연필 몇 자루를 윤기에게 주었더니 15자루가 남았습니다. 윤기에게 준 연필은 몇 자루입니까?",
        "question_en": "One stroke is 12 pencils. Namjoon had two strokes of a pencil. Namjoon gave some pencils to Yoongi, and there were 15 left. How many pencils did you give Yoongi?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "12 2 [OP_MUL] 15 [OP_SUB]",
        "solution_abst_en": "12 2 [OP_MUL] 15 [OP_SUB]",
        "solution_code_ko": "var_a = 12\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 15\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 15\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "6696": {
        "category": "Comparison",
        "question_ko": "석진이는 수영 시합에서 8등을 했습니다. 결승선에 석진이보다 빨리 들어온 사람은 모두 몇 명입니까?",
        "question_en": "Seokjin placed the 8th in the swimming competition. How many people got in the finish line faster than Seokjin?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "8 1 [OP_SUB]",
        "solution_abst_en": "8 1 [OP_SUB]",
        "solution_code_ko": "var_a = 8\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 8\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "6697": {
        "category": "Arithmetic calculation",
        "question_ko": "집합 A의 원소는 1/2, 1/3, 1/5이고, 집합 B의 원소는 0.2, 0.4, 0.5, 0.7일 때 A 차집합 B의 원소의 개수를 구하시오.",
        "question_en": "If the elements of set A are 1/2, 1/3, and 1/5, and the elements of set B are 0.2, 0.4, 0.5, and 0.7, find the number of elements in set A minus set B.",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 1/2 1/3 1/5 [OP_LIST_EOL] [OP_LIST_SOL] 0.2 0.4 0.5 0.7 [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1/2 1/3 1/5 [OP_LIST_EOL] [OP_LIST_SOL] 0.2 0.4 0.5 0.7 [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.5\nvar_b = 0.3333333333333333\nvar_c = 0.2\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.2\nvar_e = 0.4\nvar_f = 0.5\nvar_g = 0.7\nlist_b= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_h = len(list_c)\nprint(int(var_h))",
        "solution_code_en": "var_a = 0.5\nvar_b = 0.3333333333333333\nvar_c = 0.2\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.2\nvar_e = 0.4\nvar_f = 0.5\nvar_g = 0.7\nlist_b= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_h = len(list_c)\nprint(int(var_h))"
    },
    "6698": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 69를 곱해야 하는데 잘못하여 어떤 수를 96으로 나누었더니 몫이 5이고 나머지가 17이었습니다. 바르게 계산한 답은 얼마일까요?",
        "question_en": "A number needs to be multiplied by 69, but when you mistakenly divide a number by 96, the quotient is 5 and the remainder is 17. What is the correct answer?",
        "answer_ko": "34293",
        "answer_en": "34293",
        "solution_abst_ko": "5 96 [OP_MUL] 17 [OP_ADD] 69 [OP_MUL]",
        "solution_abst_en": "5 96 [OP_MUL] 17 [OP_ADD] 69 [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 96\nvar_c = var_a * var_b\nvar_d = 17\nvar_e = var_c + var_d\nvar_f = 69\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 96\nvar_c = var_a * var_b\nvar_d = 17\nvar_e = var_c + var_d\nvar_f = 69\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "6699": {
        "category": "Comparison",
        "question_ko": "호석이와 친구 16명이 한 줄로 서 있습니다. 호석이의 오른쪽에 8명이 서 있다면 호석이의 왼쪽에는 몇 명이 서 있습니까?",
        "question_en": "Hoseok and 16 of his friends are standing in a line. If 8 people are standing to the right of Hoseok, how many people are standing to the left of Hoseok?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "16 8 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "16 8 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 16\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 16\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "6700": {
        "category": "Correspondence",
        "question_ko": "305에 어떤 수를 더하고 16으로 나누었더니 31이 나왔습니다. 어떤 수를 구하시오.",
        "question_en": "When you add a number to 305 and divide it by 16, you get 31. Find the number.",
        "answer_ko": "191",
        "answer_en": "191",
        "solution_abst_ko": "31 16 [OP_MUL] 305 [OP_SUB]",
        "solution_abst_en": "31 16 [OP_MUL] 305 [OP_SUB]",
        "solution_code_ko": "var_a = 31\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 305\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 31\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 305\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "6701": {
        "category": "Comparison",
        "question_ko": "2.23, 3.12, 9.434 및 2.453를 작은 순으로 놓았습니다. 두번째로 놓이는 수는 무엇입니까?",
        "question_en": "I sorted 2.23, 3.12, 9.434, and 2.453 in ascending order. What is the number that comes in the second?",
        "answer_ko": "2.45",
        "answer_en": "2.45",
        "solution_abst_ko": "[OP_LIST_SOL] 2.23 3.12 9.434 2.453 [OP_LIST_EOL] 2 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 2.23 3.12 9.434 2.453 [OP_LIST_EOL] 2 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 2.23\nvar_b = 3.12\nvar_c = 9.434\nvar_d = 2.453\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nprint('{:.2f}'.format(round(var_f+1e-10,2)))",
        "solution_code_en": "var_a = 2.23\nvar_b = 3.12\nvar_c = 9.434\nvar_d = 2.453\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nprint('{:.2f}'.format(round(var_f+1e-10,2)))"
    },
    "6702": {
        "category": "Correspondence",
        "question_ko": "네 수 A, B, C, D가 있습니다. 네 자리 수끼리의 덧셈식 AB4C+17D8=5671에서 B를 구하시오.",
        "question_en": "There are four numbers A, B, C, and D. Find B from the four-digit addition formula, AB4C+17D8=5671.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "AB4C+17D8=5671 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "AB4C+17D8=5671 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'AB4C+17D8=5671'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'AB4C+17D8=5671'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "6703": {
        "category": "Arithmetic calculation",
        "question_ko": "리본 고리를 만들기 위해 리본을 0.82밀리미터(㎜)씩 자르려고 합니다. 리본 53.73밀리미터(㎜)로 고리를 만들고 남는 리본은 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "You want to cut a ribbon in pieces of 0.82 millimeters (mm) to make a ribbon loop. Make a loop with 53.73 millimeters (mm) of ribbon and find how many centimeters (cm) of ribbon are left.",
        "answer_ko": "0.04",
        "answer_en": "0.04",
        "solution_abst_ko": "53.73 0.82 [OP_MOD] 10 [OP_DIV]",
        "solution_abst_en": "53.73 0.82 [OP_MOD] 10 [OP_DIV]",
        "solution_code_ko": "var_a = 53.73\nvar_b = 0.82\nvar_c = var_a % var_b\nvar_d = 10\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 53.73\nvar_b = 0.82\nvar_c = var_a % var_b\nvar_d = 10\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "6704": {
        "category": "Correspondence",
        "question_ko": "A3+61B=695라는 식이 성립하려면, B에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "What number must be in B to make A3+61B=695, where A3 and 61B are each two-digit number and three-digit number?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "A3+61B=695 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A3+61B=695 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A3+61B=695'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A3+61B=695'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "6705": {
        "category": "Possibility",
        "question_ko": "4장의 숫자 2, 4, 8, 6이 적힌 카드 중에서 3장을 골라 만들 수 있는 세 자리 수의 개수를 구하시오",
        "question_en": "Write down the number of three-digit numbers that can be made by choosing three cards from four cards written as 2, 4, 8, and 6.",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "[OP_LIST_SOL] 2 4 8 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 2 4 8 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = 8\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = 8\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "6706": {
        "category": "Arithmetic calculation",
        "question_ko": "유정이는 가지고 있던 구슬 중에서 은지에게 8개를 주었더니 24개가 남았습니다. 처음에 유정이가 가지고 있던 구슬은 몇 개입니까?",
        "question_en": "Yoojeong gave 8 of the marbles she had to Eunji, and there were 24 left. How many marbles did Yoojung have at first?",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "24 8 [OP_ADD]",
        "solution_abst_en": "24 8 [OP_ADD]",
        "solution_code_ko": "var_a = 24\nvar_b = 8\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 24\nvar_b = 8\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "6707": {
        "category": "Geometry",
        "question_ko": "어떤 사다리꼴 모양의 지붕을 그렸습니다. 윗변이 5센티미터(㎝), 아랫변이 9센티미터(㎝)이고, 넓이가 56제곱센티미터(㎠)라면, 이 지붕의 높이는 몇 센티미터(㎝)입니까?",
        "question_en": "I painted some trapezoidal roofs. If the top side is 5 centimeters (cm), the bottom side is 9 centimeters (cm), and the area is 56 square cm (cm 2), what is the height in centimeters (cm) of this roof?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "56 2 [OP_MUL] 5 9 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "56 2 [OP_MUL] 5 9 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 56\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = 9\nvar_f = var_d + var_e\nvar_g = var_c / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 56\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = 9\nvar_f = var_d + var_e\nvar_g = var_c / var_f\nprint(int(var_g))"
    },
    "6708": {
        "category": "Correspondence",
        "question_ko": "A는 100개씩 묶음이 55개, 10개씩 묶음이 19개인 수입니다. B는 173에서 224씩 커지게 5번 뛰어서 센 수입니다. A-B의 값을 구하시오.",
        "question_en": "A is the number of 55 groups of 100 and 19 groups of 10. B is the number that jumps 5 times from 173 in an increment of 224. Find the value of A-B.",
        "answer_ko": "4397",
        "answer_en": "4397",
        "solution_abst_ko": "100 55 [OP_MUL] 10 19 [OP_MUL] [OP_ADD] 173 224 5 [OP_MUL] [OP_ADD] [OP_SUB]",
        "solution_abst_en": "100 55 [OP_MUL] 10 19 [OP_MUL] [OP_ADD] 173 224 5 [OP_MUL] [OP_ADD] [OP_SUB]",
        "solution_code_ko": "var_a = 100\nvar_b = 55\nvar_c = var_a * var_b\nvar_d = 10\nvar_e = 19\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 173\nvar_i = 224\nvar_j = 5\nvar_k = var_i * var_j\nvar_l = var_h + var_k\nvar_m = var_g - var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 100\nvar_b = 55\nvar_c = var_a * var_b\nvar_d = 10\nvar_e = 19\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 173\nvar_i = 224\nvar_j = 5\nvar_k = var_i * var_j\nvar_l = var_h + var_k\nvar_m = var_g - var_l\nprint(int(var_m))"
    },
    "6709": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.9, 1/3 중에서 0.4보다 크거나 같은 수를 모두 더하면 얼마일까요?",
        "question_en": "What is the sum of all numbers greater than or equal to 0.4 among 0.8, 1/2, 0.9, and 1/3?",
        "answer_ko": "2.20",
        "answer_en": "2.2",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_MORE_EQUAL] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_MORE_EQUAL] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.4\nlist_b = []\nfor i in list_a:\n    if i >= var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint('{:.2f}'.format(round(var_f+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.4\nlist_b = []\nfor i in list_a:\n    if i >= var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint('{:.2f}'.format(round(var_f+1e-10,2)))"
    },
    "6710": {
        "category": "Geometry",
        "question_ko": "직사각형의 두 변의 길이가 9 센티미터(㎝), 11 센티미터(㎝)일 때 네 변의 길이의 합을 구해 보세요.",
        "question_en": "If the lengths of the two sides of a rectangle are 9 centimeters (cm) and 11 centimeters (cm), find the sum of the lengths of the four sides.",
        "answer_ko": "40",
        "answer_en": "40",
        "solution_abst_ko": "9 11 [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "9 11 [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 9\nvar_b = 11\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 11\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "6711": {
        "category": "Geometry",
        "question_ko": "각 변의 길이가 2미터(m)인 정육면체의 부피는 각 변의 길이가 100센티미터(㎝)인 정육면체의 부피의 몇 배입니까?",
        "question_en": "How many times is the volume of a cube with a side length of 2 meters (m) bigger compared to the volume of a cube with a side length of 100 centimeters (cm)?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "2 3 [OP_POW] 100 100 [OP_DIV] 3 [OP_POW] [OP_DIV]",
        "solution_abst_en": "2 3 [OP_POW] 100 100 [OP_DIV] 3 [OP_POW] [OP_DIV]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = var_a ** var_b\nvar_d = 100\nvar_e = 100\nvar_f = var_d / var_e\nvar_g = 3\nvar_h = var_f ** var_g\nvar_i = var_c / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = var_a ** var_b\nvar_d = 100\nvar_e = 100\nvar_f = var_d / var_e\nvar_g = 3\nvar_h = var_f ** var_g\nvar_i = var_c / var_h\nprint(int(var_i))"
    },
    "6712": {
        "category": "Geometry",
        "question_ko": "어떤 정사각형의 둘레의 길이는 한 변이 6센티미터(㎝)인 정육각형의 둘레의 길이와 같다고 합니다. 이 정사각형의 한 변의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "The perimeter of a square is equal to the perimeter of a regular hexagon with sides measuring 6 centimeters (cm). What is the length of one side of this square in centimeters (cm)?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "6 6 [OP_MUL] 4 [OP_DIV]",
        "solution_abst_en": "6 6 [OP_MUL] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "6713": {
        "category": "Arithmetic calculation",
        "question_ko": "6분동안 21리터(L)가 나오는 수도를 틀어 1분동안 0.3리터(L)씩 빠져나가는 욕조에 물을 받았다. 가득 채우는데 22분 30초가 걸렸다면 처음 욕조에 담긴 물은 몇 리터(L)인지 구하여라",
        "question_en": "I turned on the tap for 21 liters (L) for 6 minutes and received water in the bathtub that drained 0.3 liters (L) for 1 minute. If it took 22 minutes and 30 seconds to fill the bathtub, how many liters of water was in the bathtub at first?",
        "answer_ko": "72",
        "answer_en": "72",
        "solution_abst_ko": "21 6 [OP_DIV] 0.3 [OP_SUB] 22 30 60 [OP_DIV] [OP_ADD] [OP_MUL]",
        "solution_abst_en": "21 6 [OP_DIV] 0.3 [OP_SUB] 22 30 60 [OP_DIV] [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 21\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.3\nvar_e = var_c - var_d\nvar_f = 22\nvar_g = 30\nvar_h = 60\nvar_i = var_g / var_h\nvar_j = var_f + var_i\nvar_k = var_e * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 21\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.3\nvar_e = var_c - var_d\nvar_f = 22\nvar_g = 30\nvar_h = 60\nvar_i = var_g / var_h\nvar_j = var_f + var_i\nvar_k = var_e * var_j\nprint(int(var_k))"
    },
    "6714": {
        "category": "Arithmetic calculation",
        "question_ko": "체육관에 있는 야구공의 수는 축구공의 5배입니다. 그리고 배구공은 축구공의 3배만큼 있습니다. 야구공의 수와 배구공의 수를 더하면 160입니다. 축구공의 개수를 구하세요.",
        "question_en": "There are 5 times as many baseballs in the gym as there are soccer balls. And volleyballs has three times as much as soccer balls. The number of baseballs plus volleyballs is equal to160. Find the number of soccer balls.",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "160 5 3 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "160 5 3 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 160\nvar_b = 5\nvar_c = 3\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 160\nvar_b = 5\nvar_c = 3\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "6715": {
        "category": "Correspondence",
        "question_ko": "1A77을 버림하여 백의 자리까지 나타내면 1700이 됩니다. A를 구하시오.",
        "question_en": "Rounding down 1A77 to the hundreds place gives 1700. Find A",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "1A77 [OP_GEN_POSSIBLE_LIST] 1700 [OP_LIST_MORE_EQUAL] 1700 100 [OP_ADD] [OP_LIST_LESS] 1A77 A [OP_LIST_FIND_UNK]",
        "solution_abst_en": "1A77 [OP_GEN_POSSIBLE_LIST] 1700 [OP_LIST_MORE_EQUAL] 1700 100 [OP_ADD] [OP_LIST_LESS] 1A77 A [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = '1A77'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 1700\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 1700\nvar_d = 100\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = '1A77'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))",
        "solution_code_en": "var_a = '1A77'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 1700\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 1700\nvar_d = 100\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = '1A77'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))"
    },
    "6716": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 35, 68, 57, 95가 있습니다. 2번째로 큰 수와 가장 작은 수의 차는 얼마입니까?",
        "question_en": "There are four numbers 35, 68, 57, and 95. What is the difference between the second-largest number and the smallest number?",
        "answer_ko": "33",
        "answer_en": "33",
        "solution_abst_ko": "[OP_LIST_SOL] 35 68 57 95 [OP_LIST_EOL] 2 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 35 68 57 95 [OP_LIST_EOL] 2 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 35\nvar_b = 68\nvar_c = 57\nvar_d = 95\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 35\nvar_b = 68\nvar_c = 57\nvar_d = 95\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))"
    },
    "6717": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 가게 앞에 500명의 손님들이 줄을 서 있습니다. 모든 손님들에게 1부터 500까지의 번호표를 차례로 나눠 주었을 때, 숫자 4는 모두 몇 번 적혀 있는지 구하시오.",
        "question_en": "There are 500 customers in line in front of a store. If all customers get number tickets numbered from 1 to 500, how many times the number 4 is written on the number tickets?",
        "answer_ko": "200",
        "answer_en": "200",
        "solution_abst_ko": "1 500 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 4 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 500 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 4 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 500\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 4\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 500\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 4\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))"
    },
    "6718": {
        "category": "Correspondence",
        "question_ko": "태형이는 어떤 수에 8을 곱하려고 합니다. 하지만 실수로 5를 곱했더니 결과는 30이 되었습니다. 바르게 계산한 결과를 구하세요.",
        "question_en": "Taehyung wants to multiply a number by 8. But when he accidentally multiplied it by 5, the result came out as 30. Find the correct calculation result.",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "30 5 [OP_DIV] 8 [OP_MUL]",
        "solution_abst_en": "30 5 [OP_DIV] 8 [OP_MUL]",
        "solution_code_ko": "var_a = 30\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 8\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 30\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 8\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "6719": {
        "category": "Correspondence",
        "question_ko": "박스에 구슬이 들어있다. 박스에서 8명에게 똑같이 65개씩 나누어 주었더니 박스의 구슬을 모두 나누어 주게 되었다. 5명에게 똑같이 나누어 준다면 한 명이 몇 개의 구슬을 받는지 구하시오.",
        "question_en": "The box contains beads. When you distribute 65 marbles equally to 8 people from the box, there is no marbles left at the box. How many marbles will each person receive if all the marbles are equally distributed to 5 people?",
        "answer_ko": "104",
        "answer_en": "104",
        "solution_abst_ko": "65 8 [OP_MUL] 5 [OP_FDIV]",
        "solution_abst_en": "65 8 [OP_MUL] 5 [OP_FDIV]",
        "solution_code_ko": "var_a = 65\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 65\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "6720": {
        "category": "Correspondence",
        "question_ko": "두 자리 수의 덧셈식 AB+BC=BCB이고 A, B, C는 서로 다른 숫자일 때 A를 구하시오",
        "question_en": "Calculate A when the two-digit addition equation AB+BC=BCB and A, B, and C are different numbers.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "AB+BC=BCB A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "AB+BC=BCB A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'AB+BC=BCB'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'AB+BC=BCB'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "6721": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 20센티미터(㎝)인 색 테이프 15장을 5센티미터(㎝)씩 겹쳐서 한 줄로 길게 이어 붙이려고 합니다. 15장을 이어 붙인 색 테이프의 전체 길이는 몇 센티미터(㎝)인지 구하시오",
        "question_en": "I am going to attach 15 pieces of colored tape, every 20 centimeters (cm) in length, overlapping each other by 5 centimeters (cm) in a long line. Find the total length in centimeters (cm) of the 15 sheets of colored tape.",
        "answer_ko": "230",
        "answer_en": "230",
        "solution_abst_ko": "20 20 5 [OP_SUB] 15 1 [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_abst_en": "20 20 5 [OP_SUB] 15 1 [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 20\nvar_b = 20\nvar_c = 5\nvar_d = var_b - var_c\nvar_e = 15\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_a + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 20\nvar_b = 20\nvar_c = 5\nvar_d = var_b - var_c\nvar_e = 15\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_a + var_h\nprint(int(var_i))"
    },
    "6722": {
        "category": "Geometry",
        "question_ko": "둘레가 96센티미터(㎝)인 정사각형의 네 변의 한가운데를 이어서 그릴 수 있는 마름모의 넓이는 몇 제곱센티미터(㎠)입니까?",
        "question_en": "How many square centimeters (cm2) is the area of a rhombus that can be drawn between the four sides of a square with a circumference of 96 centimeters (cm)?",
        "answer_ko": "288",
        "answer_en": "288",
        "solution_abst_ko": "96 4 [OP_DIV] 2 [OP_POW] 2 [OP_DIV]",
        "solution_abst_en": "96 4 [OP_DIV] 2 [OP_POW] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 96\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 96\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "6723": {
        "category": "Arithmetic calculation",
        "question_ko": "아버지께서 귤 27개를 사서 18개를 은지에게 주었습니다. 아버지에게 남은 귤은 몇 개입니까?",
        "question_en": "Her father bought 27 tangerines and gave 18 to Eunji. How many tangerines does the father have left?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "27 18 [OP_SUB]",
        "solution_abst_en": "27 18 [OP_SUB]",
        "solution_code_ko": "var_a = 27\nvar_b = 18\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 27\nvar_b = 18\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "6724": {
        "category": "Geometry",
        "question_ko": "오각뿔의 모서리의 개수는?",
        "question_en": "How many edges does a pentagonal pyramid have?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "5 2 [OP_MUL]",
        "solution_abst_en": "5 2 [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "6725": {
        "category": "Geometry",
        "question_ko": "밑변의 길이가 3이고 높이가 3인 평행사변형의 넓이를 구하시오.",
        "question_en": "Find the area of a parallelogram with base length 3 and height 3.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "3 2 [OP_POW]",
        "solution_abst_en": "3 2 [OP_POW]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = var_a ** var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = var_a ** var_b\nprint(int(var_c))"
    },
    "6726": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 24를 더하려고 합니다. 잘못하여 2를 곱했을 때의 답이 50이라면 바르게 계산한 결과는 얼마일까요?",
        "question_en": "You are going to add 24 to a specific number. If the answer when multiplied by 2 incorrectly is 50, what is the result of calculating correctly?",
        "answer_ko": "49",
        "answer_en": "49",
        "solution_abst_ko": "50 2 [OP_DIV] 24 [OP_ADD]",
        "solution_abst_en": "50 2 [OP_DIV] 24 [OP_ADD]",
        "solution_code_ko": "var_a = 50\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 24\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 50\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 24\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "6727": {
        "category": "Correspondence",
        "question_ko": "주원이네 반 학생 15명 중 7명은 색종이를 가져왔고 나머지는 가져오지 않았다. 색종이를 안 가져온 학생들에게 48개의 색종이를 똑같이 나누어주었다. 학생들은 한명 당 몇 장의 색종이를 받았는지 구하시오.",
        "question_en": "In Juwon's class, 7 out of 15 students brought colored paper, and the rest did not. 48 pieces of colored paper were distributed equally to students who did not bring any colored paper. Find how many sheets of colored paper were given to students.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "48 15 7 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "48 15 7 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 48\nvar_b = 15\nvar_c = 7\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 48\nvar_b = 15\nvar_c = 7\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "6728": {
        "category": "Possibility",
        "question_ko": "가방 안에 서로 다른 색연필 10자루가 있습니다. 만약 가방에서 3자루의 색연필을 뽑는다면 가능한 경우의 수는 모두 몇 가지입니까?",
        "question_en": "There are 10 bags containing different colored pencils. If you draw 3 colored pencils from a bag, how many possible ways are there?",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "10 3 [OP_COMB]",
        "solution_abst_en": "10 3 [OP_COMB]",
        "solution_code_ko": "var_a = 10\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))",
        "solution_code_en": "var_a = 10\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))"
    },
    "6729": {
        "category": "Correspondence",
        "question_ko": "서로 다른 두 수 A, B가 있습니다. 곱셈식 AB×6=BBB에서 A와 B의 합을 구하시오.",
        "question_en": "There are two different numbers A and B. Find the sum of A and B that satisfy the multiplication equation of AB×6=BBB.",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "AB×6=BBB A [OP_DIGIT_UNK_SOLVER] AB×6=BBB B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_abst_en": "AB×6=BBB A [OP_DIGIT_UNK_SOLVER] AB×6=BBB B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_code_ko": "var_a = 'AB×6=BBB'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 'AB×6=BBB'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 'AB×6=BBB'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 'AB×6=BBB'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "6730": {
        "category": "Comparison",
        "question_ko": "A는 64를 8로 나누었을 시 나운 몫에서 27을 더한 값이다. B는 A를 7로 나눈 후 5를 곱한 수다. 두 수 A,B 중 더 작은 수는 무엇인가?",
        "question_en": "A is the quotient of 64 divided by 8 plus 27. B is the number of A divided by 7 times 5. Which number is smaller among A and B?",
        "answer_ko": "B",
        "answer_en": "B",
        "solution_abst_ko": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 64 8 [OP_DIV] 27 [OP_ADD] 64 8 [OP_DIV] 27 [OP_ADD] 7 [OP_DIV] 5 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 64 8 [OP_DIV] 27 [OP_ADD] 64 8 [OP_DIV] 27 [OP_ADD] 7 [OP_DIV] 5 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 64\nvar_d = 8\nvar_e = var_c / var_d\nvar_f = 27\nvar_g = var_e + var_f\nvar_h = 64\nvar_i = 8\nvar_j = var_h / var_i\nvar_k = 27\nvar_l = var_j + var_k\nvar_m = 7\nvar_n = var_l / var_m\nvar_o = 5\nvar_p = var_n * var_o\nlist_b= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_q = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_r = list_c[var_q-1]\nvar_s = list_b.index(var_r)+1\nvar_t = list_a[var_s-1]\nprint(var_t)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 64\nvar_d = 8\nvar_e = var_c / var_d\nvar_f = 27\nvar_g = var_e + var_f\nvar_h = 64\nvar_i = 8\nvar_j = var_h / var_i\nvar_k = 27\nvar_l = var_j + var_k\nvar_m = 7\nvar_n = var_l / var_m\nvar_o = 5\nvar_p = var_n * var_o\nlist_b= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_q = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_r = list_c[var_q-1]\nvar_s = list_b.index(var_r)+1\nvar_t = list_a[var_s-1]\nprint(var_t)"
    },
    "6731": {
        "category": "Arithmetic calculation",
        "question_ko": "형은 2800원, 동생은 1500원을 가지고 있습니다. 형이 동생에게 얼마를 주면 형은 동생보다 360원이 많게 됩니다. 형이 동생에게 얼마를 주면 됩니까?",
        "question_en": "The older brother has 2800 won and the younger one has 1500 won. If the older brother gives some money to the younger brother, the older brother will have 360 won more than the younger brother. How much should the older brother give to the younger brother?",
        "answer_ko": "470",
        "answer_en": "470",
        "solution_abst_ko": "2800 1500 [OP_SUB] 360 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "2800 1500 [OP_SUB] 360 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 2800\nvar_b = 1500\nvar_c = var_a - var_b\nvar_d = 360\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 2800\nvar_b = 1500\nvar_c = var_a - var_b\nvar_d = 360\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "6732": {
        "category": "Geometry",
        "question_ko": "정사각형 타일을 가로와 세로 모두 10장씩 빈틈없이 놓아서 정사각형을 만들었을 때, 둘레에 놓인 타일의 수는?",
        "question_en": "If you made a square by placing 10 square tiles on each vertical and horizontal line without gaps, how many tiles are placed at the perimeter?",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "10 4 [OP_MUL] 4 [OP_SUB]",
        "solution_abst_en": "10 4 [OP_MUL] 4 [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "6733": {
        "category": "Arithmetic calculation",
        "question_ko": "놀이공원에 학생이 194명, 성인이 235명 놀러왔고, 그중에서 공짜로 입장한 사람이 68명입니다. 놀이공원에 유료로 입장한 사람은 공짜로 입장한 사람보다 몇 명 더 많은지 구하시오",
        "question_en": "194 students and 235 adults came to the amusement park, and 68 of them got free admission. Find how many more people who paid for admission to the amusement park than those who got in for free.",
        "answer_ko": "293",
        "answer_en": "293",
        "solution_abst_ko": "194 235 [OP_ADD] 68 [OP_SUB] 68 [OP_SUB]",
        "solution_abst_en": "194 235 [OP_ADD] 68 [OP_SUB] 68 [OP_SUB]",
        "solution_code_ko": "var_a = 194\nvar_b = 235\nvar_c = var_a + var_b\nvar_d = 68\nvar_e = var_c - var_d\nvar_f = 68\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 194\nvar_b = 235\nvar_c = var_a + var_b\nvar_d = 68\nvar_e = var_c - var_d\nvar_f = 68\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "6734": {
        "category": "Comparison",
        "question_ko": "준우의 키는 1.63 미터(m)이고, 하은이의 키는 1.58 미터(m) 입니다. 키가 더 큰 사람의 이름을 써 보세요.",
        "question_en": "Junwoo is 1.63 meters (m) tall and Haeun is 1.58 meters (m) tall. Write the name of the taller person.",
        "answer_ko": "준우",
        "answer_en": "Junwoo",
        "solution_abst_ko": "[OP_LIST_SOL] 준우 하은 [OP_LIST_EOL] [OP_LIST_SOL] 1.63 1.58 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Junwoo Haeun [OP_LIST_EOL] [OP_LIST_SOL] 1.63 1.58 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '준우'\nvar_b = '하은'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.63\nvar_d = 1.58\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Junwoo'\nvar_b = 'Haeun'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.63\nvar_d = 1.58\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "6735": {
        "category": "Correspondence",
        "question_ko": "55에 어떤 수를 더했더니 결과가 88이 되었습니다. 어떤 수는 얼마입니까?",
        "question_en": "If you add a number to 55, the result is 88. What is the value of the number?",
        "answer_ko": "33",
        "answer_en": "33",
        "solution_abst_ko": "88 55 [OP_SUB]",
        "solution_abst_en": "88 55 [OP_SUB]",
        "solution_code_ko": "var_a = 88\nvar_b = 55\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 88\nvar_b = 55\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "6736": {
        "category": "Possibility",
        "question_ko": "민호는 세 숫자카드를 한 번씩 이용해 가장 큰 세 자리수와 세 번째로 큰 세 자리수를 만들고 그 둘의 차이를 구하는 게임을 하고 있습니다. 숫자 카드 1, 6, 8이 있을 때 민호가 구하는 답은 얼마입니까?",
        "question_en": "Minho is playing a game of using three number cards once to create the largest three-digit number and then find the difference between the two the third largest three-digit number. What is Minho's answer when he has the number cards 1, 6, and 8?",
        "answer_ko": "180",
        "answer_en": "180",
        "solution_abst_ko": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 3 [OP_LIST_MAX] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 3 [OP_LIST_MAX] [OP_SUB]",
        "solution_code_ko": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[-var_g]\nvar_i = var_f - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[-var_g]\nvar_i = var_f - var_h\nprint(int(var_i))"
    },
    "6737": {
        "category": "Possibility",
        "question_ko": "2, 0, 4, 1, 5, 8를 한 번씩만 사용하여 여섯 자리 수를 만드려고 합니다. 만들 수 있는 수 중에서 가장 큰 수와 가장 작은 수를 더하면 얼마가 됩니까?",
        "question_en": "You want to create a six-digit number using 2, 0, 4, 1, 5, and 8 only once. What is the sum of the largest and smallest possible numbers?",
        "answer_ko": "956668",
        "answer_en": "956668",
        "solution_abst_ko": "[OP_LIST_SOL] 2 0 4 1 5 8 [OP_LIST_EOL] 6 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 2 0 4 1 5 8 [OP_LIST_EOL] 6 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 0\nvar_c = 4\nvar_d = 1\nvar_e = 5\nvar_f = 8\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 6\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_i = list_c[-var_h]\nvar_j = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_k = list_d[var_j-1]\nvar_l = var_i + var_k\nprint(int(var_l))",
        "solution_code_en": "var_a = 2\nvar_b = 0\nvar_c = 4\nvar_d = 1\nvar_e = 5\nvar_f = 8\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 6\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_i = list_c[-var_h]\nvar_j = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_k = list_d[var_j-1]\nvar_l = var_i + var_k\nprint(int(var_l))"
    },
    "6738": {
        "category": "Correspondence",
        "question_ko": "서로 다른 두 자연수 A, B가 있습니다. A를 17로 나누면 몫은 25이고 나머지는 B가 됩니다. 나머지 B가 가장 큰 수일 때 A를 구하시오.",
        "question_en": "There are two different natural numbers, A and B. When A is divided by 17, the quotient is 25 and the remainder is B. Find A when the remainder B is the largest.",
        "answer_ko": "441",
        "answer_en": "441",
        "solution_abst_ko": "25 17 [OP_MUL] 17 1 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "25 17 [OP_MUL] 17 1 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 25\nvar_b = 17\nvar_c = var_a * var_b\nvar_d = 17\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 25\nvar_b = 17\nvar_c = var_a * var_b\nvar_d = 17\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "6739": {
        "category": "Arithmetic calculation",
        "question_ko": "연속하는 7개의 자연수의 합이 63입니다. 가운데 수를 구하시오.",
        "question_en": "The sum of 7 consecutive natural numbers is 63. Find the middle number.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "63 0 7 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 7 [OP_DIV] 7 2 [OP_FDIV] [OP_ADD]",
        "solution_abst_en": "63 0 7 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 7 [OP_DIV] 7 2 [OP_FDIV] [OP_ADD]",
        "solution_code_ko": "var_a = 63\nvar_b = 0\nvar_c = 7\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nlist_a = [i for i in range(var_b, var_e + 1, var_f)]\nlist_a = [float(i) for i in list_a]\nvar_g = sum(list_a)\nvar_h = var_a - var_g\nvar_i = 7\nvar_j = var_h / var_i\nvar_k = 7\nvar_l = 2\nvar_m = var_k // var_l\nvar_n = var_j + var_m\nprint(int(var_n))",
        "solution_code_en": "var_a = 63\nvar_b = 0\nvar_c = 7\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nlist_a = [i for i in range(var_b, var_e + 1, var_f)]\nlist_a = [float(i) for i in list_a]\nvar_g = sum(list_a)\nvar_h = var_a - var_g\nvar_i = 7\nvar_j = var_h / var_i\nvar_k = 7\nvar_l = 2\nvar_m = var_k // var_l\nvar_n = var_j + var_m\nprint(int(var_n))"
    },
    "6740": {
        "category": "Geometry",
        "question_ko": "정국이는 빨간 공 5개, 파란 공 4개, 노란 공 3개를 가지고 있습니다. 윤기가 정국이에게 노란 공 1개를 주었을 때, 정국이는 파란 공을 몇 개 가지고 있습니까?",
        "question_en": "Jungkook has 5 red balls, 4 blue balls, and 3 yellow balls. If Yoon-gi gives Jungkook 1 yellow ball, how many blue balls does Jungkook have?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "4",
        "solution_abst_en": "4",
        "solution_code_ko": "var_a = 4\nprint(int(var_a))",
        "solution_code_en": "var_a = 4\nprint(int(var_a))"
    },
    "6741": {
        "category": "Arithmetic calculation",
        "question_ko": "1, 2, 4, 0가 적힌 카드 중 3장을 골라 모두 사용하여 세 자리 수를 만들 때, 4와 10으로 나누어 떨어지는 모든 수의 합은 얼마인가?",
        "question_en": "What is the sum of all numbers that are divisible by 4 and 10 when you choose 3 cards with 1, 2, 4, and 0 written on them and use them all to make a three-digit number?",
        "answer_ko": "920",
        "answer_en": "920",
        "solution_abst_ko": "[OP_LIST_SOL] 1 2 4 0 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 4 [OP_LIST_DIVISIBLE] 10 [OP_LIST_DIVISIBLE] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 1 2 4 0 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 4 [OP_LIST_DIVISIBLE] 10 [OP_LIST_DIVISIBLE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 2\nvar_c = 4\nvar_d = 0\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 4\nlist_c = []\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nvar_g = 10\nlist_d = []\nvar_g = int(var_g)\nfor i in list_c:\n    i = int(i)\n    if i % var_g == 0:\n        list_d.append(i)\nlist_d = [float(i) for i in list_d]\nvar_h = sum(list_d)\nprint(int(var_h))",
        "solution_code_en": "var_a = 1\nvar_b = 2\nvar_c = 4\nvar_d = 0\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 4\nlist_c = []\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nvar_g = 10\nlist_d = []\nvar_g = int(var_g)\nfor i in list_c:\n    i = int(i)\n    if i % var_g == 0:\n        list_d.append(i)\nlist_d = [float(i) for i in list_d]\nvar_h = sum(list_d)\nprint(int(var_h))"
    },
    "6742": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 7을 더하였더니 27이 되었습니다. 어떤 수를 5로 나눈 다음 5를 더하고 7을 곱한 값을 구하시오.",
        "question_en": "When you add 7 to a number, you get 27. Divide a number by 5, then add 5 and multiply by 7. What is the result?",
        "answer_ko": "63",
        "answer_en": "63",
        "solution_abst_ko": "27 7 [OP_SUB] 5 [OP_DIV] 5 [OP_ADD] 7 [OP_MUL]",
        "solution_abst_en": "27 7 [OP_SUB] 5 [OP_DIV] 5 [OP_ADD] 7 [OP_MUL]",
        "solution_code_ko": "var_a = 27\nvar_b = 7\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c / var_d\nvar_f = 5\nvar_g = var_e + var_f\nvar_h = 7\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 27\nvar_b = 7\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c / var_d\nvar_f = 5\nvar_g = var_e + var_f\nvar_h = 7\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "6743": {
        "category": "Comparison",
        "question_ko": "윤기는 7, 정국은 6, 유나는 9만큼 모았습니다. 가장 작은 숫자를 가진 사람은 누구입니까?",
        "question_en": "Yoongi collected 7, Jungkook 6, and Yuna 9. Who has the smallest number?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 유나 [OP_LIST_EOL] [OP_LIST_SOL] 7 6 9 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook Yuna [OP_LIST_EOL] [OP_LIST_SOL] 7 6 9 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nvar_c = '유나'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 7\nvar_e = 6\nvar_f = 9\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nvar_c = 'Yuna'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 7\nvar_e = 6\nvar_f = 9\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "6744": {
        "category": "Arithmetic calculation",
        "question_ko": "준혁이는 한 상자에 16개의 사과가 들어있는 사과상자 7개를 샀고, 지현이는 한 상자에 25개의 사과가 들어있는 사과상자 6개를 샀습니다. 준혁이와 지현이가 산 사과는 모두 몇 개인가요?",
        "question_en": "Junhyeok bought 7 apple boxes with 16 apples in each box, and Jihyun bought 6 apple boxes with 25 apples in each box. How many apples did Junhyeok and Jihyun buy?",
        "answer_ko": "262",
        "answer_en": "262",
        "solution_abst_ko": "16 7 [OP_MUL] 25 6 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "16 7 [OP_MUL] 25 6 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 16\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 25\nvar_e = 6\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 16\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 25\nvar_e = 6\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "6745": {
        "category": "Comparison",
        "question_ko": "43.23, 2/5 및 21.23을 작은 순서로 배열할 때, 마지막으로 오는 수는 무엇입니까?",
        "question_en": "When 43.23, 2/5, and 21.23 are arranged in order from smallest to greatest, which number comes last?",
        "answer_ko": "43.23",
        "answer_en": "43.23",
        "solution_abst_ko": "[OP_LIST_SOL] 43.23 2 5 [OP_DIV] 21.23 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 43.23 2 5 [OP_DIV] 21.23 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 43.23\nvar_b = 2\nvar_c = 5\nvar_d = var_b / var_c\nvar_e = 21.23\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 43.23\nvar_b = 2\nvar_c = 5\nvar_d = var_b / var_c\nvar_e = 21.23\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "6746": {
        "category": "Geometry",
        "question_ko": "마주 보는 면의 눈의 수의 합이 7인 주사위가 있습니다. 이 주사위에 그려진 눈은 1부터 6까지라고 할 때, 5와 마주보는 면의 눈의 수와 5를 곱한 값은 얼마인지 구하시오.",
        "question_en": "You have a die with the sum of the number of eyes on one side and the number of eyes on the other side is 7. Given that the eyes on this die are 1 through 6, find the number of eyes on the opposite side of 5 multiplied by 5.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "5 7 5 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "5 7 5 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 7\nvar_c = 5\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 7\nvar_c = 5\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nprint(int(var_e))"
    },
    "6747": {
        "category": "Correspondence",
        "question_ko": "3.A7>3.27입니다. 0부터 9까지의 숫자 중에서 A에 쓸 수 있는 숫자는 모두 몇 개입니까?",
        "question_en": "Given that 3.A7>3.27 is true, how many digits from 0 to 9 can be written for A?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "3.A7>3.27 A [OP_DIGIT_UNK_SOLVER] [OP_LIST_LEN]",
        "solution_abst_en": "3.A7>3.27 A [OP_DIGIT_UNK_SOLVER] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '3.A7>3.27'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = len(list_a)\nprint(int(var_c))",
        "solution_code_en": "var_a = '3.A7>3.27'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = len(list_a)\nprint(int(var_c))"
    },
    "6748": {
        "category": "Correspondence",
        "question_ko": "한 자리 수 A로 만들 수 있는 세 자리 수 A27이 있습니다. 이 수를 백의 자리에서 버림하면 200이 됩니다. A는 무엇입니까?",
        "question_en": "There is a three-digit number A27 that can be made from a single-digit number A. Rounding down this number from the hundreds place gives 200. What is A?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "A27 [OP_GEN_POSSIBLE_LIST] 200 [OP_LIST_MORE_EQUAL] 200 100 [OP_ADD] [OP_LIST_LESS] A [OP_LIST_FIND_UNK]",
        "solution_abst_en": "A27 [OP_GEN_POSSIBLE_LIST] 200 [OP_LIST_MORE_EQUAL] 200 100 [OP_ADD] [OP_LIST_LESS] A [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = 'A27'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 200\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 200\nvar_d = 100\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = 'A'\nvar_a = str(var_a)\nvar_f = str(var_f)\nunk_idx = var_a.index(var_f)\nvar_g = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_g = int(elem[unk_idx])\nprint(int(var_g))",
        "solution_code_en": "var_a = 'A27'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 200\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 200\nvar_d = 100\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = 'A'\nvar_a = str(var_a)\nvar_f = str(var_f)\nunk_idx = var_a.index(var_f)\nvar_g = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_g = int(elem[unk_idx])\nprint(int(var_g))"
    },
    "6749": {
        "category": "Comparison",
        "question_ko": "석진이가 지민이 바로 앞에 서 있습니다. 지민이가 앞에서 9번째라면 석진이는 몇 번째입니까?",
        "question_en": "Seokjin is standing right in front of Jimin. If Jimin is 9th from the front, what number is Seokjin?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "9 1 [OP_SUB]",
        "solution_abst_en": "9 1 [OP_SUB]",
        "solution_code_ko": "var_a = 9\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 9\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "6750": {
        "category": "Arithmetic calculation",
        "question_ko": "마트에서 사과를 4개 묶음으로 팝니다. 2 묶음을 샀다면 사과는 총 몇 개입니까?",
        "question_en": "Apples are on sale in packs of 4 at the supermarket. If you buy 2 bunches, how many apples are there in total?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "4 2 [OP_MUL]",
        "solution_abst_en": "4 2 [OP_MUL]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "6751": {
        "category": "Geometry",
        "question_ko": "넓이가 36.48제곱센티미터(㎠)인 직사각형의 가로가 6.08센티미터(㎝)라면 세로는 몇 센티미터(㎝)입니까?",
        "question_en": "If a rectangle with an area of 36.48 square centimeters (cm2) has a width of 6.08 centimeters (cm), how many centimeters (cm) is its length?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "36.48 6.08 [OP_DIV]",
        "solution_abst_en": "36.48 6.08 [OP_DIV]",
        "solution_code_ko": "var_a = 36.48\nvar_b = 6.08\nvar_c = var_a / var_b\nprint(int(eval('{:.2f}'.format(round(var_c+1e-10,2)))))",
        "solution_code_en": "var_a = 36.48\nvar_b = 6.08\nvar_c = var_a / var_b\nprint(int(eval('{:.2f}'.format(round(var_c+1e-10,2)))))"
    },
    "6752": {
        "category": "Correspondence",
        "question_ko": "A는 한 자리 수입니다. A76을 백의 자리에서 버림하면 700의 값을 얻을 수 있습니다. A는 무엇입니까?",
        "question_en": "A is a single digit number. If you round down A76 in the hundreds place, you get a value of 700. What is A?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "A76 [OP_GEN_POSSIBLE_LIST] 700 [OP_LIST_MORE_EQUAL] 700 100 [OP_ADD] [OP_LIST_LESS] A76 A [OP_LIST_FIND_UNK]",
        "solution_abst_en": "A76 [OP_GEN_POSSIBLE_LIST] 700 [OP_LIST_MORE_EQUAL] 700 100 [OP_ADD] [OP_LIST_LESS] A76 A [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = 'A76'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 700\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 700\nvar_d = 100\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = 'A76'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))",
        "solution_code_en": "var_a = 'A76'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 700\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = 700\nvar_d = 100\nvar_e = var_c + var_d\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = 'A76'\nvar_g = 'A'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nprint(int(var_h))"
    },
    "6753": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 9/4를 나누어야 하는데 잘못하여 곱했더니 18/5가 되었습니다. 바르게 계산하면 얼마가 됩니까?",
        "question_en": "A number that needs to be divided by 9/4, but multiplied by mistake, got 18/5. How much do you get when calculated correctly?",
        "answer_ko": "0.71",
        "answer_en": "0.71",
        "solution_abst_ko": "18/5 9/4 [OP_DIV] 9/4 [OP_DIV]",
        "solution_abst_en": "18/5 9/4 [OP_DIV] 9/4 [OP_DIV]",
        "solution_code_ko": "var_a = 3.6\nvar_b = 2.25\nvar_c = var_a / var_b\nvar_d = 2.25\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 3.6\nvar_b = 2.25\nvar_c = var_a / var_b\nvar_d = 2.25\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "6754": {
        "category": "Arithmetic calculation",
        "question_ko": "마트에 당근 250킬로그램(㎏)이 있고, 당근 무게의 2.5배가 오이의 무게라면 당근과 오이는 모두 몇 킬로그램(㎏) 있습니까?",
        "question_en": "If there are 250 kilograms (kg) of carrots in the supermarket, and 2.5 times the weight of carrots is the weight of cucumbers, how many kilograms (kg) are there both carrots and cucumbers?",
        "answer_ko": "875",
        "answer_en": "875",
        "solution_abst_ko": "250 250 2.5 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "250 250 2.5 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 250\nvar_b = 250\nvar_c = 2.5\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 250\nvar_b = 250\nvar_c = 2.5\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "6755": {
        "category": "Comparison",
        "question_ko": "꽃밭의 2/7에는 채송화 3/8에는 봉선화를 심었습니다. 어떤 꽃이 더 넓게 심어 져 있습니까?",
        "question_en": "sunplant was planted in 2/7 of the flower garden, and snapweed was planted in 3/8. Which flowers are more widely planted?",
        "answer_ko": "봉선화",
        "answer_en": "snapweed",
        "solution_abst_ko": "[OP_LIST_SOL] 채송화 봉선화 [OP_LIST_EOL] [OP_LIST_SOL] 2 7 [OP_DIV] 3 8 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] sunplant snapweed [OP_LIST_EOL] [OP_LIST_SOL] 2 7 [OP_DIV] 3 8 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '채송화'\nvar_b = '봉선화'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nvar_d = 7\nvar_e = var_c / var_d\nvar_f = 3\nvar_g = 8\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'sunplant'\nvar_b = 'snapweed'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nvar_d = 7\nvar_e = var_c / var_d\nvar_f = 3\nvar_g = 8\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "6756": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 6으로 나누어야 할 것을 잘못하여 1.5로 나누었더니 몫이 3.8이 되었습니다. 바르게 계산하면 얼마인지 답을 구해 보세요.",
        "question_en": "When you divided a number by 1.5 incorrectly, which was supposed to be divided by 6, the quotient is 3.8. Find the answer if you calculate correctly.",
        "answer_ko": "0.95",
        "answer_en": "0.95",
        "solution_abst_ko": "3.8 1.5 [OP_MUL] 6 [OP_DIV]",
        "solution_abst_en": "3.8 1.5 [OP_MUL] 6 [OP_DIV]",
        "solution_code_ko": "var_a = 3.8\nvar_b = 1.5\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 3.8\nvar_b = 1.5\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "6757": {
        "category": "Possibility",
        "question_ko": "1, 2, 7을 각각 한번씩만 사용하여 세 자리 수를 만들면 몇 가지의 다른 수를 만들 수 있겠는가?",
        "question_en": "How many different three-digit numbers can be formed using the three numbers 1, 2, and 7 once each?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 1 2 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 2 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 2\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 2\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "6758": {
        "category": "Possibility",
        "question_ko": "0부터 4까지 차례대로 있는 자연수 카드 중 3장을 꺼내 세 자리 수를 만들 때, 6과 9의 공배수는 모두 몇 가지가 나오는가?",
        "question_en": "How many common multiples of 6 and 9 are found when you pick 3 of the natural number cards in sequence from 0 to 4 to form a 3-digit number?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 6 9 [OP_LCM] [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 6 9 [OP_LCM] [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 6\nvar_h = 9\nvar_i = var_h * var_g / math.gcd(int(var_h), int(var_g))\nlist_c = []\nvar_i = int(var_i)\nfor i in list_b:\n    i = int(i)\n    if i % var_i == 0:\n        list_c.append(i)\nvar_j = len(list_c)\nprint(int(var_j))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 6\nvar_h = 9\nvar_i = var_h * var_g / math.gcd(int(var_h), int(var_g))\nlist_c = []\nvar_i = int(var_i)\nfor i in list_b:\n    i = int(i)\n    if i % var_i == 0:\n        list_c.append(i)\nvar_j = len(list_c)\nprint(int(var_j))"
    },
    "6759": {
        "category": "Possibility",
        "question_ko": "같은 색의 색연필은 구별이 되지 않는다. 빨간색, 파란색, 초록색, 보라색 색연필이 각각 2자루 이상 통에 들어 있을때 한 번에 색연필 2자루를 꺼내는 경우의 수를 구하시오.",
        "question_en": "Colored pencils of the same color cannot be distinguished. Find the number of ways to take out 2 colored pencils at a time when there are 2 or more colored pencils in each of red, blue, green, and purple.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "4 3 [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "4 3 [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 4\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 4\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "6760": {
        "category": "Comparison",
        "question_ko": "친구들이 일렬로 줄을 서 있습니다. 앞에서 8번째, 뒤에서 6번째에 석진이가 서 있습니다. 줄을 서 있는 친구들은 모두 몇 명입니까?",
        "question_en": "Friends lined up in a row. Seokjin stands 8th from the front and 6th from the back. How many friends are all in line?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "8 6 [OP_ADD] 1 [OP_SUB]",
        "solution_abst_en": "8 6 [OP_ADD] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 8\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "6761": {
        "category": "Possibility",
        "question_ko": "4 장의 숫자 카드 1, 3, 4, 7 중 3 장을 뽑아 한 번씩만 사용하여 세 자리 수를 만들려고 합니다. 만들 수 있는 수 중에서 360 이상 455 이하인 수는 모두 몇 개입니까?",
        "question_en": "You are trying to create a three-digit number by choosing 3 of the 4 number cards 1, 3, 4, 7 and using them only once. How many numbers that are greater than or equal to 360 and less than or equal to 455 can be made?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 4 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 360 [OP_LIST_MORE_EQUAL] 455 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 4 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 360 [OP_LIST_MORE_EQUAL] 455 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 4\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 360\nlist_c = []\nfor i in list_b:\n    if i >= var_f:\n        list_c.append(i)\nvar_g = 455\nlist_d = []\nfor i in list_c:\n    if i <= var_g:\n        list_d.append(i)\nvar_h = len(list_d)\nprint(int(var_h))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 4\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 360\nlist_c = []\nfor i in list_b:\n    if i >= var_f:\n        list_c.append(i)\nvar_g = 455\nlist_d = []\nfor i in list_c:\n    if i <= var_g:\n        list_d.append(i)\nvar_h = len(list_d)\nprint(int(var_h))"
    },
    "6762": {
        "category": "Geometry",
        "question_ko": "모든 모서리의 길이의 합이 72센티미터(㎝)인 정육면체 모양의 큐브가 있습니다. 이 큐브의 한 모서리의 길이는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "There is a cube in the shape of a cube, and the sum of the lengths of all its edges is 72 centimeters (cm). Find the length in centimeters (cm) of one edge of this cube.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "72 4 3 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "72 4 3 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 72\nvar_b = 4\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 72\nvar_b = 4\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "6763": {
        "category": "Possibility",
        "question_ko": "숫자 카드 3, 7, 2 중 2장을 한 번씩 모두 사용하여 가장 작은 두 자리 수를 만들 때, 사용하지 않는 카드의 숫자는 무엇입니까?",
        "question_en": "When two of the number cards 3, 7, and 2 are used once to create the smallest two-digit number, which number is unused?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "[OP_LIST_SOL] 3 7 2 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] [OP_LIST_POP] [OP_NUM2LIST] [OP_SET_DIFFERENCE] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] 3 7 2 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] [OP_LIST_POP] [OP_NUM2LIST] [OP_SET_DIFFERENCE] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 3\nvar_b = 7\nvar_c = 2\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nlist_d = []\nvar_f = int(var_f)\nwhile var_f//10 > 0:\n    list_d.append(var_f%10)\n    var_f = var_f//10\nlist_d.append(var_f%10)\nlist_d = list_d[::-1]\nlist_e = list(set(list_a) - set(list_d))\nvar_g = 1\nvar_h = list_e[var_g-1]\nprint(int(var_h))",
        "solution_code_en": "var_a = 3\nvar_b = 7\nvar_c = 2\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nlist_d = []\nvar_f = int(var_f)\nwhile var_f//10 > 0:\n    list_d.append(var_f%10)\n    var_f = var_f//10\nlist_d.append(var_f%10)\nlist_d = list_d[::-1]\nlist_e = list(set(list_a) - set(list_d))\nvar_g = 1\nvar_h = list_e[var_g-1]\nprint(int(var_h))"
    },
    "6764": {
        "category": "Correspondence",
        "question_ko": "B는 278에 365를 3번 더한 숫자이고 A는 100개 묶음 20개 10개 묶음 87개로 이루어진 숫자입니다. A+B를 구하시오.",
        "question_en": "B is 278 plus 365 three times, and A is a number consisting of 20 bundles of 100 and 87 bundles of 10. Find A+B.",
        "answer_ko": "4243",
        "answer_en": "4243",
        "solution_abst_ko": "100 20 [OP_MUL] 10 87 [OP_MUL] [OP_ADD] 278 365 3 [OP_MUL] [OP_ADD] [OP_ADD]",
        "solution_abst_en": "100 20 [OP_MUL] 10 87 [OP_MUL] [OP_ADD] 278 365 3 [OP_MUL] [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 100\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 10\nvar_e = 87\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 278\nvar_i = 365\nvar_j = 3\nvar_k = var_i * var_j\nvar_l = var_h + var_k\nvar_m = var_g + var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 100\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 10\nvar_e = 87\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 278\nvar_i = 365\nvar_j = 3\nvar_k = var_i * var_j\nvar_l = var_h + var_k\nvar_m = var_g + var_l\nprint(int(var_m))"
    },
    "6765": {
        "category": "Geometry",
        "question_ko": "원래 길이가 2.7인 떡 5개를, 0.3미터(m)씩 겹치게 하여 이은 후, 다시 6도막으로 잘라 이웃 주민들에게 공평하게 주려고 합니다. 얼마씩 주어야 합니까?",
        "question_en": "After connecting 5 rice cakes with an original length of 2.7meters (m), overlapping each other by 0.3meters (m), cut them into 6 slices again to give them to the neighbors fairly. How much should I give?",
        "answer_ko": "2.05",
        "answer_en": "2.05",
        "solution_abst_ko": "2.7 5 [OP_MUL] 0.3 5 1 [OP_SUB] [OP_MUL] [OP_SUB] 6 [OP_DIV]",
        "solution_abst_en": "2.7 5 [OP_MUL] 0.3 5 1 [OP_SUB] [OP_MUL] [OP_SUB] 6 [OP_DIV]",
        "solution_code_ko": "var_a = 2.7\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 0.3\nvar_e = 5\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_c - var_h\nvar_j = 6\nvar_k = var_i / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 2.7\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 0.3\nvar_e = 5\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_c - var_h\nvar_j = 6\nvar_k = var_i / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "6766": {
        "category": "Arithmetic calculation",
        "question_ko": "1000밀리리터(㎖)짜리 물통에 물이 가득 차 있었는데, 구멍이 생겨 1분에 5밀리리터(㎖)씩 물이 새고 있다. 물이 300밀리리터(㎖) 남아있을 때까지 지난 시간을 구하시오.",
        "question_en": "A 1000 milliliter (ml) bucket was filled with water, but there was a hole and water was leaking at a rate of 5 milliliters (ml) per minute. Find the time elapsed when 300 milliliters (ml) of water remain.",
        "answer_ko": "140",
        "answer_en": "140",
        "solution_abst_ko": "1000 300 [OP_SUB] 5 [OP_DIV]",
        "solution_abst_en": "1000 300 [OP_SUB] 5 [OP_DIV]",
        "solution_code_ko": "var_a = 1000\nvar_b = 300\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 1000\nvar_b = 300\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "6767": {
        "category": "Possibility",
        "question_ko": "숫자카드 1, 4, 6, 7 중 3개를 사용하여 3자리 수를 만들때, 십의 자리 수가 1인 세 번째 작은 수를 구하십시오.",
        "question_en": "When using 3 of the number cards 1, 4, 6, and 7 to make a 3-digit number, find the third smallest number with 1 in the tens place.",
        "answer_ko": "614",
        "answer_en": "614",
        "solution_abst_ko": "[OP_LIST_SOL] 1 4 6 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 1 [OP_LIST_SEARCH_FIXED_DIGIT] 3 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 4 6 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 1 [OP_LIST_SEARCH_FIXED_DIGIT] 3 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1\nvar_b = 4\nvar_c = 6\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 1\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 3\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 4\nvar_c = 6\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 1\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 3\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nprint(int(var_i))"
    },
    "6768": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 형준이네 반 학생 수로 나누면 몫이 1.2로 나누어떨어지고, 형준이네 반 학생수를 다시 진목이네 반 학생수로 나누면 몫이 5/6로 나누어떨어진다. 어떤 수를 진목이네 반 학생수로 나누면 그 몫은 얼마인가?",
        "question_en": "When a certain number is divided by the number of students in Hyungjun's class, the quotient is 1.2, and when the number of students in Hyungjun's class is divided by the number of students in Jinmok's class, the quotient is 5/6. If you divide a certain number by the number of students in Jinmok's class, what is the quotient?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "1.2 5/6 [OP_MUL]",
        "solution_abst_en": "1.2 5/6 [OP_MUL]",
        "solution_code_ko": "var_a = 1.2\nvar_b = 0.8333333333333334\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 1.2\nvar_b = 0.8333333333333334\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "6769": {
        "category": "Geometry",
        "question_ko": "넓이가 64/5제곱센티미터(㎠)인 마름모에서 이웃하지 않은 두 꼭짓점을 선택해 거리를 재었더니 64/9센티미터(㎝)였습니다. 선택되지 않은 두 꼭짓점 사이의 거리를 구하시오.",
        "question_en": "In a rhombus with an area of 64/5 square centimeters (cm2), two non-adjacent vertices were selected and the distance was measured, which was 64/9 centimeters (cm). Find the distance between two unselected vertices.",
        "answer_ko": "3.60",
        "answer_en": "3.6",
        "solution_abst_ko": "64/5 2 [OP_MUL] 64/9 [OP_DIV]",
        "solution_abst_en": "64/5 2 [OP_MUL] 64/9 [OP_DIV]",
        "solution_code_ko": "var_a = 12.8\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 7.111111111111111\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 12.8\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 7.111111111111111\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "6770": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 10을 더하여 5로 나눈 수가 4입니다. 어떤 수에 3을 곱하여 18을 뺀 수를 구하시오.",
        "question_en": "When you add 10 to a particular number and divide it by 5, you get 4. Multiply that particular number by 3 and subtract 18. What is the value?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "4 5 [OP_MUL] 10 [OP_SUB] 3 [OP_MUL] 18 [OP_SUB]",
        "solution_abst_en": "4 5 [OP_MUL] 10 [OP_SUB] 3 [OP_MUL] 18 [OP_SUB]",
        "solution_code_ko": "var_a = 4\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 10\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = var_e * var_f\nvar_h = 18\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 4\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 10\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = var_e * var_f\nvar_h = 18\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "6771": {
        "category": "Possibility",
        "question_ko": "숫자 카드 2, 5, 9, 6을 한 번 씩 모두 사용하여 만들 수 있는 네 자리 수는 몇 개입니까?",
        "question_en": "How many four-digit numbers can be made by using the numbers written on cards 2, 5, 9, and 6, with using all the numbers once?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "[OP_LIST_SOL] 2 5 9 6 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 2 5 9 6 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 2\nvar_b = 5\nvar_c = 9\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 2\nvar_b = 5\nvar_c = 9\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "6772": {
        "category": "Comparison",
        "question_ko": "우유 1리터(L)와 물 3리터(L)를 모양과 크기가 같은 컵에 똑같이 나누어 담으려고 합니다. 우유 1리터(L)를 컵 가 2개에, 우유 3리터(L)를 컵 나 4개에 남김없이 똑같이 나누어 담을 때, 컵 가와 컵 나 중 어느 컵에 우유가 더 많을까요?",
        "question_en": "You want to divide 1 liter (L) of milk and 3 liters (L) of water equally into cups of the same shape and size. If 1 liter (L) of milk is divided equally into 2 A cups  and 3 liters (L) of milk is divided equally into 4 B cups, which cup has more milk, Cup A or Cup B?",
        "answer_ko": "나",
        "answer_en": "B",
        "solution_abst_ko": "[OP_LIST_SOL] 가 나 [OP_LIST_EOL] [OP_LIST_SOL] 1 2 [OP_MUL] 3 4 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 1 2 [OP_MUL] 3 4 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '가'\nvar_b = '나'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 3\nvar_g = 4\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 3\nvar_g = 4\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "6773": {
        "category": "Geometry",
        "question_ko": "가로의 길이가 18밀리미터(㎜), 세로의 길이가 12밀리미터(㎜), 높이가 9밀리미터(㎜)인 직육면체 모양의 블록을 쌓아 정육면체를 만들려고 할 때, 필요한 최소의 블록을 개수를 구하시오. (단, 블록의 튀어나온 부분의 높이는 고려하지 않습니다.)",
        "question_en": "When trying to make a cube by stacking cuboid-shaped blocks with a width of 18 millimeters (mm), a length of 12 millimeters (mm), and a height of 9 millimeters (mm), find the minimum number of blocks required. (However, the height of the protruding part of the block is not considered.)",
        "answer_ko": "40310784",
        "answer_en": "40310784",
        "solution_abst_ko": "18 12 [OP_LCM] 9 [OP_LCM] 3 [OP_POW] 18 [OP_DIV] 18 12 [OP_LCM] 9 [OP_LCM] 12 [OP_DIV] 18 12 [OP_LCM] 9 [OP_LCM] 3 [OP_POW] 9 [OP_DIV] [OP_MUL] [OP_MUL]",
        "solution_abst_en": "18 12 [OP_LCM] 9 [OP_LCM] 3 [OP_POW] 18 [OP_DIV] 18 12 [OP_LCM] 9 [OP_LCM] 12 [OP_DIV] 18 12 [OP_LCM] 9 [OP_LCM] 3 [OP_POW] 9 [OP_DIV] [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 18\nvar_b = 12\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nvar_d = 9\nvar_e = var_d * var_c / math.gcd(int(var_d), int(var_c))\nvar_f = 3\nvar_g = var_e ** var_f\nvar_h = 18\nvar_i = var_g / var_h\nvar_j = 18\nvar_k = 12\nvar_l = var_k * var_j / math.gcd(int(var_k), int(var_j))\nvar_m = 9\nvar_n = var_m * var_l / math.gcd(int(var_m), int(var_l))\nvar_o = 12\nvar_p = var_n / var_o\nvar_q = 18\nvar_r = 12\nvar_s = var_r * var_q / math.gcd(int(var_r), int(var_q))\nvar_t = 9\nvar_u = var_t * var_s / math.gcd(int(var_t), int(var_s))\nvar_v = 3\nvar_w = var_u ** var_v\nvar_x = 9\nvar_y = var_w / var_x\nvar_z = var_p * var_y\nvar_A = var_i * var_z\nprint(int(var_A))",
        "solution_code_en": "var_a = 18\nvar_b = 12\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nvar_d = 9\nvar_e = var_d * var_c / math.gcd(int(var_d), int(var_c))\nvar_f = 3\nvar_g = var_e ** var_f\nvar_h = 18\nvar_i = var_g / var_h\nvar_j = 18\nvar_k = 12\nvar_l = var_k * var_j / math.gcd(int(var_k), int(var_j))\nvar_m = 9\nvar_n = var_m * var_l / math.gcd(int(var_m), int(var_l))\nvar_o = 12\nvar_p = var_n / var_o\nvar_q = 18\nvar_r = 12\nvar_s = var_r * var_q / math.gcd(int(var_r), int(var_q))\nvar_t = 9\nvar_u = var_t * var_s / math.gcd(int(var_t), int(var_s))\nvar_v = 3\nvar_w = var_u ** var_v\nvar_x = 9\nvar_y = var_w / var_x\nvar_z = var_p * var_y\nvar_A = var_i * var_z\nprint(int(var_A))"
    },
    "6774": {
        "category": "Arithmetic calculation",
        "question_ko": "40 이상 70 이하인 자연수는 모두 몇 개입니까?",
        "question_en": "How many natural numbers are 40 or greater and 70 or less?",
        "answer_ko": "31",
        "answer_en": "31",
        "solution_abst_ko": "70 40 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "70 40 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 70\nvar_b = 40\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 70\nvar_b = 40\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "6775": {
        "category": "Possibility",
        "question_ko": "알파벳 A, B, C모양 스펀지를 차례대로 쌓을 때, 몇 가지의 방법이 있습니까?",
        "question_en": "How many ways are there to stack up the sponges shaped in the alphabet A, B, and C in order?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = len(list_a)\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nprint(int(var_f))",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = len(list_a)\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nprint(int(var_f))"
    },
    "6776": {
        "category": "Geometry",
        "question_ko": "넓이가 48.6 제곱센티미터(㎠)인 평행사변형의 밑변이 5.4센티미터(㎝)이다. 이 도형의 높이는 얼마인가?",
        "question_en": "The base of a parallelogram with an area of 48.6 square centimeters (cm2) is 5.4 centimeters (cm). What is the height of this figure?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "48.6 5.4 [OP_DIV]",
        "solution_abst_en": "48.6 5.4 [OP_DIV]",
        "solution_code_ko": "var_a = 48.6\nvar_b = 5.4\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 48.6\nvar_b = 5.4\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "6777": {
        "category": "Geometry",
        "question_ko": "마름모의 넓이가 21.46제곱센티미터(㎠)이고, 한 대각선의 길이가 7.4센티미터(㎝)일 때, 다른 대각선의 길이를 구하시오.",
        "question_en": "Consider the area of the rhombus is 21.46 square centimeters (cm2) and the length of one diagonal is 7.4 centimeters (cm). Find the length of the other diagonal.",
        "answer_ko": "5.80",
        "answer_en": "5.8",
        "solution_abst_ko": "21.46 2 [OP_MUL] 7.4 [OP_DIV]",
        "solution_abst_en": "21.46 2 [OP_MUL] 7.4 [OP_DIV]",
        "solution_code_ko": "var_a = 21.46\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 7.4\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 21.46\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 7.4\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "6778": {
        "category": "Possibility",
        "question_ko": "2, 4, 5, 1, 3, 7, 6, 0 수 카드를 모두 한 번씩만 사용하여 가장 큰 수와 가장 작은 수의 차를 구하시오",
        "question_en": "Find the difference between the largest number and the smallest number using all number cards of 2, 4, 5, 1, 3, 7, 6, and 0 only once.",
        "answer_ko": "66308643",
        "answer_en": "66308643",
        "solution_abst_ko": "[OP_LIST_SOL] 2 4 5 1 3 7 6 0 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 2 4 5 1 3 7 6 0 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = 5\nvar_d = 1\nvar_e = 3\nvar_f = 7\nvar_g = 6\nvar_h = 0\nlist_a= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_i = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_i))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_j = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_k = list_c[-var_j]\nvar_l = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_m = list_d[var_l-1]\nvar_n = var_k - var_m\nprint(int(var_n))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = 5\nvar_d = 1\nvar_e = 3\nvar_f = 7\nvar_g = 6\nvar_h = 0\nlist_a= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_i = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_i))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_j = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_k = list_c[-var_j]\nvar_l = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_m = list_d[var_l-1]\nvar_n = var_k - var_m\nprint(int(var_n))"
    },
    "6779": {
        "category": "Arithmetic calculation",
        "question_ko": "꽃병이 5개 있습니다. 꽃병 4개에는 각각 5송이의 꽃이 있고, 나머지 1개의 꽃병에는 6송이의 꽃이 있습니다. 꽃병에 있는 꽃은 모두 몇 송이입니까?",
        "question_en": "There are 5 vases. 4 vases have 5 flowers each, and the other one vase has 6 flowers. Find out the total amount of flowers in the vase.",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "4 5 [OP_MUL] 1 6 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "4 5 [OP_MUL] 1 6 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 6\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 6\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "6780": {
        "category": "Correspondence",
        "question_ko": "A+C=15, A-B=1, C+C=A, B-D=2입니다. A, B, C, D가 서로 다른 수라고 한다면 D는 얼마가 되야 합니까?",
        "question_en": "A+C=15, A-B=1, C+C=A, B-D=2. If A, B, C, and D are different numbers, what should D be?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "C+C+C=15 C [OP_NUM_UNK_SOLVER] 2 [OP_MUL] 1 [OP_SUB] 2 [OP_SUB]",
        "solution_abst_en": "C+C+C=15 C [OP_NUM_UNK_SOLVER] 2 [OP_MUL] 1 [OP_SUB] 2 [OP_SUB]",
        "solution_code_ko": "var_a = 'C+C+C=15'\nvar_b = 'C'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 'C+C+C=15'\nvar_b = 'C'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "6781": {
        "category": "Arithmetic calculation",
        "question_ko": "다섯 자리 수 중 3과 5의 공배수는 모두 몇 개 입니까?",
        "question_en": "How many five-digit numbers are common multiples of 3 and 5?",
        "answer_ko": "6000",
        "answer_en": "6000",
        "solution_abst_ko": "10000 99999 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "10000 99999 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 10000\nvar_b = 99999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 10000\nvar_b = 99999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "6782": {
        "category": "Comparison",
        "question_ko": "호석이네 반 학생 30명 중 호석이보다 늦게 온 학생은 12명입니다. 호석이보다 일찍 온 학생은 몇 명인가요?",
        "question_en": "Among the 30 students in Hoseok's class, 12 students came later than Hoseok. How many students came earlier than Hoseok?",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "30 12 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "30 12 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 30\nvar_b = 12\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 30\nvar_b = 12\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "6783": {
        "category": "Comparison",
        "question_ko": "석진이는 마트에서 5번째 줄에 서있고, 남준이는 석진이보다 6명 뒤에 있습니다. 남준이는 몇 번째에 서 있습니까?",
        "question_en": "Seokjin is in the 5th row at the supermarket, and Namjoon is 6 people behind Seokjin. What's Namjoon's position?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "5 6 [OP_ADD]",
        "solution_abst_en": "5 6 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 6\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 6\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "6784": {
        "category": "Correspondence",
        "question_ko": "1/1000을 곱하면 0.735가 되는 어떤 수에 10을 곱하면 얼마가 되나요?",
        "question_en": "What will the result be if I multiply 10 by a certain number that becomes 0.735 when multiplied by 1/1000?",
        "answer_ko": "7350",
        "answer_en": "7350",
        "solution_abst_ko": "0.735 1/1000 [OP_DIV] 10 [OP_MUL]",
        "solution_abst_en": "0.735 1/1000 [OP_DIV] 10 [OP_MUL]",
        "solution_code_ko": "var_a = 0.735\nvar_b = 0.001\nvar_c = var_a / var_b\nvar_d = 10\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 0.735\nvar_b = 0.001\nvar_c = var_a / var_b\nvar_d = 10\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "6785": {
        "category": "Comparison",
        "question_ko": "4대의 버스 A, B, C, D가 있습니다. 버스 A는 버스 C보다 많은 승객들이 타고 있고, 버스 D에는 가장 적은 승객들이 타고 있습니다. 가장 많은 승객을 태운 버스는 무엇일까요?",
        "question_en": "There are 4 buses A, B, C and D. Bus A has more passengers than bus C, bus A has more passengers than bus B, and bus D has the fewest passengers. Which bus has the most passengers?",
        "answer_ko": "A",
        "answer_en": "A",
        "solution_abst_ko": "[OP_LIST_SOL] A B C D [OP_LIST_EOL] [OP_LIST_SOL] A B > A C > D A < D B < D C < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D [OP_LIST_EOL] [OP_LIST_SOL] A B > A C > D A < D B < D C < [OP_LIST_EOL] [OP_LIST_COND_M(a)X_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'A'\nvar_f = 'B'\nvar_g = '>'\nvar_h = 'A'\nvar_i = 'C'\nvar_j = '>'\nvar_k = 'D'\nvar_l = 'A'\nvar_m = '<'\nvar_n = 'D'\nvar_o = 'B'\nvar_p = '<'\nvar_q = 'D'\nvar_r = 'C'\nvar_s = '<'\nlist_b= []\nif \"/\" in str(var_s):\n    var_s = eval(str(var_s))\nlist_b.append(var_s)\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_t = 1\nvar_u = list_c[var_t-1]\nprint(var_u)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'A'\nvar_f = 'B'\nvar_g = '>'\nvar_h = 'A'\nvar_i = 'C'\nvar_j = '>'\nvar_k = 'D'\nvar_l = 'A'\nvar_m = '<'\nvar_n = 'D'\nvar_o = 'B'\nvar_p = '<'\nvar_q = 'D'\nvar_r = 'C'\nvar_s = '<'\nlist_b= []\nif \"/\" in str(var_s):\n    var_s = eval(str(var_s))\nlist_b.append(var_s)\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_t = '[OP_LIST_COND_M(a)X_MIN]'\nvar_u = 1\nvar_v = list_b[var_u-1]\nprint(var_v)"
    },
    "6786": {
        "category": "Arithmetic calculation",
        "question_ko": "연속하는 세 자연수의 합이 30일 때, 세 자연수 중 가운데 수를 구하시오.",
        "question_en": "If the sum of three consecutive natural numbers is 30, what is the middle number among the three natural numbers?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "30 0 3 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 3 [OP_DIV] 3 2 [OP_FDIV] [OP_ADD]",
        "solution_abst_en": "30 0 3 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 3 [OP_DIV] 3 2 [OP_FDIV] [OP_ADD]",
        "solution_code_ko": "var_a = 30\nvar_b = 0\nvar_c = 3\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nlist_a = [i for i in range(var_b, var_e + 1, var_f)]\nlist_a = [float(i) for i in list_a]\nvar_g = sum(list_a)\nvar_h = var_a - var_g\nvar_i = 3\nvar_j = var_h / var_i\nvar_k = 3\nvar_l = 2\nvar_m = var_k // var_l\nvar_n = var_j + var_m\nprint(int(var_n))",
        "solution_code_en": "var_a = 30\nvar_b = 0\nvar_c = 3\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nlist_a = [i for i in range(var_b, var_e + 1, var_f)]\nlist_a = [float(i) for i in list_a]\nvar_g = sum(list_a)\nvar_h = var_a - var_g\nvar_i = 3\nvar_j = var_h / var_i\nvar_k = 3\nvar_l = 2\nvar_m = var_k // var_l\nvar_n = var_j + var_m\nprint(int(var_n))"
    },
    "6787": {
        "category": "Arithmetic calculation",
        "question_ko": "10리터(L) 들이의 통에 물이 가득 들어있습니다. 이 통에서 1리터(L) 500밀리리터(㎖)들이의 그릇으로 물을 가득 담아 3번 덜어낸 후에 1리터(L) 750밀리리터(㎖)들이의 그릇으로 물을 가득 담아 한 번 덜어냈습니다. 그 후 1리터(L) 250밀리리터(㎖)들이의 그릇으로 물을 가득 담아 덜어낸다면 통을 비우기 위해선 1리터(L) 250밀리리터(㎖) 들이의 그릇으로 몇 번 덜어내야 합니까?",
        "question_en": "A container with a capacity of 10 liters (l) is filled with water. From this container, you took the water out using a bowl of 1 liter (L) 500 milliliter (㎖) three times, and then again used a bowl of 1 liter (L) and 750 milliliters (㎖) once. After that, if you poured water out using a bowl of 1 liter (L) 250 milliliters (㎖), how many times did you pour it out using 1 liter (L) 250 milliliters (㎖) bowl to empty the container?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "10 1000 [OP_MUL] 1 1000 [OP_MUL] 500 [OP_ADD] 3 [OP_MUL] [OP_SUB] 1 1000 [OP_MUL] 750 [OP_ADD] [OP_SUB] 1 1000 [OP_MUL] 250 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "10 1000 [OP_MUL] 1 1000 [OP_MUL] 500 [OP_ADD] 3 [OP_MUL] [OP_SUB] 1 1000 [OP_MUL] 750 [OP_ADD] [OP_SUB] 1 1000 [OP_MUL] 250 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = 500\nvar_h = var_f + var_g\nvar_i = 3\nvar_j = var_h * var_i\nvar_k = var_c - var_j\nvar_l = 1\nvar_m = 1000\nvar_n = var_l * var_m\nvar_o = 750\nvar_p = var_n + var_o\nvar_q = var_k - var_p\nvar_r = 1\nvar_s = 1000\nvar_t = var_r * var_s\nvar_u = 250\nvar_v = var_t + var_u\nvar_w = var_q / var_v\nprint(int(var_w))",
        "solution_code_en": "var_a = 10\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = 500\nvar_h = var_f + var_g\nvar_i = 3\nvar_j = var_h * var_i\nvar_k = var_c - var_j\nvar_l = 1\nvar_m = 1000\nvar_n = var_l * var_m\nvar_o = 750\nvar_p = var_n + var_o\nvar_q = var_k - var_p\nvar_r = 1\nvar_s = 1000\nvar_t = var_r * var_s\nvar_u = 250\nvar_v = var_t + var_u\nvar_w = var_q / var_v\nprint(int(var_w))"
    },
    "6788": {
        "category": "Arithmetic calculation",
        "question_ko": "민석이가 드라마를 보기 시작하여 어제는 전체의 1/3을, 오늘은 전체의 2/5를 봤습니다. 안 본 부분은 전체의 얼마인지 구하시오.",
        "question_en": "Minseok started watching the drama, yesterday he watched 1/3 of the total, and today he watched 2/5 of the total. Find how much of the whole is the unseen part.",
        "answer_ko": "0.27",
        "answer_en": "0.27",
        "solution_abst_ko": "1 1/3 [OP_SUB] 2/5 [OP_SUB]",
        "solution_abst_en": "1 1/3 [OP_SUB] 2/5 [OP_SUB]",
        "solution_code_ko": "var_a = 1\nvar_b = 0.3333333333333333\nvar_c = var_a - var_b\nvar_d = 0.4\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 0.3333333333333333\nvar_c = var_a - var_b\nvar_d = 0.4\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "6789": {
        "category": "Arithmetic calculation",
        "question_ko": "태형이는 집에 3번째로 들어갔고, 석진이는 바로 다음으로 집에 들어갔습니다. 석진이는 몇 번째로 들어갔습니까?",
        "question_en": "Taehyung entered the house third, and Seokjin entered the house immediately after. In what number did Seokjin enter?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "3 1 [OP_ADD]",
        "solution_abst_en": "3 1 [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "6790": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 5를 곱해야 할 것을 잘못하여 15를 곱하였더니 45가 되었습니다. 바르게 계산한 결과를 구하시오.",
        "question_en": "I mistakenly multiplied a number by 15, instead of multiplying it by 5, and I got 45. Find the result of the correct calculation.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "45 15 [OP_DIV] 5 [OP_MUL]",
        "solution_abst_en": "45 15 [OP_DIV] 5 [OP_MUL]",
        "solution_code_ko": "var_a = 45\nvar_b = 15\nvar_c = var_a / var_b\nvar_d = 5\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 45\nvar_b = 15\nvar_c = var_a / var_b\nvar_d = 5\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "6791": {
        "category": "Possibility",
        "question_ko": "1, 2, 6 총 3장의 수 카드 중 2장을 사용하여 두 자리 수를 만들려고 합니다. 만들 수 있는 3의 배수 중 가장 작은 수를 구하시오.",
        "question_en": "We are going to use 2 of our 3 number cards 1, 2, and 6 to create a two-digit number. Find the smallest possible multiple of 3.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "[OP_LIST_SOL] 1 2 6 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 3 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 2 6 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 3 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1\nvar_b = 2\nvar_c = 6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 3\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 2\nvar_c = 6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 3\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[var_f-1]\nprint(int(var_g))"
    },
    "6792": {
        "category": "Arithmetic calculation",
        "question_ko": "45개의 사탕을 5개씩 친구들에게 나눈다면 몇 명의 친구에게 나누어 줄 수 있나?",
        "question_en": "How many friends can you give 45 pieces of candy to if you give 5 pieces to each friend?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "45 5 [OP_FDIV]",
        "solution_abst_en": "45 5 [OP_FDIV]",
        "solution_code_ko": "var_a = 45\nvar_b = 5\nvar_c = var_a // var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 45\nvar_b = 5\nvar_c = var_a // var_b\nprint(int(var_c))"
    },
    "6793": {
        "category": "Arithmetic calculation",
        "question_ko": "서로 20미터(m) 떨어져 있는 은행나무와 은행나무 사이에 진달래가 같은 간격으로 7송이 심어져 있습니다. 은행나무와 진달래 사이의 간격이 1미터(m)라면, 진달래와 진달래 사이의 간격은 몇 미터(m)입니까?",
        "question_en": "Seven azaleas are planted at equal intervals between two ginkgo trees that are 20 meters apart. If the distance between the ginkgo tree and the azalea is 1 meter (m), how many meters (m) is the distance between the azaleas?",
        "answer_ko": "2.5",
        "answer_en": "2.5",
        "solution_abst_ko": "20 7 1 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "20 7 1 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 20\nvar_b = 7\nvar_c = 1\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 20\nvar_b = 7\nvar_c = 1\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "6794": {
        "category": "Geometry",
        "question_ko": "어느 직육면체 모양의 상자는 부피가 315제곱센티미터(㎠) 입니다. 이 상자의 가로의 길이가 9센티미터(㎝), 세로의 길이가 7센티미터(㎝)이라면 상자의 높이는 몇 센티미터(㎝)입니까?",
        "question_en": "A box in the shape of a cuboid has a volume of 315 square centimeters (cm2). If the width of this box is 9 centimeters (cm) and the vertical length is 7 centimeters (cm), what is the height of the box in centimeters (cm)?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "315 9 [OP_DIV] 7 [OP_DIV]",
        "solution_abst_en": "315 9 [OP_DIV] 7 [OP_DIV]",
        "solution_code_ko": "var_a = 315\nvar_b = 9\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 315\nvar_b = 9\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "6795": {
        "category": "Arithmetic calculation",
        "question_ko": "연속하는 5개의 자연수의 합이 60입니다. 가운데 수를 구하시오.",
        "question_en": "The sum of five consecutive natural numbers is 60. Find the middle number.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "60 0 5 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 5 [OP_DIV] 5 2 [OP_FDIV] [OP_ADD]",
        "solution_abst_en": "60 0 5 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 5 [OP_DIV] 5 2 [OP_FDIV] [OP_ADD]",
        "solution_code_ko": "var_a = 60\nvar_b = 0\nvar_c = 5\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nlist_a = [i for i in range(var_b, var_e + 1, var_f)]\nlist_a = [float(i) for i in list_a]\nvar_g = sum(list_a)\nvar_h = var_a - var_g\nvar_i = 5\nvar_j = var_h / var_i\nvar_k = 5\nvar_l = 2\nvar_m = var_k // var_l\nvar_n = var_j + var_m\nprint(int(var_n))",
        "solution_code_en": "var_a = 60\nvar_b = 0\nvar_c = 5\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nlist_a = [i for i in range(var_b, var_e + 1, var_f)]\nlist_a = [float(i) for i in list_a]\nvar_g = sum(list_a)\nvar_h = var_a - var_g\nvar_i = 5\nvar_j = var_h / var_i\nvar_k = 5\nvar_l = 2\nvar_m = var_k // var_l\nvar_n = var_j + var_m\nprint(int(var_n))"
    },
    "6796": {
        "category": "Comparison",
        "question_ko": "윤기는 4개, 정국에는 6 곱하기 3만큼 사과를 모았고, 유나는 5개의 사과를 모았습니다. 누가 가장 사과가 많습니까?",
        "question_en": "Yoongi collected 4 apples, Jungkook collected 6 times 3 apples, and Yuna collected 5 apples. Who has the most apples?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 유나 [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_MUL] 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook Yuna [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_MUL] 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nvar_c = '유나'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 6\nvar_f = 3\nvar_g = var_e * var_f\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nvar_c = 'Yuna'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 6\nvar_f = 3\nvar_g = var_e * var_f\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "6797": {
        "category": "Geometry",
        "question_ko": "넓이가 576제곱센티미터(㎠)인 삼각형이 있습니다. 이 삼각형의 밑변이 32센티미터(㎝)이면, 높이는 몇 센티미터(㎝)입니까?",
        "question_en": "A triangle has an area of 576 square centimeters (cm2). If the base of this triangle is 32 centimeters (cm), how many centimeters (cm) is its height?",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "576 2 [OP_MUL] 32 [OP_DIV]",
        "solution_abst_en": "576 2 [OP_MUL] 32 [OP_DIV]",
        "solution_code_ko": "var_a = 576\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 32\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 576\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 32\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "6798": {
        "category": "Correspondence",
        "question_ko": "어떤 수보다 69 작은 숫자는 37입니다. 어떤 수보다 55만큼 큰 숫자는 얼마인가요?",
        "question_en": "37 is 69 smaller than a number. What is the number that is 55 greater than the number?",
        "answer_ko": "161",
        "answer_en": "161",
        "solution_abst_ko": "69 37 [OP_ADD] 55 [OP_ADD]",
        "solution_abst_en": "69 37 [OP_ADD] 55 [OP_ADD]",
        "solution_code_ko": "var_a = 69\nvar_b = 37\nvar_c = var_a + var_b\nvar_d = 55\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 69\nvar_b = 37\nvar_c = var_a + var_b\nvar_d = 55\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "6799": {
        "category": "Arithmetic calculation",
        "question_ko": "철사 4미터(m) 로 모빌을 1 개 만들 수 있습니다. 철사 105.8미터(m) 로 같은 크기의 모빌을 몇 개 만들 수 있습니까?",
        "question_en": "You can make one mobile with 4 meters (m) of wire. How many mobiles of the same size can be made with 105.8 meters (m) of wire?",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "105.8 4 [OP_FDIV]",
        "solution_abst_en": "105.8 4 [OP_FDIV]",
        "solution_code_ko": "var_a = 105.8\nvar_b = 4\nvar_c = var_a // var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 105.8\nvar_b = 4\nvar_c = var_a // var_b\nprint(int(var_c))"
    },
    "6800": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 39를 더하고 44를 빼야 하는데 잘못하여 44를 더하고 39를 뺐더니 63이 되었습니다. 바르게 계산한 결과를 구하시오.",
        "question_en": "I need to add 39 to a number and subtract 44, but I made a mistake by adding 44 and subtracting 39, and I got 63. Find the result of the correct calculation.",
        "answer_ko": "53",
        "answer_en": "53",
        "solution_abst_ko": "63 44 [OP_SUB] 39 [OP_ADD] 39 [OP_ADD] 44 [OP_SUB]",
        "solution_abst_en": "63 44 [OP_SUB] 39 [OP_ADD] 39 [OP_ADD] 44 [OP_SUB]",
        "solution_code_ko": "var_a = 63\nvar_b = 44\nvar_c = var_a - var_b\nvar_d = 39\nvar_e = var_c + var_d\nvar_f = 39\nvar_g = var_e + var_f\nvar_h = 44\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 63\nvar_b = 44\nvar_c = var_a - var_b\nvar_d = 39\nvar_e = var_c + var_d\nvar_f = 39\nvar_g = var_e + var_f\nvar_h = 44\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "6801": {
        "category": "Arithmetic calculation",
        "question_ko": "태형이네 반 학생 수 35명 중 3명의 국어 시험 점수는 각각 93점, 83점, 87점입니다. 나머지 학생들의 국어 평균 점수는 76점일 때 반 전체 국어 평균 점수는 몇 점입니까?",
        "question_en": "Of the 35 students in Taehyung's class, 3 of them scored 93, 83, and 87 points on the Korean language test, respectively. If the average Korean language score of the rest of the students is 76, what is the average Korean language score of the whole class?",
        "answer_ko": "77",
        "answer_en": "77",
        "solution_abst_ko": "76 35 3 [OP_SUB] [OP_MUL] 93 [OP_ADD] 83 [OP_ADD] 87 [OP_ADD] 35 [OP_DIV]",
        "solution_abst_en": "76 35 3 [OP_SUB] [OP_MUL] 93 [OP_ADD] 83 [OP_ADD] 87 [OP_ADD] 35 [OP_DIV]",
        "solution_code_ko": "var_a = 76\nvar_b = 35\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 93\nvar_g = var_e + var_f\nvar_h = 83\nvar_i = var_g + var_h\nvar_j = 87\nvar_k = var_i + var_j\nvar_l = 35\nvar_m = var_k / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 76\nvar_b = 35\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 93\nvar_g = var_e + var_f\nvar_h = 83\nvar_i = var_g + var_h\nvar_j = 87\nvar_k = var_i + var_j\nvar_l = 35\nvar_m = var_k / var_l\nprint(int(var_m))"
    },
    "6802": {
        "category": "Arithmetic calculation",
        "question_ko": "다영이네 반 여학생 10명의 평균 영어 성적은 83.1점 남학생 8명의 평균 영어 성적은 84점입니다. 이 학급 전체의 평균 영어 성적은 몇 점입니까?",
        "question_en": "The average English test score of 10 female students in Dayoung's class is 83.1 points, and the average English test score of 8 male students is 84 points. What is the average English score for this class as a whole?",
        "answer_ko": "83.50",
        "answer_en": "83.5",
        "solution_abst_ko": "10 83.1 [OP_MUL] 8 84 [OP_MUL] [OP_ADD] 10 8 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "10 83.1 [OP_MUL] 8 84 [OP_MUL] [OP_ADD] 10 8 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 83.1\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = 84\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 10\nvar_i = 8\nvar_j = var_h + var_i\nvar_k = var_g / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 10\nvar_b = 83.1\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = 84\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 10\nvar_i = 8\nvar_j = var_h + var_i\nvar_k = var_g / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "6803": {
        "category": "Arithmetic calculation",
        "question_ko": "239.66미터(m)의 산책로의 한쪽에 같은 간격으로 24개의 화단을 만들려고 합니다. 산책로의 처음과 끝에 각각 하나씩 화단을 만든다면, 화단 사이의 거리는 몇 미터(m)입니까?",
        "question_en": "We plan to create 24 flower beds at equal intervals on one side of the 239.66 m (m) long trail. If you make one flower bed at the beginning and one at the end of the trail, what is the distance in meters (m) between the flower beds?",
        "answer_ko": "10.42",
        "answer_en": "10.42",
        "solution_abst_ko": "239.66 24 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "239.66 24 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 239.66\nvar_b = 24\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 239.66\nvar_b = 24\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "6804": {
        "category": "Correspondence",
        "question_ko": "27리터(L)의 물이 있는 수조에 수도꼭지를 열어 물을 받기 시작했다. 1분간 물을 받았더니 욕조에 58리터(L)의 물이 있었다. 이 수조에 다시 1분간 물을 받은 후 48리터(L)의 물을 퍼내면 수조에는 몇 리터(L)의 물이 있는지 구하시오.",
        "question_en": "I opened the faucet and started filling the water tank that has 27 liters (L) of water. When I filled water for 1 minute, the tank had 58 liters (L) of water. After filling water again for 1 minute in this tank, I scooped out 48 liters (L) of water. how many liters (L) of water are in the tank?",
        "answer_ko": "41",
        "answer_en": "41",
        "solution_abst_ko": "58 27 [OP_SUB] 58 48 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "58 27 [OP_SUB] 58 48 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 58\nvar_b = 27\nvar_c = var_a - var_b\nvar_d = 58\nvar_e = 48\nvar_f = var_d - var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 58\nvar_b = 27\nvar_c = var_a - var_b\nvar_d = 58\nvar_e = 48\nvar_f = var_d - var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "6805": {
        "category": "Comparison",
        "question_ko": "두 개의 파이가 있다. 딸기 파이는 반지름이 4센티미터(㎝)이고, 호박 파이는 지름이 10센티미터(㎝)이다. 둘 중 큰 파이는 무엇인가?",
        "question_en": "There are two pies. Strawberry pie has a radius of 4 centimeters (cm), and pumpkin pie has a diameter of 10 centimeters (cm). Which of the two is the bigger pie?",
        "answer_ko": "호박",
        "answer_en": "pumpkin",
        "solution_abst_ko": "[OP_LIST_SOL] 딸기 호박 [OP_LIST_EOL] [OP_LIST_SOL] 4 10 2 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Strawberry pumpkin [OP_LIST_EOL] [OP_LIST_SOL] 4 10 2 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '딸기'\nvar_b = '호박'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 10\nvar_e = 2\nvar_f = var_d / var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Strawberry'\nvar_b = 'pumpkin'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 10\nvar_e = 2\nvar_f = var_d / var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "6806": {
        "category": "Arithmetic calculation",
        "question_ko": "바구니에 있던 귤 중 9개를 은지가 먹고 어머니께서 5개의 귤을 바구니에 더 넣어주셨더니 바구니에 담긴 귤이 20개가 되었다. 처음 바구니에 있던 귤은 몇개인가?",
        "question_en": "Eunji ate 9 of the tangerines in the basket, and her mother put 5 more tangerines in the basket, and the number of tangerines in the basket increased to 20. How many tangerines were in the first basket?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "20 9 [OP_ADD] 5 [OP_SUB]",
        "solution_abst_en": "20 9 [OP_ADD] 5 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 9\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 9\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "6807": {
        "category": "Geometry",
        "question_ko": "어떤 세 점을 잇는 직선을 그릴 수 없습니다. 이 세 점에 대한 선분의 개수는 무엇입니까?",
        "question_en": "You cannot draw a straight line between any three points. What is the number of line segments for these three points?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "3 2 [OP_COMB]",
        "solution_abst_en": "3 2 [OP_COMB]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))"
    },
    "6808": {
        "category": "Arithmetic calculation",
        "question_ko": "효성이는 아침에 가진 물이 0.2만큼 마셨고 점심에 남은 물의 0.35만큼 마셨다. 남은 물이 130밀리리터(㎖)일 때, 효성이가 처음 가지고 있던 물은 몇 밀리리터(㎖)인지 구하시오.",
        "question_en": "Hyosung drank 0.2 of the water he had in the morning and 0.35 of the remaining water at lunch. When 130 milliliters (ml) of water remained, find how many milliliters (ml) of water Hyosung had at first.",
        "answer_ko": "250",
        "answer_en": "250",
        "solution_abst_ko": "130 1 0.35 [OP_SUB] [OP_DIV] 1 0.2 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "130 1 0.35 [OP_SUB] [OP_DIV] 1 0.2 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 130\nvar_b = 1\nvar_c = 0.35\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 1\nvar_g = 0.2\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 130\nvar_b = 1\nvar_c = 0.35\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 1\nvar_g = 0.2\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "6809": {
        "category": "Geometry",
        "question_ko": "높이가 5센티미터(㎝), 밑면 둘레가 16센티미터(㎝)인 직육면체 중 밑면의 넓이가 가장 넓은 것의 부피를 구하라.",
        "question_en": "Find the volume of  the rectangular prism with a height of 5 centimeters (cm) and a base circumference of 16 centimeters (cm), where the base has the maximum area..",
        "answer_ko": "80",
        "answer_en": "80",
        "solution_abst_ko": "16 2 [OP_DIV] 2 [OP_DIV] 2 [OP_POW] 5 [OP_MUL]",
        "solution_abst_en": "16 2 [OP_DIV] 2 [OP_DIV] 2 [OP_POW] 5 [OP_MUL]",
        "solution_code_ko": "var_a = 16\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e ** var_f\nvar_h = 5\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 16\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e ** var_f\nvar_h = 5\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "6810": {
        "category": "Comparison",
        "question_ko": "정국에는 6에서 3을 합한 수를 모았고, 윤기는 4를 모았습니다. 누가 더 작은 수를 가지고 있나요?",
        "question_en": "Jungkook collects the number that adds 3 to 6, and Yoongi collects 4. Who has the smaller number?",
        "answer_ko": "윤기",
        "answer_en": "Yoongi",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 윤기 [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_ADD] 4 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Yoongi [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_ADD] 4 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '윤기'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = 4\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Yoongi'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = 4\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "6811": {
        "category": "Geometry",
        "question_ko": "혜진이가 피규어를 모으기 위해 산 장식장은 가로가 1.2미터(m), 세로가 1.8미터(m)인 직사각형 모양입니다. 장식장의 넓이는 몇 제곱미터(㎡)인지 구하시오.",
        "question_en": "The cabinet Hyejin bought to collect the figures is rectangular in shape with a width of 1.2 meters (m) and a length of 1.8 meters (m). Find the area of the cabinet in square meters (m2).",
        "answer_ko": "2.16",
        "answer_en": "2.16",
        "solution_abst_ko": "1.2 1.8 [OP_MUL]",
        "solution_abst_en": "1.2 1.8 [OP_MUL]",
        "solution_code_ko": "var_a = 1.2\nvar_b = 1.8\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 1.2\nvar_b = 1.8\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "6812": {
        "category": "Possibility",
        "question_ko": "5명의 학생 중 3명이 남학생이고 2명이 여학생이다. 5명을 1열로 세울 때, 남학생들이 모두 연속해서 서는 경우를 구하시오.",
        "question_en": "Of the 5 students, 3 are boys and 2 are girls. When 5 students are arranged in a row, find the case in which all male students stand in a row.",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "[OP_LIST_SOL] A B C D E [OP_LIST_EOL] [OP_LIST_SOL] A C [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] A C E [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D E [OP_LIST_EOL] [OP_LIST_SOL] A C [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] A C E [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 'A'\nvar_g = 'C'\nlist_b= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_h = len(list_c)\nvar_i = len(list_c)\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nvar_k = 'A'\nvar_l = 'C'\nvar_m = 'E'\nlist_d= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_d.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_d.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_d.append(var_k)\nlist_d.reverse()\nvar_n = len(list_d)\nvar_o = len(list_d)\nvar_p = 1\nvar_n = int(var_n)\nvar_o = int(var_o)\nfor i, elem in enumerate(range(var_o)):\n    var_p = var_p * (var_n-i)\nvar_q = var_j * var_p\nprint(int(var_q))",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 'A'\nvar_g = 'C'\nlist_b= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_h = len(list_c)\nvar_i = len(list_c)\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nvar_k = 'A'\nvar_l = 'C'\nvar_m = 'E'\nlist_d= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_d.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_d.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_d.append(var_k)\nlist_d.reverse()\nvar_n = len(list_d)\nvar_o = len(list_d)\nvar_p = 1\nvar_n = int(var_n)\nvar_o = int(var_o)\nfor i, elem in enumerate(range(var_o)):\n    var_p = var_p * (var_n-i)\nvar_q = var_j * var_p\nprint(int(var_q))"
    },
    "6813": {
        "category": "Possibility",
        "question_ko": "원앙 3쌍이 있습니다. 원앙은 총 몇 마리 인가요?",
        "question_en": "There are 3 pairs of mandarin ducks. How many mandarin ducks are there in total?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "3 2 [OP_MUL]",
        "solution_abst_en": "3 2 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "6814": {
        "category": "Arithmetic calculation",
        "question_ko": "도현이가 가진 구슬은 16개씩 7개의 주머니에 담을 수 있습니다. 주현이가 가진 구슬은 25개씩 6개의 주머니에 담을 수 있습니다. 도현이와 주현이가 가진 구슬은 모두 몇 개인지 구하세요.",
        "question_en": "Dohyun's marbles can be put in 7 pockets with 16 each. Joohyun's marbles can be stored in 6 bags with 25 each. Find how many marbles Dohyun and Joohyun have in total.",
        "answer_ko": "262",
        "answer_en": "262",
        "solution_abst_ko": "16 7 [OP_MUL] 25 6 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "16 7 [OP_MUL] 25 6 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 16\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 25\nvar_e = 6\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 16\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 25\nvar_e = 6\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "6815": {
        "category": "Arithmetic calculation",
        "question_ko": "마트에 당근 250킬로그램(㎏)이 있고, 오이는 당근의 2.5배만큼 있습니다. 당근과 오이는 모두 몇 킬로그램(㎏) 있습니까?",
        "question_en": "There are 250 kilograms (kg) of carrots in the supermarket and 2.5 times as many cucumbers as carrots. How many kilograms (kg) are there in both carrots and cucumbers?",
        "answer_ko": "875",
        "answer_en": "875",
        "solution_abst_ko": "250 250 2.5 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "250 250 2.5 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 250\nvar_b = 250\nvar_c = 2.5\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 250\nvar_b = 250\nvar_c = 2.5\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "6816": {
        "category": "Geometry",
        "question_ko": "어느 직각삼각형에서, 빗변이 아닌 한 변의 길이와 나머지 빗변이 아닌 한 변의 길이가 각각 5와 12일 때 빗변의 길이는?",
        "question_en": "In a right triangle, what is the length of the hypotenuse if the length of the non-hypotenuse side and the length of the other non-hypotenuse side are 5 and 12, respectively?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "12 2 [OP_POW] 5 2 [OP_POW] [OP_ADD] 1/2 [OP_POW]",
        "solution_abst_en": "12 2 [OP_POW] 5 2 [OP_POW] [OP_ADD] 1/2 [OP_POW]",
        "solution_code_ko": "var_a = 12\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c + var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 12\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c + var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))"
    },
    "6817": {
        "category": "Possibility",
        "question_ko": "5, 9, 2, 7, 3 수 카드를 중복을 사용하여 몫이 가장 큰 (세 자리 수)/(두 자리 수)를 만들었습니다. 나머지를 구하세요.",
        "question_en": "There are (Three digit number)/(two digit number) with the highest quotient were made by using 5, 9, 2, 7, and 3 number cards allowing duplicates. Find the remainder.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "[OP_LIST_SOL] 5 9 2 7 3 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 1 [OP_LIST_MAX] [OP_LIST_POP] 2 [OP_LIST_GET_PRODUCT] 1 [OP_LIST_MIN] [OP_MOD]",
        "solution_abst_en": "[OP_LIST_SOL] 5 9 2 7 3 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 1 [OP_LIST_MAX] [OP_LIST_POP] 2 [OP_LIST_GET_PRODUCT] 1 [OP_LIST_MIN] [OP_MOD]",
        "solution_code_ko": "var_a = 5\nvar_b = 9\nvar_c = 2\nvar_d = 7\nvar_e = 3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 2\nlist_d = [str(i) for i in list_a]\nlist_d = list(itertools.product(list_d, repeat=var_i))\nlist_d = [''.join(num_list) for num_list in list_d]\nlist_d = [str_num for str_num in list_d if str_num[0] != '0']\nlist_d = [float(i) for i in list_d]\nvar_j = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_k = list_e[var_j-1]\nvar_l = var_h % var_k\nprint(int(var_l))",
        "solution_code_en": "var_a = 5\nvar_b = 9\nvar_c = 2\nvar_d = 7\nvar_e = 3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 2\nlist_d = [str(i) for i in list_a]\nlist_d = list(itertools.product(list_d, repeat=var_i))\nlist_d = [''.join(num_list) for num_list in list_d]\nlist_d = [str_num for str_num in list_d if str_num[0] != '0']\nlist_d = [float(i) for i in list_d]\nvar_j = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_k = list_e[var_j-1]\nvar_l = var_h % var_k\nprint(int(var_l))"
    },
    "6818": {
        "category": "Arithmetic calculation",
        "question_ko": "형과 동생이 받은 용돈의 합은 12000원이고, 형이 동생보다 1000원 더 받았다면, 형이 받은 용돈은 얼마인지 구하시오.",
        "question_en": "If the sum of the allowances received by the older brother and the younger brother is 12,000 won, and the older brother received 1,000 won more than the younger brother, how much money did the older brother receive?",
        "answer_ko": "6500",
        "answer_en": "6500",
        "solution_abst_ko": "12000 1000 [OP_SUB] 2 [OP_DIV] 1000 [OP_ADD]",
        "solution_abst_en": "12000 1000 [OP_SUB] 2 [OP_DIV] 1000 [OP_ADD]",
        "solution_code_ko": "var_a = 12000\nvar_b = 1000\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 1000\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 12000\nvar_b = 1000\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 1000\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "6819": {
        "category": "Possibility",
        "question_ko": "빵 7개를 윤기와 유나가 나누어 먹으려고 합니다. 한 사람은 적어도 1개의 빵을 먹어야 합니다. 빵을 나누어 먹는 방법은 모두 몇 가지입니까?",
        "question_en": "Yoongi and Yuna want to share the 7 loaves of bread. One person must eat at least 1 loaf of bread. How many ways are there to share bread?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "7 2 1 [OP_MUL] [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "7 2 1 [OP_MUL] [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 7\nvar_b = 2\nvar_c = 1\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 7\nvar_b = 2\nvar_c = 1\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "6820": {
        "category": "Comparison",
        "question_ko": "남준이는 학교에 12번째로 도착했고, 지민이는 남준이보다 3명 앞에서 먼저 학교에 도착했습니다. 지민이는 몇 번째로 도착했습니까?",
        "question_en": "Namjoon was the 12th to arrive at school, and Jimin arrived at school 3 people earlier than Namjoon. In what number did Jimin arrive?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "12 3 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "12 3 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 12\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "6821": {
        "category": "Correspondence",
        "question_ko": "샛별이네 학교 학생들이 서로 한 번씩 씨름 경기를 하려고 합니다. 씨름 경기를 모두 91번 했다면 경기에 참여한 학생은 모두 몇 명입니까?",
        "question_en": "The students of Saebyeol's school are going to have a wrestling match with each other once. How many students participated in the wrestling match if they had played 91 times?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "91 2 [OP_MUL] 1/2 [OP_POW] 1 [OP_CEIL]",
        "solution_abst_en": "91 2 [OP_MUL] 1/2 [OP_POW] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 91\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 1\nvar_g=int(((var_e+9*10**(var_f-2))//(10**(var_f-1)))*10**(var_f-1))\n\nprint(int(var_g))",
        "solution_code_en": "var_a = 91\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 1\nvar_g=int(((var_e+9*10**(var_f-2))//(10**(var_f-1)))*10**(var_f-1))\n\nprint(int(var_g))"
    },
    "6822": {
        "category": "Comparison",
        "question_ko": "20명의 학생들이 한 줄로 줄을 섰습니다. 윤기의 앞에는 정국이가 서있고, 정국이 뒤에는 11명의 학생들이 서 있습니다. 윤기의 앞에 서 있는 학생은 몇 명입니까?",
        "question_en": "20 students lined up in a single line. Jungkook is standing right in front of Yoongi, and 11 students are standing behind him. How many students are standing in front of Yoongi?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "20 11 [OP_SUB] 1 [OP_ADD] 1 [OP_SUB]",
        "solution_abst_en": "20 11 [OP_SUB] 1 [OP_ADD] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 1\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 1\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "6823": {
        "category": "Comparison",
        "question_ko": "3개의 숫자 0.8, 1/2, 0.9가 있습니다. 2보다 작거나 같은 수 중 가장 크거나 같은 숫자는 얼마인가요?",
        "question_en": "There are three numbers 0.8, 1/2, and 0.9. Which of the numbers less than or equal to 2 is the largest?",
        "answer_ko": "0.90",
        "answer_en": "0.9",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 2 [OP_LIST_LESS_EQUAL] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 2 [OP_LIST_LESS_EQUAL] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = []\nfor i in list_a:\n    if i <= var_d:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint('{:.2f}'.format(round(var_f+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = []\nfor i in list_a:\n    if i <= var_d:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint('{:.2f}'.format(round(var_f+1e-10,2)))"
    },
    "6824": {
        "category": "Comparison",
        "question_ko": "1.7, 1/5, 1/5, 1, 3/5, 3/8, 1.4 등 7개의 숫자가 있습니다. 크기를 비교하여 가장 큰 것부터 순서대로 쓸 때 네 번째 숫자는 무엇입니까?",
        "question_en": "There are 7 numbers: 1.7, 1/5, 1/5, 1, 3/5, 3/8, and 1.4. When comparing sizes and writing them in order from largest to smallest, what is the fourth number?",
        "answer_ko": "0.60",
        "answer_en": "0.6",
        "solution_abst_ko": "[OP_LIST_SOL] 1.7 1 5 [OP_DIV] 1 5 [OP_DIV] 1 3 5 [OP_DIV] 3 8 [OP_DIV] 1.4 [OP_LIST_EOL] 4 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1.7 1 5 [OP_DIV] 1 5 [OP_DIV] 1 3 5 [OP_DIV] 3 8 [OP_DIV] 1.4 [OP_LIST_EOL] 4 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1.7\nvar_b = 1\nvar_c = 5\nvar_d = var_b / var_c\nvar_e = 1\nvar_f = 5\nvar_g = var_e / var_f\nvar_h = 1\nvar_i = 3\nvar_j = 5\nvar_k = var_i / var_j\nvar_l = 3\nvar_m = 8\nvar_n = var_l / var_m\nvar_o = 1.4\nlist_a= []\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_a.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_a.append(var_n)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_a.append(var_k)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_p = 4\nlist_b=list_a.copy()\nlist_b.sort()\nvar_q = list_b[-var_p]\nprint('{:.2f}'.format(round(var_q+1e-10,2)))",
        "solution_code_en": "var_a = 1.7\nvar_b = 1\nvar_c = 5\nvar_d = var_b / var_c\nvar_e = 1\nvar_f = 5\nvar_g = var_e / var_f\nvar_h = 1\nvar_i = 3\nvar_j = 5\nvar_k = var_i / var_j\nvar_l = 3\nvar_m = 8\nvar_n = var_l / var_m\nvar_o = 1.4\nlist_a= []\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_a.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_a.append(var_n)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_a.append(var_k)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_p = 4\nlist_b=list_a.copy()\nlist_b.sort()\nvar_q = list_b[-var_p]\nprint('{:.2f}'.format(round(var_q+1e-10,2)))"
    },
    "6825": {
        "category": "Possibility",
        "question_ko": "다섯 개의 흰 공이 나란히 놓여 있고, 흰 공을 빨간 공 1개, 파란 공 1개, 노란 공 2개로 색칠하려고 한다. 색칠 된 공들의 색깔 배치가 서로 다른 경우는 모두 몇가지인가?",
        "question_en": "Five white balls are placed next to each other, and you want to color each white ball with one red, one blue, and two yellow. In how many different ways are the colored balls placed differently?",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "5 4 [OP_PERM] 2 [OP_DIV]",
        "solution_abst_en": "5 4 [OP_PERM] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 5\nvar_b = 4\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 4\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "6826": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 7센티미터(㎝)이며 변이 총 3개인 도형이 있습니다. 이 도형의 둘레는 몇 센티미터(㎝)입니까?",
        "question_en": "A figure has a side length of 7 centimeters (cm) and 3 sides in total. What is the perimeter of this shape in centimeters (cm)?",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "7 3 [OP_MUL]",
        "solution_abst_en": "7 3 [OP_MUL]",
        "solution_code_ko": "var_a = 7\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 7\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "6827": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 5를 더했더니 9가 되었습니다. 어떤 수를 구하시오.",
        "question_en": "When you add 5 to a number, you get 9. Find the number",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "9 5 [OP_SUB]",
        "solution_abst_en": "9 5 [OP_SUB]",
        "solution_code_ko": "var_a = 9\nvar_b = 5\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 9\nvar_b = 5\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "6828": {
        "category": "Arithmetic calculation",
        "question_ko": "담을 칠하는 데 페인트 6.12리터(L)가 필요하다고 합니다. 페인트 33.5리터(L)로 담을 모두 칠하고 남는 양은 얼마입니까?",
        "question_en": "It is said that it takes 6.12 liters (L) of paint to paint a wall. How much is left after painting all the walls with 33.5 liters (L) of paint?",
        "answer_ko": "2.90",
        "answer_en": "2.9",
        "solution_abst_ko": "33.5 6.12 [OP_MOD]",
        "solution_abst_en": "33.5 6.12 [OP_MOD]",
        "solution_code_ko": "var_a = 33.5\nvar_b = 6.12\nvar_c = var_a % var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 33.5\nvar_b = 6.12\nvar_c = var_a % var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "6829": {
        "category": "Arithmetic calculation",
        "question_ko": "14 이상 105 이하인 자연수 중에서 가장 큰 수를 가장 작은 수로 나눈 나머지는 얼마입니까?",
        "question_en": "What is the remainder when dividing the largest number between 14 and 105 inclusive by the smallest number?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "105 14 [OP_MOD]",
        "solution_abst_en": "105 14 [OP_MOD]",
        "solution_code_ko": "var_a = 105\nvar_b = 14\nvar_c = var_a % var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 105\nvar_b = 14\nvar_c = var_a % var_b\nprint(int(var_c))"
    },
    "6830": {
        "category": "Correspondence",
        "question_ko": "닭장 안에 병아리와 닭을 모두 합쳐 821마리가 있다. 병아리가 267마리일 때, 닭이 병아리보다 몇 마리 더 많은지 구하시오.",
        "question_en": "There are total 821 numbers of chicks and chickens in the coop. If there are 267 chicks, find how many more chickens there are than chicks.",
        "answer_ko": "287",
        "answer_en": "287",
        "solution_abst_ko": "821 267 [OP_SUB] 267 [OP_SUB]",
        "solution_abst_en": "821 267 [OP_SUB] 267 [OP_SUB]",
        "solution_code_ko": "var_a = 821\nvar_b = 267\nvar_c = var_a - var_b\nvar_d = 267\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 821\nvar_b = 267\nvar_c = var_a - var_b\nvar_d = 267\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "6831": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 479를 더해야 하는데 잘못하여 749를 뺐더니 280이 되었습니다. 바르게 계산한 결과를 구하시오.",
        "question_en": "I need to add 479 to a certain number, but I mistakenly subtracted 749, so I got 280. Find the result of the correct calculation.",
        "answer_ko": "1508",
        "answer_en": "1508",
        "solution_abst_ko": "280 749 [OP_ADD] 479 [OP_ADD]",
        "solution_abst_en": "280 749 [OP_ADD] 479 [OP_ADD]",
        "solution_code_ko": "var_a = 280\nvar_b = 749\nvar_c = var_a + var_b\nvar_d = 479\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 280\nvar_b = 749\nvar_c = var_a + var_b\nvar_d = 479\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "6832": {
        "category": "Arithmetic calculation",
        "question_ko": "32와 24의 공약수의 개수를 구하시오.",
        "question_en": "Find the number of common divisors of 32 and 24.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "32 [OP_LIST_GET_DIVISOR] 24 [OP_LIST_GET_DIVISOR] [OP_SET_INTERSECT] [OP_LIST_LEN]",
        "solution_abst_en": "32 [OP_LIST_GET_DIVISOR] 24 [OP_LIST_GET_DIVISOR] [OP_SET_INTERSECT] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 32\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 24\nlist_b = []\nnum_sqrt = int(math.sqrt(var_b))\nfor i in range(1, num_sqrt+1):\n    if var_b % i == 0:\n        list_b.append(i)\n        list_b.append(int(var_b/i))\nlist_b = sorted(set(list_b))\nlist_c = list(set(list_a) & set(list_b))\nvar_c = len(list_c)\nprint(int(var_c))",
        "solution_code_en": "var_a = 32\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 24\nlist_b = []\nnum_sqrt = int(math.sqrt(var_b))\nfor i in range(1, num_sqrt+1):\n    if var_b % i == 0:\n        list_b.append(i)\n        list_b.append(int(var_b/i))\nlist_b = sorted(set(list_b))\nlist_c = list(set(list_a) & set(list_b))\nvar_c = len(list_c)\nprint(int(var_c))"
    },
    "6833": {
        "category": "Possibility",
        "question_ko": "1부터 9까지의 자연수가 적힌 숫자 카드가 있습니다. 이 중 3개를 빼서 더했을 때 19를 만드는 방법은 모두 몇 가지입니까?",
        "question_en": "There are number cards with the natural numbers from 1 to 9 written on them. How many ways can there that makes a total of 19 when taking 3 cards out?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "1 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 19 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 19 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 19\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 19\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))"
    },
    "6834": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 46을 곱해야 할 것을 잘못하여 뺐더니 27이 되었습니다. 바르게 계산하면 얼마입니까?",
        "question_en": "I mistakenly subtracted 46 from a number that should have been multiplied by 46, and I got 27. How much do you get when you calculate it correctly?",
        "answer_ko": "3358",
        "answer_en": "3358",
        "solution_abst_ko": "27 46 [OP_ADD] 46 [OP_MUL]",
        "solution_abst_en": "27 46 [OP_ADD] 46 [OP_MUL]",
        "solution_code_ko": "var_a = 27\nvar_b = 46\nvar_c = var_a + var_b\nvar_d = 46\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 27\nvar_b = 46\nvar_c = var_a + var_b\nvar_d = 46\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "6835": {
        "category": "Geometry",
        "question_ko": "실을 사용하여 한 변이 20센티미터(㎝)인 정사각형을 만들었습니다. 똑같은 실을 사용하여 가로의 길이가 14센티미터(㎝)인 직사각형을 만들었습니다. 이 직사각형의 세로의 길이를 구하시오.",
        "question_en": "Using string, a square with a side of 20 centimeters (cm) was made. Using the same string, a rectangle wide 14 centimeters (cm) was made. Find the length of the height of this rectangle.",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "20 4 [OP_MUL] 2 [OP_DIV] 14 [OP_SUB]",
        "solution_abst_en": "20 4 [OP_MUL] 2 [OP_DIV] 14 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 14\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 20\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 14\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "6836": {
        "category": "Comparison",
        "question_ko": "은행, 학교, 문구점, 편의점, 공원 순으로 거리가 가깝습니다. 5번째로 거리가 가까운 건물은 무엇인가요?",
        "question_en": "The bank, school, stationery store, convenience store, and park are the closest in that order. What is the 5th closest building?",
        "answer_ko": "공원",
        "answer_en": "park",
        "solution_abst_ko": "[OP_LIST_SOL] 은행 학교 문구점 편의점 공원 [OP_LIST_EOL] 5 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] bank school stationery convenience park [OP_LIST_EOL] 5 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '은행'\nvar_b = '학교'\nvar_c = '문구점'\nvar_d = '편의점'\nvar_e = '공원'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 5\nvar_g = list_a[var_f-1]\nprint(var_g)",
        "solution_code_en": "var_a = 'bank'\nvar_b = 'school'\nvar_c = 'stationery'\nvar_d = 'convenience'\nvar_e = 'park'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 5\nvar_g = list_a[var_f-1]\nprint(var_g)"
    },
    "6837": {
        "category": "Comparison",
        "question_ko": "(가) 상자와 (나) 상자의 크기를 비교했더니, (가) 상자가 (나) 상자보다 컸습니다. (가), (나) 2개의 상자 중 크기가 작은 상자는 무엇입니까?",
        "question_en": "When I compared the sizes of box (a) and box (b), box (a) was larger than box (b). Between two boxes (a) and (b), which one is the smaller one?",
        "answer_ko": "(나)",
        "answer_en": "(b)",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) [OP_LIST_EOL] [OP_LIST_SOL] (가) (나) > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (a) (b) [OP_LIST_EOL] [OP_LIST_SOL] (a) (b) > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = '(가)'\nvar_d = '(나)'\nvar_e = '>'\nlist_b= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_f = len(list_c)\nvar_g = list_c[var_f-1]\nprint(var_g)",
        "solution_code_en": "var_a = '(a)'\nvar_b = '(b)'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = '(a)'\nvar_d = '(b)'\nvar_e = '>'\nlist_b= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_f = len(list_c)\nvar_g = list_c[var_f-1]\nprint(var_g)"
    },
    "6838": {
        "category": "Arithmetic calculation",
        "question_ko": "세 수 A, B, C의 평균은 130입니다. 여기에 수 D를 더 넣어서 평균을 구했더니 126이 되었습니다. D를 구하시오.",
        "question_en": "The average of the three numbers A, B, and C is 130. When you look for an average of those 3 numbers and D, you get 126. Find what D is.",
        "answer_ko": "114",
        "answer_en": "114",
        "solution_abst_ko": "126 4 [OP_MUL] 130 3 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "126 4 [OP_MUL] 130 3 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 126\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 130\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 126\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 130\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "6839": {
        "category": "Comparison",
        "question_ko": "진호는 1을 4배, 0.1을 2배, 0.001을 7배하여 더한 수를 갖고 있다. 영희는 진호가 가진 수의 100배인 수를 갖고 있다. 정수는 영희가 가진 수보다 0.05 큰 수의 인 수를 가지고 있다면, 정수가 가지고 있는 수는 얼마인지 소수로 나타내어라",
        "question_en": "Jinho has a number that is the sum of 1 multiplied by 4, 0.1 multiplied by 2, and 0.001 multiplied by 7. Younghee has a number that is 100 multiplied by Jinho's number. If Jungsoo has a number that is 0.05 greater than Younghee's number, express Jungsoo's number in a decimal number.",
        "answer_ko": "420.75",
        "answer_en": "420.75",
        "solution_abst_ko": "1 4 [OP_MUL] 0.1 2 [OP_MUL] [OP_ADD] 0.001 7 [OP_MUL] [OP_ADD] 100 [OP_MUL] 0.05 [OP_ADD]",
        "solution_abst_en": "1 4 [OP_MUL] 0.1 2 [OP_MUL] [OP_ADD] 0.001 7 [OP_MUL] [OP_ADD] 100 [OP_MUL] 0.05 [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 0.1\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 0.001\nvar_i = 7\nvar_j = var_h * var_i\nvar_k = var_g + var_j\nvar_l = 100\nvar_m = var_k * var_l\nvar_n = 0.05\nvar_o = var_m + var_n\nprint('{:.2f}'.format(round(var_o+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 0.1\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 0.001\nvar_i = 7\nvar_j = var_h * var_i\nvar_k = var_g + var_j\nvar_l = 100\nvar_m = var_k * var_l\nvar_n = 0.05\nvar_o = var_m + var_n\nprint('{:.2f}'.format(round(var_o+1e-10,2)))"
    },
    "6840": {
        "category": "Possibility",
        "question_ko": "A, B, C, D, E 5명이 있다. 5명을 한 줄로 세울 때, A를 맨 앞에 세우는 경우의 수를 구하시오.",
        "question_en": "There are 5 people A, B, C, D, and E. When 5 people are lined up, find the number of ways to put A at the front.",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "[OP_LIST_SOL] A B C D E [OP_LIST_EOL] [OP_LIST_SOL] A [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D E [OP_LIST_EOL] [OP_LIST_SOL] A [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 'A'\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_g = len(list_c)\nvar_h = len(list_c)\nvar_i = 1\nvar_g = int(var_g)\nvar_h = int(var_h)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i * (var_g-i)\nprint(int(var_i))",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nvar_e = 'E'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 'A'\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_g = len(list_c)\nvar_h = len(list_c)\nvar_i = 1\nvar_g = int(var_g)\nvar_h = int(var_h)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i * (var_g-i)\nprint(int(var_i))"
    },
    "6841": {
        "category": "Arithmetic calculation",
        "question_ko": "정민이는 연준이와 함께 줄넘기를 하고 있습니다. 정민이는 4분에 256개를 할 수 있고 지민이는 3분동안 111개를 할 수 있습니다. 3분동안 정민이와 지민이가 줄넘기를 했다면 두 사람의 줄넘기 횟수의 합을 구하세요.",
        "question_en": "Jung-min is jumping rope with Yeon-jun. Jung-min can do 256 in 4 minutes and Jimin can do 111 in 3 minutes. If Jung-min and Jimin did jumping rope for 3 minutes, find the sum of the number of times they jumped rope.",
        "answer_ko": "303",
        "answer_en": "303",
        "solution_abst_ko": "256 3 4 [OP_DIV] [OP_MUL] 111 [OP_ADD]",
        "solution_abst_en": "256 3 4 [OP_DIV] [OP_MUL] 111 [OP_ADD]",
        "solution_code_ko": "var_a = 256\nvar_b = 3\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 111\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 256\nvar_b = 3\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 111\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "6842": {
        "category": "Geometry",
        "question_ko": "높이가 8센티미터(㎝)이고, 모든 모서리의 길이의 합이 104센티미터(㎝)인 사각기둥 모양의 연필꽂이가 있습니다. 이 연필꽂이의 모든 옆면에 한 변의 길이가 4센티미터(㎝)인 정사각형 모양의 스티커를 겹치지 않게 빈틈없이 붙여 꾸미려고 한다면, 스티커는 모두 몇 장이 필요합니까?",
        "question_en": "There is a pencil case in the shape of a square prism. Its height is 8 centimeters (cm) and the sum of the lengths of all edges is 104 centimeters (cm). If you are going to decorate all the sides of this pencil case with square stickers measuring 4 centimeters (cm) on each side, without any overlaps, how many stickers are needed?",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "104 8 4 [OP_MUL] [OP_SUB] 4 2 [OP_MUL] [OP_DIV] 8 [OP_MUL] 4 [OP_MUL] 4 2 [OP_POW] [OP_DIV]",
        "solution_abst_en": "104 8 4 [OP_MUL] [OP_SUB] 4 2 [OP_MUL] [OP_DIV] 8 [OP_MUL] 4 [OP_MUL] 4 2 [OP_POW] [OP_DIV]",
        "solution_code_ko": "var_a = 104\nvar_b = 8\nvar_c = 4\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 4\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_e / var_h\nvar_j = 8\nvar_k = var_i * var_j\nvar_l = 4\nvar_m = var_k * var_l\nvar_n = 4\nvar_o = 2\nvar_p = var_n ** var_o\nvar_q = var_m / var_p\nprint(int(var_q))",
        "solution_code_en": "var_a = 104\nvar_b = 8\nvar_c = 4\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 4\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_e / var_h\nvar_j = 8\nvar_k = var_i * var_j\nvar_l = 4\nvar_m = var_k * var_l\nvar_n = 4\nvar_o = 2\nvar_p = var_n ** var_o\nvar_q = var_m / var_p\nprint(int(var_q))"
    },
    "6843": {
        "category": "Geometry",
        "question_ko": "어떤 직사각형의 넓이가 28제곱센티미터(㎠) 이고 가로가 4센티미터(㎝)이면 세로가 몇 센티미터(㎝)입니까?",
        "question_en": "If a rectangle has an area of 28 square centimeters (cm2) and a width of 4 centimeters (cm), how many centimeters (cm) is its length?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "28 4 [OP_DIV]",
        "solution_abst_en": "28 4 [OP_DIV]",
        "solution_code_ko": "var_a = 28\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 28\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "6844": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 23을 빼야 하는데 잘못하여 32를 뺐더니 25가 되었습니다. 바르게 계산한 결과를 구하시오.",
        "question_en": "I mistakenly subtracted 32 from a certain number, when I needed to subtract 23, and I got 25. Find the result of the correct calculation.",
        "answer_ko": "34",
        "answer_en": "34",
        "solution_abst_ko": "25 32 [OP_ADD] 23 [OP_SUB]",
        "solution_abst_en": "25 32 [OP_ADD] 23 [OP_SUB]",
        "solution_code_ko": "var_a = 25\nvar_b = 32\nvar_c = var_a + var_b\nvar_d = 23\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 25\nvar_b = 32\nvar_c = var_a + var_b\nvar_d = 23\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "6845": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 4.3을 더해야 할 것을 잘못하여 뺐더니 8.8이 되었습니다. 바르게 계산한 값을 구해 보시오.",
        "question_en": "You subtracted 4.3 when you should have added 4.3 to a number, resulting in 8.8. Find the correct value.",
        "answer_ko": "17.40",
        "answer_en": "17.4",
        "solution_abst_ko": "8.8 4.3 [OP_ADD] 4.3 [OP_ADD]",
        "solution_abst_en": "8.8 4.3 [OP_ADD] 4.3 [OP_ADD]",
        "solution_code_ko": "var_a = 8.8\nvar_b = 4.3\nvar_c = var_a + var_b\nvar_d = 4.3\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 8.8\nvar_b = 4.3\nvar_c = var_a + var_b\nvar_d = 4.3\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "6846": {
        "category": "Possibility",
        "question_ko": "2마리의 원숭이에게 사과 7개를 나누어 주려고 합니다. 이 때, 원숭이들은 적어도 사과 1개를 받는다고 할 때, 사과를 나누어 주는 방법은 모두 몇 가지입니까?",
        "question_en": "You want to share 7 apples with 2 monkeys. In this case, if the monkeys get at least one apple, how many ways can monkeys share the apple?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "2 7 [OP_ADD] 2 1 [OP_MUL] [OP_SUB] 1 [OP_SUB] 7 2 1 [OP_MUL] [OP_SUB] [OP_COMB]",
        "solution_abst_en": "2 7 [OP_ADD] 2 1 [OP_MUL] [OP_SUB] 1 [OP_SUB] 7 2 1 [OP_MUL] [OP_SUB] [OP_COMB]",
        "solution_code_ko": "var_a = 2\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = 1\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = 7\nvar_k = 2\nvar_l = 1\nvar_m = var_k * var_l\nvar_n = var_j - var_m\nvar_o = 1\nvar_i = int(var_i)\nvar_n = int(var_n)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o * (var_i-i)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o / (i+1)\nprint(int(var_o))",
        "solution_code_en": "var_a = 2\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = 1\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = 7\nvar_k = 2\nvar_l = 1\nvar_m = var_k * var_l\nvar_n = var_j - var_m\nvar_o = 1\nvar_i = int(var_i)\nvar_n = int(var_n)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o * (var_i-i)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o / (i+1)\nprint(int(var_o))"
    },
    "6847": {
        "category": "Arithmetic calculation",
        "question_ko": "경호네 반 남학생 10명의 평균 국어 성적은 83.1점, 여학생 8명의 평균 국어 성적은 84점입니다. 이 학급 전체의 국어 성적 평균은 몇 점입니까?",
        "question_en": "The average score for the Korean language of 10 male students in Kyungho's class was 83.1 points, and the average Korean language score of 8 female students was 84 points. What is the average Korean language score for this class as a whole?",
        "answer_ko": "83.50",
        "answer_en": "83.5",
        "solution_abst_ko": "10 83.1 [OP_MUL] 8 84 [OP_MUL] [OP_ADD] 10 8 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "10 83.1 [OP_MUL] 8 84 [OP_MUL] [OP_ADD] 10 8 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 83.1\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = 84\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 10\nvar_i = 8\nvar_j = var_h + var_i\nvar_k = var_g / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 10\nvar_b = 83.1\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = 84\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 10\nvar_i = 8\nvar_j = var_h + var_i\nvar_k = var_g / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "6848": {
        "category": "Arithmetic calculation",
        "question_ko": "인형 한 묶음에는 12개의 인형이 들어있습니다. 11명의 학생이 인형 3 묶음을 가져가서 3개씩 가져갔다고 할 때 남은 인형은 몇 개 입니까?",
        "question_en": "Each pack of dolls contains 12 dolls. How many dolls are left if 11 students took 3 dolls each from 3 packs of dolls?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "12 3 [OP_MUL] 11 3 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "12 3 [OP_MUL] 11 3 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 12\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 11\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 12\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 11\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "6849": {
        "category": "Arithmetic calculation",
        "question_ko": "191.8센티미터(㎝)의 책상 양끝에 같은 간격으로 58개의 점을 찍으려고 합니다. 책상의 처음과 끝에 모두 점을 찍는다면 점과 점 사이의 거리는 몇 센티미터(㎝)입니까?",
        "question_en": "I want to mark 58 dots at equal intervals on both sides of a 191.8 centimeters (cm) desk. If you place a dot at both the beginning and end of the desk, how many centimeters (cm) is the distance between the dots?",
        "answer_ko": "6.85",
        "answer_en": "6.85",
        "solution_abst_ko": "191.8 58 2 [OP_DIV] 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "191.8 58 2 [OP_DIV] 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 191.8\nvar_b = 58\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_a / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 191.8\nvar_b = 58\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_a / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "6850": {
        "category": "Geometry",
        "question_ko": "길이가 28센티미터(㎝)인 철사를 사용하여 가장 큰 정사각형을 만들었습니다. 정사각형의 한 변은 몇 센티미터(㎝)입니까?",
        "question_en": "I made the largest square using a piece of wire that is 28 centimeters (cm) long. How many centimeters (cm) is one side of the square?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "28 4 [OP_DIV]",
        "solution_abst_en": "28 4 [OP_DIV]",
        "solution_code_ko": "var_a = 28\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 28\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "6851": {
        "category": "Arithmetic calculation",
        "question_ko": "1달마다 처음의 2배로 복제되는 수초가 있습니다. 처음에 그릇과 그릇에 담긴 수초 100잎의 무게의 합은 23.97그램(g)이었고, 5달 후 그릇과 그릇에 담긴 수초의 무게의 합은 155.1그램(g)이었습니다. 복제된 수초 10000잎은 몇 그램(g)일까요?",
        "question_en": "There is a myelin that reproduces twice as much as the first every month. At first, the sum of the weight of 100 myelin leaves in the bowl and bowl was 23.97 grams (g), and after 5 months, the sum of the weight of the bowl and the myelin leaves in the bowl was 155.1 grams (g). How many grams (g) are 10000 cloned myelin leaves?",
        "answer_ko": "423",
        "answer_en": "423",
        "solution_abst_ko": "155.1 23.97 [OP_SUB] 100 2 5 [OP_POW] [OP_MUL] 100 [OP_SUB] [OP_DIV] 10000 [OP_MUL]",
        "solution_abst_en": "155.1 23.97 [OP_SUB] 100 2 5 [OP_POW] [OP_MUL] 100 [OP_SUB] [OP_DIV] 10000 [OP_MUL]",
        "solution_code_ko": "var_a = 155.1\nvar_b = 23.97\nvar_c = var_a - var_b\nvar_d = 100\nvar_e = 2\nvar_f = 5\nvar_g = var_e ** var_f\nvar_h = var_d * var_g\nvar_i = 100\nvar_j = var_h - var_i\nvar_k = var_c / var_j\nvar_l = 10000\nvar_m = var_k * var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 155.1\nvar_b = 23.97\nvar_c = var_a - var_b\nvar_d = 100\nvar_e = 2\nvar_f = 5\nvar_g = var_e ** var_f\nvar_h = var_d * var_g\nvar_i = 100\nvar_j = var_h - var_i\nvar_k = var_c / var_j\nvar_l = 10000\nvar_m = var_k * var_l\nprint(int(var_m))"
    },
    "6852": {
        "category": "Correspondence",
        "question_ko": "연속된 자연수 15개는 어떤 자연수와 81사이에 있다. 어떤 수가 81보다 작으면 어떤 수는 얼마인가?",
        "question_en": "15 consecutive natural numbers lie between a certain natural number and 81. What is this natural number when it is less than 81?",
        "answer_ko": "66",
        "answer_en": "66",
        "solution_abst_ko": "81 15 [OP_SUB]",
        "solution_abst_en": "81 15 [OP_SUB]",
        "solution_code_ko": "var_a = 81\nvar_b = 15\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 81\nvar_b = 15\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "6853": {
        "category": "Correspondence",
        "question_ko": "20에 어떤 수를 곱하려고 합니다. 잘못하여 40에 어떤 수를 더했더니 결과는 52가 되었습니다. 바르게 계산한 결과는 얼마일까요?",
        "question_en": "You want to multiply 20 by some number. However, you mistakenly added some number to 40, and the result was 52. What is the correct calculation result?",
        "answer_ko": "240",
        "answer_en": "240",
        "solution_abst_ko": "20 52 40 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "20 52 40 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 20\nvar_b = 52\nvar_c = 40\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 52\nvar_c = 40\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nprint(int(var_e))"
    },
    "6854": {
        "category": "Arithmetic calculation",
        "question_ko": "집에서 은행까지의 거리는 800미터(m)이고, 은행에서 약국까지의 거리는 1킬로미터(㎞) 300미터(m), 약국에서 학교까지의 거리는 1700미터(m)입니다. 집에서 은행을 거쳐 약국까지의 거리는 약국에서 학교까지의 거리보다 몇 미터(m) 더 멉니까?",
        "question_en": "The distance from the house to the bank is 800 meters (m), from the bank to the pharmacy is 1 kilometer (km) and 300 meters (m), and from the pharmacy to the school is 1700 meters (m). How many meters (m) is the distance from your house to the pharmacy through the bank greater than the distance from the pharmacy to the school?",
        "answer_ko": "400",
        "answer_en": "400",
        "solution_abst_ko": "800 1 1000 [OP_MUL] 300 [OP_ADD] [OP_ADD] 1700 [OP_SUB]",
        "solution_abst_en": "800 1 1000 [OP_MUL] 300 [OP_ADD] [OP_ADD] 1700 [OP_SUB]",
        "solution_code_ko": "var_a = 800\nvar_b = 1\nvar_c = 1000\nvar_d = var_b * var_c\nvar_e = 300\nvar_f = var_d + var_e\nvar_g = var_a + var_f\nvar_h = 1700\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 800\nvar_b = 1\nvar_c = 1000\nvar_d = var_b * var_c\nvar_e = 300\nvar_f = var_d + var_e\nvar_g = var_a + var_f\nvar_h = 1700\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "6855": {
        "category": "Correspondence",
        "question_ko": "두 자연수 A, B가 있습니다. A를 B로 나누었을 때 몫이 9이고, 나머지가 13이었다면, A를 9로 나누었을 때의 나머지는 얼마입니까?",
        "question_en": "There are two natural numbers A and B. If the quotient of A divided by B is 9 and the remainder is 13, what is the remainder when A is divided by 9?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "13 9 [OP_MOD]",
        "solution_abst_en": "13 9 [OP_MOD]",
        "solution_code_ko": "var_a = 13\nvar_b = 9\nvar_c = var_a % var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 13\nvar_b = 9\nvar_c = var_a % var_b\nprint(int(var_c))"
    },
    "6856": {
        "category": "Arithmetic calculation",
        "question_ko": "10원짜리, 50원짜리, 100원짜리 동전이 모두 12개 있습니다. 총 금액을 조사하였더니 500원이었습니다. 10원짜리와 50원짜리의 개수는 같다고 할 때, 100원짜리 동전의 개수는 몇 개입니까?",
        "question_en": "There are a total 12 of 10-won, 50-won, and 100-won coins. I checked the total amount and it was 500 won. If the number of 10-won and 50-won coins is the same, how many 100-won coins are there?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "12 500 100 12 [OP_MUL] [OP_SUB] 10 50 [OP_ADD] 100 2 [OP_MUL] [OP_SUB] [OP_DIV] 2 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "12 500 100 12 [OP_MUL] [OP_SUB] 10 50 [OP_ADD] 100 2 [OP_MUL] [OP_SUB] [OP_DIV] 2 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 12\nvar_b = 500\nvar_c = 100\nvar_d = 12\nvar_e = var_c * var_d\nvar_f = var_b - var_e\nvar_g = 10\nvar_h = 50\nvar_i = var_g + var_h\nvar_j = 100\nvar_k = 2\nvar_l = var_j * var_k\nvar_m = var_i - var_l\nvar_n = var_f / var_m\nvar_o = 2\nvar_p = var_n * var_o\nvar_q = var_a - var_p\nprint(int(var_q))",
        "solution_code_en": "var_a = 12\nvar_b = 500\nvar_c = 100\nvar_d = 12\nvar_e = var_c * var_d\nvar_f = var_b - var_e\nvar_g = 10\nvar_h = 50\nvar_i = var_g + var_h\nvar_j = 100\nvar_k = 2\nvar_l = var_j * var_k\nvar_m = var_i - var_l\nvar_n = var_f / var_m\nvar_o = 2\nvar_p = var_n * var_o\nvar_q = var_a - var_p\nprint(int(var_q))"
    },
    "6857": {
        "category": "Geometry",
        "question_ko": "넓이가 324제곱미터(㎡)인 정사각형의 둘레는 몇 미터(m)인가요?",
        "question_en": "What is the circumference of a square with an area of 324 square meters (m2) in meters (m)?",
        "answer_ko": "72",
        "answer_en": "72",
        "solution_abst_ko": "324 1/2 [OP_POW] 4 [OP_MUL]",
        "solution_abst_en": "324 1/2 [OP_POW] 4 [OP_MUL]",
        "solution_code_ko": "var_a = 324\nvar_b = 0.5\nvar_c = var_a ** var_b\nvar_d = 4\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 324\nvar_b = 0.5\nvar_c = var_a ** var_b\nvar_d = 4\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "6858": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 3으로 나누기 전 1.4를 더해주었습니다. 이 결과에 0.7을 빼고 9를 곱했더니 5.4가 되었다면 어떤 수는 얼마입니까?",
        "question_en": "We add 1.4 to a number before dividing it by 3. If you subtract 0.7 from this result and multiply it by 9, and get 5.4. What is the number?",
        "answer_ko": "2.50",
        "answer_en": "2.5",
        "solution_abst_ko": "5.4 9 [OP_DIV] 0.7 [OP_ADD] 3 [OP_MUL] 1.4 [OP_SUB]",
        "solution_abst_en": "5.4 9 [OP_DIV] 0.7 [OP_ADD] 3 [OP_MUL] 1.4 [OP_SUB]",
        "solution_code_ko": "var_a = 5.4\nvar_b = 9\nvar_c = var_a / var_b\nvar_d = 0.7\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e * var_f\nvar_h = 1.4\nvar_i = var_g - var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 5.4\nvar_b = 9\nvar_c = var_a / var_b\nvar_d = 0.7\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e * var_f\nvar_h = 1.4\nvar_i = var_g - var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "6859": {
        "category": "Arithmetic calculation",
        "question_ko": "목욕탕에서 손님들을 위해 물을 10리터(L)까지 채울 수 있는 욕조에 물을 가득 받아두었습니다. 3명의 손님이 이 욕조에서 1리터(L) 500밀리리터(㎖)의 물을 덜어 사용하였고, 1명의 손님이 1리터(L) 750밀리리터(㎖)의 물을 사용하였습니다. 남은 손님들이 물을 1리터(L) 250밀리리터(㎖)씩 사용한다면 몇 명까지 물을 사용할 수 있습니까?",
        "question_en": "In the bathhouse, a bathtub that can be filled with water up to 10 liters (L) is filled with water for the guests. 3 guests used 1 liter (L) and 500 milliliters (㎖) of water from this bathtub, and 1 guest used 1 liter (L) and 750 milliliters (㎖) of water. If the remaining guests each use 1 liter (L) and 250 milliliters (㎖) of water, how many people can take shower?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "10 1000 [OP_MUL] 1 1000 [OP_MUL] 500 [OP_ADD] 3 [OP_MUL] [OP_SUB] 1 1000 [OP_MUL] 750 [OP_ADD] [OP_SUB] 1 1000 [OP_MUL] 250 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "10 1000 [OP_MUL] 1 1000 [OP_MUL] 500 [OP_ADD] 3 [OP_MUL] [OP_SUB] 1 1000 [OP_MUL] 750 [OP_ADD] [OP_SUB] 1 1000 [OP_MUL] 250 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = 500\nvar_h = var_f + var_g\nvar_i = 3\nvar_j = var_h * var_i\nvar_k = var_c - var_j\nvar_l = 1\nvar_m = 1000\nvar_n = var_l * var_m\nvar_o = 750\nvar_p = var_n + var_o\nvar_q = var_k - var_p\nvar_r = 1\nvar_s = 1000\nvar_t = var_r * var_s\nvar_u = 250\nvar_v = var_t + var_u\nvar_w = var_q / var_v\nprint(int(var_w))",
        "solution_code_en": "var_a = 10\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = 500\nvar_h = var_f + var_g\nvar_i = 3\nvar_j = var_h * var_i\nvar_k = var_c - var_j\nvar_l = 1\nvar_m = 1000\nvar_n = var_l * var_m\nvar_o = 750\nvar_p = var_n + var_o\nvar_q = var_k - var_p\nvar_r = 1\nvar_s = 1000\nvar_t = var_r * var_s\nvar_u = 250\nvar_v = var_t + var_u\nvar_w = var_q / var_v\nprint(int(var_w))"
    },
    "6860": {
        "category": "Arithmetic calculation",
        "question_ko": "똑같은 연필 14 자루가 들어 있는 필통의 무게는 11.14킬로그램(㎏) 입니다. 빈 필통의 무게가 0.5킬로그램(㎏) 이라면 연필 한 자루의 무게는 몇 킬로그램(㎏)입니까?",
        "question_en": "Given that a pencil case with 14 identical pencils weighs 11.14 kilograms (kg). When the empty pencil case weighs 0.5 kilograms (kg), how many kilograms (kg) does one pencil weigh?",
        "answer_ko": "0.76",
        "answer_en": "0.76",
        "solution_abst_ko": "11.14 0.5 [OP_SUB] 14 [OP_DIV]",
        "solution_abst_en": "11.14 0.5 [OP_SUB] 14 [OP_DIV]",
        "solution_code_ko": "var_a = 11.14\nvar_b = 0.5\nvar_c = var_a - var_b\nvar_d = 14\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 11.14\nvar_b = 0.5\nvar_c = var_a - var_b\nvar_d = 14\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "6861": {
        "category": "Comparison",
        "question_ko": "민영, 유정, 은지가 각자 구슬을 가지고 있습니다. 민영이는 4개, 유정이는 2개 가지고 있고, 민영이는 은지보다 구슬을 1개 더 적게 가지고 있습니다. 가장 많은 구슬을 가지고 있는 사람은 누구입니까?",
        "question_en": "Minyoung, Yujeong, and Eunji each have marbles. Minyoung has 4 marbles, Yujeong has 2, and Minyoung has 1 less marble than Eunji. Who has the largest number of marbles?",
        "answer_ko": "은지",
        "answer_en": "Eunji",
        "solution_abst_ko": "[OP_LIST_SOL] 민영 유정 은지 [OP_LIST_EOL] [OP_LIST_SOL] 4 2 4 1 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Minyoung Yujeong Eunji [OP_LIST_EOL] [OP_LIST_SOL] 4 2 4 1 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '민영'\nvar_b = '유정'\nvar_c = '은지'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 2\nvar_f = 4\nvar_g = 1\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Minyoung'\nvar_b = 'Yujeong'\nvar_c = 'Eunji'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 2\nvar_f = 4\nvar_g = 1\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "6862": {
        "category": "Arithmetic calculation",
        "question_ko": "태형이의 삼촌은 태형이보다 17살 더 많습니다. 4년 후 삼촌과 태형이의 나이를 합하면 43이 됩니다. 올해 태형이는 몇 살입니까?",
        "question_en": "Taehyung is 17 years younger than Taehyung's uncle. Four years later, the sum of the ages of uncle and Taehyung is 43. How old is Taehyung this year?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "43 4 2 [OP_MUL] [OP_SUB] 17 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "43 4 2 [OP_MUL] [OP_SUB] 17 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 43\nvar_b = 4\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 17\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 43\nvar_b = 4\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 17\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "6863": {
        "category": "Comparison",
        "question_ko": "0.1, 0.8, 1/2, 0.9의 숫자가 있다. 이 중 0.3보다 작거나 같은 숫자들의 합을 구하시오.",
        "question_en": "There are numbers 0.1, 0.8, 1/2, and 0.9. Find the sum of all numbers less than or equal to 0.3.",
        "answer_ko": "0.1",
        "answer_en": "0.1",
        "solution_abst_ko": "[OP_LIST_SOL] 0.1 0.8 1/2 0.9 [OP_LIST_EOL] 0.3 [OP_LIST_LESS_EQUAL] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0.1 0.8 1/2 0.9 [OP_LIST_EOL] 0.3 [OP_LIST_LESS_EQUAL] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0.1\nvar_b = 0.8\nvar_c = 0.5\nvar_d = 0.9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.3\nlist_b = []\nfor i in list_a:\n    if i <= var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint('{:.2f}'.format(round(var_f+1e-10,2)))",
        "solution_code_en": "var_a = 0.1\nvar_b = 0.8\nvar_c = 0.5\nvar_d = 0.9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.3\nlist_b = []\nfor i in list_a:\n    if i <= var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint('{:.2f}'.format(round(var_f+1e-10,2)))"
    },
    "6864": {
        "category": "Possibility",
        "question_ko": "면접자 5명이 있다. 이 중 3명을 골라 합격시키려고 할 때, 가능한 상황은 몇 가지인가?",
        "question_en": "There are 5 interviewers. How many possible situations are there if you choose 3 of them to pass?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "5 3 [OP_COMB]",
        "solution_abst_en": "5 3 [OP_COMB]",
        "solution_code_ko": "var_a = 5\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))"
    },
    "6865": {
        "category": "Correspondence",
        "question_ko": "193은 어떤 수와 71을 더한 값이다. 어떤 수에서 108을 빼면 얼마가 되는가?",
        "question_en": "193 is a result of a particular number plus 71. What will the result be when you subtract 108 from that particular number?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "193 71 [OP_SUB] 108 [OP_SUB]",
        "solution_abst_en": "193 71 [OP_SUB] 108 [OP_SUB]",
        "solution_code_ko": "var_a = 193\nvar_b = 71\nvar_c = var_a - var_b\nvar_d = 108\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 193\nvar_b = 71\nvar_c = var_a - var_b\nvar_d = 108\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "6866": {
        "category": "Arithmetic calculation",
        "question_ko": "네 자리 수 중 3과 5의 공배수 중 가장 큰 수는?",
        "question_en": "Find the largest 4-digit number that is a common multiple of 3 and 5.",
        "answer_ko": "9990",
        "answer_en": "9990",
        "solution_abst_ko": "1000 9999 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_abst_en": "1000 9999 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[-var_f]\nprint(int(var_g))",
        "solution_code_en": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[-var_f]\nprint(int(var_g))"
    },
    "6867": {
        "category": "Correspondence",
        "question_ko": "A4+B82=216입니다. A는 얼마인가요?",
        "question_en": "A4+B82=216. What number is A, where A is one-digit number?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "A4+B82=216 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A4+B82=216 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A4+B82=216'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A4+B82=216'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "6868": {
        "category": "Possibility",
        "question_ko": "다섯 개의 수 5, 0, 1, 8, 7 중에서 서로 다른 4개의 수를 사용하여 만들 수 있는 네 자리 수가 있습니다. 이 수가 3번째로 작은 수라면, 이 수는 무엇입니까?",
        "question_en": "There is a four-digit number that can be formed using four different numbers from the five numbers 5, 0, 1, 8, and 7. If this number is the 3rd smallest number, what is this number?",
        "answer_ko": "1075",
        "answer_en": "1075",
        "solution_abst_ko": "[OP_LIST_SOL] 5 0 1 8 7 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 3 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 5 0 1 8 7 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 3 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 5\nvar_b = 0\nvar_c = 1\nvar_d = 8\nvar_e = 7\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nprint(int(var_h))",
        "solution_code_en": "var_a = 5\nvar_b = 0\nvar_c = 1\nvar_d = 8\nvar_e = 7\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nprint(int(var_h))"
    },
    "6869": {
        "category": "Possibility",
        "question_ko": "A, B, C 세 사람을 한 줄로 세우는 경우의 수를 구하시오.",
        "question_en": "Find the number of ways to put three people A, B, and C in a line.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = len(list_a)\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nprint(int(var_f))",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = len(list_a)\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nprint(int(var_f))"
    },
    "6870": {
        "category": "Geometry",
        "question_ko": "정사각형 모양의 시디 케이스의 둘레는 60센티미터(㎝)입니다. 시디 케이스의 한 변의 길이를 구하시오.",
        "question_en": "The circumference of a square CD case is 60 centimeters (cm). Find the length of one side of the CD case.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "60 4 [OP_DIV]",
        "solution_abst_en": "60 4 [OP_DIV]",
        "solution_code_ko": "var_a = 60\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 60\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "6871": {
        "category": "Possibility",
        "question_ko": "공이 3개 들어 있는 상자 2개를 정국이는 가지고 있습니다. 정국이가 가지고 있는 전체 공의 개수는?",
        "question_en": "Jungkook has 2 boxes with 3 balls in each. How many balls does Jungkook have?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "3 2 [OP_MUL]",
        "solution_abst_en": "3 2 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "6872": {
        "category": "Arithmetic calculation",
        "question_ko": "식탁에 주스가 3컵, 우유가 4컵 있습니다. 식탁에 있는 컵은 총 몇 컵인가요?",
        "question_en": "There are 3 cups of juice and 4 cups of milk on the table. How many cups are on the table in total?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "3 4 [OP_ADD]",
        "solution_abst_en": "3 4 [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 4\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 4\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "6873": {
        "category": "Possibility",
        "question_ko": "서로 다른 숫자 2개를 4, 5, 6, 7, 8 중에서 뽑아 만들 수 있는 두 자리 수는 총 몇 개인지 구하시오.",
        "question_en": "How many two-digit numbers can be formed by choosing two different numbers from 4, 5, 6, 7, or 8?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "[OP_LIST_SOL] 4 5 6 7 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 4 5 6 7 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 4\nvar_b = 5\nvar_c = 6\nvar_d = 7\nvar_e = 8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 5\nvar_c = 6\nvar_d = 7\nvar_e = 8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "6874": {
        "category": "Correspondence",
        "question_ko": "혜지는 리본이 6미터(m) 30센티미터(㎝)만큼 있다. 이 중 3미터(m) 7센티미터(㎝)는 미술시간에 사용하였고, 84센티미터(㎝) 만큼은 친구에게 주었다. 남은 리본의 길이는 몇 미터(m)인지 구하시오.",
        "question_en": "Hyeji has a ribbon of 6 meters (m) and 30 centimeters (cm). Of these, 3 meters (m) and 7 centimeters (cm) were used in art class, and 84 centimeters (cm) were given to a friend. Find the length of the remaining ribbon in meters (m).",
        "answer_ko": "239",
        "answer_en": "239",
        "solution_abst_ko": "6 100 [OP_MUL] 30 [OP_ADD] 84 [OP_SUB] 3 100 [OP_MUL] 7 [OP_ADD] [OP_SUB]",
        "solution_abst_en": "6 100 [OP_MUL] 30 [OP_ADD] 84 [OP_SUB] 3 100 [OP_MUL] 7 [OP_ADD] [OP_SUB]",
        "solution_code_ko": "var_a = 6\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 30\nvar_e = var_c + var_d\nvar_f = 84\nvar_g = var_e - var_f\nvar_h = 3\nvar_i = 100\nvar_j = var_h * var_i\nvar_k = 7\nvar_l = var_j + var_k\nvar_m = var_g - var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 6\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 30\nvar_e = var_c + var_d\nvar_f = 84\nvar_g = var_e - var_f\nvar_h = 3\nvar_i = 100\nvar_j = var_h * var_i\nvar_k = 7\nvar_l = var_j + var_k\nvar_m = var_g - var_l\nprint(int(var_m))"
    },
    "6875": {
        "category": "Possibility",
        "question_ko": "판매하고 있는 과일이 4종류 입니다. 3가지만 골라서 산다면, 조합할 수 있는 경우는 모두 몇 가지입니까?",
        "question_en": "There are 4 types of fruit on sale. If you could only choose 3 to buy, how many combinations could there be?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "4 3 [OP_COMB]",
        "solution_abst_en": "4 3 [OP_COMB]",
        "solution_code_ko": "var_a = 4\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))"
    },
    "6876": {
        "category": "Possibility",
        "question_ko": "1, 3, 5, 7, 9 다섯 장의 숫자카드가 있다. 이 카드를 사용하여 만들 수 있는 3자리 자연수 중 500초과인 수의 평균은 얼마인지 구하시오. (단, 카드는 중복사용 가능하다.)",
        "question_en": "There are five number cards 1, 3, 5, 7, and 9. What is the average of the 3-digit natural numbers that can be made using this card that are greater than 500? (However, the card can be used repeatedly.)",
        "answer_ko": "755",
        "answer_en": "755",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 5 7 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 500 [OP_LIST_MORE] [OP_LIST_MEAN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 5 7 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 500 [OP_LIST_MORE] [OP_LIST_MEAN]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 5\nvar_d = 7\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 500\nlist_c = []\nfor i in list_b:\n    if i > var_g:\n        list_c.append(i)\nlist_c = [float(i) for i in list_c]\nvar_h = sum(list_c)/len(list_c)\nprint(int(var_h))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 5\nvar_d = 7\nvar_e = 9\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 500\nlist_c = []\nfor i in list_b:\n    if i > var_g:\n        list_c.append(i)\nlist_c = [float(i) for i in list_c]\nvar_h = sum(list_c)/len(list_c)\nprint(int(var_h))"
    },
    "6877": {
        "category": "Comparison",
        "question_ko": "동균은 정국보다 키가 크고, 동욱은 정국보다 키가 크다. 동국과 동균의 키를 비교했을 때, 동국이 키가 작다면 누구의 키가 가장 큽니까?",
        "question_en": "Dongkyun is taller than Jungkook, and Dongwook is taller than Jungkook. Comparing the heights of Dongwook and Dongkyun, if Dongwook is shorter, who is the tallest?",
        "answer_ko": "동균",
        "answer_en": "Dongkyun",
        "solution_abst_ko": "[OP_LIST_SOL] 동균 정국 동욱 [OP_LIST_EOL] [OP_LIST_SOL] 동균 정국 > 동욱 정국 > 동욱 동균 < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Dongkyun Jungkook Dongwook [OP_LIST_EOL] [OP_LIST_SOL] Dongkyun Jungkook > Dongwook Jungkook > Dongwook Dongkyun < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '동균'\nvar_b = '정국'\nvar_c = '동욱'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '동균'\nvar_e = '정국'\nvar_f = '>'\nvar_g = '동욱'\nvar_h = '정국'\nvar_i = '>'\nvar_j = '동욱'\nvar_k = '동균'\nvar_l = '<'\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_m = 1\nvar_n = list_c[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'Dongkyun'\nvar_b = 'Jungkook'\nvar_c = 'Dongwook'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'Dongkyun'\nvar_e = 'Jungkook'\nvar_f = '>'\nvar_g = 'Dongwook'\nvar_h = 'Jungkook'\nvar_i = '>'\nvar_j = 'Dongwook'\nvar_k = 'Dongkyun'\nvar_l = '<'\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_m = 1\nvar_n = list_c[var_m-1]\nprint(var_n)"
    },
    "6878": {
        "category": "Arithmetic calculation",
        "question_ko": "음료수 16리터(L)를 병 6개에 똑같이 나누어 담았습니다. 병 1개에 담긴 음료수를 친구들과 4/15리터(L)씩 나누어 먹는다고 할때 몇 명이 먹을 수 있나요?",
        "question_en": "16 liters (L) of beverage was equally divided into 6 bottles. How many people can drink the beverage in one bottle if you share it with your friends by 4/15 liters (L)?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "16 6 [OP_DIV] 4/15 [OP_DIV]",
        "solution_abst_en": "16 6 [OP_DIV] 4/15 [OP_DIV]",
        "solution_code_ko": "var_a = 16\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.26666666666666666\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 16\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.26666666666666666\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "6879": {
        "category": "Possibility",
        "question_ko": "2, 4, 5 총 3장의 수 카드 중 2장을 사용하여 두 자리 수를 만들려고 합니다. 만들 수 있는 수 중에 2와 3으로 동시에 나누어 떨어지는 수는 모두 몇 개인가요?",
        "question_en": "We are going to use 2 of our 3 number cards 2, 4, 5 to create a two-digit number. How many numbers can be made that are both divisible by 2 and 3?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 2 4 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] [OP_SET_INTERSECT] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 2 4 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] [OP_SET_INTERSECT] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 3\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nlist_e = list(set(list_c) & set(list_d))\nvar_g = len(list_e)\nprint(int(var_g))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 3\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nlist_e = list(set(list_c) & set(list_d))\nvar_g = len(list_e)\nprint(int(var_g))"
    },
    "6880": {
        "category": "Comparison",
        "question_ko": "학교에서 윤기네 집까지는 1.6킬로미터(㎞)이고, 민영이네 집까지는 2.6킬로미터(㎞)입니다. 학교에서 집까지의 거리가 더 먼 친구는 누구입니까?",
        "question_en": "It is 1.6 kilometers (km) from school to Yoongi's house and 2.6 kilometers (km) to Minyoung's house. Whose home is further from school?",
        "answer_ko": "민영",
        "answer_en": "Minyoung",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 민영 [OP_LIST_EOL] [OP_LIST_SOL] 1.6 2.6 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Minyoung [OP_LIST_EOL] [OP_LIST_SOL] 1.6 2.6 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '민영'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.6\nvar_d = 2.6\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Minyoung'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.6\nvar_d = 2.6\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "6881": {
        "category": "Arithmetic calculation",
        "question_ko": "0, 1, 3, 5, 7, 9 여섯 장의 숫자 카드를 한 번씩 사용하여 만들 수 있는 가장 작은 여섯 자리 수를 올림하여 천의 자리까지 나타내어 보시오.",
        "question_en": "When there is six number cards 0, 1, 3, 5, 7, and 9, write down the smallest six-digit number you can make rounding up to the thousandth place.",
        "answer_ko": "104000",
        "answer_en": "104000",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 3 5 7 9 [OP_LIST_EOL] 6 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 4 [OP_CEIL]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 3 5 7 9 [OP_LIST_EOL] 6 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 4 [OP_CEIL]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 3\nvar_d = 5\nvar_e = 7\nvar_f = 9\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 6\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = 4\nvar_k=int(((var_i+9*10**(var_j-2))//(10**(var_j-1)))*10**(var_j-1))\n\nprint(int(var_k))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 3\nvar_d = 5\nvar_e = 7\nvar_f = 9\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 6\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_g))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_h = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = 4\nvar_k=int(((var_i+9*10**(var_j-2))//(10**(var_j-1)))*10**(var_j-1))\n\nprint(int(var_k))"
    },
    "6882": {
        "category": "Geometry",
        "question_ko": "밑변이 25센티미터(㎝)이고 높이가 16센티미터(㎝)인 삼각형의 넓이를 구하시오.",
        "question_en": "Find the area of a triangle with a base of 25 centimeters (cm) and a height of 16 centimeters (cm).",
        "answer_ko": "200",
        "answer_en": "200",
        "solution_abst_ko": "25 16 [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "25 16 [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 25\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 25\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "6883": {
        "category": "Arithmetic calculation",
        "question_ko": "세 자리 수 중 6, 5, 8, 9의 공배수 중 가장 작은 수는 무엇입니까?",
        "question_en": "Which three-digit number is the smallest common multiple of 6, 5, 8, and 9?",
        "answer_ko": "360",
        "answer_en": "360",
        "solution_abst_ko": "100 999 1 [OP_LIST_ARANGE] 6 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "100 999 1 [OP_LIST_ARANGE] 6 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = 1\nlist_f=list_e.copy()\nlist_f.sort()\nvar_i = list_f[var_h-1]\nprint(int(var_i))",
        "solution_code_en": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = 1\nlist_f=list_e.copy()\nlist_f.sort()\nvar_i = list_f[var_h-1]\nprint(int(var_i))"
    },
    "6884": {
        "category": "Arithmetic calculation",
        "question_ko": "집까지의 거리가 30미터(m)인 자동차는 시속 1미터(m)로 달리고 집까지의 거리가 20미터(m)인 자동차는 시속 0.5미터(m)로 달립니다. 두 자동차가 만났을 시 집까지의 거리를 구하여라",
        "question_en": "A car that is 30 meters (m) away from the house travels at 1 meter (m) per hour, and a car 20 meters (m) from the house travels at 0.5 meters (m) per hour. Find the distance to the house from the cars when the two cars meet.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "30 30 20 [OP_SUB] 1 0.5 [OP_SUB] [OP_DIV] [OP_SUB]",
        "solution_abst_en": "30 30 20 [OP_SUB] 1 0.5 [OP_SUB] [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 30\nvar_b = 30\nvar_c = 20\nvar_d = var_b - var_c\nvar_e = 1\nvar_f = 0.5\nvar_g = var_e - var_f\nvar_h = var_d / var_g\nvar_i = var_a - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 30\nvar_b = 30\nvar_c = 20\nvar_d = var_b - var_c\nvar_e = 1\nvar_f = 0.5\nvar_g = var_e - var_f\nvar_h = var_d / var_g\nvar_i = var_a - var_h\nprint(int(var_i))"
    },
    "6885": {
        "category": "Comparison",
        "question_ko": "결승선에 태형, 민주, 상민, 윤정, 유정이 차례로 들어갔습니다. 1등으로 들어온 사람은 누구입니까?",
        "question_en": "Taehyung, Minjoo, Sangmin, Yoonjung, and Yoojung crossed the finish line in order. Who came in first?",
        "answer_ko": "태형",
        "answer_en": "Taehyung",
        "solution_abst_ko": "[OP_LIST_SOL] 태형 민주 상민 윤정 유정 [OP_LIST_EOL] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Taehyung Minju Sangmin Yoonjeong Yoojeong [OP_LIST_EOL] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '태형'\nvar_b = '민주'\nvar_c = '상민'\nvar_d = '윤정'\nvar_e = '유정'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nvar_g = list_a[var_f-1]\nprint(var_g)",
        "solution_code_en": "var_a = 'Taehyung'\nvar_b = 'Minju'\nvar_c = 'Sangmin'\nvar_d = 'Yoonjeong'\nvar_e = 'Yoojeong'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nvar_g = list_a[var_f-1]\nprint(var_g)"
    },
    "6886": {
        "category": "Comparison",
        "question_ko": "빨간색 자동차는 왼쪽에서 19번째 열, 오른쪽에서 16번째 열, 앞에서 14번째 줄, 뒤에서 11번째 줄에 있습니다. 각 줄마다 있는 자동차의 수가 같다고 할 때, 자동차는 모두 몇 대입니까?",
        "question_en": "The red car is in the 19th row from the left, 16th row from the right, 14th row from the front and 11th row from the back. If the number of cars in each row is the same, how many cars are there in all?",
        "answer_ko": "816",
        "answer_en": "816",
        "solution_abst_ko": "19 16 [OP_ADD] 1 [OP_SUB] 14 11 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "19 16 [OP_ADD] 1 [OP_SUB] 14 11 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 19\nvar_b = 16\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 14\nvar_g = 11\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 19\nvar_b = 16\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 14\nvar_g = 11\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))"
    },
    "6887": {
        "category": "Arithmetic calculation",
        "question_ko": "3과 4로 나누어떨어지고 5로 나누면 나머지가 4인 네 자리 수를 찾으려고 합니다. 만들 수 있는 네 자리 수는 모두 몇 개입니까?",
        "question_en": "I'm trying to find a four-digit number that is divisible by 3 and 4 and has a remainder of 4 when divided by 5. How many four-digit numbers can you make?",
        "answer_ko": "150",
        "answer_en": "150",
        "solution_abst_ko": "1000 9999 1 [OP_LIST_ARANGE] 3 4 [OP_LCM] [OP_LIST_DIVISIBLE] 5 4 [OP_LIST_DIVIDE_AND_REMAIN] [OP_LIST_LEN]",
        "solution_abst_en": "1000 9999 1 [OP_LIST_ARANGE] 3 4 [OP_LCM] [OP_LIST_DIVISIBLE] 5 4 [OP_LIST_DIVIDE_AND_REMAIN] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nvar_e = 4\nvar_f = var_e * var_d / math.gcd(int(var_e), int(var_d))\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nvar_g = 5\nvar_h = 4\nlist_c = [] \nvar_g = int(var_g)\nvar_h = int(var_h)\nif var_h < 0:\n    var_h = var_h + var_g\nfor i in list_b:\n    i = int(i)\n    if i%var_g == var_h:\n        list_c.append(i)\nvar_i = len(list_c)\nprint(int(var_i))",
        "solution_code_en": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nvar_e = 4\nvar_f = var_e * var_d / math.gcd(int(var_e), int(var_d))\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nvar_g = 5\nvar_h = 4\nlist_c = [] \nvar_g = int(var_g)\nvar_h = int(var_h)\nif var_h < 0:\n    var_h = var_h + var_g\nfor i in list_b:\n    i = int(i)\n    if i%var_g == var_h:\n        list_c.append(i)\nvar_i = len(list_c)\nprint(int(var_i))"
    },
    "6888": {
        "category": "Comparison",
        "question_ko": "민영이는 줄넘기를 오늘 52번 했고, 어제는 오늘보다 19번 적게 했습니다. 유정이는 줄넘기를 오늘 18번 했고, 어제는 오늘보다 21번 더 많이 했습니다. 어제 줄넘기를 더 많이 한 사람은 누구입니까?",
        "question_en": "Minyoung jumped rope 52 times today, and yesterday she skipped 19 times less than today. Yoojung jumped rope 18 times today, and yesterday she skipped 21 times more than today. Who jumped more rope yesterday?",
        "answer_ko": "유정",
        "answer_en": "Yoojung",
        "solution_abst_ko": "[OP_LIST_SOL] 민영 유정 [OP_LIST_EOL] [OP_LIST_SOL] 52 19 [OP_SUB] 18 21 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Minyoung Yoojung [OP_LIST_EOL] [OP_LIST_SOL] 52 19 [OP_SUB] 18 21 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '민영'\nvar_b = '유정'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 52\nvar_d = 19\nvar_e = var_c - var_d\nvar_f = 18\nvar_g = 21\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Minyoung'\nvar_b = 'Yoojung'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 52\nvar_d = 19\nvar_e = var_c - var_d\nvar_f = 18\nvar_g = 21\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "6889": {
        "category": "Possibility",
        "question_ko": "숫자 카드 1, 3, 7, 8 중 2장을 뽑아 두 자리 자연수를 만들 때, 40 이하의 자연수의 개수를 구하시오.",
        "question_en": "When making a two-digit natural number by drawing two of the number cards 1, 3, 7, and 8, find the number of natural numbers less than 40.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 7 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 40 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 7 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 40 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 7\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 40\nlist_c = []\nfor i in list_b:\n    if i <= var_f:\n        list_c.append(i)\nvar_g = len(list_c)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 7\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 40\nlist_c = []\nfor i in list_b:\n    if i <= var_f:\n        list_c.append(i)\nvar_g = len(list_c)\nprint(int(var_g))"
    },
    "6890": {
        "category": "Comparison",
        "question_ko": "총 20명의 학생들이 달리기 경기를 하고 있습니다. 윤기보다 11명의 학생들이 결승점에 먼저 들어왔습니다. 윤기보다 늦게 들어오는 학생은 몇 명입니까?",
        "question_en": "A total of 20 students are running a race. 11 students reached the finish line before Yoongi. How many students came later than Yoongi?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "20 11 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "20 11 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "6891": {
        "category": "Correspondence",
        "question_ko": "식 632-A9B=41이 있습니다. A에 들어가야 하는 숫자를 구하시오",
        "question_en": "We have the expression 632-A9B=41. Find out the number that must go into A.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "632-A9B=41 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "632-A9B=41 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '632-A9B=41'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '632-A9B=41'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "6892": {
        "category": "Correspondence",
        "question_ko": "어떤 수는 69에서 5를 뺀 값의 약수이면서 또한 86에서 6을 뺀 값의 약수이다. 가능한 어떤 수 중 가장 큰 값을 구하여라.",
        "question_en": "Some numbers are divisors of 69 minus 5 and are also divisors of 86 minus 6. Find the largest of any possible number.",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "69 5 [OP_SUB] 86 6 [OP_SUB] [OP_GCD]",
        "solution_abst_en": "69 5 [OP_SUB] 86 6 [OP_SUB] [OP_GCD]",
        "solution_code_ko": "var_a = 69\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 86\nvar_e = 6\nvar_f = var_d - var_e\nvar_g = math.gcd(int(var_f), int(var_c))\nprint(int(var_g))",
        "solution_code_en": "var_a = 69\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 86\nvar_e = 6\nvar_f = var_d - var_e\nvar_g = math.gcd(int(var_f), int(var_c))\nprint(int(var_g))"
    },
    "6893": {
        "category": "Geometry",
        "question_ko": "반지름이 5센티미터(㎝)인 원판을 여러 개 쌓았더니 그 높이가 반지름보다 3센티미터(㎝) 더 길어졌다. 이 원기둥의 부피는 몇 세제곱센티미터(㎤)인가? 단, 원주율은 3.14로 계산한다.",
        "question_en": "When several disks with a radius of 5 centimeters (cm) were stacked, the height is 3 centimeters (cm) longer than the radius. What is the volume of this cylinder in cubic centimeters (cm3)? However, the ratio of the circumference of a circle to its diameter is calculated as 3.14.",
        "answer_ko": "628",
        "answer_en": "628",
        "solution_abst_ko": "5 5 [OP_MUL] 3.14 [OP_MUL] 5 3 [OP_ADD] [OP_MUL]",
        "solution_abst_en": "5 5 [OP_MUL] 3.14 [OP_MUL] 5 3 [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 3.14\nvar_e = var_c * var_d\nvar_f = 5\nvar_g = 3\nvar_h = var_f + var_g\nvar_i = var_e * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 5\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 3.14\nvar_e = var_c * var_d\nvar_f = 5\nvar_g = 3\nvar_h = var_f + var_g\nvar_i = var_e * var_h\nprint(int(var_i))"
    },
    "6894": {
        "category": "Geometry",
        "question_ko": "정십사각형의 모양의 테이블이 있다. 모든 모서리 길이의 합은 154센티미터(㎝)이다. 테이블의 한 모서리 길이는 얼마인가?",
        "question_en": "If there is a table in the shape of a regular tetradecagon, whose sum of all edge lengths is 154 centimeters (cm), what is the length of one corner of the table?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "154 14 [OP_DIV]",
        "solution_abst_en": "154 14 [OP_DIV]",
        "solution_code_ko": "var_a = 154\nvar_b = 14\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 154\nvar_b = 14\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "6895": {
        "category": "Geometry",
        "question_ko": "밑면이 같은 각기둥과 각뿔의 모서리의 합이 30이다. 각기둥의 면의 개수를 구하시오.",
        "question_en": "The sum of the edges of a prism and pyramid with the same base is 30. Find the number of faces of the prism.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "30 2 3 [OP_ADD] [OP_DIV] 2 [OP_ADD]",
        "solution_abst_en": "30 2 3 [OP_ADD] [OP_DIV] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 30\nvar_b = 2\nvar_c = 3\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 30\nvar_b = 2\nvar_c = 3\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "6896": {
        "category": "Geometry",
        "question_ko": "이십오각형의 한 꼭짓점에서 대각선을 그으려고 합니다. 몇 개의 대각선을 그을 수 있을까요?",
        "question_en": "I am trying to draw a diagonal from a vertex of an icosikaipentagon. How many diagonal lines can you draw?",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "25 3 [OP_SUB]",
        "solution_abst_en": "25 3 [OP_SUB]",
        "solution_code_ko": "var_a = 25\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 25\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "6897": {
        "category": "Arithmetic calculation",
        "question_ko": "상연이는 가지고 있던 돈의 1/4을 책을 사는 데 쓰고, 남은 돈의 2/3는 저금을 하였습니다. 지금 상연이가 2500원을 가지고 있다면 처음에 가지고 있던 돈은 얼마입니까?",
        "question_en": "Sang-yeon spent 1/4 of the money she had on buying books, and saved 2/3 of the remaining money. If Sang-yeon now has 2,500 won, how much money did she initially have?",
        "answer_ko": "10000",
        "answer_en": "10000",
        "solution_abst_ko": "2500 1 1/4 [OP_SUB] [OP_DIV] 1 2/3 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "2500 1 1/4 [OP_SUB] [OP_DIV] 1 2/3 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 2500\nvar_b = 1\nvar_c = 0.25\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 1\nvar_g = 0.6666666666666666\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 2500\nvar_b = 1\nvar_c = 0.25\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 1\nvar_g = 0.6666666666666666\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "6898": {
        "category": "Geometry",
        "question_ko": "반지름이 10센티미터(㎝)인 원 안에 가장 큰 마름모를 그린 다음, 마름모의 네 변의 한가운데를 모두 이어 작은 마름모를 그렸습니다. 작은 마름모의 넓이는 몇 ㎠입니까?",
        "question_en": "I drew the largest rhombus in a circle with a radius of 10 centimeters (cm) and then drew a smaller rhombus by connecting the middle of all four sides of the rhombus. What is the area of the small rhombus in cm2 (cm2)?",
        "answer_ko": "100",
        "answer_en": "100",
        "solution_abst_ko": "10 10 [OP_MUL]",
        "solution_abst_en": "10 10 [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 10\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 10\nvar_b = 10\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "6899": {
        "category": "Arithmetic calculation",
        "question_ko": "무와 당근이 모두 합해서 100개 있습니다. 무가 당근보다 24개 더 많다면 무는 몇 개 있습니까?",
        "question_en": "There are a total of 100 radishes and carrots. If there are 24 more radishes than carrots, how many radishes are there?",
        "answer_ko": "62",
        "answer_en": "62",
        "solution_abst_ko": "100 24 [OP_SUB] 2 [OP_FDIV] 24 [OP_ADD]",
        "solution_abst_en": "100 24 [OP_SUB] 2 [OP_FDIV] 24 [OP_ADD]",
        "solution_code_ko": "var_a = 100\nvar_b = 24\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c // var_d\nvar_f = 24\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 100\nvar_b = 24\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c // var_d\nvar_f = 24\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "6900": {
        "category": "Geometry",
        "question_ko": "40밀리리터(㎖)의 패인트 통 25개가 있다. 정육면체의 안에 페인트를 붓고 271밀리리터(㎖)가 남았다면 정육면체의 한 모서리는 몇 센티미터(㎝) 입니까?",
        "question_en": "You have 25 40-milliliter (ml) paint cans. If 271 milliliters (ml) of paint is left after pouring it into the cube, how many centimeters (cm) is one edge of the cube?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "40 25 [OP_MUL] 271 [OP_SUB] 1/3 [OP_POW]",
        "solution_abst_en": "40 25 [OP_MUL] 271 [OP_SUB] 1/3 [OP_POW]",
        "solution_code_ko": "var_a = 40\nvar_b = 25\nvar_c = var_a * var_b\nvar_d = 271\nvar_e = var_c - var_d\nvar_f = 0.3333333333333333\nvar_g = var_e ** var_f\nprint(int(eval('{:.2f}'.format(round(var_g+1e-10,2)))))",
        "solution_code_en": "var_a = 40\nvar_b = 25\nvar_c = var_a * var_b\nvar_d = 271\nvar_e = var_c - var_d\nvar_f = 0.3333333333333333\nvar_g = var_e ** var_f\nprint(int(eval('{:.2f}'.format(round(var_g+1e-10,2)))))"
    },
    "6901": {
        "category": "Correspondence",
        "question_ko": "수근이네 반 미술시간에 색종이 접기를 하게 되었다. 7명의 학생들에게 색종이를 나눠 주었더니 한 명당 12장씩 나눠가지고 5장이 남게 되었다. 이때 지각한 수근이가 들어와 8명에게 다시 색종이를 나눠 줘야한다. 이때 8명에게 색종이를 동일하게 나눠주고 남은 나머지가 몇 장일지 구하시오.",
        "question_en": "Su-geun's class is going to do origami in art class. After handing out colored papers to 7 students, each student had 12 pieces and 5 pieces were left over. Meanwhile, Su-geun came in late, so the colored papers should be redistributed to 8 people. Find out how many pieces would be left after equally handing the colored papers out to 8 students.",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "12 7 [OP_MUL] 5 [OP_ADD] 8 [OP_MOD]",
        "solution_abst_en": "12 7 [OP_MUL] 5 [OP_ADD] 8 [OP_MOD]",
        "solution_code_ko": "var_a = 12\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e % var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 12\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e % var_f\nprint(int(var_g))"
    },
    "6902": {
        "category": "Geometry",
        "question_ko": "넓이가 46제곱센티미터(㎠)인 삼각형의 높이가 10센티미터(㎝)라면, 밑면은 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "If the height of a triangle whose area is 46 square centimeters (cm2) is 10 centimeters (cm), how many centimeters (cm) is the base?",
        "answer_ko": "9.20",
        "answer_en": "9.2",
        "solution_abst_ko": "46 2 [OP_MUL] 10 [OP_DIV]",
        "solution_abst_en": "46 2 [OP_MUL] 10 [OP_DIV]",
        "solution_code_ko": "var_a = 46\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 10\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 46\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 10\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "6903": {
        "category": "Comparison",
        "question_ko": "버스를 타기 위해 30명의 학생이 줄을 서 있습니다. 윤기 앞에 20명의 학생이 있다면 윤기보다 늦게 버스에 타게 될 학생은 모두 몇 명일까요?",
        "question_en": "Thirty students are in line to catch the bus. If there are 20 students in front of Yoongi, how many students will get on the bus later than Yoongi?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "30 20 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "30 20 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 30\nvar_b = 20\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 30\nvar_b = 20\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "6904": {
        "category": "Geometry",
        "question_ko": "직각삼각형이 있습니다. 세 변의 길이가 각각 10 센티미터(㎝), 8 센티미터(㎝), 6 센티미터(㎝)일 때, 외접원의 반지름의 길이를 구하시오.",
        "question_en": "There is a right triangle. Find the length of the radius of the circumscribed circle when the lengths of the three sides of the triangle are 10 centimeters (cm), 8 centimeters (cm), and 6 centimeters (cm), respectively.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "10 2 [OP_DIV]",
        "solution_abst_en": "10 2 [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 10\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "6905": {
        "category": "Geometry",
        "question_ko": "두 대각선의 길이가 각각 9센티미터(㎝), 14센티미터(㎝)인 마름모 모양의 연이 있습니다. 이 연의 넓이는 얼마인지 구하시오.",
        "question_en": "There is a rhombic kite with two diagonals measuring 9 centimeters (cm) and 14 centimeters (cm), respectively. Find the area of this kite.",
        "answer_ko": "63",
        "answer_en": "63",
        "solution_abst_ko": "9 14 [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "9 14 [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 9\nvar_b = 14\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 14\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "6906": {
        "category": "Correspondence",
        "question_ko": "23에 어떤 수를 곱해야 하는데 잘못하여 23에서 어떤 수를 뺐더니 4가 되었습니다. 바르게 계산한 결과를 구하시오.",
        "question_en": "You need to multiply 23 by a certain number, but mistakenly subtracted a certain number from 23 and got 4. Find the result of the correct calculation.",
        "answer_ko": "437",
        "answer_en": "437",
        "solution_abst_ko": "23 23 4 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "23 23 4 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 23\nvar_b = 23\nvar_c = 4\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 23\nvar_b = 23\nvar_c = 4\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nprint(int(var_e))"
    },
    "6907": {
        "category": "Possibility",
        "question_ko": "4 장의 숫자 카드 1, 3, 4, 7 중 2 장을 뽑아 한 번씩만 사용하여 두 자리 수를 만들려고 합니다. 만들 수 있는 수 중에서 36 초과 45 이하인 수 중 가장 큰 수는 무엇입니까?",
        "question_en": "You want to create a two-digit number by drawing two of the four number cards 1, 3, 4, and 7 and using them only once. What is the largest number that can be made greater than 36 and less than or equal to 45?",
        "answer_ko": "43",
        "answer_en": "43",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 4 7 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 36 [OP_LIST_MORE] 45 [OP_LIST_LESS_EQUAL] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 4 7 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 36 [OP_LIST_MORE] 45 [OP_LIST_LESS_EQUAL] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 4\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 36\nlist_c = []\nfor i in list_b:\n    if i > var_f:\n        list_c.append(i)\nvar_g = 45\nlist_d = []\nfor i in list_c:\n    if i <= var_g:\n        list_d.append(i)\nvar_h = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_i = list_e[-var_h]\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 4\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 36\nlist_c = []\nfor i in list_b:\n    if i > var_f:\n        list_c.append(i)\nvar_g = 45\nlist_d = []\nfor i in list_c:\n    if i <= var_g:\n        list_d.append(i)\nvar_h = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_i = list_e[-var_h]\nprint(int(var_i))"
    },
    "6908": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 18로 나눈 값에서 29를 뺐더니 6이 되었습니다. 어떤 수를 구하시오.",
        "question_en": "When we divide a number by 18 and subtract 29, we get 6. Find the number.",
        "answer_ko": "630",
        "answer_en": "630",
        "solution_abst_ko": "6 29 [OP_ADD] 18 [OP_MUL]",
        "solution_abst_en": "6 29 [OP_ADD] 18 [OP_MUL]",
        "solution_code_ko": "var_a = 6\nvar_b = 29\nvar_c = var_a + var_b\nvar_d = 18\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 29\nvar_c = var_a + var_b\nvar_d = 18\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "6909": {
        "category": "Arithmetic calculation",
        "question_ko": "윤호는 1분에 90걸음을 걷습니다. 윤호의 한 걸음은 0.45미터(m)이고 13분을 걸었습니다. 윤호가 걸은 거리는 모두 몇 미터(m)인가요?",
        "question_en": "Yunho walks 90 steps a minute. If he takes 0.45 meters (m) in one step, and he walked for 13 minutes, how many meters (m) did Yunho walk?",
        "answer_ko": "526.50",
        "answer_en": "526.5",
        "solution_abst_ko": "0.45 90 [OP_MUL] 13 [OP_MUL]",
        "solution_abst_en": "0.45 90 [OP_MUL] 13 [OP_MUL]",
        "solution_code_ko": "var_a = 0.45\nvar_b = 90\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.45\nvar_b = 90\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "6910": {
        "category": "Possibility",
        "question_ko": "서희네 집에서 학교까지 가는 버스 노선은 3개, 지하철 노선은 2개일 때 버스로 가는 경우의 수를 구하시오.",
        "question_en": "If there are 3 bus routes and 2 subway routes going from Seohee's house to school, find the number of ways to go by bus.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 3 2 [OP_LIST_EOL] [OP_LIST_SOL] 버스 지하철 [OP_LIST_EOL] 버스 [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] 3 2 [OP_LIST_EOL] [OP_LIST_SOL] 버스 지하철 [OP_LIST_EOL] 버스 [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = '버스'\nvar_d = '지하철'\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = '버스'\nvar_f = list_b.index(var_e)+1\nvar_g = list_a[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = '버스'\nvar_d = '지하철'\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = '버스'\nvar_f = list_b.index(var_e)+1\nvar_g = list_a[var_f-1]\nprint(int(var_g))"
    },
    "6911": {
        "category": "Correspondence",
        "question_ko": "360÷(A×A×A/B)=5의 식을 만족하는 가장 작은 자연수 A, B의 합을 구하여라.",
        "question_en": "Find the sum of the smallest natural numbers A and B that satisfy the equation 360÷(A×A×A/B)=5.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "360÷(A×A×A/B)=5 A [OP_NUM_UNK_SOLVER] 1 [OP_LIST_MIN] 360÷(A×A×A/B)=5 B [OP_NUM_UNK_SOLVER] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "360÷(A×A×A/B)=5 A [OP_NUM_UNK_SOLVER] 1 [OP_LIST_MIN] 360÷(A×A×A/B)=5 B [OP_NUM_UNK_SOLVER] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = '360÷(A×A×A/B)=5'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[var_c-1]\nvar_e = '360÷(A×A×A/B)=5'\nvar_f = 'B'\nans_dict = dict()\nvar_e = var_e.replace('×','*')\nvar_e = var_e.replace('x','*')\nvar_e = var_e.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_e):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_e\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k].append(int(c[i]))\nlist_c = list(set(ans_dict[var_f]))\nvar_g = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_d + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = '360÷(A×A×A/B)=5'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[var_c-1]\nvar_e = '360÷(A×A×A/B)=5'\nvar_f = 'B'\nans_dict = dict()\nvar_e = var_e.replace('×','*')\nvar_e = var_e.replace('x','*')\nvar_e = var_e.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_e):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_e\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k].append(int(c[i]))\nlist_c = list(set(ans_dict[var_f]))\nvar_g = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_d + var_h\nprint(int(var_i))"
    },
    "6912": {
        "category": "Comparison",
        "question_ko": "백의 자리 숫자가 7, 일의 자리 숫자가 6인 세 자리 수 중에서 756보다 작은 수는 모두 몇 개입니까?",
        "question_en": "How many three-digit numbers with 7 in the hundreds digit and 6 in the units digit are less than 756?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "[OP_LIST_SOL] 7 A 6 [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 756 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 7 A 6 [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 756 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 7\nvar_b = 'A'\nvar_c = 6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nans_dict = dict()\nvar_d = str(var_d)\nlist_b = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_d) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_b.append(new_elem)\nvar_e = 756\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 7\nvar_b = 'A'\nvar_c = 6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nans_dict = dict()\nvar_d = str(var_d)\nlist_b = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_d) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_b.append(new_elem)\nvar_e = 756\nlist_c = []\nfor i in list_b:\n    if i < var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "6913": {
        "category": "Arithmetic calculation",
        "question_ko": "3의 배수 중 가장 작은 네 자리 수는?",
        "question_en": "What is the smallest 4-digit multiple of 3?",
        "answer_ko": "1002",
        "answer_en": "1002",
        "solution_abst_ko": "1000 9999 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "1000 9999 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nprint(int(var_f))",
        "solution_code_en": "var_a = 1000\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nprint(int(var_f))"
    },
    "6914": {
        "category": "Comparison",
        "question_ko": "발표가 진행되는 동안 학생들은 차례대로 발표를 합니다. 여섯 번째는 은정, 7명의 학생은 은정이 뒤에 발표합니다. 총 몇 명의 학생이 발표합니까?",
        "question_en": "Students give their presentations in sequence. The 6th is Eunjeong, and the 7 students are presented after Eunjeong. How many students give presentations in total?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "6 7 [OP_ADD]",
        "solution_abst_en": "6 7 [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "6915": {
        "category": "Arithmetic calculation",
        "question_ko": "시경이네 모둠 6명이 가지고 있는 사탕의 개수는 각각 16, 22, 30, 26, 18, 20개일 때, 시경이네 모둠 학생이 가진 사탕 개수의 평균은 얼마인지 구하시오.",
        "question_en": "If the number of candies each of the six students in the Sikyung group is 16, 22, 30, 26, 18, and 20, what is the average number of candies each student in the Sikyung group has?",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "[OP_LIST_SOL] 16 22 30 26 18 20 [OP_LIST_EOL] [OP_LIST_MEAN]",
        "solution_abst_en": "[OP_LIST_SOL] 16 22 30 26 18 20 [OP_LIST_EOL] [OP_LIST_MEAN]",
        "solution_code_ko": "var_a = 16\nvar_b = 22\nvar_c = 30\nvar_d = 26\nvar_e = 18\nvar_f = 20\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_g = sum(list_a)/len(list_a)\nprint(int(var_g))",
        "solution_code_en": "var_a = 16\nvar_b = 22\nvar_c = 30\nvar_d = 26\nvar_e = 18\nvar_f = 20\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_g = sum(list_a)/len(list_a)\nprint(int(var_g))"
    },
    "6916": {
        "category": "Possibility",
        "question_ko": "모든 자리 숫자를 더했을 때 34가 되는 네 자리 수의 개수를 구하시오.",
        "question_en": "Find the number of four-digit numbers whose sum of the digits is equal to 34.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "1000 10000 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] 34 [OP_LIST_MORE_EQUAL] 34 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "1000 10000 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] 34 [OP_LIST_MORE_EQUAL] 34 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1000\nvar_b = 10000\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nlist_b=[]\nfor i in list_a:\n    var_f = 0\n    i = int(i)\n    while i//10 > 0:\n        var_f = var_f + i%10\n        i = i//10\n    var_f = var_f + i%10\n    list_b.append(var_f)\nvar_g = 34\nlist_c = []\nfor i in list_b:\n    if i >= var_g:\n        list_c.append(i)\nvar_h = 34\nlist_d = []\nfor i in list_c:\n    if i <= var_h:\n        list_d.append(i)\nvar_i = len(list_d)\nprint(int(var_i))",
        "solution_code_en": "var_a = 1000\nvar_b = 10000\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nlist_b=[]\nfor i in list_a:\n    var_f = 0\n    i = int(i)\n    while i//10 > 0:\n        var_f = var_f + i%10\n        i = i//10\n    var_f = var_f + i%10\n    list_b.append(var_f)\nvar_g = 34\nlist_c = []\nfor i in list_b:\n    if i >= var_g:\n        list_c.append(i)\nvar_h = 34\nlist_d = []\nfor i in list_c:\n    if i <= var_h:\n        list_d.append(i)\nvar_i = len(list_d)\nprint(int(var_i))"
    },
    "6917": {
        "category": "Comparison",
        "question_ko": "상현이는 매일 농구 연습을 하기 위해 50번씩 공을 던집니다. 일주일 동안 상현이가 골대에 넣은 공이 각각 27개, 29개, 33개, 34개, 29개, 20개, 35개라면, 평균보다 적게 넣은 날은 며칠인지 구하시오.",
        "question_en": "Sang-hyeon throws the ball 50 times every day to practice basketball. If Sang-hyeon hits 27, 29, 33, 34, 29, 20, and 35 balls, respectively, in a week, find how many days Sang-hyeon threw less than the average hit.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 27 29 33 34 29 20 35 [OP_LIST_EOL] [OP_LIST_MEAN] [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 27 29 33 34 29 20 35 [OP_LIST_EOL] [OP_LIST_MEAN] [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 27\nvar_b = 29\nvar_c = 33\nvar_d = 34\nvar_e = 29\nvar_f = 20\nvar_g = 35\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_h = sum(list_a)/len(list_a)\nlist_b = []\nfor i in list_a:\n    if i < var_h:\n        list_b.append(i)\nvar_i = len(list_b)\nprint(int(var_i))",
        "solution_code_en": "var_a = 27\nvar_b = 29\nvar_c = 33\nvar_d = 34\nvar_e = 29\nvar_f = 20\nvar_g = 35\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_h = sum(list_a)/len(list_a)\nlist_b = []\nfor i in list_a:\n    if i < var_h:\n        list_b.append(i)\nvar_i = len(list_b)\nprint(int(var_i))"
    },
    "6918": {
        "category": "Possibility",
        "question_ko": "1부터 9까지의 자연수가 적힌 숫자 카드들이 있다. 이 중 3장을 꺼내서 합이 19가 되게 하는 방법은 모두 몇 가지인가?",
        "question_en": "There are number cards with natural numbers from 1 to 9 written on them. How many ways can you draw 3 of these cards so that the sum is 19?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "1 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 19 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 19 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 19\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 19\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))"
    },
    "6919": {
        "category": "Geometry",
        "question_ko": "팔각형 안에 그릴 수 있는 모든 대각선들이 그려져 있습니다. 그려진 대각선의 개수는?",
        "question_en": "All diagonals that can be drawn inside the octagon are drawn. How many diagonals are drawn?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "8 8 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "8 8 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 8\nvar_b = 8\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 8\nvar_b = 8\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "6920": {
        "category": "Arithmetic calculation",
        "question_ko": "당근을 0.1킬로그램(㎏) 사기 위해서는 400원이 필요합니다. 2,000원으로 살 수 있는 당근은 몇 킬로그램(㎏)인지 소수점을 포함하여 구하시오.",
        "question_en": "You need 400 won to buy 0.1 kilogram (kg) of carrots. Calculate how many kilograms (kg) of carrots you can buy with 2,000 won, including the decimal point.",
        "answer_ko": "0.50",
        "answer_en": "0.5",
        "solution_abst_ko": "2000 400 [OP_DIV] 0.1 [OP_MUL]",
        "solution_abst_en": "2000 400 [OP_DIV] 0.1 [OP_MUL]",
        "solution_code_ko": "var_a = 2000\nvar_b = 400\nvar_c = var_a / var_b\nvar_d = 0.1\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 2000\nvar_b = 400\nvar_c = var_a / var_b\nvar_d = 0.1\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "6921": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 2575미터(m)인 도로의 양쪽에 25미터(m) 간격으로 가로수를 심으려고 합니다. 도로 한쪽에 심을 가로수는 몇 그루입니까? (단, 도로의 처음과 끝에도 가로수를 심습니다.)",
        "question_en": "You want to plant street trees at intervals of 25 meters (m) on both sides of a road that is 2575 meters (m) long. What is the number of street trees planted on one side of the road if trees are also planted at the beginning and end of the road?",
        "answer_ko": "104",
        "answer_en": "104",
        "solution_abst_ko": "2575 25 [OP_DIV] 1 [OP_ADD]",
        "solution_abst_en": "2575 25 [OP_DIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 2575\nvar_b = 25\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 2575\nvar_b = 25\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "6922": {
        "category": "Geometry",
        "question_ko": "세로가 3.6미터(m)이고 가로가 세로의 2.5배인 직사각형 모양의 밭이 있습니다. 이 밭의 절반에 토마토를 심었다면 토마토를 심은 밭의 넓이는 몇 제곱미터(㎡)입니까?",
        "question_en": "There is a rectangular field with a length of 3.6 meters (m) and a width of 2.5 times the length. If you planted tomatoes in half of this field, what is the area in square meters (m2) of the field where tomatoes are planted?",
        "answer_ko": "16.2",
        "answer_en": "16.2",
        "solution_abst_ko": "3.6 3.6 2.5 [OP_MUL] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "3.6 3.6 2.5 [OP_MUL] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 3.6\nvar_b = 3.6\nvar_c = 2.5\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 3.6\nvar_b = 3.6\nvar_c = 2.5\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "6923": {
        "category": "Possibility",
        "question_ko": "6명이 있습니다. 모든 사람이 다른 사람과 한 번씩 악수를 하였습니다. 악수의 총 횟수를 구하시오.",
        "question_en": "There are 6 people. Everyone shook hands with each other once. Find the total number of handshakes.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "6 2 [OP_COMB]",
        "solution_abst_en": "6 2 [OP_COMB]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))"
    },
    "6924": {
        "category": "Geometry",
        "question_ko": "석기는 한 변의 길이가 5센티미터(㎝)인 정사각형 모양의 빨간색 색종이를 가지고 있고, 민아는 한 변의 길이가 4센티미터(㎝)인 직사각형 모양의 파란색 색종이를 가지고 있습니다. 이 빨간색 색종이와 파란색 색종이의 넓이는 같습니다. 파란색 색종이의 다른 한 변의 길이를 소수로 나타내시오.",
        "question_en": "Seokgi has a square piece of red-colored paper with a side length of 5 centimeters (cm), and Mina has a rectangular piece of blue-colored paper with a side length of 4 centimeters (cm). The red colored paper and the blue colored paper have the same area. Find the length of the other side of the blue-colored paper as a decimal number.",
        "answer_ko": "6.25",
        "answer_en": "6.25",
        "solution_abst_ko": "5 2 [OP_POW] 4 [OP_DIV]",
        "solution_abst_en": "5 2 [OP_POW] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "6925": {
        "category": "Arithmetic calculation",
        "question_ko": "민철이가 중간고사에서 수학 점수가 70점, 국어 점수가 80점, 영어 점수가 90점을 받았다. 민철이의 중간고사 평균은 얼마인지 구하시오.",
        "question_en": "Mincheol received 70 points in math, 80 points in Korean, and 90 points in English on the midterm exam. What is Mincheol's midterm average?",
        "answer_ko": "80",
        "answer_en": "80",
        "solution_abst_ko": "[OP_LIST_SOL] 70 80 90 [OP_LIST_EOL] [OP_LIST_MEAN]",
        "solution_abst_en": "[OP_LIST_SOL] 70 80 90 [OP_LIST_EOL] [OP_LIST_MEAN]",
        "solution_code_ko": "var_a = 70\nvar_b = 80\nvar_c = 90\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_d = sum(list_a)/len(list_a)\nprint(int(var_d))",
        "solution_code_en": "var_a = 70\nvar_b = 80\nvar_c = 90\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_d = sum(list_a)/len(list_a)\nprint(int(var_d))"
    },
    "6926": {
        "category": "Possibility",
        "question_ko": "세 자리 수 중 3와 2로만 이루어진 수는 총 몇개입니까?",
        "question_en": "How many three-digit numbers are made up of only 3 and 2?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "[OP_LIST_SOL] 2 3 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 2 3 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = len(list_b)\nprint(int(var_d))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = len(list_b)\nprint(int(var_d))"
    },
    "6927": {
        "category": "Possibility",
        "question_ko": "윤기는 빨간색 구슬 2개, 파란색 구슬 2개를 가지고 있습니다. 같은 색의 구슬은 각각 구별이 되지 않는다고 할 때, 구슬 4개를 서로 다르게 한 줄로 놓는 방법은 모두 몇 가지입니까?",
        "question_en": "Yoongi has 2 red marbles and 2 blue marbles. If marbles of the same color are indistinguishable from each other, how many ways can you arrange 4 marbles in a row?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "2 2 [OP_ADD] 2 2 [OP_ADD] [OP_PERM] 2 [OP_DIV] 2 [OP_DIV]",
        "solution_abst_en": "2 2 [OP_ADD] 2 2 [OP_ADD] [OP_PERM] 2 [OP_DIV] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 2\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = 2\nvar_f = var_d + var_e\nvar_g = 1\nvar_c = int(var_c)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_c-i)\nvar_h = 2\nvar_i = var_g / var_h\nvar_j = 2\nvar_k = var_i / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 2\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = 2\nvar_f = var_d + var_e\nvar_g = 1\nvar_c = int(var_c)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_c-i)\nvar_h = 2\nvar_i = var_g / var_h\nvar_j = 2\nvar_k = var_i / var_j\nprint(int(var_k))"
    },
    "6928": {
        "category": "Arithmetic calculation",
        "question_ko": "사과 몇 개와 사과의 3/5만큼 배를 샀더니 모두 240개가 되었습니다. 사과는 몇 개 샀습니까?",
        "question_en": "You bought a few apples and pears.  The number of pears are three-fifths of the number of apples, and altogeter you got 240. How many apples did you buy?",
        "answer_ko": "150",
        "answer_en": "150",
        "solution_abst_ko": "240 1 3/5 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "240 1 3/5 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 240\nvar_b = 1\nvar_c = 0.6\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 240\nvar_b = 1\nvar_c = 0.6\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "6929": {
        "category": "Geometry",
        "question_ko": "도준이가 만든 큰 케잌의 가로는 172센티미터(㎝), 세로는 295센티미터(㎝)이다. 이 케잌을 한 변의 길이가 24센티미터(㎝)인 정사각형 모양으로 최대한 많이 잘라 친구들에게 나누어 주려고 한다. 몇 명까지 줄 수 있는가?",
        "question_en": "A large cake made by Dojun measures 172 centimeters (cm) in width and 295 centimeters (cm) in length. I am going to cut this cake into as many square shapes as possible and share it with my friends. How many friends can you give the cake to?",
        "answer_ko": "50740",
        "answer_en": "50740",
        "solution_abst_ko": "172 295 [OP_MUL]",
        "solution_abst_en": "172 295 [OP_MUL]",
        "solution_code_ko": "var_a = 172\nvar_b = 295\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 172\nvar_b = 295\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "6930": {
        "category": "Geometry",
        "question_ko": "어떤 평행사변형은 넓이가 108제곱센티미터(㎠)이고 높이가 9센티미터(㎝)입니다. 이 평행사변형의 밑변의 길이는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "A parallelogram has an area of 108 square centimeters (cm2) and a height of 9 centimeters (cm). Find the length of the base of this parallelogram in centimeters (cm).",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "108 9 [OP_DIV]",
        "solution_abst_en": "108 9 [OP_DIV]",
        "solution_code_ko": "var_a = 108\nvar_b = 9\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 108\nvar_b = 9\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "6931": {
        "category": "Arithmetic calculation",
        "question_ko": "갑, 을, 병의 평균 키는 130cm이다. 여기서 정의 키와 함께 평균을 구했더니 126cm였다. 정의 키를 구하시오",
        "question_en": "While the average height of A, B, and C is 130cm (cm), the average changes to 126 cm (cm) when D is added. D  What is the height of D?",
        "answer_ko": "114",
        "answer_en": "114",
        "solution_abst_ko": "126 4 [OP_MUL] 130 3 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "126 4 [OP_MUL] 130 3 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 126\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 130\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 126\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 130\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "6932": {
        "category": "Correspondence",
        "question_ko": "여덟 자리 수 757AB384는 357의 배수입니다. A가 될 수 있는 값은 무엇입니까?",
        "question_en": "The eight-digit number 757AB84 is a multiple of 357. What value can A be?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "757AB384 [OP_GEN_POSSIBLE_LIST] 357 [OP_LIST_DIVISIBLE] 757AB384 B [OP_LIST_FIND_UNK]",
        "solution_abst_en": "757AB384 [OP_GEN_POSSIBLE_LIST] 357 [OP_LIST_DIVISIBLE] 757AB384 B [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = '757AB384'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 357\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = '757AB384'\nvar_d = 'B'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nvar_e = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_e = int(elem[unk_idx])\nprint(int(var_e))",
        "solution_code_en": "var_a = '757AB384'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 357\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = '757AB384'\nvar_d = 'B'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nvar_e = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_e = int(elem[unk_idx])\nprint(int(var_e))"
    },
    "6933": {
        "category": "Correspondence",
        "question_ko": "B보다 125만큼 작은 수는 C이고 B보다 197만큼 큰 숫자는 A이다. A가 509일때 C를 구하여라.",
        "question_en": "The number 125 less than B is C, and the number 197 greater than B is A. Find C when A is 509.",
        "answer_ko": "187",
        "answer_en": "187",
        "solution_abst_ko": "509 197 [OP_SUB] 125 [OP_SUB]",
        "solution_abst_en": "509 197 [OP_SUB] 125 [OP_SUB]",
        "solution_code_ko": "var_a = 509\nvar_b = 197\nvar_c = var_a - var_b\nvar_d = 125\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 509\nvar_b = 197\nvar_c = var_a - var_b\nvar_d = 125\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "6934": {
        "category": "Comparison",
        "question_ko": "유정은 책상 위에 갖가지 색깔의 공들을 일렬로 놓았다. 빨간색, 파란색, 노란색, 보라색, 흰색 공을 순서대로 놓았을 때 마지막 공은 무슨 색일까요?",
        "question_en": "Yujeong placed balls of various colors in a row on the desk. When the red, blue, yellow, purple, and white balls are placed in that order, what is the color of the last ball?",
        "answer_ko": "흰색",
        "answer_en": "white",
        "solution_abst_ko": "[OP_LIST_SOL] 빨간색 파란색 노란색 보라색 흰색 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] red blue yellow purple white [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '빨간색'\nvar_b = '파란색'\nvar_c = '노란색'\nvar_d = '보라색'\nvar_e = '흰색'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = list_a[var_f-1]\nprint(var_g)",
        "solution_code_en": "var_a = 'red'\nvar_b = 'blue'\nvar_c = 'yellow'\nvar_d = 'purple'\nvar_e = 'white'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = list_a[var_f-1]\nprint(var_g)"
    },
    "6935": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 수의 2배에서 6을 뺀 수는 어떤 수의 1/4배보다 8만큼 클 때, 어떤 수를 구하시오.",
        "question_en": "If 2 times a number minus 6 is 8 greater than 1/4 times the number, find what the number is.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "8 6 [OP_ADD] 2 1/4 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "8 6 [OP_ADD] 2 1/4 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 8\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = 0.25\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 8\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = 0.25\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))"
    },
    "6936": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 30센티미터(㎝)인 정사각형 색종이 안에 반지름이 3센티미터(㎝)인 원을 그리려고 합니다. 원은 모두 몇 개를 그릴 수 있겠습니까?",
        "question_en": "We are going to draw a circle with a radius of 3 centimeters (cm) inside a square piece of paper with a side length of 30 centimeters (cm). How many circles can you draw in all?",
        "answer_ko": "25",
        "answer_en": "25",
        "solution_abst_ko": "30 3 2 [OP_MUL] [OP_FDIV] 2 [OP_POW]",
        "solution_abst_en": "30 3 2 [OP_MUL] [OP_FDIV] 2 [OP_POW]",
        "solution_code_ko": "var_a = 30\nvar_b = 3\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a // var_d\nvar_f = 2\nvar_g = var_e ** var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 30\nvar_b = 3\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a // var_d\nvar_f = 2\nvar_g = var_e ** var_f\nprint(int(var_g))"
    },
    "6937": {
        "category": "Correspondence",
        "question_ko": "서로 다른 한 자리 수 A, B가 있습니다. AB×6=BBB가 맞는 식일 때 A와 B의 합을 구하시오.",
        "question_en": "There are different single digit numbers A and B. Find the sum of A and B when AB × 6 = BBB is correct.",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "AB×6=BBB A [OP_DIGIT_UNK_SOLVER] AB×6=BBB B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_abst_en": "AB×6=BBB A [OP_DIGIT_UNK_SOLVER] AB×6=BBB B [OP_DIGIT_UNK_SOLVER] [OP_ADD]",
        "solution_code_ko": "var_a = 'AB×6=BBB'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 'AB×6=BBB'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 'AB×6=BBB'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nvar_d = 'AB×6=BBB'\nvar_e = 'B'\nans_dict = dict()\nvar_d = var_d.replace('×','*')\nvar_d = var_d.replace('x','*')\nvar_d = var_d.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_d):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_d\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_d):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_f = ans_dict[var_e]\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "6938": {
        "category": "Comparison",
        "question_ko": "A, B, C, D 4명의 일주일 평균 용돈은 2300원이다. A, B 두사람의 평균 용돈은 3000원이고, C, D의 평균 용돈은 2750원이다. 또, B, C의 평균 용돈은 2100원이고, A용돈은 B의 용돈보다 800원이 많다. D의 일주일 용돈은 얼마인가?",
        "question_en": "The average pocket money for A, B, C, and D is 2,300 won. The average pocket money of A and B is 3000 won, and the average pocket money of C and D is 2750 won. Also, the average pocket money of B and C is 2100 won, and the pocket money of A is 800 won more than that of B. How much is D's pocket money?",
        "answer_ko": "3900",
        "answer_en": "3900",
        "solution_abst_ko": "2750 2 [OP_MUL] 2100 2 [OP_MUL] 3000 2 [OP_MUL] 800 [OP_SUB] 2 [OP_DIV] [OP_SUB] [OP_SUB]",
        "solution_abst_en": "2750 2 [OP_MUL] 2100 2 [OP_MUL] 3000 2 [OP_MUL] 800 [OP_SUB] 2 [OP_DIV] [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 2750\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 2100\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = 3000\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = 800\nvar_k = var_i - var_j\nvar_l = 2\nvar_m = var_k / var_l\nvar_n = var_f - var_m\nvar_o = var_c - var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 2750\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 2100\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = 3000\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = 800\nvar_k = var_i - var_j\nvar_l = 2\nvar_m = var_k / var_l\nvar_n = var_f - var_m\nvar_o = var_c - var_n\nprint(int(var_o))"
    },
    "6939": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 24를 빼려고 합니다. 잘못하여 4를 나누었을 때의 답이 50이라면 바르게 계산한 결과는 얼마일까요?",
        "question_en": "You want to subtract 24 from a number. If the answer when wrongly divided by 4 is 50, what is the correct calculation result?",
        "answer_ko": "176",
        "answer_en": "176",
        "solution_abst_ko": "50 4 [OP_MUL] 24 [OP_SUB]",
        "solution_abst_en": "50 4 [OP_MUL] 24 [OP_SUB]",
        "solution_code_ko": "var_a = 50\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 24\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 50\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 24\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "6940": {
        "category": "Correspondence",
        "question_ko": "13은 어떤 수에서 6을 뺐어야 하는데 실수로 3을 더하여 나온 결과입니다. 어떤 수는 얼마입니까?",
        "question_en": "13 is the result of mistakenly adding 3 to a particular number that should have subtracted 6 from it. What is the certain number?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "13 3 [OP_SUB]",
        "solution_abst_en": "13 3 [OP_SUB]",
        "solution_code_ko": "var_a = 13\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 13\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "6941": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 11을 나누어 2를 얻었습니다. 어떤 수에 6을 곱한 결과 값을 구하시오.",
        "question_en": "Divide 11 from a certain number, and you can get 2. Find the result of multiplying this number by 6.",
        "answer_ko": "132",
        "answer_en": "132",
        "solution_abst_ko": "2 11 [OP_MUL] 6 [OP_MUL]",
        "solution_abst_en": "2 11 [OP_MUL] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 11\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 11\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "6942": {
        "category": "Arithmetic calculation",
        "question_ko": "어제 석진이는 3,000원을 주고 물고기 10마리를 샀습니다. 오늘 같은 가게에서 이 물고기를 좀 더 많이 샀더니 어제보다 6,000원을 더 냈습니다. 석진이가 이틀 동안 산 물고기는 모두 몇 마리입니까?",
        "question_en": "Yesterday, Seokjin bought 10 fish for 3,000 won. He bought some more of this fish at the same store today and paid 6,000 won more than yesterday. How many fish did Seokjin buy for two days?",
        "answer_ko": "40",
        "answer_en": "40",
        "solution_abst_ko": "3000 6000 [OP_ADD] 3000 10 [OP_DIV] [OP_DIV] 10 [OP_ADD]",
        "solution_abst_en": "3000 6000 [OP_ADD] 3000 10 [OP_DIV] [OP_DIV] 10 [OP_ADD]",
        "solution_code_ko": "var_a = 3000\nvar_b = 6000\nvar_c = var_a + var_b\nvar_d = 3000\nvar_e = 10\nvar_f = var_d / var_e\nvar_g = var_c / var_f\nvar_h = 10\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 3000\nvar_b = 6000\nvar_c = var_a + var_b\nvar_d = 3000\nvar_e = 10\nvar_f = var_d / var_e\nvar_g = var_c / var_f\nvar_h = 10\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "6943": {
        "category": "Arithmetic calculation",
        "question_ko": "피시방 요금은 처음 30분 동안 500원이고 그 이후부터는 10분마다 200원씩 추가됩니다. 1시간 20분 동안 피시방을 이용하면 얼마를 내야합니까?",
        "question_en": "The PC room fee is 500 won for the first 30 minutes and 200 won for every 10 minutes thereafter. How much do you have to pay to use the PC room for 1 hour and 20 minutes?",
        "answer_ko": "1500",
        "answer_en": "1500",
        "solution_abst_ko": "1 60 [OP_MUL] 20 [OP_ADD] 30 [OP_SUB] 10 [OP_FDIV] 200 [OP_MUL] 500 [OP_ADD]",
        "solution_abst_en": "1 60 [OP_MUL] 20 [OP_ADD] 30 [OP_SUB] 10 [OP_FDIV] 200 [OP_MUL] 500 [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 20\nvar_e = var_c + var_d\nvar_f = 30\nvar_g = var_e - var_f\nvar_h = 10\nvar_i = var_g // var_h\nvar_j = 200\nvar_k = var_i * var_j\nvar_l = 500\nvar_m = var_k + var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 1\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 20\nvar_e = var_c + var_d\nvar_f = 30\nvar_g = var_e - var_f\nvar_h = 10\nvar_i = var_g // var_h\nvar_j = 200\nvar_k = var_i * var_j\nvar_l = 500\nvar_m = var_k + var_l\nprint(int(var_m))"
    },
    "6944": {
        "category": "Possibility",
        "question_ko": "구별이 되지 않는 장미 5송이와 튤립 1송이를 서로 다르게 한 줄로 놓는 방법은 모두 몇 가지입니까?",
        "question_en": "In how many different ways can you line up 5 indistinguishable roses and 1 tulip?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "5 1 [OP_ADD]",
        "solution_abst_en": "5 1 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "6945": {
        "category": "Geometry",
        "question_ko": "세로가 4 센티미터(㎝)이고 넓이가 25/2제곱센티미터(㎠)인 직사각형이 있습니다. 이 직사각형의 가로는 몇 센티미터(㎝)인가요?",
        "question_en": "You have a rectangle with a length of 4 centimeters (cm) and an area of 25/2 square centimeters (cm2). How many centimeters (cm) is the width of this rectangle?",
        "answer_ko": "3.13",
        "answer_en": "3.13",
        "solution_abst_ko": "25/2 4 [OP_DIV]",
        "solution_abst_en": "25/2 4 [OP_DIV]",
        "solution_code_ko": "var_a = 12.5\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 12.5\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "6946": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 15로 나누고 51을 곱하였더니 224.8 이 되었습니다. 어떤 수에 17을 곱하고 5를 더하면 얼마인지 구하시오.",
        "question_en": "When dividing a number by 15 and then multiplying by 51 results in 224.8. What will be the value if the number is multiplied by 17 and then added to 5?",
        "answer_ko": "1129",
        "answer_en": "1129",
        "solution_abst_ko": "224.8 51 [OP_DIV] 15 [OP_MUL] 17 [OP_MUL] 5 [OP_ADD]",
        "solution_abst_en": "224.8 51 [OP_DIV] 15 [OP_MUL] 17 [OP_MUL] 5 [OP_ADD]",
        "solution_code_ko": "var_a = 224.8\nvar_b = 51\nvar_c = var_a / var_b\nvar_d = 15\nvar_e = var_c * var_d\nvar_f = 17\nvar_g = var_e * var_f\nvar_h = 5\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 224.8\nvar_b = 51\nvar_c = var_a / var_b\nvar_d = 15\nvar_e = var_c * var_d\nvar_f = 17\nvar_g = var_e * var_f\nvar_h = 5\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "6947": {
        "category": "Arithmetic calculation",
        "question_ko": "바나나와 귤의 평균 개수는 89개이다. 바나나, 귤, 오랜지의 평균 개수가 91개일때 오랜지의 개수는 몇 개인가?",
        "question_en": "The average number of bananas and tangerines is 89. How many oranges are there when the average number of bananas, tangerines, and oranges is 91?",
        "answer_ko": "95",
        "answer_en": "95",
        "solution_abst_ko": "91 3 [OP_MUL] 89 2 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "91 3 [OP_MUL] 89 2 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 91\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 89\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 91\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 89\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "6948": {
        "category": "Comparison",
        "question_ko": "도형 A는 가로가 10센티미터(㎝), 둘레가 26센티미터(㎝)인 직사각형입니다. 도형 B는 가로가 8센티미터(㎝), 둘레가 40센티미터(㎝)인 직사각형입니다. 두 도형 중 넓이가 더 넓은 것은 무엇입니까?",
        "question_en": "Figure A is a rectangle with a width of 10 centimeters (cm) and a perimeter of 26 centimeters (cm). Figure B is a rectangle with a width of 8 centimeters (cm) and a perimeter of 40 centimeters (cm). Which of the two figures has the greater area?",
        "answer_ko": "B",
        "answer_en": "B",
        "solution_abst_ko": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 26 10 2 [OP_MUL] [OP_SUB] 2 [OP_DIV] 10 [OP_MUL] 40 8 2 [OP_MUL] [OP_SUB] 2 [OP_DIV] 8 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 26 10 2 [OP_MUL] [OP_SUB] 2 [OP_DIV] 10 [OP_MUL] 40 8 2 [OP_MUL] [OP_SUB] 2 [OP_DIV] 8 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 26\nvar_d = 10\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 2\nvar_i = var_g / var_h\nvar_j = 10\nvar_k = var_i * var_j\nvar_l = 40\nvar_m = 8\nvar_n = 2\nvar_o = var_m * var_n\nvar_p = var_l - var_o\nvar_q = 2\nvar_r = var_p / var_q\nvar_s = 8\nvar_t = var_r * var_s\nlist_b= []\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_b.append(var_t)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nlist_b.reverse()\nvar_u = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_v = list_c[-var_u]\nvar_w = list_b.index(var_v)+1\nvar_x = list_a[var_w-1]\nprint(var_x)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 26\nvar_d = 10\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 2\nvar_i = var_g / var_h\nvar_j = 10\nvar_k = var_i * var_j\nvar_l = 40\nvar_m = 8\nvar_n = 2\nvar_o = var_m * var_n\nvar_p = var_l - var_o\nvar_q = 2\nvar_r = var_p / var_q\nvar_s = 8\nvar_t = var_r * var_s\nlist_b= []\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_b.append(var_t)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nlist_b.reverse()\nvar_u = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_v = list_c[-var_u]\nvar_w = list_b.index(var_v)+1\nvar_x = list_a[var_w-1]\nprint(var_x)"
    },
    "6949": {
        "category": "Arithmetic calculation",
        "question_ko": "두 자리 수끼리의 뺄셈에서 빼는 수의 십의 자리 숫자 2를 5로 잘못 보고, 일의 자리 숫자 6을 9로 잘못 보고 계산하였더니 그 값이 44가 되었습니다. 바르게 계산한 결과를 구하시오.",
        "question_en": "In the subtraction of two-digit numbers, the number 2 in the tens digit of the number to be subtracted is mistakenly regarded as 5, and the digit 6 in the ones digit is mistakenly regarded as 9, and the result is 44. Find the result of the correct calculation.",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "44 10 2 5 [OP_SUB] [OP_MUL] [OP_ADD] 1 6 9 [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_abst_en": "44 10 2 5 [OP_SUB] [OP_MUL] [OP_ADD] 1 6 9 [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 44\nvar_b = 10\nvar_c = 2\nvar_d = 5\nvar_e = var_c - var_d\nvar_f = var_b * var_e\nvar_g = var_a + var_f\nvar_h = 1\nvar_i = 6\nvar_j = 9\nvar_k = var_i - var_j\nvar_l = var_h * var_k\nvar_m = var_g + var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 44\nvar_b = 10\nvar_c = 2\nvar_d = 5\nvar_e = var_c - var_d\nvar_f = var_b * var_e\nvar_g = var_a + var_f\nvar_h = 1\nvar_i = 6\nvar_j = 9\nvar_k = var_i - var_j\nvar_l = var_h * var_k\nvar_m = var_g + var_l\nprint(int(var_m))"
    },
    "6950": {
        "category": "Correspondence",
        "question_ko": "가린이는 방학숙제를 24일 동안 나눠서 하기로 하였다. 하루에 19쪽을 풀면 남는 것 없이 숙제를 끝마칠 수 있다고 한다. 가린이의 방학숙제는 모두 몇 쪽인가?",
        "question_en": "Garin decided to divide her vacation homework for 24 days. It is said that if she solves 19 pages a day, she can finish her homework with nothing left. How many pages are there in Garin's vacation homework?",
        "answer_ko": "456",
        "answer_en": "456",
        "solution_abst_ko": "19 24 [OP_MUL]",
        "solution_abst_en": "19 24 [OP_MUL]",
        "solution_code_ko": "var_a = 19\nvar_b = 24\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 19\nvar_b = 24\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "6951": {
        "category": "Arithmetic calculation",
        "question_ko": "10.4센티미터(㎝)인 티켓 종이를 3.5센티미터(㎝)씩 겹치게 하여 원을 만들려고 합니다. 티켓 종이가 16개 있다면 이어 붙인 원의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "I am going to make a circle by overlapping the 10.4 centimeters (cm) ticket paper by 3.5 centimeters (cm). If there are 16 tickets, how many centimeters (cm) is the circumference of the circle?",
        "answer_ko": "110.40",
        "answer_en": "110.4",
        "solution_abst_ko": "10.4 3.5 [OP_SUB] 16 [OP_MUL]",
        "solution_abst_en": "10.4 3.5 [OP_SUB] 16 [OP_MUL]",
        "solution_code_ko": "var_a = 10.4\nvar_b = 3.5\nvar_c = var_a - var_b\nvar_d = 16\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 10.4\nvar_b = 3.5\nvar_c = var_a - var_b\nvar_d = 16\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "6952": {
        "category": "Arithmetic calculation",
        "question_ko": "장미가 29송이 있었습니다. 병에 몇 송이를 꽂았더니 12송이가 남았습니다. 병에 꽂은 장미는 몇 송이입니까?",
        "question_en": "There were 29 roses. I put a few in the vase, and there are 12 left. How many roses did I put in the vase?",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "29 12 [OP_SUB]",
        "solution_abst_en": "29 12 [OP_SUB]",
        "solution_code_ko": "var_a = 29\nvar_b = 12\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 29\nvar_b = 12\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "6953": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 114센티미터(㎝)인 종이띠 위에 3센티미터(㎝) 간격으로 누름 못을 꽂으려고 합니다. 종이띠의 처음과 끝에는 반드시 누름 못을 꽂는다고 할 때, 필요한 누름 못은 모두 몇 개인지 구해 보시오.",
        "question_en": "You are trying to insert press nails at 3 centimeters (cm) intervals on a paper strip that is 114 centimeters (cm) long. Assuming that you must insert a presser nail at the beginning and end of the paper strip, find out how many presser nails are needed.",
        "answer_ko": "39",
        "answer_en": "39",
        "solution_abst_ko": "114 3 [OP_DIV] 1 [OP_ADD]",
        "solution_abst_en": "114 3 [OP_DIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 114\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 114\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "6954": {
        "category": "Comparison",
        "question_ko": "채영이네 집에서 학교까지는 4.3킬로미터(㎞)이고, 태훈이네 집에서 학교까지는 900미터(m) 길이의 도로를 5블럭 지나야 합니다. 채영이와 태훈이 중 학교에서 더 먼 곳에 사는 학생은 누구입니까?",
        "question_en": "It is 4.3 kilometers (km) from Chaeyoung's house to the school, and from Taehoon's house to the school, you have to pass 5 blocks of a 900m (m) long road. Which of Chaeyoung and Taehoon lives farther away from school?",
        "answer_ko": "태훈",
        "answer_en": "Taehoon",
        "solution_abst_ko": "[OP_LIST_SOL] 채영 태훈 [OP_LIST_EOL] [OP_LIST_SOL] 4.3 1000 [OP_MUL] 900 5 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Chaeyoung Taehoon [OP_LIST_EOL] [OP_LIST_SOL] 4.3 1000 [OP_MUL] 900 5 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '채영'\nvar_b = '태훈'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4.3\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 900\nvar_g = 5\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Chaeyoung'\nvar_b = 'Taehoon'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4.3\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 900\nvar_g = 5\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "6955": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 마라톤 대회에 참가한 1250명의 선수 중에서 뛰는 도중 포기한 사람이 완주한 사람보다 124명 더 많았다면 완주한 사람은 모두 몇 명인지 구하시오.",
        "question_en": "If out of 1250 runners in a marathon, 124 more gave up while running than finished, how many total runners finished?",
        "answer_ko": "563",
        "answer_en": "563",
        "solution_abst_ko": "1250 124 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "1250 124 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 1250\nvar_b = 124\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 1250\nvar_b = 124\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "6956": {
        "category": "Comparison",
        "question_ko": "동굴을 탐험하던 탐험가 앞에 문제가 나타났다. 문제의 내용은, 앞의 버튼 5개 중 1보다 작은 것을 모두 누르는 것이였다. 버튼은 총 5개가 있었고, 각각 1/10, 8, 0.9, 7/10, 5가 적혀져 있었다. 탐험가는 몇 개의 버튼을 눌러야 하는가?",
        "question_en": "A problem appeared before the explorer who was exploring the cave. The content of the problem was to press all the buttons smaller than 1 out of the 5 buttons. There were 5 buttons in total, with 1/10, 8, 0.9, 7/10, and 5 were written on each. How many buttons does the explorer have to press?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 1/10 8 0.9 7/10 5 [OP_LIST_EOL] 1 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1/10 8 0.9 7/10 5 [OP_LIST_EOL] 1 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.1\nvar_b = 8\nvar_c = 0.9\nvar_d = 0.7\nvar_e = 5\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b = []\nfor i in list_a:\n    if i < var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 0.1\nvar_b = 8\nvar_c = 0.9\nvar_d = 0.7\nvar_e = 5\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b = []\nfor i in list_a:\n    if i < var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "6957": {
        "category": "Comparison",
        "question_ko": "가는 동전 21개를 가지고 있고, 나는 가보다 9개 더 적게 가지고 있습니다. 또, 다는 나보다 17개 더 많이 가지고 있습니다. 가와 나의 동전을 더한 개수가 다와 라의 동전을 더한 개수보다 5개 더 적을 때, 라가 가지고 있는 동전은 몇 개인지 구하시오.",
        "question_en": "A has 21 coins, B has 9 coins fewer than A's, and C has 17 more than B's. If the number of coins added to A and B is 5 less than the number of coins added to C and D, how many coins does D have?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "21 21 9 [OP_SUB] [OP_ADD] 21 9 [OP_SUB] 17 [OP_ADD] [OP_SUB] 5 [OP_ADD]",
        "solution_abst_en": "21 21 9 [OP_SUB] [OP_ADD] 21 9 [OP_SUB] 17 [OP_ADD] [OP_SUB] 5 [OP_ADD]",
        "solution_code_ko": "var_a = 21\nvar_b = 21\nvar_c = 9\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 21\nvar_g = 9\nvar_h = var_f - var_g\nvar_i = 17\nvar_j = var_h + var_i\nvar_k = var_e - var_j\nvar_l = 5\nvar_m = var_k + var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 21\nvar_b = 21\nvar_c = 9\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 21\nvar_g = 9\nvar_h = var_f - var_g\nvar_i = 17\nvar_j = var_h + var_i\nvar_k = var_e - var_j\nvar_l = 5\nvar_m = var_k + var_l\nprint(int(var_m))"
    },
    "6958": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 학교의 3학년 학생 수는 모두 128명입니다. 남학생이 여학생보다 12명 더 많다면 남학생은 몇 명입니까?",
        "question_en": "A school has 128 students in 3rd grade. If there are 12 more boys than girls, how many boys are there?",
        "answer_ko": "70",
        "answer_en": "70",
        "solution_abst_ko": "128 12 [OP_SUB] 2 [OP_DIV] 12 [OP_ADD]",
        "solution_abst_en": "128 12 [OP_SUB] 2 [OP_DIV] 12 [OP_ADD]",
        "solution_code_ko": "var_a = 128\nvar_b = 12\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 12\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 128\nvar_b = 12\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 12\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "6959": {
        "category": "Comparison",
        "question_ko": "신영은 1/3, 석기는 4분의 1, 웅이은 1/5을 먹었다. 누가 케이크를 가장 많이 먹었습니까?",
        "question_en": "Shinyoung ate 1/3, Seokgi ate 1/4, and Woong ate 1/5 of the cake. Who ate the most cake?",
        "answer_ko": "신영",
        "answer_en": "Shinyoung",
        "solution_abst_ko": "[OP_LIST_SOL] 신영 석기 웅이 [OP_LIST_EOL] [OP_LIST_SOL] 1/3 1 4 [OP_DIV] 1/5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Shinyoung Seokgi Woong [OP_LIST_EOL] [OP_LIST_SOL] 1/3 1 4 [OP_DIV] 1/5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '신영'\nvar_b = '석기'\nvar_c = '웅이'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.3333333333333333\nvar_e = 1\nvar_f = 4\nvar_g = var_e / var_f\nvar_h = 0.2\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Shinyoung'\nvar_b = 'Seokgi'\nvar_c = 'Woong'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.3333333333333333\nvar_e = 1\nvar_f = 4\nvar_g = var_e / var_f\nvar_h = 0.2\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "6960": {
        "category": "Comparison",
        "question_ko": "세 명의 학생 윤기, 정국, 유나는 각각 7, 6, 9 숫자 카드를 가지고 있습니다. 2번째로 작은 숫자를 가진 사람은 누구입니까?",
        "question_en": "The three students, Yoongi, Jungkook, and Yuna, have the number cards 7, 6, and 9 each. Who has the 2nd smallest number?",
        "answer_ko": "윤기",
        "answer_en": "Yoongi",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 유나 [OP_LIST_EOL] [OP_LIST_SOL] 7 6 9 [OP_LIST_EOL] 2 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook Yuna [OP_LIST_EOL] [OP_LIST_SOL] 7 6 9 [OP_LIST_EOL] 2 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nvar_c = '유나'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 7\nvar_e = 6\nvar_f = 9\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nvar_c = 'Yuna'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 7\nvar_e = 6\nvar_f = 9\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "6961": {
        "category": "Geometry",
        "question_ko": "원의 반지름의 길이가 7센티미터(㎝)일 때, 지름의 길이는 몇 센티미터(㎝)인가요?",
        "question_en": "If the length of the radius of a circle is 7 centimeters (cm), what is the length of the diameter in centimeters (cm)?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "7 2 [OP_MUL]",
        "solution_abst_en": "7 2 [OP_MUL]",
        "solution_code_ko": "var_a = 7\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 7\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "6962": {
        "category": "Possibility",
        "question_ko": "V, W, X, Y, Z 5명을 한 줄로 세울 때, V를 제일 앞에, X와 Y를 이웃하게 세우는 경우의 수를 구하시오.",
        "question_en": "When 5 people V, W, X, Y, Z are lined up, find the number of ways to put V first and X and Y next to each other.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "[OP_LIST_SOL] V W X Y Z [OP_LIST_EOL] [OP_LIST_SOL] V [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_SOL] X [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] X Y [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] V W X Y Z [OP_LIST_EOL] [OP_LIST_SOL] V [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_SOL] X [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] X Y [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL]",
        "solution_code_ko": "var_a = 'V'\nvar_b = 'W'\nvar_c = 'X'\nvar_d = 'Y'\nvar_e = 'Z'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 'V'\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_g = 'X'\nlist_d= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_d.append(var_g)\nlist_d.reverse()\nlist_e = list(set(list_c) - set(list_d))\nvar_h = len(list_e)\nvar_i = len(list_e)\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nvar_k = 'X'\nvar_l = 'Y'\nlist_f= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_f.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_f.append(var_k)\nlist_f.reverse()\nvar_m = len(list_f)\nvar_n = len(list_f)\nvar_o = 1\nvar_m = int(var_m)\nvar_n = int(var_n)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o * (var_m-i)\nvar_p = var_j * var_o\nprint(int(var_p))",
        "solution_code_en": "var_a = 'V'\nvar_b = 'W'\nvar_c = 'X'\nvar_d = 'Y'\nvar_e = 'Z'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 'V'\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_g = 'X'\nlist_d= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_d.append(var_g)\nlist_d.reverse()\nlist_e = list(set(list_c) - set(list_d))\nvar_h = len(list_e)\nvar_i = len(list_e)\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nvar_k = 'X'\nvar_l = 'Y'\nlist_f= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_f.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_f.append(var_k)\nlist_f.reverse()\nvar_m = len(list_f)\nvar_n = len(list_f)\nvar_o = 1\nvar_m = int(var_m)\nvar_n = int(var_n)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o * (var_m-i)\nvar_p = var_j * var_o\nprint(int(var_p))"
    },
    "6963": {
        "category": "Correspondence",
        "question_ko": "호석이는 어떤 수에서 9를 나누어 8을 얻었습니다. 어떤 수에 11을 더하면 얼마일까요?",
        "question_en": "Hoseok divides a number by 9 to get 8. What do you get when 11 is added to this number?",
        "answer_ko": "83",
        "answer_en": "83",
        "solution_abst_ko": "8 9 [OP_MUL] 11 [OP_ADD]",
        "solution_abst_en": "8 9 [OP_MUL] 11 [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 11\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 11\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "6964": {
        "category": "Comparison",
        "question_ko": "동균은 정국보다 키가 크고, 동욱은 정국보다 키가 크다. 동국과 동균의 키를 비교했을 때 동국이 작으면 이 중 누가 가장 클까?",
        "question_en": "Dongkyun is taller than Jungkook, and Dongwook is taller than Jungkook. When comparing the heights of Dongwook and Dongkyun, Dongwook is shorter, Then who is the tallest?",
        "answer_ko": "동균",
        "answer_en": "Dongkyun",
        "solution_abst_ko": "[OP_LIST_SOL] 동균 정국 동욱 [OP_LIST_EOL] [OP_LIST_SOL] 동균 정국 > 동욱 정국 > 동욱 동균 < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Dongkyun Jungkook Dongwook [OP_LIST_EOL] [OP_LIST_SOL] Dongkyun Jungkook > Dongwook Jungkook > Dongwook Dongkyun < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '동균'\nvar_b = '정국'\nvar_c = '동욱'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '동균'\nvar_e = '정국'\nvar_f = '>'\nvar_g = '동욱'\nvar_h = '정국'\nvar_i = '>'\nvar_j = '동욱'\nvar_k = '동균'\nvar_l = '<'\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_m = 1\nvar_n = list_c[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'Dongkyun'\nvar_b = 'Jungkook'\nvar_c = 'Dongwook'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'Dongkyun'\nvar_e = 'Jungkook'\nvar_f = '>'\nvar_g = 'Dongwook'\nvar_h = 'Jungkook'\nvar_i = '>'\nvar_j = 'Dongwook'\nvar_k = 'Dongkyun'\nvar_l = '<'\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_m = 1\nvar_n = list_c[var_m-1]\nprint(var_n)"
    },
    "6965": {
        "category": "Geometry",
        "question_ko": "두 대변이 평행한 사각형의 밑변의 길이가 9센티미터(㎝)이고 넓이가 33.3제곱센티미터(㎠)라면, 이 사각형의 높이는 몇 센티미터(㎝)일지 구하시오.",
        "question_en": "If the base of a rectangle that has two parallel sides is 9 centimeters (cm) long and the area is 33.3 square centimeters (cm2), how many centimeters (cm) is the height of the rectangle?",
        "answer_ko": "3.70",
        "answer_en": "3.7",
        "solution_abst_ko": "33.3 9 [OP_DIV]",
        "solution_abst_en": "33.3 9 [OP_DIV]",
        "solution_code_ko": "var_a = 33.3\nvar_b = 9\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 33.3\nvar_b = 9\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "6966": {
        "category": "Comparison",
        "question_ko": "모두 다른 다섯 사람이 같은 시험을 쳤는데, 평균이 81.6점이었다. 1등의 시험 점수를 뺀, 나머지의 평균이 5등의 점수를 뺀 나머지의 평균보다 6점이 낮다고 한다. 나머지 사람들의 점수가 88점, 84점, 76점 이라고 할 때, 5등의 점수를 구하여라.",
        "question_en": "All five different people took the same test, resulting in an average score of 81.6. It is said that the average of the remaining test scores except the 1st place's score is 6 points lower than the average of the remainder except for the 5th place's score. If the rest of the people's scores are 88, 84, and 76, find the score the 5th place has received.",
        "answer_ko": "68",
        "answer_en": "68",
        "solution_abst_ko": "81.6 5 [OP_MUL] 88 84 [OP_ADD] 76 [OP_ADD] [OP_SUB] 6 4 [OP_MUL] [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "81.6 5 [OP_MUL] 88 84 [OP_ADD] 76 [OP_ADD] [OP_SUB] 6 4 [OP_MUL] [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 81.6\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 88\nvar_e = 84\nvar_f = var_d + var_e\nvar_g = 76\nvar_h = var_f + var_g\nvar_i = var_c - var_h\nvar_j = 6\nvar_k = 4\nvar_l = var_j * var_k\nvar_m = var_i - var_l\nvar_n = 2\nvar_o = var_m / var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 81.6\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 88\nvar_e = 84\nvar_f = var_d + var_e\nvar_g = 76\nvar_h = var_f + var_g\nvar_i = var_c - var_h\nvar_j = 6\nvar_k = 4\nvar_l = var_j * var_k\nvar_m = var_i - var_l\nvar_n = 2\nvar_o = var_m / var_n\nprint(int(var_o))"
    },
    "6967": {
        "category": "Correspondence",
        "question_ko": "어떤 수는 7보다 크지만 8이 아닙니다. 6, 7, 8, 9 중에서 어떤 수를 구하시오.",
        "question_en": "A certain number is greater than 7 but it is not 8. Find the number among 6, 7, 8, and 9.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "[OP_LIST_SOL] 6 7 8 9 [OP_LIST_EOL] 7 [OP_LIST_MORE] [OP_LIST_SOL] 8 [OP_LIST_EOL] [OP_SET_DIFFERENCE] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] 6 7 8 9 [OP_LIST_EOL] 7 [OP_LIST_MORE] [OP_LIST_SOL] 8 [OP_LIST_EOL] [OP_SET_DIFFERENCE] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 6\nvar_b = 7\nvar_c = 8\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 7\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nvar_f = 8\nlist_c= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_c.append(var_f)\nlist_c.reverse()\nlist_d = list(set(list_b) - set(list_c))\nvar_g = 1\nvar_h = list_d[var_g-1]\nprint(int(var_h))",
        "solution_code_en": "var_a = 6\nvar_b = 7\nvar_c = 8\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 7\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nvar_f = 8\nlist_c= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_c.append(var_f)\nlist_c.reverse()\nlist_d = list(set(list_b) - set(list_c))\nvar_g = 1\nvar_h = list_d[var_g-1]\nprint(int(var_h))"
    },
    "6968": {
        "category": "Comparison",
        "question_ko": "학교에서 국어, 수학, 영어, 과학, 사회의 순서로 시험을 봤습니다. 3번째로 시험을 본 과목은 무엇입니까?",
        "question_en": "At school, you took exams in the order of Korean, Mathematics, English, Science, and History. What subject did you take for the third time?",
        "answer_ko": "영어",
        "answer_en": "English",
        "solution_abst_ko": "[OP_LIST_SOL] 국어 수학 영어 과학 사회 [OP_LIST_EOL] 3 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Korean Mathematics English Science History [OP_LIST_EOL] 3 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '국어'\nvar_b = '수학'\nvar_c = '영어'\nvar_d = '과학'\nvar_e = '사회'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nvar_g = list_a[var_f-1]\nprint(var_g)",
        "solution_code_en": "var_a = 'Korean'\nvar_b = 'Mathematics'\nvar_c = 'English'\nvar_d = 'Science'\nvar_e = 'History'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nvar_g = list_a[var_f-1]\nprint(var_g)"
    },
    "6969": {
        "category": "Arithmetic calculation",
        "question_ko": "준혁이는 1000원짜리 공책과 2000원짜리 색연필을 합하여 15개를 사고 22000원을 사용했습니다. 색연필은 모두 몇 개 샀을까요?",
        "question_en": "Junhyuk bought 15 notebooks that cost 1,000 won each and colored pencils that cost 2,000 won each, and spent 22,000 won. How many colored pencils were bought in total?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "22000 1000 15 [OP_MUL] [OP_SUB] 2000 1000 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "22000 1000 15 [OP_MUL] [OP_SUB] 2000 1000 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 22000\nvar_b = 1000\nvar_c = 15\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 2000\nvar_g = 1000\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 22000\nvar_b = 1000\nvar_c = 15\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 2000\nvar_g = 1000\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "6970": {
        "category": "Arithmetic calculation",
        "question_ko": "농장에는 닭보다 토끼가 17마리 많습니다. 농장에서 토끼를 64마리 기르고 있다면 농장에서 기르는 토끼와 닭은 모두 몇 마리입니까?",
        "question_en": "There are 17 more rabbits than chickens on the farm. If there are 64 rabbits on the farm, how many rabbits and chickens are on the farm in total?",
        "answer_ko": "111",
        "answer_en": "111",
        "solution_abst_ko": "64 17 [OP_SUB] 64 [OP_ADD]",
        "solution_abst_en": "64 17 [OP_SUB] 64 [OP_ADD]",
        "solution_code_ko": "var_a = 64\nvar_b = 17\nvar_c = var_a - var_b\nvar_d = 64\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 64\nvar_b = 17\nvar_c = var_a - var_b\nvar_d = 64\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "6971": {
        "category": "Correspondence",
        "question_ko": "B는 자연수입니다. 식 360÷(A×A×A/B)=5을 만족하는 B 중 가장 작은 수를 구하시오.",
        "question_en": "A and B are natural numbers. Find the smallest number among B that satisfies the expression 360÷(A×A×A/B)=5.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "360÷(A×A×A/B)=5 B [OP_NUM_UNK_SOLVER] 1 [OP_LIST_MIN]",
        "solution_abst_en": "360÷(A×A×A/B)=5 B [OP_NUM_UNK_SOLVER] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = '360÷(A×A×A/B)=5'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[var_c-1]\nprint(int(var_d))",
        "solution_code_en": "var_a = '360÷(A×A×A/B)=5'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[var_c-1]\nprint(int(var_d))"
    },
    "6972": {
        "category": "Arithmetic calculation",
        "question_ko": "꿀벌은 꿀을 시속 10미터(m)로 날고 있었다. 꽃에서 꿀을 발견하고, 너무 기쁜 나머지 다시 집으로 시속 15미터(m)로 날아갔더니, 꿀을 찾을 때보다 30분 덜 걸렸다. 꿀벌의 집과 꽃 사이의 거리를 구하시오.",
        "question_en": "A honeybee was flying at 10 meters (m) per hour, seeking honey. After finding honey in a flower, it was so happy that it flew back to its nest at 15 meters (m) per hour, and it took 30 minutes less than when it was seeking honey. Find the distance between the bee's nest and the flower.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "30 60 [OP_DIV] 1 10 [OP_DIV] 1 15 [OP_DIV] [OP_SUB] [OP_DIV]",
        "solution_abst_en": "30 60 [OP_DIV] 1 10 [OP_DIV] 1 15 [OP_DIV] [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 30\nvar_b = 60\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = 10\nvar_f = var_d / var_e\nvar_g = 1\nvar_h = 15\nvar_i = var_g / var_h\nvar_j = var_f - var_i\nvar_k = var_c / var_j\nprint(int(eval('{:.2f}'.format(round(var_k+1e-10,2)))))",
        "solution_code_en": "var_a = 30\nvar_b = 60\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = 10\nvar_f = var_d / var_e\nvar_g = 1\nvar_h = 15\nvar_i = var_g / var_h\nvar_j = var_f - var_i\nvar_k = var_c / var_j\nprint(int(eval('{:.2f}'.format(round(var_k+1e-10,2)))))"
    },
    "6973": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 10까지의 홀수 중 6이하의 수의 개수를 구하시오.",
        "question_en": "Find how many odd numbers less than 6 are there from 1 to 10.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "1 10 [OP_LIST_ODD] 6 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "1 10 [OP_LIST_ODD] 6 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 10\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 6\nlist_b = []\nfor i in list_a:\n    if i <= var_c:\n        list_b.append(i)\nvar_d = len(list_b)\nprint(int(var_d))",
        "solution_code_en": "var_a = 1\nvar_b = 10\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 6\nlist_b = []\nfor i in list_a:\n    if i <= var_c:\n        list_b.append(i)\nvar_d = len(list_b)\nprint(int(var_d))"
    },
    "6974": {
        "category": "Geometry",
        "question_ko": "동상을 정사각형 모양으로 빈틈없이 정렬하여 세워 보니 6개의 동상이 남았습니다. 그래서 가로 한 변과 세로 한 변을 1열씩 늘리려 하였지만 11개의 동상이 부족하였습니다. 이 동상들을 7열로 세운다면 1열에 몇 개씩 있겠습니까?",
        "question_en": "After arranging the statues in a square shape and erecting them, there were six statues left. So, I tried to increase the horizontal and vertical sides by one row each, but i was short of 11 statues. If you put these statues in 7 rows, how many statues are in one row?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "6 11 [OP_ADD] 1 [OP_SUB] 2 [OP_DIV] 2 [OP_POW] 6 [OP_ADD] 7 [OP_DIV]",
        "solution_abst_en": "6 11 [OP_ADD] 1 [OP_SUB] 2 [OP_DIV] 2 [OP_POW] 6 [OP_ADD] 7 [OP_DIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 11\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 6\nvar_k = var_i + var_j\nvar_l = 7\nvar_m = var_k / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 6\nvar_b = 11\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 6\nvar_k = var_i + var_j\nvar_l = 7\nvar_m = var_k / var_l\nprint(int(var_m))"
    },
    "6975": {
        "category": "Arithmetic calculation",
        "question_ko": "(가) 물건을 호석이는 1시간에 27개 만들고, 정국이는 1시간에 32개 만듭니다. (가) 물건을 호석이와 정국이가 같은 빠르기로 6시간 동안 만들었다면, 정국이는 호석이보다 몇 개 더 만들었습니까?",
        "question_en": "Hoseok makes 27 A items in an hour, and Jungkook makes 32 A items in an hour. If Hoseok and Jungkook made A item at the same speed in 6 hours, how many more did Jungkook make than Hoseok?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "32 27 [OP_SUB] 6 [OP_MUL]",
        "solution_abst_en": "32 27 [OP_SUB] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 32\nvar_b = 27\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 32\nvar_b = 27\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "6976": {
        "category": "Geometry",
        "question_ko": "오각기둥의 각 면에 서로 다른 색을 칠하려고 합니다. 사용된 색은 모두 몇 가지입니까?",
        "question_en": "You want to paint different colors on each face of the pentagon. How many colors will be used?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "2 5 [OP_ADD]",
        "solution_abst_en": "2 5 [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "6977": {
        "category": "Correspondence",
        "question_ko": "효재는 친구네 집을 가면서 전체 거리의 2/5보다 300미터(m) 많은 거리를 지하철로 이동하고 나머지의 1/2보다 200미터(m)적은 거리를 택시를 이용하고, 나머지 800미터(m)를 걸어서 목적지에 도착했다고 한다. 효재가 친구네 집을 가기 위해 이동한 전체 거리는 몇 킬로미터(㎞)인지 구하시오.",
        "question_en": "Hyo-jae went to a friend's house, by travelling 300 meters (m) more than 2/5 of the total distance by subway, 200 meters (m) less than 1/2 of the remaining distance by taxi, and the remaining 800 meters (m) on foot. Find the total distance in kilometers (km) that Hyo-jae traveled to go to his friend's house.",
        "answer_ko": "2.50",
        "answer_en": "2.5",
        "solution_abst_ko": "800 200 [OP_SUB] 1 1/2 [OP_SUB] [OP_DIV] 300 [OP_ADD] 1 2/5 [OP_SUB] [OP_DIV] 1000 [OP_DIV]",
        "solution_abst_en": "800 200 [OP_SUB] 1 1/2 [OP_SUB] [OP_DIV] 300 [OP_ADD] 1 2/5 [OP_SUB] [OP_DIV] 1000 [OP_DIV]",
        "solution_code_ko": "var_a = 800\nvar_b = 200\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = 0.5\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 300\nvar_i = var_g + var_h\nvar_j = 1\nvar_k = 0.4\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nvar_n = 1000\nvar_o = var_m / var_n\nprint('{:.2f}'.format(round(var_o+1e-10,2)))",
        "solution_code_en": "var_a = 800\nvar_b = 200\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = 0.5\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 300\nvar_i = var_g + var_h\nvar_j = 1\nvar_k = 0.4\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nvar_n = 1000\nvar_o = var_m / var_n\nprint('{:.2f}'.format(round(var_o+1e-10,2)))"
    },
    "6978": {
        "category": "Arithmetic calculation",
        "question_ko": "6의 배수이면서 30이상 50이하인 수의 개수를 구하시오.",
        "question_en": "Find the number of numbers that are multiples of 6 and are not less than 30 and not more than 50.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "1 9999 1 [OP_LIST_ARANGE] 30 [OP_LIST_MORE_EQUAL] 50 [OP_LIST_LESS_EQUAL] 6 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "1 9999 1 [OP_LIST_ARANGE] 30 [OP_LIST_MORE_EQUAL] 50 [OP_LIST_LESS_EQUAL] 6 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 30\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nvar_e = 50\nlist_c = []\nfor i in list_b:\n    if i <= var_e:\n        list_c.append(i)\nvar_f = 6\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 30\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nvar_e = 50\nlist_c = []\nfor i in list_b:\n    if i <= var_e:\n        list_c.append(i)\nvar_f = 6\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))"
    },
    "6979": {
        "category": "Arithmetic calculation",
        "question_ko": "여학생이 남학생보다 38명 더 많은 (가) 학교가 있습니다. (가) 학교의 여학생이 658명이라고 할 때, 17명의 학생이 결석했다면 학교에 온 학생의 총 수는?",
        "question_en": "There is a (a) school where there are 38 more female students than male students. If there are 658 female students in the (a) school, what is the total number of students who came to (a) school if 17 students were absent?",
        "answer_ko": "1261",
        "answer_en": "1261",
        "solution_abst_ko": "658 658 38 [OP_SUB] [OP_ADD] 17 [OP_SUB]",
        "solution_abst_en": "658 658 38 [OP_SUB] [OP_ADD] 17 [OP_SUB]",
        "solution_code_ko": "var_a = 658\nvar_b = 658\nvar_c = 38\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 17\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 658\nvar_b = 658\nvar_c = 38\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 17\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "6980": {
        "category": "Geometry",
        "question_ko": "길이가 20센티미터(㎝)인 철사로 한 변의 길이가 6센티미터(㎝)이고 나머지 두 변의 길이가 같은 가장 큰 이등변삼각형을 만들려고 합니다. 다른 한 변의 길이를 몇 센티미터(㎝)로 하면 됩니까?",
        "question_en": "You want to make the largest isosceles triangle with one side 6 centimeters (cm) long and the other two sides equal in length, with a piece of wire 20 centimeters (cm) long. How many centimeters (cm) should the length of the other side be?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "20 6 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "20 6 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 20\nvar_b = 6\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 6\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "6981": {
        "category": "Geometry",
        "question_ko": "3센티미터(㎝) 길이의 모서리를 갖는 정육면체에서 부피가 1세제곱센티미터(㎤)인 정육면체를 꼭짓점의 개수만큼 잘라냈다. 남는 부분의 부피를 구하여라.",
        "question_en": "A cube with a volume of 1 cubic centimeter (cm3) was cut by the number of vertexes from a cube with one edge 3 centimeters (cm) long. Find the volume of the remaining part.",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "3 3 [OP_POW] 1 3 [OP_POW] 8 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "3 3 [OP_POW] 1 3 [OP_POW] 8 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 3\nvar_b = 3\nvar_c = var_a ** var_b\nvar_d = 1\nvar_e = 3\nvar_f = var_d ** var_e\nvar_g = 8\nvar_h = var_f * var_g\nvar_i = var_c - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 3\nvar_b = 3\nvar_c = var_a ** var_b\nvar_d = 1\nvar_e = 3\nvar_f = var_d ** var_e\nvar_g = 8\nvar_h = var_f * var_g\nvar_i = var_c - var_h\nprint(int(var_i))"
    },
    "6982": {
        "category": "Arithmetic calculation",
        "question_ko": "유정이 가진 나무도막의 길이는 31미터(m)보다 30센티미터(㎝) 깁니다. 유정이가 가진 나무도막의 길이를 미터(m)로 써보시오",
        "question_en": "The length of the wooden block that Yujung has is 30 centimeters (cm) longer than 31 meters (m). Write the length in meters (m) of the wooden block that Yujung has.",
        "answer_ko": "31.30",
        "answer_en": "31.3",
        "solution_abst_ko": "31 30 100 [OP_DIV] [OP_ADD]",
        "solution_abst_en": "31 30 100 [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 31\nvar_b = 30\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 31\nvar_b = 30\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "6983": {
        "category": "Comparison",
        "question_ko": "빨간 상자 1개의 높이는 4.2센티미터(㎝)로 모두 같고, 노란 상자 1개의 높이는 3.3센티미터(㎝)로 모두 같습니다. 현정이는 빨간 상자 15개를 한 줄로 높게 쌓았고, 슬기는 노란 상자 20개를 한 줄로 높게 쌓았습니다. 상자를 더 높게 쌓은 사람은 누구입니까?",
        "question_en": "All of the heights of a red box is 4.2 centimeters (cm), and all of the heights of a yellow box is 3.3 centimeters (cm). Hyunjeong stacked up 15 red boxes, and Seulgi stacked up 20 yellow boxes. Who stacked the boxes up higher?",
        "answer_ko": "슬기",
        "answer_en": "Seulgi",
        "solution_abst_ko": "[OP_LIST_SOL] 현정 슬기 [OP_LIST_EOL] [OP_LIST_SOL] 4.2 15 [OP_MUL] 3.3 20 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Hyunjeong Seulgi [OP_LIST_EOL] [OP_LIST_SOL] 4.2 15 [OP_MUL] 3.3 20 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '현정'\nvar_b = '슬기'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4.2\nvar_d = 15\nvar_e = var_c * var_d\nvar_f = 3.3\nvar_g = 20\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Hyunjeong'\nvar_b = 'Seulgi'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4.2\nvar_d = 15\nvar_e = var_c * var_d\nvar_f = 3.3\nvar_g = 20\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "6984": {
        "category": "Arithmetic calculation",
        "question_ko": "교실에 남학생이 여학생보다 5명 더 많이 있었습니다. 나중에 3명의 남학생과 10명의 여학생이 교실에 더 와서 여학생은 모두 22명이 되었습니다. 지금 교실에 있는 남학생은 몇 명입니까?",
        "question_en": "There were 5 more boys than girls in the classroom. Later, 3 more boys and 10 girls joined the class, bringing the total number of girls up to 22. How many boys are in the classroom now?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "22 10 [OP_SUB] 5 [OP_ADD] 3 [OP_ADD]",
        "solution_abst_en": "22 10 [OP_SUB] 5 [OP_ADD] 3 [OP_ADD]",
        "solution_code_ko": "var_a = 22\nvar_b = 10\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 22\nvar_b = 10\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "6985": {
        "category": "Correspondence",
        "question_ko": "170에서 8을 뺀 값과 120에서 12를 뺀 값은 모두 어떤 수의 배수이고 268을 어떤 수로 나눈 나머지는 어떤 수에서 2를 뺀 값이다. 어떤 수를 구하시오.",
        "question_en": "Both 170 minus 8 and 120 minus 12 are multiples of a certain number, and the remainder of 268 divided by the number is the number minus 2. Find the number.",
        "answer_ko": "54",
        "answer_en": "54",
        "solution_abst_ko": "170 8 [OP_SUB] 268 2 [OP_ADD] [OP_GCD] 120 12 [OP_SUB] [OP_GCD]",
        "solution_abst_en": "170 8 [OP_SUB] 268 2 [OP_ADD] [OP_GCD] 120 12 [OP_SUB] [OP_GCD]",
        "solution_code_ko": "var_a = 170\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 268\nvar_e = 2\nvar_f = var_d + var_e\nvar_g = math.gcd(int(var_f), int(var_c))\nvar_h = 120\nvar_i = 12\nvar_j = var_h - var_i\nvar_k = math.gcd(int(var_j), int(var_g))\nprint(int(var_k))",
        "solution_code_en": "var_a = 170\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 268\nvar_e = 2\nvar_f = var_d + var_e\nvar_g = math.gcd(int(var_f), int(var_c))\nvar_h = 120\nvar_i = 12\nvar_j = var_h - var_i\nvar_k = math.gcd(int(var_j), int(var_g))\nprint(int(var_k))"
    },
    "6986": {
        "category": "Correspondence",
        "question_ko": "4를 어떤 수에 나누어야 할 것을 잘못하여 20을 어떤 수에 뺀 결과는 52가 나옵니다. 바르게 계산하면 얼마인가요?",
        "question_en": "By mistakenly subtracting 20 from a number gives 52, when 4 should have divided by a number. How much do you get when you calculate it correctly?",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "52 20 [OP_ADD] 4 [OP_DIV]",
        "solution_abst_en": "52 20 [OP_ADD] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 52\nvar_b = 20\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 52\nvar_b = 20\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "6987": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 10, 11, 12, 13이 있습니다. 그 중에서 3번째로 큰 수와 2번째로 큰 수로 나눈 값은 얼마입니까?",
        "question_en": "There are four numbers 10, 11, 12, and 13. Divide the 3rd largest number by the 2nd largest number.",
        "answer_ko": "0.92",
        "answer_en": "0.92",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 3 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_DIV]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 3 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = var_f / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = var_f / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "6988": {
        "category": "Correspondence",
        "question_ko": "어떤 수는 8과 9의 곱에서 12를 뺀 값의 절반이다. 어떤 수를 35에서 빼면 얼마인지 구하시오.",
        "question_en": "The number is half the product of 8 and 9 minus 12. What is the answer if the number is subtracted from 35?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "35 8 9 [OP_MUL] 12 [OP_SUB] 2 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "35 8 9 [OP_MUL] 12 [OP_SUB] 2 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 35\nvar_b = 8\nvar_c = 9\nvar_d = var_b * var_c\nvar_e = 12\nvar_f = var_d - var_e\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = var_a - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 35\nvar_b = 8\nvar_c = 9\nvar_d = var_b * var_c\nvar_e = 12\nvar_f = var_d - var_e\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = var_a - var_h\nprint(int(var_i))"
    },
    "6989": {
        "category": "Arithmetic calculation",
        "question_ko": "현수네 집과 승아네 집은 2킬로미터(㎞) 100미터(m) 떨어져 있습니다. 현수와 승아가 각자의 집 사이 어딘가에서 만나기로 했을 때, 현수가 승아보다 200미터(m) 더 걸었다면 현수가 걸은 거리는 총 몇 킬로미터(㎞)입니까?",
        "question_en": "Hyeonsu's house and Seunga's house are 2 kilometers (km) and 100 meters (m) apart. When Hyeonsu and Seunga decided to meet somewhere between their respective houses, if Hyeonsu walked 200 meters (m) longer than Seunga, how many kilometers (km) did Hyeonsu walk in total?",
        "answer_ko": "1150",
        "answer_en": "1150",
        "solution_abst_ko": "2 1000 [OP_MUL] 100 [OP_ADD] 200 [OP_ADD] 2 [OP_DIV]",
        "solution_abst_en": "2 1000 [OP_MUL] 100 [OP_ADD] 200 [OP_ADD] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = var_c + var_d\nvar_f = 200\nvar_g = var_e + var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = var_c + var_d\nvar_f = 200\nvar_g = var_e + var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "6990": {
        "category": "Comparison",
        "question_ko": "유정이, 은지, 유나는 물을 마시는 양을 기록하고 있습니다. 유정이가 7/10 7/10리터(L), 은지가 0.5리터(L)를 마셨습니다. 유나가 6/10리터(L)를 마셨다면, 물을 가장 많이 마신 사람은 누구입니까?",
        "question_en": "Yoojeong, Eunji, and Yuna keep track of how much water they drink. Yoojeong drank 7/10 liters (L), and Eunji drank 0.5 liters (L). If Yuna drank 6/10 liters (L), who drank the most water?",
        "answer_ko": "유정",
        "answer_en": "Yoojeong",
        "solution_abst_ko": "[OP_LIST_SOL] 유정 은지 유나 [OP_LIST_EOL] [OP_LIST_SOL] 7 10 [OP_DIV] 0.5 6 10 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoojeong Eunji Yuna [OP_LIST_EOL] [OP_LIST_SOL] 7 10 [OP_DIV] 0.5 6 10 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '유정'\nvar_b = '은지'\nvar_c = '유나'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 7\nvar_e = 10\nvar_f = var_d / var_e\nvar_g = 0.5\nvar_h = 6\nvar_i = 10\nvar_j = var_h / var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'Yoojeong'\nvar_b = 'Eunji'\nvar_c = 'Yuna'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 7\nvar_e = 10\nvar_f = var_d / var_e\nvar_g = 0.5\nvar_h = 6\nvar_i = 10\nvar_j = var_h / var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "6991": {
        "category": "Possibility",
        "question_ko": "소설책 2권, 수필책 3권을 책꽂이에 꽂을 때, 소설책끼리는 반드시 이웃하게 세우는 경우의 수를 구하시오.",
        "question_en": "When 2 novels and 3 essays are placed on a bookshelf, find the number of cases in which the novels must be placed next to each other.",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "1 3 [OP_ADD] 1 3 [OP_ADD] [OP_PERM] 2 2 [OP_PERM] [OP_MUL]",
        "solution_abst_en": "1 3 [OP_ADD] 1 3 [OP_ADD] [OP_PERM] 2 2 [OP_PERM] [OP_MUL]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = 1\nvar_c = int(var_c)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_c-i)\nvar_h = 2\nvar_i = 2\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nvar_k = var_g * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = 1\nvar_c = int(var_c)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_c-i)\nvar_h = 2\nvar_i = 2\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nvar_k = var_g * var_j\nprint(int(var_k))"
    },
    "6992": {
        "category": "Geometry",
        "question_ko": "반지름이 2센티미터(㎝)인 원을 겹치지 않게 종이 안에 최대한 많이 그리고자 합니다. 주어진 종이가 가로 20센티미터(㎝), 세로 16센티미터(㎝)라면 몇 개까지 그릴 수 있습니까?",
        "question_en": "You are going to draw as many circles with a radius of 2 centimeters (cm) on the paper as possible without overlapping them. If the given piece of paper is 20 centimeters (cm) wide and 16 centimeters (cm) long, how many can you draw?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "20 2 2 [OP_MUL] [OP_FDIV] 16 2 2 [OP_MUL] [OP_FDIV] [OP_MUL]",
        "solution_abst_en": "20 2 2 [OP_MUL] [OP_FDIV] 16 2 2 [OP_MUL] [OP_FDIV] [OP_MUL]",
        "solution_code_ko": "var_a = 20\nvar_b = 2\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a // var_d\nvar_f = 16\nvar_g = 2\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = var_f // var_i\nvar_k = var_e * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 20\nvar_b = 2\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a // var_d\nvar_f = 16\nvar_g = 2\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = var_f // var_i\nvar_k = var_e * var_j\nprint(int(var_k))"
    },
    "6993": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 6/4를 곱하고 다시 9/4를 곱하면 18/5가 된다. 어떤 수를 구하시오.",
        "question_en": "If you multiply a number by 6/4 and then by 9/4, you get 18/5. Find the number.",
        "answer_ko": "0.71",
        "answer_en": "0.71",
        "solution_abst_ko": "18/5 9/4 [OP_DIV] 9/4 [OP_DIV]",
        "solution_abst_en": "18/5 9/4 [OP_DIV] 9/4 [OP_DIV]",
        "solution_code_ko": "var_a = 3.6\nvar_b = 2.25\nvar_c = var_a / var_b\nvar_d = 2.25\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 3.6\nvar_b = 2.25\nvar_c = var_a / var_b\nvar_d = 2.25\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "6994": {
        "category": "Geometry",
        "question_ko": "미영이는 한 모서리의 길이가 3센티미터(㎝)인 정육면체 모양의 상자를 27개 가지고 있습니다. 이 상자들을 쌓아 다시 큰 정육면체 모양을 만들었습니다. 큰 정육면체의 겉넓이를 구하시오.",
        "question_en": "Miyoung has 27 cube-shaped boxes with 3 centimeters (cm) edges. These boxes were stacked to form a large cube again. Find the surface area of the large cube.",
        "answer_ko": "486",
        "answer_en": "486",
        "solution_abst_ko": "3 27 1/3 [OP_POW] [OP_MUL] 2 [OP_POW] 6 [OP_MUL]",
        "solution_abst_en": "3 27 1/3 [OP_POW] [OP_MUL] 2 [OP_POW] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 27\nvar_c = 0.3333333333333333\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e ** var_f\nvar_h = 6\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 3\nvar_b = 27\nvar_c = 0.3333333333333333\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e ** var_f\nvar_h = 6\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "6995": {
        "category": "Arithmetic calculation",
        "question_ko": "(나) 나무 수의 2배 만큼 (가) 나무가 있고, (가) 나무는 (다) 나무보다 15그루 더 적습니다. (다) 나무가 47그루 있을 때, (가), (나), (다), 나무는 모두 몇 그루 있습니까?",
        "question_en": "(a) trees are twice as many trees as (b) trees, and (a) trees are 15 fewer trees than (c) trees. If there are 47 (c) trees, how many (a), (b), (c) trees are there in all?",
        "answer_ko": "95",
        "answer_en": "95",
        "solution_abst_ko": "47 15 [OP_SUB] 47 15 [OP_SUB] 2 [OP_DIV] [OP_ADD] 47 [OP_ADD]",
        "solution_abst_en": "47 15 [OP_SUB] 47 15 [OP_SUB] 2 [OP_DIV] [OP_ADD] 47 [OP_ADD]",
        "solution_code_ko": "var_a = 47\nvar_b = 15\nvar_c = var_a - var_b\nvar_d = 47\nvar_e = 15\nvar_f = var_d - var_e\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = var_c + var_h\nvar_j = 47\nvar_k = var_i + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 47\nvar_b = 15\nvar_c = var_a - var_b\nvar_d = 47\nvar_e = 15\nvar_f = var_d - var_e\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = var_c + var_h\nvar_j = 47\nvar_k = var_i + var_j\nprint(int(var_k))"
    },
    "6996": {
        "category": "Correspondence",
        "question_ko": "어떤 수는 20보다 작지만 2의 배수는 아닙니다. 16, 18, 19, 21 중 어떤 수를 구하시오.",
        "question_en": "Some numbers are less than 20 but not multiples of 2. Find which number it is from 16, 18, 19, and 21.",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "[OP_LIST_SOL] 16 18 19 21 [OP_LIST_EOL] 2 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] 20 [OP_LIST_LESS] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] 16 18 19 21 [OP_LIST_EOL] 2 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] 20 [OP_LIST_LESS] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 16\nvar_b = 18\nvar_c = 19\nvar_d = 21\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = []\nvar_e = int(var_e)\nfor i in list_a:\n    i = int(i)\n    if i % var_e == 0:\n        list_b.append(i)\nlist_c = list(set(list_a) - set(list_b))\nvar_f = 20\nlist_d = []\nfor i in list_c:\n    if i < var_f:\n        list_d.append(i)\nvar_g = 1\nvar_h = list_d[var_g-1]\nprint(int(var_h))",
        "solution_code_en": "var_a = 16\nvar_b = 18\nvar_c = 19\nvar_d = 21\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = []\nvar_e = int(var_e)\nfor i in list_a:\n    i = int(i)\n    if i % var_e == 0:\n        list_b.append(i)\nlist_c = list(set(list_a) - set(list_b))\nvar_f = 20\nlist_d = []\nfor i in list_c:\n    if i < var_f:\n        list_d.append(i)\nvar_g = 1\nvar_h = list_d[var_g-1]\nprint(int(var_h))"
    },
    "6997": {
        "category": "Arithmetic calculation",
        "question_ko": "동진이는 가진 돈의 1/2을 사용하여 귤 한 봉지를 샀습니다. 귤을 사고 남은 돈의 3/8은 동생에게 줬습니다. 현재 동진이가 가진 돈이 2500원 일 때, 동진이가 산 귤은 한 봉지에 얼마인지 구하세요.",
        "question_en": "Dong-jin bought a bag of tangerines with 1/2 of his money. He gave 3/8 of the money left over from buying tangerines to his younger brother. If Dong-jin's current money is 2,500 won, how much is the tangerine he bought per bag?",
        "answer_ko": "4000",
        "answer_en": "4000",
        "solution_abst_ko": "2500 1 3/8 [OP_SUB] [OP_DIV] 1/2 [OP_DIV] 1/2 [OP_MUL]",
        "solution_abst_en": "2500 1 3/8 [OP_SUB] [OP_DIV] 1/2 [OP_DIV] 1/2 [OP_MUL]",
        "solution_code_ko": "var_a = 2500\nvar_b = 1\nvar_c = 0.375\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 0.5\nvar_g = var_e / var_f\nvar_h = 0.5\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 2500\nvar_b = 1\nvar_c = 0.375\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 0.5\nvar_g = var_e / var_f\nvar_h = 0.5\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "6998": {
        "category": "Geometry",
        "question_ko": "모든 변의 길이의 합이 154센티미터(㎝)인 정십사각형의 한 변의 길이는 몇 센티미터(㎝)인가?",
        "question_en": "How many centimeters (cm) is the length of one side of a regular tetradecagon if the sum of all the sides is 154 centimeters (cm)?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "154 14 [OP_DIV]",
        "solution_abst_en": "154 14 [OP_DIV]",
        "solution_code_ko": "var_a = 154\nvar_b = 14\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 154\nvar_b = 14\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "6999": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 3으로 나눈 값에 12를 더하면 20이 됩니다. 어떤 수를 구하시오.",
        "question_en": "Any number divided by 3 plus 12 equals 20. Find the number that satisfies the condition.",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "20 12 [OP_SUB] 3 [OP_MUL]",
        "solution_abst_en": "20 12 [OP_SUB] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 20\nvar_b = 12\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 12\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "7000": {
        "category": "Geometry",
        "question_ko": "정우는 큐브의 부피를 구하고 싶다. 큐브는 정육면체 모양이고, 겉넓이는 150제곱센티미터(㎠)이다. 답은 얼마인가?",
        "question_en": "Jung-woo wants to find the volume of a cube. The cube is in the shape of a cube and has a surface area of 150 square centimeters (cm2). How much is the answer?",
        "answer_ko": "125",
        "answer_en": "125",
        "solution_abst_ko": "150 6 [OP_DIV] 1/2 [OP_POW] 3 [OP_POW]",
        "solution_abst_en": "150 6 [OP_DIV] 1/2 [OP_POW] 3 [OP_POW]",
        "solution_code_ko": "var_a = 150\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 3\nvar_g = var_e ** var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 150\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 3\nvar_g = var_e ** var_f\nprint(int(var_g))"
    },
    "7001": {
        "category": "Possibility",
        "question_ko": "4개의 숫자 카드 0, 1, 4, 8을 한 번씩 사용하여 일의 자리 숫자가 8인 세 번째 큰 세 자리 수를 구하시오.",
        "question_en": "Using the four number cards 0, 1, 4, and 8 once each, find the third largest three-digit number with the ones digit of 8.",
        "answer_ko": "148",
        "answer_en": "148",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 4 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 8 [OP_LIST_SEARCH_FIXED_DIGIT] 3 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 4 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 8 [OP_LIST_SEARCH_FIXED_DIGIT] 3 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 4\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nvar_g = 8\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 3\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nprint(int(var_i))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 4\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nvar_g = 8\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 3\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nprint(int(var_i))"
    },
    "7002": {
        "category": "Correspondence",
        "question_ko": "A4+B82=216입니다. B는 얼마인가요?",
        "question_en": "A4+B82=216. How much is B?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "A4+B82=216 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A4+B82=216 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A4+B82=216'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A4+B82=216'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "7003": {
        "category": "Geometry",
        "question_ko": "정사면체에서 면의 수는 모두 몇개인가요?",
        "question_en": "What is the total number of faces in a tetrahedron?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "4",
        "solution_abst_en": "4",
        "solution_code_ko": "var_a = 4\nprint(int(var_a))",
        "solution_code_en": "var_a = 4\nprint(int(var_a))"
    },
    "7004": {
        "category": "Correspondence",
        "question_ko": "선미의 국어 점수는 40점이다. 선미의 국어 점수와 수학 점수의 합에 5배를 하면 555이다. 수학 점수에 7배를 한 후 55를 빼면 얼마인지 구하시오.",
        "question_en": "Sunmi's Korean language score is 40 points. The sum of Sunmi's Korean language score and math score is multiplied by 5 to get 555. Multiply her math score by 7 and then subtract 55 to find what it is.",
        "answer_ko": "442",
        "answer_en": "442",
        "solution_abst_ko": "555 5 [OP_DIV] 40 [OP_SUB] 7 [OP_MUL] 55 [OP_SUB]",
        "solution_abst_en": "555 5 [OP_DIV] 40 [OP_SUB] 7 [OP_MUL] 55 [OP_SUB]",
        "solution_code_ko": "var_a = 555\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 40\nvar_e = var_c - var_d\nvar_f = 7\nvar_g = var_e * var_f\nvar_h = 55\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 555\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 40\nvar_e = var_c - var_d\nvar_f = 7\nvar_g = var_e * var_f\nvar_h = 55\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "7005": {
        "category": "Correspondence",
        "question_ko": "34를 자연수 A로 나눴더니 나머지가 4, 몫이 6이 되었습니다. A에 알맞은 값을 구하시오.",
        "question_en": "When 34 is divided by the natural number A, the remainder is 4 and the quotient is 6. Find the right value for A.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "34 4 [OP_SUB] 6 [OP_DIV]",
        "solution_abst_en": "34 4 [OP_SUB] 6 [OP_DIV]",
        "solution_code_ko": "var_a = 34\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 34\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "7006": {
        "category": "Arithmetic calculation",
        "question_ko": "석진이가 100장의 종이를 가지고 있었습니다. 이 종이로 30장짜리 공책을 3권 만들었다면 종이는 몇 장 남아 있습니까?",
        "question_en": "Seokjin had 100 sheets of paper. If he made 3 notebooks of 30 pages with this paper, how many sheets of paper are left?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "100 30 3 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "100 30 3 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 100\nvar_b = 30\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 100\nvar_b = 30\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "7007": {
        "category": "Geometry",
        "question_ko": "12개의 변으로 둘러싸인 도형의 한 꼭짓점에서 그을 수 있는 대각선은 몇 개인지 구하시오.",
        "question_en": "Find the number of diagonals drawn from the vertex of a figure enclosed by 12 sides.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "12 3 [OP_SUB]",
        "solution_abst_en": "12 3 [OP_SUB]",
        "solution_code_ko": "var_a = 12\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 12\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "7008": {
        "category": "Geometry",
        "question_ko": "모서리의 길이가 5센티미터(㎝)인 정육면체 2개의 부피의 합을 구하라.",
        "question_en": "Find the sum of the volumes of two cubes whose edges are 5 centimeters (cm) long.",
        "answer_ko": "250",
        "answer_en": "250",
        "solution_abst_ko": "5 5 2 [OP_MUL] [OP_MUL] 5 [OP_MUL]",
        "solution_abst_en": "5 5 2 [OP_MUL] [OP_MUL] 5 [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 5\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nvar_f = 5\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 5\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nvar_f = 5\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "7009": {
        "category": "Comparison",
        "question_ko": "사람들이 한 줄로 섰을 때 맨 앞에 서 있는 사람과 맨 뒤에 서있는 사람 사이에 5명이 서 있습니다. 줄을 선 사람은 모두 몇 명입니까?",
        "question_en": "When people stand in a line, there are 5 people standing between the person standing at the front and the person standing at the tail. How many people are in line?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "5 2 [OP_ADD]",
        "solution_abst_en": "5 2 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "7010": {
        "category": "Correspondence",
        "question_ko": "60개가 있는 학용품의 종류에는 연필, 공책, 지우개, 볼펜이 있다. 연필이 5개, 공책이 10개, 지우개가 32개 있다면 볼펜은 몇 개가 있는지 구하시오.",
        "question_en": "There are 60 kinds of school supplies, such as pencils, notebooks, erasers, and ballpoint pens. If there are 5 pencils, 10 notebooks, and 32 erasers, how many ballpoint pens are there?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "60 32 [OP_SUB] 10 [OP_SUB] 5 [OP_SUB]",
        "solution_abst_en": "60 32 [OP_SUB] 10 [OP_SUB] 5 [OP_SUB]",
        "solution_code_ko": "var_a = 60\nvar_b = 32\nvar_c = var_a - var_b\nvar_d = 10\nvar_e = var_c - var_d\nvar_f = 5\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 60\nvar_b = 32\nvar_c = var_a - var_b\nvar_d = 10\nvar_e = var_c - var_d\nvar_f = 5\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "7011": {
        "category": "Correspondence",
        "question_ko": "서로 다른 두 수 A와 B가 덧셈식 AB+25=B3을 만족한다면, B는 무엇입니까?",
        "question_en": "If two different numbers A and B satisfy the addition expression AB+25=B3, what is B?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "AB+25=B3 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "AB+25=B3 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'AB+25=B3'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'AB+25=B3'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "7012": {
        "category": "Geometry",
        "question_ko": "수지는 한 변의 길이가 6센티미터(㎝)인 정사각형 모양의 색종이를 갖고 있습니다. 이 색종이의 네 변에 각각 1센티미터(㎝)인 색종이를 더 붙였습니다. 이 색종이의 넓이는 처음보다 얼마나 더 늘어났습니까?",
        "question_en": "Suzy has a piece of colored paper in the shape of a square with each side measuring 6 centimeters (cm). By using additional colored paper, Suzy make the square's side 1cm larger. How much did the area of this colored paper increase than it was at first?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "6 1 [OP_ADD] 2 [OP_POW] 6 2 [OP_POW] [OP_SUB]",
        "solution_abst_en": "6 1 [OP_ADD] 2 [OP_POW] 6 2 [OP_POW] [OP_SUB]",
        "solution_code_ko": "var_a = 6\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 6\nvar_g = 2\nvar_h = var_f ** var_g\nvar_i = var_e - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 6\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 6\nvar_g = 2\nvar_h = var_f ** var_g\nvar_i = var_e - var_h\nprint(int(var_i))"
    },
    "7013": {
        "category": "Geometry",
        "question_ko": "가로가 480센티미터(㎝), 세로가 360센티미터(㎝)인 직사각형의 둘레는 몇 미터(m)인지 소수점 둘째 자리에서 반올림하여 나타내시오.",
        "question_en": "How many meters (m) are the circumference of a rectangle with 480 centimeters (cm) wide and 360 centimeters (cm) long, rounding up to the tenth digit?",
        "answer_ko": "16.80",
        "answer_en": "16.8",
        "solution_abst_ko": "480 100 [OP_DIV] 360 100 [OP_DIV] [OP_ADD] 2 [OP_MUL] 2 [OP_ROUND]",
        "solution_abst_en": "480 100 [OP_DIV] 360 100 [OP_DIV] [OP_ADD] 2 [OP_MUL] 2 [OP_ROUND]",
        "solution_code_ko": "var_a = 480\nvar_b = 100\nvar_c = var_a / var_b\nvar_d = 360\nvar_e = 100\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = 2\nvar_k = round(float(var_i)+1e-10, var_j)\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 480\nvar_b = 100\nvar_c = var_a / var_b\nvar_d = 360\nvar_e = 100\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = 2\nvar_k = round(float(var_i)+1e-10, var_j)\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "7014": {
        "category": "Arithmetic calculation",
        "question_ko": "(가) 물병에는 3.8리터(L)의 물이 들어있고, (나) 물병에는 (가) 물병보다 8.4리터(L)의 물이 더 들어있습니다. (다) 물병에는 (나) 물병의 물의 1/10보다 3720밀리리터(㎖) 더 들어있을 때 (다) 물병에 들어있는 물은 몇 리터(L)입니까?",
        "question_en": "The water bottle A contains 3.8 liters (L) of water, and the water bottle B contains 8.4 liters (L) more water than A. When the water bottle C contains 3720 milliliters (㎖) more than 1/10 of the water in B, how many liters (L) of water are in the water bottle C?",
        "answer_ko": "4.94",
        "answer_en": "4.94",
        "solution_abst_ko": "3.8 8.4 [OP_ADD] 1/10 [OP_MUL] 3720 1000 [OP_DIV] [OP_ADD]",
        "solution_abst_en": "3.8 8.4 [OP_ADD] 1/10 [OP_MUL] 3720 1000 [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 3.8\nvar_b = 8.4\nvar_c = var_a + var_b\nvar_d = 0.1\nvar_e = var_c * var_d\nvar_f = 3720\nvar_g = 1000\nvar_h = var_f / var_g\nvar_i = var_e + var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 3.8\nvar_b = 8.4\nvar_c = var_a + var_b\nvar_d = 0.1\nvar_e = var_c * var_d\nvar_f = 3720\nvar_g = 1000\nvar_h = var_f / var_g\nvar_i = var_e + var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "7015": {
        "category": "Geometry",
        "question_ko": "수지는 작은 정육면체 8개로 부피가 1000세제곱센티미터(㎤)인 큰 정육면체를 만들었습니다. 작은 정육면체의 한 모서리의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "Suzy made a large cube with a volume of 1000 cubic centimeters (cm3) from 8 small cubes. How many centimeters (cm) is the length of one edge of the small cube?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "1000 8 [OP_DIV] 1/3 [OP_POW]",
        "solution_abst_en": "1000 8 [OP_DIV] 1/3 [OP_POW]",
        "solution_code_ko": "var_a = 1000\nvar_b = 8\nvar_c = var_a / var_b\nvar_d = 0.3333333333333333\nvar_e = var_c ** var_d\nprint(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))",
        "solution_code_en": "var_a = 1000\nvar_b = 8\nvar_c = var_a / var_b\nvar_d = 0.3333333333333333\nvar_e = var_c ** var_d\nprint(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))"
    },
    "7016": {
        "category": "Geometry",
        "question_ko": "삼각형과 사각형의 변의 수의 합은 몇 개입니까?",
        "question_en": "What is the sum of the number of edges of a triangle, and a rectangle?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "3 4 [OP_ADD]",
        "solution_abst_en": "3 4 [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 4\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 4\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "7017": {
        "category": "Arithmetic calculation",
        "question_ko": "가로의 길이가 25센티미터(㎝) 새로가 30센티미터(㎝)인 색종이가 있다. 이 색종이 15장을 벽에 가로로 붙이되 0.5센티미터(㎝)씩 겹쳐서 붙힌다. 붙힌 색종이의 가로 길이는 몇 미터(m) 인지 구하시오.",
        "question_en": "There is colored paper that is 25 centimeters (cm) wide and 30 centimeters (cm) long. When 15 pieces of this colored paper are attached horizontally to the wall, overlapping each other by 0.5 cm, find the horizontal length in meters (m) of the glued colored paper.",
        "answer_ko": "3.68",
        "answer_en": "3.68",
        "solution_abst_ko": "25 25 0.5 [OP_SUB] 15 1 [OP_SUB] [OP_MUL] [OP_ADD] 100 [OP_DIV]",
        "solution_abst_en": "25 25 0.5 [OP_SUB] 15 1 [OP_SUB] [OP_MUL] [OP_ADD] 100 [OP_DIV]",
        "solution_code_ko": "var_a = 25\nvar_b = 25\nvar_c = 0.5\nvar_d = var_b - var_c\nvar_e = 15\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_a + var_h\nvar_j = 100\nvar_k = var_i / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 25\nvar_b = 25\nvar_c = 0.5\nvar_d = var_b - var_c\nvar_e = 15\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_a + var_h\nvar_j = 100\nvar_k = var_i / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "7018": {
        "category": "Comparison",
        "question_ko": "5, 8, 4, 3, 2 중에서 가장 큰 수를 고르세요.",
        "question_en": "Choose the largest number among 5, 8, 4, 3, and 2.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "[OP_LIST_SOL] 5 8 4 3 2 [OP_LIST_EOL] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 5 8 4 3 2 [OP_LIST_EOL] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 5\nvar_b = 8\nvar_c = 4\nvar_d = 3\nvar_e = 2\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 8\nvar_c = 4\nvar_d = 3\nvar_e = 2\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nprint(int(var_g))"
    },
    "7019": {
        "category": "Comparison",
        "question_ko": "지수는 1리터(L) 400밀리리터(㎖) 들이의 사과주스와 2800밀리리터(㎖)의 오렌지주스를 대야에 모두 부었더니 대야가 가득 찼습니다. 들이가 4리터(L) 100밀리리터(㎖)인 물통과 대야 중에서 어느 쪽의 들이가 더 많습니까?",
        "question_en": "Jisoo poured 1 liter (L) and 400 milliliters (㎖) of apple juice and 2800 milliliters (㎖) of orange juice into a bucket, and the bucket was filled up. Which one has more capacity, a bucket or a basin with 4 liters (L) and 100 milliliters (㎖)?",
        "answer_ko": "대야",
        "answer_en": "basin",
        "solution_abst_ko": "[OP_LIST_SOL] 대야 물통 [OP_LIST_EOL] [OP_LIST_SOL] 4 1000 [OP_MUL] 100 [OP_ADD] 2800 1 1000 [OP_MUL] 400 [OP_ADD] [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] basin bucket [OP_LIST_EOL] [OP_LIST_SOL] 4 1000 [OP_MUL] 100 [OP_ADD] 2800 1 1000 [OP_MUL] 400 [OP_ADD] [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '대야'\nvar_b = '물통'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 100\nvar_g = var_e + var_f\nvar_h = 2800\nvar_i = 1\nvar_j = 1000\nvar_k = var_i * var_j\nvar_l = 400\nvar_m = var_k + var_l\nvar_n = var_h + var_m\nlist_b= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_o = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_p = list_c[-var_o]\nvar_q = list_b.index(var_p)+1\nvar_r = list_a[var_q-1]\nprint(var_r)",
        "solution_code_en": "var_a = 'basin'\nvar_b = 'bucket'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 100\nvar_g = var_e + var_f\nvar_h = 2800\nvar_i = 1\nvar_j = 1000\nvar_k = var_i * var_j\nvar_l = 400\nvar_m = var_k + var_l\nvar_n = var_h + var_m\nlist_b= []\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_o = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_p = list_c[-var_o]\nvar_q = list_b.index(var_p)+1\nvar_r = list_a[var_q-1]\nprint(var_r)"
    },
    "7020": {
        "category": "Correspondence",
        "question_ko": "지민이는 34에 어떤 수를 곱하려고 합니다. 실수로 20에 어떤 수를 뺐을 때의 결과가 60이라면 바르게 계산한 결과를 구하세요.",
        "question_en": "Jimin wants to multiply 34 by some number. If the result of subtracting a number from 20 by mistake is 60, find the correct calculation.",
        "answer_ko": "-1360",
        "answer_en": "-1360",
        "solution_abst_ko": "34 20 60 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "34 20 60 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 34\nvar_b = 20\nvar_c = 60\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 34\nvar_b = 20\nvar_c = 60\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nprint(int(var_e))"
    },
    "7021": {
        "category": "Arithmetic calculation",
        "question_ko": "숫자 25, 17, 21, 34, 32 가 있습니다. 가장 큰 수와 가장 작은 수의 차는 얼마입니까?",
        "question_en": "There are numbers 25, 17, 21, 34, and 32. What is the difference between the largest number and the smallest number?",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "[OP_LIST_SOL] 25 17 21 34 32 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 25 17 21 34 32 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 25\nvar_b = 17\nvar_c = 21\nvar_d = 34\nvar_e = 32\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 25\nvar_b = 17\nvar_c = 21\nvar_d = 34\nvar_e = 32\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))"
    },
    "7022": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 90센티미터(㎝)인 정사각형 모양의 창문이 있습니다. 이 창문의 가장자리에 3센티미터(㎝) 간격으로 스티커를 붙여 꾸밀 때, 스티커는 모두 몇 장이 필요한지 구하시오.",
        "question_en": "There is a square-shaped window with a side of 90 centimeters (cm). When decorating the edge of this window with stickers at 3 centimeters (cm) intervals, find how many stickers are needed in total.",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "90 4 [OP_MUL] 3 [OP_FDIV]",
        "solution_abst_en": "90 4 [OP_MUL] 3 [OP_FDIV]",
        "solution_code_ko": "var_a = 90\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 90\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "7023": {
        "category": "Arithmetic calculation",
        "question_ko": "민영이가 우유를 10리터(L) 마시고, 유나는 2/3리터(L) 마셨습니다. 민영이가 마신 우유의 양은 유나가 마신 우유의 양의 몇 배인지 구하시오.",
        "question_en": "Minyoung drank 10 liters (L) of milk, and Yuna drank 2/3 liters (L). Find how many times the amount of milk that Minyoung drank was the amount of milk that Yuna drank.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "10 2/3 [OP_DIV]",
        "solution_abst_en": "10 2/3 [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 0.6666666666666666\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 10\nvar_b = 0.6666666666666666\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "7024": {
        "category": "Possibility",
        "question_ko": "1, 2, 3이 적힌 지우개 중 2개를 뽑아 거기에 적힌 수를 이용해 두 자리 자연수를 만들고자 한다. 몇개를 만들 수 있는가?",
        "question_en": "You want to create a two-digit natural number by drawing two from three erasers with the numbers 1, 2, and 3 written on them. How many can you make?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 1 2 3 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 2 3 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 2\nvar_c = 3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 2\nvar_c = 3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "7025": {
        "category": "Comparison",
        "question_ko": "현주와 승아에게는 같은 양의 물이 있습니다. 현주는 6리터(L)의 0.41배만큼 마셨고, 승아는 2.3리터(L)를 쏟았다면 남아있는 물이 더 적은 사람은 누구입니까?",
        "question_en": "Hyunju and Seungah have the same amount of water. If Hyunju drank 0.41 times 6 liters (L) and Seungah poured 2.3 liters (L), whose remaining water is less?",
        "answer_ko": "현주",
        "answer_en": "Hyunju",
        "solution_abst_ko": "[OP_LIST_SOL] 현주 승아 [OP_LIST_EOL] [OP_LIST_SOL] 6 0.41 [OP_MUL] 2.3 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Hyunju Seunga [OP_LIST_EOL] [OP_LIST_SOL] 6 0.41 [OP_MUL] 2.3 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '현주'\nvar_b = '승아'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 0.41\nvar_e = var_c * var_d\nvar_f = 2.3\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Hyunju'\nvar_b = 'Seunga'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 0.41\nvar_e = var_c * var_d\nvar_f = 2.3\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "7026": {
        "category": "Arithmetic calculation",
        "question_ko": "63명이 자동차 9대에 똑같이 나누어 탔습니다. 자동차 한 대에는 몇 명이 탔습니까?",
        "question_en": "63 people were equally divided into 9 cars. How many people were in one car?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "63 9 [OP_DIV]",
        "solution_abst_en": "63 9 [OP_DIV]",
        "solution_code_ko": "var_a = 63\nvar_b = 9\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 63\nvar_b = 9\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "7027": {
        "category": "Geometry",
        "question_ko": "평행사변형의 넓이가 44제곱센티미터(㎠)이고 높이가 11센티미터(㎝) 일 때, 밑변의 길이를 구하시오.",
        "question_en": "If the area of the parallelogram is 44 square centimeters (cm2) and the height is 11 centimeters (cm), find the length of the base.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "44 11 [OP_DIV]",
        "solution_abst_en": "44 11 [OP_DIV]",
        "solution_code_ko": "var_a = 44\nvar_b = 11\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 44\nvar_b = 11\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "7028": {
        "category": "Arithmetic calculation",
        "question_ko": "다섯 자리 수 중 2, 3, 8, 9의 공배수 중 가장 큰 수는?",
        "question_en": "Which five-digit number is the largest common multiple of 2, 3, 8, and 9?",
        "answer_ko": "99936",
        "answer_en": "99936",
        "solution_abst_ko": "10000 99999 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_abst_en": "10000 99999 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 10000\nvar_b = 99999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 3\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = 1\nlist_f=list_e.copy()\nlist_f.sort()\nvar_i = list_f[-var_h]\nprint(int(var_i))",
        "solution_code_en": "var_a = 10000\nvar_b = 99999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 3\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = 1\nlist_f=list_e.copy()\nlist_f.sort()\nvar_i = list_f[-var_h]\nprint(int(var_i))"
    },
    "7029": {
        "category": "Possibility",
        "question_ko": "0, 1, 2, 3을 하나씩 이용하여 만들 수 있는 두 자리 수는 모두 몇개인가?",
        "question_en": "How many two-digit numbers can be made using only once each of 0, 1, 2, and 3?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "7030": {
        "category": "Arithmetic calculation",
        "question_ko": "백의 자리 숫자가 7, 일의 자리 숫자가 3이면서 3으로 나눈 나머지가 1인 수 중 가장 큰 값을 구하시오.",
        "question_en": "Find the largest number whose hundreds digit is 7, the unit digit is 3, and the remainder when divided by 3 is 1.",
        "answer_ko": "793",
        "answer_en": "793",
        "solution_abst_ko": "7A3 [OP_GEN_POSSIBLE_LIST] 3 1 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MAX]",
        "solution_abst_en": "7A3 [OP_GEN_POSSIBLE_LIST] 3 1 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = '7A3'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 3\nvar_c = 1\nlist_b = [] \nvar_b = int(var_b)\nvar_c = int(var_c)\nif var_c < 0:\n    var_c = var_c + var_b\nfor i in list_a:\n    i = int(i)\n    if i%var_b == var_c:\n        list_b.append(i)\nvar_d = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_e = list_c[-var_d]\nprint(int(var_e))",
        "solution_code_en": "var_a = '7A3'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 3\nvar_c = 1\nlist_b = [] \nvar_b = int(var_b)\nvar_c = int(var_c)\nif var_c < 0:\n    var_c = var_c + var_b\nfor i in list_a:\n    i = int(i)\n    if i%var_b == var_c:\n        list_b.append(i)\nvar_d = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_e = list_c[-var_d]\nprint(int(var_e))"
    },
    "7031": {
        "category": "Arithmetic calculation",
        "question_ko": "물 135.1리터(L)가 있습니다. 이것을 7리터(L)들이 물통으로 나누어 담는다면 물통들을 가득 채우고 남는 양은 몇 리터(L)입니까?",
        "question_en": "There are 135.1 liters (L) of water. If this is divided into 7 liter (L) buckets, how many liters (L) are left after the buckets are filled with water?",
        "answer_ko": "2.10",
        "answer_en": "2.1",
        "solution_abst_ko": "135.1 7 [OP_MOD]",
        "solution_abst_en": "135.1 7 [OP_MOD]",
        "solution_code_ko": "var_a = 135.1\nvar_b = 7\nvar_c = var_a % var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 135.1\nvar_b = 7\nvar_c = var_a % var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "7032": {
        "category": "Comparison",
        "question_ko": "나나의 키는 1.618미터(m)이고, 가은이의 키는 162.3센티미터(㎝)입니다. 키가 더 큰 사람은 누구인지 구하시오.",
        "question_en": "Nana is 1.618 meters (m) tall and Gaeun is 162.3 centimeters (cm) tall. Find out who is taller.",
        "answer_ko": "가은",
        "answer_en": "Gaeun",
        "solution_abst_ko": "[OP_LIST_SOL] 나나 가은 [OP_LIST_EOL] [OP_LIST_SOL] 1.618 100 [OP_MUL] 162.3 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Nana Gaeun [OP_LIST_EOL] [OP_LIST_SOL] 1.618 100 [OP_MUL] 162.3 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '나나'\nvar_b = '가은'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.618\nvar_d = 100\nvar_e = var_c * var_d\nvar_f = 162.3\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Nana'\nvar_b = 'Gaeun'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.618\nvar_d = 100\nvar_e = var_c * var_d\nvar_f = 162.3\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "7033": {
        "category": "Correspondence",
        "question_ko": "A56B는 36으로 나누어 떨어지는 네 자리 수입니다. A가 될 수 있는 모든 숫자의 개수는 무엇입니까?",
        "question_en": "A56B is a four-digit number divisible by 36. What is the number of all numbers that can be A?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "A56B [OP_GEN_POSSIBLE_LIST] 36 [OP_LIST_DIVISIBLE] A56B A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_abst_en": "A56B [OP_GEN_POSSIBLE_LIST] 36 [OP_LIST_DIVISIBLE] A56B A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 'A56B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 36\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 'A56B'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nvar_e = len(list_c)\nprint(int(var_e))",
        "solution_code_en": "var_a = 'A56B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 36\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 'A56B'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nvar_e = len(list_c)\nprint(int(var_e))"
    },
    "7034": {
        "category": "Possibility",
        "question_ko": "A, B, C를 포함한 6명의 사람을 일렬로 세울 때, A, B, C가 이웃하도록 일렬로 세우는 경우의 수는?",
        "question_en": "When 6 people including A, B, and C are lined up, in how many ways can A, B, and C line up next to each other?",
        "answer_ko": "144",
        "answer_en": "144",
        "solution_abst_ko": "6 [OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_LEN] 1 [OP_SUB] [OP_SUB] 6 [OP_LIST_LEN] 1 [OP_SUB] [OP_SUB] [OP_PERM] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL]",
        "solution_abst_en": "6 [OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_LEN] 1 [OP_SUB] [OP_SUB] 6 [OP_LIST_LEN] 1 [OP_SUB] [OP_SUB] [OP_PERM] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL]",
        "solution_code_ko": "var_a = 6\nvar_b = 'A'\nvar_c = 'B'\nvar_d = 'C'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_a - var_g\nvar_i = 6\nvar_j = len(list_a)\nvar_k = 1\nvar_l = var_j - var_k\nvar_m = var_i - var_l\nvar_n = 1\nvar_h = int(var_h)\nvar_m = int(var_m)\nfor i, elem in enumerate(range(var_m)):\n    var_n = var_n * (var_h-i)\nvar_o = len(list_a)\nvar_p = len(list_a)\nvar_q = 1\nvar_o = int(var_o)\nvar_p = int(var_p)\nfor i, elem in enumerate(range(var_p)):\n    var_q = var_q * (var_o-i)\nvar_r = var_n * var_q\nprint(int(var_r))",
        "solution_code_en": "var_a = 6\nvar_b = 'A'\nvar_c = 'B'\nvar_d = 'C'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_a - var_g\nvar_i = 6\nvar_j = len(list_a)\nvar_k = 1\nvar_l = var_j - var_k\nvar_m = var_i - var_l\nvar_n = 1\nvar_h = int(var_h)\nvar_m = int(var_m)\nfor i, elem in enumerate(range(var_m)):\n    var_n = var_n * (var_h-i)\nvar_o = len(list_a)\nvar_p = len(list_a)\nvar_q = 1\nvar_o = int(var_o)\nvar_p = int(var_p)\nfor i, elem in enumerate(range(var_p)):\n    var_q = var_q * (var_o-i)\nvar_r = var_n * var_q\nprint(int(var_r))"
    },
    "7035": {
        "category": "Comparison",
        "question_ko": "호박의 무게는 2와 9/10킬로그램(㎏)이고 수박의 무게는 41/10킬로그램(㎏)입니다. 호박과 수박 중 어느 것이 더 무겁습니까?",
        "question_en": "A pumpkin weighs two and nine-tenths of a kilogram (kg) and a watermelon weighs forty-one-tenths of a kilogram (kg). Which one is heavier, pumpkin or watermelon?",
        "answer_ko": "수박",
        "answer_en": "watermelon",
        "solution_abst_ko": "[OP_LIST_SOL] 호박 수박 [OP_LIST_EOL] [OP_LIST_SOL] 2 9 10 [OP_DIV] [OP_ADD] 41 10 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] pumpkin watermelon [OP_LIST_EOL] [OP_LIST_SOL] 2 9 10 [OP_DIV] [OP_ADD] 41 10 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '호박'\nvar_b = '수박'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nvar_d = 9\nvar_e = 10\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nvar_h = 41\nvar_i = 10\nvar_j = var_h / var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'pumpkin'\nvar_b = 'watermelon'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nvar_d = 9\nvar_e = 10\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nvar_h = 41\nvar_i = 10\nvar_j = var_h / var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "7036": {
        "category": "Comparison",
        "question_ko": "석진이네 교실은 사각형 모양으로 책상이 배치되어 있습니다. 각 줄의 책상의 개수가 같을 때, 석진이의 자리는 앞에서 3번째 뒤에서 5번째이고, 오른쪽에서 4번째, 왼쪽에서는 2번째 자리입니다. 석진이네 교실에 배치된 책상은 모두 몇 개입니까?",
        "question_en": "Seokjin's classroom has desks arranged in a square shape. When the number of desks in each row is the same, Seokjin's seat is 3rd from the front, 5th from the back, 4th from the right, and 2nd from the left. Find the total number of desks in Seokjin's classroom.",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "3 5 [OP_ADD] 1 [OP_SUB] 4 2 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "3 5 [OP_ADD] 1 [OP_SUB] 4 2 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 4\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 3\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 4\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))"
    },
    "7037": {
        "category": "Arithmetic calculation",
        "question_ko": "호석이는 보라색 색종이를 138장 가지고 있습니다. 호석이가 가지고 있는 파란색 색종이는 노란색 색종이보다 119장 더 적고, 노란색 색종이는 보라색 색종이보다 185장 더 많습니다. 호석이가 가지고 있는 보라색, 노란색, 파란색 색종이는 모두 몇 장입니까?",
        "question_en": "Hoseok has 138 pieces of purple-colored paper. Hoseok has 119 fewer pieces of blue-colored paper than yellow-colored paper and 185 more yellow-colored paper than purple-colored paper. How many purple, yellow, and blue-colored paper does Hoseok have in total?",
        "answer_ko": "467",
        "answer_en": "467",
        "solution_abst_ko": "138 138 119 [OP_ADD] [OP_ADD] 138 119 [OP_ADD] 185 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "138 138 119 [OP_ADD] [OP_ADD] 138 119 [OP_ADD] 185 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 138\nvar_b = 138\nvar_c = 119\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nvar_f = 138\nvar_g = 119\nvar_h = var_f + var_g\nvar_i = 185\nvar_j = var_h - var_i\nvar_k = var_e + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 138\nvar_b = 138\nvar_c = 119\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nvar_f = 138\nvar_g = 119\nvar_h = var_f + var_g\nvar_i = 185\nvar_j = var_h - var_i\nvar_k = var_e + var_j\nprint(int(var_k))"
    },
    "7038": {
        "category": "Comparison",
        "question_ko": "5과 8 중에서 작은 숫자를 고르세요.",
        "question_en": "Choose the smaller number between 5 and 8.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "[OP_LIST_SOL] 5 8 [OP_LIST_EOL] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 5 8 [OP_LIST_EOL] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 5\nvar_b = 8\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[var_c-1]\nprint(int(var_d))",
        "solution_code_en": "var_a = 5\nvar_b = 8\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[var_c-1]\nprint(int(var_d))"
    },
    "7039": {
        "category": "Comparison",
        "question_ko": "5개의 숫자 5, 8, 4, 3, 2 중 가장 큰 수는 무엇인가요?",
        "question_en": "What is the greatest number among the five numbers 5, 8, 4, 3, and 2?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "[OP_LIST_SOL] 5 8 4 3 2 [OP_LIST_EOL] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 5 8 4 3 2 [OP_LIST_EOL] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 5\nvar_b = 8\nvar_c = 4\nvar_d = 3\nvar_e = 2\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 8\nvar_c = 4\nvar_d = 3\nvar_e = 2\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nprint(int(var_g))"
    },
    "7040": {
        "category": "Arithmetic calculation",
        "question_ko": "6개의 볼펜을 가진 상자가 4상자 있다. 볼펜을 한 상자에 3개씩 넣어 포장한다면 몇 상자가 필요한가?",
        "question_en": "There are 4 boxes of 6 ballpoint pens. If you pack 3 ballpoint pens in a box, how many boxes are needed?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "6 4 [OP_MUL] 3 [OP_DIV]",
        "solution_abst_en": "6 4 [OP_MUL] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "7041": {
        "category": "Comparison",
        "question_ko": "기윤이는 중간고사에서 국어 80점, 수학 94점, 사회 82점, 영어 76점, 과학 100점을 받았습니다. 평균보다 잘 본 과목은 몇 과목입니까?",
        "question_en": "Giyoon received 80 points in Korean, 94 points in mathematics, 82 points in social studies, 76 points in English, and 100 points in science in the midterm exam. How many subjects did he do better than the average points?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 80 94 82 76 100 [OP_LIST_EOL] [OP_LIST_MEAN] [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 80 94 82 76 100 [OP_LIST_EOL] [OP_LIST_MEAN] [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 80\nvar_b = 94\nvar_c = 82\nvar_d = 76\nvar_e = 100\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_f = sum(list_a)/len(list_a)\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 80\nvar_b = 94\nvar_c = 82\nvar_d = 76\nvar_e = 100\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_f = sum(list_a)/len(list_a)\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "7042": {
        "category": "Arithmetic calculation",
        "question_ko": "두 나눗셈 46.1 / 1.33, 61.8 / 88.6의 몫의 합을 구해보세요",
        "question_en": "Find the sum of the quotients of the two divisions 4610 / 133 and 618 / 886",
        "answer_ko": "34",
        "answer_en": "34",
        "solution_abst_ko": "46.1 1.33 [OP_FDIV] 61.8 88.6 [OP_FDIV] [OP_ADD]",
        "solution_abst_en": "46.1 1.33 [OP_FDIV] 61.8 88.6 [OP_FDIV] [OP_ADD]",
        "solution_code_ko": "var_a = 46.1\nvar_b = 1.33\nvar_c = var_a // var_b\nvar_d = 61.8\nvar_e = 88.6\nvar_f = var_d // var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 46.1\nvar_b = 1.33\nvar_c = var_a // var_b\nvar_d = 61.8\nvar_e = 88.6\nvar_f = var_d // var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "7043": {
        "category": "Arithmetic calculation",
        "question_ko": "국어 문제 12개를 푼 석진이가 7개를 더 풀었습니다. 석진이는 몇 개의 국어 문제를 풀었나요?",
        "question_en": "After solving 12 problems of Korean, Seokjin solved 7 more. What is a total number of problems he solved?",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "12 7 [OP_ADD]",
        "solution_abst_en": "12 7 [OP_ADD]",
        "solution_code_ko": "var_a = 12\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 12\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "7044": {
        "category": "Possibility",
        "question_ko": "0, 2, 4, 6 중에서 3개 뽑아 한 번씩만 사용하여 세 자리 수를 만들려고 합니다. 만들 수 있는 가장 큰 수와 가장 작은 수의 합을 구하시오.",
        "question_en": "If you are to form a three-digit number by selecting three from 0, 2, 4, and 6 and using them only once, what is the sum of the largest and smallest possible numbers?",
        "answer_ko": "846",
        "answer_en": "846",
        "solution_abst_ko": "[OP_LIST_SOL] 0 2 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 0 2 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 0\nvar_b = 2\nvar_c = 4\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 0\nvar_b = 2\nvar_c = 4\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))"
    },
    "7045": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 물통에 250밀리리터(㎖) 들이의 컵으로 물을 가득 담아 20번을 부은 후, 600밀리리터(㎖) 들이의 컵으로 물을 가득 담아 13번 부었더니 이 물통이 가득 찼습니다. 이 물통의 들이는 몇 리터(L)입니까?",
        "question_en": "After filling a 250 milliliters (ml) cup with water and pouring it 20 times in a water bottle, and then filling a 600 milliliters (ml) cup with water and pouring it 13 times, the water bottle was full. How many liters (L) does this water bottle hold?",
        "answer_ko": "12.80",
        "answer_en": "12.8",
        "solution_abst_ko": "250 20 [OP_MUL] 600 13 [OP_MUL] [OP_ADD] 1000 [OP_DIV]",
        "solution_abst_en": "250 20 [OP_MUL] 600 13 [OP_MUL] [OP_ADD] 1000 [OP_DIV]",
        "solution_code_ko": "var_a = 250\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 600\nvar_e = 13\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 1000\nvar_i = var_g / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 250\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 600\nvar_e = 13\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 1000\nvar_i = var_g / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "7046": {
        "category": "Possibility",
        "question_ko": "모두 다른 동전 3개를 던졌을 때, 첫 번째 동전이 앞면이 나오는 경우의 수를 구하시오.",
        "question_en": "When three different coins are tossed, find the number of ways in which the first coin will come up heads.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "2 2 [OP_MUL]",
        "solution_abst_en": "2 2 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "7047": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 7로 나누었더니 몫이 12이고 나머지가 5였습니다. 이 수를 8로 나누었을 때 몫은 얼마입니까?",
        "question_en": "When a number is divided by 7, the quotient is 12 and the remainder is 5. What is the quotient when this number is divided by 8?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "12 7 [OP_MUL] 5 [OP_ADD] 8 [OP_FDIV]",
        "solution_abst_en": "12 7 [OP_MUL] 5 [OP_ADD] 8 [OP_FDIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e // var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 12\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e // var_f\nprint(int(var_g))"
    },
    "7048": {
        "category": "Correspondence",
        "question_ko": "9A5는 세 자리 수입니다. 나눗셈 9A5÷5<197을 가능하게 하는 A가 될 수 있는 모든 수를 구하시오.",
        "question_en": "9A5 is a three digit number. Find all possible numbers for A that make division 9A5÷5<197 possible.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "9A5÷5<197 A [OP_DIGIT_UNK_SOLVER] [OP_LIST_LEN]",
        "solution_abst_en": "9A5÷5<197 A [OP_DIGIT_UNK_SOLVER] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '9A5÷5<197'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = len(list_a)\nprint(int(var_c))",
        "solution_code_en": "var_a = '9A5÷5<197'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = len(list_a)\nprint(int(var_c))"
    },
    "7049": {
        "category": "Comparison",
        "question_ko": "서로 다른 장난감 19개를 크기가 작은 것부터 순서대로 놓았습니다. (가) 장난감은 왼쪽에서 9번째에, (나) 장난감은 왼쪽에서 15번째에 있습니다. 두 장난감 사이에 있는 장난감의 수를 구하시오.",
        "question_en": "19 different toys are placed in order from the smallest. (a) Toy is 9th from the left and (b) Toy is 15th from the left. Find the number of toys between the two toys.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "15 9 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "15 9 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 15\nvar_b = 9\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 9\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "7050": {
        "category": "Comparison",
        "question_ko": "호석이는 5와 6으로 1보다 작은 분수를 만들었고, 정국이는 4와 3으로 1보다 작은 분수를 만들었습니다. 누가 만든 분수가 더 큽니까?",
        "question_en": "Hoseok made a fraction less than 1 with 5 and 6, and Jungkook made a fraction. that is smaller than 1 using 4 and 3. Whose fraction is bigger?",
        "answer_ko": "호석",
        "answer_en": "Hoseok",
        "solution_abst_ko": "[OP_LIST_SOL] 호석 정국 [OP_LIST_EOL] [OP_LIST_SOL] 5 6 [OP_DIV] 3 4 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Hoseok Jungkook [OP_LIST_EOL] [OP_LIST_SOL] 5 6 [OP_DIV] 3 4 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '호석'\nvar_b = '정국'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 5\nvar_d = 6\nvar_e = var_c / var_d\nvar_f = 3\nvar_g = 4\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Hoseok'\nvar_b = 'Jungkook'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 5\nvar_d = 6\nvar_e = var_c / var_d\nvar_f = 3\nvar_g = 4\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "7051": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 90센티미터(㎝)인 끝 중 30센티미터(㎝)는 유정이에게 주고 나머지의 8/15은 상자를 묶는데 사용했다. 상자를 묶는데 사용한 끈의 길이는 얼마인지 구하시오.",
        "question_en": "Of the 90 centimeters (cm) long string, 30 centimeters (cm) was given to Yoojung, and 8/15 of the remaining was used to tie the box. Find the length of the string used to tie the box.",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "90 30 [OP_SUB] 8/15 [OP_MUL]",
        "solution_abst_en": "90 30 [OP_SUB] 8/15 [OP_MUL]",
        "solution_code_ko": "var_a = 90\nvar_b = 30\nvar_c = var_a - var_b\nvar_d = 0.5333333333333333\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 90\nvar_b = 30\nvar_c = var_a - var_b\nvar_d = 0.5333333333333333\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "7052": {
        "category": "Comparison",
        "question_ko": "1.4, 9/10, 1.2, 0.5, 13/10 중에서 1.1보다 작은 숫자를 고르고, 다시 그 중에서 가장 큰 숫자를 구하세요",
        "question_en": "Choose a number or numbers less than 1.1 from 1.4, 9/10, 1.2, 0.5, and 13/10, then find the largest number among them.",
        "answer_ko": "0.90",
        "answer_en": "0.9",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i < var_f:\n        list_b.append(i)\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nprint('{:.2f}'.format(round(var_h+1e-10,2)))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i < var_f:\n        list_b.append(i)\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nprint('{:.2f}'.format(round(var_h+1e-10,2)))"
    },
    "7053": {
        "category": "Comparison",
        "question_ko": "물고기 A, B, C, D가 먹이를 먹고 있습니다. A는 D보다 많은 먹이를 먹었고, B는 A보다 많은 먹이를 먹었습니다. C는 A보다 적은 먹이를 먹었을 때, 가장 많은 먹이를 먹은 물고기는 무엇인가요?",
        "question_en": "Fish A, B, C, and D are feeding. A ate more feed than D, and B ate more feed than A. If C ate less feed than A, which fish ate the most?",
        "answer_ko": "B",
        "answer_en": "B",
        "solution_abst_ko": "[OP_LIST_SOL] A B C D [OP_LIST_EOL] [OP_LIST_SOL] A D > C A < B A > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D [OP_LIST_EOL] [OP_LIST_SOL] A D > C A < B A > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'A'\nvar_f = 'D'\nvar_g = '>'\nvar_h = 'C'\nvar_i = 'A'\nvar_j = '<'\nvar_k = 'B'\nvar_l = 'A'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = 1\nvar_o = list_c[var_n-1]\nprint(var_o)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'A'\nvar_f = 'D'\nvar_g = '>'\nvar_h = 'C'\nvar_i = 'A'\nvar_j = '<'\nvar_k = 'B'\nvar_l = 'A'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = 1\nvar_o = list_c[var_n-1]\nprint(var_o)"
    },
    "7054": {
        "category": "Correspondence",
        "question_ko": "A, B, C 3개의 물탱크에 물이 들어 있습니다. A 물탱크에는 물이 29리터(L) 들어있고, B 물탱크에는 A 물탱크에 들어 있는 물보다 2700밀리리터(㎖) 더 적게 들어 있고, C 물탱크에는 A 물탱크와 B 물탱크에 들어 있는 물의 합보다 4750밀리리터(㎖) 더 많이 들어 있습니다. C 물탱크에 들어 있는 물은 몇 리터(L)입니까?",
        "question_en": "Three water tanks A, B, and C contain water. Water tank A contains 29 liters (L) of water, water tank B contains 2700 milliliters (㎖) less than the water contained in water tank A, and water tank C contains 4750 milliliters (ml) more water than the sum of water of water tank A and B. How many liters (L) of water is in the water tank C?",
        "answer_ko": "60.05",
        "answer_en": "60.05",
        "solution_abst_ko": "29 29 2700 1000 [OP_DIV] [OP_SUB] [OP_ADD] 4750 1000 [OP_DIV] [OP_ADD]",
        "solution_abst_en": "29 29 2700 1000 [OP_DIV] [OP_SUB] [OP_ADD] 4750 1000 [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 29\nvar_b = 29\nvar_c = 2700\nvar_d = 1000\nvar_e = var_c / var_d\nvar_f = var_b - var_e\nvar_g = var_a + var_f\nvar_h = 4750\nvar_i = 1000\nvar_j = var_h / var_i\nvar_k = var_g + var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 29\nvar_b = 29\nvar_c = 2700\nvar_d = 1000\nvar_e = var_c / var_d\nvar_f = var_b - var_e\nvar_g = var_a + var_f\nvar_h = 4750\nvar_i = 1000\nvar_j = var_h / var_i\nvar_k = var_g + var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "7055": {
        "category": "Arithmetic calculation",
        "question_ko": "같은 길이의 테이프 2개를 겹쳐서 붙였더니 총 길이가 512센티미터(㎝)가 되었습니다. 테이프 하나의 길이가 275센티미터(㎝)이라면 겹쳐진 부분은 몇 센티미터(㎝)입니까?",
        "question_en": "Two tapes of the same length are stacked together and overlapped resulting in a total length of 512 centimeters (cm). If the length of one piece of tape is 275 centimeters (cm), how many centimeters (cm) is the overlap?",
        "answer_ko": "38",
        "answer_en": "38",
        "solution_abst_ko": "275 275 [OP_ADD] 512 [OP_SUB]",
        "solution_abst_en": "275 275 [OP_ADD] 512 [OP_SUB]",
        "solution_code_ko": "var_a = 275\nvar_b = 275\nvar_c = var_a + var_b\nvar_d = 512\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 275\nvar_b = 275\nvar_c = var_a + var_b\nvar_d = 512\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "7056": {
        "category": "Geometry",
        "question_ko": "모서리의 길이가 12센티미터(㎝)인 정육면체의 모서리에서 작은 정육면체를 파냈다. 작은 정육면체의 모서리의 길이가 4센티미터(㎝)라고 한다면, 파내고 남은 부분의 겉넓이를 구하시오.",
        "question_en": "A small cube was dug out of the edge of the cube that has the length of edge being 12 centimeters (cm). If the length of the edge of the small cube is 4 centimeters (cm), find the surface area of the portion left after the cutout.",
        "answer_ko": "1632",
        "answer_en": "1632",
        "solution_abst_ko": "12 12 [OP_MUL] 6 [OP_MUL] 4 4 [OP_MUL] 4 [OP_MUL] 12 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "12 12 [OP_MUL] 6 [OP_MUL] 4 4 [OP_MUL] 4 [OP_MUL] 12 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 12\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = 4\nvar_h = var_f * var_g\nvar_i = 4\nvar_j = var_h * var_i\nvar_k = 12\nvar_l = var_j * var_k\nvar_m = var_e + var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 12\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = 4\nvar_h = var_f * var_g\nvar_i = 4\nvar_j = var_h * var_i\nvar_k = 12\nvar_l = var_j * var_k\nvar_m = var_e + var_l\nprint(int(var_m))"
    },
    "7057": {
        "category": "Possibility",
        "question_ko": "서로 다른 연필이 3개, 서로 다른 지우개가 2개, 서로 다른 볼펜이 2개가 있다. 이 중 3개를 뽑아 선물한다고 할 때, 선물의 경우의 수를 구하시오.",
        "question_en": "There are 3 different pencils, 2 different erasers, and 2 different ballpoint pens. If 3 of these are selected and gifted, find the number of cases.",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "3 2 [OP_ADD] 2 [OP_ADD] 3 [OP_COMB]",
        "solution_abst_en": "3 2 [OP_ADD] 2 [OP_ADD] 3 [OP_COMB]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g / (i+1)\nprint(int(var_g))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g / (i+1)\nprint(int(var_g))"
    },
    "7058": {
        "category": "Possibility",
        "question_ko": "3, 1, 7, 4 가 적힌 4장의 카드를 한 번씩 모두 사용하여 만들 수 있는 가장 큰 소수 두 자리 수와 가장 작은 소수 한 자리 수의 차를 구하시오",
        "question_en": "Find the difference between the largest two-digit number and the smallest one-digit number that can be made by using all four cards with the numbers 3, 1, 7, and 4 once.",
        "answer_ko": "72.96",
        "answer_en": "72.96",
        "solution_abst_ko": "[OP_LIST_SOL] 3 1 7 4 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 10 [OP_LIST_POP] [OP_LIST_LEN] 2 [OP_SUB] [OP_POW] [OP_DIV] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 10 [OP_LIST_POP] [OP_LIST_LEN] 1 [OP_SUB] [OP_POW] [OP_DIV] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "[OP_LIST_SOL] 3 1 7 4 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 10 [OP_LIST_POP] [OP_LIST_LEN] 2 [OP_SUB] [OP_POW] [OP_DIV] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 10 [OP_LIST_POP] [OP_LIST_LEN] 1 [OP_SUB] [OP_POW] [OP_DIV] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 3\nvar_b = 1\nvar_c = 7\nvar_d = 4\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 10\nvar_i = len(list_a)\nvar_j = 2\nvar_k = var_i - var_j\nvar_l = var_h ** var_k\nvar_m = var_g / var_l\nvar_n = 4\nlist_d = [str(i) for i in list_a]\nlist_d = list(itertools.permutations(list_d, var_n))\nlist_d = [''.join(num_list) for num_list in list_d]\nlist_d = [str_num for str_num in list_d if str_num[0] != '0']\nlist_d = [float(i) for i in list_d]\nvar_o = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_p = list_e[var_o-1]\nvar_q = 10\nvar_r = len(list_a)\nvar_s = 1\nvar_t = var_r - var_s\nvar_u = var_q ** var_t\nvar_v = var_p / var_u\nvar_w = var_m - var_v\nvar_x = abs(var_w)\nprint('{:.2f}'.format(round(var_x+1e-10,2)))",
        "solution_code_en": "var_a = 3\nvar_b = 1\nvar_c = 7\nvar_d = 4\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 10\nvar_i = len(list_a)\nvar_j = 2\nvar_k = var_i - var_j\nvar_l = var_h ** var_k\nvar_m = var_g / var_l\nvar_n = 4\nlist_d = [str(i) for i in list_a]\nlist_d = list(itertools.permutations(list_d, var_n))\nlist_d = [''.join(num_list) for num_list in list_d]\nlist_d = [str_num for str_num in list_d if str_num[0] != '0']\nlist_d = [float(i) for i in list_d]\nvar_o = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_p = list_e[var_o-1]\nvar_q = 10\nvar_r = len(list_a)\nvar_s = 1\nvar_t = var_r - var_s\nvar_u = var_q ** var_t\nvar_v = var_p / var_u\nvar_w = var_m - var_v\nvar_x = abs(var_w)\nprint('{:.2f}'.format(round(var_x+1e-10,2)))"
    },
    "7059": {
        "category": "Arithmetic calculation",
        "question_ko": "노동자 한 명이 일주일 동안 생산하는 연필이 370자루입니다. 일주일 동안 연필 1000타를 생산하기 위해선 몇 명의 노동자가 필요합니까?",
        "question_en": "One worker makes 370 pencils in a week. How many workers are needed to make 1000 dozens of pencils in a week?",
        "answer_ko": "33",
        "answer_en": "33",
        "solution_abst_ko": "1000 12 [OP_MUL] 370 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "1000 12 [OP_MUL] 370 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 1000\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 370\nvar_e = var_c / var_d\nvar_f = 1\nvar_g=int(((var_e+9*10**(var_f-2))//(10**(var_f-1)))*10**(var_f-1))\n\nprint(int(var_g))",
        "solution_code_en": "var_a = 1000\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 370\nvar_e = var_c / var_d\nvar_f = 1\nvar_g=int(((var_e+9*10**(var_f-2))//(10**(var_f-1)))*10**(var_f-1))\n\nprint(int(var_g))"
    },
    "7060": {
        "category": "Arithmetic calculation",
        "question_ko": "엘리베이터에 18명이 타고 있었습니다. 잠시 후 몇 명이 내려서 11명이 남았습니다. 엘리베이터에서 내린 사람은 몇 명입니까?",
        "question_en": "There were 18 people in the elevator. After a while, a few people got off and there were 11 people left. How many people got off the elevator?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "18 11 [OP_SUB]",
        "solution_abst_en": "18 11 [OP_SUB]",
        "solution_code_ko": "var_a = 18\nvar_b = 11\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 18\nvar_b = 11\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "7061": {
        "category": "Correspondence",
        "question_ko": "등식 A45+2B3=418이 성립한다고 합니다. A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "The equation A45+2B3=418 is said to be true. What number should go in A?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "A45+2B3=418 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A45+2B3=418 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A45+2B3=418'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A45+2B3=418'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "7062": {
        "category": "Possibility",
        "question_ko": "정이십면체 모양의 상자가 있습니다. 이 상자의 한 꼭짓점에 모인 면의 개수는?",
        "question_en": "I have a box in the shape of an icosahedron. How many faces meet at one vertex of this box?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "5",
        "solution_abst_en": "5",
        "solution_code_ko": "var_a = 5\nprint(int(var_a))",
        "solution_code_en": "var_a = 5\nprint(int(var_a))"
    },
    "7063": {
        "category": "Possibility",
        "question_ko": "1부터 9까지의 홀수를 중복 사용하여 만들 수 있는 3자리 자연수 중 500초과인 수는 모두 몇 개인지 구하시오.",
        "question_en": "Find how many 3-digit natural numbers that can be formed by repeating odd numbers from 1 to 9 are greater than 500.",
        "answer_ko": "75",
        "answer_en": "75",
        "solution_abst_ko": "1 9 [OP_LIST_ODD] 3 [OP_LIST_GET_PRODUCT] 500 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "1 9 [OP_LIST_ODD] 3 [OP_LIST_GET_PRODUCT] 500 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = 500\nlist_c = []\nfor i in list_b:\n    if i > var_d:\n        list_c.append(i)\nvar_e = len(list_c)\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = 500\nlist_c = []\nfor i in list_b:\n    if i > var_d:\n        list_c.append(i)\nvar_e = len(list_c)\nprint(int(var_e))"
    },
    "7064": {
        "category": "Geometry",
        "question_ko": "정팔면체에서 면은 모두 몇개일까요?",
        "question_en": "How many faces are there in a regular octahedron?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "8",
        "solution_abst_en": "8",
        "solution_code_ko": "var_a = 8\nprint(int(var_a))",
        "solution_code_en": "var_a = 8\nprint(int(var_a))"
    },
    "7065": {
        "category": "Correspondence",
        "question_ko": "103은 어떤수를 3으로 나누고 5를 빼야할 것을 실수로 3을 곱하고 5를 빼서 나온 결과입니다. 바르게 계산하면 얼마입니까?",
        "question_en": "103 is the result of accidently multiplying a number by 3 and subtracting 5 when you have to actually divide this number by 3 and subtract 5. How much is it when you calculate correctly?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "103 5 [OP_ADD] 3 [OP_DIV] 3 [OP_DIV] 5 [OP_SUB]",
        "solution_abst_en": "103 5 [OP_ADD] 3 [OP_DIV] 3 [OP_DIV] 5 [OP_SUB]",
        "solution_code_ko": "var_a = 103\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = 5\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 103\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = 5\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "7066": {
        "category": "Arithmetic calculation",
        "question_ko": "연속된 짝수 25개의 합이 750일 때, 이 중 가장 작은 수는?",
        "question_en": "If the sum of 25 consecutive even numbers is 750, which number is the smallest?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "750 25 [OP_DIV] 25 2 [OP_FDIV] 2 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "750 25 [OP_DIV] 25 2 [OP_FDIV] 2 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 750\nvar_b = 25\nvar_c = var_a / var_b\nvar_d = 25\nvar_e = 2\nvar_f = var_d // var_e\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_c - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 750\nvar_b = 25\nvar_c = var_a / var_b\nvar_d = 25\nvar_e = 2\nvar_f = var_d // var_e\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_c - var_h\nprint(int(var_i))"
    },
    "7067": {
        "category": "Possibility",
        "question_ko": "윤기, 정국, 호석이는 각자 공책 3개를 빈 책장에 꽂아 넣었습니다. 이 책장에 있는 공책은 모두 몇 개일까요?",
        "question_en": "Yoongi, Jungkook, and Hoseok each put three notebooks in an empty bookshelf. How many notebooks are there in this bookshelf?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "3 3 [OP_MUL]",
        "solution_abst_en": "3 3 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "7068": {
        "category": "Arithmetic calculation",
        "question_ko": "상자가 5개있습니다. 한 상자에는 동화책이 20권 담겨져 있다고 할 때 동화책은 모두 몇 권 있습니까?",
        "question_en": "There are 5 boxes. If there are 20 children's books in a box, how many children's books are there in all boxes?",
        "answer_ko": "100",
        "answer_en": "100",
        "solution_abst_ko": "20 5 [OP_MUL]",
        "solution_abst_en": "20 5 [OP_MUL]",
        "solution_code_ko": "var_a = 20\nvar_b = 5\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 20\nvar_b = 5\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "7069": {
        "category": "Comparison",
        "question_ko": "윤기는 4, 정국에는 6에서 3을 뺀 수를 모았고, 유나는 5를 모았습니다. 누가 가장 큰 수를 가지고 있나요?",
        "question_en": "Yoongi collected 4, Jungkook collected 6 minus 3, and Yuna collected 5. Who has the biggest number?",
        "answer_ko": "유나",
        "answer_en": "Yuna",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 유나 [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_SUB] 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook Yuna [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_SUB] 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nvar_c = '유나'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 6\nvar_f = 3\nvar_g = var_e - var_f\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nvar_c = 'Yuna'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 6\nvar_f = 3\nvar_g = var_e - var_f\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "7070": {
        "category": "Geometry",
        "question_ko": "삼각형, 사각형, 육각형의 변의 개수를 모두 더한 값은 얼마입니까?",
        "question_en": "What is the sum of the number of sides of a triangle, square, and hexagon?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "6 3 [OP_ADD] 4 [OP_ADD]",
        "solution_abst_en": "6 3 [OP_ADD] 4 [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7071": {
        "category": "Geometry",
        "question_ko": "미진이가 가진 주사위는 한 모서리의 길이가 11센티미터(㎝)입니다. 이 주사위의 겉넓이를 구하시오.",
        "question_en": "Mijin's dice has one edge of 11 centimeters (cm). Find the surface area of this dice.",
        "answer_ko": "726",
        "answer_en": "726",
        "solution_abst_ko": "11 2 [OP_POW] 6 [OP_MUL]",
        "solution_abst_en": "11 2 [OP_POW] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 11\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 11\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "7072": {
        "category": "Arithmetic calculation",
        "question_ko": "가희는 어제 하루 숙제로 주어진 810개의 영어단어 중 1/9을 외웠다. 오늘 남은 단어의 4분의 1을 외웠다면 오늘 얼마나 많은 영어 단어를 외웠는지 세어 보세요.",
        "question_en": "Kahi memorized 1/9 of the 810 English words given as homework yesterday. If she memorized a quarter of the remaining words today, count how many English words she memorized today.",
        "answer_ko": "180",
        "answer_en": "180",
        "solution_abst_ko": "810 1 1/9 [OP_SUB] [OP_MUL] 1 4 [OP_DIV] [OP_MUL]",
        "solution_abst_en": "810 1 1/9 [OP_SUB] [OP_MUL] 1 4 [OP_DIV] [OP_MUL]",
        "solution_code_ko": "var_a = 810\nvar_b = 1\nvar_c = 0.1111111111111111\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 1\nvar_g = 4\nvar_h = var_f / var_g\nvar_i = var_e * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 810\nvar_b = 1\nvar_c = 0.1111111111111111\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 1\nvar_g = 4\nvar_h = var_f / var_g\nvar_i = var_e * var_h\nprint(int(var_i))"
    },
    "7073": {
        "category": "Geometry",
        "question_ko": "두 볼링공의 반지름의 길이의 비가 1:2이고, 작은 공의 부피가 36세제곱센티미터(㎤)일 때, 큰 공의 부피는?",
        "question_en": "If the ratio of the radii of two bowling balls is 1:2 and the volume of the small ball is 36 cubic centimeters (cm3), what is the volume of the large ball?",
        "answer_ko": "288",
        "answer_en": "288",
        "solution_abst_ko": "36 2 3 [OP_POW] [OP_MUL]",
        "solution_abst_en": "36 2 3 [OP_POW] [OP_MUL]",
        "solution_code_ko": "var_a = 36\nvar_b = 2\nvar_c = 3\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 36\nvar_b = 2\nvar_c = 3\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nprint(int(var_e))"
    },
    "7074": {
        "category": "Geometry",
        "question_ko": "한 모서리의 길이가 4센티미터(㎝)인 정육면체 27개를 붙여 하나의 큰 정육면체를 만들었습니다. 이 큰 정육면체의 겉넓이는 몇 제곱센티미터입니까?",
        "question_en": "Twenty-seven cubes with an edge of 4 centimeters (cm) long were glued together to form one large cube. What is the surface area of this large cube in square centimeters (cm2)?",
        "answer_ko": "864",
        "answer_en": "864",
        "solution_abst_ko": "4 3 [OP_MUL] 4 3 [OP_MUL] [OP_MUL] 6 [OP_MUL]",
        "solution_abst_en": "4 3 [OP_MUL] 4 3 [OP_MUL] [OP_MUL] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 4\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c * var_f\nvar_h = 6\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 4\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c * var_f\nvar_h = 6\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "7075": {
        "category": "Comparison",
        "question_ko": "27과 45의 공배수를 작은 수부터 차례대로 썼습니다. 왼쪽에서 7번째 수와 10번째 수 사이에 있는 수들의 곱은 얼마입니까?",
        "question_en": "Write the common multiples of 27 and 45 in order from smallest to largest. What is the product of the numbers between the 7th and 10th numbers from the left?",
        "answer_ko": "1312200",
        "answer_en": "1312200",
        "solution_abst_ko": "27 45 [OP_LCM] 8 [OP_MUL] 27 45 [OP_LCM] 9 [OP_MUL] [OP_MUL]",
        "solution_abst_en": "27 45 [OP_LCM] 8 [OP_MUL] 27 45 [OP_LCM] 9 [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 27\nvar_b = 45\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nvar_d = 8\nvar_e = var_c * var_d\nvar_f = 27\nvar_g = 45\nvar_h = var_g * var_f / math.gcd(int(var_g), int(var_f))\nvar_i = 9\nvar_j = var_h * var_i\nvar_k = var_e * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 27\nvar_b = 45\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nvar_d = 8\nvar_e = var_c * var_d\nvar_f = 27\nvar_g = 45\nvar_h = var_g * var_f / math.gcd(int(var_g), int(var_f))\nvar_i = 9\nvar_j = var_h * var_i\nvar_k = var_e * var_j\nprint(int(var_k))"
    },
    "7076": {
        "category": "Geometry",
        "question_ko": "어느 동전의 지름이 14 밀리미터(㎜)일 때, 이 동전의 반지름은 몇 밀리미터(㎜) 인가요?",
        "question_en": "If the diameter of a coin is 14 millimeters (mm), what is the radius of this coin in millimeters (mm)?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "14 2 [OP_DIV]",
        "solution_abst_en": "14 2 [OP_DIV]",
        "solution_code_ko": "var_a = 14\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 14\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "7077": {
        "category": "Arithmetic calculation",
        "question_ko": "물이 가득 차있는 물통은 3.4킬로그램(㎏)입니다. 물의 1/5를 마시고 물통의 무게를 다시 재었더니 무게가 2.98킬로그램(㎏)이 되었습니다. 빈 물통의 무게는 몇 킬로그램(㎏)인가요?",
        "question_en": "A full bucket of water weighs 3.4 kilograms (kg). After drinking 1/5 of the water, the bucket was re-weighed and the weight was 2.98 kilograms (kg). How many kilograms (kg) does the empty bucket weigh?",
        "answer_ko": "1.30",
        "answer_en": "1.3",
        "solution_abst_ko": "3.4 3.4 2.98 [OP_SUB] 1/5 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "3.4 3.4 2.98 [OP_SUB] 1/5 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 3.4\nvar_b = 3.4\nvar_c = 2.98\nvar_d = var_b - var_c\nvar_e = 0.2\nvar_f = var_d / var_e\nvar_g = var_a - var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 3.4\nvar_b = 3.4\nvar_c = 2.98\nvar_d = var_b - var_c\nvar_e = 0.2\nvar_f = var_d / var_e\nvar_g = var_a - var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "7078": {
        "category": "Correspondence",
        "question_ko": "총 93마리가 있는 어느 염소무리에 흑염소와 흰 염소가 존재한다. 흑염소는 66마리이고 나머지는 흰 염소이다. 새로운 흑염소 21마리가 들어왔고 흰염소의 수만큼이 죽었다면, 흑염소는 몇마리인가?",
        "question_en": "In a herd of 93 goats, there are black and white goats. There are 66 black goats, and the rest are white goats. If 21 new black goats came in and as many black goats died as white goats, how many black goats will there be?",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "66 93 66 [OP_SUB] [OP_SUB] 21 [OP_ADD]",
        "solution_abst_en": "66 93 66 [OP_SUB] [OP_SUB] 21 [OP_ADD]",
        "solution_code_ko": "var_a = 66\nvar_b = 93\nvar_c = 66\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nvar_f = 21\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 66\nvar_b = 93\nvar_c = 66\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nvar_f = 21\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "7079": {
        "category": "Comparison",
        "question_ko": "20명의 학생들이 한 줄로 줄을 섰습니다. 윤기의 뒤에는 11명의 학생들이 서 있고, 호석이는 윤기 바로 뒤에 서 있습니다. 호석이 앞에 서 있는 학생은 몇 명입니까?",
        "question_en": "20 students lined up in a single line. Eleven students are standing behind Yoongi, and Hoseok is standing right behind Yoongi. How many students are standing in front of Hoseok?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "20 11 [OP_SUB] 1 [OP_ADD] 1 [OP_SUB]",
        "solution_abst_en": "20 11 [OP_SUB] 1 [OP_ADD] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 1\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 20\nvar_b = 11\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 1\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "7080": {
        "category": "Comparison",
        "question_ko": "학교 한국어 시험 결과 태형, 민주, 상민, 윤정, 유정이 순으로 높은 점수를 받았다. 가장 높은 점수를 받은 사람은 누구입니까?",
        "question_en": "As a result of the school Korean test, Taehyung, Minju, Sangmin, Yoonjung, and Yoojung received the highest scores in that order. Who has the highest score?",
        "answer_ko": "태형",
        "answer_en": "Taehyung",
        "solution_abst_ko": "[OP_LIST_SOL] 태형 민주 상민 윤정 유정 [OP_LIST_EOL] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Taehyung Minju Sangmin Yoonjung Yoojung [OP_LIST_EOL] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '태형'\nvar_b = '민주'\nvar_c = '상민'\nvar_d = '윤정'\nvar_e = '유정'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nvar_g = list_a[var_f-1]\nprint(var_g)",
        "solution_code_en": "var_a = 'Taehyung'\nvar_b = 'Minju'\nvar_c = 'Sangmin'\nvar_d = 'Yoonjung'\nvar_e = 'Yoojung'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nvar_g = list_a[var_f-1]\nprint(var_g)"
    },
    "7081": {
        "category": "Correspondence",
        "question_ko": "36에 어떤 수를 빼야 할 것을 잘못하여 63에 어떤 수를 나누었더니 9가 되었습니다. 바르게 계산하면 얼마인지 구하시오.",
        "question_en": "There was a mistake in calculation that you divided 63 by a certain number instead of subtracting a certain number from 36. If you got the wrong answer 9, how much is it if you calculate it correctly?",
        "answer_ko": "29",
        "answer_en": "29",
        "solution_abst_ko": "36 63 9 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "36 63 9 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 36\nvar_b = 63\nvar_c = 9\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 36\nvar_b = 63\nvar_c = 9\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "7082": {
        "category": "Possibility",
        "question_ko": "흰색 구슬, 검은색 구슬, 보라색 구슬, 초록색 구슬, 빨간색 구슬이 딱 한 개씩만 있습니다. 2개의 구슬을 산다면 살 수 있는 조합은 모두 몇 개입니까?",
        "question_en": "There is only one white marble, one black marble, one purple marble, one green marble, and one red marble. How many combinations can you buy if you buy 2 marbles?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "[OP_LIST_SOL] 흰색 검은색 보라색 초록색 빨간색 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] white black purple green red [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '흰색'\nvar_b = '검은색'\nvar_c = '보라색'\nvar_d = '초록색'\nvar_e = '빨간색'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h / (i+1)\nprint(int(var_h))",
        "solution_code_en": "var_a = 'white'\nvar_b = 'black'\nvar_c = 'purple'\nvar_d = 'green'\nvar_e = 'red'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h / (i+1)\nprint(int(var_h))"
    },
    "7083": {
        "category": "Geometry",
        "question_ko": "오각형의 꼭지점 중 하나에서, 대각선을 그으면 삼각형이 몇 개 생길까요?",
        "question_en": "How many triangles will there be if you draw a diagonal from one of the vertices of the pentagon?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "5 3 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "5 3 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7084": {
        "category": "Possibility",
        "question_ko": "지우는 숫자가 적힌 자석 1, 2, 7을 가지고 있다. 이를 배치하여 두 자리 수를 만든다고 할 때 , 만들 수 있는 경우는 모두 몇 가지입니까?",
        "question_en": "Jiwoo has magnets which has 1, 2, and 7 numbers on them. If you arrange them to make a two-digit number, how many ways can he make it?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 1 2 7 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 2 7 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 2\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 2\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "7085": {
        "category": "Arithmetic calculation",
        "question_ko": "(가) 반 학생들은 8판의 피자를 먹었습니다. (나) 반 학생들은 7판의 피자를 먹었습니다. (가) 반과 (나) 반 학생들이 먹은 피자는 모두 몇 판입니까?",
        "question_en": "(A) class mates ate 8 pizzas. (B) class mates ate 7 pizzas. How many pizzas did the students in (a) and (b) eat?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "8 7 [OP_ADD]",
        "solution_abst_en": "8 7 [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 8\nvar_b = 7\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "7086": {
        "category": "Geometry",
        "question_ko": "네 변의 길이가 같은 사각형이 있습니다. 이 사각형의 대각선의 길이가 각각 6센티미터(㎝), 10센티미터(㎝)일 때 사각형의 넓이는 얼마입니까?",
        "question_en": "There is a rectangle with four sides the same length. What is the area of the rectangle if the diagonals of the rectangle are 6 centimeters (cm) and 10 centimeters (cm), respectively?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "6 10 [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "6 10 [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "7087": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 달팽이는 7/12센티미터(㎝)를 기어가는 데 5/18분이 걸립니다. 이 달팽이가 같은 빠르기로 기어간다면 1분 동안 갈 수 있는 거리는 몇 센티미터(㎝)인가요?",
        "question_en": "A snail takes 5/18 minutes to crawl 7/12 centimeters (cm). If this snail crawls at a constant speed, how many centimeters (cm) can it travel in 1 minute?",
        "answer_ko": "2.10",
        "answer_en": "2.1",
        "solution_abst_ko": "7/12 5/18 [OP_DIV] 1 [OP_MUL]",
        "solution_abst_en": "7/12 5/18 [OP_DIV] 1 [OP_MUL]",
        "solution_code_ko": "var_a = 0.5833333333333334\nvar_b = 0.2777777777777778\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.5833333333333334\nvar_b = 0.2777777777777778\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "7088": {
        "category": "Possibility",
        "question_ko": "3, 8, 2, 7의 숫자가 적힌 4 장의 카드를 모두 한 번씩 사용하여 소수 두 자리 수를 만들 때 세 번째로 큰 수를 쓰시오.",
        "question_en": "Write the third largest number when creating a two-digit decimal number using all four cards with numbers 3, 8, 2, and 7.",
        "answer_ko": "83.72",
        "answer_en": "83.72",
        "solution_abst_ko": "[OP_LIST_SOL] 3 8 2 7 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] 10 [OP_LIST_POP] [OP_LIST_LEN] 2 [OP_SUB] [OP_POW] [OP_DIV]",
        "solution_abst_en": "[OP_LIST_SOL] 3 8 2 7 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] 10 [OP_LIST_POP] [OP_LIST_LEN] 2 [OP_SUB] [OP_POW] [OP_DIV]",
        "solution_code_ko": "var_a = 3\nvar_b = 8\nvar_c = 2\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 10\nvar_i = len(list_a)\nvar_j = 2\nvar_k = var_i - var_j\nvar_l = var_h ** var_k\nvar_m = var_g / var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))",
        "solution_code_en": "var_a = 3\nvar_b = 8\nvar_c = 2\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 10\nvar_i = len(list_a)\nvar_j = 2\nvar_k = var_i - var_j\nvar_l = var_h ** var_k\nvar_m = var_g / var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))"
    },
    "7089": {
        "category": "Possibility",
        "question_ko": "정국, 지민, 윤기 중에서 2사람을 선택해서 줄 세우려고 합니다. 선택할 수 있는 경우는 모두 몇 가지 입니까?",
        "question_en": "I'm going to choose two people from Jungkook, Jimin, and Yoongi to line up. How many options are there in total?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 지민 윤기 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Jimin Yoongi [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '지민'\nvar_c = '윤기'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nprint(int(var_f))",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Jimin'\nvar_c = 'Yoongi'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nprint(int(var_f))"
    },
    "7090": {
        "category": "Possibility",
        "question_ko": "바구니에서 뽑을 수 있는 기회는 2번입니다. 바구니 속에 사과, 복숭아, 배가 각각 1개씩 들어가있는 바구니에서 차례를 고려하여 과일을 뽑는다면, 가능한 경우의 수는 몇 가지입니까?",
        "question_en": "You have 2 chances to pick from the basket. How many possible ways can fruit be picked from a basket with 1 apple, 1 peach, and 1 pear each?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 복숭아 배 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] apple peach pear [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '복숭아'\nvar_c = '배'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nprint(int(var_f))",
        "solution_code_en": "var_a = 'apple'\nvar_b = 'peach'\nvar_c = 'pear'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nvar_e = 2\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nprint(int(var_f))"
    },
    "7091": {
        "category": "Geometry",
        "question_ko": "도너츠의 안쪽에 있는 원의 반지름의 길이는 2센티미터(㎝)이고, 바깥쪽에 있는 원의 반지름의 길이는 6센티미터(㎝)입니다. 도너츠의 바깥쪽 둘레의 길이는 도너츠의 안쪽 둘레의 길이의 몇 배인지 구하시오.",
        "question_en": "The length of the radius of the circle inside the donut is 2 centimeters (cm), and the length of the radius of the circle on the outside is 6 centimeters (cm). Find how many times bigger the length of the outer circumference of the donut is compared to the length of the inner circumference of the donut.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "6 2 [OP_DIV]",
        "solution_abst_en": "6 2 [OP_DIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "7092": {
        "category": "Correspondence",
        "question_ko": "54는 어떤 수에서 39를 뺀 값이다. 어떤 수를 3으로 나눈다면 얼마가 되는가?",
        "question_en": "54 is this number minus 39. What do you get if this number is divided by 3?",
        "answer_ko": "31",
        "answer_en": "31",
        "solution_abst_ko": "39 54 [OP_ADD] 3 [OP_DIV]",
        "solution_abst_en": "39 54 [OP_ADD] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 39\nvar_b = 54\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 39\nvar_b = 54\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "7093": {
        "category": "Geometry",
        "question_ko": "선분AB 위에 4개의 점을 찍었다. 선분 AB위에 있지 않은 점 C와 4개의 점 중 2개를 연결하여 만들 수 있는 직선의 개수를 구하시오.",
        "question_en": "Place four points on the segment AB. Find the number of straight lines that can be formed by connecting two of the four points with point C that is not on line segment AB.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "4 1 [OP_ADD]",
        "solution_abst_en": "4 1 [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "7094": {
        "category": "Comparison",
        "question_ko": "유정이는 물을 7/10리터(L) 마셨습니다. 은지는 물을 0.5리터(L) 마셨습니다. 유나는 물을 6/10리터(L) 마셨습니다. 물을 가장 많이 마신 사람은 누구입니까?",
        "question_en": "Yujeong drank 7/10 liters (L) of water. Eunji drank 0.5 liters (L) of water. Yuna drank 6/10 liters (L) of water. Who drank the most water?",
        "answer_ko": "유정",
        "answer_en": "Yujeong",
        "solution_abst_ko": "[OP_LIST_SOL] 유정 은지 유나 [OP_LIST_EOL] [OP_LIST_SOL] 7 10 [OP_DIV] 0.5 6 10 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yujeong Eunji Yuna [OP_LIST_EOL] [OP_LIST_SOL] 7 10 [OP_DIV] 0.5 6 10 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '유정'\nvar_b = '은지'\nvar_c = '유나'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 7\nvar_e = 10\nvar_f = var_d / var_e\nvar_g = 0.5\nvar_h = 6\nvar_i = 10\nvar_j = var_h / var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'Yujeong'\nvar_b = 'Eunji'\nvar_c = 'Yuna'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 7\nvar_e = 10\nvar_f = var_d / var_e\nvar_g = 0.5\nvar_h = 6\nvar_i = 10\nvar_j = var_h / var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "7095": {
        "category": "Correspondence",
        "question_ko": "A4+B82=216일 때, A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "If A4+B82=216, what number should go in A?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "A4+B82=216 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A4+B82=216 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A4+B82=216'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A4+B82=216'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "7096": {
        "category": "Possibility",
        "question_ko": "연필 3종류와 지우개 2종류 중 연필과 지우개를 각각 하나씩 선택할 때, 경우의 수를 구하시오.",
        "question_en": "Find the number of cases of selecting one pencil and one eraser out of 3 types of pencils and 2 types of erasers.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "3 2 [OP_MUL]",
        "solution_abst_en": "3 2 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "7097": {
        "category": "Possibility",
        "question_ko": "귤 7개 중에서 6개를 고르려고 한다. 가능한 모든 경우의 수를 구하시오.",
        "question_en": "You are trying to choose 6 out of 7 tangerines. Find the number of all possible cases.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "7 6 [OP_COMB]",
        "solution_abst_en": "7 6 [OP_COMB]",
        "solution_code_ko": "var_a = 7\nvar_b = 6\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))",
        "solution_code_en": "var_a = 7\nvar_b = 6\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))"
    },
    "7098": {
        "category": "Geometry",
        "question_ko": "팔각형의 대각선의 개수를 A, 칠각형의 대각선의 개수를 B라 할 때, A-B의 값은?",
        "question_en": "If A is the number of diagonals in an octagon and B is the number of diagonals in a heptagon, what is the value of A-B?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "8 8 3 [OP_SUB] [OP_MUL] 2 [OP_DIV] 7 7 3 [OP_SUB] [OP_MUL] 2 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "8 8 3 [OP_SUB] [OP_MUL] 2 [OP_DIV] 7 7 3 [OP_SUB] [OP_MUL] 2 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 8\nvar_b = 8\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 7\nvar_i = 7\nvar_j = 3\nvar_k = var_i - var_j\nvar_l = var_h * var_k\nvar_m = 2\nvar_n = var_l / var_m\nvar_o = var_g - var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 8\nvar_b = 8\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 7\nvar_i = 7\nvar_j = 3\nvar_k = var_i - var_j\nvar_l = var_h * var_k\nvar_m = 2\nvar_n = var_l / var_m\nvar_o = var_g - var_n\nprint(int(var_o))"
    },
    "7099": {
        "category": "Correspondence",
        "question_ko": "70은 어떤수에 5를 곱하고 24를 더한 뒤 7로 나눠야 하는 것을 실수로 24를 더한 뒤 5로 나눈 다음 7을 곱해서 나온 결과입니다. 바르게 계산하면 얼마입니까?",
        "question_en": "70 is the result of adding 24, multiplying by 5, and dividing by 7 by mistake instead of multiplying by 5, adding 24, and dividing by 7 to a certain number. What is the value if it is correctly calculated?",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "70 7 [OP_DIV] 5 [OP_MUL] 24 [OP_SUB] 5 [OP_MUL] 24 [OP_ADD] 7 [OP_DIV]",
        "solution_abst_en": "70 7 [OP_DIV] 5 [OP_MUL] 24 [OP_SUB] 5 [OP_MUL] 24 [OP_ADD] 7 [OP_DIV]",
        "solution_code_ko": "var_a = 70\nvar_b = 7\nvar_c = var_a / var_b\nvar_d = 5\nvar_e = var_c * var_d\nvar_f = 24\nvar_g = var_e - var_f\nvar_h = 5\nvar_i = var_g * var_h\nvar_j = 24\nvar_k = var_i + var_j\nvar_l = 7\nvar_m = var_k / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 70\nvar_b = 7\nvar_c = var_a / var_b\nvar_d = 5\nvar_e = var_c * var_d\nvar_f = 24\nvar_g = var_e - var_f\nvar_h = 5\nvar_i = var_g * var_h\nvar_j = 24\nvar_k = var_i + var_j\nvar_l = 7\nvar_m = var_k / var_l\nprint(int(var_m))"
    },
    "7100": {
        "category": "Geometry",
        "question_ko": "재웅이가 도화지에 그린 마름모 모양의 지붕은 넓이가 80제곱센티미터(㎠) 였습니다. 이 지붕의 한 대각선의 길이가 16 센티미터(㎝)일 때 다른 대각선의 길이는 몇 센티미터(㎝)일까요?",
        "question_en": "Jaewoong drew the diamond-shaped roof on the drawing paper whose area is 80 square centimeters (cm2). If one diagonal of this roof is 16 centimeters (cm), how long is the other diagonal in centimeters (cm)?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "80 2 [OP_MUL] 16 [OP_DIV]",
        "solution_abst_en": "80 2 [OP_MUL] 16 [OP_DIV]",
        "solution_code_ko": "var_a = 80\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 16\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 80\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 16\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "7101": {
        "category": "Correspondence",
        "question_ko": "윤기는 두 자리 수에 57을 더하던 중, 윤기는 두 자리 수의 일의 자리 숫자 9를 6으로 잘못 봤습니다. 윤기가 구한 합이 123이라고 하면, 바르게 계산한 결과는 무엇인가요?",
        "question_en": "While Yoongi was adding 57 to the two-digit number, he mistook the 9 in the units digit of the two-digit number for 6. If the sum obtained by Yoongi is 123, what is the correct calculation result?",
        "answer_ko": "126",
        "answer_en": "126",
        "solution_abst_ko": "123 57 [OP_SUB] 6 9 [OP_SUB] [OP_SUB] 57 [OP_ADD]",
        "solution_abst_en": "123 57 [OP_SUB] 6 9 [OP_SUB] [OP_SUB] 57 [OP_ADD]",
        "solution_code_ko": "var_a = 123\nvar_b = 57\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nvar_h = 57\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 123\nvar_b = 57\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nvar_h = 57\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "7102": {
        "category": "Arithmetic calculation",
        "question_ko": "연주는 초콜렛 138개를 친구들에게 18개씩 나눠주고, 남은 것은 본인이 먹기로 하였습니다. 연주가 먹은 초콜릿이 친구 한 명이 받은 초콜릿보다 적을 때, 연주는 몇 개의 초콜릿을 먹었는지 구하시오.",
        "question_en": "Yeonjoo decided to share 18 of the 138 chocolates with her friends and eat the rest herself. If Yeonjoo ate less chocolate than one friend received, find how many chocolates she ate.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "138 18 [OP_MOD]",
        "solution_abst_en": "138 18 [OP_MOD]",
        "solution_code_ko": "var_a = 138\nvar_b = 18\nvar_c = var_a % var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 138\nvar_b = 18\nvar_c = var_a % var_b\nprint(int(var_c))"
    },
    "7103": {
        "category": "Arithmetic calculation",
        "question_ko": "바구니에 들어있는 사과 전체의 무게는 52킬로그램(㎏)입니다. 절반을 덜어내고 다시 무게를 재니 28킬로그램(㎏)였다면, 기존에 들어있던 사과만의 무게는 몇 킬로그램(㎏)입니까?",
        "question_en": "The total weight of the apples in the basket is 52 kilograms (kg). If it was 28 kg (kg) after removing half of it and weighing it again, how much kg (kg) were the apples alone?",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "52 28 [OP_SUB] 2 [OP_MUL]",
        "solution_abst_en": "52 28 [OP_SUB] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 52\nvar_b = 28\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 52\nvar_b = 28\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "7104": {
        "category": "Correspondence",
        "question_ko": "처음 사탕 개수에서 29만큼 빼고 또 13으로 나눠주면 15개밖에 안 남습니다. 처음 사탕 개수는 얼마입니까?",
        "question_en": "Subtract 29 from the original number of candies and divide by 13, leaving only 15 candies. What is the initial number of candies?",
        "answer_ko": "224",
        "answer_en": "224",
        "solution_abst_ko": "15 13 [OP_MUL] 29 [OP_ADD]",
        "solution_abst_en": "15 13 [OP_MUL] 29 [OP_ADD]",
        "solution_code_ko": "var_a = 15\nvar_b = 13\nvar_c = var_a * var_b\nvar_d = 29\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 13\nvar_c = var_a * var_b\nvar_d = 29\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7105": {
        "category": "Geometry",
        "question_ko": "정십이면체 모양의 상자가 있습니다. 모서리의 개수는?",
        "question_en": "There is a box in the shape of a regular dodecahedron. How many edges?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "30",
        "solution_abst_en": "30",
        "solution_code_ko": "var_a = 30\nprint(int(var_a))",
        "solution_code_en": "var_a = 30\nprint(int(var_a))"
    },
    "7106": {
        "category": "Possibility",
        "question_ko": "17개의 과일을 구매하려 한다. 다섯 종류의 과일을 1개 이상 구매하고 중복을 허용하여 구매한다면 과일을 사는 방법은 총 몇 가지인가?",
        "question_en": "You are going to buy 17 fruits. If you buy more than one of five types of fruit and allow duplicates, how many ways to buy fruit in total?",
        "answer_ko": "1820",
        "answer_en": "1820",
        "solution_abst_ko": "5 17 [OP_ADD] 5 1 [OP_MUL] [OP_SUB] 1 [OP_SUB] 17 5 1 [OP_MUL] [OP_SUB] [OP_COMB]",
        "solution_abst_en": "5 17 [OP_ADD] 5 1 [OP_MUL] [OP_SUB] 1 [OP_SUB] 17 5 1 [OP_MUL] [OP_SUB] [OP_COMB]",
        "solution_code_ko": "var_a = 5\nvar_b = 17\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = 1\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = 17\nvar_k = 5\nvar_l = 1\nvar_m = var_k * var_l\nvar_n = var_j - var_m\nvar_o = 1\nvar_i = int(var_i)\nvar_n = int(var_n)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o * (var_i-i)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o / (i+1)\nprint(int(var_o))",
        "solution_code_en": "var_a = 5\nvar_b = 17\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = 1\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = 17\nvar_k = 5\nvar_l = 1\nvar_m = var_k * var_l\nvar_n = var_j - var_m\nvar_o = 1\nvar_i = int(var_i)\nvar_n = int(var_n)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o * (var_i-i)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o / (i+1)\nprint(int(var_o))"
    },
    "7107": {
        "category": "Arithmetic calculation",
        "question_ko": "은지는 화요일에 책을 18쪽 읽었고, 수요일에도 읽었습니다. 이 책을 목요일에 23쪽 읽어서 3일 동안 모두 60쪽 읽었습니다. 은지는 수요일에 책을 몇 쪽 읽었습니까?",
        "question_en": "Eunji read 18 pages of the book on Tuesday, and read more on Wednesday as well. Then she read 23 pages of this book on Thursday, thus reading 60 pages in total for 3 days. How many pages did Eunji read on Wednesday?",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "60 18 [OP_SUB] 23 [OP_SUB]",
        "solution_abst_en": "60 18 [OP_SUB] 23 [OP_SUB]",
        "solution_code_ko": "var_a = 60\nvar_b = 18\nvar_c = var_a - var_b\nvar_d = 23\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 60\nvar_b = 18\nvar_c = var_a - var_b\nvar_d = 23\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "7108": {
        "category": "Possibility",
        "question_ko": "0, 1, 3, 5, 7, 중 서로 다른 숫자 2개를 뽑아 두 자리 수를 만들려고 합니다. 가능한 두 자리 수는 모두 몇 개 일까요?",
        "question_en": "I want to create a two-digit number by drawing two different numbers from 0, 1, 3, 5, 7. How many possible two-digit numbers are there?",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 3 5 7 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 3 5 7 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 3\nvar_d = 5\nvar_e = 7\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 3\nvar_d = 5\nvar_e = 7\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "7109": {
        "category": "Arithmetic calculation",
        "question_ko": "지민이네 반 학생 수는 40명입니다. 지민, 정국이의 수학 점수는 각각 98점, 100점입니다. 이 2명을 제외한 학생들의 수학 평균 점수는 79점입니다. 지민이네 반 수학 평균 점수는 몇 점입니까?",
        "question_en": "There are 40 students in Jimin's class. Jimin and Jungkook's math scores are 98 and 100, respectively. Excluding these two students, the average score in math is 79. What is the average math score of Jimin's class?",
        "answer_ko": "80",
        "answer_en": "80",
        "solution_abst_ko": "40 2 [OP_SUB] 79 [OP_MUL] 98 [OP_ADD] 100 [OP_ADD] 40 [OP_DIV]",
        "solution_abst_en": "40 2 [OP_SUB] 79 [OP_MUL] 98 [OP_ADD] 100 [OP_ADD] 40 [OP_DIV]",
        "solution_code_ko": "var_a = 40\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 79\nvar_e = var_c * var_d\nvar_f = 98\nvar_g = var_e + var_f\nvar_h = 100\nvar_i = var_g + var_h\nvar_j = 40\nvar_k = var_i / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 40\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 79\nvar_e = var_c * var_d\nvar_f = 98\nvar_g = var_e + var_f\nvar_h = 100\nvar_i = var_g + var_h\nvar_j = 40\nvar_k = var_i / var_j\nprint(int(var_k))"
    },
    "7110": {
        "category": "Geometry",
        "question_ko": "꿀벌의 집은 정육각형 모양입니다. 꿀벌의 집의 둘레가 43.56밀리미터(㎜)일 때 한 변의 길이는 얼마일지 구하시오.",
        "question_en": "The bee hive is shaped like a regular hexagon. If the circumference of the bee hive is 43.56 millimeters (mm), what is the length of one side?",
        "answer_ko": "7.26",
        "answer_en": "7.26",
        "solution_abst_ko": "43.56 6 [OP_DIV]",
        "solution_abst_en": "43.56 6 [OP_DIV]",
        "solution_code_ko": "var_a = 43.56\nvar_b = 6\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 43.56\nvar_b = 6\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "7111": {
        "category": "Correspondence",
        "question_ko": "지민이는 34에 어떤 수를 빼려고 합니다. 실수로 20에 어떤 수를 뺐을 때의 결과가 60이라면 바르게 계산한 결과를 구하세요.",
        "question_en": "While Jimin tried to subtract a number from 34, he subtracted a number from 20 by mistake and got 60. Write down the result of the correct calculation.",
        "answer_ko": "74",
        "answer_en": "74",
        "solution_abst_ko": "34 20 60 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "34 20 60 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 34\nvar_b = 20\nvar_c = 60\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 34\nvar_b = 20\nvar_c = 60\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "7112": {
        "category": "Correspondence",
        "question_ko": "어떤 소수의 소수점을 오른쪽으로 한 칸 옮겼더니 원래의 값보다 5.4 커졌습니다. 원래 소수는 무엇이었는지 구하시오.",
        "question_en": "Moving a decimal point of a prime number to the right by one place makes it 5.4 more than the original value. What was the original prime number?",
        "answer_ko": "0.60",
        "answer_en": "0.6",
        "solution_abst_ko": "5.4 9 [OP_DIV]",
        "solution_abst_en": "5.4 9 [OP_DIV]",
        "solution_code_ko": "var_a = 5.4\nvar_b = 9\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 5.4\nvar_b = 9\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "7113": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 주머니가 있습니다. 각 주머니에는 16개의 동전이 있을 때 동전의 개수는 모두 몇 개인가요?",
        "question_en": "There are 4 pockets. If there are 16 coins in each pocket, what is the total number of coins?",
        "answer_ko": "64",
        "answer_en": "64",
        "solution_abst_ko": "16 4 [OP_MUL]",
        "solution_abst_en": "16 4 [OP_MUL]",
        "solution_code_ko": "var_a = 16\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 16\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "7114": {
        "category": "Arithmetic calculation",
        "question_ko": "달리기 시합에 참가한 1학년 학생 수의 5배가 달리기 시합에 참가한 2학년 학생 수와 같습니다. 1학년 학생이 8명 참가하였다면 달리기 시합에 참가한 1학년과 2학년 학생은 모두 몇 명입니까?",
        "question_en": "Given that 5 times the number of students in first grade who participated in a running competition is the same as the number of students in second grade participating in the match. If only 8 students were from the first grade, how many students participated in the running race in total?",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "8 5 [OP_MUL] 8 [OP_ADD]",
        "solution_abst_en": "8 5 [OP_MUL] 8 [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7115": {
        "category": "Geometry",
        "question_ko": "바둑돌을 한 변의 개수가 5개인 정사각형이 되도록 빈틈없이 규칙적으로 늘어 놓았습니다. 둘레에 놓인 바둑돌의 개수는 몇 개입니까?",
        "question_en": "The stones are laid out in a tight, regular row to form a square with 5 stones at the sides. What is the number of stones laid out on the perimeter?",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "5 4 [OP_MUL] 4 [OP_SUB]",
        "solution_abst_en": "5 4 [OP_MUL] 4 [OP_SUB]",
        "solution_code_ko": "var_a = 5\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "7116": {
        "category": "Arithmetic calculation",
        "question_ko": "유나는 사탕을 60개 가지고 있었습니다. 일주일 동안 하루에 6개씩 먹었고, 앞으로는 하루에 3개씩 먹으려고 합니다. 유나는 앞으로 사탕을 며칠 더 먹을 수 있는지 구하시오.",
        "question_en": "Yuna had 60 candies. She ate 6 pieces everyday for a week, and she plan to eat 3 pieces a day from now on. How many more days she can eat candy?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "60 6 7 [OP_MUL] [OP_SUB] 3 [OP_DIV]",
        "solution_abst_en": "60 6 7 [OP_MUL] [OP_SUB] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 60\nvar_b = 6\nvar_c = 7\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 3\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 60\nvar_b = 6\nvar_c = 7\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 3\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "7117": {
        "category": "Arithmetic calculation",
        "question_ko": "똑같은 책 14 권이 들어 있는 가방의 무게는 11.14킬로그램(㎏) 입니다. 빈 가방의 무게가 0.5킬로그램(㎏) 이라면 책 한 권의 무게는 몇 킬로그램(㎏)입니까?",
        "question_en": "A bag containing 14 identical books weighs 11.14 kilograms (kg). If the empty bag weighs 0.5 kilograms (kg), how much does one book weigh in kilograms (kg)?",
        "answer_ko": "0.76",
        "answer_en": "0.76",
        "solution_abst_ko": "11.14 0.5 [OP_SUB] 14 [OP_DIV]",
        "solution_abst_en": "11.14 0.5 [OP_SUB] 14 [OP_DIV]",
        "solution_code_ko": "var_a = 11.14\nvar_b = 0.5\nvar_c = var_a - var_b\nvar_d = 14\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 11.14\nvar_b = 0.5\nvar_c = var_a - var_b\nvar_d = 14\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "7118": {
        "category": "Possibility",
        "question_ko": "학생들을 2그룹으로 나누려고 합니다. 정국, 지민, 윤기, 유나, 태형을 나누는 경우는 모두 몇 가지입니까? 각 그룹의 학생 수 차이는 1명 입니다.",
        "question_en": "We are going to divide the students into 2 groups. How many ways can you divide Jungkook, Jimin, Yoongi, Yuna, and Taehyung? The difference in the number of students in each group is 1 student.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 지민 윤기 유나 태형 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Jimin Yoongi Yuna Taehyung [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '지민'\nvar_c = '윤기'\nvar_d = '유나'\nvar_e = '태형'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h / (i+1)\nprint(int(var_h))",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Jimin'\nvar_c = 'Yoongi'\nvar_d = 'Yuna'\nvar_e = 'Taehyung'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h / (i+1)\nprint(int(var_h))"
    },
    "7119": {
        "category": "Comparison",
        "question_ko": "정국, 지민, 석진, 태형, 남준이가 일렬로 줄을 서 있습니다. 정국이는 지민이의 오른쪽 옆에 서 있고, 석진이는 지민이의 왼쪽 옆에 서 있습니다. 태형이의 왼쪽 옆에서는 정국이가, 남준이는 석진이 왼쪽 옆에 서 있을 때, 가장 오른 쪽에 서 있는 사람은 누구 입니까?",
        "question_en": "Jungkook, Jimin, Seokjin, Taehyung, and Namjoon are lined up in a row. Jungkook is standing to the right of Jimin, and Seokjin is standing to the left of Jimin. When Jeongguk is standing next to Taehyung's left and Seokjin is standing next to Namjoon's left, who is standing to the far right?",
        "answer_ko": "태형",
        "answer_en": "Taehyung",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 지민 석진 태형 남준 [OP_LIST_EOL] [OP_LIST_SOL] 정국 지민 > 석진 지민 < 남준 석진 < 정국 태형 < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Jimin Seokjin Taehyung Namjoon [OP_LIST_EOL] [OP_LIST_SOL] Jungkook Jimin > Seokjin Jimin < Namjoon Seokjin < Jungkook Taehyung < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '지민'\nvar_c = '석진'\nvar_d = '태형'\nvar_e = '남준'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = '정국'\nvar_g = '지민'\nvar_h = '>'\nvar_i = '석진'\nvar_j = '지민'\nvar_k = '<'\nvar_l = '남준'\nvar_m = '석진'\nvar_n = '<'\nvar_o = '정국'\nvar_p = '태형'\nvar_q = '<'\nlist_b= []\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_r = 1\nvar_s = list_c[var_r-1]\nprint(var_s)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Jimin'\nvar_c = 'Seokjin'\nvar_d = 'Taehyung'\nvar_e = 'Namjoon'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 'Jungkook'\nvar_g = 'Jimin'\nvar_h = '>'\nvar_i = 'Seokjin'\nvar_j = 'Jimin'\nvar_k = '<'\nvar_l = 'Namjoon'\nvar_m = 'Seokjin'\nvar_n = '<'\nvar_o = 'Jungkook'\nvar_p = 'Taehyung'\nvar_q = '<'\nlist_b= []\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_r = 1\nvar_s = list_c[var_r-1]\nprint(var_s)"
    },
    "7120": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 14미터(m)인 정사각형의 네 변의 길이의 합은 몇 미터(m)인지 소수점을 포함하여 구하시오.",
        "question_en": "Including the decimal point, find the sum of the lengths of the four sides of a square with a side length of 14 meters (m), in meters (m).",
        "answer_ko": "5.60",
        "answer_en": "5.6",
        "solution_abst_ko": "14 4 [OP_MUL] 10 [OP_DIV]",
        "solution_abst_en": "14 4 [OP_MUL] 10 [OP_DIV]",
        "solution_code_ko": "var_a = 14\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 10\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 14\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 10\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "7121": {
        "category": "Possibility",
        "question_ko": "정국이는 빨간 공 5개, 파란 공 4개, 노란 공 3개를 가지고 있습니다. 정국이가 윤기에게 파란 공 1개를 주었을 때, 정국이는 노란 공을 몇 개 가지고 있습니까?",
        "question_en": "Jungkook has 5 red balls, 4 blue balls, and 3 yellow balls. When Jungkook gives Yoongi 1 blue ball, how many yellow balls does Jungkook have?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "3",
        "solution_abst_en": "3",
        "solution_code_ko": "var_a = 3\nprint(int(var_a))",
        "solution_code_en": "var_a = 3\nprint(int(var_a))"
    },
    "7122": {
        "category": "Arithmetic calculation",
        "question_ko": "15 초과 40 미만인 자연수 중에서 3 으로 나누어 떨어지는 수는 모두 몇 개입니까?",
        "question_en": "How many natural numbers greater than 15 and less than 40 are divisible by 3?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "15 1 [OP_ADD] 40 1 [OP_SUB] 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "15 1 [OP_ADD] 40 1 [OP_SUB] 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 15\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 40\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = 3\nlist_b = []\nvar_h = int(var_h)\nfor i in list_a:\n    i = int(i)\n    if i % var_h == 0:\n        list_b.append(i)\nvar_i = len(list_b)\nprint(int(var_i))",
        "solution_code_en": "var_a = 15\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 40\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = 3\nlist_b = []\nvar_h = int(var_h)\nfor i in list_a:\n    i = int(i)\n    if i % var_h == 0:\n        list_b.append(i)\nvar_i = len(list_b)\nprint(int(var_i))"
    },
    "7123": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이는 3개, 윤기는 2개의 공이 있습니다. 정국이와 윤기가 가지고 있는 공의 개수는 몇 개입니까?",
        "question_en": "Jungkook has 3 balls and Yoongi has 2 balls. How many balls do Jungkook and Yoongi have?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "3 2 [OP_ADD]",
        "solution_abst_en": "3 2 [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "7124": {
        "category": "Geometry",
        "question_ko": "정사각형의 둘레가 17.8센티미터(㎝)입니다. 이 정사각형의 한 변 길이를 구하시오.",
        "question_en": "The perimeter of the square is 17.8 centimeters (cm). Find the length of one side of this square.",
        "answer_ko": "4.45",
        "answer_en": "4.45",
        "solution_abst_ko": "17.8 4 [OP_DIV]",
        "solution_abst_en": "17.8 4 [OP_DIV]",
        "solution_code_ko": "var_a = 17.8\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 17.8\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "7125": {
        "category": "Arithmetic calculation",
        "question_ko": "윤기네 반 전체 학생 수는 32명입니다. 그중에서 남학생은 전체의 5/8입니다. 남학생 중에서 안경을 낀 학생은 남학생 전체의 3/4입니다. 윤기네 반에서 안경을 끼지 않은 남학생은 몇 명입니까?",
        "question_en": "The total number of students in Yoongi's class is 32. Among them, male students account for 5/8 of the total. Among male students, 3/4 of all male students wear glasses. How many male students in Yoongi's class do not wear glasses?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "32 5/8 [OP_MUL] 1 3/4 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "32 5/8 [OP_MUL] 1 3/4 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 32\nvar_b = 0.625\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 0.75\nvar_f = var_d - var_e\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 32\nvar_b = 0.625\nvar_c = var_a * var_b\nvar_d = 1\nvar_e = 0.75\nvar_f = var_d - var_e\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "7126": {
        "category": "Geometry",
        "question_ko": "지름이 100 센티미터(㎝) 인 훌라후프의 둘레를 재어 보니 314 센티미터(㎝) 였습니다. 훌라후프의 둘레는 지름의 몇 배입니까?",
        "question_en": "I measured the circumference of a hula hoop with a diameter of 100 centimeters (cm) and it was 314 centimeters(cm). How many times bigger is the circumference of this hula hoop compared to its diameter?",
        "answer_ko": "3.14",
        "answer_en": "3.14",
        "solution_abst_ko": "314 100 [OP_DIV]",
        "solution_abst_en": "314 100 [OP_DIV]",
        "solution_code_ko": "var_a = 314\nvar_b = 100\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 314\nvar_b = 100\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "7127": {
        "category": "Geometry",
        "question_ko": "장난감 피라미드의 모든 모서리의 합이 14.8미터(m)입니다. 피라미드는 모든 모서리가 같도록 만들어졌을 때, 한 모서리의 길이는 얼마입니까? 미터(m)로 구하시오.",
        "question_en": "The sum of all the edges of the toy pyramid is 14.8 meters (m). What is the length of one edge of the pyramid if all edges are made the same? Find in meters (m).",
        "answer_ko": "1.85",
        "answer_en": "1.85",
        "solution_abst_ko": "14.8 4 2 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "14.8 4 2 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 14.8\nvar_b = 4\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 14.8\nvar_b = 4\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "7128": {
        "category": "Possibility",
        "question_ko": "2, 4, 5, 8을 한 번씩 모두 사용하여 두 자리 수끼리의 뺄셈식을 만들려고 합니다. 차가 가장 클 때의 결과값을 구하시오.",
        "question_en": "We are trying to create a subtraction equation between two digits using 2, 4, 5, and 8 all at once. Find the result when the difference is largest.",
        "answer_ko": "61",
        "answer_en": "61",
        "solution_abst_ko": "[OP_LIST_SOL] 2 4 5 8 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB] 10 [OP_MUL] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_SUB] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 2 4 5 8 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB] 10 [OP_MUL] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = 5\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f - var_h\nvar_j = 10\nvar_k = var_i * var_j\nvar_l = 2\nlist_d=list_a.copy()\nlist_d.sort()\nvar_m = list_d[-var_l]\nvar_n = 2\nlist_e=list_a.copy()\nlist_e.sort()\nvar_o = list_e[var_n-1]\nvar_p = var_m - var_o\nvar_q = var_k + var_p\nprint(int(var_q))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = 5\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f - var_h\nvar_j = 10\nvar_k = var_i * var_j\nvar_l = 2\nlist_d=list_a.copy()\nlist_d.sort()\nvar_m = list_d[-var_l]\nvar_n = 2\nlist_e=list_a.copy()\nlist_e.sort()\nvar_o = list_e[var_n-1]\nvar_p = var_m - var_o\nvar_q = var_k + var_p\nprint(int(var_q))"
    },
    "7129": {
        "category": "Comparison",
        "question_ko": "키가 작은 사람부터 순서대로 9명이 한 줄로 서 있습니다. 호석이는 앞에서부터 2번째에 서 있고, 유나는 호석이로부터 3번째 뒤에 서 있습니다. 키가 큰 사람부터 순서대로 다시 줄을 서면 유나는 앞에서부터 몇 번째에 서게 됩니까?",
        "question_en": "Nine people stand in a line in order from the shortest to the tallest. Hoseok stands at the 2nd from the front, and Yuna stands the 3rd behind Hoseok. If you organize the line again in order from the tallest people, what place will Yuna stand from the front?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "9 2 [OP_SUB] 3 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "9 2 [OP_SUB] 3 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 9\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 9\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "7130": {
        "category": "Correspondence",
        "question_ko": "AB+BC=BCB를 만족하는 A를 구하시오",
        "question_en": "Find A when AB+BC=BCB",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "AB+BC=BCB A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "AB+BC=BCB A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'AB+BC=BCB'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'AB+BC=BCB'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "7131": {
        "category": "Correspondence",
        "question_ko": "A는 238입니다. A는 B보다 143만큼 큽니다. B는 C보다 304만큼 작습니다. A+C의 값을 구하시오.",
        "question_en": "A is 238. A is greater than B by 143. B is lesser than C by 304. Find the value of A+C.",
        "answer_ko": "637",
        "answer_en": "637",
        "solution_abst_ko": "238 238 143 [OP_SUB] 304 [OP_ADD] [OP_ADD]",
        "solution_abst_en": "238 238 143 [OP_SUB] 304 [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 238\nvar_b = 238\nvar_c = 143\nvar_d = var_b - var_c\nvar_e = 304\nvar_f = var_d + var_e\nvar_g = var_a + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 238\nvar_b = 238\nvar_c = 143\nvar_d = var_b - var_c\nvar_e = 304\nvar_f = var_d + var_e\nvar_g = var_a + var_f\nprint(int(var_g))"
    },
    "7132": {
        "category": "Geometry",
        "question_ko": "정사각형 모양의 카드가 여러 장 있습니다. 이 카드를 빈틈없이 늘어놓아 정사각형을 만들고 보니 36장이 남아서, 가로 한 변과 세로 한 변을 1열씩 늘렸더니 아직도 3장이 남았습니다. 카드는 모두 몇 장입니까?",
        "question_en": "There are several square-shaped cards. When I laid out these cards to form a square, there were 36 cards left outside the square, so I increased one horizontal and one vertical side by one column, and there were still 3 cards left. How many cards are there in all?",
        "answer_ko": "292",
        "answer_en": "292",
        "solution_abst_ko": "36 3 [OP_SUB] 1 [OP_SUB] 2 [OP_DIV] 2 [OP_POW] 36 [OP_ADD]",
        "solution_abst_en": "36 3 [OP_SUB] 1 [OP_SUB] 2 [OP_DIV] 2 [OP_POW] 36 [OP_ADD]",
        "solution_code_ko": "var_a = 36\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 36\nvar_k = var_i + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 36\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 36\nvar_k = var_i + var_j\nprint(int(var_k))"
    },
    "7133": {
        "category": "Geometry",
        "question_ko": "이십각형의 한 꼭짓점에서 그을 수 있는 대각선의 개수를 구하시오.",
        "question_en": "Find the number of diagonals that can be drawn from one vertex of the icosahedron.",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "20 3 [OP_SUB]",
        "solution_abst_en": "20 3 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 20\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "7134": {
        "category": "Correspondence",
        "question_ko": "A는 한 자리 수입니다. 나눗셈 9A5÷5<197에서 A가 될 수 있는 모든 숫자의 합을 구하시오.",
        "question_en": "A is a single digit number. Find the sum of all possible numbers that can be A in division 9A5÷5<197.",
        "answer_ko": "28",
        "answer_en": "28",
        "solution_abst_ko": "9A5÷5<197 A [OP_DIGIT_UNK_SOLVER] [OP_LIST_SUM]",
        "solution_abst_en": "9A5÷5<197 A [OP_DIGIT_UNK_SOLVER] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = '9A5÷5<197'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nprint(int(var_c))",
        "solution_code_en": "var_a = '9A5÷5<197'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nprint(int(var_c))"
    },
    "7135": {
        "category": "Correspondence",
        "question_ko": "1분에 4개의 상의를 만드는 기계와 1분에 7개의 하의를 만드는 기계가 있다. 몇 분동안 기계가 만든 상의에 기존에 있던 상의 12벌을 더하니 36벌이 되었다. 그 시간동안 기계가 만든 하의는 몇 개인지 구하시오.",
        "question_en": "There is a machine that makes 4 tops per minute and a machine that makes 7 bottoms per minute. Adding 12 existing tops to the machine-made tops in a few minutes resulted in 36 pieces. Find how many bottoms the machine made during that time.",
        "answer_ko": "42",
        "answer_en": "42",
        "solution_abst_ko": "36 12 [OP_SUB] 7 [OP_MUL] 4 [OP_DIV]",
        "solution_abst_en": "36 12 [OP_SUB] 7 [OP_MUL] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 36\nvar_b = 12\nvar_c = var_a - var_b\nvar_d = 7\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 36\nvar_b = 12\nvar_c = var_a - var_b\nvar_d = 7\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "7136": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 100까지의 자연수 중 일의 자리 수가 0인 수의 개수를 구하시오.",
        "question_en": "Find the number of natural numbers from 1 to 100 in which the units digit is 0.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "1 100 1 [OP_LIST_ARANGE] 1 0 [OP_LIST_SEARCH_FIXED_DIGIT] [OP_LIST_LEN]",
        "solution_abst_en": "1 100 1 [OP_LIST_ARANGE] 1 0 [OP_LIST_SEARCH_FIXED_DIGIT] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 1\nvar_e = 0\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i in list_a:\n    i = int(i)\n    if (i//var_d)%10 == var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 1\nvar_e = 0\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i in list_a:\n    i = int(i)\n    if (i//var_d)%10 == var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "7137": {
        "category": "Correspondence",
        "question_ko": "서로 다른 숫자 A, B, C, D를 포함한 식 AB4C+17D8=5671이 있을 때 A가 아니라 B를 구하시오.",
        "question_en": "Given the expression AB4C+17D8=5671 containing the different numbers A, B, C, and D, find B, not A.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "AB4C+17D8=5671 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "AB4C+17D8=5671 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'AB4C+17D8=5671'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'AB4C+17D8=5671'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "7138": {
        "category": "Correspondence",
        "question_ko": "상자 안에 사탕이 들어 있습니다. 이 사탕을 20개씩 포장하면 4 개가 남고, 30개씩 포장하면 14개가 남고, 50개씩 포장하면 24개가 남고, 70개씩 포장하면 34개가 남습니다. 상자 안에 들어있는 사탕은 최소 몇 개인지 구하시오.",
        "question_en": "There are candies inside a box. When packed in sets of 20, there are 4 left over; when packed in sets of 30, there are 14 left over; when packed in sets of 50, there are 24 left over; and when packed in sets of 70, there are 34 left over. Determine the minimum number of candies inside the box.",
        "answer_ko": "524",
        "answer_en": "524",
        "solution_abst_ko": "0 9999 1 [OP_LIST_ARANGE] 20 4 [OP_LIST_DIVIDE_AND_REMAIN] 30 14 [OP_LIST_DIVIDE_AND_REMAIN] 50 24 [OP_LIST_DIVIDE_AND_REMAIN] 70 34 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MIN]",
        "solution_abst_en": "0 9999 1 [OP_LIST_ARANGE] 20 4 [OP_LIST_DIVIDE_AND_REMAIN] 30 14 [OP_LIST_DIVIDE_AND_REMAIN] 50 24 [OP_LIST_DIVIDE_AND_REMAIN] 70 34 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 0\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 20\nvar_e = 4\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 30\nvar_g = 14\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 50\nvar_i = 24\nlist_d = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_c:\n    i = int(i)\n    if i%var_h == var_i:\n        list_d.append(i)\nvar_j = 70\nvar_k = 34\nlist_e = [] \nvar_j = int(var_j)\nvar_k = int(var_k)\nif var_k < 0:\n    var_k = var_k + var_j\nfor i in list_d:\n    i = int(i)\n    if i%var_j == var_k:\n        list_e.append(i)\nvar_l = 1\nlist_f=list_e.copy()\nlist_f.sort()\nvar_m = list_f[var_l-1]\nprint(int(var_m))",
        "solution_code_en": "var_a = 0\nvar_b = 9999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 20\nvar_e = 4\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 30\nvar_g = 14\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 50\nvar_i = 24\nlist_d = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_c:\n    i = int(i)\n    if i%var_h == var_i:\n        list_d.append(i)\nvar_j = 70\nvar_k = 34\nlist_e = [] \nvar_j = int(var_j)\nvar_k = int(var_k)\nif var_k < 0:\n    var_k = var_k + var_j\nfor i in list_d:\n    i = int(i)\n    if i%var_j == var_k:\n        list_e.append(i)\nvar_l = 1\nlist_f=list_e.copy()\nlist_f.sort()\nvar_m = list_f[var_l-1]\nprint(int(var_m))"
    },
    "7139": {
        "category": "Correspondence",
        "question_ko": "A, B는 한 자리 수입니다. A2468B가 55의 배수일 때, 이 수가 될 수 있는 수는 모두 몇 개입니까?",
        "question_en": "A and B are single-digit numbers. If A2468B is a multiple of 55, how many possible numbers can this number be?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "A2468B [OP_GEN_POSSIBLE_LIST] 55 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "A2468B [OP_GEN_POSSIBLE_LIST] 55 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 'A2468B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 55\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A2468B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 55\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))"
    },
    "7140": {
        "category": "Geometry",
        "question_ko": "정이십면체의 면의 변의 개수는?",
        "question_en": "How many sides are there on the face of an icosahedron?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "3",
        "solution_abst_en": "3",
        "solution_code_ko": "var_a = 3\nprint(int(var_a))",
        "solution_code_en": "var_a = 3\nprint(int(var_a))"
    },
    "7141": {
        "category": "Geometry",
        "question_ko": "직각삼각형의 빗변과 빗변이 아닌 한변의 길이는 각각 13과 12입니다. 나머지 한 변의 길이는?",
        "question_en": "The lengths of the hypotenuse and non-hypotenuse of a right triangle are 13 and 12, respectively. What is the length of the other side?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "13 2 [OP_POW] 12 2 [OP_POW] [OP_SUB] 1/2 [OP_POW]",
        "solution_abst_en": "13 2 [OP_POW] 12 2 [OP_POW] [OP_SUB] 1/2 [OP_POW]",
        "solution_code_ko": "var_a = 13\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 12\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c - var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 13\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 12\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c - var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))"
    },
    "7142": {
        "category": "Arithmetic calculation",
        "question_ko": "서윤이네 집에서 할머니 댁까지 가는 데 한 시간에 120 킬로미터(㎞)를 가는 기차로 2시간 동안 갔더니 할머니 댁까지 남은 거리가 2.4 킬로미터(㎞)였습니다. 서윤이네 집에서 할머니 댁까지 일정한 빠르기로 가는 자동차로 3시간이 걸렸다면 자동차는 한 시간 동안 몇 킬로미터(㎞)를 간 것입니까?",
        "question_en": "Seoyoon traveled by train that goes 120 kilometers (km) per hour to get from her house to her grandmother's house. After traveling for 2 hours by train, the remaining distance to her grandmother's house was 2.4 kilometers (km). If it took 3 hours by car to go from Seoyoon's house to grandmother's house at a constant speed, how many kilometers (km) does the car travel per hour?",
        "answer_ko": "80.80",
        "answer_en": "80.8",
        "solution_abst_ko": "120 2 [OP_MUL] 2.4 [OP_ADD] 3 [OP_DIV]",
        "solution_abst_en": "120 2 [OP_MUL] 2.4 [OP_ADD] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 120\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 2.4\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 120\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 2.4\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "7143": {
        "category": "Possibility",
        "question_ko": "0, 4, 6, 7, 8 중에 한 번씩만 사용하여 만들 수 있는 다섯 자리 수 중에서 가장 작은 수를 구하시오.",
        "question_en": "Find the smallest five-digit number that can be formed using 0, 4, 6, 7, and 8 once.",
        "answer_ko": "40678",
        "answer_en": "40678",
        "solution_abst_ko": "[OP_LIST_SOL] 0 4 6 7 8 [OP_LIST_EOL] 5 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 4 6 7 8 [OP_LIST_EOL] 5 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 0\nvar_b = 4\nvar_c = 6\nvar_d = 7\nvar_e = 8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 5\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nprint(int(var_h))",
        "solution_code_en": "var_a = 0\nvar_b = 4\nvar_c = 6\nvar_d = 7\nvar_e = 8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 5\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nprint(int(var_h))"
    },
    "7144": {
        "category": "Arithmetic calculation",
        "question_ko": "10원짜리 50원짜리 동전의 개수가 같으며 10원짜리, 50원짜리, 100원짜리 동전이 모두 12개 있습니다. 총 금액이 500원이라면 100원짜리는 몇 개 있습니까?",
        "question_en": "There is a same number of 10-won and 50-won coins, and there are a total 12 of 10-won, 50-won, and 100-won coins. If the total amount is 500-won, how many 100-won coins are there?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "12 500 100 12 [OP_MUL] [OP_SUB] 10 50 [OP_ADD] 100 2 [OP_MUL] [OP_SUB] [OP_DIV] 2 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "12 500 100 12 [OP_MUL] [OP_SUB] 10 50 [OP_ADD] 100 2 [OP_MUL] [OP_SUB] [OP_DIV] 2 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 12\nvar_b = 500\nvar_c = 100\nvar_d = 12\nvar_e = var_c * var_d\nvar_f = var_b - var_e\nvar_g = 10\nvar_h = 50\nvar_i = var_g + var_h\nvar_j = 100\nvar_k = 2\nvar_l = var_j * var_k\nvar_m = var_i - var_l\nvar_n = var_f / var_m\nvar_o = 2\nvar_p = var_n * var_o\nvar_q = var_a - var_p\nprint(int(var_q))",
        "solution_code_en": "var_a = 12\nvar_b = 500\nvar_c = 100\nvar_d = 12\nvar_e = var_c * var_d\nvar_f = var_b - var_e\nvar_g = 10\nvar_h = 50\nvar_i = var_g + var_h\nvar_j = 100\nvar_k = 2\nvar_l = var_j * var_k\nvar_m = var_i - var_l\nvar_n = var_f / var_m\nvar_o = 2\nvar_p = var_n * var_o\nvar_q = var_a - var_p\nprint(int(var_q))"
    },
    "7145": {
        "category": "Geometry",
        "question_ko": "어떤 정육면체의 겉넓이는 486제곱센티미터(㎠)일 때, 모든 모서리의 길이의 합은 몇 센티미터(㎝)인지 구하시오",
        "question_en": "If the surface area of a cube is 486 square centimeters (cm2), how many centimeters (cm) is the sum of the lengths of all its edges?",
        "answer_ko": "108",
        "answer_en": "108",
        "solution_abst_ko": "486 6 [OP_DIV] 0.5 [OP_POW] 12 [OP_MUL]",
        "solution_abst_en": "486 6 [OP_DIV] 0.5 [OP_POW] 12 [OP_MUL]",
        "solution_code_ko": "var_a = 486\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 12\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 486\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 12\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "7146": {
        "category": "Correspondence",
        "question_ko": "A는 1자리 수입니다. 3.4<3.A<4, 4/3>4/A>4/6인 A는 무엇입니까?",
        "question_en": "A is a single digit number. What is A that satisfies 3.4<3.A<4, 4/3>4/A>4/6?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "3.4<3.A<4 A [OP_DIGIT_UNK_SOLVER] 4/3>4/A>4/6 A [OP_DIGIT_UNK_SOLVER] [OP_SET_INTERSECT] 1 [OP_LIST_GET]",
        "solution_abst_en": "3.4<3.A<4 A [OP_DIGIT_UNK_SOLVER] 4/3>4/A>4/6 A [OP_DIGIT_UNK_SOLVER] [OP_SET_INTERSECT] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '3.4<3.A<4'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = '4/3>4/A>4/6'\nvar_d = 'A'\nans_dict = dict()\nvar_c = var_c.replace('×','*')\nvar_c = var_c.replace('x','*')\nvar_c = var_c.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_c):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_c\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_c):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_b = list(set(ans_dict[var_d]))\nlist_c = list(set(list_a) & set(list_b))\nvar_e = 1\nvar_f = list_c[var_e-1]\nprint(int(var_f))",
        "solution_code_en": "var_a = '3.4<3.A<4'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = '4/3>4/A>4/6'\nvar_d = 'A'\nans_dict = dict()\nvar_c = var_c.replace('×','*')\nvar_c = var_c.replace('x','*')\nvar_c = var_c.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_c):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_c\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_c):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_b = list(set(ans_dict[var_d]))\nlist_c = list(set(list_a) & set(list_b))\nvar_e = 1\nvar_f = list_c[var_e-1]\nprint(int(var_f))"
    },
    "7147": {
        "category": "Comparison",
        "question_ko": "남준이는 은지보다 구슬을 더 적게 가지고 있습니다. 남준이는 태형이보다 구슬을 더 적게 가지고 있습니다. 은지는 태형이보다 구슬을 더 적게 가지고 있습니다. 구슬을 가장 많이 가지고 있는 사람은 누구입니까?",
        "question_en": "Namjoon has fewer marbles than Eunji. Namjoon has fewer marbles than Taehyung. Eunji has fewer marbles than Taehyung. Who has the most marbles?",
        "answer_ko": "태형",
        "answer_en": "Taehyung",
        "solution_abst_ko": "[OP_LIST_SOL] 남준 은지 태형 [OP_LIST_EOL] [OP_LIST_SOL] 남준 은지 < 남준 태형 < 은지 태형 < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Namjoon Eunji Taehyung [OP_LIST_EOL] [OP_LIST_SOL] Namjoon Eunji < Namjoon Taehyung < Eunji Taehyung < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '남준'\nvar_b = '은지'\nvar_c = '태형'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '남준'\nvar_e = '은지'\nvar_f = '<'\nvar_g = '남준'\nvar_h = '태형'\nvar_i = '<'\nvar_j = '은지'\nvar_k = '태형'\nvar_l = '<'\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_m = 1\nvar_n = list_c[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'Namjoon'\nvar_b = 'Eunji'\nvar_c = 'Taehyung'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'Namjoon'\nvar_e = 'Eunji'\nvar_f = '<'\nvar_g = 'Namjoon'\nvar_h = 'Taehyung'\nvar_i = '<'\nvar_j = 'Eunji'\nvar_k = 'Taehyung'\nvar_l = '<'\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_m = 1\nvar_n = list_c[var_m-1]\nprint(var_n)"
    },
    "7148": {
        "category": "Geometry",
        "question_ko": "수도꼭지를 열면 초 당 36밀리리터(㎖)의 물이 나온다고 합니다. 수조의 부피가 252세제곱센티미터(㎤)이면 이 수조를 다 체우는데 몇 초가 걸리는지 구하시오.",
        "question_en": "When you open a faucet, it is said that 36 milliliters (ml) of water comes out per second. If the volume of the tank is 252 cubic centimeters (cm3), how many seconds will it take to fill the tank?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "252 36 1 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "252 36 1 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 252\nvar_b = 36\nvar_c = 1\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 252\nvar_b = 36\nvar_c = 1\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "7149": {
        "category": "Arithmetic calculation",
        "question_ko": "1년 전 어머니의 나이는 35살이었고 호석이의 나이는 5살이었습니다. 현재로부터 4년 후 어머니의 나이는 호석이 나이의 몇 배가 되는지 구하시오.",
        "question_en": "A year ago, Hoseok's mother was 35 years old and Hoseok was 5 years old. Find how many times his mother's age is Hoseok's age 4 years from now.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "35 1 [OP_ADD] 4 [OP_ADD] 5 1 [OP_ADD] 4 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "35 1 [OP_ADD] 4 [OP_ADD] 5 1 [OP_ADD] 4 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 35\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = 4\nvar_j = var_h + var_i\nvar_k = var_e / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 35\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 5\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = 4\nvar_j = var_h + var_i\nvar_k = var_e / var_j\nprint(int(var_k))"
    },
    "7150": {
        "category": "Comparison",
        "question_ko": "지민이는 끈을 59센티미터(㎝) 가지고 있습니다. 유정이는 끈을 53센티미터(㎝) 가지고 있습니다. 더 짧은 끈을 가지고 있는 사람은 누구입니까?",
        "question_en": "Jimin has a 59 centimeters (cm) string. Yoojeong has a 53 centimeters (cm) string. Who has the shorter string?",
        "answer_ko": "유정",
        "answer_en": "Yoojeong",
        "solution_abst_ko": "[OP_LIST_SOL] 지민 유정 [OP_LIST_EOL] [OP_LIST_SOL] 59 53 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jimin Yoojeong [OP_LIST_EOL] [OP_LIST_SOL] 59 53 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '지민'\nvar_b = '유정'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 59\nvar_d = 53\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Jimin'\nvar_b = 'Yoojeong'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 59\nvar_d = 53\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "7151": {
        "category": "Arithmetic calculation",
        "question_ko": "마트에 오이가 15개 있습니다. 무의 수는 오이 수의 3배이고, 당근은 9개 있습니다. 무의 수는 당근 수의 몇 배입니까?",
        "question_en": "There are 15 cucumbers in the mart. The number of radishes is 3 times the number of cucumbers, and there are 9 carrots. How many times the number of radishes is equal to the number of carrots?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "15 3 [OP_MUL] 9 [OP_DIV]",
        "solution_abst_en": "15 3 [OP_MUL] 9 [OP_DIV]",
        "solution_code_ko": "var_a = 15\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "7152": {
        "category": "Arithmetic calculation",
        "question_ko": "중국 돈 1 위안은 우리나라 돈으로 161.5 원입니다. 우리나라 돈 17만원을 중국 돈 1000 위안과 10 위안 짜리로 바꾸려고 합니다. 1000 위안짜리를 될 수 있는 대로 많이 바꾼다면 10 위안짜리는 몇 장으로 바꿀 수 있습니까?",
        "question_en": "1 Chinese Yuan is equal to 161.5 Won in Korean money. I'm trying to change 170,000 won in Korean money into 1000 yuan and 10 yuan in Chinese money. If you change as many 1000 yuan as possible, how many 10 yuan can you get?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "17 10000 [OP_MUL] 161.5 1000 [OP_MUL] [OP_MOD] 161.5 10 [OP_MUL] [OP_FDIV]",
        "solution_abst_en": "17 10000 [OP_MUL] 161.5 1000 [OP_MUL] [OP_MOD] 161.5 10 [OP_MUL] [OP_FDIV]",
        "solution_code_ko": "var_a = 17\nvar_b = 10000\nvar_c = var_a * var_b\nvar_d = 161.5\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = var_c % var_f\nvar_h = 161.5\nvar_i = 10\nvar_j = var_h * var_i\nvar_k = var_g // var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 17\nvar_b = 10000\nvar_c = var_a * var_b\nvar_d = 161.5\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = var_c % var_f\nvar_h = 161.5\nvar_i = 10\nvar_j = var_h * var_i\nvar_k = var_g // var_j\nprint(int(var_k))"
    },
    "7153": {
        "category": "Arithmetic calculation",
        "question_ko": "30부터 50사이의 홀수 중에서 7로 나눈 나머지가 2인 수를 구하시오.",
        "question_en": "Find the odd number between 30 and 50 with a remainder of 2 when divided by 7.",
        "answer_ko": "37",
        "answer_en": "37",
        "solution_abst_ko": "30 50 [OP_LIST_ODD] 7 2 [OP_LIST_DIVIDE_AND_REMAIN] [OP_LIST_SUM]",
        "solution_abst_en": "30 50 [OP_LIST_ODD] 7 2 [OP_LIST_DIVIDE_AND_REMAIN] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 30\nvar_b = 50\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 7\nvar_d = 2\nlist_b = [] \nvar_c = int(var_c)\nvar_d = int(var_d)\nif var_d < 0:\n    var_d = var_d + var_c\nfor i in list_a:\n    i = int(i)\n    if i%var_c == var_d:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 30\nvar_b = 50\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 7\nvar_d = 2\nlist_b = [] \nvar_c = int(var_c)\nvar_d = int(var_d)\nif var_d < 0:\n    var_d = var_d + var_c\nfor i in list_a:\n    i = int(i)\n    if i%var_c == var_d:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint(int(var_e))"
    },
    "7154": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.3, 1/3 중 0.4보다 작은 수의 총합은?",
        "question_en": "What is the sum of the numbers less than 0.4 among 0.8, 1/2, 0.3, and 1/3?",
        "answer_ko": "0.63",
        "answer_en": "0.63",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.3 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_LESS] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.3 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_LESS] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.3\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.4\nlist_b = []\nfor i in list_a:\n    if i < var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint('{:.2f}'.format(round(var_f+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.3\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.4\nlist_b = []\nfor i in list_a:\n    if i < var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint('{:.2f}'.format(round(var_f+1e-10,2)))"
    },
    "7155": {
        "category": "Arithmetic calculation",
        "question_ko": "세 자리 수 중 5, 8, 2의 공배수 중 가장 작은 수는 무엇입니까?",
        "question_en": "Which three-digit number is the smallest common multiple of 5, 8, and 2?",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "100 999 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 2 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "100 999 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 2 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 8\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 2\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_h = list_e[var_g-1]\nprint(int(var_h))",
        "solution_code_en": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 8\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 2\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_h = list_e[var_g-1]\nprint(int(var_h))"
    },
    "7156": {
        "category": "Arithmetic calculation",
        "question_ko": "지하철은 1분에 1.6킬로미터(㎞)씩 이동합니다. 길이가 4.85킬로미터(㎞)인 다리를 완전히 건너는 데 3분 15초가 걸렸다면, 지하철의 길이는 몇 미터(m)입니까?",
        "question_en": "The subway travels at 1.6 kilometers (km) per minute. If it took 3 minutes and 15 seconds to completely cross a bridge that is 4.85 kilometers (km) long, how long is the subway in meters (m)?",
        "answer_ko": "350",
        "answer_en": "350",
        "solution_abst_ko": "1.6 3 15 60 [OP_DIV] [OP_ADD] [OP_MUL] 4.85 [OP_SUB] 1000 [OP_MUL]",
        "solution_abst_en": "1.6 3 15 60 [OP_DIV] [OP_ADD] [OP_MUL] 4.85 [OP_SUB] 1000 [OP_MUL]",
        "solution_code_ko": "var_a = 1.6\nvar_b = 3\nvar_c = 15\nvar_d = 60\nvar_e = var_c / var_d\nvar_f = var_b + var_e\nvar_g = var_a * var_f\nvar_h = 4.85\nvar_i = var_g - var_h\nvar_j = 1000\nvar_k = var_i * var_j\nprint(int(eval('{:.2f}'.format(round(var_k+1e-10,2)))))",
        "solution_code_en": "var_a = 1.6\nvar_b = 3\nvar_c = 15\nvar_d = 60\nvar_e = var_c / var_d\nvar_f = var_b + var_e\nvar_g = var_a * var_f\nvar_h = 4.85\nvar_i = var_g - var_h\nvar_j = 1000\nvar_k = var_i * var_j\nprint(int(eval('{:.2f}'.format(round(var_k+1e-10,2)))))"
    },
    "7157": {
        "category": "Arithmetic calculation",
        "question_ko": "둘레가 2미터(m)인 정삼각형의 한 변의 길이는 몇 미터(m)인지 소수로 나타내시오.",
        "question_en": "How many meters (m) is the length of a side of an equilateral triangle with a perimeter of 2 meters (m) in decimal numbers?",
        "answer_ko": "0.67",
        "answer_en": "0.67",
        "solution_abst_ko": "2 3 [OP_DIV]",
        "solution_abst_en": "2 3 [OP_DIV]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "7158": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 62를 빼고 45를 더했더니 55가 되었습니다. 어떤 수에 7을 곱한 값을 구하시오.",
        "question_en": "Subtract 62 from any number and add 45 to get 55. Find the value of a number multiplied by 7.",
        "answer_ko": "504",
        "answer_en": "504",
        "solution_abst_ko": "55 45 [OP_SUB] 62 [OP_ADD] 7 [OP_MUL]",
        "solution_abst_en": "55 45 [OP_SUB] 62 [OP_ADD] 7 [OP_MUL]",
        "solution_code_ko": "var_a = 55\nvar_b = 45\nvar_c = var_a - var_b\nvar_d = 62\nvar_e = var_c + var_d\nvar_f = 7\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 55\nvar_b = 45\nvar_c = var_a - var_b\nvar_d = 62\nvar_e = var_c + var_d\nvar_f = 7\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "7159": {
        "category": "Possibility",
        "question_ko": "5, 6, 7 중에서 한 번씩만 사용하여 만들 수 있는 세 자리 수중에서 가장 큰 수와 가장 작은 수의 합을 구하시오.",
        "question_en": "Find the sum of the largest and smallest three-digit number that can be formed by using 5, 6, and 7 only once.",
        "answer_ko": "1332",
        "answer_en": "1332",
        "solution_abst_ko": "[OP_LIST_SOL] 5 6 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 5 6 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 6\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 5\nvar_b = 6\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))"
    },
    "7160": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이는 빨간 공 3개, 윤기는 파란 공 2개를 가지고 있습니다. 윤기가 파란 공 1개를 정국이에게 주었을 때, 정국이가 가지고 있는 공의 개수는?",
        "question_en": "Jungkook has 3 red balls and Yoongi has 2 blue balls. When Yoongi gave 1 blue ball to Jungkook, how many balls does Jungkook have now?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "3 1 [OP_ADD]",
        "solution_abst_en": "3 1 [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "7161": {
        "category": "Arithmetic calculation",
        "question_ko": "256을 13으로 나누었을 때의 나머지를 구하시오.",
        "question_en": "Find the remainder when 256 is divided by 13.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "256 13 [OP_MOD]",
        "solution_abst_en": "256 13 [OP_MOD]",
        "solution_code_ko": "var_a = 256\nvar_b = 13\nvar_c = var_a % var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 256\nvar_b = 13\nvar_c = var_a % var_b\nprint(int(var_c))"
    },
    "7162": {
        "category": "Geometry",
        "question_ko": "가로가 25센티미터(㎝), 세로가 20센티미터(㎝)인 직사각형 모양의 도화지가 있습니다. 이 도화지의 넓이는 얼마입니까?",
        "question_en": "There is a rectangular drawing paper measuring 25 centimeters (cm) wide and 20 centimeters (cm) long. What is the area of this sheet of paper?",
        "answer_ko": "500",
        "answer_en": "500",
        "solution_abst_ko": "25 20 [OP_MUL]",
        "solution_abst_en": "25 20 [OP_MUL]",
        "solution_code_ko": "var_a = 25\nvar_b = 20\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 25\nvar_b = 20\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "7163": {
        "category": "Arithmetic calculation",
        "question_ko": "형은 나보다 1/10미터(m) 더 크고, 동생은 나보다 0.2미터(m) 작은 1.1미터(m)입니다. 형의 키는 몇 미터(m)입니까?",
        "question_en": "Your older brother is 1/10 meter (m) taller than you, and your younger brother is 1.1 meter (m) shorter than you by 0.2 meter (m). How tall is your brother in meters (m)?",
        "answer_ko": "1.40",
        "answer_en": "1.4",
        "solution_abst_ko": "0.2 1.1 [OP_ADD] 1/10 [OP_ADD]",
        "solution_abst_en": "0.2 1.1 [OP_ADD] 1/10 [OP_ADD]",
        "solution_code_ko": "var_a = 0.2\nvar_b = 1.1\nvar_c = var_a + var_b\nvar_d = 0.1\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.2\nvar_b = 1.1\nvar_c = var_a + var_b\nvar_d = 0.1\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "7164": {
        "category": "Arithmetic calculation",
        "question_ko": "(가) 반 학생들 중에서 미술을 좋아하는 학생은 35명이고, 음악을 좋아하는 학생은 32명이고, 미술과 음악을 모두 좋아하는 학생은 19명입니다. 미술과 음악을 모두 좋아하지 않는 학생이 한 명도 없을 때, (가) 반 학생은 모두 몇 명입니까?",
        "question_en": "Among the students in the (a) class, 35 students like art, 32 students like music, and 19 students like both art and music. If there is no student who does not like both art and music, how many students are in the (a) class?",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "35 32 [OP_ADD] 19 [OP_SUB]",
        "solution_abst_en": "35 32 [OP_ADD] 19 [OP_SUB]",
        "solution_code_ko": "var_a = 35\nvar_b = 32\nvar_c = var_a + var_b\nvar_d = 19\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 35\nvar_b = 32\nvar_c = var_a + var_b\nvar_d = 19\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "7165": {
        "category": "Comparison",
        "question_ko": "키가 작은 사람부터 순서대로 9명이 한 줄로 서 있습니다. 호석이는 뒤에서부터 2번째에 서 있고, 유나는 호석이 바로 뒤에 서 있습니다. 키가 큰 사람부터 순서대로 다시 줄을 서면 유나는 앞에서부터 몇 번째에 서게 됩니까?",
        "question_en": "Nine people are standing in a row in order from the short person. Hoseok is standing in the second place from the back, and Yuna is standing right behind Hoseok. If you line up again starting with the tall person, which place will Yuna stand from the front?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "2 1 [OP_SUB]",
        "solution_abst_en": "2 1 [OP_SUB]",
        "solution_code_ko": "var_a = 2\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "7166": {
        "category": "Possibility",
        "question_ko": "1, 2, 6, 7, 8 중 서로 다른 3개의 숫자를 뽑아 만들 수 있는 세 자리 수 중 가장 큰 수에서 가장 작은 수를 뺀 값은 얼마입니까?",
        "question_en": "What is the value when you subtract the smallest three-digit number from the largest three-digit number that can be made by drawing three different numbers from 1, 2, 6, 7, or 8?",
        "answer_ko": "750",
        "answer_en": "750",
        "solution_abst_ko": "[OP_LIST_SOL] 1 2 6 7 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 1 2 6 7 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 1\nvar_b = 2\nvar_c = 6\nvar_d = 7\nvar_e = 8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 1\nvar_b = 2\nvar_c = 6\nvar_d = 7\nvar_e = 8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h - var_j\nprint(int(var_k))"
    },
    "7167": {
        "category": "Geometry",
        "question_ko": "위에서 내려다 봤을 때 가로가 54센티미터(㎝), 세로가 20센티미터(㎝)인 직사각형 모양의 두부를 3조각으로 나누려고 합니다. 3조각 모두 위에서 내려다 봤을 때 같은 크기의 정사각형이 되도록 자르려고 합니다. 이때 가장 큰 정사각형을 만들려면 한 변의 길이를 몇 센티미터(㎝)로 해야 하는지 구하시오. (단, 두부는 위에서 아래로만 자릅니다.)",
        "question_en": "You are planning to divide the tofu into three pieces, each in a rectangular shape, measuring 54 centimeters (cm) long and 20 centimeters (cm) wide when viewed from above. You want to cut all 3 pieces to have the same size of a square when viewed from above. Find the length in centimeters (cm) of one side to make the largest square. (However, tofu is only cut from top to bottom.)",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "[OP_LIST_SOL] 54 3 [OP_FDIV] 20 3 [OP_FDIV] [OP_LIST_EOL] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 54 3 [OP_FDIV] 20 3 [OP_FDIV] [OP_LIST_EOL] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 54\nvar_b = 3\nvar_c = var_a // var_b\nvar_d = 20\nvar_e = 3\nvar_f = var_d // var_e\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nlist_a.reverse()\nvar_g = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_h = list_b[-var_g]\nprint(int(var_h))",
        "solution_code_en": "var_a = 54\nvar_b = 3\nvar_c = var_a // var_b\nvar_d = 20\nvar_e = 3\nvar_f = var_d // var_e\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nlist_a.reverse()\nvar_g = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_h = list_b[-var_g]\nprint(int(var_h))"
    },
    "7168": {
        "category": "Arithmetic calculation",
        "question_ko": "우유의 절반을 쓴 후의 무게가 5킬로그램(㎏)이고 처음 우유 한 통의 무게는 8킬로그램(㎏)이었다. 빈 우유 통의 무게는 몇 킬로그램(㎏)인가?",
        "question_en": "The weight after using half of the milk was 5 kilograms (kg) and the weight of the first carton was 8 kilograms (kg). How many kilograms (kg) does an empty milk carton weigh?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "8 8 5 [OP_SUB] 1 [OP_MUL] 1/2 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "8 8 5 [OP_SUB] 1 [OP_MUL] 1/2 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 8\nvar_b = 8\nvar_c = 5\nvar_d = var_b - var_c\nvar_e = 1\nvar_f = var_d * var_e\nvar_g = 0.5\nvar_h = var_f / var_g\nvar_i = var_a - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 8\nvar_b = 8\nvar_c = 5\nvar_d = var_b - var_c\nvar_e = 1\nvar_f = var_d * var_e\nvar_g = 0.5\nvar_h = var_f / var_g\nvar_i = var_a - var_h\nprint(int(var_i))"
    },
    "7169": {
        "category": "Correspondence",
        "question_ko": "A를 5로 나누면 몫이 2가 되고, 나머지는 B가 됩니다. A와 B는 모두 자연수입니다. 가능한 A 중 가장 큰 값은?",
        "question_en": "When A is divided by 5, the quotient is 2 and the remainder is B. A and B are both natural numbers. What is the largest possible value of A?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "5 2 [OP_MUL] 5 1 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "5 2 [OP_MUL] 5 1 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "7170": {
        "category": "Comparison",
        "question_ko": "달리기 시합에서 남준, 윤기, 호석이가 차례대로 결승선을 넘었습니다. 남준이는 10등을 했을때, 호석이의 등수는 몇 등입니까?",
        "question_en": "In a running race, Namjoon, Yoonki, and Hoseok crossed the finish line one after the other. If Namjoon is in 10th place, in which place is Hoseok?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "10 [OP_LIST_SOL] 남준 윤기 호석 [OP_LIST_EOL] 호석 [OP_LIST_INDEX] 남준 [OP_LIST_INDEX] [OP_SUB] [OP_ADD]",
        "solution_abst_en": "10 [OP_LIST_SOL] Namjoon Yoongi Hoseok [OP_LIST_EOL] Hoseok [OP_LIST_INDEX] Namjoon [OP_LIST_INDEX] [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = '남준'\nvar_c = '윤기'\nvar_d = '호석'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nlist_a.reverse()\nvar_e = '호석'\nvar_f = list_a.index(var_e)+1\nvar_g = '남준'\nvar_h = list_a.index(var_g)+1\nvar_i = var_f - var_h\nvar_j = var_a + var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 10\nvar_b = 'Namjoon'\nvar_c = 'Yoongi'\nvar_d = 'Hoseok'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nlist_a.reverse()\nvar_e = 'Hoseok'\nvar_f = list_a.index(var_e)+1\nvar_g = 'Namjoon'\nvar_h = list_a.index(var_g)+1\nvar_i = var_f - var_h\nvar_j = var_a + var_i\nprint(int(var_j))"
    },
    "7171": {
        "category": "Correspondence",
        "question_ko": "어떤 수가 있다. 이 수의 2/9가 10이라고 할 때, 이 수의 2/5는 얼마인지 구하시오.",
        "question_en": "There is a certain number. If 2/9 of this number is 10, what is 2/5 of this number?",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "10 2/9 [OP_DIV] 2/5 [OP_MUL]",
        "solution_abst_en": "10 2/9 [OP_DIV] 2/5 [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 0.2222222222222222\nvar_c = var_a / var_b\nvar_d = 0.4\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 0.2222222222222222\nvar_c = var_a / var_b\nvar_d = 0.4\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "7172": {
        "category": "Correspondence",
        "question_ko": "어부의 양동이 안에 9마리씩 물고기가 들어있는데 그 중 3마리만 고등어라고 한다. 고등어가 모두 27마리가 있다면 양동이는 몇 개인지 구하시오.",
        "question_en": "There are 9 fish in each fisherman's bucket, but only 3 of them are mackerel. If there are 27 mackerels in total, how many buckets are there?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "27 3 [OP_MUL] 9 [OP_DIV]",
        "solution_abst_en": "27 3 [OP_MUL] 9 [OP_DIV]",
        "solution_code_ko": "var_a = 27\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 27\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "7173": {
        "category": "Geometry",
        "question_ko": "가로 10센티미터(㎝), 세로 8센티미터(㎝), 높이 5센티미터(㎝)인 직육면체의 모서리의 길이의 합은 몇 센티미터(㎝)입니까?",
        "question_en": "How many centimeters (cm) is the sum of the lengths of the edges of a cuboid measuring 10 centimeters (cm) wide, 8 centimeters (cm) long, and 5 centimeters (cm) high?",
        "answer_ko": "92",
        "answer_en": "92",
        "solution_abst_ko": "10 4 [OP_MUL] 8 4 [OP_MUL] [OP_ADD] 5 4 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "10 4 [OP_MUL] 8 4 [OP_MUL] [OP_ADD] 5 4 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = 4\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 5\nvar_i = 4\nvar_j = var_h * var_i\nvar_k = var_g + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 10\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = 4\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 5\nvar_i = 4\nvar_j = var_h * var_i\nvar_k = var_g + var_j\nprint(int(var_k))"
    },
    "7174": {
        "category": "Geometry",
        "question_ko": "가로가 12센티미터(㎝), 세로가 15센티미터(㎝)인 직사각형 모양의 사진을 겹치지 않게 벽면에 붙여 최대한 작은 정사각형 모양으로 꾸미려고 합니다. 사진은 몇 장이 필요합니까?",
        "question_en": "I'm trying to make a square shape as small as possible by sticking a rectangular photo of 12 centimeters (cm) in width and 15 centimeters (cm) in length without overlapping them on the wall. How many photos do you need?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "12 15 [OP_LCM] 2 [OP_POW] 12 15 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "12 15 [OP_LCM] 2 [OP_POW] 12 15 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 15\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 12\nvar_g = 15\nvar_h = var_f * var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 12\nvar_b = 15\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 12\nvar_g = 15\nvar_h = var_f * var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "7175": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 가장 큰 수와 2번째로 큰 수의 합은 얼마입니까?",
        "question_en": "There are five numbers 10, 11, 12, 13, and 14. What is the sum of the largest number and the second largest number?",
        "answer_ko": "27",
        "answer_en": "27",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[-var_h]\nvar_j = var_g + var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[-var_h]\nvar_j = var_g + var_i\nprint(int(var_j))"
    },
    "7176": {
        "category": "Possibility",
        "question_ko": "1, 3, 4, 7을 한 번씩 사용하여 십의 자리 수가 1인 가장 큰 세 자리 수와 두 번째로 큰 세 자리 수를 만들 때, 둘의 합은 얼마인가?",
        "question_en": "If 1, 3, 4, and 7 are used once to form the largest three-digit number with 1 in the tens place and the second largest three-digit number, what is the sum of these two numbers?",
        "answer_ko": "1427",
        "answer_en": "1427",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 4 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 1 [OP_LIST_SEARCH_FIXED_DIGIT] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 4 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 1 [OP_LIST_SEARCH_FIXED_DIGIT] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 4\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 1\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nvar_j = 2\nlist_e=list_c.copy()\nlist_e.sort()\nvar_k = list_e[-var_j]\nvar_l = var_i + var_k\nprint(int(var_l))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 4\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 1\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nvar_j = 2\nlist_e=list_c.copy()\nlist_e.sort()\nvar_k = list_e[-var_j]\nvar_l = var_i + var_k\nprint(int(var_l))"
    },
    "7177": {
        "category": "Correspondence",
        "question_ko": "A는 34.8A>34.84를 만족하는 숫자입니다. 한 자리 자연수 중 A에 들어갈 수 있는 숫자들의 합은 얼마입니까?",
        "question_en": "A is a number satisfying 34.8A>34.84. What is the sum of all single-digit numbers that can fit in A?",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "34.8A>34.84 A [OP_DIGIT_UNK_SOLVER] [OP_LIST_SUM]",
        "solution_abst_en": "34.8A>34.84 A [OP_DIGIT_UNK_SOLVER] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = '34.8A>34.84'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nprint(int(var_c))",
        "solution_code_en": "var_a = '34.8A>34.84'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)\nprint(int(var_c))"
    },
    "7178": {
        "category": "Correspondence",
        "question_ko": "18에 어떤 수를 더하여 3으로 나눈 뒤 10을 더하여 5로 나눈 수가 4입니다. 어떤 수를 구하시오.",
        "question_en": "If we add a certain number to 18, and then divide it by 3, and then add 10, and then divide by 5, we get 4 as a result. Find out the number in question.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "4 5 [OP_MUL] 10 [OP_SUB] 3 [OP_MUL] 18 [OP_SUB]",
        "solution_abst_en": "4 5 [OP_MUL] 10 [OP_SUB] 3 [OP_MUL] 18 [OP_SUB]",
        "solution_code_ko": "var_a = 4\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 10\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = var_e * var_f\nvar_h = 18\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 4\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 10\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = var_e * var_f\nvar_h = 18\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "7179": {
        "category": "Correspondence",
        "question_ko": "등식 69A+53=748이 성립한다고 합니다. A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "The equation 69A+53=748 is said to hold. What number should go in A, where 69A is three-digit number?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "69A+53=748 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "69A+53=748 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '69A+53=748'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '69A+53=748'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "7180": {
        "category": "Possibility",
        "question_ko": "세 자연수 1, 2, 7 중 두 개만을 뽑아 만들 수 있는 두 자리 자연수의 개수는 몇 개입니까?",
        "question_en": "How many two-digit numbers can be formed by selecting only two of the three natural numbers 1, 2, and 7? (The number can be used repeatedly)",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "[OP_LIST_SOL] 1 2 7 [OP_LIST_EOL] 2 [OP_LIST_GET_PRODUCT] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 2 7 [OP_LIST_EOL] 2 [OP_LIST_GET_PRODUCT] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 2\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 2\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "7181": {
        "category": "Arithmetic calculation",
        "question_ko": "부부 대륙에는 4개의 부족이 있다. 가가 부족에는 남자가 204명, 여자가 468명이 있고 나나 부족에는 남자가 334명, 여자가 516명이 있다. 다다 부족에는 남자가 427명, 여자가 458명이 라라 부족에는 남자가 549명, 여자가 239명이 있다. 부부 대륙의 남자와 여자수의 차를 구하시오.",
        "question_en": "There are 4 tribes on the couple continent. There are 204 males and 468 females in Gaga tribe, and 334 males and 516 females in Nana tribe. There are 427 males and 458 females in Dada tribe, and 549 males and 239 females in Lala tribe. Find the difference between males and females on this couple continent.",
        "answer_ko": "167",
        "answer_en": "167",
        "solution_abst_ko": "[OP_LIST_SOL] 204 334 427 549 [OP_LIST_EOL] [OP_LIST_SUM] [OP_LIST_SOL] 468 516 458 239 [OP_LIST_EOL] [OP_LIST_SUM] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "[OP_LIST_SOL] 204 334 427 549 [OP_LIST_EOL] [OP_LIST_SUM] [OP_LIST_SOL] 468 516 458 239 [OP_LIST_EOL] [OP_LIST_SUM] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 204\nvar_b = 334\nvar_c = 427\nvar_d = 549\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_e = sum(list_a)\nvar_f = 468\nvar_g = 516\nvar_h = 458\nvar_i = 239\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nlist_b = [float(i) for i in list_b]\nvar_j = sum(list_b)\nvar_k = var_e - var_j\nvar_l = abs(var_k)\nprint(int(var_l))",
        "solution_code_en": "var_a = 204\nvar_b = 334\nvar_c = 427\nvar_d = 549\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_e = sum(list_a)\nvar_f = 468\nvar_g = 516\nvar_h = 458\nvar_i = 239\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nlist_b = [float(i) for i in list_b]\nvar_j = sum(list_b)\nvar_k = var_e - var_j\nvar_l = abs(var_k)\nprint(int(var_l))"
    },
    "7182": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 기계는 시간당 휴대폰을 2대 만든다. 공장에 기계가 모두 7개 있다면, 공장에서 182대의 휴대폰을 만드는데 몇 시간이 걸리는가?",
        "question_en": "Some machines make 2 cell phones per hour. If the factory has 7 machines in all, how many hours does it take to make 182 cell phones in the factory?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "182 7 2 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "182 7 2 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 182\nvar_b = 7\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 182\nvar_b = 7\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "7183": {
        "category": "Possibility",
        "question_ko": "0, 2, 4, 6 중 3개를 빼서 한 번만 사용하여 세 자리 수를 만들려고 합니다. 만들 수 있는 가장 큰 수와 가장 작은 수의 차이를 구하십시오.",
        "question_en": "You want to subtract three of the 4 numbers 0, 2, 4, and 6, and then create a three-digit number using each number only once. Find the difference between the largest and smallest possible numbers.",
        "answer_ko": "438",
        "answer_en": "438",
        "solution_abst_ko": "[OP_LIST_SOL] 0 2 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 0 2 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 0\nvar_b = 2\nvar_c = 4\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 0\nvar_b = 2\nvar_c = 4\nvar_d = 6\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))"
    },
    "7184": {
        "category": "Correspondence",
        "question_ko": "1부터 N까지 연속된 자연수가 N개 있습니다. 이 수 중에서 짝수들의 합은 90이고 홀수들의 합은 100입니다. N을 구하시오.",
        "question_en": "There are N consecutive natural numbers from 1 to N. The sum of the even numbers in these numbers is 90 and the sum of the odd numbers is 100. find N.",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "100 90 [OP_SUB] 2 [OP_MUL] 1 [OP_SUB]",
        "solution_abst_en": "100 90 [OP_SUB] 2 [OP_MUL] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 100\nvar_b = 90\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 1\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 100\nvar_b = 90\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 1\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "7185": {
        "category": "Correspondence",
        "question_ko": "B+A+B=814.8입니다. A의 소수점을 왼쪽으로 한 칸 옮기면 B와 같습니다. 소수점을 포함하여 A-B의 값을 구하시오",
        "question_en": "B+A+B=814.8. When the decimal point of A is shifted one place to the left, it  turns equivalent to B. Find the value of A-B including the decimal point.",
        "answer_ko": "611.10",
        "answer_en": "611.1",
        "solution_abst_ko": "814.8 10 2 [OP_ADD] [OP_DIV] 10 [OP_MUL] 814.8 10 2 [OP_ADD] [OP_DIV] [OP_SUB]",
        "solution_abst_en": "814.8 10 2 [OP_ADD] [OP_DIV] 10 [OP_MUL] 814.8 10 2 [OP_ADD] [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 814.8\nvar_b = 10\nvar_c = 2\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nvar_f = 10\nvar_g = var_e * var_f\nvar_h = 814.8\nvar_i = 10\nvar_j = 2\nvar_k = var_i + var_j\nvar_l = var_h / var_k\nvar_m = var_g - var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))",
        "solution_code_en": "var_a = 814.8\nvar_b = 10\nvar_c = 2\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nvar_f = 10\nvar_g = var_e * var_f\nvar_h = 814.8\nvar_i = 10\nvar_j = 2\nvar_k = var_i + var_j\nvar_l = var_h / var_k\nvar_m = var_g - var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))"
    },
    "7186": {
        "category": "Geometry",
        "question_ko": "어떤 사다리꼴의 높이가 8센티미터(㎝)이고, 윗변의 길이가 아랫변의 길이보다 6 센티미터(㎝) 짧으며, 넓이가 72제곱센티미터(㎠)라고 합니다. 이 사다리꼴의 윗변의 길이는?",
        "question_en": "A trapezoid is 8 centimeters (cm) high, the length of the top side is 6 centimeters (cm) shorter than the length of the bottom side, and it is 72 square centimeters (㎠) wide. What is the length of the top side of this trapezoid?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "72 2 [OP_MUL] 8 [OP_DIV] 6 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "72 2 [OP_MUL] 8 [OP_DIV] 6 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 72\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c / var_d\nvar_f = 6\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 72\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c / var_d\nvar_f = 6\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "7187": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 46을 뺐더니 결과가 15가 되었습니다. 어떤 수에서 29를 빼면?",
        "question_en": "This number minus 46 became 15. What is this number minus 29?",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "15 46 [OP_ADD] 29 [OP_SUB]",
        "solution_abst_en": "15 46 [OP_ADD] 29 [OP_SUB]",
        "solution_code_ko": "var_a = 15\nvar_b = 46\nvar_c = var_a + var_b\nvar_d = 29\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 46\nvar_c = var_a + var_b\nvar_d = 29\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "7188": {
        "category": "Correspondence",
        "question_ko": "1학년 학생수는 695명이고 그 중 여학생은 329명이다. 2학년 남학생의 수는 254명일 때, 1, 2학년 남학생 수를 구하시오.",
        "question_en": "The number of first-year students is 695, of which 329 are female students. If the number of male second-year students is 254, find the number of male students in the first-year and second-year.",
        "answer_ko": "620",
        "answer_en": "620",
        "solution_abst_ko": "695 329 [OP_SUB] 254 [OP_ADD]",
        "solution_abst_en": "695 329 [OP_SUB] 254 [OP_ADD]",
        "solution_code_ko": "var_a = 695\nvar_b = 329\nvar_c = var_a - var_b\nvar_d = 254\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 695\nvar_b = 329\nvar_c = var_a - var_b\nvar_d = 254\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7189": {
        "category": "Geometry",
        "question_ko": "팔각뿔의 면, 모서리, 꼭짓점의 수의 합을 구하시오.",
        "question_en": "Find the sum of the faces, edges, and vertices of an octagonal pyramid.",
        "answer_ko": "34",
        "answer_en": "34",
        "solution_abst_ko": "8 1 [OP_ADD] 8 2 [OP_MUL] [OP_ADD] 8 1 [OP_ADD] [OP_ADD]",
        "solution_abst_en": "8 1 [OP_ADD] 8 2 [OP_MUL] [OP_ADD] 8 1 [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 8\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 8\nvar_i = 1\nvar_j = var_h + var_i\nvar_k = var_g + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 8\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 8\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 8\nvar_i = 1\nvar_j = var_h + var_i\nvar_k = var_g + var_j\nprint(int(var_k))"
    },
    "7190": {
        "category": "Correspondence",
        "question_ko": "어떤 수의 7/8은 28입니다. 어떤 수보다 16 큰 수의 5/16는 얼마입니까?",
        "question_en": "7/8 of a number is 28. What is that number added by 16 and multiplied by 5/16?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "28 8 7 [OP_DIV] [OP_MUL] 16 [OP_ADD] 5 16 [OP_DIV] [OP_MUL]",
        "solution_abst_en": "28 8 7 [OP_DIV] [OP_MUL] 16 [OP_ADD] 5 16 [OP_DIV] [OP_MUL]",
        "solution_code_ko": "var_a = 28\nvar_b = 8\nvar_c = 7\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 16\nvar_g = var_e + var_f\nvar_h = 5\nvar_i = 16\nvar_j = var_h / var_i\nvar_k = var_g * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 28\nvar_b = 8\nvar_c = 7\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 16\nvar_g = var_e + var_f\nvar_h = 5\nvar_i = 16\nvar_j = var_h / var_i\nvar_k = var_g * var_j\nprint(int(var_k))"
    },
    "7191": {
        "category": "Possibility",
        "question_ko": "1, 2, 3, 4, 5의 숫자를 한번씩 사용하여 3자리 자연수을 만든다. 가능한 모든 수들의 자리수의 총합을 구하여라.",
        "question_en": "Use each of the numbers 1, 2, 3, 4, and 5 once to make three-digit natural numbers. Find the sum of the digits of all possible numbers.",
        "answer_ko": "540",
        "answer_en": "540",
        "solution_abst_ko": "1 5 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] [OP_LIST_SUM]",
        "solution_abst_en": "1 5 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 5\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nlist_c = [float(i) for i in list_c]\nvar_f = sum(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 5\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nlist_c = [float(i) for i in list_c]\nvar_f = sum(list_c)\nprint(int(var_f))"
    },
    "7192": {
        "category": "Comparison",
        "question_ko": "호석이는 달리기 시합에서 8등을 했습니다. 유정이는 호석이보다는 잘 했지만, 6등을 한 남준이보다는 못했습니다. 유정이는 몇 등일까요?",
        "question_en": "Hoseok placed 8th in the running event. Yoojung did better than Hoseok, but worse than Namjoon who came in 6th place. What rank is Yoojung in?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "8 6 [OP_ADD] 2 [OP_DIV]",
        "solution_abst_en": "8 6 [OP_ADD] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 8\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "7193": {
        "category": "Arithmetic calculation",
        "question_ko": "연속하는 5개의 자연수의 합이 90입니다. 이 자연수 중 가장 두 번째로 큰 수는 무엇입니까?",
        "question_en": "The sum of five consecutive natural numbers is 90. What is the second largest of these natural numbers?",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "90 0 5 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 5 [OP_DIV] 5 2 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "90 0 5 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 5 [OP_DIV] 5 2 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 90\nvar_b = 0\nvar_c = 5\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nlist_a = [i for i in range(var_b, var_e + 1, var_f)]\nlist_a = [float(i) for i in list_a]\nvar_g = sum(list_a)\nvar_h = var_a - var_g\nvar_i = 5\nvar_j = var_h / var_i\nvar_k = 5\nvar_l = 2\nvar_m = var_k - var_l\nvar_n = var_j + var_m\nprint(int(var_n))",
        "solution_code_en": "var_a = 90\nvar_b = 0\nvar_c = 5\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nlist_a = [i for i in range(var_b, var_e + 1, var_f)]\nlist_a = [float(i) for i in list_a]\nvar_g = sum(list_a)\nvar_h = var_a - var_g\nvar_i = 5\nvar_j = var_h / var_i\nvar_k = 5\nvar_l = 2\nvar_m = var_k - var_l\nvar_n = var_j + var_m\nprint(int(var_n))"
    },
    "7194": {
        "category": "Possibility",
        "question_ko": "1에서 999까지의 숫자 중 짝수를 차례로 이어 써서 2468101214...996998를 만들었다. 이 수의 각 자리 숫자들의 총합을 구하여라.",
        "question_en": "Even numbers from 1 to 999 were written sequentially to make 2468101214...996998. Find the sum of each digit in this number.",
        "answer_ko": "6500",
        "answer_en": "6500",
        "solution_abst_ko": "2 999 2 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] [OP_LIST_SUM]",
        "solution_abst_en": "2 999 2 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 2\nvar_b = 999\nvar_c = 2\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_b=[]\nfor i in list_a:\n    var_d = 0\n    i = int(i)\n    while i//10 > 0:\n        var_d = var_d + i%10\n        i = i//10\n    var_d = var_d + i%10\n    list_b.append(var_d)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 999\nvar_c = 2\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_b=[]\nfor i in list_a:\n    var_d = 0\n    i = int(i)\n    while i//10 > 0:\n        var_d = var_d + i%10\n        i = i//10\n    var_d = var_d + i%10\n    list_b.append(var_d)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint(int(var_e))"
    },
    "7195": {
        "category": "Geometry",
        "question_ko": "도화지에 직각삼각형을 그렸습니다. 이 직각삼각형은 빗변이 아닌 한 변의 길이가 6, 나머지 빗변이 아닌 한 변의 길이가 8이었습니다. 이 때 빗변의 길이는 얼마입니까?",
        "question_en": "I drew a right triangle on a paper. In this right triangle, the length of the non-hypotenuse side is 6 and the other non-hypotenuse side length is 8. What is the length of the hypotenuse at this time?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "6 2 [OP_POW] 8 2 [OP_POW] [OP_ADD] 1/2 [OP_POW]",
        "solution_abst_en": "6 2 [OP_POW] 8 2 [OP_POW] [OP_ADD] 1/2 [OP_POW]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 8\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c + var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 8\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c + var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))"
    },
    "7196": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 6 미터(m)인 밧줄에 불을 붙이면 1분에 2 미터(m)만큼 불에 탄다. 탄 밧줄의 길이가 2 미터(m)일 때, 불을 붙인지 몇 분 후인지 구하시오.",
        "question_en": "If you light a rope that is 6 meters (m) long, it burns at 2 meters (m) per minute. When the length of the burnt rope is 2 meters (m), find how many minutes have passed after the rope is lighted.",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "2 2 [OP_DIV]",
        "solution_abst_en": "2 2 [OP_DIV]",
        "solution_code_ko": "var_a = 2\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "7197": {
        "category": "Arithmetic calculation",
        "question_ko": "빨간 볼펜과 파란 볼펜이 합하여 모두 240개가 들어있는 상자가 있습니다. 파란 볼펜은 빨간 볼펜보다 2개 적게 들어있습니다. 빨간 볼펜은 모두 몇 개 들어있을지 구하세요.",
        "question_en": "A box contains a total of 240 red and blue ballpoint pens in total. There are 2 fewer blue ballpoint pens than red ballpoint pens. Find how many red ballpoint pens are in all.",
        "answer_ko": "121",
        "answer_en": "121",
        "solution_abst_ko": "240 2 [OP_SUB] 2 [OP_DIV] 2 [OP_ADD]",
        "solution_abst_en": "240 2 [OP_SUB] 2 [OP_DIV] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 240\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 240\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "7198": {
        "category": "Possibility",
        "question_ko": "공을 4번 던져 점수를 합산하는 놀이를 합니다. 빨간색 원, 초록색 원, 원을 맞히지 못한 경우 각각 3점, 2점, 1점을 얻을 때 얻을 수 있는 서로 다른 점수는 모두 몇 가지인지 구하시오.",
        "question_en": "Suppose that you throw the ball 4 times and count the points. How many different points can you get given that you get 3 points and 2 points when hitting the red circle and green circle, and 1 point if you miss the target?",
        "answer_ko": "81",
        "answer_en": "81",
        "solution_abst_ko": "[OP_LIST_SOL] 3 2 1 [OP_LIST_EOL] 4 [OP_LIST_GET_PRODUCT] [OP_LIST_NUM2SUM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 3 2 1 [OP_LIST_EOL] 4 [OP_LIST_GET_PRODUCT] [OP_LIST_NUM2SUM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = 1\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = 1\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "7199": {
        "category": "Arithmetic calculation",
        "question_ko": "32와 24의 공약수들의 총합을 구하시오.",
        "question_en": "Find the sum of the common divisors of 32 and 24.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "32 [OP_LIST_GET_DIVISOR] 24 [OP_LIST_GET_DIVISOR] [OP_SET_INTERSECT] [OP_LIST_SUM]",
        "solution_abst_en": "32 [OP_LIST_GET_DIVISOR] 24 [OP_LIST_GET_DIVISOR] [OP_SET_INTERSECT] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 32\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 24\nlist_b = []\nnum_sqrt = int(math.sqrt(var_b))\nfor i in range(1, num_sqrt+1):\n    if var_b % i == 0:\n        list_b.append(i)\n        list_b.append(int(var_b/i))\nlist_b = sorted(set(list_b))\nlist_c = list(set(list_a) & set(list_b))\nlist_c = [float(i) for i in list_c]\nvar_c = sum(list_c)\nprint(int(var_c))",
        "solution_code_en": "var_a = 32\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 24\nlist_b = []\nnum_sqrt = int(math.sqrt(var_b))\nfor i in range(1, num_sqrt+1):\n    if var_b % i == 0:\n        list_b.append(i)\n        list_b.append(int(var_b/i))\nlist_b = sorted(set(list_b))\nlist_c = list(set(list_a) & set(list_b))\nlist_c = [float(i) for i in list_c]\nvar_c = sum(list_c)\nprint(int(var_c))"
    },
    "7200": {
        "category": "Arithmetic calculation",
        "question_ko": "24와 36의 최대 공약수를 구하시오.",
        "question_en": "Find the greatest common divisor of 24 and 36.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "24 [OP_LIST_GET_DIVISOR] 36 [OP_LIST_GET_DIVISOR] [OP_SET_INTERSECT] 1 [OP_LIST_MAX]",
        "solution_abst_en": "24 [OP_LIST_GET_DIVISOR] 36 [OP_LIST_GET_DIVISOR] [OP_SET_INTERSECT] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 24\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 36\nlist_b = []\nnum_sqrt = int(math.sqrt(var_b))\nfor i in range(1, num_sqrt+1):\n    if var_b % i == 0:\n        list_b.append(i)\n        list_b.append(int(var_b/i))\nlist_b = sorted(set(list_b))\nlist_c = list(set(list_a) & set(list_b))\nvar_c = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_d = list_d[-var_c]\nprint(int(var_d))",
        "solution_code_en": "var_a = 24\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 36\nlist_b = []\nnum_sqrt = int(math.sqrt(var_b))\nfor i in range(1, num_sqrt+1):\n    if var_b % i == 0:\n        list_b.append(i)\n        list_b.append(int(var_b/i))\nlist_b = sorted(set(list_b))\nlist_c = list(set(list_a) & set(list_b))\nvar_c = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_d = list_d[-var_c]\nprint(int(var_d))"
    },
    "7201": {
        "category": "Possibility",
        "question_ko": "서로 다른 색의 5개의 공이 들어 있는 상자가 있습니다. 이 상자에서 3개의 공을 뽑는 경우는 모두 몇 가지입니까?",
        "question_en": "There is a box containing 5 balls of different colors. How many ways can 3 balls be drawn from this box?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "5 3 [OP_COMB]",
        "solution_abst_en": "5 3 [OP_COMB]",
        "solution_code_ko": "var_a = 5\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))"
    },
    "7202": {
        "category": "Arithmetic calculation",
        "question_ko": "15리터(L) 들이의 통에 석유가 7리터(L) 200밀리리터(㎖) 들어있습니다. 이 통에 석유를 가득 채우기 위해서는 600밀리리터(㎖) 용기로 최소한 몇 번 부어야 합니까?",
        "question_en": "There is a 15 liter (L) barrel with 7 liters (L) and 200 milliliters (㎖) of petroleum. At least how many times does a 600 milliliters (mL) of container must be poured into the barrel to completely fill this with oil?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "15 1000 [OP_MUL] 7 1000 [OP_MUL] 200 [OP_ADD] [OP_SUB] 600 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "15 1000 [OP_MUL] 7 1000 [OP_MUL] 200 [OP_ADD] [OP_SUB] 600 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 15\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = 200\nvar_h = var_f + var_g\nvar_i = var_c - var_h\nvar_j = 600\nvar_k = var_i / var_j\nvar_l = 1\nvar_m=int(((var_k+9*10**(var_l-2))//(10**(var_l-1)))*10**(var_l-1))\n\nprint(int(var_m))",
        "solution_code_en": "var_a = 15\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = 1000\nvar_f = var_d * var_e\nvar_g = 200\nvar_h = var_f + var_g\nvar_i = var_c - var_h\nvar_j = 600\nvar_k = var_i / var_j\nvar_l = 1\nvar_m=int(((var_k+9*10**(var_l-2))//(10**(var_l-1)))*10**(var_l-1))\n\nprint(int(var_m))"
    },
    "7203": {
        "category": "Correspondence",
        "question_ko": "유나는 8에 어떤 수를 곱하려고 합니다. 실수로 4에 어떤 수를 곱했을 때의 결과가 60이라면 바르게 계산한 결과를 구하세요.",
        "question_en": "Yuna wants to multiply 8 by some number. If the result of multiplying 4 by any number by mistake is 60, find the correct result.",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "8 60 4 [OP_DIV] [OP_MUL]",
        "solution_abst_en": "8 60 4 [OP_DIV] [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 60\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 60\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nprint(int(var_e))"
    },
    "7204": {
        "category": "Correspondence",
        "question_ko": "십의 자리 숫자가 2이고 일의 자리 숫자가 A인 두 자리 수 자연수가 있다. 각 자리의 숫자를 바꾸면 처음 수보다 9가 크다고 할 때, A를 구하시오.",
        "question_en": "There is a two-digit natural number whose tens digit is 2 and the units digit is A. If you exchange each digit, it is 9 greater than the initial number. Find A.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "2 10 [OP_MUL] 2 [OP_SUB] 9 [OP_ADD] 10 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "2 10 [OP_MUL] 2 [OP_SUB] 9 [OP_ADD] 10 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 2\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c - var_d\nvar_f = 9\nvar_g = var_e + var_f\nvar_h = 10\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_g / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 2\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c - var_d\nvar_f = 9\nvar_g = var_e + var_f\nvar_h = 10\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_g / var_j\nprint(int(var_k))"
    },
    "7205": {
        "category": "Geometry",
        "question_ko": "사각뿔대의 꼭지점의 개수를구하시오.",
        "question_en": "Find the number of vertices of the truncated square pyramid.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "4 2 [OP_MUL]",
        "solution_abst_en": "4 2 [OP_MUL]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "7206": {
        "category": "Correspondence",
        "question_ko": "서울에서 부산으로 가는 기차가 있습니다. 300명은 첫 번째 정류장에서 첫 번째 정류장의 5분의 2 이상 내렸고, 200명은 두 번째 정류장에서 남은 인원의 절반도 채 내지 못했다. 나머지 사람들이 부산에서 내렸고 부산에서 내린 총 인원이 800명이라면 처음에 몇 명이 탔을까?",
        "question_en": "There is a train from Seoul to Busan. 300 people got off more than two-fifths of the first stop at the first stop, and 200 people got off less than half of the remaining people at the second stop. If the rest of the people got off at Busan and the total number of people who got off at Busan was 800, how many people got on at first?",
        "answer_ko": "2500",
        "answer_en": "2500",
        "solution_abst_ko": "800 200 [OP_SUB] 1 1/2 [OP_SUB] [OP_DIV] 300 [OP_ADD] 1 2 5 [OP_DIV] [OP_SUB] [OP_DIV]",
        "solution_abst_en": "800 200 [OP_SUB] 1 1/2 [OP_SUB] [OP_DIV] 300 [OP_ADD] 1 2 5 [OP_DIV] [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 800\nvar_b = 200\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = 0.5\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 300\nvar_i = var_g + var_h\nvar_j = 1\nvar_k = 2\nvar_l = 5\nvar_m = var_k / var_l\nvar_n = var_j - var_m\nvar_o = var_i / var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 800\nvar_b = 200\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = 0.5\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 300\nvar_i = var_g + var_h\nvar_j = 1\nvar_k = 2\nvar_l = 5\nvar_m = var_k / var_l\nvar_n = var_j - var_m\nvar_o = var_i / var_n\nprint(int(var_o))"
    },
    "7207": {
        "category": "Comparison",
        "question_ko": "운동을 미혜는 1과 5/12시간 동안 하고 성재는 1과 3/12시간 동안 했습니다. 운동을 더 오랫동안 한 사람은 누구일까요?",
        "question_en": "Mihye worked out for 1 and 5/12 hours and Seongjae did it for 1 and 3/12 hours. Who has been exercising longer?",
        "answer_ko": "미혜",
        "answer_en": "Mihye",
        "solution_abst_ko": "[OP_LIST_SOL] 미혜 성재 [OP_LIST_EOL] [OP_LIST_SOL] 1 5/12 [OP_ADD] 1 3/12 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Mihye Seongjae [OP_LIST_EOL] [OP_LIST_SOL] 1 5/12 [OP_ADD] 1 3/12 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '미혜'\nvar_b = '성재'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1\nvar_d = 0.4166666666666667\nvar_e = var_c + var_d\nvar_f = 1\nvar_g = 0.25\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Mihye'\nvar_b = 'Seongjae'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1\nvar_d = 0.4166666666666667\nvar_e = var_c + var_d\nvar_f = 1\nvar_g = 0.25\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "7208": {
        "category": "Arithmetic calculation",
        "question_ko": "철사로 만든 사각형의 둘레가 242.7센티미터(㎝) 이다. 똑같은 사각형이 5개 있을 때, 이 사각형에 들어간 철사는 모두 몇 센티미터(㎝)입니까?",
        "question_en": "The perimeter of a rectangle made of wire is 242.7 cm (cm). Provided there are 5 identical rectangles, Find how many centimeters (cm) of the wire was used to make these squares.",
        "answer_ko": "1213.50",
        "answer_en": "1213.5",
        "solution_abst_ko": "242.7 5 [OP_MUL]",
        "solution_abst_en": "242.7 5 [OP_MUL]",
        "solution_code_ko": "var_a = 242.7\nvar_b = 5\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 242.7\nvar_b = 5\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "7209": {
        "category": "Correspondence",
        "question_ko": "영희는 수학 시험을 보다 0.42를 빼야 할 것을 잘못하여 더했더니 0.9를 답으로 제출했습니다. 원래 정답은 얼마입니까?",
        "question_en": "During a math test, Young-hee mistakenly added 0.42 which should have been subtracted, and submitted 0.9 as the answer. What is the original correct answer?",
        "answer_ko": "0.06",
        "answer_en": "0.06",
        "solution_abst_ko": "0.9 0.42 [OP_SUB] 0.42 [OP_SUB]",
        "solution_abst_en": "0.9 0.42 [OP_SUB] 0.42 [OP_SUB]",
        "solution_code_ko": "var_a = 0.9\nvar_b = 0.42\nvar_c = var_a - var_b\nvar_d = 0.42\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.9\nvar_b = 0.42\nvar_c = var_a - var_b\nvar_d = 0.42\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "7210": {
        "category": "Possibility",
        "question_ko": "가위바위보를 두 번 합니다. 이 때, 한명이 두 번 연속으로 지는 경우는 몇 가지 입니까?",
        "question_en": "Play rock-paper-scissors twice. In this case, how many times  can one person lose twice in a row?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "3 3 [OP_MUL]",
        "solution_abst_en": "3 3 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "7211": {
        "category": "Arithmetic calculation",
        "question_ko": "귤 29개를 8개의 상자에 같은 개수씩 나누어 담았더니 5개의 귤이 남았습니다. 상자의 개수는 몇 개입니까?",
        "question_en": "29 tangerines were divided into 8 boxes, each equal in number, and 5 tangerines remained. How many tangerines are there in one box?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "29 5 [OP_SUB] 8 [OP_DIV]",
        "solution_abst_en": "29 5 [OP_SUB] 8 [OP_DIV]",
        "solution_code_ko": "var_a = 29\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 29\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "7212": {
        "category": "Comparison",
        "question_ko": "손님들이 한 줄로 서서 차례대로 버스에 탑니다. 제일 먼저 타는 손님 뒤에 10명의 사람이 있다면 한 줄로 선 사람들은 모두 몇 명입니까?",
        "question_en": "Customers stand in a line and board the bus in turn. If there are 10 people behind the first passenger, how many people are in a line?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "10 1 [OP_ADD]",
        "solution_abst_en": "10 1 [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 10\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "7213": {
        "category": "Comparison",
        "question_ko": "두 볼링공이 있습니다. 빨간색 공은 1.49킬로그램(㎏), 파란색 공은 9/20킬로그램(㎏)입니다. 어느 색 공이 더 무거울까요?",
        "question_en": "There are two bowling balls. The red ball weighs 1.49 kilograms (kg) and the blue ball weighs 9/20 kilograms (kg). Which color ball is heavier?",
        "answer_ko": "빨간색",
        "answer_en": "red",
        "solution_abst_ko": "[OP_LIST_SOL] 빨간색 파란색 [OP_LIST_EOL] [OP_LIST_SOL] 1.49 9/20 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] red blue [OP_LIST_EOL] [OP_LIST_SOL] 1.49 9/20 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '빨간색'\nvar_b = '파란색'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.49\nvar_d = 0.45\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'red'\nvar_b = 'blue'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1.49\nvar_d = 0.45\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "7214": {
        "category": "Arithmetic calculation",
        "question_ko": "두 개의 저금통이 있다. 빨간 저금통에는 8000원이, 노란 저금통에는 5000이 들어 있고, 매일 각각 300원, 500원씩 넣는다. 두 저금통에 들어 있는 금액이 같아지는 날에 빨간 저금통에는 얼마가 들어 있는가?",
        "question_en": "There are two coin banks. There are 8,000 won in the red coin bank and 5,000 won in the yellow coin bank, and 300 won and 500 won in each coin bank every day. How much money is in the red coin bank on the day when the money in both coin banks is equal?",
        "answer_ko": "12500",
        "answer_en": "12500",
        "solution_abst_ko": "8000 5000 [OP_SUB] 500 300 [OP_SUB] [OP_DIV] 300 [OP_MUL] 8000 [OP_ADD]",
        "solution_abst_en": "8000 5000 [OP_SUB] 500 300 [OP_SUB] [OP_DIV] 300 [OP_MUL] 8000 [OP_ADD]",
        "solution_code_ko": "var_a = 8000\nvar_b = 5000\nvar_c = var_a - var_b\nvar_d = 500\nvar_e = 300\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 300\nvar_i = var_g * var_h\nvar_j = 8000\nvar_k = var_i + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 8000\nvar_b = 5000\nvar_c = var_a - var_b\nvar_d = 500\nvar_e = 300\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nvar_h = 300\nvar_i = var_g * var_h\nvar_j = 8000\nvar_k = var_i + var_j\nprint(int(var_k))"
    },
    "7215": {
        "category": "Arithmetic calculation",
        "question_ko": "평균이 8인 다섯 개의 수 중에 한개를 8로 바꾸니 평균이 9가 되었다.바꾼수는 원래 얼마인가?",
        "question_en": "If you change one of the five numbers, whose average is 8, to 8, the average becomes 9. What number was changed?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "8 5 [OP_MUL] 9 5 [OP_MUL] 8 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "8 5 [OP_MUL] 9 5 [OP_MUL] 8 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 8\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = 8\nvar_h = var_f - var_g\nvar_i = var_c - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 8\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = 5\nvar_f = var_d * var_e\nvar_g = 8\nvar_h = var_f - var_g\nvar_i = var_c - var_h\nprint(int(var_i))"
    },
    "7216": {
        "category": "Comparison",
        "question_ko": "남준이는 학교에 2번째로 도착했고, 지민이는 남준이 다음으로 3명이 더 도착한 뒤에 학교에 도착했습니다. 지민이는 몇 번째로 도착했습니까?",
        "question_en": "Namjoon was the second to arrive at school, and Jimin arrived after Namjoon and three more arrived. What place did Jimin arrive in?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "2 3 [OP_ADD] 1 [OP_ADD]",
        "solution_abst_en": "2 3 [OP_ADD] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7217": {
        "category": "Arithmetic calculation",
        "question_ko": "7.31에 1/5를 빼면 얼마인가요?",
        "question_en": "What is 7.31 minus 1/5?",
        "answer_ko": "7.11",
        "answer_en": "7.11",
        "solution_abst_ko": "7.31 1/5 [OP_SUB]",
        "solution_abst_en": "7.31 1/5 [OP_SUB]",
        "solution_code_ko": "var_a = 7.31\nvar_b = 0.2\nvar_c = var_a - var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 7.31\nvar_b = 0.2\nvar_c = var_a - var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "7218": {
        "category": "Arithmetic calculation",
        "question_ko": "연속하는 6개의 자연수의 합이 105입니다. 6개의 자연수 중에서 가장 큰 수와 가장 작은 수의 차를 구하시오.",
        "question_en": "The sum of 6 consecutive natural numbers is 105. Find the difference between the largest and smallest of that six natural numbers.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "6 1 [OP_SUB]",
        "solution_abst_en": "6 1 [OP_SUB]",
        "solution_code_ko": "var_a = 6\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "7219": {
        "category": "Correspondence",
        "question_ko": "어떤 수는 423으로 나누어 떨어지고, 이 때 몫은 423에서 421을 뺀 값과 같다. 어떤 수에 421을 더하면 얼마인지 구하시오.",
        "question_en": "A certain number is divisible by 423, and the quotient is equal to 423 minus 421. What is the sum of 421 added to the certain number?",
        "answer_ko": "1267",
        "answer_en": "1267",
        "solution_abst_ko": "421 423 423 421 [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_abst_en": "421 423 423 421 [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 421\nvar_b = 423\nvar_c = 423\nvar_d = 421\nvar_e = var_c - var_d\nvar_f = var_b * var_e\nvar_g = var_a + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 421\nvar_b = 423\nvar_c = 423\nvar_d = 421\nvar_e = var_c - var_d\nvar_f = var_b * var_e\nvar_g = var_a + var_f\nprint(int(var_g))"
    },
    "7220": {
        "category": "Comparison",
        "question_ko": "수 5개 1.4, 9/10, 1.2, 0.5, 13/10 중 1.1보다 큰 숫자를 구하고, 그 숫자들의 개수를 구하세요.",
        "question_en": "Find the number greater than 1.1 among the five numbers 1.4, 9/10, 1.2, 0.5 and 13/10, and find the number of that numbers.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i > var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "7221": {
        "category": "Arithmetic calculation",
        "question_ko": "연속하는 5개의 자연수의 합이 60입니다 첫번째 수를 구하시오",
        "question_en": "The sum of 5 consecutive natural numbers is 60. Find the first number.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "60 0 5 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 5 [OP_DIV]",
        "solution_abst_en": "60 0 5 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 5 [OP_DIV]",
        "solution_code_ko": "var_a = 60\nvar_b = 0\nvar_c = 5\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nlist_a = [i for i in range(var_b, var_e + 1, var_f)]\nlist_a = [float(i) for i in list_a]\nvar_g = sum(list_a)\nvar_h = var_a - var_g\nvar_i = 5\nvar_j = var_h / var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 60\nvar_b = 0\nvar_c = 5\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nlist_a = [i for i in range(var_b, var_e + 1, var_f)]\nlist_a = [float(i) for i in list_a]\nvar_g = sum(list_a)\nvar_h = var_a - var_g\nvar_i = 5\nvar_j = var_h / var_i\nprint(int(var_j))"
    },
    "7222": {
        "category": "Geometry",
        "question_ko": "어떤 직육면체의 부피가 36세제곱센티미터(㎤)이다. 이 직육면체 모서리를 2배로 늘린 정육면체의 부피가 얼마인지 구하시오",
        "question_en": "The volume of a cuboid is 36 cubic centimeters (cm3). What is the volume of a cube whose edges are doubled from the cuboid?",
        "answer_ko": "288",
        "answer_en": "288",
        "solution_abst_ko": "36 2 3 [OP_POW] [OP_MUL]",
        "solution_abst_en": "36 2 3 [OP_POW] [OP_MUL]",
        "solution_code_ko": "var_a = 36\nvar_b = 2\nvar_c = 3\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 36\nvar_b = 2\nvar_c = 3\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nprint(int(var_e))"
    },
    "7223": {
        "category": "Arithmetic calculation",
        "question_ko": "세 가지 종류의 과일이 있습니다. (가) 과일은 5개, (나) 과일은 6개, (다) 과일은 4개 있습니다. 과일은 모두 몇 개 있습니까?",
        "question_en": "There are three types of fruit. There are 5 fruit (a), 6 fruit (b), and 4 fruit (c). How many fruits are there in total?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "5 6 [OP_ADD] 4 [OP_ADD]",
        "solution_abst_en": "5 6 [OP_ADD] 4 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7224": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 일을 4명이 동일하게 나누어서 해결하였다. 한 명이 한 일은 전체 일의 얼마인지 구하시오.",
        "question_en": "If 4 people finished a task by dividing it with an equal amount. Find how much is done by one person out of the total task.",
        "answer_ko": "0.25",
        "answer_en": "0.25",
        "solution_abst_ko": "1 4 [OP_DIV]",
        "solution_abst_en": "1 4 [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "7225": {
        "category": "Geometry",
        "question_ko": "어떤 원 모양의 연못의 둘레를 재어 보니 314 센티미터(㎝)이고 지름이 100 센티미터(㎝) 였습니다. 이 연못의 둘레는 지름의 몇 배 인가요?",
        "question_en": "The circumference of a circular pond was measured and found to be 314 centimeters (cm) and 100 centimeters (cm) in diameter. How many times bigger is the circumference compared to the diameter of this pond?",
        "answer_ko": "3.14",
        "answer_en": "3.14",
        "solution_abst_ko": "314 100 [OP_DIV]",
        "solution_abst_en": "314 100 [OP_DIV]",
        "solution_code_ko": "var_a = 314\nvar_b = 100\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 314\nvar_b = 100\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "7226": {
        "category": "Comparison",
        "question_ko": "윤기는 7, 정국은 6, 유나는 9만큼 모았습니다. 2번째로 큰 숫자를 가진 사람은 누구입니까?",
        "question_en": "Yoongi, Jungkook, and Yuna each collected 7, 6, and 9. Who has the 2nd largest number?",
        "answer_ko": "윤기",
        "answer_en": "Yoongi",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 유나 [OP_LIST_EOL] [OP_LIST_SOL] 7 6 9 [OP_LIST_EOL] 2 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook Yuna [OP_LIST_EOL] [OP_LIST_SOL] 7 6 9 [OP_LIST_EOL] 2 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nvar_c = '유나'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 7\nvar_e = 6\nvar_f = 9\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nvar_c = 'Yuna'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 7\nvar_e = 6\nvar_f = 9\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "7227": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이와 석진이는 함께 서점에 가서 정국이는 18권의 책을, 석진이는 11권의 책을 더 샀습니다. 둘이 처음에 가지고 있던 책은 각각 28권이었습니다. 석진이가 가진 책은 정국이가 가진 책보다 몇 권 더 적습니까?",
        "question_en": "Jungkook and Seokjin went to the bookstore together and Jungkook bought 18 more books and Seokjin 11 more. The number of books they each had in the beginning were 28. How many fewer books does Seokjin have than Jungkook?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "28 18 [OP_ADD] 28 11 [OP_ADD] [OP_SUB]",
        "solution_abst_en": "28 18 [OP_ADD] 28 11 [OP_ADD] [OP_SUB]",
        "solution_code_ko": "var_a = 28\nvar_b = 18\nvar_c = var_a + var_b\nvar_d = 28\nvar_e = 11\nvar_f = var_d + var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 28\nvar_b = 18\nvar_c = var_a + var_b\nvar_d = 28\nvar_e = 11\nvar_f = var_d + var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "7228": {
        "category": "Arithmetic calculation",
        "question_ko": "세 자리 수 중 6, 5, 8, 9의 공배수 중 가장 큰 수는?",
        "question_en": "Find which three-digit number is the greatest common multiple of 6, 5, 8, and 9.",
        "answer_ko": "720",
        "answer_en": "720",
        "solution_abst_ko": "100 999 1 [OP_LIST_ARANGE] 6 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_abst_en": "100 999 1 [OP_LIST_ARANGE] 6 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = 1\nlist_f=list_e.copy()\nlist_f.sort()\nvar_i = list_f[-var_h]\nprint(int(var_i))",
        "solution_code_en": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = 1\nlist_f=list_e.copy()\nlist_f.sort()\nvar_i = list_f[-var_h]\nprint(int(var_i))"
    },
    "7229": {
        "category": "Geometry",
        "question_ko": "둘레가 52센티미터(㎝)인 정사각형과 직사각형이 있습니다. 직사각형의 세로 길이가 15센티미터(㎝)이다. 정사각형과 직사각형의 넓이 차를 구하시오.",
        "question_en": "You have a square and a rectangle with a perimeter of 52 centimeters (cm). The length of the rectangle is 15 centimeters (cm). Find the difference between the area of the square and the rectangle.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "52 4 [OP_DIV] 2 [OP_POW] 52 2 [OP_DIV] 15 [OP_SUB] 15 [OP_MUL] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "52 4 [OP_DIV] 2 [OP_POW] 52 2 [OP_DIV] 15 [OP_SUB] 15 [OP_MUL] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 52\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 52\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = 15\nvar_j = var_h - var_i\nvar_k = 15\nvar_l = var_j * var_k\nvar_m = var_e - var_l\nvar_n = abs(var_m)\nprint(int(var_n))",
        "solution_code_en": "var_a = 52\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 52\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = 15\nvar_j = var_h - var_i\nvar_k = 15\nvar_l = var_j * var_k\nvar_m = var_e - var_l\nvar_n = abs(var_m)\nprint(int(var_n))"
    },
    "7230": {
        "category": "Comparison",
        "question_ko": "수환이네 반 학생 7명의 등교에 걸리는 시간을 조사한 결과 10분, 12분, 15분, 6분, 3분, 8분, 9분이었습니다. 등교 시간이 10분 미만인 학생은 몇 명입니까?",
        "question_en": "As a result of investigating the time it took seven students in Suhwan's class to go to school, they were 10 minutes, 12 minutes, 15 minutes, 6 minutes, 3 minutes, 8 minutes, and 9 minutes. How many students reach the school in less than 10 minutes?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 10 12 15 6 3 8 9 [OP_LIST_EOL] 10 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 10 12 15 6 3 8 9 [OP_LIST_EOL] 10 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 10\nvar_b = 12\nvar_c = 15\nvar_d = 6\nvar_e = 3\nvar_f = 8\nvar_g = 9\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h = 10\nlist_b = []\nfor i in list_a:\n    if i < var_h:\n        list_b.append(i)\nvar_i = len(list_b)\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 12\nvar_c = 15\nvar_d = 6\nvar_e = 3\nvar_f = 8\nvar_g = 9\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h = 10\nlist_b = []\nfor i in list_a:\n    if i < var_h:\n        list_b.append(i)\nvar_i = len(list_b)\nprint(int(var_i))"
    },
    "7231": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 10센티미터(㎝)인 정사각형 몇 개를 이어 붙여서 정육면체의 전개도를 만들었습니다. 이 전개도의 넓이는 얼마입니까?",
        "question_en": "Several squares with a side length of 10 centimeters (cm) were glued together to create a planar figure of a cube. How many square centimeters (cm2) is this planar figure of a cube?",
        "answer_ko": "600",
        "answer_en": "600",
        "solution_abst_ko": "10 10 [OP_MUL] 6 [OP_MUL]",
        "solution_abst_en": "10 10 [OP_MUL] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "7232": {
        "category": "Possibility",
        "question_ko": "3, 5, 9의 숫자 중에서 2장을 뽑아 한 번씩만 사용하여 가장 큰 두 자리 수를 만들었습니다. 만든 두 자리 수보다 27 큰 수를 구하시오.",
        "question_en": "Two of the numbers 3, 5, and 9 were drawn and used only once to create the largest two-digit number. Find the number that is 27 greater than the two-digit number.",
        "answer_ko": "122",
        "answer_en": "122",
        "solution_abst_ko": "[OP_LIST_SOL] 3 5 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 27 [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 3 5 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 27 [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 5\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 27\nvar_h = var_f + var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 3\nvar_b = 5\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 27\nvar_h = var_f + var_g\nprint(int(var_h))"
    },
    "7233": {
        "category": "Geometry",
        "question_ko": "정육각뿔의 밑면의 한 변은 8센티미터(㎝)이고, 옆면의 한 변은 13센티미터(㎝)라면 모든 모서리의 합은 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "If one side of the base of a regular hexagonal pyramid is 8 centimeters (cm) and one side of the side face is 13 centimeters (cm), how many centimeters (cm) is the sum of all the edges?",
        "answer_ko": "126",
        "answer_en": "126",
        "solution_abst_ko": "13 6 [OP_MUL] 8 6 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "13 6 [OP_MUL] 8 6 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 13\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = 6\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 13\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = 6\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "7234": {
        "category": "Comparison",
        "question_ko": "세 숫자 A, B, C가 있다. A는 1/2이고 B는 9/10이다. C는 2/5일때, A, B, C 중 가장 작은 수는 무엇인가?",
        "question_en": "There are three numbers A, B, and C. A is 1/2 and B is 9/10. If C is 2/5, what is the smallest number among A, B, and C?",
        "answer_ko": "C",
        "answer_en": "C",
        "solution_abst_ko": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] 1/2 9/10 2/5 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] 1/2 9/10 2/5 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.5\nvar_e = 0.9\nvar_f = 0.4\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.5\nvar_e = 0.9\nvar_f = 0.4\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "7235": {
        "category": "Geometry",
        "question_ko": "어떤 팔각형의 한 꼭짓점에서 다른 점들에 대각선을 그었습니다. 이때 생기는 삼각형의 개수는?",
        "question_en": "Diagonals were drawn from one vertex of an octagon to the other points. How many triangles are formed in this case?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "8 3 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "8 3 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7236": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중에서 3번째로 작은 수와 2번째로 작은 수의 곱은 얼마입니까?",
        "question_en": "There are three numbers 10, 11 and 12. What is the product of the 3rd smallest number and the 2nd smallest number?",
        "answer_ko": "132",
        "answer_en": "132",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 3 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 3 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e * var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e * var_g\nprint(int(var_h))"
    },
    "7237": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 6으로 나누어야 할 것을 잘못하여 9로 나누었더니 몫이 8이고 나머지가 6이었습니다. 바르게 계산한 몫을 구하시오",
        "question_en": "When a number that should have been divided by 6 got mistakenly divided by 9, the quotient is 8 and the remainder is 6. Find the correctly calculated value.",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "8 9 [OP_MUL] 6 [OP_ADD] 6 [OP_FDIV]",
        "solution_abst_en": "8 9 [OP_MUL] 6 [OP_ADD] 6 [OP_FDIV]",
        "solution_code_ko": "var_a = 8\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c + var_d\nvar_f = 6\nvar_g = var_e // var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 8\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c + var_d\nvar_f = 6\nvar_g = var_e // var_f\nprint(int(var_g))"
    },
    "7238": {
        "category": "Possibility",
        "question_ko": "구슬이 2개, 3개, 4개 들어있는 주머니가 있다. 그중 서로 다른 주머니 2개를 선택하여 하나는 십의 자리, 하나는 일의 자리로 사용하여 두 자리 수를 만들 때, 만들 수 있는 두자리 수는 모두 몇 개입니까?",
        "question_en": "There are bags with 2, 3 or 4 marbles. How many two-digit numbers can be made by selecting two different pockets and use one for the tens place and one for the ones place to make a two-digit number?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 2 3 4 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 2 3 4 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = 4\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = 4\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "7239": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 18 로 나누어야 할 것을 잘못하여 1.8 로 나누었더니 몫은 21 이고, 나머지는 2 가 되었습니다. 바르게 계산했을 때의 몫을 반올림하여 소수 둘째 자리 까지 구하시오.",
        "question_en": "For a number that should have been divided by 18, I mistakenly divided it by 1.8, and the quotient was 21 and the remainder was 2. Find out the correct value that should have been calculated, and round it to two decimal places.",
        "answer_ko": "2.21",
        "answer_en": "2.21",
        "solution_abst_ko": "21 1.8 [OP_MUL] 2 [OP_ADD] 18 [OP_DIV] 2 [OP_ROUND]",
        "solution_abst_en": "21 1.8 [OP_MUL] 2 [OP_ADD] 18 [OP_DIV] 2 [OP_ROUND]",
        "solution_code_ko": "var_a = 21\nvar_b = 1.8\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c + var_d\nvar_f = 18\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = round(float(var_g)+1e-10, var_h)\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 21\nvar_b = 1.8\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c + var_d\nvar_f = 18\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = round(float(var_g)+1e-10, var_h)\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "7240": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 10미터(m)인 정삼각형 모양의 땅 둘레에 3미터(m) 간격으로 나무를 심으려고 합니다. 나무는 몇 그루 필요합니까?",
        "question_en": "You want to plant trees at intervals of 3 meters (m) around the land in the shape of an equilateral triangle with a side length of 10 meters (m). How many trees do you need?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "10 3 [OP_MUL] 3 [OP_FDIV]",
        "solution_abst_en": "10 3 [OP_MUL] 3 [OP_FDIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "7241": {
        "category": "Geometry",
        "question_ko": "운동장의 넓이가 143.2제곱미터(㎡)이며, 직사각형 모양이고, 세로가 4미터(m) 일 때, 가로는 몇 미터(m)입니까?",
        "question_en": "If the area of the playground is 143.2 square meters (m2), and the playground is rectangular, and the length is 4 meters (m), how many meters (m) is the width?",
        "answer_ko": "35.80",
        "answer_en": "35.8",
        "solution_abst_ko": "143.2 4 [OP_DIV]",
        "solution_abst_en": "143.2 4 [OP_DIV]",
        "solution_code_ko": "var_a = 143.2\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 143.2\nvar_b = 4\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "7242": {
        "category": "Comparison",
        "question_ko": "세 원 (가), (나), (다)가 있습니다. 원의 넓이는 각각 48제곱센티미터(㎠), 108제곱센티미터(㎠), 75제곱센티미터(㎠)입니다. 원주율을 3으로 계산했을 때 가장 큰 원의 지름의 길이에서 가장 작은 원의 지름의 길이를 뺀 값은 몇 센티미터(㎝)입니까?",
        "question_en": "There are three circles (a), (b), and (c). The areas of the circles are 48 square centimeters (cm2), 108 square centimeters (cm2), and 75 square centimeters (cm2), respectively. If pi is 3, how many centimeters (cm) is the length of the diameter of the largest circle minus the length of the diameter of the smallest circle?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 48 3 [OP_DIV] 1 2 [OP_DIV] [OP_POW] 108 3 [OP_DIV] 1 2 [OP_DIV] [OP_POW] 75 3 [OP_DIV] 1 2 [OP_DIV] [OP_POW] [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 48 3 [OP_DIV] 1 2 [OP_DIV] [OP_POW] 108 3 [OP_DIV] 1 2 [OP_DIV] [OP_POW] 75 3 [OP_DIV] 1 2 [OP_DIV] [OP_POW] [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 48\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = 2\nvar_f = var_d / var_e\nvar_g = var_c ** var_f\nvar_h = 108\nvar_i = 3\nvar_j = var_h / var_i\nvar_k = 1\nvar_l = 2\nvar_m = var_k / var_l\nvar_n = var_j ** var_m\nvar_o = 75\nvar_p = 3\nvar_q = var_o / var_p\nvar_r = 1\nvar_s = 2\nvar_t = var_r / var_s\nvar_u = var_q ** var_t\nlist_a= []\nif \"/\" in str(var_u):\n    var_u = eval(str(var_u))\nlist_a.append(var_u)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_a.append(var_n)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nlist_a.reverse()\nvar_v = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_w = list_b[-var_v]\nvar_x = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_y = list_c[var_x-1]\nvar_z = var_w - var_y\nprint(int(var_z))",
        "solution_code_en": "var_a = 48\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = 2\nvar_f = var_d / var_e\nvar_g = var_c ** var_f\nvar_h = 108\nvar_i = 3\nvar_j = var_h / var_i\nvar_k = 1\nvar_l = 2\nvar_m = var_k / var_l\nvar_n = var_j ** var_m\nvar_o = 75\nvar_p = 3\nvar_q = var_o / var_p\nvar_r = 1\nvar_s = 2\nvar_t = var_r / var_s\nvar_u = var_q ** var_t\nlist_a= []\nif \"/\" in str(var_u):\n    var_u = eval(str(var_u))\nlist_a.append(var_u)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_a.append(var_n)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nlist_a.reverse()\nvar_v = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_w = list_b[-var_v]\nvar_x = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_y = list_c[var_x-1]\nvar_z = var_w - var_y\nprint(int(var_z))"
    },
    "7243": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 16으로 나눈 값은 16에 8을 곱한 값과 같습니다. 어떤 수를 구하시오.",
        "question_en": "A number divided by 16 equals 16 multiplied by 8. Find a number.",
        "answer_ko": "2048",
        "answer_en": "2048",
        "solution_abst_ko": "8 16 [OP_MUL] 16 [OP_MUL]",
        "solution_abst_en": "8 16 [OP_MUL] 16 [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 16\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 16\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "7244": {
        "category": "Comparison",
        "question_ko": "영철이는 오늘 국어, 수학, 영어, 과학 4가지 수업을 듣는다. 국어보다 수학을 먼저 듣고 국어보다 영어를 늦게 듣고 과학보다 영어를 먼저 듣는다. 가장 늦게 듣는 수업을 구하시오.",
        "question_en": "Youngchul is taking 4 classes today: Korean, Mathematics, English, and Science. He listens to Mathematics first before Korean, and English later than Korean but before Science. Find the class he takes at last.",
        "answer_ko": "과학",
        "answer_en": "Science",
        "solution_abst_ko": "[OP_LIST_SOL] 국어 수학 영어 과학 [OP_LIST_EOL] [OP_LIST_SOL] 국어 수학 > 국어 영어 < 과학 영어 > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Korean Mathematics English Science [OP_LIST_EOL] [OP_LIST_SOL] Korean Mathematics > Korean English < Science English > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '국어'\nvar_b = '수학'\nvar_c = '영어'\nvar_d = '과학'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '국어'\nvar_f = '수학'\nvar_g = '>'\nvar_h = '국어'\nvar_i = '영어'\nvar_j = '<'\nvar_k = '과학'\nvar_l = '영어'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = 1\nvar_o = list_c[var_n-1]\nprint(var_o)",
        "solution_code_en": "var_a = 'Korean'\nvar_b = 'Mathematics'\nvar_c = 'English'\nvar_d = 'Science'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'Korean'\nvar_f = 'Mathematics'\nvar_g = '>'\nvar_h = 'Korean'\nvar_i = 'English'\nvar_j = '<'\nvar_k = 'Science'\nvar_l = 'English'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = 1\nvar_o = list_c[var_n-1]\nprint(var_o)"
    },
    "7245": {
        "category": "Comparison",
        "question_ko": "물 1리터(L)와 물 3리터(L)를 모양과 크기가 같은 병에 각각 똑같이 나누어 담으려고 합니다. 물 1리터(L)를 병 가 2개에, 물 3리터(L)를 병 나 4개에 남김없이 똑같이 나누어 담을 때, 병 가와 병 나 중 어느 병에 물이 더 많을까요?",
        "question_en": "You want to divide 1 liter (L) of water and 3 liters (L) of water equally into bottles of the same shape and size. If 1 liter (L) of water is divided equally into 2 (A) bottles and 3 liters (L) of water is divided equally into 4 (B) bottles, which bottle has more water, bottle A or bottle B?",
        "answer_ko": "나",
        "answer_en": "(B)",
        "solution_abst_ko": "[OP_LIST_SOL] 가 나 [OP_LIST_EOL] [OP_LIST_SOL] 1 2 [OP_MUL] 3 4 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (A) (B) [OP_LIST_EOL] [OP_LIST_SOL] 1 2 [OP_MUL] 3 4 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '가'\nvar_b = '나'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 3\nvar_g = 4\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = '(A)'\nvar_b = '(B)'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 3\nvar_g = 4\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "7246": {
        "category": "Arithmetic calculation",
        "question_ko": "물 135.1리터(L)가 있습니다. 이것을 7리터(L)들이 물통으로 나누어 담는다면 가득 채울 수 있는 물통은 몇 개입니까?",
        "question_en": "There are 135.1 liters (L) of water. How many water bottles can be filled if you divide the water into 7 liters (L) water bottles?",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "135.1 7 [OP_FDIV]",
        "solution_abst_en": "135.1 7 [OP_FDIV]",
        "solution_code_ko": "var_a = 135.1\nvar_b = 7\nvar_c = var_a // var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 135.1\nvar_b = 7\nvar_c = var_a // var_b\nprint(int(var_c))"
    },
    "7247": {
        "category": "Arithmetic calculation",
        "question_ko": "민영이네 집에서 기르는 오리의 4배 만큼 닭이 있습니다. 오리는 토끼보다 17마리 많습니다. 민영이네 집에서 기르는 토끼가 8마리일 때, 민영이네 집에서 기르는 닭, 오리, 토끼는 모두 몇 마리입니까?",
        "question_en": "There are four times as many chickens as ducks raised at Minyoung's house. There are 17 more ducks than rabbits. If there are 8 rabbits in Minyoung's house, how many chickens, ducks, and rabbits are there in Minyoung's house in total?",
        "answer_ko": "133",
        "answer_en": "133",
        "solution_abst_ko": "8 8 17 [OP_ADD] [OP_ADD] 4 8 17 [OP_ADD] [OP_MUL] [OP_ADD]",
        "solution_abst_en": "8 8 17 [OP_ADD] [OP_ADD] 4 8 17 [OP_ADD] [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 8\nvar_c = 17\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nvar_f = 4\nvar_g = 8\nvar_h = 17\nvar_i = var_g + var_h\nvar_j = var_f * var_i\nvar_k = var_e + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 8\nvar_b = 8\nvar_c = 17\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nvar_f = 4\nvar_g = 8\nvar_h = 17\nvar_i = var_g + var_h\nvar_j = var_f * var_i\nvar_k = var_e + var_j\nprint(int(var_k))"
    },
    "7248": {
        "category": "Possibility",
        "question_ko": "10개의 숫자 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 중 서로 다른 두 개를 택하여 일렬로 나열하여 만든 두 자리의 자연수 중 30 이하의 홀수의 개수를 구하시오.",
        "question_en": "Find the number of odd numbers that are 30 or less among the two-digit natural numbers formed by arranging two different numbers from the ten numbers 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 4 5 6 7 8 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 30 [OP_LIST_LESS_EQUAL] 2 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 4 5 6 7 8 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 30 [OP_LIST_LESS_EQUAL] 2 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nvar_f = 5\nvar_g = 6\nvar_h = 7\nvar_i = 8\nvar_j = 9\nlist_a= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_a.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_k = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_k))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_l = 30\nlist_c = []\nfor i in list_b:\n    if i <= var_l:\n        list_c.append(i)\nvar_m = 2\nlist_d = []\nvar_m = int(var_m)\nfor i in list_c:\n    i = int(i)\n    if i % var_m == 0:\n        list_d.append(i)\nlist_e = list(set(list_c) - set(list_d))\nvar_n = len(list_e)\nprint(int(var_n))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nvar_f = 5\nvar_g = 6\nvar_h = 7\nvar_i = 8\nvar_j = 9\nlist_a= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_a.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_k = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_k))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_l = 30\nlist_c = []\nfor i in list_b:\n    if i <= var_l:\n        list_c.append(i)\nvar_m = 2\nlist_d = []\nvar_m = int(var_m)\nfor i in list_c:\n    i = int(i)\n    if i % var_m == 0:\n        list_d.append(i)\nlist_e = list(set(list_c) - set(list_d))\nvar_n = len(list_e)\nprint(int(var_n))"
    },
    "7249": {
        "category": "Correspondence",
        "question_ko": "세 자리 수의 모든 자리수를 더했더니 12가 되었습니다. 이러한 세 자리 수는 모두 몇 개입니가?",
        "question_en": "Adding all the digits of the three-digit number gives 12. How many of these three-digit numbers are there?",
        "answer_ko": "66",
        "answer_en": "66",
        "solution_abst_ko": "100 1000 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] 12 [OP_LIST_MORE_EQUAL] 12 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "100 1000 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] 12 [OP_LIST_MORE_EQUAL] 12 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 100\nvar_b = 1000\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nlist_b=[]\nfor i in list_a:\n    var_f = 0\n    i = int(i)\n    while i//10 > 0:\n        var_f = var_f + i%10\n        i = i//10\n    var_f = var_f + i%10\n    list_b.append(var_f)\nvar_g = 12\nlist_c = []\nfor i in list_b:\n    if i >= var_g:\n        list_c.append(i)\nvar_h = 12\nlist_d = []\nfor i in list_c:\n    if i <= var_h:\n        list_d.append(i)\nvar_i = len(list_d)\nprint(int(var_i))",
        "solution_code_en": "var_a = 100\nvar_b = 1000\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nlist_b=[]\nfor i in list_a:\n    var_f = 0\n    i = int(i)\n    while i//10 > 0:\n        var_f = var_f + i%10\n        i = i//10\n    var_f = var_f + i%10\n    list_b.append(var_f)\nvar_g = 12\nlist_c = []\nfor i in list_b:\n    if i >= var_g:\n        list_c.append(i)\nvar_h = 12\nlist_d = []\nfor i in list_c:\n    if i <= var_h:\n        list_d.append(i)\nvar_i = len(list_d)\nprint(int(var_i))"
    },
    "7250": {
        "category": "Correspondence",
        "question_ko": "6AB-41=591이 성립합니다. A는 무엇인가요?",
        "question_en": "6AB-41=591 is true. What is A, where 6AB is three-digit number?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "6AB-41=591 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "6AB-41=591 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '6AB-41=591'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '6AB-41=591'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "7251": {
        "category": "Correspondence",
        "question_ko": "40개의 사과 중 4개가 썩어서 버렸습니다. 나머지를 4개의 상자에 똑같이 나누어 담는다면 몇 개씩 담아야합니까?",
        "question_en": "4 out of 40 apples were thrown away because they were rotten. If you put the remainder equally into 4 boxes, how many should you put per box?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "40 4 [OP_SUB] 4 [OP_DIV]",
        "solution_abst_en": "40 4 [OP_SUB] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 40\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 40\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "7252": {
        "category": "Geometry",
        "question_ko": "정육면체의 각 면에는 1부터 6까지의 수가 하나씩 쓰여 있습니다. 이 정육면체에서 서로 평행한 두 면에 쓰여진 수의 합은 7입니다. 5와 5가 쓰여진 면과 평행한 면에 쓰여진 수의 곱은 얼마인지 구하시오.",
        "question_en": "Each side of the cube has a number from 1 to 6 written on it. The sum of the numbers written on the two parallel sides of this cube is 7. Find the value of the number written on the parallel side to the side with 5 on it being multiplied by 5.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "5 7 5 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "5 7 5 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 7\nvar_c = 5\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 7\nvar_c = 5\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nprint(int(var_e))"
    },
    "7253": {
        "category": "Arithmetic calculation",
        "question_ko": "5명의 사람이 서로 한번씩 악수를 한다면 악수는 몇 번 하게되는가?",
        "question_en": "If 5 people shake each other's hand once, how many times will they shake hands?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "5 5 3 [OP_SUB] [OP_MUL] 2 [OP_DIV] 5 [OP_ADD]",
        "solution_abst_en": "5 5 3 [OP_SUB] [OP_MUL] 2 [OP_DIV] 5 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 5\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 5\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 5\nvar_b = 5\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 5\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "7254": {
        "category": "Arithmetic calculation",
        "question_ko": "감 28개와 딸기 32개가 있습니다. 한명에게 종류 상관없이 4개씩 준다면 몇명에게 줄 수 있습니까?",
        "question_en": "There are 28 persimmons and 32 strawberries. If you give one person 4 of any kind, how many people can you give them?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "28 32 [OP_ADD] 4 [OP_FDIV]",
        "solution_abst_en": "28 32 [OP_ADD] 4 [OP_FDIV]",
        "solution_code_ko": "var_a = 28\nvar_b = 32\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 28\nvar_b = 32\nvar_c = var_a + var_b\nvar_d = 4\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "7255": {
        "category": "Geometry",
        "question_ko": "한 정육면체의 겉넓이는 150제곱센티미터(㎠)이다. 부피를 구하시오.",
        "question_en": "The surface area of one cube is 150 square centimeters (cm2). Find the volume.",
        "answer_ko": "125",
        "answer_en": "125",
        "solution_abst_ko": "150 6 [OP_DIV] 1/2 [OP_POW] 3 [OP_POW]",
        "solution_abst_en": "150 6 [OP_DIV] 1/2 [OP_POW] 3 [OP_POW]",
        "solution_code_ko": "var_a = 150\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 3\nvar_g = var_e ** var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 150\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 3\nvar_g = var_e ** var_f\nprint(int(var_g))"
    },
    "7256": {
        "category": "Geometry",
        "question_ko": "세계보건기구인 WHO 에서 우리 몸의 건강을 유지하기 위해 성인 기준으로 하루에 2000세제곱센티미터(㎤)만큼의 물을 마시는 것을 권장하고 있습니다. 밑면의 넓이가 50제곱센티미터(㎠)인 직육면체 모양의 물통에 성인 한 명의 하루 권장량만큼 물을 담으려고 합니다. 물통에 물을 몇 센티미터(㎝) 높이까지 넣어야 합니까?",
        "question_en": "The World Health Organization (WHO) recommends that adults drink 2000 cubic centimeters (cm3) of water per day to maintain their health. A cuboid-shaped water container with a bottom area of 50 square centimeters (cm2) is intended to contain the recommended amount of water for an adult per day. How many centimeters (cm) high should the water be in the bucket?",
        "answer_ko": "40",
        "answer_en": "40",
        "solution_abst_ko": "2000 50 [OP_DIV]",
        "solution_abst_en": "2000 50 [OP_DIV]",
        "solution_code_ko": "var_a = 2000\nvar_b = 50\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 2000\nvar_b = 50\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "7257": {
        "category": "Geometry",
        "question_ko": "어떤 수는 30에서 3더하기 2를 나눈 값이다. 어떤 수에 2를 더하면 얼마인지 구하시오.",
        "question_en": "A number is equal to 30 divided by 3 plus 2. What is the value of 2 added to the number?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "30 2 3 [OP_ADD] [OP_DIV] 2 [OP_ADD]",
        "solution_abst_en": "30 2 3 [OP_ADD] [OP_DIV] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 30\nvar_b = 2\nvar_c = 3\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 30\nvar_b = 2\nvar_c = 3\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "7258": {
        "category": "Correspondence",
        "question_ko": "다섯자리 수 1A23B는 12의 배수이다. 가능한 A는 모두 몇 가지인가?",
        "question_en": "The five-digit number 1A23B is a multiple of 12. How many possible A are there?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "1A23B [OP_GEN_POSSIBLE_LIST] 12 [OP_LIST_DIVISIBLE] 1A23B A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_abst_en": "1A23B [OP_GEN_POSSIBLE_LIST] 12 [OP_LIST_DIVISIBLE] 1A23B A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '1A23B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 12\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = '1A23B'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nvar_e = len(list_c)\nprint(int(var_e))",
        "solution_code_en": "var_a = '1A23B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 12\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = '1A23B'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nvar_e = len(list_c)\nprint(int(var_e))"
    },
    "7259": {
        "category": "Arithmetic calculation",
        "question_ko": "유림이는 오늘 하루 동안 콜라를 2리터(L) 600밀리리터(㎖) 마셨고, 지인이는 사이다를 3700밀리리터(㎖) 마셨습니다. 두 사람이 오늘 마신 음료수는 총 몇 밀리리터(㎖)일까요?",
        "question_en": "Yurim drank 2 liters (l) and 600 milliliters (ml) of Coke during the day, and Ji-in drank 3700 milliliters (ml) of cider. How many milliliters (ml) did the two drink today?",
        "answer_ko": "6300",
        "answer_en": "6300",
        "solution_abst_ko": "2 1000 [OP_MUL] 600 [OP_ADD] 3700 [OP_ADD]",
        "solution_abst_en": "2 1000 [OP_MUL] 600 [OP_ADD] 3700 [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 600\nvar_e = var_c + var_d\nvar_f = 3700\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 600\nvar_e = var_c + var_d\nvar_f = 3700\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "7260": {
        "category": "Correspondence",
        "question_ko": "연속된 세 자연수 A, B, C이 있다. A는 8의 배수, B는 7의 배수, C는 5의 배수라고 할 때, 1000보다 큰 수 중 가장 작은 A를 구하여라.",
        "question_en": "There are three consecutive natural numbers A, B, and C. If A is a multiple of 8, B is a multiple of 7, and C is a multiple of 5, find A the smallest of the numbers greater than 1000.",
        "answer_ko": "1008",
        "answer_en": "1008",
        "solution_abst_ko": "1000 1 [OP_ADD] 9999 1 [OP_LIST_ARANGE] 8 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "1000 1 [OP_ADD] 9999 1 [OP_LIST_ARANGE] 8 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1000\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 9999\nvar_e = 1\nlist_a = [i for i in range(var_c, var_d + 1, var_e)]\nvar_f = 8\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nprint(int(var_h))",
        "solution_code_en": "var_a = 1000\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 9999\nvar_e = 1\nlist_a = [i for i in range(var_c, var_d + 1, var_e)]\nvar_f = 8\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nprint(int(var_h))"
    },
    "7261": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 연속된 자연수의 합이 48입니다. 이 3개의 수 중에서 가장 큰 수와 가장 작은 수의 곱은 얼마입니까?",
        "question_en": "The sum of three consecutive natural numbers is 48. What is the product of the largest and smallest of these 3 numbers?",
        "answer_ko": "255",
        "answer_en": "255",
        "solution_abst_ko": "48 3 [OP_DIV] 3 2 [OP_FDIV] [OP_ADD] 48 3 [OP_DIV] 3 2 [OP_FDIV] [OP_SUB] [OP_MUL]",
        "solution_abst_en": "48 3 [OP_DIV] 3 2 [OP_FDIV] [OP_ADD] 48 3 [OP_DIV] 3 2 [OP_FDIV] [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 48\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 3\nvar_e = 2\nvar_f = var_d // var_e\nvar_g = var_c + var_f\nvar_h = 48\nvar_i = 3\nvar_j = var_h / var_i\nvar_k = 3\nvar_l = 2\nvar_m = var_k // var_l\nvar_n = var_j - var_m\nvar_o = var_g * var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 48\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 3\nvar_e = 2\nvar_f = var_d // var_e\nvar_g = var_c + var_f\nvar_h = 48\nvar_i = 3\nvar_j = var_h / var_i\nvar_k = 3\nvar_l = 2\nvar_m = var_k // var_l\nvar_n = var_j - var_m\nvar_o = var_g * var_n\nprint(int(var_o))"
    },
    "7262": {
        "category": "Arithmetic calculation",
        "question_ko": "추석에 감을 5개 먹었더니 12개가 남았습니다. 감을 먹기 전 처음에 있던 감은 몇 개입니까?",
        "question_en": "I ate 5 persimmons on Chuseok, but there are 12 left. How many persimmons were there at first before eating them?",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "12 5 [OP_ADD]",
        "solution_abst_en": "12 5 [OP_ADD]",
        "solution_code_ko": "var_a = 12\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 12\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "7263": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 문구점에서 물건을 판매할 때 8000원어치를 사면 1200원을 할인해 준다고 합니다. 이 문구점에서 15000원어치 물건을 사면 얼마를 할인받습니까?",
        "question_en": "A stationery store offers a 1,200 won discount for purchases worth 8,000 won. How much discount do you get if you buy something worth 15,000 won at this stationery store?",
        "answer_ko": "2250",
        "answer_en": "2250",
        "solution_abst_ko": "1200 8000 [OP_DIV] 15000 [OP_MUL]",
        "solution_abst_en": "1200 8000 [OP_DIV] 15000 [OP_MUL]",
        "solution_code_ko": "var_a = 1200\nvar_b = 8000\nvar_c = var_a / var_b\nvar_d = 15000\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 1200\nvar_b = 8000\nvar_c = var_a / var_b\nvar_d = 15000\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "7264": {
        "category": "Correspondence",
        "question_ko": "서로 다른 수 A, B, C가 있습니다. A는 9보다 4 작은 수이고, B는 A보다 5 큰 수이고, C보다 8 작은 수는 1입니다. B에서 C를 뺀 값은 얼마입니까?",
        "question_en": "There are different numbers A, B, and C. A is 4 less than 9, B is 5 more than A, and 8 less than C is 1. What is B minus C?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "9 4 [OP_SUB] 5 [OP_ADD] 8 1 [OP_ADD] [OP_SUB]",
        "solution_abst_en": "9 4 [OP_SUB] 5 [OP_ADD] 8 1 [OP_ADD] [OP_SUB]",
        "solution_code_ko": "var_a = 9\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = var_e - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 9\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = var_e - var_h\nprint(int(var_i))"
    },
    "7265": {
        "category": "Possibility",
        "question_ko": "한 자리의 3의 배수를 중복으로 사용하여 만들 수 있는 세 자리 수 중 다섯 번째로 작은 수는 무엇입니까?",
        "question_en": "What is the fifth smallest three-digit number that can be formed by using single digit multiples of 3?",
        "answer_ko": "366",
        "answer_en": "366",
        "solution_abst_ko": "1 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 3 [OP_LIST_GET_PRODUCT] 5 [OP_LIST_MIN]",
        "solution_abst_en": "1 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 3 [OP_LIST_GET_PRODUCT] 5 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 3\nlist_c = [str(i) for i in list_b]\nlist_c = list(itertools.product(list_c, repeat=var_e))\nlist_c = [''.join(num_list) for num_list in list_c]\nlist_c = [str_num for str_num in list_c if str_num[0] != '0']\nlist_c = [float(i) for i in list_c]\nvar_f = 5\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 3\nlist_c = [str(i) for i in list_b]\nlist_c = list(itertools.product(list_c, repeat=var_e))\nlist_c = [''.join(num_list) for num_list in list_c]\nlist_c = [str_num for str_num in list_c if str_num[0] != '0']\nlist_c = [float(i) for i in list_c]\nvar_f = 5\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[var_f-1]\nprint(int(var_g))"
    },
    "7266": {
        "category": "Geometry",
        "question_ko": "가로가 28센티미터(㎝), 세로가 24센티미터(㎝), 높이가 19센티미터(㎝)인 직육면체의 각 모서리의 길이를 2배로 늘여서 새로운 직육면체를 만들었습니다. 새로 만든 직육면체의 부피는 처음 직육면체의 부피의 몇 배입니까?",
        "question_en": "A new cuboid was created by doubling the length of each corner of a cuboid measuring 28 centimeters (cm) wide, 24 centimeters (cm) long, and 19 centimeters (cm) high. How many times the volume of the newly created cuboid is the volume of the original cuboid?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "28 2 [OP_MUL] 24 [OP_MUL] 2 [OP_MUL] 19 [OP_MUL] 2 [OP_MUL] 28 24 [OP_MUL] 19 [OP_MUL] [OP_FDIV]",
        "solution_abst_en": "28 2 [OP_MUL] 24 [OP_MUL] 2 [OP_MUL] 19 [OP_MUL] 2 [OP_MUL] 28 24 [OP_MUL] 19 [OP_MUL] [OP_FDIV]",
        "solution_code_ko": "var_a = 28\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 24\nvar_e = var_c * var_d\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = 19\nvar_i = var_g * var_h\nvar_j = 2\nvar_k = var_i * var_j\nvar_l = 28\nvar_m = 24\nvar_n = var_l * var_m\nvar_o = 19\nvar_p = var_n * var_o\nvar_q = var_k // var_p\nprint(int(var_q))",
        "solution_code_en": "var_a = 28\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 24\nvar_e = var_c * var_d\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = 19\nvar_i = var_g * var_h\nvar_j = 2\nvar_k = var_i * var_j\nvar_l = 28\nvar_m = 24\nvar_n = var_l * var_m\nvar_o = 19\nvar_p = var_n * var_o\nvar_q = var_k // var_p\nprint(int(var_q))"
    },
    "7267": {
        "category": "Possibility",
        "question_ko": "4개의 숫자 1, 5, 6, 9를 한 번씩 사용하여 십의 자리 숫자가 1인 가장 큰 세 자리 수를 구하시오.",
        "question_en": "Using the four digits 1, 5, 6, and 9 once, find out the largest three-digit number with 1 in the tens place.",
        "answer_ko": "916",
        "answer_en": "916",
        "solution_abst_ko": "[OP_LIST_SOL] 1 5 6 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 1 [OP_LIST_SEARCH_FIXED_DIGIT] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1 5 6 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 1 [OP_LIST_SEARCH_FIXED_DIGIT] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1\nvar_b = 5\nvar_c = 6\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 1\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 5\nvar_c = 6\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 1\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nprint(int(var_i))"
    },
    "7268": {
        "category": "Geometry",
        "question_ko": "직사각형 모양의 똑같은 자석이 두 개가 있습니다. 자석 두개를 가로로 이어 붙이면 전체 둘레가 70센티미터(㎝)이고, 세로가 15센티미터(㎝)입니다. 자석 하나의 넓이를 구하시오.",
        "question_en": "There are two identical magnets in the shape of a rectangle. If you attach two magnets horizontally, the total circumference is 70 centimeters (cm) and the length is 15 centimeters (cm). Find the area of one magnet.",
        "answer_ko": "150",
        "answer_en": "150",
        "solution_abst_ko": "70 2 [OP_DIV] 15 [OP_SUB] 15 [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "70 2 [OP_DIV] 15 [OP_SUB] 15 [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 70\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 15\nvar_e = var_c - var_d\nvar_f = 15\nvar_g = var_e * var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 70\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 15\nvar_e = var_c - var_d\nvar_f = 15\nvar_g = var_e * var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "7269": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 100까지의 자연수 중 일의 자리 수가 0인 수들의 평균을 구하시오.",
        "question_en": "Find the average of all natural numbers from 1 to 100 where the units digit is 0.",
        "answer_ko": "55",
        "answer_en": "55",
        "solution_abst_ko": "1 100 1 [OP_LIST_ARANGE] 1 0 [OP_LIST_SEARCH_FIXED_DIGIT] [OP_LIST_MEAN]",
        "solution_abst_en": "1 100 1 [OP_LIST_ARANGE] 1 0 [OP_LIST_SEARCH_FIXED_DIGIT] [OP_LIST_MEAN]",
        "solution_code_ko": "var_a = 1\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 1\nvar_e = 0\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i in list_a:\n    i = int(i)\n    if (i//var_d)%10 == var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)/len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 1\nvar_e = 0\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i in list_a:\n    i = int(i)\n    if (i//var_d)%10 == var_e:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)/len(list_b)\nprint(int(var_f))"
    },
    "7270": {
        "category": "Possibility",
        "question_ko": "노란색 구슬, 흰색 구슬, 빨간색 구슬, 보라색 구슬, 초록색 구슬, 파란색 구슬 중에서 서로 다른 색상으로 두 개를 고릅니다. 고를 수 있는 방법의 개수를 구하시오.",
        "question_en": "Select two different colors: a yellow marble, a white marble, a red marble, a purple marble, a green marble, and a blue marble. Find the number of possible selections.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "[OP_LIST_SOL] 노란색 흰색 빨간색 보라색 초록색 파란색 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] yellow white red purple green blue [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '노란색'\nvar_b = '흰색'\nvar_c = '빨간색'\nvar_d = '보라색'\nvar_e = '초록색'\nvar_f = '파란색'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = len(list_a)\nvar_h = 2\nvar_i = 1\nvar_g = int(var_g)\nvar_h = int(var_h)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i * (var_g-i)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i / (i+1)\nprint(int(var_i))",
        "solution_code_en": "var_a = 'yellow'\nvar_b = 'white'\nvar_c = 'red'\nvar_d = 'purple'\nvar_e = 'green'\nvar_f = 'blue'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = len(list_a)\nvar_h = 2\nvar_i = 1\nvar_g = int(var_g)\nvar_h = int(var_h)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i * (var_g-i)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i / (i+1)\nprint(int(var_i))"
    },
    "7271": {
        "category": "Geometry",
        "question_ko": "초콜릿을 한 변에 6개씩 있는 정사각형이 되도록 빈틈없이 규칙적으로 늘어놓았다면, 둘레에 놓인 초콜릿은 몇 개입니까?",
        "question_en": "How many chocolates are placed around the perimeter if the chocolates are arranged in a regular pattern so that there are no gaps in a square with 6 per side?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "6 4 [OP_MUL] 4 [OP_SUB]",
        "solution_abst_en": "6 4 [OP_MUL] 4 [OP_SUB]",
        "solution_code_ko": "var_a = 6\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "7272": {
        "category": "Geometry",
        "question_ko": "민호의 책상 위에는 밑변이 15센티미터(㎝), 높이가 20센티미터(㎝)인 삼각형 모양의 삼각자가 있습니다. 이 삼각자의 넓이는 몇 제곱센티미터입니까?",
        "question_en": "On Minho's desk, there is a triangular ruler with a base of 15 centimeters (cm) and a height of 20 centimeters (cm). What is the area of this triangle in square centimeters?",
        "answer_ko": "150",
        "answer_en": "150",
        "solution_abst_ko": "15 20 [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "15 20 [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 15\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "7273": {
        "category": "Comparison",
        "question_ko": "5가지 숫자 1.4, 9/10, 1.2, 0.5, 13/10 중에서 1.1보다 작거나 같은 수들의 합을 구하면 얼마입니까?",
        "question_en": "What is the sum of the numbers less than or equal to 1.1 among five numbers 1.4, 9/10, 1.2, 0.5, and 13/10?",
        "answer_ko": "1.40",
        "answer_en": "1.4",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS_EQUAL] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS_EQUAL] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i <= var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i <= var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "7274": {
        "category": "Arithmetic calculation",
        "question_ko": "세 자리 수 중 3과 5의 공배수 중 가장 큰 수는?",
        "question_en": "Which three-digit number is the greatest common multiple of 3 and 5?",
        "answer_ko": "990",
        "answer_en": "990",
        "solution_abst_ko": "100 999 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_abst_en": "100 999 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[-var_f]\nprint(int(var_g))",
        "solution_code_en": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[-var_f]\nprint(int(var_g))"
    },
    "7275": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.9, 1/3 중에서 0.4보다 크거나 같은 수는 몇 개입니까?",
        "question_en": "How many of 0.8, 1/2, 0.9, and 1/3 are greater than or equal to 0.4?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.4\nlist_b = []\nfor i in list_a:\n    if i >= var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.4\nlist_b = []\nfor i in list_a:\n    if i >= var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "7276": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 기계 A 혼자서 일을 끝 마치는데 4시간이 걸리고 기계 B가 혼자서 일을 끝 마치는데 12시간이 걸린다. A, B가 동시에 이 일을 하면 몇 시간이 걸리는지 구하시오.",
        "question_en": "Machine A takes 4 hours to complete the job by itself and Machine B takes 12 hours to complete the job by itself. How many hours would it take for A and B to do this at the same time?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "1 1 4 [OP_DIV] 1 12 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_abst_en": "1 1 4 [OP_DIV] 1 12 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 1\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = 1\nvar_f = 12\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = var_a / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 1\nvar_c = 4\nvar_d = var_b / var_c\nvar_e = 1\nvar_f = 12\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nvar_i = var_a / var_h\nprint(int(var_i))"
    },
    "7277": {
        "category": "Arithmetic calculation",
        "question_ko": "1이상 10이하의 홀수 중 6이하의 수의 평균을 구하시오.",
        "question_en": "Find the average of the numbers less than or equal to 6, among the odd numbers that are not less than 1 and not greater than 10.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "1 10 [OP_LIST_ODD] 6 [OP_LIST_LESS_EQUAL] [OP_LIST_MEAN]",
        "solution_abst_en": "1 10 [OP_LIST_ODD] 6 [OP_LIST_LESS_EQUAL] [OP_LIST_MEAN]",
        "solution_code_ko": "var_a = 1\nvar_b = 10\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 6\nlist_b = []\nfor i in list_a:\n    if i <= var_c:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_d = sum(list_b)/len(list_b)\nprint(int(var_d))",
        "solution_code_en": "var_a = 1\nvar_b = 10\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 6\nlist_b = []\nfor i in list_a:\n    if i <= var_c:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_d = sum(list_b)/len(list_b)\nprint(int(var_d))"
    },
    "7278": {
        "category": "Comparison",
        "question_ko": "완수는 9/25리터(L)의 초코우유를 가지고 있고, 유경이는 0.41리터(L)의 초코우유를 가지고 있습니다. 초코우유를 더 많이 가지고 있는 사람은 누구입니까?",
        "question_en": "Wansoo has 9/25 liter (L) of chocolate milk, and Yugyeong has 0.41 liter (L) of chocolate milk. Who has more chocolate milk?",
        "answer_ko": "유경",
        "answer_en": "Yugyeong",
        "solution_abst_ko": "[OP_LIST_SOL] 완수 유경 [OP_LIST_EOL] [OP_LIST_SOL] 9/25 0.41 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Wansoo Yugyeong [OP_LIST_EOL] [OP_LIST_SOL] 9/25 0.41 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '완수'\nvar_b = '유경'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.36\nvar_d = 0.41\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Wansoo'\nvar_b = 'Yugyeong'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.36\nvar_d = 0.41\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "7279": {
        "category": "Arithmetic calculation",
        "question_ko": "시우가 어떤 일은 3시간 만에 끝 마쳤다. 시우가 1시간 동안 한 일의 양은 전체의 얼마인가?",
        "question_en": "Siwoo finished some work in 3 hours. What is the total amount of work Siwoo did in one hour?",
        "answer_ko": "0.33",
        "answer_en": "0.33",
        "solution_abst_ko": "1 3 [OP_DIV]",
        "solution_abst_en": "1 3 [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "7280": {
        "category": "Comparison",
        "question_ko": "학생들이 한 줄로 서 있습니다. 호석이는 윤기보다 오른쪽에 있고 그 사이에는 다른 학생 5명이 서 있습니다. 호석이의 오른쪽에는 9명이 서 있고, 윤기의 왼쪽에는 6명이 서 있습니다. 줄에 서 있는 학생은 모두 몇 명입니까?",
        "question_en": "When students are lined up, Hoseok stands at the right of Yoongi, and there are five other students between them. When there are 9 people on the right side of Hoseok, and 6 people on the left side of Yoongi, how many students are there?",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "1 1 [OP_ADD] 5 [OP_ADD] 9 [OP_ADD] 6 [OP_ADD]",
        "solution_abst_en": "1 1 [OP_ADD] 5 [OP_ADD] 9 [OP_ADD] 6 [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 9\nvar_g = var_e + var_f\nvar_h = 6\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c + var_d\nvar_f = 9\nvar_g = var_e + var_f\nvar_h = 6\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "7281": {
        "category": "Geometry",
        "question_ko": "짧은 변의 길이가 11센티미터(㎝)이고, 둘레의 길이는 52센티미터(㎝)인 직사각형의 넓이는 몇 제곱센티미터(㎠)입니까?",
        "question_en": "What is the area in square centimeters (cm2) of a rectangle whose short side is 11 centimeters (cm) and its perimeter is 52 centimeters (cm)?",
        "answer_ko": "165",
        "answer_en": "165",
        "solution_abst_ko": "11 52 2 [OP_DIV] 11 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "11 52 2 [OP_DIV] 11 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 11\nvar_b = 52\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = 11\nvar_f = var_d - var_e\nvar_g = var_a * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 11\nvar_b = 52\nvar_c = 2\nvar_d = var_b / var_c\nvar_e = 11\nvar_f = var_d - var_e\nvar_g = var_a * var_f\nprint(int(var_g))"
    },
    "7282": {
        "category": "Arithmetic calculation",
        "question_ko": "사탕이 6개 있습니다. 그중에서 석진이가 4개를 먹으면 태형이가 먹을 수 있는 사탕은 몇 개입니까?",
        "question_en": "There are 6 candies. How many candies can Taehyung eat if Seokjin eats 4 of them?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "6 4 [OP_SUB]",
        "solution_abst_en": "6 4 [OP_SUB]",
        "solution_code_ko": "var_a = 6\nvar_b = 4\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 4\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "7283": {
        "category": "Possibility",
        "question_ko": "다음 숫자 카드 0, 1, 3, 5, 6 중 3장을 뽑아 세 자리 자연수를 만들 때, 200보다 큰 자연수의 개수를 구하시오.",
        "question_en": "Find the number of natural numbers greater than 200 when making a three-digit natural number by drawing three of the following number cards: 0, 1, 3, 5, and 6.",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 3 5 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 200 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 3 5 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 200 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 3\nvar_d = 5\nvar_e = 6\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 200\nlist_c = []\nfor i in list_b:\n    if i > var_g:\n        list_c.append(i)\nvar_h = len(list_c)\nprint(int(var_h))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 3\nvar_d = 5\nvar_e = 6\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 200\nlist_c = []\nfor i in list_b:\n    if i > var_g:\n        list_c.append(i)\nvar_h = len(list_c)\nprint(int(var_h))"
    },
    "7284": {
        "category": "Correspondence",
        "question_ko": "태형이는 어떤 수에 8을 곱하려고 합니다. 하지만 실수로 5를 나누었더니 결과는 30이 되었습니다. 바르게 계산한 결과를 구하세요.",
        "question_en": "Taehyung wants to multiply a number by 8. But when he accidentally divided it by 5, the result was 30. Find the correct calculation result.",
        "answer_ko": "1200",
        "answer_en": "1200",
        "solution_abst_ko": "30 5 [OP_MUL] 8 [OP_MUL]",
        "solution_abst_en": "30 5 [OP_MUL] 8 [OP_MUL]",
        "solution_code_ko": "var_a = 30\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 30\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "7285": {
        "category": "Arithmetic calculation",
        "question_ko": "담을 칠하는 데 페인트 6.1리터(L)가 필요하다고 합니다. 페인트 333.4리터(L)로 칠할 수 있는 담은 모두 몇 개입니까?",
        "question_en": "It is said that it takes 6.1 liters (l) of paint to paint a wall. How many walls can be painted with 333.4 liters (l) of paint?",
        "answer_ko": "54",
        "answer_en": "54",
        "solution_abst_ko": "333.4 6.1 [OP_FDIV]",
        "solution_abst_en": "333.4 6.1 [OP_FDIV]",
        "solution_code_ko": "var_a = 333.4\nvar_b = 6.1\nvar_c = var_a // var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 333.4\nvar_b = 6.1\nvar_c = var_a // var_b\nprint(int(var_c))"
    },
    "7286": {
        "category": "Arithmetic calculation",
        "question_ko": "은지네 반 학생 중 (가) 악기를 칠 수 있는 학생은 24명이고, (나) 악기를 칠 수 있는 학생은 17명이고, (가), (나) 두 악기 모두 칠 수 있는 학생은 8명입니다. (가) 악기와 (나) 악기를 모두 칠 수 없는 학생이 한 명도 없을 때, 은지네 반 학생은 모두 몇 명입니까?",
        "question_en": "Among Eunji’s classmates, 24 students can play instrument (a), 17 students can play instrument (b), and 8 students can play both instruments. If there is no student who cannot play either (a) or (b), how many students are in Eunji's class?",
        "answer_ko": "33",
        "answer_en": "33",
        "solution_abst_ko": "24 17 [OP_ADD] 8 [OP_SUB]",
        "solution_abst_en": "24 17 [OP_ADD] 8 [OP_SUB]",
        "solution_code_ko": "var_a = 24\nvar_b = 17\nvar_c = var_a + var_b\nvar_d = 8\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 24\nvar_b = 17\nvar_c = var_a + var_b\nvar_d = 8\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "7287": {
        "category": "Possibility",
        "question_ko": "자연수 0, 2, 4, 5, 8 중 겹치지 않게 두 개를 뽑아 두 자리 수를 만들 때, 총 몇 개를 만들 수 있는가?",
        "question_en": "How many can you make in total when you make two digits by choosing two of the natural numbers 0, 2, 4, 5, and 8 so that they do not overlap?",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "[OP_LIST_SOL] 0 2 4 5 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 2 4 5 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 2\nvar_c = 4\nvar_d = 5\nvar_e = 8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 0\nvar_b = 2\nvar_c = 4\nvar_d = 5\nvar_e = 8\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "7288": {
        "category": "Geometry",
        "question_ko": "반지름이 15센티미터(㎝)인 고리의 둘레는 90센티미터(㎝)입니다. 고리의 둘레는 지름의 몇 배입니까?",
        "question_en": "A ring with a radius of 15 centimeters (cm) has a circumference of 90 centimeters (cm). How many times is the ring's circumference longer than the ring's diameter?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "90 15 2 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "90 15 2 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 90\nvar_b = 15\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 90\nvar_b = 15\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "7289": {
        "category": "Possibility",
        "question_ko": "A, B, C, D, E 5명이 있다. 5명 중 2명을 뽑아 일렬로 세우는 경우의 수를 구하시오.",
        "question_en": "There are 5 people A, B, C, D, and E. Find the number of ways to pick 2 people out of 5 and line them up.",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "5 2 [OP_PERM]",
        "solution_abst_en": "5 2 [OP_PERM]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))"
    },
    "7290": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 가장 큰 수와 그 다음으로 큰 수의 합은 얼마입니까?",
        "question_en": "There are five numbers 10, 11, 12, 13, and 14. What is the sum of the largest number and the next largest number?",
        "answer_ko": "27",
        "answer_en": "27",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[-var_h]\nvar_j = var_g + var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[-var_h]\nvar_j = var_g + var_i\nprint(int(var_j))"
    },
    "7291": {
        "category": "Comparison",
        "question_ko": "윤기는 4개, 유나는 5개, 정국에는 6 곱하기 3만큼 사과를 모았습니다. 누가 가장 적은 사과를 가지고 있습니까?",
        "question_en": "Yoongi collected 4 apples, Yuna collected 5 apples, and Jungkook collected 6 times 3 apples. Who has the fewest apples?",
        "answer_ko": "윤기",
        "answer_en": "Yoongi",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 유나 정국 [OP_LIST_EOL] [OP_LIST_SOL] 4 5 6 3 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Yuna Jungkook [OP_LIST_EOL] [OP_LIST_SOL] 4 5 6 3 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '유나'\nvar_c = '정국'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 5\nvar_f = 6\nvar_g = 3\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Yuna'\nvar_c = 'Jungkook'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 5\nvar_f = 6\nvar_g = 3\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "7292": {
        "category": "Comparison",
        "question_ko": "(가) 상자와 (나) 상자가 있습니다. 상자 (가)와 (나)를 비교하였습니다. (가) 상자가 (나) 상자보다 컸을 때, (가), (나) 2개의 상자 중 크기가 작은 상자는 무엇입니까?",
        "question_en": "There is a A box and a B box. You compared the two boxes. If A box is larger than B box, which of the two boxes is smaller?",
        "answer_ko": "(나)",
        "answer_en": "B",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) [OP_LIST_EOL] [OP_LIST_SOL] (가) (나) > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] A B > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = '(가)'\nvar_d = '(나)'\nvar_e = '>'\nlist_b= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_f = len(list_c)\nvar_g = list_c[var_f-1]\nprint(var_g)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 'A'\nvar_d = 'B'\nvar_e = '>'\nlist_b= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_f = len(list_c)\nvar_g = list_c[var_f-1]\nprint(var_g)"
    },
    "7293": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 293을 더해야 하는데 잘못하여 392를 더했더니 541이 되었습니다. 바르게 계산한 결과를 구하시오.",
        "question_en": "When you needed to add 293 to a number, but mistakenly added 392, it became 541. Find the result of the correct calculation.",
        "answer_ko": "442",
        "answer_en": "442",
        "solution_abst_ko": "541 392 [OP_SUB] 293 [OP_ADD]",
        "solution_abst_en": "541 392 [OP_SUB] 293 [OP_ADD]",
        "solution_code_ko": "var_a = 541\nvar_b = 392\nvar_c = var_a - var_b\nvar_d = 293\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 541\nvar_b = 392\nvar_c = var_a - var_b\nvar_d = 293\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7294": {
        "category": "Geometry",
        "question_ko": "크기가 같은 색종이를 가로 12개씩, 세로 12개씩 빈틈없이 늘어놓아 정사각형을 만들었습니다. 가장 바깥쪽의 한 변에 놓인 색종이의 개수는 몇 개일까요?",
        "question_en": "There is a square made by arranging 12 pieces of colored paper of the same size, which has 12 pieces in each side. How many pieces of colored paper are on one side?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "12",
        "solution_abst_en": "12",
        "solution_code_ko": "var_a = 12\nprint(int(var_a))",
        "solution_code_en": "var_a = 12\nprint(int(var_a))"
    },
    "7295": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 15를 곱하였더니 45가 되었습니다. 어떤 수에서 1을 뺀 결과를 구하시오.",
        "question_en": "When you multiply a number by 15, you get 45. Find the result of subtracting 1 from this number.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "45 15 [OP_DIV] 1 [OP_SUB]",
        "solution_abst_en": "45 15 [OP_DIV] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 45\nvar_b = 15\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 45\nvar_b = 15\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "7296": {
        "category": "Comparison",
        "question_ko": "네 명의 학생 지민, 윤기, 태형, 남준이가 줄을 서고 있습니다. 지민이는 윤기보다 앞에 있고, 태형이는 남준이보다 뒤에 있고, 윤기는 남준이보다 앞에 있을 때, 가장 뒤에 있는 학생은 누구입니까?",
        "question_en": "Four students, Jimin, Yoongi, Taehyung, and Namjoon, are lining up. When Jimin is in front of Yoongi, Taehyung is behind Namjoon, and Yoongi is in front of Namjoon, who is the most behind?",
        "answer_ko": "태형",
        "answer_en": "Taehyung",
        "solution_abst_ko": "[OP_LIST_SOL] 지민 윤기 태형 남준 [OP_LIST_EOL] [OP_LIST_SOL] 지민 윤기 > 태형 남준 < 윤기 남준 > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jimin Yoongi Taehyung Namjoon [OP_LIST_EOL] [OP_LIST_SOL] Jimin Yoongi > Taehyung Namjoon < Yoongi Namjoon > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '지민'\nvar_b = '윤기'\nvar_c = '태형'\nvar_d = '남준'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '지민'\nvar_f = '윤기'\nvar_g = '>'\nvar_h = '태형'\nvar_i = '남준'\nvar_j = '<'\nvar_k = '윤기'\nvar_l = '남준'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)",
        "solution_code_en": "var_a = 'Jimin'\nvar_b = 'Yoongi'\nvar_c = 'Taehyung'\nvar_d = 'Namjoon'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'Jimin'\nvar_f = 'Yoongi'\nvar_g = '>'\nvar_h = 'Taehyung'\nvar_i = 'Namjoon'\nvar_j = '<'\nvar_k = 'Yoongi'\nvar_l = 'Namjoon'\nvar_m = '>'\nlist_b= []\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_n = len(list_c)\nvar_o = list_c[var_n-1]\nprint(var_o)"
    },
    "7297": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.3, 1/3 중 0.4보다 크거나 같은 수의 개수를 구하시오.",
        "question_en": "Find the number of numbers greater than or equal to 0.4 among 0.8, 1/2, 0.3, and 1/3.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.3 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.3 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.3\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.4\nlist_b = []\nfor i in list_a:\n    if i >= var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.3\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 0.4\nlist_b = []\nfor i in list_a:\n    if i >= var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "7298": {
        "category": "Geometry",
        "question_ko": "어느 직육면체 모양의 상자가 있습니다. 겉넓이가 442제곱센티미터(㎠) 이며, 가로와 세로의 길이가 각각 7센티미터(㎝), 8센티미터(㎝)이라면 이 상자의 높이는 몇 센티미터(㎝)입니까?",
        "question_en": "There is a box in the shape of a rectangular cuboid. If the surface area is 442 square centimeters (cm2) and the length and width are 7 centimeters (cm) and 8 centimeters (cm) respectively, what is the height of this box in centimeters (cm)?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "442 2 [OP_DIV] 7 8 [OP_MUL] [OP_SUB] 7 8 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "442 2 [OP_DIV] 7 8 [OP_MUL] [OP_SUB] 7 8 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 442\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = 8\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 7\nvar_i = 8\nvar_j = var_h + var_i\nvar_k = var_g / var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 442\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = 8\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 7\nvar_i = 8\nvar_j = var_h + var_i\nvar_k = var_g / var_j\nprint(int(var_k))"
    },
    "7299": {
        "category": "Possibility",
        "question_ko": "주머니에 서로 다른 숫자가 적힌 빨간공 2개와 서로 다른 숫자가 적힌 파란공 4개가 들어있습니다. 이 중에서 공 하나를 선택하는 경우의 수를 구하세요.",
        "question_en": "A bag contains 2 red balls each with a different number and 4 blue balls each with a different number. Find the number of ways in which one ball is selected.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "2 4 [OP_ADD] 1 [OP_COMB]",
        "solution_abst_en": "2 4 [OP_ADD] 1 [OP_COMB]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 1\nvar_c = int(var_c)\nvar_d = int(var_d)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e * (var_c-i)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e / (i+1)\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 1\nvar_c = int(var_c)\nvar_d = int(var_d)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e * (var_c-i)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e / (i+1)\nprint(int(var_e))"
    },
    "7300": {
        "category": "Geometry",
        "question_ko": "정육면체의 모서리의 개수는?",
        "question_en": "How many edges does a cube have?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "4 3 [OP_MUL]",
        "solution_abst_en": "4 3 [OP_MUL]",
        "solution_code_ko": "var_a = 4\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "7301": {
        "category": "Comparison",
        "question_ko": "학생들이 한 줄로 서 있습니다. 석진이의 앞에는 4명이 서 있고, 지민이의 뒤에는 7명이 서 있습니다. 지민이가 석진이보다 뒤에 있을 때, 석진이와 지민이 사이에는 3명이 서 있습니다. 줄을 서 있는 학생은 모두 몇 명입니까?",
        "question_en": "Students stand in a line. 4 people are standing in front of Seokjin, and 7 people are standing behind Jimin. When Jimin is behind Seokjin, three people stand between Seokjin and Jimin. How many students are standing in line?",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "4 7 [OP_ADD] 3 [OP_ADD] 2 [OP_ADD]",
        "solution_abst_en": "4 7 [OP_ADD] 3 [OP_ADD] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "7302": {
        "category": "Geometry",
        "question_ko": "어떤 다각형 내부의 한 점을 선택한 후 나머지 꼭짓점들과 연결하는 선을 그었더니 스무 개의 삼각형이 생겼습니다. 이 다각형의 대각선의 개수를 구하시오.",
        "question_en": "After selecting a point inside a polygon and drawing lines connecting it to the rest of the vertices, 20 triangles were created. Find the number of diagonals of this polygon.",
        "answer_ko": "170",
        "answer_en": "170",
        "solution_abst_ko": "20 20 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "20 20 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 20\nvar_b = 20\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 20\nvar_b = 20\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "7303": {
        "category": "Arithmetic calculation",
        "question_ko": "학교가 마친 후 학원까지 빠르게 자전거를 탔더니 시속 15킬로미터(㎞)가 나왔다. 학원이 끝나고 학교에 책을 가지러 돌아갈 때는 시속 10킬로미터(㎞)로 달렸더니, 30분이 더 걸렸다. 학교와 학원 사이의 거리는 몇 킬로미터(㎞)인가?",
        "question_en": "After school, I rode my bike quickly to the academy, and it measured 15 kilometers (km) per hour. I rode at 10 kilometers (km) per hour to get back to school to pick up books after the academy, and it took another 30 minutes longer. How many kilometers (km) is the distance between the school and the academy?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "30 60 [OP_DIV] 1 10 [OP_DIV] 1 15 [OP_DIV] [OP_SUB] [OP_DIV]",
        "solution_abst_en": "30 60 [OP_DIV] 1 10 [OP_DIV] 1 15 [OP_DIV] [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 30\nvar_b = 60\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = 10\nvar_f = var_d / var_e\nvar_g = 1\nvar_h = 15\nvar_i = var_g / var_h\nvar_j = var_f - var_i\nvar_k = var_c / var_j\nprint(int(eval('{:.2f}'.format(round(var_k+1e-10,2)))))",
        "solution_code_en": "var_a = 30\nvar_b = 60\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = 10\nvar_f = var_d / var_e\nvar_g = 1\nvar_h = 15\nvar_i = var_g / var_h\nvar_j = var_f - var_i\nvar_k = var_c / var_j\nprint(int(eval('{:.2f}'.format(round(var_k+1e-10,2)))))"
    },
    "7304": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.9 중에서 0.4보다 큰 수를 모두 더하면 얼마일까요?",
        "question_en": "What is the sum of all the numbers greater than 0.4 among 0.8, 1/2, and 0.9?",
        "answer_ko": "2.20",
        "answer_en": "2.2",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 0.4 [OP_LIST_MORE] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 0.4 [OP_LIST_MORE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.4\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.4\nlist_b = []\nfor i in list_a:\n    if i > var_d:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "7305": {
        "category": "Possibility",
        "question_ko": "사과 20개를 서로 다른 2개의 바구니에 나누어 담으려고 합니다. 바구니에는 적어도 사과 1개를 담습니다. 사과를 나누어 담는 방법은 모두 몇 가지입니까?",
        "question_en": "You want to divide 20 apples into 2 different baskets. There should be at least 1 apple in the basket. How many ways are possible to divide apples?",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "20 2 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "20 2 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 20\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7306": {
        "category": "Geometry",
        "question_ko": "둘레가 56센티미터(㎝)이고, 가로가 16센티미터(㎝)인 직사각형의 넓이는 몇 제곱센티미터(㎠)인지 구하시오.",
        "question_en": "Find the area in square centimeters (cm2) of a rectangle with a perimeter of 56 centimeters (cm) and a width of 16 centimeters (cm).",
        "answer_ko": "192",
        "answer_en": "192",
        "solution_abst_ko": "56 2 [OP_DIV] 16 [OP_SUB] 16 [OP_MUL]",
        "solution_abst_en": "56 2 [OP_DIV] 16 [OP_SUB] 16 [OP_MUL]",
        "solution_code_ko": "var_a = 56\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 16\nvar_e = var_c - var_d\nvar_f = 16\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 56\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 16\nvar_e = var_c - var_d\nvar_f = 16\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "7307": {
        "category": "Comparison",
        "question_ko": "토끼와 거북이 경주. 같은 시간 동안 토끼는 10.2킬로미터(㎞)의 100분의 1을 달렸고, 거북이는 100미터(m)를 달렸다. 누가 더 많이 달렸습니까?",
        "question_en": "The rabbit and tortoise had a race. During the same amount of time, the rabbit ran one hundredth of 10.2 kilometers (km), and the tortoise ran 100 meters (m). Who ran more?",
        "answer_ko": "토끼",
        "answer_en": "rabbit",
        "solution_abst_ko": "[OP_LIST_SOL] 토끼 거북이 [OP_LIST_EOL] [OP_LIST_SOL] 10.2 1000 [OP_MUL] 100 [OP_DIV] 100 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] rabbit tortoise [OP_LIST_EOL] [OP_LIST_SOL] 10.2 1000 [OP_MUL] 100 [OP_DIV] 100 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '토끼'\nvar_b = '거북이'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10.2\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 100\nvar_g = var_e / var_f\nvar_h = 100\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'rabbit'\nvar_b = 'tortoise'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10.2\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 100\nvar_g = var_e / var_f\nvar_h = 100\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "7308": {
        "category": "Arithmetic calculation",
        "question_ko": "8명의 학생에게 인형을 똑같이 나누어 준 후 남는 인형이 없게 하려고 합니다. 인형이 62개 있을 때, 몇 개의 인형이 최소로 더 필요합니까?",
        "question_en": "You want to make no dolls left after handing out dolls equally to 8 students. When there are 62 dolls, how many more dolls do you need at least?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "62 8 [OP_MOD] 8 [OP_SUB] [OP_ABS]",
        "solution_abst_en": "62 8 [OP_MOD] 8 [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 62\nvar_b = 8\nvar_c = var_a % var_b\nvar_d = 8\nvar_e = var_c - var_d\nvar_f = abs(var_e)\nprint(int(var_f))",
        "solution_code_en": "var_a = 62\nvar_b = 8\nvar_c = var_a % var_b\nvar_d = 8\nvar_e = var_c - var_d\nvar_f = abs(var_e)\nprint(int(var_f))"
    },
    "7309": {
        "category": "Comparison",
        "question_ko": "0.34, 2/4, 9/11, 0.22, 0.76 중 가장 큰 수와 가장 작은 수의 곱을 구하시오",
        "question_en": "Find the product of the largest number and the smallest number among 0.34, 2/4, 9/11, 0.22, and 0.76.",
        "answer_ko": "0.18",
        "answer_en": "0.18",
        "solution_abst_ko": "[OP_LIST_SOL] 0.34 2/4 9/11 0.22 0.76 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 0.34 2/4 9/11 0.22 0.76 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MUL]",
        "solution_code_ko": "var_a = 0.34\nvar_b = 0.5\nvar_c = 0.8181818181818182\nvar_d = 0.22\nvar_e = 0.76\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g * var_i\nprint('{:.2f}'.format(round(var_j+1e-10,2)))",
        "solution_code_en": "var_a = 0.34\nvar_b = 0.5\nvar_c = 0.8181818181818182\nvar_d = 0.22\nvar_e = 0.76\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g * var_i\nprint('{:.2f}'.format(round(var_j+1e-10,2)))"
    },
    "7310": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 3번째로 작은 수와 2번째로 작은 수의 차는 얼마입니까?",
        "question_en": "There are five numbers 10, 11, 12, 13, and 14. What is the value of difference between the 3rd smallest number and the 2nd smallest number?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 3 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 3 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))"
    },
    "7311": {
        "category": "Correspondence",
        "question_ko": "수영이는 물건을 사러가서 첫 번째 가게에서 가진 돈의 3/8을 사용하고 두 번째 가게에서 남은 돈의 1/3을 사용하고, 세 번째 가게에서 다시 남은 돈의 4/5를 사용하였더니 남은 돈이 1200원이였습니다. 수영이가 처음 가지고 있던 돈은 얼마인지 구하십시오.",
        "question_en": "Suyeong goes shopping and uses 3/8 of her money at the first store, 1/3 of the remaining money at the second store, and 4/5 of the remaining money at the third store. The money was 1200 won. Find how much money Sooyoung had at first.",
        "answer_ko": "14400",
        "answer_en": "14400",
        "solution_abst_ko": "1200 1 4/5 [OP_SUB] [OP_DIV] 1 1/3 [OP_SUB] [OP_DIV] 1 3/8 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "1200 1 4/5 [OP_SUB] [OP_DIV] 1 1/3 [OP_SUB] [OP_DIV] 1 3/8 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 1200\nvar_b = 1\nvar_c = 0.8\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 1\nvar_g = 0.3333333333333333\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 1\nvar_k = 0.375\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 1200\nvar_b = 1\nvar_c = 0.8\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 1\nvar_g = 0.3333333333333333\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 1\nvar_k = 0.375\nvar_l = var_j - var_k\nvar_m = var_i / var_l\nprint(int(var_m))"
    },
    "7312": {
        "category": "Geometry",
        "question_ko": "반지름이 3센티미터(㎝)인 구의 겉넓이와 같은 넓이를 가지는 원의 반지름의 길이는?",
        "question_en": "What is the length of the radius of a circle with an area equal to the surface area of a sphere with a radius of 3 centimeters (cm)?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "4 3 2 [OP_POW] [OP_MUL] 1/2 [OP_POW]",
        "solution_abst_en": "4 3 2 [OP_POW] [OP_MUL] 1/2 [OP_POW]",
        "solution_code_ko": "var_a = 4\nvar_b = 3\nvar_c = 2\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 0.5\nvar_g = var_e ** var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 3\nvar_c = 2\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 0.5\nvar_g = var_e ** var_f\nprint(int(var_g))"
    },
    "7313": {
        "category": "Correspondence",
        "question_ko": "4A+B3=68이 성립할 때, A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "When 4A+B3=68, what number should go into A, when 4A and B3 is two-digit number?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "4A+B3=68 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "4A+B3=68 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '4A+B3=68'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '4A+B3=68'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "7314": {
        "category": "Geometry",
        "question_ko": "모든 모서리의 길이의 합이 96센티미터(㎝)인 정육면체가 있습니다. 이 정육면체의 한 모서리의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "There is a cube with the sum of the lengths of all its edges equal to 96 centimeters (cm). How many centimeters (cm) is the length of one edge of this cube?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "96 12 [OP_DIV]",
        "solution_abst_en": "96 12 [OP_DIV]",
        "solution_code_ko": "var_a = 96\nvar_b = 12\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 96\nvar_b = 12\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "7315": {
        "category": "Arithmetic calculation",
        "question_ko": "지민이네 반보다 태형이네 반 학생 수가 3명 많고, 석진이네 반보다 지민이네 반 학생 수가 2명 적습니다. 태형이네 반 학생이 모두 35명일 때 석진이네 반 학생은 모두 몇 명입니까?",
        "question_en": "Taehyung's class has 3 more students than Jimin's class, and Jimin's class has 2 fewer students than Seokjin's class. If there are 35 students in Taehyung's class, how many students are in Seokjin's class?",
        "answer_ko": "34",
        "answer_en": "34",
        "solution_abst_ko": "35 3 [OP_SUB] 2 [OP_ADD]",
        "solution_abst_en": "35 3 [OP_SUB] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 35\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 35\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7316": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 3번째로 큰 수를 2번째로 큰 수로 나눈 나머지는 얼마입니까?",
        "question_en": "There are five numbers 10, 11, 12, 13, and 14. What is the remainder of the 2nd largest number divided by the 3rd largest number?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 3 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_MOD]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 3 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_MOD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[-var_h]\nvar_j = var_g % var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[-var_h]\nvar_j = var_g % var_i\nprint(int(var_j))"
    },
    "7317": {
        "category": "Arithmetic calculation",
        "question_ko": "상자 속에 밀가루가 담겨있습니다. 밀가루가 가득 담긴 상자의 무게를 재었더니 3.4킬로그램(㎏)이었고 밀가루의 1/5를 사용한 후 다시 잰 상자의 무게는 2.98킬로그램(㎏)이었습니다. 상자만의 무게는 얼마인지 구하세요.",
        "question_en": "There is flour in the box. When the box full of flour was weighed, it was 3.4 kilograms (kg), and after using 1/5 of the flour, the box is weighed again and it was 2.98 kilograms (kg). Find the weight of the empty box.",
        "answer_ko": "1.30",
        "answer_en": "1.3",
        "solution_abst_ko": "3.4 3.4 2.98 [OP_SUB] 1/5 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "3.4 3.4 2.98 [OP_SUB] 1/5 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 3.4\nvar_b = 3.4\nvar_c = 2.98\nvar_d = var_b - var_c\nvar_e = 0.2\nvar_f = var_d / var_e\nvar_g = var_a - var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 3.4\nvar_b = 3.4\nvar_c = 2.98\nvar_d = var_b - var_c\nvar_e = 0.2\nvar_f = var_d / var_e\nvar_g = var_a - var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "7318": {
        "category": "Geometry",
        "question_ko": "정민이는 한 변의 길이가 13센티미터(㎝)인 정오각형을 만들기 위해 문방구에서 철사를 샀습니다. 이 철사를 이용해서 정오각형을 1개 만들었더니 8센티미터(㎝)의 철사가 남았다고 합니다. 정민이가 문방구에서 산 철사는 몇 센티미터(㎝)입니까?",
        "question_en": "Jung-min bought wire at a stationery store to make a regular pentagon with a side length of 13 centimeters (cm). After making a regular pentagon with this wire, only 8 centimeters (cm) of wire was left. How many centimeters (cm) of wire did Jung-min buy at the store?",
        "answer_ko": "73",
        "answer_en": "73",
        "solution_abst_ko": "13 5 [OP_MUL] 8 [OP_ADD]",
        "solution_abst_en": "13 5 [OP_MUL] 8 [OP_ADD]",
        "solution_code_ko": "var_a = 13\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 13\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7319": {
        "category": "Geometry",
        "question_ko": "팔각형의 대각선은 모두 몇 개입니까?",
        "question_en": "How many diagonals does an octagon have?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "8 8 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "8 8 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 8\nvar_b = 8\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 8\nvar_b = 8\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "7320": {
        "category": "Arithmetic calculation",
        "question_ko": "상자에 동전이 몇 개 들어 있었습니다. 잠시 후 상자에 동전 8개를 더 넣었더니 모두 29개가 되었습니다. 처음 상자에 들어 있던 동전은 몇 개입니까?",
        "question_en": "There were some coins in the box. After a while, I put 8 more coins in the box, and there are 29 coins in total. How many coins were in the first place?",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "29 8 [OP_SUB]",
        "solution_abst_en": "29 8 [OP_SUB]",
        "solution_code_ko": "var_a = 29\nvar_b = 8\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 29\nvar_b = 8\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "7321": {
        "category": "Comparison",
        "question_ko": "각각의 키가 다른 10명이 키가 작은 사람부터 순서대로 한 줄로 서 있습니다. 유정이는 앞에서 4번째에 서 있습니다. 키가 큰 사람부터 순서대로 다시 줄을 서면 유정이는 앞에서 몇 번째에 서게 됩니까?",
        "question_en": "Ten people of different heights stand in a line in order, starting with the shortest. Yoojung is standing at the 4th from the front. If the line is organized in order from the tallest, what place does Yoojung take in the line?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "10 4 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "10 4 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7322": {
        "category": "Arithmetic calculation",
        "question_ko": "선풍기 14개가 들어 있는 상자의 무게는 11.14킬로그램(㎏)입니다. 빈 상자의 무게가 0.5킬로그램(㎏)이라면 선풍기 한 개의 무게는 몇 킬로그램(㎏)입니까?",
        "question_en": "There is a box weighing 11.14 kilograms (kg). If there are 14 fans in the box, and the empty box weighs 0.5 kilograms (kg), how many kilograms (kg) does one fan weigh?",
        "answer_ko": "0.76",
        "answer_en": "0.76",
        "solution_abst_ko": "11.14 0.5 [OP_SUB] 14 [OP_DIV]",
        "solution_abst_en": "11.14 0.5 [OP_SUB] 14 [OP_DIV]",
        "solution_code_ko": "var_a = 11.14\nvar_b = 0.5\nvar_c = var_a - var_b\nvar_d = 14\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 11.14\nvar_b = 0.5\nvar_c = var_a - var_b\nvar_d = 14\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "7323": {
        "category": "Arithmetic calculation",
        "question_ko": "유나가 하루에 영어문제를 8문제씩 풀었습니다. 유나가 7일 동안 푼 영어 문제는 모두 몇 문제입니까?",
        "question_en": "Yuna solved 8 English questions a day. How many English questions did Yuna solve in 7 days?",
        "answer_ko": "56",
        "answer_en": "56",
        "solution_abst_ko": "7 8 [OP_MUL]",
        "solution_abst_en": "7 8 [OP_MUL]",
        "solution_code_ko": "var_a = 7\nvar_b = 8\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 7\nvar_b = 8\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "7324": {
        "category": "Possibility",
        "question_ko": "서로 다른 두개의 수를 뽑아 각각 분자와 분모로 사용하려고 한다. 6개의 수3, 5, 7, 11, 13, 17중에서 숫자를 뽑을 때 만들 수 있는 분수 중 가분수는 모두 몇 개입니까?",
        "question_en": "Two different numbers will be used as numerator and denominator, respectively. How many improper fractions can there be when those numbers are selected from 3, 5, 7, 11, 13, and 17?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "6 2 [OP_COMB]",
        "solution_abst_en": "6 2 [OP_COMB]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))"
    },
    "7325": {
        "category": "Possibility",
        "question_ko": "2, 7, 0, 9 중 서로 다른 숫자 3개를 뽑아 세 자리 수를 만들려고 합니다. 만든 세 자리 수 중 5번째로 작은 수는 몇 입니까?",
        "question_en": "You want to create a three-digit number from 2, 7, 0, and 9. What is the 5th smallest of them?",
        "answer_ko": "290",
        "answer_en": "290",
        "solution_abst_ko": "[OP_LIST_SOL] 2 7 0 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 5 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 2 7 0 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 5 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 2\nvar_b = 7\nvar_c = 0\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 5\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 2\nvar_b = 7\nvar_c = 0\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 5\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nprint(int(var_g))"
    },
    "7326": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 2.4 로 나누어야 할 것을 잘못하여 곱하였더니 288 이 되었습니다. 바르게 계산하면 얼마입니까?",
        "question_en": "You incorrectly multiplied 2.4 to a number that should have been divided by 2.4 and got 288. What is the correct number?",
        "answer_ko": "50",
        "answer_en": "50",
        "solution_abst_ko": "288 2.4 [OP_DIV] 2.4 [OP_DIV]",
        "solution_abst_en": "288 2.4 [OP_DIV] 2.4 [OP_DIV]",
        "solution_code_ko": "var_a = 288\nvar_b = 2.4\nvar_c = var_a / var_b\nvar_d = 2.4\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 288\nvar_b = 2.4\nvar_c = var_a / var_b\nvar_d = 2.4\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "7327": {
        "category": "Possibility",
        "question_ko": "공 던지기 놀이를 하는데 공을 3번 던질 수 있습니다. 빨간색 원안에 맞히면 3점, 노란색 원안에 맞히면 2점, 원안에 맞히지 못하면 0점입니다. 이때 얻을 수 있는 점수는 모두 몇 가지입니까?",
        "question_en": "You can throw the ball 3 times while playing ball toss. If you hit inside the red circle, you get 3 points, if you hit inside the yellow circle, you get 2 points, and if you don't fit inside the circle, you get 0 points. What is the total number of points you can get?",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "[OP_LIST_SOL] 3 2 0 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_NUM2SUM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 3 2 0 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_NUM2SUM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = 0\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = 0\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "7328": {
        "category": "Geometry",
        "question_ko": "한 변이 8센티미터(㎝)인 정육각형을 만드는 데에 50센티미터(㎝)짜리 철사를 사용했습니다. 육각형 모양을 만들고 철사가 남았다면, 얼마나 남았을지 계산해보시오.",
        "question_en": "A 50 cm (cm) wire was used to make a regular hexagon with a side of 8 cm (cm). If some wire is left over, calculate how much it would have left.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "50 8 6 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "50 8 6 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 50\nvar_b = 8\nvar_c = 6\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 50\nvar_b = 8\nvar_c = 6\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "7329": {
        "category": "Geometry",
        "question_ko": "여덟 명의 학생이 팔각형 모양으로 모여 있습니다. 이 학생들이 자신과 이웃한 친구들을 제외하고 한 번씩 악수를 할 때 악수는 모두 몇 번이 이루어지는지 구하시오.",
        "question_en": "8 students are gathered in octagonal shapes. Find out how many times all of these students shake hands when they shake hands once except for their neighbors.",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "8 8 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "8 8 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 8\nvar_b = 8\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 8\nvar_b = 8\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "7330": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 냉장고 1대의 생산 원가는 45만 원이고, 판매 가격은 80만 원이라고 한다. 이 냉장고의 판매 수익이 1645만 원일 때, 판매한 냉장고는 몇 대인지 구하여라.",
        "question_en": "The production cost of one refrigerator is 450,000 won, and the sales price is 800,000 won. If the sales revenue of this refrigerator is 16.45 million won, how many refrigerators have been sold?",
        "answer_ko": "47",
        "answer_en": "47",
        "solution_abst_ko": "1645 80 45 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "1645 80 45 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 1645\nvar_b = 80\nvar_c = 45\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 1645\nvar_b = 80\nvar_c = 45\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "7331": {
        "category": "Geometry",
        "question_ko": "가로가 3센티미터(㎝), 세로가 2센티미터(㎝), 높이가 4센티미터(㎝)인 직육면체 모양의 (가) 통과 가로가 4센티미터(㎝), 세로가 2센티미터(㎝)인 직육면체 모양의 (나) 통이 있습니다. (나) 통에 높이가 1.5센티미터(㎝)만큼 차 있던 물을 (가) 통으로 모두 옮긴다면, (가) 통의 물의 높이는 몇 센티미터(㎝)가 됩니까?",
        "question_en": "There is a water tank (A) in the shape of a rectangular parallelepiped shape that is 3 centimeters (cm) long, 2 centimeters (cm) wide, and 4 centimeters (cm) high. There is another tank (B) with 4 centimeters (cm) long and 2 centimeters (cm) wide. If you move all the water filled in (B) that was 1.5 centimeters (cm) high into (A), what will be the height of water in (A) in centimeters (cm)?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "4 2 [OP_MUL] 1.5 [OP_MUL] 3 2 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "4 2 [OP_MUL] 1.5 [OP_MUL] 3 2 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 1.5\nvar_e = var_c * var_d\nvar_f = 3\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 1.5\nvar_e = var_c * var_d\nvar_f = 3\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "7332": {
        "category": "Geometry",
        "question_ko": "가로가 50센티미터(㎝), 세로가 16센티미터(㎝)인 직육면체 모양의 어항에 높이가 15센티미터(㎝)만큼 되도록 물을 채워 넣었습니다. 여기에 한 모서리의 길이가 10센티미터(㎝)인 정육면체 모양의 (가) 물건을 물 안에 완전히 잠기게 넣었습니다. 이 어항의 물의 높이는 몇 센티미터(㎝)가 되는지 소수점을 포함하여 구하시오.",
        "question_en": "A cuboid-shaped fish tank with a width of 50 centimeters (cm) and a length of 16 centimeters (cm) was filled with water to a height of 15 centimeters (cm). Here, a cube-shaped object with an edge of 10 centimeters (cm) is completely submerged in the water. Calculate how many centimeters (cm) the height of the water in this fish tank is, including the decimal point.",
        "answer_ko": "16.25",
        "answer_en": "16.25",
        "solution_abst_ko": "15 10 10 [OP_MUL] 10 [OP_MUL] 50 16 [OP_MUL] [OP_DIV] [OP_ADD]",
        "solution_abst_en": "15 10 10 [OP_MUL] 10 [OP_MUL] 50 16 [OP_MUL] [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 15\nvar_b = 10\nvar_c = 10\nvar_d = var_b * var_c\nvar_e = 10\nvar_f = var_d * var_e\nvar_g = 50\nvar_h = 16\nvar_i = var_g * var_h\nvar_j = var_f / var_i\nvar_k = var_a + var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 15\nvar_b = 10\nvar_c = 10\nvar_d = var_b * var_c\nvar_e = 10\nvar_f = var_d * var_e\nvar_g = 50\nvar_h = 16\nvar_i = var_g * var_h\nvar_j = var_f / var_i\nvar_k = var_a + var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "7333": {
        "category": "Geometry",
        "question_ko": "한 변이 30인 정사각형의 넓이를 구하시오.",
        "question_en": "Find the area of a square with one side equal to 30.",
        "answer_ko": "900",
        "answer_en": "900",
        "solution_abst_ko": "30 2 [OP_POW]",
        "solution_abst_en": "30 2 [OP_POW]",
        "solution_code_ko": "var_a = 30\nvar_b = 2\nvar_c = var_a ** var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 30\nvar_b = 2\nvar_c = var_a ** var_b\nprint(int(var_c))"
    },
    "7334": {
        "category": "Geometry",
        "question_ko": "미나는 한 변의 길이가 5.9센티미터(㎝)이고 다른 한 변의 길이가 3센티미터(㎝)인 직사각형 모양의 색종이를 가지고 있습니다. 이 색종이의 넓이는 몇 제곱센티미터(㎠)입니까?",
        "question_en": "Mina has a piece of rectangular-shaped colored paper with one side 5.9 centimeters (cm) long and the other side 3 centimeters (cm) long. What is the area of this piece of paper in square centimeters (cm2)?",
        "answer_ko": "17.70",
        "answer_en": "17.7",
        "solution_abst_ko": "5.9 3 [OP_MUL]",
        "solution_abst_en": "5.9 3 [OP_MUL]",
        "solution_code_ko": "var_a = 5.9\nvar_b = 3\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 5.9\nvar_b = 3\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "7335": {
        "category": "Comparison",
        "question_ko": "정국이는 6 나누기 3만큼 사과를 모았고, 윤기는 4개, 유나는 5개의 사과를 모았습니다. 누가 가진 사과가 가장 큽니까?",
        "question_en": "Jungkook collected 6 divided by 3 apples, Yoongi collected 4 apples, and Yuna collected 5 apples. Who has the most apples?",
        "answer_ko": "유나",
        "answer_en": "Yuna",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 윤기 유나 [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_FDIV] 4 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Yoongi Yuna [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_FDIV] 4 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '윤기'\nvar_c = '유나'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 6\nvar_e = 3\nvar_f = var_d // var_e\nvar_g = 4\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Yoongi'\nvar_c = 'Yuna'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 6\nvar_e = 3\nvar_f = var_d // var_e\nvar_g = 4\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "7336": {
        "category": "Correspondence",
        "question_ko": "2A3+36=269입니다. A는 얼마인가요?",
        "question_en": "2A3+36=269. What is A?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "2A3+36=269 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "2A3+36=269 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '2A3+36=269'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '2A3+36=269'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "7337": {
        "category": "Possibility",
        "question_ko": "6개의 수 3, 5, 7, 11, 13, 17 중 서로 다른 두 개의 수를 뽑아 각각 한 분수의 분자와 분모로 합니다. 만들 수 있는 분수 중 가분수는 모두 몇 개입니까?",
        "question_en": "When you try to pick two different numbers out of the six numbers 3, 5, 7, 11, 13, and 17 as the numerator and denominator of one fraction. How many improper fractions can there be?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "6 2 [OP_COMB]",
        "solution_abst_en": "6 2 [OP_COMB]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))"
    },
    "7338": {
        "category": "Arithmetic calculation",
        "question_ko": "현재 민주의 저금통에는 12000원, 시우의 저금통에는 4000원이 들어 있다. 내일부터 민주는 매일 300원씩, 시우는 매일 500원씩 저금통에 넣는다면 민주와 시우의 저금통에 들어 있는 금액이 같아지는 것은 며칠 후인가?",
        "question_en": "Currently, Minjoo's piggy bank has 12,000 won and Siwoo's piggy bank has 4,000 won. If Minjoo puts 300 won a day and Siwoo 500 won a day into their piggy banks tarting tomorrow, after how many days will the money in Minjoo's and Siwoo's piggy banks become the same?",
        "answer_ko": "40",
        "answer_en": "40",
        "solution_abst_ko": "12000 4000 [OP_SUB] 500 300 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "12000 4000 [OP_SUB] 500 300 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 12000\nvar_b = 4000\nvar_c = var_a - var_b\nvar_d = 500\nvar_e = 300\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 12000\nvar_b = 4000\nvar_c = var_a - var_b\nvar_d = 500\nvar_e = 300\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))"
    },
    "7339": {
        "category": "Comparison",
        "question_ko": "석진, 호석, 남준이는 수학 시험을 봤습니다. 석진이의 수학 점수가 호석이의 수학 점수보다 높고 남준이의 수학 점수도 호석이의 수학 점수보다 높습니다. 석진이의 수학 점수가 남준이의 수학 점수보다 낮다면 수학 점수가 가장 높은 친구는 누구인가요?",
        "question_en": "Seokjin, Hoseok, and Namjoon took a math test. Seokjin's math score is higher than Hoseok's math score, and Namjoon's math score is also higher than Hoseok's math score. If Seokjin's math score is lower than Namjoon's math score, who has the highest math score?",
        "answer_ko": "남준",
        "answer_en": "Namjoon",
        "solution_abst_ko": "[OP_LIST_SOL] 석진 호석 남준 [OP_LIST_EOL] [OP_LIST_SOL] 석진 호석 > 남준 호석 > 석진 남준 < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Seokjin Hoseok Namjoon [OP_LIST_EOL] [OP_LIST_SOL] Seokjin Hoseok > Namjoon Hoseok > Seokjin Namjoon < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '석진'\nvar_b = '호석'\nvar_c = '남준'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '석진'\nvar_e = '호석'\nvar_f = '>'\nvar_g = '남준'\nvar_h = '호석'\nvar_i = '>'\nvar_j = '석진'\nvar_k = '남준'\nvar_l = '<'\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_m = 1\nvar_n = list_c[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'Seokjin'\nvar_b = 'Hoseok'\nvar_c = 'Namjoon'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'Seokjin'\nvar_e = 'Hoseok'\nvar_f = '>'\nvar_g = 'Namjoon'\nvar_h = 'Hoseok'\nvar_i = '>'\nvar_j = 'Seokjin'\nvar_k = 'Namjoon'\nvar_l = '<'\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_m = 1\nvar_n = list_c[var_m-1]\nprint(var_n)"
    },
    "7340": {
        "category": "Arithmetic calculation",
        "question_ko": "은지는 어머니께 용돈을 받아 마트에 가서 가져간 돈의 1/4로 책을 샀습니다. 나머지 돈의 1/3로 과자를 샀더니 남은 돈이 1,600원이었다면, 은지가 처음에 가져간 돈은 얼마였는지 구하시오.",
        "question_en": "Eunji received pocket money from her mother and went to the mart to buy a book with 1/4 of the money she took. Consider 1/3 of the remaining money was used to buy snack, and then she got 1,600 won at last. Find out the amount of initial money Eunji took to the mart.",
        "answer_ko": "3200",
        "answer_en": "3200",
        "solution_abst_ko": "1600 1 1/3 [OP_SUB] [OP_DIV] 1 1/4 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "1600 1 1/3 [OP_SUB] [OP_DIV] 1 1/4 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 1600\nvar_b = 1\nvar_c = 0.3333333333333333\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 1\nvar_g = 0.25\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))",
        "solution_code_en": "var_a = 1600\nvar_b = 1\nvar_c = 0.3333333333333333\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 1\nvar_g = 0.25\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))"
    },
    "7341": {
        "category": "Geometry",
        "question_ko": "마름모의 짧은 대각선의 길이는 6센티미터(㎝)이고, 긴 대각선의 길이는 10센티미터(㎝)일 때, 이 마름모의 넓이는 얼마입니까?",
        "question_en": "If the short diagonal of a rhombus is 6 centimeters (cm) and the long diagonal is 10 centimeters (cm), what is the area of this rhombus?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "6 10 [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "6 10 [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "7342": {
        "category": "Arithmetic calculation",
        "question_ko": "세 장의 숫자카드 3, 4, 7을 사용하여 세자리 수를 만든다. 이때 4가 십의 자리에 오는 수들 중 가장 작은 값을 구하시오.(단, 숫자카드를 중복 사용할 수 없다.)",
        "question_en": "Use the three numbers written on cards: 3, 4, and 7 to create a three-digit number. At this time, find the smallest value among the numbers where 4 is in the tens. (However, you cannot use number cards repeatedly.)",
        "answer_ko": "347",
        "answer_en": "347",
        "solution_abst_ko": "[OP_LIST_SOL] 3 4 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 4 [OP_LIST_SEARCH_FIXED_DIGIT] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 3 4 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 4 [OP_LIST_SEARCH_FIXED_DIGIT] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 3\nvar_b = 4\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 10\nvar_f = 4\nlist_c = [] \nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if (i//var_e)%10 == var_f:\n        list_c.append(i)\nvar_g = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nprint(int(var_h))",
        "solution_code_en": "var_a = 3\nvar_b = 4\nvar_c = 7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 10\nvar_f = 4\nlist_c = [] \nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if (i//var_e)%10 == var_f:\n        list_c.append(i)\nvar_g = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nprint(int(var_h))"
    },
    "7343": {
        "category": "Possibility",
        "question_ko": "숫자 카드 1, 6, 8를 한 번씩 모두 사용하여 두 번째로 큰 세 자리 수와 세 번째로 작은 세 자리수의 합을 구하시오.",
        "question_en": "Using the number cards 1, 6, and 8 all once, find the sum of the second largest three-digit number and the third smallest three-digit number.",
        "answer_ko": "1434",
        "answer_en": "1434",
        "solution_abst_ko": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))"
    },
    "7344": {
        "category": "Correspondence",
        "question_ko": "현중이는 국토대장정에 참가했습니다. 현중이는 전체 거리의 1/2을 어제까지 걸었고, 오늘 남은 길이의 1/3을 걸었습니다. 오늘 이후 남은 거리가 12킬로미터(㎞)라고 할 때, 현중이가 국토대장정에서 걷는 총 거리는 몇 킬로미터(㎞)입니까?",
        "question_en": "Hyunjoong participated in the long march through national land. Hyunjoong walked 1/2 of the total distance until yesterday, and 1/3 of the remaining distance today. If the remaining distance after today is 12 kilometers (km), how many kilometers (km) does Hyunjoong walk in the long march in total?",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "12 1 1/3 [OP_SUB] [OP_DIV] 1 1/2 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "12 1 1/3 [OP_SUB] [OP_DIV] 1 1/2 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 1\nvar_c = 0.3333333333333333\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 1\nvar_g = 0.5\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))",
        "solution_code_en": "var_a = 12\nvar_b = 1\nvar_c = 0.3333333333333333\nvar_d = var_b - var_c\nvar_e = var_a / var_d\nvar_f = 1\nvar_g = 0.5\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(eval('{:.2f}'.format(round(var_i+1e-10,2)))))"
    },
    "7345": {
        "category": "Possibility",
        "question_ko": "4, 8, 1, 2 중 3개를 사용하여 십의 자리 숫자가 2인 세 번째로 작은 수는 무엇입니까?",
        "question_en": "Using 3 of 4, 8, 1, and 2, what is the third smallest number whose tens place is 2?",
        "answer_ko": "421",
        "answer_en": "421",
        "solution_abst_ko": "[OP_LIST_SOL] 4 8 1 2 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 2 [OP_LIST_SEARCH_FIXED_DIGIT] 3 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 4 8 1 2 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 2 [OP_LIST_SEARCH_FIXED_DIGIT] 3 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 4\nvar_b = 8\nvar_c = 1\nvar_d = 2\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 2\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 3\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nprint(int(var_i))",
        "solution_code_en": "var_a = 4\nvar_b = 8\nvar_c = 1\nvar_d = 2\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nvar_g = 2\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 3\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nprint(int(var_i))"
    },
    "7346": {
        "category": "Geometry",
        "question_ko": "철사를 겹치지 않게 모두 사용하여 한 변의 길이가 16센티미터(㎝)인 정오각형을 한 개 만들었습니다. 이 철사로 가장 큰 정팔각형을 만들려면 한 변의 길이를 몇 센티미터(㎝)로 해야 합니까?",
        "question_en": "Using all of the wire, not overlapping, a regular pentagon with sides of 16 centimeters (cm) was made. How many centimeters (cm) should each side be to make the largest regular octagon with this wire?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "16 5 [OP_MUL] 8 [OP_DIV]",
        "solution_abst_en": "16 5 [OP_MUL] 8 [OP_DIV]",
        "solution_code_ko": "var_a = 16\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 16\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "7347": {
        "category": "Possibility",
        "question_ko": "550이상 850이하의, 5, 2, 8, 0 중 다른 숫자 3개로 이루어진 수는 모두 몇 개입니까?",
        "question_en": "If you form a three-digit number using three different numbers among 5, 2, 8 and 0, how many numbers are there that are greater than or equal to 550 and less than or equal to 850?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 5 2 8 0 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 550 [OP_LIST_MORE] 850 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 5 2 8 0 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 550 [OP_LIST_MORE] 850 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = 8\nvar_d = 0\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 550\nlist_c = []\nfor i in list_b:\n    if i > var_f:\n        list_c.append(i)\nvar_g = 850\nlist_d = []\nfor i in list_c:\n    if i < var_g:\n        list_d.append(i)\nvar_h = len(list_d)\nprint(int(var_h))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = 8\nvar_d = 0\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 550\nlist_c = []\nfor i in list_b:\n    if i > var_f:\n        list_c.append(i)\nvar_g = 850\nlist_d = []\nfor i in list_c:\n    if i < var_g:\n        list_d.append(i)\nvar_h = len(list_d)\nprint(int(var_h))"
    },
    "7348": {
        "category": "Geometry",
        "question_ko": "길이가 8미터(m)인 철사를 이용해 정삼각형을 만들었다면, 이 삼각형의 한 변의 길이는 몇 미터(m)가 되겠습니까?",
        "question_en": "If an equilateral triangle is formed using wire that is 8 meters (m) long, how many meters (m) is the length of one side of the triangle?",
        "answer_ko": "2.67",
        "answer_en": "2.67",
        "solution_abst_ko": "8 3 [OP_DIV]",
        "solution_abst_en": "8 3 [OP_DIV]",
        "solution_code_ko": "var_a = 8\nvar_b = 3\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 8\nvar_b = 3\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "7349": {
        "category": "Arithmetic calculation",
        "question_ko": "도영이네 학교 학생 수는 1260명입니다. 도영이네 학교 학생의 7/18은 강당에 모였고 강당에 모이지 않은 학생 중 6/11은 교실에 있습니다. 교실에 있는 학생은 모두 몇 명인가요?",
        "question_en": "Doyoung's school has 1260 students. 7/18 of Doyoung's school students gathered in the auditorium, and 6/11 of the students who was not in the auditorium are in the classroom. How many students are there in the classroom?",
        "answer_ko": "420",
        "answer_en": "420",
        "solution_abst_ko": "1260 1 7/18 [OP_SUB] [OP_MUL] 6/11 [OP_MUL]",
        "solution_abst_en": "1260 1 7/18 [OP_SUB] [OP_MUL] 6/11 [OP_MUL]",
        "solution_code_ko": "var_a = 1260\nvar_b = 1\nvar_c = 0.3888888888888889\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 0.5454545454545454\nvar_g = var_e * var_f\nprint(int(eval('{:.2f}'.format(round(var_g+1e-10,2)))))",
        "solution_code_en": "var_a = 1260\nvar_b = 1\nvar_c = 0.3888888888888889\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 0.5454545454545454\nvar_g = var_e * var_f\nprint(int(eval('{:.2f}'.format(round(var_g+1e-10,2)))))"
    },
    "7350": {
        "category": "Comparison",
        "question_ko": "밑변의 길이가 10센티미터(㎝), 높이가 11센티미터(㎝)인 삼각형, 한 변의 길이가 8센티미터(㎝)인 정사각형, 지름이 8센티미터(㎝)인 원이 있습니다. 원주율을 3.1로 계산할 때 넓이가 가장 넓은 도형은 어느 것입니까?",
        "question_en": "There are a triangle with a length of a base of 10 centimeters (cm) and a height of 11 centimeters (cm), a square with a side of 8 centimeters (cm), and a circle with a diameter of 8 centimeters (cm). Which figure has the largest area when the pi of a circle is calculated as 3.1?",
        "answer_ko": "정사각형",
        "answer_en": "square",
        "solution_abst_ko": "[OP_LIST_SOL] 삼각형 정사각형 원 [OP_LIST_EOL] [OP_LIST_SOL] 10 11 [OP_MUL] 2 [OP_DIV] 8 2 [OP_POW] 8 2 [OP_DIV] 2 [OP_POW] 3.1 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] triangle square circle [OP_LIST_EOL] [OP_LIST_SOL] 10 11 [OP_MUL] 2 [OP_DIV] 8 2 [OP_POW] 8 2 [OP_DIV] 2 [OP_POW] 3.1 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '삼각형'\nvar_b = '정사각형'\nvar_c = '원'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 10\nvar_e = 11\nvar_f = var_d * var_e\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = 8\nvar_j = 2\nvar_k = var_i ** var_j\nvar_l = 8\nvar_m = 2\nvar_n = var_l / var_m\nvar_o = 2\nvar_p = var_n ** var_o\nvar_q = 3.1\nvar_r = var_p * var_q\nlist_b= []\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nlist_b.reverse()\nvar_s = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_t = list_c[-var_s]\nvar_u = list_b.index(var_t)+1\nvar_v = list_a[var_u-1]\nprint(var_v)",
        "solution_code_en": "var_a = 'triangle'\nvar_b = 'square'\nvar_c = 'circle'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 10\nvar_e = 11\nvar_f = var_d * var_e\nvar_g = 2\nvar_h = var_f / var_g\nvar_i = 8\nvar_j = 2\nvar_k = var_i ** var_j\nvar_l = 8\nvar_m = 2\nvar_n = var_l / var_m\nvar_o = 2\nvar_p = var_n ** var_o\nvar_q = 3.1\nvar_r = var_p * var_q\nlist_b= []\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nlist_b.reverse()\nvar_s = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_t = list_c[-var_s]\nvar_u = list_b.index(var_t)+1\nvar_v = list_a[var_u-1]\nprint(var_v)"
    },
    "7351": {
        "category": "Geometry",
        "question_ko": "정육면체의 겉넓이가 864제곱센티미터(㎠)일 때, 한 변의 길이는 몇 센티미터(㎝)인지 구하세요.",
        "question_en": "If the surface area of the cube is 864 square centimeters (cm2), find how many centimeters (cm) are the length of one side of the cube.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "864 6 [OP_DIV] 1/2 [OP_POW]",
        "solution_abst_en": "864 6 [OP_DIV] 1/2 [OP_POW]",
        "solution_code_ko": "var_a = 864\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 864\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nprint(int(var_e))"
    },
    "7352": {
        "category": "Geometry",
        "question_ko": "크기가 같은 구슬을 빈틈없이 규칙적으로 늘어놓아 둘레에 놓인 구슬의 개수가 36개인 정사각형을 만들었습니다. 가장 바깥쪽의 한 변에 놓인 구슬의 개수는 몇 개입니까?",
        "question_en": "Marbles of the same size are arranged in a regular arrangement without gaps to form a square with 36 marbles around it. How many marbles are on the outermost of one side?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "36 4 [OP_DIV] 1 [OP_ADD]",
        "solution_abst_en": "36 4 [OP_DIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 36\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 36\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7353": {
        "category": "Arithmetic calculation",
        "question_ko": "집에 알루미늄배트가 32개 있습니다. 나무배트보다 알루미늄배트가 5개 적고, 글러브가 알루미눔배트보다 3개 많습니다. 집에있는 나무배트, 알루미눔배트, 글러브는 모두 몇 개입니까?",
        "question_en": "You have 32 aluminum bats at home. There are 5 fewer aluminum bats than wooden bats, and 3 more gloves than aluminum bats. How many wooden bats, aluminum bats and gloves do you have at home in total?",
        "answer_ko": "104",
        "answer_en": "104",
        "solution_abst_ko": "32 32 5 [OP_ADD] [OP_ADD] 32 3 [OP_ADD] [OP_ADD]",
        "solution_abst_en": "32 32 5 [OP_ADD] [OP_ADD] 32 3 [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 32\nvar_b = 32\nvar_c = 5\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nvar_f = 32\nvar_g = 3\nvar_h = var_f + var_g\nvar_i = var_e + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 32\nvar_b = 32\nvar_c = 5\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nvar_f = 32\nvar_g = 3\nvar_h = var_f + var_g\nvar_i = var_e + var_h\nprint(int(var_i))"
    },
    "7354": {
        "category": "Correspondence",
        "question_ko": "5와 4/9를 7로 나눈 값이 어떤 수에 5를 곱한 값과 같다고 한다. 어떤 수가 얼마인지 소수 2번째 자리까지 나타내어 보세요.",
        "question_en": "It is said that dividing 5 and 4/9 by 7 is equal to multiplying the number by 5. Find the number rounding to two decimal places.",
        "answer_ko": "0.16",
        "answer_en": "0.16",
        "solution_abst_ko": "5 4/9 [OP_ADD] 7 [OP_DIV] 5 [OP_DIV]",
        "solution_abst_en": "5 4/9 [OP_ADD] 7 [OP_DIV] 5 [OP_DIV]",
        "solution_code_ko": "var_a = 5\nvar_b = 0.4444444444444444\nvar_c = var_a + var_b\nvar_d = 7\nvar_e = var_c / var_d\nvar_f = 5\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 5\nvar_b = 0.4444444444444444\nvar_c = var_a + var_b\nvar_d = 7\nvar_e = var_c / var_d\nvar_f = 5\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "7355": {
        "category": "Arithmetic calculation",
        "question_ko": "올해 유정이는 12살이고 어머니는 42살입니다. 몇 년 전에 어머니 나이가 유정이 나이의 4배였습니까?",
        "question_en": "This year, Yujeong is 12 years old and her mother is 42 years old. In what year was her mother's age 4 times her age?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "12 4 [OP_MUL] 42 [OP_SUB] 4 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "12 4 [OP_MUL] 42 [OP_SUB] 4 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 42\nvar_e = var_c - var_d\nvar_f = 4\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 12\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 42\nvar_e = var_c - var_d\nvar_f = 4\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "7356": {
        "category": "Arithmetic calculation",
        "question_ko": "호석이는 마트에서 (가) 물건을 사면서 1,000원짜리 지폐 7장, 100원짜리 동전 4개, 10원짜리 동전 5개를 냈습니다. 호석이가 마트에서 산 (가) 물건의 값은 얼마입니까?",
        "question_en": "Hoseok paid 7 1,000 won bills, 4 100 won coins, and 5 10 won coins while shopping item (a) at the mart. What is the price of the item (a) that Hoseok bought at the mart?",
        "answer_ko": "7450",
        "answer_en": "7450",
        "solution_abst_ko": "1000 7 [OP_MUL] 100 4 [OP_MUL] [OP_ADD] 10 5 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "1000 7 [OP_MUL] 100 4 [OP_MUL] [OP_ADD] 10 5 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 1000\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = 4\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 10\nvar_i = 5\nvar_j = var_h * var_i\nvar_k = var_g + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 1000\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 100\nvar_e = 4\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 10\nvar_i = 5\nvar_j = var_h * var_i\nvar_k = var_g + var_j\nprint(int(var_k))"
    },
    "7357": {
        "category": "Correspondence",
        "question_ko": "82.04를 어떤 숫자로 나누면 28이 됩니다. 어떤 숫자의 값은 얼마인가요?",
        "question_en": "Dividing 82.04 by a certain number results in 28. What is the value of the certain number?",
        "answer_ko": "2.93",
        "answer_en": "2.93",
        "solution_abst_ko": "1 28 82.04 [OP_DIV] [OP_DIV]",
        "solution_abst_en": "1 28 82.04 [OP_DIV] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 28\nvar_c = 82.04\nvar_d = var_b / var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 28\nvar_c = 82.04\nvar_d = var_b / var_c\nvar_e = var_a / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "7358": {
        "category": "Arithmetic calculation",
        "question_ko": "한별이와 한솔이의 몸무게를 더하면 88킬로그램(㎏)이고, 한별이가 한솔이보다 4킬로그램(㎏) 더 나간다면 한솔이의 몸무게는 몇 킬로그램(㎏)인지 구하시오.",
        "question_en": "If the weights of Hanbyul and Hansol are added together, it is 88 kilograms (kg), and if Hanbyul weighs 4 kilograms (kg) more than Hansol, find out how many kilograms (kg) Hansol weighs.",
        "answer_ko": "42",
        "answer_en": "42",
        "solution_abst_ko": "88 4 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "88 4 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 88\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 88\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "7359": {
        "category": "Correspondence",
        "question_ko": "36에 어떤 수를 더해야 할 것을 잘못하여 63에 어떤 수를 뺐더니 70이 되었습니다. 바르게 계산하면 얼마인지 구하시오.",
        "question_en": "I had to add a number to 36 but I made a mistake and subtracted a number from 63 and it became 70. Find out how much it is if you calculate it correctly.",
        "answer_ko": "29",
        "answer_en": "29",
        "solution_abst_ko": "36 63 70 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "36 63 70 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 36\nvar_b = 63\nvar_c = 70\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 36\nvar_b = 63\nvar_c = 70\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "7360": {
        "category": "Comparison",
        "question_ko": "(가), (나), (다), (라), (마), (바), (사) 꽃을 순서대로 심었을 때, 5번째로 심은 꽃의 이름은 무엇입니까?",
        "question_en": "When 7 flowers (a), (b), (c), (d), (e), (f), and (g) were planted in order, what is the name of the 5th flower planted?",
        "answer_ko": "(마)",
        "answer_en": "(e)",
        "solution_abst_ko": "[OP_LIST_SOL] (가) (나) (다) (라) (마) (바) (사) [OP_LIST_EOL] 5 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] (a) (b) (c) (d) (e) (f) (g) [OP_LIST_EOL] 5 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '(가)'\nvar_b = '(나)'\nvar_c = '(다)'\nvar_d = '(라)'\nvar_e = '(마)'\nvar_f = '(바)'\nvar_g = '(사)'\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h = 5\nvar_i = list_a[var_h-1]\nprint(var_i)",
        "solution_code_en": "var_a = '(a)'\nvar_b = '(b)'\nvar_c = '(c)'\nvar_d = '(d)'\nvar_e = '(e)'\nvar_f = '(f)'\nvar_g = '(g)'\nlist_a= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_h = 5\nvar_i = list_a[var_h-1]\nprint(var_i)"
    },
    "7361": {
        "category": "Correspondence",
        "question_ko": "다섯 자리 수 A835B은 12로 나누어 떨어진다. A, B에 알맞은 숫자를 넣어 만든 다섯 자리 수 중에서 가장 큰 수와 가장 작은 수와의 차를 구하여라.",
        "question_en": "The five-digit number A835B is divisible by 12. Find the difference between the largest and the smallest five-digit number if numbers are put in A and B.",
        "answer_ko": "69996",
        "answer_en": "69996",
        "solution_abst_ko": "A835B [OP_GEN_POSSIBLE_LIST] 12 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "A835B [OP_GEN_POSSIBLE_LIST] 12 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 'A835B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 12\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_d = list_c[-var_c]\nvar_e = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_f = list_d[var_e-1]\nvar_g = var_d - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 'A835B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 12\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_d = list_c[-var_c]\nvar_e = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_f = list_d[var_e-1]\nvar_g = var_d - var_f\nprint(int(var_g))"
    },
    "7362": {
        "category": "Comparison",
        "question_ko": "석진이와 태형이는 도화지를 각각 10장씩 가지고 있었습니다. 석진이는 5장을 사용했고 태형이는 4장을 사용했습니다. 남은 도화지는 누가 더 많습니까?",
        "question_en": "Seokjin and Taehyung each had 10 pieces of drawing paper. Seokjin used 5 pieces and Taehyung used 4 pieces. Who has more drawing paper left?",
        "answer_ko": "태형",
        "answer_en": "Taehyung",
        "solution_abst_ko": "[OP_LIST_SOL] 석진 태형 [OP_LIST_EOL] [OP_LIST_SOL] 10 5 [OP_SUB] 10 4 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Seokjin Taehyung [OP_LIST_EOL] [OP_LIST_SOL] 10 5 [OP_SUB] 10 4 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '석진'\nvar_b = '태형'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10\nvar_d = 5\nvar_e = var_c - var_d\nvar_f = 10\nvar_g = 4\nvar_h = var_f - var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Seokjin'\nvar_b = 'Taehyung'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 10\nvar_d = 5\nvar_e = var_c - var_d\nvar_f = 10\nvar_g = 4\nvar_h = var_f - var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "7363": {
        "category": "Comparison",
        "question_ko": "농장에서 집까지의 거리는 396미터(m)이고, 농장에서 밭까지의 거리는 0.389킬로미터(㎞)입니다. 집과 밭 중 농장과 더 가까운 곳은?",
        "question_en": "The distance from the farm to the house is 396 meters (m), and the distance from the farm to the field is 0.389 kilometers (km). Which is closer to the farm between the house and the field?",
        "answer_ko": "밭",
        "answer_en": "field",
        "solution_abst_ko": "[OP_LIST_SOL] 집 밭 [OP_LIST_EOL] [OP_LIST_SOL] 396 0.389 1000 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] house field [OP_LIST_EOL] [OP_LIST_SOL] 396 0.389 1000 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '집'\nvar_b = '밭'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 396\nvar_d = 0.389\nvar_e = 1000\nvar_f = var_d * var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'house'\nvar_b = 'field'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 396\nvar_d = 0.389\nvar_e = 1000\nvar_f = var_d * var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "7364": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 10, 11, 12, 13이 있습니다. 그 중에서 2번째로 큰 수를 가장 작은 수로 나눈 나머지는 얼마입니까?",
        "question_en": "You are given four numbers: 10, 11, 12, and 13. What is the remainder when the second largest number is divided by the smallest number?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 2 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MOD]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 2 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MOD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f % var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f % var_h\nprint(int(var_i))"
    },
    "7365": {
        "category": "Geometry",
        "question_ko": "정사각형 모양 운동장에서 그릴 수 있는 가장 큰 원을 그렸다. 이 운동장의 넓이가 400제곱미터(㎡)이고, 원주율을 3.1라면, 원의 넓이는 얼마입니까?",
        "question_en": "I drew the largest circle that can be drawn on a square-shaped playground. Assuming pi as 3.1, if the area of this field is 400 square meters (m2), what is the area of the circle?",
        "answer_ko": "310",
        "answer_en": "310",
        "solution_abst_ko": "3.1 400 1/2 [OP_POW] 2 [OP_DIV] 2 [OP_POW] [OP_MUL]",
        "solution_abst_en": "3.1 400 1/2 [OP_POW] 2 [OP_DIV] 2 [OP_POW] [OP_MUL]",
        "solution_code_ko": "var_a = 3.1\nvar_b = 400\nvar_c = 0.5\nvar_d = var_b ** var_c\nvar_e = 2\nvar_f = var_d / var_e\nvar_g = 2\nvar_h = var_f ** var_g\nvar_i = var_a * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 3.1\nvar_b = 400\nvar_c = 0.5\nvar_d = var_b ** var_c\nvar_e = 2\nvar_f = var_d / var_e\nvar_g = 2\nvar_h = var_f ** var_g\nvar_i = var_a * var_h\nprint(int(var_i))"
    },
    "7366": {
        "category": "Comparison",
        "question_ko": "울타리 안에 말, 소, 돼지, 양, 토끼, 다람쥐 순서로 들어갔습니다. 4번째에 들어간 동물은 무엇입니까?",
        "question_en": "Horses, Cows, Pigs, Sheep, Rabbits, and Squirrels entered the fence in that order. What's the 4th animal?",
        "answer_ko": "양",
        "answer_en": "Sheep",
        "solution_abst_ko": "[OP_LIST_SOL] 말 소 돼지 양 토끼 다람쥐 [OP_LIST_EOL] 4 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Horse Cow Pig Sheep Rabbit Squirrel [OP_LIST_EOL] 4 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '말'\nvar_b = '소'\nvar_c = '돼지'\nvar_d = '양'\nvar_e = '토끼'\nvar_f = '다람쥐'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 4\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Horse'\nvar_b = 'Cow'\nvar_c = 'Pig'\nvar_d = 'Sheep'\nvar_e = 'Rabbit'\nvar_f = 'Squirrel'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 4\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "7367": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이가 나눗셈을 하였더니 몫은 29이고 나머지는 77가 나왔습니다. 하지만 이는 나누는 수 59의 십의 자리 숫자와 일의 자리 숫자를 바꾸어 잘못 보고 계산한 결과였습니다. 바르게 계산한 몫과 나머지의 합을 구하시오.",
        "question_en": "When Jungkook divided, the quotient was 29 and the remainder was 77. However, this was the result of misreading and calculating by changing the tens and ones digits of the correct divisor 59. Find the sum of the correctly calculated quotient and remainder.",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "95 29 [OP_MUL] 77 [OP_ADD] 59 [OP_FDIV] 95 29 [OP_MUL] 77 [OP_ADD] 59 [OP_MOD] [OP_ADD]",
        "solution_abst_en": "95 29 [OP_MUL] 77 [OP_ADD] 59 [OP_FDIV] 95 29 [OP_MUL] 77 [OP_ADD] 59 [OP_MOD] [OP_ADD]",
        "solution_code_ko": "var_a = 95\nvar_b = 29\nvar_c = var_a * var_b\nvar_d = 77\nvar_e = var_c + var_d\nvar_f = 59\nvar_g = var_e // var_f\nvar_h = 95\nvar_i = 29\nvar_j = var_h * var_i\nvar_k = 77\nvar_l = var_j + var_k\nvar_m = 59\nvar_n = var_l % var_m\nvar_o = var_g + var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 95\nvar_b = 29\nvar_c = var_a * var_b\nvar_d = 77\nvar_e = var_c + var_d\nvar_f = 59\nvar_g = var_e // var_f\nvar_h = 95\nvar_i = 29\nvar_j = var_h * var_i\nvar_k = 77\nvar_l = var_j + var_k\nvar_m = 59\nvar_n = var_l % var_m\nvar_o = var_g + var_n\nprint(int(var_o))"
    },
    "7368": {
        "category": "Geometry",
        "question_ko": "직사각형 모양의 지폐의 둘레는 28 센티미터(㎝) 이고, 가로는 6센티미터(㎝) 입니다. 이 지폐의 넓이를 구하시오.",
        "question_en": "A rectangular bill is 28 centimeters (cm) in perimeter and 6 centimeters (cm) in width. Find the area of this bill.",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "28 2 [OP_DIV] 6 [OP_SUB] 6 [OP_MUL]",
        "solution_abst_en": "28 2 [OP_DIV] 6 [OP_SUB] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 28\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c - var_d\nvar_f = 6\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 28\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c - var_d\nvar_f = 6\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "7369": {
        "category": "Possibility",
        "question_ko": "3, 9, 5, 8만을 가지고 숫자를 만드려고 합니다. 각 숫자는 한번씩만 사용할 수 있을 때, 가장 큰 수와, 남은 두 수를 더하면 얼마입니까?",
        "question_en": "I'm trying to make a number with only 3, 9, 5, and 8. If each number can only be used once, what is the sum of largest two-digit number and the remaining two numbers?",
        "answer_ko": "106",
        "answer_en": "106",
        "solution_abst_ko": "[OP_LIST_SOL] 3 9 5 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_NUM2LIST] [OP_LIST_SUM] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 3 9 5 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_NUM2LIST] [OP_LIST_SUM] [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 9\nvar_c = 5\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nlist_e = []\nvar_i = int(var_i)\nwhile var_i//10 > 0:\n    list_e.append(var_i%10)\n    var_i = var_i//10\nlist_e.append(var_i%10)\nlist_e = list_e[::-1]\nlist_e = [float(i) for i in list_e]\nvar_j = sum(list_e)\nvar_k = var_g + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 3\nvar_b = 9\nvar_c = 5\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nlist_e = []\nvar_i = int(var_i)\nwhile var_i//10 > 0:\n    list_e.append(var_i%10)\n    var_i = var_i//10\nlist_e.append(var_i%10)\nlist_e = list_e[::-1]\nlist_e = [float(i) for i in list_e]\nvar_j = sum(list_e)\nvar_k = var_g + var_j\nprint(int(var_k))"
    },
    "7370": {
        "category": "Possibility",
        "question_ko": "숫자 자석 세 개를 한 번씩 모두 사용하여 가장 큰 세 자리수와 세 번째로 큰 세 자리수의 차를 구하고자 합니다. 1, 6, 8이 그려진 자석이 있을 때, 답은 얼마입니까?",
        "question_en": "We want to find the difference between the largest three-digit number and the third largest three-digit number using all three number magnets once. Given a magnet with 1, 6, and 8 on it, what is the answer?",
        "answer_ko": "180",
        "answer_en": "180",
        "solution_abst_ko": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 3 [OP_LIST_MAX] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 3 [OP_LIST_MAX] [OP_SUB]",
        "solution_code_ko": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[-var_g]\nvar_i = var_f - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = 3\nlist_d=list_b.copy()\nlist_d.sort()\nvar_h = list_d[-var_g]\nvar_i = var_f - var_h\nprint(int(var_i))"
    },
    "7371": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 10, 11, 12, 13이 있습니다. 그 중에서 3번째로 작은 수와 2번째로 작은 수로 나눈 나머지는 얼마입니까?",
        "question_en": "There are four numbers 10, 11, 12, and 13. What is the remainder when the 3rd smallest number is divided by and the 2nd smallest number?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 3 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_MOD]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 3 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_MOD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f % var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f % var_h\nprint(int(var_i))"
    },
    "7372": {
        "category": "Possibility",
        "question_ko": "1부터 30까지 자연수를 쓰려고 합니다. 숫자 2는 모두 몇 번 써야 합니까?",
        "question_en": "You are trying to write natural numbers from 1 to 30. How many times should the number 2 be written in all?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "1 30 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 2 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 30 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 2 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 30\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 2\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 30\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 2\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))"
    },
    "7373": {
        "category": "Geometry",
        "question_ko": "정팔면체에서 모서리는 모두 몇 개 일까요?",
        "question_en": "How many edges are there in a regular octahedron?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "12",
        "solution_abst_en": "12",
        "solution_code_ko": "var_a = 12\nprint(int(var_a))",
        "solution_code_en": "var_a = 12\nprint(int(var_a))"
    },
    "7374": {
        "category": "Possibility",
        "question_ko": "어떤 직육면체가 있습니다. 이 직육면체의 한 꼭짓점에서 만나는 면의 개수를 구하시오.",
        "question_en": "There is a cuboid. Find the number of faces that meet at one vertex of this cuboid.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "3",
        "solution_abst_en": "3",
        "solution_code_ko": "var_a = 3\nprint(int(var_a))",
        "solution_code_en": "var_a = 3\nprint(int(var_a))"
    },
    "7375": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 10, 11, 12, 13이 있습니다. 그 중에서 2번째로 큰 수와 가장 작은 수로 나눈 몫은 얼마입니까?",
        "question_en": "There are four numbers 10, 11, 12, and 13. What is the quotient of the second largest number divided by the smallest number?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 2 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_FDIV]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 2 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_FDIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f // var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f // var_h\nprint(int(var_i))"
    },
    "7376": {
        "category": "Geometry",
        "question_ko": "길이가 32센티미터(㎝) 인 끈으로 네변의 길이가 모두 같은 사각형을 만들었습니다. 만든 사각형의 넓이는 몇 제곱센티미터(㎠) 입니까?",
        "question_en": "A 32 centimeters (cm) long string was used to make a rectangle with the same length of all four sides. What is the area of the rectangle you created in square centimeters (cm2)?",
        "answer_ko": "64",
        "answer_en": "64",
        "solution_abst_ko": "32 4 [OP_DIV] 2 [OP_POW]",
        "solution_abst_en": "32 4 [OP_DIV] 2 [OP_POW]",
        "solution_code_ko": "var_a = 32\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 32\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint(int(var_e))"
    },
    "7377": {
        "category": "Comparison",
        "question_ko": "현성이는 두 자리 수끼리의 곱셈을 한 결과, 1485를 얻었습니다. 하지만 이는 곱하는 수 중 하나의 십의 자리 숫자 5를 3으로 잘못 보고 계산한 것입니다. 바르게 계산한 값이 2385일 때, 2개의 두 자리 수 중 더 큰 수를 쓰시오.",
        "question_en": "As a result of multiplying two-digit numbers, Hyeonseong got 1485. However, this is a miscalculation of the number 5 in the tens place as 3. If the correctly calculated value is 2385, write the larger number among the two-digit number.",
        "answer_ko": "53",
        "answer_en": "53",
        "solution_abst_ko": "[OP_LIST_SOL] 1485 2385 [OP_SUB] 3 5 [OP_SUB] 10 [OP_MUL] [OP_DIV] 2385 1485 2385 [OP_SUB] 3 5 [OP_SUB] 10 [OP_MUL] [OP_DIV] [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1485 2385 [OP_SUB] 3 5 [OP_SUB] 10 [OP_MUL] [OP_DIV] 2385 1485 2385 [OP_SUB] 3 5 [OP_SUB] 10 [OP_MUL] [OP_DIV] [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1485\nvar_b = 2385\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = 5\nvar_f = var_d - var_e\nvar_g = 10\nvar_h = var_f * var_g\nvar_i = var_c / var_h\nvar_j = 2385\nvar_k = 1485\nvar_l = 2385\nvar_m = var_k - var_l\nvar_n = 3\nvar_o = 5\nvar_p = var_n - var_o\nvar_q = 10\nvar_r = var_p * var_q\nvar_s = var_m / var_r\nvar_t = var_j / var_s\nlist_a= []\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_a.append(var_t)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nlist_a.reverse()\nvar_u = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_v = list_b[-var_u]\nprint(int(var_v))",
        "solution_code_en": "var_a = 1485\nvar_b = 2385\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = 5\nvar_f = var_d - var_e\nvar_g = 10\nvar_h = var_f * var_g\nvar_i = var_c / var_h\nvar_j = 2385\nvar_k = 1485\nvar_l = 2385\nvar_m = var_k - var_l\nvar_n = 3\nvar_o = 5\nvar_p = var_n - var_o\nvar_q = 10\nvar_r = var_p * var_q\nvar_s = var_m / var_r\nvar_t = var_j / var_s\nlist_a= []\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_a.append(var_t)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nlist_a.reverse()\nvar_u = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_v = list_b[-var_u]\nprint(int(var_v))"
    },
    "7378": {
        "category": "Arithmetic calculation",
        "question_ko": "15의 배수이면서 6의 배수인 수 중에 200보다 작은 수는 모두 몇개입니까?",
        "question_en": "How numbers are less than 200, which are also multiples of 15 and 6?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "1 200 1 [OP_LIST_ARANGE] 6 [OP_LIST_DIVISIBLE] 15 [OP_LIST_DIVISIBLE] 200 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "1 200 1 [OP_LIST_ARANGE] 6 [OP_LIST_DIVISIBLE] 15 [OP_LIST_DIVISIBLE] 200 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 200\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 15\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 200\nlist_d = []\nfor i in list_c:\n    if i < var_f:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 200\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 15\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 200\nlist_d = []\nfor i in list_c:\n    if i < var_f:\n        list_d.append(i)\nvar_g = len(list_d)\nprint(int(var_g))"
    },
    "7379": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 260미터(m)인 도로의 양쪽에 4미터(m) 간격으로 가로등을 세우려고 합니다. 처음과 끝에도 가로등을 세운다고 할 때 필요한 가로등은 모두 몇 개인지 구해 보시오.",
        "question_en": "You want to set up street lights at intervals of 4 meters (m) on both sides of a road that is 260 meters (m) long. If you put up street lights at the beginning and at the end as well, find out how many street lights are needed.",
        "answer_ko": "132",
        "answer_en": "132",
        "solution_abst_ko": "260 4 [OP_DIV] 1 [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "260 4 [OP_DIV] 1 [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 260\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 260\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "7380": {
        "category": "Correspondence",
        "question_ko": "네 자리 수 A12B는 8의 배수이고 3으로 나누었을 떄 나머지가 1이다. 가능한 B들의 합을 구하시오.",
        "question_en": "The four-digit number A12B is a multiple of 8 and when divided by 3, the remainder is 1. Find the sum of the possible B's.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "A12B [OP_GEN_POSSIBLE_LIST] 8 [OP_LIST_DIVISIBLE] 3 1 [OP_LIST_DIVIDE_AND_REMAIN] A12B B [OP_LIST_FIND_UNK] [OP_LIST_SUM]",
        "solution_abst_en": "A12B [OP_GEN_POSSIBLE_LIST] 8 [OP_LIST_DIVISIBLE] 3 1 [OP_LIST_DIVIDE_AND_REMAIN] A12B B [OP_LIST_FIND_UNK] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 'A12B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 8\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 3\nvar_d = 1\nlist_c = [] \nvar_c = int(var_c)\nvar_d = int(var_d)\nif var_d < 0:\n    var_d = var_d + var_c\nfor i in list_b:\n    i = int(i)\n    if i%var_c == var_d:\n        list_c.append(i)\nvar_e = 'A12B'\nvar_f = 'B'\nvar_e = str(var_e)\nvar_f = str(var_f)\nunk_idx = var_e.index(var_f)\nlist_d = []\nfor elem in list_c:\n    elem = str(elem)\n    list_d.append(int(elem[unk_idx]))\nlist_d = list(set(list_d))\nlist_d = [float(i) for i in list_d]\nvar_g = sum(list_d)\nprint(int(var_g))",
        "solution_code_en": "var_a = 'A12B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 8\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 3\nvar_d = 1\nlist_c = [] \nvar_c = int(var_c)\nvar_d = int(var_d)\nif var_d < 0:\n    var_d = var_d + var_c\nfor i in list_b:\n    i = int(i)\n    if i%var_c == var_d:\n        list_c.append(i)\nvar_e = 'A12B'\nvar_f = 'B'\nvar_e = str(var_e)\nvar_f = str(var_f)\nunk_idx = var_e.index(var_f)\nlist_d = []\nfor elem in list_c:\n    elem = str(elem)\n    list_d.append(int(elem[unk_idx]))\nlist_d = list(set(list_d))\nlist_d = [float(i) for i in list_d]\nvar_g = sum(list_d)\nprint(int(var_g))"
    },
    "7381": {
        "category": "Geometry",
        "question_ko": "수지는 한 변의 길이가 8.5미터(m)인 정사각형 모양의 종이를 3.2장 갖고 있습니다. 이 종이를 일렬로 붙일 때 얻을 수 있는 넓이는 얼마입니까?",
        "question_en": "Suzy has 3.2 sheets of square paper with sides measuring 8.5 meters (m). How big could this area get by gluing these papers in a row?",
        "answer_ko": "231.20",
        "answer_en": "231.2",
        "solution_abst_ko": "8.5 2 [OP_POW] 3.2 [OP_MUL]",
        "solution_abst_en": "8.5 2 [OP_POW] 3.2 [OP_MUL]",
        "solution_code_ko": "var_a = 8.5\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 3.2\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 8.5\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 3.2\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "7382": {
        "category": "Arithmetic calculation",
        "question_ko": "형준이의 번호는 010-3380-2798이다. 형준이에게 전화를 걸려면 3을 몇 번 눌러야하는가?",
        "question_en": "Hyungjun's number is 010-3380-2798. How many times do you have to press 3 to call Hyeongjun?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 0 3 3 8 0 2 7 9 8 [OP_LIST_EOL] 3 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 0 3 3 8 0 2 7 9 8 [OP_LIST_EOL] 3 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 0\nvar_d = 3\nvar_e = 3\nvar_f = 8\nvar_g = 0\nvar_h = 2\nvar_i = 7\nvar_j = 9\nvar_k = 8\nlist_a= []\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_a.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_a.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_l = 3\nvar_m = 0\nvar_l = int(var_l)\nfor i in list_a:\n    i = int(i)\n    if i == var_l:\n        var_m = var_m + 1\nprint(int(var_m))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 0\nvar_d = 3\nvar_e = 3\nvar_f = 8\nvar_g = 0\nvar_h = 2\nvar_i = 7\nvar_j = 9\nvar_k = 8\nlist_a= []\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_a.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_a.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_l = 3\nvar_m = 0\nvar_l = int(var_l)\nfor i in list_a:\n    i = int(i)\n    if i == var_l:\n        var_m = var_m + 1\nprint(int(var_m))"
    },
    "7383": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 10, 11, 12, 13이 있습니다. 그 중에서 2번째로 큰 수와 가장 작은 수의 차는 얼마입니까?",
        "question_en": "There are four numbers 10, 11, 12, and 13. What do you get for the second largest number minus the smallest number?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 2 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 2 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f - var_h\nprint(int(var_i))"
    },
    "7384": {
        "category": "Arithmetic calculation",
        "question_ko": "4000킬로그램(㎏)의 물이 들어가는 물탱크에 1시간에 200킬로그램(㎏)씩 나오는 수도를 틀어 놓았습니다. 하루 동안 빈 물탱크에 수도를 틀어 놓았다면, 흘러 넘친 물의 양은 몇 킬로그램(㎏)인지 구하시오.",
        "question_en": "The water supply was turned on at a rate of 200 kilograms (kg) per hour in a water tank that can contain 4,000 kilograms (kg) of water. If you left the water running on this empty water tank for one day, find how many kilograms (kg) of water overflowed.",
        "answer_ko": "800",
        "answer_en": "800",
        "solution_abst_ko": "200 24 [OP_MUL] 4000 [OP_SUB] [OP_ABS]",
        "solution_abst_en": "200 24 [OP_MUL] 4000 [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 200\nvar_b = 24\nvar_c = var_a * var_b\nvar_d = 4000\nvar_e = var_c - var_d\nvar_f = abs(var_e)\nprint(int(var_f))",
        "solution_code_en": "var_a = 200\nvar_b = 24\nvar_c = var_a * var_b\nvar_d = 4000\nvar_e = var_c - var_d\nvar_f = abs(var_e)\nprint(int(var_f))"
    },
    "7385": {
        "category": "Comparison",
        "question_ko": "길이가 3미터(m) 48센티미터(㎝)인 끈을 두 도막으로 잘랐더니 두 도막의 길이의 차가 72센티미터(㎝)였습니다. 이때 길이가 긴 끈의 길이는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "When a string measuring 3 meters (m) and 48 centimeters (cm) in length was cut into two parts, the difference between the lengths of the two parts was 72 centimeters (cm). Find the length of the longer string in centimeters (cm).",
        "answer_ko": "210",
        "answer_en": "210",
        "solution_abst_ko": "3 100 [OP_MUL] 48 [OP_ADD] 72 [OP_SUB] 2 [OP_DIV] 72 [OP_ADD]",
        "solution_abst_en": "3 100 [OP_MUL] 48 [OP_ADD] 72 [OP_SUB] 2 [OP_DIV] 72 [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 48\nvar_e = var_c + var_d\nvar_f = 72\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nvar_j = 72\nvar_k = var_i + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 3\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 48\nvar_e = var_c + var_d\nvar_f = 72\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nvar_j = 72\nvar_k = var_i + var_j\nprint(int(var_k))"
    },
    "7386": {
        "category": "Arithmetic calculation",
        "question_ko": "현재 기차에 63명이 타고 있습니다. 처음 출발할 때 기차에 탑승한 인원이 78명이고 이후 27명이 내렸습니다. 기차에 추가로 탄 사람은 몇 명입니까?",
        "question_en": "There are currently 63 people on the train. 78 people were on the train when it first departed, and 27 people got off after that. How many extra people got on the train?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "63 27 [OP_ADD] 78 [OP_SUB]",
        "solution_abst_en": "63 27 [OP_ADD] 78 [OP_SUB]",
        "solution_code_ko": "var_a = 63\nvar_b = 27\nvar_c = var_a + var_b\nvar_d = 78\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 63\nvar_b = 27\nvar_c = var_a + var_b\nvar_d = 78\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "7387": {
        "category": "Possibility",
        "question_ko": "하연이는 숫자 자석 0, 1, 2를 가지고 있다. 가지고 있는 숫자 자석들을 이용하여 만들 수 있는 두 자리 자연수의 개수는 몇 개인가?",
        "question_en": "Hayeon has magnets written 0, 1 and 2 respectively. How many two-digit natural numbers can she make using that number magnets?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "7388": {
        "category": "Comparison",
        "question_ko": "5개의 수 1/10, 8, 0.9, 7/10, 5가 있습니다. 이 중에서 1보다 작은 수는 모두 몇 개입니까?",
        "question_en": "There are five numbers 1/10, 8, 0.9, 7/10, and 5. How many of these numbers are less than 1?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 1/10 8 0.9 7/10 5 [OP_LIST_EOL] 1 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1/10 8 0.9 7/10 5 [OP_LIST_EOL] 1 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.1\nvar_b = 8\nvar_c = 0.9\nvar_d = 0.7\nvar_e = 5\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b = []\nfor i in list_a:\n    if i < var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 0.1\nvar_b = 8\nvar_c = 0.9\nvar_d = 0.7\nvar_e = 5\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b = []\nfor i in list_a:\n    if i < var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "7389": {
        "category": "Geometry",
        "question_ko": "아랫변의 길이가 윗변의 길이보다 6 센티미터(㎝) 길고, 높이가 8 센티미터(㎝)인 사다리꼴의 넓이가 72제곱센티미터(㎠)일 때, 이 사다리꼴의 윗변의 길이를 구하시오.",
        "question_en": "If the length of the lower side is 6 centimeters (cm) longer than the length of the upper side and the area of the trapezoid is 8 centimeters (cm) and the area is 72 square cm (cm2), find the length of the upper side of the trapezoid.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "72 2 [OP_MUL] 8 [OP_DIV] 6 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "72 2 [OP_MUL] 8 [OP_DIV] 6 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 72\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c / var_d\nvar_f = 6\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 72\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c / var_d\nvar_f = 6\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "7390": {
        "category": "Comparison",
        "question_ko": "윤기는 4, 유나는 5를 모았습니다. 정국이는 6에서 3을 합한 수를 모았다면 누가 가장 작은 수를 가지고 있나요?",
        "question_en": "Yoongi collected 4 and Yuna collected 5. If Jungkook collected the sum of 6 and 3, who has the smallest number?",
        "answer_ko": "윤기",
        "answer_en": "Yoongi",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 유나 정국 [OP_LIST_EOL] [OP_LIST_SOL] 4 5 6 3 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Yuna Jungkook [OP_LIST_EOL] [OP_LIST_SOL] 4 5 6 3 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '유나'\nvar_c = '정국'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 5\nvar_f = 6\nvar_g = 3\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Yuna'\nvar_c = 'Jungkook'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 5\nvar_f = 6\nvar_g = 3\nvar_h = var_f + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "7391": {
        "category": "Possibility",
        "question_ko": "서로 다른 2개의 상자에 과자 10개를 넣으려 한다. 상자에는 최소 1개의 과자가 있다고 한다면 과자를 나누는 경우는 방법은 몇 가지인가?",
        "question_en": "Find how many are there to divide cookies when you try to put 10 cookies in 2 different boxes. (There should be at least one cookie in the box.)",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "10 2 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "10 2 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7392": {
        "category": "Comparison",
        "question_ko": "도자기를 만드는 데 찬우가 사용한 찰흙의 무게는 0.645킬로그램(㎏)이고, 예림이가 사용한 찰흙의 무게는 0.65킬로그램(㎏)입니다. 찰흙을 더 많이 사용한 사람은 누구입니까?",
        "question_en": "The weight of the clay used by Chanwoo to make pottery is 0.645 kilograms (kg), and the weight of the clay used by Yerim is 0.65 kilograms (kg). Who used more clay?",
        "answer_ko": "예림",
        "answer_en": "Yerim",
        "solution_abst_ko": "[OP_LIST_SOL] 예림 찬우 [OP_LIST_EOL] [OP_LIST_SOL] 0.65 0.645 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yerim Chanwoo [OP_LIST_EOL] [OP_LIST_SOL] 0.65 0.645 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '예림'\nvar_b = '찬우'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.65\nvar_d = 0.645\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Yerim'\nvar_b = 'Chanwoo'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.65\nvar_d = 0.645\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "7393": {
        "category": "Geometry",
        "question_ko": "가로, 세로, 높이가 2미터(m)인 정육면체의 부피는 가로, 세로, 높이가 100센티미터(㎝)인 정육면체 부피의 몇 배인가?",
        "question_en": "How many times is the volume of a cube with a width, length, and height of 2 meters (m) bigger compared to the volume of a cube with width, length, and height of 100 centimeters (cm)?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "2 3 [OP_POW] 100 100 [OP_DIV] 3 [OP_POW] [OP_DIV]",
        "solution_abst_en": "2 3 [OP_POW] 100 100 [OP_DIV] 3 [OP_POW] [OP_DIV]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = var_a ** var_b\nvar_d = 100\nvar_e = 100\nvar_f = var_d / var_e\nvar_g = 3\nvar_h = var_f ** var_g\nvar_i = var_c / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = var_a ** var_b\nvar_d = 100\nvar_e = 100\nvar_f = var_d / var_e\nvar_g = 3\nvar_h = var_f ** var_g\nvar_i = var_c / var_h\nprint(int(var_i))"
    },
    "7394": {
        "category": "Arithmetic calculation",
        "question_ko": "똑같은 사탕이 (가) 바구니에 8개, (나) 바구니에 17개 있습니다. (가) 바구니에 사탕 몇 개를 더 놓으면 양쪽의 개수가 같아집니까?",
        "question_en": "There are 8 same candies in basket (A) and 17 in basket (B). How many candies should you put in basket (A) to make the number of candies in both baskets equal?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "17 8 [OP_SUB]",
        "solution_abst_en": "17 8 [OP_SUB]",
        "solution_code_ko": "var_a = 17\nvar_b = 8\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 17\nvar_b = 8\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "7395": {
        "category": "Arithmetic calculation",
        "question_ko": "태형이의 몸무게에서 지민이의 몸무게를 빼면 4킬로그램(㎏)입니다. 태형이와 지민이의 몸무게의 합이 88킬로그램(㎏)이라면 지민이의 몸무게는 몇 킬로그램(㎏)인지 구하세요.",
        "question_en": "If you subtract Jimin's weight from Taehyung's weight, it is 4 kilograms (kg). If the sum of Taehyung's and Jimin's weights is 88 kilograms (kg), how many kilograms (kg) does Jimin weigh?",
        "answer_ko": "42",
        "answer_en": "42",
        "solution_abst_ko": "88 4 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "88 4 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 88\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 88\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "7396": {
        "category": "Arithmetic calculation",
        "question_ko": "민영이는 테이프를 17미터(m) 48센티미터(㎝) 가지고 있고 유정이는 테이프를 850센티미터(㎝) 가지고 있습니다. 두 사람이 가지고 있는 테이프의 길이가 같아지려면 민영이는 유정이에게 테이프를 몇 센티미터(㎝) 주어야 하는지 구하시오.",
        "question_en": "Minyoung has a 17 meters (m) and 48 centimeters (cm) of tape, and Yoojung has an 850 centimeters (cm) of tape. Find how much Minyoung should give Yoojung a tape in centimeters (cm), so that both of them have the same length of tape.",
        "answer_ko": "449",
        "answer_en": "449",
        "solution_abst_ko": "17 100 [OP_MUL] 48 [OP_ADD] 850 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "17 100 [OP_MUL] 48 [OP_ADD] 850 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 17\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 48\nvar_e = var_c + var_d\nvar_f = 850\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 17\nvar_b = 100\nvar_c = var_a * var_b\nvar_d = 48\nvar_e = var_c + var_d\nvar_f = 850\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "7397": {
        "category": "Possibility",
        "question_ko": "1, 7, 0, 3 중에서 3개를 뽑아 한 번씩만 사용하여 세 자리 수를 만들려고 합니다. 만들 수 있는 두 번째로 큰 수와 두 번째로 작은 수의 차를 구하시오.",
        "question_en": "You want to create a three-digit number by drawing three out of 1, 7, 0, and 3 and using them only once. Find the difference between the second largest number and the second smallest number that can be made.",
        "answer_ko": "623",
        "answer_en": "623",
        "solution_abst_ko": "[OP_LIST_SOL] 1 7 0 3 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_SUB] [OP_ABS]",
        "solution_abst_en": "[OP_LIST_SOL] 1 7 0 3 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 1\nvar_b = 7\nvar_c = 0\nvar_d = 3\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 2\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g - var_i\nvar_k = abs(var_j)\nprint(int(var_k))",
        "solution_code_en": "var_a = 1\nvar_b = 7\nvar_c = 0\nvar_d = 3\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 2\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g - var_i\nvar_k = abs(var_j)\nprint(int(var_k))"
    },
    "7398": {
        "category": "Arithmetic calculation",
        "question_ko": "동화책 한 권은 161쪽입니다. 지민이가 이 동화책을 일주일에 걸쳐 읽었다면 하루에 읽은 쪽 수의 평균을 구하세요.",
        "question_en": "One children's book is 161 pages. If Jimin read this children's book for a week, find the average number of pages she read per day.",
        "answer_ko": "23",
        "answer_en": "23",
        "solution_abst_ko": "161 7 [OP_DIV]",
        "solution_abst_en": "161 7 [OP_DIV]",
        "solution_code_ko": "var_a = 161\nvar_b = 7\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 161\nvar_b = 7\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "7399": {
        "category": "Correspondence",
        "question_ko": "철수가 어떤 수를 18 로 나누어야 할 것을 잘못하여 1.8 로 나누어 계산했더니 몫은 21 이고, 나머지는 0.2 가 되었습니다. 바르게 계산했을 때의 몫을 반올림하여 소수 둘째 자리 까지 구하시오.",
        "question_en": "Cheulsu made a mistake in dividing a number by 18, so he divided the number by 1.8, and the quotient was 21, and the remainder was 0.2. Round the correct quotient to two decimal places.",
        "answer_ko": "2.11",
        "answer_en": "2.11",
        "solution_abst_ko": "21 1.8 [OP_MUL] 0.2 [OP_ADD] 18 [OP_DIV] 2 [OP_ROUND]",
        "solution_abst_en": "21 1.8 [OP_MUL] 0.2 [OP_ADD] 18 [OP_DIV] 2 [OP_ROUND]",
        "solution_code_ko": "var_a = 21\nvar_b = 1.8\nvar_c = var_a * var_b\nvar_d = 0.2\nvar_e = var_c + var_d\nvar_f = 18\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = round(float(var_g)+1e-10, var_h)\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 21\nvar_b = 1.8\nvar_c = var_a * var_b\nvar_d = 0.2\nvar_e = var_c + var_d\nvar_f = 18\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = round(float(var_g)+1e-10, var_h)\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "7400": {
        "category": "Correspondence",
        "question_ko": "등식 A5+2B=68이 성립한다고 합니다. 이 때, A에 들어갈 수 있는 숫자는 무엇인가요?",
        "question_en": "Say that the equation A5+2B=68 is correct. What number can go into A, where A is a single-digit number?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "A5+2B=68 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A5+2B=68 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A5+2B=68'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A5+2B=68'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "7401": {
        "category": "Correspondence",
        "question_ko": "창현이는 길이가 48센티미터(㎝)인 낚시대의 길이가 너무 짧아서 낚시대를 1.33배 늘리려한다. 늘어난 낚시대의 길이는 얼마인가?",
        "question_en": "Changhyun tries to increase the length of the 48 centimeters (cm) long fishing rod by 1.33 times because it is too short. What is the length of the extended fishing rod?",
        "answer_ko": "63.84",
        "answer_en": "63.84",
        "solution_abst_ko": "48 1.33 [OP_MUL]",
        "solution_abst_en": "48 1.33 [OP_MUL]",
        "solution_code_ko": "var_a = 48\nvar_b = 1.33\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 48\nvar_b = 1.33\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "7402": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 23으로 나눈 값에서 67을 뺀 후 2를 곱한 값이 102입니다. 어떤 수를 구하시오.",
        "question_en": "A number divided by 23 minus 67 and multiplied by 2 is 102. Find the number.",
        "answer_ko": "2714",
        "answer_en": "2714",
        "solution_abst_ko": "102 2 [OP_DIV] 67 [OP_ADD] 23 [OP_MUL]",
        "solution_abst_en": "102 2 [OP_DIV] 67 [OP_ADD] 23 [OP_MUL]",
        "solution_code_ko": "var_a = 102\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 67\nvar_e = var_c + var_d\nvar_f = 23\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 102\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 67\nvar_e = var_c + var_d\nvar_f = 23\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "7403": {
        "category": "Geometry",
        "question_ko": "각뿔에서 밑면의 꼭지점을 제외한 꼭지점은 몇개 인가요?",
        "question_en": "How many vertices are there in the pyramid, excluding those at the base?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "1",
        "solution_abst_en": "1",
        "solution_code_ko": "var_a = 1\nprint(int(var_a))",
        "solution_code_en": "var_a = 1\nprint(int(var_a))"
    },
    "7404": {
        "category": "Possibility",
        "question_ko": "3, 6, 0을 모두 사용하여 만들 수 있는 세 자리 자연수의 개수를 구하시오.",
        "question_en": "Find the number of three-digit natural numbers that can be formed using all 3, 6, and 0.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 3 6 0 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 3 6 0 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 3\nvar_b = 6\nvar_c = 0\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 3\nvar_b = 6\nvar_c = 0\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "7405": {
        "category": "Geometry",
        "question_ko": "유나는 교실에서 4번째로 키가 크고, 유정이는 유나 바로 다음으로 키가 큽니다. 유정이는 몇 번째로 키가 큽니까?",
        "question_en": "Yuna is the 4th tallest in the class, and Yujeong is the next tallest after Yuna. How tall is Yujung?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "4 1 [OP_ADD]",
        "solution_abst_en": "4 1 [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "7406": {
        "category": "Geometry",
        "question_ko": "어떤 팔각형의 대각선의 개수에서 어떤 칠각형의 대각선의 개수를 뺀 값을 구하시오.",
        "question_en": "Find the number of diagonals in an octagon minus the number of diagonals in a heptagon.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "8 8 3 [OP_SUB] [OP_MUL] 2 [OP_DIV] 7 7 3 [OP_SUB] [OP_MUL] 2 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "8 8 3 [OP_SUB] [OP_MUL] 2 [OP_DIV] 7 7 3 [OP_SUB] [OP_MUL] 2 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 8\nvar_b = 8\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 7\nvar_i = 7\nvar_j = 3\nvar_k = var_i - var_j\nvar_l = var_h * var_k\nvar_m = 2\nvar_n = var_l / var_m\nvar_o = var_g - var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 8\nvar_b = 8\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 7\nvar_i = 7\nvar_j = 3\nvar_k = var_i - var_j\nvar_l = var_h * var_k\nvar_m = 2\nvar_n = var_l / var_m\nvar_o = var_g - var_n\nprint(int(var_o))"
    },
    "7407": {
        "category": "Comparison",
        "question_ko": "기영이의 교실에는 각 줄의 책상 수가 같게 놓여 있습니다. 기영이의 자리는 뒤에서 2번째, 앞에서 4번째, 왼쪽에서 3번째에 있습니다. 가람이는 기영의 바로 오른쪽 옆에 있고 오른쪽에서 2번째에 있습니다. 기영이의 교실에 있는 책상 수 는 모두 몇 개입니까?",
        "question_en": "Kiyoung's classroom has the same number of desks in each row. Kiyoung's seat is 2nd from the back, 4th from the front, and 3rd from the left. Karam is right next to Kiyoung and 2nd from the right. How many desks are there in Kiyoung's classroom?",
        "answer_ko": "25",
        "answer_en": "25",
        "solution_abst_ko": "2 4 [OP_ADD] 1 [OP_SUB] 3 2 [OP_ADD] [OP_MUL]",
        "solution_abst_en": "2 4 [OP_ADD] 1 [OP_SUB] 3 2 [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = var_e * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = var_e * var_h\nprint(int(var_i))"
    },
    "7408": {
        "category": "Possibility",
        "question_ko": "0, 3, 4, 8을 한 번 씩 사용하여 만들 수 있는 네 자리수들 중 2개의 차가 가장 큰 경우, 그 차이는 얼마인지 구하시오.",
        "question_en": "If the difference between two of the four digit numbers that can be made by using 0, 3, 4, and 8 once is the greatest, what is the difference?",
        "answer_ko": "5382",
        "answer_en": "5382",
        "solution_abst_ko": "[OP_LIST_SOL] 0 3 4 8 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 0 3 4 8 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 0\nvar_b = 3\nvar_c = 4\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 0\nvar_b = 3\nvar_c = 4\nvar_d = 8\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))"
    },
    "7409": {
        "category": "Correspondence",
        "question_ko": "5A8-21B=364입니다. A는 얼마인가요?",
        "question_en": "5A8-21B=364. How much is A?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "5A8-21B=364 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "5A8-21B=364 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '5A8-21B=364'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '5A8-21B=364'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "7410": {
        "category": "Correspondence",
        "question_ko": "사과를 박스에 25개씩 나누어 담았는데 24개가 남았다. 사과의 개수는 300개 보다 많다고 할 때, 사과는 최소 몇 개인지 구하시오.",
        "question_en": "I put 25 apples each in boxes, but there are 24 left. If the number of apples is greater than 300, find the minimum number of apples.",
        "answer_ko": "324",
        "answer_en": "324",
        "solution_abst_ko": "300 24 [OP_ADD]",
        "solution_abst_en": "300 24 [OP_ADD]",
        "solution_code_ko": "var_a = 300\nvar_b = 24\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 300\nvar_b = 24\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "7411": {
        "category": "Correspondence",
        "question_ko": "40을 어떤 수에 곱해야 할 것을 잘못하여 21을 어떤 수에 뺀 결과는 52가 나옵니다. 바르게 계산하면 얼마인가요?",
        "question_en": "A particular number should have been multiplied by 40, but when I accidentally subtracted 21 from that number, the result was 52. Find the correct calculation result.",
        "answer_ko": "2920",
        "answer_en": "2920",
        "solution_abst_ko": "52 21 [OP_ADD] 40 [OP_MUL]",
        "solution_abst_en": "52 21 [OP_ADD] 40 [OP_MUL]",
        "solution_code_ko": "var_a = 52\nvar_b = 21\nvar_c = var_a + var_b\nvar_d = 40\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 52\nvar_b = 21\nvar_c = var_a + var_b\nvar_d = 40\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "7412": {
        "category": "Arithmetic calculation",
        "question_ko": "320에서 10씩 작아지게 4번 뛰어서 세면 얼마입니까?",
        "question_en": "What is the value if you jump 4 times reducing 10 each jump from 320?",
        "answer_ko": "280",
        "answer_en": "280",
        "solution_abst_ko": "320 10 4 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "320 10 4 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 320\nvar_b = 10\nvar_c = 4\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 320\nvar_b = 10\nvar_c = 4\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "7413": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 2번째로 큰 수와 가장 작은 수의 합은 얼마입니까?",
        "question_en": "There are five numbers 10, 11, 12, 13, and 14. What is the sum of the second largest number and the smallest number?",
        "answer_ko": "23",
        "answer_en": "23",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 2 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 2 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))"
    },
    "7414": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 6, 5, 8, 9로 나누어 떨어질 수 있는 수 중 가장 작은 세 자리 수는 무엇입니까?",
        "question_en": "What is the smallest three-digit number divisible by the four numbers 6, 5, 8, and 9?",
        "answer_ko": "360",
        "answer_en": "360",
        "solution_abst_ko": "100 999 1 [OP_LIST_ARANGE] 6 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "100 999 1 [OP_LIST_ARANGE] 6 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = 1\nlist_f=list_e.copy()\nlist_f.sort()\nvar_i = list_f[var_h-1]\nprint(int(var_i))",
        "solution_code_en": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 6\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 5\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = 1\nlist_f=list_e.copy()\nlist_f.sort()\nvar_i = list_f[var_h-1]\nprint(int(var_i))"
    },
    "7415": {
        "category": "Arithmetic calculation",
        "question_ko": "종이가 7개, 빨대가 15개 있습니다. 빨대는 종이보다 몇 개 더 많습니까?",
        "question_en": "There are 7 pieces of paper and 15 straws. How many more straws are there than paper?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "15 7 [OP_SUB]",
        "solution_abst_en": "15 7 [OP_SUB]",
        "solution_code_ko": "var_a = 15\nvar_b = 7\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 15\nvar_b = 7\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "7416": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 50을 뺀 후 4로 나누고, 3을 곱한 값에 28을 더한 값이 73입니다. 어떤 수를 구하시오.",
        "question_en": "Subtracting 50 from a certain number and dividing it by 4, multiplying by 3 plus 28 equals 73. Find the certain number.",
        "answer_ko": "110",
        "answer_en": "110",
        "solution_abst_ko": "73 28 [OP_SUB] 3 [OP_DIV] 4 [OP_MUL] 50 [OP_ADD]",
        "solution_abst_en": "73 28 [OP_SUB] 3 [OP_DIV] 4 [OP_MUL] 50 [OP_ADD]",
        "solution_code_ko": "var_a = 73\nvar_b = 28\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = 4\nvar_g = var_e * var_f\nvar_h = 50\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 73\nvar_b = 28\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = var_c / var_d\nvar_f = 4\nvar_g = var_e * var_f\nvar_h = 50\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "7417": {
        "category": "Arithmetic calculation",
        "question_ko": "모든 자연수들 중 짝수만을 골랐을 때, 작은 순서대로 123번째까지의 합을 구하시오.",
        "question_en": "When only even numbers are selected among all natural numbers, find the sum up to the 123rd in descending order.",
        "answer_ko": "15252",
        "answer_en": "15252",
        "solution_abst_ko": "2 2 123 1 [OP_SUB] 2 [OP_MUL] [OP_ADD] 2 [OP_LIST_ARANGE] [OP_LIST_SUM]",
        "solution_abst_en": "2 2 123 1 [OP_SUB] 2 [OP_MUL] [OP_ADD] 2 [OP_LIST_ARANGE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 2\nvar_b = 2\nvar_c = 123\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = var_b + var_g\nvar_i = 2\nlist_a = [i for i in range(var_a, var_h + 1, var_i)]\nlist_a = [float(i) for i in list_a]\nvar_j = sum(list_a)\nprint(int(var_j))",
        "solution_code_en": "var_a = 2\nvar_b = 2\nvar_c = 123\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = var_b + var_g\nvar_i = 2\nlist_a = [i for i in range(var_a, var_h + 1, var_i)]\nlist_a = [float(i) for i in list_a]\nvar_j = sum(list_a)\nprint(int(var_j))"
    },
    "7418": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 가게에서 1킬로그램(㎏)에 2500원을 받고 팔던 상추를 파는 가격의 0.3만큼 할인하여 팔고 있습니다. 상추 1.8킬로그램(㎏)을 할인된 가격으로 사려면 얼마가 필요한지 구하시오.",
        "question_en": "Lettuce, which was sold at a store for 2,500 won per kilogram (kg), is being sold at a discount of 0.3 of the initial price. Find how much money you need to buy 1.8 kilograms (kg) of lettuce at a discounted price.",
        "answer_ko": "3150",
        "answer_en": "3150",
        "solution_abst_ko": "2500 1 0.3 [OP_SUB] [OP_MUL] 1.8 [OP_MUL]",
        "solution_abst_en": "2500 1 0.3 [OP_SUB] [OP_MUL] 1.8 [OP_MUL]",
        "solution_code_ko": "var_a = 2500\nvar_b = 1\nvar_c = 0.3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 1.8\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 2500\nvar_b = 1\nvar_c = 0.3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 1.8\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "7419": {
        "category": "Possibility",
        "question_ko": "10이하 홀수를 한 번씩 모두 이용하여 만들 수 있는 가장 작은 수는 얼마인가?",
        "question_en": "What is the smallest number that can be formed by using all odd numbers less than 10 once?",
        "answer_ko": "13579",
        "answer_en": "13579",
        "solution_abst_ko": "0 10 [OP_LIST_ODD] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]",
        "solution_abst_en": "0 10 [OP_LIST_ODD] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 0\nvar_b = 10\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_e = list_c[var_d-1]\nprint(int(var_e))",
        "solution_code_en": "var_a = 0\nvar_b = 10\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_e = list_c[var_d-1]\nprint(int(var_e))"
    },
    "7420": {
        "category": "Arithmetic calculation",
        "question_ko": "24대의 자동차 중 8대가 나가고 6대가 또 나간 후 주차장에 남아있는 자동차는 몇 대입니까?",
        "question_en": "How many cars are left in the parking lot after 8 out of 24 cars went out and another 6 went out?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "24 8 [OP_SUB] 6 [OP_SUB]",
        "solution_abst_en": "24 8 [OP_SUB] 6 [OP_SUB]",
        "solution_code_ko": "var_a = 24\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 24\nvar_b = 8\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "7421": {
        "category": "Geometry",
        "question_ko": "한 모서리의 길이가 8㎝인 정육면체 3개를 한 줄로 놓으면 1개의 직육면체가 만들어집니다. 만들어진 직육면체의 겉넓이는 몇 제곱센티미터입니까?",
        "question_en": "If you put 3 cubes with each side 8cm long in a row, you will get 1 cuboid. What is the surface area of the cuboid you created, in square centimeters (cm2)?",
        "answer_ko": "896",
        "answer_en": "896",
        "solution_abst_ko": "8 8 [OP_MUL] 6 3 [OP_MUL] 4 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "8 8 [OP_MUL] 6 3 [OP_MUL] 4 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = 4\nvar_h = var_f - var_g\nvar_i = var_c * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 8\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = 4\nvar_h = var_f - var_g\nvar_i = var_c * var_h\nprint(int(var_i))"
    },
    "7422": {
        "category": "Geometry",
        "question_ko": "넓이가 3제곱센티미터(㎠)인 마름모의 두 대각선의 길이를 각각 5배로 늘리면 넓이는 몇 제곱센티미터(㎠)가 되는지 구하시오.",
        "question_en": "If the lengths of the two diagonals of a rhombus with an area of 3 square centimeters (cm2) are each multiplied by 5, how many square centimeters (cm2) will be the area?",
        "answer_ko": "75",
        "answer_en": "75",
        "solution_abst_ko": "3 5 5 [OP_MUL] [OP_MUL]",
        "solution_abst_en": "3 5 5 [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 5\nvar_c = 5\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 3\nvar_b = 5\nvar_c = 5\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nprint(int(var_e))"
    },
    "7423": {
        "category": "Comparison",
        "question_ko": "식당에 손님들이 한 줄로 서 있습니다. 맨 앞에 줄을 선 사람 뒤에 11명이 서 있을 때, 줄을 서 있는 손님은 모두 몇 명입니까?",
        "question_en": "Customers stand in line at the restaurant. If 11 people are standing behind the person in line at the front, how many customers are in line?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "11 1 [OP_ADD]",
        "solution_abst_en": "11 1 [OP_ADD]",
        "solution_code_ko": "var_a = 11\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 11\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "7424": {
        "category": "Arithmetic calculation",
        "question_ko": "연속된 짝수 3개의 합이 1194일 때, 가장 작은 짝수는 얼마입니까?",
        "question_en": "If the sum of three consecutive even numbers is 1194, what is the smallest even number?",
        "answer_ko": "396",
        "answer_en": "396",
        "solution_abst_ko": "1194 0 3 1 [OP_SUB] 2 [OP_MUL] 2 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 3 [OP_DIV]",
        "solution_abst_en": "1194 0 3 1 [OP_SUB] 2 [OP_MUL] 2 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 1194\nvar_b = 0\nvar_c = 3\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = 2\nlist_a = [i for i in range(var_b, var_g + 1, var_h)]\nlist_a = [float(i) for i in list_a]\nvar_i = sum(list_a)\nvar_j = var_a - var_i\nvar_k = 3\nvar_l = var_j / var_k\nprint(int(var_l))",
        "solution_code_en": "var_a = 1194\nvar_b = 0\nvar_c = 3\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = 2\nlist_a = [i for i in range(var_b, var_g + 1, var_h)]\nlist_a = [float(i) for i in list_a]\nvar_i = sum(list_a)\nvar_j = var_a - var_i\nvar_k = 3\nvar_l = var_j / var_k\nprint(int(var_l))"
    },
    "7425": {
        "category": "Arithmetic calculation",
        "question_ko": "계단을 올라갈때는 시속 2킬로미터(㎞)로, 내려올때는 올라갈때 보다 2킬로미터(㎞) 더 먼 길을 시속 3킬로미터(㎞)로 걸어내려 왔더니, 4시간이 걸렸다. 내려온 거리는 얼마인가?",
        "question_en": "I went up the stairs at 2 kilometers per hour (km), but when I came down, I walked 2 kilometers (km) further at 3 kilometers per hour (km), and it took 4 hours. What is the distance of coming down the stairs?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "2 4 [OP_MUL] 2 [OP_ADD] 3 2 [OP_ADD] [OP_DIV] 3 [OP_MUL]",
        "solution_abst_en": "2 4 [OP_MUL] 2 [OP_ADD] 3 2 [OP_ADD] [OP_DIV] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = var_e / var_h\nvar_j = 3\nvar_k = var_i * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = 2\nvar_h = var_f + var_g\nvar_i = var_e / var_h\nvar_j = 3\nvar_k = var_i * var_j\nprint(int(var_k))"
    },
    "7426": {
        "category": "Possibility",
        "question_ko": "4, 6, 5, 0 중 3개를 사용하여 일의 자리 숫자가 5인 가장 작은 수는 무엇입니까?",
        "question_en": "What is the smallest number with the units digit of 5 using 3 of 4, 6, 5, and 0?",
        "answer_ko": "405",
        "answer_en": "405",
        "solution_abst_ko": "[OP_LIST_SOL] 4 6 5 0 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 5 [OP_LIST_SEARCH_FIXED_DIGIT] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 4 6 5 0 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 5 [OP_LIST_SEARCH_FIXED_DIGIT] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 4\nvar_b = 6\nvar_c = 5\nvar_d = 0\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nvar_g = 5\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nprint(int(var_i))",
        "solution_code_en": "var_a = 4\nvar_b = 6\nvar_c = 5\nvar_d = 0\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nvar_g = 5\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nprint(int(var_i))"
    },
    "7427": {
        "category": "Geometry",
        "question_ko": "재웅이 반 학생들을 정사각형으로 줄세웠습니다. 가로와 세로 모두 10명 씩 줄섰을 때, 둘레를 제외한 안쪽의 학생들은 모두 몇 명일까요?",
        "question_en": "You lined up Jaewoong's classmates in a square. When 10 students are lined up horizontally and vertically, how many students are inside the circumference?",
        "answer_ko": "64",
        "answer_en": "64",
        "solution_abst_ko": "10 2 [OP_SUB] 2 [OP_POW]",
        "solution_abst_en": "10 2 [OP_SUB] 2 [OP_POW]",
        "solution_code_ko": "var_a = 10\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c ** var_d\nprint(int(var_e))"
    },
    "7428": {
        "category": "Correspondence",
        "question_ko": "어떤 수가 102가 되기 위해서는 23으로 나누고 67을 뺀 후 2를 곱해주어야 합니다. 어떤 수를 구하시오.",
        "question_en": "To make a particular number equal to 102, it should be divided by 23, subtracted from 67, and multiplied by 2. Find the particular number.",
        "answer_ko": "2714",
        "answer_en": "2714",
        "solution_abst_ko": "102 2 [OP_DIV] 67 [OP_ADD] 23 [OP_MUL]",
        "solution_abst_en": "102 2 [OP_DIV] 67 [OP_ADD] 23 [OP_MUL]",
        "solution_code_ko": "var_a = 102\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 67\nvar_e = var_c + var_d\nvar_f = 23\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 102\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 67\nvar_e = var_c + var_d\nvar_f = 23\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "7429": {
        "category": "Comparison",
        "question_ko": "정국이는 6개의 사과에서 3개를 먹었습니다. 윤기가 가진 사과가 4개, 유나가 가진 사과가 5개라면 누가 가장 많은 사과를 가지고 있나요?",
        "question_en": "Jungkook ate 3 out of 6 apples. If Yoongi has 4 apples and Yuna has 5 apples, who has the most apples?",
        "answer_ko": "유나",
        "answer_en": "Yuna",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 윤기 유나 [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_SUB] 4 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Yoongi Yuna [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_SUB] 4 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '윤기'\nvar_c = '유나'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 6\nvar_e = 3\nvar_f = var_d - var_e\nvar_g = 4\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Yoongi'\nvar_c = 'Yuna'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 6\nvar_e = 3\nvar_f = var_d - var_e\nvar_g = 4\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "7430": {
        "category": "Arithmetic calculation",
        "question_ko": "학생들이 4명씩 8줄로 서 있다. 둘레에 서 있는 학생들의 수를 구하시오.",
        "question_en": "Students are standing in 8 rows of 4 each. Find the number of students standing at the perimeter.",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "4 8 [OP_ADD] 2 [OP_MUL] 4 [OP_SUB]",
        "solution_abst_en": "4 8 [OP_ADD] 2 [OP_MUL] 4 [OP_SUB]",
        "solution_code_ko": "var_a = 4\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "7431": {
        "category": "Arithmetic calculation",
        "question_ko": "같은 수의 남학생과 여학생이 나간 뒤 강당에 30명의 학생이 남았습니다. 처음에 강당에 남학생 24명과 여학생 14명이 있었을 때 강당에서 나간 여학생은 몇명입니까?",
        "question_en": "After the same number of boys and girls had left, there were 30 students left in the auditorium. How many girls left the auditorium when there were initially 24 boys and 14 girls in the auditorium?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "24 14 [OP_ADD] 30 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "24 14 [OP_ADD] 30 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 24\nvar_b = 14\nvar_c = var_a + var_b\nvar_d = 30\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 24\nvar_b = 14\nvar_c = var_a + var_b\nvar_d = 30\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "7432": {
        "category": "Comparison",
        "question_ko": "지민, 유정이 각자 끈을 가지고 있습니다. 지민이는 59센티미터(cm) 유정이는 53센티미터(cm)의 끈을 가지고 있다면 누가 더 짧은 끈을 가지고 있습니까?",
        "question_en": "Jimin and Yoojeong each have a strap. If Jimin has a 59 centimeters (cm) strap and Yoojeong has a 53 centimeters (cm) strap, who has the shorter strap?",
        "answer_ko": "유정",
        "answer_en": "Yoojeong",
        "solution_abst_ko": "[OP_LIST_SOL] 지민 유정 [OP_LIST_EOL] [OP_LIST_SOL] 59 53 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jimin Yoojeong [OP_LIST_EOL] [OP_LIST_SOL] 59 53 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '지민'\nvar_b = '유정'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 59\nvar_d = 53\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Jimin'\nvar_b = 'Yoojeong'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 59\nvar_d = 53\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "7433": {
        "category": "Comparison",
        "question_ko": "한 변의 길이가 3센티미터(㎝)인 정사각형과 한 변의 길이가 5센티미터(㎝)인 정삼각형 중에서 둘레의 길이가 더 긴 도형은 어느 것입니까?",
        "question_en": "Which figure has a longer perimeter, a square with a side length of 3 centimeters (cm) or an equilateral-triangle with a side length of 5 centimeters (cm)?",
        "answer_ko": "정삼각형",
        "answer_en": "equilateral-triangle",
        "solution_abst_ko": "[OP_LIST_SOL] 정사각형 정삼각형 [OP_LIST_EOL] [OP_LIST_SOL] 3 4 [OP_MUL] 5 3 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] square equilateral-triangle [OP_LIST_EOL] [OP_LIST_SOL] 3 4 [OP_MUL] 5 3 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정사각형'\nvar_b = '정삼각형'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nvar_d = 4\nvar_e = var_c * var_d\nvar_f = 5\nvar_g = 3\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'square'\nvar_b = 'equilateral-triangle'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nvar_d = 4\nvar_e = var_c * var_d\nvar_f = 5\nvar_g = 3\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "7434": {
        "category": "Comparison",
        "question_ko": "화물칸에 A, B, C 3개의 화물을 실으려고 합니다. C 화물은 A 화물보다 작고, A 화물은 B 화물보다 작습니다. 가장 큰 화물을 먼저 실으려고 할 때, 가장 먼저 실어야 하는 화물은 무엇일까요?",
        "question_en": "You want to load three cargoes, A, B, and C, into the compartment. Cargo C is smaller than Cargo A, and Cargo A is smaller than Cargo B. If you want to load the biggest cargo first, which cargo should be loaded first?",
        "answer_ko": "B",
        "answer_en": "B",
        "solution_abst_ko": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] A B < C A < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] A B < C A < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'A'\nvar_e = 'B'\nvar_f = '<'\nvar_g = 'C'\nvar_h = 'A'\nvar_i = '<'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(var_k)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'A'\nvar_e = 'B'\nvar_f = '<'\nvar_g = 'C'\nvar_h = 'A'\nvar_i = '<'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(var_k)"
    },
    "7435": {
        "category": "Correspondence",
        "question_ko": "태형이는 어떤 수에 6을 나누어 주려고 합니다. 하지만 실수로 5를 곱했더니 결과는 30이 되었습니다. 바르게 계산한 결과를 구하세요.",
        "question_en": "Taehyung wants to divide a number by 6. But when he accidentally multiplied it by 5, the result was 30. Find the correctly calculated value.",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "30 5 [OP_DIV] 6 [OP_DIV]",
        "solution_abst_en": "30 5 [OP_DIV] 6 [OP_DIV]",
        "solution_code_ko": "var_a = 30\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 30\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "7436": {
        "category": "Arithmetic calculation",
        "question_ko": "올해 은지의 나이는 7살입니다. 유나는 은지보다 5살 더 많습니다. 올해 은지와 유나의 나이의 합은 몇 살입니까?",
        "question_en": "Eunji is 7 years old this year. Yuna is 5 years older than Eunji. What is the sum of Eunji and Yuna's ages this year?",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "7 7 5 [OP_ADD] [OP_ADD]",
        "solution_abst_en": "7 7 5 [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 7\nvar_b = 7\nvar_c = 5\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 7\nvar_b = 7\nvar_c = 5\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "7437": {
        "category": "Comparison",
        "question_ko": "예원이와 동주가 문장 빨리 읽기 대결을 하였습니다. 정해진 문장을 읽는 데 예원이는 16.23초 걸렸고 동주는 16.19초 걸렸다면 누가 더 빨리 읽었습니까?",
        "question_en": "Yewon and Dongju had a fast reading competition. If it took Yewon 16.23 seconds and Dongju 16.19 seconds to read the given sentence, who read faster?",
        "answer_ko": "동주",
        "answer_en": "Dongju",
        "solution_abst_ko": "[OP_LIST_SOL] 예원 동주 [OP_LIST_EOL] [OP_LIST_SOL] 100 16.23 [OP_DIV] 100 16.19 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yewon Dongju [OP_LIST_EOL] [OP_LIST_SOL] 100 16.23 [OP_DIV] 100 16.19 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '예원'\nvar_b = '동주'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 100\nvar_d = 16.23\nvar_e = var_c / var_d\nvar_f = 100\nvar_g = 16.19\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Yewon'\nvar_b = 'Dongju'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 100\nvar_d = 16.23\nvar_e = var_c / var_d\nvar_f = 100\nvar_g = 16.19\nvar_h = var_f / var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "7438": {
        "category": "Correspondence",
        "question_ko": "식 6AB-41=591이 있습니다. A에 들어가야 하는 숫자를 구하시오",
        "question_en": "We have an expression of 6AB-41=591. Find the number that must go into A.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "6AB-41=591 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "6AB-41=591 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '6AB-41=591'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '6AB-41=591'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "7439": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 5로 나누어야 할 것을 잘못하여 7을 곱했더니 5와 4/9가 되었습니다. 바르게 계산하면 얼마인지 소수 2번째 자리까지 나타내어보세요.",
        "question_en": "When you multiply the number by 7 by mistake, which should be divided by 5, you got 5 and 4/9. Write down the result of the correct calculation indicating two decimal places.",
        "answer_ko": "7.62",
        "answer_en": "7.62",
        "solution_abst_ko": "5 4/9 [OP_ADD] 7 [OP_MUL] 5 [OP_DIV]",
        "solution_abst_en": "5 4/9 [OP_ADD] 7 [OP_MUL] 5 [OP_DIV]",
        "solution_code_ko": "var_a = 5\nvar_b = 0.4444444444444444\nvar_c = var_a + var_b\nvar_d = 7\nvar_e = var_c * var_d\nvar_f = 5\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 5\nvar_b = 0.4444444444444444\nvar_c = var_a + var_b\nvar_d = 7\nvar_e = var_c * var_d\nvar_f = 5\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "7440": {
        "category": "Geometry",
        "question_ko": "밑변의 길이가 23센티미터(㎝)이고 높이가 12센티미터(㎝)인 사다리꼴의 넓이가 222제곱센티미터(㎠)일 때, 윗변의 길이는 얼마인가요?",
        "question_en": "If the area of a trapezoid with a base of 23 centimeters (cm) and a height of 12 centimeters (cm) is 222 square cm (cm2), what is the length of the upper side?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "222 2 [OP_MUL] 12 [OP_DIV] 23 [OP_SUB]",
        "solution_abst_en": "222 2 [OP_MUL] 12 [OP_DIV] 23 [OP_SUB]",
        "solution_code_ko": "var_a = 222\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = var_c / var_d\nvar_f = 23\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 222\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = var_c / var_d\nvar_f = 23\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "7441": {
        "category": "Geometry",
        "question_ko": "연필이 144자루 있습니다. 한 다스가 12자루라면 연필은 몇 다스 있습니까?",
        "question_en": "There are 144 pencils. How many dozen pencils are there if one dozen is 12?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "144 12 [OP_DIV]",
        "solution_abst_en": "144 12 [OP_DIV]",
        "solution_code_ko": "var_a = 144\nvar_b = 12\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 144\nvar_b = 12\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "7442": {
        "category": "Correspondence",
        "question_ko": "23을 13으로 나눴더니 몫이 A가 되었고 나머지가 10이 되었습니다. 이 때 A는 무엇일까요?",
        "question_en": "When you divide 23 by 13, the quotient is A and the remainder is 10. What is A in this case?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "23 10 [OP_SUB] 13 [OP_DIV]",
        "solution_abst_en": "23 10 [OP_SUB] 13 [OP_DIV]",
        "solution_code_ko": "var_a = 23\nvar_b = 10\nvar_c = var_a - var_b\nvar_d = 13\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 23\nvar_b = 10\nvar_c = var_a - var_b\nvar_d = 13\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "7443": {
        "category": "Geometry",
        "question_ko": "어떤 정육면체는 한 모서리의 길이가 8센티미터(㎝)입니다. 이 정육면체의 겉넓이를 구하시오.",
        "question_en": "A cube has one edge 8 centimeters (cm) long. Find the surface area of this cube.",
        "answer_ko": "384",
        "answer_en": "384",
        "solution_abst_ko": "8 2 [OP_POW] 6 [OP_MUL]",
        "solution_abst_en": "8 2 [OP_POW] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "7444": {
        "category": "Geometry",
        "question_ko": "어떤 공원은 한 변의 길이가 11미터(m)인 정사각형 모양이고, 다른 공원은 한 변의 길이가 5미터(m)인 정사각형 모양입니다. 두 공원의 넓이의 합을 구하시오.",
        "question_en": "Some parks are square with sides measuring 11 meters (m), and others are square with sides measuring 5 meters (m). Find the sum of the areas of the two parks.",
        "answer_ko": "146",
        "answer_en": "146",
        "solution_abst_ko": "11 2 [OP_POW] 5 2 [OP_POW] [OP_ADD]",
        "solution_abst_en": "11 2 [OP_POW] 5 2 [OP_POW] [OP_ADD]",
        "solution_code_ko": "var_a = 11\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 11\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "7445": {
        "category": "Arithmetic calculation",
        "question_ko": "가로 24미터(m), 세로 18미터(m)인 벽에 정사각형 타일을 빠짐없이 붙히려고 한다. 타일을 최소한으로 사용한다면 타일의 한 변의 길이는 몇 미터(m)인지 구하시오.",
        "question_en": "You are trying to attach every square tile to a wall measuring 24 meters (m) wide and 18 meters (m) long. If you use a minimum number of tiles, find how many meters (m) each side of the tile is.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "24 18 [OP_GCD]",
        "solution_abst_en": "24 18 [OP_GCD]",
        "solution_code_ko": "var_a = 24\nvar_b = 18\nvar_c = math.gcd(int(var_b), int(var_a))\nprint(int(var_c))",
        "solution_code_en": "var_a = 24\nvar_b = 18\nvar_c = math.gcd(int(var_b), int(var_a))\nprint(int(var_c))"
    },
    "7446": {
        "category": "Comparison",
        "question_ko": "엄마, 아빠, 할아버지가 백화점에서 옷을 구매했습니다. 엄마보다 아빠가 옷을 더 많이 샀고, 아빠보다 할아버지가 옷을 더 많이 샀습니다. 할아버지는 몇 번째로 옷을 적게 샀습니까?",
        "question_en": "Mom, Dad and Grandpa bought clothes at the department store. Dad bought more clothes than Mom, and Grandpa bought more clothes than Dad. In what place did grandpa rank for buying the least amount of clothes?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 엄마 아빠 할아버지 [OP_LIST_EOL] 할아버지 [OP_LIST_INDEX]",
        "solution_abst_en": "[OP_LIST_SOL] Mom Dad Grandpa [OP_LIST_EOL] Grandpa [OP_LIST_INDEX]",
        "solution_code_ko": "var_a = '엄마'\nvar_b = '아빠'\nvar_c = '할아버지'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '할아버지'\nvar_e = list_a.index(var_d)+1\nprint(int(var_e))",
        "solution_code_en": "var_a = 'Mom'\nvar_b = 'Dad'\nvar_c = 'Grandpa'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'Grandpa'\nvar_e = list_a.index(var_d)+1\nprint(int(var_e))"
    },
    "7447": {
        "category": "Geometry",
        "question_ko": "직사각형 모양의 화단의 넓이가 48.6제곱미터(㎡)이다. 이 화단의 세로의 길이를 재었더니 5.4미터(m)이다. 화단의 가로의 길이는 몇 미터(m)인지 구하시오.",
        "question_en": "The area of the rectangular flower garden is 48.6 square meters (m2). When the length of this flower garden was measured, it was 5.4 meters (m). Find the width of the flower garden in meters (m).",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "48.6 5.4 [OP_DIV]",
        "solution_abst_en": "48.6 5.4 [OP_DIV]",
        "solution_code_ko": "var_a = 48.6\nvar_b = 5.4\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 48.6\nvar_b = 5.4\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "7448": {
        "category": "Comparison",
        "question_ko": "미혜는 1시간 5/12시간, 성재는 1시간 3/12시간 훈련했다. 누가 가장 오래 훈련했습니까?",
        "question_en": "Mihye trained for 1 hour and 5/12 hours, and Seongjae trained for 1 hour and 3/12 hours. Who has been training the longest?",
        "answer_ko": "미혜",
        "answer_en": "Mihye",
        "solution_abst_ko": "[OP_LIST_SOL] 미혜 성재 [OP_LIST_EOL] [OP_LIST_SOL] 1 5 12 [OP_DIV] [OP_ADD] 1 3 12 [OP_DIV] [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Mihye Seongjae [OP_LIST_EOL] [OP_LIST_SOL] 1 5 12 [OP_DIV] [OP_ADD] 1 3 12 [OP_DIV] [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '미혜'\nvar_b = '성재'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1\nvar_d = 5\nvar_e = 12\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nvar_h = 1\nvar_i = 3\nvar_j = 12\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'Mihye'\nvar_b = 'Seongjae'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1\nvar_d = 5\nvar_e = 12\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nvar_h = 1\nvar_i = 3\nvar_j = 12\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "7449": {
        "category": "Correspondence",
        "question_ko": "민기는 방울토마토를 같은 반 친구 20명에게 15개씩 나누어 주었다. 이후 남은 방울토마토의 개수가 6개이면 민기가 처음 가지고 있던 방울토마토의 개수는 몇 개인가?",
        "question_en": "Mingi gave 15 cherry tomatoes each to 20 classmates. If the remaining number of cherry tomatoes is 6, how many cherry tomatoes did Mingi have at first?",
        "answer_ko": "306",
        "answer_en": "306",
        "solution_abst_ko": "15 20 [OP_MUL] 6 [OP_ADD]",
        "solution_abst_en": "15 20 [OP_MUL] 6 [OP_ADD]",
        "solution_code_ko": "var_a = 15\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7450": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중에서 2번째로 큰 수를 2번째로 작은 수로 나눈 몫은 얼마입니까?",
        "question_en": "There are three numbers 10, 11, and 12. What is the quotient of the second largest number divided by the second smallest number?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_FDIV]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_FDIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e // var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e // var_g\nprint(int(var_h))"
    },
    "7451": {
        "category": "Arithmetic calculation",
        "question_ko": "6분 동안 21리터(L)가 나오도록 수도를 틀어 욕조에 물을 받았다. 욕조에 물이 빠져나가는 곳을 막지 않고 물을 받았더니 가득 채우는 데 22분 30초가 걸렸다. 욕조에서 물이 1분 동안 0.3리터(L)씩 빠져 나갔다면 욕조의 들이는 몇 리터(L)인지 구하여라.",
        "question_en": "I turned on the tap so that 21 liters (L) came out in 6 minutes to fill the bathtub. When I filled the water without blocking the water drain in the bathtub, it took 22 minutes and 30 seconds to fill it up. If 0.3 liters (L) of water escaped from the bathtub per 1 minute, find how many liters (L) the bathtub can contain.",
        "answer_ko": "72",
        "answer_en": "72",
        "solution_abst_ko": "21 6 [OP_DIV] 0.3 [OP_SUB] 22 30 60 [OP_DIV] [OP_ADD] [OP_MUL]",
        "solution_abst_en": "21 6 [OP_DIV] 0.3 [OP_SUB] 22 30 60 [OP_DIV] [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 21\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.3\nvar_e = var_c - var_d\nvar_f = 22\nvar_g = 30\nvar_h = 60\nvar_i = var_g / var_h\nvar_j = var_f + var_i\nvar_k = var_e * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 21\nvar_b = 6\nvar_c = var_a / var_b\nvar_d = 0.3\nvar_e = var_c - var_d\nvar_f = 22\nvar_g = 30\nvar_h = 60\nvar_i = var_g / var_h\nvar_j = var_f + var_i\nvar_k = var_e * var_j\nprint(int(var_k))"
    },
    "7452": {
        "category": "Geometry",
        "question_ko": "정사각형 상자를 빈틈없이 늘여놓으니 6개 남았습니다. 그래서 가로 한 변과 세로 한 변을 1열씩 늘리려 하였지만 11개의 상자가 부족하였습니다. 이 상자들을 7열로 늘여 놓는다면 1열에 몇 개가 있을까요?",
        "question_en": "When boxes are lined up to make square shape, there are 6 left. So, I tried to increase the width and height by one row each, but I was short of 11 boxes. If these boxes are laid out in rows of 7, how many boxes are in row 1?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "6 11 [OP_ADD] 1 [OP_SUB] 2 [OP_DIV] 2 [OP_POW] 6 [OP_ADD] 7 [OP_DIV]",
        "solution_abst_en": "6 11 [OP_ADD] 1 [OP_SUB] 2 [OP_DIV] 2 [OP_POW] 6 [OP_ADD] 7 [OP_DIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 11\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 6\nvar_k = var_i + var_j\nvar_l = 7\nvar_m = var_k / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 6\nvar_b = 11\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 6\nvar_k = var_i + var_j\nvar_l = 7\nvar_m = var_k / var_l\nprint(int(var_m))"
    },
    "7453": {
        "category": "Arithmetic calculation",
        "question_ko": "동물원에 있는 수컷 사자의 몸무게는 145/4킬로그램(㎏)이고, 수컷 사자는 암컷 사자보다 47/10킬로그램(㎏) 더 무겁다고 합니다. 암컷 사자의 몸무게는 몇 킬로그램(㎏)입니까?",
        "question_en": "Male lions in the zoo weigh 145/4 kilograms (kg), and male lions are said to weigh 47/10 kilograms (kg) more than female lions. How many kilograms (kg) does the female lion weigh?",
        "answer_ko": "31.55",
        "answer_en": "31.55",
        "solution_abst_ko": "145/4 47/10 [OP_SUB]",
        "solution_abst_en": "145/4 47/10 [OP_SUB]",
        "solution_code_ko": "var_a = 36.25\nvar_b = 4.7\nvar_c = var_a - var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 36.25\nvar_b = 4.7\nvar_c = var_a - var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "7454": {
        "category": "Correspondence",
        "question_ko": "윤기는 두 자리 수와 57의 뺄셈을 하려 합니다. 윤기는 두 자리 수의 일의 자리 숫자 9를 6으로 잘못 보았습니다. 윤기가 구한 차는 39 일 때, 두 자리 수를 구하시오.",
        "question_en": "Yoongi had to subtract 57 from a certain two-digit number. Yoongi mistook 9 as a 6 in the units digit of a two-digit number. When Yoongi's result is 39, find a two-digit number.",
        "answer_ko": "99",
        "answer_en": "99",
        "solution_abst_ko": "39 57 [OP_ADD] 6 9 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "39 57 [OP_ADD] 6 9 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 39\nvar_b = 57\nvar_c = var_a + var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 39\nvar_b = 57\nvar_c = var_a + var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "7455": {
        "category": "Comparison",
        "question_ko": "35명의 학생이 한 줄로 서 있습니다. 민영이의 앞에는 27명의 학생들이 서 있습니다. 민영이의 뒤에 서 있는 학생은 몇 명입니까?",
        "question_en": "35 students are standing in a line. 27 students are standing in front of Minyoung. How many students are standing behind Minyoung?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "35 27 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "35 27 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 35\nvar_b = 27\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 35\nvar_b = 27\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "7456": {
        "category": "Possibility",
        "question_ko": "2가지의 과일을 구매하려고 합니다. 과일 가게에서 판매하는 과일이 사과, 복숭아, 배, 참외, 딸기라면 가능한 경우의 수는 모두 몇 가지입니까?",
        "question_en": "You would like to purchase 2 kinds of fruits. If the fruits sold in the fruit store are apples, peaches, pears, melons, and strawberries, how many possible ways are there?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 복숭아 배 참외 딸기 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] apples peaches pears melons strawberries [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '복숭아'\nvar_c = '배'\nvar_d = '참외'\nvar_e = '딸기'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h / (i+1)\nprint(int(var_h))",
        "solution_code_en": "var_a = 'apples'\nvar_b = 'peaches'\nvar_c = 'pears'\nvar_d = 'melons'\nvar_e = 'strawberries'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = 2\nvar_h = 1\nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h * (var_f-i)\nfor i, elem in enumerate(range(var_g)):\n    var_h = var_h / (i+1)\nprint(int(var_h))"
    },
    "7457": {
        "category": "Geometry",
        "question_ko": "두 대각선의 길이가 6센티미터(㎝), 4센티미터(㎝)인 마름모가 있습니다. 이 마름모보다 대각선의 길이가 3배씩 긴 마름모의 넓이는 몇 제곱센티미터(㎠)인지 구하시오.",
        "question_en": "There is a rhombus with two diagonals measuring 6 centimeters (cm) and 4 centimeters (cm). Find the area in square centimeters (cm2) of a rhombus whose diagonals are 3 times longer than this rhombus.",
        "answer_ko": "108",
        "answer_en": "108",
        "solution_abst_ko": "6 3 [OP_MUL] 4 3 [OP_MUL] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "6 3 [OP_MUL] 4 3 [OP_MUL] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c * var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 6\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c * var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "7458": {
        "category": "Possibility",
        "question_ko": "5, 1, 6, 2, 4가 적힌 숫자 카드를 한 번씩 사용하여 만들 수 있는 네 자리 수 중에서 가장 큰 수를 구하시오",
        "question_en": "Find the largest four-digit number that can be made by using the number cards 5, 1, 6, 2, and 4 once.",
        "answer_ko": "6542",
        "answer_en": "6542",
        "solution_abst_ko": "[OP_LIST_SOL] 5 1 6 2 4 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 5 1 6 2 4 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 5\nvar_b = 1\nvar_c = 6\nvar_d = 2\nvar_e = 4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nprint(int(var_h))",
        "solution_code_en": "var_a = 5\nvar_b = 1\nvar_c = 6\nvar_d = 2\nvar_e = 4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nprint(int(var_h))"
    },
    "7459": {
        "category": "Comparison",
        "question_ko": "4개의 고등학교가 있다. 이들 전체의 전교생 수의 평균은 2300이다. 1번, 2번 고등학교의 전교생 수의 평균은 3000명이고, 2번, 3번 고등학교의 전교생 평균은 2100명, 3번과 4번의 평균은 2750명이다. 그리고 2번 고등학교는 1번 고등학교보다 전교생이 800명 더 적다. 4번 고등학교의 전교생은 모두 몇 명인가?",
        "question_en": "There are 4 high schools. The average student number of these schools is 2300. The average number of students in High School 1 and 2 is 3000, the average number of students for High School 2 and 3 is 2100, and the average number of students for High schools 3 and 4 is 2750. And High School 2 has 800 fewer students than High School 1. How many students are there in all four high schools?",
        "answer_ko": "3900",
        "answer_en": "3900",
        "solution_abst_ko": "2750 2 [OP_MUL] 2100 2 [OP_MUL] 3000 2 [OP_MUL] 800 [OP_SUB] 2 [OP_DIV] [OP_SUB] [OP_SUB]",
        "solution_abst_en": "2750 2 [OP_MUL] 2100 2 [OP_MUL] 3000 2 [OP_MUL] 800 [OP_SUB] 2 [OP_DIV] [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 2750\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 2100\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = 3000\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = 800\nvar_k = var_i - var_j\nvar_l = 2\nvar_m = var_k / var_l\nvar_n = var_f - var_m\nvar_o = var_c - var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 2750\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 2100\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = 3000\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = 800\nvar_k = var_i - var_j\nvar_l = 2\nvar_m = var_k / var_l\nvar_n = var_f - var_m\nvar_o = var_c - var_n\nprint(int(var_o))"
    },
    "7460": {
        "category": "Geometry",
        "question_ko": "몇 명의 학생들이 정사각형 모양으로 빈틈없이 정렬하여 서서 보니 6명이 남았습니다. 그래서 가로 한 변과 세로 한 변을 1열씩 늘리려 하였지만 11명이 부족하였습니다. 이 학생들을 7열로 세운다면 1열에 몇 명씩 서겠습니까?",
        "question_en": "Several students lined up completely in a square shape, but there were six students left. So, the students tried to increase the width and height by one row each, but they were short of 11 students. If you arrange these students in rows of 7, how many will stand in row 1?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "6 11 [OP_ADD] 1 [OP_SUB] 2 [OP_DIV] 2 [OP_POW] 6 [OP_ADD] 7 [OP_DIV]",
        "solution_abst_en": "6 11 [OP_ADD] 1 [OP_SUB] 2 [OP_DIV] 2 [OP_POW] 6 [OP_ADD] 7 [OP_DIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 11\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 6\nvar_k = var_i + var_j\nvar_l = 7\nvar_m = var_k / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 6\nvar_b = 11\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 6\nvar_k = var_i + var_j\nvar_l = 7\nvar_m = var_k / var_l\nprint(int(var_m))"
    },
    "7461": {
        "category": "Correspondence",
        "question_ko": "진영이는 과수원에서 사과를 수확하고 있습니다. 419개를 새로 수확한 다음 기존에 있던 사과 중 썩은 사과 263개를 버렸습니다. 현재 사과의 개수가 725개이면 사과를 수확하기전에 사과의 개수는 몇 개입니까?",
        "question_en": "Jinyoung is harvesting apples in the orchard. He harvested 419 new apples, and then threw away 263 rotten apples among the apples he already had. If the current number of apples is 725, how many apples did he have before harvesting?",
        "answer_ko": "569",
        "answer_en": "569",
        "solution_abst_ko": "725 263 [OP_ADD] 419 [OP_SUB]",
        "solution_abst_en": "725 263 [OP_ADD] 419 [OP_SUB]",
        "solution_code_ko": "var_a = 725\nvar_b = 263\nvar_c = var_a + var_b\nvar_d = 419\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 725\nvar_b = 263\nvar_c = var_a + var_b\nvar_d = 419\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "7462": {
        "category": "Arithmetic calculation",
        "question_ko": "산에서 밤을 은수는 2킬로그램(㎏) 600그램(g) 주웠고, 민기는 3700그램(g) 주웠습니다. 은수와 민기가 주운 밤의 무게는 모두 몇 그램(g)입니까?",
        "question_en": "Eun-soo picked up 2 kilograms (kg) and 600 grams (g) of chestnuts in the mountain, and Min-gi picked up 3700 grams (g). How many grams (g) do the chestnuts that Eunsu and Mingi picked in total weigh?",
        "answer_ko": "6300",
        "answer_en": "6300",
        "solution_abst_ko": "2 1000 [OP_MUL] 600 [OP_ADD] 3700 [OP_ADD]",
        "solution_abst_en": "2 1000 [OP_MUL] 600 [OP_ADD] 3700 [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 600\nvar_e = var_c + var_d\nvar_f = 3700\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 600\nvar_e = var_c + var_d\nvar_f = 3700\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "7463": {
        "category": "Arithmetic calculation",
        "question_ko": "4명의 사람들이 둥근 탁자에 앉아있다. 양옆으로 인접하지 않는 사람들과 악수를 한번씩하려면 악수를 모두 몇 번 하는지 구하시오.",
        "question_en": "Four people are sitting at a round table. If you want to shake hands once with people who are not sitting next to each other, find how many times you shake hands.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "4 4 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "4 4 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 4\nvar_b = 4\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 4\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "7464": {
        "category": "Possibility",
        "question_ko": "4개의 숫자 1, 2, 3, 4 중에서 중복을 허락하여 3개를 택해 일렬로 나열하여 세 자리의 자연수를 만들 때, 2와 3으로 동시에 나눠 떨어지는 수 중 제일 큰 값은?",
        "question_en": "When you select three of the four numbers 1, 2, 3, and 4, allowing duplicates, and arrange them in a row to form a three-digit natural number, which number is the largest that is divisible by both 2 and 3?",
        "answer_ko": "444",
        "answer_en": "444",
        "solution_abst_ko": "[OP_LIST_SOL] 1 2 3 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1 2 3 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1\nvar_b = 2\nvar_c = 3\nvar_d = 4\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 2\nlist_c = []\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nvar_g = 3\nlist_d = []\nvar_g = int(var_g)\nfor i in list_c:\n    i = int(i)\n    if i % var_g == 0:\n        list_d.append(i)\nvar_h = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_i = list_e[-var_h]\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 2\nvar_c = 3\nvar_d = 4\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 2\nlist_c = []\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nvar_g = 3\nlist_d = []\nvar_g = int(var_g)\nfor i in list_c:\n    i = int(i)\n    if i % var_g == 0:\n        list_d.append(i)\nvar_h = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_i = list_e[-var_h]\nprint(int(var_i))"
    },
    "7465": {
        "category": "Geometry",
        "question_ko": "가로 16센티미터(㎝), 세로 14센티미터(㎝), 높이가 9센티미터(㎝)인 그릇의 부피와 가로 16센티미터(㎝), 세로 14센티미터(㎝), 높이가 4센티미터(㎝)인 그릇의 부피 차를 구하여라.",
        "question_en": "Find the volume difference between a bowl measuring 16 centimeters (cm) wide, 14 centimeters (cm) long, and 9 centimeters (cm) high, and a bowl measuring 16 centimeters (cm) wide, 14 centimeters (cm) long, and 4 centimeters (cm) high.",
        "answer_ko": "1120",
        "answer_en": "1120",
        "solution_abst_ko": "16 14 [OP_MUL] 9 4 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "16 14 [OP_MUL] 9 4 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 16\nvar_b = 14\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = 4\nvar_f = var_d - var_e\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 16\nvar_b = 14\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = 4\nvar_f = var_d - var_e\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "7466": {
        "category": "Correspondence",
        "question_ko": "서로 다른 수 A, B, C, D가 있습니다. 2×B+B=12, C-B=5, D+C=12, A-D=5입니다. A를 구하시오.",
        "question_en": "There are different numbers A, B, C, and D. 2×B+B=12, C-B=5, D+C=12, A-D=5. Find A.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "12 2×B+B=12 B [OP_NUM_UNK_SOLVER] 5 [OP_ADD] [OP_SUB] 5 [OP_ADD]",
        "solution_abst_en": "12 2×B+B=12 B [OP_NUM_UNK_SOLVER] 5 [OP_ADD] [OP_SUB] 5 [OP_ADD]",
        "solution_code_ko": "var_a = 12\nvar_b = '2×B+B=12'\nvar_c = 'B'\nans_dict = dict()\nvar_b = var_b.replace('×','*')\nvar_b = var_b.replace('x','*')\nvar_b = var_b.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_b):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_b\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_d = ans_dict[var_c]\nvar_e = 5\nvar_f = var_d + var_e\nvar_g = var_a - var_f\nvar_h = 5\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 12\nvar_b = '2×B+B=12'\nvar_c = 'B'\nans_dict = dict()\nvar_b = var_b.replace('×','*')\nvar_b = var_b.replace('x','*')\nvar_b = var_b.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_b):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_b\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_d = ans_dict[var_c]\nvar_e = 5\nvar_f = var_d + var_e\nvar_g = var_a - var_f\nvar_h = 5\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "7467": {
        "category": "Comparison",
        "question_ko": "서로 다른 두 자연수 A와 24는 약수와 배수 관계입니다. A에 해당하는 두 자리 수를 작은 수부터 차례대로 썼을 때 왼쪽에서 3번째 수를 구하시오.",
        "question_en": "Two different natural numbers, A and 24, are either factors or multiples of each other. Find the third number from the left when the two-digit numbers corresponding to A are organized in ascending order.",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "24 [OP_LIST_GET_DIVISOR] 24 99 24 [OP_LIST_ARANGE] [OP_SET_UNION] 10 [OP_LIST_MORE_EQUAL] 3 [OP_LIST_MIN]",
        "solution_abst_en": "24 [OP_LIST_GET_DIVISOR] 24 99 24 [OP_LIST_ARANGE] [OP_SET_UNION] 10 [OP_LIST_MORE_EQUAL] 3 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 24\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 24\nvar_c = 99\nvar_d = 24\nlist_b = [i for i in range(var_b, var_c + 1, var_d)]\nlist_c = list(set(list_a) | set(list_b))\nvar_e = 10\nlist_d = []\nfor i in list_c:\n    if i >= var_e:\n        list_d.append(i)\nvar_f = 3\nlist_e=list_d.copy()\nlist_e.sort()\nvar_g = list_e[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 24\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 24\nvar_c = 99\nvar_d = 24\nlist_b = [i for i in range(var_b, var_c + 1, var_d)]\nlist_c = list(set(list_a) | set(list_b))\nvar_e = 10\nlist_d = []\nfor i in list_c:\n    if i >= var_e:\n        list_d.append(i)\nvar_f = 3\nlist_e=list_d.copy()\nlist_e.sort()\nvar_g = list_e[var_f-1]\nprint(int(var_g))"
    },
    "7468": {
        "category": "Arithmetic calculation",
        "question_ko": "1000원을 내고 210원짜리 연필 몇 자루와 270원짜리 풀 1개를 샀습니다. 거스름돈으로 100원을 받았을 때 연필은 총 몇자루를 샀나요?",
        "question_en": "I paid 1,000 won and bought several pencils for 210 won and a glue for 270 won. How many pencils did you buy in total when you received 100 won in change?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "1000 100 [OP_SUB] 270 1 [OP_MUL] [OP_SUB] 210 [OP_DIV]",
        "solution_abst_en": "1000 100 [OP_SUB] 270 1 [OP_MUL] [OP_SUB] 210 [OP_DIV]",
        "solution_code_ko": "var_a = 1000\nvar_b = 100\nvar_c = var_a - var_b\nvar_d = 270\nvar_e = 1\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 210\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1000\nvar_b = 100\nvar_c = var_a - var_b\nvar_d = 270\nvar_e = 1\nvar_f = var_d * var_e\nvar_g = var_c - var_f\nvar_h = 210\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "7469": {
        "category": "Possibility",
        "question_ko": "1, 0, 5, 8, 6 중에서 3개를 뽑아 한 번씩만 사용하여 세 자리 수를 만들려고 합니다. 만들 수 있는 세 번째로 큰 수와 두 번째로 작은 수의 합을 구하시오.",
        "question_en": "You want to create a three-digit number by picking three of 1, 0, 5, 8, and 6 and using them only once. Find the sum of the third largest and second smallest possible numbers.",
        "answer_ko": "966",
        "answer_en": "966",
        "solution_abst_ko": "[OP_LIST_SOL] 1 0 5 8 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 1 0 5 8 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 1\nvar_b = 0\nvar_c = 5\nvar_d = 8\nvar_e = 6\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 2\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 1\nvar_b = 0\nvar_c = 5\nvar_d = 8\nvar_e = 6\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = 2\nlist_d=list_b.copy()\nlist_d.sort()\nvar_j = list_d[var_i-1]\nvar_k = var_h + var_j\nprint(int(var_k))"
    },
    "7470": {
        "category": "Geometry",
        "question_ko": "가로가 4센티미터(㎝), 세로가 3센티미터(㎝), 높이가 3센티미터(㎝)인 직육면체의 모든 면에 파란색 물감을 칠하였습니다. 그리고 이 직육면체를 한 모서리의 길이가 1센티미터(㎝)인 정육면체 36개로 나누었습니다. 2개의 면이 색칠된 정육면체 조각은 몇 개입니까?",
        "question_en": "Blue paint was applied to all sides of a cuboid measuring 4 centimeters (cm) long, 3 centimeters (cm) wide, and 3 centimeters (cm) high. Then, this cuboid was divided into 36 cubes with each edge of 1 centimeter (cm) long. How many cube pieces have 2 colored faces?",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "4 2 [OP_SUB] 3 2 [OP_SUB] [OP_ADD] 3 2 [OP_SUB] [OP_ADD] 4 [OP_MUL]",
        "solution_abst_en": "4 2 [OP_SUB] 3 2 [OP_SUB] [OP_ADD] 3 2 [OP_SUB] [OP_ADD] 4 [OP_MUL]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = var_c + var_f\nvar_h = 3\nvar_i = 2\nvar_j = var_h - var_i\nvar_k = var_g + var_j\nvar_l = 4\nvar_m = var_k * var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = var_c + var_f\nvar_h = 3\nvar_i = 2\nvar_j = var_h - var_i\nvar_k = var_g + var_j\nvar_l = 4\nvar_m = var_k * var_l\nprint(int(var_m))"
    },
    "7471": {
        "category": "Possibility",
        "question_ko": "철수의 지갑 안에 500원짜리 동전 4개, 100원짜리 동전 2개, 10원짜리 동전 5개가 있습니다. 지불할 수 있는 금액은 모두 몇 가지인지 구하시오. (단, 지불 금액이 0원인 경우는 제외한다.)",
        "question_en": "There are 4 500 won coins, 2 100 won coins, and 5 10 won coins in Cheolsu's wallet. Find how much total amounts of money he can pay. (However, the case where the payment amount is 0 won is excluded.)",
        "answer_ko": "89",
        "answer_en": "89",
        "solution_abst_ko": "4 1 [OP_ADD] 2 1 [OP_ADD] [OP_MUL] 5 1 [OP_ADD] [OP_MUL] 1 [OP_SUB]",
        "solution_abst_en": "4 1 [OP_ADD] 2 1 [OP_ADD] [OP_MUL] 5 1 [OP_ADD] [OP_MUL] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 4\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = var_c * var_f\nvar_h = 5\nvar_i = 1\nvar_j = var_h + var_i\nvar_k = var_g * var_j\nvar_l = 1\nvar_m = var_k - var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 4\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = var_c * var_f\nvar_h = 5\nvar_i = 1\nvar_j = var_h + var_i\nvar_k = var_g * var_j\nvar_l = 1\nvar_m = var_k - var_l\nprint(int(var_m))"
    },
    "7472": {
        "category": "Arithmetic calculation",
        "question_ko": "호석이는 월요일에 88번, 화요일에 75번, 수요일에 62번, 목요일에 91번, 금요일에 80번 줄넘기를 했습니다. 각 요일 중 줄넘기를 가장 많이 한 요일에는 가장 적게 한 요일보다 줄넘기를 몇 회 더 했는지 구하시오.",
        "question_en": "Hoseok jumped the rope during this weekday. If he jumped 88 times, 75 times, 62 times, 91 times, and 80 times from Monday to Friday, find how many times he did more comparing the days he jumped the most and the least.",
        "answer_ko": "29",
        "answer_en": "29",
        "solution_abst_ko": "[OP_LIST_SOL] 88 75 62 91 80 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 88 75 62 91 80 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 88\nvar_b = 75\nvar_c = 62\nvar_d = 91\nvar_e = 80\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 88\nvar_b = 75\nvar_c = 62\nvar_d = 91\nvar_e = 80\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[-var_f]\nvar_h = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))"
    },
    "7473": {
        "category": "Arithmetic calculation",
        "question_ko": "숫자 3, 4로 나누어 떨어질 수 있는 다섯 자리 수 중 가장 작은 수는 무엇입니까?",
        "question_en": "What is the smallest five-digit number divisible by 3 and 4?",
        "answer_ko": "10008",
        "answer_en": "10008",
        "solution_abst_ko": "10000 99999 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 4 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "10000 99999 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 4 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 10000\nvar_b = 99999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 4\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 10000\nvar_b = 99999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 4\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[var_f-1]\nprint(int(var_g))"
    },
    "7474": {
        "category": "Geometry",
        "question_ko": "똑같은 직사각형 모양의 쿠키 두 개가 있습니다. 이 쿠키 두 개를 가로로 이어 붙이면 전체 둘레가 70센티미터(㎝)고, 세로가 15센티미터(㎝)가 됩니다. 쿠키 하나의 넓이를 구하시오.",
        "question_en": "You have two identical rectangular cookies. If you put these two cookies together horizontally, the total circumference will be 70 centimeters (cm) and the height will be 15 centimeters (cm). Find the area of one cookie.",
        "answer_ko": "150",
        "answer_en": "150",
        "solution_abst_ko": "70 2 [OP_DIV] 15 [OP_SUB] 15 [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "70 2 [OP_DIV] 15 [OP_SUB] 15 [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 70\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 15\nvar_e = var_c - var_d\nvar_f = 15\nvar_g = var_e * var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 70\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 15\nvar_e = var_c - var_d\nvar_f = 15\nvar_g = var_e * var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "7475": {
        "category": "Correspondence",
        "question_ko": "사과 12개의 무게가 배 8개의 무게보다 5400그램(g) 더 무겁다. 사과 하나가 530그램(g)이다. 배는 몇 그램(g)인지 구하시오.",
        "question_en": "The weight of 12 apples is 5400 grams (g) heavier than the weight of 8 pears. One apple weighs 530 grams (g). Find how many grams (g) a pear weigh.",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "530 12 [OP_MUL] 5400 [OP_SUB] 8 [OP_DIV]",
        "solution_abst_en": "530 12 [OP_MUL] 5400 [OP_SUB] 8 [OP_DIV]",
        "solution_code_ko": "var_a = 530\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 5400\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 530\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 5400\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "7476": {
        "category": "Correspondence",
        "question_ko": "범현이네 가족은 전체 계란 중 1/4보다 10개 많게 어제 먹었고, 남은 계란 중 3/5보다 5개 적게 오늘 점심에 먹었고, 그 나머지 계란 중 12개는 썩어서 버렸다. 남은 계란이 13개일 때, 범현이네 가족이 처음 가지고 있던 계란의 개수를 구하시오.",
        "question_en": "Beomhyeon's family ate 10 more than 1/4 of the total eggs yesterday, 5 less than 3/5 of the remaining eggs for lunch today, and 12 of the remaining eggs were rotten and so discarded. When there are 13 eggs left, find the number of eggs that Beomhyeon's family had first.",
        "answer_ko": "80",
        "answer_en": "80",
        "solution_abst_ko": "13 12 [OP_ADD] 5 [OP_SUB] 1 3/5 [OP_SUB] [OP_DIV] 10 [OP_ADD] 1 1/4 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "13 12 [OP_ADD] 5 [OP_SUB] 1 3/5 [OP_SUB] [OP_DIV] 10 [OP_ADD] 1 1/4 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 13\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = 0.6\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 10\nvar_k = var_i + var_j\nvar_l = 1\nvar_m = 0.25\nvar_n = var_l - var_m\nvar_o = var_k / var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 13\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c - var_d\nvar_f = 1\nvar_g = 0.6\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nvar_j = 10\nvar_k = var_i + var_j\nvar_l = 1\nvar_m = 0.25\nvar_n = var_l - var_m\nvar_o = var_k / var_n\nprint(int(var_o))"
    },
    "7477": {
        "category": "Comparison",
        "question_ko": "버스를 타기 위해 9명의 학생들이 한 줄로 서 있습니다. 앞에서 3번째에 서 있는 학생과 뒤에서 2번째에 서 있는 학생 사이에는 모두 몇 명의 학생이 서 있습니까?",
        "question_en": "Nine students are standing in a line to get on the bus. How many students are standing between the student standing third from the front and the student standing second from the back?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "9 3 [OP_SUB] 2 [OP_SUB]",
        "solution_abst_en": "9 3 [OP_SUB] 2 [OP_SUB]",
        "solution_code_ko": "var_a = 9\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "7478": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 연속된 자연수의 합이 100입니다. 이 5개의 수 중에서 가장 작은 수를 쓰시오.",
        "question_en": "The sum of 5 consecutive natural numbers is 100. Write the smallest of these 5 numbers.",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "100 5 [OP_DIV] 5 2 [OP_FDIV] [OP_SUB]",
        "solution_abst_en": "100 5 [OP_DIV] 5 2 [OP_FDIV] [OP_SUB]",
        "solution_code_ko": "var_a = 100\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d // var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 100\nvar_b = 5\nvar_c = var_a / var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d // var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "7479": {
        "category": "Correspondence",
        "question_ko": "어떤 소수의 소수점을 왼쪽으로 두 자리 옮기면 원래의 소수보다 1.485만큼 작아집니다. 원래의 소수를 소수점을 포함하여 구하시오.",
        "question_en": "Moving a decimal point two places to the left makes it 1.485 less than the original decimal. Find the original decimal number including the decimal point.",
        "answer_ko": "1.50",
        "answer_en": "1.5",
        "solution_abst_ko": "1.485 0.99 [OP_DIV]",
        "solution_abst_en": "1.485 0.99 [OP_DIV]",
        "solution_code_ko": "var_a = 1.485\nvar_b = 0.99\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 1.485\nvar_b = 0.99\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "7480": {
        "category": "Arithmetic calculation",
        "question_ko": "윤기네 반에서 (가) 꽃을 키우는 학생은 18명, (나) 꽃을 키우는 학생은 24명, (가) 꽃과 (나) 꽃을 모두 키우는 학생은 7명입니다. (가) 꽃과 (나) 꽃을 모두 키우지 않는 학생이 한 명도 없을 때, 윤기네 반 학생은 모두 몇 명입니까?",
        "question_en": "In Yoongi's class, there are 18 students who raise flower (a), 24 students who raise flower (b), and 7 students who raise both flower (a) and flower (b). If there is no student who does not raise any of flower (a) or flower (b), how many students are in Yoongi's class?",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "18 24 [OP_ADD] 7 [OP_SUB]",
        "solution_abst_en": "18 24 [OP_ADD] 7 [OP_SUB]",
        "solution_code_ko": "var_a = 18\nvar_b = 24\nvar_c = var_a + var_b\nvar_d = 7\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 18\nvar_b = 24\nvar_c = var_a + var_b\nvar_d = 7\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "7481": {
        "category": "Arithmetic calculation",
        "question_ko": "끈을 반으로 두 번 접었습니다. 처음 끈의 길이가 12미터(m)였다면, 현재는 몇 미터(m) 입니까?",
        "question_en": "I folded the string in half twice. If the length of the string was 12 meters (m) at first, how many meters (m) is it now?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "12 2 [OP_DIV] 2 [OP_DIV]",
        "solution_abst_en": "12 2 [OP_DIV] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "7482": {
        "category": "Arithmetic calculation",
        "question_ko": "윤기는 꽃을 28송이 가지고 있었습니다. 그중에서 7송이는 은지에게 주고, 9송이는 유나에게 주었습니다. 윤기에게 남은 꽃은 몇 송이입니까?",
        "question_en": "Yoongi had 28 flowers. Among them, 7 were given to Eunji and 9 were given to Yuna. How many flowers are left for Yoongi?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "28 7 [OP_SUB] 9 [OP_SUB]",
        "solution_abst_en": "28 7 [OP_SUB] 9 [OP_SUB]",
        "solution_code_ko": "var_a = 28\nvar_b = 7\nvar_c = var_a - var_b\nvar_d = 9\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 28\nvar_b = 7\nvar_c = var_a - var_b\nvar_d = 9\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "7483": {
        "category": "Arithmetic calculation",
        "question_ko": "민수가 120미터(m)를 달린다. 민수는 초 당 4미터(m)를 달린다고 한다. 민수가 결승점에서 20미터(m) 떨어져 있다면 달린지 몇 초가 지났는지 구하시오.",
        "question_en": "Minsu runs 120 meters (m). Minsu says that he runs 4 meters (m) per second. If Minsu is 20 meters (m) away from the finish line, find how many seconds have elapsed since he ran.",
        "answer_ko": "25",
        "answer_en": "25",
        "solution_abst_ko": "120 20 [OP_SUB] 4 [OP_DIV]",
        "solution_abst_en": "120 20 [OP_SUB] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 120\nvar_b = 20\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 120\nvar_b = 20\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "7484": {
        "category": "Comparison",
        "question_ko": "6개의 숫자 1, 4, 25, 16, 22, 14가 있습니다. 2번째로 큰 숫자는 무엇입니까?",
        "question_en": "There are 6 numbers 1, 4, 25, 16, 22, and 14. What is the 2nd largest number?",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "[OP_LIST_SOL] 1 4 25 16 22 14 [OP_LIST_EOL] 2 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1 4 25 16 22 14 [OP_LIST_EOL] 2 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1\nvar_b = 4\nvar_c = 25\nvar_d = 16\nvar_e = 22\nvar_f = 14\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_h = list_b[-var_g]\nprint(int(var_h))",
        "solution_code_en": "var_a = 1\nvar_b = 4\nvar_c = 25\nvar_d = 16\nvar_e = 22\nvar_f = 14\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_h = list_b[-var_g]\nprint(int(var_h))"
    },
    "7485": {
        "category": "Arithmetic calculation",
        "question_ko": "한 자리들 수 중 홀수들의 평균을 구하시오.",
        "question_en": "Find the average of odd one-digit numbers.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "1 9 [OP_LIST_ODD] [OP_LIST_MEAN]",
        "solution_abst_en": "1 9 [OP_LIST_ODD] [OP_LIST_MEAN]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)/len(list_a)\nprint(int(var_c))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nlist_a = [float(i) for i in list_a]\nvar_c = sum(list_a)/len(list_a)\nprint(int(var_c))"
    },
    "7486": {
        "category": "Possibility",
        "question_ko": "숫자 카드 1, 2, 3을 사용하여 네 자리 수를 만들려고 한다. 같은 숫자 카드를 여러 번 사용해도 된다고 할 때, 만들어지는 모든 수들의 합을 구하여라.",
        "question_en": "You want to make a four-digit number using the number cards 1, 2, and 3. Assuming you can use the same number card multiple times, find the sum of all the numbers that are made.",
        "answer_ko": "179982",
        "answer_en": "179982",
        "solution_abst_ko": "[OP_LIST_SOL] 1 2 3 [OP_LIST_EOL] 4 [OP_LIST_GET_PRODUCT] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 1 2 3 [OP_LIST_EOL] 4 [OP_LIST_GET_PRODUCT] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 2\nvar_c = 3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 2\nvar_c = 3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint(int(var_e))"
    },
    "7487": {
        "category": "Comparison",
        "question_ko": "[OP_LIST_SOL] 영빈 수정 [OP_LIST_EOL] [OP_LIST_SOL] 100 16.23 [OP_DIV] 100 16.19 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "question_en": "Youngbin and Sujeong had a race to pick up coins faster. If it took Yeongbin 16.23 seconds and Sujeong 16.19 seconds to pick up all the coins, who wins?",
        "answer_ko": "수정",
        "answer_en": "Sujeong",
        "solution_abst_ko": "[OP_LIST_SOL] 영빈 수정 [OP_LIST_EOL] [OP_LIST_SOL] 16.23 16.19 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Youngbin Sujeong [OP_LIST_EOL] [OP_LIST_SOL] 16.23 16.19 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '영빈'\nvar_b = '수정'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 16.23\nvar_d = 16.19\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Youngbin'\nvar_b = 'Sujeong'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 16.23\nvar_d = 16.19\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "7488": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이와 석진이는 연필을 각각 12자루씩 가지고 있었습니다. 그중에서 몇 자루씩 사용하고, 정국이는 남은 연필 중 4자루를 석진이에게 주었더니 두 사람이 가지고 있는 연필의 수는 각각 7자루가 되었습니다. 석진이가 사용한 연필은 몇 자루입니까?",
        "question_en": "Jungkook and Seokjin each had 12 pencils. After using a few of them, Jungkook gave 4 of the remaining pencils to Seokjin, and the number of pencils they both had became 7 each. How many pencils did Seokjin use?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "12 7 [OP_SUB] 4 [OP_ADD]",
        "solution_abst_en": "12 7 [OP_SUB] 4 [OP_ADD]",
        "solution_code_ko": "var_a = 12\nvar_b = 7\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 7\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7489": {
        "category": "Comparison",
        "question_ko": "예림이는 0.65킬로그램(㎏)의 우유를 마셨고, 찬우는 0.645킬로그램(㎏)의 우유를 마셨습니다. 우유를 더 많이 마신 사람은 누구일까요?",
        "question_en": "Yerim drank 0.65 kg (kg) of milk, and Chanwoo drank 0.645 kg (kg) of milk. Who drank more milk?",
        "answer_ko": "예림",
        "answer_en": "Yerim",
        "solution_abst_ko": "[OP_LIST_SOL] 예림 찬우 [OP_LIST_EOL] [OP_LIST_SOL] 0.65 0.645 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yerim Chanwoo [OP_LIST_EOL] [OP_LIST_SOL] 0.65 0.645 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '예림'\nvar_b = '찬우'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.65\nvar_d = 0.645\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Yerim'\nvar_b = 'Chanwoo'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.65\nvar_d = 0.645\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "7490": {
        "category": "Arithmetic calculation",
        "question_ko": "75, 91, 83, 72가 있습니다. 가장 큰 수와 2번째로 작은 수의 합은 얼마입니까?",
        "question_en": "There are 75, 91, 83, and 72. What is the sum of the largest number and the second smallest number?",
        "answer_ko": "166",
        "answer_en": "166",
        "solution_abst_ko": "[OP_LIST_SOL] 75 91 83 72 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 75 91 83 72 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 75\nvar_b = 91\nvar_c = 83\nvar_d = 72\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 75\nvar_b = 91\nvar_c = 83\nvar_d = 72\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f + var_h\nprint(int(var_i))"
    },
    "7491": {
        "category": "Correspondence",
        "question_ko": "713에서 어떤 수를 빼야 할 것을 잘못하여 더했더니 928이 되었습니다. 바르게 계산하면 얼마인지 구해 보시오.",
        "question_en": "I should have subtracted a number from 713, but instead mistakenly added 713 and got 928 as a result. Find out how much it is if you had calculated it correctly.",
        "answer_ko": "498",
        "answer_en": "498",
        "solution_abst_ko": "713 928 713 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "713 928 713 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 713\nvar_b = 928\nvar_c = 713\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 713\nvar_b = 928\nvar_c = 713\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "7492": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 10, 11, 12, 13이 있습니다. 그 중에서 가장 큰 수와 2번째로 큰 수의 차는 얼마입니까?",
        "question_en": "Consider there are four numbers of 10, 11, 12, and 13. What is the answer for the largest number minus the second largest number?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = var_f - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = var_f - var_h\nprint(int(var_i))"
    },
    "7493": {
        "category": "Arithmetic calculation",
        "question_ko": "생선가게에서 새벽에 잡은 생선을 오전에 3/5만큼 팔았습니다. 오후에는 오전에 팔고 남은 생선과 새로 잡은 생선을 합한 180마리를 전부 팔았습니다. 오전에 판 생선의 수와 오후에 판 생선의 수가 다르지 않다면 새벽에 잡은 생선은 몇 마리입니까?",
        "question_en": "The fish shop sold 3/5 of the fish caught at dawn in the morning. In the afternoon, all 180 fish, including the fish left from the morning and the newly caught fish, were sold. If the number of fish sold in the morning is not different from the number of fish sold in the afternoon, how many fish were caught at dawn?",
        "answer_ko": "300",
        "answer_en": "300",
        "solution_abst_ko": "180 3/5 [OP_DIV]",
        "solution_abst_en": "180 3/5 [OP_DIV]",
        "solution_code_ko": "var_a = 180\nvar_b = 0.6\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 180\nvar_b = 0.6\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "7494": {
        "category": "Correspondence",
        "question_ko": "수조에 열대어와 잉어가 모두 합쳐 52마리가 있습니다. 잉어가 37마리 있다면, 열대어는 몇 마리 있습니까?",
        "question_en": "There are 52 tropical fish and koi in the tank. If there are 37 koi, how many tropical fish are there?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "52 37 [OP_SUB]",
        "solution_abst_en": "52 37 [OP_SUB]",
        "solution_code_ko": "var_a = 52\nvar_b = 37\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 52\nvar_b = 37\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "7495": {
        "category": "Arithmetic calculation",
        "question_ko": "빵이 58개 있습니다. 빵은 우유보다 18개 더 많고, 과자보다 27개 더 적습니다. 빵, 우유, 과자는 모두 몇 개입니까?",
        "question_en": "There are 58 slices of bread. The slices of bread are 18 more than bottles of milk and 27 less than cookies. How many slices of bread, bottles of milk, and cookies are there in total?",
        "answer_ko": "183",
        "answer_en": "183",
        "solution_abst_ko": "58 58 18 [OP_SUB] [OP_ADD] 58 27 [OP_ADD] [OP_ADD]",
        "solution_abst_en": "58 58 18 [OP_SUB] [OP_ADD] 58 27 [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 58\nvar_b = 58\nvar_c = 18\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 58\nvar_g = 27\nvar_h = var_f + var_g\nvar_i = var_e + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 58\nvar_b = 58\nvar_c = 18\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 58\nvar_g = 27\nvar_h = var_f + var_g\nvar_i = var_e + var_h\nprint(int(var_i))"
    },
    "7496": {
        "category": "Geometry",
        "question_ko": "가로가 세로의 3배인 직사각형 모양의 농장이 있습니다. 이 농장의 세로가 0.6킬로미터(㎞)일 때, 농장의 넓이는 몇 ㎢입니까?",
        "question_en": "There is a rectangular farm that is three times as wide as it is length. If the length of this farm is 0.6 km (km), how many square kilometers (km2) is the farm?",
        "answer_ko": "1.08",
        "answer_en": "1.08",
        "solution_abst_ko": "0.6 3 [OP_MUL] 0.6 [OP_MUL]",
        "solution_abst_en": "0.6 3 [OP_MUL] 0.6 [OP_MUL]",
        "solution_code_ko": "var_a = 0.6\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 0.6\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.6\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 0.6\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "7497": {
        "category": "Geometry",
        "question_ko": "정사각형을 크기가 같은 2개의 직사각형으로 나누었습니다. 나누어진 직사각형 1개의 네 변의 길이의 합이 42센티미터(㎝)일 때 처음 정사각형의 한 변의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "The square is divided into 2 rectangles of equal size. If the sum of the lengths of the four sides of the divided rectangle is 42 centimeters (cm), how many centimeters (cm) is the side of the first square?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "42 2 [OP_DIV] 2 1 [OP_ADD] [OP_DIV] 2 [OP_MUL]",
        "solution_abst_en": "42 2 [OP_DIV] 2 1 [OP_ADD] [OP_DIV] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 42\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = var_c / var_f\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 42\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = var_c / var_f\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "7498": {
        "category": "Correspondence",
        "question_ko": "등식 4A+B3=68이 성립한다고 합니다. 이 때, A에 들어갈 수 있는 숫자는 무엇인가요?",
        "question_en": "Equation of two-digt numbers 4A+B3=68 is said to hold. At this time, what number can go into A?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "4A+B3=68 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "4A+B3=68 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '4A+B3=68'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '4A+B3=68'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "7499": {
        "category": "Arithmetic calculation",
        "question_ko": "15명 초과의 사람이 타야 출발하는 비행기가 있습니다. 현재 비행기 안에 있는 사람이 9명이라면 적어도 몇 명이 더 타야 출발할 수 있는지 구하시오.",
        "question_en": "Some flight requires more than 15 people to depart. If there are 9 people currently on the plane, find how many more people need to board before departure.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "15 1 [OP_ADD] 9 [OP_SUB]",
        "solution_abst_en": "15 1 [OP_ADD] 9 [OP_SUB]",
        "solution_code_ko": "var_a = 15\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "7500": {
        "category": "Geometry",
        "question_ko": "(가)와 (나)는 모두 직육면체 모양의 통입니다. (가) 통은 가로가 3센티미터(㎝), 세로가 4센티미터(㎝), 높이가 5센티미터(㎝)이고, (나) 통은 가로 4센티미터(㎝), 세로 2센티미터(㎝), 높이가 8센티미터(㎝)입니다. (나) 통에 담겨있는 물의 높이를 쟀을 때 1.5센티미터(㎝)였고, 이 물을 모두 (가) 통에 옮겨 담았다면, (가) 통의 물의 높이는 몇 센티미터(㎝)가 되겠습니까?",
        "question_en": "(A) and (B) are both rectangular parallelepiped-shaped tanks. (A) is 4 centimeters (cm) long, 3 centimeters (cm) wide, and 5 centimeters (cm) high, and (B) is 4 centimeters (cm) long, 2 centimeters (cm) wide, and 8 centimeters (cm) high. When the height of the water in (B) was measured as 1.5 centimeters (cm), and all of this water was transferred to (a) the barrel, how high would the water in (A) be in centimeters (cm)?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "4 2 [OP_MUL] 1.5 [OP_MUL] 4 3 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "4 2 [OP_MUL] 1.5 [OP_MUL] 4 3 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 4\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 1.5\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = 3\nvar_h = var_f * var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 4\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 1.5\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = 3\nvar_h = var_f * var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "7501": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 24를 빼려고 합니다. 잘못하여 2를 곱했을 때의 답이 50이라면 바르게 계산한 결과는 얼마일까요?",
        "question_en": "You want to subtract 24 from a number. If the answer when multiplied by 2 incorrectly is 50, what is the result of calculating correctly?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "50 2 [OP_DIV] 24 [OP_SUB]",
        "solution_abst_en": "50 2 [OP_DIV] 24 [OP_SUB]",
        "solution_code_ko": "var_a = 50\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 24\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 50\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 24\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "7502": {
        "category": "Arithmetic calculation",
        "question_ko": "동환이는 사탕 138개를 한 봉지에 18개씩 담아 포장하고 남은 것을 먹었습니다. 동환이가 먹은 사탕은 몇 개일까요?",
        "question_en": "Donghwan packed 138 candies in a bag, 18 each, and ate the leftovers. How many candies did Donghwan eat?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "138 18 [OP_MOD]",
        "solution_abst_en": "138 18 [OP_MOD]",
        "solution_code_ko": "var_a = 138\nvar_b = 18\nvar_c = var_a % var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 138\nvar_b = 18\nvar_c = var_a % var_b\nprint(int(var_c))"
    },
    "7503": {
        "category": "Possibility",
        "question_ko": "0, 1, 2, 3, 4의 수가 각각 적힌 5장의 카드에서 2장을 뽑아 두 자리 정수를 만들 때 홀수는 모두 몇 개인지 구하시오",
        "question_en": "To make a two-digit integer by drawing two cards from five cards with the numbers 0, 1, 2, 3, and 4 written on them, find how many odd numbers there are.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 4 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 2 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 4 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 2 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 2\nlist_c = []\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if i % var_g == 0:\n        list_c.append(i)\nlist_d = list(set(list_b) - set(list_c))\nvar_h = len(list_d)\nprint(int(var_h))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 2\nlist_c = []\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if i % var_g == 0:\n        list_c.append(i)\nlist_d = list(set(list_b) - set(list_c))\nvar_h = len(list_d)\nprint(int(var_h))"
    },
    "7504": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 수 2, 3, 8, 9로 나누어 떨어질 수 있는 수 중 가장 작은 다섯 자리 수는 무엇입니까?",
        "question_en": "What is the smallest five-digit number divisible by the four numbers 2, 3, 8, and 9?",
        "answer_ko": "10008",
        "answer_en": "10008",
        "solution_abst_ko": "10000 99999 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "10000 99999 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 10000\nvar_b = 99999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 3\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = 1\nlist_f=list_e.copy()\nlist_f.sort()\nvar_i = list_f[var_h-1]\nprint(int(var_i))",
        "solution_code_en": "var_a = 10000\nvar_b = 99999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 2\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 3\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 8\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nvar_g = int(var_g)\nfor i in list_d:\n    i = int(i)\n    if i % var_g == 0:\n        list_e.append(i)\nvar_h = 1\nlist_f=list_e.copy()\nlist_f.sort()\nvar_i = list_f[var_h-1]\nprint(int(var_i))"
    },
    "7505": {
        "category": "Arithmetic calculation",
        "question_ko": "가져간 돈의 절반으로 공책을 사고, 연필을 사는데 나머지 돈의 절반을 썼습니다. 남은 돈이 750원이라면 정국이가 처음에 가지고 간 돈은 얼마입니까?",
        "question_en": "He bought a notebook with half the money he brought, and spent half the money on a pencil. If the remaining money is 750 won, how much money did Jungkook bring at the beginning?",
        "answer_ko": "3000",
        "answer_en": "3000",
        "solution_abst_ko": "750 4 [OP_MUL]",
        "solution_abst_en": "750 4 [OP_MUL]",
        "solution_code_ko": "var_a = 750\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 750\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "7506": {
        "category": "Arithmetic calculation",
        "question_ko": "집합 A의 원소는 1, 3, 5이고, 집합 B의 원소는 2, 5일 때 A 차집합 B의 원소의 개수를 구하시오.",
        "question_en": "Find the number of elements in set A minus set B when the elements in set A are 1, 3, and 5, and in set B are 2 and 5. ",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 1 3 5 [OP_LIST_EOL] [OP_LIST_SOL] 2 5 [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 3 5 [OP_LIST_EOL] [OP_LIST_SOL] 2 5 [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nvar_e = 5\nlist_b= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nvar_e = 5\nlist_b= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nlist_c = list(set(list_a) - set(list_b))\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "7507": {
        "category": "Possibility",
        "question_ko": "다섯 개의 숫자 0, 1, 2, 3, 4 중에서 3개를 골라 세 자리의 짝수를 만들었다. 같은 수를 여러 번 사용해도 된다면, 만들 수 있는 모든 짝수의 총합은 얼마인가?",
        "question_en": "You chose three numbers among 0, 1, 2, 3, and 4 to make a three-digit even number. If you can use the same number multiple times, what is the sum of all even numbers that can be made?",
        "answer_ko": "16320",
        "answer_en": "16320",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 2 [OP_LIST_DIVISIBLE] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 2 [OP_LIST_DIVISIBLE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 2\nlist_c = []\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if i % var_g == 0:\n        list_c.append(i)\nlist_c = [float(i) for i in list_c]\nvar_h = sum(list_c)\nprint(int(var_h))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 2\nlist_c = []\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if i % var_g == 0:\n        list_c.append(i)\nlist_c = [float(i) for i in list_c]\nvar_h = sum(list_c)\nprint(int(var_h))"
    },
    "7508": {
        "category": "Arithmetic calculation",
        "question_ko": "민영이는 유정이보다 구슬을 27개 더 많이 가지고 있습니다. 민영이가 은지에게 구슬을 9개 주면 민영, 은지 두 사람이 가지고 있는 구슬은 45개로 같아집니다. 민영, 유정, 은지 세 사람이 가지고 있는 구슬은 모두 몇 개입니까?",
        "question_en": "Minyoung has 27 more marbles than Yoojeong. If Minyoung gives Eunji 9 marbles, both Minyoung and Eunji have 45 marbles. How many marbles do Minyoung, Yoojeong, and Eunji have?",
        "answer_ko": "117",
        "answer_en": "117",
        "solution_abst_ko": "45 27 [OP_SUB] 9 [OP_ADD] 27 [OP_ADD] 45 27 [OP_SUB] 9 [OP_ADD] [OP_ADD] 45 9 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "45 27 [OP_SUB] 9 [OP_ADD] 27 [OP_ADD] 45 27 [OP_SUB] 9 [OP_ADD] [OP_ADD] 45 9 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 45\nvar_b = 27\nvar_c = var_a - var_b\nvar_d = 9\nvar_e = var_c + var_d\nvar_f = 27\nvar_g = var_e + var_f\nvar_h = 45\nvar_i = 27\nvar_j = var_h - var_i\nvar_k = 9\nvar_l = var_j + var_k\nvar_m = var_g + var_l\nvar_n = 45\nvar_o = 9\nvar_p = var_n - var_o\nvar_q = var_m + var_p\nprint(int(var_q))",
        "solution_code_en": "var_a = 45\nvar_b = 27\nvar_c = var_a - var_b\nvar_d = 9\nvar_e = var_c + var_d\nvar_f = 27\nvar_g = var_e + var_f\nvar_h = 45\nvar_i = 27\nvar_j = var_h - var_i\nvar_k = 9\nvar_l = var_j + var_k\nvar_m = var_g + var_l\nvar_n = 45\nvar_o = 9\nvar_p = var_n - var_o\nvar_q = var_m + var_p\nprint(int(var_q))"
    },
    "7509": {
        "category": "Arithmetic calculation",
        "question_ko": "대영이는 300원짜리 지우개와 500원짜리 연필을 모두 더하여 8개를 샀습니다. 그리고 3000원을 냈다면 대영이가 산 연필은 모두 몇 개일까요?",
        "question_en": "Daeyoung bought 8 materials in total, including an eraser of 300 won and a pencil of 500 won. If he paid 3,000 won, how many pencils did Daeyoung buy?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "3000 300 8 [OP_MUL] [OP_SUB] 500 300 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "3000 300 8 [OP_MUL] [OP_SUB] 500 300 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 3000\nvar_b = 300\nvar_c = 8\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 500\nvar_g = 300\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 3000\nvar_b = 300\nvar_c = 8\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 500\nvar_g = 300\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "7510": {
        "category": "Possibility",
        "question_ko": "사과 7개를 서로 다른 2마리의 원숭이에게 나누어 주려고 합니다. 원숭이는 적어도 사과 1개는 받습니다. 사과를 나누어 주는 방법은 모두 몇 가지입니까?",
        "question_en": "You want to distribute 7 apples to 2 different monkeys. The monkey takes at least 1 apple. How many ways are there to distribute apples?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "7 2 1 [OP_MUL] [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "7 2 1 [OP_MUL] [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 7\nvar_b = 2\nvar_c = 1\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 7\nvar_b = 2\nvar_c = 1\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "7511": {
        "category": "Comparison",
        "question_ko": "회색 고양이와 흰색 고양이 중에는 회색 고양이가 무겁습니다. 회색 고양이가 검은색 고양이보다 가볍고, 가장 가벼운 고양이는 노란색 고양이입니다. 가장 무거운 고양이는 무슨 색입니까?",
        "question_en": "Among gray and white cat, gray cat is the heaviest. Gray cat is lighter than black cat, and the lightest is the yellow cat. What color is the heaviest cat?",
        "answer_ko": "검은색",
        "answer_en": "black",
        "solution_abst_ko": "[OP_LIST_SOL] 회색 흰색 검은색 노란색 [OP_LIST_EOL] [OP_LIST_SOL] 회색 흰색 > 회색 검은색 < 노란색 회색 < 노란색 흰색 < 노란색 검은색 < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] gray white black yellow [OP_LIST_EOL] [OP_LIST_SOL] gray white > gray black < yellow gray < yellow white < yellow black < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '회색'\nvar_b = '흰색'\nvar_c = '검은색'\nvar_d = '노란색'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = '회색'\nvar_f = '흰색'\nvar_g = '>'\nvar_h = '회색'\nvar_i = '검은색'\nvar_j = '<'\nvar_k = '노란색'\nvar_l = '회색'\nvar_m = '<'\nvar_n = '노란색'\nvar_o = '흰색'\nvar_p = '<'\nvar_q = '노란색'\nvar_r = '검은색'\nvar_s = '<'\nlist_b= []\nif \"/\" in str(var_s):\n    var_s = eval(str(var_s))\nlist_b.append(var_s)\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_t = 1\nvar_u = list_c[var_t-1]\nprint(var_u)",
        "solution_code_en": "var_a = 'gray'\nvar_b = 'white'\nvar_c = 'black'\nvar_d = 'yellow'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'gray'\nvar_f = 'white'\nvar_g = '>'\nvar_h = 'gray'\nvar_i = 'black'\nvar_j = '<'\nvar_k = 'yellow'\nvar_l = 'gray'\nvar_m = '<'\nvar_n = 'yellow'\nvar_o = 'white'\nvar_p = '<'\nvar_q = 'yellow'\nvar_r = 'black'\nvar_s = '<'\nlist_b= []\nif \"/\" in str(var_s):\n    var_s = eval(str(var_s))\nlist_b.append(var_s)\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_t = 1\nvar_u = list_c[var_t-1]\nprint(var_u)"
    },
    "7512": {
        "category": "Correspondence",
        "question_ko": "A, B는 한 자리 수이다. 5보다 3 큰 숫자는 A이고 B는 A에서 2를 뺀 숫자일때 A+B를 구하여라.",
        "question_en": "A is the number 3 greater than 5 and B is A minus 2. WhenA and B are single-digit numbers, find what A+B is.",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "5 3 [OP_ADD] 5 3 [OP_ADD] 2 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "5 3 [OP_ADD] 5 3 [OP_ADD] 2 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = 2\nvar_h = var_f - var_g\nvar_i = var_c + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 5\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = 2\nvar_h = var_f - var_g\nvar_i = var_c + var_h\nprint(int(var_i))"
    },
    "7513": {
        "category": "Correspondence",
        "question_ko": "32를 빼야한는데 실수로 23을 어떤 수에서 빼서 14가 나왔습니다. 어떤 수는 얼마입니까?",
        "question_en": "I need to subtract 32, but I accidentally subtracted 23 from some number and got 14. What number is it?",
        "answer_ko": "37",
        "answer_en": "37",
        "solution_abst_ko": "14 23 [OP_ADD]",
        "solution_abst_en": "14 23 [OP_ADD]",
        "solution_code_ko": "var_a = 14\nvar_b = 23\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 14\nvar_b = 23\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "7514": {
        "category": "Arithmetic calculation",
        "question_ko": "미술시간에 미진이가 가로 32센티미터(㎝), 세로 74센티미터(㎝)인 직사각형 모양의 색종이를 잘라 남는 부분 없이 똑같은 정사각형 모양을 여러 장 만들려고 할 때, 만들 수 있는 가장 큰 정사각형은 몇 장입니까?",
        "question_en": "In art class, when Mijin cuts a piece of colored paper in the shape of a rectangle measuring 32 centimeters (cm) wide and 74 centimeters (cm) long, and wants to make several identical squares without any leftovers, how many squares can be the largest? ?",
        "answer_ko": "592",
        "answer_en": "592",
        "solution_abst_ko": "32 32 74 [OP_GCD] [OP_FDIV] 74 32 74 [OP_GCD] [OP_FDIV] [OP_MUL]",
        "solution_abst_en": "32 32 74 [OP_GCD] [OP_FDIV] 74 32 74 [OP_GCD] [OP_FDIV] [OP_MUL]",
        "solution_code_ko": "var_a = 32\nvar_b = 32\nvar_c = 74\nvar_d = math.gcd(int(var_c), int(var_b))\nvar_e = var_a // var_d\nvar_f = 74\nvar_g = 32\nvar_h = 74\nvar_i = math.gcd(int(var_h), int(var_g))\nvar_j = var_f // var_i\nvar_k = var_e * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 32\nvar_b = 32\nvar_c = 74\nvar_d = math.gcd(int(var_c), int(var_b))\nvar_e = var_a // var_d\nvar_f = 74\nvar_g = 32\nvar_h = 74\nvar_i = math.gcd(int(var_h), int(var_g))\nvar_j = var_f // var_i\nvar_k = var_e * var_j\nprint(int(var_k))"
    },
    "7515": {
        "category": "Correspondence",
        "question_ko": "A는 한 자리 자연수입니다. 다음과 같이 한 자리 수끼리의 곱셈식 A×A×A=21A에서 A가 1의 자리 숫자일 때, A를 구하시오.",
        "question_en": "A is a single-digit natural number. Given the equation of the multiplication between single-digit numbers A×A×A=21A (21A is three-digit number), find A when A is a 1-digit number.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "A×A×A=21A A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A×A×A=21A A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A×A×A=21A'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A×A×A=21A'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "7516": {
        "category": "Geometry",
        "question_ko": "어느 직사각형과 정사각형의 넓이는 같으며, 직사각형의 두 변은 각각 9센티미터(㎝), 16센티미터(㎝)입니다. 이 때, 정사각형 한 변의 길이는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "A rectangle and a square have the same area, and the sides of the rectangle are 9 centimeters (cm) and 16 centimeters (cm), respectively. In this case, find the length of one side of the square in centimeters (cm).",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "9 16 [OP_MUL] 1/2 [OP_POW]",
        "solution_abst_en": "9 16 [OP_MUL] 1/2 [OP_POW]",
        "solution_code_ko": "var_a = 9\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 16\nvar_c = var_a * var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nprint(int(var_e))"
    },
    "7517": {
        "category": "Comparison",
        "question_ko": "미란이, 정아, 민수는 각각 색종이를 6장, 13장, 10장씩 가지고 있었습니다. 세 사람 중 가지고 있는 색종이의 수가 가장 적은 사람은 누구입니까?",
        "question_en": "Miran, Junga, and Minsu each had 6, 13, and 10 pieces of colored paper. Of the three people, who has the least number of colored paper?",
        "answer_ko": "미란",
        "answer_en": "Miran",
        "solution_abst_ko": "[OP_LIST_SOL] 미란 정아 민수 [OP_LIST_EOL] [OP_LIST_SOL] 6 13 10 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Miran Junga Minsu [OP_LIST_EOL] [OP_LIST_SOL] 6 13 10 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '미란'\nvar_b = '정아'\nvar_c = '민수'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 6\nvar_e = 13\nvar_f = 10\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Miran'\nvar_b = 'Junga'\nvar_c = 'Minsu'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 6\nvar_e = 13\nvar_f = 10\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "7518": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 15.25 센티미터(㎝) 인 색 테이프 20 장을 겹치게 이어 붙이려고 합니다. 이어 붙인 색 테이프의 전체 길이가 248 센티미터(㎝) 가 되도록 하려면 모두 몇 센티미터(㎝) 씩 겹치게 이어 붙여야 합니까?",
        "question_en": "You are going to glue together 20 sheets of colored tape, every 15.25 centimeters (cm) long, overlapping each other. How many centimeters (cm) do you have to overlap in order to make the total length of the spliced color tape 248 centimeters (cm)?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "15.25 248 15.25 [OP_SUB] 20 1 [OP_SUB] [OP_DIV] [OP_SUB]",
        "solution_abst_en": "15.25 248 15.25 [OP_SUB] 20 1 [OP_SUB] [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 15.25\nvar_b = 248\nvar_c = 15.25\nvar_d = var_b - var_c\nvar_e = 20\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d / var_g\nvar_i = var_a - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 15.25\nvar_b = 248\nvar_c = 15.25\nvar_d = var_b - var_c\nvar_e = 20\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d / var_g\nvar_i = var_a - var_h\nprint(int(var_i))"
    },
    "7519": {
        "category": "Possibility",
        "question_ko": "숫자 카드 1, 2, 3, 4 중 3장을 뽑아 만들 수 있는 세 자리 자연수의 개수를 구하시오.",
        "question_en": "Draw 3 of the number cards 1, 2, 3, and 4 and find the number of three-digit natural numbers that can be made.",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "[OP_LIST_SOL] 1 2 3 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1 2 3 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 2\nvar_c = 3\nvar_d = 4\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 2\nvar_c = 3\nvar_d = 4\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "7520": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 46을 빼야 하는데 잘못하여 64를 뺐더니 122가 되었습니다. 바르게 계산한 결과를 구하시오.",
        "question_en": "You need to subtract 46 from a certain number, but mistakenly subtracted 64, and got 122. Find the result of the correct calculation.",
        "answer_ko": "140",
        "answer_en": "140",
        "solution_abst_ko": "122 64 [OP_ADD] 46 [OP_SUB]",
        "solution_abst_en": "122 64 [OP_ADD] 46 [OP_SUB]",
        "solution_code_ko": "var_a = 122\nvar_b = 64\nvar_c = var_a + var_b\nvar_d = 46\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 122\nvar_b = 64\nvar_c = var_a + var_b\nvar_d = 46\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "7521": {
        "category": "Possibility",
        "question_ko": "7, 2, 5, 0, 1을 한 번씩만 사용하여 다섯 자리 수를 만드려고 합니다. 이때 가장 작은 수를 쓰세요.",
        "question_en": "You want to create a five-digit number using 7, 2, 5, 0, and 1 only once. Write the smallest number in this case.",
        "answer_ko": "10257",
        "answer_en": "10257",
        "solution_abst_ko": "[OP_LIST_SOL] 7 2 5 0 1 [OP_LIST_EOL] 5 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 7 2 5 0 1 [OP_LIST_EOL] 5 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 7\nvar_b = 2\nvar_c = 5\nvar_d = 0\nvar_e = 1\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 5\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nprint(int(var_h))",
        "solution_code_en": "var_a = 7\nvar_b = 2\nvar_c = 5\nvar_d = 0\nvar_e = 1\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 5\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_f))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nprint(int(var_h))"
    },
    "7522": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 기계는 시간당 1개씩 물품을 만든다. 이 기계를 1년 동안 쉬지않고 가동하면 몇 개를 만드는지 구하시오.",
        "question_en": "Some machines make one item per hour. Find how many units this machine makes if it runs non-stop for one year.",
        "answer_ko": "8760",
        "answer_en": "8760",
        "solution_abst_ko": "24 365 [OP_MUL]",
        "solution_abst_en": "24 365 [OP_MUL]",
        "solution_code_ko": "var_a = 24\nvar_b = 365\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 24\nvar_b = 365\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "7523": {
        "category": "Correspondence",
        "question_ko": "주머니에 901개의 사탕이 있습니다. 사탕은 학급의 모든 학생들에게 균등하게 분배되었습니다. 각 학생은 53개의 사탕을 받았고 사탕은 하나도 남지 않았습니다. 수업의 총 학생 수를 구하십시오.",
        "question_en": "There are 901 candies in the bag. Candies were equally distributed among all students in the class. Each student received 53 candies, and nothing left. Find the total number of students in the class.",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "1 53 901 [OP_DIV] [OP_DIV]",
        "solution_abst_en": "1 53 901 [OP_DIV] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 53\nvar_c = 901\nvar_d = var_b / var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 53\nvar_c = 901\nvar_d = var_b / var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "7524": {
        "category": "Comparison",
        "question_ko": "지성이는 9/25리터(L)의 우유를 마셨고 영표는 0.41리터(L)를 마셨습니다. 우유를 가장 많이 마신 사람은?",
        "question_en": "Ji-Sung drank 9/25 liters (L) of milk and Young-pyo drank 0.41 liters (L). Who drank the most milk?",
        "answer_ko": "영표",
        "answer_en": "Young-pyo",
        "solution_abst_ko": "[OP_LIST_SOL] 지성 영표 [OP_LIST_EOL] [OP_LIST_SOL] 9 25 [OP_DIV] 0.41 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Ji-Sung Young-pyo [OP_LIST_EOL] [OP_LIST_SOL] 9 25 [OP_DIV] 0.41 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '지성'\nvar_b = '영표'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 9\nvar_d = 25\nvar_e = var_c / var_d\nvar_f = 0.41\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Ji-Sung'\nvar_b = 'Young-pyo'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 9\nvar_d = 25\nvar_e = var_c / var_d\nvar_f = 0.41\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "7525": {
        "category": "Arithmetic calculation",
        "question_ko": "유찬이의 한 걸음은 0.75미터(m)입니다. 유찬이가 1분에 70걸음씩 걸어서 13분 동안 걸었다면, 유찬이는 모두 몇 미터(m)를 걸은 것인지 구하시오.",
        "question_en": "One step of Yu-chan is 0.75 meters (m). If Yu-chan walked for 13 minutes by walking 70 steps per minute, find how many meters (m) he walked in total.",
        "answer_ko": "682.50",
        "answer_en": "682.5",
        "solution_abst_ko": "0.75 70 [OP_MUL] 13 [OP_MUL]",
        "solution_abst_en": "0.75 70 [OP_MUL] 13 [OP_MUL]",
        "solution_code_ko": "var_a = 0.75\nvar_b = 70\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.75\nvar_b = 70\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "7526": {
        "category": "Possibility",
        "question_ko": "정환이는 색연필 4종류와 볼펜 3종류 중 각각 1개씩을 선택하려고 합니다. 이 때 선택할 수 있는 수는 몇 가지인지 구하세요.",
        "question_en": "Jeonghwan wants to choose one of the four types of colored pencils and one of the three types of ballpoint pens. Find the number of ways you can choose.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "4 1 [OP_COMB] 3 1 [OP_COMB] [OP_MUL]",
        "solution_abst_en": "4 1 [OP_COMB] 3 1 [OP_COMB] [OP_MUL]",
        "solution_code_ko": "var_a = 4\nvar_b = 1\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nvar_d = 3\nvar_e = 1\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f / (i+1)\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 1\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nvar_d = 3\nvar_e = 1\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f / (i+1)\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "7527": {
        "category": "Arithmetic calculation",
        "question_ko": "한 사람이 종이학을 1시간에 8개씩 만든다고 합니다. 5명이 종이학 200개를 만들려면 몇 시간이 걸립니까?",
        "question_en": "It is said that one person makes 8 origami cranes per hour. How many hours does it take 5 people to make 200 origami cranes?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "200 8 5 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "200 8 5 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 200\nvar_b = 8\nvar_c = 5\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 200\nvar_b = 8\nvar_c = 5\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "7528": {
        "category": "Arithmetic calculation",
        "question_ko": "두 자리 수 중 3의 배수는 모두 몇 개 있습니까?",
        "question_en": "How many two-digit numbers are multiples of 3?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "10 99 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "10 99 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 99\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "7529": {
        "category": "Geometry",
        "question_ko": "윗변의 길이가 아랫변의 길이보다 6 센티미터(㎝) 짧고, 높이가 8 센티미터(㎝)인 사다리꼴의 넓이가 72제곱센티미터(㎠)일 때, 이 사다리꼴의 윗변의 길이를 구하시오.",
        "question_en": "If the length of the upper side is 6 centimeters (cm) shorter than the length of the lower side and the area of the trapezoid is 8 centimeters (cm) and the area is 72 cm (cm2), find the length of the upper side of the trapezoid.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "72 2 [OP_MUL] 8 [OP_DIV] 6 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "72 2 [OP_MUL] 8 [OP_DIV] 6 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 72\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c / var_d\nvar_f = 6\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 72\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c / var_d\nvar_f = 6\nvar_g = var_e - var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "7530": {
        "category": "Geometry",
        "question_ko": "밑에 놓인 면의 둘레가 32센티미터(㎝)이고 가로와 세로의 길이가 같은 직육면체가 높이가 9센티미터(㎝)이면 부피는 몇 세제곱센티미터(㎤)입니까?",
        "question_en": "If the rectangular parallelepiped's perimeter of the underlying face is 32 centimeters (cm), its width and length are the same, and its height of it is 9 centimeters (cm), what is the volume in cubic centimeters (cm3)?",
        "answer_ko": "576",
        "answer_en": "576",
        "solution_abst_ko": "32 4 [OP_DIV] 2 [OP_POW] 9 [OP_MUL]",
        "solution_abst_en": "32 4 [OP_DIV] 2 [OP_POW] 9 [OP_MUL]",
        "solution_code_ko": "var_a = 32\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 9\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 32\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 9\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "7531": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 9까지의 홀수 중 6미만인 수들의 평균은 얼마입니까?",
        "question_en": "What is the average of the odd numbers from 1 to 9 that are less than 6?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "1 9 [OP_LIST_ODD] 6 [OP_LIST_LESS] [OP_LIST_MEAN]",
        "solution_abst_en": "1 9 [OP_LIST_ODD] 6 [OP_LIST_LESS] [OP_LIST_MEAN]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 6\nlist_b = []\nfor i in list_a:\n    if i < var_c:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_d = sum(list_b)/len(list_b)\nprint(int(var_d))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 6\nlist_b = []\nfor i in list_a:\n    if i < var_c:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_d = sum(list_b)/len(list_b)\nprint(int(var_d))"
    },
    "7532": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 4를 나누려고 합니다. 잘못하여 42를 더했을 때의 답이 50이라면 바르게 계산한 결과는 얼마일까요?",
        "question_en": "You want to divide a number by 4. If the answer when adding 42 incorrectly is 50, what is the correct calculation result?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "50 42 [OP_SUB] 4 [OP_DIV]",
        "solution_abst_en": "50 42 [OP_SUB] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 50\nvar_b = 42\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 50\nvar_b = 42\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "7533": {
        "category": "Correspondence",
        "question_ko": "시원이가 가진 리본의 길이가 서준이가 가진 리본의 길이보다 8.8미터(m)만큼 더 길다. 서준이가 시원이에게 자신이 가진 리본을 4.3미터(m)만큼 잘라서 주면 두 명이 가진 리본 길이의 차이는 얼마가 되는지 구하시오.",
        "question_en": "The length of Siwon's ribbon is 8.8 meters longer than Seojun's. If Seojun cuts his own ribbon 4.3 meters (m) and gives it to Siwon, find out what the difference between the lengths of the two people's ribbons.",
        "answer_ko": "17.4",
        "answer_en": "17.4",
        "solution_abst_ko": "8.8 4.3 [OP_ADD] 4.3 [OP_ADD]",
        "solution_abst_en": "8.8 4.3 [OP_ADD] 4.3 [OP_ADD]",
        "solution_code_ko": "var_a = 8.8\nvar_b = 4.3\nvar_c = var_a + var_b\nvar_d = 4.3\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 8.8\nvar_b = 4.3\nvar_c = var_a + var_b\nvar_d = 4.3\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "7534": {
        "category": "Geometry",
        "question_ko": "삼각 기둥이 3개 있다. 옆면이 아닌 면의 개수와 옆면의 개수의 합을 구하시오.",
        "question_en": "There are 3 triangular prisms. Find the sum of the number of non-side and side faces.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "3 2 [OP_MUL] 3 3 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "3 2 [OP_MUL] 3 3 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "7535": {
        "category": "Arithmetic calculation",
        "question_ko": "승화는 춘천으로 여행을 가기 위해서 고속버스와 버스를 이용하였고, 120킬로미터(㎞) 떨어진 춘천에 1시간 50분 만에 도착하였습니다. 처음엔 고속버스를 이용하였고 나중에는 1시간 10분 동안 버스를 탔습니다. 이 버스는 40.8킬로미터(㎞)를 가는 데 6리터(L)의 휘발유를 사용하였고, 승화가 버스를 타고 있는 동안 14리터(L)의 휘발유를 사용했다면, 승화가 고속버스를 이용하여 1분 동안 이동한 거리는 몇 킬로미터(㎞)입니까? (고속버스에서 버스로 갈아타기 위한 시간과 거리는 고려하지 않습니다.)",
        "question_en": "Seunghwa took an express bus and a general bus to travel to Chuncheon, and arrived in Chuncheon, 120 kilometers (km) away, in 1 hour and 50 minutes. At first, she used the express bus, and later took the general bus for 1 hour and 10 minutes. This general bus used 6 liters of gasoline to travel 40.8 kilometers, and if Seunghwa used 14 liters of gasoline while taking the general bus, how many kilometers (km) Seunghwa moved by express bus for 1 minute? (The time and distance to transfer from the express bus to the bus are not considered.)",
        "answer_ko": "0.62",
        "answer_en": "0.62",
        "solution_abst_ko": "120 40.8 6 [OP_DIV] 14 [OP_MUL] [OP_SUB] 1 60 [OP_MUL] 50 [OP_ADD] 1 60 [OP_MUL] 10 [OP_ADD] [OP_SUB] [OP_DIV]",
        "solution_abst_en": "120 40.8 6 [OP_DIV] 14 [OP_MUL] [OP_SUB] 1 60 [OP_MUL] 50 [OP_ADD] 1 60 [OP_MUL] 10 [OP_ADD] [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 120\nvar_b = 40.8\nvar_c = 6\nvar_d = var_b / var_c\nvar_e = 14\nvar_f = var_d * var_e\nvar_g = var_a - var_f\nvar_h = 1\nvar_i = 60\nvar_j = var_h * var_i\nvar_k = 50\nvar_l = var_j + var_k\nvar_m = 1\nvar_n = 60\nvar_o = var_m * var_n\nvar_p = 10\nvar_q = var_o + var_p\nvar_r = var_l - var_q\nvar_s = var_g / var_r\nprint('{:.2f}'.format(round(var_s+1e-10,2)))",
        "solution_code_en": "var_a = 120\nvar_b = 40.8\nvar_c = 6\nvar_d = var_b / var_c\nvar_e = 14\nvar_f = var_d * var_e\nvar_g = var_a - var_f\nvar_h = 1\nvar_i = 60\nvar_j = var_h * var_i\nvar_k = 50\nvar_l = var_j + var_k\nvar_m = 1\nvar_n = 60\nvar_o = var_m * var_n\nvar_p = 10\nvar_q = var_o + var_p\nvar_r = var_l - var_q\nvar_s = var_g / var_r\nprint('{:.2f}'.format(round(var_s+1e-10,2)))"
    },
    "7536": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중에서 3번째로 큰 수와 2번째로 큰 수의 곱은 얼마입니까?",
        "question_en": "Three numbers 10, 11 and 12 are given. What is the product of the 3rd largest and the 2nd largest number?",
        "answer_ko": "110",
        "answer_en": "110",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 3 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 3 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = var_e * var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = var_e * var_g\nprint(int(var_h))"
    },
    "7537": {
        "category": "Geometry",
        "question_ko": "혜진이는 한 변의 길이가 30센티미터(㎝)인 정사각형 모양의 6장의 종이를 풀로 붙여 한 줄로 이으려고 합니다. 이을 때 7센티미터(㎝)씩 겹치게 되었습니다. 이어진 종이의 넓이는 몇 제곱센티미터(㎠)입니까?",
        "question_en": "Hyejin tries to connect six pieces of paper in the shape of a square with a side length of 30 centimeters (cm) by gluing them together. When gluing was done, they overlapped each other by 7 centimeters (cm). How many square centimeters (cm²) is the area of the connected papers?",
        "answer_ko": "4350",
        "answer_en": "4350",
        "solution_abst_ko": "30 6 [OP_MUL] 7 6 1 [OP_SUB] [OP_MUL] [OP_SUB] 30 [OP_MUL]",
        "solution_abst_en": "30 6 [OP_MUL] 7 6 1 [OP_SUB] [OP_MUL] [OP_SUB] 30 [OP_MUL]",
        "solution_code_ko": "var_a = 30\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = 6\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_c - var_h\nvar_j = 30\nvar_k = var_i * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 30\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = 6\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_c - var_h\nvar_j = 30\nvar_k = var_i * var_j\nprint(int(var_k))"
    },
    "7538": {
        "category": "Comparison",
        "question_ko": "민영이와 친구들이 키가 큰 순서대로 한 줄로 서 있습니다. 민영이는 키가 큰 쪽에서 2번째이고, 작은 쪽에서 4번째입니다. 줄을 서 있는 사람은 모두 몇 명입니까?",
        "question_en": "Minyoung and her friends are standing in a line in order of height. Minyoung is 2nd on the tall side and 4th on the short side. How many people are in line?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "2 4 [OP_ADD] 1 [OP_SUB]",
        "solution_abst_en": "2 4 [OP_ADD] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "7539": {
        "category": "Possibility",
        "question_ko": "찬열이는 어버이날을 맞아 부모님께 카네이션 꽃다발을 선물하기로 했습니다. 카네이션은 빨간색, 분홍색, 하얀색, 세 종류가 있고 총 다섯 송이로 꽃다발을 만들 때, 한 종류 당 최소 한 송이씩은 포함되게 하려면 만들 수 있는 꽃다발의 경우의 수를 구하시오.",
        "question_en": "Chanyeol decided to present a bouquet of carnations to his parents for Parents' Day. There are three types of carnations: red, pink, and white. When making a bouquet with a total of five carnations, find the number of possible bouquets to include at least one of each type.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "1 3 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_NUM2SUM] 5 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 3 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_NUM2SUM] 5 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 5\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 5\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))"
    },
    "7540": {
        "category": "Correspondence",
        "question_ko": "윤기는 어떤 수에 7을 빼려고 합니다. 하지만 실수로 9를 더했더니 결과는 30이 되었습니다. 바르게 계산한 결과를 구하세요.",
        "question_en": "Yoongi is trying to subtract 7 from a number. But when I accidentally added 9, the result was 30. Find the correct calculation result.",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "30 9 [OP_SUB] 7 [OP_SUB]",
        "solution_abst_en": "30 9 [OP_SUB] 7 [OP_SUB]",
        "solution_code_ko": "var_a = 30\nvar_b = 9\nvar_c = var_a - var_b\nvar_d = 7\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 30\nvar_b = 9\nvar_c = var_a - var_b\nvar_d = 7\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "7541": {
        "category": "Correspondence",
        "question_ko": "윤기는 두 자리 수에서 네 자리 수를 빼던 중, 네 자리 수의 일의 자리 숫자 9를 6으로 잘못 보았고, 두 자리 수의 일의 자리 숫자와 십의 자리 숫자를 바꾸어 23이라고 잘못 보았습니다. 이때, 윤기가 구한 차가 -1299라고 하면, 네 자리 수는 무엇인가요?",
        "question_en": "While Yoongi was subtracting the four-digit number from the two-digit number, he mistook the one-digit number 9 for the four-digit number as 2, and then changed the ones-digit number and the tens-digit number for the two-digit number to get 23. From this, Yoongi got -1299, what is the four-digit number?",
        "answer_ko": "1279",
        "answer_en": "1279",
        "solution_abst_ko": "23 1299 [OP_SUB] 2 9 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "23 1299 [OP_SUB] 2 9 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 23\nvar_b = 1299\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 23\nvar_b = 1299\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "7542": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 학교의 3학년 학생 수는 41명이고, 남학생은 여학생보다 3명이 더 많습니다. 남학생은 몇 명입니까?",
        "question_en": "A school has 41 students in the third grade, and there are 3 more boys than girls. How many male students are there?",
        "answer_ko": "22",
        "answer_en": "22",
        "solution_abst_ko": "41 3 [OP_SUB] 2 [OP_DIV] 3 [OP_ADD]",
        "solution_abst_en": "41 3 [OP_SUB] 2 [OP_DIV] 3 [OP_ADD]",
        "solution_code_ko": "var_a = 41\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 3\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 41\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 3\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "7543": {
        "category": "Arithmetic calculation",
        "question_ko": "15000원을 모두 사용하여 1000원짜리 연필과 1300원짜리 볼펜을 모두 12자루 샀습니다. 구매한 연필은 몇 자루입니까?",
        "question_en": "You used all 15,000 won to buy 12 pencils for 1,000 won and ballpoint pens for 1,300 won. How many pencils have you purchased?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "1300 12 [OP_MUL] 15000 [OP_SUB] 1300 1000 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "1300 12 [OP_MUL] 15000 [OP_SUB] 1300 1000 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 1300\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 15000\nvar_e = var_c - var_d\nvar_f = 1300\nvar_g = 1000\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1300\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 15000\nvar_e = var_c - var_d\nvar_f = 1300\nvar_g = 1000\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "7544": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 20/9센티미터(㎝)이고 세 변의 길이가 모두 같은 삼각형이 있습니다. 이 삼각형과 둘레가 같은 오각형의 모든 변의 길이가 같다면, 한 변의 길이는 얼마일지 구하시오.",
        "question_en": "Consider a triangle with one side measuring 20/9 centimeters (cm) with all the same length. If all sides of a pentagon, which has the same perimeter as this triangle, have the same length, what is the length of one side?",
        "answer_ko": "1.33",
        "answer_en": "1.33",
        "solution_abst_ko": "20/9 3 [OP_MUL] 5 [OP_DIV]",
        "solution_abst_en": "20/9 3 [OP_MUL] 5 [OP_DIV]",
        "solution_code_ko": "var_a = 2.2222222222222223\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 2.2222222222222223\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 5\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "7545": {
        "category": "Arithmetic calculation",
        "question_ko": "은지는 (가) 시험 12문제와 (나) 시험 15문제를 풀었습니다. (가) 시험은 8문제를 틀렸고, (나) 시험은 (가 시험보다 2문제를 더 많이 틀렸습니다. 은지가 (가) 시험과 (나) 시험에서 맞춘 문제는 모두 몇 문제인지 구하시오",
        "question_en": "Eunji solved 12 questions in the exam A and 15 questions in the exam B. She got 8 questions wrong in exam A, and got 2 more questions wrong in exam B than in exam A. How many questions did Eunji get right in both exams in total?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "4 15 12 4 [OP_SUB] 2 [OP_ADD] [OP_SUB] [OP_ADD]",
        "solution_abst_en": "4 15 12 4 [OP_SUB] 2 [OP_ADD] [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 4\nvar_b = 15\nvar_c = 12\nvar_d = 4\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e + var_f\nvar_h = var_b - var_g\nvar_i = var_a + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 4\nvar_b = 15\nvar_c = 12\nvar_d = 4\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e + var_f\nvar_h = var_b - var_g\nvar_i = var_a + var_h\nprint(int(var_i))"
    },
    "7546": {
        "category": "Arithmetic calculation",
        "question_ko": "두 나눗셈 46.2 / 7, 1.8 / 0.6의 몫의 곱을 구해보세요",
        "question_en": "Find the product of the quotients of two divisions 46.2 / 7 and 1.8 / 0.6.",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "46.2 7 [OP_FDIV] 1.8 0.6 [OP_FDIV] [OP_MUL]",
        "solution_abst_en": "46.2 7 [OP_FDIV] 1.8 0.6 [OP_FDIV] [OP_MUL]",
        "solution_code_ko": "var_a = 46.2\nvar_b = 7\nvar_c = var_a // var_b\nvar_d = 1.8\nvar_e = 0.6\nvar_f = var_d // var_e\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 46.2\nvar_b = 7\nvar_c = var_a // var_b\nvar_d = 1.8\nvar_e = 0.6\nvar_f = var_d // var_e\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "7547": {
        "category": "Geometry",
        "question_ko": "미호는 한 변의 길이가 6미터(m)인 정사각형 모양의 땅을 가지고 있습니다. 이 땅의 각 변을 1미터(m)씩 늘려 새 땅을 갖게 되었습니다. 새 땅은 몇 제곱미터(㎡)의 넓이만큼 더 늘어났습니까?",
        "question_en": "Miho has a square-shaped piece of land with a side measuring 6 meters (m). Each side of this land was increased by 1 meter (m), so that he got more piece of land. By how many square meters (m2) did the area of the land increase?",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "6 1 [OP_ADD] 2 [OP_POW] 6 2 [OP_POW] [OP_SUB]",
        "solution_abst_en": "6 1 [OP_ADD] 2 [OP_POW] 6 2 [OP_POW] [OP_SUB]",
        "solution_code_ko": "var_a = 6\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 6\nvar_g = 2\nvar_h = var_f ** var_g\nvar_i = var_e - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 6\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c ** var_d\nvar_f = 6\nvar_g = 2\nvar_h = var_f ** var_g\nvar_i = var_e - var_h\nprint(int(var_i))"
    },
    "7548": {
        "category": "Arithmetic calculation",
        "question_ko": "민준이는 작년 한 해 동안 0.2미터(m) 컸고 올해 한 해 동안 1/10미터(m)가 컸습니다. 작년 1월 1일에 민준이의 키가 1.1미터(m)였다면, 민준이의 현재 키는 몇 미터(m)입니까?",
        "question_en": "Minjun grew 0.2 meters (m) last year and 1/10 meter (m) this year. If Minjun's height was 1.1 meters (m) on January 1 last year, how tall is Minjun's height in meters (m) now?",
        "answer_ko": "1.40",
        "answer_en": "1.4",
        "solution_abst_ko": "0.2 1.1 [OP_ADD] 1/10 [OP_ADD]",
        "solution_abst_en": "0.2 1.1 [OP_ADD] 1/10 [OP_ADD]",
        "solution_code_ko": "var_a = 0.2\nvar_b = 1.1\nvar_c = var_a + var_b\nvar_d = 0.1\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.2\nvar_b = 1.1\nvar_c = var_a + var_b\nvar_d = 0.1\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "7549": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 가장 작은 수와 2번째로 작은 수의 합은 얼마입니까?",
        "question_en": "There are five numbers: 10, 11, 12, 13, and 14. What is the sum of the smallest number and the second smallest number?",
        "answer_ko": "21",
        "answer_en": "21",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))"
    },
    "7550": {
        "category": "Possibility",
        "question_ko": "주어진 숫자 카드 7, 5, 2를 한 번 사용하여 520보다 크고 710보다 작은 수를 만들 때 백 자리에 들어갈 수 있는 수를 쓰십시오.",
        "question_en": "Write a number that can fit in the hundredth place when using the given number cards 7, 5, and 2 once to make a number greater than 520 and less than 710.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "[OP_LIST_SOL] 7 5 2 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 520 [OP_LIST_MORE] 710 [OP_LIST_LESS] 1 [OP_LIST_GET] [OP_NUM2LIST] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] 7 5 2 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 520 [OP_LIST_MORE] 710 [OP_LIST_LESS] 1 [OP_LIST_GET] [OP_NUM2LIST] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 7\nvar_b = 5\nvar_c = 2\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 520\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = 710\nlist_d = []\nfor i in list_c:\n    if i < var_f:\n        list_d.append(i)\nvar_g = 1\nvar_h = list_d[var_g-1]\nlist_e = []\nvar_h = int(var_h)\nwhile var_h//10 > 0:\n    list_e.append(var_h%10)\n    var_h = var_h//10\nlist_e.append(var_h%10)\nlist_e = list_e[::-1]\nvar_i = 1\nvar_j = list_e[var_i-1]\nprint(int(var_j))",
        "solution_code_en": "var_a = 7\nvar_b = 5\nvar_c = 2\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 520\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = 710\nlist_d = []\nfor i in list_c:\n    if i < var_f:\n        list_d.append(i)\nvar_g = 1\nvar_h = list_d[var_g-1]\nlist_e = []\nvar_h = int(var_h)\nwhile var_h//10 > 0:\n    list_e.append(var_h%10)\n    var_h = var_h//10\nlist_e.append(var_h%10)\nlist_e = list_e[::-1]\nvar_i = 1\nvar_j = list_e[var_i-1]\nprint(int(var_j))"
    },
    "7551": {
        "category": "Comparison",
        "question_ko": "제니는 주스를 9/5리터(L) 마셨습니다. 지수는 주스를 제니보다 0.2리터(L) 더 적게 마셨고, 로희는 지수보다 3/10리터(L) 더 많이 마셨습니다. 주스를 가장 적게 마신 사람은 누구입니까?",
        "question_en": "Jennie drank 9/5 liters (L) of juice. Jisoo drank 0.2 liters (L) less juice than Jennie, and Rohee drank 3/10 liters (L) more than Jisoo. Who drank the least juice?",
        "answer_ko": "지수",
        "answer_en": "Jisoo",
        "solution_abst_ko": "[OP_LIST_SOL] 제니 지수 로희 [OP_LIST_EOL] [OP_LIST_SOL] 9/5 9/5 0.2 [OP_SUB] 9/5 0.2 [OP_SUB] 3/10 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jennie Jisoo Rohee [OP_LIST_EOL] [OP_LIST_SOL] 9/5 9/5 0.2 [OP_SUB] 9/5 0.2 [OP_SUB] 3/10 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '제니'\nvar_b = '지수'\nvar_c = '로희'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1.8\nvar_e = 1.8\nvar_f = 0.2\nvar_g = var_e - var_f\nvar_h = 1.8\nvar_i = 0.2\nvar_j = var_h - var_i\nvar_k = 0.3\nvar_l = var_j + var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[var_m-1]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'Jennie'\nvar_b = 'Jisoo'\nvar_c = 'Rohee'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1.8\nvar_e = 1.8\nvar_f = 0.2\nvar_g = var_e - var_f\nvar_h = 1.8\nvar_i = 0.2\nvar_j = var_h - var_i\nvar_k = 0.3\nvar_l = var_j + var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[var_m-1]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "7552": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 10을 뺐더니 15가 되었습니다. 어떤 수에 5를 더한 값은 얼마입니까?",
        "question_en": "Subtracting 10 from a number gives you 15. Find the value of 5 added to the number.",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "15 10 [OP_ADD] 5 [OP_ADD]",
        "solution_abst_en": "15 10 [OP_ADD] 5 [OP_ADD]",
        "solution_code_ko": "var_a = 15\nvar_b = 10\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 10\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7553": {
        "category": "Correspondence",
        "question_ko": "지민이는 연산식 A8+3B=99 에서 A를 까먹어서 호석이에게 도움을 요청했다. 호석이가 올바른 값을 도출했다고 할 때, 호석이가 구한 A는 무엇인가?",
        "question_en": "Jimin forgot the A in the two-digit numbers summation, A8+3B=99, so he asked Hoseok for help. Supposing that Hoseok finds out the correct value, what is A that Hoseok found?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "A8+3B=99 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A8+3B=99 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A8+3B=99'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A8+3B=99'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "7554": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 62를 더해야 하는데 잘못하여 26을 더했더니 61이 되었습니다. 바르게 계산한 결과를 구하시오.",
        "question_en": "I need to add 62 to a specific number, but I mistakenly added 26 and I got 61. Find the result of the correct calculation.",
        "answer_ko": "97",
        "answer_en": "97",
        "solution_abst_ko": "61 26 [OP_SUB] 62 [OP_ADD]",
        "solution_abst_en": "61 26 [OP_SUB] 62 [OP_ADD]",
        "solution_code_ko": "var_a = 61\nvar_b = 26\nvar_c = var_a - var_b\nvar_d = 62\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 61\nvar_b = 26\nvar_c = var_a - var_b\nvar_d = 62\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7555": {
        "category": "Arithmetic calculation",
        "question_ko": "공이 5개가 담겨져 있는 상자를 3개 가지고 있을 때 공의 개수는 몇 개입니까?",
        "question_en": "Find the number of balls if you have 3 boxes containing 5 balls for each.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "5 3 [OP_MUL]",
        "solution_abst_en": "5 3 [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "7556": {
        "category": "Arithmetic calculation",
        "question_ko": "사과가 9개씩 들어있는 상자를 7개 샀습니다. 이 중에서 7개의 사과는 썩어서 버리고, 남은 것을 8명이 똑같이 나누었습니다. 한 사람이 받은 사과는 몇 개입니까?",
        "question_en": "You bought 7 boxes that each contain 9 apples. Of these, 7 apples were rotten and discarded, and the remaining was equally divided among 8 people. How many apples did one person receive?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "9 7 [OP_MUL] 7 [OP_SUB] 8 [OP_DIV]",
        "solution_abst_en": "9 7 [OP_MUL] 7 [OP_SUB] 8 [OP_DIV]",
        "solution_code_ko": "var_a = 9\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 9\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "7557": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2 중에서 0.4보다 큰 수는 몇 개입니까?",
        "question_en": "How many numbers among 0.8 and 1/2 are greater than 0.4?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 [OP_LIST_EOL] 0.4 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 [OP_LIST_EOL] 0.4 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.4\nlist_b = []\nfor i in list_a:\n    if i > var_c:\n        list_b.append(i)\nvar_d = len(list_b)\nprint(int(var_d))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.4\nlist_b = []\nfor i in list_a:\n    if i > var_c:\n        list_b.append(i)\nvar_d = len(list_b)\nprint(int(var_d))"
    },
    "7558": {
        "category": "Comparison",
        "question_ko": "6개의 사과를 가지고 있던 정국이는 3개의 사과를 더 받았습니다. 윤기는 4개의 사과를 가지고 있을 때, 누가 더 사과를 많이 가지고 있습니까?",
        "question_en": "Jungkook, who already had 6 apples, got 3 more. When Yoongi has 4 apples, who has more apples?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 윤기 [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_ADD] 4 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Yoongi [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_ADD] 4 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '윤기'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = 4\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Yoongi'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = 4\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "7559": {
        "category": "Comparison",
        "question_ko": "지민, 정국, 태형이가 줄넘기 시합을 하였습니다. 지민이는 51등을 했고, 정국이는 53등을 했습니다. 태형이는 정국이보다 잘했지만 지민이보다는 못했습니다. 태형이의 등수는 몇 등입니까?",
        "question_en": "Jimin, Jungkook, and Taehyung had a jumping rope competition. Jimin placed 51st and Jungkook placed 53rd. Taehyung did better than Jungkook but worse than Jimin. What is Taehyung's rank?",
        "answer_ko": "52",
        "answer_en": "52",
        "solution_abst_ko": "51 53 [OP_ADD] 2 [OP_FDIV]",
        "solution_abst_en": "51 53 [OP_ADD] 2 [OP_FDIV]",
        "solution_code_ko": "var_a = 51\nvar_b = 53\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 51\nvar_b = 53\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "7560": {
        "category": "Arithmetic calculation",
        "question_ko": "1번째 날에 책을 30권 팔았습니다. 2번째 날에는 1번째 날에 판 책의 수의 5배만큼 팔았습니다. 2번째 날 판 책은 1번째 날 판 책보다 몇 권 더 많습니까?",
        "question_en": "You sold 30 books on the first day. On the second day, they sold 5 times the number of books sold on the first day. How many more books were sold on Day 2 than on Day 1?",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "30 5 [OP_MUL] 30 [OP_SUB]",
        "solution_abst_en": "30 5 [OP_MUL] 30 [OP_SUB]",
        "solution_code_ko": "var_a = 30\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 30\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 30\nvar_b = 5\nvar_c = var_a * var_b\nvar_d = 30\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "7561": {
        "category": "Possibility",
        "question_ko": "4, 8, 1, 2 중 3개를 사용하여 일의 자리 숫자가 2인 수들 중에 가장 작은 수는 무엇입니까?",
        "question_en": "Using 3 of 4, 8, 1, and 2, what is the smallest number with a ones digit of 2?",
        "answer_ko": "142",
        "answer_en": "142",
        "solution_abst_ko": "[OP_LIST_SOL] 4 8 1 2 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 2 [OP_LIST_SEARCH_FIXED_DIGIT] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 4 8 1 2 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 2 [OP_LIST_SEARCH_FIXED_DIGIT] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 4\nvar_b = 8\nvar_c = 1\nvar_d = 2\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nvar_g = 2\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nprint(int(var_i))",
        "solution_code_en": "var_a = 4\nvar_b = 8\nvar_c = 1\nvar_d = 2\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nvar_g = 2\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nfor i in list_b:\n    i = int(i)\n    if (i//var_f)%10 == var_g:\n        list_c.append(i)\nvar_h = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nprint(int(var_i))"
    },
    "7562": {
        "category": "Arithmetic calculation",
        "question_ko": "한 학생이 1시간에 8문제를 풀 수 있다고 합니다. 하루에 5시간을 문제 풀이에 쓴다면 200문제를 풀기 위해 며칠이 걸립니까?",
        "question_en": "A student can solve 8 problems per hour. If she spends 5 hours a day solving problems, how many days will it take her to solve 200 problems?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "200 8 5 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "200 8 5 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 200\nvar_b = 8\nvar_c = 5\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 200\nvar_b = 8\nvar_c = 5\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "7563": {
        "category": "Arithmetic calculation",
        "question_ko": "희주네 학교 학생은 500명입니다. 이 중에서 사이다를 좋아하는 학생은 337명이고, 콜라를 좋아하는 학생은 289명입니다. 사이다와 콜라를 둘 다 좋아하지 않는 학생이 56명일 때, 사이다와 콜라를 모두 좋아하는 학생은 몇 명인가요?",
        "question_en": "Heeju's school has 500 students. Of these, 337 students like soda and 289 students like coke. If there are 56 students who neither like soda nor coke, how many students like both soda and coke?",
        "answer_ko": "182",
        "answer_en": "182",
        "solution_abst_ko": "289 337 [OP_ADD] 500 56 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "289 337 [OP_ADD] 500 56 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 289\nvar_b = 337\nvar_c = var_a + var_b\nvar_d = 500\nvar_e = 56\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 289\nvar_b = 337\nvar_c = var_a + var_b\nvar_d = 500\nvar_e = 56\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "7564": {
        "category": "Geometry",
        "question_ko": "한 꼭짓점에서 그을 수 있는 대각선의 개수가 6개인 다각형이 있습니다. 이 다각형의 꼭짓점의 개수를 구하시오.",
        "question_en": "There is a polygon that has 6 diagonals that can be drawn from a vertex. Find the number of vertices of this polygon.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "6 3 [OP_ADD]",
        "solution_abst_en": "6 3 [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 3\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 3\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "7565": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 2.345를 더해야 할 것을 잘못하여 빼었더니 1.234가 되었습니다. 바르게 계산하면 얼마입니까?",
        "question_en": "I had to add a number by 2.345 but instead subtracted it to get 1.234. What is the correctly calculated value?",
        "answer_ko": "5.92",
        "answer_en": "5.92",
        "solution_abst_ko": "1.234 2.345 [OP_ADD] 2.345 [OP_ADD]",
        "solution_abst_en": "1.234 2.345 [OP_ADD] 2.345 [OP_ADD]",
        "solution_code_ko": "var_a = 1.234\nvar_b = 2.345\nvar_c = var_a + var_b\nvar_d = 2.345\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 1.234\nvar_b = 2.345\nvar_c = var_a + var_b\nvar_d = 2.345\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "7566": {
        "category": "Arithmetic calculation",
        "question_ko": "우유가 8640개 있습니다. 우유를 한 봉투에 12개씩 나누어 담고, 한 상자에 6개의 봉투씩 담았습니다. 상자의 개수는 총 몇 개입니까?",
        "question_en": "You have 8640 bottles of milk. The bottles of milk were divided into 12 per bag and 6 bags per box. How many boxes are there in total?",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "8640 12 [OP_DIV] 6 [OP_DIV]",
        "solution_abst_en": "8640 12 [OP_DIV] 6 [OP_DIV]",
        "solution_code_ko": "var_a = 8640\nvar_b = 12\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8640\nvar_b = 12\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "7567": {
        "category": "Possibility",
        "question_ko": "윤기는 사과, 배 두 종류의 과일을 사려고 합니다. 과일 4개를 사는 방법은 모두 몇 가지인가요?",
        "question_en": "Yoongi wants to buy two types of fruit, apples and pears. How many ways are there to buy 4 fruits?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "2 1 [OP_SUB] 4 [OP_ADD] 4 [OP_COMB]",
        "solution_abst_en": "2 1 [OP_SUB] 4 [OP_ADD] 4 [OP_COMB]",
        "solution_code_ko": "var_a = 2\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 4\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g / (i+1)\nprint(int(var_g))",
        "solution_code_en": "var_a = 2\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 4\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g / (i+1)\nprint(int(var_g))"
    },
    "7568": {
        "category": "Arithmetic calculation",
        "question_ko": "108의 약수도 되고 4의 배수도 되는 수 중에서 가장 큰 수는 얼마입니까?",
        "question_en": "What is the largest number that is both a factor of 108 and a multiple of 4?",
        "answer_ko": "108",
        "answer_en": "108",
        "solution_abst_ko": "108 [OP_LIST_GET_DIVISOR] 4 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_abst_en": "108 [OP_LIST_GET_DIVISOR] 4 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 108\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 4\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_d = list_c[-var_c]\nprint(int(var_d))",
        "solution_code_en": "var_a = 108\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 4\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_d = list_c[-var_c]\nprint(int(var_d))"
    },
    "7569": {
        "category": "Comparison",
        "question_ko": "은지는 물을 0.5리터(L) 마셨고 유정이는 물을 7/10리터(L) 마셨습니다. 유나는 물을 6/10리터(L) 마셨을 때 물을 가장 많이 마신 사람은 누구인가요?",
        "question_en": "Eunji drank 0.5 liters (L) of water and Yujeong drank 7/10 liters (L) of water. Who drank the most water when Yuna drank 6/10 liters of water?",
        "answer_ko": "유정",
        "answer_en": "Yujeong",
        "solution_abst_ko": "[OP_LIST_SOL] 유정 은지 유나 [OP_LIST_EOL] [OP_LIST_SOL] 7 10 [OP_DIV] 0.5 6 10 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yujeong Eunji Yuna [OP_LIST_EOL] [OP_LIST_SOL] 7 10 [OP_DIV] 0.5 6 10 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '유정'\nvar_b = '은지'\nvar_c = '유나'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 7\nvar_e = 10\nvar_f = var_d / var_e\nvar_g = 0.5\nvar_h = 6\nvar_i = 10\nvar_j = var_h / var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'Yujeong'\nvar_b = 'Eunji'\nvar_c = 'Yuna'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 7\nvar_e = 10\nvar_f = var_d / var_e\nvar_g = 0.5\nvar_h = 6\nvar_i = 10\nvar_j = var_h / var_i\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "7570": {
        "category": "Geometry",
        "question_ko": "한 모서리가 2센티미터(㎝)인 쌓기나무 125개로 정육면체를 쌓았습니다. 이 정육면체의 부피는 몇 세제곱센티미터(㎤)입니까?",
        "question_en": "A cube is built with 125 small cubes with an edge of 2 centimeters (cm). What is the volume of this cube in cubic centimeters (cm3)?",
        "answer_ko": "1000",
        "answer_en": "1000",
        "solution_abst_ko": "2 3 [OP_POW] 125 [OP_MUL]",
        "solution_abst_en": "2 3 [OP_POW] 125 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = var_a ** var_b\nvar_d = 125\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = var_a ** var_b\nvar_d = 125\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "7571": {
        "category": "Arithmetic calculation",
        "question_ko": "32의 약수들 중에서 8의 약수가 아닌 수의 개수를 구하시오.",
        "question_en": "Find the number of factors of 32 that are not factors of 8.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "32 [OP_LIST_GET_DIVISOR] 8 [OP_LIST_GET_DIVISOR] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_abst_en": "32 [OP_LIST_GET_DIVISOR] 8 [OP_LIST_GET_DIVISOR] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 32\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 8\nlist_b = []\nnum_sqrt = int(math.sqrt(var_b))\nfor i in range(1, num_sqrt+1):\n    if var_b % i == 0:\n        list_b.append(i)\n        list_b.append(int(var_b/i))\nlist_b = sorted(set(list_b))\nlist_c = list(set(list_a) - set(list_b))\nvar_c = len(list_c)\nprint(int(var_c))",
        "solution_code_en": "var_a = 32\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 8\nlist_b = []\nnum_sqrt = int(math.sqrt(var_b))\nfor i in range(1, num_sqrt+1):\n    if var_b % i == 0:\n        list_b.append(i)\n        list_b.append(int(var_b/i))\nlist_b = sorted(set(list_b))\nlist_c = list(set(list_a) - set(list_b))\nvar_c = len(list_c)\nprint(int(var_c))"
    },
    "7572": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 3번째로 작은 수와 2번째로 작은 수로 나눈 몫은 얼마입니까?",
        "question_en": "There are five numbers 10, 11, 12, 13, and 14. What is the quotient when you divide the 3rd smallest number by the 2nd smallest number?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 3 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_FDIV]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 3 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_FDIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g // var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g // var_i\nprint(int(var_j))"
    },
    "7573": {
        "category": "Geometry",
        "question_ko": "가로가 12센티미터(㎝), 세로가 16센티미터(㎝), 높이가 14센티미터(㎝)인 직육면체를 잘라서 정육면체를 만드려고 한다. 가장 큰 정육면체의 겉넓이는?",
        "question_en": "You are going to make a cube by cutting a cuboid measuring 12 centimeters (cm) wide, 16 centimeters (cm) long, and 14 centimeters (cm) high. What is the surface area of the largest cube?",
        "answer_ko": "864",
        "answer_en": "864",
        "solution_abst_ko": "[OP_LIST_SOL] 12 16 14 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_POW] 6 [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 12 16 14 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_POW] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 12\nvar_b = 16\nvar_c = 14\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nvar_f = 2\nvar_g = var_e ** var_f\nvar_h = 6\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 12\nvar_b = 16\nvar_c = 14\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nvar_f = 2\nvar_g = var_e ** var_f\nvar_h = 6\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "7574": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수의 평균은 3입니다. 이 중 한 개의 수를 골라 1로 바꾸었더니 평균이 2가 되었습니다. 바꾼 수는 원래 얼마입니까?",
        "question_en": "The average of three numbers is 3. If you take one of these numbers and change it to 1, the average is 2. What was the original number?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "3 3 [OP_MUL] 2 3 [OP_MUL] 1 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "3 3 [OP_MUL] 2 3 [OP_MUL] 1 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 3\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_c - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 3\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_c - var_h\nprint(int(var_i))"
    },
    "7575": {
        "category": "Arithmetic calculation",
        "question_ko": "세 자리 수 중 5, 8, 2의 공배수 중 가장 큰 수는?",
        "question_en": "Which three-digit number is the greatest common multiple of 5, 8, and 2?",
        "answer_ko": "960",
        "answer_en": "960",
        "solution_abst_ko": "100 999 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 2 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_abst_en": "100 999 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 2 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 8\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 2\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_h = list_e[-var_g]\nprint(int(var_h))",
        "solution_code_en": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 8\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 2\nlist_d = []\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i % var_f == 0:\n        list_d.append(i)\nvar_g = 1\nlist_e=list_d.copy()\nlist_e.sort()\nvar_h = list_e[-var_g]\nprint(int(var_h))"
    },
    "7576": {
        "category": "Arithmetic calculation",
        "question_ko": "선물 하나를 포장하는 데 리본 테이프 0.84미터(m)가 필요합니다. 소은이가 친구 10명의 선물을 준비했더니 리본 테이프가 50센티미터(㎝) 남았습니다. 소은이가 처음에 가지고 있던 기본 테이프는 몇 미터(m)일까요?",
        "question_en": "It takes 0.84 meters (m) of ribbon tape to wrap one gift. When Soeun prepared gifts for 10 of her friends, there were 50 centimeters (cm) of ribbon tape left. How many meters (m) was the basic tape that Soeun had at first?",
        "answer_ko": "8.90",
        "answer_en": "8.9",
        "solution_abst_ko": "0.84 10 [OP_MUL] 50 100 [OP_DIV] [OP_ADD]",
        "solution_abst_en": "0.84 10 [OP_MUL] 50 100 [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 0.84\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 50\nvar_e = 100\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 0.84\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 50\nvar_e = 100\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "7577": {
        "category": "Comparison",
        "question_ko": "구슬을 한 줄로 늘어놓았습니다. 왼쪽에서 5번째, 오른쪽에서 3번째에 초록색 구슬이 있습니다. 전체 구슬의 개수는 몇 개입니까?",
        "question_en": "The beads are lined up in a row. There is a green marble at the 5th from the left and 3rd from the right. How many marbles are there in total?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "5 3 [OP_ADD] 1 [OP_SUB]",
        "solution_abst_en": "5 3 [OP_ADD] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 5\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "7578": {
        "category": "Arithmetic calculation",
        "question_ko": "120미터(m)에 있는 공이 초속 4미터(m)의 속도로 20초 동안 떨어졌다. 공은 지상에서 몇 미터(m)떨어져 있는지 구하시오.",
        "question_en": "The ball at 120 meters (m) falls for 20 seconds at a speed of 4 meters (m) per second. Find how many meters (m) the ball is from the ground.",
        "answer_ko": "40",
        "answer_en": "40",
        "solution_abst_ko": "120 4 20 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "120 4 20 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 120\nvar_b = 4\nvar_c = 20\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 120\nvar_b = 4\nvar_c = 20\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "7579": {
        "category": "Possibility",
        "question_ko": "점심은 중식에서 5종류, 일식에서 4종류가 있고, 저녁은 중식에서 3종류, 일식에서 5종류가 있다. 점심과 저녁 메뉴를 1개씩 고르는 경우의 수를 구하시오.",
        "question_en": "For lunch, there are 5 kinds of Chinese food and 4 kinds of Japanese food, and for dinner, there are 3 kinds of Chinese food and 5 kinds of Japanese food. Find the number of ways to choose one menu for lunch and one for dinner.",
        "answer_ko": "72",
        "answer_en": "72",
        "solution_abst_ko": "5 4 [OP_ADD] 3 5 [OP_ADD] [OP_MUL]",
        "solution_abst_en": "5 4 [OP_ADD] 3 5 [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 5\nvar_f = var_d + var_e\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 5\nvar_f = var_d + var_e\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "7580": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 5와 6으로 나누면 나누어떨어지고 7로 나누면 나머지가 6이라고 합니다. 어떤 수 중에서 가장 큰 세 자리 수를 구하시오.",
        "question_en": "When a number is divided by 5 and 6, it is divisible, and when divided by 7, the remainder is 6. Find the largest three-digit possible number.",
        "answer_ko": "930",
        "answer_en": "930",
        "solution_abst_ko": "100 999 1 [OP_LIST_ARANGE] 5 6 [OP_LCM] [OP_LIST_DIVISIBLE] 7 6 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MAX]",
        "solution_abst_en": "100 999 1 [OP_LIST_ARANGE] 5 6 [OP_LCM] [OP_LIST_DIVISIBLE] 7 6 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nvar_e = 6\nvar_f = var_e * var_d / math.gcd(int(var_e), int(var_d))\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nvar_g = 7\nvar_h = 6\nlist_c = [] \nvar_g = int(var_g)\nvar_h = int(var_h)\nif var_h < 0:\n    var_h = var_h + var_g\nfor i in list_b:\n    i = int(i)\n    if i%var_g == var_h:\n        list_c.append(i)\nvar_i = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_j = list_d[-var_i]\nprint(int(var_j))",
        "solution_code_en": "var_a = 100\nvar_b = 999\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 5\nvar_e = 6\nvar_f = var_e * var_d / math.gcd(int(var_e), int(var_d))\nlist_b = []\nvar_f = int(var_f)\nfor i in list_a:\n    i = int(i)\n    if i % var_f == 0:\n        list_b.append(i)\nvar_g = 7\nvar_h = 6\nlist_c = [] \nvar_g = int(var_g)\nvar_h = int(var_h)\nif var_h < 0:\n    var_h = var_h + var_g\nfor i in list_b:\n    i = int(i)\n    if i%var_g == var_h:\n        list_c.append(i)\nvar_i = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_j = list_d[-var_i]\nprint(int(var_j))"
    },
    "7581": {
        "category": "Arithmetic calculation",
        "question_ko": "5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 가장 작은 수와 그 다음으로 작은 수로 나눈 값은 얼마입니까?",
        "question_en": "There are five numbers 10, 11, 12, 13, and 14. What is the difference between the smallest number and the next smallest number?",
        "answer_ko": "0.91",
        "answer_en": "0.91",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_DIV]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g / var_i\nprint('{:.2f}'.format(round(var_j+1e-10,2)))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nvar_d = 13\nvar_e = 14\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_g = list_b[var_f-1]\nvar_h = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_i = list_c[var_h-1]\nvar_j = var_g / var_i\nprint('{:.2f}'.format(round(var_j+1e-10,2)))"
    },
    "7582": {
        "category": "Arithmetic calculation",
        "question_ko": "붕대를 이어 붙였더니 전체 길이가 580센티미터(㎝)였습니다. 붕대가 총 24개 있으며 한 개의 길이는 28센티미터(㎝)입니다. 몇 센티미터(㎝)씩 겹쳐서 이어 붙인 걸까요?",
        "question_en": "When the bandages were connected to one another, the total length became 580 centimeters (cm). There were a total of 24 bandages, and each was 28 centimeters (cm) long. How many centimeters (cm) were overlapped?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "28 24 [OP_MUL] 580 [OP_SUB] 24 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "28 24 [OP_MUL] 580 [OP_SUB] 24 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 28\nvar_b = 24\nvar_c = var_a * var_b\nvar_d = 580\nvar_e = var_c - var_d\nvar_f = 24\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 28\nvar_b = 24\nvar_c = var_a * var_b\nvar_d = 580\nvar_e = var_c - var_d\nvar_f = 24\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "7583": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 4센티미터(㎝)인 정육각형의 둘레와 같은 둘레를 가진 정사각형을 만들었습니다. 이 정사각형의 넓이는 몇 제곱센티미터(㎠)입니까?",
        "question_en": "There is a square that has the same perimeter with a regular whose side length is 4 centimeters (cm). What is the area of this square in square centimeters (cm2)?",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "4 6 [OP_MUL] 4 [OP_DIV] 2 [OP_POW]",
        "solution_abst_en": "4 6 [OP_MUL] 4 [OP_DIV] 2 [OP_POW]",
        "solution_code_ko": "var_a = 4\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e ** var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e ** var_f\nprint(int(var_g))"
    },
    "7584": {
        "category": "Arithmetic calculation",
        "question_ko": "물 135.1밀리리터(㎖)가 있습니다. 이것을 7밀리리터(㎖)들이 물통으로 나누어 담는다면 물통들을 가득 채우고 남는 양은 몇 리터(L)입니까?",
        "question_en": "There is 135.1 milliliters (ml) of water. If you are to pour that amount of water into 7 milliliter (ml) buckets, how many liters (L) are left after filling the buckets with water?",
        "answer_ko": "0",
        "answer_en": "0",
        "solution_abst_ko": "135.1 7 [OP_MOD] 1000 [OP_DIV]",
        "solution_abst_en": "135.1 7 [OP_MOD] 1000 [OP_DIV]",
        "solution_code_ko": "var_a = 135.1\nvar_b = 7\nvar_c = var_a % var_b\nvar_d = 1000\nvar_e = var_c / var_d\nprint(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))",
        "solution_code_en": "var_a = 135.1\nvar_b = 7\nvar_c = var_a % var_b\nvar_d = 1000\nvar_e = var_c / var_d\nprint(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))"
    },
    "7585": {
        "category": "Arithmetic calculation",
        "question_ko": "석진이는 귤을 29개 가지고 있었습니다. 이 귤을 매일 같은 개수씩 8일 동안 먹었더니 5개가 남았습니다. 석진이는 하루에 귤을 몇 개씩 먹었습니까?",
        "question_en": "Seokjin had 29 tangerines. After eating the same number of tangerines every day for 8 days, there were 5 left. How many tangerines did Seokjin eat a day?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "29 5 [OP_SUB] 8 [OP_DIV]",
        "solution_abst_en": "29 5 [OP_SUB] 8 [OP_DIV]",
        "solution_code_ko": "var_a = 29\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 29\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "7586": {
        "category": "Geometry",
        "question_ko": "크기가 다른 두 개의 정육면체가 있습니다. 두 정육면체의 한 면의 넓이의 비가 9:25일 때, 큰 정육면체의 부피는 작은 정육면체의 부피의 몇 배입니까?",
        "question_en": "There are two cubes of different sizes. If the ratio of the area of one side of the two cubes is 9:25, how many times the volume of the larger cube is the volume of the smaller cube?",
        "answer_ko": "4.63",
        "answer_en": "4.63",
        "solution_abst_ko": "25 1/2 [OP_POW] 3 [OP_POW] 9 1/2 [OP_POW] 3 [OP_POW] [OP_DIV]",
        "solution_abst_en": "25 1/2 [OP_POW] 3 [OP_POW] 9 1/2 [OP_POW] 3 [OP_POW] [OP_DIV]",
        "solution_code_ko": "var_a = 25\nvar_b = 0.5\nvar_c = var_a ** var_b\nvar_d = 3\nvar_e = var_c ** var_d\nvar_f = 9\nvar_g = 0.5\nvar_h = var_f ** var_g\nvar_i = 3\nvar_j = var_h ** var_i\nvar_k = var_e / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 25\nvar_b = 0.5\nvar_c = var_a ** var_b\nvar_d = 3\nvar_e = var_c ** var_d\nvar_f = 9\nvar_g = 0.5\nvar_h = var_f ** var_g\nvar_i = 3\nvar_j = var_h ** var_i\nvar_k = var_e / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "7587": {
        "category": "Correspondence",
        "question_ko": "821에서 어떤 수를 빼면 267이 된다. 어떤 수에서 267을 빼면 얼마인지 구하시오.",
        "question_en": "A number subtracted from 821 is 267. What is the value when 267 is subtracted from the number?",
        "answer_ko": "287",
        "answer_en": "287",
        "solution_abst_ko": "821 267 [OP_SUB] 267 [OP_SUB]",
        "solution_abst_en": "821 267 [OP_SUB] 267 [OP_SUB]",
        "solution_code_ko": "var_a = 821\nvar_b = 267\nvar_c = var_a - var_b\nvar_d = 267\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 821\nvar_b = 267\nvar_c = var_a - var_b\nvar_d = 267\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "7588": {
        "category": "Arithmetic calculation",
        "question_ko": "두 자리 수끼리의 덧셈에서 더하는 수의 십의 자리 숫자 4를 6으로 잘못 보았습니다. 또 더해지는 수의 일의 자리 숫자 7을 1로 잘못 보고 계산하였더니 그 값이 146이 되었습니다. 바르게 계산한 결과를 구하시오.",
        "question_en": "In the addition of two-digit numbers, the number 4 in the tens place of a number was mistaken for 6. In addition, the number 7 in the units place of the other number was mistaken for 1. As a result, the result of the addition was 146. Find the result of the correct calculation.",
        "answer_ko": "132",
        "answer_en": "132",
        "solution_abst_ko": "146 10 4 6 [OP_SUB] [OP_MUL] [OP_ADD] 1 7 1 [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_abst_en": "146 10 4 6 [OP_SUB] [OP_MUL] [OP_ADD] 1 7 1 [OP_SUB] [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 146\nvar_b = 10\nvar_c = 4\nvar_d = 6\nvar_e = var_c - var_d\nvar_f = var_b * var_e\nvar_g = var_a + var_f\nvar_h = 1\nvar_i = 7\nvar_j = 1\nvar_k = var_i - var_j\nvar_l = var_h * var_k\nvar_m = var_g + var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 146\nvar_b = 10\nvar_c = 4\nvar_d = 6\nvar_e = var_c - var_d\nvar_f = var_b * var_e\nvar_g = var_a + var_f\nvar_h = 1\nvar_i = 7\nvar_j = 1\nvar_k = var_i - var_j\nvar_l = var_h * var_k\nvar_m = var_g + var_l\nprint(int(var_m))"
    },
    "7589": {
        "category": "Possibility",
        "question_ko": "서로 다른 4장의 자연수 숫자 중 3장의 카드를 선택해 세 자리 자연수를 만드는 방법은 모두 몇 가지입니까?",
        "question_en": "How many ways are there to make a three-digit natural number by selecting three cards from four different natural numbers?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "4 3 [OP_PERM]",
        "solution_abst_en": "4 3 [OP_PERM]",
        "solution_code_ko": "var_a = 4\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))",
        "solution_code_en": "var_a = 4\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))"
    },
    "7590": {
        "category": "Comparison",
        "question_ko": "무게가 250그램(g)인 통에 모래를 가득 넣어 무게를 재었더니 1킬로그램(㎏) 780그램(g)이었고 무게가 460그램(g)인 상자에 모래를 가득 넣어 무게를 재었더니 2킬로그램(㎏) 250그램(g)이었습니다. 상자와 통 중 어느 것에 들어 있는 모래가 더 무겁습니까?",
        "question_en": "When a 250-gram (g) barrel was filled with sand and weighed, it was 1 kilogram (kg) and 780 grams (g). When a box weighing 460 grams (g) was filled with sand and weighed again, it was 2 kilograms (kg) and 250 grams (g). Which sand is more heavier - the sand in the box or the barrel?",
        "answer_ko": "상자",
        "answer_en": "box",
        "solution_abst_ko": "[OP_LIST_SOL] 통 상자 [OP_LIST_EOL] [OP_LIST_SOL] 1 1000 [OP_MUL] 780 [OP_ADD] 250 [OP_SUB] 2 1000 [OP_MUL] 250 [OP_ADD] 460 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] barrel box [OP_LIST_EOL] [OP_LIST_SOL] 1 1000 [OP_MUL] 780 [OP_ADD] 250 [OP_SUB] 2 1000 [OP_MUL] 250 [OP_ADD] 460 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '통'\nvar_b = '상자'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 780\nvar_g = var_e + var_f\nvar_h = 250\nvar_i = var_g - var_h\nvar_j = 2\nvar_k = 1000\nvar_l = var_j * var_k\nvar_m = 250\nvar_n = var_l + var_m\nvar_o = 460\nvar_p = var_n - var_o\nlist_b= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nlist_b.reverse()\nvar_q = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_r = list_c[-var_q]\nvar_s = list_b.index(var_r)+1\nvar_t = list_a[var_s-1]\nprint(var_t)",
        "solution_code_en": "var_a = 'barrel'\nvar_b = 'box'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 1\nvar_d = 1000\nvar_e = var_c * var_d\nvar_f = 780\nvar_g = var_e + var_f\nvar_h = 250\nvar_i = var_g - var_h\nvar_j = 2\nvar_k = 1000\nvar_l = var_j * var_k\nvar_m = 250\nvar_n = var_l + var_m\nvar_o = 460\nvar_p = var_n - var_o\nlist_b= []\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nlist_b.reverse()\nvar_q = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_r = list_c[-var_q]\nvar_s = list_b.index(var_r)+1\nvar_t = list_a[var_s-1]\nprint(var_t)"
    },
    "7591": {
        "category": "Correspondence",
        "question_ko": "어떤 수의 2배에서 37을 빼고, 25를 더한 값을 8로 나누면 5가 됩니다. 어떤 수를 구하시오.",
        "question_en": "Multiplying a number by 2 subtracting by 37 adding by 25 dividing by 8 equals 5. Find the number.",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "5 8 [OP_MUL] 25 [OP_SUB] 37 [OP_ADD] 2 [OP_DIV]",
        "solution_abst_en": "5 8 [OP_MUL] 25 [OP_SUB] 37 [OP_ADD] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 5\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 25\nvar_e = var_c - var_d\nvar_f = 37\nvar_g = var_e + var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 5\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 25\nvar_e = var_c - var_d\nvar_f = 37\nvar_g = var_e + var_f\nvar_h = 2\nvar_i = var_g / var_h\nprint(int(var_i))"
    },
    "7592": {
        "category": "Arithmetic calculation",
        "question_ko": "56, 72의 공약수 중 4로 나눠 떨어지는 수는 모두 몇 개인가?",
        "question_en": "How many common divisors of 56 and 72 are divisible by 4?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "56 [OP_LIST_GET_DIVISOR] 72 [OP_LIST_GET_DIVISOR] [OP_SET_INTERSECT] 4 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "56 [OP_LIST_GET_DIVISOR] 72 [OP_LIST_GET_DIVISOR] [OP_SET_INTERSECT] 4 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 56\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 72\nlist_b = []\nnum_sqrt = int(math.sqrt(var_b))\nfor i in range(1, num_sqrt+1):\n    if var_b % i == 0:\n        list_b.append(i)\n        list_b.append(int(var_b/i))\nlist_b = sorted(set(list_b))\nlist_c = list(set(list_a) & set(list_b))\nvar_c = 4\nlist_d = []\nvar_c = int(var_c)\nfor i in list_c:\n    i = int(i)\n    if i % var_c == 0:\n        list_d.append(i)\nvar_d = len(list_d)\nprint(int(var_d))",
        "solution_code_en": "var_a = 56\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = 72\nlist_b = []\nnum_sqrt = int(math.sqrt(var_b))\nfor i in range(1, num_sqrt+1):\n    if var_b % i == 0:\n        list_b.append(i)\n        list_b.append(int(var_b/i))\nlist_b = sorted(set(list_b))\nlist_c = list(set(list_a) & set(list_b))\nvar_c = 4\nlist_d = []\nvar_c = int(var_c)\nfor i in list_c:\n    i = int(i)\n    if i % var_c == 0:\n        list_d.append(i)\nvar_d = len(list_d)\nprint(int(var_d))"
    },
    "7593": {
        "category": "Arithmetic calculation",
        "question_ko": "(가) 동물이 6마리 있습니다. (가) 동물 1마리가 한 달 동안 4킬로그램(㎏)의 먹이를 먹을 때 한 달 동안 (가) 동물이 먹는 먹이는 모두 몇 킬로그램(㎏)입니까?",
        "question_en": "There are 6 (A)animals. If an (A)animal eats 4 kg (kg) of food in one month, how many kg (kg) of food do the (A)animals eat in one month?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "6 4 [OP_MUL]",
        "solution_abst_en": "6 4 [OP_MUL]",
        "solution_code_ko": "var_a = 6\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "7594": {
        "category": "Possibility",
        "question_ko": "5, 6, 4, 7 중에서 3개를 뽑아 한 번씩만 사용하여 세 자리 수를 만들려고 합니다. 만들 수 있는 가장 큰 수와 가장 작은 수의 합을 구하시오.",
        "question_en": "You want to create a three-digit number by drawing three out of 5, 6, 4, and 7 and using them only once. Find the sum of the largest and smallest possible numbers.",
        "answer_ko": "1221",
        "answer_en": "1221",
        "solution_abst_ko": "[OP_LIST_SOL] 5 6 4 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 5 6 4 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 6\nvar_c = 4\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 5\nvar_b = 6\nvar_c = 4\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g + var_i\nprint(int(var_j))"
    },
    "7595": {
        "category": "Possibility",
        "question_ko": "소설책 2권을 포함하여 총 5권의 책을 책장에 꽂으려고할 때, 소설책이 양 끝에 꽂힐 경우의 수는 얼마인가요?",
        "question_en": "If you try to put a total of 5 books, including 2 novels, on the bookshelf, how many times will the novels end up on both ends?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "5 2 [OP_SUB] 5 2 [OP_SUB] [OP_PERM] 2 [OP_MUL]",
        "solution_abst_en": "5 2 [OP_SUB] 5 2 [OP_SUB] [OP_PERM] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = 1\nvar_c = int(var_c)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_c-i)\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = 1\nvar_c = int(var_c)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_c-i)\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "7596": {
        "category": "Correspondence",
        "question_ko": "-3보다 -5만큼 큰 수를 A, +2보다 -2만큼 작은 수를 B라 할 때, A-B의 값을 구하시오.",
        "question_en": "If A is the number greater than -3 by -5 and B is the number less than +2 by -2, find the value of A-B.",
        "answer_ko": "-12",
        "answer_en": "-12",
        "solution_abst_ko": "-3 -5 [OP_ADD] 2 -2 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "-3 -5 [OP_ADD] 2 -2 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = -3\nvar_b = -5\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = -2\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = -3\nvar_b = -5\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = -2\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "7597": {
        "category": "Arithmetic calculation",
        "question_ko": "상자에 과자가 가득 들어있었습니다. 지민이가 상자에 들어 있는 과자의 2/5를 먹고 상자의 무게를 재어 보니 144그램(g)이었습니다. 잠시 후 재희가 남은 과자의 2/3을 먹고 다시 상자의 무게를 재어 보니 96그램(g)이었습니다. 모든 과자를 먹은 후의 상자의 무게만 재면 몇 그램(g)이 될까요?",
        "question_en": "The box was full of sweets. Jimin ate 2/5 of the cookies in the box and weighed the box and it was 144 grams (g). After a while, Jaehee ate 2/3 of the remaining cookies and weighed the box again and it was 96 grams (g). How many grams (g) would the box weigh after all the cookies were eaten?",
        "answer_ko": "72",
        "answer_en": "72",
        "solution_abst_ko": "144 144 96 [OP_SUB] 1 2/5 [OP_SUB] [OP_DIV] 2/3 [OP_DIV] 1 2/5 [OP_SUB] [OP_MUL] [OP_SUB]",
        "solution_abst_en": "144 144 96 [OP_SUB] 1 2/5 [OP_SUB] [OP_DIV] 2/3 [OP_DIV] 1 2/5 [OP_SUB] [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 144\nvar_b = 144\nvar_c = 96\nvar_d = var_b - var_c\nvar_e = 1\nvar_f = 0.4\nvar_g = var_e - var_f\nvar_h = var_d / var_g\nvar_i = 0.6666666666666666\nvar_j = var_h / var_i\nvar_k = 1\nvar_l = 0.4\nvar_m = var_k - var_l\nvar_n = var_j * var_m\nvar_o = var_a - var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 144\nvar_b = 144\nvar_c = 96\nvar_d = var_b - var_c\nvar_e = 1\nvar_f = 0.4\nvar_g = var_e - var_f\nvar_h = var_d / var_g\nvar_i = 0.6666666666666666\nvar_j = var_h / var_i\nvar_k = 1\nvar_l = 0.4\nvar_m = var_k - var_l\nvar_n = var_j * var_m\nvar_o = var_a - var_n\nprint(int(var_o))"
    },
    "7598": {
        "category": "Comparison",
        "question_ko": "학생 27명이 한 줄로 서 있습니다. 민영이는 뒤에서 13번째라면 앞에서 몇 번째입니까?",
        "question_en": "27 students are standing in a line. If Minyoung is in the 13th from the back, where is she placed from the front?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "27 13 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "27 13 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 27\nvar_b = 13\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 27\nvar_b = 13\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7599": {
        "category": "Arithmetic calculation",
        "question_ko": "(나) 반의 학생 수는 (가) 반보다 8명 더 적습니다. (나) 반 학생 수의 5배 만큼 (다) 반 학생이 있습니다. (나) 반 학생이 25명일 때, (가) 반, (나) 반, (다) 반의 학생 수는 모두 몇 명입니까?",
        "question_en": "The number of students in class (B) is 8 fewer than the number of students in class (A). The number of students in class (C) is 5 times the number of students in the class. If there are 25 students in class (B), how many students are in (A), (B), and (C) total?",
        "answer_ko": "183",
        "answer_en": "183",
        "solution_abst_ko": "25 8 [OP_ADD] 25 [OP_ADD] 25 5 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "25 8 [OP_ADD] 25 [OP_ADD] 25 5 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 25\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 25\nvar_e = var_c + var_d\nvar_f = 25\nvar_g = 5\nvar_h = var_f * var_g\nvar_i = var_e + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 25\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 25\nvar_e = var_c + var_d\nvar_f = 25\nvar_g = 5\nvar_h = var_f * var_g\nvar_i = var_e + var_h\nprint(int(var_i))"
    },
    "7600": {
        "category": "Possibility",
        "question_ko": "다음 조건을 만족하는 수들의 합을 구하여라. 네자리 수이고, 3, 5, 7, 9로 이루어져 있다. 또, 각 자리의 숫자는 모두 다르다.",
        "question_en": "Find the sum of the numbers that satisfy the following condition. It is a four-digit number and consists of 3, 5, 7, and 9. Also, the numbers in each digit are different.",
        "answer_ko": "159984",
        "answer_en": "159984",
        "solution_abst_ko": "[OP_LIST_SOL] 3 5 7 9 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 3 5 7 9 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 3\nvar_b = 5\nvar_c = 7\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 3\nvar_b = 5\nvar_c = 7\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint(int(var_f))"
    },
    "7601": {
        "category": "Arithmetic calculation",
        "question_ko": "태형이는 22000원을 가지고 있습니다. 이 돈으로 한 권에 1000원인 공책과 한 개에 2000원인 색연필을 사려고 합니다. 공책과 색연필을 합하여 15개를 사야한다면 색연필은 몇 개 사야하는 지 구하세요.",
        "question_en": "Taehyung has 22,000 won. With this money, he plans to buy a notebook that costs 1,000 won each and colored pencils that cost 2,000 won each. If he needs to buy 15 notebooks and colored pencils altogether, find out how many colored pencils he has to buy.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "22000 1000 15 [OP_MUL] [OP_SUB] 2000 1000 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "22000 1000 15 [OP_MUL] [OP_SUB] 2000 1000 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 22000\nvar_b = 1000\nvar_c = 15\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 2000\nvar_g = 1000\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 22000\nvar_b = 1000\nvar_c = 15\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 2000\nvar_g = 1000\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "7602": {
        "category": "Comparison",
        "question_ko": "윤기는 4, 정국에는 6에서 3을 합한 수를 모았고, 유나는 5를 모았습니다. 누가 가장 큰 수를 가지고 있나요?",
        "question_en": "There are three following numbers for Yoongi, Jungkook, and Yuna, respectively: 4, 6 plus 3, and 5. Find the person with the largest number.",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 유나 [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_ADD] 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook Yuna [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_ADD] 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nvar_c = '유나'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 6\nvar_f = 3\nvar_g = var_e + var_f\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nvar_c = 'Yuna'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 6\nvar_f = 3\nvar_g = var_e + var_f\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "7603": {
        "category": "Geometry",
        "question_ko": "반지름의 길이가 2센티미터(㎝)인 원을 한 변의 길이가 8센티미터(㎝)인 정사각형 안에 겹치지 않게 그릴 때 몇 개의 원을 그릴 수 있겠습니까?",
        "question_en": "How many circles can you draw if you draw a circle with a radius of 2 centimeters (cm) inside a square with a side length of 8 centimeters (cm) without overlapping?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "8 2 2 [OP_MUL] [OP_DIV] 2 [OP_POW]",
        "solution_abst_en": "8 2 2 [OP_MUL] [OP_DIV] 2 [OP_POW]",
        "solution_code_ko": "var_a = 8\nvar_b = 2\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nvar_f = 2\nvar_g = var_e ** var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 8\nvar_b = 2\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nvar_f = 2\nvar_g = var_e ** var_f\nprint(int(var_g))"
    },
    "7604": {
        "category": "Possibility",
        "question_ko": "말 7마리 중에서 경마대회에 출전할 말 6마리를 선발하려고 할 때, 가능한 모든 경우의 수를 구하시오.",
        "question_en": "If you are trying to select 6 horses out of 7 to compete in a horse race, find the number of all possible cases.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "7 6 [OP_COMB]",
        "solution_abst_en": "7 6 [OP_COMB]",
        "solution_code_ko": "var_a = 7\nvar_b = 6\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))",
        "solution_code_en": "var_a = 7\nvar_b = 6\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))"
    },
    "7605": {
        "category": "Geometry",
        "question_ko": "크기가 같은 동전을 빈틈없이 규칙적으로 가로와 세로 모두 12개씩 늘어놓아 정사각형을 만들었습니다. 한 변에 놓인 구슬은 몇 개입니까?",
        "question_en": "A square was created by arranging 12 coins of the same size vertically and horizontally in a regular pattern. Find the number of marbles on one side.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "12",
        "solution_abst_en": "12",
        "solution_code_ko": "var_a = 12\nprint(int(var_a))",
        "solution_code_en": "var_a = 12\nprint(int(var_a))"
    },
    "7606": {
        "category": "Geometry",
        "question_ko": "한 밑면의 넓이가 14제곱센티미터(㎠)이고 높이가 13센티미터(㎝)인 직육면체의 부피를 구하시오.",
        "question_en": "Find the volume of a cuboid whose base area is 14 square centimeters (cm2) and its height is 13 centimeters (cm).",
        "answer_ko": "182",
        "answer_en": "182",
        "solution_abst_ko": "14 13 [OP_MUL]",
        "solution_abst_en": "14 13 [OP_MUL]",
        "solution_code_ko": "var_a = 14\nvar_b = 13\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 14\nvar_b = 13\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "7607": {
        "category": "Arithmetic calculation",
        "question_ko": "웅이, 영수, 효근이는 각각 구슬을 몇 개씩 가지고 있었습니다. 차례대로 웅이는 영수에게 5개, 영수는 효근이에게 10개, 효근이는 웅이에게 7개를 주었더니, 세 사람 모두 구슬이 20개씩 되었습니다. 웅이가 처음에 가지고 있던 구슬의 개수를 구하시오.",
        "question_en": "Woong, Youngsoo, and Hyogeun each had a few marbles. In turn, Woong gave Youngsu 5 marbles, Youngsu gave Hyogeun 10 marbles, and Hyogeun gave Woong 7 marbles, so that all three of them have 20 marbles each. Find the number of marbles Woong had at first.",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "20 7 [OP_SUB] 5 [OP_ADD]",
        "solution_abst_en": "20 7 [OP_SUB] 5 [OP_ADD]",
        "solution_code_ko": "var_a = 20\nvar_b = 7\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 7\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7608": {
        "category": "Possibility",
        "question_ko": "123의 배수 중 162ABC6 모양의 수가 있다. 이러한 수 중에서 가장 큰 수를 구하여라.",
        "question_en": "Among the multiples of 123, there are numbers that look like 162ABC6. Among these numbers, find the largest one.",
        "answer_ko": "1629996",
        "answer_en": "1629996",
        "solution_abst_ko": "1620006 1629996 1 [OP_LIST_ARANGE] 123 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_abst_en": "1620006 1629996 1 [OP_LIST_ARANGE] 123 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1620006\nvar_b = 1629996\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 123\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))",
        "solution_code_en": "var_a = 1620006\nvar_b = 1629996\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 123\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))"
    },
    "7609": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 35를 빼야 하는데 잘못하여 더했더니 77이 되었습니다. 바르게 계산한 결과를 구하시오.",
        "question_en": "You need to subtract 35 from a number, but mistakenly add it, and got 77. Find the result of the correct calculation.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "77 35 [OP_SUB] 35 [OP_SUB]",
        "solution_abst_en": "77 35 [OP_SUB] 35 [OP_SUB]",
        "solution_code_ko": "var_a = 77\nvar_b = 35\nvar_c = var_a - var_b\nvar_d = 35\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 77\nvar_b = 35\nvar_c = var_a - var_b\nvar_d = 35\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "7610": {
        "category": "Comparison",
        "question_ko": "민영이는 달리기 시합에서 33등으로 도착했고, 은지는 민영이가 도착한 후 11번째로 도착했습니다. 은지의 등수는 몇 등입니까?",
        "question_en": "Minyoung arrived 33rd in the race, and Eunji arrived 11th after Minyoung arrived. What is Eunji's rank?",
        "answer_ko": "44",
        "answer_en": "44",
        "solution_abst_ko": "33 11 [OP_ADD]",
        "solution_abst_en": "33 11 [OP_ADD]",
        "solution_code_ko": "var_a = 33\nvar_b = 11\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 33\nvar_b = 11\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "7611": {
        "category": "Correspondence",
        "question_ko": "-3에 -5만큼 곱한 수를 A, +2보다 -2만큼 큰 수를 B라 할 때, A+B의 값을 구하시오.",
        "question_en": "If A is a number equivalent to -5 multiplied by -3, and B a number -2 greater than +2, find the value of A+B.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "-3 -5 [OP_MUL] 2 -2 [OP_ADD] [OP_ADD]",
        "solution_abst_en": "-3 -5 [OP_MUL] 2 -2 [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = -3\nvar_b = -5\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = -2\nvar_f = var_d + var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = -3\nvar_b = -5\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = -2\nvar_f = var_d + var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "7612": {
        "category": "Possibility",
        "question_ko": "1000부터 2000까지의 수의 자리수를 모두 더하면 얼마가 되는지 구하여라.",
        "question_en": "What is the sum of all the digits of the numbers from 1000 to 2000?",
        "answer_ko": "14502",
        "answer_en": "14502",
        "solution_abst_ko": "1000 2000 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] [OP_LIST_SUM]",
        "solution_abst_en": "1000 2000 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1000\nvar_b = 2000\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_b=[]\nfor i in list_a:\n    var_d = 0\n    i = int(i)\n    while i//10 > 0:\n        var_d = var_d + i%10\n        i = i//10\n    var_d = var_d + i%10\n    list_b.append(var_d)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 1000\nvar_b = 2000\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nlist_b=[]\nfor i in list_a:\n    var_d = 0\n    i = int(i)\n    while i//10 > 0:\n        var_d = var_d + i%10\n        i = i//10\n    var_d = var_d + i%10\n    list_b.append(var_d)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint(int(var_e))"
    },
    "7613": {
        "category": "Comparison",
        "question_ko": "집에서 도서관까지의 거리는 2+13/40 킬로미터(㎞) 이고, 집에서 은행까지의 거리는 2.56킬로미터(㎞) 입니다. 도서관과 은행 중에서 집에서 더 먼 곳은 어디입니까?",
        "question_en": "The distance from the house to the library is 2+13/40 kilometers (km), and the distance from the house to the bank is 2.56 kilometers (km). Which is farther from home, the library or the bank?",
        "answer_ko": "은행",
        "answer_en": "bank",
        "solution_abst_ko": "[OP_LIST_SOL] 도서관 은행 [OP_LIST_EOL] [OP_LIST_SOL] 2 13/40 [OP_ADD] 2.56 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] library bank [OP_LIST_EOL] [OP_LIST_SOL] 2 13/40 [OP_ADD] 2.56 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '도서관'\nvar_b = '은행'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nvar_d = 0.325\nvar_e = var_c + var_d\nvar_f = 2.56\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'library'\nvar_b = 'bank'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nvar_d = 0.325\nvar_e = var_c + var_d\nvar_f = 2.56\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "7614": {
        "category": "Geometry",
        "question_ko": "직삼각형에서 어느 한 변의 길이를 찾으려고 합니다. 빗변이 17의 길이를 갖고, 빗변이 아닌 한 변이 15의 길이를 갖는다면 나머지 한 변의 길이는 얼마일까요?",
        "question_en": "You are trying to find the length of any side of a right triangle. If the hypotenuse has a length of 17 and the non-hypotenuse has a length of 15, what is the length of the other side?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "17 2 [OP_POW] 15 2 [OP_POW] [OP_SUB] 1/2 [OP_POW]",
        "solution_abst_en": "17 2 [OP_POW] 15 2 [OP_POW] [OP_SUB] 1/2 [OP_POW]",
        "solution_code_ko": "var_a = 17\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 15\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c - var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 17\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 15\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c - var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))"
    },
    "7615": {
        "category": "Arithmetic calculation",
        "question_ko": "어머니가 사과를 사 오셨습니다. 전체의 절반을 먹고 8개가 남았습니다. 어머니가 사 오신 사과는 몇 개입니까?",
        "question_en": "Your mother bought some apples. Suppose you ate half of the whole quantity, and 8 apples left. How many apples did the mother buy?",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "8 2 [OP_MUL]",
        "solution_abst_en": "8 2 [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 8\nvar_b = 2\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "7616": {
        "category": "Comparison",
        "question_ko": "은지는 오늘 동화책을 어제보다 14쪽 더 적게 읽었고 어제 35쪽을 읽었습니다. 호석이는 오늘 어제보다 12쪽 더 많이 읽었고 어제 23쪽을 읽었습니다. 어제와 오늘 합해서 동화책을 더 많이 읽은 사람은 누구입니까?",
        "question_en": "Eunji read 14 fewer pages of children's books today than yesterday, and she read 35 pages yesterday. Hoseok read 12 more pages today than yesterday and read 23 pages yesterday. Who read more pages of children's book yesterday and today combined?",
        "answer_ko": "호석",
        "answer_en": "Hoseok",
        "solution_abst_ko": "[OP_LIST_SOL] 호석 은지 [OP_LIST_EOL] [OP_LIST_SOL] 23 12 [OP_ADD] 23 [OP_ADD] 35 14 [OP_SUB] 35 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Hoseok Eunji [OP_LIST_EOL] [OP_LIST_SOL] 23 12 [OP_ADD] 23 [OP_ADD] 35 14 [OP_SUB] 35 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '호석'\nvar_b = '은지'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 23\nvar_d = 12\nvar_e = var_c + var_d\nvar_f = 23\nvar_g = var_e + var_f\nvar_h = 35\nvar_i = 14\nvar_j = var_h - var_i\nvar_k = 35\nvar_l = var_j + var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'Hoseok'\nvar_b = 'Eunji'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 23\nvar_d = 12\nvar_e = var_c + var_d\nvar_f = 23\nvar_g = var_e + var_f\nvar_h = 35\nvar_i = 14\nvar_j = var_h - var_i\nvar_k = 35\nvar_l = var_j + var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[-var_m]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "7617": {
        "category": "Possibility",
        "question_ko": "서윤이는 구별이 되지않는 보라색 공3개와 구별이 되지않는 초록색 공 2개를 가지고 있다. 이 공들을 한줄로 배열할때 배열 할 수 있는 방법은 몇 가지인가?",
        "question_en": "Seoyoon has 3 indistinguishable purple balls and 2 indistinguishable green balls. How many ways can she arrange these balls when she arranges them in a row?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "3 2 [OP_ADD] 3 [OP_COMB]",
        "solution_abst_en": "3 2 [OP_ADD] 3 [OP_COMB]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 1\nvar_c = int(var_c)\nvar_d = int(var_d)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e * (var_c-i)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e / (i+1)\nprint(int(var_e))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 1\nvar_c = int(var_c)\nvar_d = int(var_d)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e * (var_c-i)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e / (i+1)\nprint(int(var_e))"
    },
    "7618": {
        "category": "Arithmetic calculation",
        "question_ko": "50보다 크고 100보다 작은 수 중에서 8로 나누었을 때 나머지가 4인 수는 모두 몇 개입니까?",
        "question_en": "How many numbers greater than 50 and less than 100 have a remainder of 4 when divided by 8?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "50 1 [OP_ADD] 100 1 [OP_SUB] 1 [OP_LIST_ARANGE] 8 4 [OP_LIST_DIVIDE_AND_REMAIN] [OP_LIST_LEN]",
        "solution_abst_en": "50 1 [OP_ADD] 100 1 [OP_SUB] 1 [OP_LIST_ARANGE] 8 4 [OP_LIST_DIVIDE_AND_REMAIN] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 50\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 100\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = 8\nvar_i = 4\nlist_b = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_a:\n    i = int(i)\n    if i%var_h == var_i:\n        list_b.append(i)\nvar_j = len(list_b)\nprint(int(var_j))",
        "solution_code_en": "var_a = 50\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 100\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nlist_a = [i for i in range(var_c, var_f + 1, var_g)]\nvar_h = 8\nvar_i = 4\nlist_b = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_a:\n    i = int(i)\n    if i%var_h == var_i:\n        list_b.append(i)\nvar_j = len(list_b)\nprint(int(var_j))"
    },
    "7619": {
        "category": "Geometry",
        "question_ko": "모든 모서리의 길이의 합이 144센티미터(㎝)인 정육면체가 있습니다. 이 정육면체의 한 모서리의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "There is a cube with the sum of the lengths of all its edges equal to 144 centimeters (cm). How many centimeters (cm) is the length of one edge of this cube?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "144 12 [OP_DIV]",
        "solution_abst_en": "144 12 [OP_DIV]",
        "solution_code_ko": "var_a = 144\nvar_b = 12\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 144\nvar_b = 12\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "7620": {
        "category": "Arithmetic calculation",
        "question_ko": "몇 년 전 어머니가 33살일 때 석진이는 7살 이었습니다. 그로부터 5년 후 석진이 어머니와 석진이의 나이 차는 얼마입니까?",
        "question_en": "A few years ago, Seokjin was 7 when his mother was 33 years old. Five years later, what is the age difference between Seokjin's mother and Seokjin's?",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "33 5 [OP_ADD] 7 5 [OP_ADD] [OP_SUB]",
        "solution_abst_en": "33 5 [OP_ADD] 7 5 [OP_ADD] [OP_SUB]",
        "solution_code_ko": "var_a = 33\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 7\nvar_e = 5\nvar_f = var_d + var_e\nvar_g = var_c - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 33\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 7\nvar_e = 5\nvar_f = var_d + var_e\nvar_g = var_c - var_f\nprint(int(var_g))"
    },
    "7621": {
        "category": "Arithmetic calculation",
        "question_ko": "올해 아버지 나이는 아들 나이의 6배입니다. 6년 후에 아버지와 아들의 나이의 합은 68살이 됩니다. 올해 아들의 나이는 몇 살입니까?",
        "question_en": "This year, the age of the father is 6 times the age of the son. After 6 years, the sum of the ages of father and son is 68 years old. How old is the son this year?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "68 6 2 [OP_MUL] [OP_SUB] 1 6 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "68 6 2 [OP_MUL] [OP_SUB] 1 6 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 68\nvar_b = 6\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = 6\nvar_h = var_f + var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 68\nvar_b = 6\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = 6\nvar_h = var_f + var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "7622": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 24.7센티미터(㎝) 인 양초에 불을 붙이고 40 분 후에 양초의 길이를 재었더니 17.1 센티미터(㎝) 였습니다. 이 양초가 모두 타는 데 걸리는 시간은 몇 분입니까?",
        "question_en": "A 24.7 centimeters (cm) long candle was lit and 40 minutes later, the length of the candle was measured and it was 17.1 centimeters (cm). How many minutes will it take for the candle to burn all the way down?",
        "answer_ko": "130",
        "answer_en": "130",
        "solution_abst_ko": "24.7 24.7 17.1 [OP_SUB] 40 [OP_DIV] [OP_DIV]",
        "solution_abst_en": "24.7 24.7 17.1 [OP_SUB] 40 [OP_DIV] [OP_DIV]",
        "solution_code_ko": "var_a = 24.7\nvar_b = 24.7\nvar_c = 17.1\nvar_d = var_b - var_c\nvar_e = 40\nvar_f = var_d / var_e\nvar_g = var_a / var_f\nprint(int(eval('{:.2f}'.format(round(var_g+1e-10,2)))))",
        "solution_code_en": "var_a = 24.7\nvar_b = 24.7\nvar_c = 17.1\nvar_d = var_b - var_c\nvar_e = 40\nvar_f = var_d / var_e\nvar_g = var_a / var_f\nprint(int(eval('{:.2f}'.format(round(var_g+1e-10,2)))))"
    },
    "7623": {
        "category": "Arithmetic calculation",
        "question_ko": "도연이네 반 남학생 3명의 키가 161.5센티미터(㎝), 154.3센티미터(㎝), 143.7센티미터(㎝)이고, 여학생 4명의 키가 160.1센티미터(㎝), 158.0센티미터(㎝), 153.5센티미터(㎝), 147.8센티미터(㎝)일 때, 7명의 학생 중 가장 작은 학생의 키를 구하시오.",
        "question_en": "The three male students in Doyeon's class are 161.5 centimeters (cm), 154.3 centimeters (cm), and 143.7 centimeters (cm) tall, and the four female students are 160.1 centimeters (cm), 158.0 centimeters (cm), 153.5 centimeters (cm) ,147.8 centimeters(cm) tall.  Find the height of the shortest student among the 7 students.",
        "answer_ko": "143.70",
        "answer_en": "143.7",
        "solution_abst_ko": "[OP_LIST_SOL] 161.5 154.3 143.7 [OP_LIST_EOL] [OP_LIST_SOL] 160.1 158.0 153.5 147.8 [OP_LIST_EOL] [OP_SET_UNION] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 161.5 154.3 143.7 [OP_LIST_EOL] [OP_LIST_SOL] 160.1 158.0 153.5 147.8 [OP_LIST_EOL] [OP_SET_UNION] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 161.5\nvar_b = 154.3\nvar_c = 143.7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 160.1\nvar_e = 158\nvar_f = 153.5\nvar_g = 147.8\nlist_b= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nlist_c = list(set(list_a) | set(list_b))\nvar_h = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 161.5\nvar_b = 154.3\nvar_c = 143.7\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 160.1\nvar_e = 158\nvar_f = 153.5\nvar_g = 147.8\nlist_b= []\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nlist_c = list(set(list_a) | set(list_b))\nvar_h = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "7624": {
        "category": "Comparison",
        "question_ko": "환희는 국어 80점, 수학 94점, 사회 82점, 영어 76점, 과학 100점을 받았습니다. 평균보다 점수가 낮은 과목은 몇 과목입니까?",
        "question_en": "Following numbers are points that Hwanhee got for his Korean, Mathematics, Social studies, English, and Science: 80, 94, 82, 76, and 100. How many subjects did he score below the average?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 80 94 82 76 100 [OP_LIST_EOL] [OP_LIST_MEAN] [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 80 94 82 76 100 [OP_LIST_EOL] [OP_LIST_MEAN] [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 80\nvar_b = 94\nvar_c = 82\nvar_d = 76\nvar_e = 100\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_f = sum(list_a)/len(list_a)\nlist_b = []\nfor i in list_a:\n    if i < var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 80\nvar_b = 94\nvar_c = 82\nvar_d = 76\nvar_e = 100\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_f = sum(list_a)/len(list_a)\nlist_b = []\nfor i in list_a:\n    if i < var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "7625": {
        "category": "Arithmetic calculation",
        "question_ko": "한 바구니에 16개씩 들어있는 고구마를 7바구니 샀습니다. 그중에서 13개는 싹이 나서 버리고, 남은 고구마를 8바구니에 똑같이 나누어 담으려고 합니다. 한 바구니에 몇 개씩 나누어 담게 됩니까?",
        "question_en": "I bought 7 baskets of sweet potatoes with 16 in each basket. Among them, 13 sprouted and were discarded, and the remaining sweet potatoes will be divided equally into 8 baskets. How many pieces will you put in each basket?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "16 7 [OP_MUL] 13 [OP_SUB] 8 [OP_FDIV]",
        "solution_abst_en": "16 7 [OP_MUL] 13 [OP_SUB] 8 [OP_FDIV]",
        "solution_code_ko": "var_a = 16\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = var_e // var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 16\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = var_e // var_f\nprint(int(var_g))"
    },
    "7626": {
        "category": "Comparison",
        "question_ko": "두 돼지가 있습니다. 두 돼지의 몸무게 차이는 72킬로그램(㎏)이 나고, 합은 348킬로그램(㎏)입니다. 둘 중 더 뚱뚱한 돼지의 몸무게를 구하시오.",
        "question_en": "There are two pigs. The difference in weight between the two pigs is 72 kilograms (kg), and the sum is 348 kilograms (kg). Find the weight of the fatter pig of the two.",
        "answer_ko": "210",
        "answer_en": "210",
        "solution_abst_ko": "72 348 [OP_ADD] 2 [OP_DIV]",
        "solution_abst_en": "72 348 [OP_ADD] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 72\nvar_b = 348\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 72\nvar_b = 348\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "7627": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이는 책을 읽다가 내일 이어서 읽기 위해 읽은 현재 펼쳐진 쪽수를 확인했습니다. 두 쪽수를 더한 값이 185가 되었다고 한다면, 작은 쪽은 몇 쪽인지 구하시오.",
        "question_en": "While reading the book, Jungkook checked the number of pages currently open to continue reading tomorrow. If the sum of the two pages is 185, what is the number of the smaller page?",
        "answer_ko": "92",
        "answer_en": "92",
        "solution_abst_ko": "185 2 [OP_FDIV]",
        "solution_abst_en": "185 2 [OP_FDIV]",
        "solution_code_ko": "var_a = 185\nvar_b = 2\nvar_c = var_a // var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 185\nvar_b = 2\nvar_c = var_a // var_b\nprint(int(var_c))"
    },
    "7628": {
        "category": "Arithmetic calculation",
        "question_ko": "지하 3미터(m)에 있던 풍선이 하늘로 올라간 지 4초만에 지상에 도착했다고 한다. 풍선이 지상 0.09킬로미터(㎞)를 넘어가면 터진다고 할 때, 풍선이 동일한 속력으로 올라간다면, 하늘로 올라간 지 몇 초 후에 풍선이 터지는지 구하시오.",
        "question_en": "It is said that the balloon, which was 3 meters (m) underground, reached the ground in 4 seconds after it went up into the sky. Assuming that the balloon bursts when it crosses 0.09 km (km) above the ground, and if it goes with the same velocity, how many seconds does the balloon pop after it rises into the sky?",
        "answer_ko": "124",
        "answer_en": "124",
        "solution_abst_ko": "0.09 1000 [OP_MUL] 3 [OP_ADD] 3 [OP_DIV] 4 [OP_MUL]",
        "solution_abst_en": "0.09 1000 [OP_MUL] 3 [OP_ADD] 3 [OP_DIV] 4 [OP_MUL]",
        "solution_code_ko": "var_a = 0.09\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = 4\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 0.09\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = 4\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "7629": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 학교에 1학년이 210명, 1학년이 아닌 학생이 473명이다. 전교생을 100명씩 한 줄로 세우면 몇 줄이 생기는가?(단, 100명이 온전히 다 서있는 줄만 샌다)",
        "question_en": "A school has 210 first-year students and 473 non-first-year students. How many lines will there be if all students are lined up in line with 100 students in a row? (However, only the line where all 100 students are standing counts.)",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "210 473 [OP_ADD] 100 [OP_FDIV]",
        "solution_abst_en": "210 473 [OP_ADD] 100 [OP_FDIV]",
        "solution_code_ko": "var_a = 210\nvar_b = 473\nvar_c = var_a + var_b\nvar_d = 100\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 210\nvar_b = 473\nvar_c = var_a + var_b\nvar_d = 100\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "7630": {
        "category": "Correspondence",
        "question_ko": "A82+3B=216입니다. B는 얼마인가요?",
        "question_en": "The equation of three-digit number and two-digit number is A82+3B=216. How much is B?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "A82+3B=216 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A82+3B=216 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A82+3B=216'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A82+3B=216'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "7631": {
        "category": "Possibility",
        "question_ko": "혜정이는 TV, 냉장고, 세탁기, 컴퓨터 중에서 두 가지 제품을 교체하려고 한다. 혜정이가 교체할 수 있는 두 가지 제품을 선택하는 경우의 수는?",
        "question_en": "Hyejeong wants to replace two products among TV, refrigerator, washing-machine, and computer. How many number of cases are there when Hyejeong chooses two products to change?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] TV 냉장고 세탁기 컴퓨터 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] TV refrigerator washing-machine computer [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_code_ko": "var_a = 'TV'\nvar_b = '냉장고'\nvar_c = '세탁기'\nvar_d = '컴퓨터'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g / (i+1)\nprint(int(var_g))",
        "solution_code_en": "var_a = 'TV'\nvar_b = 'refrigerator'\nvar_c = 'washing-machine'\nvar_d = 'computer'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g / (i+1)\nprint(int(var_g))"
    },
    "7632": {
        "category": "Possibility",
        "question_ko": "1부터 9까지의 숫자를 딱 한 번씩 사용하여 아홉 자리 수를 만들었다. 이 수가 55로 나누어 떨어질 때, 가장 작은 아홉자리 수를 구하여라.",
        "question_en": "The numbers 1 through 9 are used only once to form a nine-digit number. When this number is divisible by 55, find the smallest 9-digit number.",
        "answer_ko": "126374985",
        "answer_en": "126374985",
        "solution_abst_ko": "1 9 1 [OP_LIST_ARANGE] 9 [OP_LIST_GET_PERM] 55 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_abst_en": "1 9 1 [OP_LIST_ARANGE] 9 [OP_LIST_GET_PERM] 55 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 9\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 55\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[var_f-1]\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 9\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 55\nlist_c = []\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i % var_e == 0:\n        list_c.append(i)\nvar_f = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_g = list_d[var_f-1]\nprint(int(var_g))"
    },
    "7633": {
        "category": "Correspondence",
        "question_ko": "A를 7로 나눴더니 몫이 B가 되었고, 나머지는 C가 되었습니다. A, B, C는 자연수 입니다. 몫과 나머지가 같을 때, 가능한 B 중 가장 큰 수는 무엇인가요?",
        "question_en": "When A is divided by 7, the quotient is B and the remainder is C. In here, A, B, and C are natural numbers. What is the largest possible B number when the quotient and remainder are equal?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "7 1 [OP_SUB]",
        "solution_abst_en": "7 1 [OP_SUB]",
        "solution_code_ko": "var_a = 7\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 7\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "7634": {
        "category": "Arithmetic calculation",
        "question_ko": "지희네 모둠 학생 6명이 사회 수행평가를 하기 위해 컴퓨터가 있는 자료실에 갔습니다. 자료실에 남은 컴퓨터가 4대밖에 없어서 돌아가면서 컴퓨터를 시용하기로 했을 때, 수행평가를 하는 데 총 걸린 시간이 3시간 12분이라면 한 사람당 평균 몇 분씩 컴퓨터를 사용하였을지 구하시오.",
        "question_en": "Jihee's group of 6 students went to the reference room with computers to take a social performance assessment. If there are only 4 computers left in the data room and they decide to use the computers in turn, if the total time taken for the performance evaluation is 3 hours and 12 minutes, find out how many minutes each person used the computer on average.",
        "answer_ko": "128",
        "answer_en": "128",
        "solution_abst_ko": "3 60 [OP_MUL] 12 [OP_ADD] 6 [OP_DIV] 4 [OP_MUL]",
        "solution_abst_en": "3 60 [OP_MUL] 12 [OP_ADD] 6 [OP_DIV] 4 [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = var_c + var_d\nvar_f = 6\nvar_g = var_e / var_f\nvar_h = 4\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 3\nvar_b = 60\nvar_c = var_a * var_b\nvar_d = 12\nvar_e = var_c + var_d\nvar_f = 6\nvar_g = var_e / var_f\nvar_h = 4\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "7635": {
        "category": "Comparison",
        "question_ko": "이서는 미술 시간에 1/2미터(m)의 리본 테이프를 사용하였고, 원영이는 2/3미터(m)의 리본 테이프를 사용하였습니다. 두 친구 중 리본 테이프를 더 많이 사용한 친구는 누구입니까?",
        "question_en": "Lee-seo used 1/2 meter (m) of ribbon tape in art class, and Won-young used 2/3 meter (m) of ribbon tape. Which of the two friends used more ribbon tape?",
        "answer_ko": "원영",
        "answer_en": "Won-young",
        "solution_abst_ko": "[OP_LIST_SOL] 이서 원영 [OP_LIST_EOL] [OP_LIST_SOL] 1/2 2/3 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Lee-seo Won-young [OP_LIST_EOL] [OP_LIST_SOL] 1/2 2/3 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '이서'\nvar_b = '원영'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.5\nvar_d = 0.6666666666666666\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Lee-seo'\nvar_b = 'Won-young'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.5\nvar_d = 0.6666666666666666\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "7636": {
        "category": "Possibility",
        "question_ko": "노란색 구슬, 흰색 구슬, 빨간색 구슬, 보라색 구슬, 초록색 구슬, 파란색 구슬이 1개씩 있습니다. 이 구슬 중 서로 다른 2개의 구슬을 고르는 방법은 모두 몇 가지입니까?",
        "question_en": "There are 1 yellow marble, 1 white marble, 1 red marble, 1 purple marble, 1 green marble and 1 blue marble. How many different ways can there be to pick 2 different marbles?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "[OP_LIST_SOL] 노란색 흰색 빨간색 보라색 초록색 파란색 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] yellow white red purple green blue [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '노란색'\nvar_b = '흰색'\nvar_c = '빨간색'\nvar_d = '보라색'\nvar_e = '초록색'\nvar_f = '파란색'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = len(list_a)\nvar_h = 2\nvar_i = 1\nvar_g = int(var_g)\nvar_h = int(var_h)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i * (var_g-i)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i / (i+1)\nprint(int(var_i))",
        "solution_code_en": "var_a = 'yellow'\nvar_b = 'white'\nvar_c = 'red'\nvar_d = 'purple'\nvar_e = 'green'\nvar_f = 'blue'\nlist_a= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_g = len(list_a)\nvar_h = 2\nvar_i = 1\nvar_g = int(var_g)\nvar_h = int(var_h)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i * (var_g-i)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i / (i+1)\nprint(int(var_i))"
    },
    "7637": {
        "category": "Arithmetic calculation",
        "question_ko": "테이프 5개의 길이가 각각 35센티미터(㎝), 29센티미터(㎝), 35.5센티미터(㎝), 36센티미터(㎝), 30.5센티미터(㎝)라고 합니다. 이 테이프 5개의 평균 길이는 몇 센티미터(㎝)인지 소수점을 포함하여 답을 구하시오.",
        "question_en": "The lengths of the five tapes are 35 centimeters (cm), 29 centimeters (cm), 35.5 centimeters (cm), 36 centimeters (cm), and 30.5 centimeters (cm) respectively. What is the average length of these 5 tapes in centimeters (cm)? Include the decimal point in your answer.",
        "answer_ko": "33.20",
        "answer_en": "33.2",
        "solution_abst_ko": "[OP_LIST_SOL] 35 29 35.5 36 30.5 [OP_LIST_EOL] [OP_LIST_MEAN]",
        "solution_abst_en": "[OP_LIST_SOL] 35 29 35.5 36 30.5 [OP_LIST_EOL] [OP_LIST_MEAN]",
        "solution_code_ko": "var_a = 35\nvar_b = 29\nvar_c = 35.5\nvar_d = 36\nvar_e = 30.5\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_f = sum(list_a)/len(list_a)\nprint('{:.2f}'.format(round(var_f+1e-10,2)))",
        "solution_code_en": "var_a = 35\nvar_b = 29\nvar_c = 35.5\nvar_d = 36\nvar_e = 30.5\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nlist_a = [float(i) for i in list_a]\nvar_f = sum(list_a)/len(list_a)\nprint('{:.2f}'.format(round(var_f+1e-10,2)))"
    },
    "7638": {
        "category": "Correspondence",
        "question_ko": "17을 10으로 나누고 1/100을 곱하면 얼마인지 구하시오.",
        "question_en": "What is 17 divided by 10 and multiplied by 1/100?",
        "answer_ko": "0.02",
        "answer_en": "0.02",
        "solution_abst_ko": "17 10 [OP_DIV] 1/100 [OP_MUL]",
        "solution_abst_en": "17 10 [OP_DIV] 1/100 [OP_MUL]",
        "solution_code_ko": "var_a = 17\nvar_b = 10\nvar_c = var_a / var_b\nvar_d = 0.01\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 17\nvar_b = 10\nvar_c = var_a / var_b\nvar_d = 0.01\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "7639": {
        "category": "Comparison",
        "question_ko": "수 5개 1.4, 9/10, 1.2, 0.5, 13/10 중 1.1보다 크거나 같은 숫자를 구하고, 그 중에서 가장 작거나 같은 숫자를 구하면 무엇입니까?",
        "question_en": "Among the five numbers 1.4, 9/10, 1.2, 0.5, and 13/10, what is the number greater than or equal to 1.1 and the least or equal to it?",
        "answer_ko": "1.20",
        "answer_en": "1.2",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE_EQUAL] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE_EQUAL] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i >= var_f:\n        list_b.append(i)\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nprint('{:.2f}'.format(round(var_h+1e-10,2)))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i >= var_f:\n        list_b.append(i)\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nprint('{:.2f}'.format(round(var_h+1e-10,2)))"
    },
    "7640": {
        "category": "Arithmetic calculation",
        "question_ko": "4개의 숫자 3, 5, 7, 2를 한 번씩 모두 사용하여 만들 수 있는 네 자리 수 중 세 번째로 큰 것은 무엇인가?",
        "question_en": "What is the third largest four-digit number that can be formed by using all four numbers 3, 5, 7, and 2 at least once?",
        "answer_ko": "7352",
        "answer_en": "7352",
        "solution_abst_ko": "[OP_LIST_SOL] 3 5 7 2 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 3 5 7 2 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 3\nvar_b = 5\nvar_c = 7\nvar_d = 2\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint(int(var_g))",
        "solution_code_en": "var_a = 3\nvar_b = 5\nvar_c = 7\nvar_d = 2\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nprint(int(var_g))"
    },
    "7641": {
        "category": "Geometry",
        "question_ko": "어떤 한 모서리의 길이가 15센티미터(㎝)인 정육면체가 있을 때, 이 정육면체의 모든 모서리의 길이의 합을 구하시오.",
        "question_en": "Given a cube with an edge length of 15 centimeters (cm), find the sum of the lengths of all edges of the cube.",
        "answer_ko": "180",
        "answer_en": "180",
        "solution_abst_ko": "15 4 3 [OP_MUL] [OP_MUL]",
        "solution_abst_en": "15 4 3 [OP_MUL] [OP_MUL]",
        "solution_code_ko": "var_a = 15\nvar_b = 4\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 4\nvar_c = 3\nvar_d = var_b * var_c\nvar_e = var_a * var_d\nprint(int(var_e))"
    },
    "7642": {
        "category": "Possibility",
        "question_ko": "옷 가게에 상의는 후드가 5종류, 맨투맨이 4종류가 있고, 바지는 청바지가 3종류, 슬랙스가 5종류가 있다. 상의와 하의를 하나씩 고르는 경우의 수를 구하시오.",
        "question_en": "At the clothing store, there are 5 types of hoodies and 4 types of sweatshirts, 3 types of jeans, and 5 types of slacks for pants. Find the number of ways to choose one top and one bottom.",
        "answer_ko": "72",
        "answer_en": "72",
        "solution_abst_ko": "5 4 [OP_ADD] 3 5 [OP_ADD] [OP_MUL]",
        "solution_abst_en": "5 4 [OP_ADD] 3 5 [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 5\nvar_f = var_d + var_e\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 5\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 5\nvar_f = var_d + var_e\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "7643": {
        "category": "Geometry",
        "question_ko": "현주가 높이 53센티미터(㎝) 7밀리미터(㎜)인 2등 시상대에 올라서서 바닥에서부터 키를 재었더니 190센티미터(㎝)였고, 1등 시상대 위에 올라서서 바닥에서부터 키를 재었더니 232센티미터(㎝) 5밀리미터(㎜)였습니다. 1등 시상대의 높이는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "Hyeonjoo stood on the 2nd prize podium with a height of 53 centimeters (cm) and 7 millimeters (mm) and measured his height from the floor, and it was 190 centimeters (cm). She stood on the 1st prize podium and measured his height from the floor, and it was 232 centimeters (cm) and 5 millimeters (mm). Find the height in centimeters (cm) of the first-place podium.",
        "answer_ko": "96.20",
        "answer_en": "96.2",
        "solution_abst_ko": "232 5 10 [OP_DIV] [OP_ADD] 190 [OP_SUB] 53 7 10 [OP_DIV] [OP_ADD] [OP_ADD]",
        "solution_abst_en": "232 5 10 [OP_DIV] [OP_ADD] 190 [OP_SUB] 53 7 10 [OP_DIV] [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 232\nvar_b = 5\nvar_c = 10\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 190\nvar_g = var_e - var_f\nvar_h = 53\nvar_i = 7\nvar_j = 10\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_g + var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))",
        "solution_code_en": "var_a = 232\nvar_b = 5\nvar_c = 10\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 190\nvar_g = var_e - var_f\nvar_h = 53\nvar_i = 7\nvar_j = 10\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = var_g + var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))"
    },
    "7644": {
        "category": "Possibility",
        "question_ko": "색종이 15장을 정국이와 은지에게 나누어 주려고 합니다. 정국이와 은지는 적어도 색종이 1장을 받습니다. 색종이를 나누어 주는 방법은 모두 몇 가지입니까?",
        "question_en": "I'm going to hand out 15 pieces of colored paper to Jungkook and Eunji. Jungkook and Eunji will receive at least one piece of colored paper. How many ways are there to distribute the paper?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "15 2 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "15 2 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 15\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7645": {
        "category": "Correspondence",
        "question_ko": "3을 더했어야하는데 6을 어떤 수에 잘 못더하여 8이 됐습니다. 이때 어떤 수는 얼마인가?",
        "question_en": "You should have added 3, but mistakenly added 6 to a certain number, and ended up with 8. What number is this?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "8 6 [OP_SUB]",
        "solution_abst_en": "8 6 [OP_SUB]",
        "solution_code_ko": "var_a = 8\nvar_b = 6\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 8\nvar_b = 6\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "7646": {
        "category": "Arithmetic calculation",
        "question_ko": "연필 한 타는 12자루이고, 게는 182.88그램(g)입니다. 연필 한 자루의 무게는 몇 그램(g)인지 풀이 과정을 쓰고 답을 구해 보세요.",
        "question_en": "A dozen of pencils means 12 pencils, and it weighs 182.88 grams (g). Write down the process and find how many grams (g) a pencil weighs.",
        "answer_ko": "15.24",
        "answer_en": "15.24",
        "solution_abst_ko": "182.88 12 [OP_DIV]",
        "solution_abst_en": "182.88 12 [OP_DIV]",
        "solution_code_ko": "var_a = 182.88\nvar_b = 12\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 182.88\nvar_b = 12\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "7647": {
        "category": "Possibility",
        "question_ko": "부모를 포함하여 가족 5명이 나란히 서서 사진을 찍으려고 할 때, 부모가 양 끝에 서게 되는 경우의 수는?",
        "question_en": "If 5 family members, including their parents, stand side by side and try to take a picture, in how many ways will their parents stand at either end?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "5 2 [OP_SUB] 5 2 [OP_SUB] [OP_PERM] 2 [OP_MUL]",
        "solution_abst_en": "5 2 [OP_SUB] 5 2 [OP_SUB] [OP_PERM] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = 1\nvar_c = int(var_c)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_c-i)\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = 2\nvar_f = var_d - var_e\nvar_g = 1\nvar_c = int(var_c)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_c-i)\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "7648": {
        "category": "Possibility",
        "question_ko": "유나와 호석이가 사탕 8개를 나누어 가지려고 합니다. 각자 최소 1개씩은 가지도록 할 때, 사탕을 나누어 가지는 방법은 모두 몇 가지인지 구하시오.",
        "question_en": "Yuna and Hoseok want to share 8 candies. Find possible ways to divide the candies given that each person gets at least one.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "8 2 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "8 2 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7649": {
        "category": "Arithmetic calculation",
        "question_ko": "호석이는 매일 4장씩 수학문제집을 풀어 오늘까지 모두 48장을 풀었습니다. 호석이는 며칠 동안 수학 문제집을 풀었습니까?",
        "question_en": "Hoseok solves 4 pages of math workbook every day and has solved a total of 48 pages until today. How many days did Hoseok solve the workbook?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "48 4 [OP_DIV]",
        "solution_abst_en": "48 4 [OP_DIV]",
        "solution_code_ko": "var_a = 48\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 48\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "7650": {
        "category": "Possibility",
        "question_ko": "바구니에서 뽑을 수 있는 기회는 2번입니다. 바구니 속에 사과, 복숭아, 배, 참외가 각각 1개씩 들어가있는 바구니에서 차례를 고려하여 과일을 뽑는다면, 가능한 경우의 수는 몇 가지입니까?",
        "question_en": "You have 2 chances to pick from a basket. If you pick a fruit from a basket with one apple, one peach, one pear, and one melon in the basket minding the order, how many possible cases are there?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 복숭아 배 참외 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_abst_en": "[OP_LIST_SOL] apple peach pear melon [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '복숭아'\nvar_c = '배'\nvar_d = '참외'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nprint(int(var_g))",
        "solution_code_en": "var_a = 'apple'\nvar_b = 'peach'\nvar_c = 'pear'\nvar_d = 'melon'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nprint(int(var_g))"
    },
    "7651": {
        "category": "Arithmetic calculation",
        "question_ko": "두 바구니 (가), (나)에 담겨 있는 사과는 모두 72킬로그램(㎏)입니다. (가) 바구니에 담긴 사과의 무게가 42킬로그램(㎏)일 때, (나) 바구니에 담긴 사과는 (가) 바구니에 담긴 사과보다 몇 킬로그램(㎏) 더 가볍습니까?",
        "question_en": "The apples in both baskets (a) and (b) are 72 kilograms (kg). If (a) the apples in the basket weigh 42 kilograms (kg), how many kilograms (kg) are the apples in (b) lighter than the apples in the basket (a)?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "42 72 42 [OP_SUB] [OP_SUB]",
        "solution_abst_en": "42 72 42 [OP_SUB] [OP_SUB]",
        "solution_code_ko": "var_a = 42\nvar_b = 72\nvar_c = 42\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 42\nvar_b = 72\nvar_c = 42\nvar_d = var_b - var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "7652": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중에서 가장 큰 수와 2번째로 작은 수의 곱은 얼마입니까?",
        "question_en": "There are three numbers 10, 11 and 12. What is the product of the largest number and the second smallest number?",
        "answer_ko": "132",
        "answer_en": "132",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_MUL]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e * var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e * var_g\nprint(int(var_h))"
    },
    "7653": {
        "category": "Correspondence",
        "question_ko": "32+A7B=705일 때, A를 구하시오.",
        "question_en": "When 32+A7B=705, where A7B is three-digit number. Find A.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "32+A7B=705 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "32+A7B=705 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '32+A7B=705'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '32+A7B=705'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "7654": {
        "category": "Geometry",
        "question_ko": "한변의 길이가 7센티미터(㎝)인 정사면체의 겉넓이는?",
        "question_en": "What is the surface area of a tetrahedron with a side of 7 centimeters (cm)?",
        "answer_ko": "84.87",
        "answer_en": "84.87",
        "solution_abst_ko": "3 1/2 [OP_POW] 7 2 [OP_POW] [OP_MUL]",
        "solution_abst_en": "3 1/2 [OP_POW] 7 2 [OP_POW] [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 0.5\nvar_c = var_a ** var_b\nvar_d = 7\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 3\nvar_b = 0.5\nvar_c = var_a ** var_b\nvar_d = 7\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "7655": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 2를 더하고 8을 더한 값은 어떤 수의 3배와 같다. 어떤 수를 구하시오.",
        "question_en": "A number plus 2 plus 8 is equal to 3 times that number. Find the number.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "2 8 [OP_ADD] 3 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "2 8 [OP_ADD] 3 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 2\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 2\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))"
    },
    "7656": {
        "category": "Correspondence",
        "question_ko": "등식 5A8-B14=364이 성립한다고 합니다. B에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "Say that the equation 5A8-B14=364 holds. What number should be in B?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "5A8-B14=364 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "5A8-B14=364 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '5A8-B14=364'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '5A8-B14=364'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "7657": {
        "category": "Comparison",
        "question_ko": "다섯 명의 학생 윤기, 정국, 유나, 유정, 태형은 각각 7, 6, 9, 8, 10만큼의 숫자를 가지고 있습니다. 2번째로 작은 숫자를 가진 사람은 누구입니까?",
        "question_en": "The five students, Yoongi, Jungkook, Yuna, Yoojeong, and Taehyung, each have the numbers 7, 6, 9, 8, and 10. Who has the 2nd smallest number?",
        "answer_ko": "윤기",
        "answer_en": "Yoongi",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 유나 유정 태형 [OP_LIST_EOL] [OP_LIST_SOL] 7 6 9 8 10 [OP_LIST_EOL] 2 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook Yuna Yoojeong Taehyung [OP_LIST_EOL] [OP_LIST_SOL] 7 6 9 8 10 [OP_LIST_EOL] 2 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nvar_c = '유나'\nvar_d = '유정'\nvar_e = '태형'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 7\nvar_g = 6\nvar_h = 9\nvar_i = 8\nvar_j = 10\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_k = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[var_k-1]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nvar_c = 'Yuna'\nvar_d = 'Yoojeong'\nvar_e = 'Taehyung'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 7\nvar_g = 6\nvar_h = 9\nvar_i = 8\nvar_j = 10\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_k = 2\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[var_k-1]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "7658": {
        "category": "Comparison",
        "question_ko": "20명의 학생들이 한 줄로 줄을 섰습니다. 정국이는 윤기보다 앞에 서 있고, 윤기와 정국이 사이에는 5명의 학생이 있습니다. 정국의 뒤에는 6명의 학생들이 서 있습니다. 윤기의 앞에 서 있는 학생은 몇 명입니까?",
        "question_en": "20 students lined up in a single line. Jungkook is standing in front of Yoongi, and there are 5 students between Yoongi and Jungkook. There are 6 students standing behind Jungkook. How many students are standing in front of Yoongi?",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "20 6 [OP_SUB] 1 [OP_SUB] 5 [OP_ADD] 1 [OP_SUB]",
        "solution_abst_en": "20 6 [OP_SUB] 1 [OP_SUB] 5 [OP_ADD] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 20\nvar_b = 6\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 5\nvar_g = var_e + var_f\nvar_h = 1\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 20\nvar_b = 6\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 5\nvar_g = var_e + var_f\nvar_h = 1\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "7659": {
        "category": "Arithmetic calculation",
        "question_ko": "16명의 학생들이 10.4센티미터(㎝)씩 팔을 벌려 3.5센티미터(㎝)씩 겹치게 하여 원 모양으로 이어 섰습니다. 이렇게 만든 원의 길이는 몇 센티미터(㎝)인가요?",
        "question_en": "Sixteen students stood in a circle with arms spread 10.4 centimeters (cm) apart and overlapping each other by 3.5 centimeters (cm). How many centimeters (cm) is the length of this circle?",
        "answer_ko": "110.40",
        "answer_en": "110.4",
        "solution_abst_ko": "10.4 3.5 [OP_SUB] 16 [OP_MUL]",
        "solution_abst_en": "10.4 3.5 [OP_SUB] 16 [OP_MUL]",
        "solution_code_ko": "var_a = 10.4\nvar_b = 3.5\nvar_c = var_a - var_b\nvar_d = 16\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 10.4\nvar_b = 3.5\nvar_c = var_a - var_b\nvar_d = 16\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "7660": {
        "category": "Arithmetic calculation",
        "question_ko": "현주는 매일 우유를 마십니다. 20일 동안은 하루에 250밀리리터(㎖)씩 마셨고 그 후 13일 동안은 600밀리리터(㎖)씩 마셨습니다. 33일 동안 현주가 마신 우유는 몇 리터(L)인지 구하시오.",
        "question_en": "Hyunjoo drinks milk every day. She drank 250 milliliters (ml) per day for 20 days and then 600 milliliters (ml) per day for 13 days. Find how many liters (L) of milk Hyeonjoo drank for 33 days.",
        "answer_ko": "12.80",
        "answer_en": "12.8",
        "solution_abst_ko": "250 20 [OP_MUL] 600 13 [OP_MUL] [OP_ADD] 1000 [OP_DIV]",
        "solution_abst_en": "250 20 [OP_MUL] 600 13 [OP_MUL] [OP_ADD] 1000 [OP_DIV]",
        "solution_code_ko": "var_a = 250\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 600\nvar_e = 13\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 1000\nvar_i = var_g / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))",
        "solution_code_en": "var_a = 250\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 600\nvar_e = 13\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 1000\nvar_i = var_g / var_h\nprint('{:.2f}'.format(round(var_i+1e-10,2)))"
    },
    "7661": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 11을 곱했더니 103.95가 되었습니다. 어떤 수는 얼마입니까?",
        "question_en": "When you multiply a number by 11, you get 103.95. What number is it?",
        "answer_ko": "9.45",
        "answer_en": "9.45",
        "solution_abst_ko": "103.95 11 [OP_DIV]",
        "solution_abst_en": "103.95 11 [OP_DIV]",
        "solution_code_ko": "var_a = 103.95\nvar_b = 11\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 103.95\nvar_b = 11\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "7662": {
        "category": "Arithmetic calculation",
        "question_ko": "석진이는 사과를 32개 가지고 있었습니다. 일주일 동안 매일 같은 개수씩 사과를 먹었더니 4개가 남았습니다. 석진이는 하루에 사과를 몇 개씩 먹었습니까?",
        "question_en": "Seokjin had 32 apples. After eating the same number of apples every day for a week, there are 4 left. How many apples did Seokjin eat a day?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "32 4 [OP_SUB] 7 [OP_DIV]",
        "solution_abst_en": "32 4 [OP_SUB] 7 [OP_DIV]",
        "solution_code_ko": "var_a = 32\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 7\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 32\nvar_b = 4\nvar_c = var_a - var_b\nvar_d = 7\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "7663": {
        "category": "Possibility",
        "question_ko": "0, 1, 3을 한 번씩 모두 사용하여 만들 수 있는 가장 큰 자연수는 무엇입니까?",
        "question_en": "What is the largest natural number that can be formed using all 0, 1, and 3 once?",
        "answer_ko": "310",
        "answer_en": "310",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 3 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 3 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))"
    },
    "7664": {
        "category": "Geometry",
        "question_ko": "지름이 30센티미터(㎝)인 장난감 자동차 바퀴의 둘레는 94.2센티미터(㎝)입니다. 장난감 자동차 바퀴의 둘레는 지름의 몇 배입니까?",
        "question_en": "A toy car wheel with a diameter of 30 centimeters (cm) has a circumference of 94.2 centimeters (cm). How many times the circumference of a toy car wheel is greater than the diameter?",
        "answer_ko": "3.14",
        "answer_en": "3.14",
        "solution_abst_ko": "94.2 30 [OP_DIV]",
        "solution_abst_en": "94.2 30 [OP_DIV]",
        "solution_code_ko": "var_a = 94.2\nvar_b = 30\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 94.2\nvar_b = 30\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "7665": {
        "category": "Arithmetic calculation",
        "question_ko": "은지는 수요일에 논문을 18페이지 읽었고, 목요일에도 읽었습니다. 이 논문을 금요일에 23쪽 읽어서 3일 동안 모두 60쪽 읽었습니다. 은지는 목요일에 논문을 몇 쪽 읽었습니까?",
        "question_en": "Eunji read 18 pages of the thesis on Wednesday, and also read it on Thursday. She read 23 pages of this thesis on Friday, resulting in 60 pages being read for 3 days. How many pages did Eunji read on Thursday?",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "60 18 [OP_SUB] 23 [OP_SUB]",
        "solution_abst_en": "60 18 [OP_SUB] 23 [OP_SUB]",
        "solution_code_ko": "var_a = 60\nvar_b = 18\nvar_c = var_a - var_b\nvar_d = 23\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 60\nvar_b = 18\nvar_c = var_a - var_b\nvar_d = 23\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "7666": {
        "category": "Geometry",
        "question_ko": "전체 부피가 57세제곱센티미터(㎤) 인 직육면체에 높이가 절반에 올 때 까지 물을 채우려고 한다. 수도꼭지를 열면 물이 분 당 32밀리리터(㎖)가 흘러나온다고 할 때 몇 분간 수도꼭지를 틀어놔야하는지 구하시오.",
        "question_en": "A cuboid with a total volume of 57 cubic centimeters (cm3) is about to be filled with water until it reaches half of its height. If 32 milliliters (ml) of water flow out per minute when you open the faucet, find how many minutes you need to leave the faucet running.",
        "answer_ko": "36",
        "answer_en": "36",
        "solution_abst_ko": "576 2 [OP_MUL] 32 [OP_DIV]",
        "solution_abst_en": "576 2 [OP_MUL] 32 [OP_DIV]",
        "solution_code_ko": "var_a = 576\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 32\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 576\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 32\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "7667": {
        "category": "Arithmetic calculation",
        "question_ko": "2리터(L)의 물이 들어있는 물통에 460밀리리터(㎖)의 물을 더 부었습니다. 물통에 들어있는 물은 모두 몇 밀리리터(㎖)입니까?",
        "question_en": "An additional 460 milliliters (ml) of water was poured into a bucket already containing 2 liters (L) of water. How many milliliters (ml) are there in the bucket?",
        "answer_ko": "2460",
        "answer_en": "2460",
        "solution_abst_ko": "2 1000 [OP_MUL] 460 [OP_ADD]",
        "solution_abst_en": "2 1000 [OP_MUL] 460 [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 460\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 460\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7668": {
        "category": "Comparison",
        "question_ko": "사과는 한 상자에 28개씩 40상자 있고, 복숭아는 한 상자에 15개씩 65상자 있습니다. 사과와 복숭아 중에서 어느 것이 더 많습니까?",
        "question_en": "There are 40 boxes of apples, 28 each, and 65 peaches, 15 each. Which is more, apples or peaches?",
        "answer_ko": "사과",
        "answer_en": "apples",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 복숭아 [OP_LIST_EOL] [OP_LIST_SOL] 28 40 [OP_MUL] 15 65 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] apples peaches [OP_LIST_EOL] [OP_LIST_SOL] 28 40 [OP_MUL] 15 65 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '복숭아'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 28\nvar_d = 40\nvar_e = var_c * var_d\nvar_f = 15\nvar_g = 65\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'apples'\nvar_b = 'peaches'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 28\nvar_d = 40\nvar_e = var_c * var_d\nvar_f = 15\nvar_g = 65\nvar_h = var_f * var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "7669": {
        "category": "Geometry",
        "question_ko": "직각삼각형의 빗변의 길이가 10, 빗변이 아닌 한 변의 길이가 6이면 나머지 한 변의 길이는 얼마입니까?",
        "question_en": "If the length of the hypotenuse of a right triangle is 10 and the length of the non-hypotenuse is 6, what is the length of the other side?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "10 2 [OP_POW] 6 2 [OP_POW] [OP_SUB] 1/2 [OP_POW]",
        "solution_abst_en": "10 2 [OP_POW] 6 2 [OP_POW] [OP_SUB] 1/2 [OP_POW]",
        "solution_code_ko": "var_a = 10\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c - var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 6\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c - var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))"
    },
    "7670": {
        "category": "Comparison",
        "question_ko": "창고에 똑같은 선반이 28개 있습니다. 각 선반은 6칸이고, 각 칸마다 꽂혀 있는 책의 수는 19개로 같습니다. 창고에 있는 책은 모두 몇 권입니까?",
        "question_en": "There are 28 identical shelves in the warehouse. Each shelf has 6 spaces, and the number of books on each shelf is the same at 19. How many books are there in the warehouse?",
        "answer_ko": "3192",
        "answer_en": "3192",
        "solution_abst_ko": "28 6 [OP_MUL] 19 [OP_MUL]",
        "solution_abst_en": "28 6 [OP_MUL] 19 [OP_MUL]",
        "solution_code_ko": "var_a = 28\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 19\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 28\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 19\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "7671": {
        "category": "Arithmetic calculation",
        "question_ko": "윤아는 3월부터 매월 20000원씩 국제 아동 후원 단체에 기부를 하기로 했습니다. 윤아가 8월까지 기부한 금액은 모두 얼마일까요?",
        "question_en": "Starting in March, Yoona decided to donate 20,000 won per month to an international child support organization. How much did Yoona donate until August?",
        "answer_ko": "120000",
        "answer_en": "120000",
        "solution_abst_ko": "20000 8 3 [OP_SUB] 1 [OP_ADD] [OP_MUL]",
        "solution_abst_en": "20000 8 3 [OP_SUB] 1 [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 20000\nvar_b = 8\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = var_a * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 20000\nvar_b = 8\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = 1\nvar_f = var_d + var_e\nvar_g = var_a * var_f\nprint(int(var_g))"
    },
    "7672": {
        "category": "Arithmetic calculation",
        "question_ko": "5%의 설탕물 200그램(g)에서 몇 그램(g)의 물을 증발시켜야 8%의 설탕물이 되는지 구하여라",
        "question_en": "Find how many grams (g) of water must be evaporated from 200 grams (g) of 5% sugar water to make it 8% sugar water.",
        "answer_ko": "75",
        "answer_en": "75",
        "solution_abst_ko": "200 200 5 100 [OP_DIV] [OP_MUL] 100 8 [OP_DIV] [OP_MUL] [OP_SUB]",
        "solution_abst_en": "200 200 5 100 [OP_DIV] [OP_MUL] 100 8 [OP_DIV] [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 200\nvar_b = 200\nvar_c = 5\nvar_d = 100\nvar_e = var_c / var_d\nvar_f = var_b * var_e\nvar_g = 100\nvar_h = 8\nvar_i = var_g / var_h\nvar_j = var_f * var_i\nvar_k = var_a - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 200\nvar_b = 200\nvar_c = 5\nvar_d = 100\nvar_e = var_c / var_d\nvar_f = var_b * var_e\nvar_g = 100\nvar_h = 8\nvar_i = var_g / var_h\nvar_j = var_f * var_i\nvar_k = var_a - var_j\nprint(int(var_k))"
    },
    "7673": {
        "category": "Arithmetic calculation",
        "question_ko": "2시간 30동안 수조에 물을 받았더니 180리터(L)를 수조에 받았다. 1시간 동안 몇 리터(L)의 물이 흘러나왔는지 구하시오.",
        "question_en": "After receiving water in the water tank for 2 hours and 30 hours, 180 liters (L) were received in the water tank. Find how many liters (L) of water flowed out in 1 hour.",
        "answer_ko": "72",
        "answer_en": "72",
        "solution_abst_ko": "180 2 30 60 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_abst_en": "180 2 30 60 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 180\nvar_b = 2\nvar_c = 30\nvar_d = 60\nvar_e = var_c / var_d\nvar_f = var_b + var_e\nvar_g = var_a / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 180\nvar_b = 2\nvar_c = 30\nvar_d = 60\nvar_e = var_c / var_d\nvar_f = var_b + var_e\nvar_g = var_a / var_f\nprint(int(var_g))"
    },
    "7674": {
        "category": "Arithmetic calculation",
        "question_ko": "담을 칠하는 데 페인트 6.12리터(L)가 필요하다고 합니다. 페인트 33.5리터(L)로 5개의 담을 모두 칠하고 남는 양은 몇 밀리리터(㎖)입니까?",
        "question_en": "It is said that it takes 6.12 liters (L) of paint to paint a wall. How many milliliters (ml) are left after painting the 5 walls with 33.5 liters (L) of paint?",
        "answer_ko": "2900",
        "answer_en": "2900",
        "solution_abst_ko": "33.5 6.12 [OP_MOD] 1000 [OP_MUL]",
        "solution_abst_en": "33.5 6.12 [OP_MOD] 1000 [OP_MUL]",
        "solution_code_ko": "var_a = 33.5\nvar_b = 6.12\nvar_c = var_a % var_b\nvar_d = 1000\nvar_e = var_c * var_d\nprint(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))",
        "solution_code_en": "var_a = 33.5\nvar_b = 6.12\nvar_c = var_a % var_b\nvar_d = 1000\nvar_e = var_c * var_d\nprint(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))"
    },
    "7675": {
        "category": "Comparison",
        "question_ko": "두 자리 수끼리의 곱셈에서 곱하는 수의 십의 자리 숫자 5를 3으로 잘못 보고 계산한 값이 1485가 되었습니다. 바르게 계산한 값이 2385일 때, 2개의 두 자리 수 중 더 큰 수를 쓰시오.",
        "question_en": "In the multiplication of two-digit numbers, number 3 was mistakenly calculated instead of 5 in the tens place, and the value turned out to be 1485. If the correct answer is 2385, write the larger number among those two-digit numbers.",
        "answer_ko": "45",
        "answer_en": "45",
        "solution_abst_ko": "[OP_LIST_SOL] 1485 2385 [OP_SUB] 3 5 [OP_SUB] 10 [OP_MUL] [OP_DIV] 2385 1285 2385 [OP_SUB] 3 5 [OP_SUB] 10 [OP_MUL] [OP_DIV] [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1485 2385 [OP_SUB] 3 5 [OP_SUB] 10 [OP_MUL] [OP_DIV] 2385 1285 2385 [OP_SUB] 3 5 [OP_SUB] 10 [OP_MUL] [OP_DIV] [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1485\nvar_b = 2385\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = 5\nvar_f = var_d - var_e\nvar_g = 10\nvar_h = var_f * var_g\nvar_i = var_c / var_h\nvar_j = 2385\nvar_k = 1285\nvar_l = 2385\nvar_m = var_k - var_l\nvar_n = 3\nvar_o = 5\nvar_p = var_n - var_o\nvar_q = 10\nvar_r = var_p * var_q\nvar_s = var_m / var_r\nvar_t = var_j / var_s\nlist_a= []\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_a.append(var_t)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nlist_a.reverse()\nvar_u = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_v = list_b[-var_u]\nprint(int(var_v))",
        "solution_code_en": "var_a = 1485\nvar_b = 2385\nvar_c = var_a - var_b\nvar_d = 3\nvar_e = 5\nvar_f = var_d - var_e\nvar_g = 10\nvar_h = var_f * var_g\nvar_i = var_c / var_h\nvar_j = 2385\nvar_k = 1285\nvar_l = 2385\nvar_m = var_k - var_l\nvar_n = 3\nvar_o = 5\nvar_p = var_n - var_o\nvar_q = 10\nvar_r = var_p * var_q\nvar_s = var_m / var_r\nvar_t = var_j / var_s\nlist_a= []\nif \"/\" in str(var_t):\n    var_t = eval(str(var_t))\nlist_a.append(var_t)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nlist_a.reverse()\nvar_u = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_v = list_b[-var_u]\nprint(int(var_v))"
    },
    "7676": {
        "category": "Geometry",
        "question_ko": "밑면의 모양이 구각형인 각기둥이 있습니다. 이 각기둥의 모서리의 수는 몇 개입니까?",
        "question_en": "There is a prism with a nonagon base shape. How many edges does this prism have?",
        "answer_ko": "27",
        "answer_en": "27",
        "solution_abst_ko": "9 3 [OP_MUL]",
        "solution_abst_en": "9 3 [OP_MUL]",
        "solution_code_ko": "var_a = 9\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 9\nvar_b = 3\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "7677": {
        "category": "Geometry",
        "question_ko": "가로 3센티미터(㎝), 세로 4센티미터(㎝)인 직사격형 모양의 타일을 늘어놓아 될 수 있는 대로 작은 정사각형을 만들었습니다. 이때 정사각형의 한 변의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "You made a small square as much as possible by arranging the rectangular shape tiles of 3 centimeters (cm) wide and 4 centimeters (cm) long. How many centimeters (cm) is the length of one side of the square?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "3 4 [OP_LCM]",
        "solution_abst_en": "3 4 [OP_LCM]",
        "solution_code_ko": "var_a = 3\nvar_b = 4\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 4\nvar_c = var_b * var_a / math.gcd(int(var_b), int(var_a))\nprint(int(var_c))"
    },
    "7678": {
        "category": "Correspondence",
        "question_ko": "k리그에 있는 축구팀들은 1년에 리그에 있는 서로 다른 팀들과 모두 1판씩 경기를 치룬다. 1년에 경기가 모두 91개 있다면 k리그에 있는 축구팀은 모두 몇 개입니까?",
        "question_en": "Soccer teams in the K-League play one game against all other teams in the league in a year. If there are 91 matches in a year, how many soccer teams are there in the K-League?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "91 2 [OP_MUL] 1/2 [OP_POW] 1 [OP_CEIL]",
        "solution_abst_en": "91 2 [OP_MUL] 1/2 [OP_POW] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 91\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 1\nvar_g=int(((var_e+9*10**(var_f-2))//(10**(var_f-1)))*10**(var_f-1))\n\nprint(int(var_g))",
        "solution_code_en": "var_a = 91\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 0.5\nvar_e = var_c ** var_d\nvar_f = 1\nvar_g=int(((var_e+9*10**(var_f-2))//(10**(var_f-1)))*10**(var_f-1))\n\nprint(int(var_g))"
    },
    "7679": {
        "category": "Possibility",
        "question_ko": "다섯 개의 서로 다른 공룡 인형이 있다. 친구 두 명에게 하나씩 주기로 했을 때, 가능한 경우의 수를 구하시오.",
        "question_en": "There are five different dinosaur dolls. Find the number of possible ways to give one each to two friends.",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "5 2 [OP_PERM]",
        "solution_abst_en": "5 2 [OP_PERM]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))"
    },
    "7680": {
        "category": "Arithmetic calculation",
        "question_ko": "호석이는 꽃을 18송이 가지고 있었습니다. 호석이는 꽃을 민영이에게 5송이 주고, 유정이에게 6송이 주었습니다. 호석이에게 남은 꽃은 몇 송이입니까?",
        "question_en": "Hoseok had 18 flowers. Hoseok gave 5 flowers to Minyoung and 6 to Yoojeong. How many flowers does Hoseok have left?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "18 5 [OP_SUB] 6 [OP_SUB]",
        "solution_abst_en": "18 5 [OP_SUB] 6 [OP_SUB]",
        "solution_code_ko": "var_a = 18\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 18\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 6\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "7681": {
        "category": "Possibility",
        "question_ko": "10개의 숫자 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 중 서로 다른 세 개를 택하여 일렬로 나열하여 만든 세 자리의 자연수 중 300 이하의 홀수의 개수를 구하시오.",
        "question_en": "Find the number of odd numbers less than or equal to 300 out of the three-digit natural numbers which are formed by arranging three different digits chosen among 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9.",
        "answer_ko": "72",
        "answer_en": "72",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 3 4 5 6 7 8 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 300 [OP_LIST_LESS_EQUAL] 2 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 3 4 5 6 7 8 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 300 [OP_LIST_LESS_EQUAL] 2 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nvar_f = 5\nvar_g = 6\nvar_h = 7\nvar_i = 8\nvar_j = 9\nlist_a= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_a.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_k = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_k))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_l = 300\nlist_c = []\nfor i in list_b:\n    if i <= var_l:\n        list_c.append(i)\nvar_m = 2\nlist_d = []\nvar_m = int(var_m)\nfor i in list_c:\n    i = int(i)\n    if i % var_m == 0:\n        list_d.append(i)\nlist_e = list(set(list_c) - set(list_d))\nvar_n = len(list_e)\nprint(int(var_n))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 3\nvar_e = 4\nvar_f = 5\nvar_g = 6\nvar_h = 7\nvar_i = 8\nvar_j = 9\nlist_a= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_a.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_a.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_a.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_a.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_a.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_k = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_k))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_l = 300\nlist_c = []\nfor i in list_b:\n    if i <= var_l:\n        list_c.append(i)\nvar_m = 2\nlist_d = []\nvar_m = int(var_m)\nfor i in list_c:\n    i = int(i)\n    if i % var_m == 0:\n        list_d.append(i)\nlist_e = list(set(list_c) - set(list_d))\nvar_n = len(list_e)\nprint(int(var_n))"
    },
    "7682": {
        "category": "Arithmetic calculation",
        "question_ko": "화단에 카네이션이 13송이, 튤립이 7송이 있습니다. 카네이션은 튤립보다 몇 송이 더 많습니까?",
        "question_en": "There are 13 carnations and 7 tulips in the flower bed. How many more carnations are there than tulips?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "13 7 [OP_SUB]",
        "solution_abst_en": "13 7 [OP_SUB]",
        "solution_code_ko": "var_a = 13\nvar_b = 7\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 13\nvar_b = 7\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "7683": {
        "category": "Correspondence",
        "question_ko": "등식 32+A7B=705이 성립한다고 합니다. B에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "Provided that the equation 32+A7B=705 is true, what number should go in B?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "32+A7B=705 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "32+A7B=705 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '32+A7B=705'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '32+A7B=705'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "7684": {
        "category": "Arithmetic calculation",
        "question_ko": "문제를 45문제 푼 뒤 다시 18문제를 더 풀었습니다. 푼 문제의 수는 총 몇 문제입니까?",
        "question_en": "After solving 45 problems, 18 more problems were solved. What is the total number of problems solved?",
        "answer_ko": "63",
        "answer_en": "63",
        "solution_abst_ko": "45 18 [OP_ADD]",
        "solution_abst_en": "45 18 [OP_ADD]",
        "solution_code_ko": "var_a = 45\nvar_b = 18\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 45\nvar_b = 18\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "7685": {
        "category": "Possibility",
        "question_ko": "사과, 복숭아, 배, 참외를 조합하여 2개의 과일을 사려고 합니다. 중복을 허용하여 조합할 수 있는 경우의 수는 모두 몇 가지입니까?",
        "question_en": "You are trying to buy 2 fruits by combining apple, peach, pear, and melon. How many possible combinations allow for duplicates?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 복숭아 배 참외 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] apple peach pear melon [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '복숭아'\nvar_c = '배'\nvar_d = '참외'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = var_e + var_f\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = 2\nvar_k = 1\nvar_i = int(var_i)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_i-i)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k / (i+1)\nprint(int(var_k))",
        "solution_code_en": "var_a = 'apple'\nvar_b = 'peach'\nvar_c = 'pear'\nvar_d = 'melon'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = var_e + var_f\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = 2\nvar_k = 1\nvar_i = int(var_i)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_i-i)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k / (i+1)\nprint(int(var_k))"
    },
    "7686": {
        "category": "Correspondence",
        "question_ko": "40개의 성냥과 34개의 면봉이 있습니다. 고무줄로 성냥과 면봉을 묶는데 성냥은 8개씩 면봉은 12개씩 묶고 남는 것들은 묶지 않습니다. 한 묶음에 고무줄을 2개씩 사용한다고 할 때, 고무줄은 최소 몇 개가 필요합니까?",
        "question_en": "There are 40 matches and 34 cotton swabs. You are tying matches and cotton swabs together with rubber bands, tying 8 matches together and 12 cotton swabs together, and leaving the rest untied. If you use 2 rubber bands for one bundle, how many rubber bands do you need at least?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "40 8 [OP_FDIV] 34 12 [OP_FDIV] [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "40 8 [OP_FDIV] 34 12 [OP_FDIV] [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 40\nvar_b = 8\nvar_c = var_a // var_b\nvar_d = 34\nvar_e = 12\nvar_f = var_d // var_e\nvar_g = var_c + var_f\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 40\nvar_b = 8\nvar_c = var_a // var_b\nvar_d = 34\nvar_e = 12\nvar_f = var_d // var_e\nvar_g = var_c + var_f\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "7687": {
        "category": "Geometry",
        "question_ko": "반지름이 50센티미터(㎝)인 원의 둘레에 간격이 7.85센티미터(㎝)가 되도록 점을 찍으려고 합니다. 원주율이 3.14일 때 점을 모두 몇 개 찍을 수 있습니까?",
        "question_en": "You want to place points on the circumference of a circle with a radius of 50 centimeters (cm) so that they are spaced 7.85 centimeters (cm) apart. How many points can you put together when the pi is 3.14?",
        "answer_ko": "40",
        "answer_en": "40",
        "solution_abst_ko": "50 2 [OP_MUL] 3.14 [OP_MUL] 7.85 [OP_FDIV]",
        "solution_abst_en": "50 2 [OP_MUL] 3.14 [OP_MUL] 7.85 [OP_FDIV]",
        "solution_code_ko": "var_a = 50\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 3.14\nvar_e = var_c * var_d\nvar_f = 7.85\nvar_g = var_e // var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 50\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 3.14\nvar_e = var_c * var_d\nvar_f = 7.85\nvar_g = var_e // var_f\nprint(int(var_g))"
    },
    "7688": {
        "category": "Arithmetic calculation",
        "question_ko": "아버지는 닭 45마리를 기르는데 닭이 오리보다 8마리가 많습니다. 아버지가 기르는 닭과 오리는 모두 몇 마리입니까?",
        "question_en": "My father has 45 chickens, and there are 8 more chickens than ducks. How many chickens and ducks does my father have in total?",
        "answer_ko": "82",
        "answer_en": "82",
        "solution_abst_ko": "45 45 8 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "45 45 8 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 45\nvar_b = 45\nvar_c = 8\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 45\nvar_b = 45\nvar_c = 8\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "7689": {
        "category": "Arithmetic calculation",
        "question_ko": "창희는 이번 학기에 중간고사에서 열 과목의 평균 성적으로 83.1점을 받았고, 기말고사에서 여덟 과목의 평균 성적으로 84점을 받았습니다. 이번 학기 창희의 평균 성적은 몇 점입니까?",
        "question_en": "Changhee received an average score of 83.1 in ten subjects in the midterm exam this semester, and an average score of 84 in eight subjects in the final exam. What is Changhee's average score this semester?",
        "answer_ko": "83.50",
        "answer_en": "83.5",
        "solution_abst_ko": "10 83.1 [OP_MUL] 8 84 [OP_MUL] [OP_ADD] 10 8 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "10 83.1 [OP_MUL] 8 84 [OP_MUL] [OP_ADD] 10 8 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 83.1\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = 84\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 10\nvar_i = 8\nvar_j = var_h + var_i\nvar_k = var_g / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 10\nvar_b = 83.1\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = 84\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 10\nvar_i = 8\nvar_j = var_h + var_i\nvar_k = var_g / var_j\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "7690": {
        "category": "Comparison",
        "question_ko": "각각의 크기가 다른 상자 45개를 크기가 큰 것부터 순서대로 한 줄로 놓았습니다. 빨간색 상자는 왼쪽에서 29번째에 있습니다. 크기가 작은 것부터 순서대로 다시 한 줄로 놓으면 이 빨간색 상자는 왼쪽에서 몇 번째에 놓입니까?",
        "question_en": "45 boxes of different sizes are placed in a row in order from largest to smallest. The red box is 29th from the left. If you put them back in a row in order starting from the smallest, how many places from the left should the red box be?",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "45 29 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "45 29 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 45\nvar_b = 29\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 45\nvar_b = 29\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7691": {
        "category": "Arithmetic calculation",
        "question_ko": "연속하는 8개의 짝수를 더하였더니 424가 되었습니다. 8개의 짝수 중 가장 큰 수를 구하시오.",
        "question_en": "Adding 8 consecutive even numbers gives 424. Find the largest among the 8 even numbers.",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "424 0 8 1 [OP_SUB] 2 [OP_MUL] 2 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 8 [OP_DIV] 8 1 [OP_SUB] 2 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "424 0 8 1 [OP_SUB] 2 [OP_MUL] 2 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 8 [OP_DIV] 8 1 [OP_SUB] 2 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 424\nvar_b = 0\nvar_c = 8\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = 2\nlist_a = [i for i in range(var_b, var_g + 1, var_h)]\nlist_a = [float(i) for i in list_a]\nvar_i = sum(list_a)\nvar_j = var_a - var_i\nvar_k = 8\nvar_l = var_j / var_k\nvar_m = 8\nvar_n = 1\nvar_o = var_m - var_n\nvar_p = 2\nvar_q = var_o * var_p\nvar_r = var_l + var_q\nprint(int(var_r))",
        "solution_code_en": "var_a = 424\nvar_b = 0\nvar_c = 8\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e * var_f\nvar_h = 2\nlist_a = [i for i in range(var_b, var_g + 1, var_h)]\nlist_a = [float(i) for i in list_a]\nvar_i = sum(list_a)\nvar_j = var_a - var_i\nvar_k = 8\nvar_l = var_j / var_k\nvar_m = 8\nvar_n = 1\nvar_o = var_m - var_n\nvar_p = 2\nvar_q = var_o * var_p\nvar_r = var_l + var_q\nprint(int(var_r))"
    },
    "7692": {
        "category": "Comparison",
        "question_ko": "독서실은 7층에 있는 학원보다 4층 높고 독서실보다 9층 낮은 층에는 서점이 있습니다. 서점은 몇 층인지 구하시오.",
        "question_en": "There is a reading room 4 floors higher than the academy which is on the 7th floor, and there is a bookstore that is 9 floors lower than the reading room. Find the floor where the bookstore is located.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "7 4 [OP_ADD] 9 [OP_SUB]",
        "solution_abst_en": "7 4 [OP_ADD] 9 [OP_SUB]",
        "solution_code_ko": "var_a = 7\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 7\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "7693": {
        "category": "Possibility",
        "question_ko": "회사에 8명의 팀원이 있다. 그 중 한 명은 팀장, 다른 한 명은 부팀장을 시키는 경우의 수는 얼마인가?",
        "question_en": "A company has 8 team members. What are the number of cases in which one of the members becomes the leader and another member becomes the assistant manager?",
        "answer_ko": "56",
        "answer_en": "56",
        "solution_abst_ko": "8 1 1 [OP_ADD] [OP_PERM]",
        "solution_abst_en": "8 1 1 [OP_ADD] [OP_PERM]",
        "solution_code_ko": "var_a = 8\nvar_b = 1\nvar_c = 1\nvar_d = var_b + var_c\nvar_e = 1\nvar_a = int(var_a)\nvar_d = int(var_d)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e * (var_a-i)\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 1\nvar_c = 1\nvar_d = var_b + var_c\nvar_e = 1\nvar_a = int(var_a)\nvar_d = int(var_d)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e * (var_a-i)\nprint(int(var_e))"
    },
    "7694": {
        "category": "Correspondence",
        "question_ko": "A45+2B3=418라는 식이 성립하려면, A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "What number must be in A so that the equation of A45+2B3=418 becomes true?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "A45+2B3=418 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "A45+2B3=418 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'A45+2B3=418'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A45+2B3=418'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "7695": {
        "category": "Arithmetic calculation",
        "question_ko": "준수는 3일 동안 책 한권을 읽었다. 준수가 하루에 읽은 양은 전체 책의 얼마인가?",
        "question_en": "Junsu read one book in three days. How much did Junsu read in a day?",
        "answer_ko": "0.33",
        "answer_en": "0.33",
        "solution_abst_ko": "1 3 [OP_DIV]",
        "solution_abst_en": "1 3 [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "7696": {
        "category": "Arithmetic calculation",
        "question_ko": "어머니가 형과 동생에게 용돈을 각각 2800원, 1500원씩 주었습니다. 형이 동생에게 얼마를 더 주었더니 동생이 가진 돈은 형이 가진 돈보다 360원이 적었습니다. 형이 동생에게 준 돈은 얼마입니까?",
        "question_en": "My mother gave a brother and a younger brother 2800 won and 1500 won respectively. The older brother gave the younger brother some more money, and the younger brother had 360 won less than the older brother. How much money did the older brother give to the younger brother?",
        "answer_ko": "470",
        "answer_en": "470",
        "solution_abst_ko": "2800 1500 [OP_SUB] 360 [OP_SUB] 2 [OP_DIV]",
        "solution_abst_en": "2800 1500 [OP_SUB] 360 [OP_SUB] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 2800\nvar_b = 1500\nvar_c = var_a - var_b\nvar_d = 360\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 2800\nvar_b = 1500\nvar_c = var_a - var_b\nvar_d = 360\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "7697": {
        "category": "Arithmetic calculation",
        "question_ko": "큰 쇠구슬 1개를 녹여서 작은 쇠구슬 여러 개를 만들려고 한다. 작은 쇠구슬의 반지름의 길이가 큰 쇠구슬의 반지름의 길이의 1/4일 때, 작은 쇠구슬은 모두 몇 개까지 만들 수 있는지 구하여라.",
        "question_en": "I am going to melt one large iron ball to make several small iron balls. If the length of the radius of the small iron ball is 1/4 of the length of the radius of the large iron ball, how many small iron marbles can be made?",
        "answer_ko": "64",
        "answer_en": "64",
        "solution_abst_ko": "1 1/4 3 [OP_POW] [OP_DIV]",
        "solution_abst_en": "1 1/4 3 [OP_POW] [OP_DIV]",
        "solution_code_ko": "var_a = 1\nvar_b = 0.25\nvar_c = 3\nvar_d = var_b ** var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 0.25\nvar_c = 3\nvar_d = var_b ** var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "7698": {
        "category": "Geometry",
        "question_ko": "도형의 둘레가 80센티미터(㎝)이며 한 변의 길이가 16센티미터(㎝)로 모든 변의 길이가 같은 도형이 있습니다. 총 몇 개의 변이 있습니까?",
        "question_en": "A figure has a perimeter of 80 centimeters (cm) and a side length of 16 centimeters (cm), and all sides are the same length. How many sides are there in total?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "80 16 [OP_DIV]",
        "solution_abst_en": "80 16 [OP_DIV]",
        "solution_code_ko": "var_a = 80\nvar_b = 16\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 80\nvar_b = 16\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "7699": {
        "category": "Geometry",
        "question_ko": "한 모서리의 길이가 2센티미터(㎝)인 정육면체 모양의 상자가 125개 있습니다. 이 상자를 모두 쌓아 올려 큰 정육면체 모양을 만들었을 때, 큰 정육면체의 부피를 구하시오.",
        "question_en": "There are 125 cube-shaped boxes with one edge 2 centimeters (cm) long. When all these boxes are stacked to form a large cube, find the volume of the large cube.",
        "answer_ko": "1000",
        "answer_en": "1000",
        "solution_abst_ko": "2 3 [OP_POW] 125 [OP_MUL]",
        "solution_abst_en": "2 3 [OP_POW] 125 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nvar_c = var_a ** var_b\nvar_d = 125\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nvar_c = var_a ** var_b\nvar_d = 125\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "7700": {
        "category": "Geometry",
        "question_ko": "어떤 정삼각형의 둘레의 길이는 21센티미터(㎝)의 4배라고 합니다. 이 정삼각형의 한 변의 길이는 얼마입니까?",
        "question_en": "The circumference of an equilateral triangle is said to be four times 21 centimeters (cm). What is the length of one side of this equilateral triangle?",
        "answer_ko": "28",
        "answer_en": "28",
        "solution_abst_ko": "21 4 [OP_MUL] 3 [OP_DIV]",
        "solution_abst_en": "21 4 [OP_MUL] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 21\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 21\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "7701": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중에서 2번째로 큰 수와 2번째로 작은 수로 나눈 값은 얼마입니까?",
        "question_en": "When three numbers are given: 10, 11 and 12, find the 2nd largest number divided by the 2nd smallest number.",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_DIV]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_DIV]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e / var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[-var_d]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e / var_g\nprint(int(var_h))"
    },
    "7702": {
        "category": "Correspondence",
        "question_ko": "9와 어떤 수의 합을 구해야 하는데 잘못하여 차를 구했더니 1이었습니다. 어떤 수는 10보다 작은 수일 때, 9와 어떤 수의 합을 구하시오.",
        "question_en": "You need to find the sum of 9 and a certain number, but mistakenly calculated the difference of them and got 1 as the answer. If the number is less than 10, find the sum of 9 and the number.",
        "answer_ko": "17",
        "answer_en": "17",
        "solution_abst_ko": "9 1 [OP_SUB] 9 [OP_ADD]",
        "solution_abst_en": "9 1 [OP_SUB] 9 [OP_ADD]",
        "solution_code_ko": "var_a = 9\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 9\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 9\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7703": {
        "category": "Arithmetic calculation",
        "question_ko": "석기와 동민이의 집사이에 25미터(m)간격의 전봇대가 총 20개 있습니다. 석기와 동민이 집앞에는 전봇대가 없을 시 석기와 동민이의 집사이 거리는 몇미터(m)입니까?",
        "question_en": "There are a total of 20 telephone poles at 25m (m) intervals between Seokgi's and Dongmin's houses. If there is no telephone pole in front of their houses, what is the distance in meters (m) between Seokgi's and Dongmin's houses?",
        "answer_ko": "525",
        "answer_en": "525",
        "solution_abst_ko": "20 1 [OP_ADD] 25 [OP_MUL]",
        "solution_abst_en": "20 1 [OP_ADD] 25 [OP_MUL]",
        "solution_code_ko": "var_a = 20\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 25\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 25\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "7704": {
        "category": "Possibility",
        "question_ko": "석진이네 반은 20명입니다. 축구 대회에 출전할 11명을 뽑으려고 할 때, 팀을 뽑는 경우는 모두 몇 가지 입니까?",
        "question_en": "There are 20 people in Seokjin's class. If you are trying to pick 11 people to play in a soccer tournament, what are possible cases to pick a team?",
        "answer_ko": "167960",
        "answer_en": "167960",
        "solution_abst_ko": "20 11 [OP_COMB]",
        "solution_abst_en": "20 11 [OP_COMB]",
        "solution_code_ko": "var_a = 20\nvar_b = 11\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))",
        "solution_code_en": "var_a = 20\nvar_b = 11\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))"
    },
    "7705": {
        "category": "Arithmetic calculation",
        "question_ko": "지수는 로봇을 30개 얻었다. 희영이는 지수보다 로봇을 4배 더 많이 가지고 있다. 희영이와 지수는 총 몇개의 로봇을 가지고 있을까?",
        "question_en": "Jisoo got 30 robots. Heeyoung has four times as many robots as Jisoo. How many robots do Heeyoung and Jisoo have in total?",
        "answer_ko": "120",
        "answer_en": "120",
        "solution_abst_ko": "40 4 [OP_MUL] 40 [OP_SUB]",
        "solution_abst_en": "40 4 [OP_MUL] 40 [OP_SUB]",
        "solution_code_ko": "var_a = 40\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 40\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 40\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 40\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "7706": {
        "category": "Comparison",
        "question_ko": "은정이와 유정이 사이에는 8명이 서 있습니다. 은정이는 앞에서 5번째로 서 있고 유정이는 맨 뒤에 서있을 때 줄을 서 있는 학생은 모두 몇 명입니까?",
        "question_en": "Given that 8 people are standing between Eunjung and Yoojung, how many students are in a line when Eunjeong is the 5th student from the front and Yoojung is the last student in the line?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "5 8 [OP_ADD] 1 [OP_ADD]",
        "solution_abst_en": "5 8 [OP_ADD] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7707": {
        "category": "Comparison",
        "question_ko": "민수, 창현, 성현이가 버스정류장에서 줄을 서 있다. 민수가 창현이 보다 앞에 서 있고 창현인가 성현이 보다 앞에 서 있다면 가장 뒤에 서 있는 사람은 누구인지 구하시오.",
        "question_en": "Minsu, Changhyun, and Seonghyun are standing in line at the bus stop. If Minsu is standing in front of Changhyun and Changhyun is standing in front of Seonghyun, find out who is standing at the back.",
        "answer_ko": "성현",
        "answer_en": "Seonghyun",
        "solution_abst_ko": "[OP_LIST_SOL] 민수 창현 성현 [OP_LIST_EOL] [OP_LIST_SOL] 민수 창현 < 창현 성현 < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Minsu Changhyun Seonghyun [OP_LIST_EOL] [OP_LIST_SOL] Minsu Changhyun < Changhyun Seonghyun < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '민수'\nvar_b = '창현'\nvar_c = '성현'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '민수'\nvar_e = '창현'\nvar_f = '<'\nvar_g = '창현'\nvar_h = '성현'\nvar_i = '<'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(var_k)",
        "solution_code_en": "var_a = 'Minsu'\nvar_b = 'Changhyun'\nvar_c = 'Seonghyun'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'Minsu'\nvar_e = 'Changhyun'\nvar_f = '<'\nvar_g = 'Changhyun'\nvar_h = 'Seonghyun'\nvar_i = '<'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(var_k)"
    },
    "7708": {
        "category": "Possibility",
        "question_ko": "유아는 5, 2, 8, 0 중 하나의 숫자를 빼고, 남은 숫자들로 세 자리수를 만드려고 합니다. 유아가 만드는 수 중 550보다 크고 850보다 작은 수는 모두 몇 가지 입니까?",
        "question_en": "Yoo-ah left one of the digits 5, 2, 8, or 0 out and tried to form a three-digit number with the remaining digits. How many of the numbers Yoo-ah made are greater than 550 and less than 850?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 5 2 8 0 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 550 [OP_LIST_MORE] 850 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 5 2 8 0 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 550 [OP_LIST_MORE] 850 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = 8\nvar_d = 0\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 550\nlist_c = []\nfor i in list_b:\n    if i > var_f:\n        list_c.append(i)\nvar_g = 850\nlist_d = []\nfor i in list_c:\n    if i < var_g:\n        list_d.append(i)\nvar_h = len(list_d)\nprint(int(var_h))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = 8\nvar_d = 0\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 550\nlist_c = []\nfor i in list_b:\n    if i > var_f:\n        list_c.append(i)\nvar_g = 850\nlist_d = []\nfor i in list_c:\n    if i < var_g:\n        list_d.append(i)\nvar_h = len(list_d)\nprint(int(var_h))"
    },
    "7709": {
        "category": "Geometry",
        "question_ko": "9개의 각으로 이루어진 도형의 한 꼭짓점에서 대각선을 긋는다면, 3개의 각으로 이루어진 도형은 몇 개 만들어집니까?",
        "question_en": "If you draw a diagonal from one vertex of a figure made of 9 angles, how many figures made of 3 angles are made?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "9 3 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "9 3 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 9\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7710": {
        "category": "Comparison",
        "question_ko": "각각의 키가 다른 22명이 키가 큰 사람부터 순서대로 한 줄로 서 있습니다. (가)는 뒤에서 13번째에 서 있습니다. 키가 작은 사람부터 순서대로 다시 한 줄로 서면 (가)는 뒤에서 몇 번째에 서게 됩니까?",
        "question_en": "22 people of different heights stand in a line in order, tallest first. (a) stands 13th from the back. If you line up again in order of shortest to tallest, what number will you stand from the back?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "22 13 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "22 13 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 22\nvar_b = 13\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 22\nvar_b = 13\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7711": {
        "category": "Arithmetic calculation",
        "question_ko": "4%의 소금물 300그램(g)에서 몇 그램(g)의 물을 증발시켜야 10%의 소금물이 되는지 구하여라",
        "question_en": "How many grams (g) of water must be evaporated from 300 grams (g) of 4% salt water to make 10% salt water?",
        "answer_ko": "180",
        "answer_en": "180",
        "solution_abst_ko": "300 300 4 100 [OP_DIV] [OP_MUL] 100 10 [OP_DIV] [OP_MUL] [OP_SUB]",
        "solution_abst_en": "300 300 4 100 [OP_DIV] [OP_MUL] 100 10 [OP_DIV] [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 300\nvar_b = 300\nvar_c = 4\nvar_d = 100\nvar_e = var_c / var_d\nvar_f = var_b * var_e\nvar_g = 100\nvar_h = 10\nvar_i = var_g / var_h\nvar_j = var_f * var_i\nvar_k = var_a - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 300\nvar_b = 300\nvar_c = 4\nvar_d = 100\nvar_e = var_c / var_d\nvar_f = var_b * var_e\nvar_g = 100\nvar_h = 10\nvar_i = var_g / var_h\nvar_j = var_f * var_i\nvar_k = var_a - var_j\nprint(int(var_k))"
    },
    "7712": {
        "category": "Comparison",
        "question_ko": "윤기는 4개, 정국에는 6 곱하기 3만큼 사과를 모았습니다. 누가 더 사과를 적게 가지고 있습니까?",
        "question_en": "Yoongi collected 4 apples and Jungkook collected 6 times 3 apples. Who has fewer apples?",
        "answer_ko": "윤기",
        "answer_en": "Yoongi",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 6\nvar_e = 3\nvar_f = var_d * var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 4\nvar_d = 6\nvar_e = 3\nvar_f = var_d * var_e\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "7713": {
        "category": "Comparison",
        "question_ko": "정국이는 6개의 사과에서 3개를 먹었습니다. 윤기가 가진 사과가 4개라면 누가 더 적은 사과를 가지고 있나요?",
        "question_en": "Jungkook ate 3 out of 6 apples. When Yoongi has 4 apples, who has fewer apples?",
        "answer_ko": "정국",
        "answer_en": "Jungkook",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 윤기 [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_SUB] 4 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Yoongi [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_SUB] 4 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '윤기'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 3\nvar_e = var_c - var_d\nvar_f = 4\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Yoongi'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 3\nvar_e = var_c - var_d\nvar_f = 4\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "7714": {
        "category": "Arithmetic calculation",
        "question_ko": "과일 가게에 사과, 바나나, 감이 있습니다. 사과 수는 바나나 수의 4배이고, 감 수는 바나나 수의 3배입니다. 사과와 감 수의 합이 210개라면 바나나는 몇 개인지 구해 보시오.",
        "question_en": "There are apples, bananas and persimmons in the fruit shop. The number of apples is 4 times the number of bananas, and the number of persimmons is 3 times the number of bananas. If the sum of apples and persimmons is 210, how many bananas are there?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "210 4 3 [OP_ADD] [OP_DIV]",
        "solution_abst_en": "210 4 3 [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 210\nvar_b = 4\nvar_c = 3\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 210\nvar_b = 4\nvar_c = 3\nvar_d = var_b + var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "7715": {
        "category": "Arithmetic calculation",
        "question_ko": "호석이네 학교에 있는 축구공은 농구공보다 23개 더 많고 배구공은 축구공보다 18개 더 적습니다. 배구공이 40개 있을 때, 농구공은 몇 개입니까?",
        "question_en": "There are 23 more soccer balls at Hoseok's school than basketballs and 18 fewer volleyballs than soccer balls. If there are 40 volleyballs, how many basketballs are there?",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "40 18 [OP_ADD] 23 [OP_SUB]",
        "solution_abst_en": "40 18 [OP_ADD] 23 [OP_SUB]",
        "solution_code_ko": "var_a = 40\nvar_b = 18\nvar_c = var_a + var_b\nvar_d = 23\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 40\nvar_b = 18\nvar_c = var_a + var_b\nvar_d = 23\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "7716": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 0.55로 두 번 연속 곱하였더니 4.235가 되었습니다. 어떤 수는 구하시오.",
        "question_en": "Multiplying a number by 0.55 in a row gives you 4.235. Find the number.",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "4.235 0.55 [OP_DIV] 0.55 [OP_DIV]",
        "solution_abst_en": "4.235 0.55 [OP_DIV] 0.55 [OP_DIV]",
        "solution_code_ko": "var_a = 4.235\nvar_b = 0.55\nvar_c = var_a / var_b\nvar_d = 0.55\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 4.235\nvar_b = 0.55\nvar_c = var_a / var_b\nvar_d = 0.55\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "7717": {
        "category": "Comparison",
        "question_ko": "은지가 버스 줄을 섰는데 앞에 6명 뒤에 5명 있다면, 현재 줄에 있는 사람은 모두 몇 명입니까?",
        "question_en": "If Eunji stands in line for a bus and there are 6 people waiting in front and 5 people behind, how many people are there?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "6 1 [OP_ADD] 5 [OP_ADD]",
        "solution_abst_en": "6 1 [OP_ADD] 5 [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7718": {
        "category": "Arithmetic calculation",
        "question_ko": "수영이네 학교의 운동장 둘레는 242.7 미터(m) 입니다 수영이가 운동장을 5 바퀴 달렸다면, 모두 몇 미터(m)를 달린 것 입니까?",
        "question_en": "The circumference of Suyeong's school playground is 242.7 meters (m). If Suyeong ran 5 laps around the playground, how many meters (m) did she run?",
        "answer_ko": "1213.50",
        "answer_en": "1213.5",
        "solution_abst_ko": "242.7 5 [OP_MUL]",
        "solution_abst_en": "242.7 5 [OP_MUL]",
        "solution_code_ko": "var_a = 242.7\nvar_b = 5\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 242.7\nvar_b = 5\nvar_c = var_a * var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "7719": {
        "category": "Comparison",
        "question_ko": "주머니 속에 빨간 공이 3개, 파란 공이 2개, 초록 공이 5개 들어있다. 주머니에서 공 1개를 꺼낼 때, 확률이 가장 높은 공의 색깔을 쓰시오.",
        "question_en": "There are 3 red balls, 2 blue balls, and 5 green balls in the bag. When a ball is drawn from the bag, what will be the color of the ball with the highest probability?",
        "answer_ko": "초록",
        "answer_en": "green",
        "solution_abst_ko": "[OP_LIST_SOL] 빨간 파란 초록 [OP_LIST_EOL] [OP_LIST_SOL] 3 2 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] red blue green [OP_LIST_EOL] [OP_LIST_SOL] 3 2 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '빨간'\nvar_b = '파란'\nvar_c = '초록'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nvar_e = 2\nvar_f = 5\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'red'\nvar_b = 'blue'\nvar_c = 'green'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nvar_e = 2\nvar_f = 5\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "7720": {
        "category": "Possibility",
        "question_ko": "소윤이는 숫자 카드 3, 5, 8, 9중 하나를 골라 버리고, 남은 카드들로 세 자리 자연수를 만들고자 합니다. 소윤이가 만들 수 있는 수들의 개수는 총 몇개입니까?",
        "question_en": "Soyun chooses and discards one of the number cards 3, 5, 8, and 9, and wants to make a three-digit natural number with the remaining cards. How many total numbers can Soyun make?",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "[OP_LIST_SOL] 3 5 8 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 3 5 8 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 3\nvar_b = 5\nvar_c = 8\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 3\nvar_b = 5\nvar_c = 8\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "7721": {
        "category": "Possibility",
        "question_ko": "0, 3, 5, 9 중 각각 다른 3개를 골라 한 번씩 사용하여 세 자리 수를 만든다고 할 때, 가장 작은 수와 가장 큰 수의 합은 얼마인가?",
        "question_en": "If you choose three different numbers from 0, 3, 5, and 9 and use them once to make a three-digit number, what is the sum of the smallest and largest numbers?",
        "answer_ko": "1258",
        "answer_en": "1258",
        "solution_abst_ko": "[OP_LIST_SOL] 0 3 5 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 1 [OP_LIST_MAX] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 0 3 5 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 1 [OP_LIST_MAX] [OP_ADD]",
        "solution_code_ko": "var_a = 0\nvar_b = 3\nvar_c = 5\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nvar_j = var_g + var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 0\nvar_b = 3\nvar_c = 5\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[-var_h]\nvar_j = var_g + var_i\nprint(int(var_j))"
    },
    "7722": {
        "category": "Arithmetic calculation",
        "question_ko": "높이가 115미터(m)인 열기구가 있습니다. 1분에 400미터(m)를 올라간다고 할 때 1.625킬로미터(㎞)의 성층권을 통과하는데 몇 분이 걸리나요?",
        "question_en": "There is a hot air balloon that is 115 meters (m) high. How many minutes does it take to pass through the stratosphere of 1.625 kilometers (km) if it ascends 400 meters (m) in 1 minute?",
        "answer_ko": "3.78",
        "answer_en": "3.78",
        "solution_abst_ko": "1.625 1000 [OP_MUL] 115  [OP_SUB] 400 [OP_DIV]",
        "solution_abst_en": "1.625 1000 [OP_MUL] 115  [OP_SUB] 400 [OP_DIV]",
        "solution_code_ko": "var_a = 1.625\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 115\nvar_e = var_c - var_d\nvar_f = 400\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 1.625\nvar_b = 1000\nvar_c = var_a * var_b\nvar_d = 115\nvar_e = var_c - var_d\nvar_f = 400\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "7723": {
        "category": "Comparison",
        "question_ko": "영주가 가지고 있는 철사는 97.5센티미터(㎝)이고, 민호가 가지고 있는 철사는 97센티미터(㎝)보다 3밀리미터(㎜)더 깁니다. 더 짧은 철사를 가지고 있는 사람은 누구입니까?",
        "question_en": "The wire Yeongju has is 97.5 centimeters (cm), and the wire Minho has is 3 millimeters (mm) longer than 97 centimeters (cm). Who has a shorter wire?",
        "answer_ko": "민호",
        "answer_en": "Minho",
        "solution_abst_ko": "[OP_LIST_SOL] 영주 민호 [OP_LIST_EOL] [OP_LIST_SOL] 97.5 97 3 10 [OP_DIV] [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yeongju Minho [OP_LIST_EOL] [OP_LIST_SOL] 97.5 97 3 10 [OP_DIV] [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '영주'\nvar_b = '민호'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 97.5\nvar_d = 97\nvar_e = 3\nvar_f = 10\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Yeongju'\nvar_b = 'Minho'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 97.5\nvar_d = 97\nvar_e = 3\nvar_f = 10\nvar_g = var_e / var_f\nvar_h = var_d + var_g\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "7724": {
        "category": "Correspondence",
        "question_ko": "123의 배수 중 162ABC6 모양의 수가 있다. 이러한 수 중에서 가장 작은 수를 구하여라.",
        "question_en": "Among the multiples of 123, there are is a number shaped162ABC6. Find the smallest of these numbers shaped like that.",
        "answer_ko": "1620156",
        "answer_en": "1620156",
        "solution_abst_ko": "1620006 1629996 1 [OP_LIST_ARANGE] 123 [OP_LIST_DIVISIBLE] 10 6 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MIN]",
        "solution_abst_en": "1620006 1629996 1 [OP_LIST_ARANGE] 123 [OP_LIST_DIVISIBLE] 10 6 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1620006\nvar_b = 1629996\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 123\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 10\nvar_f = 6\nlist_c = [] \nvar_e = int(var_e)\nvar_f = int(var_f)\nif var_f < 0:\n    var_f = var_f + var_e\nfor i in list_b:\n    i = int(i)\n    if i%var_e == var_f:\n        list_c.append(i)\nvar_g = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nprint(int(var_h))",
        "solution_code_en": "var_a = 1620006\nvar_b = 1629996\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 123\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e = 10\nvar_f = 6\nlist_c = [] \nvar_e = int(var_e)\nvar_f = int(var_f)\nif var_f < 0:\n    var_f = var_f + var_e\nfor i in list_b:\n    i = int(i)\n    if i%var_e == var_f:\n        list_c.append(i)\nvar_g = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_h = list_d[var_g-1]\nprint(int(var_h))"
    },
    "7725": {
        "category": "Correspondence",
        "question_ko": "11을 어떤 수에서 나누었더니 결과로 2를 얻었습니다. 6을 어떤 수에 곱하면 얼마입니까?",
        "question_en": "Divide 11 by a number and you get 2 as a result. How much is 6 multiplied by a number?",
        "answer_ko": "132",
        "answer_en": "132",
        "solution_abst_ko": "2 11 [OP_MUL] 6 [OP_MUL]",
        "solution_abst_en": "2 11 [OP_MUL] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 11\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 11\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "7726": {
        "category": "Arithmetic calculation",
        "question_ko": "열기구는 한 시간에 3.8킬로미터(㎞)를 하늘로 올라간다고 합니다. 열기구가 2시간 45분동안 쉬지않고 올라간 높이는 몇 킬로미터(㎞)입니까?",
        "question_en": "Hot air balloons are said to ascend into the sky at 3.8 kilometers (km) per hour. How high in kilometers (km) does a hot air balloon rise without stopping in 2 hours and 45 minutes?",
        "answer_ko": "10.45",
        "answer_en": "10.45",
        "solution_abst_ko": "3.8 2 45 60 [OP_DIV] [OP_ADD] [OP_MUL]",
        "solution_abst_en": "3.8 2 45 60 [OP_DIV] [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 3.8\nvar_b = 2\nvar_c = 45\nvar_d = 60\nvar_e = var_c / var_d\nvar_f = var_b + var_e\nvar_g = var_a * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 3.8\nvar_b = 2\nvar_c = 45\nvar_d = 60\nvar_e = var_c / var_d\nvar_f = var_b + var_e\nvar_g = var_a * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "7727": {
        "category": "Arithmetic calculation",
        "question_ko": "12리터(L) 400밀리리터(㎖)의 기름이 있습니다. 이것을 큰 병에는 작은 병보다 2리터(L) 600밀리리터(㎖) 많게 나누어 담으려고 합니다. 큰 병에는 몇 리터(L)를 담게 됩니까?",
        "question_en": "There are 12 liters (L) and 400 milliliters (㎖) of oil. You are trying to divide this into two bottles. A large bottle can hold 2 liters (L) and 600 milliliters (㎖) more than a small bottle. How many liters (liters) will the large bottle hold?",
        "answer_ko": "7.5",
        "answer_en": "7.5",
        "solution_abst_ko": "12 400 1000 [OP_DIV] [OP_ADD] 2 [OP_DIV] 2 600 1000 [OP_DIV] [OP_ADD] 2 [OP_DIV] [OP_ADD]",
        "solution_abst_en": "12 400 1000 [OP_DIV] [OP_ADD] 2 [OP_DIV] 2 600 1000 [OP_DIV] [OP_ADD] 2 [OP_DIV] [OP_ADD]",
        "solution_code_ko": "var_a = 12\nvar_b = 400\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = 600\nvar_j = 1000\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = 2\nvar_n = var_l / var_m\nvar_o = var_g + var_n\nprint('{:.2f}'.format(round(var_o+1e-10,2)))",
        "solution_code_en": "var_a = 12\nvar_b = 400\nvar_c = 1000\nvar_d = var_b / var_c\nvar_e = var_a + var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = 600\nvar_j = 1000\nvar_k = var_i / var_j\nvar_l = var_h + var_k\nvar_m = 2\nvar_n = var_l / var_m\nvar_o = var_g + var_n\nprint('{:.2f}'.format(round(var_o+1e-10,2)))"
    },
    "7728": {
        "category": "Geometry",
        "question_ko": "10개의 각으로 이루어진 도형의 한 꼭짓점에서 그을 수 있는 대각선의 개수는 몇 개입니까?",
        "question_en": "How many diagonals can be drawn from one vertex of a 10-angle figure?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "10 3 [OP_SUB]",
        "solution_abst_en": "10 3 [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 10\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "7729": {
        "category": "Correspondence",
        "question_ko": "다섯 자리 수 A375B는 24로 나누어 떨어진다. A에 알맞은 숫자는 모두 몇 개인가?",
        "question_en": "The five-digit number A375B is divisible by 24. How many numbers fit for A?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "A375B [OP_GEN_POSSIBLE_LIST] 24 [OP_LIST_DIVISIBLE] A375B A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_abst_en": "A375B [OP_GEN_POSSIBLE_LIST] 24 [OP_LIST_DIVISIBLE] A375B A [OP_LIST_FIND_UNK] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 'A375B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 24\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 'A375B'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nvar_e = len(list_c)\nprint(int(var_e))",
        "solution_code_en": "var_a = 'A375B'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 24\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 'A375B'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nvar_e = len(list_c)\nprint(int(var_e))"
    },
    "7730": {
        "category": "Geometry",
        "question_ko": "모서리가 21개, 면이 9개이고, 다각형인 두 밑면이 서로 평행하고 합동인 도형의 꼭짓점의 개수는 총 몇 개입니까?",
        "question_en": "What is the total number of vertices of a figure with 21 edges, 9 faces, and two polygonal base sides that are parallel and congruent?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "21 3 [OP_DIV] 2 [OP_MUL]",
        "solution_abst_en": "21 3 [OP_DIV] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 21\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 21\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "7731": {
        "category": "Comparison",
        "question_ko": "4개의 숫자 0.8, 1/2, 0.9, 1/3가 있습니다. 3보다 작거나 같은 수는 몇 개입니까?",
        "question_en": "There are four numbers 0.8, 1/2, 0.9, and 1/3. How many numbers are less than or equal to 3?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 3 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 3 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = []\nfor i in list_a:\n    if i <= var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nvar_d = 0.3333333333333333\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = []\nfor i in list_a:\n    if i <= var_e:\n        list_b.append(i)\nvar_f = len(list_b)\nprint(int(var_f))"
    },
    "7732": {
        "category": "Correspondence",
        "question_ko": "여섯 자리 수 A15B94가 99의 배수일 때, A와 B의 합을 구하시오.",
        "question_en": "If the six-digit number A15B94 is a multiple of 99, find the sum of A and B.",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "A15B94 [OP_GEN_POSSIBLE_LIST] 99 [OP_LIST_DIVISIBLE] A15B94 A [OP_LIST_FIND_UNK] A15B94 B [OP_LIST_FIND_UNK] [OP_ADD]",
        "solution_abst_en": "A15B94 [OP_GEN_POSSIBLE_LIST] 99 [OP_LIST_DIVISIBLE] A15B94 A [OP_LIST_FIND_UNK] A15B94 B [OP_LIST_FIND_UNK] [OP_ADD]",
        "solution_code_ko": "var_a = 'A15B94'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 99\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 'A15B94'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nvar_e = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_e = int(elem[unk_idx])\nvar_f = 'A15B94'\nvar_g = 'B'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nvar_i = var_e + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 'A15B94'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 99\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = 'A15B94'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nvar_e = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_e = int(elem[unk_idx])\nvar_f = 'A15B94'\nvar_g = 'B'\nvar_f = str(var_f)\nvar_g = str(var_g)\nunk_idx = var_f.index(var_g)\nvar_h = 0\nfor elem in list_b:\n    elem = str(elem)\n    var_h = int(elem[unk_idx])\nvar_i = var_e + var_h\nprint(int(var_i))"
    },
    "7733": {
        "category": "Geometry",
        "question_ko": "가로의 길이가 34센티미터(㎝)인 직사각형 모양의 반죽이 있습니다. 한 변의 길이가 4센티미터(㎝)인 정사각형 모양으로 생긴 틀을 이용해 반죽을 빈틈없이 찍었을 때, 가로의 길이가 2센티미터(㎝) 남고, 쿠키가 총 24개 만들어졌다면, 틀을 찍기 전의 반죽의 최소 둘레는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "You have a rectangular piece of dough measuring 34 centimeters (cm) wide. When the dough is cut without gaps using a square mold with a side length of 4 centimeters (cm), if the width of the dough is 2 centimeters (cm) left and 24 cookies are made in total, Find the minimum perimeter of the dough before the mold is stamped in centimeters (cm).",
        "answer_ko": "92",
        "answer_en": "92",
        "solution_abst_ko": "24 34 4 [OP_FDIV] [OP_DIV] 4 [OP_MUL] 34 [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "24 34 4 [OP_FDIV] [OP_DIV] 4 [OP_MUL] 34 [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 24\nvar_b = 34\nvar_c = 4\nvar_d = var_b // var_c\nvar_e = var_a / var_d\nvar_f = 4\nvar_g = var_e * var_f\nvar_h = 34\nvar_i = var_g + var_h\nvar_j = 2\nvar_k = var_i * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 24\nvar_b = 34\nvar_c = 4\nvar_d = var_b // var_c\nvar_e = var_a / var_d\nvar_f = 4\nvar_g = var_e * var_f\nvar_h = 34\nvar_i = var_g + var_h\nvar_j = 2\nvar_k = var_i * var_j\nprint(int(var_k))"
    },
    "7734": {
        "category": "Possibility",
        "question_ko": "사과, 복숭아, 배, 딸기를 판매하는 과일가게에서 중복을 허락하여 2개의 과일을 구매하려고 합니다. 가능한 경우의 수는 몇 가지 일까요?",
        "question_en": "At a fruit store that sells apples, peaches, pears, and strawberries, you want to buy two fruits allowing duplicates. How many possible cases are there?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "[OP_LIST_SOL] 사과 복숭아 배 딸기 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] apples peaches pears strawberries [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB]",
        "solution_code_ko": "var_a = '사과'\nvar_b = '복숭아'\nvar_c = '배'\nvar_d = '딸기'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = var_e + var_f\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = 2\nvar_k = 1\nvar_i = int(var_i)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_i-i)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k / (i+1)\nprint(int(var_k))",
        "solution_code_en": "var_a = 'apples'\nvar_b = 'peaches'\nvar_c = 'pears'\nvar_d = 'strawberries'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 2\nvar_g = var_e + var_f\nvar_h = 1\nvar_i = var_g - var_h\nvar_j = 2\nvar_k = 1\nvar_i = int(var_i)\nvar_j = int(var_j)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k * (var_i-i)\nfor i, elem in enumerate(range(var_j)):\n    var_k = var_k / (i+1)\nprint(int(var_k))"
    },
    "7735": {
        "category": "Arithmetic calculation",
        "question_ko": "소금이 5% 들어있는 소금물이 200그램(g) 있습니다. 이 소금물에서 물이 증발한 후 남은 소금은 전체 소금물의 8%가 되었을 때, 물은 몇 그램(g) 증발하였는지 구하시오.",
        "question_en": "You have 200 grams (g) of salt water with 5% salt. When the remaining salt became 8% of the total salt water after the water evaporated from this salt water, find how many grams (g) of water has evaporated.",
        "answer_ko": "75",
        "answer_en": "75",
        "solution_abst_ko": "200 200 5 100 [OP_DIV] [OP_MUL] 100 8 [OP_DIV] [OP_MUL] [OP_SUB]",
        "solution_abst_en": "200 200 5 100 [OP_DIV] [OP_MUL] 100 8 [OP_DIV] [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 200\nvar_b = 200\nvar_c = 5\nvar_d = 100\nvar_e = var_c / var_d\nvar_f = var_b * var_e\nvar_g = 100\nvar_h = 8\nvar_i = var_g / var_h\nvar_j = var_f * var_i\nvar_k = var_a - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 200\nvar_b = 200\nvar_c = 5\nvar_d = 100\nvar_e = var_c / var_d\nvar_f = var_b * var_e\nvar_g = 100\nvar_h = 8\nvar_i = var_g / var_h\nvar_j = var_f * var_i\nvar_k = var_a - var_j\nprint(int(var_k))"
    },
    "7736": {
        "category": "Comparison",
        "question_ko": "도서관에 똑같은 책장이 28개 있습니다. 각 책장은 6층이고, 각 층마다 꽂혀 있는 책의 수는 같습니다. 어느 책장의 한 층에서 2개의 책을 뽑았을 때 그 층에 20권이 남았다고 합니다. 도서관의 책장에 꽂혀 있는 책은 모두 몇 권입니까?",
        "question_en": "There are 28 identical bookshelves in the library. Each bookshelf has 6 floors, and the number of books on each floor is the same. It is said that when two books are taken from one floor of a bookshelf, there are 20 books left on that floor. How many books are on the shelves in the library?",
        "answer_ko": "3696",
        "answer_en": "3696",
        "solution_abst_ko": "20 2 [OP_ADD] 6 [OP_MUL] 28 [OP_MUL]",
        "solution_abst_en": "20 2 [OP_ADD] 6 [OP_MUL] 28 [OP_MUL]",
        "solution_code_ko": "var_a = 20\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 6\nvar_e = var_c * var_d\nvar_f = 28\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 20\nvar_b = 2\nvar_c = var_a + var_b\nvar_d = 6\nvar_e = var_c * var_d\nvar_f = 28\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "7737": {
        "category": "Arithmetic calculation",
        "question_ko": "석진이가 나눗셈을 하는 과정에서 나누는 세 자리 수의 십의 자리에 있는 0을 빠뜨려서 15로 잘못 보고 계산하였더니 몫이 182로 나누어떨어졌습니다. 바르게 계산한 몫을 구하시오.",
        "question_en": "In the process of division, Seokjin left out the 0 in the tens place of the three-digit subtracting number, so he saw it as 15 by mistake. If he gets a quotient of 182 without any remainder, find the quotient of the correct calculation.\n",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "15 182 [OP_MUL] 105 [OP_FDIV]",
        "solution_abst_en": "15 182 [OP_MUL] 105 [OP_FDIV]",
        "solution_code_ko": "var_a = 15\nvar_b = 182\nvar_c = var_a * var_b\nvar_d = 105\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 182\nvar_c = var_a * var_b\nvar_d = 105\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "7738": {
        "category": "Comparison",
        "question_ko": "5가지 숫자 1.4, 9/10, 1.2, 0.5, 13/10 중에서 1.1보다 크거나 같은 수 중 가장 작거나 같은 숫자는 무엇입니까?",
        "question_en": "Which of the five numbers 1.4, 9/10, 1.2, 0.5, and 13/10 is greater than or equal to 1.1? Find the smallest or the equal number.",
        "answer_ko": "1.20",
        "answer_en": "1.2",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE_EQUAL] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE_EQUAL] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i >= var_f:\n        list_b.append(i)\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nprint('{:.2f}'.format(round(var_h+1e-10,2)))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i >= var_f:\n        list_b.append(i)\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nprint('{:.2f}'.format(round(var_h+1e-10,2)))"
    },
    "7739": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 17을 뺐더니 결과가 55가 되었습니다. 9를 어떤 수로 나누면 얼마입니까?",
        "question_en": "Subtracting 17 from a number gives 55. What number is it when the number is divided by 9?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "55 17 [OP_ADD] 9 [OP_DIV]",
        "solution_abst_en": "55 17 [OP_ADD] 9 [OP_DIV]",
        "solution_code_ko": "var_a = 55\nvar_b = 17\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 55\nvar_b = 17\nvar_c = var_a + var_b\nvar_d = 9\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "7740": {
        "category": "Possibility",
        "question_ko": "정사면체에서 한 꼭짓점에 모인 면의 수는 모두 몇개인가요?",
        "question_en": "How many faces in a tetrahedron meet at one vertex?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "3",
        "solution_abst_en": "3",
        "solution_code_ko": "var_a = 3\nprint(int(var_a))",
        "solution_code_en": "var_a = 3\nprint(int(var_a))"
    },
    "7741": {
        "category": "Geometry",
        "question_ko": "길이가 28센티미터(㎝)인 철사를 사용하여 가로의 길이가 6인 직사각형을 만들었습니다. 직사각형의 넓이를 구하시오.",
        "question_en": "Using 28 centimeters (cm) long wire, I made a rectangle with a width of 6. Find the area of the rectangle.",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "28 2 [OP_DIV] 6 [OP_SUB] 6 [OP_MUL]",
        "solution_abst_en": "28 2 [OP_DIV] 6 [OP_SUB] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 28\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c - var_d\nvar_f = 6\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 28\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 6\nvar_e = var_c - var_d\nvar_f = 6\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "7742": {
        "category": "Correspondence",
        "question_ko": "윤기는 세 자리 수에 57을 빼던 중, 윤기는 세 자리 수의 일의 자리 숫자 9를 6으로 잘못 봤습니다. 윤기가 구한 차가 819라고 하면, 바르게 계산한 결과는 무엇인가요?",
        "question_en": "While Yoongi was subtracting 57 from the three-digit number, Yoongi mistakenly saw the three-digit ones digit 9 as 6. If the difference that Yoongi found is 819, what is the correct calculation?",
        "answer_ko": "822",
        "answer_en": "822",
        "solution_abst_ko": "819 57 [OP_ADD] 6 9 [OP_SUB] [OP_SUB] 57 [OP_SUB]",
        "solution_abst_en": "819 57 [OP_ADD] 6 9 [OP_SUB] [OP_SUB] 57 [OP_SUB]",
        "solution_code_ko": "var_a = 819\nvar_b = 57\nvar_c = var_a + var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nvar_h = 57\nvar_i = var_g - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 819\nvar_b = 57\nvar_c = var_a + var_b\nvar_d = 6\nvar_e = 9\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nvar_h = 57\nvar_i = var_g - var_h\nprint(int(var_i))"
    },
    "7743": {
        "category": "Geometry",
        "question_ko": "한 직선 위에 있지 않은 세 점에 대하여 반직선의 개수를 구하시오.",
        "question_en": "Find the number of semi-straight lines for three points that are not on a straight line.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "3 2 [OP_PERM]",
        "solution_abst_en": "3 2 [OP_PERM]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))"
    },
    "7744": {
        "category": "Arithmetic calculation",
        "question_ko": "남준이가 가진 구슬 수의 5배는 윤기가 가진 구슬 개수 보다 11개 더 많습니다. 윤기가 가진 구슬 수의 2배는 호석이가 가진 구슬 개수 보다 8개 더 적습니다. 남준, 윤기, 호석이가 가지고 있는 구슬은 모두 몇 개입니까?",
        "question_en": "When three people have marbles, 5 times the number of marbles that Namjoon has is 11 more than what Yoongi has. 2 multiply by the number that Yoongi has is 8 fewer than Hoseok's marbles. Find the sum of marbles for each person: Namjoon, Yoongi, and Hoseok.",
        "answer_ko": "247",
        "answer_en": "247",
        "solution_abst_ko": "17 17 5 [OP_MUL] 11 [OP_SUB] [OP_ADD] 17 5 [OP_MUL] 11 [OP_SUB] 2 [OP_MUL] 8 [OP_ADD] [OP_ADD]",
        "solution_abst_en": "17 17 5 [OP_MUL] 11 [OP_SUB] [OP_ADD] 17 5 [OP_MUL] 11 [OP_SUB] 2 [OP_MUL] 8 [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 17\nvar_b = 17\nvar_c = 5\nvar_d = var_b * var_c\nvar_e = 11\nvar_f = var_d - var_e\nvar_g = var_a + var_f\nvar_h = 17\nvar_i = 5\nvar_j = var_h * var_i\nvar_k = 11\nvar_l = var_j - var_k\nvar_m = 2\nvar_n = var_l * var_m\nvar_o = 8\nvar_p = var_n + var_o\nvar_q = var_g + var_p\nprint(int(var_q))",
        "solution_code_en": "var_a = 17\nvar_b = 17\nvar_c = 5\nvar_d = var_b * var_c\nvar_e = 11\nvar_f = var_d - var_e\nvar_g = var_a + var_f\nvar_h = 17\nvar_i = 5\nvar_j = var_h * var_i\nvar_k = 11\nvar_l = var_j - var_k\nvar_m = 2\nvar_n = var_l * var_m\nvar_o = 8\nvar_p = var_n + var_o\nvar_q = var_g + var_p\nprint(int(var_q))"
    },
    "7745": {
        "category": "Arithmetic calculation",
        "question_ko": "큰 통에 물이 가득 들어 있습니다. 이 물을 모양과 크기가 같은 7개의 작은 물통에 나누어 담으려고 합니다. 900그램(g)씩 나누어 담으면 200그램(g)이 남습니다. 큰 물통에 들어 있는 물은 몇 킬로그램(㎏)입니까?",
        "question_en": "A large bucket is filled with water. You want to divide this water into 7 smaller buckets of the same shape and size. If you divide it by 900 grams (g), 200 grams (g) remain. How many kilograms (kg) of water is in the large bucket?",
        "answer_ko": "6.50",
        "answer_en": "6.5",
        "solution_abst_ko": "900 7 [OP_MUL] 200 [OP_ADD] 1000 [OP_DIV]",
        "solution_abst_en": "900 7 [OP_MUL] 200 [OP_ADD] 1000 [OP_DIV]",
        "solution_code_ko": "var_a = 900\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 200\nvar_e = var_c + var_d\nvar_f = 1000\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 900\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 200\nvar_e = var_c + var_d\nvar_f = 1000\nvar_g = var_e / var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "7746": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 125까지 수를 쓸 때, 0부터 9까지의 숫자 중 2는 모두 몇 번 쓰는지 구하시오.",
        "question_en": "When writing numbers from 1 to 125, find out how many times 2 are written.",
        "answer_ko": "29",
        "answer_en": "29",
        "solution_abst_ko": "1 125 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 2 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 125 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 2 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 125\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 2\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 125\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 2\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))"
    },
    "7747": {
        "category": "Arithmetic calculation",
        "question_ko": "한 상자에 16캔씩 들어있는 음료수를 7상자 샀습니다. 그중에서 13개는 운반 도중 캔이 찌그러져서 버리고, 남은 음료수를 8상자에 똑같이 나누어 담으려고 합니다. 상자에 들어가지 못하는 음료수는 몇 캔입니까?",
        "question_en": "I bought 7 boxes of soda, each box containing 16 cans. Thirteen of them are discarded because the cans were crushed during transport, and I plan to distribute the remaining beverages equally among the eight cartons. How many cans of beverages do not fit in the box?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "16 7 [OP_MUL] 13 [OP_SUB] 8 [OP_MOD]",
        "solution_abst_en": "16 7 [OP_MUL] 13 [OP_SUB] 8 [OP_MOD]",
        "solution_code_ko": "var_a = 16\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = var_e % var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 16\nvar_b = 7\nvar_c = var_a * var_b\nvar_d = 13\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = var_e % var_f\nprint(int(var_g))"
    },
    "7748": {
        "category": "Comparison",
        "question_ko": "달리기 시합에서 정국이는 7등을 했고, 민영이는 5등을 했습니다. 태형이는 민영이보다 못했지만 정국이보다는 잘했습니다. 태형이는 몇 등입니까?",
        "question_en": "In a running competition, Jungkook came in the 7th and Minyoung came in the 5th. Taehyung did worse than Minyoung but better than Jungkook. In what place did Taehyung come in?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "5 7 [OP_ADD] 2 [OP_FDIV]",
        "solution_abst_en": "5 7 [OP_ADD] 2 [OP_FDIV]",
        "solution_code_ko": "var_a = 5\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "7749": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 24로 나누었더니 몫이 19 였습니다. 어떤 수는 얼마일까요?",
        "question_en": "When a number is divided by 24, it becomes 19. What number is it?",
        "answer_ko": "456",
        "answer_en": "456",
        "solution_abst_ko": "19 24 [OP_MUL]",
        "solution_abst_en": "19 24 [OP_MUL]",
        "solution_code_ko": "var_a = 19\nvar_b = 24\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 19\nvar_b = 24\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "7750": {
        "category": "Geometry",
        "question_ko": "팔각뿔의 꼭짓점, 면, 모서리의 수의 합을 구하세요.",
        "question_en": "Find the sum of the vertices, faces, and edges of the octagonal pyramid.",
        "answer_ko": "34",
        "answer_en": "34",
        "solution_abst_ko": "8 1 [OP_ADD] 8 2 [OP_MUL] [OP_ADD] 8 1 [OP_ADD] [OP_ADD]",
        "solution_abst_en": "8 1 [OP_ADD] 8 2 [OP_MUL] [OP_ADD] 8 1 [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 8\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 8\nvar_i = 1\nvar_j = var_h + var_i\nvar_k = var_g + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 8\nvar_b = 1\nvar_c = var_a + var_b\nvar_d = 8\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 8\nvar_i = 1\nvar_j = var_h + var_i\nvar_k = var_g + var_j\nprint(int(var_k))"
    },
    "7751": {
        "category": "Comparison",
        "question_ko": "세 수 A, B, C가 있습니다. A는 8에 9를 곱한 후 3을 뺀 수입니다. B는 A를 3으로 나눈 몫입니다. C는 B를 2배 한 다음 4를 더한 수입니다. 가장 큰 수와 가장 작은 수의 합을 구하시오.",
        "question_en": "There are three numbers A, B, and C. A is 8 multiplied by 9 minus 3. B is the quotient of A divided by 3. C is equal to 2 times B plus 4. Find the sum of the largest and smallest numbers.",
        "answer_ko": "92",
        "answer_en": "92",
        "solution_abst_ko": "[OP_LIST_SOL] 8 9 [OP_MUL] 3 [OP_SUB] 8 9 [OP_MUL] 3 [OP_SUB] 3 [OP_DIV] 8 9 [OP_MUL] 3 [OP_SUB] 3 [OP_DIV] 2 [OP_MUL] 4 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] 3 [OP_LIST_MAX] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 8 9 [OP_MUL] 3 [OP_SUB] 8 9 [OP_MUL] 3 [OP_SUB] 3 [OP_DIV] 8 9 [OP_MUL] 3 [OP_SUB] 3 [OP_DIV] 2 [OP_MUL] 4 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] 3 [OP_LIST_MAX] [OP_ADD]",
        "solution_code_ko": "var_a = 8\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = 9\nvar_h = var_f * var_g\nvar_i = 3\nvar_j = var_h - var_i\nvar_k = 3\nvar_l = var_j / var_k\nvar_m = 8\nvar_n = 9\nvar_o = var_m * var_n\nvar_p = 3\nvar_q = var_o - var_p\nvar_r = 3\nvar_s = var_q / var_r\nvar_t = 2\nvar_u = var_s * var_t\nvar_v = 4\nvar_w = var_u + var_v\nlist_a= []\nif \"/\" in str(var_w):\n    var_w = eval(str(var_w))\nlist_a.append(var_w)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_a.append(var_l)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nlist_a.reverse()\nvar_x = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_y = list_b[-var_x]\nvar_z = 3\nlist_c=list_a.copy()\nlist_c.sort()\nvar_A = list_c[-var_z]\nvar_B = var_y + var_A\nprint(int(var_B))",
        "solution_code_en": "var_a = 8\nvar_b = 9\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c - var_d\nvar_f = 8\nvar_g = 9\nvar_h = var_f * var_g\nvar_i = 3\nvar_j = var_h - var_i\nvar_k = 3\nvar_l = var_j / var_k\nvar_m = 8\nvar_n = 9\nvar_o = var_m * var_n\nvar_p = 3\nvar_q = var_o - var_p\nvar_r = 3\nvar_s = var_q / var_r\nvar_t = 2\nvar_u = var_s * var_t\nvar_v = 4\nvar_w = var_u + var_v\nlist_a= []\nif \"/\" in str(var_w):\n    var_w = eval(str(var_w))\nlist_a.append(var_w)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_a.append(var_l)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nlist_a.reverse()\nvar_x = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_y = list_b[-var_x]\nvar_z = 3\nlist_c=list_a.copy()\nlist_c.sort()\nvar_A = list_c[-var_z]\nvar_B = var_y + var_A\nprint(int(var_B))"
    },
    "7752": {
        "category": "Possibility",
        "question_ko": "네 개의 숫자 3, 5, 7, 9를 각각 한 번씩만 사용하여 만들 수 있는 네 자리 수의 총합을 구하여라.",
        "question_en": "Find the sum of possible four digit numbers that can be formed by using each 3, 5, 7, and 9.",
        "answer_ko": "159984",
        "answer_en": "159984",
        "solution_abst_ko": "[OP_LIST_SOL] 3 5 7 9 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 3 5 7 9 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 3\nvar_b = 5\nvar_c = 7\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint(int(var_f))",
        "solution_code_en": "var_a = 3\nvar_b = 5\nvar_c = 7\nvar_d = 9\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_b = [float(i) for i in list_b]\nvar_f = sum(list_b)\nprint(int(var_f))"
    },
    "7753": {
        "category": "Possibility",
        "question_ko": "은희를 포함하여 5명의 친구들과 함께 교실 청소를 하려 한다. 교실 바닥 담당 2명, 창문 담당 1명을 뽑는다고 할 때, 은희가 교실 바닥 담당이 되는 경우의 수를 구하시오.",
        "question_en": "You are going to clean the classroom with 5 friends including Eunhee. When picking 2 people in charge of the classroom floor and 1 person in charge of the window, find the number of cases where Eunhee be in charge of the classroom floor.",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "5 1 [OP_SUB] 2 1 [OP_SUB] 1 [OP_ADD] [OP_PERM]",
        "solution_abst_en": "5 1 [OP_SUB] 2 1 [OP_SUB] 1 [OP_ADD] [OP_PERM]",
        "solution_code_ko": "var_a = 5\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = 1\nvar_c = int(var_c)\nvar_h = int(var_h)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i * (var_c-i)\nprint(int(var_i))",
        "solution_code_en": "var_a = 5\nvar_b = 1\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = 1\nvar_c = int(var_c)\nvar_h = int(var_h)\nfor i, elem in enumerate(range(var_h)):\n    var_i = var_i * (var_c-i)\nprint(int(var_i))"
    },
    "7754": {
        "category": "Geometry",
        "question_ko": "어느 호수의 둘레는 30미터(m)이며, 둘레는 94.2미터(m)이다. 호수의 둘레는 지름의 몇 배인가?",
        "question_en": "A lake has a circumference of 30 meters (m) and a circumference of 94.2 meters (m). How many times the circumference of the lake is greater than its diameter?",
        "answer_ko": "3.14",
        "answer_en": "3.14",
        "solution_abst_ko": "94.2 30 [OP_DIV]",
        "solution_abst_en": "94.2 30 [OP_DIV]",
        "solution_code_ko": "var_a = 94.2\nvar_b = 30\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 94.2\nvar_b = 30\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "7755": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중에서 3번째로 작은 수와 2번째로 작은 수의 차는 얼마입니까?",
        "question_en": "There are three numbers 10, 11 and 12. What is the value of difference between the 3rd smallest number and the 2nd smallest number?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 3 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 3 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e - var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e - var_g\nprint(int(var_h))"
    },
    "7756": {
        "category": "Geometry",
        "question_ko": "수민이는 한 변의 길이가 30센티미터(㎝)인 정사각형 모양의 종이를 6장 가지고 있습니다. 이 종이를 한 줄로 연결하기 위해 7센티미터(㎝)씩 겹쳐 놓고 풀로 붙였습니다. 연결된 종이의 넓이를 구하시오.",
        "question_en": "Sumin has 6 square-shaped pieces of paper with each side measuring 30 centimeters (cm). To connect these papers in a single line, she overlapped them by 7 centimeters (cm) and attached them with glue. Find the area of the connected paper.",
        "answer_ko": "4350",
        "answer_en": "4350",
        "solution_abst_ko": "30 6 [OP_MUL] 7 6 1 [OP_SUB] [OP_MUL] [OP_SUB] 30 [OP_MUL]",
        "solution_abst_en": "30 6 [OP_MUL] 7 6 1 [OP_SUB] [OP_MUL] [OP_SUB] 30 [OP_MUL]",
        "solution_code_ko": "var_a = 30\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = 6\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_c - var_h\nvar_j = 30\nvar_k = var_i * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 30\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 7\nvar_e = 6\nvar_f = 1\nvar_g = var_e - var_f\nvar_h = var_d * var_g\nvar_i = var_c - var_h\nvar_j = 30\nvar_k = var_i * var_j\nprint(int(var_k))"
    },
    "7757": {
        "category": "Possibility",
        "question_ko": "바나나 7개를 서로 다른 2개의 바구니에 나누어 담으려고 합니다. 바구니에는 적어도 바나나 1개를 담아야 합니다. 바나나를 나누어 담는 방법은 모두 몇 가지입니까?",
        "question_en": "You want to divide 7 bananas into 2 different baskets. The basket must contain at least 1 banana. How many ways are there to share bananas?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "7 2 1 [OP_MUL] [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "7 2 1 [OP_MUL] [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 7\nvar_b = 2\nvar_c = 1\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 7\nvar_b = 2\nvar_c = 1\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "7758": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 학교는 수학 실력에 따라 상반과 하반으로 나누어서 수업을 한다. 학생이 총 120명이고 하반 학생이 상반 학생보다 36명 더 많다면 하반 학생은 몇 명입니까?",
        "question_en": "Some school divides classes into upper and lower classes according to math skills. If there are a total of 120 students and there are 36 more students in the lower class than in the upper class, how many students are in the lower class?",
        "answer_ko": "78",
        "answer_en": "78",
        "solution_abst_ko": "120 36 [OP_SUB] 2 [OP_DIV] 36 [OP_ADD]",
        "solution_abst_en": "120 36 [OP_SUB] 2 [OP_DIV] 36 [OP_ADD]",
        "solution_code_ko": "var_a = 120\nvar_b = 36\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 36\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 120\nvar_b = 36\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 36\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "7759": {
        "category": "Comparison",
        "question_ko": "정국 앞에 2명이 서 있고, 정국 뒤에 4명이 서있다. 총 8줄이 있고 각 줄에 서 있는 사람의 수가 같다면 총 몇 명입니까?",
        "question_en": "There are 2 people standing in front of Jungkook and four people behind him. If there are a total of 8 lines with the same number of people for each line, how many people are there?",
        "answer_ko": "56",
        "answer_en": "56",
        "solution_abst_ko": "2 4 [OP_ADD] 1 [OP_ADD] 8 [OP_MUL]",
        "solution_abst_en": "2 4 [OP_ADD] 1 [OP_ADD] 8 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "7760": {
        "category": "Arithmetic calculation",
        "question_ko": "3/25, 1/5, 55.21 총 3개의 숫자가 있습니다. 숫자의 합은 얼마인가요?",
        "question_en": "There are 3 numbers: 3/25, 1/5, and 55.21. What is the sum of these numbers?",
        "answer_ko": "55.53",
        "answer_en": "55.53",
        "solution_abst_ko": "3/25 1/5 [OP_ADD] 55.21 [OP_ADD]",
        "solution_abst_en": "3/25 1/5 [OP_ADD] 55.21 [OP_ADD]",
        "solution_code_ko": "var_a = 0.12\nvar_b = 0.2\nvar_c = var_a + var_b\nvar_d = 55.21\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.12\nvar_b = 0.2\nvar_c = var_a + var_b\nvar_d = 55.21\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "7761": {
        "category": "Geometry",
        "question_ko": "오각형의 변과 꼭짓점의 개수를 각각 A, B라 할 때, A+B의 값은?",
        "question_en": "If A and B are the numbers of sides and vertices of a pentagon, what is the value of A+B?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "5 5 [OP_ADD]",
        "solution_abst_en": "5 5 [OP_ADD]",
        "solution_code_ko": "var_a = 5\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "7762": {
        "category": "Possibility",
        "question_ko": "1부터 9까지의 수가 적힌 숫자 카드들 중 3장을 골라서 합이 19가 되게 하는 수의 조합의 개수를 구하시오.",
        "question_en": "Find the number of combinations of numbers that add up to 19 by selecting 3 of the number cards from 1 to 9.",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "1 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 19 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 19 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 19\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 19\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))"
    },
    "7763": {
        "category": "Comparison",
        "question_ko": "2.23, 3.12, 9.434 및 2.453중 2번째로 작은 수는?",
        "question_en": "Which of 2.23, 3.12, 9.434, and 2.453 is the second smallest number?",
        "answer_ko": "2.45",
        "answer_en": "2.45",
        "solution_abst_ko": "[OP_LIST_SOL] 2.23 3.12 9.434 2.453 [OP_LIST_EOL] 2 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 2.23 3.12 9.434 2.453 [OP_LIST_EOL] 2 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 2.23\nvar_b = 3.12\nvar_c = 9.434\nvar_d = 2.453\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nprint('{:.2f}'.format(round(var_f+1e-10,2)))",
        "solution_code_en": "var_a = 2.23\nvar_b = 3.12\nvar_c = 9.434\nvar_d = 2.453\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[var_e-1]\nprint('{:.2f}'.format(round(var_f+1e-10,2)))"
    },
    "7764": {
        "category": "Arithmetic calculation",
        "question_ko": "운동장에서 놀던 학생 중에서 16명이 집에 가고, 9명이 더 와서 25명이 되었습니다. 처음에 운동장에서 놀던 학생은 몇 명입니까?",
        "question_en": "Of the students who played on the playground, 16 went home, and 9 more came, resulting in a total of 25. How many students were playing on the playground at first?",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "25 9 [OP_SUB] 16 [OP_ADD]",
        "solution_abst_en": "25 9 [OP_SUB] 16 [OP_ADD]",
        "solution_code_ko": "var_a = 25\nvar_b = 9\nvar_c = var_a - var_b\nvar_d = 16\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 25\nvar_b = 9\nvar_c = var_a - var_b\nvar_d = 16\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7765": {
        "category": "Comparison",
        "question_ko": "유나와 친구들은 서로 키가 다릅니다. 선생님께서 앞에서부터 키가 작은 순서대로 줄을 세웠더니 유나는 앞에서 4번째, 뒤에서 6번째에 있었습니다. 유나와 친구들은 모두 몇 명입니까?",
        "question_en": "Yuna and her friends are of different heights. The teacher lined up in order from the smallest height, and Yuna was 4th from the front and 6th from the back. How many Yuna and her friends are there?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "4 6 [OP_ADD] 1 [OP_SUB]",
        "solution_abst_en": "4 6 [OP_ADD] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 4\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 4\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "7766": {
        "category": "Arithmetic calculation",
        "question_ko": "필통에 연필과 지우개가 모두 240개 있습니다. 연필이 지우개보다 2개 적게 들어있다면 필통 속의 지우개는 모두 몇 개입니까?",
        "question_en": "There are 240 pencils and erasers in the pencil case. If there are 2 fewer pencils than erasers, how many erasers are there in the pencil case?",
        "answer_ko": "121",
        "answer_en": "121",
        "solution_abst_ko": "240 2 [OP_SUB] 2 [OP_DIV] 2 [OP_ADD]",
        "solution_abst_en": "240 2 [OP_SUB] 2 [OP_DIV] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 240\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 240\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = var_c / var_d\nvar_f = 2\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "7767": {
        "category": "Arithmetic calculation",
        "question_ko": "38, 114, 152, 95가 있습니다. 그중에서 가장 큰 수를 가장 작은 수로 나눈 값은 얼마입니까?",
        "question_en": "There are numbers which are 38, 114, 152, and 95. What is the value when the largest number is divided by the smallest number?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] 38 114 152 95 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_DIV]",
        "solution_abst_en": "[OP_LIST_SOL] 38 114 152 95 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_DIV]",
        "solution_code_ko": "var_a = 38\nvar_b = 114\nvar_c = 152\nvar_d = 95\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 38\nvar_b = 114\nvar_c = 152\nvar_d = 95\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_f = list_b[-var_e]\nvar_g = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nvar_i = var_f / var_h\nprint(int(var_i))"
    },
    "7768": {
        "category": "Comparison",
        "question_ko": "5개의 서로 다른 상자에 초콜릿이 각각 20개, 15개, 18개, 17개, 20개 들어있습니다. 초콜릿이 18개 이상 들어있는 상자들에서 초콜릿을 모두 꺼내 큰 상자 하나에 담았을 때, 이 상자에는 몇 개의 초콜릿이 담길지 구하시오.",
        "question_en": "5 different boxes contain 20, 15, 18, 17, and 20 chocolates respectively. If all the chocolates are taken out of boxes containing 18 or more chocolates and put into one large box, find how many chocolates will fit in this box.",
        "answer_ko": "58",
        "answer_en": "58",
        "solution_abst_ko": "[OP_LIST_SOL] 20 15 18 17 20 [OP_LIST_EOL] 18 [OP_LIST_MORE_EQUAL] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 20 15 18 17 20 [OP_LIST_EOL] 18 [OP_LIST_MORE_EQUAL] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 20\nvar_b = 15\nvar_c = 18\nvar_d = 17\nvar_e = 20\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 18\nlist_b = []\nfor i in list_a:\n    if i >= var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 20\nvar_b = 15\nvar_c = 18\nvar_d = 17\nvar_e = 20\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 18\nlist_b = []\nfor i in list_a:\n    if i >= var_f:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_g = sum(list_b)\nprint(int(var_g))"
    },
    "7769": {
        "category": "Arithmetic calculation",
        "question_ko": "아버지의 나이를 딸의 나이로 나누면 4입니다. 5년 후 두 사람의 나이를 합하면 50일 때, 올해 아버지는 몇 세입니까?",
        "question_en": "Father's age divided by daughter's age equals 4. When the sum of their ages after 5 years is 50, how old is your father this year?",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "50 5 2 [OP_MUL] [OP_SUB] 1 4 [OP_ADD] [OP_DIV] 4 [OP_MUL]",
        "solution_abst_en": "50 5 2 [OP_MUL] [OP_SUB] 1 4 [OP_ADD] [OP_DIV] 4 [OP_MUL]",
        "solution_code_ko": "var_a = 50\nvar_b = 5\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = 4\nvar_h = var_f + var_g\nvar_i = var_e / var_h\nvar_j = 4\nvar_k = var_i * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 50\nvar_b = 5\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = 4\nvar_h = var_f + var_g\nvar_i = var_e / var_h\nvar_j = 4\nvar_k = var_i * var_j\nprint(int(var_k))"
    },
    "7770": {
        "category": "Geometry",
        "question_ko": "평행사변형의 각 변의 길이는 각각 18센티미터(㎝), 12센티미터(㎝)이다. 둘레를 구하라.",
        "question_en": "The length of each side of the parallelogram is 18 centimeters (cm) and 12 centimeters (cm), respectively. Find the circumference of this parellelogram.",
        "answer_ko": "60",
        "answer_en": "60",
        "solution_abst_ko": "18 12 [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "18 12 [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 18\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 18\nvar_b = 12\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "7771": {
        "category": "Arithmetic calculation",
        "question_ko": "도로의 양쪽에 처음부터 끝까지 총 30그루의 나무가 9미터(m) 간격으로 심어져 있습니다. 이 도로의 길이는 몇 미터(m)인지 구해 보시오.",
        "question_en": "A total of 30 trees are planted 9 meters (m) apart on either side of a road from beginning to end. Find the length of this road in meters (m).",
        "answer_ko": "126",
        "answer_en": "126",
        "solution_abst_ko": "30 2 [OP_DIV] 1 [OP_SUB] 9 [OP_MUL]",
        "solution_abst_en": "30 2 [OP_DIV] 1 [OP_SUB] 9 [OP_MUL]",
        "solution_code_ko": "var_a = 30\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 9\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 30\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 9\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "7772": {
        "category": "Comparison",
        "question_ko": "세 개의 숫자 A, B, C가 있습니다. A는 1/2이고 B는 9/10입니다. C가 2/5이면 A, B, C 중 작은 수는 무엇입니까?",
        "question_en": "There are three numbers A, B, and C. A is 1/2 and B is 9/10. If C is 2/5, what is the smallest among A, B, or C?",
        "answer_ko": "C",
        "answer_en": "C",
        "solution_abst_ko": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] 1 2 [OP_DIV] 9 10 [OP_DIV] 2 5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] 1 2 [OP_DIV] 9 10 [OP_DIV] 2 5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nvar_e = 2\nvar_f = var_d / var_e\nvar_g = 9\nvar_h = 10\nvar_i = var_g / var_h\nvar_j = 2\nvar_k = 5\nvar_l = var_j / var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[var_m-1]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nvar_e = 2\nvar_f = var_d / var_e\nvar_g = 9\nvar_h = 10\nvar_i = var_g / var_h\nvar_j = 2\nvar_k = 5\nvar_l = var_j / var_k\nlist_b= []\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_m = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_n = list_c[var_m-1]\nvar_o = list_b.index(var_n)+1\nvar_p = list_a[var_o-1]\nprint(var_p)"
    },
    "7773": {
        "category": "Geometry",
        "question_ko": "길이가 각각 36센티미터(㎝), 42센티미터(㎝), 48센티미터(㎝) 인 판자가 있다. 이 판자를 다듬느라 1/6을 잘라낸 후 일정 부분을 겹쳐서 붙혔더니 총 길이가 97센티미터(㎝)이다. 겹처진 부분의 길이는 모두 같을때, 겹처진 부분은 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "There are planks that are 36 centimeters (cm), 42 centimeters (cm), and 48 centimeters (cm) respectively. After cutting out 1/6 of this plank while trimming it, I overlapped and glued certain parts together, and the total length is 97 centimeters (cm). If all overlapping parts are the same length, find how many centimeters (cm) is the overlapping part.",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "36 42 [OP_ADD] 48 [OP_ADD] 1 1/6 [OP_SUB] [OP_MUL] 97 [OP_SUB] 3 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "36 42 [OP_ADD] 48 [OP_ADD] 1 1/6 [OP_SUB] [OP_MUL] 97 [OP_SUB] 3 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 36\nvar_b = 42\nvar_c = var_a + var_b\nvar_d = 48\nvar_e = var_c + var_d\nvar_f = 1\nvar_g = 0.16666666666666666\nvar_h = var_f - var_g\nvar_i = var_e * var_h\nvar_j = 97\nvar_k = var_i - var_j\nvar_l = 3\nvar_m = 1\nvar_n = var_l - var_m\nvar_o = var_k / var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 36\nvar_b = 42\nvar_c = var_a + var_b\nvar_d = 48\nvar_e = var_c + var_d\nvar_f = 1\nvar_g = 0.16666666666666666\nvar_h = var_f - var_g\nvar_i = var_e * var_h\nvar_j = 97\nvar_k = var_i - var_j\nvar_l = 3\nvar_m = 1\nvar_n = var_l - var_m\nvar_o = var_k / var_n\nprint(int(var_o))"
    },
    "7774": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 5를 곱해야 하는데 잘못하여 5를 더했더니 43이 되었습니다. 바르게 계산한 결과를 구하시오.",
        "question_en": "A number needs to be multiplied by 5, but I mistakenly added 5 to get 43. Find the result of the correct calculation.",
        "answer_ko": "190",
        "answer_en": "190",
        "solution_abst_ko": "43 5 [OP_SUB] 5 [OP_MUL]",
        "solution_abst_en": "43 5 [OP_SUB] 5 [OP_MUL]",
        "solution_code_ko": "var_a = 43\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 43\nvar_b = 5\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "7775": {
        "category": "Geometry",
        "question_ko": "둘레가 28 미터(m) 인 원 모양의 공원에 4 미터(m) 간격으로 나무를 심으려고 합니다. 나무를 몇 그루 심을 수 있는 지 구하시오.",
        "question_en": "You want to plant trees at intervals of 4 meters (m) in a circle-shaped park with a circumference of 28 meters (m). Find how many trees you can plant.",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "28 4 [OP_DIV]",
        "solution_abst_en": "28 4 [OP_DIV]",
        "solution_code_ko": "var_a = 28\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 28\nvar_b = 4\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "7776": {
        "category": "Geometry",
        "question_ko": "모서리, 면, 꼭짓점의 수의 합이 50개인 각기둥이 있다. 이 각기둥과 밑면의 모양이 같은 각뿔의 모서리의 수는 몇개인가요?",
        "question_en": "There is a prism whose sum of the number of edges, faces, and vertices is 50. How many edges of the pyramid have the same base shape as the prism?",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "50 2 [OP_SUB] 2 3 [OP_ADD] 1 [OP_ADD] [OP_DIV] 2 [OP_MUL]",
        "solution_abst_en": "50 2 [OP_SUB] 2 3 [OP_ADD] 1 [OP_ADD] [OP_DIV] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 50\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = var_c / var_h\nvar_j = 2\nvar_k = var_i * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 50\nvar_b = 2\nvar_c = var_a - var_b\nvar_d = 2\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = var_c / var_h\nvar_j = 2\nvar_k = var_i * var_j\nprint(int(var_k))"
    },
    "7777": {
        "category": "Possibility",
        "question_ko": "0, 1, 2, 5의 숫자 중 두 개의 숫자를 뽑아 10보다 크고 100보다 작은 수를 만들고자 한다. 뽑은 수 중 각 자리 숫자가 다른 경우는 몇 가지인가?",
        "question_en": "You want to draw two numbers from the digits 0, 1, 2, and 5 to create a number greater than 10 and less than 100. In how many cases does each digit of the drawn number differ?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "[OP_LIST_SOL] 0 1 2 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 10 [OP_LIST_MORE] 100 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0 1 2 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 10 [OP_LIST_MORE] 100 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nlist_c = []\nfor i in list_b:\n    if i > var_f:\n        list_c.append(i)\nvar_g = 100\nlist_d = []\nfor i in list_c:\n    if i < var_g:\n        list_d.append(i)\nvar_h = len(list_d)\nprint(int(var_h))",
        "solution_code_en": "var_a = 0\nvar_b = 1\nvar_c = 2\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 10\nlist_c = []\nfor i in list_b:\n    if i > var_f:\n        list_c.append(i)\nvar_g = 100\nlist_d = []\nfor i in list_c:\n    if i < var_g:\n        list_d.append(i)\nvar_h = len(list_d)\nprint(int(var_h))"
    },
    "7778": {
        "category": "Geometry",
        "question_ko": "딱지 여러장이 있습니다. 딱지를 늘여놓아 큰 정사각형을 만들고 보니 36장의 딱지가 남았습니다. 가로 한 변과 세로 한 변을 1열씩 늘렸더니 아직도 3장의 딱지가 남았습니다. 딱지는 모두 몇 장입니까?",
        "question_en": "There are several ttakjis. I laid out the ttakjis to make a large square, and there were residual 36 ttakjis that were not used to make the square. I increased one horizontal and one vertical side by one column, and there are still three residual ttakjis left. How many ttakjis are there in all?",
        "answer_ko": "292",
        "answer_en": "292",
        "solution_abst_ko": "36 3 [OP_SUB] 1 [OP_SUB] 2 [OP_DIV] 2 [OP_POW] 36 [OP_ADD]",
        "solution_abst_en": "36 3 [OP_SUB] 1 [OP_SUB] 2 [OP_DIV] 2 [OP_POW] 36 [OP_ADD]",
        "solution_code_ko": "var_a = 36\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 36\nvar_k = var_i + var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 36\nvar_b = 3\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 2\nvar_i = var_g ** var_h\nvar_j = 36\nvar_k = var_i + var_j\nprint(int(var_k))"
    },
    "7779": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 4를 곱한 값을 8로 나누었더니 몫이 6이고 나머지가 4였다. 어떤 수는 얼마인지 고르시오.",
        "question_en": "When a number is multiplied by 4 and divided by 8, the quotient is 6 and the remainder is 4. Find out what this number is.",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "6 8 [OP_MUL] 4 [OP_ADD] 4 [OP_DIV]",
        "solution_abst_en": "6 8 [OP_MUL] 4 [OP_ADD] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 4\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 6\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 4\nvar_e = var_c + var_d\nvar_f = 4\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "7780": {
        "category": "Geometry",
        "question_ko": "어떤 정육면체는 크기가 작은 정육면체 8개를 쌓아서 만들어졌습니다. 쌓아 만들어진 정육면체의 부피가 1000세제곱센티미터(㎤)일 때, 작은 정육면체의 한 모서리의 길이를 구하시오.",
        "question_en": "A cube is made by stacking 8 smaller cubes. If the volume of the stacked cubes is 1000 cubic centimeters (cm3), find the length of one corner of the smaller cube.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "1000 8 [OP_DIV] 1/3 [OP_POW]",
        "solution_abst_en": "1000 8 [OP_DIV] 1/3 [OP_POW]",
        "solution_code_ko": "var_a = 1000\nvar_b = 8\nvar_c = var_a / var_b\nvar_d = 0.3333333333333333\nvar_e = var_c ** var_d\nprint(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))",
        "solution_code_en": "var_a = 1000\nvar_b = 8\nvar_c = var_a / var_b\nvar_d = 0.3333333333333333\nvar_e = var_c ** var_d\nprint(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))"
    },
    "7781": {
        "category": "Arithmetic calculation",
        "question_ko": "십의 자리의 숫자가 3인 두 자리 자연수가 있다. 이 자연수에서 십의 자리의 숫자와 일의 자리의 숫자를 서로 바꾼 수가 처음 수보다 9만큼 작다고 할 때, 처음 수를 구하시오.",
        "question_en": "There is a two-digit natural number whose tens digit is 3. If the number of digits in the tens digit and the ones digit of this natural number that are interchanged is 9 less than the initial number, find the initial number.",
        "answer_ko": "32",
        "answer_en": "32",
        "solution_abst_ko": "3 10 [OP_MUL] 9 [OP_SUB] 3 [OP_SUB] 10 1 [OP_SUB] [OP_DIV] 3 10 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "3 10 [OP_MUL] 9 [OP_SUB] 3 [OP_SUB] 10 1 [OP_SUB] [OP_DIV] 3 10 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = var_e - var_f\nvar_h = 10\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_g / var_j\nvar_l = 3\nvar_m = 10\nvar_n = var_l * var_m\nvar_o = var_k + var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 3\nvar_b = 10\nvar_c = var_a * var_b\nvar_d = 9\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = var_e - var_f\nvar_h = 10\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_g / var_j\nvar_l = 3\nvar_m = 10\nvar_n = var_l * var_m\nvar_o = var_k + var_n\nprint(int(var_o))"
    },
    "7782": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 100까지의 수 중 7로 나눈 나머지가 2이고 8로 나눈 나머지도 2인 수 중 가장 작은 값을 구하시오.",
        "question_en": "Among the numbers from 1 to 100, find the smallest number whose remainder when divided by 7 is 2 and when divided by 8 is also 2.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "1 100 1 [OP_LIST_ARANGE] 7 2 [OP_LIST_DIVIDE_AND_REMAIN] 8 2 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MIN]",
        "solution_abst_en": "1 100 1 [OP_LIST_ARANGE] 7 2 [OP_LIST_DIVIDE_AND_REMAIN] 8 2 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 7\nvar_e = 2\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 8\nvar_g = 2\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 7\nvar_e = 2\nlist_b = [] \nvar_d = int(var_d)\nvar_e = int(var_e)\nif var_e < 0:\n    var_e = var_e + var_d\nfor i in list_a:\n    i = int(i)\n    if i%var_d == var_e:\n        list_b.append(i)\nvar_f = 8\nvar_g = 2\nlist_c = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_b:\n    i = int(i)\n    if i%var_f == var_g:\n        list_c.append(i)\nvar_h = 1\nlist_d=list_c.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nprint(int(var_i))"
    },
    "7783": {
        "category": "Correspondence",
        "question_ko": "AB+21=58입니다. A는 얼마인가요?",
        "question_en": "AB+21=58. Calculate the value of A.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "AB+21=58 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "AB+21=58 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = 'AB+21=58'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = 'AB+21=58'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "7784": {
        "category": "Geometry",
        "question_ko": "가로 4센티미터(㎝), 세로 6센티미터(㎝), 높이 5센티미터(㎝)인 직육면체의 모양의 비누가 있습니다. 이 비누를 사용하였더니 정육면체가 되었다면, 이때 비누 부피의 최대는 얼마입니까?",
        "question_en": "There is a soap in the shape of a rectangular parallelepiped measuring 4 centimeters (cm) wide, 6 centimeters (cm) long, and 5 centimeters (cm) high. If you use this soap and it becomes a cube, what is the maximum volume of the soap?",
        "answer_ko": "64",
        "answer_en": "64",
        "solution_abst_ko": "[OP_LIST_SOL] 4 6 4 [OP_LIST_EOL] 1 [OP_LIST_MIN] 1 [OP_LIST_MIN] 3 [OP_POW]",
        "solution_abst_en": "[OP_LIST_SOL] 4 6 4 [OP_LIST_EOL] 1 [OP_LIST_MIN] 1 [OP_LIST_MIN] 3 [OP_POW]",
        "solution_code_ko": "var_a = 4\nvar_b = 6\nvar_c = 4\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nvar_f = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = 3\nvar_i = var_g ** var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 4\nvar_b = 6\nvar_c = 4\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nvar_f = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = 3\nvar_i = var_g ** var_h\nprint(int(var_i))"
    },
    "7785": {
        "category": "Arithmetic calculation",
        "question_ko": "올해 어머니는 43살이고 딸은 11살입니다. 어머니 나이가 딸의 나이의 5배였을 때는 몇 년 전입니까?",
        "question_en": "This year the mother is 43 years old and the daughter is 11 years old. How many years ago was the mother's age five times her daughter's age?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "5 11 [OP_MUL] 43 [OP_SUB] 5 1 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "5 11 [OP_MUL] 43 [OP_SUB] 5 1 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 5\nvar_b = 11\nvar_c = var_a * var_b\nvar_d = 43\nvar_e = var_c - var_d\nvar_f = 5\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 5\nvar_b = 11\nvar_c = var_a * var_b\nvar_d = 43\nvar_e = var_c - var_d\nvar_f = 5\nvar_g = 1\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "7786": {
        "category": "Possibility",
        "question_ko": "정팔면체의 한 면에서 변은 몇 개일까요?",
        "question_en": "How many edges are there on a face of an octahedron?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "3",
        "solution_abst_en": "3",
        "solution_code_ko": "var_a = 3\nprint(int(var_a))",
        "solution_code_en": "var_a = 3\nprint(int(var_a))"
    },
    "7787": {
        "category": "Correspondence",
        "question_ko": "백의 자리가 7인 세 자리수 중 7의 배수는 몇 개입니까?",
        "question_en": "How many multiples of 7 are three-digit numbers with 7 in the hundreds place?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "7AB [OP_GEN_POSSIBLE_LIST] 7 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "7AB [OP_GEN_POSSIBLE_LIST] 7 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = '7AB'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 7\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))",
        "solution_code_en": "var_a = '7AB'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 7\nlist_b = []\nvar_b = int(var_b)\nfor i in list_a:\n    i = int(i)\n    if i % var_b == 0:\n        list_b.append(i)\nvar_c = len(list_b)\nprint(int(var_c))"
    },
    "7788": {
        "category": "Comparison",
        "question_ko": "세 사람이 숫자 카드를 각각 가지고 있다. 각 사람이 가진 숫자 카드의 평균을 X라고 할때, A, B 두 사람의 숫자 카드의 평균은 X보다 23 크고, B, C 두사람의 숫자 평균은 X보다 17작다. B의 숫자 카드에 적힌 수는 66이었다. A의 숫자 카드에 적힌 수를 구하여라.",
        "question_en": "Three people each have a number card. If X is the average of the number cards of each person, the average of the number cards of two people A and B is 23 greater than X, and the average of the number cards of two people B and C is 17 less than X. The number written on B's number card was 66. Find the number written on A's number card.",
        "answer_ko": "124",
        "answer_en": "124",
        "solution_abst_ko": "66 23 2 [OP_MUL] [OP_ADD] 3 [OP_MUL] 17 23 [OP_ADD] 2 [OP_MUL] [OP_SUB] 66 2 [OP_MUL] [OP_SUB] 2 2 [OP_ADD] 3 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "66 23 2 [OP_MUL] [OP_ADD] 3 [OP_MUL] 17 23 [OP_ADD] 2 [OP_MUL] [OP_SUB] 66 2 [OP_MUL] [OP_SUB] 2 2 [OP_ADD] 3 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 66\nvar_b = 23\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nvar_f = 3\nvar_g = var_e * var_f\nvar_h = 17\nvar_i = 23\nvar_j = var_h + var_i\nvar_k = 2\nvar_l = var_j * var_k\nvar_m = var_g - var_l\nvar_n = 66\nvar_o = 2\nvar_p = var_n * var_o\nvar_q = var_m - var_p\nvar_r = 2\nvar_s = 2\nvar_t = var_r + var_s\nvar_u = 3\nvar_v = var_t - var_u\nvar_w = var_q / var_v\nprint(int(var_w))",
        "solution_code_en": "var_a = 66\nvar_b = 23\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a + var_d\nvar_f = 3\nvar_g = var_e * var_f\nvar_h = 17\nvar_i = 23\nvar_j = var_h + var_i\nvar_k = 2\nvar_l = var_j * var_k\nvar_m = var_g - var_l\nvar_n = 66\nvar_o = 2\nvar_p = var_n * var_o\nvar_q = var_m - var_p\nvar_r = 2\nvar_s = 2\nvar_t = var_r + var_s\nvar_u = 3\nvar_v = var_t - var_u\nvar_w = var_q / var_v\nprint(int(var_w))"
    },
    "7789": {
        "category": "Geometry",
        "question_ko": "토끼는 한 변의 길이가 13미터(m)인 공원을 산책하고 있습니다. 토끼가 걸은 거리는 총 몇 미터(m)입니까?",
        "question_en": "A rabbit is walking in a park with a side length measuring 13 meters (m). How many meters (m) did the rabbit walk?",
        "answer_ko": "52",
        "answer_en": "52",
        "solution_abst_ko": "13 4 [OP_MUL]",
        "solution_abst_en": "13 4 [OP_MUL]",
        "solution_code_ko": "var_a = 13\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 13\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "7790": {
        "category": "Correspondence",
        "question_ko": "10를 A로 나눴을 때 몫이 B, 나머지가 C 였습니다. A, B, C는 자연수 입니다. B와 C가 같을 때, 가능한 A 중 가장 큰 수를 구하시오.",
        "question_en": "When 10 is divided by A, the quotient is B and the remainder is C. A, B, and C are natural numbers. If B and C are equal, find the largest possible number of A.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "10 1 [OP_SUB]",
        "solution_abst_en": "10 1 [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 10\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "7791": {
        "category": "Correspondence",
        "question_ko": "윤기는 15를 어떤 수에 곱해 45를 얻었습니다. 어떤 수에서 1를 뺀 결과를 정확히 구하시오.",
        "question_en": "Yoongi multiplied 15 by a certain number to get 45. Find the exact result of subtracting 1 from the number.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "45 15 [OP_DIV] 1 [OP_SUB]",
        "solution_abst_en": "45 15 [OP_DIV] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 45\nvar_b = 15\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 45\nvar_b = 15\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "7792": {
        "category": "Arithmetic calculation",
        "question_ko": "정국이는 구슬을 3개 가지고 있고, 지민이가 가진 구슬은 정국이보다 4개가 더 많습니다. 두 사람이 가지고 있는 구슬은 모두 몇 개입니까?",
        "question_en": "Jungkook has 3 marbles, Jimin has 4 more marbles than what Jungkook has. What is a total number of their marbles?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "3 3 4 [OP_ADD] [OP_ADD]",
        "solution_abst_en": "3 3 4 [OP_ADD] [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 3\nvar_c = 4\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 3\nvar_b = 3\nvar_c = 4\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "7793": {
        "category": "Geometry",
        "question_ko": "어떤 육각뿔의 모서리의 합은 120센티미터(㎝)입니다. 모서리의 합을 모서리의 개수로 나누면 얼마입니까?",
        "question_en": "The sum of the edges of a hexagonal pyramid is 120 centimeters (cm). What is the sum of the edges divided by the number of edges?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "120 6 2 [OP_MUL] [OP_DIV]",
        "solution_abst_en": "120 6 2 [OP_MUL] [OP_DIV]",
        "solution_code_ko": "var_a = 120\nvar_b = 6\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 120\nvar_b = 6\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a / var_d\nprint(int(var_e))"
    },
    "7794": {
        "category": "Correspondence",
        "question_ko": "식 31+6AB=683이 있습니다. B에 들어가야 하는 숫자를 구하시오",
        "question_en": "We have the expression 31+6AB=683. Find the number that goes into B",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "31+6AB=683 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "31+6AB=683 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '31+6AB=683'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '31+6AB=683'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "7795": {
        "category": "Comparison",
        "question_ko": "정국이는 6개의 사과에서 3개를 먹었습니다. 윤기가 가진 사과가 4개라면 누가 더 많이 사과를 가지고 있나요?",
        "question_en": "Jungkook ate 3 out of 6 apples. If Yoongi has 4 apples, who has more apples?",
        "answer_ko": "윤기",
        "answer_en": "Yoongi",
        "solution_abst_ko": "[OP_LIST_SOL] 정국 윤기 [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_SUB] 4 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Jungkook Yoongi [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_SUB] 4 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '정국'\nvar_b = '윤기'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 3\nvar_e = var_c - var_d\nvar_f = 4\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)",
        "solution_code_en": "var_a = 'Jungkook'\nvar_b = 'Yoongi'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 6\nvar_d = 3\nvar_e = var_c - var_d\nvar_f = 4\nlist_b= []\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[-var_g]\nvar_i = list_b.index(var_h)+1\nvar_j = list_a[var_i-1]\nprint(var_j)"
    },
    "7796": {
        "category": "Possibility",
        "question_ko": "숫자 7, 2, 9를 한 번씩만 사용하여 세 자리 수를 만들려고 합니다. 만들 수 있는 세 자리 수는 모두 몇 개입니까?",
        "question_en": "You want to create a three-digit number using the numbers 7, 2, and 9 only once. How many three-digit numbers can you make?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "[OP_LIST_SOL] 7 2 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 7 2 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 7\nvar_b = 2\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 7\nvar_b = 2\nvar_c = 9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "7797": {
        "category": "Arithmetic calculation",
        "question_ko": "50미터(m) 간격으로 동상이 1650미터(m) 거리위에 세워져있습니다. 거리의 처음과 끝에도 동상이 세워져 있을 때, 거리 양쪽에 세워진 동상의 수는 모두 몇 개 입니까?",
        "question_en": "At intervals of 50 meters (m), statues are erected on both sides of the street a distance of 1650 meters (m). If there are statues at the beginning and end of the street, how many statues are there on both sides of the street?",
        "answer_ko": "68",
        "answer_en": "68",
        "solution_abst_ko": "1650 50 [OP_DIV] 1 [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "1650 50 [OP_DIV] 1 [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 1650\nvar_b = 50\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1650\nvar_b = 50\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "7798": {
        "category": "Arithmetic calculation",
        "question_ko": "지민이는 연필 3타를 가지고 있었습니다. 그 중 8자루를 동생에게 주고 유나에게도 몇 자루 주었더니 17자루가 남았습니다. 연필 1타는 12자루일때, 지민이가 유나에게 준 연필은 몇 자루일까요?",
        "question_en": "Jimin had three dozen pencils. He gave 8 of them to his younger brother and a few to Yuna, so he has 17 left. If one dozen is 12 pencils, how many pencils did Jimin give Yuna?",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "3 12 [OP_MUL] 8 [OP_SUB] 17 [OP_SUB]",
        "solution_abst_en": "3 12 [OP_MUL] 8 [OP_SUB] 17 [OP_SUB]",
        "solution_code_ko": "var_a = 3\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c - var_d\nvar_f = 17\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 3\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c - var_d\nvar_f = 17\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "7799": {
        "category": "Arithmetic calculation",
        "question_ko": "연속하는 세 자연수의 합이 30일 때, 세 자연수 중 첫번째 수를 구하시오.",
        "question_en": "If the sum of three consecutive natural numbers is 30, find the smallest natural number of them.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "30 3 [OP_DIV] 1 [OP_SUB]",
        "solution_abst_en": "30 3 [OP_DIV] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 30\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 30\nvar_b = 3\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "7800": {
        "category": "Possibility",
        "question_ko": "윤기는 서점에서 5개의 책 중 3개의 책을 사려고 합니다. 가능한 경우의 수는 모두 몇 가지인지 구하시오.",
        "question_en": "Yoongi wants to buy 3 out of 5 books at the bookstore. Find how many possible cases there are.",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "5 3 [OP_COMB]",
        "solution_abst_en": "5 3 [OP_COMB]",
        "solution_code_ko": "var_a = 5\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))",
        "solution_code_en": "var_a = 5\nvar_b = 3\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nprint(int(var_c))"
    },
    "7801": {
        "category": "Geometry",
        "question_ko": "두 정사각형과 직사각형의 넓이는 같습니다. 정사각형의 한 변의 길이가 5센티미터(㎝), 직사각형의 한 변의 길이가 4센티미터(㎝)라고 할 때, 직사각형의 다른 한 변의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "The square and the rectangle have the same area. If one side of the square is 5 centimeters (cm) and one side of the rectangle is 4 centimeters (cm), what is the length of the other side of the rectangle in centimeters (cm)?",
        "answer_ko": "6.25",
        "answer_en": "6.25",
        "solution_abst_ko": "5 2 [OP_POW] 4 [OP_DIV]",
        "solution_abst_en": "5 2 [OP_POW] 4 [OP_DIV]",
        "solution_code_ko": "var_a = 5\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 5\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 4\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "7802": {
        "category": "Correspondence",
        "question_ko": "성주의 나이와 성주 동생의 나이를 곱하였더니 16이 되었을 때, 성주의 나이로 가능한 수는 몇 개입니까? (단, 성주와 동생은 쌍둥이가 아닙니다.)",
        "question_en": "If you multiply the age of the Seongju by the age of Seongju's younger brother, you get 16. How many possible numbers are there for the age of Seongju? (However, Seongju and his younger brother are not twins.)",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "16 [OP_LIST_GET_DIVISOR] [OP_LIST_LEN] 2 [OP_FDIV]",
        "solution_abst_en": "16 [OP_LIST_GET_DIVISOR] [OP_LIST_LEN] 2 [OP_FDIV]",
        "solution_code_ko": "var_a = 16\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = len(list_a)\nvar_c = 2\nvar_d = var_b // var_c\nprint(int(var_d))",
        "solution_code_en": "var_a = 16\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = len(list_a)\nvar_c = 2\nvar_d = var_b // var_c\nprint(int(var_d))"
    },
    "7803": {
        "category": "Correspondence",
        "question_ko": "57A-B14=364일 때, A에 들어가야 하는 숫자는 무엇인가요?",
        "question_en": "If 57A-B14=364, what number should go in A?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "57A-B14=364 A [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "57A-B14=364 A [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '57A-B14=364'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '57A-B14=364'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "7804": {
        "category": "Correspondence",
        "question_ko": "어떤 수를 3으로 나누고 14를 더한 뒤 2를 곱해야 했는데 잘 못하여 3을 곱하고 14를 더한 뒤 2를 곱하여 946이 나왔습니다. 원래대로 계산하면 얼마입니까?",
        "question_en": "I had to divide a number by 3, add 14, then multiply by 2, but I made a mistake by multiplying by 3, adding 14, then multiplying by 2 and got 946. How much is the original calculation?",
        "answer_ko": "130",
        "answer_en": "130",
        "solution_abst_ko": "946 2 [OP_DIV] 14 [OP_SUB] 3 [OP_DIV] 3 [OP_DIV] 14 [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "946 2 [OP_DIV] 14 [OP_SUB] 3 [OP_DIV] 3 [OP_DIV] 14 [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 946\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 14\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = 3\nvar_i = var_g / var_h\nvar_j = 14\nvar_k = var_i + var_j\nvar_l = 2\nvar_m = var_k * var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 946\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 14\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = var_e / var_f\nvar_h = 3\nvar_i = var_g / var_h\nvar_j = 14\nvar_k = var_i + var_j\nvar_l = 2\nvar_m = var_k * var_l\nprint(int(var_m))"
    },
    "7805": {
        "category": "Correspondence",
        "question_ko": "서로 다른 수 A, B, C가 있습니다. 3×A-A=10, B+A=12, C-B=6입니다. C를 구하시오.",
        "question_en": "There are different numbers A, B, and C. 3×A-A=10, B+A=12, C-B=6. Get C.",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "12 3×A-A=10 A [OP_NUM_UNK_SOLVER] [OP_SUB] 6 [OP_ADD]",
        "solution_abst_en": "12 3×A-A=10 A [OP_NUM_UNK_SOLVER] [OP_SUB] 6 [OP_ADD]",
        "solution_code_ko": "var_a = 12\nvar_b = '3×A-A=10'\nvar_c = 'A'\nans_dict = dict()\nvar_b = var_b.replace('×','*')\nvar_b = var_b.replace('x','*')\nvar_b = var_b.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_b):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_b\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_d = ans_dict[var_c]\nvar_e = var_a - var_d\nvar_f = 6\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 12\nvar_b = '3×A-A=10'\nvar_c = 'A'\nans_dict = dict()\nvar_b = var_b.replace('×','*')\nvar_b = var_b.replace('x','*')\nvar_b = var_b.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_b):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandidate_num = [i for i in range(51)]\ncandi = list(itertools.product(candidate_num, repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_b\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        if term_list[i] == '':\n            new_eq += str(term_list[i])+op_list[i]\n        else:\n            new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    new_eq=new_eq.replace('=', '==')\n    new_eq=new_eq.replace('>==', '>=')\n    new_eq=new_eq.replace('<==', '<=')\n    eval_result = False\n    try:\n        if '=' in new_eq and '>' not in new_eq and '<' not in new_eq:\n            new_eq=new_eq.replace('==','=')\n            new_eq=new_eq.replace('>','')\n            new_eq=new_eq.replace('<','')\n            new_eq=new_eq.split('=')\n            for i in range(len(new_eq)-1):\n                eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1]))\n                if not eval_result:\n                    break\n        else:\n            eval_result = eval(new_eq)\n    except:\n        eval_result = False\n        pass\n    if eval_result:\n        for i, (k, _) in enumerate(ans_dict.items()):\n            ans_dict[k] = int(c[i])\nvar_d = ans_dict[var_c]\nvar_e = var_a - var_d\nvar_f = 6\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "7806": {
        "category": "Geometry",
        "question_ko": "한 원에서 지름은 반지름의 몇 배 입니까?",
        "question_en": "How many times bigger is the diameter of a circle compared to its radius?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "2",
        "solution_abst_en": "2",
        "solution_code_ko": "var_a = 2\nprint(int(var_a))",
        "solution_code_en": "var_a = 2\nprint(int(var_a))"
    },
    "7807": {
        "category": "Possibility",
        "question_ko": "달리기 시합에 참가한 태형이가 다른 모든 사람들과 악수를 한번씩 했더니 총 25번 악수를 했습니다. 이때 달리기 시험에 참가한 사람은 모두 몇명입니까?",
        "question_en": "Taehyung, who participated in the running match, shook hands with everyone else once, and he shook hands a total of 25 times. How many people participated in the running test at this time?",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "25 1 [OP_ADD]",
        "solution_abst_en": "25 1 [OP_ADD]",
        "solution_code_ko": "var_a = 25\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 25\nvar_b = 1\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "7808": {
        "category": "Comparison",
        "question_ko": "울산에 있는 공장에서 127000개의 장난감이 만들어졌습니다. 이 장난감들을 서울까지 운반하려고 할 때 5000개까지 실을 수 있는 트럭으로 운반하려면 8000개까지 실을 수 있는 트럭으로 운반할 때보다 몇 대가 더 필요합니까?",
        "question_en": "127,000 toys were made at the factory in Ulsan. How many more trucks do you need to transport these toys to Seoul by trucks with a capacity of 5000 toys than by trucks with a capacity of 8000 toys?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "127000 5000 [OP_DIV] 1 [OP_CEIL] 127000 8000 [OP_DIV] 1 [OP_CEIL] [OP_SUB]",
        "solution_abst_en": "127000 5000 [OP_DIV] 1 [OP_CEIL] 127000 8000 [OP_DIV] 1 [OP_CEIL] [OP_SUB]",
        "solution_code_ko": "var_a = 127000\nvar_b = 5000\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nvar_f = 127000\nvar_g = 8000\nvar_h = var_f / var_g\nvar_i = 1\nvar_j=int(((var_h+9*10**(var_i-2))//(10**(var_i-1)))*10**(var_i-1))\n\nvar_k = var_e - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 127000\nvar_b = 5000\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nvar_f = 127000\nvar_g = 8000\nvar_h = var_f / var_g\nvar_i = 1\nvar_j=int(((var_h+9*10**(var_i-2))//(10**(var_i-1)))*10**(var_i-1))\n\nvar_k = var_e - var_j\nprint(int(var_k))"
    },
    "7809": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 100까지의 홀수 중 가장 큰 수와 가장 작은 수의 차를 구하시오.",
        "question_en": "Find the difference between the largest and smallest odd numbers from 1 to 100.",
        "answer_ko": "98",
        "answer_en": "98",
        "solution_abst_ko": "1 100 [OP_LIST_ODD] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "1 100 [OP_LIST_ODD] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 1\nvar_b = 100\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[-var_c]\nvar_e = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = var_d - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 100\nlist_a = []\nif var_a%2==0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 1\nlist_b=list_a.copy()\nlist_b.sort()\nvar_d = list_b[-var_c]\nvar_e = 1\nlist_c=list_a.copy()\nlist_c.sort()\nvar_f = list_c[var_e-1]\nvar_g = var_d - var_f\nprint(int(var_g))"
    },
    "7810": {
        "category": "Correspondence",
        "question_ko": "36에 어떤 수를 빼야 할 것을 잘못하여 7에 어떤 수를 곱했더니 70이 되었습니다. 바르게 계산하면 얼마인지 구하시오.",
        "question_en": "I made the mistake of multiplying 7 by a number, which was supposed to be the subtraction of 36 and a number, so I got 70. Find the correctly calculated answer.",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "36 70 7 [OP_DIV] [OP_SUB]",
        "solution_abst_en": "36 70 7 [OP_DIV] [OP_SUB]",
        "solution_code_ko": "var_a = 36\nvar_b = 70\nvar_c = 7\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 36\nvar_b = 70\nvar_c = 7\nvar_d = var_b / var_c\nvar_e = var_a - var_d\nprint(int(var_e))"
    },
    "7811": {
        "category": "Comparison",
        "question_ko": "윤기는 7, 정국은 6, 유나는 9, 유정은 8, 태형은 10만큼 모았습니다. 누가 모은 숫자가 가장 큽니까?",
        "question_en": "Yoongi collected 7 points, Jungkook 6 points, Yuna 9 points, Yoojung 8 points, and Taehyung 10 points. Who collected the largest number?",
        "answer_ko": "태형",
        "answer_en": "Taehyung",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 유나 유정 태형 [OP_LIST_EOL] [OP_LIST_SOL] 7 6 9 8 10 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook Yuna Yoojung Taehyung [OP_LIST_EOL] [OP_LIST_SOL] 7 6 9 8 10 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nvar_c = '유나'\nvar_d = '유정'\nvar_e = '태형'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 7\nvar_g = 6\nvar_h = 9\nvar_i = 8\nvar_j = 10\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nvar_c = 'Yuna'\nvar_d = 'Yoojung'\nvar_e = 'Taehyung'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 7\nvar_g = 6\nvar_h = 9\nvar_i = 8\nvar_j = 10\nlist_b= []\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nlist_b.reverse()\nvar_k = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_l = list_c[-var_k]\nvar_m = list_b.index(var_l)+1\nvar_n = list_a[var_m-1]\nprint(var_n)"
    },
    "7812": {
        "category": "Correspondence",
        "question_ko": "윤기가 어떤 수에서 7을 빼 9를 얻었습니다. 이제 어떤 수에 3을 곱하고자 합니다. 이 결과값을 구하시오.",
        "question_en": "Yoongi subtracted 7 from a particular number and got 9. Now we want to multiply that particular number by 5. What will be the result then?",
        "answer_ko": "80",
        "answer_en": "80",
        "solution_abst_ko": "9 7 [OP_ADD] 5 [OP_MUL]",
        "solution_abst_en": "9 7 [OP_ADD] 5 [OP_MUL]",
        "solution_code_ko": "var_a = 9\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 5\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "7813": {
        "category": "Geometry",
        "question_ko": "이등변삼각형의 둘레의 길이를 구하고 싶습니다. 이등변삼각형의 양변의 길이는 12 센티미터(㎝)이며 다른 변의 길이는 17 센티미터(㎝)일 때, 둘레는 몇 센티미터(㎝)일까요?",
        "question_en": "You want to find the perimeter of an isosceles triangle. If the length of each side of an isosceles triangle is 12 centimeters (cm) and the length of the other side is 17 centimeters (cm), what is the perimeter in centimeters (cm)?",
        "answer_ko": "41",
        "answer_en": "41",
        "solution_abst_ko": "12 2 [OP_MUL] 17 [OP_ADD]",
        "solution_abst_en": "12 2 [OP_MUL] 17 [OP_ADD]",
        "solution_code_ko": "var_a = 12\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 17\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 17\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7814": {
        "category": "Arithmetic calculation",
        "question_ko": "일주일동안 리본 161개를 만들려고 합니다. 하루에 평균 몇 개의 리본을 만들어야 합니까?",
        "question_en": "I'm trying to make 161 ribbons in one week. How many ribbons do I need to make on average per day?",
        "answer_ko": "23",
        "answer_en": "23",
        "solution_abst_ko": "161 7 [OP_DIV]",
        "solution_abst_en": "161 7 [OP_DIV]",
        "solution_code_ko": "var_a = 161\nvar_b = 7\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 161\nvar_b = 7\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "7815": {
        "category": "Possibility",
        "question_ko": "1, 4, 5을 한 번씩 모두 사용하여 만들 수 있는 가장 큰 수를 구하시오.",
        "question_en": "Find the largest number that can be formed by using 1, 4, and 5 all once.",
        "answer_ko": "541",
        "answer_en": "541",
        "solution_abst_ko": "[OP_LIST_SOL] 1 4 5 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1 4 5 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1\nvar_b = 4\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 4\nvar_c = 5\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))"
    },
    "7816": {
        "category": "Geometry",
        "question_ko": "빗변의 길이가 15센티미터(㎝), 밑변의 길이가 9센티미터(㎝)인 삼각형의 넓이는?",
        "question_en": "What is the area of a triangle whose hypotenuse is 15 centimeters (cm) and the base is 9 centimeters (cm)?",
        "answer_ko": "54",
        "answer_en": "54",
        "solution_abst_ko": "15 2 [OP_POW] 9 2 [OP_POW] [OP_SUB] 1/2 [OP_POW] 9 [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "15 2 [OP_POW] 9 2 [OP_POW] [OP_SUB] 1/2 [OP_POW] 9 [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 15\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 9\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c - var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nvar_j = 9\nvar_k = var_i * var_j\nvar_l = 2\nvar_m = var_k / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 15\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 9\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c - var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nvar_j = 9\nvar_k = var_i * var_j\nvar_l = 2\nvar_m = var_k / var_l\nprint(int(var_m))"
    },
    "7817": {
        "category": "Correspondence",
        "question_ko": "0부터 9까지 A에 들어갈 수 있습니다. 백의 자리에서 반올림하면 63000이 되는 다섯 자리 수 62A94가 있을 때 A에 들어갈 수 있는 수들의 합을 구하시오.",
        "question_en": "A can be 0 to 9. Given the five-digit number 62A94, which, when rounded to the thousands place, is 63000, find the sum of the numbers that can fit in A.",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "62A94 [OP_GEN_POSSIBLE_LIST] 62500 [OP_LIST_MORE_EQUAL] 62A94 A [OP_LIST_FIND_UNK] [OP_LIST_SUM]",
        "solution_abst_en": "62A94 [OP_GEN_POSSIBLE_LIST] 62500 [OP_LIST_MORE_EQUAL] 62A94 A [OP_LIST_FIND_UNK] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = '62A94'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 62500\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = '62A94'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nlist_c = [float(i) for i in list_c]\nvar_e = sum(list_c)\nprint(int(var_e))",
        "solution_code_en": "var_a = '62A94'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 62500\nlist_b = []\nfor i in list_a:\n    if i >= var_b:\n        list_b.append(i)\nvar_c = '62A94'\nvar_d = 'A'\nvar_c = str(var_c)\nvar_d = str(var_d)\nunk_idx = var_c.index(var_d)\nlist_c = []\nfor elem in list_b:\n    elem = str(elem)\n    list_c.append(int(elem[unk_idx]))\nlist_c = list(set(list_c))\nlist_c = [float(i) for i in list_c]\nvar_e = sum(list_c)\nprint(int(var_e))"
    },
    "7818": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 365까지의 수 중에서 세 자리 수는 모두 몇 개인지 구하시오.",
        "question_en": "How many three-digit numbers are there in the numbers from 1 to 365?",
        "answer_ko": "365",
        "answer_en": "365",
        "solution_abst_ko": "1 365 1 [OP_LIST_ARANGE] 100 [OP_LIS_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "1 365 1 [OP_LIST_ARANGE] 100 [OP_LIS_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 365\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 100\nvar_e = '[OP_LIS_MORE_EQUAL]'\nvar_f = len(list_a)\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 365\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 100\nvar_e = '[OP_LIS_MORE_EQUAL]'\nvar_f = len(list_a)\nprint(int(var_f))"
    },
    "7819": {
        "category": "Possibility",
        "question_ko": "9, 4, 2, 5 중에서 서로 다른 숫자 2개를 뽑아 만들 수 있는 두 자리 수 중 가장 큰 수에서 가장 작은 수를 뺀 값을 구하시오.",
        "question_en": "Find the value of subtracting the smallest two-digit number from the largest two-digit number that can be formed by drawing two different numbers from 9, 4, 2, and 5.",
        "answer_ko": "71",
        "answer_en": "71",
        "solution_abst_ko": "[OP_LIST_SOL] 9 4 2 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_abst_en": "[OP_LIST_SOL] 9 4 2 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]",
        "solution_code_ko": "var_a = 9\nvar_b = 4\nvar_c = 2\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 9\nvar_b = 4\nvar_c = 2\nvar_d = 5\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 1\nlist_d=list_b.copy()\nlist_d.sort()\nvar_i = list_d[var_h-1]\nvar_j = var_g - var_i\nprint(int(var_j))"
    },
    "7820": {
        "category": "Arithmetic calculation",
        "question_ko": "두 자리 수의 뺄셈에서 빼어지는 수의 일의 자리 숫자 8을 다른 수로 잘못 보고, 빼는 수의 십의 자리 숫자 7을 다른 수로 잘못 보고 계산하였을 때 62가 되었습니다. 잘못 본 수가 각각 5와 2였다면, 바르게 계산한 결과를 구하시오.",
        "question_en": "In two-digit subtraction, 62 was obtained by incorrectly misrepresenting 8 in the ones digit of the number being subtracted as another number and incorrectly misrepresenting 7 in the tens digit of the subtracting number as another number. If the numbers incorrectly misrepresented were 5 and 2, respectively, find the result of the correct calculation.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "62 1 8 5 [OP_SUB] [OP_MUL] [OP_ADD] 10 7 2 [OP_SUB] [OP_MUL] [OP_SUB]",
        "solution_abst_en": "62 1 8 5 [OP_SUB] [OP_MUL] [OP_ADD] 10 7 2 [OP_SUB] [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 62\nvar_b = 1\nvar_c = 8\nvar_d = 5\nvar_e = var_c - var_d\nvar_f = var_b * var_e\nvar_g = var_a + var_f\nvar_h = 10\nvar_i = 7\nvar_j = 2\nvar_k = var_i - var_j\nvar_l = var_h * var_k\nvar_m = var_g - var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 62\nvar_b = 1\nvar_c = 8\nvar_d = 5\nvar_e = var_c - var_d\nvar_f = var_b * var_e\nvar_g = var_a + var_f\nvar_h = 10\nvar_i = 7\nvar_j = 2\nvar_k = var_i - var_j\nvar_l = var_h * var_k\nvar_m = var_g - var_l\nprint(int(var_m))"
    },
    "7821": {
        "category": "Possibility",
        "question_ko": "자연수 1, 2, 3만으로 이루어진 네 자리 수들의 합은 얼마인가?",
        "question_en": "What is the sum of four digit numbers made up of only the natural numbers 1, 2, and 3?",
        "answer_ko": "179982",
        "answer_en": "179982",
        "solution_abst_ko": "[OP_LIST_SOL] 1 2 3 [OP_LIST_EOL] 4 [OP_LIST_GET_PRODUCT] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 1 2 3 [OP_LIST_EOL] 4 [OP_LIST_GET_PRODUCT] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 2\nvar_c = 3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 1\nvar_b = 2\nvar_c = 3\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint(int(var_e))"
    },
    "7822": {
        "category": "Geometry",
        "question_ko": "긴 변의 길이가 1미터(m)이고, 긴 변의 길이가 짧은 변의 길이보다 2/8미터(m)만큼 긴 직사각형의 네 변의 길이의 합은 몇 미터(m)인가요?",
        "question_en": "What is the sum of the lengths in meters (m) of the four sides of a rectangle whose longer side is 1 meter (m) and whose longer side is 2/8 meter (m) longer than its shorter side?",
        "answer_ko": "3.50",
        "answer_en": "3.5",
        "solution_abst_ko": "1 1 2/8 [OP_SUB] [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "1 1 2/8 [OP_SUB] [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 1\nvar_b = 1\nvar_c = 0.25\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 1\nvar_b = 1\nvar_c = 0.25\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nvar_f = 2\nvar_g = var_e * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "7823": {
        "category": "Correspondence",
        "question_ko": "준우네 학교에서 23개의 반에 37개의 구슬을 나눠 주고 16개가 남았다고 한다. 준우네 학교에서 학생들에게 나눠준 구슬의 개수는 모두 몇 개인가?",
        "question_en": "At Junwoo's school, 37 marbles each were distributed to 23 classes, and there are 16 left. How many marbles were distributed to students at Junwoo's school?",
        "answer_ko": "867",
        "answer_en": "867",
        "solution_abst_ko": "23 37 [OP_MUL] 16 [OP_ADD]",
        "solution_abst_en": "23 37 [OP_MUL] 16 [OP_ADD]",
        "solution_code_ko": "var_a = 23\nvar_b = 37\nvar_c = var_a * var_b\nvar_d = 16\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 23\nvar_b = 37\nvar_c = var_a * var_b\nvar_d = 16\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7824": {
        "category": "Geometry",
        "question_ko": "이등변삼각형에서, 양변의 길이는 12 센티미터(㎝)이며 다른 변의 길이는 17 센티미터(㎝)라고 합니다. 이 때, 둘레의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "In an isosceles triangle, two sides are said to be 12 centimeters (cm) long, and the other side is said to be 17 centimeters (cm) long. At this time, how many centimeters (cm) is the length of the perimeter?",
        "answer_ko": "41",
        "answer_en": "41",
        "solution_abst_ko": "12 2 [OP_MUL] 17 [OP_ADD]",
        "solution_abst_en": "12 2 [OP_MUL] 17 [OP_ADD]",
        "solution_code_ko": "var_a = 12\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 17\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 17\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7825": {
        "category": "Correspondence",
        "question_ko": "2AB+36=269입니다. B는 얼마인가요?",
        "question_en": "2AB+36=269 is true. How much is B?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "2AB+36=269 B [OP_DIGIT_UNK_SOLVER]",
        "solution_abst_en": "2AB+36=269 B [OP_DIGIT_UNK_SOLVER]",
        "solution_code_ko": "var_a = '2AB+36=269'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))",
        "solution_code_en": "var_a = '2AB+36=269'\nvar_b = 'B'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 1\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k] = int(c[i])\nvar_c = ans_dict[var_b]\nprint(int(var_c))"
    },
    "7826": {
        "category": "Comparison",
        "question_ko": "국어사전에서 감, 바나나, 참외 3개의 단어를 찾으려고 한다. 감이 바나나보다 먼저 나오고 바나나가 참외보다 먼저 나온다. 사전에서 가장 나중에 나오는 단어는 무엇인지 구하시오.",
        "question_en": "I am trying to find three words persimmon, banana, and melon in the Korean dictionary. Persimmon comes out before banana, and banana comes out before melon. Find the word that comes out the last in the dictionary.",
        "answer_ko": "참외",
        "answer_en": "melon",
        "solution_abst_ko": "[OP_LIST_SOL] 감 바나나 참외 [OP_LIST_EOL] [OP_LIST_SOL] 감 바나나 < 바나나 참외 < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] persimmon banana melon [OP_LIST_EOL] [OP_LIST_SOL] persimmon banana < banana melon < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = '감'\nvar_b = '바나나'\nvar_c = '참외'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '감'\nvar_e = '바나나'\nvar_f = '<'\nvar_g = '바나나'\nvar_h = '참외'\nvar_i = '<'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(var_k)",
        "solution_code_en": "var_a = 'persimmon'\nvar_b = 'banana'\nvar_c = 'melon'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'persimmon'\nvar_e = 'banana'\nvar_f = '<'\nvar_g = 'banana'\nvar_h = 'melon'\nvar_i = '<'\nlist_b= []\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(var_k)"
    },
    "7827": {
        "category": "Correspondence",
        "question_ko": "세 자리 수 중 각 자리의 수가 모두 다르고 각 자리수의 합이 9인 수는 모두 몇 개입니까?",
        "question_en": "How many 3-digit numbers are there where each digit is different and the sum of the digits is 9?",
        "answer_ko": "34",
        "answer_en": "34",
        "solution_abst_ko": "0 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 9 [OP_LIST_MORE_EQUAL] 9 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "0 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 9 [OP_LIST_MORE_EQUAL] 9 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 9\nlist_d = []\nfor i in list_c:\n    if i >= var_f:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nfor i in list_d:\n    if i <= var_g:\n        list_e.append(i)\nvar_h = len(list_e)\nprint(int(var_h))",
        "solution_code_en": "var_a = 0\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nlist_c=[]\nfor i in list_b:\n    var_e = 0\n    i = int(i)\n    while i//10 > 0:\n        var_e = var_e + i%10\n        i = i//10\n    var_e = var_e + i%10\n    list_c.append(var_e)\nvar_f = 9\nlist_d = []\nfor i in list_c:\n    if i >= var_f:\n        list_d.append(i)\nvar_g = 9\nlist_e = []\nfor i in list_d:\n    if i <= var_g:\n        list_e.append(i)\nvar_h = len(list_e)\nprint(int(var_h))"
    },
    "7828": {
        "category": "Geometry",
        "question_ko": "한변의 길이가 2센티미터(㎝)인 정사면체의 겉넓이는?",
        "question_en": "What is the surface area of a regular tetrahedron with a side of 2 centimeters (cm)?",
        "answer_ko": "6.93",
        "answer_en": "6.93",
        "solution_abst_ko": "3 1/2 [OP_POW] 2 2 [OP_POW] [OP_MUL]",
        "solution_abst_en": "3 1/2 [OP_POW] 2 2 [OP_POW] [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 0.5\nvar_c = var_a ** var_b\nvar_d = 2\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 3\nvar_b = 0.5\nvar_c = var_a ** var_b\nvar_d = 2\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "7829": {
        "category": "Correspondence",
        "question_ko": "어떤 수는 18보다 작지만 3의 배수가 아닙니다. 12, 14, 15, 20 중에서 어떤 수를 구하시오.",
        "question_en": "There is a number that is less than 18 but not a multiple of 3. Which number is it out of 12, 14, 15, or 20?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "[OP_LIST_SOL] 12 14 15 20 [OP_LIST_EOL] 3 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] 18 [OP_LIST_LESS] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] 12 14 15 20 [OP_LIST_EOL] 3 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] 18 [OP_LIST_LESS] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 12\nvar_b = 14\nvar_c = 15\nvar_d = 20\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = []\nvar_e = int(var_e)\nfor i in list_a:\n    i = int(i)\n    if i % var_e == 0:\n        list_b.append(i)\nlist_c = list(set(list_a) - set(list_b))\nvar_f = 18\nlist_d = []\nfor i in list_c:\n    if i < var_f:\n        list_d.append(i)\nvar_g = 1\nvar_h = list_d[var_g-1]\nprint(int(var_h))",
        "solution_code_en": "var_a = 12\nvar_b = 14\nvar_c = 15\nvar_d = 20\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = []\nvar_e = int(var_e)\nfor i in list_a:\n    i = int(i)\n    if i % var_e == 0:\n        list_b.append(i)\nlist_c = list(set(list_a) - set(list_b))\nvar_f = 18\nlist_d = []\nfor i in list_c:\n    if i < var_f:\n        list_d.append(i)\nvar_g = 1\nvar_h = list_d[var_g-1]\nprint(int(var_h))"
    },
    "7830": {
        "category": "Arithmetic calculation",
        "question_ko": "상우는 1부터 9까지 적힌 9장의 카드 중 3장을 뽑고, 그 숫자들을 모두 써서 세 번째로 큰 세 자리수를 만들고자 한다. 상우가 1, 6, 8을 뽑았을 때 만들어야 하는 수는?",
        "question_en": "Sangwoo draws 3 out of 9 cards numbered 1 through 9 and wants to use all of them to create the third largest three-digit number. When he drew 1, 6, and 8, what number should Sangwoo make?",
        "answer_ko": "681",
        "answer_en": "681",
        "solution_abst_ko": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 3 [OP_LIST_MAX]",
        "solution_abst_en": "[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 3 [OP_LIST_MAX]",
        "solution_code_ko": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 6\nvar_c = 8\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = len(list_a)\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nprint(int(var_f))"
    },
    "7831": {
        "category": "Geometry",
        "question_ko": "컴퍼스를 몇 센티미터(㎝) 벌려야 지름이 14 센티미터(㎝)인 원을 그릴 수 있을까요?",
        "question_en": "How many centimeters (cm) must the compass be spread out to draw a circle with a diameter of 14 centimeters (cm)?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "14 2 [OP_DIV]",
        "solution_abst_en": "14 2 [OP_DIV]",
        "solution_code_ko": "var_a = 14\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 14\nvar_b = 2\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "7832": {
        "category": "Arithmetic calculation",
        "question_ko": "연속하는 7개의 자연수의 합이 63입니다 첫번째 수를 구하시오",
        "question_en": "The sum of 7 consecutive natural numbers is 63 Find the first number",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "63 0 7 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 7 [OP_DIV]",
        "solution_abst_en": "63 0 7 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 7 [OP_DIV]",
        "solution_code_ko": "var_a = 63\nvar_b = 0\nvar_c = 7\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nlist_a = [i for i in range(var_b, var_e + 1, var_f)]\nlist_a = [float(i) for i in list_a]\nvar_g = sum(list_a)\nvar_h = var_a - var_g\nvar_i = 7\nvar_j = var_h / var_i\nprint(int(var_j))",
        "solution_code_en": "var_a = 63\nvar_b = 0\nvar_c = 7\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 1\nlist_a = [i for i in range(var_b, var_e + 1, var_f)]\nlist_a = [float(i) for i in list_a]\nvar_g = sum(list_a)\nvar_h = var_a - var_g\nvar_i = 7\nvar_j = var_h / var_i\nprint(int(var_j))"
    },
    "7833": {
        "category": "Arithmetic calculation",
        "question_ko": "어떤 수의 7배는 어떤 수의 4배에 12를 더하고 6을 더한 값과 같다. 어떤 수를 구하시오.",
        "question_en": "7 times a certain number is equal to 4 times the certain number plus 12 plus 6. Find the certain number.",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "12 6 [OP_ADD] 7 4 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "12 6 [OP_ADD] 7 4 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 7\nvar_e = 4\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 12\nvar_b = 6\nvar_c = var_a + var_b\nvar_d = 7\nvar_e = 4\nvar_f = var_d - var_e\nvar_g = var_c / var_f\nprint(int(var_g))"
    },
    "7834": {
        "category": "Geometry",
        "question_ko": "한 변의 길이가 8센티미터(㎝)인 삼각형의 넓이는 36제곱센티미터(㎠)라고 합니다. 길이가 8센티미터(㎝)인 변과 이 변과 마주보는 꼭짓점까지의 거리는 몇 센티미터(㎝)일지 구하시오.",
        "question_en": "The area of a triangle with a side length of 8 centimeters (cm) is 36 square centimeters (cm2). Find the distance in centimeters (cm) from a side of length 8 centimeters (cm) to the vertex opposite the side.",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "36 2 [OP_MUL] 8 [OP_DIV]",
        "solution_abst_en": "36 2 [OP_MUL] 8 [OP_DIV]",
        "solution_code_ko": "var_a = 36\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 36\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "7835": {
        "category": "Geometry",
        "question_ko": "한 정구각형의 둘레는 171센티미터(㎝)입니다. 이 도형의 한 변 길이를 구하시오.",
        "question_en": "The perimeter of a regular nonagon is 171 centimeters (cm). Find the length of one side of this figure.",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "171 9 [OP_DIV]",
        "solution_abst_en": "171 9 [OP_DIV]",
        "solution_code_ko": "var_a = 171\nvar_b = 9\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 171\nvar_b = 9\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "7836": {
        "category": "Comparison",
        "question_ko": "운동장에 앉아있는 학생들 중 유정이는 오른쪽에서 12번째, 왼쪽에서 11번째, 뒤에서 18번째, 앞에서 8번째 줄에 앉아있습니다. 각 줄의 학생 수가 같을 때, 운동장에 앉아있는 학생은 모두 몇 명입니까",
        "question_en": "Among the students sitting on the playground, Yujeong is 12th from the right, 11th from the left, 18th from the back, and 8th from the front. If the number of students in each row is the same, how many students are sitting on the playground?",
        "answer_ko": "550",
        "answer_en": "550",
        "solution_abst_ko": "12 11 [OP_ADD] 1 [OP_SUB] 18 8 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_abst_en": "12 11 [OP_ADD] 1 [OP_SUB] 18 8 [OP_ADD] 1 [OP_SUB] [OP_MUL]",
        "solution_code_ko": "var_a = 12\nvar_b = 11\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 18\nvar_g = 8\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 12\nvar_b = 11\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c - var_d\nvar_f = 18\nvar_g = 8\nvar_h = var_f + var_g\nvar_i = 1\nvar_j = var_h - var_i\nvar_k = var_e * var_j\nprint(int(var_k))"
    },
    "7837": {
        "category": "Arithmetic calculation",
        "question_ko": "예리는 가게에서 120 원짜리 사탕 5 개와 350 원짜리 초콜릿을 3 개 사고 2500 원을 냈습니다. 예리는 거스름돈으로 얼마를 받아야 합니까?",
        "question_en": "Yeri bought 5 candies that cost 120 won each and 3 chocolates that cost 350 won each and handed over 2500 won at the store. How much should Yeri get in change?",
        "answer_ko": "850",
        "answer_en": "850",
        "solution_abst_ko": "2500 120 5 [OP_MUL] 350 3 [OP_MUL] [OP_ADD] [OP_SUB]",
        "solution_abst_en": "2500 120 5 [OP_MUL] 350 3 [OP_MUL] [OP_ADD] [OP_SUB]",
        "solution_code_ko": "var_a = 2500\nvar_b = 120\nvar_c = 5\nvar_d = var_b * var_c\nvar_e = 350\nvar_f = 3\nvar_g = var_e * var_f\nvar_h = var_d + var_g\nvar_i = var_a - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 2500\nvar_b = 120\nvar_c = 5\nvar_d = var_b * var_c\nvar_e = 350\nvar_f = 3\nvar_g = var_e * var_f\nvar_h = var_d + var_g\nvar_i = var_a - var_h\nprint(int(var_i))"
    },
    "7838": {
        "category": "Geometry",
        "question_ko": "넓이가 24제곱센티미터(㎠)인 평행사변형의 밑변이 4센티미터(㎝)일 때, 높이와 밑변의 길이의 차를 구하시오.",
        "question_en": "If the base of a parallelogram that has an area of 24 square centimeters (cm2) is 4 centimeters (cm), find the difference between the height and the length of the base.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "24 4 [OP_DIV] 4 [OP_SUB] [OP_ABS]",
        "solution_abst_en": "24 4 [OP_DIV] 4 [OP_SUB] [OP_ABS]",
        "solution_code_ko": "var_a = 24\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = var_c - var_d\nvar_f = abs(var_e)\nprint(int(var_f))",
        "solution_code_en": "var_a = 24\nvar_b = 4\nvar_c = var_a / var_b\nvar_d = 4\nvar_e = var_c - var_d\nvar_f = abs(var_e)\nprint(int(var_f))"
    },
    "7839": {
        "category": "Arithmetic calculation",
        "question_ko": "100 이하의 3의 배수인 자연수를 나열했을 때 3은 몇 번 등장합니까?",
        "question_en": "How many times does 3 appear in a list of natural numbers less than or equal to 100 that are multiples of 3?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "1 100 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] [OP_LIST2NUM] [OP_NUM2LIST] 3 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 100 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] [OP_LIST2NUM] [OP_NUM2LIST] 3 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e=\"\"\nfor i in list_b:\n    i = str(i)\n    var_e = var_e + i\nlist_c = []\nvar_e = int(var_e)\nwhile var_e//10 > 0:\n    list_c.append(var_e%10)\n    var_e = var_e//10\nlist_c.append(var_e%10)\nlist_c = list_c[::-1]\nvar_f = 3\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))",
        "solution_code_en": "var_a = 1\nvar_b = 100\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 3\nlist_b = []\nvar_d = int(var_d)\nfor i in list_a:\n    i = int(i)\n    if i % var_d == 0:\n        list_b.append(i)\nvar_e=\"\"\nfor i in list_b:\n    i = str(i)\n    var_e = var_e + i\nlist_c = []\nvar_e = int(var_e)\nwhile var_e//10 > 0:\n    list_c.append(var_e%10)\n    var_e = var_e//10\nlist_c.append(var_e%10)\nlist_c = list_c[::-1]\nvar_f = 3\nvar_g = 0\nvar_f = int(var_f)\nfor i in list_c:\n    i = int(i)\n    if i == var_f:\n        var_g = var_g + 1\nprint(int(var_g))"
    },
    "7840": {
        "category": "Geometry",
        "question_ko": "어떤 정육면체 (가)의 각 꼭짓점에서 한 모서리의 길이가 2센티미터(㎝)인 정육면체 모양을 잘라냈다. (가) 정육면체의 한 모서리의 길이가 8센티미터(㎝)라면, 잘라내고 남은 부분의 부분의 겉넓이는 얼마입니까?",
        "question_en": "At each vertex of a particular cube (A), a cube shape with one edge 2 centimeters (cm) long was cut out. If the length of one edge of cube (A) is 8 centimeters (cm), what is the surface area of the remaining portion of the initial cube?",
        "answer_ko": "384",
        "answer_en": "384",
        "solution_abst_ko": "8 8 [OP_MUL] 6 [OP_MUL]",
        "solution_abst_en": "8 8 [OP_MUL] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 8\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "7841": {
        "category": "Geometry",
        "question_ko": "길이가 12센티미터(㎝)인 끈을 절반으로 자르고, 잘린 끈 중 하나를 골라 다시 절반으로 잘랐다면, 현재 가장 짧은 끈의 길이는 몇 센티미터(㎝)인지 구하시오.",
        "question_en": "If you cut a piece of string that is 12 centimeters (cm) in half, choose one of the cut pieces and cut it in half again, find the length in centimeters (cm) of the current shortest piece of string.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "12 2 [OP_DIV] 2 [OP_DIV]",
        "solution_abst_en": "12 2 [OP_DIV] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 12\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 12\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "7842": {
        "category": "Comparison",
        "question_ko": "0.8, 1/2, 0.9 중에서 0.4보다 크거나 같은 수는 몇 개입니까?",
        "question_en": "How many numbers among 0.8, 1/2, and 0.9 are greater than or equal to 0.4?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 0.4 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 0.4 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.4\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.9\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.4\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nvar_e = len(list_b)\nprint(int(var_e))"
    },
    "7843": {
        "category": "Arithmetic calculation",
        "question_ko": "8%의 설탕물 300그램(g)에 물을 부었더니 5%의 설탕물이 되었습니다. 물을 몇 그램(g) 부었습니까?",
        "question_en": "When water was poured into 300 grams (g) of 8% sugar water, it became 5% sugar water. How many grams (g) of water did you pour in?",
        "answer_ko": "180",
        "answer_en": "180",
        "solution_abst_ko": "300 8 100 [OP_DIV] [OP_MUL] 100 5 [OP_DIV] [OP_MUL] 300 [OP_SUB]",
        "solution_abst_en": "300 8 100 [OP_DIV] [OP_MUL] 100 5 [OP_DIV] [OP_MUL] 300 [OP_SUB]",
        "solution_code_ko": "var_a = 300\nvar_b = 8\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 100\nvar_g = 5\nvar_h = var_f / var_g\nvar_i = var_e * var_h\nvar_j = 300\nvar_k = var_i - var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 300\nvar_b = 8\nvar_c = 100\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 100\nvar_g = 5\nvar_h = var_f / var_g\nvar_i = var_e * var_h\nvar_j = 300\nvar_k = var_i - var_j\nprint(int(var_k))"
    },
    "7844": {
        "category": "Arithmetic calculation",
        "question_ko": "집에서 은행까지 갈 때는 직선거리를 시속 2킬로미터(㎞)로, 은행에서 집으로 올때는 2킬로미터(㎞) 더 먼 길을 시속 3킬로미터(㎞)로 걸어왔다. 총 걸린시간이 4시간이라면 은행에서 집으로 오는 거리는 얼마입니까?",
        "question_en": "When I went to the bank from my house, I walked a straight line at 2 kilometers (km) per hour, and when I went home from the bank, I walked 2 kilometers (km) further at 3 kilometers (km) per hour. If it took 4 hours in total, how far is it from the bank to the house?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "2 4 [OP_MUL] 3 [OP_MUL] 4 [OP_SUB] 3 2 [OP_ADD] [OP_DIV] 2 [OP_ADD]",
        "solution_abst_en": "2 4 [OP_MUL] 3 [OP_MUL] 4 [OP_SUB] 3 2 [OP_ADD] [OP_DIV] 2 [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e - var_f\nvar_h = 3\nvar_i = 2\nvar_j = var_h + var_i\nvar_k = var_g / var_j\nvar_l = 2\nvar_m = var_k + var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c * var_d\nvar_f = 4\nvar_g = var_e - var_f\nvar_h = 3\nvar_i = 2\nvar_j = var_h + var_i\nvar_k = var_g / var_j\nvar_l = 2\nvar_m = var_k + var_l\nprint(int(var_m))"
    },
    "7845": {
        "category": "Arithmetic calculation",
        "question_ko": "윤기, 은지, 유나 세 사람이 책을 여러 권 가지고 있습니다. 윤기가 은지에게 5권 주고, 은지가 유나에게 10권 주고, 유나가 윤기에게 15권 주면, 세 사람은 모두 책을 45권씩 가지게 됩니다. 처음에 윤기가 가지고 있던 책은 몇 권입니까?",
        "question_en": "Yoongi, Eunji, and Yuna have several books. If Yoongi gives 5 books to Eunji, Eunji gives 10 books to Yuna, and Yuna gives 15 books to Yoongi, all three of them will have 45 books each. How many books did Yoongi have at first?",
        "answer_ko": "35",
        "answer_en": "35",
        "solution_abst_ko": "45 15 [OP_SUB] 5 [OP_ADD]",
        "solution_abst_en": "45 15 [OP_SUB] 5 [OP_ADD]",
        "solution_code_ko": "var_a = 45\nvar_b = 15\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 45\nvar_b = 15\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7846": {
        "category": "Arithmetic calculation",
        "question_ko": "첫째날에 215리터(L)의 물을, 둘째날에는 첫째날보다 76리터(L) 더 많은 물을, 마지막 날에는 둘째날 보다 53리터(L) 더 적은 물을 먹었습니다. 평균 몇 리터(L)의 물을 먹었나요?",
        "question_en": "They drank 215 liters (l) of water on the first day, 76 liters (l) more on the second day than on the first day, and 53 liters (l) less on the last day than on the second day. How many liters (l) of water did you drink on average?",
        "answer_ko": "248",
        "answer_en": "248",
        "solution_abst_ko": "215 215 76 [OP_ADD] [OP_ADD] 215 76 [OP_ADD] 53 [OP_SUB] [OP_ADD] 3 [OP_DIV]",
        "solution_abst_en": "215 215 76 [OP_ADD] [OP_ADD] 215 76 [OP_ADD] 53 [OP_SUB] [OP_ADD] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 215\nvar_b = 215\nvar_c = 76\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nvar_f = 215\nvar_g = 76\nvar_h = var_f + var_g\nvar_i = 53\nvar_j = var_h - var_i\nvar_k = var_e + var_j\nvar_l = 3\nvar_m = var_k / var_l\nprint(int(var_m))",
        "solution_code_en": "var_a = 215\nvar_b = 215\nvar_c = 76\nvar_d = var_b + var_c\nvar_e = var_a + var_d\nvar_f = 215\nvar_g = 76\nvar_h = var_f + var_g\nvar_i = 53\nvar_j = var_h - var_i\nvar_k = var_e + var_j\nvar_l = 3\nvar_m = var_k / var_l\nprint(int(var_m))"
    },
    "7847": {
        "category": "Geometry",
        "question_ko": "말이 정사각형 모양의 트랙을 따라 뛰고 있습니다. 이 트랙의 한 변의 길이가 40미터(m)일 때, 말이 한 바퀴 뛴 걸이는 몇 미터(m)입니까?",
        "question_en": "A horse is running along a square-shaped track. If the length of one side of this track is 40 meters (m), how many meters (m) does the horse take in one turn?",
        "answer_ko": "160",
        "answer_en": "160",
        "solution_abst_ko": "40 4 [OP_MUL]",
        "solution_abst_en": "40 4 [OP_MUL]",
        "solution_code_ko": "var_a = 40\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 40\nvar_b = 4\nvar_c = var_a * var_b\nprint(int(var_c))"
    },
    "7848": {
        "category": "Geometry",
        "question_ko": "칠각형이 있을 때 그릴 수 있는 모든 대각선의 개수는?",
        "question_en": "How many diagonals can you draw in a heptagon?",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "7 7 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "7 7 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 7\nvar_b = 7\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 7\nvar_b = 7\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "7849": {
        "category": "Geometry",
        "question_ko": "삼각뿔의 모서리에 개수에 삼각 기둥에 모서리의 개수를 더하시오.",
        "question_en": "Add the number of edges of the triangular pyramid to the number of edges of the triangular prism.",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "3 2 [OP_MUL] 3 3 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "3 2 [OP_MUL] 3 3 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 3\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 3\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = 3\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nprint(int(var_g))"
    },
    "7850": {
        "category": "Arithmetic calculation",
        "question_ko": "책을 펼쳤을 때 양 쪽의 쪽수 합이 217이었습니다. 각 쪽수의 곱은 얼마입니까?",
        "question_en": "When the book was opened, the sum of the pages on both sides was 217. What is the product of both of these page numbers?",
        "answer_ko": "11772",
        "answer_en": "11772",
        "solution_abst_ko": "217 2 [OP_FDIV] 217 2 [OP_FDIV] 1 [OP_ADD] [OP_MUL]",
        "solution_abst_en": "217 2 [OP_FDIV] 217 2 [OP_FDIV] 1 [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 217\nvar_b = 2\nvar_c = var_a // var_b\nvar_d = 217\nvar_e = 2\nvar_f = var_d // var_e\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = var_c * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 217\nvar_b = 2\nvar_c = var_a // var_b\nvar_d = 217\nvar_e = 2\nvar_f = var_d // var_e\nvar_g = 1\nvar_h = var_f + var_g\nvar_i = var_c * var_h\nprint(int(var_i))"
    },
    "7851": {
        "category": "Arithmetic calculation",
        "question_ko": "장미는 백합보다 22송이 많고, 튤립보다 20송이 적습니다. 세 종류의 꽃이 모두 합해서 100송이 있을때, 장미는 몇 송이 있는지 구하시오.",
        "question_en": "Roses are 22 more than lilies and 20 fewer than tulips. If there are 100 flowers of all three types, how many roses are there?",
        "answer_ko": "34",
        "answer_en": "34",
        "solution_abst_ko": "100 22 [OP_ADD] 20 [OP_SUB] 3 [OP_DIV]",
        "solution_abst_en": "100 22 [OP_ADD] 20 [OP_SUB] 3 [OP_DIV]",
        "solution_code_ko": "var_a = 100\nvar_b = 22\nvar_c = var_a + var_b\nvar_d = 20\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 100\nvar_b = 22\nvar_c = var_a + var_b\nvar_d = 20\nvar_e = var_c - var_d\nvar_f = 3\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "7852": {
        "category": "Geometry",
        "question_ko": "어떤 원의 반지름은 2센티미터(㎝)라고 합니다. 이 원의 다른 반지름은 몇 센티미터(㎝)입니까?",
        "question_en": "If you put 4 yellow balls in a box containing 3 red, 2 blue and 5 yellow balls, how many blue balls are there?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "2",
        "solution_abst_en": "2",
        "solution_code_ko": "var_a = 2\nprint(int(var_a))",
        "solution_code_en": "var_a = 2\nprint(int(var_a))"
    },
    "7853": {
        "category": "Arithmetic calculation",
        "question_ko": "가희에게 리본 테이프가 1.6미터(m) 있습니다. 리본을 만드는 데에 0.8미터(m)를 사용하고 선물을 포장하는 데에 0.3미터(m)를 사용했다면, 남은 리본 테이프는 몇 미터(m)입니까?",
        "question_en": "Kahi has a 1.6 meter (m) ribbon tape. If she used 0.8 meters (m) of ribbon to make a ribbon and 0.3 meters (m) to wrap a gift, how many meters (m) of ribbon tape is left?",
        "answer_ko": "0.50",
        "answer_en": "0.5",
        "solution_abst_ko": "1.6 0.8 [OP_SUB] 0.3 [OP_SUB]",
        "solution_abst_en": "1.6 0.8 [OP_SUB] 0.3 [OP_SUB]",
        "solution_code_ko": "var_a = 1.6\nvar_b = 0.8\nvar_c = var_a - var_b\nvar_d = 0.3\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 1.6\nvar_b = 0.8\nvar_c = var_a - var_b\nvar_d = 0.3\nvar_e = var_c - var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "7854": {
        "category": "Geometry",
        "question_ko": "현수가 마트에 가서 사탕을 집었는데 그 수가 마침 정십각형의 한 꼭짓점에서 그을 수 있는 대각선의 개수와 같았다. 현수가 집은 사탕은 몇 개인가?",
        "question_en": "Hyeonsu went to the mart and picked up candy, and the number coincided with the number of diagonals that could be drawn from one vertex of a regular decagon. How many candies did Hyeonsu pick up?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "10 3 [OP_SUB]",
        "solution_abst_en": "10 3 [OP_SUB]",
        "solution_code_ko": "var_a = 10\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 10\nvar_b = 3\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "7855": {
        "category": "Geometry",
        "question_ko": "직각삼각형의 빗변의 길이를 알고싶습니다. 빗변이 아닌 두 변이 각각 6과 8의 길이를 갖는다면 빗변의 길이는 얼마일까요?",
        "question_en": "You want to know the length of the hypotenuse of a right triangle. If the two non-hypotenuse sides have lengths of 6 and 8 respectively, what is the length of the hypotenuse?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "6 2 [OP_POW] 8 2 [OP_POW] [OP_ADD] 1/2 [OP_POW]",
        "solution_abst_en": "6 2 [OP_POW] 8 2 [OP_POW] [OP_ADD] 1/2 [OP_POW]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 8\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c + var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = var_a ** var_b\nvar_d = 8\nvar_e = 2\nvar_f = var_d ** var_e\nvar_g = var_c + var_f\nvar_h = 0.5\nvar_i = var_g ** var_h\nprint(int(var_i))"
    },
    "7856": {
        "category": "Arithmetic calculation",
        "question_ko": "한 자루에 1000원짜리 연필과 한 자루에 1300원짜리 볼펜을 합하여 12자루를 사고 15000원을 지불하였더니 거스름돈 없이 딱 맞았다. 연필은 몇 자루를 샀는지 구하시오.",
        "question_en": "You bought 12 pencils and pens in total. The pencils cost 1000 won each and the pens cost 1300 won each. You payed 15,000 won for them with no change. Find how many pencils you purchased.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "1300 12 [OP_MUL] 15000 [OP_SUB] 1300 1000 [OP_SUB] [OP_DIV]",
        "solution_abst_en": "1300 12 [OP_MUL] 15000 [OP_SUB] 1300 1000 [OP_SUB] [OP_DIV]",
        "solution_code_ko": "var_a = 1300\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 15000\nvar_e = var_c - var_d\nvar_f = 1300\nvar_g = 1000\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 1300\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 15000\nvar_e = var_c - var_d\nvar_f = 1300\nvar_g = 1000\nvar_h = var_f - var_g\nvar_i = var_e / var_h\nprint(int(var_i))"
    },
    "7857": {
        "category": "Arithmetic calculation",
        "question_ko": "반죽 10.4킬로그램(㎏)이 있습니다. 태형이는 이 반죽을 0.8킬로그램(㎏)씩 봉투에 소분하여 보관하려고 합니다. 이 때 필요한 봉투는 몇 개인지 구하세요.",
        "question_en": "You have 10.4 kilograms (kg) of dough. Taehyung wants to subdivide this dough into bags by 0.8 kilograms (kg) and store them. Find out how many envelopes he needs at this time.",
        "answer_ko": "13",
        "answer_en": "13",
        "solution_abst_ko": "10.4 0.8 [OP_DIV] 1 [OP_CEIL]",
        "solution_abst_en": "10.4 0.8 [OP_DIV] 1 [OP_CEIL]",
        "solution_code_ko": "var_a = 10.4\nvar_b = 0.8\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))",
        "solution_code_en": "var_a = 10.4\nvar_b = 0.8\nvar_c = var_a / var_b\nvar_d = 1\nvar_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))\n\nprint(int(var_e))"
    },
    "7858": {
        "category": "Arithmetic calculation",
        "question_ko": "정혁이네 집에서 할머니 댁까지의 거리는 100킬로미터(㎞)이고, 버스를 타고 1시간 15분이 걸려 도착했습니다. 1시간 동안 간 평균 거리는 얼마입니까?",
        "question_en": "The distance from Jeonghyeok's house to my grandmother's house is 100 kilometers (km), and it took 1 hour and 15 minutes to arrive by bus. What is the average distance traveled in 1 hour?",
        "answer_ko": "80",
        "answer_en": "80",
        "solution_abst_ko": "100 1 15 60 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_abst_en": "100 1 15 60 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 100\nvar_b = 1\nvar_c = 15\nvar_d = 60\nvar_e = var_c / var_d\nvar_f = var_b + var_e\nvar_g = var_a / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 100\nvar_b = 1\nvar_c = 15\nvar_d = 60\nvar_e = var_c / var_d\nvar_f = var_b + var_e\nvar_g = var_a / var_f\nprint(int(var_g))"
    },
    "7859": {
        "category": "Geometry",
        "question_ko": "사면체에서 면의 수를 구하시오.",
        "question_en": "Jungkook has 5 red balls, 4 blue balls, and 3 yellow balls. When Yoongi gives Jungkook 1 yellow ball, how many blue balls does Jungkook have?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "4",
        "solution_abst_en": "4",
        "solution_code_ko": "var_a = 4\nprint(int(var_a))",
        "solution_code_en": "var_a = 4\nprint(int(var_a))"
    },
    "7860": {
        "category": "Arithmetic calculation",
        "question_ko": "마트에 사과가 24개 있습니다. 사과 수의 6배 만큼 귤이 있고, 감은 8개 있습니다. 귤의 수는 감의 수의 몇 배입니까?",
        "question_en": "There are 24 apples in the supermarket. There are 6 times as many tangerines as there are apples, and 8 persimmons. How many times the number of tangerines is the number of persimmons?",
        "answer_ko": "18",
        "answer_en": "18",
        "solution_abst_ko": "24 6 [OP_MUL] 8 [OP_DIV]",
        "solution_abst_en": "24 6 [OP_MUL] 8 [OP_DIV]",
        "solution_code_ko": "var_a = 24\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 24\nvar_b = 6\nvar_c = var_a * var_b\nvar_d = 8\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "7861": {
        "category": "Correspondence",
        "question_ko": "20, 23, 26, 29 중에서 24와 28 사이의 수를 구하시오.",
        "question_en": "Find the number between 24 and 28 among 20, 23, 26, and 29.",
        "answer_ko": "26",
        "answer_en": "26",
        "solution_abst_ko": "[OP_LIST_SOL] 20 23 26 29 [OP_LIST_EOL] 24 [OP_LIST_MORE] 28 [OP_LIST_LESS] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] 20 23 26 29 [OP_LIST_EOL] 24 [OP_LIST_MORE] 28 [OP_LIST_LESS] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 20\nvar_b = 23\nvar_c = 26\nvar_d = 29\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 24\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nvar_f = 28\nlist_c = []\nfor i in list_b:\n    if i < var_f:\n        list_c.append(i)\nvar_g = 1\nvar_h = list_c[var_g-1]\nprint(int(var_h))",
        "solution_code_en": "var_a = 20\nvar_b = 23\nvar_c = 26\nvar_d = 29\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 24\nlist_b = []\nfor i in list_a:\n    if i > var_e:\n        list_b.append(i)\nvar_f = 28\nlist_c = []\nfor i in list_b:\n    if i < var_f:\n        list_c.append(i)\nvar_g = 1\nvar_h = list_c[var_g-1]\nprint(int(var_h))"
    },
    "7862": {
        "category": "Geometry",
        "question_ko": "다각형의 내부의 한 점 P와 각각의 꼭짓점을 연결하였더니 20개의 삼각형이 생겼다. 이 다각형의 대각선의 개수는?",
        "question_en": "A point P inside the polygon. When each vertex were connected with P, 20 triangles were created. How many diagonals does this polygon have?",
        "answer_ko": "170",
        "answer_en": "170",
        "solution_abst_ko": "20 20 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "20 20 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 20\nvar_b = 20\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 20\nvar_b = 20\nvar_c = 3\nvar_d = var_b - var_c\nvar_e = var_a * var_d\nvar_f = 2\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "7863": {
        "category": "Geometry",
        "question_ko": "한 모서리의 길이가 2센티미터(㎝)인 정육면체를 쌓아 한 모서리의 길이가 10센티미터(㎝)인 큰 정육면체를 만들었습니다. 큰 정육면체의 모든 면에 주황색 물감을 칠한다고 할 때, 1개의 면에만 주황색이 칠해진 정육면체는 몇 개입니까?",
        "question_en": "Cube with an edge length of 2 centimeters (cm) was stacked to make a large cube with an edge length of 10 centimeters (cm). If all sides of the large cube are painted orange, how many cubes have only one side painted orange?",
        "answer_ko": "54",
        "answer_en": "54",
        "solution_abst_ko": "10 2 [OP_DIV] 2 [OP_SUB] 2 [OP_POW] 6 [OP_MUL]",
        "solution_abst_en": "10 2 [OP_DIV] 2 [OP_SUB] 2 [OP_POW] 6 [OP_MUL]",
        "solution_code_ko": "var_a = 10\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e ** var_f\nvar_h = 6\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 10\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 2\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e ** var_f\nvar_h = 6\nvar_i = var_g * var_h\nprint(int(var_i))"
    },
    "7864": {
        "category": "Arithmetic calculation",
        "question_ko": "어느 가게에서 파는 연필이 5천원보다 2십원 쌀 때, 연필의 가격을 만원 단위로 구하시오.",
        "question_en": "If a pencil sold at a store is 20 won cheaper than 5,000 won, find the price of the pencil in units of 10,000 won.",
        "answer_ko": "0.50",
        "answer_en": "0.5",
        "solution_abst_ko": "5000 20 [OP_SUB] 10000 [OP_DIV]",
        "solution_abst_en": "5000 20 [OP_SUB] 10000 [OP_DIV]",
        "solution_code_ko": "var_a = 5000\nvar_b = 20\nvar_c = var_a - var_b\nvar_d = 10000\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 5000\nvar_b = 20\nvar_c = var_a - var_b\nvar_d = 10000\nvar_e = var_c / var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "7865": {
        "category": "Correspondence",
        "question_ko": "26을 4로 나눴을 때 몫이 A, 나머지가 B 였습니다. 이 때 B는 무엇인가요?",
        "question_en": "When 26 is divided by 4, the quotient is A and the remainder is B. What is B in this case?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "26 4 [OP_MOD]",
        "solution_abst_en": "26 4 [OP_MOD]",
        "solution_code_ko": "var_a = 26\nvar_b = 4\nvar_c = var_a % var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 26\nvar_b = 4\nvar_c = var_a % var_b\nprint(int(var_c))"
    },
    "7866": {
        "category": "Comparison",
        "question_ko": "총 3개의 숫자 0.8, 1/2, 0.6이 있습니다. 이 중 0.1보다 크거나 같은 수를 모두 더하면 얼마인가요?",
        "question_en": "There are a total of three numbers: 0.8, 1/2, and 0.6. What is the sum of all numbers greater than or equal to 0.1?",
        "answer_ko": "1.9",
        "answer_en": "1.9",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 0.6 [OP_LIST_EOL] 0.1 [OP_LIST_MORE_EQUAL] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 0.6 [OP_LIST_EOL] 0.1 [OP_LIST_MORE_EQUAL] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.1\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nvar_c = 0.6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 0.1\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nlist_b = [float(i) for i in list_b]\nvar_e = sum(list_b)\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "7867": {
        "category": "Correspondence",
        "question_ko": "빵이 37개가 있는데 빵과 함께 먹기 위해 우유를 가져왔다. 빵과 우유가 모두 합쳐 52개가 있습니다. 우유는 몇 병 있습니까?",
        "question_en": "There are 37 loaves of bread, and I brought bottles of milk to eat with the bread. There are 52 loaves of bread and bottles of milk in total. How many bottles of milk are there?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "52 37 [OP_SUB]",
        "solution_abst_en": "52 37 [OP_SUB]",
        "solution_code_ko": "var_a = 52\nvar_b = 37\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 52\nvar_b = 37\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "7868": {
        "category": "Comparison",
        "question_ko": "1.4, 9/10, 1.2, 0.5, 13/10에서 1.1보다 크거나 같은 숫자를 나열한뒤, 가장 작거나 같은 숫자를 구하면 얼마입니까?",
        "question_en": "Among 1.4, 9/10, 1.2, 0.5, and 13/10, if you list all the numbers greater than or equal to 1.1, what is the smallest or equal number among them?",
        "answer_ko": "1.20",
        "answer_en": "1.2",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE_EQUAL] 1 [OP_LIST_MIN]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE_EQUAL] 1 [OP_LIST_MIN]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i >= var_f:\n        list_b.append(i)\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nprint('{:.2f}'.format(round(var_h+1e-10,2)))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i >= var_f:\n        list_b.append(i)\nvar_g = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_h = list_c[var_g-1]\nprint('{:.2f}'.format(round(var_h+1e-10,2)))"
    },
    "7869": {
        "category": "Geometry",
        "question_ko": "직육면체 모양의 수영장의 가로는 20미터(m), 세로는 12미터(m), 깊이는 2미터(m)입니다. 수영장의 옆쪽 벽 모두와 바닥을 페인트로 칠하려고 합니다. 칠할 부분의 넓이는 모두 몇 ㎡입니까?",
        "question_en": "The cuboid-shaped swimming pool is 20 meters (m) long, 12 meters (m) wide, and 2 meters (m) deep. If you want to paint all of the side walls and floor of the pool, how many square meters (m2) of the area needs to be painted?",
        "answer_ko": "368",
        "answer_en": "368",
        "solution_abst_ko": "20 12 [OP_MUL] 20 2 [OP_MUL] 2 [OP_MUL] [OP_ADD] 12 2 [OP_MUL] 2 [OP_MUL] [OP_ADD]",
        "solution_abst_en": "20 12 [OP_MUL] 20 2 [OP_MUL] 2 [OP_MUL] [OP_ADD] 12 2 [OP_MUL] 2 [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 20\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 20\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_c + var_h\nvar_j = 12\nvar_k = 2\nvar_l = var_j * var_k\nvar_m = 2\nvar_n = var_l * var_m\nvar_o = var_i + var_n\nprint(int(var_o))",
        "solution_code_en": "var_a = 20\nvar_b = 12\nvar_c = var_a * var_b\nvar_d = 20\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = 2\nvar_h = var_f * var_g\nvar_i = var_c + var_h\nvar_j = 12\nvar_k = 2\nvar_l = var_j * var_k\nvar_m = 2\nvar_n = var_l * var_m\nvar_o = var_i + var_n\nprint(int(var_o))"
    },
    "7870": {
        "category": "Arithmetic calculation",
        "question_ko": "성현이는 180킬로미터(㎞) 떨어진 할아버지 댁에 가려고 합니다. 자동차를 타고 가는 데 걸린 시간이 2시간 30분이라면 자동차는 1시간에 몇 킬로미터(㎞)씩 간 셈입니까?",
        "question_en": "Seonghyeon wants to go to his grandfather's house, which is 180 kilometers (km) away. If it takes 2 hours and 30 minutes to travel by car, how many kilometers (km) does the car travel in 1 hour?",
        "answer_ko": "72",
        "answer_en": "72",
        "solution_abst_ko": "180 2 30 60 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_abst_en": "180 2 30 60 [OP_DIV] [OP_ADD] [OP_DIV]",
        "solution_code_ko": "var_a = 180\nvar_b = 2\nvar_c = 30\nvar_d = 60\nvar_e = var_c / var_d\nvar_f = var_b + var_e\nvar_g = var_a / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 180\nvar_b = 2\nvar_c = 30\nvar_d = 60\nvar_e = var_c / var_d\nvar_f = var_b + var_e\nvar_g = var_a / var_f\nprint(int(var_g))"
    },
    "7871": {
        "category": "Correspondence",
        "question_ko": "5를 어떤 수에서 빼면 2가 나온다. 어떤 수에 3을 더하면 얼마가 되는가?",
        "question_en": "Subtracting 5 from a certain number gives 2. What number do you get when you add 3 to it?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "2 5 [OP_ADD] 3 [OP_ADD]",
        "solution_abst_en": "2 5 [OP_ADD] 3 [OP_ADD]",
        "solution_code_ko": "var_a = 2\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 2\nvar_b = 5\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7872": {
        "category": "Possibility",
        "question_ko": "어느 편의점에 샌드위치 4종류, 삼각김밥 3종류가 있다. 샌드위치와 삼각김밥을 각각 1개씩 선택하는 경우의 수는?",
        "question_en": "A convenience store has four kinds of sandwiches, and three kinds of triangular gimbap. In how many ways can you choose one sandwich and one gimbap?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "4 1 [OP_COMB] 3 1 [OP_COMB] [OP_MUL]",
        "solution_abst_en": "4 1 [OP_COMB] 3 1 [OP_COMB] [OP_MUL]",
        "solution_code_ko": "var_a = 4\nvar_b = 1\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nvar_d = 3\nvar_e = 1\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f / (i+1)\nvar_g = var_c * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 4\nvar_b = 1\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c / (i+1)\nvar_d = 3\nvar_e = 1\nvar_f = 1\nvar_d = int(var_d)\nvar_e = int(var_e)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f * (var_d-i)\nfor i, elem in enumerate(range(var_e)):\n    var_f = var_f / (i+1)\nvar_g = var_c * var_f\nprint(int(var_g))"
    },
    "7873": {
        "category": "Geometry",
        "question_ko": "가로, 세로, 높이가 각각 350센티미터(㎝), 260센티미터(㎝), 165센티미터(㎝)인 직육면체 안에 가로, 세로, 높이 모두 5센티미터(㎝)씩 띄어져 있는 또 다른 직육면체가 있다. 이 안에 있는 직육면체를 부피가 1세제곱센티미터(㎤)인 쌓기나무로 가득 채우려고 한다. 쌓기나무 하나가 1600원이라면, 얼마가 필요할지 구하시오.",
        "question_en": "Inside a rectangular parallelepiped with dimensions of 350 cm (cm), 260 cm (cm), and 165 cm (cm), there is another rectangular parallelepiped spaced apart by 5 cm (cm) in width, length, and height. We want to fill the cuboid inside it with building blocks with a volume of 1 cubic centimeter (cm3). If one building block costs 1600 won, how much will need?",
        "answer_ko": "21080000000",
        "answer_en": "21080000000",
        "solution_abst_ko": "350 5 2 [OP_MUL] [OP_SUB] 260 5 2 [OP_MUL] [OP_SUB] [OP_MUL] 165 5 2 [OP_MUL] [OP_SUB] [OP_MUL] 1600 [OP_MUL]",
        "solution_abst_en": "350 5 2 [OP_MUL] [OP_SUB] 260 5 2 [OP_MUL] [OP_SUB] [OP_MUL] 165 5 2 [OP_MUL] [OP_SUB] [OP_MUL] 1600 [OP_MUL]",
        "solution_code_ko": "var_a = 350\nvar_b = 5\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 260\nvar_g = 5\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = var_f - var_i\nvar_k = var_e * var_j\nvar_l = 165\nvar_m = 5\nvar_n = 2\nvar_o = var_m * var_n\nvar_p = var_l - var_o\nvar_q = var_k * var_p\nvar_r = 1600\nvar_s = var_q * var_r\nprint(int(var_s))",
        "solution_code_en": "var_a = 350\nvar_b = 5\nvar_c = 2\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 260\nvar_g = 5\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = var_f - var_i\nvar_k = var_e * var_j\nvar_l = 165\nvar_m = 5\nvar_n = 2\nvar_o = var_m * var_n\nvar_p = var_l - var_o\nvar_q = var_k * var_p\nvar_r = 1600\nvar_s = var_q * var_r\nprint(int(var_s))"
    },
    "7874": {
        "category": "Correspondence",
        "question_ko": "어떤 수의 10배는 17입니다, 어떤 수의 1/100배에 3을 곱한 값은 얼마입니까?",
        "question_en": "10 times a certain number is 17. What is the result of a certain number multiplied by 1/100 and than multiplied by 3?",
        "answer_ko": "0.05",
        "answer_en": "0.05",
        "solution_abst_ko": "17 10 [OP_DIV] 1/100 [OP_MUL] 3 [OP_MUL]",
        "solution_abst_en": "17 10 [OP_DIV] 1/100 [OP_MUL] 3 [OP_MUL]",
        "solution_code_ko": "var_a = 17\nvar_b = 10\nvar_c = var_a / var_b\nvar_d = 0.01\nvar_e = var_c * var_d\nvar_f = 3\nvar_g = var_e * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 17\nvar_b = 10\nvar_c = var_a / var_b\nvar_d = 0.01\nvar_e = var_c * var_d\nvar_f = 3\nvar_g = var_e * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "7875": {
        "category": "Correspondence",
        "question_ko": "1부터 9까지의 수 A 중 A888<5001이 되게 하는 A는 모두 몇 개입니까?",
        "question_en": "What is the number of possible A which is from 1 to 9 to make A888<5001?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "A888<5001 A [OP_DIGIT_UNK_SOLVER] [OP_LIST_LEN]",
        "solution_abst_en": "A888<5001 A [OP_DIGIT_UNK_SOLVER] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 'A888<5001'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = len(list_a)\nprint(int(var_c))",
        "solution_code_en": "var_a = 'A888<5001'\nvar_b = 'A'\nans_dict = dict()\nvar_a = var_a.replace('×','*')\nvar_a = var_a.replace('x','*')\nvar_a = var_a.replace('÷','/')\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = []\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    term_list = []\n    op_list = []\n    temp_c = ''\n    for tc in temp:\n        if tc not in '+-*/=><().':\n            temp_c += tc\n        else:\n            op_list.append(tc)\n            term_list.append(temp_c)\n            temp_c = ''\n    term_list.append(temp_c)\n    new_eq = ''\n    for i in range(len(op_list)):\n        new_eq += str(int(term_list[i]))+op_list[i]\n    new_eq += str(int(term_list[-1]))\n    if len(new_eq) == len(var_a):\n        new_eq=new_eq.replace('=', '==')\n        new_eq=new_eq.replace('>==', '>=')\n        new_eq=new_eq.replace('<==', '<=')\n        eval_result = False\n        try:\n            eval_result = eval(new_eq)\n        except:\n            pass\n        if eval_result:\n            for i, (k, _) in enumerate(ans_dict.items()):\n                ans_dict[k].append(int(c[i]))\nlist_a = list(set(ans_dict[var_b]))\nvar_c = len(list_a)\nprint(int(var_c))"
    },
    "7876": {
        "category": "Arithmetic calculation",
        "question_ko": "은지는 올해 16살입니다. 은지의 어머니는 은지가 8살이었을 때 35세였습니다. 올해 어머니의 나이는 몇입니까?",
        "question_en": "Eunji is 16 years old this year. Eunji's mother was 35 when Eunji was 8 years old. How old is the mother this year?",
        "answer_ko": "43",
        "answer_en": "43",
        "solution_abst_ko": "35 16 8 [OP_SUB] [OP_ADD]",
        "solution_abst_en": "35 16 8 [OP_SUB] [OP_ADD]",
        "solution_code_ko": "var_a = 35\nvar_b = 16\nvar_c = 8\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 35\nvar_b = 16\nvar_c = 8\nvar_d = var_b - var_c\nvar_e = var_a + var_d\nprint(int(var_e))"
    },
    "7877": {
        "category": "Arithmetic calculation",
        "question_ko": "연속하는 두 홀수의 합이 48일 때 두 홀수 중 큰 수를 구하시오.",
        "question_en": "If the sum of two consecutive odd numbers is 48, find the larger of the two odd numbers.",
        "answer_ko": "25",
        "answer_en": "25",
        "solution_abst_ko": "48 2 [OP_DIV] 1 [OP_ADD]",
        "solution_abst_en": "48 2 [OP_DIV] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 48\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 48\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7878": {
        "category": "Possibility",
        "question_ko": "동전 2개와 주사위 1개를 동시에 던질 때, 두 동전은 서로 다른 면이 나오고 주사위의 눈은 3으로 나눈 나머지가 1인 경우의 수는?",
        "question_en": "Given that 2 coins and 1 dice are tossed at the same time, what is the number of cases that two coins come out on different sides and the dice divided by 3 gives a remainder of 1?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "2 1 6 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] [OP_MUL]",
        "solution_abst_en": "2 1 6 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 1\nvar_c = 6\nvar_d = 1\nlist_a = [i for i in range(var_b, var_c + 1, var_d)]\nvar_e = 3\nlist_b = []\nvar_e = int(var_e)\nfor i in list_a:\n    i = int(i)\n    if i % var_e == 0:\n        list_b.append(i)\nvar_f = len(list_b)\nvar_g = var_a * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 2\nvar_b = 1\nvar_c = 6\nvar_d = 1\nlist_a = [i for i in range(var_b, var_c + 1, var_d)]\nvar_e = 3\nlist_b = []\nvar_e = int(var_e)\nfor i in list_a:\n    i = int(i)\n    if i % var_e == 0:\n        list_b.append(i)\nvar_f = len(list_b)\nvar_g = var_a * var_f\nprint(int(var_g))"
    },
    "7879": {
        "category": "Possibility",
        "question_ko": "두 자리 수를 만드려고 하는데 3,5를 한 번씩만 사용하려고 합니다. 이때 만들 수 있는 서로 다른 두 자리 수는 모두 몇가지 입니까?",
        "question_en": "I'm trying to make a two-digit number, but I only want to use 3 and 5 once. How many different two-digit numbers can you make?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 3 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 3 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 3\nvar_b = 5\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = len(list_b)\nprint(int(var_d))",
        "solution_code_en": "var_a = 3\nvar_b = 5\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 2\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = len(list_b)\nprint(int(var_d))"
    },
    "7880": {
        "category": "Geometry",
        "question_ko": "가로가 480미터(m), 세로가 360미터(m)인 직사각형 모양의 운동장이 있다. 운동장의 가장자리를 따라 한바퀴 돈다면 몇 킬로미터(㎞)인지 구하시오.",
        "question_en": "There is a rectangular shaped playground with a width of 480 meters (m) and a length of 360 meters (m). Find how many kilometers (km) it is if you go around the edge of the field once.",
        "answer_ko": "1.68",
        "answer_en": "1.68",
        "solution_abst_ko": "480 1000 [OP_DIV] 360 1000 [OP_DIV] [OP_ADD] 2 [OP_MUL] 2 [OP_ROUND]",
        "solution_abst_en": "480 1000 [OP_DIV] 360 1000 [OP_DIV] [OP_ADD] 2 [OP_MUL] 2 [OP_ROUND]",
        "solution_code_ko": "var_a = 480\nvar_b = 1000\nvar_c = var_a / var_b\nvar_d = 360\nvar_e = 1000\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = 2\nvar_k = round(float(var_i)+1e-10, var_j)\nprint('{:.2f}'.format(round(var_k+1e-10,2)))",
        "solution_code_en": "var_a = 480\nvar_b = 1000\nvar_c = var_a / var_b\nvar_d = 360\nvar_e = 1000\nvar_f = var_d / var_e\nvar_g = var_c + var_f\nvar_h = 2\nvar_i = var_g * var_h\nvar_j = 2\nvar_k = round(float(var_i)+1e-10, var_j)\nprint('{:.2f}'.format(round(var_k+1e-10,2)))"
    },
    "7881": {
        "category": "Arithmetic calculation",
        "question_ko": "마트에 야구공이 2754개, 탁구공이 1938개 있었습니다. 그중에서 야구공 1095개와 탁구공 몇 개를 팔았더니 야구공과 탁구공이 합해서 3021개 남았습니다. 탁구공은 몇 개 팔았는지 구하시오.",
        "question_en": "There were 2754 baseballs and 1938 ping pong balls in the shop. Among them, 1095 baseballs and a few ping-pong balls were sold, and a total of 3021 balls were left. How many ping-pong balls were sold?",
        "answer_ko": "576",
        "answer_en": "576",
        "solution_abst_ko": "2754 1938 [OP_ADD] 1095 [OP_SUB] 3021 [OP_SUB]",
        "solution_abst_en": "2754 1938 [OP_ADD] 1095 [OP_SUB] 3021 [OP_SUB]",
        "solution_code_ko": "var_a = 2754\nvar_b = 1938\nvar_c = var_a + var_b\nvar_d = 1095\nvar_e = var_c - var_d\nvar_f = 3021\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 2754\nvar_b = 1938\nvar_c = var_a + var_b\nvar_d = 1095\nvar_e = var_c - var_d\nvar_f = 3021\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "7882": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 7 을 곱할 것을 잘못하여 뺐더니 0.45 가 되었습니다. 바르게 계산하면 얼마인지 구하시오.",
        "question_en": "I mistakenly subtracted 7 from this number when I was supposed to multiply it, and I got 0.45. How much is it if I calculate it correctly?",
        "answer_ko": "52.15",
        "answer_en": "52.15",
        "solution_abst_ko": "0.45 7 [OP_ADD] 7 [OP_MUL]",
        "solution_abst_en": "0.45 7 [OP_ADD] 7 [OP_MUL]",
        "solution_code_ko": "var_a = 0.45\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 7\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.45\nvar_b = 7\nvar_c = var_a + var_b\nvar_d = 7\nvar_e = var_c * var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "7883": {
        "category": "Correspondence",
        "question_ko": "상현이네 반 학생들이 안 보는 책을 도서관에 기부했다. 상현이네 반 학생은 20명이고 학생 당 15권의 책을 기부한다고 하였다. 그러나 도서관에서 받은 책의 수가 예상했던 책 수보다 6 권이 부족했다면 도서관에서 실제로 받은 도서 수는 몇권 입니까?",
        "question_en": "Sanghyun's class donated unread books to the library. There are 20 students in her class and they planned to donate 15 books per student. If the library got 6 books less than they expected, how many books the library got?",
        "answer_ko": "294",
        "answer_en": "294",
        "solution_abst_ko": "15 20 [OP_MUL] 6 [OP_SUB]",
        "solution_abst_en": "15 20 [OP_MUL] 6 [OP_SUB]",
        "solution_code_ko": "var_a = 15\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 20\nvar_c = var_a * var_b\nvar_d = 6\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "7884": {
        "category": "Comparison",
        "question_ko": "각각의 크기가 다른 장난감이 모두 19개 있습니다. 이 장난감을 크기가 작은 것부터 순서대로 놓으면 장난감 (가)는 왼쪽에서 9번째에 있고, 장난감 (나)는 왼쪽에서 15번째에 있습니다. 장난감 (가)와 장난감 (나) 사이에 있는 장난감은 몇 개입니까?",
        "question_en": "There are 19 toys in all, each in a different sizes. If you put these toys in order from the smallest, toy (a) is at 9th and toy (b) is at 15th place. How many toys are there between toy (a) and toy (b)?",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "15 9 [OP_SUB] 1 [OP_SUB]",
        "solution_abst_en": "15 9 [OP_SUB] 1 [OP_SUB]",
        "solution_code_ko": "var_a = 15\nvar_b = 9\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 15\nvar_b = 9\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "7885": {
        "category": "Arithmetic calculation",
        "question_ko": "형은 나보다 1/10미터(m) 더 크고, 동생은 나보다 0.2미터(m) 작습니다. 동생의 키가 1.1미터(m)라면 형의 키는 몇 미터(m)인지 구하시오.",
        "question_en": "Your older brother is 1/10 meter (m) taller than you, and your younger brother is 0.2 meter (m) shorter than you. If the younger brother is 1.1 meters (m), how tall is the older brother in meters (m)?",
        "answer_ko": "1.40",
        "answer_en": "1.4",
        "solution_abst_ko": "0.2 1.1 [OP_ADD] 1/10 [OP_ADD]",
        "solution_abst_en": "0.2 1.1 [OP_ADD] 1/10 [OP_ADD]",
        "solution_code_ko": "var_a = 0.2\nvar_b = 1.1\nvar_c = var_a + var_b\nvar_d = 0.1\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))",
        "solution_code_en": "var_a = 0.2\nvar_b = 1.1\nvar_c = var_a + var_b\nvar_d = 0.1\nvar_e = var_c + var_d\nprint('{:.2f}'.format(round(var_e+1e-10,2)))"
    },
    "7886": {
        "category": "Correspondence",
        "question_ko": "어떤 수에서 3을 빼면 6의 배수이고, 어떤 수에서 1을 빼면 8의 배수이다. 어떤 수를 구하시오. 단, 어떤 수는 35보다 크고 70보다 작은 자연수이다.",
        "question_en": "Subtracting 3 from the number is a multiple of 6, and subtracting 1 from the number is a multiple of 8. Find the number. However, any number is a natural number greater than 35 and less than 70.",
        "answer_ko": "57",
        "answer_en": "57",
        "solution_abst_ko": "35 70 1 [OP_SUB] 1 [OP_LIST_ARANGE] 6 3 [OP_LIST_DIVIDE_AND_REMAIN] 8 1 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "35 70 1 [OP_SUB] 1 [OP_LIST_ARANGE] 6 3 [OP_LIST_DIVIDE_AND_REMAIN] 8 1 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 35\nvar_b = 70\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nvar_f = 6\nvar_g = 3\nlist_b = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_a:\n    i = int(i)\n    if i%var_f == var_g:\n        list_b.append(i)\nvar_h = 8\nvar_i = 1\nlist_c = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_b:\n    i = int(i)\n    if i%var_h == var_i:\n        list_c.append(i)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(int(var_k))",
        "solution_code_en": "var_a = 35\nvar_b = 70\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nvar_f = 6\nvar_g = 3\nlist_b = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_a:\n    i = int(i)\n    if i%var_f == var_g:\n        list_b.append(i)\nvar_h = 8\nvar_i = 1\nlist_c = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_b:\n    i = int(i)\n    if i%var_h == var_i:\n        list_c.append(i)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(int(var_k))"
    },
    "7887": {
        "category": "Possibility",
        "question_ko": "3, 8, 2, 7의 숫자가 적힌 4 장의 카드가 있다. 각 카드를 딱 한 번씩만 사용하여 소수점 두 자리 수를 만들 때 세 번째로 큰 수는 무엇일까요?",
        "question_en": "There are 4 cards numbered 3, 8, 2, and 7. If each card is used only once when forming a number with two-digit decimal number, what is the third largest number?",
        "answer_ko": "83.72",
        "answer_en": "83.72",
        "solution_abst_ko": "[OP_LIST_SOL] 3 8 2 7 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] 10 [OP_LIST_POP] [OP_LIST_LEN] 2 [OP_SUB] [OP_POW] [OP_DIV]",
        "solution_abst_en": "[OP_LIST_SOL] 3 8 2 7 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] 10 [OP_LIST_POP] [OP_LIST_LEN] 2 [OP_SUB] [OP_POW] [OP_DIV]",
        "solution_code_ko": "var_a = 3\nvar_b = 8\nvar_c = 2\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 10\nvar_i = len(list_a)\nvar_j = 2\nvar_k = var_i - var_j\nvar_l = var_h ** var_k\nvar_m = var_g / var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))",
        "solution_code_en": "var_a = 3\nvar_b = 8\nvar_c = 2\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 4\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c=list_b.copy()\nlist_c.sort()\nvar_g = list_c[-var_f]\nvar_h = 10\nvar_i = len(list_a)\nvar_j = 2\nvar_k = var_i - var_j\nvar_l = var_h ** var_k\nvar_m = var_g / var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))"
    },
    "7888": {
        "category": "Comparison",
        "question_ko": "정국이는 0.8, 윤기는 1/2의 숫자카드를 갖고 있습니다. 0.3보다 작은 숫자카드를 가지고 있는 사람은 몇 명입니까?",
        "question_en": "Jungkook has a 0.8 number card and Yoongi has a 1/2 number card. How many people have a number card less than 0.3?",
        "answer_ko": "0",
        "answer_en": "0",
        "solution_abst_ko": "[OP_LIST_SOL] 0.8 1/2 [OP_LIST_EOL] 0.3 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 0.8 1/2 [OP_LIST_EOL] 0.3 [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 0.8\nvar_b = 0.5\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.3\nlist_b = []\nfor i in list_a:\n    if i < var_c:\n        list_b.append(i)\nvar_d = len(list_b)\nprint(int(var_d))",
        "solution_code_en": "var_a = 0.8\nvar_b = 0.5\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.3\nlist_b = []\nfor i in list_a:\n    if i < var_c:\n        list_b.append(i)\nvar_d = len(list_b)\nprint(int(var_d))"
    },
    "7889": {
        "category": "Geometry",
        "question_ko": "직사각형 모양의 농장이 있습니다. 이 농장의 둘레의 길이는 46킬로미터(㎞)이고, 가로의 길이는 세로의 길이보다 7킬로미터(㎞) 더 길다고 할 때, 이 농장의 가로의 길이는 몇 킬로미터(㎞)입니까?",
        "question_en": "There is a rectangular farm. If the circumference of this farm is 46 kilometers (km) and the width is 7 kilometers (km) longer than the length, how many kilometers (km) is the width of this farm?",
        "answer_ko": "15",
        "answer_en": "15",
        "solution_abst_ko": "46 2 [OP_DIV] 7 [OP_SUB] 2 [OP_DIV] 7 [OP_ADD]",
        "solution_abst_en": "46 2 [OP_DIV] 7 [OP_SUB] 2 [OP_DIV] 7 [OP_ADD]",
        "solution_code_ko": "var_a = 46\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 7\nvar_i = var_g + var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 46\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 7\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e / var_f\nvar_h = 7\nvar_i = var_g + var_h\nprint(int(var_i))"
    },
    "7890": {
        "category": "Comparison",
        "question_ko": "20명의 학생들의 키를 비교하고 있습니다. 정국이는 윤기보다 키가 작고, 윤기와 정국이 사이에는 5명의 학생이 있습니다. 정국이보다 키가 큰 학생은 모두 6명입니다. 윤기보다 작은 학생은 몇 명입니까?",
        "question_en": "You are comparing the heights of 20 students. Jungkook is shorter than Yoongi, and there are 5 students between Yoongi and Jungkook. There are 6 students who are taller than Jungkook. How many students are shorter than Yoongi?",
        "answer_ko": "19",
        "answer_en": "19",
        "solution_abst_ko": "20 6 [OP_SUB] 5 [OP_ADD]",
        "solution_abst_en": "20 6 [OP_SUB] 5 [OP_ADD]",
        "solution_code_ko": "var_a = 20\nvar_b = 6\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 20\nvar_b = 6\nvar_c = var_a - var_b\nvar_d = 5\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7891": {
        "category": "Comparison",
        "question_ko": "유리는 햄버거 먹기 대회에서 햄버거 6개를 먹었고, 지수는 햄버거 8개를 먹었습니다. 창현이는 유리보다는 많이 먹고 지수보다는 적게 먹었습니다. 창현이가 먹은 햄버거는 몇 개입니까?",
        "question_en": "Yuri ate 6 hamburgers in a hamburger eating contest, and Jisoo ate 8 hamburgers. Changhyun ate more than Yuri and less than Jisu. How many hamburgers did Changhyun eat?",
        "answer_ko": "7",
        "answer_en": "7",
        "solution_abst_ko": "6 8 [OP_ADD] 2 [OP_FDIV]",
        "solution_abst_en": "6 8 [OP_ADD] 2 [OP_FDIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 6\nvar_b = 8\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c // var_d\nprint(int(var_e))"
    },
    "7892": {
        "category": "Correspondence",
        "question_ko": "어떤 수의 1/1000인 수가 0.735이면 어떤 수의 10배인 수는 얼마입니까?",
        "question_en": "If 1/1000 of a certain number is 0.735, what number is 10 times that certain number?",
        "answer_ko": "7350",
        "answer_en": "7350",
        "solution_abst_ko": "0.735 1/1000 [OP_DIV] 10 [OP_MUL]",
        "solution_abst_en": "0.735 1/1000 [OP_DIV] 10 [OP_MUL]",
        "solution_code_ko": "var_a = 0.735\nvar_b = 0.001\nvar_c = var_a / var_b\nvar_d = 10\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 0.735\nvar_b = 0.001\nvar_c = var_a / var_b\nvar_d = 10\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "7893": {
        "category": "Possibility",
        "question_ko": "승희는 주사위를 세 번 던져 나온 수를 모두 사용하여 세 자리 수를 만들고자 한다. 주사위를 던져 3, 4, 6이 나왔을 때, 450보다 큰 수를 만드는 경우는 모두 몇 가지인가?",
        "question_en": "Seung-hee wants to make a three-digit number by throwing the dice three times and using all the numbers that come out. When 3, 4, and 6 came out after rolling the dice, how many cases are possible to make a number bigger than 450?",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "[OP_LIST_SOL] 3 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 450 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 3 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 450 [OP_LIST_MORE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 3\nvar_b = 4\nvar_c = 6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 450\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))",
        "solution_code_en": "var_a = 3\nvar_b = 4\nvar_c = 6\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_d))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_e = 450\nlist_c = []\nfor i in list_b:\n    if i > var_e:\n        list_c.append(i)\nvar_f = len(list_c)\nprint(int(var_f))"
    },
    "7894": {
        "category": "Possibility",
        "question_ko": "서점에서 7개의 똑같은 책을 윤기와 호석이에게 나누어주려고 합니다. 윤기와 호석이는 적어도 1개의 책을 받습니다. 책을 나누어주는 방법은 총 몇 개입니까?",
        "question_en": "I'm going to give 7 identical books to Yoongi and Hoseok. Yoongi and Hoseok will receive at least one book. How many ways can the books be distributed in total?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "7 2 1 [OP_MUL] [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "7 2 1 [OP_MUL] [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 7\nvar_b = 2\nvar_c = 1\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 7\nvar_b = 2\nvar_c = 1\nvar_d = var_b * var_c\nvar_e = var_a - var_d\nvar_f = 1\nvar_g = var_e + var_f\nprint(int(var_g))"
    },
    "7895": {
        "category": "Arithmetic calculation",
        "question_ko": "1부터 100까지의 수 중 짝수이며, 3의 배수인 수는 몇 개입니까?",
        "question_en": "How many numbers from 1 to 100 are even and multiples of 3?",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "1 100 [OP_LIST_EVEN] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_abst_en": "1 100 [OP_LIST_EVEN] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 100\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 3\nlist_b = []\nvar_c = int(var_c)\nfor i in list_a:\n    i = int(i)\n    if i % var_c == 0:\n        list_b.append(i)\nvar_d = len(list_b)\nprint(int(var_d))",
        "solution_code_en": "var_a = 1\nvar_b = 100\nlist_a = []\nif var_a%2!=0:\n    for i in range(var_a+1, var_b+1, 2):\n        list_a.append(i)\nelse:\n    for i in range(var_a, var_b+1, 2):\n        list_a.append(i)\nvar_c = 3\nlist_b = []\nvar_c = int(var_c)\nfor i in list_a:\n    i = int(i)\n    if i % var_c == 0:\n        list_b.append(i)\nvar_d = len(list_b)\nprint(int(var_d))"
    },
    "7896": {
        "category": "Arithmetic calculation",
        "question_ko": "개와 고양이를 합하면 17마리입니다. 그중에서 고양이가 8마리라면 개는 몇 마리입니까?",
        "question_en": "There are 17 dogs and cats in total. If there are 8 cats, how many dogs are there?",
        "answer_ko": "9",
        "answer_en": "9",
        "solution_abst_ko": "17 8 [OP_SUB]",
        "solution_abst_en": "17 8 [OP_SUB]",
        "solution_code_ko": "var_a = 17\nvar_b = 8\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 17\nvar_b = 8\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "7897": {
        "category": "Correspondence",
        "question_ko": "서로 다른 세 자연수 A, B, C가 있습니다. A를 25로 나누면 몫은 B이고 나머지는 C가 됩니다. 나머지 C가 될 수 있는 가장 큰 수를 구하시오.",
        "question_en": "There are three different natural numbers A, B, and C. When A is divided by 25, the quotient is B and the remainder is C. Find the largest number that can be C.",
        "answer_ko": "24",
        "answer_en": "24",
        "solution_abst_ko": "25 1 [OP_SUB]",
        "solution_abst_en": "25 1 [OP_SUB]",
        "solution_code_ko": "var_a = 25\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 25\nvar_b = 1\nvar_c = var_a - var_b\nprint(int(var_c))"
    },
    "7898": {
        "category": "Comparison",
        "question_ko": "학생 13명이 한 줄로 서 있습니다. 민영이는 왼쪽에서 8번째에 서 있고, 호석이는 오른쪽에서 9번째에 서 있습니다. 민영이와 호석이 사이에 서 있는 학생은 몇 명입니까?",
        "question_en": "13 students stand in a line. Minyoung stands at the 8th from the left, and Hoseok stands at the 9th from the right. How many students are standing between Minyoung and Hoseok?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "8 9 [OP_ADD] 13 [OP_SUB] 2 [OP_SUB]",
        "solution_abst_en": "8 9 [OP_ADD] 13 [OP_SUB] 2 [OP_SUB]",
        "solution_code_ko": "var_a = 8\nvar_b = 9\nvar_c = var_a + var_b\nvar_d = 13\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e - var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 8\nvar_b = 9\nvar_c = var_a + var_b\nvar_d = 13\nvar_e = var_c - var_d\nvar_f = 2\nvar_g = var_e - var_f\nprint(int(var_g))"
    },
    "7899": {
        "category": "Possibility",
        "question_ko": "남학생 3명과 여학생 3명이 한 명씩 출입문을 지날 때, 남학생 3명이 연속으로 출입문을 지나는 경우의 수를 구하시오.",
        "question_en": "If 3 male students and 3 female students pass through the door one by one, find the number of cases in which 3 male students pass through the door in succession.",
        "answer_ko": "144",
        "answer_en": "144",
        "solution_abst_ko": "3 3 [OP_ADD] 3 1 [OP_SUB] [OP_SUB] 3 3 [OP_ADD] 3 1 [OP_SUB] [OP_SUB] [OP_PERM] 3 3 [OP_PERM] [OP_MUL]",
        "solution_abst_en": "3 3 [OP_ADD] 3 1 [OP_SUB] [OP_SUB] 3 3 [OP_ADD] 3 1 [OP_SUB] [OP_SUB] [OP_PERM] 3 3 [OP_PERM] [OP_MUL]",
        "solution_code_ko": "var_a = 3\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nvar_h = 3\nvar_i = 3\nvar_j = var_h + var_i\nvar_k = 3\nvar_l = 1\nvar_m = var_k - var_l\nvar_n = var_j - var_m\nvar_o = 1\nvar_g = int(var_g)\nvar_n = int(var_n)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o * (var_g-i)\nvar_p = 3\nvar_q = 3\nvar_r = 1\nvar_p = int(var_p)\nvar_q = int(var_q)\nfor i, elem in enumerate(range(var_q)):\n    var_r = var_r * (var_p-i)\nvar_s = var_o * var_r\nprint(int(var_s))",
        "solution_code_en": "var_a = 3\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 3\nvar_e = 1\nvar_f = var_d - var_e\nvar_g = var_c - var_f\nvar_h = 3\nvar_i = 3\nvar_j = var_h + var_i\nvar_k = 3\nvar_l = 1\nvar_m = var_k - var_l\nvar_n = var_j - var_m\nvar_o = 1\nvar_g = int(var_g)\nvar_n = int(var_n)\nfor i, elem in enumerate(range(var_n)):\n    var_o = var_o * (var_g-i)\nvar_p = 3\nvar_q = 3\nvar_r = 1\nvar_p = int(var_p)\nvar_q = int(var_q)\nfor i, elem in enumerate(range(var_q)):\n    var_r = var_r * (var_p-i)\nvar_s = var_o * var_r\nprint(int(var_s))"
    },
    "7900": {
        "category": "Comparison",
        "question_ko": "학생들이 일렬로 줄을 섰을 때 윤정이 앞에 6명이 있고 윤정이는 뒤에서 5번째에 서 있을 때 줄을 선 학생은 모두 몇 명입니까?",
        "question_en": "When students are lined up in a single line, how many students are there when 6 people are in front of Yoonjung? (Yoonjung is at 5th from the back.)",
        "answer_ko": "11",
        "answer_en": "11",
        "solution_abst_ko": "6 5 [OP_ADD]",
        "solution_abst_en": "6 5 [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 5\nvar_c = var_a + var_b\nprint(int(var_c))"
    },
    "7901": {
        "category": "Arithmetic calculation",
        "question_ko": "철근 3/4미터(m)의 무게가 15/2킬로그램(㎏)일 때 철근 1미터(m)의 무게는 몇 킬로그램(㎏)입니까?",
        "question_en": "If 3/4 meter (m) of reinforcing bar weighs 15/2 kilograms (kg), how many kilograms (kg) does 1 meter (m) of reinforcing bar weigh?",
        "answer_ko": "10",
        "answer_en": "10",
        "solution_abst_ko": "15/2 3/4 [OP_DIV]",
        "solution_abst_en": "15/2 3/4 [OP_DIV]",
        "solution_code_ko": "var_a = 7.5\nvar_b = 0.75\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 7.5\nvar_b = 0.75\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "7902": {
        "category": "Geometry",
        "question_ko": "한 모서리의 길이가 9센티미터(㎝)인 정육면체에서 한 모서리의 길이가 3센티미터(㎝)인 정육면체를 모서리의 개수만큼 잘라내고 남은 부분의 부피는 몇 세제곱센티미터(㎤)인지 알아보아라.",
        "question_en": "From a cube with one edge length of 9 centimeters (cm), cut a cube with one edge length of 3 centimeters (cm) as many as the number of edges, and find out how many cubic centimeters (cm3) the volume of the remaining part is.",
        "answer_ko": "405",
        "answer_en": "405",
        "solution_abst_ko": "9 3 [OP_POW] 3 3 [OP_POW] 12 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "9 3 [OP_POW] 3 3 [OP_POW] 12 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 9\nvar_b = 3\nvar_c = var_a ** var_b\nvar_d = 3\nvar_e = 3\nvar_f = var_d ** var_e\nvar_g = 12\nvar_h = var_f * var_g\nvar_i = var_c - var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 9\nvar_b = 3\nvar_c = var_a ** var_b\nvar_d = 3\nvar_e = 3\nvar_f = var_d ** var_e\nvar_g = 12\nvar_h = var_f * var_g\nvar_i = var_c - var_h\nprint(int(var_i))"
    },
    "7903": {
        "category": "Arithmetic calculation",
        "question_ko": "1묶음의 개수는 10개 입니다. 검은색 바둑돌이 3묶음 있고, 흰색 바둑돌이 16개 있다면 바둑돌은 모두 몇 개 있습니까?",
        "question_en": "There are 10 go stones in 1 bundle. If there are 3 bundles of black go stones and 16 white go stones, how many go stones are there in all?",
        "answer_ko": "46",
        "answer_en": "46",
        "solution_abst_ko": "10 3 [OP_MUL] 16 [OP_ADD]",
        "solution_abst_en": "10 3 [OP_MUL] 16 [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 16\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 10\nvar_b = 3\nvar_c = var_a * var_b\nvar_d = 16\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7904": {
        "category": "Correspondence",
        "question_ko": "1부터 200까지 자연수를 쓰려고 합니다. 숫자 1은 모두 몇 번 써야 합니까?",
        "question_en": "You are trying to write natural numbers from 1 to 200. How many times should the number 1 be written in all?",
        "answer_ko": "140",
        "answer_en": "140",
        "solution_abst_ko": "1 200 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 1 [OP_LIST_FIND_NUM]",
        "solution_abst_en": "1 200 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 1 [OP_LIST_FIND_NUM]",
        "solution_code_ko": "var_a = 1\nvar_b = 200\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 1\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))",
        "solution_code_en": "var_a = 1\nvar_b = 200\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d=\"\"\nfor i in list_a:\n    i = str(i)\n    var_d = var_d + i\nlist_b = []\nvar_d = int(var_d)\nwhile var_d//10 > 0:\n    list_b.append(var_d%10)\n    var_d = var_d//10\nlist_b.append(var_d%10)\nlist_b = list_b[::-1]\nvar_e = 1\nvar_f = 0\nvar_e = int(var_e)\nfor i in list_b:\n    i = int(i)\n    if i == var_e:\n        var_f = var_f + 1\nprint(int(var_f))"
    },
    "7905": {
        "category": "Correspondence",
        "question_ko": "48은 어떤 수에 22를 더해야 하는데 실수로 12를 더하여 나온 결과입니다. 바르게 계산하면 얼마가 됩니까?",
        "question_en": "48 is the result of accidentally adding 12 to a number where 22 should have been added. How much do you get if you calculate correctly?",
        "answer_ko": "58",
        "answer_en": "58",
        "solution_abst_ko": "48 12 [OP_SUB] 22 [OP_ADD]",
        "solution_abst_en": "48 12 [OP_SUB] 22 [OP_ADD]",
        "solution_code_ko": "var_a = 48\nvar_b = 12\nvar_c = var_a - var_b\nvar_d = 22\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 48\nvar_b = 12\nvar_c = var_a - var_b\nvar_d = 22\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7906": {
        "category": "Geometry",
        "question_ko": "넓이가 33.3제곱센티미터(㎠)인 평행사변형의 밑변이 9센티미터(㎝)입니다. 평행사변형의 높이는 얼마입니까?",
        "question_en": "A parallelogram with an area of 33.3 square centimeters (cm2) has a base of 9 centimeters (cm). What is the height of the parallelogram?",
        "answer_ko": "3.70",
        "answer_en": "3.7",
        "solution_abst_ko": "33.3 9 [OP_DIV]",
        "solution_abst_en": "33.3 9 [OP_DIV]",
        "solution_code_ko": "var_a = 33.3\nvar_b = 9\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 33.3\nvar_b = 9\nvar_c = var_a / var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "7907": {
        "category": "Geometry",
        "question_ko": "부피가 8세제곱센티미터(㎤)인 주사위의 한 모서리의 길이는 몇 밀리미터(㎜)입니까?",
        "question_en": "How many millimeters (mm) is the length of one edge of a dice with a volume of 8 cubic centimeters (cm3)?",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "8 1/3 [OP_POW] 10 [OP_MUL]",
        "solution_abst_en": "8 1/3 [OP_POW] 10 [OP_MUL]",
        "solution_code_ko": "var_a = 8\nvar_b = 0.3333333333333333\nvar_c = var_a ** var_b\nvar_d = 10\nvar_e = var_c * var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 8\nvar_b = 0.3333333333333333\nvar_c = var_a ** var_b\nvar_d = 10\nvar_e = var_c * var_d\nprint(int(var_e))"
    },
    "7908": {
        "category": "Correspondence",
        "question_ko": "8A19를 반올림하여 백의 자리까지 나타내면 8500입니다. A를 구하시오",
        "question_en": "8500 is 8A19 rounded to the hundred place. Find the value of A.",
        "answer_ko": "5",
        "answer_en": "5",
        "solution_abst_ko": "8A19 [OP_GEN_POSSIBLE_LIST] 8500 50 [OP_SUB] [OP_LIST_MORE_EQUAL] 8500 50 [OP_ADD] [OP_LIST_LESS] 8A19 A [OP_LIST_FIND_UNK]",
        "solution_abst_en": "8A19 [OP_GEN_POSSIBLE_LIST] 8500 50 [OP_SUB] [OP_LIST_MORE_EQUAL] 8500 50 [OP_ADD] [OP_LIST_LESS] 8A19 A [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = '8A19'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 8500\nvar_c = 50\nvar_d = var_b - var_c\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nvar_e = 8500\nvar_f = 50\nvar_g = var_e + var_f\nlist_c = []\nfor i in list_b:\n    if i < var_g:\n        list_c.append(i)\nvar_h = '8A19'\nvar_i = 'A'\nvar_h = str(var_h)\nvar_i = str(var_i)\nunk_idx = var_h.index(var_i)\nvar_j = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_j = int(elem[unk_idx])\nprint(int(var_j))",
        "solution_code_en": "var_a = '8A19'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 8500\nvar_c = 50\nvar_d = var_b - var_c\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nvar_e = 8500\nvar_f = 50\nvar_g = var_e + var_f\nlist_c = []\nfor i in list_b:\n    if i < var_g:\n        list_c.append(i)\nvar_h = '8A19'\nvar_i = 'A'\nvar_h = str(var_h)\nvar_i = str(var_i)\nunk_idx = var_h.index(var_i)\nvar_j = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_j = int(elem[unk_idx])\nprint(int(var_j))"
    },
    "7909": {
        "category": "Comparison",
        "question_ko": "윤기는 사과를 4개를 가지고 있고, 6개의 사과를 가지고 있던 정국이는 3개의 사과를 더 받았습니다. 유나는 5개의 사과를 가지고 있을 때, 누가 가장 사과를 적게 가지고 있습니까?",
        "question_en": "Yoongi has 4 apples, and Jungkook, who had 6 apples, got 3 more. When Yuna has 5 apples, who has the fewest apples?",
        "answer_ko": "윤기",
        "answer_en": "Yoongi",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 유나 [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_ADD] 5 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook Yuna [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_ADD] 5 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nvar_c = '유나'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 6\nvar_f = 3\nvar_g = var_e + var_f\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nvar_c = 'Yuna'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 6\nvar_f = 3\nvar_g = var_e + var_f\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[var_i-1]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "7910": {
        "category": "Geometry",
        "question_ko": "8.5센티미터(㎝)의 나무 판자 2장과 7.8센티미터(㎝)의 나무 판자 두 장을 겹치는 부분이 5밀리미터(㎜)가 되도록 연결했을 때, 나무 판자의 전체 길이는 몇 센티미터(㎝)가 되는지 구하시오.",
        "question_en": "If two 8.5 centimeters (cm) wooden planks and two 7.8 centimeters (cm) wooden planks are connected so that the overlapping part is 5 millimeters (mm), calculate how many centimeters (cm) the overall length of the planks will be.",
        "answer_ko": "31.10",
        "answer_en": "31.1",
        "solution_abst_ko": "8.5 2 [OP_MUL] 7.8 2 [OP_MUL] [OP_ADD] 5 10 [OP_DIV] 3 [OP_MUL] [OP_SUB]",
        "solution_abst_en": "8.5 2 [OP_MUL] 7.8 2 [OP_MUL] [OP_ADD] 5 10 [OP_DIV] 3 [OP_MUL] [OP_SUB]",
        "solution_code_ko": "var_a = 8.5\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 7.8\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 5\nvar_i = 10\nvar_j = var_h / var_i\nvar_k = 3\nvar_l = var_j * var_k\nvar_m = var_g - var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))",
        "solution_code_en": "var_a = 8.5\nvar_b = 2\nvar_c = var_a * var_b\nvar_d = 7.8\nvar_e = 2\nvar_f = var_d * var_e\nvar_g = var_c + var_f\nvar_h = 5\nvar_i = 10\nvar_j = var_h / var_i\nvar_k = 3\nvar_l = var_j * var_k\nvar_m = var_g - var_l\nprint('{:.2f}'.format(round(var_m+1e-10,2)))"
    },
    "7911": {
        "category": "Comparison",
        "question_ko": "정국 앞에 사람들이 2줄을 서고, 정국 뒤에 4줄을 서고, 각 줄마다 서있는 사람의 수가 8명으로 같다고 할 때, 서 있는 사람들은 모두 몇 명입니까?",
        "question_en": "If there are 2 lines of people in front of Jungkook and 4 lines behind Jungkook, and the number of people standing in each line is equal to 8, how many people are standing in all?",
        "answer_ko": "56",
        "answer_en": "56",
        "solution_abst_ko": "2 4 [OP_ADD] 1 [OP_ADD] 8 [OP_MUL]",
        "solution_abst_en": "2 4 [OP_ADD] 1 [OP_ADD] 8 [OP_MUL]",
        "solution_code_ko": "var_a = 2\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e * var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 2\nvar_b = 4\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = var_c + var_d\nvar_f = 8\nvar_g = var_e * var_f\nprint(int(var_g))"
    },
    "7912": {
        "category": "Possibility",
        "question_ko": "2, 3, 5, 7 중 서로 다른 3개의 숫자로 1000이하, 100이상의 숫자를 만들 때 3과 5로 나누어 떨어지는 모든 수의 합을 수하시오.",
        "question_en": "Find the sum of all the numbers that are divisible by 3 and 5 when 3 different numbers, 2, 3, 5, and 7, are used to make a number less than or equal to 1000 and greater than 100.",
        "answer_ko": "1110",
        "answer_en": "1110",
        "solution_abst_ko": "[OP_LIST_SOL] 2 5 3 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] [OP_LIST_SUM]",
        "solution_abst_en": "[OP_LIST_SOL] 2 5 3 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] [OP_LIST_SUM]",
        "solution_code_ko": "var_a = 2\nvar_b = 5\nvar_c = 3\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c = []\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nvar_g = 5\nlist_d = []\nvar_g = int(var_g)\nfor i in list_c:\n    i = int(i)\n    if i % var_g == 0:\n        list_d.append(i)\nlist_d = [float(i) for i in list_d]\nvar_h = sum(list_d)\nprint(int(var_h))",
        "solution_code_en": "var_a = 2\nvar_b = 5\nvar_c = 3\nvar_d = 7\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.permutations(list_b, var_e))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_f = 3\nlist_c = []\nvar_f = int(var_f)\nfor i in list_b:\n    i = int(i)\n    if i % var_f == 0:\n        list_c.append(i)\nvar_g = 5\nlist_d = []\nvar_g = int(var_g)\nfor i in list_c:\n    i = int(i)\n    if i % var_g == 0:\n        list_d.append(i)\nlist_d = [float(i) for i in list_d]\nvar_h = sum(list_d)\nprint(int(var_h))"
    },
    "7913": {
        "category": "Arithmetic calculation",
        "question_ko": "수도꼭지에서 시간 당 10.8리터(L)씩 물이 흘러나온다. 수도꼭지를 1시간 24분 동안 열어 두었다면 몇 리터(L)의 물이 흘러나왔는지 구하시오.",
        "question_en": "Water flows out of the faucet at a rate of 10.8 liters (l) per hour. If you left the tap open for 1 hour and 24 minutes, find how many liters (L) of water flowed out.",
        "answer_ko": "15.12",
        "answer_en": "15.12",
        "solution_abst_ko": "10.8 1 24 60 [OP_DIV] [OP_ADD] [OP_MUL]",
        "solution_abst_en": "10.8 1 24 60 [OP_DIV] [OP_ADD] [OP_MUL]",
        "solution_code_ko": "var_a = 10.8\nvar_b = 1\nvar_c = 24\nvar_d = 60\nvar_e = var_c / var_d\nvar_f = var_b + var_e\nvar_g = var_a * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))",
        "solution_code_en": "var_a = 10.8\nvar_b = 1\nvar_c = 24\nvar_d = 60\nvar_e = var_c / var_d\nvar_f = var_b + var_e\nvar_g = var_a * var_f\nprint('{:.2f}'.format(round(var_g+1e-10,2)))"
    },
    "7914": {
        "category": "Comparison",
        "question_ko": "윤기가 가진 사과가 4개, 정국이는 6개의 사과를 가지고 있었지만 3개를 먹었습니다. 유나가 가진 사과가 5개라면 누가 가장 많은 사과를 가지고 있나요?",
        "question_en": "Yoongi has 4 apples and Jungkook had 6 apples, but he ate 3. If Yuna has 5 apples, who has the most apples?",
        "answer_ko": "유나",
        "answer_en": "Yuna",
        "solution_abst_ko": "[OP_LIST_SOL] 윤기 정국 유나 [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_SUB] 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Yoongi Jungkook Yuna [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_SUB] 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '윤기'\nvar_b = '정국'\nvar_c = '유나'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 6\nvar_f = 3\nvar_g = var_e - var_f\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)",
        "solution_code_en": "var_a = 'Yoongi'\nvar_b = 'Jungkook'\nvar_c = 'Yuna'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 4\nvar_e = 6\nvar_f = 3\nvar_g = var_e - var_f\nvar_h = 5\nlist_b= []\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nlist_b.reverse()\nvar_i = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_j = list_c[-var_i]\nvar_k = list_b.index(var_j)+1\nvar_l = list_a[var_k-1]\nprint(var_l)"
    },
    "7915": {
        "category": "Arithmetic calculation",
        "question_ko": "3개의 수 10, 11, 12가 있습니다. 그 중에서 3번째로 작은 수와 2번째로 작은 수의 합은 얼마입니까?",
        "question_en": "There are three numbers 10, 11 and 12. What is the sum of the 3rd and 2nd smallest numbers?",
        "answer_ko": "23",
        "answer_en": "23",
        "solution_abst_ko": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 3 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_abst_en": "[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 3 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_ADD]",
        "solution_code_ko": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e + var_g\nprint(int(var_h))",
        "solution_code_en": "var_a = 10\nvar_b = 11\nvar_c = 12\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 3\nlist_b=list_a.copy()\nlist_b.sort()\nvar_e = list_b[var_d-1]\nvar_f = 2\nlist_c=list_a.copy()\nlist_c.sort()\nvar_g = list_c[var_f-1]\nvar_h = var_e + var_g\nprint(int(var_h))"
    },
    "7916": {
        "category": "Correspondence",
        "question_ko": "어떤 수는 50보다 크고 70보다 작습니다. 또한 이 수는 5로 나누었을 때 나머지가 3이고 7로 나누었을 때 나머지가 2이고 8로 나누었을 때 나머지가 2입니다. 이 수는 무엇입니까?",
        "question_en": "There is a number that is greater than 50 and less than 70. Also, this number has a remainder of 3 when divided by 5, a remainder of 2 when divided by 7, and a remainder of 2 when divided by 8. What is this number?",
        "answer_ko": "58",
        "answer_en": "58",
        "solution_abst_ko": "50 70 1 [OP_SUB] 1 [OP_LIST_ARANGE] 5 3 [OP_LIST_DIVIDE_AND_REMAIN] 7 2 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "50 70 1 [OP_SUB] 1 [OP_LIST_ARANGE] 5 3 [OP_LIST_DIVIDE_AND_REMAIN] 7 2 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 50\nvar_b = 70\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nvar_f = 5\nvar_g = 3\nlist_b = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_a:\n    i = int(i)\n    if i%var_f == var_g:\n        list_b.append(i)\nvar_h = 7\nvar_i = 2\nlist_c = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_b:\n    i = int(i)\n    if i%var_h == var_i:\n        list_c.append(i)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(int(var_k))",
        "solution_code_en": "var_a = 50\nvar_b = 70\nvar_c = 1\nvar_d = var_b - var_c\nvar_e = 1\nlist_a = [i for i in range(var_a, var_d + 1, var_e)]\nvar_f = 5\nvar_g = 3\nlist_b = [] \nvar_f = int(var_f)\nvar_g = int(var_g)\nif var_g < 0:\n    var_g = var_g + var_f\nfor i in list_a:\n    i = int(i)\n    if i%var_f == var_g:\n        list_b.append(i)\nvar_h = 7\nvar_i = 2\nlist_c = [] \nvar_h = int(var_h)\nvar_i = int(var_i)\nif var_i < 0:\n    var_i = var_i + var_h\nfor i in list_b:\n    i = int(i)\n    if i%var_h == var_i:\n        list_c.append(i)\nvar_j = 1\nvar_k = list_c[var_j-1]\nprint(int(var_k))"
    },
    "7917": {
        "category": "Comparison",
        "question_ko": "270쪽의 책이 있습니다. 건영이는 하루 동안 전체의 1/3을 읽었고, 수환이는 전체의 4/9를 읽었다면, 하루 동안 책을 더 많이 읽은 사람은 누구인지 구하시오.",
        "question_en": "There is a book of 270 pages. If Kunyoung read 1/3 of the total in one day and Suhwan read 4/9 of the total, find out who read more books in a day.",
        "answer_ko": "수환",
        "answer_en": "Suhwan",
        "solution_abst_ko": "[OP_LIST_SOL] 건영 수환 [OP_LIST_EOL] [OP_LIST_SOL] 1/3 4/9 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] Kunyoung Suhwan [OP_LIST_EOL] [OP_LIST_SOL] 1/3 4/9 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]",
        "solution_code_ko": "var_a = '건영'\nvar_b = '수환'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.3333333333333333\nvar_d = 0.4444444444444444\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)",
        "solution_code_en": "var_a = 'Kunyoung'\nvar_b = 'Suhwan'\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 0.3333333333333333\nvar_d = 0.4444444444444444\nlist_b= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_b.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_b.append(var_c)\nlist_b.reverse()\nvar_e = 1\nlist_c=list_b.copy()\nlist_c.sort()\nvar_f = list_c[-var_e]\nvar_g = list_b.index(var_f)+1\nvar_h = list_a[var_g-1]\nprint(var_h)"
    },
    "7918": {
        "category": "Arithmetic calculation",
        "question_ko": "기차에 78명이 타고 있었습니다. 이 중에서 27명이 내리고 몇 명이 타서 63명이 되었습니다. 기차에 탄 사람은 몇 명입니까?",
        "question_en": "There were 78 people on the train. Of these, 27 got off and a few got on, making the total people in the train to 63. How many people got on the train?",
        "answer_ko": "12",
        "answer_en": "12",
        "solution_abst_ko": "63 27 [OP_ADD] 78 [OP_SUB]",
        "solution_abst_en": "63 27 [OP_ADD] 78 [OP_SUB]",
        "solution_code_ko": "var_a = 63\nvar_b = 27\nvar_c = var_a + var_b\nvar_d = 78\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 63\nvar_b = 27\nvar_c = var_a + var_b\nvar_d = 78\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "7919": {
        "category": "Correspondence",
        "question_ko": "숫자 32BA33이 있습니다. 이 숫자를 반올림 하여 백의 자리까지 나타내면 323400입니다. A는 무엇입니까?",
        "question_en": "There is a number 32BA33. If this number is rounded to the nearest hundred, it is 323400. What is A?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "32BA33 [OP_GEN_POSSIBLE_LIST] 323400 50 [OP_SUB] [OP_LIST_MORE_EQUAL] 323400 50 [OP_ADD] [OP_LIST_LESS] 32BA33 A [OP_LIST_FIND_UNK]",
        "solution_abst_en": "32BA33 [OP_GEN_POSSIBLE_LIST] 323400 50 [OP_SUB] [OP_LIST_MORE_EQUAL] 323400 50 [OP_ADD] [OP_LIST_LESS] 32BA33 A [OP_LIST_FIND_UNK]",
        "solution_code_ko": "var_a = '32BA33'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 323400\nvar_c = 50\nvar_d = var_b - var_c\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nvar_e = 323400\nvar_f = 50\nvar_g = var_e + var_f\nlist_c = []\nfor i in list_b:\n    if i < var_g:\n        list_c.append(i)\nvar_h = '32BA33'\nvar_i = 'A'\nvar_h = str(var_h)\nvar_i = str(var_i)\nunk_idx = var_h.index(var_i)\nvar_j = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_j = int(elem[unk_idx])\nprint(int(var_j))",
        "solution_code_en": "var_a = '32BA33'\nans_dict = dict()\nvar_a = str(var_a)\nlist_a = []\nvariable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])\nfor v in set(var_a):\n    if v in variable_candi:\n        ans_dict[v] = 0\ncandi = list(itertools.product('0123456789', repeat=len(ans_dict)))\nfor c in candi:\n    temp = var_a\n    for i, (k, _) in enumerate(ans_dict.items()):\n        temp = temp.replace(k, str(c[i]))\n    if len(var_a) == len(str(int(temp))):\n        new_elem = int(temp)\n        list_a.append(new_elem)\nvar_b = 323400\nvar_c = 50\nvar_d = var_b - var_c\nlist_b = []\nfor i in list_a:\n    if i >= var_d:\n        list_b.append(i)\nvar_e = 323400\nvar_f = 50\nvar_g = var_e + var_f\nlist_c = []\nfor i in list_b:\n    if i < var_g:\n        list_c.append(i)\nvar_h = '32BA33'\nvar_i = 'A'\nvar_h = str(var_h)\nvar_i = str(var_i)\nunk_idx = var_h.index(var_i)\nvar_j = 0\nfor elem in list_c:\n    elem = str(elem)\n    var_j = int(elem[unk_idx])\nprint(int(var_j))"
    },
    "7920": {
        "category": "Arithmetic calculation",
        "question_ko": "5/6과 19/12가 있습니다. 이들을 모두 더하면 얼마인가요?",
        "question_en": "There are 5/6 and 19/12. What is the sum of them?",
        "answer_ko": "2.42",
        "answer_en": "2.42",
        "solution_abst_ko": "5/6 19/12 [OP_ADD]",
        "solution_abst_en": "5/6 19/12 [OP_ADD]",
        "solution_code_ko": "var_a = 0.8333333333333334\nvar_b = 1.5833333333333333\nvar_c = var_a + var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))",
        "solution_code_en": "var_a = 0.8333333333333334\nvar_b = 1.5833333333333333\nvar_c = var_a + var_b\nprint('{:.2f}'.format(round(var_c+1e-10,2)))"
    },
    "7921": {
        "category": "Geometry",
        "question_ko": "직육면체의 한 점에서 만나는 면의 개수를 구하시오.",
        "question_en": "Find the number of faces of a cuboid that meet at a vertex.",
        "answer_ko": "3",
        "answer_en": "3",
        "solution_abst_ko": "3",
        "solution_abst_en": "3",
        "solution_code_ko": "var_a = 3\nprint(int(var_a))",
        "solution_code_en": "var_a = 3\nprint(int(var_a))"
    },
    "7922": {
        "category": "Comparison",
        "question_ko": "수 5개 1.4, 9/10, 1.2, 0.5, 13/10 중 1.1보다 작거나 같은 숫자를 구하면, 몇 개인가요?",
        "question_en": "Out of 5 numbers: 1.4, 9/10, 1.2, 0.5, 13/10, how many are less than or equal to 1.1?",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i <= var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))",
        "solution_code_en": "var_a = 1.4\nvar_b = 0.9\nvar_c = 1.2\nvar_d = 0.5\nvar_e = 1.3\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_f = 1.1\nlist_b = []\nfor i in list_a:\n    if i <= var_f:\n        list_b.append(i)\nvar_g = len(list_b)\nprint(int(var_g))"
    },
    "7923": {
        "category": "Correspondence",
        "question_ko": "어떤 수에 12를 더한 뒤 4로 나누었더니 몫이 12이고 나머지가 3이 되었습니다. 어떤 수에 12를 더하고 4를 곱한 값을 구하시오.",
        "question_en": "When you add 12 to a number and divide it by 4, the quotient is 12 and the remainder is 3. Add 12 to that number in question and multiply it by 4 to find the value.",
        "answer_ko": "204",
        "answer_en": "204",
        "solution_abst_ko": "12 4 [OP_MUL] 3 [OP_ADD] 12 [OP_SUB] 12 [OP_ADD] 4 [OP_MUL]",
        "solution_abst_en": "12 4 [OP_MUL] 3 [OP_ADD] 12 [OP_SUB] 12 [OP_ADD] 4 [OP_MUL]",
        "solution_code_ko": "var_a = 12\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = 12\nvar_g = var_e - var_f\nvar_h = 12\nvar_i = var_g + var_h\nvar_j = 4\nvar_k = var_i * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 12\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 3\nvar_e = var_c + var_d\nvar_f = 12\nvar_g = var_e - var_f\nvar_h = 12\nvar_i = var_g + var_h\nvar_j = 4\nvar_k = var_i * var_j\nprint(int(var_k))"
    },
    "7924": {
        "category": "Comparison",
        "question_ko": "엄마, 아빠, 할아버지가 백화점에서 옷을 구매했습니다. 엄마보다 아빠가 옷을 더 많이 샀고, 아빠보다 할아버지가 옷을 더 많이 샀습니다. 엄마는 몇 번째로 옷을 적게 샀습니까?",
        "question_en": "Mom, Dad, and Grandpa bought clothes at the department store. Dad bought more clothes than Mom, and Grandpa bought more clothes than Dad. If you lined up people based on the number of clothes they bought in ascending order, in what position will Mom be? Please answer using an natural number.",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "[OP_LIST_SOL] 엄마 아빠 할아버지 [OP_LIST_EOL] 엄마 [OP_LIST_INDEX]",
        "solution_abst_en": "[OP_LIST_SOL] Mom Dad Grandpa [OP_LIST_EOL] Mom [OP_LIST_INDEX]",
        "solution_code_ko": "var_a = '엄마'\nvar_b = '아빠'\nvar_c = '할아버지'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = '엄마'\nvar_e = list_a.index(var_d)+1\nprint(int(var_e))",
        "solution_code_en": "var_a = 'Mom'\nvar_b = 'Dad'\nvar_c = 'Grandpa'\nlist_a= []\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_d = 'Mom'\nvar_e = list_a.index(var_d)+1\nprint(int(var_e))"
    },
    "7925": {
        "category": "Geometry",
        "question_ko": "넓이가 6제곱미터(㎡)인 직사각형의 가로의 길이가 150센티미터(㎝)이면, 세로의 길이는 몇 센티미터(㎝)입니까?",
        "question_en": "If the width of a rectangle with an area of 6 square meters (m2) is 150 centimeters (cm), what is the length in centimeters (cm)?",
        "answer_ko": "400",
        "answer_en": "400",
        "solution_abst_ko": "6 100 2 [OP_POW] [OP_MUL] 150 [OP_DIV]",
        "solution_abst_en": "6 100 2 [OP_POW] [OP_MUL] 150 [OP_DIV]",
        "solution_code_ko": "var_a = 6\nvar_b = 100\nvar_c = 2\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 150\nvar_g = var_e / var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 6\nvar_b = 100\nvar_c = 2\nvar_d = var_b ** var_c\nvar_e = var_a * var_d\nvar_f = 150\nvar_g = var_e / var_f\nprint(int(var_g))"
    },
    "7926": {
        "category": "Possibility",
        "question_ko": "사과, 복숭아, 배, 참외를 2개의 과일 바구니에 나누어 담으려고 합니다. 가능한 경우의 수는 모두 몇 가지입니까?",
        "question_en": "We are going to divide Apples, Peaches, Pears, and Melons into two fruit baskets. How many possible cases are there?",
        "answer_ko": "16",
        "answer_en": "16",
        "solution_abst_ko": "2 [OP_LIST_SOL] 사과 복숭아 배 참외 [OP_LIST_EOL] [OP_LIST_LEN] [OP_POW]",
        "solution_abst_en": "2 [OP_LIST_SOL] Apple Peach Pear Melon [OP_LIST_EOL] [OP_LIST_LEN] [OP_POW]",
        "solution_code_ko": "var_a = 2\nvar_b = '사과'\nvar_c = '복숭아'\nvar_d = '배'\nvar_e = '참외'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = var_a ** var_f\nprint(int(var_g))",
        "solution_code_en": "var_a = 2\nvar_b = 'Apple'\nvar_c = 'Peach'\nvar_d = 'Pear'\nvar_e = 'Melon'\nlist_a= []\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_a.append(var_e)\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nlist_a.reverse()\nvar_f = len(list_a)\nvar_g = var_a ** var_f\nprint(int(var_g))"
    },
    "7927": {
        "category": "Possibility",
        "question_ko": "여학생 2명, 남학생 3명을 한 줄로 세울 때, 여학생끼리는 반드시 이웃하게 세우는 경우의 수를 구하시오.",
        "question_en": "When 2 female students and 3 male students are lined up in a row, find the number of cases where the female students must stand next to each other.",
        "answer_ko": "48",
        "answer_en": "48",
        "solution_abst_ko": "1 3 [OP_ADD] 1 3 [OP_ADD] [OP_PERM] 2 2 [OP_PERM] [OP_MUL]",
        "solution_abst_en": "1 3 [OP_ADD] 1 3 [OP_ADD] [OP_PERM] 2 2 [OP_PERM] [OP_MUL]",
        "solution_code_ko": "var_a = 1\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = 1\nvar_c = int(var_c)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_c-i)\nvar_h = 2\nvar_i = 2\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nvar_k = var_g * var_j\nprint(int(var_k))",
        "solution_code_en": "var_a = 1\nvar_b = 3\nvar_c = var_a + var_b\nvar_d = 1\nvar_e = 3\nvar_f = var_d + var_e\nvar_g = 1\nvar_c = int(var_c)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_c-i)\nvar_h = 2\nvar_i = 2\nvar_j = 1\nvar_h = int(var_h)\nvar_i = int(var_i)\nfor i, elem in enumerate(range(var_i)):\n    var_j = var_j * (var_h-i)\nvar_k = var_g * var_j\nprint(int(var_k))"
    },
    "7928": {
        "category": "Possibility",
        "question_ko": "서로 다른 다섯 명의 사람 중 회장 1명과 총무 1명을 뽑는 경우의 수를 구하시오.",
        "question_en": "Find the number of ways in which one president and one secretary are selected from five different people.",
        "answer_ko": "20",
        "answer_en": "20",
        "solution_abst_ko": "5 1 1 [OP_ADD] [OP_PERM]",
        "solution_abst_en": "5 1 1 [OP_ADD] [OP_PERM]",
        "solution_code_ko": "var_a = 5\nvar_b = 1\nvar_c = 1\nvar_d = var_b + var_c\nvar_e = 1\nvar_a = int(var_a)\nvar_d = int(var_d)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e * (var_a-i)\nprint(int(var_e))",
        "solution_code_en": "var_a = 5\nvar_b = 1\nvar_c = 1\nvar_d = var_b + var_c\nvar_e = 1\nvar_a = int(var_a)\nvar_d = int(var_d)\nfor i, elem in enumerate(range(var_d)):\n    var_e = var_e * (var_a-i)\nprint(int(var_e))"
    },
    "7929": {
        "category": "Arithmetic calculation",
        "question_ko": "길이가 60미터(m)인 끈을 0.6미터(m)씩 모두 자르려고 합니다. 끈을 모두 몇 개로 자를 수 있습니까?",
        "question_en": "You want to cut a string that is 60 meters (m) long into 0.6 meters (m) each. How many pieces of string can you cut in total?",
        "answer_ko": "100",
        "answer_en": "100",
        "solution_abst_ko": "60 0.6 [OP_FDIV]",
        "solution_abst_en": "60 0.6 [OP_FDIV]",
        "solution_code_ko": "var_a = 60\nvar_b = 0.6\nvar_c = var_a // var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 60\nvar_b = 0.6\nvar_c = var_a // var_b\nprint(int(var_c))"
    },
    "7930": {
        "category": "Geometry",
        "question_ko": "어떤 정사각형의 네 변을 각각 둘로 나눈 점들을 이어 마름모를 만들었습니다. 어떤 정사각형의 변의 길이가 4센티미터(㎝)라고 할 때, 마름모의 넓이는 몇 제곱센티미터(㎠)입니까?",
        "question_en": "A rhombus is formed by joining the points that divide each of the four sides of a square into two halves. If the side of a square is 4 centimeters (cm), what is the area of the rhombus in square centimeters (cm2)?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "4 4 [OP_MUL] 2 [OP_DIV]",
        "solution_abst_en": "4 4 [OP_MUL] 2 [OP_DIV]",
        "solution_code_ko": "var_a = 4\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 4\nvar_b = 4\nvar_c = var_a * var_b\nvar_d = 2\nvar_e = var_c / var_d\nprint(int(var_e))"
    },
    "7931": {
        "category": "Comparison",
        "question_ko": "상점에서 보석 A, B, C, D를 팔고 있습니다. A는 D보다 비싸고, B는 A보다 비쌉니다. C가 가장 쌀 때, 가장 비싼 보석은 무엇인가요?",
        "question_en": "The shop sells gems A, B, C, and D. A is more expensive than D, and B is more expensive than A. When C is the cheapest, which gem is the most expensive?",
        "answer_ko": "B",
        "answer_en": "B",
        "solution_abst_ko": "[OP_LIST_SOL] A B C D [OP_LIST_EOL] [OP_LIST_SOL] A D > B A > C A < C B < C D < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_abst_en": "[OP_LIST_SOL] A B C D [OP_LIST_EOL] [OP_LIST_SOL] A D > B A > C A < C B < C D < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]",
        "solution_code_ko": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'A'\nvar_f = 'D'\nvar_g = '>'\nvar_h = 'B'\nvar_i = 'A'\nvar_j = '>'\nvar_k = 'C'\nvar_l = 'A'\nvar_m = '<'\nvar_n = 'C'\nvar_o = 'B'\nvar_p = '<'\nvar_q = 'C'\nvar_r = 'D'\nvar_s = '<'\nlist_b= []\nif \"/\" in str(var_s):\n    var_s = eval(str(var_s))\nlist_b.append(var_s)\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_t = 1\nvar_u = list_c[var_t-1]\nprint(var_u)",
        "solution_code_en": "var_a = 'A'\nvar_b = 'B'\nvar_c = 'C'\nvar_d = 'D'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = 'A'\nvar_f = 'D'\nvar_g = '>'\nvar_h = 'B'\nvar_i = 'A'\nvar_j = '>'\nvar_k = 'C'\nvar_l = 'A'\nvar_m = '<'\nvar_n = 'C'\nvar_o = 'B'\nvar_p = '<'\nvar_q = 'C'\nvar_r = 'D'\nvar_s = '<'\nlist_b= []\nif \"/\" in str(var_s):\n    var_s = eval(str(var_s))\nlist_b.append(var_s)\nif \"/\" in str(var_r):\n    var_r = eval(str(var_r))\nlist_b.append(var_r)\nif \"/\" in str(var_q):\n    var_q = eval(str(var_q))\nlist_b.append(var_q)\nif \"/\" in str(var_p):\n    var_p = eval(str(var_p))\nlist_b.append(var_p)\nif \"/\" in str(var_o):\n    var_o = eval(str(var_o))\nlist_b.append(var_o)\nif \"/\" in str(var_n):\n    var_n = eval(str(var_n))\nlist_b.append(var_n)\nif \"/\" in str(var_m):\n    var_m = eval(str(var_m))\nlist_b.append(var_m)\nif \"/\" in str(var_l):\n    var_l = eval(str(var_l))\nlist_b.append(var_l)\nif \"/\" in str(var_k):\n    var_k = eval(str(var_k))\nlist_b.append(var_k)\nif \"/\" in str(var_j):\n    var_j = eval(str(var_j))\nlist_b.append(var_j)\nif \"/\" in str(var_i):\n    var_i = eval(str(var_i))\nlist_b.append(var_i)\nif \"/\" in str(var_h):\n    var_h = eval(str(var_h))\nlist_b.append(var_h)\nif \"/\" in str(var_g):\n    var_g = eval(str(var_g))\nlist_b.append(var_g)\nif \"/\" in str(var_f):\n    var_f = eval(str(var_f))\nlist_b.append(var_f)\nif \"/\" in str(var_e):\n    var_e = eval(str(var_e))\nlist_b.append(var_e)\nlist_b.reverse()\nglobal item_name_index_dict\nitems_name_list = list_a.copy()\nconditions = []\ncondition_list = list_b.copy()\ntemp_stack = []\nfor index_, cond_ in enumerate(map(str, condition_list)):\n    if cond_ in (\"<\", \">\", \"=\"):\n        operand_right = temp_stack.pop()\n        operand_left = temp_stack.pop()\n        if cond_ == \"=\":\n            cond_ = \"==\"\n        conditions.append(f\"{operand_left} {cond_} {operand_right}\")\n    else:\n        if not cond_.isdigit():\n            cond_ = \"{\" + cond_ + \"}\"\n        temp_stack.append(cond_)\nitem_name_index_dict = {}\nfor perm in itertools.permutations(range(1, len(items_name_list) + 1)):\n    item_name_index_dict = dict(zip(items_name_list, perm))\n    formatted_conditions = \\\n        [condition.format_map(item_name_index_dict) for condition in conditions]\n    if all(map(eval, formatted_conditions)):\n        break\nlist_c = list(item_name_index_dict.keys())\nlist_c.sort(key=item_name_index_dict.get, reverse=True)\nvar_t = 1\nvar_u = list_c[var_t-1]\nprint(var_u)"
    },
    "7932": {
        "category": "Correspondence",
        "question_ko": "31은 어떤수에서 13을 뺀 숫자입니다. 어떤 수에서 11을 더하면 얼마입니까?",
        "question_en": "31 is the result of subtracting 13 from a number. What is this number when 11 is added?",
        "answer_ko": "55",
        "answer_en": "55",
        "solution_abst_ko": "31 13 [OP_ADD] 11 [OP_ADD]",
        "solution_abst_en": "31 13 [OP_ADD] 11 [OP_ADD]",
        "solution_code_ko": "var_a = 31\nvar_b = 13\nvar_c = var_a + var_b\nvar_d = 11\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 31\nvar_b = 13\nvar_c = var_a + var_b\nvar_d = 11\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7933": {
        "category": "Possibility",
        "question_ko": "A에는 1부터 9까지의 자연수가 들어갈 수 있습니다. 57×7>65×A일 때, A에 들어갈 수 있는 수는 모두 몇 개입니까?",
        "question_en": "A can contain natural numbers from 1 to 9. If 57×7>65×A, how many numbers can fit in A?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "1 9 1 [OP_LIST_ARANGE] 57 7 [OP_MUL] 65 [OP_DIV] [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_abst_en": "1 9 1 [OP_LIST_ARANGE] 57 7 [OP_MUL] 65 [OP_DIV] [OP_LIST_LESS] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 57\nvar_e = 7\nvar_f = var_d * var_e\nvar_g = 65\nvar_h = var_f / var_g\nlist_b = []\nfor i in list_a:\n    if i < var_h:\n        list_b.append(i)\nvar_i = len(list_b)\nprint(int(var_i))",
        "solution_code_en": "var_a = 1\nvar_b = 9\nvar_c = 1\nlist_a = [i for i in range(var_a, var_b + 1, var_c)]\nvar_d = 57\nvar_e = 7\nvar_f = var_d * var_e\nvar_g = 65\nvar_h = var_f / var_g\nlist_b = []\nfor i in list_a:\n    if i < var_h:\n        list_b.append(i)\nvar_i = len(list_b)\nprint(int(var_i))"
    },
    "7934": {
        "category": "Possibility",
        "question_ko": "혜정이는 TV, 냉장고, 세탁기, 컴퓨터 중에서 한 가지 제품을 교체하려고 한다. 혜정이가 교체할 수 있는 한 가지 제품을 선택하는 경우의 수는?",
        "question_en": "Hyejeong wants to replace one product out of the TV, refrigerator, washer, and computer. How many ways are there for Hyejeong to choose one product to replace?",
        "answer_ko": "4",
        "answer_en": "4",
        "solution_abst_ko": "[OP_LIST_SOL] TV 냉장고 세탁기 컴퓨터 [OP_LIST_EOL] [OP_LIST_LEN] 1 [OP_COMB]",
        "solution_abst_en": "[OP_LIST_SOL] TV refrigerator washer computer [OP_LIST_EOL] [OP_LIST_LEN] 1 [OP_COMB]",
        "solution_code_ko": "var_a = 'TV'\nvar_b = '냉장고'\nvar_c = '세탁기'\nvar_d = '컴퓨터'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 1\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g / (i+1)\nprint(int(var_g))",
        "solution_code_en": "var_a = 'TV'\nvar_b = 'refrigerator'\nvar_c = 'washer'\nvar_d = 'computer'\nlist_a= []\nif \"/\" in str(var_d):\n    var_d = eval(str(var_d))\nlist_a.append(var_d)\nif \"/\" in str(var_c):\n    var_c = eval(str(var_c))\nlist_a.append(var_c)\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_e = len(list_a)\nvar_f = 1\nvar_g = 1\nvar_e = int(var_e)\nvar_f = int(var_f)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g * (var_e-i)\nfor i, elem in enumerate(range(var_f)):\n    var_g = var_g / (i+1)\nprint(int(var_g))"
    },
    "7935": {
        "category": "Arithmetic calculation",
        "question_ko": "140달러를 우리나라 돈 158760원으로 바꿨을 때 1달러는 우리나라 돈으로 얼마입니까?",
        "question_en": "If you converted $140 to 158760 Korean Won, how much is $1 in Korean Won?",
        "answer_ko": "1134",
        "answer_en": "1134",
        "solution_abst_ko": "158760 140 [OP_DIV]",
        "solution_abst_en": "158760 140 [OP_DIV]",
        "solution_code_ko": "var_a = 158760\nvar_b = 140\nvar_c = var_a / var_b\nprint(int(var_c))",
        "solution_code_en": "var_a = 158760\nvar_b = 140\nvar_c = var_a / var_b\nprint(int(var_c))"
    },
    "7936": {
        "category": "Possibility",
        "question_ko": "각 자리 숫자가 2와 3으로만 이루어진 세 자리 수가 적힌 카드가 있습니다. 가능한 카드의 개수는 모두 몇 개입니까?",
        "question_en": "There is a card with three digits where each digit only consists of numbers 2 and 3. How many possible cards are there?",
        "answer_ko": "8",
        "answer_en": "8",
        "solution_abst_ko": "[OP_LIST_SOL] 2 3 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_LEN]",
        "solution_abst_en": "[OP_LIST_SOL] 2 3 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 2\nvar_b = 3\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = len(list_b)\nprint(int(var_d))",
        "solution_code_en": "var_a = 2\nvar_b = 3\nlist_a= []\nif \"/\" in str(var_b):\n    var_b = eval(str(var_b))\nlist_a.append(var_b)\nif \"/\" in str(var_a):\n    var_a = eval(str(var_a))\nlist_a.append(var_a)\nlist_a.reverse()\nvar_c = 3\nlist_b = [str(i) for i in list_a]\nlist_b = list(itertools.product(list_b, repeat=var_c))\nlist_b = [''.join(num_list) for num_list in list_b]\nlist_b = [str_num for str_num in list_b if str_num[0] != '0']\nlist_b = [float(i) for i in list_b]\nvar_d = len(list_b)\nprint(int(var_d))"
    },
    "7937": {
        "category": "Geometry",
        "question_ko": "직사각형 모양의 휴대폰의 가로가 9센티미터(㎝)이고 둘레가 46센티미터(㎝)이다. 휴대폰의 가로의 길이를 구하시오.",
        "question_en": "The rectangular-shaped cell phone is 9 centimeters (cm) wide and 46 centimeters (cm) in circumference. Find the vertical length of the cell phone.",
        "answer_ko": "14",
        "answer_en": "14",
        "solution_abst_ko": "46 2 [OP_DIV] 9 [OP_SUB]",
        "solution_abst_en": "46 2 [OP_DIV] 9 [OP_SUB]",
        "solution_code_ko": "var_a = 46\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 9\nvar_e = var_c - var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 46\nvar_b = 2\nvar_c = var_a / var_b\nvar_d = 9\nvar_e = var_c - var_d\nprint(int(var_e))"
    },
    "7938": {
        "category": "Possibility",
        "question_ko": "필통 안에 색깔이 모두 다른 색연필이 6자루 있다. 두 개를 뽑아 하나는 앞의 친구에게, 다른 하나는 뒤의 친구에게 빌려줄 때, 가능한 상황은 모두 몇 가지가 있는가?",
        "question_en": "There are 6 colored pencils, all of different colors, in the pencil case. If you draw two and lend one to the friend in front and the other to the friend in the back, how many possible situations are there?",
        "answer_ko": "30",
        "answer_en": "30",
        "solution_abst_ko": "6 2 [OP_PERM]",
        "solution_abst_en": "6 2 [OP_PERM]",
        "solution_code_ko": "var_a = 6\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))",
        "solution_code_en": "var_a = 6\nvar_b = 2\nvar_c = 1\nvar_a = int(var_a)\nvar_b = int(var_b)\nfor i, elem in enumerate(range(var_b)):\n    var_c = var_c * (var_a-i)\nprint(int(var_c))"
    },
    "7939": {
        "category": "Comparison",
        "question_ko": "키가 작은 사람부터 순서대로 9명이 한 줄로 서 있습니다. 호석이가 가장 키가 작습니다. 키가 큰 사람부터 순서대로 다시 줄을 서면 호석이는 뒤에서부터 몇 번째에 서게 됩니까?",
        "question_en": "Nine people are standing in a line in order of height from shortest to tallest. Hoseok is the shortest. If the people line up again in order of height from the tallest to the shortest, in what number from the back will Hoseok stand?",
        "answer_ko": "1",
        "answer_en": "1",
        "solution_abst_ko": "9 9 [OP_SUB] 1 [OP_ADD]",
        "solution_abst_en": "9 9 [OP_SUB] 1 [OP_ADD]",
        "solution_code_ko": "var_a = 9\nvar_b = 9\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))",
        "solution_code_en": "var_a = 9\nvar_b = 9\nvar_c = var_a - var_b\nvar_d = 1\nvar_e = var_c + var_d\nprint(int(var_e))"
    },
    "7940": {
        "category": "Correspondence",
        "question_ko": "1/A=-3, 2/B=4, 3/C=1/2일 때, 6A-8B+C의 값을 구하여라",
        "question_en": "When 1/A=-3, 2/B=4, 3/C=1/2, find the value of 6A-8B+C",
        "answer_ko": "0",
        "answer_en": "0",
        "solution_abst_ko": "6 1 -3 [OP_DIV] [OP_MUL] 8 2 4 [OP_DIV] [OP_MUL] [OP_SUB] 1 3 1/2 [OP_DIV] [OP_MUL] [OP_ADD]",
        "solution_abst_en": "6 1 -3 [OP_DIV] [OP_MUL] 8 2 4 [OP_DIV] [OP_MUL] [OP_SUB] 1 3 1/2 [OP_DIV] [OP_MUL] [OP_ADD]",
        "solution_code_ko": "var_a = 6\nvar_b = 1\nvar_c = -3\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 8\nvar_g = 2\nvar_h = 4\nvar_i = var_g / var_h\nvar_j = var_f * var_i\nvar_k = var_e - var_j\nvar_l = 1\nvar_m = 3\nvar_n = 0.5\nvar_o = var_m / var_n\nvar_p = var_l * var_o\nvar_q = var_k + var_p\nprint(int(var_q))",
        "solution_code_en": "var_a = 6\nvar_b = 1\nvar_c = -3\nvar_d = var_b / var_c\nvar_e = var_a * var_d\nvar_f = 8\nvar_g = 2\nvar_h = 4\nvar_i = var_g / var_h\nvar_j = var_f * var_i\nvar_k = var_e - var_j\nvar_l = 1\nvar_m = 3\nvar_n = 0.5\nvar_o = var_m / var_n\nvar_p = var_l * var_o\nvar_q = var_k + var_p\nprint(int(var_q))"
    },
    "7941": {
        "category": "Possibility",
        "question_ko": "28의 약수는 모두 몇 개인지 구하세요",
        "question_en": "How many divisors are there in 28?",
        "answer_ko": "6",
        "answer_en": "6",
        "solution_abst_ko": "28 [OP_LIST_GET_DIVISOR] [OP_LIST_LEN]",
        "solution_abst_en": "28 [OP_LIST_GET_DIVISOR] [OP_LIST_LEN]",
        "solution_code_ko": "var_a = 28\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = len(list_a)\nprint(int(var_b))",
        "solution_code_en": "var_a = 28\nlist_a = []\nnum_sqrt = int(math.sqrt(var_a))\nfor i in range(1, num_sqrt+1):\n    if var_a % i == 0:\n        list_a.append(i)\n        list_a.append(int(var_a/i))\nlist_a = sorted(set(list_a))\nvar_b = len(list_a)\nprint(int(var_b))"
    },
    "7942": {
        "category": "Geometry",
        "question_ko": "박스 안에 사과가 3개, 감이 2개 있습니다. 박스 안에 감은 몇 개 들어있습니까?",
        "question_en": "If you toss 10, 50, and 100-won coins, find the number of ways in which the 10-won coin will come up heads and the 100-won coin will come up tails.",
        "answer_ko": "2",
        "answer_en": "2",
        "solution_abst_ko": "2",
        "solution_abst_en": "2",
        "solution_code_ko": "var_a = 2\nprint(int(var_a))",
        "solution_code_en": "var_a = 2\nprint(int(var_a))"
    },
    "7943": {
        "category": "Correspondence",
        "question_ko": "상현이가 어제 편의점에서 음료수를 사왔다. 어제 사온 음료수 중 절반과 2000밀리리터(㎖)의 음료수를 마시고, 오늘 남은 음료수의 절반과 2000밀리리터(㎖)를 마셨더니 남은 음료수가 없었다. 이때 상현이가 어제 사온 음료수는 몇 밀리리터(㎖)입니까?",
        "question_en": "Sanghyun bought a soda at a convenience store yesterday. He drank half of the soda he bought yesterday and an additional 2000 milliliters (ml) of soda. Today, he drank half of the remaining soda and additional 2000 milliliters (ml) of soda, and there was no soda left. How many milliliters (ml) of soda did Sanghyun buy yesterday?",
        "answer_ko": "12000",
        "answer_en": "12000",
        "solution_abst_ko": "0 2000 [OP_ADD] 2 [OP_MUL] 2000 [OP_ADD] 2 [OP_MUL]",
        "solution_abst_en": "0 2000 [OP_ADD] 2 [OP_MUL] 2000 [OP_ADD] 2 [OP_MUL]",
        "solution_code_ko": "var_a = 0\nvar_b = 2000\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 2000\nvar_g = var_e + var_f\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))",
        "solution_code_en": "var_a = 0\nvar_b = 2000\nvar_c = var_a + var_b\nvar_d = 2\nvar_e = var_c * var_d\nvar_f = 2000\nvar_g = var_e + var_f\nvar_h = 2\nvar_i = var_g * var_h\nprint(int(var_i))"
    }
}